ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x668,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x658(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x10(%rsp),%rdi
  mov    $0xc8,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  movl   $0x18f,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <genMatrix@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <displayMatrix@plt>
  mov    %rbx,%rdx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <sortMatrix@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <displayMatrix@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getInput@plt>
  mov    %eax,%ebp
  lea    0x8(%rsp),%rsi
  mov    %rbx,%r8
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    %eax,%edi
  call   <searchMatrix@plt>
  cmp    $0x1,%eax
  je     L10
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%r8d
  lea    D51(%rip),%rcx
  mov    %ebp,%edx
  lea    D54(%rip),%rsi
  lea    D67(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x658(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x668,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%r8d
  lea    D70(%rip),%rcx
  mov    %ebp,%edx
  lea    D54(%rip),%rsi
  lea    D67(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
data_type: string
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D56
data_type: string
name: read_data
arguments: label: D51
data_type: string
name: read_data
arguments: label: D54
data_type: string
name: read_data
arguments: label: D67
data_type: string
name: read_data
arguments: label: D70
data_type: string

tool: D1: 
Un-sorted randomly generated matrix of values:

tool: D22: 
Sorted previously generated matrix of values:

tool: 

tool: D51: is not found. Default position

tool: D54: The number

tool: D67: 
%s %d %s [%d][%d]


tool: D70: is found at position

assistant: ```c
int main(void) {
  srand(time(NULL));
  int array[20][20] = {0};
  int searchedNumPosition[2] = {20 * 20 - 1, 0};
  int input;
  genMatrix(array);
  puts("\nUn-sorted randomly generated matrix of values:");
  displayMatrix(array);
  sortMatrix(20, 20, array);
  puts("\nSorted previously generated matrix of values:");
  displayMatrix(array);
  puts("");
  input = getInput();
  if (searchMatrix(input, searchedNumPosition, 20, 20, array) == 1) {
    printf("\n%s %d %s [%d][%d]\n", "The number", input, "is found at position", searchedNumPosition[0], searchedNumPosition[1]);
  } else {
    printf("\n%s %d %s [%d][%d]\n", "The number", input, "is not found. Default position", searchedNumPosition[0], searchedNumPosition[1]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbx
  sub    $0x668,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x658(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0xc8,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rbx,%rdi
  movq   $0x18f,0x8(%rsp)
  call   <genMatrix@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <displayMatrix@plt>
  mov    %rbx,%rdx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <sortMatrix@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <displayMatrix@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getInput@plt>
  mov    %rbx,%r8
  lea    0x8(%rsp),%rsi
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <searchMatrix@plt>
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%r8d
  cmp    $0x1,%eax
  je     L4
  lea    D18(%rip),%rcx
  mov    %r12d,%edx
  lea    D35(%rip),%rsi
  lea    D66(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x658(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x668,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L4:
  lea    D12(%rip),%rcx
  mov    %r12d,%edx
  lea    D35(%rip),%rsi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D63
type_infered: string
name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D35
type_infered: string
name: read_data
arguments: label: D66
type_infered: string
name: read_data
arguments: label: D12
type_infered: string

tool: D21: 
Un-sorted randomly generated matrix of values:

tool: D44: 
Sorted previously generated matrix of values:

tool: 

tool: D18: is not found. Default position

tool: D35: The number

tool: D66: 
%s %d %s [%d][%d]


