ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%rcx
  mov    $0x0,%edi
L2:
  mov    %edi,%esi
  lea    -0x20(%rcx),%rax
  mov    $0x0,%edx
L17:
  mov    %edx,(%rax)
  add    %esi,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L17
  add    $0x1,%edi
  add    $0x20,%rcx
  cmp    $0x8,%edi
  jne    L2
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  lea    D12(%rip),%r13
L8:
  mov    $0x0,%ebx
L22:
  mov    (%r12,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  add    $0x20,%r12
  cmp    $0x8,%ebp
  jne    L8
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D13: Array Indicies:

tool: D12: [%d][%d]=%d

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
    }
  }
  printf("Array Indicies:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      printf("[%d][%d]=%d", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %ecx,%ecx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%rsi
  xchg   %ax,%ax
L1:
  lea    -0x20(%rsi),%rax
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L10
  add    $0x1,%ecx
  lea    0x20(%rax),%rsi
  cmp    $0x8,%ecx
  jne    L1
  lea    D13(%rip),%rdi
  xor    %r12d,%r12d
  lea    D5(%rip),%r13
  call   <puts@plt>
  nop
L21:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    0x0(%rbp,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x8,%rbx
  jne    L23
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    $0x20,%rbp
  call   <putchar@plt>
  cmp    $0x8,%r12d
  jne    L21
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x118,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D13: Array Indicies:

tool: D5: [%d][%d]=%d

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
    }
  }
  printf("Array Indicies:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      printf("[%d][%d]=%d", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<evenbits_compl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  cmpl   $0x0,-0x1c(%rbp)
  jg     L17
L28:
  mov    $0xffffffff,%eax
  jmp    L14
L17:
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  not    %eax
  mov    %al,-0x6(%rbp)
  andb   $0x2a,-0x6(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  and    $0x55,%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x6(%rbp),%eax
  or     -0x5(%rbp),%al
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int evenbits_compl(char *buff, int buff_size) {
  if (buff == NULL || buff_size <= 0)
    return -1;
  int i;
  unsigned char c1, c2;
  for (i = 0; i < buff_size; i++) {
    c1 = ~buff[i];
    c1 &= 0x2A;
    c2 = buff[i] & 0x55;
    buff[i] = c1 | c2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<evenbits_compl>:
  endbr64
  test   %rdi,%rdi
  je     L15
  test   %esi,%esi
  jle    L15
  mov    $0x0,%edx
L3:
  movzbl (%rdi,%rdx,1),%eax
  and    $0x7f,%eax
  xor    $0x2a,%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L3
  mov    $0x0,%eax
  ret
L15:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int evenbits_compl(char *buff, int buff_size) {
  if (buff == NULL || buff_size <= 0)
    return -1;
  int i;
  unsigned char c1, c2;
  for (i = 0; i < buff_size; i++) {
    c1 = ~buff[i];
    c1 &= 0x2A;
    c2 = buff[i] & 0x55;
    buff[i] = c1 | c2;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<evenbits_compl>:
  endbr64
  test   %rdi,%rdi
  je     L27
  test   %esi,%esi
  jle    L27
  xor    %edx,%edx
  nop
L22:
  movzbl (%rdi,%rdx,1),%eax
  and    $0x7f,%eax
  xor    $0x2a,%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L22
  xor    %eax,%eax
  ret
L27:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int evenbits_compl(char *buff, int buff_size) {
  if (buff == NULL || buff_size <= 0)
    return -1;
  int i;
  unsigned char c1, c2;
  for (i = 0; i < buff_size; i++) {
    c1 = ~buff[i];
    c1 &= 0x2A;
    c2 = buff[i] & 0x55;
    buff[i] = c1 | c2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<evenbits_compl>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%edi
  test   %rdx,%rdx
  je     L101
  test   %esi,%esi
  jle    L101
  mov    $0x1,%ecx
  cmovg  %esi,%ecx
  cmp    $0xf,%esi
  jle    L118
  mov    %ecx,%esi
  movdqa D30(%rip),%xmm2
  movdqa D7(%rip),%xmm1
  mov    %rdx,%rax
  shr    $0x4,%esi
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdx,%rsi,1),%rsi
  nop
L110:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pand   %xmm2,%xmm0
  pxor   %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L110
  mov    %ecx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%esi
  cmp    %eax,%ecx
  je     L57
L39:
  sub    %eax,%ecx
  lea    -0x1(%rcx),%r8d
  cmp    $0x6,%r8d
  jbe    L25
  movq   D30(%rip),%xmm1
  add    %rdx,%rax
  movq   (%rax),%xmm0
  pand   %xmm1,%xmm0
  movq   D7(%rip),%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,(%rax)
  mov    %ecx,%eax
  and    $0xfffffff8,%eax
  add    %eax,%esi
  cmp    %eax,%ecx
  je     L57
L25:
  movslq %esi,%rcx
  add    %rdx,%rcx
  movzbl (%rcx),%eax
  and    $0x7f,%eax
  xor    $0x2a,%eax
  mov    %al,(%rcx)
  lea    0x1(%rsi),%eax
  cmp    %eax,%edi
  jle    L57
  cltq
  add    %rdx,%rax
  movzbl (%rax),%ecx
  and    $0x7f,%ecx
  xor    $0x2a,%ecx
  mov    %cl,(%rax)
  lea    0x2(%rsi),%eax
  cmp    %eax,%edi
  jle    L57
  cltq
  add    %rdx,%rax
  movzbl (%rax),%ecx
  and    $0x7f,%ecx
  xor    $0x2a,%ecx
  mov    %cl,(%rax)
  lea    0x3(%rsi),%eax
  cmp    %eax,%edi
  jle    L57
  cltq
  add    %rdx,%rax
  movzbl (%rax),%ecx
  and    $0x7f,%ecx
  xor    $0x2a,%ecx
  mov    %cl,(%rax)
  lea    0x4(%rsi),%eax
  cmp    %eax,%edi
  jle    L57
  cltq
  add    %rdx,%rax
  movzbl (%rax),%ecx
  and    $0x7f,%ecx
  xor    $0x2a,%ecx
  mov    %cl,(%rax)
  lea    0x5(%rsi),%eax
  cmp    %eax,%edi
  jle    L57
  cltq
  add    $0x6,%esi
  add    %rdx,%rax
  movzbl (%rax),%ecx
  and    $0x7f,%ecx
  xor    $0x2a,%ecx
  mov    %cl,(%rax)
  cmp    %esi,%edi
  jle    L57
  movslq %esi,%rsi
  add    %rsi,%rdx
  movzbl (%rdx),%eax
  and    $0x7f,%eax
  xor    $0x2a,%eax
  mov    %al,(%rdx)
L57:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L118:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L39
L101:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D7
type_guessed: byte[16]

