ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<_to_sphere>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  push   0x18(%rdi)
  push   0x10(%rdi)
  push   0x8(%rdi)
  push   (%rdi)
  call   <atan2l@plt>
  add    $0x20,%rsp
  mov    %eax,%edi
  call   <deg@plt>
  sub    $0x10,%rsp
  fstpt  0x10(%rbp)
  fldt   0x20(%rbx)
  fdivs  0xe65(%rip)        # 2000 <_fini+0xe44>
  fstpt  (%rsp)
  call   <asin@plt>
  mov    %eax,%edi
  call   <deg@plt>
  mov    $0x1,%eax
  fstpt  0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _to_sphere(long double *x, long double *y) {
  y[1] = deg(atan2l(x[0], x[1]));
  y[0] = deg(asin(x[2] / 6371000.));
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<enc_callback_ctrl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_next@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L9
L14:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <BIO_callback_ctrl@plt>
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x10(%rbp),%rax
L9:
  leave
  ret
```

assistant: ```c
long enc_callback_ctrl(BIO *b, int cmd, bio_info_cb *fp) {
  long ret = 1;
  BIO *next = BIO_next(b);
  if (next == NULL)
    return (0);
  switch (cmd) {
  default:
    ret = BIO_callback_ctrl(next, cmd, fp);
    break;
  }
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<enc_callback_ctrl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %rdx,%rbp
  call   <BIO_next@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L3
  mov    %rbp,%rdx
  mov    %ebx,%esi
  call   <BIO_callback_ctrl@plt>
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long enc_callback_ctrl(BIO *b, int cmd, bio_info_cb *fp) {
  long ret = 1;
  BIO *next = BIO_next(b);
  if (next == NULL)
    return (0);
  switch (cmd) {
  default:
    ret = BIO_callback_ctrl(next, cmd, fp);
    break;
  }
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<enc_callback_ctrl>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <BIO_next@plt>
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <BIO_callback_ctrl@plt>
  xchg   %ax,%ax
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long enc_callback_ctrl(BIO *b, int cmd, bio_info_cb *fp) {
  long ret = 1;
  BIO *next = BIO_next(b);
  if (next == NULL)
    return (0);
  switch (cmd) {
  default:
    ret = BIO_callback_ctrl(next, cmd, fp);
    break;
  }
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<enc_callback_ctrl>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <BIO_next@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <BIO_callback_ctrl@plt>
  xchg   %ax,%ax
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long enc_callback_ctrl(BIO *b, int cmd, bio_info_cb *fp) {
  long ret = 1;
  BIO *next = BIO_next(b);
  if (next == NULL)
    return (0);
  switch (cmd) {
  default:
    ret = BIO_callback_ctrl(next, cmd, fp);
    break;
  }
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<merge>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L143:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L143
  sub    $0xc58,%rsp
  mov    %esi,%r11d
  mov    %edx,%r10d
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x9c48(%rsp)
  xor    %eax,%eax
  lea    0x1(%rdx),%ecx
  cmp    %edx,%esi
  jg     L57
  cmp    %ebx,%ecx
  jg     L57
  mov    %rsp,%r9
  mov    $0x1,%r8d
  jmp    L65
L114:
  add    $0x1,%ecx
  mov    %r8d,%eax
  mov    %ebp,%edx
L136:
  mov    %edx,(%r9)
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r10d,%esi
  jg     L14
  cmp    %ebx,%ecx
  jg     L14
L65:
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%edx
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%ebp
  cmp    %ebp,%edx
  jg     L114
  add    $0x1,%esi
  mov    %r8d,%eax
  jmp    L136
L57:
  mov    %r11d,%esi
  mov    $0x0,%eax
L14:
  cmp    %esi,%r10d
  jl     L43
  movslq %esi,%rdx
