ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<conta_giorni>:
  endbr64
  mov    $0x0,%eax
  mov    $0x0,%edx
  sub    $0x1,%esi
  jmp    L38
L30:
  lea    (%rdx,%rdi,1),%r8d
  cmove  %r8d,%edx
L36:
  add    $0x1,%rax
  cmp    $0xc,%rax
  je     L16
L38:
  cmp    %eax,%esi
  jbe    L30
  add    (%rcx,%rax,4),%edx
  jmp    L36
L16:
  mov    %edx,%eax
  ret
```

assistant: ```c
int conta_giorni(int giorno, int mese, int anno, int calendario[]) {
  int giorni;
  unsigned int indice_array;
  giorni = 0;
  indice_array = 0;
  while (indice_array < 12) {
    if (indice_array < (mese - 1)) {
      giorni += calendario[indice_array];
    } else if (indice_array == (mese - 1)) {
      giorni += giorno;
    }
    indice_array++;
  }
  return (giorni);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<conta_giorni>:
  endbr64
  sub    $0x1,%esi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L28
  xchg   %ax,%ax
L27:
  add    (%rcx,%rax,4),%r8d
  add    $0x1,%rax
  cmp    $0xc,%rax
  je     L7
L28:
  cmp    %eax,%esi
  ja     L27
  lea    (%r8,%rdi,1),%edx
  cmove  %edx,%r8d
  add    $0x1,%rax
  cmp    $0xc,%rax
  jne    L28
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int conta_giorni(int giorno, int mese, int anno, int calendario[]) {
  int giorni;
  unsigned int indice_array;
  giorni = 0;
  indice_array = 0;
  while (indice_array < 12) {
    if (indice_array < (mese - 1)) {
      giorni += calendario[indice_array];
    } else if (indice_array == (mese - 1)) {
      giorni += giorno;
    }
    indice_array++;
  }
  return (giorni);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<conta_giorni>:
  endbr64
  mov    %edi,%eax
  sub    $0x1,%esi
  je     L66
  mov    (%rcx),%edx
  cmp    $0x1,%esi
  je     L117
  add    0x4(%rcx),%edx
  cmp    $0x2,%esi
  je     L117
  add    0x8(%rcx),%edx
  cmp    $0x3,%esi
  je     L117
  add    0xc(%rcx),%edx
  cmp    $0x4,%esi
  je     L117
  add    0x10(%rcx),%edx
  cmp    $0x5,%esi
  je     L117
  add    0x14(%rcx),%edx
  cmp    $0x6,%esi
  je     L117
  add    0x18(%rcx),%edx
  cmp    $0x7,%esi
  je     L117
  add    0x1c(%rcx),%edx
  cmp    $0x8,%esi
  je     L117
  add    0x20(%rcx),%edx
  cmp    $0x9,%esi
  je     L117
  add    0x24(%rcx),%edx
  cmp    $0xa,%esi
  je     L117
  add    0x28(%rcx),%edx
  add    %edx,%eax
  cmp    $0xb,%esi
  je     L66
  mov    0x2c(%rcx),%eax
  add    %edx,%eax
L66:
  ret
  nopw   0x0(%rax,%rax,1)
L117:
  add    %edx,%eax
  ret
```

