ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getDnaDictionary>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  test   %rdi,%rdi
  je     L15
L7:
  lea    0x8(%r8),%rdi
  mov    %r8,%rcx
  xor    %eax,%eax
  movq   $0x0,(%r8)
  movq   $0x0,0x3f8(%r8)
  and    $0xfffffffffffffff8,%rdi
  movabs $0x200000002,%rdx
  sub    %rdi,%rcx
  add    $0x400,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rdx,0x1c8(%r8)
  movabs $0x100000002,%rax
  mov    %rax,0x188(%r8)
  mov    %rax,0x108(%r8)
  movabs $0x300000003,%rax
  mov    %rax,0x1d0(%r8)
  mov    %rax,0x150(%r8)
  mov    %r8,%rax
  movl   $0x2,0x19c(%r8)
  movl   $0x2,0x11c(%r8)
  movl   $0x3,0x1e4(%r8)
  movl   $0x3,0x164(%r8)
  movl   $0x2,0x1ac(%r8)
  movl   $0x2,0x12c(%r8)
  movl   $0x2,0x190(%r8)
  movl   $0x2,0x110(%r8)
  movl   $0x2,0x1b8(%r8)
  movl   $0x2,0x138(%r8)
  movl   $0x2,0x1d8(%r8)
  mov    %rdx,0x148(%r8)
  movl   $0x2,0x158(%r8)
  add    $0x8,%rsp
  ret
L15:
  mov    $0x404,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  jmp    L7
```

assistant: ```c
int *getDnaDictionary(int *dic) {
  int i;
  if (dic == NULL)
    dic = (int *)malloc((256 + 1) * sizeof(int));
  for (i = 0; i < 256; i++)
    dic[i] = 0;
  dic['a'] = 0;
  dic['c'] = 1;
  dic['g'] = 2;
  dic['t'] = 3;
  dic['A'] = 0;
  dic['C'] = 1;
  dic['G'] = 2;
  dic['T'] = 3;
  dic['r'] = dic['g'];
  dic['R'] = dic['g'];
  dic['y'] = dic['t'];
  dic['Y'] = dic['t'];
  dic['m'] = dic['a'];
  dic['M'] = dic['a'];
  dic['k'] = dic['g'];
  dic['K'] = dic['g'];
  dic['s'] = dic['g'];
  dic['S'] = dic['g'];
  dic['w'] = dic['a'];
  dic['W'] = dic['a'];
  dic['h'] = dic['a'];
  dic['H'] = dic['a'];
  dic['b'] = dic['g'];
  dic['B'] = dic['g'];
  dic['v'] = dic['g'];
  dic['V'] = dic['g'];
  dic['d'] = dic['g'];
  dic['D'] = dic['g'];
  dic['n'] = dic['g'];
  dic['N'] = dic['g'];
  dic['u'] = dic['t'];
  dic['U'] = dic['t'];
  return dic;
}
```
user: What is the c source code of the assembly code below:

```asm
<getDnaDictionary>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  test   %rdi,%rdi
  je     L4
L16:
  lea    0x8(%r8),%rdi
  mov    %r8,%rcx
  xor    %eax,%eax
  movq   $0x0,(%r8)
  and    $0xfffffffffffffff8,%rdi
  movdqa D19(%rip),%xmm0
  movq   $0x0,0x3f8(%r8)
  sub    %rdi,%rcx
  add    $0x400,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    D7(%rip),%rax
  movups %xmm0,0x184(%r8)
  movups %xmm0,0x104(%r8)
  movdqa D14(%rip),%xmm0
  mov    %rax,0x19c(%r8)
  mov    %rax,0x11c(%r8)
  mov    %rax,0x1d8(%r8)
  mov    %rax,0x158(%r8)
  mov    D19(%rip),%rax
  movl   $0x3,0x1e4(%r8)
  mov    %rax,0x1b4(%r8)
  mov    %rax,0x134(%r8)
  mov    %r8,%rax
  movl   $0x3,0x164(%r8)
  movl   $0x2,0x1ac(%r8)
  movl   $0x2,0x12c(%r8)
  movups %xmm0,0x1c8(%r8)
  movups %xmm0,0x148(%r8)
  add    $0x8,%rsp
  ret
L4:
  mov    $0x404,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  jmp    L16
```

tool_calls: name: read_data
arguments: label: D19
data_type: byte[16]
name: read_data
arguments: label: D7
data_type: byte[8]
name: read_data
arguments: label: D14
data_type: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D7": [0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D14": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int *getDnaDictionary(int *dic) {
  int i;
  if (dic == NULL)
    dic = (int *)malloc((256 + 1) * sizeof(int));
  for (i = 0; i < 256; i++)
    dic[i] = 0;
  dic['a'] = 0;
  dic['c'] = 1;
  dic['g'] = 2;
  dic['t'] = 3;
  dic['A'] = 0;
  dic['C'] = 1;
  dic['G'] = 2;
  dic['T'] = 3;
  dic['r'] = dic['g'];
  dic['R'] = dic['g'];
  dic['y'] = dic['t'];
  dic['Y'] = dic['t'];
  dic['m'] = dic['a'];
  dic['M'] = dic['a'];
  dic['k'] = dic['g'];
  dic['K'] = dic['g'];
  dic['s'] = dic['g'];
  dic['S'] = dic['g'];
  dic['w'] = dic['a'];
  dic['W'] = dic['a'];
  dic['h'] = dic['a'];
  dic['H'] = dic['a'];
  dic['b'] = dic['g'];
  dic['B'] = dic['g'];
  dic['v'] = dic['g'];
  dic['V'] = dic['g'];
  dic['d'] = dic['g'];
  dic['D'] = dic['g'];
  dic['n'] = dic['g'];
  dic['N'] = dic['g'];
  dic['u'] = dic['t'];
  dic['U'] = dic['t'];
  return dic;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L33:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L3
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L23
L3:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L33
