ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20000000,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  malloc(512 * 1024 * 1024);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20000000,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  malloc(512 * 1024 * 1024);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <FibonacciNumber@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <FibonacciSeries@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D20
datatype: string

tool: D24: %d

tool: D6: The fibonacci number at position %d is %d 

tool: D20: 
Fibonacci series:

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("The fibonacci number at position %d is %d ", num, FibonacciNumber(num));
  printf("\nFibonacci series:\n");
  FibonacciSeries(num);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <FibonacciNumber@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%edi
  call   <FibonacciSeries@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D22
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D10: %d

tool: D22: The fibonacci number at position %d is %d 

tool: D4: 
Fibonacci series:

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("The fibonacci number at position %d is %d ", num, FibonacciNumber(num));
  printf("\nFibonacci series:\n");
  FibonacciSeries(num);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <FibonacciNumber@plt>
  mov    0x4(%rsp),%esi
  lea    D23(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%edi
  call   <FibonacciSeries@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D13: %d

tool: D23: The fibonacci number at position %d is %d 

tool: D9: 
Fibonacci series:

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("The fibonacci number at position %d is %d ", num, FibonacciNumber(num));
  printf("\nFibonacci series:\n");
  FibonacciSeries(num);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <FibonacciNumber@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%edi
  call   <FibonacciSeries@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D2
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D7: %d

tool: D2: The fibonacci number at position %d is %d 

tool: D19: 
Fibonacci series:

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("The fibonacci number at position %d is %d ", num, FibonacciNumber(num));
  printf("\nFibonacci series:\n");
  FibonacciSeries(num);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ptsname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x80,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ptsname_r@plt>
  test   %rax,%rax
  jns    L12
  mov    $0x0,%eax
  jmp    L9
L12:
  lea    D7(%rip),%rax
L9:
  leave
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buf[128];
  if (ptsname_r(fd, buf, sizeof(buf)) < 0)
    return NULL;
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptsname>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80,%edx
  lea    D15(%rip),%rsi
  call   <ptsname_r@plt>
  test   %rax,%rax
  lea    D15(%rip),%rax
  mov    $0x0,%edx
  cmovs  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buf[128];
  if (ptsname_r(fd, buf, sizeof(buf)) < 0)
    return NULL;
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<ptsname>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  mov    $0x80,%edx
  mov    %rbx,%rsi
  call   <ptsname_r@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovns %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buf[128];
  if (ptsname_r(fd, buf, sizeof(buf)) < 0)
    return NULL;
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ptsname>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  mov    $0x80,%edx
  mov    %rbx,%rsi
  call   <ptsname_r@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovns %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buf[128];
  if (ptsname_r(fd, buf, sizeof(buf)) < 0)
    return NULL;
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crearAlfabero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L59:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    $0x41,%eax
  mov    %al,-0xd(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L69:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xd(%rbp)
  jne    L63
  movl   $0x1,-0x4(%rbp)
L63:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L50
  cmpl   $0x0,-0x4(%rbp)
  je     L69
L50:
  cmpl   $0x0,-0x4(%rbp)
  jne    L59
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
L15:
  addl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0x19,-0xc(%rbp)
  jle    L59
  nop
  nop
  leave
  ret
```

assistant: ```c
void crearAlfabero(char alfabeto[]) {
  int i, j, found;
  char letra;
  for (i = 0; i < 26; ++i) {
    do {
      letra = (rand() % 26) + 'A';
      found = 0;
      for (j = 0; j < i && !found; j++)
        if (alfabeto[j] == letra)
          found = 1;
    } while (found);
    if (!found)
      alfabeto[i] = letra;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crearAlfabero>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%r12d
  lea    0x1(%rdi),%r13
L41:
  lea    -0x1(%r12),%ebx
  add    %r13,%rbx
  jmp    L42
L7:
  add    $0x1,%rax
  cmp    %rbx,%rax
  je     L43
L47:
  cmp    %dl,(%rax)
  jne    L7
L42:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  cltq
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edx
  add    $0x41,%edx
  test   %r12d,%r12d
  jle    L43
  mov    %rbp,%rax
  jmp    L47
L43:
  mov    %dl,0x0(%rbp,%r12,1)
  add    $0x1,%r12
  cmp    $0x1a,%r12
  jne    L41
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void crearAlfabero(char alfabeto[]) {
  int i, j, found;
  char letra;
  for (i = 0; i < 26; ++i) {
    do {
      letra = (rand() % 26) + 'A';
      found = 0;
      for (j = 0; j < i && !found; j++)
        if (alfabeto[j] == letra)
          found = 1;
    } while (found);
    if (!found)
      alfabeto[i] = letra;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<crearAlfabero>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L6:
  mov    %ebx,%r12d
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  cltq
  imul   $0x4ec4ec4f,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x23,%rax
  sub    %ecx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edx
  add    $0x41,%edx
  test   %ebx,%ebx
  jle    L24
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L27:
  movzbl -0x1(%rbp,%rax,1),%ecx
  cmp    %eax,%r12d
  setg   %dil
  cmp    %dl,%cl
  setne  %sil
  add    $0x1,%rax
  test   %sil,%dil
  jne    L27
  cmp    %dl,%cl
  je     L7
  mov    %dl,0x0(%rbp,%rbx,1)
  cmp    $0x19,%ebx
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L24:
  mov    %dl,0x0(%rbp,%rbx,1)
L34:
  add    $0x1,%rbx
  jmp    L6
```

