ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<Test19>:
  endbr64
  push   %r12
  lea    D16(%rip),%r12
  mov    $0x28,%edx
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strlcpy@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <__builtin_object_size@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x28,%edx
  mov    %eax,%ecx
  call   <__builtin___strlcpy_chk@plt>
  mov    $0x28,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <__builtin_object_size@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  mov    $0x28,%edx
  pop    %r12
  jmp    10b0 <__builtin___strlcat_chk@plt>
```

assistant: ```c
void Test19(void) {
  static char b[40];
  static char buf[20];
  strlcpy(buf, b, sizeof(b));
  __builtin___strlcpy_chk(buf, b, sizeof(b), __builtin_object_size(buf, 0));
  strlcat(buf, b, sizeof(b));
  __builtin___strlcat_chk(buf, b, sizeof(b), __builtin_object_size(buf, 0));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bzero_5>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rsi,%r15
  and    $0xffffffffffffffc0,%r15
  lea    (%rdi,%r15,1),%r12
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%ebp
  cmp    %r12,%r14
  je     L114
  mov    %r14,%rbx
L107:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_mm_storeu_si128@plt>
  lea    0x4(%rbx),%rdi
  mov    %ebp,%esi
  call   <_mm_storeu_si128@plt>
  lea    0x8(%rbx),%rdi
  mov    %ebp,%esi
  call   <_mm_storeu_si128@plt>
  lea    0xc(%rbx),%rdi
  mov    %ebp,%esi
  call   <_mm_storeu_si128@plt>
  add    $0x40,%rbx
  cmp    %rbx,%r12
  ja     L107
  lea    0x1(%r14),%rax
  cmp    %rax,%r12
  mov    $0x40,%eax
  cmovb  %rax,%r15
  lea    (%r14,%r15,1),%r12
  test   $0x3f,%r13b
  je     L86
L112:
  test   $0x20,%r13b
  jne    L153
L47:
  test   $0x10,%r13b
  jne    L14
L33:
  test   $0x8,%r13b
  je     L85
  movq   $0x0,(%r12)
  test   $0x7,%r13b
  je     L86
  add    $0x8,%r12
L85:
  test   $0x4,%r13b
  je     L148
  movq   $0x0,(%r12)
  test   $0x3,%r13b
  je     L86
  add    $0x4,%r12
L148:
  test   $0x2,%r13b
  je     L105
  movq   $0x0,(%r12)
  test   $0x1,%r13b
  je     L86
  add    $0x2,%r12
L105:
  movq   $0x0,(%r12)
L86:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L114:
  test   %r13,%r13
  jne    L112
  jmp    L86
L153:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_mm_storeu_si128@plt>
  lea    0x4(%r12),%rdi
  mov    %ebp,%esi
  call   <_mm_storeu_si128@plt>
  test   $0x1f,%r13b
  je     L86
  add    $0x20,%r12
  jmp    L47
L14:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_mm_storeu_si128@plt>
  test   $0xf,%r13b
  je     L86
  add    $0x10,%r12
  jmp    L33
```

assistant: ```c
void bzero_5(char *s, size_t n) {
  char *e = s + (n & ~63);
  __m128i zero = _mm_setzero_si128();
  if (s != e) {
#pragma clang loop unroll(disable)
    do {
      _mm_storeu_si128(&(((__m128i *)s)[0]), zero);
      _mm_storeu_si128(&(((__m128i *)s)[1]), zero);
      _mm_storeu_si128(&(((__m128i *)s)[2]), zero);
      _mm_storeu_si128(&(((__m128i *)s)[3]), zero);
      s += 64;
    } while (s < e);
    if ((n & 63) == 0)
      return;
  } else {
    if (n == 0)
      return;
  }
  if ((n & 32) != 0) {
    _mm_storeu_si128(&(((__m128i *)s)[0]), zero);
    _mm_storeu_si128(&(((__m128i *)s)[1]), zero);
    if ((n & 31) == 0)
      return;
    s += 32;
  }
  if ((n & 16) != 0) {
    _mm_storeu_si128(&(((__m128i *)s)[0]), zero);
    if ((n & 15) == 0)
      return;
    s += 16;
  }
  if ((n & 8) != 0) {
    ((int64_t *)s)[0] = 0;
    if ((n & 7) == 0)
      return;
    s += 8;
  }
  if ((n & 4) != 0) {
    ((int32_t *)s)[0] = 0;
    if ((n & 3) == 0)
      return;
    s += 4;
  }
  if ((n & 2) != 0) {
    ((int16_t *)s)[0] = 0;
    if ((n & 1) == 0)
      return;
    s += 2;
  }
  ((int8_t *)s)[0] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_fdct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_fdct(void) {
  signed int i;
  signed int j;
  double s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_fdct>:
  endbr64
  ret
```

assistant: ```c
void init_fdct(void) {
  signed int i;
  signed int j;
  double s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_fdct>:
  endbr64
  ret
```

assistant: ```c
void init_fdct(void) {
  signed int i;
  signed int j;
  double s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pow_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char pow_2(int j) {
  int k = 1;
  k = k << j;
  return k;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pow_2>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned char pow_2(int j) {
  int k = 1;
  k = k << j;
  return k;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pow_2>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned char pow_2(int j) {
  int k = 1;
  k = k << j;
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pow_2>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned char pow_2(int j) {
  int k = 1;
  k = k << j;
  return k;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L30
L15:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L48
L42:
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D20
type_guessed: string

tool: D11: %d

tool: D17: num(%d=%d*%d) is not a prime.

