ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_max_multi>:
  endbr64
  mov    (%rdi),%rax
  movsd  (%rax),%xmm0
  test   %edx,%edx
  jle    L20
  mov    %edx,%r8d
  mov    $0x0,%ecx
  jmp    L13
L21:
  mov    (%rdi,%rcx,8),%rax
  lea    -0x1(%rdx),%edx
  lea    0x8(%rax,%rdx,8),%rdx
L6:
  maxsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
L52:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L20
L13:
  mov    (%rsi,%rcx,4),%edx
  test   %edx,%edx
  jg     L21
  jmp    L52
L20:
  ret
```

assistant: ```c
double find_max_multi(double **array, int *n, int m) {
  int i;
  int j;
  double max = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      max = (array[i][j] < max) ? max : array[i][j];
    }
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_max_multi>:
  endbr64
  mov    (%rdi),%rax
  mov    %rdi,%r9
  movsd  (%rax),%xmm0
  test   %edx,%edx
  jle    L3
  movslq %edx,%r8
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L43:
  mov    (%rsi,%rdi,4),%eax
  test   %eax,%eax
  jle    L6
  mov    (%r9,%rdi,8),%rdx
  lea    -0x1(%rax),%ecx
  lea    0x8(%rdx),%rax
  lea    (%rax,%rcx,8),%rcx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x8,%rax
L16:
  maxsd  (%rdx),%xmm0
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L40
L6:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L43
L3:
  ret
```

assistant: ```c
double find_max_multi(double **array, int *n, int m) {
  int i;
  int j;
  double max = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      max = (array[i][j] < max) ? max : array[i][j];
    }
  }
  return max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_max_multi>:
  endbr64
  mov    (%rdi),%rax
  mov    %rdi,%r9
  movsd  (%rax),%xmm0
  test   %edx,%edx
  jle    L44
  movslq %edx,%r8
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%rsi,%rdi,4),%eax
  test   %eax,%eax
  jle    L48
  mov    (%r9,%rdi,8),%rdx
  lea    -0x1(%rax),%ecx
  lea    0x8(%rdx),%rax
  lea    (%rax,%rcx,8),%rcx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x8,%rax
L8:
  maxsd  (%rdx),%xmm0
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L16
L48:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L31
L44:
  ret
```

assistant: ```c
double find_max_multi(double **array, int *n, int m) {
  int i;
  int j;
  double max = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      max = (array[i][j] < max) ? max : array[i][j];
    }
  }
  return max;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x64(%rbp)
  movl   $0x0,-0x60(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L43
L77:
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  jmp    L57
L22:
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %eax,%edx
  mov    -0x60(%rbp),%eax
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x60(%rbp)
  mov    -0x50(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x50(%rbp)
L57:
  cmpq   $0x0,-0x50(%rbp)
  jg     L22
  mov    -0x60(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x68(%rbp)
  jmp    L6
L46:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    %eax,-0x5c(%rbp)
  cmpl   $0x1a,-0x5c(%rbp)
  jg     L49
  addl   $0x1,-0x64(%rbp)
L49:
  subl   $0x1,-0x68(%rbp)
L6:
  cmpl   $0x0,-0x68(%rbp)
  jg     L46
  mov    -0x64(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x64(%rbp)
  movl   $0x0,-0x60(%rbp)
  mov    -0x70(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x6c(%rbp)
  je     L58
  mov    $0xa,%edi
  call   <putchar@plt>
L58:
  addl   $0x1,-0x6c(%rbp)
L43:
  mov    -0x70(%rbp),%eax
  cmp    %eax,-0x6c(%rbp)
  jl     L77
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D25
data_type: string

tool: D26: %d

tool: D25: %lld

assistant: ```c
main() {
  int t, s, i, k, arr[11];
  int l = 1, m = 0;
  long long int a, j, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%lld", &a);
    for (j = a; j >= 1; j = j / 10) {
      n = j;
      n = n % 10;
      arr[m] = n;
      m++;
    }
    for (k = m - 1; k > 0; k--) {
      s = arr[k] * 10 + arr[k - 1];
      if (s < 27)
        l++;
    }
    printf("%d", l);
