ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<inchi_fgetsTab>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L47:
  cmp    %r12d,%ebx
  jge    L69
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L77
  add    $0x1,%ebx
  cmp    $0x9,%eax
  je     L56
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    $0xa,%eax
  jne    L47
L52:
  movslq %ebx,%rbx
  add    %rbp,%rbx
  jmp    L68
  nopl   0x0(%rax)
L56:
  movb   $0xa,(%r14)
  movslq %ebx,%rbx
  add    %rbp,%rbx
L68:
  movb   $0x0,(%rbx)
  mov    %rbp,%rax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L77:
  test   %ebx,%ebx
  jne    L52
L11:
  xor    %eax,%eax
  jmp    L9
L69:
  test   %ebx,%ebx
  jne    L52
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L11
  mov    %rbp,%rbx
  jmp    L68
```

assistant: ```c
char *inchi_fgetsTab(char *szLine, int len, FILE *f) {
  int length = 0, c = 0;
  len--;
  while (length < len && EOF != (c = fgetc(f))) {
    if (c == '\t')
      c = '\n';
    szLine[length++] = (char)c;
    if (c == '\n')
      break;
  }
  if (!length && EOF == c) {
    return NULL;
  }
  szLine[length] = '\0';
  return szLine;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<inchi_fgetsTab>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L35:
  cmp    %r12d,%ebx
  jge    L54
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    D10(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L48
  add    $0x1,%ebx
  cmp    $0x9,%eax
  je     L32
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    $0xa,%eax
  jne    L35
L4:
  movslq %ebx,%rbx
  add    %rbp,%rbx
  jmp    L20
  nopl   0x0(%rax)
L32:
  movb   $0xa,(%r14)
  movslq %ebx,%rbx
  add    %rbp,%rbx
L20:
  movb   $0x0,(%rbx)
  mov    %rbp,%rax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L48:
  test   %ebx,%ebx
  jne    L4
L79:
  xor    %eax,%eax
  jmp    L26
L54:
  test   %ebx,%ebx
  jne    L4
  mov    D10(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L79
  mov    %rbp,%rbx
  jmp    L20
```

assistant: ```c
char *inchi_fgetsTab(char *szLine, int len, FILE *f) {
  int length = 0, c = 0;
  len--;
  while (length < len && EOF != (c = fgetc(f))) {
    if (c == '\t')
      c = '\n';
    szLine[length++] = (char)c;
    if (c == '\n')
      break;
  }
  if (!length && EOF == c) {
    return NULL;
  }
  szLine[length] = '\0';
  return szLine;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L8
L26:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L47:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x0,-0xc(%rbp)
  jle    L45
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L47
L45:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_sort(int a[], int n) {
  int j, p, tmp;
  for (p = 1; p < n; p++) {
    tmp = a[p];
    for (j = p; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L52
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  jmp    L23
L32:
  movslq %edx,%rdx
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%esi
  je     L52
L23:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9d,%edx
  test   %r9d,%r9d
  jle    L32
L59:
  mov    -0x4(%rax),%ecx
  cmp    %r8d,%ecx
  jle    L32
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L59
  jmp    L32
L52:
  ret
```

assistant: ```c
void insert_sort(int a[], int n) {
  int j, p, tmp;
  for (p = 1; p < n; p++) {
    tmp = a[p];
    for (j = p; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<insert_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L36
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L14:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L38
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rax,%rdi
  jne    L14
  mov    %rdi,%rcx
L38:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L3
L36:
  ret
```

assistant: ```c
void insert_sort(int a[], int n) {
  int j, p, tmp;
  for (p = 1; p < n; p++) {
    tmp = a[p];
    for (j = p; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L19
  nopl   0x0(%rax,%rax,1)
