ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rdi
  lea    0x17(,%rdi,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L35:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L38:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L16
  orq    $0x0,-0x8(%rsp,%rax,1)
L16:
  lea    0xf(%rsp),%rdi
  and    $0xfffffffffffffff0,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  leave
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int a) {
  int var[a] __attribute__((__aligned__(16)));
  bar(var);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x17(,%rdi,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L33
L35:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L35
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L48:
  lea    0xf(%rsp),%rdi
  and    $0xfffffffffffffff0,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  leave
  ret
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int a) {
  int var[a] __attribute__((__aligned__(16)));
  bar(var);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x17(,%rdi,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L27
L19:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L19
L27:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L7
L3:
  lea    0xf(%rsp),%rdi
  and    $0xfffffffffffffff0,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  leave
  ret
L7:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L3
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int a) {
  int var[a] __attribute__((__aligned__(16)));
  bar(var);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printDecimalAsBinary@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x13,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string

tool: D26: Decimal	Binary	Octal	Hex

tool: D0: %d	

tool: D16: 	%o	%X


assistant: ```c
int main() {
  int i;
  printf("Decimal\tBinary\tOctal\tHex\n");
  for (i = 0; i < 20; i++) {
    printf("%d\t", i);
    printDecimalAsBinary(i);
    printf("\t%o\t%X\n", i, i);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D29(%rip),%r12
  lea    D28(%rip),%rbp
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <printDecimalAsBinary@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L5
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D29
type_guessed: string
name: retrieve_data
arguments: tag: D28
type_guessed: string

tool: D19: Decimal	Binary	Octal	Hex

tool: D29: %d	

tool: D28: 	%o	%X


assistant: ```c
int main() {
  int i;
  printf("Decimal\tBinary\tOctal\tHex\n");
  for (i = 0; i < 20; i++) {
    printf("%d\t", i);
    printDecimalAsBinary(i);
    printf("\t%o\t%X\n", i, i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  lea    D21(%rip),%r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
  nopl   0x0(%rax)
L0:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <printDecimalAsBinary@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x14,%ebx
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string

tool: D10: Decimal	Binary	Octal	Hex

tool: D21: %d	

tool: D25: 	%o	%X


assistant: ```c
int main() {
  int i;
  printf("Decimal\tBinary\tOctal\tHex\n");
  for (i = 0; i < 20; i++) {
    printf("%d\t", i);
    printDecimalAsBinary(i);
    printf("\t%o\t%X\n", i, i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  lea    D2(%rip),%r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
  nopl   0x0(%rax)
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <printDecimalAsBinary@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x14,%ebx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
type: string
name: read_data
arguments: data_label: D2
type: string
name: read_data
arguments: data_label: D25
type: string

tool: D13: Decimal	Binary	Octal	Hex

tool: D2: %d	

tool: D25: 	%o	%X


assistant: ```c
int main() {
  int i;
  printf("Decimal\tBinary\tOctal\tHex\n");
  for (i = 0; i < 20; i++) {
    printf("%d\t", i);
    printDecimalAsBinary(i);
    printf("\t%o\t%X\n", i, i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x5,-0x4(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %i


assistant: ```c
void display(int *inputs) {
  int i;
  for (i = 0; i < 6; i++) {
    printf("%i\n", *(inputs + i));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<display>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x18(%rdi),%r12
  lea    D7(%rip),%rbp
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: %i


assistant: ```c
void display(int *inputs) {
  int i;
  for (i = 0; i < 6; i++) {
    printf("%i\n", *(inputs + i));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<display>:
  endbr64
  push   %r12
  lea    0x18(%rdi),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: %i


assistant: ```c
void display(int *inputs) {
  int i;
  for (i = 0; i < 6; i++) {
    printf("%i\n", *(inputs + i));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<display>:
  endbr64
  push   %r12
  lea    0x18(%rdi),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: %i


assistant: ```c
void display(int *inputs) {
  int i;
  for (i = 0; i < 6; i++) {
    printf("%i\n", *(inputs + i));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cm_today>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jne    L12
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x76c(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,8),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <add_word_args@plt>
L12:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string

tool: D13: %d %s %d

assistant: ```c
void cm_today(int arg) {
  static char *months[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  if (arg == 0) {
    time_t timer = time(0);
    struct tm *ts = localtime(&timer);
    add_word_args("%d %s %d", ts->tm_mday, months[ts->tm_mon], ts->tm_year + 1900);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cm_today>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L20
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L20:
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    0x8(%rax),%rcx
  add    $0x76c,%rcx
  mov    (%rax),%rsi
  lea    D10(%rip),%rdx
  mov    (%rdx,%rsi,8),%rdx
  mov    0x10(%rax),%esi
  lea    D15(%rip),%rdi
  call   <add_word_args@plt>
  jmp    L3
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D15: %d %s %d

