ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<float_to_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L3:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void float_to_double(double *copy, int beg, int end, float *vec) {
  int i;
  copy = copy + beg;
  vec = vec + beg;
  for (i = end - beg + 1; i; i--) {
    *copy++ = *vec++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<float_to_double>:
  endbr64
  mov    %rdi,%r8
  mov    %rcx,%rdi
  movslq %esi,%rax
  lea    (%r8,%rax,8),%rcx
  lea    (%rdi,%rax,4),%rdi
  sub    %esi,%edx
  cmp    $0xffffffff,%edx
  je     L1
  lea    0x1(%rdx),%edx
  shl    $0x2,%rdx
  mov    $0x0,%eax
L11:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi,%rax,1),%xmm0
  movsd  %xmm0,(%rcx,%rax,2)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
L1:
  ret
```

assistant: ```c
void float_to_double(double *copy, int beg, int end, float *vec) {
  int i;
  copy = copy + beg;
  vec = vec + beg;
  for (i = end - beg + 1; i; i--) {
    *copy++ = *vec++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<float_to_double>:
  endbr64
  mov    %rcx,%r8
  movslq %esi,%rax
  sub    %esi,%edx
  lea    (%rdi,%rax,8),%rcx
  lea    (%r8,%rax,4),%rdi
  cmp    $0xffffffff,%edx
  je     L7
  add    $0x1,%edx
  xor    %eax,%eax
  shl    $0x2,%rdx
  nopw   0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi,%rax,1),%xmm0
  movsd  %xmm0,(%rcx,%rax,2)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L6
L7:
  ret
```

assistant: ```c
void float_to_double(double *copy, int beg, int end, float *vec) {
  int i;
  copy = copy + beg;
  vec = vec + beg;
  for (i = end - beg + 1; i; i--) {
    *copy++ = *vec++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<float_to_double>:
  endbr64
  sub    %esi,%edx
  movslq %esi,%rax
  mov    %rcx,%r8
  mov    %edx,%esi
  lea    (%rdi,%rax,8),%rcx
  lea    (%r8,%rax,4),%rdi
  add    $0x1,%esi
  je     L39
  mov    %esi,%r8d
  cmp    $0x2,%edx
  jbe    L29
  mov    %esi,%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  xchg   %ax,%ax
L30:
  movups (%rdi,%rax,1),%xmm1
  movhlps %xmm1,%xmm0
  cvtps2pd %xmm1,%xmm2
  movups %xmm2,(%rcx,%rax,2)
  cvtps2pd %xmm0,%xmm1
  movups %xmm1,0x10(%rcx,%rax,2)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L30
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  sub    %eax,%esi
  lea    (%rcx,%rdx,8),%rcx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %eax,%r8d
  je     L39
L29:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  cmp    $0x1,%esi
  je     L39
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rdi),%xmm0
  movsd  %xmm0,0x8(%rcx)
  cmp    $0x2,%esi
  je     L39
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rdi),%xmm0
  movsd  %xmm0,0x10(%rcx)
L39:
  ret
```

assistant: ```c
void float_to_double(double *copy, int beg, int end, float *vec) {
  int i;
  copy = copy + beg;
  vec = vec + beg;
  for (i = end - beg + 1; i; i--) {
    *copy++ = *vec++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<classify_region>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x4(%rsp)
  mov    %ecx,0x10(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x14(%rsp)
  movl   $0x0,(%rsi)
  mov    0x20(%rdi),%eax
  mov    %eax,0x2c(%rsp)
  test   %eax,%eax
  je     L16
  mov    %rdi,%r14
  mov    %rsi,%r13
  movss  (%rdi),%xmm5
  movss  0x10(%rdi),%xmm4
  jle    L55
  cvttss2si %xmm0,%eax
  mov    %eax,0x18(%rsp)
  cvttss2si %xmm1,%eax
  mov    %eax,0x1c(%rsp)
  mulss  %xmm2,%xmm5
  cvttss2si %xmm5,%eax
  mov    %eax,0x20(%rsp)
  mulss  %xmm2,%xmm4
  cvttss2si %xmm4,%eax
  mov    %eax,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  mov    $0xc,%ebx
  jmp    L0
L23:
  movslq %ebx,%rax
  movss  (%r14,%rax,4),%xmm3
  add    $0x4,%ebx
  comiss 0x0(%r13),%xmm3
  jae    L2
  addl   $0x1,0x28(%rsp)
  mov    0x28(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  je     L55
L0:
  movslq %ebx,%rax
  mov    (%r14,%rax,4),%r15d
  add    $0x4,%ebx
  test   %r15d,%r15d
  jle    L23
  mov    $0x0,%ebp
L44:
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%r12
  sub    $0x8,%rsp
  mov    0x80(%rsp),%eax
  push   %rax
  mov    0x80(%rsp),%eax
  push   %rax
  mov    0x2c(%rsp),%eax
  push   %rax
  push   0x28(%rsp)
  mov    0x38(%rsp),%eax
  push   %rax
  mov    0x34(%rsp),%r9d
  mov    0x54(%rsp),%r8d
  mov    0x50(%rsp),%ecx
  mov    0x4c(%rsp),%edx
  mov    0x48(%rsp),%esi
  mov    %r12,%rdi
  call   <get_dtree_output@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0x0(%r13),%xmm0
  movss  %xmm0,0x0(%r13)
  add    $0x30,%rsp
  mov    %r12,%rdi
  call   <get_dtree_size@plt>
  add    %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r15d
  jne    L44
  jmp    L23
L55:
  movss  0x0(%r13),%xmm0
  subss  %xmm3,%xmm0
  movss  %xmm0,0x0(%r13)
  movl   $0x1,0x2c(%rsp)
L16:
  mov    0x2c(%rsp),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  movl   $0xffffffff,0x2c(%rsp)
  jmp    L16
```

