ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<zmienne>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D81(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  add    $0x2,%ebx
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  movslq %ebx,%r12
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  lea    D70(%rip),%rdi
  xor    %eax,%eax
  imul   $0x55555556,%r12,%r12
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  shr    $0x20,%r12
  call   <printf@plt>
  mov    %ebx,%eax
  lea    D73(%rip),%rdi
  sar    $0x1f,%eax
  sub    %eax,%r12d
  lea    (%r12,%r12,2),%eax
  sub    %eax,%ebx
  xor    %eax,%eax
  lea    (%rbx,%rbx,1),%ebp
  mov    %ebx,%edx
  mov    %ebp,%esi
  call   <printf@plt>
  lea    D86(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  lea    D85(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    %ebp,%edx
  mov    %ebp,%esi
  lea    D25(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D81
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D70
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string
name: disassemble_data
arguments: label: D40
datatype: string
name: disassemble_data
arguments: label: D73
datatype: string
name: disassemble_data
arguments: label: D86
datatype: string
name: disassemble_data
arguments: label: D85
datatype: string
name: disassemble_data
arguments: label: D25
datatype: string

tool: D81: 	--test 2

tool: D23: y=%i x=%i

tool: D70: 
y= %i x=%i


tool: D22: 	--test 3

tool: D40: z=%i x=%i

tool: D73: 
z= %i x=%i


tool: D86: 	--test 4*

tool: D85: g=%i x=%i

tool: D25: 
g= %i x=%i


assistant: ```c
void zmienne(int x) {
  int z = 0, y = 0, g = 0;
  printf("\t--test 2\n");
  printf("y=%i x=%i", y, x);
  y = (x += 2);
  printf("\ny= %i x=%i\n", y, x);
  printf("\t--test 3\n");
  printf("z=%i x=%i", z, x);
  z = (x %= 3) + (x %= 4);
  printf("\nz= %i x=%i\n", z, x);
  printf("\t--test 4*\n");
  printf("g=%i x=%i", g, x);
  g = (x *= 2);
  printf("\ng= %i x=%i\n", g, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wgs_wgs84_to_gcj02>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  movsd  -0x30(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <wgs_gcj02_offset@plt>
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void wgs_wgs84_to_gcj02(const double lat, const double lng, double *mlat, double *mlng) {
  double dlat, dlng;
  wgs_gcj02_offset(lat, lng, &dlat, &dlng);
  *mlat = lat + dlat;
  *mlng = lng + dlng;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wgs_wgs84_to_gcj02>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movq   %xmm0,%rbp
  movq   %xmm1,%rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <wgs_gcj02_offset@plt>
  movq   %rbp,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x0(%r13)
  movq   %rbx,%xmm0
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,(%r12)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wgs_wgs84_to_gcj02(const double lat, const double lng, double *mlat, double *mlng) {
  double dlat, dlng;
  wgs_gcj02_offset(lat, lng, &dlat, &dlng);
  *mlat = lat + dlat;
  *mlng = lng + dlng;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wgs_wgs84_to_gcj02>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    0x18(%rsp),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <wgs_gcj02_offset@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm1
  movsd  %xmm0,0x0(%rbp)
  movsd  %xmm1,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wgs_wgs84_to_gcj02(const double lat, const double lng, double *mlat, double *mlng) {
  double dlat, dlng;
  wgs_gcj02_offset(lat, lng, &dlat, &dlng);
  *mlat = lat + dlat;
  *mlng = lng + dlng;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wgs_wgs84_to_gcj02>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    0x18(%rsp),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <wgs_gcj02_offset@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm1
  movsd  %xmm0,0x0(%rbp)
  movsd  %xmm1,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wgs_wgs84_to_gcj02(const double lat, const double lng, double *mlat, double *mlng) {
  double dlat, dlng;
  wgs_gcj02_offset(lat, lng, &dlat, &dlng);
  *mlat = lat + dlat;
  *mlng = lng + dlng;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<linux_map_gid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getgrgid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L35
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L35
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <utils_strdup@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L13
L35:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <_utoa@plt>
  mov    %rax,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *linux_map_gid(gid_t gid) {
  char *name = NULL;
  struct group *grp = getgrgid(gid);
  if (grp && grp->gr_name && *grp->gr_name) {
    name = utils_strdup(grp->gr_name);
  } else {
    name = _utoa(gid);
  }
  return name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linux_map_gid>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L36
  mov    (%rax),%rdi
  test   %rdi,%rdi
  je     L36
  cmpq   $0x0,(%rdi)
  jne    L12
L36:
  mov    %ebx,%edi
  call   <_utoa@plt>
L25:
  pop    %rbx
  ret
L12:
  call   <utils_strdup@plt>
  jmp    L25
```

assistant: ```c
char *linux_map_gid(gid_t gid) {
  char *name = NULL;
  struct group *grp = getgrgid(gid);
  if (grp && grp->gr_name && *grp->gr_name) {
    name = utils_strdup(grp->gr_name);
  } else {
    name = _utoa(gid);
  }
  return name;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<linux_map_gid>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L4
  mov    (%rax),%rdi
  test   %rdi,%rdi
  je     L4
  cmpq   $0x0,(%rdi)
  jne    L0
L4:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <_utoa@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  pop    %rbp
  jmp    1070 <utils_strdup@plt>
```

