ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libbch_decode_sec>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rcx
L16:
  mov    (%rcx,%rax,1),%edx
  xor    %edx,0x80c(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x34,%rax
  jne    L16
  mov    %rbp,%rbx
  lea    0x840(%rbp),%r13
L57:
  mov    (%rbx),%edi
  call   <reverse_bits@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L57
  lea    0x80c(%rbp),%rcx
  sub    $0x8,%rsp
  lea    0x8(%rsp),%rax
  push   %rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x203,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <decode_bch@plt>
  mov    %eax,%r13d
  add    $0x10,%rsp
  test   %eax,%eax
  jle    L52
  mov    %rsp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x4(%rsp,%rax,4),%rdi
  mov    $0x1,%esi
L17:
  mov    (%rdx),%ecx
  mov    %ecx,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  and    $0x7,%ecx
  mov    %esi,%ebx
  shl    %cl,%ebx
  xor    %ebx,0x0(%rbp,%rax,4)
  add    $0x4,%rdx
  cmp    %rdx,%rdi
  jne    L17
L52:
  mov    $0x0,%ebx
L46:
  mov    0x0(%rbp,%rbx,1),%edi
  call   <reverse_bits@plt>
  mov    %eax,(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x800,%rbx
  jne    L46
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %r13d,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: N

assistant: ```c
int libbch_decode_sec(struct bch_control *bch, uint8_t *inbuf, uint8_t *outbuf) {
  unsigned int errloc[8];
  static const uint8_t mask[13] = {
      0x4e, 0x8c, 0x9d, 0x52, 0x2d, 0x6c, 0x7c, 0xcb, 0xc3, 0x12, 0x14, 0x19, 0x37,
  };
  int i, err_num = 0;
  for (i = 0; i < 13; i++)
    inbuf[512 + 3 + i] ^= mask[i];
  for (i = 0; i < (512 + 3 + 13); i++)
    inbuf[i] = reverse_bits(inbuf[i]);
  err_num = decode_bch(bch, inbuf, ((512 + 3 + 13) - 13), &inbuf[(512 + 3 + 13) - 13], NULL, NULL, errloc);
  for (i = 0; i < err_num; i++)
    inbuf[errloc[i] / 8] ^= 1 << (errloc[i] % 8);
  for (i = 0; i < 512; i++)
    outbuf[i] = reverse_bits(inbuf[i]);
  return err_num;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<libbch_decode_sec>:
  endbr64
  push   %r14
  lea    D8(%rip),%rcx
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  mov    $0x4e,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rcx,%rax,1),%edx
L7:
  xor    %edx,0x80c(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x34,%rax
  jne    L13
  mov    %rbp,%rbx
  lea    0x840(%rbp),%r13
  xchg   %ax,%ax
L16:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <reverse_bits@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbx,%r13
  jne    L16
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x203,%edx
  lea    0x8(%rsp),%rbx
  lea    0x80c(%rbp),%rcx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  push   %rbx
  call   <decode_bch@plt>
  mov    %rbx,%rsp
  mov    %eax,%r13d
  test   %eax,%eax
  jle    L58
  lea    -0x1(%rax),%eax
  mov    %rbx,%rdx
  mov    $0x1,%esi
  lea    0x4(%rsp,%rax,4),%rdi
  nopl   0x0(%rax)
L66:
  mov    (%rdx),%ecx
  mov    %esi,%ebx
  add    $0x4,%rdx
  mov    %ecx,%eax
  and    $0x7,%ecx
  shr    $0x3,%eax
  shl    %cl,%ebx
  xor    %ebx,0x0(%rbp,%rax,4)
  cmp    %rdx,%rdi
  jne    L66
L58:
  xor    %ebx,%ebx
  nopl   (%rax)
L45:
  mov    0x0(%rbp,%rbx,1),%edi
  call   <reverse_bits@plt>
  mov    %eax,(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x800,%rbx
  jne    L45
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: N

