ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<doubles_2d_scalar_add>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  jle    L7
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %ecx,%r12d
  mov    %r8,%r15
  movslq %edx,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L10:
  mov    (%r15,%rbx,8),%rcx
  mov    (%r14,%rbx,8),%rsi
  mov    %r12d,%edx
  mov    0x0(%r13,%rbx,8),%rdi
  movsd  0x8(%rsp),%xmm0
  add    $0x1,%rbx
  call   <doubles_scalar_add@plt>
  cmp    %rbx,%rbp
  jne    L10
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void doubles_2d_scalar_add(double **tdarr1, double **tdarr2, int rows, int cols, double alpha, double **res_tdarr) {
  int i;
  for (i = 0; i < rows; i++)
    doubles_scalar_add(tdarr1[i], tdarr2[i], cols, alpha, res_tdarr[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<doubles_2d_scalar_add>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  jle    L17
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %ecx,%r12d
  mov    %r8,%r15
  movslq %edx,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L10:
  mov    (%r15,%rbx,8),%rcx
  mov    (%r14,%rbx,8),%rsi
  mov    %r12d,%edx
  mov    0x0(%r13,%rbx,8),%rdi
  movsd  0x8(%rsp),%xmm0
  add    $0x1,%rbx
  call   <doubles_scalar_add@plt>
  cmp    %rbx,%rbp
  jne    L10
L17:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void doubles_2d_scalar_add(double **tdarr1, double **tdarr2, int rows, int cols, double alpha, double **res_tdarr) {
  int i;
  for (i = 0; i < rows; i++)
    doubles_scalar_add(tdarr1[i], tdarr2[i], cols, alpha, res_tdarr[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getche>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putch@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getche() {
  int c = getch();
  putch(c);
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getche>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <putch@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getche() {
  int c = getch();
  putch(c);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getche>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <putch@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int getche() {
  int c = getch();
  putch(c);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getche>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <putch@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int getche() {
  int c = getch();
  putch(c);
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<oss_pcm_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf_verbose@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: oss_pcm_open(...) = BLOCKED;

assistant: ```c
int oss_pcm_open(void) {
  printf_verbose("oss_pcm_open(...) = BLOCKED;");
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<oss_pcm_open>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf_verbose@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: oss_pcm_open(...) = BLOCKED;

assistant: ```c
int oss_pcm_open(void) {
  printf_verbose("oss_pcm_open(...) = BLOCKED;");
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<oss_pcm_open>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf_verbose@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: oss_pcm_open(...) = BLOCKED;

assistant: ```c
int oss_pcm_open(void) {
  printf_verbose("oss_pcm_open(...) = BLOCKED;");
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<oss_pcm_open>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf_verbose@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: oss_pcm_open(...) = BLOCKED;

assistant: ```c
int oss_pcm_open(void) {
  printf_verbose("oss_pcm_open(...) = BLOCKED;");
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<ace_tu_fs_append_str_to_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: a

assistant: ```c
void ace_tu_fs_append_str_to_file(char *path, char *str) {
  FILE *file = fopen(path, "a");
  fputs(str, file);
  fclose(file);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ace_tu_fs_append_str_to_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <fputs@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: a

assistant: ```c
void ace_tu_fs_append_str_to_file(char *path, char *str) {
  FILE *file = fopen(path, "a");
  fputs(str, file);
  fclose(file);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ace_tu_fs_append_str_to_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D8(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <fputs@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: a

assistant: ```c
void ace_tu_fs_append_str_to_file(char *path, char *str) {
  FILE *file = fopen(path, "a");
  fputs(str, file);
  fclose(file);
}
```
user: What is the c source code of the assembly code below?

