ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<seatest_assert_string_equal>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0x6b0,%rsp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rax
  or     %rsi,%rax
  je     L65
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L56
  test   %rsi,%rsi
  je     L19
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %r14b
  movzbl %r14b,%r14d
  mov    %rsp,%rdi
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D8(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
L59:
  mov    %rsp,%rsi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r14d,%edi
  call   <seatest_simple_test_result@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x186b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  movabs $0x6465746365707845,%rax
  movabs $0x203e4c4c554e3c20,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x2073617720747562,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x4c554e3c,0x18(%rsp)
  movw   $0x3e4c,0x1c(%rsp)
  movb   $0x0,0x1e(%rsp)
  mov    $0x1,%r14d
  jmp    L59
L56:
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  lea    D7(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    $0x0,%r14d
  jmp    L59
L19:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  lea    D16(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    $0x0,%r14d
  jmp    L59
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D7
type: string
name: retrieve_data
arguments: label: D16
type: string

tool: D8: Expected "%s" but was "%s"

tool: D7: Expected <NULL> but was "%s"

tool: D16: Expected "%s" but was <NULL>

assistant: ```c
void seatest_assert_string_equal(const char *expected, const char *actual, const char *function, unsigned int line) {
  int comparison;
  char s[100000];
  if ((expected == (char *)0) && (actual == (char *)0)) {
    sprintf(s, "Expected <NULL> but was <NULL>");
    comparison = 1;
  } else if (expected == (char *)0) {
    sprintf(s, "Expected <NULL> but was \"%s\"", actual);
    comparison = 0;
  } else if (actual == (char *)0) {
    sprintf(s, "Expected \"%s\" but was <NULL>", expected);
    comparison = 0;
  } else {
    comparison = strcmp(expected, actual) == 0;
    sprintf(s, "Expected \"%s\" but was \"%s\"", expected, actual);
  }
  seatest_simple_test_result(comparison, s, function, line);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<seatest_assert_string_equal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x6b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  mov    %rdi,%rax
  mov    %rdx,%r14
  mov    %ecx,%r15d
  or     %rsi,%rax
  je     L34
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rdi,%rdi
  je     L56
  test   %rsi,%rsi
  je     L71
  call   <strcmp@plt>
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  mov    %r13,%rcx
  test   %rax,%rax
  mov    %r12,%rdx
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  sete   %bl
  xor    %eax,%eax
  call   <sprintf@plt>
L35:
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <seatest_simple_test_result@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x186b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L34:
  movdqa D13(%rip),%xmm0
  movl   $0x4c554e3c,0x18(%rsp)
  mov    $0x1,%ebx
  mov    %rsp,%rbp
  movabs $0x2073617720747562,%rax
  movb   $0x0,0x1e(%rsp)
  mov    %rax,0x10(%rsp)
  mov    $0x3e4c,%eax
  mov    %ax,0x1c(%rsp)
  movaps %xmm0,(%rsp)
  jmp    L35
  nopl   0x0(%rax)
L71:
  mov    %rsp,%rbp
  mov    %rdi,%rdx
  lea    D4(%rip),%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  call   <sprintf@plt>
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %rsp,%rbp
  mov    %rsi,%rdx
  xor    %eax,%eax
  xor    %ebx,%ebx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L35
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D30
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: byte[16]
name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D6
data_type: string

tool: D30: Expected "%s" but was "%s"

tool: {"D13": [0x45,0x78,0x70,0x65,0x63,0x74,0x65,0x64,0x20,0x3c,0x4e,0x55,0x4c,0x4c,0x3e,0x20]}

tool: D4: Expected "%s" but was <NULL>

tool: D6: Expected <NULL> but was "%s"

