user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simplifypath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L75
L98:
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L31
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L31
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L129
L78:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L128
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L129
L128:
  addq   $0x1,-0x10(%rbp)
  jmp    L133
L129:
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L78
L133:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strdel@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L58
  subq   $0x1,-0x10(%rbp)
L58:
  subq   $0x1,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  mov    $0x3,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L125
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L125
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L125:
  mov    -0x10(%rbp),%rax
  mov    $0x3,%edx
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L39
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
L39:
  addq   $0x1,-0x10(%rbp)
L75:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L98
  cmpl   $0x0,-0x1c(%rbp)
  je     L95
  jmp    L147
L71:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L147:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L95
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L71
L95:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string

tool: D20: /../

tool: D0: /./

tool: D18: /.

assistant: ```c
void simplifypath(char *path, int head) {
  char *s;
  for (s = path; *s; ++s) {
    if (strncmp(s, "/../", 4) == 0 && s != path) {
      char *end = s + 4;
      while (--s != path)
        if (*s == '/' || *s == '\\') {
          ++s;
          break;
        }
      s = strdel(s, end);
      if (s != path)
        --s;
      --s;
    }
    if (strncmp(s, "/./", 3) == 0 && s != path)
      memmove(s + 1, s + 3, strlen(s + 3) + 1);
    if (strncmp(s, "/.", 3) == 0 && s != path)
      s[1] = 0;
  }
  if (head) {
    while (path[0] == '.' && path[1] == '/')
      memmove(path, path + 2, strlen(path + 2));
  }
}
```