ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<uninitvar_mbstowcs>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <mbstowcs@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <mbstowcs@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <mbstowcs@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <mbstowcs@plt>
```

assistant: ```c
void uninitvar_mbstowcs(wchar_t *d, const char *s, size_t m) {
  wchar_t *dest;
  char *src;
  size_t max;
  (void)mbstowcs(dest, s, m);
  (void)mbstowcs(d, src, m);
  (void)mbstowcs(d, s, max);
  (void)mbstowcs(d, s, m);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StripName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  jmp    L4
L11:
  mov    -0x28(%rbp),%rax
L4:
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L18
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L28
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L28:
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *StripName(char *name) {
  char *begin = strrchr(name, '/');
  char *end, *result;
  int length;
  begin = (begin ? begin + 1 : name);
  end = strchr(begin, '.');
  length = (end ? (end - begin) : strlen(begin));
  result = (char *)malloc(length + 1);
  strncpy(result, begin, length);
  result[length] = '\0';
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<StripName>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbp
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbx
  sub    %ebp,%ebx
L18:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L18
```

assistant: ```c
char *StripName(char *name) {
  char *begin = strrchr(name, '/');
  char *end, *result;
  int length;
  begin = (begin ? begin + 1 : name);
  end = strchr(begin, '.');
  length = (end ? (end - begin) : strlen(begin));
  result = (char *)malloc(length + 1);
  strncpy(result, begin, length);
  result[length] = '\0';
  return (result);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StripName>:
  endbr64
  push   %r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%rbp
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbx
  sub    %ebp,%ebx
L1:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L1
```

assistant: ```c
char *StripName(char *name) {
  char *begin = strrchr(name, '/');
  char *end, *result;
  int length;
  begin = (begin ? begin + 1 : name);
  end = strchr(begin, '.');
  length = (end ? (end - begin) : strlen(begin));
  result = (char *)malloc(length + 1);
  strncpy(result, begin, length);
  result[length] = '\0';
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StripName>:
  endbr64
  push   %r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%rbp
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbx
  sub    %ebp,%ebx
L18:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L18
```

assistant: ```c
char *StripName(char *name) {
  char *begin = strrchr(name, '/');
  char *end, *result;
  int length;
  begin = (begin ? begin + 1 : name);
  end = strchr(begin, '.');
  length = (end ? (end - begin) : strlen(begin));
  result = (char *)malloc(length + 1);
  strncpy(result, begin, length);
  result[length] = '\0';
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  andl   $0xa,-0x4(%rbp)
  orl    $0xa,-0x4(%rbp)
  xorl   $0x3e8,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x32,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3e8,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3e7,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x9,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int var;
  var = 0;
  var = var + 1;
  var = var - 0;
  var = var * 10;
  var = var / 1;
  var = var % 9;
  var = var & 10;
  var = var | 10;
  var = var ^ 1000;
  var = var == var;
  var = var != 50;
  var = var > 1000;
  var = var < 1000;
  var = var >= 9;
  var = var <= 10;
  var = (var + 10, 9);
  return var;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x9,%eax
  ret
```

assistant: ```c
int main(void) {
  int var;
  var = 0;
  var = var + 1;
  var = var - 0;
  var = var * 10;
  var = var / 1;
  var = var % 9;
  var = var & 10;
  var = var | 10;
  var = var ^ 1000;
  var = var == var;
  var = var != 50;
  var = var > 1000;
  var = var < 1000;
  var = var >= 9;
  var = var <= 10;
  var = (var + 10, 9);
  return var;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x9,%eax
  ret
```

assistant: ```c
int main(void) {
  int var;
  var = 0;
  var = var + 1;
  var = var - 0;
  var = var * 10;
  var = var / 1;
  var = var % 9;
  var = var & 10;
  var = var | 10;
  var = var ^ 1000;
  var = var == var;
  var = var != 50;
  var = var > 1000;
  var = var < 1000;
  var = var >= 9;
  var = var <= 10;
  var = (var + 10, 9);
  return var;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x9,%eax
  ret
```

assistant: ```c
int main(void) {
  int var;
  var = 0;
  var = var + 1;
  var = var - 0;
  var = var * 10;
  var = var / 1;
  var = var % 9;
  var = var & 10;
  var = var | 10;
  var = var ^ 1000;
  var = var == var;
  var = var != 50;
  var = var > 1000;
  var = var < 1000;
  var = var >= 9;
  var = var <= 10;
  var = (var + 10, 9);
  return var;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<flush_i_cache>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x12000000,-0x8(%rbp)
  jmp    L23
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  addq   $0x10,-0x8(%rbp)
L23:
  cmpq   $0x12003fff,-0x8(%rbp)
  jbe    L39
  mov    $0xc002f000,%eax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L11:
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  addq   $0x20,-0x8(%rbp)
L22:
  mov    $0xc0030000,%eax
  cmp    %rax,-0x8(%rbp)
  jbe    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flush_i_cache() {
  volatile unsigned char *addr;
  for (addr = ((unsigned char *)0x12000000); addr < ((unsigned char *)0x12000000) + (128 * 16 * 4) * 2; addr += 16)
    *addr;
  for (addr = ((unsigned char *)0xc0020000) + 0x0000f000; addr <= ((unsigned char *)0xc0020000) + 0x0000f000 + 128 * 32; addr += 32)
    *(unsigned long *)addr = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<flush_i_cache>:
  endbr64
  mov    $0x12000000,%eax
L16:
  movzbl (%rax),%edx
  add    $0x10,%rax
  cmp    $0x12004000,%rax
  jne    L16
  mov    $0xc002f000,%eax
  mov    $0xc0030020,%edx
L0:
  movq   $0x0,(%rax)
  add    $0x20,%rax
  cmp    %rdx,%rax
  jne    L0
  ret
```

