ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<merge_pass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L27:
  mov    -0x28(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  lea    -0x1(%rax),%edi
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <merge@plt>
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  add    %eax,-0x4(%rbp)
L38:
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    -0x28(%rbp),%edx
  add    %edx,%edx
  cmp    %edx,%eax
  jge    L27
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jge    L35
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <merge@plt>
  jmp    L2
L35:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L46
L52:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L52
L2:
  nop
  leave
  ret
```

assistant: ```c
void merge_pass(int *pdata, int *temp, int count, int len) {
  int j, first = 0;
  while (count - first >= 2 * len) {
    merge(pdata, temp, first, first + len - 1, first + 2 * len - 1);
    first = first + 2 * len;
  }
  if (count - first > len)
    merge(pdata, temp, first, first + len - 1, count - 1);
  else
    for (j = first; j < count; ++j)
      *(temp + j) = *(pdata + j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge_pass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%r15d
  mov    %ecx,0xc(%rsp)
  lea    (%rcx,%rcx,1),%r12d
  cmp    %r12d,%edx
  jl     L55
  mov    %ecx,%eax
  mov    %edx,%ebp
  sub    %r12d,%ebp
  mov    $0x0,%ebx
  sub    $0x1,%eax
  sub    %r12d,%eax
  mov    %eax,0x8(%rsp)
L26:
  mov    %ebx,%edx
  add    %r12d,%ebx
  mov    0x8(%rsp),%eax
  lea    (%rax,%rbx,1),%ecx
  lea    -0x1(%rbx),%r8d
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <merge@plt>
  mov    %ebp,%eax
  sub    %r12d,%ebp
  jge    L26
L34:
  cmp    %eax,0xc(%rsp)
  jl     L13
  movslq %ebx,%rax
  cmp    %ebx,%r15d
  jle    L43
L32:
  mov    0x0(%r13,%rax,4),%edx
  mov    %edx,(%r14,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r15d
  jg     L32
L43:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  mov    %edx,%eax
  mov    $0x0,%ebx
  jmp    L34
L13:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rbx,%rax,1),%ecx
  lea    -0x1(%r15),%r8d
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <merge@plt>
  jmp    L43
```

