ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dump_to_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: wb

assistant: ```c
int dump_to_file(uint8_t *buf, uint32_t size, char *name) {
  FILE *f = NULL;
  int write_bytes = 0;
  f = fopen(name, "wb");
  write_bytes = fwrite(buf, size, 1, f);
  fclose(f);
  return write_bytes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_to_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%rdi
  lea    D2(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: wb

assistant: ```c
int dump_to_file(uint8_t *buf, uint32_t size, char *name) {
  FILE *f = NULL;
  int write_bytes = 0;
  f = fopen(name, "wb");
  write_bytes = fwrite(buf, size, 1, f);
  fclose(f);
  return write_bytes;
}
```
user: What is the c source code of the assembly code below:

```asm
<dump_to_file>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  lea    D4(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  call   <fopen@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    $0x1,%edx
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fclose@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: wb

assistant: ```c
int dump_to_file(uint8_t *buf, uint32_t size, char *name) {
  FILE *f = NULL;
  int write_bytes = 0;
  f = fopen(name, "wb");
  write_bytes = fwrite(buf, size, 1, f);
  fclose(f);
  return write_bytes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dump_to_file>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  lea    D6(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  call   <fopen@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    $0x1,%edx
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fclose@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: wb

assistant: ```c
int dump_to_file(uint8_t *buf, uint32_t size, char *name) {
  FILE *f = NULL;
  int write_bytes = 0;
  f = fopen(name, "wb");
  write_bytes = fwrite(buf, size, 1, f);
  fclose(f);
  return write_bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<base64decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L4
L2:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get64Pos@plt>
  shl    $0x12,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get64Pos@plt>
  shl    $0xc,%eax
  or     %eax,%ebx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get64Pos@plt>
  shl    $0x6,%eax
  or     %eax,%ebx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x3(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get64Pos@plt>
  or     %ebx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rcx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  mov    %dl,(%rax)
  addl   $0x4,-0x28(%rbp)
  addl   $0x3,-0x24(%rbp)
L4:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L2
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *base64decode(char *encoded, int size) {
  char *decoded = malloc(sizeof(char) * (size / 4 * 3 + 1));
  int i, j;
  for (i = 0, j = 0; i < size; i += 4, j += 3) {
    unsigned long temp = (get64Pos(encoded[i + 0]) << 18) | (get64Pos(encoded[i + 1]) << 12) | (get64Pos(encoded[i + 2]) << 6) | (get64Pos(encoded[i + 3]) << 0);
    decoded[j + 0] = (char)((temp >> 16) & 0xFF);
    decoded[j + 1] = (char)((temp >> 8) & 0xFF);
    decoded[j + 2] = (char)((temp >> 0) & 0xFF);
  }
  decoded[j] = 0x00;
  return decoded;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<base64decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r14d
  lea    0x3(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  lea    0x1(%rax,%rax,2),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r14d,%r14d
  jle    L11
  mov    %rbx,%r12
  mov    %rax,%r13
  sub    $0x1,%r14d
  shr    $0x2,%r14d
  mov    %r14d,%eax
  lea    0x4(%rbx,%rax,4),%r15
L23:
  movsbl (%r12),%edi
  call   <get64Pos@plt>
  mov    %eax,%ebp
  movsbl 0x1(%r12),%edi
  call   <get64Pos@plt>
  shl    $0x12,%ebp
  shl    $0xc,%eax
  or     %eax,%ebp
  movsbl 0x2(%r12),%edi
  call   <get64Pos@plt>
  mov    %eax,%ebx
  movsbl 0x3(%r12),%edi
  call   <get64Pos@plt>
  shl    $0x6,%ebx
  or     %eax,%ebp
  or     %ebp,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rax
  shr    $0x10,%rax
  mov    %al,0x0(%r13)
  movzbl %bh,%eax
  mov    %al,0x1(%r13)
  mov    %bl,0x2(%r13)
  add    $0x4,%r12
  add    $0x3,%r13
  cmp    %r15,%r12
  jne    L23
  lea    0x3(%r14,%r14,2),%eax
L5:
  cltq
  mov    0x8(%rsp),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    %rdx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
char *base64decode(char *encoded, int size) {
  char *decoded = malloc(sizeof(char) * (size / 4 * 3 + 1));
  int i, j;
  for (i = 0, j = 0; i < size; i += 4, j += 3) {
    unsigned long temp = (get64Pos(encoded[i + 0]) << 18) | (get64Pos(encoded[i + 1]) << 12) | (get64Pos(encoded[i + 2]) << 6) | (get64Pos(encoded[i + 3]) << 0);
    decoded[j + 0] = (char)((temp >> 16) & 0xFF);
    decoded[j + 1] = (char)((temp >> 8) & 0xFF);
    decoded[j + 2] = (char)((temp >> 0) & 0xFF);
  }
  decoded[j] = 0x00;
  return decoded;
}
```
user: Translate the below assembly code into C programming language:

```asm
<base64decode>:
  endbr64
  push   %r15
  lea    0x3(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  lea    0x1(%rax,%rax,2),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L5
  sub    $0x1,%r12d
  mov    %rax,%r14
  shr    $0x2,%r12d
  mov    %r12d,%eax
  lea    0x4(%rbp,%rax,4),%r13
  nopl   (%rax)
L8:
  movsbl 0x0(%rbp),%edi
  add    $0x4,%rbp
  add    $0x3,%r14
  call   <get64Pos@plt>
  movsbl -0x3(%rbp),%edi
  mov    %eax,%r15d
  call   <get64Pos@plt>
  movsbl -0x2(%rbp),%edi
  shl    $0x12,%r15d
  shl    $0xc,%eax
  or     %eax,%r15d
  call   <get64Pos@plt>
  movsbl -0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <get64Pos@plt>
  shl    $0x6,%ebx
  or     %eax,%r15d
  or     %r15d,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rcx
  movzbl %bh,%eax
  mov    %bl,-0x1(%r14)
  shr    $0x10,%rcx
  mov    %al,-0x2(%r14)
  mov    %cl,-0x3(%r14)
  cmp    %r13,%rbp
  jne    L8
  lea    0x3(%r12,%r12,2),%eax
  cltq
  add    0x8(%rsp),%rax
L2:
  movb   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L5:
  mov    0x8(%rsp),%rax
  jmp    L2
```

assistant: ```c
char *base64decode(char *encoded, int size) {
  char *decoded = malloc(sizeof(char) * (size / 4 * 3 + 1));
  int i, j;
  for (i = 0, j = 0; i < size; i += 4, j += 3) {
    unsigned long temp = (get64Pos(encoded[i + 0]) << 18) | (get64Pos(encoded[i + 1]) << 12) | (get64Pos(encoded[i + 2]) << 6) | (get64Pos(encoded[i + 3]) << 0);
    decoded[j + 0] = (char)((temp >> 16) & 0xFF);
    decoded[j + 1] = (char)((temp >> 8) & 0xFF);
    decoded[j + 2] = (char)((temp >> 0) & 0xFF);
  }
  decoded[j] = 0x00;
  return decoded;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64decode>:
  endbr64
  push   %r15
  lea    0x3(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  lea    0x1(%rax,%rax,2),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L15
  sub    $0x1,%r12d
  mov    %rax,%r14
  shr    $0x2,%r12d
  mov    %r12d,%eax
  lea    0x4(%rbp,%rax,4),%r13
  nopl   (%rax)
L17:
  movsbl 0x0(%rbp),%edi
  add    $0x4,%rbp
  add    $0x3,%r14
  call   <get64Pos@plt>
  movsbl -0x3(%rbp),%edi
  mov    %eax,%r15d
  call   <get64Pos@plt>
  movsbl -0x2(%rbp),%edi
  shl    $0x12,%r15d
  shl    $0xc,%eax
  or     %eax,%r15d
  call   <get64Pos@plt>
  movsbl -0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <get64Pos@plt>
  shl    $0x6,%ebx
  or     %eax,%r15d
  or     %r15d,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rcx
  movzbl %bh,%eax
  mov    %bl,-0x1(%r14)
  shr    $0x10,%rcx
  mov    %al,-0x2(%r14)
  mov    %cl,-0x3(%r14)
  cmp    %rbp,%r13
  jne    L17
  lea    0x3(%r12,%r12,2),%eax
  cltq
  add    0x8(%rsp),%rax
L15:
  movb   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *base64decode(char *encoded, int size) {
  char *decoded = malloc(sizeof(char) * (size / 4 * 3 + 1));
  int i, j;
  for (i = 0, j = 0; i < size; i += 4, j += 3) {
    unsigned long temp = (get64Pos(encoded[i + 0]) << 18) | (get64Pos(encoded[i + 1]) << 12) | (get64Pos(encoded[i + 2]) << 6) | (get64Pos(encoded[i + 3]) << 0);
    decoded[j + 0] = (char)((temp >> 16) & 0xFF);
    decoded[j + 1] = (char)((temp >> 8) & 0xFF);
    decoded[j + 2] = (char)((temp >> 0) & 0xFF);
  }
  decoded[j] = 0x00;
  return decoded;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L34
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L34
  cmpl   $0xa,-0x8(%rbp)
  jne    L5
L34:
  cmpl   $0xa,-0x8(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _getline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_getline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L45
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L43:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L39
  cmp    $0xa,%eax
  je     L39
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L43
  mov    %r12d,%ebx
  jmp    L23
L45:
  mov    $0x0,%ebx
L39:
  cmp    $0xa,%eax
  je     L33
L23:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  add    $0x1,%ebx
  jmp    L23
```

