ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cryptoshit_secrete_key>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %rbx,%r9
  push   %r12
  mov    %eax,%ecx
  mov    $0x1388,%r8d
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  call   <PKCS5_PBKDF2_HMAC_SHA1@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x1,%eax
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <secreteLibSSLError@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: fuck the patriarchy

assistant: ```c
__attribute__((visibility("default"))) void cryptoshit_secrete_key(char *password, void *keyOut, size_t keyOutSz) {
  int status = -1;
  const char *salt = "fuck the patriarchy";
  status = PKCS5_PBKDF2_HMAC_SHA1(password, -1, (unsigned char *)salt, strlen(salt), 5000, keyOutSz, keyOut);
  if (status != 1) {
    secreteLibSSLError();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_int(int *v1, int *v2) {
  int tmp = *v1;
  *v1 = *v2;
  *v2 = tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap_int(int *v1, int *v2) {
  int tmp = *v1;
  *v1 = *v2;
  *v2 = tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap_int(int *v1, int *v2) {
  int tmp = *v1;
  *v1 = *v2;
  *v2 = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swap_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap_int(int *v1, int *v2) {
  int tmp = *v1;
  *v1 = *v2;
  *v2 = tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L17:
  shlb   -0x5(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  movzbl -0x5(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x5(%rbp)
  shrb   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x7,-0x4(%rbp)
  jle    L17
  movzbl -0x5(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char encode(unsigned char base) {
  unsigned char result = 0;
  int i;
  for (i = 0; i < 8; i++) {
    result <<= 1;
    result |= base & 0x01;
    base >>= 1;
  }
  return ~result;
}
```
user: What is the c source code of the assembly code below:

```asm
<encode>:
  endbr64
  mov    $0x8,%edx
  mov    $0x0,%eax
L0:
  add    %eax,%eax
  mov    %edi,%ecx
  and    $0x1,%ecx
  or     %ecx,%eax
  shr    %dil
  sub    $0x1,%edx
  jne    L0
  not    %eax
  ret
```

assistant: ```c
unsigned char encode(unsigned char base) {
  unsigned char result = 0;
  int i;
  for (i = 0; i < 8; i++) {
    result <<= 1;
    result |= base & 0x01;
    base >>= 1;
  }
  return ~result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode>:
  endbr64
  mov    $0x8,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edi,%ecx
  add    %eax,%eax
  shr    %dil
  and    $0x1,%ecx
  or     %ecx,%eax
  sub    $0x1,%edx
  jne    L2
  not    %eax
  ret
```

assistant: ```c
unsigned char encode(unsigned char base) {
  unsigned char result = 0;
  int i;
  for (i = 0; i < 8; i++) {
    result <<= 1;
    result |= base & 0x01;
    base >>= 1;
  }
  return ~result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<encode>:
  endbr64
  mov    %edi,%eax
  lea    (%rdi,%rdi,1),%ecx
  shr    %al
  and    $0x2,%ecx
  and    $0x1,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x2,%cl
  add    %eax,%eax
  and    $0x1,%ecx
  or     %eax,%ecx
  mov    %edi,%eax
  shr    $0x3,%al
  add    %ecx,%ecx
  and    $0x1,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x4,%cl
  add    %eax,%eax
  and    $0x1,%ecx
  or     %eax,%ecx
  mov    %edi,%eax
  shr    $0x5,%al
  add    %ecx,%ecx
  and    $0x1,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x6,%cl
  add    %eax,%eax
  and    $0x1,%ecx
  or     %eax,%ecx
  mov    %edi,%eax
  add    %ecx,%ecx
  shr    $0x7,%al
  or     %ecx,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned char encode(unsigned char base) {
  unsigned char result = 0;
  int i;
  for (i = 0; i < 8; i++) {
    result <<= 1;
    result |= base & 0x01;
    base >>= 1;
  }
  return ~result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gcd_test@plt>
  mov    $0x0,%eax
  call   <trial_division_test@plt>
  mov    $0x0,%eax
  call   <pollard_rho_test@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string

tool: D7: All tests passed!


assistant: ```c
int main() {
  gcd_test();
  trial_division_test();
  pollard_rho_test();
  printf("All tests passed!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gcd_test@plt>
  mov    $0x0,%eax
  call   <trial_division_test@plt>
  mov    $0x0,%eax
  call   <pollard_rho_test@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: All tests passed!


assistant: ```c
int main() {
  gcd_test();
  trial_division_test();
  pollard_rho_test();
  printf("All tests passed!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gcd_test@plt>
  xor    %eax,%eax
  call   <trial_division_test@plt>
  xor    %eax,%eax
  call   <pollard_rho_test@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: All tests passed!


assistant: ```c
int main() {
  gcd_test();
  trial_division_test();
  pollard_rho_test();
  printf("All tests passed!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gcd_test@plt>
  xor    %eax,%eax
  call   <trial_division_test@plt>
  xor    %eax,%eax
  call   <pollard_rho_test@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: All tests passed!


