ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IsNullOrEmpty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L36
L47:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L36
  movl   $0x0,-0x4(%rbp)
L36:
  cmpq   $0x0,-0x18(%rbp)
  je     L49
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  cmpl   $0x0,-0x4(%rbp)
  jne    L47
L49:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int IsNullOrEmpty(const char *p) {
  int empty = 1;
  while (p && *p && empty) {
    if (!isspace((unsigned char)*p++)) {
      empty = 0;
    }
  }
  return empty;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IsNullOrEmpty>:
  endbr64
  test   %rdi,%rdi
  je     L41
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L30
  mov    $0x1,%eax
  jmp    L39
L53:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L10
L30:
  add    $0x1,%rbx
  movzbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L53
L39:
  pop    %rbx
  ret
L10:
  mov    $0x1,%eax
  jmp    L39
L41:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IsNullOrEmpty(const char *p) {
  int empty = 1;
  while (p && *p && empty) {
    if (!isspace((unsigned char)*p++)) {
      empty = 0;
    }
  }
  return empty;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<IsNullOrEmpty>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L20:
  test   %rbx,%rbx
  je     L3
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L3
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %eax,%eax
  jne    L20
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int IsNullOrEmpty(const char *p) {
  int empty = 1;
  while (p && *p && empty) {
    if (!isspace((unsigned char)*p++)) {
      empty = 0;
    }
  }
  return empty;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IsNullOrEmpty>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L27:
  test   %rbx,%rbx
  je     L0
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L0
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %eax,%eax
  jne    L27
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int IsNullOrEmpty(const char *p) {
  int empty = 1;
  while (p && *p && empty) {
    if (!isspace((unsigned char)*p++)) {
      empty = 0;
    }
  }
  return empty;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<median_partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <find_median_pivot@plt>
  mov    %eax,%r12d
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdx
  movslq %r12d,%rax
  shl    $0x2,%rax
  add    %r14,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    %ebx,%r12d
  jmp    L8
L5:
  movslq %ebx,%rax
  shl    $0x2,%rax
  add    %r14,%rax
  mov    (%rax),%edx
  movslq %r13d,%rax
  shl    $0x2,%rax
  add    %r14,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L26
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdx
  movslq %r12d,%rax
  shl    $0x2,%rax
  add    %r14,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  add    $0x1,%r12d
L26:
  add    $0x1,%ebx
L8:
  cmp    %r13d,%ebx
  jl     L5
  movslq %r13d,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdx
  movslq %r12d,%rax
  shl    $0x2,%rax
  add    %r14,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int median_partition(register int *a, register int start, register int end) {
  register int pivotIndex = find_median_pivot(a, start, end);
  swap(a + pivotIndex, a + start);
  pivotIndex = start;
  while (start < end) {
    if (*(a + start) < *(a + end)) {
      swap(a + pivotIndex, a + start);
      pivotIndex++;
    }
    start++;
  }
  swap(a + pivotIndex, a + end);
  return pivotIndex;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<median_partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  call   <find_median_pivot@plt>
  movslq %ebp,%r14
  lea    (%r12,%r14,4),%rbx
  cltq
  lea    (%r12,%rax,4),%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  cmp    %r13d,%ebp
  jge    L27
  movslq %r13d,%rax
  lea    (%r12,%rax,4),%r15
  lea    -0x1(%r13),%eax
  sub    %ebp,%eax
  add    %r14,%rax
  lea    0x4(%r12,%rax,4),%r14
  jmp    L9
L21:
  add    $0x4,%rbx
  cmp    %r14,%rbx
  je     L27
L9:
  mov    (%r15),%eax
  cmp    %eax,(%rbx)
  jge    L21
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  add    $0x1,%ebp
  jmp    L21
L27:
  movslq %r13d,%r13
  lea    (%r12,%r13,4),%rsi
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rdi
  call   <swap@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int median_partition(register int *a, register int start, register int end) {
  register int pivotIndex = find_median_pivot(a, start, end);
  swap(a + pivotIndex, a + start);
  pivotIndex = start;
  while (start < end) {
    if (*(a + start) < *(a + end)) {
      swap(a + pivotIndex, a + start);
      pivotIndex++;
    }
    start++;
  }
  swap(a + pivotIndex, a + end);
  return pivotIndex;
}
```
user: What is the c source code of the assembly code below?

