ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<MatMul>:
  endbr64
  test   %edi,%edi
  jle    L35
  movslq %edi,%rdi
  push   %rbp
  mov    %rdx,%r9
  mov    %rcx,%rbp
  push   %rbx
  lea    0x0(,%rdi,8),%r10
  mov    %rsi,%rbx
  xor    %r11d,%r11d
  pxor   %xmm2,%xmm2
  nopl   (%rax)
L23:
  mov    (%rbx,%r11,8),%r8
  mov    0x0(%rbp,%r11,8),%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L10:
  movq   $0x0,(%rsi)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L7:
  mov    (%r9,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rdi,%rax
  jne    L7
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rcx,%r10
  jne    L10
  add    $0x1,%r11
  cmp    %rdi,%r11
  jne    L23
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int MatMul(int n, double **A, double **T, double **S) {
  int i, j, k;
  for (i = 0; i < n; ++i)
    for (j = 0; j < n; ++j) {
      S[i][j] = 0;
      for (k = 0; k < n; ++k)
        S[i][j] += A[i][k] * T[k][j];
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MatMul>:
  endbr64
  test   %edi,%edi
  jle    L34
  movslq %edi,%rdi
  push   %rbp
  mov    %rdx,%r9
  mov    %rcx,%rbp
  push   %rbx
  lea    0x0(,%rdi,8),%r10
  mov    %rsi,%rbx
  xor    %r11d,%r11d
  pxor   %xmm2,%xmm2
  nopl   (%rax)
L37:
  mov    (%rbx,%r11,8),%r8
  mov    0x0(%rbp,%r11,8),%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L28:
  movq   $0x0,(%rsi)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L10:
  mov    (%r9,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%rdi
  jne    L10
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rcx,%r10
  jne    L28
  add    $0x1,%r11
  cmp    %r11,%rdi
  jne    L37
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int MatMul(int n, double **A, double **T, double **S) {
  int i, j, k;
  for (i = 0; i < n; ++i)
    for (j = 0; j < n; ++j) {
      S[i][j] = 0;
      for (k = 0; k < n; ++k)
        S[i][j] += A[i][k] * T[k][j];
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scan_actual_brightness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <exists@plt>
  test   %rax,%rax
  je     L12
  lea    D28(%rip),%rax
  jmp    L37
L12:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <exists@plt>
  test   %rax,%rax
  je     L13
  lea    D24(%rip),%rax
  jmp    L37
L13:
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string

tool: D28: /sys/class/backlight/gta02-bl/actual_brightness

tool: D24: /sys/devices/virtual/backlight/acpi_video0/actual_brightness

assistant: ```c
const char *scan_actual_brightness() {
  if (exists("/sys/class/backlight/gta02-bl/actual_brightness"))
    return "/sys/class/backlight/gta02-bl/actual_brightness";
  if (exists("/sys/devices/virtual/backlight/acpi_video0/actual_brightness"))
    return "/sys/devices/virtual/backlight/acpi_video0/actual_brightness";
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scan_actual_brightness>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <exists@plt>
  mov    %rax,%rdx
  lea    D28(%rip),%rax
  test   %rdx,%rdx
  je     L8
L14:
  add    $0x8,%rsp
  ret
L8:
  lea    D37(%rip),%rdi
  call   <exists@plt>
  test   %rax,%rax
  lea    D37(%rip),%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  jmp    L14
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D37
type_guessed: string

tool: D28: /sys/class/backlight/gta02-bl/actual_brightness

tool: D37: /sys/devices/virtual/backlight/acpi_video0/actual_brightness

assistant: ```c
const char *scan_actual_brightness() {
  if (exists("/sys/class/backlight/gta02-bl/actual_brightness"))
    return "/sys/class/backlight/gta02-bl/actual_brightness";
  if (exists("/sys/devices/virtual/backlight/acpi_video0/actual_brightness"))
    return "/sys/devices/virtual/backlight/acpi_video0/actual_brightness";
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scan_actual_brightness>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <exists@plt>
  mov    %rax,%rbp
  mov    %rbx,%rax
  test   %rbp,%rbp
  jne    L9
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <exists@plt>
  test   %rax,%rax
  mov    %rbp,%rax
  cmovne %rbx,%rax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D19
type: string

