ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L78
L40:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L72
  movl   $0x1,-0x4(%rbp)
  jmp    L71
L30:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L71:
  mov    $0x6,%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L30
  jmp    L1
L72:
  mov    $0x6,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L31
L27:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L31:
  cmpl   $0x0,-0x4(%rbp)
  jg     L27
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L78:
  cmpl   $0x5,-0x8(%rbp)
  jle    L40
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    if (i % 2 != 0) {
      for (j = 1; j <= 6 - i; j++) {
        printf("%d", j);
      }
    } else {
      for (j = 6 - i; j >= 1; j--) {
        printf("%d", j);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5,%r12d
  lea    D2(%rip),%rbp
  jmp    L64
L6:
  mov    %r12d,%ebx
  test   %r12d,%r12d
  jle    L26
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L10
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  je     L44
L64:
  test   $0x1,%r12b
  je     L6
  mov    %r12d,%r13d
  test   %r12d,%r12d
  jle    L26
  mov    $0x1,%ebx
L68:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jge    L68
  jmp    L26
L44:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    if (i % 2 != 0) {
      for (j = 1; j <= 6 - i; j++) {
        printf("%d", j);
      }
    } else {
      for (j = 6 - i; j >= 1; j--) {
        printf("%d", j);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    $0x5,%ebp
  push   %rbx
L40:
  mov    %ebp,%ebx
  test   $0x1,%bpl
  je     L25
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L18:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L18
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L40
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L25
  jmp    L29
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    if (i % 2 != 0) {
      for (j = 1; j <= 6 - i; j++) {
        printf("%d", j);
      }
    } else {
      for (j = 6 - i; j >= 1; j--) {
        printf("%d", j);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    $0x5,%ebp
  push   %rbx
L28:
  mov    %ebp,%ebx
  test   $0x1,%bpl
  je     L39
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L4:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L4
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L28
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L39
  jmp    L13
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    if (i % 2 != 0) {
      for (j = 1; j <= 6 - i; j++) {
        printf("%d", j);
      }
    } else {
      for (j = 6 - i; j >= 1; j--) {
        printf("%d", j);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<txt_getNameForType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x4,%eax
  cmp    $0x1e,%eax
  ja     L53
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D26(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D33(%rip),%rax
  jmp    L39
  lea    D19(%rip),%rax
  jmp    L39
  lea    D54(%rip),%rax
  jmp    L39
  lea    D76(%rip),%rax
  jmp    L39
  lea    D34(%rip),%rax
  jmp    L39
  lea    D1(%rip),%rax
  jmp    L39
L53:
  lea    D22(%rip),%rax
L39:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D33
type: string
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D54
type: string
name: unpack_data
arguments: label: D76
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D22
type: string

tool: D33: ASCII

tool: D19: UTF-8

tool: D54: UTF-16 (LE)

tool: D76: UTF-16 (BE)

tool: D34: UTF-32 (LE)

tool: D1: UTF-32 (BE)

tool: 

assistant: ```c
const char *txt_getNameForType(unsigned int t) {
  switch (t) {
  case 0x0004:
    return "ASCII";
  case 0x0008:
    return "UTF-8";
  case ((0x0010) | (0x0001)):
    return "UTF-16 (LE)";
  case ((0x0010) | (0x0002)):
    return "UTF-16 (BE)";
  case ((0x0020) | (0x0001)):
    return "UTF-32 (LE)";
  case ((0x0020) | (0x0002)):
    return "UTF-32 (BE)";
  default:
    return "";
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<txt_getNameForType>:
  endbr64
  sub    $0x4,%edi
  cmp    $0x1e,%edi
  ja     L2
  mov    %edi,%edi
  lea    D65(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D55(%rip),%rax
  ret
  lea    D7(%rip),%rax
  ret
  lea    D5(%rip),%rax
  ret
  lea    D25(%rip),%rax
  ret
  lea    D57(%rip),%rax
  ret
L2:
  lea    D63(%rip),%rax
  ret
  lea    D39(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D55
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D57
datatype: string
name: unpack_data
arguments: data_tag: D63
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: string

