ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<programmer_read_oscal>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%r12
  movb   $0xd,0xf(%rsp)
  call   <write@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmpb   $0x43,0x10(%rsp)
  jne    L1
  xor    %ebx,%ebx
  nopl   (%rax)
L16:
  movslq %ebx,%rsi
  mov    $0x1a,%edx
  mov    %ebp,%edi
  add    %r12,%rsi
  call   <read@plt>
  add    %eax,%ebx
  cmp    $0x1a,%ebx
  jne    L16
  movzwl 0x28(%rsp),%eax
L17:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L17
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int programmer_read_oscal(int port) {
  unsigned char command;
  unsigned char buffer[256];
  int len;
  command = 13;
  write(port, &command, 1);
  read(port, buffer, 1);
  if (buffer[0] != 'C') {
    ;
    return -1;
  }
  len = 0;
  while ((len += read(port, buffer + len, 26)) != 26) {
    ;
  }
  return ((int)(buffer[25]) << 8 | buffer[24]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L59
  jmp    L61
L36:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L61:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L36
  jmp    L4
L59:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L4
  jmp    L28
L14:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L28:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L14
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xcopy(void *d, const void *s, int n) {
  char *dp = d;
  const char *sp = s;
  if (sp > dp)
    while (n--)
      *dp++ = *sp++;
  else if (sp < dp)
    while (n--)
      dp[n] = sp[n];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xcopy>:
  endbr64
  mov    %rdi,%rcx
  cmp    %rsi,%rdi
  jae    L27
  test   %edx,%edx
  je     L13
  mov    %edx,%edx
  mov    $0x0,%eax
L36:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L36
  ret
L27:
  jbe    L13
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L13
  cltq
  movslq %edx,%rdi
  sub    $0x2,%rdi
  lea    -0x1(%rdx),%edx
  sub    %rdx,%rdi
L50:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L50
L13:
  ret
```

assistant: ```c
void xcopy(void *d, const void *s, int n) {
  char *dp = d;
  const char *sp = s;
  if (sp > dp)
    while (n--)
      *dp++ = *sp++;
  else if (sp < dp)
    while (n--)
      dp[n] = sp[n];
}
```
user: What is the c source code of the assembly code below:

```asm
<xcopy>:
  endbr64
  mov    %rdi,%rcx
  cmp    %rsi,%rdi
  jae    L53
  test   %edx,%edx
  je     L47
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L31:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L31
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  ja     L54
L47:
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  je     L47
  movslq %edx,%rdx
  movslq %edi,%rax
  mov    %edi,%edi
  sub    $0x2,%rdx
  sub    %rdi,%rdx
  xchg   %ax,%ax
L42:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L42
  ret
```

