ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tdis_cdfc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L26
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  call   <cumt@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void tdis_cdfc(int n, double a, double *x, double *array) {
  int i;
  double p, q;
  for (i = 0; i < n; i++) {
    cumt(&x[i], &a, &p, &q);
    *(array + i) = p;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tdis_cdfc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L14
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r13
  lea    0x20(%rsp),%r12
L21:
  lea    0x18(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r12,%rcx
  mov    %rbx,%rdi
  call   <cumt@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r13,%rbx
  jne    L21
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tdis_cdfc(int n, double a, double *x, double *array) {
  int i;
  double p, q;
  for (i = 0; i < n; i++) {
    cumt(&x[i], &a, &p, &q);
    *(array + i) = p;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tdis_cdfc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L21
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x20(%rsp),%r14
  mov    %rdx,%rbp
  lea    0x8(%rsi,%rax,8),%r15
  lea    0x18(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   0x0(%rax)
L17:
  mov    %rbx,%rdi
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <cumt@plt>
  movsd  0x18(%rsp),%xmm0
  add    $0x8,%rbx
  add    $0x8,%rbp
  movsd  %xmm0,-0x8(%rbp)
  cmp    %r15,%rbx
  jne    L17
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tdis_cdfc(int n, double a, double *x, double *array) {
  int i;
  double p, q;
  for (i = 0; i < n; i++) {
    cumt(&x[i], &a, &p, &q);
    *(array + i) = p;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tdis_cdfc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L21
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x20(%rsp),%r14
  mov    %rdx,%rbp
  lea    0x8(%rsi,%rax,8),%r15
  lea    0x18(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   0x0(%rax)
L29:
  mov    %rbx,%rdi
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <cumt@plt>
  movsd  0x18(%rsp),%xmm0
  add    $0x8,%rbx
  add    $0x8,%rbp
  movsd  %xmm0,-0x8(%rbp)
  cmp    %r15,%rbx
  jne    L29
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tdis_cdfc(int n, double a, double *x, double *array) {
  int i;
  double p, q;
  for (i = 0; i < n; i++) {
    cumt(&x[i], &a, &p, &q);
    *(array + i) = p;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L69
  cmpq   $0x0,-0x30(%rbp)
  jne    L79
L69:
  mov    $0xffffffffffffffff,%rax
  jmp    L6
L79:
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L53
L33:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L75
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L59
  mov    -0x10(%rbp),%rax
  jmp    L6
L59:
  addq   $0x1,-0x8(%rbp)
  jmp    L53
L75:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  add    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
L53:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x20(%rbp)
  ja     L33
  mov    $0xffffffffffffffff,%rax
L6:
  pop    %rbp
  ret
```

assistant: ```c
size_t kmp(const char *haystack, size_t hlen, const char *needle, size_t nlen, size_t *ff) {
  if (!hlen || !nlen) {
    return -1;
  }
  size_t m = 0, i = 0;
  while (m + i < hlen) {
    if (needle[i] == haystack[m + i]) {
      if (i == nlen - 1) {
        return m;
      }
      ++i;
    } else {
      m += i - ff[i];
      if (ff[i] > -1) {
        i = ff[i];
      } else {
        i = 0;
      }
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kmp>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r9
  test   %rsi,%rsi
  je     L63
  test   %rcx,%rcx
  je     L63
  mov    $0x0,%edi
  mov    $0x0,%esi
  mov    $0x0,%eax
  sub    $0x1,%rcx
  jmp    L27
L51:
  cmp    %rsi,%rcx
  je     L22
  add    $0x1,%rsi
L10:
  lea    (%rax,%rsi,1),%rdi
  cmp    %r9,%rdi
  jae    L57
L27:
  movzbl (%r10,%rdi,1),%edi
  cmp    %dil,(%rdx,%rsi,1)
  je     L51
  add    %rsi,%rax
  sub    (%r8,%rsi,8),%rax
  mov    $0x0,%esi
  jmp    L10
L57:
  mov    $0xffffffffffffffff,%rax
  ret
L63:
  mov    $0xffffffffffffffff,%rax
L22:
  ret
```

