ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<io_getdata>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rsi,(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %r15d,%r15d
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  mov    %r15d,%ebx
  call   <getchar@plt>
  mov    %al,0x0(%rbp,%r15,1)
  add    $0x1,%r15
  cmp    $0xa,%al
  jne    L11
  movslq %ebx,%rax
  movb   $0x0,0x10(%rsp,%rax,1)
  test   %ebx,%ebx
  je     L9
  cmpl   $0x2e2e2e,0x0(%rbp)
  je     L17
  test   %r14d,%r14d
  je     L45
  jle    L9
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jne    L9
L45:
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  nopl   0x0(%rax)
L17:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %s

assistant: ```c
void io_getdata(const char *tip, const char *fmt, int slen, void *p) {
  int rc;
  int i;
  char input[1024];
  while (1) {
    printf("%s", tip);
    for (i = 0; (input[i] = getchar()) != '\n'; i++)
      ;
    input[i] = 0;
    if (i > 0) {
      if (!strcmp(input, "...")) {
        break;
      } else if (slen == 0 || (slen > 0 && strlen(input) == slen)) {
        sscanf(input, fmt, p);
        break;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<io_getdata>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rsi,(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %r15d,%r15d
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  mov    %r15d,%ebx
  call   <getchar@plt>
  mov    %al,0x0(%rbp,%r15,1)
  add    $0x1,%r15
  cmp    $0xa,%al
  jne    L46
  movslq %ebx,%rax
  movb   $0x0,0x10(%rsp,%rax,1)
  test   %ebx,%ebx
  je     L28
  cmpl   $0x2e2e2e,0x0(%rbp)
  je     L48
  test   %r14d,%r14d
  je     L69
  jle    L28
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jne    L28
L69:
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  nopl   0x0(%rax)
L48:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s