tool: D12: is found at position

assistant: ```c
int main(void) {
  srand(time(NULL));
  int array[20][20] = {0};
  int searchedNumPosition[2] = {20 * 20 - 1, 0};
  int input;
  genMatrix(array);
  puts("\nUn-sorted randomly generated matrix of values:");
  displayMatrix(array);
  sortMatrix(20, 20, array);
  puts("\nSorted previously generated matrix of values:");
  displayMatrix(array);
  puts("");
  input = getInput();
  if (searchMatrix(input, searchedNumPosition, 20, 20, array) == 1) {
    printf("\n%s %d %s [%d][%d]\n", "The number", input, "is found at position", searchedNumPosition[0], searchedNumPosition[1]);
  } else {
    printf("\n%s %d %s [%d][%d]\n", "The number", input, "is not found. Default position", searchedNumPosition[0], searchedNumPosition[1]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbx
  sub    $0x668,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x658(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0xc8,%ecx
  rep stos %rax,%es:(%rdi)
  mov    D6(%rip),%rax
  mov    %rbx,%rdi
  mov    %rax,0x8(%rsp)
  call   <genMatrix@plt>
  lea    D81(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <displayMatrix@plt>
  mov    %rbx,%rdx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <sortMatrix@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <displayMatrix@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getInput@plt>
  mov    %rbx,%r8
  lea    0x8(%rsp),%rsi
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <searchMatrix@plt>
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%r8d
  cmp    $0x1,%eax
  je     L6
  lea    D67(%rip),%rcx
  mov    %r12d,%edx
  lea    D56(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x658(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x668,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L6:
  lea    D74(%rip),%rcx
  mov    %r12d,%edx
  lea    D56(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D81
type_guessed: string
name: extract_symbolic_data
arguments: tag: D57
type_guessed: string
name: extract_symbolic_data
arguments: tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: tag: D56
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D74
type_guessed: string

tool: {"D6": [0x8f,0x01,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D81: 
Un-sorted randomly generated matrix of values:

tool: D57: 
Sorted previously generated matrix of values:

tool: 

tool: D67: is not found. Default position

tool: D56: The number

tool: D14: 
%s %d %s [%d][%d]


