ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mixed_volume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x4e,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mixed_volume(int *mv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(78, mv, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<mixed_volume>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x4e,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mixed_volume(int *mv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(78, mv, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mixed_volume>:
  endbr64
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x4e,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int mixed_volume(int *mv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(78, mv, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mixed_volume>:
  endbr64
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x4e,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int mixed_volume(int *mv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(78, mv, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert_l_be_shifted>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %ecx,%edi
  mov    %ecx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <ojp_ntohl@plt>
  mov    %eax,0xc(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x5,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    (%r12,%r13,1),%ebx
  mov    %ebx,%edi
  call   <get_local_offset@plt>
  mov    %eax,%edi
  mov    $0x8,%r8d
  sub    %eax,%r8d
  mov    0x1c(%rsp),%eax
  mov    %r8d,%ecx
  shl    %cl,%eax
  mov    %eax,0x30(%rsp)
  mov    $0xc,%eax
  lea    0xc(%rsp),%r9
L35:
  mov    0x10(%rsp,%rax,1),%edx
  mov    %edi,%ecx
  sar    %cl,%edx
  mov    (%r9,%rax,1),%esi
  mov    %r8d,%ecx
  shl    %cl,%esi
  or     %esi,%edx
  mov    %edx,0x20(%rsp,%rax,1)
  sub    $0x4,%rax
  jne    L35
  mov    0x10(%rsp),%eax
  mov    %edi,%ecx
  sar    %cl,%eax
  mov    %eax,0x20(%rsp)
  sar    $0x3,%r12d
  sub    %edi,%r13d
  lea    0x7(%r13),%edx
  sar    $0x3,%edx
  mov    $0x4,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L13
  cltq
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,4),%rdx
L17:
  mov    0x20(%rsp,%rax,4),%ecx
  or     %ecx,(%rdx)
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    $0x4,%eax
  jbe    L17
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %ebx,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t insert_l_be_shifted(uint8_t *bufferOut, uint32_t bitOffset, uint32_t bitSize, uint32_t val) {
  int ii;
  uint32_t jj;
  uint32_t o;
  uint8_t arrayval[sizeof(val)];
  uint8_t result[sizeof(val) + 1];
  uint8_t sl;
  uint32_t bytes;
  val = ojp_ntohl(val);
  memset(result, 0, sizeof(val) + 1);
  memcpy(arrayval, &val, sizeof(val));
  sl = get_local_offset(bitOffset + bitSize);
  result[sizeof(val)] = arrayval[sizeof(val) - 1] << (8 - sl);
  for (ii = sizeof(val) - 1; ii >= 1; --ii) {
    result[ii] = (arrayval[ii] >> sl) | (arrayval[ii - 1] << (8 - sl));
  }
  result[0] = arrayval[0] >> sl;
  jj = 0;
  o = bitOffset >> 3;
  bytes = ((bitSize + (7 - sl)) >> 3) + 1;
  for (ii = sizeof(val) + 1 - bytes; ii < sizeof(val) + 1; ++ii) {
    bufferOut[o + jj] |= result[ii];
    ++jj;
  }
  return bitOffset + bitSize;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insert_l_be_shifted>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ecx,%edi
  lea    0x0(%rbp,%r13,1),%r14d
  sub    $0x40,%rsp
  mov    %ecx,0xc(%rsp)
  lea    0x20(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <ojp_ntohl@plt>
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %eax,0xc(%rsp)
  call   <memset@plt>
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    %r14d,%edi
  call   <get_local_offset@plt>
  mov    0x1c(%rsp),%esi
  mov    $0x8,%r8d
  lea    0x18(%rsp),%r11
  sub    %eax,%r8d
  mov    %eax,%edi
  lea    0x2c(%rsp),%r10
  mov    %esi,%eax
  mov    %r8d,%ecx
  shl    %cl,%eax
  mov    %eax,0x30(%rsp)
  xor    %eax,%eax
L9:
  mov    %edi,%ecx
  sar    %cl,%esi
  mov    %r8d,%ecx
  mov    %esi,%r9d
  mov    (%r11,%rax,1),%esi
  mov    %esi,%edx
  shl    %cl,%edx
  or     %r9d,%edx
  mov    %edx,(%r10,%rax,1)
  sub    $0x4,%rax
  cmp    $0xfffffffffffffff4,%rax
  jne    L9
  mov    0x10(%rsp),%eax
  mov    %edi,%ecx
  sub    %edi,%r13d
  sar    $0x3,%ebp
  lea    0x7(%r13),%edx
  sar    %cl,%eax
  sar    $0x3,%edx
  mov    %eax,0x20(%rsp)
  mov    $0x4,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L2
  movslq %ebp,%rbp
  cltq
  lea    (%rbx,%rbp,4),%rdx
  nopl   0x0(%rax,%rax,1)
L24:
  mov    (%r12,%rax,4),%ecx
  add    $0x1,%rax
  or     %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    $0x4,%eax
  jbe    L24