assistant: ```c
int classify_region(void *od, float *o, float r, float c, float s, int cost, int sint, uint8_t pixels[], int nrows, int ncols, int ldim) {
  int8_t *ptr;
  int loc;
  int32_t nstages;
  float tsr, tsc;
  int i, j;
  int ir, ic, isr, isc;
  float threshold;
  ptr = (int8_t *)od;
  loc = 0;
  *o = 0.0f;
  tsr = *(float *)&ptr[0 * sizeof(float)];
  tsc = *(float *)&ptr[1 * sizeof(float)];
  loc += 2 * sizeof(float);
  ir = (int)(r);
  ic = (int)(c);
  isr = (int)(s * tsr);
  isc = (int)(s * tsc);
  nstages = *(int32_t *)&ptr[loc];
  loc += sizeof(int32_t);
  if (!nstages)
    return 0;
  i = 0;
  while (i < nstages) {
    int numtrees;
    numtrees = *(int32_t *)&ptr[loc];
    loc += sizeof(int32_t);
    for (j = 0; j < numtrees; ++j) {
      *o += get_dtree_output(&ptr[loc], ir, ic, isr, isc, cost, sint, pixels, nrows, ncols, ldim);
      loc += get_dtree_size(&ptr[loc]);
    }
    threshold = *(float *)&ptr[loc];
    loc += sizeof(float);
    if (*o <= threshold)
      return -1;
    ++i;
  }
  *o = *o - threshold;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string

tool: D9: %s

tool: D12: hello %s


assistant: ```c
int main(void) {
  char str[100];
  scanf("%s", str);
  printf("hello %s\n", str);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D8: %s

tool: D4: hello %s


assistant: ```c
int main(void) {
  char str[100];
  scanf("%s", str);
  printf("hello %s\n", str);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string

tool: D16: %s

tool: D15: hello %s


assistant: ```c
int main(void) {
  char str[100];
  scanf("%s", str);
  printf("hello %s\n", str);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D12: %s

tool: D0: hello %s


assistant: ```c
int main(void) {
  char str[100];
  scanf("%s", str);
  printf("hello %s\n", str);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<heap_sort_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <heapify_down@plt>
  jmp    L5
L19:
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <swap_data@plt>
  subl   $0x1,-0xc(%rbp)
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <shift_down@plt>
L5:
  cmpl   $0x0,-0xc(%rbp)
  jg     L19
  nop
  leave
  ret
```

assistant: ```c
void heap_sort_d(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  char *data = array;
  int count = asize - 1;
  heapify_down(array, asize, esize, compare);
  while (count > 0) {
    swap_data(&data[(0) * esize], &data[(count)*esize], esize);
    count--;
    shift_down(array, 0, count, esize, compare);
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<heap_sort_d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    %rcx,%r14
  lea    -0x1(%rsi),%ebx
  mov    $0x0,%eax
  call   <heapify_down@plt>
  test   %ebx,%ebx
  jle    L8
  mov    %r12d,%r15d
  neg    %r15d
  movslq %r15d,%r15
  mov    %ebx,%ebp
  imul   %r12d,%ebp
  movslq %ebp,%rbp
  add    %r13,%rbp
L9:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <swap_data@plt>
  sub    $0x1,%ebx
  mov    %r14,%r8
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <shift_down@plt>
  add    %r15,%rbp
  test   %ebx,%ebx
  jne    L9
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void heap_sort_d(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  char *data = array;
  int count = asize - 1;
  heapify_down(array, asize, esize, compare);
  while (count > 0) {
    swap_data(&data[(0) * esize], &data[(count)*esize], esize);
    count--;
    shift_down(array, 0, count, esize, compare);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heap_sort_d>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  call   <heapify_down@plt>
  test   %ebx,%ebx
  jle    L3
  mov    %ebx,%ebp
  mov    %r12d,%r15d
  imul   %r12d,%ebp
  neg    %r15d
  movslq %r15d,%r15
  movslq %ebp,%rbp
  add    %r13,%rbp
  xchg   %ax,%ax
L13:
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <swap_data@plt>
  sub    $0x1,%ebx
  mov    %r14,%r8
  mov    %r12d,%ecx
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <shift_down@plt>
  add    %r15,%rbp
  test   %ebx,%ebx
  jne    L13
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void heap_sort_d(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  char *data = array;
  int count = asize - 1;
  heapify_down(array, asize, esize, compare);
  while (count > 0) {
    swap_data(&data[(0) * esize], &data[(count)*esize], esize);
    count--;
    shift_down(array, 0, count, esize, compare);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heap_sort_d>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  call   <heapify_down@plt>
  test   %ebx,%ebx
  jle    L12
  mov    %ebx,%ebp
  mov    %r12d,%r15d
  imul   %r12d,%ebp
  neg    %r15d
  movslq %r15d,%r15
  movslq %ebp,%rbp
  add    %r13,%rbp
  xchg   %ax,%ax
L7:
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <swap_data@plt>
  sub    $0x1,%ebx
  mov    %r14,%r8
  mov    %r12d,%ecx
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <shift_down@plt>
  add    %r15,%rbp
  test   %ebx,%ebx
  jne    L7
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void heap_sort_d(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  char *data = array;
  int count = asize - 1;
  heapify_down(array, asize, esize, compare);
  while (count > 0) {
    swap_data(&data[(0) * esize], &data[(count)*esize], esize);
    count--;
    shift_down(array, 0, count, esize, compare);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<num_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L17:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int num_len(int n) {
  int len;
  len = 0;
  while (n /= 10)
    len++;
  return (len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_len>:
  endbr64
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%edi
  sub    %edi,%edx
  je     L13
  mov    $0x0,%ecx
L5:
  add    $0x1,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  jne    L5
L25:
  mov    %ecx,%eax
  ret
L13:
  mov    %edx,%ecx
  jmp    L25
```

