ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D1(%rip),%rdx
  lea    D68(%rip),%rsi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10,%ebx
  pxor   %xmm4,%xmm4
  movss  %xmm4,0xc(%rsp)
  lea    D8(%rip),%rbp
L0:
  movss  0xc(%rsp),%xmm2
  movaps %xmm2,%xmm1
  subss  D20(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  mulsd  D44(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  D62(%rip),%xmm3
  addss  0xc(%rsp),%xmm3
  movss  %xmm3,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string
name: disassemble_data
arguments: tag: D68
type: string
name: disassemble_data
arguments: tag: D57
type: string
name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D20
type: byte[4]
name: disassemble_data
arguments: tag: D44
type: byte[8]
name: disassemble_data
arguments: tag: D62
type: byte[4]

tool: D1: Celsius

tool: D68: Fahr

tool: D57: %3s %7s


tool: D8: %3.0f %6.1f


tool: {"D20": [0x00,0x00,0x00,0x42]}

tool: {"D44": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D62": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  float lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("%3s %7s\n", "Fahr", "Celsius");
  while (fahr <= upper) {
    celsius = (5.0 / 9.0) * (fahr - 32);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D65(%rip),%rdx
  lea    D38(%rip),%rsi
  xor    %eax,%eax
  push   %rbx
  lea    D42(%rip),%rdi
  mov    $0x10,%ebx
  lea    D25(%rip),%rbp
  sub    $0x18,%rsp
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L7:
  movaps %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  subss  D4(%rip),%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D66(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D51(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D65
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D42
type_guessed: string
name: retrieve_data
arguments: data_label: D25
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D66
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D51
type_guessed: byte[4]

tool: D65: Celsius

tool: D38: Fahr

tool: D42: %3s %7s


tool: D25: %3.0f %6.1f


tool: {"D4": [0x00,0x00,0x00,0x42]}

tool: {"D66": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D51": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  float lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("%3s %7s\n", "Fahr", "Celsius");
  while (fahr <= upper) {
    celsius = (5.0 / 9.0) * (fahr - 32);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdx
  lea    D20(%rip),%rsi
  xor    %eax,%eax
  push   %rbx
  lea    D43(%rip),%rdi
  mov    $0x10,%ebx
  lea    D48(%rip),%rbp
  sub    $0x18,%rsp
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L4:
  movaps %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  subss  D33(%rip),%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D3(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D39(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string
name: extract_symbolic_data
arguments: label: D43
data_type: string
name: extract_symbolic_data
arguments: label: D48
data_type: string
name: extract_symbolic_data
arguments: label: D33
data_type: byte[4]
name: extract_symbolic_data
arguments: label: D3
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D39
data_type: byte[4]

tool: D17: Celsius

tool: D20: Fahr

tool: D43: %3s %7s


tool: D48: %3.0f %6.1f


tool: {"D33": [0x00,0x00,0x00,0x42]}

tool: {"D3": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D39": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  float lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("%3s %7s\n", "Fahr", "Celsius");
  while (fahr <= upper) {
    celsius = (5.0 / 9.0) * (fahr - 32);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fild_Usleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void fild_Usleep(unsigned int useconds) {
  usleep(useconds);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fild_Usleep>:
  endbr64
  sub    $0x8,%rsp
  call   <usleep@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fild_Usleep(unsigned int useconds) {
  usleep(useconds);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fild_Usleep>:
  endbr64
  jmp    1050 <usleep@plt>
```

assistant: ```c
void fild_Usleep(unsigned int useconds) {
  usleep(useconds);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fild_Usleep>:
  endbr64
  jmp    1050 <usleep@plt>
```

