ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<emit_set_nz32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L8
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_movs@plt>
  jmp    L0
L8:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_test@plt>
L0:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <emit_cmovne_imm@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_set_nz32(int rs, int rt) {
  if (rs != rt)
    emit_movs(rs, rt);
  else
    emit_test(rs, rs);
  emit_cmovne_imm(1, rt);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<emit_set_nz32>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    %esi,%edi
  je     L9
  call   <emit_movs@plt>
L4:
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <emit_cmovne_imm@plt>
  pop    %rbx
  ret
L9:
  mov    %edi,%esi
  call   <emit_test@plt>
  jmp    L4
```

assistant: ```c
void emit_set_nz32(int rs, int rt) {
  if (rs != rt)
    emit_movs(rs, rt);
  else
    emit_test(rs, rs);
  emit_cmovne_imm(1, rt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<emit_set_nz32>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  cmp    %esi,%edi
  je     L7
  call   <emit_movs@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <emit_cmovne_imm@plt>
  nopl   (%rax)
L7:
  mov    %esi,%edi
  call   <emit_test@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <emit_cmovne_imm@plt>
```

assistant: ```c
void emit_set_nz32(int rs, int rt) {
  if (rs != rt)
    emit_movs(rs, rt);
  else
    emit_test(rs, rs);
  emit_cmovne_imm(1, rt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_set_nz32>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  cmp    %esi,%edi
  je     L7
  call   <emit_movs@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <emit_cmovne_imm@plt>
  nopl   (%rax)
L7:
  mov    %esi,%edi
  call   <emit_test@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <emit_cmovne_imm@plt>
```

assistant: ```c
void emit_set_nz32(int rs, int rt) {
  if (rs != rt)
    emit_movs(rs, rt);
  else
    emit_test(rs, rs);
  emit_cmovne_imm(1, rt);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Respond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r9d
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x8,%edx
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  je     L1
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <Log@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: WARNING: Error sending response packet


assistant: ```c
void Respond(int s, const struct sockaddr_in *dest, socklen_t salen, struct NetworkPacket *pkt) {
  ssize_t n;
  n = sendto(s, pkt, sizeof(pkt), 0, (const struct sockaddr *)dest, salen);
  if (n != sizeof(pkt)) {
    Log("WARNING: Error sending response packet\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Respond>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%r8
  mov    %edx,%r9d
  mov    %rcx,%rsi
  mov    $0x0,%ecx
  mov    $0x8,%edx
  call   <sendto@plt>
  cmp    $0x8,%eax
  jne    L7
L17:
  add    $0x8,%rsp
  ret
L7:
  lea    D1(%rip),%rdi
  call   <Log@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: WARNING: Error sending response packet


assistant: ```c
void Respond(int s, const struct sockaddr_in *dest, socklen_t salen, struct NetworkPacket *pkt) {
  ssize_t n;
  n = sendto(s, pkt, sizeof(pkt), 0, (const struct sockaddr *)dest, salen);
  if (n != sizeof(pkt)) {
    Log("WARNING: Error sending response packet\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Respond>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%r8
  mov    %edx,%r9d
  mov    %rcx,%rsi
  mov    $0x8,%edx
  xor    %ecx,%ecx
  call   <sendto@plt>
  cmp    $0x8,%eax
  jne    L7
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Log@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: WARNING: Error sending response packet


assistant: ```c
void Respond(int s, const struct sockaddr_in *dest, socklen_t salen, struct NetworkPacket *pkt) {
  ssize_t n;
  n = sendto(s, pkt, sizeof(pkt), 0, (const struct sockaddr *)dest, salen);
  if (n != sizeof(pkt)) {
    Log("WARNING: Error sending response packet\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Respond>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%r8
  mov    %edx,%r9d
  mov    %rcx,%rsi
  mov    $0x8,%edx
  xor    %ecx,%ecx
  call   <sendto@plt>
  cmp    $0x8,%eax
  jne    L4
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Log@plt>
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: WARNING: Error sending response packet


assistant: ```c
void Respond(int s, const struct sockaddr_in *dest, socklen_t salen, struct NetworkPacket *pkt) {
  ssize_t n;
  n = sendto(s, pkt, sizeof(pkt), 0, (const struct sockaddr *)dest, salen);
