ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix_multiply>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x18(%rsp)
  mov    %ecx,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  test   %ecx,%ecx
  jle    L63
  mov    %rdx,%rbp
  mov    %r9d,%ebx
  test   %r9d,%r9d
  jle    L68
  mov    %r8d,%eax
  test   %r8d,%r8d
  jle    L68
  add    $0x4,%rdi
  sub    $0x1,%eax
  mov    %rdx,0x10(%rsp)
  movslq %r9d,%r13
  mov    %rdi,0x28(%rsp)
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  mov    %rax,0x20(%rsp)
  lea    0x0(,%r13,4),%r9
  nopl   0x0(%rax)
L33:
  mov    (%rsp),%rcx
  movslq %r14d,%rax
  mov    0x10(%rsp),%rdi
  movslq %r15d,%rdx
  mov    0x18(%rsp),%r11
  xor    %r10d,%r10d
  lea    (%rcx,%rax,4),%rbp
  mov    0x28(%rsp),%rcx
  add    0x20(%rsp),%rax
  lea    (%rdi,%rdx,4),%rdi
  lea    (%rcx,%rax,4),%r8
  nopl   (%rax)
L27:
  mov    (%rdi),%esi
  mov    %r11,%rcx
  mov    %rbp,%rax
L83:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    $0x4,%rax
  add    %r9,%rcx
  add    %edx,%esi
  mov    %esi,(%rdi)
  cmp    %rax,%r8
  jne    L83
  add    $0x1,%r10
  add    $0x4,%rdi
  add    $0x4,%r11
  cmp    %r13,%r10
  jne    L27
  add    $0x1,%r12d
  add    0xc(%rsp),%r14d
  add    %ebx,%r15d
  cmp    %r12d,0x8(%rsp)
  jne    L33
  mov    0x10(%rsp),%rbp
L68:
  mov    %rbp,(%rsp)
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  lea    D2(%rip),%r13
  nop
L80:
  test   %ebx,%ebx
  jle    L14
  mov    (%rsp),%rdi
  movslq %r15d,%rcx
  lea    -0x1(%rbx),%eax
  add    %rcx,%rax
  lea    (%rdi,%rcx,4),%rbp
  lea    0x4(%rdi,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L42:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L42
L14:
  mov    $0xa,%edi
  add    $0x1,%r14d
  add    %ebx,%r15d
  call   <putchar@plt>
  cmp    %r14d,0x8(%rsp)
  jne    L80
L63:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: %d	

assistant: ```c
void matrix_multiply(int *m1, int *m2, int *r, int x, int y, int z) {
  int row = 0;
  int col = 0;
  int temp = 0;
  int position = 0;
  int b = 0;
  int c = 0;
  for (row = 0; row < x; row++) {
    for (temp = 0; temp < z; temp++) {
      for (position = 0; position < y; position++) {
        b = (*(m1 + row * y + position));
        c = (*(m2 + position * z + temp));
        (*(r + row * z + temp)) += (b * c);
      }
    }
  }
  for (row = 0; row < x; row++) {
    for (col = 0; col < z; col++) {
      printf("%d\t", *(r + row * z + col));
    }
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<charalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *charalloc(char *in) {
  char *buf;
  buf = calloc(strlen(in) + 1, 1);
  strcpy(buf, in);
  return (char *)buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<charalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *charalloc(char *in) {
  char *buf;
  buf = calloc(strlen(in) + 1, 1);
  strcpy(buf, in);
  return (char *)buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<charalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *charalloc(char *in) {
  char *buf;
  buf = calloc(strlen(in) + 1, 1);
  strcpy(buf, in);
  return (char *)buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<charalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *charalloc(char *in) {
  char *buf;
  buf = calloc(strlen(in) + 1, 1);
  strcpy(buf, in);
  return (char *)buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L5
L6:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L38
L5:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int is_in(int ch, char *s) {
  while (*s)
    if (*s++ == ch)
      return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_in>:
  endbr64
L10:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rsi
  movsbl %al,%eax
  cmp    %edi,%eax
  jne    L10
  mov    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_in(int ch, char *s) {
  while (*s)
    if (*s++ == ch)
      return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_in>:
  endbr64
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x1,%rsi
  cmp    %edi,%eax
  je     L28
L19:
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L18
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_in(int ch, char *s) {
  while (*s)
    if (*s++ == ch)
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_in>:
  endbr64
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x1,%rsi
  cmp    %edi,%eax
  je     L10
L28:
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L18
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_in(int ch, char *s) {
  while (*s)
    if (*s++ == ch)
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prune_sub1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x8,%eax
  ja     L9
  mov    -0x34(%rbp),%eax
  movl   $0x0,-0x30(%rbp,%rax,4)
L9:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void prune_sub1(unsigned int x) {
  int a[10];
  if (9 > x - 1) {
    a[x] = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<prune_sub1>:
  endbr64
  ret
```

assistant: ```c
void prune_sub1(unsigned int x) {
  int a[10];
  if (9 > x - 1) {
    a[x] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prune_sub1>:
  endbr64
  ret
```

