ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L13
  xor    %ecx,%ecx
  nopl   (%rax)
L5:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L5
  mov    %ecx,%edx
  mov    %ecx,%eax
  imul   $0x2f684bdb,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(char *symbol) {
  unsigned int sum;
  sum = 0;
  while (*symbol) {
    sum = sum * 31 + *symbol;
    symbol++;
  }
  return sum % 27;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osn_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <osn_msgq_init@plt>
  mov    $0x0,%eax
  call   <osn_task_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void osn_init(void) {
  osn_msgq_init();
  osn_task_init();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<osn_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <osn_msgq_init@plt>
  mov    $0x0,%eax
  call   <osn_task_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void osn_init(void) {
  osn_msgq_init();
  osn_task_init();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<osn_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <osn_msgq_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <osn_task_init@plt>
```

assistant: ```c
void osn_init(void) {
  osn_msgq_init();
  osn_task_init();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osn_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <osn_msgq_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <osn_task_init@plt>
```

assistant: ```c
void osn_init(void) {
  osn_msgq_init();
  osn_task_init();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<learnFrom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<learnFrom>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<learnFrom>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<learnFrom>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<replace_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x490,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x480(%rbp)
  mov    %rdx,-0x488(%rbp)
  mov    %ecx,-0x478(%rbp)
  mov    %r8d,-0x48c(%rbp)
  mov    %al,-0x474(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x470(%rbp)
  movl   $0x0,-0x46c(%rbp)
  jmp    L8
L62:
  mov    -0x46c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x488(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x474(%rbp)
  je     L1
  mov    -0x46c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x488(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x470(%rbp),%eax
  cltq
  mov    %dl,-0x460(%rbp,%rax,1)
  addl   $0x1,-0x470(%rbp)
  mov    -0x470(%rbp),%eax
  cltq
  movb   $0x0,-0x460(%rbp,%rax,1)
  jmp    L25
L1:
  movl   $0x0,-0x468(%rbp)
  jmp    L71
L49:
  mov    -0x468(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x480(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x470(%rbp),%eax
  cltq
  mov    %dl,-0x460(%rbp,%rax,1)
  addl   $0x1,-0x470(%rbp)
  addl   $0x1,-0x468(%rbp)
L71:
  mov    -0x468(%rbp),%eax
  cmp    -0x48c(%rbp),%eax
  jl     L49
  mov    -0x470(%rbp),%eax
  cltq
  movb   $0x0,-0x460(%rbp,%rax,1)
L25:
  addl   $0x1,-0x46c(%rbp)
L8:
  mov    -0x46c(%rbp),%eax
  cmp    -0x478(%rbp),%eax
  jl     L62
  movl   $0x0,-0x464(%rbp)
  jmp    L58
L79:
  mov    -0x464(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x488(%rbp),%rax
  add    %rax,%rdx
  mov    -0x464(%rbp),%eax
  cltq
  movzbl -0x460(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x464(%rbp)
L58:
  mov    -0x464(%rbp),%eax
  cmp    -0x470(%rbp),%eax
  jl     L79
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int replace_char(char c, char *new_pattern, char *string, int str_len, int pattern_len) {
  char temp[1100];
  int temp_len = 0;
  for (int i = 0; i < str_len; i++) {
    if (string[i] != c) {
      temp[temp_len] = string[i];
      temp_len++;
      temp[temp_len] = '\0';
    } else {
      for (int j = 0; j < pattern_len; j++) {
        temp[temp_len] = new_pattern[j];
        temp_len++;
      }
      temp[temp_len] = '\0';
    }
  }
  for (int i = 0; i < temp_len; i++) {
    string[i] = temp[i];
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<replace_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x460,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x458(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L97
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %edi,%ebx
  mov    %rdx,%rsi
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%rbp
  mov    $0x0,%edx
  mov    %r8d,%r11d
  mov    %rsp,%r12
  jmp    L32
L85:
  mov    $0x0,%eax
  movslq %edx,%rdi
  add    %r12,%rdi
  test   %r8d,%r8d
  jle    L67
L89:
  movzbl (%r9,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r11,%rax
  jne    L89
  add    %r8d,%edx
L67:
  movslq %edx,%rax
  movb   $0x0,(%rsp,%rax,1)
L80:
  add    $0x1,%rsi
  cmp    %rbp,%rsi
  je     L38
L32:
  movzbl (%rsi),%eax
  cmp    %bl,%al
  je     L85
  movslq %edx,%rcx
  mov    %al,(%rsp,%rcx,1)
  add    $0x1,%edx
  movslq %edx,%rax
  movb   $0x0,(%rsp,%rax,1)
  jmp    L80
L38:
  test   %edx,%edx
  jle    L97
  mov    %edx,%edx
  mov    $0x0,%eax
L22:
  movzbl (%rsp,%rax,1),%ecx
  mov    %cl,(%r10,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L22
L97:
  mov    0x458(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  mov    $0x0,%eax
  add    $0x460,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int replace_char(char c, char *new_pattern, char *string, int str_len, int pattern_len) {
