ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  shr    $0x3,%rax
  and    $0x33,%eax
  or     $0x31,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] >>= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
        state[0UL] |= state[local1];
      } else {
        state[0UL] = state[local1] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 179841843UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  shr    $0x3,%rax
  and    $0x33,%eax
  or     $0x31,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] >>= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
        state[0UL] |= state[local1];
      } else {
        state[0UL] = state[local1] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 179841843UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Delay10TCYx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  jmp    L35
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L38:
  mov    $0x0,%eax
  call   <Delay1TCY@plt>
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x9,-0x4(%rbp)
  jle    L38
  movzbl -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x14(%rbp)
L35:
  cmpb   $0x0,-0x14(%rbp)
  jne    L30
  nop
  nop
  leave
  ret
```

assistant: ```c
void Delay10TCYx(unsigned char unit) {
  int i;
  while (unit > 0) {
    for (i = 0; i < 10; i++) {
      Delay1TCY();
    }
    unit--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Delay10TCYx>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  test   %dil,%dil
  je     L6
L3:
  mov    $0xa,%ebx
L22:
  mov    $0x0,%eax
  call   <Delay1TCY@plt>
  sub    $0x1,%ebx
  jne    L22
  sub    $0x1,%bpl
  jne    L3
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Delay10TCYx(unsigned char unit) {
  int i;
  while (unit > 0) {
    for (i = 0; i < 10; i++) {
      Delay1TCY();
    }
    unit--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Delay10TCYx>:
  endbr64
  test   %dil,%dil
  je     L21
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    $0xa,%ebx
  nopl   (%rax)
L13:
  xor    %eax,%eax
  call   <Delay1TCY@plt>
  sub    $0x1,%ebx
  jne    L13
  sub    $0x1,%bpl
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  ret
```

assistant: ```c
void Delay10TCYx(unsigned char unit) {
  int i;
  while (unit > 0) {
    for (i = 0; i < 10; i++) {
      Delay1TCY();
    }
    unit--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Delay10TCYx>:
  endbr64
  test   %dil,%dil
  je     L13
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    $0xa,%ebx
  nopl   (%rax)
L12:
  xor    %eax,%eax
  call   <Delay1TCY@plt>
  sub    $0x1,%ebx
  jne    L12
  sub    $0x1,%bpl
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  ret
```

assistant: ```c
void Delay10TCYx(unsigned char unit) {
  int i;
  while (unit > 0) {
    for (i = 0; i < 10; i++) {
      Delay1TCY();
    }
    unit--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L20:
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  lea    D64(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  lea    -0x20(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L50
  lea    -0x20(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L25
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L20
L6:
  nop
  jmp    L12
L50:
  nop
  jmp    L12
L25:
  nop
L12:
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D28
datatype: string
name: read_data
arguments: data_label: D72
datatype: string
name: read_data
arguments: data_label: D75
datatype: string
name: read_data
arguments: data_label: D64
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D1
datatype: string

tool: D2: ----SCIENTIFIC CALCULATOR----


tool: D28: Enter QUIT to stop

tool: D72: Enter a command: 

tool: D75: %s

tool: D64: QUIT

tool: D11: Quit

tool: D16: quit

tool: D1: %lf


assistant: ```c
int main(void) {
  printf("----SCIENTIFIC CALCULATOR----\n\n");
  printf("Enter QUIT to stop\n");
  char str[20];
  double answer;
  while (1) {
    printf("Enter a command: ");
    scanf("%s", &str);
    if (strcmp(str, "QUIT") == 0)
      break;
    else if (strcmp(str, "Quit") == 0)
      break;
    else if (strcmp(str, "quit") == 0)
      break;
    printf("%lf\n", answer);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%r13
  lea    D48(%rip),%r12
  lea    D18(%rip),%rbp
  lea    D31(%rip),%r14
  jmp    L13
L5:
  pxor   %xmm0,%xmm0
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L13:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L1
  mov    %rsp,%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L1
  mov    %rsp,%rdi
