ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mda_stopping_points>:
  endbr64
  cmp    $0x5f,%esi
  setne  %al
  movzbl %al,%eax
  mov    %edi,%edi
  lea    (%rax,%rdi,2),%rdx
  lea    D6(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: 

assistant: ```c
int mda_stopping_points(unsigned int num_interfaces, unsigned int confidence) {
  static const int k[][2] = {
      {0, 0}, {0, 0}, {6, 8}, {11, 15}, {16, 21}, {21, 28}, {27, 36}, {33, 43}, {38, 51}, {44, 58}, {51, 66}, {57, 74}, {63, 82}, {70, 90}, {76, 98}, {83, 106}, {90, 115}, {96, 123}, {103, 132}, {110, 140}, {117, 149}, {124, 157}, {131, 166}, {138, 175}, {145, 183}, {152, 192}, {159, 201}, {167, 210}, {174, 219}, {181, 228}, {189, 237}, {196, 246}, {203, 255}, {211, 264}, {218, 273}, {226, 282}, {233, 291}, {241, 300}, {248, 309}, {256, 319}, {264, 328}, {271, 337}, {279, 347}, {287, 356}, {294, 365}, {302, 375}, {310, 384}, {318, 393}, {326, 403}, {333, 412}, {341, 422}, {349, 431}, {357, 441}, {365, 450}, {373, 460}, {381, 470}, {389, 479}, {397, 489}, {405, 499}, {413, 508}, {421, 518}, {429, 528}, {437, 537}, {445, 547}, {453, 557}, {462, 566}, {470, 576}, {478, 586}, {486, 596}, {494, 606}, {502, 616}, {511, 625}, {519, 635}, {527, 645}, {535, 655}, {544, 665}, {552, 675}, {560, 685}, {569, 695}, {577, 705}, {585, 715}, {594, 725}, {602, 735}, {610, 745}, {619, 755}, {627, 765}, {635, 775}, {644, 785}, {652, 795}, {661, 805}, {669, 815}, {678, 825}, {686, 835}, {695, 845}, {703, 855}, {712, 866}, {720, 876}, {729, 886}, {737, 896}, {746, 906},
  };
  return k[num_interfaces][(confidence == 95) ? 0 : 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mda_stopping_points>:
  endbr64
  xor    %eax,%eax
  cmp    $0x5f,%esi
  mov    %edi,%edi
  setne  %al
  lea    (%rax,%rdi,2),%rdx
  lea    D1(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: 

assistant: ```c
int mda_stopping_points(unsigned int num_interfaces, unsigned int confidence) {
  static const int k[][2] = {
      {0, 0}, {0, 0}, {6, 8}, {11, 15}, {16, 21}, {21, 28}, {27, 36}, {33, 43}, {38, 51}, {44, 58}, {51, 66}, {57, 74}, {63, 82}, {70, 90}, {76, 98}, {83, 106}, {90, 115}, {96, 123}, {103, 132}, {110, 140}, {117, 149}, {124, 157}, {131, 166}, {138, 175}, {145, 183}, {152, 192}, {159, 201}, {167, 210}, {174, 219}, {181, 228}, {189, 237}, {196, 246}, {203, 255}, {211, 264}, {218, 273}, {226, 282}, {233, 291}, {241, 300}, {248, 309}, {256, 319}, {264, 328}, {271, 337}, {279, 347}, {287, 356}, {294, 365}, {302, 375}, {310, 384}, {318, 393}, {326, 403}, {333, 412}, {341, 422}, {349, 431}, {357, 441}, {365, 450}, {373, 460}, {381, 470}, {389, 479}, {397, 489}, {405, 499}, {413, 508}, {421, 518}, {429, 528}, {437, 537}, {445, 547}, {453, 557}, {462, 566}, {470, 576}, {478, 586}, {486, 596}, {494, 606}, {502, 616}, {511, 625}, {519, 635}, {527, 645}, {535, 655}, {544, 665}, {552, 675}, {560, 685}, {569, 695}, {577, 705}, {585, 715}, {594, 725}, {602, 735}, {610, 745}, {619, 755}, {627, 765}, {635, 775}, {644, 785}, {652, 795}, {661, 805}, {669, 815}, {678, 825}, {686, 835}, {695, 845}, {703, 855}, {712, 866}, {720, 876}, {729, 886}, {737, 896}, {746, 906},
  };
  return k[num_interfaces][(confidence == 95) ? 0 : 1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mda_stopping_points>:
  endbr64
  xor    %eax,%eax
  cmp    $0x5f,%esi
  mov    %edi,%edi
  setne  %al
  lea    (%rax,%rdi,2),%rdx
  lea    D6(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: 

