ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_irc_pong>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <irc_pong@plt>
  mov    %rbp,%rdi
  call   <read_mock@plt>
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
L5:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x210,%rsp
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  lea    D24(%rip),%rdi
  call   <mu_fail@plt>
  jmp    L5
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D24
data_type: string

tool: D22: irc.freenode.net

tool: D27: PONG irc.freenode.net


tool: D24: test_irc_pong: msg should be 'PONG irc.freenode.net\r\n'

assistant: ```c
void test_irc_pong() {
  char msg[(512 + 1)];
  irc_pong("irc.freenode.net");
  read_mock(msg);
  do {
    if (!((strcmp(msg, "PONG irc.freenode.net\r\n") == 0))) {
      mu_fail("test_irc_pong: msg should be 'PONG irc.freenode.net\\r\\n'");
      return;
    }
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tcp_nonblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L47
  mov    $0xffffffff,%eax
  jmp    L23
L47:
  cmpl   $0x0,-0x18(%rbp)
  je     L35
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  or     %eax,-0x4(%rbp)
  jmp    L41
L35:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,-0x4(%rbp)
L41:
  mov    D12(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L57
  mov    $0xffffffff,%eax
  jmp    L23
L57:
  mov    $0x0,%eax
L23:
  leave
  ret
```

assistant: ```c
int tcp_nonblock(int fd, int non_block) {
  int flags = fcntl(fd, F_GETFL, 0);
  if (flags == -1)
    return -1;
  if (non_block) {
    flags |= O_NONBLOCK;
  } else {
    flags &= ~O_NONBLOCK;
  }
  if (fcntl(fd, F_SETFL, flags) == -1)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tcp_nonblock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L21
  test   %ebp,%ebp
  je     L8
  mov    D11(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
L18:
  mov    D20(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    D11(%rip),%rdx
  mov    (%rdx),%edx
  not    %edx
  and    %eax,%edx
  jmp    L18
```

assistant: ```c
int tcp_nonblock(int fd, int non_block) {
  int flags = fcntl(fd, F_GETFL, 0);
  if (flags == -1)
    return -1;
  if (non_block) {
    flags |= O_NONBLOCK;
  } else {
    flags &= ~O_NONBLOCK;
  }
  if (fcntl(fd, F_SETFL, flags) == -1)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tcp_nonblock>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    D18(%rip),%rdx
  mov    %eax,%ecx
  mov    %ebp,%edi
  mov    (%rdx),%edx
  or     %edx,%ecx
  not    %edx
  and    %eax,%edx
  mov    D7(%rip),%rax
  test   %ebx,%ebx
  cmovne %ecx,%edx
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tcp_nonblock(int fd, int non_block) {
  int flags = fcntl(fd, F_GETFL, 0);
  if (flags == -1)
    return -1;
  if (non_block) {
    flags |= O_NONBLOCK;
  } else {
    flags &= ~O_NONBLOCK;
  }
  if (fcntl(fd, F_SETFL, flags) == -1)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tcp_nonblock>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D27(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    D22(%rip),%rdx
  mov    %eax,%ecx
  mov    %ebp,%edi
  mov    (%rdx),%edx
  or     %edx,%ecx
  not    %edx
  and    %eax,%edx
  mov    D3(%rip),%rax
  test   %ebx,%ebx
  cmovne %ecx,%edx
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tcp_nonblock(int fd, int non_block) {
  int flags = fcntl(fd, F_GETFL, 0);
  if (flags == -1)
    return -1;
  if (non_block) {
    flags |= O_NONBLOCK;
  } else {
    flags &= ~O_NONBLOCK;
  }
  if (fcntl(fd, F_SETFL, flags) == -1)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %rax,-0x10(%rbp)
  mov    %rcx,-0x8(%rbp)
  nop
L86:
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  movzbl (%rsi),%esi
  test   %sil,%sil
  jne    L86
  nop
L11:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  movzbl (%rsi),%esi
  test   %sil,%sil
  jne    L11
  mov    %rax,%rdi
  sub    -0x10(%rbp),%rdi
  mov    %rcx,%rsi
  sub    -0x8(%rbp),%rsi
  cmp    %rsi,%rdi
  jge    L22
  mov    $0x0,%eax
  jmp    L6
L13:
  sub    $0x1,%rax
  movzbl (%rax),%edi
  sub    $0x1,%rcx
  movzbl (%rcx),%esi
  cmp    %sil,%dil
  je     L22
  mov    $0x0,%eax
  jmp    L6
L22:
  cmp    -0x8(%rbp),%rcx
  ja     L13
  jmp    L38
L88:
  mov    -0x10(%rbp),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,%rsi
  lea    0x1(%rsi),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rsi)
L38:
  cmp    %rax,-0x10(%rbp)
