ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rtcClearPeriodicEvent>:
  endbr64
  mov    0x40010a10,%eax
  and    $0x100,%eax
  mov    %eax,0x40010a10
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int rtcClearPeriodicEvent(void) {
  (*((volatile unsigned int *const)(0x40010a00 + 0x10))) &= (1 << 8);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rtcClearPeriodicEvent>:
  endbr64
  mov    0x40010a10,%eax
  and    $0x100,%eax
  mov    %eax,0x40010a10
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int rtcClearPeriodicEvent(void) {
  (*((volatile unsigned int *const)(0x40010a00 + 0x10))) &= (1 << 8);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<caller>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  call   *%rax
  nop
  leave
  ret
```

assistant: ```c
void caller(void *arg) {
  void (*func)(void) = (void *)(void *)arg;
  func();
}
```
user: Translate the below assembly code into C programming language:

```asm
<caller>:
  endbr64
  sub    $0x8,%rsp
  call   *%rdi
  add    $0x8,%rsp
  ret
```

assistant: ```c
void caller(void *arg) {
  void (*func)(void) = (void *)(void *)arg;
  func();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<caller>:
  endbr64
  jmp    *%rdi
```

assistant: ```c
void caller(void *arg) {
  void (*func)(void) = (void *)(void *)arg;
  func();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<caller>:
  endbr64
  jmp    *%rdi
```

assistant: ```c
void caller(void *arg) {
  void (*func)(void) = (void *)(void *)arg;
  func();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x63,%ebx
  jmp    L11
L8:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  mov    %eax,%edi
  call   <chug@plt>
L11:
  test   %ebx,%ebx
  jne    L8
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: 

tool: D9: 
Time to buy more beer!


assistant: ```c
main() {
  register beers;
  for (beers = (99); beers; chug(beers--))
    puts("");
  puts("\nTime to buy more beer!\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x63,%ebx
  lea    D14(%rip),%rbp
L0:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <chug@plt>
  test   %ebx,%ebx
  jne    L0
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D9
type: string

tool: 

tool: D9: 
Time to buy more beer!


assistant: ```c
main() {
  register beers;
  for (beers = (99); beers; chug(beers--))
    puts("");
  puts("\nTime to buy more beer!\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x63,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <chug@plt>
  test   %ebx,%ebx
  jne    L3
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D1
type: string

tool: 

tool: D1: 
Time to buy more beer!


assistant: ```c
main() {
  register beers;
  for (beers = (99); beers; chug(beers--))
    puts("");
  puts("\nTime to buy more beer!\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    $0x63,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <chug@plt>
  test   %ebx,%ebx
  jne    L8
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string

tool: 

tool: D5: 
Time to buy more beer!


assistant: ```c
main() {
  register beers;
  for (beers = (99); beers; chug(beers--))
    puts("");
  puts("\nTime to buy more beer!\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_char_size_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L22
L15:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_char_size@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L22
L31:
  mov    -0x24(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x24(%rbp),%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_strlen_screen@plt>
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int utf8_char_size_screen(const char *string) {
  int char_size;
  char utf_char[16];
  if (!string)
    return 0;
  char_size = utf8_char_size(string);
  if (char_size == 0)
    return 0;
  memcpy(utf_char, string, char_size);
  utf_char[char_size] = '\0';
  return utf8_strlen_screen(utf_char);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utf8_char_size_screen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L20
  mov    %rdi,%rbp
  call   <utf8_char_size@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L37
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    %rsp,%r12
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  mov    %r12,%rdi
  call   <utf8_strlen_screen@plt>
  mov    %eax,%ebx
  jmp    L20
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utf8_char_size_screen(const char *string) {
  int char_size;
  char utf_char[16];
  if (!string)
    return 0;
  char_size = utf8_char_size(string);
  if (char_size == 0)
    return 0;
  memcpy(utf_char, string, char_size);
  utf_char[char_size] = '\0';
  return utf8_strlen_screen(utf_char);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utf8_char_size_screen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L19
  mov    %rdi,%rbp
  call   <utf8_char_size@plt>
  movslq %eax,%rbx
  test   %ebx,%ebx
  jne    L10
L19:
  xor    %eax,%eax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rsp,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <utf8_strlen_screen@plt>
  jmp    L14
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utf8_char_size_screen(const char *string) {
  int char_size;
  char utf_char[16];
  if (!string)
    return 0;
  char_size = utf8_char_size(string);
  if (char_size == 0)
    return 0;
  memcpy(utf_char, string, char_size);
  utf_char[char_size] = '\0';
  return utf8_strlen_screen(utf_char);
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_char_size_screen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%rbp
  call   <utf8_char_size@plt>
  movslq %eax,%rbx
  test   %ebx,%ebx
  jne    L0
L12:
  xor    %eax,%eax
L31:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rsp,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <utf8_strlen_screen@plt>
  jmp    L31
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utf8_char_size_screen(const char *string) {
  int char_size;
  char utf_char[16];
  if (!string)
    return 0;
  char_size = utf8_char_size(string);
  if (char_size == 0)
    return 0;
  memcpy(utf_char, string, char_size);
  utf_char[char_size] = '\0';
  return utf8_strlen_screen(utf_char);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pexpr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <symbol@plt>
  cmp    $0x6,%eax
  jne    L28
  mov    $0xf,%edi
  call   <expr@plt>
  mov    $0x0,%eax
  call   <symbol@plt>
  cmp    $0x7,%eax
  je     L22
L28:
  mov    $0x29,%edi
  call   <error@plt>
  jmp    L6
L22:
  nop
L6:
  pop    %rbp
  ret
```

assistant: ```c
void pexpr() {
  if (symbol() == 6) {
    expr(15);
    if (symbol() == 7)
      return;
  }
  error('()');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pexpr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <symbol@plt>
  cmp    $0x6,%eax
  je     L7
L2:
  mov    $0x29,%edi
  call   <error@plt>
L5:
  add    $0x8,%rsp
  ret
L7:
  mov    $0xf,%edi
  call   <expr@plt>
  mov    $0x0,%eax
  call   <symbol@plt>
  cmp    $0x7,%eax
  jne    L2
  jmp    L5
```

