ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbx
  lea    0x81(%rsp),%rbp
  movups %xmm0,0x1(%rsp)
  movups %xmm0,0x11(%rsp)
  movups %xmm0,0x21(%rsp)
  movups %xmm0,0x31(%rsp)
  movups %xmm0,0x41(%rsp)
  movups %xmm0,0x51(%rsp)
  movups %xmm0,0x61(%rsp)
  movups %xmm0,0x71(%rsp)
  nopl   (%rax)
L21:
  cmpb   $0x5,(%rbx)
  je     L15
  xor    %eax,%eax
  call   <abort@plt>
L15:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L21
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: byte[16]

tool: {"D8": [0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05,0x05]}

assistant: ```c
int main() {
  int i;
  char ia[128 + 1];
  for (i = 1; i <= 128; i++) {
    ia[i] = 5;
  }
  for (i = 1; i <= 128; i++) {
    if (ia[i] != 5)
      abort();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strdefint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <findname@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  jmp    L18
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdec@plt>
L18:
  leave
  ret
```

assistant: ```c
char const *strdefint(unsigned long number, char const *prefix) {
  char const *name;
  name = findname(number, prefix);
  if (name)
    return name;
  return strdec(number);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strdefint>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <findname@plt>
  test   %rax,%rax
  je     L7
L6:
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  call   <strdec@plt>
  jmp    L6
```

assistant: ```c
char const *strdefint(unsigned long number, char const *prefix) {
  char const *name;
  name = findname(number, prefix);
  if (name)
    return name;
  return strdec(number);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdefint>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <findname@plt>
  test   %rax,%rax
  je     L4
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strdec@plt>
```

assistant: ```c
char const *strdefint(unsigned long number, char const *prefix) {
  char const *name;
  name = findname(number, prefix);
  if (name)
    return name;
  return strdec(number);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strdefint>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <findname@plt>
  test   %rax,%rax
  je     L1
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strdec@plt>
```

assistant: ```c
char const *strdefint(unsigned long number, char const *prefix) {
  char const *name;
  name = findname(number, prefix);
  if (name)
    return name;
  return strdec(number);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rdz_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  je     L23
  pxor   %xmm0,%xmm0
  jmp    L27
L23:
  movsd  -0x20(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D8(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
L27:
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: f64

tool: D8: 1000

assistant: ```c
double rdz_now() {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    return 0.0;
  return 1000.0 * tv.tv_sec + tv.tv_usec / 1000.0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rdz_now>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  test   %rax,%rax
  jne    L6
  movsd  D2(%rip),%xmm2
  movapd %xmm2,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: f64

tool: D2: 1000

assistant: ```c
double rdz_now() {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    return 0.0;
  return 1000.0 * tv.tv_sec + tv.tv_usec / 1000.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rdz_now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  test   %rax,%rax
  jne    L5
  movsd  D2(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: f64

tool: D2: 1000

assistant: ```c
double rdz_now() {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    return 0.0;
  return 1000.0 * tv.tv_sec + tv.tv_usec / 1000.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdz_now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  test   %rax,%rax
  jne    L16
  movsd  D8(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: f64

tool: D8: 1000

assistant: ```c
double rdz_now() {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    return 0.0;
  return 1000.0 * tv.tv_sec + tv.tv_usec / 1000.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pushHeap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <reHeapElement@plt>
  nop
  leave
  ret
```

assistant: ```c
void pushHeap(int *p, int *q, double *v, int length, int i) {
  swap(p, q, i, length + 1);
  reHeapElement(p, q, v, length + 1, length + 1);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pushHeap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %r8d,%edx
  lea    0x1(%rcx),%ebx
  mov    %ebx,%ecx
  call   <swap@plt>
  mov    %ebx,%r8d
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <reHeapElement@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void pushHeap(int *p, int *q, double *v, int length, int i) {
  swap(p, q, i, length + 1);
  reHeapElement(p, q, v, length + 1, length + 1);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pushHeap>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  mov    %r8d,%edx
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x1(%rcx),%r12d
  push   %rbp
  mov    %r12d,%ecx
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r12d,%r8d
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <reHeapElement@plt>
```

