ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<walk>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <lstat@plt>
  test   %rax,%rax
  js     L117
  mov    0x14(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L81
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%r14
  add    %r12,%r14
  movb   $0x2f,(%r14)
  add    $0x1,%eax
  cltq
  add    %r12,%rax
  mov    %rax,0x8(%rsp)
  movb   $0x0,(%rax)
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L55
  lea    D29(%rip),%r13
  lea    D7(%rip),%r15
L34:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L44
  mov    %r13,%rsi
  mov    (%rbx),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  mov    %r15,%rsi
  mov    (%rbx),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  mov    (%rbx),%esi
  mov    0x8(%rsp),%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <walk>
  test   %eax,%eax
  je     L34
L44:
  movb   $0x0,(%r14)
  mov    %rbp,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  js     L3
  mov    $0x0,%eax
L72:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L123
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  mov    %r12,%rdi
  call   <suffix@plt>
  jmp    L72
L3:
  mov    %r12,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L72
L117:
  mov    $0xffffffff,%eax
  jmp    L72
L55:
  mov    $0xffffffff,%eax
  jmp    L72
L123:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D29
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D26
type_guessed: string

tool: D29: .

tool: D7: ..

tool: D26: can't close directory %s


assistant: ```c
int walk(char *path) {
  struct stat statbuf;
  struct dirent *dirp;
  DIR *dir;
  int n;
  if (lstat(path, &statbuf) < 0) {
    return -1;
  }
  if (S_ISDIR(statbuf.st_mode) == 0) {
    return suffix(path);
  }
  n = strlen(path);
  path[n++] = '/';
  path[n] = 0;
  if ((dir = opendir(path)) == NULL) {
    return -1;
  }
  while ((dirp = readdir(dir)) != NULL) {
    if (strcmp(dirp->d_name, ".") == 0 || strcmp(dirp->d_name, "..") == 0) {
      continue;
    }
    strcpy(&path[n], dirp->d_name);
    if (walk(path) != 0) {
      break;
    }
  }
  path[n - 1] = 0;
  if (closedir(dir) < 0) {
    printf("can't close directory %s\n", path);
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<walk>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <lstat@plt>
  test   %rax,%rax
  js     L52
  mov    0x14(%rsp),%edi
  call   <S_ISDIR@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  je     L1
  call   <strlen@plt>
  mov    %r12,%rdi
  lea    0x1(%rax),%ebx
  movslq %eax,%r14
  movslq %ebx,%rbx
  lea    (%r12,%r14,1),%rcx
  add    %r12,%rbx
  movb   $0x2f,(%rcx)
  movb   $0x0,(%rbx)
  mov    %rcx,0x8(%rsp)
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L52
  lea    D5(%rip),%r13
  lea    D13(%rip),%r15
  nop
L36:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L69
  mov    (%r14),%edi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L36
  mov    (%r14),%edi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L36
  mov    (%r14),%esi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <walk>
  test   %eax,%eax
  je     L36
  nopw   0x0(%rax,%rax,1)
L69:
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  movb   $0x0,(%rax)
  call   <closedir@plt>
  test   %rax,%rax
  js     L23
  xor    %eax,%eax
L92:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L73
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  call   <suffix@plt>
  jmp    L92
L23:
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
L52:
  mov    $0xffffffff,%eax
  jmp    L92
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string

tool: D5: .

tool: D13: ..

