ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dble_sum2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
void dble_sum2(double *A, int K, int M, double *res, double epsilon) {
  int k, j;
  for (k = 0; k < K; k++) {
    res[k] = 0;
    for (j = 0; j < M; j++)
      res[k] += A[k * M + j] * A[k * M + j];
    res[k] = res[k] / 2 + epsilon;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dble_sum2>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %rbx
  mov    %rdi,%r9
  mov    %edx,%r8d
  mov    %rcx,%rdi
  lea    -0x1(%rsi),%eax
  lea    0x8(%rcx,%rax,8),%r10
  mov    $0x0,%esi
  lea    -0x1(%rdx),%ebx
  lea    0x8(%r9),%r11
  movsd  D8(%rip),%xmm2
L33:
  mov    %rdi,%rdx
  movq   $0x0,(%rdi)
  test   %r8d,%r8d
  jle    L19
  movslq %esi,%rcx
  lea    (%r9,%rcx,8),%rax
  add    %rbx,%rcx
  lea    (%r11,%rcx,8),%rcx
L12:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  (%rdx),%xmm1
  movsd  %xmm1,(%rdx)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L12
L19:
  movapd %xmm2,%xmm1
  mulsd  (%rdx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  add    $0x8,%rdi
  add    %r8d,%esi
  cmp    %r10,%rdi
  jne    L33
  pop    %rbx
  ret
L13:
  ret
```

tool_calls: name: read_data
arguments: label: D8
type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void dble_sum2(double *A, int K, int M, double *res, double epsilon) {
  int k, j;
  for (k = 0; k < K; k++) {
    res[k] = 0;
    for (j = 0; j < M; j++)
      res[k] += A[k * M + j] * A[k * M + j];
    res[k] = res[k] / 2 + epsilon;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dble_sum2>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%edi
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  lea    -0x1(%rdx),%r11d
  xor    %esi,%esi
  movsd  D2(%rip),%xmm4
  lea    0x8(%rcx,%rax,8),%r9
  lea    0x8(%r8),%r10
  nopl   0x0(%rax,%rax,1)
L4:
  movq   $0x0,(%rcx)
  test   %edi,%edi
  jle    L32
  movslq %esi,%rdx
  movapd %xmm3,%xmm2
  lea    (%r8,%rdx,8),%rax
  add    %r11,%rdx
  lea    (%r10,%rdx,8),%rdx
  nopl   (%rax)
L26:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  movsd  %xmm2,(%rcx)
  cmp    %rax,%rdx
  jne    L26
  mulsd  %xmm4,%xmm2
L22:
  addsd  %xmm0,%xmm2
  add    $0x8,%rcx
  add    %edi,%esi
  movsd  %xmm2,-0x8(%rcx)
  cmp    %r9,%rcx
  jne    L4
L10:
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  movapd %xmm3,%xmm2
  jmp    L22
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void dble_sum2(double *A, int K, int M, double *res, double epsilon) {
  int k, j;
  for (k = 0; k < K; k++) {
    res[k] = 0;
    for (j = 0; j < M; j++)
      res[k] += A[k * M + j] * A[k * M + j];
    res[k] = res[k] / 2 + epsilon;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dble_sum2>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%edi
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  lea    -0x1(%rdx),%r11d
  xor    %esi,%esi
  movsd  D8(%rip),%xmm4
  lea    0x8(%rcx,%rax,8),%r9
  lea    0x8(%r8),%r10
  nopl   0x0(%rax,%rax,1)
L19:
  movq   $0x0,(%rcx)
  test   %edi,%edi
  jle    L7
  movslq %esi,%rdx
  movapd %xmm3,%xmm2
  lea    (%r8,%rdx,8),%rax
  add    %r11,%rdx
  lea    (%r10,%rdx,8),%rdx
  nopl   (%rax)
L36:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  movsd  %xmm2,(%rcx)
  cmp    %rax,%rdx
  jne    L36
  mulsd  %xmm4,%xmm2
L33:
  addsd  %xmm0,%xmm2
  add    $0x8,%rcx
  add    %edi,%esi
  movsd  %xmm2,-0x8(%rcx)
  cmp    %r9,%rcx
  jne    L19
L45:
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movapd %xmm3,%xmm2
  jmp    L33
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void dble_sum2(double *A, int K, int M, double *res, double epsilon) {
  int k, j;
  for (k = 0; k < K; k++) {
    res[k] = 0;
    for (j = 0; j < M; j++)
      res[k] += A[k * M + j] * A[k * M + j];
    res[k] = res[k] / 2 + epsilon;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L0:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcopy(char *ch) {
  int leng = strlen(ch);
  char *t = (char *)malloc(leng + 1);
  char *rp = t;
  while ((*t++ = *ch++) != '\0')
    ;
  return rp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcopy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rdi
L2:
  mov    %rdx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rdx,%rdi,1),%ecx
  mov    %cl,(%rsi)
  test   %cl,%cl
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
char *strcopy(char *ch) {
  int leng = strlen(ch);
  char *t = (char *)malloc(leng + 1);
  char *rp = t;
  while ((*t++ = *ch++) != '\0')
    ;
  return rp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcopy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  sub    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbx,%rdi
  xchg   %ax,%ax
L2:
  mov    %rdx,%rsi
  movzbl (%rdx,%rdi,1),%ecx
  add    $0x1,%rdx
  mov    %cl,(%rsi)
  test   %cl,%cl
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
char *strcopy(char *ch) {
  int leng = strlen(ch);
  char *t = (char *)malloc(leng + 1);
