ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<titleToNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L17:
  mov    -0xc(%rbp),%eax
  imul   $0x1a,%eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x40,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int titleToNumber(char *s) {
  int res = 0, len;
  len = strlen(s);
  for (int i = 0; i < len; i++)
    res = res * 26 + (s[i] - 'A' + 1);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<titleToNumber>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L2:
  imul   $0x1a,%eax,%eax
  movsbl (%rdx),%ecx
  lea    -0x40(%rax,%rcx,1),%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L2
L28:
  pop    %rbx
  ret
L0:
  mov    $0x0,%eax
  jmp    L28
```

assistant: ```c
int titleToNumber(char *s) {
  int res = 0, len;
  len = strlen(s);
  for (int i = 0; i < len; i++)
    res = res * 26 + (s[i] - 'A' + 1);
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<titleToNumber>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L6:
  imul   $0x1a,%eax,%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  lea    -0x40(%rax,%rdx,1),%eax
  cmp    %rcx,%rdi
  jne    L6
  pop    %rbx
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int titleToNumber(char *s) {
  int res = 0, len;
  len = strlen(s);
  for (int i = 0; i < len; i++)
    res = res * 26 + (s[i] - 'A' + 1);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<titleToNumber>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L17:
  imul   $0x1a,%eax,%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  lea    -0x40(%rax,%rdx,1),%eax
  cmp    %rdi,%rcx
  jne    L17
  pop    %rbx
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int titleToNumber(char *s) {
  int res = 0, len;
  len = strlen(s);
  for (int i = 0; i < len; i++)
    res = res * 26 + (s[i] - 'A' + 1);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<aptovec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L22:
  cmp    %rdx,%rsp
  je     L11
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L22
L11:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L21
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L21:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%rcx
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void aptovec(func, n) void (*func)();
{
  int vec[n];
  func(vec, n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aptovec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L4:
  cmp    %rdx,%rsp
  je     L6
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L4
L6:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L10
  orq    $0x0,-0x8(%rsp,%rax,1)
L10:
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   *%rcx
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  leave
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aptovec(func, n) void (*func)();
{
  int vec[n];
  func(vec, n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aptovec>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L40
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L16
L40:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L12
L30:
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   *%rdx
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  leave
  ret
  nopl   0x0(%rax)
L12:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L30
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aptovec(func, n) void (*func)();
{
  int vec[n];
  func(vec, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aptovec>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L47
L46:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L46
L47:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L24
L0:
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   *%rdx
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  leave
  ret
  nopl   0x0(%rax)
L24:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L0
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aptovec(func, n) void (*func)();
{
  int vec[n];
  func(vec, n);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x1337b55,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L39
L27:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next_code@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  jne    L7
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L39
L7:
  subl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L39:
