ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readline>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
L25:
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L31
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L47
  movb   $0x0,(%rax)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L25
  cmp    $0x3b,%al
  je     L25
L19:
  xor    %eax,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  movzbl (%rbx),%eax
  cmp    $0x3b,%al
  je     L25
  test   %al,%al
  jne    L19
  jmp    L25
  nopl   (%rax)
L31:
  mov    $0xffffffff,%eax
  jmp    L24
```

assistant: ```c
int readline(FILE *str, char *dest, int destlen) {
  char *x;
  for (;;) {
    if (!fgets(dest, destlen, str))
      return -1;
    if (x = strchr(dest, '\n'))
      *x = '\0';
    if (dest[0] == '\0')
      continue;
    if (dest[0] == ';')
      continue;
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bpnn_layerforward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  movss  D5(%rip),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x1,-0x18(%rbp)
  jmp    L12
L28:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L26:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L26
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <squash@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addl   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jle    L28
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: f32

tool: D5: 1

assistant: ```c
void bpnn_layerforward(float *l1, float *l2, float **conn, int n1, int n2) {
  float sum;
  int j, k;
  l1[0] = 1.0;
#pragma omp parallel for shared(conn, n1, n2, l1) private(k, j) reduction(+ : sum) schedule(static)
  for (j = 1; j <= n2; j++) {
    sum = 0.0;
    for (k = 0; k <= n1; k++) {
      sum += conn[k][j] * l1[k];
    }
    l2[j] = squash(sum);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bpnn_layerforward>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r15
  mov    %rdx,%rbp
  mov    %ecx,%r14d
  mov    %r8d,%r13d
  movl   $0x3f800000,(%rdi)
  mov    $0x1,%r12d
  lea    0x1(%rcx),%eax
  mov    %eax,0xc(%rsp)
  test   %r8d,%r8d
  jg     L40
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  lea    0x0(,%r12,4),%rsi
  mov    0xc(%rsp),%ecx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L45:
  mov    0x0(%rbp,%rax,8),%rdx
  movss  (%rdx,%rsi,1),%xmm0
  mulss  (%rbx,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L45
L14:
  movaps %xmm1,%xmm0
  call   <squash@plt>
  movss  %xmm0,(%r15,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%r13d
  jl     L30
L40:
  pxor   %xmm1,%xmm1
  test   %r14d,%r14d
  jns    L48
  jmp    L14
```

