ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <outbyte@plt>
  test   %rax,%rax
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void outstr(char ptr[]) {
  while (outbyte(*ptr++))
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <outbyte@plt>
  test   %rax,%rax
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void outstr(char ptr[]) {
  while (outbyte(*ptr++))
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bintime_addx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bintime_addx(void) {
  int u;
  if (u > 1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bintime_addx>:
  endbr64
  ret
```

assistant: ```c
void bintime_addx(void) {
  int u;
  if (u > 1)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bintime_addx>:
  endbr64
  ret
```

assistant: ```c
void bintime_addx(void) {
  int u;
  if (u > 1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bintime_addx>:
  endbr64
  ret
```

assistant: ```c
void bintime_addx(void) {
  int u;
  if (u > 1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_digit_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L28
  jmp    L6
L5:
  nop
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_digit_index(char *input) {
  int i;
  for (i = 0; i < strlen(input); i++)
    if (isdigit(*(input + i)))
      break;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_digit_index>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L13:
  mov    %ebx,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L16
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  je     L13
L16:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_digit_index(char *input) {
  int i;
  for (i = 0; i < strlen(input); i++)
    if (isdigit(*(input + i)))
      break;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_digit_index>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L22
  nop
L2:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L10
L22:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
L10:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_digit_index(char *input) {
  int i;
  for (i = 0; i < strlen(input); i++)
    if (isdigit(*(input + i)))
      break;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_digit_index>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L5
  nop
L29:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L10
L5:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L29
L10:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_digit_index(char *input) {
  int i;
  for (i = 0; i < strlen(input); i++)
    if (isdigit(*(input + i)))
      break;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dns_cache_submit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int dns_cache_submit(struct dns_packet *query, struct dns_cache *cache) {
  (void)query;
  (void)cache;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dns_cache_submit>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int dns_cache_submit(struct dns_packet *query, struct dns_cache *cache) {
  (void)query;
  (void)cache;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dns_cache_submit>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int dns_cache_submit(struct dns_packet *query, struct dns_cache *cache) {
  (void)query;
  (void)cache;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dns_cache_submit>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int dns_cache_submit(struct dns_packet *query, struct dns_cache *cache) {
  (void)query;
  (void)cache;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x1f,-0x8(%rbp)
  jmp    L5
L29:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L25
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L30
L25:
  mov    $0x30,%edi
  call   <putchar@plt>
L30:
  mov    -0x8(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L21
  mov    $0x20,%edi
  call   <putchar@plt>
L21:
  subl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x8(%rbp)
  jns    L29
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i, z = getchar();
  for (i = sizeof(int) * 8 - 1; i >= 0; --i) {
    if (z & (1 << i)) {
      putchar('1');
    } else {
      putchar('0');
    }
    if (i % 4 == 0) {
      putchar(' ');
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  mov    $0x1f,%ebx
  jmp    L52
L16:
  mov    $0x30,%edi
  call   <putchar@plt>
L26:
  test   $0x3,%bl
  je     L30
L11:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L10
L52:
  bt     %ebx,%ebp
  jae    L16
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L26
L30:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L11
L10:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, z = getchar();
  for (i = sizeof(int) * 8 - 1; i >= 0; --i) {
    if (z & (1 << i)) {
      putchar('1');
    } else {
      putchar('0');
    }
    if (i % 4 == 0) {
      putchar(' ');
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0x1f,%ebx
  sub    $0x8,%rsp
  call   <getchar@plt>
  mov    %eax,%ebp
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0x31,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  je     L15
L49:
  sub    $0x1,%ebx
  jb     L41
L57:
  bt     %ebx,%ebp
  jb     L46
  mov    $0x30,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  jne    L49
L15:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L57
L41:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, z = getchar();
  for (i = sizeof(int) * 8 - 1; i >= 0; --i) {
    if (z & (1 << i)) {
      putchar('1');
    } else {
      putchar('0');
    }
    if (i % 4 == 0) {
      putchar(' ');
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0x1f,%ebx
  sub    $0x8,%rsp
  call   <getchar@plt>
  mov    %eax,%ebp
