ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x5,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <createQueue@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  mov    $0x1,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  mov    $0x2,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  mov    $0x3,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  mov    $0x4,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  mov    $0x5,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  mov    $0x6,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  call   <print@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <print@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <print@plt>
  mov    %rsp,%rdi
  call   <destroyQueue@plt>
  mov    (%rsp),%rdi
  mov    $0x1,%esi
  call   <enqueue@plt>
  mov    (%rsp),%rdi
  call   <dequeue@plt>
  mov    (%rsp),%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct CircularQueue *queue = createQueue(5);
  dequeue(queue);
  enqueue(queue, 1);
  enqueue(queue, 2);
  enqueue(queue, 3);
  enqueue(queue, 4);
  enqueue(queue, 5);
  enqueue(queue, 6);
  print(queue);
  dequeue(queue);
  dequeue(queue);
  print(queue);
  dequeue(queue);
  dequeue(queue);
  dequeue(queue);
  dequeue(queue);
  print(queue);
  destroyQueue(&queue);
  enqueue(queue, 1);
  dequeue(queue);
  print(queue);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myPow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L10:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int myPow(int n, int p) {
  int r = 1;
  int i;
  for (i = 0; i < p; i++) {
    r *= n;
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myPow>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    $0x0,%eax
  mov    $0x1,%edx
L8:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L8
L20:
  mov    %edx,%eax
  ret
L13:
  mov    $0x1,%edx
  jmp    L20
```

assistant: ```c
int myPow(int n, int p) {
  int r = 1;
  int i;
  for (i = 0; i < p; i++) {
    r *= n;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<myPow>:
  endbr64
  test   %esi,%esi
  jle    L13
  xor    %eax,%eax
  mov    $0x1,%r8d
L7:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L7
  mov    %r8d,%eax
  ret
  nop
L13:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int myPow(int n, int p) {
  int r = 1;
  int i;
  for (i = 0; i < p; i++) {
    r *= n;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<myPow>:
  endbr64
  test   %esi,%esi
  jle    L2
  xor    %eax,%eax
  mov    $0x1,%r8d
L5:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L5
  mov    %r8d,%eax
  ret
  nop
L2:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int myPow(int n, int p) {
  int r = 1;
  int i;
  for (i = 0; i < p; i++) {
    r *= n;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <warnx@plt>
  mov    $0x0,%eax
  call   <crash@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: realloc failed

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *p;
  if ((p = realloc(ptr, size)) == NULL) {
    warnx("realloc failed");
    crash();
  }
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrealloc>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L13:
  lea    D1(%rip),%rdi
  call   <warnx@plt>
  mov    $0x0,%eax
  call   <crash@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: realloc failed

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *p;
  if ((p = realloc(ptr, size)) == NULL) {
    warnx("realloc failed");
    crash();
  }
  return (p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L7:
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  lea    D5(%rip),%rdi
  call   <warnx@plt>
  xor    %eax,%eax
  call   <crash@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: realloc failed

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *p;
  if ((p = realloc(ptr, size)) == NULL) {
    warnx("realloc failed");
    crash();
  }
  return (p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L9:
  mov    %r12,%rax
  pop    %r12
  ret
L14:
  lea    D1(%rip),%rdi
  call   <warnx@plt>
  xor    %eax,%eax
  call   <crash@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: realloc failed

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *p;
  if ((p = realloc(ptr, size)) == NULL) {
    warnx("realloc failed");
    crash();
  }
  return (p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<os_is_setuid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L5
  mov    $0x1,%eax
  jmp    L23
L5:
  mov    $0x0,%eax
L23:
  leave
  ret
```

assistant: ```c
int os_is_setuid() {
  long uid, euid;
  uid = getuid();
  euid = geteuid();
  return (euid == 0 && euid != uid);
}
```
user: What is the c source code of the assembly code below?

