ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<randdir>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L55
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L48
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L48
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <quickcat@plt>
  mov    %rax,%rbp
  jmp    L26
  nopl   (%rax)
L48:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
L26:
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <rand@plt>
  mov    %r12,%rdi
  lea    D0(%rip),%rsi
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <quickcat@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L55:
  xor    %r12d,%r12d
  jmp    L38
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string
name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D8: /

tool: D0: dir%05d

assistant: ```c
char *randdir(const char *root) {
  char *slashdir, name[16], *dir;
  if (!root)
    return NULL;
  if (strlen(root) > 0 && root[strlen(root) - 1] != '/')
    slashdir = quickcat(root, "/");
  else
    slashdir = strdup(root);
  sprintf(name, "dir%05d", rand());
  dir = quickcat(slashdir, name);
  free(slashdir);
  return dir;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<randdir>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L44
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L29
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L29
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <quickcat@plt>
  mov    %rax,%rbp
  jmp    L48
  nopl   (%rax)
L29:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
L48:
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <rand@plt>
  mov    %r12,%rdi
  lea    D5(%rip),%rsi
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <quickcat@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L44:
  xor    %r12d,%r12d
  jmp    L4
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D5
type: string

tool: D11: /

tool: D5: dir%05d

assistant: ```c
char *randdir(const char *root) {
  char *slashdir, name[16], *dir;
  if (!root)
    return NULL;
  if (strlen(root) > 0 && root[strlen(root) - 1] != '/')
    slashdir = quickcat(root, "/");
  else
    slashdir = strdup(root);
  sprintf(name, "dir%05d", rand());
  dir = quickcat(slashdir, name);
  free(slashdir);
  return dir;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zero_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L24:
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L37:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L37
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero_matrix(int **matrix, int N, int M) {
  int i = 0, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      matrix[i][j] = 0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zero_matrix>:
  endbr64
  test   %esi,%esi
  jle    L39
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  lea    -0x1(%rdx),%eax
  lea    0x4(,%rax,4),%rsi
  jmp    L2
L36:
  mov    (%r8),%rcx
  movl   $0x0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L36
L29:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L39
L2:
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L36
  jmp    L29
L39:
  ret
```

assistant: ```c
void zero_matrix(int **matrix, int N, int M) {
  int i = 0, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      matrix[i][j] = 0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zero_matrix>:
  endbr64
  test   %esi,%esi
  jle    L25
  push   %r13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  lea    -0x1(%rdx),%eax
  push   %rbp
  lea    0x4(,%rax,4),%r13
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L19:
  test   %ebp,%ebp
  jle    L1
  mov    (%rbx),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L1:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  ret
```

assistant: ```c
void zero_matrix(int **matrix, int N, int M) {
  int i = 0, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      matrix[i][j] = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<zero_matrix>:
  endbr64
  test   %esi,%esi
  jle    L4
  test   %edx,%edx
  jle    L4
  lea    -0x1(%rsi),%eax
  movslq %edx,%rdx
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    0x0(,%rdx,4),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %rbx,%r12
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void zero_matrix(int **matrix, int N, int M) {
  int i = 0, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      matrix[i][j] = 0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ABS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L5
  movsd  -0x8(%rbp),%xmm0
  jmp    L1
L5:
  movsd  -0x8(%rbp),%xmm0
  movq   D4(%rip),%xmm1
  xorpd  %xmm1,%xmm0
L1:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double ABS(double number) {
  if (number >= 0) {
    return number;
  } else {
    return -1 * number;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putendl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L12
L8:
  nop
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: 


assistant: ```c
void ft_putendl(char const *s) {
  if (!s)
    return;
  write(1, s, ft_strlen(s));
  write(1, "\n", 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_putendl>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  pop    %rbx
  ret
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: 


assistant: ```c
void ft_putendl(char const *s) {
  if (!s)
    return;
  write(1, s, ft_strlen(s));
  write(1, "\n", 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_putendl>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x1,%edx
  mov    $0x1,%edi
  pop    %rbp
  lea    D3(%rip),%rsi
  jmp    1060 <write@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: 


assistant: ```c
void ft_putendl(char const *s) {
  if (!s)
    return;
  write(1, s, ft_strlen(s));
  write(1, "\n", 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_putendl>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x1,%edx
  mov    $0x1,%edi
  pop    %rbp
  lea    D3(%rip),%rsi
  jmp    1060 <write@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: 


assistant: ```c
void ft_putendl(char const *s) {
  if (!s)
    return;
  write(1, s, ft_strlen(s));
  write(1, "\n", 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x49(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x44(%rbp)
  jmp    L21
L9:
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  mov    %al,-0x49(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%edx
  mov    -0x48(%rbp),%eax
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x49(%rbp),%edx
  mov    %dl,-0x40(%rbp,%rax,1)
  addl   $0x1,-0x48(%rbp)
  subl   $0x1,-0x44(%rbp)
L21:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L9
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: %s

