ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bitcount@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x63,-0x4(%rbp)
  jbe    L10
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: x=%x, bitcount=%u


assistant: ```c
main() {
  unsigned x;
  for (x = 0; x < 100; ++x)
    printf("x=%x, bitcount=%u\n", x, bitcount(x));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L0:
  mov    %ebx,%edi
  call   <bitcount@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: x=%x, bitcount=%u


assistant: ```c
main() {
  unsigned x;
  for (x = 0; x < 100; ++x)
    printf("x=%x, bitcount=%u\n", x, bitcount(x));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edi
  call   <bitcount@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x64,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: x=%x, bitcount=%u


assistant: ```c
main() {
  unsigned x;
  for (x = 0; x < 100; ++x)
    printf("x=%x, bitcount=%u\n", x, bitcount(x));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  call   <bitcount@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x64,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: x=%x, bitcount=%u


assistant: ```c
main() {
  unsigned x;
  for (x = 0; x < 100; ++x)
    printf("x=%x, bitcount=%u\n", x, bitcount(x));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<onShutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void onShutdown(void *context, int32_t way) {
  struct session *s = (struct session *)context;
  free(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<onShutdown>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void onShutdown(void *context, int32_t way) {
  struct session *s = (struct session *)context;
  free(s);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<onShutdown>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void onShutdown(void *context, int32_t way) {
  struct session *s = (struct session *)context;
  free(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<onShutdown>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void onShutdown(void *context, int32_t way) {
  struct session *s = (struct session *)context;
  free(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CalulateCRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x38(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    $0x4,%esi
  mov    $0x5,%edi
  call   <ClearBitMask@plt>
  mov    $0x80,%esi
  mov    $0xa,%edi
  call   <SetBitMask@plt>
  movb   $0x0,-0x12(%rbp)
  jmp    L38
L19:
  movzbl -0x12(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x9,%edi
  call   <Write_MFRC522@plt>
  movzbl -0x12(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x12(%rbp)
L38:
  movzbl -0x12(%rbp),%eax
  cmp    -0x2c(%rbp),%al
  jb     L19
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <Write_MFRC522@plt>
  movb   $0xff,-0x12(%rbp)
L23:
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  mov    %al,-0x11(%rbp)
  movzbl -0x12(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x12(%rbp)
  cmpb   $0x0,-0x12(%rbp)
  je     L11
  movzbl -0x11(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L23
L11:
  mov    $0x22,%edi
  call   <Read_MFRC522@plt>
  mov    -0x38(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rbx
  mov    $0x21,%edi
  call   <Read_MFRC522@plt>
  mov    %al,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void CalulateCRC(unsigned char *pIndata, unsigned char len, unsigned char *pOutData) {
  unsigned char i, n;
  ClearBitMask(0x05, 0x04);
  SetBitMask(0x0A, 0x80);
  for (i = 0; i < len; i++) {
    Write_MFRC522(0x09, *(pIndata + i));
  }
  Write_MFRC522(0x01, 0x03);
  i = 0xFF;
  do {
    n = Read_MFRC522(0x05);
    i--;
  } while ((i != 0) && !(n & 0x04));
  pOutData[0] = Read_MFRC522(0x22);
  pOutData[1] = Read_MFRC522(0x21);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CalulateCRC>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    $0x4,%esi
  mov    $0x5,%edi
  call   <ClearBitMask@plt>
  mov    $0x80,%esi
  mov    $0xa,%edi
  call   <SetBitMask@plt>
  test   %r12b,%r12b
  je     L38
  mov    %r13,%rbx
  sub    $0x1,%r12d
  movzbl %r12b,%r12d
  lea    0x1(%r13,%r12,1),%r12
L1:
  movzbl (%rbx),%esi
  mov    $0x9,%edi
  call   <Write_MFRC522@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L1
L38:
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <Write_MFRC522@plt>
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  mov    $0xfffffffe,%ebx
L2:
  test   $0x4,%al
  jne    L22
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  sub    $0x1,%bl
  jne    L2
L22:
  mov    $0x22,%edi
  call   <Read_MFRC522@plt>
  mov    %al,0x0(%rbp)
  mov    $0x21,%edi
  call   <Read_MFRC522@plt>
  mov    %al,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void CalulateCRC(unsigned char *pIndata, unsigned char len, unsigned char *pOutData) {
  unsigned char i, n;
  ClearBitMask(0x05, 0x04);
  SetBitMask(0x0A, 0x80);
  for (i = 0; i < len; i++) {
    Write_MFRC522(0x09, *(pIndata + i));
  }
  Write_MFRC522(0x01, 0x03);
  i = 0xFF;
  do {
    n = Read_MFRC522(0x05);
    i--;
  } while ((i != 0) && !(n & 0x04));
  pOutData[0] = Read_MFRC522(0x22);
  pOutData[1] = Read_MFRC522(0x21);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CalulateCRC>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5,%edi
  call   <ClearBitMask@plt>
  mov    $0x80,%esi
  mov    $0xa,%edi
  call   <SetBitMask@plt>
  test   %r12b,%r12b
  je     L37
  sub    $0x1,%r12d
  movzbl %r12b,%r12d
  lea    0x1(%rbx,%r12,1),%r12
  nopl   0x0(%rax)
L49:
  movzbl (%rbx),%esi
  mov    $0x9,%edi
  add    $0x1,%rbx
  call   <Write_MFRC522@plt>
  cmp    %r12,%rbx
  jne    L49
L37:
  mov    $0x3,%esi
  mov    $0x1,%edi
  mov    $0xfffffffe,%ebx
  call   <Write_MFRC522@plt>
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  jmp    L29
  xchg   %ax,%ax
L28:
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  sub    $0x1,%bl
  je     L30
