ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<gsm0710_open_channel>:
  endbr64
  lea    -0x1(%rsi),%eax
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  cmp    $0x3e,%eax
  jbe    L1
L5:
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L1:
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x1,%r13d
  call   <is_channel_used@plt>
  test   %rax,%rax
  jne    L5
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <mark_channel_used@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x3f,%edx
  call   <gsm0710_write_frame@plt>
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int gsm0710_open_channel(struct gsm0710_context *ctx, int channel) {
  if (channel <= 0 || channel > 63)
    return 0;
  if (is_channel_used(ctx, channel))
    return 1;
  mark_channel_used(ctx, channel);
  gsm0710_write_frame(ctx, channel, 0x3F, 0, 0);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gsm0710_open_channel>:
  endbr64
  lea    -0x1(%rsi),%eax
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  cmp    $0x3e,%eax
  jbe    L14
L10:
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x1,%r13d
  call   <is_channel_used@plt>
  test   %rax,%rax
  jne    L10
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <mark_channel_used@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x3f,%edx
  call   <gsm0710_write_frame@plt>
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int gsm0710_open_channel(struct gsm0710_context *ctx, int channel) {
  if (channel <= 0 || channel > 63)
    return 0;
  if (is_channel_used(ctx, channel))
    return 1;
  mark_channel_used(ctx, channel);
  gsm0710_write_frame(ctx, channel, 0x3F, 0, 0);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<murmur_fmix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0xd,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0xc2b2ae35,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t murmur_fmix(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<murmur_fmix>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t murmur_fmix(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<murmur_fmix>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t murmur_fmix(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<murmur_fmix>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t murmur_fmix(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generic_LP_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: No linear programming kit detected


assistant: ```c
int generic_LP_C(int rows, int cols, double *obj, double *A, int model_opt_sense, double *rhs, char *constr_sense, double *Q, double *lb, double *ub, double *objval, double *sol_mat_X, double *sol_mat_RC, double *dual_mat_PI, double *dual_mat_SLACK) {
  int success = 0;
  printf("No linear programming kit detected\n");
  success = 0;
  return success;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generic_LP_C>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: No linear programming kit detected


assistant: ```c
int generic_LP_C(int rows, int cols, double *obj, double *A, int model_opt_sense, double *rhs, char *constr_sense, double *Q, double *lb, double *ub, double *objval, double *sol_mat_X, double *sol_mat_RC, double *dual_mat_PI, double *dual_mat_SLACK) {
  int success = 0;
  printf("No linear programming kit detected\n");
  success = 0;
  return success;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generic_LP_C>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2: No linear programming kit detected


assistant: ```c
int generic_LP_C(int rows, int cols, double *obj, double *A, int model_opt_sense, double *rhs, char *constr_sense, double *Q, double *lb, double *ub, double *objval, double *sol_mat_X, double *sol_mat_RC, double *dual_mat_PI, double *dual_mat_SLACK) {
  int success = 0;
  printf("No linear programming kit detected\n");
  success = 0;
  return success;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generic_LP_C>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: No linear programming kit detected


assistant: ```c
int generic_LP_C(int rows, int cols, double *obj, double *A, int model_opt_sense, double *rhs, char *constr_sense, double *Q, double *lb, double *ub, double *objval, double *sol_mat_X, double *sol_mat_RC, double *dual_mat_PI, double *dual_mat_SLACK) {
  int success = 0;
  printf("No linear programming kit detected\n");
  success = 0;
  return success;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L41
  lea    D41(%rip),%rbp
  jmp    L55
L61:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L42:
  mov    %r13d,0x4(%rsp)
  test   %r13d,%r13d
  je     L41
L24:
  movslq %ebx,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %esi,%r13d
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  mov    %ebx,%esi
  sub    %eax,%esi
  mov    %ebx,%eax
  mov    %r13d,%ebx
  cmp    $0x9,%eax
  jg     L61
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L42
L71:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L41
L55:
  test   %ebx,%ebx
  jns    L71
  neg    %ebx
  mov    %ebx,0x4(%rsp)
  lea    D41(%rip),%r12
  lea    D16(%rip),%rbp
  jmp    L24
L41:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D53
data_type: string
name: extract_symbolic_data
arguments: tag: D42
data_type: string
name: extract_symbolic_data
arguments: tag: D41
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string

tool: D53: 
Enter an integer > 

tool: D42: %d

tool: D41: 
%d

tool: D16: 
-%d

tool: D10: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n) {
    if (n < 0) {
      n = -n;
      while (n) {
        r = n % 10;
        nn = n / 10;
        if (n < 10) {
          printf("\n-%d", r);
        } else if (n >= 10) {
          printf("\n%d", r);
        }
        n = nn;
      }
    } else {
      r = n % 10;
      nn = n / 10;
      n = nn;
      printf("\n%d", r);
    }
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D41(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r14d
  test   %r14d,%r14d
  je     L73
  lea    D35(%rip),%rbx
  jmp    L41
  nopl   0x0(%rax)
L31:
  movslq %r14d,%rax
  mov    %r14d,%edx
  mov    %r14d,%esi
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%r14d
  test   %r14d,%r14d
  je     L73
L41:
  test   %r14d,%r14d
  jns    L31
  neg    %r14d
  mov    $0xcccccccd,%ebp
  lea    D35(%rip),%r13
  mov    %r14d,0x4(%rsp)
  lea    D39(%rip),%r12
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  je     L73
L51:
  mov    %r14d,%ebx
  mov    %r14d,%esi
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %r14d,%eax
  mov    %ebx,%r14d
  cmp    $0x9,%eax
  jle    L36
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  jne    L51
L73:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D41
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D35
type: string
name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D41: 
Enter an integer > 

