ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<get_region_name_MY>:
  endbr64
  cmp    $0x11,%edi
  ja     L3
  mov    %edi,%edi
  lea    D72(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D6(%rip),%rax
  ret
  lea    D13(%rip),%rax
  ret
  lea    D50(%rip),%rax
  ret
  lea    D39(%rip),%rax
  ret
  lea    D87(%rip),%rax
  ret
  lea    D29(%rip),%rax
  ret
  lea    D85(%rip),%rax
  ret
  lea    D157(%rip),%rax
  ret
  lea    D41(%rip),%rax
  ret
  lea    D131(%rip),%rax
  ret
  lea    D37(%rip),%rax
  ret
  lea    D25(%rip),%rax
  ret
  lea    D106(%rip),%rax
  ret
  lea    D17(%rip),%rax
  ret
  lea    D132(%rip),%rax
  ret
L3:
  mov    $0x0,%eax
  ret
  lea    D102(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D50
type_infered: string
name: retrieve_data
arguments: tag: D39
type_infered: string
name: retrieve_data
arguments: tag: D87
type_infered: string
name: retrieve_data
arguments: tag: D29
type_infered: string
name: retrieve_data
arguments: tag: D85
type_infered: string
name: retrieve_data
arguments: tag: D157
type_infered: string
name: retrieve_data
arguments: tag: D41
type_infered: string
name: retrieve_data
arguments: tag: D131
type_infered: string
name: retrieve_data
arguments: tag: D37
type_infered: string
name: retrieve_data
arguments: tag: D25
type_infered: string
name: retrieve_data
arguments: tag: D106
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D132
type_infered: string
name: retrieve_data
arguments: tag: D102
type_infered: string

tool: D6: Kedah

tool: D13: Kelantan

tool: D50: Melaka

tool: D39: Negeri Sembilan

tool: D87: Pahang

tool: D29: Perak

tool: D85: Perlis

tool: D157: Pulau Pinang

tool: D41: Sarawak

tool: D131: Selangor

tool: D37: Terengganu

tool: D25: Kuala Lumpur

tool: D106: Labuan

tool: D17: Sabah

tool: D132: Putrajaya

tool: D102: Johor

assistant: ```c
const char *get_region_name_MY(int region_code) {
  switch (region_code) {
  case 1:
    return "Johor";
  case 2:
    return "Kedah";
  case 3:
    return "Kelantan";
  case 4:
    return "Melaka";
  case 5:
    return "Negeri Sembilan";
  case 6:
    return "Pahang";
  case 7:
    return "Perak";
  case 8:
    return "Perlis";
  case 9:
    return "Pulau Pinang";
  case 11:
    return "Sarawak";
  case 12:
    return "Selangor";
  case 13:
    return "Terengganu";
  case 14:
    return "Kuala Lumpur";
  case 15:
    return "Labuan";
  case 16:
    return "Sabah";
  case 17:
    return "Putrajaya";
  default:
    return NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_field>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  mov    %eax,(%rsi)
  cmp    $0x9,%eax
  ja     L55
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    $0x41,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L157
  movl   $0x0,0x0(%rbp)
  mov    $0x1,%eax
L124:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L124
L157:
  mov    $0x42,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L36
  movl   $0x1,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L36:
  mov    $0x43,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L66
  movl   $0x2,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L66:
  mov    $0x44,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  movl   $0x3,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L19:
  mov    $0x45,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L56
  movl   $0x4,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L56:
  mov    $0x46,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L115
  movl   $0x5,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L115:
  mov    $0x47,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  movl   $0x6,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L7:
  mov    $0x48,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L26
  movl   $0x7,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L26:
  mov    $0x49,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L47
  movl   $0x8,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L47:
  mov    $0x4a,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L177
  movl   $0x9,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L124
L177:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L124
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: Bledne pole - podaj od A0 do J9.


