ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x0,-0x18(%rbp)
  jmp    L31
L1:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  imul   %rdx,%rax
  cmp    $0x26259ff,%rax
  jbe    L11
  addq   $0x1,-0x10(%rbp)
L11:
  addq   $0x1,-0x18(%rbp)
L31:
  mov    -0x28(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D22
datatype: string

tool: D18:  %lu

tool: D22: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long int area = 0, stars, i, ct = 0, buff;
  scanf(" %lu", &area);
  scanf(" %lu", &stars);
  for (i = 0; i < stars; ++i) {
    scanf(" %lu", &buff);
    if (buff * area >= 40000000)
      ct++;
  }
  printf("%d\n", ct);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rbp
  test   %rbp,%rbp
  je     L7
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D20(%rip),%r12
L10:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  imul   (%rsp),%rax
  cmp    $0x2625a00,%rax
  sbb    $0xffffffffffffffff,%rbp
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  ja     L10
L7:
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type_infered: string
name: extract_symbolic_data
arguments: label: D27
type_infered: string

tool: D20:  %lu

tool: D27: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long int area = 0, stars, i, ct = 0, buff;
  scanf(" %lu", &area);
  scanf(" %lu", &stars);
  for (i = 0; i < stars; ++i) {
    scanf(" %lu", &buff);
    if (buff * area >= 40000000)
      ct++;
  }
  printf("%d\n", ct);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rbp
  test   %rbp,%rbp
  je     L23
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  imul   (%rsp),%rax
  cmp    $0x2625a00,%rax
  sbb    $0xffffffffffffffff,%rbp
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  ja     L25
L23:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D16:  %lu

tool: D4: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long int area = 0, stars, i, ct = 0, buff;
  scanf(" %lu", &area);
  scanf(" %lu", &stars);
  for (i = 0; i < stars; ++i) {
    scanf(" %lu", &buff);
    if (buff * area >= 40000000)
      ct++;
  }
  printf("%d\n", ct);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rbp
  test   %rbp,%rbp
  je     L10
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  imul   (%rsp),%rax
  cmp    $0x2625a00,%rax
  sbb    $0xffffffffffffffff,%rbp
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  ja     L8
L10:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D3
type: string

