ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<check_dir>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x428,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%rbp
  mov    $0x400,%edx
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L32
  movslq %eax,%r9
  xor    %edx,%edx
  xor    %edi,%edi
  xor    %r13d,%r13d
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L65:
  cmp    $0x20,%edi
  je     L48
  movslq %r13d,%rsi
  movslq %edi,%r8
  add    $0x1,%edi
  shl    $0x5,%rsi
  add    $0x420,%rsi
  add    %rsp,%rsi
  mov    %cl,-0x410(%r8,%rsi,1)
L15:
  add    $0x1,%rdx
  cmp    %rdx,%r9
  je     L39
L4:
  movzbl (%r12,%rdx,1),%ecx
  cmp    $0x5c,%cl
  je     L36
  cmp    $0x2f,%cl
  je     L36
  cmp    $0x2e,%cl
  jne    L65
  lea    0x1(%rdx),%esi
  cmp    %eax,%esi
  jge    L65
  cmpb   $0x2e,0x1(%r12,%rdx,1)
  je     L65
  test   %edx,%edx
  je     L65
  cmpb   $0x2e,-0x1(%r12,%rdx,1)
  je     L65
L39:
  xor    %r12d,%r12d
  xor    %r15d,%r15d
L112:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdi
  mov    %rbp,%rsi
  mov    %eax,%r14d
  add    %rbx,%rdi
  mov    %eax,%edx
  call   <memcpy@plt>
  add    %r14d,%r12d
  mov    %rbx,%rdi
  mov    %r12d,%esi
  call   <check_and_create_dir_@plt>
  cmp    $0x1,%eax
  jbe    L71
L59:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L36:
  add    $0x1,%r13d
  xor    %edi,%edi
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x2,%eax
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L71:
  cmp    %r15d,%r13d
  jle    L148
  movslq %r12d,%rax
  add    $0x1,%r12d
  movb   $0x2f,(%rbx,%rax,1)
L148:
  add    $0x1,%r15d
  add    $0x20,%rbp
  cmp    %r13d,%r15d
  jle    L112
  mov    0x8(%rsp),%rax
  mov    %r12d,(%rax)
  xor    %eax,%eax
  jmp    L59
L32:
  xor    %r13d,%r13d
  jmp    L39
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_dir(const char *path, char *basepath, int *sz) {
  char dir[32][32];
  memset(dir, 0, 32 * 32);
  int len = strlen(path);
  int i = 0, j = 0, k = 0;
  for (; i < len; i++) {
    char t = path[i];
    if (t == '\\' || t == '/') {
      j++;
      k = 0;
      continue;
    }
    if (t == '.') {
      if (i + 1 < len) {
        char n1 = path[i + 1];
        if (n1 != '.') {
          if (i > 0) {
            char n2 = path[i - 1];
            if (n2 != '.')
              break;
          }
        }
      }
    }
    if (k >= 32) {
      return 2;
    }
    dir[j][k++] = t;
  }
  for (i = 0, k = 0; i <= j; i++) {
    len = strlen(dir[i]);
    memcpy(basepath + k, dir[i], len);
    k += len;
    int err = check_and_create_dir_(basepath, k);
    if (err == 0 || err == 1) {
      if (i < j)
        basepath[k++] = '/';
      continue;
    }
    return err;
  }
  *sz = k;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fPrintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x3c(%rbp)
  jle    L69
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L79:
  cmp    %rdx,%rsp
  je     L3
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L3:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L45
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L45:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L14
L12:
  mov    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  movb   $0x20,(%rdx,%rax,1)
  addl   $0x1,-0x2c(%rbp)
L14:
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L12
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  mov    -0x20(%rbp),%rdx
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rsp
  jmp    L67
L69:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L67:
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string

tool: D2: %s + 

tool: D10:  + 

assistant: ```c
void fPrintSpaces(FILE *file, int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    fprintf(file, "%s + ", string);
  } else {
    fprintf(file, " + ");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fPrintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L52
  mov    %rsp,%rbx
  add    %esi,%esi
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L2:
  cmp    %rdx,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L33:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L44
  orq    $0x0,-0x8(%rsp,%rax,1)
L44:
  mov    %rsp,%rcx
  mov    %rsp,%rax
  mov    %esi,%edx
  add    %rsp,%rdx
L25:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L25
  movslq %esi,%rsi
  movb   $0x0,(%rcx,%rsi,1)
  mov    %rcx,%rdx
  lea    D18(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rsp
L12:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    -0x8(%rbp),%rbx
  leave
  ret
L52:
  mov    %rdi,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  call   <fwrite@plt>
  jmp    L12
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D18: %s + 

