user: 下面的汇编指令对应的C源代码是什么:

```asm
<execute_regex>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x28(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %rbp,%rsi
  xor    %r8d,%r8d
  mov    %r12,%rcx
  mov    $0x5,%edx
  mov    %r13,%rdi
  call   <regexec@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  je     L132
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
L90:
  mov    (%rdi),%ecx
  cmp    $0xffffffff,%ecx
  je     L35
  mov    0x4(%rdi),%r8d
  cmp    %r8d,%ecx
  jge    L63
  movslq %ecx,%rax
  mov    %r8d,%esi
  mov    %r14,%r9
  lea    0x1(%r15,%rax,1),%r10
  sub    %ecx,%esi
  sub    %r10,%r9
  lea    -0x1(%rsi),%edx
  cmp    $0xe,%r9
  jbe    L205
  cmp    $0x6,%edx
  jbe    L205
  cmp    $0xe,%edx
  jbe    L77
  mov    %esi,%r9d
  lea    (%r15,%rax,1),%rdx
  xor    %eax,%eax
  shr    $0x4,%r9d
  shl    $0x4,%r9
  nopl   0x0(%rax,%rax,1)
L139:
  movdqu (%rdx,%rax,1),%xmm0
  movups %xmm0,(%r14,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L139
  mov    %esi,%r9d
  and    $0xfffffff0,%r9d
  mov    %r9d,%r10d
  add    %r9d,%ecx
  cmp    %r9d,%esi
  je     L160
  mov    %esi,%r11d
  sub    %r9d,%r11d
  lea    -0x1(%r11),%eax
  cmp    $0x6,%eax
  jbe    L159
L218:
  mov    (%rdx,%r9,1),%rax
  mov    %rax,(%r14,%r9,1)
  mov    %r11d,%eax
  and    $0xfffffff8,%eax
  add    %eax,%r10d
  add    %eax,%ecx
  cmp    %eax,%r11d
  je     L160
L159:
  movslq %ecx,%rax
  movzbl (%r15,%rax,1),%edx
  movslq %r10d,%rax
  mov    %dl,(%r14,%rax,1)
  lea    0x1(%rcx),%eax
  lea    0x1(%r10),%edx
  cmp    %eax,%r8d
  jle    L160
  cltq
  movslq %edx,%rdx
  movzbl (%r15,%rax,1),%eax
  mov    %al,(%r14,%rdx,1)
  lea    0x2(%rcx),%eax
  lea    0x2(%r10),%edx
  cmp    %eax,%r8d
  jle    L160
  cltq
  movslq %edx,%rdx
  movzbl (%r15,%rax,1),%eax
  mov    %al,(%r14,%rdx,1)
  lea    0x3(%rcx),%eax
  lea    0x3(%r10),%edx
  cmp    %eax,%r8d
  jle    L160
  cltq
  movslq %edx,%rdx
  movzbl (%r15,%rax,1),%eax
  mov    %al,(%r14,%rdx,1)
  lea    0x4(%rcx),%eax
  lea    0x4(%r10),%edx
  cmp    %eax,%r8d
  jle    L160
  cltq
  movslq %edx,%rdx
  movzbl (%r15,%rax,1),%eax
  mov    %al,(%r14,%rdx,1)
  lea    0x5(%rcx),%eax
  lea    0x5(%r10),%edx
  cmp    %eax,%r8d
  jle    L160
  cltq
  movslq %edx,%rdx
  add    $0x6,%r10d
  movzbl (%r15,%rax,1),%eax
  mov    %al,(%r14,%rdx,1)
  lea    0x6(%rcx),%eax
  cmp    %eax,%r8d
  jle    L160
  cltq
  movslq %r10d,%r10
  movzbl (%r15,%rax,1),%eax
  mov    %al,(%r14,%r10,1)
L160:
  movslq %esi,%rsi
  add    %r14,%rsi
L2:
  add    $0x8,%rdi
  movb   $0x0,(%rsi)
  cmp    %rbx,%rdi
  jne    L90
L35:
  movslq 0x4(%rsp),%rax
  add    %rax,%rbp
  jmp    L56
  cs nopw 0x0(%rax,%rax,1)
L205:
  mov    %r14,%rcx
  sub    %rax,%rcx
  cs nopw 0x0(%rax,%rax,1)
L6:
  movzbl (%r15,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L6
  jmp    L160
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %r14,%rsi
  jmp    L2
L77:
  mov    %esi,%r11d
  xor    %r9d,%r9d
  lea    (%r15,%rax,1),%rdx
  xor    %r10d,%r10d
  jmp    L218
L132:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L217
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L217:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: -%d-

assistant: ```c
void execute_regex(regex_t *reg, char *source, char *dest) {
  char *mpos = source;
  int match_count = 5;
  int i, k, j;
  regmatch_t result[match_count];
  while (1) {
    char *extract;
    int unmatched = regexec(reg, mpos, match_count, result, 0);
    if (unmatched == 1)
      break;
    printf("-%d-", unmatched);
    for (i = 0; i < match_count; i++) {
      int start;
      int finish;
      if (result[i].rm_so == -1)
        break;
      start = result[i].rm_so + (mpos - source);
      finish = result[i].rm_eo + (mpos - source);
      k = 0;
      for (j = result[i].rm_so; j < result[i].rm_eo; ++j) {
        dest[k] = source[j];
        k++;
      }
      dest[k] = '\0';
    }
    mpos += result[0].rm_eo;
  }
  return;
}
```