assistant: ```c
int _getline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<_getline>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L45
  mov    D1(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L48:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L18
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L57
  mov    %edx,%r14d
L46:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L48
  cmp    $0xa,%eax
  je     L58
L45:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  lea    0x1(%r14),%edx
L18:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L57:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _getline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_getline>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L19
  mov    D9(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L9:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L49
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L33
  mov    %edx,%r14d
L30:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L9
  cmp    $0xa,%eax
  je     L52
L19:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  lea    0x1(%r14),%edx
L49:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L33:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _getline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convertNativeToAgc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  and    $0x7fff,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L4
  orl    $0x4000,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t convertNativeToAgc(int n) {
  uint16_t i;
  i = (uint16_t)(abs(n) & 077777);
  if (n < 0)
    i |= 040000;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convertNativeToAgc>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  and    $0x7fff,%eax
  mov    %eax,%edx
  or     $0x40,%dh
  test   %edi,%edi
  cmovs  %edx,%eax
  ret
```

assistant: ```c
uint16_t convertNativeToAgc(int n) {
  uint16_t i;
  i = (uint16_t)(abs(n) & 077777);
  if (n < 0)
    i |= 040000;
  return (i);
}
```
user: What is the c source code of the assembly code below?

```asm
<convertNativeToAgc>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  and    $0x7fff,%eax
  mov    %eax,%edx
  or     $0x40,%dh
  test   %edi,%edi
  cmovs  %edx,%eax
  ret
```