assistant: ```c
void seatest_assert_string_equal(const char *expected, const char *actual, const char *function, unsigned int line) {
  int comparison;
  char s[100000];
  if ((expected == (char *)0) && (actual == (char *)0)) {
    sprintf(s, "Expected <NULL> but was <NULL>");
    comparison = 1;
  } else if (expected == (char *)0) {
    sprintf(s, "Expected <NULL> but was \"%s\"", actual);
    comparison = 0;
  } else if (actual == (char *)0) {
    sprintf(s, "Expected \"%s\" but was <NULL>", expected);
    comparison = 0;
  } else {
    comparison = strcmp(expected, actual) == 0;
    sprintf(s, "Expected \"%s\" but was \"%s\"", expected, actual);
  }
  seatest_simple_test_result(comparison, s, function, line);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<seatest_assert_string_equal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0x6b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  mov    %rdi,%rax
  mov    %rdx,%r14
  mov    %ecx,%r15d
  or     %rsi,%rax
  je     L64
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rdi,%rdi
  je     L13
  test   %rsi,%rsi
  je     L14
  call   <strcmp@plt>
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  mov    %r13,%rcx
  test   %rax,%rax
  mov    %r12,%rdx
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  sete   %bl
  xor    %eax,%eax
  call   <sprintf@plt>
L10:
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <seatest_simple_test_result@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x186b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L64:
  movdqa D30(%rip),%xmm0
  movl   $0x4c554e3c,0x18(%rsp)
  mov    $0x1,%ebx
  mov    %rsp,%rbp
  movabs $0x2073617720747562,%rax
  movb   $0x0,0x1e(%rsp)
  mov    %rax,0x10(%rsp)
  mov    $0x3e4c,%eax
  mov    %ax,0x1c(%rsp)
  movaps %xmm0,(%rsp)
  jmp    L10
  nopl   0x0(%rax)
L14:
  mov    %rsp,%rbp
  mov    %rdi,%rdx
  lea    D18(%rip),%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  call   <sprintf@plt>
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %rsp,%rbp
  mov    %rsi,%rdx
  xor    %eax,%eax
  xor    %ebx,%ebx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L10
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D30
type_infered: byte[16]
name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D21: Expected "%s" but was "%s"

tool: {"D30": [0x45,0x78,0x70,0x65,0x63,0x74,0x65,0x64,0x20,0x3c,0x4e,0x55,0x4c,0x4c,0x3e,0x20]}

tool: D18: Expected "%s" but was <NULL>

tool: D6: Expected <NULL> but was "%s"

assistant: ```c
void seatest_assert_string_equal(const char *expected, const char *actual, const char *function, unsigned int line) {
  int comparison;
  char s[100000];
  if ((expected == (char *)0) && (actual == (char *)0)) {
    sprintf(s, "Expected <NULL> but was <NULL>");
    comparison = 1;
  } else if (expected == (char *)0) {
    sprintf(s, "Expected <NULL> but was \"%s\"", actual);
    comparison = 0;
  } else if (actual == (char *)0) {
    sprintf(s, "Expected \"%s\" but was <NULL>", expected);
    comparison = 0;
  } else {
    comparison = strcmp(expected, actual) == 0;
    sprintf(s, "Expected \"%s\" but was \"%s\"", expected, actual);
  }
  seatest_simple_test_result(comparison, s, function, line);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<funcb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <funcc@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <OsPrint@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: funcb no-PIC OK


assistant: ```c
int funcb() {
  funcc();
  OsPrint("funcb no-PIC OK\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<funcb>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <funcc@plt>
  lea    D6(%rip),%rdi
  call   <OsPrint@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: funcb no-PIC OK


assistant: ```c
int funcb() {
  funcc();
  OsPrint("funcb no-PIC OK\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<funcb>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <funcc@plt>
  lea    D3(%rip),%rdi
  call   <OsPrint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string

tool: D3: funcb no-PIC OK


assistant: ```c
int funcb() {
  funcc();
  OsPrint("funcb no-PIC OK\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<funcb>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <funcc@plt>
  lea    D9(%rip),%rdi
  call   <OsPrint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string

tool: D9: funcb no-PIC OK


assistant: ```c
int funcb() {
  funcc();
  OsPrint("funcb no-PIC OK\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <split_words@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L7:
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    -0x30(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    $0x1,%rax
  add    %rax,-0x10(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void words(const char *sentence, void (*callback)(const char *, void *), void *memo) {
  char *words = strdup(sentence);
  int word_count = split_words(words);
  char *word = words;
  while (word_count-- > 0) {
    (*callback)(word, memo);
    word = word + strlen(word) + 1;
  }
  free(words);
}
```
user: Translate the below assembly code into C programming language:

```asm
<words>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  call   <strdup@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <split_words@plt>
  test   %eax,%eax
  jle    L9
  lea    -0x1(%rax),%ebp
  mov    %r14,%rbx
L7:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   *%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    0x1(%rbx,%rax,1),%rbx
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L7
L9:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void words(const char *sentence, void (*callback)(const char *, void *), void *memo) {
  char *words = strdup(sentence);
  int word_count = split_words(words);
  char *word = words;
  while (word_count-- > 0) {
    (*callback)(word, memo);
    word = word + strlen(word) + 1;
  }
  free(words);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<words>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <split_words@plt>
  test   %eax,%eax
  jle    L17
  lea    -0x1(%rax),%r14d
  mov    %r13,%rbx
  nopl   (%rax)
L2:
  mov    %rbx,%rdi
  mov    %r12,%rsi
  call   *%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    0x1(%rbx,%rax,1),%rbx
  sub    $0x1,%r14d
  jae    L2
L17:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free@plt>
```

assistant: ```c
void words(const char *sentence, void (*callback)(const char *, void *), void *memo) {
  char *words = strdup(sentence);
  int word_count = split_words(words);
  char *word = words;
  while (word_count-- > 0) {
    (*callback)(word, memo);
    word = word + strlen(word) + 1;
  }
  free(words);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<words>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <split_words@plt>
  test   %eax,%eax
  jle    L17
  lea    -0x1(%rax),%r14d
  mov    %r13,%rbx
  nopl   (%rax)
L1:
  mov    %rbx,%rdi
  mov    %r12,%rsi
  call   *%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    0x1(%rbx,%rax,1),%rbx
  sub    $0x1,%r14d
  jae    L1
L17:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free@plt>
```

assistant: ```c
void words(const char *sentence, void (*callback)(const char *, void *), void *memo) {
  char *words = strdup(sentence);
  int word_count = split_words(words);
  char *word = words;
  while (word_count-- > 0) {
    (*callback)(word, memo);
    word = word + strlen(word) + 1;
  }
  free(words);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trazi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xf8(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlwr@plt>
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movw   $0x2928,-0xb3(%rbp)
  movb   $0x0,-0xb1(%rbp)
  lea    -0xb3(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0xe0(%rbp)
  lea    -0xb3(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0xd8(%rbp)
  mov    -0xd8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xe4(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  lea    -0xb0(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0xd0(%rbp)
  lea    -0xb0(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0xc8(%rbp)
  lea    -0xb0(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0xc0(%rbp)
  cmpq   $0x0,-0xd0(%rbp)
  jne    L35
  cmpq   $0x0,-0xc8(%rbp)
  jne    L35
  cmpq   $0x0,-0xc0(%rbp)
  jne    L35
  cmpl   $0x2d,-0xe4(%rbp)
  jg     L8
L35:
  mov    -0xe0(%rbp),%rax
  jmp    L4
L8:
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D11
type: string

tool: D14: crn

tool: D6: bogat

tool: D11: visok

assistant: ```c
char *trazi(char *sms) {
  char copy[160 + 1];
  int dob;
  strcpy(copy, sms);
  strlwr(copy);
  char *ime = NULL, *godine = NULL;
  char delimit[] = "()";
  ime = strtok(copy, delimit);
  godine = strtok(NULL, delimit);
  dob = atoi(godine);
  char *crn = NULL, *bogat = NULL, *visok = NULL;
  crn = strstr(copy, "crn");
  bogat = strstr(copy, "bogat");
  visok = strstr(copy, "visok");
  if ((crn != NULL || bogat != NULL || visok != NULL) || (dob <= 45)) {
    return ime;
  } else {
    return NULL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<trazi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlwr@plt>
  movw   $0x2928,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0xd(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%r12
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%r14d
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  or     %r13,%rbp
  or     %rbp,%rax
  jne    L14
  cmp    $0x2d,%r14d
  mov    $0x0,%eax
  cmovg  %rax,%r12
L14:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %r12,%rax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D24
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D12: crn