assistant: ```c
void pexpr() {
  if (symbol() == 6) {
    expr(15);
    if (symbol() == 7)
      return;
  }
  error('()');
}
```
user: What is the c source code of the assembly code below?

```asm
<pexpr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <symbol@plt>
  cmp    $0x6,%eax
  je     L13
L12:
  mov    $0x29,%edi
  add    $0x8,%rsp
  jmp    1080 <error@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0xf,%edi
  call   <expr@plt>
  xor    %eax,%eax
  call   <symbol@plt>
  cmp    $0x7,%eax
  jne    L12
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pexpr() {
  if (symbol() == 6) {
    expr(15);
    if (symbol() == 7)
      return;
  }
  error('()');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pexpr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <symbol@plt>
  cmp    $0x6,%eax
  je     L6
L15:
  mov    $0x29,%edi
  add    $0x8,%rsp
  jmp    1080 <error@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xf,%edi
  call   <expr@plt>
  xor    %eax,%eax
  call   <symbol@plt>
  cmp    $0x7,%eax
  jne    L15
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pexpr() {
  if (symbol() == 6) {
    expr(15);
    if (symbol() == 7)
      return;
  }
  error('()');
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L2:
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L2
  jmp    L47
L45:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L47:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L40
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  cmp    %rax,-0x28(%rbp)
  ja     L45
L40:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L66
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L66:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
size_t ft_strlcat(char *dst, const char *src, size_t size) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (dst[i] && i < size)
    i++;
  while (src[j] && (i + j + 1) < size) {
    dst[i + j] = src[j];
    j++;
  }
  if (i < size)
    dst[i + j] = 0;
  return (i + ft_strlen(src));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_strlcat>:
  endbr64
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%rdi
  cmpb   $0x0,(%r9)
  je     L109
  test   %rdx,%rdx
  je     L109
  mov    $0x0,%ebx
L2:
  add    $0x1,%rbx
  cmpb   $0x0,(%r9,%rbx,1)
  je     L48
  cmp    %rbx,%rdx
  ja     L2
L48:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L80
  lea    0x1(%rbx),%rsi
  cmp    %rsi,%rdx
  jbe    L19
  mov    $0x0,%eax
  lea    (%r9,%rbx,1),%r10
L14:
  mov    %cl,(%r10,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L81
  lea    (%rax,%rsi,1),%r8
  cmp    %r8,%rdx
  ja     L14
L81:
  cmp    %rbx,%rdx
  jbe    L104
  add    %rbx,%r9
  movb   $0x0,(%r9,%rax,1)
L104:
  call   <ft_strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
L109:
  mov    $0x0,%ebx
  jmp    L48
L80:
  mov    $0x0,%eax
  jmp    L81
L19:
  mov    $0x0,%eax
  jmp    L81
```

assistant: ```c
size_t ft_strlcat(char *dst, const char *src, size_t size) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (dst[i] && i < size)
    i++;
  while (src[j] && (i + j + 1) < size) {
    dst[i + j] = src[j];
    j++;
  }
  if (i < size)
    dst[i + j] = 0;
  return (i + ft_strlen(src));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strlcat>:
  endbr64
  mov    %rdi,%r9
  push   %rbx
  xor    %ebx,%ebx
  mov    %rsi,%rdi
  cmpb   $0x0,(%r9)
  je     L65
  test   %rdx,%rdx
  jne    L111
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L70:
  cmp    %rbx,%rdx
  jbe    L65
L111:
  add    $0x1,%rbx
  cmpb   $0x0,(%r9,%rbx,1)
  jne    L70
L65:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L83
  lea    0x1(%rbx),%rsi
  xor    %eax,%eax
  cmp    %rsi,%rdx
  jbe    L64
  lea    (%r9,%rbx,1),%r10
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L109:
  lea    (%rax,%rsi,1),%r8
  cmp    %r8,%rdx
  jbe    L64
L72:
  mov    %cl,(%r10,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L109
L64:
  cmp    %rbx,%rdx
  jbe    L38
  add    %rbx,%r9
  movb   $0x0,(%r9,%rax,1)
L38:
  call   <ft_strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
L83:
  xor    %eax,%eax
  jmp    L64
```

