ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<column_get_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L27:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L20
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L17
L20:
  mov    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L35
L17:
  cmpl   $0x0,-0x4(%rbp)
  je     L71
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L35
L71:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L35:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  jmp    L10
L18:
  nop
L10:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int column_get_str(char *buffer, char *string) {
  int quote_flag = 0;
  while (*string) {
    if (*string == '"' || *string == '\'') {
      quote_flag = 1 - quote_flag;
      string++;
      continue;
    }
    if (quote_flag) {
      *buffer++ = *string++;
      continue;
    } else {
      if (isspace(*string))
        break;
      *buffer++ = *string++;
    }
  }
  *buffer = '\0';
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<column_get_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L66
  lea    0x1(%rsi),%rbx
  mov    $0x0,%r12d
  mov    $0x1,%r13d
  jmp    L16
L18:
  mov    %r13d,%eax
  sub    %r12d,%eax
  mov    %eax,%r12d
  mov    %rbx,%rax
L15:
  movzbl (%rax),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L66
L16:
  cmp    $0x22,%dil
  je     L18
  cmp    $0x27,%dil
  je     L18
  test   %r12d,%r12d
  je     L59
  mov    %rbx,%rax
  mov    %dil,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L15
L59:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L66
  mov    %rbx,%rax
  movzbl -0x1(%rbx),%edx
  mov    %dl,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L15
L66:
  movb   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int column_get_str(char *buffer, char *string) {
  int quote_flag = 0;
  while (*string) {
    if (*string == '"' || *string == '\'') {
      quote_flag = 1 - quote_flag;
      string++;
      continue;
    }
    if (quote_flag) {
      *buffer++ = *string++;
      continue;
    } else {
      if (isspace(*string))
        break;
      *buffer++ = *string++;
    }
  }
  *buffer = '\0';
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<column_get_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L82
  lea    0x1(%rsi),%rbx
  xor    %r12d,%r12d
  mov    $0x1,%r13d
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
L42:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L82
L63:
  cmp    $0x22,%dil
  je     L6
  cmp    $0x27,%dil
  je     L6
  test   %r12d,%r12d
  jne    L3
  call   <isspace@plt>
  test   %rax,%rax
  jne    L82
  movzbl -0x1(%rbx),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L63
L82:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r13d,%eax
  sub    %r12d,%eax
  mov    %eax,%r12d
  jmp    L42
```

assistant: ```c
int column_get_str(char *buffer, char *string) {
  int quote_flag = 0;
  while (*string) {
    if (*string == '"' || *string == '\'') {
      quote_flag = 1 - quote_flag;
      string++;
      continue;
    }
    if (quote_flag) {
      *buffer++ = *string++;
      continue;
    } else {
      if (isspace(*string))
        break;
      *buffer++ = *string++;
    }
  }
  *buffer = '\0';
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<column_get_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L3
  lea    0x1(%rsi),%rbx
  xor    %r12d,%r12d
  mov    $0x1,%r13d
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
L9:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L3
L43:
  cmp    $0x22,%dil
  je     L85
  cmp    $0x27,%dil
  je     L85
  test   %r12d,%r12d
  jne    L31
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  movzbl -0x1(%rbx),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L43
L3:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L85:
  mov    %r13d,%eax
  sub    %r12d,%eax
  mov    %eax,%r12d
  jmp    L9
```

assistant: ```c
int column_get_str(char *buffer, char *string) {
  int quote_flag = 0;
  while (*string) {
    if (*string == '"' || *string == '\'') {
      quote_flag = 1 - quote_flag;
      string++;
      continue;
    }
    if (quote_flag) {
      *buffer++ = *string++;
      continue;
    } else {
      if (isspace(*string))
        break;
      *buffer++ = *string++;
    }
  }
  *buffer = '\0';
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2f,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: The square of all the parts is %d


assistant: ```c
int main() {
  printf("The square of all the parts is %d\n", 7 + 5 * 7 + 5);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: The square of all the parts is %d


assistant: ```c
int main() {
  printf("The square of all the parts is %d\n", 7 + 5 * 7 + 5);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: The square of all the parts is %d


assistant: ```c
int main() {
  printf("The square of all the parts is %d\n", 7 + 5 * 7 + 5);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: The square of all the parts is %d


