ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<admin_send>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L9
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <shutdown@plt>
  mov    $0x0,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int admin_send(int fd, const char *str) {
  int len = strlen(str);
  if (write(fd, str, len) != len)
    return -1;
  shutdown(fd, SHUT_WR);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<admin_send>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  mov    %eax,%ebx
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L7
  mov    D3(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <shutdown@plt>
  xor    %eax,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int admin_send(int fd, const char *str) {
  int len = strlen(str);
  if (write(fd, str, len) != len)
    return -1;
  shutdown(fd, SHUT_WR);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<admin_send>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  mov    %eax,%ebx
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L12
  mov    D4(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <shutdown@plt>
  xor    %eax,%eax
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int admin_send(int fd, const char *str) {
  int len = strlen(str);
  if (write(fd, str, len) != len)
    return -1;
  shutdown(fd, SHUT_WR);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcutleftforgbk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L29
  mov    -0x28(%rbp),%rax
  jmp    L57
L29:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L31
L4:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L69
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L83
  addq   $0x1,-0x28(%rbp)
  addl   $0x2,-0x14(%rbp)
  jmp    L31
L69:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x14(%rbp)
L31:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  jmp    L3
L83:
  nop
L3:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl -0x15(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L57:
  leave
  ret
```

assistant: ```c
char *strcutleftforgbk(char *p, int len) {
  int i, alen, clen;
  char *r;
  char c;
  if (!p)
    return p;
  alen = strlen(p);
  r = p;
  for (i = 0; *p && i < len;) {
    if (*p & 0x80) {
      ++p;
      if (!*p)
        break;
      ++p;
      i += 2;
    } else {
      ++p;
      ++i;
    }
  }
  c = *p;
  *p = 0;
  clen = strlen(r);
  *p = c;
  memmove(r, p, alen - clen);
  r[alen - clen] = 0;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcutleftforgbk>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L6
  mov    %esi,%ebp
  call   <strlen@plt>
  mov    %eax,%r13d
  movzbl (%r12),%eax
  test   %ebp,%ebp
  jle    L9
  test   %al,%al
  je     L9
  mov    %r12,%rbx
  mov    $0x0,%edx
  jmp    L58
L95:
  add    $0x1,%rbx
L16:
  movzbl (%rbx),%ebp
  movb   $0x0,(%rbx)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %bpl,(%rbx)
  sub    %eax,%r13d
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movslq %r13d,%rbp
  movb   $0x0,(%r12,%rbp,1)
L6:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  add    $0x1,%rbx
  add    $0x1,%edx
L33:
  movzbl (%rbx),%eax
  cmp    %ebp,%edx
  jge    L16
  test   %al,%al
  je     L16
L58:
  test   %al,%al
  jns    L17
  cmpb   $0x0,0x1(%rbx)
  je     L95
  add    $0x2,%rbx
  add    $0x2,%edx
  jmp    L33
L9:
  mov    %r12,%rbx
  jmp    L16
```

assistant: ```c
char *strcutleftforgbk(char *p, int len) {
  int i, alen, clen;
  char *r;
  char c;
  if (!p)
    return p;
  alen = strlen(p);
  r = p;
  for (i = 0; *p && i < len;) {
    if (*p & 0x80) {
      ++p;
      if (!*p)
        break;
      ++p;
      i += 2;
    } else {
      ++p;
      ++i;
    }
  }
  c = *p;
  *p = 0;
  clen = strlen(r);
  *p = c;
  memmove(r, p, alen - clen);
  r[alen - clen] = 0;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcutleftforgbk>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L66
  mov    %esi,%r12d
  mov    %r14,%rbp
  call   <strlen@plt>
  movzbl (%r14),%ebx
  mov    %eax,%r13d
  test   %r12d,%r12d
  jle    L5
  test   %bl,%bl
  je     L5
  xor    %eax,%eax
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %rdx,%rbp
  add    $0x1,%eax
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L5
L28:
  cmp    %r12d,%eax
  jge    L5
L84:
  lea    0x1(%rbp),%rdx
  test   %bl,%bl
  jns    L50
  movzbl 0x1(%rbp),%ebx
  test   %bl,%bl
  je     L41
  movzbl 0x2(%rbp),%ebx
  add    $0x2,%rbp
  add    $0x2,%eax
  test   %bl,%bl
  jne    L28
  nopw   0x0(%rax,%rax,1)
L5:
  movb   $0x0,0x0(%rbp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %bl,0x0(%rbp)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  sub    %eax,%r13d
  mov    %r13d,%edx
  movslq %r13d,%r13