tool: D15:  %lu

tool: D3: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long int area = 0, stars, i, ct = 0, buff;
  scanf(" %lu", &area);
  scanf(" %lu", &stars);
  for (i = 0; i < stars; ++i) {
    scanf(" %lu", &buff);
    if (buff * area >= 40000000)
      ct++;
  }
  printf("%d\n", ct);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,%eax
  mov    %r8d,-0x40(%rbp)
  mov    %al,-0x3c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movsbl -0x3c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L96
  addq   $0x1,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  movl   $0x1,-0x14(%rbp)
  jmp    L43
L86:
  movsbl -0x3c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L97
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L97:
  mov    -0x40(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L71
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L43:
  cmpl   $0xf,-0x14(%rbp)
  jle    L86
  jmp    L12
L96:
  nop
  jmp    L12
L71:
  nop
L12:
  cmpq   $0x0,-0x30(%rbp)
  je     L5
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L5:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  cmpq   $0x0,-0x8(%rbp)
  jne    L58
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L58:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_args(char *buf, int *argc, char **argv, char sep, int want) {
  char *p = buf, *rp = NULL;
  int i = 0;
  p = strchr(buf, sep);
  if (!p)
    goto out;
  p += 1;
  argv[0] = p;
  for (i = 1; i < 16; i++) {
    p = strchr(p, sep);
    if (!p) {
      rp = p + 1;
      break;
    }
    if (want == i)
      break;
    *p = '\0';
    p += 1;
    argv[i] = p;
  }
out:
  if (argc)
    *argc = i;
  argv[i] = NULL;
  if (!rp)
    rp = strchr(buf, '\0') + 1;
  return rp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_args>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %r8d,%r13d
  movsbl %cl,%r12d
  mov    %r12d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  lea    0x1(%rax),%rdi
  mov    %rdi,(%r14)
  lea    0x8(%r14),%rbp
  mov    $0x1,%ebx
L54:
  mov    %r12d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L55
  cmp    %ebx,%r13d
  je     L29
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  mov    %rdi,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0x10,%ebx
  jne    L54
L25:
  test   %r15,%r15
  je     L11
  mov    %ebx,(%r15)
  movslq %ebx,%rbx
  movq   $0x0,(%r14,%rbx,8)
  jmp    L33
L55:
  test   %r15,%r15
  jne    L6
  movslq %ebx,%rbx
  movq   $0x0,(%r14,%rbx,8)
  mov    $0x1,%eax
  jmp    L41
L11:
  movslq %ebx,%rbx
  movq   $0x0,(%r14,%rbx,8)
L33:
  mov    $0x0,%esi
  mov    0x8(%rsp),%rdi
  call   <strchr@plt>
  add    $0x1,%rax
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    $0x0,%ebx
  jmp    L25
L29:
  mov    %r13d,%ebx
  jmp    L25
L6:
  mov    %ebx,(%r15)
  movslq %ebx,%rbx
  movq   $0x0,(%r14,%rbx,8)
  mov    $0x1,%eax
  jmp    L41
```

assistant: ```c
char *get_args(char *buf, int *argc, char **argv, char sep, int want) {
  char *p = buf, *rp = NULL;
  int i = 0;
  p = strchr(buf, sep);
  if (!p)
    goto out;
  p += 1;
  argv[0] = p;
  for (i = 1; i < 16; i++) {
    p = strchr(p, sep);
    if (!p) {
      rp = p + 1;
      break;
    }
    if (want == i)
      break;
    *p = '\0';
    p += 1;
    argv[i] = p;
  }
out:
  if (argc)
    *argc = i;
  argv[i] = NULL;
  if (!rp)
    rp = strchr(buf, '\0') + 1;
  return rp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_args>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  movsbl %cl,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %ebp,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L35
  lea    0x1(%rax),%rdi
  lea    0x8(%r13),%rbx
  mov    $0x1,%r14d
  mov    %rdi,0x0(%r13)
  nopl   (%rax)
L20:
  mov    %ebp,%esi
  call   <strchr@plt>
  mov    %rbx,%rcx
  test   %rax,%rax
  je     L60
  cmp    %r14d,%r12d
  je     L14
  lea    0x1(%rax),%rdi
  add    $0x1,%r14d
  movb   $0x0,(%rax)
  lea    0x8(%rbx),%rbx
  mov    %rdi,-0x8(%rbx)
  cmp    $0x10,%r14d
  jne    L20
  lea    0x80(%r13),%rcx
  mov    $0x10,%r12d
L14:
  cmpq   $0x0,0x8(%rsp)
  je     L26
  mov    0x8(%rsp),%rax
  mov    %r12d,(%rax)
L26:
  movq   $0x0,(%rcx)
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  add    $0x1,%rax
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L60:
  cmpq   $0x0,0x8(%rsp)
  jne    L1
  movq   $0x0,(%rbx)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  mov    $0x1,%eax
  movq   $0x0,(%rbx)
  jmp    L4
  xchg   %ax,%ax
L35:
  mov    %r13,%rcx
  xor    %r12d,%r12d
  jmp    L14
```

