ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%ebx
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rbx),%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string

tool: D5: 
Entre com uma letra MAIUSCULA:

tool: D2: 
Caracter lido = %c


tool: D27: 
Codigo ASCII = %d


tool: D14: 
Conversao para minuscula = %c


assistant: ```c
int main() {
  char lt;
  printf("\nEntre com uma letra MAIUSCULA:");
  lt = getchar();
  printf("\nCaracter lido = %c\n", lt);
  printf("\nCodigo ASCII = %d\n", lt);
  printf("\nConversao para minuscula = %c\n", lt + 32);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D12(%rip),%rdi
  movsbl %al,%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rbx),%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D8
type: string
name: parse_data
arguments: data_tag: D11
type: string

tool: D5: 
Entre com uma letra MAIUSCULA:

tool: D12: 
Caracter lido = %c


tool: D8: 
Codigo ASCII = %d


tool: D11: 
Conversao para minuscula = %c


assistant: ```c
int main() {
  char lt;
  printf("\nEntre com uma letra MAIUSCULA:");
  lt = getchar();
  printf("\nCaracter lido = %c\n", lt);
  printf("\nCodigo ASCII = %d\n", lt);
  printf("\nConversao para minuscula = %c\n", lt + 32);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D9(%rip),%rdi
  movsbl %al,%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rbx),%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D38
data_type: string

tool: D17: 
Entre com uma letra MAIUSCULA:

tool: D9: 
Caracter lido = %c


tool: D5: 
Codigo ASCII = %d


tool: D38: 
Conversao para minuscula = %c


assistant: ```c
int main() {
  char lt;
  printf("\nEntre com uma letra MAIUSCULA:");
  lt = getchar();
  printf("\nCaracter lido = %c\n", lt);
  printf("\nCodigo ASCII = %d\n", lt);
  printf("\nConversao para minuscula = %c\n", lt + 32);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_sorted>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L0
  mov    $0x0,%eax
  jmp    L1
L0:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L29
  mov    $0x1,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int is_sorted(long int *tab, int n) {
  int i;
  for (i = 0; i < n - 1; i++)
    if (tab[i] > tab[i + 1])
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_sorted>:
  endbr64
  cmp    $0x1,%esi
  jle    L9
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L13:
  mov    0x8(%rax),%rcx
  cmp    %rcx,(%rax)
  jg     L5
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
  mov    $0x1,%eax
  ret
L9:
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_sorted(long int *tab, int n) {
  int i;
  for (i = 0; i < n - 1; i++)
    if (tab[i] > tab[i + 1])
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_sorted>:
  endbr64
  cmp    $0x1,%esi
  jle    L11
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L11
L36:
  mov    0x8(%rdi),%rdx
  cmp    %rdx,(%rdi)
  jle    L6
  xor    %eax,%eax
  ret
  nopl   (%rax)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_sorted(long int *tab, int n) {
  int i;
  for (i = 0; i < n - 1; i++)
    if (tab[i] > tab[i + 1])
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_sorted>:
  endbr64
  cmp    $0x1,%esi
  jle    L9
  lea    -0x2(%rsi),%ecx
  mov    (%rdi),%rdx
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rcx,8),%rsi
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rax
  cmp    %rsi,%rax
  je     L9
L24:
  mov    %rdx,%rcx
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jge    L29
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_sorted(long int *tab, int n) {
  int i;
  for (i = 0; i < n - 1; i++)
    if (tab[i] > tab[i + 1])
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L27
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L27
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L27:
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void to_lower(char source[]) {
  int i, src_len = (int)strlen(source);
  for (i = 0; i < src_len; i++) {
    if ((source[i] >= 'A') && (source[i] <= 'Z')) {
      source[i] = (source[i] - 'A') + 'a';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_lower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L35
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  jmp    L39
L31:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L35
L39:
  movzbl (%rdx),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L31
  add    $0x20,%eax
  mov    %al,(%rdx)
  jmp    L31
L35:
  pop    %rbx
  ret
```

assistant: ```c
void to_lower(char source[]) {
  int i, src_len = (int)strlen(source);
  for (i = 0; i < src_len; i++) {
    if ((source[i] >= 'A') && (source[i] <= 'Z')) {
      source[i] = (source[i] - 'A') + 'a';
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<to_lower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax)
L25:
  movzbl (%rdi),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L20
  add    $0x20,%eax
  mov    %al,(%rdi)
L20:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L25
L4:
  pop    %rbx
  ret
```

