ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mmap_bad>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D85(%rip),%r15
  mov    D83(%rip),%r14
  mov    (%r15),%ecx
  or     (%r14),%ecx
  mov    D78(%rip),%r13
  mov    D19(%rip),%r12
  mov    0x0(%r13),%edx
  or     (%r12),%edx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x20000,%esi
  mov    $0x7fff0000,%edi
  call   <mmap@plt>
  mov    D44(%rip),%rbp
  cmp    %rax,0x0(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D49(%rip),%rbx
  mov    D43(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%r15),%ecx
  or     (%r14),%ecx
  mov    0x0(%r13),%edx
  or     (%r12),%edx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x1000,%esi
  mov    $0x3ff000,%edi
  call   <mmap@plt>
  cmp    %rax,0x0(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D43(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%r15),%ecx
  or     (%r14),%ecx
  mov    0x0(%r13),%edx
  or     (%r12),%edx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x1000,%esi
  mov    $0x12345678,%edi
  call   <mmap@plt>
  cmp    %rax,0x0(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D43(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmap_bad(void) {
  void *addr;
  addr = mmap(((void *)0x7fff0000), (0x20000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
  addr = mmap(((void *)0x3ff000), (0x1000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
  addr = mmap(((void *)0x12345678), (0x1000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mmap_bad>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x20000,%esi
  push   %r14
  mov    $0x7fff0000,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbx
  mov    D45(%rip),%r14
  mov    D21(%rip),%r15
  mov    D29(%rip),%r13
  mov    (%rbx),%ecx
  or     (%r14),%ecx
  mov    (%r15),%edx
  or     0x0(%r13),%edx
  call   <mmap@plt>
  mov    D82(%rip),%r12
  xor    %edi,%edi
  cmp    %rax,(%r12)
  sete   %dil
  call   <assert@plt>
  mov    D5(%rip),%rbp
  mov    D26(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    (%rbx),%ecx
  mov    $0x1000,%esi
  or     (%r14),%ecx
  mov    (%r15),%edx
  mov    $0x3ff000,%edi
  or     0x0(%r13),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,(%r12)
  sete   %dil
  call   <assert@plt>
  mov    D26(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%ecx
  mov    (%r15),%edx
  xor    %r9d,%r9d
  or     (%r14),%ecx
  or     0x0(%r13),%edx
  mov    $0xffffffff,%r8d
  mov    $0x1000,%esi
  mov    $0x12345678,%edi
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,(%r12)
  sete   %dil
  call   <assert@plt>
  mov    D26(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <assert@plt>
```

assistant: ```c
void mmap_bad(void) {
  void *addr;
  addr = mmap(((void *)0x7fff0000), (0x20000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
  addr = mmap(((void *)0x3ff000), (0x1000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
  addr = mmap(((void *)0x12345678), (0x1000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mmap_bad>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x20000,%esi
  push   %r14
  mov    $0x7fff0000,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D22(%rip),%rbx
  mov    D89(%rip),%r14
  mov    D26(%rip),%r15
  mov    D65(%rip),%r13
  mov    (%rbx),%ecx
  or     (%r14),%ecx
  mov    (%r15),%edx
  or     0x0(%r13),%edx
  call   <mmap@plt>
  mov    D55(%rip),%r12
  xor    %edi,%edi
  cmp    %rax,(%r12)
  sete   %dil
  call   <assert@plt>
  mov    D63(%rip),%rbp
  mov    D67(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    (%rbx),%ecx
  mov    $0x1000,%esi
  or     (%r14),%ecx
  mov    (%r15),%edx
  mov    $0x3ff000,%edi
  or     0x0(%r13),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,(%r12)
  sete   %dil
  call   <assert@plt>
  mov    D67(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%ecx
  mov    (%r15),%edx
  xor    %r9d,%r9d
  or     (%r14),%ecx
  or     0x0(%r13),%edx
  mov    $0xffffffff,%r8d
  mov    $0x1000,%esi
  mov    $0x12345678,%edi
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,(%r12)
  sete   %dil
  call   <assert@plt>
  mov    D67(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <assert@plt>
```

