ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aes_cfbdec>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r9,0x8(%rsp)
  cmp    $0xf,%rdx
  jbe    L19
  mov    %rsi,%rax
  mov    %edi,%ebp
  mov    %rcx,%r12
  mov    %r8,%rsi
  mov    %rax,%r15
  lea    -0x10(%rdx),%rax
  mov    %r9,%rbx
  and    $0xfffffffffffffff0,%rax
  lea    0x10(%r9,%rax,1),%r13
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %ebp,%edi
  call   <aes_cipher@plt>
  movzbl (%r15),%eax
  xor    %al,(%rbx)
  mov    %r15,%rsi
  movzbl 0x1(%r15),%eax
  xor    %al,0x1(%rbx)
  add    $0x10,%r15
  movzbl -0xe(%r15),%eax
  xor    %al,0x2(%rbx)
  movzbl -0xd(%r15),%eax
  xor    %al,0x3(%rbx)
  movzbl -0xc(%r15),%eax
  xor    %al,0x4(%rbx)
  movzbl -0xb(%r15),%eax
  xor    %al,0x5(%rbx)
  movzbl -0xa(%r15),%eax
  xor    %al,0x6(%rbx)
  movzbl -0x9(%r15),%eax
  xor    %al,0x7(%rbx)
  movzbl -0x8(%r15),%eax
  xor    %al,0x8(%rbx)
  movzbl -0x7(%r15),%eax
  xor    %al,0x9(%rbx)
  movzbl -0x6(%r15),%eax
  xor    %al,0xa(%rbx)
  movzbl -0x5(%r15),%eax
  xor    %al,0xb(%rbx)
  movzbl -0x4(%r15),%eax
  xor    %al,0xc(%rbx)
  movzbl -0x3(%r15),%eax
  xor    %al,0xd(%rbx)
  movzbl -0x2(%r15),%eax
  xor    %al,0xe(%rbx)
  movzbl -0x1(%r15),%eax
  xor    %al,0xf(%rbx)
  add    $0x10,%rbx
  cmp    %rbx,%r13
  jne    L12
L19:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  mov    %r14,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <aes_calclength@plt>
```

assistant: ```c
size_t aes_cfbdec(const int bits, const char *in, const size_t length, const char *key, const char *iv, char *out) {
  const char *vector = iv;
  for (size_t d = 0; d + 15 < length; d += 16) {
    aes_cipher(bits, vector, key, out + d);
    for (short i = 0; i < 16; i++)
      *(out + d + i) ^= *(in + d + i);
    vector = in + d;
  }
  return aes_calclength(out, length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rtsp_basic_auth_get_username_password>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L61
L32:
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rtsp_get_header@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L59
  mov    $0x0,%eax
  jmp    L61
L59:
  mov    -0x20(%rbp),%rax
  mov    $0x6,%edx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L75
  mov    $0x0,%eax
  jmp    L61
L75:
  mov    -0x20(%rbp),%rax
  add    $0x6,%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rtsp_decode_base64@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L66
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L61
L66:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L61:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D3
type: string

tool: D16: Authorization

tool: D3: Basic 

assistant: ```c
char *rtsp_basic_auth_get_username_password(struct rtsp_client *c, char **password) {
  const char *auth;
  char *decoded;
  char *username;
  char *p;
  if (c == NULL)
    return NULL;
  auth = rtsp_get_header(c, "Authorization", 0);
  if (auth == NULL)
    return NULL;
  if (strncmp(auth, "Basic ", 6) != 0)
    return NULL;
  decoded = strdup(auth + 6);
  rtsp_decode_base64(decoded);
  p = strchr(decoded, ':');
  if (p == NULL) {
    free(decoded);
    return NULL;
  }
  *p++ = '\0';
  username = strdup(decoded);
  *password = strdup(p);
  free(decoded);
  return username;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtsp_basic_auth_get_username_password>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L65
  mov    %rsi,%r12
  mov    $0x0,%edx
  lea    D15(%rip),%rsi
  call   <rtsp_get_header@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
  mov    $0x6,%edx
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L47
  lea    0x6(%rbx),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <rtsp_decode_base64@plt>
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L60
  lea    0x1(%rax),%r13
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  mov    %rbp,%rdi
  call   <free@plt>
L24:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L24
L65:
  mov    %rdi,%rbx
  jmp    L24
L47:
  mov    $0x0,%ebx
  jmp    L24
```

