ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_oligo_header>:
  endbr64
  test   %ecx,%ecx
  jne    L6
  test   %edx,%edx
  lea    D51(%rip),%rcx
  lea    D33(%rip),%rax
  mov    %rsi,%rdx
  cmove  %rax,%rcx
  lea    D28(%rip),%rsi
  jmp    1050 <fprintf@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  test   %edx,%edx
  lea    D51(%rip),%rcx
  lea    D33(%rip),%rax
  mov    %rsi,%rdx
  cmove  %rax,%rcx
  lea    D22(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D51
type: string
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string

tool: D51:   rep 

tool: 

tool: D28: %-16s start  len      tm     gc%%   any    3' %sseq


tool: D22: %-16s start  len      tm     gc%%  any_th  3'_th hairpin %sseq


assistant: ```c
void print_oligo_header(FILE *f, const char *s, const int print_lib_sim, const int thermodynamic_oligo_alignment) {
  if (thermodynamic_oligo_alignment == 0)
    fprintf(f, "%-16s start  len      tm     gc%%   any    3' %sseq\n", s, print_lib_sim ? "  rep " : "");
  else
    fprintf(f, "%-16s start  len      tm     gc%%  any_th  3'_th hairpin %sseq\n", s, print_lib_sim ? "  rep " : "");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string

tool: D13: %d%d%d

tool: D12: %d

assistant: ```c
int main() {
  int a, b, c, volume;
  scanf("%d%d%d", &a, &b, &c);
  printf("%d", volume = a * b * c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  imul   0x14(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string

tool: D0: %d%d%d

tool: D11: %d

assistant: ```c
int main() {
  int a, b, c, volume;
  scanf("%d%d%d", &a, &b, &c);
  printf("%d", volume = a * b * c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D10(%rip),%rdi
  imul   0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D1: %d%d%d

tool: D10: %d

assistant: ```c
int main() {
  int a, b, c, volume;
  scanf("%d%d%d", &a, &b, &c);
  printf("%d", volume = a * b * c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D18(%rip),%rdi
  imul   0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D18
type_infered: string

tool: D7: %d%d%d

tool: D18: %d

assistant: ```c
int main() {
  int a, b, c, volume;
  scanf("%d%d%d", &a, &b, &c);
  printf("%d", volume = a * b * c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L66
  cmpq   $0x0,-0x20(%rbp)
  je     L66
  cmpq   $0x0,-0x18(%rbp)
  jns    L45
  cmpq   $0x0,-0x20(%rbp)
  jns    L45
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jge    L66
L45:
  cmpq   $0x0,-0x18(%rbp)
  jns    L98
  cmpq   $0x0,-0x20(%rbp)
  jg     L66
L98:
  cmpq   $0x0,-0x18(%rbp)
  jle    L1
  cmpq   $0x0,-0x20(%rbp)
  js     L66
L1:
  cmpq   $0x0,-0x18(%rbp)
  jle    L147
  cmpq   $0x0,-0x20(%rbp)
  jle    L147
  mov    -0x30(%rbp),%rax
  sub    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jg     L147
L66:
  mov    $0x1,%eax
  jmp    L128
L147:
  mov    $0x0,%eax
L128:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L113
  cmpl   $0x0,-0x34(%rbp)
  je     L113
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <warning@plt>
  movl   $0x1,-0x4(%rbp)
L113:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: overflow in constant expression


