ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_alignas@plt>
  xor    %eax,%eax
  call   <test_alignof@plt>
  xor    %eax,%eax
  call   <test_constexpr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_alignas();
  test_alignof();
  test_constexpr();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_alignas@plt>
  xor    %eax,%eax
  call   <test_alignof@plt>
  xor    %eax,%eax
  call   <test_constexpr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_alignas();
  test_alignof();
  test_constexpr();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L12
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L12:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <operations@plt>
L10:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: Usage: a b c + * / %%


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1)
    printf("Usage: a b c + * / %%\n");
  else
    operations(argv);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L1
  mov    %rsi,%rdi
  call   <operations@plt>
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L1:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: Usage: a b c + * / %%


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1)
    printf("Usage: a b c + * / %%\n");
  else
    operations(argv);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L2
  mov    %rsi,%rdi
  call   <operations@plt>
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L2:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: Usage: a b c + * / %%


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1)
    printf("Usage: a b c + * / %%\n");
  else
    operations(argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L2
  mov    %rsi,%rdi
  call   <operations@plt>
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L2:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: Usage: a b c + * / %%


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1)
    printf("Usage: a b c + * / %%\n");
  else
    operations(argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L3
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L54:
  jmp    L49
L70:
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L70
  jmp    L37
L18:
  subl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L18
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L12
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
  jmp    L54
L12:
  nop
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x1c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <quicksort>
  jmp    L11
L3:
  nop
L11:
  leave
  ret
```

assistant: ```c
void quicksort(int *A, int len) {
  if (len < 2)
    return;
  int pivot = A[len / 2];
  int i, j;
  for (i = 0, j = len - 1;; i++, j--) {
    while (A[i] < pivot)
      i++;
    while (A[j] > pivot)
      j--;
    if (i >= j)
      break;
    int temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  quicksort(A, i);
  quicksort(A + i, len - i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L38
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%r12d
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%esi
  lea    -0x1(%r12),%edx
  mov    %rdi,%r8
  mov    $0x0,%r9d
  jmp    L33
L20:
  add    $0x1,%r9
  add    $0x4,%r8
L33:
  mov    %r9d,%ebp
  mov    %r8,%rbx
  mov    (%r8),%r10d
  cmp    %esi,%r10d
  jl     L20
  movslq %edx,%rax
  lea    (%r11,%rax,4),%rdi
  mov    (%rdi),%ecx
  cmp    %ecx,%esi
  jge    L21
  lea    -0x4(%r11,%rax,4),%rax
L19:
  sub    $0x1,%edx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%ecx
  cmp    %esi,%ecx
  jg     L19
L21:
  cmp    %r9d,%edx
  jle    L24
  mov    %ecx,(%rbx)
  mov    %r10d,(%rdi)
  sub    $0x1,%edx
  jmp    L20
L24:
  mov    %ebp,%esi
  mov    %r11,%rdi
  call   <quicksort>
  mov    %r12d,%esi
  sub    %ebp,%esi
  mov    %rbx,%rdi
  call   <quicksort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  ret
```

