ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t1>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x19,%edi
  call   <gpioSetMode@plt>
  mov    $0x19,%edi
  call   <gpioGetMode@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%esi
  mov    %eax,%edx
  lea    D23(%rip),%r9
  mov    $0x1,%edi
  call   <CHECK@plt>
  mov    $0x2,%esi
  mov    $0x19,%edi
  call   <gpioSetPullUpDown@plt>
  mov    $0x1,%edi
  call   <gpioDelay@plt>
  mov    $0x19,%edi
  call   <gpioRead@plt>
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  lea    D1(%rip),%r9
  mov    %eax,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <CHECK@plt>
  mov    $0x1,%esi
  mov    $0x19,%edi
  call   <gpioSetPullUpDown@plt>
  mov    $0x1,%edi
  call   <gpioDelay@plt>
  mov    $0x19,%edi
  call   <gpioRead@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x3,%esi
  mov    %eax,%edx
  lea    D1(%rip),%r9
  mov    $0x1,%edi
  call   <CHECK@plt>
  xor    %esi,%esi
  mov    $0x19,%edi
  call   <gpioWrite@plt>
  mov    $0x19,%edi
  call   <gpioGetMode@plt>
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  lea    D35(%rip),%r9
  mov    %eax,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <CHECK@plt>
  mov    $0x19,%edi
  call   <gpioRead@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%esi
  mov    %eax,%edx
  lea    D24(%rip),%r9
  mov    $0x1,%edi
  call   <CHECK@plt>
  mov    $0x1,%esi
  mov    $0x19,%edi
  call   <gpioWrite@plt>
  mov    $0x1,%edi
  call   <gpioDelay@plt>
  mov    $0x19,%edi
  call   <gpioRead@plt>
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  lea    D27(%rip),%r9
  mov    %eax,%edx
  mov    $0x6,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    10c0 <CHECK@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
datatype: string
name: extract_symbolic_data
arguments: tag: D23
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D35
datatype: string
name: extract_symbolic_data
arguments: tag: D24
datatype: string
name: extract_symbolic_data
arguments: tag: D27
datatype: string

tool: D18: Mode/PUD/read/write tests.


tool: D23: set mode, get mode

tool: D1: set pull up down, read

tool: D35: write, get mode

tool: D24: read

tool: D27: write, read

assistant: ```c
void t1() {
  int v;
  printf("Mode/PUD/read/write tests.\n");
  gpioSetMode(25, 0);
  v = gpioGetMode(25);
  CHECK(1, 1, v, 0, 0, "set mode, get mode");
  gpioSetPullUpDown(25, 2);
  gpioDelay(1);
  v = gpioRead(25);
  CHECK(1, 2, v, 1, 0, "set pull up down, read");
  gpioSetPullUpDown(25, 1);
  gpioDelay(1);
  v = gpioRead(25);
  CHECK(1, 3, v, 0, 0, "set pull up down, read");
  gpioWrite(25, 0);
  v = gpioGetMode(25);
  CHECK(1, 4, v, 1, 0, "write, get mode");
  v = gpioRead(25);
  CHECK(1, 5, v, 0, 0, "read");
  gpioWrite(25, 1);
  gpioDelay(1);
  v = gpioRead(25);
  CHECK(1, 6, v, 1, 0, "write, read");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L9:
  movss  -0xc(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  D4(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  comiss %xmm1,%xmm0
  ja     L35
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  comiss %xmm1,%xmm0
  ja     L9
  jmp    L2
L35:
  nop
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D29
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: f32

tool: D28: %f

tool: D29: %f %f


tool: D4: 0.5

assistant: ```c
int main(void) {
  float x, a;
  scanf("%f", &x);
  scanf("%f", &a);
  do {
    printf("%f %f\n", x, a);
    x += 0.5;
    if (x > a)
      break;
  } while (x > a);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D4: %f

tool: D6: %f %f


assistant: ```c
int main(void) {
  float x, a;
  scanf("%f", &x);
  scanf("%f", &a);
  do {
    printf("%f %f\n", x, a);
    x += 0.5;
    if (x > a)
      break;
  } while (x > a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string

tool: D15: %f

tool: D18: %f %f


assistant: ```c
int main(void) {
  float x, a;
  scanf("%f", &x);
  scanf("%f", &a);
  do {
    printf("%f %f\n", x, a);
    x += 0.5;
    if (x > a)
      break;
  } while (x > a);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string

