ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  push   %rbx
  lea    D39(%rip),%rbx
  sub    $0x38,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movb   $0x0,0x1a(%rsp)
  movabs $0x6e6972747320656c,%rax
  mov    %rax,0x10(%rsp)
  mov    %rbp,%rsi
  mov    $0x2e67,%eax
  mov    %ax,0x18(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strtok1@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rsi
  lea    D9(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok1@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L4
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D39
data_type: string
name: extract_symbolic_data
arguments: data_label: D18
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D12: Splitting string "%s" into tokens:


tool: D39:  ,.-

tool: {"D18": [0x2d,0x20,0x54,0x68,0x69,0x73,0x2c,0x2e,0x2e,0x20,0x61,0x20,0x73,0x61,0x6d,0x70]}

tool: D9: %s


assistant: ```c
int main() {
  char str[] = "- This,.. a sample string.";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok1(str, " ,.-");
  while (pch != NULL) {
    printf("%s\n", pch);
    pch = strtok1(NULL, " ,.-");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  push   %rbx
  lea    D20(%rip),%rbx
  sub    $0x38,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movb   $0x0,0x1a(%rsp)
  movabs $0x6e6972747320656c,%rax
  mov    %rax,0x10(%rsp)
  mov    %rbp,%rsi
  mov    $0x2e67,%eax
  mov    %ax,0x18(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strtok1@plt>
  test   %rax,%rax
  je     L24
  mov    %rax,%rsi
  lea    D22(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok1@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L18
L24:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D11
type_guessed: byte[16]
name: retrieve_data
arguments: label: D22
type_guessed: string

tool: D24: Splitting string "%s" into tokens:


tool: D20:  ,.-

tool: {"D11": [0x2d,0x20,0x54,0x68,0x69,0x73,0x2c,0x2e,0x2e,0x20,0x61,0x20,0x73,0x61,0x6d,0x70]}

tool: D22: %s


assistant: ```c
int main() {
  char str[] = "- This,.. a sample string.";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok1(str, " ,.-");
  while (pch != NULL) {
    printf("%s\n", pch);
    pch = strtok1(NULL, " ,.-");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_be_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  shr    $0x18,%rax
  mov    %al,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  mov    %al,-0xb(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  mov    %al,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %al,-0x9(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int write_be_long(unsigned long val, FILE *fp) {
  unsigned char c[4];
  c[0] = (val >> 24) & 0xFFL;
  c[1] = (val >> 16) & 0xFFL;
  c[2] = (val >> 8) & 0xFFL;
  c[3] = val & 0xFFL;
  return fwrite(c, 1, 4, fp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_be_long>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %rdi,%rdx
  shr    $0x18,%rdx
  mov    %dl,0x4(%rsp)
  mov    %rdi,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x5(%rsp)
  movzbl %ah,%edx
  mov    %dl,0x6(%rsp)
  mov    %dil,0x7(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_be_long(unsigned long val, FILE *fp) {
  unsigned char c[4];
  c[0] = (val >> 24) & 0xFFL;
  c[1] = (val >> 16) & 0xFFL;
  c[2] = (val >> 8) & 0xFFL;
  c[3] = val & 0xFFL;
  return fwrite(c, 1, 4, fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_be_long>:
  endbr64
  sub    $0x18,%rsp
  bswap  %edi
  mov    %rsi,%rcx
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_be_long(unsigned long val, FILE *fp) {
  unsigned char c[4];
  c[0] = (val >> 24) & 0xFFL;
  c[1] = (val >> 16) & 0xFFL;
  c[2] = (val >> 8) & 0xFFL;
  c[3] = val & 0xFFL;
  return fwrite(c, 1, 4, fp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_be_long>:
  endbr64
  sub    $0x18,%rsp
  bswap  %edi
  mov    %rsi,%rcx
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_be_long(unsigned long val, FILE *fp) {
  unsigned char c[4];
  c[0] = (val >> 24) & 0xFFL;
  c[1] = (val >> 16) & 0xFFL;
  c[2] = (val >> 8) & 0xFFL;
  c[3] = val & 0xFFL;
  return fwrite(c, 1, 4, fp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GZ_Close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <inflateEnd@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void GZ_Close(z_streamp zsp) {
  inflateEnd(zsp);
  free(zsp);
}
```
user: What is the c source code of the assembly code below:

```asm
<GZ_Close>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <inflateEnd@plt>
  mov    %ebx,%edi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void GZ_Close(z_streamp zsp) {
  inflateEnd(zsp);
  free(zsp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GZ_Close>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <inflateEnd@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void GZ_Close(z_streamp zsp) {
  inflateEnd(zsp);
  free(zsp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GZ_Close>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <inflateEnd@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void GZ_Close(z_streamp zsp) {
  inflateEnd(zsp);
  free(zsp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ottery_st_prevent_backtracking>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ottery_st_prevent_backtracking_nolock@plt>
  nop
  leave
  ret
```

assistant: ```c
void ottery_st_prevent_backtracking(struct ottery_state *st) {
  ((void)0);
  ottery_st_prevent_backtracking_nolock(st);
  ((void)0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ottery_st_prevent_backtracking>:
  endbr64
  sub    $0x8,%rsp
  call   <ottery_st_prevent_backtracking_nolock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ottery_st_prevent_backtracking(struct ottery_state *st) {
  ((void)0);
  ottery_st_prevent_backtracking_nolock(st);
  ((void)0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ottery_st_prevent_backtracking>:
  endbr64
  jmp    1050 <ottery_st_prevent_backtracking_nolock@plt>
```

assistant: ```c
void ottery_st_prevent_backtracking(struct ottery_state *st) {
  ((void)0);
  ottery_st_prevent_backtracking_nolock(st);
  ((void)0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ottery_st_prevent_backtracking>:
  endbr64
  jmp    1050 <ottery_st_prevent_backtracking_nolock@plt>
```

assistant: ```c
void ottery_st_prevent_backtracking(struct ottery_state *st) {
  ((void)0);
  ottery_st_prevent_backtracking_nolock(st);
  ((void)0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <setup_IO@plt>
  mov    $0x0,%eax
  call   <setup_TIM1@plt>
  mov    $0x0,%eax
  call   <setup_TIM8@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setup() {
  setup_IO();
  setup_TIM1();
  setup_TIM8();
}
```
user: What is the c source code of the assembly code below?

```asm
<setup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup_IO@plt>
  mov    $0x0,%eax
  call   <setup_TIM1@plt>
  mov    $0x0,%eax
  call   <setup_TIM8@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void setup() {
  setup_IO();
  setup_TIM1();
  setup_TIM8();
}
```
user: Translate the below assembly code into C programming language:

```asm
<setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_IO@plt>
  xor    %eax,%eax
  call   <setup_TIM1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <setup_TIM8@plt>
```

assistant: ```c
void setup() {
  setup_IO();
  setup_TIM1();
  setup_TIM8();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_IO@plt>
  xor    %eax,%eax
  call   <setup_TIM1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <setup_TIM8@plt>
```

assistant: ```c
void setup() {
  setup_IO();
  setup_TIM1();
  setup_TIM8();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<appendCRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L1:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CRC16@plt>
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L1
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  and    $0xff00,%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void appendCRC(unsigned char *buf, unsigned int len) {
  unsigned int Crc, i;
  Crc = 0xFFFF;
  for (i = 0; i < len - 2; i++) {
    Crc = CRC16(Crc, buf[i]);
  }
  buf[len - 2] = (Crc & 0x00FF);
  buf[len - 1] = (Crc & 0xFF00) / 256;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<appendCRC>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %esi,%r14d
  sub    $0x2,%r14d
  je     L16
  mov    %rdi,%rbx
  lea    -0x3(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
  mov    $0xffff,%edi
L24:
  movzbl (%rbx),%esi
  call   <CRC16@plt>
  mov    %eax,%edi
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L24
L17:
  mov    %r14d,%r14d
  mov    %dil,0x0(%r13,%r14,1)
  lea    -0x1(%r12),%eax
  mov    %edi,%ecx
  movzbl %ch,%edx
  mov    %dl,0x0(%r13,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    $0xffff,%edi
  jmp    L17
```