```asm
<ace_tu_fs_append_str_to_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D9(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <fputs@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: a

assistant: ```c
void ace_tu_fs_append_str_to_file(char *path, char *str) {
  FILE *file = fopen(path, "a");
  fputs(str, file);
  fclose(file);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rapl_get_cpu_model>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rapl_get_cpu_id@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  shl    $0x4,%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int rapl_get_cpu_model() {
  unsigned int eax;
  eax = rapl_get_cpu_id();
  return (((eax >> 16) & 0xF) << 4) + ((eax >> 4) & 0xF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rapl_get_cpu_model>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rapl_get_cpu_id@plt>
  mov    %eax,%edx
  shr    $0xc,%edx
  and    $0xf0,%edx
  shr    $0x4,%eax
  and    $0xf,%eax
  add    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rapl_get_cpu_model() {
  unsigned int eax;
  eax = rapl_get_cpu_id();
  return (((eax >> 16) & 0xF) << 4) + ((eax >> 4) & 0xF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rapl_get_cpu_model>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rapl_get_cpu_id@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  shr    $0x4,%eax
  shr    $0xc,%edx
  and    $0xf,%eax
  and    $0xf0,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int rapl_get_cpu_model() {
  unsigned int eax;
  eax = rapl_get_cpu_id();
  return (((eax >> 16) & 0xF) << 4) + ((eax >> 4) & 0xF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rapl_get_cpu_model>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rapl_get_cpu_id@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  shr    $0x4,%eax
  shr    $0xc,%edx
  and    $0xf,%eax
  and    $0xf0,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int rapl_get_cpu_model() {
  unsigned int eax;
  eax = rapl_get_cpu_id();
  return (((eax >> 16) & 0xF) << 4) + ((eax >> 4) & 0xF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L15
L7:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  imul   %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  addq   $0x2,-0x18(%rbp)
L15:
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  movq   $0x0,-0x18(%rbp)
  jmp    L14
L40:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  addq   $0x1,-0x18(%rbp)
L14:
  cmpq   $0x0,-0x18(%rbp)
  je     L40
  mov    -0x10(%rbp),%rax
  imul   $0x5746902f,%rax,%rax
  movabs $0x66c4aa81a6cf248,%rdx
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] + 316086328UL) * 1464242223UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  imul   %rax,%rax
  movabs $0x15d1a40bc,%rdx
  imul   %rdx,%rax
  movabs $0x66c4aa81a6cf248,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] + 316086328UL) * 1464242223UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movabs $0x15d1a40bc,%rdx
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  imul   %rax,%rax
  imul   %rdx,%rax
  movabs $0x66c4aa81a6cf248,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] + 316086328UL) * 1464242223UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movabs $0x15d1a40bc,%rdx
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  imul   %rax,%rax
  imul   %rdx,%rax
  movabs $0x66c4aa81a6cf248,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] + 316086328UL) * 1464242223UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L8:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strhash(x)
char *x;
{
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strhash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  mov    $0x0,%eax
L10:
  lea    (%rax,%rax,2),%ecx
  lea    (%rax,%rcx,4),%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strhash(x)
char *x;
{
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strhash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L6
  nopl   (%rax)
L1:
  lea    (%rax,%rax,2),%ecx
  add    $0x1,%rdi
  lea    (%rax,%rcx,4),%eax
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L1
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
int strhash(x)
char *x;
{
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strhash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L16
  nopl   (%rax)
L10:
  lea    (%rax,%rax,2),%ecx
  add    $0x1,%rdi
  lea    (%rax,%rcx,4),%eax
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  ret
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
int strhash(x)
char *x;
{
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_realpath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_realpath@plt>
  leave
  ret
```

assistant: ```c
char *my_realpath(const char *path1, char path2[], int decomp) {
  strcpy(path2, path1);
  return _realpath(path2, decomp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_realpath>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_realpath@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *my_realpath(const char *path1, char path2[], int decomp) {
  strcpy(path2, path1);
  return _realpath(path2, decomp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_realpath>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <_realpath@plt>
```

assistant: ```c
char *my_realpath(const char *path1, char path2[], int decomp) {
  strcpy(path2, path1);
  return _realpath(path2, decomp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_realpath>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <_realpath@plt>
```

assistant: ```c
char *my_realpath(const char *path1, char path2[], int decomp) {
  strcpy(path2, path1);
  return _realpath(path2, decomp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put_unaligned_le32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <__put_unaligned_le16@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <__put_unaligned_le16@plt>
  nop
  leave
  ret
```

