ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<digestdb_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L19:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %ecx,%rdx
  lea    D14(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  movzbl -0x9(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %ecx,%rdx
  lea    D14(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L19
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D14
type_guessed: string

tool: D14: 0123456789abcdef

assistant: ```c
void digestdb_encode(char *text, const unsigned char *bytes) {
  static const char tab[] = "0123456789abcdef";
  const unsigned char *end;
  end = bytes + 16;
  for (; bytes < end; bytes++) {
    unsigned char b;
    b = *bytes;
    *text++ = tab[(b & 0xf0) >> 4];
    *text++ = tab[(b & 0x0f) >> 0];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<digestdb_encode>:
  endbr64
  mov    $0x0,%eax
  lea    D7(%rip),%r8
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %edx,%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rdi,%rax,2)
  and    $0xf,%edx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L0
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string

tool: D7: 0123456789abcdef

assistant: ```c
void digestdb_encode(char *text, const unsigned char *bytes) {
  static const char tab[] = "0123456789abcdef";
  const unsigned char *end;
  end = bytes + 16;
  for (; bytes < end; bytes++) {
    unsigned char b;
    b = *bytes;
    *text++ = tab[(b & 0xf0) >> 4];
    *text++ = tab[(b & 0x0f) >> 0];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<digestdb_encode>:
  endbr64
  xor    %eax,%eax
  lea    D6(%rip),%r8
  nopl   (%rax)
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %edx,%ecx
  and    $0xf,%edx
  shr    $0x4,%cl
  movzbl (%r8,%rdx,1),%edx
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %dl,0x1(%rdi,%rax,2)
  mov    %cl,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: 0123456789abcdef

assistant: ```c
void digestdb_encode(char *text, const unsigned char *bytes) {
  static const char tab[] = "0123456789abcdef";
  const unsigned char *end;
  end = bytes + 16;
  for (; bytes < end; bytes++) {
    unsigned char b;
    b = *bytes;
    *text++ = tab[(b & 0xf0) >> 4];
    *text++ = tab[(b & 0x0f) >> 0];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__SASX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  and    $0xffff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x10,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  and    $0xffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     -0x8(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = ((((int32_t)x << 16) >> 16) - (((int32_t)y) >> 16)) & (int32_t)0x0000FFFF;
  s = ((((int32_t)x) >> 16) + (((int32_t)y << 16) >> 16)) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__SASX>:
  endbr64
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  movzwl %ax,%eax
  sar    $0x10,%edi
  lea    (%rdi,%rsi,1),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  cltq
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = ((((int32_t)x << 16) >> 16) - (((int32_t)y) >> 16)) & (int32_t)0x0000FFFF;
  s = ((((int32_t)x) >> 16) + (((int32_t)y << 16) >> 16)) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__SASX>:
  endbr64
  mov    %esi,%edx
  mov    %edi,%eax
  sar    $0x10,%edi
  sar    $0x10,%edx
  sub    %edx,%eax
  lea    (%rdi,%rsi,1),%edx
  shl    $0x10,%edx
  movzwl %ax,%eax
  or     %edx,%eax
  cltq
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = ((((int32_t)x << 16) >> 16) - (((int32_t)y) >> 16)) & (int32_t)0x0000FFFF;
  s = ((((int32_t)x) >> 16) + (((int32_t)y << 16) >> 16)) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__SASX>:
  endbr64
  mov    %esi,%edx
  mov    %edi,%eax
  sar    $0x10,%edi
  sar    $0x10,%edx
  sub    %edx,%eax
  lea    (%rdi,%rsi,1),%edx
  shl    $0x10,%edx
  movzwl %ax,%eax
  or     %edx,%eax
  cltq
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = ((((int32_t)x << 16) >> 16) - (((int32_t)y) >> 16)) & (int32_t)0x0000FFFF;
  s = ((((int32_t)x) >> 16) + (((int32_t)y << 16) >> 16)) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ts_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L17
L31:
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%edi
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%edx
  div    %edi
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jae    L31
  jmp    L40
L30:
  mov    -0x8(%rbp),%edi
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%edx
  div    %edi
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x1c(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x20(%rbp)
  mov    %eax,-0x8(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  lea    0x37(%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
  jmp    L40
L8:
  mov    -0x4(%rbp),%eax
  lea    0x30(%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
L40:
  cmpl   $0x0,-0x8(%rbp)
  jne    L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ts_itoa(char **buf, unsigned int d, int base) {
  int div = 1;
  while (d / div >= base) {
    div *= base;
  }
  while (div != 0) {
    int num = d / div;
    d = d % div;
    div /= base;
    if (num > 9) {
      *((*buf)++) = (num - 10) + 'A';
    } else {
      *((*buf)++) = num + '0';
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ts_itoa>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%r8d
  cmp    %edx,%esi
  jb     L19
  mov    $0x1,%ecx
L18:
  imul   %r8d,%ecx
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %ecx
  cmp    %r8d,%eax
  jae    L18
  test   %ecx,%ecx
  jne    L62
  ret
L19:
  mov    $0x1,%ecx
  jmp    L62
L9:
  mov    (%r9),%rdx
  lea    0x1(%rdx),%r10
  mov    %r10,(%r9)
  add    $0x30,%edi
  mov    %dil,(%rdx)
L59:
  test   %eax,%eax
  je     L20
L62:
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%esi
  mov    %eax,%edi
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ecx
  cmp    $0x9,%edi
  jle    L9
  mov    (%r9),%rdx
  lea    0x1(%rdx),%r10
  mov    %r10,(%r9)
  add    $0x37,%edi
  mov    %dil,(%rdx)
  jmp    L59
L20:
  ret
```

assistant: ```c
void ts_itoa(char **buf, unsigned int d, int base) {
  int div = 1;
  while (d / div >= base) {
    div *= base;
  }
  while (div != 0) {
    int num = d / div;
    d = d % div;
    div /= base;
    if (num > 9) {
      *((*buf)++) = (num - 10) + 'A';
    } else {
      *((*buf)++) = num + '0';
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ts_itoa>:
  endbr64
  mov    %rdi,%r9
  mov    $0x1,%ecx
  mov    %edx,%edi
  cmp    %edx,%esi
  jb     L31
  nopw   0x0(%rax,%rax,1)
L38:
  imul   %edi,%ecx
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  cmp    %edi,%eax
  jae    L38
  test   %ecx,%ecx
  je     L34
  nopl   0x0(%rax)
L31:
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %eax,%r8d
  mov    %ecx,%eax
  mov    %edx,%esi
  cltd
  lea    0x37(%r8),%r11d
  idiv   %edi
  mov    (%r9),%rdx
  cmp    $0xa,%r8d
  lea    0x1(%rdx),%r10
  mov    %r10,(%r9)
  mov    %eax,%ecx
  lea    0x30(%r8),%eax
  cmovge %r11d,%eax
  mov    %al,(%rdx)
  test   %ecx,%ecx
  jne    L31
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  ret
```

