ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<TimerUpdateConfigure>:
  endbr64
  mov    (%rdi),%rax
  test   %rsi,%rsi
  jne    L6
  and    $0xfffffffffffffffd,%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L6:
  or     $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void TimerUpdateConfigure(unsigned long ulBase, unsigned long ulUpdate) {

  ;

  ;
  if (ulUpdate == 0x00000000) {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) &= ~0x00000002;
  } else {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000002;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TimerUpdateConfigure>:
  endbr64
  mov    (%rdi),%rax
  test   %rsi,%rsi
  jne    L5
  and    $0xfffffffffffffffd,%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L5:
  or     $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void TimerUpdateConfigure(unsigned long ulBase, unsigned long ulUpdate) {

  ;

  ;
  if (ulUpdate == 0x00000000) {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) &= ~0x00000002;
  } else {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000002;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: Hello, world %d!!!


assistant: ```c
int main(void) {
  printf("Hello, world %d!!!\n", add(1, 2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: Hello, world %d!!!


assistant: ```c
int main(void) {
  printf("Hello, world %d!!!\n", add(1, 2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <add@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: Hello, world %d!!!


assistant: ```c
int main(void) {
  printf("Hello, world %d!!!\n", add(1, 2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <add@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: Hello, world %d!!!


assistant: ```c
int main(void) {
  printf("Hello, world %d!!!\n", add(1, 2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dsa_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x2a,-0x9(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L2
  movb   $0x2e,-0x9(%rbp)
L2:
  cmpl   $0x1,-0x14(%rbp)
  jne    L14
  movb   $0x2b,-0x9(%rbp)
L14:
  cmpl   $0x2,-0x14(%rbp)
  jne    L10
  movb   $0x2a,-0x9(%rbp)
L10:
  cmpl   $0x3,-0x14(%rbp)
  jne    L37
  movb   $0xa,-0x9(%rbp)
L37:
  lea    -0x9(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_flush@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void dsa_cb(int p, int n, void *arg) {
  char c = '*';
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(arg, &c, 1);
  (void)BIO_flush(arg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dsa_cb>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jne    L29
  movb   $0x2e,0x7(%rsp)
L9:
  cmp    $0x3,%edi
  jne    L46
  movb   $0xa,0x7(%rsp)
  jmp    L46
L29:
  cmp    $0x1,%edi
  jne    L32
  movb   $0x2b,0x7(%rsp)
L46:
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <BIO_write@plt>
  mov    %rbx,%rdi
  call   <BIO_flush@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x10,%rsp
  pop    %rbx
  ret
L32:
  movb   $0x2a,0x7(%rsp)
  cmp    $0x2,%edi
  je     L46
  jmp    L9
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dsa_cb(int p, int n, void *arg) {
  char c = '*';
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(arg, &c, 1);
  (void)BIO_flush(arg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dsa_cb>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movb   $0x2a,0x7(%rsp)
  test   %edi,%edi
  jne    L31
  movb   $0x2e,0x7(%rsp)
L33:
  mov    %rbp,%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  cmp    $0x1,%edi
  jne    L24
  movb   $0x2b,0x7(%rsp)
  jmp    L33
  nopl   0x0(%rax)
L24:
  cmp    $0x2,%edi
  je     L33
  cmp    $0x3,%edi
  jne    L33
  movb   $0xa,0x7(%rsp)
  jmp    L33
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dsa_cb(int p, int n, void *arg) {
  char c = '*';
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(arg, &c, 1);
  (void)BIO_flush(arg);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dsa_cb>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movb   $0x2a,0x7(%rsp)
  test   %edi,%edi
  jne    L42
  movb   $0x2e,0x7(%rsp)
L56:
  mov    %rbp,%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  cmp    $0x1,%edi
  jne    L4
  movb   $0x2b,0x7(%rsp)
  jmp    L56
  nopl   0x0(%rax)
L4:
  cmp    $0x2,%edi
  je     L56
  cmp    $0x3,%edi
  jne    L56
  movb   $0xa,0x7(%rsp)
  jmp    L56
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dsa_cb(int p, int n, void *arg) {
  char c = '*';
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(arg, &c, 1);
  (void)BIO_flush(arg);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L23:
  lea    -0xac(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xb0(%rbp),%eax
  test   %eax,%eax
  jne    L3
  mov    -0xac(%rbp),%eax
  test   %eax,%eax
  je     L58
L3:
  lea    -0xa0(%rbp),%rax
  mov    $0x90,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L7
L45:
  lea    -0xa4(%rbp),%rdx
  lea    -0xa8(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xa8(%rbp),%edx
  mov    -0xb0(%rbp),%eax
  imul   %eax,%edx
  mov    -0xa4(%rbp),%eax
  add    %edx,%eax
  cltq
  movb   $0x1,-0xa0(%rbp,%rax,1)
L7:
  mov    -0xac(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xac(%rbp)
  test   %eax,%eax
  jne    L45
  mov    -0xb0(%rbp),%eax
  lea    -0xa0(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <solutions@plt>
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L23
L58:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
datatype: string
name: retrieve_data
arguments: data_tag: D20
datatype: string

