ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readline>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rbp
  jmp    L8
L1:
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L5
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L1
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  movslq %r12d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int readline(char *line) {
  int c, length;
  for (length = 0; ((c = getchar()) != EOF); ++length) {
    line[length] = c;
    if (c == '\n') {
      line[++length] = '\0';
      break;
    }
  }
  return length;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readline>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rbp
  jmp    L15
L16:
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L13
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L16
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  movslq %r12d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int readline(char *line) {
  int c, length;
  for (length = 0; ((c = getchar()) != EOF); ++length) {
    line[length] = c;
    if (c == '\n') {
      line[++length] = '\0';
      break;
    }
  }
  return length;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L111
L77:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L136
L28:
  movl   $0x1,-0x10(%rbp)
  jmp    L5
L51:
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L95:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L95
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L51
  subl   $0x2,-0x10(%rbp)
  jmp    L147
L117:
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L46:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L46
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x10(%rbp)
L147:
  cmpl   $0x0,-0x10(%rbp)
  jg     L117
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  je     L59
  mov    $0xa,%edi
  call   <putchar@plt>
L59:
  addl   $0x1,-0x14(%rbp)
L136:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L28
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  je     L64
  mov    $0xa,%edi
  call   <putchar@plt>
L64:
  addl   $0x1,-0x18(%rbp)
L111:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L77
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L142
  call   <__stack_chk_fail@plt>
L142:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D30: %d

tool: D4: %d%d

assistant: ```c
int main() {
  int caseNum, amp, freq;
  int i, j, k, p;
  scanf("%d", &caseNum);
  for (i = 0; i < caseNum; i++) {
    scanf("%d%d", &amp, &freq);
    for (j = 0; j < freq; j++) {
      for (k = 1; k <= amp; k++) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      for (k = k - 2; k >= 1; k--) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      if (j != freq - 1)
        printf("\n");
    }
    if (i != caseNum - 1)
      printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L215
  mov    $0x0,%r13d
  lea    0x14(%rsp),%r15
  lea    D25(%rip),%rbp
  jmp    L37
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r14d
  cmp    %ebx,%r14d
  jne    L4
L139:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%rbx),%eax
  cmp    %eax,0x10(%rsp)
  jl     L161
  mov    %eax,%ebx
L167:
  mov    $0x0,%r14d
  test   %ebx,%ebx
  jg     L4
  jmp    L139
L161:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jg     L115
L163:
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jne    L142
L190:
  add    $0x1,%r12d
  cmp    %r12d,0x14(%rsp)
  jle    L186
L34:
  mov    $0x1,%ebx
  cmpl   $0x0,0x10(%rsp)
  jg     L167
  jmp    L163
L65:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r14d
  cmp    %ebx,%r14d
  jne    L65
L206:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  je     L163
L115:
  mov    $0x0,%r14d
  test   %ebx,%ebx
  jg     L65
  jmp    L206
L142:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L190
L186:
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r13d,%eax
  jne    L171
L75:
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jle    L215
L37:
  lea    0x10(%rsp),%rsi
  mov    %r15,%rdx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%r12d
  cmpl   $0x0,0x14(%rsp)
  jg     L34
  jmp    L186
L171:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L75
L215:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L178
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L178:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D13
type: string

tool: D25: %d

tool: D13: %d%d

assistant: ```c
int main() {
  int caseNum, amp, freq;
  int i, j, k, p;
  scanf("%d", &caseNum);
  for (i = 0; i < caseNum; i++) {
    scanf("%d%d", &amp, &freq);
    for (j = 0; j < freq; j++) {
      for (k = 1; k <= amp; k++) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      for (k = k - 2; k >= 1; k--) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      if (j != freq - 1)
        printf("\n");
    }
    if (i != caseNum - 1)
      printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%ecx
  test   %ecx,%ecx
  jle    L104
  lea    0x20(%rsp),%rax
  xor    %r12d,%r12d
  lea    0x24(%rsp),%r15
  mov    %rax,0x8(%rsp)
L12:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  xor    %eax,%eax
  xor    %ebp,%ebp
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jle    L94
  nopl   0x0(%rax,%rax,1)
L20:
  mov    0x20(%rsp),%eax
  mov    $0x1,%r13d
  test   %eax,%eax
  jle    L123
  xchg   %ax,%ax
L48:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r13d,%r14d
  jne    L44
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,0x20(%rsp)
  jl     L67
  mov    %ecx,%r13d
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L121:
  mov    $0xa,%edi
  call   <putchar@plt>
L67:
  sub    $0x1,%r14d
  je     L123
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    %r14d,%r13d
  jl     L25
  jmp    L121
L123:
  mov    0x24(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %ebp,%edx
  je     L93
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x24(%rsp),%eax
L93:
  add    $0x1,%ebp
  cmp    %ebp,%eax
  jg     L20
L94:
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %r12d,%edx
  je     L63
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%eax
L63:
  add    $0x1,%r12d
  cmp    %r12d,%eax
  jg     L12
L104:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string

