ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <task_name1@plt>
  lea    D11(%rip),%rdi
  call   <task_name2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D5: foo

tool: D11: bar

assistant: ```c
int main(int argc, char *argv[]) {
  task_name1("foo");
  task_name2("bar");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <task_name1@plt>
  lea    D17(%rip),%rdi
  call   <task_name2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D6: foo

tool: D17: bar

assistant: ```c
int main(int argc, char *argv[]) {
  task_name1("foo");
  task_name2("bar");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <task_name1@plt>
  lea    D8(%rip),%rdi
  call   <task_name2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D8
type: string

tool: D19: foo

tool: D8: bar

assistant: ```c
int main(int argc, char *argv[]) {
  task_name1("foo");
  task_name2("bar");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L19
L23:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L10
  addl   $0x1,-0x14(%rbp)
L10:
  addl   $0x1,-0x18(%rbp)
L19:
  cmpl   $0x6,-0x18(%rbp)
  jle    L23
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D8: %lf

tool: D17: %d valores positivos


assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  int positive_count = 0;
  for (i = 1; i <= 6; ++i) {
    double current_number = 0;
    scanf("%lf", &current_number);
    if (current_number > 0) {
      positive_count++;
    }
  }
  printf("%d valores positivos\n", positive_count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x6,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r13
  lea    D8(%rip),%r12
L17:
  movq   $0x0,(%rsp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L17
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string

tool: D8: %lf

tool: D13: %d valores positivos


assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  int positive_count = 0;
  for (i = 1; i <= 6; ++i) {
    double current_number = 0;
    scanf("%lf", &current_number);
    if (current_number > 0) {
      positive_count++;
    }
  }
  printf("%d valores positivos\n", positive_count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  nop
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L9
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string

tool: D19: %lf

tool: D8: %d valores positivos


assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  int positive_count = 0;
  for (i = 1; i <= 6; ++i) {
    double current_number = 0;
    scanf("%lf", &current_number);
    if (current_number > 0) {
      positive_count++;
    }
  }
  printf("%d valores positivos\n", positive_count);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  nop
L15:
  mov    %r13,%rsi
  mov    %r12,%rdi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L15
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string

tool: D15: %lf

tool: D9: %d valores positivos


assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  int positive_count = 0;
  for (i = 1; i <= 6; ++i) {
    double current_number = 0;
    scanf("%lf", &current_number);
    if (current_number > 0) {
      positive_count++;
    }
  }
  printf("%d valores positivos\n", positive_count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L7:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Power(int base, int exp) {
  int result = 1;
  while (exp--)
    result *= base;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Power>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %esi,%esi
  je     L1
  mov    $0x1,%edx
L14:
  imul   %edi,%edx
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L14
L26:
  mov    %edx,%eax
  ret
L1:
  mov    $0x1,%edx
  jmp    L26
```

assistant: ```c
int Power(int base, int exp) {
  int result = 1;
  while (exp--)
    result *= base;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Power>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L19
  nopl   0x0(%rax)
L18:
  imul   %edi,%r8d
  sub    $0x1,%eax
  jae    L18
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Power(int base, int exp) {
  int result = 1;
  while (exp--)
    result *= base;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Power>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L14
  nopl   0x0(%rax)
L2:
  imul   %edi,%r8d
  sub    $0x1,%eax
  jae    L2
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Power(int base, int exp) {
  int result = 1;
  while (exp--)
    result *= base;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_uppercase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L19
  cmpl   $0x5a,-0x4(%rbp)
  jg     L19
  mov    $0x1,%eax
  jmp    L22
L19:
  mov    $0x0,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int is_uppercase(int c) {
  if (c >= 'A' && c <= 'Z')
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_uppercase>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x19,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_uppercase(int c) {
  if (c >= 'A' && c <= 'Z')
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_uppercase>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int is_uppercase(int c) {
  if (c >= 'A' && c <= 'Z')
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_uppercase>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int is_uppercase(int c) {
  if (c >= 'A' && c <= 'Z')
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <kprintf@plt>
  mov    $0x0,%esi
  mov    $0x80,%edi
  call   <disk_partition_select@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <kprintf@plt>
L2:
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D19
type_guessed: string

tool: D10: ShovelOS Stage 1.5


tool: D19: halt

assistant: ```c
void Main() {
  kprintf("ShovelOS Stage 1.5\r\n");
  disk_partition_select(0x80, 0);
  kprintf("halt");
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <kprintf@plt>
  mov    $0x0,%esi
  mov    $0x80,%edi
  call   <disk_partition_select@plt>
  lea    D5(%rip),%rdi
  call   <kprintf@plt>
L7:
  jmp    L7
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D0: ShovelOS Stage 1.5


tool: D5: halt

assistant: ```c
void Main() {
  kprintf("ShovelOS Stage 1.5\r\n");
  disk_partition_select(0x80, 0);
  kprintf("halt");
  for (;;)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <kprintf@plt>
  mov    $0x80,%edi
  xor    %esi,%esi
  call   <disk_partition_select@plt>
  lea    D16(%rip),%rdi
  call   <kprintf@plt>
L6:
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D2: ShovelOS Stage 1.5


tool: D16: halt

assistant: ```c
void Main() {
  kprintf("ShovelOS Stage 1.5\r\n");
  disk_partition_select(0x80, 0);
  kprintf("halt");
  for (;;)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <kprintf@plt>
  mov    $0x80,%edi
  xor    %esi,%esi
  call   <disk_partition_select@plt>
  lea    D14(%rip),%rdi
  call   <kprintf@plt>
L4:
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D3: ShovelOS Stage 1.5


tool: D14: halt

assistant: ```c
void Main() {
  kprintf("ShovelOS Stage 1.5\r\n");
  disk_partition_select(0x80, 0);
  kprintf("halt");
  for (;;)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <ex1@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ex1();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ex1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ex1();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ex1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ex1();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ex1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ex1();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L72
  cmpl   $0x3,-0x4(%rbp)
  jg     L1
  cmpl   $0x1,-0x4(%rbp)
  je     L23
  cmpl   $0x2,-0x4(%rbp)
  je     L7
  jmp    L1
L23:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
L7:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
L72:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
L1:
  nop
L67:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D19
datatype: string

tool: D7: [INF] %s


tool: D2: [WAN] %s


tool: D19: [ERR] %s


assistant: ```c
void print(int level, const char *msg) {
  switch (level) {
  case 1:
    printf("[INF] %s\n", msg);
    break;
  case 2:
    printf("[WAN] %s\n", msg);
    break;
  case 3:
    printf("[ERR] %s\n", msg);
    break;
  default:
    break;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L46
  cmp    $0x3,%edi
  je     L21
  cmp    $0x1,%edi
  je     L15
L20:
  add    $0x8,%rsp
  ret
L15:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L46:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L21:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L20
```

