ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vtclock_print_blank_version_of_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wclear@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mvwin@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <waddch@plt>
  jmp    L22
L14:
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <waddch@plt>
L22:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void vtclock_print_blank_version_of_string(WINDOW *win, int y, int x, char *str) {
  char *p;
  wclear(win);
  mvwin(win, y, x);
  for (p = str; *p; ++p) {
    if (iscntrl(*p)) {
      waddch(win, *p);
    } else {
      waddch(win, ' ');
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<vtclock_print_blank_version_of_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %rcx,%rbx
  call   <wclear@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mvwin@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <waddch@plt>
L3:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L23
L16:
  movsbl %dil,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  je     L20
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <waddch@plt>
  jmp    L3
```

assistant: ```c
void vtclock_print_blank_version_of_string(WINDOW *win, int y, int x, char *str) {
  char *p;
  wclear(win);
  mvwin(win, y, x);
  for (p = str; *p; ++p) {
    if (iscntrl(*p)) {
      waddch(win, *p);
    } else {
      waddch(win, ' ');
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vtclock_print_blank_version_of_string>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <wclear@plt>
  mov    %rbp,%rdi
  mov    %r13d,%edx
  mov    %r12d,%esi
  call   <mvwin@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L12:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <waddch@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L23
L2:
  call   <iscntrl@plt>
  test   %rax,%rax
  jne    L12
  mov    %rbp,%rdi
  mov    $0x20,%esi
  add    $0x1,%rbx
  call   <waddch@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void vtclock_print_blank_version_of_string(WINDOW *win, int y, int x, char *str) {
  char *p;
  wclear(win);
  mvwin(win, y, x);
  for (p = str; *p; ++p) {
    if (iscntrl(*p)) {
      waddch(win, *p);
    } else {
      waddch(win, ' ');
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vtclock_print_blank_version_of_string>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <wclear@plt>
  mov    %rbp,%rdi
  mov    %r13d,%edx
  mov    %r12d,%esi
  call   <mvwin@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L29
  nopl   (%rax)
L20:
  call   <iscntrl@plt>
  mov    $0x20,%esi
  test   %rax,%rax
  je     L4
  movsbl (%rbx),%esi
L4:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <waddch@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L20
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void vtclock_print_blank_version_of_string(WINDOW *win, int y, int x, char *str) {
  char *p;
  wclear(win);
  mvwin(win, y, x);
  for (p = str; *p; ++p) {
    if (iscntrl(*p)) {
      waddch(win, *p);
    } else {
      waddch(win, ' ');
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<split_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x438(%rbp),%rax
  mov    %rax,-0x418(%rbp)
  movl   $0x0,-0x420(%rbp)
  movb   $0x2c,-0x421(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L21
L17:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x421(%rbp)
  je     L29
  mov    -0x41c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x41c(%rbp)
  mov    -0x418(%rbp),%rdx
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0x410(%rbp,%rax,1)
  jmp    L16
L29:
  mov    -0x41c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x41c(%rbp)
  cltq
  movb   $0x0,-0x410(%rbp,%rax,1)
  mov    -0x41c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x420(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x440(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x420(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x440(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x41c(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x41c(%rbp)
  addl   $0x1,-0x420(%rbp)
L16:
  addq   $0x1,-0x418(%rbp)
L21:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x41c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x41c(%rbp)
  cltq
  movb   $0x0,-0x410(%rbp,%rax,1)
  mov    -0x41c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x420(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x440(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x420(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x420(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x440(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x41c(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x420(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
int split_up(char *string, char *argv[]) {
  char *p = string;
  int argc = 0;
  char delimer = ',';
  int count = 0;
  char tmp[1024];
  while (*p != '\0') {
    if (*p != delimer) {
      tmp[count++] = *p;
    } else {
      tmp[count++] = '\0';
      argv[argc] = (char *)malloc(sizeof(char) * count);
      memcpy(argv[argc], tmp, count);
      count = 0;
      argc++;
    }
    p++;
  }
  tmp[count++] = '\0';
  argv[argc] = (char *)malloc(sizeof(char) * count);
  memcpy(argv[argc++], tmp, count);
  return argc;
}
```
user: What is the c source code of the assembly code below?

```asm
<split_up>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L57
  mov    %rdi,%rbx
  mov    $0x0,%edx
  mov    $0x0,%ebp
  mov    %rsp,%r13
  jmp    L28
L3:
  lea    0x1(%rdx),%r14d
