ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<clear_input_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r12
  movq   $0x0,0x18(%rsp)
  mov    %rbx,%rdi
  lea    0xb(%rsp),%r13
  movq   $0x0,0x10(%rsp)
  call   <FD_ZERO@plt>
  mov    D5(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <fileno@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L22:
  mov    0x0(%rbp),%edi
  call   <fileno@plt>
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <read@plt>
L1:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r12,%r8
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  test   %rax,%rax
  jne    L22
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void clear_input_buffer(void) {
  struct timeval tv;
  fd_set fds;
  char buf;
  tv.tv_usec = 0;
  tv.tv_sec = 0;
  FD_ZERO(&fds);
  FD_SET(fileno(stdin), &fds);
  fflush(stdin);
  while (select(1, &fds, NULL, NULL, &tv) != 0)
    read(fileno(stdin), &buf, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clear_input_buffer>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  movaps %xmm0,0x10(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rbx,%rdi
  lea    0xb(%rsp),%r13
  call   <FD_ZERO@plt>
  mov    D8(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <fileno@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  jmp    L19
  nopl   0x0(%rax)
L6:
  mov    0x0(%rbp),%edi
  call   <fileno@plt>
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <read@plt>
L19:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r12,%r8
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  test   %rax,%rax
  jne    L6
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void clear_input_buffer(void) {
  struct timeval tv;
  fd_set fds;
  char buf;
  tv.tv_usec = 0;
  tv.tv_sec = 0;
  FD_ZERO(&fds);
  FD_SET(fileno(stdin), &fds);
  fflush(stdin);
  while (select(1, &fds, NULL, NULL, &tv) != 0)
    read(fileno(stdin), &buf, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f_get_my_resident_time__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x708,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x708,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
f_get_my_resident_time__(int *wu, int *wh, int *ws) {
  char *hostname;
  *wu = 0;
  *wh = 1800;
  *ws = 1800;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f_get_my_resident_time__>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x708,(%rsi)
  movl   $0x708,(%rdx)
  ret
```

assistant: ```c
f_get_my_resident_time__(int *wu, int *wh, int *ws) {
  char *hostname;
  *wu = 0;
  *wh = 1800;
  *ws = 1800;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f_get_my_resident_time__>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x708,(%rsi)
  movl   $0x708,(%rdx)
  ret
```

assistant: ```c
f_get_my_resident_time__(int *wu, int *wh, int *ws) {
  char *hostname;
  *wu = 0;
  *wh = 1800;
  *ws = 1800;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f_get_my_resident_time__>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x708,(%rsi)
  movl   $0x708,(%rdx)
  ret
```

assistant: ```c
f_get_my_resident_time__(int *wu, int *wh, int *ws) {
  char *hostname;
  *wu = 0;
  *wh = 1800;
  *ws = 1800;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pack_add_flt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  movss  %xmm0,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  lea    -0x10(%rbp),%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pack_add_flt(uint8_t *buffer, int byteNr, float value) {
  *(buffer + byteNr + 3) = *(((uint8_t *)(&value)) + 3);
  *(buffer + byteNr + 2) = *(((uint8_t *)(&value)) + 2);
  *(buffer + byteNr + 1) = *(((uint8_t *)(&value)) + 1);
  *(buffer + byteNr) = *((uint8_t *)(&value));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack_add_flt>:
  endbr64
  movslq %esi,%rsi
  add    $0x3,%rsi
  lea    0x0(,%rsi,4),%rax
  mov    0x8(%rsp),%edx