L2:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t insert_l_be_shifted(uint8_t *bufferOut, uint32_t bitOffset, uint32_t bitSize, uint32_t val) {
  int ii;
  uint32_t jj;
  uint32_t o;
  uint8_t arrayval[sizeof(val)];
  uint8_t result[sizeof(val) + 1];
  uint8_t sl;
  uint32_t bytes;
  val = ojp_ntohl(val);
  memset(result, 0, sizeof(val) + 1);
  memcpy(arrayval, &val, sizeof(val));
  sl = get_local_offset(bitOffset + bitSize);
  result[sizeof(val)] = arrayval[sizeof(val) - 1] << (8 - sl);
  for (ii = sizeof(val) - 1; ii >= 1; --ii) {
    result[ii] = (arrayval[ii] >> sl) | (arrayval[ii - 1] << (8 - sl));
  }
  result[0] = arrayval[0] >> sl;
  jj = 0;
  o = bitOffset >> 3;
  bytes = ((bitSize + (7 - sl)) >> 3) + 1;
  for (ii = sizeof(val) + 1 - bytes; ii < sizeof(val) + 1; ++ii) {
    bufferOut[o + jj] |= result[ii];
    ++jj;
  }
  return bitOffset + bitSize;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitarray_OR_SSE2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x7ffff,-0x4(%rbp)
  jle    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void bitarray_OR_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  for (uint32_t i = 0; i < (1 << 19); i++) {
    A[i] |= B[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitarray_OR_SSE2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    $0x10,%esi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    $0x0,%edx
L2:
  mov    (%rax,%rdx,1),%ecx
  or     %ecx,(%rbx,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x200000,%rdx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bitarray_OR_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  for (uint32_t i = 0; i < (1 << 19); i++) {
    A[i] |= B[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bitarray_OR_SSE2>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x10,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <__builtin_assume_aligned@plt>
  mov    $0x10,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <__builtin_assume_aligned@plt>
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  mov    (%rax,%rdx,1),%ecx
  or     %ecx,(%rbx,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x200000,%rdx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bitarray_OR_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  for (uint32_t i = 0; i < (1 << 19); i++) {
    A[i] |= B[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitarray_OR_SSE2>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x10,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <__builtin_assume_aligned@plt>
  mov    $0x10,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <__builtin_assume_aligned@plt>
  mov    %rbx,%rdx
  lea    0x4(%rax),%rcx
  sub    %rcx,%rdx
  cmp    $0x8,%rdx
  mov    $0x0,%edx
  jbe    L29
  nopl   0x0(%rax)
L10:
  movdqu (%rbx,%rdx,1),%xmm0
  movdqu (%rax,%rdx,1),%xmm1
  por    %xmm1,%xmm0
  movups %xmm0,(%rbx,%rdx,1)
  add    $0x10,%rdx
  cmp    $0x200000,%rdx
  jne    L10
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    (%rax,%rdx,1),%ecx
  or     %ecx,(%rbx,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x200000,%rdx
  jne    L29
  jmp    L21
```

assistant: ```c
void bitarray_OR_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  for (uint32_t i = 0; i < (1 << 19); i++) {
    A[i] |= B[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L7
  mov    -0x18(%rbp),%rax
  jmp    L9
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

assistant: ```c
char *Strdup(s)
char *s;
{
  char *cs;
  if (!s)
    return s;
  cs = malloc(strlen(s) + 1);
  strcpy(cs, s);
  return cs;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L8:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *Strdup(s)
char *s;
{
  char *cs;
  if (!s)
    return s;
  cs = malloc(strlen(s) + 1);
  strcpy(cs, s);
  return cs;
}
```
user: What is the c source code of the assembly code below:

```asm
<Strdup>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *Strdup(s)
char *s;
{
  char *cs;
  if (!s)
    return s;
  cs = malloc(strlen(s) + 1);
  strcpy(cs, s);
  return cs;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Strdup>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *Strdup(s)
char *s;
{
  char *cs;
  if (!s)
    return s;
  cs = malloc(strlen(s) + 1);
  strcpy(cs, s);
  return cs;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<A7read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <A7board_available@plt>
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  call   <A7_command_read_string@plt>
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: 

assistant: ```c
char *A7read() {
  char *reply = "";
  if (A7board_available()) {
    reply = A7_command_read_string();
  }
