ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<analyse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <val_curMRIState@plt>
  mov    $0x1,%esi
  mov    0x4(%rsp),%edi
  mov    $0x0,%eax
  call   <mod_anl@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <val_cptMRIState@plt>
  mov    $0x1,%esi
  mov    0x4(%rsp),%edi
  mov    $0x0,%eax
  call   <mod_anl@plt>
  lea    0x8(%rsp),%rdi
  mov    %ebx,%esi
  mov    $0x0,%eax
  call   <cre_sees_uses@plt>
  cmpl   $0x1,0x8(%rsp)
  je     L26
L21:
  mov    0x8(%rsp),%eax
  mov    %eax,(%r12)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    0x8(%rsp),%rdi
  mov    %ebx,%esi
  mov    $0x0,%eax
  call   <cre_inc_ipt@plt>
  cmpl   $0x1,0x8(%rsp)
  jne    L21
  lea    0xc(%rsp),%rdi
  mov    $0x0,%eax
  call   <val_gset1@plt>
  lea    0x8(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    %ebx,%esi
  mov    $0x0,%eax
  call   <mod_sees_uses@plt>
  cmpl   $0x1,0x8(%rsp)
  jne    L21
  lea    0xc(%rsp),%rdi
  mov    $0x0,%eax
  call   <val_gset2@plt>
  lea    0x8(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    %ebx,%esi
  mov    $0x0,%eax
  call   <mod_inc_ipt@plt>
  cmpl   $0x1,0x8(%rsp)
  jne    L21
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  mov    $0x0,%eax
  call   <valIth_gseq@plt>
  mov    0x10(%rsp),%esi
  cmp    %ebx,%esi
  je     L73
  lea    0x14(%rsp),%rdi
  mov    $0x0,%eax
  call   <val_abs2conc@plt>
  mov    0x14(%rsp),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <cre_abs2conc@plt>
  lea    0x8(%rsp),%rdi
  mov    %ebx,%edx
  mov    0x14(%rsp),%esi
  mov    $0x0,%eax
  call   <push_a2c@plt>
  jmp    L21
L73:
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x0,%eax
  call   <make_Abs2Conc@plt>
  mov    0x14(%rsp),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <cre_abs2conc@plt>
  cmpl   $0x1,0x8(%rsp)
  jne    L21
  lea    0x8(%rsp),%rdi
  mov    %ebx,%edx
  mov    0x14(%rsp),%esi
  mov    $0x0,%eax
  call   <push_a2c@plt>
  jmp    L21
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void analyse(rep, cc) int *rep, cc;
{
  int st, rr, ss, bb, cc1, ac;
  val_curMRIState(&st, cc);
  mod_anl(st, 1);
  val_cptMRIState(&st, cc);
  mod_anl(st, 1);
  cre_sees_uses(&rr, cc);
  if (rr == 1) {
    cre_inc_ipt(&rr, cc);
    if (rr == 1) {
      val_gset1(&ss);
      mod_sees_uses(&rr, cc, ss);
      if (rr == 1) {
        val_gset2(&ss);
        mod_inc_ipt(&rr, cc, ss);
        if (rr == 1) {
          valIth_gseq(&cc1, 1);
          if (cc1 != cc) {
            val_abs2conc(&ac, cc1);
            cre_abs2conc(cc, ac);
            push_a2c(&rr, ac, cc);
          } else {
            make_Abs2Conc(&rr, &ac);
            cre_abs2conc(cc, ac);
            if (rr == 1) {
              push_a2c(&rr, ac, cc);
            }
          }
        }
      }
    }
  }
  *rep = rr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<analyse>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <val_curMRIState@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <mod_anl@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <val_cptMRIState@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  call   <mod_anl@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <cre_sees_uses@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  je     L56
L66:
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <cre_inc_ipt@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L66
  lea    0xc(%rsp),%r13
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <val_gset1@plt>
  mov    0xc(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mod_sees_uses@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L66
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <val_gset2@plt>
  mov    0xc(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mod_inc_ipt@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L66
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <valIth_gseq@plt>
  mov    0x10(%rsp),%r13d
  cmp    %r12d,%r13d
  je     L77
  lea    0x14(%rsp),%rdi
  mov    %r13d,%esi
  xor    %eax,%eax
  call   <val_abs2conc@plt>
  mov    0x14(%rsp),%esi
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <cre_abs2conc@plt>
  mov    %r12d,%edx
L7:
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <push_a2c@plt>
  mov    0x8(%rsp),%eax
  jmp    L66
L77:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <make_Abs2Conc@plt>
  mov    0x14(%rsp),%esi
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <cre_abs2conc@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L66
  mov    %r13d,%edx
  jmp    L7
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void analyse(rep, cc) int *rep, cc;
{
  int st, rr, ss, bb, cc1, ac;
  val_curMRIState(&st, cc);
  mod_anl(st, 1);
  val_cptMRIState(&st, cc);
  mod_anl(st, 1);
  cre_sees_uses(&rr, cc);
  if (rr == 1) {
    cre_inc_ipt(&rr, cc);
    if (rr == 1) {
      val_gset1(&ss);
      mod_sees_uses(&rr, cc, ss);
      if (rr == 1) {
        val_gset2(&ss);
        mod_inc_ipt(&rr, cc, ss);
        if (rr == 1) {
          valIth_gseq(&cc1, 1);
          if (cc1 != cc) {
            val_abs2conc(&ac, cc1);
            cre_abs2conc(cc, ac);
            push_a2c(&rr, ac, cc);
          } else {
            make_Abs2Conc(&rr, &ac);
            cre_abs2conc(cc, ac);
            if (rr == 1) {
              push_a2c(&rr, ac, cc);
            }
          }
        }
      }
    }
  }
  *rep = rr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<analyse>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <val_curMRIState@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <mod_anl@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <val_cptMRIState@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  call   <mod_anl@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <cre_sees_uses@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  je     L55
L24:
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <cre_inc_ipt@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L24
  lea    0xc(%rsp),%r13
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <val_gset1@plt>
  mov    0xc(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mod_sees_uses@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L24
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <val_gset2@plt>
  mov    0xc(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mod_inc_ipt@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L24
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <valIth_gseq@plt>
  mov    0x10(%rsp),%r13d
  cmp    %r12d,%r13d
  je     L7
  lea    0x14(%rsp),%rdi
  mov    %r13d,%esi
  xor    %eax,%eax
  call   <val_abs2conc@plt>
  mov    0x14(%rsp),%esi
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <cre_abs2conc@plt>
  mov    %r12d,%edx
L25:
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <push_a2c@plt>
  mov    0x8(%rsp),%eax
  jmp    L24
L7:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <make_Abs2Conc@plt>
  mov    0x14(%rsp),%esi
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <cre_abs2conc@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  jne    L24
  mov    %r13d,%edx
  jmp    L25
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void analyse(rep, cc) int *rep, cc;
{
  int st, rr, ss, bb, cc1, ac;
  val_curMRIState(&st, cc);
  mod_anl(st, 1);
  val_cptMRIState(&st, cc);
  mod_anl(st, 1);
  cre_sees_uses(&rr, cc);
  if (rr == 1) {
    cre_inc_ipt(&rr, cc);
    if (rr == 1) {
      val_gset1(&ss);
      mod_sees_uses(&rr, cc, ss);
      if (rr == 1) {
        val_gset2(&ss);
        mod_inc_ipt(&rr, cc, ss);
        if (rr == 1) {
          valIth_gseq(&cc1, 1);
          if (cc1 != cc) {
            val_abs2conc(&ac, cc1);
            cre_abs2conc(cc, ac);
            push_a2c(&rr, ac, cc);
          } else {
            make_Abs2Conc(&rr, &ac);
            cre_abs2conc(cc, ac);
            if (rr == 1) {
              push_a2c(&rr, ac, cc);
            }
          }
        }
      }
    }
  }
  *rep = rr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xb0(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <setString@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <setString@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <getString@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <getString@plt>
  lea    -0x60(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <first_instance@plt>
  cmp    $0xffffffff,%eax
  je     L21
  lea    -0x60(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <first_instance@plt>
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L21:
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L11:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D41
data_type: string
name: extract_symbolic_data
arguments: label: D35
data_type: string
name: extract_symbolic_data
arguments: label: D47
data_type: string
name: extract_symbolic_data
arguments: label: D54
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string