tool: D74: is found at position

assistant: ```c
int main(void) {
  srand(time(NULL));
  int array[20][20] = {0};
  int searchedNumPosition[2] = {20 * 20 - 1, 0};
  int input;
  genMatrix(array);
  puts("\nUn-sorted randomly generated matrix of values:");
  displayMatrix(array);
  sortMatrix(20, 20, array);
  puts("\nSorted previously generated matrix of values:");
  displayMatrix(array);
  puts("");
  input = getInput();
  if (searchMatrix(input, searchedNumPosition, 20, 20, array) == 1) {
    printf("\n%s %d %s [%d][%d]\n", "The number", input, "is found at position", searchedNumPosition[0], searchedNumPosition[1]);
  } else {
    printf("\n%s %d %s [%d][%d]\n", "The number", input, "is not found. Default position", searchedNumPosition[0], searchedNumPosition[1]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  movl   $0xa,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  movb   $0x61,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  typeof(i) j;
  __typeof__(int *) ip;
  typeof(typeof(char *)[4]) y;
  j = 10;
  *ip = j;
  *y[3] = 'a';
  printf("%d\n", *ip);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rax)
  mov    0x18(%rsp),%rdx
  movb   $0x61,(%rdx)
  mov    (%rax),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  typeof(i) j;
  __typeof__(int *) ip;
  typeof(typeof(char *)[4]) y;
  j = 10;
  *ip = j;
  *y[3] = 'a';
  printf("%d\n", *ip);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x18(%rsp),%rdx
  movl   $0xa,(%rax)
  movb   $0x61,(%rdx)
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x1,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  typeof(i) j;
  __typeof__(int *) ip;
  typeof(typeof(char *)[4]) y;
  j = 10;
  *ip = j;
  *y[3] = 'a';
  printf("%d\n", *ip);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x18(%rsp),%rdx
  movl   $0xa,(%rax)
  movb   $0x61,(%rdx)
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x1,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  typeof(i) j;
  __typeof__(int *) ip;
  typeof(typeof(char *)[4]) y;
  j = 10;
  *ip = j;
  *y[3] = 'a';
  printf("%d\n", *ip);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x0,%eax
  call   <nargs@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rbx
  mov    $0x0,%r12d
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L29
  mov    $0x0,%eax
  jmp    L54
L29:
  add    $0x1,%r12d
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  cmpl   $0x1,-0x1c(%rbp)
  jle    L36
  mov    -0x20(%rbp),%rbx
  jmp    L15
L63:
  add    $0x1,%r12d
L15:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
L36:
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <alloc@plt>
  cltq
  mov    %rax,%r12
  mov    %r12,-0x18(%rbp)
  mov    -0x28(%rbp),%rbx
  nop
L89:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L89
  cmpl   $0x1,-0x1c(%rbp)
  jle    L48
  mov    -0x20(%rbp),%rbx
  sub    $0x1,%r12
  nop
L49:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
L48:
  mov    -0x18(%rbp),%rax
L54:
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
copy(ap) char *ap;
{
  register char *p, *np;
  char *onp;
  register n;
  int na;
  na = nargs();
  p = ap;
  n = 0;
  if (*p == 0)
    return (0);
  do
    n++;
  while (*p++);
  if (na > 1) {
    p = (&ap)[1];
    while (*p++)
      n++;
  }
  onp = np = alloc(n);
  p = ap;
  while (*np++ = *p++)
    ;
  if (na > 1) {
    p = (&ap)[1];
    np--;
    while (*np++ = *p++)
      ;
  }
  return (onp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <nargs@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  cmpb   $0x0,(%rbx)
  je     L51
  mov    %rbx,%rax
  mov    $0x1,%ecx
  sub    %ebx,%ecx
L7:
  lea    (%rcx,%rax,1),%edx
  mov    %edx,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L7
  cmp    $0x1,%ebp
  jle    L46
  mov    %rbx,0x8(%rsp)
  mov    0x10(%rsp),%rax
  lea    0x1(%rax),%rcx
  cmpb   $0x0,(%rax)
  je     L46
  mov    %rcx,%rax
  sub    %ecx,%edx
  lea    0x1(%rdx),%edx
L18:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L18
L46:
  mov    $0x0,%eax
  call   <alloc@plt>
  movslq %eax,%rdx
  mov    %rbx,%rdi
  sub    %rdx,%rdi
L24:
  mov    %rdx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rdx,%rdi,1),%ecx
  mov    %cl,(%rsi)
  test   %cl,%cl
  jne    L24
  cmp    $0x1,%ebp
  jle    L51
  mov    %rbx,0x8(%rsp)
  mov    0x10(%rsp),%rdi
  mov    $0x0,%edx
L62:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L62
L51:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
copy(ap) char *ap;
{
  register char *p, *np;
  char *onp;
  register n;
  int na;
  na = nargs();
  p = ap;
  n = 0;
  if (*p == 0)
    return (0);
  do
    n++;
  while (*p++);
  if (na > 1) {
    p = (&ap)[1];
    while (*p++)
      n++;
  }
  onp = np = alloc(n);
  p = ap;
  while (*np++ = *p++)
    ;
  if (na > 1) {
    p = (&ap)[1];
    np--;
    while (*np++ = *p++)
      ;
  }
  return (onp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <nargs@plt>
  movzbl (%rbx),%edx
  mov    %eax,%ebp
  xor    %eax,%eax