assistant: ```c
void pushHeap(int *p, int *q, double *v, int length, int i) {
  swap(p, q, i, length + 1);
  reHeapElement(p, q, v, length + 1, length + 1);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pushHeap>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  mov    %r8d,%edx
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x1(%rcx),%r12d
  push   %rbp
  mov    %r12d,%ecx
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r12d,%r8d
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <reHeapElement@plt>
```

assistant: ```c
void pushHeap(int *p, int *q, double *v, int length, int i) {
  swap(p, q, i, length + 1);
  reHeapElement(p, q, v, length + 1, length + 1);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<array_squeeze2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x2c(%rbp),%eax
  cltq
  imul   -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L13
L1:
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x38(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  add    %rax,-0x10(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void array_squeeze2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  unsigned char *end;
  unsigned char *p, *q;
  assert(oldwidth > newwidth);
  end = base + nelems * oldwidth;
  p = base + 1 * oldwidth;
  q = base + 1 * newwidth;
  while (p < end) {
    memmove(q, p, newwidth);
    p += oldwidth;
    q += newwidth;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<array_squeeze2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %rdx,%r14
  mov    %rcx,%r12
  cmp    %rcx,%rdx
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %r13d,%r13
  imul   %r14,%r13
  add    %rbp,%r13
  lea    0x0(%rbp,%r14,1),%rbx
  add    %r12,%rbp
  cmp    %rbx,%r13
  jbe    L10
L12:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  add    %r14,%rbx
  add    %r12,%rbp
  cmp    %rbx,%r13
  ja     L12
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void array_squeeze2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  unsigned char *end;
  unsigned char *p, *q;
  assert(oldwidth > newwidth);
  end = base + nelems * oldwidth;
  p = base + 1 * oldwidth;
  q = base + 1 * newwidth;
  while (p < end) {
    memmove(q, p, newwidth);
    p += oldwidth;
    q += newwidth;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<array_squeeze2>:
  endbr64
  push   %r14
  movslq %esi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  cmp    %rcx,%rdx
  seta   %dil
  imul   %r13,%r14
  push   %rbx
  lea    0x0(%rbp,%r13,1),%rbx
  call   <assert@plt>
  add    %rbp,%r14
  add    %r12,%rbp
  cmp    %rbx,%r14
  jbe    L4
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  add    %r13,%rbx
  call   <memmove@plt>
  add    %r12,%rbp
  cmp    %rbx,%r14
  ja     L19
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void array_squeeze2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  unsigned char *end;
  unsigned char *p, *q;
  assert(oldwidth > newwidth);
  end = base + nelems * oldwidth;
  p = base + 1 * oldwidth;
  q = base + 1 * newwidth;
  while (p < end) {
    memmove(q, p, newwidth);
    p += oldwidth;
    q += newwidth;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_squeeze2>:
  endbr64
  push   %r14
  movslq %esi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  cmp    %rcx,%rdx
  seta   %dil
  imul   %r13,%r14
  push   %rbx
  lea    0x0(%rbp,%r13,1),%rbx
  call   <assert@plt>
  add    %rbp,%r14
  add    %r12,%rbp
  cmp    %rbx,%r14
  jbe    L14
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  add    %r13,%rbx
  call   <memmove@plt>
  add    %r12,%rbp
  cmp    %rbx,%r14
  ja     L7
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void array_squeeze2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  unsigned char *end;
  unsigned char *p, *q;
  assert(oldwidth > newwidth);
  end = base + nelems * oldwidth;
  p = base + 1 * oldwidth;
  q = base + 1 * newwidth;
  while (p < end) {
    memmove(q, p, newwidth);
    p += oldwidth;
    q += newwidth;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<primegen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L40
L20:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  jmp    L29
L4:
  addq   $0x1,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  cmp    %rax,-0x18(%rbp)
  jae    L20
  mov    $0x1,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int primegen(uint32_t n, uint64_t *sieve) {
  for (uint32_t i = 1; i * i <= n; i++) {
    if (n % i == 0) {
      if (!sieve[i + n / i])
        return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<primegen>:
  endbr64
  test   %rdi,%rdi
  je     L56
  mov    $0x1,%ecx
  jmp    L55
L5:
  add    $0x1,%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  cmp    %rdi,%rax
  ja     L1
L55:
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  test   %rdx,%rdx
  jne    L5
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    %rcx,%rax
  mov    (%rsi,%rax,4),%eax
  test   %eax,%eax
  jne    L5
L23:
  ret
L1:
  mov    $0x1,%eax
  ret
L56:
  mov    $0x1,%eax
  jmp    L23
```

assistant: ```c
int primegen(uint32_t n, uint64_t *sieve) {
  for (uint32_t i = 1; i * i <= n; i++) {
    if (n % i == 0) {
      if (!sieve[i + n / i])
        return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<primegen>:
  endbr64
  test   %rdi,%rdi
  je     L31
  mov    $0x1,%ecx
  xchg   %ax,%ax
L30:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  test   %rdx,%rdx
  jne    L4
  add    %rcx,%rax
  mov    (%rsi,%rax,4),%eax
  test   %eax,%eax
  je     L35
L4:
  add    $0x1,%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  cmp    %rdi,%rax
  jbe    L30
L31:
  mov    $0x1,%eax
L35:
  ret
```

assistant: ```c
int primegen(uint32_t n, uint64_t *sieve) {
  for (uint32_t i = 1; i * i <= n; i++) {
    if (n % i == 0) {
      if (!sieve[i + n / i])
        return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<primegen>:
  endbr64
  test   %rdi,%rdi
  je     L26
  mov    $0x1,%ecx
  xchg   %ax,%ax
L9:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  test   %rdx,%rdx
  jne    L11
  add    %rcx,%rax
  mov    (%rsi,%rax,4),%eax
  test   %eax,%eax
  je     L12
L11:
  add    $0x1,%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  cmp    %rdi,%rax
  jbe    L9
L26:
  mov    $0x1,%eax
L12:
  ret
```

