ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D18: Usage: ./sender [IPv6 do servidor] [MAC do servidor] [URL] [path]


tool: D8: Example: ./sender XXXX::XXXX:XXXX:XXXX:XXXX XX:XX:XX:XX:XX:XX www.google.com /


assistant: ```c
void usage() {
  printf("Usage: ./sender [IPv6 do servidor] [MAC do servidor] [URL] [path]\n");
  printf("Example: ./sender XXXX::XXXX:XXXX:XXXX:XXXX XX:XX:XX:XX:XX:XX www.google.com /\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D6: Usage: ./sender [IPv6 do servidor] [MAC do servidor] [URL] [path]


tool: D3: Example: ./sender XXXX::XXXX:XXXX:XXXX:XXXX XX:XX:XX:XX:XX:XX www.google.com /


assistant: ```c
void usage() {
  printf("Usage: ./sender [IPv6 do servidor] [MAC do servidor] [URL] [path]\n");
  printf("Example: ./sender XXXX::XXXX:XXXX:XXXX:XXXX XX:XX:XX:XX:XX:XX www.google.com /\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0xf(%rsp)
  movl   $0x77616853,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    $0x64,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  movsd  D46(%rip),%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  D54(%rip),%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x13(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    $0x41,%edx
  mov    %rbx,%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D46
type_infered: byte[8]
name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D54
type_infered: f64
name: parse_data
arguments: data_label: D55
type_infered: string
name: parse_data
arguments: data_label: D65
type_infered: string
name: parse_data
arguments: data_label: D23
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string
name: parse_data
arguments: data_label: D35
type_infered: string

tool: D13: You are %d miles away.


tool: {"D46": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D16: You have %f levels of power.


tool: D54: 56789.4532

tool: D55: You have %f awesome super powers.


tool: D65: I have an initial %c.


tool: D23: I have a first name: %s.


tool: D25: I have a last name: %s.


tool: D35: My whole name is %s %c. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Zed";
  char last_name[] = "Shaw";
  char *empty_string = "";
  printf("You are %d miles away.\n", distance);
  printf("You have %f levels of power.\n", power);
  printf("You have %f awesome super powers.\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name: %s.\n", first_name);
  printf("I have a last name: %s.\n", last_name);
  printf("My whole name is %s %c. %s.\n", first_name, initial, last_name);
  printf("%s", empty_string);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D51(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0xf(%rsp)
  lea    0xf(%rsp),%rbp
  lea    0x13(%rsp),%r12
  movl   $0x77616853,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <printf@plt>
  movsd  D76(%rip),%xmm0
  mov    $0x1,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  movsd  D83(%rip),%xmm0
  mov    $0x1,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D51
data_type: string
name: read_data
arguments: tag: D76
data_type: byte[8]
name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D83
data_type: f64
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D54
data_type: string
name: read_data
arguments: tag: D79
data_type: string
name: read_data
arguments: tag: D32
data_type: string
name: read_data
arguments: tag: D25
data_type: string

tool: D51: You are %d miles away.


tool: {"D76": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D9: You have %f levels of power.


tool: D83: 56789.4532

tool: D26: You have %f awesome super powers.


tool: D54: I have an initial %c.


tool: D79: I have a first name: %s.


tool: D32: I have a last name: %s.


tool: D25: My whole name is %s %c. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Zed";
  char last_name[] = "Shaw";
  char *empty_string = "";
  printf("You are %d miles away.\n", distance);
  printf("You have %f levels of power.\n", power);
  printf("You have %f awesome super powers.\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name: %s.\n", first_name);
  printf("I have a last name: %s.\n", last_name);
  printf("My whole name is %s %c. %s.\n", first_name, initial, last_name);
  printf("%s", empty_string);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D52(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0xf(%rsp)
  lea    0xf(%rsp),%rbp
  lea    0x13(%rsp),%r12
  movl   $0x77616853,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <printf@plt>
  movsd  D40(%rip),%xmm0
  mov    $0x1,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  movsd  D5(%rip),%xmm0
  mov    $0x1,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D72(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D52
data_type: string
name: retrieve_data
arguments: data_tag: D40
data_type: byte[8]
name: retrieve_data
arguments: data_tag: D58
data_type: string
name: retrieve_data
arguments: data_tag: D5
data_type: f64
name: retrieve_data
arguments: data_tag: D2
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string
name: retrieve_data
arguments: data_tag: D33
data_type: string
name: retrieve_data
arguments: data_tag: D72
data_type: string
name: retrieve_data
arguments: data_tag: D45
data_type: string

tool: D52: You are %d miles away.


