ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string

tool: D14: tochar - turns numbers into characters

tool: D37: usage: %s <number>


tool: D29: 	where <number> is the numeric ascii value of the character you want.

tool: D12: 	accepts decimal (NNN), hexidecimal (0xNN), or octal (0NNN)

assistant: ```c
void usage(char *exe) {
  printf("tochar - turns numbers into characters\n");
  printf("usage: %s <number>\n", exe);
  printf("\twhere <number> is the numeric ascii value of the character you want.\n");
  printf("\taccepts decimal (NNN), hexidecimal (0xNN), or octal (0NNN)\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getche@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D30
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string

tool: D30: (getche example) please type a letter: 

tool: D20: 
You typed: %c


tool: D17: (getch example) please type a letter...

assistant: ```c
int main(void) {
  char c;
  printf("(getche example) please type a letter: ");
  c = getche();
  printf("\nYou typed: %c\n", c);
  printf("(getch example) please type a letter...");
  c = getch();
  printf("\nYou typed: %c\n", c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getche@plt>
  movsbl %al,%esi
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  movsbl %al,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
data_type: string
name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D20
data_type: string

tool: D13: (getche example) please type a letter: 

tool: D24: 
You typed: %c


tool: D20: (getch example) please type a letter...

assistant: ```c
int main(void) {
  char c;
  printf("(getche example) please type a letter: ");
  c = getche();
  printf("\nYou typed: %c\n", c);
  printf("(getch example) please type a letter...");
  c = getch();
  printf("\nYou typed: %c\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  lea    D14(%rip),%rbp
  call   <printf@plt>
  xor    %eax,%eax
  call   <getche@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D6: (getche example) please type a letter: 

tool: D14: 
You typed: %c


tool: D5: (getch example) please type a letter...

assistant: ```c
int main(void) {
  char c;
  printf("(getche example) please type a letter: ");
  c = getche();
  printf("\nYou typed: %c\n", c);
  printf("(getch example) please type a letter...");
  c = getch();
  printf("\nYou typed: %c\n", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  lea    D7(%rip),%rbp
  call   <printf@plt>
  xor    %eax,%eax
  call   <getche@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D29: (getche example) please type a letter: 

tool: D7: 
You typed: %c


tool: D8: (getch example) please type a letter...

assistant: ```c
int main(void) {
  char c;
  printf("(getche example) please type a letter: ");
  c = getche();
  printf("\nYou typed: %c\n", c);
  printf("(getch example) please type a letter...");
  c = getch();
  printf("\nYou typed: %c\n", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<qsimp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  movss  %xmm1,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L0
L1:
  mov    -0x14(%rbp),%ecx
  movss  -0x30(%rbp),%xmm0
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <trapzd@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x8(%rbp),%xmm1
  movsd  D39(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x10(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  cmpl   $0x5,-0x14(%rbp)
  jle    L12
  movss  -0x4(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movsd  %xmm0,-0x38(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movsd  D10(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  comisd -0x38(%rbp),%xmm0
  ja     L40
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L12
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jne    L12
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L12
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jne    L12
L40:
  movss  -0x4(%rbp),%xmm0
  jmp    L17
L12:
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L0:
  cmpl   $0x14,-0x14(%rbp)
  jle    L1
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D39
type_infered: f64
name: disassemble_data
arguments: data_label: D8
type_infered: f64
name: disassemble_data
arguments: data_label: D10
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D15
type_infered: string

tool: D39: 4

tool: D8: 3

tool: {"D10": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D15: Too many steps in routine qsimp

