ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<stringToDouble>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sscanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: %lf

assistant: ```c
double stringToDouble(char str[]) {
  double result;
  sscanf(str, "%lf", &result);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stringToDouble>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sscanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D5: %lf

assistant: ```c
double stringToDouble(char str[]) {
  double result;
  sscanf(str, "%lf", &result);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pd001s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pd001s(n, a, b) int n, *a, *b;
{
  int i;
#pragma omp parallel for
  for (i = 1; i < n; i++)
    b[i] = (a[i] + a[i - 1]) / 2;
}
```
user: What is the c source code of the assembly code below?

```asm
<pd001s>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  mov    %edi,%edi
  mov    $0x1,%eax
L2:
  mov    -0x4(%rsi,%rax,4),%r8d
  add    (%rsi,%rax,4),%r8d
  mov    %r8d,%ecx
  shr    $0x1f,%ecx
  add    %r8d,%ecx
  sar    %ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L2
L4:
  ret
```

assistant: ```c
void pd001s(n, a, b) int n, *a, *b;
{
  int i;
#pragma omp parallel for
  for (i = 1; i < n; i++)
    b[i] = (a[i] + a[i - 1]) / 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pd001s>:
  endbr64
  cmp    $0x1,%edi
  jle    L17
  movslq %edi,%rdi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L14:
  mov    -0x4(%rsi,%rax,4),%r8d
  add    (%rsi,%rax,4),%r8d
  mov    %r8d,%ecx
  shr    $0x1f,%ecx
  add    %r8d,%ecx
  sar    %ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L14
L17:
  ret
```

assistant: ```c
void pd001s(n, a, b) int n, *a, *b;
{
  int i;
#pragma omp parallel for
  for (i = 1; i < n; i++)
    b[i] = (a[i] + a[i - 1]) / 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pd001s>:
  endbr64
  mov    %rsi,%rcx
  cmp    $0x1,%edi
  jle    L3
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0xc,%rax
  jbe    L6
  lea    -0x2(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L6
  lea    -0x1(%rdi),%r8d
  pxor   %xmm2,%xmm2
  mov    %r8d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  mov    $0x4,%eax
  shl    $0x4,%rsi
  add    $0x14,%rsi
  nopw   0x0(%rax,%rax,1)
L15:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu -0x4(%rcx,%rax,1),%xmm3
  movdqa %xmm2,%xmm1
  paddd  %xmm3,%xmm0
  pcmpgtd %xmm0,%xmm1
  psubd  %xmm1,%xmm0
  psrad  $0x1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L15
  mov    %r8d,%eax
  and    $0xfffffffc,%eax
  lea    0x1(%rax),%r9d
  cmp    %eax,%r8d
  je     L3
  movslq %r9d,%r9
  lea    0x0(,%r9,4),%rsi
  lea    (%rcx,%rsi,1),%r11
  mov    (%r11),%r10d
  add    -0x4(%rcx,%rsi,1),%r10d
  mov    %r10d,%r8d
  shr    $0x1f,%r8d
  add    %r10d,%r8d
  sar    %r8d
  mov    %r8d,(%rdx,%r9,4)
  lea    0x2(%rax),%r8d
  cmp    %r8d,%edi
  jle    L3
  mov    (%r11),%r9d
  add    0x4(%rcx,%rsi,1),%r9d
  add    $0x3,%eax
  mov    %r9d,%r8d
  shr    $0x1f,%r8d
  add    %r9d,%r8d
  sar    %r8d
  mov    %r8d,0x4(%rdx,%rsi,1)
  cmp    %eax,%edi
  jle    L3
  mov    0x8(%rcx,%rsi,1),%eax
  add    0x4(%rcx,%rsi,1),%eax
  mov    %eax,%ecx
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,0x8(%rdx,%rsi,1)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %edi,%edi
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L29:
  mov    -0x4(%rcx,%rax,4),%r8d
  add    (%rcx,%rax,4),%r8d
  mov    %r8d,%esi
  shr    $0x1f,%esi
  add    %r8d,%esi
  sar    %esi
  mov    %esi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L29
L3:
  ret
```

assistant: ```c
void pd001s(n, a, b) int n, *a, *b;
{
  int i;
#pragma omp parallel for
  for (i = 1; i < n; i++)
    b[i] = (a[i] + a[i - 1]) / 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x10000(%rsp),%r11
L58:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L58
  sub    $0x30,%rsp
  mov    %rdi,-0x10018(%rbp)
  mov    %rsi,-0x10020(%rbp)
  mov    %rdx,-0x10028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x10020(%rbp),%rdx
  lea    -0x10010(%rbp),%rax
  mov    $0x10000,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L28
  mov    $0x1,%eax
  jmp    L34
L28:
  mov    -0x10028(%rbp),%rdx
  lea    -0x10010(%rbp),%rcx
  mov    -0x10018(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <split@plt>
  test   %rax,%rax
