user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  jmp    L1
L40:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x5,%eax
  ja     L78
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D60(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D60(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  mov    %rax,-0x10(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <preorder@plt>
  jmp    L1
  lea    D115(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <postorder@plt>
  jmp    L1
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <inorder@plt>
  jmp    L1
  mov    $0x0,%edi
  call   <exit@plt>
L78:
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  mov    -0x18(%rbp),%eax
  cmp    $0x5,%eax
  jne    L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D44
type: string
name: retrieve_data
arguments: data_tag: D33
type: string
name: retrieve_data
arguments: data_tag: D61
type: string
name: retrieve_data
arguments: data_tag: D58
type: string
name: retrieve_data
arguments: data_tag: D38
type: string
name: retrieve_data
arguments: data_tag: D52
type: string
name: retrieve_data
arguments: data_tag: D115
type: string
name: retrieve_data
arguments: data_tag: D94
type: string
name: retrieve_data
arguments: data_tag: D74
type: string

tool: D44: 
Menu --Binary search tree 

tool: D33: 
 1. Insert	 2. Preorder Traversal 	 3.Inorder Traversal 	4.Postorder traversal


tool: D61: %d

tool: D58: 
Enter the number to insert:

tool: D38: 	inserted successfully


tool: D52: 
preorder:

tool: D115: 
 postorder:

tool: D94: 
 inorder:

tool: D74: 
Enter valid choice


assistant: ```c
int main() {
  int choice, val;
  struct node *root = NULL;
  while (choice != 5) {
    printf("\nMenu --Binary search tree ");
    printf("\n 1. Insert\t 2. Preorder Traversal \t 3.Inorder Traversal \t4.Postorder traversal\n");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("\nEnter the number to insert:");
      scanf("%d", &val);
      root = insert(root, val);
      printf("\tinserted successfully\n");
      break;
    case 2:
      printf("\npreorder:");
      preorder(root);
      break;
    case 4:
      printf("\n postorder:");
      postorder(root);
      break;
    case 3:
      printf("\n inorder:");
      inorder(root);
      break;
    case 5:
      exit(0);
    default:
      printf("\nEnter valid choice\n");
    }
  }
}
```