  test   %dl,%dl
  je     L53
  mov    $0x1,%esi
  mov    %rbx,%rax
  sub    %ebx,%esi
  jmp    L9
  nop
L58:
  movzbl (%rax),%edx
L9:
  lea    (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  mov    %ecx,%edi
  test   %dl,%dl
  jne    L58
  cmp    $0x1,%ebp
  jle    L67
  mov    0x10(%rsp),%rdx
  mov    %rbx,0x8(%rsp)
  cmpb   $0x0,(%rdx)
  lea    0x1(%rdx),%rax
  je     L67
  sub    %eax,%ecx
  lea    0x1(%rcx),%edx
  nopl   (%rax)
L84:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L84
L67:
  xor    %eax,%eax
  call   <alloc@plt>
  mov    %rbx,%rdi
  movslq %eax,%rcx
  sub    %rcx,%rdi
  nopl   (%rax)
L68:
  mov    %rcx,%rdx
  movzbl (%rcx,%rdi,1),%esi
  lea    0x1(%rcx),%rcx
  mov    %sil,(%rdx)
  test   %sil,%sil
  jne    L68
  cmp    $0x1,%ebp
  jle    L53
  mov    %rbx,0x8(%rsp)
  mov    0x10(%rsp),%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L70:
  movzbl (%rdi,%rcx,1),%esi
  mov    %sil,(%rdx,%rcx,1)
  add    $0x1,%rcx
  test   %sil,%sil
  jne    L70
L53:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
copy(ap) char *ap;
{
  register char *p, *np;
  char *onp;
  register n;
  int na;
  na = nargs();
  p = ap;
  n = 0;
  if (*p == 0)
    return (0);
  do
    n++;
  while (*p++);
  if (na > 1) {
    p = (&ap)[1];
    while (*p++)
      n++;
  }
  onp = np = alloc(n);
  p = ap;
  while (*np++ = *p++)
    ;
  if (na > 1) {
    p = (&ap)[1];
    np--;
    while (*np++ = *p++)
      ;
  }
  return (onp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <nargs@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  je     L7
  mov    $0x1,%ecx
  mov    %rbx,%rax
  sub    %ebx,%ecx
  nopl   0x0(%rax,%rax,1)
L55:
  lea    (%rcx,%rax,1),%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  mov    %edx,%edi
  jne    L55
  cmp    $0x1,%ebp
  jle    L42
  mov    0x10(%rsp),%rcx
  mov    %rbx,0x8(%rsp)
  cmpb   $0x0,(%rcx)
  lea    0x1(%rcx),%rax
  je     L42
  sub    %eax,%edx
  add    $0x1,%edx
  nopl   0x0(%rax)
L3:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
L42:
  xor    %eax,%eax
  call   <alloc@plt>
  mov    %rbx,%rdi
  movslq %eax,%rcx
  sub    %rcx,%rdi
  nopl   (%rax)
L36:
  mov    %rcx,%rdx
  movzbl (%rcx,%rdi,1),%esi
  lea    0x1(%rcx),%rcx
  mov    %sil,(%rdx)
  test   %sil,%sil
  jne    L36
  cmp    $0x1,%ebp
  jle    L7
  mov    %rbx,0x8(%rsp)
  mov    0x10(%rsp),%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L25:
  movzbl (%rdi,%rcx,1),%esi
  mov    %sil,(%rdx,%rcx,1)
  add    $0x1,%rcx
  test   %sil,%sil
  jne    L25
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
copy(ap) char *ap;
{
  register char *p, *np;
  char *onp;
  register n;
  int na;
  na = nargs();
  p = ap;
  n = 0;
  if (*p == 0)
    return (0);
  do
    n++;
  while (*p++);
  if (na > 1) {
    p = (&ap)[1];
    while (*p++)
      n++;
  }
  onp = np = alloc(n);
  p = ap;
  while (*np++ = *p++)
    ;
  if (na > 1) {
    p = (&ap)[1];
    np--;
    while (*np++ = *p++)
      ;
  }
  return (onp);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sort_pids>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x1,-0x18(%rbp)
  jmp    L42
L15:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L6
L31:
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  subq   $0x1,-0x10(%rbp)
L6:
  cmpq   $0x0,-0x10(%rbp)
  je     L40
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jl     L31
L40:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_pids(pid_t *pids, size_t count) {
  size_t i, j;
  pid_t value;
  for (i = 1; i < count; i++) {
    value = pids[i];
    for (j = i; j > 0 && value < pids[j - 1]; j--) {
      pids[j] = pids[j - 1];
    }
    pids[j] = value;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_pids>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L50
  mov    $0x2,%r9d
  mov    $0x1,%r8d
  jmp    L33
L62:
  mov    %rcx,(%rdi,%rax,8)
  cmp    %rsi,%r9
  jae    L50
L13:
  add    $0x1,%r8
  add    $0x1,%r9
L33:
  mov    (%rdi,%r8,8),%rcx
  mov    %r8,%rax
  test   %r8,%r8
  je     L28
L53:
  mov    -0x8(%rdi,%rax,8),%rdx
  cmp    %rcx,%rdx
  jle    L62
  mov    %rdx,(%rdi,%rax,8)
  sub    $0x1,%rax
  jne    L53
  jmp    L62
L28:
  mov    %rcx,(%rdi)
  jmp    L13
L50:
  ret
```

assistant: ```c
void sort_pids(pid_t *pids, size_t count) {
  size_t i, j;
  pid_t value;
  for (i = 1; i < count; i++) {
    value = pids[i];
    for (j = i; j > 0 && value < pids[j - 1]; j--) {
      pids[j] = pids[j - 1];
    }
    pids[j] = value;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort_pids>:
  endbr64
  lea    0x8(%rdi),%r11
  mov    $0x1,%r10d
  cmp    $0x1,%rsi
  jbe    L8
  nopl   0x0(%rax)
L30:
  mov    (%r11),%r9
  mov    %r11,%rax
  mov    %r10,%rdx
  nopl   0x0(%rax)
L0:
  mov    -0x8(%rax),%rcx
  mov    %rax,%r8
  cmp    %r9,%rcx
  jle    L31
  mov    %rcx,(%rax)
  lea    -0x8(%r8),%rax
  sub    $0x1,%rdx
  jne    L0
  mov    %rdi,%r8
L31:
  add    $0x1,%r10
  mov    %r9,(%r8)
  add    $0x8,%r11
  cmp    %r10,%rsi
  jne    L30
L8:
  ret
```

