ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<atof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  jmp    L8
  nopl   (%rax)
L63:
  add    $0x1,%r13d
L8:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L63
  movzbl (%r12),%eax
  cmp    $0x2d,%al
  je     L59
  mov    $0x1,%r12d
  cmp    $0x2b,%al
  je     L66
L46:
  movslq %r13d,%r14
  pxor   %xmm6,%xmm6
  add    %rbp,%r14
  movsd  %xmm6,(%rsp)
  mov    %r14,%rbx
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L28:
  movsbl (%rbx),%eax
  movsd  D33(%rip),%xmm0
  pxor   %xmm1,%xmm1
  add    $0x1,%rbx
  mulsd  (%rsp),%xmm0
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
L79:
  mov    %r13d,%r15d
  movsbl (%rbx),%edi
  sub    %r14d,%r15d
  add    %ebx,%r15d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L28
  xor    %eax,%eax
  cmpb   $0x2e,(%rbx)
  movsd  D16(%rip),%xmm7
  sete   %al
  add    %eax,%r15d
  movsd  %xmm7,0x8(%rsp)
  movslq %r15d,%r15
  add    %r15,%rbp
  jmp    L34
  nop
L5:
  movsbl 0x0(%rbp),%eax
  pxor   %xmm1,%xmm1
  add    $0x1,%rbp
  movsd  D33(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  D33(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm2
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
L34:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L59:
  mov    $0xffffffff,%r12d
L66:
  add    $0x1,%r13d
  jmp    L46
```

tool_calls: name: parse_data
arguments: data_tag: D33
datatype: f64
name: parse_data
arguments: data_tag: D16
datatype: f64

tool: D33: 10

tool: D16: 1

assistant: ```c
double atof(char s[]) {
  double val, power;
  int i, sign;
  for (i = 0; isspace(s[i]); i++)
    ;
  sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  for (val = 0.0; isdigit(s[i]); i++)
    val = 10.0 * val + (s[i] - '0');
  if (s[i] == '.')
    i++;
  for (power = 1.0; isdigit(s[i]); i++) {
    val = 10.0 * val + (s[i] - '0');
    power *= 10;
  }
  return sign * val / power;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aeron_compute_max_message_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x3,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1000000,%edx
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t aeron_compute_max_message_length(size_t term_length) {
  size_t max_length_for_term = term_length / 8;
  return max_length_for_term < (16u * 1024u * 1024u) ? max_length_for_term : (16u * 1024u * 1024u);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aeron_compute_max_message_length>:
  endbr64
  mov    %rdi,%rax
  shr    $0x3,%rax
  mov    $0x1000000,%edx
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  ret
```

assistant: ```c
size_t aeron_compute_max_message_length(size_t term_length) {
  size_t max_length_for_term = term_length / 8;
  return max_length_for_term < (16u * 1024u * 1024u) ? max_length_for_term : (16u * 1024u * 1024u);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aeron_compute_max_message_length>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1000000,%edx
  shr    $0x3,%rax
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  ret
```

assistant: ```c
size_t aeron_compute_max_message_length(size_t term_length) {
  size_t max_length_for_term = term_length / 8;
  return max_length_for_term < (16u * 1024u * 1024u) ? max_length_for_term : (16u * 1024u * 1024u);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aeron_compute_max_message_length>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1000000,%edx
  shr    $0x3,%rax
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  ret
```

assistant: ```c
size_t aeron_compute_max_message_length(size_t term_length) {
  size_t max_length_for_term = term_length / 8;
  return max_length_for_term < (16u * 1024u * 1024u) ? max_length_for_term : (16u * 1024u * 1024u);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L30
L29:
  mov    -0x18(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L48
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L2
L48:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L2:
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D13
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D57
data_type: string
name: read_data
arguments: data_tag: D41
data_type: string

tool: D1: N: 

tool: D13: %d

tool: D11: i: 

tool: D57: j: 

tool: D41: %d 

assistant: ```c
int main() {
  int n = 0, i = 0, j = 0, a = 0, final = 0;
  printf("N: ");
  scanf("%d", &n);
  printf("i: ");
  scanf("%d", &i);
  printf("j: ");
  scanf("%d", &j);
  while (a < n) {
    if (final % i == 0 || final % j == 0) {
      printf("%d ", final);
      a++;
    }
    final++;
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D44(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L6
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D28(%rip),%r12
  jmp    L17
L29:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
L27:
  add    $0x1,%ebx
  cmp    %ebp,0xc(%rsp)
  jle    L6
L17:
  mov    %ebx,%eax
  cltd
  idivl  0x10(%rsp)
  test   %edx,%edx
  je     L29
  mov    %ebx,%eax
  cltd
  idivl  0x14(%rsp)
  test   %edx,%edx
  jne    L27
  jmp    L29
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D48
datatype: string
name: extract_symbolic_data
arguments: data_label: D44
datatype: string
name: extract_symbolic_data
arguments: data_label: D46
datatype: string
name: extract_symbolic_data
arguments: data_label: D18
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string

