ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x50,%rsp
  mov    %rdi,-0x1038(%rbp)
  mov    %esi,-0x103c(%rbp)
  mov    %edx,-0x1040(%rbp)
  mov    %ecx,-0x1044(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x103c(%rbp),%eax
  mov    %eax,-0x1024(%rbp)
  jmp    L43
L88:
  mov    -0x1024(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1038(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1024(%rbp),%eax
  cltq
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x1024(%rbp)
L43:
  mov    -0x1024(%rbp),%eax
  cmp    -0x1044(%rbp),%eax
  jle    L88
  mov    -0x103c(%rbp),%eax
  mov    %eax,-0x1020(%rbp)
  mov    -0x103c(%rbp),%eax
  mov    %eax,-0x101c(%rbp)
  mov    -0x1040(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1018(%rbp)
  jmp    L26
L74:
  mov    -0x101c(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%edx
  mov    -0x1018(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L90
  mov    -0x101c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x101c(%rbp)
  mov    -0x1020(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x1020(%rbp)
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x1038(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  jmp    L26
L90:
  mov    -0x1018(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1018(%rbp)
  mov    -0x1020(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x1020(%rbp)
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x1038(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
L26:
  mov    -0x101c(%rbp),%eax
  cmp    -0x1040(%rbp),%eax
  jg     L91
  mov    -0x1018(%rbp),%eax
  cmp    -0x1044(%rbp),%eax
  jle    L74
L91:
  mov    -0x1040(%rbp),%eax
  sub    -0x101c(%rbp),%eax
  mov    %eax,-0x1014(%rbp)
  movl   $0x0,-0x1024(%rbp)
  jmp    L30
L20:
  mov    -0x101c(%rbp),%edx
  mov    -0x1024(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1020(%rbp),%edx
  mov    -0x1024(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1038(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  mov    -0x1010(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1024(%rbp)
L30:
  mov    -0x1024(%rbp),%eax
  cmp    -0x1014(%rbp),%eax
  jle    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
void merge(int a[], int begin, int middle, int end) {
  int b[1024];
  int k;
  int current, left, right;
  int remaining;
  for (k = begin; k <= end; k++)
    b[k] = a[k];
  current = begin;
  left = begin;
  right = middle + 1;
  while (left <= middle && right <= end) {
    if (b[left] < b[right])
      a[current++] = b[left++];
    else
      a[current++] = b[right++];
  }
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    a[current + k] = b[left + k];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<merge>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%r11
  mov    %edx,%r10d
  mov    %ecx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  cmp    %ecx,%esi
  jg     L15
  movslq %esi,%rax
L83:
  mov    (%r11,%rax,4),%edx
  mov    %edx,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L83
L15:
  lea    0x1(%r10),%eax
  cmp    %r10d,%esi
  jg     L5
  cmp    %eax,%edi
  jl     L5
  lea    0x1(%rsi),%ecx
  movslq %esi,%rdx
  lea    (%r11,%rdx,4),%rdx
  jmp    L64
L3:
  add    $0x1,%eax
  mov    %ecx,%ebx
  mov    %r8d,(%rdx)
L106:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %r10d,%esi
  jg     L51
  cmp    %edi,%eax
  jg     L51
L64:
  movslq %esi,%r8
  mov    (%rsp,%r8,4),%r9d
  movslq %eax,%r8
  mov    (%rsp,%r8,4),%r8d
  cmp    %r8d,%r9d
  jge    L3
  add    $0x1,%esi
  mov    %ecx,%ebx
  mov    %r9d,(%rdx)
  jmp    L106
L5:
  mov    %esi,%ebx
L51:
  sub    %esi,%r10d
  js     L11
  lea    0x1(%r10),%ecx
  shl    $0x2,%rcx
  movslq %esi,%rsi
  lea    (%rsp,%rsi,4),%rdi
  movslq %ebx,%rbx
  lea    (%r11,%rbx,4),%rsi
  mov    $0x0,%eax
L40:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L40
L11:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1010,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int a[], int begin, int middle, int end) {
