ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L12
L52:
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L7:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L33
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L25
L33:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L25:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L52
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D38
type_infered: string
name: retrieve_data
arguments: data_tag: D43
type_infered: string
name: retrieve_data
arguments: data_tag: D75
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D55
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string

tool: D38: Informe a quantidade de numeros a serem avaliadas: 

tool: D43: %d

tool: D75: Informe o numero 1: 

tool: D27: Digite o numero %d: 

tool: D55: Em ordem.

tool: D28: Nao ordenado.

assistant: ```c
void main() {
  int nAtual, nAntigo, i = 0, j = 0;
  printf("Informe a quantidade de numeros a serem avaliadas: ");
  scanf("%d", &i);
  while (j < (i - 1)) {
    if (j == 0) {
      printf("Informe o numero 1: ");
      scanf("%d", &nAntigo);
    }
    printf("Digite o numero %d: ", j + 2);
    scanf("%d", &nAtual);
    if (nAtual > nAntigo) {
      printf("Em ordem.\n");
    } else {
      printf("Nao ordenado.\n");
    }
    nAntigo = nAtual;
    j++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jle    L33
  mov    $0x0,%ebx
  lea    D58(%rip),%r14
  lea    D13(%rip),%rbp
  lea    D4(%rip),%r12
  lea    D48(%rip),%r13
  jmp    L68
L15:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  jmp    L4
L19:
  mov    %r13,%rdi
  call   <puts@plt>
L14:
  mov    0xc(%rsp),%eax
  mov    %eax,0x10(%rsp)
  add    $0x1,%ebx
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L33
L68:
  test   %ebx,%ebx
  je     L15
L4:
  lea    0x2(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  jle    L19
  lea    D30(%rip),%rdi
  call   <puts@plt>
  jmp    L14
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D64
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D58
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D48
type_infered: string
name: disassemble_data
arguments: tag: D30
type_infered: string

tool: D64: Informe a quantidade de numeros a serem avaliadas: 

tool: D13: %d

tool: D58: Informe o numero 1: 

tool: D4: Digite o numero %d: 

tool: D48: Nao ordenado.

tool: D30: Em ordem.

assistant: ```c
void main() {
  int nAtual, nAntigo, i = 0, j = 0;
  printf("Informe a quantidade de numeros a serem avaliadas: ");
  scanf("%d", &i);
  while (j < (i - 1)) {
    if (j == 0) {
      printf("Informe o numero 1: ");
      scanf("%d", &nAntigo);
    }
    printf("Digite o numero %d: ", j + 2);
    scanf("%d", &nAtual);
    if (nAtual > nAntigo) {
      printf("Em ordem.\n");
    } else {
      printf("Nao ordenado.\n");
    }
    nAntigo = nAtual;
    j++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D55(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x24(%rsp)
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x24(%rsp)
  jle    L29
  lea    0x20(%rsp),%rax
  xor    %ebx,%ebx
  lea    D32(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    0x1c(%rsp),%r12
  lea    D11(%rip),%r15
  lea    D16(%rip),%r14
  jmp    L39
  nopl   (%rax)
L1:
  mov    %r14,%rdi
  call   <puts@plt>
L50:
  mov    0x1c(%rsp),%eax
  add    $0x1,%ebx
  mov    %eax,0x20(%rsp)
  mov    0x24(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L29
L39:
  test   %ebx,%ebx
  je     L22
L12:
  lea    0x2(%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jg     L1
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L50
  xchg   %ax,%ax
L22:
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  jmp    L12
  nopl   (%rax)
L29:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D55
type: string
name: read_data
arguments: data_label: D25
type: string
name: read_data
arguments: data_label: D32
type: string
name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D56
type: string

tool: D55: Informe a quantidade de numeros a serem avaliadas: 

tool: D25: %d

tool: D32: Digite o numero %d: 

tool: D11: Nao ordenado.

tool: D16: Em ordem.

