ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<rogerstanimoto_distance_bool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L125
L44:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L54
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L54
  mov    $0x1,%eax
  jmp    L55
L54:
  mov    $0x0,%eax
L55:
  add    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    $0x1,%eax
  jmp    L53
L14:
  mov    $0x0,%eax
L53:
  add    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L76
  mov    $0x1,%eax
  jmp    L0
L76:
  mov    $0x0,%eax
L0:
  add    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    $0x1,%eax
  jmp    L65
L46:
  mov    $0x0,%eax
L65:
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L125:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L44
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x10(%rbp),%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  addsd  %xmm0,%xmm2
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double rogerstanimoto_distance_bool(const char *u, const char *v, int n) {
  int i = 0;
  int ntt = 0, nff = 0, nft = 0, ntf = 0;
  for (i = 0; i < n; i++) {
    ntt += (u[i] && v[i]);
    ntf += (u[i] && !v[i]);
    nft += (!u[i] && v[i]);
    nff += (!u[i] && !v[i]);
  }
  return (2.0 * (ntf + nft)) / ((double)ntt + nff + (2.0 * (ntf + nft)));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rogerstanimoto_distance_bool>:
  endbr64
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L119
  mov    %rdi,%r8
  mov    %edx,%edx
  mov    $0x0,%eax
  mov    $0x0,%ebx
  mov    $0x0,%r9d
  mov    $0x0,%edi
  mov    $0x0,%r11d
  mov    $0x1,%ebp
  mov    $0x0,%r10d
  jmp    L36
L119:
  mov    $0x0,%ebx
  mov    $0x0,%r9d
  mov    $0x0,%edi
  mov    $0x0,%r11d
L56:
  add    %ebx,%r9d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  addsd  %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r11d,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
L66:
  add    $0x1,%r11d
L62:
  test   %cl,%cl
  jne    L115
L10:
  add    $0x1,%r9d
L115:
  mov    %r10d,%ecx
L7:
  add    %ecx,%edi
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L56
L36:
  movzbl (%r8,%rax,1),%ecx
  test   %cl,%cl
  je     L97
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L66
  jne    L62
  add    $0x1,%ebx
  test   %cl,%cl
  jne    L115
  mov    %ebp,%ecx
  jmp    L7
L97:
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L10
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L115
  mov    %ebp,%ecx
  jmp    L7
```

assistant: ```c
double rogerstanimoto_distance_bool(const char *u, const char *v, int n) {
  int i = 0;
  int ntt = 0, nff = 0, nft = 0, ntf = 0;
  for (i = 0; i < n; i++) {
    ntt += (u[i] && v[i]);
    ntf += (u[i] && !v[i]);
    nft += (!u[i] && v[i]);
    nff += (!u[i] && !v[i]);
  }
  return (2.0 * (ntf + nft)) / ((double)ntt + nff + (2.0 * (ntf + nft)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rogerstanimoto_distance_bool>:
  endbr64
  test   %edx,%edx
  jle    L59
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %r11d,%r11d
  jmp    L5
  nop
L18:
  test   %cl,%cl
  je     L25
  add    $0x1,%r11d
L17:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L58
L5:
  cmpb   $0x0,(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  jne    L18
  cmp    $0x1,%cl
  sbb    $0xffffffff,%r9d
  cmp    $0x1,%cl
  adc    $0x0,%r8d
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
L58:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  add    %r9d,%r10d
  cvtsi2sd %r10d,%xmm0
  cvtsi2sd %r11d,%xmm1
  cvtsi2sd %r8d,%xmm2
  addsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L25:
  add    $0x1,%r10d
  jmp    L17
  xchg   %ax,%ax
L59:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double rogerstanimoto_distance_bool(const char *u, const char *v, int n) {
  int i = 0;
  int ntt = 0, nff = 0, nft = 0, ntf = 0;
  for (i = 0; i < n; i++) {
    ntt += (u[i] && v[i]);
    ntf += (u[i] && !v[i]);
    nft += (!u[i] && v[i]);
    nff += (!u[i] && !v[i]);
  }
  return (2.0 * (ntf + nft)) / ((double)ntt + nff + (2.0 * (ntf + nft)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rogerstanimoto_distance_bool>:
  endbr64
  test   %edx,%edx
  jle    L36
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r11d,%r11d
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  jmp    L54
  nop
L58:
  test   %cl,%cl
  je     L37
  add    $0x1,%r10d
L27:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L35
L54:
  cmpb   $0x0,(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  jne    L58
  cmp    $0x1,%cl
  sbb    $0xffffffff,%r8d
  cmp    $0x1,%cl
  adc    $0x0,%r9d
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L54
L35:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  add    %r11d,%r8d
  cvtsi2sd %r8d,%xmm0
  cvtsi2sd %r10d,%xmm1
  cvtsi2sd %r9d,%xmm2
  addsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L37:
  add    $0x1,%r11d
  jmp    L27
  xchg   %ax,%ax
L36:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double rogerstanimoto_distance_bool(const char *u, const char *v, int n) {
  int i = 0;
  int ntt = 0, nff = 0, nft = 0, ntf = 0;
