ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %al,-0x1c(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,-0x8(%rbp)
L39:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L15
  lea    D2(%rip),%rax
  cmp    %rax,-0x8(%rbp)
  ja     L39
L15:
  cmpb   $0x0,-0x1c(%rbp)
  je     L2
  jmp    L18
L58:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L18:
  lea    D2(%rip),%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L2
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L58
L2:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <_add@plt>
  leave
  ret
```

assistant: ```c
int _conv(int n, int digits, char pad) {
  static char buf[10];
  char *p = buf + sizeof(buf) - 2;
  do {
    *p-- = n % 10 + '0';
    n /= 10;
    --digits;
  } while (n > 0 && p > buf);
  if (pad)
    while (p > buf && digits-- > 0)
      *p-- = pad;
  return _add(++p, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_conv>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%ecx
  mov    %esi,%r9d
  mov    %edx,%r11d
  mov    %edx,%r8d
  lea    D12(%rip),%rdi
  lea    -0x8(%rdi),%r10
L56:
  sub    $0x1,%rdi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rdi)
  mov    %ecx,%edx
  mov    %eax,%ecx
  mov    %r9d,%esi
  sub    $0x1,%r9d
  cmp    %r10,%rdi
  jbe    L29
  cmp    $0x9,%edx
  jg     L56
L29:
  test   %r11b,%r11b
  je     L65
  lea    D11(%rip),%rax
  cmp    %rax,%rdi
  jbe    L65
  test   %r9d,%r9d
  jle    L65
  mov    %rdi,%rdx
  mov    %rax,%rcx
L60:
  sub    $0x1,%rdx
  mov    %r8b,0x1(%rdx)
  cmp    %rcx,%rdx
  je     L10
  lea    -0x1(%rdx),%eax
  sub    %edi,%eax
  add    %esi,%eax
  test   %eax,%eax
  jg     L60
  mov    %rdx,%rdi
  jmp    L65
L10:
  mov    %rdx,%rdi
L65:
  add    $0x1,%rdi
  mov    $0x0,%esi
  call   <_add@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _conv(int n, int digits, char pad) {
  static char buf[10];
  char *p = buf + sizeof(buf) - 2;
  do {
    *p-- = n % 10 + '0';
    n /= 10;
    --digits;
  } while (n > 0 && p > buf);
  if (pad)
    while (p > buf && digits-- > 0)
      *p-- = pad;
  return _add(++p, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_conv>:
  endbr64
  push   %rbx
  mov    %edx,%r11d
  mov    %edx,%ebx
  lea    D6(%rip),%rdx
  mov    %edi,%ecx
  mov    %esi,%r8d
  lea    -0x8(%rdx),%r9
  jmp    L62
  nopl   0x0(%rax)
L19:
  cmp    $0x9,%esi
  jle    L73
L62:
  movslq %ecx,%rax
  mov    %ecx,%esi
  mov    %rdx,%r10
  sub    $0x1,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  mov    %ecx,%esi
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,0x1(%rdx)
  mov    %ecx,%esi
  mov    %eax,%ecx
  mov    %r8d,%eax
  sub    $0x1,%r8d
  cmp    %r9,%rdx
  ja     L19
L73:
  test   %bl,%bl
  je     L21
  cmp    %r9,%rdx
  jbe    L21
  test   %r8d,%r8d
  jle    L21
  sub    $0x1,%eax
  sub    %edx,%eax
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L64:
  lea    (%rax,%rdx,1),%ecx
  test   %ecx,%ecx
  jle    L21
L37:
  mov    %rdx,%r10
  sub    $0x1,%rdx
  mov    %r11b,0x1(%rdx)
  cmp    %r9,%rdx
  jne    L64
L21:
  xor    %esi,%esi
  mov    %r10,%rdi
  pop    %rbx
  jmp    1050 <_add@plt>
```

assistant: ```c
int _conv(int n, int digits, char pad) {
  static char buf[10];
  char *p = buf + sizeof(buf) - 2;
  do {
    *p-- = n % 10 + '0';
    n /= 10;
    --digits;
  } while (n > 0 && p > buf);
  if (pad)
    while (p > buf && digits-- > 0)
      *p-- = pad;
  return _add(++p, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Pthread_cond_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_cond_destroy@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_failure@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: pthread_cond_destroy

assistant: ```c
void Pthread_cond_destroy(pthread_cond_t *cond) {
  int retval;
  assert(cond != NULL);
  retval = pthread_cond_destroy(cond);
  if (retval != 0)
    Sys_failure("pthread_cond_destroy");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Pthread_cond_destroy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <pthread_cond_destroy@plt>
  test   %eax,%eax
  jne    L3
L14:
  pop    %rbx
  ret
L3:
  lea    D3(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L14
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: pthread_cond_destroy

