ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
L19:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x14,%r12
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L19
  xor    %ebx,%ebx
  lea    D24(%rip),%r12
L6:
  add    $0x1,%ebx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  add    $0x14,%rbp
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L6
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string
name: unpack_data
arguments: data_label: D11
type_infered: string
name: unpack_data
arguments: data_label: D24
type_infered: string

tool: D9: Please enter name number %i: 

tool: D11: %s

tool: D24: Name number %i is %s:


assistant: ```c
int main() {
  char listOfNames[5][20];
  for (int i = 0; i < 5; i++) {
    printf("Please enter name number %i: ", i + 1);
    scanf("%s", listOfNames[i]);
  }
  for (int i = 0; i < 5; i++) {
    printf("Name number %i is %s:\n", i + 1, listOfNames[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ThrowException>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D2: Exception Thrown: 

tool: D12:           %s


assistant: ```c
void ThrowException(char const *errorMessage) {
  printf("Exception Thrown: \n");
  printf("          %s\n", errorMessage);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ThrowException>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D6: Exception Thrown: 

tool: D17:           %s


assistant: ```c
void ThrowException(char const *errorMessage) {
  printf("Exception Thrown: \n");
  printf("          %s\n", errorMessage);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ThrowException>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string

tool: D2: Exception Thrown: 

tool: D18:           %s


assistant: ```c
void ThrowException(char const *errorMessage) {
  printf("Exception Thrown: \n");
  printf("          %s\n", errorMessage);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ThrowException>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D10: Exception Thrown: 

tool: D1:           %s


assistant: ```c
void ThrowException(char const *errorMessage) {
  printf("Exception Thrown: \n");
  printf("          %s\n", errorMessage);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<append_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
void *append_bytes(void *buffer_ptr, void *src_ptr, int num_bytes) {
  memcpy(buffer_ptr, src_ptr, num_bytes);
  return buffer_ptr + num_bytes;
}
```
user: What is the c source code of the assembly code below?

```asm
<append_bytes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  call   <memcpy@plt>
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *append_bytes(void *buffer_ptr, void *src_ptr, int num_bytes) {
  memcpy(buffer_ptr, src_ptr, num_bytes);
  return buffer_ptr + num_bytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_bytes>:
  endbr64
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *append_bytes(void *buffer_ptr, void *src_ptr, int num_bytes) {
  memcpy(buffer_ptr, src_ptr, num_bytes);
  return buffer_ptr + num_bytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<append_bytes>:
  endbr64
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *append_bytes(void *buffer_ptr, void *src_ptr, int num_bytes) {
  memcpy(buffer_ptr, src_ptr, num_bytes);
  return buffer_ptr + num_bytes;
}
```
user: What is the c source code of the assembly code below?

```asm
<index_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L10
L18:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
int index_of(const char *s, char c) {
  char *s2 = strchr(s, c);
  if (s2 == NULL)
    return -1;
  return s2 - s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<index_of>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  sub    %ebx,%eax
L1:
  pop    %rbx
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int index_of(const char *s, char c) {
  char *s2 = strchr(s, c);
  if (s2 == NULL)
    return -1;
  return s2 - s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<index_of>:
  endbr64
  push   %rbx
  movsbl %sil,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  sub    %ebx,%eax
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int index_of(const char *s, char c) {
  char *s2 = strchr(s, c);
  if (s2 == NULL)
    return -1;
  return s2 - s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<index_of>:
  endbr64
  push   %rbx
  movsbl %sil,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  sub    %ebx,%eax
  pop    %rbx
  ret
L0:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int index_of(const char *s, char c) {
  char *s2 = strchr(s, c);
  if (s2 == NULL)
    return -1;
  return s2 - s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trans>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L20:
  addl   $0x1,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L26
  subl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L37
L26:
  addl   $0x1,-0x8(%rbp)
L37:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4(%rbp)
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void trans(int b[], int c[], int n) {
  int step = n;
  int count = 0;
  int i = 0, j = 0, k;
  for (k = 0; k < n * (n + 1) / 2; k++) {
    count++;
    c[j * (j + 1) / 2 + i] = b[k];
    if (count == step) {
      step--;
      count = 0;
      i++;
      j = n - step;
    } else
      j++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<trans>:
  endbr64
  lea    0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%r10d
  shr    $0x1f,%r10d
  add    %eax,%r10d
  sar    %r10d
  cmp    $0x1,%eax
  jle    L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %edx,%edi
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  jmp    L21
L1:
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jle    L45
L21:
  add    $0x1,%ecx
  lea    0x1(%rax),%esi
  mov    (%r11,%rdx,4),%r8d
  imul   %esi,%eax
  mov    %eax,%r12d
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  add    %r9d,%eax
  cltq
  mov    %r8d,(%rbx,%rax,4)
  mov    %esi,%eax
  cmp    %edi,%ecx
  jne    L1
  sub    $0x1,%edi
  add    $0x1,%r9d
  mov    %ebp,%eax
  sub    %edi,%eax
  mov    $0x0,%ecx
  jmp    L1
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

