ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D44(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L21
L23:
  mov    -0x14(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0xc(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  movss  -0xc(%rbp),%xmm1
  movss  D44(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L23
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D44
type_infered: f32
name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D29
type_infered: string
name: read_data
arguments: data_label: D42
type_infered: string

tool: D44: 1

tool: D5: Digite um numero inteiro:

tool: D29: %d

tool: D42: O valor da soma eh %.2f.


assistant: ```c
int main(void) {
  int n;
  float soma = 0, cont = 1;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &n);
  while (n > 0) {
    soma = soma + (cont / n);
    n--;
    cont++;
  }
  printf("O valor da soma eh %.2f.\n", soma);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  movss  D37(%rip),%xmm1
  pxor   %xmm0,%xmm0
  movaps %xmm1,%xmm4
L3:
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm3
  movaps %xmm1,%xmm2
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  addss  %xmm4,%xmm1
  sub    $0x1,%eax
  jne    L3
  movl   $0x0,0x4(%rsp)
L13:
  cvtss2sd %xmm0,%xmm0
  lea    D35(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L30:
  pxor   %xmm0,%xmm0
  jmp    L13
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D38
data_type: string
name: extract_symbolic_data
arguments: tag: D37
data_type: f32
name: extract_symbolic_data
arguments: tag: D35
data_type: string

tool: D5: Digite um numero inteiro:

tool: D38: %d

tool: D37: 1

tool: D35: O valor da soma eh %.2f.


assistant: ```c
int main(void) {
  int n;
  float soma = 0, cont = 1;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &n);
  while (n > 0) {
    soma = soma + (cont / n);
    n--;
    cont++;
  }
  printf("O valor da soma eh %.2f.\n", soma);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L23
  movss  D6(%rip),%xmm4
  pxor   %xmm0,%xmm0
  movaps %xmm4,%xmm1
  nopl   0x0(%rax)
L9:
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  addss  %xmm4,%xmm1
  cvtsi2ss %eax,%xmm3
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L9
  movl   $0x0,0x4(%rsp)
L30:
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  pxor   %xmm0,%xmm0
  jmp    L30
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: f32
name: retrieve_data
arguments: tag: D26
datatype: string

tool: D2: Digite um numero inteiro:

tool: D11: %d

tool: D6: 1

tool: D26: O valor da soma eh %.2f.


assistant: ```c
int main(void) {
  int n;
  float soma = 0, cont = 1;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &n);
  while (n > 0) {
    soma = soma + (cont / n);
    n--;
    cont++;
  }
  printf("O valor da soma eh %.2f.\n", soma);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L12
  movss  D27(%rip),%xmm4
  pxor   %xmm0,%xmm0
  movaps %xmm4,%xmm1
  nopl   0x0(%rax)
L25:
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  addss  %xmm4,%xmm1
  cvtsi2ss %eax,%xmm3
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L25
  movl   $0x0,0x4(%rsp)
L5:
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  pxor   %xmm0,%xmm0
  jmp    L5
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: f32
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D25: Digite um numero inteiro:

tool: D3: %d

tool: D27: 1

tool: D2: O valor da soma eh %.2f.


assistant: ```c
int main(void) {
  int n;
  float soma = 0, cont = 1;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &n);
  while (n > 0) {
    soma = soma + (cont / n);
    n--;
    cont++;
  }
  printf("O valor da soma eh %.2f.\n", soma);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fill_cost_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rcx),%r10d
  mov    %r10d,%eax
  imul   %r9d,%eax
  lea    (%rax,%r8,1),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  add    %eax,%r9d
  lea    -0x1(%r8),%r11d
  lea    (%r9,%r11,1),%eax
  cltq
  cmp    (%rdi,%rax,4),%esi
  jge    L17
  add    %r8d,%r9d
  movslq %r9d,%rbx
  add    (%rdx,%rbx,4),%esi
  mov    %esi,(%rdi,%rbx,4)
  mov    %rsp,%r12
  mov    %r10d,%ecx
  lea    D13(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  add    %r8d,%r9d
  movslq %r9d,%rbx
  mov    (%rdx,%rbx,4),%eax
  add    -0x4(%rdi,%rbx,4),%eax
  mov    %eax,(%rdi,%rbx,4)
  mov    %rsp,%r12
  mov    %r11d,%r8d
  lea    D13(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  jmp    L8
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D13: %d, %d