  movslq %eax,%r8
  sub    %rdx,%r8
  lea    (%rsp,%r8,4),%r9
L21:
  mov    (%rdi,%rdx,4),%r8d
  mov    %r8d,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jge    L21
  lea    0x1(%rax,%r10,1),%eax
  sub    %esi,%eax
L43:
  cmp    %ecx,%ebx
  jl     L18
  movslq %ecx,%rdx
  movslq %eax,%rsi
  sub    %rdx,%rsi
  lea    (%rsp,%rsi,4),%r8
L53:
  mov    (%rdi,%rdx,4),%esi
  mov    %esi,(%r8,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jge    L53
  sub    %ecx,%eax
  lea    0x1(%rax,%rbx,1),%eax
L18:
  sub    $0x1,%eax
  js     L147
  cltq
  movslq %r11d,%r11
  lea    (%rdi,%r11,4),%rcx
L90:
  mov    (%rsp,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L90
L147:
  mov    0x9c48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  add    $0x9c58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L106:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int a[], int low, int mid, int high) {
  int b[10000];
  int i = low, j = mid + 1, k = 0;
  while (i <= mid && j <= high) {
    if (a[i] <= a[j])
      b[k++] = a[i++];
    else
      b[k++] = a[j++];
  }
  while (i <= mid)
    b[k++] = a[i++];
  while (j <= high)
    b[k++] = a[j++];
  k--;
  while (k >= 0) {
    a[low + k] = b[k];
    k--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<merge>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L126:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L126
  sub    $0xc50,%rsp
  mov    %edx,%eax
  movslq %esi,%r8
  mov    %ecx,%r10d
  mov    %fs:0x28,%rdx
  mov    %rdx,0x9c48(%rsp)
  xor    %edx,%edx
  lea    0x1(%rax),%r12d
  mov    %r8d,%esi
  mov    %r12d,%r9d
  cmp    %eax,%r8d
  jg     L191
  cmp    %ecx,%r12d
  jg     L191
  mov    $0x1,%edx
  mov    %rsp,%rbx
  jmp    L152
  nopl   0x0(%rax)
L62:
  mov    %r11d,%ecx
  add    $0x1,%esi
  mov    %ecx,-0x4(%rbx,%rdx,4)
  add    $0x1,%rdx
  cmp    %eax,%esi
  jg     L35
L0:
  cmp    %r10d,%r9d
  jg     L35
L152:
  movslq %esi,%rcx
  mov    %edx,%ebp
  mov    (%rdi,%rcx,4),%r11d
  movslq %r9d,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,%r11d
  jle    L62
  mov    %ecx,-0x4(%rbx,%rdx,4)
  add    $0x1,%r9d
  add    $0x1,%rdx
  cmp    %eax,%esi
  jle    L0
L35:
  cmp    %esi,%eax
  jl     L11
L64:
  movslq %esi,%rcx
  movslq %ebp,%rdx
  mov    %rsp,%rbx
  sub    %rcx,%rdx
  lea    (%rbx,%rdx,4),%r11
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rdi,%rcx,4),%edx
  mov    %edx,(%r11,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%eax
  jge    L17
  add    %ebp,%r12d
  sub    %esi,%eax
  sub    %esi,%r12d
  add    %ebp,%eax
  cmp    %r9d,%r10d
  jl     L146
L111:
  movslq %r9d,%rax
  movslq %r12d,%rdx
  sub    %rax,%rdx
  lea    (%rbx,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L104:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r10d
  jge    L104
  mov    %r10d,%eax
  xor    %ecx,%ecx
  sub    %r9d,%eax
  cmp    %r9d,%r10d
  cmovl  %ecx,%eax
  add    %r12d,%eax
  cltq
L192:
  lea    (%rdi,%r8,4),%rcx
  jmp    L199
  nopl   0x0(%rax,%rax,1)
L124:
  mov    (%rsp,%rax,4),%edx
L199:
  mov    %edx,(%rcx,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L124
L139:
  mov    0x9c48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  add    $0x9c50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L191:
  xor    %ebp,%ebp
  cmp    %esi,%eax
  jge    L64
  nopw   0x0(%rax,%rax,1)
L11:
  cmp    %r9d,%r10d
  jge    L56
  lea    -0x1(%rbp),%eax
  test   %ebp,%ebp
  je     L139
  cltq
  mov    (%rsp,%rax,4),%edx
  jmp    L192
L56:
  mov    %ebp,%r12d
  mov    %rsp,%rbx
  jmp    L111
L120:
  call   <__stack_chk_fail@plt>
L146:
  cltq
  jmp    L192
```

assistant: ```c
void merge(int a[], int low, int mid, int high) {
  int b[10000];
  int i = low, j = mid + 1, k = 0;
  while (i <= mid && j <= high) {
    if (a[i] <= a[j])
      b[k++] = a[i++];
