ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<grib2ltypeToZaxisType>:
  endbr64
  cmp    $0xa6,%edi
  ja     L5
  mov    %edi,%edi
  lea    D3(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  ret
  mov    $0x10,%eax
  ret
  mov    $0x11,%eax
  ret
  mov    $0x12,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xf,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x13,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x14,%eax
  ret
  mov    $0x15,%eax
  ret
  mov    $0x16,%eax
  ret
  mov    $0x17,%eax
  ret
  mov    $0x18,%eax
  ret
  mov    $0x19,%eax
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int grib2ltypeToZaxisType(int grib_ltype) {
  int zaxistype = 1;
  switch (grib_ltype) {
  case 1: {
    zaxistype = 0;
    break;
  }
  case 2: {
    zaxistype = 16;
    break;
  }
  case 3: {
    zaxistype = 17;
    break;
  }
  case 4: {
    zaxistype = 18;
    break;
  }
  case 8: {
    zaxistype = 13;
    break;
  }
  case 9: {
    zaxistype = 14;
    break;
  }
  case 10: {
    zaxistype = 15;
    break;
  }
  case 101: {
    zaxistype = 12;
    break;
  }
  case 100: {
    zaxistype = 4;
    break;
  }
  case 103: {
    zaxistype = 5;
    break;
  }
  case 102: {
    zaxistype = 10;
    break;
  }
  case 104: {
    zaxistype = 11;
    break;
  }
  case 105: {
    zaxistype = 2;
    break;
  }
  case 106: {
    zaxistype = 7;
    break;
  }
  case 107: {
    zaxistype = 8;
    break;
  }
  case 114: {
    zaxistype = 19;
    break;
  }
  case 160: {
    zaxistype = 6;
    break;
  }
  case 162: {
    zaxistype = 20;
    break;
  }
  case 163: {
    zaxistype = 21;
    break;
  }
  case 164: {
    zaxistype = 22;
    break;
  }
  case 165: {
    zaxistype = 23;
    break;
  }
  case 166: {
    zaxistype = 24;
    break;
  }
  case 150: {
    zaxistype = 25;
    break;
  }
  }
  return (zaxistype);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<grib2ltypeToZaxisType>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  cmp    $0xa5,%edi
  ja     L5
  lea    D2(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: 

assistant: ```c
int grib2ltypeToZaxisType(int grib_ltype) {
  int zaxistype = 1;
  switch (grib_ltype) {
  case 1: {
    zaxistype = 0;
    break;
  }
  case 2: {
    zaxistype = 16;
    break;
  }
  case 3: {
    zaxistype = 17;
    break;
  }
  case 4: {
    zaxistype = 18;
    break;
  }
  case 8: {
    zaxistype = 13;
    break;
  }
  case 9: {
    zaxistype = 14;
    break;
  }
  case 10: {
    zaxistype = 15;
    break;
  }
  case 101: {
    zaxistype = 12;
    break;
  }
  case 100: {
    zaxistype = 4;
    break;
  }
  case 103: {
    zaxistype = 5;
    break;
  }
  case 102: {
    zaxistype = 10;
    break;
  }
  case 104: {
    zaxistype = 11;
    break;
  }
  case 105: {
    zaxistype = 2;
    break;
  }
  case 106: {
    zaxistype = 7;
    break;
  }
  case 107: {
    zaxistype = 8;
    break;
  }
  case 114: {
    zaxistype = 19;
    break;
  }
  case 160: {
    zaxistype = 6;
    break;
  }
  case 162: {
    zaxistype = 20;
    break;
  }
  case 163: {
    zaxistype = 21;
    break;
  }
  case 164: {
    zaxistype = 22;
    break;
  }
  case 165: {
    zaxistype = 23;
    break;
  }
  case 166: {
    zaxistype = 24;
    break;
  }
  case 150: {
    zaxistype = 25;
    break;
  }
  }
  return (zaxistype);
}
```
user: Translate the below assembly code into C programming language:

```asm
<grib2ltypeToZaxisType>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  cmp    $0xa5,%edi
  ja     L5
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: 

assistant: ```c
int grib2ltypeToZaxisType(int grib_ltype) {
  int zaxistype = 1;
  switch (grib_ltype) {
  case 1: {
    zaxistype = 0;
    break;
  }
  case 2: {
    zaxistype = 16;
    break;
  }
  case 3: {
    zaxistype = 17;
    break;
  }
  case 4: {
    zaxistype = 18;
    break;
  }
  case 8: {
    zaxistype = 13;
    break;
  }
  case 9: {
    zaxistype = 14;
    break;
  }
  case 10: {
    zaxistype = 15;
    break;
  }
  case 101: {
    zaxistype = 12;
    break;
  }
  case 100: {
    zaxistype = 4;
    break;
  }
  case 103: {
    zaxistype = 5;
    break;
  }
  case 102: {
    zaxistype = 10;
    break;
  }
  case 104: {
    zaxistype = 11;
    break;
  }
  case 105: {
    zaxistype = 2;
    break;
  }
  case 106: {
    zaxistype = 7;
    break;
  }
  case 107: {
    zaxistype = 8;
    break;
  }
  case 114: {
    zaxistype = 19;
    break;
  }
  case 160: {
    zaxistype = 6;
    break;
  }
  case 162: {
    zaxistype = 20;
    break;
  }
  case 163: {
    zaxistype = 21;
    break;
  }
  case 164: {
    zaxistype = 22;
    break;
  }
  case 165: {
    zaxistype = 23;
    break;
  }
  case 166: {
    zaxistype = 24;
    break;
  }
  case 150: {
    zaxistype = 25;
    break;
  }
  }
  return (zaxistype);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RFCCpe0IntSelectClearEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <RFCCpe0IntSelect@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <RFCCpeIntClear@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <RFCCpeIntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void RFCCpe0IntSelectClearEnable(uint32_t ui32Mask) {
  RFCCpe0IntSelect(ui32Mask);
  RFCCpeIntClear(ui32Mask);
  RFCCpeIntEnable(ui32Mask);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RFCCpe0IntSelectClearEnable>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <RFCCpe0IntSelect@plt>
  mov    %ebx,%edi
  call   <RFCCpeIntClear@plt>
  mov    %ebx,%edi
  call   <RFCCpeIntEnable@plt>
  pop    %rbx
  ret
```

assistant: ```c
void RFCCpe0IntSelectClearEnable(uint32_t ui32Mask) {
  RFCCpe0IntSelect(ui32Mask);
  RFCCpeIntClear(ui32Mask);
  RFCCpeIntEnable(ui32Mask);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RFCCpe0IntSelectClearEnable>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <RFCCpe0IntSelect@plt>
  mov    %ebp,%edi
  call   <RFCCpeIntClear@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1080 <RFCCpeIntEnable@plt>
```