assistant: ```c
char *linux_map_gid(gid_t gid) {
  char *name = NULL;
  struct group *grp = getgrgid(gid);
  if (grp && grp->gr_name && *grp->gr_name) {
    name = utils_strdup(grp->gr_name);
  } else {
    name = _utoa(gid);
  }
  return name;
}
```
user: What is the c source code of the assembly code below:

```asm
<linux_map_gid>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L5
  mov    (%rax),%rdi
  test   %rdi,%rdi
  je     L5
  cmpq   $0x0,(%rdi)
  jne    L16
L5:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <_utoa@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  pop    %rbp
  jmp    1070 <utils_strdup@plt>
```

assistant: ```c
char *linux_map_gid(gid_t gid) {
  char *name = NULL;
  struct group *grp = getgrgid(gid);
  if (grp && grp->gr_name && *grp->gr_name) {
    name = utils_strdup(grp->gr_name);
  } else {
    name = _utoa(gid);
  }
  return name;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_func_01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  cwtl
  add    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
short *test_func_01(short *p, int *x) {
  int r = 0;
  r += *p++;
  *x = r;
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_func_01>:
  endbr64
  movswl (%rdi),%eax
  mov    %eax,(%rsi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
short *test_func_01(short *p, int *x) {
  int r = 0;
  r += *p++;
  *x = r;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_func_01>:
  endbr64
  movswl (%rdi),%eax
  mov    %eax,(%rsi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
short *test_func_01(short *p, int *x) {
  int r = 0;
  r += *p++;
  *x = r;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flash_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L27
L34:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <flash_erase@plt>
  addq   $0x1,-0x10(%rbp)
L27:
  mov    -0x28(%rbp),%rax
  shr    $0xa,%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L34
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L24:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  shl    $0x8,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <flash_program@plt>
  addq   $0x2,-0x8(%rbp)
  addq   $0x10,-0x20(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void flash_write(uint8_t page, const uint8_t *src, size_t num) {
  for (uint8_t i = 0; i <= num / 1024; i++)
    flash_erase(page + i);
  for (size_t i = 0; i < num; i += 2, src += 2)
    flash_program(page, i, *src + (*(src + 1) << 8));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<flash_write>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rdx,%rax
  shr    $0xa,%rax
  lea    0x1(%rdi,%rax,1),%r14
  mov    %rdi,%rbx
L18:
  mov    %rbx,%rdi
  call   <flash_erase@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L18
  test   %r13,%r13
  je     L27
  mov    $0x0,%ebx
L28:
  mov    0x8(%rbp,%rbx,8),%rdx
  shl    $0x8,%rdx
  add    0x0(%rbp,%rbx,8),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <flash_program@plt>
  add    $0x2,%rbx
  cmp    %rbx,%r13
  ja     L28
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void flash_write(uint8_t page, const uint8_t *src, size_t num) {
  for (uint8_t i = 0; i <= num / 1024; i++)
    flash_erase(page + i);
  for (size_t i = 0; i < num; i += 2, src += 2)
    flash_program(page, i, *src + (*(src + 1) << 8));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<flash_write>:
  endbr64
  mov    %rdx,%rax
  push   %r14
  shr    $0xa,%rax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x1(%rdi,%rax,1),%r14
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <flash_erase@plt>
  cmp    %rbx,%r14
  jne    L0
  test   %r13,%r13
  je     L1
  xor    %ebx,%ebx
L13:
  mov    0x8(%rbp,%rbx,8),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  shl    $0x8,%rdx
  add    0x0(%rbp,%rbx,8),%rdx
  add    $0x2,%rbx
  call   <flash_program@plt>
  cmp    %rbx,%r13
  ja     L13
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void flash_write(uint8_t page, const uint8_t *src, size_t num) {
  for (uint8_t i = 0; i <= num / 1024; i++)
    flash_erase(page + i);
  for (size_t i = 0; i < num; i += 2, src += 2)
    flash_program(page, i, *src + (*(src + 1) << 8));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<flash_write>:
  endbr64
  mov    %rdx,%rax
  push   %r14
  shr    $0xa,%rax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x1(%rdi,%rax,1),%r14
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L27:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <flash_erase@plt>
  cmp    %rbx,%r14
  jne    L27
  test   %r13,%r13
  je     L2
  xor    %ebx,%ebx
L9:
  mov    0x8(%rbp,%rbx,8),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  shl    $0x8,%rdx
  add    0x0(%rbp,%rbx,8),%rdx
  add    $0x2,%rbx
  call   <flash_program@plt>
  cmp    %rbx,%r13
  ja     L9
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void flash_write(uint8_t page, const uint8_t *src, size_t num) {
  for (uint8_t i = 0; i <= num / 1024; i++)
    flash_erase(page + i);
  for (size_t i = 0; i < num; i += 2, src += 2)
    flash_program(page, i, *src + (*(src + 1) << 8));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L5:
  cmp    %rdx,%rsp
  je     L10
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L10:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    %rsi,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void f(int count) {
  int a[count];
  do {
  } while (0);
  if (a[0] != 3) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int count) {
  int a[count];
  do {
  } while (0);
  if (a[0] != 3) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int count) {
  int a[count];
  do {
  } while (0);
  if (a[0] != 3) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int count) {
  int a[count];
  do {
  } while (0);
  if (a[0] != 3) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<publisher>:
  endbr64
  sub    $0x8,%rsp
  movslq %esi,%rsi
  movzbl 0x1(%rdi,%rsi,1),%eax
  cmp    $0x39,%al
  je     L1
  cmp    $0x35,%al
  je     L72
  cmp    $0x34,%al
  jne    L166
  cmpb   $0x32,0x2(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x31,0x3(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x30,0x4(%rdi,%rsi,1)
  jne    L89
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L89
L1:
  cmpb   $0x33,0x2(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x33,0x3(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x33,0x4(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x34,0x5(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x36,0x6(%rdi,%rsi,1)
  jne    L89
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L89
L72:
  cmpb   $0x35,0x2(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x35,0x3(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x38,0x4(%rdi,%rsi,1)
  jne    L89
  cmpb   $0x33,0x5(%rdi,%rsi,1)
  jne    L89
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L89
L166:
  cmp    $0x30,%al
  jne    L89
  cmpb   $0x31,0x2(%rdi,%rsi,1)
  je     L10
L89:
  add    $0x8,%rsp
  ret
L10:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L89
```

