ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<GenReadLocal>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%r9d
  mov    $0x9,%eax
  cmp    $0xffffffff,%esi
  je     L2
  mov    $0xa,%eax
  cmp    $0x1,%esi
  je     L2
  mov    $0xb,%eax
  cmp    $0xfffffffe,%esi
  je     L2
  cmp    $0x2,%esi
  setne  %al
  movzbl %al,%eax
  add    $0xc,%eax
L2:
  mov    $0x3e,%r8d
  mov    $0x0,%ecx
  mov    %edi,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <GenPrintInstr2Operands@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void GenReadLocal(int regDst, int opSz, int ofs) {
  int instr = 0x0D;
  if (opSz == -1) {
    instr = 0x09;
  } else if (opSz == 1) {
    instr = 0x0A;
  } else if (opSz == -2) {
    instr = 0x0B;
  } else if (opSz == 2) {
    instr = 0x0C;
  }
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x3E, ofs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GenReadLocal>:
  endbr64
  mov    %edi,%r10d
  mov    %edx,%r9d
  mov    $0x9,%edi
  cmp    $0xffffffff,%esi
  je     L16
  mov    $0xa,%edi
  cmp    $0x1,%esi
  je     L16
  mov    $0xb,%edi
  cmp    $0xfffffffe,%esi
  je     L16
  xor    %edi,%edi
  cmp    $0x2,%esi
  setne  %dil
  add    $0xc,%edi
L16:
  mov    $0x3e,%r8d
  xor    %ecx,%ecx
  mov    %r10d,%edx
  xor    %esi,%esi
  jmp    1050 <GenPrintInstr2Operands@plt>
```

assistant: ```c
void GenReadLocal(int regDst, int opSz, int ofs) {
  int instr = 0x0D;
  if (opSz == -1) {
    instr = 0x09;
  } else if (opSz == 1) {
    instr = 0x0A;
  } else if (opSz == -2) {
    instr = 0x0B;
  } else if (opSz == 2) {
    instr = 0x0C;
  }
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x3E, ofs);
}
```
user: What is the c source code of the assembly code below?

```asm
<GenReadLocal>:
  endbr64
  mov    %edi,%r10d
  mov    %edx,%r9d
  mov    $0x9,%edi
  cmp    $0xffffffff,%esi
  je     L10
  mov    $0xa,%edi
  cmp    $0x1,%esi
  je     L10
  mov    $0xb,%edi
  cmp    $0xfffffffe,%esi
  je     L10
  xor    %edi,%edi
  cmp    $0x2,%esi
  setne  %dil
  add    $0xc,%edi
L10:
  mov    $0x3e,%r8d
  xor    %ecx,%ecx
  mov    %r10d,%edx
  xor    %esi,%esi
  jmp    1050 <GenPrintInstr2Operands@plt>
```

assistant: ```c
void GenReadLocal(int regDst, int opSz, int ofs) {
  int instr = 0x0D;
  if (opSz == -1) {
    instr = 0x09;
  } else if (opSz == 1) {
    instr = 0x0A;
  } else if (opSz == -2) {
    instr = 0x0B;
  } else if (opSz == 2) {
    instr = 0x0C;
  }
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x3E, ofs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_dvsprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x400,-0x14(%rbp)
L45:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x10(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0x0,-0xc(%rbp)
  js     L17
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L43
L17:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L39
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L2
L39:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L45
L43:
  nop
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_dvsprintf(char *dest, const char *f, va_list args) {
  char *string = NULL;
  int n, size = 2048 >> 1;
  va_list curr;
  while (1) {
    string = malloc(size);
    va_copy(curr, args);
    n = vsnprintf(string, size, f, curr);
    va_end(curr);
    if (0 <= n && n < size)
      break;
    if (-1 == n)
      size = size * 3 / 2 + 1;
    else
      size = n + 1;
    free(string);
  }
  free(dest);
