ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<charset_petcii_to_screencode>:
  endbr64
  test   %esi,%esi
  setne  %al
  shl    $0x7,%eax
  lea    -0x40(%rdi),%edx
  cmp    $0x1f,%dl
  jbe    L12
  lea    -0x60(%rdi),%ecx
  cmp    $0x1f,%cl
  jbe    L16
  lea    0x60(%rdi),%ecx
  cmp    $0x1f,%cl
  jbe    L23
  lea    0x40(%rdi),%edx
  cmp    $0x3e,%dl
  jbe    L8
  mov    %eax,%edx
  or     $0x5e,%edx
  or     %edi,%eax
  cmp    $0xff,%dil
  cmove  %edx,%eax
  ret
L12:
  or     %edx,%eax
  ret
L16:
  sub    $0x20,%edi
  or     %edi,%eax
  ret
L23:
  or     %edx,%eax
  ret
L8:
  add    $0xffffff80,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned char charset_petcii_to_screencode(unsigned char code, unsigned int reverse_mode) {
  unsigned char rev = (reverse_mode ? 0x80 : 0x00);
  if (code >= 0x40 && code <= 0x5f) {
    return (unsigned char)(code - 0x40) | rev;
  } else if (code >= 0x60 && code <= 0x7f) {
    return (unsigned char)(code - 0x20) | rev;
  } else if (code >= 0xa0 && code <= 0xbf) {
    return (unsigned char)(code - 0x40) | rev;
  } else if (code >= 0xc0 && code <= 0xfe) {
    return (unsigned char)(code - 0x80) | rev;
  } else if (code == 0xff) {
    return 0x5e | rev;
  }
  return code | rev;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<charset_petcii_to_screencode>:
  endbr64
  test   %esi,%esi
  lea    -0x40(%rdi),%edx
  setne  %al
  shl    $0x7,%eax
  cmp    $0x1f,%dl
  jbe    L26
  lea    -0x60(%rdi),%ecx
  cmp    $0x1f,%cl
  jbe    L8
  lea    0x60(%rdi),%ecx
  cmp    $0x1f,%cl
  jbe    L26
  lea    0x40(%rdi),%edx
  cmp    $0x3e,%dl
  jbe    L11
  mov    %eax,%edx
  or     %edi,%eax
  or     $0x5e,%edx
  cmp    $0xff,%dil
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  sub    $0x20,%edi
  or     %edi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  or     %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0xffffff80,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned char charset_petcii_to_screencode(unsigned char code, unsigned int reverse_mode) {
  unsigned char rev = (reverse_mode ? 0x80 : 0x00);
  if (code >= 0x40 && code <= 0x5f) {
    return (unsigned char)(code - 0x40) | rev;
  } else if (code >= 0x60 && code <= 0x7f) {
    return (unsigned char)(code - 0x20) | rev;
  } else if (code >= 0xa0 && code <= 0xbf) {
    return (unsigned char)(code - 0x40) | rev;
  } else if (code >= 0xc0 && code <= 0xfe) {
    return (unsigned char)(code - 0x80) | rev;
  } else if (code == 0xff) {
    return 0x5e | rev;
  }
  return code | rev;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<charset_petcii_to_screencode>:
  endbr64
  test   %esi,%esi
  lea    -0x40(%rdi),%edx
  setne  %al
  shl    $0x7,%eax
  cmp    $0x1f,%dl
  jbe    L28
  lea    -0x60(%rdi),%ecx
  cmp    $0x1f,%cl
  jbe    L24
  lea    0x60(%rdi),%ecx
  cmp    $0x1f,%cl
  jbe    L28
  lea    0x40(%rdi),%edx
  cmp    $0x3e,%dl
  jbe    L30
  mov    %eax,%edx
  or     %edi,%eax
  or     $0x5e,%edx
  cmp    $0xff,%dil
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  sub    $0x20,%edi
  or     %edi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  or     %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0xffffff80,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned char charset_petcii_to_screencode(unsigned char code, unsigned int reverse_mode) {
  unsigned char rev = (reverse_mode ? 0x80 : 0x00);
  if (code >= 0x40 && code <= 0x5f) {
    return (unsigned char)(code - 0x40) | rev;
  } else if (code >= 0x60 && code <= 0x7f) {
    return (unsigned char)(code - 0x20) | rev;
  } else if (code >= 0xa0 && code <= 0xbf) {
    return (unsigned char)(code - 0x40) | rev;
  } else if (code >= 0xc0 && code <= 0xfe) {
    return (unsigned char)(code - 0x80) | rev;
  } else if (code == 0xff) {
    return 0x5e | rev;
  }
  return code | rev;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printCArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L11:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L1
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D16
datatype: string

