ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int a = 5;
  double b = 1.2;
  long answer = a * b;
  printf("%ld\n", answer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int a = 5;
  double b = 1.2;
  long answer = a * b;
  printf("%ld\n", answer);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CurveGLInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glLoadIdentity@plt>
  mov    $0xffffffff,%r9d
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <glOrtho@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glLoadIdentity@plt>
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <glLineStipple@plt>
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glEnable@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glDepthFunc@plt>
  mov    $0x0,%eax
  call   <glFlush@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CurveGLInit(void) {
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  glOrtho(0, 1, 0, 5, 1, -1);
  glMatrixMode(GL_MODELVIEW);
  glLoadIdentity();
  glLineStipple(1, 0x00FF);
  glEnable(GL_DEPTH_TEST);
  glDepthFunc(GL_LEQUAL);
  glFlush();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CurveGLInit>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glLoadIdentity@plt>
  mov    $0xffffffff,%r9d
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <glOrtho@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glLoadIdentity@plt>
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <glLineStipple@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <glEnable@plt>
  mov    D38(%rip),%rax
  mov    (%rax),%edi
  call   <glDepthFunc@plt>
  mov    $0x0,%eax
  call   <glFlush@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void CurveGLInit(void) {
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  glOrtho(0, 1, 0, 5, 1, -1);
  glMatrixMode(GL_MODELVIEW);
  glLoadIdentity();
  glLineStipple(1, 0x00FF);
  glEnable(GL_DEPTH_TEST);
  glDepthFunc(GL_LEQUAL);
  glFlush();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CurveGLInit>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glLoadIdentity@plt>
  mov    $0xffffffff,%r9d
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    $0x1,%esi
  call   <glOrtho@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glLoadIdentity@plt>
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <glLineStipple@plt>
  mov    D39(%rip),%rax
  mov    (%rax),%edi
  call   <glEnable@plt>
  mov    D36(%rip),%rax
  mov    (%rax),%edi
  call   <glDepthFunc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <glFlush@plt>
```

assistant: ```c
void CurveGLInit(void) {
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  glOrtho(0, 1, 0, 5, 1, -1);
  glMatrixMode(GL_MODELVIEW);
  glLoadIdentity();
  glLineStipple(1, 0x00FF);
  glEnable(GL_DEPTH_TEST);
  glDepthFunc(GL_LEQUAL);
  glFlush();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CurveGLInit>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glLoadIdentity@plt>
  mov    $0xffffffff,%r9d
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    $0x1,%esi
  call   <glOrtho@plt>
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glLoadIdentity@plt>
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <glLineStipple@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <glEnable@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <glDepthFunc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <glFlush@plt>
```

assistant: ```c
void CurveGLInit(void) {
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  glOrtho(0, 1, 0, 5, 1, -1);
  glMatrixMode(GL_MODELVIEW);
  glLoadIdentity();
  glLineStipple(1, 0x00FF);
  glEnable(GL_DEPTH_TEST);
  glDepthFunc(GL_LEQUAL);
  glFlush();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strchomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: 


assistant: ```c
char *strchomp(char *string) {
  string[strcspn(string, "\r\n")] = '\0';
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rsi
  call   <strcspn@plt>
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: 


assistant: ```c
char *strchomp(char *string) {
  string[strcspn(string, "\r\n")] = '\0';
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strchomp>:
  endbr64
  push   %r12
  lea    D7(%rip),%rsi
  mov    %rdi,%r12
  call   <strcspn@plt>
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: D7: 


assistant: ```c
char *strchomp(char *string) {
  string[strcspn(string, "\r\n")] = '\0';
  return string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strchomp>:
  endbr64
  push   %r12
  lea    D0(%rip),%rsi
  mov    %rdi,%r12
  call   <strcspn@plt>
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: 


assistant: ```c
char *strchomp(char *string) {
  string[strcspn(string, "\r\n")] = '\0';
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SLF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L10:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int SLF(const char s[]) {
  int len = 0;
  while (s[len] != '\0')
    ++len;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<SLF>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  mov    $0x1,%eax
L1:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L1
L16:
  mov    %edx,%eax
  ret
L19:
  mov    $0x0,%edx
  jmp    L16
```

assistant: ```c
int SLF(const char s[]) {
  int len = 0;
  while (s[len] != '\0')
    ++len;
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SLF>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L15
  mov    $0x1,%eax
  xchg   %ax,%ax
L6:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int SLF(const char s[]) {
  int len = 0;
  while (s[len] != '\0')
    ++len;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SLF>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L14
  mov    $0x1,%eax
  xchg   %ax,%ax
L1:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L1
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int SLF(const char s[]) {
  int len = 0;
  while (s[len] != '\0')
    ++len;
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<keyboard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0x1b,%eax
  je     L25
  cmp    $0x20,%eax
  jne    L22
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  nop
  jmp    L22
L25:
  mov    $0x0,%edi
  call   <exit@plt>
L22:
  nop
  leave
  ret
```

