ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sequeeze>:
  endbr64
  movzbl (%rdi),%r8d
  lea    0x1(%rdi),%r10
  xor    %r11d,%r11d
  mov    $0x1,%r9d
  test   %r8b,%r8b
  je     L36
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rsi),%eax
  lea    0x1(%rsi),%rdx
  xor    %ecx,%ecx
  test   %al,%al
  je     L7
  nopl   (%rax)
L27:
  cmp    %r8b,%al
  cmove  %r9d,%ecx
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L27
  test   %ecx,%ecx
  je     L7
L3:
  movzbl (%r10),%r8d
  add    $0x1,%r10
  test   %r8b,%r8b
  jne    L15
  movslq %r11d,%r11
  add    %r11,%rdi
L36:
  movb   $0x0,(%rdi)
  ret
  nopl   (%rax)
L7:
  movslq %r11d,%rax
  add    $0x1,%r11d
  mov    %r8b,(%rdi,%rax,1)
  jmp    L3
```

assistant: ```c
void sequeeze(char s1[], char s2[]) {
  int i, j, k, flag;
  for (i = k = 0; s1[i] != '\0'; ++i) {
    flag = 0;
    for (j = 0; s2[j] != '\0'; ++j) {
      if (s1[i] == s2[j]) {
        flag = 1;
      }
    }
    if (!flag) {
      s1[k++] = s1[i];
    }
  }
  s1[k] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sequeeze>:
  endbr64
  movzbl (%rdi),%r8d
  lea    0x1(%rdi),%r10
  xor    %r11d,%r11d
  mov    $0x1,%r9d
  test   %r8b,%r8b
  je     L42
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rsi),%eax
  lea    0x1(%rsi),%rdx
  xor    %ecx,%ecx
  test   %al,%al
  je     L16
  nopl   (%rax)
L44:
  cmp    %r8b,%al
  cmove  %r9d,%ecx
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L44
  test   %ecx,%ecx
  je     L16
L5:
  movzbl (%r10),%r8d
  add    $0x1,%r10
  test   %r8b,%r8b
  jne    L15
  movslq %r11d,%r11
  add    %r11,%rdi
L42:
  movb   $0x0,(%rdi)
  ret
  nopl   (%rax)
L16:
  movslq %r11d,%rax
  add    $0x1,%r11d
  mov    %r8b,(%rdi,%rax,1)
  jmp    L5
```

assistant: ```c
void sequeeze(char s1[], char s2[]) {
  int i, j, k, flag;
  for (i = k = 0; s1[i] != '\0'; ++i) {
    flag = 0;
    for (j = 0; s2[j] != '\0'; ++j) {
      if (s1[i] == s2[j]) {
        flag = 1;
      }
    }
    if (!flag) {
      s1[k++] = s1[i];
    }
  }
  s1[k] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L54
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D33(%rip),%r12
L11:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L11
L54:
  lea    0xc(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L157
  lea    0x60(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D33(%rip),%r12
L138:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L138
L157:
  mov    0x8(%rsp),%r10d
  lea    (%r10,%rcx,1),%r11d
  test   %r11d,%r11d
  jle    L49
  lea    0xb0(%rsp),%rax
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%r8d
  jmp    L135
L59:
  cmp    %esi,%ecx
  jg     L34
  movslq %r8d,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  add    $0x1,%r8d
  mov    %edx,%r9d
L17:
  mov    %edi,(%rax)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %r11d,%r9d
  jge    L49
L135:
  cmp    %r8d,%r10d
  jg     L59
  movslq %esi,%rdi
  mov    0x60(%rsp,%rdi,4),%edi
  add    $0x1,%esi
  mov    %edx,%r9d
  jmp    L17
L34:
  movslq %r8d,%rdi
  mov    0x10(%rsp,%rdi,4),%ebx
  movslq %esi,%rdi
  mov    0x60(%rsp,%rdi,4),%edi
  cmp    %edi,%ebx
  jge    L6
  add    $0x1,%r8d
  mov    %edx,%r9d
  mov    %ebx,%edi
  jmp    L17
L6:
  add    $0x1,%esi
  mov    %edx,%r9d
  jmp    L17
L49:
  add    0xc(%rsp),%r10d
  test   %r10d,%r10d
  jle    L33
  mov    $0x0,%ebx
  lea    D28(%rip),%rbp
L53:
  mov    0xb0(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  mov    0xc(%rsp),%eax
  add    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L53
L33:
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  mov    $0x0,%eax
  add    $0x160,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D33
data_type: string
name: parse_data
arguments: tag: D28
data_type: string

