ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L37:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L37
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  jle    L30
  jmp    L37
L30:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L49
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L72
  jmp    L42
L49:
  nop
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L36
L42:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L36
L72:
  nop
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L36:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
type_infered: string
name: extract_symbolic_data
arguments: tag: D21
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string

tool: D24: Enter a number between 0 and 10: 

tool: D21: %d

tool: D34: You entered 0.


tool: D9: You entered 1.


tool: D31: You entered something between 2 and 10.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
start:
  puts("Enter a number between 0 and 10: ");
  scanf("%d", &n);
  if (n < 0 || n > 10)
    goto start;
  else if (n == 0)
    goto location0;
  else if (n == 1)
    goto location1;
  else
    goto location2;
location0:
  puts("You entered 0.\n");
  goto end;
location1:
  puts("You entered 1.\n");
  goto end;
location2:
  puts("You entered something between 2 and 10.\n");
end:
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D13(%rip),%rbx
L25:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xa,%eax
  ja     L25
  test   %eax,%eax
  je     L6
  cmp    $0x1,%eax
  je     L54
  lea    D32(%rip),%rdi
  call   <puts@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  jmp    L24
L54:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L24
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D33
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D32
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D33: Enter a number between 0 and 10: 

tool: D13: %d

tool: D32: You entered something between 2 and 10.


tool: D4: You entered 0.


tool: D18: You entered 1.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
start:
  puts("Enter a number between 0 and 10: ");
  scanf("%d", &n);
  if (n < 0 || n > 10)
    goto start;
  else if (n == 0)
    goto location0;
  else if (n == 1)
    goto location1;
  else
    goto location2;
location0:
  puts("You entered 0.\n");
  goto end;
location1:
  puts("You entered 1.\n");
  goto end;
location2:
  puts("You entered something between 2 and 10.\n");
end:
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D42(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nop
L23:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xa,%eax
  ja     L23
  test   %eax,%eax
  je     L22
  cmp    $0x1,%eax
  je     L34
  lea    D12(%rip),%rdi
  call   <puts@plt>
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  lea    D44(%rip),%rdi
  call   <puts@plt>
  jmp    L30
L22:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L30
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D42
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D44
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D23: Enter a number between 0 and 10: 

tool: D42: %d

tool: D12: You entered something between 2 and 10.


tool: D44: You entered 1.


tool: D19: You entered 0.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
start:
  puts("Enter a number between 0 and 10: ");
  scanf("%d", &n);
  if (n < 0 || n > 10)
    goto start;
  else if (n == 0)
    goto location0;
  else if (n == 1)
    goto location1;
  else
    goto location2;
location0:
  puts("You entered 0.\n");
  goto end;
location1:
  puts("You entered 1.\n");
  goto end;
location2:
  puts("You entered something between 2 and 10.\n");
end:
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D32(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nop
L29:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xa,%eax
  ja     L29
  test   %eax,%eax
  je     L39
  cmp    $0x1,%eax
  je     L47
  lea    D15(%rip),%rdi
  call   <puts@plt>
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L34
L39:
  lea    D48(%rip),%rdi
  call   <puts@plt>
  jmp    L34
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D32
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string
name: extract_symbolic_data
arguments: data_label: D48
data_type: string

tool: D14: Enter a number between 0 and 10: 

tool: D32: %d

tool: D15: You entered something between 2 and 10.


tool: D3: You entered 1.