tool: {"D30": [0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f]}

tool: {"D7": [0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a]}

assistant: ```c
int evenbits_compl(char *buff, int buff_size) {
  if (buff == NULL || buff_size <= 0)
    return -1;
  int i;
  unsigned char c1, c2;
  for (i = 0; i < buff_size; i++) {
    c1 = ~buff[i];
    c1 &= 0x2A;
    c2 = buff[i] & 0x55;
    buff[i] = c1 | c2;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6564616c676e6142,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x6873,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x13(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: Name of our country : %s


assistant: ```c
int main() {
  char s[] = "Bangladesh";
  char *p;
  p = s;
  printf("Name of our country : %s\n", p);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6564616c676e6142,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x6873,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xd(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: Name of our country : %s


assistant: ```c
int main() {
  char s[] = "Bangladesh";
  char *p;
  p = s;
  printf("Name of our country : %s\n", p);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6564616c676e6142,%rax
  lea    0xd(%rsp),%rsi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x6873,%eax
  mov    %ax,0x15(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: Name of our country : %s


assistant: ```c
int main() {
  char s[] = "Bangladesh";
  char *p;
  p = s;
  printf("Name of our country : %s\n", p);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6564616c676e6142,%rax
  lea    0xd(%rsp),%rsi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x6873,%eax
  mov    %ax,0x15(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: Name of our country : %s


