ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_result_phase_I>:
  endbr64
  push   %r15
  movslq %esi,%rax
  movslq %edx,%rdx
  mov    %rdi,%r15
  push   %r14
  mov    %rax,%r14
  push   %r13
  push   %r12
  lea    0x0(,%rdx,8),%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    (%rdi,%rax,8),%rax
  lea    D27(%rip),%rdi
  mov    %rcx,(%rsp)
  cvttsd2si (%rax,%rdx,8),%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L82
  lea    -0x1(%r14),%eax
  xor    %ebp,%ebp
  lea    D19(%rip),%r13
  mov    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  jmp    L73
  nopl   0x0(%rax)
L40:
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L8
L73:
  mov    (%rbx,%rbp,4),%esi
  lea    -0x14(%rsi),%eax
  cmp    $0x9,%eax
  ja     L40
  mov    (%r15,%rbp,8),%rax
  mov    %esi,%ecx
  mov    %r13,%rdi
  add    $0x1,%rbp
  sar    $0x1f,%ecx
  movsd  (%rax,%r12,1),%xmm0
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  add    $0x1,%esi
  call   <printf@plt>
  cmp    %rbp,%r14
  jne    L73
L8:
  mov    (%rsp),%rbx
  mov    0x8(%rsp),%rax
  lea    D19(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L68:
  add    $0x4,%rbx
  cmp    %rbx,%r12
  je     L82
L33:
  mov    (%rbx),%esi
  lea    -0x14(%rsi),%eax
  cmp    $0x9,%eax
  ja     L68
  movslq %esi,%rax
  mov    %esi,%edx
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  add    $0x4,%rbx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  add    $0x1,%esi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L33
L82:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D27
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D27: The maximum solution occurs at Z=%lf with


tool: D19: Z%d=%lf	

assistant: ```c
void print_result_phase_I(double **T, int no_of_eqns, int no_of_variables, int *column, int *row) {
  int i;
  printf("The maximum solution occurs at Z=%lf with\n", T[no_of_eqns][no_of_variables]);
  for (i = 0; i < no_of_eqns; i++) {
    if (row[i] / 10 == 2) {
      printf("Z%d=%lf\t", (row[i] % 10) + 1, T[i][no_of_variables]);
    }
  }
  for (i = 0; i < no_of_eqns; i++) {
    if (column[i] / 10 == 2) {
      printf("Z%d=%lf\t", (column[i] % 10) + 1, 0.00);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_path_equals_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D49(%rip),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <ct_path_alloc@plt>
  mov    %rax,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <ct_path_alloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <ct_path_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ct_path_equals_path@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ct_path_equals_path@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ct_path_free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ct_path_free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ct_path_free@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D49
type_guessed: string
name: extract_symbolic_data
arguments: label: D53
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D56
type_guessed: string
name: extract_symbolic_data
arguments: label: D18
type_guessed: string

tool: D49: foo

tool: D53: /tmp

tool: D2: /tmp/foo

tool: D56: /var

tool: D18: bar

assistant: ```c
void test_path_equals_path(void) {
  struct ct_path *path1 = ct_path_alloc("/tmp", "foo");
  struct ct_path *path2 = ct_path_alloc("/var", "/tmp/foo");
  struct ct_path *path3 = ct_path_alloc("/tmp", "bar");
  assert(ct_path_equals_path(path1, path1));
  assert(ct_path_equals_path(path2, path2));
  assert(ct_path_equals_path(path1, path2));
  assert(ct_path_equals_path(path2, path1));
  assert(!ct_path_equals_path(path1, path3));
  assert(!ct_path_equals_path(path3, path1));
  ct_path_free(path3);
  ct_path_free(path2);
  ct_path_free(path1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_path_equals_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D30(%rip),%rsi
  lea    D41(%rip),%r12
  mov    %r12,%rdi
  call   <ct_path_alloc@plt>
  mov    %rax,%rbx
  lea    D23(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <ct_path_alloc@plt>
  mov    %rax,%rbp
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  call   <ct_path_alloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ct_path_equals_path@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <ct_path_equals_path@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rdi
  call   <ct_path_free@plt>
  mov    %rbp,%rdi
  call   <ct_path_free@plt>
  mov    %rbx,%rdi
  call   <ct_path_free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D30
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string
name: parse_data
arguments: data_label: D23
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string

