ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0xa,0x17(%rsp)
  mov    0x8(%rsi),%r15
  lea    -0x2(%rdi),%r12d
  lea    (%r12,%r12,1),%eax
  mov    %eax,0xc(%rsp)
  mov    %r12d,%edi
  shl    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L24
  add    $0x10,%rbp
  lea    -0x3(%rbx),%r12d
  add    $0x1,%r12
  shl    $0x5,%r12
  add    %rax,%r12
  mov    %rax,%rbx
  lea    0x17(%rsp),%r13
L10:
  mov    0x0(%rbp),%rdi
  mov    %rdi,(%rbx)
  call   <strlen@plt>
  mov    %eax,0x8(%rbx)
  mov    %r13,0x10(%rbx)
  movl   $0x1,0x18(%rbx)
  add    $0x20,%rbx
  add    $0x8,%rbp
  cmp    %rbx,%r12
  jne    L10
L24:
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    D0(%rip),%rax
  or     (%rax),%esi
  mov    %r15,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  mov    0xc(%rsp),%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <writev@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd;
  struct iovec *vec;
  struct iovec *vec_next;
  int i;
  char newline = '\n';
  char *filename = argv[1];
  argc -= 2;
  argv += 2;
  vec = (struct iovec *)malloc(2 * argc * sizeof(struct iovec));
  vec_next = vec;
  for (i = 0; i < argc; i++) {
    vec_next->iov_base = argv[i];
    vec_next->iov_len = strlen(argv[i]);
    ++vec_next;
    vec_next->iov_base = &newline;
    vec_next->iov_len = 1;
    ++vec_next;
  }
  fd = open(filename, O_WRONLY | O_CREAT);
  writev(fd, vec, 2 * argc);
  close(fd);
  free(vec);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    -0x2(%rdi),%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  shl    $0x5,%edi
  sub    $0x28,%rsp
  mov    0x8(%rsi),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    (%r12,%r12,1),%eax
  movb   $0xa,0x17(%rsp)
  mov    %eax,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L22
  sub    $0x3,%ebp
  add    $0x10,%r14
  lea    0x17(%rsp),%r12
  mov    %rax,%rbx
  add    $0x1,%rbp
  shl    $0x5,%rbp
  add    %rax,%rbp
  nopl   0x0(%rax)
L20:
  mov    (%r14),%rdi
  add    $0x20,%rbx
  add    $0x8,%r14
  mov    %rdi,-0x20(%rbx)
  call   <strlen@plt>
  mov    %r12,-0x10(%rbx)
  mov    %eax,-0x18(%rbx)
  movl   $0x1,-0x8(%rbx)
  cmp    %rbx,%rbp
  jne    L20
L22:
  mov    D13(%rip),%rax
  mov    %r15,%rdi
  mov    (%rax),%esi
  mov    D14(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <writev@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd;
  struct iovec *vec;
  struct iovec *vec_next;
  int i;
  char newline = '\n';
  char *filename = argv[1];
  argc -= 2;
  argv += 2;
  vec = (struct iovec *)malloc(2 * argc * sizeof(struct iovec));
  vec_next = vec;
  for (i = 0; i < argc; i++) {
    vec_next->iov_base = argv[i];
    vec_next->iov_len = strlen(argv[i]);
    ++vec_next;
    vec_next->iov_base = &newline;
    vec_next->iov_len = 1;
    ++vec_next;
  }
  fd = open(filename, O_WRONLY | O_CREAT);
  writev(fd, vec, 2 * argc);
  close(fd);
  free(vec);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    -0x2(%rdi),%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  shl    $0x5,%edi
  sub    $0x28,%rsp
  mov    0x8(%rsi),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    (%r12,%r12,1),%eax
  movb   $0xa,0x17(%rsp)
  mov    %eax,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L12
  sub    $0x3,%ebp
  add    $0x10,%r14
  lea    0x17(%rsp),%r12
  mov    %rax,%rbx
  add    $0x1,%rbp
  shl    $0x5,%rbp
  add    %rax,%rbp
  nopl   0x0(%rax)
L1:
  mov    (%r14),%rdi
  add    $0x20,%rbx
  add    $0x8,%r14
  mov    %rdi,-0x20(%rbx)
  call   <strlen@plt>
  mov    %r12,-0x10(%rbx)
  mov    %eax,-0x18(%rbx)
  movl   $0x1,-0x8(%rbx)
  cmp    %rbx,%rbp
  jne    L1
L12:
  mov    D8(%rip),%rax
  mov    %r15,%rdi
  mov    (%rax),%esi
  mov    D18(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <writev@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd;
  struct iovec *vec;
  struct iovec *vec_next;
  int i;
  char newline = '\n';
  char *filename = argv[1];
  argc -= 2;
  argv += 2;
  vec = (struct iovec *)malloc(2 * argc * sizeof(struct iovec));
  vec_next = vec;
  for (i = 0; i < argc; i++) {
    vec_next->iov_base = argv[i];
    vec_next->iov_len = strlen(argv[i]);
    ++vec_next;
    vec_next->iov_base = &newline;
    vec_next->iov_len = 1;
    ++vec_next;
  }
  fd = open(filename, O_WRONLY | O_CREAT);
  writev(fd, vec, 2 * argc);
  close(fd);
  free(vec);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generateNextTypes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L141
  movl   $0x0,-0x8(%rbp)
  jmp    L144
L130:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,(%rsi)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L40:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L57
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L40
