user: 这段汇编代码用C语言表示是什么样的?

```asm
<printSudoku>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x0,%ebp
  jmp    L178
L83:
  lea    D95(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L78
L11:
  sub    $0x1,%ebx
  je     L148
L171:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%rcx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L11
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L148:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%rcx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L196
L163:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%rcx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L159
  lea    D90(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L106:
  mov    0x8(%rsp),%r13
  mov    $0x0,%ebx
  lea    D44(%rip),%r15
  lea    D33(%rip),%r14
  lea    D61(%rip),%r12
  jmp    L4
L196:
  mov    $0x2d,%edi
  call   <putchar@plt>
  jmp    L163
L159:
  lea    D95(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L106
L155:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L89:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L12
L4:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%rcx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L155
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L89
L12:
  mov    $0x7c,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  addq   $0x24,0x8(%rsp)
  cmp    $0x9,%ebp
  je     L135
L178:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%rcx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L83
  lea    D90(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L78:
  mov    $0x9,%ebx
  jmp    L171
L135:
  lea    D90(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rbp
  jmp    L179
L151:
  sub    $0x1,%ebx
  je     L183
L179:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%rcx
  mov    $0x9,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L151
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L151
L183:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D95
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D90
type: string
name: disassemble_data
arguments: data_tag: D44
type: string
name: disassemble_data
arguments: data_tag: D33
type: string
name: disassemble_data
arguments: data_tag: D61
type: string

tool: D95: 
		

tool: D12: - - - 

tool: D90: 

		

tool: D44: | 

tool: D33: , 

tool: D61: %3d 

assistant: ```c
void printSudoku(int grid[9][9]) {
  int i, j;
  for (i = 0; i < 9; ++i) {
    if (i % ((int)sqrt(9)) == 0)
      printf("\n\n\t\t");
    else
      printf("\n\t\t");
    for (j = 0; j < 9; ++j)
      if (i % ((int)sqrt(9)) == 0)
        printf("- - - ");
    if (i % ((int)sqrt(9)) == 0)
      printf("-");
    if (i % ((int)sqrt(9)) == 0)
      printf("\n\n\t\t");
    else
      printf("\n\t\t");
    for (j = 0; j < 9; ++j) {
      if (j % ((int)sqrt(9)))
        printf(", ");
      else
        printf("| ");
      printf("%3d ", grid[i][j]);
    }
    printf("|");
  }
  printf("\n\n\t\t");
  for (j = 0; j < 9; ++j)
    if (i % ((int)sqrt(9)) == 0)
      printf("- - - ");
  printf("\n");
}
```