    else
      b[k++] = a[j++];
  }
  while (i <= mid)
    b[k++] = a[i++];
  while (j <= high)
    b[k++] = a[j++];
  k--;
  while (k >= 0) {
    a[low + k] = b[k];
    k--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<splitnext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L52
L114:
  addq   $0x1,-0x10(%rbp)
L52:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L114
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L114
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L118
L137:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L1
  addq   $0x1,-0x10(%rbp)
  jmp    L154
L48:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L79
  addq   $0x1,-0x10(%rbp)
L79:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L154
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L154:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L97
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L48
L97:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L118
  addq   $0x1,-0x10(%rbp)
  jmp    L118
L1:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L96
  addq   $0x1,-0x10(%rbp)
L96:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L118:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L172
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L172
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L137
  jmp    L172
L5:
  addq   $0x1,-0x10(%rbp)
L172:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L5
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *splitnext(char **pos) {
  char *a, *d, *s;
  s = *pos;
  while (*s == ' ' || *s == '\t')
    s++;
  a = d = s;
  while (*s && *s != ' ' && *s != '\t') {
    if (*s == '"') {
      s++;
      while (*s && *s != '"') {
        if (*s == '\\')
          s++;
        if (*s)
          *(d++) = *(s++);
      }
      if (*s == '"')
        s++;
    } else {
      if (*s == '\\')
        s++;
      *(d++) = *(s++);
    }
  }
  while (*s == ' ' || *s == '\t')
    s++;
  *d = 0;
  *pos = s;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<splitnext>:
  endbr64
  mov    (%rdi),%rcx
  movzbl (%rcx),%eax
  cmp    $0x20,%al
  je     L114
  cmp    $0x9,%al
  jne    L87
L114:
  add    $0x1,%rcx
  movzbl (%rcx),%eax
  cmp    $0x20,%al
  je     L114
  cmp    $0x9,%al
  je     L114
L87:
  movzbl (%rcx),%edx
  test   $0xdf,%dl
  je     L48
  mov    %rcx,%rax
  mov    %rcx,%rsi
  cmp    $0x9,%dl
  jne    L64
L48:
  mov    %rcx,%rsi
  mov    %rcx,%rax
  jmp    L70
L57:
  add    $0x1,%rax
  jmp    L29
L66:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L34
L29:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L162
  cmp    $0x22,%dl
  je     L162
  cmp    $0x5c,%dl
  je     L66
  movzbl (%rax),%edx
L34:
  add    $0x1,%rax
  add    $0x1,%rsi
  mov    %dl,-0x1(%rsi)
  jmp    L29
L162:
  cmp    $0x22,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
L30:
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L190
  cmp    $0x9,%dl
  je     L190
L64:
  cmp    $0x22,%dl
  je     L57
  cmp    $0x5c,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    %dl,(%rsi)
  lea    0x1(%rax),%rax
  lea    0x1(%rsi),%rsi
  jmp    L30
L190:
  cmp    $0x20,%dl
  je     L121
  cmp    $0x9,%dl
  jne    L70
L121:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L121
  cmp    $0x9,%dl
  je     L121
L70:
  movb   $0x0,(%rsi)
  mov    %rax,(%rdi)
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *splitnext(char **pos) {
  char *a, *d, *s;
  s = *pos;
  while (*s == ' ' || *s == '\t')
    s++;
  a = d = s;
  while (*s && *s != ' ' && *s != '\t') {
    if (*s == '"') {
      s++;
      while (*s && *s != '"') {
        if (*s == '\\')
          s++;
        if (*s)
          *(d++) = *(s++);
      }
      if (*s == '"')
        s++;
    } else {
      if (*s == '\\')
