ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rbp
L3:
  mov    %rsp,%rbx
L13:
  mov    %rbx,%rdi
  call   <readline@plt>
  test   %rax,%rax
  je     L24
  mov    %rbx,%rdi
  call   <rstrip@plt>
  mov    %rbx,%rdi
  call   <len@plt>
  cmp    $0x1,%eax
  jle    L13
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L3
L24:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %s

assistant: ```c
int main() {
  int length;
  char line[500];
  length = -1;
  while (readline(line) != 0) {
    rstrip(line);
    if (len(line) > 1)
      printf("%s", line);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L35
  nopl   0x0(%rax)
L32:
  mov    %rbx,%rdi
  call   <rstrip@plt>
  mov    %rbx,%rdi
  call   <len@plt>
  cmp    $0x1,%eax
  jg     L43
L35:
  mov    %rbx,%rdi
  call   <readline@plt>
  test   %rax,%rax
  jne    L32
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x208,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L43:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L35
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: %s

assistant: ```c
int main() {
  int length;
  char line[500];
  length = -1;
  while (readline(line) != 0) {
    rstrip(line);
    if (len(line) > 1)
      printf("%s", line);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L1
  nopl   0x0(%rax)
L39:
  mov    %rbx,%rdi
  call   <rstrip@plt>
  mov    %rbx,%rdi
  call   <len@plt>
  cmp    $0x1,%eax
  jg     L46
L1:
  mov    %rbx,%rdi
  call   <readline@plt>
  test   %rax,%rax
  jne    L39
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x208,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L46:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L1
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: %s

assistant: ```c
int main() {
  int length;
  char line[500];
  length = -1;
  while (readline(line) != 0) {
    rstrip(line);
    if (len(line) > 1)
      printf("%s", line);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<int_fatalx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <display_int_fatal@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void int_fatalx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_int_fatal(lineno, filename, fmt, args);
  va_end(args);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<int_fatalx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <display_int_fatal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void int_fatalx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_int_fatal(lineno, filename, fmt, args);
  va_end(args);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int_fatalx>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <display_int_fatal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void int_fatalx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_int_fatal(lineno, filename, fmt, args);
  va_end(args);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<int_fatalx>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <display_int_fatal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void int_fatalx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_int_fatal(lineno, filename, fmt, args);
  va_end(args);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
L4:
  mov    $0x0,%eax
  call   <RND@plt>
  mov    %eax,%edi
  call   <COLOR@plt>
  mov    $0x0,%eax
  call   <RND@plt>
  and    $0x1f,%eax
  lea    0x10(%rax),%r12d
  mov    $0x0,%eax
  call   <RND@plt>
  movzbl %al,%ebx
  mov    $0x0,%eax
  call   <RND@plt>
  movzbl %al,%eax
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <draw_circle@plt>
  jmp    L4
```

assistant: ```c
void main() {
  while (1) {
    COLOR(RND());
    draw_circle(RND() & 0xff, RND() & 0xff, (RND() & 0x1f) + 16);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L0:
  mov    $0x0,%eax
  call   <RND@plt>
  mov    %eax,%edi
  call   <COLOR@plt>
  mov    $0x0,%eax
  call   <RND@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <RND@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <RND@plt>
  and    $0x1f,%ebx
  lea    0x10(%rbx),%edx
  movzbl %bpl,%esi
  movzbl %al,%edi
  call   <draw_circle@plt>
  jmp    L0
```

assistant: ```c
void main() {
  while (1) {
    COLOR(RND());
    draw_circle(RND() & 0xff, RND() & 0xff, (RND() & 0x1f) + 16);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <RND@plt>
  mov    %eax,%edi
  call   <COLOR@plt>
  xor    %eax,%eax
  call   <RND@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <RND@plt>
  and    $0x1f,%ebx
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <RND@plt>
  lea    0x10(%rbx),%edx
  movzbl %bpl,%esi
  movzbl %al,%edi
  call   <draw_circle@plt>
  jmp    L8
```

assistant: ```c
void main() {
  while (1) {
    COLOR(RND());
    draw_circle(RND() & 0xff, RND() & 0xff, (RND() & 0x1f) + 16);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <RND@plt>
  mov    %eax,%edi
  call   <COLOR@plt>
  xor    %eax,%eax
  call   <RND@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <RND@plt>
  and    $0x1f,%ebx
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <RND@plt>
  lea    0x10(%rbx),%edx
  movzbl %bpl,%esi
  movzbl %al,%edi
  call   <draw_circle@plt>
  jmp    L8
```

