ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<avgDispersion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L24:
  cmpl   $0x0,-0xc(%rbp)
  je     L51
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L19
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L39
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
L39:
  add    %eax,-0x8(%rbp)
L51:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L24
  cmpl   $0x0,-0xc(%rbp)
  je     L40
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int avgDispersion(char *text) {
  int c;
  int textLen = strlen(text);
  int avg = 0;
  for (c = 0; c < textLen; c++)
    if (c)
      avg += (text[c] > text[c - 1]) ? text[c] - text[c - 1] : text[c - 1] - text[c];
  if (c)
    avg /= textLen;
  return avg + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<avgDispersion>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L38
  mov    %eax,%r9d
  mov    %eax,%r8d
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L30
L66:
  movsbl %sil,%edi
  movsbl %cl,%ecx
  sub    %ecx,%edi
L1:
  add    %edi,%eax
L68:
  add    $0x1,%rdx
L30:
  cmp    %r8,%rdx
  je     L14
  test   %edx,%edx
  je     L68
  movzbl (%rbx,%rdx,1),%ecx
  movzbl -0x1(%rbx,%rdx,1),%esi
  cmp    %sil,%cl
  jle    L66
  movsbl %cl,%edi
  movsbl %sil,%esi
  sub    %esi,%edi
  jmp    L1
L14:
  cltd
  idiv   %r9d
L27:
  add    $0x1,%eax
  pop    %rbx
  ret
L38:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
int avgDispersion(char *text) {
  int c;
  int textLen = strlen(text);
  int avg = 0;
  for (c = 0; c < textLen; c++)
    if (c)
      avg += (text[c] > text[c - 1]) ? text[c] - text[c - 1] : text[c - 1] - text[c];
  if (c)
    avg /= textLen;
  return avg + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<avgDispersion>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L26
  lea    -0x1(%rax),%r9d
  mov    %rbx,%rdi
  mov    %eax,%r11d
  xor    %eax,%eax
  add    %rbx,%r9
  cmp    %rdi,%r9
  je     L29
  nopl   (%rax)
L9:
  movsbl 0x1(%rdi),%r8d
  movsbl (%rdi),%edx
  mov    %r8d,%r10d
  mov    %edx,%ecx
  sub    %edx,%r10d
  sub    %r8d,%edx
  cmp    %cl,%r8b
  cmovg  %r10d,%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%r9
  jne    L9
L29:
  cltd
  pop    %rbx
  idiv   %r11d
  add    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int avgDispersion(char *text) {
  int c;
  int textLen = strlen(text);
  int avg = 0;
  for (c = 0; c < textLen; c++)
    if (c)
      avg += (text[c] > text[c - 1]) ? text[c] - text[c - 1] : text[c - 1] - text[c];
  if (c)
    avg /= textLen;
  return avg + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<backup_folder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <lockAllFiles@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <string_date@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D18(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x88(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x90(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <execv@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <logInfoMessage@plt>
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <unlockAllFiles@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D18: cp

tool: D38: -R

tool: D2: /bin/cp

tool: D7: backup completed

assistant: ```c
void backup_folder(char *sourceFile, char *targetFile) {
  lockAllFiles(sourceFile);
  char date[50];
  char *time_buff = string_date(date);
  strcat(targetFile, time_buff);
  char *args[] = {"cp", "-R", sourceFile, targetFile, NULL};
  execv("/bin/cp", args);
  logInfoMessage("backup completed");
  unlockAllFiles(sourceFile);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<backup_folder>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <lockAllFiles@plt>
  lea    0x30(%rsp),%rdi
  call   <string_date@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D10(%rip),%rax
  mov    %rax,(%rsp)
  lea    D11(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rbx,0x10(%rsp)
  mov    %rbp,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    %rsp,%rsi
  lea    D30(%rip),%rdi
  call   <execv@plt>
  lea    D26(%rip),%rdi
  call   <logInfoMessage@plt>
  mov    %rbx,%rdi
  call   <unlockAllFiles@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D10: cp