tool: D48: N: 

tool: D44: %d

tool: D46: i: 

tool: D18: j: 

tool: D28: %d 

assistant: ```c
int main() {
  int n = 0, i = 0, j = 0, a = 0, final = 0;
  printf("N: ");
  scanf("%d", &n);
  printf("i: ");
  scanf("%d", &i);
  printf("j: ");
  scanf("%d", &j);
  while (a < n) {
    if (final % i == 0 || final % j == 0) {
      printf("%d ", final);
      a++;
    }
    final++;
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  lea    D13(%rip),%rbp
  xchg   %ax,%ax
L46:
  mov    %r12d,%eax
  cltd
  idivl  0x10(%rsp)
  test   %edx,%edx
  je     L27
  mov    %r12d,%eax
  cltd
  idivl  0x14(%rsp)
  test   %edx,%edx
  jne    L9
L27:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
L9:
  add    $0x1,%r12d
  cmp    %ebx,0xc(%rsp)
  jg     L46
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D41
data_type: string
name: retrieve_data
arguments: label: D43
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D2: N: 

tool: D10: %d

tool: D41: i: 

tool: D43: j: 

tool: D13: %d 

assistant: ```c
int main() {
  int n = 0, i = 0, j = 0, a = 0, final = 0;
  printf("N: ");
  scanf("%d", &n);
  printf("i: ");
  scanf("%d", &i);
  printf("j: ");
  scanf("%d", &j);
  while (a < n) {
    if (final % i == 0 || final % j == 0) {
      printf("%d ", final);
      a++;
    }
    final++;
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  lea    D14(%rip),%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L8
  xchg   %ax,%ax
L12:
  mov    %r12d,%eax
  cltd
  idivl  0x10(%rsp)
  test   %edx,%edx
  je     L33
  mov    %r12d,%eax
  cltd
  idivl  0x14(%rsp)
  test   %edx,%edx
  jne    L26
L33:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0xc(%rsp),%ecx
L26:
  add    $0x1,%r12d
  cmp    %ecx,%ebx
  jl     L12
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D40
type_infered: string
name: unpack_data
arguments: label: D37
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D13: N: 

tool: D12: %d

tool: D40: i: 

tool: D37: j: 

tool: D14: %d 

assistant: ```c
int main() {
  int n = 0, i = 0, j = 0, a = 0, final = 0;
  printf("N: ");
  scanf("%d", &n);
  printf("i: ");
  scanf("%d", &i);
  printf("j: ");
  scanf("%d", &j);
  while (a < n) {
    if (final % i == 0 || final % j == 0) {
      printf("%d ", final);
      a++;
    }
    final++;
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L11
L22:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  jne    L47
  shll   $0x10,-0x14(%rbp)
  subl   $0x10,-0x4(%rbp)
L47:
  mov    -0x14(%rbp),%eax
  and    $0xff000000,%eax
  test   %eax,%eax
  jne    L49
  shll   $0x8,-0x14(%rbp)
  subl   $0x8,-0x4(%rbp)
L49:
  mov    -0x14(%rbp),%eax
  and    $0xf0000000,%eax
  test   %eax,%eax
  jne    L2
  shll   $0x4,-0x14(%rbp)
  subl   $0x4,-0x4(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  and    $0xc0000000,%eax
  test   %eax,%eax
  jne    L12
  shll   $0x2,-0x14(%rbp)
  subl   $0x2,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x14(%rbp)
  js     L4
  subl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u))
    r -= 1;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fls>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L9
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L41
  shl    $0x10,%edi
  mov    $0x10,%eax
L41:
  test   $0xff000000,%edi
  jne    L22
  shl    $0x8,%edi
  sub    $0x8,%eax
L22:
  test   $0xf0000000,%edi
  jne    L4
  shl    $0x4,%edi
  sub    $0x4,%eax
L4:
  test   $0xc0000000,%edi
  jne    L34
  shl    $0x2,%edi
  sub    $0x2,%eax
L34:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L9:
  ret
```

assistant: ```c
int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u))
    r -= 1;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L14
  shl    $0x10,%edi
  mov    $0x10,%eax
L14:
  test   $0xff000000,%edi
  jne    L43
  shl    $0x8,%edi
  sub    $0x8,%eax
L43:
  test   $0xf0000000,%edi
  jne    L30
  shl    $0x4,%edi
  sub    $0x4,%eax
L30:
  test   $0xc0000000,%edi
  jne    L13
  shl    $0x2,%edi
  sub    $0x2,%eax
L13:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L4:
  ret
```

