ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pwrite_in_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L38
L26:
  mov    -0x28(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <xpwrite@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L43
  mov    $0xffffffffffffffff,%rax
  jmp    L31
L43:
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  jmp    L31
L4:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x38(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x28(%rbp)
L38:
  cmpq   $0x0,-0x38(%rbp)
  jne    L26
  mov    -0x10(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
ssize_t pwrite_in_full(int fd, const void *buf, size_t count, off_t offset) {
  const char *p = buf;
  ssize_t total = 0;
  while (count > 0) {
    ssize_t nr;
    nr = xpwrite(fd, p, count, offset);
    if (nr < 0)
      return -1;
    if (nr == 0) {
      errno = ENOSPC;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pwrite_in_full>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L17
  mov    %edi,%r14d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    $0x0,%r13d
L38:
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <xpwrite@plt>
  test   %rax,%rax
  js     L27
  je     L48
  add    %rax,%r13
  add    %rax,%rbp
  add    %eax,%r12d
  sub    %rax,%rbx
  jne    L38
  jmp    L58
L48:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%r13
  jmp    L58
L17:
  mov    $0x0,%r13d
  jmp    L58
L27:
  mov    $0xffffffffffffffff,%r13
L58:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
ssize_t pwrite_in_full(int fd, const void *buf, size_t count, off_t offset) {
  const char *p = buf;
  ssize_t total = 0;
  while (count > 0) {
    ssize_t nr;
    nr = xpwrite(fd, p, count, offset);
    if (nr < 0)
      return -1;
    if (nr == 0) {
      errno = ENOSPC;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pwrite_in_full>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L43
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  xor    %r13d,%r13d
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L34:
  je     L44
  add    %rax,%r13
  add    %rax,%rbp
  add    %eax,%r14d
  sub    %rax,%rbx
  je     L53
L28:
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xpwrite@plt>
  test   %rax,%rax
  jns    L34
  mov    $0xffffffffffffffff,%r13
L53:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L44:
  mov    D11(%rip),%rax
  mov    $0xffffffffffffffff,%r13
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  xor    %r13d,%r13d
  jmp    L53
```

assistant: ```c
ssize_t pwrite_in_full(int fd, const void *buf, size_t count, off_t offset) {
  const char *p = buf;
  ssize_t total = 0;
  while (count > 0) {
    ssize_t nr;
    nr = xpwrite(fd, p, count, offset);
    if (nr < 0)
      return -1;
    if (nr == 0) {
      errno = ENOSPC;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pwrite_in_full>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L54
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  xor    %r13d,%r13d
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L23:
  je     L20
  add    %rax,%r13
  add    %rax,%rbp
  add    %eax,%r14d
  sub    %rax,%rbx
  je     L14
L48:
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xpwrite@plt>
  test   %rax,%rax
  jns    L23
  mov    $0xffffffffffffffff,%r13
L14:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  mov    D0(%rip),%rax
  mov    $0xffffffffffffffff,%r13
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L54:
  xor    %r13d,%r13d
  jmp    L14
```

assistant: ```c
ssize_t pwrite_in_full(int fd, const void *buf, size_t count, off_t offset) {
  const char *p = buf;
  ssize_t total = 0;
  while (count > 0) {
    ssize_t nr;
    nr = xpwrite(fd, p, count, offset);
    if (nr < 0)
      return -1;
    if (nr == 0) {
      errno = ENOSPC;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<file_perms_parse_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L47
  mov    $0xffffffff,%eax
  jmp    L64
L47:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <is_empty_string@plt>
  test   %eax,%eax
  je     L1
  mov    $0xffffffff,%eax
  jmp    L64
L1:
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <is_empty_string@plt>
  test   %eax,%eax
  jne    L20
  mov    $0xffffffff,%eax
  jmp    L64
L20:
  andl   $0xfff,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
L64:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int file_perms_parse_mode(const unsigned char *mode) {
  char *eptr = 0;
  int m = 0;
  if (!mode)
    return -1;
  if (is_empty_string(mode))
    return -1;
  m = strtol(mode, &eptr, 8);
  if (!is_empty_string(eptr))
    return -1;
  m &= 07777;
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<file_perms_parse_mode>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbx
  call   <is_empty_string@plt>
  test   %eax,%eax
  jne    L10
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rdi
  mov    $0x0,%eax
  call   <is_empty_string@plt>
  test   %eax,%eax
  je     L24
  mov    %ebx,%eax
  and    $0xfff,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L2