assistant: ```c
void to_lower(char source[]) {
  int i, src_len = (int)strlen(source);
  for (i = 0; i < src_len; i++) {
    if ((source[i] >= 'A') && (source[i] <= 'Z')) {
      source[i] = (source[i] - 'A') + 'a';
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<to_lower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L25
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax)
L5:
  movzbl (%rdi),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L29
  add    $0x20,%eax
  mov    %al,(%rdi)
L29:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L5
L25:
  pop    %rbx
  ret
```

assistant: ```c
void to_lower(char source[]) {
  int i, src_len = (int)strlen(source);
  for (i = 0; i < src_len; i++) {
    if ((source[i] >= 'A') && (source[i] <= 'Z')) {
      source[i] = (source[i] - 'A') + 'a';
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<circulate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jg     L17
  mov    -0x14(%rbp),%eax
  jmp    L14
L17:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
L14:
  leave
  ret
```

assistant: ```c
uint32_t circulate(uint32_t i) {
  if (i < 10)
    return i;
  uint32_t len = floor(log10(i));
  uint32_t first = i % 10;
  i /= 10;
  return pow(10, len) * first + i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<circulate>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x9,%edi
  jg     L9
L16:
  mov    %ebx,%eax
  pop    %rbx
  ret
L9:
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %ecx,%ebx
  add    %eax,%ebx
  jmp    L16
```

assistant: ```c
uint32_t circulate(uint32_t i) {
  if (i < 10)
    return i;
  uint32_t len = floor(log10(i));
  uint32_t first = i % 10;
  i /= 10;
  return pow(10, len) * first + i;
}
```
user: What is the c source code of the assembly code below?

```asm
<circulate>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x9,%edi
  jle    L3
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    $0xa,%edi
  mov    %eax,%esi
  call   <pow@plt>
  mov    %r12d,%edx
  mov    %eax,%r8d
  movslq %r12d,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%r12d
  imul   %r8d,%r12d
  add    %eax,%r12d
L3:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
uint32_t circulate(uint32_t i) {
  if (i < 10)
    return i;
  uint32_t len = floor(log10(i));
  uint32_t first = i % 10;
  i /= 10;
  return pow(10, len) * first + i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<circulate>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x9,%edi
  jle    L2
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    $0xa,%edi
  mov    %eax,%esi
  call   <pow@plt>
  mov    %r12d,%edx
  mov    %eax,%r8d
  movslq %r12d,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%r12d
  imul   %r8d,%r12d
  add    %eax,%r12d
L2:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
uint32_t circulate(uint32_t i) {
  if (i < 10)
    return i;
  uint32_t len = floor(log10(i));
  uint32_t first = i % 10;
  i /= 10;
  return pow(10, len) * first + i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dotconf_continue_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x20(%rbp)
  ja     L69
  mov    $0x0,%eax
  jmp    L66
L69:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L64
  mov    $0x0,%eax
  jmp    L66
L64:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L37
  subq   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L2
  mov    $0x0,%eax
  jmp    L66
L2:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  setne  %al
  movzbl %al,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length - 1;
  if (length < 2)
    return 0;
  if (*cp1-- != '\n')
    return 0;
  if (*cp1 == '\r')
    cp1--;
  if (*cp1-- != '\\')
    return 0;
  cp1[1] = 0;
  return (*cp1 != '\\');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dotconf_continue_line>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%rsi
  jbe    L23
  lea    -0x1(%rdi,%rsi,1),%rdx
  cmpb   $0xa,(%rdx)
  jne    L23
  lea    -0x2(%rdx),%rcx
  cmpb   $0xd,-0x1(%rdx)
  je     L0
  lea    -0x1(%rdx),%rcx
L0:
  mov    $0x0,%eax
  cmpb   $0x5c,(%rcx)
  jne    L23
  movb   $0x0,(%rcx)
  cmpb   $0x5c,-0x1(%rcx)
  setne  %al
  movzbl %al,%eax
L23:
  ret
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length - 1;
  if (length < 2)
    return 0;
  if (*cp1-- != '\n')
    return 0;
  if (*cp1 == '\r')
    cp1--;
  if (*cp1-- != '\\')
    return 0;
  cp1[1] = 0;
  return (*cp1 != '\\');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dotconf_continue_line>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%rsi
  jbe    L26
  lea    -0x1(%rdi,%rsi,1),%rdx
  cmpb   $0xa,(%rdx)
  jne    L26
  movzbl -0x1(%rdx),%ecx
  lea    -0x1(%rdx),%rsi
  cmp    $0xd,%cl
  jne    L39
  movzbl -0x2(%rdx),%ecx
  lea    -0x2(%rdx),%rsi
L39:
  xor    %eax,%eax
  cmp    $0x5c,%cl
  je     L16
L26:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  cmpb   $0x5c,-0x1(%rsi)
  movb   $0x0,(%rsi)
  setne  %al
  ret
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length - 1;
  if (length < 2)
    return 0;
  if (*cp1-- != '\n')
    return 0;
  if (*cp1 == '\r')
    cp1--;
  if (*cp1-- != '\\')
    return 0;
  cp1[1] = 0;
