ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<guild_decode_emblem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L46
L139:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpl   $0x2f,-0x10(%rbp)
  jle    L48
  cmpl   $0x39,-0x10(%rbp)
  jg     L48
  mov    -0x10(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x18(%rbp)
L48:
  cmpl   $0x60,-0x10(%rbp)
  jle    L100
  cmpl   $0x66,-0x10(%rbp)
  jg     L100
  mov    -0x10(%rbp),%eax
  sub    $0x57,%eax
  mov    %eax,-0x18(%rbp)
L100:
  cmpl   $0x40,-0x10(%rbp)
  jle    L77
  cmpl   $0x46,-0x10(%rbp)
  jg     L77
  mov    -0x10(%rbp),%eax
  sub    $0x37,%eax
  mov    %eax,-0x18(%rbp)
L77:
  cmpl   $0x2f,-0xc(%rbp)
  jle    L131
  cmpl   $0x39,-0xc(%rbp)
  jg     L131
  mov    -0xc(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
L131:
  cmpl   $0x60,-0xc(%rbp)
  jle    L4
  cmpl   $0x66,-0xc(%rbp)
  jg     L4
  mov    -0xc(%rbp),%eax
  sub    $0x57,%eax
  mov    %eax,-0x14(%rbp)
L4:
  cmpl   $0x40,-0xc(%rbp)
  jle    L87
  cmpl   $0x46,-0xc(%rbp)
  jg     L87
  mov    -0xc(%rbp),%eax
  sub    $0x37,%eax
  mov    %eax,-0x14(%rbp)
L87:
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x2,-0x8(%rbp)
L46:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L139
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *guild_decode_emblem(char *dst, const char *src, int len) {
  int i;
  const char *p = src;
  for (i = 0; i < len; i++, p += 2) {
    int c1 = p[0], c2 = p[1], x1 = 0, x2 = 0;
    if (c1 >= '0' && c1 <= '9')
      x1 = c1 - '0';
    if (c1 >= 'a' && c1 <= 'f')
      x1 = c1 - 'a' + 10;
    if (c1 >= 'A' && c1 <= 'F')
      x1 = c1 - 'A' + 10;
    if (c2 >= '0' && c2 <= '9')
      x2 = c2 - '0';
    if (c2 >= 'a' && c2 <= 'f')
      x2 = c2 - 'a' + 10;
    if (c2 >= 'A' && c2 <= 'F')
      x2 = c2 - 'A' + 10;
    dst[i] = (x1 << 4) | x2;
  }
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<guild_decode_emblem>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%rdi
  test   %edx,%edx
  jle    L82
  mov    %edx,%r10d
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  jmp    L88
L89:
  lea    -0x61(%rax),%r8d
  cmp    $0x5,%r8d
  ja     L10
  sub    $0x57,%eax
  jmp    L18
L10:
  lea    -0x41(%rax),%r8d
  cmp    $0x5,%r8d
  ja     L0
  sub    $0x37,%eax
  jmp    L18
L0:
  mov    %r11d,%eax
  jmp    L18
L26:
  lea    -0x61(%rdx),%r8d
  cmp    $0x5,%r8d
  ja     L36
  lea    -0x57(%rsi),%edx
L105:
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %al,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%r10
  je     L82
L88:
  movsbl (%rdi,%rcx,2),%eax
  movzbl 0x1(%rdi,%rcx,2),%edx
  movsbl %dl,%esi
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8d
  ja     L89
  mov    %r8d,%eax
L18:
  movsbl %dl,%edx
  lea    -0x30(%rdx),%r8d
  cmp    $0x9,%r8d
  ja     L26
  lea    -0x30(%rsi),%edx
  jmp    L105
L36:
  sub    $0x41,%edx
  cmp    $0x5,%edx
  ja     L28
  lea    -0x37(%rsi),%edx
  jmp    L105
L28:
  mov    %r11d,%edx
  jmp    L105
L82:
  mov    %r9,%rax
  ret
```

assistant: ```c
char *guild_decode_emblem(char *dst, const char *src, int len) {
  int i;
  const char *p = src;
  for (i = 0; i < len; i++, p += 2) {
    int c1 = p[0], c2 = p[1], x1 = 0, x2 = 0;
    if (c1 >= '0' && c1 <= '9')
      x1 = c1 - '0';
    if (c1 >= 'a' && c1 <= 'f')
      x1 = c1 - 'a' + 10;
    if (c1 >= 'A' && c1 <= 'F')
      x1 = c1 - 'A' + 10;
    if (c2 >= '0' && c2 <= '9')
      x2 = c2 - '0';
    if (c2 >= 'a' && c2 <= 'f')
      x2 = c2 - 'a' + 10;
    if (c2 >= 'A' && c2 <= 'F')
      x2 = c2 - 'A' + 10;
    dst[i] = (x1 << 4) | x2;
  }
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<guild_decode_emblem>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%rdi
  test   %edx,%edx
  jle    L109
  movslq %edx,%r8
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rdi,%rdx,2),%ecx
  movsbl 0x1(%rdi,%rdx,2),%esi
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%eax
  jbe    L22
  lea    -0x61(%rcx),%eax
  cmp    $0x5,%eax
  ja     L38
  lea    -0x57(%rcx),%eax
L22:
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%ecx
  jbe    L101
  lea    -0x61(%rsi),%ecx
  cmp    $0x5,%ecx
  ja     L56
  lea    -0x57(%rsi),%ecx
L101:
  shl    $0x4,%eax
  or     %ecx,%eax
  mov    %al,(%r9,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L6
L109:
  mov    %r9,%rax
  ret
L38:
  lea    -0x41(%rcx),%eax
  cmp    $0x5,%eax
  ja     L41
  lea    -0x37(%rcx),%eax
  jmp    L22
L56:
  lea    -0x41(%rsi),%ecx
  cmp    $0x5,%ecx
  ja     L99
  lea    -0x37(%rsi),%ecx
  jmp    L101
L41:
  xor    %eax,%eax
  jmp    L22
L99:
  xor    %ecx,%ecx
  jmp    L101
```

