ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <nrerror@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: usage:
RNALfold [-L span]
         [-T temp] [-4] [-d[2|3]] [-noGU] [-noCloseGU]
         [-noLP] [-P paramfile] [-nsp pairs] [-noconv]


assistant: ```c
void usage(void) {
  nrerror("usage:\n"
          "RNALfold [-L span]\n"
          "         [-T temp] [-4] [-d[2|3]] [-noGU] [-noCloseGU]\n"
          "         [-noLP] [-P paramfile] [-nsp pairs] [-noconv]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  lea    D8(%rip),%rdi
  jmp    1050 <nrerror@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: usage:
RNALfold [-L span]
         [-T temp] [-4] [-d[2|3]] [-noGU] [-noCloseGU]
         [-noLP] [-P paramfile] [-nsp pairs] [-noconv]


assistant: ```c
void usage(void) {
  nrerror("usage:\n"
          "RNALfold [-L span]\n"
          "         [-T temp] [-4] [-d[2|3]] [-noGU] [-noCloseGU]\n"
          "         [-noLP] [-P paramfile] [-nsp pairs] [-noconv]\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usage>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <nrerror@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: usage:
RNALfold [-L span]
         [-T temp] [-4] [-d[2|3]] [-noGU] [-noCloseGU]
         [-noLP] [-P paramfile] [-nsp pairs] [-noconv]


assistant: ```c
void usage(void) {
  nrerror("usage:\n"
          "RNALfold [-L span]\n"
          "         [-T temp] [-4] [-d[2|3]] [-noGU] [-noCloseGU]\n"
          "         [-noLP] [-P paramfile] [-nsp pairs] [-noconv]\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<videoinput_get_norm_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L30:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <videoinput_get_norm_name@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x4(%rbp),%eax
  jmp    L14
L37:
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x7,-0x4(%rbp)
  jle    L30
  mov    $0xffffffff,%eax
L14:
  leave
  ret
```

assistant: ```c
int videoinput_get_norm_number(const char *name) {
  int i;
  for (i = 0; i < 7 + 1; i++) {
    if (!strcasecmp(name, videoinput_get_norm_name(i))) {
      return i;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<videoinput_get_norm_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L11:
  mov    %ebx,%edi
  call   <videoinput_get_norm_name@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  je     L3
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L11
  mov    $0xffffffff,%ebx
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int videoinput_get_norm_number(const char *name) {
  int i;
  for (i = 0; i < 7 + 1; i++) {
    if (!strcasecmp(name, videoinput_get_norm_name(i))) {
      return i;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<videoinput_get_norm_number>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  mov    %r12d,%edi
  call   <videoinput_get_norm_name@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <strcasecmp@plt>
  test   %eax,%eax
  je     L2
  add    $0x1,%r12d
  cmp    $0x8,%r12d
  jne    L4
  mov    $0xffffffff,%r12d
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int videoinput_get_norm_number(const char *name) {
  int i;
  for (i = 0; i < 7 + 1; i++) {
    if (!strcasecmp(name, videoinput_get_norm_name(i))) {
      return i;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<videoinput_get_norm_number>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  mov    %r12d,%edi
  call   <videoinput_get_norm_name@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <strcasecmp@plt>
  test   %eax,%eax
  je     L6
  add    $0x1,%r12d
  cmp    $0x8,%r12d
  jne    L19
  mov    $0xffffffff,%r12d
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int videoinput_get_norm_number(const char *name) {
  int i;
  for (i = 0; i < 7 + 1; i++) {
    if (!strcasecmp(name, videoinput_get_norm_name(i))) {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__scan_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L15
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <__scan_uint@plt>
  neg    %eax
  jmp    L11
L15:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <__scan_uint@plt>
L11:
  leave
  ret
```

assistant: ```c
int __scan_int(const char **_str, int width, int flags) {
  if (**_str == '-') {
    (*_str)++;
    return -__scan_uint(_str, width - 1, flags);
  } else {
    return __scan_uint(_str, width - 1, flags);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__scan_int>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  cmpb   $0x2d,(%rax)
  je     L9
  sub    $0x1,%esi
  call   <__scan_uint@plt>
L16:
  add    $0x8,%rsp
  ret
L9:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  sub    $0x1,%esi
  call   <__scan_uint@plt>
  neg    %eax
  jmp    L16
```

assistant: ```c
int __scan_int(const char **_str, int width, int flags) {
  if (**_str == '-') {
    (*_str)++;
    return -__scan_uint(_str, width - 1, flags);
  } else {
    return __scan_uint(_str, width - 1, flags);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__scan_int>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x1,%esi
  cmpb   $0x2d,(%rax)
  je     L3
  jmp    1050 <__scan_uint@plt>
  nopl   0x0(%rax)
L3:
  add    $0x1,%rax
  sub    $0x8,%rsp
  mov    %rax,(%rdi)
  call   <__scan_uint@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
```

