ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
L24:
  movq   $0x0,-0x20(%rbp)
  jmp    L8
L4:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addq   $0x1,-0x20(%rbp)
L8:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x20(%rbp)
  jb     L4
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  je     L10
  jmp    L24
L10:
  nop
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6c,%edi
  call   <sleep@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x18(%rbp)
  jmp    L21
L23:
  addq   $0x1,-0x18(%rbp)
L21:
  cmpq   $0x98967f,-0x18(%rbp)
  jbe    L23
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string

tool: D29: pid is %ld


tool: D14: %ld, %ld

assistant: ```c
int main(int argc, char *argv[]) {
  int argc_count = 0;
  while (1) {
    for (size_t j = 0; j < strlen(argv[0]); j++) {
      argv[argc_count][j] = ' ';
    }
    ++argc_count;
    if (argc_count == argc)
      break;
  }
  printf("pid is %ld\n", getpid());
  sleep(108);
  int64_t i;
  struct timeval start;
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  for (i = 0; i < 10000000ULL; i++) {
  }
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r13
  jmp    L10
L40:
  mov    0x0(%rbp),%rax
  movb   $0x20,(%rax,%rbx,1)
  add    $0x1,%rbx
L7:
  mov    (%r12),%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L40
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L1
L10:
  mov    $0x0,%ebx
  jmp    L7
L1:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6c,%edi
  call   <sleep@plt>
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x989680,%eax
L42:
  sub    $0x1,%rax
  jne    L42
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D3
type: string

tool: D21: pid is %ld


tool: D3: %ld, %ld

assistant: ```c
int main(int argc, char *argv[]) {
  int argc_count = 0;
  while (1) {
    for (size_t j = 0; j < strlen(argv[0]); j++) {
      argv[argc_count][j] = ' ';
    }
    ++argc_count;
    if (argc_count == argc)
      break;
  }
  printf("pid is %ld\n", getpid());
  sleep(108);
  int64_t i;
  struct timeval start;
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  for (i = 0; i < 10000000ULL; i++) {
  }
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%r13
  sub    $0x18,%rsp
  mov    (%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L33:
  xor    %ebx,%ebx
  jmp    L13
  nopl   0x0(%rax)
L34:
  mov    0x0(%r13),%rax
  movb   $0x20,(%rax,%rbx,1)
  mov    0x0(%rbp),%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
L13:
  cmp    %rax,%rbx
  jb     L34
  add    $0x8,%r13
  cmp    %r12,%r13
  jne    L33
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    D17(%rip),%rbp
  call   <getpid@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6c,%edi
  call   <sleep@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D17: %ld, %ld

tool: D4: pid is %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int argc_count = 0;
  while (1) {
    for (size_t j = 0; j < strlen(argv[0]); j++) {
      argv[argc_count][j] = ' ';
    }
    ++argc_count;
    if (argc_count == argc)
      break;
  }
  printf("pid is %ld\n", getpid());
  sleep(108);
  int64_t i;
  struct timeval start;
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  for (i = 0; i < 10000000ULL; i++) {
  }
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%r13
  sub    $0x18,%rsp
  mov    (%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L42:
  test   %rax,%rax
  je     L24
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L45:
  mov    0x0(%r13),%rax
  movb   $0x20,(%rax,%rbx,1)
  mov    0x0(%rbp),%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jb     L45
  add    $0x8,%r13
  cmp    %r12,%r13
  jne    L42
L10:
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    D17(%rip),%rbp
  call   <getpid@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6c,%edi
  call   <sleep@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  add    $0x8,%r13
  cmp    %r12,%r13
  je     L10
  add    $0x8,%r13
  cmp    %r12,%r13
  jne    L42
  jmp    L10
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string

