ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_sfix7>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mov    %rsp,%rcx
  test   %edi,%edi
  js     L11
L42:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  cmp    %edx,%eax
  jne    L27
  mov    $0x7,%edi
L43:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  mov    %edi,%r8d
  sub    $0x1,%edi
  movslq %edx,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %edx,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%esi
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  cmp    %esi,%edx
  jne    L9
  test   %edi,%edi
  jg     L43
L9:
  sub    $0x2,%r8d
  js     L35
L54:
  mov    %rcx,%rsi
L64:
  add    $0x1,%rsi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rsi)
  mov    %edx,%eax
  mov    %ecx,%edx
  sub    %esi,%edx
  add    %r8d,%edx
  jns    L64
  test   %r8d,%r8d
  mov    $0x0,%edx
  cmovs  %edx,%r8d
  lea    0x1(%r8),%edx
  add    %rcx,%rdx
L78:
  lea    0x1(%rdx),%rdi
  movb   $0x2e,(%rdx)
L3:
  mov    %rdi,%rsi
  add    $0x1,%rdi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  mov    %eax,%r8d
  sub    %r9d,%r8d
  add    $0x30,%r8d
  mov    %r8b,-0x1(%rdi)
  mov    %eax,%r8d
  mov    %edx,%eax
  cmp    $0x9,%r8d
  jg     L3
  movb   $0x0,(%rdi)
  cmp    %rsi,%rcx
  jae    L23
L70:
  movzbl (%rcx),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rcx)
  mov    %al,(%rsi)
  add    $0x1,%rcx
  sub    $0x1,%rsi
  cmp    %rsi,%rcx
  jb     L70
L23:
  mov    %rsp,%rdi
  call   <write_str@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  ret
L11:
  movb   $0x2d,(%rsp)
  neg    %eax
  lea    0x1(%rsp),%rcx
  jmp    L42
L27:
  mov    $0x6,%r8d
  jmp    L54
L35:
  mov    %rcx,%rdx
  jmp    L78
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_sfix7(int32_t v) {
  char s[20], *s1, *s2, c;
  int i;
  s1 = s;
  if (v < 0) {
    *s1++ = '-';
    v = -v;
  }
  s2 = s1;
  i = 7;
  while ((v % 10) == 0 && i > 0) {
    v /= 10;
    i--;
  }
  while (--i >= 0) {
    *s2++ = (v % 10) + '0';
    v /= 10;
  }
  *s2++ = '.';
  do {
    *s2++ = (v % 10) + '0';
    v /= 10;
  } while (v > 0);
  *s2-- = 0;
  while (s2 > s1) {
    c = *s1;
    *s1 = *s2;
    *s2 = c;
    s1++;
    s2--;
  }
  write_str(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_sfix7>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mov    %rsp,%r10
  mov    %r10,%rdi
  test   %eax,%eax
  jns    L28
  movb   $0x2d,(%rsp)
  neg    %eax
  lea    0x1(%rsp),%rdi
L28:
  imul   $0xcccccccd,%eax,%edx
  ror    %edx
  cmp    $0x19999999,%edx
  ja     L37
  mov    $0x7,%edx
  mov    $0xcccccccd,%esi
  nopl   (%rax)
L43:
  mov    %eax,%eax
  mov    %edx,%r8d
  sub    $0x1,%edx
  imul   %rsi,%rax
  shr    $0x23,%rax
  imul   $0xcccccccd,%eax,%ecx
  ror    %ecx
  cmp    $0x19999999,%ecx
  ja     L78
  test   %edx,%edx
  jne    L43
L94:
  mov    %rdi,%r8
L76:
  movb   $0x2e,(%r8)
  lea    0x1(%r8),%r9
  mov    $0xcccccccd,%r11d
  nopl   0x0(%rax)
L92:
  mov    %eax,%edx
  mov    %eax,%esi
  mov    %r9,%rcx
  imul   %r11,%rdx
  lea    0x1(%r9),%r9
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%esi
  mov    %eax,%r8d
  mov    %edx,%eax
  add    $0x30,%esi
  mov    %sil,-0x1(%r9)
  cmp    $0x9,%r8d
  jg     L92
  movb   $0x0,(%r9)
  cmp    %rcx,%rdi
  jb     L88
