ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  cmp    %edx,%esi
  jge    L9
  movslq %esi,%rsi
  movslq %edx,%rdx
L11:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rsi
  sub    $0x1,%rdx
  cmp    %edx,%esi
  jl     L11
L9:
  ret
```

assistant: ```c
void reverse(char *s, int i, int j) {
  char temp;
  while (i < j) {
    temp = s[i];
    s[i] = s[j];
    s[j] = temp;
    i++;
    j--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  cmp    %edx,%esi
  jge    L7
  movslq %esi,%rsi
  movslq %edx,%rdx
  xchg   %ax,%ax
L3:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  add    $0x1,%rsi
  mov    %al,(%rdi,%rdx,1)
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jg     L3
L7:
  ret
```

assistant: ```c
void reverse(char *s, int i, int j) {
  char temp;
  while (i < j) {
    temp = s[i];
    s[i] = s[j];
    s[j] = temp;
    i++;
    j--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  cmp    %edx,%esi
  jge    L13
  movslq %esi,%rsi
  movslq %edx,%rdx
  xchg   %ax,%ax
L11:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  add    $0x1,%rsi
  mov    %al,(%rdi,%rdx,1)
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jg     L11
L13:
  ret
```

assistant: ```c
void reverse(char *s, int i, int j) {
  char temp;
  while (i < j) {
    temp = s[i];
    s[i] = s[j];
    s[j] = temp;
    i++;
    j--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tc2pts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r8
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L2
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L2:
  mov    -0x14(%rbp),%eax
  imul   $0x134fd900,%eax,%edx
  mov    -0x10(%rbp),%eax
  imul   $0x5265c0,%eax,%eax
  add    %eax,%edx
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D9
type_infered: f64

tool: D29: %d:%d:%f

tool: D2: Timecode '%s' format error

tool: D9: 90000

assistant: ```c
uint_fast32_t tc2pts(char *tc) {
  int h, m;
  float sms;
  if (sscanf(tc, "%d:%d:%f", &h, &m, &sms) != 3)
    die("Timecode '%s' format error", tc);
  return h * 3600 * 90000 + m * 60 * 90000 + (int)(sms * 90000.0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tc2pts>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  lea    D14(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L6
L19:
  imul   $0x134fd900,0xc(%rsp),%eax
  imul   $0x5265c0,0x10(%rsp),%edx
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtss2sd 0x14(%rsp),%xmm0
  mulsd  D1(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  mov    %rbx,%rsi
  lea    D21(%rip),%rdi
  call   <die@plt>
  jmp    L19
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: f64
name: disassemble_data
arguments: tag: D21
datatype: string

tool: D14: %d:%d:%f

tool: D1: 90000

tool: D21: Timecode '%s' format error

assistant: ```c
uint_fast32_t tc2pts(char *tc) {
  int h, m;
  float sms;
  if (sscanf(tc, "%d:%d:%f", &h, &m, &sms) != 3)
    die("Timecode '%s' format error", tc);
  return h * 3600 * 90000 + m * 60 * 90000 + (int)(sms * 90000.0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tc2pts>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rsi
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L19
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <die@plt>
L19:
  pxor   %xmm0,%xmm0
  imul   $0x5265c0,0x10(%rsp),%edx
  cvtss2sd 0x14(%rsp),%xmm0
  mulsd  D20(%rip),%xmm0
  imul   $0x134fd900,0xc(%rsp),%eax
  add    %edx,%eax
  cvttsd2si %xmm0,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x20,%rsp
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D20
type_infered: f64

tool: D5: %d:%d:%f

tool: D7: Timecode '%s' format error

tool: D20: 90000

assistant: ```c
uint_fast32_t tc2pts(char *tc) {
  int h, m;
  float sms;
  if (sscanf(tc, "%d:%d:%f", &h, &m, &sms) != 3)
    die("Timecode '%s' format error", tc);
  return h * 3600 * 90000 + m * 60 * 90000 + (int)(sms * 90000.0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tc2pts>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L6
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <die@plt>
L6:
  pxor   %xmm0,%xmm0
  imul   $0x5265c0,0x10(%rsp),%edx
  cvtss2sd 0x14(%rsp),%xmm0
  mulsd  D18(%rip),%xmm0
  imul   $0x134fd900,0xc(%rsp),%eax
  add    %edx,%eax
  cvttsd2si %xmm0,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x20,%rsp
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string
name: unpack_data
arguments: data_label: D17
datatype: string
name: unpack_data
arguments: data_label: D18
datatype: f64

tool: D4: %d:%d:%f

tool: D17: Timecode '%s' format error

tool: D18: 90000

assistant: ```c
uint_fast32_t tc2pts(char *tc) {
  int h, m;
  float sms;
  if (sscanf(tc, "%d:%d:%f", &h, &m, &sms) != 3)
    die("Timecode '%s' format error", tc);
