ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r14d,%ebx
  mov    %r14d,%r13d
  imul   %r12,%rbx
  sar    %r13d
  lea    0x1(%r13),%eax
  shr    $0x21,%rbx
  add    $0x1,%ebx
  test   $0x1,%r14b
  cmovne %eax,%r13d
  cmp    %ebx,%r13d
  jle    L17
  nopl   (%rax)
L14:
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <gcd@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  cmp    %ebx,%r13d
  jne    L14
L17:
  add    $0x1,%r14d
  cmp    $0x2ee1,%r14d
  jne    L5
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main() {
  int count = 0;
  for (int d = 2; d <= 12000; d++) {
    for (int n = d / 3 + 1; n < (d % 2 == 0 ? d / 2 : d / 2 + 1); n++) {
      if (gcd(d, n) == 1) {
        count++;
      }
    }
  }
  printf("%d\n", count);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1c0(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b0(%rbp)
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x1a8(%rbp)
  lea    -0x1a0(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  lea    -0x1a0(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1b8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1b0(%rbp),%rax
  mov    %rax,%rdi
  call   <free_anything@plt>
  mov    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  free(use_after_free);
  free_anything(never_free);
  free(free_twice);
  free(array2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rsp,%r14
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free_anything@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  free(use_after_free);
  free_anything(never_free);
  free(free_twice);
  free(array2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free_anything@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  free(use_after_free);
  free_anything(never_free);
  free(free_twice);
  free(array2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_leading_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L7
L15:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  mov    -0x8(%rbp),%rax
L7:
  leave
  ret
```

assistant: ```c
char *remove_leading_spaces(char *value) {
  if (value == NULL) {
    return NULL;
  }
  for (; isspace(*value); value++)
    ;
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_leading_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L25
  jmp    L12
L23:
  add    $0x1,%rbx
L25:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L23
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *remove_leading_spaces(char *value) {
  if (value == NULL) {
    return NULL;
  }
  for (; isspace(*value); value++)
    ;
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<remove_leading_spaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L23
  jmp    L12
L27:
  add    $0x1,%r12
L23:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
L12:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *remove_leading_spaces(char *value) {
  if (value == NULL) {
    return NULL;
  }
  for (; isspace(*value); value++)
    ;
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<remove_leading_spaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L27
  jmp    L26
L7:
  add    $0x1,%r12
L27:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
L26:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *remove_leading_spaces(char *value) {
  if (value == NULL) {
    return NULL;
  }
  for (; isspace(*value); value++)
    ;
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x89abcdef,-0xc(%rbp)
  movl   $0x76543210,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    $0x0,%al
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: The result is: %x


assistant: ```c
int main() {
  int x = 0x89ABCDEF;
  int y = 0x76543210;
  int result = (x & 0xFF) | (y ^ (y & 0xFF));
  printf("The result is: %x\n", result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x765432ef,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: The result is: %x


assistant: ```c
int main() {
  int x = 0x89ABCDEF;
  int y = 0x76543210;
  int result = (x & 0xFF) | (y ^ (y & 0xFF));
  printf("The result is: %x\n", result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x765432ef,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: The result is: %x


assistant: ```c
int main() {
  int x = 0x89ABCDEF;
  int y = 0x76543210;
  int result = (x & 0xFF) | (y ^ (y & 0xFF));
  printf("The result is: %x\n", result);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x765432ef,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: The result is: %x


assistant: ```c
int main() {
  int x = 0x89ABCDEF;
  int y = 0x76543210;
  int result = (x & 0xFF) | (y ^ (y & 0xFF));
  printf("The result is: %x\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xffffffff,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x70,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movabs $0xffffffffffe,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D1
data_type: string

tool: D14: malloc char: %s


tool: D1: I should break now!!

