ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<collisions_found>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    $0x0,%eax
  cmp    $0x1,%esi
  jle    L19
  mov    %esi,%r13d
  mov    %rdx,%r15
  mov    %rcx,%rbp
  mov    $0x1,%ebx
L56:
  add    %ebx,%ebx
  cmp    %r13d,%ebx
  jle    L56
  lea    0x0(%r13,%r13,1),%edx
  cmp    %edx,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  lea    0x0(%rbp,%rax,4),%r12
  lea    0x3f(%rbx),%edx
  shr    $0x4,%rdx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r15,%r14
  lea    -0x1(%r13),%eax
  lea    0x8(%r15,%rax,8),%r15
  mov    $0x0,%r13d
L39:
  mov    %r13d,%edx
  testl  $0xf4000000,0xc(%rsp)
  jne    L24
L72:
  mov    (%r14),%rsi
  mov    0xc(%rsp),%edi
  call   <eval_hash_func@plt>
  mov    %eax,%edi
  mov    %eax,%esi
  mov    %r13d,%eax
  lea    -0x1(%rbx),%r9d
  mov    $0x1,%r8d
L0:
  lea    0x1(%rax,%rax,4),%eax
  add    %esi,%eax
  sar    $0x5,%esi
  mov    %r9d,%ecx
  and    %eax,%ecx
  mov    %r8d,%r10d
  shl    %cl,%r10d
  mov    %ecx,%edx
  shr    $0x6,%edx
  mov    %edx,%edx
  lea    (%r12,%rdx,4),%r11
  mov    (%r11),%edx
  test   %r10d,%edx
  je     L16
  mov    %ecx,%ecx
  cmp    %edi,0x0(%rbp,%rcx,4)
  jne    L0
  mov    $0x1,%eax
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    (%r14),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L72
L16:
  or     %r10d,%edx
  mov    %edx,(%r11)
  mov    %ecx,%ecx
  mov    %edi,0x0(%rbp,%rcx,4)
  add    $0x8,%r14
  cmp    %r15,%r14
  jne    L39
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
int collisions_found(uint32_t func, int n, const char *strings[], void *mem) {
  int i;
  unsigned bucket_count = 1;
  if (n < 2)
    return 0;
  while ((int)bucket_count <= n)
    bucket_count *= 2;
  assert((int)bucket_count <= n * 2);
  uint32_t *const buckets = mem;
  uint64_t *const bitmap = (void *)(buckets + bucket_count);
  memset(bitmap, 0, (sizeof(uint64_t) * ((bucket_count) + 63) / 64));
  for (i = 0; i < n; i++) {
    uint32_t hash = eval_hash_func(func, strings[i], (0xf4000000 & func) ? strlen(strings[i]) : 0);
    uint32_t j = 0;
    uint32_t perturb = hash;
    while (1) {
      j = j * 5 + 1 + perturb;
      perturb >>= 5;
      unsigned index = j & (bucket_count - 1);
      uint64_t mask = (uint64_t)1 << (index & 63);
      if (bitmap[index / 64] & mask) {
        if (buckets[index] == hash)
          return 1;
      } else {
        bitmap[index / 64] |= mask;
        buckets[index] = hash;
        break;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<collisions_found>:
  endbr64
  cmp    $0x1,%esi
  jle    L57
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L49:
  add    %r13d,%r13d
  cmp    %r12d,%r13d
  jle    L49
  lea    (%r12,%r12,1),%eax
  xor    %edi,%edi
  cmp    %eax,%r13d
  setle  %dil
  call   <assert@plt>
  mov    %r13d,%eax
  lea    0x3f(%r13),%edx
  xor    %esi,%esi
  lea    (%r14,%rax,4),%r15
  shr    $0x4,%rdx
  sub    $0x1,%r13d
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %ebx,%eax
  and    $0xf4000000,%eax
  mov    %eax,0xc(%rsp)
  lea    -0x1(%r12),%eax
  lea    0x8(%rbp,%rax,8),%r12
L78:
  mov    0xc(%rsp),%eax
  xor    %edx,%edx
  test   %eax,%eax
  jne    L25
L32:
  mov    0x0(%rbp),%rsi
  mov    %ebx,%edi
  call   <eval_hash_func@plt>
  mov    $0x1,%r10d
  mov    %eax,%r9d
  mov    %eax,%edx
  xor    %eax,%eax
  jmp    L72
  nopl   0x0(%rax)
L51:
  cmp    %r9d,(%rcx)
  je     L14
L72:
  lea    0x1(%rax,%rax,4),%eax
  mov    %r10d,%r11d
  add    %edx,%eax
  sar    $0x5,%edx
  mov    %eax,%ecx
  and    %r13d,%ecx
  mov    %ecx,%esi
  shl    %cl,%r11d
  lea    (%r14,%rcx,4),%rcx
  shr    $0x6,%esi
  lea    (%r15,%rsi,4),%rdi
  mov    (%rdi),%esi
  test   %r11d,%esi
  jne    L51
  or     %r11d,%esi
  add    $0x8,%rbp
