ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<dreieck>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %r14
  mov    %edi,%r14d
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rdi),%ebp
  push   %rbx
  nopl   (%rax)
L3:
  mov    %r14d,%r12d
  mov    $0x1,%ebx
  sub    %ebp,%r12d
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <pascal@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L28
  mov    $0xa,%edi
  sub    $0x1,%ebp
  call   <putchar@plt>
  mov    %r14d,%eax
  sub    %ebp,%eax
  cmp    %r14d,%eax
  jle    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9:  %2d

assistant: ```c
void dreieck(int n) {
  int rows, cols;
  for (rows = 1; rows <= n; rows++) {
    for (cols = 1; cols <= n - rows + 1; cols++) {
      printf(" %2d", pascal(rows, cols));
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L13
L18:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int is_empty(struct item *it) {
  if (it == NULL)
    return (1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_empty>:
  endbr64
  test   %rdi,%rdi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_empty(struct item *it) {
  if (it == NULL)
    return (1);
  else
    return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_empty>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
```

assistant: ```c
int is_empty(struct item *it) {
  if (it == NULL)
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_empty>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
```

assistant: ```c
int is_empty(struct item *it) {
  if (it == NULL)
    return (1);
  else
    return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_sysfs_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_get_sysfs_numeric@plt>
  test   %rax,%rax
  jne    L7
  mov    -0xc(%rbp),%eax
  jmp    L8
L7:
  mov    $0xffffffff,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int get_sysfs_int(char *sysfs_attr) {
  int number = -1;
  if (_get_sysfs_numeric(sysfs_attr, "%d", &number) == 0)
    return number;
  else
    return ((int)-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_sysfs_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  lea    D5(%rip),%rsi
  call   <_get_sysfs_numeric@plt>
  test   %rax,%rax
  jne    L24
  mov    0x4(%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L13
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: %d

assistant: ```c
int get_sysfs_int(char *sysfs_attr) {
  int number = -1;
  if (_get_sysfs_numeric(sysfs_attr, "%d", &number) == 0)
    return number;
  else
    return ((int)-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_sysfs_int>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <_get_sysfs_numeric@plt>
  test   %rax,%rax
  jne    L27
  mov    0x4(%rsp),%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
  nop
L27:
  mov    $0xffffffff,%eax
  jmp    L14
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int get_sysfs_int(char *sysfs_attr) {
  int number = -1;
  if (_get_sysfs_numeric(sysfs_attr, "%d", &number) == 0)
    return number;
  else
    return ((int)-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_sysfs_int>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <_get_sysfs_numeric@plt>
  test   %rax,%rax
  jne    L21
  mov    0x4(%rsp),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
  nop
L21:
  mov    $0xffffffff,%eax
  jmp    L2
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %d

assistant: ```c
int get_sysfs_int(char *sysfs_attr) {
  int number = -1;
  if (_get_sysfs_numeric(sysfs_attr, "%d", &number) == 0)
    return number;
  else
    return ((int)-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<clear_page_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x1000,%ecx
  xor    %eax,%eax
  rep stos %al,%es:(%rdi)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void clear_page_b(void *page) {
  asm volatile("movl $4096,%%ecx\n\t"
               "xorl %%eax,%%eax\n\t"
               "rep stosb\n\t" ::"D"(page));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clear_page_b>:
  endbr64
  mov    $0x1000,%ecx
  xor    %eax,%eax
  rep stos %al,%es:(%rdi)
  ret
```

assistant: ```c
void clear_page_b(void *page) {
  asm volatile("movl $4096,%%ecx\n\t"
               "xorl %%eax,%%eax\n\t"
               "rep stosb\n\t" ::"D"(page));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_page_b>:
  endbr64
  mov    $0x1000,%ecx
  xor    %eax,%eax
  rep stos %al,%es:(%rdi)
  ret
```

assistant: ```c
void clear_page_b(void *page) {
  asm volatile("movl $4096,%%ecx\n\t"
               "xorl %%eax,%%eax\n\t"
               "rep stosb\n\t" ::"D"(page));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_page_b>:
  endbr64
  mov    $0x1000,%ecx
  xor    %eax,%eax
  rep stos %al,%es:(%rdi)
  ret
```

assistant: ```c
void clear_page_b(void *page) {
  asm volatile("movl $4096,%%ecx\n\t"
               "xorl %%eax,%%eax\n\t"
               "rep stosb\n\t" ::"D"(page));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x44(%rbp)
  jmp    L46
L1:
  mov    -0x44(%rbp),%eax
  cltq
  movl   $0x0,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L46:
  cmpl   $0xa,-0x44(%rbp)
  jle    L1
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L23:
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x48(%rbp),%eax
  test   %eax,%eax
  jle    L21
  mov    -0x48(%rbp),%eax
  cmp    $0xa,%eax
  jle    L75
L21:
  mov    -0x48(%rbp),%eax
  cmp    $0x3e7,%eax
  je     L11
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L75:
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
L18:
  jmp    L23
L11:
  nop
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x44(%rbp)
  jmp    L42
L25:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L42:
  cmpl   $0xa,-0x44(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
data_type: string
name: retrieve_data
arguments: tag: D36
data_type: string
name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D59
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D17
data_type: string

tool: D26: Enter your responses

tool: D36: %i

tool: D4: Bad response %i


tool: D59: 

Rating   Number of Responses

tool: D20: ------   -------------------

tool: D17: %4i%14i


assistant: ```c
int main(void) {
  int i, response;
  int rating_counters[11];
  for (i = 1; i <= 10; ++i) {
    rating_counters[i] = 0;
  }
  printf("Enter your responses\n");
  while (1) {
    scanf("%i", &response);
    if (response < 1 || response > 10) {
      if (response == 999) {
        break;
      } else {
        printf("Bad response %i\n", response);
      }
    } else {
      ++rating_counters[response];
    }
  }
  printf("\n\nRating   Number of Responses\n");
  printf("------   -------------------\n");
  for (i = 1; i <= 10; ++i) {
    printf("%4i%14i\n", i, rating_counters[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  lea    0x3c(%rsp),%rdx
L29:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L29
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rbp
  lea    D59(%rip),%rbx
  lea    D28(%rip),%r12
  jmp    L13
L28:
  movslq %esi,%rsi
  addl   $0x1,0x10(%rsp,%rsi,4)
L13:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L28
  cmp    $0x3e7,%esi
  je     L44
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L44:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D45(%rip),%rbp
L12:
  mov    0x10(%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L12
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D54
type_infered: string
name: read_data
arguments: data_tag: D59
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D22
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D45
type_infered: string

tool: D54: Enter your responses

tool: D59: %i

tool: D28: Bad response %i


tool: D22: 

Rating   Number of Responses

tool: D1: ------   -------------------

tool: D45: %4i%14i


assistant: ```c
int main(void) {
  int i, response;
  int rating_counters[11];
  for (i = 1; i <= 10; ++i) {
    rating_counters[i] = 0;
  }
  printf("Enter your responses\n");
  while (1) {
    scanf("%i", &response);
    if (response < 1 || response > 10) {
      if (response == 999) {
        break;
      } else {
        printf("Bad response %i\n", response);
      }
    } else {
      ++rating_counters[response];
    }
  }
  printf("\n\nRating   Number of Responses\n");
  printf("------   -------------------\n");
  for (i = 1; i <= 10; ++i) {
    printf("%4i%14i\n", i, rating_counters[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D21(%rip),%rdi
  lea    D28(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movups %xmm0,0x14(%rsp)
  movq   $0x0,0x34(%rsp)