  int b[1024];
  int k;
  int current, left, right;
  int remaining;
  for (k = begin; k <= end; k++)
    b[k] = a[k];
  current = begin;
  left = begin;
  right = middle + 1;
  while (left <= middle && right <= end) {
    if (b[left] < b[right])
      a[current++] = b[left++];
    else
      a[current++] = b[right++];
  }
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    a[current + k] = b[left + k];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<merge>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r13d
  cmp    %ecx,%esi
  jg     L4
  movslq %esi,%rsi
  mov    %ecx,%eax
  shl    $0x2,%rsi
  sub    %ebx,%eax
  lea    (%rsp,%rsi,1),%rdi
  lea    0x4(,%rax,4),%rdx
  add    %r12,%rsi
  call   <memcpy@plt>
L4:
  lea    0x1(%rbp),%ecx
  cmp    %ebp,%ebx
  jg     L76
  cmp    %ecx,%r13d
  lea    0x1(%rbx),%eax
  setge  %dl
  cltq
  test   %dl,%dl
  jne    L56
  jmp    L76
  nopl   0x0(%rax)
L70:
  add    $0x1,%ebx
  mov    %edx,-0x4(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %ebp,%ebx
  jg     L72
L60:
  cmp    %r13d,%ecx
  jg     L72
L56:
  movslq %ebx,%rdx
  movslq %ecx,%rsi
  movslq %eax,%rdi
  mov    (%rsp,%rdx,4),%edx
  mov    (%rsp,%rsi,4),%esi
  cmp    %esi,%edx
  jl     L70
  mov    %esi,%edx
  add    $0x1,%ecx
  mov    %edx,-0x4(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %ebp,%ebx
  jle    L60
L72:
  sub    %ebx,%ebp
  js     L8
  movslq %ebp,%rbp
  movslq %ebx,%rbx
  lea    (%r12,%rdi,4),%rdi
  lea    0x4(,%rbp,4),%rdx
  lea    (%rsp,%rbx,4),%rsi
  call   <memcpy@plt>
L8:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L76:
  movslq %ebx,%rdi
  jmp    L72
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int a[], int begin, int middle, int end) {
  int b[1024];
  int k;
  int current, left, right;
  int remaining;
  for (k = begin; k <= end; k++)
    b[k] = a[k];
  current = begin;
  left = begin;
  right = middle + 1;
  while (left <= middle && right <= end) {
    if (b[left] < b[right])
      a[current++] = b[left++];
    else
      a[current++] = b[right++];
  }
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    a[current + k] = b[left + k];
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r13d
  cmp    %ecx,%esi
  jg     L118
  movslq %esi,%rsi
  mov    %ecx,%eax
  shl    $0x2,%rsi
  sub    %ebx,%eax
  lea    (%rsp,%rsi,1),%rdi
  lea    0x4(,%rax,4),%rdx
  add    %r12,%rsi
  call   <memcpy@plt>
L118:
  lea    0x1(%rbp),%edx
  cmp    %ebp,%ebx
  jg     L92
  lea    0x1(%rbx),%eax
  movslq %ebx,%rsi
  cltq
  cmp    %edx,%r13d
  jl     L92
  cs nopw 0x0(%rax,%rax,1)
L22:
  movslq %edx,%r8
  mov    (%rsp,%rsi,4),%edi
  movslq %eax,%r9
  mov    (%rsp,%r8,4),%ecx
  cmp    %ecx,%edi
  jge    L31
L115:
  add    $0x1,%ebx
  mov    %edi,-0x4(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %ebp,%ebx
  jg     L68
  cmp    %r13d,%edx
  jg     L68
  movslq %ebx,%rsi
  mov    (%rsp,%r8,4),%ecx
  movslq %eax,%r9
  mov    (%rsp,%rsi,4),%edi
  cmp    %ecx,%edi
  jl     L115
L31:
  mov    %ecx,-0x4(%r12,%rax,4)
  add    $0x1,%edx
  add    $0x1,%rax
  cmp    %ebp,%ebx
  jg     L68
  cmp    %edx,%r13d
  jge    L22
L68:
  sub    %ebx,%ebp
  js     L95
  movslq %ebp,%rbp
  movslq %ebx,%rbx
  lea    (%r12,%r9,4),%rdi
  lea    0x4(,%rbp,4),%rdx
  lea    (%rsp,%rbx,4),%rsi
  call   <memcpy@plt>
L95:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L92:
  movslq %ebx,%r9
  jmp    L68
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int a[], int begin, int middle, int end) {
  int b[1024];
  int k;
  int current, left, right;
  int remaining;
  for (k = begin; k <= end; k++)
    b[k] = a[k];
  current = begin;
  left = begin;
  right = middle + 1;
  while (left <= middle && right <= end) {
    if (b[left] < b[right])
      a[current++] = b[left++];
    else
      a[current++] = b[right++];
  }
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    a[current + k] = b[left + k];
}
```
user: Translate the below assembly code into C programming language:

