ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<p_caller>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <sourceA@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <sourceB@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <two_arg_sink_caller_p@plt>
  nop
  leave
  ret
```

assistant: ```c
int p_caller() {
  int a = sourceA();
  int b = sourceB();
  two_arg_sink_caller_p(a, b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<p_caller>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <sourceA@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <sourceB@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <two_arg_sink_caller_p@plt>
  pop    %rbx
  ret
```

assistant: ```c
int p_caller() {
  int a = sourceA();
  int b = sourceB();
  two_arg_sink_caller_p(a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<p_caller>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <sourceA@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <sourceB@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1090 <two_arg_sink_caller_p@plt>
```

assistant: ```c
int p_caller() {
  int a = sourceA();
  int b = sourceB();
  two_arg_sink_caller_p(a, b);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<p_caller>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <sourceA@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <sourceB@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1090 <two_arg_sink_caller_p@plt>
```

assistant: ```c
int p_caller() {
  int a = sourceA();
  int b = sourceB();
  two_arg_sink_caller_p(a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addq   $0x4,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int nseqs, int *arr) {
  int t = 0;
  for (int i = 0; i < nseqs; i++) {
    t += *arr;
    arr++;
  }
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sum>:
  endbr64
  test   %edi,%edi
  jle    L17
  mov    %edi,%edi
  lea    (%rsi,%rdi,4),%rdx
  mov    $0x0,%eax
L11:
  add    (%rsi),%eax
  add    $0x4,%rsi
  cmp    %rdx,%rsi
  jne    L11
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int sum(int nseqs, int *arr) {
  int t = 0;
  for (int i = 0; i < nseqs; i++) {
    t += *arr;
    arr++;
  }
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sum>:
  endbr64
  test   %edi,%edi
  jle    L6
  movslq %edi,%rdi
  xor    %eax,%eax
  lea    (%rsi,%rdi,4),%rdx
  nopl   0x0(%rax)
L1:
  add    (%rsi),%eax
  add    $0x4,%rsi
  cmp    %rdx,%rsi
  jne    L1
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum(int nseqs, int *arr) {
  int t = 0;
  for (int i = 0; i < nseqs; i++) {
    t += *arr;
    arr++;
  }
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  jle    L28
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L46
  mov    %edi,%ecx
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L20:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rcx
  jne    L20
  movdqa %xmm0,%xmm1
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  mov    %ecx,%edi
  movdqa %xmm0,%xmm1
  lea    (%rsi,%rdi,4),%rsi
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %ecx,%edx
  je     L62
L3:
  lea    0x1(%rcx),%edi
  add    (%rsi),%eax
  cmp    %edi,%edx
  jle    L24
  add    $0x2,%ecx
  add    0x4(%rsi),%eax
  cmp    %ecx,%edx
  jle    L24
  add    0x8(%rsi),%eax
  ret
  nopl   (%rax)
L28:
  xor    %eax,%eax
L24:
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  ret
L46:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L3
```

assistant: ```c
int sum(int nseqs, int *arr) {
  int t = 0;
  for (int i = 0; i < nseqs; i++) {
    t += *arr;
    arr++;
  }
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x3f60a4d,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L42
L22:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L42:
  cmpq   $0x0,-0x18(%rbp)
  je     L22
  movq   $0x0,-0x18(%rbp)
  jmp    L20
L3:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x2,-0x18(%rbp)
L20:
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  lea    -0x5fd42675(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] += state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 1607738997UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    -0x6fac4fa9(,%rax,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] += state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 1607738997UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    -0x6fac4fa9(,%rax,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] += state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 1607738997UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<write2LE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  movzwl -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void write2LE(FILE *fp, unsigned short val) {
