ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<make_texture>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  imul   %esi,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L17
  test   %ebx,%ebx
  jle    L17
  mov    %rax,%rsi
  mov    %ebx,%eax
  movslq %ebx,%r10
  mov    %ebx,%edi
  shr    $0x2,%eax
  movdqa D27(%rip),%xmm4
  and    $0xfffffffc,%edi
  xor    %edx,%edx
  lea    -0x1(%rax),%r9d
  shl    $0x2,%r10
  lea    -0x1(%rbx),%r11d
  xor    %ecx,%ecx
  add    $0x1,%r9
  movdqa D15(%rip),%xmm3
  shl    $0x4,%r9
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    %ecx,%r12d
  sar    $0x3,%r12d
  cmp    $0x2,%r11d
  jbe    L50
  movd   %r12d,%xmm5
  movdqa D10(%rip),%xmm1
  lea    (%r9,%rsi,1),%r13
  mov    %rsi,%rax
  pshufd $0x0,%xmm5,%xmm2
  nopw   0x0(%rax,%rax,1)
L56:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm4,%xmm1
  psrad  $0x3,%xmm0
  pxor   %xmm2,%xmm0
  pand   %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %r13,%rax
  jne    L56
  mov    %edi,%eax
  cmp    %ebx,%edi
  je     L18
L4:
  mov    %eax,%r13d
  lea    (%rdx,%rax,1),%r14d
  sar    $0x3,%r13d
  movslq %r14d,%r14
  xor    %r12d,%r13d
  and    $0x1,%r13d
  mov    %r13d,(%r8,%r14,4)
  lea    0x1(%rax),%r13d
  cmp    %r13d,%ebx
  jle    L18
  lea    (%rdx,%r13,1),%r14d
  sar    $0x3,%r13d
  add    $0x2,%eax
  xor    %r12d,%r13d
  movslq %r14d,%r14
  and    $0x1,%r13d
  mov    %r13d,(%r8,%r14,4)
  cmp    %eax,%ebx
  jle    L18
  lea    (%rdx,%rax,1),%r13d
  sar    $0x3,%eax
  xor    %r12d,%eax
  movslq %r13d,%r13
  and    $0x1,%eax
  mov    %eax,(%r8,%r13,4)
L18:
  add    $0x1,%ecx
  add    %ebx,%edx
  add    %r10,%rsi
  cmp    %ecx,%ebp
  jne    L57
L17:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  xor    %eax,%eax
  jmp    L4
```

tool_calls: name: read_data
arguments: data_tag: D27
type: byte[16]
name: read_data
arguments: data_tag: D15
type: byte[16]
name: read_data
arguments: data_tag: D10
type: byte[16]

tool: {"D27": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D15": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
GLfloat *make_texture(int maxs, int maxt) {
  int s, t;
  GLfloat *texture;
  texture = (GLfloat *)malloc(maxs * maxt * sizeof(GLfloat));
  for (t = 0; t < maxt; t++) {
    for (s = 0; s < maxs; s++) {
      texture[s + maxs * t] = ((s >> 3) & 0x1) ^ ((t >> 3) & 0x1);
    }
  }
  return texture;
}
```
user: What is the c source code of the assembly code below?

```asm
<__icheckhost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x1,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L29
  movl   $0xffffffff,-0x18(%rbp)
  addq   $0x1,-0x30(%rbp)
  jmp    L18
L29:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  mov    $0x1,%eax
  jmp    L17
L18:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L82
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <inet_addr@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L82
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  imul   -0x18(%rbp),%eax
  jmp    L17
L82:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L99
  mov    $0x0,%eax
  jmp    L17
L99:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L12
L71:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  lea    -0x24(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L119
  mov    -0x18(%rbp),%eax
  jmp    L17
L119:
  addq   $0x8,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L71
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string
name: read_data
arguments: label: D19
type_guessed: string

tool: D1: -

tool: D19: +

assistant: ```c
int __icheckhost(u_int32_t raddr, char *lhost, const char *rhost) {
  struct hostent *hp;
  u_int32_t laddr;
  int negate = 1;
  char **pp;
  if (strncmp("-", lhost, 1) == 0) {
    negate = -1;
    lhost++;
  } else if (strcmp("+", lhost) == 0) {
    return 1;
  }
  if (isdigit(*lhost) && (long)(laddr = inet_addr(lhost)) != -1)
    return negate * (!(raddr ^ laddr));
  hp = gethostbyname(lhost);
  if (hp == NULL)
    return 0;
  for (pp = hp->h_addr_list; *pp; ++pp)
    if (!memcmp(&raddr, *pp, sizeof(u_int32_t)))
      return negate;
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__icheckhost>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbx
  mov    $0x1,%edx
  lea    D7(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L86
  add    $0x1,%rbx
  mov    $0xffffffff,%r12d
L30:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L118
  mov    %rbx,%rdi
  call   <inet_addr@plt>
  cmp    $0xffffffff,%eax
  je     L118
  cmp    %eax,0xc(%rsp)
  sete   %al
  movzbl %al,%eax
  imul   %eax,%r12d
  jmp    L24
L86:
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  call   <strcmp@plt>
  mov    $0x1,%r12d
  test   %rax,%rax
  jne    L30
  jmp    L24
L118:
  mov    %rbx,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L11
  mov    (%rax),%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L57
  lea    0xc(%rsp),%rbp
L80:
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L24
  add    $0x8,%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L80
  mov    $0x0,%r12d
L24:
  mov    %r12d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0x0,%r12d
  jmp    L24
L57:
  mov    $0x0,%r12d
  jmp    L24
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string

tool: D7: -

tool: D18: +

assistant: ```c
int __icheckhost(u_int32_t raddr, char *lhost, const char *rhost) {
  struct hostent *hp;
  u_int32_t laddr;
  int negate = 1;
  char **pp;
  if (strncmp("-", lhost, 1) == 0) {
    negate = -1;
    lhost++;
  } else if (strcmp("+", lhost) == 0) {
    return 1;
  }
  if (isdigit(*lhost) && (long)(laddr = inet_addr(lhost)) != -1)
    return negate * (!(raddr ^ laddr));
  hp = gethostbyname(lhost);
  if (hp == NULL)
    return 0;
  for (pp = hp->h_addr_list; *pp; ++pp)
    if (!memcmp(&raddr, *pp, sizeof(u_int32_t)))
      return negate;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__icheckhost>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    D14(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L78
  add    $0x1,%rbp
  mov    $0xffffffff,%r12d
L17:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L41
L2:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L54
  mov    (%rax),%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L54
  lea    0xc(%rsp),%rbp
  jmp    L60
  nopl   0x0(%rax)
L61:
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  je     L54
L60:
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L61
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %rbp,%rdi
  call   <inet_addr@plt>
  cmp    $0xffffffff,%eax
  je     L2
  cmp    %eax,0xc(%rsp)
  sete   %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  imul   %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L54:
  add    $0x10,%rsp
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L78:
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  mov    $0x1,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D14: -

tool: D16: +

assistant: ```c
int __icheckhost(u_int32_t raddr, char *lhost, const char *rhost) {
  struct hostent *hp;
  u_int32_t laddr;
  int negate = 1;
  char **pp;
  if (strncmp("-", lhost, 1) == 0) {
    negate = -1;
    lhost++;
  } else if (strcmp("+", lhost) == 0) {
    return 1;
  }
  if (isdigit(*lhost) && (long)(laddr = inet_addr(lhost)) != -1)
    return negate * (!(raddr ^ laddr));
  hp = gethostbyname(lhost);
  if (hp == NULL)
    return 0;
  for (pp = hp->h_addr_list; *pp; ++pp)
    if (!memcmp(&raddr, *pp, sizeof(u_int32_t)))
      return negate;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__icheckhost>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    D14(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L63
  add    $0x1,%rbp
  mov    $0xffffffff,%r12d
L27:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L81
L14:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L12
  mov    (%rax),%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L12
  lea    0xc(%rsp),%rbp
  jmp    L51
  nopl   0x0(%rax)
L53:
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  je     L12
L51:
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L53
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L81:
  mov    %rbp,%rdi
  call   <inet_addr@plt>
  cmp    $0xffffffff,%eax
  je     L14
  cmp    %eax,0xc(%rsp)
  sete   %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  imul   %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L12:
  add    $0x10,%rsp
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L63:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x1,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L27
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D14: -

tool: D3: +

assistant: ```c
int __icheckhost(u_int32_t raddr, char *lhost, const char *rhost) {
  struct hostent *hp;
  u_int32_t laddr;
  int negate = 1;
  char **pp;
  if (strncmp("-", lhost, 1) == 0) {
    negate = -1;
    lhost++;
  } else if (strcmp("+", lhost) == 0) {
    return 1;
  }
  if (isdigit(*lhost) && (long)(laddr = inet_addr(lhost)) != -1)
    return negate * (!(raddr ^ laddr));
  hp = gethostbyname(lhost);
  if (hp == NULL)
    return 0;
  for (pp = hp->h_addr_list; *pp; ++pp)
    if (!memcmp(&raddr, *pp, sizeof(u_int32_t)))
      return negate;
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<triangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  -0x4(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  seta   %al
  xor    $0x1,%eax
  test   %al,%al
  je     L57
  mov    $0x2,%eax
  jmp    L114
