user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  mov    -0x414(%rbp),%eax
  mov    %eax,-0x418(%rbp)
  mov    -0x418(%rbp),%eax
  mov    %eax,-0x410(%rbp)
  mov    -0x410(%rbp),%eax
  mov    %eax,-0x408(%rbp)
  mov    -0x408(%rbp),%eax
  mov    %eax,-0x40c(%rbp)
  jmp    L110
L46:
  cmpl   $0xa,-0x404(%rbp)
  jne    L6
  movl   $0x0,-0x414(%rbp)
  mov    -0x414(%rbp),%eax
  mov    %eax,-0x418(%rbp)
  cmpl   $0x1,-0x408(%rbp)
  jne    L47
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x40c(%rbp)
L47:
  cmpl   $0x0,-0x410(%rbp)
  je     L110
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x408(%rbp)
  movl   $0x0,-0x410(%rbp)
  jmp    L110
L6:
  cmpl   $0x20,-0x404(%rbp)
  je     L3
  cmpl   $0x9,-0x404(%rbp)
  jne    L111
L3:
  mov    -0x418(%rbp),%eax
  mov    %eax,%edi
  call   <advance@plt>
  cmp    %eax,-0x414(%rbp)
  jne    L22
  mov    -0x414(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x1,-0x408(%rbp)
  mov    -0x414(%rbp),%eax
  mov    %eax,%edi
  call   <advance@plt>
  mov    %eax,-0x414(%rbp)
  movl   $0x1,-0x410(%rbp)
L22:
  mov    -0x404(%rbp),%eax
  mov    %eax,%edx
  mov    -0x418(%rbp),%eax
  cltq
  mov    %dl,-0x400(%rbp,%rax,1)
  mov    -0x418(%rbp),%eax
  mov    %eax,%edi
  call   <advance@plt>
  mov    %eax,-0x418(%rbp)
  jmp    L110
L45:
  mov    -0x414(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x414(%rbp),%eax
  mov    %eax,%edi
  call   <advance@plt>
  mov    %eax,-0x414(%rbp)
L111:
  mov    -0x418(%rbp),%eax
  cmp    -0x414(%rbp),%eax
  jne    L45
  mov    -0x404(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0x408(%rbp)
  movl   $0x1,-0x410(%rbp)
L110:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x404(%rbp)
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x404(%rbp)
  jne    L46
  cmpl   $0x1,-0x408(%rbp)
  jne    L23
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x40c(%rbp)
L23:
  mov    -0x40c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L103
  call   <__stack_chk_fail@plt>
L103:
  leave
  ret
```

assistant: ```c
int main(void) {
  char blank[1001];
  int head, tail;
  int nonspace;
  int retval;
  int c;
  int spaceJustPrinted;
  retval = spaceJustPrinted = nonspace = head = tail = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n') {
      head = tail = 0;
      if (spaceJustPrinted == 1)
        retval = EXIT_FAILURE;
      if (nonspace) {
        putchar('\n');
        spaceJustPrinted = 0;
        nonspace = 0;
      }
    } else if (c == ' ' || c == '\t') {
      if (advance(head) == tail) {
        putchar(blank[tail]);
        spaceJustPrinted = 1;
        tail = advance(tail);
        nonspace = 1;
      }
      blank[head] = c;
      head = advance(head);
    } else {
      while (head != tail) {
        putchar(blank[tail]);
        tail = advance(tail);
      }
      putchar(c);
      spaceJustPrinted = 0;
      nonspace = 1;
    }
  }
  if (spaceJustPrinted == 1)
    retval = EXIT_FAILURE;
  return retval;
}
```