  cmpl   $0xb83,-0x10(%rbp)
  jne    L27
  cmpl   $0xbd5,-0xc(%rbp)
  jne    L27
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %d %d %llu


assistant: ```c
int main() {
  uint64_t first_code = 20151125LL;
  int row = 1;
  int col = 1;
  while (row != 2947 || col != 3029) {
    first_code = next_code(first_code);
    if (row == 1) {
      row = col + 1;
      col = 1;
    } else {
      row--;
      col++;
    }
  }
  printf("%d %d %llu\n", row, col, first_code);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  mov    $0x1337b55,%edi
  jmp    L39
L23:
  lea    0x1(%rbp),%eax
  mov    %ebx,%ebp
  mov    %eax,%ebx
L39:
  call   <next_code@plt>
  mov    %rax,%rdi
  cmp    $0x1,%ebx
  je     L23
  sub    $0x1,%ebx
  add    $0x1,%ebp
  cmp    $0xb83,%ebx
  jne    L39
  cmp    $0xbd5,%ebp
  jne    L39
  mov    %rax,%rcx
  mov    $0xbd5,%edx
  mov    $0xb83,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: %d %d %llu


assistant: ```c
int main() {
  uint64_t first_code = 20151125LL;
  int row = 1;
  int col = 1;
  while (row != 2947 || col != 3029) {
    first_code = next_code(first_code);
    if (row == 1) {
      row = col + 1;
      col = 1;
    } else {
      row--;
      col++;
    }
  }
  printf("%d %d %llu\n", row, col, first_code);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1337b55,%edi
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  call   <next_code@plt>
  add    $0x1,%ebp
  mov    %rax,%rdi
  cmp    $0x1,%ebx
  je     L9
  sub    $0x1,%ebx
  cmp    $0xb83,%ebx
  jne    L13
  cmp    $0xbd5,%ebp
  jne    L13
  mov    %rax,%rcx
  mov    $0xbd5,%edx
  mov    $0xb83,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L9:
  mov    %ebp,%ebx
  mov    $0x1,%ebp
  jmp    L13
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: %d %d %llu


assistant: ```c
int main() {
  uint64_t first_code = 20151125LL;
  int row = 1;
  int col = 1;
  while (row != 2947 || col != 3029) {
    first_code = next_code(first_code);
    if (row == 1) {
      row = col + 1;
      col = 1;
    } else {
      row--;
      col++;
    }
  }
  printf("%d %d %llu\n", row, col, first_code);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1337b55,%edi
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L18:
  call   <next_code@plt>
  add    $0x1,%ebp
  mov    %rax,%rdi
  cmp    $0x1,%ebx
  je     L14
  sub    $0x1,%ebx
  cmp    $0xb83,%ebx
  jne    L18
  cmp    $0xbd5,%ebp
  jne    L18
  mov    %rax,%rcx
  mov    $0xbd5,%edx
  mov    $0xb83,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L14:
  mov    %ebp,%ebx
  mov    $0x1,%ebp
  jmp    L18
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string

tool: D0: %d %d %llu


assistant: ```c
int main() {
  uint64_t first_code = 20151125LL;
  int row = 1;
  int col = 1;
  while (row != 2947 || col != 3029) {
    first_code = next_code(first_code);
    if (row == 1) {
      row = col + 1;
      col = 1;
    } else {
      row--;
      col++;
    }
  }
  printf("%d %d %llu\n", row, col, first_code);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L19:
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L0:
  mov    -0xc(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L42
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D3(%rip),%xmm0
  movss  %xmm0,(%rax)
  jmp    L47
L42:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L47:
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: f32

tool: D3: 1

assistant: ```c
void eye(float *mat, int N) {
  int i, j, t;
  for (i = 0; i < N; ++i) {
    for (j = 0; j < N; ++j) {
      t = i * N;
      if (i == j) {
        mat[t + j] = 1.;
      } else {
        mat[t + j] = 0.;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<eye>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%r10d
  movss  D2(%rip),%xmm0
  jmp    L56
L37:
  movslq %edx,%rcx
  movss  %xmm0,(%rdi,%rcx,4)
L51:
  lea    0x1(%rax),%ecx
  add    $0x1,%edx
  cmp    %ecx,%esi
  je     L41
  mov    %ecx,%eax
L58:
  cmp    %eax,%r8d
  je     L37
  movslq %edx,%rcx
  movl   $0x0,(%rdi,%rcx,4)
  jmp    L51
L41:
  lea    0x1(%r8),%edx
  add    %esi,%r9d
  cmp    %eax,%r8d
  je     L17
  mov    %edx,%r8d
L56:
  mov    %r9d,%edx
  mov    %r10d,%eax
  jmp    L58
L17:
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: f32

tool: D2: 1

assistant: ```c
void eye(float *mat, int N) {
  int i, j, t;