  putc(val & 0xff, fp);
  putc(val >> 8, fp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write2LE>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movzbl %sil,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write2LE(FILE *fp, unsigned short val) {
  putc(val & 0xff, fp);
  putc(val >> 8, fp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write2LE>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <putc@plt>
  add    $0x8,%rsp
  movzbl %bh,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
void write2LE(FILE *fp, unsigned short val) {
  putc(val & 0xff, fp);
  putc(val >> 8, fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write2LE>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <putc@plt>
  add    $0x8,%rsp
  movzbl %bh,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
void write2LE(FILE *fp, unsigned short val) {
  putc(val & 0xff, fp);
  putc(val >> 8, fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: hello, world

assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, world");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: hello, world

assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, world");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: hello, world

assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, world");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: hello, world

assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, world");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<dothings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <somefunc1@plt>
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  cmp    $0x62,%eax
  je     L22
  cmp    $0x62,%eax
  jg     L112
  test   %eax,%eax
  je     L69
  cmp    $0x61,%eax
  jne    L112
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L66
L22:
  lea    D14(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L66
L69:
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L66
L112:
  lea    D17(%rip),%rax
  mov    %rax,-0x8(%rbp)
L66:
  movl   $0x0,-0xc(%rbp)
  jmp    L92
L107:
  cmpb   $0x61,-0x14(%rbp)
  jne    L101
  mov    -0xc(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <somefunc1@plt>
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x14(%rbp)
  jmp    L44
L101:
  cmpb   $0x62,-0x14(%rbp)
  jne    L120
  mov    -0xc(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <somefunc1@plt>
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x14(%rbp)
  jmp    L44
L120:
  mov    -0xc(%rbp),%eax
  mov    $0x6,%esi
  mov    %eax,%edi
  call   <somefunc1@plt>
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x14(%rbp)
L44:
  addl   $0x1,-0xc(%rbp)
L92:
  cmpl   $0x4,-0xc(%rbp)
  jle    L107
  mov    -0x8(%rbp),%rax
  movzbl -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D4: Got a

tool: D14: Got b

tool: D3: For serious?

tool: D17: Unknown command

assistant: ```c
const char *dothings(char opt) {
  opt += somefunc1(opt, 2);
  char *msg;
  switch (opt) {
  case 'a':
    msg = "Got a";
    break;
  case 'b':
    msg = "Got b";
    break;
  case '\0':
    msg = "For serious?";
    break;
  default:
    msg = "Unknown command";
  }
  for (int i = 0; i < 5; i++) {
    if (opt == 'a') {
      opt += somefunc1(i, 4);
    } else if (opt == 'b') {
      opt += somefunc1(i, 5);
    } else {
      opt += somefunc1(i, 6);
    }
  }
  msg[0] = opt;
  return msg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dothings>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  mov    $0x2,%esi
  call   <somefunc1@plt>
  lea    (%rbx,%rax,1),%edi
  mov    %edi,%ebx
  lea    D17(%rip),%r12
  cmp    $0x61,%dil
  je     L69
  lea    D30(%rip),%r12
  cmp    $0x62,%dil
  je     L69
  test   %dil,%dil
  lea    D4(%rip),%r12
  lea    D33(%rip),%rax
  cmove  %rax,%r12
L69:
  mov    $0x0,%ebp
  jmp    L53
L48:
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  lea    0x61(%rax),%ebx
  jmp    L58
L75:
  mov    $0x5,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  lea    0x62(%rax),%ebx
L58:
  add    $0x1,%ebp
  cmp    $0x5,%ebp
  je     L19
L53:
  cmp    $0x61,%bl
  je     L48
  cmp    $0x62,%bl
  je     L75
  mov    $0x6,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  add    %eax,%ebx
  jmp    L58
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string
name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D33
data_type: string

tool: D17: Got a

tool: D30: Got b

tool: D4: Unknown command

tool: D33: For serious?