assistant: ```c
void quicksort(int *A, int len) {
  if (len < 2)
    return;
  int pivot = A[len / 2];
  int i, j;
  for (i = 0, j = len - 1;; i++, j--) {
    while (A[i] < pivot)
      i++;
    while (A[j] > pivot)
      j--;
    if (i >= j)
      break;
    int temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  quicksort(A, i);
  quicksort(A + i, len - i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  push   %r12
  mov    %rdi,%r10
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
L54:
  mov    %r12d,%eax
  lea    -0x1(%r12),%ecx
  mov    %r10,%rbx
  xor    %r8d,%r8d
  sar    %eax
  cltq
  mov    (%r10,%rax,4),%edi
  movslq %ecx,%rax
L16:
  mov    (%rbx),%r9d
  lea    (%r10,%rax,4),%rsi
  mov    %r8d,%ebp
  mov    (%rsi),%edx
  cmp    %edi,%r9d
  jl     L27
  cmp    %edx,%edi
  jge    L30
  lea    -0x4(%r10,%rax,4),%rax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rax,%rsi
  mov    (%rax),%edx
  sub    $0x4,%rax
  sub    $0x1,%ecx
  cmp    %edi,%edx
  jg     L13
L30:
  cmp    %r8d,%ecx
  jle    L20
  mov    %edx,(%rbx)
  sub    $0x1,%ecx
  mov    %r9d,(%rsi)
  movslq %ecx,%rax
L27:
  add    $0x1,%r8
  add    $0x4,%rbx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %ebp,%esi
  mov    %r10,%rdi
  sub    %ebp,%r12d
  call   <quicksort>
  cmp    $0x1,%r12d
  jle    L76
  mov    %rbx,%r10
  jmp    L54
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  ret
```

assistant: ```c
void quicksort(int *A, int len) {
  if (len < 2)
    return;
  int pivot = A[len / 2];
  int i, j;
  for (i = 0, j = len - 1;; i++, j--) {
    while (A[i] < pivot)
      i++;
    while (A[j] > pivot)
      j--;
    if (i >= j)
      break;
    int temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  quicksort(A, i);
  quicksort(A + i, len - i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L16:
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L0
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mat_add(double **m1, double **m2, double **m3, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m3[i][j] = m1[i][j] + m2[i][j];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mat_add>:
  endbr64
  test   %ecx,%ecx
  jle    L19
  push   %rbx
  mov    %r8d,%ebx
  mov    %rsi,%r8
  mov    %rdx,%r9
  lea    -0x1(%rcx),%edx
  lea    0x8(%rdi,%rdx,8),%r11
  lea    -0x1(%rbx),%eax
  lea    0x8(,%rax,8),%r10
  jmp    L16
L26:
  mov    (%r9),%rdx
  mov    (%rdi),%rsi
  mov    (%r8),%rcx
  movsd  (%rsi,%rax,1),%xmm0
  addsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L26
L38:
  add    $0x8,%rdi
  add    $0x8,%r8
  add    $0x8,%r9
  cmp    %r11,%rdi
  je     L56
L16:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L26
  jmp    L38
L56:
  pop    %rbx
  ret
L19:
  ret
```

assistant: ```c
void mat_add(double **m1, double **m2, double **m3, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m3[i][j] = m1[i][j] + m2[i][j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat_add>:
  endbr64
  test   %ecx,%ecx
  jle    L20
  push   %rbp
  mov    %rdi,%r11
  mov    %rdx,%rbp
  movslq %ecx,%r10
  push   %rbx
  xor    %r9d,%r9d
  mov    %rsi,%rbx
  movslq %r8d,%rdi
  nopl   0x0(%rax)
L16:
  test   %r8d,%r8d
  jle    L18
  mov    (%r11,%r9,8),%rsi
  mov    (%rbx,%r9,8),%rcx
  xor    %eax,%eax
  mov    0x0(%rbp,%r9,8),%rdx
  nopl   0x0(%rax)
L26:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L26
L18:
  add    $0x1,%r9
  cmp    %r10,%r9
  jne    L16
  pop    %rbx
  pop    %rbp
  ret
L20:
  ret
```

assistant: ```c
void mat_add(double **m1, double **m2, double **m3, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m3[i][j] = m1[i][j] + m2[i][j];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mat_add>:
  endbr64
  test   %ecx,%ecx
  jle    L63
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  test   %r8d,%r8d
  jle    L73
  mov    %r8d,%eax
  mov    %rdi,%rbp
  lea    -0x1(%r8),%r15d
  mov    %rsi,%r12
  shr    %eax
  mov    %rdx,%r13
  movslq %ecx,%r14
  xor    %edi,%edi
  lea    -0x1(%rax),%r9d
  mov    %r8d,%eax
  mov    %r8d,%r8d
  and    $0xfffffffe,%eax
  add    $0x1,%r9
  mov    %eax,-0xc(%rsp)
  shl    $0x4,%r9
  shl    $0x3,%rax
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    (%r12,%rdi,8),%rsi
  mov    0x0(%r13,%rdi,8),%rdx
  mov    0x0(%rbp,%rdi,8),%rcx
  lea    0x8(%rsi),%r10
  cmp    %r10,%rdx
  lea    0x8(%rcx),%r10
  setne  %r11b
  cmp    %r10,%rdx
  setne  %r10b
  test   %r10b,%r11b
  je     L26
  xor    %r10d,%r10d
  cmp    $0x1,%r15d
  jbe    L26
  nopw   0x0(%rax,%rax,1)
L28:
  movupd (%rcx,%r10,1),%xmm0
  movupd (%rsi,%r10,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%r10,1)
  add    $0x10,%r10
  cmp    %r9,%r10
  jne    L28
  cmp    -0xc(%rsp),%ebx
  je     L6
  movsd  (%rcx,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
L6:
  add    $0x1,%rdi
  cmp    %r14,%rdi
  jne    L13
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L26:
  xor    %r10d,%r10d
  nopl   0x0(%rax,%rax,1)
L69:
  movsd  (%rsi,%r10,8),%xmm0
  addsd  (%rcx,%r10,8),%xmm0
  movsd  %xmm0,(%rdx,%r10,8)
  add    $0x1,%r10
  cmp    %r10,%r8
  jne    L69
  jmp    L6
L63:
  ret
```