tool: D30: foo

tool: D41: /tmp

tool: D23: /tmp/foo

tool: D12: /var

tool: D21: bar

assistant: ```c
void test_path_equals_path(void) {
  struct ct_path *path1 = ct_path_alloc("/tmp", "foo");
  struct ct_path *path2 = ct_path_alloc("/var", "/tmp/foo");
  struct ct_path *path3 = ct_path_alloc("/tmp", "bar");
  assert(ct_path_equals_path(path1, path1));
  assert(ct_path_equals_path(path2, path2));
  assert(ct_path_equals_path(path1, path2));
  assert(ct_path_equals_path(path2, path1));
  assert(!ct_path_equals_path(path1, path3));
  assert(!ct_path_equals_path(path3, path1));
  ct_path_free(path3);
  ct_path_free(path2);
  ct_path_free(path1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_path_equals_path>:
  endbr64
  push   %r13
  lea    D15(%rip),%r13
  lea    D26(%rip),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  call   <ct_path_alloc@plt>
  lea    D9(%rip),%rsi
  lea    D22(%rip),%rdi
  mov    %rax,%rbp
  call   <ct_path_alloc@plt>
  mov    %r13,%rdi
  lea    D6(%rip),%rsi
  mov    %rax,%r12
  call   <ct_path_alloc@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <ct_path_equals_path@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ct_path_equals_path@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdi
  call   <ct_path_free@plt>
  mov    %r12,%rdi
  call   <ct_path_free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <ct_path_free@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D6
type_guessed: string

tool: D15: /tmp

tool: D26: foo

tool: D9: /tmp/foo

tool: D22: /var

tool: D6: bar

assistant: ```c
void test_path_equals_path(void) {
  struct ct_path *path1 = ct_path_alloc("/tmp", "foo");
  struct ct_path *path2 = ct_path_alloc("/var", "/tmp/foo");
  struct ct_path *path3 = ct_path_alloc("/tmp", "bar");
  assert(ct_path_equals_path(path1, path1));
  assert(ct_path_equals_path(path2, path2));
  assert(ct_path_equals_path(path1, path2));
  assert(ct_path_equals_path(path2, path1));
  assert(!ct_path_equals_path(path1, path3));
  assert(!ct_path_equals_path(path3, path1));
  ct_path_free(path3);
  ct_path_free(path2);
  ct_path_free(path1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_path_equals_path>:
  endbr64
  push   %r13
  lea    D30(%rip),%r13
  lea    D17(%rip),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  call   <ct_path_alloc@plt>
  lea    D41(%rip),%rsi
  lea    D29(%rip),%rdi
  mov    %rax,%rbp
  call   <ct_path_alloc@plt>
  mov    %r13,%rdi
  lea    D18(%rip),%rsi
  mov    %rax,%r12
  call   <ct_path_alloc@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ct_path_equals_path@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <ct_path_equals_path@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ct_path_equals_path@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdi
  call   <ct_path_free@plt>
  mov    %r12,%rdi
  call   <ct_path_free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <ct_path_free@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
type: string
name: retrieve_data
arguments: data_label: D17
type: string
name: retrieve_data
arguments: data_label: D41
type: string
name: retrieve_data
arguments: data_label: D29
type: string
name: retrieve_data
arguments: data_label: D18
type: string

