ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_region_name_GY>:
  endbr64
  sub    $0xa,%edi
  cmp    $0x9,%edi
  ja     L6
  lea    D18(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D96(%rip),%rax
  ret
  lea    D11(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D40(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D88(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D81(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D95(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D24(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D21(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D45(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D43(%rip),%rax
  ret
L6:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D96
type: string
name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D40
type: string
name: parse_data
arguments: label: D88
type: string
name: parse_data
arguments: label: D81
type: string
name: parse_data
arguments: label: D95
type: string
name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D21
type: string
name: parse_data
arguments: label: D45
type: string
name: parse_data
arguments: label: D43
type: string

tool: D96: Cuyuni-Mazaruni

tool: D11: Barima-Waini

tool: D40: Upper Takutu-Upper Essequibo

tool: D88: Demerara-Mahaica

tool: D81: Potaro-Siparuni

tool: D95: Upper Demerara-Berbice

tool: D24: East Berbice-Corentyne

tool: D21: Essequibo Islands-West Demerara

tool: D45: Mahaica-Berbice

tool: D43: Pomeroon-Supenaam

assistant: ```c
const char *get_region_name_GY(int region_code) {
  switch (region_code) {
  case 10:
    return "Barima-Waini";
  case 11:
    return "Cuyuni-Mazaruni";
  case 12:
    return "Demerara-Mahaica";
  case 13:
    return "East Berbice-Corentyne";
  case 14:
    return "Essequibo Islands-West Demerara";
  case 15:
    return "Mahaica-Berbice";
  case 16:
    return "Pomeroon-Supenaam";
  case 17:
    return "Potaro-Siparuni";
  case 18:
    return "Upper Demerara-Berbice";
  case 19:
    return "Upper Takutu-Upper Essequibo";
  default:
    return NULL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ACCESS@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
f(int i) {
  int a[4] = {0};
  return ACCESS(a, i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  call   <ACCESS@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
f(int i) {
  int a[4] = {0};
  return ACCESS(a, i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%esi
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <ACCESS@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
f(int i) {
  int a[4] = {0};
  return ACCESS(a, i);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%esi
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <ACCESS@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
f(int i) {
  int a[4] = {0};
  return ACCESS(a, i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r11
  test   %ebx,%ebx
  js     L133
  mov    %ebx,%edx
  lea    0x1(%rax,%rdx,1),%rdx
L157:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L157
L133:
  cmp    $0x2,%r12d
  jle    L88
  lea    -0x2(%r12,%r12,1),%ecx
L117:
  mov    %ecx,%r9d
  mov    $0x0,%r10d
  mov    $0x0,%edi
  mov    $0x0,%r8d
  lea    -0x1(%r12),%r13d
  movslq %ecx,%rcx
  lea    0x1(%r11),%rax
  mov    %rax,0x8(%rsp)
  jmp    L116
L88:
  test   %r12d,%r12d
  jle    L53
  mov    %r12d,%ecx
  jmp    L117
L102:
  mov    $0x0,%esi
  cmp    %r8d,%ebx
  jle    L47
  movslq %edi,%rsi
  add    %r11,%rsi
  mov    %rsi,%rdx
  mov    %r10,%rax
  mov    $0x1,%r14d
  sub    %esi,%r14d
  mov    %r14d,%r15d
L167:
  movzbl 0x0(%rbp,%rax,1),%esi
