ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<outsb>:
  endbr64
  lea    (%rsi,%rdx,1),%rcx
  test   %rdx,%rdx
  je     L16
  nopl   (%rax)
L0:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  mov    %al,(%rdi)
  cmp    %rcx,%rsi
  jne    L0
L16:
  ret
```

assistant: ```c
void outsb(unsigned long port, const void *src, unsigned long count) {
  const unsigned char *p = src;
  while (count--)
    ((void)(void)((*(volatile unsigned char *)(port)) = (*p++)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<specheat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D8(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D26(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm2
  movsd  D32(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x18(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D9(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: f64
name: disassemble_data
arguments: tag: D8
type_infered: f64
name: disassemble_data
arguments: tag: D26
type_infered: f64
name: disassemble_data
arguments: tag: D32
type_infered: byte[8]
name: disassemble_data
arguments: tag: D9
type_infered: byte[8]

tool: D12: 3.720283

tool: D8: 4217.4

tool: D26: 0.1412855

tool: {"D32": [0x2d,0xc2,0x63,0x2b,0xa7,0xbe,0x65,0x3f]}

tool: {"D9": [0x2e,0xfc,0x77,0xd3,0xfc,0xf2,0xf5,0x3e]}

assistant: ```c
double specheat(double t) {
  double cpt;
  cpt = 4217.4 - 3.720283 * t + 0.1412855 * t * t - 2.654387e-3 * t * t * t + 2.093236e-5 * t * t * t * t;
  return cpt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<specheat>:
  endbr64
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  mulsd  D21(%rip),%xmm2
  movsd  D45(%rip),%xmm0
  subsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  mulsd  D31(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  mulsd  D2(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  mulsd  D4(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D21
datatype: f64
name: parse_data
arguments: label: D45
datatype: f64
name: parse_data
arguments: label: D31
datatype: f64
name: parse_data
arguments: label: D2
datatype: byte[8]
name: parse_data
arguments: label: D4
datatype: byte[8]

tool: D21: 3.720283

tool: D45: 4217.4

tool: D31: 0.1412855

tool: {"D2": [0x2d,0xc2,0x63,0x2b,0xa7,0xbe,0x65,0x3f]}

tool: {"D4": [0x2e,0xfc,0x77,0xd3,0xfc,0xf2,0xf5,0x3e]}

assistant: ```c
double specheat(double t) {
  double cpt;
  cpt = 4217.4 - 3.720283 * t + 0.1412855 * t * t - 2.654387e-3 * t * t * t + 2.093236e-5 * t * t * t * t;
  return cpt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<specheat>:
  endbr64
  movsd  D2(%rip),%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm2
  movsd  D45(%rip),%xmm0
  subsd  %xmm2,%xmm0
  movsd  D27(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  D39(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movsd  D6(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: f64
name: unpack_data
arguments: label: D45
datatype: f64
name: unpack_data
arguments: label: D27
datatype: f64
name: unpack_data
arguments: label: D39
datatype: byte[8]
name: unpack_data
arguments: label: D6
datatype: byte[8]

tool: D2: 3.720283

tool: D45: 4217.4

tool: D27: 0.1412855

tool: {"D39": [0x2d,0xc2,0x63,0x2b,0xa7,0xbe,0x65,0x3f]}

tool: {"D6": [0x2e,0xfc,0x77,0xd3,0xfc,0xf2,0xf5,0x3e]}

assistant: ```c
double specheat(double t) {
  double cpt;
  cpt = 4217.4 - 3.720283 * t + 0.1412855 * t * t - 2.654387e-3 * t * t * t + 2.093236e-5 * t * t * t * t;
  return cpt;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<specheat>:
  endbr64
  movsd  D13(%rip),%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm2
  movsd  D48(%rip),%xmm0
  subsd  %xmm2,%xmm0
  movsd  D23(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  D1(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movsd  D11(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type: f64
name: unpack_data
arguments: data_label: D48
type: f64
name: unpack_data
arguments: data_label: D23
type: f64
name: unpack_data
arguments: data_label: D1
type: byte[8]
name: unpack_data
arguments: data_label: D11
type: byte[8]

tool: D13: 3.720283

tool: D48: 4217.4

tool: D23: 0.1412855

tool: {"D1": [0x2d,0xc2,0x63,0x2b,0xa7,0xbe,0x65,0x3f]}

tool: {"D11": [0x2e,0xfc,0x77,0xd3,0xfc,0xf2,0xf5,0x3e]}

assistant: ```c
double specheat(double t) {
  double cpt;
  cpt = 4217.4 - 3.720283 * t + 0.1412855 * t * t - 2.654387e-3 * t * t * t + 2.093236e-5 * t * t * t * t;
  return cpt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ctoec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L17
  cmpl   $0x1f,-0x4(%rbp)
  jle    L29
L17:
  cmpl   $0x7f,-0x4(%rbp)
  jne    L10
L29:
  mov    -0x4(%rbp),%eax
  xor    $0x40,%eax
  or     $0x1,%ah
  mov    %eax,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
ctoec(int c) {
  if ((c >= 0x00 && c <= 0x1F) || c == 0x7F)
    c = 0x0100 | (c ^ 0x40);
  return (c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ctoec>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1f,%edi
  jbe    L5
  cmp    $0x7f,%edi
  jne    L15
L5:
  xor    $0x40,%eax
  or     $0x1,%ah
L15:
  ret
```