tool: D30: /tmp

tool: D17: foo

tool: D41: /tmp/foo

tool: D29: /var

tool: D18: bar

assistant: ```c
void test_path_equals_path(void) {
  struct ct_path *path1 = ct_path_alloc("/tmp", "foo");
  struct ct_path *path2 = ct_path_alloc("/var", "/tmp/foo");
  struct ct_path *path3 = ct_path_alloc("/tmp", "bar");
  assert(ct_path_equals_path(path1, path1));
  assert(ct_path_equals_path(path2, path2));
  assert(ct_path_equals_path(path1, path2));
  assert(ct_path_equals_path(path2, path1));
  assert(!ct_path_equals_path(path1, path3));
  assert(!ct_path_equals_path(path3, path1));
  ct_path_free(path3);
  ct_path_free(path2);
  ct_path_free(path1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  jmp    L9
L6:
  addl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
L9:
  cmpb   $0xa,-0x5(%rbp)
  jne    L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D6
type: string

tool: D17: Enter a message: 

tool: D6: Your message is %d character(s) long.


assistant: ```c
int main(void) {
  char ch;
  int len = 0;
  printf("Enter a message: ");
  ch = getchar();
  while (ch != '\n') {
    len++;
    ch = getchar();
  }
  printf("Your message is %d character(s) long.\n", len);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L21
  mov    $0x0,%ebx
L0:
  add    $0x1,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
L24:
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L21:
  mov    $0x0,%ebx
  jmp    L24
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string

tool: D11: Enter a message: 

tool: D10: Your message is %d character(s) long.


assistant: ```c
int main(void) {
  char ch;
  int len = 0;
  printf("Enter a message: ");
  ch = getchar();
  while (ch != '\n') {
    len++;
    ch = getchar();
  }
  printf("Your message is %d character(s) long.\n", len);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L6
L13:
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L13
L6:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D19: Enter a message: 

tool: D7: Your message is %d character(s) long.


assistant: ```c
int main(void) {
  char ch;
  int len = 0;
  printf("Enter a message: ");
  ch = getchar();
  while (ch != '\n') {
    len++;
    ch = getchar();
  }
  printf("Your message is %d character(s) long.\n", len);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L6
L10:
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L10
L6:
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D10
type_infered: string

tool: D15: Enter a message: 

tool: D10: Your message is %d character(s) long.


assistant: ```c
int main(void) {
  char ch;
  int len = 0;
  printf("Enter a message: ");
  ch = getchar();
  while (ch != '\n') {
    len++;
    ch = getchar();
  }
  printf("Your message is %d character(s) long.\n", len);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<create_drive_arc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    $0x89,%edi
  call   <create_write_byte@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L6
  mov    -0x4(%rbp),%eax
  neg    %eax
  shr    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <create_write_byte@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <create_write_byte@plt>
  jmp    L9
L6:
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <create_write_byte@plt>
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <create_write_byte@plt>
L9:
  mov    -0x8(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <create_write_byte@plt>
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <create_write_byte@plt>
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <create_wait_theta@plt>
  nop
  leave
  ret
```

assistant: ```c
void create_drive_arc(unsigned int speed, int radius, float angle) {
  ;
  create_write_byte(137);
  if ((radius * angle) < 0) {
    create_write_byte(((-1 * speed & 0xFFFF) >> 8));
    create_write_byte((-1 * speed & 0xFF));
  } else {
    create_write_byte(((speed & 0xFFFF) >> 8));
    create_write_byte((speed & 0xFF));
  }
  create_write_byte(((radius & 0xFFFF) >> 8));
  create_write_byte((radius & 0xFF));
  ;
  create_wait_theta(angle);
}
```
user: What is the c source code of the assembly code below?

```asm
<create_drive_arc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  movss  %xmm0,0xc(%rsp)
  mov    $0x89,%edi
  call   <create_write_byte@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  mulss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L13
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <create_write_byte@plt>
  movzbl %bpl,%edi
  call   <create_write_byte@plt>
L7:
  movzbl %bh,%edi
  call   <create_write_byte@plt>
  movzbl %bl,%edi
  call   <create_write_byte@plt>
  movss  0xc(%rsp),%xmm0
  call   <create_wait_theta@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  neg    %ebp
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <create_write_byte@plt>
  movzbl %bpl,%edi
  call   <create_write_byte@plt>
  jmp    L7
```