assistant: ```c
int libbch_decode_sec(struct bch_control *bch, uint8_t *inbuf, uint8_t *outbuf) {
  unsigned int errloc[8];
  static const uint8_t mask[13] = {
      0x4e, 0x8c, 0x9d, 0x52, 0x2d, 0x6c, 0x7c, 0xcb, 0xc3, 0x12, 0x14, 0x19, 0x37,
  };
  int i, err_num = 0;
  for (i = 0; i < 13; i++)
    inbuf[512 + 3 + i] ^= mask[i];
  for (i = 0; i < (512 + 3 + 13); i++)
    inbuf[i] = reverse_bits(inbuf[i]);
  err_num = decode_bch(bch, inbuf, ((512 + 3 + 13) - 13), &inbuf[(512 + 3 + 13) - 13], NULL, NULL, errloc);
  for (i = 0; i < err_num; i++)
    inbuf[errloc[i] / 8] ^= 1 << (errloc[i] % 8);
  for (i = 0; i < 512; i++)
    outbuf[i] = reverse_bits(inbuf[i]);
  return err_num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CurrentMonthReport>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <ConnectDb@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <AcctReport@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: tRadacct

assistant: ```c
void CurrentMonthReport(char *cPasswd) {
  ConnectDb();
  AcctReport("tRadacct");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CurrentMonthReport>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ConnectDb@plt>
  lea    D0(%rip),%rdi
  call   <AcctReport@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: tRadacct

assistant: ```c
void CurrentMonthReport(char *cPasswd) {
  ConnectDb();
  AcctReport("tRadacct");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CurrentMonthReport>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ConnectDb@plt>
  lea    D0(%rip),%rdi
  call   <AcctReport@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: tRadacct

assistant: ```c
void CurrentMonthReport(char *cPasswd) {
  ConnectDb();
  AcctReport("tRadacct");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CurrentMonthReport>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ConnectDb@plt>
  lea    D4(%rip),%rdi
  call   <AcctReport@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: tRadacct

assistant: ```c
void CurrentMonthReport(char *cPasswd) {
  ConnectDb();
  AcctReport("tRadacct");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x1,-0xc(%rbp)
  jne    L20
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L54
L20:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L60
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L57
  nop
L54:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L127
L57:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L9
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L127
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L127
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L127:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
L82:
  nop
L37:
  cmpl   $0x314,-0x8(%rbp)
  jle    L6
  jmp    L118
L109:
  nop
L118:
  cmpl   $0x1c7,-0x4(%rbp)
  jle    L82
L60:
  cmpl   $0x7a,-0xc(%rbp)
  jle    L109
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D43
datatype: string
name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D55
datatype: string
name: read_data
arguments: data_label: D48
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D43: 1


tool: D4: 2


tool: D7: 3


tool: D55: 4


tool: D48: 5


tool: D13: 6


assistant: ```c
int main() {
  int i, j, k;
  if (i == 1) {
    printf("1\n");
    goto next;
  } else {
    printf("2\n");
  }
  while (i < 123) {
    while (j < 456) {
      while (k < 789) {
        if (i == j) {
        next:
          printf("3\n");
        } else {
          if (j == k) {
            printf("4\n");
          } else if (i == k) {
            printf("5\n");
          }
        }
        printf("6\n");
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D6
data_type: string
name: retrieve_data
arguments: tag: D27
data_type: string

tool: D28: 2


tool: D6: 3


tool: D27: 6


assistant: ```c
int main() {
  int i, j, k;
  if (i == 1) {
    printf("1\n");
    goto next;
  } else {
    printf("2\n");
  }
  while (i < 123) {
    while (j < 456) {
      while (k < 789) {
        if (i == j) {
        next:
          printf("3\n");
        } else {
          if (j == k) {
            printf("4\n");
          } else if (i == k) {
            printf("5\n");
          }
        }
        printf("6\n");
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
L6:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D4: 2


tool: D15: 3


tool: D1: 6


assistant: ```c
int main() {
  int i, j, k;
  if (i == 1) {
    printf("1\n");
    goto next;
  } else {
    printf("2\n");
  }
  while (i < 123) {
    while (j < 456) {
      while (k < 789) {
        if (i == j) {
        next:
          printf("3\n");
        } else {
          if (j == k) {
            printf("4\n");
          } else if (i == k) {
            printf("5\n");
          }
        }
        printf("6\n");
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <printf@plt>
L8:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D27
data_type: string