  call   <memmove@plt>
  movb   $0x0,(%r14,%r13,1)
L66:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L41:
  mov    %rdx,%rbp
  jmp    L5
```

assistant: ```c
char *strcutleftforgbk(char *p, int len) {
  int i, alen, clen;
  char *r;
  char c;
  if (!p)
    return p;
  alen = strlen(p);
  r = p;
  for (i = 0; *p && i < len;) {
    if (*p & 0x80) {
      ++p;
      if (!*p)
        break;
      ++p;
      i += 2;
    } else {
      ++p;
      ++i;
    }
  }
  c = *p;
  *p = 0;
  clen = strlen(r);
  *p = c;
  memmove(r, p, alen - clen);
  r[alen - clen] = 0;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcutleftforgbk>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L62
  mov    %esi,%r12d
  mov    %r14,%rbp
  call   <strlen@plt>
  movzbl (%r14),%ebx
  mov    %eax,%r13d
  test   %r12d,%r12d
  jle    L66
  test   %bl,%bl
  je     L66
  xor    %eax,%eax
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %rdx,%rbp
  add    $0x1,%eax
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L66
L29:
  cmp    %r12d,%eax
  jge    L66
L5:
  lea    0x1(%rbp),%rdx
  test   %bl,%bl
  jns    L73
  movzbl 0x1(%rbp),%ebx
  test   %bl,%bl
  je     L84
  movzbl 0x2(%rbp),%ebx
  add    $0x2,%rbp
  add    $0x2,%eax
  test   %bl,%bl
  jne    L29
  nopw   0x0(%rax,%rax,1)
L66:
  movb   $0x0,0x0(%rbp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %bl,0x0(%rbp)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  sub    %eax,%r13d
  mov    %r13d,%edx
  movslq %r13d,%r13
  call   <memmove@plt>
  movb   $0x0,(%r14,%r13,1)
L62:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L84:
  mov    %rdx,%rbp
  jmp    L66
```

assistant: ```c
char *strcutleftforgbk(char *p, int len) {
  int i, alen, clen;
  char *r;
  char c;
  if (!p)
    return p;
  alen = strlen(p);
  r = p;
  for (i = 0; *p && i < len;) {
    if (*p & 0x80) {
      ++p;
      if (!*p)
        break;
      ++p;
      i += 2;
    } else {
      ++p;
      ++i;
    }
  }
  c = *p;
  *p = 0;
  clen = strlen(r);
  *p = c;
  memmove(r, p, alen - clen);
  r[alen - clen] = 0;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<p_ls_dist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x80(%rbp),%rdx
  mov    -0x88(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <diff_3d@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <norm_3d@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x70(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x70(%rbp),%xmm0
  jp     L59
  pxor   %xmm0,%xmm0
  ucomisd -0x70(%rbp),%xmm0
  jne    L59
  mov    -0x80(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cart_3d@plt>
  movq   %xmm0,%rax
  jmp    L12
L59:
  mov    -0x80(%rbp),%rdx
  mov    -0x78(%rbp),%rcx
  lea    -0x60(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <diff_3d@plt>
  lea    -0x40(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inner_3d@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x70(%rbp),%xmm0
  movsd  %xmm0,-0x68(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x68(%rbp),%xmm0
  jbe    L76
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <norm_3d@plt>
  movq   %xmm0,%rax
  jmp    L12
L76:
  movsd  -0x68(%rbp),%xmm0
  comisd -0x70(%rbp),%xmm0
  jbe    L69
  mov    -0x88(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cart_3d@plt>
  movq   %xmm0,%rax
  jmp    L12
L69:
  lea    -0x60(%rbp),%rdx
  lea    -0x40(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cross@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <norm_3d@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  divsd  -0x70(%rbp),%xmm1
  movq   %xmm1,%rax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double p_ls_dist(double *p0, double *x0, double *x1) {
  double p[3], x[3], u[3];
  double l, a;
  diff_3d(x, x1, x0);
  l = norm_3d(x);
  if (!l)
    return cart_3d(p0, x0);
  diff_3d(p, p0, x0);
  a = inner_3d(p, x) / l;
  if (a < 0)
    return norm_3d(p);
  else if (a > l)
    return cart_3d(p0, x1);
  cross(u, x, p);
  return norm_3d(u) / l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<p_ls_dist>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r13
  mov    %rsi,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <diff_3d@plt>
  mov    %r13,%rdi
  call   <norm_3d@plt>
  movsd  %xmm0,0x8(%rsp)
  ucomisd D4(%rip),%xmm0
  jp     L22
  je     L73
L22:
  lea    0x10(%rsp),%r13
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <diff_3d@plt>
  lea    0x30(%rsp),%rsi
  mov    %r13,%rdi
  call   <inner_3d@plt>
  divsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L43
  comisd 0x8(%rsp),%xmm0
  ja     L50
  lea    0x10(%rsp),%rdx
  lea    0x30(%rsp),%rsi
  lea    0x50(%rsp),%rbx
  mov    %rbx,%rdi
  call   <cross@plt>
  mov    %rbx,%rdi