tool: D56: Informe o numero 1: 

assistant: ```c
void main() {
  int nAtual, nAntigo, i = 0, j = 0;
  printf("Informe a quantidade de numeros a serem avaliadas: ");
  scanf("%d", &i);
  while (j < (i - 1)) {
    if (j == 0) {
      printf("Informe o numero 1: ");
      scanf("%d", &nAntigo);
    }
    printf("Digite o numero %d: ", j + 2);
    scanf("%d", &nAtual);
    if (nAtual > nAntigo) {
      printf("Em ordem.\n");
    } else {
      printf("Nao ordenado.\n");
    }
    nAntigo = nAtual;
    j++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x24(%rsp)
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x24(%rsp)
  jle    L60
  lea    0x20(%rsp),%rax
  xor    %ebx,%ebx
  lea    D6(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    0x1c(%rsp),%r12
  lea    D52(%rip),%r15
  lea    D23(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L16:
  test   %ebx,%ebx
  je     L0
L34:
  lea    0x2(%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jle    L3
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  mov    0x1c(%rsp),%eax
  mov    %eax,0x20(%rsp)
  mov    0x24(%rsp),%eax
  sub    $0x1,%eax
  cmp    %eax,%ebx
  jl     L16
L60:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  mov    0x1c(%rsp),%eax
  mov    %eax,0x20(%rsp)
  mov    0x24(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L60
  test   %ebx,%ebx
  jne    L34
L0:
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  jmp    L34
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type_infered: string
name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D52
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D43
type_infered: string

tool: D26: Informe a quantidade de numeros a serem avaliadas: 

tool: D11: %d

tool: D6: Digite o numero %d: 

tool: D52: Nao ordenado.

tool: D23: Em ordem.

tool: D43: Informe o numero 1: 

assistant: ```c
void main() {
  int nAtual, nAntigo, i = 0, j = 0;
  printf("Informe a quantidade de numeros a serem avaliadas: ");
  scanf("%d", &i);
  while (j < (i - 1)) {
    if (j == 0) {
      printf("Informe o numero 1: ");
      scanf("%d", &nAntigo);
    }
    printf("Digite o numero %d: ", j + 2);
    scanf("%d", &nAtual);
    if (nAtual > nAntigo) {
      printf("Em ordem.\n");
    } else {
      printf("Nao ordenado.\n");
    }
    nAntigo = nAtual;
    j++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L23:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x0,-0x8(%rbp)
  jle    L35
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  comiss %xmm1,%xmm0
  ja     L23
L35:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(float a[], int n) {
  int i, j, tmp;
  for (i = 0; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sort>:
  endbr64
  test   %esi,%esi
  jle    L39
  cvttss2si (%rdi),%r9d
  lea    0x4(%rdi),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  jmp    L61
L39:
  ret
L38:
  mov    %ecx,%edx
L19:
  add    $0x4,%r8
L61:
  movslq %edx,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %r9d,%xmm0
  movss  %xmm0,(%rdi,%rdx,4)
  add    $0x1,%ecx
  cmp    %ecx,%esi
  je     L34
  cvttss2si (%r8),%r9d
  test   %ecx,%ecx
  jle    L38
  mov    %r8,%rax
  mov    %ecx,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %r9d,%xmm1
L69:
  movss  -0x4(%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L19
  movss  %xmm0,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L69
  jmp    L19
L34:
  ret
```

assistant: ```c
void sort(float a[], int n) {
  int i, j, tmp;
  for (i = 0; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  test   %esi,%esi
  jle    L37
  cvttss2si (%rdi),%eax
  pxor   %xmm1,%xmm1
  sub    $0x1,%esi
  xor    %ecx,%ecx
  xor    %edx,%edx
  cvtsi2ss %eax,%xmm1
  nopl   0x0(%rax,%rax,1)
L30:
  movss  %xmm1,(%rdi,%rdx,4)
  cmp    %rsi,%rcx
  je     L25
L19:
  cvttss2si 0x4(%rdi,%rcx,4),%eax
  pxor   %xmm1,%xmm1
  add    $0x1,%rcx
  cvtsi2ss %eax,%xmm1
  mov    %rcx,%rax
  nop
L23:
  movss  -0x4(%rdi,%rax,4),%xmm0
  movslq %eax,%rdx
  comiss %xmm1,%xmm0
  jbe    L30
  movss  %xmm0,(%rdi,%rax,4)
  sub    $0x1,%rax
  jne    L23
  xor    %edx,%edx
  movss  %xmm1,(%rdi,%rdx,4)
  cmp    %rsi,%rcx
  jne    L19
L25:
  ret
L37:
  ret
```

