ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<heapify>:
  endbr64
  mov    %rdi,%rcx
  jmp    L20
  nopl   0x0(%rax)
L7:
  movslq %esi,%r8
  movslq %edi,%r9
  mov    (%rcx,%r8,4),%r11d
  cmp    %r11d,(%rcx,%r9,4)
  jle    L51
  cmp    %edx,%eax
  jle    L47
  mov    %edi,%eax
L16:
  cmp    %esi,%eax
  je     L19
  movslq %eax,%rsi
  lea    (%rcx,%rsi,4),%rdi
  lea    (%rcx,%r8,4),%rsi
  mov    (%rsi),%r8d
  mov    (%rdi),%r9d
  mov    %r8d,(%rdi)
  mov    %r9d,(%rsi)
  mov    %eax,%esi
L20:
  lea    (%rsi,%rsi,1),%edi
  lea    0x1(%rdi),%eax
  cmp    %edx,%edi
  jle    L7
L51:
  cmp    %edx,%eax
  jg     L19
  movslq %esi,%r8
  movslq %eax,%rdi
  mov    (%rcx,%r8,4),%r10d
  cmp    %r10d,(%rcx,%rdi,4)
  jg     L16
L19:
  ret
L47:
  movslq %eax,%r10
  mov    (%rcx,%r9,4),%r11d
  cmp    %r11d,(%rcx,%r10,4)
  cmovle %edi,%eax
  jmp    L16
```

assistant: ```c
void heapify(int a[], int i, int heap_size) {
  int left = 2 * i;
  int right = 2 * i + 1;
  int max = i;
  if (left <= heap_size && a[left] > a[max]) {
    max = left;
  }
  if (right <= heap_size && a[right] > a[max]) {
    max = right;
  }
  if (max != i) {
    int temp = a[max];
    a[max] = a[i];
    a[i] = temp;
    heapify(a, max, heap_size);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heapify>:
  endbr64
  mov    %rdi,%rcx
  jmp    L1
  nopl   0x0(%rax)
L31:
  movslq %eax,%r10
  movslq %esi,%r11
  lea    (%rcx,%r10,4),%r8
  mov    (%r8),%edi
  cmp    (%rcx,%r11,4),%edi
  jle    L69
  cmp    %edx,%r9d
  jle    L35
L67:
  cmp    %esi,%eax
  je     L10
  movslq %esi,%rsi
  lea    (%rcx,%rsi,4),%rsi
  mov    (%rsi),%r9d
  mov    %r9d,(%r8)
  mov    %edi,(%rsi)
  mov    %eax,%esi
L1:
  lea    (%rsi,%rsi,1),%eax
  lea    0x1(%rax),%r9d
  cmp    %edx,%eax
  jle    L31
L69:
  cmp    %edx,%r9d
  jg     L10
  mov    %esi,%eax
  movslq %esi,%r10
L35:
  movslq %r9d,%rdi
  lea    (%rcx,%r10,4),%r10
  lea    (%rcx,%rdi,4),%r8
  mov    (%r10),%r11d
  mov    (%r8),%edi
  cmp    %r11d,%edi
  jg     L16
  mov    %r11d,%edi
  mov    %r10,%r8
  jmp    L67
L16:
  mov    %r9d,%eax
  jmp    L67
  nopl   (%rax)
L10:
  ret
```

assistant: ```c
void heapify(int a[], int i, int heap_size) {
  int left = 2 * i;
  int right = 2 * i + 1;
  int max = i;
  if (left <= heap_size && a[left] > a[max]) {
    max = left;
  }
  if (right <= heap_size && a[right] > a[max]) {
    max = right;
  }
  if (max != i) {
    int temp = a[max];
    a[max] = a[i];
    a[i] = temp;
    heapify(a, max, heap_size);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D66(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  mov    0x10(%rsp),%r12d
  xor    %eax,%eax
  mov    0x14(%rsp),%ebp
  lea    D27(%rip),%rdi
  lea    (%rbx,%r12,1),%esi
  imul   %r12d,%ebx
  add    %ebp,%esi
  call   <printf@plt>
  lea    D74(%rip),%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  imul   %ebp,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%r9d
  cmp    %r8d,%esi
  jge    L121
  cmp    %r9d,%esi
  jl     L89
  cmp    %r8d,%esi
  cmovg  %r8d,%esi
  cmp    %esi,%r9d
  jl     L109
L134:
  mov    %r8d,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L121:
  mov    %r9d,%r10d
  jle    L46
  cmp    %r9d,%r8d
  jl     L21
  cmp    %r8d,%esi
  cmovle %esi,%r8d
  cmp    %r9d,%r8d
  jg     L109
L163:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  cmp    %r9d,%esi
  jle    L56
L109:
  mov    %r9d,%esi
L89:
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L66:
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%r10d
  cmp    %r8d,%esi
  jle    L149
  cmp    %r10d,%esi
  jg     L163
L56:
  cmp    %r8d,%esi
  cmovl  %r8d,%esi
  cmp    %esi,%r10d
  jle    L18
  mov    %r10d,%esi
  jmp    L163
L149:
  jge    L56
  cmp    %r10d,%r8d
  jle    L56
  jmp    L134
L21:
  mov    %r8d,%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L66
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D66
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D74
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D55
type_guessed: string

