ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<upload_source_file>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x610,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x100(%rsp),%r13
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <right_trim_session@plt>
  mov    %rax,%rdi
  call   <basename_get_filename@plt>
  mov    %rbp,%rdi
  lea    0x200(%rsp),%rbp
  mov    %rax,%r12
  call   <application_first_relative_source_directory@plt>
  mov    %r15,%rdx
  lea    D37(%rip),%rsi
  mov    %r13,%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    %r14,%rdx
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D32(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    %r13,%rdx
  lea    D14(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x610,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D37
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D32
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string

tool: D37: %s/%s

tool: D39: cp %s %s/%s

tool: D32: chmod g+w %s/%s

tool: D14: chmod -x %s/%s

assistant: ```c
void upload_source_file(char *application_name, char *source_filename_directory_session, char *appaserver_mount_point) {
  char *full_filename_directory;
  char *filename;
  char tmp_buffer[256];
  char destination_directory[256];
  char sys_string[1024];
  strcpy(tmp_buffer, source_filename_directory_session);
  full_filename_directory = right_trim_session(tmp_buffer);
  filename = basename_get_filename(full_filename_directory);
  sprintf(destination_directory, "%s/%s", appaserver_mount_point, application_first_relative_source_directory(application_name));
  sprintf(sys_string, "cp %s %s/%s", source_filename_directory_session, destination_directory, filename);
  if (system(sys_string)) {
  };
  sprintf(sys_string, "chmod g+w %s/%s", destination_directory, filename);
  sprintf(sys_string, "chmod -x %s/%s", destination_directory, filename);
  if (system(sys_string)) {
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<upload_source_file>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x610,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x100(%rsp),%r13
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <right_trim_session@plt>
  mov    %rax,%rdi
  call   <basename_get_filename@plt>
  mov    %rbp,%rdi
  lea    0x200(%rsp),%rbp
  mov    %rax,%r12
  call   <application_first_relative_source_directory@plt>
  mov    %r15,%rdx
  lea    D26(%rip),%rsi
  mov    %r13,%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    %r14,%rdx
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D25(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    %r13,%rdx
  lea    D37(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x610,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D37
type_infered: string

tool: D26: %s/%s

tool: D10: cp %s %s/%s

tool: D25: chmod g+w %s/%s

tool: D37: chmod -x %s/%s

assistant: ```c
void upload_source_file(char *application_name, char *source_filename_directory_session, char *appaserver_mount_point) {
  char *full_filename_directory;
  char *filename;
  char tmp_buffer[256];
  char destination_directory[256];
  char sys_string[1024];
  strcpy(tmp_buffer, source_filename_directory_session);
  full_filename_directory = right_trim_session(tmp_buffer);
  filename = basename_get_filename(full_filename_directory);
  sprintf(destination_directory, "%s/%s", appaserver_mount_point, application_first_relative_source_directory(application_name));
  sprintf(sys_string, "cp %s %s/%s", source_filename_directory_session, destination_directory, filename);
  if (system(sys_string)) {
  };
  sprintf(sys_string, "chmod g+w %s/%s", destination_directory, filename);
  sprintf(sys_string, "chmod -x %s/%s", destination_directory, filename);
  if (system(sys_string)) {
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  cmpl   $0x2,-0x34(%rbp)
  jne    L94
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rdx
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L94
  mov    -0x20(%rbp),%rax
  cmp    $0x1,%rax
  ja     L109
L94:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L93
L109:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x2,-0x10(%rbp)
  jmp    L89
L105:
  movl   $0x0,-0x24(%rbp)
  jmp    L88
L81:
  addl   $0x1,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
L88:
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L81
  cmpl   $0x0,-0x24(%rbp)
  je     L39
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  addq   $0x1,-0x10(%rbp)
L89:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L105
  cmpl   $0x0,-0x28(%rbp)
  je     L29
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L86
L29:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L86:
  mov    $0x0,%eax
L93:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D25
type: string
name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D15
type: string
name: read_data
arguments: data_label: D28
type: string
name: read_data
arguments: data_label: D14
type: string

tool: D25: %llu

tool: D12: You lose, you lose, you lose!

