ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_suspicious_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpq   $0x0,-0x10(%rbp)
  jne    L12
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L69
L12:
  mov    -0x10(%rbp),%rax
  cmp    $0xfffffffffffffc19,%rax
  jl     L64
  mov    -0x10(%rbp),%rax
  cmp    $0x3e7,%rax
  jg     L64
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L69
L64:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <is_printable_str@plt>
  test   %rax,%rax
  je     L49
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L69
L49:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L69:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D29
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D22: %s: 

tool: D1: (null)

tool: D29: %ld


tool: D10: [non-str]

assistant: ```c
void print_suspicious_str(char *name, char *str) {
  printf("%s: ", name);
  if (str == 0) {
    printf("(null)\n");
  } else if ((long int)str > -1000 && (long int)str < 1000) {
    printf("%ld\n", (long int)str);
  } else if (is_printable_str(str)) {
    printf("%s\n", str);
  } else {
    printf("[non-str]\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_suspicious_str>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %rbx,%rbx
  je     L20
  lea    0x3e7(%rbx),%rax
  cmp    $0x7ce,%rax
  ja     L15
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  pop    %rbx
  ret
L20:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  jmp    L36
L15:
  mov    %rbx,%rdi
  call   <is_printable_str@plt>
  test   %rax,%rax
  je     L57
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L36
L57:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  jmp    L36
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D12: %s: 

tool: D25: %ld


tool: D21: (null)

tool: D4: [non-str]

assistant: ```c
void print_suspicious_str(char *name, char *str) {
  printf("%s: ", name);
  if (str == 0) {
    printf("(null)\n");
  } else if ((long int)str > -1000 && (long int)str < 1000) {
    printf("%ld\n", (long int)str);
  } else if (is_printable_str(str)) {
    printf("%s\n", str);
  } else {
    printf("[non-str]\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_suspicious_str>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L25
  lea    0x3e7(%rbp),%rax
  cmp    $0x7ce,%rax
  jbe    L5
  mov    %rbp,%rdi
  call   <is_printable_str@plt>
  test   %rax,%rax
  je     L14
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  lea    D18(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
  nopl   (%rax)
L25:
  lea    D15(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D15
type_infered: string

tool: D5: %s: 

tool: D19: %ld


tool: D18: [non-str]

tool: D15: (null)

assistant: ```c
void print_suspicious_str(char *name, char *str) {
  printf("%s: ", name);
  if (str == 0) {
    printf("(null)\n");
  } else if ((long int)str > -1000 && (long int)str < 1000) {
    printf("%ld\n", (long int)str);
  } else if (is_printable_str(str)) {
    printf("%s\n", str);
  } else {
    printf("[non-str]\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_suspicious_str>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L24
  lea    0x3e7(%rbp),%rax
  cmp    $0x7ce,%rax
  jbe    L9
  mov    %rbp,%rdi
  call   <is_printable_str@plt>
  test   %rax,%rax
  je     L27
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  lea    D39(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
  nopl   (%rax)
L24:
  lea    D2(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D39
type: string
name: retrieve_data
arguments: data_tag: D2
type: string

tool: D20: %s: 

tool: D17: %ld


tool: D39: [non-str]

tool: D2: (null)

assistant: ```c
void print_suspicious_str(char *name, char *str) {
  printf("%s: ", name);
  if (str == 0) {
    printf("(null)\n");
  } else if ((long int)str > -1000 && (long int)str < 1000) {
    printf("%ld\n", (long int)str);
  } else if (is_printable_str(str)) {
    printf("%s\n", str);
  } else {
    printf("[non-str]\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<build_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jle    L1
  mov    -0x20(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L1
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D30(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L23
L1:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%ebx
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  lea    D26(%rip),%rcx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L23:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D30
data_type: string
name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D30: %s%s