  mov    %esi,(%rdi)
  mov    %r9d,(%rcx)
  cmp    %rbp,%r12
  jne    L78
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L25:
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
  ret
```

assistant: ```c
int collisions_found(uint32_t func, int n, const char *strings[], void *mem) {
  int i;
  unsigned bucket_count = 1;
  if (n < 2)
    return 0;
  while ((int)bucket_count <= n)
    bucket_count *= 2;
  assert((int)bucket_count <= n * 2);
  uint32_t *const buckets = mem;
  uint64_t *const bitmap = (void *)(buckets + bucket_count);
  memset(bitmap, 0, (sizeof(uint64_t) * ((bucket_count) + 63) / 64));
  for (i = 0; i < n; i++) {
    uint32_t hash = eval_hash_func(func, strings[i], (0xf4000000 & func) ? strlen(strings[i]) : 0);
    uint32_t j = 0;
    uint32_t perturb = hash;
    while (1) {
      j = j * 5 + 1 + perturb;
      perturb >>= 5;
      unsigned index = j & (bucket_count - 1);
      uint64_t mask = (uint64_t)1 << (index & 63);
      if (bitmap[index / 64] & mask) {
        if (buckets[index] == hash)
          return 1;
      } else {
        bitmap[index / 64] |= mask;
        buckets[index] = hash;
        break;
      }
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<collisions_found>:
  endbr64
  cmp    $0x1,%esi
  jle    L71
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L24:
  add    %r13d,%r13d
  cmp    %r12d,%r13d
  jle    L24
  lea    (%r12,%r12,1),%eax
  xor    %edi,%edi
  cmp    %eax,%r13d
  setle  %dil
  call   <assert@plt>
  mov    %r13d,%eax
  lea    0x3f(%r13),%edx
  xor    %esi,%esi
  lea    (%r14,%rax,4),%r15
  shr    $0x4,%rdx
  sub    $0x1,%r13d
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %ebx,%eax
  and    $0xf4000000,%eax
  mov    %eax,0xc(%rsp)
  lea    -0x1(%r12),%eax
  lea    0x8(%rbp,%rax,8),%r12
L22:
  mov    0xc(%rsp),%eax
  xor    %edx,%edx
  test   %eax,%eax
  jne    L39
L34:
  mov    0x0(%rbp),%rsi
  mov    %ebx,%edi
  call   <eval_hash_func@plt>
  mov    $0x1,%r10d
  mov    %eax,%r9d
  mov    %eax,%edx
  xor    %eax,%eax
  jmp    L77
  nopl   0x0(%rax)
L40:
  cmp    %r9d,(%rcx)
  je     L49
L77:
  lea    0x1(%rax,%rax,4),%eax
  mov    %r10d,%r11d
  add    %edx,%eax
  sar    $0x5,%edx
  mov    %eax,%ecx
  and    %r13d,%ecx
  mov    %ecx,%esi
  shl    %cl,%r11d
  lea    (%r14,%rcx,4),%rcx
  shr    $0x6,%esi
  lea    (%r15,%rsi,4),%rdi
  mov    (%rdi),%esi
  test   %r11d,%esi
  jne    L40
  or     %r11d,%esi
  add    $0x8,%rbp
  mov    %esi,(%rdi)
  mov    %r9d,(%rcx)
  cmp    %rbp,%r12
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L39:
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L71:
  xor    %eax,%eax
  ret
```

assistant: ```c
int collisions_found(uint32_t func, int n, const char *strings[], void *mem) {
  int i;
  unsigned bucket_count = 1;
  if (n < 2)
    return 0;
  while ((int)bucket_count <= n)
    bucket_count *= 2;
  assert((int)bucket_count <= n * 2);
  uint32_t *const buckets = mem;
  uint64_t *const bitmap = (void *)(buckets + bucket_count);
  memset(bitmap, 0, (sizeof(uint64_t) * ((bucket_count) + 63) / 64));
  for (i = 0; i < n; i++) {
    uint32_t hash = eval_hash_func(func, strings[i], (0xf4000000 & func) ? strlen(strings[i]) : 0);
    uint32_t j = 0;
    uint32_t perturb = hash;
    while (1) {
      j = j * 5 + 1 + perturb;
      perturb >>= 5;
      unsigned index = j & (bucket_count - 1);
      uint64_t mask = (uint64_t)1 << (index & 63);
      if (bitmap[index / 64] & mask) {
        if (buckets[index] == hash)
          return 1;
      } else {
        bitmap[index / 64] |= mask;
        buckets[index] = hash;
        break;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mem_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L0
L15:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
