ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trans>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  mov    %rdi,%r10
  mov    %esi,%r9d
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rsi,%rax,1),%r8d
  and    $0x3,%r8d
  sub    %eax,%r8d
  sub    %r8d,%edx
  test   %edx,%edx
  jle    L5
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edi
  shr    $0x2,%edi
  mov    %edi,%edx
  lea    0x4(%r10,%rdx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L37:
  movzbl (%rax),%edx
  movzbl 0x2(%rax),%ecx
  add    $0x4,%rax
  mov    %cl,-0x4(%rax)
  movzbl -0x1(%rax),%ecx
  mov    %dl,-0x2(%rax)
  movzbl -0x3(%rax),%edx
  mov    %cl,-0x3(%rax)
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L37
  lea    0x4(,%rdi,4),%eax
L7:
  and    $0x3,%r9d
  je     L4
  cmp    $0x2,%r8d
  je     L30
  cmp    $0x3,%r8d
  je     L27
  ret
  xchg   %ax,%ax
L27:
  cltq
  lea    (%r10,%rax,1),%rdx
  lea    0x2(%r10,%rax,1),%rax
  movzbl (%rdx),%ecx
  movzbl (%rax),%esi
  mov    %sil,(%rdx)
  mov    %cl,(%rax)
L4:
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  cltq
  lea    (%r10,%rax,1),%rdx
  lea    0x1(%r10,%rax,1),%rax
  movzbl (%rdx),%ecx
  movzbl (%rax),%esi
  mov    %sil,(%rdx)
  mov    %cl,(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  jmp    L7
```

assistant: ```c
void trans(char *text, int textLength) {
  char temp;
  int i;
  int lastQuad = textLength % 4;
  for (i = 0; i < (textLength - lastQuad); i += 4) {
    temp = text[i];
    text[i] = text[i + 2];
    text[i + 2] = temp;
    temp = text[i + 1];
    text[i + 1] = text[i + 3];
    text[i + 3] = temp;
  }
  if (lastQuad != 0)
    switch (lastQuad) {
    case 1:
      break;
    case 2:
      temp = text[i];
      text[i] = text[i + 1];
      text[i + 1] = temp;
      break;
    case 3:
      temp = text[i];
      text[i] = text[i + 2];
      text[i + 2] = temp;
      break;
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fsub_preg32_dword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xd8,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  add    $0x20,%eax
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void fsub_preg32_dword(int reg32) {
  put8(0xD8);
  put8(0x20 + reg32);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fsub_preg32_dword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xd8,%edi
  call   <put8@plt>
  lea    0x20(%rbx),%edi
  call   <put8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fsub_preg32_dword(int reg32) {
  put8(0xD8);
  put8(0x20 + reg32);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fsub_preg32_dword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xd8,%edi
  call   <put8@plt>
  lea    0x20(%rbx),%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void fsub_preg32_dword(int reg32) {
  put8(0xD8);
  put8(0x20 + reg32);
}
```
user: What is the c source code of the assembly code below:

```asm
<fsub_preg32_dword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xd8,%edi
  call   <put8@plt>
  lea    0x20(%rbx),%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void fsub_preg32_dword(int reg32) {
  put8(0xD8);
  put8(0x20 + reg32);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L47
L38:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L31
L48:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L31:
  cmpl   $0x0,-0x8(%rbp)
  jle    L25
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L48
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int a[], int n) {
  int i, j;
  int tmp;
  for (i = 1; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L21
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  jmp    L25
L19:
  movslq %edx,%rdx
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%esi
  je     L21
L25:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9d,%edx
  test   %r9d,%r9d
  jle    L19
L47:
  mov    -0x4(%rax),%ecx
  cmp    %r8d,%ecx
  jle    L19
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L47
  jmp    L19
L21:
  ret
```

assistant: ```c
void insertion_sort(int a[], int n) {
  int i, j;
  int tmp;
  for (i = 1; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertion_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L24
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L6:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L38
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rax,%rdi
  jne    L6
  mov    %rdi,%rcx
L38:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L8
L24:
  ret
```

assistant: ```c
void insertion_sort(int a[], int n) {
  int i, j;
  int tmp;
  for (i = 1; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertion_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L21
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L35:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L29
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rdi,%rax
  jne    L35
  mov    %rdi,%rcx
L29:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L10
L21:
  ret
```