assistant: ```c
void fild_Usleep(unsigned int useconds) {
  usleep(useconds);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x1f8(%rbp)
  jmp    L14
L20:
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x1ec,%rax
  movl   $0x1,(%rax)
  movl   $0x2,-0x1f4(%rbp)
  jmp    L65
L41:
  mov    -0x1f8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1f4(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x1f0(%rbp,%rax,4),%ecx
  mov    -0x1f8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1f4(%rbp),%eax
  movslq %eax,%rsi
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    -0x1f0(%rbp,%rax,4),%eax
  add    %eax,%ecx
  mov    -0x1f4(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    %ecx,-0x1f0(%rbp,%rax,4)
  addl   $0x1,-0x1f4(%rbp)
L65:
  mov    -0x1f4(%rbp),%eax
  cmp    -0x1f8(%rbp),%eax
  jl     L41
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x1f0,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x1f8(%rbp)
L14:
  cmpl   $0xa,-0x1f8(%rbp)
  jle    L20
  movl   $0x1,-0x1f8(%rbp)
  jmp    L2
L67:
  movl   $0x1,-0x1f4(%rbp)
  jmp    L49
L6:
  mov    -0x1f4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x1f0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1f4(%rbp)
L49:
  mov    -0x1f4(%rbp),%eax
  cmp    -0x1f8(%rbp),%eax
  jle    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x1f8(%rbp)
L2:
  cmpl   $0xa,-0x1f8(%rbp)
  jle    L67
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: %d 

assistant: ```c
int main() {
  int arr[10 + 1][10 + 1];
  int row, col;
  for (row = 1; row <= 10; row++) {
    arr[row][1] = 1;
    for (col = 2; col < row; col++) {
      arr[row][col] = arr[row - 1][col - 1] + arr[row - 1][col];
    }
    arr[row][row] = 1;
  }
  for (row = 1; row <= 10; row++) {
    for (col = 1; col <= row; col++) {
      printf("%d ", arr[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x30(%rsp)
  lea    0x30(%rsp),%r10
  lea    0x2c(%rsp),%rbp
  mov    %rbp,%r9
  mov    $0xb,%ebx
  mov    $0x58,%edi
  mov    $0xffffffffffffffd4,%rsi
  mov    $0x1,%eax
  lea    0x4(%rsp),%r12
  jmp    L66
L91:
  add    $0x30,%r10
  add    $0x2c,%r9
  sub    $0x2c,%rsi
  add    $0x2c,%rdi
  add    $0xb,%rbx
  mov    %r11d,%eax
L66:
  movl   $0x1,(%r10)
  lea    0x1(%rax),%r11d
  cmp    $0xa,%eax
  je     L96
  movl   $0x1,0x30(%r9)
  cmp    $0x2,%r11d
  jle    L91
  lea    -0x2(%rax),%eax
  add    %rbx,%rax
  lea    (%r12,%rax,4),%r8
  mov    %r9,%rax
L54:
  lea    (%rax,%rsi,1),%rcx
  mov    0x8(%rax),%edx
  add    0x4(%rax),%edx
  mov    %edx,0x8(%rcx,%rdi,1)
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L54
  jmp    L91
L96:
  mov    $0x1,%r12d
  lea    D6(%rip),%r13
  jmp    L55
L92:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L92
L56:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  add    $0x2c,%rbp
  cmp    $0xb,%r12d
  je     L8
L55:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jg     L92
  jmp    L56
L8:
  mov    0x1e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  mov    $0x0,%eax
  add    $0x1f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: %d 

assistant: ```c
int main() {
  int arr[10 + 1][10 + 1];
  int row, col;
  for (row = 1; row <= 10; row++) {
    arr[row][1] = 1;
    for (col = 2; col < row; col++) {
      arr[row][col] = arr[row - 1][col - 1] + arr[row - 1][col];
    }
    arr[row][row] = 1;
  }
  for (row = 1; row <= 10; row++) {
    for (col = 1; col <= row; col++) {
      printf("%d ", arr[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x58,%edi
  mov    $0xffffffffffffffd4,%rsi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xb,%ebx
  sub    $0x1f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbp
  mov    $0x1,%eax
  movl   $0x1,0x30(%rsp)
  mov    %rbp,%r10
  lea    0x2c(%rsp),%r9
  lea    0x4(%rsp),%r12
  movl   $0x1,(%r10)
  lea    0x1(%rax),%r11d
  cmp    $0xa,%eax
  je     L60
  cs nopw 0x0(%rax,%rax,1)
L57:
  movl   $0x1,0x30(%r9)
  cmp    $0x2,%r11d
  je     L33
  sub    $0x2,%eax
  add    %rbx,%rax
  lea    (%r12,%rax,4),%r8
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x8(%rax),%edx
  lea    (%rax,%rsi,1),%rcx
  add    0x4(%rax),%edx
  add    $0x4,%rax
  mov    %edx,0x8(%rcx,%rdi,1)
  cmp    %r8,%rax
  jne    L26
L33:
  mov    %r11d,%eax
  add    $0x30,%r10
  add    $0x2c,%r9
  sub    $0x2c,%rsi
  add    $0x2c,%rdi
  add    $0xb,%rbx
  lea    0x1(%rax),%r11d
  movl   $0x1,(%r10)
  cmp    $0xa,%eax
  jne    L57
L60:
  lea    0x34(%rsp),%r12
  lea    0x214(%rsp),%r14
  lea    D3(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L42:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L42
  mov    $0xa,%edi
  lea    0x30(%rbx),%r12
  add    $0x2c,%rbp
  call   <putchar@plt>
  cmp    %r14,%r12
  jne    L35
  mov    0x1e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x1f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d 