tool: {"D40": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D58: You have %f levels of power.


tool: D5: 56789.4532

tool: D2: You have %f awesome super powers.


tool: D6: I have an initial %c.


tool: D33: I have a first name: %s.


tool: D72: I have a last name: %s.


tool: D45: My whole name is %s %c. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Zed";
  char last_name[] = "Shaw";
  char *empty_string = "";
  printf("You are %d miles away.\n", distance);
  printf("You have %f levels of power.\n", power);
  printf("You have %f awesome super powers.\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name: %s.\n", first_name);
  printf("I have a last name: %s.\n", last_name);
  printf("My whole name is %s %c. %s.\n", first_name, initial, last_name);
  printf("%s", empty_string);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %edi,-0x434(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  mov    (%rax),%ecx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x430(%rbp)
  mov    -0x440(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x428(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x414(%rbp)
  mov    $0x1c09,%edi
  call   <htons@plt>
  mov    %eax,-0x418(%rbp)
  mov    -0x428(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x428(%rbp),%rax
  mov    0x4(%rax),%ecx
  lea    -0x41c(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x41c(%rbp),%rcx
  mov    -0x430(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  mov    D48(%rip),%rax
  mov    (%rax),%edx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %eax,-0x42c(%rbp)
  mov    -0x42c(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x430(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x410(%rbp),%rcx
  mov    -0x430(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x42c(%rbp)
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    -0x42c(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x430(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int sd, msg_len;
  char message[1024];
  struct sockaddr_in addr;
  struct hostent *hostent;
  sd = socket(PF_INET, SOCK_DGRAM, 0);
  hostent = gethostbyname(argv[1]);
  addr.sin_family = AF_INET;
  addr.sin_port = htons(7177);
  memcpy(&addr.sin_addr, hostent->h_addr, hostent->h_length);
  connect(sd, (struct sockaddr *)&addr, sizeof(addr));
  msg_len = strlen(fgets(message, 1024, stdin));
  write(sd, message, msg_len);
  memset(message, 0, 1024);
  msg_len = read(sd, message, 1024);
  write(STDOUT_FILENO, message, msg_len);
  close(sd);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D34(%rip),%rax
  mov    (%rax),%esi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  mov    0x8(%rbp),%rdi
  call   <gethostbyname@plt>
  mov    %rax,%rbp
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x1c09,%edi
  call   <htons@plt>
  mov    %eax,0x8(%rsp)
  mov    0x4(%rbp),%esi
  lea    0x4(%rsp),%r12
  mov    0x0(%rbp),%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <connect@plt>
  lea    0x10(%rsp),%rbp
  mov    D29(%rip),%rax
  mov    (%rax),%edx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    D47(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x420,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int sd, msg_len;
  char message[1024];
  struct sockaddr_in addr;
  struct hostent *hostent;
  sd = socket(PF_INET, SOCK_DGRAM, 0);
  hostent = gethostbyname(argv[1]);
  addr.sin_family = AF_INET;
  addr.sin_port = htons(7177);
  memcpy(&addr.sin_addr, hostent->h_addr, hostent->h_length);
  connect(sd, (struct sockaddr *)&addr, sizeof(addr));
  msg_len = strlen(fgets(message, 1024, stdin));
  write(sd, message, msg_len);
  memset(message, 0, 1024);
  msg_len = read(sd, message, 1024);
  write(STDOUT_FILENO, message, msg_len);
  close(sd);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    (%rax),%esi
  mov    D30(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    0x8(%r12),%rdi
  mov    %eax,%ebp
  call   <gethostbyname@plt>
  mov    $0x1c09,%edi
  mov    %rax,%r12
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  call   <htons@plt>
  mov    0x4(%r12),%esi
  mov    (%r12),%edx
  mov    %r13,%rdi
  mov    %eax,0x8(%rsp)
  lea    0x10(%rsp),%r12
  call   <memcpy@plt>
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  mov    D8(%rip),%rax
  mov    $0x400,%esi
  mov    %r12,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  xor    %esi,%esi
  mov    $0x400,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x400,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %r12,%rsi
  mov    %eax,%edx
  mov    D44(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x420,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int sd, msg_len;
  char message[1024];
  struct sockaddr_in addr;
  struct hostent *hostent;
  sd = socket(PF_INET, SOCK_DGRAM, 0);
  hostent = gethostbyname(argv[1]);
  addr.sin_family = AF_INET;
  addr.sin_port = htons(7177);
  memcpy(&addr.sin_addr, hostent->h_addr, hostent->h_length);
  connect(sd, (struct sockaddr *)&addr, sizeof(addr));
  msg_len = strlen(fgets(message, 1024, stdin));
  write(sd, message, msg_len);
  memset(message, 0, 1024);
  msg_len = read(sd, message, 1024);
  write(STDOUT_FILENO, message, msg_len);
  close(sd);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    D31(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    (%rax),%esi
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    0x8(%r12),%rdi
  mov    %eax,%ebp
  call   <gethostbyname@plt>
  mov    $0x1c09,%edi
  mov    %rax,%r12
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  call   <htons@plt>
  mov    0x4(%r12),%esi
  mov    (%r12),%edx
  mov    %r13,%rdi
  mov    %eax,0x8(%rsp)
  lea    0x10(%rsp),%r12
  call   <memcpy@plt>
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  mov    D46(%rip),%rax
  mov    $0x400,%esi
  mov    %r12,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  xor    %esi,%esi
  mov    $0x400,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x400,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %r12,%rsi
  mov    %eax,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x420,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int sd, msg_len;
  char message[1024];
  struct sockaddr_in addr;
  struct hostent *hostent;
  sd = socket(PF_INET, SOCK_DGRAM, 0);
  hostent = gethostbyname(argv[1]);
  addr.sin_family = AF_INET;
  addr.sin_port = htons(7177);
  memcpy(&addr.sin_addr, hostent->h_addr, hostent->h_length);
  connect(sd, (struct sockaddr *)&addr, sizeof(addr));
  msg_len = strlen(fgets(message, 1024, stdin));
  write(sd, message, msg_len);
  memset(message, 0, 1024);
  msg_len = read(sd, message, 1024);
  write(STDOUT_FILENO, message, msg_len);
  close(sd);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<d1_allocmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L4
L5:
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
void *d1_allocmem(unsigned int size) {
  unsigned int *ptr;
  ptr = (unsigned int *)malloc((size_t)size);
  if (!ptr) {
    return NULL;
  }
  return (void *)ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d1_allocmem>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *d1_allocmem(unsigned int size) {
  unsigned int *ptr;
  ptr = (unsigned int *)malloc((size_t)size);
  if (!ptr) {
    return NULL;
  }
  return (void *)ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<d1_allocmem>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *d1_allocmem(unsigned int size) {
  unsigned int *ptr;
  ptr = (unsigned int *)malloc((size_t)size);
  if (!ptr) {
    return NULL;
  }
  return (void *)ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<d1_allocmem>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *d1_allocmem(unsigned int size) {
  unsigned int *ptr;
  ptr = (unsigned int *)malloc((size_t)size);
  if (!ptr) {
    return NULL;
  }
  return (void *)ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64636261,-0x1a(%rbp)
  movb   $0x0,-0x16(%rbp)
  movabs $0x6868626868616868,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x64686863,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1a(%rbp),%rdx
  lea    -0x15(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <any@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D11: 
%s


