ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<fcitx_utils_strrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
  jmp    L33
L28:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  jmp    L33
L36:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <fcitx_utils_backward_search@plt>
L33:
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_strrstr(const char *haystack, const char *needle) {
  if (needle[0] == '\0') {
    return NULL;
  }
  if (needle[1] == '\0') {
    return strrchr(haystack, needle[0]);
  }
  int l = strlen(haystack);
  int ol = strlen(needle);
  return fcitx_utils_backward_search(haystack, l, needle, ol, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fcitx_utils_strrstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L1
  mov    %rdi,%rbp
  cmpb   $0x0,0x1(%rbx)
  je     L5
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    $0x0,%r8d
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <fcitx_utils_backward_search@plt>
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  movsbl %sil,%esi
  call   <strrchr@plt>
  jmp    L6
L1:
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_strrstr(const char *haystack, const char *needle) {
  if (needle[0] == '\0') {
    return NULL;
  }
  if (needle[1] == '\0') {
    return strrchr(haystack, needle[0]);
  }
  int l = strlen(haystack);
  int ol = strlen(needle);
  return fcitx_utils_backward_search(haystack, l, needle, ol, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fcitx_utils_strrstr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L18
  cmpb   $0x0,0x1(%r12)
  mov    %rdi,%rbp
  je     L7
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  xor    %r8d,%r8d
  pop    %r12
  pop    %r13
  jmp    1070 <fcitx_utils_backward_search@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strrchr@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_strrstr(const char *haystack, const char *needle) {
  if (needle[0] == '\0') {
    return NULL;
  }
  if (needle[1] == '\0') {
    return strrchr(haystack, needle[0]);
  }
  int l = strlen(haystack);
  int ol = strlen(needle);
  return fcitx_utils_backward_search(haystack, l, needle, ol, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fcitx_utils_strrstr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L17
  cmpb   $0x0,0x1(%r12)
  mov    %rdi,%rbp
  je     L8
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  xor    %r8d,%r8d
  pop    %r12
  pop    %r13
  jmp    1070 <fcitx_utils_backward_search@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strrchr@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_strrstr(const char *haystack, const char *needle) {
  if (needle[0] == '\0') {
    return NULL;
  }
  if (needle[1] == '\0') {
    return strrchr(haystack, needle[0]);
  }
  int l = strlen(haystack);
  int ol = strlen(needle);
  return fcitx_utils_backward_search(haystack, l, needle, ol, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L11:
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x13,-0xc(%rbp)
  jle    L11
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 20; i++) {
    int *p;
    p = malloc(800);
    p = malloc(8);
    free(p);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x14,%ebx
L4:
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  sub    $0x1,%ebx
  jne    L4
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 20; i++) {
    int *p;
    p = malloc(800);
    p = malloc(8);
    free(p);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x14,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  sub    $0x1,%ebx
  jne    L7
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 20; i++) {
    int *p;
    p = malloc(800);
    p = malloc(8);
    free(p);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x14,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  sub    $0x1,%ebx
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 20; i++) {
    int *p;
    p = malloc(800);
    p = malloc(8);
    free(p);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sas_read4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmpl   $0x0,-0x1c(%rbp)
  je     L1
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <byteswap4@plt>
  jmp    L13
L1:
  mov    -0xc(%rbp),%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
uint32_t sas_read4(const char *data, int bswap) {
  uint32_t tmp;
  memcpy(&tmp, data, 4);
  return bswap ? byteswap4(tmp) : tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sas_read4>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rax
  mov    $0x4,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  test   %ebx,%ebx
  jne    L29
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L29:
  mov    %eax,%edi
  call   <byteswap4@plt>
  jmp    L8
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t sas_read4(const char *data, int bswap) {
  uint32_t tmp;
  memcpy(&tmp, data, 4);
  return bswap ? byteswap4(tmp) : tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sas_read4>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%ebx
  mov    $0x4,%edx
  mov    %r8,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  test   %ebx,%ebx
  jne    L0
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L0:
  mov    %eax,%edi
  call   <byteswap4@plt>
  jmp    L5
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t sas_read4(const char *data, int bswap) {
  uint32_t tmp;
  memcpy(&tmp, data, 4);
  return bswap ? byteswap4(tmp) : tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sas_read4>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%ebx
  mov    $0x4,%edx
  mov    %r8,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  test   %ebx,%ebx
  jne    L14
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L14:
  mov    %eax,%edi
  call   <byteswap4@plt>
  jmp    L7
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t sas_read4(const char *data, int bswap) {
  uint32_t tmp;
  memcpy(&tmp, data, 4);
  return bswap ? byteswap4(tmp) : tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<anrs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fmax@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fmin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <pvrs@plt>
  movsd  D7(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L23
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L23
  movsd  -0x30(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L23
  mov    -0x48(%rbp),%rax
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x50(%rbp),%rax
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L41
L23:
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L1
  lea    -0x50(%rbp),%rcx
  lea    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <trrs@plt>
  jmp    L26
L1:
  lea    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <tsrs@plt>
  mov    -0x48(%rbp),%rax
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L41:
  nop
L26:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: f64