  if (n != sizeof(pkt)) {
    Log("WARNING: Error sending response packet\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<truncate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  comiss D6(%rip),%xmm0
  jbe    L9
  mov    $0xffffffff,%eax
  jmp    L23
L9:
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L39
  mov    $0x0,%eax
  jmp    L23
L39:
  cvttss2si -0x4(%rbp),%eax
L23:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: f32

tool: D6: 255

assistant: ```c
unsigned char truncate(float f) {
  if (f > 255.0)
    return 255;
  else if (f < 0)
    return 0;
  else
    return (unsigned char)(f / 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<truncate>:
  endbr64
  mov    $0xffffffff,%eax
  comiss D2(%rip),%xmm0
  ja     L7
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L7
  cvttss2si %xmm0,%eax
L7:
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: f32

tool: D2: 255

assistant: ```c
unsigned char truncate(float f) {
  if (f > 255.0)
    return 255;
  else if (f < 0)
    return 0;
  else
    return (unsigned char)(f / 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<truncate>:
  endbr64
  comiss D9(%rip),%xmm0
  mov    $0xffffffff,%eax
  ja     L8
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  ja     L8
  cvttss2si %xmm0,%eax
L8:
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: f32

tool: D9: 255

assistant: ```c
unsigned char truncate(float f) {
  if (f > 255.0)
    return 255;
  else if (f < 0)
    return 0;
  else
    return (unsigned char)(f / 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<truncate>:
  endbr64
  comiss D8(%rip),%xmm0
  mov    $0xffffffff,%eax
  ja     L10
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  ja     L10
  cvttss2si %xmm0,%eax
L10:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: f32

tool: D8: 255

assistant: ```c
unsigned char truncate(float f) {
  if (f > 255.0)
    return 255;
  else if (f < 0)
    return 0;
  else
    return (unsigned char)(f / 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mhandle_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    $0x0,%eax
  call   <mhandle_init@plt>
  mov    -0x28(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L0
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <mhandle_out_of_memory@plt>
L0:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mhandle_mark_corrupt@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <mhandle_hash_table_insert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mhandle_calloc(unsigned long nmemb, unsigned long size, char *at) {
  void *ptr;
  void *eff_ptr;
  unsigned long total;
  unsigned long eff_total;
  mhandle_init();
  total = nmemb * size;
  eff_total = total + (2 * 2);
  eff_ptr = calloc(1, eff_total);
  if (!eff_ptr)
    mhandle_out_of_memory(at);
  ptr = eff_ptr + 2;
  mhandle_mark_corrupt(eff_ptr, eff_total);
  mhandle_hash_table_insert(ptr, total, at, 1);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mhandle_calloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <mhandle_init@plt>
  imul   %rbp,%rbx
  lea    0x4(%rbx),%r14
  mov    %r14,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L14
L8:
  lea    0x2(%rbp),%r13
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <mhandle_mark_corrupt@plt>
  mov    $0x1,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <mhandle_hash_table_insert@plt>
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    %r12,%rdi
  call   <mhandle_out_of_memory@plt>
  jmp    L8
```

assistant: ```c
void *mhandle_calloc(unsigned long nmemb, unsigned long size, char *at) {
  void *ptr;
  void *eff_ptr;
  unsigned long total;
  unsigned long eff_total;
  mhandle_init();
  total = nmemb * size;
  eff_total = total + (2 * 2);
  eff_ptr = calloc(1, eff_total);
  if (!eff_ptr)
    mhandle_out_of_memory(at);
  ptr = eff_ptr + 2;
  mhandle_mark_corrupt(eff_ptr, eff_total);
  mhandle_hash_table_insert(ptr, total, at, 1);
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<mhandle_calloc>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  imul   %r12,%rbp
  call   <mhandle_init@plt>
  mov    $0x1,%edi
  lea    0x4(%rbp),%r15
  mov    %r15,%rsi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L0:
  lea    0x2(%r12),%r14
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <mhandle_mark_corrupt@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x1,%ecx
  call   <mhandle_hash_table_insert@plt>
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r13,%rdi
  call   <mhandle_out_of_memory@plt>
  jmp    L0
```

assistant: ```c
void *mhandle_calloc(unsigned long nmemb, unsigned long size, char *at) {
  void *ptr;
  void *eff_ptr;
  unsigned long total;
