ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<searchInsertMain>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  mov    $0x4,%esi
  push   %rbp
  lea    D2(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%r12
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x8(%rsp)
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: %d


assistant: ```c
void searchInsertMain(void) {
  int nums[] = {1, 3, 5, 6};
  int numsSize = sizeof(nums) / sizeof(nums[0]);
  printf("%d\n", searchInsert(nums, numsSize, 4));
  printf("%d\n", searchInsert(nums, numsSize, 5));
  printf("%d\n", searchInsert(nums, numsSize, 2));
  printf("%d\n", searchInsert(nums, numsSize, 7));
  printf("%d\n", searchInsert(nums, numsSize, 0));
}
```
user: What is the c source code of the assembly code below?

```asm
<searchInsertMain>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  mov    $0x4,%esi
  push   %rbp
  lea    D0(%rip),%rbp
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  movaps %xmm0,(%rsp)
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: byte[16]

tool: D0: %d


tool: {"D2": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
void searchInsertMain(void) {
  int nums[] = {1, 3, 5, 6};
  int numsSize = sizeof(nums) / sizeof(nums[0]);
  printf("%d\n", searchInsert(nums, numsSize, 4));
  printf("%d\n", searchInsert(nums, numsSize, 5));
  printf("%d\n", searchInsert(nums, numsSize, 2));
  printf("%d\n", searchInsert(nums, numsSize, 7));
  printf("%d\n", searchInsert(nums, numsSize, 0));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L18:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putc@plt>
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s)
    putc(*s++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L0:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L5:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s)
    putc(*s++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L0
L3:
  call   <putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L0:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s)
    putc(*s++);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L15:
  call   <putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L7:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s)
    putc(*s++);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getRandomHexChars>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rsi
  lea    D18(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L94
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L60
L94:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,0xc(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  cmp    $0x3,%ebp
  ja     L21
L32:
  test   %ebp,%ebp
  je     L127
L38:
  mov    %rbx,%r13
  lea    -0x1(%rbp),%r14d
  add    %rbx,%r14
L41:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    %r13,%rax
  xor    %dl,0x0(%r13)
  add    $0x1,%r13
  cmp    %rax,%r14
  jne    L41
L7:
  mov    $0x0,%eax
  lea    D27(%rip),%rcx
L39:
  movzbl (%rbx,%rax,1),%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebp
  ja     L39
L127:
  test   %r12,%r12
  je     L123
L54:
  mov    %r12,%rdi
  call   <fclose@plt>
L123:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  lea    0x14(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    0x4(%rbx),%rdi
  lea    -0x4(%rbp),%eax
  cmp    $0x3,%eax
  jbe    L32
  lea    0x10(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x8(%rbx),%rdi
  lea    -0x8(%rbp),%eax
  cmp    $0x3,%eax
  jbe    L38
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  jmp    L38
L60:
  test   %ebp,%ebp
  jne    L7
  jmp    L54
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string

tool: D26: r

tool: D18: /dev/urandom

tool: D27: 0123456789abcdef

assistant: ```c
void getRandomHexChars(char *p, unsigned int len) {
  FILE *fp = fopen("/dev/urandom", "r");
  char *charset = "0123456789abcdef";
  unsigned int j;
  if (fp == NULL || fread(p, len, 1, fp) == 0) {
    char *x = p;
    unsigned int l = len;
    struct timeval tv;
    pid_t pid = getpid();
    gettimeofday(&tv, NULL);
    if (l >= sizeof(tv.tv_usec)) {
      memcpy(x, &tv.tv_usec, sizeof(tv.tv_usec));
      l -= sizeof(tv.tv_usec);
      x += sizeof(tv.tv_usec);
    }
    if (l >= sizeof(tv.tv_sec)) {
      memcpy(x, &tv.tv_sec, sizeof(tv.tv_sec));
      l -= sizeof(tv.tv_sec);
      x += sizeof(tv.tv_sec);
    }
    if (l >= sizeof(pid)) {
      memcpy(x, &pid, sizeof(pid));
      l -= sizeof(pid);
      x += sizeof(pid);
    }
    for (j = 0; j < len; j++)
      p[j] ^= rand();
  }
  for (j = 0; j < len; j++)
    p[j] = charset[p[j] & 0x0F];
  if (fp)
    fclose(fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timeStamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rcx
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    D27(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %F %T