tool: D20: %d is a prime.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  for (int i = 2; i < num; i++) {
    if (num % i == 0) {
      printf("num(%d=%d*%d) is not a prime.", num, i, num / i);
      return 0;
    }
  }
  printf("%d is a prime.", num);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x2,%edi
  jle    L26
  test   $0x1,%dil
  je     L69
  mov    $0x2,%esi
L25:
  add    $0x1,%esi
  cmp    %edi,%esi
  je     L26
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L25
L38:
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L69:
  mov    $0x2,%esi
  jmp    L38
L26:
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type: string
name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D8
type: string

tool: D17: %d

tool: D20: num(%d=%d*%d) is not a prime.

tool: D8: %d is a prime.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  for (int i = 2; i < num; i++) {
    if (num % i == 0) {
      printf("num(%d=%d*%d) is not a prime.", num, i, num / i);
      return 0;
    }
  }
  printf("%d is a prime.", num);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L28
  mov    $0x2,%r8d
  test   $0x1,%sil
  jne    L27
  jmp    L53
L67:
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L53
L27:
  add    $0x1,%r8d
  cmp    %r8d,%esi
  jne    L67
L28:
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L53:
  mov    %esi,%eax
  lea    D19(%rip),%rdi
  cltd
  idiv   %r8d
  mov    %r8d,%edx
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L37
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D19
data_type: string

tool: D23: %d

tool: D29: %d is a prime.

tool: D19: num(%d=%d*%d) is not a prime.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  for (int i = 2; i < num; i++) {
    if (num % i == 0) {
      printf("num(%d=%d*%d) is not a prime.", num, i, num / i);
      return 0;
    }
  }
  printf("%d is a prime.", num);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L55
  mov    $0x2,%r8d
  test   $0x1,%sil
  jne    L11
  jmp    L47
L33:
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L47
L11:
  add    $0x1,%r8d
  cmp    %r8d,%esi
  jne    L33
L55:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L47:
  mov    %esi,%eax
  lea    D26(%rip),%rdi
  cltd
  idiv   %r8d
  mov    %r8d,%edx
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string

tool: D3: %d

tool: D13: %d is a prime.

tool: D26: num(%d=%d*%d) is not a prime.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  for (int i = 2; i < num; i++) {
    if (num % i == 0) {
      printf("num(%d=%d*%d) is not a prime.", num, i, num / i);
      return 0;
    }
  }
  printf("%d is a prime.", num);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<colemak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    $0x60,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x55,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D0:  1234567890-=qwfpgjluy;[]\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO"ZXCVBXM<>?

assistant: ```c
int colemak(char layout[][96], int i) {
  strncpy(layout[i], " 1234567890-=qwfpgjluy;[]\\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO\"ZXCVBXM<>?", 96);
  return 85;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<colemak>:
  endbr64
  sub    $0x8,%rsp
  movslq %esi,%rsi
  lea    (%rsi,%rsi,2),%rax
  shl    $0x5,%rax
  add    %rax,%rdi
  mov    $0x60,%edx
  lea    D8(%rip),%rsi
  call   <strncpy@plt>
  mov    $0x55,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8:  1234567890-=qwfpgjluy;[]\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO"ZXCVBXM<>?

assistant: ```c
int colemak(char layout[][96], int i) {
  strncpy(layout[i], " 1234567890-=qwfpgjluy;[]\\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO\"ZXCVBXM<>?", 96);
  return 85;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<colemak>:
  endbr64
  movslq %esi,%rsi
  sub    $0x8,%rsp
  mov    $0x60,%edx
  lea    (%rsi,%rsi,2),%rax
  lea    D4(%rip),%rsi
  shl    $0x5,%rax
  add    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x55,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4:  1234567890-=qwfpgjluy;[]\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO"ZXCVBXM<>?

assistant: ```c
int colemak(char layout[][96], int i) {
  strncpy(layout[i], " 1234567890-=qwfpgjluy;[]\\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO\"ZXCVBXM<>?", 96);
  return 85;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<colemak>:
  endbr64
  movslq %esi,%rsi
  sub    $0x8,%rsp
  mov    $0x60,%edx
  lea    (%rsi,%rsi,2),%rax
  lea    D8(%rip),%rsi
  shl    $0x5,%rax
  add    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x55,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8:  1234567890-=qwfpgjluy;[]\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO"ZXCVBXM<>?