  return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_dvsprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    $0x400,%ebp
  jmp    L33
L44:
  cmp    $0xffffffff,%ebx
  je     L3
  lea    0x1(%rbx),%ebp
L22:
  mov    %r12,%rdi
  call   <free@plt>
L33:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r14d,%esi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_copy@plt>
  mov    %r13d,%ecx
  mov    %r15,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %r13d,%edi
  call   <va_end@plt>
  test   %ebx,%ebx
  js     L44
  cmp    %ebx,%ebp
  jle    L44
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  lea    0x0(%rbp,%rbp,2),%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  add    $0x1,%ebp
  jmp    L22
```

assistant: ```c
char *str_dvsprintf(char *dest, const char *f, va_list args) {
  char *string = NULL;
  int n, size = 2048 >> 1;
  va_list curr;
  while (1) {
    string = malloc(size);
    va_copy(curr, args);
    n = vsnprintf(string, size, f, curr);
    va_end(curr);
    if (0 <= n && n < size)
      break;
    if (-1 == n)
      size = size * 3 / 2 + 1;
    else
      size = n + 1;
    free(string);
  }
  free(dest);
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str_dvsprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    $0x400,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  jmp    L29
  nopl   0x0(%rax)
L11:
  lea    0x1(%rbx),%ebp
L3:
  mov    %r15,%rdi
  call   <free@plt>
L29:
  mov    %ebp,%edi
  xor    %r14d,%r14d
  call   <malloc@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  mov    %rax,%r15
  call   <va_copy@plt>
  mov    %r15,%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%ebx
  call   <va_end@plt>
  test   %ebx,%ebx
  js     L4
  cmp    %ebx,%ebp
  jg     L41
L4:
  cmp    $0xffffffff,%ebx
  jne    L11
  lea    0x0(%rbp,%rbp,2),%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  add    $0x1,%ebp
  jmp    L3
  nopl   0x0(%rax)
L41:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *str_dvsprintf(char *dest, const char *f, va_list args) {
  char *string = NULL;
  int n, size = 2048 >> 1;
  va_list curr;
  while (1) {
    string = malloc(size);
    va_copy(curr, args);
    n = vsnprintf(string, size, f, curr);
    va_end(curr);
    if (0 <= n && n < size)
      break;
    if (-1 == n)
      size = size * 3 / 2 + 1;
    else
      size = n + 1;
    free(string);
  }
  free(dest);
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_dvsprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    $0x400,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  jmp    L44
  nopl   0x0(%rax)
L3:
  lea    0x1(%rbx),%ebp
L0:
  mov    %r15,%rdi
  call   <free@plt>
L44:
  mov    %ebp,%edi
  xor    %r14d,%r14d
  call   <malloc@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  mov    %rax,%r15
  call   <va_copy@plt>
  mov    %r15,%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%ebx
  call   <va_end@plt>
  test   %ebx,%ebx
  js     L11
  cmp    %ebx,%ebp
  jg     L37
L11:
  cmp    $0xffffffff,%ebx
  jne    L3
  lea    0x0(%rbp,%rbp,2),%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  add    $0x1,%ebp
  jmp    L0
  nopl   0x0(%rax)
L37:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *str_dvsprintf(char *dest, const char *f, va_list args) {
  char *string = NULL;
  int n, size = 2048 >> 1;
  va_list curr;
  while (1) {
    string = malloc(size);
    va_copy(curr, args);
    n = vsnprintf(string, size, f, curr);
    va_end(curr);
    if (0 <= n && n < size)
      break;
    if (-1 == n)
      size = size * 3 / 2 + 1;