assistant: ```c
int main() {
  printf("The square of all the parts is %d\n", 7 + 5 * 7 + 5);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkConvertedTermValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L55
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <showBadNumeralStringMessage@plt>
  mov    $0x0,%eax
  jmp    L46
L55:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <convertedTermValueExceedsMaximumFrequency@plt>
  test   %rax,%rax
  jle    L30
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <showViolatesModernConventionMessage@plt>
  mov    $0x0,%eax
  jmp    L46
L30:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xf9f,-0x4(%rbp)
  jg     L50
  mov    -0x4(%rbp),%eax
  jmp    L46
L50:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <showTermExceedsMaximumValueMessage@plt>
  mov    $0x0,%eax
L46:
  leave
  ret
```

assistant: ```c
int checkConvertedTermValue(int convertedTermValue, int currentTotal, char *numeralString) {
  if (convertedTermValue < 0) {
    showBadNumeralStringMessage(numeralString);
    return 0;
  }
  if (convertedTermValueExceedsMaximumFrequency(convertedTermValue, numeralString) > 0) {
    showViolatesModernConventionMessage(numeralString);
    return 0;
  }
  int newTotal = currentTotal + convertedTermValue;
  if (newTotal < 4000)
    return newTotal;
  showTermExceedsMaximumValueMessage(numeralString);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checkConvertedTermValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  test   %edi,%edi
  js     L8
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %rdx,%rsi
  call   <convertedTermValueExceedsMaximumFrequency@plt>
  test   %rax,%rax
  jg     L55
  lea    (%rbx,%r12,1),%eax
  cmp    $0xf9f,%eax
  jg     L38
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    %rdx,%rdi
  call   <showBadNumeralStringMessage@plt>
  mov    $0x0,%eax
  jmp    L17
L55:
  mov    %rbp,%rdi
  call   <showViolatesModernConventionMessage@plt>
  mov    $0x0,%eax
  jmp    L17
L38:
  mov    %rbp,%rdi
  call   <showTermExceedsMaximumValueMessage@plt>
  mov    $0x0,%eax
  jmp    L17
```

assistant: ```c
int checkConvertedTermValue(int convertedTermValue, int currentTotal, char *numeralString) {
  if (convertedTermValue < 0) {
    showBadNumeralStringMessage(numeralString);
    return 0;
  }
  if (convertedTermValueExceedsMaximumFrequency(convertedTermValue, numeralString) > 0) {
    showViolatesModernConventionMessage(numeralString);
    return 0;
  }
  int newTotal = currentTotal + convertedTermValue;
  if (newTotal < 4000)
    return newTotal;
  showTermExceedsMaximumValueMessage(numeralString);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkConvertedTermValue>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  test   %edi,%edi
  js     L20
  mov    %esi,%r12d
  mov    %rdx,%rsi
  mov    %edi,%ebx
  call   <convertedTermValueExceedsMaximumFrequency@plt>
  test   %rax,%rax
  jg     L22
  lea    (%rbx,%r12,1),%eax
  cmp    $0xf9f,%eax
  jg     L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rdi
  call   <showTermExceedsMaximumValueMessage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rdx,%rdi
  call   <showBadNumeralStringMessage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L22:
  mov    %rbp,%rdi
  call   <showViolatesModernConventionMessage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int checkConvertedTermValue(int convertedTermValue, int currentTotal, char *numeralString) {
  if (convertedTermValue < 0) {
    showBadNumeralStringMessage(numeralString);
    return 0;
  }
  if (convertedTermValueExceedsMaximumFrequency(convertedTermValue, numeralString) > 0) {
    showViolatesModernConventionMessage(numeralString);
    return 0;
  }
  int newTotal = currentTotal + convertedTermValue;
  if (newTotal < 4000)
    return newTotal;
  showTermExceedsMaximumValueMessage(numeralString);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkConvertedTermValue>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  test   %edi,%edi
  js     L6
  mov    %esi,%r12d
  mov    %rdx,%rsi
  mov    %edi,%ebx
  call   <convertedTermValueExceedsMaximumFrequency@plt>
  test   %rax,%rax
  jg     L20
  lea    (%rbx,%r12,1),%eax
  cmp    $0xf9f,%eax
  jg     L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  mov    %rbp,%rdi
  call   <showTermExceedsMaximumValueMessage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdx,%rdi
  call   <showBadNumeralStringMessage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L20:
  mov    %rbp,%rdi
  call   <showViolatesModernConventionMessage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int checkConvertedTermValue(int convertedTermValue, int currentTotal, char *numeralString) {
  if (convertedTermValue < 0) {
    showBadNumeralStringMessage(numeralString);
    return 0;
  }
  if (convertedTermValueExceedsMaximumFrequency(convertedTermValue, numeralString) > 0) {
    showViolatesModernConventionMessage(numeralString);
    return 0;
  }
  int newTotal = currentTotal + convertedTermValue;
  if (newTotal < 4000)
    return newTotal;
  showTermExceedsMaximumValueMessage(numeralString);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decodeCell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x2e,%eax
  je     L33
  cmp    $0x4f,%eax
  jne    L7
  mov    $0x1,%eax
  jmp    L6
L33:
  mov    $0x2,%eax
  jmp    L6
L7:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int decodeCell(char c) {
  switch (c) {
  case 'O':
    return 1;
  case '.':
    return 2;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decodeCell>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x2e,%dil
  je     L8
  cmp    $0x4f,%dil
  sete   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int decodeCell(char c) {
  switch (c) {
  case 'O':
    return 1;
  case '.':
    return 2;
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<decodeCell>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x2e,%dil
  je     L6
  xor    %eax,%eax
  cmp    $0x4f,%dil
  sete   %al
L6:
  ret
```

assistant: ```c
int decodeCell(char c) {
  switch (c) {
  case 'O':
    return 1;
  case '.':
    return 2;
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<decodeCell>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x2e,%dil
  je     L4
  xor    %eax,%eax
  cmp    $0x4f,%dil
  sete   %al
L4:
  ret
```

