ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_func>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  add    $0x1,%rdi
  mov    $0x0,%edx
L7:
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L7
L11:
  mov    %edx,%eax
  ret
L23:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
int hash_func(const char *str) {
  int r = 0;
  int i;
  for (i = 0; str[i]; ++i) {
    r *= 2;
    r += str[i];
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_func>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L2
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rdi
  lea    (%rax,%r8,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L1
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hash_func(const char *str) {
  int r = 0;
  int i;
  for (i = 0; str[i]; ++i) {
    r *= 2;
    r += str[i];
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_func>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L16
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rdi
  lea    (%rax,%r8,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hash_func(const char *str) {
  int r = 0;
  int i;
  for (i = 0; str[i]; ++i) {
    r *= 2;
    r += str[i];
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<halt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L7:
  hlt
  jmp    L7
```

assistant: ```c
void halt(void) {
  while (1) {
    asm volatile("hlt");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<halt>:
  endbr64
L9:
  hlt
  jmp    L9
```

assistant: ```c
void halt(void) {
  while (1) {
    asm volatile("hlt");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<halt>:
  endbr64
  nopl   0x0(%rax)
L3:
  hlt
  jmp    L3
```

assistant: ```c
void halt(void) {
  while (1) {
    asm volatile("hlt");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<halt>:
  endbr64
  nopl   0x0(%rax)
L3:
  hlt
  jmp    L3
```

assistant: ```c
void halt(void) {
  while (1) {
    asm volatile("hlt");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L33
  mov    $0xffffffff,%eax
  jmp    L22
L33:
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L35
  mov    $0x1,%eax
  jmp    L22
L35:
  mov    $0x0,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int sort_compare(const void *a, const void *b) {
  if (*((double *)a) < *((double *)b))
    return -1;
  else if (*((double *)a) > *((double *)b))
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_compare>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L9
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
int sort_compare(const void *a, const void *b) {
  if (*((double *)a) < *((double *)b))
    return -1;
  else if (*((double *)a) > *((double *)b))
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_compare>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L9
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L9:
  ret
```

assistant: ```c
int sort_compare(const void *a, const void *b) {
  if (*((double *)a) < *((double *)b))
    return -1;
  else if (*((double *)a) > *((double *)b))
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_compare>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L9
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L9:
  ret
```

assistant: ```c
int sort_compare(const void *a, const void *b) {
  if (*((double *)a) < *((double *)b))
    return -1;
  else if (*((double *)a) > *((double *)b))
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L9
  cmpl   $0x7a,-0x4(%rbp)
  jg     L9
  subl   $0x20,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int toupper(int c) {
  if ((c >= 'a') && (c <= 'z')) {
    c += 'A' - 'a';
  }
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int c) {
  if ((c >= 'a') && (c <= 'z')) {
    c += 'A' - 'a';
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int c) {
  if ((c >= 'a') && (c <= 'z')) {
    c += 'A' - 'a';
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int c) {
  if ((c >= 'a') && (c <= 'z')) {
    c += 'A' - 'a';
  }
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<death_notes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <screen_save@plt>
  mov    $0x0,%eax
  call   <do_cmd_knowledge_notes@plt>
  mov    $0x0,%eax
  call   <screen_load@plt>
  nop
  leave
  ret
```

assistant: ```c
void death_notes(void *unused, const char *title) {
  (void)unused;
  (void)title;
  screen_save();
  do_cmd_knowledge_notes();
  screen_load();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<death_notes>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <screen_save@plt>
  mov    $0x0,%eax
  call   <do_cmd_knowledge_notes@plt>
  mov    $0x0,%eax
  call   <screen_load@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void death_notes(void *unused, const char *title) {
  (void)unused;
  (void)title;
  screen_save();
  do_cmd_knowledge_notes();
  screen_load();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<death_notes>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <screen_save@plt>
  xor    %eax,%eax
  call   <do_cmd_knowledge_notes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <screen_load@plt>
```

assistant: ```c
void death_notes(void *unused, const char *title) {
  (void)unused;
  (void)title;
  screen_save();
  do_cmd_knowledge_notes();
  screen_load();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<death_notes>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <screen_save@plt>
  xor    %eax,%eax
  call   <do_cmd_knowledge_notes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <screen_load@plt>
```

assistant: ```c
void death_notes(void *unused, const char *title) {
  (void)unused;
  (void)title;
  screen_save();
  do_cmd_knowledge_notes();
  screen_load();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<NEditCalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <NEditMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *NEditCalloc(size_t nmemb, size_t size) {
  void *ptr = NEditMalloc(nmemb * size);
  memset(ptr, 0, nmemb * size);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NEditCalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <NEditMalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *NEditCalloc(size_t nmemb, size_t size) {
  void *ptr = NEditMalloc(nmemb * size);
  memset(ptr, 0, nmemb * size);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<NEditCalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <NEditMalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *NEditCalloc(size_t nmemb, size_t size) {
  void *ptr = NEditMalloc(nmemb * size);
  memset(ptr, 0, nmemb * size);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<NEditCalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <NEditMalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *NEditCalloc(size_t nmemb, size_t size) {
  void *ptr = NEditMalloc(nmemb * size);
  memset(ptr, 0, nmemb * size);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  jmp    L6
L26:
  subq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L17
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
char *strrchr(const char *str, int c) {
  const char *ptr = str + strlen(str);
  while (ptr >= str) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr--;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strrchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jb     L3
L4:
  movsbl (%rax),%edx
  cmp    %ebp,%edx
  je     L15
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L4
  mov    $0x0,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x0,%eax
  jmp    L15
```