assistant: ```c
void sort(float a[], int n) {
  int i, j, tmp;
  for (i = 0; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  test   %esi,%esi
  jle    L16
  cvttss2si (%rdi),%eax
  pxor   %xmm0,%xmm0
  movslq %esi,%r8
  mov    $0x1,%ecx
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%rdi)
  cmp    $0x1,%esi
  je     L50
  nopl   (%rax)
L30:
  cvttss2si (%rdi,%rcx,4),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    %rcx,%rax
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L59:
  movss  %xmm0,(%rdi,%rax,4)
  sub    $0x1,%rax
  movslq %eax,%rdx
  test   %eax,%eax
  je     L32
L44:
  movss  -0x4(%rdi,%rax,4),%xmm0
  movslq %eax,%rdx
  comiss %xmm1,%xmm0
  ja     L59
L32:
  add    $0x1,%rcx
  movss  %xmm1,(%rdi,%rdx,4)
  cmp    %rcx,%r8
  jne    L30
  ret
L50:
  ret
L16:
  ret
```

assistant: ```c
void sort(float a[], int n) {
  int i, j, tmp;
  for (i = 0; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<selectionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movzwl -0x1c(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  jmp    L1
L24:
  movswl -0x6(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movzwl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x8(%rbp)
  jmp    L9
L12:
  movswq -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L11
  movswl -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L11:
  movzwl -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x8(%rbp)
L9:
  movzwl -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%ax
  jle    L12
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movswq -0x6(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movzwl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x6(%rbp)
L1:
  movzwl -0x6(%rbp),%eax
  cmp    -0x20(%rbp),%ax
  jle    L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void selectionSort(int *sortMe, short start, short end) {
  short i, j;
  int minIndex;
  for (j = start; j <= end; j++) {
    minIndex = j;
    for (i = j + 1; i <= end; i++) {
      if (sortMe[i] < sortMe[minIndex])
        minIndex = i;
    }
    swap(&sortMe[j], &sortMe[minIndex]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<selectionSort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %edx,%ebp
  cmp    %dx,%si
  jle    L66
  jmp    L1
L12:
  add    $0x1,%eax
  cmp    %bp,%ax
  jg     L10
L31:
  movswq %ax,%rdx
  movslq %esi,%rcx
  mov    (%rbx,%rcx,4),%ecx
  cmp    %ecx,(%rbx,%rdx,4)
  jge    L12
  movswl %ax,%esi
  jmp    L12
L42:
  movswq %di,%rdi
  lea    (%rbx,%rdi,4),%rdi
  mov    %rdi,%rsi
  call   <swap@plt>
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  movslq %esi,%rsi
  lea    (%rbx,%rsi,4),%rsi
  movswq %di,%rdi
  lea    (%rbx,%rdi,4),%rdi
  call   <swap@plt>
  mov    %r12d,%edi
L66:
  movswl %di,%esi
  lea    0x1(%rdi),%r12d
  cmp    %bp,%r12w
  jg     L42
  mov    %r12d,%eax
  jmp    L31
```

