ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dialog_quit_confirm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <output_dialog_quit_on@plt>
  mov    D9(%rip),%r13
  lea    0x17(%rsp),%r12
  movabs $0x80800000808,%r14
  movabs $0x100000001,%r15
  jmp    L29
L76:
  mov    $0x0,%eax
  call   <pause@plt>
L29:
  mov    0x0(%r13),%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jne    L76
  movzbl 0x17(%rsp),%ecx
  cmp    $0x1b,%cl
  je     L46
  sub    $0x4e,%ecx
  cmp    $0x2b,%cl
  ja     L29
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %r14,%rax
  jne    L61
  test   %r15,%rax
  je     L29
  mov    $0x0,%ebx
  jmp    L61
L46:
  mov    $0x0,%ebx
L61:
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <output_dialog_quit_off@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dialog_quit_confirm(struct state *st, struct ui *ui) {
  output_dialog_quit_on(st, ui);
  int done = 0;
  int finished = 0;
  char buf[1];
  while (!done) {
    if (fread(buf, 1, 1, stdin) == 1) {
      char c = buf[0];
      switch (c) {
      case 'y':
      case 'Y':
      case 'q':
      case 'Q':
        finished = 1;
        done = 1;
        break;
      case 'n':
      case 'N':
      case '\033':
        finished = 0;
        done = 1;
        break;
      default:
        break;
      }
    } else
      pause();
  }
  output_dialog_quit_off(st, ui);
  return finished;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dialog_quit_confirm>:
  endbr64
  push   %r15
  movabs $0x100000001,%r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  movabs $0x80800000808,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%rbx
  call   <output_dialog_quit_on@plt>
L6:
  mov    D2(%rip),%rax
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    (%rax),%ecx
  call   <fread@plt>
  mov    %eax,%r8d
  cmp    $0x1,%eax
  jne    L31
  movzbl 0x17(%rsp),%ecx
  cmp    $0x1b,%cl
  je     L32
  sub    $0x4e,%ecx
  cmp    $0x2b,%cl
  ja     L6
  mov    %r14,%rax
  shl    %cl,%rax
  test   %r13,%rax
  jne    L2
  test   %r15,%rax
  je     L6
L32:
  xor    %r8d,%r8d
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %r8d,0xc(%rsp)
  call   <output_dialog_quit_off@plt>
  mov    0xc(%rsp),%r8d
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %eax,%eax
  call   <pause@plt>
  jmp    L6
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dialog_quit_confirm(struct state *st, struct ui *ui) {
  output_dialog_quit_on(st, ui);
  int done = 0;
  int finished = 0;
  char buf[1];
  while (!done) {
    if (fread(buf, 1, 1, stdin) == 1) {
      char c = buf[0];
      switch (c) {
      case 'y':
      case 'Y':
      case 'q':
      case 'Q':
        finished = 1;
        done = 1;
        break;
      case 'n':
      case 'N':
      case '\033':
        finished = 0;
        done = 1;
        break;
      default:
        break;
      }
    } else
      pause();
  }
  output_dialog_quit_off(st, ui);
  return finished;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dialog_quit_confirm>:
  endbr64
  push   %r15
  movabs $0x100000001,%r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  movabs $0x80800000808,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%rbx
  call   <output_dialog_quit_on@plt>
L55:
  mov    D6(%rip),%rax
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    (%rax),%ecx
  call   <fread@plt>
  mov    %eax,%r8d
  cmp    $0x1,%eax
  jne    L15
  movzbl 0x17(%rsp),%ecx
  cmp    $0x1b,%cl
  je     L36
  sub    $0x4e,%ecx
  cmp    $0x2b,%cl
  ja     L55
  mov    %r14,%rax
  shl    %cl,%rax
  test   %r13,%rax
  jne    L59
  test   %r15,%rax
  je     L55
L36:
  xor    %r8d,%r8d
L59:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %r8d,0xc(%rsp)
  call   <output_dialog_quit_off@plt>
  mov    0xc(%rsp),%r8d
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x28,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  call   <pause@plt>