  char temp[1100];
  int temp_len = 0;
  for (int i = 0; i < str_len; i++) {
    if (string[i] != c) {
      temp[temp_len] = string[i];
      temp_len++;
      temp[temp_len] = '\0';
    } else {
      for (int j = 0; j < pattern_len; j++) {
        temp[temp_len] = new_pattern[j];
        temp_len++;
      }
      temp[temp_len] = '\0';
    }
  }
  for (int i = 0; i < temp_len; i++) {
    string[i] = temp[i];
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<replace_char>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x478,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x468(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L55
  lea    -0x1(%rcx),%eax
  mov    %rdx,%r15
  mov    %rdx,%rbx
  mov    %edi,%r13d
  lea    0x1(%rdx,%rax,1),%r14
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  xor    %edx,%edx
  jmp    L2
  nopl   0x0(%rax)
L75:
  add    $0x1,%ebp
  mov    %al,0x10(%rsp,%rdx,1)
  add    $0x1,%rbx
  movslq %ebp,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  cmp    %r14,%rbx
  je     L74
L2:
  movzbl (%rbx),%eax
  cmp    %r13b,%al
  jne    L75
  test   %r8d,%r8d
  jle    L29
  lea    (%r12,%rdx,1),%rdi
  movslq %r8d,%rdx
  mov    %r8d,0xc(%rsp)
  mov    %rsi,(%rsp)
  call   <memcpy@plt>
  mov    0xc(%rsp),%r8d
  mov    (%rsp),%rsi
  add    %r8d,%ebp
  movslq %ebp,%rdx
L29:
  add    $0x1,%rbx
  movb   $0x0,0x10(%rsp,%rdx,1)
  cmp    %r14,%rbx
  jne    L2
  nopw   0x0(%rax,%rax,1)
L74:
  test   %ebp,%ebp
  je     L55
  lea    0x10(%rsp),%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
L55:
  mov    0x468(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x478,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int replace_char(char c, char *new_pattern, char *string, int str_len, int pattern_len) {
  char temp[1100];
  int temp_len = 0;
  for (int i = 0; i < str_len; i++) {
    if (string[i] != c) {
      temp[temp_len] = string[i];
      temp_len++;
      temp[temp_len] = '\0';
    } else {
      for (int j = 0; j < pattern_len; j++) {
        temp[temp_len] = new_pattern[j];
        temp_len++;
      }
      temp[temp_len] = '\0';
    }
  }
  for (int i = 0; i < temp_len; i++) {
    string[i] = temp[i];
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<replace_char>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x478,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x468(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L6
  lea    -0x1(%rcx),%eax
  mov    %rdx,%r15
  mov    %rdx,%rbx
  mov    %edi,%r13d
  lea    0x1(%rdx,%rax,1),%r14
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  xor    %edx,%edx
  jmp    L73
  nopl   0x0(%rax)
L54:
  add    $0x1,%ebp
  mov    %al,0x10(%rsp,%rdx,1)
  add    $0x1,%rbx
  movslq %ebp,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  cmp    %r14,%rbx
  je     L20
L73:
  movzbl (%rbx),%eax
  cmp    %r13b,%al
  jne    L54
  test   %r8d,%r8d
  jle    L32
  lea    (%r12,%rdx,1),%rdi
  movslq %r8d,%rdx
  mov    %r8d,0xc(%rsp)
  mov    %rsi,(%rsp)
  call   <memcpy@plt>
  mov    0xc(%rsp),%r8d
  mov    (%rsp),%rsi
  add    %r8d,%ebp
  movslq %ebp,%rdx
L32:
  add    $0x1,%rbx
  movb   $0x0,0x10(%rsp,%rdx,1)
  cmp    %r14,%rbx
  jne    L73
  nopw   0x0(%rax,%rax,1)
L20:
  test   %ebp,%ebp
  je     L6
  lea    0x10(%rsp),%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
L6:
  mov    0x468(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x478,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int replace_char(char c, char *new_pattern, char *string, int str_len, int pattern_len) {
  char temp[1100];
  int temp_len = 0;
  for (int i = 0; i < str_len; i++) {
    if (string[i] != c) {
      temp[temp_len] = string[i];
      temp_len++;
      temp[temp_len] = '\0';
    } else {
      for (int j = 0; j < pattern_len; j++) {
        temp[temp_len] = new_pattern[j];
        temp_len++;
      }
      temp[temp_len] = '\0';
    }
  }
  for (int i = 0; i < temp_len; i++) {
    string[i] = temp[i];
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<acceptData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  movl   $0xffffffff,(%rsi)
  movl   $0x0,(%rdx)
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%r13d
  lea    D46(%rip),%r14
  jmp    L27
L71:
  add    $0x1,%r13d
  add    $0x4,%r12
  cmp    $0x32,%r13d
  je     L92
L27:
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  D28(%rip),%xmm0
  ucomiss (%r12),%xmm0
  jp     L71
  jne    L71
L92:
  mov    %r13d,0x0(%rbp)
  lea    D35(%rip),%r13
  lea    D45(%rip),%r12
  lea    D48(%rip),%r15
  lea    D27(%rip),%r14
  jmp    L31
L30:
  lea    D72(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L99
  cmp    0x0(%rbp),%eax
  jge    L99
  test   $0x1,%al
  jne    L90
L99:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L30
  mov    0x0(%rbp),%esi
  cmp    %esi,%eax
  jge    L68
  test   $0x1,%al
  jne    L31
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L68:
  sub    $0x1,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D41
type_infered: string
name: unpack_data
arguments: label: D46
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: byte[4]
name: unpack_data
arguments: label: D35
type_infered: string
name: unpack_data
arguments: label: D45
type_infered: string
name: unpack_data
arguments: label: D48
type_infered: string
name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D72
type_infered: string

