ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  lea    D43(%rip),%rdi
  push   %r13
  push   %r12
  lea    D57(%rip),%r12
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x30(%rsp),%r13
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <bi_input@plt>
  lea    D70(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <bi_input@plt>
  mov    %r14,%rdx
  lea    D47(%rip),%r14
  mov    %ebp,%esi
  mov    %eax,%r12d
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r12d,%ecx
  mov    %ebp,%edi
  call   <setbit@plt>
  lea    D69(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  mov    %ebp,%edi
  mov    %r12d,%ecx
  call   <setbit@plt>
  lea    0x50(%rsp),%rsi
  mov    %eax,%edi
  call   <to2@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D43
type_guessed: string
name: parse_data
arguments: label: D57
type_guessed: string
name: parse_data
arguments: label: D70
type_guessed: string
name: parse_data
arguments: label: D47
type_guessed: string
name: parse_data
arguments: label: D64
type_guessed: string
name: parse_data
arguments: label: D27
type_guessed: string
name: parse_data
arguments: label: D69
type_guessed: string
name: parse_data
arguments: label: D67
type_guessed: string

tool: D43: input x:

tool: D57: %s

tool: D70: input y:

tool: D47: input is %d(%s)


tool: D64: p=? n=?

tool: D27: %d %d

tool: D69: The result is %d


tool: D67: result in binumber:

assistant: ```c
main() {
  char s[20];
  char c[20];
  char d[20];
  int x, y;
  int p, n;
  printf("input x:");
  scanf("%s", s);
  x = bi_input(s);
  printf("input y:");
  scanf("%s", c);
  y = bi_input(c);
  printf("input is %d(%s)\n", x, s);
  printf("input is %d(%s)\n", y, c);
  printf("p=? n=?\n");
  scanf("%d %d", &p, &n);
  printf("The result is %d\n", setbit(x, p, n, y));
  printf("result in binumber:");
  to2(setbit(x, p, n, y), d);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D70(%rip),%rdi
  push   %r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x30(%rsp),%r13
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <bi_input@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <bi_input@plt>
  mov    %r14,%rdx
  lea    D13(%rip),%r14
  mov    %ebp,%esi
  mov    %eax,%r12d
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r12d,%ecx
  mov    %ebp,%edi
  call   <setbit@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  mov    %ebp,%edi
  mov    %r12d,%ecx
  call   <setbit@plt>
  lea    0x50(%rsp),%rsi
  mov    %eax,%edi
  call   <to2@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D70
datatype: string
name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D12
datatype: string
name: read_data
arguments: data_label: D13
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D54
datatype: string
name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D79
datatype: string

tool: D70: input x:

tool: D20: %s

tool: D12: input y:

tool: D13: input is %d(%s)


tool: D11: p=? n=?

tool: D54: %d %d

tool: D27: The result is %d


tool: D79: result in binumber:

assistant: ```c
main() {
  char s[20];
  char c[20];
  char d[20];
  int x, y;
  int p, n;
  printf("input x:");
  scanf("%s", s);
  x = bi_input(s);
  printf("input y:");
  scanf("%s", c);
  y = bi_input(c);
  printf("input is %d(%s)\n", x, s);
  printf("input is %d(%s)\n", y, c);
  printf("p=? n=?\n");
  scanf("%d %d", &p, &n);
  printf("The result is %d\n", setbit(x, p, n, y));
  printf("result in binumber:");
  to2(setbit(x, p, n, y), d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: Started the main


assistant: ```c
int main() {
  printf("Started the main\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: Started the main


assistant: ```c
int main() {
  printf("Started the main\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: Started the main


assistant: ```c
int main() {
  printf("Started the main\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: Started the main


