ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<an_main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <init_accent@plt>
  mov    %rsp,%rbp
  mov    $0xffffffff,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <canon_sort@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    D4(%rip),%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0x70(%rsp),%rbx
  test   %rax,%rax
  je     L39
L59:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L25
  lea    0xe0(%rsp),%rdi
  mov    %r12d,%edx
  mov    %rbx,%rsi
  call   <canon_sort@plt>
  test   %rax,%rax
  jne    L59
  lea    0xe0(%rsp),%rsi
  mov    %rsp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L59
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,0x70(%rsp,%rax,1)
  mov    %rbx,%rdi
  call   *%r13
  jmp    L59
L39:
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L7
L25:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L7:
  mov    0x148(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: r

assistant: ```c
int an_main(char *pattern, char *dictfile, void (*callback)(const char *word)) {
  FILE *fp;
  char an[100];
  char buf[100];
  char buf2[100];
  int anlen;
  int c;
  init_accent();
  canon_sort(an, pattern, -1);
  anlen = strlen(an);
  fp = fopen(dictfile, "r");
  if (fp == 0) {
    perror(dictfile);
    return 1;
  }
  while (fgets(buf, sizeof(buf), fp) != NULL) {
    if (canon_sort(buf2, buf, anlen))
      continue;
    if (strcmp(an, buf2) == 0) {
      buf[strlen(buf) - 1] = 0;
      callback(buf);
    }
  }
  fclose(fp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<an_main>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x168,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%r14
  lea    0x80(%rsp),%rbx
  lea    0xf0(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  call   <init_accent@plt>
  mov    %rbp,%rsi
  mov    $0xffffffff,%edx
  mov    %r14,%rdi
  call   <canon_sort@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    D7(%rip),%rsi
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L49
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L66
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <canon_sort@plt>
  test   %rax,%rax
  jne    L9
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  sub    $0x1,%eax
  cltq
  movb   $0x0,0x80(%rsp,%rax,1)
  mov    0x8(%rsp),%rax
  call   *%rax
  jmp    L9
  nopl   0x0(%rax)
L66:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L42:
  mov    0x158(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x168,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %r15,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L42
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: r

assistant: ```c
int an_main(char *pattern, char *dictfile, void (*callback)(const char *word)) {
  FILE *fp;
  char an[100];
  char buf[100];
  char buf2[100];
  int anlen;
  int c;
  init_accent();
  canon_sort(an, pattern, -1);
  anlen = strlen(an);
  fp = fopen(dictfile, "r");
  if (fp == 0) {
    perror(dictfile);
    return 1;
  }
  while (fgets(buf, sizeof(buf), fp) != NULL) {
    if (canon_sort(buf2, buf, anlen))
      continue;
    if (strcmp(an, buf2) == 0) {
      buf[strlen(buf) - 1] = 0;
      callback(buf);
    }
  }
  fclose(fp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<an_main>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x168,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%r14
  lea    0x80(%rsp),%rbx
  lea    0xf0(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  call   <init_accent@plt>
  mov    %rbp,%rsi
  mov    $0xffffffff,%edx
  mov    %r14,%rdi
  call   <canon_sort@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    D7(%rip),%rsi
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L46
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L6
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <canon_sort@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  sub    $0x1,%eax
  cltq
  movb   $0x0,0x80(%rsp,%rax,1)
  mov    0x8(%rsp),%rax
  call   *%rax
  jmp    L10
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L17:
  mov    0x158(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x168,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %r15,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L17
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: r

assistant: ```c
int an_main(char *pattern, char *dictfile, void (*callback)(const char *word)) {
  FILE *fp;
  char an[100];
  char buf[100];
  char buf2[100];
  int anlen;
  int c;
  init_accent();
  canon_sort(an, pattern, -1);
  anlen = strlen(an);
  fp = fopen(dictfile, "r");
  if (fp == 0) {
    perror(dictfile);
    return 1;
  }
  while (fgets(buf, sizeof(buf), fp) != NULL) {
    if (canon_sort(buf2, buf, anlen))
      continue;
    if (strcmp(an, buf2) == 0) {
      buf[strlen(buf) - 1] = 0;
      callback(buf);
    }
  }
  fclose(fp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L69
  jmp    L34
L38:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L75
L34:
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  jmp    L69
L75:
  nop
L69:
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  cmpq   $0x0,-0x38(%rbp)
  je     L73
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L73:
  nop
L4:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
L19:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++) {
    }
  }
  return (s - src - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L46
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
L18:
  cmp    %rcx,%rdi
  je     L41
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L18
  jmp    L50
L46:
  mov    %rsi,%rax
L59:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L59
L50:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L41:
  movb   $0x0,(%rdi)
  jmp    L59
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++) {
    }
  }
  return (s - src - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L50
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L56:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L53
L44:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L56
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L13
L53:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L13
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++) {
    }
  }
  return (s - src - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L57
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L42
L22:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L7
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L8
L42:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L8
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++) {
    }
  }
  return (s - src - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inicializarProducciones>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L32:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L27:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0xffffffff,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x31,-0x4(%rbp)
  jle    L27
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0xf9,-0x8(%rbp)
  jle    L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void inicializarProducciones(int producciones[250][50]) {
  int i, j;
  for (i = 0; 250 > i; ++i) {
    for (j = 0; 50 > j; ++j) {
      producciones[i][j] = -1;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inicializarProducciones>:
  endbr64
  mov    %rdi,%rcx
  lea    0xc8(%rdi),%rdx
  add    $0xc418,%rcx
  jmp    L26
L11:
  add    $0xc8,%rdx
  cmp    %rcx,%rdx
  je     L13
L26:
  lea    -0xc8(%rdx),%rax
L22:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L22
  jmp    L11
L13:
  ret
```

assistant: ```c
void inicializarProducciones(int producciones[250][50]) {
  int i, j;
  for (i = 0; 250 > i; ++i) {
    for (j = 0; 50 > j; ++j) {
      producciones[i][j] = -1;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inicializarProducciones>:
  endbr64
  mov    $0xc350,%edx
  mov    $0xff,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void inicializarProducciones(int producciones[250][50]) {
  int i, j;
  for (i = 0; 250 > i; ++i) {
    for (j = 0; 50 > j; ++j) {
      producciones[i][j] = -1;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inicializarProducciones>:
  endbr64
  mov    $0xc350,%edx
  mov    $0xff,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void inicializarProducciones(int producciones[250][50]) {
  int i, j;
  for (i = 0; 250 > i; ++i) {
    for (j = 0; 50 > j; ++j) {
      producciones[i][j] = -1;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D27(%rip),%xmm0
  movss  %xmm0,-0x48(%rbp)
  movss  D30(%rip),%xmm0
  movss  %xmm0,-0x44(%rbp)
  movq   $0x99,-0x1c(%rbp)
  movw   $0x0,-0x14(%rbp)
  movq   $0x101,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  fldt   0xe70(%rip)        # 2040 <_fini+0xd70>
  fstpt  -0x40(%rbp)
  fldt   0xe77(%rip)        # 2050 <_fini+0xd80>
  fstpt  -0x30(%rbp)
  fldt   0xe7e(%rip)        # 2060 <_fini+0xd90>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  movss  -0x48(%rbp),%xmm0
  addss  -0x44(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x44(%rbp),%xmm2
  movq   %xmm2,%rax
  flds   -0x48(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  fldt   -0x40(%rbp)
  fldt   -0x30(%rbp)
  faddp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  push   -0x38(%rbp)
  push   -0x40(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x30,%rsp
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <pr@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <pr@plt>
  lea    -0x12(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bcddemo@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <pr@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D27
type: f32
name: retrieve_data
arguments: tag: D30
type: f32
name: retrieve_data
arguments: tag: D31
type: string
name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D42
type: string

tool: D27: 0.1

tool: D30: 0.2

tool: D31: sizeof long double: %lu


tool: D35: %g + %g = %g


tool: D42: %Lg + %Lg = %Lg


assistant: ```c
int main(void) {
  float a = 0.1;
  float b = 0.2;
  unsigned char bcda[10] = {
      9 << 4 | 9,
      0,
  };
  unsigned char bcdb[10] = {
      1,
      1,
      0,
  };
  long double aa = 0.1, bb = 0.2;
  printf("sizeof long double: %lu\n", sizeof aa);
  printf("%g + %g = %g\n", a, b, a + b);
  printf("%Lg + %Lg = %Lg\n", aa, bb, aa + bb);
  pr(bcda);
  pr(bcdb);
  bcddemo(bcda, bcdb);
  pr(bcda);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x99,0x14(%rsp)
  movw   $0x0,0x1c(%rsp)
  movq   $0x101,0x1e(%rsp)
  movw   $0x0,0x26(%rsp)
  flds   0xe7f(%rip)        # 2038 <_fini+0xd88>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  flds   0xe5f(%rip)        # 203c <_fini+0xd8c>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  movsd  D16(%rip),%xmm1
  movsd  D34(%rip),%xmm0
  lea    D41(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  push   $0x3ffd
  push   $0xffffffff99999c00
  movl   $0x99999999,0x4(%rsp)
  fldl   0xe27(%rip)        # 2050 <_fini+0xda0>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  fldl   0xe1a(%rip)        # 2058 <_fini+0xda8>
  fstpt  0x20(%rsp)
  mov    0x20(%rsp),%rax
  mov    0x28(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x30,%rsp
  lea    0x14(%rsp),%rbx
  mov    %rbx,%rdi
  call   <pr@plt>
  lea    0x1e(%rsp),%rbp
  mov    %rbp,%rdi
  call   <pr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bcddemo@plt>
  mov    %rbx,%rdi
  call   <pr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D28
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: byte[8]
name: disassemble_data
arguments: label: D34
type_infered: byte[8]
name: disassemble_data
arguments: label: D41
type_infered: string
name: disassemble_data
arguments: label: D43
type_infered: string

tool: D28: sizeof long double: %lu


tool: {"D16": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: {"D34": [0x00,0x00,0x00,0xa0,0x99,0x99,0xc9,0x3f]}

tool: D41: %g + %g = %g


tool: D43: %Lg + %Lg = %Lg


assistant: ```c
int main(void) {
  float a = 0.1;
  float b = 0.2;
  unsigned char bcda[10] = {
      9 << 4 | 9,
      0,
  };
  unsigned char bcdb[10] = {
      1,
      1,
      0,
  };
  long double aa = 0.1, bb = 0.2;
  printf("sizeof long double: %lu\n", sizeof aa);
  printf("%g + %g = %g\n", a, b, a + b);
  printf("%Lg + %Lg = %Lg\n", aa, bb, aa + bb);