  mov    %edx,(%rdi,%rsi,4)
  mov    0x4(%rsp),%edx
  mov    %edx,-0x4(%rdi,%rax,1)
  mov    (%rsp),%edx
  mov    %edx,-0x8(%rdi,%rax,1)
  movss  %xmm0,-0xc(%rdi,%rax,1)
  ret
```

assistant: ```c
void pack_add_flt(uint8_t *buffer, int byteNr, float value) {
  *(buffer + byteNr + 3) = *(((uint8_t *)(&value)) + 3);
  *(buffer + byteNr + 2) = *(((uint8_t *)(&value)) + 2);
  *(buffer + byteNr + 1) = *(((uint8_t *)(&value)) + 1);
  *(buffer + byteNr) = *((uint8_t *)(&value));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack_add_flt>:
  endbr64
  mov    0x8(%rsp),%edx
  movslq %esi,%rsi
  add    $0x3,%rsi
  mov    %edx,(%rdi,%rsi,4)
  mov    0x4(%rsp),%edx
  lea    0x0(,%rsi,4),%rax
  mov    %edx,-0x4(%rdi,%rax,1)
  mov    (%rsp),%edx
  movss  %xmm0,-0xc(%rdi,%rax,1)
  mov    %edx,-0x8(%rdi,%rax,1)
  ret
```

assistant: ```c
void pack_add_flt(uint8_t *buffer, int byteNr, float value) {
  *(buffer + byteNr + 3) = *(((uint8_t *)(&value)) + 3);
  *(buffer + byteNr + 2) = *(((uint8_t *)(&value)) + 2);
  *(buffer + byteNr + 1) = *(((uint8_t *)(&value)) + 1);
  *(buffer + byteNr) = *((uint8_t *)(&value));
}
```
user: What is the c source code of the assembly code below:

```asm
<pack_add_flt>:
  endbr64
  movss  %xmm0,-0xc(%rsp)
  movdqu -0xc(%rsp),%xmm1
  movslq %esi,%rsi
  movups %xmm1,(%rdi,%rsi,4)
  ret
```

assistant: ```c
void pack_add_flt(uint8_t *buffer, int byteNr, float value) {
  *(buffer + byteNr + 3) = *(((uint8_t *)(&value)) + 3);
  *(buffer + byteNr + 2) = *(((uint8_t *)(&value)) + 2);
  *(buffer + byteNr + 1) = *(((uint8_t *)(&value)) + 1);
  *(buffer + byteNr) = *((uint8_t *)(&value));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<camera_light_freq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x13,%edi
  call   <create_command@plt>
  mov    $0x0,%eax
  call   <send_command@plt>
  mov    $0x13,%esi
  mov    $0x186a0,%edi
  call   <wait_for_ack@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0x1eb,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7: camera_light_freq %d result=%d


assistant: ```c
int camera_light_freq(int freq) {
  create_command(0x13, freq, 0, 0, 0);
  send_command();
  int result = wait_for_ack(100000, 0x13);
  printf("camera_light_freq %d result=%d\n", 491, result);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<camera_light_freq>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x13,%edi
  call   <create_command@plt>
  mov    $0x0,%eax
  call   <send_command@plt>
  mov    $0x13,%esi
  mov    $0x186a0,%edi
  call   <wait_for_ack@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    $0x1eb,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: camera_light_freq %d result=%d


assistant: ```c
int camera_light_freq(int freq) {
  create_command(0x13, freq, 0, 0, 0);
  send_command();
  int result = wait_for_ack(100000, 0x13);
  printf("camera_light_freq %d result=%d\n", 491, result);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<camera_light_freq>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x13,%edi
  call   <create_command@plt>
  xor    %eax,%eax
  call   <send_command@plt>
  mov    $0x13,%esi
  mov    $0x186a0,%edi
  call   <wait_for_ack@plt>
  mov    $0x1eb,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%edx
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: camera_light_freq %d result=%d


assistant: ```c
int camera_light_freq(int freq) {
  create_command(0x13, freq, 0, 0, 0);
  send_command();
  int result = wait_for_ack(100000, 0x13);
  printf("camera_light_freq %d result=%d\n", 491, result);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<camera_light_freq>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x13,%edi
  call   <create_command@plt>
  xor    %eax,%eax
  call   <send_command@plt>
  mov    $0x13,%esi
  mov    $0x186a0,%edi
  call   <wait_for_ack@plt>
  mov    $0x1eb,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%edx