tool_calls: name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D38
type_infered: string

tool: D23: FUNimation Productions, Ltd.

tool: D9: Bluebridge

tool: D26: Alyson Books

tool: D38: Pyramid Books

assistant: ```c
void publisher(char input[20], int i) {
  if (input[i + 1] == '9' && input[i + 2] == '3' && input[i + 3] == '3' && input[i + 4] == '3' && input[i + 5] == '4' && input[i + 6] == '6') {
    printf("Bluebridge");
  } else {
    if (input[i + 1] == '5' && input[i + 2] == '5' && input[i + 3] == '5' && input[i + 4] == '8' && input[i + 5] == '3') {
      printf("Alyson Books");
    } else {
      if (input[i + 1] == '4' && input[i + 2] == '2' && input[i + 3] == '1' && input[i + 4] == '0') {
        printf("FUNimation Productions, Ltd.");
      } else {
        if (input[i + 1] == '0' && input[i + 2] == '1') {
          printf("Pyramid Books");
        }
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<publisher>:
  endbr64
  movslq %esi,%rsi
  movzbl 0x1(%rdi,%rsi,1),%eax
  cmp    $0x39,%al
  je     L140
  cmp    $0x35,%al
  jne    L141
  cmpb   $0x35,0x2(%rdi,%rsi,1)
  je     L37
L135:
  ret
  nopl   0x0(%rax)
L141:
  cmp    $0x34,%al
  jne    L51
  cmpb   $0x32,0x2(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x31,0x3(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x30,0x4(%rdi,%rsi,1)
  jne    L135
  lea    D21(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L51:
  cmp    $0x30,%al
  jne    L135
  cmpb   $0x31,0x2(%rdi,%rsi,1)
  jne    L135
  lea    D39(%rip),%rdi
  jmp    1050 <printf@plt>
  nop
L140:
  cmpb   $0x33,0x2(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x33,0x3(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x33,0x4(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x34,0x5(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x36,0x6(%rdi,%rsi,1)
  jne    L135
  lea    D10(%rip),%rdi
  jmp    1050 <printf@plt>
  nop
L37:
  cmpb   $0x35,0x3(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x38,0x4(%rdi,%rsi,1)
  jne    L135
  cmpb   $0x33,0x5(%rdi,%rsi,1)
  jne    L135
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_infered: string
name: extract_symbolic_data
arguments: data_label: D39
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D21: FUNimation Productions, Ltd.