tool: D18: unsigned char output[]="

tool: D27: \x%0.2x

tool: D16: "

assistant: ```c
void printCArray(unsigned char *buff, unsigned int length) {
  int i = -1;
  printf("unsigned char output[]=\"");
  while (++i < length) {
    printf("\\x%0.2x", buff[i]);
  }
  printf("\"\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printCArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L6
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%r12
  lea    D26(%rip),%rbp
L4:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
L6:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string

tool: D18: unsigned char output[]="

tool: D26: \x%0.2x

tool: D22: "

assistant: ```c
void printCArray(unsigned char *buff, unsigned int length) {
  int i = -1;
  printf("unsigned char output[]=\"");
  while (++i < length) {
    printf("\\x%0.2x", buff[i]);
  }
  printf("\"\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printCArray>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D29(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L19
  lea    -0x1(%rbp),%eax
  lea    D24(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
  xchg   %ax,%ax
L8:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
L19:
  pop    %rbx
  lea    D17(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D29
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D17
type: string

tool: D29: unsigned char output[]="

tool: D24: \x%0.2x

tool: D17: "

assistant: ```c
void printCArray(unsigned char *buff, unsigned int length) {
  int i = -1;
  printf("unsigned char output[]=\"");
  while (++i < length) {
    printf("\\x%0.2x", buff[i]);
  }
  printf("\"\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printCArray>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L9
  lea    -0x1(%rbp),%eax
  lea    D9(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
  xchg   %ax,%ax
L12:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
L9:
  pop    %rbx
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string

tool: D4: unsigned char output[]="

tool: D9: \x%0.2x

tool: D14: "

assistant: ```c
void printCArray(unsigned char *buff, unsigned int length) {
  int i = -1;
  printf("unsigned char output[]=\"");
  while (++i < length) {
    printf("\\x%0.2x", buff[i]);
  }
  printf("\"\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L6
L59:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  cmp    $0x1,%rax
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
L53:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jge    L63
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gcd@plt>
  jmp    L64
L63:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gcd@plt>
L64:
  mov    %rax,-0x18(%rbp)
L22:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L53
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L59
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D46
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D46: %d

tool: D23: %lld

tool: D4: %lld


assistant: ```c
int main(void) {
  int t;
  scanf("%d", &t);
  while (t--) {
    long long int n;
    scanf("%lld", &n);
    long long int a;
    scanf("%lld", &a);
    if (n == 1) {
      printf("%lld\n", a);
      continue;
    }
    while (--n) {
      long long int b;
      scanf("%lld", &b);
      a = a < b ? gcd(a, b) : gcd(b, a);
    }
    printf("%lld\n", a);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L23
  lea    0x10(%rsp),%r13
  lea    D15(%rip),%rbx
  lea    0x18(%rsp),%r12
  lea    D27(%rip),%rbp
  jmp    L52
L97:
  mov    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L68
L6:
  mov    %rax,%rsi
  call   <gcd@plt>
L91:
  mov    %rax,0x18(%rsp)
  mov    0x10(%rsp),%rax
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  je     L73
L108:
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  mov    0x20(%rsp),%rdi
  cmp    %rdi,%rax
  jge    L6
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <gcd@plt>
  jmp    L91
L73:
  mov    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L68:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L23
L52:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  cmp    $0x1,%rax
  je     L97
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  jne    L108
  jmp    L73
L23:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D15
datatype: string
name: read_data
arguments: data_label: D27
datatype: string

tool: D3: %d

tool: D15: %lld

tool: D27: %lld


assistant: ```c
int main(void) {
  int t;
  scanf("%d", &t);
  while (t--) {
    long long int n;
    scanf("%lld", &n);
    long long int a;
    scanf("%lld", &a);
    if (n == 1) {
      printf("%lld\n", a);
      continue;
    }
    while (--n) {
      long long int b;
      scanf("%lld", &b);
      a = a < b ? gcd(a, b) : gcd(b, a);
    }
    printf("%lld\n", a);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L104
  lea    0x10(%rsp),%r14
  lea    D5(%rip),%rbx
  lea    0x18(%rsp),%r13
  lea    D9(%rip),%r12
  lea    0x20(%rsp),%rbp
  nopl   0x0(%rax)
L87:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  cmp    $0x1,%rax
  je     L67
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  jne    L57
  jmp    L19
  nopl   0x0(%rax)
L100:
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <gcd@plt>
  subq   $0x1,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  je     L41
L57:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%r8
  mov    0x20(%rsp),%rdi
  cmp    %rdi,%r8
  jl     L100
  mov    %r8,%rsi
  call   <gcd@plt>
  subq   $0x1,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  jne    L57
L41:
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L36:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L87
L104:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L67:
  mov    0x18(%rsp),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L36
L19:
  mov    0x18(%rsp),%rax
  jmp    L41
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string