  jmp    L47
L57:
  nop
L47:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L130
  addl   $0x1,-0x8(%rbp)
L144:
  cmpl   $0x6,-0x8(%rbp)
  jle    L130
L141:
  movl   $0x7,-0x8(%rbp)
  jmp    L52
L138:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,(%rsi)
  movl   $0x7,-0x4(%rbp)
  jmp    L89
L74:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L66
  addl   $0x1,-0x4(%rbp)
L89:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L74
  jmp    L60
L66:
  nop
L60:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L138
  addl   $0x1,-0x8(%rbp)
L52:
  cmpl   $0xd,-0x8(%rbp)
  jle    L138
  nop
  leave
  ret
```

assistant: ```c
void generateNextTypes(int *nextTypes) {
  int i, j;
  if (nextTypes[0] == -1) {
    for (i = 0; i < 7; i++) {
      do {
        nextTypes[i] = rand() % 7;
        for (j = 0; j < i; j++) {
          if (nextTypes[i] == nextTypes[j]) {
            break;
          }
        }
      } while (i != j);
    }
  }
  for (i = 7; i < 14; i++) {
    do {
      nextTypes[i] = rand() % 7;
      for (j = 7; j < i; j++) {
        if (nextTypes[i] == nextTypes[j]) {
          break;
        }
      }
    } while (i != j);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generateNextTypes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmpl   $0xffffffff,(%rdi)
  je     L51
L32:
  mov    $0x7,%r12d
  jmp    L30
L51:
  mov    $0x0,%r12d
  jmp    L47
L111:
  mov    $0x0,%eax
L36:
  cmp    %ebx,%eax
  je     L19
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rcx
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x2,%ecx
  cltd
  sub    %edx,%ecx
  lea    0x0(,%rcx,8),%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %eax,0x0(%rbp,%r12,4)
  test   %r12d,%r12d
  jle    L111
  mov    %rbp,%rdx
  mov    $0x0,%eax
L105:
  cmp    (%rdx),%ecx
  je     L36
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ebx,%eax
  jne    L105
L19:
  add    $0x1,%r12
  cmp    $0x7,%r12
  je     L32
L47:
  mov    %r12d,%ebx
  jmp    L6
L60:
  mov    $0x7,%eax
L70:
  cmp    %ebx,%eax
  je     L144
L77:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rcx
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x2,%ecx
  cltd
  sub    %edx,%ecx
  lea    0x0(,%rcx,8),%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %eax,0x0(%rbp,%r12,4)
  cmp    $0x7,%r12d
  jle    L60
  lea    0x1c(%rbp),%rdx
  mov    $0x7,%eax
L31:
  cmp    (%rdx),%ecx
  je     L70
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ebx,%eax
  jne    L31
L144:
  add    $0x1,%r12
  cmp    $0xe,%r12
  je     L56
L30:
  mov    %r12d,%ebx
  jmp    L77
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void generateNextTypes(int *nextTypes) {
  int i, j;
  if (nextTypes[0] == -1) {
    for (i = 0; i < 7; i++) {
      do {
        nextTypes[i] = rand() % 7;
        for (j = 0; j < i; j++) {
          if (nextTypes[i] == nextTypes[j]) {
            break;
          }
        }
      } while (i != j);
    }
  }
  for (i = 7; i < 14; i++) {
    do {
      nextTypes[i] = rand() % 7;
      for (j = 7; j < i; j++) {
        if (nextTypes[i] == nextTypes[j]) {
          break;
        }
      }
    } while (i != j);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<generateNextTypes>:
  endbr64
  cmpl   $0xffffffff,(%rdi)
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  je     L95
L101:
  mov    $0x7,%r12d
  nopw   0x0(%rax,%rax,1)
L96:
  mov    %r12d,%ebp
  nopl   0x0(%rax,%rax,1)
L53:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rcx
  cltd
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x2,%ecx
  sub    %edx,%ecx
  lea    0x0(,%rcx,8),%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  mov    %eax,%ecx
  cmp    $0x7,%r12
  je     L117
  lea    0x1c(%rbx),%rdx
  mov    $0x7,%eax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ebp,%eax
  je     L117
L21:
  cmp    (%rdx),%ecx
  jne    L49
  cmp    %eax,%ebp
  jne    L53
  nopl   0x0(%rax,%rax,1)
L117:
  add    $0x1,%r12
  cmp    $0xe,%r12
  jne    L96
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L95:
  xor    %r12d,%r12d
L16:
  mov    %r12d,%ebp
  nopl   (%rax)
L133:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rcx
  cltd
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x2,%ecx
  sub    %edx,%ecx
  lea    0x0(,%rcx,8),%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  mov    %eax,%ecx
  test   %r12,%r12
  je     L94
  mov    %rbx,%rdx
  xor    %eax,%eax
  jmp    L106
  nopw   0x0(%rax,%rax,1)
L87:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ebp,%eax
  je     L94
L106:
  cmp    (%rdx),%ecx
  jne    L87
  cmp    %ebp,%eax
  jne    L133
  nopl   0x0(%rax,%rax,1)
L94:
  add    $0x1,%r12
  cmp    $0x7,%r12
  jne    L16
  jmp    L101
```

