ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetLastChar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl %sil,%ebx
  mov    %ebx,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
L16:
  lea    0x1(%rax),%rdi
  mov    %rax,%rbp
  mov    %ebx,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L16
L12:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rax,%rbp
  jmp    L12
```

assistant: ```c
const char *GetLastChar(const char *path, char sep) {
  const char *p = strchr(path, sep);
  const char *prev = p;
  while (p) {
    prev = p;
    p = strchr(p + 1, sep);
  }
  return prev;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GetLastChar>:
  endbr64
  push   %r12
  push   %rbx
  movsbl %sil,%ebx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L4
  nopl   0x0(%rax,%rax,1)
L10:
  lea    0x1(%rax),%rdi
  mov    %ebx,%esi
  mov    %rax,%r12
  call   <strchr@plt>
  test   %rax,%rax
  jne    L10
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *GetLastChar(const char *path, char sep) {
  const char *p = strchr(path, sep);
  const char *prev = p;
  while (p) {
    prev = p;
    p = strchr(p + 1, sep);
  }
  return prev;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetLastChar>:
  endbr64
  push   %r12
  push   %rbx
  movsbl %sil,%ebx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  nopl   0x0(%rax,%rax,1)
L9:
  lea    0x1(%rax),%rdi
  mov    %ebx,%esi
  mov    %rax,%r12
  call   <strchr@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *GetLastChar(const char *path, char sep) {
  const char *p = strchr(path, sep);
  const char *prev = p;
  while (p) {
    prev = p;
    p = strchr(p + 1, sep);
  }
  return prev;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<builtin_lt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  ja     L70
  mov    $0x0,%eax
  call   <push_nil@plt>
  jmp    L61
L70:
  movl   $0x1,-0x14(%rbp)
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  mov    %rax,-0x10(%rbp)
  subl   $0x1,-0x2c(%rbp)
  jmp    L12
L38:
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L65
  subl   $0x1,-0x14(%rbp)
  jmp    L63
L65:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  subl   $0x1,-0x2c(%rbp)
L12:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L38
L63:
  cmpl   $0x0,-0x14(%rbp)
  je     L43
  mov    $0x0,%eax
  call   <push_t@plt>
  jmp    L61
L43:
  mov    $0x0,%eax
  call   <push_nil@plt>
L61:
  leave
  ret
```

assistant: ```c
void builtin_lt(struct Context *ctx, unsigned int stack_track) {
  if (stack_track < 2) {
    push_nil();
    return;
  }
  unsigned int result = 1;
  long previous = pop_to_long(), current;
  for (stack_track--; stack_track; stack_track--) {
    current = pop_to_long();
    if (previous >= current) {
      result--;
      break;
    }
    previous = current;
  }
  if (result)
    push_t();
  else
    push_nil();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<builtin_lt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jbe    L20
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  sub    $0x1,%ebx
L49:
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  cmp    %rbp,%rax
  jle    L22
  sub    $0x1,%ebx
  jne    L49
  mov    $0x0,%eax
  call   <push_t@plt>
  jmp    L5
L20:
  mov    $0x0,%eax
  call   <push_nil@plt>
  jmp    L5
L22:
  mov    $0x0,%eax
  call   <push_nil@plt>
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void builtin_lt(struct Context *ctx, unsigned int stack_track) {
  if (stack_track < 2) {
    push_nil();
    return;
  }
  unsigned int result = 1;
  long previous = pop_to_long(), current;
  for (stack_track--; stack_track; stack_track--) {
    current = pop_to_long();
    if (previous >= current) {
      result--;
      break;
    }
    previous = current;
  }
  if (result)
    push_t();
  else
    push_nil();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<builtin_lt>:
  endbr64
  cmp    $0x1,%esi
  jbe    L6
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x8,%rsp
  call   <pop_to_long@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <pop_to_long@plt>
  cmp    %rbp,%rax
  jle    L25
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <push_t@plt>
  nopl   0x0(%rax)
L25:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1090 <push_nil@plt>
  nopl   (%rax)
L6:
  xor    %eax,%eax
  jmp    1090 <push_nil@plt>
```

assistant: ```c
void builtin_lt(struct Context *ctx, unsigned int stack_track) {
  if (stack_track < 2) {
    push_nil();
    return;
  }
  unsigned int result = 1;
  long previous = pop_to_long(), current;
  for (stack_track--; stack_track; stack_track--) {
    current = pop_to_long();
    if (previous >= current) {
      result--;
      break;
    }
    previous = current;
  }
  if (result)
    push_t();
  else
    push_nil();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<builtin_lt>:
  endbr64
  cmp    $0x1,%esi
  jbe    L29
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x8,%rsp
  call   <pop_to_long@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <pop_to_long@plt>
  cmp    %rbp,%rax
  jle    L8
  sub    $0x1,%ebx
  jne    L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <push_t@plt>
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1090 <push_nil@plt>
  nopl   (%rax)
L29:
  xor    %eax,%eax
  jmp    1090 <push_nil@plt>
```

