ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D32(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  mov    %r12,%rbx
  jmp    L96
  nopl   0x0(%rax)
L14:
  movsbl %al,%edi
  add    $0x1,%ebp
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    $0x32,%ebp
  je     L93
L96:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  cmp    $0xa,%al
  jne    L14
  lea    D29(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L98
L82:
  xor    %ebx,%ebx
  lea    D10(%rip),%r13
  nopl   0x0(%rax)
L67:
  movsbl (%r12,%rbx,1),%edi
  lea    -0x41(%rdi),%eax
  cmp    $0x12,%al
  ja     L74
  movzbl %al,%eax
  movslq 0x0(%r13,%rax,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L74:
  call   <putchar@plt>
  nopl   (%rax)
L118:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L67
L98:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
  mov    $0x35,%edi
  call   <putchar@plt>
  jmp    L118
  nopl   0x0(%rax)
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L118
  nopl   0x0(%rax)
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L118
  nopl   0x0(%rax)
  mov    $0x33,%edi
  call   <putchar@plt>
  jmp    L118
  nopl   0x0(%rax)
  mov    $0x38,%edi
  call   <putchar@plt>
  jmp    L118
  nop
  mov    $0x34,%edi
  call   <putchar@plt>
  jmp    L118
L93:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D34
datatype: string

tool: D32: enter the character: 

tool: D29: BIFF-speak: 


tool: D34: !!!!!!!!!!



assistant: ```c
int main(void) {
  char character[50];
  int i, n;
  printf("enter the character: ");
  for (n = 0; n < ((int)(sizeof(character) / sizeof(character[0]))); n++) {
    if ((character[n] = getchar()) == '\n')
      break;
    character[n] = toupper(character[n]);
  }
  printf("BIFF-speak: \n");
  for (i = 0; i < n; i++) {
    switch (character[i]) {
    case 'A':
      putchar('4');
      break;
    case 'B':
      putchar('8');
      break;
    case 'E':
      putchar('3');
      break;
    case 'I':
      putchar('1');
      break;
    case 'O':
      putchar('0');
      break;
    case 'S':
      putchar('5');
      break;
    default:
      putchar(character[i]);
    }
  }
  printf("!!!!!!!!!!\n\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dump_labeling>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L22
L15:
  movl   $0x1,-0x4(%rbp)
  jmp    L29
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L20
  mov    $0xa,%edi
  call   <putchar@plt>
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D14: labeling dump:

tool: D13: NULL

assistant: ```c
void dump_labeling(char *labeling, int c) {
  int i;
  printf("labeling dump:\n");
  if (labeling == NULL) {
    printf("NULL\n");
    return;
  }
  for (i = 1; i <= c; i++) {
    printf("%c", labeling[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dump_labeling>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    D5(%rip),%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  je     L20
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L8
L37:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L37
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string
name: retrieve_data
arguments: data_tag: D10
data_type: string

tool: D5: labeling dump:

tool: D10: NULL

assistant: ```c
void dump_labeling(char *labeling, int c) {
  int i;
  printf("labeling dump:\n");
  if (labeling == NULL) {
    printf("NULL\n");
    return;
  }
  for (i = 1; i <= c; i++) {
    printf("%c", labeling[i]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dump_labeling>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D16(%rip),%rdi
  push   %rbx
  call   <puts@plt>
  test   %rbp,%rbp
  je     L10
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L8
  nopl   0x0(%rax)
L0:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L0
L8:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L10:
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D16: labeling dump:

tool: D10: NULL

assistant: ```c
void dump_labeling(char *labeling, int c) {
  int i;
  printf("labeling dump:\n");
  if (labeling == NULL) {
    printf("NULL\n");
    return;
  }
  for (i = 1; i <= c; i++) {
    printf("%c", labeling[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dump_labeling>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  push   %rbx
  call   <puts@plt>
  test   %rbp,%rbp
  je     L7
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L16
  nopl   0x0(%rax)
L24:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L24
L16:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L7:
  pop    %rbx
  lea    D15(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string

tool: D13: labeling dump:

tool: D15: NULL

assistant: ```c
void dump_labeling(char *labeling, int c) {
  int i;
  printf("labeling dump:\n");
  if (labeling == NULL) {
    printf("NULL\n");
    return;
  }
  for (i = 1; i <= c; i++) {
    printf("%c", labeling[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x77202c6f6c6c6568,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x646c726f,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x15(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <rotate@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s


assistant: ```c
int main() {
  char tst[] = "hello, world";
  rotate(tst, 9, 12);
  printf("%s\n", tst);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x77202c6f6c6c6568,%rax
  mov    %rax,0xb(%rsp)
  movl   $0x646c726f,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xb(%rsp),%rbx
  mov    $0xc,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <rotate@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %s


assistant: ```c
int main() {
  char tst[] = "hello, world";
  rotate(tst, 9, 12);
  printf("%s\n", tst);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x9,%esi
  mov    $0xc,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x77202c6f6c6c6568,%rax
  lea    0xb(%rsp),%rbp
  movl   $0x646c726f,0x13(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  call   <rotate@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %s