assistant: ```c
void ts_itoa(char **buf, unsigned int d, int base) {
  int div = 1;
  while (d / div >= base) {
    div *= base;
  }
  while (div != 0) {
    int num = d / div;
    d = d % div;
    div /= base;
    if (num > 9) {
      *((*buf)++) = (num - 10) + 'A';
    } else {
      *((*buf)++) = num + '0';
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ts_itoa>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%r8d
  mov    $0x1,%ecx
  cmp    %edx,%esi
  jb     L36
  nopl   0x0(%rax,%rax,1)
L58:
  imul   %r8d,%ecx
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  cmp    %r8d,%eax
  jae    L58
  test   %ecx,%ecx
  je     L4
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %eax,%edi
  mov    %ecx,%eax
  mov    %edx,%esi
  cltd
  idiv   %r8d
  mov    %eax,%ecx
  mov    (%r9),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r9)
  cmp    $0x9,%edi
  jle    L46
  add    $0x37,%edi
  mov    %dil,(%rax)
  test   %ecx,%ecx
  jne    L36
  ret
  nopl   0x0(%rax)
L46:
  add    $0x30,%edi
  mov    %dil,(%rax)
  test   %ecx,%ecx
  jne    L36
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void ts_itoa(char **buf, unsigned int d, int base) {
  int div = 1;
  while (d / div >= base) {
    div *= base;
  }
  while (div != 0) {
    int num = d / div;
    d = d % div;
    div /= base;
    if (num > 9) {
      *((*buf)++) = (num - 10) + 'A';
    } else {
      *((*buf)++) = num + '0';
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FindMinDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x2c(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L8:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string

tool: D0: Shortest Path
%d 

tool: D5: %d 

assistant: ```c
void FindMinDistance(int a, int b, int mSize, int pred[mSize][mSize]) {
  int temp = b;
  printf("Shortest Path\n%d ", b);
  while (temp != a) {
    temp = pred[a][temp];
    printf("%d ", temp);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<FindMinDistance>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rcx,%r12
  movslq %edx,%r13
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L11
  movslq %ebp,%rax
  imul   %r13,%rax
  lea    (%r12,%rax,4),%r13
  lea    D11(%rip),%r12
L0:
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbx,4),%ebx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L0
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D14: Shortest Path
%d 

tool: D11: %d 

assistant: ```c
void FindMinDistance(int a, int b, int mSize, int pred[mSize][mSize]) {
  int temp = b;
  printf("Shortest Path\n%d ", b);
  while (temp != a) {
    temp = pred[a][temp];
    printf("%d ", temp);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<FindMinDistance>:
  endbr64
  push   %r13
  xor    %eax,%eax
  movslq %edx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D11(%rip),%rdi
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L17
  movslq %ebp,%rax
  imul   %r13,%rax
  lea    (%r12,%rax,4),%r13
  lea    D6(%rip),%r12
  nop
L8:
  movslq 0x0(%r13,%rbx,4),%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L8
L17:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D11: Shortest Path
%d 