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L64:
  movzbl (%rcx),%esi
L88:
  movzbl (%rdi),%eax
  sub    $0x1,%rcx
  mov    %sil,(%rdi)
  add    $0x1,%rdi
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rdi
  jb     L64
L72:
  mov    %r10,%rdi
  call   <write_str@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L78:
  lea    -0x2(%r8),%edx
  cmp    $0x1,%r8d
  je     L94
L68:
  lea    0x1(%rdx),%r8d
  mov    %rdi,%rcx
  mov    $0xcccccccd,%r9d
  movslq %r8d,%r8
  add    %rdi,%r8
  nopl   0x0(%rax)
L16:
  mov    %eax,%edx
  add    $0x1,%rcx
  imul   %r9,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rcx)
  mov    %edx,%eax
  cmp    %r8,%rcx
  jne    L16
  jmp    L76
L37:
  mov    $0x6,%edx
  jmp    L68
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_sfix7(int32_t v) {
  char s[20], *s1, *s2, c;
  int i;
  s1 = s;
  if (v < 0) {
    *s1++ = '-';
    v = -v;
  }
  s2 = s1;
  i = 7;
  while ((v % 10) == 0 && i > 0) {
    v /= 10;
    i--;
  }
  while (--i >= 0) {
    *s2++ = (v % 10) + '0';
    v /= 10;
  }
  *s2++ = '.';
  do {
    *s2++ = (v % 10) + '0';
    v /= 10;
  } while (v > 0);
  *s2-- = 0;
  while (s2 > s1) {
    c = *s1;
    *s1 = *s2;
    *s2 = c;
    s1++;
    s2--;
  }
  write_str(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ballpole>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L7
L32:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movss  (%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L17
L20:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jg     L20
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x30(%rbp),%rdx
  mov    (%rdx),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x50(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x50(%rbp)
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  cqto
  idivq  -0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,0x10(%rbp)
  jg     L32
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *ballpole(float *x, long *jcount, long npoles, float *past, float *c, float *out, long nvals) {
  int i, nfint;
  long j;
  float *retval = out;
  float temp;
  for (i = 0; i < nvals; ++i) {
    temp = *x++;
    for (j = *jcount, nfint = 0; nfint < npoles; nfint++, j++)
      temp += (*(c + nfint) * *(past + j));
    *out++ = *(past + *jcount) = *(past + *jcount + npoles) = temp;
    *jcount = (*jcount + 1) % npoles;
  }
  return (retval);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ballpole>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  test   %r12,%r12
  jle    L0
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r10
  shl    $0x2,%r12
  mov    $0x0,%r11d
L36:
  movss  (%rbx,%r11,1),%xmm1
  mov    0x0(%rbp),%rdi
  test   %r10,%r10
  jle    L29
  lea    (%r10,%rdi,1),%rsi
  mov    %rdi,%rax
  neg    %rax
  lea    (%r8,%rax,4),%rdx
  mov    %rdi,%rax
L23:
  movss  (%rdx,%rax,4),%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L23
L29:
  add    %r10,%rdi
  movss  %xmm1,(%rcx,%rdi,4)
  mov    0x0(%rbp),%rax
  movss  %xmm1,(%rcx,%rax,4)
  movss  %xmm1,(%r9,%r11,1)
  mov    0x0(%rbp),%rax
  add    $0x1,%rax
  cqto
  idiv   %r10
  mov    %rdx,0x0(%rbp)
  add    $0x4,%r11
  cmp    %r11,%r12
  jne    L36
L0:
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float *ballpole(float *x, long *jcount, long npoles, float *past, float *c, float *out, long nvals) {
