ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printhex>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
  xor    %ebx,%ebx
  jmp    L27
  nopl   0x0(%rax)
L7:
  movzbl 0x0(%rbp,%rbx,1),%edi
L27:
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <printhex1@plt>
  movzbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  and    $0xf,%edi
  call   <printhex1@plt>
  movzbl 0x0(%rbp),%eax
  cmp    %ebx,%eax
  jg     L7
L17:
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: 


assistant: ```c
void printhex(unsigned char *str) {
  int i;
  for (i = 0; i < str[0]; i++) {
    printhex1(str[i] / 16);
    printhex1(str[i] % 16);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printhex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  movzbl 0x0(%rbp,%rbx,1),%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <printhex1@plt>
  movzbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  and    $0xf,%edi
  call   <printhex1@plt>
  movzbl 0x0(%rbp),%eax
  cmp    %ebx,%eax
  jg     L6
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   (%rax)
L17:
  lea    D4(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: 


assistant: ```c
void printhex(unsigned char *str) {
  int i;
  for (i = 0; i < str[0]; i++) {
    printhex1(str[i] / 16);
    printhex1(str[i] % 16);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_in_bound>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L12
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L21
L12:
  mov    $0x0,%eax
  jmp    L22
L21:
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (arr > ptr || (arr + size - 1) < ptr) {
    return 0;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_in_bound>:
  endbr64
  mov    $0x0,%eax
  cmp    %rdx,%rdi
  ja     L9
  movslq %esi,%rsi
  lea    -0x4(%rdi,%rsi,4),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (arr > ptr || (arr + size - 1) < ptr) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_in_bound>:
  endbr64
  xor    %eax,%eax
  cmp    %rdx,%rdi
  ja     L3
  movslq %esi,%rsi
  lea    -0x4(%rdi,%rsi,4),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
L3:
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (arr > ptr || (arr + size - 1) < ptr) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_in_bound>:
  endbr64
  xor    %eax,%eax
  cmp    %rdx,%rdi
  ja     L8
  movslq %esi,%rsi
  lea    -0x4(%rdi,%rsi,4),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (arr > ptr || (arr + size - 1) < ptr) {
    return 0;
  } else {
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L21
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L21
  mov    $0x5,%eax
  jmp    L19
L21:
  mov    $0x4,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int test_and(int a, int b, int c) {
  if (a < b && b > c)
    return 5;
  else
    return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_and>:
  endbr64
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edi,%esi
  setg   %al
  movzbl %al,%eax
  add    $0x4,%eax
  ret
```

assistant: ```c
int test_and(int a, int b, int c) {
  if (a < b && b > c)
    return 5;
  else
    return 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_and>:
  endbr64
  cmp    %edx,%edi
  cmovl  %edx,%edi
  xor    %eax,%eax
  cmp    %edi,%esi
  setg   %al
  add    $0x4,%eax
  ret
```

