user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  mov    %rax,(%rsp)
  lea    0x18(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L168
L66:
  test   %edx,%edx
  jns    L27
L13:
  lea    0x20(%rsp),%rax
  lea    0x70(%rsp),%rdx
  mov    $0x1,%esi
L30:
  imul   (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L30
  lea    D4(%rip),%rdi
  call   <printf@plt>
L168:
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L116
  mov    0x18(%rsp),%edx
  mov    0x1c(%rsp),%ecx
  mov    %edx,%eax
  or     %ecx,%eax
  je     L116
  mov    $0x0,%eax
L112:
  movl   $0x1,0x20(%rsp,%rax,1)
  movl   $0x1,0x70(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x50,%rax
  jne    L112
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%ecx
  jge    L105
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,0x1c(%rsp)
L105:
  mov    0x1c(%rsp),%esi
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jl     L129
  cltq
  movslq %esi,%rcx
  neg    %rcx
  lea    0x20(%rsp,%rcx,4),%rcx
L163:
  mov    %eax,-0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edx
  jge    L163
L129:
  sub    %esi,%edx
  cmp    $0x1,%edx
  jle    L66
  lea    0x1(%rdx),%edx
  mov    $0x2,%eax
L65:
  mov    %eax,0x70(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L65
L27:
  lea    0x20(%rsp),%r14
  mov    $0x0,%r15d
  jmp    L75
L113:
  lea    0x70(%rsp),%r13
  mov    0x0(%r13,%r12,4),%ebx
  mov    (%r14),%ebp
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <bcd@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,(%r14)
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,0x0(%r13,%r12,4)
  add    $0x1,%r12
  mov    0x18(%rsp),%eax
  sub    0x1c(%rsp),%eax
  cmp    %r12d,%eax
  jge    L113
L5:
  add    $0x1,%r15d
  add    $0x4,%r14
  mov    0x18(%rsp),%eax
  sub    0x1c(%rsp),%eax
  cmp    %r15d,%eax
  jl     L13
L75:
  mov    $0x0,%r12d
  mov    0x1c(%rsp),%eax
  cmp    %eax,0x18(%rsp)
  jge    L113
  jmp    L5
L116:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  mov    $0x0,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string

tool: D4: %d


tool: D1: %d%d

assistant: ```c
int main() {
  int n, k, i, j;
  int res[20], ma[20], r, bc;
  while (scanf("%d%d", &n, &k) != -1) {
    if (n == 0 && k == 0)
      break;
    for (i = 0; i < 20; i++) {
      res[i] = 1;
      ma[i] = 1;
    }
    if (k < n / 2)
      k = n - k;
    for (i = k + 1; i <= n; i++)
      res[i - k - 1] = i;
    for (i = 2; i <= n - k; i++)
      ma[i] = i;
    for (i = 0; i <= n - k; i++)
      for (j = 0; j <= n - k; j++) {
        bc = bcd(res[i], ma[j]);
        res[i] /= bc;
        ma[j] /= bc;
      }
    r = 1;
    for (i = 0; i < 20; i++)
      r *= res[i];
    printf("%d\n", r);
  }
  return 0;
}
```