ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<fitsBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x20,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int shamt = 32 + (~n + 1);
  return !((x << shamt >> shamt) ^ x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fitsBits>:
  endbr64
  mov    $0x20,%ecx
  sub    %esi,%ecx
  mov    %edi,%eax
  shl    %cl,%eax
  sar    %cl,%eax
  cmp    %edi,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int shamt = 32 + (~n + 1);
  return !((x << shamt >> shamt) ^ x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fitsBits>:
  endbr64
  mov    $0x20,%ecx
  mov    %edi,%eax
  sub    %esi,%ecx
  shl    %cl,%eax
  sar    %cl,%eax
  cmp    %edi,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int shamt = 32 + (~n + 1);
  return !((x << shamt >> shamt) ^ x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fitsBits>:
  endbr64
  mov    $0x20,%ecx
  mov    %edi,%eax
  sub    %esi,%ecx
  shl    %cl,%eax
  sar    %cl,%eax
  cmp    %edi,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int shamt = 32 + (~n + 1);
  return !((x << shamt >> shamt) ^ x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L12:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char *s) {
  int count = 0;
  while (*s++ != '\0')
    count++;
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L16
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L18:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L18
L8:
  mov    %ecx,%eax
  ret
L16:
  mov    $0x0,%ecx
  jmp    L8
```

assistant: ```c
int strlen(char *s) {
  int count = 0;
  while (*s++ != '\0')
    count++;
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L16
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L14:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char *s) {
  int count = 0;
  while (*s++ != '\0')
    count++;
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L3
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L14:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char *s) {
  int count = 0;
  while (*s++ != '\0')
    count++;
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_time_nsec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
long long get_time_nsec() {
  struct timespec spec;
  clock_gettime(CLOCK_REALTIME, &spec);
  return spec.tv_sec * (1000LL * 1000 * 1000) + spec.tv_nsec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_time_nsec>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_time_nsec() {
  struct timespec spec;
  clock_gettime(CLOCK_REALTIME, &spec);
  return spec.tv_sec * (1000LL * 1000 * 1000) + spec.tv_nsec;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_time_nsec>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_time_nsec() {
  struct timespec spec;
  clock_gettime(CLOCK_REALTIME, &spec);
  return spec.tv_sec * (1000LL * 1000 * 1000) + spec.tv_nsec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_time_nsec>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_time_nsec() {
  struct timespec spec;
  clock_gettime(CLOCK_REALTIME, &spec);
  return spec.tv_sec * (1000LL * 1000 * 1000) + spec.tv_nsec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<padcon_get_homotopy_continuation_parameter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  cmp    $0x2,%eax
  je     L16
  mov    -0x14(%rbp),%eax
  cmp    $0x3,%eax
  je     L16
  mov    -0x14(%rbp),%eax
  cmp    $0xb,%eax
  je     L16
  mov    -0x14(%rbp),%eax
  cmp    $0xc,%eax
  jne    L15
L16:
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L32
L15:
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int padcon_get_homotopy_continuation_parameter(int k, double *val) {
  int fail, parval;
  if ((k == 2) || (k == 3) || (k == 11) || (k == 12)) {
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
    *val = (double)parval;
  } else
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<padcon_get_homotopy_continuation_parameter>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  lea    -0x2(%rdi),%edx
  cmp    $0x1,%edx
  jbe    L33
  mov    %edi,%eax
  sub    $0xb,%eax
  cmp    $0x1,%eax
  ja     L8
L33:
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    %rbx,%rcx
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    %rbx,%rcx
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  jmp    L35
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_homotopy_continuation_parameter(int k, double *val) {
  int fail, parval;
  if ((k == 2) || (k == 3) || (k == 11) || (k == 12)) {
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
    *val = (double)parval;
  } else
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<padcon_get_homotopy_continuation_parameter>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x0,%r8d
  mov    %r12,%rcx
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  lea    -0x2(%rdi),%edx
  cmp    $0x1,%edx
  lea    0x14(%rsp),%rdx
  jbe    L9
  mov    %edi,%eax
  sub    $0xb,%eax
  cmp    $0x1,%eax
  ja     L17
L9:
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm0
  movsd  %xmm0,(%r12)
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x20,%rsp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  jmp    L23
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_homotopy_continuation_parameter(int k, double *val) {
  int fail, parval;
