ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  mov    $0x20f0,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: Pseudo InfiniBand HCA switch v0.4.6
Usage: pibnetd [options]
Options:

--daemon, -B
	Run in daemon mode

--port, -p=<port-number>
	Specify the number of UDP (default: %u)

--verbose, -v
	Increase the log verbosity level.

--help, -h
	Display this usage


assistant: ```c
void usage(void) {
  printf("Pseudo InfiniBand HCA switch"
         " v"
         "0.4.6"
         "\n"
         "Usage: pibnetd [options]\n"
         "Options:\n"
         "\n"
         "--daemon, -B\n"
         "\tRun in daemon mode\n"
         "\n"
         "--port, -p=<port-number>\n"
         "\tSpecify the number of UDP (default: %u)\n"
         "\n"
         "--verbose, -v\n"
         "\tIncrease the log verbosity level.\n"
         "\n"
         "--help, -h\n"
         "\tDisplay this usage\n",
         (8432));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  mov    $0x20f0,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: Pseudo InfiniBand HCA switch v0.4.6
Usage: pibnetd [options]
Options:

--daemon, -B
	Run in daemon mode

--port, -p=<port-number>
	Specify the number of UDP (default: %u)

--verbose, -v
	Increase the log verbosity level.

--help, -h
	Display this usage


assistant: ```c
void usage(void) {
  printf("Pseudo InfiniBand HCA switch"
         " v"
         "0.4.6"
         "\n"
         "Usage: pibnetd [options]\n"
         "Options:\n"
         "\n"
         "--daemon, -B\n"
         "\tRun in daemon mode\n"
         "\n"
         "--port, -p=<port-number>\n"
         "\tSpecify the number of UDP (default: %u)\n"
         "\n"
         "--verbose, -v\n"
         "\tIncrease the log verbosity level.\n"
         "\n"
         "--help, -h\n"
         "\tDisplay this usage\n",
         (8432));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<totalRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L34
L28:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  jmp    L34
L7:
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    D36(%rip),%rax
  mov    (%rax),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L34
  mov    D36(%rip),%rax
  mov    (%rax),%rdx
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L34
  movq   $0xffffffffffffffff,-0x10(%rbp)
  jmp    L6
L34:
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L28
  jmp    L6
L33:
  nop
L6:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t totalRead(int fd, char **buf, size_t len) {
  ssize_t total = 0;
  ssize_t done = 0;
  while (len > total) {
    done = read(fd, *buf + total, len - total);
    if (done > 0) {
      total += (size_t)done;
    } else if (0 == done) {
      break;
    } else {
      if (errno != EINTR && errno != EAGAIN) {
        total = -1;
        break;
      }
    }
  }
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<totalRead>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L14
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x0,%ebx
L17:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  mov    %rbx,%rsi
  add    0x0(%r13),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L38
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L17
L38:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    %rdx,%rbx
  jmp    L38
```

assistant: ```c
ssize_t totalRead(int fd, char **buf, size_t len) {
  ssize_t total = 0;
  ssize_t done = 0;
  while (len > total) {
    done = read(fd, *buf + total, len - total);
    if (done > 0) {
      total += (size_t)done;
    } else if (0 == done) {
      break;
    } else {
      if (errno != EINTR && errno != EAGAIN) {
        total = -1;
        break;
      }
    }
  }
  return total;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<totalRead>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L39
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  jmp    L18
L0:
  add    %rax,%r12
  cmp    %r12,%rbx
  jbe    L45
L18:
  mov    0x0(%r13),%rsi
  mov    %rbx,%rdx
  mov    %ebp,%edi
  sub    %r12,%rdx
  add    %r12,%rsi
  call   <read@plt>
  test   %rax,%rax
  jne    L0
L45:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  xor    %r12d,%r12d
  jmp    L45
```