assistant: ```c
void merge_pass(int *pdata, int *temp, int count, int len) {
  int j, first = 0;
  while (count - first >= 2 * len) {
    merge(pdata, temp, first, first + len - 1, first + 2 * len - 1);
    first = first + 2 * len;
  }
  if (count - first > len)
    merge(pdata, temp, first, first + len - 1, count - 1);
  else
    for (j = first; j < count; ++j)
      *(temp + j) = *(pdata + j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge_pass>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  lea    (%rcx,%rcx,1),%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  cmp    %ebp,%edx
  jl     L39
  sub    %ebp,%edx
  lea    -0x1(%rcx),%r14d
  xor    %r12d,%r12d
  mov    %edx,%ebx
  sub    %ebp,%r14d
  nopl   0x0(%rax)
L46:
  mov    %r12d,%edx
  add    %ebp,%r12d
  mov    %r13,%rsi
  mov    %r15,%rdi
  lea    (%r14,%r12,1),%ecx
  lea    -0x1(%r12),%r8d
  call   <merge@plt>
  mov    %ebx,%eax
  sub    %ebp,%ebx
  jge    L46
L4:
  cmp    %eax,0xc(%rsp)
  jl     L52
  movslq %r12d,%rax
  cmp    %r12d,0x8(%rsp)
  jle    L32
L42:
  mov    (%r15,%rax,4),%edx
  mov    %edx,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %eax,0x8(%rsp)
  jg     L42
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    0xc(%rsp),%eax
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  lea    -0x1(%r12,%rax,1),%ecx
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  lea    -0x1(%rax),%r8d
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <merge@plt>
  nopl   (%rax)
L39:
  mov    0x8(%rsp),%eax
  xor    %r12d,%r12d
  jmp    L4
```

assistant: ```c
void merge_pass(int *pdata, int *temp, int count, int len) {
  int j, first = 0;
  while (count - first >= 2 * len) {
    merge(pdata, temp, first, first + len - 1, first + 2 * len - 1);
    first = first + 2 * len;
  }
  if (count - first > len)
    merge(pdata, temp, first, first + len - 1, count - 1);
  else
    for (j = first; j < count; ++j)
      *(temp + j) = *(pdata + j);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<merge_pass>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    (%rcx,%rcx,1),%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  cmp    %ebp,%edx
  jl     L118
  sub    %ebp,%edx
  lea    -0x1(%rcx),%r14d
  xor    %r12d,%r12d
  mov    %edx,%ebx
  sub    %ebp,%r14d
  nopl   0x0(%rax)
L50:
  mov    %r12d,%edx
  add    %ebp,%r12d
  mov    %r15,%rsi
  mov    %r13,%rdi
  lea    (%r14,%r12,1),%ecx
  lea    -0x1(%r12),%r8d
  call   <merge@plt>
  mov    %ebx,%eax
  sub    %ebp,%ebx
  jge    L50
L86:
  cmp    %eax,0xc(%rsp)
  jl     L120
  cmp    %r12d,0x8(%rsp)
  jle    L69
  movslq %r12d,%rax
  mov    0x8(%rsp),%r9d
  lea    0x0(,%rax,4),%rdx
  lea    (%r15,%rdx,1),%r8
  lea    0x4(%r13,%rdx,1),%r10
  sub    %r12d,%r9d
  mov    %r8,%rcx
  sub    %r10,%rcx
  cmp    $0x8,%rcx
  jbe    L22
  lea    -0x1(%r9),%ecx
  cmp    $0x2,%ecx
  jbe    L22
  mov    %r9d,%ecx
  add    %r13,%rdx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   (%rax)
L89:
  movdqu (%rdx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L89
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%r12d
  cmp    %eax,%r9d
  je     L69
  movslq %r12d,%rax
  mov    0x8(%rsp),%edi
  mov    0x0(%r13,%rax,4),%edx
  mov    %edx,(%r15,%rax,4)
  lea    0x1(%r12),%eax
  cmp    %eax,%edi
  jle    L69
  cltq
  add    $0x2,%r12d
  mov    0x0(%r13,%rax,4),%ecx
  lea    0x0(,%rax,4),%rdx
  mov    %ecx,(%r15,%rax,4)
  cmp    %r12d,%edi
  jle    L69
  mov    0x4(%r13,%rdx,1),%eax
  mov    %eax,0x4(%r15,%rdx,1)
L69:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L22:
  mov    0x0(%r13,%rax,4),%edx
  mov    %edx,(%r15,%rax,4)
  add    $0x1,%rax
  cmp    %eax,0x8(%rsp)
  jg     L22
  jmp    L69
  nopl   (%rax)
L120:
  mov    0xc(%rsp),%eax
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  lea    -0x1(%r12,%rax,1),%ecx
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  lea    -0x1(%rax),%r8d
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <merge@plt>
  nopl   (%rax)
L118:
  mov    %edx,%eax
  xor    %r12d,%r12d
  jmp    L86
```