assistant: ```c
void bpnn_layerforward(float *l1, float *l2, float **conn, int n1, int n2) {
  float sum;
  int j, k;
  l1[0] = 1.0;
#pragma omp parallel for shared(conn, n1, n2, l1) private(k, j) reduction(+ : sum) schedule(static)
  for (j = 1; j <= n2; j++) {
    sum = 0.0;
    for (k = 0; k <= n1; k++) {
      sum += conn[k][j] * l1[k];
    }
    l2[j] = squash(sum);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bpnn_layerforward>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x3f800000,(%rdi)
  mov    %r8d,0xc(%rsp)
  test   %r8d,%r8d
  jle    L27
  movslq %ecx,%r15
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %r15,%rbp
  mov    $0x1,%ebx
  cs nopw 0x0(%rax,%rax,1)
L36:
  lea    0x0(,%rbx,4),%rcx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  test   %ebp,%ebp
  js     L7
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%r14,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  0x0(%r13,%rax,4),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rdx,%r15
  jne    L18
L7:
  movaps %xmm1,%xmm0
  call   <squash@plt>
  movss  %xmm0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L36
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bpnn_layerforward(float *l1, float *l2, float **conn, int n1, int n2) {
  float sum;
  int j, k;
  l1[0] = 1.0;
#pragma omp parallel for shared(conn, n1, n2, l1) private(k, j) reduction(+ : sum) schedule(static)
  for (j = 1; j <= n2; j++) {
    sum = 0.0;
    for (k = 0; k <= n1; k++) {
      sum += conn[k][j] * l1[k];
    }
    l2[j] = squash(sum);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bpnn_layerforward>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x3f800000,(%rdi)
  mov    %r8d,0xc(%rsp)
  test   %r8d,%r8d
  jle    L16
  movslq %ecx,%r15
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %r15,%rbp
  mov    $0x1,%ebx
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    0x0(,%rbx,4),%rcx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  test   %ebp,%ebp
  js     L6
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%r14,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  0x0(%r13,%rax,4),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rdx,%r15
  jne    L10
L6:
  movaps %xmm1,%xmm0
  call   <squash@plt>
  movss  %xmm0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L7
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bpnn_layerforward(float *l1, float *l2, float **conn, int n1, int n2) {
  float sum;
  int j, k;
  l1[0] = 1.0;
#pragma omp parallel for shared(conn, n1, n2, l1) private(k, j) reduction(+ : sum) schedule(static)
  for (j = 1; j <= n2; j++) {
    sum = 0.0;
    for (k = 0; k <= n1; k++) {
      sum += conn[k][j] * l1[k];
    }
    l2[j] = squash(sum);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L49
L32:
  movw   $0x0,-0xe(%rbp)
  jmp    L20
L40:
  addw   $0x2,-0xe(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xe(%rbp)
  jb     L40
  addw   $0x2,-0xc(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L32
  movzwl -0xa(%rbp),%eax
  imul   $0x319d,%ax,%ax
  lea    -0x5b0d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - (unsigned short)23309;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0xb45(%rax),%r8d
  movzwl 0x2(%rdi),%edx
  mov    $0x0,%ecx
  test   %dx,%dx
  je     L14
L1:
  mov    $0x0,%eax
L22:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L22
  add    $0x2,%ecx
  cmp    %dx,%cx
  jb     L1
L14:
  imul   $0x319d,%r8w,%ax
  sub    $0x5b0d,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - (unsigned short)23309;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edx
  xor    %ecx,%ecx
  lea    0xb45(%rax),%r8d
  test   %dx,%dx
  je     L16
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L21
  add    $0x2,%ecx
  cmp    %dx,%cx
  jb     L2
L16:
  imul   $0x319d,%r8w,%ax
  sub    $0x5b0d,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - (unsigned short)23309;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edx
  xor    %ecx,%ecx
  lea    0xb45(%rax),%r8d
  test   %dx,%dx
  je     L25
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L7
  add    $0x2,%ecx
  cmp    %dx,%cx
  jb     L15
L25:
  imul   $0x319d,%r8w,%ax
  sub    $0x5b0d,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - (unsigned short)23309;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x82,-0x4(%rbp)
  movb   $0x82,-0x5(%rbp)
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  movzbl -0x5(%rbp),%eax
  add    $0x42,%eax
  mov    %al,-0x5(%rbp)
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  movzbl -0x5(%rbp),%eax
  add    $0x3c,%eax
  mov    %al,-0x5(%rbp)
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D45
type_infered: string
name: read_data
arguments: tag: D26
type_infered: string
name: read_data
arguments: tag: D41
type_infered: string
name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D75
type_infered: string
name: read_data
arguments: tag: D62
type_infered: string

tool: D45: Should print 130


tool: D26: 



tool: D41: Should print -126


tool: D32: Should print -60


tool: D75: Should print 0


tool: D62: 


assistant: ```c
void main(void) {
  int x, y;
  char letter;
  x = 'A' + 'A';
  letter = 'A' + 'A';
  print_string("Should print 130\n");
  print_int(x);
  print_string("\n\n");
  print_string("Should print -126\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 'B';
  print_string("Should print -60\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 60;
  print_string("Should print 0\n");
  print_int(letter);
  print_string("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D21(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffff82,%edi
  call   <print_int@plt>
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  call   <print_string@plt>
  lea    D22(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffff82,%edi
  call   <print_int@plt>
  mov    %rbx,%rdi
  call   <print_string@plt>
  lea    D18(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffffc4,%edi
  call   <print_int@plt>
  mov    %rbx,%rdi
  call   <print_string@plt>
  lea    D56(%rip),%rdi
  call   <print_string@plt>
  mov    $0x0,%edi
  call   <print_int@plt>
  lea    D13(%rip),%rdi
  call   <print_string@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D34
datatype: string
name: disassemble_data
arguments: data_tag: D22
datatype: string
name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D56
datatype: string
name: disassemble_data
arguments: data_tag: D13
datatype: string