assistant: ```c
int addi(long x, long y, long min, long max, int needconst) {
  int cond = x == 0 || y == 0 || (x < 0 && y < 0 && x >= min - y) || (x < 0 && y > 0) || (x > 0 && y < 0) || (x > 0 && y > 0 && x <= max - y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: What is the c source code of the assembly code below?

```asm
<addi>:
  endbr64
  test   %rdi,%rdi
  je     L103
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L103
  shr    $0x3f,%rdi
  mov    %rsi,%r9
  shr    $0x3f,%r9
  test   %rsi,%rax
  jns    L115
  sub    %rsi,%rdx
  mov    $0x1,%edi
  cmp    %rax,%rdx
  jle    L92
  test   %rsi,%rsi
  setg   %dl
L55:
  test   %rax,%rax
  setg   %r10b
  test   %r9b,%r9b
  je     L27
  mov    $0x1,%edi
  test   %r10b,%r10b
  jne    L92
L27:
  test   %r10b,%r10b
  je     L75
  test   %dl,%dl
  je     L75
  sub    %rsi,%rcx
  mov    $0x1,%edi
  cmp    %rax,%rcx
  jge    L92
L75:
  test   %r8d,%r8d
  je     L116
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%edi
  mov    %edi,%eax
  add    $0x8,%rsp
  ret
L115:
  test   %rsi,%rsi
  setg   %dl
  test   %dil,%dil
  je     L55
  mov    $0x1,%edi
  test   %dl,%dl
  jne    L92
  jmp    L55
L103:
  mov    $0x1,%edi
L92:
  mov    %edi,%eax
  ret
L116:
  mov    %r8d,%edi
  jmp    L92
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: overflow in constant expression


assistant: ```c
int addi(long x, long y, long min, long max, int needconst) {
  int cond = x == 0 || y == 0 || (x < 0 && y < 0 && x >= min - y) || (x < 0 && y > 0) || (x > 0 && y < 0) || (x > 0 && y > 0 && x <= max - y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: What is the c source code of the assembly code below?

```asm
<addi>:
  endbr64
  test   %rdi,%rdi
  je     L99
  test   %rsi,%rsi
  je     L99
  mov    %rdi,%rax
  mov    %rsi,%r10
  shr    $0x3f,%rdi
  shr    $0x3f,%r10
  test   %rsi,%rax
  js     L44
  test   %rsi,%rsi
  setg   %dl
  test   %dil,%dil
  je     L7
  mov    $0x1,%r9d
  test   %dl,%dl
  jne    L136
L7:
  test   %rax,%rax
  setg   %dil
  test   %r10b,%r10b
  je     L25
  test   %dil,%dil
  je     L25
  nopw   0x0(%rax,%rax,1)
L99:
  mov    $0x1,%r9d
L136:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  sub    %rsi,%rdx
  mov    $0x1,%r9d
  cmp    %rax,%rdx
  jle    L136
L130:
  test   %r8d,%r8d
  je     L46
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L25:
  test   %dl,%dl
  je     L130
  test   %dil,%dil
  je     L130
  sub    %rsi,%rcx
  mov    $0x1,%r9d
  cmp    %rax,%rcx
  jge    L136
  jmp    L130
L46:
  xor    %r9d,%r9d
  jmp    L136
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: overflow in constant expression


assistant: ```c
int addi(long x, long y, long min, long max, int needconst) {
  int cond = x == 0 || y == 0 || (x < 0 && y < 0 && x >= min - y) || (x < 0 && y > 0) || (x > 0 && y < 0) || (x > 0 && y > 0 && x <= max - y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<addi>:
  endbr64
  test   %rdi,%rdi
  je     L23
  test   %rsi,%rsi
  je     L23
  mov    %rdi,%rax
  mov    %rsi,%r10
  shr    $0x3f,%rdi
  shr    $0x3f,%r10
  test   %rsi,%rax
  js     L24
  test   %rsi,%rsi
  setg   %dl
  test   %dil,%dil
  je     L67
  mov    $0x1,%r9d
  test   %dl,%dl
  jne    L124
L67:
  test   %rax,%rax
  setg   %dil
  test   %r10b,%r10b
  je     L68
  test   %dil,%dil
  je     L68
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x1,%r9d
L124:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  sub    %rsi,%rdx
  mov    $0x1,%r9d
  cmp    %rax,%rdx
  jle    L124
L132:
  test   %r8d,%r8d
  je     L108
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L68:
  test   %dl,%dl
  je     L132
  test   %dil,%dil
  je     L132
  sub    %rsi,%rcx
  mov    $0x1,%r9d
  cmp    %rax,%rcx
  jge    L124
  jmp    L132
L108:
  xor    %r9d,%r9d
  jmp    L124
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: overflow in constant expression