assistant: ```c
int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u))
    r -= 1;
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L7
  test   $0xffff0000,%edi
  je     L36
  mov    $0x18,%edx
  mov    $0x20,%eax
L1:
  test   $0xff000000,%edi
  jne    L28
  shl    $0x8,%edi
  mov    %edx,%eax
L28:
  test   $0xf0000000,%edi
  jne    L24
  shl    $0x4,%edi
  sub    $0x4,%eax
L24:
  test   $0xc0000000,%edi
  jne    L51
  shl    $0x2,%edi
  sub    $0x2,%eax
L51:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L7:
  ret
  nop
L36:
  shl    $0x10,%edi
  mov    $0x8,%edx
  mov    $0x10,%eax
  jmp    L1
```

assistant: ```c
int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u))
    r -= 1;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wait_pid_nohang>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L43:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <wait_nohang@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L13
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L55
L13:
  mov    -0xc(%rbp),%eax
  jmp    L0
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L43
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int wait_pid_nohang(int pid, int *wstat) {
  int w = 0;
  int r = 0;
  while (r != pid) {
    r = wait_nohang(&w);
    if (!r || (r == (int)-1))
      return r;
  }
  *wstat = w;
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<wait_pid_nohang>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
L16:
  cmp    %ebx,%eax
  je     L7
  mov    %rbp,%rdi
  call   <wait_nohang@plt>
  lea    0x1(%rax),%edx
  cmp    $0x1,%edx
  ja     L16
  jmp    L3
L7:
  mov    0x4(%rsp),%edx
  mov    %edx,(%r12)
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wait_pid_nohang(int pid, int *wstat) {
  int w = 0;
  int r = 0;
  while (r != pid) {
    r = wait_nohang(&w);
    if (!r || (r == (int)-1))
      return r;
  }
  *wstat = w;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wait_pid_nohang>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  jmp    L5
L13:
  mov    %rbp,%rdi
  call   <wait_nohang@plt>
  lea    0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L25
L5:
  cmp    %ebx,%eax
  jne    L13
  mov    0x4(%rsp),%edx
  mov    %edx,(%r12)
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wait_pid_nohang(int pid, int *wstat) {
  int w = 0;
  int r = 0;
  while (r != pid) {
    r = wait_nohang(&w);
    if (!r || (r == (int)-1))
      return r;
  }
  *wstat = w;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wait_pid_nohang>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  jmp    L0
L4:
  mov    %rbp,%rdi
  call   <wait_nohang@plt>
  lea    0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L15
L0:
  cmp    %ebx,%eax
  jne    L4
  mov    0x4(%rsp),%edx
  mov    %edx,(%r12)
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wait_pid_nohang(int pid, int *wstat) {
  int w = 0;
  int r = 0;
  while (r != pid) {
    r = wait_nohang(&w);
    if (!r || (r == (int)-1))
      return r;
  }
  *wstat = w;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bytes_to_int32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L26
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <reverse_memcpy@plt>
  jmp    L18
L26:
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L18:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int32_t bytes_to_int32(const unsigned char bytes[4], int switch_endian) {
  int32_t dest_num;
  void *dest_ptr = (void *)&dest_num;
  if (switch_endian) {
    reverse_memcpy(dest_ptr, (void *)bytes, 4);
  } else {
    memcpy(dest_ptr, (void *)bytes, 4);
  }
  return dest_num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bytes_to_int32>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L16
  lea    0x4(%rsp),%rax
  mov    $0x4,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <reverse_memcpy@plt>
L26:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L16:
  lea    0x4(%rsp),%rax
  mov    $0x4,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L26
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t bytes_to_int32(const unsigned char bytes[4], int switch_endian) {
  int32_t dest_num;
  void *dest_ptr = (void *)&dest_num;
  if (switch_endian) {
    reverse_memcpy(dest_ptr, (void *)bytes, 4);
  } else {
    memcpy(dest_ptr, (void *)bytes, 4);
  }
  return dest_num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bytes_to_int32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  lea    0x4(%rsp),%rdi
  mov    %r8,%rsi
  je     L8
  call   <reverse_memcpy@plt>
L26:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  call   <memcpy@plt>
  jmp    L26
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t bytes_to_int32(const unsigned char bytes[4], int switch_endian) {
  int32_t dest_num;
  void *dest_ptr = (void *)&dest_num;
  if (switch_endian) {
    reverse_memcpy(dest_ptr, (void *)bytes, 4);
  } else {
    memcpy(dest_ptr, (void *)bytes, 4);
  }
  return dest_num;
}
```