assistant: ```c
int main() {
  gcd_test();
  trial_division_test();
  pollard_rho_test();
  printf("All tests passed!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<store_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <rill_store_ts@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <rill_store_ts@plt>
  cmp    %rax,%rbx
  jge    L4
  mov    $0x1,%eax
  jmp    L23
L4:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <rill_store_ts@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <rill_store_ts@plt>
  cmp    %rax,%rbx
  jle    L8
  mov    $0xffffffff,%eax
  jmp    L23
L8:
  mov    $0x0,%eax
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int store_cmp(const void *l, const void *r) {
  const struct rill_store *const *lhs = l;
  const struct rill_store *const *rhs = r;
  if (rill_store_ts(*lhs) < rill_store_ts(*rhs))
    return +1;
  if (rill_store_ts(*lhs) > rill_store_ts(*rhs))
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<store_cmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    (%rdi),%rdi
  call   <rill_store_ts@plt>
  mov    %rax,%r12
  mov    (%rbx),%rdi
  call   <rill_store_ts@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  cmp    %rdx,%r12
  jge    L17
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    0x0(%rbp),%rdi
  call   <rill_store_ts@plt>
  mov    %rax,%rbp
  mov    (%rbx),%rdi
  call   <rill_store_ts@plt>
  cmp    %rax,%rbp
  setg   %al
  movzbl %al,%eax
  neg    %eax
  jmp    L0
```

assistant: ```c
int store_cmp(const void *l, const void *r) {
  const struct rill_store *const *lhs = l;
  const struct rill_store *const *rhs = r;
  if (rill_store_ts(*lhs) < rill_store_ts(*rhs))
    return +1;
  if (rill_store_ts(*lhs) > rill_store_ts(*rhs))
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<store_cmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  mov    %rsi,%rbx
  call   <rill_store_ts@plt>
  mov    (%rbx),%rdi
  mov    %rax,%r12
  call   <rill_store_ts@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  cmp    %r8,%r12
  jl     L7
  mov    0x0(%rbp),%rdi
  call   <rill_store_ts@plt>
  mov    (%rbx),%rdi
  mov    %rax,%rbp
  call   <rill_store_ts@plt>
  cmp    %rax,%rbp
  setg   %al
  movzbl %al,%eax
  neg    %eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int store_cmp(const void *l, const void *r) {
  const struct rill_store *const *lhs = l;
  const struct rill_store *const *rhs = r;
  if (rill_store_ts(*lhs) < rill_store_ts(*rhs))
    return +1;
  if (rill_store_ts(*lhs) > rill_store_ts(*rhs))
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store_cmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  mov    %rsi,%rbx
  call   <rill_store_ts@plt>
  mov    (%rbx),%rdi
  mov    %rax,%r12
  call   <rill_store_ts@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  cmp    %r8,%r12
  jl     L5
  mov    0x0(%rbp),%rdi
  call   <rill_store_ts@plt>
  mov    (%rbx),%rdi
  mov    %rax,%rbp
  call   <rill_store_ts@plt>
  cmp    %rax,%rbp
  setg   %al
  movzbl %al,%eax
  neg    %eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int store_cmp(const void *l, const void *r) {
  const struct rill_store *const *lhs = l;
  const struct rill_store *const *rhs = r;
  if (rill_store_ts(*lhs) < rill_store_ts(*rhs))
    return +1;
  if (rill_store_ts(*lhs) > rill_store_ts(*rhs))
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L38:
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x4,-0x4(%rbp)
  jle    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0x4,-0x8(%rbp)
  jle    L38
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: %3d 

assistant: ```c
void Print(int a[][5]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%3d ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<Print>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x14(%r13),%rbp
  add    $0x78,%r13
  lea    D1(%rip),%r12
L10:
  lea    -0x14(%rbp),%rbx
L9:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x14,%rbp
  cmp    %r13,%rbp
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: %3d 

assistant: ```c
void Print(int a[][5]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%3d ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<Print>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0xa,%edi
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    0x14(%r13),%rbp
  add    $0x78,%r13
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
L2:
  lea    -0x14(%rbp),%rbx
L10:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0xa,%edi
  lea    0x14(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L2
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: %3d 

assistant: ```c
void Print(int a[][5]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%3d ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<Print>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0xa,%edi
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    0x14(%r13),%rbp
  add    $0x78,%r13
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
L15:
  lea    -0x14(%rbp),%rbx
L12:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L12
  mov    $0xa,%edi
  lea    0x14(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L15
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: %3d 

assistant: ```c
void Print(int a[][5]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%3d ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<euler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  cmpl   $0x2710,-0x34(%rbp)
