ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getKey>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L59
  sub    %rbx,%rbp
  mov    %rbp,%r12
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L51
  test   %r12d,%r12d
  je     L8
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%rsi
  mov    %rbp,%rax
  sub    %rbp,%rbx
  mov    %rbx,%rcx
L29:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L29
L8:
  mov    %r12d,%r12d
  movb   $0x0,0x0(%rbp,%r12,1)
L43:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L51:
  mov    $0x0,%ebp
  jmp    L43
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: No equals found. Input was %s


assistant: ```c
char *getKey(char *pair) {
  char *equalsAddress = strchr(pair, '=');
  if (equalsAddress == NULL) {
    printf("No equals found. Input was %s\n", pair);
    return NULL;
  }
  unsigned int numCharichters = (equalsAddress - pair) + 1;
  char *newString = (char *)malloc(numCharichters);
  if (newString == NULL)
    return NULL;
  for (unsigned int i = 0; i < numCharichters - 1; i++) {
    newString[i] = pair[i];
  }
  newString[numCharichters - 1] = '\0';
  return newString;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getKey>:
  endbr64
  push   %r12
  mov    $0x3d,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L34
  mov    %ebx,%esi
  test   %ebx,%ebx
  je     L48
  mov    %rbp,%rdi
  lea    (%rax,%rsi,1),%rcx
  mov    %rax,%rdx
  sub    %rax,%rdi
  cs nopw 0x0(%rax,%rax,1)
L6:
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L6
L48:
  movb   $0x0,(%r12,%rsi,1)
L34:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L18:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: No equals found. Input was %s