assistant: ```c
ctoec(int c) {
  if ((c >= 0x00 && c <= 0x1F) || c == 0x7F)
    c = 0x0100 | (c ^ 0x40);
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ctoec>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1f,%edi
  jbe    L8
  cmp    $0x7f,%edi
  je     L8
  ret
  nopl   0x0(%rax)
L8:
  xor    $0x40,%eax
  or     $0x1,%ah
  ret
```

assistant: ```c
ctoec(int c) {
  if ((c >= 0x00 && c <= 0x1F) || c == 0x7F)
    c = 0x0100 | (c ^ 0x40);
  return (c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ctoec>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1f,%edi
  jbe    L8
  cmp    $0x7f,%edi
  je     L8
  ret
  nopl   0x0(%rax)
L8:
  xor    $0x40,%eax
  or     $0x1,%ah
  ret
```

assistant: ```c
ctoec(int c) {
  if ((c >= 0x00 && c <= 0x1F) || c == 0x7F)
    c = 0x0100 | (c ^ 0x40);
  return (c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<open_env>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <open_path@plt>
  mov    %rax,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
FILE *open_env(const char *env, const char *name, const char *subdir) {
  FILE *result = NULL;
  char *p = getenv(env);
  if (NULL != p)
    result = open_path(p, name, subdir);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<open_env>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <getenv@plt>
  test   %rax,%rax
  je     L8
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <open_path@plt>
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
FILE *open_env(const char *env, const char *name, const char *subdir) {
  FILE *result = NULL;
  char *p = getenv(env);
  if (NULL != p)
    result = open_path(p, name, subdir);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<open_env>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <open_path@plt>
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
FILE *open_env(const char *env, const char *name, const char *subdir) {
  FILE *result = NULL;
  char *p = getenv(env);
  if (NULL != p)
    result = open_path(p, name, subdir);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<open_env>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <open_path@plt>
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
FILE *open_env(const char *env, const char *name, const char *subdir) {
  FILE *result = NULL;
  char *p = getenv(env);
  if (NULL != p)
    result = open_path(p, name, subdir);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L22:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strcpy(char *s1, const char *s2) {
  int a;
  a = 0;
  while (s2[a] != '\0') {
    s1[a] = s2[a];
    a = a + 1;
  }
  if (s2[a] == '\0')
    s1[a] = s2[a];
  return (s1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L24
  mov    $0x0,%edx
L5:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L5
L22:
  movb   $0x0,(%rax,%rdx,1)
  ret
L24:
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
char *ft_strcpy(char *s1, const char *s2) {
  int a;
  a = 0;
  while (s2[a] != '\0') {
    s1[a] = s2[a];
    a = a + 1;
  }
  if (s2[a] == '\0')
    s1[a] = s2[a];
  return (s1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L3
  xor    %edx,%edx
L16:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L16
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *ft_strcpy(char *s1, const char *s2) {
  int a;
  a = 0;
  while (s2[a] != '\0') {
    s1[a] = s2[a];
    a = a + 1;
  }
  if (s2[a] == '\0')
    s1[a] = s2[a];
  return (s1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L0
  xor    %edx,%edx
L16:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L16
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *ft_strcpy(char *s1, const char *s2) {
  int a;
  a = 0;
  while (s2[a] != '\0') {
    s1[a] = s2[a];
    a = a + 1;
  }
  if (s2[a] == '\0')
    s1[a] = s2[a];
  return (s1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xd,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <to_binary@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string

tool: D6: 


assistant: ```c
int main() {
  int num = 13;
  to_binary(num);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <to_binary@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: 


assistant: ```c
int main() {
  int num = 13;
  to_binary(num);
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <to_binary@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: 


assistant: ```c
int main() {
  int num = 13;
  to_binary(num);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <to_binary@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: 


