ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shr    $0x3,%rax
  shl    $0x5,%eax
  or     $0x56a0,%ax
  xor    $0x3ae0,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      state[0UL] <<= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      state[0UL] <<= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 736209367UL) << (unsigned short)5;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shr    $0x3,%rax
  shl    $0x5,%eax
  or     $0x56a0,%ax
  xor    $0x3ae0,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      state[0UL] <<= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      state[0UL] <<= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 736209367UL) << (unsigned short)5;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L10
L42:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  je     L58
  cmp    $0x2,%eax
  je     L4
  jmp    L10
L58:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x17(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x17(%rbp),%rax
  mov    %rax,%rdi
  call   <postfix@plt>
  jmp    L10
L4:
  movl   $0x3,-0x1c(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jle    L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D47
datatype: string
name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D59
datatype: string
name: read_data
arguments: label: D29
datatype: string
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D66
datatype: string

tool: D4: 
 MAIN MENU 


tool: D47: 1.ENTER EXPRESSION 


tool: D26: 2.EXIT 


tool: D59: ENTER YOUR CHOICE 


tool: D29: %d

tool: D7: ENTER THE EXPRESSION 


tool: D66: %s

assistant: ```c
int main() {
  char infix[15];
  int c = 0;
  while (c < 2) {
    printf("\n MAIN MENU \n");
    printf("1.ENTER EXPRESSION \n");
    printf("2.EXIT \n");
    printf("ENTER YOUR CHOICE \n");
    scanf("%d", &c);
    switch (c) {
    case 1:
      printf("ENTER THE EXPRESSION \n");
      scanf("%s", infix);
      postfix(infix);
      break;
    case 2:
      c = 3;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D8(%rip),%r13
  lea    D24(%rip),%r12
  lea    D54(%rip),%rbp
  jmp    L58
L56:
  lea    D60(%rip),%rdi
  call   <printf@plt>
  lea    0x9(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <postfix@plt>
L58:
  lea    D68(%rip),%rbx
L21:
  cmpl   $0x1,0x4(%rsp)
  jg     L52
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L56
  cmp    $0x2,%eax
  jne    L21
  movl   $0x3,0x4(%rsp)
  jmp    L58
L52:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D54
type: string
name: unpack_data
arguments: tag: D60
type: string
name: unpack_data
arguments: tag: D58
type: string
name: unpack_data
arguments: tag: D68
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D8: 
 MAIN MENU 


tool: D24: 1.ENTER EXPRESSION 


tool: D54: 2.EXIT 


tool: D60: ENTER THE EXPRESSION 


tool: D58: %s

tool: D68: ENTER YOUR CHOICE 


tool: D9: %d

assistant: ```c
int main() {
  char infix[15];
  int c = 0;
  while (c < 2) {
    printf("\n MAIN MENU \n");
    printf("1.ENTER EXPRESSION \n");
    printf("2.EXIT \n");
    printf("ENTER YOUR CHOICE \n");
    scanf("%d", &c);
    switch (c) {
    case 1:
      printf("ENTER THE EXPRESSION \n");
      scanf("%s", infix);
      postfix(infix);
      break;
    case 2:
      c = 3;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D48(%rip),%r13
  push   %r12
  lea    D30(%rip),%r12
  push   %rbp
  lea    D39(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  nopl   (%rax)
L26:
  lea    D76(%rip),%rbx
L15:
  cmp    $0x1,%eax
  jg     L29
L36:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L21
  cmp    $0x2,%eax
  jne    L15
  mov    $0x3,%eax
  movl   $0x3,0x4(%rsp)
  lea    D76(%rip),%rbx
  cmp    $0x1,%eax
  jle    L36
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L21:
  lea    D62(%rip),%rdi
  lea    0x9(%rsp),%r14
  call   <printf@plt>
  mov    %r14,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <postfix@plt>
  mov    0x4(%rsp),%eax
  jmp    L26
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D48
type_infered: string
name: extract_symbolic_data
arguments: label: D30
type_infered: string
name: extract_symbolic_data
arguments: label: D39
type_infered: string
name: extract_symbolic_data
arguments: label: D76
type_infered: string
name: extract_symbolic_data
arguments: label: D40
type_infered: string
name: extract_symbolic_data
arguments: label: D62
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D48: 
 MAIN MENU 