tool: D17: %ld, %ld

tool: D9: pid is %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int argc_count = 0;
  while (1) {
    for (size_t j = 0; j < strlen(argv[0]); j++) {
      argv[argc_count][j] = ' ';
    }
    ++argc_count;
    if (argc_count == argc)
      break;
  }
  printf("pid is %ld\n", getpid());
  sleep(108);
  int64_t i;
  struct timeval start;
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  for (i = 0; i < 10000000ULL; i++) {
  }
  gettimeofday(&start, NULL);
  printf("%ld, %ld", start.tv_sec, start.tv_usec);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ReadUint16Le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  shll   $0x8,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x2,%eax
  leave
  ret
```

assistant: ```c
int32_t ReadUint16Le(const void *in, uint16_t *value) {
  assert(in != NULL);
  assert(value != NULL);
  const uint8_t *buf = (const uint8_t *)in;
  uint16_t out = buf[1];
  out = (uint16_t)(out << 8);
  out = (uint16_t)(out | buf[0]);
  *value = out;
  return 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ReadUint16Le>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x4(%rbx),%eax
  shl    $0x8,%eax
  or     (%rbx),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x2,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int32_t ReadUint16Le(const void *in, uint16_t *value) {
  assert(in != NULL);
  assert(value != NULL);
  const uint8_t *buf = (const uint8_t *)in;
  uint16_t out = buf[1];
  out = (uint16_t)(out << 8);
  out = (uint16_t)(out | buf[0]);
  *value = out;
  return 2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ReadUint16Le>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    0x4(%rbx),%eax
  shl    $0x8,%eax
  or     (%rbx),%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int32_t ReadUint16Le(const void *in, uint16_t *value) {
  assert(in != NULL);
  assert(value != NULL);
  const uint8_t *buf = (const uint8_t *)in;
  uint16_t out = buf[1];
  out = (uint16_t)(out << 8);
  out = (uint16_t)(out | buf[0]);
  *value = out;
  return 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dmat_ldimget>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x48(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x48(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x48(%rbp),%rax
  mov    0x18(%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x48(%rbp),%rax
  mov    0x1c(%rax),%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x10(%rbp),%rdi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <Cblacs_gridinfo@plt>
  lea    -0x1c(%rbp),%rdi
  lea    -0x24(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x2c(%rbp),%rsi
  lea    -0x34(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <numroc_@plt>
  mov    -0x50(%rbp),%rdx
  mov    %eax,(%rdx)
  lea    -0x18(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x30(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <numroc_@plt>
  mov    -0x58(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L27
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L13
L27:
  mov    -0x50(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x58(%rbp),%rax
  movl   $0x0,(%rax)
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void dmat_ldimget(int *desc, int *nrows, int *ncols) {
  int M = desc[2];
  int N = desc[3];
  int Mb = desc[4];
  int Nb = desc[5];
  int ictxt = desc[1];
  int rsrc = desc[6];
  int csrc = desc[7];
  int nprow, npcol, myprow, mypcol;
  Cblacs_gridinfo(ictxt, &nprow, &npcol, &myprow, &mypcol);
  *nrows = numroc_(&M, &Mb, &myprow, &rsrc, &nprow);
  *ncols = numroc_(&N, &Nb, &mypcol, &csrc, &npcol);
  if (*nrows < 1 || *ncols < 1) {
    *nrows = 0;
    *ncols = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dmat_ldimget>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x8(%rdi),%eax
  mov    %eax,(%rsp)
  mov    0xc(%rdi),%eax
  mov    %eax,0x4(%rsp)
