ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lltoa>:
  endbr64
  lea    -0x2(%rdx),%ecx
  mov    %rdi,%rax
  mov    %rsi,%r9
  cmp    $0x22,%ecx
  jbe    L10
  cmp    $0xfffffff6,%edx
  je     L63
  movb   $0x0,(%rsi)
L29:
  mov    %r9,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  mov    $0xa,%edi
  xor    %r10d,%r10d
  test   %rax,%rax
  js     L73
L30:
  mov    %r9,%rsi
  lea    D1(%rip),%r8
  nop
L81:
  cqto
  mov    %rsi,%rcx
  add    $0x1,%rsi
  idiv   %rdi
  movzbl 0x23(%r8,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %rax,%rax
  jne    L81
  test   %r10d,%r10d
  je     L79
  lea    0x2(%rcx),%rax
  movb   $0x2d,(%rsi)
  mov    %rsi,%rcx
  mov    %rax,%rsi
L79:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  cmp    %rcx,%r9
  jae    L29
  nopw   0x0(%rax,%rax,1)
L58:
  movzbl (%rcx),%edx
  movzbl (%rax),%esi
  sub    $0x1,%rcx
  add    $0x1,%rax
  mov    %sil,0x1(%rcx)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  ja     L58
  mov    %r9,%rax
  ret
  xchg   %ax,%ax
L10:
  cmp    $0xfffffff6,%edx
  je     L63
  movslq %edx,%rdi
  xor    %r10d,%r10d
  jmp    L30
  nopl   (%rax)
L73:
  neg    %rax
  mov    $0x1,%r10d
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *lltoa(long long value, char *result, int base) {
  if ((base < 2 || base > 36) && base != -10) {
    *result = '\0';
    return result;
  }
  char *pointer = result, *aux_pointer = result, tmp_char;
  long long tmp_value;
  bool negative = false;
  if (base == -10) {
    base = 10;
    if (value & (1LL << 63)) {
      value = (~value) + 1;
      negative = true;
    }
  }
  do {
    tmp_value = value;
    value /= base;
    *pointer++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (negative)
    *pointer++ = '-';
  *pointer-- = '\0';
  while (aux_pointer < pointer) {
    tmp_char = *pointer;
    *pointer-- = *aux_pointer;
    *aux_pointer++ = tmp_char;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_hzdptr_setv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  lock orq $0x0,(%rsp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L8
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *_hzdptr_setv(void volatile *ptr_, void *hzd_) {
  void *volatile *ptr = (void *volatile *)ptr_;
  void *volatile *hzd = (void *volatile *)hzd_;
  void *val = *ptr;
  void *tmp;
  do {
    *hzd = val;
    tmp = val;
    __sync_synchronize();
    val = *ptr;
  } while (val != tmp);
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_hzdptr_setv>:
  endbr64
  mov    (%rdi),%rax
L6:
  mov    %rax,(%rsi)
  lock orq $0x0,(%rsp)
  mov    %rax,%rdx
  mov    (%rdi),%rax
  cmp    %rax,%rdx
  jne    L6
  ret
```

assistant: ```c
void *_hzdptr_setv(void volatile *ptr_, void *hzd_) {
  void *volatile *ptr = (void *volatile *)ptr_;
  void *volatile *hzd = (void *volatile *)hzd_;
  void *val = *ptr;
  void *tmp;
  do {
    *hzd = val;
    tmp = val;
    __sync_synchronize();
    val = *ptr;
  } while (val != tmp);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_hzdptr_setv>:
  endbr64
  mov    (%rdi),%rax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rax,(%rsi)
  mov    %rax,%rdx
  lock orq $0x0,(%rsp)
  mov    (%rdi),%rax
  cmp    %rax,%rdx
  jne    L8
  ret
```

assistant: ```c
void *_hzdptr_setv(void volatile *ptr_, void *hzd_) {
  void *volatile *ptr = (void *volatile *)ptr_;
  void *volatile *hzd = (void *volatile *)hzd_;
  void *val = *ptr;
  void *tmp;
  do {
    *hzd = val;
    tmp = val;
    __sync_synchronize();
    val = *ptr;
  } while (val != tmp);
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_hzdptr_setv>:
  endbr64
  mov    (%rdi),%rax
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rax,(%rsi)
  mov    %rax,%rdx
  lock orq $0x0,(%rsp)
  mov    (%rdi),%rax
  cmp    %rax,%rdx
  jne    L1
  ret
```

assistant: ```c
void *_hzdptr_setv(void volatile *ptr_, void *hzd_) {
  void *volatile *ptr = (void *volatile *)ptr_;
  void *volatile *hzd = (void *volatile *)hzd_;
  void *val = *ptr;
  void *tmp;
  do {
    *hzd = val;
    tmp = val;
    __sync_synchronize();
    val = *ptr;
  } while (val != tmp);