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int ft_memcmp(const void *s1, const void *s2, size_t n) {
  const unsigned char *cs1;
  const unsigned char *cs2;
  cs1 = (unsigned char *)s1;
  cs2 = (unsigned char *)s2;
  while (n-- > 0) {
    if (*cs1 != *cs2) {
      return (*cs1 - *cs2);
    }
    cs1++;
    cs2++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L0
  mov    $0x0,%eax
L11:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L9
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L11
  mov    $0x0,%eax
  ret
L9:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_memcmp(const void *s1, const void *s2, size_t n) {
  const unsigned char *cs1;
  const unsigned char *cs2;
  cs1 = (unsigned char *)s1;
  cs2 = (unsigned char *)s2;
  while (n-- > 0) {
    if (*cs1 != *cs2) {
      return (*cs1 - *cs2);
    }
    cs1++;
    cs2++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L23
  xor    %eax,%eax
  jmp    L19
  nopl   (%rax)
L20:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L23
L19:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L20
  movzbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_memcmp(const void *s1, const void *s2, size_t n) {
  const unsigned char *cs1;
  const unsigned char *cs2;
  cs1 = (unsigned char *)s1;
  cs2 = (unsigned char *)s2;
  while (n-- > 0) {
    if (*cs1 != *cs2) {
      return (*cs1 - *cs2);
    }
    cs1++;
    cs2++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L19
  xor    %eax,%eax
  jmp    L15
  nopl   (%rax)
L22:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L19
L15:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L22
  movzbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_memcmp(const void *s1, const void *s2, size_t n) {
  const unsigned char *cs1;
  const unsigned char *cs2;
  cs1 = (unsigned char *)s1;
  cs2 = (unsigned char *)s2;
  while (n-- > 0) {
    if (*cs1 != *cs2) {
      return (*cs1 - *cs2);
    }
    cs1++;
    cs2++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gf256_mul_0x2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x55,%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xffffffaa,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  xor    %eax,%edx
  movzbl -0x1(%rbp),%eax
  shr    %al
  xor    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char gf256_mul_0x2(unsigned char a) {
  unsigned char bit0 = a & 0x55;
  unsigned char bit1 = a & 0xaa;
  return (bit0 << 1) ^ bit1 ^ (bit1 >> 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gf256_mul_0x2>:
  endbr64
  mov    %edi,%edx
  and    $0xffffffaa,%edx
  and    $0x55,%edi
  add    %edi,%edi
  mov    %edx,%eax
  shr    %al
  xor    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned char gf256_mul_0x2(unsigned char a) {
  unsigned char bit0 = a & 0x55;
  unsigned char bit1 = a & 0xaa;
  return (bit0 << 1) ^ bit1 ^ (bit1 >> 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<gf256_mul_0x2>:
  endbr64
  mov    %edi,%edx
  and    $0x55,%edi
  and    $0xffffffaa,%edx
  add    %edi,%edi
  mov    %edx,%eax
  shr    %al
  xor    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned char gf256_mul_0x2(unsigned char a) {
  unsigned char bit0 = a & 0x55;
  unsigned char bit1 = a & 0xaa;
  return (bit0 << 1) ^ bit1 ^ (bit1 >> 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gf256_mul_0x2>:
  endbr64
  mov    %edi,%edx
  and    $0x55,%edi
  and    $0xffffffaa,%edx
  add    %edi,%edi
  mov    %edx,%eax
  shr    %al
  xor    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned char gf256_mul_0x2(unsigned char a) {
  unsigned char bit0 = a & 0x55;
  unsigned char bit1 = a & 0xaa;
  return (bit0 << 1) ^ bit1 ^ (bit1 >> 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_be_uint16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L19
  mov    $0x1,%eax
  jmp    L16
L19:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int read_be_uint16(FILE *fp, uint16_t *ptr) {
  uint16_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohs(lv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_be_uint16>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  je     L26
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  mov    0x4(%rsp),%edi
  call   <ntohs@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  jmp    L8
