ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_sll>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
L3:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L3
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  mov    %rsp,%rbx
  jmp    L16
L44:
  mov    %rbx,%rdi
  call   <chain_node@plt>
L16:
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L44
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  mov    %rsp,%rbx
L4:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L4
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  while (___sl_get_nondet_int())
    chain_node(&list);
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<create_sll>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   (%rax)
L0:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L0
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  jmp    L34
  xchg   %ax,%ax
L11:
  mov    %rbx,%rdi
  call   <chain_node@plt>
L34:
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L11
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  nopl   0x0(%rax)
L20:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L20
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  while (___sl_get_nondet_int())
    chain_node(&list);
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<create_sll>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   (%rax)
L32:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L32
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  jmp    L1
  xchg   %ax,%ax
L47:
  mov    %rbx,%rdi
  call   <chain_node@plt>
L1:
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L47
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L28
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  while (___sl_get_nondet_int())
    chain_node(&list);
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <chpl_run@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
datatype: string
name: parse_data
arguments: data_label: D8
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: D25: ls -la

tool: D8: output:
%s


tool: D10: result = %i


assistant: ```c
int main() {
  const char *cmd = "ls -la";
  const char *output;
  int result = chpl_run(cmd, &output);
  printf("output:\n%s\n", output);
  printf("result = %i\n", result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <chpl_run@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D17
data_type: string

tool: D27: ls -la

tool: D22: output:
%s


tool: D17: result = %i


assistant: ```c
int main() {
  const char *cmd = "ls -la";
  const char *output;
  int result = chpl_run(cmd, &output);
  printf("output:\n%s\n", output);
  printf("result = %i\n", result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <chpl_run@plt>
  mov    (%rsp),%rsi
  lea    D14(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
datatype: string
name: extract_symbolic_data
arguments: tag: D14
datatype: string
name: extract_symbolic_data
arguments: tag: D12
datatype: string

tool: D24: ls -la

tool: D14: output:
%s


tool: D12: result = %i


assistant: ```c
int main() {
  const char *cmd = "ls -la";
  const char *output;
  int result = chpl_run(cmd, &output);
  printf("output:\n%s\n", output);
  printf("result = %i\n", result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <chpl_run@plt>
  mov    (%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string

tool: D21: ls -la

tool: D15: output:
%s


tool: D26: result = %i


assistant: ```c
int main() {
  const char *cmd = "ls -la";
  const char *output;
  int result = chpl_run(cmd, &output);
  printf("output:\n%s\n", output);
  printf("result = %i\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x0,%ebx
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L31
L16:
  mov    -0x24(%rbp),%eax
  lea    D43(%rip),%rdx
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  addl   $0x1,-0x24(%rbp)
L31:
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,-0x40(%rbp)
  ja     L16
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L30
L7:
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L41
L34:
  mov    -0x20(%rbp),%eax
  cltq
  imul   -0x40(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  addl   $0x1,-0x1c(%rbp)
L41:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x40(%rbp)
  ja     L34
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  addl   $0x1,-0x20(%rbp)
L30:
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  ja     L7
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
data_type: string
name: retrieve_data
arguments: data_tag: D43
data_type: string
name: retrieve_data
arguments: data_tag: D32
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D62
data_type: string

tool: D39: 	

tool: 

tool: D32: j=%d%5s	

tool: D3: 


tool: D1: i=%d	

tool: D62: %f	

assistant: ```c
void printMatrix(const size_t m, const size_t n, mpfr_t array[m][n]) {
  printf("\t");
  for (int j = 0; j < n; ++j) {
    mpfr_printf("j=%d%5s\t", j, "");
  }
  printf("\n");
  for (int i = 0; i < m; ++i) {
    mpfr_printf("i=%d\t", i);
    for (int j = 0; j < n; ++j) {
      mpfr_printf("%f\t", array[i][j]);
    }
    mpfr_printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%r15
  lea    D12(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L5
  mov    $0x0,%ebx
  lea    D52(%rip),%r13
  lea    D46(%rip),%r12
L21:
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L21
L5:
  lea    D63(%rip),%rdi
  call   <printf@plt>
  cmpq   $0x0,(%rsp)
  je     L8
  lea    0x0(,%rbp,4),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r14d
  lea    D31(%rip),%r13
L59:
  mov    %r14d,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  test   %rbp,%rbp
  je     L33
  mov    %r15,%r12
  mov    $0x0,%ebx
L26:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L26
L33:
  lea    D63(%rip),%rdi
  mov    $0x0,%eax
  call   <mpfr_printf@plt>
  add    $0x1,%r14
  add    0x8(%rsp),%r15
  cmp    (%rsp),%r14
  jne    L59
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D52
type: string
name: parse_data
arguments: label: D46
type: string
name: parse_data
arguments: label: D63
type: string
name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D23
type: string

