ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<extractShiftMaxFromMask>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L5
  test   $0x1,%dil
  jne    L7
L12:
  xor    %eax,%eax
  xchg   %ax,%ax
L35:
  shr    %rbx
  add    $0x1,%eax
  test   $0x1,%bl
  je     L35
  mov    %ebx,(%r12)
  pop    %rbx
  mov    %eax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D4(%rip),%rdi
  call   <log_fatal@plt>
  jmp    L12
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  mov    %ebx,(%r12)
  pop    %rbx
  mov    %eax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: your display is not true-color one

assistant: ```c
void extractShiftMaxFromMask(unsigned long mask, unsigned *resMax, unsigned *resShift) {
  unsigned shift = 0;
  if (mask == 0)
    log_fatal("your display is not true-color one");
  while ((mask & 1) == 0) {
    mask >>= 1;
    ++shift;
  }
  *resMax = mask;
  *resShift = shift;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vga_on>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x13,%ax
  int    $0x10
  mov    $0xa000,%ax
  mov    %eax,%es
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vga_on() {
  asm volatile("mov   $0x0013, %%ax\n"
               "int   $0x10\n"
               "mov   $0xA000, %%ax\n"
               "mov   %%ax, %%es\n"
               :
               :
               : "ax");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vga_on>:
  endbr64
  mov    $0x13,%ax
  int    $0x10
  mov    $0xa000,%ax
  mov    %eax,%es
  ret
```

assistant: ```c
void vga_on() {
  asm volatile("mov   $0x0013, %%ax\n"
               "int   $0x10\n"
               "mov   $0xA000, %%ax\n"
               "mov   %%ax, %%es\n"
               :
               :
               : "ax");
}
```
user: What is the c source code of the assembly code below?

```asm
<vga_on>:
  endbr64
  mov    $0x13,%ax
  int    $0x10
  mov    $0xa000,%ax
  mov    %eax,%es
  ret
```

assistant: ```c
void vga_on() {
  asm volatile("mov   $0x0013, %%ax\n"
               "int   $0x10\n"
               "mov   $0xA000, %%ax\n"
               "mov   %%ax, %%es\n"
               :
               :
               : "ax");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vga_on>:
  endbr64
  mov    $0x13,%ax
  int    $0x10
  mov    $0xa000,%ax
  mov    %eax,%es
  ret
```

assistant: ```c
void vga_on() {
  asm volatile("mov   $0x0013, %%ax\n"
               "int   $0x10\n"
               "mov   $0xA000, %%ax\n"
               "mov   %%ax, %%es\n"
               :
               :
               : "ax");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<AUXTDCCounterGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t AUXTDCCounterGet(uint32_t ui32Base) {
  ;
  return ((*((volatile unsigned long *)(ui32Base + 0x00000014))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AUXTDCCounterGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    0x14(%rax),%rax
  ret
```

assistant: ```c
uint32_t AUXTDCCounterGet(uint32_t ui32Base) {
  ;
  return ((*((volatile unsigned long *)(ui32Base + 0x00000014))));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<AUXTDCCounterGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    0x14(%rax),%rax
  ret
```

assistant: ```c
uint32_t AUXTDCCounterGet(uint32_t ui32Base) {
  ;
  return ((*((volatile unsigned long *)(ui32Base + 0x00000014))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slurp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x100,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <xrealloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L8
L18:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L17
  mov    -0x18(%rbp),%rax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x10(%rbp)
  shlq   -0x18(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x1c(%rbp)
L8:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L18