assistant: ```c
float qsimp(float (*func)(float), float a, float b) {
  float trapzd(float (*func)(float), float a, float b, int n);
  void nrerror(char error_text[]);
  int j;
  float s, st, ost = 0.0, os = 0.0;
  for (j = 1; j <= 20; j++) {
    st = trapzd(func, a, b, j);
    s = (4.0 * st - ost) / 3.0;
    if (j > 5)
      if (fabs(s - os) < 1.0e-6 * fabs(os) || (s == 0.0 && os == 0.0))
        return s;
    os = s;
    ost = st;
  }
  nrerror("Too many steps in routine qsimp");
  return 0.0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<qsimp>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  movss  %xmm0,0x18(%rsp)
  movss  %xmm1,0x1c(%rsp)
  mov    $0x1,%esi
  call   <trapzd@plt>
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  mulsd  D21(%rip),%xmm0
  divsd  D11(%rip),%xmm0
  pxor   %xmm7,%xmm7
  cvtsd2ss %xmm0,%xmm7
  movss  %xmm7,0x10(%rsp)
  mov    $0x1,%ebx
  jmp    L6
L27:
  movss  0xc(%rsp),%xmm4
  movss  %xmm4,0x10(%rsp)
  movss  0x14(%rsp),%xmm5
  movss  %xmm5,0xc(%rsp)
L6:
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  je     L11
  mov    %ebx,%esi
  movss  0x1c(%rsp),%xmm1
  movss  0x18(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <trapzd@plt>
  movss  %xmm0,0x14(%rsp)
  cvtss2sd %xmm0,%xmm0
  mulsd  D21(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  subsd  %xmm1,%xmm0
  divsd  D11(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0xc(%rsp)
  cmp    $0x5,%ebx
  jle    L27
  subss  0x10(%rsp),%xmm0
  call   <fabs@plt>
  movq   %xmm0,%r14
  movss  0x10(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D38(%rip),%xmm0
  movq   %r14,%xmm6
  comisd %xmm6,%xmm0
  ja     L1
  movss  0xc(%rsp),%xmm2
  ucomiss D21(%rip),%xmm2
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  je     L27
  movss  0x10(%rsp),%xmm3
  ucomiss D21(%rip),%xmm3
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L27
  jmp    L1
L11:
  lea    D60(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm7,%xmm7
  movss  %xmm7,0xc(%rsp)
L1:
  movss  0xc(%rsp),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: f64
name: read_data
arguments: data_label: D11
datatype: f64
name: read_data
arguments: data_label: D38
datatype: byte[8]
name: read_data
arguments: data_label: D60
datatype: string

tool: D21: 4

tool: D11: 3

tool: {"D38": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D60: Too many steps in routine qsimp

assistant: ```c
float qsimp(float (*func)(float), float a, float b) {
  float trapzd(float (*func)(float), float a, float b, int n);
  void nrerror(char error_text[]);
  int j;
  float s, st, ost = 0.0, os = 0.0;
  for (j = 1; j <= 20; j++) {
    st = trapzd(func, a, b, j);
    s = (4.0 * st - ost) / 3.0;
    if (j > 5)
      if (fabs(s - os) < 1.0e-6 * fabs(os) || (s == 0.0 && os == 0.0))
        return s;
    os = s;
    ost = st;
  }
  nrerror("Too many steps in routine qsimp");
  return 0.0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qsimp>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  movd   %xmm0,%r14d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movss  %xmm1,0x8(%rsp)
  call   <trapzd@plt>
  pxor   %xmm6,%xmm6
  movss  0x8(%rsp),%xmm1
  movaps %xmm0,%xmm4
  cvtss2sd %xmm0,%xmm0
  mulsd  D14(%rip),%xmm0
  divsd  D24(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm6
  movss  %xmm6,0x10(%rsp)
  jmp    L10
  xchg   %ax,%ax
L48:
  mov    %r12d,%esi
  movd   %r14d,%xmm0
  mov    %rbx,%rdi
  movss  %xmm4,0x14(%rsp)
  movss  %xmm1,0x8(%rsp)
  call   <trapzd@plt>
  pxor   %xmm2,%xmm2
  cmp    $0x5,%r12d
  movss  0x14(%rsp),%xmm4
  cvtss2sd %xmm0,%xmm2
  mulsd  D14(%rip),%xmm2
  movss  0x8(%rsp),%xmm1
  movaps %xmm0,%xmm3
  cvtss2sd %xmm4,%xmm4
  subsd  %xmm4,%xmm2
  divsd  D24(%rip),%xmm2
  cvtsd2ss %xmm2,%xmm2
  jle    L27
  movss  %xmm0,0x18(%rsp)
  movaps %xmm2,%xmm0
  subss  0x10(%rsp),%xmm0
  movss  %xmm2,0x14(%rsp)
  movss  %xmm1,0x1c(%rsp)
  call   <fabs@plt>
  movsd  %xmm0,0x8(%rsp)
  movss  0x10(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D55(%rip),%xmm0
  movss  0x14(%rsp),%xmm2
  comisd 0x8(%rsp),%xmm0
  ja     L26
  pxor   %xmm7,%xmm7
  movss  0x18(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm1
  ucomiss %xmm7,%xmm2
  setnp  %al
  cmovne %ebp,%eax
  test   %al,%al
  je     L27
  movss  0x10(%rsp),%xmm5
  ucomiss %xmm7,%xmm5
  setnp  %al
  cmovne %ebp,%eax
  test   %al,%al
  jne    L26
L27:
  movss  %xmm2,0x10(%rsp)
  movaps %xmm3,%xmm4
L10:
  add    $0x1,%r12d
  cmp    $0x15,%r12d
  jne    L48
  lea    D33(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm2,%xmm2
L26:
  add    $0x28,%rsp
  movaps %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: f64
name: disassemble_data
arguments: label: D24
data_type: f64
name: disassemble_data
arguments: label: D55
data_type: byte[8]
name: disassemble_data
arguments: label: D33
data_type: string