tool: D8: /sys/class/backlight/gta02-bl/actual_brightness

tool: D19: /sys/devices/virtual/backlight/acpi_video0/actual_brightness

assistant: ```c
const char *scan_actual_brightness() {
  if (exists("/sys/class/backlight/gta02-bl/actual_brightness"))
    return "/sys/class/backlight/gta02-bl/actual_brightness";
  if (exists("/sys/devices/virtual/backlight/acpi_video0/actual_brightness"))
    return "/sys/devices/virtual/backlight/acpi_video0/actual_brightness";
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<scan_actual_brightness>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <exists@plt>
  mov    %rax,%rbp
  mov    %rbx,%rax
  test   %rbp,%rbp
  jne    L4
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <exists@plt>
  test   %rax,%rax
  mov    %rbp,%rax
  cmovne %rbx,%rax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D11: /sys/class/backlight/gta02-bl/actual_brightness

tool: D7: /sys/devices/virtual/backlight/acpi_video0/actual_brightness

assistant: ```c
const char *scan_actual_brightness() {
  if (exists("/sys/class/backlight/gta02-bl/actual_brightness"))
    return "/sys/class/backlight/gta02-bl/actual_brightness";
  if (exists("/sys/devices/virtual/backlight/acpi_video0/actual_brightness"))
    return "/sys/devices/virtual/backlight/acpi_video0/actual_brightness";
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tag2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  ja     L16
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D53(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D53(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D64(%rip),%rax
  jmp    L21
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <dtag2str@plt>
  jmp    L21
  lea    D1(%rip),%rax
  jmp    L21
  lea    D14(%rip),%rax
  jmp    L21
  lea    D54(%rip),%rax
  jmp    L21
  lea    D4(%rip),%rax
  jmp    L21
L16:
  lea    D21(%rip),%rax
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D64
type: string
name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D54
type: string
name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D21
type: string

tool: D64: TAG

tool: D1: ATTR

tool: D14: DATTR

tool: D54: BLOB

tool: D4: UDATA

tool: D21: ?

assistant: ```c
const char *tag2str(int tag, int num) {
  switch (tag) {
  case 1:
    return "TAG";
  case 2:
    return dtag2str(num);
  case 3:
    return "ATTR";
  case 4:
    return "DATTR";
  case 5:
    return "BLOB";
  case 6:
    return "UDATA";
  }
  return "?";
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tag2str>:
  endbr64
  cmp    $0x6,%edi
  ja     L2
  mov    %edi,%eax
  lea    D36(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D37(%rip),%rax
  ret
  sub    $0x8,%rsp
  mov    %esi,%edi
  call   <dtag2str@plt>
  add    $0x8,%rsp
  ret
  lea    D62(%rip),%rax
  ret
  lea    D20(%rip),%rax
  ret
  lea    D65(%rip),%rax
  ret
L2:
  lea    D51(%rip),%rax
  ret
  lea    D31(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D37
type: string
name: disassemble_data
arguments: data_tag: D62
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D65
type: string
name: disassemble_data
arguments: data_tag: D51
type: string
name: disassemble_data
arguments: data_tag: D31
type: string

tool: D37: ATTR

tool: D62: DATTR

tool: D20: BLOB

tool: D65: UDATA

tool: D51: ?

tool: D31: TAG

assistant: ```c
const char *tag2str(int tag, int num) {
  switch (tag) {
  case 1:
    return "TAG";
  case 2:
    return dtag2str(num);
  case 3:
    return "ATTR";
  case 4:
    return "DATTR";
  case 5:
    return "BLOB";
  case 6:
    return "UDATA";
  }
  return "?";
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tag2str>:
  endbr64
  mov    %edi,%eax
  cmp    $0x6,%eax
  ja     L3
  lea    D60(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D42(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D21(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  mov    %esi,%edi
  jmp    1050 <dtag2str@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D31(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D36(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D7(%rip),%rax
  ret
L3:
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D42
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D31
type_infered: string
name: disassemble_data
arguments: tag: D36
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D42: ATTR

tool: D21: TAG

tool: D31: DATTR

tool: D36: BLOB

tool: D7: UDATA

tool: D1: ?

assistant: ```c
const char *tag2str(int tag, int num) {
  switch (tag) {
  case 1:
    return "TAG";
  case 2:
    return dtag2str(num);
  case 3:
    return "ATTR";
  case 4:
    return "DATTR";
  case 5:
    return "BLOB";
  case 6:
    return "UDATA";
  }
  return "?";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tag2str>:
  endbr64
  mov    %edi,%eax
  cmp    $0x6,%eax
  ja     L8
  lea    D16(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D9(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D0(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  mov    %esi,%edi
  jmp    1050 <dtag2str@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D46(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D63(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D58(%rip),%rax
  ret
L8:
  lea    D5(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D46
datatype: string
name: retrieve_data
arguments: data_label: D63
datatype: string
name: retrieve_data
arguments: data_label: D58
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D9: ATTR

tool: D0: TAG

tool: D46: DATTR

tool: D63: BLOB

tool: D58: UDATA

tool: D5: ?

