ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <containsNearbyDuplicate@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 0, 1, 1};
  printf("%d\n", containsNearbyDuplicate(arr, 4, 1));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <containsNearbyDuplicate@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 0, 1, 1};
  printf("%d\n", containsNearbyDuplicate(arr, 4, 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%esi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x1,(%rsp)
  movabs $0x100000001,%rax
  mov    %rax,0x8(%rsp)
  call   <containsNearbyDuplicate@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 0, 1, 1};
  printf("%d\n", containsNearbyDuplicate(arr, 4, 1));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%esi
  mov    $0x1,%edx
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <containsNearbyDuplicate@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: byte[16]
name: read_data
arguments: data_label: D19
data_type: string

tool: {"D7": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D19: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 0, 1, 1};
  printf("%d\n", containsNearbyDuplicate(arr, 4, 1));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L10
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L10:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D17: 2

tool: D11: a


tool: D1: b


assistant: ```c
int main() {
  char *s1 = 0;
  char *s2 = "2";
  void **s = (void **)&s1;
  if (*s)
    printf("a\n");
  else
    printf("b\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: b


assistant: ```c
int main() {
  char *s1 = 0;
  char *s2 = "2";
  void **s = (void **)&s1;
  if (*s)
    printf("a\n");
  else
    printf("b\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: b


assistant: ```c
int main() {
  char *s1 = 0;
  char *s2 = "2";
  void **s = (void **)&s1;
  if (*s)
    printf("a\n");
  else
    printf("b\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: b


assistant: ```c
int main() {
  char *s1 = 0;
  char *s2 = "2";
  void **s = (void **)&s1;
  if (*s)
    printf("a\n");
  else
    printf("b\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f2au_loadandwrite_sram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x10000,-0x20(%rbp)
  je     L25
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  mov    $0x10000,%ecx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printerr@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L25:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <prepare_loadandwrite_sram@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0xffffffff,%eax
  jmp    L7
L0:
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x10000
  mov    $0x0,%r9d
  mov    $0x400,%r8d
  mov    $0x10000,%ecx
  mov    $0x0,%edx
  mov    $0xe0f0000,%esi
  mov    %rax,%rdi
  call   <cart_direct_write@plt>
  add    $0x10,%rsp
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: Could not write %i bytes from file %s to SRAM, %i bytes expected


assistant: ```c
int f2au_loadandwrite_sram(const char *file, int offset, int size) {
  int ret;
  unsigned char *sram;
  if (size != 65536) {
    printerr("Could not write %i bytes from file %s to SRAM, %i bytes expected\n", size, file, 65536);
    return -1;
  }
  if ((sram = prepare_loadandwrite_sram(file, offset, size)) == NULL)
    return -1;
  ret = cart_direct_write(sram, (0x0e000000 + 0x0f0000), 0, 65536, 1024, 0, 65536);
  free(sram);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f2au_loadandwrite_sram>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x10000,%edx
  jne    L36
  mov    $0x10000,%edx
  call   <prepare_loadandwrite_sram@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
  sub    $0x8,%rsp
  push   $0x10000
  mov    $0x0,%r9d
  mov    $0x400,%r8d
  mov    $0x10000,%ecx
  mov    $0x0,%edx
  mov    $0xe0f0000,%esi
  mov    %rax,%rdi
  call   <cart_direct_write@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x10,%rsp
L7:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    %edx,%eax
  mov    $0x10000,%ecx
  mov    %rdi,%rdx
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printerr@plt>
  mov    $0xffffffff,%ebp
  jmp    L7
L37:
  mov    $0xffffffff,%ebp
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: Could not write %i bytes from file %s to SRAM, %i bytes expected


assistant: ```c
int f2au_loadandwrite_sram(const char *file, int offset, int size) {
  int ret;
  unsigned char *sram;
  if (size != 65536) {
    printerr("Could not write %i bytes from file %s to SRAM, %i bytes expected\n", size, file, 65536);
    return -1;
  }
  if ((sram = prepare_loadandwrite_sram(file, offset, size)) == NULL)
    return -1;
  ret = cart_direct_write(sram, (0x0e000000 + 0x0f0000), 0, 65536, 1024, 0, 65536);
  free(sram);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<f2au_loadandwrite_sram>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x10000,%edx
  jne    L28
  mov    $0x10000,%edx
  call   <prepare_loadandwrite_sram@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %r9d,%r9d
  mov    $0x400,%r8d
  push   $0x10000
  mov    $0x10000,%ecx
  mov    $0xe0f0000,%esi
  mov    %rax,%rdi
  call   <cart_direct_write@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  pop    %rax
  pop    %rdx
L23:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %edx,%r8d
  mov    $0x10000,%ecx
  mov    %rdi,%rdx
  mov    $0xffffffff,%r12d
  mov    %r8d,%esi
  lea    D5(%rip),%rdi
  call   <printerr@plt>
  jmp    L23
L1:
  mov    $0xffffffff,%r12d
  jmp    L23
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: Could not write %i bytes from file %s to SRAM, %i bytes expected


