ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<harbol_unilist_new_from_vector>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <harbol_unilist_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <harbol_unilist_from_vector@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct HarbolUniList *harbol_unilist_new_from_vector(const struct HarbolVector *const v) {
  if (!v)
    return NULL;
  struct HarbolUniList *const unilist = harbol_unilist_new();
  harbol_unilist_from_vector(unilist, v);
  return unilist;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<harbol_unilist_new_from_vector>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L3
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <harbol_unilist_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <harbol_unilist_from_vector@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct HarbolUniList *harbol_unilist_new_from_vector(const struct HarbolVector *const v) {
  if (!v)
    return NULL;
  struct HarbolUniList *const unilist = harbol_unilist_new();
  harbol_unilist_from_vector(unilist, v);
  return unilist;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<safecpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  jmp    L36
L39:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rsi
  mov    -0x8(%rbp),%rcx
  mov    %rsi,(%rcx)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L39
L22:
  cmpl   $0x0,-0x1c(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void safecpy(char **dest, int *len, const char *source, bool terminate) {
  while (*source && *len) {
    *(*dest)++ = *source++;
    (*len)--;
  }
  if (terminate && *len) {
    *(*dest)++ = 0;
    (*len)--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<safecpy>:
  endbr64
  cmpb   $0x0,(%rdx)
  je     L18
L21:
  cmpl   $0x0,(%rsi)
  je     L10
  add    $0x1,%rdx
  mov    (%rdi),%rax
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rax)
  subl   $0x1,(%rsi)
  cmpb   $0x0,(%rdx)
  jne    L21
L18:
  test   %ecx,%ecx
  je     L29
  cmpl   $0x0,(%rsi)
  je     L29
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0x0,(%rax)
  subl   $0x1,(%rsi)
L29:
  ret
L10:
  ret
```

assistant: ```c
void safecpy(char **dest, int *len, const char *source, bool terminate) {
  while (*source && *len) {
    *(*dest)++ = *source++;
    (*len)--;
  }
  if (terminate && *len) {
    *(*dest)++ = 0;
    (*len)--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<safecpy>:
  endbr64
  cmpb   $0x0,(%rdx)
  je     L31
  mov    (%rsi),%eax
  jmp    L55
  nopl   (%rax)
L14:
  mov    (%rdi),%rax
  add    $0x1,%rdx
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rax)
  mov    (%rsi),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  cmpb   $0x0,(%rdx)
  je     L31
L55:
  test   %eax,%eax
  jne    L14
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  test   %ecx,%ecx
  je     L18
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L18
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0x0,(%rax)
  subl   $0x1,(%rsi)
L18:
  ret
```

assistant: ```c
void safecpy(char **dest, int *len, const char *source, bool terminate) {
  while (*source && *len) {
    *(*dest)++ = *source++;
    (*len)--;
  }
  if (terminate && *len) {
    *(*dest)++ = 0;
    (*len)--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<safecpy>:
  endbr64
  cmpb   $0x0,(%rdx)
  je     L19
  mov    (%rsi),%eax
  jmp    L17
  nopl   (%rax)
L34:
  mov    (%rdi),%rax
  add    $0x1,%rdx
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rax)
  mov    (%rsi),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  cmpb   $0x0,(%rdx)
  je     L19
L17:
  test   %eax,%eax
  jne    L34
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  test   %ecx,%ecx
  je     L48
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L48
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0x0,(%rax)
  subl   $0x1,(%rsi)
L48:
  ret
```

assistant: ```c
void safecpy(char **dest, int *len, const char *source, bool terminate) {
  while (*source && *len) {
    *(*dest)++ = *source++;
    (*len)--;
  }
  if (terminate && *len) {
    *(*dest)++ = 0;
    (*len)--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  cmp    %eax,%edx
  jge    L14
  mov    -0x20(%rbp),%rax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  cltq
