ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<_ends_with_semicolon>:
  endbr64
  test   %esi,%esi
  jle    L24
  push   %rbp
  movslq %esi,%rax
  push   %rbx
  lea    -0x2(%rdi,%rax,1),%rbp
  lea    -0x1(%rdi,%rax,1),%rbx
  lea    -0x1(%rsi),%eax
  sub    %rax,%rbp
  sub    $0x8,%rsp
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L39
L28:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  xor    %eax,%eax
  cmpb   $0x3b,(%rbx)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int _ends_with_semicolon(const char *z, int N) {
  while (N > 0 && isspace(z[N - 1])) {
    N--;
  }
  return N > 0 && z[N - 1] == ';';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_ends_with_semicolon>:
  endbr64
  test   %esi,%esi
  jle    L36
  push   %rbp
  movslq %esi,%rax
  push   %rbx
  lea    -0x2(%rdi,%rax,1),%rbp
  lea    -0x1(%rdi,%rax,1),%rbx
  lea    -0x1(%rsi),%eax
  sub    %rax,%rbp
  sub    $0x8,%rsp
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L4:
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L22
L30:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  xor    %eax,%eax
  cmpb   $0x3b,(%rbx)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int _ends_with_semicolon(const char *z, int N) {
  while (N > 0 && isspace(z[N - 1])) {
    N--;
  }
  return N > 0 && z[N - 1] == ';';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<man_linebreak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bufput@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: .br

assistant: ```c
int man_linebreak(struct buf *ob, void *opaque) {
  bufput(ob, ".br", sizeof ".br" - 1);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<man_linebreak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D7(%rip),%rsi
  call   <bufput@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: .br

assistant: ```c
int man_linebreak(struct buf *ob, void *opaque) {
  bufput(ob, ".br", sizeof ".br" - 1);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<man_linebreak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D2(%rip),%rsi
  call   <bufput@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: .br

assistant: ```c
int man_linebreak(struct buf *ob, void *opaque) {
  bufput(ob, ".br", sizeof ".br" - 1);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<man_linebreak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D6(%rip),%rsi
  call   <bufput@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: .br

assistant: ```c
int man_linebreak(struct buf *ob, void *opaque) {
  bufput(ob, ".br", sizeof ".br" - 1);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L50
  mov    $0x20,%eax
  jmp    L36
L50:
  movl   $0x0,-0x4(%rbp)
  cmpl   $0xffff,-0x14(%rbp)
  jg     L7
  addl   $0x10,-0x4(%rbp)
  shll   $0x10,-0x14(%rbp)
L7:
  cmpl   $0xffffff,-0x14(%rbp)
  jg     L22
  addl   $0x8,-0x4(%rbp)
  shll   $0x8,-0x14(%rbp)
L22:
  cmpl   $0xfffffff,-0x14(%rbp)
  jg     L48
  addl   $0x4,-0x4(%rbp)
  shll   $0x4,-0x14(%rbp)
L48:
  cmpl   $0x3fffffff,-0x14(%rbp)
  jg     L58
  addl   $0x2,-0x4(%rbp)
  shll   $0x2,-0x14(%rbp)
L58:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int32_t clz(uint32_t x) {
  int n;
  if (x == 0)
    return 32;
  n = 0;
  if (x <= 0x0000FFFF) {
    n = n + 16;
    x = x << 16;
  }
  if (x <= 0x00FFFFFF) {
    n = n + 8;
    x = x << 8;
  }
  if (x <= 0x0FFFFFFF) {
    n = n + 4;
    x = x << 4;
  }
  if (x <= 0x3FFFFFFF) {
    n = n + 2;
    x = x << 2;
  }
  if (x <= 0x7FFFFFFF) {
    n = n + 1;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clz>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L28
  mov    $0x0,%eax
  cmp    $0xffff,%edi
  jg     L31
  shl    $0x10,%edi
  mov    $0x10,%eax
L31:
  cmp    $0xffffff,%edi
  jg     L30
  add    $0x8,%eax
  shl    $0x8,%edi
L30:
  cmp    $0xfffffff,%edi
  jg     L4
  add    $0x4,%eax
  shl    $0x4,%edi
L4:
  lea    0x2(%rax),%edx
  cmp    $0x40000000,%edi
  cmovl  %edx,%eax
  add    $0x1,%eax
L28:
  ret
```

assistant: ```c
int32_t clz(uint32_t x) {
  int n;
  if (x == 0)
    return 32;
  n = 0;
  if (x <= 0x0000FFFF) {
    n = n + 16;
    x = x << 16;
  }
  if (x <= 0x00FFFFFF) {
    n = n + 8;
    x = x << 8;
  }
  if (x <= 0x0FFFFFFF) {
    n = n + 4;
    x = x << 4;
  }
  if (x <= 0x3FFFFFFF) {
    n = n + 2;
    x = x << 2;
  }
  if (x <= 0x7FFFFFFF) {
    n = n + 1;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clz>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L29
  xor    %eax,%eax
  cmp    $0xffff,%edi
  jg     L2
  shl    $0x10,%edi
  mov    $0x10,%eax
L2:
  cmp    $0xffffff,%edi
  jg     L23
  add    $0x8,%eax
  shl    $0x8,%edi
L23:
  cmp    $0xfffffff,%edi
  jg     L36
  add    $0x4,%eax
  shl    $0x4,%edi
L36:
  cmp    $0x40000000,%edi
  lea    0x2(%rax),%edx
  cmovl  %edx,%eax
  add    $0x1,%eax
L29:
  ret
```

