ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<sqlUshortArrayToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <newDyString@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L28
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dyStringPrintf@plt>
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <dyStringCannibalize@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: %u,

assistant: ```c
char *sqlUshortArrayToString(unsigned short *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sqlUshortArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L19
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x2(%r12,%rax,2),%r12
  lea    D8(%rip),%rbp
L1:
  movzwl (%rbx),%edx
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <dyStringPrintf@plt>
  add    $0x2,%rbx
  cmp    %r12,%rbx
  jne    L1
L19:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8: %u,

assistant: ```c
char *sqlUshortArrayToString(unsigned short *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqlUshortArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L29
  mov    %rax,%rdi
  lea    -0x1(%rbp),%eax
  lea    D3(%rip),%rbp
  lea    0x2(%rbx,%rax,2),%r12
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%rsp),%rdi
L6:
  movzwl (%rbx),%edx
  mov    %rbp,%rsi
  add    $0x2,%rbx
  call   <dyStringPrintf@plt>
  cmp    %r12,%rbx
  jne    L30
L29:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: %u,

assistant: ```c
char *sqlUshortArrayToString(unsigned short *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sqlUshortArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L25
  mov    %rax,%rdi
  lea    -0x1(%rbp),%eax
  lea    D6(%rip),%rbp
  lea    0x2(%rbx,%rax,2),%r12
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rsp),%rdi
L33:
  movzwl (%rbx),%edx
  mov    %rbp,%rsi
  add    $0x2,%rbx
  call   <dyStringPrintf@plt>
  cmp    %r12,%rbx
  jne    L6
L25:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %u,

assistant: ```c
char *sqlUshortArrayToString(unsigned short *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<high_level>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  jmp    L1
```

assistant: ```c
void high_level() {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<high_level>:
  endbr64
L9:
  jmp    L9
```

assistant: ```c
void high_level() {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<high_level>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
void high_level() {
  while (1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<high_level>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void high_level() {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int s;
  s = socket(AF_INET, SOCK_STREAM, 0);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int s;
  s = socket(AF_INET, SOCK_STREAM, 0);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int s;
  s = socket(AF_INET, SOCK_STREAM, 0);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int s;
  s = socket(AF_INET, SOCK_STREAM, 0);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<TexcoordWrap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  mov    -0xc(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L17
  mov    -0x4(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L17
  mov    -0x4(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  and    %edx,%eax
  jmp    L22
L17:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  and    -0x4(%rbp),%eax
  jmp    L22
L3:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <clamp@plt>
L22:
  leave
  ret
```

assistant: ```c
int TexcoordWrap(int c, int maxc, int mode) {
  if ((mode & (1 << 0)) != 0) {
    if ((mode & (1 << 2)) != 0 && (c & maxc) != 0)
      return (maxc - 1) - (c & (maxc - 1));
    else
      return (c & (maxc - 1));
  } else
    return clamp(c, 0, maxc - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<TexcoordWrap>:
  endbr64
  test   $0x1,%dl
  je     L14
  test   $0x4,%dl
  je     L19
  test   %edi,%esi
  je     L19
  not    %edi
  lea    -0x1(%rsi),%eax
  and    %edi,%eax
  ret
L19:
  lea    -0x1(%rsi),%eax
  and    %edi,%eax
  ret
L14:
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%edx
  mov    $0x0,%esi
  call   <clamp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int TexcoordWrap(int c, int maxc, int mode) {
  if ((mode & (1 << 0)) != 0) {
    if ((mode & (1 << 2)) != 0 && (c & maxc) != 0)
      return (maxc - 1) - (c & (maxc - 1));
    else
      return (c & (maxc - 1));
  } else
    return clamp(c, 0, maxc - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TexcoordWrap>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   $0x1,%dl
  je     L19
  and    $0x4,%edx
  je     L8
  test   %edi,%esi
  je     L8
  not    %edi
  and    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  and    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %eax,%edx
  xor    %esi,%esi
  jmp    1050 <clamp@plt>
```

assistant: ```c
int TexcoordWrap(int c, int maxc, int mode) {
  if ((mode & (1 << 0)) != 0) {
    if ((mode & (1 << 2)) != 0 && (c & maxc) != 0)
      return (maxc - 1) - (c & (maxc - 1));
    else
      return (c & (maxc - 1));
  } else
    return clamp(c, 0, maxc - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TexcoordWrap>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   $0x1,%dl
  je     L9
  and    $0x4,%edx
  je     L19
  test   %edi,%esi
  je     L19
  not    %edi
  and    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  and    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %eax,%edx
  xor    %esi,%esi
  jmp    1050 <clamp@plt>
```

assistant: ```c
int TexcoordWrap(int c, int maxc, int mode) {
  if ((mode & (1 << 0)) != 0) {
    if ((mode & (1 << 2)) != 0 && (c & maxc) != 0)
      return (maxc - 1) - (c & (maxc - 1));
    else
      return (c & (maxc - 1));
  } else
    return clamp(c, 0, maxc - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<murder_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L19
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <murder_stack>
  jmp    L13
L19:
  nop
L13:
  leave
  ret
```

