user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0x8,-0x10(%rbp)
  movl   $0xa,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x0,-0x34(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L11
L8:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L11:
  mov    -0x34(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  addl   $0x1,-0x24(%rbp)
  jmp    L61
L32:
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x30(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x30(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%ecx
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    -0x30(%rbp),%edx
  lea    0x1(%rdx),%esi
  mov    -0x30(%rbp),%edx
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x30(%rbp)
L61:
  mov    -0x30(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L32
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x2c(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L42
L51:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L42:
  mov    -0x34(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L51
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D59
data_type: string
name: extract_symbolic_data
arguments: tag: D43
data_type: string
name: extract_symbolic_data
arguments: tag: D54
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D59: The original array elements are :

tool: D43: LA[%d] = %d 


tool: D54: Value of j is %d , k is %d and n is %d 


tool: D24: Value of LA[%d] = %d and LA[%d] = %d 


tool: D8: The array elements after insertion :

assistant: ```c
main() {
  int LA[] = {1, 3, 5, 7, 8};
  int item = 10, k = 3, n = 5;
  int i = 0, j = n;
  printf("The original array elements are :\n");
  for (i = 0; i < n; i++) {
    printf("LA[%d] = %d \n", i, LA[i]);
  }
  n = n + 1;
  while (j >= k) {
    printf("Value of j is %d , k is %d and n is %d \n", j, k, n);
    LA[j + 1] = LA[j];
    printf("Value of LA[%d] = %d and LA[%d] = %d \n", j + 1, LA[j + 1], j, LA[j]);
    j = j - 1;
  }
  LA[k] = item;
  printf("The array elements after insertion :\n");
  for (i = 0; i < n; i++) {
    printf("LA[%d] = %d \n", i, LA[i]);
  }
}
```