ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_event_from_kernel>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10048(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %edi,%ebp
  lea    0x40(%rsp),%r12
  movq   %rax,%xmm0
  lea    0xc(%rsp),%rax
  lea    D1(%rip),%rdi
  mov    %r12,0x18(%rsp)
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movl   $0x10000,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  mov    %rax,0x20(%rsp)
  movups %xmm0,0x28(%rsp)
  call   <puts@plt>
  xor    %edx,%edx
  lea    0x20(%rsp),%rsi
  mov    %ebp,%edi
  call   <recvmsg@plt>
  test   %eax,%eax
  js     L23
  mov    %r12,%rdi
  call   <NLMSG_DATA@plt>
  lea    D22(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
L36:
  mov    0x10048(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10058,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  jmp    L36
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D36
type: byte[8]
name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D21
type: string

tool: D1: Ok, listening.

tool: {"D36": [0x04,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D22: Received message payload: %s


tool: D21: ret < 0.

assistant: ```c
void read_event_from_kernel(int sock) {
  struct sockaddr_nl nladdr;
  struct msghdr msg;
  struct iovec iov;
  char buffer[65536];
  int ret;
  iov.iov_base = (void *)buffer;
  iov.iov_len = sizeof(buffer);
  msg.msg_name = (void *)&(nladdr);
  msg.msg_namelen = sizeof(nladdr);
  msg.msg_iov = &iov;
  msg.msg_iovlen = 1;
  printf("Ok, listening.\n");
  ret = recvmsg(sock, &msg, 0);
  if (ret < 0)
    printf("ret < 0.\n");
  else
    printf("Received message payload: %s\n", NLMSG_DATA((struct nlmsghdr *)&buffer));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uint64_to_hexstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L42
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  cltq
  movb   $0x30,-0x20(%rbp,%rax,1)
  jmp    L42
L25:
  mov    -0x34(%rbp),%eax
  and    $0xf,%eax
  mov    %al,-0x29(%rbp)
  cmpb   $0x9,-0x29(%rbp)
  jle    L60
  cmpl   $0x0,-0x38(%rbp)
  je     L80
  mov    $0x27,%edx
  jmp    L9
L80:
  mov    $0x7,%edx
L9:
  movzbl -0x29(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x29(%rbp)
L60:
  movzbl -0x29(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  sarl   $0x4,-0x34(%rbp)
L42:
  cmpl   $0x0,-0x34(%rbp)
  jne    L25
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  je     L13
  jmp    L2
L95:
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  movzbl -0x20(%rbp,%rdx,1),%edx
  mov    %dl,(%rax)
L2:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  test   %eax,%eax
  jne    L95
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
L13:
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

assistant: ```c
int uint64_to_hexstr(uint64_t ui64Val, char *pcBuf, bool bLower) {
  int iNumDig, ix = 0;
  char cCh, tbuf[20];
  if (ui64Val == 0) {
    tbuf[ix++] = '0';
  }
  while (ui64Val) {
    cCh = ui64Val & 0xf;
    if (cCh > 9) {
      cCh += bLower ? 0x27 : 0x7;
    }
    tbuf[ix++] = cCh + '0';
    ui64Val >>= 4;
  }
  iNumDig = ix;
  if (pcBuf) {
    while (ix--) {
      *pcBuf++ = tbuf[ix];
    }
    *pcBuf = 0;
  }
  return iNumDig;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uint64_to_hexstr>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%ecx
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L7
  cmp    $0x1,%edx
  sbb    %edi,%edi
  and    $0xffffffe0,%edi
  add    $0x27,%edi
  mov    $0x1,%edx
  lea    -0x1(%rsp),%r8
L27:
  mov    %ecx,%eax
  and    $0xf,%eax
  lea    (%rax,%rdi,1),%esi
  cmp    $0x9,%al
  cmovg  %esi,%eax
  mov    %edx,%esi
  add    $0x30,%eax
  mov    %al,(%r8,%rdx,1)
  add    $0x1,%rdx
  sar    $0x4,%ecx
  jne    L27
  test   %r9,%r9
  je     L10
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L26
L49:
  movslq %esi,%rax
  lea    (%rsp,%rax,1),%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%r9,%rax,1),%r8
  mov    %r9,%rax
L12:
  add    $0x1,%rax
  movzbl -0x1(%rdx),%edi
  mov    %dil,-0x1(%rax)
  sub    $0x1,%rdx
  cmp    %r8,%rax
  jne    L12
  mov    %ecx,%ecx
  lea    0x1(%r9,%rcx,1),%r9
L26:
  movb   $0x0,(%r9)
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    %esi,%eax
  add    $0x28,%rsp
  ret
L7:
  movb   $0x30,(%rsp)
  mov    $0x1,%esi
  test   %r9,%r9
  jne    L49
  jmp    L10
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uint64_to_hexstr(uint64_t ui64Val, char *pcBuf, bool bLower) {
  int iNumDig, ix = 0;
  char cCh, tbuf[20];
  if (ui64Val == 0) {
    tbuf[ix++] = '0';
  }
  while (ui64Val) {
    cCh = ui64Val & 0xf;
    if (cCh > 9) {
      cCh += bLower ? 0x27 : 0x7;
    }
    tbuf[ix++] = cCh + '0';
    ui64Val >>= 4;
  }
  iNumDig = ix;
  if (pcBuf) {
    while (ix--) {
      *pcBuf++ = tbuf[ix];
    }
    *pcBuf = 0;
  }
  return iNumDig;
}
```
user: What is the c source code of the assembly code below?