assistant: ```c
int parse_field(char *bufor, int *x, int *y) {
  *x = bufor[1] - 48;
  if (!(*x < 10 && *x >= 0)) {
    printf("Bledne pole - podaj od A0 do J9.\n");
    return 0;
  }
  if (strstr(bufor, "A") != NULL) {
    *y = 0;
  } else if (strstr(bufor, "B") != NULL) {
    *y = 1;
  } else if (strstr(bufor, "C") != NULL) {
    *y = 2;
  } else if (strstr(bufor, "D") != NULL) {
    *y = 3;
  } else if (strstr(bufor, "E") != NULL) {
    *y = 4;
  } else if (strstr(bufor, "F") != NULL) {
    *y = 5;
  } else if (strstr(bufor, "G") != NULL) {
    *y = 6;
  } else if (strstr(bufor, "H") != NULL) {
    *y = 7;
  } else if (strstr(bufor, "I") != NULL) {
    *y = 8;
  } else if (strstr(bufor, "J") != NULL) {
    *y = 9;
  } else {
    printf("Bledne pole - podaj od A0 do J9.\n");
    return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_field>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  mov    %eax,(%rsi)
  cmp    $0x9,%eax
  ja     L90
  mov    $0x41,%esi
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L127
  movl   $0x0,(%rbx)
  mov    $0x1,%eax
L75:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L127:
  mov    $0x42,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L151
  movl   $0x1,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L90:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L151:
  mov    $0x43,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L171
  movl   $0x2,(%rbx)
  mov    $0x1,%eax
  jmp    L75
  nop
L171:
  mov    $0x44,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L26
  movl   $0x3,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L26:
  mov    $0x45,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L152
  movl   $0x4,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L152:
  mov    $0x46,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L82
  movl   $0x5,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L82:
  mov    $0x47,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L177
  movl   $0x6,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L177:
  mov    $0x48,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L11
  movl   $0x7,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L11:
  mov    $0x49,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L65
  movl   $0x8,(%rbx)
  mov    $0x1,%eax
  jmp    L75
L65:
  mov    $0x4a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L90
  movl   $0x9,(%rbx)
  mov    $0x1,%eax
  jmp    L75
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: Bledne pole - podaj od A0 do J9.


assistant: ```c
int parse_field(char *bufor, int *x, int *y) {
  *x = bufor[1] - 48;
  if (!(*x < 10 && *x >= 0)) {
    printf("Bledne pole - podaj od A0 do J9.\n");
    return 0;
  }
  if (strstr(bufor, "A") != NULL) {
    *y = 0;
  } else if (strstr(bufor, "B") != NULL) {
    *y = 1;
  } else if (strstr(bufor, "C") != NULL) {
    *y = 2;
  } else if (strstr(bufor, "D") != NULL) {
    *y = 3;
  } else if (strstr(bufor, "E") != NULL) {
    *y = 4;
  } else if (strstr(bufor, "F") != NULL) {
    *y = 5;
  } else if (strstr(bufor, "G") != NULL) {
    *y = 6;
  } else if (strstr(bufor, "H") != NULL) {
    *y = 7;
  } else if (strstr(bufor, "I") != NULL) {
    *y = 8;
  } else if (strstr(bufor, "J") != NULL) {
    *y = 9;
  } else {
    printf("Bledne pole - podaj od A0 do J9.\n");
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_field>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  mov    %eax,(%rsi)
  cmp    $0x9,%eax
  ja     L177
  mov    $0x41,%esi
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L150
  movl   $0x0,(%rbx)
  mov    $0x1,%eax
L128:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L150:
  mov    $0x42,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L148
  movl   $0x1,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L177:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L148:
  mov    $0x43,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L186
  movl   $0x2,(%rbx)
  mov    $0x1,%eax
  jmp    L128
  nop
L186:
  mov    $0x44,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L72
  movl   $0x3,(%rbx)
  mov    $0x1,%eax
  jmp    L128
L72:
  mov    $0x45,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L156
  movl   $0x4,(%rbx)
  mov    $0x1,%eax
  jmp    L128
L156:
  mov    $0x46,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L35
  movl   $0x5,(%rbx)
  mov    $0x1,%eax
  jmp    L128
L35:
  mov    $0x47,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L116
  movl   $0x6,(%rbx)
  mov    $0x1,%eax
  jmp    L128
L116:
  mov    $0x48,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L41
  movl   $0x7,(%rbx)
  mov    $0x1,%eax
  jmp    L128
L41:
  mov    $0x49,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L180
  movl   $0x8,(%rbx)
  mov    $0x1,%eax
  jmp    L128
L180:
  mov    $0x4a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L177
  movl   $0x9,(%rbx)
  mov    $0x1,%eax
  jmp    L128
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: Bledne pole - podaj od A0 do J9.