tool: D21: Should print 130


tool: D34: 



tool: D22: Should print -126


tool: D18: Should print -60


tool: D56: Should print 0


tool: D13: 


assistant: ```c
void main(void) {
  int x, y;
  char letter;
  x = 'A' + 'A';
  letter = 'A' + 'A';
  print_string("Should print 130\n");
  print_int(x);
  print_string("\n\n");
  print_string("Should print -126\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 'B';
  print_string("Should print -60\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 60;
  print_string("Should print 0\n");
  print_int(letter);
  print_string("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rdi
  lea    D28(%rip),%rbp
  call   <print_string@plt>
  mov    $0xffffff82,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  lea    D55(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffff82,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  lea    D46(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffffc4,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  lea    D49(%rip),%rdi
  call   <print_string@plt>
  xor    %edi,%edi
  call   <print_int@plt>
  lea    D4(%rip),%rdi
  pop    %rbp
  jmp    1070 <print_string@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D30
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D55
type_infered: string
name: disassemble_data
arguments: data_label: D46
type_infered: string
name: disassemble_data
arguments: data_label: D49
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D30: Should print 130


tool: D28: 



tool: D55: Should print -126


tool: D46: Should print -60


tool: D49: Should print 0


tool: D4: 


assistant: ```c
void main(void) {
  int x, y;
  char letter;
  x = 'A' + 'A';
  letter = 'A' + 'A';
  print_string("Should print 130\n");
  print_int(x);
  print_string("\n\n");
  print_string("Should print -126\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 'B';
  print_string("Should print -60\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 60;
  print_string("Should print 0\n");
  print_int(letter);
  print_string("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D36(%rip),%rbp
  call   <print_string@plt>
  mov    $0xffffff82,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  lea    D0(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffff82,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  lea    D22(%rip),%rdi
  call   <print_string@plt>
  mov    $0xffffffc4,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  lea    D59(%rip),%rdi
  call   <print_string@plt>
  xor    %edi,%edi
  call   <print_int@plt>
  lea    D23(%rip),%rdi
  pop    %rbp
  jmp    1070 <print_string@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string
name: extract_symbolic_data
arguments: data_label: D36
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D59
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string

tool: D5: Should print 130


tool: D36: 



tool: D0: Should print -126


tool: D22: Should print -60


tool: D59: Should print 0


tool: D23: 


assistant: ```c
void main(void) {
  int x, y;
  char letter;
  x = 'A' + 'A';
  letter = 'A' + 'A';
  print_string("Should print 130\n");
  print_int(x);
  print_string("\n\n");
  print_string("Should print -126\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 'B';
  print_string("Should print -60\n");
  print_int(letter);
  print_string("\n\n");
  letter = letter + 60;
  print_string("Should print 0\n");
  print_int(letter);
  print_string("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: %d arg = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("%d arg = %s\n", i, argv[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D1(%rip),%r13
L0:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    $0x0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d arg = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("%d arg = %s\n", i, argv[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: %d arg = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("%d arg = %s\n", i, argv[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: %d arg = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("%d arg = %s\n", i, argv[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bernstein>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <binomial@plt>
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x8(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  %xmm1,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  movsd  D5(%rip),%xmm0
  subsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mulsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: f64

tool: D5: 1

assistant: ```c
double bernstein(unsigned int n, unsigned int v, double x) {
  assert(v <= n);
  return binomial(n, v) * pow(x, v) * pow(1. - x, n - v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bernstein>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  movsd  %xmm0,(%rsp)
  cmp    %edi,%esi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <binomial@plt>
  movq   %xmm0,%r14
  cvttsd2si (%rsp),%edi
  mov    %ebp,%esi
  call   <pow@plt>
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    %ebp,%ebx
  mov    %ebx,%esi
  movsd  D0(%rip),%xmm0
  subsd  (%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: f64

tool: D0: 1

assistant: ```c
double bernstein(unsigned int n, unsigned int v, double x) {
  assert(v <= n);
  return binomial(n, v) * pow(x, v) * pow(1. - x, n - v);
}
```