ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L46
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L34
L46:
  cmpl   $0x1,-0x28(%rbp)
  jne    L97
  mov    -0x24(%rbp),%eax
  jmp    L34
L97:
  cmpl   $0xffffffff,-0x28(%rbp)
  jne    L80
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  je     L86
  mov    -0x24(%rbp),%eax
  neg    %eax
  jmp    L34
L86:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L34
L80:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x28(%rbp)
  jne    L137
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L34
L137:
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jns    L177
  negl   -0x28(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
L177:
  cmpl   $0x0,-0x24(%rbp)
  jns    L150
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L143
  mov    -0x28(%rbp),%eax
  add    %eax,-0x24(%rbp)
  addl   $0x1,-0x14(%rbp)
L143:
  negl   -0x24(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L150
L54:
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L164
L109:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  shll   -0x8(%rbp)
  shll   -0xc(%rbp)
L164:
  mov    -0x24(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L109
L150:
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L54
  cmpl   $0x0,-0x4(%rbp)
  je     L32
  mov    -0x14(%rbp),%eax
  neg    %eax
  jmp    L34
L32:
  mov    -0x14(%rbp),%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int divide(int dividend, int divisor) {
  if (divisor == 0)
    return INT_MAX;
  if (divisor == 1)
    return dividend;
  if (divisor == -1)
    return dividend == INT_MIN ? INT_MAX : -dividend;
  if (divisor == INT_MIN)
    return dividend == INT_MIN;
  int ret = 0;
  int sum = 0;
  int cnt;
  int tmp;
  int isNeg = 0;
  if (divisor < 0) {
    divisor = -divisor;
    isNeg = !isNeg;
  }
  if (dividend < 0) {
    if (dividend == INT_MIN) {
      dividend += divisor;
      ret++;
    }
    dividend = -dividend;
    isNeg = !isNeg;
  }
  while (sum <= dividend - divisor) {
    tmp = divisor;
    cnt = 1;
    while (sum <= dividend - tmp) {
      sum += tmp;
      ret += cnt;
      tmp += tmp;
      cnt += cnt;
    }
  }
  return isNeg ? -ret : ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divide>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    %edi,%r8d
  cmp    $0x1,%esi
  je     L139
  cmp    $0xffffffff,%esi
  je     L136
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  cmp    %esi,%eax
  je     L16
  mov    $0x0,%r11d
  test   %esi,%esi
  js     L114
L49:
  mov    $0x0,%r8d
  test   %edi,%edi
  js     L186
L69:
  mov    %esi,%eax
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    %edi,%r10d
  sub    %esi,%r10d
  jns    L176
L185:
  mov    %r8d,%eax
  neg    %eax
  test   %r11d,%r11d
  cmovne %eax,%r8d
  jmp    L139
L12:
  mov    D26(%rip),%rax
  mov    (%rax),%r8d
L139:
  mov    %r8d,%eax
  ret
L136:
  mov    D12(%rip),%rax
  cmp    %edi,(%rax)
  je     L67
  neg    %edi
  mov    %edi,%r8d
  jmp    L139
L67:
  mov    D26(%rip),%rax
  mov    (%rax),%r8d
  jmp    L139
L16:
  cmp    %edi,%esi
  sete   %r8b
  movzbl %r8b,%r8d
  jmp    L139
L114:
  neg    %esi
  mov    $0x1,%r11d
  jmp    L49
L186:
  cmp    %edi,%eax
  je     L74
L27:
  neg    %edi
  xor    $0x1,%r11d
  jmp    L69
L74:
  add    %esi,%edi
  mov    $0x1,%r8d
  jmp    L27
L119:
  mov    %esi,%eax
  mov    $0x1,%ecx
L176:
  add    %eax,%edx
  add    %ecx,%r8d
  add    %eax,%eax
  add    %ecx,%ecx
  mov    %edi,%r9d
  sub    %eax,%r9d
  cmp    %edx,%r9d
  jge    L176
  cmp    %r10d,%edx
  jle    L119
  jmp    L185
```

assistant: ```c
int divide(int dividend, int divisor) {
  if (divisor == 0)
    return INT_MAX;
  if (divisor == 1)
    return dividend;
  if (divisor == -1)
    return dividend == INT_MIN ? INT_MAX : -dividend;
  if (divisor == INT_MIN)
    return dividend == INT_MIN;
  int ret = 0;
  int sum = 0;
  int cnt;
  int tmp;
  int isNeg = 0;
  if (divisor < 0) {
    divisor = -divisor;
    isNeg = !isNeg;
  }
  if (dividend < 0) {
    if (dividend == INT_MIN) {
      dividend += divisor;
      ret++;
    }
    dividend = -dividend;
    isNeg = !isNeg;
  }
  while (sum <= dividend - divisor) {
    tmp = divisor;
    cnt = 1;
    while (sum <= dividend - tmp) {