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x31,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  je     L41
L39:
  sub    $0x1,%ebx
  jb     L29
L44:
  bt     %ebx,%ebp
  jb     L3
  mov    $0x30,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  jne    L39
L41:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L44
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, z = getchar();
  for (i = sizeof(int) * 8 - 1; i >= 0; --i) {
    if (z & (1 << i)) {
      putchar('1');
    } else {
      putchar('0');
    }
    if (i % 4 == 0) {
      putchar(' ');
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L10:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L34
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  jmp    L38
L34:
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L10
L38:
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D3
data_type: string

tool: D0: Enter two integers: 

tool: D19: %d %d

tool: D3: GCD is %d


assistant: ```c
int main(void) {
  int num1, num2, remain;
  remain = 0;
  printf("Enter two integers: ");
  scanf("%d %d", &num1, &num2);
  while (true) {
    if (num2 == 0) {
      printf("GCD is %d\n", num1);
      break;
    } else {
      remain = num1 % num2;
      num1 = num2;
      num2 = remain;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%eax
  test   %ecx,%ecx
  jne    L28
  jmp    L35
L21:
  mov    %edx,%ecx
L28:
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L21
  mov    %ecx,(%rsp)
  movl   $0x0,0x4(%rsp)
L35:
  mov    (%rsp),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string

tool: D11: Enter two integers: 

tool: D16: %d %d

tool: D25: GCD is %d


assistant: ```c
int main(void) {
  int num1, num2, remain;
  remain = 0;
  printf("Enter two integers: ");
  scanf("%d %d", &num1, &num2);
  while (true) {
    if (num2 == 0) {
      printf("GCD is %d\n", num1);
      break;
    } else {
      remain = num1 % num2;
      num1 = num2;
      num2 = remain;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%eax
  test   %esi,%esi
  jne    L19
  jmp    L28
  nopl   (%rax)
L6:
  mov    %edx,%esi
L19:
  cltd
  idiv   %esi
  mov    %esi,%eax
  test   %edx,%edx
  jne    L6
  mov    %esi,(%rsp)
  movl   $0x0,0x4(%rsp)
L11:
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L28:
  mov    %eax,%esi
  jmp    L11
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string

tool: D27: Enter two integers: 

tool: D21: %d %d

tool: D25: GCD is %d


assistant: ```c
int main(void) {
  int num1, num2, remain;
  remain = 0;
  printf("Enter two integers: ");
  scanf("%d %d", &num1, &num2);
  while (true) {
    if (num2 == 0) {
      printf("GCD is %d\n", num1);
      break;
    } else {
      remain = num1 % num2;
      num1 = num2;
      num2 = remain;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%eax
  test   %esi,%esi
  jne    L19
  jmp    L22
  nopl   (%rax)
L48:
  mov    %edx,%esi
L19:
  cltd
  idiv   %esi
  mov    %esi,%eax
  test   %edx,%edx
  jne    L48
  mov    %esi,(%rsp)
  movl   $0x0,0x4(%rsp)
L5:
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  mov    %eax,%esi
  jmp    L5
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D5: Enter two integers: 

tool: D3: %d %d

tool: D6: GCD is %d


assistant: ```c
int main(void) {
  int num1, num2, remain;
  remain = 0;
  printf("Enter two integers: ");
  scanf("%d %d", &num1, &num2);
  while (true) {
    if (num2 == 0) {
      printf("GCD is %d\n", num1);
      break;
    } else {
      remain = num1 % num2;
      num1 = num2;
      num2 = remain;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nzd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L27
  negl   -0x14(%rbp)
L27:
  cmpl   $0x0,-0x18(%rbp)
  jns    L47
  negl   -0x18(%rbp)
L47:
  cmpl   $0x0,-0x18(%rbp)
  jne    L48
  mov    -0x14(%rbp),%eax
  jmp    L88
L48:
  cmpl   $0x0,-0x14(%rbp)
  jne    L65
  mov    -0x18(%rbp),%eax
  jmp    L88
L65:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L11
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L77
L11:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L77
L4:
  subl   $0x1,-0x4(%rbp)
L77:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L4
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L4
  mov    -0x4(%rbp),%eax
L88:
  pop    %rbp
  ret
```

assistant: ```c
int nzd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (b == 0)
    return a;
  if (a == 0)
    return b;
  if (a < b)
    c = a;
  else
    c = b;
  while ((a % c != 0) || (b % c != 0))
    c--;
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nzd>:
  endbr64
  mov    %edi,%r8d
  neg    %r8d
  cmovs  %edi,%r8d
  mov    %r8d,%ecx
  test   %esi,%esi
  je     L36
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
  mov    %esi,%ecx
  test   %edi,%edi
  je     L36
  cmp    %r8d,%esi
  mov    %r8d,%ecx
  cmovle %esi,%ecx
  jmp    L0
L45:
  sub    $0x1,%ecx
L0:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L45
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L45
L36:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int nzd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (b == 0)
    return a;
  if (a == 0)
    return b;
  if (a < b)
    c = a;
  else
    c = b;
  while ((a % c != 0) || (b % c != 0))
    c--;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nzd>:
  endbr64
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    %ecx,%r8d
  test   %esi,%esi
  je     L45
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
  mov    %esi,%r8d
  test   %edi,%edi
  je     L45
  cmp    %ecx,%esi
  mov    %ecx,%r8d
  cmovle %esi,%r8d
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L8:
  sub    $0x1,%r8d
L16:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L8
