ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isort1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L35
L10:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L22
L37:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L22:
  cmpl   $0x0,-0x8(%rbp)
  jle    L46
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L37
L46:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void isort1(int elements, int *array) {
  for (int i = 1; i < elements; ++i) {
    for (int j = i; (j > 0) && (array[j - 1] > array[j]); --j) {
      int tmp = array[j - 1];
      array[j - 1] = array[j];
      array[j] = tmp;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isort1>:
  endbr64
  cmp    $0x1,%edi
  jle    L2
  lea    0x4(%rsi),%r9
  mov    $0x1,%r8d
  jmp    L24
L29:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%edi
  je     L2
L24:
  test   %r8d,%r8d
  jle    L29
  mov    %r9,%rax
L12:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L29
  mov    %edx,-0x4(%rax)
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L12
  jmp    L29
L2:
  ret
```

assistant: ```c
void isort1(int elements, int *array) {
  for (int i = 1; i < elements; ++i) {
    for (int j = i; (j > 0) && (array[j - 1] > array[j]); --j) {
      int tmp = array[j - 1];
      array[j - 1] = array[j];
      array[j] = tmp;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<isort1>:
  endbr64
  lea    0x4(%rsi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L21
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L34:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L12
  mov    %edx,-0x4(%rax)
  sub    $0x4,%rax
  mov    %ecx,0x4(%rax)
  cmp    %rsi,%rax
  jne    L34
L12:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%edi
  jne    L4
  ret
L21:
  ret
```

assistant: ```c
void isort1(int elements, int *array) {
  for (int i = 1; i < elements; ++i) {
    for (int j = i; (j > 0) && (array[j - 1] > array[j]); --j) {
      int tmp = array[j - 1];
      array[j - 1] = array[j];
      array[j] = tmp;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isort1>:
  endbr64
  lea    0x4(%rsi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L1
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L14
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L4
L14:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%edi
  jne    L7
  ret
L1:
  ret
```

assistant: ```c
void isort1(int elements, int *array) {
  for (int i = 1; i < elements; ++i) {
    for (int j = i; (j > 0) && (array[j - 1] > array[j]); --j) {
      int tmp = array[j - 1];
      array[j - 1] = array[j];
      array[j] = tmp;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <prime@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L27:
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L11
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D11
datatype: string

tool: D12: %d

tool: D11: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, *p, i;
  scanf("%d", &n);
  p = prime(n);
  for (i = 0; p[i] != 0; i++) {
    if (n % p[i] == 0)
      printf("%d ", p[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <prime@plt>
  mov    (%rax),%esi
  test   %esi,%esi
  je     L23
  lea    0x4(%rax),%rbx
  lea    D3(%rip),%rbp
  jmp    L28
L40:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  test   %esi,%esi
  je     L23
L28:
  mov    0x4(%rsp),%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L40
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L40
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D13: %d

tool: D3: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, *p, i;
  scanf("%d", &n);
  p = prime(n);
  for (i = 0; p[i] != 0; i++) {
    if (n % p[i] == 0)
      printf("%d ", p[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <prime@plt>
  mov    (%rax),%esi
  test   %esi,%esi
  je     L28
  lea    0x4(%rax),%rbx
  lea    D5(%rip),%rbp
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  test   %esi,%esi
  je     L28
L10:
  mov    0x4(%rsp),%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L31
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  test   %esi,%esi
  jne    L10
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string

tool: D16: %d

tool: D5: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, *p, i;
  scanf("%d", &n);
  p = prime(n);
  for (i = 0; p[i] != 0; i++) {
    if (n % p[i] == 0)
      printf("%d ", p[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <prime@plt>
  mov    (%rax),%esi
  test   %esi,%esi
  je     L17
  mov    0x4(%rsp),%ecx
  lea    0x4(%rax),%rbx
  lea    D13(%rip),%rbp
  nopl   0x0(%rax)
L23:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L9
  mov    (%rbx),%esi
  add    $0x4,%rbx
  test   %esi,%esi
  jne    L23
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  test   %esi,%esi
  je     L17
  mov    0x4(%rsp),%ecx
  jmp    L23
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D16: %d

tool: D13: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, *p, i;
  scanf("%d", &n);
  p = prime(n);
  for (i = 0; p[i] != 0; i++) {
    if (n % p[i] == 0)
      printf("%d ", p[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L0:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <ardser@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D1: -b 9600 -p /dev/ttyACM0 -r

tool: D18: datafrom serial: 

assistant: ```c
int main() {
  while (1) {
    char serd = ardser("-b 9600 -p /dev/ttyACM0 -r");
    printf("datafrom serial: ", serd);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D5(%rip),%rbp
  lea    D4(%rip),%rbx
L1:
  mov    %rbp,%rdi
  call   <ardser@plt>
  movsbl %al,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D4
data_type: string

tool: D5: -b 9600 -p /dev/ttyACM0 -r

tool: D4: datafrom serial: 

assistant: ```c
int main() {
  while (1) {
    char serd = ardser("-b 9600 -p /dev/ttyACM0 -r");
    printf("datafrom serial: ", serd);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  call   <ardser@plt>
  mov    %rbx,%rdi
  movsbl %al,%esi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D1: -b 9600 -p /dev/ttyACM0 -r

tool: D11: datafrom serial: 

assistant: ```c
int main() {
  while (1) {
    char serd = ardser("-b 9600 -p /dev/ttyACM0 -r");
    printf("datafrom serial: ", serd);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <ardser@plt>
  mov    %rbx,%rdi
  movsbl %al,%esi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D12: -b 9600 -p /dev/ttyACM0 -r

tool: D7: datafrom serial: 

assistant: ```c
int main() {
  while (1) {
    char serd = ardser("-b 9600 -p /dev/ttyACM0 -r");
    printf("datafrom serial: ", serd);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: string
name: retrieve_data
arguments: label: D48
datatype: string
name: retrieve_data
arguments: label: D36