assistant: ```c
void trans(int b[], int c[], int n) {
  int step = n;
  int count = 0;
  int i = 0, j = 0, k;
  for (k = 0; k < n * (n + 1) / 2; k++) {
    count++;
    c[j * (j + 1) / 2 + i] = b[k];
    if (count == step) {
      step--;
      count = 0;
      i++;
      j = n - step;
    } else
      j++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trans>:
  endbr64
  lea    0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%r10d
  shr    $0x1f,%r10d
  add    %eax,%r10d
  sar    %r10d
  cmp    $0x1,%eax
  jle    L28
  push   %r12
  mov    %edx,%r9d
  mov    %rdi,%r11
  xor    %eax,%eax
  push   %rbp
  xor    %r8d,%r8d
  mov    %edx,%ebp
  xor    %ecx,%ecx
  push   %rbx
  xor    %edx,%edx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L13:
  lea    0x1(%rax),%esi
  mov    (%r11,%rdx,4),%edi
  add    $0x1,%ecx
  imul   %esi,%eax
  mov    %eax,%r12d
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  add    %r8d,%eax
  cltq
  mov    %edi,(%rbx,%rax,4)
  mov    %esi,%eax
  cmp    %r9d,%ecx
  jne    L10
  lea    -0x1(%rcx),%r9d
  mov    %ebp,%eax
  add    $0x1,%r8d
  xor    %ecx,%ecx
  sub    %r9d,%eax
L10:
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jg     L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  ret
```

assistant: ```c
void trans(int b[], int c[], int n) {
  int step = n;
  int count = 0;
  int i = 0, j = 0, k;
  for (k = 0; k < n * (n + 1) / 2; k++) {
    count++;
    c[j * (j + 1) / 2 + i] = b[k];
    if (count == step) {
      step--;
      count = 0;
      i++;
      j = n - step;
    } else
      j++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trans>:
  endbr64
  lea    0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%r10d
  shr    $0x1f,%r10d
  add    %eax,%r10d
  sar    %r10d
  cmp    $0x1,%eax
  jle    L13
  push   %r12
  mov    %edx,%r9d
  mov    %rdi,%r11
  xor    %r12d,%r12d
  push   %rbp
  xor    %r8d,%r8d
  mov    %edx,%ebp
  xor    %ecx,%ecx
  push   %rbx
  xor    %edx,%edx
  mov    %rsi,%rbx
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jle    L24
L45:
  mov    %esi,%r12d
L59:
  lea    0x1(%r12),%esi
  mov    (%r11,%rdx,4),%edi
  add    $0x1,%ecx
  imul   %esi,%r12d
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  add    %r8d,%eax
  cltq
  mov    %edi,(%rbx,%rax,4)
  cmp    %r9d,%ecx
  jne    L35
  lea    -0x1(%rcx),%r9d
  mov    %ebp,%esi
  add    $0x1,%rdx
  add    $0x1,%r8d
  sub    %r9d,%esi
  cmp    %edx,%r10d
  jle    L24
  xor    %ecx,%ecx
  jmp    L45
  xchg   %ax,%ax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L13:
  ret
```

assistant: ```c
void trans(int b[], int c[], int n) {
  int step = n;
  int count = 0;
  int i = 0, j = 0, k;
  for (k = 0; k < n * (n + 1) / 2; k++) {
    count++;
    c[j * (j + 1) / 2 + i] = b[k];
    if (count == step) {
      step--;
      count = 0;
      i++;
      j = n - step;
    } else
      j++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sha1_extract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write32_be@plt>
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write32_be@plt>
  mov    -0x10(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write32_be@plt>
  mov    -0x10(%rbp),%rax
  lea    0x30(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write32_be@plt>
  mov    -0x10(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write32_be@plt>
  nop
  leave
  ret
```

assistant: ```c
void sha1_extract(SHA_CTX *restrict ctx, uint8_t *restrict out) {
  write32_be(ctx->h0, out);
  write32_be(ctx->h1, out + 4);
  write32_be(ctx->h2, out + 8);
  write32_be(ctx->h3, out + 12);
  write32_be(ctx->h4, out + 16);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sha1_extract>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    0x10(%rdi),%edi
  call   <write32_be@plt>
  lea    0x10(%rbx),%rsi
  mov    0xc(%rbp),%edi
  call   <write32_be@plt>
  lea    0x20(%rbx),%rsi
  mov    0x8(%rbp),%edi
  call   <write32_be@plt>
  lea    0x30(%rbx),%rsi
  mov    0x4(%rbp),%edi
  call   <write32_be@plt>
  lea    0x40(%rbx),%rsi
  mov    0x0(%rbp),%edi
  call   <write32_be@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sha1_extract(SHA_CTX *restrict ctx, uint8_t *restrict out) {
  write32_be(ctx->h0, out);
  write32_be(ctx->h1, out + 4);
  write32_be(ctx->h2, out + 8);
  write32_be(ctx->h3, out + 12);
  write32_be(ctx->h4, out + 16);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sha1_extract>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x10(%rdi),%edi
  call   <write32_be@plt>
  mov    0xc(%rbp),%edi
  lea    0x10(%rbx),%rsi
  call   <write32_be@plt>
  mov    0x8(%rbp),%edi
  lea    0x20(%rbx),%rsi
  call   <write32_be@plt>
  mov    0x4(%rbp),%edi
  lea    0x30(%rbx),%rsi
  call   <write32_be@plt>
  mov    0x0(%rbp),%edi
  add    $0x8,%rsp
  lea    0x40(%rbx),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <write32_be@plt>
```