assistant: ```c
void appendCRC(unsigned char *buf, unsigned int len) {
  unsigned int Crc, i;
  Crc = 0xFFFF;
  for (i = 0; i < len - 2; i++) {
    Crc = CRC16(Crc, buf[i]);
  }
  buf[len - 2] = (Crc & 0x00FF);
  buf[len - 1] = (Crc & 0xFF00) / 256;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<appendCRC>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x2,%r13d
  je     L8
  lea    -0x3(%rsi),%eax
  mov    %rdi,%r14
  lea    0x1(%rdi,%rax,1),%rbx
  mov    $0xffff,%edi
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%r14),%esi
  add    $0x1,%r14
  call   <CRC16@plt>
  mov    %eax,%edi
  cmp    %rbx,%r14
  jne    L14
  mov    %r13d,%r13d
  movzbl %ah,%edi
  add    %r12,%r13
L25:
  mov    %al,0x0(%r13)
  lea    -0x1(%rbp),%eax
  pop    %rbx
  mov    %dil,(%r12,%rax,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%r13
  mov    $0xffffffff,%eax
  mov    $0xffffffff,%edi
  jmp    L25
```

assistant: ```c
void appendCRC(unsigned char *buf, unsigned int len) {
  unsigned int Crc, i;
  Crc = 0xFFFF;
  for (i = 0; i < len - 2; i++) {
    Crc = CRC16(Crc, buf[i]);
  }
  buf[len - 2] = (Crc & 0x00FF);
  buf[len - 1] = (Crc & 0xFF00) / 256;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<appendCRC>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x2,%r13d
  je     L23
  lea    -0x3(%rsi),%eax
  mov    %rdi,%r14
  lea    0x1(%rdi,%rax,1),%rbx
  mov    $0xffff,%edi
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%r14),%esi
  add    $0x1,%r14
  call   <CRC16@plt>
  mov    %eax,%edi
  cmp    %r14,%rbx
  jne    L17
  mov    %r13d,%r13d
  movzbl %ah,%edi
  add    %r12,%r13
L13:
  mov    %al,0x0(%r13)
  lea    -0x1(%rbp),%eax
  pop    %rbx
  mov    %dil,(%r12,%rax,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L23:
  mov    %rdi,%r13
  mov    $0xffffffff,%eax
  mov    $0xffffffff,%edi
  jmp    L13
```

assistant: ```c
void appendCRC(unsigned char *buf, unsigned int len) {
  unsigned int Crc, i;
  Crc = 0xFFFF;
  for (i = 0; i < len - 2; i++) {
    Crc = CRC16(Crc, buf[i]);
  }
  buf[len - 2] = (Crc & 0x00FF);
  buf[len - 1] = (Crc & 0xFF00) / 256;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L8
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L29
L8:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D47
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D41
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D46
type_infered: string

tool: D47: Girdiginiz sayilardan birinci ikincinin katimidir bulalim

tool: D10: Birinci sayiyi giriniz:

tool: D41: %d

tool: D19: Ikinci sayiyi giriniz:

tool: D31: %d sayisi %d sayinin tam katidir.

tool: D46: %d sayisi %d sayisinin tam kati degildir.