assistant: ```c
char *get_args(char *buf, int *argc, char **argv, char sep, int want) {
  char *p = buf, *rp = NULL;
  int i = 0;
  p = strchr(buf, sep);
  if (!p)
    goto out;
  p += 1;
  argv[0] = p;
  for (i = 1; i < 16; i++) {
    p = strchr(p, sep);
    if (!p) {
      rp = p + 1;
      break;
    }
    if (want == i)
      break;
    *p = '\0';
    p += 1;
    argv[i] = p;
  }
out:
  if (argc)
    *argc = i;
  argv[i] = NULL;
  if (!rp)
    rp = strchr(buf, '\0') + 1;
  return rp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_args>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  movsbl %cl,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %ebp,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  lea    0x1(%rax),%rdi
  lea    0x8(%r13),%rbx
  mov    $0x1,%r14d
  mov    %rdi,0x0(%r13)
  nopl   (%rax)
L55:
  mov    %ebp,%esi
  call   <strchr@plt>
  mov    %rbx,%rcx
  test   %rax,%rax
  je     L64
  cmp    %r14d,%r12d
  je     L25
  lea    0x1(%rax),%rdi
  add    $0x1,%r14d
  movb   $0x0,(%rax)
  lea    0x8(%rbx),%rbx
  mov    %rdi,-0x8(%rbx)
  cmp    $0x10,%r14d
  jne    L55
  lea    0x80(%r13),%rcx
  mov    $0x10,%r12d
L25:
  cmpq   $0x0,0x8(%rsp)
  je     L51
  mov    0x8(%rsp),%rax
  mov    %r12d,(%rax)
L51:
  movq   $0x0,(%rcx)
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  add    $0x1,%rax
L52:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L64:
  cmpq   $0x0,0x8(%rsp)
  jne    L7
  movq   $0x0,(%rbx)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  mov    $0x1,%eax
  movq   $0x0,(%rbx)
  jmp    L52
  xchg   %ax,%ax
L0:
  mov    %r13,%rcx
  xor    %r12d,%r12d
  jmp    L25
```

assistant: ```c
char *get_args(char *buf, int *argc, char **argv, char sep, int want) {
  char *p = buf, *rp = NULL;
  int i = 0;
  p = strchr(buf, sep);
  if (!p)
    goto out;
  p += 1;
  argv[0] = p;
  for (i = 1; i < 16; i++) {
    p = strchr(p, sep);
    if (!p) {
      rp = p + 1;
      break;
    }
    if (want == i)
      break;
    *p = '\0';
    p += 1;
    argv[i] = p;
  }
out:
  if (argc)
    *argc = i;
  argv[i] = NULL;
  if (!rp)
    rp = strchr(buf, '\0') + 1;
  return rp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_exclude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x218(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L37
  mov    -0x218(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L42
L40:
  mov    -0x208(%rbp),%rax
  movb   $0x20,(%rax)
L42:
  lea    -0x70(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x208(%rbp)
  cmpq   $0x0,-0x208(%rbp)
  jne    L40
  lea    -0x200(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse@plt>
  mov    %eax,-0x20c(%rbp)
  jmp    L50
L37:
  movl   $0x1,-0x20c(%rbp)
  mov    -0x218(%rbp),%rax
  mov    %rax,-0x200(%rbp)
L50:
  movl   $0x0,-0x210(%rbp)
  jmp    L27
L11:
  mov    -0x210(%rbp),%eax
  cltq
  mov    -0x200(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <bin_exclude@plt>
  addl   $0x1,-0x210(%rbp)
L27:
  mov    -0x210(%rbp),%eax
  cmp    -0x20c(%rbp),%eax
  jl     L11
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void do_exclude(char *args) {
  int i, argc;
  char *p1, *argv[50];
  char argbuf[100];
  if (strstr(args, ",")) {
    strcpy(argbuf, args);
    while ((p1 = strstr(argbuf, ",")))
      *p1 = ' ';
    argc = parse(argbuf, argv);
  } else {
    argc = 1;
    argv[0] = args;
  }
  for (i = 0; i < argc; i++)
    bin_exclude(argv[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_exclude>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    $0x2c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L63
  lea    0x190(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  lea    0x190(%rsp),%rbx
L49:
  mov    $0x2c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L68
  movb   $0x20,(%rax)
  jmp    L49
L68:
  mov    %rsp,%rsi
  lea    0x190(%rsp),%rdi
  call   <parse@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
  test   %eax,%eax
  jle    L12
L38:
  mov    (%rsp,%rbx,8),%rdi
  call   <bin_exclude@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L38
