user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_data>:
  endbr64
  test   %esi,%esi
  jle    L87
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    $0x0,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl (%r14),%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xf(%r14),%rbp
  mov    $0x1,%ebx
  lea    D10(%rip),%r15
  lea    D44(%rip),%r13
  jmp    L136
L55:
  add    $0x1,%rbp
L136:
  test   $0xf,%bl
  je     L73
  cmp    %ebx,%r12d
  jle    L130
L58:
  movsbl 0x10(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  test   $0x7,%bl
  jne    L55
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L55
L73:
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <print_asc@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  lea    0x8(%rbp),%rdi
  mov    $0x8,%esi
  call   <print_asc@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jg     L18
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L58
L125:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L94
L25:
  sub    %r12d,%ebx
  movslq %ebx,%rdi
  add    %r14,%rdi
  mov    %r12d,%esi
  call   <print_asc@plt>
  jmp    L57
L130:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rbx,%rax,1),%r12d
  and    $0xf,%r12d
  sub    %eax,%r12d
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x10,%eax
  sub    %r12d,%eax
  cmp    $0x8,%eax
  jg     L125
L94:
  mov    $0xf,%ebp
  sub    %r12d,%ebp
  lea    D27(%rip),%r13
L36:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L36
  mov    $0x8,%ebp
  cmp    %ebp,%r12d
  cmovle %r12d,%ebp
  mov    %ebx,%edi
  sub    %r12d,%edi
  movslq %edi,%rdi
  add    %r14,%rdi
  mov    %ebp,%esi
  call   <print_asc@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    %ebp,%r12d
  test   %r12d,%r12d
  jg     L25
L57:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L6
L87:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D44
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string

tool: D10: [%03X] 

tool: D44: %02X 

tool: D27:    

assistant: ```c
void print_data(const char *buf, int len) {
  int i = 0;
  if (len <= 0)
    return;
  printf("[%03X] ", i);
  for (i = 0; i < len;) {
    printf("%02X ", (int)buf[i]);
    i++;
    if (i % 8 == 0)
      printf(" ");
    if (i % 16 == 0) {
      print_asc(&buf[i - 16], 8);
      printf(" ");
      print_asc(&buf[i - 8], 8);
      printf("\n");
      if (i < len)
        printf("[%03X] ", i);
    }
  }
  if (i % 16) {
    int n;
    n = 16 - (i % 16);
    printf(" ");
    if (n > 8)
      printf(" ");
    while (n--)
      printf("   ");
    n = i % 16;
    if (n > 8)
      n = 8;
    print_asc(&buf[i - (i % 16)], n);
    printf(" ");
    n = (i % 16) - n;
    if (n > 0)
      print_asc(&buf[i - n], n);
    printf("\n");
  }
}
```