assistant: ```c
int parse_field(char *bufor, int *x, int *y) {
  *x = bufor[1] - 48;
  if (!(*x < 10 && *x >= 0)) {
    printf("Bledne pole - podaj od A0 do J9.\n");
    return 0;
  }
  if (strstr(bufor, "A") != NULL) {
    *y = 0;
  } else if (strstr(bufor, "B") != NULL) {
    *y = 1;
  } else if (strstr(bufor, "C") != NULL) {
    *y = 2;
  } else if (strstr(bufor, "D") != NULL) {
    *y = 3;
  } else if (strstr(bufor, "E") != NULL) {
    *y = 4;
  } else if (strstr(bufor, "F") != NULL) {
    *y = 5;
  } else if (strstr(bufor, "G") != NULL) {
    *y = 6;
  } else if (strstr(bufor, "H") != NULL) {
    *y = 7;
  } else if (strstr(bufor, "I") != NULL) {
    *y = 8;
  } else if (strstr(bufor, "J") != NULL) {
    *y = 9;
  } else {
    printf("Bledne pole - podaj od A0 do J9.\n");
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a + 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a + 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a + 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x2,-0x8(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x4,-0x1c(%rbp)
  jmp    L16
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L16:
  cmpl   $0x64,-0x1c(%rbp)
  jle    L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string

tool: D5: %llu
%llu
%llu


tool: D10: %llu


assistant: ```c
int main() {
  unsigned long long a, b, c;
  int i;
  a = 2;
  b = 1;
  c = a + b;
  printf("%llu\n%llu\n%llu\n", a, b, c);
  for (i = 4; i <= 100; i++) {
    a = b;
    b = c;
    c = a + b;
    printf("%llu\n", c);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x61,%ebp
  mov    $0x3,%ebx
  mov    $0x1,%eax
  lea    D3(%rip),%r13
L7:
  mov    %rbx,%r12
  add    %rax,%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x1,%ebp
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D13: %llu
%llu
%llu


tool: D3: %llu


assistant: ```c
int main() {
  unsigned long long a, b, c;
  int i;
  a = 2;
  b = 1;
  c = a + b;
  printf("%llu\n%llu\n%llu\n", a, b, c);
  for (i = 4; i <= 100; i++) {
    a = b;
    b = c;
    c = a + b;
    printf("%llu\n", c);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%ecx
  mov    $0x1,%edx
  xor    %eax,%eax
  push   %r12
  mov    $0x2,%esi
  lea    D13(%rip),%rdi
  lea    D11(%rip),%r13
  push   %rbp
  mov    $0x61,%ebp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%eax
  nopl   0x0(%rax)
L2:
  mov    %rbx,%r12
  add    %rax,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x1,%ebp
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D11
type_infered: string