tool: D33: %d

tool: D28: %d


assistant: ```c
int main() {
  int N1, N2;
  int A1[20], A2[20], ANS[2 * 20];
  int A1_index = 0, A2_index = 0, index_sum = 0;
  int i;
  scanf("%d", &N1);
  for (i = 0; i < N1; i++) {
    scanf("%d", &A1[i]);
  }
  scanf("%d", &N2);
  for (i = 0; i < N2; i++) {
    scanf("%d", &A2[i]);
  }
  while (index_sum < N1 + N2) {
    if (A1_index >= N1) {
      ANS[index_sum] = A2[A2_index];
      A2_index++;
      index_sum++;
    } else if (A2_index >= N2) {
      ANS[index_sum] = A1[A1_index];
      A1_index++;
      index_sum++;
    } else {
      if (A1[A1_index] < A2[A2_index]) {
        ANS[index_sum] = A1[A1_index];
        A1_index++;
        index_sum++;
      } else {
        ANS[index_sum] = A2[A2_index];
        A2_index++;
        index_sum++;
      }
    }
  }
  for (i = 0; i < N1 + N2; i++) {
    printf("%d\n", ANS[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L33
  nopl   (%rax)
L100:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L100
L33:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  lea    0x60(%rsp),%rbp
  xor    %ebx,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L64
  nopl   0x0(%rax)
L133:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jg     L133
L64:
  mov    0x8(%rsp),%r8d
  lea    (%r8,%rdx,1),%ecx
  test   %ecx,%ecx
  jle    L126
  sub    $0x1,%ecx
  lea    0xb0(%rsp),%rbp
  xor    %edi,%edi
  lea    0xb4(%rsp,%rcx,4),%r9
  mov    %rbp,%rax
  xor    %ecx,%ecx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L72:
  movslq %ecx,%rsi
  add    $0x1,%ecx
  mov    0x60(%rsp,%rsi,4),%esi
L20:
  mov    %esi,(%rax)
  add    $0x4,%rax
  cmp    %rax,%r9
  je     L91
L4:
  cmp    %edi,%r8d
  jle    L72
  movslq %edi,%rsi
  mov    0x10(%rsp,%rsi,4),%esi
  cmp    %ecx,%edx
  jle    L66
  movslq %ecx,%r10
  mov    0x60(%rsp,%r10,4),%r10d
  cmp    %esi,%r10d
  jg     L66
  mov    %r10d,%esi
  add    $0x4,%rax
  add    $0x1,%ecx
  mov    %esi,-0x4(%rax)
  cmp    %rax,%r9
  jne    L4
  nopl   0x0(%rax)
L91:
  xor    %ebx,%ebx
  lea    D5(%rip),%r12
  nopl   0x0(%rax)
L115:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  add    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L115
L126:
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x160,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L66:
  add    $0x1,%edi
  jmp    L20
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string

tool: D12: %d

tool: D5: %d


assistant: ```c
int main() {
  int N1, N2;
  int A1[20], A2[20], ANS[2 * 20];
  int A1_index = 0, A2_index = 0, index_sum = 0;
  int i;
  scanf("%d", &N1);
  for (i = 0; i < N1; i++) {
    scanf("%d", &A1[i]);
  }
  scanf("%d", &N2);
  for (i = 0; i < N2; i++) {
    scanf("%d", &A2[i]);
  }
  while (index_sum < N1 + N2) {
    if (A1_index >= N1) {
      ANS[index_sum] = A2[A2_index];
      A2_index++;
      index_sum++;
    } else if (A2_index >= N2) {
      ANS[index_sum] = A1[A1_index];
      A1_index++;
      index_sum++;
    } else {
      if (A1[A1_index] < A2[A2_index]) {
        ANS[index_sum] = A1[A1_index];
        A1_index++;
        index_sum++;
      } else {
        ANS[index_sum] = A2[A2_index];
        A2_index++;
        index_sum++;
      }
    }
  }
  for (i = 0; i < N1 + N2; i++) {
    printf("%d\n", ANS[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L14
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L14:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L24:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D26
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D22
data_type: string
name: read_data
arguments: data_tag: D2
data_type: string

