ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rod13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xd4(%rbp)
  jmp    L4
L47:
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L46
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0xd,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
  mov    -0xd4(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jle    L13
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  sub    $0xd,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
  jmp    L46
L13:
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0xd,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
L46:
  addl   $0x1,-0xd4(%rbp)
L4:
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0xd,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
  mov    -0xd4(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x59,%al
  jg     L34
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  sub    $0xd,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
  jmp    L76
L34:
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0xd,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
L76:
  mov    -0xd4(%rbp),%eax
  cltq
  movb   $0x0,-0xd0(%rbp,%rax,1)
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: text:%s


assistant: ```c
void rod13(char b[200]) {
  char arrr[200];
  int i;
  for (i = 0; b[i] != '\0'; i++) {
    if (b[i] > 90) {
      if ((arrr[i] = b[i] + 13) > 122) {
        arrr[i] = b[i] + 13 - 26;
      } else
        arrr[i] = b[i] + 13;
    }
  };
  if ((arrr[i] = b[i] + 13) < 90) {
    arrr[i] = b[i] + 13 - 26;
  } else {
    arrr[i] = b[i] + 13;
  };
  arrr[i] = '\0';
  printf("text:%s\n", arrr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rod13>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L52
  mov    $0x1,%edx
  lea    -0x1(%rsp),%r8
  jmp    L3
L36:
  mov    %edx,%ecx
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  je     L53
L3:
  cmp    $0x5a,%al
  jle    L36
  lea    0xd(%rax),%esi
  sub    $0xd,%eax
  mov    %esi,%ecx
  cmp    $0x7b,%sil
  cmovl  %ecx,%eax
  mov    %al,(%r8,%rdx,1)
  jmp    L36
L52:
  mov    $0x0,%ecx
L53:
  movslq %ecx,%rcx
  movb   $0x0,(%rsp,%rcx,1)
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0xd8,%rsp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: text:%s


assistant: ```c
void rod13(char b[200]) {
  char arrr[200];
  int i;
  for (i = 0; b[i] != '\0'; i++) {
    if (b[i] > 90) {
      if ((arrr[i] = b[i] + 13) > 122) {
        arrr[i] = b[i] + 13 - 26;
      } else
        arrr[i] = b[i] + 13;
    }
  };
  if ((arrr[i] = b[i] + 13) < 90) {
    arrr[i] = b[i] + 13 - 26;
  } else {
    arrr[i] = b[i] + 13;
  };
  arrr[i] = '\0';
  printf("text:%s\n", arrr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rod13>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  mov    $0x1,%edx
  lea    -0x1(%rsp),%r8
  nop
L27:
  cmp    $0x5a,%al
  jle    L1
  lea    0xd(%rax),%esi
  sub    $0xd,%eax
  mov    %esi,%ecx
  cmp    $0x7b,%sil
  cmovl  %ecx,%eax
  mov    %al,(%r8,%rdx,1)
L1:
  movslq %edx,%rcx
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L27
L2:
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xd8,%rsp
  ret
  nopl   (%rax)
L18:
  xor    %ecx,%ecx
  jmp    L2
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: text:%s


assistant: ```c
void rod13(char b[200]) {
  char arrr[200];
  int i;
  for (i = 0; b[i] != '\0'; i++) {
    if (b[i] > 90) {
      if ((arrr[i] = b[i] + 13) > 122) {
        arrr[i] = b[i] + 13 - 26;
      } else
        arrr[i] = b[i] + 13;
    }
  };
  if ((arrr[i] = b[i] + 13) < 90) {
    arrr[i] = b[i] + 13 - 26;
  } else {
    arrr[i] = b[i] + 13;
  };
  arrr[i] = '\0';
  printf("text:%s\n", arrr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rod13>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  mov    $0x1,%edx
  lea    -0x1(%rsp),%r8
  nop
L49:
  cmp    $0x5a,%al
  jle    L7
  lea    0xd(%rax),%esi
  sub    $0xd,%eax
  mov    %esi,%ecx
  cmp    $0x7b,%sil
  cmovl  %ecx,%eax
  mov    %al,(%r8,%rdx,1)
L7:
  movslq %edx,%rcx
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L49
L31:
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0xd8,%rsp
  ret
  nopl   (%rax)
L4:
  xor    %ecx,%ecx
  jmp    L31
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: text:%s