assistant: ```c
int main() {
  char s[] = "Bangladesh";
  char *p;
  p = s;
  printf("Name of our country : %s\n", p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x2(%rbp)
  je     L15
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L18
L15:
  movzbl -0x2(%rbp),%eax
  movzbl -0x1(%rbp),%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
  } while (c1 != 0 && c1 == c2);
  return c1 - c2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  mov    $0x0,%edx
L14:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  je     L17
  cmp    %cl,%al
  je     L14
L17:
  movzbl %al,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
  } while (c1 != 0 && c1 == c2);
  return c1 - c2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  je     L10
  cmp    %cl,%al
  je     L7
L10:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
  } while (c1 != 0 && c1 == c2);
  return c1 - c2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  je     L5
  cmp    %cl,%al
  je     L17
L5:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
  } while (c1 != 0 && c1 == c2);
  return c1 - c2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nandc_uimatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9d,-0x5c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L26
L2:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L19
L5:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  and    -0x5c(%rbp),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jle    L5
  addq   $0x1,-0x20(%rbp)
L26:
  mov    -0x20(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jle    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nandc_uimatrix(uint **m1, long nrl, long nrh, long ncl, long nch, uint c, uint **m2) {
  long i, j;
  uint x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = !(x & c);
      Yi[j] = y;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nandc_uimatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  cmp    %rdx,%rsi
  jg     L21
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %rcx,%rbx
  mov    %r8,%rbp
  lea    0x1(%rdx),%r8
  lea    0x1(%rbp),%rdi
L32:
  mov    (%r11,%r10,8),%rcx
  mov    (%r12,%r10,8),%rsi
  cmp    %rbp,%rbx
  jg     L26
  mov    %rbx,%rax
L8:
  mov    %r9d,%edx
  and    (%rcx,%rax,4),%edx
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L8
L26:
  add    $0x1,%r10
  cmp    %r8,%r10
  jne    L32
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void nandc_uimatrix(uint **m1, long nrl, long nrh, long ncl, long nch, uint c, uint **m2) {
  long i, j;
  uint x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = !(x & c);
      Yi[j] = y;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nandc_uimatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  cmp    %rdx,%rsi
  jg     L24
  mov    %r8,%rbp
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %rcx,%rbx
  lea    0x1(%rdx),%r8
  lea    0x1(%rbp),%rdi
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    (%r11,%r10,8),%rcx
  mov    (%r12,%r10,8),%rsi
  cmp    %rbp,%rbx
  jg     L8
  mov    %rbx,%rax
L13:
  mov    %r9d,%edx
  and    (%rcx,%rax,4),%edx
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L13
L8:
  add    $0x1,%r10
  cmp    %r8,%r10
  jne    L26
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void nandc_uimatrix(uint **m1, long nrl, long nrh, long ncl, long nch, uint c, uint **m2) {
  long i, j;
  uint x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = !(x & c);
      Yi[j] = y;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nandc_uimatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x10(%rsp)
  cmp    %rdx,%rsi
  jg     L1
  mov    %rcx,%rax
  mov    %r8,%r12
  cmp    %r8,%rcx
  jg     L1
  lea    0x1(%rdx),%rcx
  movd   %r9d,%xmm4
  pxor   %xmm1,%xmm1
  mov    %rdi,%rbx
  mov    %rcx,-0x48(%rsp)
  mov    %r8,%rcx
  mov    %rsi,%rdi
  lea    0x1(%r12),%rbp
  sub    %rax,%rcx
  lea    0x0(,%rax,4),%r8
  pshufd $0x0,%xmm4,%xmm3
  movdqa D8(%rip),%xmm2
  mov    %rcx,-0x40(%rsp)
  add    $0x1,%rcx
  lea    0x4(%r8),%r15
  mov    %rcx,%r11
  mov    %rcx,-0x38(%rsp)
  and    $0xfffffffffffffffc,%rcx
  add    %rcx,%rax
  mov    %rcx,-0x30(%rsp)
  shr    $0x2,%r11
  lea    0x1(%rax),%rcx
  lea    0x0(,%rax,4),%r13
  add    $0x2,%rax
  shl    $0x4,%r11
  mov    %rax,-0x20(%rsp)
  shl    $0x2,%rax
  lea    0x0(,%rcx,4),%r14
  mov    %rcx,-0x28(%rsp)
  mov    %rax,-0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L55:
  mov    0x38(%rsp),%rax
  mov    (%rbx,%rdi,8),%rcx
  mov    (%rax,%rdi,8),%r10
  lea    (%rcx,%r15,1),%rsi
  lea    (%r10,%r8,1),%rdx
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L39
  cmpq   $0x2,-0x40(%rsp)
  jbe    L39
  lea    (%rcx,%r8,1),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L50:
  movdqu (%rsi,%rax,1),%xmm0
  pand   %xmm3,%xmm0
  pcmpeqd %xmm1,%xmm0
  pand   %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r11,%rax
  jne    L50
  mov    -0x30(%rsp),%rsi
  cmp    %rsi,-0x38(%rsp)
  je     L10
  mov    %r9d,%eax
  and    (%rcx,%r13,1),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r10,%r13,1)
  cmp    -0x28(%rsp),%r12
  jl     L10
  mov    %r9d,%eax
  and    (%rcx,%r14,1),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r10,%r14,1)
  cmp    -0x20(%rsp),%r12
  jl     L10
  mov    -0x18(%rsp),%rsi
  mov    %r9d,%eax
  and    (%rcx,%rsi,1),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r10,%rsi,1)
L10:
  add    $0x1,%rdi
  cmp    -0x48(%rsp),%rdi
  jne    L55
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L39:
  mov    -0x10(%rsp),%rax
  nopl   (%rax)
L93:
  mov    %r9d,%edx
  and    (%rcx,%rax,4),%edx
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L93
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: byte[16]

tool: {"D8": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void nandc_uimatrix(uint **m1, long nrl, long nrh, long ncl, long nch, uint c, uint **m2) {
  long i, j;
  uint x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = !(x & c);
      Yi[j] = y;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L15
  movb   $0x1,-0x9(%rbp)
L15:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D15
data_type: string

tool: D16: flex

tool: D15: Executable

assistant: ```c
int main() {
  _Bool C_plus_plus;
  char *program_name = "flex";
  program_name = "Executable";
  if (program_name[0] != '\0' && program_name[strlen(program_name) - 1] == '+')
    C_plus_plus = 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  _Bool C_plus_plus;
  char *program_name = "flex";
  program_name = "Executable";
  if (program_name[0] != '\0' && program_name[strlen(program_name) - 1] == '+')
    C_plus_plus = 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  _Bool C_plus_plus;
  char *program_name = "flex";
  program_name = "Executable";
  if (program_name[0] != '\0' && program_name[strlen(program_name) - 1] == '+')
    C_plus_plus = 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  _Bool C_plus_plus;
  char *program_name = "flex";
  program_name = "Executable";
  if (program_name[0] != '\0' && program_name[strlen(program_name) - 1] == '+')
    C_plus_plus = 1;
  return 0;
}
```