ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<VsLoadPlugin>:
  endbr64
  push   %r15
  lea    0x5(%rdi),%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  test   %esi,%esi
  jle    L6
  nopl   0x0(%rax)
L4:
  movslq %ebp,%rsi
  lea    0x1(%rbp),%eax
  movzbl 0x0(%r13,%rsi,1),%ebx
  cmp    $0xf,%bl
  ja     L28
  lea    0x2(%rbp),%ecx
  cltq
  lea    0x3(%rbp),%edx
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rax,1),%eax
  movzbl 0x0(%r13,%rcx,1),%ecx
  shl    $0x8,%ecx
  or     %cx,%ax
  js     L26
  lea    -0x1(%rax),%r14d
  test   %ax,%ax
  je     L1
  movslq %edx,%rdx
  add    0x8(%rsp),%rsi
  movzwl %r14w,%eax
  lea    0x0(%r13,%rdx,1),%r15
  lea    (%rsi,%rax,2),%r12
  cs nopw 0x0(%rax,%rax,1)
L29:
  movzbl 0x1(%r15),%eax
  movzbl (%r15),%esi
  mov    %ebx,%edi
  add    $0x2,%r15
  shl    $0x8,%eax
  or     %eax,%esi
  movzwl %si,%esi
  call   <VsWriteRegister@plt>
  cmp    %r15,%r12
  jne    L29
  movzwl %r14w,%r14d
  lea    0x5(%rbp,%r14,2),%ebp
L19:
  cmp    0x4(%rsp),%ebp
  jl     L4
L6:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L26:
  lea    0x4(%rbp),%ecx
  movslq %edx,%rdx
  and    $0x7fff,%ax
  add    $0x5,%ebp
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rdx,1),%r12d
  lea    -0x1(%rax),%r14d
  movzbl 0x0(%r13,%rcx,1),%ecx
  shl    $0x8,%ecx
  or     %ecx,%r12d
  test   %ax,%ax
  je     L19
  movzwl %r12w,%r12d
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r12d,%esi
  mov    %ebx,%edi
  sub    $0x1,%r14d
  call   <VsWriteRegister@plt>
  cmp    $0xffff,%r14w
  jne    L39
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %edx,%ebp
  jmp    L19
  nopl   0x0(%rax)
L28:
  add    $0x18,%rsp
  mov    $0x3,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char VsLoadPlugin(unsigned char *pluginBuffer, int length) {
  int i = 0;
  while (i < length) {
    unsigned char addr = pluginBuffer[i++];
    if (addr > 15)
      return 3;
    unsigned short n, val;
    n = pluginBuffer[i++];
    n |= pluginBuffer[i++] << 8;
    if ((n & 0x8000) != 0) {
      n &= 0x7FFF;
      val = pluginBuffer[i++];
      val |= pluginBuffer[i++] << 8;
      while (n-- != 0)
        VsWriteRegister(addr, val);
    } else
      while (n-- != 0) {
        val = pluginBuffer[i++];
        val |= pluginBuffer[i++] << 8;
        VsWriteRegister(addr, val);
      }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  jmp    L49
L11:
  mov    -0x18(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L32
  mov    -0x18(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L51
L64:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <putc@plt>
  addl   $0x1,-0x1c(%rbp)
L51:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L64
  jmp    L49
L32:
  mov    -0x18(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L27:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <putc@plt>
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
L49:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x18(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jne    L11
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void decompress(FILE *in, FILE *out) {
  int input;
  int num;
  int i;
  while ((input = getc(in)) != EOF) {
    if (input & 0x80) {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(0, out);
    } else {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(getc(in), out);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decompress>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  jmp    L56
L47:
  mov    %r12,%rdi
  call   <getc@plt>
  shl    $0x8,%ebx
  and    $0x7f00,%ebx
  or     %eax,%ebx
  jle    L56
L63:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x1,%r13d
  cmp    %r13d,%ebx
  jne    L63
L56:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  je     L15
  mov    %ebx,%r13d
  and    $0x80,%r13d
  je     L47
  mov    %r12,%rdi
  call   <getc@plt>
  shl    $0x8,%ebx
  and    $0x7f00,%ebx
  or     %eax,%ebx
  mov    %ebx,%r13d
  shl    $0x8,%r13d
  mov    %r12,%rdi
  call   <getc@plt>
  or     %eax,%r13d
  shl    $0x8,%r13d
  mov    %r12,%rdi
  call   <getc@plt>
  or     %eax,%r13d
  jle    L56
  mov    $0x0,%ebx
L24:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <putc@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L24
  jmp    L56
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void decompress(FILE *in, FILE *out) {
  int input;
  int num;
  int i;
  while ((input = getc(in)) != EOF) {
    if (input & 0x80) {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(0, out);