  pr(bcda);
  pr(bcdb);
  bcddemo(bcda, bcdb);
  pr(bcda);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  lea    D14(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  flds   0xf5e(%rip)        # 2038 <_fini+0xd8c>
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  mov    %dx,0x26(%rsp)
  mov    %ax,0x1c(%rsp)
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  movq   $0x99,0x14(%rsp)
  movq   $0x101,0x1e(%rsp)
  push   %rdx
  push   %rax
  xor    %eax,%eax
  call   <printf@plt>
  flds   0xf1a(%rip)        # 203c <_fini+0xd90>
  movsd  D33(%rip),%xmm1
  lea    D7(%rip),%rdi
  movsd  D15(%rip),%xmm0
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  movabs $0x9999999999999c00,%rcx
  fldl   0xeea(%rip)        # 2050 <_fini+0xda4>
  push   $0x3ffd
  lea    D22(%rip),%rdi
  push   %rcx
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  fldl   0xed2(%rip)        # 2058 <_fini+0xdac>
  push   %rdx
  push   %rax
  fstpt  0x20(%rsp)
  mov    0x28(%rsp),%edx
  mov    0x20(%rsp),%rax
  push   %rdx
  push   %rax
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x30,%rsp
  lea    0x14(%rsp),%rbp
  lea    0x1e(%rsp),%r12
  mov    %rbp,%rdi
  call   <pr@plt>
  mov    %r12,%rdi
  call   <pr@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <bcddemo@plt>
  mov    %rbp,%rdi
  call   <pr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D33
type_guessed: byte[8]
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: byte[8]
name: read_data
arguments: data_label: D22
type_guessed: string

tool: D14: sizeof long double: %lu


tool: {"D33": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: D7: %g + %g = %g


tool: {"D15": [0x00,0x00,0x00,0xa0,0x99,0x99,0xc9,0x3f]}

tool: D22: %Lg + %Lg = %Lg


assistant: ```c
int main(void) {
  float a = 0.1;
  float b = 0.2;
  unsigned char bcda[10] = {
      9 << 4 | 9,
      0,
  };
  unsigned char bcdb[10] = {
      1,
      1,
      0,
  };
  long double aa = 0.1, bb = 0.2;
  printf("sizeof long double: %lu\n", sizeof aa);
  printf("%g + %g = %g\n", a, b, a + b);
  printf("%Lg + %Lg = %Lg\n", aa, bb, aa + bb);
  pr(bcda);
  pr(bcdb);
  bcddemo(bcda, bcdb);
  pr(bcda);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  lea    D20(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  flds   0xf5e(%rip)        # 2038 <_fini+0xd8c>
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  mov    %dx,0x26(%rsp)
  mov    %ax,0x1c(%rsp)
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  movq   $0x99,0x14(%rsp)
  movq   $0x101,0x1e(%rsp)
  push   %rdx
  push   %rax
  xor    %eax,%eax
  call   <printf@plt>
  flds   0xf1a(%rip)        # 203c <_fini+0xd90>
  movsd  D4(%rip),%xmm1
  lea    D0(%rip),%rdi
  movsd  D5(%rip),%xmm0
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  movabs $0x9999999999999c00,%rcx
  fldl   0xeea(%rip)        # 2050 <_fini+0xda4>
  push   $0x3ffd
  lea    D40(%rip),%rdi
  push   %rcx
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  fldl   0xed2(%rip)        # 2058 <_fini+0xdac>
  push   %rdx
  push   %rax
  fstpt  0x20(%rsp)
  mov    0x28(%rsp),%edx
  mov    0x20(%rsp),%rax
  push   %rdx
  push   %rax
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x30,%rsp
  lea    0x14(%rsp),%rbp
  lea    0x1e(%rsp),%r12
  mov    %rbp,%rdi
  call   <pr@plt>
  mov    %r12,%rdi
  call   <pr@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <bcddemo@plt>
  mov    %rbp,%rdi
  call   <pr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D40
datatype: string

tool: D20: sizeof long double: %lu


tool: {"D4": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: D0: %g + %g = %g


tool: {"D5": [0x00,0x00,0x00,0xa0,0x99,0x99,0xc9,0x3f]}

tool: D40: %Lg + %Lg = %Lg


assistant: ```c
int main(void) {
  float a = 0.1;
  float b = 0.2;
  unsigned char bcda[10] = {
      9 << 4 | 9,
      0,
  };
  unsigned char bcdb[10] = {
      1,
      1,
      0,
  };
  long double aa = 0.1, bb = 0.2;
  printf("sizeof long double: %lu\n", sizeof aa);
  printf("%g + %g = %g\n", a, b, a + b);
  printf("%Lg + %Lg = %Lg\n", aa, bb, aa + bb);
  pr(bcda);
  pr(bcdb);
  bcddemo(bcda, bcdb);
  pr(bcda);
  return 0;
}
```