ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copiatabuleiro>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x288,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,(%rbx)
  mov    $0x2d9,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %r12,%r12
  je     L18
  mov    (%r12),%rcx
  mov    (%rbx),%rax
  mov    $0x2d9,%edx
  mov    (%rcx),%rsi
  mov    (%rax),%rdi
  call   <memcpy@plt>
L13:
  mov    %rbx,%rsi
  mov    $0x0,%edi
  jmp    L44
L18:
  mov    (%rbx),%rax
  mov    $0x2d9,%edx
  mov    $0x1,%esi
  mov    (%rax),%rdi
  call   <memset@plt>
  jmp    L13
L34:
  add    $0x8,%rsi
L44:
  mov    $0x0,%eax
  mov    %rsi,%r8
L41:
  mov    (%rsi),%rcx
  mov    %rax,%rdx
  add    $0x8,%rax
  mov    (%rcx,%rdx,1),%rdx
  add    $0x9,%rdx
  mov    %rdx,(%rcx,%rax,1)
  cmp    $0x40,%rax
  jne    L41
  add    $0x1,%edi
  cmp    $0x9,%edi
  je     L11
  test   %edi,%edi
  je     L34
  mov    (%r8),%rax
  lea    0x48(%rax),%rdx
  mov    %rdx,0x8(%r8)
  mov    0x40(%rax),%rcx
  lea    0x9(%rcx),%rdx
  mov    %rdx,0x48(%rax)
  jmp    L34
L11:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char ***copiatabuleiro(char ***old) {
  int i, j;
  char ***tabuleiro = malloc(9 * sizeof(char **));
  tabuleiro[0] = malloc(9 * 9 * sizeof(char *));
  tabuleiro[0][0] = malloc(9 * 9 * 9 * sizeof(char));
  if (old)
    memcpy(tabuleiro[0][0], **old, 9 * 9 * 9 * sizeof(char));
  else
    memset(tabuleiro[0][0], 1, 9 * 9 * 9 * sizeof(char));
  for (i = 0; i < 9; i++) {
    if (i) {
      tabuleiro[i] = tabuleiro[i - 1] + 9;
      tabuleiro[i][0] = tabuleiro[i - 1][9 - 1] + 9;
    }
    for (j = 1; j < 9; j++)
      tabuleiro[i][j] = tabuleiro[i][j - 1] + 9;
  }
  return tabuleiro;
}
```
user: What is the c source code of the assembly code below?

```asm
<copiatabuleiro>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x48,%edi
  push   %rbx
  call   <malloc@plt>
  mov    $0x288,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x2d9,%edi
  mov    %rax,(%r12)
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rbp,%rbp
  je     L7
  mov    0x0(%rbp),%rcx
  mov    (%r12),%rax
  mov    $0x2d9,%edx
  mov    (%rcx),%rsi
  mov    (%rax),%rdi
  call   <memcpy@plt>
L42:
  mov    (%r12),%rcx
  mov    %r12,%rsi
  lea    0x40(%r12),%rdi
  mov    (%rcx),%rdx
  nopw   0x0(%rax,%rax,1)
L50:
  lea    0x8(%rcx),%rax
  add    $0x40,%rcx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x8,%rax
L12:
  add    $0x9,%rdx
  mov    %rdx,(%rax)
  cmp    %rcx,%rax
  jne    L45
  cmp    %rsi,%rdi
  je     L48
  mov    (%rsi),%rax
  add    $0x8,%rsi
  mov    0x40(%rax),%rbx
  lea    0x48(%rax),%rcx
  mov    %rcx,(%rsi)
  lea    0x9(%rbx),%rdx
  mov    %rdx,0x48(%rax)
  jmp    L50
  nopl   0x0(%rax)
L48:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    (%r12),%rax
  mov    $0x2d9,%edx
  mov    $0x1,%esi
  mov    (%rax),%rdi
  call   <memset@plt>
  jmp    L42
```

assistant: ```c
char ***copiatabuleiro(char ***old) {
  int i, j;
  char ***tabuleiro = malloc(9 * sizeof(char **));
  tabuleiro[0] = malloc(9 * 9 * sizeof(char *));
  tabuleiro[0][0] = malloc(9 * 9 * 9 * sizeof(char));
  if (old)
    memcpy(tabuleiro[0][0], **old, 9 * 9 * 9 * sizeof(char));
  else
    memset(tabuleiro[0][0], 1, 9 * 9 * 9 * sizeof(char));
  for (i = 0; i < 9; i++) {
    if (i) {
      tabuleiro[i] = tabuleiro[i - 1] + 9;
      tabuleiro[i][0] = tabuleiro[i - 1][9 - 1] + 9;
    }
    for (j = 1; j < 9; j++)
      tabuleiro[i][j] = tabuleiro[i][j - 1] + 9;
  }
  return tabuleiro;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ai_accepttrade>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%eax
  mov    %eax,%edi
  call   <data_vps@plt>
  cmp    $0x6,%eax
  jle    L11
  mov    $0x0,%eax
  jmp    L29
L11:
  lea    -0x20(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gethand@plt>
  mov    -0x3c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rate_hand@plt>
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L22
L2:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x28(%rbp)
L22:
  cmpl   $0x4,-0x28(%rbp)
  jle    L2
  mov    -0x3c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rate_hand@plt>
  cmp    %eax,-0x24(%rbp)
  jge    L10
  mov    $0x1,%eax
  jmp    L29
L10:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int ai_accepttrade(int *trade, int player, int playerTrading) {
  if (data_vps(playerTrading) >= 7)
    return 0;
  int hand[5];
  gethand(player, hand);
  int rating = rate_hand(hand, player);