  int i, nfint;
  long j;
  float *retval = out;
  float temp;
  for (i = 0; i < nvals; ++i) {
    temp = *x++;
    for (j = *jcount, nfint = 0; nfint < npoles; nfint++, j++)
      temp += (*(c + nfint) * *(past + j));
    *out++ = *(past + *jcount) = *(past + *jcount + npoles) = temp;
    *jcount = (*jcount + 1) % npoles;
  }
  return (retval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ballpole>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x28(%rsp),%r13
  test   %r13,%r13
  jle    L2
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdi,%rbp
  mov    %rcx,%rsi
  mov    (%r12),%rdx
  shl    $0x2,%r13
  xor    %r11d,%r11d
  nopl   0x0(%rax,%rax,1)
L5:
  movss  0x0(%rbp,%r11,1),%xmm1
  lea    (%rdx,%rbx,1),%rdi
  test   %rbx,%rbx
  jle    L11
  mov    %rdx,%rax
  mov    %rdx,%rcx
  neg    %rax
  lea    (%r8,%rax,4),%r10
  nopl   (%rax)
L7:
  movss  (%r10,%rcx,4),%xmm0
  mulss  (%rsi,%rcx,4),%xmm0
  add    $0x1,%rcx
  addss  %xmm0,%xmm1
  cmp    %rdi,%rcx
  jne    L7
L11:
  lea    0x1(%rdx),%rax
  movss  %xmm1,(%rsi,%rdi,4)
  movss  %xmm1,(%rsi,%rdx,4)
  cqto
  idiv   %rbx
  movss  %xmm1,(%r9,%r11,1)
  add    $0x4,%r11
  mov    %rdx,(%r12)
  cmp    %r11,%r13
  jne    L5
L2:
  pop    %rbx
  mov    %r9,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float *ballpole(float *x, long *jcount, long npoles, float *past, float *c, float *out, long nvals) {
  int i, nfint;
  long j;
  float *retval = out;
  float temp;
  for (i = 0; i < nvals; ++i) {
    temp = *x++;
    for (j = *jcount, nfint = 0; nfint < npoles; nfint++, j++)
      temp += (*(c + nfint) * *(past + j));
    *out++ = *(past + *jcount) = *(past + *jcount + npoles) = temp;
    *jcount = (*jcount + 1) % npoles;
  }
  return (retval);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ballpole>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%rax
  test   %rax,%rax
  jle    L54
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  shl    $0x2,%rax
  mov    %rcx,%r10
  mov    %rsi,%r12
  mov    %rax,-0x20(%rsp)
  lea    -0x1(%rsi),%rax
  mov    %rsi,%rcx
  and    $0xfffffffffffffffc,%r12
  mov    %rax,-0x18(%rsp)
  shr    $0x2,%rcx
  mov    %rdi,%rbx
  mov    %r12d,-0xc(%rsp)
  mov    0x0(%rbp),%rdx
  shl    $0x4,%rcx
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L1:
  movss  (%rbx,%rdi,1),%xmm1
  test   %rsi,%rsi
  jle    L3
  cmpq   $0x2,-0x18(%rsp)
  jbe    L22
  lea    (%r10,%rdx,4),%r9
  xor    %eax,%eax
L30:
  movups (%r9,%rax,1),%xmm0
  movups (%r8,%rax,1),%xmm3
  add    $0x10,%rax
  mulps  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  movaps %xmm0,%xmm2
  shufps $0x55,%xmm0,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm0,%xmm1
  unpckhps %xmm0,%xmm1
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm1,%xmm2
  movaps %xmm0,%xmm1
  addss  %xmm2,%xmm1
  cmp    %rax,%rcx
  jne    L30
  lea    (%r12,%rdx,1),%r9
  cmp    %rsi,%r12
  je     L3
  mov    -0xc(%rsp),%eax
L76:
  movslq %eax,%r11
  lea    0x0(,%r9,4),%r15
  movss  (%r8,%r11,4),%xmm0
  mulss  (%r10,%r9,4),%xmm0
  lea    0x1(%rax),%r9d
  lea    0x0(,%r11,4),%r14
  movslq %r9d,%r9
  addss  %xmm0,%xmm1
  cmp    %r9,%rsi
  jle    L3
  movss  0x4(%r8,%r14,1),%xmm0
  mulss  0x4(%r10,%r15,1),%xmm0
  add    $0x2,%eax
  cltq