assistant: ```c
int32_t clz(uint32_t x) {
  int n;
  if (x == 0)
    return 32;
  n = 0;
  if (x <= 0x0000FFFF) {
    n = n + 16;
    x = x << 16;
  }
  if (x <= 0x00FFFFFF) {
    n = n + 8;
    x = x << 8;
  }
  if (x <= 0x0FFFFFFF) {
    n = n + 4;
    x = x << 4;
  }
  if (x <= 0x3FFFFFFF) {
    n = n + 2;
    x = x << 2;
  }
  if (x <= 0x7FFFFFFF) {
    n = n + 1;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clz>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L15
  cmp    $0xffff,%edi
  jle    L4
  mov    $0x8,%edx
  xor    %eax,%eax
L30:
  cmp    $0xffffff,%edi
  jg     L6
  shl    $0x8,%edi
  mov    %edx,%eax
L6:
  cmp    $0xfffffff,%edi
  jg     L16
  add    $0x4,%eax
  shl    $0x4,%edi
L16:
  cmp    $0x40000000,%edi
  lea    0x2(%rax),%edx
  cmovl  %edx,%eax
  add    $0x1,%eax
L15:
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  shl    $0x10,%edi
  mov    $0x18,%edx
  mov    $0x10,%eax
  jmp    L30
```

assistant: ```c
int32_t clz(uint32_t x) {
  int n;
  if (x == 0)
    return 32;
  n = 0;
  if (x <= 0x0000FFFF) {
    n = n + 16;
    x = x << 16;
  }
  if (x <= 0x00FFFFFF) {
    n = n + 8;
    x = x << 8;
  }
  if (x <= 0x0FFFFFFF) {
    n = n + 4;
    x = x << 4;
  }
  if (x <= 0x3FFFFFFF) {
    n = n + 2;
    x = x << 2;
  }
  if (x <= 0x7FFFFFFF) {
    n = n + 1;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <getpwuid@plt>
  test   %rax,%rax
  je     L16
  mov    (%rax),%rdx
  mov    %ebp,%esi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  mov    %ebx,%edi
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L91
  mov    (%rax),%rdx
  mov    %ebx,%esi
  lea    D70(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L117:
  cmp    %r13d,%ebp
  jne    L17
L25:
  cmp    %r12d,%ebx
  jne    L98
L111:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %ebp,%esi
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L91:
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L117
L17:
  mov    %r13d,%edi
  call   <getpwuid@plt>
  test   %rax,%rax
  je     L33
  mov    (%rax),%rdx
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L33:
  mov    %r13d,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L98:
  mov    %r12d,%edi
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L109
  mov    (%rax),%rdx
  mov    %r12d,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L111
L109:
  mov    %r12d,%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L111
```

tool_calls: name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D70
type: string
name: unpack_data
arguments: tag: D75
type: string
name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D43
type: string
name: unpack_data
arguments: tag: D40
type: string
name: unpack_data
arguments: tag: D37
type: string

tool: D38: uid=%d(%s) 

tool: D70: gid=%d(%s) 

tool: D75: uid=%d 

tool: D8: gid=%d 

tool: D1: euid=%d(%s) 

tool: D43: euid=%d 

tool: D40: egid=%d(%s) 