assistant: ```c
void prune_sub1(unsigned int x) {
  int a[10];
  if (9 > x - 1) {
    a[x] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prune_sub1>:
  endbr64
  ret
```

assistant: ```c
void prune_sub1(unsigned int x) {
  int a[10];
  if (9 > x - 1) {
    a[x] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_isdigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L0
  cmpl   $0x39,-0x4(%rbp)
  jg     L0
  mov    $0x1,%eax
  jmp    L25
L0:
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c >= '0' && c <= '9') {
    return (1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isdigit>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c >= '0' && c <= '9') {
    return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_isdigit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c >= '0' && c <= '9') {
    return (1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_isdigit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c >= '0' && c <= '9') {
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<p2floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  jmp    L16
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t p2floor(uint64_t x) {
  uint64_t y;
  while ((y = x & (x - 1)))
    x = y;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p2floor>:
  endbr64
L1:
  mov    %edi,%edx
  lea    -0x1(%rdi),%eax
  and    %eax,%edi
  jne    L1
  mov    %edx,%eax
  ret
```

assistant: ```c
uint64_t p2floor(uint64_t x) {
  uint64_t y;
  while ((y = x & (x - 1)))
    x = y;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<p2floor>:
  endbr64
  nopl   0x0(%rax)
L2:
  lea    -0x1(%rdi),%eax
  mov    %edi,%r8d
  and    %eax,%edi
  jne    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t p2floor(uint64_t x) {
  uint64_t y;
  while ((y = x & (x - 1)))
    x = y;
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<p2floor>:
  endbr64
  nopl   0x0(%rax)
L1:
  lea    -0x1(%rdi),%eax
  mov    %edi,%r8d
  and    %eax,%edi
  jne    L1
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t p2floor(uint64_t x) {
  uint64_t y;
  while ((y = x & (x - 1)))
    x = y;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<destructor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *destructor(void *const _self) {
  struct RESTc_OAuth2Authenticator *const self = _self;
  return self;
}
```
user: Translate the below assembly code into C programming language:

```asm
<destructor>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *destructor(void *const _self) {
  struct RESTc_OAuth2Authenticator *const self = _self;
  return self;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<destructor>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *destructor(void *const _self) {
  struct RESTc_OAuth2Authenticator *const self = _self;
  return self;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<destructor>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *destructor(void *const _self) {
  struct RESTc_OAuth2Authenticator *const self = _self;
  return self;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L6
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy_backwards@plt>
  jmp    L15
L6:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy_forward@plt>
L15:
  leave
  ret
```

assistant: ```c
void *my_memmove(void *dst, void *src, size_t n) {
  if (dst > src)
    return memcpy_backwards(dst, src, n);
  else
    return memcpy_forward(dst, src, n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_memmove>:
  endbr64
  sub    $0x8,%rsp
  cmp    %rsi,%rdi
  jbe    L2
  call   <memcpy_backwards@plt>
L3:
  add    $0x8,%rsp
  ret
L2:
  call   <memcpy_forward@plt>
  jmp    L3
```

assistant: ```c
void *my_memmove(void *dst, void *src, size_t n) {
  if (dst > src)
    return memcpy_backwards(dst, src, n);
  else
    return memcpy_forward(dst, src, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_memmove>:
  endbr64
  cmp    %rsi,%rdi
  jbe    L6
  jmp    1060 <memcpy_backwards@plt>
  xchg   %ax,%ax
L6:
  jmp    1070 <memcpy_forward@plt>
```

assistant: ```c
void *my_memmove(void *dst, void *src, size_t n) {
  if (dst > src)
    return memcpy_backwards(dst, src, n);
  else
    return memcpy_forward(dst, src, n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_memmove>:
  endbr64
  cmp    %rsi,%rdi
  jbe    L1
  jmp    1060 <memcpy_backwards@plt>
  xchg   %ax,%ax
L1:
  jmp    1070 <memcpy_forward@plt>
```

assistant: ```c
void *my_memmove(void *dst, void *src, size_t n) {
  if (dst > src)
    return memcpy_backwards(dst, src, n);
  else
    return memcpy_forward(dst, src, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_double_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: %.2e 

assistant: ```c
void print_double_line(double *line, int dim1) {
  int i;
  printf("\n");
  for (i = 0; i < dim1; i++)
    printf("%.2e ", line[i]);
  printf("\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_double_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L8
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D1(%rip),%rbp
L7:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L7
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: %.2e 

assistant: ```c
void print_double_line(double *line, int dim1) {
  int i;
  printf("\n");
  for (i = 0; i < dim1; i++)
    printf("%.2e ", line[i]);
  printf("\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_double_line>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L8
  lea    -0x1(%rbp),%eax
  lea    D2(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
L8:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D2: %.2e 