```asm
<os_is_setuid>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  sete   %dl
  cmp    %rax,%rbx
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int os_is_setuid() {
  long uid, euid;
  uid = getuid();
  euid = geteuid();
  return (euid == 0 && euid != uid);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<os_is_setuid>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  sete   %dl
  cmp    %rax,%rbx
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int os_is_setuid() {
  long uid, euid;
  uid = getuid();
  euid = geteuid();
  return (euid == 0 && euid != uid);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<os_is_setuid>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  sete   %dl
  cmp    %rax,%rbx
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int os_is_setuid() {
  long uid, euid;
  uid = getuid();
  euid = geteuid();
  return (euid == 0 && euid != uid);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sokalsneath_distance_bool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L79:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  mov    $0x1,%eax
  jmp    L12
L49:
  mov    $0x0,%eax
L12:
  add    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x1,%eax
  jmp    L39
L1:
  mov    $0x0,%eax
L39:
  add    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    $0x1,%eax
  jmp    L16
L7:
  mov    $0x0,%eax
L16:
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L79
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  addsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double sokalsneath_distance_bool(const char *u, const char *v, int n) {
  int _i = 0;
  int ntt = 0, nft = 0, ntf = 0;
  for (_i = 0; _i < n; _i++) {
    ntt += (u[_i] && v[_i]);
    ntf += (u[_i] && !v[_i]);
    nft += (!u[_i] && v[_i]);
  }
  return (2.0 * (ntf + nft)) / (2.0 * (ntf + nft) + ntt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sokalsneath_distance_bool>:
  endbr64
  test   %edx,%edx
  jle    L47
  mov    %edx,%edx
  mov    $0x0,%eax
  mov    $0x0,%r10d
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    $0x0,%r11d
  jmp    L38
L64:
  cmpb   $0x0,(%rsi,%rax,1)
  setne  %r8b
  movzbl %r8b,%r8d
L3:
  add    %r8d,%ecx
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L85
L38:
  movzbl (%rdi,%rax,1),%r8d
  test   %r8b,%r8b
  je     L64
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L43
  jne    L77
  add    $0x1,%r10d
  mov    %r11d,%r8d
  jmp    L3
L47:
  mov    $0x0,%r10d
  mov    $0x0,%ecx
  mov    $0x0,%r9d
L85:
  add    %r10d,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  addsd  %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
L43:
  add    $0x1,%r9d
L77:
  test   %r8b,%r8b
  je     L64
  mov    %r11d,%r8d
  jmp    L3
```

assistant: ```c
double sokalsneath_distance_bool(const char *u, const char *v, int n) {
  int _i = 0;
  int ntt = 0, nft = 0, ntf = 0;
  for (_i = 0; _i < n; _i++) {
    ntt += (u[_i] && v[_i]);
    ntf += (u[_i] && !v[_i]);
    nft += (!u[_i] && v[_i]);
  }
  return (2.0 * (ntf + nft)) / (2.0 * (ntf + nft) + ntt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sokalsneath_distance_bool>:
  endbr64
  test   %edx,%edx
  jle    L33
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L21:
  test   %cl,%cl
  je     L22
  add    $0x1,%r10d
L55:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L62
L12:
  cmpb   $0x0,(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  jne    L21
  cmp    $0x1,%cl
  sbb    $0xffffffff,%r8d
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
L62:
  add    %r8d,%r9d
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm0
  cvtsi2sd %r10d,%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L22:
  add    $0x1,%r9d
  jmp    L55
  cs nopw 0x0(%rax,%rax,1)
L33:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double sokalsneath_distance_bool(const char *u, const char *v, int n) {
  int _i = 0;
  int ntt = 0, nft = 0, ntf = 0;
  for (_i = 0; _i < n; _i++) {
    ntt += (u[_i] && v[_i]);
    ntf += (u[_i] && !v[_i]);
    nft += (!u[_i] && v[_i]);
  }
  return (2.0 * (ntf + nft)) / (2.0 * (ntf + nft) + ntt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sokalsneath_distance_bool>:
  endbr64
  test   %edx,%edx
  jle    L39
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r10d,%r10d
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L54:
  test   %cl,%cl
  je     L62
  add    $0x1,%r9d
L30:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L12
L40:
  cmpb   $0x0,(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  jne    L54
  cmp    $0x1,%cl
  sbb    $0xffffffff,%r8d
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L40
L12:
  add    %r10d,%r8d
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm0
  cvtsi2sd %r9d,%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L62:
  add    $0x1,%r10d
  jmp    L30
  cs nopw 0x0(%rax,%rax,1)
L39:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double sokalsneath_distance_bool(const char *u, const char *v, int n) {
  int _i = 0;
  int ntt = 0, nft = 0, ntf = 0;
  for (_i = 0; _i < n; _i++) {
    ntt += (u[_i] && v[_i]);
    ntf += (u[_i] && !v[_i]);
    nft += (!u[_i] && v[_i]);
  }
