ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<generate_public_key>:
  endbr64
  test   %rdi,%rdi
  push   %r14
  mov    %r8,%r14
  push   %r13
  setne  %al
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  and    %eax,%edi
  mov    %rcx,%rbx
  call   <assert@plt>
  test   %rbp,%rbp
  je     L15
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%r12,%rcx,8),%rax
  xor    %edx,%edx
  imul   %r13,%rax
  div    %rbx
  mov    %rdx,(%r14,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L19
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void generate_public_key(const size_t *private_key, const size_t key_size, const size_t n, const size_t m, size_t *public_key) {
  assert(private_key != NULL && key_size > 0);
  size_t i;
  for (i = 0; i < key_size; i++) {
    public_key[i] = (private_key[i] * n) % m;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generate_public_key>:
  endbr64
  test   %rdi,%rdi
  push   %r14
  mov    %r8,%r14
  push   %r13
  setne  %al
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  and    %eax,%edi
  mov    %rcx,%rbx
  call   <assert@plt>
  test   %rbp,%rbp
  je     L10
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%r12,%rcx,8),%rax
  xor    %edx,%edx
  imul   %r13,%rax
  div    %rbx
  mov    %rdx,(%r14,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L2
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void generate_public_key(const size_t *private_key, const size_t key_size, const size_t n, const size_t m, size_t *public_key) {
  assert(private_key != NULL && key_size > 0);
  size_t i;
  for (i = 0; i < key_size; i++) {
    public_key[i] = (private_key[i] * n) % m;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmallocz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0xffffffffffffffff,-0x18(%rbp)
  jne    L7
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <panic@plt>
L7:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: xmallocz: data too large to fit into virtual memory space


assistant: ```c
__attribute__((visibility("hidden"))) void *xmallocz(size_t size) {
  void *ptr;
  if (size + 1 < size)
    panic("xmallocz: data too large to fit "
          "into virtual memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xmallocz>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0xffffffffffffffff,%rdi
  je     L0
L2:
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
L0:
  lea    D0(%rip),%rdi
  call   <panic@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: xmallocz: data too large to fit into virtual memory space


assistant: ```c
__attribute__((visibility("hidden"))) void *xmallocz(size_t size) {
  void *ptr;
  if (size + 1 < size)
    panic("xmallocz: data too large to fit "
          "into virtual memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<xmallocz>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0xffffffffffffffff,%rdi
  je     L9
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
  nopl   (%rax)
L9:
  lea    D7(%rip),%rdi
  call   <panic@plt>
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: xmallocz: data too large to fit into virtual memory space


assistant: ```c
__attribute__((visibility("hidden"))) void *xmallocz(size_t size) {
  void *ptr;
  if (size + 1 < size)
    panic("xmallocz: data too large to fit "
          "into virtual memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmallocz>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0xffffffffffffffff,%rdi
  je     L0
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
  nopl   (%rax)
L0:
  lea    D2(%rip),%rdi
  call   <panic@plt>
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: xmallocz: data too large to fit into virtual memory space


assistant: ```c
__attribute__((visibility("hidden"))) void *xmallocz(size_t size) {
  void *ptr;
  if (size + 1 < size)
    panic("xmallocz: data too large to fit "
          "into virtual memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L15:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string

tool: D16: Code:

tool: D0:  %d

assistant: ```c
void print_code(unsigned char *test) {
  printf("Code:");
  int i = 0;
  while (test[i] != 0) {
    printf(" %d", test[i++]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_code>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L0
  add    $0x1,%rbx
  lea    D16(%rip),%rbp
L6:
  movzbl %sil,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L6
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D4: Code:

tool: D16:  %d

assistant: ```c
void print_code(unsigned char *test) {
  printf("Code:");
  int i = 0;
  while (test[i] != 0) {
    printf(" %d", test[i++]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_code>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  lea    D15(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L6
  add    $0x1,%rbx
  lea    D11(%rip),%rbp
  xchg   %ax,%ax
L14:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L14
L6:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D11
type_infered: string

tool: D15: Code:

tool: D11:  %d

assistant: ```c
void print_code(unsigned char *test) {
  printf("Code:");
  int i = 0;
  while (test[i] != 0) {
    printf(" %d", test[i++]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_code>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L15
  add    $0x1,%rbx
  lea    D17(%rip),%rbp
  xchg   %ax,%ax
L10:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L10
L15:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string

tool: D1: Code:

tool: D17:  %d

assistant: ```c
void print_code(unsigned char *test) {
  printf("Code:");
  int i = 0;
  while (test[i] != 0) {
    printf(" %d", test[i++]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncat_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x333231,-0x10(%rbp)
  movb   $0x0,-0x11(%rbp)
  lea    -0x11(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void strncat_empty() {
  char dst[8] = "123";
  char src[] = "";
  strncat(dst, src, 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<strncat_empty>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x333231,0x10(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <strncat@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncat_empty() {
  char dst[8] = "123";
  char src[] = "";
  strncat(dst, src, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncat_empty>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movq   $0x333231,0x10(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <strncat@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncat_empty() {
  char dst[8] = "123";
  char src[] = "";
  strncat(dst, src, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncat_empty>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movq   $0x333231,0x10(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <strncat@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncat_empty() {
  char dst[8] = "123";
  char src[] = "";
  strncat(dst, src, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L92:
  cmp    %rdx,%rsp
  je     L57
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L92
L57:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L19
  orq    $0x0,-0x8(%rsp,%rax,1)
L19:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L84
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r15
L9:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D26(%rip),%xmm0
  subsd  D0(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L9
L84:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L30
  mov    $0x0,%ebx
L69:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <stdlib_strided_dmeankbn2@plt>
  ucomisd %xmm0,%xmm0
  jp     L51
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L69
L30:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L36:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L51:
  lea    D17(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L36
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D26
type: f64
name: read_data
arguments: data_label: D0
type: f64
name: read_data
arguments: data_label: D17
type: string

tool: D26: 20000

tool: D0: 10000

tool: D17: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dmeankbn2(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L6
L58:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L58
L6:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L16
L90:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L70
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L98:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D10(%rip),%xmm0
  subsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L98
L70:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L97
  xor    %r14d,%r14d
  jmp    L29
  nopl   0x0(%rax)
L105:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L97
L29:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dmeankbn2@plt>
  ucomisd %xmm0,%xmm0
  jnp    L105
  lea    D19(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L38:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L97:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L16:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L90
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: f64
name: retrieve_data
arguments: tag: D11
datatype: f64
name: retrieve_data
arguments: tag: D19
datatype: string

tool: D10: 20000

tool: D11: 10000

tool: D19: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dmeankbn2(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L72
L116:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L116
L72:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L103
L81:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L64
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L93:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D6(%rip),%xmm0
  subsd  D23(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L93
L64:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L11
  xor    %r14d,%r14d
  jmp    L59
  nopl   0x0(%rax)
L7:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L11
L59:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dmeankbn2@plt>
  ucomisd %xmm0,%xmm0
  jnp    L7
  lea    D4(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L27:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L103:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L81
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: f64
name: disassemble_data
arguments: data_label: D23
type_guessed: f64
name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D6: 20000

tool: D23: 10000

tool: D4: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dmeankbn2(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What is the c source code of the assembly code below?

```asm
<solve_by_quaddobl_Laurent_homotopy_continuation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x308,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solve_by_quaddobl_Laurent_homotopy_continuation(int number_of_tasks) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(776, &number_of_tasks, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solve_by_quaddobl_Laurent_homotopy_continuation>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x308,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solve_by_quaddobl_Laurent_homotopy_continuation(int number_of_tasks) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(776, &number_of_tasks, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<solve_by_quaddobl_Laurent_homotopy_continuation>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x308,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solve_by_quaddobl_Laurent_homotopy_continuation(int number_of_tasks) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(776, &number_of_tasks, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solve_by_quaddobl_Laurent_homotopy_continuation>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x308,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solve_by_quaddobl_Laurent_homotopy_continuation(int number_of_tasks) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(776, &number_of_tasks, b, c, 0);
  return fail;
}
```