  return h * 3600 * 90000 + m * 60 * 90000 + (int)(sms * 90000.0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ncctop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdx,%r8
  mov    %rcx,%r9
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rsi,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L139:
  cmp    %rdx,%rsp
  je     L2
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L139
L2:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L145
  orq    $0x0,-0x8(%rsp,%rax,1)
L145:
  mov    %rsp,%rdx
  lea    0xf(,%rdi,8),%rax
  mov    %rax,%r10
  and    $0xfffffffffffffff0,%r10
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L64:
  cmp    %rcx,%rsp
  je     L8
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L64
L8:
  mov    %r10,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L76
  orq    $0x0,-0x8(%rsp,%rax,1)
L76:
  mov    %rsp,%rcx
  test   %rsi,%rsi
  jle    L141
  mov    $0x0,%eax
  movsd  D18(%rip),%xmm2
L102:
  movapd %xmm2,%xmm1
  mulsd  (%r9,%rax,8),%xmm1
  addsd  (%r8,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L102
L141:
  test   %rdi,%rdi
  jle    L128
  mov    $0x0,%eax
  movsd  D14(%rip),%xmm2
L52:
  movsd  (%rdx,%rax,8),%xmm1
  add    $0x1,%rax
  addsd  (%rdx,%rax,8),%xmm1
  mulsd  %xmm2,%xmm1
  movsd  %xmm1,-0x8(%rcx,%rax,8)
  cmp    %rdi,%rax
  jne    L52
  mov    $0x0,%eax
  jmp    L37
L122:
  mov    %rdx,%rax
L37:
  movsd  (%rcx,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  jae    L95
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rdi
  jne    L122
L95:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  leave
  ret
L128:
  mov    $0x0,%eax
  jmp    L95
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_infered: f64
name: parse_data
arguments: data_tag: D14
type_infered: f64

tool: D18: 101320

tool: D14: 0.5

assistant: ```c
long ncctop(double cptop, long nlev, long nlevp1, double *vct_a, double *vct_b) {
  long nctop = 0;
  long jk;
  double za, zb, zph[nlevp1], zp[nlev];
  for (jk = 0; jk < nlevp1; ++jk) {
    za = vct_a[jk];
    zb = vct_b[jk];
    zph[jk] = za + zb * 101320.;
  }
  for (jk = 0; jk < nlev; ++jk)
    zp[jk] = (zph[jk] + zph[jk + 1]) * 0.5;
  for (jk = 0; jk < nlev; ++jk) {
    nctop = jk;
    if (zp[jk] >= cptop)
      break;
  }
  return (nctop);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ncctop>:
  endbr64
  push   %rbp
  mov    %rdx,%r8
  mov    %rcx,%r9
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rsi,8),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L76
L74:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L74
L76:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L55
L121:
  lea    0xf(,%rdi,8),%rax
  lea    0x7(%rsp),%rdx
  mov    %rsp,%r11
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rdx,%r10
  and    $0xfffffffffffffff8,%rdx
  sub    %rax,%r11
  shr    $0x3,%r10
  and    $0xfffffffffffffff0,%rcx
  cmp    %r11,%rsp
  je     L150
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r11,%rsp
  jne    L21
L150:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L90
L30:
  movsd  D5(%rip),%xmm2
  mov    %rsp,%rcx
  xor    %eax,%eax
  test   %rsi,%rsi
  jle    L106
  nopl   0x0(%rax)
L78:
  movsd  (%r9,%rax,8),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  (%r8,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L78
L106:
  xor    %eax,%eax
  test   %rdi,%rdi
  jle    L43
  movsd  0x0(,%r10,8),%xmm2
  movsd  D6(%rip),%xmm3
  xor    %eax,%eax
  nopl   0x0(%rax)
L40:
  add    $0x1,%rax
  movapd %xmm2,%xmm1
  movsd  (%rdx,%rax,8),%xmm2
  addsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  movsd  %xmm1,-0x8(%rcx,%rax,8)
  cmp    %rdi,%rax
  jne    L40
  xor    %eax,%eax
  jmp    L141
  nopl   0x0(%rax)
L0:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rdi
  je     L43
  mov    %rdx,%rax
L141:
  movsd  (%rcx,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  jb     L0
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L132
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L121
L90:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L30
L132:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: f64
name: disassemble_data
arguments: data_tag: D6
datatype: f64

tool: D5: 101320

tool: D6: 0.5

assistant: ```c
long ncctop(double cptop, long nlev, long nlevp1, double *vct_a, double *vct_b) {
  long nctop = 0;
  long jk;
  double za, zb, zph[nlevp1], zp[nlev];
  for (jk = 0; jk < nlevp1; ++jk) {
    za = vct_a[jk];
    zb = vct_b[jk];
    zph[jk] = za + zb * 101320.;
  }
  for (jk = 0; jk < nlev; ++jk)
    zp[jk] = (zph[jk] + zph[jk + 1]) * 0.5;
  for (jk = 0; jk < nlev; ++jk) {
    nctop = jk;
    if (zp[jk] >= cptop)
      break;
  }
  return (nctop);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getrlimit@plt>
  movl   $0x1,-0xc(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <setrlimit@plt>
L7:
  jmp    L7
```