assistant: ```c
char *guild_decode_emblem(char *dst, const char *src, int len) {
  int i;
  const char *p = src;
  for (i = 0; i < len; i++, p += 2) {
    int c1 = p[0], c2 = p[1], x1 = 0, x2 = 0;
    if (c1 >= '0' && c1 <= '9')
      x1 = c1 - '0';
    if (c1 >= 'a' && c1 <= 'f')
      x1 = c1 - 'a' + 10;
    if (c1 >= 'A' && c1 <= 'F')
      x1 = c1 - 'A' + 10;
    if (c2 >= '0' && c2 <= '9')
      x2 = c2 - '0';
    if (c2 >= 'a' && c2 <= 'f')
      x2 = c2 - 'a' + 10;
    if (c2 >= 'A' && c2 <= 'F')
      x2 = c2 - 'A' + 10;
    dst[i] = (x1 << 4) | x2;
  }
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x30,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movl   $0x1,(%rax)
  mov    (%rbx),%rax
  movl   $0x0,0x4(%rax)
  movl   $0x2,0x0(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  movl   $0x2,(%rax)
  mov    0x8(%rbx),%rax
  movl   $0x1,0x4(%rax)
  movl   $0x2,0x4(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rbx)
  movl   $0x3,(%rax)
  mov    0x10(%rbx),%rax
  movl   $0x2,0x4(%rax)
  movl   $0x2,0x8(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rbx)
  movl   $0x1,(%rax)
  mov    0x18(%rbx),%rax
  movl   $0x3,0x4(%rax)
  movl   $0x2,0xc(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x20(%rbx)
  movl   $0x4,(%rax)
  mov    0x20(%rbx),%rax
  movl   $0x0,0x4(%rax)
  movl   $0x2,0x10(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x28(%rbx)
  movl   $0x0,(%rax)
  mov    0x28(%rbx),%rax
  movl   $0x5,0x4(%rax)
  movl   $0x2,0x14(%rbp)
  mov    %rbp,%rcx
  mov    $0x6,%edx
  mov    %rbx,%rsi
  mov    $0x6,%edi
  call   <canFinish@plt>
  test   %rax,%rax
  lea    D1(%rip),%rsi
  lea    D7(%rip),%rax
  cmove  %rax,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D24
data_type: string