tool: D24: bogat

tool: D4: visok

assistant: ```c
char *trazi(char *sms) {
  char copy[160 + 1];
  int dob;
  strcpy(copy, sms);
  strlwr(copy);
  char *ime = NULL, *godine = NULL;
  char delimit[] = "()";
  ime = strtok(copy, delimit);
  godine = strtok(NULL, delimit);
  dob = atoi(godine);
  char *crn = NULL, *bogat = NULL, *visok = NULL;
  crn = strstr(copy, "crn");
  bogat = strstr(copy, "bogat");
  visok = strstr(copy, "visok");
  if ((crn != NULL || bogat != NULL || visok != NULL) || (dob <= 45)) {
    return ime;
  } else {
    return NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trazi>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xd(%rsp),%r13
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlwr@plt>
  mov    %r13,%rsi
  mov    $0x2928,%eax
  mov    %rbp,%rdi
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <strtok@plt>
  mov    %r13,%rsi
  xor    %edi,%edi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <strstr@plt>
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strstr@plt>
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strstr@plt>
  or     %r13,%rbx
  or     %rbx,%rax
  jne    L8
  xor    %eax,%eax
  cmp    $0x2d,%r14d
  cmovg  %rax,%r12
L8:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0xc0,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D17
data_type: string
name: disassemble_data
arguments: data_label: D16
data_type: string

tool: D5: crn

tool: D17: bogat

tool: D16: visok

assistant: ```c
char *trazi(char *sms) {
  char copy[160 + 1];
  int dob;
  strcpy(copy, sms);
  strlwr(copy);
  char *ime = NULL, *godine = NULL;
  char delimit[] = "()";
  ime = strtok(copy, delimit);
  godine = strtok(NULL, delimit);
  dob = atoi(godine);
  char *crn = NULL, *bogat = NULL, *visok = NULL;
  crn = strstr(copy, "crn");
  bogat = strstr(copy, "bogat");
  visok = strstr(copy, "visok");
  if ((crn != NULL || bogat != NULL || visok != NULL) || (dob <= 45)) {
    return ime;
  } else {
    return NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trazi>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xd(%rsp),%r13
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlwr@plt>
  mov    %r13,%rsi
  mov    $0x2928,%eax
  mov    %rbp,%rdi
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <strtok@plt>
  mov    %r13,%rsi
  xor    %edi,%edi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <strstr@plt>
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strstr@plt>
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strstr@plt>
  or     %r13,%rbx
  or     %rbx,%rax
  jne    L9
  xor    %eax,%eax
  cmp    $0x2d,%r14d
  cmovg  %rax,%r12
L9:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0xc0,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D14
type: string

tool: D19: crn

tool: D17: bogat

tool: D14: visok

assistant: ```c
char *trazi(char *sms) {
  char copy[160 + 1];
  int dob;
  strcpy(copy, sms);
  strlwr(copy);
  char *ime = NULL, *godine = NULL;
  char delimit[] = "()";
  ime = strtok(copy, delimit);
  godine = strtok(NULL, delimit);
  dob = atoi(godine);
  char *crn = NULL, *bogat = NULL, *visok = NULL;
  crn = strstr(copy, "crn");
  bogat = strstr(copy, "bogat");
  visok = strstr(copy, "visok");
  if ((crn != NULL || bogat != NULL || visok != NULL) || (dob <= 45)) {
    return ime;
  } else {
    return NULL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dup_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  cmpq   $0x0,-0x20(%rbp)
  je     L1
  jmp    L46
L10:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stricmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x1,%eax
  jmp    L30
L32:
  addq   $0x8,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L10
L1:
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
int dup_word(char **wp, char *str) {
  char **copyWp = wp;
  if (copyWp != NULL && str != NULL) {
    while (*copyWp != NULL) {
      if (stricmp(*copyWp, str) == 0)
        return 1;
      copyWp = copyWp + 1;
    }
  }
  return 0;
}
```