assistant: ```c
int main() {
  struct rlimit rl;
  getrlimit(RLIMIT_CPU, &rl);
  rl.rlim_cur = 1;
  setrlimit(RLIMIT_CPU, &rl);
  while (1)
    ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    D2(%rip),%rbx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <getrlimit@plt>
  movl   $0x1,0x4(%rsp)
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <setrlimit@plt>
L6:
  jmp    L6
```

assistant: ```c
int main() {
  struct rlimit rl;
  getrlimit(RLIMIT_CPU, &rl);
  rl.rlim_cur = 1;
  setrlimit(RLIMIT_CPU, &rl);
  while (1)
    ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D5(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  call   <getrlimit@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  movl   $0x1,0x4(%rsp)
  call   <setrlimit@plt>
L0:
  jmp    L0
```

assistant: ```c
int main() {
  struct rlimit rl;
  getrlimit(RLIMIT_CPU, &rl);
  rl.rlim_cur = 1;
  setrlimit(RLIMIT_CPU, &rl);
  while (1)
    ;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D1(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  call   <getrlimit@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  movl   $0x1,0x4(%rsp)
  call   <setrlimit@plt>
L2:
  jmp    L2
```

assistant: ```c
int main() {
  struct rlimit rl;
  getrlimit(RLIMIT_CPU, &rl);
  rl.rlim_cur = 1;
  setrlimit(RLIMIT_CPU, &rl);
  while (1)
    ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_hashnr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L6
L7:
  mov    -0x18(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  add    %edx,%eax
  xor    %eax,-0x18(%rbp)
  addl   $0x3,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L7
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calc_hashnr(const void *key, const int key_len) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int nr = 1, nr2 = 4;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    nr ^= (((nr & 63) + nr2) * (*pKey)) + (nr << 8);
    nr2 += 3;
  }
  return nr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calc_hashnr>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  je     L21
  mov    $0x4,%ecx
  mov    $0x1,%edx
L13:
  mov    %edx,%eax
  and    $0x3f,%eax
  add    %ecx,%eax
  movzbl (%rdi),%r8d
  imul   %r8d,%eax
  mov    %edx,%r8d
  shl    $0x8,%r8d
  add    %r8d,%eax
  xor    %eax,%edx
  add    $0x3,%ecx
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L13
L1:
  mov    %edx,%eax
  ret
L21:
  mov    $0x1,%edx
  jmp    L1
```