tool: D1: true

tool: D7: false

tool: D24: %s


assistant: ```c
int main(void) {
  int i, course_num = 6, pair_num = 6;
  int **pairs = malloc(pair_num * sizeof(int *));
  int *col_sizes = malloc(pair_num * sizeof(int));
  pairs[0] = malloc(2 * sizeof(int));
  pairs[0][0] = 1;
  pairs[0][1] = 0;
  col_sizes[0] = 2;
  pairs[1] = malloc(2 * sizeof(int));
  pairs[1][0] = 2;
  pairs[1][1] = 1;
  col_sizes[1] = 2;
  pairs[2] = malloc(2 * sizeof(int));
  pairs[2][0] = 3;
  pairs[2][1] = 2;
  col_sizes[2] = 2;
  pairs[3] = malloc(2 * sizeof(int));
  pairs[3][0] = 1;
  pairs[3][1] = 3;
  col_sizes[3] = 2;
  pairs[4] = malloc(2 * sizeof(int));
  pairs[4][0] = 4;
  pairs[4][1] = 0;
  col_sizes[4] = 2;
  pairs[5] = malloc(2 * sizeof(int));
  pairs[5][0] = 0;
  pairs[5][1] = 5;
  col_sizes[5] = 2;
  printf("%s\n", canFinish(course_num, pairs, pair_num, col_sizes) ? "true" : "false");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x30,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,0x0(%rbp)
  movq   $0x1,(%rax)
  movl   $0x2,(%r12)
  call   <malloc@plt>
  mov    $0x8,%edi
  movabs $0x100000002,%rdx
  mov    %rax,0x8(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,0x4(%r12)
  call   <malloc@plt>
  mov    $0x8,%edi
  movabs $0x200000003,%rcx
  mov    %rax,0x10(%rbp)
  mov    %rcx,(%rax)
  movl   $0x2,0x8(%r12)
  call   <malloc@plt>
  mov    $0x8,%edi
  movabs $0x300000001,%rdx
  mov    %rax,0x18(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,0xc(%r12)
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,0x20(%rbp)
  movq   $0x4,(%rax)
  movl   $0x2,0x10(%r12)
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x6,%edx
  movabs $0x500000000,%rcx
  mov    %rax,0x28(%rbp)
  mov    $0x6,%edi
  mov    %rcx,(%rax)
  mov    %r12,%rcx
  movl   $0x2,0x14(%r12)
  call   <canFinish@plt>
  lea    D19(%rip),%rsi
  lea    D11(%rip),%rdi
  test   %rax,%rax
  lea    D20(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string

tool: D19: true

tool: D11: %s


tool: D20: false

assistant: ```c
int main(void) {
  int i, course_num = 6, pair_num = 6;
  int **pairs = malloc(pair_num * sizeof(int *));
  int *col_sizes = malloc(pair_num * sizeof(int));
  pairs[0] = malloc(2 * sizeof(int));
  pairs[0][0] = 1;
  pairs[0][1] = 0;
  col_sizes[0] = 2;
  pairs[1] = malloc(2 * sizeof(int));
  pairs[1][0] = 2;
  pairs[1][1] = 1;
  col_sizes[1] = 2;
  pairs[2] = malloc(2 * sizeof(int));
  pairs[2][0] = 3;
  pairs[2][1] = 2;
  col_sizes[2] = 2;
  pairs[3] = malloc(2 * sizeof(int));
  pairs[3][0] = 1;
  pairs[3][1] = 3;
  col_sizes[3] = 2;
  pairs[4] = malloc(2 * sizeof(int));
  pairs[4][0] = 4;
  pairs[4][1] = 0;
  col_sizes[4] = 2;
  pairs[5] = malloc(2 * sizeof(int));
  pairs[5][0] = 0;
  pairs[5][1] = 5;
  col_sizes[5] = 2;
  printf("%s\n", canFinish(course_num, pairs, pair_num, col_sizes) ? "true" : "false");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x30,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    D34(%rip),%rdx
  mov    $0x8,%edi
  mov    %rax,0x0(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,(%r12)
  call   <malloc@plt>
  mov    D65(%rip),%rdx
  mov    $0x8,%edi
  mov    %rax,0x8(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,0x4(%r12)
  call   <malloc@plt>
  mov    D63(%rip),%rdx
  mov    $0x8,%edi
  mov    %rax,0x10(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,0x8(%r12)
  call   <malloc@plt>
  mov    D42(%rip),%rdx
  mov    $0x8,%edi
  mov    %rax,0x18(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,0xc(%r12)
  call   <malloc@plt>
  mov    D64(%rip),%rdx
  mov    $0x8,%edi
  mov    %rax,0x20(%rbp)
  mov    %rdx,(%rax)
  movl   $0x2,0x10(%r12)
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rbp,%rsi
  mov    $0x6,%edi
  mov    D39(%rip),%rdx
  mov    %rax,0x28(%rbp)
  mov    %rdx,(%rax)
  mov    $0x6,%edx
  movl   $0x2,0x14(%r12)
  call   <canFinish@plt>
  lea    D27(%rip),%rsi
  lea    D8(%rip),%rdi
  test   %rax,%rax
  lea    D9(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D34
datatype: byte[8]
name: parse_data
arguments: label: D65
datatype: byte[8]
name: parse_data
arguments: label: D63
datatype: byte[8]
name: parse_data
arguments: label: D42
datatype: byte[8]
name: parse_data
arguments: label: D64
datatype: byte[8]
name: parse_data
arguments: label: D39
datatype: byte[8]
name: parse_data
arguments: label: D27
datatype: string
name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D9
datatype: string

