ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<RunEncryptionKeySchedule>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rsp,%r13
  lea    0x8(%rsp),%r14
  mov    %rax,(%rsi)
  mov    0x8(%rdi),%rax
  mov    %rax,0x8(%rsi)
  mov    0x10(%rdi),%rax
  mov    %rax,0x10(%rsi)
  mov    0x18(%rdi),%rax
  mov    %rax,0x18(%rsi)
  mov    0x20(%rdi),%rax
  mov    %rax,0x20(%rsi)
  mov    0x28(%rdi),%rax
  mov    %rax,0x28(%rsi)
  movdqu 0x30(%rdi),%xmm0
  movhlps %xmm0,%xmm4
  movq   %xmm4,%rax
  nopl   (%rax)
L16:
  add    %r12,%rax
  movdqu (%rbx),%xmm2
  mov    %r14,%rsi
  mov    %r13,%rdi
  movq   %rax,%xmm1
  add    $0x1,%r12
  add    $0x30,%rbx
  punpcklqdq %xmm1,%xmm0
  movaps %xmm2,(%rsp)
  movups %xmm0,(%rbx)
  call   <speckey@plt>
  movdqa (%rsp),%xmm3
  movq   -0x10(%rbx),%xmm0
  movq   %xmm3,%rax
  add    -0x20(%rbx),%rax
  movups %xmm3,0x10(%rbx)
  mov    %rax,0x20(%rbx)
  mov    0x8(%rsp),%rax
  add    -0x18(%rbx),%rax
  movq   %xmm0,(%rsp)
  mov    %rax,0x28(%rbx)
  mov    -0x8(%rbx),%rax
  cmp    $0x10,%r12
  jne    L16
  add    $0x10,%rax
  movdqu 0x2d0(%rbp),%xmm6
  mov    %r14,%rsi
  mov    %r13,%rdi
  movq   %rax,%xmm5
  punpcklqdq %xmm5,%xmm0
  movaps %xmm6,(%rsp)
  movups %xmm0,0x300(%rbp)
  call   <speckey@plt>
  movdqa (%rsp),%xmm7
  movups %xmm7,0x310(%rbp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RunEncryptionKeySchedule(uint8_t *key, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t temp[2];
  uint16_t *Key = (uint16_t *)key;
  uint16_t *RoundKeys = (uint16_t *)roundKeys;
  RoundKeys[0] = Key[0];
  RoundKeys[1] = Key[1];
  RoundKeys[2] = Key[2];
  RoundKeys[3] = Key[3];
  RoundKeys[4] = Key[4];
  RoundKeys[5] = Key[5];
  temp[0] = Key[6];
  temp[1] = Key[7];
  for (i = 1; i < 2 * 8; i++) {
    RoundKeys[6 * i + 0] = temp[0];
    RoundKeys[6 * i + 1] = temp[1] + i;
    temp[0] = RoundKeys[6 * (i - 1) + 0];
    temp[1] = RoundKeys[6 * (i - 1) + 1];
    speckey(temp, temp + 1);
    RoundKeys[6 * i + 2] = temp[0];
    RoundKeys[6 * i + 3] = temp[1];
    RoundKeys[6 * i + 4] = temp[0] + RoundKeys[6 * (i - 1) + 2];
    RoundKeys[6 * i + 5] = temp[1] + RoundKeys[6 * (i - 1) + 3];
    temp[0] = RoundKeys[6 * (i - 1) + 4];
    temp[1] = RoundKeys[6 * (i - 1) + 5];
  }
  RoundKeys[6 * 2 * 8 + 0] = temp[0];
  RoundKeys[6 * 2 * 8 + 1] = temp[1] + 2 * 8;
  temp[0] = RoundKeys[6 * (2 * 8 - 1) + 0];
  temp[1] = RoundKeys[6 * (2 * 8 - 1) + 1];
  speckey(temp, temp + 1);
  RoundKeys[6 * 2 * 8 + 2] = temp[0];
  RoundKeys[6 * 2 * 8 + 3] = temp[1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_polynomial_subtraction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%ecx
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  lea    D103(%rip),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <check_polynomial_subtraction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x2,%ecx
  lea    D139(%rip),%rax
  mov    %rax,%rdx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <check_polynomial_subtraction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%ecx
  lea    D120(%rip),%rax
  mov    %rax,%rdx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D133(%rip),%rax
  mov    %rax,%rdi
  call   <check_polynomial_subtraction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%ecx
  lea    D63(%rip),%rax
  mov    %rax,%rdx
  lea    D133(%rip),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <check_polynomial_subtraction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%ecx
  lea    D133(%rip),%rax
  mov    %rax,%rdx
  lea    D133(%rip),%rax
  mov    %rax,%rsi
  lea    D133(%rip),%rax
  mov    %rax,%rdi
  call   <check_polynomial_subtraction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D24
type_infered: string
name: unpack_data
arguments: data_label: D103
type_infered: string
name: unpack_data
arguments: data_label: D53
type_infered: string
name: unpack_data
arguments: data_label: D139
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D120
type_infered: string
name: unpack_data
arguments: data_label: D133
type_infered: string
name: unpack_data
arguments: data_label: D63
type_infered: string