tool: D23: %d

tool: D35: 
%d

tool: D39: 
-%d

tool: D15: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n) {
    if (n < 0) {
      n = -n;
      while (n) {
        r = n % 10;
        nn = n / 10;
        if (n < 10) {
          printf("\n-%d", r);
        } else if (n >= 10) {
          printf("\n%d", r);
        }
        n = nn;
      }
    } else {
      r = n % 10;
      nn = n / 10;
      n = nn;
      printf("\n%d", r);
    }
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L69
  lea    D12(%rip),%rbx
  jmp    L36
L17:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L69
L36:
  test   %esi,%esi
  jns    L17
  neg    %esi
  mov    $0xcccccccd,%ebp
  lea    D12(%rip),%r13
  mov    %esi,0x4(%rsp)
  lea    D29(%rip),%r12
  jmp    L43
  nopl   0x0(%rax)
L16:
  mov    %ebx,%esi
L43:
  mov    %esi,%ebx
  mov    %esi,%r8d
  mov    %r12,%rdi
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%r8d
  cmp    $0x9,%esi
  mov    %r8d,%esi
  jle    L22
  mov    %r13,%rdi
L22:
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  jne    L16
L69:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D50
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D29
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string

tool: D16: 
Enter an integer > 

tool: D50: %d

tool: D12: 
%d

tool: D29: 
-%d

tool: D18: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n) {
    if (n < 0) {
      n = -n;
      while (n) {
        r = n % 10;
        nn = n / 10;
        if (n < 10) {
          printf("\n-%d", r);
        } else if (n >= 10) {
          printf("\n%d", r);
        }
        n = nn;
      }
    } else {
      r = n % 10;
      nn = n / 10;
      n = nn;
      printf("\n%d", r);
    }
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x8,%eax
  mov    %al,-0xb(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x10,%eax
  mov    %al,-0xa(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x18,%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    $0x4,%eax
  je     L8
  mov    $0xffffffff,%eax
  jmp    L29
L8:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int write_int(FILE *out, unsigned int n) {
  unsigned char buffer[4];
  buffer[0] = n;
  buffer[1] = n >> 8;
  buffer[2] = n >> 16;
  buffer[3] = n >> 24;
  if (fwrite(buffer, 1, 4, out) != 4)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %sil,0x4(%rsp)
  movzbl %ah,%edx
  mov    %dl,0x5(%rsp)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x6(%rsp)
  shr    $0x18,%eax
  mov    %al,0x7(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    $0x4,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_int(FILE *out, unsigned int n) {
  unsigned char buffer[4];
  buffer[0] = n;
  buffer[1] = n >> 8;
  buffer[2] = n >> 16;
  buffer[3] = n >> 24;
  if (fwrite(buffer, 1, 4, out) != 4)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    %esi,0x4(%rsp)
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    $0x4,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_int(FILE *out, unsigned int n) {
  unsigned char buffer[4];
  buffer[0] = n;
  buffer[1] = n >> 8;
  buffer[2] = n >> 16;
  buffer[3] = n >> 24;
  if (fwrite(buffer, 1, 4, out) != 4)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    %esi,0x4(%rsp)
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    $0x4,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_int(FILE *out, unsigned int n) {
  unsigned char buffer[4];
  buffer[0] = n;
  buffer[1] = n >> 8;
  buffer[2] = n >> 16;
  buffer[3] = n >> 24;
  if (fwrite(buffer, 1, 4, out) != 4)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D63
type_guessed: string
name: read_data
arguments: tag: D75
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D62
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D88
type_guessed: string
name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string

tool: D63: Enter any number: 

tool: D75: %d

tool: D10: Enter another number: 

tool: D62: x + y = %d


tool: D12: x - y = %d


tool: D88: x * y = %d


tool: D11: x / y = %d


tool: D15: x %% y = %d


assistant: ```c
int main() {
  int x;
  int y;
  int sum;
  int difference;
  int product;
  int quotient;
  int modulus;
  printf("Enter any number: ");
  scanf("%d", &x);
  printf("Enter another number: ");
  scanf("%d", &y);
  sum = x + y;
  difference = x - y;
  product = x * y;
  quotient = x / y;
  modulus = x % y;
  printf("x + y = %d\n", sum);
  printf("x - y = %d\n", difference);
  printf("x * y = %d\n", product);
  printf("x / y = %d\n", quotient);
  printf("x %% y = %d\n", modulus);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D40(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%ebp
  lea    (%rbx,%rbp,1),%esi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  sub    %ebp,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  imul   %ebp,%esi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %edx,%ebx
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D75(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string
name: retrieve_data
arguments: tag: D44
type_infered: string
name: retrieve_data
arguments: tag: D58
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D50
type_infered: string
name: retrieve_data
arguments: tag: D15
type_infered: string
name: retrieve_data
arguments: tag: D75
type_infered: string

tool: D7: Enter any number: 

tool: D40: %d

tool: D44: Enter another number: 

tool: D58: x + y = %d


tool: D13: x - y = %d


tool: D50: x * y = %d


tool: D15: x / y = %d


tool: D75: x %% y = %d


assistant: ```c
int main() {
  int x;
  int y;
  int sum;
  int difference;
  int product;
  int quotient;
  int modulus;
  printf("Enter any number: ");
  scanf("%d", &x);
  printf("Enter another number: ");
  scanf("%d", &y);
  sum = x + y;
  difference = x - y;
  product = x * y;
  quotient = x / y;
  modulus = x % y;
  printf("x + y = %d\n", sum);
  printf("x - y = %d\n", difference);
  printf("x * y = %d\n", product);
  printf("x / y = %d\n", quotient);
  printf("x %% y = %d\n", modulus);
  return 0;
}
```