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movslq %ebp,%rax
  mov    %rdi,(%r12,%rax,8)
  mov    %r14d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    $0x1,%ebp
  mov    $0x0,%edx
L32:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L47
L28:
  cmp    $0x2c,%al
  je     L3
  movslq %edx,%rcx
  mov    %al,(%rsp,%rcx,1)
  lea    0x1(%rdx),%edx
  jmp    L32
L57:
  mov    $0x0,%edx
  mov    $0x0,%ebp
L47:
  lea    0x1(%rdx),%ebx
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movslq %ebp,%rax
  mov    %rdi,(%r12,%rax,8)
  mov    %rsp,%rsi
  mov    %ebx,%edx
  call   <memcpy@plt>
  lea    0x1(%rbp),%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int split_up(char *string, char *argv[]) {
  char *p = string;
  int argc = 0;
  char delimer = ',';
  int count = 0;
  char tmp[1024];
  while (*p != '\0') {
    if (*p != delimer) {
      tmp[count++] = *p;
    } else {
      tmp[count++] = '\0';
      argv[argc] = (char *)malloc(sizeof(char) * count);
      memcpy(argv[argc], tmp, count);
      count = 0;
      argc++;
    }
    p++;
  }
  tmp[count++] = '\0';
  argv[argc] = (char *)malloc(sizeof(char) * count);
  memcpy(argv[argc++], tmp, count);
  return argc;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<split_up>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x418,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %dl,%dl
  je     L13
  mov    %rdi,%r12
  xor    %r15d,%r15d
  mov    %rsp,%rbp
  jmp    L58
  nopl   0x0(%rax)
L0:
  movslq %eax,%rcx
  add    $0x1,%r12
  lea    0x2(%rax),%r13d
  movslq %r14d,%rax
  mov    %dl,(%rsp,%rcx,1)
  movzbl (%r12),%edx
  test   %dl,%dl
  je     L46
L58:
  lea    0x1(%rax),%r14d
  cmp    $0x2c,%dl
  jne    L0
  cltq
  mov    %r14d,%edi
  lea    0x1(%r15),%r13d
  add    $0x1,%r12
  movb   $0x0,(%rsp,%rax,1)
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,(%rbx,%r15,8)
  mov    %rax,%rdi
  movslq %r13d,%r15
  mov    $0x1,%r13d
  call   <memcpy@plt>
  movzbl (%r12),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L58
L46:
  movslq %r15d,%rdx
  add    $0x1,%r15d
  lea    (%rbx,%rdx,8),%rbx
L42:
  mov    %r13d,%edi
  movb   $0x0,(%rsp,%rax,1)
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x418,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%r15d
  mov    $0x1,%r13d
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L42
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int split_up(char *string, char *argv[]) {
  char *p = string;
  int argc = 0;
  char delimer = ',';
  int count = 0;
  char tmp[1024];
  while (*p != '\0') {
    if (*p != delimer) {
      tmp[count++] = *p;
    } else {
      tmp[count++] = '\0';
      argv[argc] = (char *)malloc(sizeof(char) * count);
      memcpy(argv[argc], tmp, count);
      count = 0;
      argc++;
    }
    p++;
  }
  tmp[count++] = '\0';
  argv[argc] = (char *)malloc(sizeof(char) * count);
  memcpy(argv[argc++], tmp, count);
  return argc;
}
```
user: What is the c source code of the assembly code below?

```asm
<split_up>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  mov    %rdi,%r13
  xor    %edx,%edx
  xor    %r15d,%r15d
  mov    %rsp,%rbp
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L20:
  movslq %edx,%rcx
  add    $0x1,%r13
  lea    0x2(%rdx),%r12d
  mov    %al,(%rsp,%rcx,1)
  movzbl 0x0(%r13),%eax
  test   %al,%al
  je     L57
L43:
  movslq %r14d,%rdx
L53:
  lea    0x1(%rdx),%r14d
  cmp    $0x2c,%al
  jne    L20
  mov    %r14d,%edi
  movb   $0x0,(%rsp,%rdx,1)
  add    $0x1,%r13
  lea    0x1(%r15),%r12d
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,(%rbx,%r15,8)
  mov    %rax,%rdi
  call   <memcpy@plt>
  movzbl 0x0(%r13),%eax
  test   %al,%al
  je     L61
  movslq %r12d,%r15
  xor    %r14d,%r14d
  jmp    L43
  nopl   0x0(%rax)
L61:
  mov    %r12d,%r15d
  xor    %r14d,%r14d
  mov    $0x1,%r12d
L57:
  movslq %r15d,%rax
  add    $0x1,%r15d
  lea    (%rbx,%rax,8),%rbx
L55:
  mov    %r12d,%edi
  movslq %r14d,%r14
  movb   $0x0,(%rsp,%r14,1)
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x418,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%r15d
  mov    $0x1,%r12d
  xor    %r14d,%r14d
  mov    %rsp,%rbp
  jmp    L55
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int split_up(char *string, char *argv[]) {
  char *p = string;
  int argc = 0;
  char delimer = ',';
  int count = 0;
  char tmp[1024];
  while (*p != '\0') {
    if (*p != delimer) {
      tmp[count++] = *p;
    } else {
      tmp[count++] = '\0';
      argv[argc] = (char *)malloc(sizeof(char) * count);
      memcpy(argv[argc], tmp, count);
      count = 0;
      argc++;
    }
    p++;
  }
  tmp[count++] = '\0';
  argv[argc] = (char *)malloc(sizeof(char) * count);
  memcpy(argv[argc++], tmp, count);
  return argc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_branch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L40:
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L11
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L11:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L40
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_branch(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (A[j]) {
        res = j;
      }
    }
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_branch>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    %esi,%r8d
  test   %edx,%edx
  jg     L15
L32:
  mov    %ecx,%eax
  ret
L17:
  cmpl   $0x0,(%rdi,%rax,4)
  cmovne %eax,%ecx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L17
L19:
  add    $0x1,%r9d
  cmp    %r9d,%edx
  je     L32
L15:
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L17
  jmp    L19
```

