user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1d000(%rsp),%r11
L111:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L111
  sub    $0x508,%rsp
  lea    D22(%rip),%rbp
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1d4f8(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  lea    0x2c(%rsp),%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x28(%rsp),%rsi
  call   <scanf@plt>
  mov    0x28(%rsp),%eax
  cmp    %eax,0x24(%rsp)
  jne    L24
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  cmpl   $0x0,0x20(%rsp)
  lea    D48(%rip),%r12
  jle    L52
L121:
  mov    0x24(%rsp),%ecx
  test   %ecx,%ecx
  jle    L71
  lea    0x30(%rsp,%r14,4),%rbp
  xor    %ebx,%ebx
  nop
L87:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x24(%rsp)
  jg     L87
L71:
  add    $0x1,%r13d
  add    $0x64,%r14
  cmp    %r13d,0x20(%rsp)
  jg     L121
L52:
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  cmpl   $0x0,0x28(%rsp)
  lea    D48(%rip),%r12
  jle    L43
  nopl   0x0(%rax)
L1:
  mov    0x2c(%rsp),%edx
  test   %edx,%edx
  jle    L92
  lea    0x9c70(%rsp,%r14,4),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x2c(%rsp)
  jg     L30
L92:
  mov    0x28(%rsp),%eax
  add    $0x1,%r13d
  add    $0x64,%r14
  cmp    %r13d,%eax
  jg     L1
  test   %eax,%eax
  jle    L43
  sub    $0x1,%eax
  mov    0x20(%rsp),%r15d
  mov    0x24(%rsp),%ebx
  lea    0x138b0(%rsp),%rdi
  imul   $0x190,%rax,%rax
  mov    %rdi,0x18(%rsp)
  lea    0x30(%rsp),%r14
  lea    -0x1(%rbx),%edx
  lea    0x4(,%rdx,4),%r13
  lea    0x9c74(%rsp,%rdx,4),%r12
  lea    0x13a40(%rsp,%rax,1),%rbp
  lea    0x9c70(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r15),%eax
  imul   $0x190,%rax,%rax
  lea    0x9e00(%rsp,%rax,1),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L35:
  test   %ebx,%ebx
  jle    L91
  mov    %r13,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    0x8(%rsp),%r9
  mov    0x10(%rsp),%r10
  mov    %rax,%rdi
  mov    %rax,%r11
  xchg   %ax,%ax
L131:
  test   %r15d,%r15d
  jle    L145
  mov    %r10,%rax
  mov    %r14,%rcx
  xor    %esi,%esi
  nopl   (%rax)
L5:
  mov    (%rcx),%edx
  imul   (%rax),%edx
  add    $0x190,%rax
  add    $0x4,%rcx
  add    %edx,%esi
  cmp    %r9,%rax
  jne    L5
  mov    %esi,(%r11)
L145:
  add    $0x4,%r10
  add    $0x4,%r11
  add    $0x4,%r9
  cmp    %r12,%r10
  jne    L131
L91:
  add    $0x190,%rdi
  add    $0x190,%r14
  cmp    %rbp,%rdi
  jne    L35
  cmpl   $0x0,0x28(%rsp)
  jle    L43
  mov    0x18(%rsp),%rbp
  xor    %r13d,%r13d
  lea    D21(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L37:
  mov    0x2c(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L124
  nopw   0x0(%rax,%rax,1)
L174:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x2c(%rsp)
  jg     L174
L124:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    $0x190,%rbp
  call   <putchar@plt>
  cmp    %r13d,0x28(%rsp)
  jg     L37
L43:
  mov    0x1d4f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x1d508,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L43
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D48
data_type: string
name: disassemble_data
arguments: data_tag: D21
data_type: string
name: disassemble_data
arguments: data_tag: D25
data_type: string

tool: D22: %d %d

tool: D48: %d

tool: D21: %d	

tool: D25: Multiplication can not be done!

assistant: ```c
int main() {
  int a[100][100], b[100][100], c[100][100];
  int i, j, k, tmp, m1, n1, m2, n2;
  scanf("%d %d", &m1, &n1);
  scanf("%d %d", &m2, &n2);
  if (n1 == m2) {
    for (i = 0; i < m1; i++) {
      for (j = 0; j < n1; j++) {
        scanf("%d", &a[i][j]);
      }
    }
    for (i = 0; i < m2; i++) {
      for (j = 0; j < n2; j++) {
        scanf("%d", &b[i][j]);
      }
    }
    for (i = 0; i < m2; i++) {
      for (j = 0; j < n1; j++) {
        c[i][j] = 0;
        for (k = 0; k < m1; k++) {
          c[i][j] = c[i][j] + a[i][k] * b[k][j];
        }
      }
    }
    for (i = 0; i < m2; i++) {
      for (j = 0; j < n2; j++) {
        printf("%d\t", c[i][j]);
      }
      printf("\n");
    }
  } else {
    printf("Multiplication can not be done!\n");
  }
  return 0;
}
```