ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D11(%rip),%r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  lea    D39(%rip),%r12
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rdi
  call   <system@plt>
  mov    %ebx,%edi
  call   <draw_x@plt>
  mov    %ebp,%edi
  call   <draw_y@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <kbhit@plt>
  test   %rax,%rax
  je     L25
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0x73,%al
  je     L62
  jg     L88
  cmp    $0x61,%al
  je     L80
  cmp    $0x64,%al
  jne    L16
  add    $0x1,%ebp
  jmp    L25
  nopl   0x0(%rax)
L88:
  cmp    $0x77,%al
  jne    L16
  sub    $0x1,%ebx
  jmp    L25
  nopl   0x0(%rax)
L62:
  add    $0x1,%ebx
  jmp    L25
  nopl   (%rax)
L16:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L80:
  sub    $0x1,%ebp
  jmp    L25
```

tool_calls: name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D7
data_type: string
name: unpack_data
arguments: label: D15
data_type: string
name: unpack_data
arguments: label: D39
data_type: string

tool: D11: Please input a/d/w/s


tool: D7: clear

tool: D15: *

tool: D39: 


assistant: ```c
int main(int argc, char *argv[]) {
  int axis_x = 5;
  int axis_y = 10;
  char user_input;
  while (1) {
    system("clear");
    draw_x(axis_x);
    draw_y(axis_y);
    printf("*");
    printf("\n");
    if (kbhit()) {
      user_input = getch();
      switch (user_input) {
      case 'a':
        axis_y--;
        break;
      case 'd':
        axis_y++;
        break;
      case 'w':
        axis_x--;
        break;
      case 's':
        axis_x++;
        break;
      default:
        printf("Please input a/d/w/s\n");
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rdi
  call   <system@plt>
  mov    %ebx,%edi
  call   <draw_x@plt>
  mov    %ebp,%edi
  call   <draw_y@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <kbhit@plt>
  test   %rax,%rax
  je     L25
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0x73,%al
  je     L14
  jg     L108
  cmp    $0x61,%al
  je     L82
  cmp    $0x64,%al
  jne    L94
  add    $0x1,%ebp
  jmp    L25
  nopl   0x0(%rax)
L108:
  cmp    $0x77,%al
  jne    L94
  sub    $0x1,%ebx
  jmp    L25
  nopl   0x0(%rax)
L14:
  add    $0x1,%ebx
  jmp    L25
  nopl   (%rax)
L94:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L82:
  sub    $0x1,%ebp
  jmp    L25
```

tool_calls: name: read_data
arguments: data_label: D16
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string

tool: D16: Please input a/d/w/s


tool: D17: clear

tool: D15: *

tool: D0: 


assistant: ```c
int main(int argc, char *argv[]) {
  int axis_x = 5;
  int axis_y = 10;
  char user_input;
  while (1) {
    system("clear");
    draw_x(axis_x);
    draw_y(axis_y);
    printf("*");
    printf("\n");
    if (kbhit()) {
      user_input = getch();
      switch (user_input) {
      case 'a':
        axis_y--;
        break;
      case 'd':
        axis_y++;
        break;
      case 'w':
        axis_x--;
        break;
      case 's':
        axis_x++;
        break;
      default:
        printf("Please input a/d/w/s\n");
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L7
  andl   $0xffffffdf,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    c &= ~0x20;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<toupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <islower@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    c &= ~0x20;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <islower@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  and    $0xffffffdf,%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    c &= ~0x20;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <islower@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  and    $0xffffffdf,%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    c &= ~0x20;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printLogHeader>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    (%rsp),%edx
  movslq %edx,%r9
  imul   $0x10624dd3,%r9,%r9
  sar    $0x26,%r9
  sar    $0x1f,%edx
  sub    %edx,%r9d
  cmp    $0x1e,%ebx
  je     L48
  jle    L68
  cmp    $0x28,%ebx
  je     L5
  cmp    $0x32,%ebx
  jne    L103
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  jmp    L103
L68:
  cmp    $0xa,%ebx
  je     L91
  cmp    $0x14,%ebx
  jne    L103
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  jmp    L103
L91:
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
L103:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  jmp    L103
L5:
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  jmp    L103
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D44
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D35
datatype: string

tool: D10: %02d:%02d:%02d,%03d CRITICAL: 

tool: D19: %02d:%02d:%02d,%03d INFO    : 

tool: D44: %02d:%02d:%02d,%03d DEBUG   : 

tool: D25: %02d:%02d:%02d,%03d WARNING : 