  cmp    %rax,%rdx
  jbe    L14
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L59:
  mov    -0x8(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L0:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L59
  jmp    L69
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L30:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L22:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L30
L69:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t acount) {
  char *d;
  const char *s;
  if (((int)src < (int)dst) && ((((int)src) + acount) > (int)dst)) {
    d = ((char *)dst) + acount - 1;
    s = ((char *)src) + acount - 1;
    while (acount--)
      *d-- = *s--;
  } else {
    d = dst;
    s = src;
    while (acount--)
      *d++ = *s++;
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %edi,%esi
  jl     L34
L18:
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L41
L56:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L56
L20:
  ret
L41:
  ret
L34:
  movslq %esi,%rcx
  add    %rdx,%rcx
  movslq %edi,%rdi
  cmp    %rdi,%rcx
  jbe    L18
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L20
L11:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L11
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t acount) {
  char *d;
  const char *s;
  if (((int)src < (int)dst) && ((((int)src) + acount) > (int)dst)) {
    d = ((char *)dst) + acount - 1;
    s = ((char *)src) + acount - 1;
    while (acount--)
      *d-- = *s--;
  } else {
    d = dst;
    s = src;
    while (acount--)
      *d++ = *s++;
  }
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  lea    -0x1(%rdx),%rax
  cmp    %edi,%esi
  jge    L44
  movslq %esi,%rcx
  movslq %edi,%rdi
  add    %rdx,%rcx
  cmp    %rdi,%rcx
  jbe    L44
  test   %rdx,%rdx
  je     L4
  sub    $0x1,%rsi
  lea    -0x1(%r8),%rcx
  nopw   0x0(%rax,%rax,1)
L41:
  movzbl 0x1(%rsi,%rax,1),%edx
  mov    %dl,0x1(%rcx,%rax,1)
  sub    $0x1,%rax
  jae    L41
L4:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L4
  nop
L26:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t acount) {
  char *d;
  const char *s;
  if (((int)src < (int)dst) && ((((int)src) + acount) > (int)dst)) {
    d = ((char *)dst) + acount - 1;
    s = ((char *)src) + acount - 1;
    while (acount--)
      *d-- = *s--;
  } else {
    d = dst;
    s = src;
    while (acount--)
      *d++ = *s++;
  }
  return dst;
}
```
user: What is the c source code of the assembly code below:

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rax
  cmp    %edi,%esi
  jge    L172
  movslq %esi,%rdx
  movslq %edi,%rdi
  add    %rcx,%rdx
  cmp    %rdi,%rdx
  ja     L114
L172:
  test   %rcx,%rcx
  je     L167
  lea    0x1(%rsi),%rdi
  mov    %r8,%rdx
  sub    %rdi,%rdx
  cmp    $0xe,%rdx
  jbe    L140
  cmp    $0x6,%rax
  jbe    L140
  cmp    $0xe,%rax
  jbe    L21
  mov    %rcx,%rdi
  xor    %edx,%edx
  and    $0xfffffffffffffff0,%rdi
  xchg   %ax,%ax
L50:
  movdqu (%rsi,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdi,%rdx
  jne    L50
  mov    %rcx,%rdx
  and    $0xfffffffffffffff0,%rdx
  lea    (%r8,%rdx,1),%rdi
  lea    (%rsi,%rdx,1),%r9
  sub    %rdx,%rax
  cmp    %rdx,%rcx
  je     L167
  sub    %rdx,%rcx
  lea    -0x1(%rcx),%r10
  cmp    $0x6,%r10
  jbe    L141
L186:
  mov    (%rsi,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %rcx,%rdx
  and    $0xfffffffffffffff8,%rdx
  add    %rdx,%rdi
  add    %rdx,%r9
  sub    %rdx,%rax
  cmp    %rdx,%rcx
  je     L167
L141:
  movzbl (%r9),%edx
  mov    %dl,(%rdi)
  test   %rax,%rax
  je     L167
  movzbl 0x1(%r9),%edx
  mov    %dl,0x1(%rdi)
  cmp    $0x1,%rax
  je     L167
  movzbl 0x2(%r9),%edx
  mov    %dl,0x2(%rdi)
  cmp    $0x2,%rax
  je     L167
  movzbl 0x3(%r9),%edx
  mov    %dl,0x3(%rdi)
  cmp    $0x3,%rax
  je     L167
  movzbl 0x4(%r9),%edx
  mov    %dl,0x4(%rdi)
  cmp    $0x4,%rax
  je     L167
  movzbl 0x5(%r9),%edx
  mov    %dl,0x5(%rdi)
  cmp    $0x5,%rax
  je     L167
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdi)
L167:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L114:
  test   %rcx,%rcx
  je     L167
  sub    $0x1,%rsi
  lea    -0x1(%r8),%rcx
  nopl   (%rax)
L144:
  movzbl 0x1(%rsi,%rax,1),%edx
  mov    %dl,0x1(%rcx,%rax,1)
  sub    $0x1,%rax
  jae    L144
  mov    %r8,%rax
  ret
L21:
  mov    %rsi,%r9