assistant: ```c
int conta_giorni(int giorno, int mese, int anno, int calendario[]) {
  int giorni;
  unsigned int indice_array;
  giorni = 0;
  indice_array = 0;
  while (indice_array < 12) {
    if (indice_array < (mese - 1)) {
      giorni += calendario[indice_array];
    } else if (indice_array == (mese - 1)) {
      giorni += giorno;
    }
    indice_array++;
  }
  return (giorni);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_value>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r14d
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  lea    -0x47(%r14),%esi
  cmp    $0xe,%sil
  ja     L45
  movzbl %sil,%esi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%r13d
  mov    $0x3,%r12d
  jmp    L45
  mov    $0x3,%r13d
  mov    $0x4,%r12d
L45:
  movzbl (%rbx),%edx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L5
  jmp    L170
  mov    $0x4,%r13d
  mov    $0x5,%r12d
  jmp    L45
  mov    $0x5,%r13d
  mov    $0x6,%r12d
  jmp    L45
  mov    $0x6,%r13d
  mov    $0x7,%r12d
  jmp    L45
L56:
  add    $0x1,%ecx
  add    $0x1,%eax
  cmp    $0x7,%ecx
  je     L9
  jmp    L24
L65:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbp,%rax,1)
  je     L19
L170:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L170
L144:
  add    $0x1,%eax
L24:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%edx
  test   %dl,%dl
  je     L170
L5:
  cmp    $0x3a,%dl
  je     L56
L9:
  cmp    %r12d,%ecx
  je     L65
  movslq %eax,%rdx
  cmpb   $0x0,0x1(%rbx,%rdx,1)
  je     L65
  cmp    %r13d,%ecx
  jne    L144
  movzbl (%rbx,%rdx,1),%edi
  movslq %esi,%rdx
  mov    %dil,0x0(%rbp,%rdx,1)
  add    $0x1,%esi
  jmp    L144
  mov    $0x0,%r13d
  mov    $0x1,%r12d
  jmp    L45
```

assistant: ```c
char *get_value(char *line, char flag) {
  int i = 0;
  int j = 0;
  int max, min;
  int count = 0;
  char *buffer = calloc(100, sizeof(char));
  bzero(buffer, 100);
  switch (flag) {
  case 'U':
    min = 2;
    max = 3;
    break;
  case 'L':
    min = 0;
    max = 1;
    break;
  case 'G':
    min = 3;
    max = 4;
    break;
  case 'N':
    min = 4;
    max = 5;
    break;
  case 'H':
    min = 5;
    max = 6;
    break;
  case 'S':
    min = 6;
    max = 7;
    break;
  }
  while (line[i] != '\0') {
    if (line[i] == ':') {
      count++;
      i++;
      if (count != 7)
        continue;
    }
    if (count == max || line[i + 1] == '\0') {
      if (buffer[strlen(buffer) - 1] == '\n') {
        buffer[strlen(buffer) - 1] = '\0';
      }
      return buffer;
    }
    if (count == min) {
      buffer[j] = line[i];
      j++;
    }
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_value>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    $0x1,%esi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    $0x64,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <bzero@plt>
  lea    -0x47(%r14),%esi
  cmp    $0xe,%sil
  ja     L151
  lea    D2(%rip),%rdx
  movzbl %sil,%esi
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x3,%r13d
  mov    $0x4,%ebp
  nopl   0x0(%rax,%rax,1)
L151:
  movzbl (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  test   %dl,%dl
  jne    L8
  jmp    L123
  nop
L133:
  cmp    %ebp,%ecx
  je     L144
L93:
  movslq %eax,%rdx
  cmpb   $0x0,0x1(%rbx,%rdx,1)
  je     L144
  cmp    %r13d,%ecx
  jne    L30
  movzbl (%rbx,%rdx,1),%edi
  movslq %esi,%rdx
  add    $0x1,%esi
  mov    %dil,(%r12,%rdx,1)
L30:
  add    $0x1,%eax
L145:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%edx
  test   %dl,%dl
  je     L123
L8:
  cmp    $0x3a,%dl
  jne    L133
  add    $0x1,%ecx
  add    $0x1,%eax
  cmp    $0x7,%ecx
  jne    L145
  cmp    %ebp,%ecx
  jne    L93
  nopl   0x0(%rax,%rax,1)
L144:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%r12,%rax,1)
  je     L91
L123:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L91:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  mov    $0x5,%r13d
  mov    $0x6,%ebp
  jmp    L151
  mov    $0x4,%r13d
  mov    $0x5,%ebp
  jmp    L151
  mov    $0x6,%r13d
  mov    $0x7,%ebp
  jmp    L151
  xor    %r13d,%r13d
  mov    $0x1,%ebp
  jmp    L151
  mov    $0x2,%r13d
  mov    $0x3,%ebp
  jmp    L151
```