assistant: ```c
int calc_hashnr(const void *key, const int key_len) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int nr = 1, nr2 = 4;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    nr ^= (((nr & 63) + nr2) * (*pKey)) + (nr << 8);
    nr2 += 3;
  }
  return nr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_hashnr>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  je     L19
  mov    $0x4,%edx
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r8d,%eax
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  and    $0x3f,%eax
  add    %edx,%eax
  add    $0x3,%edx
  imul   %ecx,%eax
  mov    %r8d,%ecx
  shl    $0x8,%ecx
  add    %ecx,%eax
  xor    %eax,%r8d
  cmp    %rdi,%rsi
  jne    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calc_hashnr(const void *key, const int key_len) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int nr = 1, nr2 = 4;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    nr ^= (((nr & 63) + nr2) * (*pKey)) + (nr << 8);
    nr2 += 3;
  }
  return nr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calc_hashnr>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  je     L10
  mov    $0x4,%edx
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r8d,%eax
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  and    $0x3f,%eax
  add    %edx,%eax
  add    $0x3,%edx
  imul   %ecx,%eax
  mov    %r8d,%ecx
  shl    $0x8,%ecx
  add    %ecx,%eax
  xor    %eax,%r8d
  cmp    %rdi,%rsi
  jne    L9
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calc_hashnr(const void *key, const int key_len) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int nr = 1, nr2 = 4;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    nr ^= (((nr & 63) + nr2) * (*pKey)) + (nr << 8);
    nr2 += 3;
  }
  return nr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<io>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <now@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L19
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addl   $0x1,-0x28(%rbp)
L19:
  cmpl   $0xf423f,-0x28(%rbp)
  jle    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  call   <now@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D37
type_infered: string
name: unpack_data
arguments: tag: D48
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D34
type_infered: string

tool: D37: r

tool: D48: /dev/urandom

tool: D16: w

tool: D10: /tmp/test

tool: D34: I/O benchmark time: %.04f


assistant: ```c
void io() {
  double start = now();
  int i;
  FILE *in = fopen("/dev/urandom", "r");
  FILE *out = fopen("/tmp/test", "w");
  for (i = 0; (i < 1000000); i++) {
    int ch = fgetc(in);
    fputc(ch, out);
  }
  fclose(in);
  fclose(out);
  double end = now();
  printf("I/O benchmark time: %.04f\r\n", end - start);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<io>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <now@plt>
  movq   %xmm0,%r14
  lea    D1(%rip),%rsi
  lea    D34(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  lea    D38(%rip),%rsi
  lea    D47(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0xf4240,%ebx
L6:
  mov    %r12,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  call   <now@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string

tool: D1: r

tool: D34: /dev/urandom

tool: D38: w

tool: D47: /tmp/test

tool: D11: I/O benchmark time: %.04f


assistant: ```c
void io() {
  double start = now();
  int i;
  FILE *in = fopen("/dev/urandom", "r");
  FILE *out = fopen("/tmp/test", "w");
  for (i = 0; (i < 1000000); i++) {
    int ch = fgetc(in);
    fputc(ch, out);
  }
  fclose(in);
  fclose(out);
  double end = now();
  printf("I/O benchmark time: %.04f\r\n", end - start);
}
```
user: Translate the below assembly code into C programming language:

```asm
<io>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x10,%rsp
  call   <now@plt>
  lea    D15(%rip),%rsi
  lea    D13(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <fopen@plt>
  lea    D48(%rip),%rsi
  lea    D34(%rip),%rdi
  mov    %rax,%r12
  call   <fopen@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  call   <now@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  lea    D18(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10b0 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D48
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string

tool: D15: r

tool: D13: /dev/urandom

tool: D48: w

tool: D34: /tmp/test

tool: D18: I/O benchmark time: %.04f


assistant: ```c
void io() {
  double start = now();
  int i;
  FILE *in = fopen("/dev/urandom", "r");
  FILE *out = fopen("/tmp/test", "w");
  for (i = 0; (i < 1000000); i++) {
    int ch = fgetc(in);
    fputc(ch, out);
  }
  fclose(in);
  fclose(out);
  double end = now();
  printf("I/O benchmark time: %.04f\r\n", end - start);
}
```