ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_expr>:
  endbr64
  push   %rbx
  test   %edi,%edi
  je     L8
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  jg     L24
L8:
  mov    $0x0,%eax
  call   <gen_variable_expr@plt>
L6:
  pop    %rbx
  ret
L24:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    $0x13,%eax
  jle    L9
  mov    %ebx,%edi
  call   <gen_arith_expr@plt>
  jmp    L6
L9:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <gen_test_expr@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <gen_expr>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <gen_expr>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D14
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string

tool: D24: (

tool: D14:  ? 

tool: D22:  : 

tool: D15: )

assistant: ```c
void gen_expr(unsigned int level) {
  if (!level || rand() % 100 < 5) {
    gen_variable_expr();
    return;
  }
  if (rand() % 100 < 20) {
    printf("(");
    gen_test_expr(level);
    printf(" ? ");
    gen_expr(level);
    printf(" : ");
    gen_expr(level);
    printf(")");
    return;
  }
  gen_arith_expr(level);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gen_expr>:
  endbr64
  test   %edi,%edi
  je     L19
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  mov    $0x0,%eax
  jg     L21
  pop    %rbp
  jmp    1090 <gen_variable_expr@plt>
  nopl   0x0(%rax)
L21:
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    $0x13,%eax
  jle    L4
  mov    %ebp,%edi
  pop    %rbp
  jmp    10c0 <gen_arith_expr@plt>
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  jmp    1090 <gen_variable_expr@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <gen_test_expr@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <gen_expr>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <gen_expr>
  lea    D9(%rip),%rdi
  pop    %rbp
  jmp    10a0 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D21
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D7: (

tool: D38:  ? 

tool: D21:  : 

tool: D9: )

assistant: ```c
void gen_expr(unsigned int level) {
  if (!level || rand() % 100 < 5) {
    gen_variable_expr();
    return;
  }
  if (rand() % 100 < 20) {
    printf("(");
    gen_test_expr(level);
    printf(" ? ");
    gen_expr(level);
    printf(" : ");
    gen_expr(level);
    printf(")");
    return;
  }
  gen_arith_expr(level);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <bar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  bar(1);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <bar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bar(1);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <bar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bar(1);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <bar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bar(1);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqrOfSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  leave
  ret
```

assistant: ```c
int sqrOfSum(int x) {
  int sum = (1 + x) * x / 2;
  return pow(sum, 2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sqrOfSum>:
  endbr64
  sub    $0x8,%rsp
  lea    0x1(%rdi),%eax
  imul   %edi,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  mov    $0x2,%esi
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sqrOfSum(int x) {
  int sum = (1 + x) * x / 2;
  return pow(sum, 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqrOfSum>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    $0x2,%esi
  imul   %edi,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  jmp    1050 <pow@plt>
```

assistant: ```c
int sqrOfSum(int x) {
  int sum = (1 + x) * x / 2;
  return pow(sum, 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sqrOfSum>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    $0x2,%esi
  imul   %edi,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  jmp    1050 <pow@plt>
```

assistant: ```c
int sqrOfSum(int x) {
  int sum = (1 + x) * x / 2;
  return pow(sum, 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hammingWeight_naive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L14
L21:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  addl   $0x1,-0x4(%rbp)
L3:
  sarl   -0x8(%rbp)
L14:
  cmpl   $0x0,-0x8(%rbp)
  jg     L21
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hammingWeight_naive(uint32_t n) {
  uint32_t i;
  int dist;
  dist = 0;
  i = n;
  while (i > 0) {
    if (i & 1)
      dist++;
    i >>= 1;
  }
  return dist;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hammingWeight_naive>:
  endbr64
  test   %edi,%edi
  jle    L2
  mov    $0x0,%eax
L3:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  test   %edi,%edi
  jg     L3
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int hammingWeight_naive(uint32_t n) {
  uint32_t i;
  int dist;
  dist = 0;
  i = n;
  while (i > 0) {
    if (i & 1)
      dist++;
    i >>= 1;
  }
  return dist;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hammingWeight_naive>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L17
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  jne    L6
  ret
L17:
  ret
```

assistant: ```c
int hammingWeight_naive(uint32_t n) {
  uint32_t i;
  int dist;
  dist = 0;
  i = n;
  while (i > 0) {
    if (i & 1)
      dist++;
    i >>= 1;
  }
  return dist;
}
```
user: What is the c source code of the assembly code below?