tool: D55: UTF-8

tool: D7: UTF-16 (LE)

tool: D5: UTF-16 (BE)

tool: D25: UTF-32 (LE)

tool: D57: UTF-32 (BE)

tool: 

tool: D39: ASCII

assistant: ```c
const char *txt_getNameForType(unsigned int t) {
  switch (t) {
  case 0x0004:
    return "ASCII";
  case 0x0008:
    return "UTF-8";
  case ((0x0010) | (0x0001)):
    return "UTF-16 (LE)";
  case ((0x0010) | (0x0002)):
    return "UTF-16 (BE)";
  case ((0x0020) | (0x0001)):
    return "UTF-32 (LE)";
  case ((0x0020) | (0x0002)):
    return "UTF-32 (BE)";
  default:
    return "";
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<txt_getNameForType>:
  endbr64
  sub    $0x4,%edi
  cmp    $0x1e,%edi
  ja     L9
  lea    D32(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L9:
  lea    D67(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D5(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D24(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D56(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D29(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D20(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D67
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D56
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D20
type: string

tool: 

tool: D5: UTF-16 (LE)

tool: D24: UTF-16 (BE)

tool: D56: UTF-32 (LE)

tool: D28: UTF-32 (BE)

tool: D29: ASCII

tool: D20: UTF-8

assistant: ```c
const char *txt_getNameForType(unsigned int t) {
  switch (t) {
  case 0x0004:
    return "ASCII";
  case 0x0008:
    return "UTF-8";
  case ((0x0010) | (0x0001)):
    return "UTF-16 (LE)";
  case ((0x0010) | (0x0002)):
    return "UTF-16 (BE)";
  case ((0x0020) | (0x0001)):
    return "UTF-32 (LE)";
  case ((0x0020) | (0x0002)):
    return "UTF-32 (BE)";
  default:
    return "";
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<txt_getNameForType>:
  endbr64
  sub    $0x4,%edi
  cmp    $0x1e,%edi
  ja     L5
  lea    D34(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L5:
  lea    D43(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D6(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D55(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D24(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D77(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D57(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D35(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D43
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string
name: extract_symbolic_data
arguments: data_tag: D55
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D77
type: string
name: extract_symbolic_data
arguments: data_tag: D57
type: string
name: extract_symbolic_data
arguments: data_tag: D35
type: string

tool: 

tool: D6: UTF-16 (LE)

tool: D55: UTF-16 (BE)

tool: D24: UTF-32 (LE)

tool: D77: UTF-32 (BE)

tool: D57: ASCII

tool: D35: UTF-8

assistant: ```c
const char *txt_getNameForType(unsigned int t) {
  switch (t) {
  case 0x0004:
    return "ASCII";
  case 0x0008:
    return "UTF-8";
  case ((0x0010) | (0x0001)):
    return "UTF-16 (LE)";
  case ((0x0010) | (0x0002)):
    return "UTF-16 (BE)";
  case ((0x0020) | (0x0001)):
    return "UTF-32 (LE)";
  case ((0x0020) | (0x0002)):
    return "UTF-32 (BE)";
  default:
    return "";
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<walk_stack_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L1:
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L1
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t walk_stack_usage(int32_t *stack_usage) {
  uint32_t idx = 0;
  while (stack_usage[idx]) {
    idx++;
  }
  return idx;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<walk_stack_usage>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L16
  mov    $0x0,%eax
L8:
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L8
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint32_t walk_stack_usage(int32_t *stack_usage) {
  uint32_t idx = 0;
  while (stack_usage[idx]) {
    idx++;
  }
  return idx;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<walk_stack_usage>:
  endbr64
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L11
  nopl   0x0(%rax)
L5:
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L5
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
uint32_t walk_stack_usage(int32_t *stack_usage) {
  uint32_t idx = 0;
  while (stack_usage[idx]) {
    idx++;
  }
  return idx;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<walk_stack_usage>:
  endbr64
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L2
  nopl   0x0(%rax)
L18:
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L18
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
uint32_t walk_stack_usage(int32_t *stack_usage) {
  uint32_t idx = 0;
  while (stack_usage[idx]) {
    idx++;
  }
  return idx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <SafeMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string

