ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<gffi_get_int_32_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0xc(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int32_t gffi_get_int_32_swapped(int8_t *location, int offset) {
  int8_t buf[4];
  buf[3] = location[offset];
  buf[2] = location[offset + 1];
  buf[1] = location[offset + 2];
  buf[0] = location[offset + 3];
  return *(int32_t *)buf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gffi_get_int_32_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0xc(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int32_t gffi_get_int_32_swapped(int8_t *location, int offset) {
  int8_t buf[4];
  buf[3] = location[offset];
  buf[2] = location[offset + 1];
  buf[1] = location[offset + 2];
  buf[0] = location[offset + 3];
  return *(int32_t *)buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gffi_get_int_32_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0xc(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int32_t gffi_get_int_32_swapped(int8_t *location, int offset) {
  int8_t buf[4];
  buf[3] = location[offset];
  buf[2] = location[offset + 1];
  buf[1] = location[offset + 2];
  buf[0] = location[offset + 3];
  return *(int32_t *)buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L2
  movsd  -0x8(%rbp),%xmm0
  jmp    L6
L2:
  movsd  -0x10(%rbp),%xmm0
L6:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double min(double new, double old) {
  if (new < old) {
    return new;
  }
  return old;
}
```
user: What is the c source code of the assembly code below:

```asm
<min>:
  endbr64
  minsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double min(double new, double old) {
  if (new < old) {
    return new;
  }
  return old;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<min>:
  endbr64
  minsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double min(double new, double old) {
  if (new < old) {
    return new;
  }
  return old;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_binary_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L41
L9:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L11
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L11:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L48
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L48:
  subl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string

tool: D28: 1

tool: D25: 0

tool: D27:  

assistant: ```c
void test_binary_printf(uint64_t n, int bits_num) {
  int i;
  for (i = bits_num - 1; i >= 0; i--) {
    if ((n >> i) & 1) {
      printf("1");
    } else {
      printf("0");
    }
    if (i % 4 == 0) {
      printf(" ");
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_binary_printf>:
  endbr64
  sub    $0x1,%esi
  js     L61
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  lea    D8(%rip),%r13
  lea    D15(%rip),%r12
  lea    D12(%rip),%r14
  jmp    L47
L2:
  mov    %r13,%rdi
  call   <printf@plt>
L40:
  test   $0x3,%bl
  je     L17
L25:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L28
L47:
  bt     %ebx,%ebp
  jae    L2
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L40
L17:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L25
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L61:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string

tool: D8: 0

tool: D15: 1

tool: D12:  

assistant: ```c
void test_binary_printf(uint64_t n, int bits_num) {
  int i;
  for (i = bits_num - 1; i >= 0; i--) {
    if ((n >> i) & 1) {
      printf("1");
    } else {
      printf("0");
    }
    if (i % 4 == 0) {
      printf(" ");
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_binary_printf>:
  endbr64
  sub    $0x1,%esi
  js     L30
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  jmp    L7
  nopl   0x0(%rax)
L61:
  mov    %r12,%rdi
  call   <printf@plt>
  test   $0x3,%bl
  je     L58
L8:
  sub    $0x1,%ebx
  jb     L55
L7:
  bt     %ebx,%ebp
  jb     L61
  mov    %r13,%rdi
  call   <printf@plt>
  test   $0x3,%bl
  jne    L8
L58:
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L7
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D20
datatype: string

tool: D14:  

tool: D23: 0

tool: D20: 1

assistant: ```c
void test_binary_printf(uint64_t n, int bits_num) {
  int i;
  for (i = bits_num - 1; i >= 0; i--) {
    if ((n >> i) & 1) {
      printf("1");
    } else {
      printf("0");
    }
    if (i % 4 == 0) {
      printf(" ");
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_binary_printf>:
  endbr64
  sub    $0x1,%esi
  js     L60
  push   %r14
  lea    D27(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  jmp    L27
  nopl   0x0(%rax)
L16:
  mov    %r12,%rdi
  call   <printf@plt>
  test   $0x3,%bl
  je     L26
L45:
  sub    $0x1,%ebx
  jb     L46
L27:
  bt     %ebx,%ebp
  jb     L16
  mov    %r13,%rdi
  call   <printf@plt>
  test   $0x3,%bl
  jne    L45
L26:
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L27
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D27
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string

tool: D27:  

tool: D19: 0

tool: D2: 1

assistant: ```c
void test_binary_printf(uint64_t n, int bits_num) {
  int i;
  for (i = bits_num - 1; i >= 0; i--) {
    if ((n >> i) & 1) {
      printf("1");
    } else {
      printf("0");
    }
    if (i % 4 == 0) {
      printf(" ");
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%r9
  lea    -0x14(%rbp),%r8
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  lea    -0x24(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0xc(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <processOpts@plt>
  add    $0x10,%rsp
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L22
  mov    -0x24(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <add@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D58(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jne    L25
  mov    -0x24(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sub@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jne    L47
  mov    -0x24(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mult@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L47:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L39
  mov    -0x24(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <divide@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D65(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D58
type_guessed: string
name: read_data
arguments: data_label: D54
type_guessed: string
name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D65
type_guessed: string

