ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<transfer_YUV888_to_VYU888>:
  endbr64
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x2(%rax)
  addq   $0x3,(%rdi)
  ret
```

assistant: ```c
void transfer_YUV888_to_VYU888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[2];
  (*output)[1] = input[0];
  (*output)[2] = input[1];
  (*output) += 3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transfer_YUV888_to_VYU888>:
  endbr64
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x2(%rax)
  addq   $0x3,(%rdi)
  ret
```

assistant: ```c
void transfer_YUV888_to_VYU888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[2];
  (*output)[1] = input[0];
  (*output)[2] = input[1];
  (*output) += 3;
}
```
user: What is the c source code of the assembly code below?

```asm
<transfer_YUV888_to_VYU888>:
  endbr64
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x2(%rax)
  addq   $0x3,(%rdi)
  ret
```

assistant: ```c
void transfer_YUV888_to_VYU888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[2];
  (*output)[1] = input[0];
  (*output)[2] = input[1];
  (*output) += 3;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sub_by>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <by@plt>
  mov    $0x0,%eax
  call   <sub@plt>
  nop
  leave
  ret
```

assistant: ```c
void sub_by(uint32_t x) {
  by(x);
  sub();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sub_by>:
  endbr64
  sub    $0x8,%rsp
  call   <by@plt>
  mov    $0x0,%eax
  call   <sub@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sub_by(uint32_t x) {
  by(x);
  sub();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sub_by>:
  endbr64
  sub    $0x8,%rsp
  call   <by@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sub@plt>
```

assistant: ```c
void sub_by(uint32_t x) {
  by(x);
  sub();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sub_by>:
  endbr64
  sub    $0x8,%rsp
  call   <by@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sub@plt>
```

assistant: ```c
void sub_by(uint32_t x) {
  by(x);
  sub();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GreenRedColRamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movsd  D3(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rbp),%xmm1
  movsd  D31(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D50(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rbp),%xmm1
  movsd  D5(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  D31(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D50(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: f64
name: retrieve_data
arguments: tag: D31
type: f64
name: retrieve_data
arguments: tag: D50
type: f64
name: retrieve_data
arguments: tag: D5
type: f64

tool: D3: 1

tool: D31: 0.8

tool: D50: 0.1

tool: D5: 3.141592653589793

assistant: ```c
void GreenRedColRamp(double frac, double *red, double *green, double *blue) {
  *red = (1.0 - frac);
  *green = (0.80 * frac + 0.1);
  *blue = (0.80 * sin(3.141592653589793238462643383279502884197169399 * frac) + 0.1);
}
```
user: What is the c source code of the assembly code below:

```asm
<GreenRedColRamp>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  movsd  D24(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  D10(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D51(%rip),%xmm1
  movsd  %xmm1,(%rsi)
  mulsd  D16(%rip),%xmm0
  call   <sin@plt>
  mulsd  D10(%rip),%xmm0
  addsd  D51(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D24
type: f64
name: disassemble_data
arguments: tag: D10
type: f64
name: disassemble_data
arguments: tag: D51
type: f64
name: disassemble_data
arguments: tag: D16
type: f64

tool: D24: 1

tool: D10: 0.8

tool: D51: 0.1

tool: D16: 3.141592653589793

assistant: ```c
void GreenRedColRamp(double frac, double *red, double *green, double *blue) {
  *red = (1.0 - frac);
  *green = (0.80 * frac + 0.1);
  *blue = (0.80 * sin(3.141592653589793238462643383279502884197169399 * frac) + 0.1);
}
```
user: What is the c source code of the assembly code below?

```asm
<GreenRedColRamp>:
  endbr64
  movsd  D40(%rip),%xmm1
  push   %rbx
  mov    %rdx,%rbx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  D43(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  D7(%rip),%xmm0
  addsd  D27(%rip),%xmm1
  movsd  %xmm1,(%rsi)
  call   <sin@plt>
  mulsd  D43(%rip),%xmm0
  addsd  D27(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D40
datatype: f64
name: extract_symbolic_data
arguments: tag: D43
datatype: f64
name: extract_symbolic_data
arguments: tag: D7
datatype: f64
name: extract_symbolic_data
arguments: tag: D27
datatype: f64