        s++;
      *(d++) = *(s++);
    }
  }
  while (*s == ' ' || *s == '\t')
    s++;
  *d = 0;
  *pos = s;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<splitnext>:
  endbr64
  mov    (%rdi),%r8
  movzbl (%r8),%eax
  cmp    $0x9,%al
  je     L48
  cmp    $0x20,%al
  jne    L107
  nopl   0x0(%rax,%rax,1)
L48:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  cmp    $0x20,%al
  je     L48
  cmp    $0x9,%al
  je     L48
L107:
  mov    %r8,%rdx
  mov    %r8,%r9
  test   $0xdf,%al
  jne    L69
  jmp    L132
  nopl   (%rax)
L172:
  cmp    $0x5c,%al
  jne    L49
  mov    %rsi,%rdx
  lea    0x1(%rsi),%rsi
L49:
  movzbl (%rdx),%eax
  add    $0x1,%r9
  mov    %al,-0x1(%r9)
  movzbl 0x1(%rdx),%eax
  mov    %rsi,%rdx
L89:
  test   $0xdf,%al
  je     L74
  cmp    $0x9,%al
  je     L74
L69:
  lea    0x1(%rdx),%rsi
  mov    %rsi,%rcx
  cmp    $0x22,%al
  jne    L172
L71:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L145
  cmp    $0x22,%al
  je     L66
  lea    0x1(%rcx),%rsi
  mov    %rsi,%rdx
  cmp    $0x5c,%al
  jne    L193
  movzbl 0x1(%rcx),%eax
  test   %al,%al
  je     L89
  lea    0x2(%rcx),%rsi
  nopw   0x0(%rax,%rax,1)
L193:
  add    $0x1,%r9
  mov    %rsi,%rcx
  mov    %al,-0x1(%r9)
  jmp    L71
  nopl   (%rax)
L112:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
L74:
  cmp    $0x20,%al
  je     L112
  cmp    $0x9,%al
  je     L112
L132:
  movb   $0x0,(%r9)
  mov    %r8,%rax
  mov    %rdx,(%rdi)
  ret
L145:
  cmp    $0x22,%al
  jne    L142
L66:
  movzbl 0x1(%rcx),%eax
  lea    0x1(%rcx),%rdx
  jmp    L89
L142:
  mov    %rcx,%rdx
  jmp    L89
```

assistant: ```c
char *splitnext(char **pos) {
  char *a, *d, *s;
  s = *pos;
  while (*s == ' ' || *s == '\t')
    s++;
  a = d = s;
  while (*s && *s != ' ' && *s != '\t') {
    if (*s == '"') {
      s++;
      while (*s && *s != '"') {
        if (*s == '\\')
          s++;
        if (*s)
          *(d++) = *(s++);
      }
      if (*s == '"')
        s++;
    } else {
      if (*s == '\\')
        s++;
      *(d++) = *(s++);
    }
  }
  while (*s == ' ' || *s == '\t')
    s++;
  *d = 0;
  *pos = s;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<splitnext>:
  endbr64
  mov    (%rdi),%r8
  movzbl (%r8),%eax
  cmp    $0x9,%al
  je     L89
  cmp    $0x20,%al
  jne    L130
  nopl   0x0(%rax,%rax,1)
L89:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  cmp    $0x20,%al
  je     L89
  cmp    $0x9,%al
  je     L89
L130:
  mov    %r8,%rdx
  mov    %r8,%r9
  test   $0xdf,%al
  jne    L67
  jmp    L87
  nopl   (%rax)
L169:
  cmp    $0x5c,%al
  jne    L140
  movzbl 0x1(%rdx),%eax
  mov    %rsi,%rdx
  lea    0x1(%rsi),%rsi
L140:
  mov    %al,(%r9)
  add    $0x1,%r9
  movzbl 0x1(%rdx),%eax
  mov    %rsi,%rdx
L119:
  test   $0xdf,%al
  je     L9
  cmp    $0x9,%al
  je     L9
L67:
  lea    0x1(%rdx),%rsi
  mov    %rsi,%rcx
  cmp    $0x22,%al
  jne    L169
L92:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L177
  cmp    $0x22,%al
  je     L43
  lea    0x1(%rcx),%rsi
  mov    %rsi,%rdx
  cmp    $0x5c,%al
  jne    L109
  movzbl 0x1(%rcx),%eax
  test   %al,%al
  je     L119
  lea    0x2(%rcx),%rsi
  nopw   0x0(%rax,%rax,1)
L109:
  add    $0x1,%r9
  mov    %rsi,%rcx
  mov    %al,-0x1(%r9)
  jmp    L92
  nopl   (%rax)
L13:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
L9:
  cmp    $0x20,%al
  je     L13
  cmp    $0x9,%al
  je     L13
L87:
  movb   $0x0,(%r9)
  mov    %r8,%rax
  mov    %rdx,(%rdi)
  ret
L177:
  cmp    $0x22,%al
  jne    L98
L43:
  movzbl 0x1(%rcx),%eax
  lea    0x1(%rcx),%rdx
  jmp    L119
L98:
  mov    %rcx,%rdx
  jmp    L119
```

assistant: ```c
char *splitnext(char **pos) {
  char *a, *d, *s;
  s = *pos;
  while (*s == ' ' || *s == '\t')
    s++;
  a = d = s;
  while (*s && *s != ' ' && *s != '\t') {
    if (*s == '"') {
      s++;