tool: D6: can't close directory %s


assistant: ```c
int walk(char *path) {
  struct stat statbuf;
  struct dirent *dirp;
  DIR *dir;
  int n;
  if (lstat(path, &statbuf) < 0) {
    return -1;
  }
  if (S_ISDIR(statbuf.st_mode) == 0) {
    return suffix(path);
  }
  n = strlen(path);
  path[n++] = '/';
  path[n] = 0;
  if ((dir = opendir(path)) == NULL) {
    return -1;
  }
  while ((dirp = readdir(dir)) != NULL) {
    if (strcmp(dirp->d_name, ".") == 0 || strcmp(dirp->d_name, "..") == 0) {
      continue;
    }
    strcpy(&path[n], dirp->d_name);
    if (walk(path) != 0) {
      break;
    }
  }
  path[n - 1] = 0;
  if (closedir(dir) < 0) {
    printf("can't close directory %s\n", path);
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<walk>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <lstat@plt>
  test   %rax,%rax
  js     L96
  mov    0x14(%rsp),%edi
  call   <S_ISDIR@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  je     L48
  call   <strlen@plt>
  mov    %r12,%rdi
  lea    0x1(%rax),%ebx
  movslq %eax,%r14
  movslq %ebx,%rbx
  lea    (%r12,%r14,1),%rcx
  add    %r12,%rbx
  movb   $0x2f,(%rcx)
  movb   $0x0,(%rbx)
  mov    %rcx,0x8(%rsp)
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L96
  lea    D19(%rip),%r13
  lea    D27(%rip),%r15
  nop
L57:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L25
  mov    (%r14),%edi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L57
  mov    (%r14),%edi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L57
  mov    (%r14),%esi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <walk>
  test   %eax,%eax
  je     L57
  nopw   0x0(%rax,%rax,1)
L25:
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  movb   $0x0,(%rax)
  call   <closedir@plt>
  test   %rax,%rax
  js     L90
  xor    %eax,%eax
L89:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  call   <suffix@plt>
  jmp    L89
L90:
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L96:
  mov    $0xffffffff,%eax
  jmp    L89
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D27
type_infered: string
name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D19: .

tool: D27: ..

tool: D3: can't close directory %s


assistant: ```c
int walk(char *path) {
  struct stat statbuf;
  struct dirent *dirp;
  DIR *dir;
  int n;
  if (lstat(path, &statbuf) < 0) {
    return -1;
  }
  if (S_ISDIR(statbuf.st_mode) == 0) {
    return suffix(path);
  }
  n = strlen(path);
  path[n++] = '/';
  path[n] = 0;
  if ((dir = opendir(path)) == NULL) {
    return -1;
  }
  while ((dirp = readdir(dir)) != NULL) {
    if (strcmp(dirp->d_name, ".") == 0 || strcmp(dirp->d_name, "..") == 0) {
      continue;
    }
    strcpy(&path[n], dirp->d_name);
    if (walk(path) != 0) {
      break;
    }
  }
  path[n - 1] = 0;
  if (closedir(dir) < 0) {
    printf("can't close directory %s\n", path);
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EncodeBase64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  lea    -0x100(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1d,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  mov    %ax,(%rdx)
  add    $0x2,%rdx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movl   $0x0,-0x114(%rbp)
  lea    -0x110(%rbp),%rcx
  mov    -0x128(%rbp),%rax
  mov    $0xff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Base64Encode@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D9: 


assistant: ```c
void EncodeBase64(char *str) {
  char buf[255] = "";
  int b = 0;
  Base64Encode(str, buf, 255);
  printf(buf);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EncodeBase64>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x1d,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movw   $0x0,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  mov    %rsp,%rbx
  mov    $0xff,%edx
  mov    %rbx,%rsi
  mov    %r8,%rdi
  call   <Base64Encode@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x110,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: 


assistant: ```c
void EncodeBase64(char *str) {
  char buf[255] = "";
  int b = 0;
  Base64Encode(str, buf, 255);
  printf(buf);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EncodeBase64>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    $0x1d,%ecx
  pxor   %xmm0,%xmm0
  mov    $0xff,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  mov    %rbp,%rsi
  rep stos %rax,%es:(%rdi)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %ax,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  mov    %r8,%rdi
  call   <Base64Encode@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x110,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: 


assistant: ```c
void EncodeBase64(char *str) {
  char buf[255] = "";
  int b = 0;
  Base64Encode(str, buf, 255);
  printf(buf);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EncodeBase64>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    $0x1d,%ecx
  pxor   %xmm0,%xmm0
  mov    $0xff,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  mov    %rbp,%rsi
  rep stos %rax,%es:(%rdi)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %ax,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  mov    %r8,%rdi
  call   <Base64Encode@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: 


assistant: ```c
void EncodeBase64(char *str) {
  char buf[255] = "";
  int b = 0;
  Base64Encode(str, buf, 255);
  printf(buf);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Hello World!


