ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_TemmaRAcorrspeed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <portWrite@plt>
  test   %rax,%rax
  jns    L23
  mov    $0xffffffff,%eax
  jmp    L26
L23:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <portRead@plt>
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L26
L37:
  mov    $0xffffffff,%eax
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
datatype: string

tool: D10: la

assistant: ```c
int get_TemmaRAcorrspeed(char *local_buffer) {
  if (portWrite("la") < 0)
    return -1;
  portRead(local_buffer, -1, 1);
  if (strstr(local_buffer, "la") == local_buffer) {
    return 0;
  } else
    return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_TemmaRAcorrspeed>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D13(%rip),%rdi
  call   <portWrite@plt>
  test   %rax,%rax
  js     L0
  mov    $0x1,%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <portRead@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  setne  %al
  movzbl %al,%eax
  neg    %eax
L3:
  pop    %rbx
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D13: la

assistant: ```c
int get_TemmaRAcorrspeed(char *local_buffer) {
  if (portWrite("la") < 0)
    return -1;
  portRead(local_buffer, -1, 1);
  if (strstr(local_buffer, "la") == local_buffer) {
    return 0;
  } else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_TemmaRAcorrspeed>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rdi
  call   <portWrite@plt>
  test   %rax,%rax
  js     L18
  mov    $0x1,%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <portRead@plt>
  movzbl (%rbx),%eax
  sub    $0x6c,%eax
  je     L27
  neg    %eax
  sbb    %eax,%eax
L23:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L27:
  movzbl 0x1(%rbx),%eax
  sub    $0x61,%eax
  neg    %eax
  sbb    %eax,%eax
  jmp    L23
  nopl   (%rax)
L18:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: la

assistant: ```c
int get_TemmaRAcorrspeed(char *local_buffer) {
  if (portWrite("la") < 0)
    return -1;
  portRead(local_buffer, -1, 1);
  if (strstr(local_buffer, "la") == local_buffer) {
    return 0;
  } else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_TemmaRAcorrspeed>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  call   <portWrite@plt>
  test   %rax,%rax
  js     L13
  mov    $0x1,%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <portRead@plt>
  movzbl (%rbx),%eax
  sub    $0x6c,%eax
  je     L9
  neg    %eax
  sbb    %eax,%eax
L14:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  movzbl 0x1(%rbx),%eax
  sub    $0x61,%eax
  neg    %eax
  sbb    %eax,%eax
  jmp    L14
  nopl   (%rax)
L13:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: la

