ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calc_energy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %edi,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm6
  movapd %xmm3,%xmm7
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L33
L16:
  mov    $0x0,%r13d
  jmp    L35
L27:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm4
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm4,%xmm0
  movapd %xmm7,%xmm5
  addsd  %xmm5,%xmm0
  movapd %xmm0,%xmm7
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  movapd %xmm0,%xmm6
  add    $0x1,%r13d
  add    $0x1,%ebx
L35:
  cmp    %r12d,%r13d
  jl     L27
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm7,%xmm0
  movapd %xmm0,%xmm7
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm6,%xmm5
  addsd  %xmm5,%xmm0
  movapd %xmm0,%xmm6
  add    $0x1,%ebx
  add    $0x1,%r12d
L33:
  cmp    -0x1c(%rbp),%r12d
  jl     L16
  movapd %xmm7,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm6,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: f64

tool: D15: 0.5

assistant: ```c
double calc_energy(int no, const double *pm, const double *hm, const double *gm) {
  register int i, j, ij;
  register double sum1, sum2, pij;
  sum1 = sum2 = 0.0;
  ij = 0;
  for (i = 0; i < no; ++i) {
    for (j = 0; j < i; ++j, ++ij) {
      pij = pm[ij];
      sum1 += hm[ij] * pij;
      sum2 += gm[ij] * pij;
    }
    pij = pm[ij];
    sum1 += pij * hm[ij] * 0.5;
    sum2 += pij * gm[ij] * 0.5;
    ++ij;
  }
  return (sum1 + sum1 + sum2);
}
```
user: What is the c source code of the assembly code below?

```asm
<calc_energy>:
  endbr64
  test   %edi,%edi
  jle    L56
  push   %rbp
  push   %rbx
  mov    %rdx,%r8
  lea    -0x1(%rdi),%ebx
  mov    $0x0,%edi
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  mov    $0x0,%r9d
  movsd  D4(%rip),%xmm4
  jmp    L19
L20:
  add    $0x8,%rax
  lea    0x2(%rdx,%rdi,1),%rdx
  shl    $0x3,%rdx
L6:
  movsd  (%rsi,%rax,1),%xmm1
  movapd %xmm1,%xmm3
  mulsd  (%r8,%rax,1),%xmm3
  addsd  %xmm3,%xmm0
  mulsd  (%rcx,%rax,1),%xmm1
  addsd  %xmm1,%xmm2
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
  lea    0x2(%r9,%r10,1),%r9d
L1:
  add    $0x1,%rdi
L19:
  mov    %edi,%r10d
  movslq %r9d,%rdx
  lea    0x0(,%rdx,8),%rax
  movsd  (%rsi,%rdx,8),%xmm1
  movapd %xmm1,%xmm3
  mulsd  (%r8,%rdx,8),%xmm3
  mulsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  (%rcx,%rdx,8),%xmm1
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm2
  lea    0x1(%r9),%ebp
  cmp    %rbx,%rdi
  je     L16
  lea    0x1(%rdi),%r11d
  test   %r11d,%r11d
  jg     L20
  mov    %ebp,%r9d
  jmp    L1
L56:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm0
  ret
L16:
  addsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: f64

tool: D4: 0.5

assistant: ```c
double calc_energy(int no, const double *pm, const double *hm, const double *gm) {
  register int i, j, ij;
  register double sum1, sum2, pij;
  sum1 = sum2 = 0.0;
  ij = 0;
  for (i = 0; i < no; ++i) {
    for (j = 0; j < i; ++j, ++ij) {
      pij = pm[ij];
      sum1 += hm[ij] * pij;
      sum2 += gm[ij] * pij;
    }
    pij = pm[ij];
    sum1 += pij * hm[ij] * 0.5;
    sum2 += pij * gm[ij] * 0.5;
    ++ij;
  }
  return (sum1 + sum1 + sum2);
}
```
user: What is the c source code of the assembly code below?

