user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D5(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%ebx
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L175
  xor    %r14d,%r14d
  lea    D0(%rip),%r13
  nopl   0x0(%rax)
L99:
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L57:
  imul   %r14d,%ebx
  mov    %r13,%rdi
  add    %r15d,%ebx
  add    $0x1,%r15d
  movslq %ebx,%rbx
  lea    (%r12,%rbx,4),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  cmp    %r15d,%ebx
  jg     L57
  add    $0x1,%r14d
  cmp    %r14d,%ebx
  jle    L112
  test   %ebx,%ebx
  jg     L99
L175:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L112:
  test   %ebx,%ebx
  jle    L175
  xor    %r14d,%r14d
L55:
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L148:
  imul   %r14d,%ebx
  mov    %r13,%rdi
  add    %r15d,%ebx
  add    $0x1,%r15d
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,4),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  cmp    %r15d,%ebx
  jg     L148
  add    $0x1,%r14d
  cmp    %r14d,%ebx
  jle    L69
  test   %ebx,%ebx
  jg     L55
  jmp    L175
L90:
  call   <__stack_chk_fail@plt>
L69:
  test   %ebx,%ebx
  jle    L175
  xor    %r13d,%r13d
  lea    D22(%rip),%r15
  xchg   %ax,%ax
L129:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L161:
  mov    %ebx,%eax
  movslq %ebx,%rdi
  lea    0x0(%rbp,%r14,4),%rcx
  xor    %r9d,%r9d
  imul   %r13d,%eax
  shl    $0x2,%rdi
  xor    %edx,%edx
  cltq
  lea    (%r12,%rax,4),%rsi
  nopl   (%rax)
L113:
  mov    (%rsi),%eax
  imul   (%rcx),%eax
  add    $0x1,%edx
  add    $0x4,%rsi
  add    %rdi,%rcx
  add    %eax,%r9d
  cmp    %ebx,%edx
  jl     L113
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %r9d,%esi
  call   <printf@plt>
  xor    %edi,%edi
  lea    -0x1(%rbx),%eax
  test   %ebx,%ebx
  cmovle %edi,%eax
  cmp    %r14d,%eax
  je     L42
L102:
  mov    0x4(%rsp),%ebx
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jg     L161
  add    $0x1,%r13d
  cmp    %r13d,%ebx
  jle    L175
  test   %ebx,%ebx
  jg     L129
  jmp    L175
  nopl   (%rax)
L42:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L102
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D0
datatype: string
name: unpack_data
arguments: label: D22
datatype: string

tool: D5: %i


tool: D0: %i

tool: D22: %i 

assistant: ```c
int main(int argc, char **argv) {
  int size = 0;
  int i, j, k;
  scanf("%i\n", &size);
  int *matice1 = (int *)malloc(size * size * sizeof(int));
  int *matice2 = (int *)malloc(size * size * sizeof(int));
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      scanf("%i", &matice1[i * size + j]);
    }
  }
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      scanf("%i", &matice2[i * size + j]);
    }
  }
  int sum = 0;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      for (k = 0; k < size; k++) {
        sum += matice1[i * size + k] * matice2[k * size + j];
      }
      printf("%i ", sum);
      sum = 0;
      if (j == k - 1)
        printf("\n");
    }
  }
  free(matice1);
  free(matice2);
  return 0;
}
```