tool: D14: 4

tool: D24: 3

tool: {"D55": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D33: Too many steps in routine qsimp

assistant: ```c
float qsimp(float (*func)(float), float a, float b) {
  float trapzd(float (*func)(float), float a, float b, int n);
  void nrerror(char error_text[]);
  int j;
  float s, st, ost = 0.0, os = 0.0;
  for (j = 1; j <= 20; j++) {
    st = trapzd(func, a, b, j);
    s = (4.0 * st - ost) / 3.0;
    if (j > 5)
      if (fabs(s - os) < 1.0e-6 * fabs(os) || (s == 0.0 && os == 0.0))
        return s;
    os = s;
    ost = st;
  }
  nrerror("Too many steps in routine qsimp");
  return 0.0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<qsimp>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  movd   %xmm0,%r14d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movss  %xmm1,0x8(%rsp)
  call   <trapzd@plt>
  pxor   %xmm6,%xmm6
  movss  0x8(%rsp),%xmm1
  movaps %xmm0,%xmm4
  cvtss2sd %xmm0,%xmm0
  mulsd  D25(%rip),%xmm0
  divsd  D45(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm6
  movss  %xmm6,0x10(%rsp)
  jmp    L42
  xchg   %ax,%ax
L1:
  mov    %r12d,%esi
  movd   %r14d,%xmm0
  mov    %rbx,%rdi
  movss  %xmm4,0x14(%rsp)
  movss  %xmm1,0x8(%rsp)
  call   <trapzd@plt>
  pxor   %xmm2,%xmm2
  cmp    $0x5,%r12d
  movss  0x14(%rsp),%xmm4
  cvtss2sd %xmm0,%xmm2
  mulsd  D25(%rip),%xmm2
  movss  0x8(%rsp),%xmm1
  movaps %xmm0,%xmm3
  cvtss2sd %xmm4,%xmm4
  subsd  %xmm4,%xmm2
  divsd  D45(%rip),%xmm2
  cvtsd2ss %xmm2,%xmm2
  jle    L39
  movss  %xmm0,0x18(%rsp)
  movaps %xmm2,%xmm0
  subss  0x10(%rsp),%xmm0
  movss  %xmm2,0x14(%rsp)
  movss  %xmm1,0x1c(%rsp)
  call   <fabs@plt>
  movsd  %xmm0,0x8(%rsp)
  movss  0x10(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D49(%rip),%xmm0
  movss  0x14(%rsp),%xmm2
  comisd 0x8(%rsp),%xmm0
  ja     L13
  pxor   %xmm7,%xmm7
  movss  0x18(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm1
  ucomiss %xmm7,%xmm2
  setnp  %al
  cmovne %ebp,%eax
  test   %al,%al
  je     L39
  movss  0x10(%rsp),%xmm5
  ucomiss %xmm7,%xmm5
  setnp  %al
  cmovne %ebp,%eax
  test   %al,%al
  jne    L13
L39:
  movss  %xmm2,0x10(%rsp)
  movaps %xmm3,%xmm4
L42:
  add    $0x1,%r12d
  cmp    $0x15,%r12d
  jne    L1
  lea    D20(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm2,%xmm2
L13:
  add    $0x28,%rsp
  movaps %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D25
data_type: f64
name: disassemble_data
arguments: data_label: D45
data_type: f64
name: disassemble_data
arguments: data_label: D49
data_type: byte[8]
name: disassemble_data
arguments: data_label: D20
data_type: string