  if ((k == 2) || (k == 3) || (k == 11) || (k == 12)) {
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
    *val = (double)parval;
  } else
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<padcon_get_homotopy_continuation_parameter>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x0,%r8d
  mov    %r12,%rcx
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  lea    -0x2(%rdi),%edx
  cmp    $0x1,%edx
  lea    0x14(%rsp),%rdx
  jbe    L0
  mov    %edi,%eax
  sub    $0xb,%eax
  cmp    $0x1,%eax
  ja     L4
L0:
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm0
  movsd  %xmm0,(%r12)
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x20,%rsp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x2e1,%edi
  call   <_ada_use_c2phc4c@plt>
  jmp    L8
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_homotopy_continuation_parameter(int k, double *val) {
  int fail, parval;
  if ((k == 2) || (k == 3) || (k == 11) || (k == 12)) {
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
    *val = (double)parval;
  } else
    fail = _ada_use_c2phc4c(737, &k, &parval, val, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L1:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  mov    -0x14(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int factorial(int j) {
  int sum;
  if (j == 0)
    sum = 1;
  else
    sum = j * factorial(j - 1);
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L3
  ret
L3:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int factorial(int j) {
  int sum;
  if (j == 0)
    sum = 1;
  else
    sum = j * factorial(j - 1);
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L9
  nopl   (%rax)
L8:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L8
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
int factorial(int j) {
  int sum;
  if (j == 0)
    sum = 1;
  else
    sum = j * factorial(j - 1);
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L19
  nopl   (%rax)
L3:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L3
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
int factorial(int j) {
  int sum;
  if (j == 0)
    sum = 1;
  else
    sum = j * factorial(j - 1);
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<block_quote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next@plt>
  cmp    $0x3e,%eax
  jne    L5
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parser_emit_string@plt>
  jmp    L18
L72:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  jne    L105
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parser_emit_string@plt>
  mov    $0x1,%eax
  jmp    L37
L105:
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <match@plt>
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L37
L28:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next@plt>
  cmp    $0xa,%eax
  je     L75
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  jne    L55
L75:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <consume@plt>
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parser_emit_string@plt>
  mov    $0x1,%eax
  jmp    L37
L55:
  mov    -0x8(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <parser_emit_char@plt>
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <block_quote_line@plt>
  test   %rax,%rax
  jne    L72
  mov    $0x1,%eax
  jmp    L37
L5:
  mov    $0x0,%eax
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D18
type: string

tool: D1: <blockquote>

tool: D18: </blockquote>

assistant: ```c
bool block_quote(struct cymkd_parser *parser) {
  if (next(parser) == '>') {
    parser_emit_string(parser, "<blockquote>");
    while (block_quote_line(parser)) {
      if (next(parser) == -1) {
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      if (!match(parser, '\n')) {
        return false;
      }
      if (next(parser) == '\n' || next(parser) == -1) {
        consume(parser);
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      parser_emit_char(parser, ' ');
    }
    return true;
  }
  return false;
}
```
user: What is the c source code of the assembly code below:

```asm
<block_quote>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <next@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x3e,%edx
  je     L96
L33:
  pop    %rbx
  ret
L96:
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <parser_emit_string@plt>
L64:
  mov    %rbx,%rdi
  call   <block_quote_line@plt>
  test   %rax,%rax
  je     L47
  mov    %rbx,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  je     L53
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <match@plt>
  test   %eax,%eax
  je     L33
  mov    %rbx,%rdi
  call   <next@plt>
  cmp    $0xa,%eax
  je     L31
  mov    %rbx,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  je     L31
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <parser_emit_char@plt>
  jmp    L64
L53:
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <parser_emit_string@plt>
  mov    $0x1,%eax
  jmp    L33
L31:
  mov    %rbx,%rdi
  call   <consume@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <parser_emit_string@plt>
  mov    $0x1,%eax
  jmp    L33
L47:
  mov    $0x1,%eax
  jmp    L33
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D8
datatype: string

tool: D3: <blockquote>

tool: D8: </blockquote>

assistant: ```c
bool block_quote(struct cymkd_parser *parser) {
  if (next(parser) == '>') {