    else
      size = n + 1;
    free(string);
  }
  free(dest);
  return string;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inhib_save_fill>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  jmp    L12
L145:
  cmpq   $0x0,0x10(%rbx)
  jne    L5
  testb  $0x1,0x18(%rbx)
  jne    L5
  addq   $0x1,0x20(%rbx)
  jmp    L27
L111:
  cmpq   $0x0,0x10(%rbx)
  jne    L5
  testb  $0x1,0x20(%rbx)
  jne    L5
  addq   $0x1,0x18(%rbx)
  jmp    L27
L146:
  movzbl 0x1(%rbp,%rdx,1),%eax
  mov    %eax,%esi
  and    $0xfffffff7,%esi
  cmp    $0x27,%sil
  je     L171
  cmp    $0x22,%al
  je     L171
  cmpb   $0x5c,-0x1(%rbp,%rdx,1)
  jne    L171
  mov    0x8(%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x8(%rbx)
  movzbl (%rcx),%edx
  mov    %dl,(%r12,%rax,1)
  jmp    L171
L5:
  mov    0x8(%rbx),%rdx
  mov    %al,(%r12,%rdx,1)
  addq   $0x1,0x8(%rbx)
  movq   $0x0,0x10(%rbx)
L27:
  addq   $0x1,(%rbx)
L12:
  mov    (%rbx),%r13
  mov    %rbp,%rdi
  call   <ft_strlen@plt>
  cmp    %rax,%r13
  jae    L153
  mov    (%rbx),%rdx
  lea    0x0(%rbp,%rdx,1),%rcx
  movzbl (%rcx),%eax
  cmp    $0x22,%al
  je     L145
  cmp    $0x27,%al
  je     L111
  cmp    $0x5c,%al
  jne    L5
  test   %rdx,%rdx
  je     L171
  cmpq   $0x1,0x10(%rbx)
  je     L146
L171:
  cmpq   $0x0,0x10(%rbx)
  sete   %al
  movzbl %al,%eax
  mov    %rax,0x10(%rbx)
  jmp    L27
L153:
  mov    0x8(%rbx),%rax
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void inhib_save_fill(char *str, char *save, size_t (*var)[5]) {
  while ((*var)[0] < ft_strlen(str)) {
    if (str[(*var)[0]] == '"' && (*var)[2] == 0 && !((*var)[3] % 2))
      ++(*var)[4];
    else if (str[(*var)[0]] == '\'' && (*var)[2] == 0 && !((*var)[4] % 2))
      ++(*var)[3];
    else if (str[(*var)[0]] == '\\') {
      if ((*var)[0] > 0 && (*var)[2] == 1 && str[(*var)[0] + 1] != '/' && str[(*var)[0] + 1] != '"' && str[(*var)[0] + 1] != '\'' && str[(*var)[0] - 1] == '\\')
        save[++(*var)[1] - 1] = str[(*var)[0]];
      (*var)[2] = ((*var)[2] ? 0 : 1);
    } else {
      save[(*var)[1]] = str[(*var)[0]];
      ++(*var)[1];
      (*var)[2] = 0;
    }
    ++(*var)[0];
  }
  save[(*var)[1]] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inhib_save_fill>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%rbp
  jmp    L102
  nopl   0x0(%rax)
L54:
  cmp    $0x27,%al
  je     L31
  cmp    $0x5c,%al
  jne    L50
  mov    0x10(%rbx),%rax
  lea    0x1(%rdx),%rbp
  test   %rdx,%rdx
  je     L5
  cmp    $0x1,%rax
  je     L66
L168:
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %rax,0x10(%rbx)
L24:
  mov    %rbp,(%rbx)
L102:
  mov    %r13,%rdi
  call   <ft_strlen@plt>
  cmp    %rbp,%rax
  jbe    L0
  mov    (%rbx),%rdx
  lea    0x0(%r13,%rdx,1),%rcx
  movzbl (%rcx),%eax
  cmp    $0x22,%al
  jne    L54
  cmpq   $0x0,0x10(%rbx)
  jne    L50
  testb  $0x1,0x18(%rbx)
  jne    L50
  addq   $0x1,0x20(%rbx)
  lea    0x1(%rdx),%rbp
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L50:
  mov    0x8(%rbx),%rdx
  mov    %al,(%r12,%rdx,1)
  mov    (%rbx),%rax
  addq   $0x1,0x8(%rbx)
  movq   $0x0,0x10(%rbx)
  lea    0x1(%rax),%rbp
  jmp    L24
  xchg   %ax,%ax
L31:
  cmpq   $0x0,0x10(%rbx)
  jne    L50
  testb  $0x1,0x20(%rbx)
  jne    L50
  addq   $0x1,0x18(%rbx)
  lea    0x1(%rdx),%rbp
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%ebp
  jmp    L168
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rbx),%rax
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L66:
  movzbl 0x1(%r13,%rdx,1),%esi
  mov    %esi,%edi