tool: D13: %llu
%llu
%llu


tool: D11: %llu


assistant: ```c
int main() {
  unsigned long long a, b, c;
  int i;
  a = 2;
  b = 1;
  c = a + b;
  printf("%llu\n%llu\n%llu\n", a, b, c);
  for (i = 4; i <= 100; i++) {
    a = b;
    b = c;
    c = a + b;
    printf("%llu\n", c);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%ecx
  mov    $0x1,%edx
  xor    %eax,%eax
  push   %r12
  mov    $0x2,%esi
  lea    D14(%rip),%rdi
  lea    D13(%rip),%r13
  push   %rbp
  mov    $0x61,%ebp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%eax
  nopl   0x0(%rax)
L3:
  mov    %rbx,%r12
  add    %rax,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x1,%ebp
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D14: %llu
%llu
%llu


tool: D13: %llu


assistant: ```c
int main() {
  unsigned long long a, b, c;
  int i;
  a = 2;
  b = 1;
  c = a + b;
  printf("%llu\n%llu\n%llu\n", a, b, c);
  for (i = 4; i <= 100; i++) {
    a = b;
    b = c;
    c = a + b;
    printf("%llu\n", c);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<r_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L16
  mov    D4(%rip),%rax
  mov    (%rax),%rdx
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L18
L16:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L16:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  jne    L14
  mov    D9(%rip),%rcx
  mov    D16(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L16
L14:
  pop    %rbx
  ret
```

assistant: ```c
r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L11:
  mov    D11(%rip),%rdx
  mov    D18(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L27
L5:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L11
L27:
  pop    %rbx
  ret
```

assistant: ```c
r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L6:
  mov    D13(%rip),%rdx
  mov    D8(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L0
L25:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L6
L0:
  pop    %rbx
  ret
```

assistant: ```c
r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str2enum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x38(%rbp)
L69:
  mov    -0x48(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L96
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L35
  subq   $0x2,-0x38(%rbp)
  jmp    L34
L27:
  subq   $0x1,-0x38(%rbp)
L34:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L1
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L27
L1:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L84
L35:
  nop
  addq   $0x1,-0x38(%rbp)
  jmp    L69
L96:
  nop
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L58
  mov    -0x58(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L84
L58:
  mov    $0x0,%eax
L84:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string

tool: D15: %d

tool: D7: %30.30s:

assistant: ```c
int str2enum(const char *str, const char *comment, int *val) {
  const char *p;
  char s[32];
  for (p = comment;; p++) {
    if (!(p = strstr(p, str)))
      break;
    if (*(p - 1) != ':')
      continue;
    for (p -= 2; '0' <= *p && *p <= '9'; p--)
      ;
    return sscanf(p + 1, "%d", val) == 1;
  }
  sprintf(s, "%30.30s:", str);
  if ((p = strstr(comment, s))) {
    return sscanf(p, "%d", val) == 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str2enum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
L77:
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L13
  cmpb   $0x3a,-0x1(%rax)
  jne    L59
  lea    -0x2(%rax),%rdi
  movzbl -0x2(%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L50
L67:
  sub    $0x1,%rdi
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L67
L50:
  add    $0x1,%rdi
  mov    %rbx,%rdx
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L33:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  lea    0x1(%rax),%rdi
  jmp    L77
L13:
  mov    %rsp,%r13
  mov    %rbp,%rdx
  lea    D25(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L33
  mov    %rbx,%rdx
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L33
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D25
data_type: string

tool: D3: %d

tool: D25: %30.30s:

assistant: ```c
int str2enum(const char *str, const char *comment, int *val) {
  const char *p;
  char s[32];
  for (p = comment;; p++) {
    if (!(p = strstr(p, str)))
      break;
    if (*(p - 1) != ':')
      continue;
    for (p -= 2; '0' <= *p && *p <= '9'; p--)
      ;
    return sscanf(p + 1, "%d", val) == 1;
  }
  sprintf(s, "%30.30s:", str);
  if ((p = strstr(comment, s))) {
    return sscanf(p, "%d", val) == 1;
  }
  return 0;
}
```