assistant: ```c
void Pthread_cond_destroy(pthread_cond_t *cond) {
  int retval;
  assert(cond != NULL);
  retval = pthread_cond_destroy(cond);
  if (retval != 0)
    Sys_failure("pthread_cond_destroy");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Pthread_cond_destroy>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  mov    %rdi,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <pthread_cond_destroy@plt>
  test   %eax,%eax
  jne    L4
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1080 <Sys_failure@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: pthread_cond_destroy

assistant: ```c
void Pthread_cond_destroy(pthread_cond_t *cond) {
  int retval;
  assert(cond != NULL);
  retval = pthread_cond_destroy(cond);
  if (retval != 0)
    Sys_failure("pthread_cond_destroy");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Pthread_cond_destroy>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  mov    %rdi,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <pthread_cond_destroy@plt>
  test   %eax,%eax
  jne    L5
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    D3(%rip),%rdi
  pop    %rbp
  jmp    1080 <Sys_failure@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string

tool: D3: pthread_cond_destroy

assistant: ```c
void Pthread_cond_destroy(pthread_cond_t *cond) {
  int retval;
  assert(cond != NULL);
  retval = pthread_cond_destroy(cond);
  if (retval != 0)
    Sys_failure("pthread_cond_destroy");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<slaDtt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sla_dtt_@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double slaDtt(double utc) {
  double UTC;
  double RETVAL;
  double retval;
  UTC = utc;
  RETVAL = sla_dtt_(&UTC);
  retval = RETVAL;
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<slaDtt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  mov    %rsp,%rdi
  call   <sla_dtt_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double slaDtt(double utc) {
  double UTC;
  double RETVAL;
  double retval;
  UTC = utc;
  RETVAL = sla_dtt_(&UTC);
  retval = RETVAL;
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<slaDtt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movsd  %xmm0,(%rsp)
  call   <sla_dtt_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double slaDtt(double utc) {
  double UTC;
  double RETVAL;
  double retval;
  UTC = utc;
  RETVAL = sla_dtt_(&UTC);
  retval = RETVAL;
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slaDtt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movsd  %xmm0,(%rsp)
  call   <sla_dtt_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double slaDtt(double utc) {
  double UTC;
  double RETVAL;
  double retval;
  UTC = utc;
  RETVAL = sla_dtt_(&UTC);
  retval = RETVAL;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  imul   %edx,%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L8
L2:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float **fmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  float **m, *p;
  m = (float **)malloc((maxx - minx + 1) * sizeof(float *));
  assert(m);
  m -= minx;
  p = (float *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(float));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,0xc(%rsp)
  mov    %ecx,%r13d
  mov    %esi,%r14d
  sub    %edi,%r14d
  add    $0x1,%r14d
  movslq %r14d,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  movslq %r12d,%r15
  lea    0x0(,%r15,8),%rax
  mov    %rbx,%rcx
  sub    %rax,%rcx
  mov    %rcx,(%rsp)
  sub    0xc(%rsp),%r13d
  lea    0x1(%r13),%edi
  imul   %r14d,%edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %r12d,%ebp
  jl     L16
  movslq %r13d,%r13
  lea    0x4(,%r13,4),%rdx
  movslq 0xc(%rsp),%rax
  shl    $0x2,%rax
  sub    %rax,%r14
  sub    %r12d,%ebp
  lea    0x1(%r15,%rbp,1),%rax
  mov    (%rsp),%rcx
  lea    (%rcx,%rax,8),%rax
L18:
  mov    %r14,(%rbx)
  add    %rdx,%r14
  add    $0x8,%rbx
  cmp    %rax,%rbx
  jne    L18
L16:
  mov    (%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float **fmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  float **m, *p;
  m = (float **)malloc((maxx - minx + 1) * sizeof(float *));
  assert(m);
  m -= minx;
  p = (float *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(float));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fmatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  sub    %edi,%r14d
  mov    %edi,%r13d
  push   %r12
  movslq %edx,%r12
  push   %rbp
  lea    0x1(%r14),%ebp
  push   %rbx
  movslq %ebp,%rdi
  shl    $0x3,%rdi
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %ecx,(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <assert@plt>
  mov    (%rsp),%edx
  movslq %r13d,%rcx
  mov    %rbx,%r15
  lea    0x0(,%rcx,8),%rax
  mov    %rcx,0x8(%rsp)
  sub    %r12d,%edx
  sub    %rax,%r15
  lea    0x1(%rdx),%edi
  mov    %edx,(%rsp)
  imul   %ebp,%edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  cmp    %r13d,%esi
  jl     L13
  mov    0x8(%rsp),%rcx
  movslq (%rsp),%rdx
  shl    $0x2,%r12
  mov    %rbp,%rax
  sub    %r12,%rax
  lea    0x1(%rcx,%r14,1),%rcx
  lea    0x4(,%rdx,4),%rsi
  mov    %rbx,%rdx
  lea    (%r15,%rcx,8),%rcx
L6:
  mov    %rax,(%rdx)
  add    $0x8,%rdx
  add    %rsi,%rax
  cmp    %rcx,%rdx
  jne    L6
L13:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float **fmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  float **m, *p;
