user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D22(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x678,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x668(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L121
  lea    0x20(%rsp),%rax
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  lea    D59(%rip),%r14
  lea    D27(%rip),%r12
  xchg   %ax,%ax
L17:
  mov    0x8(%rsp),%rax
  xor    %r13d,%r13d
  lea    (%rax,%r15,4),%rbx
  nopl   0x0(%rax)
L108:
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  cmp    %r13d,%eax
  jg     L108
  add    $0x1,%ebp
  add    $0x14,%r15
  cmp    %ebp,%eax
  jg     L17
  test   %eax,%eax
  jle    L121
  mov    0x8(%rsp),%rbp
  xor    %r14d,%r14d
  lea    D39(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L1
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L87:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x1c(%rsp),%edx
  cmp    %ebx,%edx
  jg     L87
  add    $0x1,%r14d
  add    $0x50,%rbp
  cmp    %r14d,%edx
  jg     L47
  nop
L1:
  cmp    $0x1,%edx
  jle    L121
  lea    -0x1(%rdx),%r10d
  lea    -0x2(%rdx),%r11d
  mov    0x8(%rsp),%r8
  xor    %esi,%esi
  lea    (%r10,%r10,4),%rax
  lea    0x24(%rsp),%rdi
  shl    $0x4,%rax
  lea    (%rdi,%r11,4),%r9
  lea    0x70(%rsp,%rax,1),%rcx
  xchg   %ax,%ax
L166:
  mov    %r8,%rax
  test   %edx,%edx
  jle    L131
  nopw   0x0(%rax,%rax,1)
L152:
  add    (%rax),%esi
  add    $0x50,%rax
  cmp    %rcx,%rax
  jne    L152
L131:
  add    $0x4,%r8
  add    $0x4,%rcx
  cmp    %r9,%r8
  jne    L166
  mov    0x8(%rsp),%rbx
  lea    (%r11,%r11,4),%rcx
  lea    0x0(,%r10,4),%rax
  mov    $0xfffffffffffffffc,%r8
  lea    (%r10,%rcx,4),%rcx
  add    %rax,%rdi
  sub    %rax,%r8
  lea    0x54(%rbx,%rcx,4),%r9
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L102:
  lea    (%r8,%rdi,1),%rax
  test   %edx,%edx
  jle    L22
L101:
  add    (%rax),%ecx
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L101
L22:
  add    $0x50,%rdi
  cmp    %r9,%rdi
  jne    L102
  cmp    %ecx,%esi
  je     L121
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L130:
  mov    0x668(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x678,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L121:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L130
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D59
data_type: string
name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D39
data_type: string
name: disassemble_data
arguments: data_tag: D68
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string

tool: D22: enter number of rows=

tool: D13: %d

tool: D59: 
 enter number %d=

tool: D27: 	%d

tool: D39:    %d

tool: D68: 
 Invalid square

tool: D17: 
valid

assistant: ```c
int main() {
  int i = 0;
  int n[20][20];
  int check;
  int boss = 0;
  int choice = 0;
  int rows;
  int box = 0;
  int box2 = 0;
  int base = 0;
  int b = 0;
  printf("enter number of rows=");
  scanf("%d", &rows);
  for (i = 0; i < rows; i++) {
    for (choice = 0; choice < rows; choice++) {
      printf("\n enter number %d=", i);
      scanf("\t%d", &n[i][choice]);
    }
  }
  for (i = 0; i < rows; i++) {
    printf("\n");
    for (choice = 0; choice < rows; choice++) {
      printf("   %d", n[i][choice]);
    }
  }
  for (choice = 0; choice < rows - 1; choice++) {
    for (b = 0; b < rows; b++) {
      boss = boss + n[b][choice];
    }
  }
  for (b = 0; b < rows - 1; b++) {
    for (choice = 0; choice < rows; choice++) {
      box = box + n[b][choice];
    }
  }
  if (box == boss) {
    base = 2;
  } else {
    base = 1;
  }
  if (base == 2) {
    printf("\nvalid");
  } else
    printf("\n Invalid square");
  return 0;
}
```