ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putendl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
L0:
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  jmp    L27
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <ft_putendl>
L27:
  leave
  ret
```

assistant: ```c
void ft_putendl(char const *s) {
  if (!s || !(*s)) {
    ft_putchar('\n');
    return;
  }
  ft_putchar(*s);
  ft_putendl(s + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_putendl>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L20
L6:
  mov    $0xa,%edi
  call   <ft_putchar@plt>
L29:
  pop    %rbx
  ret
L20:
  movsbl %dil,%edi
  call   <ft_putchar@plt>
  lea    0x1(%rbx),%rdi
  call   <ft_putendl>
  jmp    L29
```

assistant: ```c
void ft_putendl(char const *s) {
  if (!s || !(*s)) {
    ft_putchar('\n');
    return;
  }
  ft_putchar(*s);
  ft_putendl(s + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putendl>:
  endbr64
  test   %rdi,%rdi
  je     L13
  push   %rbx
  mov    %rdi,%rbx
  jmp    L0
  nop
L9:
  call   <ft_putchar@plt>
  add    $0x1,%rbx
L0:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <ft_putchar@plt>
L13:
  mov    $0xa,%edi
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_putendl(char const *s) {
  if (!s || !(*s)) {
    ft_putchar('\n');
    return;
  }
  ft_putchar(*s);
  ft_putendl(s + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_putendl>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L17
  nopl   (%rax)
L6:
  call   <ft_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L6
L17:
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <ft_putchar@plt>
L5:
  mov    $0xa,%edi
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_putendl(char const *s) {
  if (!s || !(*s)) {
    ft_putchar('\n');
    return;
  }
  ft_putchar(*s);
  ft_putendl(s + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gen_58>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_58@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_58(void) {
  handle_58(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_58>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_58@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_58(void) {
  handle_58(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gen_58>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_58@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_58(void) {
  handle_58(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gen_58>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_58@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_58(void) {
  handle_58(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minutes16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_millisecond_timer@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x45e7b272f608770f,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xe,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  and    $0xffff,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint16_t minutes16(void) {
  uint32_t ms = get_millisecond_timer();
  uint16_t m16;
  m16 = (ms / (60000L)) & 0xFFFF;
  return m16;
}
```
user: What is the c source code of the assembly code below:

```asm
<minutes16>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_millisecond_timer@plt>
  mov    %rax,%rcx
  movabs $0x45e7b272f608770f,%rdx
  imul   %rdx
  sar    $0xe,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  movzwl %dx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t minutes16(void) {
  uint32_t ms = get_millisecond_timer();
  uint16_t m16;
  m16 = (ms / (60000L)) & 0xFFFF;
  return m16;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<minutes16>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_millisecond_timer@plt>
  add    $0x8,%rsp
  movabs $0x45e7b272f608770f,%rdx
  mov    %rax,%rcx
  imul   %rdx
  sar    $0x3f,%rcx
  sar    $0xe,%rdx
  sub    %rcx,%rdx
  movzwl %dx,%eax
  ret
```

assistant: ```c
uint16_t minutes16(void) {
  uint32_t ms = get_millisecond_timer();
  uint16_t m16;
  m16 = (ms / (60000L)) & 0xFFFF;
  return m16;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<minutes16>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_millisecond_timer@plt>
  add    $0x8,%rsp
  movabs $0x45e7b272f608770f,%rdx
  mov    %rax,%rcx
  imul   %rdx
  sar    $0x3f,%rcx
  sar    $0xe,%rdx
  sub    %rcx,%rdx
  movzwl %dx,%eax
  ret
```