  mov    %sil,(%rdx)
  lea    (%r15,%rdx,1),%esi
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %eax,%ebx
  jg     L167
L47:
  add    %esi,%edi
  jmp    L156
L127:
  mov    $0x0,%esi
L158:
  lea    0x1(%rdi,%rsi,2),%edi
  cmp    %edi,%r15d
  cmovle %r15d,%edi
L156:
  add    $0x1,%r8d
  add    $0x1,%r10
  sub    $0x1,%r9d
  cmp    %r8d,%r12d
  jle    L53
L116:
  test   %r8d,%r8d
  je     L102
  cmp    %r8d,%r13d
  je     L102
  mov    $0x0,%esi
  cmp    %r8d,%ebx
  jle    L60
  movslq %edi,%rdx
  add    %r11,%rdx
  mov    %r10,%rax
  mov    $0x0,%esi
L11:
  movzbl 0x0(%rbp,%rax,1),%r15d
  mov    %r15b,(%rdx)
  add    $0x1,%esi
  add    %rcx,%rax
  add    $0x2,%rdx
  cmp    %eax,%ebx
  jg     L11
L60:
  lea    (%rdi,%rsi,2),%r15d
  cmp    %r9d,%ebx
  jle    L127
  movslq %r9d,%rax
  movslq %edi,%rdx
  add    0x8(%rsp),%rdx
  mov    $0x0,%esi
L147:
  movzbl 0x0(%rbp,%rax,1),%r14d
  mov    %r14b,(%rdx)
  add    $0x1,%esi
  add    %rcx,%rax
  add    $0x2,%rdx
  cmp    %eax,%ebx
  jg     L147
  jmp    L158
L53:
  mov    %r11,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *convert(char *s, int num_row) {
  int length = strlen(s);
  char *retval = (char *)malloc(length + 1);
  int i, r, mem, mem1, mem2;
  int num_per_trk;
  for (i = 0; i < length + 1; i++)
    retval[i] = 0;
  num_per_trk = (num_row > 2) ? (2 * num_row - 2) : num_row;
  mem = 0;
  for (r = 0; r < num_row; r++) {
    if (r == 0 || r == num_row - 1) {
      for (i = 0; i * num_per_trk + r < length; i++)
        retval[mem + i] = s[i * num_per_trk + r];
      mem += i;
      continue;
    }
    for (i = 0; i * num_per_trk + r < length; i++)
      retval[mem + i * 2] = s[i * num_per_trk + r];
    mem1 = mem + i * 2;
    for (i = 0; i * num_per_trk + num_per_trk - r < length; i++)
      retval[mem + i * 2 + 1] = s[i * num_per_trk + num_per_trk - r];
    mem2 = mem + i * 2 + 1;
    mem = (mem1 < mem2) ? mem1 : mem2;
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  mov    %rax,%r11
  test   %ebx,%ebx
  js     L68
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %rax,%r11
L68:
  cmp    $0x2,%r12d
  jle    L32
  lea    -0x2(%r12,%r12,1),%r10d
L39:
  lea    0x1(%r11),%rax
  xor    %r13d,%r13d
  xor    %edi,%edi
  xor    %r9d,%r9d
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r12),%r15d
  movslq %r10d,%rsi
  nopw   0x0(%rax,%rax,1)
L1:
  test   %r9d,%r9d
  je     L13
  cmp    %r9d,%r15d
  je     L13
  mov    %edi,%r14d
  cmp    %r9d,%ebx
  jle    L35
  movslq %edi,%rdx
  mov    %r13,%rax
  xor    %ecx,%ecx
  add    %r11,%rdx
  nopl   (%rax)
L36:
  movzbl 0x0(%rbp,%rax,1),%r8d
  add    %rsi,%rax
  add    $0x1,%ecx
  add    $0x2,%rdx
  mov    %r8b,-0x2(%rdx)
  cmp    %eax,%ebx
  jg     L36
  lea    (%rdi,%rcx,2),%r14d
L35:
  cmp    %r10d,%ebx
  jle    L134
  mov    %edi,0x4(%rsp)
  movslq %edi,%rdx
  movslq %r10d,%rax
  add    0x8(%rsp),%rdx
  mov    $0x1,%ecx
  nopl   (%rax)
L90:
  movzbl 0x0(%rbp,%rax,1),%edi
  add    %rsi,%rax
  mov    %ecx,%r8d
  add    $0x2,%rdx
  add    $0x1,%ecx
  mov    %dil,-0x2(%rdx)
  cmp    %eax,%ebx
  jg     L90
  mov    0x4(%rsp),%edi
  lea    (%rdi,%r8,2),%edi
L134:
  add    $0x1,%edi
  cmp    %r14d,%edi
  cmovg  %r14d,%edi
L96:
  add    $0x1,%r9d
  add    $0x1,%r13
  sub    $0x1,%r10d
  cmp    %r9d,%r12d
  jg     L1
L66:
  add    $0x18,%rsp
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    %r9d,%ebx
  jle    L96
  movslq %edi,%rax
  mov    $0x1,%r8d
  mov    %r13,%rdx
  add    %r11,%rax
  sub    %eax,%r8d
  nop
L43:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  add    %rsi,%rdx
  mov    %cl,(%rax)