  jmp    L12
L63:
  mov    %rbx,(%rsp)
  mov    %rbx,%rdi
  call   <bin_exclude@plt>
L12:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_exclude(char *args) {
  int i, argc;
  char *p1, *argv[50];
  char argbuf[100];
  if (strstr(args, ",")) {
    strcpy(argbuf, args);
    while ((p1 = strstr(argbuf, ",")))
      *p1 = ' ';
    argc = parse(argbuf, argv);
  } else {
    argc = 1;
    argv[0] = args;
  }
  for (i = 0; i < argc; i++)
    bin_exclude(argv[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<do_exclude>:
  endbr64
  push   %r12
  mov    $0x2c,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  lea    0x190(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L43
  nopl   0x0(%rax)
L10:
  movb   $0x20,(%rax)
L43:
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L10
  mov    %rsp,%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <parse@plt>
  test   %eax,%eax
  jg     L52
L58:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x200,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    %r12,%rdi
  mov    %r12,(%rsp)
  call   <bin_exclude@plt>
  jmp    L58
L52:
  sub    $0x1,%eax
  lea    0x8(%rsp,%rax,8),%rbp
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <bin_exclude@plt>
  cmp    %rbp,%rbx
  jne    L19
  jmp    L58
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_exclude(char *args) {
  int i, argc;
  char *p1, *argv[50];
  char argbuf[100];
  if (strstr(args, ",")) {
    strcpy(argbuf, args);
    while ((p1 = strstr(argbuf, ",")))
      *p1 = ' ';
    argc = parse(argbuf, argv);
  } else {
    argc = 1;
    argv[0] = args;
  }
  for (i = 0; i < argc; i++)
    bin_exclude(argv[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_exclude>:
  endbr64
  push   %r12
  mov    $0x2c,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L18
  lea    0x190(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L75
  nopl   0x0(%rax)
L36:
  movb   $0x20,(%rax)
L75:
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L36
  mov    %rsp,%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <parse@plt>
  test   %eax,%eax
  jg     L25
L74:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x200,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  mov    %r12,(%rsp)
  call   <bin_exclude@plt>
  jmp    L74
L25:
  sub    $0x1,%eax
  lea    0x8(%rsp,%rax,8),%rbp
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <bin_exclude@plt>
  cmp    %rbp,%rbx
  jne    L45
  jmp    L74
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_exclude(char *args) {
  int i, argc;
  char *p1, *argv[50];
  char argbuf[100];
  if (strstr(args, ",")) {
    strcpy(argbuf, args);
    while ((p1 = strstr(argbuf, ",")))
      *p1 = ' ';
    argc = parse(argbuf, argv);
  } else {
    argc = 1;
    argv[0] = args;
  }
  for (i = 0; i < argc; i++)
    bin_exclude(argv[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L23
L59:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x3c(%rbp)
L23:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L59
  movl   $0x0,-0x3c(%rbp)
  jmp    L74
L18:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L74:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  addq   $0x4,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L15
L63:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L15:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L63
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  subq   $0x4,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L51
L44:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L51:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L44
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D28
datatype: string

tool: D28: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int a[10], i;
  int *pa = &a[0];
  for (i = 0; i < 10; i++)
    pa[i] = i;
  for (i = 0; i < 10; i++)
    printf("%d ", pa[i]);
  printf("\n");
  pa += 1;
  for (i = 0; i < 10; i++)
    printf("%d ", pa[i]);
  printf("\n");
  pa = a;
  pa--;
  for (i = 0; i < 10; i++)
    printf("%d ", pa[i]);
  printf("\n");
  return 0;
}
```