ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_idx>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <str_length@plt>
  test   %eax,%eax
  jle    L1
  cltq
  xor    %edx,%edx
  jmp    L30
  xchg   %ax,%ax
L8:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L1
L30:
  mov    %edx,%r8d
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L8
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int find_idx(char *s, char c) {
  int i, len;
  len = str_length(s);
  for (i = 0; i < len; i++) {
    if (s[i] == c) {
      return i;
    }
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_idx>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <str_length@plt>
  test   %eax,%eax
  jle    L0
  cltq
  xor    %edx,%edx
  jmp    L10
  xchg   %ax,%ax
L27:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L0
L10:
  mov    %edx,%r8d
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L27
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int find_idx(char *s, char c) {
  int i, len;
  len = str_length(s);
  for (i = 0; i < len; i++) {
    if (s[i] == c) {
      return i;
    }
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<filename_no_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L21
L15:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L20:
  mov    -0x10(%rbp),%rax
L21:
  leave
  ret
```

assistant: ```c
char *filename_no_ext(char *str) {
  if (str == NULL)
    return NULL;
  char *name = basename(str);
  char *retstr = strdup(name);
  char *lastdot = strrchr(retstr, '.');
  if (lastdot != NULL)
    *lastdot = '\0';
  return retstr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<filename_no_ext>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L23
  call   <basename@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L11
  movb   $0x0,(%rax)
L11:
  mov    %rbx,%rax
  pop    %rbx
  ret
L23:
  mov    %rdi,%rbx
  jmp    L11
```

assistant: ```c
char *filename_no_ext(char *str) {
  if (str == NULL)
    return NULL;
  char *name = basename(str);
  char *retstr = strdup(name);
  char *lastdot = strrchr(retstr, '.');
  if (lastdot != NULL)
    *lastdot = '\0';
  return retstr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<filename_no_ext>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L5
  call   <basename@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax)
L4:
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *filename_no_ext(char *str) {
  if (str == NULL)
    return NULL;
  char *name = basename(str);
  char *retstr = strdup(name);
  char *lastdot = strrchr(retstr, '.');
  if (lastdot != NULL)
    *lastdot = '\0';
  return retstr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<filename_no_ext>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L15
  call   <basename@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strrchr@plt>
  test   %rax,%rax
  je     L18
  movb   $0x0,(%rax)
L18:
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *filename_no_ext(char *str) {
  if (str == NULL)
    return NULL;
  char *name = basename(str);
  char *retstr = strdup(name);
  char *lastdot = strrchr(retstr, '.');
  if (lastdot != NULL)
    *lastdot = '\0';
  return retstr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dll_func@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  dll_func();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dll_func@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dll_func();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dll_func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dll_func();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dll_func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dll_func();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_167_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_167_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_167_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%edx
  or     %esi,%edx
  movzbl %dl,%edx
  xor    %esi,%edx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  not    %edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_167_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_167_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  or     %esi,%edx
  mov    %esi,%eax
  movzbl %dl,%edx
  not    %eax
  or     %edi,%eax
  xor    %esi,%edx
  not    %edi
  not    %edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_167_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xrop3_167_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  or     %esi,%edx
  mov    %esi,%eax
  movzbl %dl,%edx
  not    %eax
  or     %edi,%eax
  xor    %esi,%edx
  not    %edi
  not    %edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_167_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: string

tool: D26: %d

tool: D28: 
%d

assistant: ```c
int main() {
  int a, n;
  scanf("%d", &n);
  a = n;
  a = a * n;
  printf("\n%d", a);
  a = 0;
  a = n;
  a = a * n * n;
  printf("\n%d", a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  imul   %esi,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string

tool: D1: %d

tool: D7: 
%d

assistant: ```c
int main() {
  int a, n;
  scanf("%d", &n);
  a = n;
  a = a * n;
  printf("\n%d", a);
  a = 0;
  a = n;
  a = a * n * n;
  printf("\n%d", a);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string

tool: D5: %d

tool: D10: 
%d

assistant: ```c
int main() {
  int a, n;
  scanf("%d", &n);
  a = n;
  a = a * n;
  printf("\n%d", a);
  a = 0;
  a = n;
  a = a * n * n;
  printf("\n%d", a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string