assistant: ```c
const char *tag2str(int tag, int num) {
  switch (tag) {
  case 1:
    return "TAG";
  case 2:
    return dtag2str(num);
  case 3:
    return "ATTR";
  case 4:
    return "DATTR";
  case 5:
    return "BLOB";
  case 6:
    return "UDATA";
  }
  return "?";
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<murmur3_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <is_aligned32@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  and    $0xfffffffffffffffc,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L8:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mixin@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <remix@plt>
  mov    %eax,-0x14(%rbp)
  addq   $0x4,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L8
  mov    -0x30(%rbp),%rax
  and    $0x3,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get32@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mixin@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  xor    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <burn@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t murmur3_32(const void *key, size_t size, uint32_t seed) {
  assert(is_aligned32(key));
  const uint32_t *cursor = (const uint32_t *)key;
  const uint32_t *tail = cursor + size / 4;
  uint32_t hash = seed;
  for (; cursor < tail; ++cursor) {
    hash = mixin(hash, *cursor);
    hash = remix(hash);
  }
  hash = mixin(hash, get32((const uint8_t *)tail, size % 4));
  hash ^= (uint32_t)size;
  hash = burn(hash);
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<murmur3_32>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%ebp
  call   <is_aligned32@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r13,%r12
  and    $0xfffffffffffffffc,%r12
  add    %rbx,%r12
  cmp    %r12,%rbx
  jae    L13
L7:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  call   <mixin@plt>
  mov    %eax,%edi
  call   <remix@plt>
  mov    %eax,%ebp
  add    $0x4,%rbx
  cmp    %rbx,%r12
  ja     L7
L13:
  mov    %r13,%rsi
  and    $0x3,%esi
  mov    %r12,%rdi
  call   <get32@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <mixin@plt>
  xor    %r13d,%eax
  mov    %eax,%edi
  call   <burn@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t murmur3_32(const void *key, size_t size, uint32_t seed) {
  assert(is_aligned32(key));
  const uint32_t *cursor = (const uint32_t *)key;
  const uint32_t *tail = cursor + size / 4;
  uint32_t hash = seed;
  for (; cursor < tail; ++cursor) {
    hash = mixin(hash, *cursor);
    hash = remix(hash);
  }
  hash = mixin(hash, get32((const uint8_t *)tail, size % 4));
  hash ^= (uint32_t)size;
  hash = burn(hash);
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<murmur3_32>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r12,%r13
  mov    %edx,%ebp
  push   %rbx
  and    $0xfffffffffffffffc,%r13
  mov    %rdi,%rbx
  add    %rbx,%r13
  sub    $0x8,%rsp
  call   <is_aligned32@plt>
  mov    %eax,%edi
  call   <assert@plt>
  cmp    %r13,%rbx
  jae    L11
  nopl   0x0(%rax)
L17:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  add    $0x4,%rbx
  call   <mixin@plt>
  mov    %eax,%edi
  call   <remix@plt>
  mov    %eax,%ebp
  cmp    %rbx,%r13
  ja     L17
L11:
  mov    %r12,%rsi
  mov    %r13,%rdi
  and    $0x3,%esi
  call   <get32@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <mixin@plt>
  add    $0x8,%rsp
  xor    %r12d,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  jmp    10a0 <burn@plt>
```

assistant: ```c
uint32_t murmur3_32(const void *key, size_t size, uint32_t seed) {
  assert(is_aligned32(key));
  const uint32_t *cursor = (const uint32_t *)key;
  const uint32_t *tail = cursor + size / 4;
  uint32_t hash = seed;
  for (; cursor < tail; ++cursor) {
    hash = mixin(hash, *cursor);
    hash = remix(hash);
  }
  hash = mixin(hash, get32((const uint8_t *)tail, size % 4));
  hash ^= (uint32_t)size;
  hash = burn(hash);
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<murmur3_32>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r12,%r13
  mov    %edx,%ebp
  push   %rbx
  and    $0xfffffffffffffffc,%r13
  mov    %rdi,%rbx
  add    %rbx,%r13
  sub    $0x8,%rsp
  call   <is_aligned32@plt>
  mov    %eax,%edi
  call   <assert@plt>
  cmp    %r13,%rbx
  jae    L3
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  add    $0x4,%rbx
  call   <mixin@plt>
  mov    %eax,%edi
  call   <remix@plt>
  mov    %eax,%ebp
  cmp    %rbx,%r13
  ja     L14
L3:
  mov    %r12,%rsi
  mov    %r13,%rdi
  and    $0x3,%esi
  call   <get32@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <mixin@plt>
  add    $0x8,%rsp
  xor    %r12d,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  jmp    10a0 <burn@plt>
```

