ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<divisible>:
  endbr64
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x3,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  shl    $0x2,%rax
  cmp    %rax,%rdi
  jne    L26
  mov    $0x13,%ecx
L3:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L20
  sub    $0x1,%rcx
  cmp    $0xa,%rcx
  jne    L3
  mov    $0x1,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool divisible(long n) {
  for (int i = 20; i >= 11; i--) {
    if (n % i != 0) {
      return false;
    }
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divisible>:
  endbr64
  mov    $0x14,%ecx
  nopl   0x0(%rax)
L18:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L7
  sub    $0x1,%rcx
  cmp    $0xa,%rcx
  jne    L18
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool divisible(long n) {
  for (int i = 20; i >= 11; i--) {
    if (n % i != 0) {
      return false;
    }
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<divisible>:
  endbr64
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  mov    %rdi,%rcx
  sar    $0x3f,%rdi
  imul   %rdx
  mov    %rcx,%rsi
  sar    $0x3,%rdx
  sub    %rdi,%rdx
  lea    (%rdx,%rdx,4),%rax
  movabs $0xd79435e50d79436,%rdx
  shl    $0x2,%rax
  sub    %rax,%rsi
  mov    %rcx,%rax
  imul   %rdx
  sub    %rdi,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  movabs $0xe38e38e38e38e39,%rdx
  or     %rax,%rsi
  mov    %rcx,%rax
  imul   %rdx
  sub    %rdi,%rdx
  lea    (%rdx,%rdx,8),%rax
  mov    %rcx,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  mov    %rcx,%rax
  or     %rdx,%rsi
  movabs $0x7878787878787879,%rdx
  imul   %rdx
  sar    $0x3,%rdx
  sub    %rdi,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  add    %rdx,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  or     %rdx,%rsi
  mov    %rdi,%rdx
  shr    $0x3c,%rdx
  lea    (%rcx,%rdx,1),%rax
  and    $0xf,%eax
  sub    %rdx,%rax
  movabs $0x8888888888888889,%rdx
  or     %rax,%rsi
  mov    %rcx,%rax
  imul   %rdx
  add    %rcx,%rdx
  sar    $0x3,%rdx
  sub    %rdi,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  or     %rdx,%rsi
  movabs $0x4924924924924925,%rdx
  imul   %rdx
  sar    $0x2,%rdx
  sub    %rdi,%rdx
  lea    0x0(,%rdx,8),%rax
  sub    %rdx,%rax
  mov    %rcx,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  mov    %rcx,%rax
  or     %rdx,%rsi
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  imul   %rdx
  sar    $0x2,%rdx
  sub    %rdi,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  movabs $0x2aaaaaaaaaaaaaab,%rdx
  or     %rax,%rsi
  mov    %rcx,%rax
  imul   %rdx
  sar    %rdx
  sub    %rdi,%rdx
  lea    (%rdx,%rdx,2),%rax
  mov    %rcx,%rdx
  shl    $0x2,%rax
  sub    %rax,%rdx
  mov    %rcx,%rax
  or     %rdx,%rsi
  movabs $0x2e8ba2e8ba2e8ba3,%rdx
  imul   %rdx
  sar    %rdx
  sub    %rdi,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rdx,%rax,2),%rax
  sub    %rax,%rcx
  xor    %eax,%eax
  or     %rcx,%rsi
  sete   %al
  ret
```

assistant: ```c
bool divisible(long n) {
  for (int i = 20; i >= 11; i--) {
    if (n % i != 0) {
      return false;
    }
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<retrieve_hyperplane_sections>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3d,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int retrieve_hyperplane_sections(int m, int k, int n, int i, double *c) {
  int a[3], fail;
  a[0] = m;
  a[1] = k;
  a[2] = n;
  fail = _ada_use_c2phc(61, a, &i, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<retrieve_hyperplane_sections>:
  endbr64
  sub    $0x38,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %r8,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edi,0x1c(%rsp)
  mov    %esi,0x20(%rsp)
  mov    %edx,0x24(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  mov    $0x3d,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int retrieve_hyperplane_sections(int m, int k, int n, int i, double *c) {
  int a[3], fail;
  a[0] = m;
  a[1] = k;
  a[2] = n;
  fail = _ada_use_c2phc(61, a, &i, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<retrieve_hyperplane_sections>:
  endbr64
  sub    $0x38,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %r8,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edi,0x1c(%rsp)
  mov    $0x3d,%edi
  mov    %esi,0x20(%rsp)
  lea    0x1c(%rsp),%rsi
  mov    %edx,0x24(%rsp)
  lea    0xc(%rsp),%rdx
  call   <_ada_use_c2phc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int retrieve_hyperplane_sections(int m, int k, int n, int i, double *c) {
  int a[3], fail;
  a[0] = m;
  a[1] = k;
  a[2] = n;
  fail = _ada_use_c2phc(61, a, &i, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<retrieve_hyperplane_sections>:
  endbr64
  sub    $0x38,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  mov    $0x3d,%edi
  mov    %ecx,0xc(%rsp)
  punpckldq %xmm1,%xmm0
  mov    %r8,%rcx
  lea    0x18(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edx,0x20(%rsp)
  lea    0xc(%rsp),%rdx
  movq   %xmm0,0x18(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int retrieve_hyperplane_sections(int m, int k, int n, int i, double *c) {
  int a[3], fail;
  a[0] = m;
  a[1] = k;
  a[2] = n;