tool: D3: 
%d


assistant: ```c
int main() {
  char badchars[] = "abcd";
  char source[] = "hhahhbhhchhd";
  printf("\n%s\n", source);
  printf("\n%d\n", any(source, badchars));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64636261,0x6(%rsp)
  movb   $0x0,0xa(%rsp)
  movabs $0x6868626868616868,%rax
  mov    %rax,0xb(%rsp)
  movl   $0x64686863,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xb(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x6(%rsp),%rsi
  mov    %rbx,%rdi
  call   <any@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D14: 
%s


tool: D19: 
%d


assistant: ```c
int main() {
  char badchars[] = "abcd";
  char source[] = "hhahhbhhchhd";
  printf("\n%s\n", source);
  printf("\n%d\n", any(source, badchars));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xb(%rsp),%rbp
  movb   $0x0,0xa(%rsp)
  movabs $0x6868626868616868,%rax
  mov    %rax,0xb(%rsp)
  mov    %rbp,%rsi
  xor    %eax,%eax
  movl   $0x64636261,0x6(%rsp)
  movl   $0x64686863,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <printf@plt>
  lea    0x6(%rsp),%rsi
  mov    %rbp,%rdi
  call   <any@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string
name: unpack_data
arguments: data_tag: D19
type_infered: string

tool: D0: 
%s


tool: D19: 
%d


assistant: ```c
int main() {
  char badchars[] = "abcd";
  char source[] = "hhahhbhhchhd";
  printf("\n%s\n", source);
  printf("\n%d\n", any(source, badchars));
}
```