  return (2.0 * (ntf + nft)) / (2.0 * (ntf + nft) + ntt);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _write(SSL_CTX *ctx, int sockfd) {
  int res = 0;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_write>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _write(SSL_CTX *ctx, int sockfd) {
  int res = 0;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_write>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int _write(SSL_CTX *ctx, int sockfd) {
  int res = 0;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movl   $0x0,-0x20(%rbp)
  jmp    L11
L7:
  movl   $0x0,-0x1c(%rbp)
  jmp    L2
L5:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: %d 

assistant: ```c
void printMatrix(int size, int m[size][size]) {
  int x, y;
  for (x = 0; x < size; ++x) {
    for (y = 0; y < size; ++y) {
      printf("%d ", m[x][y]);
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printMatrix>:
  endbr64
  test   %edi,%edi
  jle    L23
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  movslq %edi,%rax
  shl    $0x2,%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rbp
  mov    $0x0,%r13d
  mov    %edi,%r15d
  neg    %r15
  shl    $0x2,%r15
  lea    D9(%rip),%r12
L13:
  lea    (%r15,%rbp,1),%rbx
L14:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    0x8(%rsp),%rbp
  cmp    %r13d,%r14d
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: %d 

assistant: ```c
void printMatrix(int size, int m[size][size]) {
  int x, y;
  for (x = 0; x < size; ++x) {
    for (y = 0; y < size; ++y) {
      printf("%d ", m[x][y]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printMatrix>:
  endbr64
  push   %r15
  push   %r14
  movslq %edi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %r14d,%r14d
  jle    L18
  lea    0x0(,%r14,4),%rax
  mov    $0xfffffffffffffffc,%r15
  mov    %r14,%r13
  xor    %r12d,%r12d
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r14),%eax
  lea    D7(%rip),%rbp
  shl    $0x2,%rax
  lea    0x4(%rsi,%rax,1),%rbx
  sub    %rax,%r15
  nopl   0x0(%rax,%rax,1)
L24:
  lea    (%r15,%rbx,1),%r14
  nopl   0x0(%rax)
L27:
  mov    (%r14),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L27
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L24
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d 

assistant: ```c
void printMatrix(int size, int m[size][size]) {
  int x, y;
  for (x = 0; x < size; ++x) {
    for (y = 0; y < size; ++y) {
      printf("%d ", m[x][y]);
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printMatrix>:
  endbr64
  push   %r15
  push   %r14
  movslq %edi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %r14d,%r14d
  jle    L4
  lea    0x0(,%r14,4),%rax
  mov    $0xfffffffffffffffc,%r15
  mov    %r14,%r13
  xor    %r12d,%r12d
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r14),%eax
  lea    D8(%rip),%rbp
  shl    $0x2,%rax
  lea    0x4(%rsi,%rax,1),%rbx
  sub    %rax,%r15
  nopl   0x0(%rax,%rax,1)
L16:
  lea    (%r15,%rbx,1),%r14
  nopl   0x0(%rax)
L17:
  mov    (%r14),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L17
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L16
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: %d 

assistant: ```c
void printMatrix(int size, int m[size][size]) {
  int x, y;
  for (x = 0; x < size; ++x) {
    for (y = 0; y < size; ++y) {
      printf("%d ", m[x][y]);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<displayMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  lea    D109(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,0x8(%rsp)
  mov    $0x0,%r13d
  lea    D5(%rip),%rbp
  lea    D109(%rip),%r15
  jmp    L82
L38:
  lea    D4(%rip),%rsi
  lea    D80(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%ebx
L79:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L79
  mov    %r15,%rdi
  call   <puts@plt>
  lea    D4(%rip),%rsi
  lea    D80(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%r12
  lea    D11(%rip),%r14
L86:
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L86
  jmp    L2
L89:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  je     L31
L44:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jne    L89
  mov    %r15,%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L89
L31:
  add    $0x1,%r13d
  addq   $0x50,0x8(%rsp)
  cmp    $0x14,%r13d
  je     L93
L82:
  test   %r13d,%r13d
  je     L38
L2:
  mov    0x8(%rsp),%r12
  mov    $0x0,%ebx
  lea    D22(%rip),%r14
  jmp    L44
L93:
  lea    D109(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D109
type_guessed: string
name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D80
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string

tool: 

tool: D5:  %3d 

tool: D4:  

tool: D80:  %3s  

tool: D12: V

tool: D11:  %3s 

tool: D7: >

tool: D22:  %3d %s

assistant: ```c
void displayMatrix(const int A[][20]) {
  puts("");
  for (int i = 0; i < 20; i++) {
    if (i == 0) {
      printf(" %3s  ", " ");
      for (int j = 0; j < 20; j++) {
        printf(" %3d ", j);
      }
      puts("");
      printf(" %3s  ", " ");
      for (int j = 0; j < 20; j++) {
        printf(" %3s ", "V");
      }
    }
    for (int j = 0; j < 20; j++) {
      if (j % 20 == 0) {
        puts("");
        printf(" %3d %s", i, ">");
      }
      printf(" %3d ", A[i][j]);
    }
  }
  puts("");
}
```