assistant: ```c
void fill_cost_path(int *cost_matrix, char **path_matrix, int *questionMatrix, int i, int j, int size) {
  char path[32];
  if (cost_matrix[(i - 1) * size + j] < cost_matrix[i * size + (j - 1)]) {
    cost_matrix[i * size + j] = cost_matrix[(i - 1) * size + j] + questionMatrix[i * size + j];
    snprintf(path, 32, "%d, %d", i - 1, j);
    path_matrix[i * size + j] = strdup(path);
  } else {
    cost_matrix[i * size + j] = cost_matrix[(i)*size + j - 1] + questionMatrix[i * size + j];
    snprintf(path, 32, "%d, %d", i, j - 1);
    path_matrix[i * size + j] = strdup(path);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fill_cost_path>:
  endbr64
  push   %r13
  lea    -0x1(%rcx),%r10d
  push   %r12
  push   %rbp
  lea    -0x1(%r8),%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r10d,%eax
  imul   %r9d,%eax
  add    %eax,%r9d
  lea    (%rax,%r8,1),%r11d
  lea    (%r9,%r8,1),%eax
  add    %ebp,%r9d
  movslq %r11d,%r11
  cltq
  movslq %r9d,%r9
  mov    (%rdi,%r11,4),%r11d
  lea    0x0(,%rax,4),%r12
  mov    (%rdx,%rax,4),%r13d
  lea    (%rsi,%rax,8),%rbx
  lea    (%rdi,%r12,1),%rdx
  cmp    (%rdi,%r9,4),%r11d
  jge    L17
  add    %r13d,%r11d
  mov    %rsp,%rbp
  mov    %r10d,%ecx
  mov    $0x20,%esi
  mov    %r11d,(%rdx)
  mov    %rbp,%rdi
  lea    D3(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
L28:
  mov    %rax,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L17:
  add    -0x4(%rdi,%r12,1),%r13d
  mov    %rsp,%r12
  mov    %ebp,%r8d
  mov    $0x20,%esi
  mov    %r13d,(%rdx)
  mov    %r12,%rdi
  lea    D3(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  jmp    L28
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d, %d

assistant: ```c
void fill_cost_path(int *cost_matrix, char **path_matrix, int *questionMatrix, int i, int j, int size) {
  char path[32];
  if (cost_matrix[(i - 1) * size + j] < cost_matrix[i * size + (j - 1)]) {
    cost_matrix[i * size + j] = cost_matrix[(i - 1) * size + j] + questionMatrix[i * size + j];
    snprintf(path, 32, "%d, %d", i - 1, j);
    path_matrix[i * size + j] = strdup(path);
  } else {
    cost_matrix[i * size + j] = cost_matrix[(i)*size + j - 1] + questionMatrix[i * size + j];
    snprintf(path, 32, "%d, %d", i, j - 1);
    path_matrix[i * size + j] = strdup(path);
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fill_cost_path>:
  endbr64
  push   %r13
  lea    -0x1(%rcx),%r10d
  push   %r12
  push   %rbp
  lea    -0x1(%r8),%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r10d,%eax
  imul   %r9d,%eax
  add    %eax,%r9d
  lea    (%rax,%r8,1),%r11d
  lea    (%r9,%r8,1),%eax
  add    %ebp,%r9d
  movslq %r11d,%r11
  cltq
  movslq %r9d,%r9
  mov    (%rdi,%r11,4),%r11d
  lea    0x0(,%rax,4),%r12
  mov    (%rdx,%rax,4),%r13d
  lea    (%rsi,%rax,8),%rbx
  lea    (%rdi,%r12,1),%rdx
  cmp    (%rdi,%r9,4),%r11d
  jge    L22
  add    %r13d,%r11d
  mov    %rsp,%rbp
  mov    %r10d,%ecx
  mov    $0x20,%esi
  mov    %r11d,(%rdx)
  mov    %rbp,%rdi
  lea    D17(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
L25:
  mov    %rax,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  add    -0x4(%rdi,%r12,1),%r13d
  mov    %rsp,%r12
  mov    %ebp,%r8d
  mov    $0x20,%esi
  mov    %r13d,(%rdx)
  mov    %r12,%rdi
  lea    D17(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  jmp    L25
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D17: %d, %d