assistant: ```c
void crearAlfabero(char alfabeto[]) {
  int i, j, found;
  char letra;
  for (i = 0; i < 26; ++i) {
    do {
      letra = (rand() % 26) + 'A';
      found = 0;
      for (j = 0; j < i && !found; j++)
        if (alfabeto[j] == letra)
          found = 1;
    } while (found);
    if (!found)
      alfabeto[i] = letra;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crearAlfabero>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L10:
  mov    %ebx,%ebp
  nopw   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  cltq
  imul   $0x4ec4ec4f,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x23,%rax
  sub    %ecx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edx
  add    $0x41,%edx
  test   %ebp,%ebp
  jle    L6
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl -0x1(%r12,%rax,1),%ecx
  cmp    %eax,%ebp
  setg   %dil
  cmp    %dl,%cl
  setne  %sil
  add    $0x1,%rax
  test   %sil,%dil
  jne    L19
  cmp    %dl,%cl
  je     L35
  mov    %dl,(%r12,%rbx,1)
  cmp    $0x19,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L6:
  mov    %dl,(%r12,%rbx,1)
L5:
  add    $0x1,%rbx
  jmp    L10
```

assistant: ```c
void crearAlfabero(char alfabeto[]) {
  int i, j, found;
  char letra;
  for (i = 0; i < 26; ++i) {
    do {
      letra = (rand() % 26) + 'A';
      found = 0;
      for (j = 0; j < i && !found; j++)
        if (alfabeto[j] == letra)
          found = 1;
    } while (found);
    if (!found)
      alfabeto[i] = letra;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %edi,-0x1a4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
L2:
  cmpl   $0x0,-0x1a4(%rbp)
  jne    L2
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int isPalindrome(int a) {
  int arr[100];
  while (a) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPalindrome>:
  endbr64
L7:
  test   %edi,%edi
  jne    L7
  ret
```