assistant: ```c
int main() {
  printf("Started the main\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L6
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L30
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L27
  mov    -0x10(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L30
L27:
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
L30:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void check(int a, int b, int *c) {
  if (a > b) {
    *c = b;
  } else if (a < b) {
    *c = a;
  } else {
    *c = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check>:
  endbr64
  cmp    %esi,%edi
  jg     L8
  mov    $0x0,%esi
  cmovl  %edi,%esi
L8:
  mov    %esi,(%rdx)
  ret
```

assistant: ```c
void check(int a, int b, int *c) {
  if (a > b) {
    *c = b;
  } else if (a < b) {
    *c = a;
  } else {
    *c = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check>:
  endbr64
  cmp    %esi,%edi
  jg     L8
  mov    $0x0,%esi
  cmovl  %edi,%esi
L8:
  mov    %esi,(%rdx)
  ret
```

assistant: ```c
void check(int a, int b, int *c) {
  if (a > b) {
    *c = b;
  } else if (a < b) {
    *c = a;
  } else {
    *c = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check>:
  endbr64
  cmp    %esi,%edi
  jg     L3
  mov    $0x0,%esi
  cmovl  %edi,%esi
L3:
  mov    %esi,(%rdx)
  ret
```

assistant: ```c
void check(int a, int b, int *c) {
  if (a > b) {
    *c = b;
  } else if (a < b) {
    *c = a;
  } else {
    *c = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fast_clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xfffffc30,%eax
  movq   $0xb,(%rax)
L8:
  mov    $0xfffffc68,%eax
  mov    (%rax),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fast_clock() {
  *(volatile unsigned long *)((void *)0xfffffc00 + 0x30) = (0x03 | (((2) & 7) << 2));
  do {
  } while (!(*(volatile unsigned long *)((void *)0xfffffc00 + 0x68) & 0x08));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fast_clock>:
  endbr64
  mov    $0xfffffc30,%eax
  movq   $0xb,(%rax)
  mov    $0xfffffc68,%edx
L8:
  mov    (%rdx),%rax
  test   $0x8,%al
  je     L8
  ret
```

assistant: ```c
void fast_clock() {
  *(volatile unsigned long *)((void *)0xfffffc00 + 0x30) = (0x03 | (((2) & 7) << 2));
  do {
  } while (!(*(volatile unsigned long *)((void *)0xfffffc00 + 0x68) & 0x08));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fast_clock>:
  endbr64
  mov    $0xfffffc30,%eax
  mov    $0xfffffc68,%edx
  movq   $0xb,(%rax)
  nopl   (%rax)
L6:
  mov    (%rdx),%rax
  test   $0x8,%al
  je     L6
  ret
```

assistant: ```c
void fast_clock() {
  *(volatile unsigned long *)((void *)0xfffffc00 + 0x30) = (0x03 | (((2) & 7) << 2));
  do {
  } while (!(*(volatile unsigned long *)((void *)0xfffffc00 + 0x68) & 0x08));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fast_clock>:
  endbr64
  mov    $0xfffffc30,%eax
  mov    $0xfffffc68,%edx
  movq   $0xb,(%rax)
  nopl   (%rax)
L4:
  mov    (%rdx),%rax
  test   $0x8,%al
  je     L4
  ret
```

assistant: ```c
void fast_clock() {
  *(volatile unsigned long *)((void *)0xfffffc00 + 0x30) = (0x03 | (((2) & 7) << 2));
  do {
  } while (!(*(volatile unsigned long *)((void *)0xfffffc00 + 0x68) & 0x08));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ctohex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %esi,%edx
  mov    %edx,%esi
  sar    $0x4,%esi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  movslq %esi,%rsi
  lea    D14(%rip),%rdi
  movzbl (%rsi,%rdi,1),%esi
  mov    %sil,(%rcx)
  and    $0xf,%edx
  movslq %edx,%rdx
  lea    D14(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ctohex(buf, c) register char *buf;
register int c;
{
  static char hex[] = "0123456789abcdef";
  *buf++ = hex[c >> 4];
  *buf = hex[c & 0xf];
}
```
user: Translate the below assembly code into C programming language:

```asm
<ctohex>:
  endbr64
  lea    D9(%rip),%rdx
  mov    %esi,%eax
  sar    $0x4,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,0x1(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: 0123456789abcdef

assistant: ```c
void ctohex(buf, c) register char *buf;
register int c;
{
  static char hex[] = "0123456789abcdef";
  *buf++ = hex[c >> 4];
  *buf = hex[c & 0xf];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ctohex>:
  endbr64
  mov    %esi,%eax
  lea    D7(%rip),%rdx
  and    $0xf,%esi
  sar    $0x4,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,0x1(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: 0123456789abcdef

assistant: ```c
void ctohex(buf, c) register char *buf;
register int c;
{
  static char hex[] = "0123456789abcdef";
  *buf++ = hex[c >> 4];
  *buf = hex[c & 0xf];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ctohex>:
  endbr64
  mov    %esi,%eax
  lea    D5(%rip),%rdx
  and    $0xf,%esi
  sar    $0x4,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,0x1(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: 0123456789abcdef

assistant: ```c
void ctohex(buf, c) register char *buf;
register int c;
{
  static char hex[] = "0123456789abcdef";
  *buf++ = hex[c >> 4];
  *buf = hex[c & 0xf];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L9:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L0:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memzero(void *a, unsigned long n) {
  char *p = (char *)a;
  char *e = p + n;
  while (p < e)
    *p++ = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memzero>:
  endbr64
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L6
L17:
  add    $0x1,%rdi
  movb   $0x0,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L17
L6:
  ret
```

assistant: ```c
void memzero(void *a, unsigned long n) {
  char *p = (char *)a;
  char *e = p + n;
  while (p < e)
    *p++ = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memzero>:
  endbr64
  lea    (%rdi,%rsi,1),%rax
  mov    %rsi,%rdx
  cmp    %rax,%rdi
  jae    L3
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void memzero(void *a, unsigned long n) {
  char *p = (char *)a;
  char *e = p + n;
  while (p < e)
    *p++ = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memzero>:
  endbr64
  lea    (%rdi,%rsi,1),%rax
  mov    %rsi,%rdx
  cmp    %rax,%rdi
  jae    L6
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void memzero(void *a, unsigned long n) {
  char *p = (char *)a;
  char *e = p + n;
  while (p < e)
    *p++ = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jg     L21
  cmpl   $0x0,-0x4(%rbp)
  jg     L4
  jmp    L13
L21:
  cmpl   $0x4,-0x4(%rbp)
  je     L0
  jmp    L13
L4:
  mov    $0x1,%eax
  jmp    L29
L0:
  mov    $0x2,%eax
  jmp    L29
L13:
  mov    $0x3,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
map(int i) {
  switch (i) {
  case 1 ... 3:
    return 1;
  case 4:
    return 2;
  default:
    return 3;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<map>:
  endbr64
  cmp    $0x3,%edi
  jle    L6
  cmp    $0x4,%edi
  setne  %al
  movzbl %al,%eax
  add    $0x2,%eax
  ret
L6:
  test   %edi,%edi
  setle  %al
  movzbl %al,%eax
  lea    0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
map(int i) {
  switch (i) {
  case 1 ... 3:
    return 1;
  case 4:
    return 2;
  default:
    return 3;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<map>:
  endbr64
  cmp    $0x3,%edi
  jle    L3
  xor    %eax,%eax
  cmp    $0x4,%edi
  setne  %al
  add    $0x2,%eax
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  test   %edi,%edi
  setle  %al
  lea    0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
map(int i) {
  switch (i) {
  case 1 ... 3:
    return 1;
  case 4:
    return 2;
  default:
    return 3;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<map>:
  endbr64
  cmp    $0x3,%edi
  jle    L0
  xor    %eax,%eax
  cmp    $0x4,%edi
  setne  %al
  add    $0x2,%eax
  ret
  nopl   (%rax)
L0:
  xor    %eax,%eax
  test   %edi,%edi
  setle  %al
  lea    0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
map(int i) {
  switch (i) {
  case 1 ... 3:
    return 1;
  case 4:
    return 2;
  default:
    return 3;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hb_pjw_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x20,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shr    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L0
L27:
  mov    -0x8(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L3
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  xor    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L3:
  addl   $0x1,-0x18(%rbp)
  addq   $0x1,-0x28(%rbp)
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jb     L27
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int hb_pjw_hash(char *value) {
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  const unsigned int bits_in_u = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int three_quarters = (unsigned int)((bits_in_u * 3) / 4);
  const unsigned int one_eight = (unsigned int)(bits_in_u / 8);
  const unsigned int high_bits = (unsigned int)(0xffffffff) << (bits_in_u - one_eight);
  for (i = 0; i < strlen(value); i++, value++) {
    hash = (hash << one_eight) + *value;
    if ((test = hash & high_bits)) {
      hash = ((hash ^ (test >> three_quarters)) & (~high_bits));
    }
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hb_pjw_hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L19
L15:
  add    $0x1,%r12d
  add    $0x1,%rbp
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jbe    L7
  shl    $0x4,%ebx
  movsbl 0x0(%rbp),%eax
  add    %eax,%ebx
  mov    %ebx,%eax
  and    $0xf0000000,%eax
  je     L15
  shr    $0x18,%eax
  xor    %eax,%ebx
  and    $0xfffffff,%ebx
  jmp    L15
L7:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int hb_pjw_hash(char *value) {
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  const unsigned int bits_in_u = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int three_quarters = (unsigned int)((bits_in_u * 3) / 4);
  const unsigned int one_eight = (unsigned int)(bits_in_u / 8);
  const unsigned int high_bits = (unsigned int)(0xffffffff) << (bits_in_u - one_eight);
  for (i = 0; i < strlen(value); i++, value++) {
    hash = (hash << one_eight) + *value;
    if ((test = hash & high_bits)) {
      hash = ((hash ^ (test >> three_quarters)) & (~high_bits));
    }
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hb_pjw_hash>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl (%rbx),%eax
  shl    $0x4,%r12d
  add    %eax,%r12d
  mov    %r12d,%eax
  and    $0xf0000000,%eax
  je     L29
  shr    $0x18,%eax
  xor    %eax,%r12d
  and    $0xfffffff,%r12d
L29:
  add    $0x1,%ebp
  add    $0x1,%rbx
L23:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  ja     L0
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int hb_pjw_hash(char *value) {
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  const unsigned int bits_in_u = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int three_quarters = (unsigned int)((bits_in_u * 3) / 4);
  const unsigned int one_eight = (unsigned int)(bits_in_u / 8);
  const unsigned int high_bits = (unsigned int)(0xffffffff) << (bits_in_u - one_eight);
  for (i = 0; i < strlen(value); i++, value++) {
    hash = (hash << one_eight) + *value;
    if ((test = hash & high_bits)) {
      hash = ((hash ^ (test >> three_quarters)) & (~high_bits));
    }
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hb_pjw_hash>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L15:
  movsbl (%rbx),%eax
  shl    $0x4,%r12d
  add    %eax,%r12d
  mov    %r12d,%eax
  and    $0xf0000000,%eax
  je     L21
  shr    $0x18,%eax
  xor    %eax,%r12d
  and    $0xfffffff,%r12d
L21:
  add    $0x1,%ebp
  add    $0x1,%rbx
L16:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  ja     L15
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int hb_pjw_hash(char *value) {
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  const unsigned int bits_in_u = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int three_quarters = (unsigned int)((bits_in_u * 3) / 4);
  const unsigned int one_eight = (unsigned int)(bits_in_u / 8);
  const unsigned int high_bits = (unsigned int)(0xffffffff) << (bits_in_u - one_eight);
  for (i = 0; i < strlen(value); i++, value++) {
    hash = (hash << one_eight) + *value;
    if ((test = hash & high_bits)) {
      hash = ((hash ^ (test >> three_quarters)) & (~high_bits));
    }
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: Test Executable Sucessfully Built!


assistant: ```c
int main() {
  printf("Test Executable Sucessfully Built!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: Test Executable Sucessfully Built!


assistant: ```c
int main() {
  printf("Test Executable Sucessfully Built!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Test Executable Sucessfully Built!


assistant: ```c
int main() {
  printf("Test Executable Sucessfully Built!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: Test Executable Sucessfully Built!


assistant: ```c
int main() {
  printf("Test Executable Sucessfully Built!\n");
  return 0;
}
```