assistant: ```c
int get_TemmaRAcorrspeed(char *local_buffer) {
  if (portWrite("la") < 0)
    return -1;
  portRead(local_buffer, -1, 1);
  if (strstr(local_buffer, "la") == local_buffer) {
    return 0;
  } else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<firfilter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L4
  mov    -0x34(%rbp),%eax
  sub    %eax,-0x2c(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L47
L4:
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L47:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L50
L32:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x40(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L50:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L32
  jmp    L0
L53:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x40(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L53
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
int16_t firfilter(int16_t *buf, int pos, int len, int count, double *coefficients) {
  double result = 0.0;
  int count1, count2;
  int16_t *ptr;
  if (pos >= count) {
    pos -= count;
    count1 = count;
    count2 = 0;
  } else {
    count2 = pos;
    count1 = count - pos;
    pos = len - count1;
  }
  ptr = &buf[pos];
  while (count1--)
    result += *ptr++ * *coefficients++;
  while (count2--)
    result += *buf++ * *coefficients++;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<firfilter>:
  endbr64
  cmp    %ecx,%esi
  jl     L6
  sub    %ecx,%esi
  movslq %esi,%rdx
  lea    (%rdi,%rdx,8),%r9
  lea    -0x1(%rcx),%eax
  mov    $0x0,%esi
  test   %ecx,%ecx
  jne    L10
  pxor   %xmm0,%xmm0
  ret
L6:
  sub    %esi,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%r9
  lea    -0x1(%rcx),%eax
L10:
  mov    %eax,%eax
  lea    0x8(,%rax,8),%rdx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L26:
  movsd  (%r9,%rax,1),%xmm1
  mulsd  (%r8,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L26
  add    %rdx,%r8
  test   %esi,%esi
  je     L32
  mov    %esi,%edx
  mov    $0x0,%eax
L5:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L32:
  ret
```

assistant: ```c
int16_t firfilter(int16_t *buf, int pos, int len, int count, double *coefficients) {
  double result = 0.0;
  int count1, count2;
  int16_t *ptr;
  if (pos >= count) {
    pos -= count;
    count1 = count;
    count2 = 0;
  } else {
    count2 = pos;
    count1 = count - pos;
    pos = len - count1;
  }
  ptr = &buf[pos];
  while (count1--)
    result += *ptr++ * *coefficients++;
  while (count2--)
    result += *buf++ * *coefficients++;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<firfilter>:
  endbr64
  cmp    %ecx,%esi
  jl     L51
  sub    %ecx,%esi
  lea    -0x1(%rcx),%eax
  mov    $0xffffffff,%r9d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rdx
  xor    %esi,%esi
  test   %ecx,%ecx
  je     L38
L52:
  lea    0x8(,%rax,8),%rcx
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  xchg   %ax,%ax
L6:
  movsd  (%rdx,%rax,1),%xmm1
  mulsd  (%r8,%rax,1),%xmm1
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L6
  add    %rax,%r8
  test   %esi,%esi
  je     L57
  mov    %r9d,%r9d
  xor    %eax,%eax
  lea    0x8(,%r9,8),%rdx
  nopl   0x0(%rax)
L19:
  movsd  (%rdi,%rax,1),%xmm1
  mulsd  (%r8,%rax,1),%xmm1
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L19
L57:
  ret
  nopl   0x0(%rax)
L51:
  sub    %esi,%ecx
  lea    -0x1(%rsi),%r9d
  sub    %ecx,%edx
  lea    -0x1(%rcx),%eax
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rdx
  jmp    L52
  nopl   0x0(%rax)
L38:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
int16_t firfilter(int16_t *buf, int pos, int len, int count, double *coefficients) {
  double result = 0.0;
  int count1, count2;
  int16_t *ptr;
  if (pos >= count) {
    pos -= count;
    count1 = count;
    count2 = 0;
  } else {
    count2 = pos;
    count1 = count - pos;
    pos = len - count1;
  }
  ptr = &buf[pos];
  while (count1--)
    result += *ptr++ * *coefficients++;
  while (count2--)
    result += *buf++ * *coefficients++;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<firfilter>:
  endbr64
  cmp    %ecx,%esi
  jl     L61
  sub    %ecx,%esi
  lea    -0x1(%rcx),%r9d
  mov    $0xffffffff,%r10d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rdx
  xor    %esi,%esi
  test   %ecx,%ecx
  je     L24
L72:
  push   %rbx
  lea    0x1(%r9),%r11d
  test   %r9d,%r9d
  je     L68
  mov    %r11d,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  cs nopw 0x0(%rax,%rax,1)
L44:
  movupd (%rdx,%rax,1),%xmm1
  movupd (%r8,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L44
  mov    %r11d,%ebx
  and    $0xfffffffe,%ebx
  mov    %ebx,%ecx
  shl    $0x3,%rcx
  lea    (%r8,%rcx,1),%rax
  add    %rcx,%rdx
  cmp    %ebx,%r11d
  je     L37
L76:
  movsd  (%rdx),%xmm1
  mulsd  (%rax),%xmm1
  addsd  %xmm1,%xmm0
L37:
  mov    %r9d,%r9d
  lea    0x8(%r8,%r9,8),%rdx
  test   %esi,%esi
  je     L82
  lea    0x1(%r10),%esi
  test   %r10d,%r10d
  je     L23
  mov    %esi,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L11:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rdx,%rax,1),%xmm4
  add    $0x10,%rax
  mulpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L11
  mov    %esi,%ecx
  and    $0xfffffffe,%ecx
  mov    %ecx,%eax
  shl    $0x3,%rax
  add    %rax,%rdi
  add    %rax,%rdx
  cmp    %ecx,%esi
  je     L82
L23:
  movsd  (%rdx),%xmm1
  mulsd  (%rdi),%xmm1
  addsd  %xmm1,%xmm0
L82:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L61:
  sub    %esi,%ecx
  lea    -0x1(%rsi),%r10d
  sub    %ecx,%edx
  lea    -0x1(%rcx),%r9d
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rdx
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L24:
  pxor   %xmm0,%xmm0
  ret
L68:
  mov    %r8,%rax
  pxor   %xmm0,%xmm0
  jmp    L76
```

