user: 下面的汇编指令对应的C源代码是什么:

```asm
<ftoa>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movaps %xmm0,%xmm3
  movss  %xmm0,0xc(%rsp)
  mov    %rdi,%rbx
  pxor   %xmm0,%xmm0
  mov    $0x0,%r12d
  comiss %xmm3,%xmm0
  ja     L55
L15:
  movss  0xc(%rsp),%xmm4
  ucomiss D11(%rip),%xmm4
  jp     L34
  mov    $0x0,%ebp
  jne    L34
L37:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  movsd  D76(%rip),%xmm0
  call   <pow@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  comiss D32(%rip),%xmm0
  jbe    L58
  ucomiss D11(%rip),%xmm0
  setp   %al
  mov    $0x1,%edx
  cmovne %edx,%eax
  test   %al,%al
  je     L58
  movss  D15(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L102
L58:
  cvttss2si %xmm0,%eax
  movslq %r12d,%rdx
  lea    0x30(%rax),%ecx
  mov    %cl,(%rbx,%rdx,1)
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  lea    0x2(%r12),%esi
  add    $0x1,%r12d
  movslq %r12d,%r12
  movb   $0x2e,(%rbx,%r12,1)
L33:
  movslq %esi,%rdx
  lea    (%rbx,%rdx,1),%rax
  lea    0x4(%rbx,%rdx,1),%rdi
  movss  D3(%rip),%xmm2
L40:
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%edx
  lea    0x30(%rdx),%ecx
  mov    %cl,(%rax)
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  subss  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L40
  lea    0x4(%rsi),%eax
  test   %ebp,%ebp
  jne    L63
  cltq
  movb   $0x0,(%rbx,%rax,1)
L29:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  movb   $0x2d,(%rdi)
  xorps  D59(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
  mov    $0x1,%r12d
  jmp    L15
L34:
  movss  0xc(%rsp),%xmm0
  call   <log10@plt>
  mov    %eax,%ebp
  jmp    L37
L102:
  mulss  D3(%rip),%xmm0
  sub    $0x1,%ebp
  cvttss2si %xmm0,%eax
  movslq %r12d,%rdx
  lea    0x30(%rax),%ecx
  mov    %cl,(%rbx,%rdx,1)
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  lea    0x2(%r12),%esi
  add    $0x1,%r12d
  movslq %r12d,%r12
  movb   $0x2e,(%rbx,%r12,1)
  jmp    L33
L63:
  cltq
  movb   $0x78,(%rbx,%rax,1)
  lea    0x5(%rsi),%eax
  cltq
  movb   $0x31,(%rbx,%rax,1)
  lea    0x6(%rsi),%eax
  cltq
  movb   $0x30,(%rbx,%rax,1)
  lea    0x7(%rsi),%eax
  cltq
  movb   $0x65,(%rbx,%rax,1)
  add    $0x8,%esi
  movslq %esi,%rsi
  add    %rbx,%rsi
  mov    %ebp,%edi
  call   <ltoa@plt>
  jmp    L29
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: f64
name: extract_symbolic_data
arguments: data_tag: D76
type: f64
name: extract_symbolic_data
arguments: data_tag: D32
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D15
type: f32
name: extract_symbolic_data
arguments: data_tag: D3
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D59
type: byte[16]

tool: D11: 0

tool: D76: 10

tool: {"D32": [0x00,0x00,0x80,0xbf]}

tool: D15: 1

tool: {"D3": [0x00,0x00,0x20,0x41]}

tool: {"D59": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void ftoa(float fval, char *buf) {
  int index = 0, count, exponent;
  double temp1, temp2;
  if (fval < 0) {
    buf[index++] = '-';
    fval = -fval;
  }
  exponent = fval != 0.0 ? log10(fval) : 0;
  fval /= pow((double)10.0, (double)exponent);
  if ((fval > -1.0) && (fval < 1.0) && (fval != 0.0)) {
    fval *= 10;
    exponent--;
    buf[index++] = '0' + (int)fval;
    fval -= (int)fval;
    buf[index++] = '.';
  } else {
    buf[index++] = '0' + (int)fval;
    fval -= (int)fval;
    buf[index++] = '.';
  }
  for (count = 0; count < 4; count++) {
    fval *= 10;
    buf[index++] = '0' + (int)fval;
    fval -= (int)fval;
  }
  if (exponent) {
    buf[index++] = 'x';
    buf[index++] = '1';
    buf[index++] = '0';
    buf[index++] = 'e';
    ltoa(exponent, buf + index);
  } else {
    buf[index] = '\0';
  }
}
```