assistant: ```c
void mmap_bad(void) {
  void *addr;
  addr = mmap(((void *)0x7fff0000), (0x20000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
  addr = mmap(((void *)0x3ff000), (0x1000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
  addr = mmap(((void *)0x12345678), (0x1000), PROT_READ | PROT_WRITE, MAP_ANON | MAP_PRIVATE, -1, 0);
  assert(addr == MAP_FAILED);
  assert(errno == EINVAL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_walls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L74
L57:
  mov    -0x4(%rbp),%eax
  mov    $0x23,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L74:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L57
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L73:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x23,%edx
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L73
  movl   $0x0,-0x4(%rbp)
  jmp    L76
L38:
  mov    -0x4(%rbp),%eax
  mov    $0x23,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L76:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L38
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L58:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x23,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L58
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_walls(int screen_x, int screen_y) {
  int i;
  for (i = 0; i < screen_x; i++)
    mvaddch(0, i, '#');
  for (i = 0; i < screen_x; i++)
    mvaddch(screen_y - 1, i, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, 0, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, screen_x - 1, '#');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_walls>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r13d
  test   %edi,%edi
  jle    L19
  mov    $0x0,%ebx
L1:
  mov    $0x23,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <mvaddch@plt>
  mov    %ebx,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L1
  mov    $0x0,%ebx
  lea    -0x1(%r13),%r14d
L20:
  mov    $0x23,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <mvaddch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jne    L20
L19:
  test   %r13d,%r13d
  jle    L32
  mov    $0x0,%ebx
L27:
  mov    $0x23,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <mvaddch@plt>
  mov    %ebx,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L27
  mov    $0x0,%ebx
  sub    $0x1,%ebp
L8:
  mov    $0x23,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mvaddch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jne    L8
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_walls(int screen_x, int screen_y) {
  int i;
  for (i = 0; i < screen_x; i++)
    mvaddch(0, i, '#');
  for (i = 0; i < screen_x; i++)
    mvaddch(screen_y - 1, i, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, 0, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, screen_x - 1, '#');
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_walls>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  test   %edi,%edi
  jle    L26
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%esi
  mov    $0x23,%edx
  xor    %edi,%edi
  mov    %ebx,%ebp
  call   <mvaddch@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r12d
  jne    L11
  lea    -0x1(%r13),%r14d
  xor    %ebx,%ebx
  xchg   %ax,%ax
L42:
  mov    %ebx,%esi
  mov    $0x23,%edx
  mov    %r14d,%edi
  call   <mvaddch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L42
L26:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L57
  nop
L35:
  mov    %ebx,%edi
  mov    $0x23,%edx
  xor    %esi,%esi
  mov    %ebx,%ebp
  call   <mvaddch@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r13d
  jne    L35
  sub    $0x1,%r12d
  xor    %ebx,%ebx
  xchg   %ax,%ax
L6:
  mov    %ebx,%edi
  mov    $0x23,%edx
  mov    %r12d,%esi
  call   <mvaddch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L6
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_walls(int screen_x, int screen_y) {
  int i;
  for (i = 0; i < screen_x; i++)
    mvaddch(0, i, '#');
  for (i = 0; i < screen_x; i++)
    mvaddch(screen_y - 1, i, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, 0, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, screen_x - 1, '#');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_walls>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  test   %edi,%edi
  jle    L46
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %ebx,%esi
  mov    $0x23,%edx
  xor    %edi,%edi
  mov    %ebx,%ebp
  call   <mvaddch@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r12d
  jne    L34
  lea    -0x1(%r13),%r14d
  xor    %ebx,%ebx
  xchg   %ax,%ax
L27:
  mov    %ebx,%esi
  mov    $0x23,%edx
  mov    %r14d,%edi
  call   <mvaddch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L27
L46:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L33
  nop
L53:
  mov    %ebx,%edi
  mov    $0x23,%edx
  xor    %esi,%esi
  mov    %ebx,%ebp
  call   <mvaddch@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r13d
  jne    L53
  sub    $0x1,%r12d
  xor    %ebx,%ebx
  xchg   %ax,%ax
L24:
  mov    %ebx,%edi
  mov    $0x23,%edx
  mov    %r12d,%esi
  call   <mvaddch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L24
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_walls(int screen_x, int screen_y) {
  int i;
  for (i = 0; i < screen_x; i++)
    mvaddch(0, i, '#');
  for (i = 0; i < screen_x; i++)
    mvaddch(screen_y - 1, i, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, 0, '#');
  for (i = 0; i < screen_y; i++)
    mvaddch(i, screen_x - 1, '#');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strToResponse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: %s

assistant: ```c
void strToResponse(char *str, char *msg) {
  bzero(msg, 255);
  sprintf(msg, "%s", str);
}
```
user: What is the c source code of the assembly code below?

