ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HibernateDataGet>:
  endbr64
  test   %rsi,%rsi
  je     L18
  movabs $0xffffffff7fe07fa0,%rdx
  lea    0x400fc030(,%rsi,4),%rcx
  mov    $0x400fc030,%eax
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rax),%rdx
  mov    %rdx,(%rdi,%rax,2)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L17
L18:
  ret
```

assistant: ```c
void HibernateDataGet(uint32_t *pui32Data, uint32_t ui32Count) {
  uint32_t ui32Idx;
  ;
  ;
  for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx++) {
    pui32Data[ui32Idx] = (*((volatile uint32_t *)(0x400FC030 + (ui32Idx * 4))));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HibernateDataGet>:
  endbr64
  test   %rsi,%rsi
  je     L10
  movabs $0xffffffff7fe07fa0,%rdx
  lea    0x400fc030(,%rsi,4),%rcx
  mov    $0x400fc030,%eax
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rax),%rdx
  mov    %rdx,(%rdi,%rax,2)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L18
L10:
  ret
```

assistant: ```c
void HibernateDataGet(uint32_t *pui32Data, uint32_t ui32Count) {
  uint32_t ui32Idx;
  ;
  ;
  for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx++) {
    pui32Data[ui32Idx] = (*((volatile uint32_t *)(0x400FC030 + (ui32Idx * 4))));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<smallest_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L9
  cmpl   $0x0,-0x20(%rbp)
  jne    L34
L9:
  mov    $0xffffffff,%eax
  jmp    L20
L34:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L70
L50:
  movl   $0x0,-0x8(%rbp)
  jmp    L36
L73:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L78
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L78:
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L73
  addl   $0x1,-0xc(%rbp)
L70:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L50
  mov    -0x10(%rbp),%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int smallest_diff(int a[], int asize, int b[], int bsize) {
  if (asize == 0 || bsize == 0)
    return -1;
  int min = abs(a[0] - b[0]);
  int diff;
  for (int i = 0; i < asize; i++) {
    for (int j = 0; j < bsize; j++) {
      diff = abs(a[i] - b[j]);
      if (diff < min)
        min = diff;
    }
  }
  return min;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<smallest_diff>:
  endbr64
  test   %esi,%esi
  je     L46
  mov    %rdi,%r8
  mov    %rdx,%r11
  mov    %ecx,%r10d
  test   %ecx,%ecx
  je     L46
  mov    (%rdi),%eax
  sub    (%rdx),%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  test   %esi,%esi
  jle    L0
  push   %rbx
  mov    %r8,%r9
  lea    -0x1(%rsi),%eax
  lea    0x4(%r8,%rax,4),%rbx
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r8
  jmp    L20
L57:
  mov    (%r9),%esi
  mov    %r11,%rdx
L48:
  mov    %esi,%ecx
  sub    (%rdx),%ecx
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  cmp    %eax,%edi
  cmovg  %eax,%edi
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L48
L8:
  add    $0x4,%r9
  cmp    %rbx,%r9
  je     L40
L20:
  test   %r10d,%r10d
  jg     L57
  jmp    L8
L46:
  mov    $0xffffffff,%edi
L0:
  mov    %edi,%eax
  ret
L40:
  mov    %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
int smallest_diff(int a[], int asize, int b[], int bsize) {
  if (asize == 0 || bsize == 0)
    return -1;
  int min = abs(a[0] - b[0]);
  int diff;
  for (int i = 0; i < asize; i++) {
    for (int j = 0; j < bsize; j++) {
      diff = abs(a[i] - b[j]);
      if (diff < min)
        min = diff;
    }
  }
  return min;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<smallest_diff>:
  endbr64
  test   %esi,%esi
  je     L61
  mov    %ecx,%r11d
  test   %ecx,%ecx
  je     L61
  push   %rbp
  mov    %rdi,%r9
  push   %rbx
  mov    (%rdx),%ebx
  mov    (%rdi),%eax
  sub    %ebx,%eax
  mov    %eax,%r8d
  neg    %r8d
  cmovs  %eax,%r8d
  test   %esi,%esi
  jle    L68
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdx),%r10
  lea    0x4(%rdi,%rax,4),%rbp
  lea    -0x1(%rcx),%eax
  lea    (%r10,%rax,4),%rdi
  nopl   0x0(%rax,%rax,1)
L50:
  test   %r11d,%r11d
  jle    L51
  mov    (%r9),%esi
  mov    %r10,%rcx
  mov    %ebx,%eax
  jmp    L29
  nop
L56:
  mov    (%rcx),%eax
  add    $0x4,%rcx
L29:
  mov    %esi,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cmp    %eax,%r8d
  cmovg  %eax,%r8d
  cmp    %rdi,%rcx
  jne    L56
L51:
  add    $0x4,%r9
  cmp    %rbp,%r9
  jne    L50
L68:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L61:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int smallest_diff(int a[], int asize, int b[], int bsize) {
  if (asize == 0 || bsize == 0)
    return -1;