assistant: ```c
int f2au_loadandwrite_sram(const char *file, int offset, int size) {
  int ret;
  unsigned char *sram;
  if (size != 65536) {
    printerr("Could not write %i bytes from file %s to SRAM, %i bytes expected\n", size, file, 65536);
    return -1;
  }
  if ((sram = prepare_loadandwrite_sram(file, offset, size)) == NULL)
    return -1;
  ret = cart_direct_write(sram, (0x0e000000 + 0x0f0000), 0, 65536, 1024, 0, 65536);
  free(sram);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f2au_loadandwrite_sram>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x10000,%edx
  jne    L28
  mov    $0x10000,%edx
  call   <prepare_loadandwrite_sram@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L26
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %r9d,%r9d
  mov    $0x400,%r8d
  push   $0x10000
  mov    $0x10000,%ecx
  mov    $0xe0f0000,%esi
  mov    %rax,%rdi
  call   <cart_direct_write@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  pop    %rax
  pop    %rdx
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %edx,%r8d
  mov    $0x10000,%ecx
  mov    %rdi,%rdx
  mov    $0xffffffff,%r12d
  mov    %r8d,%esi
  lea    D7(%rip),%rdi
  call   <printerr@plt>
  jmp    L21
L26:
  mov    $0xffffffff,%r12d
  jmp    L21
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: Could not write %i bytes from file %s to SRAM, %i bytes expected