tool: D11: %d

tool: D10: 
%d

assistant: ```c
int main() {
  int a, n;
  scanf("%d", &n);
  a = n;
  a = a * n;
  printf("\n%d", a);
  a = 0;
  a = n;
  a = a * n * n;
  printf("\n%d", a);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shl    $0x7,%rdx
  movabs $0x1b4334b500,%rax
  and    %rax,%rdx
  mov    %rdx,%rax
  rol    $0x20,%rax
  mov    %rdx,%rcx
  shr    $0x20,%rcx
  shl    $0x30,%rcx
  movabs $0xff00ffffffffffff,%rdi
  and    %rdi,%rax
  or     %rcx,%rax
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%al
  movabs $0xffffffffffffff,%rcx
  and    %rcx,%rax
  sar    $0x18,%edx
  mov    %dl,%ah
  movabs $0x7ffffffffffffff,%rdx
  and    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy12;
  char copy13;
  unsigned short copy14;
  unsigned int copy15;
  char copy16;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    if ((state[0UL] >> 1UL) & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        if ((state[0UL] >> 4UL) & 1UL) {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy13;
          copy13 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy13;
          copy14 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy14;
        }
      } else {
        state[0UL] >>= ((state[0UL] >> 1UL) & 7UL) | 1UL;
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      }
    } else {
      copy15 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy15;
      copy16 = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy16 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy16;
    }
    output[0UL] = (state[0UL] << 5UL) >> 5UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movabs $0x1b4334b500,%rax
  mov    (%rdi),%rdx
  movabs $0xff00ffffffffffff,%rdi
  shl    $0x7,%rdx
  and    %rax,%rdx
  mov    %rdx,%rax
  mov    %rdx,%rcx
  rol    $0x20,%rax
  shr    $0x20,%rcx
  shl    $0x30,%rcx
  and    %rdi,%rax
  or     %rcx,%rax
  mov    %edx,%ecx
  sar    $0x18,%edx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%al
  movabs $0xffffffffffffff,%rcx
  and    %rcx,%rax
  mov    %dl,%ah
  movabs $0x7ffffffffffffff,%rdx
  and    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy12;
  char copy13;
  unsigned short copy14;
  unsigned int copy15;
  char copy16;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    if ((state[0UL] >> 1UL) & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        if ((state[0UL] >> 4UL) & 1UL) {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy13;
          copy13 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy13;
          copy14 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy14;
        }
      } else {
        state[0UL] >>= ((state[0UL] >> 1UL) & 7UL) | 1UL;
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      }
    } else {
      copy15 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy15;
      copy16 = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy16 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy16;
    }
    output[0UL] = (state[0UL] << 5UL) >> 5UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  movabs $0x1b4334b500,%rdx
  mov    (%rdi),%rax
  mov    %rsi,%r8
  shl    $0x7,%rax
  and    %rdx,%rax
  movabs $0xffffffffffff,%rdx
  movq   %rax,%xmm1
  mov    %rax,%rcx
  pshufd $0xe1,%xmm1,%xmm0
  shr    $0x20,%rcx
  movq   %xmm0,%rsi
  shl    $0x30,%rcx
  and    %rsi,%rdx
  mov    %eax,%esi
  sar    $0x18,%eax
  shl    $0x8,%esi
  or     %rcx,%rdx
  xor    %ecx,%ecx
  sar    $0x18,%esi
  mov    %sil,%cl
  mov    %al,%ch
  movabs $0x7ffffffffffffff,%rax
  mov    %cx,%dx
  and    %rax,%rdx
  mov    %rdx,(%r8)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy12;
  char copy13;
  unsigned short copy14;
  unsigned int copy15;
  char copy16;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    if ((state[0UL] >> 1UL) & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        if ((state[0UL] >> 4UL) & 1UL) {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy13;
          copy13 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy13;
          copy14 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy14;
        }
      } else {
        state[0UL] >>= ((state[0UL] >> 1UL) & 7UL) | 1UL;
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      }
    } else {
      copy15 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy15;
      copy16 = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy16 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy16;
    }
    output[0UL] = (state[0UL] << 5UL) >> 5UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<debug_throw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <debug_log@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void debug_throw(unsigned int severity, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  debug_log(severity, fmt, args);
  va_end(args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<debug_throw>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <debug_log@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug_throw(unsigned int severity, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  debug_log(severity, fmt, args);
  va_end(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug_throw>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <debug_log@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void debug_throw(unsigned int severity, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  debug_log(severity, fmt, args);
  va_end(args);
}
```