ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<all_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_write@plt>
  test   %rax,%rax
  je     L2
L19:
  add    $0x8,%rsp
  ret
L2:
  call   <test_read@plt>
  test   %rax,%rax
  jne    L19
  call   <test_geolocation@plt>
  jmp    L19
```

assistant: ```c
char *all_tests() {
  do {
    char *message = test_write();
    if (message)
      return message;
  } while (0);
  do {
    char *message = test_read();
    if (message)
      return message;
  } while (0);
  do {
    char *message = test_geolocation();
    if (message)
      return message;
  } while (0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<all_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_write@plt>
  test   %rax,%rax
  je     L7
L14:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L7:
  call   <test_read@plt>
  test   %rax,%rax
  jne    L14
  add    $0x8,%rsp
  jmp    1070 <test_geolocation@plt>
```

assistant: ```c
char *all_tests() {
  do {
    char *message = test_write();
    if (message)
      return message;
  } while (0);
  do {
    char *message = test_read();
    if (message)
      return message;
  } while (0);
  do {
    char *message = test_geolocation();
    if (message)
      return message;
  } while (0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<all_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_write@plt>
  test   %rax,%rax
  je     L5
L1:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  call   <test_read@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  jmp    1070 <test_geolocation@plt>
```

assistant: ```c
char *all_tests() {
  do {
    char *message = test_write();
    if (message)
      return message;
  } while (0);
  do {
    char *message = test_read();
    if (message)
      return message;
  } while (0);
  do {
    char *message = test_geolocation();
    if (message)
      return message;
  } while (0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i > -1; i++) {
    printf("%d\n", i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x80000000,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i > -1; i++) {
    printf("%d\n", i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i > -1; i++) {
    printf("%d\n", i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i > -1; i++) {
    printf("%d\n", i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xil_fpo_div_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <xip_fpo_div_d@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double xil_fpo_div_d(double a, double b) {
  double res_d;
  xip_fpo_div_d(&res_d, a, b);
  return res_d;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xil_fpo_div_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_div_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_div_d(double a, double b) {
  double res_d;
  xip_fpo_div_d(&res_d, a, b);
  return res_d;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xil_fpo_div_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_div_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_div_d(double a, double b) {
  double res_d;
  xip_fpo_div_d(&res_d, a, b);
  return res_d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xil_fpo_div_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_div_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_div_d(double a, double b) {
  double res_d;
  xip_fpo_div_d(&res_d, a, b);
  return res_d;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D17(%rip),%edx
  mov    D2(%rip),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
data_type: byte[4]
name: unpack_data
arguments: data_tag: D2
data_type: byte[4]

tool: {"D17": [0x00,0x00,0x00,0x00]}

tool: {"D2": [0x0e,0x00,0x00,0x00]}

assistant: ```c
int foo(void) {
  static const int a = 0.5;
  static const int b = (int)13.5 + 1;
  return a + b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  mov    $0xe,%eax
  ret
```

assistant: ```c
int foo(void) {
  static const int a = 0.5;
  static const int b = (int)13.5 + 1;
  return a + b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    $0xe,%eax
  ret
```

assistant: ```c
int foo(void) {
  static const int a = 0.5;
  static const int b = (int)13.5 + 1;
  return a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  mov    $0xe,%eax
  ret
```

assistant: ```c
int foo(void) {
  static const int a = 0.5;
  static const int b = (int)13.5 + 1;
  return a + b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<natural_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <topDynArr@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <popDynArr@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pushDynArr@plt>
  nop
  leave
  ret
```

assistant: ```c
void natural_log(struct DynArr *stack) {
  double i = topDynArr(stack);
  popDynArr(stack);
  pushDynArr(stack, log(i));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<natural_log>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <topDynArr@plt>
  movq   %xmm0,%rbp
  mov    %rbx,%rdi
  call   <popDynArr@plt>
  movq   %rbp,%xmm0
  call   <log@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <pushDynArr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void natural_log(struct DynArr *stack) {
  double i = topDynArr(stack);
  popDynArr(stack);
  pushDynArr(stack, log(i));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<natural_log>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  call   <topDynArr@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <popDynArr@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  add    $0x10,%rsp
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  jmp    1090 <pushDynArr@plt>
```