  mov    0x10(%rdi),%eax
  mov    %eax,0x8(%rsp)
  mov    0x14(%rdi),%eax
  mov    %eax,0xc(%rsp)
  mov    0x4(%rdi),%eax
  mov    0x18(%rdi),%edx
  mov    %edx,0x10(%rsp)
  mov    0x1c(%rdi),%edx
  mov    %edx,0x14(%rsp)
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%r14
  lea    0x1c(%rsp),%r13
  lea    0x18(%rsp),%r15
  mov    %r12,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %eax,%edi
  call   <Cblacs_gridinfo@plt>
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %r15,%r8
  mov    %r14,%rdx
  call   <numroc_@plt>
  mov    %eax,(%rbx)
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %r13,%r8
  mov    %r12,%rdx
  call   <numroc_@plt>
  mov    %eax,0x0(%rbp)
  cmpl   $0x0,(%rbx)
  jle    L1
  test   %eax,%eax
  jg     L24
L1:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
L24:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dmat_ldimget(int *desc, int *nrows, int *ncols) {
  int M = desc[2];
  int N = desc[3];
  int Mb = desc[4];
  int Nb = desc[5];
  int ictxt = desc[1];
  int rsrc = desc[6];
  int csrc = desc[7];
  int nprow, npcol, myprow, mypcol;
  Cblacs_gridinfo(ictxt, &nprow, &npcol, &myprow, &mypcol);
  *nrows = numroc_(&M, &Mb, &myprow, &rsrc, &nprow);
  *ncols = numroc_(&N, &Nb, &mypcol, &csrc, &npcol);
  if (*nrows < 1 || *ncols < 1) {
    *nrows = 0;
    *ncols = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dmat_ldimget>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    0x4(%rdi),%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    0x8(%rdi),%eax
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%r14
  lea    0x1c(%rsp),%r13
  lea    0x18(%rsp),%r15
  mov    %r12,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %eax,(%rsp)
  mov    0xc(%rdi),%eax
  mov    %eax,0x4(%rsp)
  mov    0x10(%rdi),%eax
  mov    %eax,0x8(%rsp)
  mov    0x14(%rdi),%eax
  mov    %eax,0xc(%rsp)
  mov    0x18(%rdi),%eax
  mov    %eax,0x10(%rsp)
  mov    0x1c(%rdi),%eax
  mov    %r9d,%edi
  mov    %eax,0x14(%rsp)
  call   <Cblacs_gridinfo@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rdi
  mov    %r15,%r8
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdx
  call   <numroc_@plt>
  mov    %r12,%rdx
  lea    0x14(%rsp),%rcx
  mov    %r13,%r8
  mov    %eax,(%rbx)
  lea    0xc(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <numroc_@plt>
  mov    %eax,0x0(%rbp)
  mov    (%rbx),%edx
  test   %edx,%edx
  jle    L13
  test   %eax,%eax
  jle    L13
L31:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
  jmp    L31
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dmat_ldimget(int *desc, int *nrows, int *ncols) {
  int M = desc[2];
  int N = desc[3];
  int Mb = desc[4];
  int Nb = desc[5];
  int ictxt = desc[1];
  int rsrc = desc[6];
  int csrc = desc[7];
  int nprow, npcol, myprow, mypcol;
  Cblacs_gridinfo(ictxt, &nprow, &npcol, &myprow, &mypcol);
  *nrows = numroc_(&M, &Mb, &myprow, &rsrc, &nprow);
  *ncols = numroc_(&N, &Nb, &mypcol, &csrc, &npcol);
  if (*nrows < 1 || *ncols < 1) {
    *nrows = 0;
    *ncols = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dmat_ldimget>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    0x4(%rdi),%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    0x8(%rdi),%eax
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%r14
  lea    0x1c(%rsp),%r13
  lea    0x18(%rsp),%r15
  mov    %r12,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %eax,(%rsp)
  mov    0xc(%rdi),%eax
  mov    %eax,0x4(%rsp)
  mov    0x10(%rdi),%eax
  mov    %eax,0x8(%rsp)
  mov    0x14(%rdi),%eax
  mov    %eax,0xc(%rsp)
  mov    0x18(%rdi),%eax
  mov    %eax,0x10(%rsp)
  mov    0x1c(%rdi),%eax
  mov    %r9d,%edi
  mov    %eax,0x14(%rsp)
  call   <Cblacs_gridinfo@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rdi
  mov    %r15,%r8
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdx
  call   <numroc_@plt>
  mov    %r12,%rdx