```asm
<hammingWeight_naive>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L10
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  jne    L0
  ret
L10:
  ret
```

assistant: ```c
int hammingWeight_naive(uint32_t n) {
  uint32_t i;
  int dist;
  dist = 0;
  i = n;
  while (i > 0) {
    if (i & 1)
      dist++;
    i >>= 1;
  }
  return dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  movl   $0x28,-0x8(%rbp)
  jmp    L26
L15:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L0
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
L0:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D5: Ratio hit! [%d]


tool: D9: No hit! [%d]


assistant: ```c
void main(void) {
  int count = 0;
  int ratio = 5;
  int limit = 40;
  while (count < limit) {
    int rem = count % ratio;
    if (rem) {
      printf("Ratio hit! [%d]\n", count);
    } else {
      printf("No hit! [%d]\n", count);
    }
    count++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
  lea    D18(%rip),%rbp
  jmp    L21
L2:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L34:
  add    $0x1,%ebx
  cmp    $0x28,%ebx
  je     L39
L21:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  je     L2
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L34
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: string

tool: D10: No hit! [%d]


tool: D18: Ratio hit! [%d]


assistant: ```c
void main(void) {
  int count = 0;
  int ratio = 5;
  int limit = 40;
  while (count < limit) {
    int rem = count % ratio;
    if (rem) {
      printf("Ratio hit! [%d]\n", count);
    } else {
      printf("No hit! [%d]\n", count);
    }
    count++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x28,%ebx
  je     L30
L28:
  imul   $0xcccccccd,%ebx,%eax
  mov    %ebx,%esi
  cmp    $0x33333333,%eax
  ja     L14
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x28,%ebx
  jne    L28
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string

tool: D5: No hit! [%d]


tool: D10: Ratio hit! [%d]


assistant: ```c
void main(void) {
  int count = 0;
  int ratio = 5;
  int limit = 40;
  while (count < limit) {
    int rem = count % ratio;
    if (rem) {
      printf("Ratio hit! [%d]\n", count);
    } else {
      printf("No hit! [%d]\n", count);
    }
    count++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x28,%ebx
  je     L35
L4:
  imul   $0xcccccccd,%ebx,%eax
  mov    %ebx,%esi
  cmp    $0x33333333,%eax
  ja     L23
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x28,%ebx
  jne    L4
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D5
datatype: string

tool: D6: No hit! [%d]


tool: D5: Ratio hit! [%d]


assistant: ```c
void main(void) {
  int count = 0;
  int ratio = 5;
  int limit = 40;
  while (count < limit) {
    int rem = count % ratio;
    if (rem) {
      printf("Ratio hit! [%d]\n", count);
    } else {
      printf("No hit! [%d]\n", count);
    }
    count++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ssl_x509_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L20
L4:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <X509_print@plt>
  lea    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_get_mem_data@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L24
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
  mov    $0x0,%eax
  jmp    L20
L24:
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
  mov    -0x10(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
char *ssl_x509_to_str(X509 *crt) {
  BIO *bio;
  char *p, *ret;
  size_t sz;
  bio = BIO_new(BIO_s_mem());
  if (!bio)
    return NULL;
  X509_print(bio, crt);
  sz = BIO_get_mem_data(bio, &p);
  if (!(ret = malloc(sz + 1))) {
    BIO_free(bio);
    return NULL;
  }
  memcpy(ret, p, sz);
  ret[sz] = '\0';
  BIO_free(bio);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ssl_x509_to_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L42
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <X509_print@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <BIO_get_mem_data@plt>
  mov    %rax,%r12
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L43
  mov    %r12,%rdx
  mov    (%rsp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  mov    %rbx,%rdi
  call   <BIO_free@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    %rbx,%rdi
  call   <BIO_free@plt>
  jmp    L33
L42:
  mov    %rax,%rbp
  jmp    L33