  m = (float **)malloc((maxx - minx + 1) * sizeof(float *));
  assert(m);
  m -= minx;
  p = (float *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(float));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fmatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  movslq %edx,%r13
  mov    %esi,%edx
  push   %r12
  sub    %edi,%edx
  mov    %ecx,%r12d
  push   %rbp
  add    $0x1,%edx
  sub    %r13d,%r12d
  push   %rbx
  movslq %edx,%rdi
  shl    $0x3,%rdi
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %edx,(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <assert@plt>
  mov    (%rsp),%edx
  lea    0x1(%r12),%edi
  movslq %r14d,%rcx
  lea    0x0(,%rcx,8),%rax
  mov    %rbx,%r15
  mov    %rcx,0x8(%rsp)
  imul   %edx,%edi
  sub    %rax,%r15
  movslq %edi,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  cmp    %r14d,%esi
  jl     L32
  shl    $0x2,%r13
  movslq %r12d,%r12
  mov    0x8(%rsp),%rcx
  add    $0x1,%r12
  neg    %r13
  cmp    %r14d,%esi
  lea    0x0(,%r12,4),%rdi
  je     L17
  mov    (%rsp),%edx
  lea    (%rdi,%rbp,1),%rax
  movq   %rbp,%xmm1
  movq   %r13,%xmm3
  movq   %rax,%xmm4
  lea    0x0(,%r12,8),%rax
  punpcklqdq %xmm3,%xmm3
  mov    %edx,%ecx
  movq   %rax,%xmm2
  punpcklqdq %xmm4,%xmm1
  mov    %rbx,%rax
  shr    %ecx
  punpcklqdq %xmm2,%xmm2
  shl    $0x4,%rcx
  add    %rbx,%rcx
  nopl   0x0(%rax)
L12:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddq  %xmm2,%xmm1
  paddq  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L12
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  mov    %eax,%ecx
  add    %eax,%r14d
  imul   %rdi,%rcx
  add    %rcx,%rbp
  cmp    %eax,%edx
  je     L32
  movslq %r14d,%rcx
L17:
  lea    0x0(%rbp,%r13,1),%rax
  mov    %rax,(%r15,%rcx,8)
L32:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float **fmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  float **m, *p;
  m = (float **)malloc((maxx - minx + 1) * sizeof(float *));
  assert(m);
  m -= minx;
  p = (float *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(float));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_107_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_107_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = T | S;
  stk3 = *D & stk4;
  stk2 = S ^ stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rop3_107_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%sil
  xor    %eax,%edx
  xor    %edx,%esi
  or     %eax,%esi
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_107_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = T | S;
  stk3 = *D & stk4;
  stk2 = S ^ stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_107_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  or     %eax,%esi
  xor    %eax,%edx
  and    (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_107_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = T | S;
  stk3 = *D & stk4;
  stk2 = S ^ stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_107_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  or     %eax,%esi
  xor    %eax,%edx
  and    (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_107_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = T | S;
  stk3 = *D & stk4;
  stk2 = S ^ stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L30
L13:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
  mov    $0xffffffff,%eax
  jmp    L19
L8:
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L13
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *a, const void *b, size_t n) {
  for (uintptr_t i = 0; i < n; i++) {
    if (((char *)a)[i] != ((char *)b)[i]) {
      return -1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L19
  mov    $0x0,%eax
L1:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L26
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L1
  mov    $0x0,%eax
  ret
L19:
  mov    $0x0,%eax
  ret
L26:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int memcmp(const void *a, const void *b, size_t n) {
  for (uintptr_t i = 0; i < n; i++) {
    if (((char *)a)[i] != ((char *)b)[i]) {
      return -1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L21
  xor    %eax,%eax
  jmp    L3
  nopl   (%rax)
L25:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L21
L3:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L25
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *a, const void *b, size_t n) {
  for (uintptr_t i = 0; i < n; i++) {
    if (((char *)a)[i] != ((char *)b)[i]) {
      return -1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L13
  xor    %eax,%eax
  jmp    L37
  nopl   (%rax)
L17:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L13
L37:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L17
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *a, const void *b, size_t n) {
  for (uintptr_t i = 0; i < n; i++) {
    if (((char *)a)[i] != ((char *)b)[i]) {
      return -1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a4(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1a4(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a4(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x1a0(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <showPowerset@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D2: how many elements in alphabet set?

tool: D13: %d

assistant: ```c
int main(void) {
  int n = 0;
  int list[100];
  puts("how many elements in alphabet set?");
  scanf("%d", &n);
  showPowerset(list, 0, n - 1);
  return 0;
}
```