user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<security>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x4(%rsp)
  mov    %esi,0x30(%rsp)
  mov    %rdx,%rbx
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x20(%rsp)
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L103
L142:
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L50
L146:
  mov    0x30(%rsp),%eax
  test   %eax,%eax
  jle    L153
  mov    %eax,%eax
  mov    0x10(%rsp),%rdi
  lea    (%rdi,%rax,4),%rcx
  mov    %rdi,%rax
  sub    %rdi,%rbx
L161:
  mov    (%rbx,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L161
L153:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L14
  mov    0x8(%rsp),%rdi
  mov    %rdi,%rbx
  mov    %eax,%eax
  lea    (%rdi,%rax,4),%r12
  mov    %rdi,%rax
L145:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L145
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    0x30(%rsp),%eax
  lea    -0x1(%rax),%eax
  lea    0x4(,%rax,4),%rax
  mov    %rax,0x28(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%edi
  jmp    L26
L103:
  lea    D68(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L142
L50:
  lea    D68(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L146
L75:
  mov    (%rbx),%eax
  cmp    $0x1,%eax
  jne    L102
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L75
  jmp    L44
L102:
  mov    $0x0,%eax
L44:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L213:
  mov    %edi,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    0x20(%rsp),%r14
  mov    $0x0,%r15d
  mov    %ebp,0x34(%rsp)
  mov    %rbx,0x38(%rsp)
  mov    0x10(%rsp),%rbx
  mov    0x28(%rsp),%rbp
L144:
  lea    (%r15,%rbx,1),%rax
  mov    (%r14),%rdx
  mov    (%rax),%esi
  add    (%rdx,%r15,1),%esi
  mov    %esi,(%rax)
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r15
  cmp    %rbp,%r15
  jne    L144
  mov    0x34(%rsp),%ebp
  mov    0x38(%rsp),%rbx
L104:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,0x0(%r13)
  mov    %ebp,%edi
  mov    %ebp,%edx
  jmp    L26
L162:
  cmp    %edx,0x30(%rsp)
  je     L213
L188:
  add    $0x1,%edi
  cmp    %edi,0x4(%rsp)
  jle    L75
L26:
  movslq %edi,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,4),%r13
  mov    0x0(%r13),%ebp
  test   %ebp,%ebp
  jne    L188
  mov    0x30(%rsp),%esi
  test   %esi,%esi
  jle    L222
  lea    0x0(,%rax,8),%r14
  mov    0x18(%rsp),%rcx
  mov    (%rcx,%rax,8),%rcx
  add    %edx,%esi
  mov    0x10(%rsp),%r10
  mov    %r10,%rax
  sub    %r10,%rcx
L131:
  mov    (%rax),%r9d
  cmp    %r9d,(%rcx,%rax,1)
  jg     L162
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %esi,%edx
  jne    L131
  mov    %esi,%edx
  jmp    L162
L222:
  cmp    %edx,0x30(%rsp)
  jne    L188
  mov    %edi,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L104
L14:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L44
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D68
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string

tool: D8: sequence:

tool: D68: malloc all error

tool: D28: p%d: 

tool: D9: %d 

assistant: ```c
int security(int n, int m, int *available, int **need, int **allocation) {
  int *work = NULL;
  int *finish = NULL;
  int i = 0;
  int j = 0;
  int k = 0;
  int num = 0;
  if ((work = (int *)malloc(m * sizeof(int))) == NULL) {
    perror("malloc all error");
    exit(1);
  }
  if ((finish = (int *)malloc(n * sizeof(int))) == NULL) {
    perror("malloc all error");
    exit(1);
  }
  for (i = 0; i < m; i++) {
    work[i] = available[i];
  }
  for (i = 0; i < n; i++) {
    finish[i] = 0;
  }
  printf("sequence:\n");
  for (i = 0; i < n; i++) {
    if (finish[i] == 0) {
      for (j = 0; j < m; j++) {
        if (need[i][j] <= work[j]) {
          num++;
        } else {
          break;
        }
      }
      if (num == m) {
        num = 0;
        printf("p%d: ", i);
        for (k = 0; k < m; k++) {
          work[k] = work[k] + allocation[i][k];
          printf("%d ", work[k]);
        }
        printf("\n");
        finish[i] = 1;
        i = -1;
      } else {
        continue;
      }
    } else {
      continue;
    }
  }
  for (i = 0; i < n; i++) {
    if (finish[i] != 1) {
      return 0;
    }
  }
  return 1;
}
```