ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %edi,-0x814(%rbp)
  mov    %rsi,-0x820(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x814(%rbp)
  jne    L32
  mov    $0x0,%edx
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
L32:
  movl   $0x1,-0x804(%rbp)
  lea    -0x800(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xff,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D23(%rip),%rax
  mov    %rax,-0x800(%rbp)
  jmp    L13
L14:
  mov    -0x804(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x820(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x804(%rbp),%eax
  cltq
  mov    %rdx,-0x800(%rbp,%rax,8)
  addl   $0x1,-0x804(%rbp)
L13:
  mov    -0x804(%rbp),%eax
  cmp    -0x814(%rbp),%eax
  jl     L14
  mov    -0x804(%rbp),%eax
  cltq
  movq   $0x0,-0x800(%rbp,%rax,8)
  lea    -0x800(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <execvp@plt>
  mov    $0xffffffff,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
data_type: string

tool: D23: git

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 0)
    execl("git", "git", NULL);
  int i = 1;
  char *args[255] = {"git"};
  for (; i < argc; i++) {
    args[i] = argv[i];
  }
  args[i] = NULL;
  execvp("git", args);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7f8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L42
  mov    %edi,%r8d
  mov    %rsp,%rdi
  mov    $0xff,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  lea    D11(%rip),%rax
  mov    %rax,(%rsp)
  cmp    $0x1,%r8d
  jle    L21
  mov    %r8d,%ecx
  mov    $0x1,%eax
L58:
  mov    (%rsi,%rax,8),%rdx
  mov    %rdx,(%rsp,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L58
L13:
  movslq %r8d,%r8
  movq   $0x0,(%rsp,%r8,8)
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <execvp@plt>
  mov    0x7f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0xffffffff,%eax
  add    $0x800,%rsp
  pop    %rbx
  ret
L42:
  mov    $0x0,%edx
  lea    D11(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <execl@plt>
  mov    %rsp,%rdi
  mov    $0xff,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rbx,(%rsp)
  mov    $0x1,%r8d
  jmp    L13
L21:
  mov    $0x1,%r8d
  jmp    L13
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string

tool: D11: git

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 0)
    execl("git", "git", NULL);
  int i = 1;
  char *args[255] = {"git"};
  for (; i < argc; i++) {
    args[i] = argv[i];
  }
  args[i] = NULL;
  execvp("git", args);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7f8(%rsp)
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L9
  mov    %rsp,%rbp
  mov    $0xff,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  lea    D9(%rip),%r12
  rep stos %rax,%es:(%rdi)
  mov    %r12,(%rsp)
  cmp    $0x1,%ebx
  jle    L27
  lea    -0x1(%rbx),%edx
  lea    0x8(%rsp),%rdi
  add    $0x8,%rsi
  shl    $0x3,%rdx
  call   <memcpy@plt>
L34:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movq   $0x0,(%rsp,%rbx,8)
  call   <execvp@plt>
  mov    0x7f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x800,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D9(%rip),%r12
  xor    %edx,%edx
  mov    %rsp,%rbp
  mov    $0x1,%ebx
  mov    %r12,%rdi
  mov    %r12,%rsi
  call   <execl@plt>
  mov    $0xff,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r12,(%rsp)
  jmp    L34
L45:
  call   <__stack_chk_fail@plt>
L27:
  mov    $0x1,%ebx
  jmp    L34
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: git

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 0)
    execl("git", "git", NULL);
  int i = 1;
  char *args[255] = {"git"};
  for (; i < argc; i++) {
    args[i] = argv[i];
  }
  args[i] = NULL;
  execvp("git", args);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7f8(%rsp)
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L21
  mov    %rsp,%rbp
  mov    $0xff,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  lea    D9(%rip),%r12
  rep stos %rax,%es:(%rdi)
  mov    %r12,(%rsp)
  cmp    $0x1,%ebx
  jle    L19
  lea    -0x1(%rbx),%edx
  lea    0x8(%rsp),%rdi
  add    $0x8,%rsi
  shl    $0x3,%rdx
  call   <memcpy@plt>
L22:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movq   $0x0,(%rsp,%rbx,8)
  call   <execvp@plt>
  mov    0x7f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x800,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  lea    D9(%rip),%r12
  xor    %edx,%edx
  mov    %rsp,%rbp
  mov    $0x1,%ebx
  mov    %r12,%rdi
  mov    %r12,%rsi
  call   <execl@plt>
  mov    $0xff,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r12,(%rsp)
  jmp    L22
L36:
  call   <__stack_chk_fail@plt>
L19:
  mov    $0x1,%ebx
  jmp    L22
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: git