tool: D26: 2


tool: D4: 3


tool: D27: 6


assistant: ```c
int main() {
  int i, j, k;
  if (i == 1) {
    printf("1\n");
    goto next;
  } else {
    printf("2\n");
  }
  while (i < 123) {
    while (j < 456) {
      while (k < 789) {
        if (i == j) {
        next:
          printf("3\n");
        } else {
          if (j == k) {
            printf("4\n");
          } else if (i == k) {
            printf("5\n");
          }
        }
        printf("6\n");
      }
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L17:
  subl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x0,-0x4(%rbp)
  js     L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L17
L23:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rtrim(char *str) {
  int i;
  for (i = strlen(str) - 1; i >= 0 && str[i] == ' '; i--)
    ;
  str[++i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L12
  movslq %eax,%rdx
  add    %rbx,%rdx
L1:
  cmpb   $0x20,(%rdx)
  jne    L12
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L1
L12:
  add    $0x1,%eax
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int rtrim(char *str) {
  int i;
  for (i = strlen(str) - 1; i >= 0 && str[i] == ' '; i--)
    ;
  str[++i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L12
  movslq %ecx,%rax
  add    %rbx,%rax
  jmp    L25
  nopl   0x0(%rax)
L3:
  sub    $0x1,%ecx
  lea    -0x1(%rdx),%rax
  cmp    $0xffffffff,%ecx
  je     L8
L25:
  cmpb   $0x20,(%rax)
  mov    %rax,%rdx
  je     L3
  lea    0x1(%rcx),%eax
L12:
  movslq %eax,%rdx
  add    %rbx,%rdx
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rtrim(char *str) {
  int i;
  for (i = strlen(str) - 1; i >= 0 && str[i] == ' '; i--)
    ;
  str[++i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L27
  movslq %ecx,%rax
  add    %rbx,%rax
  jmp    L16
  nopl   0x0(%rax)
L35:
  sub    $0x1,%ecx
  lea    -0x1(%rdx),%rax
  cmp    $0xffffffff,%ecx
  je     L25
L16:
  cmpb   $0x20,(%rax)
  mov    %rax,%rdx
  je     L35
  lea    0x1(%rcx),%eax
L27:
  movslq %eax,%rdx
  add    %rbx,%rdx
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rtrim(char *str) {
  int i;
  for (i = strlen(str) - 1; i >= 0 && str[i] == ' '; i--)
    ;
  str[++i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getinput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getalleles@plt>
  mov    $0x0,%eax
  call   <getdata@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getinput() {
  getalleles();
  getdata();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getinput>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getalleles@plt>
  mov    $0x0,%eax
  call   <getdata@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void getinput() {
  getalleles();
  getdata();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getinput>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getalleles@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getdata@plt>
```

assistant: ```c
void getinput() {
  getalleles();
  getdata();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getinput>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getalleles@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getdata@plt>
```

assistant: ```c
void getinput() {
  getalleles();
  getdata();
}
```
user: What is the c source code of the assembly code below:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x10(%rbp),%rbx
  nop
L7:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strcpy(char *__restrict s1, const char *__restrict s2) {
  register char *s = s1;
  while ((*s++ = *s2++) != 0)
    ;
  return s1;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *__restrict s1, const char *__restrict s2) {
  register char *s = s1;
  while ((*s++ = *s2++) != 0)
    ;
  return s1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L0
  ret
```