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: camera_light_freq %d result=%d


assistant: ```c
int camera_light_freq(int freq) {
  create_command(0x13, freq, 0, 0, 0);
  send_command();
  int result = wait_for_ack(100000, 0x13);
  printf("camera_light_freq %d result=%d\n", 491, result);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<b64_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2b,-0x4(%rbp)
  jne    L42
  mov    $0x3e,%eax
  jmp    L94
L42:
  cmpl   $0x2f,-0x4(%rbp)
  jne    L135
  mov    $0x3f,%eax
  jmp    L94
L135:
  cmpl   $0x3d,-0x4(%rbp)
  jne    L44
  mov    $0x40,%eax
  jmp    L94
L44:
  cmpl   $0x2f,-0x4(%rbp)
  jbe    L144
  cmpl   $0x39,-0x4(%rbp)
  ja     L144
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L94
L144:
  cmpl   $0x40,-0x4(%rbp)
  jbe    L38
  cmpl   $0x5a,-0x4(%rbp)
  ja     L38
  mov    -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L94
L38:
  cmpl   $0x60,-0x4(%rbp)
  jbe    L24
  cmpl   $0x7a,-0x4(%rbp)
  ja     L24
  mov    -0x4(%rbp),%eax
  sub    $0x47,%eax
  jmp    L94
L24:
  mov    $0x0,%eax
L94:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int b64_int(unsigned int ch) {
  if (ch == 43)
    return 62;
  if (ch == 47)
    return 63;
  if (ch == 61)
    return 64;
  if ((ch > 47) && (ch < 58))
    return ch + 4;
  if ((ch > 64) && (ch < 91))
    return ch - 'A';
  if ((ch > 96) && (ch < 123))
    return (ch - 'a') + 26;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<b64_int>:
  endbr64
  cmp    $0x2b,%edi
  je     L29
  cmp    $0x2f,%edi
  je     L45
  cmp    $0x3d,%edi
  je     L5
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L31
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L16
  lea    -0x61(%rdi),%eax
  sub    $0x47,%edi
  cmp    $0x1a,%eax
  mov    $0x0,%eax
  cmovb  %edi,%eax
  ret
L31:
  lea    0x4(%rdi),%eax
  ret
L29:
  mov    $0x3e,%eax
  ret
L45:
  mov    $0x3f,%eax
  ret
L5:
  mov    $0x40,%eax
L16:
  ret
```

assistant: ```c
unsigned int b64_int(unsigned int ch) {
  if (ch == 43)
    return 62;
  if (ch == 47)
    return 63;
  if (ch == 61)
    return 64;
  if ((ch > 47) && (ch < 58))
    return ch + 4;
  if ((ch > 64) && (ch < 91))
    return ch - 'A';
  if ((ch > 96) && (ch < 123))
    return (ch - 'a') + 26;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<b64_int>:
  endbr64
  cmp    $0x2b,%edi
  je     L21
  cmp    $0x2f,%edi
  je     L2
  cmp    $0x3d,%edi
  je     L32
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L25
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L14
  lea    -0x61(%rdi),%eax
  sub    $0x47,%edi
  cmp    $0x1a,%eax
  mov    $0x0,%eax
  cmovb  %edi,%eax
  ret
  nopl   (%rax)
L25:
  lea    0x4(%rdi),%eax
  ret
  nopl   0x0(%rax)
L32:
  mov    $0x40,%eax
L14:
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    $0x3e,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x3f,%eax
  ret
```

assistant: ```c
unsigned int b64_int(unsigned int ch) {
  if (ch == 43)
    return 62;
  if (ch == 47)
    return 63;
  if (ch == 61)
    return 64;
  if ((ch > 47) && (ch < 58))
    return ch + 4;
  if ((ch > 64) && (ch < 91))
    return ch - 'A';
  if ((ch > 96) && (ch < 123))
    return (ch - 'a') + 26;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<b64_int>:
  endbr64
  cmp    $0x2b,%edi
  je     L21
  cmp    $0x2f,%edi
  je     L27
  cmp    $0x3d,%edi
  je     L5
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L6
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L11
  lea    -0x61(%rdi),%eax
  sub    $0x47,%edi
  cmp    $0x1a,%eax
  mov    $0x0,%eax
  cmovb  %edi,%eax
  ret
  nopl   (%rax)
L6:
  lea    0x4(%rdi),%eax
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x40,%eax
L11:
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    $0x3e,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    $0x3f,%eax
  ret
```

assistant: ```c