  int min = abs(a[0] - b[0]);
  int diff;
  for (int i = 0; i < asize; i++) {
    for (int j = 0; j < bsize; j++) {
      diff = abs(a[i] - b[j]);
      if (diff < min)
        min = diff;
    }
  }
  return min;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<smallest_diff>:
  endbr64
  test   %esi,%esi
  je     L45
  mov    %ecx,%r8d
  test   %ecx,%ecx
  je     L45
  mov    %rdx,%r10
  mov    (%rdi),%edx
  sub    (%r10),%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  test   %esi,%esi
  jle    L46
  lea    -0x1(%rsi),%edx
  push   %r13
  mov    %r8d,%r11d
  push   %r12
  and    $0xfffffffc,%r11d
  push   %rbp
  lea    -0x1(%rcx),%ebp
  push   %rbx
  lea    0x4(%rdi,%rdx,4),%rbx
  mov    %ecx,%edx
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%r10,%rdx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L48:
  test   %r8d,%r8d
  jle    L68
  mov    (%rdi),%edx
  cmp    $0x2,%ebp
  jbe    L79
  movd   %eax,%xmm5
  movd   %edx,%xmm6
  mov    %r10,%rax
  pshufd $0x0,%xmm5,%xmm1
  pshufd $0x0,%xmm6,%xmm3
  nopl   0x0(%rax)
L21:
  movdqu (%rax),%xmm4
  movdqa %xmm3,%xmm0
  add    $0x10,%rax
  psubd  %xmm4,%xmm0
  movdqa %xmm0,%xmm2
  psrad  $0x1f,%xmm2
  pxor   %xmm2,%xmm0
  psubd  %xmm2,%xmm0
  movdqa %xmm0,%xmm2
  pcmpgtd %xmm1,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm0,%xmm2
  por    %xmm2,%xmm1
  cmp    %rcx,%rax
  jne    L21
  movdqa %xmm1,%xmm2
  mov    %r11d,%esi
  psrldq $0x8,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %r8d,%r11d
  je     L68
L25:
  movslq %esi,%r9
  mov    %edx,%r13d
  sub    (%r10,%r9,4),%r13d
  lea    0x0(,%r9,4),%r12
  mov    %r13d,%r9d
  neg    %r9d
  cmovs  %r13d,%r9d
  cmp    %r9d,%eax
  cmovg  %r9d,%eax
  lea    0x1(%rsi),%r9d
  cmp    %r9d,%r8d
  jle    L68
  mov    %edx,%r13d
  sub    0x4(%r10,%r12,1),%r13d
  mov    %r13d,%r9d
  neg    %r9d
  cmovs  %r13d,%r9d
  cmp    %r9d,%eax
  cmovg  %r9d,%eax
  add    $0x2,%esi
  cmp    %esi,%r8d
  jle    L68
  sub    0x8(%r10,%r12,1),%edx
  mov    %edx,%esi
  neg    %esi
  cmovns %esi,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L68:
  add    $0x4,%rdi
  cmp    %rbx,%rdi
  jne    L48
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L79:
  xor    %esi,%esi
  jmp    L25
L46:
  ret
L45:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int smallest_diff(int a[], int asize, int b[], int bsize) {
  if (asize == 0 || bsize == 0)
    return -1;
  int min = abs(a[0] - b[0]);
  int diff;
  for (int i = 0; i < asize; i++) {
    for (int j = 0; j < bsize; j++) {
      diff = abs(a[i] - b[j]);
      if (diff < min)
        min = diff;
    }
  }
  return min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ffiTestDoubles15>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  %xmm3,-0x20(%rbp)
  movsd  %xmm4,-0x28(%rbp)
  movsd  %xmm5,-0x30(%rbp)
  movsd  %xmm6,-0x38(%rbp)
  movsd  %xmm7,-0x40(%rbp)
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  addsd  0x10(%rbp),%xmm0
  addsd  0x18(%rbp),%xmm0
  addsd  0x20(%rbp),%xmm0
  addsd  0x28(%rbp),%xmm0
  addsd  0x30(%rbp),%xmm0
  addsd  0x38(%rbp),%xmm0
  addsd  0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double ffiTestDoubles15(double f1, double f2, double f3, double f4, double f5, double f6, double f7, double f8, double f9, double f10, double f11, double f12, double f13, double f14, double f15) {
  ;
  return (double)(f1 + f2 + f3 + f4 + f5 + f6 + f7 + f8 + f9 + f10 + f11 + f12 + f13 + f14 + f15);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ffiTestDoubles15>:
  endbr64
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm4,%xmm0
  addsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  addsd  %xmm7,%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  addsd  0x28(%rsp),%xmm0
  addsd  0x30(%rsp),%xmm0
  addsd  0x38(%rsp),%xmm0
  ret
```

assistant: ```c
double ffiTestDoubles15(double f1, double f2, double f3, double f4, double f5, double f6, double f7, double f8, double f9, double f10, double f11, double f12, double f13, double f14, double f15) {
  ;
  return (double)(f1 + f2 + f3 + f4 + f5 + f6 + f7 + f8 + f9 + f10 + f11 + f12 + f13 + f14 + f15);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ffiTestDoubles15>:
  endbr64
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm4,%xmm0
  addsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  addsd  %xmm7,%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  addsd  0x28(%rsp),%xmm0
  addsd  0x30(%rsp),%xmm0
  addsd  0x38(%rsp),%xmm0
  ret
```

assistant: ```c
double ffiTestDoubles15(double f1, double f2, double f3, double f4, double f5, double f6, double f7, double f8, double f9, double f10, double f11, double f12, double f13, double f14, double f15) {
