ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L22
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L27
  nopl   (%rax)
L33:
  add    $0x1,%ebx
  movsbl %bl,%ebp
  cmp    %r12d,%ebp
  jge    L23
L27:
  movsbq %bl,%rax
  pxor   %xmm0,%xmm0
  mov    %r14,%rdi
  cvtss2sd 0x0(%r13,%rax,4),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %r15d,%ebp
  jne    L33
  add    $0x1,%ebx
  mov    $0xa,%edi
  call   <putchar@plt>
  movsbl %bl,%ebp
  cmp    %r12d,%ebp
  jl     L27
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: %.1f, 

assistant: ```c
void printArray(float *array, int length) {
  char i = 0;
  for (i = 0; i < length; i++) {
    printf("%.1f, ", array[i]);
    if (i == length - 1) {
      printf("\n");
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<router_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <router_restart@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <con_runfile@plt>
  mov    $0x0,%eax
  call   <reset_timeouts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: autoexec.script

assistant: ```c
void router_init(void) {
  router_restart();
  con_runfile("autoexec.script");
  reset_timeouts();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<router_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <router_restart@plt>
  lea    D9(%rip),%rdi
  call   <con_runfile@plt>
  mov    $0x0,%eax
  call   <reset_timeouts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string

tool: D9: autoexec.script

assistant: ```c
void router_init(void) {
  router_restart();
  con_runfile("autoexec.script");
  reset_timeouts();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<router_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <router_restart@plt>
  lea    D9(%rip),%rdi
  call   <con_runfile@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <reset_timeouts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: autoexec.script

assistant: ```c
void router_init(void) {
  router_restart();
  con_runfile("autoexec.script");
  reset_timeouts();
}
```
user: Translate the below assembly code into C programming language:

```asm
<router_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <router_restart@plt>
  lea    D0(%rip),%rdi
  call   <con_runfile@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <reset_timeouts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: autoexec.script

assistant: ```c
void router_init(void) {
  router_restart();
  con_runfile("autoexec.script");
  reset_timeouts();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  ja     L3
  mov    $0x1,%eax
  jmp    L42
L3:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L46
  mov    $0x0,%eax
  jmp    L42
L46:
  movl   $0x3,-0x4(%rbp)
  jmp    L60
L18:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L25
  mov    $0x0,%eax
  jmp    L42
L25:
  addl   $0x2,-0x4(%rbp)
L60:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jae    L18
  mov    $0x1,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(unsigned int number) {
  if (number <= 3) {
    return 1;
  }
  if (number % 2 == 0) {
    return 0;
  }
  for (unsigned int i = 3; i * i <= number; i += 2) {
    if (number % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrime>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jbe    L27
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L27
  cmp    $0x8,%edi
  jbe    L5
  mov    %edi,%eax
  mov    $0xaaaaaaab,%edx
  imul   %rdx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  je     L42
  mov    $0x3,%ecx
L7:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  ja     L25
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  test   %edx,%edx
  jne    L7
  mov    $0x0,%eax
L27:
  ret
L25:
  mov    $0x1,%eax
  ret
L5:
  mov    $0x1,%eax
  ret
L42:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isPrime(unsigned int number) {
  if (number <= 3) {
    return 1;
  }
  if (number % 2 == 0) {
    return 0;
  }
  for (unsigned int i = 3; i * i <= number; i += 2) {
    if (number % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isPrime>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jbe    L3
  xor    %eax,%eax
  test   $0x1,%dil
  je     L3
  cmp    $0x8,%edi
  jbe    L1
  imul   $0xaaaaaaab,%edi,%edx
  cmp    $0x55555555,%edx
  jbe    L3
  mov    $0x3,%ecx
  jmp    L42
L23:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L11
L42:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jbe    L23
L1:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
L3:
  ret
```

assistant: ```c
int isPrime(unsigned int number) {
  if (number <= 3) {
    return 1;
  }
  if (number % 2 == 0) {
    return 0;
  }
  for (unsigned int i = 3; i * i <= number; i += 2) {
    if (number % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPrime>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jbe    L50
  xor    %eax,%eax
  test   $0x1,%dil
  je     L50
  cmp    $0x8,%edi
  jbe    L58
  imul   $0xaaaaaaab,%edi,%edx
  cmp    $0x55555555,%edx
  jbe    L50
  mov    $0x3,%ecx
  jmp    L63
L60:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L27
L63:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jbe    L60
L58:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L27:
  xor    %eax,%eax
L50:
  ret
```

assistant: ```c
int isPrime(unsigned int number) {
  if (number <= 3) {
    return 1;
  }
  if (number % 2 == 0) {
    return 0;
  }
  for (unsigned int i = 3; i * i <= number; i += 2) {
    if (number % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x6000,-0xc(%rbp)
  jmp    L28
L0:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <udiv32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L11
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L28:
  cmpl   $0x600f,-0xc(%rbp)
  jbe    L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string