assistant: ```c
void print_double_line(double *line, int dim1) {
  int i;
  printf("\n");
  for (i = 0; i < dim1; i++)
    printf("%.2e ", line[i]);
  printf("\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_double_line>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L15
  lea    -0x1(%rbp),%eax
  lea    D0(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L4:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
L15:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: %.2e 

assistant: ```c
void print_double_line(double *line, int dim1) {
  int i;
  printf("\n");
  for (i = 0; i < dim1; i++)
    printf("%.2e ", line[i]);
  printf("\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getsuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rbx
  mov    $0x0,%r12d
  jmp    L61
L20:
  cmp    $0x2f,%r13d
  jne    L68
  mov    $0x0,%r12d
  jmp    L61
L68:
  add    $0x1,%r12d
L61:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movsbl %al,%r13d
  test   %r13d,%r13d
  jne    L20
  mov    $0xfffffffffffffffd,%rbx
  cmp    $0xe,%r12d
  jg     L70
  cmp    $0x2,%r12d
  jle    L70
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L70
  movzbl (%rbx),%eax
  movsbl %al,%eax
  jmp    L42
L70:
  mov    $0x0,%eax
L42:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
getsuf(as) char as[];
{
  register int c;
  register char *s;
  register int t;
  s = as;
  c = 0;
  while (t = *s++)
    if (t == '/')
      c = 0;
    else
      c++;
  s = -3;
  if (c <= 14 && c > 2 && *s++ == '.')
    return (*s);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getsuf>:
  endbr64
  lea    0x1(%rdi),%rcx
  movsbl (%rdi),%edx
  test   %edx,%edx
  je     L35
  mov    $0x0,%eax
  mov    $0x0,%esi
L23:
  add    $0x1,%eax
  cmp    $0x2f,%edx
  cmove  %esi,%eax
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L23
  sub    $0x3,%eax
  cmp    $0xb,%eax
  ja     L35
  cmpb   $0x2e,0xfffffffffffffffd
  je     L12
L35:
  mov    %edx,%eax
  ret
L12:
  movsbl 0xfffffffffffffffe,%edx
  jmp    L35
```

assistant: ```c
getsuf(as) char as[];
{
  register int c;
  register char *s;
  register int t;
  s = as;
  c = 0;
  while (t = *s++)
    if (t == '/')
      c = 0;
    else
      c++;
  s = -3;
  if (c <= 14 && c > 2 && *s++ == '.')
    return (*s);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getsuf>:
  endbr64
  movsbl (%rdi),%r8d
  lea    0x1(%rdi),%rdx
  test   %r8d,%r8d
  je     L28
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   (%rax)
L12:
  add    $0x1,%eax
  cmp    $0x2f,%r8d
  cmove  %ecx,%eax
  movsbl (%rdx),%r8d
  add    $0x1,%rdx
  test   %r8d,%r8d
  jne    L12
  sub    $0x3,%eax
  cmp    $0xb,%eax
  ja     L28
  cmpb   $0x2e,0xfffffffffffffffd
  je     L37
L28:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L37:
  movsbl 0xfffffffffffffffe,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
getsuf(as) char as[];
{
  register int c;
  register char *s;
  register int t;
  s = as;
  c = 0;
  while (t = *s++)
    if (t == '/')
      c = 0;
    else
      c++;
  s = -3;
  if (c <= 14 && c > 2 && *s++ == '.')
    return (*s);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getsuf>:
  endbr64
  movsbl (%rdi),%r8d
  lea    0x1(%rdi),%rdx
  test   %r8d,%r8d
  je     L27
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   (%rax)
L38:
  add    $0x1,%eax
  cmp    $0x2f,%r8d
  cmove  %ecx,%eax
  movsbl (%rdx),%r8d
  add    $0x1,%rdx
  test   %r8d,%r8d
  jne    L38
  sub    $0x3,%eax
  cmp    $0xb,%eax
  ja     L27
  cmpb   $0x2e,0xfffffffffffffffd
  je     L39
L27:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L39:
  movsbl 0xfffffffffffffffe,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
getsuf(as) char as[];
{
  register int c;
  register char *s;
  register int t;
  s = as;
  c = 0;
  while (t = *s++)
    if (t == '/')
      c = 0;
    else
      c++;
  s = -3;
  if (c <= 14 && c > 2 && *s++ == '.')
    return (*s);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x13,%eax
  jle    L3
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D42(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L7
L3:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D29(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D42(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
L7:
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D54
datatype: string
name: retrieve_data
arguments: data_label: D22
datatype: f64
name: retrieve_data
arguments: data_label: D42
datatype: byte[8]
name: retrieve_data
arguments: data_label: D29
datatype: f64
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D54: %d %d

tool: D22: 80

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D29: 90

tool: D15: %.2f

assistant: ```c
int main() {
  int user, price;
  scanf("%d %d", &user, &price);
  printf("%.2f", (user >= 20) ? price * user * 80.0 / 100 : ((user / 2) * 2) * price * 90.0 / 100 + (user % 2) * price);
  return 0;
}
```