assistant: ```c
void builtin_lt(struct Context *ctx, unsigned int stack_track) {
  if (stack_track < 2) {
    push_nil();
    return;
  }
  unsigned int result = 1;
  long previous = pop_to_long(), current;
  for (stack_track--; stack_track; stack_track--) {
    current = pop_to_long();
    if (previous >= current) {
      result--;
      break;
    }
    previous = current;
  }
  if (result)
    push_t();
  else
    push_nil();
}
```
user: Translate the below assembly code into C programming language:

```asm
<indexxd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L29
  mov    $0xffffffffffffffff,%rax
  jmp    L98
L29:
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jb     L22
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  jmp    L98
L22:
  movq   $0x0,-0x10(%rbp)
  cmpq   $0xa,-0x28(%rbp)
  jle    L34
  mov    -0x28(%rbp),%rax
  sar    %rax
  mov    %rax,-0x8(%rbp)
  jmp    L69
L81:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jge    L27
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L81
L27:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x10(%rbp)
  sarq   -0x8(%rbp)
L69:
  cmpq   $0x5,-0x8(%rbp)
  jg     L46
  jmp    L34
L26:
  addq   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jge    L43
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L26
L43:
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
L98:
  pop    %rbp
  ret
```

assistant: ```c
long indexxd(double x0, double *x, long n) {
  long i, delta;
  if (x0 < x[0])
    return (-1);
  if (x0 >= x[n - 1])
    return (n - 1);
  i = 0;
  if (n > 10) {
    delta = n >> 1;
    while (delta > 5) {
      for (; i < n && x0 >= x[i]; i += delta)
        ;
      i -= delta;
      delta >>= 1;
    }
  }
  for (; i < n && x0 >= x[i]; i++)
    ;
  return (i - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<indexxd>:
  endbr64
  movsd  (%rdi),%xmm1
  comisd %xmm0,%xmm1
  ja     L11
  lea    -0x1(%rsi),%rax
  comisd -0x8(%rdi,%rsi,8),%xmm0
  jae    L2
  cmp    $0xa,%rsi
  jg     L3
  mov    $0x0,%eax
L129:
  cmp    %rax,%rsi
  jle    L60
L44:
  comisd (%rdi,%rax,8),%xmm0
  jb     L60
  add    $0x1,%rax
  cmp    %rax,%rsi
  jg     L44
L60:
  sub    $0x1,%rax
  ret
L3:
  mov    %rsi,%rdx
  sar    %rdx
  mov    $0x0,%eax
  cmp    $0xb,%rsi
  jg     L99
  jmp    L44
L121:
  sub    %rdx,%rax
  sar    %rdx
  cmp    $0x5,%rdx
  jle    L129
L99:
  cmp    %rax,%rsi
  jle    L121
L72:
  comisd (%rdi,%rax,8),%xmm0
  jb     L121
  add    %rdx,%rax
  cmp    %rax,%rsi
  jg     L72
  jmp    L121
L11:
  mov    $0xffffffffffffffff,%rax
L2:
  ret
```