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_be_uint16(FILE *fp, uint16_t *ptr) {
  uint16_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohs(lv);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_be_uint16>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    $0x1,%edx
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  je     L18
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rsp),%edi
  call   <ntohs@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  jmp    L21
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_be_uint16(FILE *fp, uint16_t *ptr) {
  uint16_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohs(lv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_be_uint16>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    $0x1,%edx
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  je     L18
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rsp),%edi
  call   <ntohs@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  jmp    L17
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_be_uint16(FILE *fp, uint16_t *ptr) {
  uint16_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohs(lv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x30332c30322c3031,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x612c,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x13(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <str_get_rowNumber@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: %d

assistant: ```c
int main(void) {
  char array[] = "10,20,30,a";
  printf("%d", str_get_rowNumber(array, ','));
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x30332c30322c3031,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x612c,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xd(%rsp),%rdi
  mov    $0x2c,%esi
  call   <str_get_rowNumber@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main(void) {
  char array[] = "10,20,30,a";
  printf("%d", str_get_rowNumber(array, ','));
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x2c,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x30332c30322c3031,%rax
  lea    0xd(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x612c,%eax
  mov    %ax,0x15(%rsp)
  call   <str_get_rowNumber@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: %d

assistant: ```c
int main(void) {
  char array[] = "10,20,30,a";
  printf("%d", str_get_rowNumber(array, ','));
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x2c,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x30332c30322c3031,%rax
  lea    0xd(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x612c,%eax
  mov    %ax,0x15(%rsp)
  call   <str_get_rowNumber@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main(void) {
  char array[] = "10,20,30,a";
  printf("%d", str_get_rowNumber(array, ','));
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Julian_Date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %eax,%edi
  call   <Julian_Date_of_Year@plt>
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0xc(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <DOY@plt>
  movapd %xmm0,%xmm1
  addsd  -0x20(%rbp),%xmm1
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Fraction_of_Day@plt>
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double Julian_Date(struct tm *cdate) {
  double julian_date;
  julian_date = Julian_Date_of_Year(cdate->tm_year) + DOY(cdate->tm_year, cdate->tm_mon, cdate->tm_mday) + Fraction_of_Day(cdate->tm_hour, cdate->tm_min, cdate->tm_sec);
  return (julian_date);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Julian_Date>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    0x14(%rdi),%edi
  call   <Julian_Date_of_Year@plt>
  movq   %xmm0,%r14
  mov    0xc(%rbx),%edx
  mov    0x10(%rbx),%esi
  mov    0x14(%rbx),%edi
  call   <DOY@plt>
  movq   %r14,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    0x4(%rbx),%esi
  mov    0x8(%rbx),%edi
  mov    (%rbx),%edx
  call   <Fraction_of_Day@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double Julian_Date(struct tm *cdate) {
  double julian_date;
  julian_date = Julian_Date_of_Year(cdate->tm_year) + DOY(cdate->tm_year, cdate->tm_mon, cdate->tm_mday) + Fraction_of_Day(cdate->tm_hour, cdate->tm_min, cdate->tm_sec);