assistant: ```c
int test_and(int a, int b, int c) {
  if (a < b && b > c)
    return 5;
  else
    return 4;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_and>:
  endbr64
  cmp    %edx,%edi
  cmovl  %edx,%edi
  xor    %eax,%eax
  cmp    %edi,%esi
  setg   %al
  add    $0x4,%eax
  ret
```

assistant: ```c
int test_and(int a, int b, int c) {
  if (a < b && b > c)
    return 5;
  else
    return 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unpackkmer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L92
L111:
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  sarl   $0x2,-0x14(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L39
  cmpl   $0x3,-0x4(%rbp)
  jg     L11
  cmpl   $0x2,-0x4(%rbp)
  je     L119
  cmpl   $0x2,-0x4(%rbp)
  jg     L11
  cmpl   $0x0,-0x4(%rbp)
  je     L65
  cmpl   $0x1,-0x4(%rbp)
  je     L107
  jmp    L11
L65:
  mov    -0x20(%rbp),%rax
  movb   $0x41,(%rax)
  jmp    L56
L107:
  mov    -0x20(%rbp),%rax
  movb   $0x43,(%rax)
  jmp    L56
L119:
  mov    -0x20(%rbp),%rax
  movb   $0x47,(%rax)
  jmp    L56
L39:
  mov    -0x20(%rbp),%rax
  movb   $0x54,(%rax)
  jmp    L56
L11:
  nop
L56:
  addl   $0x1,-0x8(%rbp)
  addq   $0x1,-0x20(%rbp)
L92:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L111
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unpackkmer(uint32_t kmer, char *s, int k) {
  int i;
  uint32_t nt;
  for (i = 0; i < k; i++, s++) {
    nt = kmer & 0x3;
    kmer = kmer >> 2;
    switch (nt) {
    case 0:
      *s = 'A';
      break;
    case 1:
      *s = 'C';
      break;
    case 2:
      *s = 'G';
      break;
    case 3:
      *s = 'T';
      break;
    default:
      break;
    }
  }
  *s = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unpackkmer>:
  endbr64
  test   %edx,%edx
  jle    L77
  mov    %edx,%edx
  add    %rsi,%rdx
  jmp    L98
L41:
  movb   $0x41,(%rsi)
L99:
  add    $0x1,%rsi
  cmp    %rdx,%rsi
  je     L9
L98:
  mov    %edi,%eax
  and    $0x3,%eax
  sar    $0x2,%edi
  cmp    $0x2,%eax
  je     L87
  jg     L70
  test   %eax,%eax
  je     L41
  cmp    $0x1,%eax
  jne    L99
  movb   $0x43,(%rsi)
  jmp    L99
L87:
  movb   $0x47,(%rsi)
  jmp    L99
L70:
  movb   $0x54,(%rsi)
  jmp    L99
L77:
  mov    %rsi,%rdx
L9:
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
void unpackkmer(uint32_t kmer, char *s, int k) {
  int i;
  uint32_t nt;
  for (i = 0; i < k; i++, s++) {
    nt = kmer & 0x3;
    kmer = kmer >> 2;
    switch (nt) {
    case 0:
      *s = 'A';
      break;
    case 1:
      *s = 'C';
      break;
    case 2:
      *s = 'G';
      break;
    case 3:
      *s = 'T';
      break;
    default:
      break;
    }
  }
  *s = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unpackkmer>:
  endbr64
  test   %edx,%edx
  jle    L6
  movslq %edx,%rdx
  lea    (%rsi,%rdx,1),%rcx
  nop
L11:
  mov    %edi,%edx
  mov    $0x47,%eax
  sar    $0x2,%edi
  and    $0x3,%edx
  cmp    $0x2,%edx
  je     L1
  mov    $0x54,%eax
  cmp    $0x3,%edx
  je     L1
  cmp    $0x1,%edx
  sete   %al
  lea    0x41(%rax,%rax,1),%eax
L1:
  mov    %al,(%rsi)
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  jne    L11
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L6:
  mov    %rsi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void unpackkmer(uint32_t kmer, char *s, int k) {
  int i;
  uint32_t nt;
  for (i = 0; i < k; i++, s++) {
    nt = kmer & 0x3;
    kmer = kmer >> 2;
    switch (nt) {
    case 0:
      *s = 'A';
      break;
    case 1:
      *s = 'C';
      break;
    case 2:
      *s = 'G';
      break;
    case 3:
      *s = 'T';
      break;
    default:
      break;
    }
  }
  *s = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unpackkmer>:
  endbr64
  test   %edx,%edx
  jle    L28
  movslq %edx,%rdx
  lea    (%rsi,%rdx,1),%rcx
  nop
L10:
  mov    %edi,%edx
  mov    $0x47,%eax
  sar    $0x2,%edi
  and    $0x3,%edx
  cmp    $0x2,%edx
  je     L34
  mov    $0x54,%eax
  cmp    $0x3,%edx
  je     L34
  cmp    $0x1,%edx
  sete   %al
  lea    0x41(%rax,%rax,1),%eax
L34:
  mov    %al,(%rsi)
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  jne    L10
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L28:
  mov    %rsi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void unpackkmer(uint32_t kmer, char *s, int k) {
  int i;
  uint32_t nt;
  for (i = 0; i < k; i++, s++) {
    nt = kmer & 0x3;
    kmer = kmer >> 2;
    switch (nt) {
    case 0:
      *s = 'A';
      break;
    case 1:
      *s = 'C';
      break;
    case 2:
      *s = 'G';
      break;
    case 3:
      *s = 'T';
      break;
    default:
      break;
    }
  }
  *s = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lflip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movzbl -0x15(%rbp),%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x16(%rbp),%eax
  mov    %al,-0xf(%rbp)
  movzbl -0x17(%rbp),%eax
  mov    %al,-0xe(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
long lflip(long x) {
  union {
    char b[4];
    long l;
  } in, out;
  in.l = x;
  out.b[0] = in.b[3];
  out.b[1] = in.b[2];
  out.b[2] = in.b[1];
  out.b[3] = in.b[0];
  return out.l;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lflip>:
  endbr64
  mov    %rdi,%rcx
  mov    %edi,%eax
  sar    $0x18,%eax
  mov    $0x0,%edx
  mov    %al,%dl
  mov    %edi,%eax
  shl    $0x8,%eax
  sar    $0x18,%eax
  mov    %al,%dh
  movzbl %ch,%esi
  shl    $0x10,%rsi
  mov    %rdx,%rax
  and    $0xffffffffff00ffff,%rax
  or     %rsi,%rax
  movzbl %dil,%ecx
  shl    $0x18,%rcx
  movabs $0xffffffff00ffffff,%rdx
  and    %rdx,%rax
  or     %rcx,%rax
  ret
```