  mov    %r8,%rdi
  xor    %edx,%edx
  jmp    L186
  nopl   0x0(%rax,%rax,1)
L140:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L112:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L112
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t acount) {
  char *d;
  const char *s;
  if (((int)src < (int)dst) && ((((int)src) + acount) > (int)dst)) {
    d = ((char *)dst) + acount - 1;
    s = ((char *)src) + acount - 1;
    while (acount--)
      *d-- = *s--;
  } else {
    d = dst;
    s = src;
    while (acount--)
      *d++ = *s++;
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L25
L22:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L5
  addl   $0x1,-0x14(%rbp)
L5:
  addq   $0x1,-0x10(%rbp)
L25:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L22
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int contains(char const *str, char c) {
  int count;
  size_t i;
  size_t len = strlen(str);
  count = 0;
  for (i = 0; i < len; i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<contains>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  test   %rax,%rax
  je     L17
  mov    %rbx,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x0,%eax
L23:
  cmp    %bpl,(%rdx)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L23
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x0,%eax
  jmp    L20
```

assistant: ```c
int contains(char const *str, char c) {
  int count;
  size_t i;
  size_t len = strlen(str);
  count = 0;
  for (i = 0; i < len; i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<contains>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L3
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %edx,%edx
  cmp    %bpl,(%rdi)
  sete   %dl
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int contains(char const *str, char c) {
  int count;
  size_t i;
  size_t len = strlen(str);
  count = 0;
  for (i = 0; i < len; i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0xd18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d08(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%ebx
L30:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x29,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1f40,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,(%rsp,%rbx,1)
  mov    %eax,0x3e80(%rsp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x3e80,%rbx
  jne    L30
  mov    $0xfa0,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x3e80(%rsp),%r12
  mov    %rbx,%rbp
  lea    D40(%rip),%r13
L20:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L20
  mov    %rsp,%rdi
  mov    $0xfa0,%esi
  call   <bubbleSort@plt>
  lea    0x3e80(%rsp),%rdi
  mov    $0xfa0,%esi
  call   <impBsort@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D40(%rip),%rbp
L45:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L45
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x7d08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x7d18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D40
type_infered: string
name: extract_symbolic_data
arguments: tag: D36
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D4: N = %d
Array is:


tool: D40: %d 

tool: D36: 

Sorted Array is: 

tool: D2: 

[Press Enter to close]

assistant: ```c
int main() {
  srand(time(NULL));
  int i, myarray[4000], myarray2[4000];
  int n = 4000;
  for (i = 0; i < n; i++) {
    myarray[i] = (rand() % (n * 2)) + 1;
    myarray2[i] = myarray[i];
  }
  printf("N = %d\nArray is:\n", n);
  for (i = 0; i < n; i++) {
    printf("%d ", myarray[i]);
  }
  bubbleSort(myarray, n);
  impBsort(myarray2, n);
  printf("\n\nSorted Array is: \n");
  for (i = 0; i < n; i++) {
    printf("%d ", myarray[i]);
  }
  printf("\n\n[Press Enter to close]");
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7000(%rsp),%r11
L35:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L35
  sub    $0xd10,%rsp
  xor    %edi,%edi
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x7d08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x3e80(%rsp),%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x29,%rdx
  sub    %ecx,%edx
  imul   $0x1f40,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,0x0(%rbp,%r12,1)
  mov    %eax,(%rbx,%r12,1)
  add    $0x4,%r12
  cmp    $0x3e80,%r12
  jne    L22
  mov    $0xfa0,%esi