assistant: ```c
int main() {
  int arr[10 + 1][10 + 1];
  int row, col;
  for (row = 1; row <= 10; row++) {
    arr[row][1] = 1;
    for (col = 2; col < row; col++) {
      arr[row][col] = arr[row - 1][col - 1] + arr[row - 1][col];
    }
    arr[row][row] = 1;
  }
  for (row = 1; row <= 10; row++) {
    for (col = 1; col <= row; col++) {
      printf("%d ", arr[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isbinaryfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x138(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <open@plt>
  mov    %eax,-0x120(%rbp)
  cmpl   $0xffffffff,-0x120(%rbp)
  jne    L78
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L78:
  lea    -0x110(%rbp),%rcx
  mov    -0x120(%rbp),%eax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,-0x124(%rbp)
  cmpl   $0xffffffff,-0x124(%rbp)
  jne    L5
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    -0x120(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <close@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  jmp    L84
L67:
  mov    -0x118(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x118(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0x11c(%rbp)
  cmpl   $0x0,-0x11c(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L1
L15:
  mov    -0x11c(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L84
  mov    $0x1,%eax
  jmp    L1
L84:
  mov    -0x124(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x124(%rbp)
  test   %eax,%eax
  jg     L67
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L89
  call   <__stack_chk_fail@plt>
L89:
  leave
  ret
```

assistant: ```c
isbinaryfile(s) char *s;
{
  char buf[256];
  char *p;
  int n, f, c;
  f = open(s, 0);
  if (f == -1) {
    perror(s);
    exit(1);
  }
  n = read(f, buf, sizeof(buf));
  if (n == -1) {
    perror(s);
    exit(1);
  }
  (void)close(f);
  p = buf;
  while (n-- > 0) {
    c = *p++ & 0xff;
    if (c == 0)
      return 1;
    if (c & 0x80)
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isbinaryfile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L49
  mov    %eax,%ebp
  mov    %rsp,%rsi
  mov    $0x100,%edx
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L25
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <close@plt>
  mov    %rsp,%rdx
  mov    %rsp,%rax
  add    %ebx,%eax
L24:
  mov    %eax,%ecx
  sub    %edx,%ecx
  test   %ecx,%ecx
  jle    L34
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  test   %cl,%cl
  je     L58
  jns    L24
L58:
  mov    $0x1,%eax
L30:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L25:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L34:
  mov    $0x0,%eax
  jmp    L30
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
isbinaryfile(s) char *s;
{
  char buf[256];
  char *p;
  int n, f, c;
  f = open(s, 0);
  if (f == -1) {
    perror(s);
    exit(1);
  }
  n = read(f, buf, sizeof(buf));
  if (n == -1) {
    perror(s);
    exit(1);
  }
  (void)close(f);
  p = buf;
  while (n-- > 0) {
    c = *p++ & 0xff;
    if (c == 0)
      return 1;
    if (c & 0x80)
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isbinaryfile>:
  endbr64
  push   %r13
  xor    %esi,%esi
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    %rsp,%rbx
  mov    %eax,%edi
  mov    %eax,%r12d
  mov    $0x100,%edx
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <read@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L1
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <close@plt>
  mov    %rbx,%rdx
  lea    0x0(%rbp,%rbx,1),%eax
  jmp    L28
  nopl   0x0(%rax)
L27:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L0
  js     L0
L28:
  mov    %eax,%ecx
  sub    %edx,%ecx
  test   %ecx,%ecx
  jg     L27
  xor    %eax,%eax
  jmp    L33
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
L33:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
isbinaryfile(s) char *s;
{
  char buf[256];
  char *p;
  int n, f, c;
  f = open(s, 0);
  if (f == -1) {
    perror(s);
    exit(1);
  }
  n = read(f, buf, sizeof(buf));
  if (n == -1) {
    perror(s);
    exit(1);
  }
  (void)close(f);
  p = buf;
  while (n-- > 0) {
    c = *p++ & 0xff;
    if (c == 0)
      return 1;
    if (c & 0x80)
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isbinaryfile>:
  endbr64
  push   %r13
  xor    %esi,%esi
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    %rsp,%rbx
  mov    %eax,%edi
  mov    %eax,%r12d
  mov    $0x100,%edx
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <read@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L2
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <close@plt>
  mov    %rbx,%rdx
  lea    0x0(%rbp,%rbx,1),%eax
  jmp    L48
  nopl   0x0(%rax)
L34:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L10
  js     L10
L48:
  mov    %eax,%ecx
  sub    %edx,%ecx
  test   %ecx,%ecx
  jg     L34
  xor    %eax,%eax
  jmp    L76
  nopl   0x0(%rax)
L10:
  mov    $0x1,%eax
L76:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
isbinaryfile(s) char *s;
{
  char buf[256];
  char *p;
  int n, f, c;
  f = open(s, 0);
  if (f == -1) {
    perror(s);
    exit(1);
  }
  n = read(f, buf, sizeof(buf));
  if (n == -1) {
    perror(s);
    exit(1);
  }
  (void)close(f);
  p = buf;
  while (n-- > 0) {
    c = *p++ & 0xff;
    if (c == 0)
      return 1;
    if (c & 0x80)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L2
L25:
  subl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L60
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L60
  cmpl   $0x0,-0x4(%rbp)
  jg     L25
L60:
  cmpl   $0x0,-0x4(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L15
L42:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L63
  mov    $0x0,%eax
  jmp    L15
L63:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L15:
  leave
  ret
```