assistant: ```c
int addi(long x, long y, long min, long max, int needconst) {
  int cond = x == 0 || y == 0 || (x < 0 && y < 0 && x >= min - y) || (x < 0 && y > 0) || (x > 0 && y < 0) || (x > 0 && y > 0 && x <= max - y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xbb8,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <config_timer@plt>
L3:
  jmp    L3
```

assistant: ```c
int main() {
  config_timer(0, 1, 0, 0, 3000);
  while (1)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xbb8,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <config_timer@plt>
L5:
  jmp    L5
```

assistant: ```c
int main() {
  config_timer(0, 1, 0, 0, 3000);
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xbb8,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <config_timer@plt>
L1:
  jmp    L1
```

assistant: ```c
int main() {
  config_timer(0, 1, 0, 0, 3000);
  while (1)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xbb8,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <config_timer@plt>
L6:
  jmp    L6
```

assistant: ```c
int main() {
  config_timer(0, 1, 0, 0, 3000);
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4ee728,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x63427,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5a06e,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2427e6,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x21507d,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D38
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string
name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D34
data_type: string

tool: D1: Reversed 5170984 = %d


tool: D38: Reversed 406567 = %d


tool: D5: Reversed 368750 = %d


tool: D48: Reversed2369510 = %d


tool: D34: Reversed 2183293 = %d


assistant: ```c
int main() {
  printf("Reversed 5170984 = %d\n", reversed_number(5170984));
  printf("Reversed 406567 = %d\n", reversed_number(406567));
  printf("Reversed 368750 = %d\n", reversed_number(368750));
  printf("Reversed2369510 = %d\n", reversed_number(2369510));
  printf("Reversed 2183293 = %d\n", reversed_number(2183293));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4ee728,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x63427,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x5a06e,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x2427e6,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x21507d,%edi
  call   <reversed_number@plt>
  mov    %eax,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D19
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string

tool: D12: Reversed 5170984 = %d


tool: D23: Reversed 406567 = %d


tool: D19: Reversed 368750 = %d


tool: D1: Reversed2369510 = %d


tool: D26: Reversed 2183293 = %d


assistant: ```c
int main() {
  printf("Reversed 5170984 = %d\n", reversed_number(5170984));
  printf("Reversed 406567 = %d\n", reversed_number(406567));
  printf("Reversed 368750 = %d\n", reversed_number(368750));
  printf("Reversed2369510 = %d\n", reversed_number(2369510));
  printf("Reversed 2183293 = %d\n", reversed_number(2183293));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4ee728,%edi
  call   <reversed_number@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x63427,%edi
  call   <reversed_number@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5a06e,%edi
  call   <reversed_number@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2427e6,%edi
  call   <reversed_number@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x21507d,%edi
  call   <reversed_number@plt>
  lea    D30(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string
name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D30
data_type: string

tool: D3: Reversed 5170984 = %d


tool: D21: Reversed 406567 = %d


tool: D1: Reversed 368750 = %d


tool: D29: Reversed2369510 = %d


tool: D30: Reversed 2183293 = %d


assistant: ```c
int main() {
  printf("Reversed 5170984 = %d\n", reversed_number(5170984));
  printf("Reversed 406567 = %d\n", reversed_number(406567));
  printf("Reversed 368750 = %d\n", reversed_number(368750));
  printf("Reversed2369510 = %d\n", reversed_number(2369510));
  printf("Reversed 2183293 = %d\n", reversed_number(2183293));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4ee728,%edi
  call   <reversed_number@plt>
  lea    D43(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x63427,%edi
  call   <reversed_number@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5a06e,%edi
  call   <reversed_number@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2427e6,%edi
  call   <reversed_number@plt>
  lea    D36(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x21507d,%edi
  call   <reversed_number@plt>
  lea    D42(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D43
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string
name: parse_data
arguments: data_label: D42
type_guessed: string