assistant: ```c
int isPalindrome(int a) {
  int arr[100];
  while (a) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isPalindrome>:
  endbr64
  nopl   0x0(%rax)
L8:
  test   %edi,%edi
  jne    L8
  ret
```

assistant: ```c
int isPalindrome(int a) {
  int arr[100];
  while (a) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L17
L15:
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
int isPalindrome(int a) {
  int arr[100];
  while (a) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strconcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strconcat(char *str1, char *str2) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  char *str3 = (char *)malloc(sizeof(char) * (len1 + len2 + 1));
  strcpy(str3, str1);
  strcpy(&(str3[len1]), str2);
  return str3;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strconcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strconcat(char *str1, char *str2) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  char *str3 = (char *)malloc(sizeof(char) * (len1 + len2 + 1));
  strcpy(str3, str1);
  strcpy(&(str3[len1]), str2);
  return str3;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strconcat>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rdi
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strconcat(char *str1, char *str2) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  char *str3 = (char *)malloc(sizeof(char) * (len1 + len2 + 1));
  strcpy(str3, str1);
  strcpy(&(str3[len1]), str2);
  return str3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strconcat>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rdi
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strconcat(char *str1, char *str2) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  char *str3 = (char *)malloc(sizeof(char) * (len1 + len2 + 1));
  strcpy(str3, str1);
  strcpy(&(str3[len1]), str2);
  return str3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L16
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L10
L16:
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: Error %s != %s


assistant: ```c
int eq(char *str1, char *str2) {
  if (strcmp(str1, str2) != 0) {
    printf("Error %s != %s\n", str1, str2);
    return 0;
  }
  printf(".");
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<eq>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: Error %s != %s


assistant: ```c
int eq(char *str1, char *str2) {
  if (strcmp(str1, str2) != 0) {
    printf("Error %s != %s\n", str1, str2);
    return 0;
  }
  printf(".");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  mov    $0x2e,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: Error %s != %s


assistant: ```c
int eq(char *str1, char *str2) {
  if (strcmp(str1, str2) != 0) {
    printf("Error %s != %s\n", str1, str2);
    return 0;
  }
  printf(".");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x2e,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: Error %s != %s


assistant: ```c
int eq(char *str1, char *str2) {
  if (strcmp(str1, str2) != 0) {
    printf("Error %s != %s\n", str1, str2);
    return 0;
  }
  printf(".");
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sb_utf8n32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x7f,-0x14(%rbp)
  jg     L78
  movq   $0x1,-0x8(%rbp)
  jmp    L18
L78:
  cmpl   $0x7ff,-0x14(%rbp)
  jg     L12
  movq   $0x2,-0x8(%rbp)
  jmp    L18
L12:
  cmpl   $0xffff,-0x14(%rbp)
  jg     L38
  movq   $0x3,-0x8(%rbp)
  jmp    L18
L38:
  cmpl   $0x10fff,-0x14(%rbp)
  jg     L21
  movq   $0x4,-0x8(%rbp)
  jmp    L18
L21:
  movq   $0x0,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t sb_utf8n32(uint32_t wc) {
  size_t len;
  if (wc < 0x000080) {
    len = 1;
  } else if (wc < 0x00800) {
    len = 2;
  } else if (wc < 0x10000) {
    len = 3;
  } else if (wc < 0x11000) {
    len = 4;
  } else {
    len = 0;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sb_utf8n32>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L13
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L13
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L13
  cmp    $0x10fff,%edi
  setle  %al
  movzbl %al,%eax
  shl    $0x2,%rax
L13:
  ret
```

assistant: ```c
size_t sb_utf8n32(uint32_t wc) {
  size_t len;
  if (wc < 0x000080) {
    len = 1;
  } else if (wc < 0x00800) {
    len = 2;
  } else if (wc < 0x10000) {
    len = 3;
  } else if (wc < 0x11000) {
    len = 4;
  } else {
    len = 0;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sb_utf8n32>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L26
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L26
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L26
  xor    %eax,%eax
  cmp    $0x10fff,%edi
  setle  %al
  shl    $0x2,%rax
L26:
  ret
```

assistant: ```c
size_t sb_utf8n32(uint32_t wc) {
  size_t len;
  if (wc < 0x000080) {
    len = 1;
  } else if (wc < 0x00800) {
    len = 2;
  } else if (wc < 0x10000) {
    len = 3;
  } else if (wc < 0x11000) {
    len = 4;
  } else {
    len = 0;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sb_utf8n32>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L26
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L26
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L26
  xor    %eax,%eax
  cmp    $0x10fff,%edi
  setle  %al
  shl    $0x2,%rax
L26:
  ret
```

assistant: ```c
size_t sb_utf8n32(uint32_t wc) {
  size_t len;
  if (wc < 0x000080) {
    len = 1;
  } else if (wc < 0x00800) {
    len = 2;
  } else if (wc < 0x10000) {
    len = 3;
  } else if (wc < 0x11000) {
    len = 4;
  } else {
    len = 0;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jae    L10
  mov    -0x4(%rbp),%eax
  jmp    L15
L10:
  mov    -0x8(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int Min(unsigned int a, unsigned int b) {
  if (a < b) {
    return a;
  } else {
    return b;
  }
  __builtin_unreachable();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovbe %edi,%eax
  ret
```

assistant: ```c
unsigned int Min(unsigned int a, unsigned int b) {
  if (a < b) {
    return a;
  } else {
    return b;
  }
  __builtin_unreachable();
}
```
user: Translate the below assembly code into C programming language:

```asm
<Min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovbe %edi,%eax
  ret
```

assistant: ```c
unsigned int Min(unsigned int a, unsigned int b) {
  if (a < b) {
    return a;
  } else {
    return b;
  }
  __builtin_unreachable();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovbe %edi,%eax
  ret
```

assistant: ```c
unsigned int Min(unsigned int a, unsigned int b) {
  if (a < b) {
    return a;
  } else {
    return b;
  }
  __builtin_unreachable();
}
```