L57:
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L9
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jne    L9
  movss  -0x8(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L9
  movss  -0x8(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jne    L9
  mov    $0x3,%eax
  jmp    L114
L9:
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L14
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  je     L101
L14:
  movss  -0x8(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L116
  movss  -0x8(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  je     L101
L116:
  movss  -0x4(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L47
  movss  -0x4(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jne    L47
L101:
  mov    $0x4,%eax
  jmp    L114
L47:
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L106
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  je     L114
L106:
  movss  -0x4(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L33
  movss  -0x4(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  je     L114
L33:
  mov    $0x5,%eax
  jmp    L114
L114:
  pop    %rbp
  ret
```

assistant: ```c
int triangle(float a, float b, float c) {
  if (!(a + b > c)) {
    return 2;
  } else {
    if (a == b && b == c) {
      return 3;
    } else if (a == b || b == c || a == c) {
      return 4;
    } else if (a != b && a != c) {
      return 5;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<triangle>:
  endbr64
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm2,%xmm3
  jbe    L3
  ucomiss %xmm1,%xmm0
  setnp  %cl
  mov    $0x0,%eax
  cmovne %eax,%ecx
  ucomiss %xmm2,%xmm1
  setnp  %sil
  cmovne %eax,%esi
  test   %cl,%cl
  je     L5
  mov    $0x3,%eax
  test   %sil,%sil
  jne    L8
L5:
  ucomiss %xmm2,%xmm0
  setnp  %dl
  mov    $0x0,%eax
  cmovne %eax,%edx
  or     %ecx,%edx
  or     %esi,%edx
  movzbl %dl,%edx
  mov    $0x5,%eax
  sub    %edx,%eax
  ret
L3:
  mov    $0x2,%eax
L8:
  ret
```

assistant: ```c
int triangle(float a, float b, float c) {
  if (!(a + b > c)) {
    return 2;
  } else {
    if (a == b && b == c) {
      return 3;
    } else if (a == b || b == c || a == c) {
      return 4;
    } else if (a != b && a != c) {
      return 5;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<triangle>:
  endbr64
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm2,%xmm3
  jbe    L24
  ucomiss %xmm1,%xmm0
  mov    $0x0,%eax
  setnp  %cl
  cmovne %eax,%ecx
  ucomiss %xmm2,%xmm1
  setnp  %sil
  cmovne %eax,%esi
  test   %cl,%cl
  je     L7
  mov    $0x3,%eax
  test   %sil,%sil
  jne    L29
L7:
  ucomiss %xmm2,%xmm0
  mov    $0x0,%eax
  setnp  %dl
  cmovne %eax,%edx
  mov    $0x5,%eax
  or     %ecx,%edx
  or     %esi,%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0x2,%eax
L29:
  ret
```

assistant: ```c
int triangle(float a, float b, float c) {
  if (!(a + b > c)) {
    return 2;
  } else {
    if (a == b && b == c) {
      return 3;
    } else if (a == b || b == c || a == c) {
      return 4;
    } else if (a != b && a != c) {
      return 5;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<triangle>:
  endbr64
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm2,%xmm3
  jbe    L9
  ucomiss %xmm1,%xmm0
  mov    $0x0,%eax
  setnp  %cl
  cmovne %eax,%ecx
  ucomiss %xmm2,%xmm1
  setnp  %sil
  cmovne %eax,%esi
  test   %cl,%cl
  je     L5
  mov    $0x3,%eax
  test   %sil,%sil
  jne    L6
L5:
  ucomiss %xmm2,%xmm0
  mov    $0x0,%eax
  setnp  %dl
  cmovne %eax,%edx
  mov    $0x5,%eax
  or     %ecx,%edx
  or     %esi,%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x2,%eax
L6:
  ret
```

assistant: ```c
int triangle(float a, float b, float c) {
  if (!(a + b > c)) {
    return 2;
  } else {
    if (a == b && b == c) {
      return 3;
    } else if (a == b || b == c || a == c) {
      return 4;
    } else if (a != b && a != c) {
      return 5;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isKingLockedByQueen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <getCellIdLeft@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <getCellIdRight@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <getCellIdAbove@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <getCellIdBelow@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L44
L40:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  test   %eax,%eax
  js     L19
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    -0x38(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  jne    L19
  mov    $0x0,%eax
  jmp    L34
L19:
  addl   $0x1,-0x28(%rbp)
L44:
  cmpl   $0x3,-0x28(%rbp)
  jle    L40
  mov    $0x1,%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int isKingLockedByQueen(int kingCellId, int queenCellId) {
  int kingNeighborId[4];
