ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<task3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe589eac7,%edi
  call   <fermat@plt>
  pop    %rbp
  ret
```

assistant: ```c
int task3() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 3 can only be calculated under 64bit. =( \n");
    return 6857;
  } else {
    return fermat(600851475143);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<task3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe589eac7,%edi
  call   <fermat@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int task3() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 3 can only be calculated under 64bit. =( \n");
    return 6857;
  } else {
    return fermat(600851475143);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<task3>:
  endbr64
  mov    $0xe589eac7,%edi
  jmp    1050 <fermat@plt>
```

assistant: ```c
int task3() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 3 can only be calculated under 64bit. =( \n");
    return 6857;
  } else {
    return fermat(600851475143);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<task3>:
  endbr64
  mov    $0xe589eac7,%edi
  jmp    1050 <fermat@plt>
```

assistant: ```c
int task3() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 3 can only be calculated under 64bit. =( \n");
    return 6857;
  } else {
    return fermat(600851475143);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<database_done>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <structdata_done@plt>
  nop
  leave
  ret
```

assistant: ```c
void database_done(struct DATA *p) {
  structdata_done(p);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<database_done>:
  endbr64
  sub    $0x8,%rsp
  call   <structdata_done@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void database_done(struct DATA *p) {
  structdata_done(p);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<database_done>:
  endbr64
  jmp    1050 <structdata_done@plt>
```

assistant: ```c
void database_done(struct DATA *p) {
  structdata_done(p);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<database_done>:
  endbr64
  jmp    1050 <structdata_done@plt>
```

assistant: ```c
void database_done(struct DATA *p) {
  structdata_done(p);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D53
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D44
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D61
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D64
type_guessed: string

tool: D53: Enter a number:

tool: D11: %d

tool: D49: division is: %d


tool: D44: multiplication is: %d


tool: D61: addition is: %d


tool: D67: subtraction is: %d


tool: D64: modulus is: %d


assistant: ```c
int main() {
  int x;
  printf("Enter a number:");
  scanf("%d", &x);
  int division = x / 2;
  printf("division is: %d\n", division);
  int multiplication = x * 2;
  printf("multiplication is: %d\n", multiplication);
  int addition = x + 2;
  printf("addition is: %d\n", addition);
  int subtraction = x - 2;
  printf("subtraction is: %d\n", subtraction);
  int modulus = x % 2;
  printf("modulus is: %d\n", modulus);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    0x2(%rax),%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  and    $0x1,%esi
  sub    %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D34
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D40
data_type: string

tool: D5: Enter a number:

tool: D18: %d

tool: D13: division is: %d


tool: D4: multiplication is: %d


tool: D34: addition is: %d


tool: D6: subtraction is: %d


tool: D40: modulus is: %d


assistant: ```c
int main() {
  int x;
  printf("Enter a number:");
  scanf("%d", &x);
  int division = x / 2;
  printf("division is: %d\n", division);
  int multiplication = x * 2;
  printf("multiplication is: %d\n", multiplication);
  int addition = x + 2;
  printf("addition is: %d\n", addition);
  int subtraction = x - 2;
  printf("subtraction is: %d\n", subtraction);
  int modulus = x % 2;
  printf("modulus is: %d\n", modulus);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D68(%rip),%rdi
  lea    (%rax,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D19(%rip),%rdi
  lea    0x2(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D44(%rip),%rdi
  lea    -0x2(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D31(%rip),%rdi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  and    $0x1,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D56
type: string
name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D68
type: string
name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D44
type: string
name: read_data
arguments: tag: D31
type: string

tool: D13: Enter a number:

tool: D56: %d

tool: D7: division is: %d


tool: D68: multiplication is: %d


tool: D19: addition is: %d


tool: D44: subtraction is: %d


tool: D31: modulus is: %d


assistant: ```c
int main() {
  int x;
  printf("Enter a number:");
  scanf("%d", &x);
  int division = x / 2;
  printf("division is: %d\n", division);
  int multiplication = x * 2;
  printf("multiplication is: %d\n", multiplication);
  int addition = x + 2;
  printf("addition is: %d\n", addition);
  int subtraction = x - 2;
  printf("subtraction is: %d\n", subtraction);
  int modulus = x % 2;
  printf("modulus is: %d\n", modulus);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D52(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D69(%rip),%rdi
  lea    (%rax,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D2(%rip),%rdi
  lea    0x2(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D30(%rip),%rdi
  lea    -0x2(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D50(%rip),%rdi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  and    $0x1,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D45
type_infered: string
name: parse_data
arguments: tag: D52
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D69
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D30
type_infered: string
name: parse_data
arguments: tag: D50
type_infered: string

tool: D45: Enter a number:

tool: D52: %d

tool: D18: division is: %d


tool: D69: multiplication is: %d


tool: D2: addition is: %d


tool: D30: subtraction is: %d


tool: D50: modulus is: %d


assistant: ```c
int main() {
  int x;
  printf("Enter a number:");
  scanf("%d", &x);
  int division = x / 2;
  printf("division is: %d\n", division);
  int multiplication = x * 2;
  printf("multiplication is: %d\n", multiplication);
  int addition = x + 2;
  printf("addition is: %d\n", addition);
  int subtraction = x - 2;
  printf("subtraction is: %d\n", subtraction);
  int modulus = x % 2;
  printf("modulus is: %d\n", modulus);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jne    L12
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  lea    D55(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  lea    D55(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  jmp    L8
L12:
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L8:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D55
type: string
name: extract_symbolic_data
arguments: tag: D50
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D55: %d

tool: D50: 
*** User Error: Command line arguments needed! ***



tool: D20: Please run with the following arguments:



tool: D15: ./poisson2D <number of data points in X> <number of data points in Y>



tool: D13: Exiting...



assistant: ```c
int getArgs(int argc, char **argv, int *nX, int *nY) {
  if (argc == 3) {
    sscanf(argv[1], "%d", &(*nX));
    sscanf(argv[2], "%d", &(*nY));
  } else {
    printf("\n*** User Error: Command line arguments needed! ***\n\n");
    printf("Please run with the following arguments:\n\n");
    printf("./poisson2D <number of data points in X> <number of data points in Y>\n\n");
    printf("Exiting...\n\n");
    exit(-1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getArgs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%edi
  je     L6
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L1:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rsi,%rbp
  mov    %rcx,%rbx
  mov    0x8(%rsi),%rdi
  lea    D42(%rip),%r12
  mov    %r12,%rsi
  call   <sscanf@plt>
  mov    0x10(%rbp),%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <sscanf@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D49
type_guessed: string
name: parse_data
arguments: tag: D42
type_guessed: string

tool: D15: 
*** User Error: Command line arguments needed! ***



tool: D27: Please run with the following arguments:



tool: D19: ./poisson2D <number of data points in X> <number of data points in Y>



tool: D49: Exiting...



tool: D42: %d

assistant: ```c
int getArgs(int argc, char **argv, int *nX, int *nY) {
  if (argc == 3) {
    sscanf(argv[1], "%d", &(*nX));
    sscanf(argv[2], "%d", &(*nY));
  } else {
    printf("\n*** User Error: Command line arguments needed! ***\n\n");
    printf("Please run with the following arguments:\n\n");
    printf("./poisson2D <number of data points in X> <number of data points in Y>\n\n");
    printf("Exiting...\n\n");
    exit(-1);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getArgs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%edi
  je     L4
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  mov    0x8(%rsi),%rdi
  lea    D2(%rip),%rbp
  mov    %rsi,%rbx
  mov    %rcx,%r12
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D29
type_guessed: string
name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D39
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D29: 
*** User Error: Command line arguments needed! ***



tool: D3: Please run with the following arguments:



tool: D39: ./poisson2D <number of data points in X> <number of data points in Y>



tool: D8: Exiting...