tool: D12: 	

tool: 

tool: D46: j=%d%5s	

tool: D63: 


tool: D31: %f	

tool: D23: i=%d	

assistant: ```c
void printMatrix(const size_t m, const size_t n, mpfr_t array[m][n]) {
  printf("\t");
  for (int j = 0; j < n; ++j) {
    mpfr_printf("j=%d%5s\t", j, "");
  }
  printf("\n");
  for (int i = 0; i < m; ++i) {
    mpfr_printf("i=%d\t", i);
    for (int j = 0; j < n; ++j) {
      mpfr_printf("%f\t", array[i][j]);
    }
    mpfr_printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  lea    D42(%rip),%rdi
  call   <printf@plt>
  test   %rbx,%rbx
  je     L38
  xor    %r12d,%r12d
  lea    D55(%rip),%r14
  lea    D52(%rip),%r13
  xchg   %ax,%ax
L30:
  mov    %r12d,%esi
  mov    %r14,%rdx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <mpfr_printf@plt>
  add    $0x1,%r12
  cmp    %r12,%rbx
  jne    L30
L38:
  lea    D0(%rip),%r14
  mov    %r14,%rdi
  call   <printf@plt>
  cmpq   $0x0,(%rsp)
  je     L18
  lea    0x0(,%rbx,4),%rax
  xor    %r13d,%r13d
  lea    D36(%rip),%r12
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  mov    %r13d,%esi
  lea    D13(%rip),%rdi
  call   <mpfr_printf@plt>
  test   %rbx,%rbx
  je     L54
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L36:
  mov    0x0(%rbp,%r15,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <mpfr_printf@plt>
  cmp    %r15,%rbx
  jne    L36
L54:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <mpfr_printf@plt>
  add    0x8(%rsp),%rbp
  cmp    (%rsp),%r13
  jne    L20
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D42
type: string
name: read_data
arguments: tag: D55
type: string
name: read_data
arguments: tag: D52
type: string
name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D36
type: string
name: read_data
arguments: tag: D13
type: string

tool: D42: 	

tool: 

tool: D52: j=%d%5s	

tool: D0: 


tool: D36: %f	

tool: D13: i=%d	

assistant: ```c
void printMatrix(const size_t m, const size_t n, mpfr_t array[m][n]) {
  printf("\t");
  for (int j = 0; j < n; ++j) {
    mpfr_printf("j=%d%5s\t", j, "");
  }
  printf("\n");
  for (int i = 0; i < m; ++i) {
    mpfr_printf("i=%d\t", i);
    for (int j = 0; j < n; ++j) {
      mpfr_printf("%f\t", array[i][j]);
    }
    mpfr_printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  lea    D58(%rip),%rdi
  call   <printf@plt>
  test   %rbx,%rbx
  je     L57
  xor    %r12d,%r12d
  lea    D40(%rip),%r14
  lea    D15(%rip),%r13
  xchg   %ax,%ax
L6:
  mov    %r12d,%esi
  mov    %r14,%rdx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <mpfr_printf@plt>
  add    $0x1,%r12
  cmp    %rbx,%r12
  jne    L6
L57:
  lea    D51(%rip),%r14
  mov    %r14,%rdi
  call   <printf@plt>
  cmpq   $0x0,(%rsp)
  je     L19
  lea    0x0(,%rbx,4),%rax
  xor    %r13d,%r13d
  lea    D28(%rip),%r12
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  mov    %r13d,%esi
  lea    D5(%rip),%rdi
  call   <mpfr_printf@plt>
  test   %rbx,%rbx
  je     L32
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L51:
  mov    0x0(%rbp,%r15,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <mpfr_printf@plt>
  cmp    %r15,%rbx
  jne    L51
L32:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <mpfr_printf@plt>
  add    0x8(%rsp),%rbp
  cmp    (%rsp),%r13
  jne    L42
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D58
type_infered: string
name: disassemble_data
arguments: tag: D40
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D51
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D58: 	

tool: 

tool: D15: j=%d%5s	

tool: D51: 