assistant: ```c
void xcopy(void *d, const void *s, int n) {
  char *dp = d;
  const char *sp = s;
  if (sp > dp)
    while (n--)
      *dp++ = *sp++;
  else if (sp < dp)
    while (n--)
      dp[n] = sp[n];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xcopy>:
  endbr64
  mov    %rdi,%rcx
  movslq %edx,%rax
  cmp    %rsi,%rdi
  jae    L183
  lea    -0x1(%rax),%r8d
  test   %eax,%eax
  je     L82
  lea    0x1(%rsi),%rdi
  mov    %rcx,%rdx
  sub    %rdi,%rdx
  cmp    $0xe,%rdx
  jbe    L96
  cmp    $0x6,%r8d
  jbe    L96
  cmp    $0xe,%r8d
  jbe    L29
  mov    %eax,%edi
  xor    %edx,%edx
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L126:
  movdqu (%rsi,%rdx,1),%xmm0
  movups %xmm0,(%rcx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L126
  mov    %eax,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%edi
  sub    %edx,%r8d
  lea    (%rcx,%rdi,1),%r9
  add    %rsi,%rdi
  cmp    %edx,%eax
  je     L44
L169:
  sub    %edx,%eax
  lea    -0x1(%rax),%r10d
  cmp    $0x6,%r10d
  jbe    L34
  mov    (%rsi,%rdx,1),%rsi
  mov    %rsi,(%rcx,%rdx,1)
  mov    %eax,%edx
  and    $0xfffffff8,%edx
  mov    %edx,%ecx
  sub    %edx,%r8d
  add    %rcx,%r9
  add    %rcx,%rdi
  cmp    %edx,%eax
  je     L82
L34:
  movzbl (%rdi),%eax
  mov    %al,(%r9)
  test   %r8d,%r8d
  je     L82
  movzbl 0x1(%rdi),%eax
  mov    %al,0x1(%r9)
  cmp    $0x1,%r8d
  je     L82
  movzbl 0x2(%rdi),%eax
  mov    %al,0x2(%r9)
  cmp    $0x2,%r8d
  je     L82
  movzbl 0x3(%rdi),%eax
  mov    %al,0x3(%r9)
  cmp    $0x3,%r8d
  je     L82
  movzbl 0x4(%rdi),%eax
  mov    %al,0x4(%r9)
  cmp    $0x4,%r8d
  je     L82
  movzbl 0x5(%rdi),%eax
  mov    %al,0x5(%r9)
  cmp    $0x5,%r8d
  je     L82
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%r9)
  ret
  nopl   (%rax)
L183:
  ja     L69
L82:
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  lea    -0x1(%rax),%edi
  test   %eax,%eax
  je     L82
  movslq %edi,%rdx
  sub    $0x2,%rax
  mov    %edi,%edi
  sub    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L103:
  movzbl (%rsi,%rdx,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L103
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  mov    %r8d,%eax
  xor    %edx,%edx
  nopl   (%rax)
L38:
  movzbl (%rsi,%rdx,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  mov    %rdx,%rdi
  add    $0x1,%rdx
  cmp    %rax,%rdi
  jne    L38
  ret
L29:
  mov    %rsi,%rdi
  mov    %rcx,%r9
  xor    %edx,%edx
  jmp    L169
L44:
  ret
```

assistant: ```c
void xcopy(void *d, const void *s, int n) {
  char *dp = d;
  const char *sp = s;
  if (sp > dp)
    while (n--)
      *dp++ = *sp++;
  else if (sp < dp)
    while (n--)
      dp[n] = sp[n];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isal_deflate_hash_mad_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x10(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L10
L4:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <load_u32@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <compute_hash_mad@plt>
  and    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x4,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void isal_deflate_hash_mad_base(uint16_t *hash_table, uint32_t hash_mask, uint32_t current_index, uint8_t *dict, uint32_t dict_len) {
  uint8_t *next_in = dict;
  uint8_t *end_in = dict + dict_len - 4;
  uint32_t literal;
  uint32_t hash;
  uint16_t index = current_index - dict_len;
  while (next_in <= end_in) {
    literal = load_u32(next_in);
    hash = compute_hash_mad(literal) & hash_mask;
    hash_table[hash] = index;
    index++;
    next_in++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isal_deflate_hash_mad_base>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rcx,%rbx
  movslq %r8d,%rax
  lea    -0x10(%rcx,%rax,4),%r14
  sub    %r8d,%edx
  mov    %edx,%ebp
  cmp    %r14,%rcx
  ja     L0
L7:
  mov    %rbx,%rdi
  call   <load_u32@plt>
  mov    %eax,%edi
  call   <compute_hash_mad@plt>
  and    %r12d,%eax
  cltq
  mov    %ebp,0x0(%r13,%rax,4)
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %rbx,%r14
  jae    L7
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void isal_deflate_hash_mad_base(uint16_t *hash_table, uint32_t hash_mask, uint32_t current_index, uint8_t *dict, uint32_t dict_len) {
  uint8_t *next_in = dict;
  uint8_t *end_in = dict + dict_len - 4;
  uint32_t literal;
  uint32_t hash;
  uint16_t index = current_index - dict_len;
  while (next_in <= end_in) {
    literal = load_u32(next_in);
    hash = compute_hash_mad(literal) & hash_mask;
    hash_table[hash] = index;
    index++;
    next_in++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isal_deflate_hash_mad_base>:
  endbr64
  movslq %r8d,%rax
  push   %r14
  sub    %r8d,%edx
  push   %r13
  push   %r12
  lea    -0x10(%rcx,%rax,4),%r12
  push   %rbp
  push   %rbx
  cmp    %r12,%rcx
  ja     L11
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rcx,%r13
  mov    %edx,%r14d
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rdi
  add    $0x4,%r13
  call   <load_u32@plt>
  mov    %eax,%edi
  call   <compute_hash_mad@plt>
  and    %ebx,%eax
  cltq
  mov    %r14d,0x0(%rbp,%rax,4)
  add    $0x1,%r14d
  cmp    %r13,%r12
  jae    L0
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void isal_deflate_hash_mad_base(uint16_t *hash_table, uint32_t hash_mask, uint32_t current_index, uint8_t *dict, uint32_t dict_len) {
  uint8_t *next_in = dict;
  uint8_t *end_in = dict + dict_len - 4;
  uint32_t literal;
  uint32_t hash;
  uint16_t index = current_index - dict_len;
  while (next_in <= end_in) {
    literal = load_u32(next_in);
    hash = compute_hash_mad(literal) & hash_mask;
    hash_table[hash] = index;
    index++;
    next_in++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isal_deflate_hash_mad_base>:
  endbr64
  movslq %r8d,%rax
  push   %r14
  sub    %r8d,%edx
  push   %r13
  push   %r12
  lea    -0x10(%rcx,%rax,4),%r12
  push   %rbp
  push   %rbx
  cmp    %r12,%rcx
  ja     L11
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rcx,%r13
  mov    %edx,%r14d
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %r13,%rdi
  add    $0x4,%r13
  call   <load_u32@plt>
  mov    %eax,%edi
  call   <compute_hash_mad@plt>
  and    %ebx,%eax
  cltq
  mov    %r14d,0x0(%rbp,%rax,4)
  add    $0x1,%r14d
  cmp    %r13,%r12
  jae    L17
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void isal_deflate_hash_mad_base(uint16_t *hash_table, uint32_t hash_mask, uint32_t current_index, uint8_t *dict, uint32_t dict_len) {
  uint8_t *next_in = dict;
  uint8_t *end_in = dict + dict_len - 4;
  uint32_t literal;
  uint32_t hash;
  uint16_t index = current_index - dict_len;
  while (next_in <= end_in) {
    literal = load_u32(next_in);
    hash = compute_hash_mad(literal) & hash_mask;
    hash_table[hash] = index;
    index++;
    next_in++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0xfffffffe,-0x8(%rbp)
  mov    D14(%rip),%edx
  mov    D2(%rip),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <func1@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  static int static_var = 85;
  static int static_var2;
  int a = 1;
  int b;
  int x = -2;
  func1(static_var + static_var2 + a + b);
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x56,%edi
  call   <func1@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  static int static_var = 85;
  static int static_var2;
  int a = 1;
  int b;
  int x = -2;
  func1(static_var + static_var2 + a + b);
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x56,%edi
  call   <func1@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  static int static_var = 85;
  static int static_var2;
  int a = 1;
  int b;
  int x = -2;
  func1(static_var + static_var2 + a + b);
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x56,%edi
  call   <func1@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  static int static_var = 85;
  static int static_var2;
  int a = 1;
  int b;
  int x = -2;
  func1(static_var + static_var2 + a + b);
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<matrix_copy_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L19:
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L36:
  mov    -0x4(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L36
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  nop
  pop    %rbp
  ret
```

