ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tan>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L9
  jmp    1050 <_tan_reduce@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  sub    $0x8,%rsp
  movq   D13(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  call   <_tan_reduce@plt>
  movq   D13(%rip),%xmm1
  add    $0x8,%rsp
  xorpd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type: f32[2]

tool: {"D13": [0.0,-0.0]}

assistant: ```c
double tan(double x) {
  if (x < 0.0)
    return -_tan_reduce(-x);
  else
    return _tan_reduce(x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tan>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
  jmp    1050 <_tan_reduce@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x8,%rsp
  movq   D13(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  call   <_tan_reduce@plt>
  movq   D13(%rip),%xmm1
  add    $0x8,%rsp
  xorpd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: f32[2]

tool: {"D13": [0.0,-0.0]}

assistant: ```c
double tan(double x) {
  if (x < 0.0)
    return -_tan_reduce(-x);
  else
    return _tan_reduce(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  lea    D25(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x6b5fca6b,%rdx,%rdx
  sar    $0x36,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x989680,%edx,%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D35(%rip),%xmm0
  movsd  %xmm0,0x0(%rbp,%rbx,1)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D35(%rip),%xmm0
  movsd  %xmm0,(%r12,%rbx,1)
  movq   $0x0,0x0(%r13,%rbx,1)
  add    $0x8,%rbx
  cmp    $0x2faf0800,%rbx
  jne    L4
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
L2:
  movsd  0x0(%rbp,%rax,1),%xmm0
  divsd  (%r12,%rax,1),%xmm0
  movsd  %xmm0,0x0(%r13,%rax,1)
  add    $0x8,%rax
  cmp    $0x2faf0800,%rax
  jne    L2
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %rbx,%xmm1
  subsd  %xmm1,%xmm0
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D35
type_infered: f64
name: retrieve_data
arguments: label: D36
type_infered: string

tool: D25: %lf


tool: D35: 0.01

tool: D36: Vector Division Complete - %lf Seconds


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i = 0;
  double *mainVector = malloc(100000000 * sizeof(double));
  double *divVector = malloc(100000000 * sizeof(double));
  double *solVector = malloc(100000000 * sizeof(double));
  double x = rand();
  printf("%lf\n", x);
  for (i = 0; i < 100000000; i++) {
    mainVector[i] = (rand() % 10000000) * 0.01;
    divVector[i] = (rand() % 1000) * 0.01;
    solVector[i] = 0;
  }
  if (0) {
    for (i = 0; i < 100000000; i++) {
      printf("  %5.2lf %1.2lf\n", mainVector[i], divVector[i]);
    }
  }
  double start = omp_get_wtime();
#pragma omp parallel for shared(mainVector, divVector, solVector) private(i) schedule(static, 10) num_threads(4)
  for (i = 0; i < 100000000; i++) {
    solVector[i] = mainVector[i] / divVector[i];
  }
  double end = omp_get_wtime();
  if (0) {
    for (i = 0; i < 100000000; i++) {
      printf("  %1.2lf\n", solVector[i]);
    }
  }
  double solTime = end - start;
  printf("Vector Division Complete - %lf Seconds\n", solTime);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    $0x2faf0800,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    $0x2faf0800,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  lea    D14(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x6b5fca6b,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x36,%rdx
  sub    %ecx,%edx
  imul   $0x989680,%edx,%edx
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D1(%rip),%xmm0
  xor    %eax,%eax
  movsd  %xmm0,(%rbx,%r13,1)
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D1(%rip),%xmm0
  movsd  %xmm0,0x0(%rbp,%r13,1)
  movq   $0x0,(%r12,%r13,1)
  add    $0x8,%r13
  cmp    $0x2faf0800,%r13
  jne    L13
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  nopl   (%rax)
L8:
  movsd  (%rbx,%rax,1),%xmm0
  divsd  0x0(%rbp,%rax,1),%xmm0
  movsd  %xmm0,(%r12,%rax,1)
  add    $0x8,%rax
  cmp    $0x2faf0800,%rax
  jne    L8
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  subsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D1
datatype: f64
name: retrieve_data
arguments: data_tag: D33
datatype: string