  jb     L88
  movb   $0x0,(%rdx)
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int suffix(a, b, p)
register char *a, *b, *p;
{
  char *a0 = a, *b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<suffix>:
  endbr64
  mov    %rdi,%rcx
L25:
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L25
  mov    %rsi,%rax
L39:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L39
  mov    %rcx,%r10
  sub    %rdi,%r10
  mov    %rax,%r9
  sub    %rsi,%r9
  mov    $0x0,%r8d
  cmp    %r9,%r10
  jl     L64
L66:
  cmp    %rsi,%rax
  jbe    L72
  sub    $0x1,%rcx
  sub    $0x1,%rax
  movzbl (%rax),%r11d
  cmp    %r11b,(%rcx)
  je     L66
  mov    $0x0,%r8d
  jmp    L64
L72:
  cmp    %rdi,%rcx
  jbe    L37
  sub    %rdi,%rcx
  mov    $0x0,%eax
L0:
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L0
  add    %rcx,%rdx
L37:
  movb   $0x0,(%rdx)
  mov    $0x1,%r8d
L64:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int suffix(a, b, p)
register char *a, *b, *p;
{
  char *a0 = a, *b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<suffix>:
  endbr64
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L40
  mov    %rsi,%rax
  nopl   (%rax)
L26:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L26
  mov    %rcx,%r10
  mov    %rax,%r9
  xor    %r8d,%r8d
  sub    %rdi,%r10
  sub    %rsi,%r9
  cmp    %r9,%r10
  jge    L12
  jmp    L61
L65:
  sub    $0x1,%rcx
  sub    $0x1,%rax
  movzbl (%rax),%r11d
  cmp    %r11b,(%rcx)
  jne    L70
L12:
  cmp    %rsi,%rax
  ja     L65
  cmp    %rdi,%rcx
  jbe    L39
  sub    %rdi,%rcx
  xor    %eax,%eax
L41:
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L41
  add    %rax,%rdx
L39:
  movb   $0x0,(%rdx)
  mov    $0x1,%r8d
L61:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L70:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int suffix(a, b, p)
register char *a, *b, *p;
{
  char *a0 = a, *b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<suffix>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  nopl   (%rax)
L89:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L89
  mov    %rsi,%rax
  nopl   (%rax)
L121:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L121
  mov    %rdx,%r10
  mov    %rax,%r9
  xor    %r8d,%r8d
  sub    %rcx,%r10
  sub    %rsi,%r9
  cmp    %r9,%r10
  jge    L98
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L103:
  sub    $0x1,%rdx
  sub    $0x1,%rax
  movzbl (%rax),%r11d
  cmp    %r11b,(%rdx)
  jne    L199
L98:
  cmp    %rsi,%rax
  ja     L103
  cmp    %rcx,%rdx
  jbe    L97
  mov    %rdx,%rsi
  lea    0x1(%rcx),%r9
  mov    %rdi,%r8
  sub    %rcx,%rsi
  sub    %r9,%r8
  lea    -0x1(%rsi),%rax
  cmp    $0xe,%r8
  jbe    L144
  cmp    $0x6,%rax
  jbe    L144
  cmp    $0xe,%rax
  jbe    L105
  mov    %rsi,%r8
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%r8
  cs nopw 0x0(%rax,%rax,1)
L6:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L6
  mov    %rsi,%r9
  and    $0xfffffffffffffff0,%r9
  lea    (%rdi,%r9,1),%r8
  lea    (%rcx,%r9,1),%rax
  cmp    %r9,%rsi
  je     L36
  mov    %rsi,%r10
  sub    %r9,%r10
  lea    -0x1(%r10),%r11
  cmp    $0x6,%r11
  jbe    L207
L155:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%rdi,%r9,1)
  mov    %r10,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%r8
  add    %rcx,%rax
  cmp    %rcx,%r10
  je     L36
L207:
  movzbl (%rax),%ecx
  mov    %cl,(%r8)
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L36
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x1(%r8)
  lea    0x2(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L36
  movzbl 0x2(%rax),%ecx
  mov    %cl,0x2(%r8)
  lea    0x3(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L36
  movzbl 0x3(%rax),%ecx
  mov    %cl,0x3(%r8)
  lea    0x4(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L36
  movzbl 0x4(%rax),%ecx
  mov    %cl,0x4(%r8)
  lea    0x5(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L36
  movzbl 0x5(%rax),%ecx
  mov    %cl,0x5(%r8)
  lea    0x6(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L36
  movzbl 0x6(%rax),%eax
  mov    %al,0x6(%r8)
L36:
  add    %rsi,%rdi
L97:
  movb   $0x0,(%rdi)
  mov    $0x1,%r8d
L90:
  mov    %r8d,%eax
  ret
L199:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
L144:
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L22
  jmp    L36
L105:
  mov    %rsi,%r10
  mov    %rcx,%rax
  mov    %rdi,%r8
  xor    %r9d,%r9d
  jmp    L155
```

assistant: ```c
int suffix(a, b, p)