assistant: ```c
void keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case ' ':
    glutPostRedisplay();
    break;
  case 27:
    exit(0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<keyboard>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1b,%dil
  je     L13
  cmp    $0x20,%dil
  jne    L5
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
L5:
  add    $0x8,%rsp
  ret
L13:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L5
```

assistant: ```c
void keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case ' ':
    glutPostRedisplay();
    break;
  case 27:
    exit(0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<keyboard>:
  endbr64
  cmp    $0x1b,%dil
  je     L12
  cmp    $0x20,%dil
  jne    L10
  xor    %eax,%eax
  jmp    1060 <glutPostRedisplay@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %edi,%edi
  jmp    1070 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
void keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case ' ':
    glutPostRedisplay();
    break;
  case 27:
    exit(0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<keyboard>:
  endbr64
  cmp    $0x1b,%dil
  je     L15
  cmp    $0x20,%dil
  jne    L12
  xor    %eax,%eax
  jmp    1060 <glutPostRedisplay@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %edi,%edi
  jmp    1070 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case ' ':
    glutPostRedisplay();
    break;
  case 27:
    exit(0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<encodestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movw   $0x10ea,-0x2(%rbp)
  jmp    L8
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x4(%rbp)
  movzwl -0x2(%rbp),%eax
  shr    $0x8,%ax
  xor    -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x3(%rbp),%edx
  movzwl -0x2(%rbp),%eax
  add    %edx,%eax
  imul   $0xce6d,%ax,%ax
  add    $0x58bf,%ax
  mov    %ax,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x3(%rbp),%edx
  mov    %dl,(%rax)
L8:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jg     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void encodestr(unsigned char *str, int len) {
  unsigned short r = 4330;
  unsigned char plain, cypher;
  while (len-- > 0) {
    plain = *str;
    cypher = (plain ^ (r >> 8));
    r = (cypher + r) * (unsigned short)52845 + (unsigned short)22719;
    *str++ = cypher;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encodestr>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %esi,%esi
  add    %rdi,%rsi
  mov    $0x10ea,%eax
L13:
  mov    %eax,%edx
  shr    $0x8,%dx
  xor    (%rdi),%dl
  movzbl %dl,%ecx
  add    %ecx,%eax
  imul   $0xce6d,%ax,%ax
  add    $0x58bf,%ax
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  cmp    %rsi,%rdi
  jne    L13
L4:
  ret
```

assistant: ```c
void encodestr(unsigned char *str, int len) {
  unsigned short r = 4330;
  unsigned char plain, cypher;
  while (len-- > 0) {
    plain = *str;
    cypher = (plain ^ (r >> 8));
    r = (cypher + r) * (unsigned short)52845 + (unsigned short)22719;
    *str++ = cypher;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<encodestr>:
  endbr64
  test   %esi,%esi
  jle    L8
  movslq %esi,%rsi
  mov    $0x10ea,%eax
  add    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %eax,%edx
  add    $0x1,%rdi
  shr    $0x8,%dx
  xor    -0x1(%rdi),%dl
  movzbl %dl,%ecx
  mov    %dl,-0x1(%rdi)
  add    %ecx,%eax
  imul   $0xce6d,%ax,%ax
  add    $0x58bf,%ax
  cmp    %rsi,%rdi
  jne    L14
L8:
  ret
```

assistant: ```c
void encodestr(unsigned char *str, int len) {
  unsigned short r = 4330;
  unsigned char plain, cypher;
  while (len-- > 0) {
    plain = *str;
    cypher = (plain ^ (r >> 8));
    r = (cypher + r) * (unsigned short)52845 + (unsigned short)22719;
    *str++ = cypher;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encodestr>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  mov    $0x10ea,%eax
  add    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %eax,%edx
  add    $0x1,%rdi
  shr    $0x8,%dx
  xor    -0x1(%rdi),%dl
  movzbl %dl,%ecx
  mov    %dl,-0x1(%rdi)
  add    %ecx,%eax
  imul   $0xce6d,%ax,%ax
  add    $0x58bf,%ax
  cmp    %rsi,%rdi
  jne    L11
L7:
  ret
```

