ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_table>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %rbp,%rdx
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L1
  mov    %rbp,%rbx
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%r12
  lea    D25(%rip),%rbp
L4:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
L1:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D26: Proces %d, tablica pod adresem %p:


tool: D25: |%c

tool: D10: |


assistant: ```c
void print_table(char *t, int len) {
  int i;
  printf("Proces %d, tablica pod adresem %p:\n", getpid(), t);
  for (i = 0; i < len + 0; ++i)
    printf("|%c", t[i]);
  printf("|\n\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_table>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <getpid@plt>
  mov    %rbx,%rdx
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L18
  lea    -0x1(%rbp),%eax
  lea    D0(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L3:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
L18:
  pop    %rbx
  lea    D18(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string
name: parse_data
arguments: tag: D18
type_guessed: string

tool: D22: Proces %d, tablica pod adresem %p:


tool: D0: |%c

tool: D18: |


assistant: ```c
void print_table(char *t, int len) {
  int i;
  printf("Proces %d, tablica pod adresem %p:\n", getpid(), t);
  for (i = 0; i < len + 0; ++i)
    printf("|%c", t[i]);
  printf("|\n\n");
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_table>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <getpid@plt>
  mov    %rbx,%rdx
  lea    D26(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L2
  lea    -0x1(%rbp),%eax
  lea    D10(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
L2:
  pop    %rbx
  lea    D7(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
datatype: string
name: extract_symbolic_data
arguments: data_label: D10
datatype: string
name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D26: Proces %d, tablica pod adresem %p:


tool: D10: |%c

tool: D7: |


assistant: ```c
void print_table(char *t, int len) {
  int i;
  printf("Proces %d, tablica pod adresem %p:\n", getpid(), t);
  for (i = 0; i < len + 0; ++i)
    printf("|%c", t[i]);
  printf("|\n\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<core___core__NativeString____91d_93d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x2(%rbp),%eax
  mov    %al,-0x1(%rbp)
  nop
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char core___core__NativeString____91d_93d(char *self, long p0) {
  unsigned char var;
  unsigned char var1;
  var1 = (unsigned char)((int)self[p0]);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<core___core__NativeString____91d_93d>:
  endbr64
  movzbl (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
unsigned char core___core__NativeString____91d_93d(char *self, long p0) {
  unsigned char var;
  unsigned char var1;
  var1 = (unsigned char)((int)self[p0]);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<core___core__NativeString____91d_93d>:
  endbr64
  movzbl (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
unsigned char core___core__NativeString____91d_93d(char *self, long p0) {
  unsigned char var;
  unsigned char var1;
  var1 = (unsigned char)((int)self[p0]);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<core___core__NativeString____91d_93d>:
  endbr64
  movzbl (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
unsigned char core___core__NativeString____91d_93d(char *self, long p0) {
  unsigned char var;
  unsigned char var1;
  var1 = (unsigned char)((int)self[p0]);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ibv_get_async_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_get_async_event@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ibv_get_async_event(struct ibv_context *context, struct ibv_async_event *event) {
  dmtcp_plugin_disable_ckpt();
  int rslt = _get_async_event(context, event);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ibv_get_async_event>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_get_async_event@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ibv_get_async_event(struct ibv_context *context, struct ibv_async_event *event) {
  dmtcp_plugin_disable_ckpt();
  int rslt = _get_async_event(context, event);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: What is the c source code of the assembly code below:

```asm
<ibv_get_async_event>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_get_async_event@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ibv_get_async_event(struct ibv_context *context, struct ibv_async_event *event) {
  dmtcp_plugin_disable_ckpt();
  int rslt = _get_async_event(context, event);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ibv_get_async_event>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_get_async_event@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ibv_get_async_event(struct ibv_context *context, struct ibv_async_event *event) {
  dmtcp_plugin_disable_ckpt();
  int rslt = _get_async_event(context, event);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x61,(%rax)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: Hola mundo


assistant: ```c
void msg() {
  char *a = 0;
  *a = 'a';
  printf("Hola mundo\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<msg>:
  endbr64
  sub    $0x8,%rsp
  movb   $0x61,0x0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: Hola mundo


assistant: ```c
void msg() {
  char *a = 0;
  *a = 'a';
  printf("Hola mundo\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<msg>:
  endbr64
  movb   $0x0,0x0
  ud2
```