    l = 1;
    m = 0;
    if (i != (t - 1))
      printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L42
  mov    $0x0,%ebp
  lea    0x8(%rsp),%r14
  lea    D23(%rip),%r13
  movabs $0x6666666666666667,%rbx
  lea    D11(%rip),%r12
  jmp    L6
L22:
  mov    $0x1,%esi
  jmp    L80
L119:
  mov    $0x1,%esi
  jmp    L80
L27:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L42
L6:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  jle    L22
  mov    $0x0,%esi
L73:
  mov    %esi,%edi
  mov    %rcx,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rcx,%r8
  sub    %rax,%r8
  mov    %r8d,0x10(%rsp,%rsi,4)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  add    $0x1,%rsi
  cmp    $0x9,%rax
  jg     L73
  test   %edi,%edi
  jle    L119
  movslq %edi,%rdi
  shl    $0x2,%rdi
  lea    0x10(%rsp,%rdi,1),%rax
  lea    0xc(%rsp,%rdi,1),%rdi
  lea    -0x1(%rdx),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rdi
  mov    $0x1,%esi
L44:
  mov    (%rax),%edx
  lea    (%rdx,%rdx,4),%ecx
  mov    -0x4(%rax),%edx
  lea    (%rdx,%rcx,2),%edx
  cmp    $0x1b,%edx
  setl   %dl
  movzbl %dl,%edx
  add    %edx,%esi
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L44
L80:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  je     L27
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L27
L42:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D23
type_guessed: string

tool: D11: %d

tool: D23: %lld

assistant: ```c
main() {
  int t, s, i, k, arr[11];
  int l = 1, m = 0;
  long long int a, j, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%lld", &a);
    for (j = a; j >= 1; j = j / 10) {
      n = j;
      n = n % 10;
      arr[m] = n;
      m++;
    }
    for (k = m - 1; k > 0; k--) {
      s = arr[k] * 10 + arr[k - 1];
      if (s < 27)
        l++;
    }
    printf("%d", l);
    l = 1;
    m = 0;
    if (i != (t - 1))
      printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  movabs $0xcccccccccccccccd,%r14
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x8(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L21
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  xor    %edi,%edi
  lea    0x10(%rsp),%rcx
  test   %rsi,%rsi
  jle    L40
  nopw   0x0(%rax,%rax,1)
L77:
  mov    %rsi,%rax
  mov    %rsi,%r9
  mov    %edi,%r8d
  mul    %r14
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r9
  mov    %r9d,(%rcx,%rdi,4)
  mov    %r9d,%eax
  mov    %rsi,%r9
  add    $0x1,%rdi
  mov    %rdx,%rsi
  cmp    $0x9,%r9
  jg     L77
  test   %r8d,%r8d
  je     L40
  movslq %r8d,%rsi
  shl    $0x2,%rsi
  lea    (%rcx,%rsi,1),%rdx
  lea    -0x1(%r8),%ecx
  lea    0xc(%rsp,%rsi,1),%rdi
  shl    $0x2,%rcx
  mov    $0x1,%esi
  sub    %rcx,%rdi
  nopw   0x0(%rax,%rax,1)
L73:
  lea    (%rax,%rax,4),%ecx
  mov    -0x4(%rdx),%eax
  lea    (%rax,%rcx,2),%ecx
  cmp    $0x1b,%ecx
  setl   %cl
  sub    $0x4,%rdx
  movzbl %cl,%ecx
  add    %ecx,%esi
  cmp    %rdi,%rdx
  jne    L73
L27:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %ebx,%edx
  je     L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
L2:
  add    $0x1,%ebx
  cmp    %ebx,%eax
  jg     L52
L21:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  mov    $0x1,%esi
  jmp    L27
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D19
datatype: string

tool: D15: %lld

tool: D19: %d

assistant: ```c
main() {
  int t, s, i, k, arr[11];
  int l = 1, m = 0;
  long long int a, j, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%lld", &a);
    for (j = a; j >= 1; j = j / 10) {
      n = j;
      n = n % 10;
      arr[m] = n;
      m++;
    }
    for (k = m - 1; k > 0; k--) {
      s = arr[k] * 10 + arr[k - 1];
      if (s < 27)
        l++;
    }
    printf("%d", l);
    l = 1;
    m = 0;
    if (i != (t - 1))
      printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L52
L47:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jle    L63
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jle    L63
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jle    L117
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L15