tool: D19: %f

tool: D5: %f %f


assistant: ```c
int main(void) {
  float x, a;
  scanf("%f", &x);
  scanf("%f", &a);
  do {
    printf("%f %f\n", x, a);
    x += 0.5;
    if (x > a)
      break;
  } while (x > a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x65,-0x1a4(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  jmp    L31
L22:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a8(%rbp),%edx
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L31:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L22
  movl   $0x0,-0x1a8(%rbp)
  jmp    L41
L39:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    -0x1a4(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x1a4(%rbp)
  addl   $0x1,-0x1a8(%rbp)
L41:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L39
  cmpl   $0x0,-0x1a4(%rbp)
  je     L59
  mov    $0x0,%eax
  call   <abort@plt>
L59:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i, x = 100 + 1;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(mymin : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
L37:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L37
  mov    %rsp,%rax
  lea    0x190(%rsp),%rsi
  mov    $0x65,%edx
L17:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L17
  test   %edx,%edx
  jne    L3
L16:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int i, x = 100 + 1;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(mymin : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %edx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x64,%rdx
  jne    L37
  lea    0x190(%rsp),%rsi
  mov    $0x65,%edx
  nopw   0x0(%rax,%rax,1)
L47:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L47
  test   %edx,%edx
  jne    L15
L39:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L15:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L39
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int i, x = 100 + 1;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(mymin : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  movdqa D4(%rip),%xmm0
  movdqa D29(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  mov    %rsp,%rax
  lea    0x190(%rsp),%rcx
  mov    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L45:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rdx)
  cmp    %rcx,%rdx
  jne    L45
  movdqa D22(%rip),%xmm2
  nopl   (%rax)
L40:
  movdqa %xmm2,%xmm1
  movdqa (%rax),%xmm0
  add    $0x10,%rax
  pcmpgtd -0x10(%rax),%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rax,%rcx
  jne    L40
  movdqa %xmm2,%xmm1
  psrldq $0x8,%xmm1
  movdqa %xmm1,%xmm0
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  test   %eax,%eax
  jne    L42
L26:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L42:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L26
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: byte[16]
name: read_data
arguments: data_tag: D29
datatype: byte[16]
name: read_data
arguments: data_tag: D22
datatype: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D29": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D22": [0x65,0x00,0x00,0x00,0x65,0x00,0x00,0x00,0x65,0x00,0x00,0x00,0x65,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  int i, x = 100 + 1;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(mymin : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_leap_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L47
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L47
  mov    $0x1,%eax
  jmp    L18
L47:
  mov    $0x0,%eax
  jmp    L18
L12:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int is_leap_year(int year) {
  if (year % 100 == 0) {
    return (year % 4 == 0 && year % 400 == 0) ? 1 : 0;
  }
  return (year % 4 == 0) ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_leap_year>:
  endbr64
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  test   $0x3,%dil
  sete   %dl
  movzbl %dl,%edx
  cmp    %eax,%edi
  je     L11
L3:
  mov    %edx,%eax
  ret
L11:
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  mov    %edi,%edx
  sub    %eax,%edx
  and    $0x3,%edi
  or     %edi,%edx
  sete   %dl
  movzbl %dl,%edx
  jmp    L3
```

assistant: ```c
int is_leap_year(int year) {
  if (year % 100 == 0) {
    return (year % 4 == 0 && year % 400 == 0) ? 1 : 0;
  }
  return (year % 4 == 0) ? 1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_leap_year>:
  endbr64
  imul   $0xc28f5c29,%edi,%eax
  mov    %edi,%edx
  xor    %r8d,%r8d
  and    $0x3,%edx
  add    $0x51eb850,%eax
  ror    $0x2,%eax
  test   %edx,%edx
  sete   %r8b
  cmp    $0x28f5c28,%eax
  ja     L0
  movslq %edi,%rax
  mov    %edi,%ecx
  xor    %r8d,%r8d
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x27,%rax
  sub    %ecx,%eax
  imul   $0x190,%eax,%eax
  sub    %eax,%edi
  or     %edx,%edi
  sete   %r8b
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_leap_year(int year) {
  if (year % 100 == 0) {
    return (year % 4 == 0 && year % 400 == 0) ? 1 : 0;
  }
  return (year % 4 == 0) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_leap_year>:
  endbr64
  imul   $0xc28f5c29,%edi,%eax
  mov    %edi,%edx
  xor    %r8d,%r8d
  and    $0x3,%edx
  add    $0x51eb850,%eax
  ror    $0x2,%eax
  test   %edx,%edx
  sete   %r8b
  cmp    $0x28f5c28,%eax
  ja     L4
  movslq %edi,%rax
  mov    %edi,%ecx
  xor    %r8d,%r8d
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x27,%rax
  sub    %ecx,%eax
  imul   $0x190,%eax,%eax
  sub    %eax,%edi
  or     %edx,%edi
  sete   %r8b
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_leap_year(int year) {
  if (year % 100 == 0) {
    return (year % 4 == 0 && year % 400 == 0) ? 1 : 0;
  }
  return (year % 4 == 0) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inet6_srcrt_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L17
  cmpl   $0x18,-0x8(%rbp)
  jle    L19
L17:
  mov    $0x0,%eax
  jmp    L11
L19:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x2,%rax
  shl    $0x2,%rax
L11:
  pop    %rbp
  ret
```

