ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calc_posicao_lru>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L35
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L64
  mov    %esi,%ecx
  pcmpeqd %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  shr    $0x2,%ecx
  movdqa D17(%rip),%xmm2
  movdqa D0(%rip),%xmm5
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L16:
  movdqu (%rax),%xmm0
  movdqa %xmm2,%xmm1
  add    $0x10,%rax
  paddd  %xmm5,%xmm2
  pcmpgtd %xmm4,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm3,%xmm0
  movdqa %xmm0,%xmm3
  por    %xmm1,%xmm3
  cmp    %rax,%rcx
  jne    L16
  movdqa %xmm3,%xmm0
  xor    %ecx,%ecx
  psrldq $0x8,%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm3,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    $0xffffffff,%eax
  cmove  %ecx,%eax
  mov    %esi,%ecx
  and    $0xfffffffc,%ecx
  test   $0x3,%sil
  je     L20
L2:
  movslq %ecx,%rdi
  mov    (%rdx,%rdi,4),%r10d
  lea    0x0(,%rdi,4),%r8
  lea    0x1(%rcx),%edi
  test   %r10d,%r10d
  cmovg  %ecx,%eax
  cmp    %esi,%edi
  jge    L19
  mov    0x4(%rdx,%r8,1),%r9d
  test   %r9d,%r9d
  cmovle %eax,%edi
  lea    0x2(%rcx),%eax
  cmp    %eax,%esi
  jle    L58
  mov    0x8(%rdx,%r8,1),%edx
  test   %edx,%edx
  cmovle %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
L19:
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  ret
L64:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L2
L58:
  mov    %edi,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
data_type: byte[16]
name: disassemble_data
arguments: label: D0
data_type: byte[16]

tool: {"D17": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D0": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int calc_posicao_lru(int *vetor_acesso, int numero_de_quadros) {
  int cont_alloc, cont_result;
  int menor_acesso = 0;
  int indice;
  cont_result = 0;
  for (indice = 0; indice < numero_de_quadros; indice++) {
    if (menor_acesso < vetor_acesso[indice])
      cont_result = indice;
  }
  return cont_result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__put_unaligned_be16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __put_unaligned_be16(uint16_t val, uint8_t *p) {
  *p++ = val >> 8;
  *p++ = val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__put_unaligned_be16>:
  endbr64
  mov    %edi,%eax
  sar    $0x8,%eax
  mov    %eax,(%rsi)
  mov    %edi,0x4(%rsi)
  ret
```

assistant: ```c
void __put_unaligned_be16(uint16_t val, uint8_t *p) {
  *p++ = val >> 8;
  *p++ = val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__put_unaligned_be16>:
  endbr64
  mov    %edi,%eax
  mov    %edi,0x4(%rsi)
  sar    $0x8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void __put_unaligned_be16(uint16_t val, uint8_t *p) {
  *p++ = val >> 8;
  *p++ = val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__put_unaligned_be16>:
  endbr64
  mov    %edi,%eax
  movd   %edi,%xmm1
  sar    $0x8,%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsi)
  ret
```

assistant: ```c
void __put_unaligned_be16(uint16_t val, uint8_t *p) {
  *p++ = val >> 8;
  *p++ = val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix_all_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void matrix_all_free(void **m) {
  void *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_all_free>:
  endbr64
  push   %rbx
  mov    (%rdi),%rbx
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void matrix_all_free(void **m) {
  void *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matrix_all_free>:
  endbr64
  push   %rbp
  mov    (%rdi),%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void matrix_all_free(void **m) {
  void *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_all_free>:
  endbr64
  push   %rbp
  mov    (%rdi),%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void matrix_all_free(void **m) {
  void *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<blankstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L10
L44:
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L15
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L15
  movzbl (%rbx),%eax
  cmp    $0xd,%al
  je     L15
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L15
  mov    $0x0,%eax
  jmp    L64
L15:
  add    $0x1,%rbx
L10:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L44
  mov    $0x1,%eax
L64:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int blankstring(char *str) {
  register char *cp;
  for (cp = str; *cp; cp++) {
    if (*cp != ' ' && *cp != '\t' && *cp != '\r' && *cp != '\n')
      return (0);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blankstring>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  movabs $0x100002600,%rdx
