ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<print_spaces>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x14,%esi
  jbe    L9
  nopl   0x0(%rax)
L2:
  mov    $0x14,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  sub    $0x14,%ebx
  call   <strbuf_write@plt>
  cmp    $0x14,%ebx
  ja     L2
  mov    %ebx,%edx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <strbuf_write@plt>
  nopl   0x0(%rax)
L9:
  pop    %rbx
  mov    %esi,%edx
  mov    %rbp,%rdi
  mov    %r12,%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <strbuf_write@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0:                     

assistant: ```c
void print_spaces(struct strbuf *buf, int count) {
  static const char s[] = "                    ";
  while (count >= sizeof(s)) {
    strbuf_write(buf, s, sizeof(s) - 1);
    count -= sizeof(s) - 1;
  }
  strbuf_write(buf, s, count);
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L9
  mov    $0x0,%edi
  call   <assert@plt>
L9:
  movl   $0x0,-0x20(%rbp)
  jmp    L27
L20:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <push@plt>
  addl   $0x1,-0x20(%rbp)
L27:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  movl   $0x0,-0x1c(%rbp)
  jmp    L19
L23:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    %al,(%rbx)
L19:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  je     L23
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void reverse(char str[]) {
  struct stack *stack = createStack(strlen(str));
  if (!stack) {
    assert(0);
  }
  for (int i = 0; str[i]; i++) {
    push(stack, str[i]);
  }
  int i = 0;
  while (!isEmpty(stack)) {
    str[i++] = pop(stack);
  }
  str[i] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
L3:
  movzbl (%r12),%esi
  test   %sil,%sil
  je     L32
  lea    0x1(%r12),%rbx
L28:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L28
L32:
  mov    $0x0,%ebx
  jmp    L2
L24:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L3
L57:
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L2:
  mov    %rbp,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  je     L57
  movslq %ebx,%r13
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void reverse(char str[]) {
  struct stack *stack = createStack(strlen(str));
  if (!stack) {
    assert(0);
  }
  for (int i = 0; str[i]; i++) {
    push(stack, str[i]);
  }
  int i = 0;
  while (!isEmpty(stack)) {
    str[i++] = pop(stack);
  }
  str[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L52:
  movsbl (%rbx),%esi
  lea    0x1(%rbx),%r12
  test   %sil,%sil
  je     L1
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <push@plt>
  movsbl -0x1(%r12),%esi
  test   %sil,%sil
  jne    L24
  mov    %rbp,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  jne    L55
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <pop@plt>
  mov    %al,-0x1(%rbx)
L1:
  mov    %rbp,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  je     L26
L55:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %edi,%edi
  call   <assert@plt>
  jmp    L52
```

assistant: ```c
void reverse(char str[]) {
  struct stack *stack = createStack(strlen(str));
  if (!stack) {
    assert(0);
  }
  for (int i = 0; str[i]; i++) {
    push(stack, str[i]);
  }
  int i = 0;
  while (!isEmpty(stack)) {
    str[i++] = pop(stack);
  }
  str[i] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
L24:
  movsbl (%rbx),%esi
  lea    0x1(%rbx),%r12
  test   %sil,%sil
  je     L0
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <push@plt>
  movsbl -0x1(%r12),%esi
  test   %sil,%sil
  jne    L34
  mov    %rbp,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  jne    L49
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <pop@plt>
  mov    %al,-0x1(%rbx)
L0:
  mov    %rbp,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  je     L31
L49:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %edi,%edi
  call   <assert@plt>
  jmp    L24
```

assistant: ```c
void reverse(char str[]) {
  struct stack *stack = createStack(strlen(str));
  if (!stack) {
    assert(0);
  }
  for (int i = 0; str[i]; i++) {
    push(stack, str[i]);
  }
  int i = 0;
  while (!isEmpty(stack)) {
    str[i++] = pop(stack);
  }
  str[i] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L15
L2:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  negl   -0x4(%rbp)
L15:
  cmpl   $0x0,-0x8(%rbp)
  jg     L2
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int q, z;
  q = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (q > 0) {
    q = q + z - 1;
    z = -z;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L0
L16:
  lea    -0x1(%rbx,%rax,1),%ebx
  neg    %eax
  test   %ebx,%ebx
  jg     L16
L0:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int q, z;
  q = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (q > 0) {
    q = q + z - 1;
    z = -z;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L16
  nopl   0x0(%rax)
L19:
  lea    -0x1(%rbx,%rax,1),%ebx
  neg    %eax
  test   %ebx,%ebx
  jg     L19
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int q, z;
  q = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (q > 0) {
    q = q + z - 1;
    z = -z;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L8
  nopl   0x0(%rax)
L6:
  lea    -0x1(%rbx,%rax,1),%ebx
  neg    %eax
  test   %ebx,%ebx
  jg     L6
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int q, z;
  q = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (q > 0) {
    q = q + z - 1;
    z = -z;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<drv_Pertelian_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <drv_generic_serial_close@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int drv_Pertelian_close(void) {
  drv_generic_serial_close();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drv_Pertelian_close>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <drv_generic_serial_close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int drv_Pertelian_close(void) {
  drv_generic_serial_close();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<drv_Pertelian_close>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <drv_generic_serial_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int drv_Pertelian_close(void) {
  drv_generic_serial_close();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<drv_Pertelian_close>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <drv_generic_serial_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int drv_Pertelian_close(void) {
  drv_generic_serial_close();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mp4tree_selftest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x80,-0x30(%rbp)
  movl   $0x40,-0x2c(%rbp)
  movl   $0x60,-0x28(%rbp)
  movl   $0x20,-0x24(%rbp)
  movl   $0x28,-0x20(%rbp)
  movl   $0x30,-0x1c(%rbp)
  movl   $0x38,-0x18(%rbp)
  movl   $0x10,-0x14(%rbp)
  movl   $0x12,-0x10(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L21
L64:
  mov    -0x34(%rbp),%edx
  lea    -0x3c(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get_bit@plt>
  cmp    $0x1,%eax
  je     L24
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L35
L24:
  addl   $0x1,-0x34(%rbp)
L21:
  cmpl   $0x1f,-0x34(%rbp)
  jle    L64
  movl   $0x0,-0x34(%rbp)
  jmp    L5
L16:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <get_exp_golomb@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L5:
  mov    -0x34(%rbp),%eax
  cmp    $0x8,%eax
  jbe    L16
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
type_infered: string
name: retrieve_data
arguments: tag: D15
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string

