user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D100(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D85(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D83(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x25,%eax
  cmp    $0xa,%al
  ja     L23
  movzbl %al,%eax
  lea    D40(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  lea    D27(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  ret
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  lea    D26(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L28
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  lea    D61(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L28
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  lea    D46(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L28
  movsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  cvttsd2si 0x10(%rsp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%esi
  movsd  0x10(%rsp),%xmm1
  lea    D39(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L28
L23:
  lea    D105(%rip),%rdi
  call   <puts@plt>
  jmp    L28
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D100
data_type: string
name: unpack_data
arguments: label: D85
data_type: string
name: unpack_data
arguments: label: D83
data_type: string
name: unpack_data
arguments: label: D32
data_type: string
name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D61
data_type: string
name: unpack_data
arguments: label: D46
data_type: string
name: unpack_data
arguments: label: D39
data_type: string
name: unpack_data
arguments: label: D105
data_type: string

tool: D100: Which operation you want to perform (+,-,*,/,%%)?


tool: D85: %c

tool: D83: Enter two operands:

tool: D32: %lf%lf

tool: D27: addition of %0.2lf & %0.2lf is: %0.4lf


tool: D26: subtraction of %0.2lf & %0.2lf is: %0.4lf


tool: D61: multiplication of %0.2lf & %0.2lf is: %0.4lf


tool: D46: division of %0.2lf & %0.2lf is: %0.4lf


tool: D39: mod remainder of %0.2lf & %0.2lf is: %d


tool: D105: Please enter valid operator

assistant: ```c
void main(void) {
  double a, b;
  char operator;
  printf("Which operation you want to perform (+,-,*,/,%%)?\n");
  scanf("%c", &operator);
  printf("Enter two operands:\n");
  scanf("%lf%lf", &a, &b);
  switch (operator) {
  case '+':
    printf("addition of %0.2lf & %0.2lf is: %0.4lf\n", a, b, a + b);
    break;
  case '-':
    printf("subtraction of %0.2lf & %0.2lf is: %0.4lf\n", a, b, a - b);
    break;
  case '*':
    printf("multiplication of %0.2lf & %0.2lf is: %0.4lf\n", a, b, a * b);
    break;
  case '/':
    printf("division of %0.2lf & %0.2lf is: %0.4lf\n", a, b, a / b);
    break;
  case '%':
    printf("mod remainder of %0.2lf & %0.2lf is: %d\n", a, b, (int)a % (int)b);
    break;
  default:
    printf("Please enter valid operator\n");
  }
}
```