assistant: ```c
void msg() {
  char *a = 0;
  *a = 'a';
  printf("Hola mundo\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<msg>:
  endbr64
  movb   $0x0,0x0
  ud2
```

assistant: ```c
void msg() {
  char *a = 0;
  *a = 'a';
  printf("Hola mundo\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L11:
  lea    -0x1e(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x1e(%rbp),%eax
  cmp    $0x2a,%al
  je     L33
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x1d(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x1e(%rbp),%eax
  movsbl %al,%eax
  mov    $0x45,%edx
  sub    %eax,%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
L33:
  movzbl -0x1e(%rbp),%eax
  cmp    $0x2a,%al
  jne    L11
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x18(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  js     L20
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L39
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L53
L20:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L53:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D45
type_guessed: string
name: unpack_data
arguments: tag: D28
type_guessed: string
name: unpack_data
arguments: tag: D41
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string

tool: D45: %c

tool: D28:  %d

tool: D41: CR = %.4f


tool: D48: CR = Indefinido

assistant: ```c
int main() {
  char x, aux;
  int y = -1, divisor = 0, dividendo = 0;
  double resultado;
  while (x != '*') {
    scanf("%c", &x);
    if (x != '*') {
      scanf(" %d", &y);
      scanf("%c", &aux);
      dividendo += (69 - x) * y;
      divisor += y;
    }
  }
  resultado = (double)dividendo / divisor;
  if (y >= 0) {
    if (y == 0) {
      resultado = 0;
    }
    printf("CR = %.4f\n", resultado);
  } else
    printf("CR = Indefinido\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  lea    D4(%rip),%rbx
  lea    0x2(%rsp),%rbp
  lea    D5(%rip),%r14
L1:
  cmpb   $0x2a,0x2(%rsp)
  je     L40
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpb   $0x2a,0x2(%rsp)
  je     L1
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x3(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movsbl 0x2(%rsp),%ecx
  mov    $0x45,%eax
  sub    %ecx,%eax
  imul   %edx,%eax
  add    %eax,%r13d
  add    %edx,%r12d
  jmp    L1
L40:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L58
  pxor   %xmm0,%xmm0
  je     L23
  pxor   %xmm0,%xmm0
  cvtsi2sd %r13d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r12d,%xmm1
  divsd  %xmm1,%xmm0
L23:
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  jmp    L30
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D5
type: string
name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D39
type: string

tool: D4: %c

tool: D5:  %d

tool: D26: CR = %.4f


tool: D39: CR = Indefinido

assistant: ```c
int main() {
  char x, aux;
  int y = -1, divisor = 0, dividendo = 0;
  double resultado;
  while (x != '*') {
    scanf("%c", &x);
    if (x != '*') {
      scanf(" %d", &y);
      scanf("%c", &aux);
      dividendo += (69 - x) * y;
      divisor += y;
    }
  }
  resultado = (double)dividendo / divisor;
  if (y >= 0) {
    if (y == 0) {
      resultado = 0;
    }
    printf("CR = %.4f\n", resultado);
  } else
    printf("CR = Indefinido\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl 0x2(%rsp),%edx
  lea    0x2(%rsp),%rbp
  movl   $0xffffffff,0x4(%rsp)
  lea    0x4(%rsp),%r15
L35:
  cmp    $0x2a,%dl
  je     L59
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x2a,0x2(%rsp)
  jne    L67
L59:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L22
  pxor   %xmm0,%xmm0
  jne    L77
L73:
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x3(%rsp),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsbl 0x2(%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    $0x45,%eax
  sub    %esi,%eax
  mov    %esi,%edx
  add    %ecx,%r12d
  imul   %ecx,%eax
  add    %eax,%r13d
  jmp    L35
L77:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm0
  cvtsi2sd %r12d,%xmm1
  divsd  %xmm1,%xmm0
  jmp    L73
L22:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L64
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string
name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string

tool: D8:  %d

tool: D4: %c

tool: D38: CR = %.4f


tool: D10: CR = Indefinido

assistant: ```c
int main() {
  char x, aux;
  int y = -1, divisor = 0, dividendo = 0;
  double resultado;
  while (x != '*') {
    scanf("%c", &x);
    if (x != '*') {
      scanf(" %d", &y);
      scanf("%c", &aux);
      dividendo += (69 - x) * y;
      divisor += y;
    }
  }
  resultado = (double)dividendo / divisor;
  if (y >= 0) {
    if (y == 0) {
      resultado = 0;
    }
