ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<scale_up_coeffs>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    -0x1(%rdi),%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %edi,0x4(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  test   %esi,%esi
  jg     L52
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L23:
  cltq
  sub    %ebp,%ecx
  movss  0x14(%rsp),%xmm0
  mov    $0x4,%esi
  addl   $0x1,0x0(%r13,%rax,4)
  movslq %ecx,%rax
  lea    (%rbx,%rax,4),%rdi
L16:
  call   <calc_coeffs@plt>
  add    $0x1,%r15d
  add    $0x10,%rbx
  cmp    %r15d,%r12d
  je     L48
L52:
  mov    0x8(%rsp),%rcx
  mov    0x4(%rsp),%edi
  mov    %r15d,%edx
  mov    %r12d,%esi
  call   <split_map@plt>
  mov    %ebp,%esi
  lea    0x2(%rax),%ecx
  mov    %eax,%r14d
  mov    %ecx,%edi
  mov    %ecx,(%rsp)
  call   <min@plt>
  mov    $0x1,%edx
  mov    (%rsp),%ecx
  xor    %esi,%esi
  sub    %r14d,%edx
  test   %r14d,%r14d
  cmovg  %esi,%edx
  cmp    %ecx,%ebp
  jl     L23
  cltq
  movss  0x14(%rsp),%xmm0
  xor    %ecx,%ecx
  mov    $0x4,%esi
  addl   $0x1,0x0(%r13,%rax,4)
  mov    %rbx,%rdi
  jmp    L16
  nopl   (%rax)
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void scale_up_coeffs(int in_width, int out_width, float *coeff_buf, int *border_buf) {
  int i, smp_i, start, end, ltrim, rtrim, safe_end, max_pos;
  float tx;
  max_pos = in_width - 1;
  for (i = 0; i < out_width; i++) {
    smp_i = split_map(in_width, out_width, i, &tx);
    start = smp_i - 1;
    end = smp_i + 2;
    safe_end = min(end, max_pos);
    ltrim = 0;
    rtrim = 0;
    if (start < 0) {
      ltrim = -1 * start;
    }
    if (end > max_pos) {
      rtrim = end - max_pos;
    }
    border_buf[safe_end] += 1;
    calc_coeffs(coeff_buf + rtrim, tx, 4, ltrim, rtrim);
    coeff_buf += 4;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L93
  mov    $0x0,%eax
  jmp    L70
L93:
  mov    -0x38(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L0
  mov    $0xffffffff,%eax
  jmp    L70
L0:
  mov    -0x38(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L43
L114:
  movq   $0x0,-0x18(%rbp)
  jmp    L111
L122:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L6
  addq   $0x1,-0x18(%rbp)
L111:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L122
  jmp    L28
L6:
  nop
L28:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L121
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  jmp    L70
L121:
  addq   $0x1,-0x20(%rbp)
L43:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L126
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L114
L126:
  mov    $0xffffffff,%eax
L70:
  leave
  ret
```

assistant: ```c
int strnstr(const char *haystack, const char *needle, size_t haystack_len) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_len = strlen(needle);
  if (needle_len == 0)
    return 0;
  if (haystack_len < needle_len)
    return -1;
  const char *end = haystack + haystack_len - needle_len;
  for (const char *p = haystack; *p != '\0' && p <= end; p++) {
    size_t i;
    for (i = 0; i < needle_len; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_len)
      return p - haystack;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strnstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L116
  cmp    %r12,%rsi
  ja     L30
  sub    %rsi,%r12
  lea    0x0(%rbp,%r12,1),%rax
  cmpb   $0x0,0x0(%rbp)
  je     L74
  mov    %rbp,%rcx
  cmp    %rax,%rbp
  jbe    L118
L74:
  mov    $0xffffffff,%eax
  jmp    L116
L16:
  cmp    %rdx,%rsi
  je     L112
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L79
  cmp    %rcx,%rax
  jb     L79
L118:
  mov    $0x0,%edx
L103:
  movzbl (%rbx,%rdx,1),%edi
  cmp    %dil,(%rcx,%rdx,1)
  jne    L16
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L103
L112:
  mov    %ecx,%eax
  sub    %ebp,%eax
  jmp    L116
L30:
  mov    $0xffffffff,%eax
  jmp    L116
L79:
  mov    $0xffffffff,%eax
L116:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strnstr(const char *haystack, const char *needle, size_t haystack_len) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_len = strlen(needle);
  if (needle_len == 0)
    return 0;
  if (haystack_len < needle_len)