  int numCanMove = 0, index;
  kingNeighborId[0] = getCellIdLeft(kingCellId);
  kingNeighborId[1] = getCellIdRight(kingCellId);
  kingNeighborId[2] = getCellIdAbove(kingCellId);
  kingNeighborId[3] = getCellIdBelow(kingCellId);
  for (index = 0; index < 4; index++)
    if (kingNeighborId[index] >= 0 && !isOnQueenRoute(kingNeighborId[index], queenCellId))
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<isKingLockedByQueen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <getCellIdLeft@plt>
  mov    %eax,(%rsp)
  mov    %ebx,%edi
  call   <getCellIdRight@plt>
  mov    %eax,0x4(%rsp)
  mov    %ebx,%edi
  call   <getCellIdAbove@plt>
  mov    %eax,0x8(%rsp)
  mov    %ebx,%edi
  call   <getCellIdBelow@plt>
  mov    %eax,0xc(%rsp)
  mov    %rsp,%rbx
  lea    0x10(%rsp),%r12
  jmp    L8
L37:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L27
L8:
  mov    (%rbx),%edi
  test   %edi,%edi
  js     L37
  mov    %ebp,%esi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  jne    L37
  jmp    L40
L27:
  mov    $0x1,%eax
L40:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isKingLockedByQueen(int kingCellId, int queenCellId) {
  int kingNeighborId[4];
  int numCanMove = 0, index;
  kingNeighborId[0] = getCellIdLeft(kingCellId);
  kingNeighborId[1] = getCellIdRight(kingCellId);
  kingNeighborId[2] = getCellIdAbove(kingCellId);
  kingNeighborId[3] = getCellIdBelow(kingCellId);
  for (index = 0; index < 4; index++)
    if (kingNeighborId[index] >= 0 && !isOnQueenRoute(kingNeighborId[index], queenCellId))
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isKingLockedByQueen>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <getCellIdLeft@plt>
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <getCellIdRight@plt>
  mov    %r13d,%edi
  mov    %eax,0x4(%rsp)
  call   <getCellIdAbove@plt>
  mov    %r13d,%edi
  lea    0x10(%rsp),%r13
  mov    %eax,0x8(%rsp)
  call   <getCellIdBelow@plt>
  mov    %eax,0xc(%rsp)
  test   %ebp,%ebp
  jns    L54
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L39
  mov    (%rbx),%ebp
  test   %ebp,%ebp
  js     L17
L54:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  jne    L17
  nopl   (%rax)
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  jmp    L21
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isKingLockedByQueen(int kingCellId, int queenCellId) {
  int kingNeighborId[4];
  int numCanMove = 0, index;
  kingNeighborId[0] = getCellIdLeft(kingCellId);
  kingNeighborId[1] = getCellIdRight(kingCellId);
  kingNeighborId[2] = getCellIdAbove(kingCellId);
  kingNeighborId[3] = getCellIdBelow(kingCellId);
  for (index = 0; index < 4; index++)
    if (kingNeighborId[index] >= 0 && !isOnQueenRoute(kingNeighborId[index], queenCellId))
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isKingLockedByQueen>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <getCellIdLeft@plt>
  mov    %ebp,%edi
  mov    %eax,%r15d
  call   <getCellIdRight@plt>
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <getCellIdAbove@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <getCellIdBelow@plt>
  mov    %eax,%ebp
  test   %r15d,%r15d
  jns    L46
  test   %r14d,%r14d
  jns    L84
L102:
  test   %r13d,%r13d
  jns    L14
L59:
  test   %ebp,%ebp
  jns    L3
L32:
  mov    $0x1,%eax
L100:
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L46:
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  je     L100
  test   %r14d,%r14d
  js     L102
L84:
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  je     L100
  test   %r13d,%r13d
  js     L59
L14:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  je     L100
  test   %ebp,%ebp
  js     L32
L3:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <isOnQueenRoute@plt>
  test   %eax,%eax
  jne    L32
  jmp    L100
```

assistant: ```c
int isKingLockedByQueen(int kingCellId, int queenCellId) {
  int kingNeighborId[4];
  int numCanMove = 0, index;
  kingNeighborId[0] = getCellIdLeft(kingCellId);
  kingNeighborId[1] = getCellIdRight(kingCellId);
  kingNeighborId[2] = getCellIdAbove(kingCellId);
  kingNeighborId[3] = getCellIdBelow(kingCellId);
  for (index = 0; index < 4; index++)
    if (kingNeighborId[index] >= 0 && !isOnQueenRoute(kingNeighborId[index], queenCellId))
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: %d ,%d


assistant: ```c
int main() {
  int hi = 2;
  int r = 0, r2 = 0;
  int low = 1;
  r = hi << 4 + low;
  r2 = (hi << 4) + low;
  printf("%d ,%d\n", r, r2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edx
  mov    $0x40,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: %d ,%d


assistant: ```c
int main() {
  int hi = 2;
  int r = 0, r2 = 0;
  int low = 1;
  r = hi << 4 + low;
  r2 = (hi << 4) + low;
  printf("%d ,%d\n", r, r2);
  return 0;
}
```