ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<show>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    (%rdi),%esi
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L17:
  mov    (%r12,%rbx,4),%eax
  lea    (%rax,%rsi,2),%esi
  lea    0x1(%rbx),%eax
  test   $0x7,%al
  jne    L8
  cmp    $0x1f,%rbx
  mov    $0xa,%eax
  mov    $0x2e,%edx
  mov    %rbp,%rdi
  cmove  %eax,%edx
  call   <printf@plt>
  xor    %esi,%esi
L8:
  add    $0x1,%rbx
  cmp    $0x20,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: %d%c

assistant: ```c
void show(int *ad) {
  int t, i;
  for (i = t = 0; i < 32; ++i) {
    t *= 2;
    t += ad[i];
    if ((i + 1) % 8 == 0) {
      printf("%d%c", t, i == 31 ? '\n' : '.');
      t = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<show>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    (%rdi),%esi
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L8:
  mov    (%r12,%rbx,4),%eax
  lea    (%rax,%rsi,2),%esi
  lea    0x1(%rbx),%eax
  test   $0x7,%al
  jne    L17
  cmp    $0x1f,%rbx
  mov    $0xa,%eax
  mov    $0x2e,%edx
  mov    %rbp,%rdi
  cmove  %eax,%edx
  call   <printf@plt>
  xor    %esi,%esi
L17:
  add    $0x1,%rbx
  cmp    $0x20,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %d%c

assistant: ```c
void show(int *ad) {
  int t, i;
  for (i = t = 0; i < 32; ++i) {
    t *= 2;
    t += ad[i];
    if ((i + 1) % 8 == 0) {
      printf("%d%c", t, i == 31 ? '\n' : '.');
      t = 0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmpr_checkfiletype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <filename_extension@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <cmpr_checkextension@plt>
  mov    %eax,-0x414(%rbp)
  mov    -0x414(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int cmpr_checkfiletype(const char *filename) {
  int cmpr = 0;
  char extension[1024];
  filename_extension(extension, 1024, filename);
  cmpr = cmpr_checkextension(extension);
  return (cmpr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmpr_checkfiletype>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <filename_extension@plt>
  mov    %rbx,%rdi
  call   <cmpr_checkextension@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x410,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmpr_checkfiletype(const char *filename) {
  int cmpr = 0;
  char extension[1024];
  filename_extension(extension, 1024, filename);
  cmpr = cmpr_checkextension(extension);
  return (cmpr);
}
```
user: What is the c source code of the assembly code below:

```asm
<cmpr_checkfiletype>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0x400,%esi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <filename_extension@plt>
  mov    %rbp,%rdi
  call   <cmpr_checkextension@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x410,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmpr_checkfiletype(const char *filename) {
  int cmpr = 0;
  char extension[1024];
  filename_extension(extension, 1024, filename);
  cmpr = cmpr_checkextension(extension);
  return (cmpr);
}
```
user: What is the c source code of the assembly code below?

```asm
<cmpr_checkfiletype>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0x400,%esi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <filename_extension@plt>
  mov    %rbp,%rdi
  call   <cmpr_checkextension@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x410,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmpr_checkfiletype(const char *filename) {
  int cmpr = 0;
  char extension[1024];
  filename_extension(extension, 1024, filename);
  cmpr = cmpr_checkextension(extension);
  return (cmpr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<e_ldy_abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <e_abs@plt>
  mov    $0x0,%eax
  call   <e_ldy@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e_ldy_abs() {
  e_abs();
  e_ldy();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<e_ldy_abs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <e_abs@plt>
  mov    $0x0,%eax
  call   <e_ldy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void e_ldy_abs() {
  e_abs();
  e_ldy();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<e_ldy_abs>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_abs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <e_ldy@plt>
```

assistant: ```c
void e_ldy_abs() {
  e_abs();
  e_ldy();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<e_ldy_abs>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_abs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <e_ldy@plt>
```

assistant: ```c
void e_ldy_abs() {
  e_abs();
  e_ldy();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_smatrix_T_number_k>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    0x18(%rbp),%eax
  mov    %eax,%ecx
  mov    0x10(%rbp),%rdx
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x30(%rbp),%r9
  mov    -0x28(%rbp),%r8
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <write_smatrix_T_number@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D20
type: string

tool: D20: %s%02d.txt

assistant: ```c
void write_smatrix_T_number_k(short **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_smatrix_T_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_smatrix_T_number_k>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  mov    0x58(%rsp),%ecx
  mov    0x50(%rsp),%rdx
  lea    D10(%rip),%rsi
  lea    D7(%rip),%r15
  mov    %r15,%rdi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  push   %r15
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    0x18(%rsp),%rdi
  call   <write_smatrix_T_number@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D10
type: string