assistant: ```c
char *strrchr(const char *str, int c) {
  const char *ptr = str + strlen(str);
  while (ptr >= str) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr--;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jae    L8
  jmp    L4
  nopl   (%rax)
L15:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  ja     L4
L8:
  movsbl (%rax),%edx
  cmp    %ebp,%edx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *str, int c) {
  const char *ptr = str + strlen(str);
  while (ptr >= str) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr--;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jae    L26
  jmp    L8
  nopl   (%rax)
L20:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  ja     L8
L26:
  movsbl (%rax),%edx
  cmp    %ebp,%edx
  jne    L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *str, int c) {
  const char *ptr = str + strlen(str);
  while (ptr >= str) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr--;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isValidBackground>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L29
  mov    $0x1,%eax
  jmp    L0
L29:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int isValidBackground(char *input) {
  int i = 0;
  for (i = 0; input[i] != '\0'; i++) {
    if (input[i] == '&')
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isValidBackground>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  add    $0x1,%rdi
L29:
  cmp    $0x26,%al
  je     L26
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L29
  mov    $0x0,%eax
  ret
L4:
  mov    $0x0,%eax
  ret
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isValidBackground(char *input) {
  int i = 0;
  for (i = 0; input[i] != '\0'; i++) {
    if (input[i] == '&')
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isValidBackground>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
  add    $0x1,%rdi
  jmp    L17
  nopl   0x0(%rax)
L8:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L36
L17:
  cmp    $0x26,%al
  jne    L8
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isValidBackground(char *input) {
  int i = 0;
  for (i = 0; input[i] != '\0'; i++) {
    if (input[i] == '&')
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isValidBackground>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdi
  jmp    L10
  nopl   0x0(%rax)
L39:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L0
L10:
  cmp    $0x26,%al
  jne    L39
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isValidBackground(char *input) {
  int i = 0;
  for (i = 0; input[i] != '\0'; i++) {
    if (input[i] == '&')
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uncompress2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  shll   $0x7,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x7f,%eax
  or     %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L20
  mov    -0xc(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L17
  jmp    L3
L20:
  nop
L3:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int uncompress2(unsigned char **buffer) {
  int _c;
  int num = 0;
  unsigned char *p = *buffer;
  do {
    _c = (int)((unsigned char)*p++);
    num <<= 7;
    num |= _c & 127;
    if (!num)
      break;
  } while (_c & 128);
  *buffer = p;
  return num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uncompress2>:
  endbr64
  mov    (%rdi),%rdx
  mov    $0x0,%eax
L17:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%esi
  shl    $0x7,%eax
  mov    %esi,%ecx
  and    $0x7f,%ecx
  or     %ecx,%eax
  je     L16
  test   %sil,%sil
  js     L17
L16:
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int uncompress2(unsigned char **buffer) {
  int _c;
  int num = 0;
  unsigned char *p = *buffer;
  do {
    _c = (int)((unsigned char)*p++);
    num <<= 7;
    num |= _c & 127;
    if (!num)
      break;
  } while (_c & 128);
  *buffer = p;
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uncompress2>:
  endbr64
  mov    (%rdi),%rdx
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L0:
  test   %sil,%sil
  jns    L25
L10:
  movzbl (%rdx),%esi
  shl    $0x7,%eax
  add    $0x1,%rdx
  mov    %esi,%ecx
  and    $0x7f,%ecx
  or     %ecx,%eax
  jne    L0
L25:
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int uncompress2(unsigned char **buffer) {
  int _c;
  int num = 0;
  unsigned char *p = *buffer;
  do {
    _c = (int)((unsigned char)*p++);
    num <<= 7;
    num |= _c & 127;
    if (!num)
      break;
  } while (_c & 128);
  *buffer = p;
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uncompress2>:
  endbr64
  mov    (%rdi),%rdx
  xor    %eax,%eax
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L3:
  test   %sil,%sil
  jns    L10
L24:
  movzbl (%rdx),%esi
  shl    $0x7,%eax
  add    $0x1,%rdx
  mov    %esi,%ecx
  and    $0x7f,%ecx
  or     %ecx,%eax
  jne    L3
L10:
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int uncompress2(unsigned char **buffer) {
  int _c;
  int num = 0;
  unsigned char *p = *buffer;
  do {
    _c = (int)((unsigned char)*p++);
    num <<= 7;
    num |= _c & 127;
    if (!num)
      break;
  } while (_c & 128);
  *buffer = p;
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <diff@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <mag@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dist(double v1[3], double v2[3]) {
  double diff_vector[3];
  diff(v1, v2, diff_vector);
  return mag(diff_vector);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dist>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdx
  call   <diff@plt>
  mov    %rbx,%rdi
  call   <mag@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double dist(double v1[3], double v2[3]) {
  double diff_vector[3];
  diff(v1, v2, diff_vector);
  return mag(diff_vector);
}
```
user: What is the c source code of the assembly code below?

```asm
<dist>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <diff@plt>
  mov    %rbp,%rdi
  call   <mag@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double dist(double v1[3], double v2[3]) {
  double diff_vector[3];
  diff(v1, v2, diff_vector);
  return mag(diff_vector);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dist>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <diff@plt>
  mov    %rbp,%rdi
  call   <mag@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double dist(double v1[3], double v2[3]) {
  double diff_vector[3];
  diff(v1, v2, diff_vector);
  return mag(diff_vector);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```