user: 这段汇编代码用C语言表示是什么样的?

```asm
<PrintVisible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L82
  movb   $0x0,D71(%rip)
  jmp    L96
L82:
  mov    -0x78(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L96
  movb   $0x0,-0x6f(%rbp)
  movb   $0x0,-0x6d(%rbp)
  movb   $0x0,-0x6e(%rbp)
  movl   $0x0,-0x6c(%rbp)
  jmp    L154
L14:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    D71(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  cmp    $0x2b,%al
  jne    L83
  movzbl -0x6f(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x6f(%rbp)
L83:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    D71(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  cmp    $0x2a,%al
  jne    L143
  movzbl -0x6e(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x6e(%rbp)
L143:
  cmpb   $0x3,-0x6f(%rbp)
  jg     L10
  cmpb   $0x2,-0x6f(%rbp)
  jle    L6
  cmpb   $0x2,-0x6e(%rbp)
  jle    L6
L10:
  movb   $0x1,-0x6d(%rbp)
L6:
  addl   $0x1,-0x6c(%rbp)
L154:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    D71(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  test   %al,%al
  je     L142
  cmpb   $0x0,-0x6d(%rbp)
  je     L14
L142:
  cmpb   $0x0,-0x6d(%rbp)
  je     L173
  movl   $0x0,-0x6c(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L169
L146:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    D71(%rip),%rdx
  movzbl (%rax,%rdx,1),%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    %dl,-0x60(%rbp,%rax,1)
  mov    -0x68(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  jne    L50
  mov    -0x68(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,-0x60(%rbp,%rax,1)
  lea    -0x60(%rbp),%rax
  mov    $0x76,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Print@plt>
  mov    %eax,-0x64(%rbp)
  movb   $0x0,-0x60(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L124
L50:
  addl   $0x1,-0x68(%rbp)
L124:
  addl   $0x1,-0x6c(%rbp)
L169:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    D71(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  test   %al,%al
  je     L173
  cmpl   $0x0,-0x64(%rbp)
  je     L146
L173:
  movb   $0x0,D71(%rip)
L96:
  mov    -0x64(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int PrintVisible(string)
char *string;
{
  static char buffer[10000];
  char line[80], plus, asterisk, visible;
  int x, y, quit = 0;
  if (string[0] == 0)
    buffer[0] = 0;
  else {
    strcat(buffer, string);
    if (string[0] == '\n') {
      plus = 0;
      visible = 0;
      asterisk = 0;
      for (x = 0; buffer[x] != 0 && visible == 0; x++) {
        if (buffer[x] == '+')
          plus++;
        if (buffer[x] == '*')
          asterisk++;
        if ((plus > 3) || (plus > 2 && asterisk > 2))
          visible = 1;
      }
      if (visible) {
        for (x = 0, y = 0; buffer[x] != 0 && quit == 0; x++) {
          line[y] = buffer[x];
          if (line[y] == '\n') {
            line[y + 1] = 0;
            quit = Print(line, 'v');
            line[0] = 0;
            y = 0;
          } else
            y++;
        }
      }
      buffer[0] = 0;
    }
  }
  return quit;
}
```