tool: D35: %02d:%02d:%02d,%03d ERROR   : 

assistant: ```c
void printLogHeader(int level, FILE *outfile) {
  struct timeval current_time;
  struct tm *t;
  int msecs;
  gettimeofday(&current_time, NULL);
  t = gmtime(&current_time.tv_sec);
  msecs = current_time.tv_usec / 1000;
  switch (level) {
  case 10:
    fprintf(outfile, "%02d:%02d:%02d,%03d DEBUG   : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 20:
    fprintf(outfile, "%02d:%02d:%02d,%03d INFO    : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 30:
    fprintf(outfile, "%02d:%02d:%02d,%03d WARNING : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 40:
    fprintf(outfile, "%02d:%02d:%02d,%03d ERROR   : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 50:
    fprintf(outfile, "%02d:%02d:%02d,%03d CRITICAL: ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printLogHeader>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  movslq (%rsp),%r9
  mov    %r9,%rdx
  imul   $0x10624dd3,%r9,%r9
  sar    $0x1f,%edx
  sar    $0x26,%r9
  sub    %edx,%r9d
  cmp    $0x1e,%ebx
  je     L43
  jle    L69
  cmp    $0x28,%ebx
  je     L5
  cmp    $0x32,%ebx
  jne    L16
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  cmp    $0xa,%ebx
  je     L100
  cmp    $0x14,%ebx
  jne    L16
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L16
  nopl   0x0(%rax)
L43:
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L5:
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L16
  nopl   (%rax)
L100:
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L16
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D24
type_infered: string
name: disassemble_data
arguments: label: D15
type_infered: string
name: disassemble_data
arguments: label: D21
type_infered: string

tool: D2: %02d:%02d:%02d,%03d CRITICAL: 

tool: D18: %02d:%02d:%02d,%03d INFO    : 

tool: D24: %02d:%02d:%02d,%03d WARNING : 

tool: D15: %02d:%02d:%02d,%03d ERROR   : 

tool: D21: %02d:%02d:%02d,%03d DEBUG   : 

assistant: ```c
void printLogHeader(int level, FILE *outfile) {
  struct timeval current_time;
  struct tm *t;
  int msecs;
  gettimeofday(&current_time, NULL);
  t = gmtime(&current_time.tv_sec);
  msecs = current_time.tv_usec / 1000;
  switch (level) {
  case 10:
    fprintf(outfile, "%02d:%02d:%02d,%03d DEBUG   : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 20:
    fprintf(outfile, "%02d:%02d:%02d,%03d INFO    : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 30:
    fprintf(outfile, "%02d:%02d:%02d,%03d WARNING : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 40:
    fprintf(outfile, "%02d:%02d:%02d,%03d ERROR   : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 50:
    fprintf(outfile, "%02d:%02d:%02d,%03d CRITICAL: ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printLogHeader>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  movslq (%rsp),%r9
  mov    %r9,%rdx
  imul   $0x10624dd3,%r9,%r9
  sar    $0x1f,%edx
  sar    $0x26,%r9
  sub    %edx,%r9d
  cmp    $0x1e,%ebx
  je     L38
  jle    L88
  cmp    $0x28,%ebx
  je     L50
  cmp    $0x32,%ebx
  jne    L55
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D42(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  cmp    $0xa,%ebx
  je     L19
  cmp    $0x14,%ebx
  jne    L55
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D43(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L55
  nopl   0x0(%rax)
L38:
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L50:
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D47(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L55
  nopl   (%rax)
L19:
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%r8d
  call   <fprintf@plt>
  jmp    L55
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D42
datatype: string
name: parse_data
arguments: data_tag: D43
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D47
datatype: string
name: parse_data
arguments: data_tag: D13
datatype: string

tool: D42: %02d:%02d:%02d,%03d CRITICAL: 

tool: D43: %02d:%02d:%02d,%03d INFO    : 

tool: D4: %02d:%02d:%02d,%03d WARNING : 

tool: D47: %02d:%02d:%02d,%03d ERROR   : 

tool: D13: %02d:%02d:%02d,%03d DEBUG   : 

