ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unmsf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x1d0,%rsp
  mov    %esi,0xc(%rsp)
  lea    0x10(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  call   <msf_unpack_init@plt>
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    $0x1b0,%edx
  call   <memset@plt>
  mov    $0x1,%esi
  mov    $0x3e6c,%edi
  call   <calloc@plt>
  test   %rax,%rax
  je     L31
  mov    %rax,%rbp
  mov    %r14,%rdi
  lea    0xc(%rsp),%rcx
  mov    %r13,%rdx
  movabs $0x1000000000002,%rax
  mov    %r12d,%esi
  mov    %rbp,0x20(%rsp)
  mov    %rax,0x18(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x1f3600000001,%rax
  mov    %rbx,0x24(%rsp)
  movq   $0x3,0x10(%rsp)
  mov    %r12d,0x38(%rsp)
  movl   $0x0,0x34(%rsp)
  movq   $0x0,0x3c(%rsp)
  mov    %rax,0x60(%rsp)
  movl   $0x0,0x68(%rsp)
  call   <msf_unpack@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  test   %ebx,%ebx
  jne    L31
  mov    0x34(%rsp),%eax
L9:
  mov    0x1c8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x1d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L31:
  mov    $0xffffffff,%eax
  jmp    L9
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unmsf(void *in, int insz, void *out, int outsz) {
  int ret;
  unsigned char esi[0x1b0], *tmp;
  msf_unpack_init();
  memset(esi, 0, sizeof(esi));
  tmp = calloc(0x3e6c, 1);
  if (!tmp)
    return (-1);
  *(int *)(esi) = 3;
  *(int *)(esi + 0x04) = 0;
  *(int *)(esi + 0x08) = 2;
  *(int *)(esi + 0x0c) = 0x10000;
  *(int *)(esi + 0x54) = 0x1f36;
  *(void **)(esi + 0x10) = tmp;
  *(void **)(esi + 0x14) = out;
  *(int *)(esi + 0x28) = outsz;
  *(int *)(esi + 0x24) = 0;
  *(int *)(esi + 0x4c) = 1;
  *(int *)(esi + 0x48) = 0;
  *(int *)(esi + 0x58) = 0;
  *(int *)(esi + 0x2c) = 0;
  *(int *)(esi + 0x30) = 0;
  *(int *)(esi + 0x50) = 1;
  ret = msf_unpack(esi, outsz, in, &insz);
  free(tmp);
  if (ret)
    return (-1);
  return (*(int *)(esi + 0x24));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unmsf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x1d0,%rsp
  mov    %esi,0xc(%rsp)
  lea    0x10(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  call   <msf_unpack_init@plt>
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    $0x1b0,%edx
  call   <memset@plt>
  mov    $0x1,%esi
  mov    $0x3e6c,%edi
  call   <calloc@plt>
  test   %rax,%rax
  je     L0
  mov    %r14,%rdi
  lea    0xc(%rsp),%rcx
  mov    %r13,%rdx
  mov    %r12d,%esi
  movdqa D7(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  mov    %rax,%rbp
  mov    %rbx,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %r12d,0x38(%rsp)
  movl   $0x0,0x34(%rsp)
  movl   $0x0,0x68(%rsp)
  movq   $0x0,0x3c(%rsp)
  movups %xmm0,0x58(%rsp)
  call   <msf_unpack@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  test   %ebx,%ebx
  jne    L0
  mov    0x34(%rsp),%eax
L31:
  mov    0x1c8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x1d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  jmp    L31
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D5
type_guessed: byte[16]

tool: {"D7": [0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x01,0x00]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x36,0x1f,0x00,0x00]}

