ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_mv_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int is_mv_double(const double *d) {
  const unsigned char u[sizeof(double)] = {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF};
  return (memcmp(d, &u, sizeof(double)) == 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_mv_double>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_mv_double(const double *d) {
  const unsigned char u[sizeof(double)] = {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF};
  return (memcmp(d, &u, sizeof(double)) == 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_mv_double>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0xffffffffffffffff,(%rsp)
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_mv_double(const double *d) {
  const unsigned char u[sizeof(double)] = {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF};
  return (memcmp(d, &u, sizeof(double)) == 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_mv_double>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0xffffffffffffffff,(%rsp)
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_mv_double(const double *d) {
  const unsigned char u[sizeof(double)] = {0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF};
  return (memcmp(d, &u, sizeof(double)) == 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vecadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vecadd(float t[], float u[], float v[]) {
  t[0] = u[0] + v[0];
  t[1] = u[1] + v[1];
  t[2] = u[2] + v[2];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vecadd>:
  endbr64
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void vecadd(float t[], float u[], float v[]) {
  t[0] = u[0] + v[0];
  t[1] = u[1] + v[1];
  t[2] = u[2] + v[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vecadd>:
  endbr64
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void vecadd(float t[], float u[], float v[]) {
  t[0] = u[0] + v[0];
  t[1] = u[1] + v[1];
  t[2] = u[2] + v[2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vecadd>:
  endbr64
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void vecadd(float t[], float u[], float v[]) {
  t[0] = u[0] + v[0];
  t[1] = u[1] + v[1];
  t[2] = u[2] + v[2];
}
```
user: What is the c source code of the assembly code below?

```asm
<free_attr_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  jmp    L20
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <SAFE_FREE@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L27
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <SAFE_FREE@plt>
  jmp    L18
L28:
  nop
L18:
  leave
  ret
```

assistant: ```c
void free_attr_list(const char **list) {
  int i = 0;
  if (!list)
    return;
  while (list[i]) {
    SAFE_FREE(list[i]);
    i += 1;
  }
  SAFE_FREE(list);
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_attr_list>:
  endbr64
  test   %rdi,%rdi
  je     L22
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L24
  lea    0x8(%rbp),%rbx
L18:
  mov    $0x0,%eax
  call   <SAFE_FREE@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L18
L24:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <SAFE_FREE@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  ret
```

assistant: ```c
void free_attr_list(const char **list) {
  int i = 0;
  if (!list)
    return;
  while (list[i]) {
    SAFE_FREE(list[i]);
    i += 1;
  }
  SAFE_FREE(list);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_attr_list>:
  endbr64
  test   %rdi,%rdi
  je     L20
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  lea    0x8(%rbp),%rbx
  xchg   %ax,%ax
L27:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <SAFE_FREE@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L27
L9:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <SAFE_FREE@plt>
  nopl   0x0(%rax)
L20:
  ret
```

assistant: ```c
void free_attr_list(const char **list) {
  int i = 0;
  if (!list)
    return;
  while (list[i]) {
    SAFE_FREE(list[i]);
    i += 1;
  }
  SAFE_FREE(list);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_attr_list>:
  endbr64
  test   %rdi,%rdi
  je     L24
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L22
  lea    0x8(%rbp),%rbx
  xchg   %ax,%ax
L18:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <SAFE_FREE@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L18
L22:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <SAFE_FREE@plt>
  nopl   0x0(%rax)
L24:
  ret
```