tool: D48: You entered 0.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
start:
  puts("Enter a number between 0 and 10: ");
  scanf("%d", &n);
  if (n < 0 || n > 10)
    goto start;
  else if (n == 0)
    goto location0;
  else if (n == 1)
    goto location1;
  else
    goto location2;
location0:
  puts("You entered 0.\n");
  goto end;
location1:
  puts("You entered 1.\n");
  goto end;
location2:
  puts("You entered something between 2 and 10.\n");
end:
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L58
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L58:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L0
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L45
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int i, j, n;
  for (i = 0; i < an; i++) {
    for (j = 0; j < bm; j++) {
      C[i][j] = 0.0f;
      for (n = 0; n < ambn; n++) {
        C[i][j] += A[i][n] * B[n][j];
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mm>:
  endbr64
  test   %r8d,%r8d
  jle    L24
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %rdx,%rax
  mov    %ecx,%r11d
  mov    %r9d,%ebp
  mov    %rdx,%r9
  lea    -0x1(%r8),%edx
  lea    0x8(%rax,%rdx,8),%r12
  lea    -0x1(%rbp),%eax
  lea    0x4(,%rax,4),%rbx
  lea    -0x1(%rcx),%eax
  lea    0x4(,%rax,4),%r8
  jmp    L61
L25:
  mov    %r9,%rsi
  mov    (%r9),%rax
  movl   $0x0,(%rax,%rcx,1)
  test   %r11d,%r11d
  jle    L16
  mov    $0x0,%eax
L27:
  mov    %rcx,%rdx
  add    (%rsi),%rdx
  mov    (%rdi),%r14
  movss  (%r14,%rax,1),%xmm0
  mov    (%r10,%rax,2),%r14
  mulss  (%r14,%rcx,1),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x4,%rax
  cmp    %rax,%r8
  jne    L27
L16:
  add    $0x4,%rcx
  cmp    %rbx,%rcx
  jne    L25
L21:
  add    $0x8,%r9
  add    $0x8,%rdi
  cmp    %r12,%r9
  je     L70
L61:
  mov    $0x0,%ecx
  test   %ebp,%ebp
  jg     L25
  jmp    L21
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L24:
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int i, j, n;
  for (i = 0; i < an; i++) {
    for (j = 0; j < bm; j++) {
      C[i][j] = 0.0f;
      for (n = 0; n < ambn; n++) {
        C[i][j] += A[i][n] * B[n][j];
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  movslq %r8d,%r12
  push   %rbp
  push   %rbx
  test   %r12d,%r12d
  jle    L45
  lea    -0x1(%r9),%eax
  mov    %rdi,%r11
  mov    %r9d,%r13d
  mov    %rsi,%rdi
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  xor    %r9d,%r9d
  movslq %ecx,%r8
  lea    0x4(,%rax,4),%r14
  pxor   %xmm2,%xmm2
  xchg   %ax,%ax
L39:
  test   %r13d,%r13d
  jle    L36
  mov    0x0(%rbp,%r9,8),%rdx
  xor    %ecx,%ecx
  lea    (%r14,%rdx,1),%r10
L24:
  movl   $0x0,(%rdx)
  test   %ebx,%ebx
  jle    L38
  mov    (%r11,%r9,8),%rsi
  xor    %eax,%eax
  movaps %xmm2,%xmm1
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rdi,%rax,8),%r15
  movss  (%r15,%rcx,1),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %r8,%rax
  jne    L0
L38:
  add    $0x4,%rdx
  add    $0x4,%rcx
  cmp    %rdx,%r10
  jne    L24
L36:
  add    $0x1,%r9
  cmp    %r12,%r9
  jne    L39
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int i, j, n;
  for (i = 0; i < an; i++) {
    for (j = 0; j < bm; j++) {
      C[i][j] = 0.0f;
      for (n = 0; n < ambn; n++) {
        C[i][j] += A[i][n] * B[n][j];
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mm>:
  endbr64
  push   %r14
  movslq %r8d,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %r14d,%r14d
  jle    L1
  mov    %r9d,%eax
  test   %eax,%eax
  jle    L1
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  xor    %r9d,%r9d
  pxor   %xmm2,%xmm2
  lea    0x0(,%rax,4),%r13
  movslq %ecx,%r8
  nopl   (%rax)
L46:
  mov    0x0(%rbp,%r9,8),%rcx
  xor    %esi,%esi
  lea    0x0(%r13,%rcx,1),%rbx
  nopl   0x0(%rax)
L10:
  movl   $0x0,(%rcx)
  test   %r12d,%r12d
  jle    L54
  mov    (%r11,%r9,8),%rdi
  xor    %eax,%eax
  movaps %xmm2,%xmm1
  nopl   0x0(%rax)
L38:
  mov    (%r10,%rax,8),%rdx
  movss  (%rdx,%rsi,1),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  cmp    %rax,%r8
  jne    L38
L54:
  add    $0x4,%rcx
  add    $0x4,%rsi
  cmp    %rcx,%rbx
  jne    L10
  add    $0x1,%r9
  cmp    %r9,%r14
  jne    L46
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int i, j, n;
  for (i = 0; i < an; i++) {
    for (j = 0; j < bm; j++) {
      C[i][j] = 0.0f;
      for (n = 0; n < ambn; n++) {
        C[i][j] += A[i][n] * B[n][j];
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x74(%rbp)
  je     L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L8:
  movl   $0x3,-0x70(%rbp)
  movl   $0x2,-0x6c(%rbp)
  movl   $0x6,-0x68(%rbp)
  movl   $0x4,-0x64(%rbp)
  movl   $0x5,-0x60(%rbp)
  movl   $0x1,-0x5c(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x8,-0x4c(%rbp)
  movl   $0x4,-0x48(%rbp)
  movl   $0xc,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0xa,-0x3c(%rbp)
  movl   $0x6,-0x38(%rbp)
  movl   $0xe,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0xd,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0xf,-0x14(%rbp)
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <lis@plt>
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x50(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <lis@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: 
ERROR: Insufficient arguments!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("\nERROR: Insufficient arguments!\n");
    exit(-1);
  }
  int x[] = {3, 2, 6, 4, 5, 1};
  int y[] = {0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15};
  lis(x, sizeof(x) / sizeof(int), argv[1]);
  lis(y, sizeof(y) / sizeof(int), argv[1]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L6
L28:
  movl   $0x3,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x8,0x24(%rsp)
  movl   $0x4,0x28(%rsp)
  movl   $0xc,0x2c(%rsp)
  movl   $0x2,0x30(%rsp)
  movl   $0xa,0x34(%rsp)
  movl   $0x6,0x38(%rsp)
  movl   $0xe,0x3c(%rsp)
  movl   $0x1,0x40(%rsp)
  movl   $0x9,0x44(%rsp)
  movl   $0x5,0x48(%rsp)
  movl   $0xd,0x4c(%rsp)
  movl   $0x3,0x50(%rsp)
  movl   $0xb,0x54(%rsp)
  movl   $0x7,0x58(%rsp)
  movl   $0xf,0x5c(%rsp)
  mov    0x8(%rbx),%rdx
  mov    %rsp,%rdi
  mov    $0x6,%esi
  call   <lis@plt>
  mov    0x8(%rbx),%rdx
  lea    0x20(%rsp),%rdi
  mov    $0x10,%esi
  call   <lis@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L6:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L28
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: 
ERROR: Insufficient arguments!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("\nERROR: Insufficient arguments!\n");
    exit(-1);
  }
  int x[] = {3, 2, 6, 4, 5, 1};
  int y[] = {0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15};
  lis(x, sizeof(x) / sizeof(int), argv[1]);
  lis(y, sizeof(y) / sizeof(int), argv[1]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L6
  lea    D2(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L6:
  mov    0x8(%rbx),%rdx
  mov    %rsp,%rdi
  mov    $0x6,%esi
  movabs $0x200000003,%rax
  mov    %rax,(%rsp)
  movabs $0x400000006,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000000,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xc00000004,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xa00000002,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xe00000006,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x900000001,%rax
  mov    %rax,0x40(%rsp)
  movabs $0xd00000005,%rax
  mov    %rax,0x48(%rsp)
  movabs $0xb00000003,%rax
  mov    %rax,0x50(%rsp)
  movabs $0xf00000007,%rax
  mov    %rax,0x58(%rsp)
  call   <lis@plt>
  mov    0x8(%rbx),%rdx
  lea    0x20(%rsp),%rdi
  mov    $0x10,%esi
  call   <lis@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: 
ERROR: Insufficient arguments!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("\nERROR: Insufficient arguments!\n");
    exit(-1);
  }
  int x[] = {3, 2, 6, 4, 5, 1};
  int y[] = {0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15};
  lis(x, sizeof(x) / sizeof(int), argv[1]);
  lis(y, sizeof(y) / sizeof(int), argv[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L9
  lea    D1(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L9:
  movdqa D52(%rip),%xmm0
  mov    0x8(%rbx),%rdx
  mov    %rsp,%rdi
  mov    $0x6,%esi
  mov    D40(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D55(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D38(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  call   <lis@plt>
  mov    0x8(%rbx),%rdx
  lea    0x20(%rsp),%rdi
  mov    $0x10,%esi
  call   <lis@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D52
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D40
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D23
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D55
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D38
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D8
type_infered: byte[16]

