ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0xffffffff,(%rax)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L95
L73:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L108
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L108
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L108:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L7
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L7
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L7
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L7:
  cmpl   $0x0,-0x4(%rbp)
  js     L75
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L103
L75:
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L95:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L73
  jmp    L66
L103:
  nop
L66:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int32_t trim(char *str, int32_t slen, int32_t *end) {
  int32_t i, j;
  int32_t start = -1;
  *end = -1;
  for (i = 0, j = slen - 1; i < slen; i++, j--) {
    if (start == -1 && !isspace((int32_t)str[i]))
      start = i;
    if (*end == -1 && str[j] != '\0' && !isspace((int32_t)str[j])) {
      *end = j + 1;
      if (j < slen)
        str[*end] = '\0';
    }
    if (start > -1 && *end > -1)
      break;
  }
  return start;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  movl   $0xffffffff,(%rdx)
  test   %esi,%esi
  jle    L53
  mov    %rdi,%r15
  mov    %rdx,%r13
  lea    -0x1(%rsi),%ebp
  movslq %ebp,%rbp
  mov    %esi,%r14d
  mov    $0x0,%ebx
  mov    $0xffffffff,%r12d
  jmp    L135
L6:
  movsbl (%r15,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L41
  mov    %ebx,%r12d
  jmp    L14
L144:
  mov    %eax,%r12d
L82:
  movzbl (%r15,%rbp,1),%edi
  test   %dil,%dil
  je     L25
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L25
  mov    0xc(%rsp),%ecx
  mov    %ecx,%eax
  sub    0x8(%rsp),%eax
  mov    %eax,0x0(%r13)
  cmp    %ebp,%ecx
  jle    L81
  cltq
  movb   $0x0,(%r15,%rax,1)
  jmp    L81
L53:
  mov    $0xffffffff,%r12d
  jmp    L18
L41:
  mov    0x0(%r13),%eax
  cmp    $0xffffffff,%eax
  je     L144
L25:
  add    $0x1,%rbx
  sub    $0x1,%rbp
  cmp    %r14,%rbx
  je     L18
L135:
  mov    %ebx,0x8(%rsp)
  mov    %ebx,0x4(%rsp)
  cmp    $0xffffffff,%r12d
  je     L6
L14:
  cmpl   $0xffffffff,0x0(%r13)
  je     L82
L81:
  test   %r12d,%r12d
  js     L25
  cmpl   $0x0,0x0(%r13)
  js     L25
L18:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int32_t trim(char *str, int32_t slen, int32_t *end) {
  int32_t i, j;
  int32_t start = -1;
  *end = -1;
  for (i = 0, j = slen - 1; i < slen; i++, j--) {
    if (start == -1 && !isspace((int32_t)str[i]))
      start = i;
    if (*end == -1 && str[j] != '\0' && !isspace((int32_t)str[j])) {
      *end = j + 1;
      if (j < slen)
        str[*end] = '\0';
    }
    if (start > -1 && *end > -1)
      break;
  }
  return start;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  movl   $0xffffffff,(%rdx)
  test   %esi,%esi
  jle    L101
  push   %r15
  mov    $0xffffffff,%r8d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  jmp    L115
  nopl   0x0(%rax,%rax,1)
L128:
  cmpl   $0xffffffff,0x0(%r13)
  je     L145
L59:
  mov    0x0(%r13),%r12d
L136:
  test   %r12d,%r12d
  jns    L75
L7:
  add    $0x1,%ebx
  sub    $0x1,%ebp
  cmp    %ebx,%esi
  jle    L75
L115:
  cmp    $0xffffffff,%r8d
  jne    L128
  mov    0x0(%r13),%r12d
  movslq %ebx,%r15
  add    %ebp,%ebx
L80:
  movsbl (%r14,%r15,1),%edi
  mov    %esi,0xc(%rsp)
  mov    %ebx,%ebp
  mov    %r15d,0x8(%rsp)
  sub    %r15d,%ebp
  call   <isspace@plt>
  mov    0xc(%rsp),%esi
  mov    %r15d,%r8d
  test   %eax,%eax
  jne    L54
  mov    %r15d,%ebx
  cmp    $0xffffffff,%r12d
  jne    L136
  movslq %ebp,%rax
  movsbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L7
L130:
  mov    %esi,0xc(%rsp)
  mov    %r8d,0x8(%rsp)
  call   <isspace@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%esi
  test   %eax,%eax
  jne    L59
  lea    0x1(%rbp),%eax
  mov    %eax,0x0(%r13)
  mov    %eax,%r12d
  cmp    %ebp,%esi
  jle    L136
L147:
  cltq
  movb   $0x0,(%r14,%rax,1)
  cmp    $0xffffffff,%r8d
  jne    L59
  add    $0x1,%ebx
  sub    $0x1,%ebp
  cmp    %ebx,%esi
  jg     L115