tool: {"D34": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D65": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D63": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D42": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D64": [0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D27: true

tool: D8: %s


tool: D9: false

assistant: ```c
int main(void) {
  int i, course_num = 6, pair_num = 6;
  int **pairs = malloc(pair_num * sizeof(int *));
  int *col_sizes = malloc(pair_num * sizeof(int));
  pairs[0] = malloc(2 * sizeof(int));
  pairs[0][0] = 1;
  pairs[0][1] = 0;
  col_sizes[0] = 2;
  pairs[1] = malloc(2 * sizeof(int));
  pairs[1][0] = 2;
  pairs[1][1] = 1;
  col_sizes[1] = 2;
  pairs[2] = malloc(2 * sizeof(int));
  pairs[2][0] = 3;
  pairs[2][1] = 2;
  col_sizes[2] = 2;
  pairs[3] = malloc(2 * sizeof(int));
  pairs[3][0] = 1;
  pairs[3][1] = 3;
  col_sizes[3] = 2;
  pairs[4] = malloc(2 * sizeof(int));
  pairs[4][0] = 4;
  pairs[4][1] = 0;
  col_sizes[4] = 2;
  pairs[5] = malloc(2 * sizeof(int));
  pairs[5][0] = 0;
  pairs[5][1] = 5;
  col_sizes[5] = 2;
  printf("%s\n", canFinish(course_num, pairs, pair_num, col_sizes) ? "true" : "false");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tcbwtsortchrcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %esi,-0x42c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x428(%rbp)
  je     L37
  cmpl   $0x0,-0x42c(%rbp)
  js     L37
  mov    $0x1,%eax
  jmp    L32
L37:
  mov    $0x0,%eax
L32:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x41c(%rbp)
  jmp    L73
L59:
  mov    -0x41c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  movslq %eax,%rdx
  mov    -0x410(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x410(%rbp,%rax,4)
  addl   $0x1,-0x41c(%rbp)
L73:
  mov    -0x41c(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jl     L59
  movl   $0x0,-0x418(%rbp)
  movl   $0x0,-0x414(%rbp)
  jmp    L61
L68:
  mov    -0x414(%rbp),%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  movslq %eax,%rdx
  mov    -0x418(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x428(%rbp),%rax
  add    %rax,%rcx
  mov    -0x414(%rbp),%eax
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x414(%rbp),%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  add    %eax,-0x418(%rbp)
  addl   $0x1,-0x414(%rbp)
L61:
  cmpl   $0xff,-0x414(%rbp)
  jle    L68
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
void tcbwtsortchrcount(unsigned char *str, int len) {
  assert(str && len >= 0);
  int cnt[0x100];
  memset(cnt, 0, ((int)sizeof(cnt)));
  for (int i = 0; i < len; i++) {
    cnt[str[i]]++;
  }
  int pos = 0;
  for (int i = 0; i < 0x100; i++) {
    memset(str + pos, i, cnt[i]);
    pos += cnt[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tcbwtsortchrcount>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %al
  mov    %esi,%edi
  not    %edi
  shr    $0x1f,%edi
  and    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rsp,%rdx
  mov    $0x80,%ecx
  mov    $0x0,%eax
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  test   %ebx,%ebx
  jle    L11
  mov    %r13,%rax
  lea    -0x1(%rbx),%edx
  lea    0x1(%r13,%rdx,1),%rcx
L4:
  movzbl (%rax),%edx
  addl   $0x1,(%rsp,%rdx,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L4
L11:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L12:
  mov    (%rsp,%rbx,4),%r12d
  movslq %r12d,%rdx
  movslq %ebp,%rdi
  add    %r13,%rdi
  mov    %ebx,%esi
  call   <memset@plt>
  add    %r12d,%ebp
  add    $0x1,%rbx
  cmp    $0x100,%rbx
  jne    L12
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tcbwtsortchrcount(unsigned char *str, int len) {
  assert(str && len >= 0);
  int cnt[0x100];
  memset(cnt, 0, ((int)sizeof(cnt)));
  for (int i = 0; i < len; i++) {
    cnt[str[i]]++;
  }
  int pos = 0;
  for (int i = 0; i < 0x100; i++) {
    memset(str + pos, i, cnt[i]);
    pos += cnt[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tcbwtsortchrcount>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  mov    %esi,%edi
  mov    %rsp,%r13
  not    %edi
  setne  %al
  shr    $0x1f,%edi