assistant: ```c
int main() {
  int num = 13;
  to_binary(num);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HibernateTamperUnLock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400fc360,%eax
  movl   $0xa3359554,(%rax)
  mov    $0x0,%eax
  call   <_HibernateWriteComplete@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void HibernateTamperUnLock(void) {
  (*((volatile uint32_t *)(0x400FC360))) = 0xA3359554;
  _HibernateWriteComplete();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HibernateTamperUnLock>:
  endbr64
  sub    $0x8,%rsp
  movl   $0xa3359554,0x400fc360
  mov    $0x0,%eax
  call   <_HibernateWriteComplete@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void HibernateTamperUnLock(void) {
  (*((volatile uint32_t *)(0x400FC360))) = 0xA3359554;
  _HibernateWriteComplete();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<HibernateTamperUnLock>:
  endbr64
  movl   $0xa3359554,0x400fc360
  xor    %eax,%eax
  jmp    1050 <_HibernateWriteComplete@plt>
```

assistant: ```c
void HibernateTamperUnLock(void) {
  (*((volatile uint32_t *)(0x400FC360))) = 0xA3359554;
  _HibernateWriteComplete();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HibernateTamperUnLock>:
  endbr64
  movl   $0xa3359554,0x400fc360
  xor    %eax,%eax
  jmp    1050 <_HibernateWriteComplete@plt>
```

assistant: ```c
void HibernateTamperUnLock(void) {
  (*((volatile uint32_t *)(0x400FC360))) = 0xA3359554;
  _HibernateWriteComplete();
}
```
user: Translate the below assembly code into C programming language:

```asm
<_perm_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xf,%rax
  and    $0xfffffffffffffff0,%rax
  mov    %rax,-0x18(%rbp)
  mov    D46(%rip),%rax
  cmp    %rax,-0x18(%rbp)
  ja     L2
  mov    D46(%rip),%rax
  test   %rax,%rax
  jne    L14
L2:
  mov    $0x800000,%edi
  call   <malloc@plt>
  mov    %rax,D84(%rip)
  mov    D84(%rip),%rax
  test   %rax,%rax
  jne    L27
  mov    $0x1,%edi
  call   <exit@plt>
L27:
  movq   $0x800000,D46(%rip)
L14:
  mov    D84(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    D46(%rip),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,D0(%rip)
  mov    D84(%rip),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,D0(%rip)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *_perm_alloc(size_t size) {
  static uint8_t *ptr;
  static size_t rem;
  void *ret;
  size = (((size) + ((2 * sizeof(void *)) - 1)) & ~((2 * sizeof(void *)) - 1));
  if (size > rem || rem == 0) {
    ptr = malloc((1 << 23));
    if (ptr == NULL)
      exit(1);
    rem = (1 << 23);
  }
  ret = ptr;
  rem -= size;
  ptr += size;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_perm_alloc>:
  endbr64
  push   %rbx
  lea    0xf(%rdi),%rbx
  and    $0xfffffffffffffff0,%rbx
  mov    D33(%rip),%rax
  test   %rax,%rax
  je     L13
  cmp    %rbx,%rax
  jae    L31
L13:
  mov    $0x800000,%edi
  call   <malloc@plt>
  mov    %rax,D24(%rip)
  test   %rax,%rax
  je     L36
L27:
  movq   $0x800000,D33(%rip)
L31:
  mov    D24(%rip),%rax
  sub    %rbx,D44(%rip)
  lea    (%rax,%rbx,4),%rdx
  mov    %rdx,D44(%rip)
  pop    %rbx
  ret
L36:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L27
```

assistant: ```c
void *_perm_alloc(size_t size) {
  static uint8_t *ptr;
  static size_t rem;
  void *ret;
  size = (((size) + ((2 * sizeof(void *)) - 1)) & ~((2 * sizeof(void *)) - 1));
  if (size > rem || rem == 0) {
    ptr = malloc((1 << 23));
    if (ptr == NULL)
      exit(1);
    rem = (1 << 23);
  }
  ret = ptr;
  rem -= size;
  ptr += size;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_perm_alloc>:
  endbr64
  push   %rbx
  mov    D44(%rip),%rdx
  lea    0xf(%rdi),%rbx
  and    $0xfffffffffffffff0,%rbx
  cmp    %rbx,%rdx
  jb     L14
  mov    D24(%rip),%rax
  test   %rdx,%rdx
  je     L14
L18:
  sub    %rbx,%rdx
  mov    %rdx,D13(%rip)
  lea    (%rax,%rbx,4),%rdx
  pop    %rbx
  mov    %rdx,D13(%rip)
  ret
  nopl   0x0(%rax)
L14:
  mov    $0x800000,%edi
  call   <malloc@plt>
  mov    %rax,D13(%rip)
  test   %rax,%rax
  je     L29
L36:
  mov    $0x800000,%edx
  jmp    L18
  nopl   (%rax)
L29:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    D13(%rip),%rax
  jmp    L36
```