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 0)
    execl("git", "git", NULL);
  int i = 1;
  char *args[255] = {"git"};
  for (; i < argc; i++) {
    args[i] = argv[i];
  }
  args[i] = NULL;
  execvp("git", args);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<netio_null_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x30d40,%edi
  call   <usleep@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
ssize_t netio_null_recv(void *null_ptr, void *pkt, size_t max_len) {
  usleep(200000);
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<netio_null_recv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x30d40,%edi
  call   <usleep@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t netio_null_recv(void *null_ptr, void *pkt, size_t max_len) {
  usleep(200000);
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<netio_null_recv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x30d40,%edi
  call   <usleep@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t netio_null_recv(void *null_ptr, void *pkt, size_t max_len) {
  usleep(200000);
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<netio_null_recv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x30d40,%edi
  call   <usleep@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t netio_null_recv(void *null_ptr, void *pkt, size_t max_len) {
  usleep(200000);
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L24
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L24:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L6
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L6:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D24
type_infered: string

tool: D25: %d

tool: D2: 0


tool: D17: 1


tool: D24: 2


assistant: ```c
int main() {
  int discriminant;
  scanf("%d", &discriminant);
  if (discriminant < 0) {
    printf("0\n");
  } else if (discriminant == 0) {
    printf("1\n");
  } else {
    printf("2\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L13
  jne    L47
  lea    D13(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L13:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L47:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D33
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D31
type_guessed: string
name: retrieve_data
arguments: data_label: D25
type_guessed: string

tool: D33: %d

tool: D13: 1


tool: D31: 0


tool: D25: 2


assistant: ```c
int main() {
  int discriminant;
  scanf("%d", &discriminant);
  if (discriminant < 0) {
    printf("0\n");
  } else if (discriminant == 0) {
    printf("1\n");
  } else {
    printf("2\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L34
  je     L13
  lea    D22(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L13:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L34:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D0: %d

tool: D22: 2


tool: D32: 1


tool: D11: 0


assistant: ```c
int main() {
  int discriminant;
  scanf("%d", &discriminant);
  if (discriminant < 0) {
    printf("0\n");
  } else if (discriminant == 0) {
    printf("1\n");
  } else {
    printf("2\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L19
  je     L49
  lea    D18(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L49:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L19:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D29
type: string
name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D28
type: string