tool: D43: Reversed 5170984 = %d


tool: D11: Reversed 406567 = %d


tool: D2: Reversed 368750 = %d


tool: D36: Reversed2369510 = %d


tool: D42: Reversed 2183293 = %d


assistant: ```c
int main() {
  printf("Reversed 5170984 = %d\n", reversed_number(5170984));
  printf("Reversed 406567 = %d\n", reversed_number(406567));
  printf("Reversed 368750 = %d\n", reversed_number(368750));
  printf("Reversed2369510 = %d\n", reversed_number(2369510));
  printf("Reversed 2183293 = %d\n", reversed_number(2183293));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scsi_smartDEXCPTdisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %edi,-0x114(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rdx
  mov    -0x114(%rbp),%eax
  mov    $0xff,%ecx
  mov    $0x1c,%esi
  mov    %eax,%edi
  call   <scsi_modesense@plt>
  test   %rax,%rax
  je     L23
  mov    $0x1,%eax
  jmp    L3
L23:
  movzbl -0x102(%rbp),%eax
  movzbl %al,%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L41
  movzbl -0x102(%rbp),%eax
  and    $0xfffffff7,%eax
  mov    %al,-0x102(%rbp)
  movb   $0x4,-0x101(%rbp)
  lea    -0x110(%rbp),%rdx
  mov    -0x114(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <scsi_modeselect@plt>
  jmp    L3
L41:
  mov    $0x0,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int scsi_smartDEXCPTdisable(int device) {
  unsigned char buf[255];
  if (scsi_modesense(device, 0x1c, buf, sizeof(buf)) != 0)
    return 1;
  if (buf[14] & 0x08) {
    buf[14] &= 0xf7;
    buf[15] = 0x04;
    return scsi_modeselect(device, buf);
  } else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scsi_smartDEXCPTdisable>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0xff,%ecx
  mov    $0x1c,%esi
  call   <scsi_modesense@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L3
  movzbl 0xe(%rsp),%edx
  mov    $0x0,%eax
  test   $0x8,%dl
  jne    L23
L3:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x110,%rsp
  pop    %rbx
  ret
L23:
  and    $0xfffffff7,%edx
  mov    %dl,0xe(%rsp)
  movb   $0x4,0xf(%rsp)
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <scsi_modeselect@plt>
  jmp    L3
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scsi_smartDEXCPTdisable(int device) {
  unsigned char buf[255];
  if (scsi_modesense(device, 0x1c, buf, sizeof(buf)) != 0)
    return 1;
  if (buf[14] & 0x08) {
    buf[14] &= 0xf7;
    buf[15] = 0x04;
    return scsi_modeselect(device, buf);
  } else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scsi_smartDEXCPTdisable>:
  endbr64
  push   %r12
  mov    $0xff,%ecx
  mov    $0x1c,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdx
  call   <scsi_modesense@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L0
  movzbl 0xe(%rsp),%edx
  xor    %eax,%eax
  test   $0x8,%dl
  jne    L11
L0:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L11:
  and    $0xfffffff7,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movb   $0x4,0xf(%rsp)
  mov    %dl,0xe(%rsp)
  call   <scsi_modeselect@plt>
  jmp    L0
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scsi_smartDEXCPTdisable(int device) {
  unsigned char buf[255];
  if (scsi_modesense(device, 0x1c, buf, sizeof(buf)) != 0)
    return 1;
  if (buf[14] & 0x08) {
    buf[14] &= 0xf7;
    buf[15] = 0x04;
    return scsi_modeselect(device, buf);
  } else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scsi_smartDEXCPTdisable>:
  endbr64
  push   %r12
  mov    $0xff,%ecx
  mov    $0x1c,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdx
  call   <scsi_modesense@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L32
  movzbl 0xe(%rsp),%edx
  xor    %eax,%eax
  test   $0x8,%dl
  jne    L29
L32:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L29:
  and    $0xfffffff7,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movb   $0x4,0xf(%rsp)
  mov    %dl,0xe(%rsp)
  call   <scsi_modeselect@plt>
  jmp    L32
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scsi_smartDEXCPTdisable(int device) {
  unsigned char buf[255];
  if (scsi_modesense(device, 0x1c, buf, sizeof(buf)) != 0)
    return 1;
  if (buf[14] & 0x08) {
    buf[14] &= 0xf7;
    buf[15] = 0x04;
    return scsi_modeselect(device, buf);
  } else
    return 0;
}
```