ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readHB_newmat_double>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  lea    0xc(%rsp),%r9
  lea    0x10(%rsp),%r8
  mov    0x60(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <readHB_info@plt>
  mov    (%r15),%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L67
L33:
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L79
L74:
  mov    0x10(%rsp),%rax
  movzbl (%rax),%eax
  cmp    $0x43,%al
  je     L30
  cmp    $0x50,%al
  jne    L77
L20:
  mov    (%r14),%rcx
L75:
  mov    0x0(%r13),%rdx
  mov    (%r12),%rsi
  mov    %rbp,%rdi
  call   <readHB_mat_double@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L77:
  mov    (%rbx),%edi
  shl    $0x3,%edi
L35:
  call   <malloc@plt>
  mov    %rax,(%r14)
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L75
  lea    D21(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L30:
  mov    (%rbx),%edi
  shl    $0x4,%edi
  jmp    L35
  nop
L67:
  lea    D6(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L33
  nopl   0x0(%rax)
L79:
  lea    D26(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L74
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string

tool: D21: Insufficient memory for val.


tool: D6: Insufficient memory for colptr.


tool: D26: Insufficient memory for rowind.


assistant: ```c
int readHB_newmat_double(const char *filename, int *M, int *N, int *nonzeros, int **colptr, int **rowind, double **val) {
  int Nrhs;
  char *Type;
  readHB_info(filename, M, N, nonzeros, &Type, &Nrhs);
  *colptr = (int *)malloc((*N + 1) * sizeof(int));
  if (*colptr == NULL)
    IOHBTerminate("Insufficient memory for colptr.\n");
  *rowind = (int *)malloc(*nonzeros * sizeof(int));
  if (*rowind == NULL)
    IOHBTerminate("Insufficient memory for rowind.\n");
  if (Type[0] == 'C') {
    *val = (double *)malloc(*nonzeros * sizeof(double) * 2);
    if (*val == NULL)
      IOHBTerminate("Insufficient memory for val.\n");
  } else {
    if (Type[0] != 'P') {
      *val = (double *)malloc(*nonzeros * sizeof(double));
      if (*val == NULL)
        IOHBTerminate("Insufficient memory for val.\n");
    }
  }
  return readHB_mat_double(filename, *colptr, *rowind, *val);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readHB_newmat_double>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  lea    0xc(%rsp),%r9
  lea    0x10(%rsp),%r8
  mov    0x60(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <readHB_info@plt>
  mov    (%r15),%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L89
L27:
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L54
L95:
  mov    0x10(%rsp),%rax
  movzbl (%rax),%eax
  cmp    $0x43,%al
  je     L69
  cmp    $0x50,%al
  jne    L75
L87:
  mov    (%r14),%rcx
L45:
  mov    0x0(%r13),%rdx
  mov    (%r12),%rsi
  mov    %rbp,%rdi
  call   <readHB_mat_double@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L75:
  mov    (%rbx),%edi
  shl    $0x3,%edi
L82:
  call   <malloc@plt>
  mov    %rax,(%r14)
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L45
  lea    D13(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L69:
  mov    (%rbx),%edi
  shl    $0x4,%edi
  jmp    L82
  nop
L89:
  lea    D18(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L27
  nopl   0x0(%rax)
L54:
  lea    D17(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L95
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string
name: unpack_data
arguments: data_label: D17
data_type: string

tool: D13: Insufficient memory for val.


tool: D18: Insufficient memory for colptr.


tool: D17: Insufficient memory for rowind.


