ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<getflags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int getflags(int fd, unsigned long *flags) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getflags>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getflags(int fd, unsigned long *flags) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<getflags>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getflags(int fd, unsigned long *flags) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getflags>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getflags(int fd, unsigned long *flags) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<getShComm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L26
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L26
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  cmp    $0x1d,%eax
  jle    L31
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L26
L31:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x1d,%edx
  sub    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x20(%rbp),%rax
  add    $0x1d,%rax
  movb   $0x0,(%rax)
L26:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D6: HATSHCOMM_

tool: D11: SN too long

assistant: ```c
void getShComm(char *SerialNumber, char *semaphoreName) {
  strcpy(semaphoreName, "HATSHCOMM_");
  if (SerialNumber != NULL && strlen(SerialNumber) > 0) {
    if (strlen(semaphoreName) + strlen(SerialNumber) + 1 > 30) {
      printf("SN too long");
    } else {
      strncat(semaphoreName, SerialNumber, 30 - strlen(semaphoreName) - 1);
      semaphoreName[30 - 1] = '\0';
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getShComm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  test   %rbx,%rbx
  je     L14
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L43
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %eax,%r12d
  cmp    $0x1d,%r12d
  jle    L35
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L35:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x1d,%edx
  sub    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  movb   $0x0,0x1d(%rbp)
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D8: HATSHCOMM_

tool: D13: SN too long

assistant: ```c
void getShComm(char *SerialNumber, char *semaphoreName) {
  strcpy(semaphoreName, "HATSHCOMM_");
  if (SerialNumber != NULL && strlen(SerialNumber) > 0) {
    if (strlen(semaphoreName) + strlen(SerialNumber) + 1 > 30) {
      printf("SN too long");
    } else {
      strncat(semaphoreName, SerialNumber, 30 - strlen(semaphoreName) - 1);
      semaphoreName[30 - 1] = '\0';
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getShComm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L2
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L28
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  add    %eax,%r12d
  cmp    $0x1d,%r12d
  jle    L12
  pop    %rbx
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <printf@plt>
  nopl   0x0(%rax)
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x1d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  sub    %eax,%edx
  call   <strncat@plt>
  movb   $0x0,0x1d(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D0: HATSHCOMM_

tool: D14: SN too long

assistant: ```c
void getShComm(char *SerialNumber, char *semaphoreName) {
  strcpy(semaphoreName, "HATSHCOMM_");
  if (SerialNumber != NULL && strlen(SerialNumber) > 0) {
    if (strlen(semaphoreName) + strlen(SerialNumber) + 1 > 30) {
      printf("SN too long");
    } else {
      strncat(semaphoreName, SerialNumber, 30 - strlen(semaphoreName) - 1);
      semaphoreName[30 - 1] = '\0';
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getShComm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L28
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L11
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  add    %eax,%r12d
  cmp    $0x1d,%r12d
  jle    L4
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <printf@plt>
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x1d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  sub    %eax,%edx
  call   <strncat@plt>
  movb   $0x0,0x1d(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D7: HATSHCOMM_

tool: D0: SN too long

assistant: ```c
void getShComm(char *SerialNumber, char *semaphoreName) {
  strcpy(semaphoreName, "HATSHCOMM_");
  if (SerialNumber != NULL && strlen(SerialNumber) > 0) {
    if (strlen(semaphoreName) + strlen(SerialNumber) + 1 > 30) {
      printf("SN too long");
    } else {
      strncat(semaphoreName, SerialNumber, 30 - strlen(semaphoreName) - 1);
      semaphoreName[30 - 1] = '\0';
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copyUpToNextSwitch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L12:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copyUpToNextSwitch(char *dest[], char *src[], int start, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    dest[i] = src[start + i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copyUpToNextSwitch>:
  endbr64
  test   %ecx,%ecx
  jle    L8
  mov    %ecx,%ecx
  movslq %edx,%rdx
  lea    (%rsi,%rdx,8),%rsi
  mov    $0x0,%eax
L18:
  mov    (%rsi,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L18
L8:
  ret
```

assistant: ```c
void copyUpToNextSwitch(char *dest[], char *src[], int start, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    dest[i] = src[start + i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<copyUpToNextSwitch>:
  endbr64
  test   %ecx,%ecx
  jle    L11
  movslq %edx,%rdx
  movslq %ecx,%rcx
  xor    %eax,%eax
  lea    (%rsi,%rdx,8),%rsi
  nopl   0x0(%rax)
L5:
  mov    (%rsi,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L5
L11:
  ret
```