tool: D30: 1.ENTER EXPRESSION 


tool: D39: 2.EXIT 


tool: D76: ENTER YOUR CHOICE 


tool: D40: %d

tool: D62: ENTER THE EXPRESSION 


tool: D2: %s

assistant: ```c
int main() {
  char infix[15];
  int c = 0;
  while (c < 2) {
    printf("\n MAIN MENU \n");
    printf("1.ENTER EXPRESSION \n");
    printf("2.EXIT \n");
    printf("ENTER YOUR CHOICE \n");
    scanf("%d", &c);
    switch (c) {
    case 1:
      printf("ENTER THE EXPRESSION \n");
      scanf("%s", infix);
      postfix(infix);
      break;
    case 2:
      c = 3;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  lea    D44(%rip),%r12
  push   %rbp
  lea    D54(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  nopl   (%rax)
L18:
  lea    D34(%rip),%rbx
L28:
  cmp    $0x1,%eax
  jg     L23
L57:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L25
  cmp    $0x2,%eax
  jne    L28
  mov    $0x3,%eax
  movl   $0x3,0x4(%rsp)
  lea    D34(%rip),%rbx
  cmp    $0x1,%eax
  jle    L57
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L25:
  lea    D7(%rip),%rdi
  lea    0x9(%rsp),%r14
  call   <printf@plt>
  mov    %r14,%rsi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <postfix@plt>
  mov    0x4(%rsp),%eax
  jmp    L18
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D54
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string
name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D40
type_infered: string

tool: D22: 
 MAIN MENU 


tool: D44: 1.ENTER EXPRESSION 


tool: D54: 2.EXIT 


tool: D34: ENTER YOUR CHOICE 


tool: D16: %d

tool: D7: ENTER THE EXPRESSION 


tool: D40: %s

assistant: ```c
int main() {
  char infix[15];
  int c = 0;
  while (c < 2) {
    printf("\n MAIN MENU \n");
    printf("1.ENTER EXPRESSION \n");
    printf("2.EXIT \n");
    printf("ENTER YOUR CHOICE \n");
    scanf("%d", &c);
    switch (c) {
    case 1:
      printf("ENTER THE EXPRESSION \n");
      scanf("%s", infix);
      postfix(infix);
      break;
    case 2:
      c = 3;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solve_degree_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L62
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L62
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <solve_degree_1@plt>
  jmp    L67
L62:
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <zero@plt>
  test   %rax,%rax
  je     L12
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x20(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  (%rax),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x1,%eax
  jmp    L67
L12:
  movsd  -0x28(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L14
  mov    $0x0,%eax
  jmp    L67
L14:
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  subsd  -0x20(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x2,%eax
L67:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: f32[2]

tool: {"D3": [0.0,-0.0]}

assistant: ```c
int solve_degree_2(const double *c, double *x) {
  if (c[2] == 0)
    return solve_degree_1(c, x);
  double p = c[1] / (2.0 * c[2]);
  double q = c[0] / c[2];
  double D = p * p - q;
  if (zero(&D)) {
    x[0] = x[1] = -p;
    return 1;
  } else if (D < 0)
    return 0;
  else {
    double sqrt_D = sqrt(D);
    x[0] = -sqrt_D - p;
    x[1] = sqrt_D - p;
    return 2;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solve_degree_2>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsd  0x10(%rdi),%xmm0
  ucomisd D13(%rip),%xmm0
  jp     L46
  je     L76
L46:
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm2
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  movsd  (%rdi),%xmm2
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  call   <zero@plt>
  test   %rax,%rax
  jne    L71
  movsd  0x10(%rsp),%xmm0
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L59
  ucomisd %xmm0,%xmm1
  ja     L14
  sqrtsd %xmm0,%xmm0
L19:
  movapd %xmm0,%xmm1
  xorpd  D24(%rip),%xmm1
  movsd  0x8(%rsp),%xmm3
  subsd  %xmm3,%xmm1
  movsd  %xmm1,(%rbx)
  subsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rbx)
  mov    $0x2,%eax
  jmp    L59
L76:
  call   <solve_degree_1@plt>
L59:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L71:
  movsd  0x8(%rsp),%xmm0
  xorpd  D24(%rip),%xmm0
  movsd  %xmm0,0x8(%rbx)
  movsd  %xmm0,(%rbx)
  mov    $0x1,%eax
  jmp    L59
L14:
  call   <sqrt@plt>
  jmp    L19
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: f64
name: unpack_data
arguments: data_tag: D24
type: byte[16]