assistant: ```c
void natural_log(struct DynArr *stack) {
  double i = topDynArr(stack);
  popDynArr(stack);
  pushDynArr(stack, log(i));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<natural_log>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  call   <topDynArr@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <popDynArr@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  add    $0x10,%rsp
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  jmp    1090 <pushDynArr@plt>
```

assistant: ```c
void natural_log(struct DynArr *stack) {
  double i = topDynArr(stack);
  popDynArr(stack);
  pushDynArr(stack, log(i));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_words>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r10
  movzbl (%rdi),%eax
  test   %al,%al
  je     L82
  mov    %rdi,%rcx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%edx
  jmp    L16
L83:
  test   %dl,%dl
  jne    L29
L46:
  cltq
  movb   $0x0,(%r10,%rax,1)
  add    $0x2,%edi
L1:
  cmpb   $0x1,(%rcx)
  sbb    $0xffffffff,%esi
L106:
  movslq %esi,%rdx
  lea    (%r8,%rdx,1),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L82
L16:
  lea    -0x30(%rax),%r9d
  cmp    $0x9,%r9b
  jbe    L56
  mov    %eax,%r9d
  and    $0xffffffdf,%r9d
  sub    $0x41,%r9d
  cmp    $0x19,%r9b
  ja     L85
L56:
  movslq %edi,%r9
  mov    %al,(%r10,%r9,1)
  lea    0x1(%rdi),%eax
  movzbl 0x1(%r8,%rdx,1),%edx
  lea    -0x30(%rdx),%r9d
  cmp    $0x9,%r9b
  jbe    L83
  mov    %edx,%r9d
  and    $0xffffffdf,%r9d
  sub    $0x41,%r9d
  cmp    $0x19,%r9b
  ja     L46
  jmp    L83
L29:
  mov    %eax,%edi
  jmp    L1
L85:
  add    $0x1,%esi
  jmp    L106
L82:
  ret
```

assistant: ```c
void add_words(char *str, char *words) {
  int c;
  int i;
  c = 0;
  i = 0;
  while (str[i]) {
    if (((str[i] >= '0' && str[i] <= '9' || str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z')) && str[i]) {
      words[c] = str[i];
      c += 1;
      if ((str[i + 1] < '0' || str[i + 1] > '9') && (str[i + 1] < 'a' || str[i + 1] > 'z') && (str[i + 1] < 'A' || str[i + 1] > 'Z') || str[i + 1] == '\0') {
        words[c] = '\0';
        ++c;
      }
      if (str[i] != '\0')
        i += 1;
    } else if (str[i] != '\0')
      i += 1;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_words>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  mov    %rsi,%r10
  test   %al,%al
  je     L21
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  jmp    L74
  nopl   (%rax)
L70:
  mov    %eax,%r9d
  and    $0xffffffdf,%r9d
  sub    $0x41,%r9d
  cmp    $0x19,%r9b
  jbe    L26
  add    $0x1,%edx
  movslq %edx,%rsi
  lea    (%r8,%rsi,1),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
L74:
  lea    -0x30(%rax),%r9d
  cmp    $0x9,%r9b
  ja     L70
L26:
  movslq %ecx,%r9
  mov    %al,(%r10,%r9,1)
  movzbl 0x1(%r8,%rsi,1),%esi
  lea    0x1(%rcx),%eax
  lea    -0x30(%rsi),%r9d
  cmp    $0x9,%r9b
  jbe    L49
  mov    %esi,%r9d
  and    $0xffffffdf,%r9d
  sub    $0x41,%r9d
  cmp    $0x19,%r9b
  ja     L11
  test   %sil,%sil
  jne    L49
L11:
  cltq
  add    $0x2,%ecx
  movb   $0x0,(%r10,%rax,1)
L28:
  cmpb   $0x1,(%rdi)
  sbb    $0xffffffff,%edx
  movslq %edx,%rsi
  lea    (%r8,%rsi,1),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L74
L21:
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %eax,%ecx
  jmp    L28
```

assistant: ```c
void add_words(char *str, char *words) {
  int c;
  int i;
  c = 0;
  i = 0;
  while (str[i]) {
    if (((str[i] >= '0' && str[i] <= '9' || str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z')) && str[i]) {
      words[c] = str[i];
      c += 1;
      if ((str[i + 1] < '0' || str[i + 1] > '9') && (str[i + 1] < 'a' || str[i + 1] > 'z') && (str[i + 1] < 'A' || str[i + 1] > 'Z') || str[i + 1] == '\0') {
        words[c] = '\0';
        ++c;
      }
      if (str[i] != '\0')
        i += 1;
    } else if (str[i] != '\0')
      i += 1;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_words>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  mov    %rsi,%r10
  test   %al,%al
  je     L31
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  jmp    L51
  nopl   (%rax)
L84:
  mov    %eax,%r9d
  and    $0xffffffdf,%r9d
  sub    $0x41,%r9d
  cmp    $0x19,%r9b
  jbe    L81
  add    $0x1,%edx
  movslq %edx,%rsi
  lea    (%r8,%rsi,1),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
L51:
  lea    -0x30(%rax),%r9d
  cmp    $0x9,%r9b
  ja     L84
L81:
  movslq %ecx,%r9
  mov    %al,(%r10,%r9,1)
  movzbl 0x1(%r8,%rsi,1),%esi
  lea    0x1(%rcx),%eax
  lea    -0x30(%rsi),%r9d
  cmp    $0x9,%r9b
  jbe    L62
  mov    %esi,%r9d
  and    $0xffffffdf,%r9d
  sub    $0x41,%r9d
  cmp    $0x19,%r9b
  ja     L43
  test   %sil,%sil
  jne    L62
L43:
  cltq
  add    $0x2,%ecx
  movb   $0x0,(%r10,%rax,1)
L85:
  cmpb   $0x1,(%rdi)
  sbb    $0xffffffff,%edx
  movslq %edx,%rsi
  lea    (%r8,%rsi,1),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L51
L31:
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %eax,%ecx
  jmp    L85
```