assistant: ```c
void insertion_sort(int a[], int n) {
  int i, j;
  int tmp;
  for (i = 1; i < n; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--)
      a[j] = a[j - 1];
    a[j] = tmp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x201,-0xb(%rbp)
  movb   $0x3,-0x9(%rbp)
  movb   $0x4,-0xa(%rbp)
  movzbl -0xb(%rbp),%eax
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0xa(%rbp),%eax
  cmp    $0x4,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x3,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movw   $0x1,-0x42(%rbp)
  movw   $0x2,-0x40(%rbp)
  movw   $0x3,-0x3e(%rbp)
  movw   $0x4,-0x40(%rbp)
  movzwl -0x42(%rbp),%eax
  cmp    $0x1,%ax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzwl -0x40(%rbp),%eax
  cmp    $0x4,%ax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzwl -0x3e(%rbp),%eax
  cmp    $0x3,%ax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  movl   $0x4,-0x38(%rbp)
  mov    -0x3c(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x38(%rbp),%eax
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x34(%rbp),%eax
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x1,-0x30(%rbp)
  movq   $0x2,-0x28(%rbp)
  movq   $0x3,-0x20(%rbp)
  movq   $0x4,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  cmp    $0x1,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  cmp    $0x4,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  cmp    $0x3,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x1,-0x58(%rbp)
  shlq   $0x28,-0x58(%rbp)
  movq   $0x0,-0x58(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  movq   $0x0,-0x50(%rbp)
  cmpq   $0x0,-0x50(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  unsigned char a[] = {1, 2, 3};
  a[1] = 4;
  assert(a[0] == 1);
  assert(a[1] == 4);
  assert(a[2] == 3);
  unsigned short b[] = {1, 2, 3};
  b[1] = 4;
  assert(b[0] == 1);
  assert(b[1] == 4);
  assert(b[2] == 3);
  unsigned int c[] = {1, 2, 3};
  c[1] = 4;
  assert(c[0] == 1);
  assert(c[1] == 4);
  assert(c[2] == 3);
  unsigned long d[] = {1, 2, 3};
  d[1] = 4;
  assert(d[0] == 1);
  assert(d[1] == 4);
  assert(d[2] == 3);
  long x = 1;
  x <<= 40;
  x = 0;
  assert(x == 0);
  int *foo = (int *)x;
  foo = NULL;
  assert(foo == NULL);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned char a[] = {1, 2, 3};
  a[1] = 4;
  assert(a[0] == 1);
  assert(a[1] == 4);
  assert(a[2] == 3);
  unsigned short b[] = {1, 2, 3};
  b[1] = 4;
  assert(b[0] == 1);
  assert(b[1] == 4);
  assert(b[2] == 3);
  unsigned int c[] = {1, 2, 3};
  c[1] = 4;
  assert(c[0] == 1);
  assert(c[1] == 4);
  assert(c[2] == 3);
  unsigned long d[] = {1, 2, 3};
  d[1] = 4;
  assert(d[0] == 1);
  assert(d[1] == 4);
  assert(d[2] == 3);
  long x = 1;
  x <<= 40;
  x = 0;
  assert(x == 0);
  int *foo = (int *)x;
  foo = NULL;
  assert(foo == NULL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned char a[] = {1, 2, 3};
  a[1] = 4;
  assert(a[0] == 1);
  assert(a[1] == 4);
  assert(a[2] == 3);
  unsigned short b[] = {1, 2, 3};
  b[1] = 4;
  assert(b[0] == 1);
  assert(b[1] == 4);
  assert(b[2] == 3);
  unsigned int c[] = {1, 2, 3};
  c[1] = 4;
  assert(c[0] == 1);
  assert(c[1] == 4);
  assert(c[2] == 3);
  unsigned long d[] = {1, 2, 3};
  d[1] = 4;
  assert(d[0] == 1);
  assert(d[1] == 4);
  assert(d[2] == 3);
  long x = 1;
  x <<= 40;
  x = 0;
  assert(x == 0);
  int *foo = (int *)x;
  foo = NULL;
  assert(foo == NULL);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned char a[] = {1, 2, 3};
  a[1] = 4;
  assert(a[0] == 1);
  assert(a[1] == 4);
  assert(a[2] == 3);
  unsigned short b[] = {1, 2, 3};
  b[1] = 4;
  assert(b[0] == 1);
  assert(b[1] == 4);
  assert(b[2] == 3);
  unsigned int c[] = {1, 2, 3};
  c[1] = 4;
  assert(c[0] == 1);
  assert(c[1] == 4);
  assert(c[2] == 3);
  unsigned long d[] = {1, 2, 3};
  d[1] = 4;
  assert(d[0] == 1);
  assert(d[1] == 4);
  assert(d[2] == 3);
  long x = 1;
  x <<= 40;
  x = 0;
  assert(x == 0);
  int *foo = (int *)x;
  foo = NULL;
  assert(foo == NULL);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L22
L47:
  movl   $0x0,-0x24(%rbp)
  jmp    L43
L4:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L31
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L31:
  addl   $0x1,-0x24(%rbp)
