ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swapBigCol>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jg     L6
  cmp    $0x2,%esi
  jg     L6
  lea    (%rsi,%rsi,2),%ebp
  lea    (%rdi,%rdi,2),%ebx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <swapLittleCol@plt>
  lea    0x1(%rbp),%esi
  lea    0x1(%rbx),%edi
  call   <swapLittleCol@plt>
  lea    0x2(%rbp),%esi
  lea    0x2(%rbx),%edi
  call   <swapLittleCol@plt>
  jmp    L24
L6:
  lea    D1(%rip),%rdi
  call   <printf@plt>
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: BIG ERROR

assistant: ```c
void swapBigCol(int bcol1, int bcol2) {
  if (bcol1 > 2 || bcol2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleCol(bcol1 * 3, bcol2 * 3);
    swapLittleCol(bcol1 * 3 + 1, bcol2 * 3 + 1);
    swapLittleCol(bcol1 * 3 + 2, bcol2 * 3 + 2);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swapBigCol>:
  endbr64
  cmp    $0x2,%edi
  jg     L15
  cmp    $0x2,%esi
  jg     L15
  push   %rbp
  lea    (%rsi,%rsi,2),%ebp
  push   %rbx
  lea    (%rdi,%rdi,2),%ebx
  mov    %ebp,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <swapLittleCol@plt>
  lea    0x1(%rbp),%esi
  lea    0x1(%rbx),%edi
  call   <swapLittleCol@plt>
  add    $0x8,%rsp
  lea    0x2(%rbp),%esi
  lea    0x2(%rbx),%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <swapLittleCol@plt>
  nop
L15:
  lea    D4(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: BIG ERROR

assistant: ```c
void swapBigCol(int bcol1, int bcol2) {
  if (bcol1 > 2 || bcol2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleCol(bcol1 * 3, bcol2 * 3);
    swapLittleCol(bcol1 * 3 + 1, bcol2 * 3 + 1);
    swapLittleCol(bcol1 * 3 + 2, bcol2 * 3 + 2);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swapBigCol>:
  endbr64
  cmp    $0x2,%edi
  jg     L8
  cmp    $0x2,%esi
  jg     L8
  push   %rbp
  lea    (%rsi,%rsi,2),%ebp
  push   %rbx
  lea    (%rdi,%rdi,2),%ebx
  mov    %ebp,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <swapLittleCol@plt>
  lea    0x1(%rbp),%esi
  lea    0x1(%rbx),%edi
  call   <swapLittleCol@plt>
  add    $0x8,%rsp
  lea    0x2(%rbp),%esi
  lea    0x2(%rbx),%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <swapLittleCol@plt>
  nop
L8:
  lea    D2(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: BIG ERROR

assistant: ```c
void swapBigCol(int bcol1, int bcol2) {
  if (bcol1 > 2 || bcol2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleCol(bcol1 * 3, bcol2 * 3);
    swapLittleCol(bcol1 * 3 + 1, bcol2 * 3 + 1);
    swapLittleCol(bcol1 * 3 + 2, bcol2 * 3 + 2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<WpeSignalChild>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void WpeSignalChild(int sig) {
  int statloc;
  wait(&statloc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WpeSignalChild>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void WpeSignalChild(int sig) {
  int statloc;
  wait(&statloc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WpeSignalChild>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void WpeSignalChild(int sig) {
  int statloc;
  wait(&statloc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WpeSignalChild>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void WpeSignalChild(int sig) {
  int statloc;
  wait(&statloc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
L24:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L18:
  cmpl   $0x0,-0xc(%rbp)
  jne    L24
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L8
  mov    $0x1,%eax
  jmp    L28
L8:
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int isPalindrome(int x) {
  int rem, temp, ans;
  ans = 0;
  temp = x;
  while (temp != 0) {
    rem = temp % 10;
    temp = temp / 10;
    ans = ans * 10 + rem;
  }
  if (ans == x)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L21
  mov    %edi,%edx
  mov    $0x0,%esi
L6:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%r8d
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %r8d,%edx
  lea    (%rsi,%rsi,4),%ecx
  lea    (%rax,%rcx,2),%esi
  test   %r8d,%r8d
  jne    L6
L17:
  cmp    %esi,%edi
  sete   %al
  movzbl %al,%eax
  ret
L21:
  mov    %edi,%esi
  jmp    L17
```

assistant: ```c
int isPalindrome(int x) {
  int rem, temp, ans;
  ans = 0;
  temp = x;
  while (temp != 0) {
    rem = temp % 10;
    temp = temp / 10;