  and    $0xfffffff7,%edi
  cmp    $0x27,%dil
  je     L168
  cmp    $0x22,%sil
  je     L168
  cmpb   $0x5c,-0x1(%r13,%rdx,1)
  jne    L168
  mov    0x8(%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x8(%rbx)
  movzbl (%rcx),%edx
  mov    %dl,(%r12,%rax,1)
  mov    (%rbx),%rsi
  mov    0x10(%rbx),%rax
  lea    0x1(%rsi),%rbp
  jmp    L168
```

assistant: ```c
void inhib_save_fill(char *str, char *save, size_t (*var)[5]) {
  while ((*var)[0] < ft_strlen(str)) {
    if (str[(*var)[0]] == '"' && (*var)[2] == 0 && !((*var)[3] % 2))
      ++(*var)[4];
    else if (str[(*var)[0]] == '\'' && (*var)[2] == 0 && !((*var)[4] % 2))
      ++(*var)[3];
    else if (str[(*var)[0]] == '\\') {
      if ((*var)[0] > 0 && (*var)[2] == 1 && str[(*var)[0] + 1] != '/' && str[(*var)[0] + 1] != '"' && str[(*var)[0] + 1] != '\'' && str[(*var)[0] - 1] == '\\')
        save[++(*var)[1] - 1] = str[(*var)[0]];
      (*var)[2] = ((*var)[2] ? 0 : 1);
    } else {
      save[(*var)[1]] = str[(*var)[0]];
      ++(*var)[1];
      (*var)[2] = 0;
    }
    ++(*var)[0];
  }
  save[(*var)[1]] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<inhib_save_fill>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%rbp
  jmp    L59
  nopl   0x0(%rax)
L15:
  cmp    $0x27,%al
  je     L133
  cmp    $0x5c,%al
  jne    L112
  mov    0x10(%rbx),%rax
  lea    0x1(%rdx),%rbp
  test   %rdx,%rdx
  je     L18
  cmp    $0x1,%rax
  je     L71
L6:
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %rax,0x10(%rbx)
L160:
  mov    %rbp,(%rbx)
L59:
  mov    %r13,%rdi
  call   <ft_strlen@plt>
  cmp    %rbp,%rax
  jbe    L22
  mov    (%rbx),%rdx
  lea    0x0(%r13,%rdx,1),%rcx
  movzbl (%rcx),%eax
  cmp    $0x22,%al
  jne    L15
  cmpq   $0x0,0x10(%rbx)
  jne    L112
  testb  $0x1,0x18(%rbx)
  jne    L112
  addq   $0x1,0x20(%rbx)
  lea    0x1(%rdx),%rbp
  jmp    L160
  nopl   0x0(%rax,%rax,1)
L112:
  mov    0x8(%rbx),%rdx
  mov    %al,(%r12,%rdx,1)
  mov    (%rbx),%rax
  addq   $0x1,0x8(%rbx)
  movq   $0x0,0x10(%rbx)
  lea    0x1(%rax),%rbp
  jmp    L160
  xchg   %ax,%ax
L133:
  cmpq   $0x0,0x10(%rbx)
  jne    L112
  testb  $0x1,0x20(%rbx)
  jne    L112
  addq   $0x1,0x18(%rbx)
  lea    0x1(%rdx),%rbp
  jmp    L160
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%ebp
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L22:
  mov    0x8(%rbx),%rax
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L71:
  movzbl 0x1(%r13,%rdx,1),%esi
  mov    %esi,%edi
  and    $0xfffffff7,%edi
  cmp    $0x27,%dil
  je     L6
  cmp    $0x22,%sil
  je     L6
  cmpb   $0x5c,-0x1(%r13,%rdx,1)
  jne    L6
  mov    0x8(%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x8(%rbx)
  movzbl (%rcx),%edx
  mov    %dl,(%r12,%rax,1)
  mov    (%rbx),%rsi
  mov    0x10(%rbx),%rax
  lea    0x1(%rsi),%rbp
  jmp    L6
```

assistant: ```c
void inhib_save_fill(char *str, char *save, size_t (*var)[5]) {
  while ((*var)[0] < ft_strlen(str)) {
    if (str[(*var)[0]] == '"' && (*var)[2] == 0 && !((*var)[3] % 2))
      ++(*var)[4];
    else if (str[(*var)[0]] == '\'' && (*var)[2] == 0 && !((*var)[4] % 2))
      ++(*var)[3];
    else if (str[(*var)[0]] == '\\') {
      if ((*var)[0] > 0 && (*var)[2] == 1 && str[(*var)[0] + 1] != '/' && str[(*var)[0] + 1] != '"' && str[(*var)[0] + 1] != '\'' && str[(*var)[0] - 1] == '\\')
        save[++(*var)[1] - 1] = str[(*var)[0]];
      (*var)[2] = ((*var)[2] ? 0 : 1);
    } else {
      save[(*var)[1]] = str[(*var)[0]];
      ++(*var)[1];
      (*var)[2] = 0;
    }
    ++(*var)[0];
  }