assistant: ```c
void generateNextTypes(int *nextTypes) {
  int i, j;
  if (nextTypes[0] == -1) {
    for (i = 0; i < 7; i++) {
      do {
        nextTypes[i] = rand() % 7;
        for (j = 0; j < i; j++) {
          if (nextTypes[i] == nextTypes[j]) {
            break;
          }
        }
      } while (i != j);
    }
  }
  for (i = 7; i < 14; i++) {
    do {
      nextTypes[i] = rand() % 7;
      for (j = 7; j < i; j++) {
        if (nextTypes[i] == nextTypes[j]) {
          break;
        }
      }
    } while (i != j);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generateNextTypes>:
  endbr64
  cmpl   $0xffffffff,(%rdi)
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  je     L252
L376:
  mov    $0x7,%r12d
  nopw   0x0(%rax,%rax,1)
L326:
  mov    %r12d,%ebp
  nopl   0x0(%rax,%rax,1)
L307:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff92492493,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,(%rbx,%r12,4)
  cmp    $0x7,%r12
  je     L238
  cmp    0x1c(%rbx),%eax
  je     L307
  cmp    $0x8,%ebp
  je     L273
  cmp    0x20(%rbx),%eax
  je     L307
  cmp    $0x9,%ebp
  je     L58
  cmp    0x24(%rbx),%eax
  je     L307
  cmp    $0xa,%ebp
  je     L150
  cmp    0x28(%rbx),%eax
  je     L307
  cmp    $0xb,%ebp
  je     L157
  cmp    0x2c(%rbx),%eax
  je     L307
  cmp    $0xd,%ebp
  jne    L86
  cmp    0x30(%rbx),%eax
  je     L307
  mov    $0xd,%eax
L2:
  cmp    %ebp,%eax
  jne    L307
L238:
  add    $0x1,%r12
  cmp    $0xe,%r12
  jne    L326
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L273:
  mov    $0x8,%eax
  jmp    L2
L58:
  mov    $0x9,%eax
  jmp    L2
L150:
  mov    $0xa,%eax
  jmp    L2
L157:
  mov    $0xb,%eax
  jmp    L2
L86:
  mov    $0xc,%eax
  jmp    L2
L252:
  xor    %r12d,%r12d
L224:
  mov    %r12d,%ebp
  nopw   0x0(%rax,%rax,1)
L75:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff92492493,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,(%rbx,%r12,4)
  test   %r12,%r12
  je     L277
  cmp    (%rbx),%eax
  je     L75
  cmp    $0x1,%ebp
  je     L156
  cmp    0x4(%rbx),%eax
  je     L75
  cmp    $0x2,%ebp
  je     L40
  cmp    0x8(%rbx),%eax
  je     L75
  cmp    $0x3,%ebp
  je     L305
  cmp    0xc(%rbx),%eax
  je     L75
  cmp    $0x4,%ebp
  je     L317
  cmp    0x10(%rbx),%eax
  je     L75
  cmp    $0x6,%ebp
  jne    L38
  cmp    0x14(%rbx),%eax
  je     L75
  mov    $0x6,%eax
L324:
  cmp    %ebp,%eax
  jne    L75
L277:
  add    $0x1,%r12
  cmp    $0x7,%r12
  jne    L224
  jmp    L376
L156:
  mov    $0x1,%eax
  jmp    L324
L40:
  mov    $0x2,%eax
  jmp    L324
L305:
  mov    $0x3,%eax
  jmp    L324
L317:
  mov    $0x4,%eax
  jmp    L324
L38:
  mov    $0x5,%eax
  jmp    L324
```

assistant: ```c
void generateNextTypes(int *nextTypes) {
  int i, j;
  if (nextTypes[0] == -1) {
    for (i = 0; i < 7; i++) {
      do {
        nextTypes[i] = rand() % 7;
        for (j = 0; j < i; j++) {
          if (nextTypes[i] == nextTypes[j]) {
            break;
          }
        }
      } while (i != j);
    }
  }
  for (i = 7; i < 14; i++) {
    do {
      nextTypes[i] = rand() % 7;
      for (j = 7; j < i; j++) {
        if (nextTypes[i] == nextTypes[j]) {
          break;
        }
      }
    } while (i != j);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sumToN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <sumToN>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  jmp    L13
L13:
  leave
  ret
```