tool: D25: 4

tool: D45: 3

tool: {"D49": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D20: Too many steps in routine qsimp

assistant: ```c
float qsimp(float (*func)(float), float a, float b) {
  float trapzd(float (*func)(float), float a, float b, int n);
  void nrerror(char error_text[]);
  int j;
  float s, st, ost = 0.0, os = 0.0;
  for (j = 1; j <= 20; j++) {
    st = trapzd(func, a, b, j);
    s = (4.0 * st - ost) / 3.0;
    if (j > 5)
      if (fabs(s - os) < 1.0e-6 * fabs(os) || (s == 0.0 && os == 0.0))
        return s;
    os = s;
    ost = st;
  }
  nrerror("Too many steps in routine qsimp");
  return 0.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jle    L34
  cmpl   $0x24,-0x34(%rbp)
  jle    L41
L34:
  cmpl   $0xfffffff6,-0x34(%rbp)
  je     L41
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  jmp    L92
L41:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpl   $0xfffffff6,-0x34(%rbp)
  jne    L35
  movl   $0xa,-0x34(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jns    L35
  negq   -0x28(%rbp)
  movl   $0x1,-0x1c(%rbp)
L35:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  cqto
  idiv   %rsi
  mov    %rax,-0x28(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  lea    0x23(%rax),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  lea    D2(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  jne    L35
  cmpl   $0x0,-0x1c(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x2d,(%rax)
L28:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
  jmp    L27
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x1d(%rbp),%edx
  mov    %dl,(%rax)
L27:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L39
  mov    -0x30(%rbp),%rax
L92:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *lltoa(long long value, char *result, int base) {
  if ((base < 2 || base > 36) && base != -10) {
    *result = '\0';
    return result;
  }
  char *pointer = result, *aux_pointer = result, tmp_char;
  long long tmp_value;
  bool negative = false;
  if (base == -10) {
    base = 10;
    if (value & (1LL << 63)) {
      value = (~value) + 1;
      negative = true;
    }
  }
  do {
    tmp_value = value;
    value /= base;
    *pointer++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (negative)
    *pointer++ = '-';
  *pointer-- = '\0';
  while (aux_pointer < pointer) {
    tmp_char = *pointer;
    *pointer-- = *aux_pointer;
    *aux_pointer++ = tmp_char;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lltoa>:
  endbr64
  mov    %rsi,%r10
  lea    -0x2(%rdx),%eax
  cmp    $0x22,%eax
  jbe    L2
  cmp    $0xfffffff6,%edx
  je     L2
  movb   $0x0,(%rsi)
  mov    %rsi,%rax
  ret
L2:
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  cmp    $0xfffffff6,%edx
  je     L81
L73:
  mov    %r10,%rsi
  movslq %edx,%rcx
  lea    D3(%rip),%r11
L13:
  mov    %rdi,%r8
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r9
  mov    %rax,%rdi
  mov    %rsi,%rbx
  add    $0x1,%rsi
  mov    %r8,%rax
  cqto
  idiv   %rcx
  movzbl 0x23(%r11,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  test   %r9,%r9
  jne    L13
  test   %ebp,%ebp
