ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_free_list>:
  endbr64
  cmp    $0x200,%edi
  je     L2
  mov    $0x200,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    %eax,%edx
  lea    0x1(%r8,%r8,1),%r8d
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%edi
  jne    L4
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_free_list(int size) {
  int index = 0, current_size = 512;
  while (current_size != size) {
    index = 2 * index + 1;
    current_size = current_size / 2;
  }
  return index;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_summary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D51
type_guessed: string
name: parse_data
arguments: tag: D21
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D56
type_guessed: string
name: parse_data
arguments: tag: D45
type_guessed: string

tool: D51: #

tool: D21: 1..%d


tool: D3: # total %d


tool: D56: # pass  %d


tool: D45: # ok

assistant: ```c
void print_summary(int total, int passing) {
  printf("#\n");
  printf("1..%d\n", total);
  printf("# total %d\n", total);
  printf("# pass  %d\n", passing);
  printf("#\n");
  printf("# ok\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_summary>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D41(%rip),%r12
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D41
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D42
type_guessed: string
name: read_data
arguments: data_label: D25
type_guessed: string

tool: D41: #

tool: D19: 1..%d


tool: D13: # total %d


tool: D42: # pass  %d


tool: D25: # ok

assistant: ```c
void print_summary(int total, int passing) {
  printf("#\n");
  printf("1..%d\n", total);
  printf("# total %d\n", total);
  printf("# pass  %d\n", passing);
  printf("#\n");
  printf("# ok\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_summary>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  pop    %rbp
  lea    D24(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D9
type_guessed: string
name: read_data
arguments: label: D44
type_guessed: string
name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string

tool: D5: #

tool: D9: 1..%d


tool: D44: # total %d


tool: D19: # pass  %d


tool: D24: # ok

assistant: ```c
void print_summary(int total, int passing) {
  printf("#\n");
  printf("1..%d\n", total);
  printf("# total %d\n", total);
  printf("# pass  %d\n", passing);
  printf("#\n");
  printf("# ok\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_summary>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  pop    %rbp
  lea    D27(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string

tool: D10: #

tool: D7: 1..%d


tool: D17: # total %d


tool: D49: # pass  %d


tool: D27: # ok

assistant: ```c
void print_summary(int total, int passing) {
  printf("#\n");
  printf("1..%d\n", total);
  printf("# total %d\n", total);
  printf("# pass  %d\n", passing);
  printf("#\n");
  printf("# ok\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filelen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L23
  mov    $0xffffffff,%eax
  jmp    L6
L23:
  mov    -0xc(%rbp),%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int filelen(const char *file) {
  struct stat st;
  if (stat(file, &st))
    return -1;
  return st.st_size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<filelen>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L20
  mov    0x4(%rsp),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L20:
  mov    $0xffffffff,%eax
  jmp    L18
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filelen(const char *file) {
  struct stat st;
  if (stat(file, &st))
    return -1;
  return st.st_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filelen>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L23
  mov    0x4(%rsp),%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L1
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filelen(const char *file) {
  struct stat st;
  if (stat(file, &st))
    return -1;
  return st.st_size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<filelen>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L13
  mov    0x4(%rsp),%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L16
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filelen(const char *file) {
  struct stat st;
  if (stat(file, &st))
    return -1;
  return st.st_size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cstr_from_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x404(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%ecx
  lea    D20(%rip),%rdx
  mov    $0x3e7,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x3fc(%rbp)
  mov    -0x3fc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x3f8(%rbp)
  cmpq   $0x0,-0x3f8(%rbp)
  jne    L10
  lea    D36(%rip),%rax
  mov    %rax,%rcx
  mov    $0x89,%edx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fatal_error@plt>
L10:
  lea    -0x3f0(%rbp),%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x3f8(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D36
type: string
name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D8
type: string

tool: D20: %d

tool: D36: Cannot allocate memory for return c-string while converting from int

tool: D14: cstr_from_int

tool: D8: cubestr.c

assistant: ```c
char *cstr_from_int(int val) {
  char buffer[1000];
  snprintf(buffer, 999, "%d", val);
  int size = strlen(buffer);
  char *str = (char *)malloc((sizeof(char)) * (size + 1));
  if (str == NULL)
    fatal_error("cubestr.c", "cstr_from_int", 137, "Cannot allocate memory for return c-string while converting from int");
  strcpy(str, buffer);
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<cstr_from_int>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %edi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D13(%rip),%rdx
  mov    $0x3e7,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L20
L14:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %rbx,%rax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L20:
  lea    D20(%rip),%rcx
  mov    $0x89,%edx
  lea    D21(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <fatal_error@plt>
  jmp    L14
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: D13: %d