assistant: ```c
int sumToN(int n) {
  if (n != 0)
    return n + sumToN(n - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sumToN>:
  endbr64
  test   %edi,%edi
  jne    L3
  ret
L3:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <sumToN>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int sumToN(int n) {
  if (n != 0)
    return n + sumToN(n - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sumToN>:
  endbr64
  ret
```

assistant: ```c
int sumToN(int n) {
  if (n != 0)
    return n + sumToN(n - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<sumToN>:
  endbr64
  ret
```

assistant: ```c
int sumToN(int n) {
  if (n != 0)
    return n + sumToN(n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<doUpgrade>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jne    L68
  mov    $0x0,%eax
  call   <getDbVersion@plt>
  mov    %eax,%ebx
L28:
  mov    %ebx,%edx
  lea    D19(%rip),%rsi
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <logMsg@plt>
  mov    $0x0,%ebp
  jmp    L40
L68:
  mov    $0xffffffff,%esi
  mov    (%rdx),%rdi
  call   <strToInt@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <getDbVersion@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%r12d
  je     L28
  cmp    %eax,%r12d
  jl     L54
  je     L36
  cmp    $0x7,%r12d
  jle    L78
  mov    $0x7,%ecx
  mov    %r12d,%edx
  lea    D25(%rip),%rsi
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <logMsg@plt>
  mov    $0x0,%ebp
  jmp    L40
L54:
  mov    %eax,%ecx
  mov    %r12d,%edx
  lea    D20(%rip),%rsi
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <logMsg@plt>
  mov    $0x0,%ebp
L40:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    %eax,%edx
  lea    D12(%rip),%rsi
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <logMsg@plt>
  mov    $0x0,%ebp
  jmp    L40
L78:
  cmp    %eax,%r12d
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x1(%rbx),%edi
  add    $0x1,%r12d
L65:
  cmp    %edi,%r12d
  je     L40
  lea    0x1(%rdi),%ebx
  call   <upgradeTo@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L40
  mov    %ebx,%edi
  jmp    L65
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_infered: string
name: unpack_data
arguments: data_tag: D25
type_infered: string
name: unpack_data
arguments: data_tag: D20
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: string

tool: D19: Please specify a valid database level for the upgrade, the database is currently at level %d.