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x10(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *slurp(FILE *fp, size_t *final_len) {
  size_t len = 256;
  int c;
  char *l = (char *)xrealloc(NULL, len), *s = l;
  for (c = getc(fp); c != EOF; c = getc(fp)) {
    if (s == l + len) {
      l = (char *)xrealloc(l, len * 2);
      len *= 2;
    }
    *s++ = c;
  }
  if (s == l + len)
    l = (char *)xrealloc(l, len + 1);
  *s++ = '\0';
  *final_len = s - l;
  l = (char *)xrealloc(l, s - l);
  return l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<slurp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,0x8(%rsp)
  mov    $0x100,%esi
  mov    $0x0,%edi
  call   <xrealloc@plt>
  mov    %rax,%r13
  mov    %r15,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D15(%rip),%rax
  cmp    (%rax),%ebx
  je     L17
  mov    %r13,%rbp
  mov    $0x100,%r14d
  jmp    L31
L60:
  lea    0x1(%rbp),%r12
  mov    %bl,0x0(%rbp)
  mov    %r15,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D15(%rip),%rax
  cmp    %ebx,(%rax)
  je     L21
  mov    %r12,%rbp
L31:
  lea    0x0(%r13,%r14,1),%rax
  cmp    %rax,%rbp
  jne    L60
  lea    (%r14,%r14,1),%esi
  mov    %r13,%rdi
  call   <xrealloc@plt>
  mov    %rax,%r13
  add    %r14,%r14
  jmp    L60
L17:
  mov    %r13,%r12
  mov    $0x100,%r14d
L21:
  lea    0x0(%r13,%r14,1),%rax
  cmp    %rax,%r12
  je     L56
L41:
  movb   $0x0,(%r12)
  add    $0x1,%r12
  sub    %r13,%r12
  mov    0x8(%rsp),%rax
  mov    %r12,(%rax)
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <xrealloc@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  lea    0x1(%r14),%esi
  mov    %r13,%rdi
  call   <xrealloc@plt>
  mov    %rax,%r13
  jmp    L41
```

assistant: ```c
char *slurp(FILE *fp, size_t *final_len) {
  size_t len = 256;
  int c;
  char *l = (char *)xrealloc(NULL, len), *s = l;
  for (c = getc(fp); c != EOF; c = getc(fp)) {
    if (s == l + len) {
      l = (char *)xrealloc(l, len * 2);
      len *= 2;
    }
    *s++ = c;
  }
  if (s == l + len)
    l = (char *)xrealloc(l, len + 1);
  *s++ = '\0';
  *final_len = s - l;
  l = (char *)xrealloc(l, s - l);
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<slurp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  mov    $0x100,%esi
  call   <xrealloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <getc@plt>
  mov    D1(%rip),%r13
  cmp    0x0(%r13),%eax
  je     L15
  movq   $0x100,(%rsp)
  mov    %eax,%edx
  mov    %rbp,%rcx
  lea    0x100(%rbp),%r14
  jmp    L24
  nopl   0x0(%rax)
L40:
  mov    %dl,(%rcx)
  mov    %rbx,%rdi
  lea    0x1(%rcx),%r15
  call   <getc@plt>
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  je     L36
  mov    %r15,%rcx
L24:
  mov    %r14,%r12
  cmp    %rcx,%r14
  jne    L40
  mov    (%rsp),%r15
  mov    %rbp,%rdi
  mov    %rcx,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  lea    (%r15,%r15,1),%esi
  add    %r15,%r15
  call   <xrealloc@plt>
  mov    %r15,(%rsp)
  mov    0x10(%rsp),%rcx
  lea    (%rax,%r15,1),%r14
  mov    0xc(%rsp),%edx
  mov    %rax,%rbp
  mov    %r14,%r12
  jmp    L40
  xchg   %ax,%ax
L15:
  movq   $0x100,(%rsp)
  lea    0x100(%rbp),%r12
  mov    %rbp,%r15
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %r15,%r12
  je     L20
L51:
  mov    0x18(%rsp),%rax
  lea    0x1(%r15),%r8
  movb   $0x0,(%r15)
  mov    %rbp,%rdi
  sub    %rbp,%r8
  mov    %r8,(%rax)
  add    $0x28,%rsp
  mov    %r8d,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <xrealloc@plt>
  nopl   0x0(%rax)
L20:
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  add    $0x1,%esi
  call   <xrealloc@plt>
  mov    %rax,%rbp
  jmp    L51
```

assistant: ```c
char *slurp(FILE *fp, size_t *final_len) {
  size_t len = 256;
  int c;
  char *l = (char *)xrealloc(NULL, len), *s = l;
  for (c = getc(fp); c != EOF; c = getc(fp)) {
    if (s == l + len) {
      l = (char *)xrealloc(l, len * 2);
      len *= 2;
    }
    *s++ = c;
  }
  if (s == l + len)