tool: D11: -R

tool: D30: /bin/cp

tool: D26: backup completed

assistant: ```c
void backup_folder(char *sourceFile, char *targetFile) {
  lockAllFiles(sourceFile);
  char date[50];
  char *time_buff = string_date(date);
  strcat(targetFile, time_buff);
  char *args[] = {"cp", "-R", sourceFile, targetFile, NULL};
  execv("/bin/cp", args);
  logInfoMessage("backup completed");
  unlockAllFiles(sourceFile);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<backup_folder>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <lockAllFiles@plt>
  lea    0x30(%rsp),%rdi
  call   <string_date@plt>
  mov    %rbx,%rdi
  mov    %rax,%rsi
  call   <strcat@plt>
  lea    D6(%rip),%rax
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  mov    %rax,(%rsp)
  lea    D27(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rbp,0x10(%rsp)
  mov    %rbx,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  call   <execv@plt>
  lea    D16(%rip),%rdi
  call   <logInfoMessage@plt>
  mov    %rbp,%rdi
  call   <unlockAllFiles@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D21
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string

tool: D6: cp

tool: D21: /bin/cp

tool: D27: -R

tool: D16: backup completed

assistant: ```c
void backup_folder(char *sourceFile, char *targetFile) {
  lockAllFiles(sourceFile);
  char date[50];
  char *time_buff = string_date(date);
  strcat(targetFile, time_buff);
  char *args[] = {"cp", "-R", sourceFile, targetFile, NULL};
  execv("/bin/cp", args);
  logInfoMessage("backup completed");
  unlockAllFiles(sourceFile);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<backup_folder>:
  endbr64
  push   %r12
  movq   %rsi,%xmm2
  movq   %rdi,%xmm1
  mov    %rsi,%r12
  push   %rbp
  punpcklqdq %xmm2,%xmm1
  mov    %rdi,%rbp
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movaps %xmm1,(%rsp)
  call   <lockAllFiles@plt>
  lea    0x40(%rsp),%rdi
  call   <string_date@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <strcat@plt>
  movdqa (%rsp),%xmm1
  lea    0x10(%rsp),%rsi
  lea    D18(%rip),%rdx
  lea    D31(%rip),%rax
  movq   %rdx,%xmm0
  lea    D11(%rip),%rdi
  movq   $0x0,0x30(%rsp)
  movq   %rax,%xmm3
  movaps %xmm1,0x20(%rsp)
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <execv@plt>
  lea    D12(%rip),%rdi
  call   <logInfoMessage@plt>
  mov    %rbp,%rdi
  call   <unlockAllFiles@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x88,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D31
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string

