ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<mult>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  sub    $0x10,%rsp
  lea    0xc(%rsp),%rbp
  mov    %edi,0xc(%rsp)
  mov    $0xa,%edi
  call   <__CrestCall@plt>
  mov    %rbp,%rsi
  mov    $0x9,%edi
  call   <__CrestStore@plt>
  mov    $0x6,%edx
  xor    %esi,%esi
  mov    $0xd,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <__CrestLoad@plt>
  mov    0xc(%rsp),%eax
  mov    $0x2,%esi
  mov    $0xb,%edi
  lea    (%rax,%rax,2),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  call   <__CrestApply2@plt>
  mov    %rbp,%rsi
  mov    $0xe,%edi
  call   <__CrestStore@plt>
  mov    0xc(%rsp),%eax
  mov    %rbp,%rsi
  mov    $0xf,%edi
  lea    (%rax,%rax,2),%edx
  add    %edx,%edx
  mov    %edx,0xc(%rsp)
  movslq %edx,%rdx
  call   <__CrestLoad@plt>
  mov    0xc(%rsp),%edi
  call   <inc@plt>
  mov    $0x11,%edi
  movslq %eax,%rsi
  mov    %eax,0xc(%rsp)
  call   <__CrestHandleReturn@plt>
  mov    %rbp,%rsi
  mov    $0x10,%edi
  call   <__CrestStore@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x12,%edi
  call   <__CrestLoad@plt>
  mov    $0x13,%edi
  call   <__CrestReturn@plt>
  mov    0xc(%rsp),%eax
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
int mult(int y) {
  {
    __CrestCall(10, 2);
    __CrestStore(9, (unsigned long)(&y));
    __CrestLoad(13, (unsigned long)0, (long long)6);
    __CrestLoad(12, (unsigned long)(&y), (long long)y);
    __CrestApply2(11, 2, (long long)(6 * y));
    __CrestStore(14, (unsigned long)(&y));
    y = 6 * y;
    __CrestLoad(15, (unsigned long)(&y), (long long)y);
    y = inc(y);
    __CrestHandleReturn(17, (long long)y);
    __CrestStore(16, (unsigned long)(&y));
    {
      __CrestLoad(18, (unsigned long)(&y), (long long)y);
      __CrestReturn(19);
      return (y);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_173_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_173_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & *D;
  stk2 = T | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_173_0_0>:
  endbr64
  and    (%rdi),%sil
  or     %edx,%esi
  xor    (%rdi),%sil
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_173_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & *D;
  stk2 = T | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_173_0_0>:
  endbr64
  and    (%rdi),%sil
  or     %edx,%esi
  xor    (%rdi),%sil
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_173_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & *D;
  stk2 = T | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_173_0_0>:
  endbr64
  and    (%rdi),%sil
  or     %edx,%esi
  xor    (%rdi),%sil
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_173_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & *D;
  stk2 = T | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ompx_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void ompx_free(void **ptrs) {
#pragma omp parallel shared(ptrs)
  {
    int me = omp_get_thread_num();
    free(ptrs[me]);
  }
  free(ptrs);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ompx_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  cltq
  mov    (%rbx,%rax,8),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ompx_free(void **ptrs) {
#pragma omp parallel shared(ptrs)
  {
    int me = omp_get_thread_num();
    free(ptrs[me]);
  }
  free(ptrs);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ompx_free>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <omp_get_thread_num@plt>
  cltq
  mov    0x0(%rbp,%rax,8),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void ompx_free(void **ptrs) {
#pragma omp parallel shared(ptrs)
  {
    int me = omp_get_thread_num();
    free(ptrs[me]);
  }
  free(ptrs);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ompx_free>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <omp_get_thread_num@plt>
  cltq
  mov    0x0(%rbp,%rax,8),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void ompx_free(void **ptrs) {
#pragma omp parallel shared(ptrs)
  {
    int me = omp_get_thread_num();
    free(ptrs[me]);
  }
  free(ptrs);
}
```
user: What is the c source code of the assembly code below:

```asm
<test_utils>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_utils_strncpy_basic@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_overflow@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_1@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_0@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_concat@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_concat_loop@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: All utils tests passed!


