user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x9000(%rsp),%r11
L64:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L64
  sub    $0xc78,%rsp
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x9c84(%rbp),%rsi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movslq -0x9c84(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L0
L86:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L86
L0:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L102
L40:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L101
  lea    -0x9c80(%rbp),%rax
  lea    -0x9c58(%rbp),%r12
  movq   $0x0,-0x9ca0(%rbp)
  mov    %rax,-0x9c98(%rbp)
L63:
  mov    -0x9c98(%rbp),%r14
  mov    %rsp,%r15
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %r14,%r12
  jne    L37
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L16
L52:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L52
L16:
  sub    $0x30,%rsp
  orq    $0x0,0x28(%rsp)
  mov    $0xa,%esi
  movdqu -0x9c6c(%rbp),%xmm0
  movdqu -0x9c7c(%rbp),%xmm1
  psubd  -0x9c70(%rbp),%xmm0
  psubd  -0x9c80(%rbp),%xmm1
  lea    0x3(%rsp),%rdi
  mov    %rdi,%rax
  and    $0xfffffffffffffffc,%rdi
  shr    $0x2,%rax
  movl   $0x0,0x24(,%rax,4)
  movups %xmm1,0x0(,%rax,4)
  movups %xmm0,0x10(,%rax,4)
  call   <lonlen@plt>
  mov    -0x9ca0(%rbp),%r14
  mov    $0xa,%edi
  mov    %eax,0x0(%r13,%r14,4)
  add    $0x1,%r14
  call   <putchar@plt>
  mov    -0x9c84(%rbp),%eax
  mov    %r14,-0x9ca0(%rbp)
  mov    %r15,%rsp
  cmp    %r14d,%eax
  jg     L63
  test   %eax,%eax
  jle    L101
  xor    %ebx,%ebx
  lea    D8(%rip),%r12
L1:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x9c84(%rbp)
  jg     L1
L101:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L123
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L102:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L40
L123:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D15: %d

tool: D8: %d 


assistant: ```c
int main(void) {
  int N;
  int ar[10000];
  scanf("%d", &N);
  printf("\n");
  int i, l = 0, j, k = 0, count = 0;
  int len[N];
  for (i = 0; i < N; i++) {
    count = 0;
    for (j = 0; j < 10; j++) {
      scanf("%d", &ar[j]);
      count++;
    }
    int r[count];
    k = 0;
    for (j = 0; j < (count - 2); j++) {
      r[k++] = ar[j + 1] - ar[j];
    }
    r[count - 1] = 0;
    len[l++] = lonlen(r, count);
    printf("\n");
  }
  for (i = 0; i < N; i++)
    printf("%d \n", len[i]);
  return 0;
}
```