ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<charger_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: Charnger close


assistant: ```c
int charger_close() {
  printf("Charnger close\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<charger_close>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: Charnger close


assistant: ```c
int charger_close() {
  printf("Charnger close\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<charger_close>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Charnger close


assistant: ```c
int charger_close() {
  printf("Charnger close\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<charger_close>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: Charnger close


assistant: ```c
int charger_close() {
  printf("Charnger close\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L15:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L16:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L15
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *dst, const void *src, unsigned int len) {
  const char *s = src;
  char *d = dst;
  while (len--)
    *d++ = *s++;
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  je     L9
  mov    %edi,%edi
  mov    $0x0,%edx
L14:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L14
L9:
  ret
```

assistant: ```c
void *memcpy(void *dst, const void *src, unsigned int len) {
  const char *s = src;
  char *d = dst;
  while (len--)
    *d++ = *s++;
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L18
  mov    %edx,%edx
  xor    %ecx,%ecx
  nop
L15:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L15
L18:
  ret
```

assistant: ```c
void *memcpy(void *dst, const void *src, unsigned int len) {
  const char *s = src;
  char *d = dst;
  while (len--)
    *d++ = *s++;
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%r10d
  test   %edx,%edx
  je     L86
  lea    0x1(%rsi),%rsi
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    $0xe,%rax
  jbe    L19
  cmp    $0x6,%r10d
  jbe    L19
  cmp    $0xe,%r10d
  jbe    L66
  mov    %edx,%esi
  xor    %eax,%eax
  shr    $0x4,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L139:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L139
  mov    %edx,%r9d
  and    $0xfffffff0,%r9d
  mov    %r9d,%edi
  sub    %r9d,%r10d
  lea    (%rcx,%rdi,1),%rsi
  lea    (%r8,%rdi,1),%rax
  cmp    %r9d,%edx
  je     L86
  sub    %r9d,%edx
  lea    -0x1(%rdx),%r9d
  cmp    $0x6,%r9d
  jbe    L154
L20:
  mov    (%rcx,%rdi,1),%rcx
  mov    %rcx,(%r8,%rdi,1)
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%edi
  sub    %ecx,%r10d
  add    %rdi,%rsi
  add    %rdi,%rax
  cmp    %ecx,%edx
  je     L86
L154:
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  test   %r10d,%r10d
  je     L86
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  cmp    $0x1,%r10d
  je     L86
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  cmp    $0x2,%r10d
  je     L86
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  cmp    $0x3,%r10d
  je     L86
  movzbl 0x4(%rsi),%edx
  mov    %dl,0x4(%rax)
  cmp    $0x4,%r10d
  je     L86
  movzbl 0x5(%rsi),%edx
  mov    %dl,0x5(%rax)
  cmp    $0x5,%r10d
  je     L86
  movzbl 0x6(%rsi),%edx
  mov    %dl,0x6(%rax)
L86:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L19:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  mov    %r8,%rax
  ret
L66:
  mov    %rdi,%rax
  mov    %rcx,%rsi
  xor    %edi,%edi
  jmp    L20
```

assistant: ```c
void *memcpy(void *dst, const void *src, unsigned int len) {
  const char *s = src;
  char *d = dst;
  while (len--)
    *d++ = *s++;
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_putnbr_X>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  jbe    L19
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edi
  call   <ft_putnbr_X>
L19:
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  add    $0x30,%eax
  cmp    $0x39,%eax
  jbe    L12
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  add    $0x37,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  jmp    L22
L12:
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  add    $0x30,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L22:
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbr_X(unsigned int n) {
  if (n > 15)
    ft_putnbr_X(n / 16);
  if ((n % 16) + 48 > '9')
    ft_putchar((n % 16) + 55);
  else
    ft_putchar((n % 16) + 48);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_putnbr_X>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xf,%edi
  ja     L2
L0:
  and    $0xf,%ebx
  lea    0x30(%rbx),%edi
  cmp    $0x39,%edi
  jbe    L13
  lea    0x37(%rbx),%edi
  call   <ft_putchar@plt>
L30:
  pop    %rbx
  ret
L2:
  shr    $0x4,%edi
  call   <ft_putnbr_X>
  jmp    L0
L13:
  call   <ft_putchar@plt>
  jmp    L30
```

