ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<winsize_unpack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x13,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  add    $0xe,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x9,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rdx
  add    $0x4,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x5,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,0x2(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xa,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,0x4(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xf,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,0x6(%rax)
  nop
  leave
  ret
```

assistant: ```c
int winsize_unpack(struct winsize *w, char *buf) {
  buf[4] = buf[9] = buf[14] = buf[19] = 0;
  w->ws_row = (unsigned short int)atoi(buf);
  w->ws_col = (unsigned short int)atoi(buf + 5);
  w->ws_xpixel = (unsigned short int)atoi(buf + 10);
  w->ws_ypixel = (unsigned short int)atoi(buf + 15);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<winsize_unpack>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movb   $0x0,0x13(%rsi)
  movb   $0x0,0xe(%rsi)
  movb   $0x0,0x9(%rsi)
  movb   $0x0,0x4(%rsi)
  mov    %rsi,%rdi
  call   <atoi@plt>
  mov    %ax,0x0(%rbp)
  lea    0x5(%rbx),%rdi
  call   <atoi@plt>
  mov    %ax,0x2(%rbp)
  lea    0xa(%rbx),%rdi
  call   <atoi@plt>
  mov    %ax,0x4(%rbp)
  lea    0xf(%rbx),%rdi
  call   <atoi@plt>
  mov    %ax,0x6(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int winsize_unpack(struct winsize *w, char *buf) {
  buf[4] = buf[9] = buf[14] = buf[19] = 0;
  w->ws_row = (unsigned short int)atoi(buf);
  w->ws_col = (unsigned short int)atoi(buf + 5);
  w->ws_xpixel = (unsigned short int)atoi(buf + 10);
  w->ws_ypixel = (unsigned short int)atoi(buf + 15);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<winsize_unpack>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movb   $0x0,0x13(%rsi)
  movb   $0x0,0xe(%rsi)
  movb   $0x0,0x9(%rsi)
  movb   $0x0,0x4(%rsi)
  call   <atoi@plt>
  lea    0x5(%rbx),%rdi
  mov    %ax,0x0(%rbp)
  call   <atoi@plt>
  lea    0xa(%rbx),%rdi
  mov    %ax,0x2(%rbp)
  call   <atoi@plt>
  lea    0xf(%rbx),%rdi
  mov    %ax,0x4(%rbp)
  call   <atoi@plt>
  mov    %ax,0x6(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int winsize_unpack(struct winsize *w, char *buf) {
  buf[4] = buf[9] = buf[14] = buf[19] = 0;
  w->ws_row = (unsigned short int)atoi(buf);
  w->ws_col = (unsigned short int)atoi(buf + 5);
  w->ws_xpixel = (unsigned short int)atoi(buf + 10);
  w->ws_ypixel = (unsigned short int)atoi(buf + 15);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<winsize_unpack>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movb   $0x0,0x13(%rsi)
  movb   $0x0,0xe(%rsi)
  movb   $0x0,0x9(%rsi)
  movb   $0x0,0x4(%rsi)
  call   <atoi@plt>
  lea    0x5(%rbx),%rdi
  mov    %ax,0x0(%rbp)
  call   <atoi@plt>
  lea    0xa(%rbx),%rdi
  mov    %ax,0x2(%rbp)
  call   <atoi@plt>
  lea    0xf(%rbx),%rdi
  mov    %ax,0x4(%rbp)
  call   <atoi@plt>
  mov    %ax,0x6(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int winsize_unpack(struct winsize *w, char *buf) {
  buf[4] = buf[9] = buf[14] = buf[19] = 0;
  w->ws_row = (unsigned short int)atoi(buf);
  w->ws_col = (unsigned short int)atoi(buf + 5);
  w->ws_xpixel = (unsigned short int)atoi(buf + 10);
  w->ws_ypixel = (unsigned short int)atoi(buf + 15);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L10
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L10:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string

tool: D4: You are the winner of the game with %d guesses.


tool: D19: You lost the game. %d guesses were not enough for you to find the word %s.


assistant: ```c
int print_result(int winner, int numberofguesses, char storedstring[7]) {
  if (winner == 1) {
    printf("You are the winner of the game with %d guesses.\n", numberofguesses + 1);
  } else {
    printf("You lost the game. %d guesses were not enough for you to find the word %s.\n", numberofguesses + 1, storedstring);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_result>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L10
  add    $0x1,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  add    $0x8,%rsp
  ret
L10:
  add    $0x1,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D0: You lost the game. %d guesses were not enough for you to find the word %s.


tool: D5: You are the winner of the game with %d guesses.