```asm
<uint64_to_hexstr>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jne    L35
  mov    $0x1,%r8d
  test   %rsi,%rsi
  je     L42
  movb   $0x30,(%rsi)
  lea    0x1(%rsi),%rcx
  mov    $0x1,%r8d
L61:
  movb   $0x0,(%rcx)
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    %r8d,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  cmp    $0x1,%edx
  mov    %rsp,%r9
  mov    %edi,%ecx
  sbb    %r11d,%r11d
  mov    %r9,%rdi
  xor    %r10d,%r10d
  and    $0xffffffe0,%r11d
  add    $0x27,%r11d
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L25:
  movslq %r8d,%r10
L26:
  mov    %ecx,%edx
  lea    0x1(%r10),%r8d
  and    $0xf,%edx
  cmp    $0x9,%dl
  lea    (%rdx,%r11,1),%eax
  cmovle %edx,%eax
  add    $0x1,%rdi
  add    $0x30,%eax
  mov    %al,-0x1(%rdi)
  sar    $0x4,%ecx
  jne    L25
  test   %rsi,%rsi
  je     L42
  movslq %r8d,%rcx
  lea    (%r9,%r10,1),%rdx
  add    %rsi,%rcx
  jmp    L10
  xchg   %ax,%ax
L1:
  movzbl (%rdx),%eax
L10:
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %al,-0x1(%rsi)
  cmp    %rcx,%rsi
  jne    L1
  jmp    L61
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uint64_to_hexstr(uint64_t ui64Val, char *pcBuf, bool bLower) {
  int iNumDig, ix = 0;
  char cCh, tbuf[20];
  if (ui64Val == 0) {
    tbuf[ix++] = '0';
  }
  while (ui64Val) {
    cCh = ui64Val & 0xf;
    if (cCh > 9) {
      cCh += bLower ? 0x27 : 0x7;
    }
    tbuf[ix++] = cCh + '0';
    ui64Val >>= 4;
  }
  iNumDig = ix;
  if (pcBuf) {
    while (ix--) {
      *pcBuf++ = tbuf[ix];
    }
    *pcBuf = 0;
  }
  return iNumDig;
}
```
user: What is the c source code of the assembly code below:

```asm
<uint64_to_hexstr>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jne    L16
  mov    $0x1,%r9d
  test   %rsi,%rsi
  je     L70
  movb   $0x30,(%rsi)
  lea    0x1(%rsi),%rcx
  mov    $0x1,%r9d
L17:
  movb   $0x0,(%rcx)
L70:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    %r9d,%eax
  add    $0x28,%rsp
  ret
  nop
L16:
  cmp    $0x1,%edx
  mov    %rsp,%r8
  mov    %edi,%ecx
  sbb    %r11d,%r11d
  mov    %r8,%rdi
  xor    %r10d,%r10d
  and    $0xffffffe0,%r11d
  add    $0x27,%r11d
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L50:
  movslq %r9d,%r10
L32:
  mov    %ecx,%edx
  lea    0x1(%r10),%r9d
  and    $0xf,%edx
  cmp    $0x9,%dl
  lea    (%rdx,%r11,1),%eax
  cmovle %edx,%eax
  add    $0x1,%rdi
  add    $0x30,%eax
  mov    %al,-0x1(%rdi)
  sar    $0x4,%ecx
  jne    L50
  test   %rsi,%rsi
  je     L70
  movslq %r9d,%rcx
  lea    (%r8,%r10,1),%rax
  add    %rsi,%rcx
  nopl   0x0(%rax)
L66:
  movzbl (%rax),%edx
  add    $0x1,%rsi
  sub    $0x1,%rax
  mov    %dl,-0x1(%rsi)
  cmp    %rcx,%rsi
  jne    L66
  jmp    L17
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uint64_to_hexstr(uint64_t ui64Val, char *pcBuf, bool bLower) {
  int iNumDig, ix = 0;
  char cCh, tbuf[20];
  if (ui64Val == 0) {
    tbuf[ix++] = '0';
  }
  while (ui64Val) {
    cCh = ui64Val & 0xf;
    if (cCh > 9) {
      cCh += bLower ? 0x27 : 0x7;
    }
    tbuf[ix++] = cCh + '0';
    ui64Val >>= 4;
  }
  iNumDig = ix;
  if (pcBuf) {
    while (ix--) {
      *pcBuf++ = tbuf[ix];
    }
    *pcBuf = 0;
  }
  return iNumDig;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psi_h_stable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: byte[8]