  for (i = 0; i < N; ++i) {
    for (j = 0; j < N; ++j) {
      t = i * N;
      if (i == j) {
        mat[t + j] = 1.;
      } else {
        mat[t + j] = 0.;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<eye>:
  endbr64
  test   %esi,%esi
  jle    L37
  movslq %esi,%rcx
  movss  D8(%rip),%xmm1
  xor    %edx,%edx
  pxor   %xmm2,%xmm2
  lea    0x0(,%rcx,4),%r8
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movaps %xmm1,%xmm0
  cmp    %eax,%edx
  je     L24
  movaps %xmm2,%xmm0
L24:
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L12
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %edx,%esi
  jne    L32
L37:
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: f32

tool: D8: 1

assistant: ```c
void eye(float *mat, int N) {
  int i, j, t;
  for (i = 0; i < N; ++i) {
    for (j = 0; j < N; ++j) {
      t = i * N;
      if (i == j) {
        mat[t + j] = 1.;
      } else {
        mat[t + j] = 0.;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<eye>:
  endbr64
  test   %esi,%esi
  jle    L86
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r10d
  movss  D33(%rip),%xmm5
  shr    $0x2,%eax
  push   %rbp
  movdqa D14(%rip),%xmm4
  mov    %rdi,%r9
  lea    -0x1(%rax),%r11d
  push   %rbx
  movaps D33(%rip),%xmm3
  movslq %esi,%rbx
  add    $0x1,%r11
  mov    %rdi,%r8
  shl    $0x2,%rbx
  lea    -0x1(%rsi),%ebp
  and    $0xfffffffc,%r10d
  xor    %edi,%edi
  xor    %ecx,%ecx
  shl    $0x4,%r11
  pxor   %xmm6,%xmm6
  nopw   0x0(%rax,%rax,1)
L48:
  cmp    $0x2,%ebp
  jbe    L83
  movd   %ecx,%xmm7
  movdqa D28(%rip),%xmm1
  lea    (%r11,%r8,1),%rdx
  mov    %r8,%rax
  pshufd $0x0,%xmm7,%xmm2
  nopl   0x0(%rax)
L73:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm4,%xmm1
  pcmpeqd %xmm2,%xmm0
  andps  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L73
  mov    %r10d,%eax
  cmp    %r10d,%esi
  je     L49
L4:
  lea    (%rdi,%rax,1),%edx
  movaps %xmm5,%xmm0
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rdx
  cmp    %eax,%ecx
  je     L88
  movaps %xmm6,%xmm0
L88:
  movss  %xmm0,(%rdx)
  lea    0x1(%rax),%edx
  cmp    %esi,%edx
  jge    L49
  lea    (%rdx,%rdi,1),%r12d
  movaps %xmm5,%xmm0
  movslq %r12d,%r12
  lea    (%r9,%r12,4),%r12
  cmp    %ecx,%edx
  je     L108
  movaps %xmm6,%xmm0
L108:
  add    $0x2,%eax
  movss  %xmm0,(%r12)
  cmp    %esi,%eax
  jge    L49
  lea    (%rax,%rdi,1),%edx
  movaps %xmm5,%xmm0
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rdx
  cmp    %ecx,%eax
  je     L84
  movaps %xmm6,%xmm0
L84:
  movss  %xmm0,(%rdx)
L49:
  add    $0x1,%ecx
  add    %esi,%edi
  add    %rbx,%r8
  cmp    %esi,%ecx
  jne    L48
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L83:
  xor    %eax,%eax
  jmp    L4
L86:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
datatype: f32[4]
name: retrieve_data
arguments: data_tag: D14
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D28
datatype: f32[4]

tool: {"D33": [1.0,1.0,1.0,1.0]}

tool: {"D14": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D28": [0.0,1.401298464324817e-45,2.802596928649634e-45,4.203895392974451e-45]}

assistant: ```c
void eye(float *mat, int N) {
  int i, j, t;
  for (i = 0; i < N; ++i) {
    for (j = 0; j < N; ++j) {
      t = i * N;
      if (i == j) {
        mat[t + j] = 1.;
      } else {
        mat[t + j] = 0.;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wr__min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L4
  mov    -0x4(%rbp),%eax
  jmp    L2
L4:
  mov    -0x8(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int wr__min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wr__min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int wr__min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wr__min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int wr__min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wr__min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int wr__min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TimerInternalClkConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  and    $0xfffffffffffffff8,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerInternalClkConfigure(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) &= ~0x00000007;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TimerInternalClkConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  and    $0xfffffffffffffff8,%rax