assistant: ```c
size_t ft_strlcat(char *dst, const char *src, size_t size) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (dst[i] && i < size)
    i++;
  while (src[j] && (i + j + 1) < size) {
    dst[i + j] = src[j];
    j++;
  }
  if (i < size)
    dst[i + j] = 0;
  return (i + ft_strlen(src));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strlcat>:
  endbr64
  mov    %rdi,%r9
  push   %rbx
  xor    %ebx,%ebx
  mov    %rsi,%rdi
  cmpb   $0x0,(%r9)
  je     L96
  test   %rdx,%rdx
  jne    L31
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L69:
  cmp    %rbx,%rdx
  jbe    L96
L31:
  add    $0x1,%rbx
  cmpb   $0x0,(%r9,%rbx,1)
  jne    L69
L96:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L42
  lea    0x1(%rbx),%rsi
  xor    %eax,%eax
  cmp    %rsi,%rdx
  jbe    L48
  lea    (%r9,%rbx,1),%r10
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L15:
  lea    (%rax,%rsi,1),%r8
  cmp    %r8,%rdx
  jbe    L48
L87:
  mov    %cl,(%r10,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L15
L48:
  cmp    %rbx,%rdx
  jbe    L101
  add    %rbx,%r9
  movb   $0x0,(%r9,%rax,1)
L101:
  call   <ft_strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
L42:
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
size_t ft_strlcat(char *dst, const char *src, size_t size) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (dst[i] && i < size)
    i++;
  while (src[j] && (i + j + 1) < size) {
    dst[i + j] = src[j];
    j++;
  }
  if (i < size)
    dst[i + j] = 0;
  return (i + ft_strlen(src));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_random>:
  endbr64
  mov    D38(%rip),%rdi
  imul   $0xe66d,%rdi,%rcx
  add    $0xb,%rcx
  imul   $0xdeec,%rdi,%rsi
  mov    %rcx,%rax
  shr    $0x10,%rax
  add    %rax,%rsi
  mov    D46(%rip),%r8
  imul   $0xe66d,%r8,%rdx
  movzwl %si,%eax
  add    %rax,%rdx
  imul   $0xe66d,0x2f01(%rip),%rax        # 4040 <x.1+0x10>
  imul   $0xdeec,%r8,%r8
  add    %r8,%rax
  lea    (%rdi,%rdi,4),%rdi
  add    %rdi,%rax
  shr    $0x10,%rsi
  add    %rsi,%rax
  mov    %rdx,%rsi
  shr    $0x10,%rsi
  add    %rsi,%rax
  and    $0xffff,%ecx
  mov    %rcx,D12(%rip)
  movzwl %dx,%edx
  mov    %rdx,D12(%rip)
  movzwl %ax,%eax
  mov    %rax,D12(%rip)
  shl    $0x10,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
unsigned long hash_random(void) {
  static unsigned long x[3] = {0xe66du, 0xdeecu, 0x5u};
  const unsigned long MASK = 0x0000ffffu;
  const unsigned long A[3] = {0xe66du, 0xdeecu, 0x5u};
  const unsigned long B = 0xBu;
  unsigned long product[3];
  product[0] = A[0] * x[0] + B;
  product[1] = A[1] * x[0] + (product[0] >> 16);
  product[2] = A[1] * x[1] + A[0] * x[2] + A[2] * x[0] + (product[1] >> 16);
  product[1] = A[0] * x[1] + (product[1] & MASK);
  product[2] += (product[1] >> 16);
  x[0] = (product[0] & MASK);
  x[1] = (product[1] & MASK);
  x[2] = (product[2] & MASK);
  return x[1] + (x[2] << 16);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash_random>:
  endbr64
  mov    D34(%rip),%rdi
  mov    D22(%rip),%r8
  imul   $0xe66d,%rdi,%rcx
  imul   $0xdeec,%rdi,%rsi
  lea    (%rdi,%rdi,4),%rdi
  imul   $0xe66d,%r8,%rdx
  add    $0xb,%rcx
  imul   $0xdeec,%r8,%r8
  mov    %rcx,%rax
  and    $0xffff,%ecx
  shr    $0x10,%rax
  mov    %rcx,D43(%rip)
  add    %rax,%rsi
  movzwl %si,%eax
  shr    $0x10,%rsi
  add    %rax,%rdx
  imul   $0xe66d,0x2ede(%rip),%rax        # 4040 <x.1+0x10>
  add    %r8,%rax
  add    %rdi,%rax
  add    %rsi,%rax
  mov    %rdx,%rsi
  movzwl %dx,%edx
  shr    $0x10,%rsi
  mov    %rdx,D43(%rip)
  add    %rsi,%rax
  movzwl %ax,%eax
  mov    %rax,D43(%rip)