    } else {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(getc(in), out);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<decompress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%r13
  nop
L68:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%r13)
  je     L2
L54:
  mov    %ebx,%r15d
  mov    %r12,%rdi
  shl    $0x8,%r15d
  and    $0x7f00,%r15d
  and    $0x80,%ebx
  je     L48
  call   <getc@plt>
  mov    %r12,%rdi
  xor    %ebx,%ebx
  or     %r15d,%eax
  mov    %eax,%r14d
  call   <getc@plt>
  shl    $0x8,%r14d
  mov    %r12,%rdi
  or     %eax,%r14d
  call   <getc@plt>
  shl    $0x8,%r14d
  or     %eax,%r14d
  jle    L68
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x1,%ebx
  call   <putc@plt>
  cmp    %ebx,%r14d
  jne    L28
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%r13)
  jne    L54
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L48:
  call   <getc@plt>
  or     %eax,%r15d
  jle    L68
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <getc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  cmp    %ebx,%r15d
  jne    L55
  jmp    L68
```

assistant: ```c
void decompress(FILE *in, FILE *out) {
  int input;
  int num;
  int i;
  while ((input = getc(in)) != EOF) {
    if (input & 0x80) {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(0, out);
    } else {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(getc(in), out);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decompress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D1(%rip),%r13
  nop
L63:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%r13)
  je     L70
L40:
  mov    %ebx,%r15d
  mov    %r12,%rdi
  shl    $0x8,%r15d
  and    $0x7f00,%r15d
  and    $0x80,%ebx
  je     L72
  call   <getc@plt>
  mov    %r12,%rdi
  xor    %ebx,%ebx
  or     %r15d,%eax
  mov    %eax,%r14d
  call   <getc@plt>
  shl    $0x8,%r14d
  mov    %r12,%rdi
  or     %eax,%r14d
  call   <getc@plt>
  shl    $0x8,%r14d
  or     %eax,%r14d
  jle    L63
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x1,%ebx
  call   <putc@plt>
  cmp    %ebx,%r14d
  jne    L55
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%r13)
  jne    L40
L70:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L72:
  call   <getc@plt>
  or     %eax,%r15d
  jle    L63
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <getc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  cmp    %ebx,%r15d
  jne    L2
  jmp    L63
```

assistant: ```c
void decompress(FILE *in, FILE *out) {
  int input;
  int num;
  int i;
  while ((input = getc(in)) != EOF) {
    if (input & 0x80) {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(0, out);
    } else {
      num = input & 0x7f;
      num = (num << 8) | getc(in);
      for (i = 0; i < num; i++)
        putc(getc(in), out);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uint16_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L20
L28:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  add    %rax,-0x8(%rbp)
  addq   $0x4,-0x18(%rbp)
  subq   $0x2,-0x20(%rbp)
L20:
  cmpq   $0x1,-0x20(%rbp)
  ja     L28
  cmpq   $0x1,-0x20(%rbp)
  jne    L29
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  add    %rax,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint32_t uint16_checksum(uint16_t *data, size_t n) {
  uint32_t sum = 0;
  while (n >= 2) {
    sum += (uint32_t)ntohs(*data);
    data++;
    n -= 2;
  }
  if (n == 1) {
    sum += (uint32_t)ntohs(*(uint8_t *)data);
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uint16_checksum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r13
  cmp    $0x1,%rsi
  jbe    L18
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  mov    $0x0,%r12d
L36:
  mov    (%rbx),%edi
  call   <ntohs@plt>
  add    %rax,%r12
  add    $0x4,%rbx
  sub    $0x2,%rbp
  cmp    $0x1,%rbp
  ja     L36
  lea    -0x2(%r13),%rax
  shr    %rax
  lea    0x4(%r14,%rax,4),%r14
  and    $0x1,%r13d
L14:
  cmp    $0x1,%r13
  je     L47
L37:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    $0x0,%r12d
  jmp    L14
L47:
  mov    (%r14),%edi
  call   <ntohs@plt>
  add    %rax,%r12
  jmp    L37
```

assistant: ```c
uint32_t uint16_checksum(uint16_t *data, size_t n) {
  uint32_t sum = 0;
  while (n >= 2) {
    sum += (uint32_t)ntohs(*data);
    data++;
    n -= 2;
  }
  if (n == 1) {
    sum += (uint32_t)ntohs(*(uint8_t *)data);
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uint16_checksum>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%rsi
