ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<make_substring>:
  endbr64
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  sub    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L6
  xor    %edx,%edx
  lea    0x0(%rbp,%r12,1),%rsi
  nopl   0x0(%rax)
L11:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L11
  add    $0x1,%rbx
  movb   $0x0,(%rax,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%ebx
  movb   $0x0,(%rax,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *make_substring(char *str, int b, int e) {
  char *new_string = malloc(sizeof(int) * (e - b) + 1);
  int i;
  for (i = 0; i < (e - b); i++) {
    new_string[i] = str[b + i];
  }
  new_string[i + 1] = '\0';
  return new_string;
}
```
user: What is the c source code of the assembly code below?

```asm
<make_substring>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    %esi,%ebx
  lea    0x1(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L15
  movslq %r12d,%rdx
  mov    %r8,%rcx
  movslq %ebx,%rbp
  mov    %ebx,%esi
  lea    0x1(%r13,%rdx,1),%rdi
  lea    -0x1(%rbx),%eax
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L89
  cmp    $0x6,%eax
  jbe    L89
  cmp    $0xe,%eax
  jbe    L67
  mov    %ebx,%ecx
  add    %r13,%rdx
  xor    %eax,%eax
  shr    $0x4,%ecx
  shl    $0x4,%rcx
  nop
L45:
  movdqu (%rdx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L45
  mov    %ebx,%ecx
  and    $0xfffffff0,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%ebx
  je     L43
  mov    %ebx,%esi
  sub    %ecx,%esi
  lea    -0x1(%rsi),%edi
  cmp    $0x6,%edi
  jbe    L11
L100:
  mov    (%rdx,%rcx,1),%rdx
  mov    %rdx,(%r8,%rcx,1)
  mov    %esi,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%esi
  je     L43
L11:
  lea    (%r12,%rax,1),%edx
  movslq %edx,%rdx
  movzbl 0x0(%r13,%rdx,1),%ecx
  movslq %eax,%rdx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jle    L43
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rcx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L43
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rcx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L43
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rcx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L43
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rcx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L43
  lea    (%r12,%rdx,1),%ecx
  add    $0x6,%eax
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rcx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%ebx
  jle    L43
  add    %eax,%r12d
  cltq
  movslq %r12d,%r12
  movzbl 0x0(%r13,%r12,1),%edx
  mov    %dl,(%r8,%rax,1)
L43:
  add    $0x1,%rbp
L95:
  movb   $0x0,(%r8,%rbp,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L89:
  mov    %ebx,%ebx
  xor    %eax,%eax
  add    %r13,%rdx
  nop
L61:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L61
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%ebp
  jmp    L95
L67:
  xor    %ecx,%ecx
  xor    %eax,%eax
  add    %r13,%rdx
  jmp    L100
```

assistant: ```c
char *make_substring(char *str, int b, int e) {
  char *new_string = malloc(sizeof(int) * (e - b) + 1);
  int i;
  for (i = 0; i < (e - b); i++) {
    new_string[i] = str[b + i];
  }
  new_string[i + 1] = '\0';
  return new_string;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ne0fucktheworld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x77e108,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <set@plt>
  mov    $0x0,%eax
  call   <load@plt>
  mov    $0x355f98,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <set@plt>
  mov    $0xffc61b58,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <save@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ne0fucktheworld() {
  add(0x77e108);
  set();
  load();
  add(-0x97950 + 0x3ed8e8);
  set();
  add(-0x3ed8e8 + 0x4f440);
  save();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ne0fucktheworld>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x77e108,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <set@plt>
  mov    $0x0,%eax
  call   <load@plt>
  mov    $0x355f98,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <set@plt>
  mov    $0xffc61b58,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <save@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ne0fucktheworld() {
  add(0x77e108);
  set();
  load();
  add(-0x97950 + 0x3ed8e8);
  set();
  add(-0x3ed8e8 + 0x4f440);