assistant: ```c
int main() {
  char tst[] = "hello, world";
  rotate(tst, 9, 12);
  printf("%s\n", tst);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x9,%esi
  mov    $0xc,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x77202c6f6c6c6568,%rax
  lea    0xb(%rsp),%rbp
  movl   $0x646c726f,0x13(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  call   <rotate@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: %s


assistant: ```c
int main() {
  char tst[] = "hello, world";
  rotate(tst, 9, 12);
  printf("%s\n", tst);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<conjecture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L5
L116:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L117
  movl   $0x2,-0xc(%rbp)
  jmp    L108
L9:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L88
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L46
L51:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L83
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L83
  movl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L88
L83:
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L51
L88:
  cmpl   $0x0,-0x4(%rbp)
  je     L95
  movl   $0x0,-0x4(%rbp)
  jmp    L117
L95:
  addl   $0x1,-0xc(%rbp)
L108:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L9
L117:
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L116
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: %3i = %3i + %3i


assistant: ```c
void conjecture(int low, int high) {
  int i, j, k, primeSumFound = 0;
  for (i = low; i <= high; i++) {
    if (i % 2 == 0) {
      for (j = 2; j < high; j++) {
        if (is_prime(j)) {
          for (k = j; k < high; k++) {
            if (k + j == i && is_prime(k)) {
              primeSumFound = 1;
              printf("%3i = %3i + %3i\n", i, j, k);
              break;
            }
          }
        }
        if (primeSumFound) {
          primeSumFound = 0;
          break;
        }
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<conjecture>:
  endbr64
  cmp    %esi,%edi
  jg     L11
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%r12d
  lea    D1(%rip),%r14
  jmp    L34
L44:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L64
L13:
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %r13d,%eax
  jne    L44
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L44
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L68:
  add    $0x1,%r13d
  cmp    %r13d,%r12d
  jl     L57
L34:
  test   $0x1,%r13b
  jne    L68
  cmp    $0x2,%r12d
  jle    L68
  mov    $0x2,%ebp
  jmp    L79
L64:
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  je     L68
L79:
  mov    %ebp,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L64
  cmp    %ebp,%r12d
  jle    L64
  mov    %ebp,%ebx
  jmp    L13
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %3i = %3i + %3i


assistant: ```c
void conjecture(int low, int high) {
  int i, j, k, primeSumFound = 0;
  for (i = low; i <= high; i++) {
    if (i % 2 == 0) {
      for (j = 2; j < high; j++) {
        if (is_prime(j)) {
          for (k = j; k < high; k++) {
            if (k + j == i && is_prime(k)) {
              primeSumFound = 1;
              printf("%3i = %3i + %3i\n", i, j, k);
              break;
            }
          }
        }
        if (primeSumFound) {
          primeSumFound = 0;
          break;
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<conjecture>:
  endbr64
  cmp    %esi,%edi
  jg     L129
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  jmp    L30
  nopl   0x0(%rax)
L2:
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jl     L37
L30:
  test   $0x1,%bpl
  jne    L2
  cmp    $0x2,%ebx
  jle    L2
  mov    $0x2,%r13d
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L89:
  add    $0x1,%r13d
  cmp    %r13d,%ebx
  je     L2
L9:
  mov    %r13d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L89
  mov    %r13d,%r12d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L65:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jle    L89
L45:
  lea    0x0(%r13,%r12,1),%eax
  cmp    %ebp,%eax
  jne    L65
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L65
  mov    %ebp,%esi
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jge    L30
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L129:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: %3i = %3i + %3i


assistant: ```c
void conjecture(int low, int high) {
  int i, j, k, primeSumFound = 0;
  for (i = low; i <= high; i++) {
    if (i % 2 == 0) {
      for (j = 2; j < high; j++) {
        if (is_prime(j)) {
          for (k = j; k < high; k++) {
            if (k + j == i && is_prime(k)) {
              primeSumFound = 1;
              printf("%3i = %3i + %3i\n", i, j, k);
              break;
            }
          }
        }
        if (primeSumFound) {
          primeSumFound = 0;
          break;
        }
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<conjecture>:
  endbr64
  cmp    %esi,%edi
  jg     L28
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  jmp    L26
  nopl   0x0(%rax)
L118:
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jl     L72
L26:
  test   $0x1,%bpl
  jne    L118
  cmp    $0x2,%ebx
  jle    L118
  mov    $0x2,%r13d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%r13d
  cmp    %r13d,%ebx
  je     L118
L6:
  mov    %r13d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L51
  mov    %r13d,%r12d
  jmp    L110
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jle    L51
L110:
  lea    0x0(%r13,%r12,1),%eax
  cmp    %ebp,%eax
  jne    L0
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L0
  mov    %ebp,%esi
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jge    L26
L72:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %3i = %3i + %3i