  lea    0x14(%rsp),%rcx
  mov    %r13,%r8
  mov    %eax,(%rbx)
  lea    0xc(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <numroc_@plt>
  mov    %eax,0x0(%rbp)
  mov    (%rbx),%edx
  test   %edx,%edx
  jle    L26
  test   %eax,%eax
  jle    L26
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
  jmp    L1
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dmat_ldimget(int *desc, int *nrows, int *ncols) {
  int M = desc[2];
  int N = desc[3];
  int Mb = desc[4];
  int Nb = desc[5];
  int ictxt = desc[1];
  int rsrc = desc[6];
  int csrc = desc[7];
  int nprow, npcol, myprow, mypcol;
  Cblacs_gridinfo(ictxt, &nprow, &npcol, &myprow, &mypcol);
  *nrows = numroc_(&M, &Mb, &myprow, &rsrc, &nprow);
  *ncols = numroc_(&N, &Nb, &mypcol, &csrc, &npcol);
  if (*nrows < 1 || *ncols < 1) {
    *nrows = 0;
    *ncols = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quotestring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L21
L25:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L17
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x27,(%rax)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x27,(%rax)
  addl   $0x1,-0x10(%rbp)
  jmp    L4
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L4:
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L25
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *quotestring(char *stringIn) {
  int slen = strlen(stringIn);
  char *stringOut = malloc(slen * 2 + 1);
  int x, y = 0;
  for (x = 0; x < slen; x++) {
    if (stringIn[x] == '\'') {
      stringOut[y] = '\'';
      y++;
      stringOut[y] = '\'';
      y++;
    } else {
      stringOut[y] = stringIn[x];
      y++;
    }
  }
  stringOut[y] = '\0';
  return stringOut;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quotestring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax,%rax,1),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L7
  mov    %rbp,%rdx
  lea    -0x1(%rbx),%ecx
  lea    0x1(%rbp,%rcx,1),%r8
  mov    $0x0,%ecx
  jmp    L14
L30:
  movslq %ecx,%rsi
  movb   $0x27,(%rax,%rsi,1)
  lea    0x1(%rcx),%esi
  movslq %esi,%rsi
  movb   $0x27,(%rax,%rsi,1)
  add    $0x2,%ecx
L1:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L28
L14:
  movzbl (%rdx),%esi
  cmp    $0x27,%sil
  je     L30
  movslq %ecx,%rdi
  mov    %sil,(%rax,%rdi,1)
  add    $0x1,%ecx
  jmp    L1
L7:
  mov    $0x0,%ecx
L28:
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *quotestring(char *stringIn) {
  int slen = strlen(stringIn);
  char *stringOut = malloc(slen * 2 + 1);
  int x, y = 0;
  for (x = 0; x < slen; x++) {
    if (stringIn[x] == '\'') {
      stringOut[y] = '\'';
      y++;
      stringOut[y] = '\'';
      y++;
    } else {
      stringOut[y] = stringIn[x];
      y++;
    }
  }
  stringOut[y] = '\0';
  return stringOut;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quotestring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax,%rax,1),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L36
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rdx,1),%r9
  xor    %edx,%edx
  jmp    L3
L34:
  add    $0x1,%rdi
  mov    %r8b,(%rcx)
  mov    %esi,%edx
  cmp    %rdi,%r9
  je     L32
L3:
  movzbl (%rdi),%r8d
  movslq %edx,%rcx
  lea    0x1(%rdx),%esi
  add    %rax,%rcx
  cmp    $0x27,%r8b
  jne    L34
  movslq %esi,%rsi
  add    $0x1,%rdi
  movb   $0x27,(%rcx)
  add    $0x2,%edx
  movb   $0x27,(%rax,%rsi,1)
  cmp    %rdi,%r9
  jne    L3
L32:
  movslq %edx,%rdx
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *quotestring(char *stringIn) {
  int slen = strlen(stringIn);
  char *stringOut = malloc(slen * 2 + 1);
  int x, y = 0;
  for (x = 0; x < slen; x++) {
    if (stringIn[x] == '\'') {
      stringOut[y] = '\'';
      y++;
      stringOut[y] = '\'';
      y++;
    } else {
      stringOut[y] = stringIn[x];
      y++;
    }
  }
  stringOut[y] = '\0';
  return stringOut;
}
```