assistant: ```c
int main(int c, char **v) {
  printf("Hello World!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Hello World!


assistant: ```c
int main(int c, char **v) {
  printf("Hello World!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: Hello World!


assistant: ```c
int main(int c, char **v) {
  printf("Hello World!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: Hello World!


assistant: ```c
int main(int c, char **v) {
  printf("Hello World!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mm>:
  endbr64
  cmp    $0xfffffffd,%r8d
  jl     L90
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r10
  mov    %r8d,%r14d
  mov    %r9d,%edi
  sub    $0x20,%rbp
  lea    -0x20(%rdx),%r9
  lea    0x4(%r8),%eax
  mov    %eax,-0x4(%rsp)
  lea    -0x1(%rdi),%eax
  lea    0x4(,%rax,4),%r15
  lea    -0x1(%rcx),%eax
  lea    0x4(,%rax,4),%r13
  lea    -0x2(%rcx),%eax
  lea    0x8(,%rax,4),%r12
  mov    $0x0,%ebx
  mov    %edi,%eax
  mov    %ecx,%edi
  mov    %eax,%esi
  jmp    L97
L122:
  cmp    $0x3,%ebx
  jg     L9
L148:
  add    $0x4,%rax
  cmp    %r15,%rax
  je     L36
L87:
  cmp    %ebx,%r14d
  jle    L122
  mov    %r9,%r8
  mov    0x20(%r9),%rdx
  movl   $0x0,(%rdx,%rax,1)
  cmp    $0x3,%ebx
  jle    L148
  mov    %rax,%rdx
  add    (%r9),%rdx
  mov    %rbp,%r11
  mov    0x0(%rbp),%rcx
  mov    %rcx,-0x10(%rsp)
  mov    (%r10),%rcx
  movss  (%rcx,%rax,1),%xmm0
  mov    -0x10(%rsp),%rcx
  mulss  (%rcx),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  cmp    $0x1,%esi
  jle    L148
  mov    $0x4,%edx
  mov    %esi,-0x10(%rsp)
L34:
  mov    %rax,%rcx
  add    (%r8),%rcx
  mov    (%r11),%rsi
  movss  (%rsi,%rdx,1),%xmm0
  mov    (%r10,%rdx,2),%rsi
  mulss  (%rsi,%rax,1),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rdx
  cmp    %r12,%rdx
  jne    L34
  mov    -0x10(%rsp),%esi
  jmp    L148
L9:
  test   %esi,%esi
  jle    L148
  mov    $0x0,%edx
L144:
  mov    %rax,%rcx
  add    (%r9),%rcx
  mov    0x0(%rbp),%r11
  mov    (%r10,%rdx,2),%r8
  movss  (%r11,%rdx,1),%xmm0
  mulss  (%r8,%rax,1),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rdx
  cmp    %r13,%rdx
  jne    L144
  jmp    L148
L36:
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %eax,%esi
L70:
  add    $0x1,%ebx
  add    $0x8,%rbp
  add    $0x8,%r9
  cmp    -0x4(%rsp),%ebx
  je     L14
L97:
  mov    $0x0,%eax
  test   %esi,%esi
  jle    L70
  mov    %esi,%edx
  mov    %edi,%esi
  mov    %edx,%edi
  jmp    L87
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L90:
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int t6;
  int t4;
  int t2;
  int i;
  int j;
  int n;
  for (t2 = 0; t2 <= an + 3; t2 += 1)
    for (t4 = 0; t4 <= bm - 1; t4 += 1)
      if (t2 + 1 <= an) {
        C[t2][t4] = 0.0f;
        if (4 <= t2)
          C[t2 - 4][t4] += (A[t2 - 4][0] * B[0][t4]);
        if (4 <= t2)
          for (t6 = 1; t6 <= ambn - 1; t6 += 1)
            C[t2 - 4][t4] += (A[t2 - 4][t6] * B[t6][t4]);
      } else if (4 <= t2)
        for (t6 = 0; t6 <= ambn - 1; t6 += 1)
