ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ILLutil_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L20
  mov    -0x4(%rbp),%eax
  jmp    L29
L20:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L36
  mov    $0xffffffff,%eax
L29:
  leave
  ret
```

assistant: ```c
int ILLutil_index(const char *list[], const char *name) {
  int i;
  for (i = 0; list[i] != NULL; i++) {
    if (!strcmp(name, list[i])) {
      return i;
    }
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ILLutil_index>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L10
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L16:
  mov    %ebx,%r13d
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L37
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rsi
  test   %rsi,%rsi
  jne    L16
  mov    $0xffffffff,%r13d
L37:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    $0xffffffff,%r13d
  jmp    L37
```

assistant: ```c
int ILLutil_index(const char *list[], const char *name) {
  int i;
  for (i = 0; list[i] != NULL; i++) {
    if (!strcmp(name, list[i])) {
      return i;
    }
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ILLutil_index>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L20
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L11
L9:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L20
L11:
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L9
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ILLutil_index(const char *list[], const char *name) {
  int i;
  for (i = 0; list[i] != NULL; i++) {
    if (!strcmp(name, list[i])) {
      return i;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ILLutil_index>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L5
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L21
L12:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L5
L21:
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L12
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ILLutil_index(const char *list[], const char *name) {
  int i;
  for (i = 0; list[i] != NULL; i++) {
    if (!strcmp(name, list[i])) {
      return i;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pass_size_as1@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pass_size_unsigned_as1@plt>
  nop
  leave
  ret
```

assistant: ```c
void test16(__attribute__((address_space(1))) unsigned *I) {
  pass_size_as1(I);
  pass_size_unsigned_as1(I);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test16>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <pass_size_as1@plt>
  mov    %rbx,%rdi
  call   <pass_size_unsigned_as1@plt>
  pop    %rbx
  ret
```

assistant: ```c
void test16(__attribute__((address_space(1))) unsigned *I) {
  pass_size_as1(I);
  pass_size_unsigned_as1(I);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <pass_size_as1@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <pass_size_unsigned_as1@plt>
```

assistant: ```c
void test16(__attribute__((address_space(1))) unsigned *I) {
  pass_size_as1(I);
  pass_size_unsigned_as1(I);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <pass_size_as1@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <pass_size_unsigned_as1@plt>
```

assistant: ```c
void test16(__attribute__((address_space(1))) unsigned *I) {
  pass_size_as1(I);
  pass_size_unsigned_as1(I);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<d_zeros_align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  lea    -0x18(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L32
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L32:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L6
L31:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x20(%rbp)
L6:
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L31
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: Memory allocation error

assistant: ```c
void d_zeros_align(double **pA, int row, int col) {
  void *temp;
  int err = posix_memalign(&temp, 64, (row * col) * sizeof(double));
  if (err != 0) {
    printf("Memory allocation error");
    exit(1);
  }
  *pA = temp;
  double *A = *pA;
  int i;
  for (i = 0; i < row * col; i++)
    A[i] = 0.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<d_zeros_align>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%ebx
  imul   %edx,%ebx
  lea    0x0(,%rbx,8),%edx
  mov    %rsp,%rdi
  mov    $0x40,%esi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L8
L11:
  mov    (%rsp),%rdx
  mov    %rdx,0x0(%rbp)
  test   %ebx,%ebx
  jle    L27
  mov    %rdx,%rax
  lea    -0x1(%rbx),%ecx
  lea    0x8(%rdx,%rcx,8),%rdx
L31:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L31
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L11
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: Memory allocation error