```asm
<HA_AlignFromTemplate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movb   $0x2a,(%rax)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x1,-0x1c(%rbp)
  jmp    L65
L41:
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <HA_GetCellTemplateN@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6c,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L10
L46:
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L46
  mov    -0x18(%rbp),%rax
  mov    $0x5,%edx
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x63,(%rax)
  jmp    L33
L3:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x72,(%rax)
L33:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x1c(%rbp)
L65:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L41
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: \hfil

assistant: ```c
char *HA_AlignFromTemplate(const char *HA_template, int ncols, int tcols, int trepeat) {
  char *s, *cell, *align;
  int i;
  align = (char *)malloc((ncols + 2) * sizeof(char));
  align[0] = '*';
  align[ncols + 1] = '\0';
  for (i = 1; i <= ncols; i++) {
    cell = HA_GetCellTemplateN(HA_template, i, tcols, trepeat);
    align[i] = 'l';
    s = cell;
    while (isspace(*s))
      s++;
    if (strncmp(s, "\\hfil", 5) == 0) {
      if (strstr(s + 5, "\\hfil") != NULL)
        align[i] = 'c';
      else
        align[i] = 'r';
    }
    free(cell);
  }
  return align;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HA_AlignFromTemplate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,%r14d
  mov    %edx,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  lea    0x2(%rsi),%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  mov    %rax,0x8(%rsp)
  movb   $0x2a,(%rax)
  movslq %r14d,%rax
  movb   $0x0,0x1(%rcx,%rax,1)
  test   %r14d,%r14d
  jle    L6
  mov    $0x1,%ebp
  lea    D7(%rip),%r15
  jmp    L23
L28:
  add    $0x1,%rbx
L10:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
  mov    $0x5,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L59
  lea    0x5(%rbx),%rdi
  mov    %r15,%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xf,%eax
  add    $0x63,%eax
  mov    %al,0x0(%r13)
L59:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x1,%rbp
  cmp    %ebp,%r14d
  jl     L6
L23:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    %ebp,%esi
  mov    0x10(%rsp),%rdi
  call   <HA_GetCellTemplateN@plt>
  mov    %rax,%r12
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbp,1),%r13
  movb   $0x6c,0x0(%r13)
  mov    %r12,%rbx
  jmp    L10
L6:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: \hfil

assistant: ```c
char *HA_AlignFromTemplate(const char *HA_template, int ncols, int tcols, int trepeat) {
  char *s, *cell, *align;
  int i;
  align = (char *)malloc((ncols + 2) * sizeof(char));
  align[0] = '*';
  align[ncols + 1] = '\0';
  for (i = 1; i <= ncols; i++) {
    cell = HA_GetCellTemplateN(HA_template, i, tcols, trepeat);
    align[i] = 'l';
    s = cell;
    while (isspace(*s))
      s++;
    if (strncmp(s, "\\hfil", 5) == 0) {
      if (strstr(s + 5, "\\hfil") != NULL)
        align[i] = 'c';
      else
        align[i] = 'r';
    }
    free(cell);
  }
  return align;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HA_AlignFromTemplate>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  lea    0x2(%rsi),%edi
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  call   <malloc@plt>
  movb   $0x2a,(%rax)
  mov    %rax,%rcx
  mov    %rax,0x8(%rsp)
  movslq %ebx,%rax
  movb   $0x0,0x1(%rcx,%rax,1)
  test   %ebx,%ebx
  jle    L43
  mov    $0x1,%ebx
  lea    D3(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x1c(%rsp),%edx
  mov    0x10(%rsp),%rdi
  mov    %r15d,%ecx
  mov    %ebx,%esi
  call   <HA_GetCellTemplateN@plt>
  mov    %rax,%rbp
  mov    0x8(%rsp),%rax
  mov    %rbp,%r14
  lea    (%rax,%rbx,1),%r12
  movb   $0x6c,(%r12)
  jmp    L35
  nopl   0x0(%rax)
L4:
  add    $0x1,%r14
L35:
  movsbl (%r14),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L8
  lea    0x5(%r14),%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xf,%eax
  add    $0x63,%eax
  mov    %al,(%r12)
L8:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <free@plt>
  cmp    %ebx,0x18(%rsp)
  jge    L10
L43:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: \hfil