      sum += tmp;
      ret += cnt;
      tmp += tmp;
      cnt += cnt;
    }
  }
  return isNeg ? -ret : ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divide>:
  endbr64
  test   %esi,%esi
  je     L96
  mov    %edi,%r8d
  cmp    $0x1,%esi
  je     L10
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%esi
  je     L99
  cmp    %eax,%esi
  je     L45
  xor    %r11d,%r11d
  test   %esi,%esi
  js     L92
  xor    %r8d,%r8d
  test   %edi,%edi
  js     L55
L132:
  mov    %edi,%r10d
  mov    %esi,%eax
  mov    $0x1,%ecx
  xor    %edx,%edx
  sub    %esi,%r10d
  js     L54
  nopl   0x0(%rax)
L121:
  add    %eax,%edx
  mov    %edi,%r9d
  add    %eax,%eax
  add    %ecx,%r8d
  sub    %eax,%r9d
  add    %ecx,%ecx
  cmp    %edx,%r9d
  jge    L121
  cmp    %edx,%r10d
  jl     L54
  mov    %esi,%eax
  mov    $0x1,%ecx
  jmp    L121
  nopw   0x0(%rax,%rax,1)
L96:
  mov    D15(%rip),%rax
  mov    (%rax),%r8d
L10:
  mov    %r8d,%eax
  ret
L54:
  mov    %r8d,%eax
  neg    %eax
  test   %r11d,%r11d
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
L55:
  cmp    %eax,%edi
  jne    L104
  add    %esi,%edi
  mov    $0x1,%r8d
L104:
  neg    %edi
  xor    $0x1,%r11d
  jmp    L132
L92:
  neg    %esi
  mov    $0x1,%r11d
  xor    %r8d,%r8d
  test   %edi,%edi
  jns    L132
  jmp    L55
L99:
  cmp    %eax,%edi
  je     L96
  neg    %r8d
  jmp    L10
L45:
  cmp    %esi,%edi
  sete   %r8b
  movzbl %r8b,%r8d
  jmp    L10
```

assistant: ```c
int divide(int dividend, int divisor) {
  if (divisor == 0)
    return INT_MAX;
  if (divisor == 1)
    return dividend;
  if (divisor == -1)
    return dividend == INT_MIN ? INT_MAX : -dividend;
  if (divisor == INT_MIN)
    return dividend == INT_MIN;
  int ret = 0;
  int sum = 0;
  int cnt;
  int tmp;
  int isNeg = 0;
  if (divisor < 0) {
    divisor = -divisor;
    isNeg = !isNeg;
  }
  if (dividend < 0) {
    if (dividend == INT_MIN) {
      dividend += divisor;
      ret++;
    }
    dividend = -dividend;
    isNeg = !isNeg;
  }
  while (sum <= dividend - divisor) {
    tmp = divisor;
    cnt = 1;
    while (sum <= dividend - tmp) {
      sum += tmp;
      ret += cnt;
      tmp += tmp;
      cnt += cnt;
    }
  }
  return isNeg ? -ret : ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<divide>:
  endbr64
  test   %esi,%esi
  je     L48
  mov    %edi,%r8d
  cmp    $0x1,%esi
  je     L70
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%esi
  je     L5
  cmp    %eax,%esi
  je     L20
  mov    $0x1,%edx
  xor    %r11d,%r11d
  test   %esi,%esi
  js     L36
  xor    %r8d,%r8d
  test   %edi,%edi
  js     L85
L150:
  mov    %edi,%r10d
  mov    %esi,%eax
  mov    $0x1,%ecx
  xor    %edx,%edx
  sub    %esi,%r10d
  js     L105
  xchg   %ax,%ax
L19:
  add    %eax,%edx
  mov    %edi,%r9d
  add    %eax,%eax
  add    %ecx,%r8d
  sub    %eax,%r9d
  add    %ecx,%ecx
  cmp    %edx,%r9d
  jge    L19
  cmp    %edx,%r10d
  jl     L105
  mov    %esi,%eax
  mov    $0x1,%ecx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L48:
  mov    D5(%rip),%rax
  mov    (%rax),%r8d
L70:
  mov    %r8d,%eax
  ret
L105:
  mov    %r8d,%eax
  neg    %eax
  test   %r11d,%r11d
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
L85:
  cmp    %eax,%edi
  jne    L101
  add    %esi,%edi
  mov    $0x1,%r8d
L101:
  neg    %edi
  mov    %edx,%r11d
  jmp    L150
L36:
  neg    %esi
  xor    %edx,%edx
  mov    $0x1,%r11d
  xor    %r8d,%r8d
  test   %edi,%edi
  jns    L150
  jmp    L85
L5:
  cmp    %eax,%edi
  je     L48
  neg    %r8d
  jmp    L70
L20:
  cmp    %esi,%edi
  sete   %r8b
  movzbl %r8b,%r8d
  jmp    L70
```

assistant: ```c
int divide(int dividend, int divisor) {
  if (divisor == 0)
    return INT_MAX;
  if (divisor == 1)
    return dividend;
  if (divisor == -1)
    return dividend == INT_MIN ? INT_MAX : -dividend;
  if (divisor == INT_MIN)
    return dividend == INT_MIN;
  int ret = 0;
  int sum = 0;
  int cnt;
  int tmp;
  int isNeg = 0;
  if (divisor < 0) {
    divisor = -divisor;
    isNeg = !isNeg;
  }
  if (dividend < 0) {
    if (dividend == INT_MIN) {
      dividend += divisor;
      ret++;
    }
    dividend = -dividend;
    isNeg = !isNeg;
  }
  while (sum <= dividend - divisor) {
    tmp = divisor;
    cnt = 1;
    while (sum <= dividend - tmp) {