assistant: ```c
void cm_today(int arg) {
  static char *months[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  if (arg == 0) {
    time_t timer = time(0);
    struct tm *ts = localtime(&timer);
    add_word_args("%d %s %d", ts->tm_mday, months[ts->tm_mon], ts->tm_year + 1900);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cm_today>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L10
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L10:
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D14(%rip),%rdx
  lea    D1(%rip),%rdi
  mov    (%rax),%rsi
  mov    0x8(%rax),%rcx
  mov    (%rdx,%rsi,8),%rdx
  mov    0x10(%rax),%esi
  add    $0x76c,%rcx
  call   <add_word_args@plt>
  jmp    L13
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %d %s %d

assistant: ```c
void cm_today(int arg) {
  static char *months[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  if (arg == 0) {
    time_t timer = time(0);
    struct tm *ts = localtime(&timer);
    add_word_args("%d %s %d", ts->tm_mday, months[ts->tm_mon], ts->tm_year + 1900);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cm_today>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L4:
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D16(%rip),%rdx
  lea    D11(%rip),%rdi
  mov    (%rax),%rsi
  mov    0x8(%rax),%rcx
  mov    (%rdx,%rsi,8),%rdx
  mov    0x10(%rax),%esi
  add    $0x76c,%rcx
  call   <add_word_args@plt>
  jmp    L24
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
datatype: string

tool: D11: %d %s %d

assistant: ```c
void cm_today(int arg) {
  static char *months[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  if (arg == 0) {
    time_t timer = time(0);
    struct tm *ts = localtime(&timer);
    add_word_args("%d %s %d", ts->tm_mday, months[ts->tm_mon], ts->tm_year + 1900);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<util_cpu_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getrusage@plt>
  mov    -0x18(%rbp),%rax
  imul   $0x3e8,%rax,%rcx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
long util_cpu_time(void) {
  long t = 0;
  struct rusage rusage;
  (void)getrusage(RUSAGE_SELF, &rusage);
  t = (long)rusage.ru_utime.tv_sec * 1000 + rusage.ru_utime.tv_usec / 1000;
  return t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<util_cpu_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <getrusage@plt>
  imul   $0x3e8,0x8(%rsp),%rax
  mov    (%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long util_cpu_time(void) {
  long t = 0;
  struct rusage rusage;
  (void)getrusage(RUSAGE_SELF, &rusage);
  t = (long)rusage.ru_utime.tv_sec * 1000 + rusage.ru_utime.tv_usec / 1000;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_cpu_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <getrusage@plt>
  movslq (%rsp),%rdx
  imul   $0x3e8,0x8(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long util_cpu_time(void) {
  long t = 0;
  struct rusage rusage;
  (void)getrusage(RUSAGE_SELF, &rusage);
  t = (long)rusage.ru_utime.tv_sec * 1000 + rusage.ru_utime.tv_usec / 1000;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_cpu_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <getrusage@plt>
  movslq (%rsp),%rdx
  imul   $0x3e8,0x8(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long util_cpu_time(void) {
  long t = 0;
  struct rusage rusage;
  (void)getrusage(RUSAGE_SELF, &rusage);
  t = (long)rusage.ru_utime.tv_sec * 1000 + rusage.ru_utime.tv_usec / 1000;
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<vlr_igual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L34
  addl   $0x1,-0xc(%rbp)
L34:
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x4,-0x4(%rbp)
  jle    L29
  addl   $0x1,-0x8(%rbp)
L4:
  cmpl   $0xe,-0x8(%rbp)
  jle    L11
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int vlr_igual(int vet[][5], int num) {
  int vzs = 0;
  for (int i = 0; i < 15; i++) {
    for (int j = 0; j < 5; j++) {
      if (vet[i][j] == num) {
        vzs++;
      }
    }
  }
  return vzs;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vlr_igual>:
  endbr64
  lea    0x14(%rdi),%r8
  add    $0x140,%rdi
  mov    $0x0,%edx
  jmp    L9
L22:
  add    $0x14,%r8
  cmp    %rdi,%r8
  je     L31
L9:
  lea    -0x14(%r8),%rax
L11:
  cmp    %esi,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L11
  jmp    L22
L31:
  mov    %edx,%eax
  ret
```

assistant: ```c
int vlr_igual(int vet[][5], int num) {
  int vzs = 0;
  for (int i = 0; i < 15; i++) {
    for (int j = 0; j < 5; j++) {
      if (vet[i][j] == num) {
        vzs++;
      }
    }
  }
  return vzs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vlr_igual>:
  endbr64
  lea    0x14(%rdi),%rcx
  xor    %r8d,%r8d
  add    $0x140,%rdi
  nopw   0x0(%rax,%rax,1)
L18:
  lea    -0x14(%rcx),%rax
L11:
  xor    %edx,%edx
  cmp    %esi,(%rax)
  sete   %dl
  add    $0x4,%rax
  add    %edx,%r8d
  cmp    %rcx,%rax
  jne    L11
  lea    0x14(%rax),%rcx
  cmp    %rdi,%rcx
  jne    L18
  mov    %r8d,%eax
  ret
```

