user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D42(%rip),%rdi
  push   %r14
  lea    D65(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x78(%rsp),%r12
  mov    %rbp,%rbx
  call   <printf@plt>
L38:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x4(%rbx),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x8(%rbx),%rsi
  mov    %r14,%rdi
  add    $0x28,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L38
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  lea    0x190(%rsp),%r13
  call   <printf@plt>
  lea    0x208(%rsp),%r15
  mov    %r13,%rbx
L33:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x4(%rbx),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x8(%rbx),%rsi
  mov    %r14,%rdi
  add    $0x28,%rbx
  call   <scanf@plt>
  cmp    %rbx,%r15
  jne    L33
  lea    D29(%rip),%rdi
  mov    %rbp,%r14
  lea    D14(%rip),%rbx
  call   <puts@plt>
L20:
  mov    (%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x28,%r14
  call   <printf@plt>
  mov    -0x24(%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x20(%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12,%r14
  jne    L20
  lea    D32(%rip),%rdi
  mov    %r13,%r14
  call   <puts@plt>
L9:
  mov    (%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x28,%r14
  call   <printf@plt>
  mov    -0x24(%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x20(%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r15,%r14
  jne    L9
  lea    0x320(%rsp),%r14
  lea    0xc(%r13),%r10
  mov    %r14,%r11
L65:
  mov    0x0(%rbp),%r9d
  mov    0x4(%rbp),%r8d
  mov    %r11,%rsi
  mov    %r13,%rax
  mov    0x8(%rbp),%edi
L27:
  mov    (%rax),%ecx
  mov    0x28(%rax),%edx
  add    $0x4,%rax
  add    $0x4,%rsi
  imul   %r8d,%edx
  imul   %r9d,%ecx
  add    %edx,%ecx
  mov    0x4c(%rax),%edx
  imul   %edi,%edx
  add    %ecx,%edx
  mov    %edx,-0x4(%rsi)
  cmp    %rax,%r10
  jne    L27
  add    $0x28,%rbp
  add    $0x28,%r11
  cmp    %r12,%rbp
  jne    L65
  lea    D19(%rip),%rdi
  lea    0x78(%r14),%rbp
  call   <puts@plt>
L50:
  mov    (%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x28,%r14
  call   <printf@plt>
  mov    -0x24(%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x20(%r14),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%r14
  jne    L50
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x4c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D42
data_type: string
name: retrieve_data
arguments: data_label: D65
data_type: string
name: retrieve_data
arguments: data_label: D44
data_type: string
name: retrieve_data
arguments: data_label: D29
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D32
data_type: string
name: retrieve_data
arguments: data_label: D19
data_type: string

tool: D42: 
Enter First Matrix : n

tool: D65: %d

tool: D44: 
Enter Second Matrix:n

tool: D29: The First Matrix is: 

tool: D14:  %d 

tool: D32: The Second Matrix is : 

tool: D19: 
Multiplication Of Two Matrices : 

assistant: ```c
int main() {
  int a[10][10], b[10][10], c[10][10], i, j, k;
  int sum = 0;
  printf("\nEnter First Matrix : n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%d", &a[i][j]);
    }
  }
  printf("\nEnter Second Matrix:n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%d", &b[i][j]);
    }
  }
  printf("The First Matrix is: \n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf(" %d ", a[i][j]);
    }
    printf("\n");
  }
  printf("The Second Matrix is : \n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf(" %d ", b[i][j]);
    }
    printf("\n");
  }
  for (i = 0; i <= 2; i++) {
    for (j = 0; j <= 2; j++) {
      sum = 0;
      for (k = 0; k <= 2; k++) {
        sum = sum + a[i][k] * b[k][j];
      }
      c[i][j] = sum;
    }
  }
  printf("\nMultiplication Of Two Matrices : \n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf(" %d ", c[i][j]);
    }
    printf("\n");
  }
  return (0);
}
```