  lea    (%r8,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %edx,%ebx
  jg     L43
  add    %ecx,%edi
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r12d,%r10d
  test   %r12d,%r12d
  jg     L39
  jmp    L66
```

assistant: ```c
char *convert(char *s, int num_row) {
  int length = strlen(s);
  char *retval = (char *)malloc(length + 1);
  int i, r, mem, mem1, mem2;
  int num_per_trk;
  for (i = 0; i < length + 1; i++)
    retval[i] = 0;
  num_per_trk = (num_row > 2) ? (2 * num_row - 2) : num_row;
  mem = 0;
  for (r = 0; r < num_row; r++) {
    if (r == 0 || r == num_row - 1) {
      for (i = 0; i * num_per_trk + r < length; i++)
        retval[mem + i] = s[i * num_per_trk + r];
      mem += i;
      continue;
    }
    for (i = 0; i * num_per_trk + r < length; i++)
      retval[mem + i * 2] = s[i * num_per_trk + r];
    mem1 = mem + i * 2;
    for (i = 0; i * num_per_trk + num_per_trk - r < length; i++)
      retval[mem + i * 2 + 1] = s[i * num_per_trk + num_per_trk - r];
    mem2 = mem + i * 2 + 1;
    mem = (mem1 < mem2) ? mem1 : mem2;
  }
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<filename_non_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <HAVE_DRIVE@plt>
  test   %rax,%rax
  je     L3
  addq   $0x2,-0x18(%rbp)
  jmp    L3
L10:
  sub    $0x1,%rbx
L3:
  cmp    -0x18(%rbp),%rbx
  jbe    L19
  lea    -0x1(%rbx),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L10
L19:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if (HAVE_DRIVE(pathname))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return (filename);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filename_non_directory>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  mov    %rbp,%rdi
  call   <HAVE_DRIVE@plt>
  mov    %rax,%rdx
  lea    0x2(%rbp),%rax
  test   %rdx,%rdx
  cmovne %rax,%rbp
  cmp    %rbp,%rbx
  jbe    L2
L6:
  cmpb   $0x2f,-0x1(%rbx)
  je     L2
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
  mov    %rbp,%rbx
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if (HAVE_DRIVE(pathname))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return (filename);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filename_non_directory>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  movslq %eax,%r12
  call   <HAVE_DRIVE@plt>
  add    %rbx,%r12
  mov    %rax,%r8
  lea    0x2(%rbx),%rax
  test   %r8,%r8
  cmovne %rax,%rbx
  cmp    %rbx,%r12
  ja     L13
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L17:
  sub    $0x1,%r12
  cmp    %rbx,%r12
  je     L23
L13:
  cmpb   $0x2f,-0x1(%r12)
  jne    L17
L23:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if (HAVE_DRIVE(pathname))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return (filename);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filename_non_directory>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  movslq %eax,%r12
  call   <HAVE_DRIVE@plt>
  add    %rbx,%r12
  mov    %rax,%r8
  lea    0x2(%rbx),%rax
  test   %r8,%r8
  cmovne %rax,%rbx
  cmp    %rbx,%r12
  ja     L22
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L0:
  sub    $0x1,%r12
  cmp    %rbx,%r12
  je     L14
L22:
  cmpb   $0x2f,-0x1(%r12)
  jne    L0
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if (HAVE_DRIVE(pathname))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return (filename);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kernel__Int___42d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long kernel__Int___42d(long self, long p0) {
  long var;
  long var1;
  var1 = self * p0;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: What is the c source code of the assembly code below:

```asm
<kernel__Int___42d>:
  endbr64
  mov    %rdi,%rax
  imul   %rsi,%rax
  ret
```

assistant: ```c
long kernel__Int___42d(long self, long p0) {
  long var;
  long var1;
  var1 = self * p0;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kernel__Int___42d>:
  endbr64
  mov    %rdi,%rax
  imul   %rsi,%rax
  ret
```

assistant: ```c
long kernel__Int___42d(long self, long p0) {
  long var;
  long var1;
  var1 = self * p0;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kernel__Int___42d>:
  endbr64
  mov    %rdi,%rax
  imul   %rsi,%rax
  ret
```

assistant: ```c
long kernel__Int___42d(long self, long p0) {
  long var;
  long var1;
  var1 = self * p0;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D19(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  movq   %rdx,%xmm0
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <trans@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: f64
name: parse_data
arguments: label: D22
data_type: f64
name: parse_data
arguments: label: D19
data_type: byte[8]

tool: D1: 1

tool: D22: 0.7

tool: {"D19": [0x33,0x33,0x33,0x33,0x33,0x33,0xd3,0xbf]}

assistant: ```c
double f(double x) {
  double fp[5] = {+1.0, 0.7, -0.3, 0.0, 0.0};
  double y;
  y = trans(fp, 5, x);
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D24(%rip),%rax
  mov    %rax,(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D4(%rip),%rax
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <trans@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D24
datatype: f64
name: disassemble_data
arguments: label: D25
datatype: f64
name: disassemble_data
arguments: label: D4
datatype: byte[8]

tool: D24: 1

tool: D25: 0.7

tool: {"D4": [0x33,0x33,0x33,0x33,0x33,0x33,0xd3,0xbf]}

assistant: ```c
double f(double x) {
  double fp[5] = {+1.0, 0.7, -0.3, 0.0, 0.0};
  double y;
  y = trans(fp, 5, x);
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    %rsp,%rdi
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    %rax,(%rsp)
  mov    D0(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D1(%rip),%rax
  mov    %rax,0x10(%rsp)
  call   <trans@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: f64
name: retrieve_data
arguments: data_label: D0
datatype: f64
name: retrieve_data
arguments: data_label: D1
datatype: byte[8]

tool: D26: 1

tool: D0: 0.7

tool: {"D1": [0x33,0x33,0x33,0x33,0x33,0x33,0xd3,0xbf]}

assistant: ```c
double f(double x) {
  double fp[5] = {+1.0, 0.7, -0.3, 0.0, 0.0};
  double y;
  y = trans(fp, 5, x);
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  sub    $0x38,%rsp
  movapd D17(%rip),%xmm1
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,0x20(%rsp)
  movaps %xmm1,(%rsp)
  movq   D6(%rip),%xmm1
  movaps %xmm1,0x10(%rsp)
  call   <trans@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
type_guessed: f64[2]
name: parse_data
arguments: data_label: D6
type_guessed: byte[8]

tool: {"D17": [1.0,0.7]}

tool: {"D6": [0x33,0x33,0x33,0x33,0x33,0x33,0xd3,0xbf]}

assistant: ```c
double f(double x) {
  double fp[5] = {+1.0, 0.7, -0.3, 0.0, 0.0};
  double y;
  y = trans(fp, 5, x);
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sem_read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  je     L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strip_newline@plt>
  jmp    L11
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *sem_read_line(FILE *in) {
  char *line = NULL;
  size_t len = 0;
  if (getline(&line, &len, in) != -1) {
    return strip_newline(line);
  } else {
    free(line);
    return NULL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sem_read_line>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    0x8(%rsp),%rdi
  call   <strip_newline@plt>
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x28,%rsp
  ret
L3:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L8
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *sem_read_line(FILE *in) {
  char *line = NULL;
  size_t len = 0;
  if (getline(&line, &len, in) != -1) {
    return strip_newline(line);
  } else {
    free(line);
    return NULL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sem_read_line>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <getline@plt>
  mov    0x8(%rsp),%rdi
  cmp    $0xffffffff,%eax
  je     L26
  call   <strip_newline@plt>
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x28,%rsp
  ret
L26:
  call   <free@plt>
  xor    %eax,%eax
  jmp    L24
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *sem_read_line(FILE *in) {
  char *line = NULL;
  size_t len = 0;
  if (getline(&line, &len, in) != -1) {
    return strip_newline(line);
  } else {
    free(line);
    return NULL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sem_read_line>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <getline@plt>
  mov    0x8(%rsp),%rdi
  cmp    $0xffffffff,%eax
  je     L23
  call   <strip_newline@plt>
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  ret
L23:
  call   <free@plt>
  xor    %eax,%eax
  jmp    L17
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *sem_read_line(FILE *in) {
  char *line = NULL;
  size_t len = 0;
  if (getline(&line, &len, in) != -1) {
    return strip_newline(line);
  } else {
    free(line);
    return NULL;
  }
}
```