assistant: ```c
int vlr_igual(int vet[][5], int num) {
  int vzs = 0;
  for (int i = 0; i < 15; i++) {
    for (int j = 0; j < 5; j++) {
      if (vet[i][j] == num) {
        vzs++;
      }
    }
  }
  return vzs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vlr_igual>:
  endbr64
  lea    0x12c(%rdi),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L2:
  xor    %edx,%edx
  cmp    (%rdi),%esi
  sete   %dl
  add    %edx,%eax
  xor    %edx,%edx
  cmp    0x4(%rdi),%esi
  sete   %dl
  add    %edx,%eax
  xor    %edx,%edx
  cmp    0x8(%rdi),%esi
  sete   %dl
  add    %edx,%eax
  xor    %edx,%edx
  cmp    0xc(%rdi),%esi
  sete   %dl
  add    %edx,%eax
  xor    %edx,%edx
  cmp    0x10(%rdi),%esi
  sete   %dl
  add    $0x14,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L2
  ret
```

assistant: ```c
int vlr_igual(int vet[][5], int num) {
  int vzs = 0;
  for (int i = 0; i < 15; i++) {
    for (int j = 0; j < 5; j++) {
      if (vet[i][j] == num) {
        vzs++;
      }
    }
  }
  return vzs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clipt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L92
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L102
  movl   $0x0,-0xc(%rbp)
  jmp    L68
L102:
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L68
  mov    -0x28(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L68
L92:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L105
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L81
  movl   $0x0,-0xc(%rbp)
  jmp    L68
L81:
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L68
  mov    -0x30(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L68
L105:
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L68
  movl   $0x0,-0xc(%rbp)
L68:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
clipt(p, q, t0, t1) double p, q, *t0, *t1;
{
  double r;
  int accept = !0;
  if (p < 0.0) {
    r = q / p;
    if (r > *t1)
      accept = 0;
    else if (r > *t0)
      *t0 = r;
  } else if (p > 0.0) {
    r = q / p;
    if (r < *t0)
      accept = 0;
    else if (r < *t1)
      *t1 = r;
  } else if (q < 0.0)
    accept = 0;
  return (accept);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clipt>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  ja     L48
  comisd D7(%rip),%xmm0
  jbe    L21
  divsd  %xmm0,%xmm1
  movsd  (%rdi),%xmm0
  mov    $0x0,%eax
  comisd %xmm1,%xmm0
  ja     L33
  movsd  (%rsi),%xmm0
  comisd %xmm1,%xmm0
  jbe    L38
  movsd  %xmm1,(%rsi)
  mov    $0x1,%eax
  ret
L48:
  divsd  %xmm0,%xmm1
  mov    $0x0,%eax
  comisd (%rsi),%xmm1
  ja     L33
  comisd (%rdi),%xmm1
  jbe    L29
  movsd  %xmm1,(%rdi)
  mov    $0x1,%eax
  ret
L21:
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  setbe  %al
  movzbl %al,%eax
  ret
L29:
  mov    $0x1,%eax
  ret
L38:
  mov    $0x1,%eax
L33:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: f64

tool: D7: 0

assistant: ```c
clipt(p, q, t0, t1) double p, q, *t0, *t1;
{
  double r;
  int accept = !0;
  if (p < 0.0) {
    r = q / p;
    if (r > *t1)
      accept = 0;
    else if (r > *t0)
      *t0 = r;
  } else if (p > 0.0) {
    r = q / p;
    if (r < *t0)
      accept = 0;
    else if (r < *t1)
      *t1 = r;
  } else if (q < 0.0)
    accept = 0;
  return (accept);
}
```