tool: D26: /

tool: D2: %s%s%s

assistant: ```c
char *build_path(const char *dir, const char *component) {
  const int dir_len = strlen(dir);
  const int comp_len = strlen(component);
  char *buf;
  if (dir_len > 0 && dir[dir_len - 1] == '/') {
    buf = malloc(sizeof(char) * dir_len + comp_len + 1);
    sprintf(buf, "%s%s", dir, component);
  } else {
    buf = malloc(sizeof(char) * dir_len + comp_len + strlen("/") + comp_len + 1);
    sprintf(buf, "%s%s%s", dir, "/", component);
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<build_path>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  test   %ebp,%ebp
  jle    L7
  movslq %ebp,%rax
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  je     L19
L7:
  lea    D21(%rip),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%r14,2),%edi
  add    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    %rbx,%rdx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L8:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  lea    0x1(%rbp,%r14,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rcx
  mov    %rbx,%rdx
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L8
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string

tool: D21: /

tool: D13: %s%s%s

tool: D25: %s%s

assistant: ```c
char *build_path(const char *dir, const char *component) {
  const int dir_len = strlen(dir);
  const int comp_len = strlen(component);
  char *buf;
  if (dir_len > 0 && dir[dir_len - 1] == '/') {
    buf = malloc(sizeof(char) * dir_len + comp_len + 1);
    sprintf(buf, "%s%s", dir, component);
  } else {
    buf = malloc(sizeof(char) * dir_len + comp_len + strlen("/") + comp_len + 1);
    sprintf(buf, "%s%s%s", dir, "/", component);
  }
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<build_path>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r14d
  test   %ebx,%ebx
  jle    L2
  movslq %ebx,%rax
  cmpb   $0x2f,-0x1(%r12,%rax,1)
  je     L3
L2:
  lea    D27(%rip),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%r14,2),%edi
  add    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%r8
  mov    %r15,%rcx
  mov    %r12,%rdx
  mov    %rax,%r14
  mov    %rax,%rdi
  lea    D5(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  lea    0x1(%rbx,%r14,1),%edi
  call   <malloc@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D27
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string

tool: D27: /

tool: D5: %s%s%s

tool: D17: %s%s

assistant: ```c
char *build_path(const char *dir, const char *component) {
  const int dir_len = strlen(dir);
  const int comp_len = strlen(component);
  char *buf;
  if (dir_len > 0 && dir[dir_len - 1] == '/') {
    buf = malloc(sizeof(char) * dir_len + comp_len + 1);
    sprintf(buf, "%s%s", dir, component);
  } else {
    buf = malloc(sizeof(char) * dir_len + comp_len + strlen("/") + comp_len + 1);
    sprintf(buf, "%s%s%s", dir, "/", component);
  }
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<build_path>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r14d
  test   %ebx,%ebx
  jle    L10
  movslq %ebx,%rax
  cmpb   $0x2f,-0x1(%r12,%rax,1)
  je     L11
L10:
  lea    D12(%rip),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%r14,2),%edi
  add    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%r8
  mov    %r15,%rcx
  mov    %r12,%rdx
  mov    %rax,%r14
  mov    %rax,%rdi
  lea    D13(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L11:
  lea    0x1(%rbx,%r14,1),%edi
  call   <malloc@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D12: /

tool: D13: %s%s%s

tool: D17: %s%s

assistant: ```c
char *build_path(const char *dir, const char *component) {
  const int dir_len = strlen(dir);
  const int comp_len = strlen(component);
  char *buf;
  if (dir_len > 0 && dir[dir_len - 1] == '/') {
    buf = malloc(sizeof(char) * dir_len + comp_len + 1);
    sprintf(buf, "%s%s", dir, component);
  } else {
    buf = malloc(sizeof(char) * dir_len + comp_len + strlen("/") + comp_len + 1);
    sprintf(buf, "%s%s%s", dir, "/", component);
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_bmp_GetLineLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  jg     L0
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _bmp_GetLineLength(int width, int bpp) {
  int bits;
  int pad_bits;
  bits = width * bpp;
  pad_bits = 32 - (bits & 0x1f);
  if (pad_bits < 32)
    bits += pad_bits;
  return bits / 8;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_bmp_GetLineLength>:
  endbr64
  imul   %esi,%edi
  mov    %edi,%edx
  and    $0x1f,%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  lea    (%rdi,%rax,1),%edx
  cmp    $0x20,%eax
  cmovl  %edx,%edi
  lea    0x7(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x3,%eax
  ret
```

assistant: ```c
int _bmp_GetLineLength(int width, int bpp) {
  int bits;
  int pad_bits;
  bits = width * bpp;
  pad_bits = 32 - (bits & 0x1f);
  if (pad_bits < 32)
    bits += pad_bits;
  return bits / 8;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_bmp_GetLineLength>:
  endbr64
  imul   %esi,%edi
  mov    $0x20,%eax
  mov    %edi,%edx
  and    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rdi,%rax,1),%edx
  cmp    $0x20,%eax
  cmovne %edx,%edi
  test   %edi,%edi
  lea    0x7(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x3,%eax
  ret
```