assistant: ```c
int main(int argc, char *argv[]) {
  char *c = (char *)malloc(0xfffffffffff);
  *c = 'p';
  *(c + 1) = '\0';
  printf("malloc char: %s\n", c);
  printf("I should break now!!\n");
  *(c + (0xffffffffffe)) = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xffffffff,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movb   $0x70,(%rax)
  movb   $0x0,0x1(%rax)
  mov    %rax,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  movabs $0xffffffffffe,%rax
  movb   $0x0,(%rbx,%rax,1)
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D0: malloc char: %s


tool: D8: I should break now!!

assistant: ```c
int main(int argc, char *argv[]) {
  char *c = (char *)malloc(0xfffffffffff);
  *c = 'p';
  *(c + 1) = '\0';
  printf("malloc char: %s\n", c);
  printf("I should break now!!\n");
  *(c + (0xffffffffffe)) = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xffffffff,%edi
  call   <malloc@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rbx
  mov    $0x70,%eax
  mov    %ax,(%rbx)
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  movabs $0xffffffffffe,%rax
  movb   $0x0,(%rbx,%rax,1)
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string

tool: D12: malloc char: %s


tool: D16: I should break now!!

assistant: ```c
int main(int argc, char *argv[]) {
  char *c = (char *)malloc(0xfffffffffff);
  *c = 'p';
  *(c + 1) = '\0';
  printf("malloc char: %s\n", c);
  printf("I should break now!!\n");
  *(c + (0xffffffffffe)) = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xffffffff,%edi
  call   <malloc@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rbx
  mov    $0x70,%eax
  mov    %ax,(%rbx)
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  movabs $0xffffffffffe,%rax
  movb   $0x0,(%rbx,%rax,1)
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D4: malloc char: %s


tool: D2: I should break now!!

assistant: ```c
int main(int argc, char *argv[]) {
  char *c = (char *)malloc(0xfffffffffff);
  *c = 'p';
  *(c + 1) = '\0';
  printf("malloc char: %s\n", c);
  printf("I should break now!!\n");
  *(c + (0xffffffffffe)) = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<isNumNull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L31
L18:
  mov    $0x0,%eax
  jmp    L1
L31:
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int isNumNull(t)
char t[];
{
  int f = 0;
  while (t[f] != 0) {
    if (!(t[f] >= '0' && t[f] <= '9'))
      return 0;
    f++;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isNumNull>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
  add    $0x1,%rdi
L17:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L2
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L17
  mov    $0x1,%eax
  ret
L13:
  mov    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isNumNull(t)
char t[];
{
  int f = 0;
  while (t[f] != 0) {
    if (!(t[f] >= '0' && t[f] <= '9'))
      return 0;
    f++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isNumNull>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  add    $0x1,%rdi
  jmp    L20
  nopl   0x0(%rax)
L34:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L30
L20:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L34
  xor    %eax,%eax
  ret
  nopl   (%rax)
L30:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isNumNull(t)
char t[];
{
  int f = 0;
  while (t[f] != 0) {
    if (!(t[f] >= '0' && t[f] <= '9'))
      return 0;
    f++;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isNumNull>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  add    $0x1,%rdi
  jmp    L35
  nopl   0x0(%rax)
L26:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L19
L35:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L26
  xor    %eax,%eax
  ret
  nopl   (%rax)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isNumNull(t)
char t[];
{
  int f = 0;
  while (t[f] != 0) {
    if (!(t[f] >= '0' && t[f] <= '9'))
      return 0;
    f++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <warn@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *msg, ...) {
  warn(msg);
  exit(EXIT_FAILURE);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <warn@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(const char *msg, ...) {
  warn(msg);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <warn@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(const char *msg, ...) {
