user: Demonstrate the C code that generates the assembly output below:

```asm
<testa_cholesky>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  call   <tempo_em_microsegundos@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,(%rsp)
  test   %ebx,%ebx
  jne    L36
  call   <cholrow@plt>
  cmp    $0xffffffff,%eax
  je     L39
  xor    %eax,%eax
  call   <tempo_em_microsegundos@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <forwrow@plt>
  cmp    $0xffffffff,%eax
  je     L39
  xor    %eax,%eax
  call   <tempo_em_microsegundos@plt>
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,0x8(%rsp)
  call   <backrow@plt>
  cmp    $0xffffffff,%eax
  jne    L15
  nop
L39:
  mov    $0xffffffff,%r12d
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L36:
  call   <cholcol@plt>
  cmp    $0xffffffff,%eax
  je     L39
  xor    %eax,%eax
  call   <tempo_em_microsegundos@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <forwcol@plt>
  cmp    $0xffffffff,%eax
  je     L39
  xor    %eax,%eax
  call   <tempo_em_microsegundos@plt>
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,0x8(%rsp)
  call   <backcol@plt>
  cmp    $0xffffffff,%eax
  je     L39
L15:
  xor    %eax,%eax
  call   <tempo_em_microsegundos@plt>
  test   %r15d,%r15d
  jne    L25
  xor    %r12d,%r12d
  cmp    $0x1,%r14d
  je     L32
L38:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    0x8(%rsp),%r12
  sub    %r12,%rax
  mov    %rax,%rdi
  call   <converte_milisegundo@plt>
  mov    %r12,%rdi
  sub    %rbx,%rdi
  mov    %eax,%r15d
  call   <converte_milisegundo@plt>
  sub    (%rsp),%rbx
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <converte_milisegundo@plt>
  mov    %r12d,%edx
  mov    %r15d,%ecx
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  cmp    $0x1,%r14d
  jne    L38
L32:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <imprime_vetor@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D12
datatype: string

tool: D5: | %6.2lf | %.2lf | %.2lf


tool: D12: x eh:

assistant: ```c
int testa_cholesky(int n, double A[][800], double b[], int modo, int imprime_solucao, int imprime_tempo) {
  unsigned long long mark0, mark1, mark2, mark3;
  mark0 = tempo_em_microsegundos();
  if (modo == 0) {
    if (cholrow(n, A) == -1)
      return -1;
  } else {
    if (cholcol(n, A) == -1)
      return -1;
  }
  mark1 = tempo_em_microsegundos();
  if (modo == 0) {
    if (forwrow(n, A, b) == -1)
      return -1;
  } else {
    if (forwcol(n, A, b) == -1)
      return -1;
  }
  mark2 = tempo_em_microsegundos();
  if (modo == 0) {
    if (backrow(n, A, b, 1) == -1)
      return -1;
  } else {
    if (backcol(n, A, b, 1) == -1)
      return -1;
  }
  mark3 = tempo_em_microsegundos();
  if (imprime_tempo) {
    printf("| %6.2lf | %.2lf | %.2lf\n", converte_milisegundo(mark1 - mark0), converte_milisegundo(mark2 - mark1), converte_milisegundo(mark3 - mark2));
  }
  if (imprime_solucao == 1) {
    printf("x eh:\n");
    imprime_vetor(n, b);
  }
  return 0;
}
```