tool: D29: %d

tool: D18: 2


tool: D33: 1


tool: D28: 0


assistant: ```c
int main() {
  int discriminant;
  scanf("%d", &discriminant);
  if (discriminant < 0) {
    printf("0\n");
  } else if (discriminant == 0) {
    printf("1\n");
  } else {
    printf("2\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x2cdb,%ax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L22
  movzwl -0xa(%rbp),%eax
  shr    $0x2,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L37
  movzwl -0xa(%rbp),%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edx,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L37
L22:
  movzwl -0xa(%rbp),%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %ax,-0xa(%rbp)
L37:
  movzwl -0xa(%rbp),%eax
  xor    $0x5399,%ax
  lea    0x797c(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
        state[0UL] |= (state[0UL] & (unsigned short)31) << 4UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
    }
    output[0UL] = (state[0UL] ^ 498160537UL) + (unsigned short)31100;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  movzwl %ax,%edx
  test   $0x1,%al
  je     L6
  test   $0x4,%al
  je     L0
  shl    $0x4,%edx
  and    $0x1f0,%dx
  or     %edx,%eax
  jmp    L0
L6:
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %edx,%eax
L0:
  xor    $0x5399,%ax
  add    $0x797c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
        state[0UL] |= (state[0UL] & (unsigned short)31) << 4UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
    }
    output[0UL] = (state[0UL] ^ 498160537UL) + (unsigned short)31100;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  movzwl %ax,%edx
  test   $0x1,%al
  je     L15
  test   $0x4,%al
  je     L4
  shl    $0x4,%edx
  and    $0x1f0,%dx
  or     %edx,%eax
L4:
  xor    $0x5399,%ax
  add    $0x797c,%ax
  mov    %ax,(%rsi)
  ret
  nopl   0x0(%rax)
L15:
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %edx,%eax
  xor    $0x5399,%ax
  add    $0x797c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
        state[0UL] |= (state[0UL] & (unsigned short)31) << 4UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
    }
    output[0UL] = (state[0UL] ^ 498160537UL) + (unsigned short)31100;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  movzwl %ax,%edx
  test   $0x1,%al
  je     L3
  test   $0x4,%al
  je     L11
  shl    $0x4,%edx
  and    $0x1f0,%dx
  or     %edx,%eax
L11:
  xor    $0x5399,%ax
  add    $0x797c,%ax
  mov    %ax,(%rsi)
  ret
  nopl   0x0(%rax)
L3:
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %edx,%eax
  xor    $0x5399,%ax
  add    $0x797c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
        state[0UL] |= (state[0UL] & (unsigned short)31) << 4UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
    }
    output[0UL] = (state[0UL] ^ 498160537UL) + (unsigned short)31100;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<base64_encode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,%r8d
  mov    %rdx,%r11
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  lea    0x2(%rsi),%eax
  movslq %eax,%r10
  imul   $0x55555556,%r10,%r10
  shr    $0x20,%r10
  sar    $0x1f,%eax
  sub    %eax,%r10d
  shl    $0x2,%r10d
  test   %esi,%esi
  jle    L52
  mov    %rdi,%r9
  mov    $0x0,%ecx
  mov    $0x0,%ebx
  lea    D6(%rip),%rdi
  jmp    L65
L68:
  mov    %esi,%ecx
  mov    %ebx,%esi
  mov    %ebx,%ebp
L99:
  shl    $0x10,%eax
  shl    $0x8,%esi
  add    %esi,%eax
  lea    (%rax,%rbp,1),%esi
  mov    %eax,%ebp
  shr    $0x12,%ebp
  movslq %ebp,%rbp
  movzbl (%rdi,%rbp,1),%ebp
  mov    %bpl,(%rdx)
  shr    $0xc,%eax
  and    $0x3f,%eax
  movzbl (%rdi,%rax,1),%eax
  mov    %al,0x1(%rdx)
  mov    %esi,%eax
  sar    $0x6,%eax
  and    $0x3f,%eax
  movzbl (%rdi,%rax,1),%eax
  mov    %al,0x2(%rdx)
  and    $0x3f,%esi
  movzbl (%rdi,%rsi,1),%eax
  mov    %al,0x3(%rdx)
  add    $0x4,%rdx
  cmp    %r8d,%ecx
  jge    L52
L65:
  lea    0x1(%rcx),%esi
  movslq %ecx,%rax
  movzbl (%r9,%rax,1),%eax
  cmp    %esi,%r8d
  jle    L68
  lea    0x2(%rcx),%ebp
  movslq %esi,%rsi
  movzbl (%r9,%rsi,1),%esi
  cmp    %ebp,%r8d
  jle    L59
  add    $0x3,%ecx
  movslq %ebp,%rbp
  movzbl (%r9,%rbp,1),%ebp
  jmp    L99
L59:
  mov    %ebp,%ecx
  mov    %ebx,%ebp
  jmp    L99
L52:
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%r8d
