ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_func>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L3:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <send_data@plt>
  mov    $0x186a0,%edi
  mov    %eax,%ebx
  call   <usleep@plt>
  test   %ebx,%ebx
  jns    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D19: Sending measure request.


tool: D5: Reserved:"for future request flags"

assistant: ```c
void *send_func(void *param) {
  int n = 0;
  while (n >= 0) {
    printf("Sending measure request.\n");
    n = send_data((size_t)param, "Reserved:\"for future request flags\"");
    usleep(100000);
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_func>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L4:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <send_data@plt>
  mov    $0x186a0,%edi
  mov    %eax,%ebx
  call   <usleep@plt>
  test   %ebx,%ebx
  jns    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D5
type: string

tool: D6: Sending measure request.


tool: D5: Reserved:"for future request flags"

assistant: ```c
void *send_func(void *param) {
  int n = 0;
  while (n >= 0) {
    printf("Sending measure request.\n");
    n = send_data((size_t)param, "Reserved:\"for future request flags\"");
    usleep(100000);
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<rio_writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L1
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L53
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L53:
  mov    $0xffffffff,%eax
  jmp    L33
L1:
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L49:
  cmpq   $0x0,-0x10(%rbp)
  jne    L0
  mov    -0x38(%rbp),%rax
L33:
  leave
  ret
```

assistant: ```c
ssize_t rio_writen(int fd, void *usrbuf, size_t n) {
  size_t nleft = n;
  ssize_t nwritten;
  char *bufp = usrbuf;
  while (nleft > 0) {
    if ((nwritten = write(fd, bufp, nleft)) <= 0) {
      if (EINTR == errno)
        nwritten = 0;
      else
        return -1;
    }
    nleft -= nwritten;
    bufp += nwritten;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rio_writen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L61
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%r14d
  jmp    L36
L69:
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L61
L36:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L69
  mov    D15(%rip),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L4
  mov    %r14d,%eax
  jmp    L69
L61:
  mov    %r13d,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
ssize_t rio_writen(int fd, void *usrbuf, size_t n) {
  size_t nleft = n;
  ssize_t nwritten;
  char *bufp = usrbuf;
  while (nleft > 0) {
    if ((nwritten = write(fd, bufp, nleft)) <= 0) {
      if (EINTR == errno)
        nwritten = 0;
      else
        return -1;
    }
    nleft -= nwritten;
    bufp += nwritten;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rio_writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L31
  xchg   %ax,%ax
L30:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L14
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L30
L31:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L14:
  mov    D0(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L30
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t rio_writen(int fd, void *usrbuf, size_t n) {
  size_t nleft = n;
  ssize_t nwritten;
  char *bufp = usrbuf;
  while (nleft > 0) {
    if ((nwritten = write(fd, bufp, nleft)) <= 0) {
      if (EINTR == errno)
        nwritten = 0;
      else
        return -1;
    }
    nleft -= nwritten;
    bufp += nwritten;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rio_writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L4
  xchg   %ax,%ax
L32:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L7
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L32
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    D16(%rip),%rax
  mov    D5(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L32
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t rio_writen(int fd, void *usrbuf, size_t n) {
  size_t nleft = n;
  ssize_t nwritten;
  char *bufp = usrbuf;
  while (nleft > 0) {
    if ((nwritten = write(fd, bufp, nleft)) <= 0) {
      if (EINTR == errno)
        nwritten = 0;
      else
        return -1;
    }
    nleft -= nwritten;
    bufp += nwritten;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cop_csb_spin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cop_csb_valid@plt>
  test   %eax,%eax
  je     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void cop_csb_spin(struct cop_csb *csb) {
  do {
  } while (!cop_csb_valid(csb));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cop_csb_spin>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L9:
  mov    %rbx,%rdi
  call   <cop_csb_valid@plt>
  test   %eax,%eax
  je     L9
  pop    %rbx
  ret
```

assistant: ```c
void cop_csb_spin(struct cop_csb *csb) {
  do {
  } while (!cop_csb_valid(csb));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cop_csb_spin>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  call   <cop_csb_valid@plt>
  test   %eax,%eax
  je     L8
  pop    %rbx
  ret
```

assistant: ```c
void cop_csb_spin(struct cop_csb *csb) {
  do {
  } while (!cop_csb_valid(csb));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cop_csb_spin>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rdi
  call   <cop_csb_valid@plt>
  test   %eax,%eax
  je     L5
  pop    %rbx
  ret
```

assistant: ```c
void cop_csb_spin(struct cop_csb *csb) {
  do {
  } while (!cop_csb_valid(csb));
}
```
user: What is the c source code of the assembly code below?