assistant: ```c
long lflip(long x) {
  union {
    char b[4];
    long l;
  } in, out;
  in.l = x;
  out.b[0] = in.b[3];
  out.b[1] = in.b[2];
  out.b[2] = in.b[1];
  out.b[3] = in.b[0];
  return out.l;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lflip>:
  endbr64
  bswap  %edi
  mov    %edi,%eax
  ret
```

assistant: ```c
long lflip(long x) {
  union {
    char b[4];
    long l;
  } in, out;
  in.l = x;
  out.b[0] = in.b[3];
  out.b[1] = in.b[2];
  out.b[2] = in.b[1];
  out.b[3] = in.b[0];
  return out.l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lflip>:
  endbr64
  bswap  %edi
  mov    %edi,%eax
  ret
```

assistant: ```c
long lflip(long x) {
  union {
    char b[4];
    long l;
  } in, out;
  in.l = x;
  out.b[0] = in.b[3];
  out.b[1] = in.b[2];
  out.b[2] = in.b[1];
  out.b[3] = in.b[0];
  return out.l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<libmds_headers_cherrypick_binary_unsorted>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd0(%rbp),%rdx
  mov    -0xc0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc0(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <libmds_headers_cherrypick_binary_unsorted_v@plt>
  mov    %rax,-0xb8(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xbc(%rbp)
  mov    -0xc0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D14(%rip),%rax
  mov    -0xbc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t libmds_headers_cherrypick_binary_unsorted(char **restrict headers, size_t header_count, ...) {
  va_list args;
  size_t r;
  int saved_errno;
  va_start(args, header_count);
  r = libmds_headers_cherrypick_binary_unsorted_v(headers, header_count, args);
  saved_errno = errno;
  va_end(args);
  errno = saved_errno;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libmds_headers_cherrypick_binary_unsorted>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <libmds_headers_cherrypick_binary_unsorted_v@plt>
  mov    %rax,%rbx
  mov    D7(%rip),%r12
  mov    (%r12),%r13d
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13d,(%r12)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t libmds_headers_cherrypick_binary_unsorted(char **restrict headers, size_t header_count, ...) {
  va_list args;
  size_t r;
  int saved_errno;
  va_start(args, header_count);
  r = libmds_headers_cherrypick_binary_unsorted_v(headers, header_count, args);
  saved_errno = errno;
  va_end(args);
  errno = saved_errno;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<libmds_headers_cherrypick_binary_unsorted>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <libmds_headers_cherrypick_binary_unsorted_v@plt>
  mov    D0(%rip),%rbp
  mov    %r13d,%edi
  mov    %rax,%r12
  mov    0x0(%rbp),%ebx
  call   <va_end@plt>
  mov    %r12,%rax
  mov    %ebx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t libmds_headers_cherrypick_binary_unsorted(char **restrict headers, size_t header_count, ...) {
  va_list args;
  size_t r;
  int saved_errno;
  va_start(args, header_count);
  r = libmds_headers_cherrypick_binary_unsorted_v(headers, header_count, args);
  saved_errno = errno;
  va_end(args);
  errno = saved_errno;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<libmds_headers_cherrypick_binary_unsorted>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <libmds_headers_cherrypick_binary_unsorted_v@plt>
  mov    D6(%rip),%rbp
  mov    %r13d,%edi
  mov    %rax,%r12
  mov    0x0(%rbp),%ebx
  call   <va_end@plt>
  mov    %r12,%rax
  mov    %ebx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t libmds_headers_cherrypick_binary_unsorted(char **restrict headers, size_t header_count, ...) {
  va_list args;
  size_t r;
  int saved_errno;
  va_start(args, header_count);
  r = libmds_headers_cherrypick_binary_unsorted_v(headers, header_count, args);
  saved_errno = errno;
  va_end(args);
  errno = saved_errno;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<removePiece>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ClearGameBlock@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x3,-0x4(%rbp)
  jle    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void removePiece(int x, int y, const int piece[][2]) {
  {
    for (int coord = 0; coord < 4; ++coord) {
      ClearGameBlock(piece[coord][0] + x, piece[coord][1] + y);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<removePiece>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%rbx
  lea    0x20(%rdx),%r13
L8:
  mov    %ebp,%esi
  add    0x4(%rbx),%esi
  mov    %r12d,%edi
  add    (%rbx),%edi
  call   <ClearGameBlock@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void removePiece(int x, int y, const int piece[][2]) {
  {
    for (int coord = 0; coord < 4; ++coord) {
      ClearGameBlock(piece[coord][0] + x, piece[coord][1] + y);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removePiece>:
  endbr64
  push   %r13
  lea    0x20(%rdx),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
L4:
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    $0x8,%rbx
  add    %ebp,%esi
  add    %r12d,%edi
  call   <ClearGameBlock@plt>
  cmp    %r13,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void removePiece(int x, int y, const int piece[][2]) {
  {
    for (int coord = 0; coord < 4; ++coord) {
      ClearGameBlock(piece[coord][0] + x, piece[coord][1] + y);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<removePiece>:
  endbr64
  push   %r13
  lea    0x20(%rdx),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
L2:
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    $0x8,%rbx
  add    %ebp,%esi
  add    %r12d,%edi
  call   <ClearGameBlock@plt>
  cmp    %rbx,%r13
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void removePiece(int x, int y, const int piece[][2]) {
  {
    for (int coord = 0; coord < 4; ++coord) {
      ClearGameBlock(piece[coord][0] + x, piece[coord][1] + y);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str2num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %esi,-0x12c(%rbp)
  mov    %edx,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  cmpl   $0x0,-0x12c(%rbp)
  js     L96
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x12c(%rbp)
  jg     L96
  cmpl   $0xff,-0x130(%rbp)
  jle    L16
L96:
  pxor   %xmm0,%xmm0
  jmp    L68
L16:
  mov    -0x12c(%rbp),%eax
  cltq
  add    %rax,-0x128(%rbp)
  jmp    L103
L99:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x64,%al
  je     L121
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x44,%al
  je     L121
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%edx
  jmp    L86
L121:
  mov    $0x45,%edx
L86:
  mov    -0x118(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x118(%rbp)
  mov    %dl,(%rax)
  addq   $0x1,-0x128(%rbp)
L103:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  subl   $0x1,-0x130(%rbp)
  cmpl   $0x0,-0x130(%rbp)
  jns    L99
L42:
  mov    -0x118(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x120(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L39
  movsd  -0x120(%rbp),%xmm0
  jmp    L68
L39:
  pxor   %xmm0,%xmm0
L68:
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2: %lf