L10:
  mov    $0xffffffff,%eax
  jmp    L2
L24:
  mov    $0xffffffff,%eax
  jmp    L2
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_perms_parse_mode(const unsigned char *mode) {
  char *eptr = 0;
  int m = 0;
  if (!mode)
    return -1;
  if (is_empty_string(mode))
    return -1;
  m = strtol(mode, &eptr, 8);
  if (!is_empty_string(eptr))
    return -1;
  m &= 07777;
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_perms_parse_mode>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L5
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <is_empty_string@plt>
  test   %eax,%eax
  jne    L5
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <is_empty_string@plt>
  test   %eax,%eax
  je     L5
  mov    %ebp,%eax
  and    $0xfff,%eax
L43:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  jmp    L43
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_perms_parse_mode(const unsigned char *mode) {
  char *eptr = 0;
  int m = 0;
  if (!mode)
    return -1;
  if (is_empty_string(mode))
    return -1;
  m = strtol(mode, &eptr, 8);
  if (!is_empty_string(eptr))
    return -1;
  m &= 07777;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<file_perms_parse_mode>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L48
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <is_empty_string@plt>
  test   %eax,%eax
  jne    L48
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <is_empty_string@plt>
  test   %eax,%eax
  je     L48
  mov    %ebp,%eax
  and    $0xfff,%eax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  mov    $0xffffffff,%eax
  jmp    L21
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_perms_parse_mode(const unsigned char *mode) {
  char *eptr = 0;
  int m = 0;
  if (!mode)
    return -1;
  if (is_empty_string(mode))
    return -1;
  m = strtol(mode, &eptr, 8);
  if (!is_empty_string(eptr))
    return -1;
  m &= 07777;
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getAck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <rx_timeout@plt>
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L10
  cmpl   $0x0,-0x14(%rbp)
  setg   %al
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L10:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int getAck(int *status, int timeout) {
  uint8_t mybuf[2];
  int rc = rx_timeout(mybuf, 1, timeout);
  if (status)
    *status = rc <= 0 ? 0 : 1;
  return *mybuf & 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getAck>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1,%esi
  call   <rx_timeout@plt>
  test   %rbx,%rbx
  je     L0
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,(%rbx)
L0:
  mov    (%rsp),%eax
  and    $0x1,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getAck(int *status, int timeout) {
  uint8_t mybuf[2];
  int rc = rx_timeout(mybuf, 1, timeout);
  if (status)
    *status = rc <= 0 ? 0 : 1;
  return *mybuf & 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getAck>:
  endbr64
  push   %rbx
  mov    %esi,%edx
  mov    %rdi,%rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <rx_timeout@plt>
  test   %rbx,%rbx
  je     L0
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,(%rbx)
L0:
  mov    (%rsp),%eax
  and    $0x1,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getAck(int *status, int timeout) {
  uint8_t mybuf[2];
  int rc = rx_timeout(mybuf, 1, timeout);
  if (status)
    *status = rc <= 0 ? 0 : 1;
  return *mybuf & 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getAck>:
  endbr64
  push   %rbx
  mov    %esi,%edx
  mov    %rdi,%rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <rx_timeout@plt>
  test   %rbx,%rbx
  je     L6
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,(%rbx)
L6:
  mov    (%rsp),%eax
  and    $0x1,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getAck(int *status, int timeout) {
  uint8_t mybuf[2];
  int rc = rx_timeout(mybuf, 1, timeout);
  if (status)
    *status = rc <= 0 ? 0 : 1;
  return *mybuf & 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cquat_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <cquat_norm@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void cquat_normalize(double *qdest, const double *qorg) {
  double norm = cquat_norm(qorg);
  qdest[0] = qorg[0] / norm;
  qdest[1] = qorg[1] / norm;
  qdest[2] = qorg[2] / norm;
  qdest[3] = qorg[3] / norm;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cquat_normalize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <cquat_norm@plt>
  movsd  (%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
  movsd  0x18(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cquat_normalize(double *qdest, const double *qorg) {
  double norm = cquat_norm(qorg);
  qdest[0] = qorg[0] / norm;
  qdest[1] = qorg[1] / norm;
  qdest[2] = qorg[2] / norm;
  qdest[3] = qorg[3] / norm;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cquat_normalize>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <cquat_norm@plt>
  movsd  (%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
