ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<newPDoubleDArea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L56
  cmpl   $0x0,-0x14(%rbp)
  js     L56
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L46
  cmpq   $0x0,-0x8(%rbp)
  jne    L46
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L46
L56:
  cmpq   $0x0,-0x20(%rbp)
  je     L78
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printInt@plt>
  mov    $0x1,%edx
  mov    $0x147,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printLnAndFile@plt>
  jmp    L70
L78:
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printVoidSt@plt>
  mov    $0x1,%edx
  mov    $0x14c,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printLnAndFile@plt>
  jmp    L70
L46:
  nop
L70:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D30
type_guessed: string
name: unpack_data
arguments: label: D37
type_guessed: string

tool: D24: Error Cannot allocate space ,size:

tool: D30: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c

tool: D37: Error ret is

assistant: ```c
double **newPDoubleDArea(int size, int *ret) {
  void *pTmp = NULL;
  if ((ret != NULL) && (size >= 0)) {
    pTmp = malloc(sizeof(double *) * size);
    if ((size != 0) && (pTmp == NULL)) {
      *ret = 0;
    } else {
    }
  } else if (ret != NULL) {
    *ret = 0;
    printInt("Error Cannot allocate space ,size:", size, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 327, 1);
  } else {
    printVoidSt("Error ret is", ret, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 332, 1);
  }
  return (double **)pTmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<newPDoubleDArea>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L58
  test   %edi,%edi
  jns    L13
L58:
  test   %rbx,%rbx
  je     L68
  movl   $0x0,(%rbx)
  mov    $0x0,%edx
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  call   <printInt@plt>
  mov    $0x1,%edx
  mov    $0x147,%esi
  lea    D35(%rip),%rdi
  call   <printLnAndFile@plt>
  mov    $0x0,%eax
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  je     L48
  test   %rax,%rax
  jne    L48
  movl   $0x0,(%rbx)
  jmp    L48
L68:
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D23(%rip),%rdi
  call   <printVoidSt@plt>
  mov    $0x1,%edx
  mov    $0x14c,%esi
  lea    D35(%rip),%rdi
  call   <printLnAndFile@plt>
  mov    %rbx,%rax
  jmp    L48
```

tool_calls: name: read_data
arguments: data_label: D21
data_type: string
name: read_data
arguments: data_label: D35
data_type: string
name: read_data
arguments: data_label: D23
data_type: string

tool: D21: Error Cannot allocate space ,size:

tool: D35: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c

tool: D23: Error ret is

assistant: ```c
double **newPDoubleDArea(int size, int *ret) {
  void *pTmp = NULL;
  if ((ret != NULL) && (size >= 0)) {
    pTmp = malloc(sizeof(double *) * size);
    if ((size != 0) && (pTmp == NULL)) {
      *ret = 0;
    } else {
    }
  } else if (ret != NULL) {
    *ret = 0;
    printInt("Error Cannot allocate space ,size:", size, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 327, 1);
  } else {
    printVoidSt("Error ret is", ret, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 332, 1);
  }
  return (double **)pTmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<newPDoubleDArea>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L29
  mov    %edi,%ebp
  mov    %rsi,%rbx
  test   %edi,%edi
  jns    L12
  test   %rsi,%rsi
  je     L29
  movl   $0x0,(%rsi)
  xor    %edx,%edx
  mov    %edi,%esi
  lea    D24(%rip),%rdi
  call   <printInt@plt>
  mov    $0x1,%edx
  mov    $0x147,%esi
  lea    D34(%rip),%rdi
  call   <printLnAndFile@plt>
  xor    %eax,%eax
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  je     L46
  test   %rax,%rax
  jne    L46
  movl   $0x0,(%rbx)
  jmp    L46
  nopl   (%rax)
L29:
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D36(%rip),%rdi
  call   <printVoidSt@plt>
  mov    $0x1,%edx
  mov    $0x14c,%esi
  lea    D34(%rip),%rdi
  call   <printLnAndFile@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_infered: string
name: disassemble_data
arguments: data_label: D34
type_infered: string
name: disassemble_data
arguments: data_label: D36
type_infered: string

tool: D24: Error Cannot allocate space ,size:

tool: D34: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c

tool: D36: Error ret is

assistant: ```c
double **newPDoubleDArea(int size, int *ret) {
  void *pTmp = NULL;
  if ((ret != NULL) && (size >= 0)) {
    pTmp = malloc(sizeof(double *) * size);
    if ((size != 0) && (pTmp == NULL)) {
      *ret = 0;
    } else {
    }
  } else if (ret != NULL) {
    *ret = 0;
    printInt("Error Cannot allocate space ,size:", size, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 327, 1);
  } else {
    printVoidSt("Error ret is", ret, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 332, 1);
  }
  return (double **)pTmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<newPDoubleDArea>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L26
  mov    %edi,%ebp
  mov    %rsi,%rbx
  test   %edi,%edi
  jns    L5
  test   %rsi,%rsi
  je     L26
  movl   $0x0,(%rsi)
  xor    %edx,%edx
  mov    %edi,%esi
  lea    D14(%rip),%rdi
  call   <printInt@plt>
  mov    $0x1,%edx
  mov    $0x147,%esi
  lea    D5(%rip),%rdi
  call   <printLnAndFile@plt>
  xor    %eax,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  je     L7
  test   %rax,%rax
  jne    L7
  movl   $0x0,(%rbx)
  jmp    L7
  nopl   (%rax)
L26:
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D35(%rip),%rdi
  call   <printVoidSt@plt>
  mov    $0x1,%edx
  mov    $0x14c,%esi
  lea    D5(%rip),%rdi
  call   <printLnAndFile@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D35
type_infered: string

tool: D14: Error Cannot allocate space ,size:

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c

tool: D35: Error ret is

assistant: ```c
double **newPDoubleDArea(int size, int *ret) {
  void *pTmp = NULL;
  if ((ret != NULL) && (size >= 0)) {
    pTmp = malloc(sizeof(double *) * size);
    if ((size != 0) && (pTmp == NULL)) {
      *ret = 0;
    } else {
    }
  } else if (ret != NULL) {
    *ret = 0;
    printInt("Error Cannot allocate space ,size:", size, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 327, 1);
  } else {
    printVoidSt("Error ret is", ret, 0);
    printLnAndFile("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Chalearm/MachineLearning-/refs/heads/master/mProject/library_jui/dataStruct/src/basicVarArea.c", 332, 1);