tool: D26: Podaj kod ASCII: 

tool: D6: %i

tool: D22: %c


tool: D2: Znak jest niedrukowalny

assistant: ```c
int main() {
  int kod;
  printf("Podaj kod ASCII: ");
  scanf("%i", &kod);
  if (isprint(kod)) {
    printf("%c\n", kod);
  } else {
    printf("Znak jest niedrukowalny\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L16
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L16:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L28
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string

tool: D19: Podaj kod ASCII: 

tool: D7: %i

tool: D1: %c


tool: D18: Znak jest niedrukowalny

assistant: ```c
int main() {
  int kod;
  printf("Podaj kod ASCII: ");
  scanf("%i", &kod);
  if (isprint(kod)) {
    printf("%c\n", kod);
  } else {
    printf("Znak jest niedrukowalny\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L13
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L13:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  jmp    L18
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D22: Podaj kod ASCII: 

tool: D2: %i

tool: D4: %c


tool: D13: Znak jest niedrukowalny

assistant: ```c
int main() {
  int kod;
  printf("Podaj kod ASCII: ");
  scanf("%i", &kod);
  if (isprint(kod)) {
    printf("%c\n", kod);
  } else {
    printf("Znak jest niedrukowalny\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D32(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L10
  mov    0x4(%rsp),%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L10:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D32
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D33
datatype: string

tool: D39: Podaj kod ASCII: 

tool: D32: %i

tool: D22: %c


tool: D33: Znak jest niedrukowalny

assistant: ```c
int main() {
  int kod;
  printf("Podaj kod ASCII: ");
  scanf("%i", &kod);
  if (isprint(kod)) {
    printf("%c\n", kod);
  } else {
    printf("Znak jest niedrukowalny\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mat_libera>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  subl   $0x1,-0x4(%rbp)
  jmp    L1
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  subl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L17
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void mat_libera(int m, double **A) {
  for (m -= 1; m + 1; m--) {
    free(A[m]);
  }
  free(A);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat_libera>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %edi,%edi
  je     L19
  lea    -0x1(%rdi),%ebx
  movslq %ebx,%rbx
L6:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <free@plt>
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  jne    L6
L19:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mat_libera(int m, double **A) {
  for (m -= 1; m + 1; m--) {
    free(A[m]);
  }
  free(A);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat_libera>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L18
  lea    -0x1(%rdi),%ebx
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <free@plt>
  cmp    $0xffffffff,%ebx
  jne    L4
L18:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void mat_libera(int m, double **A) {
  for (m -= 1; m + 1; m--) {
    free(A[m]);
  }
  free(A);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mat_libera>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L5
  lea    -0x1(%rdi),%ebx
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <free@plt>
  cmp    $0xffffffff,%ebx
  jne    L6
L5:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void mat_libera(int m, double **A) {
  for (m -= 1; m + 1; m--) {
    free(A[m]);
  }
  free(A);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ll_atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int64_t ll_atol(int8_t *s) {
  int64_t i = atoi((char *)s);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ll_atol>:
  endbr64
  sub    $0x8,%rsp
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int64_t ll_atol(int8_t *s) {
  int64_t i = atoi((char *)s);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ll_atol>:
  endbr64
  jmp    1050 <atoi@plt>
```

assistant: ```c
int64_t ll_atol(int8_t *s) {
  int64_t i = atoi((char *)s);
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ll_atol>:
  endbr64
  jmp    1050 <atoi@plt>
```