tool_calls: name: read_data
arguments: tag: D15
datatype: string
name: read_data
arguments: tag: D11
datatype: string

tool: D15: Authorization

tool: D11: Basic 

assistant: ```c
char *rtsp_basic_auth_get_username_password(struct rtsp_client *c, char **password) {
  const char *auth;
  char *decoded;
  char *username;
  char *p;
  if (c == NULL)
    return NULL;
  auth = rtsp_get_header(c, "Authorization", 0);
  if (auth == NULL)
    return NULL;
  if (strncmp(auth, "Basic ", 6) != 0)
    return NULL;
  decoded = strdup(auth + 6);
  rtsp_decode_base64(decoded);
  p = strchr(decoded, ':');
  if (p == NULL) {
    free(decoded);
    return NULL;
  }
  *p++ = '\0';
  username = strdup(decoded);
  *password = strdup(p);
  free(decoded);
  return username;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtsp_basic_auth_get_username_password>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L5
  mov    %rsi,%rbx
  xor    %edx,%edx
  lea    D16(%rip),%rsi
  call   <rtsp_get_header@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    $0x6,%edx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L5
  lea    0x6(%r12),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <rtsp_decode_base64@plt>
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
  movb   $0x0,(%rax)
  lea    0x1(%rax),%r13
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strdup@plt>
  mov    %rax,(%rbx)
L39:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string

tool: D16: Authorization

tool: D10: Basic 

assistant: ```c
char *rtsp_basic_auth_get_username_password(struct rtsp_client *c, char **password) {
  const char *auth;
  char *decoded;
  char *username;
  char *p;
  if (c == NULL)
    return NULL;
  auth = rtsp_get_header(c, "Authorization", 0);
  if (auth == NULL)
    return NULL;
  if (strncmp(auth, "Basic ", 6) != 0)
    return NULL;
  decoded = strdup(auth + 6);
  rtsp_decode_base64(decoded);
  p = strchr(decoded, ':');
  if (p == NULL) {
    free(decoded);
    return NULL;
  }
  *p++ = '\0';
  username = strdup(decoded);
  *password = strdup(p);
  free(decoded);
  return username;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rtsp_basic_auth_get_username_password>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  mov    %rsi,%rbx
  xor    %edx,%edx
  lea    D7(%rip),%rsi
  call   <rtsp_get_header@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    $0x6,%edx
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L17
  lea    0x6(%r12),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <rtsp_decode_base64@plt>
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L33
  movb   $0x0,(%rax)
  lea    0x1(%rax),%r13
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strdup@plt>
  mov    %rax,(%rbx)
L33:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D12
type_infered: string