  save();
}
```
user: Translate the below assembly code into C programming language:

```asm
<ne0fucktheworld>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x77e108,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <set@plt>
  xor    %eax,%eax
  call   <load@plt>
  mov    $0x355f98,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <set@plt>
  mov    $0xffc61b58,%edi
  call   <add@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <save@plt>
```

assistant: ```c
void ne0fucktheworld() {
  add(0x77e108);
  set();
  load();
  add(-0x97950 + 0x3ed8e8);
  set();
  add(-0x3ed8e8 + 0x4f440);
  save();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ne0fucktheworld>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x77e108,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <set@plt>
  xor    %eax,%eax
  call   <load@plt>
  mov    $0x355f98,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <set@plt>
  mov    $0xffc61b58,%edi
  call   <add@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <save@plt>
```

assistant: ```c
void ne0fucktheworld() {
  add(0x77e108);
  set();
  load();
  add(-0x97950 + 0x3ed8e8);
  set();
  add(-0x3ed8e8 + 0x4f440);
  save();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memchr64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x20(%rbp),%rbx
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    $0x38,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x28(%rbp),%rax
  mov    %eax,%esi
  mov    $0x30,%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %eax,%esi
  mov    $0x28,%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    -0x28(%rbp),%rax
  mov    %eax,%edi
  mov    $0x20,%eax
  mov    %eax,%ecx
  shl    %cl,%edi
  mov    %edi,%eax
  lea    (%rsi,%rax,1),%ecx
  mov    -0x28(%rbp),%rax
  shl    $0x18,%eax
  mov    %eax,%esi
  mov    -0x28(%rbp),%rax
  shl    $0x10,%eax
  add    %eax,%esi
  mov    -0x28(%rbp),%rax
  shl    $0x8,%eax
  mov    %eax,%edi
  mov    -0x28(%rbp),%rax
  add    %edi,%eax
  add    %esi,%eax
  add    %ecx,%eax
  lea    (%rdx,%rax,1),%r13d
  jmp    L14
L57:
  mov    (%rbx),%eax
  xor    %r13d,%eax
  mov    %eax,%r12d
  movslq %r12d,%rax
  movabs $0xfefefefefefefeff,%rdx
  add    %rax,%rdx
  mov    %r12d,%eax
  not    %eax
  cltq
  and    %rax,%rdx
  movabs $0x8080808080808080,%rax
  and    %rdx,%rax
  test   %rax,%rax
  jne    L41
  subq   $0x4,-0x30(%rbp)
  add    $0x4,%rbx
L14:
  cmpq   $0x3,-0x30(%rbp)
  ja     L57
  jmp    L4
L41:
  nop
  jmp    L4
L72:
  mov    (%rbx),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L0
  mov    %rbx,%rax
  jmp    L23
L0:
  add    $0x8,%rbx
L4:
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  test   %rax,%rax
  jne    L72
  mov    $0x0,%eax
L23:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void *memchr64(const void *s, uint8_t c, size_t n) {
  register const uint64_t *ip = (const uint64_t *)s;
  register const uint8_t *p;
  register uint64_t mask;
  register uint64_t x;
  mask = ((((uint64_t)c) << 56) + (((uint64_t)c) << 48) + ((((uint64_t)c) << 40) + (((uint64_t)c) << 32) + ((((uint64_t)c) << 24) + (((uint64_t)c) << 16) + ((((uint64_t)c) << 8) + ((uint64_t)c)))));
  while (n >= sizeof(uint64_t)) {
    x = *ip ^ mask;
    if ((x - 0x0101010101010101ULL) & ~(x)&0x8080808080808080ULL)
      break;
    n -= sizeof(uint64_t);
    ip++;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (*p == c)
      return ((void *)p);
    p++;
  }
  return (NULL);
}
```
user: What is the c source code of the assembly code below:

```asm
<memchr64>:
  endbr64
  mov    %rdi,%rax
  imul   $0x1010101,%esi,%r8d
  cmp    $0x3,%rdx
  jbe    L3
  movabs $0xfefefefefefefeff,%r10
  movabs $0x8080808080808080,%r9
L25:
  mov    %r8d,%ecx
  xor    (%rax),%ecx
  movslq %ecx,%rdi
  add    %r10,%rdi
  not    %ecx
  movslq %ecx,%rcx
  and    %rdi,%rcx
  test   %r9,%rcx
  jne    L3
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    $0x3,%rdx
  ja     L25
L3:
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L34
L29:
  cmp    %rsi,(%rax)
  je     L2
  add    $0x8,%rax
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L29
  mov    $0x0,%eax
L2:
  ret
L34:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *memchr64(const void *s, uint8_t c, size_t n) {
  register const uint64_t *ip = (const uint64_t *)s;
  register const uint8_t *p;
  register uint64_t mask;
  register uint64_t x;