assistant: ```c
void ft_putnbr_X(unsigned int n) {
  if (n > 15)
    ft_putnbr_X(n / 16);
  if ((n % 16) + 48 > '9')
    ft_putchar((n % 16) + 55);
  else
    ft_putchar((n % 16) + 48);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_putnbr_X>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xf,%edi
  ja     L77
L108:
  and    $0xf,%ebx
  lea    0x30(%rbx),%edi
  cmp    $0x39,%edi
  jbe    L2
  lea    0x37(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  nopl   0x0(%rax)
L77:
  mov    %edi,%ebp
  shr    $0x4,%ebp
  cmp    $0xff,%edi
  ja     L43
L109:
  mov    %ebp,%edi
  and    $0xf,%edi
  lea    0x30(%rdi),%r8d
  cmp    $0x39,%r8d
  jbe    L11
  add    $0x37,%edi
  call   <ft_putchar@plt>
  jmp    L108
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %r8d,%edi
  call   <ft_putchar@plt>
  jmp    L108
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %edi,%r12d
  shr    $0x8,%r12d
  cmp    $0xfff,%edi
  ja     L83
L35:
  mov    %r12d,%edi
  and    $0xf,%edi
  lea    0x30(%rdi),%r8d
  cmp    $0x39,%r8d
  jbe    L13
  add    $0x37,%edi
  call   <ft_putchar@plt>
  jmp    L109
  nopl   0x0(%rax)
L13:
  mov    %r8d,%edi
  call   <ft_putchar@plt>
  jmp    L109
  nopw   0x0(%rax,%rax,1)
L83:
  shr    $0xc,%edi
  call   <ft_putnbr_X>
  jmp    L35
```

assistant: ```c
void ft_putnbr_X(unsigned int n) {
  if (n > 15)
    ft_putnbr_X(n / 16);
  if ((n % 16) + 48 > '9')
    ft_putchar((n % 16) + 55);
  else
    ft_putchar((n % 16) + 48);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_putnbr_X>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xf,%edi
  ja     L61
L77:
  and    $0xf,%ebx
  lea    0x30(%rbx),%edi
  cmp    $0x39,%edi
  jbe    L9
  lea    0x37(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  nopl   0x0(%rax)
L61:
  mov    %edi,%ebp
  shr    $0x4,%ebp
  cmp    $0xff,%edi
  ja     L80
L40:
  mov    %ebp,%edi
  and    $0xf,%edi
  lea    0x30(%rdi),%r8d
  cmp    $0x39,%r8d
  jbe    L94
  add    $0x37,%edi
  call   <ft_putchar@plt>
  jmp    L77
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    %r8d,%edi
  call   <ft_putchar@plt>
  jmp    L77
  nopw   0x0(%rax,%rax,1)
L80:
  mov    %edi,%r12d
  shr    $0x8,%r12d
  cmp    $0xfff,%edi
  ja     L79
L44:
  mov    %r12d,%edi
  and    $0xf,%edi
  lea    0x30(%rdi),%r8d
  cmp    $0x39,%r8d
  jbe    L58
  add    $0x37,%edi
  call   <ft_putchar@plt>
  jmp    L40
  nopl   0x0(%rax)
L58:
  mov    %r8d,%edi
  call   <ft_putchar@plt>
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L79:
  shr    $0xc,%edi
  call   <ft_putnbr_X>
  jmp    L44
```

