ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<dllockinit>:
  endbr64
  sub    $0x8,%rsp
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  je     L3
  call   *%rax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dllockinit(void *context, void *(*lock_create)(void *context), void (*rlock_acquire)(void *lock), void (*wlock_acquire)(void *lock), void (*lock_release)(void *lock), void (*lock_destroy)(void *lock), void (*context_destroy)(void *context)) {
  if (context_destroy != NULL)
    context_destroy(context);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dllockinit>:
  endbr64
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L3
  jmp    *%rax
L3:
  ret
```

assistant: ```c
void dllockinit(void *context, void *(*lock_create)(void *context), void (*rlock_acquire)(void *lock), void (*wlock_acquire)(void *lock), void (*lock_release)(void *lock), void (*lock_destroy)(void *lock), void (*context_destroy)(void *context)) {
  if (context_destroy != NULL)
    context_destroy(context);
}
```
user: What is the c source code of the assembly code below?

```asm
<dllockinit>:
  endbr64
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L5
  jmp    *%rax
L5:
  ret
```

assistant: ```c
void dllockinit(void *context, void *(*lock_create)(void *context), void (*rlock_acquire)(void *lock), void (*wlock_acquire)(void *lock), void (*lock_release)(void *lock), void (*lock_destroy)(void *lock), void (*context_destroy)(void *context)) {
  if (context_destroy != NULL)
    context_destroy(context);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<net_sock_nonblocking>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L20
  mov    $0xffffffff,%eax
  jmp    L1
L20:
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  or     %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  test   %rax,%rax
  jns    L10
  mov    $0xffffffff,%eax
  jmp    L1
L10:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int net_sock_nonblocking(int sock) {
  int flags = fcntl(sock, F_GETFL, 0);
  if (flags < 0)
    return -1;
  flags |= O_NONBLOCK;
  if (fcntl(sock, F_SETFL, flags) < 0)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<net_sock_nonblocking>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  js     L18
  mov    D1(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  sar    $0x3f,%rax
L3:
  pop    %rbx
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int net_sock_nonblocking(int sock) {
  int flags = fcntl(sock, F_GETFL, 0);
  if (flags < 0)
    return -1;
  flags |= O_NONBLOCK;
  if (fcntl(sock, F_SETFL, flags) < 0)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<net_sock_nonblocking>:
  endbr64
  mov    D15(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  js     L4
  mov    D6(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  pop    %rbp
  sar    $0x3f,%rax
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int net_sock_nonblocking(int sock) {
  int flags = fcntl(sock, F_GETFL, 0);
  if (flags < 0)
    return -1;
  flags |= O_NONBLOCK;
  if (fcntl(sock, F_SETFL, flags) < 0)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<net_sock_nonblocking>:
  endbr64
  mov    D25(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  js     L1
  mov    D9(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  pop    %rbp
  sar    $0x3f,%rax
  ret
  nopl   0x0(%rax)
L1:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int net_sock_nonblocking(int sock) {
  int flags = fcntl(sock, F_GETFL, 0);
  if (flags < 0)
    return -1;
  flags |= O_NONBLOCK;
  if (fcntl(sock, F_SETFL, flags) < 0)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stbi_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <e@plt>
  mov    $0x0,%eax
  jmp    L13
L2:
  mov    -0x34(%rbp),%edi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <stbi_load_from_file@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D24
datatype: string

tool: D4: rb

tool: D5: Can't open file


tool: D24: can't fopen

assistant: ```c
unsigned char *stbi_load(char const *filename, int *x, int *y, int *comp, int req_comp) {
  FILE *f = fopen(filename, "rb");
  unsigned char *result;
  if (!f) {
    printf("Can't open file\n");
    return ((unsigned char *)(e("can't fopen") ? NULL : NULL));
  }
  result = stbi_load_from_file(f, x, y, comp, req_comp);
  fclose(f);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stbi_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8d,%r14d
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
  mov    %r14d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <stbi_load_from_file@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fclose@plt>
L17:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <e@plt>
  mov    %rbx,%rbp
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string