    l = (char *)xrealloc(l, len + 1);
  *s++ = '\0';
  *final_len = s - l;
  l = (char *)xrealloc(l, s - l);
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<slurp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  mov    $0x100,%esi
  call   <xrealloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <getc@plt>
  mov    D9(%rip),%r13
  cmp    0x0(%r13),%eax
  je     L24
  movq   $0x100,(%rsp)
  mov    %eax,%edx
  mov    %rbp,%rcx
  lea    0x100(%rbp),%r14
  jmp    L8
  nopl   0x0(%rax)
L30:
  mov    %dl,(%rcx)
  mov    %rbx,%rdi
  call   <getc@plt>
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  je     L22
  mov    %r15,%rcx
L8:
  mov    %r14,%r12
  lea    0x1(%rcx),%r15
  cmp    %rcx,%r14
  jne    L30
  mov    (%rsp),%r15
  mov    %rbp,%rdi
  mov    %rcx,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  lea    (%r15,%r15,1),%esi
  add    %r15,%r15
  call   <xrealloc@plt>
  mov    0x10(%rsp),%rcx
  mov    %r15,(%rsp)
  lea    (%rax,%r15,1),%r14
  mov    0xc(%rsp),%edx
  mov    %rax,%rbp
  mov    %r14,%r12
  lea    0x1(%rcx),%r15
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L24:
  movq   $0x100,(%rsp)
  lea    0x100(%rbp),%r12
  mov    %rbp,%r15
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    %r15,%r12
  je     L61
L42:
  mov    0x18(%rsp),%rax
  lea    0x1(%r15),%r8
  movb   $0x0,(%r15)
  mov    %rbp,%rdi
  sub    %rbp,%r8
  mov    %r8,(%rax)
  add    $0x28,%rsp
  mov    %r8d,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <xrealloc@plt>
  nopl   0x0(%rax)
L61:
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  add    $0x1,%esi
  call   <xrealloc@plt>
  mov    %rax,%rbp
  jmp    L42
```

assistant: ```c
char *slurp(FILE *fp, size_t *final_len) {
  size_t len = 256;
  int c;
  char *l = (char *)xrealloc(NULL, len), *s = l;
  for (c = getc(fp); c != EOF; c = getc(fp)) {
    if (s == l + len) {
      l = (char *)xrealloc(l, len * 2);
      len *= 2;
    }
    *s++ = c;
  }
  if (s == l + len)
    l = (char *)xrealloc(l, len + 1);
  *s++ = '\0';
  *final_len = s - l;
  l = (char *)xrealloc(l, s - l);
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L62
L84:
  addl   $0x1,-0x14(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jne    L105
  addl   $0x1,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L62
L105:
  cmpl   $0x9,-0x4(%rbp)
  jne    L22
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <columns_to_next_tabstop@plt>
  add    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L62
L22:
  cmpl   $0xa,-0x4(%rbp)
  jne    L21
  movl   $0x0,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L62
L21:
  cmpl   $0x0,-0x8(%rbp)
  jne    L56
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L50:
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <columns_to_next_tabstop@plt>
  add    $0x1,%eax
  add    %eax,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <columns_to_next_tabstop@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L50
  jmp    L107
L122:
  mov    $0x5f,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L107:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L122
  movl   $0x0,-0x10(%rbp)
L56:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L62:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L84
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  int nc;
  int ns;
  int pt;
  int state;
  nc = ns = pt = 0;
  state = 1;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ') {
      ++ns;
      state = 0;
    } else if (c == '\t') {
      nc += columns_to_next_tabstop(nc);
      putchar(c);
    } else if (c == '\n') {
      nc = 0;
      putchar(c);
    } else {
      if (state == 0) {
        state = 1;
        pt = nc - ns;
        while ((pt + columns_to_next_tabstop(pt)) < nc) {
          putchar('\t');
          pt += (columns_to_next_tabstop(pt) + 1);
        }
        while (pt < nc) {
          putchar('_');
          ++pt;
        }