  jmp    L55
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dialog_quit_confirm(struct state *st, struct ui *ui) {
  output_dialog_quit_on(st, ui);
  int done = 0;
  int finished = 0;
  char buf[1];
  while (!done) {
    if (fread(buf, 1, 1, stdin) == 1) {
      char c = buf[0];
      switch (c) {
      case 'y':
      case 'Y':
      case 'q':
      case 'Q':
        finished = 1;
        done = 1;
        break;
      case 'n':
      case 'N':
      case '\033':
        finished = 0;
        done = 1;
        break;
      default:
        break;
      }
    } else
      pause();
  }
  output_dialog_quit_off(st, ui);
  return finished;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nextToken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L55
L51:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L99
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%eax
  jmp    L49
L99:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  cmpb   $0x20,-0x9(%rbp)
  jne    L21
  cmpl   $0x0,-0x8(%rbp)
  jne    L93
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x2c(%rbp)
  jmp    L15
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L93
  movl   $0x1,-0x8(%rbp)
L93:
  addl   $0x1,-0x2c(%rbp)
L55:
  mov    -0x2c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L51
L15:
  cmpl   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0xffffffff,%eax
  jmp    L49
L17:
  mov    -0x2c(%rbp),%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int nextToken(char *token, int tokenLen, char *line, int lineLen, int index) {
  int tokenIsDone = 0;
  int i = 0;
  while (index < lineLen) {
    char c = line[index];
    if (c == '\0') {
      token[i] = '\0';
      return lineLen;
    }
    token[i] = c;
    if (c == ' ') {
      if (!tokenIsDone) {
        token[i] = '\0';
        tokenIsDone = 1;
        index++;
        break;
      }
    } else {
      token[i] = c;
      i++;
      if (i == tokenLen)
        tokenIsDone = 1;
    }
    index++;
  }
  if (!tokenIsDone)
    return -1;
  return index;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nextToken>:
  endbr64
  cmp    %ecx,%r8d
  jge    L17
  push   %rbx
  mov    %rdi,%r9
  mov    %esi,%r11d
  mov    %ecx,%eax
  movslq %r8d,%rcx
  add    %rcx,%rdx
  mov    $0x0,%edi
  mov    $0x0,%r10d
  mov    $0x1,%ebx
  jmp    L32
L46:
  movslq %edi,%rdi
  movb   $0x0,(%r9,%rdi,1)
  jmp    L72
L33:
  test   %r10d,%r10d
  je     L28
L85:
  add    $0x1,%r8d
  add    $0x1,%rdx
  cmp    %r8d,%eax
  je     L80
L32:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L46
  movslq %edi,%rsi
  add    %r9,%rsi
  mov    %cl,(%rsi)
  cmp    $0x20,%cl
  je     L33
  add    $0x1,%edi
  cmp    %r11d,%edi
  cmove  %ebx,%r10d
  jmp    L85
L28:
  movb   $0x0,(%rsi)
  lea    0x1(%r8),%eax
  jmp    L72
L80:
  test   %r10d,%r10d
  mov    $0xffffffff,%eax
  cmovne %r8d,%eax
L72:
  pop    %rbx
  ret
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int nextToken(char *token, int tokenLen, char *line, int lineLen, int index) {
  int tokenIsDone = 0;
  int i = 0;
  while (index < lineLen) {
    char c = line[index];
    if (c == '\0') {
      token[i] = '\0';
      return lineLen;
    }
    token[i] = c;
    if (c == ' ') {
      if (!tokenIsDone) {
        token[i] = '\0';
        tokenIsDone = 1;
        index++;
        break;
      }
    } else {
      token[i] = c;
      i++;
      if (i == tokenLen)
        tokenIsDone = 1;
    }
    index++;
  }
  if (!tokenIsDone)
    return -1;
  return index;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextToken>:
  endbr64
  cmp    %ecx,%r8d
  jge    L46
  movslq %r8d,%rax
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebx
  add    %rax,%rdx
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  mov    $0x1,%eax