assistant: ```c
char *getKey(char *pair) {
  char *equalsAddress = strchr(pair, '=');
  if (equalsAddress == NULL) {
    printf("No equals found. Input was %s\n", pair);
    return NULL;
  }
  unsigned int numCharichters = (equalsAddress - pair) + 1;
  char *newString = (char *)malloc(numCharichters);
  if (newString == NULL)
    return NULL;
  for (unsigned int i = 0; i < numCharichters - 1; i++) {
    newString[i] = pair[i];
  }
  newString[numCharichters - 1] = '\0';
  return newString;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<srot13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L3
L8:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <rot13@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *srot13(char *str) {
  int length = strlen(str);
  for (int i = 0; i < length; i++) {
    str[i] = rot13(str[i]);
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<srot13>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%rbp
L6:
  movsbl (%rbx),%edi
  call   <rot13@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *srot13(char *str) {
  int length = strlen(str);
  for (int i = 0; i < length; i++) {
    str[i] = rot13(str[i]);
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<srot13>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L14
  sub    $0x1,%eax
  mov    %r12,%rbx
  lea    0x1(%r12,%rax,1),%rbp
  nop
L8:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <rot13@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L8
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *srot13(char *str) {
  int length = strlen(str);
  for (int i = 0; i < length; i++) {
    str[i] = rot13(str[i]);
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<srot13>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  sub    $0x1,%eax
  mov    %r12,%rbx
  lea    0x1(%r12,%rax,1),%rbp
  nop
L15:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <rot13@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L15
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *srot13(char *str) {
  int length = strlen(str);
  for (int i = 0; i < length; i++) {
    str[i] = rot13(str[i]);
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_ncurses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <keypad@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%edi
  call   <timeout@plt>
  mov    D20(%rip),%rax
  mov    (%rax),%edx
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <init_pair@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int init_ncurses() {
  initscr();
  start_color();
  cbreak();
  keypad(stdscr, TRUE);
  noecho();
  curs_set(0);
  refresh();
  timeout(0);
  init_pair(1, COLOR_BLACK, COLOR_CYAN);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_ncurses>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  mov    D30(%rip),%rax
  mov    (%rax),%edi
  call   <keypad@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%edi
  call   <timeout@plt>
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    $0x1,%edi
  call   <init_pair@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_ncurses() {
  initscr();
  start_color();
  cbreak();
  keypad(stdscr, TRUE);
  noecho();
  curs_set(0);
  refresh();
  timeout(0);
  init_pair(1, COLOR_BLACK, COLOR_CYAN);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_ncurses>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <start_color@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    D28(%rip),%rax
  mov    (%rax),%edi
  call   <keypad@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %edi,%edi
  call   <curs_set@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %edi,%edi
  call   <timeout@plt>
  mov    D17(%rip),%rax
  mov    $0x1,%edi
  mov    (%rax),%edx
  mov    D20(%rip),%rax
  mov    (%rax),%esi
  call   <init_pair@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_ncurses() {
  initscr();
  start_color();
  cbreak();
  keypad(stdscr, TRUE);
  noecho();
  curs_set(0);
  refresh();
  timeout(0);
  init_pair(1, COLOR_BLACK, COLOR_CYAN);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<init_ncurses>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <start_color@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  mov    D36(%rip),%rax
  mov    (%rax),%esi
  mov    D34(%rip),%rax
  mov    (%rax),%edi
  call   <keypad@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %edi,%edi
  call   <curs_set@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %edi,%edi
  call   <timeout@plt>
  mov    D20(%rip),%rax
  mov    $0x1,%edi
  mov    (%rax),%edx
  mov    D35(%rip),%rax
  mov    (%rax),%esi
  call   <init_pair@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_ncurses() {
  initscr();
  start_color();
  cbreak();
  keypad(stdscr, TRUE);
  noecho();
  curs_set(0);
  refresh();
  timeout(0);
  init_pair(1, COLOR_BLACK, COLOR_CYAN);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumlista>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumlista(int *lista, int lenght) {
  int sum = 0;
  for (int i = 0; i < lenght; i++) {
    sum += lista[i];
    ;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sumlista>:
  endbr64
  test   %esi,%esi
  jle    L20
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L6:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
L5:
  mov    %edx,%eax
  ret
L20:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
int sumlista(int *lista, int lenght) {
  int sum = 0;
  for (int i = 0; i < lenght; i++) {
    sum += lista[i];
    ;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sumlista>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L16
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumlista(int *lista, int lenght) {
  int sum = 0;
  for (int i = 0; i < lenght; i++) {
    sum += lista[i];
    ;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sumlista>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L58
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L54:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L54
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L22
L29:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L39
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L39
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
L39:
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  ret
L58:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
int sumlista(int *lista, int lenght) {
  int sum = 0;
  for (int i = 0; i < lenght; i++) {
    sum += lista[i];
    ;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cdf_getdays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x641,-0x4(%rbp)
  jmp    L47
L16:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L37
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L15
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L37
L15:
  mov    $0x1,%eax
  jmp    L17
L37:
  mov    $0x0,%eax
L17:
  add    $0x16d,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cdf_getdays(int year) {
  int days = 0;
  int y;
  for (y = 1601; y < year; y++)
    days += ((((y) % 4) == 0) && ((((y) % 100) != 0) || (((y) % 400) == 0))) + 365;
  return days;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cdf_getdays>:
  endbr64
  cmp    $0x641,%edi
  jle    L56
  mov    $0x641,%eax
  mov    $0x0,%esi
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  jmp    L46
L3:
  lea    0x16d(%rcx,%rsi,1),%esi
  add    $0x1,%eax
  cmp    %eax,%edi
  je     L37
L46:
  mov    %r8d,%ecx
  test   $0x3,%al
  jne    L3
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  mov    %r9d,%ecx
  cmp    %edx,%eax
  jne    L3
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x190,%edx,%edx
  cmp    %edx,%eax
  sete   %cl
  movzbl %cl,%ecx
  jmp    L3
L56:
  mov    $0x0,%esi
L37:
  mov    %esi,%eax
  ret
```

assistant: ```c
int cdf_getdays(int year) {
  int days = 0;
  int y;
  for (y = 1601; y < year; y++)
    days += ((((y) % 4) == 0) && ((((y) % 100) != 0) || (((y) % 400) == 0))) + 365;
  return days;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cdf_getdays>:
  endbr64
  cmp    $0x641,%edi
  jle    L34
  mov    $0x641,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L39:
  mov    $0x16d,%edx
  test   $0x3,%al
  jne    L10
  imul   $0xc28f5c29,%eax,%ecx
  mov    $0x16e,%edx
  mov    %ecx,%esi
  ror    $0x2,%esi
  cmp    $0x28f5c28,%esi
  ja     L10
  ror    $0x4,%ecx
  xor    %edx,%edx
  cmp    $0xa3d70b,%ecx
  setb   %dl
  add    $0x16d,%edx
L10:
  add    $0x1,%eax
  add    %edx,%r8d
  cmp    %eax,%edi
  jne    L39
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cdf_getdays(int year) {
  int days = 0;
  int y;
  for (y = 1601; y < year; y++)
    days += ((((y) % 4) == 0) && ((((y) % 100) != 0) || (((y) % 400) == 0))) + 365;
  return days;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atmpvc_gen_sockaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x18(%rax)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x10(%rdx)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x8(%rdx)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  movq   $0x20,(%rax)
  jmp    L12
L19:
  nop
L12:
  leave
  ret
```