          C[t2 - 4][t4] += (A[t2 - 4][t6] * B[t6][t4]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mm>:
  endbr64
  cmp    $0xfffffffd,%r8d
  jl     L34
  push   %r15
  lea    -0x1(%r9),%eax
  xor    %r10d,%r10d
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  lea    0x4(,%rax,4),%r9
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  lea    -0x20(%rdx),%r8
  push   %rbx
  lea    0x3(%rbp),%r14d
  mov    %rdi,%rbx
  movslq %ecx,%rdi
  xchg   %ax,%ax
L71:
  xor    %edx,%edx
  test   %r13d,%r13d
  jle    L120
  nopw   0x0(%rax,%rax,1)
L1:
  cmp    %ebp,%r10d
  jge    L16
  mov    0x20(%r8),%rax
  movl   $0x0,(%rax,%rdx,1)
  cmp    $0x3,%r10d
  jle    L77
  mov    (%r8),%rcx
  mov    -0x20(%rbx,%r10,8),%r11
  mov    (%rsi),%rax
  add    %rdx,%rcx
  movss  (%rax,%rdx,1),%xmm0
  mulss  (%r11),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  cmp    $0x1,%r12d
  jle    L77
  mov    $0x1,%eax
  nopl   (%rax)
L8:
  mov    (%rsi,%rax,8),%r15
  movss  (%r15,%rdx,1),%xmm1
  mulss  (%r11,%rax,4),%xmm1
  add    $0x1,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
  cmp    %rdi,%rax
  jne    L8
L77:
  add    $0x4,%rdx
  cmp    %rdx,%r9
  jne    L1
L120:
  lea    0x1(%r10),%rax
  add    $0x8,%r8
  cmp    %r10,%r14
  je     L111
  mov    %rax,%r10
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    $0x3,%r10d
  jle    L77
  test   %r12d,%r12d
  jle    L77
  mov    (%r8),%rcx
  mov    -0x20(%rbx,%r10,8),%r11
  xor    %eax,%eax
  add    %rdx,%rcx
  movss  (%rcx),%xmm1
  nopl   0x0(%rax)
L108:
  mov    (%rsi,%rax,8),%r15
  movss  (%r15,%rdx,1),%xmm0
  mulss  (%r11,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  cmp    %rax,%rdi
  jne    L108
  add    $0x4,%rdx
  cmp    %rdx,%r9
  jne    L1
  jmp    L120
L111:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int t6;
  int t4;
  int t2;
  int i;
  int j;
  int n;
  for (t2 = 0; t2 <= an + 3; t2 += 1)
    for (t4 = 0; t4 <= bm - 1; t4 += 1)
      if (t2 + 1 <= an) {
        C[t2][t4] = 0.0f;
        if (4 <= t2)
          C[t2 - 4][t4] += (A[t2 - 4][0] * B[0][t4]);
        if (4 <= t2)
          for (t6 = 1; t6 <= ambn - 1; t6 += 1)
            C[t2 - 4][t4] += (A[t2 - 4][t6] * B[t6][t4]);
      } else if (4 <= t2)
        for (t6 = 0; t6 <= ambn - 1; t6 += 1)
          C[t2 - 4][t4] += (A[t2 - 4][t6] * B[t6][t4]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mm>:
  endbr64
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  add    $0x3,%r13d
  js     L13
  test   %r9d,%r9d
  jle    L13
  mov    %rdi,%r12
  mov    $0x3,%edi
  movslq %r9d,%r9
  mov    %ecx,%ebp
  cmp    %edi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rcx
  cmovle %r13d,%edi
  lea    0x0(,%r9,4),%r11
  xor    %r10d,%r10d
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L158:
  cmp    %r10d,%r8d
  jle    L88
  mov    (%rcx),%rdx
  movl   $0x0,(%rdx,%rax,1)
L88:
  add    $0x4,%rax
  cmp    %r11,%rax
  jne    L158
  add    $0x1,%r10d
  add    $0x8,%rcx
  cmp    %edi,%r10d
  jle    L33
  cmp    %r13d,%r10d
