ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test(int *a, int *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  mov    $0x0,%eax
L2:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x9c40,%rax
  jne    L2
  ret
```

assistant: ```c
void test(int *a, int *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x9c40,%rax
  jne    L6
  ret
```

assistant: ```c
void test(int *a, int *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  lea    0x4(%rsi),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  mov    $0x0,%eax
  jbe    L9
  nopl   0x0(%rax)
L0:
  movdqu (%rsi,%rax,1),%xmm0
  movdqa %xmm0,%xmm1
  psrad  $0x1f,%xmm1
  pxor   %xmm1,%xmm0
  psubd  %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    $0x9c40,%rax
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x9c40,%rax
  jne    L9
  ret
```

assistant: ```c
void test(int *a, int *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fputc('\n', stderr);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<die>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D6(%rip),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    (%r12),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    (%r12),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fputc('\n', stderr);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D9(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fputc('\n', stderr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D7(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fputc('\n', stderr);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <simputs@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <simputs@plt>
  mov    $0x2a,%edi
  call   <simputn@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <simputs@plt>
  mov    $0x0,%eax
  call   <level1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D29
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D14: Hello World!


tool: D29: The answer is 

tool: D8: 


assistant: ```c
main() {
  simputs("Hello World!\n");
  simputs("The answer is ");
  simputn(6 * 7);
  simputs("\n");
  level1();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <simputs@plt>
  lea    D19(%rip),%rdi
  call   <simputs@plt>
  mov    $0x2a,%edi
  call   <simputn@plt>
  lea    D23(%rip),%rdi
  call   <simputs@plt>
  mov    $0x0,%eax
  call   <level1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string

tool: D24: Hello World!


tool: D19: The answer is 

tool: D23: 


assistant: ```c
main() {
  simputs("Hello World!\n");
  simputs("The answer is ");
  simputn(6 * 7);
  simputs("\n");
  level1();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <simputs@plt>
  lea    D4(%rip),%rdi
  call   <simputs@plt>
  mov    $0x2a,%edi
  call   <simputn@plt>
  lea    D29(%rip),%rdi
  call   <simputs@plt>
  xor    %eax,%eax
  call   <level1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D29
data_type: string

tool: D26: Hello World!


tool: D4: The answer is 

tool: D29: 


assistant: ```c
main() {
  simputs("Hello World!\n");
  simputs("The answer is ");
  simputn(6 * 7);
  simputs("\n");
  level1();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <simputs@plt>
  lea    D29(%rip),%rdi
  call   <simputs@plt>
  mov    $0x2a,%edi
  call   <simputn@plt>
  lea    D28(%rip),%rdi
  call   <simputs@plt>
  xor    %eax,%eax
  call   <level1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D28
data_type: string

tool: D9: Hello World!


tool: D29: The answer is 

tool: D28: 


assistant: ```c
main() {
  simputs("Hello World!\n");
  simputs("The answer is ");
  simputn(6 * 7);
  simputs("\n");
  level1();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x28,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: 
%d

assistant: ```c
int main() {
  int x = 40;
  printf("\n%d", (((int)(x) + ((4) - 1)) & ~((4) - 1)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: 
%d

assistant: ```c
int main() {
  int x = 40;
  printf("\n%d", (((int)(x) + ((4) - 1)) & ~((4) - 1)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: 
%d

assistant: ```c
int main() {
  int x = 40;
  printf("\n%d", (((int)(x) + ((4) - 1)) & ~((4) - 1)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: 
%d

assistant: ```c
int main() {
  int x = 40;
  printf("\n%d", (((int)(x) + ((4) - 1)) & ~((4) - 1)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<igd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L21
L16:
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L77
L84:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L20
L35:
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x58(%rbp)
  ja     L35
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L64
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L64:
  addl   $0x1,-0x20(%rbp)
L77:
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x48(%rbp)
  ja     L84
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x24(%rbp)
L21:
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,-0x50(%rbp)
  ja     L16
  mov    -0x50(%rbp),%rax
  test   %rax,%rax
  js     L8
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L15
L8:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L15:
  movsd  -0x8(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: f64

tool: D5: 1e+200

assistant: ```c
double igd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelB; i++) {
    min = 1.0E200;
    for (j = 0; j < numelA; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (B[i * nObjs + k] - A[j * nObjs + k]) * (B[i * nObjs + k] - A[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelB);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<igd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,%r15
  test   %rcx,%rcx
  je     L56
  mov    %rsi,%rbp
  mov    %r8,%r12
  lea    0x0(,%r8,8),%rbx
  mov    $0x0,%r14d
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  mov    %edx,%r13d
  jmp    L22
L57:
  movsd  0x0(%rbp,%rax,1),%xmm0
  subsd  (%rdx,%rax,1),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rbx,%rax
  jne    L57
L83:
  minsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  add    $0x1,%ecx
  add    %rbx,%rdx
  cmp    %r13d,%ecx
  je     L85
L5:
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  test   %r12,%r12
  jne    L57
  jmp    L83
L21:
  movsd  D13(%rip),%xmm2
L85:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%r14
  add    %rbx,%rbp
  cmp    %r14,%r15
  je     L52
L22:
  cmpq   $0x0,0x10(%rsp)
  je     L21
  mov    0x18(%rsp),%rdx
  movsd  D13(%rip),%xmm2
  mov    $0x0,%ecx
  jmp    L5
L56:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L52:
  test   %r15,%r15
  js     L79
  pxor   %xmm1,%xmm1
  cvtsi2sd %r15,%xmm1
L94:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    %r15,%rax
  shr    %rax
  and    $0x1,%r15d
  or     %r15,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L94
```