tool: D19:  + 

assistant: ```c
void fPrintSpaces(FILE *file, int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    fprintf(file, "%s + ", string);
  } else {
    fprintf(file, " + ");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fPrintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L47
  add    %esi,%esi
  mov    %rsp,%rcx
  mov    %rsp,%r13
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L16
L44:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L44
L16:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L1
L28:
  movslq %esi,%rbx
  mov    %rsp,%rdi
  mov    $0x20,%esi
  mov    %rbx,%rdx
  call   <memset@plt>
  movb   $0x0,(%rsp,%rbx,1)
  mov    %rsp,%rdx
  mov    %r12,%rdi
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r13,%rsp
L5:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L47:
  mov    %rdi,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <fwrite@plt>
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L1:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L28
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D6
data_type: string

tool: D19: %s + 

tool: D6:  + 

assistant: ```c
void fPrintSpaces(FILE *file, int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    fprintf(file, "%s + ", string);
  } else {
    fprintf(file, " + ");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fPrintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L25
  add    %esi,%esi
  mov    %rsp,%rcx
  mov    %rsp,%r13
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L51
L48:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L48
L51:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L64
L47:
  movslq %esi,%rbx
  mov    %rsp,%rdi
  mov    $0x20,%esi
  mov    %rbx,%rdx
  call   <memset@plt>
  movb   $0x0,(%rsp,%rbx,1)
  mov    %rsp,%rdx
  mov    %r12,%rdi
  lea    D14(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r13,%rsp
L52:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L25:
  mov    %rdi,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  call   <fwrite@plt>
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L64:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L47
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string

tool: D14: %s + 

tool: D13:  + 

assistant: ```c
void fPrintSpaces(FILE *file, int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    fprintf(file, "%s + ", string);
  } else {
    fprintf(file, " + ");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<y2uyvy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,%r12d
  mov    -0x38(%rbp),%rax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,%ebx
  jmp    L10
L1:
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%r14d
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%r13d
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x80,(%rax)
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %r14d,%edx
  mov    %dl,(%rax)
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x80,(%rax)
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %r13d,%edx
  mov    %dl,(%rax)
L10:
  test   %r12d,%r12d
  jg     L1
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
void y2uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels) {
  register int i = NumPixels - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y0 = src[i--];
    dest[j--] = 128;
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<y2uyvy>:
  endbr64
  lea    -0x1(%rdx),%eax
  lea    -0x1(%rdx,%rdx,1),%edx
  test   %eax,%eax
  jle    L12
  cltq
  movslq %edx,%rdx
  add    %rdx,%rsi
L19:
  movzbl (%rdi,%rax,1),%ecx
  movzbl -0x1(%rdi,%rax,1),%edx
  movb   $0x80,(%rsi)
  mov    %cl,-0x1(%rsi)
  movb   $0x80,-0x2(%rsi)
  mov    %dl,-0x3(%rsi)
  sub    $0x2,%rax
  sub    $0x4,%rsi
  test   %eax,%eax
  jg     L19
L12:
  ret
```

assistant: ```c
void y2uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels) {
  register int i = NumPixels - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y0 = src[i--];
    dest[j--] = 128;
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<y2uyvy>:
  endbr64
  lea    -0x1(%rdx),%eax
  lea    -0x1(%rdx,%rdx,1),%edx
  test   %eax,%eax
  jle    L17
  movslq %edx,%rdx
  cltq
  add    %rdx,%rsi
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%rdi,%rax,1),%ecx
  movzbl -0x1(%rdi,%rax,1),%edx
  sub    $0x2,%rax
  movb   $0x80,(%rsi)
  movb   $0x80,-0x2(%rsi)
  sub    $0x4,%rsi
  mov    %cl,0x3(%rsi)
  mov    %dl,0x1(%rsi)
  test   %eax,%eax
  jg     L16
L17:
  ret
```