tool: D24: x^2+4x-5

tool: D103: x-1

tool: D53: x^2+5x-6

tool: D139: 0.00

tool: D13: 6x^2-6

tool: D120: -6x^2+6

tool: D133: 0

tool: D63: 1

assistant: ```c
int test_polynomial_subtraction() {
  int ret = 0;
  ret += check_polynomial_subtraction("x^2+5x-6", "x-1", "x^2+4x-5", 0);
  ret += check_polynomial_subtraction("6x^2-6", "6x^2-6", "0.00", 2);
  ret += check_polynomial_subtraction("0", "6x^2-6", "-6x^2+6", 0);
  ret += check_polynomial_subtraction("1", "0", "1", 0);
  ret += check_polynomial_subtraction("0", "0", "0", 0);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_polynomial_subtraction>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  lea    D8(%rip),%rdx
  lea    D71(%rip),%rsi
  lea    D72(%rip),%rdi
  call   <check_polynomial_subtraction@plt>
  mov    %rax,%rbx
  mov    $0x2,%ecx
  lea    D67(%rip),%rdx
  lea    D54(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <check_polynomial_subtraction@plt>
  add    %eax,%ebx
  mov    $0x0,%ecx
  lea    D39(%rip),%rdx
  mov    %rbp,%rsi
  lea    D73(%rip),%rbp
  mov    %rbp,%rdi
  call   <check_polynomial_subtraction@plt>
  add    %eax,%ebx
  mov    $0x0,%ecx
  lea    D13(%rip),%rdi
  mov    %rdi,%rdx
  mov    %rbp,%rsi
  call   <check_polynomial_subtraction@plt>
  add    %eax,%ebx
  mov    $0x0,%ecx
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <check_polynomial_subtraction@plt>
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D71
datatype: string
name: disassemble_data
arguments: tag: D72
datatype: string
name: disassemble_data
arguments: tag: D67
datatype: string
name: disassemble_data
arguments: tag: D54
datatype: string
name: disassemble_data
arguments: tag: D39
datatype: string
name: disassemble_data
arguments: tag: D73
datatype: string
name: disassemble_data
arguments: tag: D13
datatype: string

tool: D8: x^2+4x-5

tool: D71: x-1

tool: D72: x^2+5x-6

tool: D67: 0.00

tool: D54: 6x^2-6

tool: D39: -6x^2+6

tool: D73: 0

tool: D13: 1

assistant: ```c
int test_polynomial_subtraction() {
  int ret = 0;
  ret += check_polynomial_subtraction("x^2+5x-6", "x-1", "x^2+4x-5", 0);
  ret += check_polynomial_subtraction("6x^2-6", "6x^2-6", "0.00", 2);
  ret += check_polynomial_subtraction("0", "6x^2-6", "-6x^2+6", 0);
  ret += check_polynomial_subtraction("1", "0", "1", 0);
  ret += check_polynomial_subtraction("0", "0", "0", 0);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_polynomial_subtraction>:
  endbr64
  push   %rbp
  xor    %ecx,%ecx
  lea    D55(%rip),%rbp
  lea    D39(%rip),%rdx
  push   %rbx
  lea    D2(%rip),%rsi
  lea    D21(%rip),%rdi
  sub    $0x8,%rsp
  call   <check_polynomial_subtraction@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  lea    D56(%rip),%rdx
  mov    %rax,%rbx
  call   <check_polynomial_subtraction@plt>
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  lea    D41(%rip),%rbp
  mov    %rbp,%rdi
  lea    D35(%rip),%rdx
  add    %eax,%ebx
  call   <check_polynomial_subtraction@plt>
  lea    D0(%rip),%rdi
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    %rdi,%rdx
  add    %eax,%ebx
  call   <check_polynomial_subtraction@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  add    %eax,%ebx
  call   <check_polynomial_subtraction@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D55
data_type: string
name: retrieve_data
arguments: data_label: D39
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D56
data_type: string
name: retrieve_data
arguments: data_label: D41
data_type: string
name: retrieve_data
arguments: data_label: D35
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D55: 6x^2-6