assistant: ```c
char *timeStamp() {
  static char buf[32];
  struct timeval now;
  struct tm tmp;
  gettimeofday(&now, NULL);
  localtime_r(&now.tv_sec, &tmp);
  strftime(buf, sizeof(buf), "%F %T", &tmp);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timeStamp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  mov    %rbx,%rcx
  lea    D11(%rip),%rdx
  mov    $0x20,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string

tool: D11: %F %T

assistant: ```c
char *timeStamp() {
  static char buf[32];
  struct timeval now;
  struct tm tmp;
  gettimeofday(&now, NULL);
  localtime_r(&now.tv_sec, &tmp);
  strftime(buf, sizeof(buf), "%F %T", &tmp);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timeStamp>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  mov    %r12,%rcx
  mov    $0x20,%esi
  lea    D9(%rip),%r12
  lea    D13(%rip),%rdx
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D13: %F %T

assistant: ```c
char *timeStamp() {
  static char buf[32];
  struct timeval now;
  struct tm tmp;
  gettimeofday(&now, NULL);
  localtime_r(&now.tv_sec, &tmp);
  strftime(buf, sizeof(buf), "%F %T", &tmp);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<timeStamp>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  mov    %r12,%rcx
  mov    $0x20,%esi
  lea    D8(%rip),%r12
  lea    D4(%rip),%rdx
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: %F %T

assistant: ```c
char *timeStamp() {
  static char buf[32];
  struct timeval now;
  struct tm tmp;
  gettimeofday(&now, NULL);
  localtime_r(&now.tv_sec, &tmp);
  strftime(buf, sizeof(buf), "%F %T", &tmp);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_leap_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L37
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L27
L37:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L12
L27:
  mov    $0x1,%eax
  jmp    L0
L12:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t is_leap_year(uint16_t y) {
  if (((y % 4 == 0) && (y % 100 != 0)) || (y % 400 == 0))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_leap_year>:
  endbr64
  test   $0x3,%dil
  jne    L7
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  mov    $0x1,%edx
  cmp    %eax,%edi
  jne    L16
L7:
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edi
  sete   %dl
  movzbl %dl,%edx
L16:
  mov    %edx,%eax
  ret
```

assistant: ```c
uint8_t is_leap_year(uint16_t y) {
  if (((y % 4 == 0) && (y % 100 != 0)) || (y % 400 == 0))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_leap_year>:
  endbr64
  test   $0x3,%dil
  jne    L10
  imul   $0xc28f5c29,%edi,%eax
  mov    $0x1,%r8d
  add    $0x51eb850,%eax
  ror    $0x2,%eax
  cmp    $0x28f5c28,%eax
  ja     L15
L10:
  imul   $0xc28f5c29,%edi,%edi
  xor    %r8d,%r8d
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70a,%edi
  setbe  %r8b
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint8_t is_leap_year(uint16_t y) {
  if (((y % 4 == 0) && (y % 100 != 0)) || (y % 400 == 0))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_leap_year>:
  endbr64
  test   $0x3,%dil
  jne    L11
  imul   $0xc28f5c29,%edi,%eax
  mov    $0x1,%r8d
  add    $0x51eb850,%eax
  ror    $0x2,%eax
  cmp    $0x28f5c28,%eax
  ja     L8
L11:
  imul   $0xc28f5c29,%edi,%edi
  xor    %r8d,%r8d
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70a,%edi
  setbe  %r8b
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint8_t is_leap_year(uint16_t y) {
  if (((y % 4 == 0) && (y % 100 != 0)) || (y % 400 == 0))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<deinterleave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x7,-0x4(%rbp)
  jmp    L16
L14:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void deinterleave(uint16_t interleaved, uint8_t *upper, uint8_t *lower) {
  *upper = *lower = 0;
  for (int i = 7; i >= 0; i--) {
    *upper = (*upper << 1) + ((interleaved >> (i * 2 + 1)) & 0x01);
    *lower = (*lower << 1) + ((interleaved >> (i * 2)) & 0x01);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deinterleave>:
  endbr64
  movl   $0x0,(%rdx)
  movl   $0x0,(%rsi)
  mov    $0xf,%eax
L0:
  mov    (%rsi),%r8d
  mov    %edi,%r9d
  mov    %eax,%ecx
  sar    %cl,%r9d
  mov    %r9d,%ecx
  and    $0x1,%ecx
  lea    (%rcx,%r8,2),%ecx
  mov    %ecx,(%rsi)
  lea    -0x1(%rax),%ecx
  mov    %edi,%r10d
  sar    %cl,%r10d
  mov    %r10d,%ecx
  and    $0x1,%ecx
  mov    (%rdx),%r8d
  lea    (%rcx,%r8,2),%ecx
  mov    %ecx,(%rdx)
  sub    $0x2,%eax
  cmp    $0xffffffff,%eax
  jne    L0
  ret
```