assistant: ```c
int unmsf(void *in, int insz, void *out, int outsz) {
  int ret;
  unsigned char esi[0x1b0], *tmp;
  msf_unpack_init();
  memset(esi, 0, sizeof(esi));
  tmp = calloc(0x3e6c, 1);
  if (!tmp)
    return (-1);
  *(int *)(esi) = 3;
  *(int *)(esi + 0x04) = 0;
  *(int *)(esi + 0x08) = 2;
  *(int *)(esi + 0x0c) = 0x10000;
  *(int *)(esi + 0x54) = 0x1f36;
  *(void **)(esi + 0x10) = tmp;
  *(void **)(esi + 0x14) = out;
  *(int *)(esi + 0x28) = outsz;
  *(int *)(esi + 0x24) = 0;
  *(int *)(esi + 0x4c) = 1;
  *(int *)(esi + 0x48) = 0;
  *(int *)(esi + 0x58) = 0;
  *(int *)(esi + 0x2c) = 0;
  *(int *)(esi + 0x30) = 0;
  *(int *)(esi + 0x50) = 1;
  ret = msf_unpack(esi, outsz, in, &insz);
  free(tmp);
  if (ret)
    return (-1);
  return (*(int *)(esi + 0x24));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ui@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  ui();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ui@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  ui();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ui@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  ui();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ui@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  ui();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mpfrsetstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  mov    $0xa,%edx
  mov    %eax,%edi
  call   <mpfr_set_str@plt>
  nop
  leave
  ret
```

assistant: ```c
void mpfrsetstr(mpfr_t r1, char *chr1, mpfr_rnd_t *irnd) {
  int n1;
  n1 = *irnd;
  mpfr_set_str(r1, chr1, 10, n1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mpfrsetstr>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdx),%ecx
  mov    $0xa,%edx
  call   <mpfr_set_str@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void mpfrsetstr(mpfr_t r1, char *chr1, mpfr_rnd_t *irnd) {
  int n1;
  n1 = *irnd;
  mpfr_set_str(r1, chr1, 10, n1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mpfrsetstr>:
  endbr64
  mov    (%rdx),%ecx
  mov    $0xa,%edx
  jmp    1050 <mpfr_set_str@plt>
```

assistant: ```c
void mpfrsetstr(mpfr_t r1, char *chr1, mpfr_rnd_t *irnd) {
  int n1;
  n1 = *irnd;
  mpfr_set_str(r1, chr1, 10, n1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mpfrsetstr>:
  endbr64
  mov    (%rdx),%ecx
  mov    $0xa,%edx
  jmp    1050 <mpfr_set_str@plt>
```

assistant: ```c
void mpfrsetstr(mpfr_t r1, char *chr1, mpfr_rnd_t *irnd) {
  int n1;
  n1 = *irnd;
  mpfr_set_str(r1, chr1, 10, n1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<u8_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <u8_strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L1
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L1:
  leave
  ret
```

assistant: ```c
u_int32_t *u8_strncpy(u_int32_t *dest, const u_int32_t *src, size_t n) {
  int future_length = u8_strlen(dest) + n;
  if (NULL == (dest = (u_int32_t *)memcpy(dest, src, n * sizeof(u_int32_t)))) {
    return NULL;
  }
  dest[future_length] = '\0';
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<u8_strncpy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <u8_strlen@plt>
  lea    (%rax,%r12,1),%ebx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  test   %rax,%rax
  je     L4
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0x0,%eax
  jmp    L13
```

assistant: ```c
u_int32_t *u8_strncpy(u_int32_t *dest, const u_int32_t *src, size_t n) {
  int future_length = u8_strlen(dest) + n;
  if (NULL == (dest = (u_int32_t *)memcpy(dest, src, n * sizeof(u_int32_t)))) {
    return NULL;
  }
  dest[future_length] = '\0';
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<u8_strncpy>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <u8_strlen@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    (%rax,%r12,1),%ebx
  call   <memcpy@plt>
  test   %rax,%rax
  je     L3
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
u_int32_t *u8_strncpy(u_int32_t *dest, const u_int32_t *src, size_t n) {
  int future_length = u8_strlen(dest) + n;
  if (NULL == (dest = (u_int32_t *)memcpy(dest, src, n * sizeof(u_int32_t)))) {
    return NULL;
  }
  dest[future_length] = '\0';
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<u8_strncpy>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <u8_strlen@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    (%rax,%r12,1),%ebx
  call   <memcpy@plt>
  test   %rax,%rax
  je     L0
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
u_int32_t *u8_strncpy(u_int32_t *dest, const u_int32_t *src, size_t n) {
  int future_length = u8_strlen(dest) + n;
  if (NULL == (dest = (u_int32_t *)memcpy(dest, src, n * sizeof(u_int32_t)))) {
    return NULL;
  }
  dest[future_length] = '\0';
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xc,-0x4(%rbp)
L7:
  jmp    L7
```