  jbe    L15
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L25:
  mov    (%rbx),%edi
  sub    $0x2,%rbp
  add    $0x4,%rbx
  call   <ntohs@plt>
  add    %rax,%r12
  cmp    $0x1,%rbp
  ja     L25
  lea    -0x2(%r13),%rax
  and    $0x1,%r13d
  shr    %rax
  lea    0x4(%r14,%rax,4),%r14
L6:
  cmp    $0x1,%r13
  je     L18
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%r14),%edi
  call   <ntohs@plt>
  pop    %rbx
  pop    %rbp
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L15:
  xor    %r12d,%r12d
  jmp    L6
```

assistant: ```c
uint32_t uint16_checksum(uint16_t *data, size_t n) {
  uint32_t sum = 0;
  while (n >= 2) {
    sum += (uint32_t)ntohs(*data);
    data++;
    n -= 2;
  }
  if (n == 1) {
    sum += (uint32_t)ntohs(*(uint8_t *)data);
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<uint16_checksum>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%rsi
  jbe    L9
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L13:
  mov    (%rbx),%edi
  sub    $0x2,%rbp
  add    $0x4,%rbx
  call   <ntohs@plt>
  add    %rax,%r12
  cmp    $0x1,%rbp
  ja     L13
  lea    -0x2(%r13),%rax
  and    $0x1,%r13d
  shr    %rax
  lea    0x4(%r14,%rax,4),%r14
L12:
  cmp    $0x1,%r13
  je     L29
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%r14),%edi
  call   <ntohs@plt>
  pop    %rbx
  pop    %rbp
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L9:
  xor    %r12d,%r12d
  jmp    L12
```

assistant: ```c
uint32_t uint16_checksum(uint16_t *data, size_t n) {
  uint32_t sum = 0;
  while (n >= 2) {
    sum += (uint32_t)ntohs(*data);
    data++;
    n -= 2;
  }
  if (n == 1) {
    sum += (uint32_t)ntohs(*(uint8_t *)data);
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pwm_isr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7f006044,%eax
  mov    (%rax),%eax
  mov    $0x7f006044,%edx
  or     $0x20,%eax
  mov    %eax,(%rdx)
  mov    $0x71200f00,%eax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  call   <OSTimeTick@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pwm_isr(void) {
  (*(volatile unsigned int *)(0x7F006044)) |= (1 << 5);
  (*(volatile unsigned int *)(0x71200F00)) = 0;
  OSTimeTick();
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pwm_isr>:
  endbr64
  sub    $0x8,%rsp
  mov    0x7f006044,%eax
  or     $0x20,%eax
  mov    %eax,0x7f006044
  movl   $0x0,0x71200f00
  mov    $0x0,%eax
  call   <OSTimeTick@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pwm_isr(void) {
  (*(volatile unsigned int *)(0x7F006044)) |= (1 << 5);
  (*(volatile unsigned int *)(0x71200F00)) = 0;
  OSTimeTick();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<pwm_isr>:
  endbr64
  mov    0x7f006044,%eax
  or     $0x20,%eax
  mov    %eax,0x7f006044
  xor    %eax,%eax
  movl   $0x0,0x71200f00
  jmp    1050 <OSTimeTick@plt>
```

assistant: ```c
void pwm_isr(void) {
  (*(volatile unsigned int *)(0x7F006044)) |= (1 << 5);
  (*(volatile unsigned int *)(0x71200F00)) = 0;
  OSTimeTick();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pwm_isr>:
  endbr64
  mov    0x7f006044,%eax
  or     $0x20,%eax
  mov    %eax,0x7f006044
  xor    %eax,%eax
  movl   $0x0,0x71200f00
  jmp    1050 <OSTimeTick@plt>
```

assistant: ```c
void pwm_isr(void) {
  (*(volatile unsigned int *)(0x7F006044)) |= (1 << 5);
  (*(volatile unsigned int *)(0x71200F00)) = 0;
  OSTimeTick();
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<san_fail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <exit@plt>
```

assistant: ```c
void san_fail(void) {
  extern _Noreturn void exit(int);
  exit(5);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<san_fail>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <exit@plt>
```

assistant: ```c
void san_fail(void) {
  extern _Noreturn void exit(int);
  exit(5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<san_fail>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <exit@plt>
```

assistant: ```c
void san_fail(void) {
  extern _Noreturn void exit(int);
  exit(5);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<san_fail>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <exit@plt>
```

assistant: ```c
void san_fail(void) {
  extern _Noreturn void exit(int);
  exit(5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uafAndCallsFooWithEmptyReturn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xc,%edi
  call   <fooWithEmptyReturn@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int uafAndCallsFooWithEmptyReturn() {
  int *x = (int *)malloc(12);