assistant: ```c
void mat_add(double **m1, double **m2, double **m3, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m3[i][j] = m1[i][j] + m2[i][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compareChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  leave
  ret
```

assistant: ```c
int compareChar(void *pn, void *pm) {
  char *n = (char *)pn;
  char *m = (char *)pm;
  return memcmp(n, m, sizeof(char));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compareChar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  call   <memcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compareChar(void *pn, void *pm) {
  char *n = (char *)pn;
  char *m = (char *)pm;
  return memcmp(n, m, sizeof(char));
}
```
user: Translate the below assembly code into C programming language:

```asm
<compareChar>:
  endbr64
  mov    $0x1,%edx
  jmp    1050 <memcmp@plt>
```

assistant: ```c
int compareChar(void *pn, void *pm) {
  char *n = (char *)pn;
  char *m = (char *)pm;
  return memcmp(n, m, sizeof(char));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compareChar>:
  endbr64
  mov    $0x1,%edx
  jmp    1050 <memcmp@plt>
```

assistant: ```c
int compareChar(void *pn, void *pm) {
  char *n = (char *)pn;
  char *m = (char *)pm;
  return memcmp(n, m, sizeof(char));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%ecx
  test   %ecx,%ecx
  je     L48
  mov    $0x0,%eax
  lea    0x4(%rsp),%r9
  jmp    L12
L23:
  mov    %eax,%edx
  lea    (%r9,%rdx,4),%rdx
  movzwl 0x2(%rdx),%edi
  movzwl (%rdx),%r8d
  mov    %r8w,0x2(%rdx)
  mov    %di,(%rdx)
L22:
  add    $0x2,%eax
  cmp    %eax,%ecx
  jbe    L48
L12:
  mov    0x4(%rsp),%edx
  cmp    %eax,%edx
  jbe    L23
  add    %edx,%edx
  mov    %edx,0x4(%rsp)
  jmp    L22
L48:
  mov    0x4(%rsp),%eax
  sub    $0x168df30a,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  char copy13;
  unsigned short copy15;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[0UL] += state[0UL];
        } else {
          copy12 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          state[local1] = state[0UL] * state[0UL];
        }
      } else if (state[0UL] > local1) {
        state[0UL] -= state[local1];
        copy13 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy15 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 378401546U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edi
  sub    $0x99f4bb,%eax
  test   %edi,%edi
  je     L17
  xor    %edx,%edx
  nopl   0x0(%rax)
L12:
  cmp    %eax,%edx
  lea    (%rax,%rax,1),%ecx
  cmovb  %ecx,%eax
  add    $0x2,%edx
  cmp    %edx,%edi
  ja     L12
L17:
  sub    $0x168df30a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  char copy13;
  unsigned short copy15;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[0UL] += state[0UL];
        } else {
          copy12 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          state[local1] = state[0UL] * state[0UL];
        }
      } else if (state[0UL] > local1) {
        state[0UL] -= state[local1];
        copy13 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy15 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 378401546U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edi
  sub    $0x99f4bb,%eax
  test   %edi,%edi
  je     L9
  xor    %edx,%edx
  nopl   0x0(%rax)
L2:
  cmp    %eax,%edx
  lea    (%rax,%rax,1),%ecx
  cmovb  %ecx,%eax
  add    $0x2,%edx
  cmp    %edi,%edx
  jb     L2
L9:
  sub    $0x168df30a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  char copy13;
  unsigned short copy15;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[0UL] += state[0UL];
        } else {
          copy12 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          state[local1] = state[0UL] * state[0UL];
        }
      } else if (state[0UL] > local1) {
        state[0UL] -= state[local1];
        copy13 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy15 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 378401546U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pauseMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L4:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  mov    $0x0,%eax
  call   <pause@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D4: %s

tool: D11: Presione enter para continuar ...

assistant: ```c
void pauseMessage(char *message) {
  if (NULL != message) {
    printf("%s", message);
  } else {
    printf("Presione enter para continuar ...");
  }
  pause();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pauseMessage>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  mov    $0x0,%eax
  call   <pause@plt>
  add    $0x8,%rsp
  ret
L6:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D7: %s

tool: D2: Presione enter para continuar ...

assistant: ```c
void pauseMessage(char *message) {
  if (NULL != message) {
    printf("%s", message);
  } else {
    printf("Presione enter para continuar ...");
  }
  pause();
}
```