user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x3c(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L40
L41:
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x30(%rbp)
L40:
  mov    -0x3c(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  jb     L41
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L36
L87:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L66
  addl   $0x1,-0x38(%rbp)
L66:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  sub    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L82
  addl   $0x1,-0x34(%rbp)
L82:
  addq   $0x1,-0x28(%rbp)
L36:
  mov    -0x3c(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jb     L87
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L83
  mov    -0x3c(%rbp),%eax
  sub    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L73
L83:
  mov    -0x3c(%rbp),%eax
  sub    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L73:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D28: r

tool: D19: input.txt

tool: D4: %d

tool: D10: %d


assistant: ```c
int main() {
  FILE *fp;
  fp = fopen("input.txt", "r");
  int n;
  fscanf(fp, "%d", &n);
  int *a = malloc(sizeof(int) * n);
  int *s = malloc(sizeof(int) * n);
  for (size_t i = 0; i < n; i++) {
    fscanf(fp, "%d", &a[i]);
    s[i] = a[i];
  }
  quick_sort(s, 0, n - 1);
  int cnt = 0, rcnt = 0;
  for (size_t i = 0; i < n; i++) {
    if (a[i] == s[i]) {
      cnt++;
    }
    if (a[i] == s[n - 1 - i]) {
      rcnt++;
    }
  }
  if (cnt > rcnt) {
    printf("%d\n", n - cnt - 1);
  } else {
    printf("%d\n", n - rcnt - 1);
  }
  fclose(fp);
  free(a);
  free(s);
  return 0;
}
```