assistant: ```c
void fill_cost_path(int *cost_matrix, char **path_matrix, int *questionMatrix, int i, int j, int size) {
  char path[32];
  if (cost_matrix[(i - 1) * size + j] < cost_matrix[i * size + (j - 1)]) {
    cost_matrix[i * size + j] = cost_matrix[(i - 1) * size + j] + questionMatrix[i * size + j];
    snprintf(path, 32, "%d, %d", i - 1, j);
    path_matrix[i * size + j] = strdup(path);
  } else {
    cost_matrix[i * size + j] = cost_matrix[(i)*size + j - 1] + questionMatrix[i * size + j];
    snprintf(path, 32, "%d, %d", i, j - 1);
    path_matrix[i * size + j] = strdup(path);
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<permut_indiv_among_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <ivector@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L29:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L29
  mov    -0x30(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <resample_shuffle@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L21:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L21
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <free_ivector@plt>
  nop
  leave
  ret
```

assistant: ```c
void permut_indiv_among_pop(int n, int *popi, int Npop, int *popimix, long *seed) {
  int i;
  int *ind;
  ind = ivector(0, n);
  for (i = 1; i <= n; i++)
    ind[i] = i;
  resample_shuffle(ind, 1, n, seed);
  for (i = 1; i <= n; i++)
    popimix[i] = popi[ind[i]];
  free_ivector(ind, 0, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permut_indiv_among_pop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r12
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %edi,%esi
  mov    $0x0,%edi
  call   <ivector@plt>
  mov    %rax,%rbx
  test   %r14d,%r14d
  jle    L32
  lea    0x1(%r14),%ebp
  mov    $0x1,%eax
L6:
  mov    %eax,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L6
  mov    %r15,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <resample_shuffle@plt>
  mov    $0x1,%eax
L10:
  movslq (%rbx,%rax,4),%rdx
  mov    (%r12,%rdx,4),%edx
  mov    %edx,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L10
L30:
  mov    %r14d,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <free_ivector@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    %r15,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <resample_shuffle@plt>
  jmp    L30
```