  call   <norm_3d@plt>
  divsd  0x8(%rsp),%xmm0
L37:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L73:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <cart_3d@plt>
  jmp    L37
L43:
  mov    %r13,%rdi
  call   <norm_3d@plt>
  jmp    L37
L50:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <cart_3d@plt>
  jmp    L37
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double p_ls_dist(double *p0, double *x0, double *x1) {
  double p[3], x[3], u[3];
  double l, a;
  diff_3d(x, x1, x0);
  l = norm_3d(x);
  if (!l)
    return cart_3d(p0, x0);
  diff_3d(p, p0, x0);
  a = inner_3d(p, x) / l;
  if (a < 0)
    return norm_3d(p);
  else if (a > l)
    return cart_3d(p0, x1);
  cross(u, x, p);
  return norm_3d(u) / l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p_ls_dist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    %rsi,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r14
  mov    %r14,%rdi
  call   <diff_3d@plt>
  mov    %r14,%rdi
  call   <norm_3d@plt>
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  movapd %xmm0,%xmm1
  jp     L27
  je     L58
L27:
  lea    0x10(%rsp),%r15
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movsd  %xmm1,0x8(%rsp)
  mov    %r15,%rdi
  call   <diff_3d@plt>
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <inner_3d@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  divsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  ja     L74
  comisd %xmm1,%xmm0
  ja     L66
  lea    0x50(%rsp),%rbp
  mov    %r15,%rdx
  mov    %r14,%rsi
  movsd  %xmm1,0x8(%rsp)
  mov    %rbp,%rdi
  call   <cross@plt>
  mov    %rbp,%rdi
  call   <norm_3d@plt>
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm1,%xmm0
L54:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x70,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <cart_3d@plt>
  jmp    L54
  nopl   (%rax)
L66:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <cart_3d@plt>
  jmp    L54
  nopl   (%rax)
L74:
  mov    %r15,%rdi
  call   <norm_3d@plt>
  jmp    L54
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double p_ls_dist(double *p0, double *x0, double *x1) {
  double p[3], x[3], u[3];
  double l, a;
  diff_3d(x, x1, x0);
  l = norm_3d(x);
  if (!l)
    return cart_3d(p0, x0);
  diff_3d(p, p0, x0);
  a = inner_3d(p, x) / l;
  if (a < 0)
    return norm_3d(p);
  else if (a > l)
    return cart_3d(p0, x1);
  cross(u, x, p);
  return norm_3d(u) / l;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<p_ls_dist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    %rsi,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r14
  mov    %r14,%rdi
  call   <diff_3d@plt>
  mov    %r14,%rdi
  call   <norm_3d@plt>
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  movapd %xmm0,%xmm1
  jp     L50
  je     L55
L50:
  lea    0x10(%rsp),%r15
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movsd  %xmm1,0x8(%rsp)
  mov    %r15,%rdi
  call   <diff_3d@plt>
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <inner_3d@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  divsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  ja     L5
  comisd %xmm1,%xmm0
  ja     L65
  lea    0x50(%rsp),%rbp
  mov    %r15,%rdx
  mov    %r14,%rsi
  movsd  %xmm1,0x8(%rsp)
  mov    %rbp,%rdi
  call   <cross@plt>
  mov    %rbp,%rdi
  call   <norm_3d@plt>
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm1,%xmm0
L46:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x70,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <cart_3d@plt>
  jmp    L46
  nopl   (%rax)
L65:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <cart_3d@plt>
  jmp    L46
  nopl   (%rax)
L5:
  mov    %r15,%rdi
  call   <norm_3d@plt>
  jmp    L46
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double p_ls_dist(double *p0, double *x0, double *x1) {
  double p[3], x[3], u[3];
  double l, a;
  diff_3d(x, x1, x0);
  l = norm_3d(x);
  if (!l)
    return cart_3d(p0, x0);
  diff_3d(p, p0, x0);
  a = inner_3d(p, x) / l;
  if (a < 0)
    return norm_3d(p);
  else if (a > l)
    return cart_3d(p0, x1);
  cross(u, x, p);
  return norm_3d(u) / l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_da>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzwl (%rax),%ebx
  mov    $0x100,%edi
  call   <le16_to_cpu@plt>
  and    %ebx,%eax
  test   %ax,%ax
  je     L39
  mov    $0x2,%r12d
  jmp    L33
L39:
  mov    $0x0,%r12d
L33:
  mov    -0x28(%rbp),%rax
  movzwl (%rax),%ebx
  mov    $0x200,%edi
  call   <le16_to_cpu@plt>
  and    %ebx,%eax
  test   %ax,%ax
  setne  %al
  movzbl %al,%eax
  or     %r12d,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  je     L31
  cmpl   $0x2,-0x1c(%rbp)
  ja     L44
  cmpl   $0x0,-0x1c(%rbp)
  je     L21
  cmpl   $0x1,-0x1c(%rbp)