    return -1;
  const char *end = haystack + haystack_len - needle_len;
  for (const char *p = haystack; *p != '\0' && p <= end; p++) {
    size_t i;
    for (i = 0; i < needle_len; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_len)
      return p - haystack;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strnstr>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rdx,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L25
  cmp    %rbp,%rdi
  ja     L62
  movzbl (%r12),%ecx
  sub    %rdi,%rbp
  lea    (%r12,%rbp,1),%rax
  test   %cl,%cl
  je     L62
  cmp    %rax,%r12
  ja     L62
  mov    %r12,%rsi
  xchg   %ax,%ax
L14:
  xor    %edx,%edx
  jmp    L15
  nopl   0x0(%rax)
L16:
  movzbl (%rsi,%rdx,1),%ecx
L15:
  cmp    %cl,(%rbx,%rdx,1)
  jne    L99
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L16
L79:
  mov    %esi,%eax
  sub    %r12d,%eax
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L99:
  cmp    %rdx,%rdi
  je     L79
  movzbl 0x1(%rsi),%ecx
  add    $0x1,%rsi
  test   %cl,%cl
  je     L62
  cmp    %rsi,%rax
  jae    L14
L62:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strnstr(const char *haystack, const char *needle, size_t haystack_len) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_len = strlen(needle);
  if (needle_len == 0)
    return 0;
  if (haystack_len < needle_len)
    return -1;
  const char *end = haystack + haystack_len - needle_len;
  for (const char *p = haystack; *p != '\0' && p <= end; p++) {
    size_t i;
    for (i = 0; i < needle_len; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_len)
      return p - haystack;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strnstr>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rdx,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L58
  cmp    %rbp,%rsi
  ja     L20
  sub    %rsi,%rbp
  cmpb   $0x0,(%r12)
  lea    (%r12,%rbp,1),%rax
  je     L20
  cmp    %rax,%r12
  ja     L20
  mov    %r12,%rcx
  nopl   0x0(%rax)
L26:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L82:
  movzbl (%rbx,%rdx,1),%edi
  cmp    %dil,(%rcx,%rdx,1)
  jne    L75
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L82
L12:
  mov    %ecx,%eax
  sub    %r12d,%eax
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L75:
  cmp    %rdx,%rsi
  je     L12
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L20
  cmp    %rcx,%rax
  jae    L26
L20:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strnstr(const char *haystack, const char *needle, size_t haystack_len) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_len = strlen(needle);
  if (needle_len == 0)
    return 0;
  if (haystack_len < needle_len)
    return -1;
  const char *end = haystack + haystack_len - needle_len;
  for (const char *p = haystack; *p != '\0' && p <= end; p++) {
    size_t i;
    for (i = 0; i < needle_len; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_len)
      return p - haystack;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<distanceUB_l2_m128_mine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %edx,-0x64(%rbp)
  movss  %xmm0,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x48(%rbp)
  movss  -0x68(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L27
L46:
  mov    -0x4c(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    %rdx,%rcx
  shl    $0x4,%rcx
  mov    -0x58(%rbp),%rdx
  add    %rdx,%rcx
  mov    0x8(%rax),%rdx
  mov    (%rax),%rax
  mov    (%rcx),%rdi
  mov    0x8(%rcx),%rsi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <_mm_sub_ps@plt>
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rsi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  mov    %eax,%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rdi
  mov    %rax,%rsi
  call   <_mm_add_ps@plt>
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x4c(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L44
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_mm_store_ss@plt>
  movss  -0x20(%rbp),%xmm0
  comiss -0x44(%rbp),%xmm0
  jbe    L44
  mov    -0x20(%rbp),%eax
  jmp    L24
L44:
  addl   $0x1,-0x4c(%rbp)
L27:
  mov    -0x64(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L46