assistant: ```c
void merge_pass(int *pdata, int *temp, int count, int len) {
  int j, first = 0;
  while (count - first >= 2 * len) {
    merge(pdata, temp, first, first + len - 1, first + 2 * len - 1);
    first = first + 2 * len;
  }
  if (count - first > len)
    merge(pdata, temp, first, first + len - 1, count - 1);
  else
    for (j = first; j < count; ++j)
      *(temp + j) = *(pdata + j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<occurrences>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L20
  ucomisd -0x18(%rbp),%xmm0
  jne    L20
  addl   $0x1,-0x8(%rbp)
L20:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int occurrences(double value, double arr[], int size) {
  int counter = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] == value)
      ++counter;
  return counter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<occurrences>:
  endbr64
  test   %esi,%esi
  jle    L30
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rcx
  mov    $0x0,%edx
  jmp    L33
L28:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L43
L33:
  ucomisd (%rax),%xmm0
  jp     L28
  jne    L28
  add    $0x1,%edx
  jmp    L28
L30:
  mov    $0x0,%edx
L43:
  mov    %edx,%eax
  ret
```

assistant: ```c
int occurrences(double value, double arr[], int size) {
  int counter = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] == value)
      ++counter;
  return counter;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<occurrences>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L35:
  ucomisd (%rdi),%xmm0
  jp     L28
  jne    L28
  add    $0x1,%eax
L28:
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L35
  ret
  nopl   (%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int occurrences(double value, double arr[], int size) {
  int counter = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] == value)
      ++counter;
  return counter;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<occurrences>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edx
  test   %esi,%esi
  jle    L107
  lea    -0x1(%rsi),%eax
  cmp    $0x3,%eax
  jbe    L73
  mov    %esi,%ecx
  movapd %xmm0,%xmm5
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  shr    $0x2,%ecx
  movdqa D4(%rip),%xmm4
  unpcklpd %xmm5,%xmm5
  sub    $0x1,%ecx
  shl    $0x5,%rcx
  lea    0x20(%rdi,%rcx,1),%rcx
  nopl   (%rax)
L159:
  movupd (%rax),%xmm1
  movupd 0x10(%rax),%xmm2
  add    $0x20,%rax
  cmpeqpd %xmm5,%xmm1
  cmpeqpd %xmm5,%xmm2
  pand   %xmm4,%xmm1
  pand   %xmm4,%xmm2
  shufps $0x88,%xmm2,%xmm1
  paddd  %xmm1,%xmm3
  cmp    %rax,%rcx
  jne    L159
  movdqa %xmm3,%xmm1
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm3
  movdqa %xmm3,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm3
  movd   %xmm3,%eax
  test   $0x3,%dl
  je     L124
L104:
  movslq %ecx,%rdi
  ucomisd (%r8,%rdi,8),%xmm0
  lea    0x0(,%rdi,8),%rsi
  jp     L91
  jne    L91
  add    $0x1,%eax
L91:
  lea    0x1(%rcx),%edi
  cmp    %edx,%edi
  jge    L79
  ucomisd 0x8(%r8,%rsi,1),%xmm0
  jp     L141
  jne    L141
  add    $0x1,%eax
L141:
  lea    0x2(%rcx),%edi
  cmp    %edi,%edx
  jle    L79
  ucomisd 0x10(%r8,%rsi,1),%xmm0
  jp     L78
  jne    L78
  add    $0x1,%eax
L78:
  add    $0x3,%ecx
  cmp    %ecx,%edx
  jle    L79
  ucomisd 0x18(%r8,%rsi,1),%xmm0
  jp     L79
  jne    L79
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L107:
  xor    %eax,%eax
L79:
  ret
  nopl   0x0(%rax,%rax,1)
L124:
  ret
L73:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L104
```

tool_calls: name: read_data
arguments: tag: D4
data_type: byte[16]

tool: {"D4": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int occurrences(double value, double arr[], int size) {
  int counter = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] == value)
      ++counter;
  return counter;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<digitsInLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  test   %eax,%eax
  je     L37
  cmp    $0xa,%eax
  jne    L25
L37:
  mov    -0x8(%rbp),%eax
  jmp    L10
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L54
  addl   $0x1,-0x8(%rbp)
L54:
  nop
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%eax
L10:
  leave
  ret
```

assistant: ```c
int digitsInLine(const char *str, int strSize) {
  int result = 0;
  {
    int i;
    for (i = 0; (i < strSize); ++i) {
      switch (str[i]) {
      case '\0':
      case '\n':
        return result;
        break;
      default:
        if (isdigit(str[i]))
          result++;
        break;
      };
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<digitsInLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0x0,%ebp
L45:
  movzbl (%rbx),%eax
  movsbl %al,%edi
  test   %al,%al
  je     L36
  cmp    $0xa,%al
  je     L36
  call   <isdigit@plt>
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L45
L36:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    $0x0,%ebp
  jmp    L36
```