assistant: ```c
void murder_stack(unsigned int depth) {
  if (!depth)
    return;
  murder_stack(depth - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<murder_stack>:
  endbr64
  test   %edi,%edi
  jne    L4
  ret
L4:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <murder_stack>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void murder_stack(unsigned int depth) {
  if (!depth)
    return;
  murder_stack(depth - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<murder_stack>:
  endbr64
  ret
```

assistant: ```c
void murder_stack(unsigned int depth) {
  if (!depth)
    return;
  murder_stack(depth - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<murder_stack>:
  endbr64
  ret
```

assistant: ```c
void murder_stack(unsigned int depth) {
  if (!depth)
    return;
  murder_stack(depth - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i_contain_r>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  or     %esi,%edi
  je     L152
  mov    %esi,%r8d
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %esi,%edi
  sub    %eax,%edi
  test   %ecx,%ecx
  jle    L106
  push   %rbx
  jmp    L110
L37:
  mov    %edi,%edx
  jmp    L95
L42:
  mov    %r8d,%r9d
L51:
  test   %r9d,%r9d
  je     L0
  test   %ecx,%ecx
  jle    L28
L110:
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  cmp    %dl,%dil
  je     L37
L124:
  mov    %ecx,%esi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  cmp    %al,%dil
  je     L68
  cmp    $0x9,%esi
  jg     L124
L68:
  test   %ecx,%ecx
  je     L90
L95:
  cmp    %dil,%dl
  sete   %dl
  test   %ecx,%ecx
  setg   %al
  test   %al,%dl
  je     L42
  test   %r8d,%r8d
  jle    L42
  mov    %r8d,%r9d
L75:
  mov    %ecx,%r11d
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  mov    %r9d,%r10d
  movslq %r9d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  mov    %eax,%r9d
  movslq %edx,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %edx,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%esi
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %eax,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%esi
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  cmp    %al,%dl
  jne    L51
  cmp    $0x9,%r11d
  setg   %dl
  cmp    $0x9,%r10d
  setg   %al
  test   %al,%dl
  jne    L75
  jmp    L51
L28:
  mov    $0x0,%eax
L148:
  pop    %rbx
  ret
L90:
  mov    %ecx,%eax
  jmp    L148
L0:
  mov    $0x1,%eax
  jmp    L148
L106:
  mov    $0x0,%eax
L152:
  ret
```

assistant: ```c
int i_contain_r(int i, int r) {
  if (i == 0 && r == 0)
    return 1;
  while (i > 0) {
    char ic = i % 10;
    int rr = r;
    char rc = rr % 10;
    while (ic != rc && i > 0) {
      i /= 10;
      ic = i % 10;
    }
    if (i == 0)
      return 0;
    while (ic == rc && i > 0 && rr > 0) {
      i /= 10;
      ic = i % 10;
      rr /= 10;
      rc = rr % 10;
    }
    if (rr == 0)
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<i_contain_r>:
  endbr64
  mov    %edi,%eax
  or     %esi,%edi
  mov    $0x1,%r9d
  je     L9
  movslq %esi,%rdx
  mov    %esi,%ecx
  mov    %esi,%edi
  mov    %esi,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  mov    $0xcccccccd,%esi
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  test   %eax,%eax
  jle    L128
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L87:
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  mov    %eax,%ecx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  cmp    %cl,%dil
  je     L126
  nop
L72:
  mov    %eax,%ecx
  mov    %rcx,%r10
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  mov    %ecx,%edx
  mov    %ecx,%r9d
  mov    %ecx,%eax
  imul   %rsi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%r9d
  mov    %r9d,%edx
  cmp    %r9b,%dil
  je     L48
  cmp    $0x9,%r10d
  jg     L72
L48:
  test   %ecx,%ecx
  je     L17
  test   %r8d,%r8d
  jle    L11
L82:
  cmp    %dil,%dl
  jne    L11
  mov    %r8d,%edx
  jmp    L83
  nopl   0x0(%rax)
L39:
  cmp    $0x9,%r10d
  setg   %r10b
  cmp    $0x9,%r9d
  setg   %cl
  test   %cl,%r10b
  je     L114
L83:
  mov    %eax,%eax
  mov    %edx,%edx
  mov    %rax,%r10
  imul   %rsi,%rax
  mov    %rdx,%r9
  imul   %rsi,%rdx
  shr    $0x23,%rax
  mov    %eax,%ecx
  shr    $0x23,%rdx
  mov    %eax,%ebx
  imul   %rsi,%rcx
  mov    %edx,%r11d
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  mov    %edx,%ecx
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%r11d
  cmp    %r11b,%bl
  je     L39
L114:
  test   %edx,%edx
  je     L90
L134:
  test   %eax,%eax
  jg     L87
L17:
  xor    %r9d,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L126:
  mov    %edi,%edx
  test   %r8d,%r8d
  jg     L82
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r8d,%edx
  test   %edx,%edx
  jne    L134
L90:
  mov    $0x1,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
L128:
  xor    %r9d,%r9d
L9:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int i_contain_r(int i, int r) {
  if (i == 0 && r == 0)
    return 1;
  while (i > 0) {
    char ic = i % 10;
    int rr = r;
    char rc = rr % 10;
    while (ic != rc && i > 0) {
      i /= 10;
      ic = i % 10;
    }
    if (i == 0)
      return 0;
    while (ic == rc && i > 0 && rr > 0) {
      i /= 10;
      ic = i % 10;
      rr /= 10;
      rc = rr % 10;
    }
    if (rr == 0)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i_contain_r>:
  endbr64
  mov    %edi,%eax
  or     %esi,%edi
  mov    $0x1,%r9d
  je     L117
  movslq %esi,%rdx
  mov    %esi,%ecx
  mov    %esi,%edi
  mov    %esi,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  mov    $0xcccccccd,%esi
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  test   %eax,%eax
  jle    L26
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L57:
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  mov    %eax,%ecx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  cmp    %cl,%dil
  je     L24
  nop
L50:
  mov    %eax,%ecx
  mov    %rcx,%r10
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  mov    %ecx,%edx
  mov    %ecx,%r9d
  mov    %ecx,%eax
  imul   %rsi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%r9d
  mov    %r9d,%edx
  cmp    %r9b,%dil
  je     L68
  cmp    $0x9,%r10d
  jg     L50
L68:
  test   %ecx,%ecx
  je     L69
  test   %r8d,%r8d
  jle    L61
L46:
  cmp    %dil,%dl
  jne    L61
  mov    %r8d,%edx
  jmp    L33
  nopl   0x0(%rax)
L44:
  cmp    $0x9,%r10d
  setg   %r10b
  cmp    $0x9,%r9d
  setg   %cl
  test   %cl,%r10b
  je     L94
L33:
  mov    %eax,%eax
  mov    %edx,%edx
  mov    %rax,%r10
  imul   %rsi,%rax
  mov    %rdx,%r9
  imul   %rsi,%rdx
  shr    $0x23,%rax
  mov    %eax,%ecx
  shr    $0x23,%rdx
  mov    %eax,%ebx
  imul   %rsi,%rcx
  mov    %edx,%r11d
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  mov    %edx,%ecx
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%r11d
  cmp    %r11b,%bl
  je     L44
L94:
  test   %edx,%edx
  je     L73
L36:
  test   %eax,%eax
  jg     L57
L69:
  xor    %r9d,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %edi,%edx
  test   %r8d,%r8d
  jg     L46
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %r8d,%edx
  test   %edx,%edx
  jne    L36
L73:
  mov    $0x1,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
L26:
  xor    %r9d,%r9d
L117:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int i_contain_r(int i, int r) {
  if (i == 0 && r == 0)
    return 1;
  while (i > 0) {
    char ic = i % 10;
    int rr = r;
    char rc = rr % 10;
    while (ic != rc && i > 0) {
      i /= 10;
      ic = i % 10;
    }
    if (i == 0)
      return 0;
    while (ic == rc && i > 0 && rr > 0) {
      i /= 10;
      ic = i % 10;
      rr /= 10;
      rc = rr % 10;
    }
    if (rr == 0)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  jmp    L1
```