assistant: ```c
void selectionSort(int *sortMe, short start, short end) {
  short i, j;
  int minIndex;
  for (j = start; j <= end; j++) {
    minIndex = j;
    for (i = j + 1; i <= end; i++) {
      if (sortMe[i] < sortMe[minIndex])
        minIndex = i;
    }
    swap(&sortMe[j], &sortMe[minIndex]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<selectionSort>:
  endbr64
  cmp    %dx,%si
  jg     L25
  push   %r12
  movswq %si,%rax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    0x1(%rax),%r12d
  movswl %ax,%edi
  lea    (%rbx,%rax,4),%r8
  cmp    %r12w,%bp
  jl     L16
  mov    %r12d,%eax
  nopl   0x0(%rax)
L36:
  movslq %edi,%rcx
  movswq %ax,%rdx
  lea    (%rbx,%rcx,4),%rsi
  lea    (%rbx,%rdx,4),%rdx
  mov    (%rsi),%ecx
  cmp    %ecx,(%rdx)
  jge    L33
  movswl %ax,%edi
  mov    %rdx,%rsi
L33:
  add    $0x1,%eax
  cmp    %ax,%bp
  jge    L36
  mov    %r8,%rdi
  call   <swap@plt>
  movswq %r12w,%rax
  jmp    L12
  nopl   0x0(%rax)
L16:
  pop    %rbx
  mov    %r8,%rsi
  pop    %rbp
  mov    %r8,%rdi
  pop    %r12
  jmp    1050 <swap@plt>
L25:
  ret
```

assistant: ```c
void selectionSort(int *sortMe, short start, short end) {
  short i, j;
  int minIndex;
  for (j = start; j <= end; j++) {
    minIndex = j;
    for (i = j + 1; i <= end; i++) {
      if (sortMe[i] < sortMe[minIndex])
        minIndex = i;
    }
    swap(&sortMe[j], &sortMe[minIndex]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<selectionSort>:
  endbr64
  cmp    %dx,%si
  jg     L44
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movswl %si,%edi
  movswq %si,%rsi
  lea    (%rbx,%rsi,4),%r8
  cmp    %r12w,%dx
  jl     L33
  nopl   0x0(%rax,%rax,1)
L41:
  mov    (%r8),%ecx
  mov    %r12d,%eax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L64:
  movslq %edi,%rdx
  add    $0x1,%eax
  lea    (%rbx,%rdx,4),%rsi
  cmp    %ax,%bp
  jl     L19
L63:
  movswq %ax,%rdx
  lea    (%rbx,%rdx,4),%rsi
  mov    (%rsi),%edx
  cmp    %edx,%ecx
  jle    L64
  movswl %ax,%edi
  add    $0x1,%eax
  mov    %edx,%ecx
  cmp    %ax,%bp
  jge    L63
L19:
  mov    %r8,%rdi
  call   <swap@plt>
  movswl %r12w,%edi
  lea    0x1(%r12),%eax
  movswq %r12w,%r12
  lea    (%rbx,%r12,4),%r8
  cmp    %bp,%ax
  jg     L33
  mov    %eax,%r12d
  jmp    L41
  nopl   (%rax)
L33:
  pop    %rbx
  mov    %r8,%rsi
  pop    %rbp
  mov    %r8,%rdi
  pop    %r12
  jmp    1050 <swap@plt>
L44:
  ret
```

assistant: ```c
void selectionSort(int *sortMe, short start, short end) {
  short i, j;
  int minIndex;
  for (j = start; j <= end; j++) {
    minIndex = j;
    for (i = j + 1; i <= end; i++) {
      if (sortMe[i] < sortMe[minIndex])
        minIndex = i;
    }
    swap(&sortMe[j], &sortMe[minIndex]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<draw_grid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L52:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L14:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <grid_at@plt>
  test   %rax,%rax
  je     L22
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L22:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L14
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L52
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D25
datatype: string
name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string

tool: D25: *

tool: D29:  

tool: D18: 


assistant: ```c
void draw_grid(struct grid *grid, const int from_x, const int from_y, const int to_x, const int to_y) {
  int x, y;
  for (y = from_y; y <= to_y; ++y) {
    for (x = from_x; x <= to_x; ++x)
      if (grid_at(grid, x, y))
        printf("*");
      else
        printf(" ");
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw_grid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,0x8(%rsp)
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %r8d,0xc(%rsp)
  lea    D5(%rip),%r15
  lea    D16(%rip),%r14
  cmp    %r8d,%edx
  jle    L39
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %r15,%rdi
  call   <printf@plt>
L7:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jl     L18
L22:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <grid_at@plt>
  test   %rax,%rax
  je     L8
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L7
L18:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jl     L9
L39:
  mov    0x8(%rsp),%eax
  mov    %eax,%ebx
  cmp    %r12d,%eax
  jle    L22
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D5:  

tool: D16: *

tool: D8: 


assistant: ```c
void draw_grid(struct grid *grid, const int from_x, const int from_y, const int to_x, const int to_y) {
  int x, y;
  for (y = from_y; y <= to_y; ++y) {
    for (x = from_x; x <= to_x; ++x)
      if (grid_at(grid, x, y))
        printf("*");
      else
        printf(" ");
    printf("\n");
  }
}
```