ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rewrite_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %eax,%eax
  jne    L31
  mov    -0x8(%rbp),%rax
  movb   $0x2e,(%rax)
L31:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void rewrite_ascii(char *string) {
  char *p;
  for (p = string; *p; p++) {
    if (!isgraph(*p) && !isblank(*p))
      *p = '.';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rewrite_ascii>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L47
L6:
  pop    %rbx
  ret
L24:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L6
L47:
  movsbl %dil,%edi
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L24
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %eax,%eax
  jne    L24
  movb   $0x2e,(%rbx)
  jmp    L24
```

assistant: ```c
void rewrite_ascii(char *string) {
  char *p;
  for (p = string; *p; p++) {
    if (!isgraph(*p) && !isblank(*p))
      *p = '.';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rewrite_ascii>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L52
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L55:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L44
L52:
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L55
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %eax,%eax
  jne    L55
  movb   $0x2e,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L52
L44:
  pop    %rbx
  ret
```

assistant: ```c
void rewrite_ascii(char *string) {
  char *p;
  for (p = string; *p; p++) {
    if (!isgraph(*p) && !isblank(*p))
      *p = '.';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rewrite_ascii>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L59
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L23:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L6
L59:
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L23
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %eax,%eax
  jne    L23
  movb   $0x2e,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L59
L6:
  pop    %rbx
  ret
```

assistant: ```c
void rewrite_ascii(char *string) {
  char *p;
  for (p = string; *p; p++) {
    if (!isgraph(*p) && !isblank(*p))
      *p = '.';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fdt_subnode_offset_namelen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fdt_check_header@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L54
  mov    -0xc(%rbp),%eax
  jmp    L89
L54:
  movl   $0x0,-0x10(%rbp)
  jmp    L95
L0:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L109
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_fdt_nodename_eq@plt>
  test   %rax,%rax
  je     L109
  mov    -0x1c(%rbp),%eax
  jmp    L89
L109:
  lea    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fdt_next_node@plt>
  mov    %eax,-0x1c(%rbp)
L95:
  cmpl   $0x0,-0x1c(%rbp)
  js     L77
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L0
L77:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L60
  mov    $0xffffffff,%eax
  jmp    L89
L60:
  mov    -0x1c(%rbp),%eax
L89:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
int fdt_subnode_offset_namelen(const void *fdt, int offset, const char *name, int namelen) {
  int depth;
  {
    int err;
    if ((err = fdt_check_header(fdt)) != 0)
      return err;
  };
  for (depth = 0; (offset >= 0) && (depth >= 0); offset = fdt_next_node(fdt, offset, &depth))
    if ((depth == 1) && _fdt_nodename_eq(fdt, offset, name, namelen))
      return offset;
  if (depth < 0)
    return -1;
  return offset;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fdt_subnode_offset_namelen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %ecx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fdt_check_header@plt>
  test   %eax,%eax
  jne    L1
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r12
  test   %ebx,%ebx
  js     L16
L70:
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <fdt_next_node@plt>
  mov    %eax,%ebx
  mov    0x4(%rsp),%eax
  mov    %eax,%ecx
  or     %ebx,%ecx
  js     L17
  cmp    $0x1,%eax
  jne    L70
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <_fdt_nodename_eq@plt>
  test   %rax,%rax
  je     L70
  jmp    L16
L17:
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovs  %eax,%ebx
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    %eax,%ebx
  jmp    L16
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_subnode_offset_namelen(const void *fdt, int offset, const char *name, int namelen) {
  int depth;
  {
    int err;
    if ((err = fdt_check_header(fdt)) != 0)
      return err;
  };
  for (depth = 0; (offset >= 0) && (depth >= 0); offset = fdt_next_node(fdt, offset, &depth))
    if ((depth == 1) && _fdt_nodename_eq(fdt, offset, name, namelen))
      return offset;
  if (depth < 0)
    return -1;
  return offset;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fdt_subnode_offset_namelen>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fdt_check_header@plt>
  test   %eax,%eax
  jne    L58
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r12
  test   %ebp,%ebp
  js     L61
  nopl   (%rax)
L69:
  mov    %ebp,%esi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <fdt_next_node@plt>
  mov    %eax,%ebp
  mov    0x4(%rsp),%eax
  mov    %eax,%ecx
  or     %ebp,%ecx
  js     L39
  cmp    $0x1,%eax
  jne    L69
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_fdt_nodename_eq@plt>
  test   %rax,%rax
  je     L69
  nopl   0x0(%rax,%rax,1)
L61:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L39:
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovs  %eax,%ebp
  jmp    L61
  nopl   0x0(%rax)
L58:
  mov    %eax,%ebp
  jmp    L61