  return (*cp1 != '\\');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dotconf_continue_line>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%rsi
  jbe    L6
  lea    -0x1(%rdi,%rsi,1),%rdx
  cmpb   $0xa,(%rdx)
  jne    L6
  movzbl -0x1(%rdx),%ecx
  lea    -0x1(%rdx),%rsi
  cmp    $0xd,%cl
  jne    L26
  movzbl -0x2(%rdx),%ecx
  lea    -0x2(%rdx),%rsi
L26:
  xor    %eax,%eax
  cmp    $0x5c,%cl
  je     L5
L6:
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  cmpb   $0x5c,-0x1(%rsi)
  movb   $0x0,(%rsi)
  setne  %al
  ret
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length - 1;
  if (length < 2)
    return 0;
  if (*cp1-- != '\n')
    return 0;
  if (*cp1 == '\r')
    cp1--;
  if (*cp1-- != '\\')
    return 0;
  cp1[1] = 0;
  return (*cp1 != '\\');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L15
L21:
  cmpl   $0x1,-0x14(%rbp)
  je     L34
  mov    -0x14(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   %rbx,%rax
  jmp    L15
L34:
  mov    $0x1,%eax
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long int factorial(int n) {
  if (n == 0)
    return 1;
  if (n != 1) {
    return n * factorial(n - 1);
  } else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  ja     L2
  ret
L2:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <factorial>
  mov    %rax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long int factorial(int n) {
  if (n == 0)
    return 1;
  if (n != 1) {
    return n * factorial(n - 1);
  } else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jbe    L1
  movslq %edi,%rdx
  lea    -0x2(%rdi),%esi
  mov    $0x1,%r8d
  lea    -0x1(%rdx),%rax
  mov    %rax,%rcx
  sub    %rsi,%rcx
  jmp    L20
  nopl   0x0(%rax)
L23:
  sub    $0x1,%rax
L20:
  imul   %rdx,%r8
  mov    %rax,%rdx
  cmp    %rcx,%rax
  jne    L23
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long int factorial(int n) {
  if (n == 0)
    return 1;
  if (n != 1) {
    return n * factorial(n - 1);
  } else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jbe    L28
  movslq %edi,%rdx
  lea    -0x2(%rdi),%esi
  mov    $0x1,%r8d
  lea    -0x1(%rdx),%rax
  mov    %rax,%rcx
  sub    %rsi,%rcx
  jmp    L0
  nopl   0x0(%rax)
L22:
  sub    $0x1,%rax
L0:
  imul   %rdx,%r8
  mov    %rax,%rdx
  cmp    %rcx,%rax
  jne    L22
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long int factorial(int n) {
  if (n == 0)
    return 1;
  if (n != 1) {
    return n * factorial(n - 1);
  } else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clSetCommandQueueProperty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x3f5,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
cl_int clSetCommandQueueProperty(cl_command_queue command_queue, cl_command_queue_properties properties, cl_bool enable, cl_command_queue_properties *old_properties) {
  unsigned int sys_args[4];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)properties;
  sys_args[2] = (unsigned int)enable;
  sys_args[3] = (unsigned int)old_properties;
  return (cl_int)syscall(325, 1013, sys_args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clSetCommandQueueProperty>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %rsp,%rdx
  mov    $0x3f5,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clSetCommandQueueProperty(cl_command_queue command_queue, cl_command_queue_properties properties, cl_bool enable, cl_command_queue_properties *old_properties) {
  unsigned int sys_args[4];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)properties;
  sys_args[2] = (unsigned int)enable;
  sys_args[3] = (unsigned int)old_properties;
  return (cl_int)syscall(325, 1013, sys_args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clSetCommandQueueProperty>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x145,%edi
  mov    %esi,0x4(%rsp)
  mov    $0x3f5,%esi
  mov    %edx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    %ecx,0xc(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clSetCommandQueueProperty(cl_command_queue command_queue, cl_command_queue_properties properties, cl_bool enable, cl_command_queue_properties *old_properties) {
  unsigned int sys_args[4];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)properties;
  sys_args[2] = (unsigned int)enable;
  sys_args[3] = (unsigned int)old_properties;
  return (cl_int)syscall(325, 1013, sys_args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<clSetCommandQueueProperty>:
  endbr64
  sub    $0x28,%rsp
  movq   %rdi,%xmm0
  movq   %rsi,%xmm2
  mov    $0x145,%edi
  movq   %rdx,%xmm1
  movq   %rcx,%xmm3
  punpcklqdq %xmm2,%xmm0
  mov    %rsp,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpcklqdq %xmm3,%xmm1
  mov    $0x3f5,%esi
  shufps $0x88,%xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clSetCommandQueueProperty(cl_command_queue command_queue, cl_command_queue_properties properties, cl_bool enable, cl_command_queue_properties *old_properties) {
  unsigned int sys_args[4];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)properties;
  sys_args[2] = (unsigned int)enable;
  sys_args[3] = (unsigned int)old_properties;
  return (cl_int)syscall(325, 1013, sys_args);
}
```