ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<command_tune>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L59
  mov    %rdi,%rbp
  call   <dectou@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <skipstring@plt>
  cmpb   $0x0,(%rax)
  je     L38
  mov    %rbp,%rdi
  lea    0x10(,%r12,4),%ebp
  call   <skipstring@plt>
  mov    %rax,%rdi
  call   <strtofreq@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  mov    %eax,%esi
  call   <write_reg@plt>
  mov    %ebx,%esi
  lea    0x1(%rbp),%edi
  shr    $0x8,%esi
  call   <write_reg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  shr    $0x10,%ebx
  lea    0x2(%rbp),%edi
  mov    %ebx,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10d0 <write_reg@plt>
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    $0x1,%esi
  mov    $0xa,%edi
  lea    0x7(%rsp),%rdx
  call   <read_registers@plt>
  movzbl 0x7(%rsp),%esi
  mov    %r12d,%edi
  and    $0x3,%esi
  call   <tune_report@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L59:
  lea    0x7(%rsp),%rdx
  mov    $0x1,%esi
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <read_registers@plt>
L33:
  movzbl 0x7(%rsp),%esi
  mov    %ebx,%edi
  add    $0x1,%ebx
  and    $0x3,%esi
  call   <tune_report@plt>
  cmp    $0x4,%ebx
  jne    L33
  jmp    L27
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void command_tune(char *params) {
  if (*params == 0) {
    unsigned char a;
    read_registers(10, 1, &a);
    for (int i = 0; i != 4; ++i)
      tune_report(i, a & 3);
    return;
  }
  unsigned c = dectou(params);
  const char *p = skipstring(params);
  if (*p == 0) {
    unsigned char a;
    read_registers(10, 1, &a);
    tune_report(c, a & 3);
    return;
  }
  unsigned f = strtofreq(skipstring(params));
  write_reg(c * 4 + 16, f);
  write_reg(c * 4 + 17, f >> 8);
  write_reg(c * 4 + 18, f >> 16);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eembed_nibble_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x9,-0x4(%rbp)
  ja     L11
  movzbl -0x4(%rbp),%eax
  add    $0x30,%eax
  jmp    L6
L11:
  movzbl -0x4(%rbp),%eax
  add    $0x37,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
char eembed_nibble_to_hex(unsigned char nibble) {
  if (nibble < 10) {
    return '0' + nibble;
  }
  return 'A' + (nibble - 10);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eembed_nibble_to_hex>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%dil
  cmovbe %edx,%eax
  ret
```

assistant: ```c
char eembed_nibble_to_hex(unsigned char nibble) {
  if (nibble < 10) {
    return '0' + nibble;
  }
  return 'A' + (nibble - 10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eembed_nibble_to_hex>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%dil
  cmovbe %edx,%eax
  ret
```

assistant: ```c
char eembed_nibble_to_hex(unsigned char nibble) {
  if (nibble < 10) {
    return '0' + nibble;
  }
  return 'A' + (nibble - 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eembed_nibble_to_hex>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%dil
  cmovbe %edx,%eax
  ret
```

assistant: ```c
char eembed_nibble_to_hex(unsigned char nibble) {
  if (nibble < 10) {
    return '0' + nibble;
  }
  return 'A' + (nibble - 10);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<h_util_str_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L11:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
L9:
  cmpq   $0x0,-0x30(%rbp)
  jne    L10
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L10:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
L13:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *h_util_str_join(const char *s1, const char *s2) {
  int len1, len2;
  if (s1 == NULL)
    len1 = 0;
  else
    len1 = strlen(s1);
  if (s2 == NULL)
    len2 = 0;
  else
    len2 = strlen(s2);
  int len = len1 + len2 + 1;
  char *str = malloc(len);
  memcpy(str, s1, len1);
  memcpy(str + len1, s2, len2);
  str[len - 1] = '\0';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h_util_str_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L3
  call   <strlen@plt>
  mov    %eax,%ebx
L3:
  mov    $0x0,%r14d
  test   %r12,%r12
  je     L12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
L12:
  lea    0x1(%rbx,%r14,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  movslq %r13d,%r13
  movb   $0x0,-0x1(%rbp,%r13,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *h_util_str_join(const char *s1, const char *s2) {
  int len1, len2;
  if (s1 == NULL)
    len1 = 0;
  else
    len1 = strlen(s1);
  if (s2 == NULL)
    len2 = 0;
  else
    len2 = strlen(s2);
  int len = len1 + len2 + 1;
  char *str = malloc(len);
  memcpy(str, s1, len1);
  memcpy(str + len1, s2, len2);
  str[len - 1] = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<h_util_str_join>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L7
  call   <strlen@plt>
  mov    %eax,%r15d
  cltq
  mov    %rax,0x8(%rsp)
  test   %rbp,%rbp
  je     L2
L23:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    (%r15,%rax,1),%ebx
L12:
  add    $0x1,%ebx
  mov    %ebx,%edi
  movslq %ebx,%rbx
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L7:
  movq   $0x0,0x8(%rsp)
  xor    %r15d,%r15d
  test   %rbp,%rbp
  jne    L23
L2:
  mov    %r15d,%ebx
  xor    %r13d,%r13d
  jmp    L12
```