    ans = ans * 10 + rem;
  }
  if (ans == x)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L13
  mov    %edi,%edx
  xor    %r8d,%r8d
  nopl   (%rax)
L8:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  lea    (%r8,%r8,4),%ecx
  sub    %esi,%eax
  lea    (%rax,%rcx,2),%r8d
  test   %edx,%edx
  jne    L8
  xor    %eax,%eax
  cmp    %r8d,%edi
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  xor    %eax,%eax
  cmp    %r8d,%edi
  sete   %al
  ret
```

assistant: ```c
int isPalindrome(int x) {
  int rem, temp, ans;
  ans = 0;
  temp = x;
  while (temp != 0) {
    rem = temp % 10;
    temp = temp / 10;
    ans = ans * 10 + rem;
  }
  if (ans == x)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L0
  mov    %edi,%edx
  xor    %r8d,%r8d
  nopl   (%rax)
L5:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  lea    (%r8,%r8,4),%ecx
  sub    %esi,%eax
  lea    (%rax,%rcx,2),%r8d
  test   %edx,%edx
  jne    L5
  xor    %eax,%eax
  cmp    %r8d,%edi
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  xor    %eax,%eax
  cmp    %r8d,%edi
  sete   %al
  ret
```

assistant: ```c
int isPalindrome(int x) {
  int rem, temp, ans;
  ans = 0;
  temp = x;
  while (temp != 0) {
    rem = temp % 10;
    temp = temp / 10;
    ans = ans * 10 + rem;
  }
  if (ans == x)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<darwin_dynamic_link_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L25
  mov    -0x28(%rbp),%rax
  lea    -0x28(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <safe_strtol@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L25
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L34
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
L34:
  mov    -0x28(%rbp),%rax
  lea    -0x28(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <safe_strtol@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L25
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L42
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
L42:
  mov    -0x28(%rbp),%rax
  lea    -0x28(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <safe_strtol@plt>
  mov    %rax,-0x10(%rbp)
L25:
  cmpq   $0x0,-0x20(%rbp)
  jne    L21
  movq   $0x1,-0x20(%rbp)
L21:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: -compatibility_version %ld -current_version %ld.%ld

assistant: ```c
const char *darwin_dynamic_link_function(const char *version_info) {
  char *newarg;
  long major, minor, patch;
  major = 0;
  minor = 0;
  patch = 0;
  if (version_info) {
    major = safe_strtol(version_info, &version_info, 10);
    if (version_info) {
      if (version_info[0] == ':') {
        version_info++;
      }
      minor = safe_strtol(version_info, &version_info, 10);
      if (version_info) {
        if (version_info[0] == ':') {
          version_info++;
        }
        patch = safe_strtol(version_info, &version_info, 10);
      }
    }
  }
  if (major == 0) {
    major = 1;
  }
  newarg = (char *)malloc(100);
  snprintf(newarg, 99, "-compatibility_version %ld -current_version %ld.%ld", major, major, minor);
  return newarg;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<darwin_dynamic_link_function>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  je     L53
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  call   <safe_strtol@plt>
  mov    %rax,%rbx
  mov    0x8(%rsp),%rax
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L64
  cmpb   $0x3a,(%rax)
  je     L54
L78:
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  mov    0x8(%rsp),%rdi
  call   <safe_strtol@plt>
  mov    %rax,%r12
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L64
  cmpb   $0x3a,(%rax)
  je     L3
L79:
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  mov    0x8(%rsp),%rdi
  call   <safe_strtol@plt>
L64:
  test   %rbx,%rbx
  mov    $0x1,%eax
  cmove  %rax,%rbx
L5:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%r9
  mov    %rbx,%r8
  mov    %rbx,%rcx
  lea    D8(%rip),%rdx
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  jmp    L78
L3:
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  jmp    L79
L53:
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  jmp    L5
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8: -compatibility_version %ld -current_version %ld.%ld

assistant: ```c
const char *darwin_dynamic_link_function(const char *version_info) {
  char *newarg;