assistant: ```c
int decodeCell(char c) {
  switch (c) {
  case 'O':
    return 1;
  case '.':
    return 2;
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<d_pthread_mutex_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int d_pthread_mutex_unlock(pthread_mutex_t *mutex) {
  int err = pthread_mutex_unlock(mutex);
  assert(err != EPERM);
  assert(err == 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<d_pthread_mutex_unlock>:
  endbr64
  push   %rbx
  call   <pthread_mutex_unlock@plt>
  mov    %eax,%ebx
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebx,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int d_pthread_mutex_unlock(pthread_mutex_t *mutex) {
  int err = pthread_mutex_unlock(mutex);
  assert(err != EPERM);
  assert(err == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<d_pthread_mutex_unlock>:
  endbr64
  push   %rbx
  call   <pthread_mutex_unlock@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebx,%ebx
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int d_pthread_mutex_unlock(pthread_mutex_t *mutex) {
  int err = pthread_mutex_unlock(mutex);
  assert(err != EPERM);
  assert(err == 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<d_pthread_mutex_unlock>:
  endbr64
  push   %rbx
  call   <pthread_mutex_unlock@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebx,%ebx
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int d_pthread_mutex_unlock(pthread_mutex_t *mutex) {
  int err = pthread_mutex_unlock(mutex);
  assert(err != EPERM);
  assert(err == 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L39
L30:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <id>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L23
  mov    $0x3,%eax
  jmp    L39
L23:
  mov    -0x4(%rbp),%eax
L39:
  leave
  ret
```

assistant: ```c
int id(int x) {
  if (x == 0)
    return 0;
  int ret = id(x - 1) + 1;
  if (ret > 3)
    return 3;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<id>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%edi
  call   <id>
  add    $0x1,%eax
  mov    $0x3,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int id(int x) {
  if (x == 0)
    return 0;
  int ret = id(x - 1) + 1;
  if (ret > 3)
    return 3;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<id>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jne    L20
L25:
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x1,%edi
  je     L25
  cmp    $0x2,%edi
  je     L25
  cmp    $0x3,%edi
  je     L25
  sub    $0x8,%rsp
  lea    -0x4(%rdi),%edi
  call   <id>
  mov    $0x3,%edx
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int id(int x) {
  if (x == 0)
    return 0;
  int ret = id(x - 1) + 1;
  if (ret > 3)
    return 3;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<id>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jne    L4
L22:
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  cmp    $0x1,%edi
  je     L22
  cmp    $0x2,%edi
  je     L22
  cmp    $0x3,%edi
  je     L22
  sub    $0x8,%rsp
  lea    -0x4(%rdi),%edi
  call   <id>
  mov    $0x3,%edx
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int id(int x) {
  if (x == 0)
    return 0;
  int ret = id(x - 1) + 1;
  if (ret > 3)
    return 3;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <crash@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  extern void crash(void);
  crash();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <crash@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  extern void crash(void);
  crash();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <crash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  extern void crash(void);
  crash();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <crash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  extern void crash(void);
  crash();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<altermap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L0:
  addl   $0x1,-0x4(%rbp)
L29:
  cmpl   $0x6,-0x4(%rbp)
  jle    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void altermap(basemap, basemul, modmap, modmul) char basemap[7], modmap[7];
int basemul[7], modmul[7];
{
  int i;
  for (i = 0; i < 7; i++) {
    if (modmap[i] != ' ') {
      basemap[i] = modmap[i];
      basemul[i] = modmul[i];
    };
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<altermap>:
  endbr64
  mov    $0x0,%eax
  jmp    L36
L26:
  add    $0x1,%rax
  cmp    $0x7,%rax
  je     L14
L36:
  movzbl (%rdx,%rax,1),%r8d
  cmp    $0x20,%r8b
  je     L26
  mov    %r8b,(%rdi,%rax,1)
  mov    (%rcx,%rax,4),%r8d
  mov    %r8d,(%rsi,%rax,4)
  jmp    L26
L14:
  ret
```

assistant: ```c
void altermap(basemap, basemul, modmap, modmul) char basemap[7], modmap[7];
int basemul[7], modmul[7];
{
  int i;
  for (i = 0; i < 7; i++) {
    if (modmap[i] != ' ') {
      basemap[i] = modmap[i];
      basemul[i] = modmul[i];
    };
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<altermap>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl (%rdx,%rax,1),%r8d
  cmp    $0x20,%r8b
  je     L18
  mov    %r8b,(%rdi,%rax,1)
  mov    (%rcx,%rax,4),%r8d
  mov    %r8d,(%rsi,%rax,4)
L18:
  add    $0x1,%rax
  cmp    $0x7,%rax
  jne    L2
  ret
```

assistant: ```c
void altermap(basemap, basemul, modmap, modmul) char basemap[7], modmap[7];
int basemul[7], modmul[7];
{
  int i;
  for (i = 0; i < 7; i++) {
    if (modmap[i] != ' ') {
      basemap[i] = modmap[i];
      basemul[i] = modmul[i];
    };
  };
}
```