  mask = ((((uint64_t)c) << 56) + (((uint64_t)c) << 48) + ((((uint64_t)c) << 40) + (((uint64_t)c) << 32) + ((((uint64_t)c) << 24) + (((uint64_t)c) << 16) + ((((uint64_t)c) << 8) + ((uint64_t)c)))));
  while (n >= sizeof(uint64_t)) {
    x = *ip ^ mask;
    if ((x - 0x0101010101010101ULL) & ~(x)&0x8080808080808080ULL)
      break;
    n -= sizeof(uint64_t);
    ip++;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (*p == c)
      return ((void *)p);
    p++;
  }
  return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memchr64>:
  endbr64
  mov    %rdi,%rax
  imul   $0x1010101,%esi,%r8d
  mov    %rsi,%rdi
  cmp    $0x3,%rdx
  jbe    L73
  movabs $0xfefefefefefefeff,%r10
  movabs $0x8080808080808080,%r9
  jmp    L71
  nopl   (%rax)
L66:
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    $0x3,%rdx
  jbe    L73
L71:
  mov    (%rax),%ecx
  xor    %r8d,%ecx
  movslq %ecx,%rsi
  not    %ecx
  add    %r10,%rsi
  movslq %ecx,%rcx
  and    %rsi,%rcx
  test   %r9,%rcx
  je     L66
  lea    -0x1(%rdx),%rcx
  cmp    %rdi,(%rax)
  je     L67
  nop
L18:
  add    $0x8,%rax
  sub    $0x1,%rcx
  jb     L74
L37:
  cmp    %rdi,(%rax)
  jne    L18
L67:
  ret
L73:
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  jne    L37
L74:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr64(const void *s, uint8_t c, size_t n) {
  register const uint64_t *ip = (const uint64_t *)s;
  register const uint8_t *p;
  register uint64_t mask;
  register uint64_t x;
  mask = ((((uint64_t)c) << 56) + (((uint64_t)c) << 48) + ((((uint64_t)c) << 40) + (((uint64_t)c) << 32) + ((((uint64_t)c) << 24) + (((uint64_t)c) << 16) + ((((uint64_t)c) << 8) + ((uint64_t)c)))));
  while (n >= sizeof(uint64_t)) {
    x = *ip ^ mask;
    if ((x - 0x0101010101010101ULL) & ~(x)&0x8080808080808080ULL)
      break;
    n -= sizeof(uint64_t);
    ip++;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (*p == c)
      return ((void *)p);
    p++;
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memchr64>:
  endbr64
  mov    %rdi,%rax
  imul   $0x1010101,%esi,%r8d
  mov    %rsi,%rdi
  cmp    $0x3,%rdx
  jbe    L42
  movabs $0xfefefefefefefeff,%r10
  movabs $0x8080808080808080,%r9
  jmp    L78
  nopl   (%rax)
L74:
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    $0x3,%rdx
  jbe    L42
L78:
  mov    (%rax),%ecx
  xor    %r8d,%ecx
  movslq %ecx,%rsi
  not    %ecx
  add    %r10,%rsi
  movslq %ecx,%rcx
  and    %rsi,%rcx
  test   %r9,%rcx
  je     L74
  lea    -0x1(%rdx),%rcx
  cmp    %rdi,(%rax)
  je     L8
  nop
L51:
  add    $0x8,%rax
  sub    $0x1,%rcx
  jb     L43
L69:
  cmp    %rdi,(%rax)
  jne    L51
L8:
  ret
L42:
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  jne    L69
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr64(const void *s, uint8_t c, size_t n) {
  register const uint64_t *ip = (const uint64_t *)s;
  register const uint8_t *p;
  register uint64_t mask;
  register uint64_t x;
  mask = ((((uint64_t)c) << 56) + (((uint64_t)c) << 48) + ((((uint64_t)c) << 40) + (((uint64_t)c) << 32) + ((((uint64_t)c) << 24) + (((uint64_t)c) << 16) + ((((uint64_t)c) << 8) + ((uint64_t)c)))));
  while (n >= sizeof(uint64_t)) {
    x = *ip ^ mask;
    if ((x - 0x0101010101010101ULL) & ~(x)&0x8080808080808080ULL)
      break;
    n -= sizeof(uint64_t);
    ip++;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (*p == c)
      return ((void *)p);
    p++;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibo@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D0: Unesite n: 

tool: D3: %d

tool: D7: %d-ti element Finacijevog niza je: %d

assistant: ```c
int main() {
  int n;
  printf("Unesite n: ");
  scanf("%d", &n);
  printf("%d-ti element Finacijevog niza je: %d", n, fibo(n - 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edi
  call   <fibo@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type_guessed: string
name: retrieve_data
arguments: data_label: D24
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D27: Unesite n: 

tool: D24: %d

tool: D15: %d-ti element Finacijevog niza je: %d

assistant: ```c
int main() {
  int n;
  printf("Unesite n: ");
  scanf("%d", &n);
  printf("%d-ti element Finacijevog niza je: %d", n, fibo(n - 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edi
  call   <fibo@plt>
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string
name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D9: Unesite n: 