assistant: ```c
void main() {
  while (1) {
    COLOR(RND());
    draw_circle(RND() & 0xff, RND() & 0xff, (RND() & 0x1f) + 16);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atof_nonlocalized>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  call   <atoi_nonlocalized@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movzbl (%rbx),%ecx
  cmp    $0x20,%cl
  jne    L142
  mov    $0x1,%eax
L120:
  mov    %eax,%edx
  add    $0x1,%rax
  movzbl -0x1(%rbx,%rax,1),%ecx
  cmp    $0x20,%cl
  je     L120
L37:
  lea    -0x2b(%rcx),%eax
  mov    $0x1,%ebp
  test   $0xfd,%al
  jne    L114
  cmp    $0x2d,%cl
  setne  %bpl
  movzbl %bpl,%ebp
  lea    -0x1(%rbp,%rbp,1),%ebp
  add    $0x1,%edx
L114:
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  je     L55
  mov    $0x0,%r12d
  mov    $0xffffffff,%eax
  jmp    L134
L142:
  mov    $0x0,%edx
  jmp    L37
L129:
  test   %eax,%eax
  js     L156
  cmp    $0x9,%sil
  ja     L126
  add    $0x1,%r12d
L75:
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  je     L126
L134:
  mov    %edx,%edi
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L129
  cmp    $0x2e,%cl
  je     L129
L126:
  pxor   %xmm0,%xmm0
  test   %r12d,%r12d
  jne    L54
L106:
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L156:
  cmp    $0x2e,%cl
  cmove  %edi,%eax
  jmp    L75
L54:
  cltq
  lea    0x1(%rbx,%rax,1),%rdi
  call   <atoi_nonlocalized@plt>
  imul   %ebp,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  sub    $0x1,%r12d
  mov    $0x1,%eax
L6:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    $0x1,%r12d
  cmp    $0xffffffff,%r12d
  jne    L6
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  jmp    L106
L55:
  pxor   %xmm0,%xmm0
  jmp    L106
```

assistant: ```c
double atof_nonlocalized(const char *str) {
  int i = 0, dot_pos = -1, decimals = 0, sign = 1;
  double value, value2 = 0.0;
  value = atoi_nonlocalized(str);
  while (str[i] == ' ') {
    i++;
  }
  if ((str[i] == '+') || (str[i] == '-')) {
    if (str[i] == '-') {
      sign = -1;
    }
    i++;
  }
  for (;; i++) {
    if (str[i] == 0) {
      break;
    }
    if (((str[i] < '0') || (str[i] > '9')) && (str[i] != '.')) {
      break;
    }
    if (dot_pos >= 0) {
      if ((str[i] >= '0') && (str[i] <= '9')) {
        decimals++;
      } else {
        break;
      }
    }
    if (str[i] == '.') {
      if (dot_pos < 0) {
        dot_pos = i;
      }
    }
  }
  if (decimals) {
    value2 = atoi_nonlocalized(str + dot_pos + 1) * sign;
    i = 1;
    while (decimals--) {
      i *= 10;
    }
    value2 /= i;
  }
  return (value + value2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<atof_nonlocalized>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  call   <atoi_nonlocalized@plt>
  movzbl (%rbx),%ecx
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  cmp    $0x20,%cl
  jne    L33
  mov    $0x1,%eax
  nopl   (%rax)
L113:
  mov    %eax,%edx
  add    $0x1,%rax
  movzbl -0x1(%rbx,%rax,1),%ecx
  cmp    $0x20,%cl
  je     L113
L83:
  lea    -0x2b(%rcx),%eax
  mov    $0x1,%r12d
  test   $0xfd,%al
  jne    L98
  xor    %r12d,%r12d
  cmp    $0x2d,%cl
  setne  %r12b
  add    $0x1,%edx
  lea    -0x1(%r12,%r12,1),%r12d
L98:
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  je     L126
  xor    %ebp,%ebp
  mov    $0xffffffffffffffff,%rsi
  jmp    L44
  nopl   0x0(%rax)
L23:
  cmp    $0x9,%r8b
  ja     L93
  add    $0x1,%rdx
  add    $0x1,%ebp
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  je     L93
L44:
  lea    -0x30(%rcx),%r8d
  movslq %edx,%rdi
  cmp    $0x9,%r8b
  jbe    L135
  cmp    $0x2e,%cl
  jne    L93
L135:
  cmp    $0xffffffff,%esi
  jne    L23
  cmp    $0x2e,%cl
  cmove  %rdi,%rsi
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L44
L93:
  pxor   %xmm0,%xmm0
  test   %ebp,%ebp
  jne    L144
L13:
  add    $0x10,%rsp
  addsd  %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L144:
  lea    0x1(%rbx,%rsi,1),%rdi
  movsd  %xmm1,0x8(%rsp)
  sub    $0x1,%ebp
  call   <atoi_nonlocalized@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  imul   %r12d,%eax
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L125:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    $0x1,%ebp
  jae    L125
  pxor   %xmm2,%xmm2
  add    $0x10,%rsp
  cvtsi2sd %eax,%xmm2
  pop    %rbx
  pop    %rbp
  pop    %r12
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  xor    %edx,%edx
  jmp    L83
L126:
  pxor   %xmm0,%xmm0
  jmp    L13
```