  jmp    L29
L43:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L37
L29:
  cmp    $0x20,%al
  ja     L3
  bt     %rax,%rdx
  jb     L43
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int blankstring(char *str) {
  register char *cp;
  for (cp = str; *cp; cp++) {
    if (*cp != ' ' && *cp != '\t' && *cp != '\r' && *cp != '\n')
      return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<blankstring>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  movabs $0xfffffffeffffd9ff,%rdx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L29:
  bt     %rax,%rdx
  jb     L45
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L28
L17:
  cmp    $0x20,%al
  jbe    L29
L45:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int blankstring(char *str) {
  register char *cp;
  for (cp = str; *cp; cp++) {
    if (*cp != ' ' && *cp != '\t' && *cp != '\r' && *cp != '\n')
      return (0);
  }
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<blankstring>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  movabs $0xfffffffeffffd9ff,%rdx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L18:
  bt     %rax,%rdx
  jb     L41
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L11
L8:
  cmp    $0x20,%al
  jbe    L18
L41:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int blankstring(char *str) {
  register char *cp;
  for (cp = str; *cp; cp++) {
    if (*cp != ' ' && *cp != '\t' && *cp != '\r' && *cp != '\n')
      return (0);
  }
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UartRx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L3:
  mov    $0xfffd0014,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  mov    $0xfffd0018,%eax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
char UartRx(void) {
  while (((*((volatile unsigned int *)((0xFFFD0000 + 0x14)))) & 0x00000001) == 0)
    ;
  return (char)(*((volatile unsigned int *)((0xFFFD0000 + 0x18))));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UartRx>:
  endbr64
  mov    $0xfffd0014,%edx
L1:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L1
  movabs 0xfffd0018,%eax
  ret
```

assistant: ```c
char UartRx(void) {
  while (((*((volatile unsigned int *)((0xFFFD0000 + 0x14)))) & 0x00000001) == 0)
    ;
  return (char)(*((volatile unsigned int *)((0xFFFD0000 + 0x18))));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<UartRx>:
  endbr64
  mov    $0xfffd0014,%edx
  nopl   0x0(%rax)
L0:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L0
  movabs 0xfffd0018,%eax
  ret
```

assistant: ```c
char UartRx(void) {
  while (((*((volatile unsigned int *)((0xFFFD0000 + 0x14)))) & 0x00000001) == 0)
    ;
  return (char)(*((volatile unsigned int *)((0xFFFD0000 + 0x18))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<UartRx>:
  endbr64
  mov    $0xfffd0014,%edx
  nopl   0x0(%rax)
L0:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L0
  movabs 0xfffd0018,%eax
  ret
```

assistant: ```c
char UartRx(void) {
  while (((*((volatile unsigned int *)((0xFFFD0000 + 0x14)))) & 0x00000001) == 0)
    ;
  return (char)(*((volatile unsigned int *)((0xFFFD0000 + 0x18))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_prime_numbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L21
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x14(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L24
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L41:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime_number@plt>
  test   %rax,%rax
  je     L3
  addl   $0x1,-0x8(%rbp)
L3:
  addl   $0x2,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L41
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int count_prime_numbers(int a, int b) {
  int nprimes = 0;
  if (a <= 2) {
    nprimes = 1;
    a = 2;
  }
  if (a % 2 == 0)
    a++;
  for (int i = a; i <= b; i += 2) {
    if (is_prime_number(i))
      nprimes++;
  }
  return nprimes;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count_prime_numbers>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  cmp    $0x2,%edi
  jle    L54
  mov    %edi,%ebx
  test   $0x1,%dil
  je     L43
  mov    $0x0,%ebp
  jmp    L9
L43:
  mov    $0x0,%ebp
  jmp    L27
L54:
  mov    $0x1,%ebp
  mov    $0x2,%ebx
L27:
  add    $0x1,%ebx
L9:
  cmp    %ebx,%r12d
  jl     L19
L31:
  mov    %ebx,%edi
  call   <is_prime_number@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x2,%ebx
  cmp    %ebx,%r12d
  jge    L31
L19:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int count_prime_numbers(int a, int b) {
  int nprimes = 0;
  if (a <= 2) {
    nprimes = 1;
    a = 2;
  }
  if (a % 2 == 0)
    a++;
  for (int i = a; i <= b; i += 2) {
    if (is_prime_number(i))