assistant: ```c
char *strcpy(char *__restrict s1, const char *__restrict s2) {
  register char *s = s1;
  while ((*s++ = *s2++) != 0)
    ;
  return s1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L3
  ret
```

assistant: ```c
char *strcpy(char *__restrict s1, const char *__restrict s2) {
  register char *s = s1;
  while ((*s++ = *s2++) != 0)
    ;
  return s1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<adddata>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %al,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x3f,%eax
  test   %eax,%eax
  jne    L29
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x2,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x10(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  and    $0x3f,%eax
  cmp    $0x3f,%eax
  jne    L21
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <enddata@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L26
L21:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int adddata(char *buff, int p, char d) {
  if ((p & 63) == 0) {
    buff[p] = 0;
    p += 2;
  }
  buff[p] = d;
  if ((p & 63) == 63)
    p = enddata(buff, p);
  else
    p++;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adddata>:
  endbr64
  test   $0x3f,%sil
  jne    L16
  movslq %esi,%rax
  movb   $0x0,(%rdi,%rax,1)
  add    $0x2,%esi
L16:
  movslq %esi,%rax
  mov    %dl,(%rdi,%rax,1)
  mov    %esi,%edx
  and    $0x3f,%edx
  lea    0x1(%rsi),%eax
  cmp    $0x3f,%edx
  je     L8
  ret
L8:
  sub    $0x8,%rsp
  call   <enddata@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int adddata(char *buff, int p, char d) {
  if ((p & 63) == 0) {
    buff[p] = 0;
    p += 2;
  }
  buff[p] = d;
  if ((p & 63) == 63)
    p = enddata(buff, p);
  else
    p++;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<adddata>:
  endbr64
  mov    %esi,%eax
  and    $0x3f,%eax
  jne    L18
  movslq %esi,%rax
  add    $0x2,%esi
  movb   $0x0,(%rdi,%rax,1)
  mov    %esi,%eax
  and    $0x3f,%eax
L18:
  movslq %esi,%rcx
  mov    %dl,(%rdi,%rcx,1)
  cmp    $0x3f,%eax
  je     L9
  lea    0x1(%rsi),%eax
  ret
  nopl   0x0(%rax)
L9:
  jmp    1050 <enddata@plt>
```

assistant: ```c
int adddata(char *buff, int p, char d) {
  if ((p & 63) == 0) {
    buff[p] = 0;
    p += 2;
  }
  buff[p] = d;
  if ((p & 63) == 63)
    p = enddata(buff, p);
  else
    p++;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<adddata>:
  endbr64
  mov    %esi,%eax
  and    $0x3f,%eax
  jne    L9
  movslq %esi,%rax
  add    $0x2,%esi
  movb   $0x0,(%rdi,%rax,1)
  mov    %esi,%eax
  and    $0x3f,%eax
L9:
  movslq %esi,%rcx
  mov    %dl,(%rdi,%rcx,1)
  cmp    $0x3f,%eax
  je     L8
  lea    0x1(%rsi),%eax
  ret
  nopl   0x0(%rax)
L8:
  jmp    1050 <enddata@plt>
```

assistant: ```c
int adddata(char *buff, int p, char d) {
  if ((p & 63) == 0) {
    buff[p] = 0;
    p += 2;
  }
  buff[p] = d;
  if ((p & 63) == 63)
    p = enddata(buff, p);
  else
    p++;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3039,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x19,%edx
  add    %edx,%eax
  and    $0x7f,%eax
  sub    %edx,%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string

tool: D19: %c


assistant: ```c
int main(void) {
  int a = 12345;
  char c;
  c = a % 128;
  printf("%c\n", a);
  printf("%c\n", c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x39,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x39,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: %c


assistant: ```c
int main(void) {
  int a = 12345;
  char c;
  c = a % 128;
  printf("%c\n", a);
  printf("%c\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    $0x39,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x39,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: %c


assistant: ```c
int main(void) {
  int a = 12345;
  char c;
  c = a % 128;
  printf("%c\n", a);
  printf("%c\n", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    $0x39,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x39,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string

tool: D9: %c


assistant: ```c
int main(void) {
  int a = 12345;
  char c;
  c = a % 128;
  printf("%c\n", a);
  printf("%c\n", c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mgrApConfigure>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <mgrSendMessageToLedController@plt>
  lea    D3(%rip),%rdi
  call   <mgrSendMessageToLedController@plt>
  lea    D5(%rip),%rdi
  call   <mgrSendMessageToLedController@plt>
  lea    D21(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string

tool: D22: /led/red/off

tool: D3: /led/green/blink

tool: D5: /led/orange/off

tool: D21: /usr/bin/python /pws/py/ap_conf.py &

assistant: ```c
int mgrApConfigure(int code, void *arg1, void *arg2) {
  static const char *cmd = "/usr/bin/python /pws/py/ap_conf.py &";
  ;
  mgrSendMessageToLedController("/led/red/off");
  mgrSendMessageToLedController("/led/green/blink");
  mgrSendMessageToLedController("/led/orange/off");
  system(cmd);
  return 0;
}
```