L43:
  mov    $0x9,%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L4
  addl   $0x1,-0x28(%rbp)
L22:
  cmpl   $0x8,-0x28(%rbp)
  jle    L47
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void sort(char s[10][6]) {
  int i, j;
  char *p, temp[10];
  p = temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (strcmp(s[j], s[j + 1]) > 0) {
        strcpy(p, s[j]);
        strcpy(s[j], s[j + 1]);
        strcpy(s[j + 1], p);
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x36(%rdi),%r12
  mov    $0x9,%r14d
  lea    0xe(%rsp),%r13
  jmp    L77
L0:
  cmp    %r12,%rbx
  je     L39
L10:
  mov    %rbx,%rbp
  add    $0x6,%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L0
L39:
  sub    $0x6,%r12
  sub    $0x1,%r14d
  je     L8
L77:
  mov    %r15,%rbx
  test   %r14d,%r14d
  jg     L10
  jmp    L39
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sort(char s[10][6]) {
  int i, j;
  char *p, temp[10];
  p = temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (strcmp(s[j], s[j + 1]) > 0) {
        strcpy(p, s[j]);
        strcpy(s[j], s[j + 1]);
        strcpy(s[j + 1], p);
      }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    0x36(%rdi),%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  nopl   0x0(%rax)
L8:
  mov    %r14,%rbx
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %rbx,%rbp
  add    $0x6,%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L10
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
L10:
  cmp    %r12,%rbx
  jne    L39
  lea    -0x6(%rbx),%r12
  cmp    %r14,%r12
  jne    L8
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sort(char s[10][6]) {
  int i, j;
  char *p, temp[10];
  p = temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (strcmp(s[j], s[j + 1]) > 0) {
        strcpy(p, s[j]);
        strcpy(s[j], s[j + 1]);
        strcpy(s[j + 1], p);
      }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    0x36(%rdi),%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  nopl   0x0(%rax)
L23:
  mov    %r14,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rbp
  add    $0x6,%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L37
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
L37:
  cmp    %r12,%rbx
  jne    L2
  lea    -0x6(%rbx),%r12
  cmp    %r14,%r12
  jne    L23
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sort(char s[10][6]) {
  int i, j;
  char *p, temp[10];
  p = temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (strcmp(s[j], s[j + 1]) > 0) {
        strcpy(p, s[j]);
        strcpy(s[j], s[j + 1]);
        strcpy(s[j + 1], p);
      }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <runConverter@plt>
  lea    D50(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <runConverter@plt>
  lea    D27(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <runConverter@plt>
  lea    D33(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <runConverter@plt>
  lea    D49(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <runConverter@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D22
data_type: string
name: unpack_data
arguments: data_label: D13
data_type: string
name: unpack_data
arguments: data_label: D50
data_type: string
name: unpack_data
arguments: data_label: D27
data_type: string
name: unpack_data
arguments: data_label: D33
data_type: string
name: unpack_data
arguments: data_label: D49
data_type: string

tool: D22: A + B - C

tool: D13: 
INFIX   : %s
POSTFIX : 

tool: D50: A + 7 * (C - D) / E % F

tool: D27: A*(B-C)+(D/(E+F%G))

tool: D33: (A + (B - C * D) / E % F

tool: D49: A + B * (C / (D - (E % F)))

assistant: ```c
int main(int argc, char **argv) {
  char infix[40];
  strcpy(infix, "A + B - C");
  printf("\nINFIX   : %s\nPOSTFIX : ", infix);
  runConverter(infix);
  strcpy(infix, "A + 7 * (C - D) / E % F");
  printf("\nINFIX   : %s\nPOSTFIX : ", infix);
  runConverter(infix);
  strcpy(infix, "A*(B-C)+(D/(E+F%G))");
  printf("\nINFIX   : %s\nPOSTFIX : ", infix);
  runConverter(infix);
  strcpy(infix, "(A + (B - C * D) / E % F");
  printf("\nINFIX   : %s\nPOSTFIX : ", infix);
  runConverter(infix);
  strcpy(infix, "A + B * (C / (D - (E % F)))");
  printf("\nINFIX   : %s\nPOSTFIX : ", infix);
  runConverter(infix);
  printf("\n");
  return (0);
}
```