tool: D18: cp

tool: D31: -R

tool: D11: /bin/cp

tool: D12: backup completed

assistant: ```c
void backup_folder(char *sourceFile, char *targetFile) {
  lockAllFiles(sourceFile);
  char date[50];
  char *time_buff = string_date(date);
  strcat(targetFile, time_buff);
  char *args[] = {"cp", "-R", sourceFile, targetFile, NULL};
  execv("/bin/cp", args);
  logInfoMessage("backup completed");
  unlockAllFiles(sourceFile);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Dswap4B>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Dswap4B(void *val) {
  char *c = (char *)val;
  char a;
  a = c[0];
  c[0] = c[3];
  c[3] = a;
  a = c[1];
  c[1] = c[2];
  c[2] = a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Dswap4B>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x1(%rdi)
  mov    %al,0x2(%rdi)
  ret
```

assistant: ```c
void Dswap4B(void *val) {
  char *c = (char *)val;
  char a;
  a = c[0];
  c[0] = c[3];
  c[3] = a;
  a = c[1];
  c[1] = c[2];
  c[2] = a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Dswap4B>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  rolw   $0x8,0x1(%rdi)
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void Dswap4B(void *val) {
  char *c = (char *)val;
  char a;
  a = c[0];
  c[0] = c[3];
  c[3] = a;
  a = c[1];
  c[1] = c[2];
  c[2] = a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Dswap4B>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  rolw   $0x8,0x1(%rdi)
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void Dswap4B(void *val) {
  char *c = (char *)val;
  char a;
  a = c[0];
  c[0] = c[3];
  c[3] = a;
  a = c[1];
  c[1] = c[2];
  c[2] = a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_base64_decode_triple>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
L56:
  movsbl (%r12,%rbx,1),%edi
  call   <_base64_char_value@plt>
  mov    %eax,(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L56
  mov    $0x3,%eax
  mov    $0x1,%edi
  mov    $0x3,%ecx
  mov    %rsp,%rdx
  mov    $0x0,%esi
L2:
  cmpl   $0x0,(%rdx,%rax,4)
  js     L47
  mov    %esi,%edi
L43:
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L2
  test   %ecx,%ecx
  mov    $0x0,%edi
  cmovns %ecx,%edi
  mov    (%rsp),%eax
  shl    $0x6,%eax
  add    0x4(%rsp),%eax
  shl    $0x6,%eax
  add    0x8(%rsp),%eax
  shl    $0x6,%eax
  add    0xc(%rsp),%eax
  cmp    $0x2,%ecx
  jg     L33
  mov    %edi,%ecx
L72:
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  add    $0x1,%ecx
  cmp    $0x2,%ecx
  jle    L72
L33:
  mov    %edi,%esi
  sub    $0x1,%esi
  js     L15
  movslq %esi,%rsi
  add    %rbp,%rsi
  movslq %edi,%rdx
  lea    -0x2(%rbp,%rdx,1),%r8
  lea    -0x1(%rdi),%edx
  sub    %rdx,%r8
L119:
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x18,%ecx
  lea    (%rax,%rcx,1),%edx
  movzbl %dl,%edx
  sub    %ecx,%edx
  mov    %dl,(%rsi)
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  sub    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L119
  jmp    L15
L47:
  test   %edi,%edi
  je     L15
  cmpb   $0x3d,(%r12,%rax,1)
  je     L116
  mov    $0x0,%edi
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L111
  mov    %edi,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L116:
  movl   $0x0,(%rdx,%rax,4)
  sub    $0x1,%ecx
  jmp    L43
L111:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _base64_decode_triple(char quadruple[4], unsigned char *result) {
  int i, triple_value, bytes_to_decode = 3, only_equals_yet = 1;
  int char_value[4];
  for (i = 0; i < 4; i++)
    char_value[i] = _base64_char_value(quadruple[i]);
  for (i = 3; i >= 0; i--) {
    if (char_value[i] < 0) {
      if (only_equals_yet && quadruple[i] == '=') {
        char_value[i] = 0;
        bytes_to_decode--;
        continue;
      }
      return 0;
    }
    only_equals_yet = 0;
  }
  if (bytes_to_decode < 0)
    bytes_to_decode = 0;
  triple_value = char_value[0];
  triple_value *= 64;
  triple_value += char_value[1];
  triple_value *= 64;
  triple_value += char_value[2];
  triple_value *= 64;
  triple_value += char_value[3];
  for (i = bytes_to_decode; i < 3; i++)
    triple_value /= 256;
  for (i = bytes_to_decode - 1; i >= 0; i--) {