assistant: ```c
int print_result(int winner, int numberofguesses, char storedstring[7]) {
  if (winner == 1) {
    printf("You are the winner of the game with %d guesses.\n", numberofguesses + 1);
  } else {
    printf("You lost the game. %d guesses were not enough for you to find the word %s.\n", numberofguesses + 1, storedstring);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_result>:
  endbr64
  add    $0x1,%esi
  cmp    $0x1,%edi
  je     L6
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string

tool: D7: You lost the game. %d guesses were not enough for you to find the word %s.


tool: D13: You are the winner of the game with %d guesses.


assistant: ```c
int print_result(int winner, int numberofguesses, char storedstring[7]) {
  if (winner == 1) {
    printf("You are the winner of the game with %d guesses.\n", numberofguesses + 1);
  } else {
    printf("You lost the game. %d guesses were not enough for you to find the word %s.\n", numberofguesses + 1, storedstring);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_result>:
  endbr64
  add    $0x1,%esi
  cmp    $0x1,%edi
  je     L6
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D12: You lost the game. %d guesses were not enough for you to find the word %s.


tool: D1: You are the winner of the game with %d guesses.


assistant: ```c
int print_result(int winner, int numberofguesses, char storedstring[7]) {
  if (winner == 1) {
    printf("You are the winner of the game with %d guesses.\n", numberofguesses + 1);
  } else {
    printf("You lost the game. %d guesses were not enough for you to find the word %s.\n", numberofguesses + 1, storedstring);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pack_A>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L55
L42:
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <pack_MRxk@plt>
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x3,%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L42
  cmpl   $0x0,-0x4(%rbp)
  jle    L50
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L20:
  movl   $0x0,-0x10(%rbp)
  jmp    L78
L15:
  mov    -0x10(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L78:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L15
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L26
L8:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L26:
  cmpl   $0x7,-0x10(%rbp)
  jle    L8
  addq   $0x40,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L20
L50:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
void pack_A(int mc, int kc, const double *A, int incRowA, int incColA, double *buffer) {
  int mp = mc / 8;
  int _mr = mc % 8;
  int i, j;
  for (i = 0; i < mp; ++i) {
    pack_MRxk(kc, A, incRowA, incColA, buffer);
    buffer += kc * 8;
    A += 8 * incRowA;
  }
  if (_mr > 0) {
    for (j = 0; j < kc; ++j) {
      for (i = 0; i < _mr; ++i) {
        buffer[i] = A[i * incRowA];
      }
      for (i = _mr; i < 8; ++i) {
        buffer[i] = 1000;
      }
      buffer += 8;
      A += incColA;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pack_A>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x24(%rsp)
  mov    %esi,0x38(%rsp)
  mov    %rdx,%r14
  mov    %ecx,0x3c(%rsp)
  mov    %r8d,0x1c(%rsp)
  mov    %r9,%rbx
  lea    0x7(%rdi),%r15d
  test   %edi,%edi
  cmovns %edi,%r15d
  sar    $0x3,%r15d
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%rdi,%rax,1),%edx
  and    $0x7,%edx
  sub    %eax,%edx
  mov    %edx,0x20(%rsp)
  cmp    $0x7,%edi
  jle    L35
  lea    0x0(,%rsi,8),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rcx,8),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,0x10(%rsp)
  mov    %r9,%r13
  mov    %r14,%r12
  mov    $0x0,%ebp
  mov    %r14,0x28(%rsp)
  mov    %ecx,%r14d
  mov    %r9,0x30(%rsp)
  mov    %esi,%ebx
L54:
  mov    %r13,%r8
  mov    0x1c(%rsp),%ecx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <pack_MRxk@plt>
  add    0x8(%rsp),%r13
  add    0x10(%rsp),%r12
  add    $0x1,%ebp
  cmp    %ebp,%r15d
  jg     L54
  mov    0x28(%rsp),%r14
  mov    0x30(%rsp),%rbx
  lea    -0x1(%r15),%edx
  add    $0x1,%rdx
  cmpl   $0x7,0x24(%rsp)
  mov    $0x1,%eax
  cmovle %rax,%rdx
  mov    0x8(%rsp),%rax
  imul   %rdx,%rax
  add    %rax,%rbx