L29:
  test   $0x4,%al
  je     L28
L30:
  mov    $0x22,%edi
  call   <Read_MFRC522@plt>
  mov    $0x21,%edi
  mov    %al,0x0(%rbp)
  call   <Read_MFRC522@plt>
  pop    %rbx
  mov    %al,0x1(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void CalulateCRC(unsigned char *pIndata, unsigned char len, unsigned char *pOutData) {
  unsigned char i, n;
  ClearBitMask(0x05, 0x04);
  SetBitMask(0x0A, 0x80);
  for (i = 0; i < len; i++) {
    Write_MFRC522(0x09, *(pIndata + i));
  }
  Write_MFRC522(0x01, 0x03);
  i = 0xFF;
  do {
    n = Read_MFRC522(0x05);
    i--;
  } while ((i != 0) && !(n & 0x04));
  pOutData[0] = Read_MFRC522(0x22);
  pOutData[1] = Read_MFRC522(0x21);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CalulateCRC>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5,%edi
  call   <ClearBitMask@plt>
  mov    $0x80,%esi
  mov    $0xa,%edi
  call   <SetBitMask@plt>
  test   %r12b,%r12b
  je     L13
  sub    $0x1,%r12d
  movzbl %r12b,%r12d
  lea    0x1(%rbx,%r12,1),%r12
  nopl   0x0(%rax)
L42:
  movzbl (%rbx),%esi
  mov    $0x9,%edi
  add    $0x1,%rbx
  call   <Write_MFRC522@plt>
  cmp    %r12,%rbx
  jne    L42
L13:
  mov    $0x3,%esi
  mov    $0x1,%edi
  mov    $0xfffffffe,%ebx
  call   <Write_MFRC522@plt>
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  jmp    L39
  xchg   %ax,%ax
L26:
  mov    $0x5,%edi
  call   <Read_MFRC522@plt>
  sub    $0x1,%bl
  je     L25
L39:
  test   $0x4,%al
  je     L26
L25:
  mov    $0x22,%edi
  call   <Read_MFRC522@plt>
  mov    $0x21,%edi
  mov    %al,0x0(%rbp)
  call   <Read_MFRC522@plt>
  pop    %rbx
  mov    %al,0x1(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void CalulateCRC(unsigned char *pIndata, unsigned char len, unsigned char *pOutData) {
  unsigned char i, n;
  ClearBitMask(0x05, 0x04);
  SetBitMask(0x0A, 0x80);
  for (i = 0; i < len; i++) {
    Write_MFRC522(0x09, *(pIndata + i));
  }
  Write_MFRC522(0x01, 0x03);
  i = 0xFF;
  do {
    n = Read_MFRC522(0x05);
    i--;
  } while ((i != 0) && !(n & 0x04));
  pOutData[0] = Read_MFRC522(0x22);
  pOutData[1] = Read_MFRC522(0x21);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convert_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,%rax
  sub    $0x1,%rax
  add    %rax,-0x18(%rbp)
  jmp    L4
L1:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
L4:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void convert_name(char *out, char *name) {
  unsigned long len;
  len = strlen(name);
  out += len * 2 - 1;
  while (len--) {
    *out-- = '\x00';
    *out-- = name[len];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<convert_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L15
  lea    -0x1(%rax,%rax,1),%rcx
  lea    -0x1(%rax),%rdx
  neg    %rax
  lea    (%rcx,%rax,2),%rax
  add    %rbx,%rax
L2:
  movb   $0x0,0x2(%rax,%rdx,2)
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,0x1(%rax,%rdx,2)
  sub    $0x1,%rdx
  cmp    $0xffffffffffffffff,%rdx
  jne    L2
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void convert_name(char *out, char *name) {
  unsigned long len;
  len = strlen(name);
  out += len * 2 - 1;
  while (len--) {
    *out-- = '\x00';
    *out-- = name[len];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_name>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L11
  lea    -0x1(%rax),%rdx
  lea    -0x1(%rbx),%rdi
  nopl   (%rax)
L3:
  movb   $0x0,0x2(%rdi,%rdx,2)
  movzbl 0x0(%rbp,%rdx,1),%eax
  mov    %al,0x1(%rdi,%rdx,2)
  sub    $0x1,%rdx
  jae    L3
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void convert_name(char *out, char *name) {
  unsigned long len;
  len = strlen(name);
  out += len * 2 - 1;
  while (len--) {
    *out-- = '\x00';
    *out-- = name[len];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_name>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L5
  lea    -0x1(%rax),%rdx
  lea    -0x1(%rbx),%rdi
  nopl   (%rax)
L19:
  movb   $0x0,0x2(%rdi,%rdx,2)
  movzbl 0x0(%rbp,%rdx,1),%eax
  mov    %al,0x1(%rdi,%rdx,2)
  sub    $0x1,%rdx
  jae    L19
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void convert_name(char *out, char *name) {
  unsigned long len;
  len = strlen(name);
  out += len * 2 - 1;
  while (len--) {
    *out-- = '\x00';
    *out-- = name[len];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<catmullrom_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  movss  %xmm4,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <catmullrom_w0@plt>
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <catmullrom_w1@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x1c(%rbp),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <catmullrom_w2@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x20(%rbp),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <catmullrom_w3@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x24(%rbp),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float catmullrom_filter(float x, float c0, float c1, float c2, float c3) {
  float r = c0 * catmullrom_w0(x);
  r += c1 * catmullrom_w1(x);
  r += c2 * catmullrom_w2(x);
  r += c3 * catmullrom_w3(x);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<catmullrom_filter>:
  endbr64
  sub    $0x28,%rsp
  movss  %xmm1,0x10(%rsp)
  movss  %xmm2,0x14(%rsp)
  movss  %xmm3,0x18(%rsp)
  movss  %xmm4,0x1c(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <catmullrom_w0@plt>
  movaps %xmm0,%xmm5
  mulss  0x10(%rsp),%xmm5
  movss  %xmm5,0x10(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <catmullrom_w1@plt>
  mulss  0x14(%rsp),%xmm0
  movaps %xmm0,%xmm6
  addss  0x10(%rsp),%xmm6
  movss  %xmm6,0x10(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <catmullrom_w2@plt>
  mulss  0x18(%rsp),%xmm0
  movaps %xmm0,%xmm7
  addss  0x10(%rsp),%xmm7
  movss  %xmm7,0x10(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <catmullrom_w3@plt>
  mulss  0x1c(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

