ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_help>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  lea    D8(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rcx
  mov    $0x9,%edx
  mov    $0x1,%esi
  lea    D33(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0xc,%edx
  mov    $0x1,%esi
  lea    D53(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0xf,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x2a,%edx
  mov    $0x1,%esi
  lea    D62(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D44(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D99(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D74(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x40,%edx
  mov    $0x1,%esi
  lea    D34(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D68(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D82(%rip),%rdi
  call   <fwrite@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D53
type: string
name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D62
type: string
name: disassemble_data
arguments: data_label: D44
type: string
name: disassemble_data
arguments: data_label: D99
type: string
name: disassemble_data
arguments: data_label: D74
type: string
name: disassemble_data
arguments: data_label: D34
type: string
name: disassemble_data
arguments: data_label: D68
type: string
name: disassemble_data
arguments: data_label: D82
type: string

tool: D8: Usage: %s [option...]

tool: D33: Options:


tool: D53: 	-h, --help


tool: D7: 	-v, --verbose


tool: D62: 	-d?, --double=?		test one specific value


tool: D44: 	-s?, --test_sin=?	defaults to 1


tool: D99: 	-c?, --test_cos=?	defaults to 1


tool: D74: 	-t?, --test_tan=?	defaults to 0


tool: D34: 	-e?, --exhaustive_sin=?	defaults to 0 (takes about 30 minutes)


tool: D68: 	-o?, --exhaustive_cos=?	defaults to 0


tool: D82: 	-a?, --exhaustive_tan=?	defaults to 0


assistant: ```c
void print_help(FILE *stream, const char *prog_name) {
  fprintf(stream, "Usage: %s [option...]", prog_name);
  fprintf(stream, "Options:\n");
  fprintf(stream, "\t-h, --help\n");
  fprintf(stream, "\t-v, --verbose\n");
  fprintf(stream, "\t-d?, --double=?\t\ttest one specific value\n");
  fprintf(stream, "\t-s?, --test_sin=?\tdefaults to 1\n");
  fprintf(stream, "\t-c?, --test_cos=?\tdefaults to 1\n");
  fprintf(stream, "\t-t?, --test_tan=?\tdefaults to 0\n");
  fprintf(stream, "\t-e?, --exhaustive_sin=?\tdefaults to 0"
                  " (takes about 30 minutes)\n");
  fprintf(stream, "\t-o?, --exhaustive_cos=?\tdefaults to 0\n");
  fprintf(stream, "\t-a?, --exhaustive_tan=?\tdefaults to 0\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_help>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rdi,%r12
  lea    D6(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x9,%edx
  mov    $0x1,%esi
  lea    D79(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0xc,%edx
  mov    $0x1,%esi
  lea    D46(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0xf,%edx
  mov    $0x1,%esi
  lea    D35(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x2a,%edx
  mov    $0x1,%esi
  lea    D90(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D107(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D45(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x40,%edx
  mov    $0x1,%esi
  lea    D89(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  pop    %r12
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D37(%rip),%rdi
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string
name: retrieve_data
arguments: tag: D79
data_type: string
name: retrieve_data
arguments: tag: D46
data_type: string
name: retrieve_data
arguments: tag: D35
data_type: string
name: retrieve_data
arguments: tag: D90
data_type: string
name: retrieve_data
arguments: tag: D107
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D45
data_type: string
name: retrieve_data
arguments: tag: D89
data_type: string
name: retrieve_data
arguments: tag: D21
data_type: string
name: retrieve_data
arguments: tag: D37
data_type: string

tool: D6: Usage: %s [option...]

tool: D79: Options:


tool: D46: 	-h, --help


tool: D35: 	-v, --verbose


tool: D90: 	-d?, --double=?		test one specific value


tool: D107: 	-s?, --test_sin=?	defaults to 1


tool: D1: 	-c?, --test_cos=?	defaults to 1


tool: D45: 	-t?, --test_tan=?	defaults to 0


tool: D89: 	-e?, --exhaustive_sin=?	defaults to 0 (takes about 30 minutes)