assistant: ```c
void ft_putnbr_X(unsigned int n) {
  if (n > 15)
    ft_putnbr_X(n / 16);
  if ((n % 16) + 48 > '9')
    ft_putchar((n % 16) + 55);
  else
    ft_putchar((n % 16) + 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %rdx,-0x438(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L20
L19:
  mov    -0x418(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x430(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x418(%rbp)
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x438(%rbp),%rdx
  mov    -0x428(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x410(%rbp),%rdx
  mov    -0x428(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L20:
  mov    -0x430(%rbp),%rdx
  mov    -0x428(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L19
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void strchg(char *buf, const char *target, const char *repl) {
  char tmp[1024 + 1];
  char *p;
  while ((p = strstr(buf, target)) != NULL) {
    *p = '\0';
    p += strlen(target);
    strcpy(tmp, p);
    strcat(buf, repl);
    strcat(buf, tmp);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strchg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  jmp    L14
L5:
  movb   $0x0,(%rbx)
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  add    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L5
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strchg(char *buf, const char *target, const char *repl) {
  char tmp[1024 + 1];
  char *p;
  while ((p = strstr(buf, target)) != NULL) {
    *p = '\0';
    p += strlen(target);
    strcpy(tmp, p);
    strcat(buf, repl);
    strcat(buf, tmp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strchg>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  jmp    L27
  nopl   0x0(%rax)
L12:
  movb   $0x0,(%rbx)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  cltq
  lea    (%rbx,%rax,1),%rsi
  call   <strcpy@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L27:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L12
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strchg(char *buf, const char *target, const char *repl) {
  char tmp[1024 + 1];
  char *p;
  while ((p = strstr(buf, target)) != NULL) {
    *p = '\0';
    p += strlen(target);
    strcpy(tmp, p);
    strcat(buf, repl);
    strcat(buf, tmp);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strchg>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  jmp    L18
  nopl   0x0(%rax)
L13:
  movb   $0x0,(%rbx)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  cltq
  lea    (%rbx,%rax,1),%rsi
  call   <strcpy@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L13
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strchg(char *buf, const char *target, const char *repl) {
  char tmp[1024 + 1];
  char *p;
  while ((p = strstr(buf, target)) != NULL) {
    *p = '\0';
    p += strlen(target);
    strcpy(tmp, p);
    strcat(buf, repl);
    strcat(buf, tmp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<recv_control>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L4
  movzbl -0xd(%rbp),%eax
  movzbl %al,%eax
  jmp    L24
L4:
  mov    $0xffffffff,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int recv_control(int fd) {
  unsigned char c;
  const ssize_t size = read(fd, &c, sizeof(c));
  if (size == sizeof(c))
    return c;
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<recv_control>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L18
  movzbl 0x7(%rsp),%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L10
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recv_control(int fd) {
  unsigned char c;
  const ssize_t size = read(fd, &c, sizeof(c));
  if (size == sizeof(c))
    return c;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recv_control>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L9
  movzbl 0x7(%rsp),%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  jmp    L8
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recv_control(int fd) {
  unsigned char c;
  const ssize_t size = read(fd, &c, sizeof(c));
  if (size == sizeof(c))
    return c;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<recv_control>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L5
  movzbl 0x7(%rsp),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recv_control(int fd) {
  unsigned char c;
  const ssize_t size = read(fd, &c, sizeof(c));
  if (size == sizeof(c))
    return c;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L2:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L2
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverse_string(char *test_string, int string_size) {
  char *pb = test_string;
  char *pe = pb + string_size;
  while (pb < pe) {
    swap(pb, pe);
    pb++;
    pe--;
  }
  return test_string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movslq %esi,%rbx