assistant: ```c
char *get_value(char *line, char flag) {
  int i = 0;
  int j = 0;
  int max, min;
  int count = 0;
  char *buffer = calloc(100, sizeof(char));
  bzero(buffer, 100);
  switch (flag) {
  case 'U':
    min = 2;
    max = 3;
    break;
  case 'L':
    min = 0;
    max = 1;
    break;
  case 'G':
    min = 3;
    max = 4;
    break;
  case 'N':
    min = 4;
    max = 5;
    break;
  case 'H':
    min = 5;
    max = 6;
    break;
  case 'S':
    min = 6;
    max = 7;
    break;
  }
  while (line[i] != '\0') {
    if (line[i] == ':') {
      count++;
      i++;
      if (count != 7)
        continue;
    }
    if (count == max || line[i + 1] == '\0') {
      if (buffer[strlen(buffer) - 1] == '\n') {
        buffer[strlen(buffer) - 1] = '\0';
      }
      return buffer;
    }
    if (count == min) {
      buffer[j] = line[i];
      j++;
    }
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_value>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    $0x1,%esi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    $0x64,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <bzero@plt>
  lea    -0x47(%r14),%esi
  cmp    $0xe,%sil
  ja     L128
  lea    D7(%rip),%rdx
  movzbl %sil,%esi
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x3,%r13d
  mov    $0x4,%ebp
  nopl   0x0(%rax,%rax,1)
L128:
  movzbl (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  test   %dl,%dl
  jne    L153
  jmp    L115
  nop
L83:
  cmp    %ebp,%ecx
  je     L19
L53:
  movslq %eax,%rdx
  cmpb   $0x0,0x1(%rbx,%rdx,1)
  je     L19
  cmp    %r13d,%ecx
  jne    L152
  movzbl (%rbx,%rdx,1),%edi
  movslq %esi,%rdx
  add    $0x1,%esi
  mov    %dil,(%r12,%rdx,1)
L152:
  add    $0x1,%eax
L74:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%edx
  test   %dl,%dl
  je     L115
L153:
  cmp    $0x3a,%dl
  jne    L83
  add    $0x1,%ecx
  add    $0x1,%eax
  cmp    $0x7,%ecx
  jne    L74
  cmp    %ebp,%ecx
  jne    L53
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%r12,%rax,1)
  je     L117
L115:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L117:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  mov    $0x5,%r13d
  mov    $0x6,%ebp
  jmp    L128
  mov    $0x4,%r13d
  mov    $0x5,%ebp
  jmp    L128
  mov    $0x6,%r13d
  mov    $0x7,%ebp
  jmp    L128
  xor    %r13d,%r13d
  mov    $0x1,%ebp
  jmp    L128
  mov    $0x2,%r13d
  mov    $0x3,%ebp
  jmp    L128
```

assistant: ```c
char *get_value(char *line, char flag) {
  int i = 0;
  int j = 0;
  int max, min;
  int count = 0;
  char *buffer = calloc(100, sizeof(char));
  bzero(buffer, 100);
  switch (flag) {
  case 'U':
    min = 2;
    max = 3;
    break;
  case 'L':
    min = 0;
    max = 1;
    break;
  case 'G':
    min = 3;
    max = 4;
    break;
  case 'N':
    min = 4;
    max = 5;
    break;
  case 'H':
    min = 5;
    max = 6;
    break;
  case 'S':
    min = 6;
    max = 7;
    break;
  }
  while (line[i] != '\0') {
    if (line[i] == ':') {
      count++;
      i++;
      if (count != 7)
        continue;
    }
    if (count == max || line[i + 1] == '\0') {
      if (buffer[strlen(buffer) - 1] == '\n') {
        buffer[strlen(buffer) - 1] = '\0';
      }
      return buffer;
    }
    if (count == min) {
      buffer[j] = line[i];
      j++;
    }
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<element_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x43,%eax
  cmp    $0x12,%eax
  ja     L30
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L87
  mov    $0x1,%eax
  jmp    L87
  mov    $0x2,%eax
  jmp    L87
  mov    $0x2,%eax
  jmp    L87
  mov    $0x4,%eax
  jmp    L87
  mov    $0x8,%eax
  jmp    L87
  mov    $0x4,%eax
  jmp    L87
  mov    $0x8,%eax
  jmp    L87
L30:
  mov    $0x0,%eax
L87:
  pop    %rbp
  ret
```

assistant: ```c
size_t element_length(char type) {
  switch (type) {
  case 'C':
    return (sizeof(char));
  case 'U':
    return (sizeof(unsigned char));
  case 'H':
    return (sizeof(unsigned short));
  case 'S':
    return (sizeof(short));
  case 'I':
    return (sizeof(int));
  case 'L':
    return (sizeof(long));
  case 'F':
    return (sizeof(float));
  case 'D':
    return (sizeof(double));
  default:
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<element_length>:
  endbr64
  sub    $0x43,%edi
  cmp    $0x12,%dil
  ja     L9
  movzbl %dil,%edi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x8,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t element_length(char type) {
  switch (type) {
  case 'C':
    return (sizeof(char));
  case 'U':
    return (sizeof(unsigned char));
  case 'H':
    return (sizeof(unsigned short));
  case 'S':
    return (sizeof(short));
  case 'I':
    return (sizeof(int));
  case 'L':
    return (sizeof(long));
  case 'F':
    return (sizeof(float));
  case 'D':
    return (sizeof(double));
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<element_length>:
  endbr64
  sub    $0x43,%edi
  xor    %eax,%eax
  cmp    $0x12,%dil
  ja     L3
  movzbl %dil,%edi
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L3:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: 