assistant: ```c
int f2au_loadandwrite_sram(const char *file, int offset, int size) {
  int ret;
  unsigned char *sram;
  if (size != 65536) {
    printerr("Could not write %i bytes from file %s to SRAM, %i bytes expected\n", size, file, 65536);
    return -1;
  }
  if ((sram = prepare_loadandwrite_sram(file, offset, size)) == NULL)
    return -1;
  ret = cart_direct_write(sram, (0x0e000000 + 0x0f0000), 0, 65536, 1024, 0, 65536);
  free(sram);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotate_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x20,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L9
  mov    -0x4(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%ecx
  shr    %cl,%esi
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, int n) {
  int w = sizeof(int) << 3;
  unsigned shift_left_count = 0;
  n == 0 || (shift_left_count = w - n);
  x = (x >> n) | (x << shift_left_count);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rotate_right>:
  endbr64
  mov    %esi,%ecx
  mov    $0x20,%edx
  sub    %esi,%edx
  test   %esi,%esi
  mov    $0x0,%eax
  cmove  %eax,%edx
  mov    %edi,%eax
  shr    %cl,%eax
  mov    %edx,%ecx
  shl    %cl,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, int n) {
  int w = sizeof(int) << 3;
  unsigned shift_left_count = 0;
  n == 0 || (shift_left_count = w - n);
  x = (x >> n) | (x << shift_left_count);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rotate_right>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L8
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shl    %cl,%eax
L8:
  mov    %esi,%ecx
  shr    %cl,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, int n) {
  int w = sizeof(int) << 3;
  unsigned shift_left_count = 0;
  n == 0 || (shift_left_count = w - n);
  x = (x >> n) | (x << shift_left_count);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotate_right>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L2
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shl    %cl,%eax
L2:
  mov    %esi,%ecx
  shr    %cl,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, int n) {
  int w = sizeof(int) << 3;
  unsigned shift_left_count = 0;
  n == 0 || (shift_left_count = w - n);
  x = (x >> n) | (x << shift_left_count);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setRowColors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x28(%rbp)
  mov    %esi,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L5
L11:
  movzbl -0x1(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edi
  movzbl -0x1(%rbp),%ecx
  movzbl -0x20(%rbp),%edx
  movzbl -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <setSquare@plt>
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L5:
  cmpb   $0x2,-0x1(%rbp)
  jbe    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void setRowColors(struct rubikCube *cube, unsigned char face, unsigned char row, unsigned char *rowColors) {
  unsigned char col;
  for (col = 0; col < 3; col++) {
    setSquare(cube, face, row, col, rowColors[col]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setRowColors>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rcx,%r13
  mov    %esi,%r12d
  mov    $0x0,%ebx
  movzbl %dl,%ebp
L4:
  movzbl %r12b,%esi
  movzbl 0x0(%r13,%rbx,1),%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r14,%rdi
  call   <setSquare@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void setRowColors(struct rubikCube *cube, unsigned char face, unsigned char row, unsigned char *rowColors) {
  unsigned char col;
  for (col = 0; col < 3; col++) {
    setSquare(cube, face, row, col, rowColors[col]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setRowColors>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  movzbl %dl,%r12d
  push   %rbp
  movzbl %sil,%ebp
  push   %rbx
  xor    %ebx,%ebx
L1:
  movzbl 0x0(%r13,%rbx,1),%r8d
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <setSquare@plt>
  cmp    $0x3,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void setRowColors(struct rubikCube *cube, unsigned char face, unsigned char row, unsigned char *rowColors) {
  unsigned char col;
  for (col = 0; col < 3; col++) {
    setSquare(cube, face, row, col, rowColors[col]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setRowColors>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  movzbl %dl,%r12d
  push   %rbp
  movzbl %sil,%ebp
  push   %rbx
  xor    %ebx,%ebx
L6:
  movzbl 0x0(%r13,%rbx,1),%r8d
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <setSquare@plt>
  cmp    $0x3,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void setRowColors(struct rubikCube *cube, unsigned char face, unsigned char row, unsigned char *rowColors) {
  unsigned char col;
  for (col = 0; col < 3; col++) {
    setSquare(cube, face, row, col, rowColors[col]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isport>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L41
  mov    $0x0,%eax
  jmp    L49
L41:
  mov    D18(%rip),%rax
  movq   $0x0,(%rax)
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L72
  cmpq   $0xfffe,-0x10(%rbp)
  jg     L72
  cmpq   $0x0,-0x10(%rbp)
  jle    L72
  mov    -0x10(%rbp),%rax
  jmp    L49
L72:
  mov    $0x0,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int isport(const char *digit) {
  char *end;
  long int l;
  if (digit == NULL)
    return 0;
  errno = 0;
  l = strtol(digit, &end, 10);
  if (*end == '\0' && errno == 0 && l < 0xFFFF && l > 0)
    return (int)l;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isport>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L35
  mov    D11(%rip),%rax
  movq   $0x0,(%rax)
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    %rax,%rcx
  mov    $0x0,%eax
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L35
  mov    D11(%rip),%rdx
  cmpq   $0x0,(%rdx)
  jne    L35
  lea    -0x1(%rcx),%rax
  cmp    $0xfffd,%rax
  mov    $0x0,%edx
  mov    %edx,%eax
  cmovbe %ecx,%eax
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isport(const char *digit) {
  char *end;
  long int l;
  if (digit == NULL)
    return 0;
  errno = 0;
  l = strtol(digit, &end, 10);
  if (*end == '\0' && errno == 0 && l < 0xFFFF && l > 0)
    return (int)l;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isport>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L47
  mov    D7(%rip),%rbx
  mov    $0xa,%edx
  mov    %rsp,%rsi
  movq   $0x0,(%rbx)
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L44
L47:
  xor    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  cmpq   $0x0,(%rbx)
  jne    L47
  lea    -0x1(%rax),%rdx
  cmp    $0xfffd,%rdx
  ja     L47
  jmp    L4
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isport(const char *digit) {
  char *end;
  long int l;
  if (digit == NULL)
    return 0;
  errno = 0;
  l = strtol(digit, &end, 10);
  if (*end == '\0' && errno == 0 && l < 0xFFFF && l > 0)
    return (int)l;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isport>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L51
  mov    D5(%rip),%rbx
  mov    $0xa,%edx
  mov    %rsp,%rsi
  movq   $0x0,(%rbx)
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L12
L51:
  xor    %eax,%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  cmpq   $0x0,(%rbx)
  jne    L51
  lea    -0x1(%rax),%rdx
  cmp    $0xfffd,%rdx
  ja     L51
  jmp    L22
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isport(const char *digit) {
  char *end;
  long int l;
  if (digit == NULL)
    return 0;
  errno = 0;
  l = strtol(digit, &end, 10);
  if (*end == '\0' && errno == 0 && l < 0xFFFF && l > 0)
    return (int)l;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L15
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L5
L15:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getClock@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fib_recursion@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <getTime@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movq   %xmm1,%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getClock@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fib_repeated@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <getTime@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movq   %xmm2,%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D14
datatype: string

tool: D1: USAGE: TEST ${NUMBER}

tool: D6: Get fibonacci %d as recursion is %d, T : %f


tool: D14: Get fibonacci %d as repeated is %d, T : %f


assistant: ```c
int main(int argc, char *argv[]) {
  int number, ret;
  float gap;
  clock_t startTime;
  if (argc != 2) {
    printf("USAGE: TEST ${NUMBER}\n");
    return 0;
  }
  number = atoi(argv[1]);
  startTime = getClock();
  ret = fib_recursion(number);
  gap = getTime(startTime);
  printf("Get fibonacci %d as recursion is %d, T : %f\n", number, ret, gap);
  startTime = getClock();
  ret = fib_repeated(number);
  gap = getTime(startTime);
  printf("Get fibonacci %d as repeated is %d, T : %f\n", number, ret, gap);
  return 0;
}
```