tool: D20: Cannot allocate memory for return c-string while converting from int

tool: D21: cstr_from_int

tool: D17: cubestr.c

assistant: ```c
char *cstr_from_int(int val) {
  char buffer[1000];
  snprintf(buffer, 999, "%d", val);
  int size = strlen(buffer);
  char *str = (char *)malloc((sizeof(char)) * (size + 1));
  if (str == NULL)
    fatal_error("cubestr.c", "cstr_from_int", 137, "Cannot allocate memory for return c-string while converting from int");
  strcpy(str, buffer);
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cstr_from_int>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  lea    D0(%rip),%rdx
  mov    $0x3e7,%esi
  push   %rbp
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L26
L1:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3f8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L26:
  lea    D32(%rip),%rcx
  mov    $0x89,%edx
  lea    D23(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <fatal_error@plt>
  jmp    L1
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D32
type: string
name: extract_symbolic_data
arguments: data_label: D23
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D0: %d

tool: D32: Cannot allocate memory for return c-string while converting from int

tool: D23: cstr_from_int

tool: D4: cubestr.c

assistant: ```c
char *cstr_from_int(int val) {
  char buffer[1000];
  snprintf(buffer, 999, "%d", val);
  int size = strlen(buffer);
  char *str = (char *)malloc((sizeof(char)) * (size + 1));
  if (str == NULL)
    fatal_error("cubestr.c", "cstr_from_int", 137, "Cannot allocate memory for return c-string while converting from int");
  strcpy(str, buffer);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cstr_from_int>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  lea    D14(%rip),%rdx
  mov    $0x3e7,%esi
  push   %rbp
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L29
L20:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x3f8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L29:
  lea    D5(%rip),%rcx
  mov    $0x89,%edx
  lea    D35(%rip),%rsi
  lea    D11(%rip),%rdi
  call   <fatal_error@plt>
  jmp    L20
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D35
datatype: string
name: retrieve_data
arguments: label: D11
datatype: string