tool: D40: 1

tool: D43: 0.8

tool: D7: 3.141592653589793

tool: D27: 0.1

assistant: ```c
void GreenRedColRamp(double frac, double *red, double *green, double *blue) {
  *red = (1.0 - frac);
  *green = (0.80 * frac + 0.1);
  *blue = (0.80 * sin(3.141592653589793238462643383279502884197169399 * frac) + 0.1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GreenRedColRamp>:
  endbr64
  movsd  D14(%rip),%xmm1
  push   %rbx
  mov    %rdx,%rbx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  D36(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  D52(%rip),%xmm0
  addsd  D21(%rip),%xmm1
  movsd  %xmm1,(%rsi)
  call   <sin@plt>
  mulsd  D36(%rip),%xmm0
  addsd  D21(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: f64
name: unpack_data
arguments: label: D36
datatype: f64
name: unpack_data
arguments: label: D52
datatype: f64
name: unpack_data
arguments: label: D21
datatype: f64

tool: D14: 1

tool: D36: 0.8

tool: D52: 3.141592653589793

tool: D21: 0.1

assistant: ```c
void GreenRedColRamp(double frac, double *red, double *green, double *blue) {
  *red = (1.0 - frac);
  *green = (0.80 * frac + 0.1);
  *blue = (0.80 * sin(3.141592653589793238462643383279502884197169399 * frac) + 0.1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptls_hexdump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L17
L0:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %ecx,%rdx
  lea    D0(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %ecx,%rdx
  lea    D0(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jne    L0
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: 0123456789abcdef

assistant: ```c
char *ptls_hexdump(char *buf, const void *_src, size_t len) {
  char *dst = buf;
  const uint8_t *src = _src;
  size_t i;
  for (i = 0; i != len; ++i) {
    *dst++ = "0123456789abcdef"[src[i] >> 4];
    *dst++ = "0123456789abcdef"[src[i] & 0xf];
  }
  *dst++ = '\0';
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ptls_hexdump>:
  endbr64
  test   %rdx,%rdx
  je     L16
  mov    $0x0,%eax
  lea    D9(%rip),%r8
L12:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x4,%ecx
  movslq %ecx,%rcx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rdi,%rax,2)
  mov    (%rsi,%rax,4),%ecx
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
  lea    (%rdi,%rax,2),%rax
L5:
  movb   $0x0,(%rax)
  mov    %rdi,%rax
  ret
L16:
  mov    %rdi,%rax
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: 0123456789abcdef

assistant: ```c
char *ptls_hexdump(char *buf, const void *_src, size_t len) {
  char *dst = buf;
  const uint8_t *src = _src;
  size_t i;
  for (i = 0; i != len; ++i) {
    *dst++ = "0123456789abcdef"[src[i] >> 4];
    *dst++ = "0123456789abcdef"[src[i] & 0xf];
  }
  *dst++ = '\0';
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<ptls_hexdump>:
  endbr64
  mov    %rdi,%r8
  test   %rdx,%rdx
  je     L18
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  nopl   (%rax)
L5:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x4,%ecx
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,(%r8,%rax,2)
  mov    (%rsi,%rax,4),%ecx
  and    $0xf,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,0x1(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
  lea    (%r8,%rdx,2),%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L18:
  mov    %rdi,%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D4: 0123456789abcdef

assistant: ```c
char *ptls_hexdump(char *buf, const void *_src, size_t len) {
  char *dst = buf;
  const uint8_t *src = _src;
  size_t i;
  for (i = 0; i != len; ++i) {
    *dst++ = "0123456789abcdef"[src[i] >> 4];
    *dst++ = "0123456789abcdef"[src[i] & 0xf];
  }
  *dst++ = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptls_hexdump>:
  endbr64
  mov    %rdi,%r8
  test   %rdx,%rdx
  je     L12
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  nopl   (%rax)
L17:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x4,%ecx
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,(%r8,%rax,2)
  mov    (%rsi,%rax,4),%ecx
  and    $0xf,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,0x1(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L17
  lea    (%r8,%rdx,2),%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L12:
  mov    %rdi,%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: 0123456789abcdef

assistant: ```c
char *ptls_hexdump(char *buf, const void *_src, size_t len) {
  char *dst = buf;
  const uint8_t *src = _src;
  size_t i;
  for (i = 0; i != len; ++i) {
    *dst++ = "0123456789abcdef"[src[i] >> 4];
    *dst++ = "0123456789abcdef"[src[i] & 0xf];
  }
  *dst++ = '\0';
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  ja     L70
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D111(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D111(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D116(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L70:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D21
type_infered: string
name: parse_data
arguments: label: D68
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D73
type_infered: string
name: parse_data
arguments: label: D116
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D39
type_infered: string
name: parse_data
arguments: label: D54
type_infered: string

