ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solv_latin1toutf8>:
  endbr64
  push   %rbx
  movzbl (%rdi),%edx
  mov    %rdi,%rbx
  test   %dl,%dl
  je     L73
  mov    %rdi,%rax
  mov    $0x1,%edi
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    $0x80,%dl
  sbb    $0xffffffff,%edi
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L23
  sub    %rbx,%rax
  add    %eax,%edi
L74:
  call   <solv_malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  jne    L48
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L46:
  add    $0x1,%rbx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L78
L48:
  test   %dl,%dl
  jns    L46
  and    $0x40,%edx
  setne  %dl
  add    $0x1,%rbx
  add    $0x2,%rcx
  sub    $0x3e,%edx
  mov    %dl,-0x2(%rcx)
  movzbl -0x1(%rbx),%edx
  and    $0xffffffbf,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L48
L78:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nop
L73:
  mov    $0x1,%edi
  jmp    L74
```

assistant: ```c
char *solv_latin1toutf8(const char *buf) {
  int l = 1;
  const char *p;
  char *r, *rp;
  for (p = buf; *p; p++)
    if ((*(const unsigned char *)p & 128) != 0)
      l++;
  r = rp = solv_malloc(p - buf + l);
  for (p = buf; *p; p++) {
    if ((*(const unsigned char *)p & 128) != 0) {
      *rp++ = *(const unsigned char *)p & 64 ? 0xc3 : 0xc2;
      *rp++ = *p & 0xbf;
    } else
      *rp++ = *p;
  }
  *rp = 0;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solv_latin1toutf8>:
  endbr64
  push   %rbx
  movzbl (%rdi),%edx
  mov    %rdi,%rbx
  test   %dl,%dl
  je     L56
  mov    %rdi,%rax
  mov    $0x1,%edi
  nopl   0x0(%rax,%rax,1)
L6:
  cmp    $0x80,%dl
  sbb    $0xffffffff,%edi
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L6
  sub    %rbx,%rax
  add    %eax,%edi
L21:
  call   <solv_malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  jne    L23
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L78:
  add    $0x1,%rbx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L66
L23:
  test   %dl,%dl
  jns    L78
  and    $0x40,%edx
  setne  %dl
  add    $0x1,%rbx
  add    $0x2,%rcx
  sub    $0x3e,%edx
  mov    %dl,-0x2(%rcx)
  movzbl -0x1(%rbx),%edx
  and    $0xffffffbf,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L23
L66:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nop
L56:
  mov    $0x1,%edi
  jmp    L21
```

assistant: ```c
char *solv_latin1toutf8(const char *buf) {
  int l = 1;
  const char *p;
  char *r, *rp;
  for (p = buf; *p; p++)
    if ((*(const unsigned char *)p & 128) != 0)
      l++;
  r = rp = solv_malloc(p - buf + l);
  for (p = buf; *p; p++) {
    if ((*(const unsigned char *)p & 128) != 0) {
      *rp++ = *(const unsigned char *)p & 64 ? 0xc3 : 0xc2;
      *rp++ = *p & 0xbf;
    } else
      *rp++ = *p;
  }
  *rp = 0;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getNewArithmeticOperation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x8,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpl   $0x4,-0x34(%rbp)
  ja     L23
  mov    -0x34(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D63(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D63(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D37(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L23
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D46(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L23
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D50(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L23
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D14(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L23
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D26(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  nop
L23:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D37
type_infered: string
name: retrieve_data
arguments: label: D46
type_infered: string
name: retrieve_data
arguments: label: D50
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string

tool: D37: ADD(%s; %s)

tool: D46: SUB(%s; %s)

tool: D50: MUL(%s; %s)

tool: D14: DIV(%s; %s)

tool: D26: MOD(%s; %s)