  addss  %xmm0,%xmm1
  cmp    %rax,%rsi
  jle    L3
  movss  0x8(%r10,%r15,1),%xmm0
  mulss  0x8(%r8,%r14,1),%xmm0
  addss  %xmm0,%xmm1
L3:
  lea    (%rdx,%rsi,1),%rax
  movss  %xmm1,(%r10,%rax,4)
  lea    0x1(%rdx),%rax
  movss  %xmm1,(%r10,%rdx,4)
  cqto
  idiv   %rsi
  movss  %xmm1,0x0(%r13,%rdi,1)
  add    $0x4,%rdi
  mov    %rdx,0x0(%rbp)
  cmp    -0x20(%rsp),%rdi
  jne    L1
L54:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    %rdx,%r9
  xor    %eax,%eax
  jmp    L76
```

assistant: ```c
float *ballpole(float *x, long *jcount, long npoles, float *past, float *c, float *out, long nvals) {
  int i, nfint;
  long j;
  float *retval = out;
  float temp;
  for (i = 0; i < nvals; ++i) {
    temp = *x++;
    for (j = *jcount, nfint = 0; nfint < npoles; nfint++, j++)
      temp += (*(c + nfint) * *(past + j));
    *out++ = *(past + *jcount) = *(past + *jcount + npoles) = temp;
    *jcount = (*jcount + 1) % npoles;
  }
  return (retval);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<load64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L7:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x7,-0x8(%rbp)
  jbe    L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t load64(const unsigned char *x) {
  unsigned int i;
  uint64_t r = 0;
  for (i = 0; i < 8; ++i)
    r |= (uint64_t)x[i] << 8 * i;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<load64>:
  endbr64
  mov    $0x0,%eax
  mov    $0x0,%esi
L6:
  movzbl (%rdi,%rax,1),%edx
  lea    0x0(,%rax,8),%ecx
  shl    %cl,%edx
  or     %edx,%esi
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L6
  mov    %esi,%eax
  ret
```

assistant: ```c
uint64_t load64(const unsigned char *x) {
  unsigned int i;
  uint64_t r = 0;
  for (i = 0; i < 8; ++i)
    r |= (uint64_t)x[i] << 8 * i;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<load64>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L8:
  movzbl (%rdi,%rax,1),%edx
  lea    0x0(,%rax,8),%ecx
  add    $0x1,%rax
  shl    %cl,%edx
  or     %edx,%r8d
  cmp    $0x8,%rax
  jne    L8
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t load64(const unsigned char *x) {
  unsigned int i;
  uint64_t r = 0;
  for (i = 0; i < 8; ++i)
    r |= (uint64_t)x[i] << 8 * i;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load64>:
  endbr64
  movzbl 0x1(%rdi),%edx
  movzbl 0x2(%rdi),%ecx
  mov    %rdi,%rax
  shl    $0x10,%ecx
  shl    $0x8,%edx
  or     %ecx,%edx
  movzbl (%rdi),%ecx
  or     %ecx,%edx
  movzbl 0x3(%rdi),%ecx
  shl    $0x18,%ecx
  mov    %ecx,%esi
  mov    $0x20,%ecx
  or     %edx,%esi
  movzbl 0x4(%rdi),%edx
  movzbl 0x5(%rdi),%edi
  shl    %cl,%edx
  mov    $0x28,%ecx
  shl    %cl,%edi
  or     %esi,%edx
  mov    $0x30,%ecx
  mov    %edi,%esi
  or     %edx,%esi
  movzbl 0x6(%rax),%edx
  movzbl 0x7(%rax),%eax
  shl    %cl,%edx
  mov    $0x38,%ecx
  or     %esi,%edx
  shl    %cl,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint64_t load64(const unsigned char *x) {
  unsigned int i;
  uint64_t r = 0;
  for (i = 0; i < 8; ++i)
    r |= (uint64_t)x[i] << 8 * i;
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse_breaks_idx_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse_breaks_idx_list(int *breaks_idx, int nBreaks, int *reverseBreaks_idx) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks_idx[nBreaks - i - 1] = breaks_idx[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse_breaks_idx_list>:
  endbr64
  sub    $0x1,%esi
  js     L2
  movslq %esi,%rsi
L19:
  mov    (%rdi,%rsi,4),%eax
  mov    %eax,(%rdx)
  sub    $0x1,%rsi
  add    $0x4,%rdx
  test   %esi,%esi
  jns    L19
L2:
  ret
```

assistant: ```c
void reverse_breaks_idx_list(int *breaks_idx, int nBreaks, int *reverseBreaks_idx) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks_idx[nBreaks - i - 1] = breaks_idx[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverse_breaks_idx_list>:
  endbr64
  sub    $0x1,%esi
  js     L10
  movslq %esi,%rsi
  nopl   0x0(%rax)
L18:
  mov    (%rdi,%rsi,4),%eax
  sub    $0x1,%rsi
  add    $0x4,%rdx
  mov    %eax,-0x4(%rdx)
  test   %esi,%esi
  jns    L18
L10:
  ret
```

assistant: ```c
void reverse_breaks_idx_list(int *breaks_idx, int nBreaks, int *reverseBreaks_idx) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks_idx[nBreaks - i - 1] = breaks_idx[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse_breaks_idx_list>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  mov    %esi,%r10d
  mov    %rdx,%r9
  sub    $0x1,%edi
  js     L9
  movslq %esi,%rcx
  mov    %esi,%esi
  shl    $0x2,%rcx
  shl    $0x2,%rsi
  mov    %rcx,%rax
  lea    (%rdx,%rsi,1),%rdx
  sub    %rsi,%rax
  add    %r8,%rax
  cmp    %rax,%rdx
  lea    (%r8,%rcx,1),%rdx
  setbe  %al
  cmp    %rdx,%r9
  setae  %dl
  or     %dl,%al
  je     L10
  cmp    $0x2,%edi
  jbe    L10
  mov    %r10d,%esi
  lea    -0x10(%r8,%rcx,1),%rcx
  mov    %r9,%rdx
  shr    $0x2,%esi
  lea    -0x10(%rcx),%rax
  lea    -0x1(%rsi),%r11d
  mov    %rax,%rsi
  shl    $0x4,%r11
  sub    %r11,%rsi
  jmp    L65
  nopl   (%rax)
L74:
  sub    $0x10,%rax
L65:
  movdqu (%rcx),%xmm0
  add    $0x10,%rdx
  mov    %rax,%rcx
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rsi,%rax
  jne    L74
  mov    %r10d,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  cmp    %eax,%r10d
  je     L9
  movslq %edi,%rax
  mov    (%r8,%rax,4),%ecx
  mov    %r10d,%eax
  sub    %edi,%eax
  cltq
  mov    %ecx,-0x4(%r9,%rax,4)
  lea    -0x1(%rdi),%ecx
  test   %edi,%edi
  je     L9
  movslq %ecx,%rax
  mov    (%r8,%rax,4),%esi
  lea    0x0(,%rax,4),%rdi
  mov    %r10d,%eax
  sub    %ecx,%eax
  cltq
  mov    %esi,-0x4(%r9,%rax,4)
  lea    -0x2(%rdx),%eax
  cmp    $0x1,%edx
  je     L9
  mov    %r10d,%edx
  mov    -0x4(%r8,%rdi,1),%ecx
  sub    %eax,%edx
  movslq %edx,%rdx
  mov    %ecx,-0x4(%r9,%rdx,4)
  ret
  nopl   0x0(%rax)
L10:
  movslq %edi,%rdx
  mov    %r9,%rax
  xchg   %ax,%ax
L58:
  mov    (%r8,%rdx,4),%ecx
  sub    $0x1,%rdx
  add    $0x4,%rax
  mov    %ecx,-0x4(%rax)
  test   %edx,%edx
  jns    L58
L9:
  ret
```

assistant: ```c
void reverse_breaks_idx_list(int *breaks_idx, int nBreaks, int *reverseBreaks_idx) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks_idx[nBreaks - i - 1] = breaks_idx[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_time_unit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x11(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D23(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L25
  cmpl   $0x1,-0xc(%rbp)
  jne    L70
  mov    -0x10(%rbp),%eax
  jmp    L61
L70:
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  sub    $0x48,%eax
