ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<buf_free>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x48(%rdi),%rbp
L1:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void buf_free(char *buf[]) {
  int i;
  for (i = 0; i < 9; i++) {
    free(buf[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buf_free>:
  endbr64
  push   %rbp
  lea    0x48(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void buf_free(char *buf[]) {
  int i;
  for (i = 0; i < 9; i++) {
    free(buf[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<buf_free>:
  endbr64
  push   %rbp
  lea    0x48(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void buf_free(char *buf[]) {
  int i;
  for (i = 0; i < 9; i++) {
    free(buf[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_action>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <skipspace@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    $0x0,%eax
  call   <show_actions@plt>
  jmp    L18
L16:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <parse_action@plt>
L18:
  nop
  leave
  ret
```

assistant: ```c
void cmd_action(char *arg) {
  arg = skipspace(arg);
  if (!*arg)
    show_actions();
  else
    parse_action(arg, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_action>:
  endbr64
  sub    $0x8,%rsp
  call   <skipspace@plt>
  cmpb   $0x0,(%rax)
  jne    L10
  mov    $0x0,%eax
  call   <show_actions@plt>
L5:
  add    $0x8,%rsp
  ret
L10:
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <parse_action@plt>
  jmp    L5
```

assistant: ```c
void cmd_action(char *arg) {
  arg = skipspace(arg);
  if (!*arg)
    show_actions();
  else
    parse_action(arg, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<cmd_action>:
  endbr64
  sub    $0x8,%rsp
  call   <skipspace@plt>
  cmpb   $0x0,(%rax)
  jne    L2
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <show_actions@plt>
  nopl   (%rax)
L2:
  mov    %rax,%rdi
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1090 <parse_action@plt>
```

assistant: ```c
void cmd_action(char *arg) {
  arg = skipspace(arg);
  if (!*arg)
    show_actions();
  else
    parse_action(arg, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmd_action>:
  endbr64
  sub    $0x8,%rsp
  call   <skipspace@plt>
  cmpb   $0x0,(%rax)
  jne    L3
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <show_actions@plt>
  nopl   (%rax)
L3:
  mov    %rax,%rdi
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1090 <parse_action@plt>
```

assistant: ```c
void cmd_action(char *arg) {
  arg = skipspace(arg);
  if (!*arg)
    show_actions();
  else
    parse_action(arg, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Cmp_Definition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: struct Cmp {
  int (*cmp)(var, var);
};


assistant: ```c
const char *Cmp_Definition(void) {
  return "struct Cmp {\n"
         "  int (*cmp)(var, var);\n"
         "};\n";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Cmp_Definition>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: struct Cmp {
  int (*cmp)(var, var);
};


assistant: ```c
const char *Cmp_Definition(void) {
  return "struct Cmp {\n"
         "  int (*cmp)(var, var);\n"
         "};\n";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Cmp_Definition>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: struct Cmp {
  int (*cmp)(var, var);
};


assistant: ```c
const char *Cmp_Definition(void) {
  return "struct Cmp {\n"
         "  int (*cmp)(var, var);\n"
         "};\n";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Cmp_Definition>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: struct Cmp {
  int (*cmp)(var, var);
};


assistant: ```c
const char *Cmp_Definition(void) {
  return "struct Cmp {\n"
         "  int (*cmp)(var, var);\n"
         "};\n";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  je     L66
  lea    0x10(%rsp),%r15
  lea    D38(%rip),%r14
  lea    D30(%rip),%r13
  jmp    L15
L44:
  mov    %rbp,%rbx
L5:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
L31:
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L66
L15:
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x18(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x20(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x20(%rsp),%rax
  mov    0x18(%rsp),%rcx
  add    0x10(%rsp),%rcx
  cqto
  idiv   %rcx
  lea    (%rax,%rax,1),%rbp
  cmp    $0x1,%rdx
  sbb    $0xffffffffffffffff,%rbp
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  mov    0x10(%rsp),%rbx
  mov    %rsi,%rax
  sub    %rbx,%rax
  lea    -0x5(%rbp),%rcx
  cqto
  idiv   %rcx
  mov    %rax,%r12
  lea    (%rax,%rax,1),%rax
  sub    %rax,%rbx
  test   %r12,%r12
  je     L93
  lea    (%rsi,%rax,1),%rbp
  cmp    %rbp,%rbx
  je     L44
L103:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %r12,%rbx
  cmp    %rbx,%rbp
  jne    L103
  jmp    L5
L93:
  test   %rbp,%rbp
  jle    L46
  mov    $0x1,%r12d
L104:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12
  cmp    %r12,%rbp
  jge    L104
L46:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  jmp    L31
L66:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D38
type_infered: string
name: read_data
arguments: data_tag: D30
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string