assistant: ```c
ssize_t totalRead(int fd, char **buf, size_t len) {
  ssize_t total = 0;
  ssize_t done = 0;
  while (len > total) {
    done = read(fd, *buf + total, len - total);
    if (done > 0) {
      total += (size_t)done;
    } else if (0 == done) {
      break;
    } else {
      if (errno != EINTR && errno != EAGAIN) {
        total = -1;
        break;
      }
    }
  }
  return total;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<totalRead>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L35
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  jmp    L36
L24:
  add    %rax,%r12
  cmp    %r12,%rbx
  jbe    L9
L36:
  mov    0x0(%r13),%rsi
  mov    %rbx,%rdx
  mov    %ebp,%edi
  sub    %r12,%rdx
  add    %r12,%rsi
  call   <read@plt>
  test   %rax,%rax
  jne    L24
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  xor    %r12d,%r12d
  jmp    L9
```

assistant: ```c
ssize_t totalRead(int fd, char **buf, size_t len) {
  ssize_t total = 0;
  ssize_t done = 0;
  while (len > total) {
    done = read(fd, *buf + total, len - total);
    if (done > 0) {
      total += (size_t)done;
    } else if (0 == done) {
      break;
    } else {
      if (errno != EINTR && errno != EAGAIN) {
        total = -1;
        break;
      }
    }
  }
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AnalogRead_MeanPC2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L7
L3:
  mov    $0x0,%eax
  call   <AnalogRead_PC2@plt>
  add    %eax,-0xc(%rbp)
  mov    $0xa,%edi
  call   <_delay_ms@plt>
  addl   $0x1,-0x8(%rbp)
L7:
  movzbl -0x14(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L3
  movzbl -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int AnalogRead_MeanPC2(unsigned char NumOfSamplesToAverage) {
  int TotalValue = 0;
  int MeanValue = 0;
  int i = 0;
  for (i = 1; i <= NumOfSamplesToAverage; i++) {
    TotalValue = TotalValue + AnalogRead_PC2();
    _delay_ms(10);
  }
  MeanValue = TotalValue / NumOfSamplesToAverage;
  return MeanValue;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AnalogRead_MeanPC2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  and    $0xff,%r13d
  je     L15
  movzbl %dil,%edi
  lea    0x1(%rdi),%r12d
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L6:
  mov    $0x0,%eax
  call   <AnalogRead_PC2@plt>
  add    %eax,%ebp
  mov    $0xa,%edi
  call   <_delay_ms@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L6
L23:
  mov    %ebp,%eax
  cltd
  idiv   %r13d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x0,%ebp
  jmp    L23
```

assistant: ```c
int AnalogRead_MeanPC2(unsigned char NumOfSamplesToAverage) {
  int TotalValue = 0;
  int MeanValue = 0;
  int i = 0;
  for (i = 1; i <= NumOfSamplesToAverage; i++) {
    TotalValue = TotalValue + AnalogRead_PC2();
    _delay_ms(10);
  }
  MeanValue = TotalValue / NumOfSamplesToAverage;
  return MeanValue;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AnalogRead_MeanPC2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0xff,%edi
  mov    %edi,%r13d
  je     L10
  lea    0x1(%rdi),%r12d
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <AnalogRead_PC2@plt>
  mov    $0xa,%edi
  add    %eax,%ebp
  call   <_delay_ms@plt>
  cmp    %ebx,%r12d
  jne    L1
  mov    %ebp,%eax
  cltd
  idiv   %r13d
  mov    %eax,%r13d
L10:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int AnalogRead_MeanPC2(unsigned char NumOfSamplesToAverage) {
  int TotalValue = 0;
  int MeanValue = 0;
  int i = 0;
  for (i = 1; i <= NumOfSamplesToAverage; i++) {
    TotalValue = TotalValue + AnalogRead_PC2();
    _delay_ms(10);
  }
  MeanValue = TotalValue / NumOfSamplesToAverage;
  return MeanValue;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AnalogRead_MeanPC2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0xff,%edi
  mov    %edi,%r13d
  je     L14
  lea    0x1(%rdi),%r12d
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <AnalogRead_PC2@plt>
  mov    $0xa,%edi
  add    %eax,%ebp
  call   <_delay_ms@plt>
  cmp    %ebx,%r12d
  jne    L3
  mov    %ebp,%eax
  cltd
  idiv   %r13d
  mov    %eax,%r13d
L14:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int AnalogRead_MeanPC2(unsigned char NumOfSamplesToAverage) {
  int TotalValue = 0;
  int MeanValue = 0;
  int i = 0;
  for (i = 1; i <= NumOfSamplesToAverage; i++) {
    TotalValue = TotalValue + AnalogRead_PC2();
    _delay_ms(10);
  }
  MeanValue = TotalValue / NumOfSamplesToAverage;
  return MeanValue;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0x7,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x9,-0x14(%rbp)
  movl   $0xc,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L2
L14:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L2:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d

