ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<diff_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += fabs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<diff_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L26
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %edi,%ebp
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
L3:
  movsd  (%r12,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
L15:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L15
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += fabs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<diff_buffer>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L13:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L13
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += fabs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<diff_buffer>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L5:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L5
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += fabs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test(argc);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test(argc);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test(argc);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test(argc);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prompt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: %s


assistant: ```c
int prompt(char *msg) {
  int retValue_acc;
  int retval;
  char const *__restrict __cil_tmp4;
  {
    {
      __cil_tmp4 = (char const *__restrict)"%s\n";
      printf(__cil_tmp4, msg);
      retValue_acc = retval;
    }
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<prompt>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: %s


assistant: ```c
int prompt(char *msg) {
  int retValue_acc;
  int retval;
  char const *__restrict __cil_tmp4;
  {
    {
      __cil_tmp4 = (char const *__restrict)"%s\n";
      printf(__cil_tmp4, msg);
      retValue_acc = retval;
    }
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prompt>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %s


assistant: ```c
int prompt(char *msg) {
  int retValue_acc;
  int retval;
  char const *__restrict __cil_tmp4;
  {
    {
      __cil_tmp4 = (char const *__restrict)"%s\n";
      printf(__cil_tmp4, msg);
      retValue_acc = retval;
    }
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prompt>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %s


assistant: ```c
int prompt(char *msg) {
  int retValue_acc;
  int retval;
  char const *__restrict __cil_tmp4;
  {
    {
      __cil_tmp4 = (char const *__restrict)"%s\n";
      printf(__cil_tmp4, msg);
      retValue_acc = retval;
    }
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Concat_Definition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: struct Concat {
  void (*concat)(var, var);
  void (*append)(var, var);
};


assistant: ```c
const char *Concat_Definition(void) {
  return "struct Concat {\n"
         "  void (*concat)(var, var);\n"
         "  void (*append)(var, var);\n"
         "};\n";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Concat_Definition>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: struct Concat {
  void (*concat)(var, var);
  void (*append)(var, var);
};


assistant: ```c
const char *Concat_Definition(void) {
  return "struct Concat {\n"
         "  void (*concat)(var, var);\n"
         "  void (*append)(var, var);\n"
         "};\n";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Concat_Definition>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: struct Concat {
  void (*concat)(var, var);
  void (*append)(var, var);
};


assistant: ```c
const char *Concat_Definition(void) {
  return "struct Concat {\n"
         "  void (*concat)(var, var);\n"
         "  void (*append)(var, var);\n"
         "};\n";
}
```
user: What is the c source code of the assembly code below:

```asm
<Concat_Definition>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: struct Concat {
  void (*concat)(var, var);
  void (*append)(var, var);
};


assistant: ```c
const char *Concat_Definition(void) {
  return "struct Concat {\n"
         "  void (*concat)(var, var);\n"
         "  void (*append)(var, var);\n"
         "};\n";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <g@plt>
  leave
  ret
```

assistant: ```c
main() {
  if (0) {
    int i;
    f();
  a:
    i = 2;
    return g(i);
  }
  goto a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <g@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  if (0) {
    int i;
    f();
  a:
    i = 2;
    return g(i);
  }
  goto a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x2,%edi
  jmp    1050 <g@plt>
```