tool: D14: %lf


tool: D1: 0.01

tool: D33: Vector Division Complete - %lf Seconds


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i = 0;
  double *mainVector = malloc(100000000 * sizeof(double));
  double *divVector = malloc(100000000 * sizeof(double));
  double *solVector = malloc(100000000 * sizeof(double));
  double x = rand();
  printf("%lf\n", x);
  for (i = 0; i < 100000000; i++) {
    mainVector[i] = (rand() % 10000000) * 0.01;
    divVector[i] = (rand() % 1000) * 0.01;
    solVector[i] = 0;
  }
  if (0) {
    for (i = 0; i < 100000000; i++) {
      printf("  %5.2lf %1.2lf\n", mainVector[i], divVector[i]);
    }
  }
  double start = omp_get_wtime();
#pragma omp parallel for shared(mainVector, divVector, solVector) private(i) schedule(static, 10) num_threads(4)
  for (i = 0; i < 100000000; i++) {
    solVector[i] = mainVector[i] / divVector[i];
  }
  double end = omp_get_wtime();
  if (0) {
    for (i = 0; i < 100000000; i++) {
      printf("  %1.2lf\n", solVector[i]);
    }
  }
  double solTime = end - start;
  printf("Vector Division Complete - %lf Seconds\n", solTime);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<convertlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  D0(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L23
  movsd  -0x8(%rbp),%xmm0
  movq   D21(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L5
L23:
  movsd  -0x8(%rbp),%xmm0
  comisd D0(%rip),%xmm0
  jbe    L5
  movsd  D24(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L5:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: f64[2]
name: extract_symbolic_data
arguments: label: D21
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D24
datatype: f64

tool: {"D0": [180.0,0.0]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D24: 360

assistant: ```c
double convertlong(longitude)
double longitude;
{
  if (longitude < 180.0)
    longitude = -longitude;
  else if (longitude > 180.0)
    longitude = 360.0 - longitude;
  return longitude;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<convertlong>:
  endbr64
  movsd  D37(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L17
  movapd %xmm0,%xmm1
  xorpd  D14(%rip),%xmm1
L22:
  movapd %xmm1,%xmm0
  ret
L17:
  movapd %xmm0,%xmm1
  comisd D37(%rip),%xmm0
  jbe    L22
  movsd  D4(%rip),%xmm1
  subsd  %xmm0,%xmm1
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: data_label: D37
type: f64[2]
name: retrieve_data
arguments: data_label: D14
type: byte[16]
name: retrieve_data
arguments: data_label: D4
type: f64

tool: {"D37": [180.0,360.0]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D4: 360

assistant: ```c
double convertlong(longitude)
double longitude;
{
  if (longitude < 180.0)
    longitude = -longitude;
  else if (longitude > 180.0)
    longitude = 360.0 - longitude;
  return longitude;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convertlong>:
  endbr64
  movsd  D6(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L11
  movapd %xmm0,%xmm1
  xorpd  D21(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  comisd %xmm1,%xmm0
  jbe    L0
  movsd  D22(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
  nop
L0:
  movapd %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: f64
name: unpack_data
arguments: tag: D21
datatype: byte[16]
name: unpack_data
arguments: tag: D22
datatype: f64

tool: D6: 180

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D22: 360

assistant: ```c
double convertlong(longitude)
double longitude;
{
  if (longitude < 180.0)
    longitude = -longitude;
  else if (longitude > 180.0)
    longitude = 360.0 - longitude;
  return longitude;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convertlong>:
  endbr64
  movsd  D20(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L17
  movapd %xmm0,%xmm1
  xorpd  D18(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  comisd %xmm1,%xmm0
  jbe    L10
  movsd  D2(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
  nop
L10:
  movapd %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D20
type: f64
name: read_data
arguments: label: D18
type: byte[16]
name: read_data
arguments: label: D2
type: f64