  je     L7
  mov    $0xffffffff,%eax
  jmp    L34
L7:
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int parse_line(char *parts[64], FILE *fp, size_t parts_count) {
  char line[65536];
  if (fgets(line, sizeof line, fp) == NULL) {
    return 1;
  }
  if (split(parts, line, parts_count) != 0) {
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_line>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  mov    $0x10000,%esi
  call   <fgets@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L28
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <split@plt>
  neg    %rax
  sbb    %eax,%eax
L28:
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_line(char *parts[64], FILE *fp, size_t parts_count) {
  char line[65536];
  if (fgets(line, sizeof line, fp) == NULL) {
    return 1;
  }
  if (split(parts, line, parts_count) != 0) {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,%rbp
  mov    %rdx,%r12
  mov    %r13,%rdi
  mov    %rsi,%rdx
  mov    $0x10000,%esi
  call   <fgets@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L7
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  neg    %rax
  sbb    %eax,%eax
L7:
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_line(char *parts[64], FILE *fp, size_t parts_count) {
  char line[65536];
  if (fgets(line, sizeof line, fp) == NULL) {
    return 1;
  }
  if (split(parts, line, parts_count) != 0) {
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,%rbp
  mov    %rdx,%r12
  mov    %r13,%rdi
  mov    %rsi,%rdx
  mov    $0x10000,%esi
  call   <fgets@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L2
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  neg    %rax
  sbb    %eax,%eax
L2:
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_line(char *parts[64], FILE *fp, size_t parts_count) {
  char line[65536];
  if (fgets(line, sizeof line, fp) == NULL) {
    return 1;
  }
  if (split(parts, line, parts_count) != 0) {
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat_multiply_matrix_i3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  jmp    L28
L16:
  movl   $0x0,-0x34(%rbp)
  jmp    L25
L44:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x58(%rbp),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  imul   %eax,%ecx
  mov    %ecx,%esi
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%edx
  mov    -0x58(%rbp),%rax
  lea    0xc(%rax),%rcx
  mov    -0x34(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,%esi
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    0x8(%rax),%edx
  mov    -0x58(%rbp),%rax
  lea    0x18(%rax),%rcx
  mov    -0x34(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  imul   %edx,%eax
  lea    (%rsi,%rax,1),%ecx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    %ecx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L25:
  cmpl   $0x2,-0x34(%rbp)
  jle    L44
  addl   $0x1,-0x38(%rbp)
L28:
  cmpl   $0x2,-0x38(%rbp)
  jle    L16
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat_copy_matrix_i3@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void mat_multiply_matrix_i3(int m[3][3], int a[3][3], int b[3][3]) {
  int i, j;
  int c[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      c[i][j] = a[i][0] * b[0][j] + a[i][1] * b[1][j] + a[i][2] * b[2][j];
    }
  }
  mat_copy_matrix_i3(m, c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mat_multiply_matrix_i3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r11
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x24(%rsp),%rbp
  jmp    L34
L21:
  add    $0xc,%rsi
  add    $0xc,%rdi
  cmp    %rbp,%rdi
  je     L49
L34:
  mov    (%rsi),%ebx
  mov    0x4(%rsi),%r10d
  mov    0x8(%rsi),%r9d
  mov    $0x0,%eax
L43:
  mov    %ebx,%edx
  imul   (%rcx,%rax,1),%edx
  mov    %r10d,%r8d
  imul   0xc(%rcx,%rax,1),%r8d
  add    %r8d,%edx
  mov    %r9d,%r8d
  imul   0x18(%rcx,%rax,1),%r8d
  add    %r8d,%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L43
  jmp    L21
L49:
  mov    %rsp,%rsi
  mov    %r11,%rdi
  call   <mat_copy_matrix_i3@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat_multiply_matrix_i3(int m[3][3], int a[3][3], int b[3][3]) {
  int i, j;
  int c[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      c[i][j] = a[i][0] * b[0][j] + a[i][1] * b[1][j] + a[i][2] * b[2][j];
    }
  }
  mat_copy_matrix_i3(m, c);
}
```
user: What is the c source code of the assembly code below?