  int i;
  for (i = 0; i < 5; i++)
    hand[i] += trade[i];
  if (rate_hand(hand, player) > rating)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ai_accepttrade>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <data_vps@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x6,%edx
  jle    L11
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <gethand@plt>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <rate_hand@plt>
  mov    %eax,%r13d
  mov    %rbx,%rax
  mov    %rbp,%rdx
  lea    0x14(%rsp),%rsi
L19:
  mov    (%rdx),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rsi,%rax
  jne    L19
  mov    %rsp,%rdi
  mov    %r12d,%esi
  call   <rate_hand@plt>
  cmp    %r13d,%eax
  setg   %al
  movzbl %al,%eax
  jmp    L10
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ai_accepttrade(int *trade, int player, int playerTrading) {
  if (data_vps(playerTrading) >= 7)
    return 0;
  int hand[5];
  gethand(player, hand);
  int rating = rate_hand(hand, player);
  int i;
  for (i = 0; i < 5; i++)
    hand[i] += trade[i];
  if (rate_hand(hand, player) > rating)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ai_accepttrade>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <data_vps@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x6,%r8d
  jle    L33
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    %rsp,%r13
  mov    %ebp,%edi
  mov    %r13,%rsi
  call   <gethand@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <rate_hand@plt>
  mov    %rbx,%rdx
  lea    0x14(%rsp),%rsi
  mov    %eax,%r12d
  mov    %r13,%rax
L21:
  mov    (%rdx),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rsi,%rax
  jne    L21
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <rate_hand@plt>
  cmp    %r12d,%eax
  setg   %al
  movzbl %al,%eax
  jmp    L35
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ai_accepttrade(int *trade, int player, int playerTrading) {
  if (data_vps(playerTrading) >= 7)
    return 0;
  int hand[5];
  gethand(player, hand);
  int rating = rate_hand(hand, player);
  int i;
  for (i = 0; i < 5; i++)
    hand[i] += trade[i];
  if (rate_hand(hand, player) > rating)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ai_accepttrade>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %edx,%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <data_vps@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x6,%r8d
  jg     L17
  mov    %rsp,%r12
  mov    %ebp,%edi
  mov    %r12,%rsi
  call   <gethand@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <rate_hand@plt>
  movdqu 0x0(%r13),%xmm0
  mov    %ebp,%esi
  mov    %r12,%rdi
  paddd  (%rsp),%xmm0
  mov    %eax,%ebx
  mov    0x10(%r13),%eax
  add    %eax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <rate_hand@plt>
  cmp    %ebx,%eax
  setg   %al
  movzbl %al,%eax
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ai_accepttrade(int *trade, int player, int playerTrading) {
  if (data_vps(playerTrading) >= 7)
    return 0;
  int hand[5];
  gethand(player, hand);
  int rating = rate_hand(hand, player);
  int i;
  for (i = 0; i < 5; i++)
    hand[i] += trade[i];
  if (rate_hand(hand, player) > rating)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<floats_scale_self>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void floats_scale_self(float *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] = (float)(v[i] * scale);
}
```
user: Translate the below assembly code into C programming language:

```asm
<floats_scale_self>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L19:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rax),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
L4:
  ret
```

assistant: ```c
void floats_scale_self(float *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] = (float)(v[i] * scale);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<floats_scale_self>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L3:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtss2sd -0x4(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L3
L5:
  ret
```

assistant: ```c
void floats_scale_self(float *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] = (float)(v[i] * scale);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floats_scale_self>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edx
  movapd %xmm0,%xmm4
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L36
  shr    $0x2,%esi
  movapd %xmm0,%xmm3
  mov    %rdi,%rax