tool: D66: Wprowadz trzy liczby calkowite: 

tool: D25: %d %d %d

tool: D27: Suma wynosi: %d


tool: D74: Iloczyn wynosi: %d


tool: D12: Najwieksza liczba to: %d


tool: D55: Najmniejsza liczba to: %d


assistant: ```c
int main() {
  int a, b, c, suma, iloczyn;
  char *msg1 = "Najwieksza liczba to: %d\n";
  char *msg2 = "Najmniejsza liczba to: %d\n";
  printf("Wprowadz trzy liczby calkowite: ");
  scanf("%d %d %d", &a, &b, &c);
  suma = a + b + c;
  iloczyn = a * b * c;
  printf("Suma wynosi: %d\n", suma);
  printf("Iloczyn wynosi: %d\n", iloczyn);
  if (a < b && a < c) {
    printf(msg2, a);
  } else if (b < a && b < c) {
    printf(msg2, b);
  } else if (c < b && c < a) {
    printf(msg2, c);
  }
  if (a > b && a > c) {
    printf(msg1, a);
  } else if (b > a && b > c) {
    printf(msg1, b);
  } else if (c > b && c > a) {
    printf(msg1, c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<random_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L62
  cmpq   $0x0,-0x40(%rbp)
  je     L62
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  jne    L23
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  imul   $0x41c64e6d,%eax,%eax
  add    $0x3039,%eax
  and    $0x7fffffff,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L3
L23:
  mov    -0x38(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0x20(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L54
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  addq   $0x4,-0x18(%rbp)
  jmp    L15
L54:
  addq   $0x4,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L15
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L15:
  mov    -0x38(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,0x10(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,0x18(%rax)
L3:
  mov    $0x0,%eax
  jmp    L22
L62:
  nop
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
L22:
  leave
  ret
```

assistant: ```c
int random_r(struct random_data *buf, int32_t *result) {
  int32_t *state;
  if (buf == NULL || result == NULL)
    goto fail;
  state = buf->state;
  if (buf->rand_type == 0) {
    int32_t val = state[0];
    val = ((state[0] * 1103515245) + 12345) & 0x7fffffff;
    state[0] = val;
    *result = val;
  } else {
    int32_t *fptr = buf->fptr;
    int32_t *rptr = buf->rptr;
    int32_t *end_ptr = buf->end_ptr;
    int32_t val;
    val = *fptr += *rptr;
    *result = (val >> 1) & 0x7fffffff;
    ++fptr;
    if (fptr >= end_ptr) {
      fptr = state;
      ++rptr;
    } else {
      ++rptr;
      if (rptr >= end_ptr)
        rptr = state;
    }
    buf->fptr = fptr;
    buf->rptr = rptr;
  }
  return 0;
fail:
  __set_errno(EINVAL);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random_r>:
  endbr64
  test   %rdi,%rdi
  je     L35
  test   %rsi,%rsi
  je     L35
  mov    (%rdi),%r8
  cmpq   $0x0,0x8(%rdi)
  jne    L10
  imul   $0x41c64e6d,(%r8),%eax
  add    $0x3039,%eax
  and    $0x7fffffff,%eax
  mov    %eax,(%r8)
  mov    %eax,(%rsi)
  mov    $0x0,%eax
  ret
L35:
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L10:
  mov    0x10(%rdi),%rax
  mov    0x18(%rdi),%rcx
  mov    0x20(%rdi),%r9
  mov    (%rcx),%edx
  add    (%rax),%edx
  mov    %edx,(%rax)
  shr    %edx
  mov    %edx,(%rsi)
  add    $0x4,%rax
  cmp    %rax,%r9
  ja     L32
  lea    0x4(%rcx),%rdx
  mov    %r8,%rax
L6:
  mov    %rax,0x10(%rdi)
  mov    %rdx,0x18(%rdi)
  mov    $0x0,%eax
  ret
L32:
  lea    0x4(%rcx),%rdx
  cmp    %rdx,%r9
  cmovbe %r8,%rdx
  jmp    L6
```