assistant: ```c
int colemak(char layout[][96], int i) {
  strncpy(layout[i], " 1234567890-=qwfpgjluy;[]\\arstdhneio'zxcvbkm,./!@#$%^&*()_+QWFPGJLUY:{}|ARSTDHNEIO\"ZXCVBXM<>?", 96);
  return 85;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<yy_2_MagicWordAutoCorrect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yy_2_MagicWordAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yy_2_MagicWordAutoCorrect>:
  endbr64
  ret
```

assistant: ```c
void yy_2_MagicWordAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yy_2_MagicWordAutoCorrect>:
  endbr64
  ret
```

assistant: ```c
void yy_2_MagicWordAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yy_2_MagicWordAutoCorrect>:
  endbr64
  ret
```

assistant: ```c
void yy_2_MagicWordAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L14:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *src) {
  int nr_char = 0;
  while (*src) {
    src++;
    nr_char++;
  }
  return nr_char;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  mov    $0x0,%eax
L0:
  add    $0x1,%rdi
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L0
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strlen(const char *src) {
  int nr_char = 0;
  while (*src) {
    src++;
    nr_char++;
  }
  return nr_char;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L16
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L10
  ret
  nopl   (%rax)
L16:
  ret
```

assistant: ```c
int strlen(const char *src) {
  int nr_char = 0;
  while (*src) {
    src++;
    nr_char++;
  }
  return nr_char;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L1
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rdi
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L14
  ret
  nopl   (%rax)
L1:
  ret
```

assistant: ```c
int strlen(const char *src) {
  int nr_char = 0;
  while (*src) {
    src++;
    nr_char++;
  }
  return nr_char;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_cp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L0
L18:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *str_cp(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_cp>:
  endbr64
  mov    %rdi,%rax
  lea    0x1(%rsi),%rdx
  movzbl (%rsi),%ecx
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L5
L16:
  add    $0x1,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L16
L5:
  ret
```

assistant: ```c
char *str_cp(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_cp>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  lea    0x1(%rsi),%rdx
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L0
  nopl   0x0(%rax)
L13:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L13
L0:
  ret
```

assistant: ```c
char *str_cp(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_cp>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  lea    0x1(%rsi),%rdx
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L14
  nopl   0x0(%rax)
L11:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L11
L14:
  ret
```

assistant: ```c
char *str_cp(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Memory_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  jmp    L1
L11:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: [memory.c] Could not reallocate %d bytes


assistant: ```c
void *Memory_realloc(void *memblock, size_t size) {
  void *ptr;
  ptr = realloc(memblock, size);
  if (ptr != ((void *)0)) {
    return ptr;
  }
  printf("[memory.c] Could not reallocate %d bytes\n", size);
  return ((void *)0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Memory_realloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L15:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: [memory.c] Could not reallocate %d bytes


assistant: ```c
void *Memory_realloc(void *memblock, size_t size) {
  void *ptr;
  ptr = realloc(memblock, size);
  if (ptr != ((void *)0)) {
    return ptr;
  }
  printf("[memory.c] Could not reallocate %d bytes\n", size);
  return ((void *)0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Memory_realloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: [memory.c] Could not reallocate %d bytes


assistant: ```c
void *Memory_realloc(void *memblock, size_t size) {
  void *ptr;
  ptr = realloc(memblock, size);
  if (ptr != ((void *)0)) {
    return ptr;
  }
  printf("[memory.c] Could not reallocate %d bytes\n", size);
  return ((void *)0);
}
```
user: What is the c source code of the assembly code below?

```asm
<Memory_realloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: [memory.c] Could not reallocate %d bytes


assistant: ```c
void *Memory_realloc(void *memblock, size_t size) {
  void *ptr;
  ptr = realloc(memblock, size);
  if (ptr != ((void *)0)) {
    return ptr;
  }
  printf("[memory.c] Could not reallocate %d bytes\n", size);
  return ((void *)0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L112
L52:
  movl   $0x0,-0x8(%rbp)
  jmp    L95
L58:
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L22:
  mov    -0xc(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmpl   $0x0,-0x4(%rbp)
  je     L61
  mov    -0x4(%rbp),%esi
  jmp    L93
L61:
  mov    $0x1,%esi
L93:
  cltd
  idiv   %esi
  mov    %edx,%ecx
  mov    %ecx,%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    $0x8,%eax
  je     L114
L11:
  cmpl   $0x9,-0x4(%rbp)
  jle    L22
  jmp    L47
L114:
  nop
L47:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  je     L55
  addl   $0x1,-0x8(%rbp)
L95:
  cmpl   $0x9,-0x8(%rbp)
  jle    L58
  jmp    L78
L55:
  nop
L78:
  addl   $0x1,-0xc(%rbp)
L112:
  cmpl   $0x9,-0xc(%rbp)
  jle    L52
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int sum = 0;
  int i, j, k;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      k = 0;
      while (k < 10) {
        sum += ((i - 2 + j) % (k == 0 ? 1 : k));
        k++;
        if ((k + i) == 8) {
          break;
        }
      }
      if ((i + j) % 3 == 2) {
        break;
      }
    }
  }
  return sum % 100;
}
```