ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  setne  %cl
  setne  %dl
  movzbl %cl,%ecx
  cmp    %ecx,%edi
  jle    L10
  lea    -0x1(%rdi),%eax
  movzbl %dl,%edx
  push   %r14
  lea    D7(%rip),%r14
  sub    %ecx,%eax
  push   %r13
  lea    D17(%rip),%r13
  add    %rdx,%rax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    (%rsi,%rdx,8),%rbx
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    (%rbx),%rdi
  call   <ft_file_to_str@plt>
  mov    %rax,%rdi
  test   %rdi,%rdi
  je     L43
L1:
  call   <ft_handle_bsq@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L38
L59:
  cmp    $0x1,%ebp
  jne    L41
  xor    %eax,%eax
  call   <ft_stdin_file@plt>
  mov    %r13,%rdi
  call   <ft_file_to_str@plt>
  mov    %rax,%rdi
  test   %rdi,%rdi
  jne    L1
L43:
  mov    %r14,%rdi
  add    $0x8,%rbx
  call   <ft_puterr@plt>
  cmp    %r12,%rbx
  jne    L59
L38:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string

tool: D7: map error


tool: D17: temp

assistant: ```c
int main(int argc, char **argv) {
  char *map;
  int i;
  i = 0;
  if (argc != 1)
    i = 1;
  while (i < argc) {
    if (argc == 1) {
      ft_stdin_file();
      map = ft_file_to_str("temp");
      i++;
    } else
      map = ft_file_to_str(argv[i++]);
    if (!map)
      ft_puterr("map error\n");
    else
      ft_handle_bsq(map);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  push   %r12
  push   %rbp
  setne  %bpl
  setne  %al
  movzbl %bpl,%ebp
  push   %rbx
  cmp    %ebp,%edi
  jle    L72
  lea    D4(%rip),%rbx
  lea    D13(%rip),%r12
  cmp    $0x1,%edi
  je     L74
  sub    $0x1,%edi
  movzbl %al,%eax
  lea    D13(%rip),%r12
  sub    %ebp,%edi
  lea    (%rsi,%rax,8),%rbx
  add    %rax,%rdi
  lea    0x8(%rsi,%rdi,8),%rbp
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L11:
  call   <ft_handle_bsq@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L72
L25:
  mov    (%rbx),%rdi
  call   <ft_file_to_str@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <ft_puterr@plt>
  cmp    %rbp,%rbx
  jne    L25
L72:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L55:
  call   <ft_handle_bsq@plt>
L16:
  cmp    $0x1,%ebp
  je     L72
L74:
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <ft_stdin_file@plt>
  mov    %rbx,%rdi
  call   <ft_file_to_str@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L55
  mov    %r12,%rdi
  call   <ft_puterr@plt>
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D4: temp