tool_calls: name: disassemble_data
arguments: tag: D20
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string

tool: D20: [INF] %s


tool: D19: [WAN] %s


tool: D13: [ERR] %s


assistant: ```c
void print(int level, const char *msg) {
  switch (level) {
  case 1:
    printf("[INF] %s\n", msg);
    break;
  case 2:
    printf("[WAN] %s\n", msg);
    break;
  case 3:
    printf("[ERR] %s\n", msg);
    break;
  default:
    break;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print>:
  endbr64
  cmp    $0x2,%edi
  je     L17
  cmp    $0x3,%edi
  je     L10
  cmp    $0x1,%edi
  je     L19
  ret
  nopl   0x0(%rax)
L17:
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L19:
  lea    D24(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L10:
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D9: [WAN] %s


tool: D24: [INF] %s


tool: D19: [ERR] %s


assistant: ```c
void print(int level, const char *msg) {
  switch (level) {
  case 1:
    printf("[INF] %s\n", msg);
    break;
  case 2:
    printf("[WAN] %s\n", msg);
    break;
  case 3:
    printf("[ERR] %s\n", msg);
    break;
  default:
    break;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print>:
  endbr64
  cmp    $0x2,%edi
  je     L4
  cmp    $0x3,%edi
  je     L19
  cmp    $0x1,%edi
  je     L3
  ret
  nopl   0x0(%rax)
L4:
  lea    D12(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L3:
  lea    D26(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L19:
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string
name: read_data
arguments: data_label: D5
type_guessed: string

tool: D12: [WAN] %s


tool: D26: [INF] %s


tool: D5: [ERR] %s


assistant: ```c
void print(int level, const char *msg) {
  switch (level) {
  case 1:
    printf("[INF] %s\n", msg);
    break;
  case 2:
    printf("[WAN] %s\n", msg);
    break;
  case 3:
    printf("[ERR] %s\n", msg);
    break;
  default:
    break;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<user_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    $0x44,%eax
  mov    $0xc,%esi
  mov    -0x20(%rbp),%rdx
  mov    %esi,%ebx
  mov    %rdx,%rcx
  int    $0x40
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int user_free(void *mem) {
  int val;
  __asm__ __volatile__("int $0x40" : "=a"(val) : "a"(68), "b"(12), "c"(mem));
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<user_free>:
  endbr64
  push   %rbx
  mov    $0x44,%eax
  mov    $0xc,%ebx
  mov    %rdi,%rcx
  int    $0x40
  pop    %rbx
  ret
```

assistant: ```c
int user_free(void *mem) {
  int val;
  __asm__ __volatile__("int $0x40" : "=a"(val) : "a"(68), "b"(12), "c"(mem));
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<user_free>:
  endbr64
  push   %rbx
  mov    $0x44,%eax
  mov    $0xc,%ebx
  mov    %rdi,%rcx
  int    $0x40
  pop    %rbx
  ret
```