  movslq %r8d,%r8
  mov    0xc(%rsp,%r8,4),%ecx
  test   %ecx,%ecx
  jle    L89
  movslq %r10d,%rdx
  lea    -0x1(%r11,%rdx,1),%rax
  lea    -0x2(%r11,%rdx,1),%rdx
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rdx
L94:
  movb   $0x3d,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L94
L89:
  movslq %r10d,%r10
  movb   $0x0,(%r11,%r10,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void base64_encode(unsigned char *data, int len, char *out) {
  char *lookup = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int mod_table[] = {0, 2, 1};
  int out_len = 4 * ((len + 2) / 3);
  int i, j;
  for (i = 0, j = 0; i < len;) {
    uint32_t octet_a = i < len ? (unsigned char)data[i++] : 0;
    uint32_t octet_b = i < len ? (unsigned char)data[i++] : 0;
    uint32_t octet_c = i < len ? (unsigned char)data[i++] : 0;
    uint32_t triple = (octet_a << 0x10) + (octet_b << 0x08) + octet_c;
    out[j++] = lookup[(triple >> 3 * 6) & 0x3F];
    out[j++] = lookup[(triple >> 2 * 6) & 0x3F];
    out[j++] = lookup[(triple >> 1 * 6) & 0x3F];
    out[j++] = lookup[(triple >> 0 * 6) & 0x3F];
  }
  for (i = 0; i < mod_table[len % 3]; i++)
    out[out_len - 1 - i] = '=';
  out[out_len] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<base64_encode>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %rdx,%rbp
  push   %rbx
  xor    %ecx,%ecx
  lea    D4(%rip),%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000000,%rax
  movl   $0x1,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  lea    0x2(%rsi),%eax
  movslq %eax,%rbx
  sar    $0x1f,%eax
  imul   $0x55555556,%rbx,%rbx
  shr    $0x20,%rbx
  sub    %eax,%ebx
  shl    $0x2,%ebx
  test   %esi,%esi
  jg     L60
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L23:
  movslq %esi,%rsi
  lea    0x2(%rcx),%r10d
  movzbl (%r8,%rsi,1),%esi
  shl    $0x8,%esi
  cmp    %r10d,%r9d
  jle    L36
  movslq %r10d,%r10
  add    $0x3,%ecx
  movzbl (%r8,%r10,1),%r10d
L73:
  shl    $0x10,%eax
  add    $0x4,%rdx
  add    %esi,%eax
  lea    (%rax,%r10,1),%esi
  mov    %eax,%r10d
  shr    $0xc,%eax
  and    $0x3f,%eax
  shr    $0x12,%r10d
  movzbl (%rdi,%rax,1),%eax
  movzbl (%rdi,%r10,1),%r10d
  mov    %al,-0x3(%rdx)
  mov    %esi,%eax
  and    $0x3f,%esi
  sar    $0x6,%eax
  mov    %r10b,-0x4(%rdx)
  and    $0x3f,%eax
  movzbl (%rdi,%rax,1),%eax
  mov    %al,-0x2(%rdx)
  movzbl (%rdi,%rsi,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    %r9d,%ecx
  jge    L59
L60:
  movslq %ecx,%rax
  lea    0x1(%rcx),%esi
  movzbl (%r8,%rax,1),%eax
  cmp    %esi,%r9d
  jg     L23
  mov    %esi,%ecx
  xor    %r10d,%r10d
  xor    %esi,%esi
  jmp    L73
  nopl   0x0(%rax)
L59:
  movslq %r9d,%rax
  mov    %r9d,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%r9d
  movslq %r9d,%r9
  mov    0xc(%rsp,%r9,4),%eax
  test   %eax,%eax
  jle    L26
  lea    -0x1(%rbx),%edi
  mov    %eax,%edx
  sub    $0x1,%eax
  mov    $0x3d,%esi
  movslq %edi,%rdi
  sub    %rax,%rdi
  add    %rbp,%rdi
  call   <memset@plt>
L26:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    %r10d,%ecx
  xor    %r10d,%r10d
  jmp    L73
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void base64_encode(unsigned char *data, int len, char *out) {
  char *lookup = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int mod_table[] = {0, 2, 1};
  int out_len = 4 * ((len + 2) / 3);
  int i, j;
  for (i = 0, j = 0; i < len;) {
    uint32_t octet_a = i < len ? (unsigned char)data[i++] : 0;
    uint32_t octet_b = i < len ? (unsigned char)data[i++] : 0;
    uint32_t octet_c = i < len ? (unsigned char)data[i++] : 0;
    uint32_t triple = (octet_a << 0x10) + (octet_b << 0x08) + octet_c;
    out[j++] = lookup[(triple >> 3 * 6) & 0x3F];
    out[j++] = lookup[(triple >> 2 * 6) & 0x3F];
    out[j++] = lookup[(triple >> 1 * 6) & 0x3F];
    out[j++] = lookup[(triple >> 0 * 6) & 0x3F];
  }
  for (i = 0; i < mod_table[len % 3]; i++)
    out[out_len - 1 - i] = '=';
  out[out_len] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transfer_YUV888_to_VYU888>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  movzbl 0x2(%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_YUV888_to_VYU888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[2];
  (*output)[1] = input[0];
  (*output)[2] = input[1];
  (*output) += 3;
}
```