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L8
L45:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nzd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (b == 0)
    return a;
  if (a == 0)
    return b;
  if (a < b)
    c = a;
  else
    c = b;
  while ((a % c != 0) || (b % c != 0))
    c--;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nzd>:
  endbr64
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    %ecx,%r8d
  test   %esi,%esi
  je     L1
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
  mov    %esi,%r8d
  test   %edi,%edi
  je     L1
  cmp    %ecx,%esi
  mov    %ecx,%r8d
  cmovle %esi,%r8d
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L48:
  sub    $0x1,%r8d
L44:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L48
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L48
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nzd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (b == 0)
    return a;
  if (a == 0)
    return b;
  if (a < b)
    c = a;
  else
    c = b;
  while ((a % c != 0) || (b % c != 0))
    c--;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nonzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <abs@plt>
  movss  -0x18(%rbp),%xmm1
  comiss %xmm0,%xmm1
  jbe    L6
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <sign@plt>
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L18
L6:
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
L18:
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float nonzero(float f, float eps) {
  float r;
  if (abs(f) < eps)
    r = sign(f) * eps;
  else
    r = f;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nonzero>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  call   <abs@plt>
  movss  0xc(%rsp),%xmm2
  comiss %xmm0,%xmm2
  ja     L10
L2:
  movss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L10:
  movss  0x8(%rsp),%xmm0
  call   <sign@plt>
  mulss  0xc(%rsp),%xmm0
  movss  %xmm0,0x8(%rsp)
  jmp    L2
```

assistant: ```c
float nonzero(float f, float eps) {
  float r;
  if (abs(f) < eps)
    r = sign(f) * eps;
  else
    r = f;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nonzero>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <abs@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm2
  comiss %xmm0,%xmm3
  ja     L2
  movaps %xmm2,%xmm0
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movaps %xmm2,%xmm0
  call   <sign@plt>
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  mulss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float nonzero(float f, float eps) {
  float r;
  if (abs(f) < eps)
    r = sign(f) * eps;
  else
    r = f;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nonzero>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <abs@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm2
  comiss %xmm0,%xmm3
  ja     L2
  movaps %xmm2,%xmm0
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movaps %xmm2,%xmm0
  call   <sign@plt>
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  mulss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float nonzero(float f, float eps) {
  float r;
  if (abs(f) < eps)
    r = sign(f) * eps;
  else
    r = f;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qstrgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L52
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L52
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
L52:
  mov    $0x0,%eax
  jmp    L101
L14:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L96
L47:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L62
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L25
  addq   $0x1,-0x10(%rbp)
  jmp    L72
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  jmp    L48
L62:
  nop
L48:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L96:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L72
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L47
L72:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
L101:
  pop    %rbp
  ret
```

assistant: ```c
char *qstrgets(char *buf, size_t size, char **offset) {
  if (offset == NULL || *offset == NULL || **offset == '\0')
    return NULL;
  size_t i;
  char *from = *offset;
  char *to = buf;
  for (i = 0; *from != '\0' && i < (size - 1); i++, from++) {
    if (*from == '\r')
      continue;
    if (*from == '\n') {
      from++;
      break;
    }
    *to = *from;
    to++;
  }
  *to = '\0';
  *offset = from;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<qstrgets>:
  endbr64
  test   %rdx,%rdx
  je     L82
  mov    (%rdx),%rax
  test   %rax,%rax
  je     L89
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L85
  sub    $0x1,%rsi
  je     L115
  lea    (%rax,%rsi,1),%r8
  mov    %rdi,%rsi
  jmp    L24
L61:
  add    $0x1,%rax
  jmp    L13
L36:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L13
  cmp    %rax,%r8
  je     L76
L24:
  cmp    $0xd,%cl
  je     L36
  cmp    $0xa,%cl
  je     L61
  mov    %cl,(%rsi)
  add    $0x1,%rsi
  jmp    L36
L76:
  mov    %r8,%rax
L13:
  movb   $0x0,(%rsi)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
L115:
  mov    %rdi,%rsi
  jmp    L13
L82:
  mov    %rdx,%rax
  ret
L85:
  mov    $0x0,%eax
L89:
  ret
```

assistant: ```c
char *qstrgets(char *buf, size_t size, char **offset) {
  if (offset == NULL || *offset == NULL || **offset == '\0')
    return NULL;
  size_t i;
  char *from = *offset;
  char *to = buf;
  for (i = 0; *from != '\0' && i < (size - 1); i++, from++) {
    if (*from == '\r')
      continue;
    if (*from == '\n') {
      from++;
      break;
    }
    *to = *from;
    to++;
  }
  *to = '\0';
  *offset = from;
  return buf;
}
```