```asm
<calc_energy>:
  endbr64
  mov    %rdx,%r8
  test   %edi,%edi
  jle    L29
  pxor   %xmm2,%xmm2
  movsd  D7(%rip),%xmm4
  lea    -0x1(%rdi),%r11d
  xor    %r9d,%r9d
  xor    %edi,%edi
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L23:
  movslq %r9d,%rdx
  mov    %edi,%r10d
  movsd  (%rsi,%rdx,8),%xmm1
  movsd  (%r8,%rdx,8),%xmm3
  lea    0x0(,%rdx,8),%rax
  mulsd  %xmm1,%xmm3
  mulsd  (%rcx,%rdx,8),%xmm1
  mulsd  %xmm4,%xmm3
  mulsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm2
  cmp    %rdi,%r11
  je     L2
  lea    0x2(%rdx,%rdi,1),%rdx
  add    $0x8,%rax
  shl    $0x3,%rdx
  nopl   0x0(%rax)
L34:
  movsd  (%rsi,%rax,1),%xmm1
  movsd  (%r8,%rax,1),%xmm3
  mulsd  %xmm1,%xmm3
  mulsd  (%rcx,%rax,1),%xmm1
  add    $0x8,%rax
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm2
  cmp    %rax,%rdx
  jne    L34
  lea    0x2(%r10,%r9,1),%r9d
  add    $0x1,%rdi
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L2:
  addsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  ret
L29:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: f64

tool: D7: 0.5

assistant: ```c
double calc_energy(int no, const double *pm, const double *hm, const double *gm) {
  register int i, j, ij;
  register double sum1, sum2, pij;
  sum1 = sum2 = 0.0;
  ij = 0;
  for (i = 0; i < no; ++i) {
    for (j = 0; j < i; ++j, ++ij) {
      pij = pm[ij];
      sum1 += hm[ij] * pij;
      sum2 += gm[ij] * pij;
    }
    pij = pm[ij];
    sum1 += pij * hm[ij] * 0.5;
    sum2 += pij * gm[ij] * 0.5;
    ++ij;
  }
  return (sum1 + sum1 + sum2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_energy>:
  endbr64
  mov    %edi,%r9d
  test   %edi,%edi
  jle    L18
  mov    %rsi,%r8
  push   %r12
  movsd  D1(%rip),%xmm4
  mov    %rdx,%rdi
  push   %rbp
  pxor   %xmm1,%xmm1
  mov    %rcx,%rsi
  mov    $0x1,%r11d
  push   %rbx
  movsd  (%r8),%xmm2
  xor    %ebx,%ebx
  mov    $0x1,%r10d
  movsd  (%rdx),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  (%rcx),%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm4,%xmm2
  addsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm2
  cmp    $0x1,%r9d
  je     L62
  nopl   0x0(%rax)
L44:
  test   %ebx,%ebx
  je     L39
  movslq %r10d,%rdx
  mov    %r11d,%ecx
  xor    %eax,%eax
  shl    $0x3,%rdx
  shr    %ecx
  lea    (%r8,%rdx,1),%r12
  lea    (%rdi,%rdx,1),%rbp
  shl    $0x4,%rcx
  add    %rsi,%rdx
  nopl   (%rax)
L20:
  movupd (%r12,%rax,1),%xmm5
  movupd 0x0(%rbp,%rax,1),%xmm1
  mulpd  %xmm5,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movupd (%rdx,%rax,1),%xmm1
  add    $0x10,%rax
  mulpd  %xmm5,%xmm1
  addsd  %xmm1,%xmm2
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  cmp    %rcx,%rax
  jne    L20
  mov    %r11d,%edx
  and    $0xfffffffe,%edx
  lea    (%rdx,%r10,1),%eax
  cmp    %edx,%r11d
  je     L35
L46:
  cltq
  movsd  (%r8,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm3
  mulsd  %xmm1,%xmm3
  mulsd  (%rsi,%rax,8),%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm2
L35:
  lea    0x1(%r10,%rbx,1),%r10d
  add    $0x1,%r11d
  add    $0x1,%ebx
  movslq %r10d,%rax
  add    $0x1,%r10d
  movsd  (%r8,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm3
  mulsd  %xmm1,%xmm3
  mulsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm4,%xmm3
  mulsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm2
  cmp    %r11d,%r9d
  jne    L44
L62:
  addsd  %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  addsd  %xmm2,%xmm0
  ret
L39:
  mov    %r10d,%eax
  jmp    L46
L18:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: f64