assistant: ```c
void fun(void) {
  int decl1;
  int decl2;
  switch (decl2) {
  case 1:
  case 'a':
  default:
    decl1 = 12;
  }
  do {
    for (;;)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      if (0)
                        if (0)
                          1;
  } while (0);
  if (0)
    if (0)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      1;
  if (0)
    if (0)
      1;
    else
      while (1)
        2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun>:
  endbr64
L7:
  jmp    L7
```

assistant: ```c
void fun(void) {
  int decl1;
  int decl2;
  switch (decl2) {
  case 1:
  case 'a':
  default:
    decl1 = 12;
  }
  do {
    for (;;)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      if (0)
                        if (0)
                          1;
  } while (0);
  if (0)
    if (0)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      1;
  if (0)
    if (0)
      1;
    else
      while (1)
        2;
}
```
user: What is the c source code of the assembly code below:

```asm
<fun>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void fun(void) {
  int decl1;
  int decl2;
  switch (decl2) {
  case 1:
  case 'a':
  default:
    decl1 = 12;
  }
  do {
    for (;;)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      if (0)
                        if (0)
                          1;
  } while (0);
  if (0)
    if (0)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      1;
  if (0)
    if (0)
      1;
    else
      while (1)
        2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fun>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void fun(void) {
  int decl1;
  int decl2;
  switch (decl2) {
  case 1:
  case 'a':
  default:
    decl1 = 12;
  }
  do {
    for (;;)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      if (0)
                        if (0)
                          1;
  } while (0);
  if (0)
    if (0)
      if (0)
        if (0)
          if (0)
            if (0)
              if (0)
                if (0)
                  if (0)
                    if (0)
                      1;
  if (0)
    if (0)
      1;
    else
      while (1)
        2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RSA_padding_add_PKCS1_type_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L3
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L7
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x1,(%rax)
  mov    -0x1c(%rbp),%eax
  sub    $0x3,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_1(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int j;
  unsigned char *p;
  if (flen > (tlen - RSA_PKCS1_PADDING_SIZE)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_1, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 1;
  j = tlen - 3 - flen;
  memset(p, 0xff, j);
  p += j;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RSA_padding_add_PKCS1_type_1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %ecx,%ebp
  mov    D10(%rip),%rax
  mov    %esi,%ecx
  sub    (%rax),%ecx
  cmp    %ebp,%ecx
  jl     L10
  mov    %rdx,%r13
  movb   $0x0,(%rdi)
  lea    0x2(%rdi),%r12
  movb   $0x1,0x1(%rdi)
  lea    -0x3(%rsi),%ebx
  sub    %ebp,%ebx
  mov    %ebx,%edx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  movslq %ebx,%rbx
  add    %rbx,%r12
  movb   $0x0,(%r12)
  lea    0x1(%r12),%rdi
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x1,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    D26(%rip),%rax
  mov    (%rax),%esi
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L13
```