tool: D6: %d 

assistant: ```c
void FindMinDistance(int a, int b, int mSize, int pred[mSize][mSize]) {
  int temp = b;
  printf("Shortest Path\n%d ", b);
  while (temp != a) {
    temp = pred[a][temp];
    printf("%d ", temp);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FindMinDistance>:
  endbr64
  push   %r13
  xor    %eax,%eax
  movslq %edx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D14(%rip),%rdi
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L18
  movslq %ebp,%rax
  imul   %r13,%rax
  lea    (%r12,%rax,4),%r13
  lea    D11(%rip),%r12
  nop
L1:
  movslq 0x0(%r13,%rbx,4),%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L1
L18:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string

tool: D14: Shortest Path
%d 

tool: D11: %d 

assistant: ```c
void FindMinDistance(int a, int b, int mSize, int pred[mSize][mSize]) {
  int temp = b;
  printf("Shortest Path\n%d ", b);
  while (temp != a) {
    temp = pred[a][temp];
    printf("%d ", temp);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L2
  mov    D8(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D4(%rip)
  mov    D4(%rip),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L2:
  movl   $0x2,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int x) {
  int retval = 0;
  if (x % 2 == 1) {
    static int staticInt;
    retval = ++staticInt;
  } else {
    retval = 2;
  }
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  and    $0x1,%edi
  sub    %eax,%edi
  mov    $0x2,%eax
  cmp    $0x1,%edi
  je     L17
L14:
  ret
L17:
  mov    D17(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D12(%rip)
  jmp    L14
```

assistant: ```c
int f(int x) {
  int retval = 0;
  if (x % 2 == 1) {
    static int staticInt;
    retval = ++staticInt;
  } else {
    retval = 2;
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  and    $0x1,%edi
  sub    %eax,%edi
  mov    $0x2,%eax
  cmp    $0x1,%edi
  je     L6
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D18(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D8(%rip)
  ret
```

assistant: ```c
int f(int x) {
  int retval = 0;
  if (x % 2 == 1) {
    static int staticInt;
    retval = ++staticInt;
  } else {
    retval = 2;
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  and    $0x1,%edi
  sub    %eax,%edi
  mov    $0x2,%eax
  cmp    $0x1,%edi
  je     L7
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    D7(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D16(%rip)
  ret
```

assistant: ```c
int f(int x) {
  int retval = 0;
  if (x % 2 == 1) {
    static int staticInt;
    retval = ++staticInt;
  } else {
    retval = 2;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sans_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %rsi,-0xf0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xd8(%rbp)
  lea    -0xd8(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %eax,%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%ecx
  lea    D12(%rip),%rdx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0xd0(%rbp),%rdx
  mov    -0xe8(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0xf0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd4(%rbp),%edx
  mov    -0xf0(%rbp),%rcx
  mov    -0xe8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    -0xd4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D12: %y-%m-%d %H:%M:%S

tool: D5: [%s] 

assistant: ```c
void sans_log(FILE *stream, const char *format, ...) {
  time_t now = time(NULL);
  char timestr[20];
  strftime(timestr, 20, "%y-%m-%d %H:%M:%S", localtime(&now));
  fprintf(stream, "[%s] ", timestr);
  va_list args;
  va_start(args, format);
  vfprintf(stream, format, args);
  va_end(args);
  putchar('\n');
  fflush(stream);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sans_log>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%ecx
  lea    0x10(%rsp),%r12
  lea    D4(%rip),%rdx
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <fflush@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D4: %y-%m-%d %H:%M:%S

tool: D0: [%s] 

assistant: ```c
void sans_log(FILE *stream, const char *format, ...) {
  time_t now = time(NULL);
  char timestr[20];
  strftime(timestr, 20, "%y-%m-%d %H:%M:%S", localtime(&now));
  fprintf(stream, "[%s] ", timestr);
  va_list args;
  va_start(args, format);
  vfprintf(stream, format, args);
  va_end(args);
  putchar('\n');
  fflush(stream);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sans_log>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <time@plt>
  lea    0xc(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime@plt>
  mov    %r13,%rdi
  mov    $0x14,%esi
  lea    D13(%rip),%rdx
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  lea    D4(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D13: %y-%m-%d %H:%M:%S

tool: D4: [%s] 

assistant: ```c
void sans_log(FILE *stream, const char *format, ...) {
  time_t now = time(NULL);
  char timestr[20];
  strftime(timestr, 20, "%y-%m-%d %H:%M:%S", localtime(&now));
  fprintf(stream, "[%s] ", timestr);
  va_list args;
  va_start(args, format);
  vfprintf(stream, format, args);
  va_end(args);
  putchar('\n');
  fflush(stream);
}
```