assistant: ```c
uint16_t minutes16(void) {
  uint32_t ms = get_millisecond_timer();
  uint16_t m16;
  m16 = (ms / (60000L)) & 0xFFFF;
  return m16;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_scancode@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <translate_scancode@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char get_char(void) {
  unsigned char tmpchar;
  tmpchar = get_scancode();
  tmpchar = translate_scancode(tmpchar);
  return tmpchar;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_char>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_scancode@plt>
  movzbl %al,%edi
  call   <translate_scancode@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char get_char(void) {
  unsigned char tmpchar;
  tmpchar = get_scancode();
  tmpchar = translate_scancode(tmpchar);
  return tmpchar;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_char>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_scancode@plt>
  add    $0x8,%rsp
  movzbl %al,%edi
  jmp    1070 <translate_scancode@plt>
```

assistant: ```c
unsigned char get_char(void) {
  unsigned char tmpchar;
  tmpchar = get_scancode();
  tmpchar = translate_scancode(tmpchar);
  return tmpchar;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_char>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_scancode@plt>
  add    $0x8,%rsp
  movzbl %al,%edi
  jmp    1070 <translate_scancode@plt>
```

assistant: ```c
unsigned char get_char(void) {
  unsigned char tmpchar;
  tmpchar = get_scancode();
  tmpchar = translate_scancode(tmpchar);
  return tmpchar;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_multprec_start_system_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L1:
  cmp    %rdx,%rsp
  je     L42
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L42:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L48
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L48:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L12
L16:
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x30(%rbp),%rax
  mov    -0x40(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x40(%rbp)
L12:
  mov    -0x40(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L16
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x223,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int read_multprec_start_system_from_file(int decimals, int n, char *filename) {
  int b[n], i, fail;
  int a[2];
  double *c;
  a[0] = n;
  a[1] = decimals;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc(547, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_multprec_start_system_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%r8d
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L38:
  cmp    %rdx,%rsp
  je     L22
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L38
L22:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L57
  orq    $0x0,-0x8(%rsp,%rax,1)
L57:
  mov    %rsp,%rdi
  mov    %esi,-0x10(%rbp)
  mov    %r8d,-0xc(%rbp)
  test   %esi,%esi
  jle    L58
  mov    %esi,%esi
  mov    $0x0,%eax
L8:
  movsbl (%rcx,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L8
L58:
  lea    -0x10(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x223,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  leave
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_multprec_start_system_from_file(int decimals, int n, char *filename) {
  int b[n], i, fail;
  int a[2];
  double *c;
  a[0] = n;
  a[1] = decimals;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc(547, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_multprec_start_system_from_file>:
  endbr64
  push   %rbp
  mov    %edi,%r10d
  movslq %esi,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdi,4),%rax
  mov    %rsp,%r8
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rcx
  cmp    %r8,%rsp
  je     L26
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L22
L26:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L35
L65:
  mov    %esi,-0x10(%rbp)
  mov    %rsp,%r9
  mov    %r10d,-0xc(%rbp)
  test   %esi,%esi
  jle    L42
  xor    %eax,%eax
  nopl   0x0(%rax)
L41:
  movsbl (%rdx,%rax,1),%ecx
  mov    %ecx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L41
L42:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r9,%rdx
  mov    $0x223,%edi
  lea    -0x10(%rbp),%rsi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  leave
  ret
L35:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L65
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_multprec_start_system_from_file(int decimals, int n, char *filename) {
  int b[n], i, fail;
  int a[2];
  double *c;
  a[0] = n;
  a[1] = decimals;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc(547, a, b, c, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <is_pstate@plt>
  test   %rax,%rax
  je     L2
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <do_pstate@plt>
  jmp    L6
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <do_cpufreq@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: Pstate driver


assistant: ```c
int main(int argc, char **argv) {
  if (is_pstate()) {
    printf("Pstate driver\n");
    return do_pstate(argc, argv);
  } else
    return do_cpufreq(argc, argv);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <is_pstate@plt>
  test   %rax,%rax
  je     L0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <do_pstate@plt>
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <do_cpufreq@plt>
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: Pstate driver


assistant: ```c
int main(int argc, char **argv) {
  if (is_pstate()) {
    printf("Pstate driver\n");
    return do_pstate(argc, argv);
  } else
    return do_cpufreq(argc, argv);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <is_pstate@plt>
  test   %rax,%rax
  je     L5
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    10a0 <do_pstate@plt>
L5:
  pop    %rax
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <do_cpufreq@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: Pstate driver