```asm
<median_partition>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <find_median_pivot@plt>
  movslq %r12d,%rdx
  lea    (%r14,%rdx,4),%rbp
  cltq
  mov    %rdx,0x8(%rsp)
  lea    (%r14,%rax,4),%rdi
  mov    %rbp,%rsi
  call   <swap@plt>
  movslq %r13d,%rax
  lea    (%r14,%rax,4),%r15
  cmp    %r13d,%r12d
  jge    L28
  mov    0x8(%rsp),%rdx
  sub    $0x1,%r13d
  mov    %rbp,%rbx
  sub    %r12d,%r13d
  add    %rdx,%r13
  lea    0x4(%r14,%r13,4),%rbp
  jmp    L21
  nop
L22:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L46
L21:
  mov    (%r15),%eax
  cmp    %eax,(%rbx)
  jge    L22
  movslq %r12d,%rax
  mov    %rbx,%rsi
  add    $0x4,%rbx
  add    $0x1,%r12d
  lea    (%r14,%rax,4),%rdi
  call   <swap@plt>
  cmp    %rbx,%rbp
  jne    L21
L46:
  movslq %r12d,%rax
  lea    (%r14,%rax,4),%rbp
L28:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int median_partition(register int *a, register int start, register int end) {
  register int pivotIndex = find_median_pivot(a, start, end);
  swap(a + pivotIndex, a + start);
  pivotIndex = start;
  while (start < end) {
    if (*(a + start) < *(a + end)) {
      swap(a + pivotIndex, a + start);
      pivotIndex++;
    }
    start++;
  }
  swap(a + pivotIndex, a + end);
  return pivotIndex;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<median_partition>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <find_median_pivot@plt>
  movslq %r12d,%rdx
  lea    (%r14,%rdx,4),%rbp
  cltq
  mov    %rdx,0x8(%rsp)
  lea    (%r14,%rax,4),%rdi
  mov    %rbp,%rsi
  call   <swap@plt>
  movslq %r13d,%rax
  lea    (%r14,%rax,4),%r15
  cmp    %r13d,%r12d
  jge    L1
  mov    0x8(%rsp),%rdx
  sub    $0x1,%r13d
  mov    %rbp,%rbx
  sub    %r12d,%r13d
  add    %rdx,%r13
  lea    0x4(%r14,%r13,4),%rbp
  jmp    L26
  nop
L22:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L49
L26:
  mov    (%r15),%eax
  cmp    %eax,(%rbx)
  jge    L22
  movslq %r12d,%rax
  mov    %rbx,%rsi
  add    $0x4,%rbx
  add    $0x1,%r12d
  lea    (%r14,%rax,4),%rdi
  call   <swap@plt>
  cmp    %rbx,%rbp
  jne    L26
L49:
  movslq %r12d,%rax
  lea    (%r14,%rax,4),%rbp
L1:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int median_partition(register int *a, register int start, register int end) {
  register int pivotIndex = find_median_pivot(a, start, end);
  swap(a + pivotIndex, a + start);
  pivotIndex = start;
  while (start < end) {
    if (*(a + start) < *(a + end)) {
      swap(a + pivotIndex, a + start);
      pivotIndex++;
    }
    start++;
  }
  swap(a + pivotIndex, a + end);
  return pivotIndex;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0xc(%rbp)
  jmp    L16
L20:
  movl   $0x1,-0x8(%rbp)
  jmp    L19
L10:
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0xa,-0x8(%rbp)
  jle    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0xa,-0xc(%rbp)
  jle    L20
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8:  %d