assistant: ```c
int random_r(struct random_data *buf, int32_t *result) {
  int32_t *state;
  if (buf == NULL || result == NULL)
    goto fail;
  state = buf->state;
  if (buf->rand_type == 0) {
    int32_t val = state[0];
    val = ((state[0] * 1103515245) + 12345) & 0x7fffffff;
    state[0] = val;
    *result = val;
  } else {
    int32_t *fptr = buf->fptr;
    int32_t *rptr = buf->rptr;
    int32_t *end_ptr = buf->end_ptr;
    int32_t val;
    val = *fptr += *rptr;
    *result = (val >> 1) & 0x7fffffff;
    ++fptr;
    if (fptr >= end_ptr) {
      fptr = state;
      ++rptr;
    } else {
      ++rptr;
      if (rptr >= end_ptr)
        rptr = state;
    }
    buf->fptr = fptr;
    buf->rptr = rptr;
  }
  return 0;
fail:
  __set_errno(EINVAL);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<random_r>:
  endbr64
  test   %rdi,%rdi
  je     L2
  test   %rsi,%rsi
  je     L2
  cmpq   $0x0,0x8(%rdi)
  mov    (%rdi),%r8
  je     L13
  mov    0x10(%rdi),%rdx
  mov    0x18(%rdi),%rcx
  mov    0x20(%rdi),%r9
  mov    (%rcx),%eax
  add    (%rdx),%eax
  add    $0x4,%rdx
  add    $0x4,%rcx
  mov    %eax,-0x4(%rdx)
  shr    %eax
  mov    %eax,(%rsi)
  cmp    %rdx,%r9
  jbe    L27
  cmp    %rcx,%r9
  ja     L11
  mov    %r8,%rcx
  mov    %rdx,%r8
L27:
  mov    %r8,0x10(%rdi)
  xor    %eax,%eax
  mov    %rcx,0x18(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  imul   $0x41c64e6d,(%r8),%eax
  add    $0x3039,%eax
  and    $0x7fffffff,%eax
  mov    %eax,(%r8)
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L11:
  mov    %rdx,%r8
  mov    %rcx,0x18(%rdi)
  xor    %eax,%eax
  mov    %r8,0x10(%rdi)
  ret
L2:
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int random_r(struct random_data *buf, int32_t *result) {
  int32_t *state;
  if (buf == NULL || result == NULL)
    goto fail;
  state = buf->state;
  if (buf->rand_type == 0) {
    int32_t val = state[0];
    val = ((state[0] * 1103515245) + 12345) & 0x7fffffff;
    state[0] = val;
    *result = val;
  } else {
    int32_t *fptr = buf->fptr;
    int32_t *rptr = buf->rptr;
    int32_t *end_ptr = buf->end_ptr;
    int32_t val;
    val = *fptr += *rptr;
    *result = (val >> 1) & 0x7fffffff;
    ++fptr;
    if (fptr >= end_ptr) {
      fptr = state;
      ++rptr;
    } else {
      ++rptr;
      if (rptr >= end_ptr)
        rptr = state;
    }
    buf->fptr = fptr;
    buf->rptr = rptr;
  }
  return 0;
fail:
  __set_errno(EINVAL);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<random_r>:
  endbr64
  test   %rdi,%rdi
  je     L5
  test   %rsi,%rsi
  je     L5
  cmpq   $0x0,0x8(%rdi)
  mov    (%rdi),%rax
  je     L30
  mov    0x10(%rdi),%rcx
  mov    0x18(%rdi),%r8
  mov    0x20(%rdi),%r9
  mov    (%r8),%edx
  add    (%rcx),%edx
  add    $0x4,%rcx
  add    $0x4,%r8
  mov    %edx,-0x4(%rcx)
  shr    %edx
  mov    %edx,(%rsi)
  cmp    %rcx,%r9
  jbe    L55
  cmp    %r8,%r9
  ja     L20
  mov    %rax,%r8
  mov    %rcx,%rax
L55:
  movq   %rax,%xmm0
  movq   %r8,%xmm1
  xor    %eax,%eax
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,0x10(%rdi)
  ret
  nopl   (%rax)
L30:
  imul   $0x41c64e6d,(%rax),%edx
  add    $0x3039,%edx
  and    $0x7fffffff,%edx
  mov    %edx,(%rax)
  xor    %eax,%eax
  mov    %edx,(%rsi)
  ret
  nopl   0x0(%rax)
L20:
  mov    %rcx,%rax
  jmp    L55
L5:
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int random_r(struct random_data *buf, int32_t *result) {
  int32_t *state;
  if (buf == NULL || result == NULL)
    goto fail;
  state = buf->state;
  if (buf->rand_type == 0) {
    int32_t val = state[0];
    val = ((state[0] * 1103515245) + 12345) & 0x7fffffff;
    state[0] = val;
    *result = val;
  } else {
    int32_t *fptr = buf->fptr;
    int32_t *rptr = buf->rptr;
    int32_t *end_ptr = buf->end_ptr;
    int32_t val;
    val = *fptr += *rptr;
    *result = (val >> 1) & 0x7fffffff;
    ++fptr;
    if (fptr >= end_ptr) {
      fptr = state;
      ++rptr;
    } else {
      ++rptr;
      if (rptr >= end_ptr)
        rptr = state;
    }
    buf->fptr = fptr;
    buf->rptr = rptr;
  }
  return 0;
fail:
  __set_errno(EINVAL);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__pok_partition_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <main@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __pok_partition_start() {
  main();
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__pok_partition_start>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <main@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __pok_partition_start() {
  main();
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__pok_partition_start>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __pok_partition_start() {
  main();
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__pok_partition_start>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __pok_partition_start() {
  main();
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<countc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %esi,%edx
  mov    %dl,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L16
L23:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  cmp    %dl,-0x14(%rbp)
  jne    L16
  movzbl -0x1(%rbp),%edx
  add    $0x1,%edx
  mov    %dl,-0x1(%rbp)
L16:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L23
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char countc(register char *s, char c) {
  char n = 0;
  while (*s)
    if (*s++ == c)
      n++;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<countc>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  mov    $0x0,%edx
L19:
  add    $0x1,%rdi
  lea    0x1(%rdx),%ecx
  cmp    %al,%sil
  cmove  %ecx,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
L0:
  mov    %edx,%eax
  ret
L12:
  mov    %eax,%edx
  jmp    L0
```

assistant: ```c
char countc(register char *s, char c) {
  char n = 0;
  while (*s)
    if (*s++ == c)
      n++;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<countc>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  xchg   %ax,%ax
L0:
  add    $0x1,%rdi
  cmp    %al,%sil
  lea    0x1(%r8),%edx
  movzbl (%rdi),%eax
  cmove  %edx,%r8d
  test   %al,%al
  jne    L0
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char countc(register char *s, char c) {
  char n = 0;
  while (*s)
    if (*s++ == c)
      n++;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<countc>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L2
  xchg   %ax,%ax
L10:
  add    $0x1,%rdi
  cmp    %sil,%al
  lea    0x1(%r8),%edx
  movzbl (%rdi),%eax
  cmove  %edx,%r8d
  test   %al,%al
  jne    L10
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char countc(register char *s, char c) {
  char n = 0;
  while (*s)
    if (*s++ == c)
      n++;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_uvp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %ecx,%r8d
  mov    $0x0,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <init_matrix@plt>
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %ecx,%r8d
  mov    $0x0,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <init_matrix@plt>
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %ecx,%r8d
  mov    $0x0,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <init_matrix@plt>
  nop
  leave
  ret
```