tool: D16: %d

tool: D11: %d%d

assistant: ```c
int main() {
  int caseNum, amp, freq;
  int i, j, k, p;
  scanf("%d", &caseNum);
  for (i = 0; i < caseNum; i++) {
    scanf("%d%d", &amp, &freq);
    for (j = 0; j < freq; j++) {
      for (k = 1; k <= amp; k++) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      for (k = k - 2; k >= 1; k--) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      if (j != freq - 1)
        printf("\n");
    }
    if (i != caseNum - 1)
      printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%ecx
  test   %ecx,%ecx
  jle    L63
  lea    0x20(%rsp),%rax
  xor    %r12d,%r12d
  lea    0x24(%rsp),%r15
  mov    %rax,0x8(%rsp)
L142:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  xor    %eax,%eax
  xor    %ebp,%ebp
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  jle    L53
L23:
  mov    0x20(%rsp),%edx
  mov    $0x1,%r13d
  test   %edx,%edx
  jle    L39
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r13d,%r14d
  jne    L62
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,0x20(%rsp)
  jl     L38
  mov    %ecx,%r13d
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L139:
  mov    $0xa,%edi
  call   <putchar@plt>
L38:
  sub    $0x1,%r14d
  je     L130
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L82:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    %r14d,%r13d
  jl     L82
  jmp    L139
L130:
  mov    0x24(%rsp),%eax
L39:
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jne    L152
L53:
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jne    L35
L63:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L152:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  mov    0x24(%rsp),%eax
  cmp    %ebp,%eax
  jg     L23
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L63
L35:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    0x1c(%rsp),%r12d
  jl     L142
  jmp    L63
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D16: %d