tool: D13: 0

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int solve_degree_2(const double *c, double *x) {
  if (c[2] == 0)
    return solve_degree_1(c, x);
  double p = c[1] / (2.0 * c[2]);
  double q = c[0] / c[2];
  double D = p * p - q;
  if (zero(&D)) {
    x[0] = x[1] = -p;
    return 1;
  } else if (D < 0)
    return 0;
  else {
    double sqrt_D = sqrt(D);
    x[0] = -sqrt_D - p;
    x[1] = sqrt_D - p;
    return 2;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solve_degree_2>:
  endbr64
  push   %rbp
  pxor   %xmm4,%xmm4
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  movsd  0x10(%rdi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  ucomisd %xmm4,%xmm0
  jp     L61
  je     L25
L61:
  movapd %xmm0,%xmm2
  movsd  0x8(%rdi),%xmm1
  movsd  (%rdi),%xmm3
  lea    0x10(%rsp),%rdi
  addsd  %xmm0,%xmm2
  divsd  %xmm0,%xmm3
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  movsd  %xmm2,0x10(%rsp)
  call   <zero@plt>
  movsd  0x8(%rsp),%xmm1
  test   %rax,%rax
  jne    L83
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm5,%xmm5
  xor    %eax,%eax
  comisd %xmm0,%xmm5
  jbe    L99
L46:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L71
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L83:
  xorpd  D17(%rip),%xmm1
  mov    $0x1,%eax
  movsd  %xmm1,0x8(%rbp)
  movsd  %xmm1,0x0(%rbp)
  jmp    L46
  nopl   0x0(%rax)
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x20,%rsp
  pop    %rbp
  jmp    1080 <solve_degree_1@plt>
  nopw   0x0(%rax,%rax,1)
L99:
  ucomisd %xmm0,%xmm5
  ja     L48
  sqrtsd %xmm0,%xmm0
L77:
  movapd %xmm0,%xmm2
  xorpd  D17(%rip),%xmm2
  subsd  %xmm1,%xmm0
  mov    $0x2,%eax
  subsd  %xmm1,%xmm2
  movsd  %xmm0,0x8(%rbp)
  movsd  %xmm2,0x0(%rbp)
  jmp    L46
L71:
  call   <__stack_chk_fail@plt>
L48:
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  jmp    L77
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: f32[4]

tool: {"D17": [0.0,-0.0,0.0,0.0]}

assistant: ```c
int solve_degree_2(const double *c, double *x) {
  if (c[2] == 0)
    return solve_degree_1(c, x);
  double p = c[1] / (2.0 * c[2]);
  double q = c[0] / c[2];
  double D = p * p - q;
  if (zero(&D)) {
    x[0] = x[1] = -p;
    return 1;
  } else if (D < 0)
    return 0;
  else {
    double sqrt_D = sqrt(D);
    x[0] = -sqrt_D - p;
    x[1] = sqrt_D - p;
    return 2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solve_degree_2>:
  endbr64
  push   %rbp
  pxor   %xmm5,%xmm5
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  movsd  0x10(%rdi),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  ucomisd %xmm5,%xmm1
  jp     L8
  je     L58
L8:
  movapd %xmm1,%xmm2
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm3
  lea    0x20(%rsp),%rdi
  addsd  %xmm1,%xmm2
  divsd  %xmm1,%xmm3
  divsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm4
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm2
  unpcklpd %xmm4,%xmm4
  movaps %xmm4,0x10(%rsp)
  subsd  %xmm3,%xmm2
  movsd  %xmm2,0x20(%rsp)
  call   <zero@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jne    L25
  movsd  0x20(%rsp),%xmm0
  pxor   %xmm6,%xmm6
  xor    %eax,%eax
  comisd %xmm0,%xmm6
  jbe    L3
L64:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L75
  add    $0x30,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L25:
  xorpd  D19(%rip),%xmm0
  mov    $0x1,%eax
  unpcklpd %xmm0,%xmm0
  movups %xmm0,0x0(%rbp)
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L58:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x30,%rsp
  pop    %rbp
  jmp    1080 <solve_degree_1@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  ucomisd %xmm0,%xmm6
  ja     L21
  sqrtsd %xmm0,%xmm0
L68:
  movapd %xmm0,%xmm1
  xorpd  D19(%rip),%xmm1
  mov    $0x2,%eax
  unpcklpd %xmm0,%xmm1
  subpd  0x10(%rsp),%xmm1
  movups %xmm1,0x0(%rbp)
  jmp    L64
L75:
  call   <__stack_chk_fail@plt>
L21:
  call   <sqrt@plt>
  jmp    L68
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: f32[4]