tool: D39: Pyramid Books

tool: D10: Bluebridge

tool: D8: Alyson Books

assistant: ```c
void publisher(char input[20], int i) {
  if (input[i + 1] == '9' && input[i + 2] == '3' && input[i + 3] == '3' && input[i + 4] == '3' && input[i + 5] == '4' && input[i + 6] == '6') {
    printf("Bluebridge");
  } else {
    if (input[i + 1] == '5' && input[i + 2] == '5' && input[i + 3] == '5' && input[i + 4] == '8' && input[i + 5] == '3') {
      printf("Alyson Books");
    } else {
      if (input[i + 1] == '4' && input[i + 2] == '2' && input[i + 3] == '1' && input[i + 4] == '0') {
        printf("FUNimation Productions, Ltd.");
      } else {
        if (input[i + 1] == '0' && input[i + 2] == '1') {
          printf("Pyramid Books");
        }
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<publisher>:
  endbr64
  movslq %esi,%rsi
  movzbl 0x1(%rdi,%rsi,1),%eax
  cmp    $0x39,%al
  je     L9
  cmp    $0x35,%al
  jne    L94
  cmpb   $0x35,0x2(%rdi,%rsi,1)
  je     L81
L150:
  ret
  nopl   0x0(%rax)
L94:
  cmp    $0x34,%al
  jne    L160
  cmpb   $0x32,0x2(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x31,0x3(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x30,0x4(%rdi,%rsi,1)
  jne    L150
  lea    D35(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L160:
  cmp    $0x30,%al
  jne    L150
  cmpb   $0x31,0x2(%rdi,%rsi,1)
  jne    L150
  lea    D32(%rip),%rdi
  jmp    1050 <printf@plt>
  nop
L9:
  cmpb   $0x33,0x2(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x33,0x3(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x33,0x4(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x34,0x5(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x36,0x6(%rdi,%rsi,1)
  jne    L150
  lea    D18(%rip),%rdi
  jmp    1050 <printf@plt>
  nop
L81:
  cmpb   $0x35,0x3(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x38,0x4(%rdi,%rsi,1)
  jne    L150
  cmpb   $0x33,0x5(%rdi,%rsi,1)
  jne    L150
  lea    D34(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D35
datatype: string
name: read_data
arguments: tag: D32
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D34
datatype: string

tool: D35: FUNimation Productions, Ltd.

tool: D32: Pyramid Books

tool: D18: Bluebridge

tool: D34: Alyson Books

assistant: ```c
void publisher(char input[20], int i) {
  if (input[i + 1] == '9' && input[i + 2] == '3' && input[i + 3] == '3' && input[i + 4] == '3' && input[i + 5] == '4' && input[i + 6] == '6') {
    printf("Bluebridge");
  } else {
    if (input[i + 1] == '5' && input[i + 2] == '5' && input[i + 3] == '5' && input[i + 4] == '8' && input[i + 5] == '3') {
      printf("Alyson Books");
    } else {
      if (input[i + 1] == '4' && input[i + 2] == '2' && input[i + 3] == '1' && input[i + 4] == '0') {
        printf("FUNimation Productions, Ltd.");
      } else {
        if (input[i + 1] == '0' && input[i + 2] == '1') {
          printf("Pyramid Books");
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x38(%rbp)
  jmp    L12
L4:
  mov    $0xa,%eax
  sub    -0x38(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x38(%rbp)
L12:
  mov    -0x38(%rbp),%eax
  cmp    $0xa,%eax
  jbe    L4
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int main() {
  int x, y;
  int a[10];
  x = 1U;
  while (x <= 10U) {
    y = 10 - x;
    a[y] = -1;
    x++;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int x, y;
  int a[10];
  x = 1U;
  while (x <= 10U) {
    y = 10 - x;
    a[y] = -1;
    x++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int x, y;
  int a[10];
  x = 1U;
  while (x <= 10U) {
    y = 10 - x;
    a[y] = -1;
    x++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int x, y;
  int a[10];
  x = 1U;
  while (x <= 10U) {
    y = 10 - x;
    a[y] = -1;
    x++;
  }
  return 1;
}
```