user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D73(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rsi
  and    $0xfffffffffffffff0,%rdx
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L48
L127:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L127
L48:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L165
L153:
  mov    %rax,%rsi
  mov    %rax,%rdx
  mov    %rsp,%rcx
  mov    %rsp,%r13
  and    $0xfffffffffffff000,%rsi
  and    $0xfffffffffffffff0,%rdx
  sub    %rsi,%rcx
L66:
  cmp    %rcx,%rsp
  je     L19
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L66
L165:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L153
L19:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L31
L69:
  mov    %rax,%rdx
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rbx
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rcx
L157:
  cmp    %rcx,%rsp
  je     L151
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L157
L31:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L69
L151:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L94
  orq    $0x0,-0x8(%rsp,%rax,1)
L94:
  lea    D69(%rip),%rdi
  mov    %rsp,-0x48(%rbp)
  call   <puts@plt>
  cmpl   $0x0,-0x40(%rbp)
  jle    L161
  mov    %r13,%r15
  mov    %rbx,%r12
  xor    %r14d,%r14d
  xchg   %ax,%ax
L45:
  mov    %r12,%rdx
  mov    %r15,%rsi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%r14d
  add    $0x4,%r15
  add    $0x4,%r12
  cmp    %r14d,-0x40(%rbp)
  jg     L45
L161:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    -0x3c(%rbp),%rsi
  lea    D72(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%r8d
  test   %r8d,%r8d
  jle    L189
  movss  -0x3c(%rbp),%xmm0
  mov    -0x48(%rbp),%rdx
  mov    %r13,%rdi
  xor    %ecx,%ecx
  movss  D48(%rip),%xmm4
  movslq %r8d,%rsi
  nopw   0x0(%rax,%rax,1)
L122:
  movss  %xmm4,(%rdx)
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L46:
  cmp    %eax,%ecx
  je     L39
  movss  0x0(%r13,%rax,4),%xmm3
  movss  (%rdi),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm3,%xmm1
  subss  %xmm3,%xmm2
  divss  %xmm2,%xmm1
  mulss  (%rdx),%xmm1
  movss  %xmm1,(%rdx)
L39:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L46
  add    $0x1,%ecx
  add    $0x4,%rdx
  add    $0x4,%rdi
  cmp    %r8d,%ecx
  jne    L122
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L159:
  mov    -0x48(%rbp),%rdi
  movss  (%rbx,%rax,4),%xmm2
  mulss  (%rdi,%rax,4),%xmm2
  add    $0x1,%rax
  addss  %xmm2,%xmm1
  cmp    %rax,%rsi
  jne    L159
L135:
  lea    D68(%rip),%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L131
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L189:
  movss  -0x3c(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  jmp    L135
L131:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D73
data_type: string
name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D69
data_type: string
name: unpack_data
arguments: label: D49
data_type: string
name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D72
data_type: string
name: unpack_data
arguments: label: D48
data_type: byte[4]
name: unpack_data
arguments: label: D68
data_type: string

tool: D73: Enter the number of given values in the table:	

tool: D11: %d

tool: D69: Enter the x_i and f(x_i) values, one at a time.

tool: D49: %f %f

tool: D19: Enter the value of x for which value has to be interpolated.

tool: D72: %f

tool: {"D48": [0x00,0x00,0x80,0x3f]}

tool: D68: f(%f) = %f


assistant: ```c
int main(void) {
  int i, j, n;
  printf("Enter the number of given values in the table:\t");
  scanf("%d", &n);
  float x[n], y[n], l[n], z, fz, c;
  printf("Enter the x_i and f(x_i) values, one at a time.\n");
  for (i = 0; i < n; i++)
    scanf("%f %f", &x[i], &y[i]);
  printf("Enter the value of x for which value has to be interpolated.\n");
  scanf("%f", &z);
  for (i = 0; i < n; i++) {
    l[i] = 1;
    for (j = 0; j < n; j++) {
      if (i != j)
        l[i] *= (z - x[j]) / (x[i] - x[j]);
    }
  }
  fz = 0;
  for (i = 0; i < n; i++)
    fz += y[i] * l[i];
  printf("f(%f) = %f\n", z, fz);
  return 0;
}
```