L75:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L145:
  movslq %ebp,%rax
  mov    $0xffffffff,%r12d
  movsbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L136
  jmp    L130
  nopl   0x0(%rax)
L54:
  cmp    $0xffffffff,%r12d
  je     L84
  add    $0x1,%r15
  cmp    %r15d,%esi
  jg     L80
  mov    $0xffffffff,%r8d
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L84:
  movslq %ebp,%rax
  movsbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L105
  mov    %esi,0x8(%rsp)
  call   <isspace@plt>
  mov    0x8(%rsp),%esi
  test   %eax,%eax
  jne    L105
  lea    0x1(%rbp),%eax
  mov    %eax,0x0(%r13)
  cmp    %ebp,%esi
  jle    L105
  mov    %r15d,%ebx
  mov    $0xffffffff,%r8d
  jmp    L147
  nopw   0x0(%rax,%rax,1)
L105:
  mov    %r15d,%ebx
  mov    $0xffffffff,%r8d
  jmp    L7
L101:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int32_t trim(char *str, int32_t slen, int32_t *end) {
  int32_t i, j;
  int32_t start = -1;
  *end = -1;
  for (i = 0, j = slen - 1; i < slen; i++, j--) {
    if (start == -1 && !isspace((int32_t)str[i]))
      start = i;
    if (*end == -1 && str[j] != '\0' && !isspace((int32_t)str[j])) {
      *end = j + 1;
      if (j < slen)
        str[*end] = '\0';
    }
    if (start > -1 && *end > -1)
      break;
  }
  return start;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  movl   $0xffffffff,(%rdx)
  test   %esi,%esi
  jle    L10
  push   %r15
  mov    $0xffffffff,%r8d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  jmp    L127
  nopl   0x0(%rax,%rax,1)
L9:
  cmpl   $0xffffffff,0x0(%r13)
  je     L71
L219:
  mov    0x0(%r13),%r12d
L58:
  test   %r12d,%r12d
  jns    L88
L217:
  add    $0x1,%ebx
  sub    $0x1,%ebp
  cmp    %ebx,%esi
  jle    L88
L127:
  cmp    $0xffffffff,%r8d
  jne    L9
  mov    0x0(%r13),%r12d
  movslq %ebx,%r15
  add    %ebp,%ebx
L3:
  movsbl (%r14,%r15,1),%edi
  mov    %esi,0xc(%rsp)
  mov    %ebx,%ebp
  mov    %r15d,0x8(%rsp)
  sub    %r15d,%ebp
  call   <isspace@plt>
  mov    0xc(%rsp),%esi
  mov    %r15d,%r8d
  test   %eax,%eax
  jne    L116
  mov    %r15d,%ebx
  cmp    $0xffffffff,%r12d
  jne    L58
  movslq %ebp,%rax
  movsbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L217
L40:
  mov    %esi,0xc(%rsp)
  mov    %r8d,0x8(%rsp)
  call   <isspace@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%esi
  test   %eax,%eax
  jne    L219
  lea    0x1(%rbp),%eax
  mov    %eax,0x0(%r13)
  mov    %eax,%r12d
  cmp    %ebp,%esi
  jle    L58
L78:
  cltq
  movb   $0x0,(%r14,%rax,1)
  cmp    $0xffffffff,%r8d
  jne    L219
  add    $0x1,%ebx
  sub    $0x1,%ebp
  cmp    %ebx,%esi
  jg     L127
L88:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L71:
  movslq %ebp,%rax
  mov    $0xffffffff,%r12d
  movsbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L58
  jmp    L40
  nopl   0x0(%rax)
L116:
  cmp    $0xffffffff,%r12d
  je     L66
  add    $0x1,%r15
  cmp    %r15d,%esi
  jg     L3
  mov    $0xffffffff,%r8d
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L66:
  movslq %ebp,%rax
  movsbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L48
  mov    %esi,0x8(%rsp)
  call   <isspace@plt>
  mov    0x8(%rsp),%esi
  test   %eax,%eax
  jne    L48
  lea    0x1(%rbp),%eax
  mov    %eax,0x0(%r13)
  cmp    %ebp,%esi
  jle    L48
  mov    %r15d,%ebx
  mov    $0xffffffff,%r8d
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %r15d,%ebx
  mov    $0xffffffff,%r8d
  jmp    L217
L10:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int32_t trim(char *str, int32_t slen, int32_t *end) {
  int32_t i, j;
  int32_t start = -1;
  *end = -1;
  for (i = 0, j = slen - 1; i < slen; i++, j--) {
    if (start == -1 && !isspace((int32_t)str[i]))
      start = i;
    if (*end == -1 && str[j] != '\0' && !isspace((int32_t)str[j])) {
      *end = j + 1;
      if (j < slen)
        str[*end] = '\0';
    }
    if (start > -1 && *end > -1)
      break;
  }
  return start;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x62d,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isLeapYear@plt>
  test   %rax,%rax
  je     L28
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L22
L28:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string

