ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x98(%rbp)
  cmpq   $0x0,-0x98(%rbp)
  jne    L26
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L6
L26:
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type: string
name: disassemble_data
arguments: data_tag: D31
type: string
name: disassemble_data
arguments: data_tag: D9
type: string
name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D28
type: string

tool: D23: wr

tool: D31: pwd

tool: D9: open cmd err!


tool: D13: buf = %s


tool: D28: hehe ...

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp = NULL;
  char buf[128] = {0};
  fp = popen("pwd", "wr");
  if (!fp) {
    perror("open cmd err!\n");
    return 1;
  }
  fgets(buf, 128, fp);
  printf("buf = %s\n", buf);
  pclose(fp);
  printf("hehe ...\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  lea    D49(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <popen@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbx
  mov    %rsp,%rbp
  mov    %rax,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <pclose@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L25:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  lea    D40(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L25
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D49
type: string
name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D21
type: string
name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D40
type: string

tool: D49: wr

tool: D13: pwd

tool: D21: buf = %s


tool: D7: hehe ...

tool: D40: open cmd err!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp = NULL;
  char buf[128] = {0};
  fp = popen("pwd", "wr");
  if (!fp) {
    perror("open cmd err!\n");
    return 1;
  }
  fgets(buf, 128, fp);
  printf("buf = %s\n", buf);
  pclose(fp);
  printf("hehe ...\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D48(%rip),%rsi
  lea    D13(%rip),%rdi
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <popen@plt>
  test   %rax,%rax
  je     L23
  mov    %rsp,%r12
  mov    %rax,%rdx
  mov    $0x80,%esi
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %r12,%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pclose@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
L1:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x98,%rsp
  pop    %rbp
  pop    %r12
  ret
L23:
  lea    D23(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L1
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D48
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D31
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string

tool: D48: wr

tool: D13: pwd

tool: D31: buf = %s


tool: D10: hehe ...

tool: D23: open cmd err!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp = NULL;
  char buf[128] = {0};
  fp = popen("pwd", "wr");
  if (!fp) {
    perror("open cmd err!\n");
    return 1;
  }
  fgets(buf, 128, fp);
  printf("buf = %s\n", buf);
  pclose(fp);
  printf("hehe ...\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rsi
  lea    D8(%rip),%rdi
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <popen@plt>
  test   %rax,%rax
  je     L19
  mov    %rsp,%r12
  mov    %rax,%rdx
  mov    $0x80,%esi
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %r12,%rsi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pclose@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
L5:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x98,%rsp
  pop    %rbp
  pop    %r12
  ret
L19:
  lea    D45(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L5
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D8
datatype: string
name: disassemble_data
arguments: data_tag: D41
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D45
datatype: string

tool: D16: wr

tool: D8: pwd

tool: D41: buf = %s


tool: D26: hehe ...

tool: D45: open cmd err!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp = NULL;
  char buf[128] = {0};
  fp = popen("pwd", "wr");
  if (!fp) {
    perror("open cmd err!\n");
    return 1;
  }
  fgets(buf, 128, fp);
  printf("buf = %s\n", buf);
  pclose(fp);
  printf("hehe ...\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kr_net_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L86
L71:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L75
  mov    -0x8(%rbp),%eax
  jmp    L47
L75:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L64
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L86
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D20(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L31
  jmp    L86
L31:
  mov    $0xffffffff,%eax
  jmp    L47
L64:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L86:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L71
  mov    -0x8(%rbp),%eax
L47:
  leave
  ret
```

assistant: ```c
int kr_net_write(int fd, char *buf, int count) {
  int nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1) {
      if (errno == EAGAIN || errno == EINTR)
        continue;
      return -1;
    }
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kr_net_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r12d
  test   %edx,%edx
  je     L34
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  jmp    L26
L77:
  add    %eax,%ebx
  cltq
  add    %rax,%rbp
L53:
  cmp    %ebx,%r12d
  je     L4
L26:
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %eax,%eax
  je     L4
  cmp    $0xffffffff,%eax
  jne    L77
  mov    D19(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D23(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L53
  mov    D22(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L53
  mov    %eax,%ebx
L4:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    %edx,%ebx
  jmp    L4
```

