user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1000,-0x30(%rbp)
  movl   $0xa14,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L9
L14:
  mov    -0x34(%rbp),%edx
  lea    -0x20(%rbp),%rax
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  imul   $0x10624d,%eax,%eax
  add    $0xfffff,%eax
  sar    $0x14,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0xa,%eax
  add    $0x30,%eax
  mov    %al,-0x1c(%rbp)
  andl   $0x3ff,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0xa,%eax
  add    $0x30,%eax
  mov    %al,-0x1b(%rbp)
  andl   $0x3ff,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0xa,%eax
  add    $0x30,%eax
  mov    %al,-0x1a(%rbp)
  andl   $0x3ff,-0x24(%rbp)
  movb   $0x0,-0x19(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x34(%rbp)
  je     L12
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  lea    0x0(,%rax,4),%edx
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
L12:
  addl   $0x1,-0x34(%rbp)
L9:
  cmpl   $0x3e7,-0x34(%rbp)
  jle    L14
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D17: %03d

tool: D0: % d 

assistant: ```c
int main(int argc, char *argv[]) {
  char ta[4], tb[4];
  int i, j, k, bi, sc, sh;
  bi = 4096;
  sc = 2580;
  sh = 8;
  for (i = 0; i < 1000; i++) {
    sprintf(ta, "%03d", i);
    j = i;
    j = (i * 1073741 + 1048575) >> 20;
    j = j * 10;
    tb[0] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[1] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[2] = '0' + (j >> 10);
    j &= 1023;
    tb[3] = 0;
    printf("% d ", atoi(ta) - atoi(tb));
    if (i && !((i + 1) % 25))
      printf("\n");
  }
}
```