  free(x);
  fooWithEmptyReturn(12);
  return *x;
}
```
user: What is the c source code of the assembly code below:

```asm
<uafAndCallsFooWithEmptyReturn>:
  endbr64
  push   %rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xc,%edi
  call   <fooWithEmptyReturn@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int uafAndCallsFooWithEmptyReturn() {
  int *x = (int *)malloc(12);
  free(x);
  fooWithEmptyReturn(12);
  return *x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uafAndCallsFooWithEmptyReturn>:
  endbr64
  push   %rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <free@plt>
  mov    $0xc,%edi
  call   <fooWithEmptyReturn@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int uafAndCallsFooWithEmptyReturn() {
  int *x = (int *)malloc(12);
  free(x);
  fooWithEmptyReturn(12);
  return *x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uafAndCallsFooWithEmptyReturn>:
  endbr64
  push   %rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <free@plt>
  mov    $0xc,%edi
  call   <fooWithEmptyReturn@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int uafAndCallsFooWithEmptyReturn() {
  int *x = (int *)malloc(12);
  free(x);
  fooWithEmptyReturn(12);
  return *x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<event_base_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ev_loop@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int event_base_loop(struct event_base *base, int flags) {
  struct ev_loop *loop = (struct ev_loop *)base;
  ev_loop(loop, flags);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<event_base_loop>:
  endbr64
  sub    $0x8,%rsp
  call   <ev_loop@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int event_base_loop(struct event_base *base, int flags) {
  struct ev_loop *loop = (struct ev_loop *)base;
  ev_loop(loop, flags);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<event_base_loop>:
  endbr64
  sub    $0x8,%rsp
  call   <ev_loop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int event_base_loop(struct event_base *base, int flags) {
  struct ev_loop *loop = (struct ev_loop *)base;
  ev_loop(loop, flags);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<event_base_loop>:
  endbr64
  sub    $0x8,%rsp
  call   <ev_loop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int event_base_loop(struct event_base *base, int flags) {
  struct ev_loop *loop = (struct ev_loop *)base;
  ev_loop(loop, flags);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<groupRecognize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rsi
  mov    -0x34(%rbp),%edi
  mov    -0x30(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <recognize@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void groupRecognize(double **neurons, double **images, double **result, int num_images, int rec_images_num, int data_dim) {
  int i;
  for (i = 0; i < num_images; i++) {
    recognize(neurons, images[i], result[i], rec_images_num, data_dim);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<groupRecognize>:
  endbr64
  test   %ecx,%ecx
  jle    L17
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %r8d,%r13d
  mov    %r9d,%r14d
  mov    %rdx,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%r15
L1:
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    (%rbx),%rdx
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  call   <recognize@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r15,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  ret
```

assistant: ```c
void groupRecognize(double **neurons, double **images, double **result, int num_images, int rec_images_num, int data_dim) {
  int i;
  for (i = 0; i < num_images; i++) {
    recognize(neurons, images[i], result[i], rec_images_num, data_dim);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<groupRecognize>:
  endbr64
  test   %ecx,%ecx
  jle    L19
  push   %r15
  lea    -0x1(%rcx),%eax
  push   %r14
  lea    0x8(%rdx,%rax,8),%r15
  mov    %r9d,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L4:
  mov    (%rbx),%rdx
  mov    0x0(%rbp),%rsi
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12,%rdi
  add    $0x8,%rbx
  add    $0x8,%rbp
  call   <recognize@plt>
  cmp    %r15,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void groupRecognize(double **neurons, double **images, double **result, int num_images, int rec_images_num, int data_dim) {
  int i;
  for (i = 0; i < num_images; i++) {
    recognize(neurons, images[i], result[i], rec_images_num, data_dim);
  }
}
```