assistant: ```c
void conjecture(int low, int high) {
  int i, j, k, primeSumFound = 0;
  for (i = low; i <= high; i++) {
    if (i % 2 == 0) {
      for (j = 2; j < high; j++) {
        if (is_prime(j)) {
          for (k = j; k < high; k++) {
            if (k + j == i && is_prime(k)) {
              primeSumFound = 1;
              printf("%3i = %3i + %3i\n", i, j, k);
              break;
            }
          }
        }
        if (primeSumFound) {
          primeSumFound = 0;
          break;
        }
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_affection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L43:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L43
  sub    $0xe50,%rsp
  mov    %rdi,-0x4e48(%rbp)
  mov    %rsi,-0x4e50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4e48(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <open_file@plt>
  mov    %rax,-0x4e38(%rbp)
  movl   $0x0,-0x4e3c(%rbp)
  jmp    L44
L48:
  lea    -0x4e40(%rbp),%rdx
  lea    -0x4e30(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x4e3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x4e50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4e40(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4e3c(%rbp)
L44:
  mov    -0x4e38(%rbp),%rdx
  lea    -0x4e30(%rbp),%rax
  mov    $0x4e20,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L21
  movzbl -0x4e30(%rbp),%eax
  test   %al,%al
  jne    L48
L21:
  mov    -0x4e3c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D3
type: string

tool: D0: r

tool: D3: %d

assistant: ```c
int read_affection(char *filename, int *affection) {
  FILE *infile;
  char buf[20000];
  int indicator, count;
  infile = open_file(filename, "r");
  count = 0;
  while ((fgets(buf, 20000, infile) != NULL) && buf[0] != '\0') {
    sscanf(buf, "%d", &indicator);
    affection[count] = indicator;
    count++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<read_affection>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L33:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L33
  sub    $0xe40,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x4e38(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rsi
  call   <open_file@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D17(%rip),%r14
  jmp    L24
L30:
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
L24:
  mov    %ebx,%r13d
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0x4e20,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L36
  cmpb   $0x0,0x10(%rsp)
  jne    L30
L36:
  mov    0x4e38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %r13d,%eax
  add    $0x4e40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D17
data_type: string

tool: D5: r

tool: D17: %d

assistant: ```c
int read_affection(char *filename, int *affection) {
  FILE *infile;
  char buf[20000];
  int indicator, count;
  infile = open_file(filename, "r");
  count = 0;
  while ((fgets(buf, 20000, infile) != NULL) && buf[0] != '\0') {
    sscanf(buf, "%d", &indicator);
    affection[count] = indicator;
    count++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_affection>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0xe48,%rsp
  xor    %ebx,%ebx
  lea    D10(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x4e38(%rsp)
  xor    %eax,%eax
  mov    %rsi,%r13
  lea    D5(%rip),%rsi
  lea    0x10(%rsp),%rbp
  call   <open_file@plt>
  mov    %rax,%r12
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L49:
  cmpb   $0x0,0x10(%rsp)
  je     L15
  lea    0xc(%rsp),%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
L14:
  mov    %r12,%rdx
  mov    $0x4e20,%esi
  mov    %rbp,%rdi
  mov    %ebx,%r14d
  call   <fgets@plt>
  test   %rax,%rax
  jne    L49
L15:
  mov    0x4e38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x4e48,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D10: %d

tool: D5: r

assistant: ```c
int read_affection(char *filename, int *affection) {
  FILE *infile;
  char buf[20000];
  int indicator, count;
  infile = open_file(filename, "r");
  count = 0;
  while ((fgets(buf, 20000, infile) != NULL) && buf[0] != '\0') {
    sscanf(buf, "%d", &indicator);
    affection[count] = indicator;
    count++;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_affection>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L43:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L43
  sub    $0xe48,%rsp
  xor    %ebx,%ebx
  lea    D0(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x4e38(%rsp)
  xor    %eax,%eax
  mov    %rsi,%r13
  lea    D1(%rip),%rsi
  lea    0x10(%rsp),%rbp
  call   <open_file@plt>
  mov    %rax,%r12
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L46:
  cmpb   $0x0,0x10(%rsp)
  je     L21
  lea    0xc(%rsp),%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
L31:
  mov    %r12,%rdx
  mov    $0x4e20,%esi
  mov    %rbp,%rdi
  mov    %ebx,%r14d
  call   <fgets@plt>
  test   %rax,%rax
  jne    L46
L21:
  mov    0x4e38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x4e48,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D0: %d

tool: D1: r

assistant: ```c
int read_affection(char *filename, int *affection) {
  FILE *infile;
  char buf[20000];
  int indicator, count;
  infile = open_file(filename, "r");
  count = 0;
  while ((fgets(buf, 20000, infile) != NULL) && buf[0] != '\0') {
    sscanf(buf, "%d", &indicator);
    affection[count] = indicator;
    count++;
  }
  return count;
}
```