assistant: ```c
void deinterleave(uint16_t interleaved, uint8_t *upper, uint8_t *lower) {
  *upper = *lower = 0;
  for (int i = 7; i >= 0; i--) {
    *upper = (*upper << 1) + ((interleaved >> (i * 2 + 1)) & 0x01);
    *lower = (*lower << 1) + ((interleaved >> (i * 2)) & 0x01);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<deinterleave>:
  endbr64
  movl   $0x0,(%rdx)
  mov    $0xf,%eax
  xor    %r8d,%r8d
  jmp    L11
  nopl   0x0(%rax)
L0:
  mov    (%rsi),%r8d
L11:
  mov    %eax,%ecx
  mov    %edi,%r9d
  mov    %edi,%r10d
  sar    %cl,%r9d
  mov    %r9d,%ecx
  and    $0x1,%ecx
  lea    (%rcx,%r8,2),%ecx
  mov    %ecx,(%rsi)
  lea    -0x1(%rax),%ecx
  mov    (%rdx),%r8d
  sub    $0x2,%eax
  sar    %cl,%r10d
  mov    %r10d,%ecx
  and    $0x1,%ecx
  lea    (%rcx,%r8,2),%ecx
  mov    %ecx,(%rdx)
  cmp    $0xffffffff,%eax
  jne    L0
  ret
```

assistant: ```c
void deinterleave(uint16_t interleaved, uint8_t *upper, uint8_t *lower) {
  *upper = *lower = 0;
  for (int i = 7; i >= 0; i--) {
    *upper = (*upper << 1) + ((interleaved >> (i * 2 + 1)) & 0x01);
    *lower = (*lower << 1) + ((interleaved >> (i * 2)) & 0x01);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<deinterleave>:
  endbr64
  mov    %rsi,%rcx
  mov    %edi,%esi
  mov    %edi,%eax
  movl   $0x0,(%rdx)
  sar    $0xf,%esi
  and    $0x1,%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0xe,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  sar    $0xd,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0xc,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  sar    $0xb,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0xa,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  sar    $0x9,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0x8,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  sar    $0x7,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0x6,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  sar    $0x5,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0x4,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  sar    $0x3,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    %eax,%esi
  mov    (%rdx),%edi
  sar    $0x2,%esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  mov    (%rcx),%edi
  and    $0x1,%eax
  sar    %esi
  and    $0x1,%esi
  lea    (%rsi,%rdi,2),%esi
  mov    %esi,(%rcx)
  mov    (%rdx),%ecx
  lea    (%rax,%rcx,2),%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void deinterleave(uint16_t interleaved, uint8_t *upper, uint8_t *lower) {
  *upper = *lower = 0;
  for (int i = 7; i >= 0; i--) {
    *upper = (*upper << 1) + ((interleaved >> (i * 2 + 1)) & 0x01);
    *lower = (*lower << 1) + ((interleaved >> (i * 2)) & 0x01);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<USBNumEndpointsGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70000000,%eax
  test   %rax,%rax
  je     L1
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10000000,%rax
  je     L1
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10010000,%rax
  jne    L31
L1:
  mov    $0x0,%eax
  jmp    L8
L31:
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10030000,%rax
  jne    L100
  mov    $0x3,%eax
  jmp    L8
L100:
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10040000,%rax
  je     L6
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10060000,%rax
  jne    L92
L6:
  mov    $0xf,%eax
  jmp    L8
L92:
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10050000,%rax
  jne    L98
  mov    $0x7,%eax
  jmp    L8
L98:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long USBNumEndpointsGet(unsigned long ulBase) {
  if (((((*((volatile unsigned long *)(0x400FE000))) & 0x70000000) == 0x00000000) || (((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00000000))) || (((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00010000))) {
    return (0);
  } else if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00030000))) {
    return (3);
  } else if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00040000)) || (((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00060000))) {
    return (15);
  } else if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00050000))) {
    return (7);
  } else {
    return (0);
  }
}
```