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ssl_x509_to_str(X509 *crt) {
  BIO *bio;
  char *p, *ret;
  size_t sz;
  bio = BIO_new(BIO_s_mem());
  if (!bio)
    return NULL;
  X509_print(bio, crt);
  sz = BIO_get_mem_data(bio, &p);
  if (!(ret = malloc(sz + 1))) {
    BIO_free(bio);
    return NULL;
  }
  memcpy(ret, p, sz);
  ret[sz] = '\0';
  BIO_free(bio);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<ssl_x509_to_str>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L30
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <X509_print@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <BIO_get_mem_data@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    (%rsp),%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L9:
  mov    %rbp,%rdi
  call   <BIO_free@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L30:
  xor    %r12d,%r12d
  jmp    L27
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ssl_x509_to_str(X509 *crt) {
  BIO *bio;
  char *p, *ret;
  size_t sz;
  bio = BIO_new(BIO_s_mem());
  if (!bio)
    return NULL;
  X509_print(bio, crt);
  sz = BIO_get_mem_data(bio, &p);
  if (!(ret = malloc(sz + 1))) {
    BIO_free(bio);
    return NULL;
  }
  memcpy(ret, p, sz);
  ret[sz] = '\0';
  BIO_free(bio);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssl_x509_to_str>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L31
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <X509_print@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <BIO_get_mem_data@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  mov    (%rsp),%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L15:
  mov    %rbp,%rdi
  call   <BIO_free@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L31:
  xor    %r12d,%r12d
  jmp    L13
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ssl_x509_to_str(X509 *crt) {
  BIO *bio;
  char *p, *ret;
  size_t sz;
  bio = BIO_new(BIO_s_mem());
  if (!bio)
    return NULL;
  X509_print(bio, crt);
  sz = BIO_get_mem_data(bio, &p);
  if (!(ret = malloc(sz + 1))) {
    BIO_free(bio);
    return NULL;
  }
  memcpy(ret, p, sz);
  ret[sz] = '\0';
  BIO_free(bio);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_17_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0xff,-0x10(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%eax
  and    -0x8(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_17_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_17_1_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  or     %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_17_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_17_1_1>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  shl    $0x8,%edi
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_17_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_17_1_1>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  shl    $0x8,%edi
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_17_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
L61:
  lea    -0x40(%rbp),%rcx
  lea    -0x44(%rbp),%rdx
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x48(%rbp),%eax
  test   %eax,%eax
  js     L61
  mov    -0x44(%rbp),%eax
  test   %eax,%eax
  js     L61
  mov    -0x44(%rbp),%eax
  cmp    $0x1,%eax
  jg     L61
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  js     L61
  mov    -0x40(%rbp),%eax
  cmp    $0x7,%eax
  jg     L61
  jmp    L93
L87:
  mov    -0x48(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x48(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x48(%rbp)
  addl   $0x1,-0x3c(%rbp)
L93:
  mov    -0x48(%rbp),%eax
  test   %eax,%eax
  jg     L87
  mov    -0x40(%rbp),%eax
  mov    -0x44(%rbp),%edx
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  jmp    L0
L71:
  mov    -0x38(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    %eax,-0x38(%rbp)
  subl   $0x1,-0x34(%rbp)
L0:
  cmpl   $0x0,-0x34(%rbp)
  jns    L71
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D0
type: string

tool: D14: %d %d %d

tool: D0: %d

assistant: ```c
int main() {
  int n, v, p, i = 0, array[8], a = 0, j = 0;
  do {
    scanf("%d %d %d", &n, &v, &p);
  } while (n < 0 || v < 0 || v > 1 || p < 0 || p > 7);
  while (n > 0) {
    array[i] = n % 2;
    n = n / 2;
    i++;
  }
  array[p] = v;
  for (j = i - 1; j >= 0; j--) {
    a = (a * 2) + array[j];
  }
  printf("%d", a);
}
```