assistant: ```c
void free_attr_list(const char **list) {
  int i = 0;
  if (!list)
    return;
  while (list[i]) {
    SAFE_FREE(list[i]);
    i += 1;
  }
  SAFE_FREE(list);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L22:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L33
L7:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  addq   $0x1,-0x8(%rbp)
L5:
  cmpq   $0x3ff,-0x8(%rbp)
  jbe    L22
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int is_loop(ino_t *ino_list, ino_t this_ino) {
  for (size_t i = 0; i < 1024; i++) {
    if (ino_list[i] == this_ino) {
      return 1;
    }
    if (ino_list[i] == 0)
      continue;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_loop>:
  endbr64
  mov    %rdi,%rax
  add    $0x2000,%rdi
L10:
  cmp    %rsi,(%rax)
  je     L8
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L10
  mov    $0x0,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_loop(ino_t *ino_list, ino_t this_ino) {
  for (size_t i = 0; i < 1024; i++) {
    if (ino_list[i] == this_ino) {
      return 1;
    }
    if (ino_list[i] == 0)
      continue;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_loop>:
  endbr64
  lea    0x2000(%rdi),%rax
  jmp    L0
  nopl   (%rax)
L15:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L12
L0:
  cmp    %rsi,(%rdi)
  jne    L15
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_loop(ino_t *ino_list, ino_t this_ino) {
  for (size_t i = 0; i < 1024; i++) {
    if (ino_list[i] == this_ino) {
      return 1;
    }
    if (ino_list[i] == 0)
      continue;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_loop>:
  endbr64
  lea    0x2000(%rdi),%rax
  jmp    L10
  nopl   (%rax)
L18:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L17
L10:
  cmp    %rsi,(%rdi)
  jne    L18
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_loop(ino_t *ino_list, ino_t this_ino) {
  for (size_t i = 0; i < 1024; i++) {
    if (ino_list[i] == this_ino) {
      return 1;
    }
    if (ino_list[i] == 0)
      continue;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ipmpar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movl   $0x2,D41(%rip)
  movl   $0x1f,D10(%rip)
  movl   $0x7fffffff,D29(%rip)
  movl   $0x2,D109(%rip)
  movl   $0x18,D64(%rip)
  movl   $0xffffff83,D7(%rip)
  movl   $0x80,D44(%rip)
  movl   $0x35,D58(%rip)
  movl   $0xfffffc03,D105(%rip)
  movl   $0x400,D70(%rip)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D52(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ipmpar(int *i) {
  static int imach[11];
  imach[1] = 2;
  imach[2] = 31;
  imach[3] = 2147483647;
  imach[4] = 2;
  imach[5] = 24;
  imach[6] = -125;
  imach[7] = 128;
  imach[8] = 53;
  imach[9] = -1021;
  imach[10] = 1024;
  return imach[*i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ipmpar>:
  endbr64
  movl   $0x2,D52(%rip)
  movl   $0x1f,D58(%rip)
  movl   $0x7fffffff,D76(%rip)
  movl   $0x2,D17(%rip)
  movl   $0x18,D91(%rip)
  movl   $0xffffff83,D61(%rip)
  movl   $0x80,D21(%rip)
  movl   $0x35,D33(%rip)
  movl   $0xfffffc03,D23(%rip)
  movl   $0x400,D95(%rip)
  movslq (%rdi),%rdx
  lea    D27(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
```

assistant: ```c
int ipmpar(int *i) {
  static int imach[11];
  imach[1] = 2;
  imach[2] = 31;
  imach[3] = 2147483647;
  imach[4] = 2;
  imach[5] = 24;
  imach[6] = -125;
  imach[7] = 128;
  imach[8] = 53;
  imach[9] = -1021;
  imach[10] = 1024;
  return imach[*i];
}
```
user: What is the c source code of the assembly code below:

```asm
<ipmpar>:
  endbr64
  movabs $0x1f00000002,%rax
  movslq (%rdi),%rdx
  mov    %rax,D45(%rip)
  movabs $0x27fffffff,%rax
  mov    %rax,D43(%rip)
  movabs $0xffffff8300000018,%rax
  mov    %rax,D30(%rip)
  movabs $0x3500000080,%rax
  mov    %rax,D26(%rip)
  movabs $0x400fffffc03,%rax
  mov    %rax,D14(%rip)
  lea    D6(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
```