assistant: ```c
long indexxd(double x0, double *x, long n) {
  long i, delta;
  if (x0 < x[0])
    return (-1);
  if (x0 >= x[n - 1])
    return (n - 1);
  i = 0;
  if (n > 10) {
    delta = n >> 1;
    while (delta > 5) {
      for (; i < n && x0 >= x[i]; i += delta)
        ;
      i -= delta;
      delta >>= 1;
    }
  }
  for (; i < n && x0 >= x[i]; i++)
    ;
  return (i - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<indexxd>:
  endbr64
  movsd  (%rdi),%xmm1
  comisd %xmm0,%xmm1
  ja     L45
  comisd -0x8(%rdi,%rsi,8),%xmm0
  lea    -0x1(%rsi),%rax
  jae    L139
  cmp    $0xa,%rsi
  jg     L17
  xor    %eax,%eax
L138:
  cmp    %rax,%rsi
  jle    L58
  movsd  (%rdi,%rax,8),%xmm1
  jmp    L118
  xchg   %ax,%ax
L134:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rsi
  jle    L139
  movsd  (%rdi,%rdx,8),%xmm1
  mov    %rdx,%rax
L118:
  comisd %xmm1,%xmm0
  jae    L134
L58:
  sub    $0x1,%rax
  ret
L45:
  mov    $0xffffffffffffffff,%rax
L139:
  ret
  nopl   0x0(%rax)
L17:
  mov    %rsi,%rcx
  xor    %eax,%eax
  sar    %rcx
  cmp    $0x5,%rcx
  je     L118
  cs nopw 0x0(%rax,%rax,1)
L119:
  cmp    %rax,%rsi
  jg     L23
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L91:
  lea    (%rax,%rcx,1),%rdx
  cmp    %rdx,%rsi
  jle    L131
  mov    %rdx,%rax
L23:
  comisd (%rdi,%rax,8),%xmm0
  jae    L91
L18:
  sub    %rcx,%rax
L131:
  sar    %rcx
  cmp    $0x5,%rcx
  jg     L119
  jmp    L138
```

assistant: ```c
long indexxd(double x0, double *x, long n) {
  long i, delta;
  if (x0 < x[0])
    return (-1);
  if (x0 >= x[n - 1])
    return (n - 1);
  i = 0;
  if (n > 10) {
    delta = n >> 1;
    while (delta > 5) {
      for (; i < n && x0 >= x[i]; i += delta)
        ;
      i -= delta;
      delta >>= 1;
    }
  }
  for (; i < n && x0 >= x[i]; i++)
    ;
  return (i - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<indexxd>:
  endbr64
  movsd  (%rdi),%xmm1
  comisd %xmm0,%xmm1
  ja     L13
  comisd -0x8(%rdi,%rsi,8),%xmm0
  lea    -0x1(%rsi),%rax
  jae    L85
  cmp    $0xa,%rsi
  jle    L135
  mov    %rsi,%rcx
  xor    %eax,%eax
  sar    %rcx
  cmp    $0x5,%rcx
  je     L83
  xchg   %ax,%ax
L133:
  cmp    %rax,%rsi
  jg     L52
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L50:
  lea    (%rax,%rcx,1),%rdx
  cmp    %rdx,%rsi
  jle    L81
  mov    %rdx,%rax
L52:
  comisd (%rdi,%rax,8),%xmm0
  jae    L50
L88:
  sub    %rcx,%rax
L81:
  sar    %rcx
  cmp    $0x5,%rcx
  jg     L133
  jmp    L123
L13:
  mov    $0xffffffffffffffff,%rax
L85:
  ret
  nopl   0x0(%rax)
L135:
  xor    %eax,%eax
L123:
  cmp    %rax,%rsi
  jg     L83
  jmp    L89
  nopl   0x0(%rax)
L73:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rsi
  jle    L85
  mov    %rdx,%rax
L83:
  comisd (%rdi,%rax,8),%xmm0
  jae    L73
L89:
  sub    $0x1,%rax
  ret
```

assistant: ```c
long indexxd(double x0, double *x, long n) {
  long i, delta;
  if (x0 < x[0])
    return (-1);
  if (x0 >= x[n - 1])
    return (n - 1);
  i = 0;
  if (n > 10) {
    delta = n >> 1;
    while (delta > 5) {
      for (; i < n && x0 >= x[i]; i += delta)
        ;
      i -= delta;
      delta >>= 1;
    }
  }
  for (; i < n && x0 >= x[i]; i++)
    ;
  return (i - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<libusb_cpu_to_le16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
uint16_t libusb_cpu_to_le16(uint16_t x) {
  union {
    uint8_t b8[2];
    uint16_t b16;
  } _tmp;
  uint16_t _tmp2 = (uint16_t)(x);
  _tmp.b8[1] = _tmp2 >> 8;
  _tmp.b8[0] = _tmp2 & 0xff;
  return _tmp.b16;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libusb_cpu_to_le16>:
  endbr64
  movzbl %dil,%eax
  ret
```

assistant: ```c
uint16_t libusb_cpu_to_le16(uint16_t x) {
  union {
    uint8_t b8[2];
    uint16_t b16;
  } _tmp;
  uint16_t _tmp2 = (uint16_t)(x);
  _tmp.b8[1] = _tmp2 >> 8;
  _tmp.b8[0] = _tmp2 & 0xff;
  return _tmp.b16;
}
```
user: What is the c source code of the assembly code below:

```asm
<libusb_cpu_to_le16>:
  endbr64
  movzbl %dil,%eax
  ret
```