assistant: ```c
void y2uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels) {
  register int i = NumPixels - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y0 = src[i--];
    dest[j--] = 128;
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<y2uyvy>:
  endbr64
  lea    -0x1(%rdx),%eax
  lea    -0x1(%rdx,%rdx,1),%edx
  test   %eax,%eax
  jle    L9
  movslq %edx,%rdx
  cltq
  add    %rdx,%rsi
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl (%rdi,%rax,1),%ecx
  movzbl -0x1(%rdi,%rax,1),%edx
  sub    $0x2,%rax
  movb   $0x80,(%rsi)
  movb   $0x80,-0x2(%rsi)
  sub    $0x4,%rsi
  mov    %cl,0x3(%rsi)
  mov    %dl,0x1(%rsi)
  test   %eax,%eax
  jg     L10
L9:
  ret
```

assistant: ```c
void y2uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels) {
  register int i = NumPixels - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y0 = src[i--];
    dest[j--] = 128;
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<shipnewer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    (%rbx),%rax
  test   %rax,%rax
  je     L69
  mov    (%rbx),%rax
  lea    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L88
L69:
  mov    $0x1,%eax
  jmp    L64
L88:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L47
L87:
  mov    (%rbx),%rax
  lea    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x28(%rbp),%rax
  cmp    %rax,-0x20(%rbp)
  jae    L47
L8:
  mov    $0x1,%eax
  jmp    L64
L47:
  add    $0x8,%rbx
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L87
  mov    $0x0,%eax
L64:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int shipnewer(register char **argv) {
  unsigned long ref;
  struct stat st;
  if (!*argv || stat(*argv, &st))
    return (1);
  ref = (unsigned long)st.st_mtime;
  while (*++argv)
    if (stat(*argv, &st) || ref < (unsigned long)st.st_mtime)
      return (1);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<shipnewer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L66
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L66
  mov    (%rsp),%r12
  mov    %rsp,%rbp
L36:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L65
  mov    %rbp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L56
  cmp    %r12,(%rsp)
  jbe    L36
  mov    $0x1,%eax
  jmp    L66
L65:
  mov    $0x0,%eax
L66:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L73
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  mov    $0x1,%eax
  jmp    L66
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int shipnewer(register char **argv) {
  unsigned long ref;
  struct stat st;
  if (!*argv || stat(*argv, &st))
    return (1);
  ref = (unsigned long)st.st_mtime;
  while (*++argv)
    if (stat(*argv, &st) || ref < (unsigned long)st.st_mtime)
      return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shipnewer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L30
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <stat@plt>
  mov    (%rsp),%r12
  test   %rax,%rax
  je     L53
L30:
  mov    $0x1,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    %rbp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L30
  cmp    %r12,(%rsp)
  ja     L30
L53:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L17
  xor    %eax,%eax
  jmp    L2
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int shipnewer(register char **argv) {
  unsigned long ref;
  struct stat st;
  if (!*argv || stat(*argv, &st))
    return (1);
  ref = (unsigned long)st.st_mtime;
  while (*++argv)
    if (stat(*argv, &st) || ref < (unsigned long)st.st_mtime)
      return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shipnewer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L55
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <stat@plt>
  mov    (%rsp),%r12
  test   %rax,%rax
  je     L49
L55:
  mov    $0x1,%eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    %rbp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L55
  cmp    %r12,(%rsp)
  ja     L55
L49:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L14
  xor    %eax,%eax
  jmp    L48
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int shipnewer(register char **argv) {
  unsigned long ref;
  struct stat st;
  if (!*argv || stat(*argv, &st))
    return (1);
  ref = (unsigned long)st.st_mtime;
  while (*++argv)
    if (stat(*argv, &st) || ref < (unsigned long)st.st_mtime)
      return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getFileExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L78
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  cmp    %rax,-0x10(%rbp)
  jae    L54
L78:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <scalloc@plt>
  jmp    L21
L54:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <smalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  jmp    L65
L56:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L15
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L15
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x1a,%eax
  mov    %eax,%edx
  jmp    L53
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
L53:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,-0x14(%rbp)
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L65:
  cmpl   $0x0,-0x14(%rbp)
  jns    L56
  mov    -0x8(%rbp),%rax
L21:
  leave
  ret
```

assistant: ```c
char *getFileExt(char *path) {
  char *ext, *point = strrchr(path, '.');
  int extLen;
  if (!point || point < strrchr(path, '/'))
    return scalloc(1, 1);
  point++;
  ext = smalloc((extLen = strlen(point)) + 1);
  ext[extLen] = 0;
  for (point += --extLen; extLen >= 0; point--)
    ext[extLen--] = ('A' <= *point && *point <= 'Z') ? ((*point) - 26) : *point;
  return ext;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getFileExt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L44
  mov    %rax,%rbx
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  cmp    %rax,%rbx
  jae    L13
L44:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <scalloc@plt>
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  lea    0x1(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <smalloc@plt>
  movslq %ebp,%rdx
  movb   $0x0,(%rax,%rdx,1)
  sub    $0x1,%ebp
  movslq %ebp,%rcx
  js     L10
L43:
  movzbl 0x1(%rbx,%rcx,1),%edx
  lea    -0x41(%rdx),%edi
  lea    -0x1a(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jns    L43
  jmp    L10
```

assistant: ```c
char *getFileExt(char *path) {
  char *ext, *point = strrchr(path, '.');
  int extLen;
  if (!point || point < strrchr(path, '/'))
    return scalloc(1, 1);
  point++;
  ext = smalloc((extLen = strlen(point)) + 1);
  ext[extLen] = 0;
  for (point += --extLen; extLen >= 0; point--)
    ext[extLen--] = ('A' <= *point && *point <= 'Z') ? ((*point) - 26) : *point;
  return ext;
}
```