user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x2,-0x1a0(%rbp)
  movl   $0x4,-0x19c(%rbp)
  movl   $0x7,-0x198(%rbp)
  movl   $0x8,-0x194(%rbp)
  movl   $0xb,-0x190(%rbp)
  movl   $0xe,-0x18c(%rbp)
  movl   $0x11,-0x188(%rbp)
  movl   $0x13,-0x184(%rbp)
  movl   $0x15,-0x180(%rbp)
  movl   $0x18,-0x17c(%rbp)
  movl   $0x0,-0x1b0(%rbp)
  jmp    L2
L37:
  mov    -0x1b0(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%edx
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1b0(%rbp)
L2:
  cmpl   $0x63,-0x1b0(%rbp)
  jle    L37
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1b0(%rbp)
  jmp    L10
L1:
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1b0(%rbp)
L10:
  cmpl   $0x63,-0x1b0(%rbp)
  jle    L1
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1b4(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1ac(%rbp)
  movl   $0x63,-0x1a8(%rbp)
  mov    -0x1b4(%rbp),%ecx
  mov    -0x1a8(%rbp),%edx
  mov    -0x1ac(%rbp),%esi
  lea    -0x1a0(%rbp),%rax
  mov    %rax,%rdi
  call   <BinarySearch@plt>
  mov    %eax,-0x1a4(%rbp)
  cmpl   $0xffffffff,-0x1a4(%rbp)
  jne    L7
  mov    -0x1b4(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L7:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    -0x1a4(%rbp),%edx
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D25
type: string
name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D14
type: string
name: parse_data
arguments: tag: D48
type: string
name: parse_data
arguments: tag: D42
type: string

tool: D8: 
Array is 

tool: D25: %d 

tool: D26: 
Input value to search for: 

tool: D14: %d

tool: D48: 
Value %d not found



tool: D42: 
Value %d found at array position: %d



assistant: ```c
int main() {
  int myarray[100] = {2, 4, 7, 8, 11, 14, 17, 19, 21, 24};
  int position, key, i;
  int low, high;
  for (i = 0; i < 100; i++) {
    myarray[i] = 2 * i + 1;
  }
  printf("\nArray is ");
  for (i = 0; i < 100; ++i)
    printf("%d ", myarray[i]);
  printf("\nInput value to search for: ");
  scanf("%d", &key);
  low = 0;
  high = 99;
  position = BinarySearch(myarray, low, high, key);
  if (position == -1)
    printf("\nValue %d not found\n\n", key);
  else
    printf("\nValue %d found at array position: %d\n\n", myarray[position], position);
  getchar();
  getchar();
  return 0;
}
```