tool: D12: enter a string A (< 80 chars): 

tool: D41: enter a string B (< 80 chars): 

tool: D35: String A: 

tool: D47: 
String B: 

tool: D54: 
string B offset %d chars from beginning of A

tool: D31: 
String B can not be found in string A

assistant: ```c
void main() {
  char a[80], b[80];
  printf("enter a string A (< 80 chars): ");
  setString(a, 80);
  printf("enter a string B (< 80 chars): ");
  setString(b, 80);
  printf("String A: ");
  getString(a);
  printf("\nString B: ");
  getString(b);
  (first_instance(a, b) != -1) ? printf("\nstring B offset %d chars from beginning of A", first_instance(a, b)) : printf("\nString B can not be found in string A");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    $0x50,%esi
  mov    %rbx,%rdi
  call   <setString@plt>
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x50(%rsp),%rbp
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <setString@plt>
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <getString@plt>
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <getString@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <first_instance@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  call   <first_instance@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L17
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D58
datatype: string
name: unpack_data
arguments: data_label: D17
datatype: string
name: unpack_data
arguments: data_label: D35
datatype: string
name: unpack_data
arguments: data_label: D39
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string

tool: D58: enter a string A (< 80 chars): 

tool: D17: enter a string B (< 80 chars): 

tool: D35: String A: 

tool: D39: 
String B: 