assistant: ```c
void d_zeros_align(double **pA, int row, int col) {
  void *temp;
  int err = posix_memalign(&temp, 64, (row * col) * sizeof(double));
  if (err != 0) {
    printf("Memory allocation error");
    exit(1);
  }
  *pA = temp;
  double *A = *pA;
  int i;
  for (i = 0; i < row * col; i++)
    A[i] = 0.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<d_zeros_align>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x40,%esi
  imul   %edx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rbx,8),%edx
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L34
L30:
  mov    (%rsp),%rdi
  mov    %rdi,0x0(%rbp)
  test   %ebx,%ebx
  jle    L39
  movslq %ebx,%rdx
  xor    %esi,%esi
  shl    $0x3,%rdx
  call   <memset@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L30
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Memory allocation error

assistant: ```c
void d_zeros_align(double **pA, int row, int col) {
  void *temp;
  int err = posix_memalign(&temp, 64, (row * col) * sizeof(double));
  if (err != 0) {
    printf("Memory allocation error");
    exit(1);
  }
  *pA = temp;
  double *A = *pA;
  int i;
  for (i = 0; i < row * col; i++)
    A[i] = 0.0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<d_zeros_align>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x40,%esi
  imul   %edx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rbx,8),%edx
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L9
L19:
  mov    (%rsp),%rdi
  mov    %rdi,0x0(%rbp)
  test   %ebx,%ebx
  jle    L21
  movslq %ebx,%rdx
  xor    %esi,%esi
  shl    $0x3,%rdx
  call   <memset@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: Memory allocation error

assistant: ```c
void d_zeros_align(double **pA, int row, int col) {
  void *temp;
  int err = posix_memalign(&temp, 64, (row * col) * sizeof(double));
  if (err != 0) {
    printf("Memory allocation error");
    exit(1);
  }
  *pA = temp;
  double *A = *pA;
  int i;
  for (i = 0; i < row * col; i++)
    A[i] = 0.0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UTIL_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L16:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t UTIL_atoi(char *a, uint8_t aLength) {
  uint8_t value = 0;
  uint8_t i;
  for (i = 0; i < aLength; i++) {
    value = (value * 10) + (a[i] - '0');
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UTIL_atoi>:
  endbr64
  test   %esi,%esi
  jle    L28
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    $0x0,%edx
L27:
  lea    (%rdx,%rdx,4),%ecx
  movsbl (%rax),%edx
  lea    -0x30(%rdx,%rcx,2),%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L27
L14:
  mov    %edx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
uint8_t UTIL_atoi(char *a, uint8_t aLength) {
  uint8_t value = 0;
  uint8_t i;
  for (i = 0; i < aLength; i++) {
    value = (value * 10) + (a[i] - '0');
  }
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<UTIL_atoi>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  lea    (%rax,%rax,4),%edx
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%eax
  cmp    %rcx,%rdi
  jne    L5
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t UTIL_atoi(char *a, uint8_t aLength) {
  uint8_t value = 0;
  uint8_t i;
  for (i = 0; i < aLength; i++) {
    value = (value * 10) + (a[i] - '0');
  }
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UTIL_atoi>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  lea    (%rax,%rax,4),%edx
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%eax
  cmp    %rdi,%rcx
  jne    L7
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t UTIL_atoi(char *a, uint8_t aLength) {
  uint8_t value = 0;
  uint8_t i;
  for (i = 0; i < aLength; i++) {
    value = (value * 10) + (a[i] - '0');
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getScores>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D12: Score from judge %d? 

tool: D13: %lf

assistant: ```c
void getScores(int judgeNo, double scores[]) {
  for (int n = 0; n < judgeNo; n++) {
    printf("Score from judge %d? ", (n + 1));
    scanf("%lf", &scores[n]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getScores>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r14
  lea    D11(%rip),%r13
L4:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x8,%rbp
  cmp    %r12d,%ebx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string

tool: D4: Score from judge %d? 

tool: D11: %lf

assistant: ```c
void getScores(int judgeNo, double scores[]) {
  for (int n = 0; n < judgeNo; n++) {
    printf("Score from judge %d? ", (n + 1));
    scanf("%lf", &scores[n]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getScores>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L16:
  add    $0x1,%ebx
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x8,%rbp
  call   <scanf@plt>
  cmp    %r12d,%ebx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D5: Score from judge %d? 