tool: D39: x^2+4x-5

tool: D2: x-1

tool: D21: x^2+5x-6

tool: D56: 0.00

tool: D41: 0

tool: D35: -6x^2+6

tool: D0: 1

assistant: ```c
int test_polynomial_subtraction() {
  int ret = 0;
  ret += check_polynomial_subtraction("x^2+5x-6", "x-1", "x^2+4x-5", 0);
  ret += check_polynomial_subtraction("6x^2-6", "6x^2-6", "0.00", 2);
  ret += check_polynomial_subtraction("0", "6x^2-6", "-6x^2+6", 0);
  ret += check_polynomial_subtraction("1", "0", "1", 0);
  ret += check_polynomial_subtraction("0", "0", "0", 0);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_polynomial_subtraction>:
  endbr64
  push   %rbp
  xor    %ecx,%ecx
  lea    D25(%rip),%rbp
  lea    D40(%rip),%rdx
  push   %rbx
  lea    D29(%rip),%rsi
  lea    D50(%rip),%rdi
  sub    $0x8,%rsp
  call   <check_polynomial_subtraction@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  lea    D46(%rip),%rdx
  mov    %rax,%rbx
  call   <check_polynomial_subtraction@plt>
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  lea    D28(%rip),%rbp
  mov    %rbp,%rdi
  lea    D67(%rip),%rdx
  add    %eax,%ebx
  call   <check_polynomial_subtraction@plt>
  lea    D63(%rip),%rdi
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    %rdi,%rdx
  add    %eax,%ebx
  call   <check_polynomial_subtraction@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  add    %eax,%ebx
  call   <check_polynomial_subtraction@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
data_type: string
name: retrieve_data
arguments: tag: D40
data_type: string
name: retrieve_data
arguments: tag: D29
data_type: string
name: retrieve_data
arguments: tag: D50
data_type: string
name: retrieve_data
arguments: tag: D46
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D67
data_type: string
name: retrieve_data
arguments: tag: D63
data_type: string

tool: D25: 6x^2-6

tool: D40: x^2+4x-5

tool: D29: x-1

tool: D50: x^2+5x-6

tool: D46: 0.00

tool: D28: 0

tool: D67: -6x^2+6

tool: D63: 1

assistant: ```c
int test_polynomial_subtraction() {
  int ret = 0;
  ret += check_polynomial_subtraction("x^2+5x-6", "x-1", "x^2+4x-5", 0);
  ret += check_polynomial_subtraction("6x^2-6", "6x^2-6", "0.00", 2);
  ret += check_polynomial_subtraction("0", "6x^2-6", "-6x^2+6", 0);
  ret += check_polynomial_subtraction("1", "0", "1", 0);
  ret += check_polynomial_subtraction("0", "0", "0", 0);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_number_of_runs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  js     L7
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L14
L7:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L14:
  divss  -0x1c(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <ceil@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
int32_t get_number_of_runs(unsigned long file_length, const int32_t AVAILABLE_MEMORY) {
  int32_t number_of_runs = ceil((float)file_length / AVAILABLE_MEMORY);
  return number_of_runs;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_number_of_runs>:
  endbr64
  sub    $0x8,%rsp
  movaps %xmm0,%xmm1
  test   %rdi,%rdi
  js     L15
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdi,%xmm0
L13:
  divss  %xmm1,%xmm0
  call   <ceil@plt>
  add    $0x8,%rsp
  ret
L15:
  mov    %rdi,%rax
  shr    %rax
  and    $0x1,%edi
  or     %rdi,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm0
  jmp    L13
```

assistant: ```c
int32_t get_number_of_runs(unsigned long file_length, const int32_t AVAILABLE_MEMORY) {
  int32_t number_of_runs = ceil((float)file_length / AVAILABLE_MEMORY);
  return number_of_runs;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_number_of_runs>:
  endbr64
  movaps %xmm0,%xmm1
  test   %rdi,%rdi
  js     L7
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdi,%xmm0
  divss  %xmm1,%xmm0
  jmp    1050 <ceil@plt>
  xchg   %ax,%ax
L7:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm0
  divss  %xmm1,%xmm0
  jmp    1050 <ceil@plt>
```