tool_calls: name: parse_data
arguments: data_label: D13
data_type: f64

tool: D13: 1e+200

assistant: ```c
double igd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelB; i++) {
    min = 1.0E200;
    for (j = 0; j < numelA; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (B[i * nObjs + k] - A[j * nObjs + k]) * (B[i * nObjs + k] - A[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelB);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<igd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rcx,0x10(%rsp)
  test   %rcx,%rcx
  je     L55
  pxor   %xmm3,%xmm3
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %r8,%r15
  lea    0x0(,%r8,8),%rbx
  xor    %ebp,%ebp
  movapd %xmm3,%xmm4
  mov    %edx,%r13d
  nopl   0x0(%rax,%rax,1)
L16:
  test   %r12,%r12
  je     L28
  mov    D7(%rip),%rax
  mov    0x18(%rsp),%rdx
  xor    %ecx,%ecx
  movq   %rax,%xmm2
  nopl   0x0(%rax)
L65:
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  test   %r15,%r15
  je     L31
  nopl   0x0(%rax,%rax,1)
L10:
  movsd  (%r14,%rax,1),%xmm0
  subsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rax
  jne    L10
L31:
  minsd  %xmm2,%xmm1
  add    $0x1,%ecx
  add    %rbx,%rdx
  movapd %xmm1,%xmm2
  cmp    %ecx,%r13d
  jne    L65
L54:
  movapd %xmm2,%xmm0
  movsd  %xmm4,0x8(%rsp)
  add    $0x1,%rbp
  add    %rbx,%r14
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm4
  cmp    0x10(%rsp),%rbp
  cvtsi2sd %rax,%xmm0
  pxor   %xmm3,%xmm3
  addsd  %xmm0,%xmm4
  jne    L16
L69:
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  ret
L28:
  mov    D7(%rip),%rax
  movq   %rax,%xmm2
  jmp    L54
L55:
  pxor   %xmm4,%xmm4
  jmp    L69
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: f64

tool: D7: 1e+200

assistant: ```c
double igd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelB; i++) {
    min = 1.0E200;
    for (j = 0; j < numelA; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (B[i * nObjs + k] - A[j * nObjs + k]) * (B[i * nObjs + k] - A[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelB);
}
```
user: What is the c source code of the assembly code below?