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_mm_store_ps@plt>
  movss  -0x20(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
L24:
  movd   %eax,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
float distanceUB_l2_m128_mine(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 4 == 1) {
      _mm_store_ss(fsum, sum);
      if (fsum[0] > dist2) {
        return fsum[0];
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<distanceUB_l2_m128_mine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mulss  %xmm0,%xmm0
  movss  %xmm0,0x4(%rsp)
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    0x3(%rdx),%r15d
  test   %edx,%edx
  cmovns %edx,%r15d
  sar    $0x2,%r15d
  cmp    $0x3,%edx
  jle    L17
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    (%rdi),%rdi
  mov    0x8(%r13),%rsi
  mov    (%r14),%rdx
  mov    0x8(%r14),%rcx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rax,%rdi
  mov    %rcx,%rsi
  call   <_mm_mul_ps@plt>
  mov    %eax,%edx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  mov    %rdx,%rbp
  add    $0x10,%r13
  add    $0x10,%r14
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L0
L28:
  add    $0x10,%r13
  add    $0x10,%r14
L0:
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  jge    L17
  mov    0x0(%r13),%rdi
  mov    0x8(%r13),%rsi
  mov    (%r14),%rdx
  mov    0x8(%r14),%rcx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rax,%rdi
  mov    %rcx,%rsi
  call   <_mm_mul_ps@plt>
  mov    %eax,%edx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  mov    %rdx,%rbp
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L28
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    0x8(%rsp),%rdi
  call   <_mm_store_ss@plt>
  movss  0x10(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jbe    L28
  jmp    L30
L17:
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  mov    %rbp,%rdx
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  call   <sqrt@plt>
L30:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float distanceUB_l2_m128_mine(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 4 == 1) {
      _mm_store_ss(fsum, sum);
      if (fsum[0] > dist2) {
        return fsum[0];
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<distanceUB_l2_m128_mine>:
  endbr64
  push   %r15
  mulss  %xmm0,%xmm0
  push   %r14
  lea    0x3(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  movss  %xmm0,0xc(%rsp)
  cmovns %edx,%r14d
  sar    $0x2,%r14d
  cmp    $0x3,%edx
  jle    L20
  mov    %rsi,%r15
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  xor    %r13d,%r13d
  mov    0x8(%rbx),%rsi
  mov    0x8(%r15),%rcx
  add    $0x10,%rbx
  add    $0x10,%r15
  mov    -0x10(%r15),%rdx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  xor    %edi,%edi
  xor    %esi,%esi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  lea    0x10(%rsp),%rax
  mov    %rdx,%rbp
  mov    %rax,(%rsp)
  jmp    L45
  nopl   (%rax)
L35:
  add    $0x10,%rbx
  add    $0x10,%r15
L45:
  add    $0x1,%r13d
  cmp    %r14d,%r13d
  jge    L52
  mov    (%rbx),%rdi
  mov    0x8(%rbx),%rsi
  mov    0x8(%r15),%rcx
  mov    (%r15),%rdx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  mov    %r13d,%eax
  mov    %rdx,%rbp
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L35
  mov    (%rsp),%rdi
  mov    %r12,%rsi
  call   <_mm_store_ss@plt>
  movss  0x10(%rsp),%xmm0
  comiss 0xc(%rsp),%xmm0
  jbe    L35
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  lea    0x10(%rsp),%rax
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  mov    %rax,(%rsp)
  nopl   (%rax)
L52:
  mov    (%rsp),%rdi
  mov    %r12,%rsi
  mov    %rbp,%rdx
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L2
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float distanceUB_l2_m128_mine(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 4 == 1) {
      _mm_store_ss(fsum, sum);
      if (fsum[0] > dist2) {
        return fsum[0];
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<distanceUB_l2_m128_mine>:
  endbr64
  push   %r15
  mulss  %xmm0,%xmm0
  push   %r14
  lea    0x3(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  movss  %xmm0,0xc(%rsp)
