ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<set_gap_penalties>:
  endbr64
  mov    %esi,%r8d
  pxor   %xmm3,%xmm3
  cvtsi2ss %ecx,%xmm3
  lea    0x1(%rsi),%r9d
  mov    %r9d,%eax
  shl    $0x6,%eax
  cltq
  lea    (%rdi,%rax,4),%rsi
  mov    %rsi,%rax
  lea    0x5c(%rsi),%rdi
  mov    %rsi,%rcx
  pxor   %xmm1,%xmm1
L35:
  addss  (%rcx),%xmm1
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L35
  cvtss2sd %xmm3,%xmm3
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  movsd  D19(%rip),%xmm1
  subsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm5,%xmm5
  cvtsi2ss %edx,%xmm5
  movaps %xmm5,%xmm1
  mulss  0xdc(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x6c(%rsi)
  movaps %xmm5,%xmm1
  mulss  0xe0(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x70(%rsi)
  movaps %xmm5,%xmm1
  mulss  0xe4(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x74(%rsi)
  test   %r9d,%r9d
  je     L7
  lea    -0xa4(%rax),%rdx
  lea    0x1(%r8),%eax
  shl    $0x8,%rax
  mov    %rsi,%rcx
  sub    %rax,%rcx
  movsd  D19(%rip),%xmm4
L39:
  sub    $0x100,%rsi
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
L14:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L14
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm4,%xmm0
  divsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm4,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm5,%xmm1
  mulss  0xdc(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x6c(%rsi)
  movaps %xmm5,%xmm1
  mulss  0xe0(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x70(%rsi)
  movaps %xmm5,%xmm1
  mulss  0xe4(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x74(%rsi)
  sub    $0x100,%rdx
  cmp    %rcx,%rsi
  jne    L39
L7:
  ret
```

tool_calls: name: parse_data
arguments: label: D19
datatype: f64

tool: D19: 1

assistant: ```c
void set_gap_penalties(float *prof, int len, int nsip, float strength, int nsip_c) {
  int i;
  int j;
  float res = (float)nsip_c;
  float local_res = 0;
  float w = 0.0;
  prof += (64 * (len + 1));
  local_res = 0;
  for (j = 0; j < 23; j++) {
    local_res += prof[j];
  }
  w = 1.0 + (((local_res - 1.0) / res) * strength);
  prof[27] = prof[55] * nsip * w;
  prof[28] = prof[56] * nsip * w;
  prof[29] = prof[57] * nsip * w;
  i = len + 1;
  while (i--) {
    prof -= 64;
    local_res = 0;
    for (j = 0; j < 23; j++) {
      local_res += prof[j];
    }
    w = 1.0 + (((local_res - 1.0) / res) * strength);
    prof[27] = prof[55] * nsip * w;
    prof[28] = prof[56] * nsip * w;
    prof[29] = prof[57] * nsip * w;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<set_gap_penalties>:
  endbr64
  add    $0x1,%esi
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  mov    %rdi,%r8
  mov    %esi,%eax
  cvtsi2ss %ecx,%xmm3
  movaps %xmm4,%xmm1
  mov    %edx,%edi
  shl    $0x6,%eax
  cltq
  lea    (%r8,%rax,4),%rcx
  lea    0x5c(%rcx),%rdx
  mov    %rcx,%rax
  nopl   (%rax)
L30:
  addss  (%rax),%xmm1
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L30
  movsd  D3(%rip),%xmm5
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm3,%xmm3
  pxor   %xmm6,%xmm6
  cvtss2sd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm6
  cvtss2sd %xmm1,%xmm0
  subsd  %xmm5,%xmm0
  movss  0xdc(%rcx),%xmm1
  divsd  %xmm3,%xmm0
  mulss  %xmm6,%xmm1
  mulsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x6c(%rcx)
  movss  0xe0(%rcx),%xmm1
  mulss  %xmm6,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x70(%rcx)
  movss  0xe4(%rcx),%xmm1
  mulss  %xmm6,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x74(%rcx)
  test   %esi,%esi
  je     L15
  mov    %esi,%eax
  mov    %rcx,%rsi
  lea    -0xa4(%rcx),%rdx
  shl    $0x8,%rax
  sub    %rax,%rsi
  nop
L19:
  sub    $0x100,%rcx
  movaps %xmm4,%xmm0
  mov    %rcx,%rax
  nopl   (%rax)
L38:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L38
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm5,%xmm0
  movss  0xdc(%rcx),%xmm1
  sub    $0x100,%rdx
  mulss  %xmm6,%xmm1
  divsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x6c(%rcx)
  movss  0xe0(%rcx),%xmm1
  mulss  %xmm6,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x70(%rcx)
  movss  0xe4(%rcx),%xmm1
  mulss  %xmm6,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x74(%rcx)
  cmp    %rsi,%rcx
  jne    L19
L15:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: f64

tool: D3: 1

assistant: ```c
void set_gap_penalties(float *prof, int len, int nsip, float strength, int nsip_c) {
  int i;
  int j;
  float res = (float)nsip_c;
  float local_res = 0;
  float w = 0.0;
  prof += (64 * (len + 1));
  local_res = 0;
  for (j = 0; j < 23; j++) {
    local_res += prof[j];
  }
  w = 1.0 + (((local_res - 1.0) / res) * strength);
  prof[27] = prof[55] * nsip * w;
  prof[28] = prof[56] * nsip * w;