assistant: ```c
size_t inet6_srcrt_space(int type, int segments) {
  if (type != 0 || segments > 24)
    return 0;
  return (sizeof(struct cmsghdr) + sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inet6_srcrt_space>:
  endbr64
  test   %edi,%edi
  jne    L6
  cmp    $0x18,%esi
  jg     L6
  movslq %esi,%rsi
  lea    0x8(,%rsi,4),%rax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t inet6_srcrt_space(int type, int segments) {
  if (type != 0 || segments > 24)
    return 0;
  return (sizeof(struct cmsghdr) + sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inet6_srcrt_space>:
  endbr64
  test   %edi,%edi
  jne    L11
  cmp    $0x18,%esi
  jg     L11
  lea    0x2(%rsi),%eax
  cltq
  shl    $0x2,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t inet6_srcrt_space(int type, int segments) {
  if (type != 0 || segments > 24)
    return 0;
  return (sizeof(struct cmsghdr) + sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inet6_srcrt_space>:
  endbr64
  test   %edi,%edi
  jne    L5
  cmp    $0x18,%esi
  jg     L5
  lea    0x2(%rsi),%eax
  cltq
  shl    $0x2,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t inet6_srcrt_space(int type, int segments) {
  if (type != 0 || segments > 24)
    return 0;
  return (sizeof(struct cmsghdr) + sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1(%rdi),%r14
  mov    $0x2b,%eax
  comisd D60(%rip),%xmm0
  jb     L24
L56:
  mov    %al,(%rdi)
  movq   %rbx,%xmm6
  ucomisd D60(%rip),%xmm6
  jp     L26
  mov    $0x1,%ebp
  jne    L26
L1:
  mov    %ebp,0x1c(%rsp)
  lea    0x12(%r14),%r13
  mov    %r14,%rbp
  lea    0x20(%rsp),%r12
L102:
  mov    %r12,%rdi
  movq   %rbx,%xmm0
  call   <modf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D5(%rip),%xmm0
  movq   %xmm0,%rbx
  add    $0x1,%rbp
  movsd  D12(%rip),%xmm0
  addsd  0x20(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbp
  jne    L102
  movb   $0x0,0x12(%r14)
  mov    $0x1,%eax
  sub    0x1c(%rsp),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L108
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  movapd %xmm0,%xmm5
  xorpd  D25(%rip),%xmm5
  movq   %xmm5,%rbx
  mov    $0x2d,%eax
  jmp    L56
L26:
  lea    0x1c(%rsp),%rdi
  movq   %rbx,%xmm0
  call   <frexp@plt>
  imul   $0xffff8a69,0x1c(%rsp),%eax
  movslq %eax,%rbp
  imul   $0x14f8b589,%rbp,%rbp
  mov    %rbp,%rcx
  sar    $0x2d,%rcx
  mov    %rcx,%r12
  sar    $0x1f,%eax
  sub    %eax,%r12d
  mov    %r12d,0x1c(%rsp)
  sar    $0x2e,%rbp
  sub    %eax,%ebp
  sub    %ebp,%r12d
  mov    %r12d,%edi
  call   <pow10@plt>
  movq   %rbx,%xmm6
  mulsd  %xmm0,%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L43
L60:
  add    $0x1,%ebp
L43:
  mov    %ebp,%edi
  call   <pow10@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  D24(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L60
  jmp    L0
L68:
  sub    $0x1,%ebp
L0:
  mov    %ebp,%edi
  call   <pow10@plt>
  mulsd  0x8(%rsp),%xmm0
  movq   %xmm0,%rbx
  comisd D5(%rip),%xmm0
  jae    L68
  add    %r12d,%ebp
  jmp    L1
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D60
type_infered: f64[2]
name: unpack_data
arguments: tag: D5
type_infered: f64[2]
name: unpack_data
arguments: tag: D12
type_infered: byte[8]
name: unpack_data
arguments: tag: D25
type_infered: byte[16]
name: unpack_data
arguments: tag: D24
type_infered: f64