tool: D25: Cannot upgrade database to level %d, the maximum available upgrade level is %d.

tool: D20: Cannot upgrade database to level %d, the database is already at level %d.

tool: D12: Database is already at level %d, nothing to do.

assistant: ```c
int doUpgrade(FILE *file, int argc, char **argv) {
  int requestLevel;
  if (argc == 0) {
    requestLevel = -1;
  } else {
    requestLevel = strToInt(argv[0], -1);
  }
  int status;
  int currentLevel = getDbVersion();
  if (requestLevel == -1) {
    logMsg(2, "Please specify a valid database level for the upgrade, the database is currently at level %d.", currentLevel);
    status = 0;
  } else if (requestLevel < currentLevel) {
    logMsg(2, "Cannot upgrade database to level %d, the database is already at level %d.", requestLevel, currentLevel);
    status = 0;
  } else if (requestLevel == currentLevel) {
    logMsg(2, "Database is already at level %d, nothing to do.", requestLevel);
    status = 0;
  } else if (requestLevel > 7) {
    logMsg(2, "Cannot upgrade database to level %d, the maximum available upgrade level is %d.", requestLevel, 7);
    status = 0;
  } else {
    assert(currentLevel < requestLevel);
    int level = currentLevel + 1;
    while (level <= requestLevel) {
      status = upgradeTo(level++);
      if (status == 0) {
        break;
      }
    }
  }
  return status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fghCircleTable>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%r12d
  neg    %r12d
  cmovs  %edx,%r12d
  movsd  D25(%rip),%xmm0
  test   %edx,%edx
  je     L46
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
L46:
  movsd  D33(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  lea    0x1(%r12),%ebx
  mov    %ebx,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%r13)
  mov    %ebx,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,(%r14)
  mov    0x0(%r13),%rdi
  test   %rax,%rax
  je     L53
  test   %rdi,%rdi
  je     L53
L23:
  mov    0x0(%r13),%rax
  movq   $0x0,(%rax)
  mov    (%r14),%rax
  mov    D25(%rip),%rcx
  mov    %rcx,(%rax)
  cmp    $0x1,%r12d
  jle    L49
  mov    $0x8,%ebp
  mov    $0x1,%ebx
  lea    0x18(%rsp),%r15
L7:
  lea    0x10(%rsp),%rsi
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    %r15,%rdi
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x0(%r13),%rax
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm1,(%rax,%rbp,1)
  mov    (%r14),%rax
  movsd  %xmm0,(%rax,%rbp,1)
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r12d
  jne    L7
L49:
  mov    0x0(%r13),%rax
  movslq %r12d,%r12
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rax,%r12,8)
  mov    (%r14),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rax,%r12,8)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  call   <free@plt>
  mov    (%r14),%rdi
  call   <free@plt>
  lea    D32(%rip),%rdi
  call   <fgError@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: label: D25
type: f64
name: parse_data
arguments: label: D33
type: byte[8]
name: parse_data
arguments: label: D32
type: string

tool: D25: 1

tool: {"D33": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D32: Failed to allocate memory in fghCircleTable

assistant: ```c
void fghCircleTable(double **sint, double **cost, const int n) {
  int i;
  const int size = abs(n);
  const double angle = 2 * 3.14159265358979323846 / (double)((n == 0) ? 1 : n);
  *sint = (double *)calloc(sizeof(double), size + 1);
  *cost = (double *)calloc(sizeof(double), size + 1);
  if (!(*sint) || !(*cost)) {
    free(*sint);
    free(*cost);
    fgError("Failed to allocate memory in fghCircleTable");
  }
  (*sint)[0] = 0.0;
  (*cost)[0] = 1.0;
  for (i = 1; i < size; i++) {
    (*sint)[i] = sin(angle * i);
    (*cost)[i] = cos(angle * i);
  }
  (*sint)[size] = (*sint)[0];
  (*cost)[size] = (*cost)[0];
}
```