tool: D14: %d%d

assistant: ```c
int main() {
  int caseNum, amp, freq;
  int i, j, k, p;
  scanf("%d", &caseNum);
  for (i = 0; i < caseNum; i++) {
    scanf("%d%d", &amp, &freq);
    for (j = 0; j < freq; j++) {
      for (k = 1; k <= amp; k++) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      for (k = k - 2; k >= 1; k--) {
        for (p = 0; p < k; p++)
          printf("%d", k);
        printf("\n");
      }
      if (j != freq - 1)
        printf("\n");
    }
    if (i != caseNum - 1)
      printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L37
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L22
L37:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L35
L22:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *chop(char *src) {
  char *p = src + strlen(src) - 1;
  while (p >= src) {
    if (*p == '\n' || *p == '\r') {
      *p-- = 0;
    } else {
      break;
    }
  }
  return (src);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jbe    L31
  jmp    L29
L9:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%rbx
  ja     L29
L31:
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L9
  cmp    $0xd,%dl
  je     L9
L29:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *chop(char *src) {
  char *p = src + strlen(src) - 1;
  while (p >= src) {
    if (*p == '\n' || *p == '\r') {
      *p-- = 0;
    } else {
      break;
    }
  }
  return (src);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chop>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmp    %rax,%r12
  jbe    L44
  jmp    L7
  nopl   0x0(%rax)
L33:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%r12
  ja     L7
L44:
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L33
  cmp    $0xd,%dl
  je     L33
L7:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *chop(char *src) {
  char *p = src + strlen(src) - 1;
  while (p >= src) {
    if (*p == '\n' || *p == '\r') {
      *p-- = 0;
    } else {
      break;
    }
  }
  return (src);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chop>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmp    %rax,%r12
  jbe    L10
  jmp    L48
  nopl   0x0(%rax)
L49:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%r12
  ja     L48
L10:
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L49
  cmp    $0xd,%dl
  je     L49
L48:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *chop(char *src) {
  char *p = src + strlen(src) - 1;
  while (p >= src) {
    if (*p == '\n' || *p == '\r') {
      *p-- = 0;
    } else {
      break;
    }
  }
  return (src);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<valid_utf8_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movl   $0x0,-0x8(%rbp)
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  js     L8
  movl   $0x0,-0x8(%rbp)
  jmp    L164
L8:
  movzbl -0x9(%rbp),%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  jne    L21
  movl   $0x1,-0x8(%rbp)
  jmp    L164
L21:
  movzbl -0x9(%rbp),%eax
  and    $0xf0,%eax
  cmp    $0xe0,%eax
  jne    L148
  movl   $0x2,-0x8(%rbp)
  jmp    L164
L148:
  movzbl -0x9(%rbp),%eax
  and    $0xf8,%eax
  cmp    $0xf0,%eax
  jne    L146
  movl   $0x3,-0x8(%rbp)
  jmp    L164
L146:
  movzbl -0x9(%rbp),%eax
  and    $0xfc,%eax
  cmp    $0xf8,%eax
  jne    L79
  movl   $0x4,-0x8(%rbp)
  jmp    L164
L79:
  movzbl -0x9(%rbp),%eax
  and    $0xfe,%eax
  cmp    $0xfc,%eax
  jne    L26
  movl   $0x5,-0x8(%rbp)
  jmp    L164
L26:
  mov    $0xffffffff,%eax
  jmp    L111
L164:
  movl   $0x0,-0x4(%rbp)
  jmp    L90
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L82
  mov    $0xffffffff,%eax
  jmp    L111
L82:
  addl   $0x1,-0x4(%rbp)
L90:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L36
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
L111:
  pop    %rbp
  ret
```

assistant: ```c
int valid_utf8_char(const char *str) {
  unsigned char c = (unsigned char)*str;
  int n = 0;
  if ((c & 0x80) == 0x00) {
    n = 0;
  } else if ((c & 0xe0) == 0xc0) {
    n = 1;
  } else if ((c & 0xf0) == 0xe0) {
    n = 2;
  } else if ((c & 0xf8) == 0xf0) {
    n = 3;
  } else if ((c & 0xfc) == 0xf8) {
    n = 4;
  } else if ((c & 0xfe) == 0xfc) {
    n = 5;
  } else {
    return -1;
  }
  int i;
  for (i = 0; i < n; i++) {
    if ((((unsigned char)(str[i + 1])) & 0xc0) != 0x80) {
      return -1;
    }
  }
  return n + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_utf8_char>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  js     L108
L20:
  add    $0x1,%eax
  ret
L108:
  mov    %edx,%eax
  and    $0xffffffe0,%eax
  cmp    $0xc0,%al
  je     L111
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  cmp    $0xe0,%al
  je     L65
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0xf0,%al
  je     L98
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  cmp    $0xf8,%al
  je     L92
  and    $0xfffffffe,%edx
  cmp    $0xfc,%dl
  jne    L118
  mov    $0x5,%eax
  jmp    L110
L118:
  mov    $0xffffffff,%eax
  ret
L95:
  mov    $0xffffffff,%eax
  ret
L111:
  mov    $0x1,%eax
L110:
  mov    $0x0,%ecx
L50:
  movzbl 0x1(%rdi,%rcx,1),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L95
  add    $0x1,%rcx
  cmp    %ecx,%eax
  jg     L50
  jmp    L20
L65:
  mov    $0x2,%eax
  jmp    L110
L98:
  mov    $0x3,%eax
  jmp    L110
L92:
  mov    $0x4,%eax
  jmp    L110
```