assistant: ```c
char *split_ext(char *path) {
  int i;
  i = strlen(path);
  while ((path[i] != '.') && (path[i] != '/') && (i > 0)) {
    i--;
  }
  if (i == 0) {
    return NULL;
  }
  if (path[i] == '/') {
    return NULL;
  }
  return &path[i + 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<split_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%r8
  movzbl (%rbx,%r8,1),%ecx
  lea    -0x2e(%rcx),%edx
  cmp    $0x1,%dl
  jbe    L35
  test   %eax,%eax
  jle    L35
  sub    $0x1,%eax
  movslq %eax,%rdx
L10:
  mov    %edx,%eax
  movzbl (%rbx,%rdx,1),%ecx
  lea    -0x2e(%rcx),%esi
  cmp    $0x1,%sil
  seta   %dil
  test   %edx,%edx
  setg   %sil
  mov    %rdx,%r8
  sub    $0x1,%rdx
  test   %sil,%dil
  jne    L10
L35:
  cmp    $0x2f,%cl
  je     L20
  test   %eax,%eax
  je     L20
  lea    0x1(%rbx,%r8,1),%rax
L46:
  pop    %rbx
  ret
L20:
  mov    $0x0,%eax
  jmp    L46
```

assistant: ```c
char *split_ext(char *path) {
  int i;
  i = strlen(path);
  while ((path[i] != '.') && (path[i] != '/') && (i > 0)) {
    i--;
  }
  if (i == 0) {
    return NULL;
  }
  if (path[i] == '/') {
    return NULL;
  }
  return &path[i + 1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<split_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdi
  movzbl (%rbx,%rdi,1),%ecx
  lea    -0x2e(%rcx),%edx
  cmp    $0x1,%dl
  jbe    L31
  test   %eax,%eax
  jle    L31
  sub    $0x1,%eax
  movslq %eax,%rdx
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %edx,%eax
  mov    %rdx,%rdi
  lea    -0x2e(%rcx),%esi
  cmp    $0x1,%sil
  seta   %r8b
  test   %edx,%edx
  setg   %sil
  sub    $0x1,%rdx
  test   %sil,%r8b
  jne    L4
L31:
  test   %eax,%eax
  je     L14
  cmp    $0x2f,%cl
  je     L14
  lea    0x1(%rbx,%rdi,1),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *split_ext(char *path) {
  int i;
  i = strlen(path);
  while ((path[i] != '.') && (path[i] != '/') && (i > 0)) {
    i--;
  }
  if (i == 0) {
    return NULL;
  }
  if (path[i] == '/') {
    return NULL;
  }
  return &path[i + 1];
}
```