assistant: ```c
void *_perm_alloc(size_t size) {
  static uint8_t *ptr;
  static size_t rem;
  void *ret;
  size = (((size) + ((2 * sizeof(void *)) - 1)) & ~((2 * sizeof(void *)) - 1));
  if (size > rem || rem == 0) {
    ptr = malloc((1 << 23));
    if (ptr == NULL)
      exit(1);
    rem = (1 << 23);
  }
  ret = ptr;
  rem -= size;
  ptr += size;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_perm_alloc>:
  endbr64
  push   %rbx
  mov    D25(%rip),%rdx
  lea    0xf(%rdi),%rbx
  and    $0xfffffffffffffff0,%rbx
  cmp    %rbx,%rdx
  jb     L12
  mov    D43(%rip),%rax
  test   %rdx,%rdx
  je     L12
L19:
  sub    %rbx,%rdx
  mov    %rdx,D24(%rip)
  lea    (%rax,%rbx,4),%rdx
  pop    %rbx
  mov    %rdx,D24(%rip)
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x800000,%edi
  call   <malloc@plt>
  mov    %rax,D24(%rip)
  test   %rax,%rax
  je     L26
L24:
  mov    $0x800000,%edx
  jmp    L19
  nopl   (%rax)
L26:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    D24(%rip),%rax
  jmp    L24
```

assistant: ```c
void *_perm_alloc(size_t size) {
  static uint8_t *ptr;
  static size_t rem;
  void *ret;
  size = (((size) + ((2 * sizeof(void *)) - 1)) & ~((2 * sizeof(void *)) - 1));
  if (size > rem || rem == 0) {
    ptr = malloc((1 << 23));
    if (ptr == NULL)
      exit(1);
    rem = (1 << 23);
  }
  ret = ptr;
  rem -= size;
  ptr += size;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strnconcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  test   %rdi,%rdi
  je     L24
  test   %rsi,%rsi
  jne    L64
L24:
  test   %rbp,%rbp
  jne    L62
  mov    %rbx,%rsi
  test   %rbx,%rbx
  je     L113
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <my_strlen@plt>
  cmp    %r12d,%eax
  cmovbe %eax,%r12d
  mov    %r12d,%edi
  add    $0x1,%rdi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  movslq %eax,%rsi
  test   %r12d,%r12d
  je     L113
  lea    -0x1(%r12),%edx
  lea    0x1(%rsi,%rdx,1),%rcx
  mov    %rsi,%rdx
  sub    %rsi,%rbx
L80:
  movzbl (%rbx,%rdx,1),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L80
L113:
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  mov    $0x0,%eax
  call   <my_strlen@plt>
  mov    %eax,%r13d
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <my_strlen@plt>
  cmp    %r12d,%eax
  cmovbe %eax,%r12d
  lea    0x0(%r13,%r12,1),%edi
  add    $0x1,%rdi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  movslq %eax,%rsi
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L115
  mov    $0x1,%edx
  mov    %rsi,%r8
L125:
  mov    %cl,-0x1(%rdx,%r8,1)
  mov    %edx,%edi
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L125
L21:
  test   %r12d,%r12d
  je     L113
  movslq %edi,%rdi
  cltq
  lea    (%rax,%rdi,1),%rdx
  lea    -0x1(%r12),%ecx
  lea    0x1(%rax,%rcx,1),%rcx
  add    %rdi,%rcx
  mov    %rdx,%rax
  sub    %rdx,%rbx
L82:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L82
  jmp    L113
L115:
  mov    $0x0,%edi
  jmp    L21
L62:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <my_strdup@plt>
  movslq %eax,%rsi
  jmp    L113
```

assistant: ```c
char *my_strnconcat(char *s1, char *s2, unsigned int n) {
  int l1;
  int l2;
  char *s3 = ((void *)0);
  int i;
  int j;
  if (s1 && s2) {
    l1 = my_strlen(s1);
    l2 = my_strlen(s2);
    if (n > l2)
      n = l2;
    s3 = (char *)xmalloc((l1 + n) * sizeof(char) + 1);
    for (i = 0; s1[i]; i++)
      s3[i] = s1[i];
    for (j = 0; j < n; i++, j++)
      s3[i] = s2[j];
    return s3;
  } else if (s1)
    return my_strdup(s1);
  else if (s2) {
    l2 = my_strlen(s2);
    if (n > l2)
      n = l2;
    s3 = xmalloc(n * sizeof(char) + 1);
    for (i = 0; i < n; ++i)
      s3[i] = s2[i];
    return s3;
  } else
    return ((void *)0);
}
```