ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rolld100>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x9,%esi
  mov    $0x0,%edi
  call   <rand_born@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x9,%esi
  mov    $0x0,%edi
  call   <rand_born@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rolld100(void) {
  int a, b;
  a = rand_born(0, 9);
  b = rand_born(0, 9);
  a += b * 10;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rolld100>:
  endbr64
  push   %rbx
  mov    $0x9,%esi
  mov    $0x0,%edi
  call   <rand_born@plt>
  mov    %eax,%ebx
  mov    $0x9,%esi
  mov    $0x0,%edi
  call   <rand_born@plt>
  lea    (%rax,%rax,4),%eax
  lea    (%rbx,%rax,2),%eax
  pop    %rbx
  ret
```

assistant: ```c
int rolld100(void) {
  int a, b;
  a = rand_born(0, 9);
  b = rand_born(0, 9);
  a += b * 10;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rolld100>:
  endbr64
  push   %rbx
  mov    $0x9,%esi
  xor    %edi,%edi
  call   <rand_born@plt>
  mov    $0x9,%esi
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <rand_born@plt>
  lea    (%rax,%rax,4),%eax
  lea    (%rbx,%rax,2),%eax
  pop    %rbx
  ret
```

assistant: ```c
int rolld100(void) {
  int a, b;
  a = rand_born(0, 9);
  b = rand_born(0, 9);
  a += b * 10;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rolld100>:
  endbr64
  push   %rbx
  mov    $0x9,%esi
  xor    %edi,%edi
  call   <rand_born@plt>
  mov    $0x9,%esi
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <rand_born@plt>
  lea    (%rax,%rax,4),%eax
  lea    (%rbx,%rax,2),%eax
  pop    %rbx
  ret
```

assistant: ```c
int rolld100(void) {
  int a, b;
  a = rand_born(0, 9);
  b = rand_born(0, 9);
  a += b * 10;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InsertionTest3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x30(%rbp)
  movl   $0x7,-0x2c(%rbp)
  movl   $0x9,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x1,-0x40(%rbp)
  jmp    L45
L18:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x40(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  jmp    L43
L24:
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0x30(%rbp,%rax,4)
  subl   $0x1,-0x3c(%rbp)
L43:
  cmpl   $0x0,-0x3c(%rbp)
  js     L8
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L24
L8:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x40(%rbp)
L45:
  mov    -0x40(%rbp),%eax
  cmp    $0x9,%eax
  jbe    L18
  movl   $0x0,-0x38(%rbp)
  jmp    L9
L47:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L9:
  mov    -0x38(%rbp),%eax
  cmp    $0x9,%eax
  jbe    L47
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: %d, 

assistant: ```c
int InsertionTest3() {
  int m[] = {8, 7, 9, 3, 4, 1, 2, 0, 5, 6};
  for (int i = 1; i < sizeof(m) / sizeof(int); i++) {
    int min = m[i];
    int k = i - 1;
    while (k >= 0 && min < m[k]) {
      m[k + 1] = m[k];
      k--;
    }
    m[k + 1] = min;
  }
  for (int i = 0; i < sizeof(m) / sizeof(int); i++) {
    printf("%d, ", m[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<InsertionTest3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0x7,0x4(%rsp)
  movl   $0x9,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x5,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  lea    0x4(%rsp),%r8
  mov    $0x0,%edi
  jmp    L28
L8:
  add    $0x1,%edx
  movslq %edx,%rdx
  mov    %esi,(%rsp,%rdx,4)
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    $0x9,%rdi
  je     L39
L28:
  mov    (%r8),%esi
  mov    %edi,%edx
  mov    %r8,%rax
  test   %edi,%edi
  js     L8
L44:
  mov    -0x4(%rax),%ecx
  cmp    %esi,%ecx
  jle    L8
  mov    %ecx,(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L44
  jmp    L8
L39:
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  lea    D2(%rip),%rbp
L68:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L68
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: %d, 

assistant: ```c
int InsertionTest3() {
  int m[] = {8, 7, 9, 3, 4, 1, 2, 0, 5, 6};
  for (int i = 1; i < sizeof(m) / sizeof(int); i++) {
    int min = m[i];
    int k = i - 1;
    while (k >= 0 && min < m[k]) {
      m[k + 1] = m[k];
      k--;
    }
    m[k + 1] = min;
  }
  for (int i = 0; i < sizeof(m) / sizeof(int); i++) {
    printf("%d, ", m[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<InsertionTest3>:
  endbr64
  push   %r12
  mov    $0x8,%ecx
  mov    $0x7,%edi
  mov    $0x1,%r9d
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x700000008,%rax
  lea    0x4(%rsp),%r8
  movq   $0x2,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000009,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x20(%rsp)
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r9d,%eax
  mov    %r8,%rdx
  jmp    L40
L8:
  mov    -0x4(%rdx),%ecx
L40:
  movslq %eax,%rsi
  cmp    %ecx,%edi
  jge    L54
  mov    %ecx,(%rdx)
  sub    $0x4,%rdx
  sub    $0x1,%eax
  jne    L8
  xor    %esi,%esi
L54:
  add    $0x1,%r9d
  mov    %edi,(%rsp,%rsi,4)
  add    $0x4,%r8
  cmp    $0xa,%r9d
  je     L26
  mov    (%r8),%edi
  mov    -0x4(%r8),%ecx
  jmp    L3
  nopl   0x0(%rax)
L26:
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  lea    D5(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L69:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L69
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %d, 

assistant: ```c
int InsertionTest3() {
  int m[] = {8, 7, 9, 3, 4, 1, 2, 0, 5, 6};
  for (int i = 1; i < sizeof(m) / sizeof(int); i++) {
    int min = m[i];
    int k = i - 1;
    while (k >= 0 && min < m[k]) {
      m[k + 1] = m[k];
      k--;
    }
    m[k + 1] = min;
  }
  for (int i = 0; i < sizeof(m) / sizeof(int); i++) {
    printf("%d, ", m[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timeval_subtract_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long long int timeval_subtract_us(struct timeval *x, struct timeval *y) {
  long long int usec_part;
  long long int sec_part;
  usec_part = x->tv_usec - y->tv_usec;
  sec_part = x->tv_sec - y->tv_sec;
  return ((1000000 * sec_part) + usec_part);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<timeval_subtract_us>:
  endbr64
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  imul   $0xf4240,%rax,%rax
  add    (%rdi),%rax
  sub    (%rsi),%rax
  ret
```