tool: {"D7": [0x7d,0xd6,0x0d,0xa6,0xc8,0x67,0x19,0xc0]}

assistant: ```c
double psi_h_stable(double zeta, double zeta0) {
  double psi_h = -6.351351351351352 * (zeta - zeta0);
  return psi_h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<psi_h_stable>:
  endbr64
  subsd  %xmm1,%xmm0
  mulsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: byte[8]

tool: {"D4": [0x7d,0xd6,0x0d,0xa6,0xc8,0x67,0x19,0xc0]}

assistant: ```c
double psi_h_stable(double zeta, double zeta0) {
  double psi_h = -6.351351351351352 * (zeta - zeta0);
  return psi_h;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<psi_h_stable>:
  endbr64
  subsd  %xmm1,%xmm0
  mulsd  D8(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: byte[8]

tool: {"D8": [0x7d,0xd6,0x0d,0xa6,0xc8,0x67,0x19,0xc0]}

assistant: ```c
double psi_h_stable(double zeta, double zeta0) {
  double psi_h = -6.351351351351352 * (zeta - zeta0);
  return psi_h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<psi_h_stable>:
  endbr64
  subsd  %xmm1,%xmm0
  mulsd  D8(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: byte[8]

tool: {"D8": [0x7d,0xd6,0x0d,0xa6,0xc8,0x67,0x19,0xc0]}

assistant: ```c
double psi_h_stable(double zeta, double zeta0) {
  double psi_h = -6.351351351351352 * (zeta - zeta0);
  return psi_h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L17
L9:
  addq   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L13
L27:
  subq   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L19
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
L19:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t trim(char *s, char *s2) {
  char *l;
  size_t ans;
  while (isspace(*s2))
    s2++;
  l = s2 + strlen(s2) - 1;
  while (l > s2 && isspace(*l))
    l--;
  l++;
  ans = l - s2;
  memcpy(s, s2, ans);
  s[ans] = 0;
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  jmp    L42
L38:
  add    $0x1,%rbp
L42:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jae    L32
L11:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L32
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L11
L32:
  add    $0x1,%rbx
  sub    %rbp,%rbx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t trim(char *s, char *s2) {
  char *l;
  size_t ans;
  while (isspace(*s2))
    s2++;
  l = s2 + strlen(s2) - 1;
  while (l > s2 && isspace(*l))
    l--;
  l++;
  ans = l - s2;
  memcpy(s, s2, ans);
  s[ans] = 0;
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  jmp    L39
  nopl   0x0(%rax)
L35:
  add    $0x1,%rbp
L39:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%r12
  cmp    %r12,%rbp
  jb     L37
  jmp    L9
L48:
  lea    -0x1(%r12),%rax
  cmp    %rax,%rbp
  je     L2
  mov    %rax,%r12
L37:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  add    $0x1,%r12
L2:
  sub    %rbp,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  lea    0x0(%rbp,%rax,1),%r12
  jmp    L2
```

assistant: ```c
size_t trim(char *s, char *s2) {
  char *l;
  size_t ans;
  while (isspace(*s2))
    s2++;
  l = s2 + strlen(s2) - 1;
  while (l > s2 && isspace(*l))
    l--;
  l++;
  ans = l - s2;
  memcpy(s, s2, ans);
  s[ans] = 0;
  return ans;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  jmp    L17
  nopl   0x0(%rax)
L32:
  add    $0x1,%rbp
L17:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%r12
  cmp    %r12,%rbp
  jb     L43
  jmp    L0
L1:
  lea    -0x1(%r12),%rax
  cmp    %rax,%rbp
  je     L54
  mov    %rax,%r12
L43:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  add    $0x1,%r12
L54:
  sub    %rbp,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  lea    0x0(%rbp,%rax,1),%r12
  jmp    L54
```