tool: D28: %f	

tool: D5: i=%d	

assistant: ```c
void printMatrix(const size_t m, const size_t n, mpfr_t array[m][n]) {
  printf("\t");
  for (int j = 0; j < n; ++j) {
    mpfr_printf("j=%d%5s\t", j, "");
  }
  printf("\n");
  for (int i = 0; i < m; ++i) {
    mpfr_printf("i=%d\t", i);
    for (int j = 0; j < n; ++j) {
      mpfr_printf("%f\t", array[i][j]);
    }
    mpfr_printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<res_tmp_txt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    $0x0,%eax
  call   <res_tmp_txt_start@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
L11:
  cmpq   $0x0,-0x10(%rbp)
  je     L7
  mov    $0x0,%eax
  call   <res_tmp_txt_size@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
L7:
  cmpq   $0x0,-0x18(%rbp)
  je     L27
  mov    $0x0,%eax
  call   <res_tmp_txt_end@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
L27:
  nop
  leave
  ret
```

assistant: ```c
void res_tmp_txt(const char **start, size_t *size, const char **end) {
  if (start)
    *start = res_tmp_txt_start();
  if (size)
    *size = res_tmp_txt_size();
  if (end)
    *end = res_tmp_txt_end();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<res_tmp_txt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%r12
  mov    $0x0,%eax
  call   <res_tmp_txt_start@plt>
  mov    %rax,(%r12)
L0:
  test   %rbp,%rbp
  je     L6
  mov    $0x0,%eax
  call   <res_tmp_txt_size@plt>
  mov    %rax,0x0(%rbp)
L6:
  test   %rbx,%rbx
  je     L4
  mov    $0x0,%eax
  call   <res_tmp_txt_end@plt>
  mov    %rax,(%rbx)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void res_tmp_txt(const char **start, size_t *size, const char **end) {
  if (start)
    *start = res_tmp_txt_start();
  if (size)
    *size = res_tmp_txt_size();
  if (end)
    *end = res_tmp_txt_end();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<res_tmp_txt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L21
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <res_tmp_txt_start@plt>
  mov    %rax,(%r12)
L21:
  test   %rbp,%rbp
  je     L0
  xor    %eax,%eax
  call   <res_tmp_txt_size@plt>
  mov    %rax,0x0(%rbp)
L0:
  test   %rbx,%rbx
  je     L28
  xor    %eax,%eax
  call   <res_tmp_txt_end@plt>
  mov    %rax,(%rbx)
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void res_tmp_txt(const char **start, size_t *size, const char **end) {
  if (start)
    *start = res_tmp_txt_start();
  if (size)
    *size = res_tmp_txt_size();
  if (end)
    *end = res_tmp_txt_end();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<res_tmp_txt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L0
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <res_tmp_txt_start@plt>
  mov    %rax,(%r12)
L0:
  test   %rbp,%rbp
  je     L16
  xor    %eax,%eax
  call   <res_tmp_txt_size@plt>
  mov    %rax,0x0(%rbp)
L16:
  test   %rbx,%rbx
  je     L9
  xor    %eax,%eax
  call   <res_tmp_txt_end@plt>
  mov    %rax,(%rbx)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void res_tmp_txt(const char **start, size_t *size, const char **end) {
  if (start)
    *start = res_tmp_txt_start();
  if (size)
    *size = res_tmp_txt_size();
  if (end)
    *end = res_tmp_txt_end();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BNCFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x63,-0x4(%rbp)
  mov    $0x15,%edi
  call   <BNCIO@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int BNCFunction() {
  int ii, stat = 99;
  char com1, data;
  BNCIO(21);
  return (stat);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BNCFunction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%edi
  call   <BNCIO@plt>
  mov    $0x63,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int BNCFunction() {
  int ii, stat = 99;
  char com1, data;
  BNCIO(21);
  return (stat);
}
```
user: Translate the below assembly code into C programming language:

```asm
<BNCFunction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%edi
  call   <BNCIO@plt>
  mov    $0x63,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int BNCFunction() {
  int ii, stat = 99;
  char com1, data;
  BNCIO(21);
  return (stat);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BNCFunction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%edi
  call   <BNCIO@plt>
  mov    $0x63,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int BNCFunction() {
  int ii, stat = 99;
  char com1, data;
  BNCIO(21);
  return (stat);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <esc@plt>
  mov    $0x5,%edi
  call   <extra_padding@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: M

assistant: ```c
void ri(void) {
  esc("M");
  extra_padding(5);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ri>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <esc@plt>
  mov    $0x5,%edi
  call   <extra_padding@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: M

assistant: ```c
void ri(void) {
  esc("M");
  extra_padding(5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ri>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <esc@plt>
  mov    $0x5,%edi
  add    $0x8,%rsp
  jmp    1070 <extra_padding@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: M

assistant: ```c
void ri(void) {
  esc("M");
  extra_padding(5);
}
```
user: What is the c source code of the assembly code below:

```asm
<ri>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <esc@plt>
  mov    $0x5,%edi
  add    $0x8,%rsp
  jmp    1070 <extra_padding@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: M

assistant: ```c
void ri(void) {
  esc("M");
  extra_padding(5);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<emalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x1,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string
name: parse_data
arguments: tag: D13
data_type: string

tool: 

tool: D13: out of memory

assistant: ```c
void *emalloc(size_t n) {
  void *rv;
  if ((rv = malloc(n)) == NULL)
    fatal("out of memory", "", 1);
  return rv;
}
```