  jg     L3
  mov    -0x40(%rbp),%rax
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x1c(%rbp)
  jmp    L26
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm4
  movsd  %xmm4,-0x48(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <f@plt>
  movsd  %xmm0,-0x58(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm5
  movsd  %xmm5,-0x60(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <f@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm3
  mulsd  -0x18(%rbp),%xmm3
  movapd %xmm3,%xmm0
  addsd  -0x60(%rbp),%xmm0
  mov    -0x38(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <f@plt>
  addsd  -0x58(%rbp),%xmm0
  mulsd  -0x50(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L12
  jmp    L1
L3:
  nop
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: f64
name: disassemble_data
arguments: tag: D7
data_type: byte[8]

tool: D6: 1

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
void euler(double a, double b, int n, double *w, int func) {
  double h = (b - a) / n;
  int i;
  if (n > 10000)
    return;
  w[0] = 1;
  for (i = 0; i < n; i++) {
    double ti = a + i * h;
    double tnext = a + (i + 1) * h;
    w[i + 1] = w[i] + h / 2 * (f(ti, w[i], func) + f(tnext, w[i] + h * f(ti, w[i], func), func));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<euler>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x20(%rsp)
  cmp    $0x2710,%edi
  jg     L25
  mov    %edi,%r15d
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    D14(%rip),%rax
  mov    %rax,(%rsi)
  test   %edi,%edi
  jle    L25
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  mulsd  D2(%rip),%xmm1
  movsd  %xmm1,0x28(%rsp)
  mov    $0x0,%ebp
L22:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  movsd  (%rsp),%xmm2
  mulsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  movsd  0x20(%rsp),%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x10(%rsp)
  add    $0x1,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm4,%xmm0
  movsd  %xmm0,0x18(%rsp)
  mov    (%rbx),%r13
  mov    %r12d,%edi
  movq   %r13,%xmm1
  movapd %xmm3,%xmm0
  call   <f@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    (%rbx),%r14
  mov    %r12d,%edi
  movq   %r14,%xmm1
  movsd  0x10(%rsp),%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  mulsd  (%rsp),%xmm1
  mov    %r12d,%edi
  movq   %r14,%xmm5
  addsd  %xmm5,%xmm1
  movsd  0x18(%rsp),%xmm0
  call   <f@plt>
  addsd  0x8(%rsp),%xmm0
  mulsd  0x28(%rsp),%xmm0
  movq   %r13,%xmm5
  addsd  %xmm5,%xmm0
  movsd  %xmm0,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %r15d,%ebp
  jne    L22
L25:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type: f64
name: parse_data
arguments: data_tag: D2
type: byte[8]

tool: D14: 1

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void euler(double a, double b, int n, double *w, int func) {
  double h = (b - a) / n;
  int i;
  if (n > 10000)
    return;
  w[0] = 1;
  for (i = 0; i < n; i++) {
    double ti = a + i * h;
    double tnext = a + (i + 1) * h;
    w[i + 1] = w[i] + h / 2 * (f(ti, w[i], func) + f(tnext, w[i] + h * f(ti, w[i], func), func));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<euler>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  movsd  %xmm0,0x40(%rsp)
  cmp    $0x2710,%edi
  jg     L36
  movsd  D9(%rip),%xmm4
  mov    %edi,%ebp
  mov    %rsi,%rbx
  movsd  %xmm4,(%rsi)
  test   %edi,%edi
  jle    L36
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  xor    %r13d,%r13d
  mov    %edx,%r12d
  cvtsi2sd %edi,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %r13d,%xmm2
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  mulsd  D16(%rip),%xmm1
  movsd  %xmm1,0x48(%rsp)
  jmp    L27
  xchg   %ax,%ax
L20:
  movsd  0x38(%rsp),%xmm2
  movapd %xmm0,%xmm4
L27:
  add    $0x1,%r13d
  movapd %xmm4,%xmm1
  mov    %r12d,%edi
  add    $0x8,%rbx
  movsd  0x8(%rsp),%xmm6
  movsd  0x40(%rsp),%xmm7
  movsd  %xmm4,0x28(%rsp)
  mulsd  %xmm6,%xmm2
  movapd %xmm6,%xmm3
  movapd %xmm2,%xmm5
  pxor   %xmm2,%xmm2
  cvtsi2sd %r13d,%xmm2
  addsd  %xmm7,%xmm5
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x20(%rsp)
  mulsd  %xmm2,%xmm3
  movsd  %xmm2,0x38(%rsp)
  addsd  %xmm7,%xmm3
  movsd  %xmm3,0x30(%rsp)
  call   <f@plt>
  movsd  0x20(%rsp),%xmm5
  movsd  -0x8(%rbx),%xmm1
  mov    %r12d,%edi
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm5,%xmm0
  movsd  %xmm1,0x18(%rsp)
  call   <f@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm1
  mov    %r12d,%edi
  movsd  0x30(%rsp),%xmm3
  addsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  call   <f@plt>
  addsd  0x10(%rsp),%xmm0
  mulsd  0x48(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm4
  addsd  %xmm4,%xmm0
  movsd  %xmm0,(%rbx)
  cmp    %ebp,%r13d
  jne    L20
L36:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: f64
name: unpack_data
arguments: data_tag: D16
type_infered: byte[8]

tool: D9: 1

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void euler(double a, double b, int n, double *w, int func) {
  double h = (b - a) / n;
  int i;
  if (n > 10000)
    return;
  w[0] = 1;
  for (i = 0; i < n; i++) {
    double ti = a + i * h;
    double tnext = a + (i + 1) * h;
    w[i + 1] = w[i] + h / 2 * (f(ti, w[i], func) + f(tnext, w[i] + h * f(ti, w[i], func), func));
  }
}
```