user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x84(%rbp)
  lea    -0x88(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L67
L120:
  movl   $0x0,-0x84(%rbp)
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L173
L146:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x61,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x64,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x6f,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x70,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x72,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x41,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x51,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x44,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x50,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x52,%al
  je     L32
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x71,%al
  jne    L41
L32:
  addl   $0x1,-0x84(%rbp)
  jmp    L50
L41:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x62,%al
  je     L45
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x42,%al
  jne    L50
L45:
  addl   $0x2,-0x84(%rbp)
L50:
  addl   $0x1,-0x7c(%rbp)
L173:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L146
  mov    -0x84(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x80(%rbp)
L67:
  mov    -0x88(%rbp),%eax
  cmp    %eax,-0x80(%rbp)
  jl     L120
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D13: %d

tool: D24: %s

tool: D4: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int t;
  int hole = 0;
  scanf("%d", &t);
  for (int i = 0; i < t; i++) {
    hole = 0;
    char str[100];
    int j = 0;
    scanf("%s", str);
    int len = strlen(str);
    for (int i = 0; i < len; i++) {
      if (str[i] == 'a' || str[i] == 'd' || str[i] == 'o' || str[i] == 'p' || str[i] == 'r' || str[i] == 'A' || str[i] == 'Q' || str[i] == 'D' || str[i] == 'O' || str[i] == 'P' || str[i] == 'R' || str[i] == 'q') {
        hole++;
      } else if (str[i] == 'b' || str[i] == 'B') {
        hole = hole + 2;
      }
    }
    printf("%d\n", hole);
  }
  return 0;
}
```