  mov    0x10(%rsp),%rax
  imul   %rdx,%rax
  add    %rax,%r14
L35:
  mov    0x20(%rsp),%r9d
  test   %r9d,%r9d
  jle    L46
  mov    0x38(%rsp),%edi
  test   %edi,%edi
  jle    L46
  movslq 0x1c(%rsp),%r8
  shl    $0x3,%r8
  mov    %r9d,%eax
  lea    (%rbx,%rax,8),%rsi
  mov    %edi,%edi
  shl    $0x6,%rdi
  add    %rbx,%rdi
  movslq 0x3c(%rsp),%rcx
  shl    $0x3,%rcx
  movsd  D4(%rip),%xmm1
  jmp    L66
L52:
  add    $0x40,%rbx
  add    %r8,%r14
  add    $0x40,%rsi
  cmp    %rdi,%rbx
  je     L46
L66:
  mov    %r14,%rdx
  mov    %rbx,%rax
L13:
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  add    %rcx,%rdx
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L13
  movslq %r9d,%rax
L21:
  movsd  %xmm1,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    $0x7,%eax
  jle    L21
  jmp    L52
L46:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
void pack_A(int mc, int kc, const double *A, int incRowA, int incColA, double *buffer) {
  int mp = mc / 8;
  int _mr = mc % 8;
  int i, j;
  for (i = 0; i < mp; ++i) {
    pack_MRxk(kc, A, incRowA, incColA, buffer);
    buffer += kc * 8;
    A += 8 * incRowA;
  }
  if (_mr > 0) {
    for (j = 0; j < kc; ++j) {
      for (i = 0; i < _mr; ++i) {
        buffer[i] = A[i * incRowA];
      }
      for (i = _mr; i < 8; ++i) {
        buffer[i] = 1000;
      }
      buffer += 8;
      A += incColA;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack_A>:
  endbr64
  push   %r15
  lea    0x7(%rdi),%eax
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x38,%rsp
  test   %edi,%edi
  cmovns %edi,%eax
  mov    %edi,0x28(%rsp)
  mov    %r8d,0x2c(%rsp)
  sar    $0x3,%eax
  mov    %eax,0x10(%rsp)
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%rdi,%rax,1),%edx
  and    $0x7,%edx
  sub    %eax,%edx
  mov    %edx,0x14(%rsp)
  cmp    $0x7,%edi
  jle    L3
  lea    0x0(,%rsi,8),%r14d
  lea    0x0(,%rbp,8),%r15d
  mov    %r9,0x20(%rsp)
  movslq %r14d,%r14
  movslq %r15d,%r15
  mov    %r12,0x18(%rsp)
  lea    0x0(,%r14,8),%rax
  xor    %r14d,%r14d
  mov    %rax,(%rsp)
  lea    0x0(,%r15,8),%rax
  mov    %r12,%r15
  mov    %r9,%r12
  mov    %rax,0x8(%rsp)
  mov    %r15,%rbx
  mov    %r8d,%r15d
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12,%r8
  mov    %rbx,%rsi
  mov    %r15d,%ecx
  mov    %ebp,%edx
  mov    %r13d,%edi
  add    $0x1,%r14d
  call   <pack_MRxk@plt>
  add    (%rsp),%r12
  add    0x8(%rsp),%rbx
  cmp    %r14d,0x10(%rsp)
  jg     L22
  mov    0x10(%rsp),%eax
  mov    $0x1,%edx
  mov    0x8(%rsp),%r15
  mov    (%rsp),%r14
  mov    0x18(%rsp),%r12
  sub    $0x1,%eax
  mov    0x20(%rsp),%rbx
  add    $0x1,%rax
  cmpl   $0x7,0x28(%rsp)
  cmovle %rdx,%rax
  imul   %rax,%r15
  imul   %rax,%r14
  add    %r15,%r12
  add    %r14,%rbx
L3:
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L6
  test   %r13d,%r13d
  jle    L6
  movslq 0x2c(%rsp),%r8
  movslq %r13d,%rdi
  mov    %edx,%eax
  movslq %ebp,%rcx
  shl    $0x6,%rdi
  lea    (%rbx,%rax,8),%rsi
  shl    $0x3,%rcx
  movslq %edx,%r9
  movsd  D9(%rip),%xmm1
  shl    $0x3,%r8
  add    %rbx,%rdi
  nopl   (%rax)
L63:
  mov    %r12,%rdx
  mov    %rbx,%rax
  cs nopw 0x0(%rax,%rax,1)
L57:
  movsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rcx,%rdx
  movsd  %xmm0,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L57
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L44:
  movsd  %xmm1,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    $0x8,%eax
  jne    L44
  add    $0x40,%rbx
  add    %r8,%r12
  add    $0x40,%rsi
  cmp    %rdi,%rbx
  jne    L63
L6:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
void pack_A(int mc, int kc, const double *A, int incRowA, int incColA, double *buffer) {
  int mp = mc / 8;
  int _mr = mc % 8;
  int i, j;
  for (i = 0; i < mp; ++i) {
    pack_MRxk(kc, A, incRowA, incColA, buffer);
    buffer += kc * 8;
    A += 8 * incRowA;
  }
  if (_mr > 0) {
    for (j = 0; j < kc; ++j) {
      for (i = 0; i < _mr; ++i) {
        buffer[i] = A[i * incRowA];
      }
      for (i = _mr; i < 8; ++i) {
        buffer[i] = 1000;
      }
      buffer += 8;
      A += incColA;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<obtener_elemento>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L56:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L77