  unsigned long eff_total;
  mhandle_init();
  total = nmemb * size;
  eff_total = total + (2 * 2);
  eff_ptr = calloc(1, eff_total);
  if (!eff_ptr)
    mhandle_out_of_memory(at);
  ptr = eff_ptr + 2;
  mhandle_mark_corrupt(eff_ptr, eff_total);
  mhandle_hash_table_insert(ptr, total, at, 1);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mhandle_calloc>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  imul   %r12,%rbp
  call   <mhandle_init@plt>
  mov    $0x1,%edi
  lea    0x4(%rbp),%r15
  mov    %r15,%rsi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L10:
  lea    0x2(%r12),%r14
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <mhandle_mark_corrupt@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x1,%ecx
  call   <mhandle_hash_table_insert@plt>
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r13,%rdi
  call   <mhandle_out_of_memory@plt>
  jmp    L10
```

assistant: ```c
void *mhandle_calloc(unsigned long nmemb, unsigned long size, char *at) {
  void *ptr;
  void *eff_ptr;
  unsigned long total;
  unsigned long eff_total;
  mhandle_init();
  total = nmemb * size;
  eff_total = total + (2 * 2);
  eff_ptr = calloc(1, eff_total);
  if (!eff_ptr)
    mhandle_out_of_memory(at);
  ptr = eff_ptr + 2;
  mhandle_mark_corrupt(eff_ptr, eff_total);
  mhandle_hash_table_insert(ptr, total, at, 1);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shellsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L10
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L51
L35:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L40
L57:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x10(%rbp)
L40:
  cmpl   $0x0,-0x10(%rbp)
  js     L3
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L57
L3:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L35
  subl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x0,-0xc(%rbp)
  jns    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shellsort(int a[], int n, int inc, int incarray[]) {
  int i, j, val, k, span;
  for (k = inc - 1; k >= 0; k--) {
    span = incarray[k];
    for (i = span; i < n; i++) {
      val = a[i];
      for (j = i - span; j >= 0 && val < a[j]; j = j - span) {
        a[j + span] = a[j];
      }
      a[j + span] = val;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shellsort>:
  endbr64
  sub    $0x1,%edx
  js     L65
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebp
  mov    %rcx,%r13
  movslq %edx,%r12
  jmp    L10
L14:
  add    %ecx,%edx
  movslq %edx,%rdx
  mov    %esi,(%r11,%rdx,4)
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %ebx,%r9d
  je     L11
L80:
  mov    (%r10,%rdi,4),%esi
  mov    %r9d,%edx
  mov    %r10,%rax
  test   %r9d,%r9d
  js     L14
L29:
  mov    (%rax),%r14d
  cmp    %esi,%r14d
  jle    L14
  mov    %r14d,(%rax,%rdi,4)
  add    %r8,%rax
  sub    %ecx,%edx
  jns    L29
  jmp    L14
L11:
  sub    $0x1,%r12
  test   %r12d,%r12d
  js     L17
L10:
  mov    0x0(%r13,%r12,4),%ecx
  cmp    %ebp,%ecx
  jge    L11
  mov    %r11,%r10
  mov    %ebp,%ebx
  sub    %ecx,%ebx
  mov    %ecx,%r8d
  neg    %r8d
  movslq %r8d,%r8
  shl    $0x2,%r8
  mov    $0x0,%r9d
  movslq %ecx,%rdi
  jmp    L80
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  ret
```

assistant: ```c
void shellsort(int a[], int n, int inc, int incarray[]) {
  int i, j, val, k, span;
  for (k = inc - 1; k >= 0; k--) {
    span = incarray[k];
    for (i = span; i < n; i++) {
      val = a[i];
      for (j = i - span; j >= 0 && val < a[j]; j = j - span) {
        a[j + span] = a[j];
      }
      a[j + span] = val;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shellsort>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %eax,%eax
  js     L0
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  movslq %eax,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   (%rax)
L32:
  mov    (%r14,%r13,4),%r8d
  cmp    %r12d,%r8d
  jge    L65
  movslq %r8d,%rdi
  mov    %r12d,%r15d
  xor    %ebx,%ebx
  shl    $0x2,%rdi
  sub    %r8d,%r15d
  lea    0x0(%rbp,%rdi,1),%r11
  nopl   (%rax)
L20:
  mov    %r11,%rax
  mov    (%r11),%r9d
  mov    %ebx,%ecx
  mov    %r11,%rdx
  sub    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L61:
  mov    (%rax),%esi
  mov    %rax,%r10
  cmp    %r9d,%esi
  jle    L57
  mov    %esi,(%rdx)
  sub    %rdi,%rax
  sub    %rdi,%rdx
  sub    %r8d,%ecx
  jns    L61
  add    $0x1,%ebx
  mov    %r9d,(%r10)
  add    $0x4,%r11
  cmp    %r15d,%ebx
  jne    L20
L65:
  sub    $0x1,%r13
  test   %r13d,%r13d
  jns    L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %rdx,%r10
  add    $0x1,%ebx
  add    $0x4,%r11
  mov    %r9d,(%r10)
  cmp    %r15d,%ebx
  jne    L20
  jmp    L65
L0:
  ret
```

assistant: ```c