assistant: ```c
int main(void) {
  int A[] = {5, 0, 2, 4, 5, 7, 1, 6, 3, 6, 2, 9};
  int n = sizeof(A) / sizeof(int);
  merge_sort(A, 0, n - 1);
  for (int i = 0; i < n; i++)
    printf("%d", A[i]);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x7,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  movl   $0x2,0x28(%rsp)
  movl   $0x9,0x2c(%rsp)
  mov    %rsp,%rbx
  mov    $0xb,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <merge_sort@plt>
  lea    0x30(%rsp),%r12
  lea    D7(%rip),%rbp
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: %d

assistant: ```c
int main(void) {
  int A[] = {5, 0, 2, 4, 5, 7, 1, 6, 3, 6, 2, 9};
  int n = sizeof(A) / sizeof(int);
  merge_sort(A, 0, n - 1);
  for (int i = 0; i < n; i++)
    printf("%d", A[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r12
  movabs $0x400000002,%rax
  mov    %rax,0x8(%rsp)
  mov    %rbx,%rdi
  movabs $0x700000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x600000001,%rax
  mov    %rax,0x18(%rsp)
  add    $0x2,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x900000002,%rax
  movq   $0x5,(%rsp)
  mov    %rax,0x28(%rsp)
  call   <merge_sort@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main(void) {
  int A[] = {5, 0, 2, 4, 5, 7, 1, 6, 3, 6, 2, 9};
  int n = sizeof(A) / sizeof(int);
  merge_sort(A, 0, n - 1);
  for (int i = 0; i < n; i++)
    printf("%d", A[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D38(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D4(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <merge_sort@plt>
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: byte[16]
name: retrieve_data
arguments: data_label: D38
datatype: byte[16]
name: retrieve_data
arguments: data_label: D4
datatype: byte[16]

tool: D21: %d

tool: {"D11": [0x05,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D38": [0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D4": [0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int A[] = {5, 0, 2, 4, 5, 7, 1, 6, 3, 6, 2, 9};
  int n = sizeof(A) / sizeof(int);
  merge_sort(A, 0, n - 1);
  for (int i = 0; i < n; i++)
    printf("%d", A[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<left_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L52
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_digit@plt>
  test   %eax,%eax
  je     L57
  subl   $0x1,-0xc(%rbp)
L52:
  cmpl   $0x0,-0xc(%rbp)
  jns    L11
  jmp    L12
L57:
  nop
L12:
  cmpl   $0x0,-0xc(%rbp)
  je     L67
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L32
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_digit@plt>
  test   %eax,%eax
  je     L67
L32:
  addl   $0x1,-0xc(%rbp)
L67:
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0x1c(%rbp),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *left_argument(char buffer[], int index) {
  int count;
  int *values;
  values = (int *)malloc(2 * sizeof(int));
  for (count = index - 1; count >= 0; count--) {
    if (!is_digit(buffer[count]))
      break;
  }
  if (count != 0) {
    if (!((buffer[count] == '-') && (!is_digit(buffer[count - 1]))))
      count++;
  }
  values[0] = count;
  values[1] = index - 1;
  return values;
}
```
user: Translate the below assembly code into C programming language:

```asm
<left_argument>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  sub    $0x1,%r12d
  js     L86
  movslq %r12d,%rbp
  add    %r14,%rbp
  mov    %r12d,%ebx
L33:
  movsbl 0x0(%rbp),%edi
  call   <is_digit@plt>
  test   %eax,%eax
  je     L45
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  jne    L33
L85:
  movslq %ebx,%rax
  cmpb   $0x2d,(%r14,%rax,1)
  je     L56
L41:
  add    $0x1,%ebx
  jmp    L16
L45:
  test   %ebx,%ebx
  jne    L85
L16:
  mov    %ebx,0x0(%r13)
  mov    %r12d,0x4(%r13)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  movsbl -0x1(%r14,%rax,1),%edi
  call   <is_digit@plt>
  test   %eax,%eax
  je     L16
  jmp    L41
L86:
  mov    %r12d,%ebx
  jmp    L85
```

assistant: ```c
int *left_argument(char buffer[], int index) {
  int count;
  int *values;
  values = (int *)malloc(2 * sizeof(int));
  for (count = index - 1; count >= 0; count--) {
    if (!is_digit(buffer[count]))
      break;
  }
  if (count != 0) {
    if (!((buffer[count] == '-') && (!is_digit(buffer[count - 1]))))
      count++;
  }
  values[0] = count;
  values[1] = index - 1;
  return values;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<left_argument>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    $0x8,%edi
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r13
  sub    $0x1,%r12d
  js     L23
  movslq %r12d,%rbp
  mov    %r12d,%ebx
  add    %r14,%rbp
  jmp    L33
L1:
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  je     L14
L33:
  movsbl 0x0(%rbp),%edi
  call   <is_digit@plt>
  test   %eax,%eax
  jne    L1
  test   %ebx,%ebx
  jne    L14
L53:
  mov    %ebx,0x0(%r13)
  mov    %r13,%rax
  mov    %r12d,0x4(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    %r12d,%ebx
  nopl   0x0(%rax)
L14:
  movslq %ebx,%rax
  cmpb   $0x2d,(%r14,%rax,1)
  je     L6
L72:
  add    $0x1,%ebx
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl -0x1(%r14,%rax,1),%edi
  call   <is_digit@plt>
  test   %eax,%eax
  jne    L72
  jmp    L53
```

