ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Triplet>:
  endbr64
  push   %r12
  mov    D2(%rip),%r12
  push   %rbp
  push   %rbx
  mov    (%r12),%edi
  call   <getc@plt>
  mov    (%r12),%edi
  mov    %eax,%ebp
  call   <getc@plt>
  mov    (%r12),%edi
  mov    %eax,%ebx
  call   <getc@plt>
  shl    $0x8,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Triplet(FILE *fp) {
  int i0;
  int i1;
  int i2;
  i0 = getc(stdin);
  i1 = getc(stdin);
  i2 = getc(stdin);
  return i0 | i1 << 8 | i2 << 16;
}
```
user: What is the c source code of the assembly code below?

```asm
<Triplet>:
  endbr64
  push   %r12
  mov    D6(%rip),%r12
  push   %rbp
  push   %rbx
  mov    (%r12),%edi
  call   <getc@plt>
  mov    (%r12),%edi
  mov    %eax,%ebp
  call   <getc@plt>
  mov    (%r12),%edi
  mov    %eax,%ebx
  call   <getc@plt>
  shl    $0x8,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Triplet(FILE *fp) {
  int i0;
  int i1;
  int i2;
  i0 = getc(stdin);
  i1 = getc(stdin);
  i2 = getc(stdin);
  return i0 | i1 << 8 | i2 << 16;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %edi,-0x3f4(%rbp)
  mov    %rsi,-0x400(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x3f0(%rbp)
  movq   $0x0,-0x3e8(%rbp)
  lea    -0x3e0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7b,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x400(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Copied a %u-byte-long buffer


assistant: ```c
int main(int argc, char **argv) {
  char buffer[1000] = "";
  strcpy(buffer, argv[1]);
  printf("Copied a %u-byte-long buffer\n", strlen(buffer));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7b,%ecx
  rep stos %rax,%es:(%rdi)
  mov    0x8(%rsi),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: Copied a %u-byte-long buffer


assistant: ```c
int main(int argc, char **argv) {
  char buffer[1000] = "";
  strcpy(buffer, argv[1]);
  printf("Copied a %u-byte-long buffer\n", strlen(buffer));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x7b,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x3f0,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: Copied a %u-byte-long buffer


assistant: ```c
int main(int argc, char **argv) {
  char buffer[1000] = "";
  strcpy(buffer, argv[1]);
  printf("Copied a %u-byte-long buffer\n", strlen(buffer));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x7b,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x3f0,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: Copied a %u-byte-long buffer


assistant: ```c
int main(int argc, char **argv) {
  char buffer[1000] = "";
  strcpy(buffer, argv[1]);
  printf("Copied a %u-byte-long buffer\n", strlen(buffer));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L13:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %esi,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_is_digit@plt>
  cmp    $0x1,%eax
  je     L13
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int _atoi(const char **str) {
  unsigned int i = 0U;
  while (_is_digit(**str) == 1) {
    i = i * 10U + (unsigned int)(*((*str)++) - '0');
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_atoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L19
L5:
  lea    0x0(%rbp,%rbp,4),%edx
  mov    (%rbx),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rbx)
  movsbl (%rax),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
L19:
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <_is_digit@plt>
  cmp    $0x1,%eax
  je     L5
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int _atoi(const char **str) {
  unsigned int i = 0U;
  while (_is_digit(**str) == 1) {
    i = i * 10U + (unsigned int)(*((*str)++) - '0');
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_atoi>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdx
  lea    (%r12,%r12,4),%ecx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rbx)
  movsbl (%rdx),%edx
  lea    -0x30(%rdx,%rcx,2),%r12d
L17:
  movsbl (%rax),%edi
  call   <_is_digit@plt>
  cmp    $0x1,%eax
  je     L12
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int _atoi(const char **str) {
  unsigned int i = 0U;
  while (_is_digit(**str) == 1) {
    i = i * 10U + (unsigned int)(*((*str)++) - '0');
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_atoi>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdx
  lea    (%r12,%r12,4),%ecx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rbx)
  movsbl (%rdx),%edx
  lea    -0x30(%rdx,%rcx,2),%r12d
L16:
  movsbl (%rax),%edi
  call   <_is_digit@plt>
  cmp    $0x1,%eax
  je     L12
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int _atoi(const char **str) {
  unsigned int i = 0U;
  while (_is_digit(**str) == 1) {
    i = i * 10U + (unsigned int)(*((*str)++) - '0');
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pr_tocs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x13,%edi
  call   <ass_tk@plt>
  mov    $0x7,%edi
  call   <sendtype@plt>
  mov    $0x13,%edi
  call   <pr_token@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pr_tocs() {
  ass_tk(19);
  sendtype(7);
  pr_token(19);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pr_tocs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%edi
  call   <ass_tk@plt>
  mov    $0x7,%edi
  call   <sendtype@plt>
  mov    $0x13,%edi
  call   <pr_token@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pr_tocs() {
  ass_tk(19);
  sendtype(7);
  pr_token(19);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pr_tocs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%edi
  call   <ass_tk@plt>
  mov    $0x7,%edi
  call   <sendtype@plt>
  mov    $0x13,%edi
  add    $0x8,%rsp
  jmp    1070 <pr_token@plt>
```

assistant: ```c
void pr_tocs() {
  ass_tk(19);
  sendtype(7);
  pr_token(19);
}
```
user: What is the c source code of the assembly code below:

```asm
<pr_tocs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%edi
  call   <ass_tk@plt>
  mov    $0x7,%edi
  call   <sendtype@plt>
  mov    $0x13,%edi
  add    $0x8,%rsp
  jmp    1070 <pr_token@plt>
```