assistant: ```c
size_t element_length(char type) {
  switch (type) {
  case 'C':
    return (sizeof(char));
  case 'U':
    return (sizeof(unsigned char));
  case 'H':
    return (sizeof(unsigned short));
  case 'S':
    return (sizeof(short));
  case 'I':
    return (sizeof(int));
  case 'L':
    return (sizeof(long));
  case 'F':
    return (sizeof(float));
  case 'D':
    return (sizeof(double));
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<element_length>:
  endbr64
  sub    $0x43,%edi
  xor    %eax,%eax
  cmp    $0x12,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L1:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: 

assistant: ```c
size_t element_length(char type) {
  switch (type) {
  case 'C':
    return (sizeof(char));
  case 'U':
    return (sizeof(unsigned char));
  case 'H':
    return (sizeof(unsigned short));
  case 'S':
    return (sizeof(short));
  case 'I':
    return (sizeof(int));
  case 'L':
    return (sizeof(long));
  case 'F':
    return (sizeof(float));
  case 'D':
    return (sizeof(double));
  default:
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<CheckSimple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    D8(%rip),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D8
type: f64

tool: D2: %d %lld %f

tool: D8: 3

assistant: ```c
int CheckSimple() {
#pragma omp target
  {
    const char *fmt = "%d %lld %f";
    printf(fmt, 1, 2ll, 3.0);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CheckSimple>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: f64
name: disassemble_data
arguments: data_label: D15
data_type: string

tool: D3: 3

tool: D15: %d %lld %f

assistant: ```c
int CheckSimple() {
#pragma omp target
  {
    const char *fmt = "%d %lld %f";
    printf(fmt, 1, 2ll, 3.0);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CheckSimple>:
  endbr64
  sub    $0x8,%rsp
  movsd  D14(%rip),%xmm0
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
data_type: f64
name: unpack_data
arguments: tag: D9
data_type: string

tool: D14: 3

tool: D9: %d %lld %f

assistant: ```c
int CheckSimple() {
#pragma omp target
  {
    const char *fmt = "%d %lld %f";
    printf(fmt, 1, 2ll, 3.0);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CheckSimple>:
  endbr64
  sub    $0x8,%rsp
  movsd  D14(%rip),%xmm0
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: f64
name: retrieve_data
arguments: label: D17
type_guessed: string

tool: D14: 3

tool: D17: %d %lld %f

assistant: ```c
int CheckSimple() {
#pragma omp target
  {
    const char *fmt = "%d %lld %f";
    printf(fmt, 1, 2ll, 3.0);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<givens>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r11
  cmp    $0x1,%edi
  jle    L0
  mov    %edi,%r12d
  lea    0x8(%rsi),%r8
  lea    0x1(%rdi),%r14d
  mov    $0x10,%edx
  mov    $0x1,%ebp
  mov    $0x1,%eax
  jmp    L90
L0:
  movsd  0x8(%rcx),%xmm0
  movsd  %xmm0,0x8(%rdx)
  mov    0x8(%rsi),%rax
  mov    D0(%rip),%rdi
  mov    %rdi,0x8(%rax)
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    $0x8,%eax
L79:
  movsd  (%rsi,%rax,1),%xmm0
  mov    0x8(%rdi),%rcx
  movsd  %xmm0,(%rcx,%rax,1)
  mov    (%rbx,%rax,1),%rcx
  movsd  %xmm0,(%rcx,%rdx,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L79
  lea    0x0(%rbp,%r10,1),%eax
L2:
  add    $0x8,%r8
  add    $0x8,%rdx
  mov    %r9d,%ebp
L90:
  lea    0x1(%rax),%r10d
  cltq
  lea    (%r11,%rax,8),%rsi
  mov    %r8,%rdi
  movsd  (%rsi),%xmm0
  mov    (%r8),%rax
  movsd  %xmm0,-0x8(%rax,%rdx,1)
  lea    0x1(%rbp),%r9d
  cmp    %r14d,%r9d
  je     L47
  cmp    $0x1,%r9d
  jg     L23
  mov    %r10d,%eax
  jmp    L2
L47:
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <dvector@plt>
  mov    %rax,%r14
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <tred2@plt>
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <tqli@plt>
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <free_dvector@plt>
  lea    0x10(%rbx),%rdi
  mov    $0x10,%edx
  mov    $0x1,%eax
  jmp    L42
L61:
  mov    $0x8,%eax
L106:
  mov    %rax,%rcx
  add    (%rdi),%rcx
  movsd  (%rcx),%xmm0
  mov    (%rbx,%rax,1),%rsi
  movsd  (%rsi,%rdx,1),%xmm1
  movsd  %xmm1,(%rcx)
  mov    (%rbx,%rax,1),%rcx
  movsd  %xmm0,(%rcx,%rdx,1)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L106
L39:
  add    $0x8,%rdi
  add    $0x8,%rdx
  mov    %r8d,%eax
L42:
  lea    0x1(%rax),%r8d
  cmp    %ebp,%eax
  je     L6
  cmp    $0x1,%r8d
  jg     L61
  jmp    L39
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: f64