assistant: ```c
void sort_pids(pid_t *pids, size_t count) {
  size_t i, j;
  pid_t value;
  for (i = 1; i < count; i++) {
    value = pids[i];
    for (j = i; j > 0 && value < pids[j - 1]; j--) {
      pids[j] = pids[j - 1];
    }
    pids[j] = value;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_pids>:
  endbr64
  lea    0x8(%rdi),%r11
  mov    $0x1,%r10d
  cmp    $0x1,%rsi
  jbe    L24
  nopl   0x0(%rax)
L30:
  mov    (%r11),%r9
  mov    %r11,%rax
  mov    %r10,%rdx
  nopl   0x0(%rax)
L23:
  mov    -0x8(%rax),%rcx
  mov    %rax,%r8
  cmp    %r9,%rcx
  jle    L6
  mov    %rcx,(%rax)
  lea    -0x8(%r8),%rax
  sub    $0x1,%rdx
  jne    L23
  mov    %rdi,%r8
L6:
  add    $0x1,%r10
  mov    %r9,(%r8)
  add    $0x8,%r11
  cmp    %r10,%rsi
  jne    L30
L24:
  ret
```

assistant: ```c
void sort_pids(pid_t *pids, size_t count) {
  size_t i, j;
  pid_t value;
  for (i = 1; i < count; i++) {
    value = pids[i];
    for (j = i; j > 0 && value < pids[j - 1]; j--) {
      pids[j] = pids[j - 1];
    }
    pids[j] = value;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pvCancelCapture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: f

assistant: ```c
int pvCancelCapture(char byBoardNum) {
  notify_pvcall("f");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<pvCancelCapture>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: f

assistant: ```c
int pvCancelCapture(char byBoardNum) {
  notify_pvcall("f");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<pvCancelCapture>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: f

assistant: ```c
int pvCancelCapture(char byBoardNum) {
  notify_pvcall("f");
  return (0);
}
```