assistant: ```c
void pr_tocs() {
  ass_tk(19);
  sendtype(7);
  pr_token(19);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_strnequ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L59
L53:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L41
  mov    $0x0,%eax
  jmp    L66
L41:
  addq   $0x1,-0x8(%rbp)
L59:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L58
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L58
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L58
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L53
L58:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L88
  mov    $0x0,%eax
  jmp    L66
L88:
  mov    $0x1,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strnequ(const char *s1, const char *s2, size_t n) {
  size_t i;
  i = 0;
  while (i < n && (s1[i] && s2[i]) && s1[i] == s2[i]) {
    if (s1[i] != s2[i])
      return (0);
    i++;
  }
  if (s1[i] != s2[i])
    return (0);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strnequ>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L30
L24:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L36
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L36
  test   %r8b,%r8b
  je     L36
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L24
  mov    %rdx,%rax
L36:
  movzbl (%rsi,%rax,1),%edx
  cmp    %dl,(%rdi,%rax,1)
  sete   %al
  movzbl %al,%eax
  ret
L30:
  mov    %rdx,%rax
  jmp    L36
```

assistant: ```c
int ft_strnequ(const char *s1, const char *s2, size_t n) {
  size_t i;
  i = 0;
  while (i < n && (s1[i] && s2[i]) && s1[i] == s2[i]) {
    if (s1[i] != s2[i])
      return (0);
    i++;
  }
  if (s1[i] != s2[i])
    return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strnequ>:
  endbr64
  xor    %ecx,%ecx
  test   %rdx,%rdx
  jne    L61
  jmp    L63
  nopl   (%rax)
L17:
  test   %r9b,%r9b
  je     L16
  test   %al,%al
  je     L16
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L14
L61:
  movzbl (%rdi,%rcx,1),%r8d
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %r9b,%r8b
  sete   %al
  test   %r8b,%r8b
  jne    L17
L16:
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rsi,%rdx,1),%eax
  cmp    %al,(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L63:
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  sete   %al
  jmp    L16
```