assistant: ```c
void io_getdata(const char *tip, const char *fmt, int slen, void *p) {
  int rc;
  int i;
  char input[1024];
  while (1) {
    printf("%s", tip);
    for (i = 0; (input[i] = getchar()) != '\n'; i++)
      ;
    input[i] = 0;
    if (i > 0) {
      if (!strcmp(input, "...")) {
        break;
      } else if (slen == 0 || (slen > 0 && strlen(input) == slen)) {
        sscanf(input, fmt, p);
        break;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movsbl -0x1c(%rbp),%eax
  cmp    $0x2f,%eax
  jg     L44
  cmp    $0x25,%eax
  jl     L10
  sub    $0x25,%eax
  cmp    $0xa,%eax
  ja     L10
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L44:
  cmp    $0x5e,%eax
  je     L6
  jmp    L10
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L105
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L105
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L105
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  jmp    L105
L6:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L105
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  jmp    L105
L10:
  nop
L105:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int calculate(int op1, int op2, char operator) {
  int result = 0;
  switch (operator) {
  case '+':
    result = op1 + op2;
    break;
  case '-':
    result = op1 - op2;
    break;
  case '*':
    result = op1 * op2;
    break;
  case '/':
    result = op1 / op2;
    break;
  case '^':
    result = pow(op1, op2);
    break;
  case '%':
    result = op1 % op2;
    break;
  default:
    break;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calculate>:
  endbr64
  cmp    $0x2f,%dl
  jg     L6
  mov    $0x0,%ecx
  cmp    $0x24,%dl
  jle    L71
  sub    $0x25,%edx
  cmp    $0xa,%dl
  ja     L67
  movzbl %dl,%edx
  lea    D4(%rip),%rcx
  movslq (%rcx,%rdx,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
L6:
  mov    $0x0,%ecx
  cmp    $0x5e,%dl
  jne    L71
  sub    $0x8,%rsp
  call   <pow@plt>
  add    $0x8,%rsp
  ret
  lea    (%rdi,%rsi,1),%ecx
  jmp    L71
  sub    %esi,%edi
  mov    %edi,%ecx
  jmp    L71
  imul   %esi,%edi
  mov    %edi,%ecx
  jmp    L71
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  jmp    L71
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%ecx
  jmp    L71
L67:
  mov    $0x0,%ecx
L71:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int calculate(int op1, int op2, char operator) {
  int result = 0;
  switch (operator) {
  case '+':
    result = op1 + op2;
    break;
  case '-':
    result = op1 - op2;
    break;
  case '*':
    result = op1 * op2;
    break;
  case '/':
    result = op1 / op2;
    break;
  case '^':
    result = pow(op1, op2);
    break;
  case '%':
    result = op1 % op2;
    break;
  default:
    break;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculate>:
  endbr64
  cmp    $0x2f,%dl
  jg     L10
  xor    %r8d,%r8d
  cmp    $0x24,%dl
  jle    L5
  sub    $0x25,%edx
  cmp    $0xa,%dl
  ja     L13
  lea    D1(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L13:
  xor    %r8d,%r8d
L5:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    $0x5e,%dl
  jne    L13
  jmp    1050 <pow@plt>
  nopw   0x0(%rax,%rax,1)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
  imul   %esi,%edi
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  lea    (%rdi,%rsi,1),%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  sub    %esi,%edi
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calculate(int op1, int op2, char operator) {
  int result = 0;
  switch (operator) {
  case '+':
    result = op1 + op2;
    break;
  case '-':
    result = op1 - op2;
    break;
  case '*':
    result = op1 * op2;
    break;
  case '/':
    result = op1 / op2;
    break;
  case '^':
    result = pow(op1, op2);
    break;
  case '%':
    result = op1 % op2;
    break;
  default:
    break;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<calculate>:
  endbr64
  cmp    $0x2f,%dl
  jg     L31
  xor    %r8d,%r8d
  cmp    $0x24,%dl
  jle    L6
  sub    $0x25,%edx
  cmp    $0xa,%dl
  ja     L25
  lea    D6(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L25:
  xor    %r8d,%r8d
L6:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  cmp    $0x5e,%dl
  jne    L25
  jmp    1050 <pow@plt>
  nopw   0x0(%rax,%rax,1)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
  imul   %esi,%edi
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  lea    (%rdi,%rsi,1),%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  sub    %esi,%edi
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calculate(int op1, int op2, char operator) {
  int result = 0;
  switch (operator) {
  case '+':
    result = op1 + op2;
    break;
  case '-':
    result = op1 - op2;
    break;
  case '*':
    result = op1 * op2;
    break;
  case '/':
    result = op1 / op2;
    break;
  case '^':
    result = pow(op1, op2);
    break;
  case '%':
    result = op1 % op2;
    break;
  default:
    break;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ADS1299ReadAllReg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movb   $0x0,-0x11(%rbp)
  jmp    L2
L16:
  movzbl -0x11(%rbp),%eax
  movzbl -0x11(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <ADS1299ReadReg@plt>
  mov    %al,(%rbx)
  movzbl -0x11(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x11(%rbp)
L2:
  cmpb   $0x18,-0x11(%rbp)
  jbe    L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void ADS1299ReadAllReg(unsigned char *registers) {
  unsigned char iReg;
  for (iReg = 0; iReg < 25; iReg++) {
    registers[iReg] = ADS1299ReadReg(iReg);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ADS1299ReadAllReg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L1:
  mov    %ebx,%edi
  call   <ADS1299ReadReg@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x19,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADS1299ReadAllReg(unsigned char *registers) {
  unsigned char iReg;
  for (iReg = 0; iReg < 25; iReg++) {
    registers[iReg] = ADS1299ReadReg(iReg);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ADS1299ReadAllReg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L9:
  mov    %ebx,%edi
  call   <ADS1299ReadReg@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x19,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADS1299ReadAllReg(unsigned char *registers) {
  unsigned char iReg;
  for (iReg = 0; iReg < 25; iReg++) {
    registers[iReg] = ADS1299ReadReg(iReg);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ADS1299ReadAllReg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L5:
  mov    %ebx,%edi
  call   <ADS1299ReadReg@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x19,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADS1299ReadAllReg(unsigned char *registers) {
  unsigned char iReg;
  for (iReg = 0; iReg < 25; iReg++) {
    registers[iReg] = ADS1299ReadReg(iReg);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ifj16_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  mov    $0xffffffff,%eax
  jmp    L5
L16:
  cmpl   $0x0,-0x4(%rbp)
  jle    L31
  mov    $0x1,%eax
  jmp    L5
L31:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int ifj16_compare(char *s1, char *s2) {
  int ret = strcmp(s1, s2);
  if (ret < 0) {
    return -1;
  } else if (ret > 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ifj16_compare>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  js     L0
  setg   %dl
  movzbl %dl,%edx
L0:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ifj16_compare(char *s1, char *s2) {
  int ret = strcmp(s1, s2);
  if (ret < 0) {
    return -1;
  } else if (ret > 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ifj16_compare>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0xffffffff,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ifj16_compare(char *s1, char *s2) {
  int ret = strcmp(s1, s2);
  if (ret < 0) {
    return -1;
  } else if (ret > 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ifj16_compare>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0xffffffff,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ifj16_compare(char *s1, char *s2) {
  int ret = strcmp(s1, s2);
  if (ret < 0) {
    return -1;
  } else if (ret > 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L40:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L47:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L5
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L5:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L40
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _sort(int *array, int size) {
  for (int i = 0; i < size - 1; i++) {
    int k = i;
    for (int j = i + 1; j < size; j++) {
      if (array[k] < array[j])
        k = j;
    }
    int t = array[i];
    array[i] = array[k];
    array[k] = t;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L21
  lea    -0x2(%rsi),%r9d
  add    $0x2,%r9
  mov    $0x1,%r8d
L32:
  lea    -0x1(%r8),%edx
  cmp    %r8d,%esi
  jle    L25
  mov    %r8,%rax
L35:
  movslq %edx,%rcx
  mov    (%rdi,%rax,4),%r10d
  cmp    %r10d,(%rdi,%rcx,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L35
L25:
  mov    -0x4(%rdi,%r8,4),%ecx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%rdi,%r8,4)
  mov    %ecx,(%rax)
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L32
L21:
  ret
```

assistant: ```c
void _sort(int *array, int size) {
  for (int i = 0; i < size - 1; i++) {
    int k = i;
    for (int j = i + 1; j < size; j++) {
      if (array[k] < array[j])
        k = j;
    }
    int t = array[i];
    array[i] = array[k];
    array[k] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sort>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %r13d,%r13d
  jle    L12
  mov    %rdi,%r11
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L80:
  mov    %r10d,%r9d
  add    $0x1,%r10d
  mov    (%rbx),%ebp
  cmp    %r10d,%esi
  jle    L44
  lea    0x4(%rbx),%r12
  mov    %ebp,%edi
  mov    %r10d,%edx
  mov    %r12,%rax
  jmp    L1
  nopl   0x0(%rax)
L65:
  movslq %r9d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%r11,%rcx,4),%r8
  cmp    %edx,%esi
  je     L2
L1:
  mov    (%rax),%ecx
  mov    %rax,%r8
  cmp    %edi,%ecx
  jle    L65
  mov    %edx,%r9d
  add    $0x1,%edx
  mov    %ecx,%edi
  add    $0x4,%rax
  cmp    %edx,%esi
  jne    L1
L2:
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  mov    %ebp,(%r8)
  cmp    %r13d,%r10d
  jne    L80
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L44:
  mov    %rbx,%r8
  mov    %ebp,%edi
  lea    0x4(%rbx),%r12
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  mov    %ebp,(%r8)
  cmp    %r13d,%r10d
  jne    L80
  jmp    L12
```