assistant: ```c
uint16_t convertNativeToAgc(int n) {
  uint16_t i;
  i = (uint16_t)(abs(n) & 077777);
  if (n < 0)
    i |= 040000;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convertNativeToAgc>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  and    $0x7fff,%eax
  mov    %eax,%edx
  or     $0x40,%dh
  test   %edi,%edi
  cmovs  %edx,%eax
  ret
```

assistant: ```c
uint16_t convertNativeToAgc(int n) {
  uint16_t i;
  i = (uint16_t)(abs(n) & 077777);
  if (n < 0)
    i |= 040000;
  return (i);
}
```
user: What is the c source code of the assembly code below:

```asm
<__divsi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L3
  negq   -0x18(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
L3:
  cmpq   $0x0,-0x20(%rbp)
  jns    L21
  negq   -0x20(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
L21:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <udivmodsi4@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L25
  negq   -0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long __divsi3(long a, long b) {
  int neg = 0;
  long res;
  if (a < 0) {
    a = -a;
    neg = !neg;
  }
  if (b < 0) {
    b = -b;
    neg = !neg;
  }
  res = udivmodsi4(a, b, 0);
  if (neg)
    res = -res;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__divsi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L4
  test   %rsi,%rsi
  js     L33
  mov    $0x0,%edx
  call   <udivmodsi4@plt>
  jmp    L29
L4:
  neg    %rdi
  test   %rsi,%rsi
  js     L55
  mov    $0x0,%edx
  call   <udivmodsi4@plt>
L51:
  neg    %rax
L29:
  add    $0x8,%rsp
  ret
L33:
  neg    %rsi
  mov    $0x0,%edx
  call   <udivmodsi4@plt>
  jmp    L51
L55:
  neg    %rsi
  mov    $0x0,%edx
  call   <udivmodsi4@plt>
  jmp    L29
```

assistant: ```c
long __divsi3(long a, long b) {
  int neg = 0;
  long res;
  if (a < 0) {
    a = -a;
    neg = !neg;
  }
  if (b < 0) {
    b = -b;
    neg = !neg;
  }
  res = udivmodsi4(a, b, 0);
  if (neg)
    res = -res;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__divsi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L19
  test   %rsi,%rsi
  js     L12
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udivmodsi4@plt>
  nopl   (%rax)
L12:
  neg    %rsi
L3:
  xor    %edx,%edx
  call   <udivmodsi4@plt>
  add    $0x8,%rsp
  neg    %rax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  neg    %rdi
  test   %rsi,%rsi
  jns    L3
  neg    %rsi
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udivmodsi4@plt>
```

assistant: ```c
long __divsi3(long a, long b) {
  int neg = 0;
  long res;
  if (a < 0) {
    a = -a;
    neg = !neg;
  }
  if (b < 0) {
    b = -b;
    neg = !neg;
  }
  res = udivmodsi4(a, b, 0);
  if (neg)
    res = -res;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__divsi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L26
  test   %rsi,%rsi
  js     L13
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udivmodsi4@plt>
  nopl   (%rax)
L13:
  neg    %rsi
L5:
  xor    %edx,%edx
  call   <udivmodsi4@plt>
  add    $0x8,%rsp
  neg    %rax
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  neg    %rdi
  test   %rsi,%rsi
  jns    L5
  neg    %rsi
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udivmodsi4@plt>
```

assistant: ```c
long __divsi3(long a, long b) {
  int neg = 0;
  long res;
  if (a < 0) {
    a = -a;
    neg = !neg;
  }
  if (b < 0) {
    b = -b;
    neg = !neg;
  }
  res = udivmodsi4(a, b, 0);
  if (neg)
    res = -res;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x414(%rbp)
  lea    -0x410(%rbp),%rcx
  mov    -0x414(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <flistxattr@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(void) {
  int fd = 3;
  char list[1024];
  return flistxattr(fd, list, sizeof(list));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x400,%edx
  mov    $0x3,%edi
  call   <flistxattr@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x418,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int fd = 3;
  char list[1024];
  return flistxattr(fd, list, sizeof(list));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x418,%rsp
  mov    $0x400,%edx
  mov    $0x3,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <flistxattr@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x418,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int fd = 3;
  char list[1024];
  return flistxattr(fd, list, sizeof(list));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x418,%rsp
  mov    $0x400,%edx
  mov    $0x3,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <flistxattr@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x418,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int fd = 3;
  char list[1024];
  return flistxattr(fd, list, sizeof(list));
}
```