assistant: ```c
uint32_t murmur3_32(const void *key, size_t size, uint32_t seed) {
  assert(is_aligned32(key));
  const uint32_t *cursor = (const uint32_t *)key;
  const uint32_t *tail = cursor + size / 4;
  uint32_t hash = seed;
  for (; cursor < tail; ++cursor) {
    hash = mixin(hash, *cursor);
    hash = remix(hash);
  }
  hash = mixin(hash, get32((const uint8_t *)tail, size % 4));
  hash ^= (uint32_t)size;
  hash = burn(hash);
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<prog_flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sort_prog@plt>
  mov    $0x0,%eax
  call   <prog_GC@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void prog_flush(void) {
  sort_prog();
  prog_GC();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prog_flush>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sort_prog@plt>
  mov    $0x0,%eax
  call   <prog_GC@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void prog_flush(void) {
  sort_prog();
  prog_GC();
}
```
user: Translate the below assembly code into C programming language:

```asm
<prog_flush>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sort_prog@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <prog_GC@plt>
```

assistant: ```c
void prog_flush(void) {
  sort_prog();
  prog_GC();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<prog_flush>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sort_prog@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <prog_GC@plt>
```

assistant: ```c
void prog_flush(void) {
  sort_prog();
  prog_GC();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: string

tool: D7: #Args = %d. They are:


assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("#Args = %d. They are:\n", argc - 1);
  for (i = 1; i < argc; ++i)
    puts(argv[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    -0x1(%rdi),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L15
  lea    0x8(%r12),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x10(%r12,%rax,8),%rbp
L4:
  mov    (%rbx),%rdi
  call   <puts@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L4
L15:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: #Args = %d. They are:


assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("#Args = %d. They are:\n", argc - 1);
  for (i = 1; i < argc; ++i)
    puts(argv[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    -0x1(%rdi),%esi
  push   %rbp
  mov    %edi,%ebp
  lea    D2(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L3
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%rbp
  xchg   %ax,%ax
L8:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L8
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: #Args = %d. They are:


assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("#Args = %d. They are:\n", argc - 1);
  for (i = 1; i < argc; ++i)
    puts(argv[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    -0x1(%rdi),%esi
  push   %rbp
  mov    %edi,%ebp
  lea    D3(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L2
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%rbp
  xchg   %ax,%ax
L6:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L6
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: #Args = %d. They are:


assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("#Args = %d. They are:\n", argc - 1);
  for (i = 1; i < argc; ++i)
    puts(argv[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_parenthesis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L69
L23:
  cmpb   $0x28,-0x5(%rbp)
  jne    L54
  addl   $0x1,-0x4(%rbp)
  jmp    L43
L54:
  cmpb   $0x29,-0x5(%rbp)
  jne    L43
  subl   $0x1,-0x4(%rbp)
L43:
  cmpl   $0x0,-0x4(%rbp)
  js     L60
L69:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L23
  jmp    L8
L60:
  nop
L8:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int check_parenthesis(const char *input) {
  int pcount = 0;
  char c;
  while ((c = *input++) != '\0') {
    if (c == '(') {
      pcount++;
    } else if (c == ')') {
      pcount--;
    }
    if (pcount < 0)
      break;
  }
  return pcount;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_parenthesis>:
  endbr64
  mov    $0x0,%edx
  jmp    L19
L36:
  add    $0x1,%edx
L8:
  test   %edx,%edx
  js     L27
L19:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L27
  cmp    $0x28,%al
  je     L36
  cmp    $0x29,%al
  sete   %al
  movzbl %al,%eax
  sub    %eax,%edx
  jmp    L8
L27:
  mov    %edx,%eax
  ret
```

assistant: ```c
int check_parenthesis(const char *input) {
  int pcount = 0;
  char c;
  while ((c = *input++) != '\0') {
    if (c == '(') {
      pcount++;
    } else if (c == ')') {
      pcount--;
    }
    if (pcount < 0)
      break;
  }
  return pcount;
}
```