ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<square_sum>:
  endbr64
  test   %edi,%edi
  jle    L14
  lea    0x1(%rdi,%rdi,1),%edx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  add    %eax,%r8d
  add    $0x2,%eax
  cmp    %edx,%eax
  jne    L4
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t square_sum(uint64_t num) {
  uint64_t n = 0;
  for (uint64_t i = 0; i < num; i++) {
    n += (i << 1) + 1;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<square_sum>:
  endbr64
  test   %edi,%edi
  jle    L21
  lea    -0x1(%rdi),%eax
  cmp    $0x3,%eax
  jbe    L64
  mov    %edi,%edx
  movdqa D11(%rip),%xmm2
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  movdqa D0(%rip),%xmm4
  movdqa D12(%rip),%xmm3
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L43:
  movdqa %xmm2,%xmm0
  add    $0x1,%eax
  paddd  %xmm4,%xmm2
  pslld  $0x1,%xmm0
  paddd  %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %eax,%edx
  jne    L43
  movdqa %xmm1,%xmm0
  mov    %edi,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%dil
  je     L62
L26:
  lea    0x1(%rdx),%ecx
  lea    0x1(%rax,%rdx,2),%eax
  cmp    %ecx,%edi
  jle    L44
  lea    0x1(%rax,%rcx,2),%eax
  lea    0x2(%rdx),%ecx
  cmp    %ecx,%edi
  jle    L44
  add    $0x3,%edx
  lea    0x1(%rax,%rcx,2),%eax
  cmp    %edx,%edi
  jle    L44
  lea    0x1(%rax,%rdx,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
L44:
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  ret
L64:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L26
```

tool_calls: name: unpack_data
arguments: data_label: D11
datatype: byte[16]
name: unpack_data
arguments: data_label: D0
datatype: byte[16]
name: unpack_data
arguments: data_label: D12
datatype: byte[16]

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D0": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D12": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
uint64_t square_sum(uint64_t num) {
  uint64_t n = 0;
  for (uint64_t i = 0; i < num; i++) {
    n += (i << 1) + 1;
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x5,(%rax)
  mov    -0x8(%rbp),%rax
  movl   $0x3,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
foo(int *a) {
  *a = 5;
  *a = 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
foo(int *a) {
  *a = 5;
  *a = 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
foo(int *a) {
  *a = 5;
  *a = 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
foo(int *a) {
  *a = 5;
  *a = 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cgdb_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  jmp    L11
L13:
  mov    $0xffffffff,%edi
  call   <exit@plt>
L11:
  leave
  ret
```

assistant: ```c
void *cgdb_calloc(size_t nmemb, size_t size) {
  void *t = calloc(nmemb, size);
  if (t)
    return t;
  exit(-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cgdb_calloc>:
  endbr64
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rax,%rax
  je     L6
L17:
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L17
```

assistant: ```c
void *cgdb_calloc(size_t nmemb, size_t size) {
  void *t = calloc(nmemb, size);
  if (t)
    return t;
  exit(-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cgdb_calloc>:
  endbr64
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rax,%rax
  je     L18
L15:
  add    $0x8,%rsp
  ret
L18:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L15
```

assistant: ```c
void *cgdb_calloc(size_t nmemb, size_t size) {
  void *t = calloc(nmemb, size);
  if (t)
    return t;
  exit(-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cgdb_calloc>:
  endbr64
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rax,%rax
  je     L3
L10:
  add    $0x8,%rsp
  ret
L3:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L10
```

assistant: ```c
void *cgdb_calloc(size_t nmemb, size_t size) {
  void *t = calloc(nmemb, size);
  if (t)
    return t;
  exit(-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<normalizeyear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L38
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L38
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L38
  mov    -0x10(%rbp),%rax
  movb   $0x31,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movb   $0x39,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x3,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L2
L38:
  mov    -0x8(%rbp),%rax
L2:
  pop    %rbp
  ret
```

assistant: ```c
char const *normalizeyear(date, year)
char const *date;
char year[5];
{
  if ((((unsigned)(date[0]) - '0') <= 9) && (((unsigned)(date[1]) - '0') <= 9) && !(((unsigned)(date[2]) - '0') <= 9)) {
    year[0] = '1';
    year[1] = '9';
    year[2] = date[0];
    year[3] = date[1];
    year[4] = 0;
    return year;
  } else
    return date;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<normalizeyear>:
  endbr64
  mov    %rdi,%rax
  movsbl (%rdi),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L11