tool: D7: 2

assistant: ```c
void anrs(const double *WL, const double *WR, double *ps, double *us) {
  double pmax = fmax(WL[2], WR[2]);
  double pmin = fmin(WL[2], WR[2]);
  double Q = pmax / pmin;
  double pstar, ustar;
  pvrs(WL, WR, &pstar, &ustar);
  if ((Q < 2.0) && (pstar < pmax) && (pstar > pmin)) {
    *ps = pstar;
    *us = ustar;
  } else {
    if (pstar < pmin) {
      trrs(WL, WR, &ps, &us);
    } else {
      tsrs(WL, WR, &pstar, &us);
      *ps = pstar;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<anrs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    0x10(%rsi),%r14
  mov    0x10(%rdi),%r13
  movq   %r14,%xmm1
  movq   %r13,%xmm0
  call   <fmax@plt>
  movq   %xmm0,%r12
  movq   %r14,%xmm1
  movq   %r13,%xmm0
  call   <fmin@plt>
  movq   %r12,%xmm3
  movsd  %xmm0,(%rsp)
  divsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  lea    0x30(%rsp),%rcx
  lea    0x28(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pvrs@plt>
  movsd  D5(%rip),%xmm0
  comisd 0x8(%rsp),%xmm0
  jbe    L56
  movsd  0x28(%rsp),%xmm0
  movq   %r12,%xmm5
  comisd %xmm0,%xmm5
  jbe    L56
  comisd (%rsp),%xmm0
  jbe    L56
  mov    0x18(%rsp),%rax
  movsd  %xmm0,(%rax)
  mov    0x10(%rsp),%rax
  movsd  0x30(%rsp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L41
L56:
  movsd  (%rsp),%xmm4
  comisd 0x28(%rsp),%xmm4
  jbe    L4
  lea    0x10(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <trrs@plt>
L41:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  lea    0x10(%rsp),%rcx
  lea    0x28(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <tsrs@plt>
  mov    0x18(%rsp),%rax
  movsd  0x28(%rsp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L41
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: f64

tool: D5: 2

assistant: ```c
void anrs(const double *WL, const double *WR, double *ps, double *us) {
  double pmax = fmax(WL[2], WR[2]);
  double pmin = fmin(WL[2], WR[2]);
  double Q = pmax / pmin;
  double pstar, ustar;
  pvrs(WL, WR, &pstar, &ustar);
  if ((Q < 2.0) && (pstar < pmax) && (pstar > pmin)) {
    *ps = pstar;
    *us = ustar;
  } else {
    if (pstar < pmin) {
      trrs(WL, WR, &ps, &us);
    } else {
      tsrs(WL, WR, &pstar, &us);
      *ps = pstar;
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<anrs>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  movsd  0x10(%rdi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mov    %rdx,0x28(%rsp)
  lea    0x38(%rsp),%r13
  mov    %rcx,0x20(%rsp)
  movapd %xmm2,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <fmax@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <fmin@plt>
  lea    0x40(%rsp),%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  movsd  0x8(%rsp),%xmm3
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rsp)
  divsd  %xmm0,%xmm3
  movsd  %xmm3,0x10(%rsp)
  call   <pvrs@plt>
  movsd  D2(%rip),%xmm1
  comisd 0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  movsd  0x38(%rsp),%xmm1
  jbe    L16
  movsd  0x8(%rsp),%xmm3
  comisd %xmm1,%xmm3
  jbe    L16
  comisd %xmm0,%xmm1
  jbe    L16
  mov    0x28(%rsp),%rax
  movsd  %xmm1,(%rax)
  mov    0x20(%rsp),%rax
  movsd  0x40(%rsp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L24
  nopl   (%rax)
L16:
  comisd %xmm1,%xmm0
  lea    0x20(%rsp),%rcx
  ja     L13
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <tsrs@plt>
  movsd  0x38(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  movsd  %xmm0,(%rax)
L24:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  lea    0x28(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <trrs@plt>
  jmp    L24
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: f64