tool: D37: egid=%d 

assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pwd;
  struct group *grp;
  int uid, gid, euid, egid;
  uid = getuid();
  gid = getgid();
  euid = geteuid();
  egid = getegid();
  if ((pwd = getpwuid(uid)) == NULL)
    printf("uid=%d ", uid);
  else
    printf("uid=%d(%s) ", uid, pwd->pw_name);
  if ((grp = getgrgid(gid)) == NULL)
    printf("gid=%d ", gid);
  else
    printf("gid=%d(%s) ", gid, grp->gr_name);
  if (uid != euid)
    if ((pwd = getpwuid(euid)) != NULL)
      printf("euid=%d(%s) ", euid, pwd->pw_name);
    else
      printf("euid=%d ", euid);
  if (gid != egid)
    if ((grp = getgrgid(egid)) != NULL)
      printf("egid=%d(%s) ", egid, grp->gr_name);
    else
      printf("egid=%d ", egid);
  printf("\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getuid@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <getegid@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <getpwuid@plt>
  test   %rax,%rax
  je     L3
  mov    (%rax),%rdx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    %ebx,%edi
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L49
  mov    (%rax),%rdx
  mov    %ebx,%esi
  lea    D75(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L5:
  cmp    %r13d,%ebp
  jne    L65
L114:
  cmp    %r12d,%ebx
  jne    L1
L69:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L65:
  mov    %r13d,%edi
  call   <getpwuid@plt>
  test   %rax,%rax
  je     L8
  mov    (%rax),%rdx
  mov    %r13d,%esi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L114
L1:
  mov    %r12d,%edi
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L109
  mov    (%rax),%rdx
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L69
L49:
  mov    %ebx,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L3:
  mov    %ebp,%esi
  lea    D74(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L8:
  mov    %r13d,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L114
L109:
  mov    %r12d,%esi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L69
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string
name: retrieve_data
arguments: tag: D75
type_infered: string
name: retrieve_data
arguments: tag: D52
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D22
type_infered: string
name: retrieve_data
arguments: tag: D74
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string
name: retrieve_data
arguments: tag: D57
type_infered: string

tool: D9: uid=%d(%s) 

tool: D75: gid=%d(%s) 

tool: D52: euid=%d(%s) 

tool: D4: egid=%d(%s) 

tool: D22: gid=%d 

tool: D74: uid=%d 

tool: D35: euid=%d 

tool: D57: egid=%d 

assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pwd;
  struct group *grp;
  int uid, gid, euid, egid;
  uid = getuid();
  gid = getgid();
  euid = geteuid();
  egid = getegid();
  if ((pwd = getpwuid(uid)) == NULL)
    printf("uid=%d ", uid);
  else
    printf("uid=%d(%s) ", uid, pwd->pw_name);
  if ((grp = getgrgid(gid)) == NULL)
    printf("gid=%d ", gid);
  else
    printf("gid=%d(%s) ", gid, grp->gr_name);
  if (uid != euid)
    if ((pwd = getpwuid(euid)) != NULL)
      printf("euid=%d(%s) ", euid, pwd->pw_name);
    else
      printf("euid=%d ", euid);
  if (gid != egid)
    if ((grp = getgrgid(egid)) != NULL)
      printf("egid=%d(%s) ", egid, grp->gr_name);
    else
      printf("egid=%d ", egid);
  printf("\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getuid@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <getegid@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <getpwuid@plt>
  test   %rax,%rax
  je     L32
  mov    (%rax),%rdx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L28:
  mov    %ebx,%edi
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L22
  mov    (%rax),%rdx
  mov    %ebx,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L109:
  cmp    %r13d,%ebp
  jne    L87
L26:
  cmp    %r12d,%ebx
  jne    L60
L64:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L87:
  mov    %r13d,%edi
  call   <getpwuid@plt>
  test   %rax,%rax
  je     L29
  mov    (%rax),%rdx
  mov    %r13d,%esi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
L60:
  mov    %r12d,%edi
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L58
  mov    (%rax),%rdx
  mov    %r12d,%esi
  lea    D73(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L64
L22:
  mov    %ebx,%esi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L32:
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L29:
  mov    %r13d,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
L58:
  mov    %r12d,%esi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L64
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string
name: parse_data
arguments: data_label: D12
type: string
name: parse_data
arguments: data_label: D69
type: string
name: parse_data
arguments: data_label: D73
type: string
name: parse_data
arguments: data_label: D49
type: string
name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D46
type: string

tool: D4: uid=%d(%s) 

