ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tst_timeval_diff>:
  endbr64
  sub    %rcx,%rsi
  mov    %rdi,%rax
  mov    %rsi,%r8
  sub    %rdx,%rax
  cmp    %rdx,%rdi
  jge    L3
  sub    $0x1,%r8
  lea    0xf4240(%rax),%rax
L3:
  mov    %r8,%rdx
  ret
```

assistant: ```c
struct timeval tst_timeval_diff(struct timeval t1, struct timeval t2) {
  struct timeval res;
  res.tv_sec = t1.tv_sec - t2.tv_sec;
  if (t1.tv_usec < t2.tv_usec) {
    res.tv_sec--;
    res.tv_usec = 1000000 - (t2.tv_usec - t1.tv_usec);
  } else {
    res.tv_usec = t1.tv_usec - t2.tv_usec;
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0x18(%rbp),%rax
  cmp    $0x3cc0,%rax
  jne    L34
  mov    -0x10(%rbp),%rax
  cmp    $0x510,%rax
  je     L17
L34:
  mov    $0x0,%eax
  call   <abort@plt>
L17:
  movq   $0x1,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0x18(%rbp),%rax
  cmp    $0x3cc0,%rax
  jne    L68
  mov    -0x10(%rbp),%rax
  cmp    $0x510,%rax
  je     L49
L68:
  mov    $0x0,%eax
  call   <abort@plt>
L49:
  movq   $0x1,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0x18(%rbp),%rax
  cmp    $0x3cc0,%rax
  jne    L42
  mov    -0x10(%rbp),%rax
  cmp    $0x510,%rax
  je     L65
L42:
  mov    $0x0,%eax
  call   <abort@plt>
L65:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int main() {
  long long int p = 1LL, q = 1LL;
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp taskgroup
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp parallel
#pragma omp single
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x1,0x8(%rsp)
  movq   $0x1,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L6
  cmpq   $0x510,0x10(%rsp)
  je     L49
L6:
  mov    $0x0,%eax
  call   <abort@plt>
L49:
  movq   $0x1,0x8(%rsp)
  movq   $0x1,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L18
  cmpq   $0x510,0x10(%rsp)
  je     L54
L18:
  mov    $0x0,%eax
  call   <abort@plt>
L54:
  movq   $0x1,0x8(%rsp)
  movq   $0x1,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L1
  cmpq   $0x510,0x10(%rsp)
  je     L16
L1:
  mov    $0x0,%eax
  call   <abort@plt>
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long long int p = 1LL, q = 1LL;
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp taskgroup
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp parallel
#pragma omp single
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  movq   $0x1,0x8(%rsp)
  movq   $0x1,0x10(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L36
  cmpq   $0x510,0x10(%rsp)
  je     L27
L36:
  xor    %eax,%eax
  call   <abort@plt>
L27:
  movq   $0x1,0x8(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   $0x1,0x10(%rsp)
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L46
  cmpq   $0x510,0x10(%rsp)
  je     L16
L46:
  xor    %eax,%eax
  call   <abort@plt>
L16:
  movq   $0x1,0x8(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   $0x1,0x10(%rsp)
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L6
  cmpq   $0x510,0x10(%rsp)
  je     L21
L6:
  xor    %eax,%eax
  call   <abort@plt>
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long long int p = 1LL, q = 1LL;
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp taskgroup
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp parallel
#pragma omp single
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  movq   $0x1,0x8(%rsp)
  movq   $0x1,0x10(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L2
  cmpq   $0x510,0x10(%rsp)
  je     L12
L2:
  xor    %eax,%eax
  call   <abort@plt>
L12:
  movq   $0x1,0x8(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   $0x1,0x10(%rsp)
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L23
  cmpq   $0x510,0x10(%rsp)
  je     L32
L23:
  xor    %eax,%eax
  call   <abort@plt>
L32:
  movq   $0x1,0x8(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   $0x1,0x10(%rsp)
  call   <foo@plt>
  cmpq   $0x3cc0,0x8(%rsp)
  jne    L43
  cmpq   $0x510,0x10(%rsp)
  je     L46
L43:
  xor    %eax,%eax
  call   <abort@plt>
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long long int p = 1LL, q = 1LL;
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp taskgroup
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  p = 1LL;
  q = 1LL;
#pragma omp parallel
#pragma omp single
  foo(&p, &q);
  if (p != 6LL * 6LL * 6LL * 6LL * 6LL * 2LL || q != 6LL * 6LL * 6LL * 6LL)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binarySearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L43
  mov    $0x0,%eax
  jmp    L49
L43:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jns    L24
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binarySearch>
  jmp    L49
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jle    L0
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <binarySearch>
  jmp    L49
L0:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
L49:
  leave
  ret
```