tool: D25: Failed 1

tool: D15: %x -> %u


tool: D12: bit = %u


assistant: ```c
int mp4tree_selftest() {
  uint32_t t1 = 0xffffffff;
  uint32_t bit = 0;
  uint8_t v[] = {
      0x80, 0x40, 0x60, 0x20, 0x28, 0x30, 0x38, 0x10, 0x12,
  };
  int i;
  for (i = 0; i < 32; i++) {
    if (get_bit((uint8_t *)&t1, i) != 1) {
      printf("Failed 1\n");
      return -1;
    }
  }
  for (i = 0; i < sizeof(v) / sizeof(v[0]); i++) {
    printf("%x -> %u\n", i, get_exp_golomb(&v[i], &bit));
    printf("bit = %u\n", bit);
    bit = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mp4tree_selftest>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x80,0x10(%rsp)
  movl   $0x40,0x14(%rsp)
  movl   $0x60,0x18(%rsp)
  movl   $0x20,0x1c(%rsp)
  movl   $0x28,0x20(%rsp)
  movl   $0x30,0x24(%rsp)
  movl   $0x38,0x28(%rsp)
  movl   $0x10,0x2c(%rsp)
  movl   $0x12,0x30(%rsp)
  mov    $0x0,%ebx
  lea    0x8(%rsp),%rbp
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <get_bit@plt>
  cmp    $0x1,%eax
  jne    L20
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  jne    L7
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    0xc(%rsp),%r14
  lea    D20(%rip),%r13
  lea    D4(%rip),%r12
L43:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <get_exp_golomb@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x9,%ebx
  jne    L43
  mov    $0x0,%eax
  jmp    L31
L20:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L31:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D20: %x -> %u


tool: D4: bit = %u


tool: D1: Failed 1

assistant: ```c
int mp4tree_selftest() {
  uint32_t t1 = 0xffffffff;
  uint32_t bit = 0;
  uint8_t v[] = {
      0x80, 0x40, 0x60, 0x20, 0x28, 0x30, 0x38, 0x10, 0x12,
  };
  int i;
  for (i = 0; i < 32; i++) {
    if (get_bit((uint8_t *)&t1, i) != 1) {
      printf("Failed 1\n");
      return -1;
    }
  }
  for (i = 0; i < sizeof(v) / sizeof(v[0]); i++) {
    printf("%x -> %u\n", i, get_exp_golomb(&v[i], &bit));
    printf("bit = %u\n", bit);
    bit = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mp4tree_selftest>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movabs $0x4000000080,%rax
  movl   $0xffffffff,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x2000000060,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3000000028,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x1000000038,%rax
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x28(%rsp)
  movl   $0x12,0x30(%rsp)
  jmp    L34
  nopl   (%rax)
L40:
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  je     L32
L34:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <get_bit@plt>
  cmp    $0x1,%eax
  je     L40
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L4:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L32:
  lea    0x10(%rsp),%r14
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r13
  lea    D12(%rip),%r12
  lea    D8(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r14,%rdi
  mov    %r13,%rsi
  add    $0x4,%r14
  call   <get_exp_golomb@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  cmp    $0x9,%ebx
  jne    L42
  xor    %eax,%eax
  jmp    L4
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D8
datatype: string