  char *rp = t;
  while ((*t++ = *ch++) != '\0')
    ;
  return rp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcopy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  sub    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbx,%rdi
  xchg   %ax,%ax
L6:
  mov    %rdx,%rsi
  movzbl (%rdx,%rdi,1),%ecx
  add    $0x1,%rdx
  mov    %cl,(%rsi)
  test   %cl,%cl
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
char *strcopy(char *ch) {
  int leng = strlen(ch);
  char *t = (char *)malloc(leng + 1);
  char *rp = t;
  while ((*t++ = *ch++) != '\0')
    ;
  return rp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cnt_null>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  cmpl   $0x0,-0x24(%rbp)
  je     L44
  cmpq   $0x0,-0x30(%rbp)
  jne    L61
L44:
  mov    $0x0,%eax
  jmp    L56
L61:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L63
L39:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  addl   $0x1,-0x14(%rbp)
L53:
  addq   $0x1,-0x10(%rbp)
L63:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jne    L39
  mov    -0x38(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L43
L27:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L81
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  mov    %rdx,(%rax)
L81:
  addq   $0x1,-0x10(%rbp)
L43:
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L27
  mov    -0x8(%rbp),%rax
L56:
  leave
  ret
```

assistant: ```c
char **cnt_null(int l, char *str, int *_n) {
  int n = 0;
  char *p, **list;
  *_n = 0;
  if (l == 0 || str == 0)
    return 0;
  for (p = str; p != str + l; ++p)
    if (*p == 0)
      ++n;
  *_n = n;
  list = calloc(n, sizeof(void *));
  list[0] = str;
  for (p = str, n = 1; p < str + l - 1; ++p)
    if (*p == 0)
      list[n++] = p + 1;
  return list;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cnt_null>:
  endbr64
  movl   $0x0,(%rdx)
  test   %edi,%edi
  je     L47
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L74
  movslq %edi,%rbp
  lea    (%rsi,%rbp,1),%rcx
  mov    %rsi,%rax
  mov    $0x0,%edi
L58:
  cmpb   $0x1,(%rax)
  adc    $0x0,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L58
  mov    %edi,(%rdx)
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rbx,(%rax)
  lea    -0x1(%rbx,%rbp,1),%rdi
  cmp    %rdi,%rbx
  jae    L38
  lea    0x1(%rbx),%rdx
  mov    $0x1,%esi
  jmp    L73
L40:
  lea    0x1(%rdx),%rcx
  cmp    %rdx,%rdi
  je     L38
  mov    %rcx,%rdx
L73:
  cmpb   $0x0,-0x1(%rdx)
  jne    L40
  movslq %esi,%rcx
  mov    %rdx,(%rax,%rcx,8)
  lea    0x1(%rsi),%esi
  jmp    L40
L74:
  mov    $0x0,%eax
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L47:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char **cnt_null(int l, char *str, int *_n) {
  int n = 0;
  char *p, **list;
  *_n = 0;
  if (l == 0 || str == 0)
    return 0;
  for (p = str; p != str + l; ++p)
    if (*p == 0)
      ++n;
  *_n = n;
  list = calloc(n, sizeof(void *));
  list[0] = str;
  for (p = str, n = 1; p < str + l - 1; ++p)
    if (*p == 0)
      list[n++] = p + 1;
  return list;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cnt_null>:
  endbr64
  movl   $0x0,(%rdx)
  test   %edi,%edi
  je     L41
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L36
  movslq %edi,%rbp
  mov    %rsi,%rax
  xor    %edi,%edi
  lea    (%rsi,%rbp,1),%rcx
  nopl   0x0(%rax)
L49:
  cmpb   $0x1,(%rax)
  adc    $0x0,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L49
  mov    %edi,(%rdx)
  mov    $0x8,%esi
  call   <calloc@plt>
  lea    -0x1(%rbx,%rbp,1),%rsi
  mov    %rbx,(%rax)
  cmp    %rsi,%rbx
  jae    L35
  mov    $0x1,%ecx
  nopl   (%rax)
L10:
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  jne    L59
  movslq %ecx,%rdx
  add    $0x1,%ecx
  mov    %rbx,(%rax,%rdx,8)
L59:
  cmp    %rsi,%rbx
  jne    L10
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
  ret
```

assistant: ```c
char **cnt_null(int l, char *str, int *_n) {
  int n = 0;
  char *p, **list;
  *_n = 0;
  if (l == 0 || str == 0)
    return 0;
  for (p = str; p != str + l; ++p)
    if (*p == 0)
      ++n;
  *_n = n;
  list = calloc(n, sizeof(void *));
  list[0] = str;
  for (p = str, n = 1; p < str + l - 1; ++p)
    if (*p == 0)
      list[n++] = p + 1;
  return list;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snake_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void snake_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vsyslog(LOG_ERR, fmt, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<snake_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void snake_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vsyslog(LOG_ERR, fmt, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snake_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void snake_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vsyslog(LOG_ERR, fmt, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<snake_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void snake_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vsyslog(LOG_ERR, fmt, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fft2pt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movss  0x8(%rax),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movss  0xc(%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x18(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x14(%rbp),%xmm0