assistant: ```c
int __scan_int(const char **_str, int width, int flags) {
  if (**_str == '-') {
    (*_str)++;
    return -__scan_uint(_str, width - 1, flags);
  } else {
    return __scan_uint(_str, width - 1, flags);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__scan_int>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x1,%esi
  cmpb   $0x2d,(%rax)
  je     L7
  jmp    1050 <__scan_uint@plt>
  nopl   0x0(%rax)
L7:
  add    $0x1,%rax
  sub    $0x8,%rsp
  mov    %rax,(%rdi)
  call   <__scan_uint@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
```

assistant: ```c
int __scan_int(const char **_str, int width, int flags) {
  if (**_str == '-') {
    (*_str)++;
    return -__scan_uint(_str, width - 1, flags);
  } else {
    return __scan_uint(_str, width - 1, flags);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_2d_dbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L35
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L2
L35:
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <alloc_1d_dbl@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  mov    -0x18(%rbp),%rax
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs


assistant: ```c
float **alloc_2d_dbl(int m, int n) {
  int i;
  float **new_t;
  new_t = (float **)malloc((unsigned)(m * sizeof(float *)));
  if (new_t == NULL) {
    printf("ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs\n");
    return (NULL);
  }
  for (i = 0; i < m; i++) {
    new_t[i] = alloc_1d_dbl(n);
  }
  return (new_t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alloc_2d_dbl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L34
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L32
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L21:
  mov    %ebp,%edi
  call   <alloc_1d_dbl@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L21
L32:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r13d
  jmp    L32
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs


assistant: ```c
float **alloc_2d_dbl(int m, int n) {
  int i;
  float **new_t;
  new_t = (float **)malloc((unsigned)(m * sizeof(float *)));
  if (new_t == NULL) {
    printf("ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs\n");
    return (NULL);
  }
  for (i = 0; i < m; i++) {
    new_t[i] = alloc_1d_dbl(n);
  }
  return (new_t);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_2d_dbl>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L28
  test   %r12d,%r12d
  jle    L7
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopl   0x0(%rax)
L23:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <alloc_1d_dbl@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L23
L7:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs


assistant: ```c
float **alloc_2d_dbl(int m, int n) {
  int i;
  float **new_t;
  new_t = (float **)malloc((unsigned)(m * sizeof(float *)));
  if (new_t == NULL) {
    printf("ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs\n");
    return (NULL);
  }
  for (i = 0; i < m; i++) {
    new_t[i] = alloc_1d_dbl(n);
  }
  return (new_t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alloc_2d_dbl>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L27
  test   %r12d,%r12d
  jle    L22
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopl   0x0(%rax)
L8:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <alloc_1d_dbl@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L8
L22:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs


assistant: ```c
float **alloc_2d_dbl(int m, int n) {
  int i;
  float **new_t;
  new_t = (float **)malloc((unsigned)(m * sizeof(float *)));
  if (new_t == NULL) {
    printf("ALLOC_2D_DBL: Couldn't allocate array of dbl ptrs\n");
    return (NULL);
  }
  for (i = 0; i < m; i++) {
    new_t[i] = alloc_1d_dbl(n);
  }
  return (new_t);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  int t;
  t = *b;
  *b = *a;
  *a = t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  int t;
  t = *b;
  *b = *a;
  *a = t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  int t;
  t = *b;
  *b = *a;
  *a = t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x0,-0x8(%rbp)
  jns    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *string, char *reversed, int len) {
  reversed[len] = '\0';
  for (int i = len - 1; i > -1; i--) {
    char c = string[i];
    int reversed_index = (len - 1) - i;
    reversed[reversed_index] = c;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  movslq %edx,%rax
  movb   $0x0,(%rsi,%rax,1)
  mov    %edx,%eax
  sub    $0x1,%eax
  js     L14
  cltq
  add    %rax,%rdi
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rsi,%rdx,1),%rcx
L12:
  movzbl (%rdi),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rdi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
L14:
  ret
```