  cmovns %edx,%r14d
  sar    $0x2,%r14d
  cmp    $0x3,%edx
  jle    L64
  mov    %rsi,%r15
  mov    %rdi,%r12
  mov    (%rdi),%rdi
  xor    %r13d,%r13d
  mov    0x8(%r12),%rsi
  mov    (%r15),%rdx
  add    $0x10,%r12
  add    $0x10,%r15
  mov    -0x8(%r15),%rcx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  xor    %edi,%edi
  xor    %esi,%esi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%rbp
  lea    0x10(%rsp),%rax
  mov    %rdx,%rbx
  mov    %rax,(%rsp)
  jmp    L34
  nopl   (%rax)
L47:
  add    $0x10,%r12
  add    $0x10,%r15
L34:
  add    $0x1,%r13d
  cmp    %r14d,%r13d
  jge    L23
  mov    (%r12),%rdi
  mov    0x8(%r12),%rsi
  mov    0x8(%r15),%rcx
  mov    (%r15),%rdx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%rbp
  mov    %r13d,%eax
  mov    %rdx,%rbx
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L47
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  call   <_mm_store_ss@plt>
  movss  0x10(%rsp),%xmm0
  comiss 0xc(%rsp),%xmm0
  jbe    L47
  nopw   0x0(%rax,%rax,1)
L22:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  lea    0x10(%rsp),%rax
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L23:
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  mov    %rbx,%rdx
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L22
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float distanceUB_l2_m128_mine(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 4 == 1) {
      _mm_store_ss(fsum, sum);
      if (fsum[0] > dist2) {
        return fsum[0];
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<schar_put>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0x9,-0x4(%rbp)
  jle    L3
  movzbl -0x4(%rbp),%edx
  mov    $0x67,%ecx
  mov    %ecx,%eax
  imul   %dl
  shr    $0x8,%ax
  sar    $0x2,%al
  sar    $0x7,%dl
  sub    %edx,%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <schar_put>
L3:
  movzbl -0x4(%rbp),%edx
  mov    $0x67,%ecx
  mov    %ecx,%eax
  imul   %dl
  shr    $0x8,%ax
  sar    $0x2,%al
  mov    %edx,%esi
  sar    $0x7,%sil
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void schar_put(signed char number, FILE *stream) {
  if (number > (signed char)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    schar_put(number / (signed char)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed char)10), stream);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<schar_put>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  cmp    $0x9,%dil
  jg     L4
L5:
  mov    $0x67,%edx
  mov    %edx,%eax
  imul   %bl
  sar    $0xa,%ax
  mov    %ebx,%edx
  sar    $0x7,%dl
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  movsbl %dil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0x67,%edi
  mov    %edi,%eax
  imul   %bl
  mov    %eax,%edi
  sar    $0xa,%di
  mov    %ebx,%eax
  sar    $0x7,%al
  sub    %eax,%edi
  movsbl %dil,%edi
  call   <schar_put>
  jmp    L5
```

assistant: ```c
void schar_put(signed char number, FILE *stream) {
  if (number > (signed char)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    schar_put(number / (signed char)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed char)10), stream);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<schar_put>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x9,%dil
  jg     L25
L11:
  mov    $0x67,%eax
  mov    %ebx,%edx
  mov    %r12,%rsi
  imul   %bl
  sar    $0x7,%dl
  sar    $0xa,%ax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  movzbl %dil,%edi
  pop    %r12
  jmp    1050 <fputc@plt>
  nop
L25:
  mov    $0x67,%eax
  imul   %dil
  mov    %eax,%ebp
  mov    %edi,%eax
  sar    $0xa,%bp
  sar    $0x7,%al
  sub    %eax,%ebp
  cmp    $0x63,%dil
  jg     L4
L35:
  mov    $0xffffffcd,%eax
  mov    %r12,%rsi
  mul    %bpl
  shr    $0xb,%ax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  jmp    L11
  nop
L4:
  mov    $0x31,%edi
  call   <fputc@plt>
  jmp    L35
```

assistant: ```c
void schar_put(signed char number, FILE *stream) {
  if (number > (signed char)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    schar_put(number / (signed char)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed char)10), stream);
}
```