tool: D6: %d

tool: D5: %lld

tool: D9: %lld


assistant: ```c
int main(void) {
  int t;
  scanf("%d", &t);
  while (t--) {
    long long int n;
    scanf("%lld", &n);
    long long int a;
    scanf("%lld", &a);
    if (n == 1) {
      printf("%lld\n", a);
      continue;
    }
    while (--n) {
      long long int b;
      scanf("%lld", &b);
      a = a < b ? gcd(a, b) : gcd(b, a);
    }
    printf("%lld\n", a);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D24(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L14
  lea    0x10(%rsp),%r14
  lea    D3(%rip),%rbx
  lea    0x18(%rsp),%r13
  lea    D28(%rip),%r12
  lea    0x20(%rsp),%rbp
  nopl   0x0(%rax)
L34:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  cmp    $0x1,%rax
  je     L2
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  je     L2
  nopl   0x0(%rax)
L55:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%r8
  mov    0x20(%rsp),%rdi
  mov    %r8,%rsi
  cmp    %rdi,%r8
  jge    L44
  mov    %rdi,%rsi
  mov    %r8,%rdi
L44:
  call   <gcd@plt>
  subq   $0x1,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,%rsi
  jne    L55
L61:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L34
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  mov    0x18(%rsp),%rsi
  jmp    L61
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string

tool: D24: %d

tool: D3: %lld

tool: D28: %lld


assistant: ```c
int main(void) {
  int t;
  scanf("%d", &t);
  while (t--) {
    long long int n;
    scanf("%lld", &n);
    long long int a;
    scanf("%lld", &a);
    if (n == 1) {
      printf("%lld\n", a);
      continue;
    }
    while (--n) {
      long long int b;
      scanf("%lld", &b);
      a = a < b ? gcd(a, b) : gcd(b, a);
    }
    printf("%lld\n", a);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x98(%rbp)
  cmpq   $0x0,-0x98(%rbp)
  jne    L0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract_lfn@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D12
data_type: string

tool: D21: r

tool: D26: lfn

tool: D12: cnt open fiel


assistant: ```c
int main() {
  char buf[((10 + 12 + 4) / 2) * 2];
  char name[100];
  FILE *f = fopen("lfn", "r");
  if (!f)
    printf("cnt open fiel\n");
  fread(buf, 32, 1, f);
  extract_lfn(buf, name);
  puts(name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
L7:
  mov    %rsp,%rbp
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <extract_lfn@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D2
type: string

tool: D19: r

tool: D9: lfn

tool: D2: cnt open fiel


assistant: ```c
int main() {
  char buf[((10 + 12 + 4) / 2) * 2];
  char name[100];
  FILE *f = fopen("lfn", "r");
  if (!f)
    printf("cnt open fiel\n");
  fread(buf, 32, 1, f);
  extract_lfn(buf, name);
  puts(name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rsi
  lea    D15(%rip),%rdi
  push   %rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L29
L18:
  lea    0x10(%rsp),%r12
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    %r12,%rdi
  lea    0x30(%rsp),%rbp
  call   <fread@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <extract_lfn@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L29:
  lea    D9(%rip),%rdi
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rcx
  jmp    L18
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D21: r

tool: D15: lfn

tool: D9: cnt open fiel


assistant: ```c
int main() {
  char buf[((10 + 12 + 4) / 2) * 2];
  char name[100];
  FILE *f = fopen("lfn", "r");
  if (!f)
    printf("cnt open fiel\n");
  fread(buf, 32, 1, f);
  extract_lfn(buf, name);
  puts(name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rsi
  lea    D2(%rip),%rdi
  push   %rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L13
L0:
  lea    0x10(%rsp),%r12
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    %r12,%rdi
  lea    0x30(%rsp),%rbp
  call   <fread@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <extract_lfn@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    D9(%rip),%rdi
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rcx
  jmp    L0
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string
name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D28: r

tool: D2: lfn

tool: D9: cnt open fiel


assistant: ```c
int main() {
  char buf[((10 + 12 + 4) / 2) * 2];
  char name[100];
  FILE *f = fopen("lfn", "r");
  if (!f)
    printf("cnt open fiel\n");
  fread(buf, 32, 1, f);
  extract_lfn(buf, name);
  puts(name);
}
```