ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<exec_shellcode>:
  endbr64
  test   %rdi,%rdi
  je     L8
  xor    %eax,%eax
  jmp    *%rdi
  nopl   (%rax)
L8:
  ret
```

assistant: ```c
void exec_shellcode(unsigned char *shellcode, int shellcode_size, char *payload_info) {
  0;
  if (shellcode != NULL) {
    int (*funct)();
    funct = (int (*)())shellcode;
    (int)(*funct)();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <ParseDouble@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <ParseDouble@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <Bmi@plt>
  mov    %eax,%edi
  call   <PrintOutput@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  double lbs, inches;
  lbs = ParseDouble();
  inches = ParseDouble();
  PrintOutput(Bmi(lbs, inches));
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <ParseDouble@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <ParseDouble@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  call   <Bmi@plt>
  mov    %eax,%edi
  call   <PrintOutput@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  double lbs, inches;
  lbs = ParseDouble();
  inches = ParseDouble();
  PrintOutput(Bmi(lbs, inches));
  return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <ParseDouble@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <ParseDouble@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <Bmi@plt>
  mov    %eax,%edi
  call   <PrintOutput@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  double lbs, inches;
  lbs = ParseDouble();
  inches = ParseDouble();
  PrintOutput(Bmi(lbs, inches));
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <ParseDouble@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <ParseDouble@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <Bmi@plt>
  mov    %eax,%edi
  call   <PrintOutput@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  double lbs, inches;
  lbs = ParseDouble();
  inches = ParseDouble();
  PrintOutput(Bmi(lbs, inches));
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x7fffffff,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: %d


assistant: ```c
void main() {
  int i = 2147483647;
  printf("%d\n", ++i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000000,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: %d


assistant: ```c
void main() {
  int i = 2147483647;
  printf("%d\n", ++i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x80000000,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: %d


assistant: ```c
void main() {
  int i = 2147483647;
  printf("%d\n", ++i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x80000000,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: %d


assistant: ```c
void main() {
  int i = 2147483647;
  printf("%d\n", ++i);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L64
  mov    $0x1,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L64:
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L0:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0xa(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L26:
  cmpl   $0x0,-0x14(%rbp)
  jle    L0
  lea    -0x9(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x69,%al
  jne    L32
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L32:
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L42:
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L52:
  cmpl   $0x0,-0x10(%rbp)
  jle    L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D29
type: string
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D17
type: string

tool: D29: Call this program with %i arguments


tool: D3: You win!

tool: D17: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 105) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L19
L27:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %al,0x6(%rsp)
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpb   $0x69,0x7(%rsp)
  je     L0
L9:
  movzbl 0x7(%rsp),%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x1,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L27
L0:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string

tool: D12: %u


tool: D25: Call this program with %i arguments


tool: D29: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 105) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L36
  lea    D2(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L36:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x69,%sil
  je     L3
L33:
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L33
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string

tool: D2: Call this program with %i arguments


tool: D22: %u


tool: D10: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 105) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L5
  lea    D21(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x69,%sil
  je     L31
L34:
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L31:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L34
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D21: Call this program with %i arguments


tool: D9: %u


tool: D5: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 105) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x64,%edi
  call   <__builtin_alloca@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x32,%rax
  mov    %rax,%rdi
  call   <goo@plt>
  leave
  ret
```

assistant: ```c
int foo9() {
  char *p = __builtin_alloca(100);
  return goo((int *)(p + 50));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <__builtin_alloca@plt>
  lea    0x32(%rax),%rdi
  call   <goo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int foo9() {
  char *p = __builtin_alloca(100);
  return goo((int *)(p + 50));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <__builtin_alloca@plt>
  add    $0x8,%rsp
  lea    0x32(%rax),%rdi
  jmp    1060 <goo@plt>
```

assistant: ```c
int foo9() {
  char *p = __builtin_alloca(100);
  return goo((int *)(p + 50));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <__builtin_alloca@plt>
  add    $0x8,%rsp
  lea    0x32(%rax),%rdi
  jmp    1060 <goo@plt>
```