assistant: ```c
void flush_i_cache() {
  volatile unsigned char *addr;
  for (addr = ((unsigned char *)0x12000000); addr < ((unsigned char *)0x12000000) + (128 * 16 * 4) * 2; addr += 16)
    *addr;
  for (addr = ((unsigned char *)0xc0020000) + 0x0000f000; addr <= ((unsigned char *)0xc0020000) + 0x0000f000 + 128 * 32; addr += 32)
    *(unsigned long *)addr = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<flush_i_cache>:
  endbr64
  mov    $0x12000000,%eax
  nopl   0x0(%rax)
L8:
  movzbl (%rax),%edx
  add    $0x10,%rax
  cmp    $0x12004000,%rax
  jne    L8
  mov    $0xc002f000,%eax
  mov    $0xc0030020,%edx
  nopl   0x0(%rax)
L17:
  movq   $0x0,(%rax)
  add    $0x20,%rax
  cmp    %rdx,%rax
  jne    L17
  ret
```

assistant: ```c
void flush_i_cache() {
  volatile unsigned char *addr;
  for (addr = ((unsigned char *)0x12000000); addr < ((unsigned char *)0x12000000) + (128 * 16 * 4) * 2; addr += 16)
    *addr;
  for (addr = ((unsigned char *)0xc0020000) + 0x0000f000; addr <= ((unsigned char *)0xc0020000) + 0x0000f000 + 128 * 32; addr += 32)
    *(unsigned long *)addr = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flush_i_cache>:
  endbr64
  mov    $0x12000000,%eax
  nopl   0x0(%rax)
L13:
  movzbl (%rax),%edx
  add    $0x10,%rax
  cmp    $0x12004000,%rax
  jne    L13
  mov    $0xc002f000,%eax
  mov    $0xc0030020,%edx
  nopl   0x0(%rax)
L19:
  movq   $0x0,(%rax)
  add    $0x20,%rax
  cmp    %rdx,%rax
  jne    L19
  ret
```

assistant: ```c
void flush_i_cache() {
  volatile unsigned char *addr;
  for (addr = ((unsigned char *)0x12000000); addr < ((unsigned char *)0x12000000) + (128 * 16 * 4) * 2; addr += 16)
    *addr;
  for (addr = ((unsigned char *)0xc0020000) + 0x0000f000; addr <= ((unsigned char *)0xc0020000) + 0x0000f000 + 128 * 32; addr += 32)
    *(unsigned long *)addr = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x8,-0x4(%rbp)
  jmp    L1
L11:
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%edi
  call   <use_stuff@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L11
  nop
  leave
  ret
```

assistant: ```c
int h(int a, int b) {
  int i;
  for (i = 8; i <= b; i++)
    use_stuff(a + 8);
}
```
user: What is the c source code of the assembly code below?

```asm
<h>:
  endbr64
  cmp    $0x7,%esi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    $0x8,%ebx
  lea    0x8(%rdi),%ebp
L19:
  mov    %ebp,%edi
  call   <use_stuff@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  ret
```

assistant: ```c
int h(int a, int b) {
  int i;
  for (i = 8; i <= b; i++)
    use_stuff(a + 8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<h>:
  endbr64
  cmp    $0x7,%esi
  jle    L12
  push   %r12
  lea    0x8(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x8,%ebx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <use_stuff@plt>
  cmp    %ebx,%ebp
  jge    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int h(int a, int b) {
  int i;
  for (i = 8; i <= b; i++)
    use_stuff(a + 8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<h>:
  endbr64
  cmp    $0x7,%esi
  jle    L3
  push   %r12
  lea    0x8(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x8,%ebx
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <use_stuff@plt>
  cmp    %ebx,%ebp
  jge    L10
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int h(int a, int b) {
  int i;
  for (i = 8; i <= b; i++)
    use_stuff(a + 8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
L9:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x11(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L21
  movzbl -0x11(%rbp),%eax
  cmp    $0xa,%al
  je     L12
L21:
  mov    $0x1,%eax
  jmp    L41
L12:
  mov    $0x0,%eax
L41:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L52
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L52:
  cmpl   $0x0,-0xc(%rbp)
  jne    L9
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D14
type_infered: string

tool: D27: Zahl?: 

tool: D13: %d%c

tool: D14: Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:


assistant: ```c
int readNumber() {
  int invalidInput = 0, number;
  char c;
  do {
    printf("Zahl?: ");
    invalidInput = scanf("%d%c", &number, &c) != 2 || c != '\n';
    if (invalidInput)
      printf("Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:\n");
  } while (invalidInput);
  return number;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readNumber>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%r12
  lea    0x3(%rsp),%rbp
  lea    D1(%rip),%rbx
  lea    D9(%rip),%r13
  jmp    L33
L27:
  mov    %r13,%rdi
  call   <printf@plt>
L33:
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L27
  cmpb   $0xa,0x3(%rsp)
  jne    L27
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D2: Zahl?: 

tool: D1: %d%c

tool: D9: Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:


assistant: ```c
int readNumber() {
  int invalidInput = 0, number;
  char c;
  do {
    printf("Zahl?: ");
    invalidInput = scanf("%d%c", &number, &c) != 2 || c != '\n';
    if (invalidInput)
      printf("Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:\n");
  } while (invalidInput);
  return number;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readNumber>:
  endbr64
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  lea    0x4(%rsp),%rbp
  jmp    L35
  nopl   0x0(%rax)
L9:
  mov    %r14,%rdi
  call   <printf@plt>
L35:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L9
  cmpb   $0xa,0x3(%rsp)
  jne    L9
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D15: Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:


tool: D24: Zahl?: 

tool: D14: %d%c

assistant: ```c
int readNumber() {
  int invalidInput = 0, number;
  char c;
  do {
    printf("Zahl?: ");
    invalidInput = scanf("%d%c", &number, &c) != 2 || c != '\n';
    if (invalidInput)
      printf("Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:\n");
  } while (invalidInput);
  return number;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readNumber>:
  endbr64
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D20(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  lea    0x4(%rsp),%rbp
  jmp    L15
  nopl   0x0(%rax)
L23:
  mov    %r14,%rdi
  call   <printf@plt>
L15:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L23
  cmpb   $0xa,0x3(%rsp)
  jne    L23
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D20
type_infered: string

tool: D12: Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:


tool: D10: Zahl?: 

tool: D20: %d%c

assistant: ```c
int readNumber() {
  int invalidInput = 0, number;
  char c;
  do {
    printf("Zahl?: ");
    invalidInput = scanf("%d%c", &number, &c) != 2 || c != '\n';
    if (invalidInput)
      printf("Die Eingabe ist inkorrekt. Bitte eine korrekte Ganzzahl eingeben:\n");
  } while (invalidInput);
  return number;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cgemm_print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L32:
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L21:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %ecx,%xmm0
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x8,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L21
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L32
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: %d,%d:	%f	%f


assistant: ```c
void cgemm_print_matrix(int M, int K, float *A) {
  int i, j;
  float *ap = A;
  for (i = 0; i < M; i++) {
    for (j = 0; j < K; j++) {
      printf("%d,%d:	%f\t%f\n", i, j, ap[0], ap[1]);
      ap += 2;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cgemm_print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  test   %edi,%edi
  jle    L34
  mov    %esi,%r15d
  mov    %rdx,%rbp
  lea    -0x1(%rsi),%r13d
  lea    0x8(,%r13,8),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r12d
  lea    D1(%rip),%r14
  jmp    L49
L56:
  movss  0x0(%rbp,%rbx,8),%xmm0
  movss  0x4(%rbp,%rbx,8),%xmm1
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %r13,%rax
  jne    L56
  add    0x8(%rsp),%rbp
L51:
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  je     L34
L49:
  mov    $0x0,%ebx
  test   %r15d,%r15d
  jg     L56
  jmp    L51
L34:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: %d,%d:	%f	%f


assistant: ```c
void cgemm_print_matrix(int M, int K, float *A) {
  int i, j;
  float *ap = A;
  for (i = 0; i < M; i++) {
    for (j = 0; j < K; j++) {
      printf("%d,%d:	%f\t%f\n", i, j, ap[0], ap[1]);
      ap += 2;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cgemm_print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  test   %edi,%edi
  jle    L29
  lea    -0x1(%rsi),%ebp
  mov    %esi,%r14d
  mov    %rdx,%r15
  xor    %ebx,%ebx
  lea    0x8(,%rbp,8),%rax
  lea    D9(%rip),%r12
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L2:
  xor    %r13d,%r13d
  test   %r14d,%r14d
  jle    L19
  nopl   0x0(%rax,%rax,1)
L15:
  movss  (%r15,%r13,8),%xmm0
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  movss  0x4(%r15,%r13,8),%xmm1
  call   <printf@plt>
  mov    %r13,%rax
  add    $0x1,%r13
  cmp    %rax,%rbp
  jne    L15
  add    0x8(%rsp),%r15
L19:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jne    L2
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: %d,%d:	%f	%f


assistant: ```c
void cgemm_print_matrix(int M, int K, float *A) {
  int i, j;
  float *ap = A;
  for (i = 0; i < M; i++) {
    for (j = 0; j < K; j++) {
      printf("%d,%d:	%f\t%f\n", i, j, ap[0], ap[1]);
      ap += 2;
    }
  }
}
```