ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<devnum2devname>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fmt_devname@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x70,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *devnum2devname(int num) {
  char name[100];
  fmt_devname(name, num);
  return strdup(name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_write_decimal_100>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  sar    $0x6,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_write_decimal@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void _write_decimal_100(uint16_t value) {
  uint8_t decimal_100 = (value % 1000) / 100;
  if (decimal_100 != 0) {
    _write_decimal(decimal_100);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_write_decimal_100>:
  endbr64
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  movslq %eax,%rdi
  test   %rdi,%rdi
  jne    L1
  ret
L1:
  sub    $0x8,%rsp
  call   <_write_decimal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _write_decimal_100(uint16_t value) {
  uint8_t decimal_100 = (value % 1000) / 100;
  if (decimal_100 != 0) {
    _write_decimal(decimal_100);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_write_decimal_100>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sub    %edi,%eax
  jne    L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %eax,%rdi
  jmp    1050 <_write_decimal@plt>
```

assistant: ```c
void _write_decimal_100(uint16_t value) {
  uint8_t decimal_100 = (value % 1000) / 100;
  if (decimal_100 != 0) {
    _write_decimal(decimal_100);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_write_decimal_100>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sub    %edi,%eax
  jne    L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %eax,%rdi
  jmp    1050 <_write_decimal@plt>
```

assistant: ```c
void _write_decimal_100(uint16_t value) {
  uint8_t decimal_100 = (value % 1000) / 100;
  if (decimal_100 != 0) {
    _write_decimal(decimal_100);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<movzbl_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x12345678,%eax
  mov    $0x22,%al
  movzbl %al,%eax
  mov    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int movzbl_1(void) {
  int res;
  __asm__ __volatile__("movl $0x12345678, %%eax\n\t"
                       "movb $0x22, %%al\n\t"
                       "movzbl %%al,%%eax\n\t"
                       "mov %%eax, %0"
                       : "=r"(res)
                       :
                       : "eax");
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<movzbl_1>:
  endbr64
  mov    $0x12345678,%eax
  mov    $0x22,%al
  movzbl %al,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int movzbl_1(void) {
  int res;
  __asm__ __volatile__("movl $0x12345678, %%eax\n\t"
                       "movb $0x22, %%al\n\t"
                       "movzbl %%al,%%eax\n\t"
                       "mov %%eax, %0"
                       : "=r"(res)
                       :
                       : "eax");
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<movzbl_1>:
  endbr64
  mov    $0x12345678,%eax
  mov    $0x22,%al
  movzbl %al,%eax
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int movzbl_1(void) {
  int res;
  __asm__ __volatile__("movl $0x12345678, %%eax\n\t"
                       "movb $0x22, %%al\n\t"
                       "movzbl %%al,%%eax\n\t"
                       "mov %%eax, %0"
                       : "=r"(res)
                       :
                       : "eax");
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L9
L19:
  mov    $0xffffffffffffffff,%rax
L9:
  leave
  ret
```

assistant: ```c
extern long long str_idx(const char *s, const char *seq) {
  char *pos = strstr(s, seq);
  return (pos == NULL) ? -1 : pos - s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_idx>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
  sub    %rbx,%rax
L12:
  pop    %rbx
  ret
L3:
  mov    $0xffffffffffffffff,%rax
  jmp    L12
```

assistant: ```c
extern long long str_idx(const char *s, const char *seq) {
  char *pos = strstr(s, seq);
  return (pos == NULL) ? -1 : pos - s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_idx>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L0
  sub    %rbx,%rax
  pop    %rbx
  ret
L0:
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  ret
```

assistant: ```c
extern long long str_idx(const char *s, const char *seq) {
  char *pos = strstr(s, seq);
  return (pos == NULL) ? -1 : pos - s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_idx>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
  sub    %rbx,%rax
  pop    %rbx
  ret
L3:
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  ret
```