assistant: ```c
void atmpvc_gen_sockaddr(unsigned long *addr, unsigned long *addrlen) {
  struct sockaddr_atmpvc *atmpvc;
  atmpvc = malloc(sizeof(struct sockaddr_atmpvc));
  if (atmpvc == NULL)
    return;
  atmpvc->sap_family = PF_ATMPVC;
  atmpvc->sap_addr.itf = rand();
  atmpvc->sap_addr.vpi = rand();
  atmpvc->sap_addr.vci = rand();
  *addr = (unsigned long)atmpvc;
  *addrlen = sizeof(struct sockaddr_atmpvc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atmpvc_gen_sockaddr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x20,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rbx)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,0x10(%rbx)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,0x8(%rbx)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,(%rbx)
  mov    %rbx,(%r12)
  movq   $0x20,0x0(%rbp)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void atmpvc_gen_sockaddr(unsigned long *addr, unsigned long *addrlen) {
  struct sockaddr_atmpvc *atmpvc;
  atmpvc = malloc(sizeof(struct sockaddr_atmpvc));
  if (atmpvc == NULL)
    return;
  atmpvc->sap_family = PF_ATMPVC;
  atmpvc->sap_addr.itf = rand();
  atmpvc->sap_addr.vpi = rand();
  atmpvc->sap_addr.vci = rand();
  *addr = (unsigned long)atmpvc;
  *addrlen = sizeof(struct sockaddr_atmpvc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atmpvc_gen_sockaddr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x20,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,0x10(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,0x8(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,(%rbx)
  mov    %rbx,(%r12)
  movq   $0x20,0x0(%rbp)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void atmpvc_gen_sockaddr(unsigned long *addr, unsigned long *addrlen) {
  struct sockaddr_atmpvc *atmpvc;
  atmpvc = malloc(sizeof(struct sockaddr_atmpvc));
  if (atmpvc == NULL)
    return;
  atmpvc->sap_family = PF_ATMPVC;
  atmpvc->sap_addr.itf = rand();
  atmpvc->sap_addr.vpi = rand();
  atmpvc->sap_addr.vci = rand();
  *addr = (unsigned long)atmpvc;
  *addrlen = sizeof(struct sockaddr_atmpvc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<atmpvc_gen_sockaddr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x20,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,0x10(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,0x8(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,(%rbx)
  mov    %rbx,(%r12)
  movq   $0x20,0x0(%rbp)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void atmpvc_gen_sockaddr(unsigned long *addr, unsigned long *addrlen) {
  struct sockaddr_atmpvc *atmpvc;
  atmpvc = malloc(sizeof(struct sockaddr_atmpvc));
  if (atmpvc == NULL)
    return;
  atmpvc->sap_family = PF_ATMPVC;
  atmpvc->sap_addr.itf = rand();
  atmpvc->sap_addr.vpi = rand();
  atmpvc->sap_addr.vci = rand();
  *addr = (unsigned long)atmpvc;
  *addrlen = sizeof(struct sockaddr_atmpvc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glmComputeBarycentricCoordinates3f>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
  mov    %rsi,%rdx
  mov    %rcx,%rsi
  mov    %r12,%rdi
  call   <glmMakeVector3f@plt>
  lea    0x20(%rsp),%rbp
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <glmMakeVector3f@plt>
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <glmDotProduct3f@plt>
  movss  %xmm0,(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <glmDotProduct3f@plt>
  movss  %xmm0,0x4(%rsp)
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <glmDotProduct3f@plt>
  movss  %xmm0,0x8(%rsp)
  lea    0x2c(%rsp),%r14
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <glmMakeVector3f@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <glmDotProduct3f@plt>
  movss  %xmm0,0xc(%rsp)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <glmDotProduct3f@plt>
  movss  (%rsp),%xmm1
  mulss  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm5
  movaps %xmm5,%xmm2
  mulss  %xmm5,%xmm2
  subss  %xmm2,%xmm1
  ucomiss D2(%rip),%xmm1
  jp     L37
  je     L14
L37:
  movss  D15(%rip),%xmm3
  movaps %xmm3,%xmm4
  divss  %xmm1,%xmm4
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm7
  mulss  %xmm7,%xmm1
  movss  0x4(%rsp),%xmm6
  movaps %xmm6,%xmm2
  mulss  %xmm0,%xmm2
  subss  %xmm2,%xmm1
  mulss  %xmm4,%xmm1
  mulss  %xmm7,%xmm6
  mulss  (%rsp),%xmm0
  subss  %xmm6,%xmm0
  mulss  %xmm4,%xmm0
  subss  %xmm1,%xmm3
  movaps %xmm3,%xmm2
  subss  %xmm0,%xmm2
L4:
  movss  %xmm1,(%rbx)
  movss  %xmm0,0x4(%rbx)
  movss  %xmm2,0x8(%rbx)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  movaps %xmm1,%xmm2
  jmp    L4
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D15
data_type: f32

tool: {"D2": [0x00,0x00,0x00,0x00]}

tool: D15: 1

assistant: ```c
void glmComputeBarycentricCoordinates3f(float result[3], const float v1[3], const float v2[3], const float v3[3], const float p[3]) {
  float a, b, c, u, v, D;
  float tv1[3], tv2[3], tv3[3];
  glmMakeVector3f(tv1, v3, v1);
  glmMakeVector3f(tv2, v3, v2);
  a = glmDotProduct3f(tv1, tv1);
  b = glmDotProduct3f(tv2, tv1);
  c = glmDotProduct3f(tv2, tv2);
  glmMakeVector3f(tv3, v3, p);
  u = glmDotProduct3f(tv3, tv1);
  v = glmDotProduct3f(tv3, tv2);
  D = a * c - b * b;
  if (D == 0) {
    result[0] = 0;
    result[1] = 0;
    result[2] = 0;
    return;
  }
  D = 1.0 / D;
  result[0] = (c * u - b * v) * D;
  result[1] = (-b * u + a * v) * D;
  result[2] = 1 - result[0] - result[1];
}
```