```asm
<yalex_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L19
L3:
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L15:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int yalex_strlen(const char *str) {
  if (str == 0)
    return 0;
  int len = 0;
  while (str[len])
    len++;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<yalex_strlen>:
  endbr64
  test   %rdi,%rdi
  je     L34
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
L0:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L0
L21:
  mov    %edx,%eax
  ret
L34:
  mov    $0x0,%edx
  jmp    L21
L11:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
int yalex_strlen(const char *str) {
  if (str == 0)
    return 0;
  int len = 0;
  while (str[len])
    len++;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<yalex_strlen>:
  endbr64
  test   %rdi,%rdi
  je     L1
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L27
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int yalex_strlen(const char *str) {
  if (str == 0)
    return 0;
  int len = 0;
  while (str[len])
    len++;
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<yalex_strlen>:
  endbr64
  test   %rdi,%rdi
  je     L13
  cmpb   $0x0,(%rdi)
  je     L13
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L8
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int yalex_strlen(const char *str) {
  if (str == 0)
    return 0;
  int len = 0;
  while (str[len])
    len++;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rop3_30_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_30_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T ^ stk2;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_30_0_0>:
  endbr64
  or     (%rdi),%sil
  xor    %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_30_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T ^ stk2;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_30_0_0>:
  endbr64
  or     (%rdi),%sil
  xor    %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_30_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T ^ stk2;
  *D = stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_30_0_0>:
  endbr64
  or     (%rdi),%sil
  xor    %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_30_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T ^ stk2;
  *D = stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<M4U_ReadReg32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <ioread32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int M4U_ReadReg32(unsigned int M4uBase, unsigned int Offset) {
  unsigned int val;
  val = ioread32((void *)(M4uBase + Offset));
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<M4U_ReadReg32>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdi,%rsi,1),%edi
  call   <ioread32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int M4U_ReadReg32(unsigned int M4uBase, unsigned int Offset) {
  unsigned int val;
  val = ioread32((void *)(M4uBase + Offset));
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<M4U_ReadReg32>:
  endbr64
  add    %esi,%edi
  mov    %edi,%edi
  jmp    1050 <ioread32@plt>
```

assistant: ```c
unsigned int M4U_ReadReg32(unsigned int M4uBase, unsigned int Offset) {
  unsigned int val;
  val = ioread32((void *)(M4uBase + Offset));
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<M4U_ReadReg32>:
  endbr64
  add    %esi,%edi
  mov    %edi,%edi
  jmp    1050 <ioread32@plt>
```

assistant: ```c
unsigned int M4U_ReadReg32(unsigned int M4uBase, unsigned int Offset) {
  unsigned int val;
  val = ioread32((void *)(M4uBase + Offset));
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ecx
  mov    %ecx,%edx
  sub    -0x40(%rbp),%edx
  lea    0x1(%rdx),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L1:
  cmp    %rsi,%rsp
  je     L76
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L76:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L82
  orq    $0x0,-0x8(%rsp,%rax,1)
L82:
  mov    %rsp,%r14
  test   %edx,%edx
  js     L94
  mov    %r14,%rax
  lea    0x1(%rdx),%edx
  lea    (%r14,%rdx,4),%rdx
L11:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L11
L94:
  mov    $0x1,%r13d
  mov    $0x0,%r15d
  test   %ecx,%ecx
  jg     L91
L108:
  mov    %r15d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L127:
  add    $0x1,%ebx
  cmp    %ebx,-0x3c(%rbp)
  jl     L84
L23:
  mov    %ebx,%edi
  imul   %ebx,%edi
  add    %r12d,%edi
  call   <sqrt@plt>
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L127
  jne    L127
  mov    -0x40(%rbp),%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  comisd %xmm1,%xmm0
  jb     L127
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x3c(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jb     L127
  sub    %edx,%eax
  movslq %eax,%rdx
  cmpl   $0x0,(%r14,%rdx,4)
  jne    L127
  add    $0x1,%r15d
  movl   $0x1,(%r14,%rdx,4)
  jmp    L127
L84:
  add    $0x1,%r13d
  cmp    %r13d,-0x3c(%rbp)
  jl     L108
L91:
  cmp    %r13d,-0x3c(%rbp)
  jl     L84
  mov    %r13d,%r12d
  imul   %r13d,%r12d
  mov    %r13d,%ebx
  jmp    L23
L124:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D9
data_type: string