tool: D8: Please enter a year


tool: D27: %d

tool: D9: is a leap year


tool: D11: is not a leap year


assistant: ```c
int main(int argc, char *argv[]) {
  int year;
  printf("Please enter a year\n");
  scanf("%d", &year);
  assert(year >= 1582);
  if (isLeapYear(year)) {
    printf("is a leap year\n");
  } else {
    printf("is not a leap year\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x62d,0x4(%rsp)
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%edi
  call   <isLeapYear@plt>
  test   %rax,%rax
  je     L8
  lea    D35(%rip),%rdi
  call   <printf@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D35
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string

tool: D12: Please enter a year


tool: D11: %d

tool: D35: is a leap year


tool: D19: is not a leap year


assistant: ```c
int main(int argc, char *argv[]) {
  int year;
  printf("Please enter a year\n");
  scanf("%d", &year);
  assert(year >= 1582);
  if (isLeapYear(year)) {
    printf("is a leap year\n");
  } else {
    printf("is not a leap year\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  cmpl   $0x62d,0x4(%rsp)
  setg   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%edi
  call   <isLeapYear@plt>
  test   %rax,%rax
  je     L22
  lea    D13(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D10
type: string

tool: D26: Please enter a year


tool: D11: %d

tool: D13: is a leap year


tool: D10: is not a leap year


assistant: ```c
int main(int argc, char *argv[]) {
  int year;
  printf("Please enter a year\n");
  scanf("%d", &year);
  assert(year >= 1582);
  if (isLeapYear(year)) {
    printf("is a leap year\n");
  } else {
    printf("is not a leap year\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  cmpl   $0x62d,0x4(%rsp)
  setg   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%edi
  call   <isLeapYear@plt>
  test   %rax,%rax
  je     L12
  lea    D19(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D30
type_guessed: string

tool: D0: Please enter a year


tool: D1: %d

tool: D19: is a leap year


tool: D30: is not a leap year


assistant: ```c
int main(int argc, char *argv[]) {
  int year;
  printf("Please enter a year\n");
  scanf("%d", &year);
  assert(year >= 1582);
  if (isLeapYear(year)) {
    printf("is a leap year\n");
  } else {
    printf("is not a leap year\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L3
  cmpb   $0x39,-0x4(%rbp)
  jle    L7
L3:
  mov    $0x0,%eax
  jmp    L17
L7:
  mov    $0x1,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int is_digit(char d) {
  if (d < '0' || d > '9')
    return (0);
  else
    return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_digit>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_digit(char d) {
  if (d < '0' || d > '9')
    return (0);
  else
    return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_digit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_digit(char d) {
  if (d < '0' || d > '9')
    return (0);
  else
    return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_digit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_digit(char d) {
  if (d < '0' || d > '9')
    return (0);
  else
    return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<macttGetSep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <tt_getSep@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *macttGetSep(char *arg) {
  *arg = tt_getSep();
  arg[1] = '\0';
  return arg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<macttGetSep>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <tt_getSep@plt>
  mov    %al,(%rbx)
  movb   $0x0,0x1(%rbx)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *macttGetSep(char *arg) {
  *arg = tt_getSep();
  arg[1] = '\0';
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<macttGetSep>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <tt_getSep@plt>
  movb   $0x0,0x1(%r12)
  mov    %al,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *macttGetSep(char *arg) {
  *arg = tt_getSep();
  arg[1] = '\0';
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<macttGetSep>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <tt_getSep@plt>
  movb   $0x0,0x1(%r12)
  mov    %al,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *macttGetSep(char *arg) {
  *arg = tt_getSep();
  arg[1] = '\0';
  return arg;
}
```
user: What is the c source code of the assembly code below?