assistant: ```c
int primegen(uint32_t n, uint64_t *sieve) {
  for (uint32_t i = 1; i * i <= n; i++) {
    if (n % i == 0) {
      if (!sieve[i + n / i])
        return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convertBinToByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char convertBinToByte(char *binary) {
  unsigned char c;
  c = strtol(binary, 0, 2);
  return (c);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<convertBinToByte>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char convertBinToByte(char *binary) {
  unsigned char c;
  c = strtol(binary, 0, 2);
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convertBinToByte>:
  endbr64
  mov    $0x2,%edx
  xor    %esi,%esi
  jmp    1050 <strtol@plt>
```

assistant: ```c
unsigned char convertBinToByte(char *binary) {
  unsigned char c;
  c = strtol(binary, 0, 2);
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<convertBinToByte>:
  endbr64
  mov    $0x2,%edx
  xor    %esi,%esi
  jmp    1050 <strtol@plt>
```

assistant: ```c
unsigned char convertBinToByte(char *binary) {
  unsigned char c;
  c = strtol(binary, 0, 2);
  return (c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dijkstra>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x24(%rsp),%r14
  mov    %r12,%rax
L56:
  movl   $0x1e240,(%rax)
  add    $0x4,%rax
  cmp    %r14,%rax
  jne    L56
  movslq %esi,%rax
  movl   $0x0,(%rsp,%rax,4)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movl   $0x0,0x50(%rsp)
  mov    $0x9,%r13d
  lea    0x30(%rsp),%rbx
  mov    %rsp,%rbp
  jmp    L16
L27:
  add    $0x4,%rdx
  cmp    $0x24,%rdx
  je     L59
L67:
  cmpl   $0x0,(%rdx,%rbx,1)
  jne    L27
  mov    (%rdi,%rdx,1),%ecx
  mov    %ecx,%esi
  add    (%rsp,%rax,4),%esi
  cmp    %esi,0x0(%rbp,%rdx,1)
  jle    L27
  test   %ecx,%ecx
  je     L27
  mov    %esi,(%rdx,%rbp,1)
  jmp    L27
L59:
  sub    $0x1,%r13d
  je     L97
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <minIndex@plt>
  movslq %eax,%rdx
  movl   $0x1,0x30(%rsp,%rdx,4)
  lea    (%rdx,%rdx,8),%rdx
  lea    (%r15,%rdx,4),%rdi
  mov    $0x0,%edx
  cltq
  jmp    L67
L97:
  lea    D7(%rip),%rbx
L47:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r12
  cmp    %r14,%r12
  jne    L47
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %d,

assistant: ```c
void dijkstra(int graph[9][9], int src) {
  int dist[9];
  for (int i = 0; i < 9; i++) {
    dist[i] = 123456;
  }
  dist[src] = 0;
  int spt[9] = {0};
  for (int i = 0; i < 9; i++) {
    int u = minIndex(dist, spt);
    spt[u] = 1;
    for (int j = 0; j < 9; j++) {
      if (!spt[j] && dist[j] > (dist[u] + graph[u][j]) && graph[u][j]) {
        dist[j] = dist[u] + graph[u][j];
      }
    }
  }
  for (int i = 0; i < 9; i++) {
    printf("%d,", dist[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dijkstra>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x24(%rsp),%r12
  mov    %r15,%rbx
  mov    %r15,%rax
  nopl   0x0(%rax,%rax,1)
L13:
  movl   $0x1e240,(%rax)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L13
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  mov    $0x9,%ebp
  movl   $0x0,0x50(%rsp)
  movl   $0x0,(%rsp,%rax,4)
  lea    0x30(%rsp),%r14
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  nopl   0x0(%rax)
L8:
  mov    %r15,%rdi
  mov    %r14,%rsi
  call   <minIndex@plt>
  cltq
  movl   $0x1,0x30(%rsp,%rax,4)
  lea    (%rax,%rax,8),%rdx
  lea    0x0(%r13,%rdx,4),%rdi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%r14,%rdx,1),%ecx
  test   %ecx,%ecx
  jne    L71
  mov    (%rdi,%rdx,1),%ecx
  mov    (%rsp,%rax,4),%esi
  add    %ecx,%esi
  cmp    %esi,(%r15,%rdx,1)
  jle    L71
  test   %ecx,%ecx
  je     L71
  mov    %esi,(%r15,%rdx,1)
  xchg   %ax,%ax
L71:
  add    $0x4,%rdx
  cmp    $0x24,%rdx
  jne    L34
  sub    $0x1,%ebp
  jne    L8
  lea    D9(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L44
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: %d,

assistant: ```c
void dijkstra(int graph[9][9], int src) {
  int dist[9];
  for (int i = 0; i < 9; i++) {
    dist[i] = 123456;
  }
  dist[src] = 0;
  int spt[9] = {0};
  for (int i = 0; i < 9; i++) {
    int u = minIndex(dist, spt);
    spt[u] = 1;
    for (int j = 0; j < 9; j++) {
      if (!spt[j] && dist[j] > (dist[u] + graph[u][j]) && graph[u][j]) {
        dist[j] = dist[u] + graph[u][j];
      }
    }
  }
  for (int i = 0; i < 9; i++) {
    printf("%d,", dist[i]);
  }
  printf("\n");
}
```