assistant: ```c
extern long long str_idx(const char *s, const char *seq) {
  char *pos = strstr(s, seq);
  return (pos == NULL) ? -1 : pos - s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<syck_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *syck_strndup(char *buf, long len) {
  char *new = (char *)malloc(sizeof(char) * (len + 1));
  memset((new), 0, sizeof(char) * (len + 1));
  memcpy((new), (buf), sizeof(char) * (len));
  return new;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<syck_strndup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    0x1(%rsi),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *syck_strndup(char *buf, long len) {
  char *new = (char *)malloc(sizeof(char) * (len + 1));
  memset((new), 0, sizeof(char) * (len + 1));
  memcpy((new), (buf), sizeof(char) * (len));
  return new;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<syck_strndup>:
  endbr64
  push   %r13
  lea    0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *syck_strndup(char *buf, long len) {
  char *new = (char *)malloc(sizeof(char) * (len + 1));
  memset((new), 0, sizeof(char) * (len + 1));
  memcpy((new), (buf), sizeof(char) * (len));
  return new;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<syck_strndup>:
  endbr64
  push   %r13
  lea    0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *syck_strndup(char *buf, long len) {
  char *new = (char *)malloc(sizeof(char) * (len + 1));
  memset((new), 0, sizeof(char) * (len + 1));
  memcpy((new), (buf), sizeof(char) * (len));
  return new;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hal_io_IPI_send_eoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hal_io_irq_send_eoi@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hal_io_IPI_send_eoi() {
  hal_io_irq_send_eoi();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hal_io_IPI_send_eoi>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hal_io_irq_send_eoi@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void hal_io_IPI_send_eoi() {
  hal_io_irq_send_eoi();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hal_io_IPI_send_eoi>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <hal_io_irq_send_eoi@plt>
```

assistant: ```c
void hal_io_IPI_send_eoi() {
  hal_io_irq_send_eoi();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<hal_io_IPI_send_eoi>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <hal_io_irq_send_eoi@plt>
```

assistant: ```c
void hal_io_IPI_send_eoi() {
  hal_io_irq_send_eoi();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L14
L24:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L24
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  for (; *str1 && (*str1 == *str2); str1++, str2++)
    ;
  return *(const unsigned char *)str1 - *(const unsigned char *)str2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
L12:
  cmp    %al,(%rsi)
  jne    L19
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
L19:
  movzbl %al,%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  for (; *str1 && (*str1 == *str2); str1++, str2++)
    ;
  return *(const unsigned char *)str1 - *(const unsigned char *)str2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    %al,(%rsi)
  jne    L6
  add    $0x1,%rdi
  add    $0x1,%rsi
L10:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
  xor    %eax,%eax
L6:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  for (; *str1 && (*str1 == *str2); str1++, str2++)
    ;
  return *(const unsigned char *)str1 - *(const unsigned char *)str2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L25:
  cmp    %al,(%rsi)
  jne    L0
  add    $0x1,%rdi
  add    $0x1,%rsi
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L25
  xor    %eax,%eax
L0:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  for (; *str1 && (*str1 == *str2); str1++, str2++)
    ;
  return *(const unsigned char *)str1 - *(const unsigned char *)str2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L59
  mov    $0x0,%edx
  lea    D57(%rip),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L25
L59:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L46
  mov    $0x0,%edx
  lea    D86(%rip),%rax
  mov    %rax,%rsi
  lea    D106(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L25
L46:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  mov    $0x0,%edx
  lea    D57(%rip),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L25
L2:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L25:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D57
datatype: string
name: retrieve_data
arguments: label: D42
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D86
datatype: string
name: retrieve_data
arguments: label: D106
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string

tool: D57: ls

tool: D42: /bin/ls

tool: D28: Error!

tool: D86: pwd

tool: D106: /bin/pwd

tool: D5: Unknown command.