        ns = 0;
      }
      putchar(c);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%r14d
  mov    $0x0,%r15d
  mov    $0x0,%r12d
  jmp    L94
L56:
  add    $0x1,%r15d
  mov    %r13d,%r12d
  mov    $0x0,%r14d
  jmp    L94
L110:
  mov    %r13d,%edi
  call   <columns_to_next_tabstop@plt>
  lea    0x0(%r13,%rax,1),%r12d
  mov    $0x9,%edi
  call   <putchar@plt>
  jmp    L94
L92:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%r12d
  jmp    L94
L32:
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <columns_to_next_tabstop@plt>
  lea    0x1(%rbx,%rax,1),%ebx
L125:
  mov    %ebx,%edi
  call   <columns_to_next_tabstop@plt>
  add    %ebx,%eax
  cmp    %r13d,%eax
  jl     L32
  cmp    %r13d,%ebx
  jge    L129
  add    $0x1,%r12d
L34:
  mov    $0x5f,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L34
  mov    %r14d,%r15d
L116:
  mov    %ebp,%edi
  call   <putchar@plt>
  mov    %r13d,%r12d
  mov    $0x1,%r14d
L94:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  mov    D3(%rip),%rax
  cmp    %ebp,(%rax)
  je     L82
  lea    0x1(%r12),%r13d
  cmp    $0x20,%ebp
  je     L56
  cmp    $0x9,%ebp
  je     L110
  cmp    $0xa,%ebp
  je     L92
  mov    %r13d,%ebx
  sub    %r15d,%ebx
  test   %r14d,%r14d
  jne    L116
  jmp    L125
L129:
  mov    %r14d,%r15d
  jmp    L116
L82:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int main() {
  int c;
  int nc;
  int ns;
  int pt;
  int state;
  nc = ns = pt = 0;
  state = 1;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ') {
      ++ns;
      state = 0;
    } else if (c == '\t') {
      nc += columns_to_next_tabstop(nc);
      putchar(c);
    } else if (c == '\n') {
      nc = 0;
      putchar(c);
    } else {
      if (state == 0) {
        state = 1;
        pt = nc - ns;
        while ((pt + columns_to_next_tabstop(pt)) < nc) {
          putchar('\t');
          pt += (columns_to_next_tabstop(pt) + 1);
        }
        while (pt < nc) {
          putchar('_');
          ++pt;
        }
        ns = 0;
      }
      putchar(c);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  mov    D5(%rip),%r14
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  je     L115
L106:
  lea    0x1(%r12),%r13d
  cmp    $0x20,%ebp
  je     L30
  cmp    $0x9,%ebp
  je     L2
  cmp    $0xa,%ebp
  je     L14
  test   %ebx,%ebx
  je     L92
L101:
  mov    %ebp,%edi
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  jne    L106
L115:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  add    $0x1,%r15d
  mov    %r13d,%r12d
  xor    %ebx,%ebx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r13d,%edi
  call   <columns_to_next_tabstop@plt>
  mov    $0x9,%edi
  lea    0x0(%r13,%rax,1),%r12d
  call   <putchar@plt>
  jmp    L13
  nopl   0x0(%rax)
L92:
  mov    %r13d,%ebx
  sub    %r15d,%ebx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L112:
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <columns_to_next_tabstop@plt>
  lea    0x1(%rbx,%rax,1),%ebx
L41:
  mov    %ebx,%edi
  call   <columns_to_next_tabstop@plt>
  add    %ebx,%eax
  cmp    %r13d,%eax
  jl     L112
  cmp    %r13d,%ebx
  jge    L19
  nopl   0x0(%rax,%rax,1)
L59:
  mov    $0x5f,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jne    L59
L19:
  xor    %r15d,%r15d
  jmp    L101
  nopl   0x0(%rax)
L14:
  mov    $0xa,%edi
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L13
```

assistant: ```c
int main() {
  int c;
  int nc;
  int ns;
  int pt;
  int state;
  nc = ns = pt = 0;
  state = 1;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ') {
      ++ns;
      state = 0;
    } else if (c == '\t') {
      nc += columns_to_next_tabstop(nc);
      putchar(c);
    } else if (c == '\n') {
      nc = 0;
      putchar(c);
    } else {
      if (state == 0) {
        state = 1;
        pt = nc - ns;
        while ((pt + columns_to_next_tabstop(pt)) < nc) {
          putchar('\t');
          pt += (columns_to_next_tabstop(pt) + 1);