tool: D17: %d

tool: D38: %lld

tool: D30: %lld 

tool: D28: %lld


assistant: ```c
int main() {
  long long int a, b, S, i;
  int t;
  scanf("%d", &t);
  while (t != 0) {
    scanf("%lld", &a);
    scanf("%lld", &b);
    scanf("%lld", &S);
    long long int n = S / (a + b);
    n *= 2;
    if (S % (a + b) != 0) {
      n++;
    }
    printf("%lld\n", n);
    long long int d = (b - a) / (n - 5);
    long long int p = a - 2 * d, q = b + 2 * d;
    if (d == 0) {
      for (i = 1; i <= n; i++) {
        printf("%lld ", p);
      }
      printf("\n");
      t--;
      continue;
    }
    for (i = p; i != q; i += d) {
      printf("%lld ", i);
    }
    printf("%lld ", i);
    printf("\n");
    t--;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D11(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L79
  lea    0x28(%rsp),%rax
  lea    0x20(%rsp),%r15
  mov    %rax,(%rsp)
  lea    0x30(%rsp),%rax
  lea    D39(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    D15(%rip),%r12
  nopl   (%rax)
L31:
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x30(%rsp),%rax
  mov    0x28(%rsp),%rcx
  lea    D25(%rip),%rdi
  add    0x20(%rsp),%rcx
  cqto
  idiv   %rcx
  cmp    $0x1,%rdx
  lea    (%rax,%rax,1),%rbp
  sbb    $0xffffffffffffffff,%rbp
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rdi
  mov    0x20(%rsp),%rsi
  lea    -0x5(%rbp),%rcx
  mov    %rdi,%rax
  sub    %rsi,%rax
  cqto
  idiv   %rcx
  mov    %rax,%rbx
  lea    (%rax,%rax,1),%rax
  sub    %rax,%rsi
  mov    %rsi,%r14
  test   %rbx,%rbx
  je     L23
  lea    (%rdi,%rax,1),%rbp
  cmp    %rbp,%rsi
  je     L17
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %rbx,%r14
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L30
L17:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L77:
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,0x1c(%rsp)
  jne    L31
L79:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x1,%ebx
  test   %rbp,%rbp
  jle    L77
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jge    L70
  jmp    L77
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D39
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string

tool: D11: %d

tool: D39: %lld

tool: D15: %lld 

tool: D25: %lld


assistant: ```c
int main() {
  long long int a, b, S, i;
  int t;
  scanf("%d", &t);
  while (t != 0) {
    scanf("%lld", &a);
    scanf("%lld", &b);
    scanf("%lld", &S);
    long long int n = S / (a + b);
    n *= 2;
    if (S % (a + b) != 0) {
      n++;
    }
    printf("%lld\n", n);
    long long int d = (b - a) / (n - 5);
    long long int p = a - 2 * d, q = b + 2 * d;
    if (d == 0) {
      for (i = 1; i <= n; i++) {
        printf("%lld ", p);
      }
      printf("\n");
      t--;
      continue;
    }
    for (i = p; i != q; i += d) {
      printf("%lld ", i);
    }
    printf("%lld ", i);
    printf("\n");
    t--;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L5
  lea    0x28(%rsp),%rax
  lea    0x20(%rsp),%r15
  mov    %rax,(%rsp)
  lea    0x30(%rsp),%rax
  lea    D23(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    D24(%rip),%r12
  nopl   (%rax)
L10:
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x30(%rsp),%rax
  mov    0x28(%rsp),%rcx
  lea    D0(%rip),%rdi
  add    0x20(%rsp),%rcx
  cqto
  idiv   %rcx
  cmp    $0x1,%rdx
  lea    (%rax,%rax,1),%rbp
  sbb    $0xffffffffffffffff,%rbp
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rdi
  mov    0x20(%rsp),%rsi
  lea    -0x5(%rbp),%rcx
  mov    %rdi,%rax
  sub    %rsi,%rax
  cqto
  idiv   %rcx
  mov    %rax,%rbx
  lea    (%rax,%rax,1),%rax
  sub    %rax,%rsi
  mov    %rsi,%r14
  test   %rbx,%rbx
  je     L67
  lea    (%rdi,%rax,1),%rbp
  cmp    %rbp,%rsi
  je     L18
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %rbx,%r14
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L9
L18:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,0x1c(%rsp)
  jne    L10
L5:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  mov    $0x1,%ebx
  test   %rbp,%rbp
  jle    L0
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jge    L79
  jmp    L0
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D32
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D24
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D32: %d