tool: D21: 	-o?, --exhaustive_cos=?	defaults to 0


tool: D37: 	-a?, --exhaustive_tan=?	defaults to 0


assistant: ```c
void print_help(FILE *stream, const char *prog_name) {
  fprintf(stream, "Usage: %s [option...]", prog_name);
  fprintf(stream, "Options:\n");
  fprintf(stream, "\t-h, --help\n");
  fprintf(stream, "\t-v, --verbose\n");
  fprintf(stream, "\t-d?, --double=?\t\ttest one specific value\n");
  fprintf(stream, "\t-s?, --test_sin=?\tdefaults to 1\n");
  fprintf(stream, "\t-c?, --test_cos=?\tdefaults to 1\n");
  fprintf(stream, "\t-t?, --test_tan=?\tdefaults to 0\n");
  fprintf(stream, "\t-e?, --exhaustive_sin=?\tdefaults to 0"
                  " (takes about 30 minutes)\n");
  fprintf(stream, "\t-o?, --exhaustive_cos=?\tdefaults to 0\n");
  fprintf(stream, "\t-a?, --exhaustive_tan=?\tdefaults to 0\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_help>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rdi,%r12
  lea    D109(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x9,%edx
  mov    $0x1,%esi
  lea    D49(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0xc,%edx
  mov    $0x1,%esi
  lea    D76(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0xf,%edx
  mov    $0x1,%esi
  lea    D73(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x2a,%edx
  mov    $0x1,%esi
  lea    D77(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D10(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x21,%edx
  mov    $0x1,%esi
  lea    D58(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x40,%edx
  mov    $0x1,%esi
  lea    D51(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D88(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  pop    %r12
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D90(%rip),%rdi
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D109
type: string
name: retrieve_data
arguments: data_tag: D49
type: string
name: retrieve_data
arguments: data_tag: D76
type: string
name: retrieve_data
arguments: data_tag: D73
type: string
name: retrieve_data
arguments: data_tag: D77
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D58
type: string
name: retrieve_data
arguments: data_tag: D51
type: string
name: retrieve_data
arguments: data_tag: D88
type: string
name: retrieve_data
arguments: data_tag: D90
type: string

tool: D109: Usage: %s [option...]

tool: D49: Options:


tool: D76: 	-h, --help


tool: D73: 	-v, --verbose


tool: D77: 	-d?, --double=?		test one specific value


tool: D17: 	-s?, --test_sin=?	defaults to 1


tool: D10: 	-c?, --test_cos=?	defaults to 1


tool: D58: 	-t?, --test_tan=?	defaults to 0


tool: D51: 	-e?, --exhaustive_sin=?	defaults to 0 (takes about 30 minutes)


