ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x5,%ebx
  mov    D21(%rip),%ebp
  mov    %ebp,0xc(%rsp)
  lea    D46(%rip),%r14
  lea    0x14(%rsp),%r13
  lea    D20(%rip),%r12
L2:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  addss  0x14(%rsp),%xmm1
  movss  %xmm1,0xc(%rsp)
  movd   %ebp,%xmm2
  addss  D34(%rip),%xmm2
  movd   %xmm2,%ebp
  sub    $0x1,%ebx
  jne    L2
  movaps %xmm1,%xmm0
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_guessed: f32
name: disassemble_data
arguments: data_label: D46
type_guessed: string
name: disassemble_data
arguments: data_label: D20
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D21: 0

tool: D46: Rentrez votre nombre :

tool: D20: %f

tool: {"D34": [0x00,0x00,0x80,0x3f]}

tool: D8: La moyenne est de %f

assistant: ```c
int main(int argc, char *argv[], char *env[]) {
  float M = 0, x, i;
  for (i = 0; i < 5; i++) {
    printf("Rentrez votre nombre :");
    scanf("%f", &x);
    M += x;
  }
  printf("La moyenne est de %f", (M / i));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm1,%xmm1
  lea    D4(%rip),%r13
  push   %r12
  movaps %xmm1,%xmm0
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
L16:
  mov    %r13,%rdi
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  addss  0x14(%rsp),%xmm0
  addss  D35(%rip),%xmm1
  sub    $0x1,%ebx
  jne    L16
  divss  %xmm1,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D35
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D24
type_guessed: string

tool: D4: Rentrez votre nombre :

tool: D17: %f

tool: {"D35": [0x00,0x00,0x80,0x3f]}

tool: D24: La moyenne est de %f

assistant: ```c
int main(int argc, char *argv[], char *env[]) {
  float M = 0, x, i;
  for (i = 0; i < 5; i++) {
    printf("Rentrez votre nombre :");
    scanf("%f", &x);
    M += x;
  }
  printf("La moyenne est de %f", (M / i));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm1,%xmm1
  lea    D15(%rip),%r13
  push   %r12
  movaps %xmm1,%xmm0
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
L0:
  mov    %r13,%rdi
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  addss  0x14(%rsp),%xmm0
  addss  D14(%rip),%xmm1
  sub    $0x1,%ebx
  jne    L0
  divss  %xmm1,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D14
datatype: byte[4]
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D15: Rentrez votre nombre :

tool: D11: %f

tool: {"D14": [0x00,0x00,0x80,0x3f]}

tool: D19: La moyenne est de %f

assistant: ```c
int main(int argc, char *argv[], char *env[]) {
  float M = 0, x, i;
  for (i = 0; i < 5; i++) {
    printf("Rentrez votre nombre :");
    scanf("%f", &x);
    M += x;
  }
  printf("La moyenne est de %f", (M / i));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<seedgen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D6: rb

tool: D18: /dev/urandom

assistant: ```c
uint64_t seedgen(void) {
  uint64_t seed = 0;
  FILE *urandom = fopen("/dev/urandom", "rb");
  int r = fread(&seed, sizeof(seed), 1, urandom);
  (void)r;
  assert(r == 1);
  fclose(urandom);
  return seed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<seedgen>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D16(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rdi
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D15
data_type: string

tool: D16: rb

tool: D15: /dev/urandom

assistant: ```c
uint64_t seedgen(void) {
  uint64_t seed = 0;
  FILE *urandom = fopen("/dev/urandom", "rb");
  int r = fread(&seed, sizeof(seed), 1, urandom);
  (void)r;
  assert(r == 1);
  fclose(urandom);
  return seed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<seedgen>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rsi
  lea    D12(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <fopen@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  lea    0x4(%rsp),%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fread@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string

tool: D9: rb

tool: D12: /dev/urandom

assistant: ```c
uint64_t seedgen(void) {
  uint64_t seed = 0;
  FILE *urandom = fopen("/dev/urandom", "rb");
  int r = fread(&seed, sizeof(seed), 1, urandom);
  (void)r;
  assert(r == 1);
  fclose(urandom);
  return seed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<seedgen>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rsi
  lea    D7(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <fopen@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  lea    0x4(%rsp),%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fread@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D16: rb