assistant: ```c
int valid_utf8_char(const char *str) {
  unsigned char c = (unsigned char)*str;
  int n = 0;
  if ((c & 0x80) == 0x00) {
    n = 0;
  } else if ((c & 0xe0) == 0xc0) {
    n = 1;
  } else if ((c & 0xf0) == 0xe0) {
    n = 2;
  } else if ((c & 0xf8) == 0xf0) {
    n = 3;
  } else if ((c & 0xfc) == 0xf8) {
    n = 4;
  } else if ((c & 0xfe) == 0xfc) {
    n = 5;
  } else {
    return -1;
  }
  int i;
  for (i = 0; i < n; i++) {
    if ((((unsigned char)(str[i + 1])) & 0xc0) != 0x80) {
      return -1;
    }
  }
  return n + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_utf8_char>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  js     L84
  ret
  nopl   0x0(%rax)
L84:
  mov    %edx,%eax
  and    $0xffffffe0,%eax
  cmp    $0xc0,%al
  je     L5
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  cmp    $0xe0,%al
  je     L111
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0xf0,%al
  je     L61
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  cmp    $0xf8,%al
  je     L71
  and    $0xfffffffe,%edx
  cmp    $0xfc,%dl
  jne    L7
  mov    $0x5,%esi
  nopl   0x0(%rax)
L55:
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi),%rdx
  lea    0x2(%rdi,%rax,1),%rcx
  jmp    L52
  xchg   %ax,%ax
L42:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L85
L52:
  movzbl (%rdx),%eax
  and    $0xffffffc0,%eax
  cmp    $0x80,%al
  je     L42
L7:
  mov    $0xffffffff,%eax
  ret
L111:
  mov    $0x2,%esi
  jmp    L55
L5:
  mov    $0x1,%esi
  jmp    L55
L61:
  mov    $0x3,%esi
  jmp    L55
L71:
  mov    $0x4,%esi
  jmp    L55
L85:
  lea    0x1(%rsi),%eax
  ret
```

assistant: ```c
int valid_utf8_char(const char *str) {
  unsigned char c = (unsigned char)*str;
  int n = 0;
  if ((c & 0x80) == 0x00) {
    n = 0;
  } else if ((c & 0xe0) == 0xc0) {
    n = 1;
  } else if ((c & 0xf0) == 0xe0) {
    n = 2;
  } else if ((c & 0xf8) == 0xf0) {
    n = 3;
  } else if ((c & 0xfc) == 0xf8) {
    n = 4;
  } else if ((c & 0xfe) == 0xfc) {
    n = 5;
  } else {
    return -1;
  }
  int i;
  for (i = 0; i < n; i++) {
    if ((((unsigned char)(str[i + 1])) & 0xc0) != 0x80) {
      return -1;
    }
  }
  return n + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<valid_utf8_char>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    $0x1,%r8d
  test   %dl,%dl
  js     L76
L83:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  mov    %edx,%ecx
  and    $0xffffffe0,%ecx
  cmp    $0xc0,%cl
  je     L47
  mov    %edx,%ecx
  and    $0xfffffff0,%ecx
  cmp    $0xe0,%cl
  je     L173
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  cmp    $0xf0,%cl
  je     L36
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  cmp    $0xf8,%cl
  je     L45
  and    $0xfffffffe,%edx
  cmp    $0xfc,%dl
  jne    L219
  movzbl 0x1(%rdi),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  mov    $0x5,%r8d
L54:
  movzbl 0x2(%rax),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  movzbl 0x3(%rax),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  cmp    $0x3,%r8d
  je     L50
  movzbl 0x4(%rax),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  cmp    $0x5,%r8d
  jne    L212
  movzbl 0x5(%rax),%eax
  and    $0xffffffc0,%eax
  cmp    $0x80,%al
  jne    L219
L50:
  add    $0x1,%r8d
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L173:
  movzbl 0x1(%rdi),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  movzbl 0x2(%rdi),%eax
  and    $0xffffffc0,%eax
  cmp    $0x80,%al
  je     L16
L219:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L47:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffc0,%eax
  cmp    $0x80,%al
  jne    L219
  mov    $0x1,%r8d
  jmp    L50
L36:
  movzbl 0x1(%rdi),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  mov    $0x3,%r8d
  jmp    L54
L45:
  movzbl 0x1(%rdi),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L219
  mov    $0x4,%r8d
  jmp    L54
L212:
  mov    $0x4,%r8d
  jmp    L50
L16:
  mov    $0x2,%r8d
  jmp    L50
```

assistant: ```c
int valid_utf8_char(const char *str) {
  unsigned char c = (unsigned char)*str;
  int n = 0;
  if ((c & 0x80) == 0x00) {
    n = 0;
  } else if ((c & 0xe0) == 0xc0) {
    n = 1;
  } else if ((c & 0xf0) == 0xe0) {
    n = 2;
  } else if ((c & 0xf8) == 0xf0) {
    n = 3;
  } else if ((c & 0xfc) == 0xf8) {
    n = 4;
  } else if ((c & 0xfe) == 0xfc) {
    n = 5;
  } else {
    return -1;
  }
  int i;
  for (i = 0; i < n; i++) {
    if ((((unsigned char)(str[i + 1])) & 0xc0) != 0x80) {
      return -1;
    }
  }
  return n + 1;
}
```