tool: D7: Authorization

tool: D12: Basic 

assistant: ```c
char *rtsp_basic_auth_get_username_password(struct rtsp_client *c, char **password) {
  const char *auth;
  char *decoded;
  char *username;
  char *p;
  if (c == NULL)
    return NULL;
  auth = rtsp_get_header(c, "Authorization", 0);
  if (auth == NULL)
    return NULL;
  if (strncmp(auth, "Basic ", 6) != 0)
    return NULL;
  decoded = strdup(auth + 6);
  rtsp_decode_base64(decoded);
  p = strchr(decoded, ':');
  if (p == NULL) {
    free(decoded);
    return NULL;
  }
  *p++ = '\0';
  username = strdup(decoded);
  *password = strdup(p);
  free(decoded);
  return username;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L15:
  mov    D7(%rip),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%ecx
  mov    D27(%rip),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    D27(%rip),%rdx
  cltq
  movzbl (%rdx,%rax,1),%eax
  test   %al,%al
  jne    L27
  movl   $0xffffffff,-0x4(%rbp)
L27:
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copia(void) {
  int i;
  extern char linea[], linea_max[];
  i = 0;
  while (i >= 0) {
    linea_max[i] = linea[i];
    if (linea_max[i++] == '\0')
      i = -1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copia>:
  endbr64
  mov    $0x0,%eax
  mov    D4(%rip),%rsi
  mov    D19(%rip),%rcx
L6:
  movzbl (%rax,%rsi,1),%edx
  mov    %dl,(%rax,%rcx,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L6
  ret
```

assistant: ```c
void copia(void) {
  int i;
  extern char linea[], linea_max[];
  i = 0;
  while (i >= 0) {
    linea_max[i] = linea[i];
    if (linea_max[i++] == '\0')
      i = -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copia>:
  endbr64
  mov    D18(%rip),%rsi
  mov    D2(%rip),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L2:
  movzbl (%rax,%rsi,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax,%rcx,1)
  test   %dl,%dl
  jne    L2
  ret
```

assistant: ```c
void copia(void) {
  int i;
  extern char linea[], linea_max[];
  i = 0;
  while (i >= 0) {
    linea_max[i] = linea[i];
    if (linea_max[i++] == '\0')
      i = -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copia>:
  endbr64
  mov    D10(%rip),%rsi
  mov    D13(%rip),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L5:
  movzbl (%rax,%rsi,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax,%rcx,1)
  test   %dl,%dl
  jne    L5
  ret
```

assistant: ```c
void copia(void) {
  int i;
  extern char linea[], linea_max[];
  i = 0;
  while (i >= 0) {
    linea_max[i] = linea[i];
    if (linea_max[i++] == '\0')
      i = -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sync_find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  movl   $0x12,-0x2c(%rbp)
  mov    %rbx,%rax
  lea    0x8(%rax),%rbx
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L70
L37:
  mov    %rbx,%rax
  lea    0x8(%rax),%rbx
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L42
L56:
  mov    -0x20(%rbp),%rax
  mov    $0x3e4ba81b,%esi
  mov    %rax,%rdi
  call   <comp32@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jg     L35
  mov    %rbx,%rax
  jmp    L74
L35:
  mov    -0x20(%rbp),%rax
  mov    $0xaaaaaaaa,%esi
  mov    %rax,%rdi
  call   <comp32@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jle    L34
  cmpl   $0x1d,-0x24(%rbp)
  jle    L82
L34:
  mov    -0x28(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x13,-0x2c(%rbp)
  jmp    L45
L82:
  mov    -0x20(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  shr    $0x1f,%rax
  or     %rdx,%rax
  mov    %rax,-0x20(%rbp)
  shlq   -0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
L42:
  cmpl   $0x1f,-0x28(%rbp)
  jle    L56
L45:
  subl   $0x1,-0x2c(%rbp)
L70:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L37
  mov    $0x0,%eax
L74:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long int *sync_find(register unsigned long int *dptr) {
  int num_err;
  int sync_window = 18;
  int bit_cnt;
  unsigned long int sample1, sample2;
  sample1 = *dptr++;
  while (sync_window > 0) {
    sample2 = *dptr++;
    bit_cnt = 0;
    while (bit_cnt < 32) {
      num_err = comp32(sample1, 0x3e4ba81b);
      if (num_err <= 2)
        return (dptr);
      num_err = comp32(sample1, 0xaaaaaaaa);
      if ((num_err <= 2) || (num_err >= 30)) {
        sample1 = sample2 >> bit_cnt;
        sync_window = 19;
        break;
      } else {
        sample1 = (sample1 << 1) | (sample2 >> 31);
        sample2 = sample2 << 1;
      }
      bit_cnt++;
    }
    sync_window--;
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_find>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rdi),%r13
  mov    (%rdi),%rbx
  mov    $0x12,%r14d
L33:
  add    $0x8,%r13
  mov    -0x8(%r13),%r12
  mov    $0x0,%ebp
L37:
  mov    $0x3e4ba81b,%esi
  mov    %rbx,%rdi
  call   <comp32@plt>
  cmp    $0x2,%eax
  jle    L38
  mov    $0xaaaaaaaa,%esi
  mov    %rbx,%rdi
  call   <comp32@plt>
  sub    $0x3,%eax
  cmp    $0x1a,%eax
  ja     L43
  add    %rbx,%rbx
  mov    %r12,%rax
  shr    $0x1f,%rax
  or     %rax,%rbx
  add    %r12,%r12
  add    $0x1,%ebp
  cmp    $0x20,%ebp
  jne    L37
  sub    $0x1,%r14d
  test   %r14d,%r14d
  jg     L33
  mov    $0x0,%r13d
L38:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  mov    %r12,%rbx
  mov    %ebp,%ecx
  shr    %cl,%rbx
  mov    $0x12,%r14d
  jmp    L33
```