  fail = _ada_use_c2phc(61, a, &i, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L16
L36:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L50
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jne    L24
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L62
L24:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  mov    %eax,%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  add    %edx,%eax
  movzbl %al,%eax
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L62
L50:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  mov    %eax,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  shl    $0x4,%eax
  and    $0xfffffff0,%eax
  or     %eax,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L62:
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L36
  movzbl -0x9(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
        } else {
          state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        }
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
        state[0UL] += state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] << (unsigned char)5;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  movzbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L27
  mov    $0x0,%edx
  jmp    L11
L23:
  mov    %eax,%ecx
  shl    $0x4,%ecx
  or     %ecx,%eax
  add    %eax,%eax
L16:
  add    $0x1,%edx
  cmp    %dil,%dl
  je     L27
L11:
  cmp    %dl,%al
  jbe    L23
  lea    0x0(,%rax,8),%ecx
  and    $0x38,%ecx
  or     %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  and    $0x78,%ecx
  or     %ecx,%eax
  jmp    L16
L27:
  shl    $0x5,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
        } else {
          state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        }
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
        state[0UL] += state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] << (unsigned char)5;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  add    $0x6a,%eax
  xor    $0xb,%eax
  test   %dil,%dil
  je     L23
  xor    %edx,%edx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L13:
  lea    0x0(,%rax,8),%ecx
  add    $0x1,%edx
  and    $0x38,%ecx
  or     %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  and    $0x78,%ecx
  or     %ecx,%eax
  cmp    %dil,%dl
  je     L23
L2:
  cmp    %dl,%al
  ja     L13
  mov    %eax,%ecx
  add    $0x1,%edx
  shl    $0x4,%ecx
  or     %ecx,%eax
  add    %eax,%eax
  cmp    %dil,%dl
  jne    L2
L23:
  shl    $0x5,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
        } else {
          state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        }
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
        state[0UL] += state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] << (unsigned char)5;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  add    $0x6a,%eax
  xor    $0xb,%eax
  test   %dil,%dil
  je     L22
  xor    %edx,%edx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L23:
  lea    0x0(,%rax,8),%ecx
  add    $0x1,%edx
  and    $0x38,%ecx
  or     %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  and    $0x78,%ecx
  or     %ecx,%eax
  cmp    %dl,%dil
  je     L22
L27:
  cmp    %al,%dl
  jb     L23
  mov    %eax,%ecx
  add    $0x1,%edx
  shl    $0x4,%ecx
  or     %ecx,%eax
  add    %eax,%eax
  cmp    %dl,%dil
  jne    L27
L22:
  shl    $0x5,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
        } else {
          state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        }
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
        state[0UL] += state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] << (unsigned char)5;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <wait4@plt>
  test   %rax,%rax
  jne    L38
  mov    $0x0,%eax
  jmp    L29
L38:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <WIFSIGNALED@plt>
  test   %eax,%eax
  je     L20
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <WTERMSIG@plt>
  mov    D9(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  je     L27
L20:
  lea    -0xc(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Read@plt>
  jmp    L29
L27:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int Wait(pid_t *pif, int *si, int i) {
  struct rusage ru;
  if (wait4(*pif, si, 0, &ru) == 0)
    return 0;
  if (!WIFSIGNALED(*si) || WTERMSIG(*si) != SIGKILL)
    return Read(pif, i, &ru);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Wait>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  mov    $0x0,%edx
  mov    (%rdi),%edi
  call   <wait4@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L15
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    (%rbx),%edi
  call   <WIFSIGNALED@plt>
  test   %eax,%eax
  je     L11
  mov    (%rbx),%edi
  call   <WTERMSIG@plt>
  mov    %rax,%rcx
  mov    $0x0,%eax
  mov    D2(%rip),%rdx
  cmp    (%rdx),%rcx
  je     L47
L11:
  lea    0x4(%rsp),%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <Read@plt>
  jmp    L47
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Wait(pid_t *pif, int *si, int i) {
  struct rusage ru;
  if (wait4(*pif, si, 0, &ru) == 0)
    return 0;
  if (!WIFSIGNALED(*si) || WTERMSIG(*si) != SIGKILL)