assistant: ```c
int main() {
  int sayi1, sayi2, mod;
  printf("Girdiginiz sayilardan birinci ikincinin katimidir bulalim\n");
  printf("Birinci sayiyi giriniz:");
  scanf("%d", &sayi1);
  printf("Ikinci sayiyi giriniz:");
  scanf("%d", &sayi2);
  mod = sayi1 % sayi2;
  if (mod == 0) {
    printf("%d sayisi %d sayinin tam katidir.", sayi1, sayi2);
  } else {
    printf("%d sayisi %d sayisinin tam kati degildir.", sayi1, sayi2);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D35(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L28
  mov    %ecx,%edx
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  mov    %ecx,%edx
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D52
type_infered: string
name: parse_data
arguments: tag: D44
type_infered: string
name: parse_data
arguments: tag: D35
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D39
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D52: Girdiginiz sayilardan birinci ikincinin katimidir bulalim

tool: D44: Birinci sayiyi giriniz:

tool: D35: %d

tool: D25: Ikinci sayiyi giriniz:

tool: D39: %d sayisi %d sayinin tam katidir.

tool: D18: %d sayisi %d sayisinin tam kati degildir.

assistant: ```c
int main() {
  int sayi1, sayi2, mod;
  printf("Girdiginiz sayilardan birinci ikincinin katimidir bulalim\n");
  printf("Birinci sayiyi giriniz:");
  scanf("%d", &sayi1);
  printf("Ikinci sayiyi giriniz:");
  scanf("%d", &sayi2);
  mod = sayi1 % sayi2;
  if (mod == 0) {
    printf("%d sayisi %d sayinin tam katidir.", sayi1, sayi2);
  } else {
    printf("%d sayisi %d sayisinin tam kati degildir.", sayi1, sayi2);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  mov    %r8d,%edx
  jne    L5
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L17
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D45
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D46
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D44
type: string

tool: D45: Girdiginiz sayilardan birinci ikincinin katimidir bulalim

tool: D10: %d

tool: D4: Birinci sayiyi giriniz:

tool: D46: Ikinci sayiyi giriniz:

tool: D2: %d sayisi %d sayinin tam katidir.

tool: D44: %d sayisi %d sayisinin tam kati degildir.

assistant: ```c
int main() {
  int sayi1, sayi2, mod;
  printf("Girdiginiz sayilardan birinci ikincinin katimidir bulalim\n");
  printf("Birinci sayiyi giriniz:");
  scanf("%d", &sayi1);
  printf("Ikinci sayiyi giriniz:");
  scanf("%d", &sayi2);
  mod = sayi1 % sayi2;
  if (mod == 0) {
    printf("%d sayisi %d sayinin tam katidir.", sayi1, sayi2);
  } else {
    printf("%d sayisi %d sayisinin tam kati degildir.", sayi1, sayi2);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D40(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  mov    %r8d,%edx
  jne    L12
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L12:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D40
datatype: string
name: parse_data
arguments: data_label: D27
datatype: string
name: parse_data
arguments: data_label: D45
datatype: string
name: parse_data
arguments: data_label: D48
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string

tool: D28: Girdiginiz sayilardan birinci ikincinin katimidir bulalim

tool: D40: %d

tool: D27: Birinci sayiyi giriniz:

tool: D45: Ikinci sayiyi giriniz:

tool: D48: %d sayisi %d sayinin tam katidir.

tool: D0: %d sayisi %d sayisinin tam kati degildir.

assistant: ```c
int main() {
  int sayi1, sayi2, mod;
  printf("Girdiginiz sayilardan birinci ikincinin katimidir bulalim\n");
  printf("Birinci sayiyi giriniz:");
  scanf("%d", &sayi1);
  printf("Ikinci sayiyi giriniz:");
  scanf("%d", &sayi2);
  mod = sayi1 % sayi2;
  if (mod == 0) {
    printf("%d sayisi %d sayinin tam katidir.", sayi1, sayi2);
  } else {
    printf("%d sayisi %d sayisinin tam kati degildir.", sayi1, sayi2);
  }
  return 0;
}
```