assistant: ```c
int main() {
  char str[50], rts = 0;
  int k = 0, n = 0;
  scanf("%s", str);
  n = strlen(str) - 1;
  while (k < n) {
    rts = str[k];
    str[k] = str[n];
    str[n] = rts;
    k++;
    n--;
  }
  printf("%s", str);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L12
  mov    %rsp,%rsi
  movslq %eax,%rdx
  add    %rbx,%rdx
L17:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rsi)
  mov    %dil,-0x1(%rdx)
  mov    %ecx,%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %eax,%edi
  sub    %r8d,%edi
  cmp    %edi,%ecx
  jg     L17
L12:
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D8: %s

assistant: ```c
int main() {
  char str[50], rts = 0;
  int k = 0, n = 0;
  scanf("%s", str);
  n = strlen(str) - 1;
  while (k < n) {
    rts = str[k];
    str[k] = str[n];
    str[n] = rts;
    k++;
    n--;
  }
  printf("%s", str);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L28
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L3
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: %s

assistant: ```c
int main() {
  char str[50], rts = 0;
  int k = 0, n = 0;
  scanf("%s", str);
  n = strlen(str) - 1;
  while (k < n) {
    rts = str[k];
    str[k] = str[n];
    str[n] = rts;
    k++;
    n--;
  }
  printf("%s", str);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L17
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L6
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D5: %s