tool: D13: %d %d

tool: D9: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int je[b - a + 1];
  for (int i = 0; i < b - a + 1; ++i) {
    je[i] = 0;
  }
  int c = 0;
  for (int i = 1; i <= b; ++i) {
    for (int j = i; j <= b; ++j) {
      int g = i * i + j * j;
      double t = sqrt(g);
      if ((int)t == t && t >= a && t <= b && je[(int)t - a] == 0) {
        c++;
        je[(int)t - a] = 1;
      }
    }
  }
  printf("%d\n", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ecx
  mov    %rsp,%rdi
  mov    %ecx,%eax
  sub    -0x40(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rdi
  and    $0xfffffffffffffff0,%rsi
  cmp    %rdi,%rsp
  je     L31
L100:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L100
L31:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L35
L64:
  mov    %rsp,%r13
  test   %eax,%eax
  js     L136
  cltq
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %ecx,-0x44(%rbp)
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
  mov    -0x44(%rbp),%ecx
L136:
  mov    $0x1,%r12d
  xor    %r14d,%r14d
  test   %ecx,%ecx
  jle    L16
  cmp    %r12d,%ecx
  jl     L71
  nopl   0x0(%rax)
L112:
  mov    %r12d,%ebx
  mov    %r12d,%r15d
  imul   %r12d,%ebx
  jmp    L62
  nopl   0x0(%rax)
L98:
  mov    -0x3c(%rbp),%ecx
L95:
  add    $0x1,%r15d
  cmp    %ecx,%r15d
  jg     L71
L62:
  mov    %r15d,%edi
  imul   %r15d,%edi
  add    %ebx,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%eax
  cvtsi2sd %eax,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L98
  jne    L98
  mov    -0x40(%rbp),%edx
  pxor   %xmm1,%xmm1
  mov    -0x3c(%rbp),%ecx
  cvtsi2sd %edx,%xmm1
  comisd %xmm1,%xmm0
  jb     L95
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  comisd %xmm0,%xmm1
  jb     L95
  sub    %edx,%eax
  cltq
  mov    0x0(%r13,%rax,4),%edx
  test   %edx,%edx
  jne    L95
  add    $0x1,%r15d
  add    $0x1,%r14d
  movl   $0x1,0x0(%r13,%rax,4)
  cmp    %ecx,%r15d
  jle    L62
  nopl   0x0(%rax,%rax,1)
L71:
  add    $0x1,%r12d
  cmp    %r12d,%ecx
  jge    L112
L16:
  mov    %r14d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L35:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L64
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D18
datatype: string

tool: D0: %d %d

tool: D18: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int je[b - a + 1];
  for (int i = 0; i < b - a + 1; ++i) {
    je[i] = 0;
  }
  int c = 0;
  for (int i = 1; i <= b; ++i) {
    for (int j = i; j <= b; ++j) {
      int g = i * i + j * j;
      double t = sqrt(g);
      if ((int)t == t && t >= a && t <= b && je[(int)t - a] == 0) {
        c++;
        je[(int)t - a] = 1;
      }
    }
  }
  printf("%d\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ecx
  mov    %rsp,%rdi
  mov    %ecx,%eax
  sub    -0x40(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rdi
  and    $0xfffffffffffffff0,%rsi
  cmp    %rdi,%rsp
  je     L71
L45:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L45
L71:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L12
L103:
  mov    %rsp,%r13
  test   %eax,%eax
  js     L33
  cltq
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %ecx,-0x44(%rbp)
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
  mov    -0x44(%rbp),%ecx
L33:
  mov    $0x1,%r12d
  xor    %r14d,%r14d
  test   %ecx,%ecx
  jle    L87
  cmp    %r12d,%ecx
  jl     L141
  nopl   0x0(%rax)
L78:
  mov    %r12d,%ebx
  mov    %r12d,%r15d
  imul   %r12d,%ebx
  jmp    L152
  nopl   0x0(%rax)
L62:
  mov    -0x3c(%rbp),%ecx
L93:
  add    $0x1,%r15d
  cmp    %r15d,%ecx
  jl     L141
L152:
  mov    %r15d,%edi
  imul   %r15d,%edi
  add    %ebx,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%eax
  cvtsi2sd %eax,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L62
  jne    L62
  mov    -0x40(%rbp),%edx
  pxor   %xmm1,%xmm1
  mov    -0x3c(%rbp),%ecx
  cvtsi2sd %edx,%xmm1
  comisd %xmm1,%xmm0
  jb     L93
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  comisd %xmm0,%xmm1
  jb     L93
  sub    %edx,%eax
  cltq
  mov    0x0(%r13,%rax,4),%edx
  test   %edx,%edx
  jne    L93
  add    $0x1,%r15d
  add    $0x1,%r14d
  movl   $0x1,0x0(%r13,%rax,4)
  cmp    %r15d,%ecx
  jge    L152
  nopl   0x0(%rax,%rax,1)
L141:
  add    $0x1,%r12d
  cmp    %r12d,%ecx
  jge    L78
L87:
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L135
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L12:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L103
L135:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D1
datatype: string

tool: D16: %d %d

tool: D1: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int je[b - a + 1];
  for (int i = 0; i < b - a + 1; ++i) {
    je[i] = 0;
  }
  int c = 0;
  for (int i = 1; i <= b; ++i) {
    for (int j = i; j <= b; ++j) {
      int g = i * i + j * j;
      double t = sqrt(g);
      if ((int)t == t && t >= a && t <= b && je[(int)t - a] == 0) {
        c++;
        je[(int)t - a] = 1;
      }
    }
  }
  printf("%d\n", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <epoll_create@plt>
  mov    %eax,-0x58(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%eax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  lea    -0x50(%rbp),%rsi
  mov    -0x58(%rbp),%eax
  mov    $0x14,%ecx
  mov    $0x4,%edx
  mov    %eax,%edi
  call   <epoll_wait@plt>
  mov    %eax,-0x54(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  struct epoll_event ev[4];
  int nfds;
  int efd;
  efd = epoll_create(4);
  ev[0].events = EPOLLIN | EPOLLOUT;
  ev[0].data.fd = 0;
  epoll_ctl(efd, EPOLL_CTL_ADD, 0, &(ev[0]));
  if ((nfds = epoll_wait(efd, ev, 4, 20))) {
  }
  return (0);
}
```