assistant: ```c
int _bmp_GetLineLength(int width, int bpp) {
  int bits;
  int pad_bits;
  bits = width * bpp;
  pad_bits = 32 - (bits & 0x1f);
  if (pad_bits < 32)
    bits += pad_bits;
  return bits / 8;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_bmp_GetLineLength>:
  endbr64
  imul   %esi,%edi
  mov    $0x20,%eax
  mov    %edi,%edx
  and    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rdi,%rax,1),%edx
  cmp    $0x20,%eax
  cmovne %edx,%edi
  test   %edi,%edi
  lea    0x7(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x3,%eax
  ret
```

assistant: ```c
int _bmp_GetLineLength(int width, int bpp) {
  int bits;
  int pad_bits;
  bits = width * bpp;
  pad_bits = 32 - (bits & 0x1f);
  if (pad_bits < 32)
    bits += pad_bits;
  return bits / 8;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gmove_bca_1a2t_b3@plt>
  mov    $0x0,%eax
  call   <gmove_bca_1a2t_b4@plt>
  mov    $0x0,%eax
  call   <gmove_bca_1a2t_b5@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  gmove_bca_1a2t_b3();
  gmove_bca_1a2t_b4();
  gmove_bca_1a2t_b5();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gmove_bca_1a2t_b3@plt>
  mov    $0x0,%eax
  call   <gmove_bca_1a2t_b4@plt>
  mov    $0x0,%eax
  call   <gmove_bca_1a2t_b5@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gmove_bca_1a2t_b3();
  gmove_bca_1a2t_b4();
  gmove_bca_1a2t_b5();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gmove_bca_1a2t_b3@plt>
  xor    %eax,%eax
  call   <gmove_bca_1a2t_b4@plt>
  xor    %eax,%eax
  call   <gmove_bca_1a2t_b5@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gmove_bca_1a2t_b3();
  gmove_bca_1a2t_b4();
  gmove_bca_1a2t_b5();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gmove_bca_1a2t_b3@plt>
  xor    %eax,%eax
  call   <gmove_bca_1a2t_b4@plt>
  xor    %eax,%eax
  call   <gmove_bca_1a2t_b5@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gmove_bca_1a2t_b3();
  gmove_bca_1a2t_b4();
  gmove_bca_1a2t_b5();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<change_check_pull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L9:
  movl   $0x0,-0xc(%rbp)
  jmp    L108
L76:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    $0x20,%al
  jne    L113
  movl   $0x0,-0x8(%rbp)
  movb   $0x20,-0x15(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L70
L40:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L49
  cmpl   $0x0,-0x8(%rbp)
  jne    L58
  movl   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  jmp    L49
L58:
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L49:
  addl   $0x1,-0x4(%rbp)
L70:
  cmpl   $0x8,-0x4(%rbp)
  jle    L40
L17:
  cmpl   $0x0,-0x8(%rbp)
  je     L113
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,(%rcx,%rax,1)
  movl   $0x1,-0x14(%rbp)
L113:
  addl   $0x1,-0xc(%rbp)
L108:
  cmpl   $0x8,-0xc(%rbp)
  jle    L76
  addl   $0x1,-0x10(%rbp)
L2:
  cmpl   $0x8,-0x10(%rbp)
  jle    L9
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
bool change_check_pull(char pattern[9][9], char possibilities[9][9][9]) {
  bool change = false;
  for (int x = 0; x < 9; x++) {
    for (int y = 0; y < 9; y++) {
      if (pattern[x][y] == ' ') {
        bool numberbool = false;
        char numberchar = ' ';
        for (int z = 0; z < 9; z++) {
          if (possibilities[x][y][z] != ' ') {
            if (!numberbool) {
              numberbool = true;
              numberchar = possibilities[x][y][z];
            } else {
              numberbool = false;
              break;
            }
          }
        }
        if (numberbool) {