assistant: ```c
long long int timeval_subtract_us(struct timeval *x, struct timeval *y) {
  long long int usec_part;
  long long int sec_part;
  usec_part = x->tv_usec - y->tv_usec;
  sec_part = x->tv_sec - y->tv_sec;
  return ((1000000 * sec_part) + usec_part);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timeval_subtract_us>:
  endbr64
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  imul   $0xf4240,%rax,%rax
  add    (%rdi),%rax
  sub    (%rsi),%rax
  ret
```

assistant: ```c
long long int timeval_subtract_us(struct timeval *x, struct timeval *y) {
  long long int usec_part;
  long long int sec_part;
  usec_part = x->tv_usec - y->tv_usec;
  sec_part = x->tv_sec - y->tv_sec;
  return ((1000000 * sec_part) + usec_part);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<timeval_subtract_us>:
  endbr64
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  imul   $0xf4240,%rax,%rax
  add    (%rdi),%rax
  sub    (%rsi),%rax
  ret
```

assistant: ```c
long long int timeval_subtract_us(struct timeval *x, struct timeval *y) {
  long long int usec_part;
  long long int sec_part;
  usec_part = x->tv_usec - y->tv_usec;
  sec_part = x->tv_sec - y->tv_sec;
  return ((1000000 * sec_part) + usec_part);
}
```
user: Translate the below assembly code into C programming language:

```asm
<func_2c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  movl   $0xa,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x1e,-0x28(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D4
data_type: string
name: unpack_data
arguments: label: D11
data_type: string

tool: D26: func_2c : %d >> 

tool: D4: %d >> 

tool: D11: %d


assistant: ```c
void func_2c(int *const *i) {
  printf("func_2c : %d >> ", **i);
  {
    int bkup = **i;
    **i = 10;
    printf("%d >> ", **i);
    **i = bkup;
  }
  {
    int *const *bkup = i;
    int x = 30;
    int *y = &x;
    int *const *z = &y;
    i = z;
    printf("%d\n", **i);
    i = bkup;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func_2c>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  mov    (%rax),%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    (%rax),%ebp
  movl   $0xa,(%rax)
  mov    (%rbx),%rax
  mov    (%rax),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    %ebp,(%rax)
  mov    $0x1e,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
type: string
name: retrieve_data
arguments: label: D7
type: string
name: retrieve_data
arguments: label: D17
type: string

tool: D24: func_2c : %d >> 

tool: D7: %d >> 

tool: D17: %d


assistant: ```c
void func_2c(int *const *i) {
  printf("func_2c : %d >> ", **i);
  {
    int bkup = **i;
    **i = 10;
    printf("%d >> ", **i);
    **i = bkup;
  }
  {
    int *const *bkup = i;
    int x = 30;
    int *y = &x;
    int *const *z = &y;
    i = z;
    printf("%d\n", **i);
    i = bkup;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func_2c>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    D11(%rip),%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    $0xa,%esi
  lea    D3(%rip),%rdi
  mov    (%rax),%ebp
  movl   $0xa,(%rax)
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    $0x1e,%esi
  lea    D15(%rip),%rdi
  mov    %ebp,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D11: func_2c : %d >> 

tool: D3: %d >> 

tool: D15: %d


assistant: ```c
void func_2c(int *const *i) {
  printf("func_2c : %d >> ", **i);
  {
    int bkup = **i;
    **i = 10;
    printf("%d >> ", **i);
    **i = bkup;
  }
  {
    int *const *bkup = i;
    int x = 30;
    int *y = &x;
    int *const *z = &y;
    i = z;
    printf("%d\n", **i);
    i = bkup;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func_2c>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    D5(%rip),%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    $0xa,%esi
  lea    D15(%rip),%rdi
  mov    (%rax),%ebp
  movl   $0xa,(%rax)
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    $0x1e,%esi
  lea    D12(%rip),%rdi
  mov    %ebp,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D5: func_2c : %d >> 

tool: D15: %d >> 

tool: D12: %d


assistant: ```c
void func_2c(int *const *i) {
  printf("func_2c : %d >> ", **i);
  {
    int bkup = **i;
    **i = 10;
    printf("%d >> ", **i);
    **i = bkup;
  }
  {
    int *const *bkup = i;
    int x = 30;
    int *y = &x;
    int *const *z = &y;
    i = z;
    printf("%d\n", **i);
    i = bkup;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<null_pointer_interproc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x8c,%edx
  mov    $0x40,%esi
  mov    $0x20,%edi
  call   <Person_create@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_age@plt>
  leave
  ret
```

assistant: ```c
int null_pointer_interproc() {
  struct Person *joe = Person_create(32, 64, 140);
  return get_age(joe);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<null_pointer_interproc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8c,%edx
  mov    $0x40,%esi
  mov    $0x20,%edi
  call   <Person_create@plt>
  mov    %rax,%rdi
  call   <get_age@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int null_pointer_interproc() {
  struct Person *joe = Person_create(32, 64, 140);
  return get_age(joe);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<null_pointer_interproc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20,%edi
  mov    $0x8c,%edx
  mov    $0x40,%esi
  call   <Person_create@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <get_age@plt>
```

