ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gf8mul_01111001>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm2
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm3
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm3
  pxor   %xmm5,%xmm2
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm2
  pxor   %xmm4,%xmm0
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm1
  pxor   %xmm5,%xmm3
  pxor   %xmm2,%xmm7
  pxor   %xmm2,%xmm0
  pxor   %xmm7,%xmm2
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  ret
```

assistant: ```c
void gf8mul_01111001(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm2, %xmm7\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gf8mul_01111001>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm2
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm3
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm3
  pxor   %xmm5,%xmm2
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm2
  pxor   %xmm4,%xmm0
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm1
  pxor   %xmm5,%xmm3
  pxor   %xmm2,%xmm7
  pxor   %xmm2,%xmm0
  pxor   %xmm7,%xmm2
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  ret
```

assistant: ```c
void gf8mul_01111001(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm2, %xmm7\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  jmp    L97
L113:
  mov    -0x2c(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x2c(%rbp)
L97:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L113
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L49
L46:
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L120
L108:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L26
  jmp    L5
L26:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    $0xffffffff,%eax
  jne    L17
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  jmp    L41
L17:
  nop
  addl   $0x1,-0x28(%rbp)
L120:
  cmpl   $0x5,-0x28(%rbp)
  jle    L108
L41:
  addl   $0x1,-0x28(%rbp)
L49:
  cmpl   $0x5,-0x28(%rbp)
  jle    L46
  mov    $0x24,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L32
L103:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L32:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L103
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string

tool: D23: THE AMAZING LOTTERY

tool: D38: %d


tool: D14: Today's numbers are : %c

tool: D27: %d, 

assistant: ```c
int main() {
  int x, y, z, numbers[6];
  for (x = 0; x < 6; x++)
    numbers[x] = -1;
  srand((unsigned)time(NULL));
  puts("THE AMAZING LOTTERY");
  for (y = 0; y < 6; y++) {
    printf("%d\n", y);
  label:
    z = rand() % 6;
    for (y = 0; y < 6; y++) {
      if (z == numbers[y])
        goto label;
      else if (numbers[y] != -1)
        continue;
      else {
        numbers[y] = z;
        break;
      }
    }
  }
  printf("Today's numbers are : %c", 36);
  for (x = 0; x < 6; x++)
    printf("%d, ", numbers[x]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0xffffffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%esi
  lea    D25(%rip),%rbx
  jmp    L35
L46:
  movslq %eax,%rcx
  mov    %edx,(%rsp,%rcx,4)
  lea    0x1(%rax),%esi
  cmp    $0x5,%esi
  jg     L44
L35:
  mov    %rbx,%rdi
  call   <printf@plt>
L69:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    $0x0,%eax
L68:
  mov    (%rsi),%ecx
  cmp    %edx,%ecx
  je     L69
  cmp    $0xffffffff,%ecx
  je     L46
  add    $0x1,%eax
  add    $0x4,%rsi
  cmp    $0x6,%eax
  jne    L68
L44:
  mov    $0x24,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x18(%rbp),%r12
  lea    D12(%rip),%rbx
L51:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L51
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D25
data_type: string
name: parse_data
arguments: data_label: D11
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string

tool: D0: THE AMAZING LOTTERY

tool: D25: %d


tool: D11: Today's numbers are : %c

tool: D12: %d, 

assistant: ```c
int main() {
  int x, y, z, numbers[6];
  for (x = 0; x < 6; x++)
    numbers[x] = -1;
  srand((unsigned)time(NULL));
  puts("THE AMAZING LOTTERY");
  for (y = 0; y < 6; y++) {
    printf("%d\n", y);
  label:
    z = rand() % 6;
    for (y = 0; y < 6; y++) {
      if (z == numbers[y])
        goto label;
      else if (numbers[y] != -1)
        continue;
      else {
        numbers[y] = z;
        break;
      }
    }
  }
  printf("Today's numbers are : %c", 36);
  for (x = 0; x < 6; x++)
    printf("%d, ", numbers[x]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  mov    $0xffffffff,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  mov    %rsp,%rbx
  movq   $0xffffffffffffffff,0x8(%rsp)
  movq   $0xffffffffffffffff,0x10(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdi
  call   <printf@plt>
L87:
  xor    %eax,%eax
  mov    %rbx,%r13
  call   <rand@plt>
  mov    %rbx,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %ebp,%ecx
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    %edx,%ecx
  je     L87
  lea    0x1(%rax),%esi
  cmp    $0xffffffff,%ecx
  je     L75
L74:
  add    $0x4,%rdi
  cmp    $0x6,%esi
  je     L73
  mov    (%rdi),%ecx
  movslq %esi,%rax
  cmp    %edx,%ecx
  je     L87
  lea    0x1(%rax),%esi
  cmp    $0xffffffff,%ecx
  jne    L74
L75:
  mov    %edx,(%rsp,%rax,4)
  cmp    $0x6,%esi
  je     L73
  mov    (%rsp),%ebp
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L73:
  mov    $0x24,%esi
  lea    D10(%rip),%rdi
  add    $0x18,%rbx
  call   <printf@plt>
  lea    D35(%rip),%rbp
L67:
  mov    0x0(%r13),%esi
  mov    %rbp,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L67
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
type_guessed: string
name: parse_data
arguments: data_tag: D32
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D35
type_guessed: string