tool: D7: /dev/urandom

assistant: ```c
uint64_t seedgen(void) {
  uint64_t seed = 0;
  FILE *urandom = fopen("/dev/urandom", "rb");
  int r = fread(&seed, sizeof(seed), 1, urandom);
  (void)r;
  assert(r == 1);
  fclose(urandom);
  return seed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cstrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L14
L20:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  cmp    %dl,%al
  jne    L20
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L34
  mov    -0x8(%rbp),%rax
  jmp    L31
L34:
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char *(cstrchr)(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cstrchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
L27:
  cmp    %sil,%al
  je     L16
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L27
L16:
  movsbl %al,%eax
  cmp    %esi,%eax
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *(cstrchr)(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<cstrchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L34
  mov    %esi,%edx
  jmp    L3
  nop
L18:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L34
L3:
  cmp    %al,%dl
  jne    L18
  movsbl %sil,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L34:
  xor    %eax,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *(cstrchr)(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cstrchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  mov    %esi,%edx
  jmp    L16
  nop
L30:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L7
L16:
  cmp    %al,%dl
  jne    L30
  movsbl %sil,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L7:
  xor    %eax,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *(cstrchr)(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<request_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x11c(%rbp),%rax
  mov    %rax,%rdi
  call   <getLastRequest@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x11c(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <respond@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D1
data_type: string

tool: D7: client request arrived

tool: D1: chau %s

assistant: ```c
void request_handler(int n) {
  char response[255], *lastRequest;
  printf("client request arrived\n");
  pid_t lastClient;
  lastRequest = getLastRequest(&lastClient);
  printf("%s\n", lastRequest);
  sprintf(response, "chau %s", lastRequest);
  respond(response, lastClient);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<request_handler>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rdi
  call   <getLastRequest@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rdx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <respond@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D14
type_guessed: string

tool: D13: client request arrived

tool: D14: chau %s

assistant: ```c
void request_handler(int n) {
  char response[255], *lastRequest;
  printf("client request arrived\n");
  pid_t lastClient;
  lastRequest = getLastRequest(&lastClient);
  printf("%s\n", lastRequest);
  sprintf(response, "chau %s", lastRequest);
  respond(response, lastClient);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<request_handler>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  push   %rbp
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rdi
  call   <getLastRequest@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <sprintf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <respond@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x128,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D8
datatype: string

tool: D13: client request arrived

tool: D8: chau %s

assistant: ```c
void request_handler(int n) {
  char response[255], *lastRequest;
  printf("client request arrived\n");
  pid_t lastClient;
  lastRequest = getLastRequest(&lastClient);
  printf("%s\n", lastRequest);
  sprintf(response, "chau %s", lastRequest);
  respond(response, lastClient);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<request_handler>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rdi
  call   <getLastRequest@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <sprintf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <respond@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x128,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D1: client request arrived

tool: D7: chau %s

assistant: ```c
void request_handler(int n) {
  char response[255], *lastRequest;
  printf("client request arrived\n");
  pid_t lastClient;
  lastRequest = getLastRequest(&lastClient);
  printf("%s\n", lastRequest);
  sprintf(response, "chau %s", lastRequest);
  respond(response, lastClient);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: Hello from deeper.c


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: Hello from deeper.c


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: Hello from deeper.c


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: Hello from deeper.c


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L18:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L18
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void vexp(double *a, double *b, int n) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] = exp(b[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vexp>:
  endbr64
  test   %edx,%edx
  jle    L0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L16:
  movsd  0x0(%r13,%rbx,8),%xmm0
  call   <exp@plt>
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  ret
```

assistant: ```c
void vexp(double *a, double *b, int n) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] = exp(b[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vexp>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L14:
  movsd  0x0(%r13,%rbx,8),%xmm0
  call   <exp@plt>
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void vexp(double *a, double *b, int n) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] = exp(b[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vexp>:
  endbr64
  test   %edx,%edx
  jle    L1
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L13:
  movsd  0x0(%r13,%rbx,8),%xmm0
  call   <exp@plt>
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void vexp(double *a, double *b, int n) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] = exp(b[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_cvav>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L50
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L50
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L50
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L50
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L50
  mov    $0x1,%eax
  jmp    L19
L50:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int is_cvav(char *s) {
  int len = strlen(s);
  if ((len >= 4) && is_consonant(s[0]) && is_vowel(s[1]) && (s[2] == '\'') && is_vowel(s[3])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_cvav>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x3,%edx
  jg     L29
L4:
  pop    %rbx
  ret
L29:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L4
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L4
  cmpb   $0x27,0x2(%rbx)
  jne    L4
  movsbl 0x3(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L4
```

assistant: ```c
int is_cvav(char *s) {
  int len = strlen(s);
  if ((len >= 4) && is_consonant(s[0]) && is_vowel(s[1]) && (s[2] == '\'') && is_vowel(s[3])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_cvav>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x3,%eax
  jg     L37
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L3
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L3
  cmpb   $0x27,0x2(%rbx)
  jne    L3
  movsbl 0x3(%rbx),%edi
  call   <is_vowel@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_cvav(char *s) {
  int len = strlen(s);
  if ((len >= 4) && is_consonant(s[0]) && is_vowel(s[1]) && (s[2] == '\'') && is_vowel(s[3])) {
    return 1;
  } else {
    return 0;
  }
}
```