tool: D13: map error


assistant: ```c
int main(int argc, char **argv) {
  char *map;
  int i;
  i = 0;
  if (argc != 1)
    i = 1;
  while (i < argc) {
    if (argc == 1) {
      ft_stdin_file();
      map = ft_file_to_str("temp");
      i++;
    } else
      map = ft_file_to_str(argv[i++]);
    if (!map)
      ft_puterr("map error\n");
    else
      ft_handle_bsq(map);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wait_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L8:
  mov    $0x3e8,%edi
  call   <wait_ms@plt>
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void wait_s(long s) {
  long i = 0;
  while (i < s) {
    wait_ms(1000);
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wait_s>:
  endbr64
  test   %rdi,%rdi
  jle    L18
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L2:
  mov    $0x3e8,%edi
  call   <wait_ms@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void wait_s(long s) {
  long i = 0;
  while (i < s) {
    wait_ms(1000);
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wait_s>:
  endbr64
  test   %rdi,%rdi
  jle    L3
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L11:
  mov    $0x3e8,%edi
  add    $0x1,%rbx
  call   <wait_ms@plt>
  cmp    %rbx,%rbp
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void wait_s(long s) {
  long i = 0;
  while (i < s) {
    wait_ms(1000);
    i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wait_s>:
  endbr64
  test   %rdi,%rdi
  jle    L12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  mov    $0x3e8,%edi
  add    $0x1,%rbx
  call   <wait_ms@plt>
  cmp    %rbx,%rbp
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void wait_s(long s) {
  long i = 0;
  while (i < s) {
    wait_ms(1000);
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ExecLampCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D55(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L26
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ProcessCommand@plt>
  jmp    L23
L26:
  mov    -0x10(%rbp),%rax
  lea    D51(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L24
  mov    -0x8(%rbp),%rax
  lea    D64(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ProcessCommand@plt>
  jmp    L23
L24:
  mov    -0x10(%rbp),%rax
  lea    D57(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L54
  mov    -0x8(%rbp),%rax
  lea    D45(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ProcessCommand@plt>
  jmp    L23
L54:
  mov    -0x10(%rbp),%rax
  lea    D69(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L36
  mov    -0x8(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ProcessCommand@plt>
  jmp    L23
L36:
  mov    $0x2,%eax
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D55
type_infered: string
name: retrieve_data
arguments: data_tag: D17
type_infered: string
name: retrieve_data
arguments: data_tag: D51
type_infered: string
name: retrieve_data
arguments: data_tag: D64
type_infered: string
name: retrieve_data
arguments: data_tag: D57
type_infered: string
name: retrieve_data
arguments: data_tag: D45
type_infered: string
name: retrieve_data
arguments: data_tag: D69
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D55: normal