tool: D11: rb

tool: D15: Can't open file


tool: D27: can't fopen

assistant: ```c
unsigned char *stbi_load(char const *filename, int *x, int *y, int *comp, int req_comp) {
  FILE *f = fopen(filename, "rb");
  unsigned char *result;
  if (!f) {
    printf("Can't open file\n");
    return ((unsigned char *)(e("can't fopen") ? NULL : NULL));
  }
  result = stbi_load_from_file(f, x, y, comp, req_comp);
  fclose(f);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stbi_load>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D7(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <fopen@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <stbi_load_from_file@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
L7:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D18(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <e@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string

tool: D7: rb

tool: D18: Can't open file


tool: D21: can't fopen

assistant: ```c
unsigned char *stbi_load(char const *filename, int *x, int *y, int *comp, int req_comp) {
  FILE *f = fopen(filename, "rb");
  unsigned char *result;
  if (!f) {
    printf("Can't open file\n");
    return ((unsigned char *)(e("can't fopen") ? NULL : NULL));
  }
  result = stbi_load_from_file(f, x, y, comp, req_comp);
  fclose(f);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stbi_load>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D22(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <fopen@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <stbi_load_from_file@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
L14:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  lea    D8(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <e@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string

tool: D22: rb

tool: D8: Can't open file


tool: D19: can't fopen

assistant: ```c
unsigned char *stbi_load(char const *filename, int *x, int *y, int *comp, int req_comp) {
  FILE *f = fopen(filename, "rb");
  unsigned char *result;
  if (!f) {
    printf("Can't open file\n");
    return ((unsigned char *)(e("can't fopen") ? NULL : NULL));
  }
  result = stbi_load_from_file(f, x, y, comp, req_comp);
  fclose(f);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<initialize_quaddobl_monodromy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x29e,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int initialize_quaddobl_monodromy(int n, int d, int k) {
  int fail;
  double *c;
  int dk[2];
  dk[0] = d;
  dk[1] = k;
  fail = _ada_use_c2phc4c(670, &n, dk, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<initialize_quaddobl_monodromy>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x29e,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_quaddobl_monodromy(int n, int d, int k) {
  int fail;
  double *c;
  int dk[2];
  dk[0] = d;
  dk[1] = k;
  fail = _ada_use_c2phc4c(670, &n, dk, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initialize_quaddobl_monodromy>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  mov    $0x29e,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %edx,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_quaddobl_monodromy(int n, int d, int k) {
  int fail;
  double *c;
  int dk[2];
  dk[0] = d;
  dk[1] = k;
  fail = _ada_use_c2phc4c(670, &n, dk, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initialize_quaddobl_monodromy>:
  endbr64
  sub    $0x28,%rsp
  movd   %esi,%xmm0
  movd   %edx,%xmm1
  xor    %r8d,%r8d
  mov    %edi,0xc(%rsp)
  punpckldq %xmm1,%xmm0
  lea    0x10(%rsp),%rdx
  xor    %ecx,%ecx
  lea    0xc(%rsp),%rsi
  mov    $0x29e,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_quaddobl_monodromy(int n, int d, int k) {
  int fail;
  double *c;
  int dk[2];
  dk[0] = d;
  dk[1] = k;
  fail = _ada_use_c2phc4c(670, &n, dk, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<NS_GetTotalXPforLevel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L24:
  cmpl   $0x1,-0x4(%rbp)
  jle    L22
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  jmp    L31
L22:
  nop
L31:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L24
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int NS_GetTotalXPforLevel(int level) {
  int total = 0;
  int i;
  for (i = 0; i <= level; i++) {
    if (i <= 1) {
      continue;
    }
    total += i;
  }
  return total;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<NS_GetTotalXPforLevel>:
  endbr64
  test   %edi,%edi
  js     L6
  add    $0x1,%edi
  mov    $0x0,%eax
  mov    $0x0,%edx
  jmp    L2
L13:
  lea    (%rdx,%rax,1),%ecx
  cmp    $0x1,%eax
  cmovg  %ecx,%edx
L2:
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L13
L22:
  mov    %edx,%eax
  ret
L6:
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
int NS_GetTotalXPforLevel(int level) {
  int total = 0;
  int i;
  for (i = 0; i <= level; i++) {
    if (i <= 1) {
      continue;
    }
    total += i;
  }
  return total;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NS_GetTotalXPforLevel>:
  endbr64
  test   %edi,%edi
  js     L1
  add    $0x1,%edi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L15:
  lea    (%r8,%rax,1),%edx
  cmp    $0x1,%eax
  cmovg  %edx,%r8d
L7:
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L15
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int NS_GetTotalXPforLevel(int level) {
  int total = 0;
  int i;
  for (i = 0; i <= level; i++) {
    if (i <= 1) {
      continue;
    }
    total += i;
  }
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NS_GetTotalXPforLevel>:
  endbr64
  test   %edi,%edi
  js     L0
  je     L0
  lea    -0x1(%rdi),%eax
  cmp    $0x5,%eax
  jbe    L88
  mov    %edi,%edx
  movdqa D14(%rip),%xmm2
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D18(%rip),%xmm5
  movdqa D7(%rip),%xmm4
  shr    $0x2,%edx
  nopl   0x0(%rax)
L34:
  movdqa %xmm2,%xmm3
  add    $0x1,%eax
  paddd  %xmm5,%xmm2
  movdqa %xmm3,%xmm1
  pcmpgtd %xmm4,%xmm1
  pand   %xmm3,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %eax,%edx
  jne    L34
  movdqa %xmm0,%xmm1
  mov    %edi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  lea    0x1(%rcx),%edx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %ecx,%edi
  je     L35
  add    %edx,%eax
L79:
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%edi
  jl     L35
  add    %ecx,%eax
  lea    0x2(%rdx),%ecx
  cmp    %ecx,%edi
  jl     L35
  add    %ecx,%eax
  lea    0x3(%rdx),%ecx
  cmp    %ecx,%edi
  jl     L35
  add    %ecx,%eax
  lea    0x4(%rdx),%ecx
  cmp    %ecx,%edi
  jl     L35
  add    %ecx,%eax
  add    $0x5,%edx
  lea    (%rax,%rdx,1),%ecx
  cmp    %edx,%edi
  cmovge %ecx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
L35:
  ret
L88:
  mov    $0x1,%edx
  xor    %eax,%eax
  jmp    L79
```

tool_calls: name: unpack_data
arguments: data_label: D14
datatype: byte[16]
name: unpack_data
arguments: data_label: D18
datatype: byte[16]
name: unpack_data
arguments: data_label: D7
datatype: byte[16]

tool: {"D14": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D18": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D7": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int NS_GetTotalXPforLevel(int level) {
  int total = 0;
  int i;
  for (i = 0; i <= level; i++) {
    if (i <= 1) {
      continue;
    }
    total += i;
  }
  return total;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<string_has_highlight_regex_compiled>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x58(%rbp)
  je     L53
  cmpq   $0x0,-0x60(%rbp)
  jne    L158
L53:
  mov    $0x0,%eax
  jmp    L148
L156:
  lea    -0x30(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  mov    -0x60(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <regexec@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jne    L124
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  js     L124
  mov    -0x28(%rbp),%eax
  test   %eax,%eax
  jle    L124