assistant: ```c
void RFCCpe0IntSelectClearEnable(uint32_t ui32Mask) {
  RFCCpe0IntSelect(ui32Mask);
  RFCCpeIntClear(ui32Mask);
  RFCCpeIntEnable(ui32Mask);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RFCCpe0IntSelectClearEnable>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <RFCCpe0IntSelect@plt>
  mov    %ebp,%edi
  call   <RFCCpeIntClear@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1080 <RFCCpeIntEnable@plt>
```

assistant: ```c
void RFCCpe0IntSelectClearEnable(uint32_t ui32Mask) {
  RFCCpe0IntSelect(ui32Mask);
  RFCCpeIntClear(ui32Mask);
  RFCCpeIntEnable(ui32Mask);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nj_modify_branch_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebp
  mov    (%r8),%rax
  movslq %edi,%rbx
  lea    (%rax,%rbx,1),%r12
  cmpb   $0x0,(%r12)
  jne    L39
  movslq %esi,%r9
  cmpb   $0x0,(%rax,%r9,1)
  je     L110
L93:
  cmp    $0x1,%ecx
  jle    L69
  mov    %ecx,%r10d
  mov    $0x1,%eax
  mov    $0xffffffff,%r13d
  jmp    L119
L39:
  movslq %esi,%r9
  cmpb   $0x0,(%rax,%r9,1)
  jne    L93
  mov    $0xffffffff,%r13d
  jmp    L14
L66:
  lea    (%rdi,%rbp,1),%r15d
  movslq %r15d,%r15
  cmpb   $0x2,-0x1(%rcx,%r15,1)
  cmove  %eax,%r13d
  jmp    L78
L5:
  mov    %dl,(%r11)
L105:
  movb   $0x0,(%rsi)
L57:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L64
L119:
  mov    (%r8,%rax,8),%rcx
  lea    (%rcx,%r9,1),%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L57
  movsbl %dl,%edi
  lea    (%rcx,%rbx,1),%r11
  cmp    (%r11),%dl
  je     L66
L78:
  cmpb   $0x0,(%r12)
  je     L5
  add    %ebp,%edi
  movslq %edi,%rdi
  subb   $0x1,-0x1(%rcx,%rdi,1)
  jmp    L105
L69:
  mov    $0xffffffff,%r13d
L64:
  movb   $0x1,(%r12)
L14:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L110:
  mov    $0xffffffff,%r13d
  jmp    L14
```

assistant: ```c
int nj_modify_branch_matrix(int mi, int mj, int n, int m, char **branch_matrix) {
  int i, ret_val;
  char *array, *first;
  first = branch_matrix[0];
  ret_val = -1;
  if (first[mi] == 0 && first[mj] == 0)
    return -1;
  if (first[mj]) {
    for (i = 1; i < m; ++i) {
      array = branch_matrix[i];
      if (array[mj]) {
        int tmp = array[mj];
        if (array[mi] == tmp && array[n + tmp - 1] == 2)
          ret_val = i;
        if (first[mi])
          --array[n + tmp - 1];
        else
          array[mi] = tmp;
        array[mj] = 0;
      }
    }
    first[mi] = 1;
  }
  return ret_val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nj_modify_branch_matrix>:
  endbr64
  mov    (%r8),%rax
  movslq %esi,%r10
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  cmpb   $0x0,(%rax,%r10,1)
  lea    (%rax,%rbx,1),%r12
  je     L33
  cmp    $0x1,%ecx
  jle    L35
  mov    %edx,%ebp
  movslq %ecx,%r9
  mov    $0x1,%eax
  mov    $0xffffffff,%r13d
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L38:
  add    %ebp,%edi
  movslq %edi,%rdi
  subb   $0x1,-0x1(%rcx,%rdi,1)
L85:
  movb   $0x0,(%rsi)
L21:
  add    $0x1,%rax
  cmp    %rax,%r9
  je     L65
L17:
  mov    (%r8,%rax,8),%rcx
  lea    (%rcx,%r10,1),%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L21
  lea    (%rcx,%rbx,1),%r11
  movsbl %dl,%edi
  cmp    (%r11),%dl
  jne    L64
  lea    (%rdi,%rbp,1),%r14d
  movslq %r14d,%r14
  cmpb   $0x2,-0x1(%rcx,%r14,1)
  cmove  %eax,%r13d
L64:
  cmpb   $0x0,(%r12)
  jne    L38
  mov    %dl,(%r11)
  jmp    L85
  xchg   %ax,%ax
L35:
  mov    $0xffffffff,%r13d
  cs nopw 0x0(%rax,%rax,1)
L65:
  movb   $0x1,(%r12)
L37:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  mov    $0xffffffff,%r13d
  jmp    L37
```

assistant: ```c
int nj_modify_branch_matrix(int mi, int mj, int n, int m, char **branch_matrix) {
  int i, ret_val;
  char *array, *first;
  first = branch_matrix[0];
  ret_val = -1;
  if (first[mi] == 0 && first[mj] == 0)
    return -1;
  if (first[mj]) {
    for (i = 1; i < m; ++i) {
      array = branch_matrix[i];
      if (array[mj]) {
        int tmp = array[mj];
        if (array[mi] == tmp && array[n + tmp - 1] == 2)
          ret_val = i;
        if (first[mi])
          --array[n + tmp - 1];
        else
          array[mi] = tmp;
        array[mj] = 0;
      }
    }
    first[mi] = 1;
  }
  return ret_val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nj_modify_branch_matrix>:
  endbr64
  mov    (%r8),%rax
  movslq %esi,%r10
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  cmpb   $0x0,(%rax,%r10,1)
  lea    (%rax,%rbx,1),%r12
  je     L82
  cmp    $0x1,%ecx
  jle    L14
  mov    %edx,%ebp
  movslq %ecx,%r9
  mov    $0x1,%eax
  mov    $0xffffffff,%r13d
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L7:
  add    %ebp,%edi
  movslq %edi,%rdi
  subb   $0x1,-0x1(%rcx,%rdi,1)
L26:
  movb   $0x0,(%rsi)
L43:
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L74
L75:
  mov    (%r8,%rax,8),%rcx
  lea    (%rcx,%r10,1),%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L43
  lea    (%rcx,%rbx,1),%r11
  movsbl %dl,%edi
  cmp    (%r11),%dl
  jne    L83
  lea    (%rdi,%rbp,1),%r14d
  movslq %r14d,%r14
  cmpb   $0x2,-0x1(%rcx,%r14,1)
  cmove  %eax,%r13d
L83:
  cmpb   $0x0,(%r12)
  jne    L7
  mov    %dl,(%r11)
  jmp    L26
  xchg   %ax,%ax
L14:
  mov    $0xffffffff,%r13d
  cs nopw 0x0(%rax,%rax,1)
L74:
  movb   $0x1,(%r12)
L9:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L82:
  mov    $0xffffffff,%r13d
  jmp    L9
```

