user: What would the C source look like for the assembly code provided here:

```asm
<faure_permutation>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L68
  mov    %edi,%ebx
  lea    0x8(,%rdi,8),%edi
  mov    $0x1,%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x8(%rax),%r13
  nopl   0x0(%rax)
L9:
  add    $0x1,%ebp
  add    $0x8,%r13
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%r13)
  cmp    %ebx,%ebp
  jle    L9
  mov    0x8(%r12),%rax
  movq   $0x0,(%r12)
  movabs $0x100000000,%rsi
  mov    %rsi,(%rax)
  cmp    $0x2,%ebx
  je     L68
  mov    $0x3,%edi
  lea    0x10(%r12),%r8
  mov    $0x2,%esi
  mov    (%r8),%rax
  test   $0x1,%dil
  jne    L143
  xchg   %ax,%ax
L21:
  mov    %edi,%r11d
  xor    %edx,%edx
  sar    %r11d
  movslq %r11d,%r9
  mov    -0x8(%r12,%r9,8),%r10
L158:
  mov    (%r10,%rdx,4),%ecx
  add    %ecx,%ecx
  mov    %ecx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r9
  jne    L158
  cmp    %r11d,%edi
  jle    L44
  lea    -0x1(%rdi),%edx
  sub    %r11d,%edx
  lea    0x4(%rax,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L157:
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax,%r9,4)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L157
L44:
  lea    0x1(%rdi),%eax
  add    $0x8,%r8
  add    $0x1,%esi
  cmp    %edi,%ebx
  je     L68
L140:
  mov    %eax,%edi
  mov    (%r8),%rax
  test   $0x1,%dil
  je     L21
L143:
  mov    %esi,%ebp
  mov    -0x8(%r8),%r9
  xor    %edx,%edx
  sar    %ebp
  movslq %ebp,%r13
  lea    0x0(,%r13,4),%r11
  jmp    L142
  xchg   %ax,%ax
L114:
  add    $0x1,%ecx
  mov    %ecx,(%rax,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdx,%r11
  je     L132
L142:
  mov    (%r9,%rdx,1),%ecx
  lea    (%rcx,%rcx,1),%r10d
  cmp    %esi,%r10d
  jge    L114
  mov    %ecx,(%rax,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdx,%r11
  jne    L142
L132:
  mov    %ebp,(%rax,%r13,4)
  add    $0x1,%ebp
  movslq %ebp,%rdx
  cmp    %edi,%ebp
  jge    L44
  cs nopw 0x0(%rax,%rax,1)
L148:
  mov    -0x4(%r9,%rdx,4),%ecx
  lea    (%rcx,%rcx,1),%r10d
  cmp    %esi,%r10d
  setge  %r10b
  movzbl %r10b,%r10d
  add    %r10d,%ecx
  mov    %ecx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%edi
  jg     L148
  lea    0x1(%rdi),%eax
  add    $0x8,%r8
  add    $0x1,%esi
  cmp    %edi,%ebx
  jne    L140
L68:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **faure_permutation(int n) {
  int i, j, c;
  int **p;
  if (n < 2)
    return NULL;
  p = (int **)malloc(sizeof(int *) * (n + 1));
  for (i = 1; i < n + 1; i++) {
    p[i] = (int *)malloc(sizeof(int) * (i + 1));
  }
  p[0] = NULL;
  p[1][0] = 0;
  p[1][1] = 1;
  for (i = 3; i < n + 1; i++) {
    if (i % 2 != 0) {
      for (j = 0; j < (i - 1) / 2; j++) {
        if (2 * p[i - 2][j] >= i - 1) {
          p[i - 1][j] = p[i - 2][j] + 1;
        } else {
          p[i - 1][j] = p[i - 2][j];
        }
      }
      c = (int)((i - 1) / 2);
      p[i - 1][c] = c;
      for (j = (i - 1) / 2 + 1; j < i; j++) {
        if (2 * p[i - 2][j - 1] >= i - 1) {
          p[i - 1][j] = p[i - 2][j - 1] + 1;
        } else {
          p[i - 1][j] = p[i - 2][j - 1];
        }
      }
    } else {
      for (j = 0; j < i / 2; j++) {
        p[i - 1][j] = 2 * p[i / 2 - 1][j];
      }
      for (j = i / 2; j < i; j++) {
        p[i - 1][j] = p[i - 1][j - i / 2] + 1;
      }
    }
  }
  return p;
}
```