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerInternalClkConfigure(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) &= ~0x00000007;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TimerInternalClkConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  and    $0xfffffffffffffff8,%rax
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerInternalClkConfigure(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) &= ~0x00000007;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TimerInternalClkConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  and    $0xfffffffffffffff8,%rax
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerInternalClkConfigure(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) &= ~0x00000007;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ratio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x4(%rbp)
  ja     L19
  mov    -0x4(%rbp),%eax
  imul   $0x64,%eax,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L26
L19:
  mov    -0x8(%rbp),%eax
  mov    %eax,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  mov    %eax,-0x8(%rbp)
L26:
  cmpl   $0x0,-0x8(%rbp)
  jne    L11
  movl   $0x1,-0x8(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ratio(unsigned int x, unsigned int y) {
  if (x <= UINT_MAX / 100)
    x *= 100;
  else
    y /= 100;
  if (y == 0)
    y = 1;
  return x / y;
}
```
user: What is the c source code of the assembly code below:

```asm
<ratio>:
  endbr64
  mov    %edi,%eax
  mov    D3(%rip),%rdx
  mov    (%rdx),%ecx
  movslq %ecx,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  cmp    %edi,%edx
  jb     L5
  imul   $0x64,%edi,%eax
L4:
  test   %esi,%esi
  mov    $0x1,%edx
  cmove  %edx,%esi
  mov    $0x0,%edx
  div    %esi
  ret
L5:
  mov    %esi,%esi
  imul   $0x51eb851f,%rsi,%rsi
  shr    $0x25,%rsi
  jmp    L4
```

assistant: ```c
unsigned int ratio(unsigned int x, unsigned int y) {
  if (x <= UINT_MAX / 100)
    x *= 100;
  else
    y /= 100;
  if (y == 0)
    y = 1;
  return x / y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ratio>:
  endbr64
  mov    D2(%rip),%rdx
  mov    %edi,%eax
  movslq (%rdx),%rdx
  mov    %rdx,%rcx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  cmp    %edi,%edx
  jb     L2
  imul   $0x64,%edi,%eax
  mov    $0x1,%edx
  test   %esi,%esi
  cmove  %edx,%esi
  xor    %edx,%edx
  div    %esi
  ret
  nopl   0x0(%rax)
L2:
  mov    %esi,%esi
  mov    $0x1,%edx
  imul   $0x51eb851f,%rsi,%rsi
  shr    $0x25,%rsi
  test   %esi,%esi
  cmove  %edx,%esi
  xor    %edx,%edx
  div    %esi
  ret
```

assistant: ```c
unsigned int ratio(unsigned int x, unsigned int y) {
  if (x <= UINT_MAX / 100)
    x *= 100;
  else
    y /= 100;
  if (y == 0)
    y = 1;
  return x / y;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ratio>:
  endbr64
  mov    D0(%rip),%rdx
  mov    %edi,%eax
  movslq (%rdx),%rdx
  mov    %rdx,%rcx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  cmp    %edi,%edx
  jb     L9
  imul   $0x64,%edi,%eax
  mov    $0x1,%edx
  test   %esi,%esi
  cmove  %edx,%esi
  xor    %edx,%edx
  div    %esi
  ret
  nopl   0x0(%rax)
L9:
  mov    %esi,%esi
  mov    $0x1,%edx
  imul   $0x51eb851f,%rsi,%rsi
  shr    $0x25,%rsi
  test   %esi,%esi
  cmove  %edx,%esi
  xor    %edx,%edx
  div    %esi
  ret
```

assistant: ```c
unsigned int ratio(unsigned int x, unsigned int y) {
  if (x <= UINT_MAX / 100)
    x *= 100;
  else
    y /= 100;
  if (y == 0)
    y = 1;
  return x / y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_current_dir_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <getcwd@plt>
  pop    %rbp
  ret
```

assistant: ```c
char *get_current_dir_name(void) {
  ;
  return getcwd(NULL, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_current_dir_name>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <getcwd@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_current_dir_name(void) {
  ;
  return getcwd(NULL, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_current_dir_name>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <getcwd@plt>
```

assistant: ```c
char *get_current_dir_name(void) {
  ;
  return getcwd(NULL, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_current_dir_name>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <getcwd@plt>
```

assistant: ```c
char *get_current_dir_name(void) {
  ;
  return getcwd(NULL, 0);
}
```