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_subnode_offset_namelen(const void *fdt, int offset, const char *name, int namelen) {
  int depth;
  {
    int err;
    if ((err = fdt_check_header(fdt)) != 0)
      return err;
  };
  for (depth = 0; (offset >= 0) && (depth >= 0); offset = fdt_next_node(fdt, offset, &depth))
    if ((depth == 1) && _fdt_nodename_eq(fdt, offset, name, namelen))
      return offset;
  if (depth < 0)
    return -1;
  return offset;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fdt_subnode_offset_namelen>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fdt_check_header@plt>
  test   %eax,%eax
  jne    L29
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r12
  test   %ebp,%ebp
  js     L39
  nopl   (%rax)
L54:
  mov    %ebp,%esi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <fdt_next_node@plt>
  mov    %eax,%ebp
  mov    0x4(%rsp),%eax
  mov    %eax,%ecx
  or     %ebp,%ecx
  js     L52
  cmp    $0x1,%eax
  jne    L54
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_fdt_nodename_eq@plt>
  test   %rax,%rax
  je     L54
  nopl   0x0(%rax,%rax,1)
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L52:
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovs  %eax,%ebp
  jmp    L39
  nopl   0x0(%rax)
L29:
  mov    %eax,%ebp
  jmp    L39
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_subnode_offset_namelen(const void *fdt, int offset, const char *name, int namelen) {
  int depth;
  {
    int err;
    if ((err = fdt_check_header(fdt)) != 0)
      return err;
  };
  for (depth = 0; (offset >= 0) && (depth >= 0); offset = fdt_next_node(fdt, offset, &depth))
    if ((depth == 1) && _fdt_nodename_eq(fdt, offset, name, namelen))
      return offset;
  if (depth < 0)
    return -1;
  return offset;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dlg_strclone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <dlg_exiterr@plt>
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: cannot allocate memory in dlg_strclone

assistant: ```c
char *dlg_strclone(const char *cprompt) {
  char *prompt = (char *)malloc(strlen(cprompt) + 1);
  if ((prompt) == 0)
    dlg_exiterr("cannot allocate memory in "
                "dlg_strclone");
  strcpy(prompt, cprompt);
  return prompt;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dlg_strclone>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L11:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D4(%rip),%rdi
  call   <dlg_exiterr@plt>
  jmp    L11
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: cannot allocate memory in dlg_strclone

assistant: ```c
char *dlg_strclone(const char *cprompt) {
  char *prompt = (char *)malloc(strlen(cprompt) + 1);
  if ((prompt) == 0)
    dlg_exiterr("cannot allocate memory in "
                "dlg_strclone");
  strcpy(prompt, cprompt);
  return prompt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dlg_strclone>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  lea    D4(%rip),%rdi
  call   <dlg_exiterr@plt>
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: cannot allocate memory in dlg_strclone

assistant: ```c
char *dlg_strclone(const char *cprompt) {
  char *prompt = (char *)malloc(strlen(cprompt) + 1);
  if ((prompt) == 0)
    dlg_exiterr("cannot allocate memory in "
                "dlg_strclone");
  strcpy(prompt, cprompt);
  return prompt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dlg_strclone>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    D4(%rip),%rdi
  call   <dlg_exiterr@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: cannot allocate memory in dlg_strclone

assistant: ```c
char *dlg_strclone(const char *cprompt) {
  char *prompt = (char *)malloc(strlen(cprompt) + 1);
  if ((prompt) == 0)
    dlg_exiterr("cannot allocate memory in "
                "dlg_strclone");
  strcpy(prompt, cprompt);
  return prompt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<htmlspecialchars_nmov>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L72:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3e,%eax
  je     L104
  cmp    $0x3e,%eax
  jg     L97
  cmp    $0x3c,%eax
  je     L118
  cmp    $0x3c,%eax
  jg     L97
  cmp    $0x22,%eax
  je     L64
  cmp    $0x26,%eax
  jne    L97
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x5,-0x8(%rbp)
  jmp    L114
L118:
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  lea    D30(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x4,-0x8(%rbp)
  jmp    L114
L104:
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  lea    D39(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x4,-0x8(%rbp)
  jmp    L114
L64:
  mov    -0x8(%rbp),%rax
  mov    $0x6,%edx
  lea    D27(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x6,-0x8(%rbp)
  jmp    L114
L97:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  nop
L114:
  addq   $0x1,-0x20(%rbp)
L37:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L102
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L72
L102:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: string
name: extract_symbolic_data
arguments: label: D30
type: string
name: extract_symbolic_data
arguments: label: D39
type: string
name: extract_symbolic_data
arguments: label: D27
type: string

tool: D11: &amp;

tool: D30: &lt;

tool: D39: &gt;

tool: D27: &quot;

assistant: ```c
char *htmlspecialchars_nmov(char *out, char *in, int len) {
  char *o = out;
  while (*in && --len >= 0) {
    switch (*in) {
    case '&':
      memcpy(o, "&amp;", 5);
      o += 5;
      break;
      ;
    case '<':
      memcpy(o, "&lt;", 4);
      o += 4;
      break;
      ;
    case '>':
      memcpy(o, "&gt;", 4);