assistant: ```c
void rod13(char b[200]) {
  char arrr[200];
  int i;
  for (i = 0; b[i] != '\0'; i++) {
    if (b[i] > 90) {
      if ((arrr[i] = b[i] + 13) > 122) {
        arrr[i] = b[i] + 13 - 26;
      } else
        arrr[i] = b[i] + 13;
    }
  };
  if ((arrr[i] = b[i] + 13) < 90) {
    arrr[i] = b[i] + 13 - 26;
  } else {
    arrr[i] = b[i] + 13;
  };
  arrr[i] = '\0';
  printf("text:%s\n", arrr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<saludar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D15: Bienvenido al programa


tool: D7:  de ejemplo


assistant: ```c
void saludar() {
  printf("Bienvenido al programa\n");
  printf(" de ejemplo\n");
  printf("Bienvenido al programa\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<saludar>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D0: Bienvenido al programa


tool: D15:  de ejemplo


assistant: ```c
void saludar() {
  printf("Bienvenido al programa\n");
  printf(" de ejemplo\n");
  printf("Bienvenido al programa\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<saludar>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D18
datatype: string

tool: D8: Bienvenido al programa


tool: D18:  de ejemplo


assistant: ```c
void saludar() {
  printf("Bienvenido al programa\n");
  printf(" de ejemplo\n");
  printf("Bienvenido al programa\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<saludar>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D14: Bienvenido al programa


tool: D11:  de ejemplo


assistant: ```c
void saludar() {
  printf("Bienvenido al programa\n");
  printf(" de ejemplo\n");
  printf("Bienvenido al programa\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  xor    -0x24(%rbp),%al
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void Enc(char *plain, char *cipher, char key) {
  int p_len = strlen(plain);
  for (int i = 0; i < p_len; i += 1) {
    cipher[i] = plain[i] ^ key;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Enc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  mov    %eax,%eax
  mov    $0x0,%edx
L7:
  mov    %r12d,%ecx
  xor    (%rbx,%rdx,1),%cl
  mov    %cl,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L7
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Enc(char *plain, char *cipher, char key) {
  int p_len = strlen(plain);
  for (int i = 0; i < p_len; i += 1) {
    cipher[i] = plain[i] ^ key;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Enc>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  cltq
  xor    %ecx,%ecx
  xchg   %ax,%ax
L17:
  movzbl (%rbx,%rcx,1),%r8d
  xor    %r12d,%r8d
  mov    %r8b,0x0(%rbp,%rcx,1)
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L17
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Enc(char *plain, char *cipher, char key) {
  int p_len = strlen(plain);
  for (int i = 0; i < p_len; i += 1) {
    cipher[i] = plain[i] ^ key;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Enc>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %edx,%edx
  jle    L129
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rcx
  lea    -0x1(%rdx),%eax
  mov    %edx,%r8d
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L59
  cmp    $0x6,%eax
  jbe    L59
  cmp    $0xe,%eax
  jbe    L65
  movd   %r12d,%xmm1
  mov    %edx,%ecx
  xor    %eax,%eax
  punpcklbw %xmm1,%xmm1
  shr    $0x4,%ecx
  punpcklwd %xmm1,%xmm1
  shl    $0x4,%rcx
  pshufd $0x0,%xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L29:
  movdqu (%rbx,%rax,1),%xmm0
  pxor   %xmm1,%xmm0
  movups %xmm0,0x0(%rbp,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L29
  mov    %edx,%ecx
  and    $0xfffffff0,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%edx
  je     L129
  mov    %edx,%r8d
  sub    %ecx,%r8d
  lea    -0x1(%r8),%esi
  cmp    $0x6,%esi
  jbe    L85
L38:
  mov    %r12d,%esi
  movzbl %r12b,%edi
  movq   (%rbx,%rcx,1),%xmm1
  shl    $0x8,%esi
  or     %edi,%esi
  movd   %esi,%xmm2
  pshuflw $0x0,%xmm2,%xmm0
  pxor   %xmm1,%xmm0
  movq   %xmm0,0x0(%rbp,%rcx,1)
  mov    %r8d,%ecx
  and    $0xfffffff8,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r8d
  je     L129
L85:
  movslq %eax,%rcx
  movzbl (%rbx,%rcx,1),%esi
  xor    %r12d,%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L129
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  xor    %r12d,%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jle    L129
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  xor    %r12d,%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jle    L129
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  xor    %r12d,%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L129
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  xor    %r12d,%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jle    L129
  movslq %ecx,%rcx
  add    $0x6,%eax
  movzbl (%rbx,%rcx,1),%esi
  xor    %r12d,%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  cmp    %eax,%edx
  jle    L129
  cltq
  xor    (%rbx,%rax,1),%r12b
  mov    %r12b,0x0(%rbp,%rax,1)
L129:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L59:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L141:
  movzbl (%rbx,%rax,1),%ecx
  xor    %r13d,%ecx
  mov    %cl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L141
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L65:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L38
```

assistant: ```c
void Enc(char *plain, char *cipher, char key) {
  int p_len = strlen(plain);
  for (int i = 0; i < p_len; i += 1) {
    cipher[i] = plain[i] ^ key;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FindTempIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  leave
  ret
```