assistant: ```c
double atof_nonlocalized(const char *str) {
  int i = 0, dot_pos = -1, decimals = 0, sign = 1;
  double value, value2 = 0.0;
  value = atoi_nonlocalized(str);
  while (str[i] == ' ') {
    i++;
  }
  if ((str[i] == '+') || (str[i] == '-')) {
    if (str[i] == '-') {
      sign = -1;
    }
    i++;
  }
  for (;; i++) {
    if (str[i] == 0) {
      break;
    }
    if (((str[i] < '0') || (str[i] > '9')) && (str[i] != '.')) {
      break;
    }
    if (dot_pos >= 0) {
      if ((str[i] >= '0') && (str[i] <= '9')) {
        decimals++;
      } else {
        break;
      }
    }
    if (str[i] == '.') {
      if (dot_pos < 0) {
        dot_pos = i;
      }
    }
  }
  if (decimals) {
    value2 = atoi_nonlocalized(str + dot_pos + 1) * sign;
    i = 1;
    while (decimals--) {
      i *= 10;
    }
    value2 /= i;
  }
  return (value + value2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Vector_Add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x2,-0x4(%rbp)
  jle    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Vector_Add(float vectorOut[3], float vectorIn1[3], float vectorIn2[3]) {
  int c = 0;
  while (c < 3) {
    vectorOut[c] = vectorIn1[c] + vectorIn2[c];
    c++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Vector_Add>:
  endbr64
  mov    $0x0,%eax
L8:
  movss  (%rsi,%rax,1),%xmm0
  addss  (%rdx,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L8
  ret
```

assistant: ```c
void Vector_Add(float vectorOut[3], float vectorIn1[3], float vectorIn2[3]) {
  int c = 0;
  while (c < 3) {
    vectorOut[c] = vectorIn1[c] + vectorIn2[c];
    c++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<Vector_Add>:
  endbr64
  xor    %eax,%eax
L8:
  movss  (%rsi,%rax,1),%xmm0
  addss  (%rdx,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L8
  ret
```

assistant: ```c
void Vector_Add(float vectorOut[3], float vectorIn1[3], float vectorIn2[3]) {
  int c = 0;
  while (c < 3) {
    vectorOut[c] = vectorIn1[c] + vectorIn2[c];
    c++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Vector_Add>:
  endbr64
  lea    0x4(%rdx),%rcx
  mov    %rdi,%rax
  cmp    %rcx,%rdi
  je     L2
  lea    0x4(%rsi),%rcx
  cmp    %rcx,%rdi
  je     L2
  movq   (%rsi),%xmm0
  movq   (%rdx),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rax)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rax)
  ret
```

assistant: ```c
void Vector_Add(float vectorOut[3], float vectorIn1[3], float vectorIn2[3]) {
  int c = 0;
  while (c < 3) {
    vectorOut[c] = vectorIn1[c] + vectorIn2[c];
    c++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<convtile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L45:
  movl   $0x0,-0xc(%rbp)
  jmp    L56
L28:
  movl   $0x0,-0x8(%rbp)
  jmp    L72
L34:
  cmpl   $0x0,-0x2c(%rbp)
  je     L62
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  imul   -0x28(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x10(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rsi
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edi
  mov    -0x8(%rbp),%eax
  add    %edi,%eax
  imul   -0x24(%rbp),%eax
  cltq
  add    %rsi,%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L60
L62:
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  add    %esi,%eax
  imul   -0x24(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  add    %esi,%eax
  imul   -0x28(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  add    %rsi,%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L60:
  addl   $0x1,-0x8(%rbp)
L72:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L34
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L28
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L45
  nop
  nop
  leave
  ret
```