tool: D15: Divisor: %llu^%d


tool: D28: Prime

tool: D14: Divisor: %llu^1


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long long biggest, tsqrt, i;
  int prime = 1;
  int this_num = 0;
  if ((argc != 2) || (!sscanf(argv[1], "%llu", &biggest)) || (biggest < 2)) {
    printf("You lose, you lose, you lose!\n");
    return 2;
  }
  tsqrt = sqrt(biggest);
  for (i = 2; i < tsqrt; i++) {
    this_num = 0;
    while (biggest % i == 0) {
      this_num++;
      biggest = biggest / i;
      tsqrt = sqrt(biggest);
      prime = 0;
    }
    if (this_num) {
      printf("Divisor: %llu^%d\n", i, this_num);
    }
  }
  if (prime) {
    printf("Prime\n");
  } else {
    printf("Divisor: %llu^1\n", biggest);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L16
  mov    %rsp,%rdx
  mov    0x8(%rsi),%rdi
  lea    D22(%rip),%rsi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L16
  mov    (%rsp),%rdi
  cmp    $0x1,%rdi
  jbe    L16
  call   <sqrt@plt>
  mov    %rax,%r13
  mov    $0x1,%ebp
  mov    $0x2,%ebx
  lea    D49(%rip),%r12
  cmp    $0x2,%rax
  ja     L70
L51:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  jmp    L3
L16:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%ebp
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jbe    L56
L70:
  mov    (%rsp),%rdi
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rbx
  test   %rdx,%rdx
  jne    L18
  mov    $0x0,%ebp
L125:
  add    $0x1,%ebp
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rbx
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <sqrt@plt>
  mov    %rax,%r13
  mov    (%rsp),%rdi
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rbx
  test   %rdx,%rdx
  je     L125
  test   %ebp,%ebp
  je     L18
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebp
  jmp    L18
L56:
  test   %ebp,%ebp
  jne    L51
  mov    (%rsp),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string

tool: D22: %llu

tool: D49: Divisor: %llu^%d


tool: D11: Prime

tool: D21: You lose, you lose, you lose!

tool: D10: Divisor: %llu^1


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long long biggest, tsqrt, i;
  int prime = 1;
  int this_num = 0;
  if ((argc != 2) || (!sscanf(argv[1], "%llu", &biggest)) || (biggest < 2)) {
    printf("You lose, you lose, you lose!\n");
    return 2;
  }
  tsqrt = sqrt(biggest);
  for (i = 2; i < tsqrt; i++) {
    this_num = 0;
    while (biggest % i == 0) {
      this_num++;
      biggest = biggest / i;
      tsqrt = sqrt(biggest);
      prime = 0;
    }
    if (this_num) {
      printf("Divisor: %llu^%d\n", i, this_num);
    }
  }
  if (prime) {
    printf("Prime\n");
  } else {
    printf("Divisor: %llu^1\n", biggest);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L58
  mov    0x8(%rsi),%rdi
  mov    %rsp,%rdx
  lea    D37(%rip),%rsi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L58
  mov    (%rsp),%rdi
  cmp    $0x1,%rdi
  jbe    L58
  call   <sqrt@plt>
  mov    $0x1,%r14d
  mov    $0x2,%ebx
  lea    D19(%rip),%rbp
  mov    %rax,%r13
  cmp    $0x2,%rax
  jbe    L9
  cs nopw 0x0(%rax,%rax,1)
L77:
  mov    (%rsp),%rdi
  xor    %edx,%edx
  xor    %r12d,%r12d
  mov    %rdi,%rax
  div    %rbx
  test   %rdx,%rdx
  jne    L99
  nopl   0x0(%rax)
L54:
  mov    %rdi,%rax
  xor    %edx,%edx
  add    $0x1,%r12d
  div    %rbx
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <sqrt@plt>
  mov    (%rsp),%rdi
  xor    %edx,%edx
  mov    %rax,%r13
  mov    %rdi,%rax
  div    %rbx
  test   %rdx,%rdx
  je     L54
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %r14d,%r14d
L99:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L77
  test   %r14d,%r14d
  jne    L9
  mov    (%rsp),%rsi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L93
L58:
  lea    D22(%rip),%rdi
  mov    $0x2,%r14d
  call   <puts@plt>
L93:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x10,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  lea    D4(%rip),%rdi
  xor    %r14d,%r14d
  call   <puts@plt>
  jmp    L93
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D37
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D34
type: string
name: unpack_data
arguments: data_label: D22
type: string
name: unpack_data
arguments: data_label: D4
type: string

tool: D37: %llu

tool: D19: Divisor: %llu^%d


tool: D34: Divisor: %llu^1


tool: D22: You lose, you lose, you lose!