      sum += tmp;
      ret += cnt;
      tmp += tmp;
      cnt += cnt;
    }
  }
  return isNeg ? -ret : ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  D14(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: f32
name: parse_data
arguments: data_tag: D19
type_infered: string

tool: D14: 7

tool: D19: %.2f


assistant: ```c
int main(int argc, char *argv[]) {
  float f = 7;
  printf("%.2f\n", f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D9(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: f32
name: retrieve_data
arguments: tag: D15
data_type: string

tool: D9: 7

tool: D15: %.2f


assistant: ```c
int main(int argc, char *argv[]) {
  float f = 7;
  printf("%.2f\n", f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D10(%rip),%xmm0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D10
type: f32
name: read_data
arguments: label: D7
type: string

tool: D10: 7

tool: D7: %.2f


assistant: ```c
int main(int argc, char *argv[]) {
  float f = 7;
  printf("%.2f\n", f);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D11(%rip),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_infered: f32
name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D11: 7

tool: D0: %.2f


assistant: ```c
int main(int argc, char *argv[]) {
  float f = 7;
  printf("%.2f\n", f);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<nbre_champs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L59:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L37
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  addl   $0x1,-0xc(%rbp)
  jmp    L42
L37:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L4
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L42
L4:
  movl   $0x0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L42:
  cmpl   $0x1,-0x8(%rbp)
  je     L59
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nbre_champs(char *buffer) {
  int i = 0;
  int test = 1;
  int nbre = 0;
  while (test == 1) {
    if (buffer[i] != ',' && buffer[i] != '\0') {
      i++;
    } else if (buffer[i] == ',') {
      nbre++;
      i++;
    } else {
      test = 0;
      nbre++;
    }
  }
  return nbre;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nbre_champs>:
  endbr64
  mov    $0x0,%eax
  jmp    L15
L29:
  add    $0x1,%eax
L24:
  add    $0x1,%rdi
L15:
  movzbl (%rdi),%edx
  cmp    $0x2c,%dl
  je     L39
  test   %dl,%dl
  jne    L24
L39:
  cmp    $0x2c,%dl
  je     L29
  add    $0x1,%eax
  ret
```

assistant: ```c
int nbre_champs(char *buffer) {
  int i = 0;
  int test = 1;
  int nbre = 0;
  while (test == 1) {
    if (buffer[i] != ',' && buffer[i] != '\0') {
      i++;
    } else if (buffer[i] == ',') {
      nbre++;
      i++;
    } else {
      test = 0;
      nbre++;
    }
  }
  return nbre;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nbre_champs>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    $0x2c,%al
  je     L23
  xchg   %ax,%ax
L36:
  test   %al,%al
  je     L23
L13:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x2c,%al
  jne    L36
L23:
  add    $0x1,%r8d
  cmp    $0x2c,%al
  je     L13
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nbre_champs(char *buffer) {
  int i = 0;
  int test = 1;
  int nbre = 0;
  while (test == 1) {
    if (buffer[i] != ',' && buffer[i] != '\0') {
      i++;
    } else if (buffer[i] == ',') {
      nbre++;
      i++;
    } else {
      test = 0;
      nbre++;
    }
  }
  return nbre;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nbre_champs>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    $0x2c,%al
  je     L36
  xchg   %ax,%ax
L7:
  test   %al,%al
  je     L36
L30:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x2c,%al
  jne    L7
L36:
  add    $0x1,%r8d
  cmp    $0x2c,%al
  je     L30
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nbre_champs(char *buffer) {
  int i = 0;
  int test = 1;
  int nbre = 0;
  while (test == 1) {
    if (buffer[i] != ',' && buffer[i] != '\0') {
      i++;
    } else if (buffer[i] == ',') {
      nbre++;
      i++;
    } else {
      test = 0;
      nbre++;
    }
  }
  return nbre;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x25,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edi