tool: D5: strdup

assistant: ```c
char *strdup(char *str) {
  char *temp;
  temp = (char *)SafeMalloc(strlen(str) + 1, "strdup");
  strcpy(temp, str);
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  lea    D6(%rip),%rsi
  call   <SafeMalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: strdup

assistant: ```c
char *strdup(char *str) {
  char *temp;
  temp = (char *)SafeMalloc(strlen(str) + 1, "strdup");
  strcpy(temp, str);
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D9(%rip),%rsi
  lea    0x1(%rax),%rdi
  call   <SafeMalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: strdup

assistant: ```c
char *strdup(char *str) {
  char *temp;
  temp = (char *)SafeMalloc(strlen(str) + 1, "strdup");
  strcpy(temp, str);
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D3(%rip),%rsi
  lea    0x1(%rax),%rdi
  call   <SafeMalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: strdup

assistant: ```c
char *strdup(char *str) {
  char *temp;
  temp = (char *)SafeMalloc(strlen(str) + 1, "strdup");
  strcpy(temp, str);
  return temp;
}
```
user: What is the c source code of the assembly code below?

```asm
<h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L6
L34:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  je     L7
  mov    $0x0,%eax
  call   <abort@plt>
L7:
  addl   $0x1,-0x24(%rbp)
L6:
  cmpl   $0x3,-0x24(%rbp)
  jle    L34
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
h() {
  int c[4];
  c[0] = 0;
  c[1] = 1;
  c[2] = 2;
  c[3] = 3;
  for (int i = 0; i < 4; i++)
    if (!(c[i] == i))
      abort();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<h>:
  endbr64
  ret
```

assistant: ```c
h() {
  int c[4];
  c[0] = 0;
  c[1] = 1;
  c[2] = 2;
  c[3] = 3;
  for (int i = 0; i < 4; i++)
    if (!(c[i] == i))
      abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<h>:
  endbr64
  ret
```