assistant: ```c
const char *dothings(char opt) {
  opt += somefunc1(opt, 2);
  char *msg;
  switch (opt) {
  case 'a':
    msg = "Got a";
    break;
  case 'b':
    msg = "Got b";
    break;
  case '\0':
    msg = "For serious?";
    break;
  default:
    msg = "Unknown command";
  }
  for (int i = 0; i < 5; i++) {
    if (opt == 'a') {
      opt += somefunc1(i, 4);
    } else if (opt == 'b') {
      opt += somefunc1(i, 5);
    } else {
      opt += somefunc1(i, 6);
    }
  }
  msg[0] = opt;
  return msg;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dothings>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <somefunc1@plt>
  add    %eax,%ebx
  cmp    $0x61,%bl
  je     L4
  lea    D2(%rip),%r12
  cmp    $0x62,%bl
  je     L4
  test   %bl,%bl
  lea    D16(%rip),%r12
  lea    D32(%rip),%rax
  cmovne %rax,%r12
L4:
  xor    %ebp,%ebp
L3:
  cmp    $0x61,%bl
  je     L19
  cmp    $0x62,%bl
  je     L43
  mov    $0x6,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  add    %eax,%ebx
L1:
  add    $0x1,%ebp
  cmp    $0x5,%ebp
  jne    L3
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    $0x5,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  lea    0x62(%rax),%ebx
  jmp    L1
  nopl   0x0(%rax)
L19:
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  lea    0x61(%rax),%ebx
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D32
data_type: string

tool: D1: Got a

tool: D2: Got b

tool: D16: For serious?

tool: D32: Unknown command

assistant: ```c
const char *dothings(char opt) {
  opt += somefunc1(opt, 2);
  char *msg;
  switch (opt) {
  case 'a':
    msg = "Got a";
    break;
  case 'b':
    msg = "Got b";
    break;
  case '\0':
    msg = "For serious?";
    break;
  default:
    msg = "Unknown command";
  }
  for (int i = 0; i < 5; i++) {
    if (opt == 'a') {
      opt += somefunc1(i, 4);
    } else if (opt == 'b') {
      opt += somefunc1(i, 5);
    } else {
      opt += somefunc1(i, 6);
    }
  }
  msg[0] = opt;
  return msg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dothings>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <somefunc1@plt>
  add    %eax,%ebx
  cmp    $0x61,%bl
  je     L19
  lea    D21(%rip),%r12
  cmp    $0x62,%bl
  je     L19
  test   %bl,%bl
  lea    D12(%rip),%r12
  lea    D25(%rip),%rax
  cmovne %rax,%r12
L19:
  xor    %ebp,%ebp
L45:
  cmp    $0x61,%bl
  je     L53
  cmp    $0x62,%bl
  je     L60
  mov    $0x6,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  add    %eax,%ebx
L51:
  add    $0x1,%ebp
  cmp    $0x5,%ebp
  jne    L45
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L60:
  mov    $0x5,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  lea    0x62(%rax),%ebx
  jmp    L51
  nopl   0x0(%rax)
L53:
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <somefunc1@plt>
  lea    0x61(%rax),%ebx
  jmp    L51
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D20: Got a

tool: D21: Got b

tool: D12: For serious?

tool: D25: Unknown command

assistant: ```c
const char *dothings(char opt) {
  opt += somefunc1(opt, 2);
  char *msg;
  switch (opt) {
  case 'a':
    msg = "Got a";
    break;
  case 'b':
    msg = "Got b";
    break;
  case '\0':
    msg = "For serious?";
    break;
  default:
    msg = "Unknown command";
  }
  for (int i = 0; i < 5; i++) {
    if (opt == 'a') {
      opt += somefunc1(i, 4);
    } else if (opt == 'b') {
      opt += somefunc1(i, 5);
    } else {
      opt += somefunc1(i, 6);
    }
  }
  msg[0] = opt;
  return msg;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<proc9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    %ax,-0x10(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movswq -0x10(%rbp),%rax
  add    %rdx,%rax
  movsbq -0x14(%rbp),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  imul   0x10(%rbp),%rax