L36:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L30:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L26
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rdi,%rax
  jne    L30
  mov    %rdi,%rcx
L26:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L36
L19:
  ret
```

assistant: ```c
void insert_sort(int a[], int n) {
  int j, p, tmp;
  for (p = 1; p < n; p++) {
    tmp = a[p];
    for (j = p; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D27: Valores de a y b: 

tool: D21: %d %d

tool: D5: La suma es %d


assistant: ```c
main() {
  int a = 0, b = 0, s = 0;
  printf("Valores de a y b: ");
  scanf("%d %d", &a, &b);
  s = a + b;
  printf("La suma es %d\n", s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D28: Valores de a y b: 

tool: D17: %d %d

tool: D8: La suma es %d


assistant: ```c
main() {
  int a = 0, b = 0, s = 0;
  printf("Valores de a y b: ");
  scanf("%d %d", &a, &b);
  s = a + b;
  printf("La suma es %d\n", s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D15
datatype: string

tool: D22: Valores de a y b: 

tool: D2: %d %d

tool: D15: La suma es %d


assistant: ```c
main() {
  int a = 0, b = 0, s = 0;
  printf("Valores de a y b: ");
  scanf("%d %d", &a, &b);
  s = a + b;
  printf("La suma es %d\n", s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string

tool: D2: Valores de a y b: 

tool: D16: %d %d

tool: D10: La suma es %d


assistant: ```c
main() {
  int a = 0, b = 0, s = 0;
  printf("Valores de a y b: ");
  scanf("%d %d", &a, &b);
  s = a + b;
  printf("La suma es %d\n", s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uuid_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L11
L19:
  mov    -0x38(%rbp),%rax
  add    $0x3c,%rax
  mov    (%rax),%ecx
  mov    -0x38(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%r15d
  mov    -0x38(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%r14d
  mov    -0x38(%rbp),%rax
  add    $0x2c,%rax
  mov    (%rax),%r13d
  mov    -0x38(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%r12d
  mov    -0x38(%rbp),%rax
  add    $0x24,%rax
  mov    (%rax),%ebx
  mov    -0x38(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%r11d
  mov    -0x38(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%r10d
  mov    -0x38(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%r9d
  mov    -0x38(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%r8d
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edi
  mov    -0x38(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%esi
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    %edx,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x8,%rsp
  push   %rcx
  mov    -0x3c(%rbp),%ecx
  push   %rcx
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  push   %r11
  push   %r10
  push   %r9
  push   %r8
  push   %rdi
  push   %rsi
  mov    -0x40(%rbp),%r9d
  mov    %edx,%r8d
  mov    %eax,%ecx
  lea    D20(%rip),%rax
  mov    %rax,%rdx
  mov    $0x28,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  add    $0x70,%rsp
  lea    D23(%rip),%rax
L11:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D20
type_infered: string

tool: D20: {%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}

assistant: ```c
char *uuid_to_string(const uint8_t *uuid) {
  static char uuid_string[40];
  if (uuid == NULL)
    return NULL;
  snprintf(uuid_string, sizeof(uuid_string), "{%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}", uuid[0], uuid[1], uuid[2], uuid[3], uuid[4], uuid[5], uuid[6], uuid[7], uuid[8], uuid[9], uuid[10], uuid[11], uuid[12], uuid[13], uuid[14], uuid[15]);
  return uuid_string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uuid_to_string>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L0
  push   %rbx
  sub    $0x8,%rsp
  mov    0x3c(%rdi),%edx
  push   %rdx
  mov    0x38(%rdi),%edx
  push   %rdx
  mov    0x34(%rdi),%edx
  push   %rdx
  mov    0x30(%rdi),%edx
  push   %rdx
  mov    0x2c(%rdi),%edx
  push   %rdx
  mov    0x28(%rdi),%edx
  push   %rdx
  mov    0x24(%rdi),%edx