```asm
<mat_multiply_matrix_i3>:
  endbr64
  push   %r12
  mov    %rdi,%r11
  mov    %rdx,%rcx
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x24(%rsp),%rbp
  mov    %r12,%rdi
L6:
  mov    (%rsi),%ebx
  mov    0x4(%rsi),%r10d
  xor    %eax,%eax
  mov    0x8(%rsi),%r9d
L13:
  mov    (%rcx,%rax,1),%edx
  mov    0xc(%rcx,%rax,1),%r8d
  imul   %ebx,%edx
  imul   %r10d,%r8d
  add    %r8d,%edx
  mov    0x18(%rcx,%rax,1),%r8d
  imul   %r9d,%r8d
  add    %r8d,%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L13
  add    $0xc,%rdi
  add    $0xc,%rsi
  cmp    %rdi,%rbp
  jne    L6
  mov    %r12,%rsi
  mov    %r11,%rdi
  call   <mat_copy_matrix_i3@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat_multiply_matrix_i3(int m[3][3], int a[3][3], int b[3][3]) {
  int i, j;
  int c[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      c[i][j] = a[i][0] * b[0][j] + a[i][1] * b[1][j] + a[i][2] * b[2][j];
    }
  }
  mat_copy_matrix_i3(m, c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x16,-0x40(%rbp)
  movl   $0x22,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x20,-0x34(%rbp)
  movl   $0x52,-0x30(%rbp)
  movl   $0x37,-0x2c(%rbp)
  movl   $0x59,-0x28(%rbp)
  movl   $0x32,-0x24(%rbp)
  movl   $0x25,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x40,-0x18(%rbp)
  movl   $0x23,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x46,-0xc(%rbp)
  movl   $0xe,-0x44(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L26
L28:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L26:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string

tool: D8: %d


tool: D11: %d 

assistant: ```c
int main() {
  int arr[] = {22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70};
  int len = (int)sizeof(arr) / sizeof(*arr);
  printf("%d\n", *arr);
  bubble_sort(arr, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x16,(%rsp)
  movl   $0x22,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x20,0xc(%rsp)
  movl   $0x52,0x10(%rsp)
  movl   $0x37,0x14(%rsp)
  movl   $0x59,0x18(%rsp)
  movl   $0x32,0x1c(%rsp)
  movl   $0x25,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  movl   $0x40,0x28(%rsp)
  movl   $0x23,0x2c(%rsp)
  movl   $0x9,0x30(%rsp)
  movl   $0x46,0x34(%rsp)
  mov    $0x16,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <bubble_sort@plt>
  lea    0x38(%rsp),%r12
  lea    D6(%rip),%rbp
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D19: %d


tool: D6: %d 

assistant: ```c
int main() {
  int arr[] = {22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70};
  int len = (int)sizeof(arr) / sizeof(*arr);
  printf("%d\n", *arr);
  bubble_sort(arr, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x16,%esi
  lea    D12(%rip),%rdi
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x2200000016,%rax
  mov    %rsp,%rbx
  lea    0x38(%rsp),%r12
  mov    %rax,(%rsp)
  movabs $0x2000000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x3700000052,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x3200000059,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x500000025,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x2300000040,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x4600000009,%rax
  mov    %rax,0x30(%rsp)
  call   <printf@plt>
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <bubble_sort@plt>
  nop
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D15
type: string

tool: D12: %d


tool: D15: %d 

assistant: ```c
int main() {
  int arr[] = {22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70};
  int len = (int)sizeof(arr) / sizeof(*arr);
  printf("%d\n", *arr);
  bubble_sort(arr, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x16,%esi
  lea    D29(%rip),%rdi
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D59(%rip),%rax
  mov    %rsp,%rbx
  lea    0x38(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D41(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D35(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <printf@plt>
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <bubble_sort@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L1
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D45
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: byte[16]
name: parse_data
arguments: data_label: D59
type_infered: byte[8]
name: parse_data
arguments: data_label: D41
type_infered: byte[16]
name: parse_data
arguments: data_label: D35
type_infered: byte[16]

tool: D29: %d


tool: D45: %d 

tool: {"D14": [0x16,0x00,0x00,0x00,0x22,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x20,0x00,0x00,0x00]}

tool: {"D59": [0x09,0x00,0x00,0x00,0x46,0x00,0x00,0x00]}

tool: {"D41": [0x52,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x59,0x00,0x00,0x00,0x32,0x00,0x00,0x00]}

tool: {"D35": [0x25,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x23,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int arr[] = {22, 34, 3, 32, 82, 55, 89, 50, 37, 5, 64, 35, 9, 70};
  int len = (int)sizeof(arr) / sizeof(*arr);
  printf("%d\n", *arr);
  bubble_sort(arr, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_color_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L9
L13:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <write_color_char_no_space@plt>
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_color_string(int c, const char *str) {
  while (*str)
    write_color_char_no_space(c, *str++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_color_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L4
L17:
  add    $0x1,%rbx
  movsbl %sil,%esi
  mov    %ebp,%edi
  call   <write_color_char_no_space@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L17
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_color_string(int c, const char *str) {
  while (*str)
    write_color_char_no_space(c, *str++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_color_string>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L9
  mov    %edi,%ebp
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rbx
  mov    %ebp,%edi
  call   <write_color_char_no_space@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L17
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_color_string(int c, const char *str) {
  while (*str)
    write_color_char_no_space(c, *str++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<write_color_string>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L13
  mov    %edi,%ebp
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rbx
  mov    %ebp,%edi
  call   <write_color_char_no_space@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L14
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_color_string(int c, const char *str) {
  while (*str)
    write_color_char_no_space(c, *str++);
}
```