assistant: ```c
int readHB_newmat_double(const char *filename, int *M, int *N, int *nonzeros, int **colptr, int **rowind, double **val) {
  int Nrhs;
  char *Type;
  readHB_info(filename, M, N, nonzeros, &Type, &Nrhs);
  *colptr = (int *)malloc((*N + 1) * sizeof(int));
  if (*colptr == NULL)
    IOHBTerminate("Insufficient memory for colptr.\n");
  *rowind = (int *)malloc(*nonzeros * sizeof(int));
  if (*rowind == NULL)
    IOHBTerminate("Insufficient memory for rowind.\n");
  if (Type[0] == 'C') {
    *val = (double *)malloc(*nonzeros * sizeof(double) * 2);
    if (*val == NULL)
      IOHBTerminate("Insufficient memory for val.\n");
  } else {
    if (Type[0] != 'P') {
      *val = (double *)malloc(*nonzeros * sizeof(double));
      if (*val == NULL)
        IOHBTerminate("Insufficient memory for val.\n");
    }
  }
  return readHB_mat_double(filename, *colptr, *rowind, *val);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  movss  %xmm0,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L49
  movss  -0x8(%rbp),%xmm0
  mulss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L2
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L49
L2:
  mov    $0x1,%eax
  jmp    L58
L49:
  mov    $0x0,%eax
L58:
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  call   <a@plt>
  jmp    L36
L11:
  mov    $0x0,%eax
  call   <b@plt>
L36:
  nop
  leave
  ret
```

assistant: ```c
void f(int i, float j, int i2, float j2) {
  if (__builtin_expect((i * i2) > 0 && (j * j2), 0))
    a();
  else
    b();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  imul   %esi,%edi
  mov    $0x0,%eax
  test   %edi,%edi
  jle    L14
  mulss  %xmm1,%xmm0
  ucomiss D0(%rip),%xmm0
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
L14:
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L28
  mov    $0x0,%eax
  call   <a@plt>
L27:
  add    $0x8,%rsp
  ret
L28:
  mov    $0x0,%eax
  call   <b@plt>
  jmp    L27
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x00]}

assistant: ```c
void f(int i, float j, int i2, float j2) {
  if (__builtin_expect((i * i2) > 0 && (j * j2), 0))
    a();
  else
    b();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  imul   %esi,%edi
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L11
  mulss  %xmm1,%xmm0
  xor    %r8d,%r8d
  mov    $0x1,%eax
  ucomiss D2(%rip),%xmm0
  setp   %r8b
  cmovne %eax,%r8d
L11:
  xor    %esi,%esi
  mov    %r8d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L3
  add    $0x8,%rsp
  jmp    1090 <a@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  jmp    1070 <b@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x00]}

assistant: ```c
void f(int i, float j, int i2, float j2) {
  if (__builtin_expect((i * i2) > 0 && (j * j2), 0))
    a();
  else
    b();
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  imul   %esi,%edi
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L9
  mulss  %xmm1,%xmm0
  xor    %r8d,%r8d
  mov    $0x1,%eax
  ucomiss D8(%rip),%xmm0
  setp   %r8b
  cmovne %eax,%r8d
L9:
  xor    %esi,%esi
  mov    %r8d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L19
  add    $0x8,%rsp
  jmp    1090 <a@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  jmp    1070 <b@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x00]}

assistant: ```c
void f(int i, float j, int i2, float j2) {
  if (__builtin_expect((i * i2) > 0 && (j * j2), 0))
    a();
  else
    b();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<e_ror_zpx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_ror@plt>
  mov    $0x0,%eax
  call   <e_writeback@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e_ror_zpx() {
  e_zpx();
  e_ror();
  e_writeback();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<e_ror_zpx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_ror@plt>
  mov    $0x0,%eax
  call   <e_writeback@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void e_ror_zpx() {
  e_zpx();
  e_ror();
  e_writeback();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<e_ror_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  call   <e_ror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <e_writeback@plt>
```

assistant: ```c
void e_ror_zpx() {
  e_zpx();
  e_ror();
  e_writeback();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<create_quaddobl_homotopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xb6,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int create_quaddobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(182, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<create_quaddobl_homotopy>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xb6,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int create_quaddobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(182, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<create_quaddobl_homotopy>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xb6,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int create_quaddobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(182, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<create_quaddobl_homotopy>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xb6,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int create_quaddobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(182, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<CheckVarName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  addl   $0x1,-0x4(%rbp)
L3:
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int CheckVarName(char **varlist, int numvars, char *sVarName) {
  int i, foundit = 0;
  for (i = 0; i < numvars; ++i)
    if (strcmp(varlist[i], sVarName) == 0)
      foundit++;
  return (foundit);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CheckVarName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L1
  mov    %rdx,%r12
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r13
  mov    $0x0,%ebp
L13:
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L13
L10:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    $0x0,%ebp
  jmp    L10
```

assistant: ```c
int CheckVarName(char **varlist, int numvars, char *sVarName) {
  int i, foundit = 0;
  for (i = 0; i < numvars; ++i)
    if (strcmp(varlist[i], sVarName) == 0)
      foundit++;
  return (foundit);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CheckVarName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %rdx,%rbp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x8(%rdi,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L12
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int CheckVarName(char **varlist, int numvars, char *sVarName) {
  int i, foundit = 0;
  for (i = 0; i < numvars; ++i)
    if (strcmp(varlist[i], sVarName) == 0)
      foundit++;
  return (foundit);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CheckVarName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  mov    %rdx,%rbp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x8(%rdi,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int CheckVarName(char **varlist, int numvars, char *sVarName) {
  int i, foundit = 0;
  for (i = 0; i < numvars; ++i)
    if (strcmp(varlist[i], sVarName) == 0)
      foundit++;
  return (foundit);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L8
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L8
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L16
L8:
  mov    $0x1,%eax
  jmp    L39
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L44
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int get_int(char *in, int *out) {
  int i, o = 0, len = strlen(in);
  for (i = 0; i < len; i++) {
    if ('0' <= *in && *in <= '9')
      o = o * 10 + *in - '0';
    else
      return 1;
    in++;
  }
  *out = o;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L31
  mov    %eax,%eax
  lea    (%rbx,%rax,1),%rsi
  mov    $0x0,%edx
L2:
  movzbl (%rbx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L39
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rbx
  cmp    %rsi,%rbx
  jne    L2
L13:
  mov    %edx,0x0(%rbp)
  mov    $0x0,%eax
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    $0x0,%edx
  jmp    L13
L39:
  mov    $0x1,%eax
  jmp    L48
```