datatype: string
name: retrieve_data
arguments: label: D43
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string

tool: D18: *************************


tool: D48: test program


tool: D36: second time commit


tool: D43: this is third commit


tool: D13: good


assistant: ```c
int main() {
  printf("*************************\n");
  printf("test program\n");
  printf("second time commit\n");
  printf("this is third commit\n");
  printf("good\n");
  printf("*************************\n");
  printf("*************************\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D41(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D41
data_type: string
name: disassemble_data
arguments: label: D42
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string

tool: D41: *************************


tool: D42: test program


tool: D18: second time commit


tool: D14: this is third commit


tool: D13: good


assistant: ```c
int main() {
  printf("*************************\n");
  printf("test program\n");
  printf("second time commit\n");
  printf("this is third commit\n");
  printf("good\n");
  printf("*************************\n");
  printf("*************************\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: tag: D47
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D43
type_guessed: string

tool: D49: *************************


tool: D47: test program


tool: D9: second time commit


tool: D17: this is third commit


tool: D43: good


assistant: ```c
int main() {
  printf("*************************\n");
  printf("test program\n");
  printf("second time commit\n");
  printf("this is third commit\n");
  printf("good\n");
  printf("*************************\n");
  printf("*************************\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D40
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D22: *************************


tool: D39: test program


tool: D23: second time commit


tool: D40: this is third commit


tool: D15: good


assistant: ```c
int main() {
  printf("*************************\n");
  printf("test program\n");
  printf("second time commit\n");
  printf("this is third commit\n");
  printf("good\n");
  printf("*************************\n");
  printf("*************************\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_236_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_236_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_236_1_0>:
  endbr64
  and    (%rdi),%dl
  or     %esi,%edx
  mov    %esi,%eax
  not    %eax
  and    %eax,%edx
  mov    %esi,%eax
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_236_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_236_1_0>:
  endbr64
  and    (%rdi),%dl
  mov    %esi,%eax
  not    %eax
  or     %esi,%edx
  and    %eax,%edx
  movzbl (%rdi),%eax
  and    %esi,%eax
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_236_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_236_1_0>:
  endbr64
  and    (%rdi),%dl
  mov    %esi,%eax
  not    %eax
  or     %esi,%edx
  and    %eax,%edx
  movzbl (%rdi),%eax
  and    %esi,%eax
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_236_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jump_next_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L37
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L44
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L37
L44:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
char *jump_next_line(char *ptr) {
  char *temp;
  if (!ptr)
    return NULL;
  for (temp = ptr; temp[0] != '\0'; temp++)
    if (temp[0] == '\n')
      return (temp + 1);
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jump_next_line>:
  endbr64
  test   %rdi,%rdi
  je     L34
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
L17:
  cmp    $0xa,%al
  je     L37
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L17
  mov    $0x0,%eax
  ret
L37:
  lea    0x1(%rdi),%rax
  ret
L34:
  mov    %rdi,%rax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *jump_next_line(char *ptr) {
  char *temp;
  if (!ptr)
    return NULL;
  for (temp = ptr; temp[0] != '\0'; temp++)
    if (temp[0] == '\n')
      return (temp + 1);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jump_next_line>:
  endbr64
  test   %rdi,%rdi
  jne    L30
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdi
  cmp    $0xa,%al
  je     L19
L30:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L8
L5:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *jump_next_line(char *ptr) {
  char *temp;
  if (!ptr)
    return NULL;
  for (temp = ptr; temp[0] != '\0'; temp++)
    if (temp[0] == '\n')
      return (temp + 1);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jump_next_line>:
  endbr64
  test   %rdi,%rdi
  jne    L22
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rdi
  cmp    $0xa,%al
  je     L9
L22:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
L28:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *jump_next_line(char *ptr) {
  char *temp;
  if (!ptr)
    return NULL;
  for (temp = ptr; temp[0] != '\0'; temp++)
    if (temp[0] == '\n')
      return (temp + 1);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  not    %rax
  and    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __clear_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % (8 * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / (8 * 8));
  *p &= ~mask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__clear_bit>:
  endbr64
  mov    %edi,%ecx
  lea    0x3f(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x6,%eax
  cltq
  mov    $0xfffffffffffffffe,%rdx
  rol    %cl,%rdx
  and    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void __clear_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % (8 * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / (8 * 8));
  *p &= ~mask;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__clear_bit>:
  endbr64
  test   %edi,%edi
  lea    0x3f(%rdi),%eax
  mov    %edi,%ecx
  mov    $0xfffffffffffffffe,%rdx
  cmovns %edi,%eax
  rol    %cl,%rdx
  sar    $0x6,%eax
  cltq
  and    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void __clear_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % (8 * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / (8 * 8));
  *p &= ~mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__clear_bit>:
  endbr64
  test   %edi,%edi
  lea    0x3f(%rdi),%eax
  mov    %edi,%ecx
  mov    $0xfffffffffffffffe,%rdx
  cmovns %edi,%eax
  rol    %cl,%rdx
  sar    $0x6,%eax
  cltq
  and    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void __clear_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % (8 * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / (8 * 8));
  *p &= ~mask;
}
```