tool: D28: %d %d

tool: D20: %d


assistant: ```c
int main() {
  int n, h;
  char holes[144];
  while (1) {
    scanf("%d %d", &n, &h);
    if (!n && !h)
      break;
    memset(holes, 0, 144 * sizeof(char));
    while (h--) {
      int r, c;
      scanf("%d %d", &r, &c);
      holes[r * n + c] = 1;
    }
    printf("%d\n", solutions(n, holes));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  lea    D0(%rip),%rbx
  lea    D4(%rip),%r13
  jmp    L30
L27:
  lea    0x10(%rsp),%rsi
  mov    (%rsp),%edi
  call   <solutions@plt>
  mov    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L30:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  or     0x4(%rsp),%eax
  je     L17
  lea    0x10(%rsp),%rdi
  mov    $0x90,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L27
L26:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  imul   (%rsp),%eax
  add    0xc(%rsp),%eax
  cltq
  movb   $0x1,0x10(%rsp,%rax,1)
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L26
  jmp    L27
L17:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D0: %d %d

tool: D4: %d


assistant: ```c
int main() {
  int n, h;
  char holes[144];
  while (1) {
    scanf("%d %d", &n, &h);
    if (!n && !h)
      break;
    memset(holes, 0, 144 * sizeof(char));
    while (h--) {
      int r, c;
      scanf("%d %d", &r, &c);
      holes[r * n + c] = 1;
    }
    printf("%d\n", solutions(n, holes));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  mov    %rsp,%r14
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  or     0x4(%rsp),%eax
  je     L11
  lea    0x10(%rsp),%r13
  mov    $0x90,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L29
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  mov    0x8(%rsp),%eax
  imul   %edi,%eax
  add    0xc(%rsp),%eax
  cltq
  movb   $0x1,0x10(%rsp,%rax,1)
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L46
L59:
  mov    %r13,%rsi
  call   <solutions@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L51
  nopl   (%rax)
L29:
  mov    (%rsp),%edi
  jmp    L59
  nopl   (%rax)
L11:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string

