ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_nand>:
  endbr64
  test   %edi,%edi
  jle    L34
  lea    -0x1(%rdi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rsi,%rax,8),%rax
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsi
  cmp    %rax,%rsi
  je     L0
L20:
  ucomisd (%rsi),%xmm0
  jp     L1
  jne    L1
  movsd  D3(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
L34:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double _nand(const int numInputs, const double *inputs, const double *connectionWeights) {
  int i;
  for (i = 0; i < numInputs; i++) {
    if (inputs[i] == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_nand>:
  endbr64
  test   %edi,%edi
  jle    L34
  lea    -0x1(%rdi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rsi,%rax,8),%rax
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsi
  cmp    %rax,%rsi
  je     L17
L33:
  ucomisd (%rsi),%xmm0
  jp     L10
  jne    L10
  movsd  D9(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
L34:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double _nand(const int numInputs, const double *inputs, const double *connectionWeights) {
  int i;
  for (i = 0; i < numInputs; i++) {
    if (inputs[i] == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_der_seq_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L8
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L1
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L45:
  shll   $0x8,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L45
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L8
L1:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x2,%eax
  mov    %eax,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_der_seq_size(unsigned char *buf) {
  unsigned int len = 0;
  if (buf[0] == 0x30) {
    if (buf[1] & 0x80) {
      int i, num_bytes = (buf[1] & 0x7f);
      for (i = 0; i < num_bytes; i++) {
        len *= 256;
        len += buf[i + 2];
      }
      len += num_bytes + 2;
    } else
      len = buf[1] + 2;
  };
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_der_seq_size>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x30,(%rdi)
  je     L36
L10:
  ret
L36:
  movzbl 0x1(%rdi),%edx
  movzbl %dl,%eax
  add    $0x2,%eax
  test   %dl,%dl
  jns    L10
  mov    %edx,%ecx
  and    $0x7f,%ecx
  je     L4
  lea    0x2(%rdi),%rdx
  movzbl %cl,%eax
  lea    -0x1(%rax),%eax
  lea    0x3(%rdi,%rax,1),%rdi
  mov    $0x0,%eax
L13:
  shl    $0x8,%eax
  movzbl (%rdx),%esi
  add    %esi,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L13
L27:
  lea    0x2(%rcx),%edx
  movzbl %dl,%edx
  add    %edx,%eax
  jmp    L10
L4:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
unsigned int get_der_seq_size(unsigned char *buf) {
  unsigned int len = 0;
  if (buf[0] == 0x30) {
    if (buf[1] & 0x80) {
      int i, num_bytes = (buf[1] & 0x7f);
      for (i = 0; i < num_bytes; i++) {
        len *= 256;
        len += buf[i + 2];
      }
      len += num_bytes + 2;
    } else
      len = buf[1] + 2;
  };
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_der_seq_size>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x30,(%rdi)
  je     L13
L28:
  ret
  nopl   0x0(%rax)
L13:
  movzbl 0x1(%rdi),%edx
  lea    0x2(%rdx),%eax
  movzbl %al,%eax
  test   %dl,%dl
  jns    L28
  mov    %edx,%ecx
  and    $0x7f,%ecx
  je     L20
  movzbl %cl,%eax
  lea    0x2(%rdi),%rdx
  sub    $0x1,%eax
  lea    0x3(%rdi,%rax,1),%rdi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L32:
  movzbl (%rdx),%esi
  shl    $0x8,%eax
  add    $0x1,%rdx
  add    %esi,%eax
  cmp    %rdi,%rdx
  jne    L32
L19:
  lea    0x2(%rcx),%edx
  movzbl %dl,%edx
  add    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  jmp    L19
```

assistant: ```c
unsigned int get_der_seq_size(unsigned char *buf) {
  unsigned int len = 0;
  if (buf[0] == 0x30) {
    if (buf[1] & 0x80) {
      int i, num_bytes = (buf[1] & 0x7f);
      for (i = 0; i < num_bytes; i++) {
        len *= 256;
        len += buf[i + 2];
      }
      len += num_bytes + 2;
    } else
      len = buf[1] + 2;
  };
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_der_seq_size>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x30,(%rdi)
  je     L23
L0:
  ret
  nopl   0x0(%rax)
L23:
  movzbl 0x1(%rdi),%edx
  lea    0x2(%rdx),%eax
  movzbl %al,%eax
  test   %dl,%dl
  jns    L0
  mov    %edx,%ecx
  and    $0x7f,%ecx
  je     L46
  movzbl %cl,%eax
  lea    0x2(%rdi),%rdx
  sub    $0x1,%eax
  lea    0x3(%rdi,%rax,1),%rdi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L49:
  movzbl (%rdx),%esi
  shl    $0x8,%eax
  add    $0x1,%rdx
  add    %esi,%eax
  cmp    %rdx,%rdi
  jne    L49
L26:
  lea    0x2(%rcx),%edx
  movzbl %dl,%edx
  add    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  jmp    L26
```