assistant: ```c
int kr_net_write(int fd, char *buf, int count) {
  int nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1) {
      if (errno == EAGAIN || errno == EINTR)
        continue;
      return -1;
    }
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kr_net_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L72
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%ebx
  xor    %r12d,%r12d
  jmp    L73
  xchg   %ax,%ax
L9:
  add    %eax,%r12d
  cltq
  add    %rax,%r13
L17:
  cmp    %r12d,%ebx
  je     L51
L73:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  call   <write@plt>
  test   %eax,%eax
  je     L51
  cmp    $0xffffffff,%eax
  jne    L9
  mov    D28(%rip),%rax
  mov    D11(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L17
  mov    D17(%rip),%rdx
  cmp    (%rdx),%rax
  je     L17
  mov    $0xffffffff,%r12d
L51:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  xor    %r12d,%r12d
  jmp    L51
```

assistant: ```c
int kr_net_write(int fd, char *buf, int count) {
  int nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1) {
      if (errno == EAGAIN || errno == EINTR)
        continue;
      return -1;
    }
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kr_net_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L4
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%ebx
  xor    %r12d,%r12d
  jmp    L17
  xchg   %ax,%ax
L13:
  add    %eax,%r12d
  cltq
  add    %rax,%r13
L62:
  cmp    %r12d,%ebx
  je     L47
L17:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  call   <write@plt>
  test   %eax,%eax
  je     L47
  cmp    $0xffffffff,%eax
  jne    L13
  mov    D3(%rip),%rax
  mov    D17(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L62
  mov    D23(%rip),%rdx
  cmp    (%rdx),%rax
  je     L62
  mov    $0xffffffff,%r12d
L47:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  xor    %r12d,%r12d
  jmp    L47
```

assistant: ```c
int kr_net_write(int fd, char *buf, int count) {
  int nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1) {
      if (errno == EAGAIN || errno == EINTR)
        continue;
      return -1;
    }
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: What is the c source code of the assembly code below?

```asm
<show_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %x 

assistant: ```c
void show_bytes(char *p, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%x ", p[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_bytes>:
  endbr64
  test   %esi,%esi
  jle    L8
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D1(%rip),%rbp
L9:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: %x 

assistant: ```c
void show_bytes(char *p, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%x ", p[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<show_bytes>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L6:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: %x 

assistant: ```c
void show_bytes(char *p, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%x ", p[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_bytes>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L5:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: %x 

assistant: ```c
void show_bytes(char *p, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%x ", p[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tor_main@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L24
  cmpl   $0xff,-0x4(%rbp)
  jle    L20
L24:
  mov    $0x1,%eax
  jmp    L19
L20:
  mov    -0x4(%rbp),%eax
L19:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  r = tor_main(argc, argv);
  if (r < 0 || r > 255)
    return 1;
  else
    return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <tor_main@plt>
  cmp    $0x100,%eax
  mov    $0x1,%edx
  cmovae %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  r = tor_main(argc, argv);
  if (r < 0 || r > 255)
    return 1;
  else
    return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <tor_main@plt>
  mov    $0x1,%edx
  cmp    $0x100,%eax
  cmovae %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  r = tor_main(argc, argv);
  if (r < 0 || r > 255)
    return 1;
  else
    return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <tor_main@plt>
  mov    $0x1,%edx
  cmp    $0x100,%eax
  cmovae %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  r = tor_main(argc, argv);
  if (r < 0 || r > 255)
    return 1;
  else
    return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L25
  addl   $0x1,-0xc(%rbp)
  jmp    L9
L25:
  addl   $0x1,-0x8(%rbp)
L9:
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L21
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c, x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  c = 0;
  while (x < y) {
    if (x < z) {
      x = x + 1;
    } else {
      z = z + 1;
    }
    c = c + 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    %ebp,%ebx
  jl     L24
L27:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  add    $0x1,%eax
L26:
  cmp    %ebp,%ebx
  jge    L27
L24:
  cmp    %eax,%ebx
  jge    L36
  add    $0x1,%ebx
  jmp    L26
```

assistant: ```c
int main() {
  int c, x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  c = 0;
  while (x < y) {
    if (x < z) {
      x = x + 1;
    } else {
      z = z + 1;
    }
    c = c + 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c, x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  c = 0;
  while (x < y) {
    if (x < z) {
      x = x + 1;
    } else {
      z = z + 1;
    }
    c = c + 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c, x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  c = 0;
  while (x < y) {
    if (x < z) {
      x = x + 1;
    } else {
      z = z + 1;
    }
    c = c + 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_current_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
long get_current_time() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000 + (ts.tv_nsec / 1000000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  cltq
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_current_time() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000 + (ts.tv_nsec / 1000000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x32,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  cltq
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_current_time() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000 + (ts.tv_nsec / 1000000);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x32,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_current_time() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000 + (ts.tv_nsec / 1000000);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pmu_adc_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x17efff,%edx
  mov    $0x3b,%esi
  mov    $0x6,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  call   <delay@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pmu_adc_enable() {
  mbus_remote_register_write(0x6, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (1 << 11) | (0 << 12) | (1 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (0 << 19) | (1 << 20)));
  delay(100);
}
```