assistant: ```c
void init_uvp(double UI, double VI, double PI, int imax, int jmax, double **U, double **V, double **P, char *problem) {
  init_matrix(U, 0, imax + 1, 0, jmax + 1, UI);
  init_matrix(V, 0, imax + 1, 0, jmax + 1, VI);
  init_matrix(P, 0, imax + 1, 0, jmax + 1, PI);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_uvp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm1,%r15
  movq   %xmm2,%r13
  mov    %edi,%ebx
  mov    %rdx,%rdi
  mov    %rcx,%r14
  mov    %r8,%r12
  lea    0x1(%rsi),%ebp
  add    $0x1,%ebx
  mov    %ebp,%r8d
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  call   <init_matrix@plt>
  movq   %r15,%xmm0
  mov    %ebp,%r8d
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <init_matrix@plt>
  movq   %r13,%xmm0
  mov    %ebp,%r8d
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <init_matrix@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void init_uvp(double UI, double VI, double PI, int imax, int jmax, double **U, double **V, double **P, char *problem) {
  init_matrix(U, 0, imax + 1, 0, jmax + 1, UI);
  init_matrix(V, 0, imax + 1, 0, jmax + 1, VI);
  init_matrix(P, 0, imax + 1, 0, jmax + 1, PI);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_uvp>:
  endbr64
  push   %r13
  mov    %rdx,%r9
  mov    %rcx,%r13
  xor    %ecx,%ecx
  push   %r12
  lea    0x1(%rdi),%r12d
  mov    %r9,%rdi
  push   %rbp
  mov    %r12d,%edx
  mov    %r8,%rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  xor    %esi,%esi
  mov    %ebx,%r8d
  sub    $0x18,%rsp
  movsd  %xmm2,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <init_matrix@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%r8d
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %esi,%esi
  movapd %xmm1,%xmm0
  call   <init_matrix@plt>
  movsd  (%rsp),%xmm2
  add    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %ebx,%r8d
  mov    %r12d,%edx
  pop    %rbx
  mov    %rbp,%rdi
  movapd %xmm2,%xmm0
  pop    %rbp
  xor    %esi,%esi
  pop    %r12
  pop    %r13
  jmp    1050 <init_matrix@plt>
```

assistant: ```c
void init_uvp(double UI, double VI, double PI, int imax, int jmax, double **U, double **V, double **P, char *problem) {
  init_matrix(U, 0, imax + 1, 0, jmax + 1, UI);
  init_matrix(V, 0, imax + 1, 0, jmax + 1, VI);
  init_matrix(P, 0, imax + 1, 0, jmax + 1, PI);
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_uvp>:
  endbr64
  push   %r13
  mov    %rdx,%r9
  mov    %rcx,%r13
  xor    %ecx,%ecx
  push   %r12
  lea    0x1(%rdi),%r12d
  mov    %r9,%rdi
  push   %rbp
  mov    %r12d,%edx
  mov    %r8,%rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  xor    %esi,%esi
  mov    %ebx,%r8d
  sub    $0x18,%rsp
  movsd  %xmm2,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <init_matrix@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%r8d
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %esi,%esi
  movapd %xmm1,%xmm0
  call   <init_matrix@plt>
  movsd  (%rsp),%xmm2
  add    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %ebx,%r8d
  mov    %r12d,%edx
  pop    %rbx
  mov    %rbp,%rdi
  movapd %xmm2,%xmm0
  pop    %rbp
  xor    %esi,%esi
  pop    %r12
  pop    %r13
  jmp    1050 <init_matrix@plt>
```