tool: D20: 180

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D2: 360

assistant: ```c
double convertlong(longitude)
double longitude;
{
  if (longitude < 180.0)
    longitude = -longitude;
  else if (longitude > 180.0)
    longitude = 360.0 - longitude;
  return longitude;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<EMACIntClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x4045,%eax
  test   %eax,%eax
  je     L3
  orl    $0x10000,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  and    $0x27ba,%eax
  test   %eax,%eax
  je     L16
  orl    $0x8000,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  test   %eax,%eax
  je     L18
  mov    -0x4(%rbp),%eax
  add    $0xc14,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,(%rdx)
L18:
  cmpl   $0x0,-0x8(%rbp)
  jns    L2
  mov    -0x4(%rbp),%eax
  add    $0xfd8,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0xfd8,%edx
  movslq %edx,%rdx
  or     $0x1,%eax
  mov    %eax,(%rdx)
L2:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EMACIntClear>:
  endbr64
  mov    %esi,%eax
  or     $0x10000,%eax
  test   $0x4045,%esi
  cmovne %eax,%esi
  mov    %esi,%eax
  or     $0x80,%ah
  test   $0x27ba,%esi
  cmovne %eax,%esi
  test   $0x7fffffff,%esi
  je     L17
  lea    0xc14(%rdi),%eax
  cltq
  mov    %esi,%edx
  and    $0x7fffffff,%edx
  mov    %edx,(%rax)
L17:
  test   %esi,%esi
  js     L0
L18:
  ret
L0:
  add    $0xfd8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  jmp    L18
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EMACIntClear>:
  endbr64
  mov    %esi,%eax
  or     $0x10000,%eax
  test   $0x4045,%esi
  cmovne %eax,%esi
  mov    %esi,%eax
  or     $0x80,%ah
  test   $0x27ba,%esi
  cmovne %eax,%esi
  mov    %esi,%edx
  and    $0x7fffffff,%edx
  je     L3
  lea    0xc14(%rdi),%eax
  cltq
  mov    %edx,(%rax)
L3:
  test   %esi,%esi
  js     L2
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0xfd8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<EMACIntClear>:
  endbr64
  mov    %esi,%eax
  or     $0x10000,%eax
  test   $0x4045,%esi
  cmovne %eax,%esi
  mov    %esi,%eax
  or     $0x80,%ah
  test   $0x27ba,%esi
  cmovne %eax,%esi
  mov    %esi,%edx
  and    $0x7fffffff,%edx
  je     L4
  lea    0xc14(%rdi),%eax
  cltq
  mov    %edx,(%rax)
L4:
  test   %esi,%esi
  js     L3
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0xfd8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_set_de>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  movzwl -0x1c(%rbp),%eax
  shr    $0x8,%ax
  mov    %al,-0x2(%rbp)
  movzwl -0x1c(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cpu_set_d@plt>
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cpu_set_e@plt>
  nop
  leave
  ret
```

assistant: ```c
void cpu_set_de(struct cpu *cpu, unsigned short de) {
  unsigned char d = ((unsigned char)(((unsigned short)(de)) >> 8));
  unsigned char e = ((unsigned char)(((unsigned short)(de)) >> 0));
  cpu_set_d(cpu, d);
  cpu_set_e(cpu, e);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpu_set_de>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movzbl %bh,%esi
  call   <cpu_set_d@plt>
  movzbl %bl,%esi
  mov    %rbp,%rdi
  call   <cpu_set_e@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cpu_set_de(struct cpu *cpu, unsigned short de) {
  unsigned char d = ((unsigned char)(((unsigned short)(de)) >> 8));
  unsigned char e = ((unsigned char)(((unsigned short)(de)) >> 0));
  cpu_set_d(cpu, d);
  cpu_set_e(cpu, e);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpu_set_de>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  movzbl %bh,%esi
  sub    $0x8,%rsp
  call   <cpu_set_d@plt>
  add    $0x8,%rsp
  movzbl %bl,%esi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <cpu_set_e@plt>
```