  warn(msg);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <warn@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(const char *msg, ...) {
  warn(msg);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movabs $0x123456789abcd00,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  bsf    %rax,%rcx
  mov    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x8,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned long arg = 0x0123456789ABCD00;
  unsigned long out = 0;
  __asm__("bsfq %%rax, %%rcx" : "=c"(out) : "a"(arg));
  return (out == 8);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  movabs $0x123456789abcd00,%rax
  bsf    %rax,%rcx
  cmp    $0x8,%rcx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long arg = 0x0123456789ABCD00;
  unsigned long out = 0;
  __asm__("bsfq %%rax, %%rcx" : "=c"(out) : "a"(arg));
  return (out == 8);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  movabs $0x123456789abcd00,%rax
  bsf    %rax,%rcx
  xor    %eax,%eax
  cmp    $0x8,%rcx
  sete   %al
  ret
```

assistant: ```c
int main() {
  unsigned long arg = 0x0123456789ABCD00;
  unsigned long out = 0;
  __asm__("bsfq %%rax, %%rcx" : "=c"(out) : "a"(arg));
  return (out == 8);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  movabs $0x123456789abcd00,%rax
  bsf    %rax,%rcx
  xor    %eax,%eax
  cmp    $0x8,%rcx
  sete   %al
  ret
```

assistant: ```c
int main() {
  unsigned long arg = 0x0123456789ABCD00;
  unsigned long out = 0;
  __asm__("bsfq %%rax, %%rcx" : "=c"(out) : "a"(arg));
  return (out == 8);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<translate_binary_string_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L44
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  add    %eax,-0xc(%rbp)
  jmp    L3
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L3
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: Wrong value on translate_binary_string_to_int!


assistant: ```c
unsigned int translate_binary_string_to_int(char *input) {
  unsigned int value = 0;
  int input_size = strlen(input);
  for (int i = 0; i < input_size; i++) {
    if (input[i] == '1') {
      value += pow(2, input_size - (i + 1));
    } else if (input[i] != '0') {
      printf("Wrong value on translate_binary_string_to_int!\n");
    }
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<translate_binary_string_to_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  lea    -0x1(%rax),%ebx
  mov    $0x0,%r12d
  lea    D1(%rip),%r13
  jmp    L57
L33:
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  add    %eax,%r12d
L47:
  add    $0x1,%rbp
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L12
L57:
  movzbl 0x0(%rbp),%eax
  cmp    $0x31,%al
  je     L33
  cmp    $0x30,%al
  je     L47
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L47
L2:
  mov    $0x0,%r12d
L12:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: Wrong value on translate_binary_string_to_int!


assistant: ```c
unsigned int translate_binary_string_to_int(char *input) {
  unsigned int value = 0;
  int input_size = strlen(input);
  for (int i = 0; i < input_size; i++) {
    if (input[i] == '1') {
      value += pow(2, input_size - (i + 1));
    } else if (input[i] != '0') {
      printf("Wrong value on translate_binary_string_to_int!\n");
    }
  }
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<translate_binary_string_to_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L47
  lea    -0x1(%rax),%ebx
  xor    %r12d,%r12d
  lea    D4(%rip),%r13
  jmp    L34
  nopl   0x0(%rax)
L55:
  cmp    $0x30,%al
  je     L12
  mov    %r13,%rdi
  call   <printf@plt>
L12:
  add    $0x1,%rbp
  sub    $0x1,%ebx
  jb     L26
L34:
  movzbl 0x0(%rbp),%eax
  cmp    $0x31,%al
  jne    L55
  mov    %ebx,%esi
  mov    $0x2,%edi
  add    $0x1,%rbp
  call   <pow@plt>
  add    %eax,%r12d
  sub    $0x1,%ebx
  jae    L34
L26:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: Wrong value on translate_binary_string_to_int!


assistant: ```c
unsigned int translate_binary_string_to_int(char *input) {
  unsigned int value = 0;
  int input_size = strlen(input);
  for (int i = 0; i < input_size; i++) {
    if (input[i] == '1') {
      value += pow(2, input_size - (i + 1));
    } else if (input[i] != '0') {
      printf("Wrong value on translate_binary_string_to_int!\n");
    }
  }
  return value;
}
```