assistant: ```c
void init_uvp(double UI, double VI, double PI, int imax, int jmax, double **U, double **V, double **P, char *problem) {
  init_matrix(U, 0, imax + 1, 0, jmax + 1, UI);
  init_matrix(V, 0, imax + 1, 0, jmax + 1, VI);
  init_matrix(P, 0, imax + 1, 0, jmax + 1, PI);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scalblnl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  je     L12
  cmpq   $0x0,-0x18(%rbp)
  jle    L21
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L21:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %eax,%edi
  call   <scalbnl@plt>
  add    $0x10,%rsp
  leave
  ret
```

assistant: ```c
long double scalblnl(long double x, long n) {
  int in;
  in = (int)n;
  if (in != n) {
    if (n > 0)
      in = INT_MAX;
    else
      in = INT_MIN;
  }
  return (scalbnl(x, (int)n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<scalblnl>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <scalbnl@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
long double scalblnl(long double x, long n) {
  int in;
  in = (int)n;
  if (in != n) {
    if (n > 0)
      in = INT_MAX;
    else
      in = INT_MIN;
  }
  return (scalbnl(x, (int)n));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scalblnl>:
  endbr64
  jmp    1050 <scalbnl@plt>
```

assistant: ```c
long double scalblnl(long double x, long n) {
  int in;
  in = (int)n;
  if (in != n) {
    if (n > 0)
      in = INT_MAX;
    else
      in = INT_MIN;
  }
  return (scalbnl(x, (int)n));
}
```
user: Translate the below assembly code into C programming language:

```asm
<scalblnl>:
  endbr64
  jmp    1050 <scalbnl@plt>
```

assistant: ```c
long double scalblnl(long double x, long n) {
  int in;
  in = (int)n;
  if (in != n) {
    if (n > 0)
      in = INT_MAX;
    else
      in = INT_MIN;
  }
  return (scalbnl(x, (int)n));
}
```