unsigned int b64_int(unsigned int ch) {
  if (ch == 43)
    return 62;
  if (ch == 47)
    return 63;
  if (ch == 61)
    return 64;
  if ((ch > 47) && (ch < 58))
    return ch + 4;
  if ((ch > 64) && (ch < 91))
    return ch - 'A';
  if ((ch > 96) && (ch < 123))
    return (ch - 'a') + 26;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_putnbr_16_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %edi,-0x824(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x824(%rbp)
  jns    L51
  negl   -0x824(%rbp)
L51:
  movl   $0x0,-0x81c(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  mov    %rax,-0x818(%rbp)
  jmp    L14
L5:
  mov    -0x824(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x818(%rbp)
  mov    %rdx,%rcx
  mov    -0x81c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x81c(%rbp)
  lea    D7(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  cltq
  mov    %dl,-0x810(%rbp,%rax,1)
  mov    -0x824(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x818(%rbp)
  mov    %eax,-0x824(%rbp)
L14:
  mov    -0x824(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x818(%rbp)
  cmp    %rax,-0x818(%rbp)
  jbe    L5
  mov    -0x824(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x818(%rbp)
  mov    %rdx,%rcx
  mov    -0x81c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x81c(%rbp)
  lea    D7(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  cltq
  mov    %dl,-0x810(%rbp,%rax,1)
  mov    -0x824(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x818(%rbp)
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  movzbl (%rdx,%rax,1),%edx
  mov    -0x81c(%rbp),%eax
  cltq
  mov    %dl,-0x810(%rbp,%rax,1)
  jmp    L0
L2:
  mov    -0x81c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x81c(%rbp)
  cltq
  movzbl -0x810(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L0:
  cmpl   $0x0,-0x81c(%rbp)
  jns    L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string

tool: D7: 0123456789abcdef

assistant: ```c
void ft_putnbr_16_base(int nbr) {
  unsigned long base_len;
  char resault[2048];
  int it;
  if (nbr < 0)
    nbr *= -1;
  it = 0;
  base_len = str_len("0123456789abcdef");
  while (nbr / base_len >= base_len) {
    resault[it++] = "0123456789abcdef"[nbr % base_len];
    nbr /= base_len;
  }
  resault[it++] = "0123456789abcdef"[nbr % base_len];
  resault[it] = "0123456789abcdef"[nbr / base_len];
  while (it >= 0)
    ft_putchar(resault[it--]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_putnbr_16_base>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <str_len@plt>
  mov    %rax,%r9
  mov    %ebx,%ecx
  neg    %ecx
  cmovs  %ebx,%ecx
  movslq %ecx,%rcx
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %r9
  cmp    %rax,%r9
  ja     L51
  mov    %rax,%r10
  mov    %rsp,%rdi
  mov    $0x0,%esi
  lea    D15(%rip),%r8
L6:
  mov    %esi,%ebx
  add    $0x1,%esi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %r9
  movzbl (%r8,%rdx,1),%eax
  mov    %al,(%rdi)
  movslq %r10d,%rcx
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %r9
  mov    %rax,%r10
  add    $0x1,%rdi
  cmp    %r9,%rax
  jae    L6
  add    $0x2,%ebx
  movslq %esi,%rsi
  lea    D15(%rip),%rdi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %r9
  movzbl (%rdi,%rdx,1),%eax
  mov    %al,(%rsp,%rsi,1)
  movslq %ebx,%rax
  movzbl (%rdi,%r10,1),%edx
  mov    %dl,(%rsp,%rax,1)
  test   %ebx,%ebx
  js     L2
L25:
  movslq %ebx,%rbx
  mov    %rsp,%rbp
L31:
  movsbl (%rbx,%rbp,1),%edi
  call   <ft_putchar@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L31
L2:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  mov    %rax,%rsi
  lea    D15(%rip),%rdi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %r9
  movzbl (%rdi,%rdx,1),%eax
  mov    %al,(%rsp)
  movzbl (%rdi,%rsi,1),%eax
  mov    %al,0x1(%rsp)
  mov    $0x1,%ebx
  jmp    L25
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
data_type: string