assistant: ```c
int main() {
  char str[50], rts = 0;
  int k = 0, n = 0;
  scanf("%s", str);
  n = strlen(str) - 1;
  while (k < n) {
    rts = str[k];
    str[k] = str[n];
    str[n] = rts;
    k++;
    n--;
  }
  printf("%s", str);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hierholzer_uniqCircles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L28
L24:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L86
L106:
  addl   $0x1,-0x4(%rbp)
L86:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L95
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L106
L95:
  mov    -0x4(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L62
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
L93:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L32
L70:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L81
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L81
  mov    $0x0,%eax
  jmp    L25
L81:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L70
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L93
L62:
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  mov    $0x1,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
char hierholzer_uniqCircles(int *parents, int new, char *flags) {
  int i, j, k, l;
  for (i = 1; i < new; i++) {
    l = i;
    while (l + 1 < new &&parents[l + 1] == parents[i]) {
      l++;
    }
    if (l > i) {
      for (j = i; j < l; j++) {
        for (k = j + 1; k <= l; k++) {
          if (flags[j] && flags[k])
            return 0;
        }
      }
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hierholzer_uniqCircles>:
  endbr64
  cmp    $0x1,%esi
  jle    L87
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%r11
  add    $0x4,%rdi
  mov    %esi,%ebx
  mov    $0x1,%r8d
  jmp    L36
L94:
  cmp    %r8d,%ecx
  jg     L145
L14:
  add    $0x1,%r8
  add    $0x4,%rdi
  cmp    %rbx,%r8
  je     L54
L36:
  mov    %r8d,%r9d
  mov    %r8d,%eax
  mov    %rdi,%rdx
L107:
  mov    %eax,%ecx
  add    $0x1,%eax
  cmp    %r10d,%eax
  jge    L94
  mov    0x4(%rdx),%esi
  add    $0x4,%rdx
  cmp    (%rdi),%esi
  je     L107
  jmp    L94
L145:
  lea    0x1(%r8),%rsi
  mov    %ecx,%eax
  sub    %r9d,%eax
  lea    -0x1(%rax),%eax
  lea    0x2(%r8,%rax,1),%r9
  jmp    L59
L125:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jl     L82
L116:
  test   %dl,%dl
  je     L125
  cmpb   $0x0,(%r11,%rax,1)
  je     L125
  mov    $0x0,%eax
L42:
  pop    %rbx
  ret
L82:
  add    $0x1,%rsi
  cmp    %r9,%rsi
  je     L14
L59:
  cmp    %esi,%ecx
  jl     L82
  movzbl -0x1(%r11,%rsi,1),%edx
  movslq %esi,%rax
  jmp    L116
L54:
  mov    $0x1,%eax
  jmp    L42
L87:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char hierholzer_uniqCircles(int *parents, int new, char *flags) {
  int i, j, k, l;
  for (i = 1; i < new; i++) {
    l = i;
    while (l + 1 < new &&parents[l + 1] == parents[i]) {
      l++;
    }
    if (l > i) {
      for (j = i; j < l; j++) {
        for (k = j + 1; k <= l; k++) {
          if (flags[j] && flags[k])
            return 0;
        }
      }
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<hierholzer_uniqCircles>:
  endbr64
  cmp    $0x1,%esi
  jle    L60
  push   %rbp
  mov    %esi,%r11d
  add    $0x4,%rdi
  movslq %esi,%rbp
  push   %rbx
  mov    $0x1,%r8d
  mov    %rdx,%rbx
L4:
  mov    %r8d,%r10d
  mov    %r8d,%eax
  mov    %rdi,%rdx
  jmp    L48
  nopl   (%rax)
L77:
  mov    0x4(%rdx),%esi
  add    $0x4,%rdx
  cmp    (%rdi),%esi
  jne    L53
L48:
  mov    %eax,%ecx
  add    $0x1,%eax
  cmp    %r11d,%eax
  jl     L77
L53:
  lea    0x1(%r8),%r9
  cmp    %r8d,%ecx
  jg     L108
L22:
  mov    %r9,%r8
  add    $0x4,%rdi
  cmp    %rbp,%r9
  jne    L4
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L108:
  mov    %ecx,%eax
  mov    %r9,%rsi
  sub    %r10d,%eax
  sub    $0x1,%eax
  lea    0x2(%r8,%rax,1),%r8
L24:
  cmp    %esi,%ecx
  jl     L51
  movzbl -0x1(%rbx,%rsi,1),%edx
  movslq %esi,%rax
  nopl   0x0(%rax)
L3:
  test   %dl,%dl
  je     L73
  cmpb   $0x0,(%rbx,%rax,1)
  jne    L65
L73:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jge    L3
L51:
  add    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L24
  jmp    L22
  nopl   (%rax)
L65:
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L60:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char hierholzer_uniqCircles(int *parents, int new, char *flags) {
  int i, j, k, l;
  for (i = 1; i < new; i++) {
    l = i;
    while (l + 1 < new &&parents[l + 1] == parents[i]) {
      l++;
    }
    if (l > i) {
      for (j = i; j < l; j++) {
        for (k = j + 1; k <= l; k++) {
          if (flags[j] && flags[k])
            return 0;
        }
      }
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hierholzer_uniqCircles>:
  endbr64
  cmp    $0x1,%esi
  jle    L60
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%r11
  add    $0x4,%rdi
  movslq %esi,%rbx
  mov    $0x1,%r8d
L15:
  mov    %r8d,%r9d
  mov    %r8d,%eax
  mov    %rdi,%rdx
  jmp    L42
  nopl   0x0(%rax)
L33:
  mov    0x4(%rdx),%ecx
  add    $0x4,%rdx
  cmp    (%rdi),%ecx
  jne    L64
L42:
  mov    %eax,%esi
  add    $0x1,%eax
  cmp    %r10d,%eax
  jl     L33
L64:
  lea    0x1(%r8),%rcx
  cmp    %r8d,%esi
  jg     L18
L6:
  mov    %rcx,%r8
  add    $0x4,%rdi
  cmp    %rbx,%rcx
  jne    L15
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L18:
  mov    %esi,%eax
  mov    %rcx,%rdx
  sub    %r9d,%eax
  sub    $0x1,%eax
  lea    0x2(%r8,%rax,1),%r8
L86:
  movslq %edx,%rax
  cmp    %edx,%esi
  jl     L4
  cmpb   $0x0,-0x1(%r11,%rdx,1)
  jne    L119
L4:
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L86
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmp    %eax,%esi
  jl     L4
L119:
  cmpb   $0x0,(%r11,%rax,1)
  je     L1
  xor    %eax,%eax
  pop    %rbx
  ret
L60:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char hierholzer_uniqCircles(int *parents, int new, char *flags) {
  int i, j, k, l;
  for (i = 1; i < new; i++) {
    l = i;
    while (l + 1 < new &&parents[l + 1] == parents[i]) {
      l++;
    }
    if (l > i) {
      for (j = i; j < l; j++) {
        for (k = j + 1; k <= l; k++) {
          if (flags[j] && flags[k])
            return 0;
        }
      }
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Kit_TruthIsConst1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L38:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L11
  mov    $0x0,%eax
  jmp    L6
L11:
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L38
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int Kit_TruthIsConst1(unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    if (pIn[w] != ~(unsigned)0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Kit_TruthIsConst1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L22
  cltq
L21:
  cmpl   $0xffffffff,(%rbx,%rax,4)
  jne    L41
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L21
  mov    $0x1,%eax
  jmp    L19
L22:
  mov    $0x1,%eax
  jmp    L19
L41:
  mov    $0x0,%eax
L19:
  pop    %rbx
  ret
```

assistant: ```c
int Kit_TruthIsConst1(unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    if (pIn[w] != ~(unsigned)0)
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Kit_TruthIsConst1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L15
  cltq
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L20:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L15
L2:
  cmpl   $0xffffffff,(%rbx,%rax,4)
  je     L20
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int Kit_TruthIsConst1(unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    if (pIn[w] != ~(unsigned)0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Kit_TruthIsConst1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L16
  cltq
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L16
L5:
  cmpl   $0xffffffff,(%rbx,%rax,4)
  je     L21
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int Kit_TruthIsConst1(unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    if (pIn[w] != ~(unsigned)0)
      return 0;
  return 1;
}
```