assistant: ```c
int ft_strnequ(const char *s1, const char *s2, size_t n) {
  size_t i;
  i = 0;
  while (i < n && (s1[i] && s2[i]) && s1[i] == s2[i]) {
    if (s1[i] != s2[i])
      return (0);
    i++;
  }
  if (s1[i] != s2[i])
    return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strnequ>:
  endbr64
  xor    %ecx,%ecx
  test   %rdx,%rdx
  jne    L29
  jmp    L15
  nopl   (%rax)
L12:
  test   %r9b,%r9b
  je     L60
  test   %al,%al
  je     L60
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L4
L29:
  movzbl (%rdi,%rcx,1),%r8d
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %r9b,%r8b
  sete   %al
  test   %r8b,%r8b
  jne    L12
L60:
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rdx,1),%eax
  cmp    %al,(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L15:
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  sete   %al
  jmp    L60
```

assistant: ```c
int ft_strnequ(const char *s1, const char *s2, size_t n) {
  size_t i;
  i = 0;
  while (i < n && (s1[i] && s2[i]) && s1[i] == s2[i]) {
    if (s1[i] != s2[i])
      return (0);
    i++;
  }
  if (s1[i] != s2[i])
    return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<insort_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rax
  mov    %esi,%edx
  mov    $0x1,%r12d
  jmp    L22
L3:
  mov    %r12d,%ebx
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rax,%rcx
  movss  (%rcx),%xmm1
  movaps %xmm1,%xmm4
  jmp    L14
L9:
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  sub    $0x4,%rcx
  lea    (%rax,%rcx,1),%rsi
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rax,%rcx
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rcx)
  sub    $0x1,%ebx
L14:
  test   %ebx,%ebx
  jle    L45
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  sub    $0x4,%rcx
  add    %rax,%rcx
  movss  (%rcx),%xmm0
  movaps %xmm4,%xmm2
  comiss %xmm2,%xmm0
  ja     L9
L45:
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rax,%rcx
  movaps %xmm4,%xmm3
  movss  %xmm3,(%rcx)
  add    $0x1,%r12d
L22:
  cmp    %edx,%r12d
  jl     L3
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void insort_float(array, len) register float array[];
register int len;
{
  register int i, j;
  register float temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<insort_float>:
  endbr64
  cmp    $0x1,%esi
  jle    L59
  lea    0x4(%rdi),%r8
  mov    $0x1,%ecx
  jmp    L43
L39:
  movslq %edx,%rdx
  movss  %xmm1,(%rdi,%rdx,4)
  add    $0x1,%ecx
  add    $0x4,%r8
  cmp    %ecx,%esi
  je     L59
L43:
  movss  (%r8),%xmm1
  mov    %r8,%rax
  mov    %ecx,%edx
  test   %ecx,%ecx
  jle    L39
L31:
  movss  -0x4(%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L39
  movss  %xmm0,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L31
  jmp    L39
L59:
  ret
```

assistant: ```c
void insort_float(array, len) register float array[];
register int len;
{
  register int i, j;
  register float temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<insort_float>:
  endbr64
  lea    0x4(%rdi),%rcx
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L2
  nopl   0x0(%rax,%rax,1)
L9:
  movss  (%rcx),%xmm1
  mov    %rcx,%rax
  nop
L36:
  movss  -0x4(%rax),%xmm0
  mov    %rax,%rdx
  comiss %xmm1,%xmm0
  jbe    L22
  movss  %xmm0,(%rax)
  lea    -0x4(%rdx),%rax
  cmp    %rax,%rdi
  jne    L36
  mov    %rdi,%rdx
L22:
  add    $0x1,%r8d
  movss  %xmm1,(%rdx)
  add    $0x4,%rcx
  cmp    %r8d,%esi
  jne    L9
L2:
  ret
```

assistant: ```c
void insort_float(array, len) register float array[];
register int len;
{
  register int i, j;
  register float temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insort_float>:
  endbr64
  lea    0x4(%rdi),%rcx
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L2
  nopl   0x0(%rax,%rax,1)
L14:
  movss  (%rcx),%xmm1
  mov    %rcx,%rax
  nop
L31:
  movss  -0x4(%rax),%xmm0
  mov    %rax,%rdx
  comiss %xmm1,%xmm0
  jbe    L32
  movss  %xmm0,(%rax)
  lea    -0x4(%rdx),%rax
  cmp    %rdi,%rax
  jne    L31
  mov    %rdi,%rdx
L32:
  add    $0x1,%r8d
  movss  %xmm1,(%rdx)
  add    $0x4,%rcx
  cmp    %r8d,%esi
  jne    L14
L2:
  ret
```