assistant: ```c
int matrix_copy_matrix(double *output, double *input, int rows, int cols) {
  int i, j;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      output[i + j * rows] = input[i + j * rows];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_copy_matrix>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L16
  mov    %edx,%r10d
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rdi
  mov    $0x0,%r9d
  jmp    L29
L10:
  movsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%r8,%rax,1)
  add    $0x1,%edx
  add    %rdi,%rax
  cmp    %edx,%ecx
  jne    L10
L44:
  add    $0x1,%r9
  cmp    %r10,%r9
  je     L16
L29:
  lea    0x0(,%r9,8),%rax
  mov    $0x0,%edx
  test   %ecx,%ecx
  jg     L10
  jmp    L44
L16:
  ret
```

assistant: ```c
int matrix_copy_matrix(double *output, double *input, int rows, int cols) {
  int i, j;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      output[i + j * rows] = input[i + j * rows];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix_copy_matrix>:
  endbr64
  test   %edx,%edx
  jle    L6
  movslq %edx,%r10
  xor    %r9d,%r9d
  lea    0x0(,%r10,8),%r8
  cs nopw 0x0(%rax,%rax,1)
L24:
  lea    0x0(,%r9,8),%rax
  xor    %edx,%edx
  test   %ecx,%ecx
  jle    L27
  xchg   %ax,%ax
L2:
  movsd  (%rsi,%rax,1),%xmm0
  add    $0x1,%edx
  movsd  %xmm0,(%rdi,%rax,1)
  add    %r8,%rax
  cmp    %edx,%ecx
  jne    L2
L27:
  add    $0x1,%r9
  cmp    %r10,%r9
  jne    L24
L6:
  ret
```