tool: D21: %d

tool: D68: zero


tool: D29: one


tool: D73: two


tool: D116: three


tool: D13: four


tool: D22: five


tool: D6: six


tool: D17: seven


tool: D39: eight


tool: D54: nine


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D92(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L105
  mov    0x4(%rsp),%eax
  lea    D42(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D108(%rip),%rdi
  call   <printf@plt>
L105:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D89(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D117(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D78(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L105
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L105
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D92
type_guessed: string
name: retrieve_data
arguments: tag: D108
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D89
type_guessed: string
name: retrieve_data
arguments: tag: D46
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D41
type_guessed: string
name: retrieve_data
arguments: tag: D117
type_guessed: string
name: retrieve_data
arguments: tag: D78
type_guessed: string
name: retrieve_data
arguments: tag: D80
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D92: %d

tool: D108: zero


tool: D22: one


tool: D89: two


tool: D46: three


tool: D4: four


tool: D41: five


tool: D117: six


tool: D78: seven


tool: D80: eight


tool: D13: nine


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D50(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L104
  mov    0x4(%rsp),%eax
  lea    D96(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D87(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L104:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D104(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D82(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D109(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D92(%rip),%rdi
  call   <printf@plt>
  jmp    L104
  lea    D113(%rip),%rdi
  call   <printf@plt>
  jmp    L104
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D50
type: string
name: disassemble_data
arguments: label: D87
type: string
name: disassemble_data
arguments: label: D104
type: string
name: disassemble_data
arguments: label: D82
type: string
name: disassemble_data
arguments: label: D1
type: string
name: disassemble_data
arguments: label: D57
type: string
name: disassemble_data
arguments: label: D109
type: string
name: disassemble_data
arguments: label: D20
type: string
name: disassemble_data
arguments: label: D15
type: string
name: disassemble_data
arguments: label: D92
type: string
name: disassemble_data
arguments: label: D113
type: string

tool: D50: %d

tool: D87: nine


tool: D104: eight


tool: D82: zero


tool: D1: one


tool: D57: two


tool: D109: three


tool: D20: four


tool: D15: five


tool: D92: six


tool: D113: seven


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L74
  mov    0x4(%rsp),%eax
  lea    D49(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D71(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L74:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D86(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D59(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D55(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D94(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D92(%rip),%rdi
  call   <printf@plt>
  jmp    L74
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L74
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type: string
name: extract_symbolic_data
arguments: data_label: D71
type: string
name: extract_symbolic_data
arguments: data_label: D86
type: string
name: extract_symbolic_data
arguments: data_label: D59
type: string
name: extract_symbolic_data
arguments: data_label: D43
type: string
name: extract_symbolic_data
arguments: data_label: D69
type: string
name: extract_symbolic_data
arguments: data_label: D55
type: string
name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D94
type: string
name: extract_symbolic_data
arguments: data_label: D92
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string

tool: D30: %d

tool: D71: nine


tool: D86: eight


tool: D59: zero


tool: D43: one


tool: D69: two


tool: D55: three


tool: D20: four


tool: D94: five


tool: D92: six


tool: D39: seven


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x28(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <utimes@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int utime(const char *filename, const struct utimbuf *buf) {
  struct timeval tvp[2];
  tvp[0].tv_sec = buf->actime;
  tvp[0].tv_usec = 0;
  tvp[1].tv_sec = buf->modtime;
  tvp[1].tv_usec = 0;
  return utimes(filename, tvp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utime>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsi),%eax
  mov    %eax,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    (%rsi),%eax
  mov    %eax,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rsi
  call   <utimes@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utime(const char *filename, const struct utimbuf *buf) {
  struct timeval tvp[2];
  tvp[0].tv_sec = buf->actime;
  tvp[0].tv_usec = 0;
  tvp[1].tv_sec = buf->modtime;
  tvp[1].tv_usec = 0;
  return utimes(filename, tvp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utime>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    0x4(%rsi),%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %eax,0x8(%rsp)
  mov    (%rsi),%eax
  mov    %rsp,%rsi
  mov    %eax,0x18(%rsp)
  call   <utimes@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utime(const char *filename, const struct utimbuf *buf) {
  struct timeval tvp[2];
  tvp[0].tv_sec = buf->actime;
  tvp[0].tv_usec = 0;
  tvp[1].tv_sec = buf->modtime;
  tvp[1].tv_usec = 0;
  return utimes(filename, tvp);
}
```