  je     L49
  jmp    L44
L21:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L60
L49:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L60
L31:
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L60
L44:
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x18(%rbp)
  nop
L60:
  mov    -0x18(%rbp),%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *get_da(unsigned char *pframe) {
  unsigned char *da;
  unsigned int to_fr_ds = ((((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (8)))) != 0) << 1) | (((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (9)))) != 0);
  switch (to_fr_ds) {
  case 0x00:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x01:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x02:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  default:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  }
  return da;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_da>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzwl (%rdi),%r13d
  mov    $0x100,%edi
  call   <le16_to_cpu@plt>
  mov    %eax,%ebp
  movzwl (%rbx),%r12d
  mov    $0x200,%edi
  call   <le16_to_cpu@plt>
  test   %bp,%r13w
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%edx
  test   %ax,%r12w
  setne  %al
  movzbl %al,%eax
  or     %eax,%edx
  lea    0x4(%rbx),%rax
  cmp    $0x1,%edx
  je     L8
  lea    0x10(%rbx),%rax
  cmp    $0x2,%edx
  je     L8
  lea    0x4(%rbx),%rax
  add    $0x10,%rbx
  test   %edx,%edx
  cmovne %rbx,%rax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *get_da(unsigned char *pframe) {
  unsigned char *da;
  unsigned int to_fr_ds = ((((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (8)))) != 0) << 1) | (((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (9)))) != 0);
  switch (to_fr_ds) {
  case 0x00:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x01:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x02:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  default:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  }
  return da;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_da>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzwl (%rdi),%r13d
  mov    $0x100,%edi
  call   <le16_to_cpu@plt>
  mov    $0x200,%edi
  movzwl (%rbx),%r12d
  mov    %eax,%ebp
  call   <le16_to_cpu@plt>
  lea    0x4(%rbx),%rcx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %bp,%r13w
  setne  %al
  xor    %edx,%edx
  add    %eax,%eax
  test   %r8w,%r12w
  setne  %dl
  or     %eax,%edx
  lea    0x10(%rbx),%rax
  cmp    $0x1,%edx
  cmovle %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *get_da(unsigned char *pframe) {
  unsigned char *da;
  unsigned int to_fr_ds = ((((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (8)))) != 0) << 1) | (((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (9)))) != 0);
  switch (to_fr_ds) {
  case 0x00:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x01:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x02:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  default:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  }
  return da;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_da>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzwl (%rdi),%r13d
  mov    $0x100,%edi
  call   <le16_to_cpu@plt>
  mov    $0x200,%edi
  movzwl (%rbx),%r12d
  mov    %eax,%ebp
  call   <le16_to_cpu@plt>
  lea    0x4(%rbx),%rcx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %bp,%r13w
  setne  %al
  xor    %edx,%edx
  add    %eax,%eax
  test   %r8w,%r12w
  setne  %dl
  or     %eax,%edx
  lea    0x10(%rbx),%rax
  cmp    $0x1,%edx
  cmovle %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *get_da(unsigned char *pframe) {
  unsigned char *da;
  unsigned int to_fr_ds = ((((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (8)))) != 0) << 1) | (((*(unsigned short *)(pframe)) & le16_to_cpu((1 << (9)))) != 0);
  switch (to_fr_ds) {
  case 0x00:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x01:
    da = ((unsigned char *)((unsigned long)(pframe) + 4));
    break;
  case 0x02:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  default:
    da = ((unsigned char *)((unsigned long)(pframe) + 16));
    break;
  }
  return da;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mystricmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
L28:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
L19:
  mov    -0x14(%rbp),%eax
  jmp    L32
L10:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
  jmp    L28
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int mystricmp(char const *a, char const *b) {
  for (;; a++, b++) {
    int d = tolower(*a) - tolower(*b);
    if ((d != 0) || (!*a))
      return d;
  }
}
```