```asm
<strToResponse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0xff,%esi
  mov    %rbx,%rdi
  call   <bzero@plt>
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: %s

assistant: ```c
void strToResponse(char *str, char *msg) {
  bzero(msg, 255);
  sprintf(msg, "%s", str);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strToResponse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0xff,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <bzero@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  pop    %rbp
  pop    %r12
  jmp    1070 <sprintf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %s

assistant: ```c
void strToResponse(char *str, char *msg) {
  bzero(msg, 255);
  sprintf(msg, "%s", str);
}
```
user: What is the c source code of the assembly code below:

```asm
<strToResponse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0xff,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <bzero@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  pop    %rbp
  pop    %r12
  jmp    1070 <sprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: %s

assistant: ```c
void strToResponse(char *str, char *msg) {
  bzero(msg, 255);
  sprintf(msg, "%s", str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  lea    D37(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string
name: parse_data
arguments: data_tag: D31
type_infered: string
name: parse_data
arguments: data_tag: D37
type_infered: string

tool: D2: 98993489

tool: D31: String value = %s, Float value = %f


tool: D37: Linkerist.com

assistant: ```c
int main() {
  float val;
  char str[20];
  strcpy(str, "98993489");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  strcpy(str, "Linkerist.com");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: string

tool: D14: 98993489

tool: D9: String value = %s, Float value = %f


tool: D11: Linkerist.com

assistant: ```c
int main() {
  float val;
  char str[20];
  strcpy(str, "98993489");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  strcpy(str, "Linkerist.com");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%rsi
  lea    D22(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string

tool: D29: 98993489

tool: D22: String value = %s, Float value = %f


tool: D4: Linkerist.com

assistant: ```c
int main() {
  float val;
  char str[20];
  strcpy(str, "98993489");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  strcpy(str, "Linkerist.com");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  lea    D25(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D25
type_infered: string
name: unpack_data
arguments: tag: D22
type_infered: string

tool: D2: 98993489

tool: D25: String value = %s, Float value = %f


tool: D22: Linkerist.com

assistant: ```c
int main() {
  float val;
  char str[20];
  strcpy(str, "98993489");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  strcpy(str, "Linkerist.com");
  val = atof(str);
  printf("String value = %s, Float value = %f\n", str, val);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getWinner>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x5,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x2,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  je     L59
  cmpl   $0x4,-0x4(%rbp)
  jg     L53
  cmpl   $0x3,-0x4(%rbp)
  je     L42
  cmpl   $0x3,-0x4(%rbp)
  jg     L53
  cmpl   $0x1,-0x4(%rbp)
  je     L42
  cmpl   $0x2,-0x4(%rbp)
  je     L59
  jmp    L53
L42:
  mov    $0x1,%eax
  jmp    L6
L59:
  mov    $0x2,%eax
  jmp    L6
L53:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int getWinner(int playerChoice, int AIChoice) {
  int difference = (5 + playerChoice - AIChoice);
  int remainder = difference % 5;
  switch (remainder) {
  case 1:
  case 3:
    return 1;
  case 2:
  case 4:
    return 2;
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getWinner>:
  endbr64
  add    $0x5,%edi
  sub    %esi,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  cmp    $0x3,%eax
  je     L27
  cmp    $0x3,%eax
  jg     L3
  cmp    $0x1,%eax
  je     L16
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
L27:
  mov    $0x1,%eax
  ret
L3:
  mov    $0x2,%eax
L16:
  ret
```

assistant: ```c
int getWinner(int playerChoice, int AIChoice) {
  int difference = (5 + playerChoice - AIChoice);
  int remainder = difference % 5;
  switch (remainder) {
  case 1:
  case 3:
    return 1;
  case 2:
  case 4:
    return 2;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getWinner>:
  endbr64
  add    $0x5,%edi
  sub    %esi,%edi
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  cmp    $0x3,%eax
  je     L29
  cmp    $0x4,%eax
  je     L8
  cmp    $0x1,%eax
  je     L0
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
L8:
  mov    $0x2,%eax
L0:
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int getWinner(int playerChoice, int AIChoice) {
  int difference = (5 + playerChoice - AIChoice);
  int remainder = difference % 5;
  switch (remainder) {
  case 1:
  case 3:
    return 1;
  case 2:
  case 4:
    return 2;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<getWinner>:
  endbr64
  add    $0x5,%edi
  sub    %esi,%edi
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  cmp    $0x3,%eax
  je     L0
  cmp    $0x4,%eax
  je     L1
  cmp    $0x1,%eax
  je     L3
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
L1:
  mov    $0x2,%eax
L3:
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int getWinner(int playerChoice, int AIChoice) {
  int difference = (5 + playerChoice - AIChoice);
  int remainder = difference % 5;
  switch (remainder) {
  case 1:
  case 3:
    return 1;
  case 2:
  case 4:
    return 2;
  default:
    return 0;
  }
}
```