ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_manypaths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <read_dobldobl_target_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <read_dobldobl_start_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <copy_dobldobl_start_solutions_to_container@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <solcon_number_of_dobldobl_solutions@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    D12(%rip),%rax
  pxor   %xmm1,%xmm1
  movq   %rax,%xmm0
  mov    $0x1,%edi
  call   <ade_manypaths_dd@plt>
  mov    %eax,-0xc(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <solcon_write_dobldobl_solutions@plt>
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: f64
name: disassemble_data
arguments: tag: D15
type_guessed: string

tool: D18: 
Tracking many solution paths ...

tool: D10: The solution container has size %d.


tool: D12: 1

tool: D15: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_dobldobl_target_system();
  fail = read_dobldobl_start_system();
  fail = copy_dobldobl_start_solutions_to_container();
  fail = solcon_number_of_dobldobl_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_dd(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_dobldobl_solutions();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_manypaths>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <read_dobldobl_target_system@plt>
  mov    $0x0,%eax
  call   <read_dobldobl_start_system@plt>
  mov    $0x0,%eax
  call   <copy_dobldobl_start_solutions_to_container@plt>
  lea    0x4(%rsp),%rdi
  call   <solcon_number_of_dobldobl_solutions@plt>
  mov    0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movsd  D30(%rip),%xmm0
  mov    $0x1,%edi
  call   <ade_manypaths_dd@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <solcon_write_dobldobl_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D30
type: f64
name: parse_data
arguments: tag: D33
type: string

tool: D34: 
Tracking many solution paths ...

tool: D6: The solution container has size %d.


tool: D30: 1

tool: D33: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_dobldobl_target_system();
  fail = read_dobldobl_start_system();
  fail = copy_dobldobl_start_solutions_to_container();
  fail = solcon_number_of_dobldobl_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_dd(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_dobldobl_solutions();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_manypaths>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %eax,%eax
  call   <read_dobldobl_target_system@plt>
  xor    %eax,%eax
  call   <read_dobldobl_start_system@plt>
  xor    %eax,%eax
  call   <copy_dobldobl_start_solutions_to_container@plt>
  lea    0x4(%rsp),%rdi
  call   <solcon_number_of_dobldobl_solutions@plt>
  mov    0x4(%rsp),%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  movsd  D1(%rip),%xmm0
  call   <ade_manypaths_dd@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <solcon_write_dobldobl_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D1
type: f64
name: retrieve_data
arguments: label: D21
type: string

tool: D17: 
Tracking many solution paths ...

tool: D12: The solution container has size %d.


tool: D1: 1

tool: D21: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_dobldobl_target_system();
  fail = read_dobldobl_start_system();
  fail = copy_dobldobl_start_solutions_to_container();
  fail = solcon_number_of_dobldobl_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_dd(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_dobldobl_solutions();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_manypaths>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %eax,%eax
  call   <read_dobldobl_target_system@plt>
  xor    %eax,%eax
  call   <read_dobldobl_start_system@plt>
  xor    %eax,%eax
  call   <copy_dobldobl_start_solutions_to_container@plt>
  lea    0x4(%rsp),%rdi
  call   <solcon_number_of_dobldobl_solutions@plt>
  mov    0x4(%rsp),%esi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  movsd  D31(%rip),%xmm0
  call   <ade_manypaths_dd@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <solcon_write_dobldobl_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D31
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D35
type_guessed: string

tool: D1: 
Tracking many solution paths ...

tool: D37: The solution container has size %d.