      nprimes++;
  }
  return nprimes;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_prime_numbers>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x2,%edi
  jle    L31
  mov    %edi,%ebx
  test   $0x1,%dil
  je     L20
  xor    %r12d,%r12d
L58:
  cmp    %ebp,%ebx
  jg     L41
  xchg   %ax,%ax
L2:
  mov    %ebx,%edi
  call   <is_prime_number@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x2,%ebx
  cmp    %ebx,%ebp
  jge    L2
L41:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L31:
  mov    $0x3,%ebx
  mov    $0x1,%r12d
  jmp    L58
L20:
  add    $0x1,%ebx
  xor    %r12d,%r12d
  jmp    L58
```

assistant: ```c
int count_prime_numbers(int a, int b) {
  int nprimes = 0;
  if (a <= 2) {
    nprimes = 1;
    a = 2;
  }
  if (a % 2 == 0)
    a++;
  for (int i = a; i <= b; i += 2) {
    if (is_prime_number(i))
      nprimes++;
  }
  return nprimes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_prime_numbers>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x2,%edi
  jle    L13
  mov    %edi,%ebx
  test   $0x1,%dil
  je     L20
  xor    %r12d,%r12d
L44:
  cmp    %ebp,%ebx
  jg     L32
  xchg   %ax,%ax
L1:
  mov    %ebx,%edi
  call   <is_prime_number@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x2,%ebx
  cmp    %ebx,%ebp
  jge    L1
L32:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L13:
  mov    $0x3,%ebx
  mov    $0x1,%r12d
  jmp    L44
L20:
  add    $0x1,%ebx
  xor    %r12d,%r12d
  jmp    L44
```

assistant: ```c
int count_prime_numbers(int a, int b) {
  int nprimes = 0;
  if (a <= 2) {
    nprimes = 1;
    a = 2;
  }
  if (a % 2 == 0)
    a++;
  for (int i = a; i <= b; i += 2) {
    if (is_prime_number(i))
      nprimes++;
  }
  return nprimes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_line_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L107
  cmpq   $0x0,-0x20(%rbp)
  je     L107
  cmpl   $0x0,-0x24(%rbp)
  jle    L107
  mov    $0x1,%eax
  jmp    L71
L107:
  mov    $0x0,%eax
L71:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L29
L62:
  cmpl   $0x0,-0x24(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L3
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L109
L3:
  movl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x24(%rbp)
  jmp    L43
L109:
  cmpl   $0x0,-0xc(%rbp)
  jne    L95
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x24(%rbp)
L43:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  jmp    L69
L95:
  nop
L69:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_line_str(char *strBuff, char *input, int buffSize) {
  char *p = input;
  int sawEOLChar = 0;
  assert(strBuff != NULL && input != NULL && buffSize > 0);
  memset(strBuff, 0, (size_t)buffSize);
  while (*p) {
    assert(buffSize > 0);
    if (*p == '\r' || *p == '\n') {
      sawEOLChar = 1;
      *strBuff = *p;
      strBuff++;
      buffSize--;
    } else if (sawEOLChar) {
      break;
    } else {
      *strBuff = *p;
      strBuff++;
      buffSize--;
    }
    p++;
  }
  *strBuff = 0;
  return (char *)p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_line_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%r12d
  test   %rdi,%rdi
  setne  %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  movslq %r12d,%rdx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  cmpb   $0x0,0x0(%rbp)
  je     L36
  lea    0x1(%r13),%rbx
  sub    $0x1,%r12d
  mov    $0x0,%r14d
  mov    $0x1,%r15d
  jmp    L19
L3:
  mov    %rbx,%r13
  mov    %r15d,%r14d
L54:
  mov    %al,-0x1(%rbx)
  add    $0x1,%rbp
  add    $0x1,%rbx
  sub    $0x1,%r12d
  cmpb   $0x0,0x0(%rbp)
  je     L36
L19:
  lea    -0x1(%rbx),%r13
  lea    0x1(%r12),%eax
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl 0x0(%rbp),%eax
  cmp    $0xd,%al
  je     L3
  cmp    $0xa,%al
  je     L3
  test   %r14d,%r14d
  jne    L36
  mov    %rbx,%r13
  jmp    L54
L36:
  movb   $0x0,0x0(%r13)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *get_line_str(char *strBuff, char *input, int buffSize) {
  char *p = input;
  int sawEOLChar = 0;
  assert(strBuff != NULL && input != NULL && buffSize > 0);
  memset(strBuff, 0, (size_t)buffSize);
  while (*p) {
    assert(buffSize > 0);
    if (*p == '\r' || *p == '\n') {
      sawEOLChar = 1;
      *strBuff = *p;
      strBuff++;
      buffSize--;
    } else if (sawEOLChar) {
      break;
    } else {
      *strBuff = *p;
      strBuff++;
      buffSize--;
    }
    p++;
  }
  *strBuff = 0;
  return (char *)p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_line_str>:
  endbr64
  test   %rdi,%rdi
  push   %r14
  setne  %al
  test   %edx,%edx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  setg   %dl
  xor    %edi,%edi
  and    %edx,%eax
  push   %rbx