assistant: ```c
int main() {
  int r;
  int tab;
  int i;
  tab = 2;
  while (tab <= 10) {
    i = 1;
    while (i <= 10) {
      r = tab * i;
      printf(" %d", r);
      i++;
    }
    printf("\n");
    tab++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%r14d
  lea    D8(%rip),%r13
L9:
  mov    %r14d,%r12d
  mov    %r14d,%ebp
  mov    $0xa,%ebx
L12:
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %r12d,%ebp
  sub    $0x1,%ebx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  cmp    $0xb,%r14d
  jne    L9
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8:  %d

assistant: ```c
int main() {
  int r;
  int tab;
  int i;
  tab = 2;
  while (tab <= 10) {
    i = 1;
    while (i <= 10) {
      r = tab * i;
      printf(" %d", r);
      i++;
    }
    printf("\n");
    tab++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12d,%ebp
  mov    $0xa,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    %r12d,%ebp
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L4
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0xb,%r12d
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6:  %d

assistant: ```c
int main() {
  int r;
  int tab;
  int i;
  tab = 2;
  while (tab <= 10) {
    i = 1;
    while (i <= 10) {
      r = tab * i;
      printf(" %d", r);
      i++;
    }
    printf("\n");
    tab++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12d,%ebp
  mov    $0xa,%ebx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    %r12d,%ebp
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L12
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0xb,%r12d
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7:  %d

assistant: ```c
int main() {
  int r;
  int tab;
  int i;
  tab = 2;
  while (tab <= 10) {
    i = 1;
    while (i <= 10) {
      r = tab * i;
      printf(" %d", r);
      i++;
    }
    printf("\n");
    tab++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstrTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x656c706d69732061,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0x676e6972747320,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x6,%edx
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D2: simple

tool: D15: sample

assistant: ```c
void strstrTest() {
  char str[] = "This is a simple string";
  char *pch;
  pch = strstr(str, "simple");
  strncpy(pch, "sample", 6);
  puts(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strstrTest>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x656c706d69732061,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x676e6972747320,%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rbx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rdi
  mov    $0x6,%edx
  lea    D19(%rip),%rsi
  call   <strncpy@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D7: simple

tool: D19: sample

assistant: ```c
void strstrTest() {
  char str[] = "This is a simple string";
  char *pch;
  pch = strstr(str, "simple");
  strncpy(pch, "sample", 6);
  puts(str);
}
```
user: What is the c source code of the assembly code below:

```asm
<strstrTest>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rsi
  sub    $0x20,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movabs $0x676e6972747320,%rax
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <strstr@plt>
  mov    $0x6,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string
name: retrieve_data
arguments: label: D26
datatype: byte[16]
name: retrieve_data
arguments: label: D9
datatype: string

tool: D8: simple

tool: {"D26": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x73,0x69,0x6d,0x70,0x6c,0x65]}

tool: D9: sample

assistant: ```c
void strstrTest() {
  char str[] = "This is a simple string";
  char *pch;
  pch = strstr(str, "simple");
  strncpy(pch, "sample", 6);
  puts(str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstrTest>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rsi
  sub    $0x20,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movabs $0x676e6972747320,%rax
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <strstr@plt>
  mov    $0x6,%edx
  lea    D28(%rip),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: byte[16]
name: disassemble_data
arguments: data_label: D28
datatype: string

tool: D19: simple

tool: {"D17": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x73,0x69,0x6d,0x70,0x6c,0x65]}