tool: D1: 0.5

assistant: ```c
double calc_energy(int no, const double *pm, const double *hm, const double *gm) {
  register int i, j, ij;
  register double sum1, sum2, pij;
  sum1 = sum2 = 0.0;
  ij = 0;
  for (i = 0; i < no; ++i) {
    for (j = 0; j < i; ++j, ++ij) {
      pij = pm[ij];
      sum1 += hm[ij] * pij;
      sum2 += gm[ij] * pij;
    }
    pij = pm[ij];
    sum1 += pij * hm[ij] * 0.5;
    sum2 += pij * gm[ij] * 0.5;
    ++ij;
  }
  return (sum1 + sum1 + sum2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<euclidean_algorithm_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  jmp    L9
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  jmp    L9
L4:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L31
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int euclidean_algorithm_1(int m, int n) {
  while (m != n) {
    if (m > n) {
      m = m - n;
    } else {
      n = n - m;
    }
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<euclidean_algorithm_1>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jne    L28
L34:
  ret
L13:
  sub    %edi,%eax
L12:
  cmp    %eax,%edi
  je     L34
L28:
  cmp    %eax,%edi
  jle    L13
  sub    %eax,%edi
  jmp    L12
```

assistant: ```c
int euclidean_algorithm_1(int m, int n) {
  while (m != n) {
    if (m > n) {
      m = m - n;
    } else {
      n = n - m;
    }
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<euclidean_algorithm_1>:
  endbr64
  mov    %edi,%eax
  cmp    %esi,%edi
  jne    L25
  jmp    L48
  nopl   0x0(%rax)
L20:
  sub    %esi,%eax
  cmp    %eax,%esi
  je     L48
L25:
  cmp    %eax,%esi
  jl     L20
  sub    %eax,%esi
  cmp    %eax,%esi
  jne    L25
L48:
  ret
```

assistant: ```c
int euclidean_algorithm_1(int m, int n) {
  while (m != n) {
    if (m > n) {
      m = m - n;
    } else {
      n = n - m;
    }
  }
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<euclidean_algorithm_1>:
  endbr64
  cmp    %esi,%edi
  je     L34
  nopl   0x0(%rax,%rax,1)
L37:
  cmp    %esi,%edi
  jle    L33
  sub    %esi,%edi
  cmp    %edi,%esi
  jne    L37
  mov    %esi,%eax
  ret
  nopl   (%rax)
L33:
  sub    %edi,%esi
  cmp    %esi,%edi
  jne    L37
L34:
  mov    %edi,%eax
  ret
```

assistant: ```c
int euclidean_algorithm_1(int m, int n) {
  while (m != n) {
    if (m > n) {
      m = m - n;
    } else {
      n = n - m;
    }
  }
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitmap_subset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L14
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  not    %rax
  mov    %rdx,%rsi
  and    %rax,%rsi
  mov    D28(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L11
  mov    D28(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  sub    $0x1,%rax
  jmp    L20
L11:
  mov    $0xffffffffffffffff,%rax
L20:
  and    %rsi,%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L13
L14:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__bitmap_subset@plt>
L13:
  leave
  ret
```

assistant: ```c
int bitmap_subset(const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    return !((*src1 & ~(*src2)) & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_subset(src1, src2, nbits);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmap_subset>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%r8d
  cmp    %edx,%r8d
  jl     L7
  mov    (%rsi),%rsi
  not    %rsi
  and    (%rdi),%rsi
  mov    %edx,%eax
  cltd
  idiv   %r8d
  mov    $0xffffffffffffffff,%rax
  test   %edx,%edx
  je     L2
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%rax
  sub    $0x1,%rax
L2:
  test   %rax,%rsi
  sete   %al
  movzbl %al,%eax
  ret
L7:
  sub    $0x8,%rsp
  call   <__bitmap_subset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bitmap_subset(const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    return !((*src1 & ~(*src2)) & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_subset(src1, src2, nbits);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bitmap_subset>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%r8d
  cmp    %edx,%r8d
  jl     L13
  mov    %edx,%eax
  mov    (%rsi),%rsi
  cltd
  idiv   %r8d
  not    %rsi
  and    (%rdi),%rsi
  test   %edx,%edx
  je     L7
  mov    $0xffffffffffffffff,%rax
  mov    %edx,%ecx
  shl    %cl,%rax
  not    %rax
  and    %rax,%rsi
L7:
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  ret
  nopl   0x0(%rax)
L13:
  jmp    1050 <__bitmap_subset@plt>
```

assistant: ```c
int bitmap_subset(const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    return !((*src1 & ~(*src2)) & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_subset(src1, src2, nbits);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitmap_subset>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%r8d
  cmp    %edx,%r8d
  jl     L17
  mov    %edx,%eax
  mov    (%rsi),%rsi
  cltd
  idiv   %r8d
  not    %rsi
  and    (%rdi),%rsi
  test   %edx,%edx
  je     L7
  mov    $0xffffffffffffffff,%rax
  mov    %edx,%ecx
  shl    %cl,%rax
  not    %rax
  and    %rax,%rsi
L7:
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  ret
  nopl   0x0(%rax)
L17:
  jmp    1050 <__bitmap_subset@plt>
```