tool: D17: C74

tool: D51: auto1

tool: D64: C72

tool: D57: auto2

tool: D45: C73

tool: D69: eco

tool: D12: C75

assistant: ```c
int ExecLampCommand(char ret[], const char *arg) {
  if (!strcmp(arg, "normal"))
    return (ProcessCommand(ret, "C74\r"));
  if (!strcmp(arg, "auto1"))
    return (ProcessCommand(ret, "C72\r"));
  if (!strcmp(arg, "auto2"))
    return (ProcessCommand(ret, "C73\r"));
  if (!strcmp(arg, "eco"))
    return (ProcessCommand(ret, "C75\r"));
  return (2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ExecLampCommand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L40
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
  lea    D41(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L71
L78:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <ProcessCommand@plt>
  jmp    L78
L8:
  lea    D76(%rip),%rsi
  mov    %rbp,%rdi
  call   <ProcessCommand@plt>
  jmp    L78
L14:
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <ProcessCommand@plt>
  jmp    L78
L71:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <ProcessCommand@plt>
  jmp    L78
```

tool_calls: name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string
name: disassemble_data
arguments: data_label: D20
datatype: string
name: disassemble_data
arguments: data_label: D76
datatype: string
name: disassemble_data
arguments: data_label: D30
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D13: normal

tool: D22: auto1

tool: D41: auto2

tool: D17: eco

tool: D20: C74

tool: D76: C72

tool: D30: C73

tool: D3: C75

assistant: ```c
int ExecLampCommand(char ret[], const char *arg) {
  if (!strcmp(arg, "normal"))
    return (ProcessCommand(ret, "C74\r"));
  if (!strcmp(arg, "auto1"))
    return (ProcessCommand(ret, "C72\r"));
  if (!strcmp(arg, "auto2"))
    return (ProcessCommand(ret, "C73\r"));
  if (!strcmp(arg, "eco"))
    return (ProcessCommand(ret, "C75\r"));
  return (2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ExecLampCommand>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D47(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  lea    D31(%rip),%rsi
  test   %eax,%eax
  je     L24
  lea    D64(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  lea    D17(%rip),%rsi
  test   %eax,%eax
  je     L24
  lea    D74(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  lea    D3(%rip),%rsi
  test   %eax,%eax
  je     L24
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L31
  add    $0x8,%rsp
  mov    $0x2,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L31:
  lea    D33(%rip),%rsi
L24:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <ProcessCommand@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D47
data_type: string
name: disassemble_data
arguments: tag: D31
data_type: string
name: disassemble_data
arguments: tag: D64
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string
name: disassemble_data
arguments: tag: D74
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string

tool: D47: normal

tool: D31: C74

tool: D64: auto1

tool: D17: C72

tool: D74: auto2

tool: D3: C73

tool: D5: eco

tool: D33: C75

assistant: ```c
int ExecLampCommand(char ret[], const char *arg) {
  if (!strcmp(arg, "normal"))
    return (ProcessCommand(ret, "C74\r"));
  if (!strcmp(arg, "auto1"))
    return (ProcessCommand(ret, "C72\r"));
  if (!strcmp(arg, "auto2"))
    return (ProcessCommand(ret, "C73\r"));
  if (!strcmp(arg, "eco"))
    return (ProcessCommand(ret, "C75\r"));
  return (2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ExecLampCommand>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D43(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  lea    D13(%rip),%rsi
  test   %eax,%eax
  je     L37
  lea    D46(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  lea    D48(%rip),%rsi
  test   %eax,%eax
  je     L37
  lea    D77(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  lea    D41(%rip),%rsi
  test   %eax,%eax
  je     L37
  lea    D40(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L31
  add    $0x8,%rsp
  mov    $0x2,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L31:
  lea    D7(%rip),%rsi
L37:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <ProcessCommand@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D43
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D46
type_infered: string
name: extract_symbolic_data
arguments: label: D48
type_infered: string
name: extract_symbolic_data
arguments: label: D77
type_infered: string
name: extract_symbolic_data
arguments: label: D41
type_infered: string
name: extract_symbolic_data
arguments: label: D40
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D43: normal

tool: D13: C74

tool: D46: auto1

tool: D48: C72

tool: D77: auto2

tool: D41: C73

tool: D40: eco

tool: D7: C75

assistant: ```c
int ExecLampCommand(char ret[], const char *arg) {
  if (!strcmp(arg, "normal"))
    return (ProcessCommand(ret, "C74\r"));
  if (!strcmp(arg, "auto1"))
    return (ProcessCommand(ret, "C72\r"));
  if (!strcmp(arg, "auto2"))
    return (ProcessCommand(ret, "C73\r"));
  if (!strcmp(arg, "eco"))
    return (ProcessCommand(ret, "C75\r"));
  return (2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SKP_Silk_LPC_inverse_pred_gain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %edx,-0xb4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb4(%rbp),%eax
  and    $0x1,%eax
  lea    -0x90(%rbp),%rdx
  cltq
  shl    $0x6,%rax
  add    %rdx,%rax
  mov    %rax,-0x98(%rbp)
  movl   $0x0,-0x9c(%rbp)
  jmp    L21
L22:
  mov    -0x9c(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  mov    -0x9c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x98(%rbp),%rax