register char *a, *b, *p;
{
  char *a0 = a, *b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pdfBinomial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <LogChoose@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  imul   -0x38(%rbp),%rax
  mov    %rax,%r12
  mov    -0x28(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,%rbx
  movsd  D0(%rip),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  imul   %rbx,%rax
  add    %r12,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: f64

tool: D0: 1

assistant: ```c
double pdfBinomial(long n, double p, long x) {
  double s, t;
  s = LogChoose(n, x);
  t = x * log(p) + (n - x) * log(1.0 - p);
  return (exp(s + t));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pdfBinomial>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movq   %xmm0,%r14
  mov    %rsi,%rbx
  call   <LogChoose@plt>
  movq   %xmm0,%r15
  movq   %r14,%xmm0
  call   <log@plt>
  imul   %rbx,%rax
  mov    %rax,%r12
  sub    %rbx,%rbp
  movsd  D0(%rip),%xmm0
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  call   <log@plt>
  imul   %rbp,%rax
  add    %r12,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movq   %r15,%xmm2
  addsd  %xmm2,%xmm0
  call   <exp@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: f64

tool: D0: 1

assistant: ```c
double pdfBinomial(long n, double p, long x) {
  double s, t;
  s = LogChoose(n, x);
  t = x * log(p) + (n - x) * log(1.0 - p);
  return (exp(s + t));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pdfBinomial>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    %rbp,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <LogChoose@plt>
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm0
  call   <log@plt>
  movsd  D6(%rip),%xmm0
  subsd  (%rsp),%xmm0
  imul   %rbp,%rax
  mov    %rax,%r12
  call   <log@plt>
  pxor   %xmm0,%xmm0
  imul   %rax,%rbx
  add    %r12,%rbx
  cvtsi2sd %rbx,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <exp@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: f64

tool: D6: 1

assistant: ```c
double pdfBinomial(long n, double p, long x) {
  double s, t;
  s = LogChoose(n, x);
  t = x * log(p) + (n - x) * log(1.0 - p);
  return (exp(s + t));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pdfBinomial>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    %rbp,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <LogChoose@plt>
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm0
  call   <log@plt>
  movsd  D6(%rip),%xmm0
  subsd  (%rsp),%xmm0
  imul   %rbp,%rax
  mov    %rax,%r12
  call   <log@plt>
  pxor   %xmm0,%xmm0
  imul   %rax,%rbx
  add    %r12,%rbx
  cvtsi2sd %rbx,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <exp@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: f64

tool: D6: 1

assistant: ```c
double pdfBinomial(long n, double p, long x) {
  double s, t;
  s = LogChoose(n, x);
  t = x * log(p) + (n - x) * log(1.0 - p);
  return (exp(s + t));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<argstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movb   $0x0,D15(%rip)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L28:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x18fff,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x18fff,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  lea    D56(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strncat@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L28
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L16
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    D15(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
L16:
  lea    D15(%rip),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D56
data_type: string

tool: D56:  

assistant: ```c
char *argstr(int arg, int argc, char **argv) {
  static char s[102400];
  int i;
  s[0] = '\0';
  for (i = arg; i < argc; i++) {
    strncat(s, argv[i], sizeof(s) - strlen(s) - 1);
    strncat(s, " ", sizeof(s) - strlen(s) - 1);
  }
  if ((i = strlen(s)) > 0)
    s[i - 1] = '\0';
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movb   $0x0,D20(%rip)
  cmp    %esi,%edi
  jge    L24
  movslq %edi,%rax
  lea    (%rdx,%rax,8),%rbp
  sub    $0x1,%esi
  sub    %edi,%esi
  add    %rax,%rsi
  lea    0x8(%rdx,%rsi,8),%r14
  lea    D20(%rip),%rbx
  mov    $0x18fff,%r12d
  lea    D9(%rip),%r13
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    0x0(%rbp),%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L17