assistant: ```c
float catmullrom_filter(float x, float c0, float c1, float c2, float c3) {
  float r = c0 * catmullrom_w0(x);
  r += c1 * catmullrom_w1(x);
  r += c2 * catmullrom_w2(x);
  r += c3 * catmullrom_w3(x);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<catmullrom_filter>:
  endbr64
  sub    $0x28,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x10(%rsp)
  movss  %xmm3,0x14(%rsp)
  movss  %xmm4,0x18(%rsp)
  movss  %xmm0,0x1c(%rsp)
  call   <catmullrom_w0@plt>
  mulss  0xc(%rsp),%xmm0
  movss  0x1c(%rsp),%xmm5
  movss  %xmm0,0xc(%rsp)
  movaps %xmm5,%xmm0
  call   <catmullrom_w1@plt>
  mulss  0x10(%rsp),%xmm0
  movss  0xc(%rsp),%xmm7
  movss  0x1c(%rsp),%xmm5
  movss  %xmm5,0x10(%rsp)
  addss  %xmm0,%xmm7
  movaps %xmm5,%xmm0
  movss  %xmm7,0xc(%rsp)
  call   <catmullrom_w2@plt>
  mulss  0x14(%rsp),%xmm0
  movss  0x10(%rsp),%xmm5
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  movaps %xmm5,%xmm0
  call   <catmullrom_w3@plt>
  mulss  0x18(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

assistant: ```c
float catmullrom_filter(float x, float c0, float c1, float c2, float c3) {
  float r = c0 * catmullrom_w0(x);
  r += c1 * catmullrom_w1(x);
  r += c2 * catmullrom_w2(x);
  r += c3 * catmullrom_w3(x);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<catmullrom_filter>:
  endbr64
  sub    $0x28,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x10(%rsp)
  movss  %xmm3,0x14(%rsp)
  movss  %xmm4,0x18(%rsp)
  movss  %xmm0,0x1c(%rsp)
  call   <catmullrom_w0@plt>
  mulss  0xc(%rsp),%xmm0
  movss  0x1c(%rsp),%xmm5
  movss  %xmm0,0xc(%rsp)
  movaps %xmm5,%xmm0
  call   <catmullrom_w1@plt>
  mulss  0x10(%rsp),%xmm0
  movss  0xc(%rsp),%xmm7
  movss  0x1c(%rsp),%xmm5
  movss  %xmm5,0x10(%rsp)
  addss  %xmm0,%xmm7
  movaps %xmm5,%xmm0
  movss  %xmm7,0xc(%rsp)
  call   <catmullrom_w2@plt>
  mulss  0x14(%rsp),%xmm0
  movss  0x10(%rsp),%xmm5
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  movaps %xmm5,%xmm0
  call   <catmullrom_w3@plt>
  mulss  0x18(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