      o += 4;
      break;
      ;
    case '"':
      memcpy(o, "&quot;", 6);
      o += 6;
      break;
      ;
    default:
      *o++ = *in;
      break;
    }
    in++;
  }
  *o = 0;
  return o;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<htmlspecialchars_nmov>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L76
  mov    %rsi,%rbx
  test   %edx,%edx
  jle    L102
  lea    -0x1(%rdx),%edx
  lea    0x1(%rsi,%rdx,1),%r12
  mov    %rdi,%rbp
  lea    D13(%rip),%r15
  lea    D5(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L93
L42:
  cmp    $0x3e,%al
  jne    L70
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x4,%rbp
  jmp    L38
L74:
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x4,%rbp
L38:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L92
  cmp    %r12,%rbx
  je     L92
L93:
  cmp    $0x3c,%al
  je     L74
  jg     L42
  cmp    $0x22,%al
  je     L22
  cmp    $0x26,%al
  jne    L70
  mov    $0x5,%edx
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x5,%rbp
  jmp    L38
L22:
  mov    $0x6,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x6,%rbp
  jmp    L38
L70:
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L38
L76:
  mov    %rdi,%rbp
L92:
  movb   $0x0,0x0(%rbp)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L102:
  mov    %rdi,%rbp
  jmp    L92
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: string
name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D19
datatype: string
name: read_data
arguments: data_label: D32
datatype: string

tool: D13: &lt;

tool: D5: &gt;

tool: D19: &quot;

tool: D32: &amp;

assistant: ```c
char *htmlspecialchars_nmov(char *out, char *in, int len) {
  char *o = out;
  while (*in && --len >= 0) {
    switch (*in) {
    case '&':
      memcpy(o, "&amp;", 5);
      o += 5;
      break;
      ;
    case '<':
      memcpy(o, "&lt;", 4);
      o += 4;
      break;
      ;
    case '>':
      memcpy(o, "&gt;", 4);
      o += 4;
      break;
      ;
    case '"':
      memcpy(o, "&quot;", 6);
      o += 6;
      break;
      ;
    default:
      *o++ = *in;
      break;
    }
    in++;
  }
  *o = 0;
  return o;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<htmlspecialchars_nmov>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L145
  test   %edx,%edx
  jle    L145
  sub    $0x1,%edx
  mov    %rsi,%r15
  lea    D7(%rip),%r14
  mov    %rdi,%r12
  lea    0x1(%rsi,%rdx,1),%rbx
  lea    D2(%rip),%r13
  lea    D26(%rip),%rbp
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L87:
  cmp    $0x26,%al
  jne    L71
  mov    %r12,%rdi
  mov    $0x5,%edx
  mov    %rbp,%rsi
  add    $0x5,%r12
  call   <memcpy@plt>
L78:
  movzbl 0x1(%r15),%eax
  add    $0x1,%r15
  test   %al,%al
  je     L33
L22:
  cmp    %rbx,%r15
  je     L33
L61:
  cmp    $0x3c,%al
  je     L117
  jg     L140
  cmp    $0x22,%al
  jne    L87
  mov    %r12,%rdi
  mov    $0x6,%edx
  add    $0x1,%r15
  add    $0x6,%r12
  lea    D30(%rip),%rsi
  call   <memcpy@plt>
  movzbl (%r15),%eax
  test   %al,%al
  jne    L22
L33:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L140:
  cmp    $0x3e,%al
  jne    L71
  mov    %r12,%rdi
  mov    $0x4,%edx
  mov    %r13,%rsi
  add    $0x4,%r12
  call   <memcpy@plt>
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L117:
  mov    %r12,%rdi
  mov    $0x4,%edx
  mov    %r14,%rsi
  add    $0x4,%r12
  call   <memcpy@plt>
  jmp    L78
  nopl   0x0(%rax)
L71:
  mov    %al,(%r12)
  add    $0x1,%r12
  jmp    L78
  nopl   (%rax)
L145:
  mov    %rdi,%r12
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D26
data_type: string
name: extract_symbolic_data
arguments: data_tag: D30
data_type: string

tool: D7: &lt;

tool: D2: &gt;

tool: D26: &amp;

tool: D30: &quot;

assistant: ```c
char *htmlspecialchars_nmov(char *out, char *in, int len) {
  char *o = out;
  while (*in && --len >= 0) {
    switch (*in) {
    case '&':
      memcpy(o, "&amp;", 5);
      o += 5;
      break;
      ;
    case '<':
      memcpy(o, "&lt;", 4);
      o += 4;
      break;
      ;
    case '>':
      memcpy(o, "&gt;", 4);
      o += 4;
      break;
      ;
    case '"':
      memcpy(o, "&quot;", 6);
      o += 6;
      break;
      ;
    default:
      *o++ = *in;
      break;
    }
    in++;
  }
  *o = 0;
  return o;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<htmlspecialchars_nmov>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L93
  test   %edx,%edx
  jle    L93
  sub    $0x1,%edx
  mov    %rsi,%r15
  lea    D21(%rip),%r14
  mov    %rdi,%r12
  lea    0x1(%rsi,%rdx,1),%rbx
  lea    D27(%rip),%r13
  lea    D8(%rip),%rbp
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L120:
  cmp    $0x26,%al
  jne    L27
  mov    %r12,%rdi
  mov    $0x5,%edx
  mov    %rbp,%rsi
  add    $0x5,%r12
  call   <memcpy@plt>
L145:
  movzbl 0x1(%r15),%eax
  add    $0x1,%r15
  test   %al,%al
  je     L73
L10:
  cmp    %rbx,%r15
  je     L73
L98:
  cmp    $0x3c,%al
  je     L58
  jg     L49
  cmp    $0x22,%al
  jne    L120
  mov    %r12,%rdi
  mov    $0x6,%edx
  add    $0x1,%r15
  add    $0x6,%r12
  lea    D36(%rip),%rsi
  call   <memcpy@plt>
  movzbl (%r15),%eax
  test   %al,%al
  jne    L10
L73:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  cmp    $0x3e,%al
  jne    L27
  mov    %r12,%rdi
  mov    $0x4,%edx
  mov    %r13,%rsi
  add    $0x4,%r12
  call   <memcpy@plt>
  jmp    L145
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %r12,%rdi
  mov    $0x4,%edx
  mov    %r14,%rsi
  add    $0x4,%r12
  call   <memcpy@plt>
  jmp    L145
  nopl   0x0(%rax)
L27:
  mov    %al,(%r12)
  add    $0x1,%r12
  jmp    L145
  nopl   (%rax)
L93:
  mov    %rdi,%r12
  jmp    L73
```