  imul   0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void proc9(long p1, int p2, short p3, char p4, long *p5, long p6, long p7, long p8, long *p9) {
  *p5 = p1 + p2 + p3 - p4;
  *p9 = p6 * p7 * p8;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<proc9>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  movswq %dx,%rdx
  add    %rdx,%rsi
  movsbq %cl,%rcx
  sub    %rcx,%rsi
  mov    %rsi,(%r8)
  imul   0x8(%rsp),%r9
  imul   0x10(%rsp),%r9
  mov    0x18(%rsp),%rax
  mov    %r9,(%rax)
  ret
```

assistant: ```c
void proc9(long p1, int p2, short p3, char p4, long *p5, long p6, long p7, long p8, long *p9) {
  *p5 = p1 + p2 + p3 - p4;
  *p9 = p6 * p7 * p8;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<proc9>:
  endbr64
  movslq %esi,%rsi
  movswq %dx,%rdx
  mov    0x18(%rsp),%rax
  movsbq %cl,%rcx
  imul   0x8(%rsp),%r9
  add    %rdi,%rsi
  imul   0x10(%rsp),%r9
  add    %rdx,%rsi
  sub    %rcx,%rsi
  mov    %rsi,(%r8)
  mov    %r9,(%rax)
  ret
```

assistant: ```c
void proc9(long p1, int p2, short p3, char p4, long *p5, long p6, long p7, long p8, long *p9) {
  *p5 = p1 + p2 + p3 - p4;
  *p9 = p6 * p7 * p8;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<proc9>:
  endbr64
  movslq %esi,%rsi
  movswq %dx,%rdx
  mov    0x18(%rsp),%rax
  movsbq %cl,%rcx
  imul   0x8(%rsp),%r9
  add    %rdi,%rsi
  imul   0x10(%rsp),%r9
  add    %rdx,%rsi
  sub    %rcx,%rsi
  mov    %rsi,(%r8)
  mov    %r9,(%rax)
  ret
```

assistant: ```c
void proc9(long p1, int p2, short p3, char p4, long *p5, long p6, long p7, long p8, long *p9) {
  *p5 = p1 + p2 + p3 - p4;
  *p9 = p6 * p7 * p8;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<medianOfMedians>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %edx,%esi
  mov    %edx,0x8(%rsp)
  mov    %ecx,%r13d
  mov    %r8d,%r12d
  lea    (%r8,%r8,4),%ebp
  mov    %ecx,%eax
  sub    %edx,%eax
  lea    0x1(%rax),%ebx
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L50
  lea    0x0(%rbp,%rsi,1),%eax
  mov    %eax,%ebx
  cmp    %eax,%ecx
  jle    L5
L22:
  mov    %ebx,0x4(%rsp)
  lea    -0x1(%rbx),%ecx
  mov    %ebx,%edx
  sub    %ebp,%edx
  mov    %r12d,%r8d
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <_insertion@plt>
  add    %ebp,%ebx
  cmp    %ebx,%r13d
  jg     L22
L18:
  mov    0xc(%rsp),%ebx
  cmp    $0x4,%ebx
  jg     L49
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
  mov    0x8(%rsp),%r12d
  add    %r12d,%edx
  mov    %ebp,%r8d
  mov    %r13d,%ecx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <_insertion@plt>
  mov    %ebx,%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %r12d,%eax
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    %esi,0x4(%rsp)
  jmp    L18
L50:
  mov    0x8(%rsp),%ebp
  mov    %ebp,%edx
  mov    %r15,%rsi
  call   <_insertion@plt>
  mov    %ebx,%eax
  cltd
  idiv   %r12d
  sub    $0x1,%eax
  imul   %r12d,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %edi,%eax
  sar    %eax
  add    %ebp,%eax
  jmp    L27
L49:
  mov    0x4(%rsp),%ecx
  sub    $0x1,%ecx
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
  add    0x8(%rsp),%edx
  mov    %ebp,%r8d
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <medianOfMedians>
  jmp    L27
```

assistant: ```c
int medianOfMedians(void **ar, int (*cmp)(const void *, const void *), int left, int right, int gap) {
  int s, num;
  int span = 5 * gap;
  num = (right - left + 1) / span;
  if (num == 0) {
    _insertion(ar, cmp, left, right, gap);
    num = (right - left + 1) / gap;
    return left + gap * (num - 1) / 2;
  }
  for (s = left; s + span < right; s += span) {
    _insertion(ar, cmp, s, s + span - 1, gap);
  }
  if (num < 5) {
    _insertion(ar, cmp, left + span / 2, right, span);
    return left + num * span / 2;
  } else {
    return medianOfMedians(ar, cmp, left + span / 2, s - 1, 5 * gap);
  }
}
```