  cmpl   $0x0,-0xc(%rbp)
  jle    L77
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L77
  addl   $0x1,-0x4(%rbp)
L77:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L53
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  je     L104
L53:
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L56
  jmp    L64
L104:
  nop
  jmp    L64
L48:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L25
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L122
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L122:
  addl   $0x1,-0xc(%rbp)
L64:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L48
  jmp    L78
L25:
  nop
L78:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void obtener_elemento(char *inst_o_dato, char *ps_inst, int elemento, int longitud) {
  int i = 0, k = 0, num_elem = 1;
  for (; i < strlen(inst_o_dato); i++) {
    if (inst_o_dato[i] == ' ' && i > 0 && inst_o_dato[i - 1] != ' ')
      num_elem++;
    if (inst_o_dato[i] != ' ' && num_elem == elemento)
      break;
  }
  for (; i < strlen(inst_o_dato); i++)
    if (inst_o_dato[i] != ' ') {
      if (k < longitud - 1)
        ps_inst[k++] = inst_o_dato[i];
    } else
      break;
  ps_inst[k] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<obtener_elemento>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    %ecx,0xc(%rsp)
  mov    $0x0,%ebx
  mov    $0x1,%r13d
  jmp    L105
L16:
  cmpb   $0x20,-0x1(%r12,%rbx,1)
  je     L107
  add    $0x1,%r13d
L107:
  add    $0x1,%rbx
L105:
  mov    %ebx,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L31
  movzbl (%r12,%rbx,1),%eax
  test   %ebx,%ebx
  jle    L29
  cmp    $0x20,%al
  je     L16
L29:
  cmp    %r14d,%r13d
  jne    L107
  cmp    $0x20,%al
  je     L107
L31:
  movslq %ebp,%rbp
  mov    $0x0,%ebx
  mov    0xc(%rsp),%r13d
  sub    $0x1,%r13d
  jmp    L46
L33:
  add    $0x1,%rbp
L46:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L23
  movzbl (%r12,%rbp,1),%eax
  cmp    $0x20,%al
  je     L23
  cmp    %ebx,%r13d
  jle    L33
  movslq %ebx,%rdx
  mov    %al,(%r15,%rdx,1)
  lea    0x1(%rbx),%ebx
  jmp    L33
L23:
  movslq %ebx,%rbx
  movb   $0x0,(%r15,%rbx,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void obtener_elemento(char *inst_o_dato, char *ps_inst, int elemento, int longitud) {
  int i = 0, k = 0, num_elem = 1;
  for (; i < strlen(inst_o_dato); i++) {
    if (inst_o_dato[i] == ' ' && i > 0 && inst_o_dato[i - 1] != ' ')
      num_elem++;
    if (inst_o_dato[i] != ' ' && num_elem == elemento)
      break;
  }
  for (; i < strlen(inst_o_dato); i++)
    if (inst_o_dato[i] != ' ') {
      if (k < longitud - 1)
        ps_inst[k++] = inst_o_dato[i];
    } else
      break;
  ps_inst[k] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<obtener_elemento>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  jmp    L31
  nopl   0x0(%rax)
L10:
  cmp    %r12d,%r14d
  je     L55
L37:
  add    $0x1,%rbx
L31:
  mov    %r15,%rdi
  movslq %ebx,%rbp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L55
  cmpb   $0x20,(%r15,%rbx,1)
  jne    L10
  test   %ebp,%ebp
  je     L37
  cmpb   $0x20,-0x1(%r15,%rbx,1)
  je     L37
  add    $0x1,%r14d
  jmp    L37
  nopl   0x0(%rax)
L55:
  mov    0xc(%rsp),%r12d
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  sub    $0x1,%r12d
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L20:
  movzbl (%r15,%rbp,1),%eax
  cmp    $0x20,%al
  je     L42
  cmp    %ebx,%r12d
  jle    L2
  mov    %al,(%rdx)
  add    $0x1,%ebx
  movslq %ebx,%r14
L2:
  add    $0x1,%rbp
L17:
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x0(%r13,%r14,1),%rdx
  cmp    %ebp,%eax
  jg     L20
L42:
  movb   $0x0,(%rdx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void obtener_elemento(char *inst_o_dato, char *ps_inst, int elemento, int longitud) {
  int i = 0, k = 0, num_elem = 1;
  for (; i < strlen(inst_o_dato); i++) {
    if (inst_o_dato[i] == ' ' && i > 0 && inst_o_dato[i - 1] != ' ')
      num_elem++;
    if (inst_o_dato[i] != ' ' && num_elem == elemento)
      break;
  }
  for (; i < strlen(inst_o_dato); i++)
    if (inst_o_dato[i] != ' ') {
      if (k < longitud - 1)
        ps_inst[k++] = inst_o_dato[i];
    } else
      break;
  ps_inst[k] = '\0';
}
```