tool: D58: Sum:

tool: D54: %-12s %.3f


tool: D36: Difference:

tool: D14: Product:

tool: D65: Quotient:

assistant: ```c
int main(int argc, char *argv[]) {
  int addFlag = 0;
  int subFlag = 0;
  int multFlag = 0;
  int divFlag = 0;
  int numOpts = 0;
  processOpts(&argc, argv, &addFlag, &subFlag, &multFlag, &divFlag, &numOpts);
  argv += numOpts;
  if (addFlag == 1)
    printf("%-12s %.3f\n", "Sum:", add(argc, argv));
  if (subFlag == 1)
    printf("%-12s %.3f\n", "Difference:", sub(argc, argv));
  if (multFlag == 1)
    printf("%-12s %.3f\n", "Product:", mult(argc, argv));
  if (divFlag == 1)
    printf("%-12s %.3f\n", "Quotient:", divide(argc, argv));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  lea    0x18(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rdi
  sub    $0x8,%rsp
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x2c(%rsp),%r8
  call   <processOpts@plt>
  movslq 0x34(%rsp),%rax
  lea    (%rbx,%rax,8),%rbx
  add    $0x10,%rsp
  cmpl   $0x1,0x14(%rsp)
  je     L34
L17:
  cmpl   $0x1,0x18(%rsp)
  je     L11
L71:
  cmpl   $0x1,0x1c(%rsp)
  je     L61
L88:
  cmpl   $0x1,0x20(%rsp)
  je     L39
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L34:
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <add@plt>
  lea    D53(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L11:
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <sub@plt>
  lea    D40(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L61:
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <mult@plt>
  lea    D22(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L88
L39:
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <divide@plt>
  lea    D62(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D53
data_type: string
name: read_data
arguments: data_label: D23
data_type: string
name: read_data
arguments: data_label: D40
data_type: string
name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D62
data_type: string

tool: D53: Sum:

tool: D23: %-12s %.3f


tool: D40: Difference:

tool: D22: Product:

tool: D62: Quotient:

assistant: ```c
int main(int argc, char *argv[]) {
  int addFlag = 0;
  int subFlag = 0;
  int multFlag = 0;
  int divFlag = 0;
  int numOpts = 0;
  processOpts(&argc, argv, &addFlag, &subFlag, &multFlag, &divFlag, &numOpts);
  argv += numOpts;
  if (addFlag == 1)
    printf("%-12s %.3f\n", "Sum:", add(argc, argv));
  if (subFlag == 1)
    printf("%-12s %.3f\n", "Difference:", sub(argc, argv));
  if (multFlag == 1)
    printf("%-12s %.3f\n", "Product:", mult(argc, argv));
  if (divFlag == 1)
    printf("%-12s %.3f\n", "Quotient:", divide(argc, argv));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0x18(%rsp),%rcx
  lea    0xc(%rsp),%rdi
  sub    $0x8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x2c(%rsp),%r8
  call   <processOpts@plt>
  movslq 0x34(%rsp),%rax
  lea    (%rbx,%rax,8),%rbp
  pop    %rax
  pop    %rdx
  cmpl   $0x1,0x14(%rsp)
  je     L13
L63:
  cmpl   $0x1,0x18(%rsp)
  je     L14
L32:
  cmpl   $0x1,0x1c(%rsp)
  je     L72
L43:
  cmpl   $0x1,0x20(%rsp)
  je     L34
L62:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <add@plt>
  lea    D39(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L63
L34:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <divide@plt>
  lea    D68(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L62
L72:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <mult@plt>
  lea    D57(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L14:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <sub@plt>
  lea    D29(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D39
data_type: string
name: unpack_data
arguments: data_tag: D54
data_type: string
name: unpack_data
arguments: data_tag: D68
data_type: string
name: unpack_data
arguments: data_tag: D57
data_type: string
name: unpack_data
arguments: data_tag: D29
data_type: string

tool: D39: Sum:

tool: D54: %-12s %.3f


tool: D68: Quotient:

tool: D57: Product:

tool: D29: Difference:

assistant: ```c
int main(int argc, char *argv[]) {
  int addFlag = 0;
  int subFlag = 0;
  int multFlag = 0;
  int divFlag = 0;
  int numOpts = 0;
  processOpts(&argc, argv, &addFlag, &subFlag, &multFlag, &divFlag, &numOpts);
  argv += numOpts;
  if (addFlag == 1)
    printf("%-12s %.3f\n", "Sum:", add(argc, argv));
  if (subFlag == 1)
    printf("%-12s %.3f\n", "Difference:", sub(argc, argv));
  if (multFlag == 1)
    printf("%-12s %.3f\n", "Product:", mult(argc, argv));
  if (divFlag == 1)
    printf("%-12s %.3f\n", "Quotient:", divide(argc, argv));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0x18(%rsp),%rcx
  lea    0xc(%rsp),%rdi
  sub    $0x8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x2c(%rsp),%r8
  call   <processOpts@plt>
  movslq 0x34(%rsp),%rax
  lea    (%rbx,%rax,8),%rbp
  pop    %rax
  pop    %rdx
  cmpl   $0x1,0x14(%rsp)
  je     L11
L1:
  cmpl   $0x1,0x18(%rsp)
  je     L31
L8:
  cmpl   $0x1,0x1c(%rsp)
  je     L40
L51:
  cmpl   $0x1,0x20(%rsp)
  je     L86
L71:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <add@plt>
  lea    D47(%rip),%rsi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L86:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <divide@plt>
  lea    D52(%rip),%rsi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L40:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <mult@plt>
  lea    D43(%rip),%rsi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L51
L31:
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <sub@plt>
  lea    D27(%rip),%rsi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D47
datatype: string
name: retrieve_data
arguments: data_label: D69
datatype: string
name: retrieve_data
arguments: data_label: D52
datatype: string
name: retrieve_data
arguments: data_label: D43
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string

tool: D47: Sum:

tool: D69: %-12s %.3f


tool: D52: Quotient:

tool: D43: Product:

tool: D27: Difference:

assistant: ```c
int main(int argc, char *argv[]) {
  int addFlag = 0;
  int subFlag = 0;
  int multFlag = 0;
  int divFlag = 0;
  int numOpts = 0;
  processOpts(&argc, argv, &addFlag, &subFlag, &multFlag, &divFlag, &numOpts);
  argv += numOpts;
  if (addFlag == 1)
    printf("%-12s %.3f\n", "Sum:", add(argc, argv));
  if (subFlag == 1)
    printf("%-12s %.3f\n", "Difference:", sub(argc, argv));
  if (multFlag == 1)
    printf("%-12s %.3f\n", "Product:", mult(argc, argv));
  if (divFlag == 1)
    printf("%-12s %.3f\n", "Quotient:", divide(argc, argv));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<nwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L11
L19:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L19
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t nwrite(int fd, const void *buf, size_t count) {
  ssize_t ret = 0;
  ssize_t written = 0;
  for (written = 0; written != count; written += ret) {
    ret = write(fd, buf + written, count - written);
    if (ret < 0) {
      if (errno == EINTR)
        ret = 0;
      else
        goto out;
    }
  }
  ret = written;
out:
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nwrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L7
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x0,%ebx
L29:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    %r12d,%edi
  call   <write@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jne    L29
L26:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %rdx,%rbx
  jmp    L26
```

assistant: ```c
ssize_t nwrite(int fd, const void *buf, size_t count) {
  ssize_t ret = 0;
  ssize_t written = 0;
  for (written = 0; written != count; written += ret) {
    ret = write(fd, buf + written, count - written);
    if (ret < 0) {
      if (errno == EINTR)
        ret = 0;
      else
        goto out;
    }
  }
  ret = written;
out:
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<nwrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L2
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L5:
  mov    %rbx,%rdx
  lea    0x0(%r13,%r12,1),%rsi
  mov    %ebp,%edi
  sub    %r12,%rdx
  call   <write@plt>
  add    %rax,%r12
  cmp    %r12,%rbx
  jne    L5
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t nwrite(int fd, const void *buf, size_t count) {
  ssize_t ret = 0;
  ssize_t written = 0;
  for (written = 0; written != count; written += ret) {
    ret = write(fd, buf + written, count - written);
    if (ret < 0) {
      if (errno == EINTR)
        ret = 0;
      else
        goto out;
    }
  }
  ret = written;
out:
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nwrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L18
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L16:
  mov    %rbx,%rdx
  lea    0x0(%r13,%r12,1),%rsi
  mov    %ebp,%edi
  sub    %r12,%rdx
  call   <write@plt>
  add    %rax,%r12
  cmp    %r12,%rbx
  jne    L16
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t nwrite(int fd, const void *buf, size_t count) {
  ssize_t ret = 0;
  ssize_t written = 0;
  for (written = 0; written != count; written += ret) {
    ret = write(fd, buf + written, count - written);
    if (ret < 0) {
      if (errno == EINTR)
        ret = 0;
      else
        goto out;
    }
  }
  ret = written;
out:
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<z_freec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void z_freec(char *c_str) {
  free(c_str);
  c_str = NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<z_freec>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void z_freec(char *c_str) {
  free(c_str);
  c_str = NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<z_freec>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void z_freec(char *c_str) {
  free(c_str);
  c_str = NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<z_freec>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void z_freec(char *c_str) {
  free(c_str);
  c_str = NULL;
}
```