assistant: ```c
unsigned long int *sync_find(register unsigned long int *dptr) {
  int num_err;
  int sync_window = 18;
  int bit_cnt;
  unsigned long int sample1, sample2;
  sample1 = *dptr++;
  while (sync_window > 0) {
    sample2 = *dptr++;
    bit_cnt = 0;
    while (bit_cnt < 32) {
      num_err = comp32(sample1, 0x3e4ba81b);
      if (num_err <= 2)
        return (dptr);
      num_err = comp32(sample1, 0xaaaaaaaa);
      if ((num_err <= 2) || (num_err >= 30)) {
        sample1 = sample2 >> bit_cnt;
        sync_window = 19;
        break;
      } else {
        sample1 = (sample1 << 1) | (sample2 >> 31);
        sample2 = sample2 << 1;
      }
      bit_cnt++;
    }
    sync_window--;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sync_find>:
  endbr64
  push   %r14
  mov    $0x12,%r14d
  push   %r13
  lea    0x8(%rdi),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rbx
L52:
  add    $0x8,%r13
  xor    %ebp,%ebp
  mov    -0x8(%r13),%r12
  jmp    L14
  nopl   (%rax)
L42:
  mov    $0xaaaaaaaa,%esi
  mov    %rbx,%rdi
  call   <comp32@plt>
  sub    $0x3,%eax
  cmp    $0x1a,%eax
  ja     L11
  mov    %r12,%rax
  add    %rbx,%rbx
  add    $0x1,%ebp
  add    %r12,%r12
  shr    $0x1f,%rax
  or     %rax,%rbx
  cmp    $0x20,%ebp
  je     L0
L14:
  mov    $0x3e4ba81b,%esi
  mov    %rbx,%rdi
  call   <comp32@plt>
  cmp    $0x2,%eax
  jg     L42
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r12,%rbx
  mov    %ebp,%ecx
  mov    $0x12,%r14d
  shr    %cl,%rbx
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x1,%r14d
  jne    L52
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long int *sync_find(register unsigned long int *dptr) {
  int num_err;
  int sync_window = 18;
  int bit_cnt;
  unsigned long int sample1, sample2;
  sample1 = *dptr++;
  while (sync_window > 0) {
    sample2 = *dptr++;
    bit_cnt = 0;
    while (bit_cnt < 32) {
      num_err = comp32(sample1, 0x3e4ba81b);
      if (num_err <= 2)
        return (dptr);
      num_err = comp32(sample1, 0xaaaaaaaa);
      if ((num_err <= 2) || (num_err >= 30)) {
        sample1 = sample2 >> bit_cnt;
        sync_window = 19;
        break;
      } else {
        sample1 = (sample1 << 1) | (sample2 >> 31);
        sample2 = sample2 << 1;
      }
      bit_cnt++;
    }
    sync_window--;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sync_find>:
  endbr64
  push   %r14
  mov    $0x12,%r14d
  push   %r13
  lea    0x8(%rdi),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rbx
L11:
  add    $0x8,%r13
  xor    %ebp,%ebp
  mov    -0x8(%r13),%r12
  jmp    L0
  nopl   (%rax)
L4:
  mov    $0xaaaaaaaa,%esi
  mov    %rbx,%rdi
  call   <comp32@plt>
  sub    $0x3,%eax
  cmp    $0x1a,%eax
  ja     L42
  mov    %r12,%rax
  add    %rbx,%rbx
  add    $0x1,%ebp
  add    %r12,%r12
  shr    $0x1f,%rax
  or     %rax,%rbx
  cmp    $0x20,%ebp
  je     L16
L0:
  mov    $0x3e4ba81b,%esi
  mov    %rbx,%rdi
  call   <comp32@plt>
  cmp    $0x2,%eax
  jg     L4
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r12,%rbx
  mov    %ebp,%ecx
  mov    $0x12,%r14d
  shr    %cl,%rbx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L16:
  sub    $0x1,%r14d
  jne    L11
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long int *sync_find(register unsigned long int *dptr) {
  int num_err;
  int sync_window = 18;
  int bit_cnt;
  unsigned long int sample1, sample2;
  sample1 = *dptr++;
  while (sync_window > 0) {
    sample2 = *dptr++;
    bit_cnt = 0;
    while (bit_cnt < 32) {
      num_err = comp32(sample1, 0x3e4ba81b);
      if (num_err <= 2)
        return (dptr);
      num_err = comp32(sample1, 0xaaaaaaaa);
      if ((num_err <= 2) || (num_err >= 30)) {
        sample1 = sample2 >> bit_cnt;
        sync_window = 19;
        break;
      } else {
        sample1 = (sample1 << 1) | (sample2 >> 31);
        sample2 = sample2 << 1;
      }
      bit_cnt++;
    }
    sync_window--;
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fetch16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bswap32@plt>
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint16_t fetch16(char *data, bool swap) {
  uint16_t tmp = *(uint16_t *)data;
  if (swap)
    tmp = bswap32(tmp);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fetch16>:
  endbr64
  mov    (%rdi),%eax
  test   %esi,%esi
  jne    L3
  ret
L3:
  sub    $0x8,%rsp
  mov    %eax,%edi
  call   <bswap32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t fetch16(char *data, bool swap) {
  uint16_t tmp = *(uint16_t *)data;
  if (swap)
    tmp = bswap32(tmp);
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fetch16>:
  endbr64
  mov    (%rdi),%eax
  test   %esi,%esi
  jne    L2
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %eax,%edi
  jmp    1050 <bswap32@plt>
```

assistant: ```c
uint16_t fetch16(char *data, bool swap) {
  uint16_t tmp = *(uint16_t *)data;
  if (swap)
    tmp = bswap32(tmp);
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fetch16>:
  endbr64
  mov    (%rdi),%eax
  test   %esi,%esi
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %eax,%edi
  jmp    1050 <bswap32@plt>
```

assistant: ```c
uint16_t fetch16(char *data, bool swap) {
  uint16_t tmp = *(uint16_t *)data;
  if (swap)
    tmp = bswap32(tmp);
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  fldz
  fstpt  -0x30(%rbp)
  fld1
  fstpt  -0x20(%rbp)
  movl   $0x1,-0x34(%rbp)
  jmp    L17
L9:
  fld1
  fldt   -0x20(%rbp)
  fdivrp %st,%st(1)
  fldt   -0x30(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x30(%rbp)
  mov    -0x34(%rbp),%eax
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x34(%rbp)
  fldt   -0x20(%rbp)
  fadd   %st(0),%st
  fstpt  -0x20(%rbp)
L17:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D28
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D7: Enter the number of terms you want: 

tool: D28: %d

tool: D2: time = %Lf when terms = %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int t_ct;
  int limit;
  long double time, x;
  printf("Enter the number of terms you want: ");
  scanf("%d", &limit);
  for (time = 0, x = 1, t_ct = 1; t_ct <= limit; t_ct++, x *= 2.0) {
    time += 1.0 / x;
    printf("time = %Lf when terms = %d\n", time, t_ct);
  }
  return 0;
}
```