  shl    $0x10,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
unsigned long hash_random(void) {
  static unsigned long x[3] = {0xe66du, 0xdeecu, 0x5u};
  const unsigned long MASK = 0x0000ffffu;
  const unsigned long A[3] = {0xe66du, 0xdeecu, 0x5u};
  const unsigned long B = 0xBu;
  unsigned long product[3];
  product[0] = A[0] * x[0] + B;
  product[1] = A[1] * x[0] + (product[0] >> 16);
  product[2] = A[1] * x[1] + A[0] * x[2] + A[2] * x[0] + (product[1] >> 16);
  product[1] = A[0] * x[1] + (product[1] & MASK);
  product[2] += (product[1] >> 16);
  x[0] = (product[0] & MASK);
  x[1] = (product[1] & MASK);
  x[2] = (product[2] & MASK);
  return x[1] + (x[2] << 16);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_random>:
  endbr64
  mov    D38(%rip),%rdi
  mov    D45(%rip),%r8
  imul   $0xe66d,%rdi,%rcx
  imul   $0xdeec,%rdi,%rsi
  lea    (%rdi,%rdi,4),%rdi
  imul   $0xe66d,%r8,%rdx
  add    $0xb,%rcx
  imul   $0xdeec,%r8,%r8
  mov    %rcx,%rax
  and    $0xffff,%ecx
  shr    $0x10,%rax
  mov    %rcx,D16(%rip)
  add    %rax,%rsi
  movzwl %si,%eax
  shr    $0x10,%rsi
  add    %rax,%rdx
  imul   $0xe66d,0x2ede(%rip),%rax        # 4040 <x.1+0x10>
  add    %r8,%rax
  add    %rdi,%rax
  add    %rsi,%rax
  mov    %rdx,%rsi
  movzwl %dx,%edx
  shr    $0x10,%rsi
  mov    %rdx,D16(%rip)
  add    %rsi,%rax
  movzwl %ax,%eax
  mov    %rax,D16(%rip)
  shl    $0x10,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
unsigned long hash_random(void) {
  static unsigned long x[3] = {0xe66du, 0xdeecu, 0x5u};
  const unsigned long MASK = 0x0000ffffu;
  const unsigned long A[3] = {0xe66du, 0xdeecu, 0x5u};
  const unsigned long B = 0xBu;
  unsigned long product[3];
  product[0] = A[0] * x[0] + B;
  product[1] = A[1] * x[0] + (product[0] >> 16);
  product[2] = A[1] * x[1] + A[0] * x[2] + A[2] * x[0] + (product[1] >> 16);
  product[1] = A[0] * x[1] + (product[1] & MASK);
  product[2] += (product[1] >> 16);
  x[0] = (product[0] & MASK);
  x[1] = (product[1] & MASK);
  x[2] = (product[2] & MASK);
  return x[1] + (x[2] << 16);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gnu_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x18(%rbp),%rax
  jmp    L13
L11:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L13:
  leave
  ret
```

assistant: ```c
const char *gnu_basename(const char *path) {
  const char *last_slash = strrchr(path, '/');
  if (!last_slash)
    return path;
  return last_slash + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gnu_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *gnu_basename(const char *path) {
  const char *last_slash = strrchr(path, '/');
  if (!last_slash)
    return path;
  return last_slash + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gnu_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *gnu_basename(const char *path) {
  const char *last_slash = strrchr(path, '/');
  if (!last_slash)
    return path;
  return last_slash + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gnu_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *gnu_basename(const char *path) {
  const char *last_slash = strrchr(path, '/');
  if (!last_slash)
    return path;
  return last_slash + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<contains_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L11
  mov    $0x1,%eax
  jmp    L24
L11:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L9
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
int contains_char(char *str, char search) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == search)
      return 1;
  }
  return 0;
}
```