assistant: ```c
h() {
  int c[4];
  c[0] = 0;
  c[1] = 1;
  c[2] = 2;
  c[3] = 3;
  for (int i = 0; i < 4; i++)
    if (!(c[i] == i))
      abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<h>:
  endbr64
  ret
```

assistant: ```c
h() {
  int c[4];
  c[0] = 0;
  c[1] = 1;
  c[2] = 2;
  c[3] = 3;
  for (int i = 0; i < 4; i++)
    if (!(c[i] == i))
      abort();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mfm_dump_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %esi,%r8d
  lea    D16(%rip),%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  lea    D33(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cmp    $0xf,%eax
  jne    L25
  mov    -0x2c(%rbp),%eax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <msg@plt>
L25:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    -0x2c(%rbp),%eax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D33
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string

tool: D16: %4d %2d %2d:

tool: D33: 0x%02x,

tool: D23: 


assistant: ```c
void mfm_dump_bytes(uint8_t bytes[], int len, int cyl, int head, int sector_index, int msg_level) {
  int i;
  msg(msg_level, "%4d %2d %2d:", cyl, head, sector_index);
  for (i = 0; i < len; i++) {
    msg(msg_level, "0x%02x,", bytes[i]);
    if (i % 16 == 15) {
      msg(msg_level, "\n");
    }
  }
  msg(msg_level, "\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mfm_dump_bytes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %r9d,%ebp
  lea    D6(%rip),%rsi
  mov    %r9d,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  test   %r12d,%r12d
  jle    L31
  mov    0x0(%r13),%edx
  lea    D45(%rip),%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  mov    %r12d,%r12d
  mov    $0x1,%ebx
  lea    D45(%rip),%r14
  lea    D31(%rip),%r15
  jmp    L33
L19:
  mov    %r15,%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <msg@plt>
L28:
  add    $0x1,%rbx
L33:
  cmp    %r12,%rbx
  je     L31
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cmp    $0xf,%eax
  jne    L28
  jmp    L19
L31:
  lea    D31(%rip),%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <msg@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D45
type_infered: string
name: unpack_data
arguments: data_tag: D31
type_infered: string

tool: D6: %4d %2d %2d:

tool: D45: 0x%02x,

tool: D31: 


assistant: ```c
void mfm_dump_bytes(uint8_t bytes[], int len, int cyl, int head, int sector_index, int msg_level) {
  int i;
  msg(msg_level, "%4d %2d %2d:", cyl, head, sector_index);
  for (i = 0; i < len; i++) {
    msg(msg_level, "0x%02x,", bytes[i]);
    if (i % 16 == 15) {
      msg(msg_level, "\n");
    }
  }
  msg(msg_level, "\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mfm_dump_bytes>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %r9d,%edi
  push   %r12
  movslq %esi,%r12
  lea    D15(%rip),%rsi
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <msg@plt>
  test   %r12d,%r12d
  jle    L0
  mov    0x0(%r13),%edx
  lea    D13(%rip),%r14
  mov    %ebp,%edi
  xor    %eax,%eax
  mov    %r14,%rsi
  mov    $0x1,%ebx
  lea    D23(%rip),%r15
  call   <msg@plt>
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
L29:
  cmp    %rbx,%r12
  je     L38
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <msg@plt>
  mov    %ebx,%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  jne    L4
  mov    %r15,%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <msg@plt>
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D23(%rip),%r15
L38:
  add    $0x8,%rsp
  mov    %r15,%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <msg@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D23
type_infered: string

tool: D15: %4d %2d %2d:

tool: D13: 0x%02x,

tool: D23: 


assistant: ```c
void mfm_dump_bytes(uint8_t bytes[], int len, int cyl, int head, int sector_index, int msg_level) {
  int i;
  msg(msg_level, "%4d %2d %2d:", cyl, head, sector_index);
  for (i = 0; i < len; i++) {
    msg(msg_level, "0x%02x,", bytes[i]);
    if (i % 16 == 15) {
      msg(msg_level, "\n");
    }
  }
  msg(msg_level, "\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mfm_dump_bytes>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r9d,%edi
  push   %rbx
  mov    %esi,%ebx
  lea    D34(%rip),%rsi
  sub    $0x8,%rsp
  call   <msg@plt>
  test   %ebx,%ebx
  jle    L37
  mov    0x0(%rbp),%edx
  lea    D30(%rip),%r12
  mov    %r14d,%edi
  xor    %eax,%eax
  mov    %r12,%rsi
  movslq %ebx,%r13
  lea    D11(%rip),%r15
  mov    $0x1,%ebx
  call   <msg@plt>
  cmp    $0x1,%r13d
  jne    L46
  jmp    L4
  nopl   0x0(%rax)
L22:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L4
L46:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %r12,%rsi
  mov    %r14d,%edi
  xor    %eax,%eax
  call   <msg@plt>
  mov    %ebx,%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  jne    L22
  mov    %r15,%rsi
  mov    %r14d,%edi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <msg@plt>
  cmp    %rbx,%r13
  jne    L46
L4:
  add    $0x8,%rsp
  mov    %r15,%rsi
  mov    %r14d,%edi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <msg@plt>
  nopl   (%rax)
L37:
  lea    D11(%rip),%r15
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D34
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D34: %4d %2d %2d:

tool: D30: 0x%02x,

tool: D11: 


assistant: ```c
void mfm_dump_bytes(uint8_t bytes[], int len, int cyl, int head, int sector_index, int msg_level) {
  int i;
  msg(msg_level, "%4d %2d %2d:", cyl, head, sector_index);
  for (i = 0; i < len; i++) {
    msg(msg_level, "0x%02x,", bytes[i]);
    if (i % 16 == 15) {
      msg(msg_level, "\n");
    }
  }
  msg(msg_level, "\n");
}
```