assistant: ```c
int binarySearch(char **array, char *word, int iMin, int iMax) {
  if (iMax < iMin)
    return 0;
  else {
    int iMid = (iMin + iMax) / 2;
    if (strcasecmp(word, array[iMid]) < 0)
      return binarySearch(array, word, iMin, iMid - 1);
    else if (strcasecmp(word, array[iMid]) > 0)
      return binarySearch(array, word, iMid + 1, iMax);
    else
      return iMid + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binarySearch>:
  endbr64
  mov    $0x0,%eax
  cmp    %edx,%ecx
  jge    L33
  ret
L33:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %ecx,%ebx
  lea    (%rcx,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  movslq %r13d,%rax
  lea    (%rdi,%rax,8),%r15
  mov    (%r15),%rsi
  mov    %r12,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  js     L3
  mov    (%r15),%rsi
  mov    %r12,%rdi
  call   <strcasecmp@plt>
  mov    %rax,%rdx
  lea    0x1(%r13),%eax
  test   %rdx,%rdx
  jg     L23
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  lea    -0x1(%r13),%ecx
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <binarySearch>
  jmp    L19
L23:
  mov    %eax,%edx
  mov    %ebx,%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <binarySearch>
  jmp    L19
```

assistant: ```c
int binarySearch(char **array, char *word, int iMin, int iMax) {
  if (iMax < iMin)
    return 0;
  else {
    int iMid = (iMin + iMax) / 2;
    if (strcasecmp(word, array[iMid]) < 0)
      return binarySearch(array, word, iMin, iMid - 1);
    else if (strcasecmp(word, array[iMid]) > 0)
      return binarySearch(array, word, iMid + 1, iMax);
    else
      return iMid + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<binarySearch>:
  endbr64
  cmp    %ecx,%edx
  jg     L12
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L8:
  lea    -0x1(%rbx),%ebp
L28:
  cmp    %r14d,%ebp
  jl     L23
L46:
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r12,%rdi
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,8),%r15
  mov    (%r15),%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  js     L8
  mov    (%r15),%rsi
  mov    %r12,%rdi
  lea    0x1(%rbx),%r14d
  call   <strcasecmp@plt>
  test   %rax,%rax
  jg     L28
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L23:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int binarySearch(char **array, char *word, int iMin, int iMax) {
  if (iMax < iMin)
    return 0;
  else {
    int iMid = (iMin + iMax) / 2;
    if (strcasecmp(word, array[iMid]) < 0)
      return binarySearch(array, word, iMin, iMid - 1);
    else if (strcasecmp(word, array[iMid]) > 0)
      return binarySearch(array, word, iMid + 1, iMax);
    else
      return iMid + 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<binarySearch>:
  endbr64
  cmp    %ecx,%edx
  jg     L37
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L5:
  lea    -0x1(%rbx),%ebp
L46:
  cmp    %r14d,%ebp
  jl     L29
L2:
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r12,%rdi
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,8),%r15
  mov    (%r15),%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  js     L5
  mov    (%r15),%rsi
  mov    %r12,%rdi
  lea    0x1(%rbx),%r14d
  call   <strcasecmp@plt>
  test   %rax,%rax
  jg     L46
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
int binarySearch(char **array, char *word, int iMin, int iMax) {
  if (iMax < iMin)
    return 0;
  else {
    int iMid = (iMin + iMax) / 2;
    if (strcasecmp(word, array[iMid]) < 0)
      return binarySearch(array, word, iMin, iMid - 1);
    else if (strcasecmp(word, array[iMid]) > 0)
      return binarySearch(array, word, iMid + 1, iMax);
    else
      return iMid + 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_line_and_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L10
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L10
  cmpl   $0xa,-0x8(%rbp)
  jne    L49
L10:
  cmpl   $0xa,-0x8(%rbp)
  jne    L22
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L22:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_line_and_len(char line[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    line[i] = c;
  if (c == '\n')
    line[i] = c;
  ++i;
  line[i] = '\0';
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_line_and_len>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  cmp    $0x1,%esi
  jle    L62
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r13d
  mov    $0x0,%ebx
L63:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L54
  cmp    $0xa,%eax
  je     L54
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r13d,%ebx
  jne    L63
  mov    %r13d,%ebx
  jmp    L10
L62:
  mov    $0x0,%ebx
L54:
  cmp    $0xa,%eax
  je     L18
L10:
  lea    0x1(%rbx),%eax
  movslq %eax,%rdx
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  movslq %ebx,%rax
  movb   $0xa,(%r12,%rax,1)
  jmp    L10
```