assistant: ```c
void put_unaligned_le32(uint32_t val, uint8_t *p) {
  __put_unaligned_le16(val >> 16, p + 2);
  __put_unaligned_le16(val, p);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<put_unaligned_le32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    0x8(%rsi),%rsi
  sar    $0x10,%edi
  call   <__put_unaligned_le16@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <__put_unaligned_le16@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void put_unaligned_le32(uint32_t val, uint8_t *p) {
  __put_unaligned_le16(val >> 16, p + 2);
  __put_unaligned_le16(val, p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<put_unaligned_le32>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    0x8(%rsi),%rsi
  push   %rbp
  mov    %edi,%ebp
  sar    $0x10,%edi
  sub    $0x8,%rsp
  call   <__put_unaligned_le16@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <__put_unaligned_le16@plt>
```

assistant: ```c
void put_unaligned_le32(uint32_t val, uint8_t *p) {
  __put_unaligned_le16(val >> 16, p + 2);
  __put_unaligned_le16(val, p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<put_unaligned_le32>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    0x8(%rsi),%rsi
  push   %rbp
  mov    %edi,%ebp
  sar    $0x10,%edi
  sub    $0x8,%rsp
  call   <__put_unaligned_le16@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <__put_unaligned_le16@plt>
```

assistant: ```c
void put_unaligned_le32(uint32_t val, uint8_t *p) {
  __put_unaligned_le16(val >> 16, p + 2);
  __put_unaligned_le16(val, p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort_dirs_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L6
  mov    $0xffffffff,%eax
  jmp    L20
L6:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L13
  mov    $0x1,%eax
  jmp    L20
L13:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcoll@plt>
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: string

tool: D14: ../

assistant: ```c
int sort_dirs_func(const void *a, const void *b) {
  char *sa = *(char **)a;
  char *sb = *(char **)b;
  if (!strcmp(sa, "../"))
    return -1;
  if (!strcmp(sb, "../"))
    return 1;
  return strcoll(sa, sb);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_dirs_func>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    (%rsi),%rbp
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L39
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L34
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcoll@plt>
  jmp    L12
L39:
  mov    $0xffffffff,%eax
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D15: ../

assistant: ```c
int sort_dirs_func(const void *a, const void *b) {
  char *sa = *(char **)a;
  char *sb = *(char **)b;
  if (!strcmp(sa, "../"))
    return -1;
  if (!strcmp(sb, "../"))
    return 1;
  return strcoll(sa, sb);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sort_dirs_func>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    (%rdi),%r12
  lea    D4(%rip),%rbp
  mov    (%rsi),%r13
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L6
L29:
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  pop    %rbp
  mov    %r13,%rsi
  mov    %r12,%rdi
  pop    %r12
  pop    %r13
  jmp    1070 <strcoll@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%r8d
  jmp    L29
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: ../

assistant: ```c
int sort_dirs_func(const void *a, const void *b) {
  char *sa = *(char **)a;
  char *sb = *(char **)b;
  if (!strcmp(sa, "../"))
    return -1;
  if (!strcmp(sb, "../"))
    return 1;
  return strcoll(sa, sb);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort_dirs_func>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    (%rdi),%r12
  lea    D2(%rip),%rbp
  mov    (%rsi),%r13
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L18
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L3
L26:
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  pop    %rbp
  mov    %r13,%rsi
  mov    %r12,%rdi
  pop    %r12
  pop    %r13
  jmp    1070 <strcoll@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%r8d
  jmp    L26
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: ../

assistant: ```c
int sort_dirs_func(const void *a, const void *b) {
  char *sa = *(char **)a;
  char *sb = *(char **)b;
  if (!strcmp(sa, "../"))
    return -1;
  if (!strcmp(sb, "../"))
    return 1;
  return strcoll(sa, sb);
}
```