ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<shm_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  mov    %eax,%r12d
  call   <alloca@plt>
  mov    $0x9,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r12),%edx
  lea    0x9(%rbx),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <open_cloexec@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string

tool: D6: /dev/shm/

assistant: ```c
int shm_open(const char *path, int oflag, mode_t mode) {
  int len = strlen(path);
  char *pathbuf = alloca(len + 10);
  memcpy(pathbuf, "/dev/shm/", 9);
  memcpy(pathbuf + 9, path, len + 1);
  return open_cloexec(path, oflag, mode);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D31(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <str_hash@plt>
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <str_hash@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <test_columns@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D31
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D1: a

tool: D31: b

tool: D10: c

tool: D6: %d,%d


assistant: ```c
int main(int argc, char **argv) {
  const char *columns[4] = {"a", "b", "c", NULL};
  printf("%d,%d\n", str_hash(argv[1]), str_hash(argv[1]) % 64);
  test_columns(columns);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,(%rsp)
  lea    D4(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D8(%rip),%rax
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    0x8(%rsi),%rdi
  call   <str_hash@plt>
  mov    %eax,%ebx
  mov    0x8(%rbp),%rdi
  call   <str_hash@plt>
  mov    %eax,%esi
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1a,%ecx
  lea    (%rbx,%rcx,1),%edx
  and    $0x3f,%edx
  sub    %ecx,%edx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <test_columns@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D14: a

tool: D4: b

tool: D8: c

tool: D9: %d,%d


assistant: ```c
int main(int argc, char **argv) {
  const char *columns[4] = {"a", "b", "c", NULL};
  printf("%d,%d\n", str_hash(argv[1]), str_hash(argv[1]) % 64);
  test_columns(columns);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D22(%rip),%rax
  movq   $0x0,0x18(%rsp)
  mov    %rax,(%rsp)
  lea    D13(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D6(%rip),%rax
  mov    %rax,0x10(%rsp)
  call   <str_hash@plt>
  mov    0x8(%rbp),%rdi
  mov    %eax,%ebx
  call   <str_hash@plt>
  mov    %ebx,%ecx
  lea    D17(%rip),%rdi
  sar    $0x1f,%ecx
  mov    %eax,%esi
  shr    $0x1a,%ecx
  lea    (%rbx,%rcx,1),%edx
  and    $0x3f,%edx
  sub    %ecx,%edx
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <test_columns@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D17
datatype: string

tool: D22: a

tool: D13: b

tool: D6: c

tool: D17: %d,%d


assistant: ```c
int main(int argc, char **argv) {
  const char *columns[4] = {"a", "b", "c", NULL};
  printf("%d,%d\n", str_hash(argv[1]), str_hash(argv[1]) % 64);
  test_columns(columns);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  lea    D16(%rip),%rbx
  movq   %rbx,%xmm0
  sub    $0x38,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D33(%rip),%rax
  movq   $0x0,0x18(%rsp)
  movq   %rax,%xmm1
  lea    D29(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <str_hash@plt>
  mov    0x8(%rbp),%rdi
  mov    %eax,%ebx
  call   <str_hash@plt>
  mov    %ebx,%ecx
  lea    D28(%rip),%rdi
  sar    $0x1f,%ecx
  mov    %eax,%esi
  shr    $0x1a,%ecx
  lea    (%rbx,%rcx,1),%edx
  and    $0x3f,%edx
  sub    %ecx,%edx
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <test_columns@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D33
datatype: string
name: extract_symbolic_data
arguments: data_label: D29
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string

tool: D16: a

tool: D33: b

tool: D29: c

tool: D28: %d,%d


assistant: ```c
int main(int argc, char **argv) {
  const char *columns[4] = {"a", "b", "c", NULL};
  printf("%d,%d\n", str_hash(argv[1]), str_hash(argv[1]) % 64);
  test_columns(columns);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_middle_angle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  test   %eax,%eax
  jle    L14
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <fix_angle@plt>
  jmp    L6
L14:
  mov    -0x8(%rbp),%eax
  lea    0xe10(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <fix_angle@plt>
L6:
  leave
  ret
```

assistant: ```c
int calc_middle_angle(int dir1, int dir2) {
  if ((dir2 - dir1) > 0) {
    return (fix_angle((dir2 + dir1) / 2));
  } else {
    return (fix_angle((dir2 + 3600 + dir1) / 2));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_middle_angle>:
  endbr64
  sub    $0x8,%rsp
  cmp    %edi,%esi
  jle    L17
  add    %edi,%esi
  mov    %esi,%edi
  shr    $0x1f,%edi
  add    %esi,%edi
  sar    %edi
  call   <fix_angle@plt>
L6:
  add    $0x8,%rsp
  ret
L17:
  lea    0xe10(%rdi,%rsi,1),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <fix_angle@plt>
  jmp    L6
```

