ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x18(%rsp)
  call   <productExceptSelf@plt>
  mov    %rax,%rbp
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L8
  xor    %ebx,%ebx
  lea    D2(%rip),%r12
L7:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L7
L8:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {1, 2, 3, 4};
  int len, i;
  int *res = productExceptSelf(a, 4, &len);
  for (i = 0; i < len; i++) {
    printf("%d ", res[i]);
  }
  free(res);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  call   <productExceptSelf@plt>
  mov    %rax,%rbp
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L15
  xor    %ebx,%ebx
  lea    D17(%rip),%r12
  nopl   0x0(%rax)
L22:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L22
L15:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: byte[16]
name: retrieve_data
arguments: tag: D17
type: string

tool: {"D11": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D17: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {1, 2, 3, 4};
  int len, i;
  int *res = productExceptSelf(a, 4, &len);
  for (i = 0; i < len; i++) {
    printf("%d ", res[i]);
  }
  free(res);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %esi,%r10d
  mov    %edx,%r9d
  mov    %ecx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %ecx,%eax
  sub    %esi,%eax
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L14:
  cmp    %rcx,%rsp
  je     L134
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L134:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L138
  orq    $0x0,-0x8(%rsp,%rax,1)
L138:
  mov    %rsp,%r11
  lea    0x1(%r9),%esi
  cmp    %r9d,%r10d
  jle    L83
  cmp    %esi,%edx
  jl     L6
L83:
  mov    %r11,%rcx
  mov    %r10d,%eax
  jmp    L141
L80:
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  lea    0x1(%rax),%eax
L27:
  mov    %edi,(%rcx)
  add    $0x4,%rcx
  cmp    %r9d,%eax
  jle    L141
  cmp    %edx,%esi
  jg     L6
L141:
  cmp    %esi,%edx
  jl     L80
  cmp    %eax,%r9d
  jl     L118
  movslq %eax,%rdi
  movslq %esi,%rbx
  mov    (%r8,%rbx,4),%ebx
  cmp    %ebx,(%r8,%rdi,4)
  jle    L80
L118:
  movslq %esi,%rdi
  mov    (%r8,%rdi,4),%edi
  lea    0x1(%rsi),%esi
  jmp    L27
L6:
  cmp    %r10d,%edx
  jl     L33
  sub    %r10d,%edx
  movslq %r10d,%r10
  lea    (%r8,%r10,4),%rsi
  mov    $0x0,%eax
L75:
  mov    (%r11,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L75
L33:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  mov    -0x8(%rbp),%rbx
  leave
  ret
L124:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _merge(int *nums, int left, int mid, int right) {
  int t[right - left + 1], k = 0;
  int p = left, q = mid + 1;
  while (p <= mid || q <= right) {
    if (q > right || (p <= mid && nums[p] <= nums[q])) {
      t[k++] = nums[p++];
    } else {
      t[k++] = nums[q++];
    }
  }
  for (int i = left, k = 0; i <= right; i++, k++) {
    nums[i] = t[k];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_merge>:
  endbr64
  push   %rbp
  mov    %esi,%r10d
  mov    %edx,%r8d
  mov    %ecx,%esi
  mov    %rdi,%r9
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %rsp,%rcx
  sub    %r10d,%eax
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L9
L127:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L127
L9:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L74
  mov    %rsp,%r12
  lea    0x1(%r8),%ecx
  cmp    %r8d,%r10d
  jle    L99
L111:
  cmp    %ecx,%esi
  jl     L119
L99:
  mov    %r12,%rdx
  mov    %r10d,%eax
  nopl   (%rax)
L41:
  cmp    %ecx,%esi
  jge    L0
  movslq %eax,%rdi
  mov    (%r9,%rdi,4),%edi
L153:
  add    $0x1,%eax
L39:
  mov    %edi,(%rdx)
  add    $0x4,%rdx
  cmp    %r8d,%eax
  jle    L41
  cmp    %esi,%ecx
  jle    L41
L119:
  cmp    %r10d,%esi
  jl     L61
  sub    %r10d,%esi
  movslq %r10d,%rax
  lea    0x4(,%rsi,4),%rdx
  lea    (%r9,%rax,4),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
L61:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L131
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax)
L0:
  movslq %ecx,%rdi
  mov    (%r9,%rdi,4),%edi
  cmp    %eax,%r8d
  jl     L141
  movslq %eax,%r11
  mov    (%r9,%r11,4),%r11d
  cmp    %edi,%r11d
  jg     L141
  mov    %r11d,%edi
  jmp    L153
  nopl   (%rax)
L141:
  add    $0x1,%ecx
  jmp    L39
  nopl   (%rax)
L74:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  mov    %rsp,%r12
  lea    0x1(%r8),%ecx
  cmp    %r8d,%r10d
  jg     L111
  jmp    L99
L131:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _merge(int *nums, int left, int mid, int right) {
  int t[right - left + 1], k = 0;
  int p = left, q = mid + 1;
  while (p <= mid || q <= right) {
    if (q > right || (p <= mid && nums[p] <= nums[q])) {
      t[k++] = nums[p++];
    } else {
      t[k++] = nums[q++];
    }
  }
  for (int i = left, k = 0; i <= right; i++, k++) {
    nums[i] = t[k];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_merge>:
  endbr64
  push   %rbp
  mov    %esi,%r11d