tool: D31: 1

tool: D35: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_dobldobl_target_system();
  fail = read_dobldobl_start_system();
  fail = copy_dobldobl_start_solutions_to_container();
  fail = solcon_number_of_dobldobl_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_dd(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_dobldobl_solutions();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tri_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L6
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  jmp    L18
L6:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int tri_min(int x, int y, int z) {
  if (x < y) {
    return (x < z ? x : z);
  }
  return (y < z ? y : z);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tri_min>:
  endbr64
  cmp    %edx,%edi
  mov    %edx,%eax
  cmovle %edi,%eax
  cmp    %edx,%esi
  cmovle %esi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int tri_min(int x, int y, int z) {
  if (x < y) {
    return (x < z ? x : z);
  }
  return (y < z ? y : z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tri_min>:
  endbr64
  cmp    %edx,%edi
  mov    %edx,%eax
  cmovle %edi,%eax
  cmp    %edx,%esi
  cmovle %esi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int tri_min(int x, int y, int z) {
  if (x < y) {
    return (x < z ? x : z);
  }
  return (y < z ? y : z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L39:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jae    L0
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    $0x2,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,%rdx
  movzwl -0x12(%rbp),%eax
  mov    %ax,(%rdx)
  jmp    L6
L0:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shr    $0x4,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
L6:
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L39
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 1U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%edi
  test   %edi,%edi
  je     L32
  lea    0x4(%rsp),%rdx
  mov    $0x0,%eax
  jmp    L4
L22:
  mov    %esi,%ecx
  shr    $0x4,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%esi
  mov    %esi,0x4(%rsp)
L42:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %edi,%eax
  je     L32
L4:
  mov    0x4(%rsp),%esi
  cmp    %eax,%esi
  jbe    L22
  movzwl 0x2(%rdx),%ecx
  movzwl (%rdx),%esi
  mov    %si,0x2(%rdx)
  mov    %cx,(%rdx)
  jmp    L42
L32:
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  mov    %eax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 1U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  mov    0x4(%rdi),%edi
  shl    $0x7,%edx
  and    $0x4334b500,%edx
  test   %edi,%edi
  je     L8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    %edx,%eax
  jb     L4
  mov    %edx,%ecx
  shr    $0x4,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%edx
L4:
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L13
L8:
  add    %edx,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 1U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  mov    0x4(%rdi),%edi
  shl    $0x7,%edx
  and    $0x4334b500,%edx
  test   %edi,%edi
  je     L6
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    %edx,%eax
  jb     L12
  mov    %edx,%ecx
  shr    $0x4,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%edx
L12:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L20
L6:
  add    %edx,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> 4U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 1U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L33:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L33
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x10(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x10(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%esi
  mov    -0xc(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L23
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: f64
name: retrieve_data
arguments: label: D6
type: string

tool: D9: 256

tool: D6: %5d : %5d %3d %3d


assistant: ```c
void print_table(int *x, int max) {
  int total, sum;
  int i;
  int kk, kk1;
  total = 0;
  for (i = 0; i <= max; i++) {
    total += x[i];
  }
  sum = 0;
  kk1 = 0;
  for (i = 0; i <= max; i++) {
    sum += x[i];
    kk = (int)((double)sum * 256.0 / (double)total);
    printf("%5d : %5d %3d %3d\n", i, x[i], kk - kk1, kk);
    kk1 = kk;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_table>:
  endbr64
  test   %esi,%esi
  js     L25
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdi,%rax
  mov    %esi,%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L27:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L27
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  mov    $0x0,%ebp
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm2
  movsd  %xmm2,0x8(%rsp)
  lea    D0(%rip),%r14
L13:
  mov    0x0(%r13,%rbx,4),%edx
  add    %edx,%ebp
  mov    %r15d,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  D6(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%r15d
  mov    %r15d,%ecx
  sub    %eax,%ecx
  mov    %r15d,%r8d
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string
name: read_data
arguments: data_tag: D6
type: f64