assistant: ```c
void test_utils(void) {
  test_utils_strncpy_basic();
  test_utils_strncpy_overflow();
  test_utils_strncpy_1();
  test_utils_strncpy_0();
  test_utils_strncpy_concat();
  test_utils_strncpy_concat_loop();
  printf("All utils tests passed!\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_utils>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_utils_strncpy_basic@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_overflow@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_1@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_0@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_concat@plt>
  mov    $0x0,%eax
  call   <test_utils_strncpy_concat_loop@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: All utils tests passed!


assistant: ```c
void test_utils(void) {
  test_utils_strncpy_basic();
  test_utils_strncpy_overflow();
  test_utils_strncpy_1();
  test_utils_strncpy_0();
  test_utils_strncpy_concat();
  test_utils_strncpy_concat_loop();
  printf("All utils tests passed!\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_utils>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_utils_strncpy_basic@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_overflow@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_1@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_0@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_concat@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_concat_loop@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    10c0 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: All utils tests passed!


assistant: ```c
void test_utils(void) {
  test_utils_strncpy_basic();
  test_utils_strncpy_overflow();
  test_utils_strncpy_1();
  test_utils_strncpy_0();
  test_utils_strncpy_concat();
  test_utils_strncpy_concat_loop();
  printf("All utils tests passed!\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_utils>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_utils_strncpy_basic@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_overflow@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_1@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_0@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_concat@plt>
  xor    %eax,%eax
  call   <test_utils_strncpy_concat_loop@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    10c0 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: All utils tests passed!


assistant: ```c
void test_utils(void) {
  test_utils_strncpy_basic();
  test_utils_strncpy_overflow();
  test_utils_strncpy_1();
  test_utils_strncpy_0();
  test_utils_strncpy_concat();
  test_utils_strncpy_concat_loop();
  printf("All utils tests passed!\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverse_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x18000(%rsp),%r11
L54:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L54
  sub    $0x6d0,%rsp
  mov    %rdi,-0x186c8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x186bc(%rbp)
  movl   $0x0,-0x186b8(%rbp)
  movl   $0x0,-0x186b4(%rbp)
  lea    -0x186b0(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_string@plt>
  mov    -0x186c8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x186b4(%rbp)
  jmp    L29
L47:
  mov    -0x186bc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x186c8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x186bc(%rbp),%eax
  cltq
  mov    %dl,-0x186b0(%rbp,%rax,1)
  addl   $0x1,-0x186bc(%rbp)
L29:
  mov    -0x186bc(%rbp),%eax
  cmp    -0x186b4(%rbp),%eax
  jl     L47
  mov    -0x186c8(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_string@plt>
  mov    -0x186b4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x186b8(%rbp)
  movl   $0x0,-0x186bc(%rbp)
  jmp    L37
L38:
  mov    -0x186bc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x186c8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x186b8(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x186bc(%rbp)
  subl   $0x1,-0x186b8(%rbp)
L37:
  mov    -0x186bc(%rbp),%eax
  cmp    -0x186b4(%rbp),%eax
  jl     L38
  addl   $0x1,-0x186bc(%rbp)
  mov    -0x186bc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x186c8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void reverse_string(char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  char string_tmp[100000];