assistant: ```c
int calc_middle_angle(int dir1, int dir2) {
  if ((dir2 - dir1) > 0) {
    return (fix_angle((dir2 + dir1) / 2));
  } else {
    return (fix_angle((dir2 + 3600 + dir1) / 2));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_middle_angle>:
  endbr64
  cmp    %edi,%esi
  jle    L6
  add    %edi,%esi
  mov    %esi,%edi
  shr    $0x1f,%edi
  add    %esi,%edi
  sar    %edi
  jmp    1050 <fix_angle@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  lea    0xe10(%rdi,%rsi,1),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  jmp    1050 <fix_angle@plt>
```

assistant: ```c
int calc_middle_angle(int dir1, int dir2) {
  if ((dir2 - dir1) > 0) {
    return (fix_angle((dir2 + dir1) / 2));
  } else {
    return (fix_angle((dir2 + 3600 + dir1) / 2));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calc_middle_angle>:
  endbr64
  cmp    %edi,%esi
  jle    L2
  add    %edi,%esi
  mov    %esi,%edi
  shr    $0x1f,%edi
  add    %esi,%edi
  sar    %edi
  jmp    1050 <fix_angle@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  lea    0xe10(%rdi,%rsi,1),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  jmp    1050 <fix_angle@plt>
```

assistant: ```c
int calc_middle_angle(int dir1, int dir2) {
  if ((dir2 - dir1) > 0) {
    return (fix_angle((dir2 + dir1) / 2));
  } else {
    return (fix_angle((dir2 + 3600 + dir1) / 2));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getOuterCircleArea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <computeOuterSquareRadius@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%edi
  call   <acos@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double getOuterCircleArea(int numSide, double regularPolygonArea) {
  double squareRadius = computeOuterSquareRadius(numSide, regularPolygonArea);
  return (2 * acos(0)) * squareRadius;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getOuterCircleArea>:
  endbr64
  push   %rbx
  call   <computeOuterSquareRadius@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%edi
  call   <acos@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %rbx,%xmm1
  mulsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double getOuterCircleArea(int numSide, double regularPolygonArea) {
  double squareRadius = computeOuterSquareRadius(numSide, regularPolygonArea);
  return (2 * acos(0)) * squareRadius;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getOuterCircleArea>:
  endbr64
  sub    $0x18,%rsp
  call   <computeOuterSquareRadius@plt>
  xor    %edi,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <acos@plt>
  pxor   %xmm0,%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double getOuterCircleArea(int numSide, double regularPolygonArea) {
  double squareRadius = computeOuterSquareRadius(numSide, regularPolygonArea);
  return (2 * acos(0)) * squareRadius;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getOuterCircleArea>:
  endbr64
  sub    $0x18,%rsp
  call   <computeOuterSquareRadius@plt>
  xor    %edi,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <acos@plt>
  pxor   %xmm0,%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double getOuterCircleArea(int numSide, double regularPolygonArea) {
  double squareRadius = computeOuterSquareRadius(numSide, regularPolygonArea);
  return (2 * acos(0)) * squareRadius;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<simple_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L30
L70:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L10
  mov    -0x18(%rbp),%rax
  jmp    L31
L10:
  subq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L70
  jmp    L45
L55:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L31
L19:
  subq   $0x1,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L55
  mov    -0x18(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
const char *simple_basename(const char *name) {
  const char *p;
  p = name + strlen(name) - 1;
  while (*p == '/') {
    if (p == name)
      return name;
    p--;
  }
  while (p != name) {
    if (*p == '/')
      return p + 1;
    p--;
  }
  return name;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<simple_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L75
  cmp    %rax,%rbx
  je     L82
L19:
  sub    $0x1,%rax
  cmpb   $0x2f,(%rax)
  jne    L75
  cmp    %rax,%rbx
  jne    L19
L82:
  pop    %rbx
  ret
L75:
  cmp    %rax,%rbx
  je     L82
L3:
  cmpb   $0x2f,(%rax)
  je     L87
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L3
  jmp    L82
L87:
  add    $0x1,%rax
  jmp    L82
```

assistant: ```c
const char *simple_basename(const char *name) {
  const char *p;
  p = name + strlen(name) - 1;
  while (*p == '/') {
    if (p == name)
      return name;
    p--;
  }
  while (p != name) {
    if (*p == '/')
      return p + 1;
    p--;
  }
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simple_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  je     L42
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L26:
  sub    $0x1,%rax
  cmpb   $0x2f,(%rax)
  jne    L30
L42:
  cmp    %rax,%rbx
  jne    L26
L22:
  pop    %rbx
  ret
L36:
  cmpb   $0x2f,(%rax)
  je     L47
  sub    $0x1,%rax
L30:
  cmp    %rax,%rbx
  jne    L36
  jmp    L22
L47:
  add    $0x1,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *simple_basename(const char *name) {
  const char *p;
  p = name + strlen(name) - 1;
  while (*p == '/') {
    if (p == name)
      return name;
    p--;
  }
  while (p != name) {
    if (*p == '/')
      return p + 1;
    p--;
  }
  return name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<simple_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  je     L59
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L51:
  sub    $0x1,%rax
  cmpb   $0x2f,(%rax)
  jne    L38
L59:
  cmp    %rax,%rbx
  jne    L51
L4:
  pop    %rbx
  ret
L33:
  cmpb   $0x2f,(%rax)
  je     L54
  sub    $0x1,%rax
L38:
  cmp    %rax,%rbx
  jne    L33
  jmp    L4
L54:
  add    $0x1,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *simple_basename(const char *name) {
  const char *p;
  p = name + strlen(name) - 1;
  while (*p == '/') {
    if (p == name)
      return name;
    p--;
  }
  while (p != name) {
    if (*p == '/')
      return p + 1;
    p--;
  }
  return name;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<string_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_length@plt>
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_length@plt>
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L15:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  cmpl   $0x0,-0x10(%rbp)
  jns    L15
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *string_reverse(char *palabra) {
  char *resultado = calloc(1, string_length(palabra) + 1);
  int i = string_length(palabra) - 1, j = 0;
  while (i >= 0) {
    resultado[j] = palabra[i];
    i--;
    j++;
  }
  return resultado;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<string_reverse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <string_length@plt>
  lea    0x1(%rax),%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <string_length@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L11
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rcx
  mov    %rbp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rsi
L4:
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L4
L11:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *string_reverse(char *palabra) {
  char *resultado = calloc(1, string_length(palabra) + 1);
  int i = string_length(palabra) - 1, j = 0;
  while (i >= 0) {
    resultado[j] = palabra[i];
    i--;
    j++;
  }
  return resultado;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_reverse>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <string_length@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%esi
  call   <calloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <string_length@plt>
  sub    $0x1,%eax
  js     L4
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    (%rbx,%rdx,1),%rdi
  lea    0x1(%r12,%rax,1),%rcx
  mov    %r12,%rdx
  nopl   0x0(%rax)
L16:
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  sub    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L16
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *string_reverse(char *palabra) {
  char *resultado = calloc(1, string_length(palabra) + 1);
  int i = string_length(palabra) - 1, j = 0;
  while (i >= 0) {
    resultado[j] = palabra[i];
    i--;
    j++;
  }
  return resultado;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_reverse>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <string_length@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%esi
  call   <calloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <string_length@plt>
  sub    $0x1,%eax
  js     L16
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    (%rbx,%rdx,1),%rdi
  lea    0x1(%r12,%rax,1),%rcx
  mov    %r12,%rdx
  nopl   0x0(%rax)
L15:
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  sub    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L15
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *string_reverse(char *palabra) {
  char *resultado = calloc(1, string_length(palabra) + 1);
  int i = string_length(palabra) - 1, j = 0;
  while (i >= 0) {
    resultado[j] = palabra[i];
    i--;
    j++;
  }
  return resultado;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<client_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3c,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
L12:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L12
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  lea    -0x18(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <client_process@plt>
  jmp    L12
```