assistant: ```c
int foo9() {
  char *p = __builtin_alloca(100);
  return goo((int *)(p + 50));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<select_display>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm0
  call   <glClearColor@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  mov    D1(%rip),%rax
  or     (%rax),%edi
  call   <glClear@plt>
  mov    $0x0,%eax
  call   <drawScene@plt>
  mov    $0x0,%eax
  call   <selectObjects@plt>
  mov    $0x0,%eax
  call   <glFlush@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void select_display(void) {
  glClearColor(0.0, 0.0, 0.0, 0.0);
  glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
  drawScene();
  selectObjects();
  glFlush();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<select_display>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm0
  call   <glClearColor@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  mov    D14(%rip),%rax
  or     (%rax),%edi
  call   <glClear@plt>
  xor    %eax,%eax
  call   <drawScene@plt>
  xor    %eax,%eax
  call   <selectObjects@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <glFlush@plt>
```

assistant: ```c
void select_display(void) {
  glClearColor(0.0, 0.0, 0.0, 0.0);
  glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
  drawScene();
  selectObjects();
  glFlush();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<select_display>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm0
  call   <glClearColor@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  mov    D11(%rip),%rax
  or     (%rax),%edi
  call   <glClear@plt>
  xor    %eax,%eax
  call   <drawScene@plt>
  xor    %eax,%eax
  call   <selectObjects@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <glFlush@plt>
```

assistant: ```c
void select_display(void) {
  glClearColor(0.0, 0.0, 0.0, 0.0);
  glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
  drawScene();
  selectObjects();
  glFlush();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  je     L14
  cmpl   $0x6,-0x4(%rbp)
  jg     L27
  cmpl   $0x4,-0x4(%rbp)
  je     L51
  cmpl   $0x5,-0x4(%rbp)
  je     L31
  jmp    L27
L51:
  mov    $0x4,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L31:
  mov    $0x5,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L14:
  mov    $0x6,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L27:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D20
type_guessed: string

tool: D5: %d


tool: D20: default

assistant: ```c
int main(void) {
  int a = 5;
  switch (a) {
  case 4:
    printf("%d\n", 4);
    break;
  case 5:
    printf("%d\n", 5);
    break;
  case 6:
    printf("%d\n", 6);
    break;
  default:
    printf("default");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: %d


assistant: ```c
int main(void) {
  int a = 5;
  switch (a) {
  case 4:
    printf("%d\n", 4);
    break;
  case 5:
    printf("%d\n", 5);
    break;
  case 6:
    printf("%d\n", 6);
    break;
  default:
    printf("default");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(void) {
  int a = 5;
  switch (a) {
  case 4:
    printf("%d\n", 4);
    break;
  case 5:
    printf("%d\n", 5);
    break;
  case 6:
    printf("%d\n", 6);
    break;
  default:
    printf("default");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main(void) {
  int a = 5;
  switch (a) {
  case 4:
    printf("%d\n", 4);
    break;
  case 5:
    printf("%d\n", 5);
    break;
  case 6:
    printf("%d\n", 6);
    break;
  default:
    printf("default");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcop(char *str) {
  char *ret = malloc(strlen(str) + 1);
  strcpy(ret, str);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcop(char *str) {
  char *ret = malloc(strlen(str) + 1);
  strcpy(ret, str);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcop>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcop(char *str) {
  char *ret = malloc(strlen(str) + 1);
  strcpy(ret, str);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcop>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcop(char *str) {
  char *ret = malloc(strlen(str) + 1);
  strcpy(ret, str);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pack_MRxk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L26:
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L10:
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0x7,-0x8(%rbp)
  jle    L10
  addq   $0x40,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pack_MRxk(int k, const double *A, int incRowA, int incColA, double *buffer) {
  int i, j;
  for (j = 0; j < k; ++j) {
    for (i = 0; i < 8; ++i) {
      buffer[i] = A[i * incRowA];
    }
    buffer += 8;
    A += incColA;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pack_MRxk>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  test   %eax,%eax
  jle    L27
  movslq %ecx,%rcx
  lea    0x0(,%rcx,8),%r10
  lea    0x40(%r8),%rcx
  mov    %eax,%eax
  shl    $0x6,%rax
  lea    (%r8,%rax,1),%r9
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rsi
  jmp    L6
L49:
  add    $0x40,%r8
  add    %r10,%rdi
  add    $0x40,%rcx
  cmp    %r9,%r8
  je     L27
L6:
  mov    %rdi,%rdx
  mov    %r8,%rax
L1:
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L1
  jmp    L49
L27:
  ret
```

assistant: ```c
void pack_MRxk(int k, const double *A, int incRowA, int incColA, double *buffer) {
  int i, j;
  for (j = 0; j < k; ++j) {
    for (i = 0; i < 8; ++i) {
      buffer[i] = A[i * incRowA];
    }
    buffer += 8;
    A += incColA;
  }
}
```