user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D52(%rip),%r12
  push   %rbp
  lea    D39(%rip),%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  nopl   0x0(%rax)
L108:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L108
  mov    (%rsp),%eax
  movl   $0x0,0x30(%rsp)
  xor    %ebp,%ebp
  test   $0x1,%al
  jne    L113
  mov    %eax,0x30(%rsp)
  mov    $0x1,%ebp
L113:
  mov    0x4(%rsp),%eax
  movl   $0x0,0x34(%rsp)
  test   $0x1,%al
  jne    L120
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L120:
  mov    0x8(%rsp),%eax
  movl   $0x0,0x38(%rsp)
  test   $0x1,%al
  jne    L4
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L4:
  mov    0xc(%rsp),%eax
  movl   $0x0,0x3c(%rsp)
  test   $0x1,%al
  jne    L10
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L10:
  mov    0x10(%rsp),%eax
  movl   $0x0,0x40(%rsp)
  test   $0x1,%al
  jne    L66
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L66:
  mov    0x14(%rsp),%eax
  movl   $0x0,0x44(%rsp)
  test   $0x1,%al
  jne    L143
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L143:
  mov    0x18(%rsp),%eax
  movl   $0x0,0x48(%rsp)
  test   $0x1,%al
  jne    L12
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L12:
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x4c(%rsp)
  test   $0x1,%al
  jne    L61
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
L61:
  mov    0x20(%rsp),%eax
  movl   $0x0,0x50(%rsp)
  test   $0x1,%al
  jne    L160
  movslq %ebp,%rdx
  movl   $0x0,0x54(%rsp)
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
  mov    0x24(%rsp),%eax
  test   $0x1,%al
  je     L79
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L140
L160:
  mov    0x24(%rsp),%eax
  movl   $0x0,0x54(%rsp)
  test   $0x1,%al
  jne    L141
L79:
  movslq %ebp,%rdx
  lea    D9(%rip),%rdi
  add    $0x1,%ebp
  mov    %eax,0x30(%rsp,%rdx,4)
  xor    %eax,%eax
  call   <printf@plt>
L140:
  lea    -0x1(%rbp),%eax
  lea    0x30(%rsp),%rbx
  lea    0x34(%rsp,%rax,4),%r12
  lea    D44(%rip),%rbp
  nopl   0x0(%rax)
L116:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L116
L50:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L141:
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jne    L140
  jmp    L50
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D52
type_guessed: string
name: parse_data
arguments: tag: D39
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D44
type_guessed: string

tool: D52: Inserisci un numero: 

tool: D39: %d

tool: D9: I numeri pari sono: 

tool: D44: %d 

assistant: ```c
int main() {
  int I;
  int vet[10];
  int pari[10];
  int K;
  for (I = 0; I < 10; I++) {
    printf("Inserisci un numero: ");
    scanf("%d", &vet[I]);
  }
  K = 0;
  for (I = 0; I < 10; I++) {
    pari[I] = 0;
    if (vet[I] % 2 == 0) {
      pari[K] = vet[I];
      K++;
    }
  }
  printf("I numeri pari sono: ");
  for (I = 0; I < K; I++) {
    printf("%d ", pari[I]);
  }
}
```