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  mov    $0x8,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edi,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  shl    $0x4,%eax
  and    $0xfffffff0,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L1
L14:
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  add    %eax,%eax
  shl    $0x2,%eax
  and    $0x38,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  add    %eax,%eax
  shl    $0x2,%eax
  and    $0x38,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
L1:
  movzbl -0x9(%rbp),%eax
  xor    $0x63,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
    }
    output[0UL] = state[0UL] ^ 95286627UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  movzbl (%rax),%esi
  sub    $0x25,%esi
  movzbl %sil,%eax
  test   $0x1,%sil
  je     L14
  mov    %esi,%r8d
  shr    $0x3,%r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  mov    $0x8,%ecx
  sub    %r8d,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  shl    $0x3,%edx
  and    $0x78,%edx
  or     %esi,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %edx,%eax
L18:
  xor    $0x63,%eax
  mov    %al,(%rdi)
  ret
L14:
  lea    0x0(,%rax,8),%edx
  and    $0x38,%edx
  or     %esi,%edx
  lea    0x0(,%rdx,8),%eax
  and    $0x38,%eax
  or     %edx,%eax
  jmp    L18
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
    }
    output[0UL] = state[0UL] ^ 95286627UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzbl (%r8),%esi
  sub    $0x25,%esi
  movzbl %sil,%eax
  test   $0x1,%sil
  je     L5
  mov    %esi,%r8d
  mov    $0x8,%ecx
  shr    $0x3,%r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  shl    $0x3,%edx
  and    $0x78,%edx
  or     %esi,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  xor    $0x63,%eax
  mov    %al,(%rdi)
  ret
  nopl   (%rax)
L5:
  lea    0x0(,%rax,8),%edx
  and    $0x38,%edx
  or     %esi,%edx
  lea    0x0(,%rdx,8),%eax
  and    $0x38,%eax
  or     %edx,%eax
  xor    $0x63,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
    }
    output[0UL] = state[0UL] ^ 95286627UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzbl (%r8),%esi
  sub    $0x25,%esi
  movzbl %sil,%eax
  test   $0x1,%sil
  je     L9
  mov    %esi,%r8d
  mov    $0x8,%ecx
  shr    $0x3,%r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  shl    $0x3,%edx
  and    $0x78,%edx
  or     %esi,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  xor    $0x63,%eax
  mov    %al,(%rdi)
  ret
  nopl   (%rax)
L9:
  lea    0x0(,%rax,8),%edx
  and    $0x38,%edx
  or     %esi,%edx
  lea    0x0(,%rdx,8),%eax
  and    $0x38,%eax
  or     %edx,%eax
  xor    $0x63,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
    }
    output[0UL] = state[0UL] ^ 95286627UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<proc1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long proc1(long p1) {
  long a = 1;
  return p1 + a * 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<proc1>:
  endbr64
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
long proc1(long p1) {
  long a = 1;
  return p1 + a * 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<proc1>:
  endbr64
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
long proc1(long p1) {
  long a = 1;
  return p1 + a * 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fork_test@plt>
  cmpq   $0x0,-0x10(%rbp)
  jle    L19
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
L19:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: ps -ef | grep marsud

assistant: ```c
int main(int argc, char *argv[]) {
  pid_t f1;
  int st;
  f1 = fork();
  fork_test(f1);
  if (f1 > 0) {
    wait(&st);
  }
  system("ps -ef | grep marsud");
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <fork_test@plt>
  test   %rbx,%rbx
  jg     L25
L18:
  lea    D2(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x1,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L25:
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  jmp    L18
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: ps -ef | grep marsud

assistant: ```c
int main(int argc, char *argv[]) {
  pid_t f1;
  int st;
  f1 = fork();
  fork_test(f1);
  if (f1 > 0) {
    wait(&st);
  }
  system("ps -ef | grep marsud");
  return 1;
}
```