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<splitspeci>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %edx,%edi
  mov    %ecx,%r13d
  mov    0x28(%rsp),%rbp
  mov    0x30(%rsp),%rbx
  mov    0x38(%rsp),%esi
  mov    0x48(%rsp),%ecx
  test   %ecx,%ecx
  jle    L95
  mov    %ecx,%edx
  mov    $0x0,%eax
L87:
  movl   $0x0,(%r8,%rax,4)
  movl   $0x0,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L87
  cmp    0x40(%rsp),%esi
  jge    L71
L89:
  add    %r13d,%esi
  add    0x40(%rsp),%r13d
L76:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  movslq %edx,%r12
  mov    %edi,%eax
  add    (%r10,%r12,4),%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movss  0x0(%rbp,%rdx,4),%xmm2
  movss  %xmm2,(%r8,%rdx,4)
  mov    %edi,%eax
  add    (%r11,%r12,4),%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movss  0x0(%rbp,%rdx,4),%xmm2
  movss  %xmm2,(%r9,%rdx,4)
  add    $0x1,%esi
  cmp    %r13d,%esi
  jne    L76
  test   %ecx,%ecx
  jle    L13
L71:
  mov    %ecx,%ecx
  mov    $0x0,%eax
  pxor   %xmm4,%xmm4
  movaps %xmm4,%xmm5
  movaps %xmm4,%xmm6
  movaps %xmm4,%xmm7
  jmp    L32
L100:
  movaps %xmm0,%xmm3
  mulss  (%r9,%rax,4),%xmm3
  mulss  %xmm1,%xmm2
  addss  %xmm2,%xmm3
  movss  %xmm3,(%rbx,%rax,4)
L80:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L13
L32:
  movss  (%r8,%rax,4),%xmm2
  ucomiss %xmm4,%xmm2
  jp     L100
  ucomiss %xmm5,%xmm2
  jne    L100
  ucomiss (%r9,%rax,4),%xmm6
  jp     L100
  ucomiss (%r9,%rax,4),%xmm7
  jne    L100
  movl   $0x0,(%rbx,%rax,4)
  jmp    L80
L95:
  cmp    0x40(%rsp),%esi
  jl     L89
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void splitspeci(int *current_binsplit, int *last_binsplit, int bin_offset, int table_offset, float *current_mag, float *last_mag, float *inmag, float *dest_mag, int start, int end, int n, float oldfrac, float newfrac) {
  int i;
  int bindex;
  for (i = 0; i < n; i++) {
    last_mag[i] = current_mag[i] = 0.0;
  }
  for (i = start; i < end; i++) {
    bindex = current_binsplit[(i + table_offset) % n];
    bindex = (bindex + bin_offset) % n;
    current_mag[bindex] = inmag[bindex];
    bindex = last_binsplit[(i + table_offset) % n];
    bindex = (bindex + bin_offset) % n;
    last_mag[bindex] = inmag[bindex];
  }
  for (i = 0; i < n; i++) {
    if (!current_mag[i] && !last_mag[i]) {
      dest_mag[i] = 0.0;
    } else {
      dest_mag[i] = oldfrac * last_mag[i] + newfrac * current_mag[i];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  and    $0x3ff,%eax
  mov    %eax,-0x4(%rbp)
  movzwl -0x14(%rbp),%eax
  and    $0x400,%eax
  test   %eax,%eax
  je     L7
  shll   $0x6,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int xbits(unsigned short x) {
  int bt = x & 0x3ff;
  if (x & (1 << 10))
    bt = bt << 6;
  return bt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xbits>:
  endbr64
  mov    %edi,%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  shl    $0x6,%edx
  test   $0x400,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int xbits(unsigned short x) {
  int bt = x & 0x3ff;
  if (x & (1 << 10))
    bt = bt << 6;
  return bt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xbits>:
  endbr64
  mov    %edi,%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  shl    $0x6,%edx
  and    $0x400,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int xbits(unsigned short x) {
  int bt = x & 0x3ff;
  if (x & (1 << 10))
    bt = bt << 6;
  return bt;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xbits>:
  endbr64
  mov    %edi,%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  shl    $0x6,%edx
  and    $0x400,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int xbits(unsigned short x) {
  int bt = x & 0x3ff;
  if (x & (1 << 10))
    bt = bt << 6;
  return bt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L9
L20:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x3c(%rbp)
L9:
  cmpl   $0x2,-0x3c(%rbp)
  jle    L20
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D38
type_infered: string
name: parse_data
arguments: label: D30
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string

tool: D18: This is p0

tool: D38: This is p1

tool: D30: This is p2

tool: D5: 
Press any key to end...