  movups %xmm0,0x24(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rsi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L44
  cmp    $0x3e7,%esi
  je     L42
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L54
  nopl   0x0(%rax)
L44:
  addl   $0x1,0x10(%rsp,%rsi,4)
  jmp    L54
  nop
L42:
  lea    D51(%rip),%rdi
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    D13(%rip),%rdi
  lea    D34(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L43:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xb,%rbx
  jne    L43
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D28
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D51
type: string
name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D34
type: string

tool: D21: Enter your responses

tool: D28: Bad response %i


tool: D8: %i

tool: D51: 

Rating   Number of Responses

tool: D13: ------   -------------------

tool: D34: %4i%14i


assistant: ```c
int main(void) {
  int i, response;
  int rating_counters[11];
  for (i = 1; i <= 10; ++i) {
    rating_counters[i] = 0;
  }
  printf("Enter your responses\n");
  while (1) {
    scanf("%i", &response);
    if (response < 1 || response > 10) {
      if (response == 999) {
        break;
      } else {
        printf("Bad response %i\n", response);
      }
    } else {
      ++rating_counters[response];
    }
  }
  printf("\n\nRating   Number of Responses\n");
  printf("------   -------------------\n");
  for (i = 1; i <= 10; ++i) {
    printf("%4i%14i\n", i, rating_counters[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D4(%rip),%rdi
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D45(%rip),%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movups %xmm0,0x14(%rsp)
  movq   $0x0,0x34(%rsp)
  movups %xmm0,0x24(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rsi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L17
  cmp    $0x3e7,%esi
  je     L55
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
  nopl   0x0(%rax)
L17:
  addl   $0x1,0x10(%rsp,%rsi,4)
  jmp    L13
  nop
L55:
  lea    D38(%rip),%rdi
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    D24(%rip),%rdi
  lea    D53(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L35:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xb,%rbx
  jne    L35
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D45
type_infered: string
name: parse_data
arguments: data_label: D38
type_infered: string
name: parse_data
arguments: data_label: D24
type_infered: string
name: parse_data
arguments: data_label: D53
type_infered: string

tool: D4: Enter your responses

tool: D16: Bad response %i


tool: D45: %i

tool: D38: 

Rating   Number of Responses

tool: D24: ------   -------------------

tool: D53: %4i%14i


assistant: ```c
int main(void) {
  int i, response;
  int rating_counters[11];
  for (i = 1; i <= 10; ++i) {
    rating_counters[i] = 0;
  }
  printf("Enter your responses\n");
  while (1) {
    scanf("%i", &response);
    if (response < 1 || response > 10) {
      if (response == 999) {
        break;
      } else {
        printf("Bad response %i\n", response);
      }
    } else {
      ++rating_counters[response];
    }
  }
  printf("\n\nRating   Number of Responses\n");
  printf("------   -------------------\n");
  for (i = 1; i <= 10; ++i) {
    printf("%4i%14i\n", i, rating_counters[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_sudoku>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x8,-0x4(%rbp)
  jle    L31
  addl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x8,-0x8(%rbp)
  jle    L20
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %i

assistant: ```c
void print_sudoku(int sudoku[(9)][(9)]) {
  int n, o;
  for (n = 0; n < (9); n++) {
    printf("\n");
    for (o = 0; o < (9); o++) {
      printf("%i", sudoku[n][o]);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_sudoku>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x24(%rdi),%rbp
  lea    0x168(%rdi),%r13
  lea    D1(%rip),%r12
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x24(%rbp),%rbx
L8:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L8
  add    $0x24,%rbp
  cmp    %r13,%rbp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: %i

assistant: ```c
void print_sudoku(int sudoku[(9)][(9)]) {
  int n, o;
  for (n = 0; n < (9); n++) {
