user: 下面的汇编指令对应的C源代码是什么:

```asm
<Q16_8_FullXorMin_AUTOTEST>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L30:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  sub    $0x8000,%eax
  mov    %eax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  shl    $0x10,%eax
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  and    %ebx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_q168fxormin@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <prog_q168fxormin@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L7
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  movswl %ax,%edx
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  cwtl
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  movswl %ax,%edx
  mov    -0x18(%rbp),%eax
  sar    $0x10,%eax
  cwtl
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  movswl %ax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  cwtl
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L20
L7:
  addl   $0x1,-0x24(%rbp)
L26:
  cmpl   $0x9,-0x24(%rbp)
  jle    L30
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D75
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string
name: parse_data
arguments: tag: D73
type_guessed: string
name: parse_data
arguments: tag: D62
type_guessed: string
name: parse_data
arguments: tag: D54
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D52
type_guessed: string
name: parse_data
arguments: tag: D28
type_guessed: string

tool: D75: LAUNCHING THE (Q16_8_FullXorMin) RESOURCE AUTOTEST...

tool: D0: - TEST OF THE (Q16_8_FullXorMin) RESOURCE => FAILED !

tool: D73:   + %d COMPUTATION(s) BEFORE ERROR...


tool: D62:   + OPERANDE 1 [%d]


tool: D54:   + OPERANDE 2 [%d, %d]


tool: D8:   + ASM INSTR. [%d, %d]


tool: D52:   + REF C CODE [%d, %d]


tool: D28: - TEST OF THE (Q16_8_FullXorMin) RESOURCE => OK

assistant: ```c
int Q16_8_FullXorMin_AUTOTEST() {
  printf("LAUNCHING THE (Q16_8_FullXorMin) RESOURCE AUTOTEST...\n");
  int i, j;
  for (j = 0; j < 10; j++) {
    int op1 = (rand() % 65536) - 32768;
    int op2 = ((rand() % 65536) << 16) & (rand() % 65536);
    int op3 = instr_q168fxormin(op1, op2);
    int op4 = prog_q168fxormin(op1, op2);
    if (op3 != op4) {
      printf("- TEST OF THE (Q16_8_FullXorMin) RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION(s) BEFORE ERROR...\n", j);
      printf("  + OPERANDE 1 [%d]\n", op1);
      printf("  + OPERANDE 2 [%d, %d]\n", ((short)(op2 >> 16)), ((short)op2));
      printf("  + ASM INSTR. [%d, %d]\n", ((short)(op3 >> 16)), ((short)op3));
      printf("  + REF C CODE [%d, %d]\n", ((short)(op4 >> 16)), ((short)op4));
      return 0;
    }
  }
  printf("- TEST OF THE (Q16_8_FullXorMin) RESOURCE => OK\n");
  return 1;
}
```