assistant: ```c
unsigned int get_der_seq_size(unsigned char *buf) {
  unsigned int len = 0;
  if (buf[0] == 0x30) {
    if (buf[1] & 0x80) {
      int i, num_bytes = (buf[1] & 0x7f);
      for (i = 0; i < num_bytes; i++) {
        len *= 256;
        len += buf[i + 2];
      }
      len += num_bytes + 2;
    } else
      len = buf[1] + 2;
  };
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L8
L7:
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L8:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jae    L7
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: f64

tool: D1: 1

assistant: ```c
double factorial(double n) {
  double res = 1;
  double i;
  for (i = 1; i <= n; i++) {
    res = res * i;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorial>:
  endbr64
  movsd  D17(%rip),%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm3
  comisd %xmm1,%xmm0
  jb     L23
L2:
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm1
  comisd %xmm1,%xmm0
  jae    L2
L9:
  movapd %xmm2,%xmm0
  ret
L23:
  movsd  D17(%rip),%xmm2
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: f64

tool: D17: 1

assistant: ```c
double factorial(double n) {
  double res = 1;
  double i;
  for (i = 1; i <= n; i++) {
    res = res * i;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<factorial>:
  endbr64
  movsd  D8(%rip),%xmm3
  comisd %xmm3,%xmm0
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm2
  jb     L5
  nopw   0x0(%rax,%rax,1)
L13:
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm1
  comisd %xmm1,%xmm0
  jae    L13
L5:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: f64

tool: D8: 1

assistant: ```c
double factorial(double n) {
  double res = 1;
  double i;
  for (i = 1; i <= n; i++) {
    res = res * i;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<factorial>:
  endbr64
  movsd  D6(%rip),%xmm3
  comisd %xmm3,%xmm0
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm2
  jb     L9
  nopw   0x0(%rax,%rax,1)
L10:
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm1
  comisd %xmm1,%xmm0
  jae    L10
L9:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 1

