user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L14
L22:
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L118
L41:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L36
  addl   $0x1,-0xc(%rbp)
L36:
  addl   $0x1,-0x14(%rbp)
L118:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L104
L66:
  movl   $0x0,-0x18(%rbp)
  jmp    L37
L107:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L69
L90:
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x14(%rbp)
L69:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L90
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x18(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L107
  mov    -0x18(%rbp),%eax
  add    %eax,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L15
L89:
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L89
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x10(%rbp)
L104:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L66
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int str_rev(char *string) {
  if (!string) {
    return 0;
  }
  int ins_pos = 0;
  int ch = 0;
  int swap_time = 0;
  int i = 0;
  int j = 0;
  int counter = 0;
  int word = 0;
  for (i = 0, word = 1; string[i] != '\0'; i++) {
    if (string[i] == ' ') {
      word++;
    }
  }
  counter = i;
  for (j = 0, swap_time = 0, ins_pos = 0, ch = 0; j < word - 1; j++) {
    for (swap_time = 0; string[counter - 1] != ' ';) {
      ch = string[counter - 1];
      for (i = counter - 1; i > ins_pos; i--) {
        string[i] = string[i - 1];
      }
      string[ins_pos] = ch;
      swap_time++;
    }
    ins_pos += swap_time;
    ch = string[counter - 1];
    for (i = counter - 1; i > ins_pos; i--) {
      string[i] = string[i - 1];
    }
    string[ins_pos] = ch;
    ins_pos++;
  }
  return 0;
}
```