assistant: ```c
extern double str2num(const char *s, int i, int n) {
  double value;
  char str[256], *p = str;
  if (i < 0 || (int)strlen(s) < i || (int)sizeof(str) - 1 < n) {
    return 0.0;
  }
  for (s += i; *s && --n >= 0; s++) {
    *p++ = *s == 'd' || *s == 'D' ? 'E' : *s;
  }
  *p = '\0';
  return sscanf(str, "%lf", &value) == 1 ? value : 0.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<str2num>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  js     L53
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <strlen@plt>
  cmp    $0xff,%r12d
  jg     L14
  cmp    %eax,%ebp
  jg     L14
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L33
  test   %r12d,%r12d
  jle    L88
  lea    -0x1(%r12),%edx
  lea    0x11(%rsp,%rdx,1),%r8
  lea    0x10(%rsp),%rdx
  mov    $0x45,%edi
L103:
  mov    %eax,%esi
  and    $0xffffffdf,%esi
  cmp    $0x44,%sil
  cmove  %edi,%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  add    $0x1,%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L100
  cmp    %r8,%rdx
  jne    L103
  mov    %r8,%rdx
L100:
  movb   $0x0,(%rdx)
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  lea    D4(%rip),%rsi
  call   <sscanf@plt>
  pxor   %xmm0,%xmm0
  cmp    $0x1,%eax
  jne    L53
  movsd  0x8(%rsp),%xmm0
  jmp    L53
L33:
  lea    0x10(%rsp),%rdx
  jmp    L100
L88:
  lea    0x10(%rsp),%rdx
  jmp    L100
L14:
  pxor   %xmm0,%xmm0
L53:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: %lf

assistant: ```c
extern double str2num(const char *s, int i, int n) {
  double value;
  char str[256], *p = str;
  if (i < 0 || (int)strlen(s) < i || (int)sizeof(str) - 1 < n) {
    return 0.0;
  }
  for (s += i; *s && --n >= 0; s++) {
    *p++ = *s == 'd' || *s == 'D' ? 'E' : *s;
  }
  *p = '\0';
  return sscanf(str, "%lf", &value) == 1 ? value : 0.0;
}
```