assistant: ```c
void reverse(char *string, char *reversed, int len) {
  reversed[len] = '\0';
  for (int i = len - 1; i > -1; i--) {
    char c = string[i];
    int reversed_index = (len - 1) - i;
    reversed[reversed_index] = c;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  movslq %edx,%rax
  movb   $0x0,(%rsi,%rax,1)
  sub    $0x1,%edx
  js     L2
  movslq %edx,%rax
  mov    %edx,%edx
  add    %rax,%rdi
  lea    0x1(%rsi,%rdx,1),%rdx
  nopl   (%rax)
L1:
  movzbl (%rdi),%eax
  add    $0x1,%rsi
  sub    $0x1,%rdi
  mov    %al,-0x1(%rsi)
  cmp    %rdx,%rsi
  jne    L1
L2:
  ret
```

assistant: ```c
void reverse(char *string, char *reversed, int len) {
  reversed[len] = '\0';
  for (int i = len - 1; i > -1; i--) {
    char c = string[i];
    int reversed_index = (len - 1) - i;
    reversed[reversed_index] = c;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  movslq %edx,%rax
  movb   $0x0,(%rsi,%rax,1)
  sub    $0x1,%edx
  js     L15
  movslq %edx,%rax
  mov    %edx,%edx
  add    %rax,%rdi
  lea    0x1(%rsi,%rdx,1),%rdx
  nopl   (%rax)
L0:
  movzbl (%rdi),%eax
  add    $0x1,%rsi
  sub    $0x1,%rdi
  mov    %al,-0x1(%rsi)
  cmp    %rdx,%rsi
  jne    L0
L15:
  ret
```

assistant: ```c
void reverse(char *string, char *reversed, int len) {
  reversed[len] = '\0';
  for (int i = len - 1; i > -1; i--) {
    char c = string[i];
    int reversed_index = (len - 1) - i;
    reversed[reversed_index] = c;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L14
L2:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L2
  mov    -0x8(%rbp),%rax
  and    $0x7ff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++) != '\0')
    hash = ((hash << 5) + hash) + c;
  return hash & (2048 - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L8
  mov    $0x1505,%eax
L17:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L17
L20:
  and    $0x7ff,%eax
  ret
L8:
  mov    $0x1505,%eax
  jmp    L20
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++) != '\0')
    hash = ((hash << 5) + hash) + c;
  return hash & (2048 - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L8
  mov    $0x1505,%eax
  nopl   (%rax)
L17:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L17
  and    $0x7ff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x505,%eax
  ret
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++) != '\0')
    hash = ((hash << 5) + hash) + c;
  return hash & (2048 - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L7
  mov    $0x1505,%eax
  nopl   (%rax)
L12:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L12
  and    $0x7ff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x505,%eax
  ret
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++) != '\0')
    hash = ((hash << 5) + hash) + c;
  return hash & (2048 - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ana_asm>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L69
  movb   $0xa0,0x7(%rsp)
L9:
  lea    0x7(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L69:
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L80
  movb   $0xa1,0x7(%rsp)
  jmp    L9
L80:
  lea    D69(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L155
  movb   $0xa2,0x7(%rsp)
  jmp    L9
L155:
  lea    D35(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
  movb   $0xa3,0x7(%rsp)
  jmp    L9
L42:
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L59
  movb   $0xa4,0x7(%rsp)
  jmp    L9
L59:
  lea    D37(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L52
  movb   $0xa5,0x7(%rsp)
  jmp    L9
L52:
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L71
  movb   $0xa6,0x7(%rsp)
  jmp    L9
L71:
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
  movb   $0xa7,0x7(%rsp)
  jmp    L9
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D69
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D35
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string

tool: D3: b

tool: D22: c

tool: D69: d

tool: D35: e

tool: D25: h

tool: D37: l

tool: D11: m

tool: D10: a

assistant: ```c
void ana_asm(char *reg, FILE *file) {
  unsigned char buffer[] = {0};
  if (strcmp(reg, "b") == 0)
    buffer[0] = 0xa0;
  else if (strcmp(reg, "c") == 0)
    buffer[0] = 0xa1;
  else if (strcmp(reg, "d") == 0)
    buffer[0] = 0xa2;
  else if (strcmp(reg, "e") == 0)
    buffer[0] = 0xa3;
  else if (strcmp(reg, "h") == 0)
    buffer[0] = 0xa4;
  else if (strcmp(reg, "l") == 0)
    buffer[0] = 0xa5;
  else if (strcmp(reg, "m") == 0)
    buffer[0] = 0xa6;
  else if (strcmp(reg, "a") == 0)
    buffer[0] = 0xa7;
  fwrite(buffer, sizeof(buffer), 1, file);
}
```