assistant: ```c
void _sort(int *array, int size) {
  for (int i = 0; i < size - 1; i++) {
    int k = i;
    for (int j = i + 1; j < size; j++) {
      if (array[k] < array[j])
        k = j;
    }
    int t = array[i];
    array[i] = array[k];
    array[k] = t;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<_sort>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %r13d,%r13d
  jle    L17
  mov    %rdi,%r11
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L45:
  mov    %r10d,%r9d
  add    $0x1,%r10d
  mov    (%rbx),%ebp
  cmp    %r10d,%esi
  jle    L52
  lea    0x4(%rbx),%r12
  mov    %ebp,%edi
  mov    %r10d,%edx
  mov    %r12,%rax
  jmp    L27
  nopl   0x0(%rax)
L88:
  movslq %r9d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%r11,%rcx,4),%r8
  cmp    %esi,%edx
  je     L59
L27:
  mov    (%rax),%ecx
  mov    %rax,%r8
  cmp    %edi,%ecx
  jle    L88
  mov    %edx,%r9d
  add    $0x1,%edx
  mov    %ecx,%edi
  add    $0x4,%rax
  cmp    %esi,%edx
  jne    L27
L59:
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  mov    %ebp,(%r8)
  cmp    %r13d,%r10d
  jne    L45
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L52:
  mov    %rbx,%r8
  mov    %ebp,%edi
  lea    0x4(%rbx),%r12
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  mov    %ebp,(%r8)
  cmp    %r13d,%r10d
  jne    L45
  jmp    L17
```

assistant: ```c
void _sort(int *array, int size) {
  for (int i = 0; i < size - 1; i++) {
    int k = i;
    for (int j = i + 1; j < size; j++) {
      if (array[k] < array[j])
        k = j;
    }
    int t = array[i];
    array[i] = array[k];
    array[k] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UI_ProportionalSizeScale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L16
  movss  D6(%rip),%xmm0
  jmp    L9
L16:
  movss  D8(%rip),%xmm0
L9:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: f32
name: parse_data
arguments: data_tag: D8
datatype: f32

tool: D6: 0.75

tool: D8: 1

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  return 1.00;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UI_ProportionalSizeScale>:
  endbr64
  movss  D10(%rip),%xmm0
  test   $0x10,%dil
  jne    L19
L0:
  ret
L19:
  movss  D16(%rip),%xmm0
  jmp    L0
```