tool: D20: %d


tool: D32: THE AMAZING LOTTERY

tool: D10: Today's numbers are : %c

tool: D35: %d, 

assistant: ```c
int main() {
  int x, y, z, numbers[6];
  for (x = 0; x < 6; x++)
    numbers[x] = -1;
  srand((unsigned)time(NULL));
  puts("THE AMAZING LOTTERY");
  for (y = 0; y < 6; y++) {
    printf("%d\n", y);
  label:
    z = rand() % 6;
    for (y = 0; y < 6; y++) {
      if (z == numbers[y])
        goto label;
      else if (numbers[y] != -1)
        continue;
      else {
        numbers[y] = z;
        break;
      }
    }
  }
  printf("Today's numbers are : %c", 36);
  for (x = 0; x < 6; x++)
    printf("%d, ", numbers[x]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jp2_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L17:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  xor    %eax,-0x4(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t jp2_checksum(uint8_t *data, int len) {
  uint8_t csum = 0;
  while (len--) {
    csum ^= *data++;
  }
  return csum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<jp2_checksum>:
  endbr64
  test   %esi,%esi
  je     L7
  mov    %esi,%eax
  lea    (%rdi,%rax,4),%rdx
  mov    $0x0,%eax
L9:
  add    $0x4,%rdi
  xor    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L9
  ret
L7:
  mov    %esi,%eax
  ret
```

assistant: ```c
uint8_t jp2_checksum(uint8_t *data, int len) {
  uint8_t csum = 0;
  while (len--) {
    csum ^= *data++;
  }
  return csum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<jp2_checksum>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,4),%rdx
L18:
  add    $0x4,%rdi
  xor    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L18
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t jp2_checksum(uint8_t *data, int len) {
  uint8_t csum = 0;
  while (len--) {
    csum ^= *data++;
  }
  return csum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jp2_checksum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L68
  cmp    $0x2,%ecx
  jbe    L12
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L23:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L23
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  pxor   %xmm1,%xmm0
  mov    %edx,%r8d
  sub    %edx,%ecx
  movdqa %xmm0,%xmm1
  lea    (%rdi,%r8,4),%rdi
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%esi
  je     L13
L5:
  xor    (%rdi),%eax
  test   %ecx,%ecx
  je     L35
  xor    0x4(%rdi),%eax
  cmp    $0x1,%ecx
  je     L35
  xor    0x8(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
L35:
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
L12:
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
uint8_t jp2_checksum(uint8_t *data, int len) {
  uint8_t csum = 0;
  while (len--) {
    csum ^= *data++;
  }
  return csum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L10
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L32
  movzbl -0x9(%rbp),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L27
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L18
L27:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L18
L32:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L18
L10:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L18:
  movzbl -0x9(%rbp),%eax
  lea    -0x4d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 315155497UL) - (unsigned char)118;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  lea    0x0(,%rax,4),%edx
  test   $0x10,%al
  sub    $0x4d,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 315155497UL) - (unsigned char)118;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    0xb(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 315155497UL) - (unsigned char)118;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    0xb(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 315155497UL) - (unsigned char)118;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<waitConexion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x10,-0x44(%rbp)
  lea    -0x44(%rbp),%rdx
  lea    -0x40(%rbp),%rcx
  mov    -0x54(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <accept@plt>
  mov    -0x60(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x60(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L4
  mov    $0xffffffff,%eax
  jmp    L2
L4:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <inet_ntoa@plt>
  mov    %eax,%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%rax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D23
type: string
name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D27
type: string

tool: D23: I have been connected from:

tool: D15: 	IP address: %s


tool: D27: 	port: %u


assistant: ```c
int waitConexion(int serverSock, int *psockConnection) {
  struct sockaddr_in cAddr;
  socklen_t sockLen;
  char str[30];
  sockLen = sizeof(cAddr);
  if ((*psockConnection = accept(serverSock, (struct sockaddr *)&cAddr, &sockLen)) == -1) {
    return -1;
  }
  printf("I have been connected from:\n");
  strcpy(str, inet_ntoa(cAddr.sin_addr));
  printf("\tIP address: %s\n", str);
  printf("\tport: %u\n", (unsigned int)cAddr.sin_port);
  return 0;
}
```