ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x80,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbp
  mov    $0x80,%ebx
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x1(%r13),%eax
  add    %ebx,%ebx
  test   %r13d,%r13d
  mov    %rbp,%rdi
  cmovns %eax,%ebx
  mov    %ebx,%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
L6:
  xor    %r14d,%r14d
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  cmp    %ebx,%r13d
  jae    L7
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %ebp,%ebp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *vstr(char *fmt, ...) {
  int n, size = 128;
  char *str;
  va_list ap;
  if ((str = malloc(size)) == NULL) {
    return NULL;
  }
  while (1) {
    va_start(ap, fmt);
    n = vsnprintf(str, size, fmt, ap);
    va_end(ap);
    if (n > -1 && n < size) {
      return str;
    }
    if (n > -1) {
      size = n + 1;
    } else {
      size *= 2;
    }
    if ((str = realloc(str, size)) == NULL) {
      return NULL;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <rotr@plt>
  mov    -0x28(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D12: %d

tool: D3: %d %d %d 


assistant: ```c
int main() {
  int a, b, c, n;
  int *pointer_a = &a, *pointer_b = &b, *pointer_c = &c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  rotr(pointer_a, pointer_b, pointer_c, n);
  printf("%d %d %d \n", a, b, c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%r13
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D14: %d

tool: D18: %d %d %d 


assistant: ```c
int main() {
  int a, b, c, n;
  int *pointer_a = &a, *pointer_b = &b, *pointer_c = &c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  rotr(pointer_a, pointer_b, pointer_c, n);
  printf("%d %d %d \n", a, b, c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  mov    %r12,%rsi
  lea    0x10(%rsp),%r14
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D11(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: string
name: disassemble_data
arguments: data_tag: D11
data_type: string

tool: D7: %d

tool: D11: %d %d %d 


assistant: ```c
int main() {
  int a, b, c, n;
  int *pointer_a = &a, *pointer_b = &b, *pointer_c = &c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  rotr(pointer_a, pointer_b, pointer_c, n);
  printf("%d %d %d \n", a, b, c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  mov    %r12,%rsi
  lea    0x10(%rsp),%r14
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D0(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D0
type: string

tool: D1: %d

tool: D0: %d %d %d 


assistant: ```c
int main() {
  int a, b, c, n;
  int *pointer_a = &a, *pointer_b = &b, *pointer_c = &c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  rotr(pointer_a, pointer_b, pointer_c, n);
  printf("%d %d %d \n", a, b, c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setup_ima_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <remove_ima_buffer@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int setup_ima_buffer(const struct kimage *image, void *fdt, int chosen_node) {
  remove_ima_buffer(fdt, chosen_node);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<setup_ima_buffer>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %edx,%esi
  call   <remove_ima_buffer@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int setup_ima_buffer(const struct kimage *image, void *fdt, int chosen_node) {
  remove_ima_buffer(fdt, chosen_node);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setup_ima_buffer>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %edx,%esi
  call   <remove_ima_buffer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int setup_ima_buffer(const struct kimage *image, void *fdt, int chosen_node) {
  remove_ima_buffer(fdt, chosen_node);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setup_ima_buffer>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %edx,%esi
  call   <remove_ima_buffer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int setup_ima_buffer(const struct kimage *image, void *fdt, int chosen_node) {
  remove_ima_buffer(fdt, chosen_node);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_terminal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <is_a_device@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  jmp    L12
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_tty@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
char *get_terminal(char *s) {
  char *devname;
  if (devname = is_a_device(s)) {
    return devname;
  }
  devname = get_tty(s);
  return devname;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_terminal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <is_a_device@plt>
  test   %rax,%rax
  je     L7
L6:
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  call   <get_tty@plt>
  jmp    L6
```

assistant: ```c
char *get_terminal(char *s) {
  char *devname;
  if (devname = is_a_device(s)) {
    return devname;
  }
  devname = get_tty(s);
  return devname;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_terminal>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <is_a_device@plt>
  test   %rax,%rax
  je     L3
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <get_tty@plt>
```