tool: D6: W %d %d %d


tool: D9: %d %d %d


assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0x6000; i < 0x6010; i++) {
    unsigned int exact_answer = i / 10;
    unsigned int xxx = udiv32(i);
    if (xxx != exact_answer) {
      printf("W %d %d %d\n", i, exact_answer, xxx);
    }
    printf("%d %d %d\n", i, exact_answer, xxx);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x6000,%ebp
  mov    $0xcccccccd,%r14d
  lea    D7(%rip),%r15
  lea    D5(%rip),%r13
  jmp    L35
L26:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x6010,%ebp
  je     L28
L35:
  mov    %ebp,%ebx
  imul   %r14,%rbx
  shr    $0x23,%rbx
  mov    %ebp,%edi
  call   <udiv32@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  je     L26
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L26
L28:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D7: W %d %d %d


tool: D5: %d %d %d


assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0x6000; i < 0x6010; i++) {
    unsigned int exact_answer = i / 10;
    unsigned int xxx = udiv32(i);
    if (xxx != exact_answer) {
      printf("W %d %d %d\n", i, exact_answer, xxx);
    }
    printf("%d %d %d\n", i, exact_answer, xxx);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x6000,%r14d
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0xcccccccd,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r14d,%r12d
  mov    %r14d,%edi
  call   <udiv32@plt>
  imul   %rbx,%r12
  mov    %eax,%r15d
  shr    $0x23,%r12
  cmp    %eax,%r12d
  je     L2
  mov    %eax,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L2:
  mov    %r14d,%esi
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%r14d
  cmp    $0x6010,%r14d
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string

tool: D10: W %d %d %d


tool: D0: %d %d %d


assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0x6000; i < 0x6010; i++) {
    unsigned int exact_answer = i / 10;
    unsigned int xxx = udiv32(i);
    if (xxx != exact_answer) {
      printf("W %d %d %d\n", i, exact_answer, xxx);
    }
    printf("%d %d %d\n", i, exact_answer, xxx);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x6000,%r14d
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0xcccccccd,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r14d,%r12d
  mov    %r14d,%edi
  call   <udiv32@plt>
  imul   %rbx,%r12
  mov    %eax,%r15d
  shr    $0x23,%r12
  mov    %r12d,%ecx
  cmp    %eax,%r12d
  je     L9
  mov    %eax,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r15d,%ecx
L9:
  mov    %r14d,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    $0x6010,%r14d
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D8
type: string