      while (*s && *s != '"') {
        if (*s == '\\')
          s++;
        if (*s)
          *(d++) = *(s++);
      }
      if (*s == '"')
        s++;
    } else {
      if (*s == '\\')
        s++;
      *(d++) = *(s++);
    }
  }
  while (*s == ' ' || *s == '\t')
    s++;
  *d = 0;
  *pos = s;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fnFibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L1
L18:
  cmpl   $0x1,-0x14(%rbp)
  jne    L6
  mov    $0x1,%eax
  jmp    L1
L6:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fnFibonacci>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fnFibonacci>
  add    %ebx,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fnFibonacci(int n) {
  if (0 == n)
    return 0;
  else if (1 == n)
    return 1;
  else {
    return fnFibonacci(n - 1) + fnFibonacci(n - 2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fnFibonacci>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L26
  cmp    $0x1,%edi
  jne    L18
L26:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  lea    -0x1(%rdi),%edi
  call   <fnFibonacci>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fnFibonacci>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L26
```

assistant: ```c
int fnFibonacci(int n) {
  if (0 == n)
    return 0;
  else if (1 == n)
    return 1;
  else {
    return fnFibonacci(n - 1) + fnFibonacci(n - 2);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getWriteLock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getWriteLock(void *mem) {
  int *p = mem;
  return p[(3)];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getWriteLock>:
  endbr64
  mov    0xc(%rdi),%eax
  ret
```

assistant: ```c
int getWriteLock(void *mem) {
  int *p = mem;
  return p[(3)];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getWriteLock>:
  endbr64
  mov    0xc(%rdi),%eax
  ret
```

assistant: ```c
int getWriteLock(void *mem) {
  int *p = mem;
  return p[(3)];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x7372696620656874,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x6e65746e65732074,%rax
  mov    $0x2e6563,%edx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movabs $0x2073692073696854,%rax
  movabs $0x6f63657320656874,%rdx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  movabs $0x65746e657320646e,%rax
  mov    %rax,-0x80(%rbp)
  movl   $0x2e65636e,-0x78(%rbp)
  movb   $0x0,-0x74(%rbp)
  lea    -0x70(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat2@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat2@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
data_type: string
name: unpack_data
arguments: data_label: D11
data_type: string

tool: D15:  

tool: D11: %s


assistant: ```c
int main(int argc, char **argv) {
  char s[100] = "This is the first sentence.";
  char t[] = "This is the second sentence.";
  strcat2(s, " ");
  strcat2(s, t);
  printf("%s\n", s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x7372696620656874,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6e65746e65732074,%rax
  mov    $0x2e6563,%edx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movl   $0x0,0x80(%rsp)
  movabs $0x2073692073696854,%rax
  movabs $0x6f63657320656874,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x65746e657320646e,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x2e65636e,0x18(%rsp)
  movb   $0x0,0x1c(%rsp)
  lea    0x20(%rsp),%rbx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat2@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strcat2@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D3:  

tool: D1: %s


assistant: ```c
int main(int argc, char **argv) {
  char s[100] = "This is the first sentence.";
  char t[] = "This is the second sentence.";
  strcat2(s, " ");
  strcat2(s, t);
  printf("%s\n", s);
  return 0;
}
```