tool: D28: sample

assistant: ```c
void strstrTest() {
  char str[] = "This is a simple string";
  char *pch;
  pch = strstr(str, "simple");
  strncpy(pch, "sample", 6);
  puts(str);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0xfffffffb,-0x4(%rbp)
  je     L21
  call   <abort@plt>
L21:
  cmpl   $0xffffffb8,-0xc(%rbp)
  je     L26
  call   <abort@plt>
L26:
  cmpl   $0x1,-0x8(%rbp)
  je     L25
  call   <abort@plt>
L25:
  nop
  leave
  ret
```

assistant: ```c
void f(int g_, int i_, int h_) {
  _Noreturn void abort(void);
  if (g_ != -5)
    abort();
  if (h_ != -72)
    abort();
  if (i_ != 1)
    abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xfffffffb,%edi
  jne    L20
  cmp    $0xffffffb8,%edx
  jne    L1
  cmp    $0x1,%esi
  jne    L22
  add    $0x8,%rsp
  ret
L20:
  call   <abort@plt>
L1:
  call   <abort@plt>
L22:
  call   <abort@plt>
```

assistant: ```c
void f(int g_, int i_, int h_) {
  _Noreturn void abort(void);
  if (g_ != -5)
    abort();
  if (h_ != -72)
    abort();
  if (i_ != 1)
    abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  cmp    $0xfffffffb,%edi
  jne    1060 <f.cold>
  cmp    $0xffffffb8,%edx
  jne    1060 <f.cold>
  cmp    $0x1,%esi
  jne    1060 <f.cold>
  ret
```

assistant: ```c
void f(int g_, int i_, int h_) {
  _Noreturn void abort(void);
  if (g_ != -5)
    abort();
  if (h_ != -72)
    abort();
  if (i_ != 1)
    abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  cmp    $0xfffffffb,%edi
  jne    1060 <f.cold>
  cmp    $0xffffffb8,%edx
  jne    1060 <f.cold>
  cmp    $0x1,%esi
  jne    1060 <f.cold>
  ret
```

assistant: ```c
void f(int g_, int i_, int h_) {
  _Noreturn void abort(void);
  if (g_ != -5)
    abort();
  if (h_ != -72)
    abort();
  if (i_ != 1)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L2:
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string

tool: D9: 



tool: D14: 

 -- System halted

assistant: ```c
void error(char *x) {
  puts("\n\n");
  puts(x);
  puts("\n\n -- System halted");
  while (1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
L4:
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D16
type_infered: string

tool: D15: 



tool: D16: 

 -- System halted

assistant: ```c
void error(char *x) {
  puts("\n\n");
  puts(x);
  puts("\n\n -- System halted");
  while (1)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
L0:
  jmp    L0
```

tool_calls: name: read_data
arguments: data_tag: D10
data_type: string
name: read_data
arguments: data_tag: D16
data_type: string

tool: D10: 



tool: D16: 

 -- System halted

assistant: ```c
void error(char *x) {
  puts("\n\n");
  puts(x);
  puts("\n\n -- System halted");
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
L6:
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D5
type: string

tool: D14: 



tool: D5: 

 -- System halted

assistant: ```c
void error(char *x) {
  puts("\n\n");
  puts(x);
  puts("\n\n -- System halted");
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type_guessed: f64
name: read_data
arguments: data_tag: D24
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string

tool: D21: 3.14

tool: D24: %lf

tool: D25: Perimeter: %.2lf
Area: %.2f


assistant: ```c
int main() {
  double r;
  double Pi = 3.14;
  scanf("%lf", &r);
  double perimeter = 2 * Pi * r;
  double area = Pi * r * r;
  printf("Perimeter: %.2lf\nArea: %.2f\n", perimeter, area);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  D20(%rip),%xmm1
  movapd %xmm0,%xmm2
  mulsd  D13(%rip),%xmm2
  mulsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D20
data_type: f64
name: retrieve_data
arguments: data_tag: D13
data_type: byte[8]
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D0: %lf

tool: D20: 3.14

tool: {"D13": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x19,0x40]}

tool: D2: Perimeter: %.2lf
Area: %.2f


assistant: ```c
int main() {
  double r;
  double Pi = 3.14;
  scanf("%lf", &r);
  double perimeter = 2 * Pi * r;
  double area = Pi * r * r;
  printf("Perimeter: %.2lf\nArea: %.2f\n", perimeter, area);
  return 0;
}
```