tool: D2: %d

assistant: ```c
int getArgs(int argc, char **argv, int *nX, int *nY) {
  if (argc == 3) {
    sscanf(argv[1], "%d", &(*nX));
    sscanf(argv[2], "%d", &(*nY));
  } else {
    printf("\n*** User Error: Command line arguments needed! ***\n\n");
    printf("Please run with the following arguments:\n\n");
    printf("./poisson2D <number of data points in X> <number of data points in Y>\n\n");
    printf("Exiting...\n\n");
    exit(-1);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getArgs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%edi
  je     L0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  mov    0x8(%rsi),%rdi
  lea    D45(%rip),%rbp
  mov    %rsi,%rbx
  mov    %rcx,%r12
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D33
data_type: string
name: read_data
arguments: data_label: D38
data_type: string
name: read_data
arguments: data_label: D47
data_type: string
name: read_data
arguments: data_label: D45
data_type: string

tool: D16: 
*** User Error: Command line arguments needed! ***



tool: D33: Please run with the following arguments:



tool: D38: ./poisson2D <number of data points in X> <number of data points in Y>



tool: D47: Exiting...



tool: D45: %d

assistant: ```c
int getArgs(int argc, char **argv, int *nX, int *nY) {
  if (argc == 3) {
    sscanf(argv[1], "%d", &(*nX));
    sscanf(argv[2], "%d", &(*nY));
  } else {
    printf("\n*** User Error: Command line arguments needed! ***\n\n");
    printf("Please run with the following arguments:\n\n");
    printf("./poisson2D <number of data points in X> <number of data points in Y>\n\n");
    printf("Exiting...\n\n");
    exit(-1);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vflip1_usmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L8
L3:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L10
L0:
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L0
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vflip1_usmatrix(ushort **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  ushort t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vflip1_usmatrix>:
  endbr64
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L29
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r8,%rbp
  mov    %edx,%r11d
  lea    (%rdi,%rax,8),%rsi
  lea    0x8(%rdi,%rdx,8),%r13
  movslq %ecx,%r12
  shl    $0x2,%r12
  lea    0x4(,%r8,4),%r10
  movslq %ecx,%r8
L33:
  cmp    %r8,%rbp
  jl     L19
  movslq %r11d,%rax
  lea    (%rbx,%rax,8),%r9
  mov    %r12,%rax
L11:
  mov    %rax,%rdx
  add    (%r9),%rdx
  mov    (%rdx),%ecx
  mov    (%rsi),%rdi
  mov    (%rdi,%rax,1),%edi
  mov    %edi,(%rdx)
  mov    (%rsi),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %r10,%rax
  jne    L11
L19:
  add    $0x8,%rsi
  sub    $0x1,%r11d
  cmp    %r13,%rsi
  jne    L33
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  ret
```

assistant: ```c
void vflip1_usmatrix(ushort **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  ushort t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vflip1_usmatrix>:
  endbr64
  movslq %esi,%r10
  push   %r13
  push   %r12
  lea    (%rsi,%rdx,1),%r12d
  push   %rbp
  push   %rbx
  cmp    %r10,%rdx
  jl     L20
  mov    %r8,%rbp
  movslq %ecx,%r8
  mov    %rdi,%r11
  mov    %rdx,%rbx
  lea    0x0(,%r8,4),%r13
  lea    0x4(,%rbp,4),%r9
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %r8,%rbp
  jl     L7
  mov    %r12d,%eax
  mov    (%r11,%r10,8),%rdx
  sub    %r10d,%eax
  cltq
  mov    (%r11,%rax,8),%rcx
  mov    %r13,%rax
L47:
  mov    (%rcx,%rax,1),%esi
  mov    (%rdx,%rax,1),%edi
  mov    %edi,(%rcx,%rax,1)
  mov    %esi,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L47
L7:
  lea    0x1(%r10),%rax
  cmp    %r10,%rbx
  je     L20
  mov    %rax,%r10
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void vflip1_usmatrix(ushort **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  ushort t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```