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  xor    %esi,%esi
  movslq %ebp,%rdx
  mov    %r13,%rdi
  call   <memset@plt>
  cmpb   $0x0,(%r12)
  je     L59
  lea    0x1(%r13),%rbx
  sub    $0x1,%ebp
  xor    %r14d,%r14d
  jmp    L8
  nopl   0x0(%rax)
L49:
  test   %r14d,%r14d
  jne    L59
  mov    %rbx,%r13
L52:
  add    $0x1,%r12
  mov    %al,-0x1(%rbx)
  sub    $0x1,%ebp
  add    $0x1,%rbx
  cmpb   $0x0,(%r12)
  je     L59
L8:
  lea    0x1(%rbp),%eax
  xor    %edi,%edi
  lea    -0x1(%rbx),%r13
  test   %eax,%eax
  setg   %dil
  call   <assert@plt>
  movzbl (%r12),%eax
  cmp    $0xd,%al
  je     L62
  cmp    $0xa,%al
  jne    L49
L62:
  mov    %rbx,%r13
  mov    $0x1,%r14d
  jmp    L52
  nopl   0x0(%rax)
L59:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *get_line_str(char *strBuff, char *input, int buffSize) {
  char *p = input;
  int sawEOLChar = 0;
  assert(strBuff != NULL && input != NULL && buffSize > 0);
  memset(strBuff, 0, (size_t)buffSize);
  while (*p) {
    assert(buffSize > 0);
    if (*p == '\r' || *p == '\n') {
      sawEOLChar = 1;
      *strBuff = *p;
      strBuff++;
      buffSize--;
    } else if (sawEOLChar) {
      break;
    } else {
      *strBuff = *p;
      strBuff++;
      buffSize--;
    }
    p++;
  }
  *strBuff = 0;
  return (char *)p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_line_str>:
  endbr64
  test   %rdi,%rdi
  push   %r14
  setne  %al
  test   %edx,%edx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  setg   %dl
  xor    %edi,%edi
  and    %edx,%eax
  push   %rbx
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  xor    %esi,%esi
  movslq %ebp,%rdx
  mov    %r13,%rdi
  call   <memset@plt>
  cmpb   $0x0,(%r12)
  je     L27
  lea    0x1(%r13),%rbx
  sub    $0x1,%ebp
  xor    %r14d,%r14d
  jmp    L37
  nopl   0x0(%rax)
L53:
  test   %r14d,%r14d
  jne    L27
  mov    %rbx,%r13
L49:
  add    $0x1,%r12
  mov    %al,-0x1(%rbx)
  sub    $0x1,%ebp
  add    $0x1,%rbx
  cmpb   $0x0,(%r12)
  je     L27
L37:
  lea    0x1(%rbp),%eax
  xor    %edi,%edi
  lea    -0x1(%rbx),%r13
  test   %eax,%eax
  setg   %dil
  call   <assert@plt>
  movzbl (%r12),%eax
  cmp    $0xd,%al
  je     L15
  cmp    $0xa,%al
  jne    L53
L15:
  mov    %rbx,%r13
  mov    $0x1,%r14d
  jmp    L49
  nopl   0x0(%rax)
L27:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *get_line_str(char *strBuff, char *input, int buffSize) {
  char *p = input;
  int sawEOLChar = 0;
  assert(strBuff != NULL && input != NULL && buffSize > 0);
  memset(strBuff, 0, (size_t)buffSize);
  while (*p) {
    assert(buffSize > 0);
    if (*p == '\r' || *p == '\n') {
      sawEOLChar = 1;
      *strBuff = *p;
      strBuff++;
      buffSize--;
    } else if (sawEOLChar) {
      break;
    } else {
      *strBuff = *p;
      strBuff++;
      buffSize--;
    }
    p++;
  }
  *strBuff = 0;
  return (char *)p;
}
```
user: What is the c source code of the assembly code below?

```asm
<arr2free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void arr2free(void **aa, const int n1, const int n2) {
  int i;
  for (i = 0; i < n1; i++) {
    free(aa[i]);
  }
  free(aa);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arr2free>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L3:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
L13:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arr2free(void **aa, const int n1, const int n2) {
  int i;
  for (i = 0; i < n1; i++) {
    free(aa[i]);
  }
  free(aa);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arr2free>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L12
L13:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void arr2free(void **aa, const int n1, const int n2) {
  int i;
  for (i = 0; i < n1; i++) {
    free(aa[i]);
  }
  free(aa);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arr2free>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L17
L11:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void arr2free(void **aa, const int n1, const int n2) {
  int i;
  for (i = 0; i < n1; i++) {
    free(aa[i]);
  }
  free(aa);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L14
  movss  -0x4(%rbp),%xmm0
  jmp    L9
L14:
  movss  -0x8(%rbp),%xmm0
L9:
  pop    %rbp
  ret
```

assistant: ```c
float max_f(float a, float b) {
  if (a > b)
    return a;
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_f>:
  endbr64
  maxss  %xmm1,%xmm0
  ret
```

assistant: ```c
float max_f(float a, float b) {
  if (a > b)
    return a;
  return b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<max_f>:
  endbr64
  maxss  %xmm1,%xmm0
  ret
```

assistant: ```c
float max_f(float a, float b) {
  if (a > b)
    return a;
  return b;
}
```