  xor    %eax,%eax
  mov    %rbp,%r12
  mov    %rbp,%r13
  lea    D1(%rip),%rdi
  lea    D32(%rip),%r14
  call   <printf@plt>
  nopl   (%rax)
L28:
  mov    0x0(%r13),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L28
  mov    $0xfa0,%esi
  mov    %rbp,%rdi
  call   <bubbleSort@plt>
  mov    %rbx,%rdi
  mov    $0xfa0,%esi
  call   <impBsort@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L47:
  mov    (%r12),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L47
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x7d08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x7d10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string
name: disassemble_data
arguments: data_tag: D32
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D28
type_infered: string

tool: D1: N = %d
Array is:


tool: D32: %d 

tool: D0: 

Sorted Array is: 

tool: D28: 

[Press Enter to close]

assistant: ```c
int main() {
  srand(time(NULL));
  int i, myarray[4000], myarray2[4000];
  int n = 4000;
  for (i = 0; i < n; i++) {
    myarray[i] = (rand() % (n * 2)) + 1;
    myarray2[i] = myarray[i];
  }
  printf("N = %d\nArray is:\n", n);
  for (i = 0; i < n; i++) {
    printf("%d ", myarray[i]);
  }
  bubbleSort(myarray, n);
  impBsort(myarray2, n);
  printf("\n\nSorted Array is: \n");
  for (i = 0; i < n; i++) {
    printf("%d ", myarray[i]);
  }
  printf("\n\n[Press Enter to close]");
  getchar();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0xd10,%rsp
  xor    %edi,%edi
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x7d08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x3e80(%rsp),%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x29,%rdx
  sub    %ecx,%edx
  imul   $0x1f40,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,0x0(%rbp,%r12,1)
  mov    %eax,(%rbx,%r12,1)
  add    $0x4,%r12
  cmp    $0x3e80,%r12
  jne    L17
  mov    $0xfa0,%esi
  xor    %eax,%eax
  mov    %rbp,%r12
  mov    %rbp,%r13
  lea    D32(%rip),%rdi
  lea    D21(%rip),%r14
  call   <printf@plt>
  nopl   (%rax)
L3:
  mov    0x0(%r13),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L3
  mov    $0xfa0,%esi
  mov    %rbp,%rdi
  call   <bubbleSort@plt>
  mov    %rbx,%rdi
  mov    $0xfa0,%esi
  call   <impBsort@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L6:
  mov    (%r12),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L6
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x7d08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x7d10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D32
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D1
datatype: string

tool: D32: N = %d
Array is:


tool: D21: %d 

tool: D17: 

Sorted Array is: 

tool: D1: 

[Press Enter to close]

assistant: ```c
int main() {
  srand(time(NULL));
  int i, myarray[4000], myarray2[4000];
  int n = 4000;
  for (i = 0; i < n; i++) {
    myarray[i] = (rand() % (n * 2)) + 1;
    myarray2[i] = myarray[i];
  }
  printf("N = %d\nArray is:\n", n);
  for (i = 0; i < n; i++) {
    printf("%d ", myarray[i]);
  }
  bubbleSort(myarray, n);
  impBsort(myarray2, n);
  printf("\n\nSorted Array is: \n");
  for (i = 0; i < n; i++) {
    printf("%d ", myarray[i]);
  }
  printf("\n\n[Press Enter to close]");
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<filenameValid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L19
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L15
L19:
  mov    $0x0,%eax
  jmp    L20
L15:
  mov    $0x1,%eax
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: \/:*?"<>|

assistant: ```c
int filenameValid(char const *const aFileNameWithoutPath) {
  if (!aFileNameWithoutPath || !strlen(aFileNameWithoutPath) || strpbrk(aFileNameWithoutPath, "\\/:*?\"<>|")) {
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<filenameValid>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L2
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jne    L17
L10:
  pop    %rbx
  ret
L17:
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L10
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: \/:*?"<>|

assistant: ```c
int filenameValid(char const *const aFileNameWithoutPath) {
  if (!aFileNameWithoutPath || !strlen(aFileNameWithoutPath) || strpbrk(aFileNameWithoutPath, "\\/:*?\"<>|")) {
    return 0;
  }
  return 1;
}
```