assistant: ```c
void create_drive_arc(unsigned int speed, int radius, float angle) {
  ;
  create_write_byte(137);
  if ((radius * angle) < 0) {
    create_write_byte(((-1 * speed & 0xFFFF) >> 8));
    create_write_byte((-1 * speed & 0xFF));
  } else {
    create_write_byte(((speed & 0xFFFF) >> 8));
    create_write_byte((speed & 0xFF));
  }
  create_write_byte(((radius & 0xFFFF) >> 8));
  create_write_byte((radius & 0xFF));
  ;
  create_wait_theta(angle);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<create_drive_arc>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x89,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <create_write_byte@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm0
  mulss  0xc(%rsp),%xmm0
  comiss %xmm0,%xmm1
  jbe    L7
  neg    %ebp
L7:
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <create_write_byte@plt>
  movzbl %bpl,%edi
  call   <create_write_byte@plt>
  movzbl %bh,%edi
  call   <create_write_byte@plt>
  movzbl %bl,%edi
  call   <create_write_byte@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <create_wait_theta@plt>
```

assistant: ```c
void create_drive_arc(unsigned int speed, int radius, float angle) {
  ;
  create_write_byte(137);
  if ((radius * angle) < 0) {
    create_write_byte(((-1 * speed & 0xFFFF) >> 8));
    create_write_byte((-1 * speed & 0xFF));
  } else {
    create_write_byte(((speed & 0xFFFF) >> 8));
    create_write_byte((speed & 0xFF));
  }
  create_write_byte(((radius & 0xFFFF) >> 8));
  create_write_byte((radius & 0xFF));
  ;
  create_wait_theta(angle);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<create_drive_arc>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x89,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <create_write_byte@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm0
  mulss  0xc(%rsp),%xmm0
  comiss %xmm0,%xmm1
  jbe    L8
  neg    %ebp
L8:
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <create_write_byte@plt>
  movzbl %bpl,%edi
  call   <create_write_byte@plt>
  movzbl %bh,%edi
  call   <create_write_byte@plt>
  movzbl %bl,%edi
  call   <create_write_byte@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <create_wait_theta@plt>
```

assistant: ```c
void create_drive_arc(unsigned int speed, int radius, float angle) {
  ;
  create_write_byte(137);
  if ((radius * angle) < 0) {
    create_write_byte(((-1 * speed & 0xFFFF) >> 8));
    create_write_byte((-1 * speed & 0xFF));
  } else {
    create_write_byte(((speed & 0xFFFF) >> 8));
    create_write_byte((speed & 0xFF));
  }
  create_write_byte(((radius & 0xFFFF) >> 8));
  create_write_byte((radius & 0xFF));
  ;
  create_wait_theta(angle);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ru>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L13
  mov    $0x1,%eax
  jmp    L2
L13:
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int ru(int num) {
  if (num % 2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ru>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int ru(int num) {
  if (num % 2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x10(%rbp)
L37:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L6
L31:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jle    L9
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L51
L9:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L51:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0x14(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L31
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D21
type: string
name: read_data
arguments: label: D10
type: string
name: read_data
arguments: label: D27
type: string

tool: D0: Dwse neo arithmo

tool: D21: %d

tool: D10: H antistrofi dyadiki anaparastasi tou %d einai: 

tool: D27: Lathos epilogi


assistant: ```c
int main() {
  int n, d;
  const a = 2;
  do {
    printf("Dwse neo arithmo\n");
    scanf("%d", &n);
    d = getchar();
    printf("H antistrofi dyadiki anaparastasi tou %d einai: ", n);
    for (n = n; n > 0; n = n / a) {
      d = n % a;
      n > 0 ? putchar(d) : printf("Lathos epilogi\n");
    }
  } while (n != 0);
}
```