assistant: ```c
void convtile(double *A, double *B, int n, int bs, int tofrom) {
  int i, j, ii, jj, i2, j2, nb = n / bs;
  for (i = 0; i < nb; i++) {
    for (j = 0; j < nb; j++) {
      for (jj = 0; jj < bs; jj++) {
        if (tofrom)
          memcpy(B + i * bs + (j * bs + jj) * n, A + (i + j * nb) * bs * bs + jj * bs, bs * sizeof(double));
        else
          memcpy(B + (i + j * nb) * bs * bs + jj * bs, A + i * bs + (j * bs + jj) * n, bs * sizeof(double));
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convtile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edx,%ebx
  mov    %r8d,0x24(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %edx,%eax
  cltd
  idiv   %ecx
  mov    %eax,0x34(%rsp)
  test   %eax,%eax
  jle    L60
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %ecx,%r15d
  lea    0x0(,%rcx,8),%ecx
  mov    %ecx,0x1c(%rsp)
  mov    %r15d,%ecx
  imul   %r15d,%ecx
  mov    %ecx,0x4c(%rsp)
  mov    %ebx,%edx
  imul   %r15d,%edx
  mov    %edx,0x38(%rsp)
  imul   %ecx,%eax
  mov    %eax,0x3c(%rsp)
  movl   $0x0,0x48(%rsp)
  movl   $0x0,0x44(%rsp)
  movl   $0x0,0x40(%rsp)
  jmp    L10
L46:
  movslq %r12d,%rax
  add    0x10(%rsp),%rax
  lea    (%r14,%rax,8),%rsi
  movslq %ebp,%rax
  add    0x8(%rsp),%rax
  lea    0x0(%r13,%rax,8),%rdi
  mov    0x1c(%rsp),%edx
  call   <memcpy@plt>
L67:
  add    $0x1,%ebx
  add    %r15d,%ebp
  add    0x20(%rsp),%r12d
  cmp    %ebx,%r15d
  je     L8
L55:
  cmpl   $0x0,0x24(%rsp)
  je     L46
  movslq %ebp,%rax
  add    0x8(%rsp),%rax
  lea    (%r14,%rax,8),%rsi
  movslq %r12d,%rax
  add    0x10(%rsp),%rax
  lea    0x0(%r13,%rax,8),%rdi
  mov    0x1c(%rsp),%edx
  call   <memcpy@plt>
  jmp    L67
L8:
  addl   $0x1,0x28(%rsp)
  mov    0x28(%rsp),%eax
  mov    0x38(%rsp),%edx
  add    %edx,0x2c(%rsp)
  mov    0x3c(%rsp),%edx
  add    %edx,0x30(%rsp)
  cmp    %eax,0x34(%rsp)
  je     L20
L76:
  test   %r15d,%r15d
  jle    L8
  movslq 0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x2c(%rsp),%r12d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L55
L20:
  addl   $0x1,0x40(%rsp)
  mov    0x40(%rsp),%eax
  add    %r15d,0x44(%rsp)
  mov    0x4c(%rsp),%edx
  add    %edx,0x48(%rsp)
  cmp    %eax,0x34(%rsp)
  je     L60
L10:
  movslq 0x44(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    0x48(%rsp),%eax
  mov    %eax,0x30(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x28(%rsp)
  jmp    L76
L60:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convtile(double *A, double *B, int n, int bs, int tofrom) {
  int i, j, ii, jj, i2, j2, nb = n / bs;
  for (i = 0; i < nb; i++) {
    for (j = 0; j < nb; j++) {
      for (jj = 0; jj < bs; jj++) {
        if (tofrom)
          memcpy(B + i * bs + (j * bs + jj) * n, A + (i + j * nb) * bs * bs + jj * bs, bs * sizeof(double));
        else
          memcpy(B + (i + j * nb) * bs * bs + jj * bs, A + i * bs + (j * bs + jj) * n, bs * sizeof(double));
      }
    }
  }
}
```