  and    %eax,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x80,%ecx
  xor    %eax,%eax
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  test   %ebx,%ebx
  jle    L58
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rax
  lea    0x1(%rbp,%rdx,1),%rcx
  xchg   %ax,%ax
L32:
  movzbl (%rax),%edx
  add    $0x1,%rax
  addl   $0x1,(%rsp,%rdx,4)
  cmp    %rax,%rcx
  jne    L32
  movslq (%rsp),%rdx
L18:
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L44:
  movslq 0x0(%r13,%rbx,4),%rdx
L39:
  movslq %r12d,%rdi
  mov    %ebx,%esi
  add    %rbp,%rdi
  call   <memset@plt>
  add    0x0(%r13,%rbx,4),%r12d
  add    $0x1,%rbx
  cmp    $0x100,%rbx
  jne    L44
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  xor    %edx,%edx
  jmp    L18
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tcbwtsortchrcount(unsigned char *str, int len) {
  assert(str && len >= 0);
  int cnt[0x100];
  memset(cnt, 0, ((int)sizeof(cnt)));
  for (int i = 0; i < len; i++) {
    cnt[str[i]]++;
  }
  int pos = 0;
  for (int i = 0; i < 0x100; i++) {
    memset(str + pos, i, cnt[i]);
    pos += cnt[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tcbwtsortchrcount>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  mov    %esi,%edi
  mov    %rsp,%r12
  not    %edi
  setne  %al
  shr    $0x1f,%edi
  and    %eax,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x80,%ecx
  xor    %eax,%eax
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  test   %ebx,%ebx
  jle    L4
  lea    -0x1(%rbx),%edx
  mov    %r13,%rax
  lea    0x1(%r13,%rdx,1),%rcx
  xchg   %ax,%ax
L27:
  movzbl (%rax),%edx
  add    $0x1,%rax
  addl   $0x1,(%rsp,%rdx,4)
  cmp    %rax,%rcx
  jne    L27
L4:
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L21:
  movslq (%r12,%rbx,4),%rdx
  movslq %ebp,%rdi
  mov    %ebx,%esi
  add    %r13,%rdi
  call   <memset@plt>
  add    (%r12,%rbx,4),%ebp
  add    $0x1,%rbx
  cmp    $0x100,%rbx
  jne    L21
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tcbwtsortchrcount(unsigned char *str, int len) {
  assert(str && len >= 0);
  int cnt[0x100];
  memset(cnt, 0, ((int)sizeof(cnt)));
  for (int i = 0; i < len; i++) {
    cnt[str[i]]++;
  }
  int pos = 0;
  for (int i = 0; i < 0x100; i++) {
    memset(str + pos, i, cnt[i]);
    pos += cnt[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intio_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L27
L4:
  mov    -0x1c(%rbp),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0xd(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  sarl   $0x8,-0x1c(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  cmpl   $0x2,-0xc(%rbp)
  jle    L4
  mov    -0x1c(%rbp),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0xd(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void intio_write(FILE *f, int v) {
  unsigned char b;
  int i;
  for (i = 0; i < 3; i++) {
    b = v & 0xff;
    fwrite(&b, 1, 1, f);
    v >>= 8;
  }
  b = v > 0 ? v : v + 256;
  fwrite(&b, 1, 1, f);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<intio_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x3,%ebp
  lea    0x7(%rsp),%r13
L16:
  mov    %bl,0x7(%rsp)
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  sar    $0x8,%ebx
  sub    $0x1,%ebp
  jne    L16
  mov    %bl,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void intio_write(FILE *f, int v) {
  unsigned char b;
  int i;
  for (i = 0; i < 3; i++) {
    b = v & 0xff;
    fwrite(&b, 1, 1, f);
    v >>= 8;
  }
  b = v > 0 ? v : v + 256;
  fwrite(&b, 1, 1, f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<intio_write>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
L2:
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    %bl,0x7(%rsp)
  sar    $0x8,%ebx
  call   <fwrite@plt>
  sub    $0x1,%ebp
  jne    L2
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    %bl,0x7(%rsp)
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void intio_write(FILE *f, int v) {
  unsigned char b;
  int i;
  for (i = 0; i < 3; i++) {
    b = v & 0xff;
    fwrite(&b, 1, 1, f);
    v >>= 8;
  }
  b = v > 0 ? v : v + 256;
  fwrite(&b, 1, 1, f);
}
```