assistant: ```c
int digitsInLine(const char *str, int strSize) {
  int result = 0;
  {
    int i;
    for (i = 0; (i < strSize); ++i) {
      switch (str[i]) {
      case '\0':
      case '\n':
        return result;
        break;
      default:
        if (isdigit(str[i]))
          result++;
        break;
      };
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<digitsInLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L28
  cmp    $0xa,%dil
  je     L28
  call   <isdigit@plt>
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L11
L28:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  xor    %r12d,%r12d
  jmp    L28
```

assistant: ```c
int digitsInLine(const char *str, int strSize) {
  int result = 0;
  {
    int i;
    for (i = 0; (i < strSize); ++i) {
      switch (str[i]) {
      case '\0':
      case '\n':
        return result;
        break;
      default:
        if (isdigit(str[i]))
          result++;
        break;
      };
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<digitsInLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L24:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L46
  cmp    $0xa,%dil
  je     L46
  call   <isdigit@plt>
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L24
L46:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  xor    %r12d,%r12d
  jmp    L46
```

assistant: ```c
int digitsInLine(const char *str, int strSize) {
  int result = 0;
  {
    int i;
    for (i = 0; (i < strSize); ++i) {
      switch (str[i]) {
      case '\0':
      case '\n':
        return result;
        break;
      default:
        if (isdigit(str[i]))
          result++;
        break;
      };
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: tb: running


assistant: ```c
void *tb(void *arg) {
  (void)arg;
  printf("tb: running\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tb>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0: tb: running


assistant: ```c
void *tb(void *arg) {
  (void)arg;
  printf("tb: running\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tb>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: tb: running


assistant: ```c
void *tb(void *arg) {
  (void)arg;
  printf("tb: running\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tb>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: tb: running


assistant: ```c
void *tb(void *arg) {
  (void)arg;
  printf("tb: running\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D40(%rip),%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  D44(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  D5(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L21
L18:
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <stdlib_base_hypotf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  movss  -0x24(%rbp),%xmm1
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0x28(%rbp)
L21:
  cmpl   $0x3,-0x28(%rbp)
  jle    L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D40
type: byte[4]
name: unpack_data
arguments: label: D9
type: byte[4]
name: unpack_data
arguments: label: D44
type: byte[4]
name: unpack_data
arguments: label: D5
type: byte[4]
name: unpack_data
arguments: label: D33
type: string

tool: {"D40": [0x00,0x00,0x40,0x40]}

tool: {"D9": [0x00,0x00,0x80,0x40]}

tool: {"D44": [0x00,0x00,0xa0,0x40]}

tool: {"D5": [0x00,0x00,0x40,0x41]}

tool: D33: hypotf(%f, %f) = %f


assistant: ```c
int main() {
  float x[] = {3.0f, 4.0f, 5.0f, 12.0f};
  float y;
  int i;
  for (i = 0; i < 4; i += 2) {
    y = stdlib_base_hypotf(x[i], x[i + 1]);
    printf("hypotf(%f, %f) = %f\n", x[i], x[i + 1], y);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  movss  D76(%rip),%xmm1
  movss  D11(%rip),%xmm0
  call   <stdlib_base_hypotf@plt>
  movaps %xmm0,%xmm2
  movss  D76(%rip),%xmm1
  movss  D11(%rip),%xmm0
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movss  D25(%rip),%xmm1
  movss  D49(%rip),%xmm0
  call   <stdlib_base_hypotf@plt>
  movaps %xmm0,%xmm2
  movss  D25(%rip),%xmm1
  movss  D49(%rip),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D76
type: byte[4]
name: read_data
arguments: data_label: D11
type: byte[4]
name: read_data
arguments: data_label: D38
type: string
name: read_data
arguments: data_label: D25
type: byte[4]
name: read_data
arguments: data_label: D49
type: byte[4]