assistant: ```c
size_t trim(char *s, char *s2) {
  char *l;
  size_t ans;
  while (isspace(*s2))
    s2++;
  l = s2 + strlen(s2) - 1;
  while (l > s2 && isspace(*l))
    l--;
  l++;
  ans = l - s2;
  memcpy(s, s2, ans);
  s[ans] = 0;
  return ans;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<power_tick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D15(%rip),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,D20(%rip)
  test   %eax,%eax
  jne    L6
  movl   $0x1f4,D20(%rip)
  mov    $0x0,%eax
  call   <power_update@plt>
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void power_tick(void) {
  static uint16_t c = 0;
  if (c-- == 0) {
    c = 500;
    power_update();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<power_tick>:
  endbr64
  mov    D4(%rip),%eax
  test   %eax,%eax
  je     L9
  sub    $0x1,%eax
  mov    %eax,D7(%rip)
  ret
L9:
  sub    $0x8,%rsp
  movl   $0x1f4,D7(%rip)
  mov    $0x0,%eax
  call   <power_update@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void power_tick(void) {
  static uint16_t c = 0;
  if (c-- == 0) {
    c = 500;
    power_update();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power_tick>:
  endbr64
  mov    D7(%rip),%eax
  test   %eax,%eax
  je     L2
  sub    $0x1,%eax
  mov    %eax,D15(%rip)
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movl   $0x1f4,D15(%rip)
  xor    %eax,%eax
  jmp    1050 <power_update@plt>
```

assistant: ```c
void power_tick(void) {
  static uint16_t c = 0;
  if (c-- == 0) {
    c = 500;
    power_update();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power_tick>:
  endbr64
  mov    D12(%rip),%eax
  test   %eax,%eax
  je     L2
  sub    $0x1,%eax
  mov    %eax,D2(%rip)
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movl   $0x1f4,D2(%rip)
  xor    %eax,%eax
  jmp    1050 <power_update@plt>
```

assistant: ```c
void power_tick(void) {
  static uint16_t c = 0;
  if (c-- == 0) {
    c = 500;
    power_update();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L1
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
L1:
  mov    $0x1,%eax
  jmp    L21
L16:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   -0x4(%rbp),%eax
L21:
  leave
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1 || n == 0) {
    return 1;
  } else {
    return factorial(n - 1) * n;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  ja     L0
  ret
L0:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1 || n == 0) {
    return 1;
  } else {
    return factorial(n - 1) * n;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L13
  xchg   %ax,%ax
L6:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L6
L13:
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1 || n == 0) {
    return 1;
  } else {
    return factorial(n - 1) * n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L11
  xchg   %ax,%ax
L5:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L5
L11:
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1 || n == 0) {
    return 1;
  } else {
    return factorial(n - 1) * n;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copy_ulong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movq   $0x0,-0x10(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <copy_token@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  call   <malformed_events@plt>
L9:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long copy_ulong(char **c, char delim) {
  unsigned long val = 0;
  char *str = copy_token(c, delim);
  if (!str)
    malformed_events();
  val = strtoul(str, NULL, 0);
  free(str);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_ulong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <copy_token@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
L10:
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtoul@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x0,%eax
  call   <malformed_events@plt>
  jmp    L10
```

assistant: ```c
unsigned long copy_ulong(char **c, char delim) {
  unsigned long val = 0;
  char *str = copy_token(c, delim);
  if (!str)
    malformed_events();
  val = strtoul(str, NULL, 0);
  free(str);
  return val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_ulong>:
  endbr64
  push   %r12
  movsbl %sil,%esi
  push   %rbp
  sub    $0x8,%rsp
  call   <copy_token@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
L12:
  mov    %rbp,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  call   <malformed_events@plt>
  jmp    L12
```

assistant: ```c
unsigned long copy_ulong(char **c, char delim) {
  unsigned long val = 0;
  char *str = copy_token(c, delim);
  if (!str)
    malformed_events();
  val = strtoul(str, NULL, 0);
  free(str);
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_ulong>:
  endbr64
  push   %r12
  movsbl %sil,%esi
  push   %rbp
  sub    $0x8,%rsp
  call   <copy_token@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
L12:
  mov    %rbp,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  call   <malformed_events@plt>
  jmp    L12
```

assistant: ```c
unsigned long copy_ulong(char **c, char delim) {
  unsigned long val = 0;
  char *str = copy_token(c, delim);
  if (!str)
    malformed_events();
  val = strtoul(str, NULL, 0);
  free(str);
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<dnorm_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L8
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x38(%rbp),%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L11
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: f32[2]

tool: {"D7": [0.0,-1.75]}

assistant: ```c
double dnorm_log(double *x, int n, double location, double scale) {
  int i;
  double logDensity = 0, z, logScale;
  logScale = log(scale);
  for (i = 0; i < n; i++) {
    z = (x[i] - location) / scale;
    logDensity += -0.5 * z * z - logScale;
  }
  return logDensity;
}
```