assistant: ```c
int test_branch(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (A[j]) {
        res = j;
      }
    }
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_branch>:
  endbr64
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  movslq %esi,%rcx
  test   %edx,%edx
  jle    L8
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  test   %esi,%esi
  jle    L35
  xchg   %ax,%ax
L4:
  mov    (%rdi,%rax,4),%r10d
  test   %r10d,%r10d
  cmovne %eax,%r8d
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L4
L35:
  add    $0x1,%r9d
  cmp    %r9d,%edx
  jne    L26
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int test_branch(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (A[j]) {
        res = j;
      }
    }
  }
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_branch>:
  endbr64
  test   %edx,%edx
  jle    L83
  mov    %esi,%eax
  mov    %esi,%r11d
  movdqa D9(%rip),%xmm5
  push   %rbp
  shr    $0x2,%eax
  push   %rbx
  mov    %rdi,%r9
  mov    %edx,%ebx
  sub    $0x1,%eax
  mov    %esi,%ecx
  lea    -0x1(%rsi),%ebp
  and    $0xfffffffc,%r11d
  shl    $0x4,%rax
  pcmpeqd %xmm6,%xmm6
  pxor   %xmm4,%xmm4
  xor    %r8d,%r8d
  lea    0x10(%rdi,%rax,1),%rdx
  xor    %edi,%edi
  nopl   (%rax)
L6:
  test   %ecx,%ecx
  jle    L36
  cmp    $0x2,%ebp
  jbe    L26
  movdqa D16(%rip),%xmm2
  mov    %r9,%rax
  movdqa %xmm6,%xmm1
  nopl   0x0(%rax,%rax,1)
L48:
  movdqu (%rax),%xmm0
  movdqa %xmm2,%xmm3
  add    $0x10,%rax
  paddd  %xmm5,%xmm2
  pcmpeqd %xmm4,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm3,%xmm0
  por    %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L48
  movdqa %xmm1,%xmm2
  psrldq $0x8,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    $0xffffffff,%eax
  cmovne %eax,%r8d
  mov    %r11d,%eax
  cmp    %r11d,%ecx
  je     L36
L55:
  movslq %eax,%rsi
  lea    0x0(,%rsi,4),%r10
  mov    (%r9,%rsi,4),%esi
  test   %esi,%esi
  lea    0x1(%rax),%esi
  cmovne %eax,%r8d
  cmp    %ecx,%esi
  jge    L36
  cmpl   $0x0,0x4(%r9,%r10,1)
  cmove  %r8d,%esi
  lea    0x2(%rax),%r8d
  cmp    %ecx,%r8d
  jge    L67
  mov    0x8(%r9,%r10,1),%eax
  test   %eax,%eax
  cmove  %esi,%r8d
L36:
  add    $0x1,%edi
  cmp    %edi,%ebx
  jne    L6
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L26:
  xor    %eax,%eax
  jmp    L55
L67:
  mov    %esi,%r8d
  jmp    L36
L83:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: byte[16]
name: parse_data
arguments: tag: D16
type: byte[16]