  for (i = 0; i < n; i++) {
    ntt += (u[i] && v[i]);
    ntf += (u[i] && !v[i]);
    nft += (!u[i] && v[i]);
    nff += (!u[i] && !v[i]);
  }
  return (2.0 * (ntf + nft)) / ((double)ntt + nff + (2.0 * (ntf + nft)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L21:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  jmp    L23
L26:
  nop
L23:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    if ((*dst++ = *src++) == 0)
      break;
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L19
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rcx
L2:
  add    $0x1,%rsi
  add    $0x1,%rax
  movzbl -0x1(%rsi),%edx
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  je     L19
  cmp    %rcx,%rax
  jne    L2
  mov    %rcx,%rax
L19:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    if ((*dst++ = *src++) == 0)
      break;
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L18
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rcx
  jmp    L38
  nopl   0x0(%rax)
L23:
  cmp    %rcx,%rax
  je     L18
L38:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L23
L18:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    if ((*dst++ = *src++) == 0)
      break;
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L23
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rcx
  jmp    L19
  nopl   0x0(%rax)
L37:
  cmp    %rcx,%rax
  je     L23
L19:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L37
L23:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    if ((*dst++ = *src++) == 0)
      break;
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<av_strlcatf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L11
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L11:
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd0(%rbp),%rax
  cmp    -0xb8(%rbp),%rax
  jbe    L7
  mov    -0xd0(%rbp),%rax
  sub    -0xb8(%rbp),%rax
  jmp    L0
L7:
  mov    $0x0,%eax
L0:
  mov    -0xc8(%rbp),%rcx
  mov    -0xb8(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0xbc(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    %rax,%rsi
  call   <vsnprintf@plt>
  add    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t av_strlcatf(char *dst, size_t size, const char *fmt, ...) {
  size_t len = strlen(dst);
  va_list vl;
  va_start(vl, fmt);
  len += vsnprintf(dst + len, size > len ? size - len : 0, fmt, vl);
  va_end(vl);
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<av_strlcatf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %r13,%rsi
  sub    %rbx,%rsi
  cmp    %r13,%rbx
  mov    $0x0,%eax
  cmovae %rax,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  call   <vsnprintf@plt>
  add    %rax,%rbx
  mov    %r14d,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t av_strlcatf(char *dst, size_t size, const char *fmt, ...) {
  size_t len = strlen(dst);
  va_list vl;
  va_start(vl, fmt);
  len += vsnprintf(dst + len, size > len ? size - len : 0, fmt, vl);
  va_end(vl);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<av_strlcatf>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14d,%edi
  mov    %rax,%rbx
  call   <va_start@plt>
  mov    %r13,%rsi
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,1),%rdi
  sub    %rbx,%rsi
  cmp    %r13,%rbx
  mov    %r14d,%ecx
  mov    %r12,%rdx
  cmovae %rax,%rsi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  lea    (%rax,%rbx,1),%r12
  call   <va_end@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t av_strlcatf(char *dst, size_t size, const char *fmt, ...) {
  size_t len = strlen(dst);
  va_list vl;
  va_start(vl, fmt);
  len += vsnprintf(dst + len, size > len ? size - len : 0, fmt, vl);
  va_end(vl);
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<av_strlcatf>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14d,%edi
  mov    %rax,%rbx
  call   <va_start@plt>
  mov    %r13,%rsi
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,1),%rdi
  sub    %rbx,%rsi
  cmp    %r13,%rbx
  mov    %r14d,%ecx
  mov    %r12,%rdx
  cmovae %rax,%rsi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  lea    (%rax,%rbx,1),%r12
  call   <va_end@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t av_strlcatf(char *dst, size_t size, const char *fmt, ...) {
  size_t len = strlen(dst);
  va_list vl;
  va_start(vl, fmt);
  len += vsnprintf(dst + len, size > len ? size - len : 0, fmt, vl);
  va_end(vl);
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<round_f_inverse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    0x4(%rdi),%r13
  lea    0x4(%rsi),%r14
  mov    (%rsi),%edx
  mov    %edx,%eax
  shl    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x18,%ecx
  or     %ecx,%eax
  mov    %edx,%ecx
  xor    (%rdi),%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x8,%ecx
  mov    %edx,%esi
  shl    $0x18,%esi
  or     %esi,%ecx
  xor    %ecx,%eax
  mov    %eax,0x0(%rbp)
  mov    %edx,(%rdi)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0x14(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0x10(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0xc(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x8(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x4(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void round_f_inverse(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  uint32_t temp;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  temp = *right;