assistant: ```c
int main() {
  char *p0 = "This is p0";
  char *p1 = "This is p1";
  char *p2 = "This is p2";
  char *ptrs[3];
  int i;
  ptrs[0] = p0;
  ptrs[1] = p1;
  ptrs[2] = p2;
  for (i = 0; i < 3; i++)
    printf("%s\n", ptrs[i]);
  printf("\nPress any key to end...");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D27: This is p0

tool: D8: This is p1

tool: D13: This is p2

tool: D15: 
Press any key to end...

assistant: ```c
int main() {
  char *p0 = "This is p0";
  char *p1 = "This is p1";
  char *p2 = "This is p2";
  char *ptrs[3];
  int i;
  ptrs[0] = p0;
  ptrs[1] = p1;
  ptrs[2] = p2;
  for (i = 0; i < 3; i++)
    printf("%s\n", ptrs[i]);
  printf("\nPress any key to end...");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D39
data_type: string
name: disassemble_data
arguments: data_tag: D37
data_type: string
name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D34
data_type: string

tool: D39: This is p0

tool: D37: This is p1

tool: D15: This is p2

tool: D34: 
Press any key to end...

assistant: ```c
int main() {
  char *p0 = "This is p0";
  char *p1 = "This is p1";
  char *p2 = "This is p2";
  char *ptrs[3];
  int i;
  ptrs[0] = p0;
  ptrs[1] = p1;
  ptrs[2] = p2;
  for (i = 0; i < 3; i++)
    printf("%s\n", ptrs[i]);
  printf("\nPress any key to end...");
  getchar();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D36
data_type: string
name: retrieve_data
arguments: tag: D21
data_type: string

tool: D2: This is p0

tool: D19: This is p1

tool: D36: This is p2

tool: D21: 
Press any key to end...

assistant: ```c
int main() {
  char *p0 = "This is p0";
  char *p1 = "This is p1";
  char *p2 = "This is p2";
  char *ptrs[3];
  int i;
  ptrs[0] = p0;
  ptrs[1] = p1;
  ptrs[2] = p2;
  for (i = 0; i < 3; i++)
    printf("%s\n", ptrs[i]);
  printf("\nPress any key to end...");
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<px_readline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x11(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L23
  mov    $0x0,%eax
  jmp    L63
L23:
  lea    -0x11(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L72
  mov    -0x30(%rbp),%rax
  jmp    L63
L72:
  movzbl -0x11(%rbp),%eax
  cmp    $0xa,%al
  jne    L46
  cmpq   $0x0,-0x30(%rbp)
  jne    L62
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <px_strdup@plt>
  jmp    L63
L62:
  mov    -0x30(%rbp),%rax
  jmp    L63
L46:
  cmpq   $0x0,-0x30(%rbp)
  jne    L104
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <px_strdup@plt>
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x38(%rbp)
L104:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rax,-0x38(%rbp)
  ja     L2
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x401,%eax
  mov    %eax,%edi
  call   <px_malloc0@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x400,%eax
  cltq
  mov    %rax,-0x38(%rbp)
L2:
  lea    -0x11(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <px_readline>
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: 

assistant: ```c
char *px_readline(int fd, char *buffer, size_t bufsize) {
  char c = '\0';
  if (fd < 0)
    return NULL;
  if (read(fd, &c, 1) != 1)
    return buffer;
  if (c == '\n')
    return buffer ? buffer : px_strdup("");
  if (!buffer) {
    buffer = px_strdup("");
    bufsize = 0;
  }
  if (bufsize <= strlen(buffer)) {
    char *tmp = px_malloc0(1024 + strlen(buffer) + 1);
    strcpy(tmp, buffer);
    free(buffer);
    buffer = tmp;
    bufsize = strlen(buffer) + 1024;
  }
  strncat(buffer, &c, 1);
  return px_readline(fd, buffer, bufsize);
}
```
user: What is the c source code of the assembly code below:

```asm
<px_readline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %edi,%edi
  js     L3
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %eax,%edx
  mov    %rbx,%rax
  cmp    $0x1,%edx
  jne    L3
  cmpb   $0xa,0x7(%rsp)
  je     L90
  test   %rbx,%rbx
  je     L87
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rbp,%rax
  jae    L56
L10:
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <px_readline>
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L90:
  test   %rbx,%rbx
  jne    L3
  lea    D7(%rip),%rdi
  call   <px_strdup@plt>
  jmp    L3
L87:
  lea    D7(%rip),%rdi
  call   <px_strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
L43:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x401(%rax),%edi
  call   <px_malloc0@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x400(%rax),%edx
  movslq %edx,%rbp
  jmp    L10
L56:
  mov    %rbx,%rbp
  jmp    L43
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: 

assistant: ```c
char *px_readline(int fd, char *buffer, size_t bufsize) {
  char c = '\0';
  if (fd < 0)
    return NULL;
  if (read(fd, &c, 1) != 1)