assistant: ```c
void add_words(char *str, char *words) {
  int c;
  int i;
  c = 0;
  i = 0;
  while (str[i]) {
    if (((str[i] >= '0' && str[i] <= '9' || str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z')) && str[i]) {
      words[c] = str[i];
      c += 1;
      if ((str[i + 1] < '0' || str[i + 1] > '9') && (str[i + 1] < 'a' || str[i + 1] > 'z') && (str[i + 1] < 'A' || str[i + 1] > 'Z') || str[i + 1] == '\0') {
        words[c] = '\0';
        ++c;
      }
      if (str[i] != '\0')
        i += 1;
    } else if (str[i] != '\0')
      i += 1;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clGetMemObjectInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x3fd,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
cl_int clGetMemObjectInfo(cl_mem memobj, cl_mem_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)memobj;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1021, sys_args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clGetMemObjectInfo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %rsp,%rdx
  mov    $0x3fd,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetMemObjectInfo(cl_mem memobj, cl_mem_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)memobj;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1021, sys_args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clGetMemObjectInfo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x145,%edi
  mov    %esi,0x4(%rsp)
  mov    $0x3fd,%esi
  mov    %edx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetMemObjectInfo(cl_mem memobj, cl_mem_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)memobj;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1021, sys_args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<clGetMemObjectInfo>:
  endbr64
  movd   %edx,%xmm1
  movd   %edi,%xmm0
  movd   %esi,%xmm3
  sub    $0x28,%rsp
  movd   %ecx,%xmm2
  punpckldq %xmm3,%xmm0
  mov    %rsp,%rdx
  mov    $0x3fd,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpckldq %xmm2,%xmm1
  mov    $0x145,%edi
  mov    %r8d,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetMemObjectInfo(cl_mem memobj, cl_mem_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)memobj;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1021, sys_args);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<util_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  mov    $0x0,%eax
  jmp    L18
L2:
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
bool util_malloc(void **ptr, size_t len) {
  assert(ptr != NULL);
  *ptr = malloc(len);
  if (*ptr == NULL) {
    return false;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<util_malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool util_malloc(void **ptr, size_t len) {
  assert(ptr != NULL);
  *ptr = malloc(len);
  if (*ptr == NULL) {
    return false;
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<util_malloc>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  mov    %rax,(%rbx)
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool util_malloc(void **ptr, size_t len) {
  assert(ptr != NULL);
  *ptr = malloc(len);
  if (*ptr == NULL) {
    return false;
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_malloc>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  mov    %rax,(%rbx)
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool util_malloc(void **ptr, size_t len) {
  assert(ptr != NULL);
  *ptr = malloc(len);
  if (*ptr == NULL) {
    return false;
  }
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jne    L4
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L4:
  mov    $0x0,%edi
  call   <omp_set_dynamic@plt>
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D17: should be run this program on multi threads.


tool: D1: err_sections 002 : FAILED, can not compile this program.


assistant: ```c
main() {
  int thds;
  int buf[3];
  thds = omp_get_max_threads();
  if (thds == 1) {
    printf("should be run this program on multi threads.\n");
    exit(0);
  }
  omp_set_dynamic(0);
  memset(buf, 0, sizeof(buf));
#pragma omp parallel
  {
#pragma omp sections
    {
      buf[0] += 1;
      buf[1] += 2;
#pragma omp section
      buf[2] += 3;
    }
  }
  printf("err_sections 002 : FAILED, can not compile this program.\n");
  return 1;
}
```