tool: D41: 
Enter up to 50 integers or -1 to exit: 

tool: D46: %f

tool: {"D28": [0x00,0x00,0x80,0xbf]}

tool: D35: 
Enter desired window length: 

tool: D45: %d

tool: D48: 
Error! Window value must be an odd number.

tool: D27: 
Error! Maximum window length is %d.

tool: D72: 
Error! Minimum window length is 1.

assistant: ```c
void acceptData(float valueSet[], int *win, int *size) {
  int i = 0;
  int j = 0;
  *win = -1;
  *size = 0;
  printf("\nEnter up to 50 integers or -1 to exit: ");
  for (j = 0; j < 50; j++) {
    scanf("%f", &valueSet[j]);
    if (valueSet[j] == -1) {
      j = 55;
      i--;
    }
    i++;
  }
  *size = i;
  while (*win <= 0 || *win > *size - 1 || *win % 2 == 0) {
    printf("\nEnter desired window length: ");
    scanf("%d", win);
    if (*win <= 0)
      printf("\nError! Minimum window length is 1.");
    else if (*win > *size - 1)
      printf("\nError! Maximum window length is %d.", *size - 1);
    else if (*win % 2 == 0)
      printf("\nError! Window value must be an odd number.");
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<does_too>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L13:
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x4,-0x4(%rbp)
  jle    L13
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: Does too!

assistant: ```c
void *does_too() {
  int i = 0;
  for (i = 0; i < 5; i++) {
    sleep(1);
    puts("Does too!");
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<does_too>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5,%ebx
  lea    D6(%rip),%rbp
L1:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  sub    $0x1,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Does too!

assistant: ```c
void *does_too() {
  int i = 0;
  for (i = 0; i < 5; i++) {
    sleep(1);
    puts("Does too!");
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<does_too>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
L7:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  sub    $0x1,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: Does too!

assistant: ```c
void *does_too() {
  int i = 0;
  for (i = 0; i < 5; i++) {
    sleep(1);
    puts("Does too!");
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<does_too>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
L9:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: Does too!