void shellsort(int a[], int n, int inc, int incarray[]) {
  int i, j, val, k, span;
  for (k = inc - 1; k >= 0; k--) {
    span = incarray[k];
    for (i = span; i < n; i++) {
      val = a[i];
      for (j = i - span; j >= 0 && val < a[j]; j = j - span) {
        a[j + span] = a[j];
      }
      a[j + span] = val;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shellsort>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %eax,%eax
  js     L11
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  movslq %eax,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   (%rax)
L54:
  mov    (%r14,%r13,4),%r8d
  cmp    %r12d,%r8d
  jge    L37
  movslq %r8d,%rdi
  mov    %r12d,%r15d
  xor    %ebx,%ebx
  shl    $0x2,%rdi
  sub    %r8d,%r15d
  lea    0x0(%rbp,%rdi,1),%r11
  nopl   (%rax)
L15:
  mov    %r11,%rax
  mov    (%r11),%r9d
  mov    %ebx,%ecx
  mov    %r11,%rdx
  sub    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    (%rax),%esi
  mov    %rax,%r10
  cmp    %r9d,%esi
  jle    L23
  mov    %esi,(%rdx)
  sub    %rdi,%rax
  sub    %rdi,%rdx
  sub    %r8d,%ecx
  jns    L0
  add    $0x1,%ebx
  mov    %r9d,(%r10)
  add    $0x4,%r11
  cmp    %ebx,%r15d
  jne    L15
L37:
  sub    $0x1,%r13
  test   %r13d,%r13d
  jns    L54
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rdx,%r10
  add    $0x1,%ebx
  add    $0x4,%r11
  mov    %r9d,(%r10)
  cmp    %ebx,%r15d
  jne    L15
  jmp    L37
L11:
  ret
```

assistant: ```c
void shellsort(int a[], int n, int inc, int incarray[]) {
  int i, j, val, k, span;
  for (k = inc - 1; k >= 0; k--) {
    span = incarray[k];
    for (i = span; i < n; i++) {
      val = a[i];
      for (j = i - span; j >= 0 && val < a[j]; j = j - span) {
        a[j + span] = a[j];
      }
      a[j + span] = val;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<op_0xc9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  mov    $0x4,%edi
  call   <RET@plt>
  mov    $0xa,%edi
  call   <T_WAIT_UNTIL@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op_0xc9(void) {
  RET(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<op_0xc9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x4,%edi
  call   <RET@plt>
  mov    $0xa,%edi
  call   <T_WAIT_UNTIL@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op_0xc9(void) {
  RET(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<op_0xc9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x7,%esi
  call   <RET@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_0xc9(void) {
  RET(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<op_0xc9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x7,%esi
  call   <RET@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_0xc9(void) {
  RET(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<large_alignment_untagging>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  and    $0xffffffffffffffe0,%rsp
  sub    $0x360,%rsp
  mov    %edi,0x1c(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rcx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x358(%rsp)
  xor    %eax,%eax
  mov    0x1c(%rsp),%eax
  cltq
  mov    0x1c0(%rsp,%rax,4),%edx
  mov    0x1c(%rsp),%eax
  cltq
  mov    0x20(%rsp,%rax,4),%eax
  add    %eax,%edx
  mov    0x10(%rsp),%rax
  mov    %edx,(%rax)
  lea    0x1c0(%rsp),%rax
  mov    %rax,%rdi
  call   <Ident@plt>
  mov    %rax,%rdx
  mov    0x8(%rsp),%rax
  mov    %rdx,(%rax)
  lea    0x20(%rsp),%rax
  mov    %rax,%rdi
  call   <Ident@plt>
  mov    %rax,%rdx
  mov    (%rsp),%rax
  mov    %rdx,(%rax)
  nop
  mov    0x358(%rsp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void __attribute__((no)) large_alignment_untagging(int num, int *retval, int **big, int **other) {
  int other_array[100] __attribute__((aligned(32)));
  int big_array[100] __attribute__((aligned(32)));
  *retval = big_array[num] + other_array[num];
  *big = (int *)Ident(big_array);
  *other = (int *)Ident(other_array);
}
```
user: What is the c source code of the assembly code below?

```asm
<large_alignment_untagging>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  and    $0xffffffffffffffe0,%rsp
  sub    $0x340,%rsp
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  add    0x1a0(%rsp,%rdi,4),%eax
  mov    %eax,(%rsi)
  lea    0x1a0(%rsp),%rdi
  call   <Ident@plt>
  mov    %rax,(%r12)
  mov    %rsp,%rdi
  call   <Ident@plt>
  mov    %rax,(%rbx)
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) large_alignment_untagging(int num, int *retval, int **big, int **other) {
  int other_array[100] __attribute__((aligned(32)));
  int big_array[100] __attribute__((aligned(32)));
  *retval = big_array[num] + other_array[num];
  *big = (int *)Ident(big_array);
  *other = (int *)Ident(other_array);
}
```