tool: D4: Prime

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long long biggest, tsqrt, i;
  int prime = 1;
  int this_num = 0;
  if ((argc != 2) || (!sscanf(argv[1], "%llu", &biggest)) || (biggest < 2)) {
    printf("You lose, you lose, you lose!\n");
    return 2;
  }
  tsqrt = sqrt(biggest);
  for (i = 2; i < tsqrt; i++) {
    this_num = 0;
    while (biggest % i == 0) {
      this_num++;
      biggest = biggest / i;
      tsqrt = sqrt(biggest);
      prime = 0;
    }
    if (this_num) {
      printf("Divisor: %llu^%d\n", i, this_num);
    }
  }
  if (prime) {
    printf("Prime\n");
  } else {
    printf("Divisor: %llu^1\n", biggest);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L74
  mov    0x8(%rsi),%rdi
  mov    %rsp,%rdx
  lea    D22(%rip),%rsi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L74
  mov    (%rsp),%rdi
  cmp    $0x1,%rdi
  jbe    L74
  call   <sqrt@plt>
  mov    $0x1,%r14d
  mov    $0x2,%ebx
  lea    D27(%rip),%rbp
  mov    %rax,%r13
  cmp    $0x2,%rax
  jbe    L57
  cs nopw 0x0(%rax,%rax,1)
L90:
  mov    (%rsp),%rdi
  xor    %edx,%edx
  xor    %r12d,%r12d
  mov    %rdi,%rax
  div    %rbx
  test   %rdx,%rdx
  jne    L55
  nopl   0x0(%rax)
L39:
  mov    %rdi,%rax
  xor    %edx,%edx
  add    $0x1,%r12d
  div    %rbx
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <sqrt@plt>
  mov    (%rsp),%rdi
  xor    %edx,%edx
  mov    %rax,%r13
  mov    %rdi,%rax
  div    %rbx
  test   %rdx,%rdx
  je     L39
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %r14d,%r14d
L55:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L90
  test   %r14d,%r14d
  jne    L57
  mov    (%rsp),%rsi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L79
L74:
  lea    D4(%rip),%rdi
  mov    $0x2,%r14d
  call   <puts@plt>
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0x10,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  lea    D36(%rip),%rdi
  xor    %r14d,%r14d
  call   <puts@plt>
  jmp    L79
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D27
data_type: string
name: retrieve_data
arguments: tag: D34
data_type: string
name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D36
data_type: string

tool: D22: %llu

tool: D27: Divisor: %llu^%d


tool: D34: Divisor: %llu^1


tool: D4: You lose, you lose, you lose!