assistant: ```c
int main(int argc, char **argv) {
  if (is_pstate()) {
    printf("Pstate driver\n");
    return do_pstate(argc, argv);
  } else
    return do_cpufreq(argc, argv);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <is_pstate@plt>
  test   %rax,%rax
  je     L2
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pop    %rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    10a0 <do_pstate@plt>
L2:
  pop    %rax
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <do_cpufreq@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Pstate driver


assistant: ```c
int main(int argc, char **argv) {
  if (is_pstate()) {
    printf("Pstate driver\n");
    return do_pstate(argc, argv);
  } else
    return do_cpufreq(argc, argv);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<udie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xf4000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0x320,%rsp
  mov    %rdi,-0xf4318(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0xf4318(%rbp),%rdx
  mov    -0xf4308(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xf4308(%rbp),%edx
  mov    -0xf4318(%rbp),%rcx
  lea    -0xf4300(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0xf4308(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0xf4300(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xf4304(%rbp)
  mov    -0xf4304(%rbp),%eax
  cltq
  movb   $0xa,-0xf4300(%rbp,%rax,1)
  mov    -0xf4304(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,-0xf4300(%rbp,%rax,1)
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  lea    -0xf4300(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void udie(const char *fmt, ...) {
  char buf[(1000 * 1000)];
  va_list args;
  va_start(args, fmt);
  vsprintf(buf, fmt, args);
  va_end(args);
  int len = strlen(buf);
  buf[len] = '\n';
  buf[len + 1] = 0;
  fputs(buf, stderr);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udie>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf4000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0x250,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xf4248(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%rbp
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  movb   $0xa,(%rsp,%rdx,1)
  add    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  call   <fputs@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    0xf4248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0xf4250,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void udie(const char *fmt, ...) {
  char buf[(1000 * 1000)];
  va_list args;
  va_start(args, fmt);
  vsprintf(buf, fmt, args);
  va_end(args);
  int len = strlen(buf);
  buf[len] = '\n';
  buf[len + 1] = 0;
  fputs(buf, stderr);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<udie>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0xf4000(%rsp),%r11
L1:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L1
  sub    $0x250,%rsp
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0xf4248(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  add    $0x1,%eax
  cltq
  movb   $0xa,(%rsp,%rdx,1)
  movb   $0x0,(%rsp,%rax,1)
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  call   <fputs@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    0xf4248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xf4250,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void udie(const char *fmt, ...) {
  char buf[(1000 * 1000)];
  va_list args;
  va_start(args, fmt);
  vsprintf(buf, fmt, args);
  va_end(args);
  int len = strlen(buf);
  buf[len] = '\n';
  buf[len + 1] = 0;
  fputs(buf, stderr);
  exit(EXIT_FAILURE);
}
```
user: What is the c source code of the assembly code below:

```asm
<udie>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0xf4000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x250,%rsp
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0xf4248(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  add    $0x1,%eax
  cltq
  movb   $0xa,(%rsp,%rdx,1)
  movb   $0x0,(%rsp,%rax,1)
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <fputs@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    0xf4248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xf4250,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void udie(const char *fmt, ...) {
  char buf[(1000 * 1000)];
  va_list args;
  va_start(args, fmt);
  vsprintf(buf, fmt, args);
  va_end(args);
  int len = strlen(buf);
  buf[len] = '\n';
  buf[len + 1] = 0;
  fputs(buf, stderr);
  exit(EXIT_FAILURE);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i386_cpuid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L19
L10:
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    %edx,-0x4(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i386_cpuid>:
  endbr64
  mov    $0x0,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    $0x0,%edx
  test   %eax,%eax
  je     L5
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
L5:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i386_cpuid>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  test   %eax,%eax
  je     L5
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    %edx,%r8d
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<i386_cpuid>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  test   %eax,%eax
  je     L2
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    %edx,%r8d
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```