  add    %rdi,%rbx
  cmp    %rbx,%rdi
  jae    L2
  mov    %rdi,%rbp
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x1,%rbp
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jb     L0
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reverse_string(char *test_string, int string_size) {
  char *pb = test_string;
  char *pe = pb + string_size;
  while (pb < pe) {
    swap(pb, pe);
    pb++;
    pe--;
  }
  return test_string;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reverse_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  add    %rdi,%rbx
  cmp    %rbx,%rdi
  jae    L11
  mov    %rdi,%rbp
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  add    $0x1,%rbp
  call   <swap@plt>
  cmp    %rbx,%rbp
  jb     L4
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reverse_string(char *test_string, int string_size) {
  char *pb = test_string;
  char *pe = pb + string_size;
  while (pb < pe) {
    swap(pb, pe);
    pb++;
    pe--;
  }
  return test_string;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  add    %rdi,%rbx
  cmp    %rbx,%rdi
  jae    L9
  mov    %rdi,%rbp
  nopl   0x0(%rax)
L11:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  add    $0x1,%rbp
  call   <swap@plt>
  cmp    %rbx,%rbp
  jb     L11
L9:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reverse_string(char *test_string, int string_size) {
  char *pb = test_string;
  char *pe = pb + string_size;
  while (pb < pe) {
    swap(pb, pe);
    pb++;
    pe--;
  }
  return test_string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<udev_device_add_property_from_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x30,%rsp
  mov    %rdi,-0x4028(%rbp)
  mov    %rsi,-0x4030(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4030(%rbp),%rdx
  lea    -0x4010(%rbp),%rax
  mov    $0x4000,%esi
  mov    %rax,%rdi
  call   <util_strscpy@plt>
  lea    -0x4010(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x4018(%rbp)
  cmpq   $0x0,-0x4018(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L37
L8:
  mov    -0x4018(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x4018(%rbp)
  mov    -0x4018(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  movq   $0x0,-0x4018(%rbp)
L6:
  mov    -0x4018(%rbp),%rdx
  lea    -0x4010(%rbp),%rcx
  mov    -0x4028(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <udev_device_add_property@plt>
L37:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
struct udev_list_entry *udev_device_add_property_from_string(struct udev_device *udev_device, const char *property) {
  char name[16384];
  char *val;
  util_strscpy(name, sizeof(name), property);
  val = strchr(name, '=');
  if (val == NULL)
    return NULL;
  val[0] = '\0';
  val = &val[1];
  if (val[0] == '\0')
    val = NULL;
  return udev_device_add_property(udev_device, name, val);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<udev_device_add_property_from_string>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x4000,%esi
  mov    %rbp,%rdi
  call   <util_strscpy@plt>
  mov    $0x3d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
  mov    $0x0,%edx
  cmpb   $0x0,0x1(%rax)
  je     L1
  lea    0x1(%rax),%rdx
L1:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <udev_device_add_property@plt>
L8:
  mov    0x4008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x4018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct udev_list_entry *udev_device_add_property_from_string(struct udev_device *udev_device, const char *property) {
  char name[16384];
  char *val;
  util_strscpy(name, sizeof(name), property);
  val = strchr(name, '=');
  if (val == NULL)
    return NULL;
  val[0] = '\0';
  val = &val[1];
  if (val[0] == '\0')
    val = NULL;
  return udev_device_add_property(udev_device, name, val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<udev_device_add_property_from_string>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rsi,%rdx
  mov    %rdi,%rbp
  mov    $0x4000,%esi
  mov    %r12,%rdi
  call   <util_strscpy@plt>
  mov    $0x3d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L29
  xor    %edx,%edx
  cmpb   $0x0,0x1(%rax)
  movb   $0x0,(%rax)
  jne    L1
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <udev_device_add_property@plt>
L29:
  mov    0x4008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x4018,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0x1(%rax),%rdx
  jmp    L26
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct udev_list_entry *udev_device_add_property_from_string(struct udev_device *udev_device, const char *property) {
  char name[16384];
  char *val;
  util_strscpy(name, sizeof(name), property);
  val = strchr(name, '=');
  if (val == NULL)
    return NULL;
  val[0] = '\0';
  val = &val[1];
  if (val[0] == '\0')
    val = NULL;
  return udev_device_add_property(udev_device, name, val);
}
```