assistant: ```c
int matrix_copy_matrix(double *output, double *input, int rows, int cols) {
  int i, j;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      output[i + j * rows] = input[i + j * rows];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_copy_matrix>:
  endbr64
  test   %edx,%edx
  jle    L10
  test   %ecx,%ecx
  jle    L10
  movslq %edx,%r10
  xor    %r9d,%r9d
  lea    0x0(,%r10,8),%r8
  nopw   0x0(%rax,%rax,1)
L18:
  lea    0x0(,%r9,8),%rax
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L22:
  movsd  (%rsi,%rax,1),%xmm0
  add    $0x1,%edx
  movsd  %xmm0,(%rdi,%rax,1)
  add    %r8,%rax
  cmp    %edx,%ecx
  jne    L22
  add    $0x1,%r9
  cmp    %r9,%r10
  jne    L18
L10:
  ret
```

assistant: ```c
int matrix_copy_matrix(double *output, double *input, int rows, int cols) {
  int i, j;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      output[i + j * rows] = input[i + j * rows];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reorder1>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  jle    L11
L7:
  mov    (%rdi,%rax,8),%r8
  mov    -0x8(%rdi,%rax,8),%rdx
  cmp    %rdx,%r8
  jge    L11
  mov    %rdx,(%rdi,%rax,8)
  mov    %r8,-0x8(%rdi,%rax,8)
  mov    (%rsi,%rax,8),%rdx
  mov    -0x8(%rsi,%rax,8),%r8
  mov    %r8,(%rsi,%rax,8)
  sub    $0x1,%rax
  mov    %rdx,(%rsi,%rax,8)
  jne    L7
L11:
  lea    -0x1(%rcx),%rdx
  cmp    %rdx,%rax
  jge    L49
  mov    %rdx,%rcx
L44:
  mov    (%rdi,%rax,8),%r8
  mov    0x8(%rdi,%rax,8),%rdx
  cmp    %rdx,%r8
  jle    L49
  mov    %rdx,(%rdi,%rax,8)
  mov    %r8,0x8(%rdi,%rax,8)
  mov    (%rsi,%rax,8),%rdx
  mov    0x8(%rsi,%rax,8),%r8
  mov    %r8,(%rsi,%rax,8)
  add    $0x1,%rax
  mov    %rdx,(%rsi,%rax,8)
  cmp    %rcx,%rax
  jne    L44
L49:
  ret
```