    result[i] = triple_value % 256;
    triple_value /= 256;
  }
  return bytes_to_decode;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_base64_decode_triple>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L16:
  movsbl (%r12,%rbp,1),%edi
  call   <_base64_char_value@plt>
  mov    %eax,0x0(%r13,%rbp,4)
  add    $0x1,%rbp
  cmp    $0x4,%rbp
  jne    L16
  mov    $0x3,%eax
  mov    $0x1,%ecx
  mov    $0x3,%edx
L34:
  mov    0x0(%r13,%rax,4),%esi
  test   %esi,%esi
  js     L22
  xor    %ecx,%ecx
L79:
  sub    $0x1,%rax
  jae    L34
  mov    (%rsp),%eax
  xor    %r8d,%r8d
  test   %edx,%edx
  cmovns %edx,%r8d
  shl    $0x6,%eax
  add    0x4(%rsp),%eax
  shl    $0x6,%eax
  add    0x8(%rsp),%eax
  lea    -0x1(%r8),%esi
  shl    $0x6,%eax
  add    0xc(%rsp),%eax
  cmp    $0x3,%edx
  je     L62
  mov    %r8d,%edx
  nopl   0x0(%rax,%rax,1)
L70:
  test   %eax,%eax
  lea    0xff(%rax),%ecx
  cmovs  %ecx,%eax
  add    $0x1,%edx
  sar    $0x8,%eax
  cmp    $0x3,%edx
  jne    L70
  cmp    $0xffffffff,%esi
  je     L12
L62:
  movslq %esi,%rsi
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x18,%ecx
  lea    (%rax,%rcx,1),%edx
  movzbl %dl,%edx
  sub    %ecx,%edx
  test   %eax,%eax
  mov    %dl,(%rbx,%rsi,1)
  lea    0xff(%rax),%edx
  cmovs  %edx,%eax
  sub    $0x1,%rsi
  sar    $0x8,%eax
  cmp    $0xffffffff,%esi
  jne    L25
  jmp    L18
  nopl   0x0(%rax)
L22:
  test   %ecx,%ecx
  je     L12
  cmpb   $0x3d,(%r12,%rax,1)
  je     L11
L12:
  xor    %r8d,%r8d
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  movl   $0x0,0x0(%r13,%rax,4)
  sub    $0x1,%edx
  jmp    L79
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _base64_decode_triple(char quadruple[4], unsigned char *result) {
  int i, triple_value, bytes_to_decode = 3, only_equals_yet = 1;
  int char_value[4];
  for (i = 0; i < 4; i++)
    char_value[i] = _base64_char_value(quadruple[i]);
  for (i = 3; i >= 0; i--) {
    if (char_value[i] < 0) {
      if (only_equals_yet && quadruple[i] == '=') {
        char_value[i] = 0;
        bytes_to_decode--;
        continue;
      }
      return 0;
    }
    only_equals_yet = 0;
  }
  if (bytes_to_decode < 0)
    bytes_to_decode = 0;
  triple_value = char_value[0];
  triple_value *= 64;
  triple_value += char_value[1];
  triple_value *= 64;
  triple_value += char_value[2];
  triple_value *= 64;
  triple_value += char_value[3];
  for (i = bytes_to_decode; i < 3; i++)
    triple_value /= 256;
  for (i = bytes_to_decode - 1; i >= 0; i--) {
    result[i] = triple_value % 256;
    triple_value /= 256;
  }
  return bytes_to_decode;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<array1to3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L20:
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L37:
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L42:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L42
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L37
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void array1to3(int a, int b, int c, double *y, double ***x) {
  int i, j, k, m;
  k = 0;
  for (i = 0; i < a; i++) {
    for (j = 0; j < b; j++) {
      for (m = 0; m < c; m++) {
        x[i][j][m] = y[k];
        k++;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<array1to3>:
  endbr64
  test   %edi,%edi
  jle    L38
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r9d
  mov    %esi,%ebx
  mov    %edx,%r10d
  mov    %rcx,%rbp
  mov    %r8,%rdi
  lea    -0x1(%r9),%edx
  lea    0x8(%r8,%rdx,8),%r12
  lea    -0x1(%rsi),%eax
  lea    0x8(,%rax,8),%r11
  lea    -0x1(%r10),%eax
  lea    0x8(,%rax,8),%r8
  mov    $0x0,%r9d
  jmp    L75
L72:
  movslq %r9d,%rax
  lea    0x0(%rbp,%rax,8),%rsi
  mov    $0x0,%eax
L19:
  movsd  (%rsi,%rax,1),%xmm0
  mov    (%rdi),%rdx
  mov    (%rdx,%rcx,1),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L19
  add    %r10d,%r9d
L11:
  add    $0x8,%rcx
  cmp    %r11,%rcx
  je     L28
L50:
  test   %r10d,%r10d
  jg     L72
  jmp    L11
L28:
  add    $0x8,%rdi
  cmp    %r12,%rdi
  je     L45
L75:
  mov    $0x0,%ecx
  test   %ebx,%ebx
  jg     L50
  jmp    L28
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  ret
```