assistant: ```c
void permut_indiv_among_pop(int n, int *popi, int Npop, int *popimix, long *seed) {
  int i;
  int *ind;
  ind = ivector(0, n);
  for (i = 1; i <= n; i++)
    ind[i] = i;
  resample_shuffle(ind, 1, n, seed);
  for (i = 1; i <= n; i++)
    popimix[i] = popi[ind[i]];
  free_ivector(ind, 0, n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<permut_indiv_among_pop>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%esi
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ivector@plt>
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L29
  lea    0x1(%r14),%ebx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L12
  mov    %r15,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <resample_shuffle@plt>
  mov    $0x1,%eax
  nopl   (%rax)
L27:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    (%r12,%rdx,4),%edx
  mov    %edx,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L27
L10:
  add    $0x8,%rsp
  mov    %r14d,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free_ivector@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r15,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <resample_shuffle@plt>
  jmp    L10
```

assistant: ```c
void permut_indiv_among_pop(int n, int *popi, int Npop, int *popimix, long *seed) {
  int i;
  int *ind;
  ind = ivector(0, n);
  for (i = 1; i <= n; i++)
    ind[i] = i;
  resample_shuffle(ind, 1, n, seed);
  for (i = 1; i <= n; i++)
    popimix[i] = popi[ind[i]];
  free_ivector(ind, 0, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<permut_indiv_among_pop>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  xor    %edi,%edi
  call   <ivector@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L77
  lea    -0x1(%r12),%eax
  cmp    $0x2,%eax
  jbe    L46
  mov    %r12d,%edx
  movdqa D1(%rip),%xmm0
  movdqa D9(%rip),%xmm2
  lea    0x4(%rbp),%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%rbp,%rdx,1),%rdx
  nopl   0x0(%rax)
L61:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L61
  mov    %r12d,%edx
  and    $0xfffffffc,%edx
  lea    0x1(%rdx),%eax
  cmp    %r12d,%edx
  je     L60
L53:
  movslq %eax,%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jl     L60
  add    $0x2,%eax
  mov    %edx,0x4(%rbp,%rcx,1)
  cmp    %eax,%r12d
  jl     L60
  mov    %eax,0x8(%rbp,%rcx,1)
L60:
  mov    %r14,%rcx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <resample_shuffle@plt>
  lea    0x1(%r12),%ecx
  mov    $0x1,%eax
  nop
L12:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    (%rbx,%rdx,4),%edx
  mov    %edx,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L12
L9:
  pop    %rbx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free_ivector@plt>
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %r14,%rcx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <resample_shuffle@plt>
  jmp    L9
L46:
  mov    $0x1,%eax
  jmp    L53
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: byte[16]
name: unpack_data
arguments: data_tag: D9
data_type: byte[16]

tool: {"D1": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D9": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void permut_indiv_among_pop(int n, int *popi, int Npop, int *popimix, long *seed) {
  int i;
  int *ind;
  ind = ivector(0, n);
  for (i = 1; i <= n; i++)
    ind[i] = i;
  resample_shuffle(ind, 1, n, seed);
  for (i = 1; i <= n; i++)
    popimix[i] = popi[ind[i]];
  free_ivector(ind, 0, n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum_nostf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x5c(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x5c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x5c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L2
L11:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x58(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x58(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x58(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x34(%rbp)
L2:
  mov    -0x34(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sum_nostf(float *s, float *u, float *slip, int nt) {
  float *sv, *sn, *se, *uv, *un, *ue;
  int it;
  sv = s;
  sn = s + nt;
  se = s + 2 * nt;
  uv = u;
  un = u + nt;
  ue = u + 2 * nt;
  for (it = 0; it < nt; it++) {
    sv[it] = sv[it] + (*slip) * uv[it];
    sn[it] = sn[it] + (*slip) * un[it];
    se[it] = se[it] + (*slip) * ue[it];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum_nostf>:
  endbr64
  mov    %rdi,%r11
  movslq %ecx,%r10
  lea    0x0(,%r10,4),%rdi
  lea    (%rcx,%rcx,1),%r9d
  movslq %r9d,%r9
  lea    0x0(,%r9,4),%r8
  test   %ecx,%ecx
  jle    L2
  mov    %r11,%rax
  lea    -0x1(%rcx),%ecx
  lea    0x4(%r11,%rcx,4),%rcx
L5:
  movss  (%rdx),%xmm0
  mulss  (%rsi),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  movss  (%rdx),%xmm0
  mulss  (%rsi,%r10,4),%xmm0
  addss  (%rax,%rdi,1),%xmm0
  movss  %xmm0,(%rax,%rdi,1)
  movss  (%rdx),%xmm0
  mulss  (%rsi,%r9,4),%xmm0
  addss  (%rax,%r8,1),%xmm0
  movss  %xmm0,(%rax,%r8,1)
  add    $0x4,%rax
  add    $0x4,%rsi
  cmp    %rcx,%rax
  jne    L5
L2:
  ret
```

assistant: ```c
void sum_nostf(float *s, float *u, float *slip, int nt) {
  float *sv, *sn, *se, *uv, *un, *ue;
  int it;
  sv = s;
  sn = s + nt;
  se = s + 2 * nt;
  uv = u;
  un = u + nt;
  ue = u + 2 * nt;
  for (it = 0; it < nt; it++) {
    sv[it] = sv[it] + (*slip) * uv[it];
    sn[it] = sn[it] + (*slip) * un[it];
    se[it] = se[it] + (*slip) * ue[it];
  }
}
```