  mov    %edx,%r8d
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %rsp,%rsi
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L152
L148:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L148
L152:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L77
  mov    %rsp,%r12
  lea    0x1(%r8),%edx
  cmp    %r8d,%r11d
  jle    L113
L130:
  cmp    %edx,%ecx
  jl     L137
L113:
  mov    %r12,%rsi
  mov    %r11d,%eax
  mov    $0x1,%r10d
  xchg   %ax,%ax
L149:
  cmp    %edx,%ecx
  jge    L89
  movslq %eax,%rdx
  add    $0x1,%eax
  mov    (%rdi,%rdx,4),%edx
  mov    %edx,(%rsi)
  cmp    %eax,%r8d
  jge    L83
L137:
  cmp    %r11d,%ecx
  jl     L151
  movslq %r11d,%rax
  sub    %r11d,%ecx
  mov    %r12,%rsi
  lea    (%rdi,%rax,4),%rdi
  lea    0x4(,%rcx,4),%rdx
  call   <memcpy@plt>
L151:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L89:
  movslq %edx,%r9
  mov    (%rdi,%r9,4),%r9d
  cmp    %eax,%r8d
  jl     L110
  movslq %eax,%rbx
  mov    (%rdi,%rbx,4),%ebx
  cmp    %r9d,%ebx
  jg     L131
  mov    %ebx,(%rsi)
  add    $0x1,%eax
L93:
  add    $0x1,%r10d
  add    $0x4,%rsi
  jmp    L149
  cs nopw 0x0(%rax,%rax,1)
L110:
  add    $0x1,%edx
  mov    %r9d,(%rsi)
  cmp    %edx,%ecx
  jge    L93
  jmp    L137
  nopl   0x0(%rax)
L83:
  jmp    1080 <_merge.cold>
  nopl   (%rax)
L131:
  mov    %r9d,(%rsi)
  add    $0x1,%edx
  jmp    L93
L77:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  mov    %rsp,%r12
  lea    0x1(%r8),%edx
  cmp    %r8d,%r11d
  jg     L130
  jmp    L113
L109:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _merge(int *nums, int left, int mid, int right) {
  int t[right - left + 1], k = 0;
  int p = left, q = mid + 1;
  while (p <= mid || q <= right) {
    if (q > right || (p <= mid && nums[p] <= nums[q])) {
      t[k++] = nums[p++];
    } else {
      t[k++] = nums[q++];
    }
  }
  for (int i = left, k = 0; i <= right; i++, k++) {
    nums[i] = t[k];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mergeKLists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L9
L34:
  cmpl   $0x1,-0x2c(%rbp)
  jne    L24
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  jmp    L9
L24:
  mov    -0x2c(%rbp),%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mergeKLists>
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <mergeKLists>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <merge2@plt>
L9:
  leave
  ret
```

assistant: ```c
struct ListNode *mergeKLists(struct ListNode **lists, int listsSize) {
  if (!listsSize)
    return (((struct ListNode *)0));
  if (listsSize == 1)
    return (lists[0]);
  int m;
  struct ListNode *h1, *h2;
  m = listsSize >> 1;
  h1 = mergeKLists(lists, m);
  h2 = mergeKLists(lists + m, listsSize - m);
  return (merge2(h1, h2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mergeKLists>:
  endbr64
  test   %esi,%esi
  je     L7
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  cmp    $0x1,%esi
  je     L0
  mov    %esi,%r12d
  sar    %r12d
  mov    %r12d,%esi
  call   <mergeKLists>
  mov    %rax,%r13
  sub    %r12d,%ebx
  mov    %ebx,%esi
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,8),%rdi
  call   <mergeKLists>
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <merge2@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    (%rdi),%rax
  jmp    L9
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct ListNode *mergeKLists(struct ListNode **lists, int listsSize) {
  if (!listsSize)
    return (((struct ListNode *)0));
  if (listsSize == 1)
    return (lists[0]);
  int m;
  struct ListNode *h1, *h2;
  m = listsSize >> 1;
  h1 = mergeKLists(lists, m);
  h2 = mergeKLists(lists + m, listsSize - m);
  return (merge2(h1, h2));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mergeKLists>:
  endbr64
  test   %esi,%esi
  je     L8
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L11
  mov    %esi,%r12d
  sar    %r12d
  mov    %r12d,%esi
  sub    %r12d,%ebx
  movslq %r12d,%r12
  call   <mergeKLists>
  lea    0x0(%rbp,%r12,8),%rdi
  mov    %ebx,%esi
  mov    %rax,%r13
  call   <mergeKLists>
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  mov    %rax,%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <merge2@plt>
  nopl   0x0(%rax)
L11:
  mov    (%rdi),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct ListNode *mergeKLists(struct ListNode **lists, int listsSize) {
  if (!listsSize)
    return (((struct ListNode *)0));
  if (listsSize == 1)
    return (lists[0]);
  int m;
  struct ListNode *h1, *h2;
  m = listsSize >> 1;
  h1 = mergeKLists(lists, m);
  h2 = mergeKLists(lists + m, listsSize - m);
  return (merge2(h1, h2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L8
L18:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  movss  -0x4(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  subl   $0x1,-0x18(%rbp)
L8:
  cmpl   $0x0,-0x18(%rbp)
  jg     L18
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: f32

tool: D0: 1

assistant: ```c