assistant: ```c
void copyUpToNextSwitch(char *dest[], char *src[], int start, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    dest[i] = src[start + i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copyUpToNextSwitch>:
  endbr64
  mov    %edx,%eax
  test   %ecx,%ecx
  jle    L0
  movslq %edx,%rdx
  lea    0x8(,%rdx,8),%rdx
  lea    (%rsi,%rdx,1),%r8
  cmp    %r8,%rdi
  je     L25
  lea    -0x1(%rcx),%r8d
  cmp    $0x2,%r8d
  jbe    L25
  mov    %ecx,%r8d
  lea    -0x8(%rsi,%rdx,1),%r9
  xor    %edx,%edx
  shr    %r8d
  shl    $0x4,%r8
  nopl   (%rax)
L10:
  movdqu (%r9,%rdx,1),%xmm0
  movups %xmm0,(%rdi,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L10
  mov    %ecx,%edx
  and    $0xfffffffe,%edx
  and    $0x1,%ecx
  je     L0
  add    %edx,%eax
  cltq
  mov    (%rsi,%rax,8),%rax
  mov    %rax,(%rdi,%rdx,8)
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %ecx,%ecx
  lea    -0x8(%rsi,%rdx,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  mov    (%rsi,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L16
L0:
  ret
```

assistant: ```c
void copyUpToNextSwitch(char *dest[], char *src[], int start, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    dest[i] = src[start + i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<argNextFilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L12
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L57
L44:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L60
  mov    -0xc(%rbp),%eax
  jmp    L2
L60:
  addl   $0x1,-0xc(%rbp)
L57:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L44
L12:
  mov    $0xffffffff,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int argNextFilename(int argc, char **argv, int last) {
  int i;
  if (argv)
    for (i = last + 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && strlen(arg) && (arg[0] != '-')) {
        return i;
      }
    }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<argNextFilename>:
  endbr64
  mov    %edx,%eax
  test   %rsi,%rsi
  je     L24
  add    $0x1,%eax
  cmp    %edi,%eax
  jge    L46
  cltq
  jmp    L64
L52:
  add    $0x1,%rax
  cmp    %eax,%edi
  jle    L76
L64:
  mov    %eax,%ecx
  mov    (%rsi,%rax,8),%rdx
  test   %rdx,%rdx
  je     L52
  movzbl (%rdx),%edx
  cmp    $0x2d,%dl
  je     L52
  test   %dl,%dl
  je     L52
  jmp    L4
L76:
  mov    $0xffffffff,%ecx
L4:
  mov    %ecx,%eax
  ret
L24:
  mov    $0xffffffff,%ecx
  jmp    L4
L46:
  mov    $0xffffffff,%ecx
  jmp    L4
```

assistant: ```c
int argNextFilename(int argc, char **argv, int last) {
  int i;
  if (argv)
    for (i = last + 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && strlen(arg) && (arg[0] != '-')) {
        return i;
      }
    }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<argNextFilename>:
  endbr64
  mov    %edx,%eax
  test   %rsi,%rsi
  je     L36
  add    $0x1,%eax
  cmp    %edi,%eax
  jge    L36
  cltq
  nopl   0x0(%rax)
L58:
  mov    (%rsi,%rax,8),%rdx
  mov    %eax,%r8d
  test   %rdx,%rdx
  je     L11
  movzbl (%rdx),%edx
  cmp    $0x2d,%dl
  je     L11
  test   %dl,%dl
  jne    L17
L11:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L58
L36:
  mov    $0xffffffff,%r8d
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int argNextFilename(int argc, char **argv, int last) {
  int i;
  if (argv)
    for (i = last + 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && strlen(arg) && (arg[0] != '-')) {
        return i;
      }
    }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argNextFilename>:
  endbr64
  mov    %edx,%eax
  test   %rsi,%rsi
  je     L37
  add    $0x1,%eax
  cmp    %edi,%eax
  jge    L37
  cltq
  nopl   0x0(%rax)
L12:
  mov    (%rsi,%rax,8),%rdx
  mov    %eax,%r8d
  test   %rdx,%rdx
  je     L0
  movzbl (%rdx),%edx
  cmp    $0x2d,%dl
  je     L0
  test   %dl,%dl
  jne    L21
L0:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L12
L37:
  mov    $0xffffffff,%r8d
L21:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int argNextFilename(int argc, char **argv, int last) {
  int i;
  if (argv)
    for (i = last + 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && strlen(arg) && (arg[0] != '-')) {
        return i;
      }
    }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<setValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void setValue(char *pSource, char dest[]) {
  memset(dest, 0, 256);
  memcpy(dest, pSource, strlen(pSource));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setValue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void setValue(char *pSource, char dest[]) {
  memset(dest, 0, 256);
  memcpy(dest, pSource, strlen(pSource));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setValue>:
  endbr64
  push   %r12
  mov    $0x100,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1090 <memcpy@plt>
```

assistant: ```c
void setValue(char *pSource, char dest[]) {
  memset(dest, 0, 256);
  memcpy(dest, pSource, strlen(pSource));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setValue>:
  endbr64
  push   %r12
  mov    $0x100,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1090 <memcpy@plt>
```