  clear_string(string_tmp);
  len = strlen(string);
  while (i < len) {
    string_tmp[i] = string[i];
    i++;
  };
  clear_string(string);
  j = len - 1;
  i = 0;
  while (i < len) {
    string[i] = string_tmp[j];
    i++;
    j--;
  };
  i++;
  string[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L35:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L35
  sub    $0x6b0,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <clear_string@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L31
  mov    %eax,%ebp
  lea    -0x1(%rax),%r12d
  mov    %eax,%ecx
  mov    $0x0,%eax
L24:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L24
  mov    %rbx,%rdi
  call   <clear_string@plt>
  movslq %ebp,%rcx
  lea    (%rsp,%rcx,1),%rax
  mov    %rbx,%rdx
  lea    -0x1(%rsp,%rcx,1),%rsi
  sub    %r12,%rsi
L33:
  movzbl -0x1(%rax),%ecx
  mov    %cl,(%rdx)
  sub    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L33
L52:
  add    $0x1,%ebp
  movslq %ebp,%rbp
  movb   $0x0,(%rbx,%rbp,1)
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x186b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    %rbx,%rdi
  call   <clear_string@plt>
  mov    $0x0,%ebp
  jmp    L52
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reverse_string(char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  char string_tmp[100000];
  clear_string(string_tmp);
  len = strlen(string);
  while (i < len) {
    string_tmp[i] = string[i];
    i++;
  };
  clear_string(string);
  j = len - 1;
  i = 0;
  while (i < len) {
    string[i] = string_tmp[j];
    i++;
    j--;
  };
  i++;
  string[i] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L45:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L45
  sub    $0x6b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <clear_string@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L29
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <clear_string@plt>
  movslq %ebx,%rax
  lea    -0x1(%rbx),%ecx
  lea    -0x1(%r12,%rax,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rsi
  mov    %rbp,%rax
  nop
L36:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L36
  add    $0x1,%ebx
  movslq %ebx,%rbx
L3:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x186b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L29:
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  call   <clear_string@plt>
  jmp    L3
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reverse_string(char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  char string_tmp[100000];
  clear_string(string_tmp);
  len = strlen(string);
  while (i < len) {
    string_tmp[i] = string[i];
    i++;
  };
  clear_string(string);
  j = len - 1;
  i = 0;
  while (i < len) {
    string[i] = string_tmp[j];
    i++;
    j--;
  };
  i++;
  string[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L10:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L10
  sub    $0x6b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <clear_string@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L43
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <clear_string@plt>
  movslq %ebx,%rax
  lea    -0x1(%rbx),%ecx
  lea    -0x1(%r12,%rax,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rsi
  mov    %rbp,%rax
  nop
L48:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rax,%rsi
  jne    L48
  add    $0x1,%ebx
  movslq %ebx,%rbx
L5:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x186b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L43:
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  call   <clear_string@plt>
  jmp    L5
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reverse_string(char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  char string_tmp[100000];
  clear_string(string_tmp);
  len = strlen(string);
  while (i < len) {
    string_tmp[i] = string[i];
    i++;
  };
  clear_string(string);
  j = len - 1;
  i = 0;
  while (i < len) {
    string[i] = string_tmp[j];
    i++;
    j--;
  };
  i++;
  string[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%rbp
  mov    %r8,%r15
  mov    %r9,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    0xa8(%rsp),%rsi
  mov    0xb0(%rsp),%rdi
  call   <morus_initialization@plt>
  cmp    $0x1f,%r12
  jbe    L91
  mov    $0x20,%ebx
  lea    0x10(%rsp),%rax
  mov    %rax,(%rsp)
L82:
  lea    0x30(%rsp),%rsi