  lea    D77(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x1,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D54
data_type: string
name: extract_symbolic_data
arguments: label: D34
data_type: string
name: extract_symbolic_data
arguments: label: D43
data_type: string
name: extract_symbolic_data
arguments: label: D48
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D77
data_type: string

tool: D54: ----SCIENTIFIC CALCULATOR----


tool: D34: Enter QUIT to stop

tool: D43: Enter a command: 

tool: D48: %s

tool: D18: QUIT

tool: D31: Quit

tool: D15: %lf


tool: D77: quit

assistant: ```c
int main(void) {
  printf("----SCIENTIFIC CALCULATOR----\n\n");
  printf("Enter QUIT to stop\n");
  char str[20];
  double answer;
  while (1) {
    printf("Enter a command: ");
    scanf("%s", &str);
    if (strcmp(str, "QUIT") == 0)
      break;
    else if (strcmp(str, "Quit") == 0)
      break;
    else if (strcmp(str, "quit") == 0)
      break;
    printf("%lf\n", answer);
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D71(%rip),%rdi
  lea    D9(%rip),%r15
  push   %r14
  lea    D24(%rip),%r14
  push   %r13
  lea    D77(%rip),%r13
  push   %r12
  lea    D72(%rip),%r12
  push   %rbp
  lea    D38(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  pxor   %xmm0,%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L2:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D71
type: string
name: disassemble_data
arguments: tag: D9
type: string
name: disassemble_data
arguments: tag: D24
type: string
name: disassemble_data
arguments: tag: D77
type: string
name: disassemble_data
arguments: tag: D72
type: string
name: disassemble_data
arguments: tag: D38
type: string
name: disassemble_data
arguments: tag: D56
type: string
name: disassemble_data
arguments: tag: D55
type: string

tool: D71: ----SCIENTIFIC CALCULATOR----


tool: D9: quit

tool: D24: Quit

tool: D77: Enter a command: 

tool: D72: %s

tool: D38: QUIT

tool: D56: Enter QUIT to stop

tool: D55: %lf


assistant: ```c
int main(void) {
  printf("----SCIENTIFIC CALCULATOR----\n\n");
  printf("Enter QUIT to stop\n");
  char str[20];
  double answer;
  while (1) {
    printf("Enter a command: ");
    scanf("%s", &str);
    if (strcmp(str, "QUIT") == 0)
      break;
    else if (strcmp(str, "Quit") == 0)
      break;
    else if (strcmp(str, "quit") == 0)
      break;
    printf("%lf\n", answer);
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D64(%rip),%rdi
  lea    D23(%rip),%r15
  push   %r14
  lea    D38(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  lea    D71(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L21
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L21
  pxor   %xmm0,%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L22:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L35
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D64
type: string
name: parse_data
arguments: label: D23
type: string
name: parse_data
arguments: label: D38
type: string
name: parse_data
arguments: label: D20
type: string
name: parse_data
arguments: label: D71
type: string
name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D55
type: string

tool: D64: ----SCIENTIFIC CALCULATOR----


tool: D23: quit

tool: D38: Quit

tool: D20: Enter a command: 

tool: D71: %s

tool: D19: QUIT

tool: D36: Enter QUIT to stop

tool: D55: %lf


assistant: ```c
int main(void) {
  printf("----SCIENTIFIC CALCULATOR----\n\n");
  printf("Enter QUIT to stop\n");
  char str[20];
  double answer;
  while (1) {
    printf("Enter a command: ");
    scanf("%s", &str);
    if (strcmp(str, "QUIT") == 0)
      break;
    else if (strcmp(str, "Quit") == 0)
      break;
    else if (strcmp(str, "quit") == 0)
      break;
    printf("%lf\n", answer);
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<display_buffer_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L11:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L7:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jbe    L93
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L85
L93:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L85:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0xf,-0x4(%rbp)
  jbe    L7
  mov    $0x20,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L115:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jbe    L13
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jbe    L97
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jbe    L117
L97:
  mov    $0x2e,%edi
  call   <putchar@plt>
  jmp    L13
L117:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L13:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0xf,-0x4(%rbp)