assistant: ```c
void cpu_set_de(struct cpu *cpu, unsigned short de) {
  unsigned char d = ((unsigned char)(((unsigned short)(de)) >> 8));
  unsigned char e = ((unsigned char)(((unsigned short)(de)) >> 0));
  cpu_set_d(cpu, d);
  cpu_set_e(cpu, e);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpu_set_de>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  movzbl %bh,%esi
  sub    $0x8,%rsp
  call   <cpu_set_d@plt>
  add    $0x8,%rsp
  movzbl %bl,%esi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <cpu_set_e@plt>
```

assistant: ```c
void cpu_set_de(struct cpu *cpu, unsigned short de) {
  unsigned char d = ((unsigned char)(((unsigned short)(de)) >> 8));
  unsigned char e = ((unsigned char)(((unsigned short)(de)) >> 0));
  cpu_set_d(cpu, d);
  cpu_set_e(cpu, e);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hayConflictoEnColumna>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L8:
  movl   $0x0,-0x8(%rbp)
  jmp    L53
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L27
  mov    $0x1,%eax
  jmp    L29
L27:
  addl   $0x1,-0x8(%rbp)
L53:
  cmpl   $0x8,-0x8(%rbp)
  jle    L17
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x9,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int hayConflictoEnColumna(int sudoku[9][9], int jj) {
  int i, nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    for (i = 0; i < 9; i++) {
      if (sudoku[i][jj] == nuevoCandidato) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hayConflictoEnColumna>:
  endbr64
  movslq %esi,%rsi
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%r8
  lea    0x144(%rdi,%rsi,1),%rcx
  mov    $0x1,%edx
  jmp    L11
L5:
  add    $0x1,%edx
  cmp    $0xa,%edx
  je     L32
L11:
  mov    %r8,%rax
L30:
  cmp    %edx,(%rax)
  je     L7
  add    $0x24,%rax
  cmp    %rcx,%rax
  jne    L30
  jmp    L5
L7:
  mov    $0x1,%eax
  ret
L32:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int hayConflictoEnColumna(int sudoku[9][9], int jj) {
  int i, nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    for (i = 0; i < 9; i++) {
      if (sudoku[i][jj] == nuevoCandidato) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hayConflictoEnColumna>:
  endbr64
  movslq %esi,%rsi
  mov    $0x1,%edx
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%r8
  lea    0x144(%rdi,%rsi,1),%rcx
L1:
  mov    %r8,%rax
  nop
L28:
  cmp    %edx,(%rax)
  je     L24
  add    $0x24,%rax
  cmp    %rcx,%rax
  jne    L28
  add    $0x1,%edx
  cmp    $0xa,%edx
  jne    L1
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int hayConflictoEnColumna(int sudoku[9][9], int jj) {
  int i, nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    for (i = 0; i < 9; i++) {
      if (sudoku[i][jj] == nuevoCandidato) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<hayConflictoEnColumna>:
  endbr64
  movslq %esi,%rsi
  mov    $0x1,%eax
  lea    (%rdi,%rsi,4),%rdx
  mov    (%rdx),%ecx
L92:
  cmp    %ecx,%eax
  je     L99
  cmp    0x24(%rdx),%eax
  je     L99
  cmp    0x48(%rdx),%eax
  je     L99
  cmp    0x6c(%rdx),%eax
  je     L99
  cmp    0x90(%rdx),%eax
  je     L99
  cmp    0xb4(%rdx),%eax
  je     L99
  cmp    0xd8(%rdx),%eax
  je     L99
  cmp    0xfc(%rdx),%eax
  je     L99
  cmp    0x120(%rdx),%eax
  je     L99
  add    $0x1,%eax
  cmp    $0xa,%eax
  jne    L92
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L99:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int hayConflictoEnColumna(int sudoku[9][9], int jj) {
  int i, nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    for (i = 0; i < 9; i++) {
      if (sudoku[i][jj] == nuevoCandidato) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L11
  mov    $0x1,%eax
  jmp    L3
L11:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L27
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int Check(int *array1, int *array2, int length) {
  for (int i = 0; i < length; i++) {
    if (!(array1[i] == array2[i]))
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Check>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  mov    $0x0,%eax
L29:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L14
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L29
  mov    $0x0,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Check(int *array1, int *array2, int length) {
  for (int i = 0; i < length; i++) {
    if (!(array1[i] == array2[i]))
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Check>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L20
  nop
L39:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L1
L20:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L39
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Check(int *array1, int *array2, int length) {
  for (int i = 0; i < length; i++) {
    if (!(array1[i] == array2[i]))
      return 1;
  }
  return 0;
}
```