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r9d
  cmp    %ebx,%r9d
  cmove  %eax,%r10d
L39:
  add    $0x1,%r8d
  add    $0x1,%rdx
  cmp    %r8d,%ecx
  je     L38
L33:
  movzbl (%rdx),%edi
  movslq %r9d,%rsi
  add    %r11,%rsi
  test   %dil,%dil
  je     L26
  mov    %dil,(%rsi)
  cmp    $0x20,%dil
  jne    L13
  test   %r10d,%r10d
  jne    L39
  movb   $0x0,(%rsi)
  lea    0x1(%r8),%eax
  pop    %rbx
  ret
  nopl   (%rax)
L26:
  movb   $0x0,(%rsi)
  mov    %ecx,%eax
  pop    %rbx
  ret
  nop
L38:
  test   %r10d,%r10d
  je     L69
  mov    %ecx,%eax
  pop    %rbx
  ret
L69:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L46:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int nextToken(char *token, int tokenLen, char *line, int lineLen, int index) {
  int tokenIsDone = 0;
  int i = 0;
  while (index < lineLen) {
    char c = line[index];
    if (c == '\0') {
      token[i] = '\0';
      return lineLen;
    }
    token[i] = c;
    if (c == ' ') {
      if (!tokenIsDone) {
        token[i] = '\0';
        tokenIsDone = 1;
        index++;
        break;
      }
    } else {
      token[i] = c;
      i++;
      if (i == tokenLen)
        tokenIsDone = 1;
    }
    index++;
  }
  if (!tokenIsDone)
    return -1;
  return index;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nextToken>:
  endbr64
  cmp    %ecx,%r8d
  jge    L39
  movslq %r8d,%rax
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebx
  add    %rax,%rdx
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  mov    $0x1,%eax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L55:
  add    $0x1,%r9d
  cmp    %ebx,%r9d
  cmove  %eax,%r10d
L34:
  add    $0x1,%r8d
  add    $0x1,%rdx
  cmp    %r8d,%ecx
  je     L66
L21:
  movzbl (%rdx),%edi
  movslq %r9d,%rsi
  add    %r11,%rsi
  test   %dil,%dil
  je     L27
  mov    %dil,(%rsi)
  cmp    $0x20,%dil
  jne    L55
  test   %r10d,%r10d
  jne    L34
  movb   $0x0,(%rsi)
  lea    0x1(%r8),%eax
  pop    %rbx
  ret
  nopl   (%rax)
L27:
  movb   $0x0,(%rsi)
  mov    %ecx,%eax
  pop    %rbx
  ret
  nop
L66:
  test   %r10d,%r10d
  je     L2
  mov    %ecx,%eax
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L39:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int nextToken(char *token, int tokenLen, char *line, int lineLen, int index) {
  int tokenIsDone = 0;
  int i = 0;
  while (index < lineLen) {
    char c = line[index];
    if (c == '\0') {
      token[i] = '\0';
      return lineLen;
    }
    token[i] = c;
    if (c == ' ') {
      if (!tokenIsDone) {
        token[i] = '\0';
        tokenIsDone = 1;
        index++;
        break;
      }
    } else {
      token[i] = c;
      i++;
      if (i == tokenLen)
        tokenIsDone = 1;
    }
    index++;
  }
  if (!tokenIsDone)
    return -1;
  return index;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<OLE_parse_uni_software_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x8,%eax
  cmp    %eax,-0x20(%rbp)
  jae    L31
  mov    -0x20(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  lea    0x4(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get32u@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x1c(%rbp),%eax
  shr    %eax
  cmp    %eax,-0x8(%rbp)
  ja     L53
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  ja     L49
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <software_uni2ext@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L69
L31:
  nop
  jmp    L69
L53:
  nop
  jmp    L69
L49:
  nop
L69:
  leave
  ret
```

assistant: ```c
void OLE_parse_uni_software_entry(const char *buffer, const unsigned int size, const unsigned int offset, const char **ext) {
  if (offset >= size - 8) {
    return;
  }
  {
    const unsigned int offset_soft = offset + 8;
    const unsigned int count = get32u(buffer, offset + 4);
    unsigned int count2;
    if (count == 0 || count > size / 2) {