assistant: ```c
int user_free(void *mem) {
  int val;
  __asm__ __volatile__("int $0x40" : "=a"(val) : "a"(68), "b"(12), "c"(mem));
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<user_free>:
  endbr64
  push   %rbx
  mov    $0x44,%eax
  mov    $0xc,%ebx
  mov    %rdi,%rcx
  int    $0x40
  pop    %rbx
  ret
```

assistant: ```c
int user_free(void *mem) {
  int val;
  __asm__ __volatile__("int $0x40" : "=a"(val) : "a"(68), "b"(12), "c"(mem));
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decode_dxt5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %rcx,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x90(%rbp),%rax
  add    $0x3,%rax
  lea    0x3(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x98(%rbp),%rax
  add    $0x3,%rax
  lea    0x3(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x88(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  jmp    L29
L12:
  movq   $0x0,-0x68(%rbp)
  jmp    L42
L14:
  lea    -0x50(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decode_dxt5_block@plt>
  mov    -0x98(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  push   -0xa0(%rbp)
  lea    -0x50(%rbp),%rdi
  push   %rdi
  mov    $0x4,%r9d
  mov    $0x4,%r8d
  mov    %rax,%rdi
  call   <copy_block_buffer@plt>
  add    $0x10,%rsp
  addq   $0x1,-0x68(%rbp)
  addq   $0x40,-0x78(%rbp)
L42:
  mov    -0x68(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jl     L14
  addq   $0x1,-0x70(%rbp)
L29:
  mov    -0x70(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jl     L12
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int decode_dxt5(const uint8_t *data, const long w, const long h, uint32_t *image) {
  long num_blocks_x = (w + 3) / 4;
  long num_blocks_y = (h + 3) / 4;
  uint32_t buffer[16];
  const uint8_t *d = data;
  for (long by = 0; by < num_blocks_y; by++) {
    for (long bx = 0; bx < num_blocks_x; bx++, d += 16) {
      decode_dxt5_block(d, buffer);
      copy_block_buffer(bx, by, w, h, 4, 4, buffer, image);
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decode_dxt5>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsi),%r14
  mov    %rsi,%rax
  add    $0x3,%rax
  cmovns %rax,%r14
  sar    $0x2,%r14
  lea    0x6(%rdx),%rax
  mov    %rdx,%rcx
  add    $0x3,%rdx
  cmovns %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,0x20(%rsp)
  test   %rcx,%rcx
  jle    L54
  mov    %r14,%rdx
  shl    $0x6,%rdx
  test   %rsi,%rsi
  mov    $0x40,%eax
  cmovg  %rdx,%rax
  mov    %rax,0x28(%rsp)
  mov    $0x0,%r13d
  lea    0x30(%rsp),%r12
  jmp    L25
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <decode_dxt5_block@plt>
  push   %r15
  push   %r12
  mov    $0x4,%r9d
  mov    $0x4,%r8d
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <copy_block_buffer@plt>
  add    $0x1,%rbx
  add    $0x40,%rbp
  add    $0x10,%rsp
  cmp    %rbx,%r14
  jg     L2
  mov    0x28(%rsp),%rcx
  add    %rcx,0x18(%rsp)
L42:
  add    $0x1,%r13
  cmp    %r13,0x20(%rsp)
  jle    L54
L25:
  mov    0x18(%rsp),%rbp
  mov    $0x0,%ebx
  cmpq   $0x0,0x8(%rsp)
  jg     L2
  jmp    L42
L54:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x1,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_dxt5(const uint8_t *data, const long w, const long h, uint32_t *image) {
  long num_blocks_x = (w + 3) / 4;
  long num_blocks_y = (h + 3) / 4;
  uint32_t buffer[16];
  const uint8_t *d = data;
  for (long by = 0; by < num_blocks_y; by++) {
    for (long bx = 0; bx < num_blocks_x; bx++, d += 16) {
      decode_dxt5_block(d, buffer);
      copy_block_buffer(bx, by, w, h, 4, 4, buffer, image);
    }
  }
  return 1;
}
```