assistant: ```c
char *h_util_str_join(const char *s1, const char *s2) {
  int len1, len2;
  if (s1 == NULL)
    len1 = 0;
  else
    len1 = strlen(s1);
  if (s2 == NULL)
    len2 = 0;
  else
    len2 = strlen(s2);
  int len = len1 + len2 + 1;
  char *str = malloc(len);
  memcpy(str, s1, len1);
  memcpy(str + len1, s2, len2);
  str[len - 1] = '\0';
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<h_util_str_join>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L1
  call   <strlen@plt>
  mov    %eax,%r15d
  cltq
  mov    %rax,0x8(%rsp)
  test   %rbp,%rbp
  je     L16
L31:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    (%r15,%rax,1),%ebx
L17:
  add    $0x1,%ebx
  mov    %ebx,%edi
  movslq %ebx,%rbx
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  movq   $0x0,0x8(%rsp)
  xor    %r15d,%r15d
  test   %rbp,%rbp
  jne    L31
L16:
  mov    %r15d,%ebx
  xor    %r13d,%r13d
  jmp    L17
```

assistant: ```c
char *h_util_str_join(const char *s1, const char *s2) {
  int len1, len2;
  if (s1 == NULL)
    len1 = 0;
  else
    len1 = strlen(s1);
  if (s2 == NULL)
    len2 = 0;
  else
    len2 = strlen(s2);
  int len = len1 + len2 + 1;
  char *str = malloc(len);
  memcpy(str, s1, len1);
  memcpy(str + len1, s2, len2);
  str[len - 1] = '\0';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pimote_onoff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pimote_onoff(int socket, int on1off) {
  int r = 0;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pimote_onoff>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int pimote_onoff(int socket, int on1off) {
  int r = 0;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pimote_onoff>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pimote_onoff(int socket, int on1off) {
  int r = 0;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pimote_onoff>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pimote_onoff(int socket, int on1off) {
  int r = 0;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reader_thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L8:
  mov    $0x0,%eax
  call   <read_from_serial_device@plt>
  jmp    L8
```

assistant: ```c
void *reader_thread(void *arg) {
  while (1) {
    read_from_serial_device();
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reader_thread>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x0,%eax
  call   <read_from_serial_device@plt>
  jmp    L8
```

assistant: ```c
void *reader_thread(void *arg) {
  while (1) {
    read_from_serial_device();
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reader_thread>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <read_from_serial_device@plt>
  jmp    L8
```

assistant: ```c
void *reader_thread(void *arg) {
  while (1) {
    read_from_serial_device();
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reader_thread>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <read_from_serial_device@plt>
  jmp    L7
```

assistant: ```c
void *reader_thread(void *arg) {
  while (1) {
    read_from_serial_device();
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UARTCharGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x49f,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <AssertFailure@plt>
L1:
  nop
L0:
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  and    $0x10,%eax
  test   %rax,%rax
  jne    L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c", 1183);
    }
  };
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<UARTCharGet>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  je     L13
L16:
  mov    0x18(%rbx),%rax
  test   $0x10,%al
  jne    L16
  mov    (%rbx),%rax
  pop    %rbx
  ret
L13:
  mov    $0x49f,%esi
  lea    D8(%rip),%rdi
  call   <AssertFailure@plt>
  jmp    L16
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c", 1183);
    }
  };
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UARTCharGet>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  je     L23
L29:
  lea    0x18(%rbx),%rdx
  nopl   (%rax)
L4:
  mov    (%rdx),%rax
  test   $0x10,%al
  jne    L4
  mov    (%rbx),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L23:
  mov    $0x49f,%esi
  lea    D0(%rip),%rdi
  call   <AssertFailure@plt>
  jmp    L29
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c", 1183);
    }
  };
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTCharGet>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  je     L0
L6:
  lea    0x18(%rbx),%rdx
  nopl   (%rax)
L7:
  mov    (%rdx),%rax
  test   $0x10,%al
  jne    L7
  mov    (%rbx),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x49f,%esi
  lea    D9(%rip),%rdi
  call   <AssertFailure@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S6965_Crossworks/Boot/lib/driverlib/uartlib.c", 1183);
    }
  };
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mpeg_file_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L9
L6:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
L9:
  leave
  ret
```