      return;
    }
    count2 = 2 * count;
    if (count2 > size - offset_soft) {
      return;
    }
    *ext = software_uni2ext(&buffer[offset_soft], count);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<OLE_parse_uni_software_entry>:
  endbr64
  lea    -0x8(%rsi),%eax
  cmp    %edx,%eax
  ja     L13
  ret
L13:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %rcx,%r13
  lea    0x4(%rdx),%esi
  call   <get32u@plt>
  mov    %eax,%esi
  test   %eax,%eax
  je     L14
  mov    %ebp,%eax
  shr    %eax
  cmp    %esi,%eax
  jb     L14
  add    $0x8,%ebx
  sub    %ebx,%ebp
  lea    (%rsi,%rsi,1),%eax
  cmp    %eax,%ebp
  jae    L4
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %ebx,%ebx
  lea    (%r12,%rbx,1),%rdi
  call   <software_uni2ext@plt>
  mov    %rax,0x0(%r13)
  jmp    L14
```

assistant: ```c
void OLE_parse_uni_software_entry(const char *buffer, const unsigned int size, const unsigned int offset, const char **ext) {
  if (offset >= size - 8) {
    return;
  }
  {
    const unsigned int offset_soft = offset + 8;
    const unsigned int count = get32u(buffer, offset + 4);
    unsigned int count2;
    if (count == 0 || count > size / 2) {
      return;
    }
    count2 = 2 * count;
    if (count2 > size - offset_soft) {
      return;
    }
    *ext = software_uni2ext(&buffer[offset_soft], count);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<OLE_parse_uni_software_entry>:
  endbr64
  lea    -0x8(%rsi),%eax
  cmp    %edx,%eax
  ja     L2
  ret
  nopl   0x0(%rax)
L2:
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  lea    0x4(%rdx),%esi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <get32u@plt>
  mov    %eax,%esi
  test   %eax,%eax
  je     L16
  mov    %ebp,%eax
  shr    %eax
  cmp    %esi,%eax
  jb     L16
  add    $0x8,%ebx
  lea    (%rsi,%rsi,1),%eax
  sub    %ebx,%ebp
  cmp    %eax,%ebp
  jae    L15
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  lea    0x0(%r13,%rbx,1),%rdi
  call   <software_uni2ext@plt>
  mov    %rax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void OLE_parse_uni_software_entry(const char *buffer, const unsigned int size, const unsigned int offset, const char **ext) {
  if (offset >= size - 8) {
    return;
  }
  {
    const unsigned int offset_soft = offset + 8;
    const unsigned int count = get32u(buffer, offset + 4);
    unsigned int count2;
    if (count == 0 || count > size / 2) {
      return;
    }
    count2 = 2 * count;
    if (count2 > size - offset_soft) {
      return;
    }
    *ext = software_uni2ext(&buffer[offset_soft], count);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<OLE_parse_uni_software_entry>:
  endbr64
  lea    -0x8(%rsi),%eax
  cmp    %edx,%eax
  ja     L1
  ret
  nopl   0x0(%rax)
L1:
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  lea    0x4(%rdx),%esi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <get32u@plt>
  mov    %eax,%esi
  test   %eax,%eax
  je     L37
  mov    %ebp,%eax
  shr    %eax
  cmp    %esi,%eax
  jb     L37
  add    $0x8,%ebx
  lea    (%rsi,%rsi,1),%eax
  sub    %ebx,%ebp
  cmp    %eax,%ebp
  jae    L19
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  lea    0x0(%r13,%rbx,1),%rdi
  call   <software_uni2ext@plt>
  mov    %rax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void OLE_parse_uni_software_entry(const char *buffer, const unsigned int size, const unsigned int offset, const char **ext) {
  if (offset >= size - 8) {
    return;
  }
  {
    const unsigned int offset_soft = offset + 8;
    const unsigned int count = get32u(buffer, offset + 4);
    unsigned int count2;
    if (count == 0 || count > size / 2) {
      return;
    }
    count2 = 2 * count;
    if (count2 > size - offset_soft) {
      return;
    }
    *ext = software_uni2ext(&buffer[offset_soft], count);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<longerString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  and    $0x7,%eax