  save[(*var)[1]] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<provide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    $0xc0,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L13
L29:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x34(%rbp)
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x8,-0x30(%rbp)
L13:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L29
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string

tool: D6: abi

tool: D5: accounting

assistant: ```c
char **provide() {
  char *items[] = {"abi", "accounting", NULL};
  char **arr = items;
  char **results = (char **)malloc(sizeof(char *) * sizeof(items));
  int i = 0;
  while (*arr) {
    results[i] = (char *)malloc(sizeof(char) * strlen(*arr));
    strcpy(results[i++], *arr);
    arr++;
  }
  return results;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<provide>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rbx
  mov    %rbx,(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    $0xc0,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  mov    %rsp,%r12
  sub    %rax,%r12
L14:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rsi
  call   <strcpy@plt>
  add    $0x8,%rbp
  mov    (%r12,%rbp,1),%rbx
  test   %rbx,%rbx
  jne    L14
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %r13,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D2: abi

tool: D0: accounting

assistant: ```c
char **provide() {
  char *items[] = {"abi", "accounting", NULL};
  char **arr = items;
  char **results = (char **)malloc(sizeof(char *) * sizeof(items));
  int i = 0;
  while (*arr) {
    results[i] = (char *)malloc(sizeof(char) * strlen(*arr));
    strcpy(results[i++], *arr);
    arr++;
  }
  return results;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<provide>:
  endbr64
  push   %r13
  mov    $0xc0,%edi
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rbp,(%rsp)
  mov    %rsp,%r13
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rbx
  sub    %rax,%r13
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,-0x8(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    0x0(%r13,%rbx,1),%rbp
  test   %rbp,%rbp
  jne    L5
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D16: abi

tool: D5: accounting

assistant: ```c
char **provide() {
  char *items[] = {"abi", "accounting", NULL};
  char **arr = items;
  char **results = (char **)malloc(sizeof(char *) * sizeof(items));
  int i = 0;
  while (*arr) {
    results[i] = (char *)malloc(sizeof(char) * strlen(*arr));
    strcpy(results[i++], *arr);
    arr++;
  }
  return results;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<provide>:
  endbr64
  push   %r13
  mov    $0xc0,%edi
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  movq   %rbp,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rsp,%r13
  movq   $0x0,0x10(%rsp)
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rbx
  sub    %rax,%r13
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,-0x8(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    0x0(%r13,%rbx,1),%rbp
  test   %rbp,%rbp
  jne    L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D8: abi

tool: D9: accounting

assistant: ```c
char **provide() {
  char *items[] = {"abi", "accounting", NULL};
  char **arr = items;
  char **results = (char **)malloc(sizeof(char *) * sizeof(items));
  int i = 0;
  while (*arr) {
    results[i] = (char *)malloc(sizeof(char) * strlen(*arr));
    strcpy(results[i++], *arr);
    arr++;
  }
  return results;
}
```