  }
  return (double **)pTmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L76
L62:
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x38(%rbp)
  jmp    L73
L8:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cltd
  idivl  -0x38(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L5
  addl   $0x1,-0x34(%rbp)
L5:
  addl   $0x1,-0x38(%rbp)
L73:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x38(%rbp)
  jle    L8
  cmpl   $0x2,-0x34(%rbp)
  jne    L2
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L61
L2:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L61:
  movl   $0x0,-0x34(%rbp)
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x3c(%rbp)
L76:
  cmpl   $0x8,-0x3c(%rbp)
  jle    L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D49
type_guessed: string

tool: D27: %d - Please, insert the integer value: 

tool: D26: %d

tool: D21: Result: is prime, position: %d

tool: D6: Result: is dont prime

tool: D49: 
-----------------------------------------

assistant: ```c
int main() {
  int number[10];
  int i, j;
  int count = 0;
  for (i = 0; i < 9; i++) {
    printf("%d - Please, insert the integer value: ", i);
    scanf("%d", &number[i]);
    for (j = 1; j <= number[i]; j++) {
      if (number[i] % j == 0) {
        count++;
      }
    }
    if (count == 2) {
      printf("Result: is prime, position: %d", i);
    } else {
      printf("Result: is dont prime");
    }
    count = 0;
    printf("\n-----------------------------------------\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D23(%rip),%r13
  lea    D38(%rip),%r12
  lea    D40(%rip),%r14
  lea    D41(%rip),%r15
  jmp    L1
L11:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x9,%ebx
  je     L16
L1:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%esi
  test   %esi,%esi
  jle    L11
  lea    0x1(%rsi),%r8d
  mov    $0x0,%edi
  mov    $0x1,%ecx
L12:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L12
  cmp    $0x2,%edi
  jne    L11
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L44
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D38
type_infered: string
name: parse_data
arguments: label: D40
type_infered: string
name: parse_data
arguments: label: D41
type_infered: string
name: parse_data
arguments: label: D33
type_infered: string

tool: D23: %d - Please, insert the integer value: 

tool: D38: %d

tool: D40: Result: is dont prime

tool: D41: Result: is prime, position: %d

tool: D33: 
-----------------------------------------

assistant: ```c
int main() {
  int number[10];
  int i, j;
  int count = 0;
  for (i = 0; i < 9; i++) {
    printf("%d - Please, insert the integer value: ", i);
    scanf("%d", &number[i]);
    for (j = 1; j <= number[i]; j++) {
      if (number[i] % j == 0) {
        count++;
      }
    }
    if (count == 2) {
      printf("Result: is prime, position: %d", i);
    } else {
      printf("Result: is dont prime");
    }
    count = 0;
    printf("\n-----------------------------------------\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%r15
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    D34(%rip),%r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%esi
  test   %esi,%esi
  jle    L16
  lea    0x1(%rsi),%r8d
  xor    %edi,%edi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L40:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L40
  cmp    $0x2,%edi
  je     L13
L16:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L38:
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <puts@plt>
  cmp    $0x9,%ebx
  jne    L27
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L13:
  mov    %ebx,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L38
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D34
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D49
type_infered: string

tool: D26: Result: is dont prime

tool: D14: %d - Please, insert the integer value: 

tool: D34: %d

tool: D3: 
-----------------------------------------

tool: D49: Result: is prime, position: %d

assistant: ```c
int main() {
  int number[10];
  int i, j;
  int count = 0;
  for (i = 0; i < 9; i++) {
    printf("%d - Please, insert the integer value: ", i);
    scanf("%d", &number[i]);
    for (j = 1; j <= number[i]; j++) {
      if (number[i] % j == 0) {
        count++;
      }
    }
    if (count == 2) {
      printf("Result: is prime, position: %d", i);
    } else {
      printf("Result: is dont prime");
    }
    count = 0;
    printf("\n-----------------------------------------\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D33(%rip),%r15
  push   %r14
  lea    D39(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%esi
  test   %esi,%esi
  jle    L43
  lea    0x1(%rsi),%r8d
  xor    %edi,%edi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L24:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L24
  cmp    $0x2,%edi
  je     L18
L43:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L8:
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <puts@plt>
  cmp    $0x9,%ebx
  jne    L26
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L18:
  mov    %ebx,%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D33
datatype: string
name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D48
datatype: string
name: extract_symbolic_data
arguments: data_label: D43
datatype: string

tool: D33: Result: is dont prime

tool: D39: %d - Please, insert the integer value: 

tool: D17: %d

tool: D48: 
-----------------------------------------

tool: D43: Result: is prime, position: %d

assistant: ```c
int main() {
  int number[10];
  int i, j;
  int count = 0;
  for (i = 0; i < 9; i++) {
    printf("%d - Please, insert the integer value: ", i);
    scanf("%d", &number[i]);
    for (j = 1; j <= number[i]; j++) {
      if (number[i] % j == 0) {
        count++;
      }
    }
    if (count == 2) {
      printf("Result: is prime, position: %d", i);
    } else {
      printf("Result: is dont prime");
    }
    count = 0;
    printf("\n-----------------------------------------\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ReverseStringInPlace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L27
  cmpq   $0x0,-0x30(%rbp)
  jne    L13
L27:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L18
L13:
  movb   $0x0,-0x11(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L26:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L17:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L26
  mov    -0x28(%rbp),%rax
L18:
  pop    %rbp
  ret
```