assistant: ```c
main() {
  if (0) {
    int i;
    f();
  a:
    i = 2;
    return g(i);
  }
  goto a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2,%edi
  jmp    1050 <g@plt>
```

assistant: ```c
main() {
  if (0) {
    int i;
    f();
  a:
    i = 2;
    return g(i);
  }
  goto a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <isp1362_probe@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  isp1362_probe();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <isp1362_probe@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  isp1362_probe();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <isp1362_probe@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  isp1362_probe();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <isp1362_probe@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  isp1362_probe();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glmGenerateConjugateQuaterniond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movq   D26(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movq   D26(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movq   D26(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
type_infered: byte[8]

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaterniond(double result[4], const double q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmGenerateConjugateQuaterniond>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x18(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaterniond(double result[4], const double q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<glmGenerateConjugateQuaterniond>:
  endbr64
  movsd  (%rsi),%xmm0
  movq   D1(%rip),%xmm1
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x18(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaterniond(double result[4], const double q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glmGenerateConjugateQuaterniond>:
  endbr64
  movsd  (%rsi),%xmm0
  movq   D7(%rip),%xmm1
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x18(%rsi),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaterniond(double result[4], const double q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<OnePointIteration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x64,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L38
L37:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <TheFunction@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   D5(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L36
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  jmp    L35
L36:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L37
L35:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: qword
name: unpack_data
arguments: label: D14
type_guessed: f64

tool: D5: 9223372036854775807

tool: D14: 0.0001

assistant: ```c
double OnePointIteration(double x) {
  int maxIterationNumber = 100, n = 1;
  double xNext;
  while (n <= maxIterationNumber) {
    xNext = TheFunction(x);
    if (fabs((xNext - x) / xNext) < 0.0001) {
      return xNext;
    } else {
      x = xNext;
    }
    ++n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OnePointIteration>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebx
L15:
  movq   %xmm0,%r14
  call   <TheFunction@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  andpd  D11(%rip),%xmm1
  movsd  D12(%rip),%xmm3
  comisd %xmm1,%xmm3
  ja     L19
  sub    $0x1,%ebx
  jne    L15
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: qword[2]
name: retrieve_data
arguments: tag: D12
type_guessed: f64

tool: {"D11": [0x7fffffffffffffff,0x0000000000000000]}

tool: D12: 0.0001

assistant: ```c
double OnePointIteration(double x) {
  int maxIterationNumber = 100, n = 1;
  double xNext;
  while (n <= maxIterationNumber) {
    xNext = TheFunction(x);
    if (fabs((xNext - x) / xNext) < 0.0001) {
      return xNext;
    } else {
      x = xNext;
    }
    ++n;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OnePointIteration>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x10,%rsp
  jmp    L24
L2:
  sub    $0x1,%ebx
  je     L18
L24:
  movsd  %xmm0,0x8(%rsp)
  call   <TheFunction@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  D7(%rip),%xmm3
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  andpd  D2(%rip),%xmm1
  comisd %xmm1,%xmm3
  jbe    L2
L18:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: f64
name: extract_symbolic_data
arguments: label: D2
type: qword[2]

tool: D7: 0.0001

tool: {"D2": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double OnePointIteration(double x) {
  int maxIterationNumber = 100, n = 1;
  double xNext;
  while (n <= maxIterationNumber) {
    xNext = TheFunction(x);
    if (fabs((xNext - x) / xNext) < 0.0001) {
      return xNext;
    } else {
      x = xNext;
    }
    ++n;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<OnePointIteration>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x10,%rsp
  jmp    L11
L0:
  sub    $0x1,%ebx
  je     L25
L11:
  movsd  %xmm0,0x8(%rsp)
  call   <TheFunction@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  D1(%rip),%xmm3
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  andpd  D19(%rip),%xmm1
  comisd %xmm1,%xmm3
  jbe    L0
L25:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: f64
name: read_data
arguments: label: D19
datatype: qword[2]

tool: D1: 0.0001

tool: {"D19": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double OnePointIteration(double x) {
  int maxIterationNumber = 100, n = 1;
  double xNext;
  while (n <= maxIterationNumber) {
    xNext = TheFunction(x);
    if (fabs((xNext - x) / xNext) < 0.0001) {
      return xNext;
    } else {
      x = xNext;
    }
    ++n;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LEN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L5:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int LEN(const char *str) {
  const char *s;
  for (s = str; *s; ++s)
    ;
  return (s - str);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<LEN>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %rdi,%rax
L14:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
L6:
  sub    %edi,%eax
  ret
L23:
  mov    %rdi,%rax
  jmp    L6
```

assistant: ```c
int LEN(const char *str) {
  const char *s;
  for (s = str; *s; ++s)
    ;
  return (s - str);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LEN>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    %rdi,%rax
  nopl   0x0(%rax)
L6:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L6
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int LEN(const char *str) {
  const char *s;
  for (s = str; *s; ++s)
    ;
  return (s - str);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LEN>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    %rdi,%rax
  nopl   0x0(%rax)
L7:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L7
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int LEN(const char *str) {
  const char *s;
  for (s = str; *s; ++s)
    ;
  return (s - str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7a1000(%rsp),%r11
L111:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L111
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7a1218(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L130
  mov    $0x0,%r12d
  lea    0xc(%rsp),%r13
  lea    D23(%rip),%rbx
  lea    D2(%rip),%rbp
  jmp    L155
L35:
  mov    %eax,(%rcx)
L82:
  sub    $0x8,%rcx
  sub    $0x1,%edx
  js     L145
L68:
  mov    0x4(%rcx),%eax
  add    (%rcx),%eax
  cmp    $0x9,%eax
  jle    L35
  sub    $0xa,%eax
  mov    %eax,(%rcx)
  lea    -0x1(%rdx),%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,8)
  jmp    L82
L145:
  cmpl   $0x0,0xc(%rsp)
  jle    L74
  mov    $0x0,%r14d
L66:
  mov    0x10(%rsp,%r14,8),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r14
  cmp    %r14d,0xc(%rsp)
  jg     L66
L74:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jg     L20
L57:
  add    $0x1,%r12d
  cmp    %r12d,0x8(%rsp)
  jle    L130
L155:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L74
  lea    0x10(%rsp),%r14
  mov    $0x0,%r15d
L101:
  lea    0x4(%r14),%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%r15d
  mov    0xc(%rsp),%edx
  add    $0x8,%r14
  cmp    %r15d,%edx
  jg     L101
  sub    $0x1,%edx
  js     L145
  movslq %edx,%rax
  lea    0x10(%rsp,%rax,8),%rcx
  jmp    L68
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L57
L130:
  mov    0x7a1218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0x7a1228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D23: %d

tool: D2: %d %d

assistant: ```c
int main() {
  int i, j, n, m, sum, a[1000000][2];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &m);
    for (j = 0; j < m; j++)
      scanf("%d %d", &a[j][0], &a[j][1]);
    for (j = m - 1; j >= 0; j--) {
      sum = a[j][0] + a[j][1];
      if (sum >= 10) {
        a[j][0] = sum - 10;
        a[j - 1][0]++;
      } else
        a[j][0] = sum;
    }
    for (j = 0; j < m; j++)
      printf("%d", a[j][0]);
    printf("\n");
    if (i < n - 1)
      printf("\n");
  }
  return 0;
}
```