assistant: ```c
void client_loop(int remotefd, int localfd) {
  fd_set set;
  struct timeval tv = {60, 0};
  int max;
  while (1) {
    FD_ZERO(&set);
    FD_SET(localfd, &set);
    max = localfd;
    max = select(max + 1, &set, NULL, NULL, &tv);
    if (max != -1)
      client_process(max, &set, remotefd, localfd);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<client_loop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3c,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rbx
L5:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  lea    0x1(%rbp),%edi
  lea    0x10(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <client_process@plt>
  jmp    L5
```

assistant: ```c
void client_loop(int remotefd, int localfd) {
  fd_set set;
  struct timeval tv = {60, 0};
  int max;
  while (1) {
    FD_ZERO(&set);
    FD_SET(localfd, &set);
    max = localfd;
    max = select(max + 1, &set, NULL, NULL, &tv);
    if (max != -1)
      client_process(max, &set, remotefd, localfd);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<client_loop>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  lea    0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r12
  movq   $0x3c,0x10(%rsp)
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r13d,%edi
  mov    %r12,%r8
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbx,%rsi
  call   <select@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L14
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %rbx,%rsi
  call   <client_process@plt>
  jmp    L14
```

assistant: ```c
void client_loop(int remotefd, int localfd) {
  fd_set set;
  struct timeval tv = {60, 0};
  int max;
  while (1) {
    FD_ZERO(&set);
    FD_SET(localfd, &set);
    max = localfd;
    max = select(max + 1, &set, NULL, NULL, &tv);
    if (max != -1)
      client_process(max, &set, remotefd, localfd);
  }
}
```