assistant: ```c
char *HA_AlignFromTemplate(const char *HA_template, int ncols, int tcols, int trepeat) {
  char *s, *cell, *align;
  int i;
  align = (char *)malloc((ncols + 2) * sizeof(char));
  align[0] = '*';
  align[ncols + 1] = '\0';
  for (i = 1; i <= ncols; i++) {
    cell = HA_GetCellTemplateN(HA_template, i, tcols, trepeat);
    align[i] = 'l';
    s = cell;
    while (isspace(*s))
      s++;
    if (strncmp(s, "\\hfil", 5) == 0) {
      if (strstr(s + 5, "\\hfil") != NULL)
        align[i] = 'c';
      else
        align[i] = 'r';
    }
    free(cell);
  }
  return align;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HA_AlignFromTemplate>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  lea    0x2(%rsi),%edi
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  call   <malloc@plt>
  movb   $0x2a,(%rax)
  mov    %rax,%rcx
  mov    %rax,0x8(%rsp)
  movslq %ebx,%rax
  movb   $0x0,0x1(%rcx,%rax,1)
  test   %ebx,%ebx
  jle    L40
  mov    $0x1,%ebx
  lea    D2(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L13:
  mov    0x1c(%rsp),%edx
  mov    0x10(%rsp),%rdi
  mov    %r15d,%ecx
  mov    %ebx,%esi
  call   <HA_GetCellTemplateN@plt>
  mov    %rax,%rbp
  mov    0x8(%rsp),%rax
  mov    %rbp,%r14
  lea    (%rax,%rbx,1),%r12
  movb   $0x6c,(%r12)
  jmp    L29
  nopl   0x0(%rax)
L2:
  add    $0x1,%r14
L29:
  movsbl (%r14),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L27
  lea    0x5(%r14),%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xf,%eax
  add    $0x63,%eax
  mov    %al,(%r12)
L27:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <free@plt>
  cmp    %ebx,0x18(%rsp)
  jge    L13
L40:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: \hfil

assistant: ```c
char *HA_AlignFromTemplate(const char *HA_template, int ncols, int tcols, int trepeat) {
  char *s, *cell, *align;
  int i;
  align = (char *)malloc((ncols + 2) * sizeof(char));
  align[0] = '*';
  align[ncols + 1] = '\0';
  for (i = 1; i <= ncols; i++) {
    cell = HA_GetCellTemplateN(HA_template, i, tcols, trepeat);
    align[i] = 'l';
    s = cell;
    while (isspace(*s))
      s++;
    if (strncmp(s, "\\hfil", 5) == 0) {
      if (strstr(s + 5, "\\hfil") != NULL)
        align[i] = 'c';
      else
        align[i] = 'r';
    }
    free(cell);
  }
  return align;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0x9,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x34(%rbp)
  mov    $0xa,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D23: %d


tool: D18: ---------------%p


assistant: ```c
int main() {
  int test[10] = {10, 11, 9, 5, 9};
  int l = length(test);
  printf("%d\n", (int)(sizeof(test) / sizeof(test[0])));
  printf("---------------%p\n", test);
  printf("%d\n", l);
  printf("%d\n", '1' - '0');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0xa,(%rsp)
  movl   $0xb,0x4(%rsp)
  movl   $0x9,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <length@plt>
  mov    %eax,%ebp
  mov    $0xa,%esi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D12
type: string

tool: D11: %d


tool: D12: ---------------%p


assistant: ```c
int main() {
  int test[10] = {10, 11, 9, 5, 9};
  int l = length(test);
  printf("%d\n", (int)(sizeof(test) / sizeof(test[0])));
  printf("---------------%p\n", test);
  printf("%d\n", l);
  printf("%d\n", '1' - '0');
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xb0000000a,%rax
  mov    %rsp,%r13
  movq   $0x9,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r13,%rdi
  movq   $0x0,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x500000009,%rax
  mov    %rax,0x8(%rsp)
  call   <length@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string

tool: D4: %d


tool: D17: ---------------%p


assistant: ```c
int main() {
  int test[10] = {10, 11, 9, 5, 9};
  int l = length(test);
  printf("%d\n", (int)(sizeof(test) / sizeof(test[0])));
  printf("---------------%p\n", test);
  printf("%d\n", l);
  printf("%d\n", '1' - '0');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  lea    D21(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movaps %xmm0,0x10(%rsp)
  movdqa D12(%rip),%xmm0
  mov    %r13,%rdi
  movl   $0x9,0x10(%rsp)
  movaps %xmm0,(%rsp)
  movq   $0x0,0x20(%rsp)
  call   <length@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D12
type: byte[16]
name: retrieve_data
arguments: label: D17
type: string

tool: D21: %d


tool: {"D12": [0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D17: ---------------%p


assistant: ```c
int main() {
  int test[10] = {10, 11, 9, 5, 9};
  int l = length(test);
  printf("%d\n", (int)(sizeof(test) / sizeof(test[0])));
  printf("---------------%p\n", test);
  printf("%d\n", l);
  printf("%d\n", '1' - '0');
  return 0;
}
```