assistant: ```c
char *getNewArithmeticOperation(char *left, char *right, int opCode) {
  int size = strlen(left) + strlen(right) + 8;
  char *result = (char *)malloc(size);
  switch (opCode) {
  case 0:
    snprintf(result, size, "ADD(%s; %s)", left, right);
    break;
  case 1:
    snprintf(result, size, "SUB(%s; %s)", left, right);
    break;
  case 2:
    snprintf(result, size, "MUL(%s; %s)", left, right);
    break;
  case 3:
    snprintf(result, size, "DIV(%s; %s)", left, right);
    break;
  case 4:
    snprintf(result, size, "MOD(%s; %s)", left, right);
    break;
  }
  free(left);
  free(right);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getNewArithmeticOperation>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x8(%r13,%rax,1),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x4,%ebx
  ja     L38
  mov    %ebx,%ebx
  lea    D3(%rip),%rdx
  movslq (%rdx,%rbx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D33(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
L38:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D22(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L38
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D34(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L38
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D18(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L38
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D26(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L38
```

tool_calls: name: unpack_data
arguments: tag: D33
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D34
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string

tool: D33: ADD(%s; %s)

tool: D22: SUB(%s; %s)

tool: D34: MUL(%s; %s)

tool: D18: DIV(%s; %s)

tool: D26: MOD(%s; %s)

assistant: ```c
char *getNewArithmeticOperation(char *left, char *right, int opCode) {
  int size = strlen(left) + strlen(right) + 8;
  char *result = (char *)malloc(size);
  switch (opCode) {
  case 0:
    snprintf(result, size, "ADD(%s; %s)", left, right);
    break;
  case 1:
    snprintf(result, size, "SUB(%s; %s)", left, right);
    break;
  case 2:
    snprintf(result, size, "MUL(%s; %s)", left, right);
    break;
  case 3:
    snprintf(result, size, "DIV(%s; %s)", left, right);
    break;
  case 4:
    snprintf(result, size, "MOD(%s; %s)", left, right);
    break;
  }
  free(left);
  free(right);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getNewArithmeticOperation>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    0x8(%r13,%rax,1),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x4,%ebx
  ja     L1
  lea    D48(%rip),%rdx
  mov    %rbp,%r8
  mov    %r12,%rcx
  movslq (%rdx,%rbx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D4(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
L1:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
  lea    D10(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L1
  nopl   0x0(%rax)
  lea    D18(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L1
  nopl   0x0(%rax)
  lea    D45(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L1
  nopl   0x0(%rax)
  lea    D2(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D45
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D4: MOD(%s; %s)

tool: D10: DIV(%s; %s)

tool: D18: ADD(%s; %s)

tool: D45: SUB(%s; %s)

tool: D2: MUL(%s; %s)

assistant: ```c
char *getNewArithmeticOperation(char *left, char *right, int opCode) {
  int size = strlen(left) + strlen(right) + 8;
  char *result = (char *)malloc(size);
  switch (opCode) {
  case 0:
    snprintf(result, size, "ADD(%s; %s)", left, right);
    break;
  case 1:
    snprintf(result, size, "SUB(%s; %s)", left, right);
    break;
  case 2:
    snprintf(result, size, "MUL(%s; %s)", left, right);
    break;
  case 3:
    snprintf(result, size, "DIV(%s; %s)", left, right);
    break;
  case 4:
    snprintf(result, size, "MOD(%s; %s)", left, right);
    break;
  }
  free(left);
  free(right);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getNewArithmeticOperation>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    0x8(%r13,%rax,1),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x4,%ebx
  ja     L44
  lea    D21(%rip),%rdx
  mov    %rbp,%r8
  mov    %r12,%rcx
  movslq (%rdx,%rbx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D49(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
L44:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
  lea    D45(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L44
  nopl   0x0(%rax)
  lea    D57(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L44
  nopl   0x0(%rax)
  lea    D34(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L44
  nopl   0x0(%rax)
  lea    D4(%rip),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  jmp    L44
```

tool_calls: name: parse_data
arguments: data_label: D49
datatype: string
name: parse_data
arguments: data_label: D45
datatype: string
name: parse_data
arguments: data_label: D57
datatype: string
name: parse_data
arguments: data_label: D34
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string

tool: D49: MOD(%s; %s)

tool: D45: DIV(%s; %s)

tool: D57: ADD(%s; %s)

tool: D34: SUB(%s; %s)

tool: D4: MUL(%s; %s)

assistant: ```c
char *getNewArithmeticOperation(char *left, char *right, int opCode) {
  int size = strlen(left) + strlen(right) + 8;
  char *result = (char *)malloc(size);
  switch (opCode) {
  case 0:
    snprintf(result, size, "ADD(%s; %s)", left, right);
    break;
  case 1:
    snprintf(result, size, "SUB(%s; %s)", left, right);
    break;
  case 2:
    snprintf(result, size, "MUL(%s; %s)", left, right);
    break;
  case 3:
    snprintf(result, size, "DIV(%s; %s)", left, right);
    break;
  case 4:
    snprintf(result, size, "MOD(%s; %s)", left, right);
    break;
  }
  free(left);
  free(right);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<DeactivateHorizontalScroll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x2e,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <oled_SendCommand@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void DeactivateHorizontalScroll() {
  unsigned char d[] = {0x2E};
  oled_SendCommand(d, sizeof(d));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DeactivateHorizontalScroll>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x2e,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  mov    $0x1,%esi
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DeactivateHorizontalScroll() {
  unsigned char d[] = {0x2E};
  oled_SendCommand(d, sizeof(d));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DeactivateHorizontalScroll>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x2e,0x7(%rsp)
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DeactivateHorizontalScroll() {
  unsigned char d[] = {0x2E};
  oled_SendCommand(d, sizeof(d));
}
```
user: Translate the below assembly code into C programming language:

```asm
<DeactivateHorizontalScroll>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x2e,0x7(%rsp)
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DeactivateHorizontalScroll() {
  unsigned char d[] = {0x2E};
  oled_SendCommand(d, sizeof(d));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D24(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D27: r

tool: D20: readIntFromFile

tool: D24: %d

tool: D0: %d


assistant: ```c
int main(void) {
  FILE *p = NULL;
  int i = 0;
  p = fopen("readIntFromFile", "r");
  fscanf(p, "%d", &i);
  printf("%d\n", i);
  fclose(p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D4(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rdx
  lea    D34(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D23
data_type: string
name: parse_data
arguments: data_label: D34
data_type: string
name: parse_data
arguments: data_label: D36
data_type: string

tool: D4: r

tool: D23: readIntFromFile

tool: D34: %d

tool: D36: %d


assistant: ```c
int main(void) {
  FILE *p = NULL;
  int i = 0;
  p = fopen("readIntFromFile", "r");
  fscanf(p, "%d", &i);
  printf("%d\n", i);
  fclose(p);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rsi
  lea    D19(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D33
type: string
name: read_data
arguments: data_label: D19
type: string
name: read_data
arguments: data_label: D29
type: string
name: read_data
arguments: data_label: D20
type: string

tool: D33: r

tool: D19: readIntFromFile

tool: D29: %d

tool: D20: %d


assistant: ```c
int main(void) {
  FILE *p = NULL;
  int i = 0;
  p = fopen("readIntFromFile", "r");
  fscanf(p, "%d", &i);
  printf("%d\n", i);
  fclose(p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rsi
  lea    D17(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D38
type_infered: string

tool: D26: r

tool: D17: readIntFromFile

tool: D13: %d

tool: D38: %d


assistant: ```c
int main(void) {
  FILE *p = NULL;
  int i = 0;
  p = fopen("readIntFromFile", "r");
  fscanf(p, "%d", &i);
  printf("%d\n", i);
  fclose(p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TOSH_long_uwait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jbe    L29
  subl   $0x4,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L13
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <TOSH_short_uwait@plt>
L13:
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  mov    %al,-0x1(%rbp)
  jmp    L11
L16:
  mov    $0xff,%edi
  mov    $0x0,%eax
  call   <TOSH_short_uwait@plt>
  movzbl -0x1(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x1(%rbp)
  nop
  nop
  nop
  nop
L11:
  cmpb   $0x0,-0x1(%rbp)
  jne    L16
L29:
  nop
  leave
  ret
```

assistant: ```c
void TOSH_long_uwait(unsigned int u_sec) {
  if (u_sec >= 4) {
    u_sec -= 4;
    {
      unsigned char u = (u_sec & 255);
      if (u > 0)
        TOSH_short_uwait(u);
      u = u_sec >> 8;
      while (u > 0) {
        TOSH_short_uwait(255);
        u--;
        asm("nop");
        asm("nop");
        asm("nop");
        asm("nop");
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TOSH_long_uwait>:
  endbr64
  cmp    $0x3,%edi
  jbe    L48
  push   %rbx
  lea    -0x4(%rdi),%ebx
  cmp    $0x4,%dil
  jne    L26
L21:
  mov    %ebx,%eax
  shr    $0x8,%eax
  mov    %eax,%ebx
  test   %al,%al
  je     L20
L28:
  mov    $0xff,%edi
  mov    $0x0,%eax
  call   <TOSH_short_uwait@plt>
  sub    $0x1,%ebx
  nop
  nop
  nop
  nop
  test   %bl,%bl
  jne    L28
L20:
  pop    %rbx
  ret
L26:
  movzbl %bl,%edi
  mov    $0x0,%eax
  call   <TOSH_short_uwait@plt>
  jmp    L21
L48:
  ret
```

assistant: ```c
void TOSH_long_uwait(unsigned int u_sec) {
  if (u_sec >= 4) {
    u_sec -= 4;
    {
      unsigned char u = (u_sec & 255);
      if (u > 0)
        TOSH_short_uwait(u);
      u = u_sec >> 8;
      while (u > 0) {
        TOSH_short_uwait(255);
        u--;
        asm("nop");
        asm("nop");
        asm("nop");
        asm("nop");
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TOSH_long_uwait>:
  endbr64
  cmp    $0x3,%edi
  jbe    L44
  push   %rbx
  lea    -0x4(%rdi),%ebx
  cmp    $0x4,%dil
  jne    L23
  mov    %ebx,%eax
  shr    $0x8,%eax
  mov    %eax,%ebx
  test   %al,%al
  je     L20
  xchg   %ax,%ax
L9:
  mov    $0xff,%edi
  xor    %eax,%eax
  sub    $0x1,%ebx
  call   <TOSH_short_uwait@plt>
  nop
  nop
  nop
  nop
  test   %bl,%bl
  jne    L9
L20:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L44:
  ret
  nopl   0x0(%rax)
L23:
  movzbl %bl,%edi
  xor    %eax,%eax
  call   <TOSH_short_uwait@plt>
  mov    %ebx,%eax
  shr    $0x8,%eax
  mov    %eax,%ebx
  test   %al,%al
  jne    L9
  jmp    L20
```

assistant: ```c
void TOSH_long_uwait(unsigned int u_sec) {
  if (u_sec >= 4) {
    u_sec -= 4;
    {
      unsigned char u = (u_sec & 255);
      if (u > 0)
        TOSH_short_uwait(u);
      u = u_sec >> 8;
      while (u > 0) {
        TOSH_short_uwait(255);
        u--;
        asm("nop");
        asm("nop");
        asm("nop");
        asm("nop");
      }
    }
  }
}
```