  long major, minor, patch;
  major = 0;
  minor = 0;
  patch = 0;
  if (version_info) {
    major = safe_strtol(version_info, &version_info, 10);
    if (version_info) {
      if (version_info[0] == ':') {
        version_info++;
      }
      minor = safe_strtol(version_info, &version_info, 10);
      if (version_info) {
        if (version_info[0] == ':') {
          version_info++;
        }
        patch = safe_strtol(version_info, &version_info, 10);
      }
    }
  }
  if (major == 0) {
    major = 1;
  }
  newarg = (char *)malloc(100);
  snprintf(newarg, 99, "-compatibility_version %ld -current_version %ld.%ld", major, major, minor);
  return newarg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<darwin_dynamic_link_function>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  je     L52
  lea    0x8(%rsp),%r13
  mov    $0xa,%edx
  xor    %ebx,%ebx
  mov    %r13,%rsi
  call   <safe_strtol@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%r12
  test   %rdi,%rdi
  je     L46
  cmpb   $0x3a,(%rdi)
  jne    L6
  add    $0x1,%rdi
  mov    %rdi,0x8(%rsp)
L6:
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <safe_strtol@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%rbx
  test   %rdi,%rdi
  je     L46
  cmpb   $0x3a,(%rdi)
  je     L7
L34:
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <safe_strtol@plt>
L46:
  test   %r12,%r12
  mov    $0x1,%eax
  cmove  %rax,%r12
L50:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rbx,%r9
  mov    %r12,%r8
  mov    %r12,%rcx
  lea    D6(%rip),%rdx
  mov    $0x63,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <snprintf@plt>
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L52:
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdi
  mov    %rdi,0x8(%rsp)
  jmp    L34
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: -compatibility_version %ld -current_version %ld.%ld

assistant: ```c
const char *darwin_dynamic_link_function(const char *version_info) {
  char *newarg;
  long major, minor, patch;
  major = 0;
  minor = 0;
  patch = 0;
  if (version_info) {
    major = safe_strtol(version_info, &version_info, 10);
    if (version_info) {
      if (version_info[0] == ':') {
        version_info++;
      }
      minor = safe_strtol(version_info, &version_info, 10);
      if (version_info) {
        if (version_info[0] == ':') {
          version_info++;
        }
        patch = safe_strtol(version_info, &version_info, 10);
      }
    }
  }
  if (major == 0) {
    major = 1;
  }
  newarg = (char *)malloc(100);
  snprintf(newarg, 99, "-compatibility_version %ld -current_version %ld.%ld", major, major, minor);
  return newarg;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<darwin_dynamic_link_function>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  je     L61
  lea    0x8(%rsp),%r13
  mov    $0xa,%edx
  xor    %ebx,%ebx
  mov    %r13,%rsi
  call   <safe_strtol@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%r12
  test   %rdi,%rdi
  je     L53
  cmpb   $0x3a,(%rdi)
  jne    L49
  add    $0x1,%rdi
  mov    %rdi,0x8(%rsp)
L49:
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <safe_strtol@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%rbx
  test   %rdi,%rdi
  je     L53
  cmpb   $0x3a,(%rdi)
  je     L2
L36:
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <safe_strtol@plt>
L53:
  test   %r12,%r12
  mov    $0x1,%eax
  cmove  %rax,%r12
L52:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rbx,%r9
  mov    %r12,%r8
  mov    %r12,%rcx
  lea    D1(%rip),%rdx
  mov    $0x63,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <snprintf@plt>
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L61:
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rdi
  mov    %rdi,0x8(%rsp)
  jmp    L36
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: -compatibility_version %ld -current_version %ld.%ld

assistant: ```c
const char *darwin_dynamic_link_function(const char *version_info) {
  char *newarg;
  long major, minor, patch;
  major = 0;
  minor = 0;
  patch = 0;
  if (version_info) {
    major = safe_strtol(version_info, &version_info, 10);
    if (version_info) {
      if (version_info[0] == ':') {
        version_info++;
      }
      minor = safe_strtol(version_info, &version_info, 10);
      if (version_info) {
        if (version_info[0] == ':') {
          version_info++;