assistant: ```c
uint16_t libusb_cpu_to_le16(uint16_t x) {
  union {
    uint8_t b8[2];
    uint16_t b16;
  } _tmp;
  uint16_t _tmp2 = (uint16_t)(x);
  _tmp.b8[1] = _tmp2 >> 8;
  _tmp.b8[0] = _tmp2 & 0xff;
  return _tmp.b16;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<libusb_cpu_to_le16>:
  endbr64
  movzbl %dil,%eax
  ret
```

assistant: ```c
uint16_t libusb_cpu_to_le16(uint16_t x) {
  union {
    uint8_t b8[2];
    uint16_t b16;
  } _tmp;
  uint16_t _tmp2 = (uint16_t)(x);
  _tmp.b8[1] = _tmp2 >> 8;
  _tmp.b8[0] = _tmp2 & 0xff;
  return _tmp.b16;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L2
L14:
  mov    -0x4(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int mod(int a, int b) {
  int r = a % b;
  return r < 0 ? r + b : r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  test   %edx,%edx
  mov    %edx,%eax
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int a, int b) {
  int r = a % b;
  return r < 0 ? r + b : r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int a, int b) {
  int r = a % b;
  return r < 0 ? r + b : r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int a, int b) {
  int r = a % b;
  return r < 0 ? r + b : r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_min_buf_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <__buf_size_arg_constraint_concrete@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void test_min_buf_size() {
  char buf[9];
  __buf_size_arg_constraint_concrete(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_min_buf_size>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rdi
  call   <__buf_size_arg_constraint_concrete@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_min_buf_size() {
  char buf[9];
  __buf_size_arg_constraint_concrete(buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_min_buf_size>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rdi
  call   <__buf_size_arg_constraint_concrete@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_min_buf_size() {
  char buf[9];
  __buf_size_arg_constraint_concrete(buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_min_buf_size>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rdi
  call   <__buf_size_arg_constraint_concrete@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_min_buf_size() {
  char buf[9];
  __buf_size_arg_constraint_concrete(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<____atomic_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  not    %rax
  and    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ____atomic_clear_bit(unsigned int bit, unsigned long *p) {
  unsigned long flags;
  unsigned long mask;
  unsigned long temp;
  mask = 1UL << (bit & 31U);
  p += bit >> 5;
  (*p) &= (unsigned long)(~mask);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<____atomic_clear_bit>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  and    $0x1f,%ecx
  mov    $0xfffffffffffffffe,%rdx
  rol    %cl,%rdx
  and    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void ____atomic_clear_bit(unsigned int bit, unsigned long *p) {
  unsigned long flags;
  unsigned long mask;
  unsigned long temp;
  mask = 1UL << (bit & 31U);
  p += bit >> 5;
  (*p) &= (unsigned long)(~mask);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<____atomic_clear_bit>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  mov    $0xfffffffffffffffe,%rdx
  shr    $0x5,%eax
  and    $0x1f,%ecx
  rol    %cl,%rdx
  and    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void ____atomic_clear_bit(unsigned int bit, unsigned long *p) {
  unsigned long flags;
  unsigned long mask;
  unsigned long temp;
  mask = 1UL << (bit & 31U);
  p += bit >> 5;
  (*p) &= (unsigned long)(~mask);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<____atomic_clear_bit>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  mov    $0xfffffffffffffffe,%rdx
  shr    $0x5,%eax
  and    $0x1f,%ecx
  rol    %cl,%rdx
  and    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void ____atomic_clear_bit(unsigned int bit, unsigned long *p) {
  unsigned long flags;
  unsigned long mask;
  unsigned long temp;
  mask = 1UL << (bit & 31U);
  p += bit >> 5;
  (*p) &= (unsigned long)(~mask);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<keypress_pushapp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cpushapp@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <refocus@plt>
  nop
  leave
  ret
```

assistant: ```c
void keypress_pushapp(struct client *c, unsigned state, Time time) {
  cpushapp(c);
  refocus(time);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<keypress_pushapp>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <cpushapp@plt>
  mov    %ebx,%edi
  call   <refocus@plt>
  pop    %rbx
  ret
```

assistant: ```c
void keypress_pushapp(struct client *c, unsigned state, Time time) {
  cpushapp(c);
  refocus(time);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<keypress_pushapp>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <cpushapp@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <refocus@plt>
```

assistant: ```c
void keypress_pushapp(struct client *c, unsigned state, Time time) {
  cpushapp(c);
  refocus(time);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<keypress_pushapp>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <cpushapp@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <refocus@plt>
```

assistant: ```c
void keypress_pushapp(struct client *c, unsigned state, Time time) {
  cpushapp(c);
  refocus(time);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L17:
  nop
L69:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L69
  jmp    L24
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L56
L24:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L0
  jmp    L11
L56:
  nop
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L45
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L17
L45:
  nop
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int *a, int l, int r) {
  int v;
  int t;
  int i, j;
  i = l - 1;
  j = r;
  v = a[r];
  while (1) {
    while (a[++i] < v)
      ;
    while (a[--j] > v) {
      if (j == l)
        break;
    }
    if (i >= j)
      break;
    {
      (t) = (a[i]);
      (a[i]) = (a[j]);
      (a[j]) = (t);
    };
  }
  {
    (t) = (a[i]);
    (a[i]) = (a[r]);
    (a[r]) = (t);
  };
  return (i);
}
```