  addss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x18(%rbp),%xmm0
  subss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fft2pt(float *ioptr) {
  float f0r, f0i, f1r, f1i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[2];
  f1i = ioptr[3];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = f1r;
  ioptr[3] = f1i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fft2pt>:
  endbr64
  movss  (%rdi),%xmm1
  movss  0x4(%rdi),%xmm0
  movss  0x8(%rdi),%xmm3
  movss  0xc(%rdi),%xmm2
  movaps %xmm1,%xmm4
  addss  %xmm3,%xmm4
  movss  %xmm4,(%rdi)
  movaps %xmm0,%xmm4
  addss  %xmm2,%xmm4
  movss  %xmm4,0x4(%rdi)
  subss  %xmm3,%xmm1
  movss  %xmm1,0x8(%rdi)
  subss  %xmm2,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void fft2pt(float *ioptr) {
  float f0r, f0i, f1r, f1i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[2];
  f1i = ioptr[3];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = f1r;
  ioptr[3] = f1i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fft2pt>:
  endbr64
  movss  (%rdi),%xmm1
  movss  0x8(%rdi),%xmm3
  movss  0x4(%rdi),%xmm0
  movss  0xc(%rdi),%xmm2
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm1
  addss  %xmm3,%xmm4
  movss  %xmm1,0x8(%rdi)
  movss  %xmm4,(%rdi)
  movaps %xmm0,%xmm4
  subss  %xmm2,%xmm0
  addss  %xmm2,%xmm4
  movss  %xmm0,0xc(%rdi)
  movss  %xmm4,0x4(%rdi)
  ret
```

assistant: ```c
void fft2pt(float *ioptr) {
  float f0r, f0i, f1r, f1i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[2];
  f1i = ioptr[3];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = f1r;
  ioptr[3] = f1i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fft2pt>:
  endbr64
  movups (%rdi),%xmm0
  movaps %xmm0,%xmm1
  movlhps %xmm0,%xmm1
  shufps $0xee,%xmm0,%xmm0
  movaps %xmm1,%xmm2
  subps  %xmm0,%xmm1
  addps  %xmm0,%xmm2
  shufps $0xe4,%xmm1,%xmm2
  movups %xmm2,(%rdi)
  ret
```

assistant: ```c
void fft2pt(float *ioptr) {
  float f0r, f0i, f1r, f1i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[2];
  f1i = ioptr[3];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = f1r;
  ioptr[3] = f1i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<x_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L11
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  jle    L17
  cmpl   $0x0,-0x8(%rbp)
  jg     L16
L17:
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int x_recv(int fd, char *buf, int len) {
  int bytes = -1;
  int length = len;
  do {
    bytes = recv(fd, buf, length, 0);
    if (bytes > 0) {
      length -= bytes;
      buf += bytes;
    }
  } while (length > 0 && bytes > 0);
  if (length == 0) {
    bytes = len;
  }
  return bytes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<x_recv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %edx,%ebx
  jmp    L17
L11:
  sub    %eax,%ebx
  movslq %eax,%rdx
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L28
L17:
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %eax,%eax
  jg     L11
L28:
  test   %ebx,%ebx
  cmove  %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int x_recv(int fd, char *buf, int len) {
  int bytes = -1;
  int length = len;
  do {
    bytes = recv(fd, buf, length, 0);
    if (bytes > 0) {
      length -= bytes;
      buf += bytes;
    }
  } while (length > 0 && bytes > 0);
  if (length == 0) {
    bytes = len;
  }
  return bytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<x_recv>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L8:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L4
L18:
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %eax,%eax
  jg     L8
L4:
  test   %ebx,%ebx
  cmove  %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int x_recv(int fd, char *buf, int len) {
  int bytes = -1;
  int length = len;
  do {
    bytes = recv(fd, buf, length, 0);
    if (bytes > 0) {
      length -= bytes;
      buf += bytes;
    }
  } while (length > 0 && bytes > 0);
  if (length == 0) {
    bytes = len;
  }
  return bytes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<x_recv>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L10:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L19
L29:
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %eax,%eax
  jg     L10
L19:
  test   %ebx,%ebx
  cmove  %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int x_recv(int fd, char *buf, int len) {
  int bytes = -1;
  int length = len;
  do {
    bytes = recv(fd, buf, length, 0);
    if (bytes > 0) {
      length -= bytes;
      buf += bytes;
    }
  } while (length > 0 && bytes > 0);
  if (length == 0) {
    bytes = len;
  }
  return bytes;
}
```