    parser_emit_string(parser, "<blockquote>");
    while (block_quote_line(parser)) {
      if (next(parser) == -1) {
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      if (!match(parser, '\n')) {
        return false;
      }
      if (next(parser) == '\n' || next(parser) == -1) {
        consume(parser);
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      parser_emit_char(parser, ' ');
    }
    return true;
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<block_quote>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <next@plt>
  cmp    $0x3e,%eax
  je     L45
L26:
  xor    %eax,%eax
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <parser_emit_string@plt>
  jmp    L1
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <match@plt>
  test   %eax,%eax
  je     L26
  mov    %rbp,%rdi
  call   <next@plt>
  cmp    $0xa,%eax
  je     L16
  mov    %rbp,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  je     L16
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <parser_emit_char@plt>
L1:
  mov    %rbp,%rdi
  call   <block_quote_line@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rdi
  call   <consume@plt>
L33:
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <parser_emit_string@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D14: <blockquote>

tool: D8: </blockquote>

assistant: ```c
bool block_quote(struct cymkd_parser *parser) {
  if (next(parser) == '>') {
    parser_emit_string(parser, "<blockquote>");
    while (block_quote_line(parser)) {
      if (next(parser) == -1) {
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      if (!match(parser, '\n')) {
        return false;
      }
      if (next(parser) == '\n' || next(parser) == -1) {
        consume(parser);
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      parser_emit_char(parser, ' ');
    }
    return true;
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<block_quote>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <next@plt>
  cmp    $0x3e,%eax
  je     L12
L58:
  xor    %eax,%eax
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <parser_emit_string@plt>
  jmp    L42
  nopl   0x0(%rax)
L9:
  mov    %rbp,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  je     L63
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <match@plt>
  test   %eax,%eax
  je     L58
  mov    %rbp,%rdi
  call   <next@plt>
  cmp    $0xa,%eax
  je     L5
  mov    %rbp,%rdi
  call   <next@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <parser_emit_char@plt>
L42:
  mov    %rbp,%rdi
  call   <block_quote_line@plt>
  test   %rax,%rax
  jne    L9
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  call   <consume@plt>
L63:
  mov    %rbp,%rdi
  lea    D3(%rip),%rsi
  call   <parser_emit_string@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D8: <blockquote>

tool: D3: </blockquote>

assistant: ```c
bool block_quote(struct cymkd_parser *parser) {
  if (next(parser) == '>') {
    parser_emit_string(parser, "<blockquote>");
    while (block_quote_line(parser)) {
      if (next(parser) == -1) {
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      if (!match(parser, '\n')) {
        return false;
      }
      if (next(parser) == '\n' || next(parser) == -1) {
        consume(parser);
        parser_emit_string(parser, "</blockquote>");
        return true;
      }
      parser_emit_char(parser, ' ');
    }
    return true;
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__add__>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %ecx,%r11d
  and    $0x7,%r11d
  sar    $0x3,%ecx
  je     L0
  mov    %rdi,%rax
  lea    -0x1(%rcx),%edi
  shl    $0x6,%rdi
  lea    0x40(%r8,%rdi,1),%rdi
L4:
  movsd  (%rax),%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rax),%xmm0
  addsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rax),%xmm0
  addsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x18(%rax),%xmm0
  addsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x20(%rax),%xmm0
  addsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x28(%rax),%xmm0
  addsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x28(%rdx)
  movsd  0x30(%rax),%xmm0
  addsd  0x30(%rsi),%xmm0
  movsd  %xmm0,0x30(%rdx)
  movsd  0x38(%rax),%xmm0
  addsd  0x38(%rsi),%xmm0
  movsd  %xmm0,0x38(%rdx)
  add    $0x40,%rax
  add    $0x40,%rsi
  add    $0x40,%rdx
  cmp    %rdi,%rax
  jne    L4
  shl    $0x3,%ecx
L0:
  mov    %r11d,%r11d
  lea    D0(%rip),%rdx
  movslq (%rdx,%r11,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movslq %ecx,%rax
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movsd  (%r8,%rcx,8),%xmm0
  addsd  (%r9,%rcx,8),%xmm0
  movsd  %xmm0,(%r10,%rcx,8)
  ret
```

assistant: ```c
void __add__(dp1, dp2, out, len) register double *dp1, *dp2, *out;
register int len;
{
  register int i;
  register int j, k;
  i = len >> 3;
  j = 0;
  k = len & 7;
  while (i--) {
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
    out[j] = dp1[j] + dp2[j];
    j++;
  }
  switch (k) {
  case 7:
    out[j] = dp1[j] + dp2[j];
    j++;
  case 6:
    out[j] = dp1[j] + dp2[j];
    j++;
  case 5:
    out[j] = dp1[j] + dp2[j];
    j++;
  case 4:
    out[j] = dp1[j] + dp2[j];
    j++;
  case 3:
    out[j] = dp1[j] + dp2[j];
    j++;
  case 2:
    out[j] = dp1[j] + dp2[j];
    j++;
  case 1:
    out[j] = dp1[j] + dp2[j];
    j++;
  }
}
```