assistant: ```c
FILE *mpeg_file_open(char *file, char *mode) {
  if (!file) {
    return NULL;
  }
  return fopen(file, mode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mpeg_file_open>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <fopen@plt>
  add    $0x8,%rsp
  ret
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
FILE *mpeg_file_open(char *file, char *mode) {
  if (!file) {
    return NULL;
  }
  return fopen(file, mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mpeg_file_open>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <fopen@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
FILE *mpeg_file_open(char *file, char *mode) {
  if (!file) {
    return NULL;
  }
  return fopen(file, mode);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mpeg_file_open>:
  endbr64
  test   %rdi,%rdi
  je     L9
  jmp    1050 <fopen@plt>
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
FILE *mpeg_file_open(char *file, char *mode) {
  if (!file) {
    return NULL;
  }
  return fopen(file, mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__ashldi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x20,%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L0
  mov    -0x4(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L0:
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    $0x20,%eax
  sub    -0x4(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  add    %esi,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0xc(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  shl    $0x20,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long __ashldi3(unsigned long long v, signed int cnt) {
  signed int c = cnt & 31;
  unsigned int vl = (unsigned int)v;
  unsigned int vh = (unsigned int)(v >> 32);
  if (cnt & 32) {
    vh = (vl << c);
    vl = 0;
  } else {
    vh = (vh << c) + (vl >> (32 - c));
    vl = (vl << c);
  }
  return ((unsigned long long)vh << 32) + vl;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__ashldi3>:
  endbr64
  mov    %esi,%edx
  and    $0x1f,%edx
  test   $0x20,%sil
  je     L2
  mov    %edi,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    $0x0,%edi
L12:
  shl    $0x20,%rax
  mov    %edi,%edi
  add    %rdi,%rax
  ret
L2:
  mov    %rdi,%rsi
  shr    $0x20,%rsi
  mov    %edx,%ecx
  shl    %cl,%esi
  mov    $0x20,%ecx
  sub    %edx,%ecx
  mov    %edi,%eax
  shr    %cl,%eax
  add    %esi,%eax
  mov    %edx,%ecx
  shl    %cl,%edi
  jmp    L12
```

assistant: ```c
unsigned long long __ashldi3(unsigned long long v, signed int cnt) {
  signed int c = cnt & 31;
  unsigned int vl = (unsigned int)v;
  unsigned int vh = (unsigned int)(v >> 32);
  if (cnt & 32) {
    vh = (vl << c);
    vl = 0;
  } else {
    vh = (vh << c) + (vl >> (32 - c));
    vl = (vl << c);
  }
  return ((unsigned long long)vh << 32) + vl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__ashldi3>:
  endbr64
  mov    %esi,%ecx
  mov    %edi,%eax
  and    $0x1f,%esi
  xor    %edx,%edx
  shl    %cl,%eax
  and    $0x20,%ecx
  jne    L2
  mov    %eax,%edx
  mov    %rdi,%rax
  mov    %esi,%ecx
  shr    $0x20,%rax
  shl    %cl,%eax
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%edi
  add    %edi,%eax
L2:
  shl    $0x20,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long __ashldi3(unsigned long long v, signed int cnt) {
  signed int c = cnt & 31;
  unsigned int vl = (unsigned int)v;
  unsigned int vh = (unsigned int)(v >> 32);
  if (cnt & 32) {
    vh = (vl << c);
    vl = 0;
  } else {
    vh = (vh << c) + (vl >> (32 - c));
    vl = (vl << c);
  }
  return ((unsigned long long)vh << 32) + vl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__ashldi3>:
  endbr64
  mov    %esi,%ecx
  mov    %edi,%eax
  and    $0x1f,%esi
  xor    %edx,%edx
  shl    %cl,%eax
  and    $0x20,%ecx
  jne    L3
  mov    %eax,%edx
  mov    %rdi,%rax
  mov    %esi,%ecx
  shr    $0x20,%rax
  shl    %cl,%eax
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%edi
  add    %edi,%eax
L3:
  shl    $0x20,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long __ashldi3(unsigned long long v, signed int cnt) {
  signed int c = cnt & 31;
  unsigned int vl = (unsigned int)v;
  unsigned int vh = (unsigned int)(v >> 32);
  if (cnt & 32) {
    vh = (vl << c);
    vl = 0;
  } else {
    vh = (vh << c) + (vl >> (32 - c));
    vl = (vl << c);
  }
  return ((unsigned long long)vh << 32) + vl;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_first_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L72
L42:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L56
  addq   $0x20,-0x10(%rbp)
  subq   $0x20,-0x30(%rbp)
L72:
  mov    -0x30(%rbp),%rax
  and    $0xffffffffffffffe0,%rax
  test   %rax,%rax
  jne    L42
  cmpq   $0x0,-0x30(%rbp)
  jne    L74
  mov    -0x10(%rbp),%rax
  jmp    L25
L74:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %eax,%ecx
  mov    $0x20,%eax
  sub    %ecx,%eax
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%ecx
  shr    %cl,%rsi
  mov    %rsi,%rax
  and    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  jmp    L25
L56:
  nop
  jmp    L17
L9:
  nop
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__ffs@plt>
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rax
L25:
  leave
  ret
```

assistant: ```c
unsigned long find_first_bit(const unsigned long *addr, unsigned long size) {
  const unsigned long *p = addr;
  unsigned long result = 0;
  unsigned long tmp;
  while (size & ~(32 - 1)) {
    if ((tmp = *(p++)))
      goto found;
    result += 32;
    size -= 32;
  }
  if (!size)
    return result;
  tmp = (*p) & (~0UL >> (32 - size));
  if (tmp == 0UL)
    return result + size;
found:
  return result + __ffs(tmp);
}
```