tool: D19: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int n, h;
  char holes[144];
  while (1) {
    scanf("%d %d", &n, &h);
    if (!n && !h)
      break;
    memset(holes, 0, 144 * sizeof(char));
    while (h--) {
      int r, c;
      scanf("%d %d", &r, &c);
      holes[r * n + c] = 1;
    }
    printf("%d\n", solutions(n, holes));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  mov    %rsp,%r14
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  or     0x4(%rsp),%eax
  je     L12
  lea    0x10(%rsp),%r13
  mov    $0x90,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L19
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  mov    0x8(%rsp),%eax
  imul   %edi,%eax
  add    0xc(%rsp),%eax
  cltq
  movb   $0x1,0x10(%rsp,%rax,1)
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L5
L8:
  mov    %r13,%rsi
  call   <solutions@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L43
  nopl   (%rax)
L19:
  mov    (%rsp),%edi
  jmp    L8
  nopl   (%rax)
L12:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D13: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int n, h;
  char holes[144];
  while (1) {
    scanf("%d %d", &n, &h);
    if (!n && !h)
      break;
    memset(holes, 0, 144 * sizeof(char));
    while (h--) {
      int r, c;
      scanf("%d %d", &r, &c);
      holes[r * n + c] = 1;
    }
    printf("%d\n", solutions(n, holes));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strUnderline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jg     L11
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L31
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2d,(%rax)
L31:
  addq   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strUnderline(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0') {
    if ((*in >= ' ') || (*in < '\0'))
      *scan++ = '-';
    in++;
  }
  *scan = '\0';
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<strUnderline>:
  endbr64
  mov    %rsi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L31
  mov    %rsi,%rcx
  jmp    L42
L20:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L36
L42:
  cmp    $0x1f,%dl
  jbe    L20
  movb   $0x2d,(%rcx)
  lea    0x1(%rcx),%rcx
  jmp    L20
L31:
  mov    %rsi,%rcx
L36:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strUnderline(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0') {
    if ((*in >= ' ') || (*in < '\0'))
      *scan++ = '-';
    in++;
  }
  *scan = '\0';
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strUnderline>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L9
  nopl   0x0(%rax)
L6:
  cmp    $0x1f,%dl
  jbe    L26
  movb   $0x2d,(%rcx)
  add    $0x1,%rcx
L26:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L6
L9:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strUnderline(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0') {
    if ((*in >= ' ') || (*in < '\0'))
      *scan++ = '-';
    in++;
  }
  *scan = '\0';
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strUnderline>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L14
  nopl   0x0(%rax)
L25:
  cmp    $0x1f,%dl
  jbe    L22
  add    $0x1,%rdi
  movb   $0x2d,(%rcx)
  lea    0x1(%rcx),%r8
  movzbl (%rdi),%edx
  mov    %r8,%rcx
  test   %dl,%dl
  jne    L25
L14:
  movb   $0x0,(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L25
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strUnderline(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0') {
    if ((*in >= ' ') || (*in < '\0'))
      *scan++ = '-';
    in++;
  }
  *scan = '\0';
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    D11(%rip),%eax
  mov    %eax,%edi
  call   <doCalc@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int key = 9973;
  static char mbuf[10240000];
  char *p;
  p = malloc(1024);
  doCalc(key);
  exit(EXIT_SUCCESS);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x26f5,%edi
  call   <doCalc@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int key = 9973;
  static char mbuf[10240000];
  char *p;
  p = malloc(1024);
  doCalc(key);
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x26f5,%edi
  call   <doCalc@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int key = 9973;
  static char mbuf[10240000];
  char *p;
  p = malloc(1024);
  doCalc(key);
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x26f5,%edi
  call   <doCalc@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int key = 9973;
  static char mbuf[10240000];
  char *p;
  p = malloc(1024);
  doCalc(key);
  exit(EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below:

```asm
<PICA_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7a6a,%edi
  call   <PICA_log_entry@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void PICA_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  PICA_log_entry(31338, fmt, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PICA_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x7a6a,%edi
  call   <PICA_log_entry@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void PICA_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  PICA_log_entry(31338, fmt, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PICA_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x7a6a,%edi
  call   <PICA_log_entry@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void PICA_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  PICA_log_entry(31338, fmt, args);
  va_end(args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PICA_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x7a6a,%edi
  call   <PICA_log_entry@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void PICA_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  PICA_log_entry(31338, fmt, args);
  va_end(args);
}
```
user: What is the c source code of the assembly code below?

```asm
<long_div_round>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  cmp    %rax,-0x8(%rbp)
  jle    L8
  addq   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long_div_round(long num, long dem) {
  long divvie, moddo;
  divvie = num / dem;
  moddo = num % dem;
  if (moddo > (dem / 2))
    ++divvie;
  return divvie;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<long_div_round>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  mov    %rsi,%rcx
  shr    $0x3f,%rcx
  add    %rsi,%rcx
  sar    %rcx
  cmp    %rdx,%rcx
  setl   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  ret
```

assistant: ```c
long long_div_round(long num, long dem) {
  long divvie, moddo;
  divvie = num / dem;
  moddo = num % dem;
  if (moddo > (dem / 2))
    ++divvie;
  return divvie;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<long_div_round>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  cqto
  shr    $0x3f,%rcx
  idiv   %rsi
  add    %rsi,%rcx
  sar    %rcx
  cmp    %rdx,%rcx
  setl   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  ret
```

assistant: ```c
long long_div_round(long num, long dem) {
  long divvie, moddo;
  divvie = num / dem;
  moddo = num % dem;
  if (moddo > (dem / 2))
    ++divvie;
  return divvie;
}
```