          pattern[x][y] = numberchar;
          change = true;
        }
      }
    }
  }
  return change;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<change_check_pull>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  lea    0x51(%rsi),%r10
  mov    %rdi,%r12
  lea    0x32a(%rsi),%r14
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  mov    $0x1,%ebx
  jmp    L101
L15:
  add    $0x1,%rax
  cmp    %r11,%rax
  je     L91
L29:
  movzbl (%rax),%esi
  cmp    $0x20,%sil
  je     L15
  test   %r9d,%r9d
  jne    L5
  mov    %esi,%r8d
  mov    %ebx,%r9d
  jmp    L15
L91:
  test   %r9d,%r9d
  je     L5
  mov    %r8b,(%rdi)
  mov    %r9d,%r15d
L5:
  add    $0x1,%rdx
  add    $0x9,%rcx
  cmp    %r10,%rcx
  je     L76
L63:
  mov    %rdx,%rdi
  movzbl (%rdx),%r8d
  cmp    $0x20,%r8b
  jne    L5
  mov    %rcx,%rax
  mov    %r13d,%r9d
  lea    0x9(%rcx),%r11
  jmp    L29
L76:
  add    $0x51,%r10
  add    $0x51,%rbp
  add    $0x9,%r12
  cmp    %r14,%r10
  je     L88
L101:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  jmp    L63
L88:
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
bool change_check_pull(char pattern[9][9], char possibilities[9][9][9]) {
  bool change = false;
  for (int x = 0; x < 9; x++) {
    for (int y = 0; y < 9; y++) {
      if (pattern[x][y] == ' ') {
        bool numberbool = false;
        char numberchar = ' ';
        for (int z = 0; z < 9; z++) {
          if (possibilities[x][y][z] != ' ') {
            if (!numberbool) {
              numberbool = true;
              numberchar = possibilities[x][y][z];
            } else {
              numberbool = false;
              break;
            }
          }
        }
        if (numberbool) {
          pattern[x][y] = numberchar;
          change = true;
        }
      }
    }
  }
  return change;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<change_check_pull>:
  endbr64
  lea    0x51(%rsi),%r11
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %r11,%r10
  lea    0x32a(%rsi),%rbx
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rdi,%rax
  jmp    L66
  nopl   (%rax)
L64:
  add    $0x1,%rax
  mov    %rdx,%rsi
  cmp    %r10,%rdx
  je     L32
L66:
  movzbl (%rax),%r8d
  lea    0x9(%rsi),%rdx
  cmp    $0x20,%r8b
  jne    L64
  xor    %r9d,%r9d
  nopl   (%rax)
L3:
  movzbl (%rsi),%ecx
  cmp    $0x20,%cl
  je     L34
  test   %r9d,%r9d
  jne    L64
  mov    %ecx,%r8d
  mov    $0x1,%r9d
L34:
  add    $0x1,%rsi
  cmp    %rdx,%rsi
  jne    L3
  test   %r9d,%r9d
  je     L64
  mov    %r8b,(%rax)
  mov    %r9d,%r12d
  add    $0x1,%rax
  mov    %rdx,%rsi
  cmp    %r10,%rdx
  jne    L66
  xchg   %ax,%ax
L32:
  add    $0x51,%r10
  mov    %r11,%rsi
  add    $0x9,%rdi
  cmp    %rbx,%r10
  je     L94
  add    $0x51,%r11
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
bool change_check_pull(char pattern[9][9], char possibilities[9][9][9]) {
  bool change = false;
  for (int x = 0; x < 9; x++) {
    for (int y = 0; y < 9; y++) {
      if (pattern[x][y] == ' ') {
        bool numberbool = false;
        char numberchar = ' ';
        for (int z = 0; z < 9; z++) {
          if (possibilities[x][y][z] != ' ') {
            if (!numberbool) {
              numberbool = true;
              numberchar = possibilities[x][y][z];
            } else {
              numberbool = false;
              break;
            }
          }
        }
        if (numberbool) {
          pattern[x][y] = numberchar;
          change = true;
        }
      }
    }
  }
  return change;
}
```