assistant: ```c
char *ReverseStringInPlace(char *str, size_t len) {
  if (!str || len <= 0) {
    errno = EINVAL;
    return NULL;
  }
  char temp = 0;
  for (size_t i = 0, j = len - 1; i < j; ++i, --j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ReverseStringInPlace>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L22
  test   %rsi,%rsi
  je     L22
  sub    $0x1,%rsi
  je     L7
  mov    $0x0,%edx
L2:
  movzbl (%rax,%rdx,1),%ecx
  movzbl (%rax,%rsi,1),%edi
  mov    %dil,(%rax,%rdx,1)
  mov    %cl,(%rax,%rsi,1)
  add    $0x1,%rdx
  sub    $0x1,%rsi
  cmp    %rsi,%rdx
  jb     L2
L7:
  ret
L22:
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *ReverseStringInPlace(char *str, size_t len) {
  if (!str || len <= 0) {
    errno = EINVAL;
    return NULL;
  }
  char temp = 0;
  for (size_t i = 0, j = len - 1; i < j; ++i, --j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ReverseStringInPlace>:
  endbr64
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L19
  sub    $0x1,%rsi
  je     L30
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L27:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  mov    %al,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %rsi,%rdx
  jb     L27
L30:
  mov    %rdi,%rax
  ret
  nop
L19:
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ReverseStringInPlace(char *str, size_t len) {
  if (!str || len <= 0) {
    errno = EINVAL;
    return NULL;
  }
  char temp = 0;
  for (size_t i = 0, j = len - 1; i < j; ++i, --j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ReverseStringInPlace>:
  endbr64
  test   %rdi,%rdi
  je     L28
  test   %rsi,%rsi
  je     L28
  sub    $0x1,%rsi
  je     L23
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  mov    %al,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %rsi,%rdx
  jb     L3
L23:
  mov    %rdi,%rax
  ret
  nop
L28:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ReverseStringInPlace(char *str, size_t len) {
  if (!str || len <= 0) {
    errno = EINVAL;
    return NULL;
  }
  char temp = 0;
  for (size_t i = 0, j = len - 1; i < j; ++i, --j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <__NONDET__@plt>
  mov    %eax,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  cltq
  movl   $0x1,-0x90(%rbp,%rax,4)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  int a[32];
  int x = __NONDET__();
  a[x % 32] = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__NONDET__@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a[32];
  int x = __NONDET__();
  a[x % 32] = 1;
}
```