assistant: ```c
int ipmpar(int *i) {
  static int imach[11];
  imach[1] = 2;
  imach[2] = 31;
  imach[3] = 2147483647;
  imach[4] = 2;
  imach[5] = 24;
  imach[6] = -125;
  imach[7] = 128;
  imach[8] = 53;
  imach[9] = -1021;
  imach[10] = 1024;
  return imach[*i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L40
L79:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L17
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L19
L17:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L4
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L19
L4:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L14
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L19
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  addl   $0x1,-0x4(%rbp)
L40:
  cmpl   $0x64,-0x4(%rbp)
  jle    L79
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D36
type_guessed: string
name: retrieve_data
arguments: label: D24
type_guessed: string

tool: D17: fizzbuzz

tool: D26: fizz

tool: D36: buzz

tool: D24: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 1; i <= 100; i++) {
    if (!(i % 15)) {
      printf("fizzbuzz\n");
    } else if (!(i % 3)) {
      printf("fizz\n");
    } else if (!(i % 5)) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D32(%rip),%r13
  lea    D22(%rip),%r12
  lea    D17(%rip),%r14
  lea    D34(%rip),%rbp
  jmp    L29
L25:
  mov    %rbp,%rdi
  call   <puts@plt>
L9:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L32
L29:
  movslq %ebx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x3,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  sub    %eax,%edx
  cmp    %edx,%ebx
  je     L25
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L47
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L74
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L9
L47:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L9
L74:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L32:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D22
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string
name: read_data
arguments: tag: D34
type_infered: string

tool: D32: %d


tool: D22: buzz

tool: D17: fizz

tool: D34: fizzbuzz

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 1; i <= 100; i++) {
    if (!(i % 15)) {
      printf("fizzbuzz\n");
    } else if (!(i % 3)) {
      printf("fizz\n");
    } else if (!(i % 5)) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D27(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L76
  nop
L62:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  jbe    L53
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L12
  mov    %r12,%rdi
  call   <puts@plt>
L14:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L1
L76:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  ja     L62
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L76
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: tag: D27
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D6
type: string
name: unpack_data
arguments: tag: D15
type: string

tool: D27: fizz

tool: D0: %d


tool: D6: buzz

tool: D15: fizzbuzz

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 1; i <= 100; i++) {
    if (!(i % 15)) {
      printf("fizzbuzz\n");
    } else if (!(i % 3)) {
      printf("fizz\n");
    } else if (!(i % 5)) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L51
  nop
L13:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  jbe    L0
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L37
  mov    %r12,%rdi
  call   <puts@plt>
L25:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L44
L51:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  ja     L13
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L51
L44:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L25
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D3
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string

tool: D9: fizz

tool: D3: %d


tool: D7: buzz

tool: D8: fizzbuzz

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 1; i <= 100; i++) {
    if (!(i % 15)) {
      printf("fizzbuzz\n");
    } else if (!(i % 3)) {
      printf("fizz\n");
    } else if (!(i % 5)) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D8
type: string

tool: D11: The command line has %d arguments: 


tool: D17: %d: %s


tool: D8: Done

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  printf("The command line has %d arguments: \n", argc);
  for (count = 0; count < argc; count++)
    printf("%d: %s\n", count, argv[count]);
  printf("\n");
  puts("Done");
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edi,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L17
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D26(%rip),%r13
L10:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
datatype: string
name: disassemble_data
arguments: label: D26
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D11: The command line has %d arguments: 


tool: D26: %d: %s


tool: D0: Done

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  printf("The command line has %d arguments: \n", argc);
  for (count = 0; count < argc; count++)
    printf("%d: %s\n", count, argv[count]);
  printf("\n");
  puts("Done");
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D16(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L5
  xor    %ebx,%ebx
  lea    D19(%rip),%r13
  nopl   0x0(%rax)
L19:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L19
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string

tool: D16: The command line has %d arguments: 


tool: D19: %d: %s


tool: D8: Done

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  printf("The command line has %d arguments: \n", argc);
  for (count = 0; count < argc; count++)
    printf("%d: %s\n", count, argv[count]);
  printf("\n");
  puts("Done");
  getchar();
}
```