assistant: ```c
int get_line_and_len(char line[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    line[i] = c;
  if (c == '\n')
    line[i] = c;
  ++i;
  line[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_line_and_len>:
  endbr64
  push   %r14
  mov    $0x1,%ecx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L50
  mov    D9(%rip),%rbp
  mov    %rdi,%r14
  xor    %r12d,%r12d
  jmp    L59
L10:
  cmp    $0xa,%eax
  je     L49
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    %r12d,%ebx
  je     L71
L59:
  xor    %eax,%eax
  call   <getchar@plt>
  movslq %r12d,%rdx
  add    $0x1,%r12d
  cmp    %eax,0x0(%rbp)
  jne    L10
  movslq %r12d,%rsi
  mov    %rsi,%rcx
  cmp    $0xa,%eax
  je     L41
L50:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  movb   $0x0,0x0(%r13,%rcx,1)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L49:
  movslq %r12d,%rsi
L41:
  movb   $0xa,0x0(%r13,%rdx,1)
  mov    %rsi,%rcx
  jmp    L50
  cs nopw 0x0(%rax,%rax,1)
L71:
  lea    0x2(%rdx),%r12d
  movslq %r12d,%rcx
  jmp    L50
```

assistant: ```c
int get_line_and_len(char line[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    line[i] = c;
  if (c == '\n')
    line[i] = c;
  ++i;
  line[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_line_and_len>:
  endbr64
  push   %r14
  mov    $0x1,%ecx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L79
  mov    D9(%rip),%rbp
  mov    %rdi,%r14
  xor    %r12d,%r12d
  jmp    L24
L26:
  cmp    $0xa,%eax
  je     L6
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    %r12d,%ebx
  je     L72
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  movslq %r12d,%rdx
  add    $0x1,%r12d
  cmp    %eax,0x0(%rbp)
  jne    L26
  movslq %r12d,%rsi
  mov    %rsi,%rcx
  cmp    $0xa,%eax
  je     L38
L79:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  movb   $0x0,0x0(%r13,%rcx,1)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  movslq %r12d,%rsi
L38:
  movb   $0xa,0x0(%r13,%rdx,1)
  mov    %rsi,%rcx
  jmp    L79
  cs nopw 0x0(%rax,%rax,1)
L72:
  lea    0x2(%rdx),%r12d
  movslq %r12d,%rcx
  jmp    L79
```

assistant: ```c
int get_line_and_len(char line[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    line[i] = c;
  if (c == '\n')
    line[i] = c;
  ++i;
  line[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<overlappingWriteFunction_swab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swab@plt>
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swab@plt>
  nop
  leave
  ret
```

assistant: ```c
void overlappingWriteFunction_swab(char *src, char *dest, ssize_t n) {
  swab(dest, src, n);
  swab(src, src + 3, 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<overlappingWriteFunction_swab>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rbx,%rsi
  call   <swab@plt>
  lea    0x3(%rbx),%rsi
  mov    $0x4,%edx
  mov    %rbx,%rdi
  call   <swab@plt>
  pop    %rbx
  ret
```

assistant: ```c
void overlappingWriteFunction_swab(char *src, char *dest, ssize_t n) {
  swab(dest, src, n);
  swab(src, src + 3, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<overlappingWriteFunction_swab>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rsi
  call   <swab@plt>
  lea    0x3(%rbp),%rsi
  mov    %rbp,%rdi
  pop    %rbp
  mov    $0x4,%edx
  jmp    1050 <swab@plt>
```

assistant: ```c
void overlappingWriteFunction_swab(char *src, char *dest, ssize_t n) {
  swab(dest, src, n);
  swab(src, src + 3, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<overlappingWriteFunction_swab>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rsi
  call   <swab@plt>
  lea    0x3(%rbp),%rsi
  mov    %rbp,%rdi
  pop    %rbp
  mov    $0x4,%edx
  jmp    1050 <swab@plt>
```

assistant: ```c
void overlappingWriteFunction_swab(char *src, char *dest, ssize_t n) {
  swab(dest, src, n);
  swab(src, src + 3, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L11
L8:
  lea    D6(%rip),%rax
  jmp    L2
L11:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: 

assistant: ```c
char *file_extension(char *filename) {
  char *dot = (char *)strrchr(filename, '.');
  if (!dot || dot == filename)
    return "";
  return dot + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_extension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L9
  cmp    %rax,%rbx
  je     L9
  add    $0x1,%rax
L17:
  pop    %rbx
  ret
L9:
  lea    D8(%rip),%rax
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: 

assistant: ```c
char *file_extension(char *filename) {
  char *dot = (char *)strrchr(filename, '.');
  if (!dot || dot == filename)
    return "";
  return dot + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_extension>:
  endbr64
  push   %rbx
  mov    $0x2e,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L14
  cmp    %rax,%rbx
  je     L14
  add    $0x1,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  lea    D1(%rip),%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: 

assistant: ```c
char *file_extension(char *filename) {
  char *dot = (char *)strrchr(filename, '.');
  if (!dot || dot == filename)
    return "";
  return dot + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<file_extension>:
  endbr64
  push   %rbx
  mov    $0x2e,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L10
  cmp    %rax,%rbx
  je     L10
  add    $0x1,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  lea    D4(%rip),%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: 

assistant: ```c
char *file_extension(char *filename) {
  char *dot = (char *)strrchr(filename, '.');
  if (!dot || dot == filename)
    return "";
  return dot + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort_r_swap_blocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L19
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L24
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sort_r_swap@plt>
  jmp    L19
L24:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sort_r_swap@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void sort_r_swap_blocks(char *ptr, size_t na, size_t nb) {
  if ((na > 0) && (nb > 0)) {
    if (na > nb) {
      sort_r_swap(ptr, ptr + na, nb);
    } else {
      sort_r_swap(ptr, ptr + nb, na);
    }
  }
}
```