assistant: ```c
void encodestr(unsigned char *str, int len) {
  unsigned short r = 4330;
  unsigned char plain, cypher;
  while (len-- > 0) {
    plain = *str;
    cypher = (plain ^ (r >> 8));
    r = (cypher + r) * (unsigned short)52845 + (unsigned short)22719;
    *str++ = cypher;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstrmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L7
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  jmp    L1
L7:
  mov    $0x0,%eax
L1:
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L18
L11:
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
L18:
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L36
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L43
L36:
  mov    $0x0,%eax
L43:
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strstrmove(char *whither, const char *whence, const char *restrict str) {
  const char *stop = str == NULL ? NULL : strstr(whence, str);
  size_t n = stop == NULL ? strlen(whence) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  whither[n] = 0;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstrmove>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdx,%rdx
  je     L18
  mov    %rdx,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  sub    %rbx,%r12
  lea    0x0(%rbp,%r12,1),%r13
  test   %rax,%rax
  jne    L7
L18:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    $0x0,%r13d
L7:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstrmove(char *whither, const char *whence, const char *restrict str) {
  const char *stop = str == NULL ? NULL : strstr(whence, str);
  size_t n = stop == NULL ? strlen(whence) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  whither[n] = 0;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstrmove>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L4
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L4
  sub    %rbp,%rdx
  lea    (%r12,%rdx,1),%r13
  mov    %r13,%rbx
L2:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  call   <strlen@plt>
  mov    %rax,%rdx
  lea    (%r12,%rax,1),%rbx
  jmp    L2
```

assistant: ```c
char *strstrmove(char *whither, const char *whence, const char *restrict str) {
  const char *stop = str == NULL ? NULL : strstr(whence, str);
  size_t n = stop == NULL ? strlen(whence) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  whither[n] = 0;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strstrmove>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L28
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L28
  sub    %rbp,%rdx
  lea    (%r12,%rdx,1),%r13
  mov    %r13,%rbx
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  call   <strlen@plt>
  mov    %rax,%rdx
  lea    (%r12,%rax,1),%rbx
  jmp    L10
```

assistant: ```c
char *strstrmove(char *whither, const char *whence, const char *restrict str) {
  const char *stop = str == NULL ? NULL : strstr(whence, str);
  size_t n = stop == NULL ? strlen(whence) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  whither[n] = 0;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigismember@plt>
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L4
L28:
  mov    $0x1,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  sigset_t mask;
  sigemptyset(&mask);
  sigprocmask(SIG_BLOCK, NULL, &mask);
  if (!sigismember(&mask, SIGCHLD))
    return 0;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigismember@plt>
  test   %eax,%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movzbl %al,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  sigset_t mask;
  sigemptyset(&mask);
  sigprocmask(SIG_BLOCK, NULL, &mask);
  if (!sigismember(&mask, SIGCHLD))
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D9(%rip),%rax
  xor    %esi,%esi
  mov    %rbp,%rdx
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    D15(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigismember@plt>
  test   %eax,%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  sigset_t mask;
  sigemptyset(&mask);
  sigprocmask(SIG_BLOCK, NULL, &mask);
  if (!sigismember(&mask, SIGCHLD))
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D10(%rip),%rax
  xor    %esi,%esi
  mov    %rbp,%rdx
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    D12(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigismember@plt>
  test   %eax,%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  sigset_t mask;
  sigemptyset(&mask);
  sigprocmask(SIG_BLOCK, NULL, &mask);
  if (!sigismember(&mask, SIGCHLD))
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x0,-0x4(%rbp)
  je     L35
  nop
  jmp    L42
L8:
  nop
L42:
  cmpl   $0x0,-0x4(%rbp)
  je     L57
  jmp    L50
L35:
  nop
L50:
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  jmp    L1
L57:
  nop
L1:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int x;
  if (x) {
    goto L1;
  } else {
    goto L2;
  }
L1:
  if (x) {
    goto L2;
  } else {
    goto end;
  }
L2:
  if (x) {
    goto L1;
  } else {
    goto end;
  }
end:;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int x;
  if (x) {
    goto L1;
  } else {
    goto L2;
  }
L1:
  if (x) {
    goto L2;
  } else {
    goto end;
  }
L2:
  if (x) {
    goto L1;
  } else {
    goto end;
  }
end:;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int x;
  if (x) {
    goto L1;
  } else {
    goto L2;
  }
L1:
  if (x) {
    goto L2;
  } else {
    goto end;
  }
L2:
  if (x) {
    goto L1;
  } else {
    goto end;
  }
end:;
}
```
user: Translate the below assembly code into C programming language:

```asm
<emptystr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *emptystr() {
  char *str;
  str = (char *)malloc(sizeof(char));
  *str = 0;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<emptystr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *emptystr() {
  char *str;
  str = (char *)malloc(sizeof(char));
  *str = 0;
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emptystr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *emptystr() {
  char *str;
  str = (char *)malloc(sizeof(char));
  *str = 0;
  return str;
}
```