assistant: ```c
void printLogHeader(int level, FILE *outfile) {
  struct timeval current_time;
  struct tm *t;
  int msecs;
  gettimeofday(&current_time, NULL);
  t = gmtime(&current_time.tv_sec);
  msecs = current_time.tv_usec / 1000;
  switch (level) {
  case 10:
    fprintf(outfile, "%02d:%02d:%02d,%03d DEBUG   : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 20:
    fprintf(outfile, "%02d:%02d:%02d,%03d INFO    : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 30:
    fprintf(outfile, "%02d:%02d:%02d,%03d WARNING : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 40:
    fprintf(outfile, "%02d:%02d:%02d,%03d ERROR   : ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  case 50:
    fprintf(outfile, "%02d:%02d:%02d,%03d CRITICAL: ", t->tm_hour, t->tm_min, t->tm_sec, msecs);
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_putnbr_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  negl   -0x4(%rbp)
  mov    $0x2d,%edi
  call   <my_putchar@plt>
L13:
  cmpl   $0x0,-0x4(%rbp)
  je     L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <my_putnbr_base>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  cltd
  idiv   %esi
  mov    %edx,%ecx
  mov    %ecx,%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <my_putchar@plt>
L10:
  nop
  leave
  ret
```

assistant: ```c
void my_putnbr_base(int nbr, char *base) {
  if (nbr < 0) {
    nbr = -nbr;
    my_putchar('-');
  }
  if (nbr != 0) {
    my_putnbr_base((nbr / my_strlen(base)), base);
    my_putchar(base[(nbr % my_strlen(base))]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_putnbr_base>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %edi,%edi
  js     L18
  jne    L25
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  neg    %ebx
  mov    $0x2d,%edi
  call   <my_putchar@plt>
L25:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <my_putnbr_base>
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movsbl 0x0(%rbp,%rdx,1),%edi
  call   <my_putchar@plt>
  jmp    L29
```

assistant: ```c
void my_putnbr_base(int nbr, char *base) {
  if (nbr < 0) {
    nbr = -nbr;
    my_putchar('-');
  }
  if (nbr != 0) {
    my_putnbr_base((nbr / my_strlen(base)), base);
    my_putchar(base[(nbr % my_strlen(base))]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_putnbr_base>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L17
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x2d,%edi
  neg    %ebx
  call   <my_putchar@plt>
L18:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %rbp,%rsi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%edi
  call   <my_putnbr_base>
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  movsbl 0x0(%rbp,%rdx,1),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <my_putchar@plt>
```

assistant: ```c
void my_putnbr_base(int nbr, char *base) {
  if (nbr < 0) {
    nbr = -nbr;
    my_putchar('-');
  }
  if (nbr != 0) {
    my_putnbr_base((nbr / my_strlen(base)), base);
    my_putchar(base[(nbr % my_strlen(base))]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_putnbr_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L12
  jne    L30
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x2d,%edi
  neg    %ebx
  call   <my_putchar@plt>
L30:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  test   %eax,%eax
  js     L64
  jne    L47
L35:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  movsbl 0x0(%rbp,%rdx,1),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <my_putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L64:
  mov    $0x2d,%edi
  neg    %r12d
  call   <my_putchar@plt>
L47:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r13d
  test   %eax,%eax
  js     L3
  jne    L38
L66:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  movsbl 0x0(%rbp,%rdx,1),%edi
  call   <my_putchar@plt>
  jmp    L35
  nopl   0x0(%rax)
L3:
  mov    $0x2d,%edi
  neg    %r13d
  call   <my_putchar@plt>
L38:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %rbp,%rsi
  mov    %eax,%r8d
  mov    %r13d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%edi
  call   <my_putnbr_base>
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %r13d,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  movsbl 0x0(%rbp,%rdx,1),%edi
  call   <my_putchar@plt>
  jmp    L66
```