assistant: ```c
void array1to3(int a, int b, int c, double *y, double ***x) {
  int i, j, k, m;
  k = 0;
  for (i = 0; i < a; i++) {
    for (j = 0; j < b; j++) {
      for (m = 0; m < c; m++) {
        x[i][j][m] = y[k];
        k++;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<array1to3>:
  endbr64
  test   %edi,%edi
  jle    L51
  mov    %edi,%eax
  push   %r12
  mov    %r8,%r10
  mov    %edx,%r9d
  sub    $0x1,%eax
  push   %rbp
  mov    %rcx,%rbp
  lea    0x8(%r8,%rax,8),%r12
  lea    -0x1(%rsi),%eax
  push   %rbx
  xor    %r8d,%r8d
  mov    %esi,%ebx
  lea    0x8(,%rax,8),%r11
  movslq %edx,%rsi
  cs nopw 0x0(%rax,%rax,1)
L34:
  xor    %edi,%edi
  test   %ebx,%ebx
  jle    L59
  cs nopw 0x0(%rax,%rax,1)
L54:
  test   %r9d,%r9d
  jle    L24
  mov    (%r10),%rax
  mov    (%rax,%rdi,1),%rcx
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,8),%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L31:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L31
  add    %r9d,%r8d
L24:
  add    $0x8,%rdi
  cmp    %r11,%rdi
  jne    L54
L59:
  add    $0x8,%r10
  cmp    %r12,%r10
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  ret
```

assistant: ```c
void array1to3(int a, int b, int c, double *y, double ***x) {
  int i, j, k, m;
  k = 0;
  for (i = 0; i < a; i++) {
    for (j = 0; j < b; j++) {
      for (m = 0; m < c; m++) {
        x[i][j][m] = y[k];
        k++;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<array1to3>:
  endbr64
  test   %edi,%edi
  jle    L48
  movslq %esi,%rax
  test   %eax,%eax
  jle    L48
  push   %r15
  mov    %edx,%r11d
  lea    -0x1(%rdi),%edx
  xor    %r9d,%r9d
  push   %r14
  lea    0x0(,%rax,8),%r14
  mov    %r11d,%eax
  push   %r13
  shr    %eax
  mov    %r8,%r13
  push   %r12
  mov    %r11d,%r12d
  lea    -0x1(%rax),%edi
  push   %rbp
  and    $0xfffffffe,%r12d
  add    $0x1,%rdi
  lea    -0x1(%r11),%ebp
  push   %rbx
  lea    0x8(%r8,%rdx,8),%rbx
  movslq %r12d,%rsi
  shl    $0x4,%rdi
  shl    $0x3,%rsi
  mov    %rbp,%r15
  mov    %rbx,-0x10(%rsp)
  nopl   0x0(%rax)
L62:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L46:
  test   %r11d,%r11d
  jle    L45
  mov    0x0(%r13),%rax
  mov    (%rax,%r8,1),%rdx
  movslq %r9d,%rax
  lea    0x8(,%rax,8),%rax
  lea    (%rcx,%rax,1),%r10
  cmp    %r10,%rdx
  je     L31
  cmp    $0x2,%r15d
  jbe    L31
  lea    -0x8(%rcx,%rax,1),%r10
  xor    %eax,%eax
  xchg   %ax,%ax
L37:
  movupd (%r10,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L37
  lea    (%r9,%r12,1),%eax
  cmp    %r12d,%r11d
  je     L49
  cltq
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rsi,1)
L49:
  add    %r11d,%r9d
L45:
  add    $0x8,%r8
  cmp    %r14,%r8
  jne    L46
  add    $0x8,%r13
  cmp    -0x10(%rsp),%r13
  jne    L62
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  lea    -0x8(%rcx,%rax,1),%rbx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  movsd  (%rbx,%rax,8),%xmm0
  mov    %rax,%r10
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %r10,%rbp
  jne    L27
  jmp    L49
L48:
  ret
```

assistant: ```c
void array1to3(int a, int b, int c, double *y, double ***x) {
  int i, j, k, m;
  k = 0;
  for (i = 0; i < a; i++) {
    for (j = 0; j < b; j++) {
      for (m = 0; m < c; m++) {
        x[i][j][m] = y[k];
        k++;
      }
    }
  }
}
```