  push   %rdx
  mov    0x20(%rdi),%edx
  push   %rdx
  mov    0x1c(%rdi),%edx
  push   %rdx
  mov    0x18(%rdi),%edx
  push   %rdx
  mov    0x14(%rdi),%edx
  push   %rdx
  mov    0x10(%rdi),%edx
  push   %rdx
  mov    0xc(%rdi),%edx
  push   %rdx
  mov    0x8(%rdi),%r9d
  mov    0x4(%rdi),%r8d
  mov    (%rdi),%ecx
  lea    D1(%rip),%rdx
  mov    $0x28,%esi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  add    $0x70,%rsp
  mov    %rbx,%rax
  pop    %rbx
  ret
L0:
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: {%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}

assistant: ```c
char *uuid_to_string(const uint8_t *uuid) {
  static char uuid_string[40];
  if (uuid == NULL)
    return NULL;
  snprintf(uuid_string, sizeof(uuid_string), "{%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}", uuid[0], uuid[1], uuid[2], uuid[3], uuid[4], uuid[5], uuid[6], uuid[7], uuid[8], uuid[9], uuid[10], uuid[11], uuid[12], uuid[13], uuid[14], uuid[15]);
  return uuid_string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uuid_to_string>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    0x3c(%rdi),%edx
  lea    D1(%rip),%rbx
  mov    $0x28,%esi
  sub    $0x8,%rsp
  push   %rdx
  mov    0x38(%rdi),%edx
  push   %rdx
  mov    0x34(%rdi),%edx
  push   %rdx
  mov    0x30(%rdi),%edx
  push   %rdx
  mov    0x2c(%rdi),%edx
  push   %rdx
  mov    0x28(%rdi),%edx
  push   %rdx
  mov    0x24(%rdi),%edx
  push   %rdx
  mov    0x20(%rdi),%edx
  push   %rdx
  mov    0x1c(%rdi),%edx
  push   %rdx
  mov    0x18(%rdi),%edx
  push   %rdx
  mov    0x14(%rdi),%edx
  push   %rdx
  mov    0x10(%rdi),%edx
  push   %rdx
  mov    0xc(%rdi),%edx
  push   %rdx
  mov    0x8(%rdi),%r9d
  lea    D14(%rip),%rdx
  mov    0x4(%rdi),%r8d
  mov    (%rdi),%ecx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  add    $0x70,%rsp
  mov    %rbx,%rax
  pop    %rbx
  ret
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D14: {%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}

assistant: ```c
char *uuid_to_string(const uint8_t *uuid) {
  static char uuid_string[40];
  if (uuid == NULL)
    return NULL;
  snprintf(uuid_string, sizeof(uuid_string), "{%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}", uuid[0], uuid[1], uuid[2], uuid[3], uuid[4], uuid[5], uuid[6], uuid[7], uuid[8], uuid[9], uuid[10], uuid[11], uuid[12], uuid[13], uuid[14], uuid[15]);
  return uuid_string;
}
```
user: What is the c source code of the assembly code below:

```asm
<uuid_to_string>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbx
  mov    0x3c(%rdi),%edx
  lea    D18(%rip),%rbx
  mov    $0x28,%esi
  sub    $0x8,%rsp
  push   %rdx
  mov    0x38(%rdi),%edx
  push   %rdx
  mov    0x34(%rdi),%edx
  push   %rdx
  mov    0x30(%rdi),%edx
  push   %rdx
  mov    0x2c(%rdi),%edx
  push   %rdx
  mov    0x28(%rdi),%edx
  push   %rdx
  mov    0x24(%rdi),%edx
  push   %rdx
  mov    0x20(%rdi),%edx
  push   %rdx
  mov    0x1c(%rdi),%edx
  push   %rdx
  mov    0x18(%rdi),%edx
  push   %rdx
  mov    0x14(%rdi),%edx
  push   %rdx
  mov    0x10(%rdi),%edx
  push   %rdx
  mov    0xc(%rdi),%edx
  push   %rdx
  mov    0x8(%rdi),%r9d
  lea    D17(%rip),%rdx
  mov    0x4(%rdi),%r8d
  mov    (%rdi),%ecx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  add    $0x70,%rsp
  mov    %rbx,%rax
  pop    %rbx
  ret
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_infered: string

tool: D17: {%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}

assistant: ```c
char *uuid_to_string(const uint8_t *uuid) {
  static char uuid_string[40];
  if (uuid == NULL)
    return NULL;
  snprintf(uuid_string, sizeof(uuid_string), "{%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x}", uuid[0], uuid[1], uuid[2], uuid[3], uuid[4], uuid[5], uuid[6], uuid[7], uuid[8], uuid[9], uuid[10], uuid[11], uuid[12], uuid[13], uuid[14], uuid[15]);
  return uuid_string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<resolv_hostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <inet_addr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  je     L38