assistant: ```c
void my_putnbr_base(int nbr, char *base) {
  if (nbr < 0) {
    nbr = -nbr;
    my_putchar('-');
  }
  if (nbr != 0) {
    my_putnbr_base((nbr / my_strlen(base)), base);
    my_putchar(base[(nbr % my_strlen(base))]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<median3>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rdi
  mov    (%rdi),%r8d
  add    %edx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%esi
  cmp    %esi,%r8d
  jle    L24
  mov    %r8d,(%rax)
  mov    %esi,(%rdi)
L24:
  mov    (%rdi),%r9d
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    (%rsi),%r8d
  cmp    %r8d,%r9d
  jle    L3
  mov    %r9d,(%rsi)
  mov    %r8d,(%rdi)
L3:
  mov    (%rax),%r8d
  mov    (%rsi),%edi
  cmp    %edi,%r8d
  jle    L17
  mov    %r8d,(%rsi)
  mov    %edi,(%rax)
L17:
  lea    -0x4(%rcx,%rdx,1),%rdx
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  mov    (%rdx),%eax
  ret
```

assistant: ```c
int median3(int a[], int left, int right) {
  int center = (left + right) / 2;
  if (a[left] > a[center])
    do {
      typeof(a[left]) t = a[center];
      a[center] = a[left];
      a[left] = t;
    } while (0);
  if (a[left] > a[right])
    do {
      typeof(a[left]) t = a[right];
      a[right] = a[left];
      a[left] = t;
    } while (0);
  if (a[center] > a[right])
    do {
      typeof(a[center]) t = a[right];
      a[right] = a[center];
      a[center] = t;
    } while (0);
  do {
    typeof(a[center]) t = a[right - 1];
    a[right - 1] = a[center];
    a[center] = t;
  } while (0);
  return a[right - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<median3>:
  endbr64
  movslq %esi,%rax
  add    %edx,%esi
  mov    %rdi,%rcx
  lea    (%rdi,%rax,4),%r9
  mov    %esi,%eax
  shr    $0x1f,%eax
  mov    (%r9),%edi
  add    %esi,%eax
  sar    %eax
  cltq
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%esi
  cmp    %esi,%edi
  jle    L8
  mov    %edi,(%rax)
  mov    %esi,%edi
  mov    %esi,(%r9)
L8:
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rcx,%rdx,1),%r8
  mov    (%r8),%esi
  cmp    %edi,%esi
  jge    L23
  mov    %edi,(%r8)
  mov    %esi,(%r9)
  mov    (%r8),%esi
L23:
  mov    (%rax),%edi
  cmp    %esi,%edi
  jle    L18
  mov    %edi,(%r8)
  mov    %esi,%edi
  mov    %esi,(%rax)
L18:
  lea    -0x4(%rcx,%rdx,1),%rdx
  mov    (%rdx),%ecx
  mov    %edi,(%rdx)
  mov    %ecx,(%rax)
  mov    (%rdx),%eax
  ret
```

assistant: ```c
int median3(int a[], int left, int right) {
  int center = (left + right) / 2;
  if (a[left] > a[center])
    do {
      typeof(a[left]) t = a[center];
      a[center] = a[left];
      a[left] = t;
    } while (0);
  if (a[left] > a[right])
    do {
      typeof(a[left]) t = a[right];
      a[right] = a[left];
      a[left] = t;
    } while (0);
  if (a[center] > a[right])
    do {
      typeof(a[center]) t = a[right];
      a[right] = a[center];
      a[center] = t;
    } while (0);
  do {
    typeof(a[center]) t = a[right - 1];
    a[right - 1] = a[center];
    a[center] = t;
  } while (0);
  return a[right - 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<median3>:
  endbr64
  movslq %esi,%rax
  add    %edx,%esi
  mov    %rdi,%rcx
  lea    (%rdi,%rax,4),%r9
  mov    %esi,%eax
  shr    $0x1f,%eax
  mov    (%r9),%edi
  add    %esi,%eax
  sar    %eax
  cltq
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%esi
  cmp    %esi,%edi
  jle    L3
  mov    %edi,(%rax)
  mov    %esi,%edi
  mov    %esi,(%r9)
L3:
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rcx,%rdx,1),%r8
  mov    (%r8),%esi
  cmp    %edi,%esi
  jge    L12
  mov    %edi,(%r8)
  mov    %esi,(%r9)
  mov    (%r8),%esi
L12:
  mov    (%rax),%edi
  cmp    %esi,%edi
  jle    L1
  mov    %edi,(%r8)
  mov    %esi,%edi
  mov    %esi,(%rax)
L1:
  lea    -0x4(%rcx,%rdx,1),%rdx
  mov    (%rdx),%ecx
  mov    %edi,(%rdx)
  mov    %ecx,(%rax)
  mov    (%rdx),%eax
  ret
```

assistant: ```c
int median3(int a[], int left, int right) {
  int center = (left + right) / 2;
  if (a[left] > a[center])
    do {
      typeof(a[left]) t = a[center];
      a[center] = a[left];
      a[left] = t;
    } while (0);
  if (a[left] > a[right])
    do {
      typeof(a[left]) t = a[right];
      a[right] = a[left];
      a[left] = t;
    } while (0);
  if (a[center] > a[right])
    do {
      typeof(a[center]) t = a[right];
      a[right] = a[center];
      a[center] = t;
    } while (0);
  do {
    typeof(a[center]) t = a[right - 1];
    a[right - 1] = a[center];
    a[center] = t;
  } while (0);
  return a[right - 1];
}
```