tool: D14: 
string B offset %d chars from beginning of A

tool: D16: 
String B can not be found in string A

assistant: ```c
void main() {
  char a[80], b[80];
  printf("enter a string A (< 80 chars): ");
  setString(a, 80);
  printf("enter a string B (< 80 chars): ");
  setString(b, 80);
  printf("String A: ");
  getString(a);
  printf("\nString B: ");
  getString(b);
  (first_instance(a, b) != -1) ? printf("\nstring B offset %d chars from beginning of A", first_instance(a, b)) : printf("\nString B can not be found in string A");
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  push   %rbp
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x50(%rsp),%r12
  call   <printf@plt>
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <setString@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x50,%esi
  mov    %r12,%rdi
  call   <setString@plt>
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <getString@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <getString@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <first_instance@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <first_instance@plt>
  lea    D43(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L13:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xb8,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D59
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D43
data_type: string
name: parse_data
arguments: data_tag: D46
data_type: string

tool: D24: enter a string A (< 80 chars): 

tool: D31: enter a string B (< 80 chars): 

tool: D59: String A: 

tool: D17: 
String B: 

tool: D43: 
string B offset %d chars from beginning of A

tool: D46: 
String B can not be found in string A

assistant: ```c
void main() {
  char a[80], b[80];
  printf("enter a string A (< 80 chars): ");
  setString(a, 80);
  printf("enter a string B (< 80 chars): ");
  setString(b, 80);
  printf("String A: ");
  getString(a);
  printf("\nString B: ");
  getString(b);
  (first_instance(a, b) != -1) ? printf("\nstring B offset %d chars from beginning of A", first_instance(a, b)) : printf("\nString B can not be found in string A");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D49(%rip),%rdi
  push   %rbp
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x50(%rsp),%r12
  call   <printf@plt>
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <setString@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x50,%esi
  mov    %r12,%rdi
  call   <setString@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <getString@plt>
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <getString@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <first_instance@plt>
  cmp    $0xffffffff,%eax
  je     L26
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <first_instance@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xb8,%rsp
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L2
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D49
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D35
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D47
type_infered: string

tool: D49: enter a string A (< 80 chars): 

tool: D32: enter a string B (< 80 chars): 

tool: D26: String A: 

tool: D35: 
String B: 

tool: D29: 
string B offset %d chars from beginning of A

tool: D47: 
String B can not be found in string A

assistant: ```c
void main() {
  char a[80], b[80];
  printf("enter a string A (< 80 chars): ");
  setString(a, 80);
  printf("enter a string B (< 80 chars): ");
  setString(b, 80);
  printf("String A: ");
  getString(a);
  printf("\nString B: ");
  getString(b);
  (first_instance(a, b) != -1) ? printf("\nstring B offset %d chars from beginning of A", first_instance(a, b)) : printf("\nString B can not be found in string A");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<display_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: nanddump $Revision: 4848 $

nanddump comes with NO WARRANTY
to the extent permitted by law.

You may redistribute copies of nanddump
under the terms of the GNU General Public Licence.
See the file `COPYING' for more information.


assistant: ```c
void display_version(void) {
  printf("nanddump"
         " "
         "$Revision: 4848 $"
         "\n"
         "\n"
         "nanddump"
         " comes with NO WARRANTY\n"
         "to the extent permitted by law.\n"
         "\n"
         "You may redistribute copies of "
         "nanddump"
         "\n"
         "under the terms of the GNU General Public Licence.\n"
         "See the file `COPYING' for more information.\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: nanddump $Revision: 4848 $

nanddump comes with NO WARRANTY
to the extent permitted by law.

You may redistribute copies of nanddump
under the terms of the GNU General Public Licence.
See the file `COPYING' for more information.


assistant: ```c
void display_version(void) {
  printf("nanddump"
         " "
         "$Revision: 4848 $"
         "\n"
         "\n"
         "nanddump"
         " comes with NO WARRANTY\n"
         "to the extent permitted by law.\n"
         "\n"
         "You may redistribute copies of "
         "nanddump"
         "\n"
         "under the terms of the GNU General Public Licence.\n"
         "See the file `COPYING' for more information.\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<display_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: nanddump $Revision: 4848 $

nanddump comes with NO WARRANTY
to the extent permitted by law.

You may redistribute copies of nanddump
under the terms of the GNU General Public Licence.
See the file `COPYING' for more information.


assistant: ```c
void display_version(void) {
  printf("nanddump"
         " "
         "$Revision: 4848 $"
         "\n"
         "\n"
         "nanddump"
         " comes with NO WARRANTY\n"
         "to the extent permitted by law.\n"
         "\n"
         "You may redistribute copies of "
         "nanddump"
         "\n"
         "under the terms of the GNU General Public Licence.\n"
         "See the file `COPYING' for more information.\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: nanddump $Revision: 4848 $

nanddump comes with NO WARRANTY
to the extent permitted by law.

You may redistribute copies of nanddump
under the terms of the GNU General Public Licence.
See the file `COPYING' for more information.


assistant: ```c
void display_version(void) {
  printf("nanddump"
         " "
         "$Revision: 4848 $"
         "\n"
         "\n"
         "nanddump"
         " comes with NO WARRANTY\n"
         "to the extent permitted by law.\n"
         "\n"
         "You may redistribute copies of "
         "nanddump"
         "\n"
         "under the terms of the GNU General Public Licence.\n"
         "See the file `COPYING' for more information.\n");
  exit(0);
}
```