assistant: ```c
size_t kmp(const char *haystack, size_t hlen, const char *needle, size_t nlen, size_t *ff) {
  if (!hlen || !nlen) {
    return -1;
  }
  size_t m = 0, i = 0;
  while (m + i < hlen) {
    if (needle[i] == haystack[m + i]) {
      if (i == nlen - 1) {
        return m;
      }
      ++i;
    } else {
      m += i - ff[i];
      if (ff[i] > -1) {
        i = ff[i];
      } else {
        i = 0;
      }
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<kmp>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r9
  test   %rsi,%rsi
  je     L3
  test   %rcx,%rcx
  je     L3
  xor    %edi,%edi
  xor    %esi,%esi
  xor    %eax,%eax
  sub    $0x1,%rcx
  jmp    L68
L7:
  add    %rsi,%rax
  sub    (%r8,%rsi,8),%rax
  xor    %esi,%esi
  mov    %rax,%rdi
  cmp    %rdi,%r9
  jbe    L3
L68:
  movzbl (%r10,%rdi,1),%edi
  cmp    %dil,(%rdx,%rsi,1)
  jne    L7
  cmp    %rsi,%rcx
  je     L13
  add    $0x1,%rsi
  lea    (%rsi,%rax,1),%rdi
  cmp    %rdi,%r9
  ja     L68
L3:
  mov    $0xffffffffffffffff,%rax
L13:
  ret
```

assistant: ```c
size_t kmp(const char *haystack, size_t hlen, const char *needle, size_t nlen, size_t *ff) {
  if (!hlen || !nlen) {
    return -1;
  }
  size_t m = 0, i = 0;
  while (m + i < hlen) {
    if (needle[i] == haystack[m + i]) {
      if (i == nlen - 1) {
        return m;
      }
      ++i;
    } else {
      m += i - ff[i];
      if (ff[i] > -1) {
        i = ff[i];
      } else {
        i = 0;
      }
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kmp>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r9
  test   %rsi,%rsi
  je     L21
  test   %rcx,%rcx
  je     L21
  xor    %edi,%edi
  xor    %esi,%esi
  xor    %eax,%eax
  sub    $0x1,%rcx
  jmp    L32
L63:
  add    %rsi,%rax
  sub    (%r8,%rsi,8),%rax
  xor    %esi,%esi
  mov    %rax,%rdi
  cmp    %rdi,%r9
  jbe    L21
L32:
  movzbl (%r10,%rdi,1),%edi
  cmp    %dil,(%rdx,%rsi,1)
  jne    L63
  cmp    %rsi,%rcx
  je     L47
  add    $0x1,%rsi
  lea    (%rsi,%rax,1),%rdi
  cmp    %rdi,%r9
  ja     L32
L21:
  mov    $0xffffffffffffffff,%rax
L47:
  ret
```

assistant: ```c
size_t kmp(const char *haystack, size_t hlen, const char *needle, size_t nlen, size_t *ff) {
  if (!hlen || !nlen) {
    return -1;
  }
  size_t m = 0, i = 0;
  while (m + i < hlen) {
    if (needle[i] == haystack[m + i]) {
      if (i == nlen - 1) {
        return m;
      }
      ++i;
    } else {
      m += i - ff[i];
      if (ff[i] > -1) {
        i = ff[i];
      } else {
        i = 0;
      }
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printbitssimple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x80000000,-0x4(%rbp)
  jmp    L6
L36:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L26
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L26:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  shrl   -0x4(%rbp)
L6:
  cmpl   $0x0,-0x4(%rbp)
  jne    L36
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D16: 1

tool: D14: 0

assistant: ```c
void printbitssimple(int n) {
  unsigned int i;
  i = 1 << 31;
  while (i > 0) {
    if (n & i)
      printf("1");
    else
      printf("0");
    i >>= 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printbitssimple>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x20,%ebp
  mov    $0x80000000,%ebx
  lea    D13(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L18
L16:
  mov    %r14,%rdi
  call   <printf@plt>
L14:
  shr    %ebx
  sub    $0x1,%ebp
  je     L12
L18:
  test   %ebx,%r12d
  je     L16
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L14
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string

tool: D13: 0

tool: D19: 1

assistant: ```c
void printbitssimple(int n) {
  unsigned int i;
  i = 1 << 31;
  while (i > 0) {
    if (n & i)
      printf("1");
    else
      printf("0");
    i >>= 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printbitssimple>:
  endbr64
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    $0x80000000,%ebx
  jmp    L8
  nopl   0x0(%rax)
L26:
  mov    %r13,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  je     L14
L8:
  test   %ebx,%r12d
  jne    L26
  mov    %r14,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L8
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D19: 0

tool: D14: 1

assistant: ```c
void printbitssimple(int n) {
  unsigned int i;
  i = 1 << 31;
  while (i > 0) {
    if (n & i)
      printf("1");
    else
      printf("0");
    i >>= 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printbitssimple>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    $0x80000000,%ebx
  jmp    L17
  nopl   0x0(%rax)
L21:
  mov    %r13,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  je     L30
L17:
  test   %ebx,%r12d
  jne    L21
  mov    %r14,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L17
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string