tool: D0: 1

assistant: ```c
void givens(int nx, double **vect, double *root, double *a) {
  int l, j, k;
  double *e;
  if (nx <= 1) {
    root[1] = a[1];
    vect[1][1] = 1.0;
    return;
  }
  for (k = 1, l = 1; k <= nx; k++) {
    for (j = 1; j < k; j++) {
      vect[k][j] = a[l];
      vect[j][k] = a[l++];
    }
    vect[k][k] = a[l++];
  }
  e = dvector(1, nx);
  tred2(vect, nx, root, e);
  tqli(root, e, nx, vect);
  free_dvector(e, 1);
  for (k = 1; k <= nx; k++)
    for (j = 1; j < k; j++) {
      double p = vect[k][j];
      vect[k][j] = vect[j][k];
      vect[j][k] = p;
    }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<givens>:
  endbr64
  push   %r14
  mov    %rcx,%r10
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L63
  mov    %edi,%r12d
  lea    0x1(%rdi),%r11d
  mov    $0x8,%r8d
  mov    $0x2,%ebp
  mov    $0x1,%eax
  nopl   (%rax)
L48:
  lea    0x1(%rax),%r9d
  cltq
  lea    (%r10,%rax,8),%rcx
  mov    (%rbx,%r8,1),%rax
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rax,%r8,1)
  cmp    %rbp,%r11
  je     L79
  mov    (%rbx,%rbp,8),%rsi
  lea    0x0(,%rbp,8),%rdi
  cmp    $0x1,%ebp
  jle    L21
  mov    $0x1,%eax
  nop
L4:
  movsd  (%rcx,%rax,8),%xmm0
  mov    (%rbx,%rax,8),%rdx
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%rdi,1)
  cmp    %rax,%rbp
  jne    L4
  lea    -0x1(%r9,%rbp,1),%eax
L9:
  add    $0x1,%rbp
  add    $0x8,%r8
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <dvector@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %rax,%r14
  mov    %rax,%rcx
  call   <tred2@plt>
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <tqli@plt>
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <free_dvector@plt>
  mov    $0x2,%esi
  nopl   0x0(%rax)
L23:
  mov    (%rbx,%rsi,8),%rcx
  lea    0x0(,%rsi,8),%rdi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L30:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rcx,%rax,8),%xmm0
  add    %rdi,%rdx
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L30
  add    $0x1,%rsi
  cmp    %rsi,%rbp
  jne    L23
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  movsd  0x8(%rcx),%xmm0
  mov    0x8(%rsi),%rax
  mov    D4(%rip),%rdi
  movsd  %xmm0,0x8(%rdx)
  mov    %rdi,0x8(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  mov    %r9d,%eax
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
void givens(int nx, double **vect, double *root, double *a) {
  int l, j, k;
  double *e;
  if (nx <= 1) {
    root[1] = a[1];
    vect[1][1] = 1.0;
    return;
  }
  for (k = 1, l = 1; k <= nx; k++) {
    for (j = 1; j < k; j++) {
      vect[k][j] = a[l];
      vect[j][k] = a[l++];
    }
    vect[k][k] = a[l++];
  }
  e = dvector(1, nx);
  tred2(vect, nx, root, e);
  tqli(root, e, nx, vect);
  free_dvector(e, 1);
  for (k = 1; k <= nx; k++)
    for (j = 1; j < k; j++) {
      double p = vect[k][j];
      vect[k][j] = vect[j][k];
      vect[j][k] = p;
    }
}
```