tool: D2: 2

assistant: ```c
void anrs(const double *WL, const double *WR, double *ps, double *us) {
  double pmax = fmax(WL[2], WR[2]);
  double pmin = fmin(WL[2], WR[2]);
  double Q = pmax / pmin;
  double pstar, ustar;
  pvrs(WL, WR, &pstar, &ustar);
  if ((Q < 2.0) && (pstar < pmax) && (pstar > pmin)) {
    *ps = pstar;
    *us = ustar;
  } else {
    if (pstar < pmin) {
      trrs(WL, WR, &ps, &us);
    } else {
      tsrs(WL, WR, &pstar, &us);
      *ps = pstar;
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<anrs>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  movsd  0x10(%rdi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mov    %rdx,0x28(%rsp)
  lea    0x38(%rsp),%r13
  mov    %rcx,0x20(%rsp)
  movapd %xmm2,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <fmax@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <fmin@plt>
  lea    0x40(%rsp),%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  movsd  0x8(%rsp),%xmm3
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rsp)
  divsd  %xmm0,%xmm3
  movsd  %xmm3,0x10(%rsp)
  call   <pvrs@plt>
  movsd  D9(%rip),%xmm1
  comisd 0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  movsd  0x38(%rsp),%xmm1
  jbe    L11
  movsd  0x8(%rsp),%xmm3
  comisd %xmm1,%xmm3
  jbe    L11
  comisd %xmm0,%xmm1
  jbe    L11
  mov    0x28(%rsp),%rax
  movsd  %xmm1,(%rax)
  mov    0x20(%rsp),%rax
  movsd  0x40(%rsp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L12
  nopl   (%rax)
L11:
  comisd %xmm1,%xmm0
  lea    0x20(%rsp),%rcx
  ja     L29
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <tsrs@plt>
  movsd  0x38(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  movsd  %xmm0,(%rax)
L12:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  lea    0x28(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <trrs@plt>
  jmp    L12
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: f64

tool: D9: 2

assistant: ```c
void anrs(const double *WL, const double *WR, double *ps, double *us) {
  double pmax = fmax(WL[2], WR[2]);
  double pmin = fmin(WL[2], WR[2]);
  double Q = pmax / pmin;
  double pstar, ustar;
  pvrs(WL, WR, &pstar, &ustar);
  if ((Q < 2.0) && (pstar < pmax) && (pstar > pmin)) {
    *ps = pstar;
    *us = ustar;
  } else {
    if (pstar < pmin) {
      trrs(WL, WR, &ps, &us);
    } else {
      tsrs(WL, WR, &pstar, &us);
      *ps = pstar;
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<eye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x8(%rbp)
  jmp    L49
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L48:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L33
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L31
L33:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
L31:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L48
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int eye(int n, double **id) {
  *id = calloc(n * n, sizeof(double));
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i == j) {
        (*id)[i * n + j] = 1;
      } else {
        (*id)[i * n + j] = 0;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eye>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  imul   %edi,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %ebx,%ebx
  jle    L36
  mov    $0x0,%edi
  mov    $0x0,%esi
  mov    $0x0,%r8d
  movsd  D4(%rip),%xmm0
  jmp    L28
L4:
  lea    (%rax,%rdi,1),%edx
  movslq %edx,%rdx
  mov    0x0(%rbp),%rcx
  movsd  %xmm0,(%rcx,%rdx,8)
L15:
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  je     L35
  mov    %edx,%eax
L54:
  cmp    %eax,%esi
  je     L4
  lea    (%rax,%rdi,1),%edx
  movslq %edx,%rdx
  mov    0x0(%rbp),%rcx
  movq   $0x0,(%rcx,%rdx,8)
  jmp    L15
L35:
  lea    0x1(%rsi),%edx
  add    %ebx,%edi
  cmp    %eax,%esi
  je     L36
  mov    %edx,%esi
L28:
  mov    %r8d,%eax
  jmp    L54
L36:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int eye(int n, double **id) {
  *id = calloc(n * n, sizeof(double));
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i == j) {
        (*id)[i * n + j] = 1;
      } else {
        (*id)[i * n + j] = 0;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eye>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  imul   %edi,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %ebx,%ebx
  jle    L37
  movsd  D0(%rip),%xmm1
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  movslq %ebx,%rdi
  pxor   %xmm2,%xmm2
  nopl   0x0(%rax,%rax,1)
L32:
  movslq %r8d,%rdx
  lea    (%rax,%rdx,8),%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L30:
  movapd %xmm1,%xmm0
  cmp    %edx,%ecx
  je     L23
  movapd %xmm2,%xmm0
L23:
  movsd  %xmm0,(%rsi,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L30
  add    $0x1,%ecx
  add    %ebx,%r8d
  cmp    %ecx,%ebx
  jne    L32
L37:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int eye(int n, double **id) {
  *id = calloc(n * n, sizeof(double));
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i == j) {
        (*id)[i * n + j] = 1;
      } else {
        (*id)[i * n + j] = 0;
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<eye>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  imul   %edi,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %ebx,%ebx
  jle    L66
  movsd  D4(%rip),%xmm0
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  movslq %ebx,%rdi
  nopl   0x0(%rax)
L23:
  movslq %r8d,%rdx
  lea    (%rax,%rdx,8),%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L59:
  cmp    %edx,%ecx
  je     L30
  movq   $0x0,(%rsi,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L59
  add    $0x1,%ecx
  add    %ebx,%r8d
  cmp    %ebx,%ecx
  jne    L23
L66:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L30:
  movsd  %xmm0,(%rsi,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L59
  add    $0x1,%ecx
  add    %ebx,%r8d
  cmp    %ebx,%ecx
  jne    L23
  jmp    L66
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int eye(int n, double **id) {
  *id = calloc(n * n, sizeof(double));
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i == j) {
        (*id)[i * n + j] = 1;
      } else {
        (*id)[i * n + j] = 0;
      }
    }
  }
  return 0;
}
```