    printf("\n");
    for (o = 0; o < (9); o++) {
      printf("%i", sudoku[n][o]);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_sudoku>:
  endbr64
  push   %r13
  lea    0x168(%rdi),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    0x24(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L13:
  mov    $0xa,%edi
  lea    -0x24(%rbp),%rbx
  call   <putchar@plt>
  xchg   %ax,%ax
L3:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L3
  lea    0x24(%rbx),%rbp
  cmp    %r13,%rbp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: %i

assistant: ```c
void print_sudoku(int sudoku[(9)][(9)]) {
  int n, o;
  for (n = 0; n < (9); n++) {
    printf("\n");
    for (o = 0; o < (9); o++) {
      printf("%i", sudoku[n][o]);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_sudoku>:
  endbr64
  push   %r13
  lea    0x168(%rdi),%r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    0x24(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L17:
  mov    $0xa,%edi
  lea    -0x24(%rbp),%rbx
  call   <putchar@plt>
  xchg   %ax,%ax
L16:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L16
  lea    0x24(%rbx),%rbp
  cmp    %r13,%rbp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: %i

assistant: ```c
void print_sudoku(int sudoku[(9)][(9)]) {
  int n, o;
  for (n = 0; n < (9); n++) {
    printf("\n");
    for (o = 0; o < (9); o++) {
      printf("%i", sudoku[n][o]);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i_hyperloglogGetAlpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  je     L65
  cmpl   $0x40,-0x4(%rbp)
  ja     L42
  cmpl   $0x10,-0x4(%rbp)
  je     L38
  cmpl   $0x20,-0x4(%rbp)
  je     L55
  jmp    L42
L38:
  movsd  D32(%rip),%xmm0
  jmp    L3
L55:
  movsd  D47(%rip),%xmm0
  jmp    L3
L65:
  movsd  D29(%rip),%xmm0
  jmp    L3
L42:
  mov    -0x4(%rbp),%eax
  test   %rax,%rax
  js     L63
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L49
L63:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L49:
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D25(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D49(%rip),%xmm0
  divsd  %xmm1,%xmm0
L3:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D32
type_infered: byte[8]
name: parse_data
arguments: data_tag: D47
type_infered: byte[8]
name: parse_data
arguments: data_tag: D29
type_infered: byte[8]
name: parse_data
arguments: data_tag: D25
type_infered: f64
name: parse_data
arguments: data_tag: D2
type_infered: f64
name: parse_data
arguments: data_tag: D49
type_infered: f64

tool: {"D32": [0x00,0x00,0x00,0x40,0x37,0x89,0xe5,0x3f]}

tool: {"D47": [0x00,0x00,0x00,0x00,0xd3,0x4d,0xe6,0x3f]}

tool: {"D29": [0x00,0x00,0x00,0xc0,0x20,0xb0,0xe6,0x3f]}

tool: D25: 1.079

tool: D2: 1

tool: D49: 0.7213

assistant: ```c
double i_hyperloglogGetAlpha(unsigned int k) {
  switch (k) {
  case 16:
    return 0.673f;
  case 32:
    return 0.697f;
  case 64:
    return 0.709f;
  }
  return 0.7213 / (1.0 + 1.079 / (float)k);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i_hyperloglogGetAlpha>:
  endbr64
  cmp    $0x20,%edi
  je     L17
  movsd  D29(%rip),%xmm0
  cmp    $0x40,%edi
  je     L15
  movsd  D30(%rip),%xmm0
  cmp    $0x10,%edi
  je     L15
  mov    %edi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdi,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D56(%rip),%xmm1
  divsd  %xmm0,%xmm1
  addsd  D51(%rip),%xmm1
  movsd  D57(%rip),%xmm0
  divsd  %xmm1,%xmm0
  ret
L17:
  movsd  D50(%rip),%xmm0
L15:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D29
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D30
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D56
type_infered: f64
name: retrieve_data
arguments: data_label: D51
type_infered: f64
name: retrieve_data
arguments: data_label: D57
type_infered: f64
name: retrieve_data
arguments: data_label: D50
type_infered: byte[8]

tool: {"D29": [0x00,0x00,0x00,0xc0,0x20,0xb0,0xe6,0x3f]}

tool: {"D30": [0x00,0x00,0x00,0x40,0x37,0x89,0xe5,0x3f]}

tool: D56: 1.079

tool: D51: 1

tool: D57: 0.7213

tool: {"D50": [0x00,0x00,0x00,0x00,0xd3,0x4d,0xe6,0x3f]}

assistant: ```c
double i_hyperloglogGetAlpha(unsigned int k) {
  switch (k) {
  case 16:
    return 0.673f;
  case 32:
    return 0.697f;
  case 64:
    return 0.709f;
  }
  return 0.7213 / (1.0 + 1.079 / (float)k);
}
```