  *left ^= *right ^ (((*right) << (8)) | ((*right) >> (32 - 8))) ^ (((*right) >> (8)) | ((*right) << (32 - 8)));
  *right = *left;
  *left = temp;
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[5]);
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[4]);
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[3]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[2]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[1]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[0]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<round_f_inverse>:
  endbr64
  push   %r14
  lea    0x4(%rsi),%r14
  push   %r13
  lea    0x4(%rdi),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%edx
  mov    %rdi,%rbx
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x18,%ecx
  shl    $0x8,%eax
  or     %ecx,%eax
  mov    (%rdi),%ecx
  shl    $0x18,%esi
  xor    %edx,%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x8,%ecx
  or     %esi,%ecx
  mov    %r14,%rsi
  xor    %ecx,%eax
  mov    %eax,0x0(%rbp)
  mov    %edx,(%rdi)
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0x14(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0x10(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0xc(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x8(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x4(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void round_f_inverse(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  uint32_t temp;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  temp = *right;
  *left ^= *right ^ (((*right) << (8)) | ((*right) >> (32 - 8))) ^ (((*right) >> (8)) | ((*right) << (32 - 8)));
  *right = *left;
  *left = temp;
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[5]);
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[4]);
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[3]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[2]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[1]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[0]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<round_f_inverse>:
  endbr64
  push   %r14
  lea    0x4(%rsi),%r14
  push   %r13
  lea    0x4(%rdi),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%edx
  mov    %rdi,%rbx
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x18,%ecx
  shl    $0x8,%eax
  or     %ecx,%eax
  mov    (%rdi),%ecx
  shl    $0x18,%esi
  xor    %edx,%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x8,%ecx
  or     %esi,%ecx
  mov    %r14,%rsi
  xor    %ecx,%eax
  mov    %eax,0x0(%rbp)
  mov    %edx,(%rdi)
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0x14(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0x10(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    0xc(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x8(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x4(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void round_f_inverse(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  uint32_t temp;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  temp = *right;
  *left ^= *right ^ (((*right) << (8)) | ((*right) >> (32 - 8))) ^ (((*right) >> (8)) | ((*right) << (32 - 8)));
  *right = *left;
  *left = temp;
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[5]);
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[4]);
  speckey_inverse(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[3]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[2]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[1]);
  speckey_inverse(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[0]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  call   <outb@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 1016 + 0x01);
  outb(0x01, 1016 + 0x02);
  outb(0x80 | 3, 1016 + 0x03);
  outb((115200 / 115200) & 0xFF, 1016 + 0x00);
  outb(((115200 / 115200) >> 8) & 0xFF, 1016 + 0x01);
  outb(3, 1016 + 0x03);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  call   <outb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 1016 + 0x01);
  outb(0x01, 1016 + 0x02);
  outb(0x80 | 3, 1016 + 0x03);
  outb((115200 / 115200) & 0xFF, 1016 + 0x00);
  outb(((115200 / 115200) >> 8) & 0xFF, 1016 + 0x01);
  outb(3, 1016 + 0x03);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <outb@plt>
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 1016 + 0x01);
  outb(0x01, 1016 + 0x02);
  outb(0x80 | 3, 1016 + 0x03);
  outb((115200 / 115200) & 0xFF, 1016 + 0x00);
  outb(((115200 / 115200) >> 8) & 0xFF, 1016 + 0x01);
  outb(3, 1016 + 0x03);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <outb@plt>
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 1016 + 0x01);
  outb(0x01, 1016 + 0x02);
  outb(0x80 | 3, 1016 + 0x03);
  outb((115200 / 115200) & 0xFF, 1016 + 0x00);
  outb(((115200 / 115200) >> 8) & 0xFF, 1016 + 0x01);
  outb(3, 1016 + 0x03);
}
```