    printf("CR = %.4f\n", resultado);
  } else
    printf("CR = Indefinido\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl 0x2(%rsp),%edx
  lea    0x2(%rsp),%rbp
  movl   $0xffffffff,0x4(%rsp)
  lea    0x4(%rsp),%r15
L73:
  cmp    $0x2a,%dl
  je     L19
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x2a,0x2(%rsp)
  jne    L36
L19:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L65
  pxor   %xmm0,%xmm0
  jne    L38
L7:
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x3(%rsp),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsbl 0x2(%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    $0x45,%eax
  sub    %esi,%eax
  mov    %esi,%edx
  add    %ecx,%r12d
  imul   %ecx,%eax
  add    %eax,%r13d
  jmp    L73
L38:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm0
  cvtsi2sd %r12d,%xmm1
  divsd  %xmm1,%xmm0
  jmp    L7
L65:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D3:  %d

tool: D15: %c

tool: D4: CR = %.4f


tool: D6: CR = Indefinido

assistant: ```c
int main() {
  char x, aux;
  int y = -1, divisor = 0, dividendo = 0;
  double resultado;
  while (x != '*') {
    scanf("%c", &x);
    if (x != '*') {
      scanf(" %d", &y);
      scanf("%c", &aux);
      dividendo += (69 - x) * y;
      divisor += y;
    }
  }
  resultado = (double)dividendo / divisor;
  if (y >= 0) {
    if (y == 0) {
      resultado = 0;
    }
    printf("CR = %.4f\n", resultado);
  } else
    printf("CR = Indefinido\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_dup2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <chk_dup@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L40
L29:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L47
  mov    -0x14(%rbp),%eax
  jmp    L40
L47:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <do_dup2@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L49
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L40
L49:
  mov    -0x4(%rbp),%eax
L40:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: [my_dup2]: do dup failed!


assistant: ```c
int my_dup2(int src_fd, int new_fd) {
  int ret;
  if ((ret = chk_dup(src_fd, new_fd)) == -1)
    return -1;
  if (src_fd == new_fd)
    return src_fd;
  close(new_fd);
  if ((ret = do_dup2(src_fd, new_fd)) == -1) {
    printf("[my_dup2]: do dup failed!\n");
    return -1;
  } else
    return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_dup2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  call   <chk_dup@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L18
  mov    %ebp,%ebx
  cmp    %ebp,%r12d
  je     L18
  mov    %ebp,%edi
  call   <close@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <do_dup2@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L28
L18:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: [my_dup2]: do dup failed!


assistant: ```c
int my_dup2(int src_fd, int new_fd) {
  int ret;
  if ((ret = chk_dup(src_fd, new_fd)) == -1)
    return -1;
  if (src_fd == new_fd)
    return src_fd;
  close(new_fd);
  if ((ret = do_dup2(src_fd, new_fd)) == -1) {
    printf("[my_dup2]: do dup failed!\n");
    return -1;
  } else
    return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_dup2>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  call   <chk_dup@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L14
  mov    %ebx,%r12d
  cmp    %ebp,%ebx
  je     L14
  mov    %ebp,%edi
  call   <close@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <do_dup2@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L30
L14:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: [my_dup2]: do dup failed!


assistant: ```c
int my_dup2(int src_fd, int new_fd) {
  int ret;
  if ((ret = chk_dup(src_fd, new_fd)) == -1)
    return -1;
  if (src_fd == new_fd)
    return src_fd;
  close(new_fd);
  if ((ret = do_dup2(src_fd, new_fd)) == -1) {
    printf("[my_dup2]: do dup failed!\n");
    return -1;
  } else
    return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_dup2>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  call   <chk_dup@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L6
  mov    %ebx,%r12d
  cmp    %ebp,%ebx
  je     L6
  mov    %ebp,%edi
  call   <close@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <do_dup2@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L35
L6:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: [my_dup2]: do dup failed!


assistant: ```c
int my_dup2(int src_fd, int new_fd) {
  int ret;
  if ((ret = chk_dup(src_fd, new_fd)) == -1)
    return -1;
  if (src_fd == new_fd)
    return src_fd;
  close(new_fd);
  if ((ret = do_dup2(src_fd, new_fd)) == -1) {
    printf("[my_dup2]: do dup failed!\n");
    return -1;
  } else
    return ret;
}
```