  mov    -0x30(%rbp),%rax
  lea    -0x18(%rbp),%rcx
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L37
L38:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L35
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L48
L35:
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L37:
  mov    $0x0,%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: ERROR resolving hostname

assistant: ```c
int resolv_hostname(const char *hname, struct sockaddr_in *sin) {
  struct hostent *hostp;
  unsigned long addr;
  addr = inet_addr(hname);
  if (addr != (in_addr_t)-1)
    memcpy(&sin->sin_addr, &addr, sizeof(addr));
  else {
    hostp = gethostbyname(hname);
    if (hostp == NULL) {
      perror("ERROR resolving hostname");
      return -1;
    } else
      memcpy(&sin->sin_addr, hostp->h_addr, hostp->h_length);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<resolv_hostname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <inet_addr@plt>
  mov    %rax,(%rsp)
  cmp    $0xffffffffffffffff,%rax
  je     L18
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %rbx,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L6
  mov    0x8(%rax),%edx
  mov    (%rax),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  jmp    L5
L6:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L5
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: ERROR resolving hostname

assistant: ```c
int resolv_hostname(const char *hname, struct sockaddr_in *sin) {
  struct hostent *hostp;
  unsigned long addr;
  addr = inet_addr(hname);
  if (addr != (in_addr_t)-1)
    memcpy(&sin->sin_addr, &addr, sizeof(addr));
  else {
    hostp = gethostbyname(hname);
    if (hostp == NULL) {
      perror("ERROR resolving hostname");
      return -1;
    } else
      memcpy(&sin->sin_addr, hostp->h_addr, hostp->h_length);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<resolv_hostname>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <inet_addr@plt>
  mov    %rax,(%rsp)
  cmp    $0xffffffffffffffff,%rax
  je     L28
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  xor    %eax,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L3
  mov    0x8(%rax),%edx
  mov    (%rax),%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  xor    %eax,%eax
  jmp    L10
L3:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L10
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string

tool: D2: ERROR resolving hostname

assistant: ```c
int resolv_hostname(const char *hname, struct sockaddr_in *sin) {
  struct hostent *hostp;
  unsigned long addr;
  addr = inet_addr(hname);
  if (addr != (in_addr_t)-1)
    memcpy(&sin->sin_addr, &addr, sizeof(addr));
  else {
    hostp = gethostbyname(hname);
    if (hostp == NULL) {
      perror("ERROR resolving hostname");
      return -1;
    } else
      memcpy(&sin->sin_addr, hostp->h_addr, hostp->h_length);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<resolv_hostname>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <inet_addr@plt>
  mov    %rax,(%rsp)
  cmp    $0xffffffffffffffff,%rax
  je     L47
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  xor    %eax,%eax
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L6
  mov    0x8(%rax),%edx
  mov    (%rax),%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  xor    %eax,%eax
  jmp    L39
L6:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L39
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: ERROR resolving hostname

assistant: ```c
int resolv_hostname(const char *hname, struct sockaddr_in *sin) {
  struct hostent *hostp;
  unsigned long addr;
  addr = inet_addr(hname);
  if (addr != (in_addr_t)-1)
    memcpy(&sin->sin_addr, &addr, sizeof(addr));
  else {
    hostp = gethostbyname(hname);
    if (hostp == NULL) {
      perror("ERROR resolving hostname");
      return -1;
    } else
      memcpy(&sin->sin_addr, hostp->h_addr, hostp->h_length);
  }
  return 0;
}
```