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jne    L129
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <utf8_prev_char@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <string_is_word_char@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x44(%rbp)
L129:
  movl   $0x0,-0x40(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  je     L106
  mov    -0x28(%rbp),%ebx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L16
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <string_is_word_char@plt>
  test   %eax,%eax
  jne    L108
L16:
  mov    $0x1,%eax
  jmp    L47
L108:
  mov    $0x0,%eax
L47:
  mov    %eax,-0x40(%rbp)
L106:
  cmpl   $0x0,-0x44(%rbp)
  je     L91
  cmpl   $0x0,-0x40(%rbp)
  je     L91
  mov    $0x1,%eax
  jmp    L148
L91:
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,-0x58(%rbp)
L158:
  cmpq   $0x0,-0x58(%rbp)
  je     L124
  mov    -0x58(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L156
L124:
  mov    $0x0,%eax
L148:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int string_has_highlight_regex_compiled(const char *string, regex_t *regex) {
  int rc, startswith, endswith;
  regmatch_t regex_match;
  const char *match_pre;
  if (!string || !regex)
    return 0;
  while (string && string[0]) {
    rc = regexec(regex, string, 1, &regex_match, 0);
    if ((rc != 0) || (regex_match.rm_so < 0) || (regex_match.rm_eo <= 0))
      break;
    startswith = (regex_match.rm_so == 0);
    if (!startswith) {
      match_pre = utf8_prev_char(string, string + regex_match.rm_so);
      startswith = !string_is_word_char(match_pre);
    }
    endswith = 0;
    if (startswith) {
      endswith = ((regex_match.rm_eo == (int)strlen(string)) || !string_is_word_char(string + regex_match.rm_eo));
    }
    if (startswith && endswith)
      return 1;
    string += regex_match.rm_eo;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<string_has_highlight_regex_compiled>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L150
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L150
  mov    %rsp,%r12
  jmp    L97
L102:
  add    %rbx,%rsi
  mov    %rbx,%rdi
  call   <utf8_prev_char@plt>
  mov    %rax,%rdi
  call   <string_is_word_char@plt>
  test   %eax,%eax
  jne    L31
  jmp    L53
L132:
  movslq %r13d,%rdi
  add    %rbx,%rdi
  call   <string_is_word_char@plt>
  test   %eax,%eax
  je     L88
L31:
  movslq 0x8(%rsp),%rax
  add    %rax,%rbx
L97:
  cmpb   $0x0,(%rbx)
  je     L2
  mov    $0x0,%r8d
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <regexec@plt>
  test   %eax,%eax
  jne    L129
  mov    (%rsp),%rsi
  test   %rsi,%rsi
  js     L75
  cmpl   $0x0,0x8(%rsp)
  jle    L75
  test   %rsi,%rsi
  jne    L102
L53:
  mov    0x8(%rsp),%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %eax,%r13d
  jne    L132
  mov    $0x1,%eax
L75:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L143
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0x0,%eax
  jmp    L75
L150:
  mov    $0x0,%eax
  jmp    L75
L129:
  mov    $0x0,%eax
  jmp    L75
L88:
  mov    $0x1,%eax
  jmp    L75
L143:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_has_highlight_regex_compiled(const char *string, regex_t *regex) {
  int rc, startswith, endswith;
  regmatch_t regex_match;
  const char *match_pre;
  if (!string || !regex)
    return 0;
  while (string && string[0]) {
    rc = regexec(regex, string, 1, &regex_match, 0);
    if ((rc != 0) || (regex_match.rm_so < 0) || (regex_match.rm_eo <= 0))
      break;
    startswith = (regex_match.rm_so == 0);
    if (!startswith) {
      match_pre = utf8_prev_char(string, string + regex_match.rm_so);
      startswith = !string_is_word_char(match_pre);
    }
    endswith = 0;
    if (startswith) {
      endswith = ((regex_match.rm_eo == (int)strlen(string)) || !string_is_word_char(string + regex_match.rm_eo));
    }
    if (startswith && endswith)
      return 1;
    string += regex_match.rm_eo;
  }
  return 0;
}
```