assistant: ```c
int FindTempIndex(char *name) {
  char *p = &name[1];
  return atoi(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FindTempIndex>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int FindTempIndex(char *name) {
  char *p = &name[1];
  return atoi(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FindTempIndex>:
  endbr64
  add    $0x1,%rdi
  jmp    1050 <atoi@plt>
```

assistant: ```c
int FindTempIndex(char *name) {
  char *p = &name[1];
  return atoi(p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FindTempIndex>:
  endbr64
  add    $0x1,%rdi
  jmp    1050 <atoi@plt>
```

assistant: ```c
int FindTempIndex(char *name) {
  char *p = &name[1];
  return atoi(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <shlib_function@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int ret = shlib_function();
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <shlib_function@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int ret = shlib_function();
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <shlib_function@plt>
```

assistant: ```c
int main(void) {
  int ret = shlib_function();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <shlib_function@plt>
```

assistant: ```c
int main(void) {
  int ret = shlib_function();
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L14
  mov    $0x1,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L14:
  movl   $0x0,-0x28(%rbp)
  jmp    L46
L36:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L46:
  cmpl   $0x0,-0x28(%rbp)
  jle    L36
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  movabs $0x26cf0000569b5dbd,%rdx
  cmp    %rdx,%rax
  jne    L52
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L52:
  movl   $0x0,-0x24(%rbp)
  jmp    L5
L44:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L5:
  cmpl   $0x0,-0x24(%rbp)
  jle    L44
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D10
datatype: string

tool: D5: Call this program with %i arguments


tool: D19: You win!

tool: D10: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2796453895073390013UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L3
L27:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  movabs $0x26cf0000569b5dbd,%rax
  cmp    %rax,0x10(%rsp)
  je     L2
L40:
  mov    0x10(%rsp),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L27
L2:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L40
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D12: %lu


tool: D4: Call this program with %i arguments


tool: D16: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2796453895073390013UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L10
  lea    D27(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L10:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x26cf0000569b5dbd,%rax
  cmp    %rax,%rsi
  je     L22
L16:
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L16
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D12
data_type: string
name: read_data
arguments: label: D26
data_type: string

tool: D27: Call this program with %i arguments


tool: D12: %lu


tool: D26: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2796453895073390013UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```