  prof[29] = prof[57] * nsip * w;
  i = len + 1;
  while (i--) {
    prof -= 64;
    local_res = 0;
    for (j = 0; j < 23; j++) {
      local_res += prof[j];
    }
    w = 1.0 + (((local_res - 1.0) / res) * strength);
    prof[27] = prof[55] * nsip * w;
    prof[28] = prof[56] * nsip * w;
    prof[29] = prof[57] * nsip * w;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%edi
  call   <ucgen_ciz@plt>
  mov    $0x3,%edi
  call   <ters_ucgen_ciz@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  ucgen_ciz(4);
  ters_ucgen_ciz(3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <ucgen_ciz@plt>
  mov    $0x3,%edi
  call   <ters_ucgen_ciz@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ucgen_ciz(4);
  ters_ucgen_ciz(3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <ucgen_ciz@plt>
  mov    $0x3,%edi
  call   <ters_ucgen_ciz@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ucgen_ciz(4);
  ters_ucgen_ciz(3);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <ucgen_ciz@plt>
  mov    $0x3,%edi
  call   <ters_ucgen_ciz@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ucgen_ciz(4);
  ters_ucgen_ciz(3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ConvertIntegerToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x12d687,-0x204(%rbp)
  mov    -0x204(%rbp),%edx
  lea    -0x200(%rbp),%rax
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x200(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <lr_output_message@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D8
type_guessed: string

tool: D19: %d

tool: D8: New string is [%s]

assistant: ```c
ConvertIntegerToString() {
  char String[500];
  int integerVariable = 1234567;
  sprintf(String, "%d", integerVariable);
  lr_output_message("New string is [%s]", String);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ConvertIntegerToString>:
  endbr64
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x12d687,%edx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <lr_output_message@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x200,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string

tool: D18: %d

tool: D9: New string is [%s]

assistant: ```c
ConvertIntegerToString() {
  char String[500];
  int integerVariable = 1234567;
  sprintf(String, "%d", integerVariable);
  lr_output_message("New string is [%s]", String);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ConvertIntegerToString>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rsi
  mov    $0x12d687,%edx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <lr_output_message@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D8
type: string

tool: D7: %d

tool: D8: New string is [%s]

assistant: ```c
ConvertIntegerToString() {
  char String[500];
  int integerVariable = 1234567;
  sprintf(String, "%d", integerVariable);
  lr_output_message("New string is [%s]", String);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ConvertIntegerToString>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  mov    $0x12d687,%edx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <lr_output_message@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D11
data_type: string

tool: D4: %d

tool: D11: New string is [%s]

assistant: ```c
ConvertIntegerToString() {
  char String[500];
  int integerVariable = 1234567;
  sprintf(String, "%d", integerVariable);
  lr_output_message("New string is [%s]", String);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_check_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  ja     L6
  cmpl   $0x10000000,-0xc(%rbp)
  jbe    L17
L6:
  mov    $0x180,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L17:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c", 384));
  return word_ans;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_check_times>:
  endbr64
  push   %rbx
  mov    %edi,%edi
  mov    %esi,%esi
  imul   %rsi,%rdi
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    %rax,%rdi
  ja     L19
  cmp    $0x10000000,%edi
  jbe    L10
L19:
  mov    $0x180,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L10:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c", 384));
  return word_ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L11
  cmp    $0x10000000,%edi
  ja     L11
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x180,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c", 384));
  return word_ans;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L5
  cmp    $0x10000000,%edi
  ja     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x180,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/tcpat.c", 384));
  return word_ans;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<LCDIntDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x64,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LCDIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000064))) = ui32IntFlags;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<LCDIntDisable>:
  endbr64
  mov    %rsi,0x64(%rdi)
  ret
```

assistant: ```c
void LCDIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000064))) = ui32IntFlags;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LCDIntDisable>:
  endbr64
  mov    %rsi,0x64(%rdi)
  ret
```

assistant: ```c
void LCDIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000064))) = ui32IntFlags;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LCDIntDisable>:
  endbr64
  mov    %rsi,0x64(%rdi)
  ret
```

assistant: ```c
void LCDIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000064))) = ui32IntFlags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<module_dummy_loadargs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void module_dummy_loadargs(const char *args) {
  (void)args;
  do {
  } while (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<module_dummy_loadargs>:
  endbr64
  ret
```

assistant: ```c
void module_dummy_loadargs(const char *args) {
  (void)args;
  do {
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<module_dummy_loadargs>:
  endbr64
  ret
```

assistant: ```c
void module_dummy_loadargs(const char *args) {
  (void)args;
  do {
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<module_dummy_loadargs>:
  endbr64
  ret
```

assistant: ```c
void module_dummy_loadargs(const char *args) {
  (void)args;
  do {
  } while (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D15
type: string

tool: D12: ptr1 = %p


tool: D15: ptr2 = %p


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1 = malloc(64);
  void *ptr2 = malloc(64);
  printf("ptr1 = %p\n", ptr1);
  printf("ptr2 = %p\n", ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr2);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string

tool: D5: ptr1 = %p


tool: D12: ptr2 = %p


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1 = malloc(64);
  void *ptr2 = malloc(64);
  printf("ptr1 = %p\n", ptr1);
  printf("ptr2 = %p\n", ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x40,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x40,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  mov    %rax,%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string

tool: D14: ptr1 = %p


tool: D10: ptr2 = %p


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1 = malloc(64);
  void *ptr2 = malloc(64);
  printf("ptr1 = %p\n", ptr1);
  printf("ptr2 = %p\n", ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x40,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x40,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  mov    %rax,%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D11: ptr1 = %p


tool: D2: ptr2 = %p


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1 = malloc(64);
  void *ptr2 = malloc(64);
  printf("ptr1 = %p\n", ptr1);
  printf("ptr2 = %p\n", ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr1);
  getchar();
  free(ptr2);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_char_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  sub    $0x41,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L4
  cmpl   $0x39,-0x4(%rbp)
  jle    L27
L4:
  movzbl -0x14(%rbp),%eax
  jmp    L9
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D9(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
L9:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: TVGHEFCDIJMLKNOPQYWAABSXRZ[\]^_`tvghefcdijmlknopqywaabsxrz

assistant: ```c
char get_char_comp(char c) {
  int i = c - 65;
  if (i < 0 || i > 57) {
    return c;
  } else {
    return "TVGHEFCDIJMLKNOPQYWAABSXRZ[\\]^_`tvghefcdijmlknopqywaabsxrz"[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_char_comp>:
  endbr64
  mov    %edi,%eax
  movsbl %dil,%edi
  sub    $0x41,%edi
  cmp    $0x39,%edi
  ja     L4
  movslq %edi,%rdi
  lea    D5(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: TVGHEFCDIJMLKNOPQYWAABSXRZ[\]^_`tvghefcdijmlknopqywaabsxrz

assistant: ```c
char get_char_comp(char c) {
  int i = c - 65;
  if (i < 0 || i > 57) {
    return c;
  } else {
    return "TVGHEFCDIJMLKNOPQYWAABSXRZ[\\]^_`tvghefcdijmlknopqywaabsxrz"[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_char_comp>:
  endbr64
  mov    %edi,%eax
  movsbl %dil,%edi
  sub    $0x41,%edi
  cmp    $0x39,%edi
  ja     L3
  movslq %edi,%rdi
  lea    D1(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L3:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: TVGHEFCDIJMLKNOPQYWAABSXRZ[\]^_`tvghefcdijmlknopqywaabsxrz

assistant: ```c
char get_char_comp(char c) {
  int i = c - 65;
  if (i < 0 || i > 57) {
    return c;
  } else {
    return "TVGHEFCDIJMLKNOPQYWAABSXRZ[\\]^_`tvghefcdijmlknopqywaabsxrz"[i];
  }
}
```