  movsd  0x18(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cquat_normalize(double *qdest, const double *qorg) {
  double norm = cquat_norm(qorg);
  qdest[0] = qorg[0] / norm;
  qdest[1] = qorg[1] / norm;
  qdest[2] = qorg[2] / norm;
  qdest[3] = qorg[3] / norm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cquat_normalize>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <cquat_norm@plt>
  movsd  (%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
  movsd  0x18(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cquat_normalize(double *qdest, const double *qorg) {
  double norm = cquat_norm(qorg);
  qdest[0] = qorg[0] / norm;
  qdest[1] = qorg[1] / norm;
  qdest[2] = qorg[2] / norm;
  qdest[3] = qorg[3] / norm;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<logMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L22
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L22:
  cmpl   $0x0,-0xc4(%rbp)
  je     L4
  mov    -0xc4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L27
L4:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
L27:
  nop
  leave
  ret
```

assistant: ```c
void logMessage(int vb_mask, const char *format, ...) {
  va_list argList;
  if ((vb_mask == 0) || (vb_mask & 3)) {
    va_start(argList, format);
    vfprintf(stderr, format, argList);
    va_end(argList);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<logMessage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  test   %edi,%edi
  je     L12
  test   $0x3,%dil
  je     L10
L12:
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void logMessage(int vb_mask, const char *format, ...) {
  va_list argList;
  if ((vb_mask == 0) || (vb_mask & 3)) {
    va_start(argList, format);
    vfprintf(stderr, format, argList);
    va_end(argList);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<logMessage>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L13
  and    $0x3,%edi
  je     L2
L13:
  xor    %r12d,%r12d
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
L2:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void logMessage(int vb_mask, const char *format, ...) {
  va_list argList;
  if ((vb_mask == 0) || (vb_mask & 3)) {
    va_start(argList, format);
    vfprintf(stderr, format, argList);
    va_end(argList);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<logMessage>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L1
  and    $0x3,%edi
  je     L9
L1:
  xor    %r12d,%r12d
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void logMessage(int vb_mask, const char *format, ...) {
  va_list argList;
  if ((vb_mask == 0) || (vb_mask & 3)) {
    va_start(argList, format);
    vfprintf(stderr, format, argList);
    va_end(argList);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L15
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9: r

assistant: ```c
int file_exists(char *path) {
  FILE *Fp;
  Fp = fopen(path, "r");
  if (Fp == NULL)
    return 0;
  fclose(Fp);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_exists>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L5
  call   <fclose@plt>
  mov    $0x1,%eax
L5:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: r

assistant: ```c
int file_exists(char *path) {
  FILE *Fp;
  Fp = fopen(path, "r");
  if (Fp == NULL)
    return 0;
  fclose(Fp);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<file_exists>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  call   <fclose@plt>
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string

tool: D3: r

assistant: ```c
int file_exists(char *path) {
  FILE *Fp;
  Fp = fopen(path, "r");
  if (Fp == NULL)
    return 0;
  fclose(Fp);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_exists>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L9
  call   <fclose@plt>
  mov    $0x1,%eax
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: r

assistant: ```c
int file_exists(char *path) {
  FILE *Fp;
  Fp = fopen(path, "r");
  if (Fp == NULL)
    return 0;
  fclose(Fp);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_refine_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L48
L17:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L62
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L33
L62:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L52
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L53
L52:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L82
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L82
L53:
  addq   $0x1,-0x10(%rbp)
L82:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L35
L33:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L35:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L48:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int str_refine_buffer(char *buf) {
  char *src = buf, *dest = buf;
  while (*src) {
    if (*src == 0x0A || *src == 0x0D) {
      if ((*src == 0x0D && *(src + 1) == 0x0A) || (*src == 0x0A && *(src + 1) == 0x0D))
        src++;
      *dest = '\0';
    } else
      *dest = *src;
    src++;
    dest++;
  }
  *dest = '\0';
  return dest - buf + 1;
}
```