  return (julian_date);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Julian_Date>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    0x14(%rdi),%edi
  call   <Julian_Date_of_Year@plt>
  mov    0xc(%rbx),%edx
  mov    0x10(%rbx),%esi
  mov    0x14(%rbx),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <DOY@plt>
  movsd  0x8(%rsp),%xmm1
  mov    0x4(%rbx),%esi
  mov    0x8(%rbx),%edi
  mov    (%rbx),%edx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <Fraction_of_Day@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double Julian_Date(struct tm *cdate) {
  double julian_date;
  julian_date = Julian_Date_of_Year(cdate->tm_year) + DOY(cdate->tm_year, cdate->tm_mon, cdate->tm_mday) + Fraction_of_Day(cdate->tm_hour, cdate->tm_min, cdate->tm_sec);
  return (julian_date);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<esPrimo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2,-0x8(%rbp)
  jmp    L26
L1:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L0
  mov    $0x0,%eax
  jmp    L16
L0:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jl     L1
  mov    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
int esPrimo(long long int n) {
  long i;
  for (i = 2; i < (int)floor(sqrt(n)) + 1; i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<esPrimo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2,%ebx
  jmp    L7
L36:
  add    $0x1,%rbx
L7:
  mov    %rbp,%rdi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    %rbx,%rdx
  jle    L26
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L36
  mov    $0x0,%eax
  jmp    L6
L26:
  mov    $0x1,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int esPrimo(long long int n) {
  long i;
  for (i = 2; i < (int)floor(sqrt(n)) + 1; i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<esPrimo>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L29
  nopl   (%rax)
L23:
  mov    %r12,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L22
  add    $0x1,%rbx
L29:
  mov    %r12,%rdi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  cltq
  cmp    %rbx,%rax
  jg     L23
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  nop
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int esPrimo(long long int n) {
  long i;
  for (i = 2; i < (int)floor(sqrt(n)) + 1; i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<esPrimo>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   (%rax)
L2:
  mov    %r12,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L27
  add    $0x1,%rbx
L0:
  mov    %r12,%rdi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  cltq
  cmp    %rbx,%rax
  jg     L2
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  nop
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int esPrimo(long long int n) {
  long i;
  for (i = 2; i < (int)floor(sqrt(n)) + 1; i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mipsim_config_init@plt>
  test   %rax,%rax
  je     L15
  mov    $0x0,%eax
  call   <version@plt>
  mov    $0x0,%eax
  jmp    L8
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mipsim_shell@plt>
  mov    $0x0,%eax
  call   <mipsim_config_fini@plt>
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (mipsim_config_init(argc, argv)) {
    version();
    return 0;
  }
  mipsim_shell(argc, argv);
  mipsim_config_fini();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  call   <mipsim_config_init@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <mipsim_shell@plt>
  mov    $0x0,%eax
  call   <mipsim_config_fini@plt>
L19:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x0,%eax
  call   <version@plt>
  jmp    L19
```

assistant: ```c
int main(int argc, char **argv) {
  if (mipsim_config_init(argc, argv)) {
    version();
    return 0;
  }
  mipsim_shell(argc, argv);
  mipsim_config_fini();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <mipsim_config_init@plt>
  test   %rax,%rax
  jne    L0
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <mipsim_shell@plt>
  xor    %eax,%eax
  call   <mipsim_config_fini@plt>
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  xor    %eax,%eax
  call   <version@plt>
  jmp    L13
```

assistant: ```c
int main(int argc, char **argv) {
  if (mipsim_config_init(argc, argv)) {
    version();
    return 0;
  }
  mipsim_shell(argc, argv);
  mipsim_config_fini();
  return 0;
}
```