  sub    $0x1,%esi
  unpcklpd %xmm3,%xmm3
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   0x0(%rax,%rax,1)
L16:
  movlps 0x8(%rax),%xmm2
  cvtps2pd (%rax),%xmm0
  add    $0x10,%rax
  mulpd  %xmm3,%xmm0
  cvtps2pd %xmm2,%xmm1
  mulpd  %xmm3,%xmm1
  cvtpd2ps %xmm0,%xmm0
  cvtpd2ps %xmm1,%xmm1
  movlhps %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L16
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L32
L6:
  movslq %eax,%rsi
  pxor   %xmm0,%xmm0
  shl    $0x2,%rsi
  lea    (%rcx,%rsi,1),%rdi
  cvtss2sd (%rdi),%xmm0
  mulsd  %xmm4,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L15
  lea    0x4(%rcx,%rsi,1),%rdi
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtss2sd (%rdi),%xmm0
  mulsd  %xmm4,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi)
  cmp    %eax,%edx
  jle    L15
  lea    0x8(%rcx,%rsi,1),%rax
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  mulsd  %xmm4,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
L15:
  ret
  nopl   0x0(%rax)
L32:
  ret
L36:
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
void floats_scale_self(float *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] = (float)(v[i] * scale);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strrindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L61
L19:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L3:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L3
L29:
  cmpl   $0x0,-0x8(%rbp)
  jle    L14
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L14:
  addl   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k;
  int pos = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && t[k] == s[j]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      pos = i;
  }
  return pos;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L79
  movzbl (%rsi),%r9d
  mov    $0xffffffff,%r10d
  mov    $0x0,%r8d
  jmp    L34
L76:
  test   %dl,%dl
  jne    L74
  test   %ecx,%ecx
  cmovg  %r8d,%r10d
L74:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L39
L34:
  mov    %r9d,%edx
  mov    $0x0,%eax
  test   %r9b,%r9b
  je     L74
L16:
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rax,1)
  jne    L76
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L16
  jmp    L76
L79:
  mov    $0xffffffff,%r10d
L39:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k;
  int pos = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && t[k] == s[j]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      pos = i;
  }
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L69
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  mov    $0xffffffff,%r10d
  nopl   (%rax)
L53:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L46
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L51:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L49
L46:
  cmp    %dl,(%rdi,%rax,1)
  je     L51
L34:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L53
  mov    %r10d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    %r9d,%r10d
  jmp    L34
L69:
  mov    $0xffffffff,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k;
  int pos = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && t[k] == s[j]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      pos = i;
  }
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strrindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L32
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  mov    $0xffffffff,%r10d
  nopl   (%rax)
L1:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L51
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L5
L51:
  cmp    %dl,(%rdi,%rax,1)
  je     L44
L53:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L1
  mov    %r10d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %r9d,%r10d
  jmp    L53
L32:
  mov    $0xffffffff,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k;
  int pos = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && t[k] == s[j]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      pos = i;
  }
  return pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prompt_ShowHelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prompt_Printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D53(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prompt_Printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prompt_Printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prompt_Printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D54(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prompt_Printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prompt_Printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D53