        }
        patch = safe_strtol(version_info, &version_info, 10);
      }
    }
  }
  if (major == 0) {
    major = 1;
  }
  newarg = (char *)malloc(100);
  snprintf(newarg, 99, "-compatibility_version %ld -current_version %ld.%ld", major, major, minor);
  return newarg;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L29
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shr    %eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L21
L29:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shr    $0x4,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    if ((state[0UL] >> 1U) & 1U) {
      state[0UL] >>= ((state[0UL] >> 1U) & 7U) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x9,%eax
  and    $0xcd2d400,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    if ((state[0UL] >> 1U) & 1U) {
      state[0UL] >>= ((state[0UL] >> 1U) & 7U) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x9,%eax
  and    $0xcd2d400,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    if ((state[0UL] >> 1U) & 1U) {
      state[0UL] >>= ((state[0UL] >> 1U) & 7U) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stress_badhandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x1,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((__section__("mlocked_text"))) stress_badhandler(int signum) {
  (void)signum;
  _exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stress_badhandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((__section__("mlocked_text"))) stress_badhandler(int signum) {
  (void)signum;
  _exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stress_badhandler>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <_exit@plt>
```

assistant: ```c
void __attribute__((__section__("mlocked_text"))) stress_badhandler(int signum) {
  (void)signum;
  _exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stress_badhandler>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <_exit@plt>
```

assistant: ```c
void __attribute__((__section__("mlocked_text"))) stress_badhandler(int signum) {
  (void)signum;
  _exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<I2C_Read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%ecx
  mov    %rsi,-0x10(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  mov    $0x0,%eax
  call   <i2cstart@plt>
  movzbl -0x4(%rbp),%eax
  or     $0x1,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <i2csendbyte@plt>
  mov    $0x0,%eax
  call   <i2cgetack@plt>
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  call   <i2cstop@plt>
  mov    $0x0,%eax
  jmp    L7
L38:
  mov    $0x0,%eax
  call   <i2cgetbyte@plt>
  mov    -0x10(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  cmpb   $0x0,-0x8(%rbp)
  jle    L4
  mov    $0x0,%eax
  call   <i2csendack@plt>
L4:
  movzbl -0x8(%rbp),%eax
  mov    %eax,%edx
  sub    $0x1,%edx
  mov    %dl,-0x8(%rbp)
  test   %al,%al
  jne    L38
  mov    $0x0,%eax
  call   <i2cstop@plt>
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
char I2C_Read(char Address, char *Data, char Num) {
  i2cstart();
  i2csendbyte(Address | 0x01);
  if (!i2cgetack()) {
    i2cstop();
    return (0);
  }
  while (Num--) {
    *Data = i2cgetbyte();
    Data++;
    if (Num > 0) {
      i2csendack();
    }
  }
  i2cstop();
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<I2C_Read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    $0x0,%eax
  call   <i2cstart@plt>
  or     $0x1,%r12d
  movsbl %r12b,%edi
  call   <i2csendbyte@plt>
  mov    $0x0,%eax
  call   <i2cgetack@plt>
  test   %eax,%eax
  je     L47
  test   %bl,%bl
  je     L0
  sub    $0x2,%ebx
  jmp    L12
L47:
  mov    $0x0,%eax
  call   <i2cstop@plt>
  mov    $0x0,%eax
  jmp    L9
L15:
  mov    $0x0,%eax
  call   <i2csendack@plt>
L45:
  sub    $0x1,%ebx
L12:
  mov    $0x0,%eax
  call   <i2cgetbyte@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  lea    0x1(%rbx),%eax
  test   %al,%al
  jg     L15
  jne    L45
L0:
  mov    $0x0,%eax
  call   <i2cstop@plt>
  mov    $0x1,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char I2C_Read(char Address, char *Data, char Num) {
  i2cstart();
  i2csendbyte(Address | 0x01);
  if (!i2cgetack()) {
    i2cstop();
    return (0);
  }
  while (Num--) {
    *Data = i2cgetbyte();
    Data++;
    if (Num > 0) {
      i2csendack();
    }
  }
  i2cstop();
  return (1);
}
```