assistant: ```c
int num_len(int n) {
  int len;
  len = 0;
  while (n /= 10)
    len++;
  return (len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<num_len>:
  endbr64
  movslq %edi,%rdx
  sar    $0x1f,%edi
  xor    %r8d,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %edi,%edx
  je     L2
  nopl   0x0(%rax)
L17:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L17
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int num_len(int n) {
  int len;
  len = 0;
  while (n /= 10)
    len++;
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<num_len>:
  endbr64
  movslq %edi,%rdx
  sar    $0x1f,%edi
  xor    %r8d,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %edi,%edx
  je     L9
  nopl   0x0(%rax)
L19:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L19
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int num_len(int n) {
  int len;
  len = 0;
  while (n /= 10)
    len++;
  return (len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D3
type_infered: string

tool: D19: %*[^
]

tool: D3: %*c

assistant: ```c
void clear(void) {
  scanf("%*[^\n]");
  scanf("%*c");
}
```
user: Translate the below assembly code into C programming language:

```asm
<clear>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string
name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D7: %*[^
]

tool: D6: %*c

assistant: ```c
void clear(void) {
  scanf("%*[^\n]");
  scanf("%*c");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clear>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <scanf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D15: %*[^
]

tool: D3: %*c

assistant: ```c
void clear(void) {
  scanf("%*[^\n]");
  scanf("%*c");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clear>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <scanf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D15: %*[^
]

tool: D18: %*c

assistant: ```c
void clear(void) {
  scanf("%*[^\n]");
  scanf("%*c");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  cltq
  shl    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L32
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  jmp    L6
L22:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  mov    %al,(%rbx)
  addq   $0x1,-0x20(%rbp)
L6:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x18(%rbp),%rax
  jmp    L1
L32:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  size_t i;
  char *str_new;
  i = 0;
  str_new = malloc(sizeof(str_new) * ft_strlen((char *)s) + 1);
  if (str_new) {
    ft_strcpy(str_new, s);
    while (s[i]) {
      str_new[i] = (*f)(s[i]);
      i++;
    }
    return (str_new);
  } else
    return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <ft_strlen@plt>
  lea    0x1(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L27
  mov    $0x0,%ebx
L13:
  movsbl %dil,%edi
  call   *%r13
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%edi
  test   %dil,%dil
  jne    L13
L27:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  size_t i;
  char *str_new;
  i = 0;
  str_new = malloc(sizeof(str_new) * ft_strlen((char *)s) + 1);
  if (str_new) {
    ft_strcpy(str_new, s);
    while (s[i]) {
      str_new[i] = (*f)(s[i]);
      i++;
    }
    return (str_new);
  } else
    return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strmap>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  lea    0x1(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L23
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <ft_strcpy@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L23
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L13:
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L13
L23:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  size_t i;
  char *str_new;
  i = 0;
  str_new = malloc(sizeof(str_new) * ft_strlen((char *)s) + 1);
  if (str_new) {
    ft_strcpy(str_new, s);
    while (s[i]) {
      str_new[i] = (*f)(s[i]);
      i++;
    }
    return (str_new);
  } else
    return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strmap>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  lea    0x1(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <ft_strcpy@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L0
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L6:
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L6
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  size_t i;
  char *str_new;
  i = 0;
  str_new = malloc(sizeof(str_new) * ft_strlen((char *)s) + 1);
  if (str_new) {
    ft_strcpy(str_new, s);
    while (s[i]) {
      str_new[i] = (*f)(s[i]);
      i++;
    }
    return (str_new);
  } else
    return (NULL);
}
```