tool: D10: 0

tool: D1: 1

assistant: ```c
void printbitssimple(int n) {
  unsigned int i;
  i = 1 << 31;
  while (i > 0) {
    if (n & i)
      printf("1");
    else
      printf("0");
    i >>= 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mus_char_to_bint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x3,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int mus_char_to_bint(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mus_char_to_bint>:
  endbr64
  mov    $0x0,%eax
  mov    (%rdi),%al
  movzbl 0x1(%rdi),%edx
  mov    %dl,%ah
  movzbl 0x2(%rdi),%ecx
  shl    $0x10,%ecx
  movzwl %ax,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int mus_char_to_bint(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mus_char_to_bint>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int mus_char_to_bint(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mus_char_to_bint>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int mus_char_to_bint(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L11:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L14
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3d08ff,-0x4(%rbp)
  jle    L11
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    $0x466664,%esi
  mov    $0x2,%edi
  call   <check@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int prev = 0, next = 1, sum = 0, cur = 0;
  do {
    cur = prev + next;
    if (cur % 2 == 0) {
      sum += cur;
    }
    prev = next;
    next = cur;
  } while (cur < 4000000);
  return check(2, 4613732, sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  mov    $0x1,%ecx
  mov    $0x0,%edx
L3:
  mov    %eax,%esi
  add    %ecx,%eax
  lea    (%rdx,%rax,1),%ecx
  test   $0x1,%al
  cmove  %ecx,%edx
  mov    %esi,%ecx
  cmp    $0x3d08ff,%eax
  jle    L3
  mov    $0x466664,%esi
  mov    $0x2,%edi
  call   <check@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int prev = 0, next = 1, sum = 0, cur = 0;
  do {
    cur = prev + next;
    if (cur % 2 == 0) {
      sum += cur;
    }
    prev = next;
    next = cur;
  } while (cur < 4000000);
  return check(2, 4613732, sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  mov    $0x1,%ecx
  xor    %edx,%edx
L1:
  mov    %eax,%esi
  add    %ecx,%eax
  lea    (%rdx,%rax,1),%ecx
  test   $0x1,%al
  cmove  %ecx,%edx
  mov    %esi,%ecx
  cmp    $0x3d08ff,%eax
  jle    L1
  mov    $0x466664,%esi
  mov    $0x2,%edi
  jmp    1050 <check@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int prev = 0, next = 1, sum = 0, cur = 0;
  do {
    cur = prev + next;
    if (cur % 2 == 0) {
      sum += cur;
    }
    prev = next;
    next = cur;
  } while (cur < 4000000);
  return check(2, 4613732, sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  mov    $0x1,%ecx
  xor    %edx,%edx
L4:
  mov    %eax,%esi
  add    %ecx,%eax
  lea    (%rdx,%rax,1),%ecx
  test   $0x1,%al
  cmove  %ecx,%edx
  mov    %esi,%ecx
  cmp    $0x3d08ff,%eax
  jle    L4
  mov    $0x466664,%esi
  mov    $0x2,%edi
  jmp    1050 <check@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int prev = 0, next = 1, sum = 0, cur = 0;
  do {
    cur = prev + next;
    if (cur % 2 == 0) {
      sum += cur;
    }
    prev = next;
    next = cur;
  } while (cur < 4000000);
  return check(2, 4613732, sum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  D17(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_infered: f32
name: retrieve_data
arguments: data_tag: D18
type_infered: string

tool: D17: 123.456

tool: D18: %f


assistant: ```c
int main(int argc, char *argv[]) {
  float a = 123.456;
  printf("%f\n", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D17(%rip),%xmm0
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: f32
name: extract_symbolic_data
arguments: data_label: D14
type: string

tool: D17: 123.456

tool: D14: %f


assistant: ```c
int main(int argc, char *argv[]) {
  float a = 123.456;
  printf("%f\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D10(%rip),%xmm0
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type: f32
name: retrieve_data
arguments: tag: D17
type: string

tool: D10: 123.456

tool: D17: %f


assistant: ```c
int main(int argc, char *argv[]) {
  float a = 123.456;
  printf("%f\n", a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D9(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: f32
name: extract_symbolic_data
arguments: tag: D15
datatype: string

tool: D9: 123.456

tool: D15: %f


assistant: ```c
int main(int argc, char *argv[]) {
  float a = 123.456;
  printf("%f\n", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<newInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *newInt(int i) {
  int *tmp = (int *)malloc(sizeof(int));
  *tmp = i;
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<newInt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *newInt(int i) {
  int *tmp = (int *)malloc(sizeof(int));
  *tmp = i;
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<newInt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *newInt(int i) {
  int *tmp = (int *)malloc(sizeof(int));
  *tmp = i;
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<newInt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *newInt(int i) {
  int *tmp = (int *)malloc(sizeof(int));
  *tmp = i;
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<close_pp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
void close_pp(int fd) {
  if (fd)
    return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<close_pp>:
  endbr64
  ret
```

assistant: ```c
void close_pp(int fd) {
  if (fd)
    return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<close_pp>:
  endbr64
  ret
```

assistant: ```c
void close_pp(int fd) {
  if (fd)
    return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<close_pp>:
  endbr64
  ret
```

assistant: ```c
void close_pp(int fd) {
  if (fd)
    return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L18
L17:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <uart_putchar@plt>
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_puts(int offset, const char *s) {
  while (*s != '\0')
    uart_putchar(offset, *s++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uart_puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L2
L12:
  add    $0x1,%rbx
  movsbl %sil,%esi
  mov    %ebp,%edi
  call   <uart_putchar@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L12
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uart_puts(int offset, const char *s) {
  while (*s != '\0')
    uart_putchar(offset, *s++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uart_puts>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L1
  mov    %edi,%ebp
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rbx
  mov    %ebp,%edi
  call   <uart_putchar@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L0
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uart_puts(int offset, const char *s) {
  while (*s != '\0')
    uart_putchar(offset, *s++);
}
```