assistant: ```c
int nj_modify_branch_matrix(int mi, int mj, int n, int m, char **branch_matrix) {
  int i, ret_val;
  char *array, *first;
  first = branch_matrix[0];
  ret_val = -1;
  if (first[mi] == 0 && first[mj] == 0)
    return -1;
  if (first[mj]) {
    for (i = 1; i < m; ++i) {
      array = branch_matrix[i];
      if (array[mj]) {
        int tmp = array[mj];
        if (array[mi] == tmp && array[n + tmp - 1] == 2)
          ret_val = i;
        if (first[mi])
          --array[n + tmp - 1];
        else
          array[mi] = tmp;
        array[mj] = 0;
      }
    }
    first[mi] = 1;
  }
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WriteINIInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %edx,-0x74(%rbp)
  mov    %rcx,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x74(%rbp),%edx
  lea    -0x60(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x80(%rbp),%rcx
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <WriteINIString@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string

tool: D0: %i

assistant: ```c
void WriteINIInt(char *section, char *key, int32_t value, char *filename) {
  char buf[80];
  sprintf(buf, "%i", value);
  WriteINIString(section, key, buf, filename);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<WriteINIInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    D9(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <WriteINIString@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string

tool: D9: %i

assistant: ```c
void WriteINIInt(char *section, char *key, int32_t value, char *filename) {
  char buf[80];
  sprintf(buf, "%i", value);
  WriteINIString(section, key, buf, filename);
}
```
user: What is the c source code of the assembly code below:

```asm
<WriteINIInt>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D2(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <WriteINIString@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: %i

assistant: ```c
void WriteINIInt(char *section, char *key, int32_t value, char *filename) {
  char buf[80];
  sprintf(buf, "%i", value);
  WriteINIString(section, key, buf, filename);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<WriteINIInt>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D9(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <WriteINIString@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: %i

assistant: ```c
void WriteINIInt(char *section, char *key, int32_t value, char *filename) {
  char buf[80];
  sprintf(buf, "%i", value);
  WriteINIString(section, key, buf, filename);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bit_num_ints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shr    $0x5,%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  and    $0x1f,%eax
  test   %rax,%rax
  je     L1
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int bit_num_ints(int num_bits) {
  unsigned int i;
  i = num_bits / (sizeof(unsigned int) * 8);
  if (num_bits % (sizeof(unsigned int) * 8))
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bit_num_ints>:
  endbr64
  movslq %edi,%rax
  shr    $0x5,%rax
  and    $0x1f,%edi
  cmp    $0x1,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int bit_num_ints(int num_bits) {
  unsigned int i;
  i = num_bits / (sizeof(unsigned int) * 8);
  if (num_bits % (sizeof(unsigned int) * 8))
    i++;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<bit_num_ints>:
  endbr64
  movslq %edi,%rax
  and    $0x1f,%edi
  shr    $0x5,%rax
  cmp    $0x1,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int bit_num_ints(int num_bits) {
  unsigned int i;
  i = num_bits / (sizeof(unsigned int) * 8);
  if (num_bits % (sizeof(unsigned int) * 8))
    i++;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bit_num_ints>:
  endbr64
  movslq %edi,%rax
  and    $0x1f,%edi
  shr    $0x5,%rax
  cmp    $0x1,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int bit_num_ints(int num_bits) {
  unsigned int i;
  i = num_bits / (sizeof(unsigned int) * 8);
  if (num_bits % (sizeof(unsigned int) * 8))
    i++;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string

tool: D21: pid = %d


tool: D24: system before.

tool: D26: ./system_sub 123 abc xyz

assistant: ```c
int main(void) {
  pid_t pid;
  pid = getpid();
  printf("pid = %d\n", pid);
  sleep(60);
  printf("system before.\n");
  system("./system_sub 123 abc xyz");
  sleep(60);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <system@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D29
type_infered: string

tool: D18: pid = %d


tool: D15: system before.

tool: D29: ./system_sub 123 abc xyz

assistant: ```c
int main(void) {
  pid_t pid;
  pid = getpid();
  printf("pid = %d\n", pid);
  sleep(60);
  printf("system before.\n");
  system("./system_sub 123 abc xyz");
  sleep(60);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D19(%rip),%rdi
  call   <system@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D19
type: string

tool: D15: pid = %d


tool: D2: system before.

tool: D19: ./system_sub 123 abc xyz

assistant: ```c
int main(void) {
  pid_t pid;
  pid = getpid();
  printf("pid = %d\n", pid);
  sleep(60);
  printf("system before.\n");
  system("./system_sub 123 abc xyz");
  sleep(60);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <system@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D25
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D15: pid = %d


tool: D25: system before.

tool: D6: ./system_sub 123 abc xyz

assistant: ```c
int main(void) {
  pid_t pid;
  pid = getpid();
  printf("pid = %d\n", pid);
  sleep(60);
  printf("system before.\n");
  system("./system_sub 123 abc xyz");
  sleep(60);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_oom_infinite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <setpgid@plt>
L14:
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  movb   $0xff,(%rax)
  jmp    L14
L20:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L14
```

assistant: ```c
void test_oom_infinite(char *pgids) {
  if (pgids != NULL) {
    int pgid = atoi(pgids);
    setpgid(0, pgid);
  }
  while (1) {
    char *p = (char *)malloc(4096);
    if (p != NULL) {
      p[0] = 0xFF;
    } else {
      exit(1);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_oom_infinite>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L0
  call   <atoi@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <setpgid@plt>
  jmp    L0
L19:
  movb   $0xff,(%rax)
L0:
  mov    $0x1000,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L0
```

assistant: ```c
void test_oom_infinite(char *pgids) {
  if (pgids != NULL) {
    int pgid = atoi(pgids);
    setpgid(0, pgid);
  }
  while (1) {
    char *p = (char *)malloc(4096);
    if (p != NULL) {
      p[0] = 0xFF;
    } else {
      exit(1);
    }
  }
}
```