```asm
<igd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,0x28(%rsp)
  mov    %rcx,0x20(%rsp)
  test   %rcx,%rcx
  je     L60
  mov    %r8,%r15
  mov    %rdi,%rbx
  pxor   %xmm4,%xmm4
  mov    %r8,%rdi
  shr    %r15
  mov    %rsi,%r14
  and    $0xfffffffffffffffe,%rdi
  xor    %r13d,%r13d
  shl    $0x4,%r15
  xor    %r12d,%r12d
  movapd %xmm4,%xmm5
  mov    %edx,%ebp
  nopl   0x0(%rax)
L69:
  cmpq   $0x0,0x28(%rsp)
  je     L109
  mov    D4(%rip),%rax
  lea    (%r14,%r13,8),%rcx
  xor    %edx,%edx
  xor    %r10d,%r10d
  movq   %rax,%xmm3
  nopl   0x0(%rax)
L32:
  movapd %xmm4,%xmm1
  test   %r8,%r8
  je     L80
  cmp    $0x1,%r8
  je     L21
  lea    (%rbx,%rdx,8),%r11
  xor    %eax,%eax
  movapd %xmm4,%xmm1
  nopl   (%rax)
L93:
  movupd (%rcx,%rax,1),%xmm0
  movupd (%r11,%rax,1),%xmm6
  add    $0x10,%rax
  subpd  %xmm6,%xmm0
  mulpd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%r15
  jne    L93
  mov    %rdi,%rax
  cmp    %rdi,%r8
  je     L80
L0:
  lea    0x0(%r13,%rax,1),%r11
  add    %rdx,%rax
  movsd  (%r14,%r11,8),%xmm0
  subsd  (%rbx,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
L80:
  minsd  %xmm3,%xmm1
  add    $0x1,%r10d
  add    %r8,%rdx
  movapd %xmm1,%xmm3
  cmp    %ebp,%r10d
  jne    L32
L67:
  movapd %xmm3,%xmm0
  mov    %r8,0x18(%rsp)
  add    $0x1,%r12
  mov    %rdi,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  mov    0x18(%rsp),%r8
  movsd  0x8(%rsp),%xmm5
  cvtsi2sd %rax,%xmm0
  mov    0x10(%rsp),%rdi
  pxor   %xmm4,%xmm4
  add    %r8,%r13
  cmp    0x20(%rsp),%r12
  addsd  %xmm0,%xmm5
  jne    L69
L64:
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x20(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm0,%xmm5
  movapd %xmm5,%xmm0
  ret
L21:
  movapd %xmm4,%xmm1
  xor    %eax,%eax
  jmp    L0
L109:
  mov    D4(%rip),%rax
  movq   %rax,%xmm3
  jmp    L67
L60:
  pxor   %xmm5,%xmm5
  jmp    L64
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: f64

tool: D4: 1e+200

assistant: ```c
double igd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelB; i++) {
    min = 1.0E200;
    for (j = 0; j < numelA; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (B[i * nObjs + k] - A[j * nObjs + k]) * (B[i * nObjs + k] - A[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelB);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <load_users@plt>
  cmp    $0xffffffff,%eax
  jne    L24
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <error_exit@plt>
L24:
  cmpl   $0x1,-0x14(%rbp)
  jle    L7
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  jmp    L29
L7:
  mov    $0x0,%eax
L29:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <make_socket@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <serve@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: Error loading user file

assistant: ```c
int main(int argc, char **argv) {
  if (load_users() == -1)
    error_exit("Error loading user file");
  char *port_str = (argc > 1) ? argv[1] : NULL;
  int sockfd = make_socket(port_str, 1);
  serve(sockfd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <load_users@plt>
  cmp    $0xffffffff,%eax
  je     L17
L8:
  mov    $0x0,%edi
  cmp    $0x1,%ebx
  jle    L18
  mov    0x8(%rbp),%rdi
L18:
  mov    $0x1,%esi
  call   <make_socket@plt>
  mov    %eax,%edi
  call   <serve@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D9(%rip),%rdi
  call   <error_exit@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: Error loading user file

assistant: ```c
int main(int argc, char **argv) {
  if (load_users() == -1)
    error_exit("Error loading user file");
  char *port_str = (argc > 1) ? argv[1] : NULL;
  int sockfd = make_socket(port_str, 1);
  serve(sockfd);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <load_users@plt>
  cmp    $0xffffffff,%eax
  je     L18
L9:
  xor    %edi,%edi
  cmp    $0x1,%ebx
  jle    L7
  mov    0x8(%rbp),%rdi
L7:
  mov    $0x1,%esi
  call   <make_socket@plt>
  mov    %eax,%edi
  call   <serve@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L18:
  lea    D2(%rip),%rdi
  call   <error_exit@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: Error loading user file

assistant: ```c
int main(int argc, char **argv) {
  if (load_users() == -1)
    error_exit("Error loading user file");
  char *port_str = (argc > 1) ? argv[1] : NULL;
  int sockfd = make_socket(port_str, 1);
  serve(sockfd);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <load_users@plt>
  cmp    $0xffffffff,%eax
  je     L25
L8:
  xor    %edi,%edi
  cmp    $0x1,%ebx
  jle    L18
  mov    0x8(%rbp),%rdi
L18:
  mov    $0x1,%esi
  call   <make_socket@plt>
  mov    %eax,%edi
  call   <serve@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L25:
  lea    D6(%rip),%rdi
  call   <error_exit@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: Error loading user file

assistant: ```c
int main(int argc, char **argv) {
  if (load_users() == -1)
    error_exit("Error loading user file");
  char *port_str = (argc > 1) ? argv[1] : NULL;
  int sockfd = make_socket(port_str, 1);
  serve(sockfd);
  return 0;
}
```