tool: D12: %d

tool: D0: %d-ti element Finacijevog niza je: %d

assistant: ```c
int main() {
  int n;
  printf("Unesite n: ");
  scanf("%d", &n);
  printf("%d-ti element Finacijevog niza je: %d", n, fibo(n - 1));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edi
  call   <fibo@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
datatype: string
name: extract_symbolic_data
arguments: tag: D24
datatype: string
name: extract_symbolic_data
arguments: tag: D27
datatype: string

tool: D18: Unesite n: 

tool: D24: %d

tool: D27: %d-ti element Finacijevog niza je: %d

assistant: ```c
int main() {
  int n;
  printf("Unesite n: ");
  scanf("%d", &n);
  printf("%d-ti element Finacijevog niza je: %d", n, fibo(n - 1));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ui_to_a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ui_to_a(unsigned int i) {
  static char buf[20 + 1];
  char *p = buf + 20;
  do {
    *--p = '0' + (i % 10);
    i /= 10;
  } while (i != 0);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ui_to_a>:
  endbr64
  lea    D3(%rip),%rsi
  mov    $0xcccccccd,%r8d
L7:
  sub    $0x1,%rsi
  mov    %edi,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%edx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%rsi)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  ja     L7
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *ui_to_a(unsigned int i) {
  static char buf[20 + 1];
  char *p = buf + 20;
  do {
    *--p = '0' + (i % 10);
    i /= 10;
  } while (i != 0);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<ui_to_a>:
  endbr64
  lea    D3(%rip),%r8
  mov    $0xcccccccd,%esi
L2:
  mov    %edi,%eax
  mov    %edi,%edx
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  ja     L2
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ui_to_a(unsigned int i) {
  static char buf[20 + 1];
  char *p = buf + 20;
  do {
    *--p = '0' + (i % 10);
    i /= 10;
  } while (i != 0);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ui_to_a>:
  endbr64
  lea    D2(%rip),%r8
  mov    $0xcccccccd,%esi
L6:
  mov    %edi,%eax
  mov    %edi,%edx
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  ja     L6
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ui_to_a(unsigned int i) {
  static char buf[20 + 1];
  char *p = buf + 20;
  do {
    *--p = '0' + (i % 10);
    i /= 10;
  } while (i != 0);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_187_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_187_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_187_1_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_187_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_187_1_0>:
  endbr64
  mov    %esi,%eax
  and    (%rdi),%sil
  not    %eax
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_187_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_187_1_0>:
  endbr64
  mov    %esi,%eax
  and    (%rdi),%sil
  not    %eax
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_187_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m68k_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D9(%rip),%eax
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  call   <m68ki_build_opcode_table@plt>
  movl   $0x1,D9(%rip)
L8:
  mov    $0x0,%edi
  call   <m68k_set_int_ack_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_bkpt_ack_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_reset_instr_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_cmpild_instr_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_rte_instr_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_tas_instr_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_pc_changed_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_fc_callback@plt>
  mov    $0x0,%edi
  call   <m68k_set_instr_hook_callback@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void m68k_init(void) {
  static unsigned int emulation_initialized = 0;
  if (!emulation_initialized) {
    m68ki_build_opcode_table();
    emulation_initialized = 1;
  }
  m68k_set_int_ack_callback(((void *)0));
  m68k_set_bkpt_ack_callback(((void *)0));
  m68k_set_reset_instr_callback(((void *)0));
  m68k_set_cmpild_instr_callback(((void *)0));
  m68k_set_rte_instr_callback(((void *)0));
  m68k_set_tas_instr_callback(((void *)0));
  m68k_set_pc_changed_callback(((void *)0));
  m68k_set_fc_callback(((void *)0));
  m68k_set_instr_hook_callback(((void *)0));
}
```