tool: {"D19": [0.0,-0.0,0.0,0.0]}

assistant: ```c
int solve_degree_2(const double *c, double *x) {
  if (c[2] == 0)
    return solve_degree_1(c, x);
  double p = c[1] / (2.0 * c[2]);
  double q = c[0] / c[2];
  double D = p * p - q;
  if (zero(&D)) {
    x[0] = x[1] = -p;
    return 1;
  } else if (D < 0)
    return 0;
  else {
    double sqrt_D = sqrt(D);
    x[0] = -sqrt_D - p;
    x[1] = sqrt_D - p;
    return 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<leds_ON_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7f008808,%eax
  mov    (%rax),%rax
  mov    $0x7f008808,%edx
  and    $0xffffffffffffffef,%rax
  mov    %rax,(%rdx)
  mov    $0x7f008808,%eax
  mov    (%rax),%rax
  mov    $0x7f008808,%edx
  and    $0xffffffffffffffdf,%rax
  mov    %rax,(%rdx)
  mov    $0x7f008808,%eax
  mov    (%rax),%rax
  mov    $0x7f008808,%edx
  and    $0xffffffffffffffbf,%rax
  mov    %rax,(%rdx)
  mov    $0x7f008808,%eax
  mov    (%rax),%rax
  mov    $0x7f008808,%edx
  and    $0x7f,%al
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void leds_ON_all(void) {
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 4));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 5));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 6));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 7));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<leds_ON_all>:
  endbr64
  mov    0x7f008808,%rax
  and    $0xffffffffffffffef,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0xffffffffffffffdf,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0xffffffffffffffbf,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0x7f,%al
  mov    %rax,0x7f008808
  ret
```

assistant: ```c
void leds_ON_all(void) {
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 4));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 5));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 6));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 7));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<leds_ON_all>:
  endbr64
  mov    0x7f008808,%rax
  and    $0xffffffffffffffef,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0xffffffffffffffdf,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0xffffffffffffffbf,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0x7f,%al
  mov    %rax,0x7f008808
  ret
```

assistant: ```c
void leds_ON_all(void) {
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 4));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 5));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 6));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 7));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<leds_ON_all>:
  endbr64
  mov    0x7f008808,%rax
  and    $0xffffffffffffffef,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0xffffffffffffffdf,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0xffffffffffffffbf,%rax
  mov    %rax,0x7f008808
  mov    0x7f008808,%rax
  and    $0x7f,%al
  mov    %rax,0x7f008808
  ret
```

assistant: ```c
void leds_ON_all(void) {
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 4));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 5));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 6));
  ((*(volatile unsigned long *)0x7F008808) &= ~(1 << 7));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dosys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,-0x14(%rbp)
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <metas@plt>
  test   %eax,%eax
  je     L3
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <doshell@plt>
  mov    %eax,%ebx
  jmp    L2
L3:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <doexec@plt>
  mov    %eax,%ebx
L2:
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int dosys(comstring, nohalt)
register char *comstring;
int nohalt;
{
  register int status;
  if (metas(comstring))
    status = doshell(comstring, nohalt);
  else
    status = doexec(comstring);
  return (status);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dosys>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <metas@plt>
  test   %eax,%eax
  je     L2
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <doshell@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <doexec@plt>
  jmp    L11
```

assistant: ```c
int dosys(comstring, nohalt)
register char *comstring;
int nohalt;
{
  register int status;
  if (metas(comstring))
    status = doshell(comstring, nohalt);
  else
    status = doexec(comstring);
  return (status);
}
```