assistant: ```c
double factorial(double n) {
  double res = 1;
  double i;
  for (i = 1; i <= n; i++) {
    res = res * i;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x78,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x58(%rbp)
  mov    -0x70(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%ecx
  mov    -0x58(%rbp),%esi
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x50(%rbp)
  movslq %ecx,%rax
  mov    %rax,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movslq %esi,%rax
  sub    $0x1,%rax
  mov    %rax,-0x48(%rbp)
  movslq %ecx,%rax
  mov    %rax,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movslq %esi,%rax
  mov    %rax,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  mov    -0x80(%rbp),%r8
  mov    -0x78(%rbp),%r9
  mov    %r9,%rdx
  mov    -0x90(%rbp),%r10
  mov    -0x88(%rbp),%r11
  imul   %r10,%rdx
  mov    %r11,%rax
  imul   %r8,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r8,%rax
  mul    %r10
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  movslq %esi,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    %r15,%rdx
  imul   %r12,%rdx
  mov    %r13,%rax
  imul   %r14,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r14,%rax
  mul    %r12
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rdx
  movslq %esi,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L10:
  cmp    %rdx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L23:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L21
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L21:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%ecx
  mov    -0x58(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <get_identity@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%ecx
  mov    -0x58(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <print_sandpile@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int rows = atoi(argv[1]), cols = atoi(argv[2]);
  int sandpile[rows][cols];
  get_identity(rows, cols, sandpile);
  print_sandpile(rows, cols, sandpile);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  cltq
  movslq %r12d,%rdx
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L15:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L15
L29:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L3
  orq    $0x0,-0x8(%rsp,%rax,1)
L3:
  mov    %rsp,%r13
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <get_identity@plt>
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <print_sandpile@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int rows = atoi(argv[1]), cols = atoi(argv[2]);
  int sandpile[rows][cols];
  get_identity(rows, cols, sandpile);
  print_sandpile(rows, cols, sandpile);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  movslq %r12d,%rdx
  mov    %rsp,%rcx
  mov    %eax,%r13d
  cltq
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L39
L40:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L40
L39:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L31
L18:
  mov    %rsp,%r14
  mov    %r13d,%esi
  mov    %r12d,%edi
  mov    %r14,%rdx
  call   <get_identity@plt>
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <print_sandpile@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L31:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L18
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int rows = atoi(argv[1]), cols = atoi(argv[2]);
  int sandpile[rows][cols];
  get_identity(rows, cols, sandpile);
  print_sandpile(rows, cols, sandpile);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  movslq %r12d,%rdx
  mov    %rsp,%rcx
  mov    %eax,%r13d
  cltq
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L9
L14:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L14
L9:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L19
L32:
  mov    %rsp,%r14
  mov    %r13d,%esi
  mov    %r12d,%edi
  mov    %r14,%rdx
  call   <get_identity@plt>
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <print_sandpile@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L19:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L32
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int rows = atoi(argv[1]), cols = atoi(argv[2]);
  int sandpile[rows][cols];
  get_identity(rows, cols, sandpile);
  print_sandpile(rows, cols, sandpile);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(char *key) {
  unsigned int result = 0;
  while (*key) {
    result += *key;
    key++;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  mov    $0x0,%edx
L10:
  movsbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
L7:
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%edx
  jmp    L7
```

assistant: ```c
unsigned int hash(char *key) {
  unsigned int result = 0;
  while (*key) {
    result += *key;
    key++;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L0
  xchg   %ax,%ax
L17:
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L17
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int hash(char *key) {
  unsigned int result = 0;
  while (*key) {
    result += *key;
    key++;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L4
  xchg   %ax,%ax
L1:
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L1
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int hash(char *key) {
  unsigned int result = 0;
  while (*key) {
    result += *key;
    key++;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cum_normal>:
  endbr64
  pxor   %xmm3,%xmm3
  comisd %xmm2,%xmm3
  jae    L22
  sub    $0x18,%rsp
  subsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm1
  xorpd  D113(%rip),%xmm1
  cmpltsd %xmm3,%xmm0
  andpd  %xmm0,%xmm1
  movsd  %xmm5,(%rsp)
  andnpd %xmm5,%xmm0
  orpd   %xmm0,%xmm1
  movapd %xmm1,%xmm0
  mulsd  D137(%rip),%xmm0
  addsd  D30(%rip),%xmm0
  movsd  D30(%rip),%xmm4
  divsd  %xmm0,%xmm4
  movsd  %xmm4,0x8(%rsp)
  movapd %xmm1,%xmm0
  mulsd  D116(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm0
  mulsd  D84(%rip),%xmm0
  mulsd  %xmm4,%xmm0
  movapd %xmm4,%xmm1
  mulsd  D118(%rip),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm4,%xmm1
  mulsd  D114(%rip),%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm4,%xmm1
  mulsd  D21(%rip),%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm4,%xmm1
  mulsd  D29(%rip),%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D37(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  movsd  D30(%rip),%xmm1
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd (%rsp),%xmm0
  ja     L0
L17:
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
L0:
  movsd  D30(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  jmp    L17
L22:
  movsd  D104(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D113
type: f32[4]
name: retrieve_data
arguments: data_tag: D137
type: byte[8]
name: retrieve_data
arguments: data_tag: D30
type: f64
name: retrieve_data
arguments: data_tag: D116
type: f32[2]
name: retrieve_data
arguments: data_tag: D84
type: byte[8]
name: retrieve_data
arguments: data_tag: D118
type: f64
name: retrieve_data
arguments: data_tag: D114
type: f64
name: retrieve_data
arguments: data_tag: D21
type: byte[8]
name: retrieve_data
arguments: data_tag: D29
type: f64
name: retrieve_data
arguments: data_tag: D37
type: f64
name: retrieve_data
arguments: data_tag: D104
type: f32[2]

tool: {"D113": [0.0,-0.0,0.0,0.0]}

tool: {"D137": [0x0e,0x10,0x71,0x18,0x71,0xa6,0xcd,0x3f]}

tool: D30: 1

tool: {"D116": [0.0,-1.75]}

tool: {"D84": [0x5b,0x32,0xa8,0xe5,0xf0,0xd1,0xd6,0xbf]}

tool: D118: 0.31938153

tool: D114: 1.781477937

tool: {"D21": [0xd0,0x78,0xf2,0x4e,0xdd,0x23,0xfd,0xbf]}

tool: D29: 1.330274429

tool: D37: 0.39894228040143

tool: {"D104": [0.0,-1.875]}

assistant: ```c
double cum_normal(double sample, double mean, double stddev) {
  double a, b, c, d, e, f, g, h, temp;
  a = 0.319381530;
  b = -0.356563782;
  c = 1.781477937;
  d = -1.821255978;
  e = 1.330274429;
  f = .2316419;
  if (stddev <= 0.0)
    return -1.0;
  sample = (sample - mean) / stddev;
  if (sample < 0.0)
    temp = -sample;
  else
    temp = sample;
  g = 1.0 / (1.0 + f * temp);
  h = 1.0 - (0.39894228040143 * exp(-0.5 * temp * temp)) * (a * g + b * g * g + c * g * g * g + d * g * g * g * g + e * g * g * g * g * g);
  if (sample < 0.0)
    h = 1.0 - h;
  return h;
}
```