tool: D36: Prime

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long long biggest, tsqrt, i;
  int prime = 1;
  int this_num = 0;
  if ((argc != 2) || (!sscanf(argv[1], "%llu", &biggest)) || (biggest < 2)) {
    printf("You lose, you lose, you lose!\n");
    return 2;
  }
  tsqrt = sqrt(biggest);
  for (i = 2; i < tsqrt; i++) {
    this_num = 0;
    while (biggest % i == 0) {
      this_num++;
      biggest = biggest / i;
      tsqrt = sqrt(biggest);
      prime = 0;
    }
    if (this_num) {
      printf("Divisor: %llu^%d\n", i, this_num);
    }
  }
  if (prime) {
    printf("Prime\n");
  } else {
    printf("Divisor: %llu^1\n", biggest);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Xorriso_get_pattern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L39
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Xorriso_lst_get_text@plt>
  jmp    L25
L39:
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Xorriso_lst_get_next@plt>
  mov    %rax,-0x8(%rbp)
L13:
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
char *Xorriso_get_pattern(struct XorrisO *xorriso, struct Xorriso_lsT *patternlist, int index, int flag) {
  int i = 0;
  struct Xorriso_lsT *s;
  for (s = patternlist; s != NULL; s = Xorriso_lst_get_next(s, 0)) {
    if (i == index)
      return (Xorriso_lst_get_text(s, 0));
    i++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Xorriso_get_pattern>:
  endbr64
  mov    %rsi,%rdi
  test   %rsi,%rsi
  je     L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    $0x0,%ebx
  test   %edx,%edx
  je     L37
L12:
  mov    $0x0,%esi
  call   <Xorriso_lst_get_next@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L36
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
L37:
  mov    $0x0,%esi
  call   <Xorriso_lst_get_text@plt>
  mov    %rax,%rdi
L36:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *Xorriso_get_pattern(struct XorrisO *xorriso, struct Xorriso_lsT *patternlist, int index, int flag) {
  int i = 0;
  struct Xorriso_lsT *s;
  for (s = patternlist; s != NULL; s = Xorriso_lst_get_next(s, 0)) {
    if (i == index)
      return (Xorriso_lst_get_text(s, 0));
    i++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Xorriso_get_pattern>:
  endbr64
  test   %rsi,%rsi
  je     L31
  mov    %rsi,%rdi
  test   %edx,%edx
  je     L23
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L49
  nopl   0x0(%rax)
L2:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L7
L49:
  xor    %esi,%esi
  call   <Xorriso_lst_get_next@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  add    $0x8,%rsp
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <Xorriso_lst_get_text@plt>
L31:
  xor    %eax,%eax
  ret
L23:
  xor    %esi,%esi
  jmp    1060 <Xorriso_lst_get_text@plt>
```

assistant: ```c
char *Xorriso_get_pattern(struct XorrisO *xorriso, struct Xorriso_lsT *patternlist, int index, int flag) {
  int i = 0;
  struct Xorriso_lsT *s;
  for (s = patternlist; s != NULL; s = Xorriso_lst_get_next(s, 0)) {
    if (i == index)
      return (Xorriso_lst_get_text(s, 0));
    i++;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Xorriso_get_pattern>:
  endbr64
  test   %rsi,%rsi
  je     L7
  mov    %rsi,%rdi
  test   %edx,%edx
  je     L21
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L22
  nopl   0x0(%rax)
L46:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L14
L22:
  xor    %esi,%esi
  call   <Xorriso_lst_get_next@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L46
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  add    $0x8,%rsp
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <Xorriso_lst_get_text@plt>
L7:
  xor    %eax,%eax
  ret
L21:
  xor    %esi,%esi
  jmp    1060 <Xorriso_lst_get_text@plt>
```

assistant: ```c
char *Xorriso_get_pattern(struct XorrisO *xorriso, struct Xorriso_lsT *patternlist, int index, int flag) {
  int i = 0;
  struct Xorriso_lsT *s;
  for (s = patternlist; s != NULL; s = Xorriso_lst_get_next(s, 0)) {
    if (i == index)
      return (Xorriso_lst_get_text(s, 0));
    i++;
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap16(uint16_t *word) {
  uint16_t w1, w2;
  w1 = *word << 8;
  w2 = *word >> 8;
  *word = w1 | w2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap16>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  shl    $0x8,%edx
  sar    $0x8,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void swap16(uint16_t *word) {
  uint16_t w1, w2;
  w1 = *word << 8;
  w2 = *word >> 8;
  *word = w1 | w2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap16>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  sar    $0x8,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void swap16(uint16_t *word) {
  uint16_t w1, w2;
  w1 = *word << 8;
  w2 = *word >> 8;
  *word = w1 | w2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap16>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  sar    $0x8,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void swap16(uint16_t *word) {
  uint16_t w1, w2;
  w1 = *word << 8;
  w2 = *word >> 8;
  *word = w1 | w2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_usectime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
uint64_t get_usectime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((uint64_t)(tv.tv_sec)) * 1000000 + tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_usectime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  add    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_usectime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((uint64_t)(tv.tv_sec)) * 1000000 + tv.tv_usec;
}
```