float power(int a, int exp) {
  float result = 1.0;
  while (exp > 0) {
    result = result * a;
    exp--;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L6
  movss  D9(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
L5:
  mulss  %xmm1,%xmm0
  sub    $0x1,%esi
  jne    L5
  ret
L6:
  movss  D9(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: f32

tool: D9: 1

assistant: ```c
float power(int a, int exp) {
  float result = 1.0;
  while (exp > 0) {
    result = result * a;
    exp--;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L14
  pxor   %xmm1,%xmm1
  movss  D19(%rip),%xmm0
  cvtsi2ss %edi,%xmm1
  nopl   0x0(%rax,%rax,1)
L3:
  mulss  %xmm1,%xmm0
  sub    $0x1,%esi
  jne    L3
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  movss  D19(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type: f32

tool: D19: 1

assistant: ```c
float power(int a, int exp) {
  float result = 1.0;
  while (exp > 0) {
    result = result * a;
    exp--;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L3
  pxor   %xmm1,%xmm1
  movss  D4(%rip),%xmm0
  cvtsi2ss %edi,%xmm1
  nopl   0x0(%rax,%rax,1)
L0:
  mulss  %xmm1,%xmm0
  sub    $0x1,%esi
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  movss  D4(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type: f32

tool: D4: 1

assistant: ```c
float power(int a, int exp) {
  float result = 1.0;
  while (exp > 0) {
    result = result * a;
    exp--;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L51
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L31
L17:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L37
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L37
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L51
L37:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L51:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L17
L31:
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D42
type_infered: string
name: extract_symbolic_data
arguments: data_label: D37
type_infered: string
name: extract_symbolic_data
arguments: data_label: D53
type_infered: string

tool: D14: 
Enter an integer > 

tool: D6: %d

tool: D1: 0

tool: D42: -%d


tool: D37: %d


tool: D53: That's all, have a nice day!

assistant: ```c
int main() {
  int n, t, d;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  printf("\n");
  t = n;
  if (n == 0)
    printf("0\n");
  else
    while (n != 0) {
      d = n % 10;
      n = n / 10;
      if ((t < 0) && (n == 0))
        printf("-%d\n", abs(d));
      else
        printf("%d\n", abs(d));
    }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  lea    D8(%rip),%rbx
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  lea    D44(%rip),%r12
  test   %eax,%eax
  jne    L41
  lea    D43(%rip),%rdi
  call   <puts@plt>
L52:
  lea    D53(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L52
L41:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jne    L56
  test   %bpl,%bpl
  je     L56
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D44
type: string
name: disassemble_data
arguments: tag: D43
type: string
name: disassemble_data
arguments: tag: D53
type: string

tool: D33: 
Enter an integer > 

tool: D19: %d

tool: D8: %d


tool: D44: -%d


tool: D43: 0

tool: D53: That's all, have a nice day!

assistant: ```c
int main() {
  int n, t, d;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  printf("\n");
  t = n;
  if (n == 0)
    printf("0\n");
  else
    while (n != 0) {
      d = n % 10;
      n = n / 10;
      if ((t < 0) && (n == 0))
        printf("-%d\n", abs(d));
      else
        printf("%d\n", abs(d));
    }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D51(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L52
  mov    %edx,%eax
  lea    D52(%rip),%rbx
  lea    D34(%rip),%r12
  shr    $0x1f,%eax
  mov    %eax,%ebp
  jmp    L67
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L47
L67:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,0x4(%rsp)
  add    %ecx,%ecx
  sub    %ecx,%edx
  mov    %edx,%esi
  neg    %esi
  cmovs  %edx,%esi
  test   %eax,%eax
  jne    L33
  test   %bpl,%bpl
  je     L33
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L67
  nopw   0x0(%rax,%rax,1)
L47:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L47
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D51
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D52
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D17: 
Enter an integer > 

tool: D51: %d

tool: D52: %d


tool: D34: -%d


tool: D7: That's all, have a nice day!

tool: D16: 0

assistant: ```c
int main() {
  int n, t, d;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  printf("\n");
  t = n;
  if (n == 0)
    printf("0\n");
  else
    while (n != 0) {
      d = n % 10;
      n = n / 10;
      if ((t < 0) && (n == 0))
        printf("-%d\n", abs(d));
      else
        printf("%d\n", abs(d));
    }
  printf("That's all, have a nice day!\n");
  return (0);
}
```