  return reply;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<A7read>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <A7board_available@plt>
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  test   %rdx,%rdx
  jne    L1
L16:
  add    $0x8,%rsp
  ret
L1:
  mov    $0x0,%eax
  call   <A7_command_read_string@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: 

assistant: ```c
char *A7read() {
  char *reply = "";
  if (A7board_available()) {
    reply = A7_command_read_string();
  }
  return reply;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<A7read>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <A7board_available@plt>
  test   %rax,%rax
  jne    L7
  lea    D6(%rip),%rax
  add    $0x8,%rsp
  ret
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <A7_command_read_string@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: 

assistant: ```c
char *A7read() {
  char *reply = "";
  if (A7board_available()) {
    reply = A7_command_read_string();
  }
  return reply;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<A7read>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <A7board_available@plt>
  test   %rax,%rax
  jne    L4
  lea    D9(%rip),%rax
  add    $0x8,%rsp
  ret
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <A7_command_read_string@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: 

assistant: ```c
char *A7read() {
  char *reply = "";
  if (A7board_available()) {
    reply = A7_command_read_string();
  }
  return reply;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  nop
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L3
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  jmp    L12
L3:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D8: %d %d %d %d

tool: D9: %d %d %d


assistant: ```c
int main() {
  int a, b, c, i;
  scanf("%d %d %d %d", &a, &b, &c, &i);
  while (i >= 0) {
    rotr(&a, &b, &c);
    printf("%d %d %d\n", a, b, c);
    i--;
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jns    L25
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L25:
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D11
type: string

tool: D12: %d %d %d %d

tool: D11: %d %d %d


assistant: ```c
int main() {
  int a, b, c, i;
  scanf("%d %d %d %d", &a, &b, &c, &i);
  while (i >= 0) {
    rotr(&a, &b, &c);
    printf("%d %d %d\n", a, b, c);
    i--;
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    0x14(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  js     L19
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D19(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string

tool: D10: %d %d %d %d

tool: D19: %d %d %d


assistant: ```c
int main() {
  int a, b, c, i;
  scanf("%d %d %d %d", &a, &b, &c, &i);
  while (i >= 0) {
    rotr(&a, &b, &c);
    printf("%d %d %d\n", a, b, c);
    i--;
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    0x14(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  js     L7
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D2(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D2
data_type: string

tool: D16: %d %d %d %d

tool: D2: %d %d %d


assistant: ```c
int main() {
  int a, b, c, i;
  scanf("%d %d %d %d", &a, &b, &c, &i);
  while (i >= 0) {
    rotr(&a, &b, &c);
    printf("%d %d %d\n", a, b, c);
    i--;
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<path_append>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x2,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x28(%rbp)
  movb   $0x2f,-0x19(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x19(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *path_append(const char *basedir, const char *append) {
  char *r = calloc(strlen(basedir) + strlen(append) + 1 + 1, sizeof(char));
  char sep[] = {'/'};
  strcat(r, basedir);
  strcat(r, sep);
  strcat(r, append);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<path_append>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  movb   $0x2f,0x7(%rsp)
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *path_append(const char *basedir, const char *append) {
  char *r = calloc(strlen(basedir) + strlen(append) + 1 + 1, sizeof(char));
  char sep[] = {'/'};
  strcat(r, basedir);
  strcat(r, sep);
  strcat(r, append);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<path_append>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x2(%r12,%rax,1),%rdi
  call   <calloc@plt>
  mov    %r13,%rsi
  movb   $0x2f,0x7(%rsp)
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    0x7(%rsp),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *path_append(const char *basedir, const char *append) {
  char *r = calloc(strlen(basedir) + strlen(append) + 1 + 1, sizeof(char));
  char sep[] = {'/'};
  strcat(r, basedir);
  strcat(r, sep);
  strcat(r, append);
  return r;
}
```