user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x3,%edi
  call   <iopl@plt>
  mov    $0x74,%esi
  mov    $0xa,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    $0x74,%esi
  mov    $0x7,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    %eax,%ebp
  mov    $0x74,%esi
  mov    $0x8,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    %eax,%r12d
  mov    $0x74,%esi
  mov    $0x9,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    %eax,%r13d
  mov    $0x74,%esi
  mov    $0x4,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    %eax,%r14d
  mov    $0x74,%esi
  mov    $0x2,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    %eax,%r15d
  mov    $0x74,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  mov    %eax,%ebx
  mov    $0x74,%esi
  mov    $0x6,%edi
  call   <outb@plt>
  mov    $0x75,%edi
  call   <inb@plt>
  cmp    $0x7,%al
  ja     L46
  movzbl %al,%eax
  lea    D13(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movb   $0x65,0xf(%rsp)
  movb   $0x4e,0xe(%rsp)
L46:
  cmp    $0x9,%bl
  ja     L76
  movzbl %r13b,%ecx
  movzbl %r12b,%edx
  movzbl %bpl,%esi
  sub    $0x8,%rsp
  movzbl %bl,%ebx
  push   %rbx
  movzbl %r15b,%r15d
  push   %r15
  movzbl %r14b,%r14d
  push   %r14
  movsbl 0x2f(%rsp),%r9d
  movsbl 0x2e(%rsp),%r8d
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
L50:
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  movb   $0x6f,0xf(%rsp)
  movb   $0x50,0xe(%rsp)
  jmp    L46
  movb   $0x74,0xf(%rsp)
  movb   $0x55,0xe(%rsp)
  jmp    L46
  movb   $0x74,0xf(%rsp)
  movb   $0x53,0xe(%rsp)
  jmp    L46
  movb   $0x74,0xf(%rsp)
  movb   $0x43,0xe(%rsp)
  jmp    L46
  movb   $0x61,0xf(%rsp)
  movb   $0x50,0xe(%rsp)
  jmp    L46
  movb   $0x6f,0xf(%rsp)
  movb   $0x53,0xe(%rsp)
  jmp    L46
L76:
  movzbl %r13b,%ecx
  movzbl %r12b,%edx
  movzbl %bpl,%esi
  sub    $0x8,%rsp
  movzbl %bl,%ebx
  push   %rbx
  movzbl %r15b,%r15d
  push   %r15
  movzbl %r14b,%r14d
  push   %r14
  movsbl 0x2f(%rsp),%r9d
  movsbl 0x2e(%rsp),%r8d
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  jmp    L50
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D16
datatype: string

tool: D2: %x.%x.%x, %c%c %x:%x:0%x 


tool: D16: %x.%x.%x, %c%c %x:%x:%x 


assistant: ```c
int main() {
  iopl(3);
  unsigned char ret, h, s, m, d, mo, r, dt;
  char den[2];
  outb(0xA, 0x74);
  ret = inb(0x75);
  while (ret & 0x80 == 1)
    ;
  outb(0x7, 0x74);
  d = inb(0x75);
  outb(0x8, 0x74);
  mo = inb(0x75);
  outb(0x9, 0x74);
  r = inb(0x75);
  outb(0x4, 0x74);
  h = inb(0x75);
  outb(0x2, 0x74);
  m = inb(0x75);
  outb(0x0, 0x74);
  s = inb(0x75);
  outb(0x6, 0x74);
  dt = inb(0x75);
  int idt = (int)dt;
  switch (idt) {
  case 7: {
    den[0] = 'N';
    den[1] = 'e';
    break;
  }
  case 1: {
    den[0] = 'P';
    den[1] = 'o';
    break;
  }
  case 2: {
    den[0] = 'U';
    den[1] = 't';
    break;
  }
  case 3: {
    den[0] = 'S';
    den[1] = 't';
    break;
  }
  case 4: {
    den[0] = 'C';
    den[1] = 't';
    break;
  }
  case 5: {
    den[0] = 'P';
    den[1] = 'a';
    break;
  }
  case 6: {
    den[0] = 'S';
    den[1] = 'o';
    break;
  }
  }
  if (s < 10) {
    printf("%x.%x.%x, %c%c %x:%x:0%x \n", d, mo, r, den[0], den[1], h, m, s);
  } else {
    printf("%x.%x.%x, %c%c %x:%x:%x \n", d, mo, r, den[0], den[1], h, m, s);
  }
  return 0;
}
```