assistant: ```c
void sha1_extract(SHA_CTX *restrict ctx, uint8_t *restrict out) {
  write32_be(ctx->h0, out);
  write32_be(ctx->h1, out + 4);
  write32_be(ctx->h2, out + 8);
  write32_be(ctx->h3, out + 12);
  write32_be(ctx->h4, out + 16);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sha1_extract>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x10(%rdi),%edi
  call   <write32_be@plt>
  mov    0xc(%rbp),%edi
  lea    0x10(%rbx),%rsi
  call   <write32_be@plt>
  mov    0x8(%rbp),%edi
  lea    0x20(%rbx),%rsi
  call   <write32_be@plt>
  mov    0x4(%rbp),%edi
  lea    0x30(%rbx),%rsi
  call   <write32_be@plt>
  mov    0x0(%rbp),%edi
  add    $0x8,%rsp
  lea    0x40(%rbx),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <write32_be@plt>
```

assistant: ```c
void sha1_extract(SHA_CTX *restrict ctx, uint8_t *restrict out) {
  write32_be(ctx->h0, out);
  write32_be(ctx->h1, out + 4);
  write32_be(ctx->h2, out + 8);
  write32_be(ctx->h3, out + 12);
  write32_be(ctx->h4, out + 16);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BigFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <VirtualFree@plt>
  jmp    L16
L5:
  nop
L16:
  leave
  ret
```

assistant: ```c
void BigFree(void *address) {
  if (address == 0)
    return;
  VirtualFree(address);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BigFree>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <VirtualFree@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
void BigFree(void *address) {
  if (address == 0)
    return;
  VirtualFree(address);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BigFree>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <VirtualFree@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void BigFree(void *address) {
  if (address == 0)
    return;
  VirtualFree(address);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BigFree>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <VirtualFree@plt>
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void BigFree(void *address) {
  if (address == 0)
    return;
  VirtualFree(address);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x330(%rbp),%rax
  mov    $0x3e8,%ecx
  mov    $0x0,%edx
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <randomIntArray@plt>
  lea    -0x330(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  lea    -0x330(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <checkAscending@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x330(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <bubbleSort0@plt>
  lea    -0x330(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  lea    -0x330(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <checkAscending@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: After sorting:
***********************


assistant: ```c
void main() {
  int numbers[200];
  randomIntArray(numbers, 200, 0, 1000);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
  printf("After sorting:\n***********************\n");
  bubbleSort0(numbers, 200);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x3e8,%ecx
  mov    $0x0,%edx
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <randomIntArray@plt>
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <checkAscending@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <bubbleSort0@plt>
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <checkAscending@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x330,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: After sorting:
***********************


assistant: ```c
void main() {
  int numbers[200];
  randomIntArray(numbers, 200, 0, 1000);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
  printf("After sorting:\n***********************\n");
  bubbleSort0(numbers, 200);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x3e8,%ecx
  mov    $0xc8,%esi
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <randomIntArray@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <checkAscending@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <bubbleSort0@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <checkAscending@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x330,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: After sorting:
***********************


assistant: ```c
void main() {
  int numbers[200];
  randomIntArray(numbers, 200, 0, 1000);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
  printf("After sorting:\n***********************\n");
  bubbleSort0(numbers, 200);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x3e8,%ecx
  mov    $0xc8,%esi
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <randomIntArray@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <checkAscending@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <bubbleSort0@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <checkAscending@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x330,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: After sorting:
***********************


assistant: ```c
void main() {
  int numbers[200];
  randomIntArray(numbers, 200, 0, 1000);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
  printf("After sorting:\n***********************\n");
  bubbleSort0(numbers, 200);
  printArray(numbers, 200);
  checkAscending(numbers, 200);
}
```