ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<XawInitializeWidgetSet>:
  endbr64
  cmpl   $0x0,D25(%rip)
  jne    L6
  ret
L6:
  sub    $0x8,%rsp
  movl   $0x0,D25(%rip)
  mov    D24(%rip),%rax
  mov    (%rax),%edi
  call   <XtInitializeWidgetClass@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void XawInitializeWidgetSet() {
  static int firsttime = 1;
  if (firsttime) {
    firsttime = 0;
    XtInitializeWidgetClass(vendorShellWidgetClass);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<XawInitializeWidgetSet>:
  endbr64
  mov    D14(%rip),%eax
  test   %eax,%eax
  jne    L4
  ret
  nop
L4:
  mov    D19(%rip),%rax
  movl   $0x0,D14(%rip)
  mov    (%rax),%edi
  jmp    1050 <XtInitializeWidgetClass@plt>
```

assistant: ```c
void XawInitializeWidgetSet() {
  static int firsttime = 1;
  if (firsttime) {
    firsttime = 0;
    XtInitializeWidgetClass(vendorShellWidgetClass);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<XawInitializeWidgetSet>:
  endbr64
  mov    D5(%rip),%eax
  test   %eax,%eax
  jne    L6
  ret
  nop
L6:
  mov    D10(%rip),%rax
  movl   $0x0,D5(%rip)
  mov    (%rax),%edi
  jmp    1050 <XtInitializeWidgetClass@plt>
```

assistant: ```c
void XawInitializeWidgetSet() {
  static int firsttime = 1;
  if (firsttime) {
    firsttime = 0;
    XtInitializeWidgetClass(vendorShellWidgetClass);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <_prevent_memset_lto@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void test_func(void) {
  char buf[16];
  void *buffer_to_confuse_compiler = buf;
  memset(buffer_to_confuse_compiler, 0, 32);
  _prevent_memset_lto(buf, 0, 32);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_func>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <_prevent_memset_lto@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_func(void) {
  char buf[16];
  void *buffer_to_confuse_compiler = buf;
  memset(buffer_to_confuse_compiler, 0, 32);
  _prevent_memset_lto(buf, 0, 32);
}
```
user: What is the c source code of the assembly code below:

```asm
<test_func>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x20,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  mov    $0x20,%edx
  mov    %rbp,%rdi
  call   <_prevent_memset_lto@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_func(void) {
  char buf[16];
  void *buffer_to_confuse_compiler = buf;
  memset(buffer_to_confuse_compiler, 0, 32);
  _prevent_memset_lto(buf, 0, 32);
}
```
user: What is the c source code of the assembly code below:

```asm
<Cyc_Unify_unify_effect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Cyc_Tcutil_normalize_effect@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Cyc_Tcutil_normalize_effect@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L22
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L74
  mov    $0x1,%eax
  jmp    L39
L22:
  nop
  jmp    L65
L74:
  nop
L65:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L68
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L23
  mov    $0x1,%eax
  jmp    L39
L68:
  nop
  jmp    L47
L23:
  nop
L47:
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int Cyc_Unify_unify_effect(void *e1, void *e2) {
  int _T0;
  int _T1;
  int _T2;
  int _T3;
  e1 = Cyc_Tcutil_normalize_effect(e1);
  e2 = Cyc_Tcutil_normalize_effect(e2);
  _T0 = Cyc_Tcutil_subset_effect(0, e1, e2);
  if (!_T0)
    goto _TL7C;
  _T1 = Cyc_Tcutil_subset_effect(0, e2, e1);
  if (!_T1)
    goto _TL7C;
  return 1;
_TL7C:
  _T2 = Cyc_Tcutil_subset_effect(1, e1, e2);
  if (!_T2)
    goto _TL7E;
  _T3 = Cyc_Tcutil_subset_effect(1, e2, e1);
  if (!_T3)
    goto _TL7E;
  return 1;
_TL7E:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cyc_Unify_unify_effect>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <Cyc_Tcutil_normalize_effect@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <Cyc_Tcutil_normalize_effect@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  jne    L32
L24:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  jne    L46
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L43
  jmp    L24
L46:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L43
```

assistant: ```c
int Cyc_Unify_unify_effect(void *e1, void *e2) {
  int _T0;
  int _T1;
  int _T2;