  cmp    $0x2b,%eax
  seta   %dl
  test   %dl,%dl
  jne    L101
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x100000001,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L75
  movabs $0x2000000020,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L46
  movabs $0x80000000800,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L101
  mov    -0x10(%rbp),%eax
  jmp    L61
L46:
  mov    -0x10(%rbp),%eax
  imul   $0x3c,%eax,%eax
  jmp    L61
L75:
  mov    -0x10(%rbp),%eax
  imul   $0xe10,%eax,%eax
  jmp    L61
L101:
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <log_error@plt>
  mov    $0x0,%eax
  jmp    L61
L25:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L110
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <log_perror@plt>
L110:
  mov    $0x0,%eax
L61:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D23: %u %c

tool: D16: Invalid time unit specified: %c

tool: D19: nyx: sscanf

assistant: ```c
uint32_t parse_time_unit(const char *input) {
  char unit;
  int32_t matched = 0;
  uint32_t seconds = 0;
  if ((matched = sscanf(input, "%u %c", &seconds, &unit)) >= 1) {
    if (matched == 1)
      return seconds;
    switch (unit) {
    case 's':
    case 'S':
      return seconds;
    case 'm':
    case 'M':
      return seconds * 60;
    case 'h':
    case 'H':
      return seconds * 3600;
    default:
      log_error("Invalid time unit specified: %c", unit);
      return 0;
    }
  } else if (matched == -1) {
    log_perror("nyx: sscanf");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_time_unit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x3(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  test   %eax,%eax
  jle    L48
  mov    0x4(%rsp),%edx
  cmp    $0x1,%eax
  je     L75
  movzbl 0x3(%rsp),%esi
  lea    -0x48(%rsi),%ecx
  cmp    $0x2b,%cl
  ja     L81
  mov    $0x1,%eax
  shl    %cl,%rax
  movabs $0x100000001,%rdx
  test   %rdx,%rax
  jne    L82
  movabs $0x2000000020,%rdx
  test   %rdx,%rax
  jne    L56
  movabs $0x80000000800,%rdx
  test   %rdx,%rax
  jne    L45
L81:
  movsbl %sil,%esi
  lea    D0(%rip),%rdi
  call   <log_error@plt>
  mov    $0x0,%edx
  jmp    L75
L45:
  mov    0x4(%rsp),%edx
  jmp    L75
L56:
  imul   $0x3c,0x4(%rsp),%edx
  jmp    L75
L82:
  imul   $0xe10,0x4(%rsp),%edx
  jmp    L75
L48:
  mov    $0x0,%edx
  cmp    $0xffffffff,%eax
  je     L122
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %edx,%eax
  add    $0x18,%rsp
  ret
L122:
  lea    D13(%rip),%rdi
  call   <log_perror@plt>
  mov    $0x0,%edx
  jmp    L75
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D13
type: string

tool: D3: %u %c

tool: D0: Invalid time unit specified: %c

tool: D13: nyx: sscanf

assistant: ```c
uint32_t parse_time_unit(const char *input) {
  char unit;
  int32_t matched = 0;
  uint32_t seconds = 0;
  if ((matched = sscanf(input, "%u %c", &seconds, &unit)) >= 1) {
    if (matched == 1)
      return seconds;
    switch (unit) {
    case 's':
    case 'S':
      return seconds;
    case 'm':
    case 'M':
      return seconds * 60;
    case 'h':
    case 'H':
      return seconds * 3600;
    default:
      log_error("Invalid time unit specified: %c", unit);
      return 0;
    }
  } else if (matched == -1) {
    log_perror("nyx: sscanf");
  }
  return 0;
}
```