assistant: ```c
int RSA_padding_add_PKCS1_type_1(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int j;
  unsigned char *p;
  if (flen > (tlen - RSA_PKCS1_PADDING_SIZE)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_1, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 1;
  j = tlen - 3 - flen;
  memset(p, 0xff, j);
  p += j;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RSA_padding_add_PKCS1_type_1>:
  endbr64
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  mov    %esi,%ecx
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D14(%rip),%rax
  sub    (%rax),%ecx
  cmp    %r12d,%ecx
  jl     L4
  mov    $0x100,%eax
  lea    -0x3(%rsi),%ebx
  mov    %rdx,%r13
  mov    $0xff,%esi
  sub    %r12d,%ebx
  mov    %ax,(%rdi)
  lea    0x2(%rdi),%rbp
  mov    %ebx,%edx
  movslq %ebx,%rbx
  mov    %rbp,%rdi
  add    %rbx,%rbp
  call   <memset@plt>
  movb   $0x0,0x0(%rbp)
  lea    0x1(%rbp),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L4:
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_1(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int j;
  unsigned char *p;
  if (flen > (tlen - RSA_PKCS1_PADDING_SIZE)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_1, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 1;
  j = tlen - 3 - flen;
  memset(p, 0xff, j);
  p += j;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RSA_padding_add_PKCS1_type_1>:
  endbr64
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  mov    %esi,%ecx
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D24(%rip),%rax
  sub    (%rax),%ecx
  cmp    %r12d,%ecx
  jl     L9
  mov    $0x100,%eax
  lea    -0x3(%rsi),%ebx
  mov    %rdx,%r13
  mov    $0xff,%esi
  sub    %r12d,%ebx
  mov    %ax,(%rdi)
  lea    0x2(%rdi),%rbp
  mov    %ebx,%edx
  movslq %ebx,%rbx
  mov    %rbp,%rdi
  add    %rbx,%rbp
  call   <memset@plt>
  movb   $0x0,0x0(%rbp)
  lea    0x1(%rbp),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L9:
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_1(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int j;
  unsigned char *p;
  if (flen > (tlen - RSA_PKCS1_PADDING_SIZE)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_1, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 1;
  j = tlen - 3 - flen;
  memset(p, 0xff, j);
  p += j;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L22:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L22
  cmpb   $0x9,-0x5(%rbp)
  je     L22
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L34
  cmpb   $0x2e,-0x5(%rbp)
  je     L34
  movsbl -0x5(%rbp),%eax
  jmp    L68
L34:
  movl   $0x0,-0x4(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L0
  cmpb   $0x2e,-0x5(%rbp)
  je     L0
  nop
L91:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L91
L0:
  cmpb   $0x2e,-0x5(%rbp)
  jne    L42
  nop
L25:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L25
L42:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D9(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L75
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L75:
  mov    $0x30,%eax
L68:
  leave
  ret
```

assistant: ```c
int getop(char str[]) {
  int i;
  char ch;
  while ((str[0] = ch = getch()) == ' ' || ch == '\t')
    ;
  str[1] = '\0';
  if (!isdigit(ch) && ch != '.') {
    return ch;
  }
  i = 0;
  if (isdigit(ch) && ch != '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  if (ch == '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  str[i] = '\0';
  if (ch != EOF) {
    ungetch(ch);
  }
  return '0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L65:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%al
  je     L65
  cmp    $0x20,%al
  je     L65
  movb   $0x0,0x1(%rbp)
  movsbl %al,%r12d
  mov    %r12d,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%bl
  setne  %r13b
  test   %rax,%rax
  jne    L86
  test   %r13b,%r13b
  jne    L38
L86:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L95
  test   %r13b,%r13b
  jne    L31
L95:
  mov    $0x0,%r13d
L19:
  cmp    $0x2e,%bl
  je     L122
L78:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    $0x30,%r12d
  mov    D5(%rip),%rax
  cmp    %bl,(%rax)
  jne    L126
L38:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    $0x1,%r12d
L96:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L96
  jmp    L19
L122:
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L104:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L104
  jmp    L78
L126:
  movsbl %bl,%edi
  call   <ungetch@plt>
  jmp    L38
```

assistant: ```c
int getop(char str[]) {
  int i;
  char ch;
  while ((str[0] = ch = getch()) == ' ' || ch == '\t')
    ;
  str[1] = '\0';
  if (!isdigit(ch) && ch != '.') {
    return ch;
  }
  i = 0;
  if (isdigit(ch) && ch != '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  if (ch == '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  str[i] = '\0';
  if (ch != EOF) {
    ungetch(ch);
  }
  return '0';
}
```