assistant: ```c
int *left_argument(char buffer[], int index) {
  int count;
  int *values;
  values = (int *)malloc(2 * sizeof(int));
  for (count = index - 1; count >= 0; count--) {
    if (!is_digit(buffer[count]))
      break;
  }
  if (count != 0) {
    if (!((buffer[count] == '-') && (!is_digit(buffer[count - 1]))))
      count++;
  }
  values[0] = count;
  values[1] = index - 1;
  return values;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<left_argument>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    $0x8,%edi
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r13
  sub    $0x1,%r12d
  js     L17
  movslq %r12d,%rbp
  mov    %r12d,%ebx
  add    %r14,%rbp
  jmp    L11
L54:
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  je     L22
L11:
  movsbl 0x0(%rbp),%edi
  call   <is_digit@plt>
  test   %eax,%eax
  jne    L54
  test   %ebx,%ebx
  jne    L22
L44:
  movd   %ebx,%xmm0
  movd   %r12d,%xmm1
  mov    %r13,%rax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %r12d,%ebx
  nop
L22:
  movslq %ebx,%rax
  cmpb   $0x2d,(%r14,%rax,1)
  je     L61
L58:
  add    $0x1,%ebx
  jmp    L44
  nop
L61:
  movsbl -0x1(%r14,%rax,1),%edi
  call   <is_digit@plt>
  test   %eax,%eax
  jne    L58
  jmp    L44
```

assistant: ```c
int *left_argument(char buffer[], int index) {
  int count;
  int *values;
  values = (int *)malloc(2 * sizeof(int));
  for (count = index - 1; count >= 0; count--) {
    if (!is_digit(buffer[count]))
      break;
  }
  if (count != 0) {
    if (!((buffer[count] == '-') && (!is_digit(buffer[count - 1]))))
      count++;
  }
  values[0] = count;
  values[1] = index - 1;
  return values;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compress512>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %rdx,-0x438(%rbp)
  mov    %rcx,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x410(%rbp),%rax
  add    $0x100,%rax
  mov    -0x430(%rbp),%rcx
  mov    $0xc0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x440(%rbp),%rcx
  mov    -0x438(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <echo_compress@plt>
  movl   $0x0,-0x414(%rbp)
  jmp    L16
L19:
  mov    -0x414(%rbp),%eax
  shl    $0x6,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x430(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x428(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memxor@plt>
  addl   $0x1,-0x414(%rbp)
L16:
  cmpl   $0x2,-0x414(%rbp)
  jle    L19
  movl   $0x0,-0x414(%rbp)
  jmp    L42
L25:
  mov    -0x414(%rbp),%eax
  shl    $0x6,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x410(%rbp),%rax
  lea    (%rax,%rdx,1),%rcx
  mov    -0x428(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memxor@plt>
  addl   $0x1,-0x414(%rbp)
L42:
  cmpl   $0x3,-0x414(%rbp)
  jle    L25
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
void compress512(void *v, void *m, uint64_t *c, void *salt) {
  uint8_t s[16 * 16];
  uint8_t i;
  memcpy(s, v, 16 * 4);
  memcpy(s + 16 * 4, m, 16 * 12);
  echo_compress(s, 8, c, salt);
  for (i = 0; i < 3; ++i) {
    memxor(v, (uint8_t *)m + 4 * 16 * i, 4 * 16);
  }
  for (i = 0; i < 4; ++i) {
    memxor(v, s + 4 * 16 * i, 4 * 16);
  }
}
```