tool: {"D76": [0x00,0x00,0x80,0x40]}

tool: {"D11": [0x00,0x00,0x40,0x40]}

tool: D38: hypotf(%f, %f) = %f


tool: {"D25": [0x00,0x00,0x40,0x41]}

tool: {"D49": [0x00,0x00,0xa0,0x40]}

assistant: ```c
int main() {
  float x[] = {3.0f, 4.0f, 5.0f, 12.0f};
  float y;
  int i;
  for (i = 0; i < 4; i += 2) {
    y = stdlib_base_hypotf(x[i], x[i + 1]);
    printf("hypotf(%f, %f) = %f\n", x[i], x[i + 1], y);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  movss  D85(%rip),%xmm3
  lea    D12(%rip),%rbp
  movss  D30(%rip),%xmm1
  movaps %xmm3,%xmm0
  call   <stdlib_base_hypotf@plt>
  movss  D85(%rip),%xmm3
  movss  D30(%rip),%xmm1
  mov    %rbp,%rdi
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm0
  call   <printf@plt>
  movss  D43(%rip),%xmm3
  movss  D68(%rip),%xmm1
  movaps %xmm3,%xmm0
  call   <stdlib_base_hypotf@plt>
  movss  D43(%rip),%xmm3
  movss  D68(%rip),%xmm1
  mov    %rbp,%rdi
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D85
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D43
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D68
type_infered: byte[4]

tool: {"D85": [0x00,0x00,0x40,0x40]}

tool: D12: hypotf(%f, %f) = %f


tool: {"D30": [0x00,0x00,0x80,0x40]}

tool: {"D43": [0x00,0x00,0xa0,0x40]}

tool: {"D68": [0x00,0x00,0x40,0x41]}

assistant: ```c
int main() {
  float x[] = {3.0f, 4.0f, 5.0f, 12.0f};
  float y;
  int i;
  for (i = 0; i < 4; i += 2) {
    y = stdlib_base_hypotf(x[i], x[i + 1]);
    printf("hypotf(%f, %f) = %f\n", x[i], x[i + 1], y);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  movss  D43(%rip),%xmm3
  lea    D16(%rip),%rbp
  movss  D70(%rip),%xmm1
  movaps %xmm3,%xmm0
  call   <stdlib_base_hypotf@plt>
  movss  D43(%rip),%xmm3
  movss  D70(%rip),%xmm1
  mov    %rbp,%rdi
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm0
  call   <printf@plt>
  movss  D12(%rip),%xmm3
  movss  D65(%rip),%xmm1
  movaps %xmm3,%xmm0
  call   <stdlib_base_hypotf@plt>
  movss  D12(%rip),%xmm3
  movss  D65(%rip),%xmm1
  mov    %rbp,%rdi
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D43
datatype: byte[4]
name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D70
datatype: byte[4]
name: read_data
arguments: label: D12
datatype: byte[4]
name: read_data
arguments: label: D65
datatype: byte[4]

tool: {"D43": [0x00,0x00,0x40,0x40]}

tool: D16: hypotf(%f, %f) = %f


tool: {"D70": [0x00,0x00,0x80,0x40]}

tool: {"D12": [0x00,0x00,0xa0,0x40]}

tool: {"D65": [0x00,0x00,0x40,0x41]}

assistant: ```c
int main() {
  float x[] = {3.0f, 4.0f, 5.0f, 12.0f};
  float y;
  int i;
  for (i = 0; i < 4; i += 2) {
    y = stdlib_base_hypotf(x[i], x[i + 1]);
    printf("hypotf(%f, %f) = %f\n", x[i], x[i + 1], y);
  }
}
```