assistant: ```c
int bitmap_subset(const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    return !((*src1 & ~(*src2)) & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_subset(src1, src2, nbits);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  and    $0x80000000,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L6:
  mov    $0x0,%eax
  call   <abort@plt>
L13:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  sar    %eax
  mov    %eax,%edx
  and    $0x7fffffff,%edx
  add    $0x7fffffff,%edx
  and    $0x7fffffff,%edx
  add    %edx,%edx
  sar    %edx
  mov    %edx,%ecx
  and    $0x7fffffff,%ecx
  mov    -0x4(%rbp),%edx
  and    $0x80000000,%edx
  or     %ecx,%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L6
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  struct {
    int count : 31;
  } s = {0};
  while (s.count--)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  struct {
    int count : 31;
  } s = {0};
  while (s.count--)
    abort();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  struct {
    int count : 31;
  } s = {0};
  while (s.count--)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  struct {
    int count : 31;
  } s = {0};
  while (s.count--)
    abort();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gf8_muladd_28>:
  endbr64
  test   %edx,%edx
  je     L12
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,%r11d
  shl    $0x2,%r11
  lea    (%rdx,%rdx,1),%esi
  mov    %esi,%r13d
  shl    $0x2,%r13
  add    %edx,%esi
  mov    %esi,%r12d
  shl    $0x2,%r12
  mov    %r11d,%ebp
  shl    $0x2,%rbp
  lea    (%rdx,%rdx,4),%edi
  lea    0x0(,%rdi,4),%r9
  add    %esi,%esi
  mov    %esi,%esi
  lea    0x0(,%rsi,4),%r14
  lea    0x0(,%rdx,8),%ebx
  sub    %edx,%ebx
  shl    $0x2,%rbx
  lea    (%rcx,%r11,1),%rdi
  mov    %rdi,-0x8(%rsp)
L3:
  mov    (%rax,%r13,1),%edi
  mov    (%rax,%r12,1),%edx
  mov    (%rax,%rbp,1),%esi
  mov    %esi,%r10d
  xor    (%rax,%r14,1),%r10d
  mov    %edx,%r8d
  xor    (%rax,%r9,1),%r8d
  xor    (%rax,%rbx,1),%r8d
  mov    %r10d,%r15d
  xor    (%rax,%rbx,1),%r15d
  xor    %r8d,%esi
  mov    %r15d,-0x10(%rsp)
  xor    (%rax,%r11,1),%r15d
  mov    %r15d,-0xc(%rsp)
  mov    %esi,%r15d
  xor    (%rax),%r15d
  xor    (%rcx),%r8d
  mov    %r8d,(%rax)
  xor    (%rcx,%r11,1),%r10d
  mov    %r10d,(%rax,%r11,1)
  mov    %edx,%r8d
  xor    (%rcx,%r13,1),%r8d
  mov    %r8d,(%rax,%r13,1)
  mov    %r15d,%r8d
  xor    (%rcx,%r12,1),%r8d
  mov    %r8d,(%rax,%r12,1)
  mov    %edx,%r8d
  xor    (%rcx,%rbp,1),%r8d
  mov    -0xc(%rsp),%r10d
  xor    %r10d,%r8d
  mov    %r8d,(%rax,%rbp,1)
  xor    %edi,%edx
  xor    (%rcx,%r9,1),%edx
  xor    %r15d,%edx
  mov    %edx,(%rax,%r9,1)
  xor    %r10d,%esi
  xor    (%rcx,%r14,1),%esi
  mov    %esi,(%rax,%r14,1)
  xor    (%rcx,%rbx,1),%edi
  xor    -0x10(%rsp),%edi
  mov    %edi,(%rax,%rbx,1)
  add    $0x4,%rcx
  add    $0x4,%rax
  cmp    -0x8(%rsp),%rcx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  ret
```

assistant: ```c
void gf8_muladd_28(uint8_t *out, uint8_t *in, unsigned int width) {
  unsigned int i;
  uint64_t *in_ptr = (uint64_t *)in;
  uint64_t *out_ptr = (uint64_t *)out;
  for (i = 0; i < width; i++) {
    uint64_t out0, out1, out2, out3, out4, out5, out6, out7;
    uint64_t tmp0, tmp1, tmp2;
    uint64_t in0 = out_ptr[0];
    uint64_t in1 = out_ptr[width];
    uint64_t in2 = out_ptr[width * 2];
    uint64_t in3 = out_ptr[width * 3];
    uint64_t in4 = out_ptr[width * 4];
    uint64_t in5 = out_ptr[width * 5];