assistant: ```c
int16_t firfilter(int16_t *buf, int pos, int len, int count, double *coefficients) {
  double result = 0.0;
  int count1, count2;
  int16_t *ptr;
  if (pos >= count) {
    pos -= count;
    count1 = count;
    count2 = 0;
  } else {
    count2 = pos;
    count1 = count - pos;
    pos = len - count1;
  }
  ptr = &buf[pos];
  while (count1--)
    result += *ptr++ * *coefficients++;
  while (count2--)
    result += *buf++ * *coefficients++;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <read_stdin@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L17
  mov    $0xffffffff,%eax
  jmp    L35
L17:
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%ecx
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <modp_init@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  js     L23
L29:
  mov    $0x0,%eax
  call   <modp_run@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jg     L29
L23:
  mov    -0x18(%rbp),%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int main() {
  char *buf;
  int len = read_stdin(&buf);
  if (len < 0) {
    return -1;
  }
  int ret = modp_init(buf, len, 0);
  if (ret >= 0) {
    do {
      ret = modp_run();
    } while (ret > 0);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <read_stdin@plt>
  test   %eax,%eax
  js     L23
  mov    %eax,%esi
  mov    $0x0,%edx
  mov    (%rsp),%rdi
  call   <modp_init@plt>
  test   %eax,%eax
  js     L44
L41:
  mov    $0x0,%eax
  call   <modp_run@plt>
  test   %eax,%eax
  jg     L41
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L44
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char *buf;
  int len = read_stdin(&buf);
  if (len < 0) {
    return -1;
  }
  int ret = modp_init(buf, len, 0);
  if (ret >= 0) {
    do {
      ret = modp_run();
    } while (ret > 0);
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <read_stdin@plt>
  test   %eax,%eax
  js     L13
  mov    (%rsp),%rdi
  xor    %edx,%edx
  mov    %eax,%esi
  call   <modp_init@plt>
  test   %eax,%eax
  js     L46
  nopl   (%rax)
L2:
  xor    %eax,%eax
  call   <modp_run@plt>
  test   %eax,%eax
  jg     L2
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L13:
  or     $0xffffffff,%eax
  jmp    L46
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char *buf;
  int len = read_stdin(&buf);
  if (len < 0) {
    return -1;
  }
  int ret = modp_init(buf, len, 0);
  if (ret >= 0) {
    do {
      ret = modp_run();
    } while (ret > 0);
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <read_stdin@plt>
  test   %eax,%eax
  js     L46
  mov    (%rsp),%rdi
  xor    %edx,%edx
  mov    %eax,%esi
  call   <modp_init@plt>
  test   %eax,%eax
  js     L21
  nopl   (%rax)
L23:
  xor    %eax,%eax
  call   <modp_run@plt>
  test   %eax,%eax
  jg     L23
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L46:
  or     $0xffffffff,%eax
  jmp    L21
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char *buf;
  int len = read_stdin(&buf);
  if (len < 0) {
    return -1;
  }
  int ret = modp_init(buf, len, 0);
  if (ret >= 0) {
    do {
      ret = modp_run();
    } while (ret > 0);
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<conver>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L3:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x2,%eax
  add    %ebx,%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
L15:
  cmpl   $0x0,-0x24(%rbp)
  jne    L3
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int conver(int octal) {
  int decimal = 0;
  int i = 0;
  while (octal != 0) {
    decimal = decimal + (octal % 10) * pow(8, i++);
    octal = octal / 10;
  }
  return decimal;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<conver>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  je     L22
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L19:
  mov    %ebp,%esi
  add    $0x1,%ebp
  mov    $0x8,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %ecx,%ebx
  add    %ebx,%r12d
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L19
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    %edi,%r12d
  jmp    L12
```

assistant: ```c
int conver(int octal) {
  int decimal = 0;
  int i = 0;
  while (octal != 0) {
    decimal = decimal + (octal % 10) * pow(8, i++);
    octal = octal / 10;
  }
  return decimal;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<conver>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L12
  mov    %edi,%ebx
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebp,%esi
  mov    $0x8,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %ebx,%edx
  mov    %eax,%r8d
  movslq %ebx,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %r8d,%ebx
  add    %ebx,%r12d
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L3
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int conver(int octal) {
  int decimal = 0;
  int i = 0;
  while (octal != 0) {
    decimal = decimal + (octal % 10) * pow(8, i++);
    octal = octal / 10;
  }
  return decimal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<conver>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L10
  mov    %edi,%ebx
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebp,%esi
  mov    $0x8,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %ebx,%edx
  mov    %eax,%r8d
  movslq %ebx,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %r8d,%ebx
  add    %ebx,%r12d
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L11
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int conver(int octal) {
  int decimal = 0;
  int i = 0;
  while (octal != 0) {
    decimal = decimal + (octal % 10) * pow(8, i++);
    octal = octal / 10;
  }
  return decimal;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L50
L6:
  lea    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  cqto
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L9
  mov    -0x18(%rbp),%rax
  cqto
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L9
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L50
L9:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D29
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D38
data_type: string
name: read_data
arguments: tag: D25
data_type: string

tool: D29: %lld

tool: D39: %lld%lld

tool: D38: No


tool: D25: Yes


assistant: ```c
int main(void) {
  long long t, m, n;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld%lld", &n, &m);
    if (n % 2 == 1 && m % 2 == 1)
      printf("No\n");
    else
      printf("Yes\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  test   %rax,%rax
  je     L13
  lea    0x8(%rsp),%rbp
  lea    D7(%rip),%rbx
  lea    D30(%rip),%r12
  lea    D0(%rip),%r13
  jmp    L35
L20:
  mov    %r12,%rdi
  call   <printf@plt>
L68:
  mov    (%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  test   %rax,%rax
  je     L13
L35:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L20
  mov    0x8(%rsp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L20
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L68
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D30
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D10: %lld

tool: D7: %lld%lld

tool: D30: Yes


tool: D0: No


assistant: ```c
int main(void) {
  long long t, m, n;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld%lld", &n, &m);
    if (n % 2 == 1 && m % 2 == 1)
      printf("No\n");
    else
      printf("Yes\n");
  }
  return 0;
}
```