tool: D0: %5d : %5d %3d %3d


tool: D6: 256

assistant: ```c
void print_table(int *x, int max) {
  int total, sum;
  int i;
  int kk, kk1;
  total = 0;
  for (i = 0; i <= max; i++) {
    total += x[i];
  }
  sum = 0;
  kk1 = 0;
  for (i = 0; i <= max; i++) {
    sum += x[i];
    kk = (int)((double)sum * 256.0 / (double)total);
    printf("%5d : %5d %3d %3d\n", i, x[i], kk - kk1, kk);
    kk1 = kk;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_table>:
  endbr64
  test   %esi,%esi
  js     L12
  push   %r15
  movslq %esi,%rdx
  mov    %rdi,%rax
  push   %r14
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    %rdi,%r14
  xor    %edx,%edx
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L22:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L22
  pxor   %xmm2,%xmm2
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  cvtsi2sd %edx,%xmm2
  lea    D6(%rip),%r12
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%r14,%rbx,4),%edx
  pxor   %xmm0,%xmm0
  mov    %r13d,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    %edx,%r15d
  cvtsi2sd %r15d,%xmm0
  mulsd  D11(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%r13d
  mov    %r13d,%ecx
  mov    %r13d,%r8d
  sub    %eax,%ecx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L12:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: f64

tool: D6: %5d : %5d %3d %3d


tool: D11: 256

assistant: ```c
void print_table(int *x, int max) {
  int total, sum;
  int i;
  int kk, kk1;
  total = 0;
  for (i = 0; i <= max; i++) {
    total += x[i];
  }
  sum = 0;
  kk1 = 0;
  for (i = 0; i <= max; i++) {
    sum += x[i];
    kk = (int)((double)sum * 256.0 / (double)total);
    printf("%5d : %5d %3d %3d\n", i, x[i], kk - kk1, kk);
    kk1 = kk;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_table>:
  endbr64
  test   %esi,%esi
  js     L30
  push   %r15
  lea    0x1(%rsi),%ecx
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x2,%esi
  jle    L47
  mov    %ecx,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L5:
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  paddd  %xmm3,%xmm0
  cmp    %rdx,%rax
  jne    L5
  movdqa %xmm0,%xmm1
  mov    %ecx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  and    $0x3,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  je     L9
L12:
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%rsi
  add    (%r15,%rcx,4),%eax
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%ebp
  jl     L9
  add    $0x2,%edx
  add    0x4(%r15,%rsi,1),%eax
  cmp    %edx,%ebp
  jl     L9
  add    0x8(%r15,%rsi,1),%eax
L9:
  pxor   %xmm4,%xmm4
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  cvtsi2sd %eax,%xmm4
  lea    D3(%rip),%r12
  movsd  %xmm4,0x8(%rsp)
  nopl   (%rax)
L11:
  mov    (%r15,%rbx,4),%edx
  pxor   %xmm0,%xmm0
  mov    %r13d,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    %edx,%r14d
  cvtsi2sd %r14d,%xmm0
  mulsd  D15(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%r13d
  mov    %r13d,%ecx
  mov    %r13d,%r8d
  sub    %eax,%ecx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  ret
L47:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D15
type: f64

tool: D3: %5d : %5d %3d %3d


tool: D15: 256

assistant: ```c
void print_table(int *x, int max) {
  int total, sum;
  int i;
  int kk, kk1;
  total = 0;
  for (i = 0; i <= max; i++) {
    total += x[i];
  }
  sum = 0;
  kk1 = 0;
  for (i = 0; i <= max; i++) {
    sum += x[i];
    kk = (int)((double)sum * 256.0 / (double)total);
    printf("%5d : %5d %3d %3d\n", i, x[i], kk - kk1, kk);
    kk1 = kk;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strncat_symbolic_dst_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: 1234

assistant: ```c
void strncat_symbolic_dst_length(char *dst) {
  strncat(dst, "1234", 5);
  clang_analyzer_eval(strlen(dst) >= 4);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncat_symbolic_dst_length>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5,%edx
  lea    D3(%rip),%rsi
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: 1234

assistant: ```c
void strncat_symbolic_dst_length(char *dst) {
  strncat(dst, "1234", 5);
  clang_analyzer_eval(strlen(dst) >= 4);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncat_symbolic_dst_length>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  mov    %rdi,%rbp
  lea    D7(%rip),%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  pop    %rbp
  cmp    $0x3,%eax
  setg   %dil
  jmp    1090 <clang_analyzer_eval@plt>
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: 1234

assistant: ```c
void strncat_symbolic_dst_length(char *dst) {
  strncat(dst, "1234", 5);
  clang_analyzer_eval(strlen(dst) >= 4);
}
```