void *mem_double(void *ptr, int size) {
  void *newptr;
  newptr = calloc(2 * size, 1);
  if (newptr == NULL) {
    return NULL;
  }
  memcpy(newptr, ptr, size);
  free(ptr);
  return newptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mem_double>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    (%rsi,%rsi,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
L3:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *mem_double(void *ptr, int size) {
  void *newptr;
  newptr = calloc(2 * size, 1);
  if (newptr == NULL) {
    return NULL;
  }
  memcpy(newptr, ptr, size);
  free(ptr);
  return newptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_double>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rax,%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L7:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *mem_double(void *ptr, int size) {
  void *newptr;
  newptr = calloc(2 * size, 1);
  if (newptr == NULL) {
    return NULL;
  }
  memcpy(newptr, ptr, size);
  free(ptr);
  return newptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_double>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *mem_double(void *ptr, int size) {
  void *newptr;
  newptr = calloc(2 * size, 1);
  if (newptr == NULL) {
    return NULL;
  }
  memcpy(newptr, ptr, size);
  free(ptr);
  return newptr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pem_check_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jg     L47
  mov    $0x0,%eax
  jmp    L38
L47:
  mov    -0x10(%rbp),%eax
  cltq
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L58
  mov    $0x0,%eax
  jmp    L38
L58:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L35
  mov    $0x0,%eax
  jmp    L38
L35:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
int pem_check_suffix(const char *pem_str, const char *suffix) {
  int pem_len = strlen(pem_str);
  int suffix_len = strlen(suffix);
  const char *p;
  if (suffix_len + 1 >= pem_len)
    return 0;
  p = pem_str + pem_len - suffix_len;
  if (strcmp(p, suffix))
    return 0;
  p--;
  if (*p != ' ')
    return 0;
  return p - pem_str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pem_check_suffix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
  mov    $0x0,%edx
  cmp    %ebx,%ecx
  jl     L16
L25:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  movslq %ebx,%rbx
  cltq
  sub    %rax,%rbx
  add    %rbp,%rbx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  jne    L25
  cmpb   $0x20,-0x1(%rbx)
  jne    L25
  lea    -0x1(%rbx),%rdx
  sub    %ebp,%edx
  jmp    L25
```

assistant: ```c
int pem_check_suffix(const char *pem_str, const char *suffix) {
  int pem_len = strlen(pem_str);
  int suffix_len = strlen(suffix);
  const char *p;
  if (suffix_len + 1 >= pem_len)
    return 0;
  p = pem_str + pem_len - suffix_len;
  if (strcmp(p, suffix))
    return 0;
  p--;
  if (*p != ' ')
    return 0;
  return p - pem_str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pem_check_suffix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  cmp    %ebx,%edx
  jl     L13
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  cltq
  mov    %rbp,%rsi
  sub    %rax,%rbx
  add    %r12,%rbx
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  cmpb   $0x20,-0x1(%rbx)
  jne    L1
  lea    -0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  sub    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int pem_check_suffix(const char *pem_str, const char *suffix) {
  int pem_len = strlen(pem_str);
  int suffix_len = strlen(suffix);
  const char *p;
  if (suffix_len + 1 >= pem_len)
    return 0;
  p = pem_str + pem_len - suffix_len;
  if (strcmp(p, suffix))
    return 0;
  p--;
  if (*p != ' ')
    return 0;
  return p - pem_str;
}
```
user: What is the c source code of the assembly code below?