assistant: ```c
int main(int argc, char const *argv[]) {
  if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else if (strcmp("pwd", argv[1]) == 0) {
    execl("/bin/pwd", "pwd", NULL);
    perror("Error!");
  } else if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else
    puts("Unknown command.");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  lea    D104(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x0,%edx
  lea    D104(%rip),%rsi
  lea    D115(%rip),%rdi
  call   <execl@plt>
  lea    D7(%rip),%rdi
  call   <perror@plt>
L47:
  mov    $0x0,%eax
  pop    %rbx
  ret
L11:
  mov    0x8(%rbx),%rsi
  lea    D99(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x0,%edx
  lea    D99(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <execl@plt>
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L47
L13:
  mov    0x8(%rbx),%rsi
  lea    D104(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x0,%edx
  lea    D104(%rip),%rsi
  lea    D115(%rip),%rdi
  call   <execl@plt>
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L47
L19:
  lea    D129(%rip),%rdi
  call   <puts@plt>
  jmp    L47
```

tool_calls: name: read_data
arguments: data_label: D104
type: string
name: read_data
arguments: data_label: D115
type: string
name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D99
type: string
name: read_data
arguments: data_label: D54
type: string
name: read_data
arguments: data_label: D129
type: string

tool: D104: ls

tool: D115: /bin/ls

tool: D7: Error!

tool: D99: pwd

tool: D54: /bin/pwd

tool: D129: Unknown command.

assistant: ```c
int main(int argc, char const *argv[]) {
  if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else if (strcmp("pwd", argv[1]) == 0) {
    execl("/bin/pwd", "pwd", NULL);
    perror("Error!");
  } else if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else
    puts("Unknown command.");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D57(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L35
  lea    D5(%rip),%r12
  mov    0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
  xor    %edx,%edx
  mov    %r12,%rsi
  lea    D39(%rip),%rdi
  call   <execl@plt>
  lea    D34(%rip),%rdi
  call   <perror@plt>
  jmp    L18
L26:
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
L35:
  lea    D25(%rip),%rdi
  xor    %edx,%edx
  mov    %rbp,%rsi
  call   <execl@plt>
  lea    D34(%rip),%rdi
  call   <perror@plt>
L18:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L19:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: data_label: D57
data_type: string
name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D39
data_type: string
name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D25
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D57: ls

tool: D5: pwd

tool: D39: /bin/pwd

tool: D34: Error!

tool: D25: /bin/ls

tool: D19: Unknown command.

assistant: ```c
int main(int argc, char const *argv[]) {
  if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else if (strcmp("pwd", argv[1]) == 0) {
    execl("/bin/pwd", "pwd", NULL);
    perror("Error!");
  } else if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else
    puts("Unknown command.");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D68(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L0
  lea    D8(%rip),%r12
  mov    0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L33
  xor    %edx,%edx
  mov    %r12,%rsi
  lea    D49(%rip),%rdi
  call   <execl@plt>
  lea    D20(%rip),%rdi
  call   <perror@plt>
  jmp    L18
L33:
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
L0:
  lea    D60(%rip),%rdi
  xor    %edx,%edx
  mov    %rbp,%rsi
  call   <execl@plt>
  lea    D20(%rip),%rdi
  call   <perror@plt>
L18:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L19:
  lea    D61(%rip),%rdi
  call   <puts@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: data_label: D68
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D49
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D60
type_infered: string
name: retrieve_data
arguments: data_label: D61
type_infered: string

tool: D68: ls

tool: D8: pwd

tool: D49: /bin/pwd

tool: D20: Error!

tool: D60: /bin/ls

tool: D61: Unknown command.

assistant: ```c
int main(int argc, char const *argv[]) {
  if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else if (strcmp("pwd", argv[1]) == 0) {
    execl("/bin/pwd", "pwd", NULL);
    perror("Error!");
  } else if (strcmp("ls", argv[1]) == 0) {
    execl("/bin/ls", "ls", NULL);
    perror("Error!");
  } else
    puts("Unknown command.");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x6,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x11,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x9,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xa,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0xf,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t hashint(uint32_t a) {
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hashint>:
  endbr64
  mov    %edi,%edx
  shl    $0x6,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  mov    %eax,%edi
  sar    $0x11,%edi
  xor    %eax,%edi
  mov    %edi,%eax
  shl    $0x9,%eax
  sub    %eax,%edi
  mov    %edi,%eax
  shl    $0x4,%eax
  xor    %edi,%eax
  lea    0x0(,%rax,8),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0xa,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0xf,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hashint(uint32_t a) {
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashint>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x6,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  sar    $0x11,%edi
  xor    %eax,%edi
  mov    %edi,%eax
  shl    $0x9,%eax
  sub    %eax,%edi
  mov    %edi,%eax
  shl    $0x4,%eax
  xor    %edi,%eax
  lea    0x0(,%rax,8),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0xa,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0xf,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hashint(uint32_t a) {
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hashint>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x6,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  sar    $0x11,%edi
  xor    %eax,%edi
  mov    %edi,%eax
  shl    $0x9,%eax
  sub    %eax,%edi
  mov    %edi,%eax
  shl    $0x4,%eax
  xor    %edi,%eax
  lea    0x0(,%rax,8),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0xa,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0xf,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hashint(uint32_t a) {
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```