tool: D1: 
ERROR: Insufficient arguments!


tool: {"D52": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D40": [0x05,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D55": [0x02,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x0e,0x00,0x00,0x00]}

tool: {"D38": [0x01,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D8": [0x03,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("\nERROR: Insufficient arguments!\n");
    exit(-1);
  }
  int x[] = {3, 2, 6, 4, 5, 1};
  int y[] = {0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15};
  lis(x, sizeof(x) / sizeof(int), argv[1]);
  lis(y, sizeof(y) / sizeof(int), argv[1]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mp_decode_strbin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mp_decode_strbinl@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *mp_decode_strbin(const char **data, uint32_t *len) {
  assert(len != NULL);
  *len = mp_decode_strbinl(data);
  const char *str = *data;
  *data += *len;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mp_decode_strbin>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <mp_decode_strbinl@plt>
  mov    %eax,0x0(%rbp)
  mov    (%rbx),%rdx
  cltq
  add    %rdx,%rax
  mov    %rax,(%rbx)
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *mp_decode_strbin(const char **data, uint32_t *len) {
  assert(len != NULL);
  *len = mp_decode_strbinl(data);
  const char *str = *data;
  *data += *len;
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mp_decode_strbin>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <mp_decode_strbinl@plt>
  mov    (%rbx),%r8
  mov    %eax,0x0(%rbp)
  cltq
  add    %r8,%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *mp_decode_strbin(const char **data, uint32_t *len) {
  assert(len != NULL);
  *len = mp_decode_strbinl(data);
  const char *str = *data;
  *data += *len;
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mp_decode_strbin>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <mp_decode_strbinl@plt>
  mov    (%rbx),%r8
  mov    %eax,0x0(%rbp)
  cltq
  add    %r8,%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *mp_decode_strbin(const char **data, uint32_t *len) {
  assert(len != NULL);
  *len = mp_decode_strbinl(data);
  const char *str = *data;
  *data += *len;
  return str;
}
```