  lea    -0x20(%r15,%rbx,1),%rdi
  mov    (%rsp),%rdx
  call   <morus_enc_aut_step@plt>
  mov    %rbx,%rax
  add    $0x20,%rbx
  cmp    %rbx,%r12
  jae    L82
L11:
  mov    %r12,%rdx
  and    $0x1f,%edx
  jne    L38
L98:
  cmp    $0x1f,%rbp
  jbe    L97
  mov    $0x20,%ebx
  lea    0x10(%rsp),%r15
L8:
  lea    -0x20(%r13,%rbx,1),%rsi
  lea    -0x20(%r14,%rbx,1),%rdi
  mov    %r15,%rdx
  call   <morus_enc_aut_step@plt>
  mov    %rbx,%rax
  add    $0x20,%rbx
  cmp    %rbx,%rbp
  jae    L8
L46:
  mov    %rbp,%rdx
  and    $0x1f,%edx
  jne    L75
L107:
  lea    0x10(%rsp),%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <morus_tag_generation@plt>
  add    $0x10,%rbp
  mov    0x8(%rsp),%rax
  mov    %rbp,(%rax)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L91:
  mov    $0x0,%eax
  jmp    L11
L38:
  lea    0x10(%rsp),%rcx
  lea    0x30(%rsp),%rsi
  lea    (%r15,%rax,1),%rdi
  call   <morus_enc_aut_partialblock@plt>
  jmp    L98
L97:
  mov    $0x0,%eax
  jmp    L46
L75:
  lea    0x10(%rsp),%rcx
  lea    0x0(%r13,%rax,1),%rsi
  lea    (%r14,%rax,1),%rdi
  call   <morus_enc_aut_partialblock@plt>
  jmp    L107
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  unsigned long long i, j;
  unsigned char ciphertextblock[32];
  __m256i morus_state[5];
  morus_initialization(k, npub, morus_state);
  for (i = 0; (i + 32) <= adlen; i += 32) {
    morus_enc_aut_step(ad + i, ciphertextblock, morus_state);
  }
  if ((adlen & 0x1f) != 0) {
    morus_enc_aut_partialblock(ad + i, ciphertextblock, adlen & 0x1f, morus_state);
  }
  for (i = 0; (i + 32) <= mlen; i += 32) {
    morus_enc_aut_step(m + i, c + i, morus_state);
  }
  if ((mlen & 0x1f) != 0) {
    morus_enc_aut_partialblock(m + i, c + i, mlen & 0x1f, morus_state);
  }
  morus_tag_generation(mlen, adlen, c, morus_state);
  *clen = mlen + 16;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x78,%rsp
  mov    %rdi,(%rsp)
  lea    0x20(%rsp),%r14
  mov    0xc0(%rsp),%rdi
  mov    %rsi,0x10(%rsp)
  mov    0xb8(%rsp),%rsi
  mov    %rdx,0x8(%rsp)
  mov    %r14,%rdx
  mov    %r8,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <morus_initialization@plt>
  cmp    $0x1f,%rbp
  jbe    L106
  mov    $0x20,%r15d
  lea    0x40(%rsp),%r13
  sub    $0x20,%r12
  nopl   0x0(%rax)
L60:
  lea    (%r12,%r15,1),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <morus_enc_aut_step@plt>
  mov    %r15,%rax
  add    $0x20,%r15
  cmp    %r15,%rbp
  jae    L60
L79:
  mov    %rbp,%rdx
  and    $0x1f,%edx
  jne    L49
  cmp    $0x1f,%rbx
  jbe    L30
L18:
  mov    (%rsp),%rax
  mov    $0x20,%r15d
  lea    -0x20(%rax),%r13
  mov    0x8(%rsp),%rax
  lea    -0x20(%rax),%r12
L96:
  lea    0x0(%r13,%r15,1),%rsi
  lea    (%r12,%r15,1),%rdi
  mov    %r14,%rdx
  call   <morus_enc_aut_step@plt>
  mov    %r15,%rax
  add    $0x20,%r15
  cmp    %rbx,%r15
  jbe    L96
  mov    %rbx,%rdx
  and    $0x1f,%edx
  jne    L32
L84:
  mov    (%rsp),%rdx
  mov    %rbx,%rdi
  mov    %r14,%rcx
  mov    %rbp,%rsi
  add    $0x10,%rbx
  call   <morus_tag_generation@plt>
  mov    0x10(%rsp),%rax
  mov    %rbx,(%rax)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  mov    0x18(%rsp),%rdi
  lea    0x40(%rsp),%rsi
  mov    %r14,%rcx
  add    %rax,%rdi
  call   <morus_enc_aut_partialblock@plt>
  cmp    $0x1f,%rbx
  ja     L18
L30:
  mov    %rbx,%rdx
  xor    %eax,%eax
  and    $0x1f,%edx
  je     L84
  nopl   0x0(%rax)
L32:
  mov    (%rsp),%rcx
  mov    0x8(%rsp),%rdi
  lea    (%rcx,%rax,1),%rsi
  add    %rax,%rdi
  mov    %r14,%rcx
  call   <morus_enc_aut_partialblock@plt>
  jmp    L84
  nopl   (%rax)
L106:
  xor    %eax,%eax
  jmp    L79
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  unsigned long long i, j;
  unsigned char ciphertextblock[32];
  __m256i morus_state[5];
  morus_initialization(k, npub, morus_state);
  for (i = 0; (i + 32) <= adlen; i += 32) {
    morus_enc_aut_step(ad + i, ciphertextblock, morus_state);
  }
  if ((adlen & 0x1f) != 0) {
    morus_enc_aut_partialblock(ad + i, ciphertextblock, adlen & 0x1f, morus_state);
  }
  for (i = 0; (i + 32) <= mlen; i += 32) {
    morus_enc_aut_step(m + i, c + i, morus_state);
  }
  if ((mlen & 0x1f) != 0) {
    morus_enc_aut_partialblock(m + i, c + i, mlen & 0x1f, morus_state);
  }
  morus_tag_generation(mlen, adlen, c, morus_state);
  *clen = mlen + 16;
  return 0;
}
```