```asm
<pem_check_suffix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  cmp    %ebx,%edx
  jl     L27
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  cltq
  mov    %rbp,%rsi
  sub    %rax,%rbx
  add    %r12,%rbx
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
  cmpb   $0x20,-0x1(%rbx)
  jne    L11
  lea    -0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  sub    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int pem_check_suffix(const char *pem_str, const char *suffix) {
  int pem_len = strlen(pem_str);
  int suffix_len = strlen(suffix);
  const char *p;
  if (suffix_len + 1 >= pem_len)
    return 0;
  p = pem_str + pem_len - suffix_len;
  if (strcmp(p, suffix))
    return 0;
  p--;
  if (*p != ' ')
    return 0;
  return p - pem_str;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  jmp    L0
L22:
  addq   $0x1,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jne    L78
  mov    -0x28(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  je     L31
L78:
  movq   $0x1,-0x20(%rbp)
  jmp    L1
L2:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jg     L101
  mov    -0x30(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L30
  addq   $0x1,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x30(%rbp)
  jmp    L1
L30:
  addq   $0x1,-0x20(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  jmp    L1
L101:
  subq   $0x1,-0x20(%rbp)
  jmp    L111
L1:
  mov    -0x30(%rbp),%rax
  cmp    $0x1,%rax
  jne    L2
L111:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L22
  jmp    L66
L31:
  nop
L66:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L99
  call   <__stack_chk_fail@plt>
L99:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D15
data_type: string

tool: D5: Case %lld: A = %lld, limit = %lld, number of terms = %lld


tool: D15: %lld%lld

assistant: ```c
main() {
  long long A, limit, a, l, number, i = 0;
  while (scanf("%lld%lld", &a, &l) > 0) {
    i++;
    A = a;
    if (a == l && l == -1)
      break;
    number = 1;
    while (a != 1) {
      if (a <= l)
        if (a % 2 == 0) {
          number++;
          a /= 2;
        } else {
          number++;
          a = a * 3 + 1;
        }
      else {
        number--;
        break;
      }
    }
    printf("Case %lld: A = %lld, limit = %lld, number of terms = %lld\n", i, A, l, number);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  lea    D14(%rip),%r13
  mov    $0x1,%ebx
  lea    D1(%rip),%r14
  jmp    L102
L13:
  mov    %rdx,%r8
  lea    0x1(%rax,%rax,2),%rax
L88:
  add    $0x1,%rdx
  mov    %ebx,%ecx
  cmp    $0x1,%rax
  je     L119
  mov    %rax,%rbp
L2:
  cmp    %rax,%rsi
  jl     L72
  test   $0x1,%al
  jne    L13
  mov    %rdx,%r8
  mov    %rax,%rcx
  shr    $0x3f,%rcx
  add    %rcx,%rax
  sar    %rax
  jmp    L88
L72:
  test   %cl,%cl
  je     L53
  mov    %rbp,0x8(%rsp)
L53:
  lea    -0x2(%rdx),%r8
L25:
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
L102:
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L77
  add    $0x1,%r12
  mov    0x8(%rsp),%rdi
  mov    0x10(%rsp),%rsi
  cmp    $0xffffffffffffffff,%rsi
  sete   %cl
  cmp    %rdi,%rsi
  sete   %al
  and    %al,%cl
  jne    L77
  cmp    $0x1,%rdi
  je     L11
  mov    %rdi,%rax
  mov    $0x2,%edx
  jmp    L2
L119:
  movq   $0x1,0x8(%rsp)
  jmp    L25
L11:
  mov    %rdi,%r8
  jmp    L25
L77:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D14: %lld%lld

tool: D1: Case %lld: A = %lld, limit = %lld, number of terms = %lld


assistant: ```c
main() {
  long long A, limit, a, l, number, i = 0;
  while (scanf("%lld%lld", &a, &l) > 0) {
    i++;
    A = a;
    if (a == l && l == -1)
      break;
    number = 1;
    while (a != 1) {
      if (a <= l)
        if (a % 2 == 0) {
          number++;
          a /= 2;
        } else {
          number++;
          a = a * 3 + 1;
        }
      else {
        number--;
        break;
      }
    }
    printf("Case %lld: A = %lld, limit = %lld, number of terms = %lld\n", i, A, l, number);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   0x0(%rax)
L66:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L46
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%r9
  add    $0x1,%rbx
  cmp    $0xffffffffffffffff,%rcx
  sete   %dl
  cmp    %r9,%rcx
  sete   %al
  and    %al,%dl
  jne    L46
  cmp    $0x1,%r9
  je     L99
  mov    %r9,%rax
  mov    $0x1,%r8d
  jmp    L69
  nop
L1:
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  mov    $0x1,%edx
  sar    %rax
  cmp    $0x1,%rax
  je     L106
L38:
  mov    %rax,%r15
L69:
  cmp    %rax,%rcx
  jl     L35
  add    $0x1,%r8
  test   $0x1,%al
  je     L1
  lea    0x1(%rax,%rax,2),%rax
  mov    $0x1,%edx
  cmp    $0x1,%rax
  jne    L38
L106:
  movq   $0x1,0x8(%rsp)
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L35:
  test   %dl,%dl
  je     L40
  mov    %r15,0x8(%rsp)
L40:
  sub    $0x1,%r8
L0:
  mov    %r9,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L66
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  mov    $0x1,%r8d
  jmp    L0
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string

tool: D10: Case %lld: A = %lld, limit = %lld, number of terms = %lld


tool: D11: %lld%lld

assistant: ```c
main() {
  long long A, limit, a, l, number, i = 0;
  while (scanf("%lld%lld", &a, &l) > 0) {
    i++;
    A = a;
    if (a == l && l == -1)
      break;
    number = 1;
    while (a != 1) {
      if (a <= l)
        if (a % 2 == 0) {
          number++;
          a /= 2;
        } else {
          number++;
          a = a * 3 + 1;
        }
      else {
        number--;
        break;
      }
    }
    printf("Case %lld: A = %lld, limit = %lld, number of terms = %lld\n", i, A, l, number);
  }
  return 0;
}
```