  ;
  return (double)(f1 + f2 + f3 + f4 + f5 + f6 + f7 + f8 + f9 + f10 + f11 + f12 + f13 + f14 + f15);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ffiTestDoubles15>:
  endbr64
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm4,%xmm0
  addsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  addsd  %xmm7,%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  addsd  0x28(%rsp),%xmm0
  addsd  0x30(%rsp),%xmm0
  addsd  0x38(%rsp),%xmm0
  ret
```

assistant: ```c
double ffiTestDoubles15(double f1, double f2, double f3, double f4, double f5, double f6, double f7, double f8, double f9, double f10, double f11, double f12, double f13, double f14, double f15) {
  ;
  return (double)(f1 + f2 + f3 + f4 + f5 + f6 + f7 + f8 + f9 + f10 + f11 + f12 + f13 + f14 + f15);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_k_mod_dl_set_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <dlerror@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <k_mod_set_error@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: unknown dlerror

assistant: ```c
void _k_mod_dl_set_error(void) {
  const char *err = dlerror();
  if (!err)
    err = "unknown dlerror";
  k_mod_set_error(err);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_k_mod_dl_set_error>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dlerror@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  lea    D9(%rip),%rax
  cmove  %rax,%rdi
  call   <k_mod_set_error@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: unknown dlerror

assistant: ```c
void _k_mod_dl_set_error(void) {
  const char *err = dlerror();
  if (!err)
    err = "unknown dlerror";
  k_mod_set_error(err);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_k_mod_dl_set_error>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dlerror@plt>
  test   %rax,%rax
  mov    %rax,%rdi
  lea    D6(%rip),%rax
  cmove  %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <k_mod_set_error@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: unknown dlerror

assistant: ```c
void _k_mod_dl_set_error(void) {
  const char *err = dlerror();
  if (!err)
    err = "unknown dlerror";
  k_mod_set_error(err);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_k_mod_dl_set_error>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dlerror@plt>
  test   %rax,%rax
  mov    %rax,%rdi
  lea    D8(%rip),%rax
  cmove  %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <k_mod_set_error@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: unknown dlerror

assistant: ```c
void _k_mod_dl_set_error(void) {
  const char *err = dlerror();
  if (!err)
    err = "unknown dlerror";
  k_mod_set_error(err);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rop3_7_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_7_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & S;
  stk1 = T | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rop3_7_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%esi
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_7_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & S;
  stk1 = T | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_7_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_7_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & S;
  stk1 = T | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_7_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_7_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & S;
  stk1 = T | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_palindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L14
  mov    $0x0,%eax
  jmp    L34
L14:
  movq   $0x0,-0x8(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L30
L5:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rsi
  mov    -0x14(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rax,%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jbe    L5
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int is_palindrome(int n) {
  if (n < 0) {
    return 0;
  }
  unsigned long long int divn;
  unsigned long long int rev;
  for (rev = 0, divn = 1; n / divn != 0; divn *= 10) {
    rev = rev * 10 + (n / divn) % 10;
  }
  return rev == n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_palindrome>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L35
  movslq %edi,%rdi
  test   %rdi,%rdi
  je     L22
  mov    $0x0,%edx
  mov    $0x1,%ecx
  movabs $0xcccccccccccccccd,%r9
L36:
  lea    (%rdx,%rdx,4),%r8
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%rsi