assistant: ```c
int null_pointer_interproc() {
  struct Person *joe = Person_create(32, 64, 140);
  return get_age(joe);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<null_pointer_interproc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20,%edi
  mov    $0x8c,%edx
  mov    $0x40,%esi
  call   <Person_create@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <get_age@plt>
```

assistant: ```c
int null_pointer_interproc() {
  struct Person *joe = Person_create(32, 64, 140);
  return get_age(joe);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_prime_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x3,-0x8(%rbp)
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x14(%rbp),%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  movss  D0(%rip),%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%rax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L26:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L15
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L26
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x3f]}

assistant: ```c
int is_prime_number(int num) {
  int limit, factor = 3;
  limit = (long)(sqrtf((float)num) + 0.5f);
  while ((factor <= limit) && (num % factor))
    factor++;
  return (factor > limit);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_prime_number>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  D1(%rip),%xmm0
  cvttss2si %xmm0,%rdi
  cmp    $0x2,%edi
  jle    L23
  mov    %edi,%esi
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L49
  mov    $0x3,%ecx
L7:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L40
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L7
L40:
  cmp    %ecx,%edi
  setl   %al
  movzbl %al,%eax
  pop    %rbx
  ret
L23:
  mov    $0x3,%ecx
  jmp    L40
L49:
  mov    $0x3,%ecx
  jmp    L40
```

tool_calls: name: parse_data
arguments: label: D1
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3f]}

assistant: ```c
int is_prime_number(int num) {
  int limit, factor = 3;
  limit = (long)(sqrtf((float)num) + 0.5f);
  while ((factor <= limit) && (num % factor))
    factor++;
  return (factor > limit);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime_number>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    %edi,%ebx
  cvtsi2ss %edi,%xmm0
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  D3(%rip),%xmm0
  cvttss2si %xmm0,%rdi
  cmp    $0x2,%edi
  jle    L16
  imul   $0xaaaaaaab,%ebx,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L16
  mov    %edi,%esi
  mov    $0x3,%ecx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L49
L34:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L32
L49:
  xor    %eax,%eax
  cmp    %ecx,%edi
  pop    %rbx
  setl   %al
  ret
  nopl   0x0(%rax)
L16:
  mov    $0x3,%ecx
  xor    %eax,%eax
  pop    %rbx
  cmp    %ecx,%edi
  setl   %al
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x3f]}

assistant: ```c
int is_prime_number(int num) {
  int limit, factor = 3;
  limit = (long)(sqrtf((float)num) + 0.5f);
  while ((factor <= limit) && (num % factor))
    factor++;
  return (factor > limit);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime_number>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    %edi,%ebx
  cvtsi2ss %edi,%xmm0
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  D5(%rip),%xmm0
  cvttss2si %xmm0,%rdi
  cmp    $0x2,%edi
  jle    L0
  imul   $0xaaaaaaab,%ebx,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L0
  mov    %edi,%esi
  mov    $0x3,%ecx
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L9
L22:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L15
L9:
  xor    %eax,%eax
  cmp    %ecx,%edi
  pop    %rbx
  setl   %al
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x3,%ecx
  xor    %eax,%eax
  pop    %rbx
  cmp    %ecx,%edi
  setl   %al
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x3f]}

assistant: ```c
int is_prime_number(int num) {
  int limit, factor = 3;
  limit = (long)(sqrtf((float)num) + 0.5f);
  while ((factor <= limit) && (num % factor))
    factor++;
  return (factor > limit);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L6:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  leave
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (*p && isspace((int)(*p)))
    p++;
  return strdup(p);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L27
L1:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L27
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
L27:
  mov    %rbx,%rdi
  call   <strdup@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (*p && isspace((int)(*p)))
    p++;
  return strdup(p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L35
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L37
L35:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
L37:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <strdup@plt>
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (*p && isspace((int)(*p)))
    p++;
  return strdup(p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L2
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L8
L2:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L8:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <strdup@plt>
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (*p && isspace((int)(*p)))
    p++;
  return strdup(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LPCHalfWordWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x14(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  add    $0x400,%rax
  mov    %rax,%rdx
  movzwl -0x14(%rbp),%eax
  mov    %ax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LPCHalfWordWrite(unsigned long ulBase, unsigned long ulOffset, unsigned short usData) {
  ;
  ;

  ;
  (*((volatile unsigned short *)(ulBase + 0x00000400 + ulOffset))) = usData;
}
```