user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printDump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L96
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%r12d
  mov    %eax,0xc(%rsp)
  xor    %r14d,%r14d
  lea    D78(%rip),%r13
  jmp    L131
  nopl   (%rax)
L33:
  cmp    $0xf,%eax
  je     L147
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L36:
  add    $0x1,%r14
  cmp    %r14,%r12
  je     L31
L131:
  mov    %r14d,%eax
  movzbl (%rbx,%r14,1),%esi
  and    $0xf,%eax
  jne    L33
  movzbl %sil,%edx
  lea    D60(%rip),%rdi
  mov    %r14d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r14
  cmp    %r14,%r12
  jne    L131
L31:
  mov    %ebp,%eax
  and    $0xf,%eax
  je     L87
  mov    %ebp,%r12d
  cmp    $0xf,%eax
  je     L152
  lea    D29(%rip),%r13
  nopl   0x0(%rax)
L135:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  mov    %r12d,%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  jne    L135
L152:
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0xf(%r12),%eax
  cmp    %eax,%ebp
  jle    L51
  cltq
  sub    $0x10,%r12d
  add    %rax,%rbx
  sub    %ebx,%r12d
  nopl   0x0(%rax)
L25:
  movzbl (%rbx),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5f,%al
  jbe    L40
  mov    $0x2e,%edi
L40:
  call   <putchar@plt>
  add    $0x1,%rbx
  lea    (%r12,%rbx,1),%eax
  cmp    0xc(%rsp),%eax
  jl     L25
L51:
  lea    D27(%rip),%rdi
  call   <puts@plt>
L87:
  add    $0x18,%rsp
  mov    %ebp,%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
  nopl   0x0(%rax)
L147:
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  lea    -0xf(%r14),%r15
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L126:
  movzbl (%rbx,%r15,1),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5f,%al
  jbe    L4
  mov    $0x2e,%edi
L4:
  call   <putchar@plt>
  add    $0x1,%r15
  cmp    %r14d,%r15d
  jle    L126
  lea    D27(%rip),%rdi
  call   <puts@plt>
  jmp    L36
L96:
  xor    %ebp,%ebp
  jmp    L87
```

tool_calls: name: disassemble_data
arguments: label: D78
datatype: string
name: disassemble_data
arguments: label: D60
datatype: string
name: disassemble_data
arguments: label: D29
datatype: string
name: disassemble_data
arguments: label: D67
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D32
datatype: string
name: disassemble_data
arguments: label: D51
datatype: string

tool: D78: %02x 

tool: D60: %08x  %02x 

tool: D29:    

tool: D67:     |

tool: D27: |

tool: D32: %08x


tool: D51: %02x  |

assistant: ```c
void printDump(const unsigned char *buffer, int count) {
  int i, j;
  int i2;
  int bytesPerLine = 16;
  for (i = 0; i < count; i++) {
    if ((i % bytesPerLine) == 0) {
      printf("%08x  %02x ", i, buffer[i]);
    } else if ((i % bytesPerLine) == (bytesPerLine - 1)) {
      printf("%02x  |", buffer[i]);
      for (j = i - (bytesPerLine - 1); j <= i; j++) {
        if ((buffer[j] > 31) && (buffer[j] < 128)) {
          printf("%c", buffer[j]);
        } else {
          printf(".");
        }
      }
      printf("|\n");
    } else {
      printf("%02x ", buffer[i]);
    }
  }
  if ((i % bytesPerLine) != 0) {
    i2 = i;
    for (i2 = i; (i2 % bytesPerLine) != (bytesPerLine - 1); i2++) {
      printf("   ");
    }
    printf("    |");
    i2 -= (bytesPerLine - 1);
    for (j = i2; j < i; j++) {
      if ((buffer[j] > 31) && (buffer[j] < 128)) {
        printf("%c", buffer[j]);
      } else {
        printf(".");
      }
    }
    printf("|\n");
  }
  printf("%08x\n", i);
  return;
}
```