assistant: ```c
int32_t get_number_of_runs(unsigned long file_length, const int32_t AVAILABLE_MEMORY) {
  int32_t number_of_runs = ceil((float)file_length / AVAILABLE_MEMORY);
  return number_of_runs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_number_of_runs>:
  endbr64
  movaps %xmm0,%xmm1
  test   %rdi,%rdi
  js     L5
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdi,%xmm0
  divss  %xmm1,%xmm0
  jmp    1050 <ceil@plt>
  xchg   %ax,%ax
L5:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm0
  divss  %xmm1,%xmm0
  jmp    1050 <ceil@plt>
```

assistant: ```c
int32_t get_number_of_runs(unsigned long file_length, const int32_t AVAILABLE_MEMORY) {
  int32_t number_of_runs = ceil((float)file_length / AVAILABLE_MEMORY);
  return number_of_runs;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x9,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: Hola Zynq


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hola Zynq\n");
  return 9;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: Hola Zynq


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hola Zynq\n");
  return 9;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: Hola Zynq


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hola Zynq\n");
  return 9;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: Hola Zynq


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hola Zynq\n");
  return 9;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  cltq
  or     %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movzbl %al,%eax
  cltq
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long decode_size(char **str) {
  unsigned char **ustr = (unsigned char **)str;
  unsigned long size = (*((*ustr)++) & 0xff) << 16;
  size |= (*((*ustr)++) & 0xff) << 8;
  size |= (*((*ustr)++) & 0xff);
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode_size>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%ecx
  shl    $0x10,%ecx
  lea    0x2(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rax),%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  movslq %edx,%rdx
  lea    0x3(%rax),%rcx
  mov    %rcx,(%rdi)
  movzbl 0x2(%rax),%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long decode_size(char **str) {
  unsigned char **ustr = (unsigned char **)str;
  unsigned long size = (*((*ustr)++) & 0xff) << 16;
  size |= (*((*ustr)++) & 0xff) << 8;
  size |= (*((*ustr)++) & 0xff);
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_size>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  lea    0x2(%rax),%rdx
  movzbl (%rax),%ecx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rax),%edx
  shl    $0x10,%ecx
  shl    $0x8,%edx
  or     %ecx,%edx
  lea    0x3(%rax),%rcx
  mov    %rcx,(%rdi)
  movzbl 0x2(%rax),%eax
  movslq %edx,%rdx
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long decode_size(char **str) {
  unsigned char **ustr = (unsigned char **)str;
  unsigned long size = (*((*ustr)++) & 0xff) << 16;
  size |= (*((*ustr)++) & 0xff) << 8;
  size |= (*((*ustr)++) & 0xff);
  return size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_size>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  lea    0x2(%rax),%rdx
  movzbl (%rax),%ecx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rax),%edx
  shl    $0x10,%ecx
  shl    $0x8,%edx
  or     %ecx,%edx
  lea    0x3(%rax),%rcx
  mov    %rcx,(%rdi)
  movzbl 0x2(%rax),%eax
  movslq %edx,%rdx
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long decode_size(char **str) {
  unsigned char **ustr = (unsigned char **)str;
  unsigned long size = (*((*ustr)++) & 0xff) << 16;
  size |= (*((*ustr)++) & 0xff) << 8;
  size |= (*((*ustr)++) & 0xff);
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<utarray_str_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L19
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L3
L19:
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L3:
  nop
  leave
  ret
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src != NULL) {
    *_dst = (char *)malloc(strlen(*_src) + 1);
    memcpy(*_dst, *_src, strlen(*_src) + 1);
  } else {
    *_dst = NULL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<utarray_str_cpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L15
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  movq   $0x0,0x0(%rbp)
  jmp    L6
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src != NULL) {
    *_dst = (char *)malloc(strlen(*_src) + 1);
    memcpy(*_dst, *_src, strlen(*_src) + 1);
  } else {
    *_dst = NULL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utarray_str_cpy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rbp
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  lea    0x1(%rax),%rdx
  pop    %r12
  jmp    1080 <memcpy@plt>
  nopl   0x0(%rax)
L8:
  movq   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src != NULL) {
    *_dst = (char *)malloc(strlen(*_src) + 1);
    memcpy(*_dst, *_src, strlen(*_src) + 1);
  } else {
    *_dst = NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utarray_str_cpy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L2
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rbp
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  lea    0x1(%rax),%rdx
  pop    %r12
  jmp    1080 <memcpy@plt>
  nopl   0x0(%rax)
L2:
  movq   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src != NULL) {
    *_dst = (char *)malloc(strlen(*_src) + 1);
    memcpy(*_dst, *_src, strlen(*_src) + 1);
  } else {
    *_dst = NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<textureRemoveAlphaChannel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L21
L10:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  and    $0x3,%eax
  test   %rax,%rax
  je     L29
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L29:
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void textureRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0;
  for (i = 0; i < srcsize; i++) {
    if ((i + 1) % 4 != 0) {
      bufdest[j] = bufsrc[i];
      ++j;
    }
  }
}
```