  je     L0
  movb   $0x2d,(%rsi)
  lea    0x2(%rbx),%rsi
L0:
  lea    -0x1(%rsi),%rax
  movb   $0x0,(%rsi)
  cmp    %rax,%r10
  jae    L7
  mov    %r10,%rdx
L68:
  movzbl (%rax),%ecx
  sub    $0x1,%rax
  movzbl (%rdx),%esi
  mov    %sil,0x1(%rax)
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rax
  ja     L68
L7:
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  ret
L81:
  mov    $0xa,%edx
  test   %rdi,%rdi
  jns    L73
  neg    %rdi
  mov    $0x1,%ebp
  jmp    L73
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *lltoa(long long value, char *result, int base) {
  if ((base < 2 || base > 36) && base != -10) {
    *result = '\0';
    return result;
  }
  char *pointer = result, *aux_pointer = result, tmp_char;
  long long tmp_value;
  bool negative = false;
  if (base == -10) {
    base = 10;
    if (value & (1LL << 63)) {
      value = (~value) + 1;
      negative = true;
    }
  }
  do {
    tmp_value = value;
    value /= base;
    *pointer++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (negative)
    *pointer++ = '-';
  *pointer-- = '\0';
  while (aux_pointer < pointer) {
    tmp_char = *pointer;
    *pointer-- = *aux_pointer;
    *aux_pointer++ = tmp_char;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lltoa>:
  endbr64
  lea    -0x2(%rdx),%ecx
  mov    %rdi,%rax
  mov    %rsi,%r9
  cmp    $0x22,%ecx
  jbe    L4
  cmp    $0xfffffff6,%edx
  je     L85
  movb   $0x0,(%rsi)
L52:
  mov    %r9,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  mov    $0xa,%edi
  xor    %r10d,%r10d
  test   %rax,%rax
  js     L87
L70:
  mov    %r9,%rsi
  lea    D9(%rip),%r8
  nop
L30:
  cqto
  mov    %rsi,%rcx
  add    $0x1,%rsi
  idiv   %rdi
  movzbl 0x23(%r8,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %rax,%rax
  jne    L30
  test   %r10d,%r10d
  je     L57
  lea    0x2(%rcx),%rax
  movb   $0x2d,(%rsi)
  mov    %rsi,%rcx
  mov    %rax,%rsi
L57:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  cmp    %rcx,%r9
  jae    L52
  nopw   0x0(%rax,%rax,1)
L61:
  movzbl (%rcx),%edx
  movzbl (%rax),%esi
  sub    $0x1,%rcx
  add    $0x1,%rax
  mov    %sil,0x1(%rcx)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  ja     L61
  mov    %r9,%rax
  ret
  xchg   %ax,%ax
L4:
  cmp    $0xfffffff6,%edx
  je     L85
  movslq %edx,%rdi
  xor    %r10d,%r10d
  jmp    L70
  nopl   (%rax)
L87:
  neg    %rax
  mov    $0x1,%r10d
  jmp    L70
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *lltoa(long long value, char *result, int base) {
  if ((base < 2 || base > 36) && base != -10) {
    *result = '\0';
    return result;
  }
  char *pointer = result, *aux_pointer = result, tmp_char;
  long long tmp_value;
  bool negative = false;
  if (base == -10) {
    base = 10;
    if (value & (1LL << 63)) {
      value = (~value) + 1;
      negative = true;
    }
  }
  do {
    tmp_value = value;
    value /= base;
    *pointer++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (negative)
    *pointer++ = '-';
  *pointer-- = '\0';
  while (aux_pointer < pointer) {
    tmp_char = *pointer;
    *pointer-- = *aux_pointer;
    *aux_pointer++ = tmp_char;
  }
  return result;
}
```