  add    %rcx,%rax
  shl    $0x4,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x9c(%rbp)
L21:
  mov    -0x9c(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L22
  mov    -0xb4(%rbp),%edx
  lea    -0x90(%rbp),%rcx
  mov    -0xa8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <LPC_inverse_pred_gain_QA@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int SKP_Silk_LPC_inverse_pred_gain(int *invGain_Q30, const short *A_Q12, const int order) {
  int k;
  int Atmp_QA[2][16];
  int *Anew_QA;
  Anew_QA = Atmp_QA[order & 1];
  for (k = 0; k < order; k++) {
    Anew_QA[k] = (((int)A_Q12[k]) << (16 - 12));
  }
  return LPC_inverse_pred_gain_QA(invGain_Q30, Atmp_QA, order);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SKP_Silk_LPC_inverse_pred_gain>:
  endbr64
  sub    $0x98,%rsp
  mov    %rdi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %edx,%eax
  and    $0x1,%eax
  shl    $0x6,%rax
  lea    (%rsp,%rax,1),%rdi
  test   %edx,%edx
  jle    L20
  mov    %edx,%r8d
  mov    $0x0,%eax
L5:
  movswl (%rsi,%rax,2),%ecx
  shl    $0x4,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L5
L20:
  mov    %rsp,%rsi
  mov    %r9,%rdi
  call   <LPC_inverse_pred_gain_QA@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x98,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SKP_Silk_LPC_inverse_pred_gain(int *invGain_Q30, const short *A_Q12, const int order) {
  int k;
  int Atmp_QA[2][16];
  int *Anew_QA;
  Anew_QA = Atmp_QA[order & 1];
  for (k = 0; k < order; k++) {
    Anew_QA[k] = (((int)A_Q12[k]) << (16 - 12));
  }
  return LPC_inverse_pred_gain_QA(invGain_Q30, Atmp_QA, order);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SKP_Silk_LPC_inverse_pred_gain>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%edi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  and    $0x1,%edi
  mov    %rsp,%r10
  shl    $0x6,%rdi
  add    %r10,%rdi
  test   %edx,%edx
  jle    L14
  movslq %edx,%r8
  nopw   0x0(%rax,%rax,1)
L5:
  movswl (%rsi,%rax,2),%ecx
  shl    $0x4,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L5
L14:
  mov    %r10,%rsi
  mov    %r9,%rdi
  call   <LPC_inverse_pred_gain_QA@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x98,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SKP_Silk_LPC_inverse_pred_gain(int *invGain_Q30, const short *A_Q12, const int order) {
  int k;
  int Atmp_QA[2][16];
  int *Anew_QA;
  Anew_QA = Atmp_QA[order & 1];
  for (k = 0; k < order; k++) {
    Anew_QA[k] = (((int)A_Q12[k]) << (16 - 12));
  }
  return LPC_inverse_pred_gain_QA(invGain_Q30, Atmp_QA, order);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SKP_Silk_LPC_inverse_pred_gain>:
  endbr64
  push   %rbx
  mov    %edx,%r8d
  and    $0x1,%edx
  shl    $0x6,%rdx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  add    %r9,%rdx
  test   %r8d,%r8d
  jle    L9
  lea    -0x1(%r8),%eax
  cmp    $0x6,%eax
  jbe    L73
  mov    %r8d,%ecx
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  shr    $0x3,%ecx
  shl    $0x4,%rcx
  nopl   (%rax)
L98:
  movdqu (%rsi,%rax,1),%xmm0
  movdqa %xmm3,%xmm2
  pcmpgtw %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  punpcklwd %xmm2,%xmm1
  punpckhwd %xmm2,%xmm0
  pslld  $0x4,%xmm1
  pslld  $0x4,%xmm0
  movaps %xmm1,(%rdx,%rax,2)
  movaps %xmm0,0x10(%rdx,%rax,2)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L98
  mov    %r8d,%eax
  and    $0xfffffff8,%eax
  test   $0x7,%r8b
  je     L9
L95:
  movslq %eax,%r11
  movswl (%rsi,%r11,2),%ebx
  lea    (%r11,%r11,1),%r10
  lea    0x0(,%r11,4),%rcx
  shl    $0x4,%ebx
  mov    %ebx,(%rdx,%r11,4)
  lea    0x1(%rax),%r11d
  cmp    %r11d,%r8d
  jle    L9
  movswl 0x2(%rsi,%r10,1),%r11d
  shl    $0x4,%r11d
  mov    %r11d,0x4(%rdx,%rcx,1)
  lea    0x2(%rax),%r11d
  cmp    %r11d,%r8d
  jle    L9
  movswl 0x4(%rsi,%r10,1),%r11d
  shl    $0x4,%r11d
  mov    %r11d,0x8(%rdx,%rcx,1)
  lea    0x3(%rax),%r11d
  cmp    %r11d,%r8d
  jle    L9
  movswl 0x6(%rsi,%r10,1),%r11d
  shl    $0x4,%r11d
  mov    %r11d,0xc(%rdx,%rcx,1)
  lea    0x4(%rax),%r11d
  cmp    %r11d,%r8d
  jle    L9
  movswl 0x8(%rsi,%r10,1),%r11d
  shl    $0x4,%r11d
  mov    %r11d,0x10(%rdx,%rcx,1)
  lea    0x5(%rax),%r11d
  cmp    %r11d,%r8d
  jle    L9
  movswl 0xa(%rsi,%r10,1),%r11d
  add    $0x6,%eax
  shl    $0x4,%r11d
  mov    %r11d,0x14(%rdx,%rcx,1)
  cmp    %eax,%r8d
  jle    L9
  movswl 0xc(%rsi,%r10,1),%eax
  shl    $0x4,%eax
  mov    %eax,0x18(%rdx,%rcx,1)
L9:
  mov    %r8d,%edx
  mov    %r9,%rsi
  call   <LPC_inverse_pred_gain_QA@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x90,%rsp
  pop    %rbx
  ret
L73:
  xor    %eax,%eax
  jmp    L95
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SKP_Silk_LPC_inverse_pred_gain(int *invGain_Q30, const short *A_Q12, const int order) {
  int k;
  int Atmp_QA[2][16];
  int *Anew_QA;
  Anew_QA = Atmp_QA[order & 1];
  for (k = 0; k < order; k++) {
    Anew_QA[k] = (((int)A_Q12[k]) << (16 - 12));
  }
  return LPC_inverse_pred_gain_QA(invGain_Q30, Atmp_QA, order);
}
```
user: What is the c source code of the assembly code below?

```asm
<read_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const uint8_t *read_u16(const uint8_t *p, size_t *s, uint16_t *v) {
  *v = 0;
  *v |= (uint16_t)*p++ << 8;
  *v |= (uint16_t)*p++ << 0;
  *s -= 2;
  return (p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_u16>:
  endbr64
  movl   $0x0,(%rdx)
  mov    (%rdi),%eax
  shl    $0x8,%eax
  mov    %eax,(%rdx)
  or     0x4(%rdi),%eax
  mov    %eax,(%rdx)
  subq   $0x2,(%rsi)
  lea    0x8(%rdi),%rax
  ret
```

