user: 这段汇编代码用C语言表示是什么样的?

```asm
<root2poly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %edx,%eax
  lea    0x2(%rax,%rax,1),%r13d
  movslq %r13d,%rax
  lea    0xf(,%rax,8),%rdx
  shl    $0x3,%rax
  mov    %rdx,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L13
L83:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L83
L13:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L10
L14:
  lea    0x7(%rsp),%r15
  mov    %rdx,%rax
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rdx
  mov    %r15,%r14
  sub    %rdx,%rcx
  and    $0xfffffffffffffff8,%r15
  and    $0xfffffffffffffff0,%rax
  shr    $0x3,%r14
  cmp    %rcx,%rsp
  je     L42
L64:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L64
L42:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L39
L104:
  lea    0x7(%rsp),%rcx
  shl    $0x3,%r13d
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rcx,%rax
  and    $0xfffffffffffffff8,%rcx
  mov    %r13d,%edx
  mov    %rcx,%rbx
  shr    $0x3,%rax
  mov    %rax,-0x58(%rbp)
  call   <memset@plt>
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movsd  D5(%rip),%xmm0
  mov    -0x58(%rbp),%rax
  movsd  %xmm0,0x0(,%rax,8)
  movslq -0x4c(%rbp),%rax
  movsd  %xmm0,0x0(,%r14,8)
  test   %eax,%eax
  jle    L17
  mov    %rax,-0x58(%rbp)
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L25:
  movsd  0x10(%r15),%xmm1
  pxor   %xmm4,%xmm4
  pxor   %xmm5,%xmm5
  cvtss2sd (%r12,%r14,8),%xmm4
  cvtss2sd 0x4(%r12,%r14,8),%xmm5
  movapd %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  movsd  %xmm0,0x10(%rbx)
  movsd  0x18(%r15),%xmm0
  movapd %xmm0,%xmm2
  subsd  %xmm5,%xmm2
  movsd  %xmm2,0x18(%rbx)
  test   %r14,%r14
  je     L35
  lea    -0x1(%r14),%esi
  lea    0x28(%r15),%rax
  shl    $0x4,%rsi
  lea    0x28(%rbx),%rdx
  add    %rax,%rsi
  jmp    L105
  nopl   (%rax)
L58:
  add    $0x10,%rax
  movapd %xmm2,%xmm0
  movapd %xmm3,%xmm1
L105:
  movapd %xmm4,%xmm2
  movapd %xmm5,%xmm6
  movsd  -0x8(%rax),%xmm3
  add    $0x10,%rdx
  mulsd  %xmm0,%xmm6
  mulsd  %xmm1,%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm5,%xmm1
  subsd  %xmm6,%xmm2
  movapd %xmm3,%xmm6
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm6
  movsd  (%rax),%xmm2
  movapd %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm6,-0x18(%rdx)
  movsd  %xmm1,-0x10(%rdx)
  cmp    %rsi,%rax
  jne    L58
L35:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  add    $0x1,%r14
  call   <memcpy@plt>
  cmp    %r14,-0x58(%rbp)
  jne    L25
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L140:
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rcx
  shl    $0x4,%rdx
  movsd  (%r15,%rdx,1),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,-0x4c(%rbp)
  jge    L140
L22:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L147
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L10:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L14
L17:
  jne    L22
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L22
  nopl   0x0(%rax)
L39:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L104
L147:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void root2poly(float *r, double *p, const int n) {
  int i, ir, ii, j, jr, ji;
  double pp[(n + 1) * 2];
  double qq[(n + 1) * 2];
  memset(pp, 0, ((n + 1) * 2) * sizeof(double));
  memset(qq, 0, ((n + 1) * 2) * sizeof(double));
  pp[0] = qq[0] = 1;
  for (i = 0; i < n; i++) {
    ir = i * 2;
    ii = i * 2 + 1;
    qq[2] = pp[2] - r[ir];
    qq[3] = pp[3] - r[ii];
    for (j = 0; j < i; j++) {
      jr = j * 2;
      ji = j * 2 + 1;
      qq[jr + 4] = pp[jr + 4] - (pp[jr + 2] * r[ir] - pp[ji + 2] * r[ii]);
      qq[ji + 4] = pp[ji + 4] - (pp[ji + 2] * r[ir] + pp[jr + 2] * r[ii]);
    }
    memcpy(pp, qq, ((n + 1) * 2) * sizeof(double));
  }
  for (i = 0; i < (n + 1); i++) {
    p[i] = pp[i * 2];
  }
}
```