```asm
<basis_dmatrix_zeiger_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <basis_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L15
L22:
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  movq   $0x0,-0x10(%rbp)
  jmp    L17
L34:
  mov    -0x10(%rbp),%rax
  imul   -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L34
  mov    -0x8(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
double **basis_dmatrix_zeiger_alloc(double *a, long zn, long sn) {
  double **m;
  long i;
  m = (double **)basis_malloc((size_t)(zn + 1) * sizeof(double *));
  if (m == NULL)
    return NULL;
  m[0] = a;
#pragma omp parallel for
  for (i = 0; i < zn; i++)
    m[i + 1] = a + i * sn;
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<basis_dmatrix_zeiger_alloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  lea    0x8(,%rsi,8),%r12
  mov    %r12,%rdi
  call   <basis_malloc@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  mov    %rbx,(%rax)
  test   %r13,%r13
  jle    L37
  lea    0x0(,%rbp,8),%rsi
  mov    %rbx,%rcx
  lea    0x8(%rax),%rdx
  add    %r12,%rax
L22:
  mov    %rcx,(%rdx)
  add    %rsi,%rcx
  add    $0x8,%rdx
  cmp    %rax,%rdx
  jne    L22
L37:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0x0,%edi
  jmp    L37
```

assistant: ```c
double **basis_dmatrix_zeiger_alloc(double *a, long zn, long sn) {
  double **m;
  long i;
  m = (double **)basis_malloc((size_t)(zn + 1) * sizeof(double *));
  if (m == NULL)
    return NULL;
  m[0] = a;
#pragma omp parallel for
  for (i = 0; i < zn; i++)
    m[i + 1] = a + i * sn;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basis_dmatrix_zeiger_alloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x8(,%rsi,8),%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <basis_malloc@plt>
  test   %rax,%rax
  je     L26
  mov    %rbx,(%rax)
  test   %r13,%r13
  jle    L26
  lea    0x0(,%rbp,8),%rdx
  mov    %rbx,%rdi
  lea    0x8(%rax),%rcx
  lea    (%r12,%rax,1),%rsi
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,(%rcx)
  add    $0x8,%rcx
  add    %rdx,%rdi
  cmp    %rsi,%rcx
  jne    L6
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **basis_dmatrix_zeiger_alloc(double *a, long zn, long sn) {
  double **m;
  long i;
  m = (double **)basis_malloc((size_t)(zn + 1) * sizeof(double *));
  if (m == NULL)
    return NULL;
  m[0] = a;
#pragma omp parallel for
  for (i = 0; i < zn; i++)
    m[i + 1] = a + i * sn;
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basis_dmatrix_zeiger_alloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x8(,%rsi,8),%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <basis_malloc@plt>
  test   %rax,%rax
  je     L13
  mov    %rbx,(%rax)
  test   %r13,%r13
  jle    L13
  lea    0x0(,%rbp,8),%rdx
  mov    %rbx,%rdi
  lea    0x8(%rax),%rcx
  lea    (%r12,%rax,1),%rsi
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rdi,(%rcx)
  add    $0x8,%rcx
  add    %rdx,%rdi
  cmp    %rsi,%rcx
  jne    L17
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **basis_dmatrix_zeiger_alloc(double *a, long zn, long sn) {
  double **m;
  long i;
  m = (double **)basis_malloc((size_t)(zn + 1) * sizeof(double *));
  if (m == NULL)
    return NULL;
  m[0] = a;
#pragma omp parallel for
  for (i = 0; i < zn; i++)
    m[i + 1] = a + i * sn;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L17:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jle    L35
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L17
  jmp    L25
L35:
  nop
L25:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t write_all(int socket, void *buffer, ssize_t size) {
  ssize_t i = 0, res = 0;
  while (i < size) {
    res = write(socket, buffer + i, size - i);
    if (res < 1)
      break;
    i += res;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jle    L16
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L35:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jle    L9
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jg     L35
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%ebx
  jmp    L9
```

assistant: ```c
ssize_t write_all(int socket, void *buffer, ssize_t size) {
  ssize_t i = 0, res = 0;
  while (i < size) {
    res = write(socket, buffer + i, size - i);
    if (res < 1)
      break;
    i += res;
  }
  return i;
}
```