tool: D12: gid=%d(%s) 

tool: D69: euid=%d(%s) 

tool: D73: egid=%d(%s) 

tool: D49: gid=%d 

tool: D11: uid=%d 

tool: D22: euid=%d 

tool: D46: egid=%d 

assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pwd;
  struct group *grp;
  int uid, gid, euid, egid;
  uid = getuid();
  gid = getgid();
  euid = geteuid();
  egid = getegid();
  if ((pwd = getpwuid(uid)) == NULL)
    printf("uid=%d ", uid);
  else
    printf("uid=%d(%s) ", uid, pwd->pw_name);
  if ((grp = getgrgid(gid)) == NULL)
    printf("gid=%d ", gid);
  else
    printf("gid=%d(%s) ", gid, grp->gr_name);
  if (uid != euid)
    if ((pwd = getpwuid(euid)) != NULL)
      printf("euid=%d(%s) ", euid, pwd->pw_name);
    else
      printf("euid=%d ", euid);
  if (gid != egid)
    if ((grp = getgrgid(egid)) != NULL)
      printf("egid=%d(%s) ", egid, grp->gr_name);
    else
      printf("egid=%d ", egid);
  printf("\n");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  js     L16
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  jns    L16
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  mov    %rax,%r8
  mov    %rdx,%rcx
  not    %rdi
  test   %rdx,%rdi
  js     L11
L16:
  mov    %r8,%rax
  mov    %rcx,%rdx
  ret
L11:
  lea    0x1(%rax),%r8
  sub    %rsi,%rcx
  jmp    L16
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  not    %rdi
  cqto
  idiv   %rsi
  test   %rdx,%rdi
  js     L3
  ret
  nopl   (%rax)
L3:
  add    $0x1,%rax
  sub    %rsi,%rdx
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  not    %rdi
  cqto
  idiv   %rsi
  test   %rdx,%rdi
  js     L0
  ret
  nopl   (%rax)
L0:
  add    $0x1,%rax
  sub    %rsi,%rdx
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <alarm@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test(void) {
  unsigned int seconds;
  unsigned int result;
  seconds = 10;
  result = alarm(seconds);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <alarm@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test(void) {
  unsigned int seconds;
  unsigned int result;
  seconds = 10;
  result = alarm(seconds);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  mov    $0xa,%edi
  jmp    1050 <alarm@plt>
```

assistant: ```c
int test(void) {
  unsigned int seconds;
  unsigned int result;
  seconds = 10;
  result = alarm(seconds);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  mov    $0xa,%edi
  jmp    1050 <alarm@plt>
```

assistant: ```c
int test(void) {
  unsigned int seconds;
  unsigned int result;
  seconds = 10;
  result = alarm(seconds);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<neos_strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L44
L50:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L44:
  cmpl   $0x0,-0x4(%rbp)
  js     L35
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L50
  jmp    L35
L9:
  addq   $0x1,-0x18(%rbp)
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
L41:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *neos_strip(char *s) {
  int x;
  x = strlen(s) - 1;
  while (x >= 0 && isspace(s[x]))
    s[x--] = '\0';
  while (*s && isspace(*s))
    s++;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<neos_strip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L49
  movslq %ebx,%rbx
  add    %rbp,%rbx
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rdx,1),%r12
  lea    -0x1(%rax),%eax
  sub    %rax,%r12
L67:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L49
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L67
L49:
  movzbl 0x0(%rbp),%edi
  mov    %rbp,%rax
  test   %dil,%dil
  je     L59
L38:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L57
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L38
  mov    %rbp,%rax
  jmp    L59
L57:
  mov    %rbp,%rax
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *neos_strip(char *s) {
  int x;
  x = strlen(s) - 1;
  while (x >= 0 && isspace(s[x]))
    s[x--] = '\0';
  while (*s && isspace(*s))
    s++;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<neos_strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L14
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  lea    -0x2(%r12,%rax,1),%rbp
  add    %r12,%rbx
  sub    %rdx,%rbp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L42:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L14
L19:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L52
  nopl   0x0(%rax,%rax,1)
L62:
  call   <isspace@plt>
  test   %rax,%rax
  je     L52
  add    $0x1,%r12
L14:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L62
L52:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *neos_strip(char *s) {
  int x;
  x = strlen(s) - 1;
  while (x >= 0 && isspace(s[x]))
    s[x--] = '\0';
  while (*s && isspace(*s))
    s++;
  return s;
}
```