tool_calls: name: parse_data
arguments: label: D10
type: f32
name: parse_data
arguments: label: D16
type: f32

tool: D10: 1

tool: D16: 0.75

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  return 1.00;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UI_ProportionalSizeScale>:
  endbr64
  and    $0x10,%edi
  movss  D4(%rip),%xmm0
  jne    L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  movss  D17(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: f32
name: unpack_data
arguments: label: D17
type: f32

tool: D4: 1

tool: D17: 0.75

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  return 1.00;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UI_ProportionalSizeScale>:
  endbr64
  and    $0x10,%edi
  movss  D18(%rip),%xmm0
  jne    L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movss  D17(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
datatype: f32
name: unpack_data
arguments: label: D17
datatype: f32

tool: D18: 1

tool: D17: 0.75

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  return 1.00;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <selectionSort@plt>
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <printIntVector@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  int vector[10] = {6, 5, 7, 4, 8, 3, 9, 2, 0, 1};
  selectionSort(vector, 10);
  printIntVector(vector, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x8,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x9,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <selectionSort@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printIntVector@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int vector[10] = {6, 5, 7, 4, 8, 3, 9, 2, 0, 1};
  selectionSort(vector, 10);
  printIntVector(vector, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x500000006,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000007,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x300000008,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000009,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0x20(%rsp)
  call   <selectionSort@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printIntVector@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int vector[10] = {6, 5, 7, 4, 8, 3, 9, 2, 0, 1};
  selectionSort(vector, 10);
  printIntVector(vector, 10);
}
```