assistant: ```c
int get_int(char *in, int *out) {
  int i, o = 0, len = strlen(in);
  for (i = 0; i < len; i++) {
    if ('0' <= *in && *in <= '9')
      o = o * 10 + *in - '0';
    else
      return 1;
    in++;
  }
  *out = o;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L32
  cltq
  xor    %edx,%edx
  lea    (%rbx,%rax,1),%rsi
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L14:
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%edx
  cmp    %rsi,%rbx
  je     L28
L21:
  movsbl (%rbx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L14
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  xor    %edx,%edx
L28:
  mov    %edx,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_int(char *in, int *out) {
  int i, o = 0, len = strlen(in);
  for (i = 0; i < len; i++) {
    if ('0' <= *in && *in <= '9')
      o = o * 10 + *in - '0';
    else
      return 1;
    in++;
  }
  *out = o;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L39
  cltq
  xor    %edx,%edx
  lea    (%rbx,%rax,1),%rsi
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L32:
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%edx
  cmp    %rbx,%rsi
  je     L16
L18:
  movsbl (%rbx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L32
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L39:
  xor    %edx,%edx
L16:
  mov    %edx,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_int(char *in, int *out) {
  int i, o = 0, len = strlen(in);
  for (i = 0; i < len; i++) {
    if ('0' <= *in && *in <= '9')
      o = o * 10 + *in - '0';
    else
      return 1;
    in++;
  }
  *out = o;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L16
L28:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  mov    %eax,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D15: /

tool: D8: cd: cannot change to %s


assistant: ```c
int cd(char *dir) {
  int ret;
  if (dir)
    ret = chdir(dir);
  else
    ret = chdir("/");
  if (ret < 0) {
    printf("cd: cannot change to %s\n", dir);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L20
  call   <chdir@plt>
  mov    %eax,%ebx
L35:
  test   %ebx,%ebx
  js     L1
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  lea    D12(%rip),%rdi
  call   <chdir@plt>
  mov    %eax,%ebx
  jmp    L35
L1:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D0
type: string

tool: D12: /

tool: D0: cd: cannot change to %s


assistant: ```c
int cd(char *dir) {
  int ret;
  if (dir)
    ret = chdir(dir);
  else
    ret = chdir("/");
  if (ret < 0) {
    printf("cd: cannot change to %s\n", dir);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cd>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  call   <chdir@plt>
  mov    %eax,%r12d
  test   %r12d,%r12d
  js     L15
L26:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D14(%rip),%rdi
  call   <chdir@plt>
  mov    %eax,%r12d
  test   %r12d,%r12d
  jns    L26
L15:
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D10
type: string

tool: D14: /

tool: D10: cd: cannot change to %s


assistant: ```c
int cd(char *dir) {
  int ret;
  if (dir)
    ret = chdir(dir);
  else
    ret = chdir("/");
  if (ret < 0) {
    printf("cd: cannot change to %s\n", dir);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cd>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L16
  call   <chdir@plt>
  mov    %eax,%r12d
  test   %r12d,%r12d
  js     L28
L23:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  lea    D11(%rip),%rdi
  call   <chdir@plt>
  mov    %eax,%r12d
  test   %r12d,%r12d
  jns    L23
L28:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D11: /

tool: D6: cd: cannot change to %s


assistant: ```c
int cd(char *dir) {
  int ret;
  if (dir)
    ret = chdir(dir);
  else
    ret = chdir("/");
  if (ret < 0) {
    printf("cd: cannot change to %s\n", dir);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D4
type: string

tool: D9: abcdec

tool: D4: s=%s, res=%d


assistant: ```c
int main() {
  char *s = "abcdec";
  printf("s=%s, res=%d\n", s, lengthOfLongestSubstring(s));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string

tool: D17: abcdec

tool: D12: s=%s, res=%d


assistant: ```c
int main() {
  char *s = "abcdec";
  printf("s=%s, res=%d\n", s, lengthOfLongestSubstring(s));
  return 0;
}
```