assistant: ```c
char *get_terminal(char *s) {
  char *devname;
  if (devname = is_a_device(s)) {
    return devname;
  }
  devname = get_tty(s);
  return devname;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_terminal>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <is_a_device@plt>
  test   %rax,%rax
  je     L5
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <get_tty@plt>
```

assistant: ```c
char *get_terminal(char *s) {
  char *devname;
  if (devname = is_a_device(s)) {
    return devname;
  }
  devname = get_tty(s);
  return devname;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<voltea_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x9,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L13
L1:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x20(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  movzbl (%rbx),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x20(%rbp)
L13:
  cmpq   $0x0,-0x20(%rbp)
  jns    L1
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: %s


assistant: ```c
char *voltea_string(char *s) {
  long int i;
  char *intermediate;
  intermediate = malloc(sizeof(strlen(s)) + 1);
  for (i = strlen(s); 0 <= i; i--) {
    *(intermediate + (strlen(s) - i)) = *(s + (i - 1));
  }
  intermediate[strlen(s)] = '\0';
  printf("%s\n", intermediate);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<voltea_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x9,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movzbl -0x1(%rbp,%rbx,1),%edx
  sub    %rbx,%rax
  mov    %dl,(%r12,%rax,1)
  sub    $0x1,%rbx
  jns    L4
  mov    %rbp,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: %s


assistant: ```c
char *voltea_string(char *s) {
  long int i;
  char *intermediate;
  intermediate = malloc(sizeof(strlen(s)) + 1);
  for (i = strlen(s); 0 <= i; i--) {
    *(intermediate + (strlen(s) - i)) = *(s + (i - 1));
  }
  intermediate[strlen(s)] = '\0';
  printf("%s\n", intermediate);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<voltea_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x9,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  jmp    L17
  nopl   (%rax)
L11:
  call   <strlen@plt>
L17:
  movzbl -0x1(%r12,%rbx,1),%edx
  sub    %rbx,%rax
  sub    $0x1,%rbx
  mov    %r12,%rdi
  mov    %dl,0x0(%rbp,%rax,1)
  cmp    $0xffffffffffffffff,%rbx
  jne    L11
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  movb   $0x0,0x0(%rbp,%rax,1)
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %s


assistant: ```c
char *voltea_string(char *s) {
  long int i;
  char *intermediate;
  intermediate = malloc(sizeof(strlen(s)) + 1);
  for (i = strlen(s); 0 <= i; i--) {
    *(intermediate + (strlen(s) - i)) = *(s + (i - 1));
  }
  intermediate[strlen(s)] = '\0';
  printf("%s\n", intermediate);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<voltea_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x9,%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  movzbl -0x1(%rbp,%rax,1),%edx
  mov    %dl,(%r12)
  test   %rax,%rax
  je     L4
  lea    -0x1(%rax),%rbx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movzbl -0x1(%rbp,%rbx,1),%edx
  sub    %rbx,%rax
  mov    %dl,(%r12,%rax,1)
  sub    $0x1,%rbx
  jae    L19
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  movb   $0x0,(%r12,%rax,1)
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: %s


assistant: ```c
char *voltea_string(char *s) {
  long int i;
  char *intermediate;
  intermediate = malloc(sizeof(strlen(s)) + 1);
  for (i = strlen(s); 0 <= i; i--) {
    *(intermediate + (strlen(s) - i)) = *(s + (i - 1));
  }
  intermediate[strlen(s)] = '\0';
  printf("%s\n", intermediate);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string

tool: D19: %d

tool: D17: %d
%d


assistant: ```c
int main() {
  int n, square, cube;
  scanf("%d", &n);
  square = n * n;
  cube = square * n;
  printf("%d\n%d\n", square, cube);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string

tool: D10: %d

tool: D19: %d
%d


assistant: ```c
int main() {
  int n, square, cube;
  scanf("%d", &n);
  square = n * n;
  cube = square * n;
  printf("%d\n%d\n", square, cube);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    D15(%rip),%rdi
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string

tool: D12: %d

tool: D15: %d
%d


assistant: ```c
int main() {
  int n, square, cube;
  scanf("%d", &n);
  square = n * n;
  cube = square * n;
  printf("%d\n%d\n", square, cube);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    D17(%rip),%rdi
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D6: %d

tool: D17: %d
%d


assistant: ```c
int main() {
  int n, square, cube;
  scanf("%d", &n);
  square = n * n;
  cube = square * n;
  printf("%d\n%d\n", square, cube);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cheat_printed_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  cltq
  leave
  ret
```

assistant: ```c
__attribute__((__unused__)) size_t cheat_printed_length(char const *const format, va_list list) {
  va_list another_list;
  va_copy(another_list, list);
  return (size_t)vsnprintf(NULL, 0, format, another_list);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cheat_printed_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_copy@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  cltq
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__unused__)) size_t cheat_printed_length(char const *const format, va_list list) {
  va_list another_list;
  va_copy(another_list, list);
  return (size_t)vsnprintf(NULL, 0, format, another_list);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cheat_printed_length>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <va_copy@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  add    $0x8,%rsp
  cltq
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((__unused__)) size_t cheat_printed_length(char const *const format, va_list list) {
  va_list another_list;
  va_copy(another_list, list);
  return (size_t)vsnprintf(NULL, 0, format, another_list);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cheat_printed_length>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <va_copy@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  add    $0x8,%rsp
  cltq
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((__unused__)) size_t cheat_printed_length(char const *const format, va_list list) {
  va_list another_list;
  va_copy(another_list, list);
  return (size_t)vsnprintf(NULL, 0, format, another_list);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove_good2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rcx
  lea    -0x60(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void memmove_good2() {
  int arr1[10];
  int arr2[20];
  memmove(arr2, arr1, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memmove_good2>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x30(%rsp),%rdi
  mov    $0x0,%edx
  call   <memmove@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x98,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memmove_good2() {
  int arr1[10];
  int arr2[20];
  memmove(arr2, arr1, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memmove_good2>:
  endbr64
  sub    $0x98,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x30(%rsp),%rdi
  call   <memmove@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x98,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memmove_good2() {
  int arr1[10];
  int arr2[20];
  memmove(arr2, arr1, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memmove_good2>:
  endbr64
  sub    $0x98,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x30(%rsp),%rdi
  call   <memmove@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memmove_good2() {
  int arr1[10];
  int arr2[20];
  memmove(arr2, arr1, 0);
}
```