tool: D10: %s%02d.txt

assistant: ```c
void write_smatrix_T_number_k(short **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_smatrix_T_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_smatrix_T_number_k>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D16(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%ecx
  mov    0x40(%rsp),%rdx
  call   <sprintf@plt>
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    D7(%rip),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rdi,0x40(%rsp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <write_smatrix_T_number@plt>
```

tool_calls: name: disassemble_data
arguments: label: D16
type_guessed: string

tool: D16: %s%02d.txt

assistant: ```c
void write_smatrix_T_number_k(short **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_smatrix_T_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_smatrix_T_number_k>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D20(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D24(%rip),%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%ecx
  mov    0x40(%rsp),%rdx
  call   <sprintf@plt>
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    D24(%rip),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rdi,0x40(%rsp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <write_smatrix_T_number@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type: string

tool: D20: %s%02d.txt

assistant: ```c
void write_smatrix_T_number_k(short **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_smatrix_T_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *v = (int *)malloc(argc * sizeof(int));
  v[0] = 0;
  return v[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *v = (int *)malloc(argc * sizeof(int));
  v[0] = 0;
  return v[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *v = (int *)malloc(argc * sizeof(int));
  v[0] = 0;
  return v[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *v = (int *)malloc(argc * sizeof(int));
  v[0] = 0;
  return v[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dlmallocfork_restore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  lea    0x4(%rax),%ecx
  mov    -0x30(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  lea    0x4(%rax),%edi
  mov    -0x30(%rbp),%eax
  sub    %edi,%eax
  mov    %eax,%esi
  mov    -0x2c(%rbp),%eax
  sub    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void dlmallocfork_restore(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int datalen = (target[0] << 24) | (target[1] << 16) | (target[2] << 8) | (target[3] << 0);
  memcpy(source, &target[4], datalen);
  memcpy(&source[source_max - (target_max - (datalen + 4))], &target[datalen + 4], target_max - (datalen + 4));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dlmallocfork_restore>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  mov    (%rdx),%ebx
  shl    $0x18,%ebx
  mov    0x4(%rdx),%eax
  shl    $0x10,%eax
  or     %eax,%ebx
  or     0xc(%rdx),%ebx
  mov    0x8(%rdx),%eax
  shl    $0x8,%eax
  or     %eax,%ebx
  lea    0x10(%rdx),%rsi
  mov    %ebx,%edx
  call   <memcpy@plt>
  lea    0x4(%rbx),%eax
  mov    %r13d,%edx
  sub    %eax,%edx
  movslq %ebx,%rbx
  lea    0x10(%rbp,%rbx,4),%rsi
  sub    %edx,%r12d
  movslq %r12d,%r12
  lea    (%r14,%r12,4),%rdi
  call   <memcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void dlmallocfork_restore(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int datalen = (target[0] << 24) | (target[1] << 16) | (target[2] << 8) | (target[3] << 0);
  memcpy(source, &target[4], datalen);
  memcpy(&source[source_max - (target_max - (datalen + 4))], &target[datalen + 4], target_max - (datalen + 4));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dlmallocfork_restore>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  lea    0x10(%rdx),%rsi
  push   %rbx
  mov    (%rdx),%ebx
  mov    0x4(%rdx),%eax
  shl    $0x18,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  mov    0x8(%rdx),%eax
  or     0xc(%rdx),%ebx
  shl    $0x8,%eax
  or     %eax,%ebx
  mov    %ebx,%edx
  call   <memcpy@plt>
  lea    0x4(%rbx),%eax
  mov    %r12d,%edx
  movslq %ebx,%rbx
  sub    %eax,%edx
  lea    0x10(%r13,%rbx,4),%rsi
  pop    %rbx
  sub    %edx,%ebp
  movslq %ebp,%rbp
  lea    (%r14,%rbp,4),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void dlmallocfork_restore(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int datalen = (target[0] << 24) | (target[1] << 16) | (target[2] << 8) | (target[3] << 0);
  memcpy(source, &target[4], datalen);
  memcpy(&source[source_max - (target_max - (datalen + 4))], &target[datalen + 4], target_max - (datalen + 4));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dlmallocfork_restore>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  lea    0x10(%rdx),%rsi
  push   %rbx
  mov    (%rdx),%ebx
  mov    0x4(%rdx),%eax
  shl    $0x18,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  mov    0x8(%rdx),%eax
  or     0xc(%rdx),%ebx
  shl    $0x8,%eax
  or     %eax,%ebx
  mov    %ebx,%edx
  call   <memcpy@plt>
  lea    0x4(%rbx),%eax
  mov    %r12d,%edx
  movslq %ebx,%rbx
  sub    %eax,%edx
  lea    0x10(%r13,%rbx,4),%rsi
  pop    %rbx
  sub    %edx,%ebp
  movslq %ebp,%rbp