assistant: ```c
void *does_too() {
  int i = 0;
  for (i = 0; i < 5; i++) {
    sleep(1);
    puts("Does too!");
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uniquify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  seta   %al
  xor    $0x1,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x14(%rbp)
  jg     L15
  mov    $0x0,%eax
  jmp    L29
L15:
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L20
L7:
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x28(%rbp),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L43
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L43:
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int uniquify(int n, double *list, double tolerance) {
  int i;
  int pos;
  double val;
  assert(!(tolerance < 0.0));
  if (n < 1)
    return 0;
  pos = 0;
  val = list[pos++];
  for (i = 1; i < n; ++i) {
    if (val + tolerance < list[i]) {
      val = list[i];
      list[pos++] = val;
    }
  }
  list[pos - 1] = list[n - 1];
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uniquify>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  movapd %xmm0,%xmm3
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm3,%xmm0
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edx
  test   %ebp,%ebp
  jle    L28
  movsd  (%rbx),%xmm2
  cmp    $0x1,%ebp
  jle    L56
  lea    0x8(%rbx),%rax
  lea    -0x2(%rbp),%edx
  lea    0x10(%rbx,%rdx,8),%rcx
  mov    $0x1,%edx
  jmp    L2
L27:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L34
L2:
  movsd  (%rax),%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jbe    L27
  movslq %edx,%rsi
  movsd  %xmm0,(%rbx,%rsi,8)
  movapd %xmm0,%xmm2
  lea    0x1(%rdx),%edx
  jmp    L27
L56:
  mov    $0x1,%edx
L34:
  movslq %ebp,%rbp
  movsd  -0x8(%rbx,%rbp,8),%xmm0
  movslq %edx,%rax
  movsd  %xmm0,-0x8(%rbx,%rax,8)
L28:
  mov    %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int uniquify(int n, double *list, double tolerance) {
  int i;
  int pos;
  double val;
  assert(!(tolerance < 0.0));
  if (n < 1)
    return 0;
  pos = 0;
  val = list[pos++];
  for (i = 1; i < n; ++i) {
    if (val + tolerance < list[i]) {
      val = list[i];
      list[pos++] = val;
    }
  }
  list[pos - 1] = list[n - 1];
  return pos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uniquify>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  movslq %edi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  comisd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %r8d,%r8d
  test   %ebp,%ebp
  jle    L27
  movsd  (%rbx),%xmm3
  cmp    $0x1,%ebp
  je     L8
  lea    -0x2(%rbp),%edx
  movsd  0x8(%rsp),%xmm0
  lea    0x8(%rbx),%rax
  mov    $0x1,%r8d
  lea    0x10(%rbx,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L22:
  movapd %xmm0,%xmm2
  movsd  (%rax),%xmm1
  addsd  %xmm3,%xmm2
  comisd %xmm2,%xmm1
  jbe    L42
  movslq %r8d,%rcx
  movapd %xmm1,%xmm3
  add    $0x1,%r8d
  movsd  %xmm1,(%rbx,%rcx,8)
L42:
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L22
  movslq %r8d,%rax
  lea    -0x8(%rbx,%rax,8),%rax
L16:
  movsd  -0x8(%rbx,%rbp,8),%xmm0
  movsd  %xmm0,(%rax)
L27:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L8:
  mov    %rbx,%rax
  mov    $0x1,%r8d
  jmp    L16
```

assistant: ```c
int uniquify(int n, double *list, double tolerance) {
  int i;
  int pos;
  double val;
  assert(!(tolerance < 0.0));
  if (n < 1)
    return 0;
  pos = 0;
  val = list[pos++];
  for (i = 1; i < n; ++i) {
    if (val + tolerance < list[i]) {
      val = list[i];
      list[pos++] = val;
    }
  }
  list[pos - 1] = list[n - 1];
  return pos;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uniquify>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  movslq %edi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  comisd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %r8d,%r8d
  test   %ebp,%ebp
  jle    L13
  movsd  (%rbx),%xmm3
  cmp    $0x1,%ebp
  je     L1
  lea    -0x2(%rbp),%edx
  movsd  0x8(%rsp),%xmm0
  lea    0x8(%rbx),%rax
  mov    $0x1,%r8d
  lea    0x10(%rbx,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L3:
  movapd %xmm0,%xmm2
  movsd  (%rax),%xmm1
  addsd  %xmm3,%xmm2
  comisd %xmm2,%xmm1
  jbe    L4
  movslq %r8d,%rcx
  movapd %xmm1,%xmm3
  add    $0x1,%r8d
  movsd  %xmm1,(%rbx,%rcx,8)
L4:
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L3
  movslq %r8d,%rax
  lea    -0x8(%rbx,%rax,8),%rax
L9:
  movsd  -0x8(%rbx,%rbp,8),%xmm0
  movsd  %xmm0,(%rax)
L13:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L1:
  mov    %rbx,%rax
  mov    $0x1,%r8d
  jmp    L9
```

assistant: ```c
int uniquify(int n, double *list, double tolerance) {
  int i;
  int pos;
  double val;
  assert(!(tolerance < 0.0));
  if (n < 1)
    return 0;
  pos = 0;
  val = list[pos++];
  for (i = 1; i < n; ++i) {
    if (val + tolerance < list[i]) {
      val = list[i];
      list[pos++] = val;
    }
  }
  list[pos - 1] = list[n - 1];
  return pos;
}
```