  int _T3;
  e1 = Cyc_Tcutil_normalize_effect(e1);
  e2 = Cyc_Tcutil_normalize_effect(e2);
  _T0 = Cyc_Tcutil_subset_effect(0, e1, e2);
  if (!_T0)
    goto _TL7C;
  _T1 = Cyc_Tcutil_subset_effect(0, e2, e1);
  if (!_T1)
    goto _TL7C;
  return 1;
_TL7C:
  _T2 = Cyc_Tcutil_subset_effect(1, e1, e2);
  if (!_T2)
    goto _TL7E;
  _T3 = Cyc_Tcutil_subset_effect(1, e2, e1);
  if (!_T3)
    goto _TL7E;
  return 1;
_TL7E:
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Cyc_Unify_unify_effect>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <Cyc_Tcutil_normalize_effect@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <Cyc_Tcutil_normalize_effect@plt>
  xor    %edi,%edi
  mov    %r12,%rsi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  jne    L11
L8:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  jne    L16
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L16:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L11:
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  je     L8
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Cyc_Unify_unify_effect(void *e1, void *e2) {
  int _T0;
  int _T1;
  int _T2;
  int _T3;
  e1 = Cyc_Tcutil_normalize_effect(e1);
  e2 = Cyc_Tcutil_normalize_effect(e2);
  _T0 = Cyc_Tcutil_subset_effect(0, e1, e2);
  if (!_T0)
    goto _TL7C;
  _T1 = Cyc_Tcutil_subset_effect(0, e2, e1);
  if (!_T1)
    goto _TL7C;
  return 1;
_TL7C:
  _T2 = Cyc_Tcutil_subset_effect(1, e1, e2);
  if (!_T2)
    goto _TL7E;
  _T3 = Cyc_Tcutil_subset_effect(1, e2, e1);
  if (!_T3)
    goto _TL7E;
  return 1;
_TL7E:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cyc_Unify_unify_effect>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <Cyc_Tcutil_normalize_effect@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <Cyc_Tcutil_normalize_effect@plt>
  xor    %edi,%edi
  mov    %r12,%rsi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  jne    L25
L16:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  jne    L7
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L7:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L25:
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <Cyc_Tcutil_subset_effect@plt>
  test   %eax,%eax
  je     L16
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Cyc_Unify_unify_effect(void *e1, void *e2) {
  int _T0;
  int _T1;
  int _T2;
  int _T3;
  e1 = Cyc_Tcutil_normalize_effect(e1);
  e2 = Cyc_Tcutil_normalize_effect(e2);
  _T0 = Cyc_Tcutil_subset_effect(0, e1, e2);
  if (!_T0)
    goto _TL7C;
  _T1 = Cyc_Tcutil_subset_effect(0, e2, e1);
  if (!_T1)
    goto _TL7C;
  return 1;
_TL7C:
  _T2 = Cyc_Tcutil_subset_effect(1, e1, e2);
  if (!_T2)
    goto _TL7E;
  _T3 = Cyc_Tcutil_subset_effect(1, e2, e1);
  if (!_T3)
    goto _TL7E;
  return 1;
_TL7E:
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UPnPRenderingControl_SetVolumeDB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %ax,-0x10(%rbp)
  movswl -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UPnPResponse_RenderingControl_SetVolumeDB@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);


assistant: ```c
void UPnPRenderingControl_SetVolumeDB(void *upnptoken, unsigned int InstanceID, char *Channel, short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolumeDB(upnptoken);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UPnPRenderingControl_SetVolumeDB>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movswl %cx,%ecx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <UPnPResponse_RenderingControl_SetVolumeDB@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);


assistant: ```c
void UPnPRenderingControl_SetVolumeDB(void *upnptoken, unsigned int InstanceID, char *Channel, short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolumeDB(upnptoken);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UPnPRenderingControl_SetVolumeDB>:
  endbr64
  push   %rbp
  movswl %cx,%ecx
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UPnPResponse_RenderingControl_SetVolumeDB@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);


assistant: ```c
void UPnPRenderingControl_SetVolumeDB(void *upnptoken, unsigned int InstanceID, char *Channel, short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolumeDB(upnptoken);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UPnPRenderingControl_SetVolumeDB>:
  endbr64
  push   %rbp
  movswl %cx,%ecx
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UPnPResponse_RenderingControl_SetVolumeDB@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);


assistant: ```c
void UPnPRenderingControl_SetVolumeDB(void *upnptoken, unsigned int InstanceID, char *Channel, short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolumeDB(%u,%s,%d);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolumeDB(upnptoken);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_03>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x4,-0x10(%rbp)
  jle    L9
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  jmp    L7
L9:
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int test_03(int a, int b, int c, int d) {
  if (d > 4)
    return a + b + 1;
  else
    return a + c + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_03>:
  endbr64
  lea    0x1(%rdi,%rsi,1),%esi
  lea    0x1(%rdi,%rdx,1),%eax
  cmp    $0x5,%ecx
  cmovge %esi,%eax
  ret
```

assistant: ```c
int test_03(int a, int b, int c, int d) {
  if (d > 4)
    return a + b + 1;
  else
    return a + c + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_03>:
  endbr64
  lea    0x1(%rdi,%rsi,1),%esi
  lea    0x1(%rdi,%rdx,1),%eax
  cmp    $0x5,%ecx
  cmovge %esi,%eax
  ret
```

assistant: ```c
int test_03(int a, int b, int c, int d) {
  if (d > 4)
    return a + b + 1;
  else
    return a + c + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  a = 5;
  int b;
  b = 2;
  return a / b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  a = 5;
  int b;
  b = 2;
  return a / b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  a = 5;
  int b;
  b = 2;
  return a / b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  a = 5;
  int b;
  b = 2;
  return a / b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tai__parse_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L118
L99:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  imul   $0xa,%eax,%eax
  jno    L11
  mov    $0x1,%edx
L11:
  mov    %eax,-0x14(%rbp)
  mov    %edx,%eax
  and    $0x1,%eax
  test   %al,%al
  je     L78
  mov    $0x0,%eax
  jmp    L67
L78:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    $0x0,%ecx
  add    %edx,%eax
  jno    L122
  mov    $0x1,%ecx
L122:
  mov    %eax,-0x14(%rbp)
  mov    %ecx,%eax
  and    $0x1,%eax
  test   %al,%al
  je     L88
  mov    $0x0,%eax
  jmp    L67
L88:
  addq   $0x1,-0x10(%rbp)
L118:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L127
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L99
L127:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L42
  mov    $0x0,%eax
  jmp    L67
L42:
  cmpq   $0x0,-0x30(%rbp)
  je     L68
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L68:
  mov    -0x10(%rbp),%rax
L67:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
const char *tai__parse_number(const char *s, int *i) {
  int n = 0;
  const char *p;
  p = s;
  while ('0' <= *p && *p <= '9') {
    if (__builtin_mul_overflow(n, 10, &n))
      return 0;
    if (__builtin_add_overflow(n, *p - '0', &n))
      return 0;
    ++p;
  }
  if (p == s)
    return 0;
  if (i)
    *i = n;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tai__parse_number>:
  endbr64
  mov    %rdi,%r8
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L22
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %rdi,%rcx
L77:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  ja     L31
  imul   $0xa,%eax,%eax
  jo     L80
  movsbl %dl,%edx
  sub    $0x30,%edx
  add    %edx,%eax
  jno    L77
  mov    $0x0,%ecx
  jmp    L2
L31:
  cmp    %rcx,%r8
  je     L10
  test   %rsi,%rsi
  je     L2
  mov    %eax,(%rsi)
  jmp    L2
L22:
  mov    $0x0,%ecx
  jmp    L2
L80:
  mov    $0x0,%ecx
L2:
  mov    %rcx,%rax
  ret
L10:
  mov    $0x0,%ecx
  jmp    L2
```

assistant: ```c
const char *tai__parse_number(const char *s, int *i) {
  int n = 0;
  const char *p;
  p = s;
  while ('0' <= *p && *p <= '9') {
    if (__builtin_mul_overflow(n, 10, &n))
      return 0;
    if (__builtin_add_overflow(n, *p - '0', &n))
      return 0;
    ++p;
  }
  if (p == s)
    return 0;
  if (i)