assistant: ```c
int64_t ll_atol(int8_t *s) {
  int64_t i = atoi((char *)s);
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nextTriang>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D45(%rip),%rdx
  mov    D47(%rip),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,D10(%rip)
  mov    D47(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D10(%rip)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long nextTriang() {
  static long lasttriang = 0, num = 1;
  long triang;
  triang = lasttriang + num;
  lasttriang = triang;
  num++;
  return triang;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nextTriang>:
  endbr64
  mov    D20(%rip),%rax
  mov    %rax,%rdx
  add    D24(%rip),%rdx
  mov    %rdx,D21(%rip)
  add    $0x1,%rax
  mov    %rax,D21(%rip)
  mov    %rdx,%rax
  ret
```

assistant: ```c
long nextTriang() {
  static long lasttriang = 0, num = 1;
  long triang;
  triang = lasttriang + num;
  lasttriang = triang;
  num++;
  return triang;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextTriang>:
  endbr64
  mov    D23(%rip),%rax
  mov    D20(%rip),%r8
  add    %rax,%r8
  add    $0x1,%rax
  mov    %rax,D27(%rip)
  mov    %r8,%rax
  mov    %r8,D27(%rip)
  ret
```

assistant: ```c
long nextTriang() {
  static long lasttriang = 0, num = 1;
  long triang;
  triang = lasttriang + num;
  lasttriang = triang;
  num++;
  return triang;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nextTriang>:
  endbr64
  mov    D25(%rip),%rax
  mov    D13(%rip),%r8
  add    %rax,%r8
  add    $0x1,%rax
  mov    %rax,D18(%rip)
  mov    %r8,%rax
  mov    %r8,D18(%rip)
  ret
```

assistant: ```c
long nextTriang() {
  static long lasttriang = 0, num = 1;
  long triang;
  triang = lasttriang + num;
  lasttriang = triang;
  num++;
  return triang;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<put1c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  lea    -0x4(%rbp),%rcx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  nop
  nop
  leave
  ret
```

assistant: ```c
put1c(c, fd) int fd;
char c;
{
  write(fd, &c, 1);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<put1c>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %al,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%eax
  call   <write@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
put1c(c, fd) int fd;
char c;
{
  write(fd, &c, 1);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<put1c>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%r8d
  mov    $0x1,%edx
  mov    %esi,%edi
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  mov    %r8b,0xc(%rsp)
  call   <write@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
put1c(c, fd) int fd;
char c;
{
  write(fd, &c, 1);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<put1c>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%r8d
  mov    $0x1,%edx
  mov    %esi,%edi
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  mov    %r8b,0xc(%rsp)
  call   <write@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
put1c(c, fd) int fd;
char c;
{
  write(fd, &c, 1);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<append_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L14
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  jmp    L18
L14:
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

assistant: ```c
int append_string(char *s, const char *s2, size_t n) {
  size_t l1 = strlen(s);
  size_t l2 = strlen(s2);
  if (l1 + l2 < n) {
    memcpy(s + l1, s2, l2);
    memset(s + l1 + l2, 0, n - l1 - l2);
    return 0;
  } else {
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r14
  cmp    %rbp,%r14
  jae    L10
  mov    %rax,%rdx
  lea    (%rbx,%r12,1),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdx
  sub    %r14,%rdx
  lea    (%rbx,%r14,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int append_string(char *s, const char *s2, size_t n) {
  size_t l1 = strlen(s);
  size_t l2 = strlen(s2);
  if (l1 + l2 < n) {
    memcpy(s + l1, s2, l2);
    memset(s + l1 + l2, 0, n - l1 - l2);
    return 0;
  } else {
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<append_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x0(%rbp,%rax,1),%r14
  cmp    %r12,%r14
  jae    L9
  mov    %rax,%rdx
  lea    (%rbx,%rbp,1),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %r12,%rdx
  lea    (%rbx,%r14,1),%rdi
  xor    %esi,%esi
  sub    %r14,%rdx
  call   <memset@plt>
  xor    %eax,%eax
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int append_string(char *s, const char *s2, size_t n) {
  size_t l1 = strlen(s);
  size_t l2 = strlen(s2);
  if (l1 + l2 < n) {
    memcpy(s + l1, s2, l2);
    memset(s + l1 + l2, 0, n - l1 - l2);
    return 0;
  } else {
    return -1;
  }
}
```