tool_calls: name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D27
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string

tool: D21: &lt;

tool: D27: &gt;

tool: D8: &amp;

tool: D36: &quot;

assistant: ```c
char *htmlspecialchars_nmov(char *out, char *in, int len) {
  char *o = out;
  while (*in && --len >= 0) {
    switch (*in) {
    case '&':
      memcpy(o, "&amp;", 5);
      o += 5;
      break;
      ;
    case '<':
      memcpy(o, "&lt;", 4);
      o += 4;
      break;
      ;
    case '>':
      memcpy(o, "&gt;", 4);
      o += 4;
      break;
      ;
    case '"':
      memcpy(o, "&quot;", 6);
      o += 6;
      break;
      ;
    default:
      *o++ = *in;
      break;
    }
    in++;
  }
  *o = 0;
  return o;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BsplnWght2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x8(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movq   D57(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D38(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L38
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D18(%rip),%xmm0
  subsd  %xmm1,%xmm0
  jmp    L23
L38:
  movsd  D49(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L22
  movsd  -0x10(%rbp),%xmm0
  movsd  D49(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  jmp    L23
L22:
  pxor   %xmm0,%xmm0
L23:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D57
data_type: qword
name: read_data
arguments: tag: D38
data_type: f64
name: read_data
arguments: tag: D18
data_type: f64
name: read_data
arguments: tag: D49
data_type: f64

tool: D57: 9223372036854775807

tool: D38: 0.5

tool: D18: 0.75

tool: D49: 1.5

assistant: ```c
double BsplnWght2(long i, double x) {
  x = fabs(x - (double)i);
  if (x < 0.5)
    return (0.75 - x * x);
  if (x < 1.5) {
    x -= 1.5;
    return (0.5 * x * x);
  }
  return (0.0);
}
```