tool: D23: %lld

tool: D24: %lld 

tool: D0: %lld


assistant: ```c
int main() {
  long long int a, b, S, i;
  int t;
  scanf("%d", &t);
  while (t != 0) {
    scanf("%lld", &a);
    scanf("%lld", &b);
    scanf("%lld", &S);
    long long int n = S / (a + b);
    n *= 2;
    if (S % (a + b) != 0) {
      n++;
    }
    printf("%lld\n", n);
    long long int d = (b - a) / (n - 5);
    long long int p = a - 2 * d, q = b + 2 * d;
    if (d == 0) {
      for (i = 1; i <= n; i++) {
        printf("%lld ", p);
      }
      printf("\n");
      t--;
      continue;
    }
    for (i = p; i != q; i += d) {
      printf("%lld ", i);
    }
    printf("%lld ", i);
    printf("\n");
    t--;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<autohelperowl_attackpat192>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x3,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <play_attack_defend2_n@plt>
  test   %eax,%eax
  jne    L28
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  je     L28
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  je     L28
  mov    $0x1,%eax
  jmp    L20
L28:
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat192(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 0, move, transformation);
  return !play_attack_defend2_n((1 + 2 - (color)), 0, 1, move, a, b) && vital_chain(a) && vital_chain(b);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<autohelperowl_attackpat192>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    $0x3,%edi
  sub    %r13d,%edi
  mov    %eax,%r9d
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <play_attack_defend2_n@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L18
L20:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  je     L20
  mov    %ebp,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  setne  %bl
  movzbl %bl,%ebx
  jmp    L20
```

assistant: ```c
int autohelperowl_attackpat192(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 0, move, transformation);
  return !play_attack_defend2_n((1 + 2 - (color)), 0, 1, move, a, b) && vital_chain(a) && vital_chain(b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<autohelperowl_attackpat192>:
  endbr64
  push   %r13
  xor    %edi,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    $0x1,%edi
  mov    %eax,%ebp
  call   <offset@plt>
  mov    $0x3,%edi
  xor    %esi,%esi
  mov    %ebp,%r8d
  sub    %ebx,%edi
  mov    %eax,%r9d
  mov    %r12d,%ecx
  mov    $0x1,%edx
  mov    %eax,%r13d
  call   <play_attack_defend2_n@plt>
  test   %eax,%eax
  je     L17
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %ebp,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  je     L15
  mov    %r13d,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat192(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 0, move, transformation);
  return !play_attack_defend2_n((1 + 2 - (color)), 0, 1, move, a, b) && vital_chain(a) && vital_chain(b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<autohelperowl_attackpat192>:
  endbr64
  push   %r13
  xor    %edi,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    $0x1,%edi
  mov    %eax,%ebp
  call   <offset@plt>
  mov    $0x3,%edi
  xor    %esi,%esi
  mov    %ebp,%r8d
  sub    %ebx,%edi
  mov    %eax,%r9d
  mov    %r12d,%ecx
  mov    $0x1,%edx
  mov    %eax,%r13d
  call   <play_attack_defend2_n@plt>
  test   %eax,%eax
  je     L1
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebp,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  je     L9
  mov    %r13d,%edi
  call   <vital_chain@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat192(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 0, move, transformation);
  return !play_attack_defend2_n((1 + 2 - (color)), 0, 1, move, a, b) && vital_chain(a) && vital_chain(b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rp_decode_4bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L11:
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rp_decode_nibble@plt>
  test   %eax,%eax
  je     L35
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x28(%rbp)
L26:
  cmpl   $0x7,-0xc(%rbp)
  jle    L11
  jmp    L30
L35:
  nop
L30:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int rp_decode_4bytes(const char *in, uint32_t *val) {
  unsigned int nibble;
  uint32_t tmp;
  int count;
  for (tmp = 0, count = 0; count < 8; count++, in++) {
    if (!rp_decode_nibble(in, &nibble))
      break;
    tmp = (tmp << 4) + nibble;
  }
  *val = tmp;
  return (!0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rp_decode_4bytes>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rdi),%r13
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r12
L23:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <rp_decode_nibble@plt>
  test   %eax,%eax
  je     L22
  shl    $0x4,%ebp
  add    0x4(%rsp),%ebp
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L23
L22:
  mov    %ebp,(%r14)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x1,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rp_decode_4bytes(const char *in, uint32_t *val) {
  unsigned int nibble;
  uint32_t tmp;
  int count;
  for (tmp = 0, count = 0; count < 8; count++, in++) {
    if (!rp_decode_nibble(in, &nibble))
      break;
    tmp = (tmp << 4) + nibble;
  }
  *val = tmp;
  return (!0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rp_decode_4bytes>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    0x8(%rdi),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L28:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <rp_decode_nibble@plt>
  test   %eax,%eax
  je     L11
  add    $0x1,%rbx
  shl    $0x4,%ebp
  add    0x4(%rsp),%ebp
  cmp    %rbx,%r13
  jne    L28
L11:
  mov    %ebp,(%r14)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rp_decode_4bytes(const char *in, uint32_t *val) {
  unsigned int nibble;
  uint32_t tmp;
  int count;
  for (tmp = 0, count = 0; count < 8; count++, in++) {
    if (!rp_decode_nibble(in, &nibble))
      break;
    tmp = (tmp << 4) + nibble;
  }
  *val = tmp;
  return (!0);
}
```