tool: {"D60": [0.0,1.0]}

tool: {"D5": [10.0,48.0]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x48,0x40]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D24: 1

assistant: ```c
int ftoa(double f, char *bp) {
  int e, e1, e2, i;
  double digit, g, p;
  if (f >= 0)
    *bp++ = '+';
  else {
    f = -f;
    *bp++ = '-';
  }
  if (f == 0.)
    e = 1;
  else {
    frexp(f, &e);
    e = -e * 30103 / 100000;
    e1 = e / 2;
    e2 = e - e1;
    p = f * pow10(e2);
    while ((g = p * pow10(e1)) < 1.)
      e1++;
    while ((g = p * pow10(e1)) >= 10.)
      --e1;
    e = e1 + e2;
    f = g;
  }
  for (i = 0; i != 18; i++) {
    f = modf(f, &digit) * 10.;
    *bp++ = digit + '0';
  }
  *bp = '\0';
  return 1 - e;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ftoa>:
  endbr64
  push   %r13
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  mov    $0x2b,%eax
  jae    L49
  xorpd  D26(%rip),%xmm1
  mov    $0x2d,%eax
L49:
  ucomisd %xmm0,%xmm1
  mov    %al,(%r12)
  jp     L56
  movsd  D28(%rip),%xmm7
  mov    $0x1,%ebp
  movsd  %xmm7,(%rsp)
  jne    L56
L96:
  mov    %ebp,0x1c(%rsp)
  lea    0x13(%r12),%r13
  lea    0x20(%rsp),%rbp
  nopl   (%rax)
L31:
  movapd %xmm1,%xmm0
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <modf@plt>
  movsd  D15(%rip),%xmm0
  addsd  0x20(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  (%rsp),%xmm1
  cvttsd2si %xmm0,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r13
  jne    L31
  movb   $0x0,0x13(%r12)
  mov    $0x1,%eax
  sub    0x1c(%rsp),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L56:
  movapd %xmm1,%xmm0
  lea    0x1c(%rsp),%rdi
  movsd  %xmm1,(%rsp)
  call   <frexp@plt>
  imul   $0xffff8a69,0x1c(%rsp),%eax
  movslq %eax,%rbp
  sar    $0x1f,%eax
  imul   $0x14f8b589,%rbp,%rbp
  mov    %rbp,%rcx
  sar    $0x2e,%rbp
  sar    $0x2d,%rcx
  sub    %eax,%ebp
  mov    %rcx,%r13
  sub    %eax,%r13d
  mov    %r13d,0x1c(%rsp)
  sub    %ebp,%r13d
  mov    %r13d,%edi
  call   <pow10@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L77
  nopl   0x0(%rax)
L62:
  add    $0x1,%ebp
L77:
  mov    %ebp,%edi
  call   <pow10@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  D24(%rip),%xmm4
  comisd %xmm0,%xmm4
  ja     L62
  movsd  D28(%rip),%xmm7
  movsd  %xmm7,(%rsp)
  jmp    L78
  nopl   (%rax)
L9:
  sub    $0x1,%ebp
L78:
  mov    %ebp,%edi
  call   <pow10@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  comisd (%rsp),%xmm1
  jae    L9
  add    %r13d,%ebp
  jmp    L96
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type_infered: f32[4]
name: unpack_data
arguments: data_tag: D28
type_infered: f64
name: unpack_data
arguments: data_tag: D15
type_infered: f32[2]
name: unpack_data
arguments: data_tag: D24
type_infered: f64

tool: {"D26": [0.0,-0.0,0.0,0.0]}

tool: D28: 10

tool: {"D15": [0.0,3.125]}

tool: D24: 1

assistant: ```c
int ftoa(double f, char *bp) {
  int e, e1, e2, i;
  double digit, g, p;
  if (f >= 0)
    *bp++ = '+';
  else {
    f = -f;
    *bp++ = '-';
  }
  if (f == 0.)
    e = 1;
  else {
    frexp(f, &e);
    e = -e * 30103 / 100000;
    e1 = e / 2;
    e2 = e - e1;
    p = f * pow10(e2);
    while ((g = p * pow10(e1)) < 1.)
      e1++;
    while ((g = p * pow10(e1)) >= 10.)
      --e1;
    e = e1 + e2;
    f = g;
  }
  for (i = 0; i != 18; i++) {
    f = modf(f, &digit) * 10.;
    *bp++ = digit + '0';
  }
  *bp = '\0';
  return 1 - e;
}
```