  lea    (%r14,%rbp,4),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void dlmallocfork_restore(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int datalen = (target[0] << 24) | (target[1] << 16) | (target[2] << 8) | (target[3] << 0);
  memcpy(source, &target[4], datalen);
  memcpy(&source[source_max - (target_max - (datalen + 4))], &target[datalen + 4], target_max - (datalen + 4));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eof_test_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  cmp    $0x1,%rsi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%rax
  cmp    $0x22,%rax
  jbe    L49
  cmp    $0x23,%rax
  je     L36
  mov    $0x0,%edx
  cmp    $0x45,%rax
  ja     L44
  lea    D5(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,(%r12)
  addq   $0x1,(%rbx)
  mov    %rbp,%rdx
L44:
  mov    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  lea    D16(%rip),%rdx
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%r12)
  addq   $0x1,(%rbx)
  mov    %rbp,%rdx
  jmp    L44
L36:
  mov    $0x1,%edi
  call   <assert@plt>
  addq   $0x1,(%rbx)
  mov    $0x0,%edx
  jmp    L44
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string
name: extract_symbolic_data
arguments: data_tag: D16
datatype: string

tool: 

tool: D16: _:s1 <http://example.org/p> _:o1 .
_:s2 <http://example.org/p> _:o2 .


assistant: ```c
size_t eof_test_read(void *buf, size_t size, size_t nmemb, void *stream) {
  assert(size == 1);
  assert(nmemb == 1);
  (void)size;
  static const char *const string = "_:s1 <http://example.org/p> _:o1 .\n"
                                    "_:s2 <http://example.org/p> _:o2 .\n";
  size_t *const count = (size_t *)stream;
  if (*count < 35) {
    *(char *)buf = string[*count];
    ++*count;
    return nmemb;
  }
  if (*count == 35) {
    assert(string[*count] == '_');
    ++*count;
    return 0;
  }
  if (*count >= strlen(string)) {
    return 0;
  }
  *(char *)buf = string[*count - 1];
  ++*count;
  return nmemb;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eof_test_read>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  cmp    $0x1,%rsi
  push   %rbp
  sete   %dil
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x1,%rbp
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%rax
  cmp    $0x22,%rax
  jbe    L10
  cmp    $0x23,%rax
  je     L21
  xor    %r8d,%r8d
  cmp    $0x45,%rax
  ja     L0
  lea    D3(%rip),%rdx
  mov    %rbp,%r8
  movzbl (%rax,%rdx,1),%eax
  mov    %al,(%r12)
  addq   $0x1,(%rbx)
L0:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L10:
  lea    D5(%rip),%rdx
  mov    %rbp,%r8
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%r12)
  mov    %r8,%rax
  addq   $0x1,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    $0x1,%edi
  call   <assert@plt>
  addq   $0x1,(%rbx)
  xor    %r8d,%r8d
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: 

tool: D5: _:s1 <http://example.org/p> _:o1 .
_:s2 <http://example.org/p> _:o2 .


assistant: ```c
size_t eof_test_read(void *buf, size_t size, size_t nmemb, void *stream) {
  assert(size == 1);
  assert(nmemb == 1);
  (void)size;
  static const char *const string = "_:s1 <http://example.org/p> _:o1 .\n"
                                    "_:s2 <http://example.org/p> _:o2 .\n";
  size_t *const count = (size_t *)stream;
  if (*count < 35) {
    *(char *)buf = string[*count];
    ++*count;
    return nmemb;
  }
  if (*count == 35) {
    assert(string[*count] == '_');
    ++*count;
    return 0;
  }
  if (*count >= strlen(string)) {
    return 0;
  }
  *(char *)buf = string[*count - 1];
  ++*count;
  return nmemb;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eof_test_read>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  cmp    $0x1,%rsi
  push   %rbp
  sete   %dil
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x1,%rbp
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%rax
  cmp    $0x22,%rax
  jbe    L32
  cmp    $0x23,%rax
  je     L14
  xor    %r8d,%r8d
  cmp    $0x45,%rax
  ja     L17
  lea    D18(%rip),%rdx
  mov    %rbp,%r8
  movzbl (%rax,%rdx,1),%eax
  mov    %al,(%r12)
  addq   $0x1,(%rbx)
L17:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L32:
  lea    D8(%rip),%rdx
  mov    %rbp,%r8
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%r12)
  mov    %r8,%rax
  addq   $0x1,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    $0x1,%edi
  call   <assert@plt>
  addq   $0x1,(%rbx)
  xor    %r8d,%r8d
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string

tool: 

tool: D8: _:s1 <http://example.org/p> _:o1 .
_:s2 <http://example.org/p> _:o2 .


assistant: ```c
size_t eof_test_read(void *buf, size_t size, size_t nmemb, void *stream) {
  assert(size == 1);
  assert(nmemb == 1);
  (void)size;
  static const char *const string = "_:s1 <http://example.org/p> _:o1 .\n"
                                    "_:s2 <http://example.org/p> _:o2 .\n";
  size_t *const count = (size_t *)stream;
  if (*count < 35) {
    *(char *)buf = string[*count];
    ++*count;
    return nmemb;
  }
  if (*count == 35) {
    assert(string[*count] == '_');
    ++*count;
    return 0;
  }
  if (*count >= strlen(string)) {
    return 0;
  }
  *(char *)buf = string[*count - 1];
  ++*count;
  return nmemb;
}
```