tool: D88: 	-o?, --exhaustive_cos=?	defaults to 0


tool: D90: 	-a?, --exhaustive_tan=?	defaults to 0


assistant: ```c
void print_help(FILE *stream, const char *prog_name) {
  fprintf(stream, "Usage: %s [option...]", prog_name);
  fprintf(stream, "Options:\n");
  fprintf(stream, "\t-h, --help\n");
  fprintf(stream, "\t-v, --verbose\n");
  fprintf(stream, "\t-d?, --double=?\t\ttest one specific value\n");
  fprintf(stream, "\t-s?, --test_sin=?\tdefaults to 1\n");
  fprintf(stream, "\t-c?, --test_cos=?\tdefaults to 1\n");
  fprintf(stream, "\t-t?, --test_tan=?\tdefaults to 0\n");
  fprintf(stream, "\t-e?, --exhaustive_sin=?\tdefaults to 0"
                  " (takes about 30 minutes)\n");
  fprintf(stream, "\t-o?, --exhaustive_cos=?\tdefaults to 0\n");
  fprintf(stream, "\t-a?, --exhaustive_tan=?\tdefaults to 0\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_add_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xb(%rbp)
  jmp    L11
L64:
  movb   $0x0,-0xa(%rbp)
  jmp    L66
L17:
  movb   $0x0,-0x9(%rbp)
  jmp    L69
L1:
  movb   $0x0,-0xd(%rbp)
  movb   $0x0,-0xc(%rbp)
  movsbl -0x9(%rbp),%edx
  movsbl -0xa(%rbp),%esi
  movsbl -0xb(%rbp),%eax
  lea    -0xc(%rbp),%rdi
  lea    -0xd(%rbp),%rcx
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <add_digits@plt>
  movzbl -0xd(%rbp),%eax
  movsbl %al,%edx
  movsbl -0xb(%rbp),%ecx
  movsbl -0xa(%rbp),%eax
  add    %eax,%ecx
  movsbl -0x9(%rbp),%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  imul   $0x66666667,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ASRT_char@plt>
  movzbl -0xc(%rbp),%eax
  movsbl %al,%esi
  movsbl -0xb(%rbp),%edx
  movsbl -0xa(%rbp),%eax
  add    %eax,%edx
  movsbl -0x9(%rbp),%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  mov    %ecx,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ASRT_char@plt>
  movzbl -0x9(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x9(%rbp)
L69:
  cmpb   $0x9,-0x9(%rbp)
  jle    L1
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L66:
  cmpb   $0x9,-0xa(%rbp)
  jle    L17
  movzbl -0xb(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb(%rbp)
L11:
  cmpb   $0x9,-0xb(%rbp)
  jle    L64
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
void test_add_digits() {
  for (char a = 0; a < 10; a++) {
    for (char b = 0; b < 10; b++) {
      for (char c = 0; c < 10; c++) {
        char d = 0;
        char e = 0;
        add_digits(a, b, c, &d, &e);
        ASRT_char((a + b + c) / 10, d);
        ASRT_char((a + b + c) % 10, e);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_add_digits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r14d
  lea    0x17(%rsp),%r15
L22:
  mov    %r14d,0xc(%rsp)
  mov    $0x0,%r13d
L30:
  mov    $0x0,%r12d
L0:
  movb   $0x0,0x16(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0x16(%rsp),%rcx
  mov    %r15,%r8
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <add_digits@plt>
  mov    0xc(%rsp),%eax
  lea    (%r12,%rax,1),%ebp
  movsbl 0x16(%rsp),%esi
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  movsbl %bl,%edi
  call   <ASRT_char@plt>
  movsbl 0x17(%rsp),%esi
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  movsbl %bpl,%edi
  call   <ASRT_char@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L0
  add    $0x1,%r13d
  addl   $0x1,0xc(%rsp)
  cmp    $0xa,%r13d
  jne    L30
  add    $0x1,%r14d
  cmp    $0xa,%r14d
  jne    L22
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_add_digits() {
  for (char a = 0; a < 10; a++) {
    for (char b = 0; b < 10; b++) {
      for (char c = 0; c < 10; c++) {
        char d = 0;
        char e = 0;
        add_digits(a, b, c, &d, &e);
        ASRT_char((a + b + c) / 10, d);
        ASRT_char((a + b + c) % 10, e);
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_add_digits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%r8
  lea    0x16(%rsp),%r15
L25:
  mov    %r13d,0xc(%rsp)
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L22:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r12d,%edx
  mov    %r15,%rcx
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    %r8,(%rsp)
  movb   $0x0,0x16(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <add_digits@plt>
  mov    0xc(%rsp),%eax
  movsbl 0x16(%rsp),%esi
  lea    (%r12,%rax,1),%ebx
  mov    $0xcccccccd,%eax
  add    $0x1,%r12d
  mov    %rbx,%r14
  imul   %rax,%rbx
  shr    $0x23,%rbx
  mov    %ebx,%edi
  call   <ASRT_char@plt>
  lea    (%rbx,%rbx,4),%eax
  movsbl 0x17(%rsp),%esi
  mov    %r14d,%edi
  add    %eax,%eax
  sub    %eax,%edi
  call   <ASRT_char@plt>
  cmp    $0xa,%r12d
  mov    (%rsp),%r8
  jne    L15
  add    $0x1,%ebp
  addl   $0x1,0xc(%rsp)
  cmp    $0xa,%ebp
  jne    L22
  add    $0x1,%r13d
  cmp    $0xa,%r13d
  jne    L25
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_add_digits() {
  for (char a = 0; a < 10; a++) {
    for (char b = 0; b < 10; b++) {
      for (char c = 0; c < 10; c++) {
        char d = 0;
        char e = 0;
        add_digits(a, b, c, &d, &e);
        ASRT_char((a + b + c) / 10, d);
        ASRT_char((a + b + c) % 10, e);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_add_digits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%r8
  lea    0x16(%rsp),%r15
L9:
  mov    %r13d,0xc(%rsp)
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%edx
  mov    %r15,%rcx
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    %r8,(%rsp)
  movb   $0x0,0x16(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <add_digits@plt>
  mov    0xc(%rsp),%eax
  movsbl 0x16(%rsp),%esi
  lea    (%rax,%r12,1),%ebx
  mov    $0xcccccccd,%eax
  add    $0x1,%r12d
  mov    %rbx,%r14
  imul   %rax,%rbx
  shr    $0x23,%rbx
  mov    %ebx,%edi
  call   <ASRT_char@plt>
  lea    (%rbx,%rbx,4),%eax
  movsbl 0x17(%rsp),%esi
  mov    %r14d,%edi
  add    %eax,%eax
  sub    %eax,%edi
  call   <ASRT_char@plt>
  cmp    $0xa,%r12d
  mov    (%rsp),%r8
  jne    L19
  add    $0x1,%ebp
  addl   $0x1,0xc(%rsp)
  cmp    $0xa,%ebp
  jne    L17
  add    $0x1,%r13d
  cmp    $0xa,%r13d
  jne    L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_add_digits() {
  for (char a = 0; a < 10; a++) {
    for (char b = 0; b < 10; b++) {
      for (char c = 0; c < 10; c++) {
        char d = 0;
        char e = 0;
        add_digits(a, b, c, &d, &e);
        ASRT_char((a + b + c) / 10, d);
        ASRT_char((a + b + c) % 10, e);
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L5
L4:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  add    $0x1,%ebx
L5:
  cmp    -0x2c(%rbp),%ebx
  jl     L4
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double norm(double *x, int n) {
  double s = 0;
  register int i;
  for (i = 0; i < n; i++)
    s += x[i] * x[i];
  return (sqrt(s));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<norm>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L25:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L25
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L27
L12:
  sqrtsd %xmm0,%xmm0
  ret
L3:
  pxor   %xmm0,%xmm0
  jmp    L12
L27:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double norm(double *x, int n) {
  double s = 0;
  register int i;
  for (i = 0; i < n; i++)
    s += x[i] * x[i];
  return (sqrt(s));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<norm>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L0:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L0
  ucomisd %xmm0,%xmm2
  ja     L29
  sqrtsd %xmm0,%xmm0
  ret
L9:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L29:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm(double *x, int n) {
  double s = 0;
  register int i;
  for (i = 0; i < n; i++)
    s += x[i] * x[i];
  return (sqrt(s));
}
```
user: Translate the below assembly code into C programming language:

```asm
<norm>:
  endbr64
  test   %esi,%esi
  jle    L36
  cmp    $0x1,%esi
  je     L16
  mov    %esi,%edx
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L45:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L45
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L2
L20:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L2:
  ucomisd %xmm0,%xmm3
  ja     L21
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L36:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L16:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L20
L21:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm(double *x, int n) {
  double s = 0;
  register int i;
  for (i = 0; i < n; i++)
    s += x[i] * x[i];
  return (sqrt(s));
}
```
user: What is the c source code of the assembly code below?

```asm
<mini_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L31:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L26
L5:
  nop
L26:
  leave
  ret
```

assistant: ```c
void mini_printf(char *str, int fd) {
  char *p;
  if (str == NULL)
    return;
  p = str;
  while (*p)
    p++;
  write(fd, str, (size_t)(p - str));
}
```
user: What is the c source code of the assembly code below:

```asm
<mini_printf>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L31
  sub    $0x8,%rsp
  mov    %esi,%edi
  cmpb   $0x0,(%rax)
  je     L23
  mov    %rax,%rdx
L38:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L38
L1:
  sub    %rax,%rdx
  mov    %rax,%rsi
  call   <write@plt>
  add    $0x8,%rsp
  ret
L23:
  mov    %rax,%rdx
  jmp    L1
L31:
  ret
```

assistant: ```c
void mini_printf(char *str, int fd) {
  char *p;
  if (str == NULL)
    return;
  p = str;
  while (*p)
    p++;
  write(fd, str, (size_t)(p - str));
}
```
user: Translate the below assembly code into C programming language:

```asm
<mini_printf>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  test   %r8,%r8
  je     L39
  cmpb   $0x0,(%r8)
  je     L33
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L7
  sub    %r8,%rdx
L38:
  mov    %r8,%rsi
  jmp    1050 <write@plt>
  nopl   0x0(%rax)
L39:
  ret
  nopl   0x0(%rax)
L33:
  xor    %edx,%edx
  jmp    L38
```

assistant: ```c
void mini_printf(char *str, int fd) {
  char *p;
  if (str == NULL)
    return;
  p = str;
  while (*p)
    p++;
  write(fd, str, (size_t)(p - str));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mini_printf>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  test   %r8,%r8
  je     L27
  cmpb   $0x0,(%r8)
  je     L19
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L37
  sub    %r8,%rdx
L1:
  mov    %r8,%rsi
  jmp    1050 <write@plt>
  nopl   0x0(%rax)
L27:
  ret
  nopl   0x0(%rax)
L19:
  xor    %edx,%edx
  jmp    L1
```

assistant: ```c
void mini_printf(char *str, int fd) {
  char *p;
  if (str == NULL)
    return;
  p = str;
  while (*p)
    p++;
  write(fd, str, (size_t)(p - str));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<selsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L6:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L37
L35:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L18
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L18:
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L35
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L6
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *selsort(int *a, unsigned n) {
  unsigned i, j, small;
  int temp;
  for (i = 0; i < n; ++i) {
    small = i;
    for (j = i + 1; j < n; ++j)
      if (a[j] < a[small])
        small = j;
    temp = a[small];
    a[small] = a[i];
    a[i] = temp;
  }
  return a;
}
```