  jg     L13
  movslq %r10d,%rax
  lea    0x4(%r8),%r13d
  movslq %ebp,%r9
  shl    $0x3,%rax
  add    %rax,%rbx
  add    %rax,%r12
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L140:
  cmp    %r10d,%r8d
  jle    L2
  mov    (%rbx),%rax
  mov    -0x20(%rbx),%rcx
  mov    -0x20(%r12),%rdi
  movl   $0x0,(%rax,%rdx,1)
  mov    (%rsi),%rax
  add    %rdx,%rcx
  movss  (%rax,%rdx,1),%xmm0
  mulss  (%rdi),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  cmp    $0x1,%ebp
  jle    L3
  mov    $0x1,%eax
  nopl   (%rax)
L47:
  mov    (%rsi,%rax,8),%r14
  movss  (%r14,%rdx,1),%xmm1
  mulss  (%rdi,%rax,4),%xmm1
  add    $0x1,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
  cmp    %rax,%r9
  jne    L47
L3:
  add    $0x4,%rdx
  cmp    %r11,%rdx
  jne    L140
L103:
  add    $0x1,%r10d
  add    $0x8,%rbx
  add    $0x8,%r12
  cmp    %r13d,%r10d
  jne    L16
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L2:
  cmp    $0x3,%r10d
  jle    L3
  test   %ebp,%ebp
  jle    L3
  mov    -0x20(%rbx),%rdi
  mov    -0x20(%r12),%r14
  xor    %eax,%eax
  add    %rdx,%rdi
  movss  (%rdi),%xmm1
  nopl   0x0(%rax)
L117:
  mov    (%rsi,%rax,8),%rcx
  movss  (%rcx,%rdx,1),%xmm0
  mulss  (%r14,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    %r9,%rax
  jne    L117
  add    $0x4,%rdx
  cmp    %r11,%rdx
  jne    L140
  jmp    L103
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int t6;
  int t4;
  int t2;
  int i;
  int j;
  int n;
  for (t2 = 0; t2 <= an + 3; t2 += 1)
    for (t4 = 0; t4 <= bm - 1; t4 += 1)
      if (t2 + 1 <= an) {
        C[t2][t4] = 0.0f;
        if (4 <= t2)
          C[t2 - 4][t4] += (A[t2 - 4][0] * B[0][t4]);
        if (4 <= t2)
          for (t6 = 1; t6 <= ambn - 1; t6 += 1)
            C[t2 - 4][t4] += (A[t2 - 4][t6] * B[t6][t4]);
      } else if (4 <= t2)
        for (t6 = 0; t6 <= ambn - 1; t6 += 1)
          C[t2 - 4][t4] += (A[t2 - 4][t6] * B[t6][t4]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<llvm_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  jmp    L38
L37:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
L38:
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L37
  jmp    L27
L50:
  nop
L27:
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  cmpq   $0x0,-0x38(%rbp)
  je     L0
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L0:
  nop
L45:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
L8:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t llvm_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<llvm_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L10
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
L49:
  cmp    %rcx,%rdi
  je     L32
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L49
  jmp    L11
L10:
  mov    %rsi,%rax
L55:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L55
L11:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L32:
  movb   $0x0,(%rdi)
  jmp    L55
```

assistant: ```c
size_t llvm_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```