  jbe    L115
  addl   $0x10,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D11: 
  %08x  

tool: D4: %02x

tool: D17:   

assistant: ```c
void display_buffer_hex(unsigned char *buffer, unsigned size) {
  unsigned i, j, k;
  for (i = 0; i < size; i += 16) {
    printf("\n  %08x  ", i);
    for (j = 0, k = 0; k < 16; j++, k++) {
      if (i + j < size) {
        printf("%02x", buffer[i + j]);
      } else {
        printf("  ");
      }
      printf(" ");
    }
    printf(" ");
    for (j = 0, k = 0; k < 16; j++, k++) {
      if (i + j < size) {
        if ((buffer[i + j] < 32) || (buffer[i + j] > 126)) {
          printf(".");
        } else {
          printf("%c", buffer[i + j]);
        }
      }
    }
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<display_buffer_hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L60
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    $0x10,%r12d
  lea    D28(%rip),%r15
  jmp    L105
L75:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L72:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  je     L91
L51:
  cmp    %ebp,%r13d
  jbe    L75
  mov    %ebp,%eax
  movzbl (%r14,%rax,1),%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L72
L91:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L116
L53:
  movzbl %dil,%edi
  call   <putchar@plt>
L64:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L38
L116:
  cmp    %r13d,%ebx
  jae    L64
  mov    %ebx,%eax
  movzbl (%r14,%rax,1),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%al
  jbe    L53
  mov    $0x2e,%edi
  call   <putchar@plt>
  jmp    L64
L38:
  lea    0x10(%r12),%eax
  cmp    %r13d,%r12d
  jae    L60
  mov    %eax,%r12d
L105:
  lea    -0x10(%r12),%ebx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%ebp
  jmp    L51
L60:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D28
data_type: string
name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D7
data_type: string

tool: D28:   

tool: D6: %02x

tool: D7: 
  %08x  

assistant: ```c
void display_buffer_hex(unsigned char *buffer, unsigned size) {
  unsigned i, j, k;
  for (i = 0; i < size; i += 16) {
    printf("\n  %08x  ", i);
    for (j = 0, k = 0; k < 16; j++, k++) {
      if (i + j < size) {
        printf("%02x", buffer[i + j]);
      } else {
        printf("  ");
      }
      printf(" ");
    }
    printf(" ");
    for (j = 0, k = 0; k < 16; j++, k++) {
      if (i + j < size) {
        if ((buffer[i + j] < 32) || (buffer[i + j] > 126)) {
          printf(".");
        } else {
          printf("%c", buffer[i + j]);
        }
      }
    }
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display_buffer_hex>:
  endbr64
  test   %esi,%esi
  je     L94
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    $0x10,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L45:
  lea    -0x10(%r12),%ebx
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %ebx,%ebp
  call   <printf@plt>
  jmp    L25
  nopl   0x0(%rax)
L30:
  mov    %ebp,%eax
  lea    D14(%rip),%rdi
  movzbl (%r14,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
L112:
  mov    $0x20,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,%r12d
  je     L36
L25:
  cmp    %ebp,%r13d
  ja     L30
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L112
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L51
  nopl   0x0(%rax)
L9:
  mov    $0x2e,%edi
  call   <putchar@plt>
L14:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L118
L51:
  cmp    %r13d,%ebx
  jae    L14
  mov    %ebx,%eax
  movzbl (%r14,%rax,1),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%al
  ja     L9
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L51
L118:
  lea    0x10(%r12),%eax
  cmp    %r12d,%r13d
  jbe    L16
  mov    %eax,%r12d
  jmp    L45
L16:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
L94:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D14
type: string

tool: D7:   

tool: D20: 
  %08x  

tool: D14: %02x

assistant: ```c
void display_buffer_hex(unsigned char *buffer, unsigned size) {
  unsigned i, j, k;
  for (i = 0; i < size; i += 16) {
    printf("\n  %08x  ", i);
    for (j = 0, k = 0; k < 16; j++, k++) {
      if (i + j < size) {
        printf("%02x", buffer[i + j]);
      } else {
        printf("  ");
      }
      printf(" ");
    }
    printf(" ");
    for (j = 0, k = 0; k < 16; j++, k++) {
      if (i + j < size) {
        if ((buffer[i + j] < 32) || (buffer[i + j] > 126)) {
          printf(".");
        } else {
          printf("%c", buffer[i + j]);
        }
      }
    }
  }
  printf("\n");
}
```