    return Read(pif, i, &ru);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Wait>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rcx
  call   <wait4@plt>
  test   %rax,%rax
  jne    L35
L31:
  xor    %eax,%eax
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%rbx),%edi
  call   <WIFSIGNALED@plt>
  test   %eax,%eax
  je     L39
  mov    (%rbx),%edi
  call   <WTERMSIG@plt>
  mov    D5(%rip),%rdx
  cmp    (%rdx),%rax
  je     L31
L39:
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <Read@plt>
  jmp    L46
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Wait(pid_t *pif, int *si, int i) {
  struct rusage ru;
  if (wait4(*pif, si, 0, &ru) == 0)
    return 0;
  if (!WIFSIGNALED(*si) || WTERMSIG(*si) != SIGKILL)
    return Read(pif, i, &ru);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Wait>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rcx
  call   <wait4@plt>
  test   %rax,%rax
  jne    L25
L34:
  xor    %eax,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    (%rbx),%edi
  call   <WIFSIGNALED@plt>
  test   %eax,%eax
  je     L18
  mov    (%rbx),%edi
  call   <WTERMSIG@plt>
  mov    D3(%rip),%rdx
  cmp    (%rdx),%rax
  je     L34
L18:
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <Read@plt>
  jmp    L2
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Wait(pid_t *pif, int *si, int i) {
  struct rusage ru;
  if (wait4(*pif, si, 0, &ru) == 0)
    return 0;
  if (!WIFSIGNALED(*si) || WTERMSIG(*si) != SIGKILL)
    return Read(pif, i, &ru);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar(void) {

#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wdeprecated-declarations"

  foo();

#pragma GCC diagnostic pop
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bar(void) {

#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wdeprecated-declarations"

  foo();

#pragma GCC diagnostic pop
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bar>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
void bar(void) {

#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wdeprecated-declarations"

  foo();

#pragma GCC diagnostic pop
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
void bar(void) {

#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wdeprecated-declarations"

  foo();

#pragma GCC diagnostic pop
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strMatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L73
L43:
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L76:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L68
  movl   $0x0,-0xc(%rbp)
  jmp    L72
L68:
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L76
L72:
  addl   $0x1,-0x14(%rbp)
L73:
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L81
  cmpl   $0x0,-0xc(%rbp)
  je     L43
L81:
  cmpl   $0x0,-0xc(%rbp)
  je     L82
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  jmp    L53
L82:
  mov    $0xffffffff,%eax
L53:
  leave
  ret
```

assistant: ```c
int strMatch(const char *s1, const char *s2) {
  int i, j, find = 0;
  int len1 = strlen(s1), len2 = strlen(s2);
  for (i = 0; i + len2 <= len1 && !find; i++) {
    find = 1;
    for (j = 0; j < len2; j++)
      if (s1[i + j] != s2[j]) {
        find = 0;
        break;
      }
  }
  if (find)
    return i - 1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strMatch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L86
  mov    %eax,%r8d
  mov    %rbx,%rsi
  mov    $0x0,%eax
  lea    -0x1(%r8),%edi
  mov    $0x0,%r9d
  jmp    L5
L0:
  mov    %rcx,%rdx
L8:
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rsi,%rdx,1)
  jne    L14
  lea    0x1(%rdx),%rcx
  cmp    %rdx,%rdi
  jne    L0
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  add    $0x1,%eax
  add    $0x1,%rsi
  lea    (%rax,%r8,1),%edx
  cmp    %edx,%r12d
  jl     L80
L5:
  test   %r8d,%r8d
  jle    L57
  mov    %r9,%rdx
  jmp    L8
L86:
  mov    $0xffffffff,%eax
  jmp    L57
L80:
  mov    $0xffffffff,%eax
  jmp    L57
```

assistant: ```c
int strMatch(const char *s1, const char *s2) {
  int i, j, find = 0;
  int len1 = strlen(s1), len2 = strlen(s2);
  for (i = 0; i + len2 <= len1 && !find; i++) {
    find = 1;
    for (j = 0; j < len2; j++)
      if (s1[i + j] != s2[j]) {
        find = 0;
        break;
      }
  }
  if (find)
    return i - 1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strMatch>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L21
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  movslq %eax,%rcx
  nopl   0x0(%rax)
L11:
  test   %eax,%eax
  jle    L0
  xor    %edx,%edx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  je     L0
L43:
  movzbl 0x0(%rbp,%rdx,1),%esi
  cmp    %sil,(%rdi,%rdx,1)
  je     L13
  add    $0x1,%r8d
  add    $0x1,%rdi
  lea    (%r8,%rax,1),%edx
  cmp    %edx,%r12d
  jge    L11
L21:
  mov    $0xffffffff,%r8d
L0:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strMatch(const char *s1, const char *s2) {
  int i, j, find = 0;
  int len1 = strlen(s1), len2 = strlen(s2);
  for (i = 0; i + len2 <= len1 && !find; i++) {
    find = 1;
    for (j = 0; j < len2; j++)
      if (s1[i + j] != s2[j]) {
        find = 0;
        break;
      }
  }
  if (find)
    return i - 1;
  return -1;
}
```