L119:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L119
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L117:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L52
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L58
L97:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L97
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
L52:
  cmpl   $0x1,-0xc(%rbp)
  je     L47
L63:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D11: %d%d

tool: D17: %d 

tool: D2: Sum=%d


assistant: ```c
int main() {
  int m, n, i, j, sum = 0;
  for (i = 1; i == 1;) {
    scanf("%d%d", &m, &n);
    if (m <= 0 || n <= 0) {
      break;
    } else if (m > n) {
      for (j = n; j <= m; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    } else if (m < n) {
      for (j = m; j <= n; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  lea    D10(%rip),%r13
  lea    D0(%rip),%r12
  lea    D14(%rip),%r15
  jmp    L7
L38:
  mov    $0x0,%ebp
L26:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    %ebx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L26
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <printf@plt>
L7:
  mov    %rsp,%rsi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  test   %ebp,%ebp
  jle    L61
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jle    L61
  cmp    %ebx,%ebp
  jg     L38
  jge    L7
  mov    $0x0,%ebx
L17:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    %ebp,%ebx
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jge    L17
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L7
L61:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string

tool: D10: %d%d

tool: D0: %d 

tool: D14: Sum=%d


assistant: ```c
int main() {
  int m, n, i, j, sum = 0;
  for (i = 1; i == 1;) {
    scanf("%d%d", &m, &n);
    if (m <= 0 || n <= 0) {
      break;
    } else if (m > n) {
      for (j = n; j <= m; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    } else if (m < n) {
      for (j = m; j <= n; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  mov    %rsp,%r13
  nopl   0x0(%rax)
L48:
  mov    %r14,%rdx
  mov    %r13,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r15d
  test   %r15d,%r15d
  jle    L5
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  jle    L5
  cmp    %r12d,%r15d
  jg     L32
  jge    L48
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  add    %r15d,%ebp
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x4(%rsp)
  jge    L70
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L48
  nopl   0x0(%rax)
L32:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L86:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  add    %r12d,%ebp
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,(%rsp)
  jge    L86
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string

tool: D6: %d 

tool: D13: %d%d

tool: D18: Sum=%d


assistant: ```c
int main() {
  int m, n, i, j, sum = 0;
  for (i = 1; i == 1;) {
    scanf("%d%d", &m, &n);
    if (m <= 0 || n <= 0) {
      break;
    } else if (m > n) {
      for (j = n; j <= m; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    } else if (m < n) {
      for (j = m; j <= n; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D39(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  mov    %rsp,%r13
  nopl   0x0(%rax)
L72:
  mov    %r14,%rdx
  mov    %r13,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r15d
  test   %r15d,%r15d
  jle    L36
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  jle    L36
  cmp    %r12d,%r15d
  jg     L9
  jge    L72
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L77:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  add    %r15d,%ebp
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x4(%rsp)
  jge    L77
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L72
  nopl   0x0(%rax)
L9:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  add    %r12d,%ebp
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,(%rsp)
  jge    L31
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D39