  movsbl 0x1(%rdi),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L11
  movsbl 0x2(%rdi),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L11
  movb   $0x31,(%rsi)
  movb   $0x39,0x1(%rsi)
  movzbl (%rdi),%edx
  mov    %dl,0x2(%rsi)
  movzbl 0x1(%rdi),%eax
  mov    %al,0x3(%rsi)
  movb   $0x0,0x4(%rsi)
  mov    %rsi,%rax
L11:
  ret
```

assistant: ```c
char const *normalizeyear(date, year)
char const *date;
char year[5];
{
  if ((((unsigned)(date[0]) - '0') <= 9) && (((unsigned)(date[1]) - '0') <= 9) && !(((unsigned)(date[2]) - '0') <= 9)) {
    year[0] = '1';
    year[1] = '9';
    year[2] = date[0];
    year[3] = date[1];
    year[4] = 0;
    return year;
  } else
    return date;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<normalizeyear>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L3
  movsbl 0x1(%rdi),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L3
  movsbl 0x2(%rdi),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L3
  mov    $0x3931,%edx
  mov    %dx,(%rsi)
  movzbl (%rdi),%edx
  mov    %dl,0x2(%rsi)
  movzbl 0x1(%rdi),%eax
  movb   $0x0,0x4(%rsi)
  mov    %al,0x3(%rsi)
  mov    %rsi,%rax
L3:
  ret
```

assistant: ```c
char const *normalizeyear(date, year)
char const *date;
char year[5];
{
  if ((((unsigned)(date[0]) - '0') <= 9) && (((unsigned)(date[1]) - '0') <= 9) && !(((unsigned)(date[2]) - '0') <= 9)) {
    year[0] = '1';
    year[1] = '9';
    year[2] = date[0];
    year[3] = date[1];
    year[4] = 0;
    return year;
  } else
    return date;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x61,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L49
  mov    $0x0,%eax
  call   <abort@plt>
L49:
  mov    $0x7a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L42
  mov    $0x0,%eax
  call   <abort@plt>
L42:
  mov    $0x41,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L27
  mov    $0x0,%eax
  call   <abort@plt>
L27:
  mov    $0x5a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L26
  mov    $0x0,%eax
  call   <abort@plt>
L26:
  mov    $0x20,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x35,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L73
  mov    $0x0,%eax
  call   <abort@plt>
L73:
  mov    $0x21,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L59
  mov    $0x0,%eax
  call   <abort@plt>
L59:
  mov    $0x40,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  call   <abort@plt>
L9:
  mov    $0x5b,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L78
  mov    $0x0,%eax
  call   <abort@plt>
L78:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (!isalpha('a')) {
    abort();
  }
  if (!isalpha('z')) {
    abort();
  }
  if (!isalpha('A')) {
    abort();
  }
  if (!isalpha('Z')) {
    abort();
  }
  if (isalpha(' ')) {
    abort();
  }
  if (isalpha('5')) {
    abort();
  }
  if (isalpha('!')) {
    abort();
  }
  if (isalpha('@')) {
    abort();
  }
  if (isalpha('[')) {
    abort();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L130
L168:
  mov    $0x7a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L64
L22:
  mov    $0x41,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L92
L47:
  mov    $0x5a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L167
L56:
  mov    $0x20,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L114
L59:
  mov    $0x35,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L27
L103:
  mov    $0x21,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L84
L100:
  mov    $0x40,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L21
L101:
  mov    $0x5b,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L119
L49:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L130:
  call   <abort@plt>
  jmp    L168
L64:
  call   <abort@plt>
  jmp    L22
L92:
  call   <abort@plt>
  jmp    L47
L167:
  call   <abort@plt>
  jmp    L56
L114:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L59
L27:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L103
L84:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L100
L21:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L101
L119:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L49
```

assistant: ```c
int main() {
  if (!isalpha('a')) {
    abort();
  }
  if (!isalpha('z')) {
    abort();
  }
  if (!isalpha('A')) {
    abort();
  }
  if (!isalpha('Z')) {
    abort();
  }
  if (isalpha(' ')) {
    abort();
  }
  if (isalpha('5')) {
    abort();
  }
  if (isalpha('!')) {
    abort();
  }
  if (isalpha('@')) {
    abort();
  }
  if (isalpha('[')) {
    abort();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L85
L140:
  mov    $0x7a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L106
L128:
  mov    $0x41,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L146
L74:
  mov    $0x5a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L58
L49:
  mov    $0x20,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L39
L112:
  mov    $0x35,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L57
L138:
  mov    $0x21,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L8
L105:
  mov    $0x40,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L149
L62:
  mov    $0x5b,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L162
L143:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L85:
  call   <abort@plt>
  jmp    L140
L162:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L143
L149:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L62
L8:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L105
L57:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L138
L39:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L112
L58:
  call   <abort@plt>
  jmp    L49
L146:
  call   <abort@plt>
  jmp    L74
L106:
  call   <abort@plt>
  jmp    L128
```

assistant: ```c
int main() {
  if (!isalpha('a')) {
    abort();
  }
  if (!isalpha('z')) {
    abort();
  }
  if (!isalpha('A')) {
    abort();
  }
  if (!isalpha('Z')) {
    abort();
  }
  if (isalpha(' ')) {
    abort();
  }
  if (isalpha('5')) {
    abort();
  }
  if (isalpha('!')) {
    abort();
  }
  if (isalpha('@')) {
    abort();
  }
  if (isalpha('[')) {
    abort();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L165
L62:
  mov    $0x7a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L177
L116:
  mov    $0x41,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L120
L115:
  mov    $0x5a,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L79
L74:
  mov    $0x20,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L131
L153:
  mov    $0x35,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L167
L151:
  mov    $0x21,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L39
L94:
  mov    $0x40,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L121
L29:
  mov    $0x5b,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L75
L134:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L165:
  call   <abort@plt>
  jmp    L62
L75:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L134
L121:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L29
L39:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L94
L167:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L151
L131:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L153
L79:
  call   <abort@plt>
  jmp    L74
L120:
  call   <abort@plt>
  jmp    L115
L177:
  call   <abort@plt>
  jmp    L116
```

assistant: ```c
int main() {
  if (!isalpha('a')) {
    abort();
  }
  if (!isalpha('z')) {
    abort();
  }
  if (!isalpha('A')) {
    abort();
  }
  if (!isalpha('Z')) {
    abort();
  }
  if (isalpha(' ')) {
    abort();
  }
  if (isalpha('5')) {
    abort();
  }
  if (isalpha('!')) {
    abort();
  }
  if (isalpha('@')) {
    abort();
  }
  if (isalpha('[')) {
    abort();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<msync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int msync(__ptr_t addr, size_t len, int flags) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<msync>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int msync(__ptr_t addr, size_t len, int flags) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<msync>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int msync(__ptr_t addr, size_t len, int flags) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<msync>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int msync(__ptr_t addr, size_t len, int flags) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power_recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L60
  movsd  D5(%rip),%xmm0
  jmp    L45
L60:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L67
  movsd  -0x18(%rbp),%xmm0
  jmp    L45
L67:
  mov    -0x1c(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L63
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <power_recurse>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  jmp    L45
L63:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L19
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <power_recurse>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  jmp    L45
L19:
  movsd  D1(%rip),%xmm0
L45:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: f64
name: read_data
arguments: data_label: D1
type_infered: byte[8]

tool: D5: 1

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double power_recurse(double b, int e) {
  if (e == 0) {
    return 1;
  } else if (e == 1) {
    return b;
  } else if (e % 2 == 1) {
    double res = power_recurse(b, e / 2);
    return res * res * b;
  } else if (e % 2 == 0) {
    double res = power_recurse(b, e / 2);
    return res * res;
  }
  return -1.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power_recurse>:
  endbr64
  test   %edi,%edi
  je     L6
  push   %rbx
  movq   %xmm0,%rbx
  cmp    $0x1,%edi
  je     L35
  mov    %edi,%edx
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L46
  movsd  D7(%rip),%xmm0
  test   $0x1,%dil
  je     L1
L35:
  pop    %rbx
  ret
L46:
  add    %edx,%edi
  sar    %edi
  call   <power_recurse>