tool: D15: 0123456789abcdef

assistant: ```c
void ft_putnbr_16_base(int nbr) {
  unsigned long base_len;
  char resault[2048];
  int it;
  if (nbr < 0)
    nbr *= -1;
  it = 0;
  base_len = str_len("0123456789abcdef");
  while (nbr / base_len >= base_len) {
    resault[it++] = "0123456789abcdef"[nbr % base_len];
    nbr /= base_len;
  }
  resault[it++] = "0123456789abcdef"[nbr % base_len];
  resault[it] = "0123456789abcdef"[nbr / base_len];
  while (it >= 0)
    ft_putchar(resault[it--]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_putnbr_16_base>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <str_len@plt>
  mov    %ebx,%edi
  neg    %edi
  mov    %rax,%rcx
  cmovs  %ebx,%edi
  xor    %edx,%edx
  movslq %edi,%rdi
  mov    %rdi,%rax
  div    %rcx
  mov    %rax,%rsi
  cmp    %rax,%rcx
  ja     L17
  mov    $0x1,%r8d
  lea    -0x1(%rsp),%r10
  nopl   (%rax)
L40:
  mov    %rdi,%rax
  xor    %edx,%edx
  movslq %r8d,%r9
  mov    %rsi,%rdi
  div    %rcx
  movzbl 0x0(%rbp,%rdx,1),%eax
  xor    %edx,%edx
  mov    %al,(%r10,%r8,1)
  mov    %rsi,%rax
  add    $0x1,%r8
  div    %rcx
  mov    %rax,%rsi
  cmp    %rcx,%rax
  jae    L40
  lea    0x1(%r9),%ebx
L28:
  mov    %rdi,%rax
  xor    %edx,%edx
  movsbl 0x0(%rbp,%rsi,1),%edi
  div    %rcx
  movzbl 0x0(%rbp,%rdx,1),%eax
  mov    %al,(%rsp,%r9,1)
  movslq %ebx,%rax
  sub    $0x1,%ebx
  mov    %dil,(%rsp,%rax,1)
  movslq %ebx,%rbx
  jmp    L50
  nopl   0x0(%rax)
L56:
  movsbl (%rsp,%rbx,1),%edi
  sub    $0x1,%rbx
L50:
  call   <ft_putchar@plt>
  cmp    $0xffffffff,%ebx
  jne    L56
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%ebx
  xor    %r9d,%r9d
  jmp    L28
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: 0123456789abcdef

assistant: ```c
void ft_putnbr_16_base(int nbr) {
  unsigned long base_len;
  char resault[2048];
  int it;
  if (nbr < 0)
    nbr *= -1;
  it = 0;
  base_len = str_len("0123456789abcdef");
  while (nbr / base_len >= base_len) {
    resault[it++] = "0123456789abcdef"[nbr % base_len];
    nbr /= base_len;
  }
  resault[it++] = "0123456789abcdef"[nbr % base_len];
  resault[it] = "0123456789abcdef"[nbr / base_len];
  while (it >= 0)
    ft_putchar(resault[it--]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_putnbr_16_base>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <str_len@plt>
  mov    %ebp,%edi
  neg    %edi
  mov    %rax,%rcx
  cmovs  %ebp,%edi
  xor    %edx,%edx
  movslq %edi,%rdi
  mov    %rdi,%rax
  div    %rcx
  mov    %rax,%rsi
  cmp    %rax,%rcx
  ja     L10
  mov    $0x1,%r8d
  lea    -0x1(%rsp),%r9
  nopl   (%rax)
L25:
  mov    %rdi,%rax
  xor    %edx,%edx
  movslq %r8d,%r10
  mov    %rsi,%rdi
  div    %rcx
  movzbl (%rbx,%rdx,1),%eax
  xor    %edx,%edx
  mov    %al,(%r9,%r8,1)
  mov    %rsi,%rax
  add    $0x1,%r8
  div    %rcx
  mov    %rax,%rsi
  cmp    %rcx,%rax
  jae    L25
  lea    0x1(%r10),%r8d
L23:
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %r9,%rbp
  div    %rcx
  movzbl (%rbx,%rdx,1),%eax
  movzbl (%rbx,%rsi,1),%edx
  mov    %al,(%rsp,%r10,1)
  movslq %r8d,%rax
  mov    %dl,(%rsp,%rax,1)
  lea    (%rsp,%rax,1),%rbx
  nop
L30:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <ft_putchar@plt>
  cmp    %rbp,%rbx
  jne    L30
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L10:
  mov    $0x1,%r8d
  xor    %r10d,%r10d
  lea    -0x1(%rsp),%r9
  jmp    L23
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: 0123456789abcdef

assistant: ```c
void ft_putnbr_16_base(int nbr) {
  unsigned long base_len;
  char resault[2048];
  int it;
  if (nbr < 0)
    nbr *= -1;
  it = 0;
  base_len = str_len("0123456789abcdef");
  while (nbr / base_len >= base_len) {
    resault[it++] = "0123456789abcdef"[nbr % base_len];
    nbr /= base_len;
  }
  resault[it++] = "0123456789abcdef"[nbr % base_len];
  resault[it] = "0123456789abcdef"[nbr / base_len];
  while (it >= 0)
    ft_putchar(resault[it--]);
}
```