assistant: ```c
void insort_float(array, len) register float array[];
register int len;
{
  register int i, j;
  register float temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chpl_decRefCountsForDomainsInArrayEltTypes3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <compilerAssert@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chpl_decRefCountsForDomainsInArrayEltTypes3(void) {
  compilerAssert();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<chpl_decRefCountsForDomainsInArrayEltTypes3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <compilerAssert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void chpl_decRefCountsForDomainsInArrayEltTypes3(void) {
  compilerAssert();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<chpl_decRefCountsForDomainsInArrayEltTypes3>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <compilerAssert@plt>
```

assistant: ```c
void chpl_decRefCountsForDomainsInArrayEltTypes3(void) {
  compilerAssert();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<chpl_decRefCountsForDomainsInArrayEltTypes3>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <compilerAssert@plt>
```

assistant: ```c
void chpl_decRefCountsForDomainsInArrayEltTypes3(void) {
  compilerAssert();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<synaptics_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x2ff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <psmouse_command@plt>
  test   %rax,%rax
  je     L11
  mov    $0xffffffff,%eax
  jmp    L21
L11:
  movzbl -0xa(%rbp),%eax
  cmp    $0xaa,%al
  jne    L16
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  jne    L16
  mov    $0x0,%eax
  jmp    L21
L16:
  mov    $0xffffffff,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int synaptics_reset(struct psmouse *psmouse) {
  unsigned char r[2];
  if (psmouse_command(psmouse, r, 0x02ff))
    return -1;
  if (r[0] == 0xaa && r[1] == 0x00)
    return 0;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<synaptics_reset>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  mov    $0x2ff,%edx
  call   <psmouse_command@plt>
  test   %rax,%rax
  jne    L33
  cmpb   $0xaa,0x6(%rsp)
  jne    L22
  movzbl 0x7(%rsp),%eax
  neg    %al
  sbb    %eax,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x18,%rsp
  ret
L33:
  mov    $0xffffffff,%eax
  jmp    L17
L22:
  mov    $0xffffffff,%eax
  jmp    L17
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synaptics_reset(struct psmouse *psmouse) {
  unsigned char r[2];
  if (psmouse_command(psmouse, r, 0x02ff))
    return -1;
  if (r[0] == 0xaa && r[1] == 0x00)
    return 0;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<synaptics_reset>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2ff,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  call   <psmouse_command@plt>
  test   %rax,%rax
  jne    L32
  cmpb   $0xaa,0x6(%rsp)
  jne    L32
  movzbl 0x7(%rsp),%eax
  neg    %al
  sbb    %eax,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L32:
  mov    $0xffffffff,%eax
  jmp    L10
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synaptics_reset(struct psmouse *psmouse) {
  unsigned char r[2];
  if (psmouse_command(psmouse, r, 0x02ff))
    return -1;
  if (r[0] == 0xaa && r[1] == 0x00)
    return 0;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<synaptics_reset>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2ff,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  call   <psmouse_command@plt>
  test   %rax,%rax
  jne    L20
  cmpb   $0xaa,0x6(%rsp)
  jne    L20
  movzbl 0x7(%rsp),%eax
  neg    %al
  sbb    %eax,%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%eax
  jmp    L22
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synaptics_reset(struct psmouse *psmouse) {
  unsigned char r[2];
  if (psmouse_command(psmouse, r, 0x02ff))
    return -1;
  if (r[0] == 0xaa && r[1] == 0x00)
    return 0;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stripcomment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L8
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L38
L8:
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
L38:
  leave
  ret
```

assistant: ```c
void stripcomment(char *str) {
  int i, len;
  len = strlen(str);
  for (i = 0; i < len; i++) {
    if (str[i] == '#') {
      str[i] = '\0';
      return;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stripcomment>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L22
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rcx
L17:
  cmpb   $0x23,(%rdx)
  je     L37
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L17
  jmp    L22
L37:
  movb   $0x0,(%rdx)
L22:
  pop    %rbx
  ret
```

assistant: ```c
void stripcomment(char *str) {
  int i, len;
  len = strlen(str);
  for (i = 0; i < len; i++) {
    if (str[i] == '#') {
      str[i] = '\0';
      return;
    }
  }
}
```