tool: {"D9": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int test_branch(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (A[j]) {
        res = j;
      }
    }
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<up_and_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x4(%rbp),%rdx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cmp    $0x3,%eax
  jg     L3
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <up_and_down>
L3:
  mov    -0x4(%rbp),%eax
  lea    -0x4(%rbp),%rdx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string

tool: D3: Level %d: n location %#x


tool: D6: Level %d: n location %#p


assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %#x\n", n, &n);
  if (n < 4)
    up_and_down(n + 1);
  printf("Level %d: n location %#p\n", n, &n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<up_and_down>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edi
  cmp    $0x3,%edi
  jle    L18
L10:
  lea    0xc(%rsp),%rdx
  mov    0xc(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  ret
L18:
  add    $0x1,%edi
  call   <up_and_down>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D11: Level %d: n location %#x


tool: D3: Level %d: n location %#p


assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %#x\n", n, &n);
  if (n < 4)
    up_and_down(n + 1);
  printf("Level %d: n location %#p\n", n, &n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<up_and_down>:
  endbr64
  push   %r15
  mov    %edi,%esi
  push   %r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  lea    D13(%rip),%rbp
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%r12
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0x3,%esi
  jle    L49
L27:
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L49:
  lea    0x10(%rsp),%r14
  add    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r14,%rdx
  mov    %esi,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  cmp    $0x3,%esi
  jle    L69
L51:
  mov    %r14,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  jmp    L27
  nopl   (%rax)
L69:
  lea    0x14(%rsp),%r15
  add    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r15,%rdx
  mov    %esi,0x14(%rsp)
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  cmp    $0x3,%esi
  jle    L42
L29:
  lea    D13(%rip),%rbp
  mov    %r15,%rdx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  jmp    L51
  nopl   0x0(%rax)
L42:
  lea    0x1(%rsi),%edi
  call   <up_and_down>
  mov    0x14(%rsp),%esi
  jmp    L29
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D29: Level %d: n location %#x


tool: D13: Level %d: n location %#p


assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %#x\n", n, &n);
  if (n < 4)
    up_and_down(n + 1);
  printf("Level %d: n location %#p\n", n, &n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<up_and_down>:
  endbr64
  push   %r15
  mov    %edi,%esi
  push   %r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%r12
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0x3,%esi
  jle    L14
L15:
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L14:
  lea    0x10(%rsp),%r14
  add    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r14,%rdx
  mov    %esi,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  cmp    $0x3,%esi
  jle    L37
L19:
  mov    %r14,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  jmp    L15
  nopl   (%rax)
L37:
  lea    0x14(%rsp),%r15
  add    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r15,%rdx
  mov    %esi,0x14(%rsp)
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  cmp    $0x3,%esi
  jle    L56
L39:
  lea    D12(%rip),%rbp
  mov    %r15,%rdx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  jmp    L19
  nopl   0x0(%rax)
L56:
  lea    0x1(%rsi),%edi
  call   <up_and_down>
  mov    0x14(%rsp),%esi
  jmp    L39
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string

tool: D14: Level %d: n location %#x


tool: D12: Level %d: n location %#p


assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %#x\n", n, &n);
  if (n < 4)
    up_and_down(n + 1);
  printf("Level %d: n location %#p\n", n, &n);
}
```