assistant: ```c
float catmullrom_filter(float x, float c0, float c1, float c2, float c3) {
  float r = c0 * catmullrom_w0(x);
  r += c1 * catmullrom_w1(x);
  r += c2 * catmullrom_w2(x);
  r += c3 * catmullrom_w3(x);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<advance_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  nop
L12:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void advance_pos(int *y, int *x) {
  if ((++*x) > COLS) {
    *x = 0;
    if ((++*y) > LINES)
      *y = 0;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<advance_pos>:
  endbr64
  mov    (%rsi),%eax
  add    $0x1,%eax
  mov    %eax,(%rsi)
  mov    D0(%rip),%rdx
  cmp    (%rdx),%eax
  jle    L18
  movl   $0x0,(%rsi)
  mov    (%rdi),%eax
  add    $0x1,%eax
  mov    %eax,(%rdi)
  mov    D11(%rip),%rdx
  cmp    (%rdx),%eax
  jle    L18
  movl   $0x0,(%rdi)
L18:
  ret
```

assistant: ```c
void advance_pos(int *y, int *x) {
  if ((++*x) > COLS) {
    *x = 0;
    if ((++*y) > LINES)
      *y = 0;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<advance_pos>:
  endbr64
  mov    (%rsi),%eax
  mov    D6(%rip),%rdx
  add    $0x1,%eax
  mov    %eax,(%rsi)
  cmp    (%rdx),%eax
  jle    L10
  movl   $0x0,(%rsi)
  mov    (%rdi),%eax
  mov    D0(%rip),%rdx
  add    $0x1,%eax
  mov    %eax,(%rdi)
  cmp    (%rdx),%eax
  jle    L10
  movl   $0x0,(%rdi)
L10:
  ret
```

assistant: ```c
void advance_pos(int *y, int *x) {
  if ((++*x) > COLS) {
    *x = 0;
    if ((++*y) > LINES)
      *y = 0;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<advance_pos>:
  endbr64
  mov    (%rsi),%eax
  mov    D3(%rip),%rdx
  add    $0x1,%eax
  mov    %eax,(%rsi)
  cmp    (%rdx),%eax
  jle    L3
  movl   $0x0,(%rsi)
  mov    (%rdi),%eax
  mov    D16(%rip),%rdx
  add    $0x1,%eax
  mov    %eax,(%rdi)
  cmp    (%rdx),%eax
  jle    L3
  movl   $0x0,(%rdi)
L3:
  ret
```

assistant: ```c
void advance_pos(int *y, int *x) {
  if ((++*x) > COLS) {
    *x = 0;
    if ((++*y) > LINES)
      *y = 0;
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<reorder_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <list_length@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L33
L11:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L24
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  subl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L19
  addl   $0x2,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void reorder_list(int *list) {
  int size = list_length(list);
  int i = 0, j = 0;
  for (i = 1; i < size; i += 2) {
    for (j = size - 1; j > i; j--) {
      list[j] ^= list[j - 1];
      list[j - 1] ^= list[j];
      list[j] ^= list[j - 1];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reorder_list>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <list_length@plt>
  cmp    $0x1,%eax
  jle    L22
  mov    %eax,%r8d
  lea    -0x1(%rax),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rbx
  movslq %r8d,%rax
  mov    $0x1,%edi
  lea    -0x1(%r8),%r9d
  lea    -0x8(%rbp,%rax,4),%r11
  lea    -0x2(%r8),%r10d
L2:
  cmp    %edi,%r9d
  jle    L5
  mov    %r10d,%eax
  sub    %edi,%eax
  shl    $0x2,%rax
  mov    %r11,%rsi
  sub    %rax,%rsi
  mov    %rbx,%rax
L14:
  mov    -0x4(%rax),%edx
  mov    (%rax),%ecx
  mov    %ecx,-0x4(%rax)
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L14
L5:
  add    $0x2,%edi
  cmp    %edi,%r8d
  jg     L2
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void reorder_list(int *list) {
  int size = list_length(list);
  int i = 0, j = 0;
  for (i = 1; i < size; i += 2) {
    for (j = size - 1; j > i; j--) {
      list[j] ^= list[j - 1];
      list[j - 1] ^= list[j];
      list[j] ^= list[j - 1];
    }
  }
}
```