tool: D0: %lf

assistant: ```c
void getScores(int judgeNo, double scores[]) {
  for (int n = 0; n < judgeNo; n++) {
    printf("Score from judge %d? ", (n + 1));
    scanf("%lf", &scores[n]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getScores>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebx
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x8,%rbp
  call   <scanf@plt>
  cmp    %r12d,%ebx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string

tool: D10: Score from judge %d? 

tool: D0: %lf

assistant: ```c
void getScores(int judgeNo, double scores[]) {
  for (int n = 0; n < judgeNo; n++) {
    printf("Score from judge %d? ", (n + 1));
    scanf("%lf", &scores[n]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rtnl_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L15
L29:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L12
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
L12:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <RTA_NEXT@plt>
  mov    %rax,-0x18(%rbp)
L15:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <RTA_OK@plt>
  test   %rax,%rax
  jne    L29
  nop
  nop
  leave
  ret
```

assistant: ```c
void rtnl_parse(struct rtattr *tb[], int max, struct rtattr *rta, int len) {
  memset(tb, 0, sizeof(struct rtattr *) * (max + 1));
  while (RTA_OK(rta, len)) {
    if (rta->rta_type <= max)
      tb[rta->rta_type] = rta;
    rta = RTA_NEXT(rta, len);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rtnl_parse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  lea    0x8(,%rsi,8),%edx
  mov    $0x0,%esi
  call   <memset@plt>
  jmp    L37
L25:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <RTA_NEXT@plt>
  mov    %rax,%rbx
L37:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <RTA_OK@plt>
  test   %rax,%rax
  je     L32
  mov    (%rbx),%eax
  cmp    %r12d,%eax
  jg     L25
  cltq
  mov    %rbx,0x0(%r13,%rax,8)
  jmp    L25
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rtnl_parse(struct rtattr *tb[], int max, struct rtattr *rta, int len) {
  memset(tb, 0, sizeof(struct rtattr *) * (max + 1));
  while (RTA_OK(rta, len)) {
    if (rta->rta_type <= max)
      tb[rta->rta_type] = rta;
    rta = RTA_NEXT(rta, len);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtnl_parse>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  lea    0x8(,%rsi,8),%edx
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  jmp    L22
  nopl   0x0(%rax)
L3:
  movslq 0x0(%rbp),%rax
  cmp    %ebx,%eax
  jg     L19
  mov    %rbp,(%r12,%rax,8)
L19:
  mov    %rbp,%rdi
  mov    %r13d,%esi
  call   <RTA_NEXT@plt>
  mov    %rax,%rbp
L22:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <RTA_OK@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rtnl_parse(struct rtattr *tb[], int max, struct rtattr *rta, int len) {
  memset(tb, 0, sizeof(struct rtattr *) * (max + 1));
  while (RTA_OK(rta, len)) {
    if (rta->rta_type <= max)
      tb[rta->rta_type] = rta;
    rta = RTA_NEXT(rta, len);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtnl_parse>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  lea    0x8(,%rsi,8),%edx
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  jmp    L23
  nopl   0x0(%rax)
L6:
  movslq 0x0(%rbp),%rax
  cmp    %ebx,%eax
  jg     L3
  mov    %rbp,(%r12,%rax,8)
L3:
  mov    %rbp,%rdi
  mov    %r13d,%esi
  call   <RTA_NEXT@plt>
  mov    %rax,%rbp
L23:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <RTA_OK@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rtnl_parse(struct rtattr *tb[], int max, struct rtattr *rta, int len) {
  memset(tb, 0, sizeof(struct rtattr *) * (max + 1));
  while (RTA_OK(rta, len)) {
    if (rta->rta_type <= max)
      tb[rta->rta_type] = rta;
    rta = RTA_NEXT(rta, len);
  }
}
```