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D21
type: string

tool: D39: %d 

tool: D24: %d%d

tool: D21: Sum=%d


assistant: ```c
int main() {
  int m, n, i, j, sum = 0;
  for (i = 1; i == 1;) {
    scanf("%d%d", &m, &n);
    if (m <= 0 || n <= 0) {
      break;
    } else if (m > n) {
      for (j = n; j <= m; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    } else if (m < n) {
      for (j = m; j <= n; j++) {
        printf("%d ", j);
        sum = sum + j;
      }
      printf("Sum=%d\n", sum);
      sum = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fts_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x40,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L52
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  jne    L7
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x38(%rdx)
  mov    -0x8(%rbp),%rax
  mov    0x38(%rax),%rax
  test   %rax,%rax
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L52
L7:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L51
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x38(%rax)
L51:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x34(%rax),%eax
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <memmove@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  ja     L50
  mov    -0x28(%rbp),%rax
  mov    %eax,%eax
  jmp    L65
L50:
  mov    D18(%rip),%rax
  mov    (%rax),%rax
L65:
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x30(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x28(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x20(%rax)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x18(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    -0x8(%rbp),%rax
L52:
  leave
  ret
```

assistant: ```c
FTSENT *fts_alloc(FTS *sp, const char *name, size_t namelen) {
  FTSENT *p;
  ;
  ;
  if ((p = malloc(sizeof(FTSENT) + namelen)) == NULL)
    return (NULL);
  if (!(sp->fts_options & (FTS_NOSTAT)))
    if ((p->fts_statp = malloc(sizeof(*(p->fts_statp)))) == NULL) {
      free(p);
      return (NULL);
    }
  if ((sp->fts_options & (FTS_NOSTAT)))
    p->fts_statp = NULL;
  memmove(p->fts_name, name, namelen + 1);
  p->fts_namelen = ((namelen) > UINT_MAX ? UINT_MAX : (unsigned int)(namelen));
  p->fts_path = sp->fts_path;
  p->fts_errno = 0;
  p->fts_flags = 0;
  p->fts_instr = FTS_NOINSTR;
  p->fts_number = 0;
  p->fts_pointer = NULL;
  return (p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fts_alloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  lea    0x40(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    (%r12),%eax
  mov    D5(%rip),%rdx
  and    (%rdx),%eax
  je     L19
L30:
  movq   $0x0,0x38(%rbx)
  jmp    L24
L19:
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,0x38(%rbx)
  test   %rax,%rax
  je     L48
  mov    (%r12),%eax
  mov    D5(%rip),%rdx
  and    (%rdx),%eax
  jne    L30
L24:
  lea    0x1(%rbp),%rdx
  mov    0x34(%rbx),%edi
  mov    %r13,%rsi
  call   <memmove@plt>
  mov    D38(%rip),%rax
  mov    (%rax),%rax
  mov    %ebp,%edx
  cmp    %rbp,%rax
  cmovae %rdx,%rax
  mov    %rax,(%rbx)
  mov    0x4(%r12),%eax
  mov    %eax,0x30(%rbx)
  movq   $0x0,0x28(%rbx)
  movq   $0x0,0x20(%rbx)
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rbx)
  movq   $0x0,0x10(%rbx)
  movq   $0x0,0x8(%rbx)
L9:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r14,%rbx
  jmp    L9
```

assistant: ```c
FTSENT *fts_alloc(FTS *sp, const char *name, size_t namelen) {
  FTSENT *p;
  ;
  ;
  if ((p = malloc(sizeof(FTSENT) + namelen)) == NULL)
    return (NULL);
  if (!(sp->fts_options & (FTS_NOSTAT)))
    if ((p->fts_statp = malloc(sizeof(*(p->fts_statp)))) == NULL) {
      free(p);
      return (NULL);
    }
  if ((sp->fts_options & (FTS_NOSTAT)))
    p->fts_statp = NULL;
  memmove(p->fts_name, name, namelen + 1);
  p->fts_namelen = ((namelen) > UINT_MAX ? UINT_MAX : (unsigned int)(namelen));
  p->fts_path = sp->fts_path;
  p->fts_errno = 0;
  p->fts_flags = 0;
  p->fts_instr = FTS_NOINSTR;
  p->fts_number = 0;
  p->fts_pointer = NULL;
  return (p);
}
```