    uint64_t in6 = out_ptr[width * 6];
    uint64_t in7 = out_ptr[width * 7];
    out2 = in3;
    out1 = in4 ^ in6;
    out0 = in3 ^ in5 ^ in7;
    tmp0 = out1 ^ in7;
    tmp1 = out0 ^ in4;
    out7 = tmp0 ^ in2;
    tmp2 = tmp0 ^ in1;
    out3 = tmp1 ^ in0;
    out6 = tmp1 ^ tmp2;
    out4 = tmp2 ^ in3;
    out5 = out3 ^ in2 ^ in3;
    out_ptr[0] = out0 ^ in_ptr[0];
    out_ptr[width] = out1 ^ in_ptr[width];
    out_ptr[width * 2] = out2 ^ in_ptr[width * 2];
    out_ptr[width * 3] = out3 ^ in_ptr[width * 3];
    out_ptr[width * 4] = out4 ^ in_ptr[width * 4];
    out_ptr[width * 5] = out5 ^ in_ptr[width * 5];
    out_ptr[width * 6] = out6 ^ in_ptr[width * 6];
    out_ptr[width * 7] = out7 ^ in_ptr[width * 7];
    in_ptr++;
    out_ptr++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0x40,%rsp
  mov    %rdi,-0x20028(%rbp)
  mov    %rsi,-0x20030(%rbp)
  mov    %edx,-0x20034(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20028(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20018(%rbp)
  cmpq   $0x0,-0x20018(%rbp)
  jne    L0
  mov    $0x0,%eax
  call   <std_err@plt>
L0:
  movl   $0x1ffff,-0x2001c(%rbp)
  jmp    L4
L45:
  mov    -0x2001c(%rbp),%eax
  cmp    -0x20034(%rbp),%eax
  jle    L53
  mov    -0x20034(%rbp),%eax
  mov    %eax,-0x2001c(%rbp)
L53:
  mov    -0x20018(%rbp),%rdx
  mov    -0x2001c(%rbp),%esi
  lea    -0x20010(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L1
  mov    $0x0,%eax
  call   <read_err@plt>
L1:
  mov    -0x20030(%rbp),%rdx
  mov    -0x2001c(%rbp),%esi
  lea    -0x20010(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    $0x1,%eax
  je     L32
  mov    $0x0,%eax
  call   <write_err@plt>
L32:
  mov    -0x2001c(%rbp),%eax
  sub    %eax,-0x20034(%rbp)
L4:
  cmpl   $0x0,-0x20034(%rbp)
  jne    L45
  mov    -0x20018(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: rb

assistant: ```c
void putfile(u_char *fname, FILE *fdout, u_int size) {
  FILE *fdin;
  int len;
  u_char buff[32768];
  fdin = fopen(fname, "rb");
  if (!fdin)
    std_err();
  for (len = sizeof(buff) - 1; size; size -= len) {
    if (len > size)
      len = size;
    if (fread(buff, len, 1, fdin) != 1)
      read_err();
    if (fwrite(buff, len, 1, fdout) != 1)
      write_err();
  }
  fclose(fdin);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<putfile>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0x10,%rsp
  mov    %rsi,%r14
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L30
L40:
  test   %ebp,%ebp
  je     L19
  mov    $0x1ffff,%ebx
  mov    %rsp,%r12
  jmp    L17
L30:
  mov    $0x0,%eax
  call   <std_err@plt>
  jmp    L40
L2:
  mov    $0x0,%eax
  call   <read_err@plt>
  jmp    L29
L43:
  sub    %ebx,%ebp
  je     L19
L17:
  cmp    %ebp,%ebx
  cmovg  %ebp,%ebx
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  jne    L2
L29:
  mov    %r14,%rcx
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  cmp    $0x1,%eax
  je     L43
  mov    $0x0,%eax
  call   <write_err@plt>
  jmp    L43
L19:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x20010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: rb

assistant: ```c
void putfile(u_char *fname, FILE *fdout, u_int size) {
  FILE *fdin;
  int len;
  u_char buff[32768];
  fdin = fopen(fname, "rb");
  if (!fdin)
    std_err();
  for (len = sizeof(buff) - 1; size; size -= len) {
    if (len > size)
      len = size;
    if (fread(buff, len, 1, fdin) != 1)
      read_err();
    if (fwrite(buff, len, 1, fdout) != 1)
      write_err();
  }
  fclose(fdin);
}
```