assistant: ```c
int main(void) {
  for (;;)
    ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
int main(void) {
  for (;;)
    ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
int main(void) {
  for (;;)
    ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
int main(void) {
  for (;;)
    ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string

tool: D1: xterm -e './ifme --gui'

assistant: ```c
int main() {
  system("xterm -e './ifme --gui'");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: xterm -e './ifme --gui'

assistant: ```c
int main() {
  system("xterm -e './ifme --gui'");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D0: xterm -e './ifme --gui'

assistant: ```c
int main() {
  system("xterm -e './ifme --gui'");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7: xterm -e './ifme --gui'

assistant: ```c
int main() {
  system("xterm -e './ifme --gui'");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findLast>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L47
L9:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L27
  cmpl   $0x0,-0x4(%rbp)
  jns    L23
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
L27:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *findLast(const char *s, char v) {
  int i, j = -1;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == v || (j < 0 && s[i] == '\0')) {
      j = i;
    }
  }
  return s + j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<findLast>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L20
  mov    $0x0,%edx
  mov    $0xffffffff,%r8d
L21:
  cmp    %cl,%sil
  cmove  %edx,%r8d
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L21
L14:
  movslq %r8d,%r8
  lea    (%rdi,%r8,1),%rax
  ret
L20:
  mov    $0xffffffff,%r8d
  jmp    L14
```

assistant: ```c
const char *findLast(const char *s, char v) {
  int i, j = -1;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == v || (j < 0 && s[i] == '\0')) {
      j = i;
    }
  }
  return s + j;
}
```