  mulsd  %xmm0,%xmm0
  movq   %rbx,%xmm1
  mulsd  %xmm1,%xmm0
  jmp    L35
L1:
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  sar    %edi
  movq   %rbx,%xmm0
  call   <power_recurse>
  mulsd  %xmm0,%xmm0
  jmp    L35
L6:
  movsd  D12(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: byte[8]
name: read_data
arguments: data_label: D12
type: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D12: 1

assistant: ```c
double power_recurse(double b, int e) {
  if (e == 0) {
    return 1;
  } else if (e == 1) {
    return b;
  } else if (e % 2 == 1) {
    double res = power_recurse(b, e / 2);
    return res * res * b;
  } else if (e % 2 == 0) {
    double res = power_recurse(b, e / 2);
    return res * res;
  }
  return -1.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<power_recurse>:
  endbr64
  test   %edi,%edi
  je     L12
  movapd %xmm0,%xmm1
  cmp    $0x1,%edi
  je     L21
  mov    %edi,%edx
  sub    $0x18,%rsp
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L40
  movsd  D15(%rip),%xmm1
  test   $0x1,%dil
  je     L20
L57:
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L12:
  movsd  D11(%rip),%xmm1
L21:
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L40:
  sar    %edi
  movsd  %xmm0,0x8(%rsp)
  call   <power_recurse>
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  jmp    L57
  nopl   (%rax)
L20:
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  sar    %edi
  call   <power_recurse>
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  jmp    L57
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: byte[8]
name: parse_data
arguments: data_label: D11
data_type: f64

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D11: 1

assistant: ```c
double power_recurse(double b, int e) {
  if (e == 0) {
    return 1;
  } else if (e == 1) {
    return b;
  } else if (e % 2 == 1) {
    double res = power_recurse(b, e / 2);
    return res * res * b;
  } else if (e % 2 == 0) {
    double res = power_recurse(b, e / 2);
    return res * res;
  }
  return -1.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<power_recurse>:
  endbr64
  test   %edi,%edi
  je     L17
  movapd %xmm0,%xmm1
  cmp    $0x1,%edi
  je     L31
  mov    %edi,%edx
  sub    $0x18,%rsp
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L40
  movsd  D18(%rip),%xmm1
  test   $0x1,%dil
  je     L41
L51:
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L17:
  movsd  D7(%rip),%xmm1
L31:
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L40:
  sar    %edi
  movsd  %xmm0,0x8(%rsp)
  call   <power_recurse>
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  jmp    L51
  nopl   (%rax)
L41:
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  sar    %edi
  call   <power_recurse>
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  jmp    L51
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: byte[8]
name: parse_data
arguments: data_label: D7
type_infered: f64

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D7: 1

assistant: ```c
double power_recurse(double b, int e) {
  if (e == 0) {
    return 1;
  } else if (e == 1) {
    return b;
  } else if (e % 2 == 1) {
    double res = power_recurse(b, e / 2);
    return res * res * b;
  } else if (e % 2 == 0) {
    double res = power_recurse(b, e / 2);
    return res * res;
  }
  return -1.0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ldtoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <lddec@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  mov    $0x2d,%eax
  sub    -0x4(%rbp),%eax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %eax,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  lea    D26(%rip),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: %.*Lf

assistant: ```c
char *ldtoa(long double x) {
  int dec = lddec(x);
  static char output[(45 + 3) - 1];
  sprintf(output, "%.*Lf", ((45 + 3) - 3 - dec), x);
  return output;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ldtoa>:
  endbr64
  push   %rbx
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <lddec@plt>
  mov    $0x2d,%edx
  sub    %eax,%edx
  push   0x28(%rsp)
  push   0x28(%rsp)
  lea    D1(%rip),%rsi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x20,%rsp
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: %.*Lf

assistant: ```c
char *ldtoa(long double x) {
  int dec = lddec(x);
  static char output[(45 + 3) - 1];
  sprintf(output, "%.*Lf", ((45 + 3) - 3 - dec), x);
  return output;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ldtoa>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <lddec@plt>
  push   0x28(%rsp)
  mov    %r12,%rdi
  mov    $0x2d,%edx
  push   0x28(%rsp)
  sub    %eax,%edx
  lea    D19(%rip),%rsi
  call   <sprintf@plt>
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D19: %.*Lf

assistant: ```c
char *ldtoa(long double x) {
  int dec = lddec(x);
  static char output[(45 + 3) - 1];
  sprintf(output, "%.*Lf", ((45 + 3) - 3 - dec), x);
  return output;
}
```