type_infered: string
name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D16
type_infered: string
name: unpack_data
arguments: label: D54
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string

tool: D10: The following commands are available:


tool: D53:  ~p	Enter Packet mode


tool: D36:  ~t	Show timers


tool: D16:  ~m	Show memory map


tool: D54:  ~.	Terminate program


tool: D30:  ~?	This help


assistant: ```c
void prompt_ShowHelp(struct prompt *p) {
  prompt_Printf(p, "The following commands are available:\n");
  prompt_Printf(p, " ~p\tEnter Packet mode\n");
  prompt_Printf(p, " ~t\tShow timers\n");
  prompt_Printf(p, " ~m\tShow memory map\n");
  prompt_Printf(p, " ~.\tTerminate program\n");
  prompt_Printf(p, " ~?\tThis help\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prompt_ShowHelp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D31(%rip),%rsi
  call   <prompt_Printf@plt>
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <prompt_Printf@plt>
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <prompt_Printf@plt>
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <prompt_Printf@plt>
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <prompt_Printf@plt>
  lea    D36(%rip),%rsi
  mov    %rbx,%rdi
  call   <prompt_Printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D31
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D21
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string

tool: D31: The following commands are available:


tool: D23:  ~p	Enter Packet mode


tool: D18:  ~t	Show timers


tool: D21:  ~m	Show memory map


tool: D22:  ~.	Terminate program


tool: D36:  ~?	This help


assistant: ```c
void prompt_ShowHelp(struct prompt *p) {
  prompt_Printf(p, "The following commands are available:\n");
  prompt_Printf(p, " ~p\tEnter Packet mode\n");
  prompt_Printf(p, " ~t\tShow timers\n");
  prompt_Printf(p, " ~m\tShow memory map\n");
  prompt_Printf(p, " ~.\tTerminate program\n");
  prompt_Printf(p, " ~?\tThis help\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prompt_ShowHelp>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rsi
  mov    %rdi,%rbp
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D16(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D46(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D56(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  pop    %rbp
  jmp    1050 <prompt_Printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D46
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D56
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D27: The following commands are available:


tool: D16:  ~p	Enter Packet mode


tool: D46:  ~t	Show timers


tool: D5:  ~m	Show memory map


tool: D56:  ~.	Terminate program


tool: D7:  ~?	This help


assistant: ```c
void prompt_ShowHelp(struct prompt *p) {
  prompt_Printf(p, "The following commands are available:\n");
  prompt_Printf(p, " ~p\tEnter Packet mode\n");
  prompt_Printf(p, " ~t\tShow timers\n");
  prompt_Printf(p, " ~m\tShow memory map\n");
  prompt_Printf(p, " ~.\tTerminate program\n");
  prompt_Printf(p, " ~?\tThis help\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prompt_ShowHelp>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rsi
  mov    %rdi,%rbp
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D40(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D55(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D27(%rip),%rsi
  call   <prompt_Printf@plt>
  mov    %rbp,%rdi
  lea    D20(%rip),%rsi
  pop    %rbp
  jmp    1050 <prompt_Printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string
name: retrieve_data
arguments: tag: D55
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D19: The following commands are available:


tool: D40:  ~p	Enter Packet mode


tool: D55:  ~t	Show timers


tool: D5:  ~m	Show memory map


tool: D27:  ~.	Terminate program


tool: D20:  ~?	This help


assistant: ```c
void prompt_ShowHelp(struct prompt *p) {
  prompt_Printf(p, "The following commands are available:\n");
  prompt_Printf(p, " ~p\tEnter Packet mode\n");
  prompt_Printf(p, " ~t\tShow timers\n");
  prompt_Printf(p, " ~m\tShow memory map\n");
  prompt_Printf(p, " ~.\tTerminate program\n");
  prompt_Printf(p, " ~?\tThis help\n");
}
```