    return buffer;
  if (c == '\n')
    return buffer ? buffer : px_strdup("");
  if (!buffer) {
    buffer = px_strdup("");
    bufsize = 0;
  }
  if (bufsize <= strlen(buffer)) {
    char *tmp = px_malloc0(1024 + strlen(buffer) + 1);
    strcpy(tmp, buffer);
    free(buffer);
    buffer = tmp;
    bufsize = strlen(buffer) + 1024;
  }
  strncat(buffer, &c, 1);
  return px_readline(fd, buffer, bufsize);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<px_readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %edi,%edi
  js     L22
  lea    0x7(%rsp),%r14
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %edi,%r12d
  call   <read@plt>
  mov    %eax,%r8d
  mov    %rbp,%rax
  cmp    $0x1,%r8d
  jne    L22
  cmpb   $0xa,0x7(%rsp)
  je     L29
  test   %rbp,%rbp
  je     L76
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmp    %r13,%rax
  jae    L5
L40:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <px_readline>
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L29:
  test   %rbp,%rbp
  jne    L22
  lea    D17(%rip),%rdi
  call   <px_strdup@plt>
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L76:
  lea    D17(%rip),%rdi
  call   <px_strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
L80:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x401(%rax),%edi
  call   <px_malloc0@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x400(%rax),%edx
  movslq %edx,%r13
  jmp    L40
  xchg   %ax,%ax
L5:
  mov    %rbp,%r13
  jmp    L80
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type: string

tool: 

assistant: ```c
char *px_readline(int fd, char *buffer, size_t bufsize) {
  char c = '\0';
  if (fd < 0)
    return NULL;
  if (read(fd, &c, 1) != 1)
    return buffer;
  if (c == '\n')
    return buffer ? buffer : px_strdup("");
  if (!buffer) {
    buffer = px_strdup("");
    bufsize = 0;
  }
  if (bufsize <= strlen(buffer)) {
    char *tmp = px_malloc0(1024 + strlen(buffer) + 1);
    strcpy(tmp, buffer);
    free(buffer);
    buffer = tmp;
    bufsize = strlen(buffer) + 1024;
  }
  strncat(buffer, &c, 1);
  return px_readline(fd, buffer, bufsize);
}
```
user: What is the c source code of the assembly code below?

```asm
<px_readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %edi,%edi
  js     L20
  lea    0x7(%rsp),%r14
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %edi,%r12d
  call   <read@plt>
  mov    %eax,%r8d
  mov    %rbp,%rax
  cmp    $0x1,%r8d
  jne    L20
  cmpb   $0xa,0x7(%rsp)
  je     L61
  test   %rbp,%rbp
  je     L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmp    %r13,%rax
  jae    L79
L97:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <px_readline>
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L76
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L61:
  test   %rbp,%rbp
  jne    L20
  lea    D15(%rip),%rdi
  call   <px_strdup@plt>
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L8:
  lea    D15(%rip),%rdi
  call   <px_strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
L27:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x401(%rax),%edi
  call   <px_malloc0@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x400(%rax),%edx
  movslq %edx,%r13
  jmp    L97
  xchg   %ax,%ax
L79:
  mov    %rbp,%r13
  jmp    L27
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string

tool: 

assistant: ```c
char *px_readline(int fd, char *buffer, size_t bufsize) {
  char c = '\0';
  if (fd < 0)
    return NULL;
  if (read(fd, &c, 1) != 1)
    return buffer;
  if (c == '\n')
    return buffer ? buffer : px_strdup("");
  if (!buffer) {
    buffer = px_strdup("");
    bufsize = 0;
  }
  if (bufsize <= strlen(buffer)) {
    char *tmp = px_malloc0(1024 + strlen(buffer) + 1);
    strcpy(tmp, buffer);
    free(buffer);
    buffer = tmp;
    bufsize = strlen(buffer) + 1024;
  }
  strncat(buffer, &c, 1);
  return px_readline(fd, buffer, bufsize);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d1cp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *d1cp(void *key) {
  double *newkey = malloc(sizeof(double));
  *newkey = *(double *)key;
  return newkey;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d1cp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  movsd  (%rbx),%xmm0
  movsd  %xmm0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void *d1cp(void *key) {
  double *newkey = malloc(sizeof(double));
  *newkey = *(double *)key;
  return newkey;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<d1cp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  movsd  (%rbx),%xmm0
  movsd  %xmm0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void *d1cp(void *key) {
  double *newkey = malloc(sizeof(double));
  *newkey = *(double *)key;
  return newkey;
}
```