  test   %eax,%eax
  jne    L10
  subl   $0x1,-0x4(%rbp)
L10:
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L17:
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: 	

assistant: ```c
char *longerString(char *string, int largo) {
  int i, a = (largo - strlen(string)) / 8;
  if (strlen(string) % 8 == 0)
    a--;
  for (i = 0; i < a; i++) {
    strcat(string, "\t");
  }
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<longerString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %ebx,%esi
  sub    %eax,%esi
  lea    0x7(%rsi),%ebp
  cmovns %esi,%ebp
  sar    $0x3,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  and    $0x7,%eax
  cmp    $0x1,%eax
  sbb    $0x0,%ebp
  test   %ebp,%ebp
  jle    L0
  mov    $0x0,%ebx
  lea    D2(%rip),%r13
L17:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L17
L0:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: 	

assistant: ```c
char *longerString(char *string, int largo) {
  int i, a = (largo - strlen(string)) / 8;
  if (strlen(string) % 8 == 0)
    a--;
  for (i = 0; i < a; i++) {
    strcat(string, "\t");
  }
  return string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<longerString>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  sub    %eax,%esi
  lea    0x7(%rsi),%ebp
  cmovns %esi,%ebp
  call   <strlen@plt>
  and    $0x7,%eax
  sar    $0x3,%ebp
  cmp    $0x1,%eax
  sbb    $0x0,%ebp
  test   %ebp,%ebp
  jle    L12
  xor    %ebx,%ebx
  lea    D0(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <strcat@plt>
  cmp    %ebx,%ebp
  jne    L11
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: 	

assistant: ```c
char *longerString(char *string, int largo) {
  int i, a = (largo - strlen(string)) / 8;
  if (strlen(string) % 8 == 0)
    a--;
  for (i = 0; i < a; i++) {
    strcat(string, "\t");
  }
  return string;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<longerString>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  sub    %eax,%esi
  lea    0x7(%rsi),%ebp
  cmovns %esi,%ebp
  call   <strlen@plt>
  and    $0x7,%eax
  sar    $0x3,%ebp
  cmp    $0x1,%eax
  sbb    $0x0,%ebp
  test   %ebp,%ebp
  jle    L11
  xor    %ebx,%ebx
  lea    D7(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <strcat@plt>
  cmp    %ebx,%ebp
  jne    L19
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: 	

assistant: ```c
char *longerString(char *string, int largo) {
  int i, a = (largo - strlen(string)) / 8;
  if (strlen(string) % 8 == 0)
    a--;
  for (i = 0; i < a; i++) {
    strcat(string, "\t");
  }
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_last_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L1
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  nop
  leave
  ret
```

assistant: ```c
void check_last_char(char *dirpath) {
  int len = strlen(dirpath);
  if (dirpath[len - 1] != '/') {
    dirpath[len++] = '/';
    dirpath[len] = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_last_char>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  cmpb   $0x2f,-0x1(%rbx,%rdx,1)
  je     L5
  movb   $0x2f,(%rbx,%rdx,1)
  add    $0x1,%eax
  cltq
  movb   $0x0,(%rbx,%rax,1)
L5:
  pop    %rbx
  ret
```

assistant: ```c
void check_last_char(char *dirpath) {
  int len = strlen(dirpath);
  if (dirpath[len - 1] != '/') {
    dirpath[len++] = '/';
    dirpath[len] = '\0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_last_char>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  cmpb   $0x2f,-0x1(%rbx,%rdx,1)
  je     L9
  add    $0x1,%eax
  movb   $0x2f,(%rbx,%rdx,1)
  cltq
  movb   $0x0,(%rbx,%rax,1)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void check_last_char(char *dirpath) {
  int len = strlen(dirpath);
  if (dirpath[len - 1] != '/') {
    dirpath[len++] = '/';
    dirpath[len] = '\0';
  }
}
```