L24:
  lea    D20(%rip),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L19
  sub    $0x1,%eax
  cltq
  lea    D20(%rip),%rdx
  movb   $0x0,(%rdx,%rax,1)
L19:
  lea    D20(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9:  

assistant: ```c
char *argstr(int arg, int argc, char **argv) {
  static char s[102400];
  int i;
  s[0] = '\0';
  for (i = arg; i < argc; i++) {
    strncat(s, argv[i], sizeof(s) - strlen(s) - 1);
    strncat(s, " ", sizeof(s) - strlen(s) - 1);
  }
  if ((i = strlen(s)) > 0)
    s[i - 1] = '\0';
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argstr>:
  endbr64
  push   %r14
  movb   $0x0,D25(%rip)
  push   %r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  cmp    %esi,%edi
  jge    L8
  sub    $0x1,%esi
  movslq %edi,%rax
  mov    $0x18fff,%ebp
  sub    %edi,%esi
  lea    (%rdx,%rax,8),%rbx
  lea    D3(%rip),%r13
  add    %rax,%rsi
  lea    0x8(%rdx,%rsi,8),%r14
  xchg   %ax,%ax
L25:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    -0x8(%rbx),%rsi
  mov    %ebp,%edx
  mov    %r12,%rdi
  sub    %eax,%edx
  call   <strncat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  sub    %eax,%edx
  call   <strncat@plt>
  cmp    %r14,%rbx
  jne    L25
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%r12,%rax,1)
L15:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3:  

assistant: ```c
char *argstr(int arg, int argc, char **argv) {
  static char s[102400];
  int i;
  s[0] = '\0';
  for (i = arg; i < argc; i++) {
    strncat(s, argv[i], sizeof(s) - strlen(s) - 1);
    strncat(s, " ", sizeof(s) - strlen(s) - 1);
  }
  if ((i = strlen(s)) > 0)
    s[i - 1] = '\0';
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<argstr>:
  endbr64
  push   %r14
  movb   $0x0,D17(%rip)
  push   %r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  cmp    %esi,%edi
  jge    L25
  sub    $0x1,%esi
  movslq %edi,%rax
  mov    $0x18fff,%ebp
  sub    %edi,%esi
  lea    (%rdx,%rax,8),%rbx
  lea    D5(%rip),%r13
  add    %rax,%rsi
  lea    0x8(%rdx,%rsi,8),%r14
  xchg   %ax,%ax
L15:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    -0x8(%rbx),%rsi
  mov    %ebp,%edx
  mov    %r12,%rdi
  sub    %eax,%edx
  call   <strncat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  sub    %eax,%edx
  call   <strncat@plt>
  cmp    %r14,%rbx
  jne    L15
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L17
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%r12,%rax,1)
L17:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5:  

assistant: ```c
char *argstr(int arg, int argc, char **argv) {
  static char s[102400];
  int i;
  s[0] = '\0';
  for (i = arg; i < argc; i++) {
    strncat(s, argv[i], sizeof(s) - strlen(s) - 1);
    strncat(s, " ", sizeof(s) - strlen(s) - 1);
  }
  if ((i = strlen(s)) > 0)
    s[i - 1] = '\0';
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<percentage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x20(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: f64

tool: D0: 100

assistant: ```c
double percentage(double num, double den) {
  double per = num / den * 100.0;
  return per;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<percentage>:
  endbr64
  divsd  %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: f64

tool: D7: 100

assistant: ```c
double percentage(double num, double den) {
  double per = num / den * 100.0;
  return per;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<percentage>:
  endbr64
  divsd  %xmm1,%xmm0
  mulsd  D8(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: f64

tool: D8: 100

assistant: ```c
double percentage(double num, double den) {
  double per = num / den * 100.0;
  return per;
}
```
user: Translate the below assembly code into C programming language:

```asm
<percentage>:
  endbr64
  divsd  %xmm1,%xmm0
  mulsd  D6(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: f64

tool: D6: 100

assistant: ```c
double percentage(double num, double den) {
  double per = num / den * 100.0;
  return per;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gf_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1e,%edi
  call   <gf_error@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: Could not malloc %ld bytes!


assistant: ```c
void *gf_malloc(size_t size) {
  void *ptr = malloc(size);
  if (!ptr) {
    gf_error(30, "Could not malloc %ld bytes!\n", size);
  }
  return ptr;
}
```