tool: D7: Failed 1

tool: D12: %x -> %u


tool: D8: bit = %u


assistant: ```c
int mp4tree_selftest() {
  uint32_t t1 = 0xffffffff;
  uint32_t bit = 0;
  uint8_t v[] = {
      0x80, 0x40, 0x60, 0x20, 0x28, 0x30, 0x38, 0x10, 0x12,
  };
  int i;
  for (i = 0; i < 32; i++) {
    if (get_bit((uint8_t *)&t1, i) != 1) {
      printf("Failed 1\n");
      return -1;
    }
  }
  for (i = 0; i < sizeof(v) / sizeof(v[0]); i++) {
    printf("%x -> %u\n", i, get_exp_golomb(&v[i], &bit));
    printf("bit = %u\n", bit);
    bit = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mp4tree_selftest>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movl   $0xffffffff,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D49(%rip),%xmm0
  movl   $0x0,0xc(%rsp)
  movl   $0x12,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  je     L35
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <get_bit@plt>
  cmp    $0x1,%eax
  je     L56
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L27:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L35:
  lea    0x10(%rsp),%r14
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r13
  lea    D45(%rip),%r12
  lea    D3(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rdi
  mov    %r13,%rsi
  add    $0x4,%r14
  call   <get_exp_golomb@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  cmp    $0x9,%ebx
  jne    L25
  xor    %eax,%eax
  jmp    L27
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: byte[16]
name: read_data
arguments: tag: D49
type_guessed: byte[16]
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D45
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string

tool: {"D8": [0x80,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x60,0x00,0x00,0x00,0x20,0x00,0x00,0x00]}

tool: {"D49": [0x28,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x38,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: D1: Failed 1

tool: D45: %x -> %u


tool: D3: bit = %u


assistant: ```c
int mp4tree_selftest() {
  uint32_t t1 = 0xffffffff;
  uint32_t bit = 0;
  uint8_t v[] = {
      0x80, 0x40, 0x60, 0x20, 0x28, 0x30, 0x38, 0x10, 0x12,
  };
  int i;
  for (i = 0; i < 32; i++) {
    if (get_bit((uint8_t *)&t1, i) != 1) {
      printf("Failed 1\n");
      return -1;
    }
  }
  for (i = 0; i < sizeof(v) / sizeof(v[0]); i++) {
    printf("%x -> %u\n", i, get_exp_golomb(&v[i], &bit));
    printf("bit = %u\n", bit);
    bit = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_next_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x14,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L33
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L33
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L33
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x24(%rbp)
L33:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L8
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L8
L80:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x24(%rbp)
L8:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L48
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L80
L48:
  cmpl   $0x0,-0x24(%rbp)
  jne    L94
  mov    $0x0,%eax
  jmp    L52
L94:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L52:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L85
  call   <__stack_chk_fail@plt>
L85:
  leave
  ret
```

assistant: ```c
int read_next_int(const char *str, int *pos) {
  int opos = 0;
  char buf[20];
  memset(buf, 0, 20);
  if (str[*pos] == '-' && str[(*pos) + 1] >= '0' && str[(*pos) + 1] <= '9') {
    buf[opos] = str[*pos];
    (*pos)++;
    opos++;
  }
  if (str[*pos] == '+') {
    (*pos)++;
  }
  while (str[*pos] >= '0' && str[*pos] <= '9') {
    buf[opos] = str[*pos];
    (*pos)++;
    opos++;
  }
  if (opos == 0)
    return 0;
  return atoi(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_next_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x14,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    (%rbx),%ecx
  movslq %ecx,%rdx
  mov    $0x0,%eax
  cmpb   $0x2d,0x0(%rbp,%rdx,1)
  je     L17
L75:
  mov    (%rbx),%edx
  movslq %edx,%rcx
  cmpb   $0x2b,0x0(%rbp,%rcx,1)
  je     L59
L26:
  mov    (%rbx),%esi
  movslq %esi,%r8
  movzbl 0x0(%rbp,%r8,1),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  ja     L5
  lea    0x1(%rsi),%edx
  movslq %edx,%rdx
  movslq %eax,%rdi
  sub    %r8,%rdi
  lea    (%rsp,%rdi,1),%r8
  sub    %esi,%eax
  mov    %eax,%edi
L36:
  mov    %cl,-0x1(%r8,%rdx,1)
  mov    %edx,(%rbx)
  lea    (%rdi,%rdx,1),%eax
  movzbl 0x0(%rbp,%rdx,1),%ecx
  add    $0x1,%rdx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L36
L5:
  test   %eax,%eax
  jne    L70
L71:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  movzbl 0x1(%rbp,%rdx,1),%edx
  sub    $0x30,%edx
  cmp    $0x9,%dl
  ja     L5
  movb   $0x2d,(%rsp)
  add    $0x1,%ecx
  mov    %ecx,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L59:
  add    $0x1,%edx
  mov    %edx,(%rbx)
  jmp    L26
L70:
  mov    %rsp,%rdi
  call   <atoi@plt>
  jmp    L71
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_next_int(const char *str, int *pos) {
  int opos = 0;
  char buf[20];
  memset(buf, 0, 20);
  if (str[*pos] == '-' && str[(*pos) + 1] >= '0' && str[(*pos) + 1] <= '9') {
    buf[opos] = str[*pos];
    (*pos)++;
    opos++;
  }
  if (str[*pos] == '+') {
    (*pos)++;
  }
  while (str[*pos] >= '0' && str[*pos] <= '9') {
    buf[opos] = str[*pos];
    (*pos)++;
    opos++;
  }
  if (opos == 0)
    return 0;
  return atoi(buf);
}
```