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rsi
  lea    (%rsi,%r8,2),%rdx
  lea    (%rcx,%rcx,4),%rax
  add    %rax,%rax
  mov    %rax,%rcx
  cmp    %rdi,%rax
  jbe    L36
L6:
  cmp    %rdx,%rdi
  sete   %al
  movzbl %al,%eax
L35:
  ret
L22:
  mov    %rdi,%rdx
  jmp    L6
```

assistant: ```c
int is_palindrome(int n) {
  if (n < 0) {
    return 0;
  }
  unsigned long long int divn;
  unsigned long long int rev;
  for (rev = 0, divn = 1; n / divn != 0; divn *= 10) {
    rev = rev * 10 + (n / divn) % 10;
  }
  return rev == n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_palindrome>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L16
  movslq %edi,%rdi
  je     L18
  xor    %eax,%eax
  mov    $0x1,%ecx
  movabs $0xcccccccccccccccd,%r9
L11:
  lea    (%rax,%rax,4),%r8
  xor    %edx,%edx
  mov    %rdi,%rax
  div    %rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rcx
  mov    %rax,%rsi
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rsi
  lea    (%rsi,%r8,2),%rax
  cmp    %rdi,%rcx
  jbe    L11
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
L16:
  ret
```

assistant: ```c
int is_palindrome(int n) {
  if (n < 0) {
    return 0;
  }
  unsigned long long int divn;
  unsigned long long int rev;
  for (rev = 0, divn = 1; n / divn != 0; divn *= 10) {
    rev = rev * 10 + (n / divn) % 10;
  }
  return rev == n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_palindrome>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L7
  movslq %edi,%rdi
  je     L29
  xor    %eax,%eax
  mov    $0x1,%ecx
  movabs $0xcccccccccccccccd,%r9
L20:
  lea    (%rax,%rax,4),%r8
  xor    %edx,%edx
  mov    %rdi,%rax
  div    %rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rcx
  mov    %rax,%rsi
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rsi
  lea    (%rsi,%r8,2),%rax
  cmp    %rdi,%rcx
  jbe    L20
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
L7:
  ret
```

assistant: ```c
int is_palindrome(int n) {
  if (n < 0) {
    return 0;
  }
  unsigned long long int divn;
  unsigned long long int rev;
  for (rev = 0, divn = 1; n / divn != 0; divn *= 10) {
    rev = rev * 10 + (n / divn) % 10;
  }
  return rev == n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nrf_drv_radio802154_rx_duration_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x6,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L1
  addl   $0x2e,-0x4(%rbp)
L1:
  shll   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t nrf_drv_radio802154_rx_duration_get(uint8_t psdu_length, bool ack_requested) {
  uint16_t result = 10 + (psdu_length + 1) * 2;
  if (ack_requested) {
    result += 12 + 10 + (6 * 2) + 12;
  }
  result *= 16;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nrf_drv_radio802154_rx_duration_get>:
  endbr64
  lea    0xc(%rdi,%rdi,1),%eax
  lea    0x2e(%rax),%edx
  test   %esi,%esi
  cmovne %edx,%eax
  shl    $0x4,%eax
  ret
```

assistant: ```c
uint16_t nrf_drv_radio802154_rx_duration_get(uint8_t psdu_length, bool ack_requested) {
  uint16_t result = 10 + (psdu_length + 1) * 2;
  if (ack_requested) {
    result += 12 + 10 + (6 * 2) + 12;
  }
  result *= 16;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nrf_drv_radio802154_rx_duration_get>:
  endbr64
  lea    0xc(%rdi,%rdi,1),%eax
  test   %esi,%esi
  lea    0x2e(%rax),%edx
  cmovne %edx,%eax
  shl    $0x4,%eax
  ret
```

assistant: ```c
uint16_t nrf_drv_radio802154_rx_duration_get(uint8_t psdu_length, bool ack_requested) {
  uint16_t result = 10 + (psdu_length + 1) * 2;
  if (ack_requested) {
    result += 12 + 10 + (6 * 2) + 12;
  }
  result *= 16;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nrf_drv_radio802154_rx_duration_get>:
  endbr64
  lea    0xc(%rdi,%rdi,1),%eax
  test   %esi,%esi
  lea    0x2e(%rax),%edx
  cmovne %edx,%eax
  shl    $0x4,%eax
  ret
```

assistant: ```c
uint16_t nrf_drv_radio802154_rx_duration_get(uint8_t psdu_length, bool ack_requested) {
  uint16_t result = 10 + (psdu_length + 1) * 2;
  if (ack_requested) {
    result += 12 + 10 + (6 * 2) + 12;
  }
  result *= 16;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CommReceive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,%edi
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <msgrcv@plt>
  cmp    $0xffffffff,%eax
  jne    L4
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: Error! Receive message wrong!


assistant: ```c
void CommReceive(int channel_id, void *message, int size) {
  long type = *(long *)message;
  if (msgrcv(channel_id, message, size - sizeof(long), type, 0) == -1) {
    printf("Error! Receive message wrong!\n");
    exit(1);
  }
}
```