    *i = n;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tai__parse_number>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L8
  movsbl %al,%eax
  mov    %rdi,%r8
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L49:
  imul   $0xa,%eax,%eax
  jo     L8
  movsbl %dl,%edx
  add    %edx,%eax
  jo     L8
L44:
  movzbl 0x1(%r8),%ecx
  add    $0x1,%r8
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L49
  cmp    %r8,%rdi
  je     L8
  test   %rsi,%rsi
  je     L14
  mov    %eax,(%rsi)
L14:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L8:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *tai__parse_number(const char *s, int *i) {
  int n = 0;
  const char *p;
  p = s;
  while ('0' <= *p && *p <= '9') {
    if (__builtin_mul_overflow(n, 10, &n))
      return 0;
    if (__builtin_add_overflow(n, *p - '0', &n))
      return 0;
    ++p;
  }
  if (p == s)
    return 0;
  if (i)
    *i = n;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tai__parse_number>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L42
  movsbl %al,%eax
  mov    %rdi,%r8
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L56:
  imul   $0xa,%eax,%eax
  jo     L42
  movsbl %dl,%edx
  add    %edx,%eax
  jo     L42
L15:
  movzbl 0x1(%r8),%ecx
  add    $0x1,%r8
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L56
  cmp    %r8,%rdi
  je     L42
  test   %rsi,%rsi
  je     L40
  mov    %eax,(%rsi)
L40:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L42:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *tai__parse_number(const char *s, int *i) {
  int n = 0;
  const char *p;
  p = s;
  while ('0' <= *p && *p <= '9') {
    if (__builtin_mul_overflow(n, 10, &n))
      return 0;
    if (__builtin_add_overflow(n, *p - '0', &n))
      return 0;
    ++p;
  }
  if (p == s)
    return 0;
  if (i)
    *i = n;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<r_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L25
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <r_malloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L25
L35:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

assistant: ```c
char *r_strdup(str) const char *str;
{
  int len;
  char *nstr;
  if (!str)
    return (0);
  len = strlen(str) + 1;
  if (!(nstr = r_malloc(0, len)))
    return (0);
  memcpy(nstr, str, len);
  return (nstr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<r_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L12
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  mov    %ebp,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <r_malloc@plt>
  mov    $0x0,%r12d
  test   %eax,%eax
  je     L6
  movslq %eax,%r12
  movslq %ebp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %rdi,%r12
  jmp    L6
```

assistant: ```c
char *r_strdup(str) const char *str;
{
  int len;
  char *nstr;
  if (!str)
    return (0);
  len = strlen(str) + 1;
  if (!(nstr = r_malloc(0, len)))
    return (0);
  memcpy(nstr, str, len);
  return (nstr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<r_strdup>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  lea    0x1(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <r_malloc@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L1
  movslq %eax,%r8
  movslq %ebx,%rdx
  mov    %rbp,%rsi
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    %rax,%r8
L1:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *r_strdup(str) const char *str;
{
  int len;
  char *nstr;
  if (!str)
    return (0);
  len = strlen(str) + 1;
  if (!(nstr = r_malloc(0, len)))
    return (0);
  memcpy(nstr, str, len);
  return (nstr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<r_strdup>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  lea    0x1(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <r_malloc@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L5
  movslq %eax,%r8
  movslq %ebx,%rdx
  mov    %rbp,%rsi
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    %rax,%r8
L5:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *r_strdup(str) const char *str;
{
  int len;
  char *nstr;
  if (!str)
    return (0);
  len = strlen(str) + 1;
  if (!(nstr = r_malloc(0, len)))
    return (0);
  memcpy(nstr, str, len);
  return (nstr);
}
```