assistant: ```c
void reorder1(long a[], long b[], long newone, long range) {
  long temp;
  while (newone > 0 && a[newone] < a[newone - 1]) {
    temp = a[newone];
    a[newone] = a[newone - 1];
    a[newone - 1] = temp;
    temp = b[newone];
    b[newone] = b[newone - 1];
    b[--newone] = temp;
  }
  while (newone < range - 1 && a[newone] > a[newone + 1]) {
    temp = a[newone];
    a[newone] = a[newone + 1];
    a[newone + 1] = temp;
    temp = b[newone];
    b[newone] = b[newone + 1];
    b[++newone] = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reorder1>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  jg     L60
  jmp    L31
  xchg   %ax,%ax
L41:
  mov    %rdi,(%rax,%rdx,8)
  mov    %r8,-0x8(%rax,%rdx,8)
  mov    -0x8(%rsi,%rdx,8),%r8
  mov    (%rsi,%rdx,8),%rdi
  mov    %r8,(%rsi,%rdx,8)
  sub    $0x1,%rdx
  mov    %rdi,(%rsi,%rdx,8)
  je     L31
L60:
  mov    (%rax,%rdx,8),%r8
  mov    -0x8(%rax,%rdx,8),%rdi
  cmp    %rdi,%r8
  jl     L41
L31:
  sub    $0x1,%rcx
  cmp    %rcx,%rdx
  jl     L48
  jmp    L6
  nopl   0x0(%rax)
L66:
  mov    %rdi,(%rax,%rdx,8)
  mov    %r8,0x8(%rax,%rdx,8)
  mov    0x8(%rsi,%rdx,8),%r8
  mov    (%rsi,%rdx,8),%rdi
  mov    %r8,(%rsi,%rdx,8)
  add    $0x1,%rdx
  mov    %rdi,(%rsi,%rdx,8)
  cmp    %rcx,%rdx
  je     L61
L48:
  mov    (%rax,%rdx,8),%r8
  mov    0x8(%rax,%rdx,8),%rdi
  cmp    %rdi,%r8
  jg     L66
L61:
  ret
L6:
  ret
```

assistant: ```c
void reorder1(long a[], long b[], long newone, long range) {
  long temp;
  while (newone > 0 && a[newone] < a[newone - 1]) {
    temp = a[newone];
    a[newone] = a[newone - 1];
    a[newone - 1] = temp;
    temp = b[newone];
    b[newone] = b[newone - 1];
    b[--newone] = temp;
  }
  while (newone < range - 1 && a[newone] > a[newone + 1]) {
    temp = a[newone];
    a[newone] = a[newone + 1];
    a[newone + 1] = temp;
    temp = b[newone];
    b[newone] = b[newone + 1];
    b[++newone] = temp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reorder1>:
  endbr64
  test   %rdx,%rdx
  jg     L45
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L31:
  movups %xmm1,-0x8(%rdi,%rdx,8)
  movdqu -0x8(%rsi,%rdx,8),%xmm0
  sub    $0x1,%rdx
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%rsi,%rdx,8)
  je     L60
L45:
  movdqu -0x8(%rdi,%rdx,8),%xmm0
  movhlps %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  movq   %xmm0,%r8
  movq   %xmm2,%rax
  shufpd $0x1,%xmm0,%xmm1
  cmp    %rax,%r8
  jg     L31
L60:
  sub    $0x1,%rcx
  cmp    %rcx,%rdx
  jl     L24
  jmp    L66
  cs nopw 0x0(%rax,%rax,1)
L39:
  movups %xmm1,(%rdi,%rdx,8)
  movdqu (%rsi,%rdx,8),%xmm0
  add    $0x1,%rdx
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,-0x8(%rsi,%rdx,8)
  cmp    %rcx,%rdx
  je     L47
L24:
  movdqu (%rdi,%rdx,8),%xmm0
  movhlps %xmm0,%xmm3
  movdqa %xmm0,%xmm1
  movq   %xmm0,%r8
  movq   %xmm3,%rax
  shufpd $0x1,%xmm0,%xmm1
  cmp    %rax,%r8
  jg     L39
L47:
  ret
L66:
  ret
```

assistant: ```c
void reorder1(long a[], long b[], long newone, long range) {
  long temp;
  while (newone > 0 && a[newone] < a[newone - 1]) {
    temp = a[newone];
    a[newone] = a[newone - 1];
    a[newone - 1] = temp;
    temp = b[newone];
    b[newone] = b[newone - 1];
    b[--newone] = temp;
  }
  while (newone < range - 1 && a[newone] > a[newone + 1]) {
    temp = a[newone];
    a[newone] = a[newone + 1];
    a[newone + 1] = temp;
    temp = b[newone];
    b[newone] = b[newone + 1];
    b[++newone] = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_task_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0x11e(%rbp)
  mov    -0x128(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x118(%rbp)
  jmp    L0
L1:
  lea    -0x11e(%rbp),%rdx
  lea    -0x90(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x11c(%rbp)
  cmpl   $0x0,-0x11c(%rbp)
  jg     L30
L0:
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x7f,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L1
  jmp    L40
L30:
  nop
L40:
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  movzwl -0x11e(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string

tool: D9: %s %%hu

tool: D16: r

tool: D6: task rc.report.all.columns:uuid,id rc.report.all.labels:UUID,id rc.report.all.sort:id- all status:pending rc._forcecolor=no

assistant: ```c
unsigned short get_task_id(char *uuid) {
  FILE *cmd;
  char line[128];
  char format[128];
  int ret;
  unsigned short id = 0;
  sprintf(format, "%s %%hu", uuid);
  cmd = popen("task rc.report.all.columns:uuid,id rc.report.all.labels:UUID,id rc.report.all.sort:id- all status:pending rc._forcecolor=no", "r");
  while (fgets(line, sizeof(line) - 1, cmd) != NULL) {
    ret = sscanf(line, format, &id);
    if (ret > 0) {
      break;
    }
  }
  pclose(cmd);
  return id;
}
```