user: What would the C source look like for the assembly code provided here?

```asm
<get_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  movsbl -0x2c(%rbp),%eax
  sub    $0x47,%eax
  cmp    $0xe,%eax
  ja     L102
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0x14(%rbp)
  jmp    L157
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L157
  movl   $0x3,-0x10(%rbp)
  movl   $0x4,-0x14(%rbp)
  jmp    L157
  movl   $0x4,-0x10(%rbp)
  movl   $0x5,-0x14(%rbp)
  jmp    L157
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0x14(%rbp)
  jmp    L157
  movl   $0x6,-0x10(%rbp)
  movl   $0x7,-0x14(%rbp)
  nop
L157:
  jmp    L102
L113:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L131
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x1c(%rbp)
  cmpl   $0x7,-0xc(%rbp)
  je     L131
  jmp    L102
L131:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L65
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L133
L65:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L144
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L144:
  mov    -0x8(%rbp),%rax
  jmp    L10
L133:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L87
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L87:
  addl   $0x1,-0x1c(%rbp)
L102:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L113
L10:
  leave
  ret
```

assistant: ```c
char *get_value(char *line, char flag) {
  int i = 0;
  int j = 0;
  int max, min;
  int count = 0;
  char *buffer = calloc(100, sizeof(char));
  bzero(buffer, 100);
  switch (flag) {
  case 'U':
    min = 2;
    max = 3;
    break;
  case 'L':
    min = 0;
    max = 1;
    break;
  case 'G':
    min = 3;
    max = 4;
    break;
  case 'N':
    min = 4;
    max = 5;
    break;
  case 'H':
    min = 5;
    max = 6;
    break;
  case 'S':
    min = 6;
    max = 7;
    break;
  }
  while (line[i] != '\0') {
    if (line[i] == ':') {
      count++;
      i++;
      if (count != 7)
        continue;
    }
    if (count == max || line[i + 1] == '\0') {
      if (buffer[strlen(buffer) - 1] == '\n') {
        buffer[strlen(buffer) - 1] = '\0';
      }
      return buffer;
    }
    if (count == min) {
      buffer[j] = line[i];
      j++;
    }
    i++;
  }
}
```