assistant: ```c
const uint8_t *read_u16(const uint8_t *p, size_t *s, uint16_t *v) {
  *v = 0;
  *v |= (uint16_t)*p++ << 8;
  *v |= (uint16_t)*p++ << 0;
  *s -= 2;
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_u16>:
  endbr64
  movl   $0x0,(%rdx)
  mov    (%rdi),%eax
  shl    $0x8,%eax
  mov    %eax,(%rdx)
  or     0x4(%rdi),%eax
  mov    %eax,(%rdx)
  lea    0x8(%rdi),%rax
  subq   $0x2,(%rsi)
  ret
```

assistant: ```c
const uint8_t *read_u16(const uint8_t *p, size_t *s, uint16_t *v) {
  *v = 0;
  *v |= (uint16_t)*p++ << 8;
  *v |= (uint16_t)*p++ << 0;
  *s -= 2;
  return (p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_u16>:
  endbr64
  movl   $0x0,(%rdx)
  mov    (%rdi),%eax
  shl    $0x8,%eax
  mov    %eax,(%rdx)
  or     0x4(%rdi),%eax
  mov    %eax,(%rdx)
  lea    0x8(%rdi),%rax
  subq   $0x2,(%rsi)
  ret
```

assistant: ```c
const uint8_t *read_u16(const uint8_t *p, size_t *s, uint16_t *v) {
  *v = 0;
  *v |= (uint16_t)*p++ << 8;
  *v |= (uint16_t)*p++ << 0;
  *s -= 2;
  return (p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<onError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <netCloseSocket@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: onError: socket %i


assistant: ```c
void onError(int socket) {
  printf("onError: socket %i\n", socket);
  netCloseSocket(socket);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<onError>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <netCloseSocket@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: onError: socket %i


assistant: ```c
void onError(int socket) {
  printf("onError: socket %i\n", socket);
  netCloseSocket(socket);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<onError>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <netCloseSocket@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: onError: socket %i


assistant: ```c
void onError(int socket) {
  printf("onError: socket %i\n", socket);
  netCloseSocket(socket);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<onError>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <netCloseSocket@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: onError: socket %i


assistant: ```c
void onError(int socket) {
  printf("onError: socket %i\n", socket);
  netCloseSocket(socket);
}
```