        }
        while (pt < nc) {
          putchar('_');
          ++pt;
        }
        ns = 0;
      }
      putchar(c);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  mov    D5(%rip),%r14
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  je     L127
L3:
  lea    0x1(%r12),%r13d
  cmp    $0x20,%ebp
  je     L69
  cmp    $0x9,%ebp
  je     L93
  cmp    $0xa,%ebp
  je     L116
  test   %ebx,%ebx
  je     L112
L52:
  mov    %ebp,%edi
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  jne    L3
L127:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  add    $0x1,%r15d
  mov    %r13d,%r12d
  xor    %ebx,%ebx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %r13d,%edi
  call   <columns_to_next_tabstop@plt>
  mov    $0x9,%edi
  lea    0x0(%r13,%rax,1),%r12d
  call   <putchar@plt>
  jmp    L28
  nopl   0x0(%rax)
L112:
  mov    %r13d,%ebx
  sub    %r15d,%ebx
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L31:
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <columns_to_next_tabstop@plt>
  lea    0x1(%rbx,%rax,1),%ebx
L75:
  mov    %ebx,%edi
  call   <columns_to_next_tabstop@plt>
  add    %ebx,%eax
  cmp    %r13d,%eax
  jl     L31
  cmp    %r13d,%ebx
  jge    L49
  nopl   0x0(%rax,%rax,1)
L83:
  mov    $0x5f,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jne    L83
L49:
  xor    %r15d,%r15d
  jmp    L52
  nopl   0x0(%rax)
L116:
  mov    $0xa,%edi
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L28
```

assistant: ```c
int main() {
  int c;
  int nc;
  int ns;
  int pt;
  int state;
  nc = ns = pt = 0;
  state = 1;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ') {
      ++ns;
      state = 0;
    } else if (c == '\t') {
      nc += columns_to_next_tabstop(nc);
      putchar(c);
    } else if (c == '\n') {
      nc = 0;
      putchar(c);
    } else {
      if (state == 0) {
        state = 1;
        pt = nc - ns;
        while ((pt + columns_to_next_tabstop(pt)) < nc) {
          putchar('\t');
          pt += (columns_to_next_tabstop(pt) + 1);
        }
        while (pt < nc) {
          putchar('_');
          ++pt;
        }
        ns = 0;
      }
      putchar(c);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checkDescending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L15:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L15
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L21
  mov    $0x1,%eax
  jmp    L42
L21:
  mov    $0x0,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int checkDescending(int **board, int player, int board_size) {
  int total = 0;
  int n = 0;
  while (n < board_size && player == board[n][n]) {
    total += 1;
    n += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkDescending>:
  endbr64
  mov    $0x0,%eax
  mov    $0x0,%ecx
  test   %edx,%edx
  jle    L14
L7:
  mov    (%rdi,%rax,2),%r8
  cmp    %esi,(%r8,%rax,1)
  jne    L14
  add    $0x1,%ecx
  add    $0x4,%rax
  cmp    %ecx,%edx
  jne    L7
  mov    %edx,%ecx
L14:
  cmp    %ecx,%edx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int checkDescending(int **board, int player, int board_size) {
  int total = 0;
  int n = 0;
  while (n < board_size && player == board[n][n]) {
    total += 1;
    n += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkDescending>:
  endbr64
  xor    %eax,%eax
  xor    %ecx,%ecx
  test   %edx,%edx
  jg     L24
  jmp    L9
  xchg   %ax,%ax
L26:
  add    $0x1,%ecx
  add    $0x4,%rax
  cmp    %ecx,%edx
  je     L12
L24:
  mov    (%rdi,%rax,2),%r8
  cmp    %esi,(%r8,%rax,1)
  je     L26
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %edx,%eax
L9:
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int checkDescending(int **board, int player, int board_size) {
  int total = 0;
  int n = 0;
  while (n < board_size && player == board[n][n]) {
    total += 1;
    n += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```