assistant: ```c
void setValue(char *pSource, char dest[]) {
  memset(dest, 0, 256);
  memcpy(dest, pSource, strlen(pSource));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ADC_absx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x1,%edi
  call   <ADC_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ADC_absx(void) {
  c64_memAbsoluteAddrX();
  ADC_(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ADC_absx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x1,%edi
  call   <ADC_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ADC_absx(void) {
  c64_memAbsoluteAddrX();
  ADC_(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ADC_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <ADC_@plt>
```

assistant: ```c
void ADC_absx(void) {
  c64_memAbsoluteAddrX();
  ADC_(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ADC_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <ADC_@plt>
```

assistant: ```c
void ADC_absx(void) {
  c64_memAbsoluteAddrX();
  ADC_(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<raw_scan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  mov    -0x30(%rbp),%r8
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <raw_scan_nonroot@plt>
  add    $0x10,%rsp
  jmp    L1
L18:
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    0x10(%rbp),%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <raw_scan_root@plt>
L1:
  leave
  ret
```

assistant: ```c
int raw_scan(struct super_block *sb, int start, const char *name, int *number, int *ino, struct buffer_head **res_bh, struct msdos_dir_entry **res_de) {
  if (start)
    return raw_scan_nonroot(sb, start, name, number, ino, res_bh, res_de);
  else
    return raw_scan_root(sb, name, number, ino, res_bh, res_de);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<raw_scan>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rax
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%r8
  test   %esi,%esi
  je     L18
  sub    $0x8,%rsp
  push   0x18(%rsp)
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <raw_scan_nonroot@plt>
  add    $0x10,%rsp
L13:
  add    $0x8,%rsp
  ret
L18:
  mov    0x10(%rsp),%r9
  mov    %rax,%rsi
  call   <raw_scan_root@plt>
  jmp    L13
```

assistant: ```c
int raw_scan(struct super_block *sb, int start, const char *name, int *number, int *ino, struct buffer_head **res_bh, struct msdos_dir_entry **res_de) {
  if (start)
    return raw_scan_nonroot(sb, start, name, number, ino, res_bh, res_de);
  else
    return raw_scan_root(sb, name, number, ino, res_bh, res_de);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<raw_scan>:
  endbr64
  mov    %rdx,%r10
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%r8
  mov    0x8(%rsp),%r9
  test   %esi,%esi
  je     L9
  mov    %r9,0x8(%rsp)
  mov    %r8,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %r10,%rdx
  jmp    1070 <raw_scan_nonroot@plt>
  nop
L9:
  mov    %r10,%rsi
  jmp    1060 <raw_scan_root@plt>
```

assistant: ```c
int raw_scan(struct super_block *sb, int start, const char *name, int *number, int *ino, struct buffer_head **res_bh, struct msdos_dir_entry **res_de) {
  if (start)
    return raw_scan_nonroot(sb, start, name, number, ino, res_bh, res_de);
  else
    return raw_scan_root(sb, name, number, ino, res_bh, res_de);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<raw_scan>:
  endbr64
  mov    %rdx,%r10
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%r8
  mov    0x8(%rsp),%r9
  test   %esi,%esi
  je     L9
  mov    %r9,0x8(%rsp)
  mov    %r8,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %r10,%rdx
  jmp    1070 <raw_scan_nonroot@plt>
  nop
L9:
  mov    %r10,%rsi
  jmp    1060 <raw_scan_root@plt>
```

assistant: ```c
int raw_scan(struct super_block *sb, int start, const char *name, int *number, int *ino, struct buffer_head **res_bh, struct msdos_dir_entry **res_de) {
  if (start)
    return raw_scan_nonroot(sb, start, name, number, ino, res_bh, res_de);
  else
    return raw_scan_root(sb, name, number, ino, res_bh, res_de);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <simplesample_amqp_run@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  simplesample_amqp_run();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <simplesample_amqp_run@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  simplesample_amqp_run();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <simplesample_amqp_run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  simplesample_amqp_run();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <simplesample_amqp_run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  simplesample_amqp_run();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<basLeft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <popString@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <left@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <eFree@plt>
  nop
  leave
  ret
```

assistant: ```c
void basLeft() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = left(string, pos);
  pushStringCopy(dest);
  eFree(string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<basLeft>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <popString@plt>
  mov    %rax,%rbp
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <left@plt>
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    %rbp,%rdi
  call   <eFree@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void basLeft() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = left(string, pos);
  pushStringCopy(dest);
  eFree(string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<basLeft>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <popNumber@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <popString@plt>
  mov    %ebx,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <left@plt>
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10c0 <eFree@plt>
```

assistant: ```c
void basLeft() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = left(string, pos);
  pushStringCopy(dest);
  eFree(string);
}
```