tool: D14: %d

tool: D5: Cannot allocate memory for return c-string while converting from int

tool: D35: cstr_from_int

tool: D11: cubestr.c

assistant: ```c
char *cstr_from_int(int val) {
  char buffer[1000];
  snprintf(buffer, 999, "%d", val);
  int size = strlen(buffer);
  char *str = (char *)malloc((sizeof(char)) * (size + 1));
  if (str == NULL)
    fatal_error("cubestr.c", "cstr_from_int", 137, "Cannot allocate memory for return c-string while converting from int");
  strcpy(str, buffer);
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<add_nodename_to_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <nodename_to_filename_1@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <add_word@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void add_nodename_to_filename(char *nodename, int href) {
  char *filename = nodename_to_filename_1(nodename, href);
  add_word(filename);
  free(filename);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_nodename_to_filename>:
  endbr64
  push   %rbx
  call   <nodename_to_filename_1@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <add_word@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void add_nodename_to_filename(char *nodename, int href) {
  char *filename = nodename_to_filename_1(nodename, href);
  add_word(filename);
  free(filename);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_nodename_to_filename>:
  endbr64
  push   %rbp
  call   <nodename_to_filename_1@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <add_word@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void add_nodename_to_filename(char *nodename, int href) {
  char *filename = nodename_to_filename_1(nodename, href);
  add_word(filename);
  free(filename);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<add_nodename_to_filename>:
  endbr64
  push   %rbp
  call   <nodename_to_filename_1@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <add_word@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void add_nodename_to_filename(char *nodename, int href) {
  char *filename = nodename_to_filename_1(nodename, href);
  add_word(filename);
  free(filename);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_instances>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L76
L68:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L69
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L59
L13:
  subl   $0x1,-0x8(%rbp)
L59:
  cmpl   $0x0,-0x8(%rbp)
  js     L1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L1:
  cmpl   $0x0,-0x8(%rbp)
  jle    L69
  addl   $0x1,-0x4(%rbp)
L69:
  addl   $0x1,-0xc(%rbp)
L76:
  mov    -0x18(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L68
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int count_instances(int offset, off_t size, char *file_address, const char *search, int len) {
  int i, k, count = 0;
  for (i = offset; i < size - len; i++) {
    if (!memcmp(file_address + i, search, len)) {
      for (k = i; k >= 0 && file_address[k] != '"' && file_address[k]; k--)
        ;
      if (k > 0)
        count++;
    }
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_instances>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  sub    %r8d,%esi
  cmp    %esi,%edi
  jge    L43
  mov    %edi,%ebx
  mov    %rcx,%r14
  mov    %r8d,%r13d
  mov    %esi,%r12d
  movslq %edi,%rax
  lea    (%rdx,%rax,1),%rbp
  mov    $0x0,%r15d
  jmp    L28
L49:
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  add    %eax,%r15d
L3:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  je     L34
L28:
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L3
  mov    %rbp,%rdx
  mov    %ebx,%eax
  test   %ebx,%ebx
  js     L49
L20:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L49
  cmp    $0x22,%cl
  je     L49
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L20
  jmp    L3
L43:
  mov    $0x0,%r15d
L34:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int count_instances(int offset, off_t size, char *file_address, const char *search, int len) {
  int i, k, count = 0;
  for (i = offset; i < size - len; i++) {
    if (!memcmp(file_address + i, search, len)) {
      for (k = i; k >= 0 && file_address[k] != '"' && file_address[k]; k--)
        ;
      if (k > 0)
        count++;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_instances>:
  endbr64
  push   %r15
  sub    %r8d,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %esi,%edi
  jge    L56
  sub    $0x1,%esi
  movslq %edi,%r15
  mov    %edi,%r12d
  mov    %rdx,%r14
  sub    %edi,%esi
  movl   $0x0,0xc(%rsp)
  mov    %rcx,%rbp
  mov    %r8d,%ebx
  lea    0x1(%r15,%rsi,1),%r13
  sub    %r15d,%r12d
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%r15
  cmp    %r13,%r15
  je     L50
L30:
  lea    (%r14,%r15,1),%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L4
  mov    %r12d,%esi
  mov    %r15,%rax
  add    %r15d,%esi
  jns    L91
  jmp    L4
L82:
  cmp    $0x22,%dl
  je     L75
  sub    $0x1,%rax
  test   %eax,%eax
  js     L4
L91:
  movzbl (%r14,%rax,1),%edx
  mov    %eax,%ecx
  test   %dl,%dl
  jne    L82
L75:
  xor    %eax,%eax
  test   %ecx,%ecx
  setg   %al
  add    $0x1,%r15
  add    %eax,0xc(%rsp)
  cmp    %r13,%r15
  jne    L30
L50:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  movl   $0x0,0xc(%rsp)
  jmp    L50
```

assistant: ```c
int count_instances(int offset, off_t size, char *file_address, const char *search, int len) {
  int i, k, count = 0;
  for (i = offset; i < size - len; i++) {
    if (!memcmp(file_address + i, search, len)) {
      for (k = i; k >= 0 && file_address[k] != '"' && file_address[k]; k--)
        ;
      if (k > 0)
        count++;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<count_instances>:
  endbr64
  push   %r15
  sub    %r8d,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %esi,%edi
  jge    L75
  mov    %edi,%r15d
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %r8d,%ebp
  mov    %esi,%r13d
  test   %edi,%edi
  jns    L45
  xor    %r14d,%r14d
  test   %esi,%esi
  movslq %edi,%rcx
  cmovle %esi,%r14d
  mov    %r14d,0xc(%rsp)
  lea    (%rdx,%rcx,1),%r14
  nopl   (%rax)
L112:
  mov    %r14,%rdi
  mov    %ebp,%edx
  mov    %r12,%rsi
  add    $0x1,%r15d
  call   <memcmp@plt>
  add    $0x1,%r14
  cmp    0xc(%rsp),%r15d
  jl     L112
  cmp    %r13d,%r15d
  jge    L75
L45:
  movslq %r15d,%r15
  xor    %r14d,%r14d
  jmp    L61
  nopl   0x0(%rax)
L41:
  add    $0x1,%r15
  cmp    %r15d,%r13d
  jle    L40
L61:
  lea    (%rbx,%r15,1),%rdi
  mov    %ebp,%edx
  mov    %r12,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L41
  mov    %r15,%rax
  jmp    L121
  nopl   0x0(%rax,%rax,1)
L59:
  cmp    $0x22,%dl
  je     L54
  sub    $0x1,%rax
  test   %eax,%eax
  js     L41
L121:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%ecx
  test   %dl,%dl
  jne    L59
L54:
  xor    %eax,%eax
  test   %ecx,%ecx
  setg   %al
  add    $0x1,%r15
  add    %eax,%r14d
  cmp    %r15d,%r13d
  jg     L61
L40:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L75:
  xor    %r14d,%r14d
  jmp    L40
```

assistant: ```c
int count_instances(int offset, off_t size, char *file_address, const char *search, int len) {
  int i, k, count = 0;
  for (i = offset; i < size - len; i++) {
    if (!memcmp(file_address + i, search, len)) {
      for (k = i; k >= 0 && file_address[k] != '"' && file_address[k]; k--)
        ;
      if (k > 0)
        count++;
    }
  }
  return count;
}
```