tool: D16: W %d %d %d


tool: D8: %d %d %d


assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0x6000; i < 0x6010; i++) {
    unsigned int exact_answer = i / 10;
    unsigned int xxx = udiv32(i);
    if (xxx != exact_answer) {
      printf("W %d %d %d\n", i, exact_answer, xxx);
    }
    printf("%d %d %d\n", i, exact_answer, xxx);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_missing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xff,%al
  je     L31
  mov    $0x0,%eax
  jmp    L5
L31:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int is_missing(unsigned const char *p, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (p[i] != 255)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_missing>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L6:
  cmpb   $0xff,(%rax)
  jne    L0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
  mov    $0x1,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_missing(unsigned const char *p, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (p[i] != 255)
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_missing>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L7
L4:
  cmpb   $0xff,(%rdi)
  je     L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_missing(unsigned const char *p, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (p[i] != 255)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_missing>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L2
L1:
  cmpb   $0xff,(%rdi)
  je     L9
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_missing(unsigned const char *p, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (p[i] != 255)
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xfe,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  xor    %esi,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void x(char *p) {
  int i, key = 0xFE;
  for (i = 0; i < strlen(p); i++)
    p[i] ^= key;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<x>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L14
L19:
  xorb   $0xfe,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void x(char *p) {
  int i, key = 0xFE;
  for (i = 0; i < strlen(p); i++)
    p[i] ^= key;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<x>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax)
L12:
  xorb   $0xfe,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void x(char *p) {
  int i, key = 0xFE;
  for (i = 0; i < strlen(p); i++)
    p[i] ^= key;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L18
  nopl   0x0(%rax)
L0:
  xorb   $0xfe,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void x(char *p) {
  int i, key = 0xFE;
  for (i = 0; i < strlen(p); i++)
    p[i] ^= key;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GrOffScreen1BPPPixelDraw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  add    $0x7,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  add    %ecx,%eax
  cltq
  add    $0x5,%rax
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  not    %eax
  and    $0x7,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  mov    %edx,%esi
  and    %eax,%esi
  mov    -0x1c(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GrOffScreen1BPPPixelDraw(void *pvDisplayData, int32_t i32X, int32_t i32Y, uint32_t ui32Value) {
  uint8_t *pui8Data;
  int32_t i32BytesPerRow;
  ;
  pui8Data = (uint8_t *)pvDisplayData;
  i32BytesPerRow = (*(uint16_t *)(pui8Data + 1) + 7) / 8;
  pui8Data += (i32BytesPerRow * i32Y) + (i32X / 8) + 5;
  i32X = 7 - (i32X & 7);
  *pui8Data = (*pui8Data & ~(1 << i32X)) | (ui32Value << i32X);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GrOffScreen1BPPPixelDraw>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%r8d
  mov    %ecx,%esi
  mov    0x4(%rdi),%ecx
  lea    0xe(%rcx),%edx
  add    $0x7,%ecx
  cmovns %ecx,%edx
  sar    $0x3,%edx
  imul   %r8d,%edx
  lea    0x7(%rax),%ecx
  test   %eax,%eax
  cmovns %eax,%ecx
  sar    $0x3,%ecx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x14(%rdi,%rdx,4),%rdx
  not    %eax
  mov    %eax,%ecx
  and    $0x7,%ecx
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  and    (%rdx),%eax
  shl    %cl,%esi
  or     %esi,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void GrOffScreen1BPPPixelDraw(void *pvDisplayData, int32_t i32X, int32_t i32Y, uint32_t ui32Value) {
  uint8_t *pui8Data;
  int32_t i32BytesPerRow;
  ;
  pui8Data = (uint8_t *)pvDisplayData;
  i32BytesPerRow = (*(uint16_t *)(pui8Data + 1) + 7) / 8;
  pui8Data += (i32BytesPerRow * i32Y) + (i32X / 8) + 5;
  i32X = 7 - (i32X & 7);
  *pui8Data = (*pui8Data & ~(1 << i32X)) | (ui32Value << i32X);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GrOffScreen1BPPPixelDraw>:
  endbr64
  mov    %ecx,%r8d
  mov    0x4(%rdi),%ecx
  mov    %edx,%r9d
  mov    %esi,%eax
  not    %eax
  lea    0xe(%rcx),%edx
  add    $0x7,%ecx
  cmovns %ecx,%edx
  lea    0x7(%rsi),%ecx
  sar    $0x3,%edx
  imul   %r9d,%edx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x3,%ecx
  add    %ecx,%edx
  mov    %eax,%ecx
  mov    $0xfffffffe,%eax
  movslq %edx,%rdx
  and    $0x7,%ecx
  lea    0x14(%rdi,%rdx,4),%rdx
  rol    %cl,%eax
  shl    %cl,%r8d
  and    (%rdx),%eax
  or     %r8d,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void GrOffScreen1BPPPixelDraw(void *pvDisplayData, int32_t i32X, int32_t i32Y, uint32_t ui32Value) {
  uint8_t *pui8Data;
  int32_t i32BytesPerRow;
  ;
  pui8Data = (uint8_t *)pvDisplayData;
  i32BytesPerRow = (*(uint16_t *)(pui8Data + 1) + 7) / 8;
  pui8Data += (i32BytesPerRow * i32Y) + (i32X / 8) + 5;
  i32X = 7 - (i32X & 7);
  *pui8Data = (*pui8Data & ~(1 << i32X)) | (ui32Value << i32X);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GrOffScreen1BPPPixelDraw>:
  endbr64
  mov    %ecx,%r8d
  mov    0x4(%rdi),%ecx
  mov    %edx,%r9d
  mov    %esi,%eax
  not    %eax
  lea    0xe(%rcx),%edx
  add    $0x7,%ecx
  cmovns %ecx,%edx
  lea    0x7(%rsi),%ecx
  sar    $0x3,%edx
  imul   %r9d,%edx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x3,%ecx
  add    %ecx,%edx
  mov    %eax,%ecx
  mov    $0xfffffffe,%eax
  movslq %edx,%rdx
  and    $0x7,%ecx
  lea    0x14(%rdi,%rdx,4),%rdx
  rol    %cl,%eax
  shl    %cl,%r8d
  and    (%rdx),%eax
  or     %r8d,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void GrOffScreen1BPPPixelDraw(void *pvDisplayData, int32_t i32X, int32_t i32Y, uint32_t ui32Value) {
  uint8_t *pui8Data;
  int32_t i32BytesPerRow;
  ;
  pui8Data = (uint8_t *)pvDisplayData;
  i32BytesPerRow = (*(uint16_t *)(pui8Data + 1) + 7) / 8;
  pui8Data += (i32BytesPerRow * i32Y) + (i32X / 8) + 5;
  i32X = 7 - (i32X & 7);
  *pui8Data = (*pui8Data & ~(1 << i32X)) | (ui32Value << i32X);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_put_nbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <my_putnbr_base@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: 0123456789

assistant: ```c
int my_put_nbr(int nb) {
  my_putnbr_base(nb, "0123456789");
  my_putchar('\n');
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_put_nbr>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <my_putnbr_base@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: 0123456789

assistant: ```c
int my_put_nbr(int nb) {
  my_putnbr_base(nb, "0123456789");
  my_putchar('\n');
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_put_nbr>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <my_putnbr_base@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: 0123456789

assistant: ```c
int my_put_nbr(int nb) {
  my_putnbr_base(nb, "0123456789");
  my_putchar('\n');
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_put_nbr>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  call   <my_putnbr_base@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: 0123456789

assistant: ```c
int my_put_nbr(int nb) {
  my_putnbr_base(nb, "0123456789");
  my_putchar('\n');
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_downshift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rbx
  jmp    L28
L22:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L26
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
L26:
  add    $0x1,%rbx
L28:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *string_downshift(s)
char *s;
{
  register char *x = s;
  for (; *x; x++)
    if (isupper(*x))
      *x = tolower(*x);
  return (s);
}
```