assistant: ```c
int mda_stopping_points(unsigned int num_interfaces, unsigned int confidence) {
  static const int k[][2] = {
      {0, 0}, {0, 0}, {6, 8}, {11, 15}, {16, 21}, {21, 28}, {27, 36}, {33, 43}, {38, 51}, {44, 58}, {51, 66}, {57, 74}, {63, 82}, {70, 90}, {76, 98}, {83, 106}, {90, 115}, {96, 123}, {103, 132}, {110, 140}, {117, 149}, {124, 157}, {131, 166}, {138, 175}, {145, 183}, {152, 192}, {159, 201}, {167, 210}, {174, 219}, {181, 228}, {189, 237}, {196, 246}, {203, 255}, {211, 264}, {218, 273}, {226, 282}, {233, 291}, {241, 300}, {248, 309}, {256, 319}, {264, 328}, {271, 337}, {279, 347}, {287, 356}, {294, 365}, {302, 375}, {310, 384}, {318, 393}, {326, 403}, {333, 412}, {341, 422}, {349, 431}, {357, 441}, {365, 450}, {373, 460}, {381, 470}, {389, 479}, {397, 489}, {405, 499}, {413, 508}, {421, 518}, {429, 528}, {437, 537}, {445, 547}, {453, 557}, {462, 566}, {470, 576}, {478, 586}, {486, 596}, {494, 606}, {502, 616}, {511, 625}, {519, 635}, {527, 645}, {535, 655}, {544, 665}, {552, 675}, {560, 685}, {569, 695}, {577, 705}, {585, 715}, {594, 725}, {602, 735}, {610, 745}, {619, 755}, {627, 765}, {635, 775}, {644, 785}, {652, 795}, {661, 805}, {669, 815}, {678, 825}, {686, 835}, {695, 845}, {703, 855}, {712, 866}, {720, 876}, {729, 886}, {737, 896}, {746, 906},
  };
  return k[num_interfaces][(confidence == 95) ? 0 : 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rop3_157_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_157_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | *D;
  stk2 = S & stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_157_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  or     (%rdi),%sil
  and    %eax,%esi
  xor    (%rdi),%sil
  or     %eax,%esi
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_157_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | *D;
  stk2 = S & stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_157_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %edx,%esi
  and    %eax,%esi
  xor    (%rdi),%sil
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_157_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | *D;
  stk2 = S & stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_157_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %edx,%esi
  and    %eax,%esi
  xor    (%rdi),%sil
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_157_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | *D;
  stk2 = S & stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aes_key_mgmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  jmp    L5
L18:
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <AES_set_decrypt_key@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void aes_key_mgmt(AES_KEY *akey, unsigned char *key, unsigned int key_length, int direction) {
  if (direction == 1) {
    AES_set_encrypt_key(key, key_length, akey);
  } else {
    AES_set_decrypt_key(key, key_length, akey);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aes_key_mgmt>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %edx,%esi
  cmp    $0x1,%ecx
  je     L9
  mov    %rax,%rdx
  call   <AES_set_decrypt_key@plt>
L12:
  add    $0x8,%rsp
  ret
L9:
  mov    %rax,%rdx
  call   <AES_set_encrypt_key@plt>
  jmp    L12
```

assistant: ```c
void aes_key_mgmt(AES_KEY *akey, unsigned char *key, unsigned int key_length, int direction) {
  if (direction == 1) {
    AES_set_encrypt_key(key, key_length, akey);
  } else {
    AES_set_decrypt_key(key, key_length, akey);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aes_key_mgmt>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %r8,%rdx
  cmp    $0x1,%ecx
  je     L4
  jmp    1060 <AES_set_decrypt_key@plt>
  nopl   0x0(%rax)
L4:
  jmp    1070 <AES_set_encrypt_key@plt>
```

assistant: ```c
void aes_key_mgmt(AES_KEY *akey, unsigned char *key, unsigned int key_length, int direction) {
  if (direction == 1) {
    AES_set_encrypt_key(key, key_length, akey);
  } else {
    AES_set_decrypt_key(key, key_length, akey);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<aes_key_mgmt>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %r8,%rdx
  cmp    $0x1,%ecx
  je     L6
  jmp    1060 <AES_set_decrypt_key@plt>
  nopl   0x0(%rax)
L6:
  jmp    1070 <AES_set_encrypt_key@plt>
```

assistant: ```c
void aes_key_mgmt(AES_KEY *akey, unsigned char *key, unsigned int key_length, int direction) {
  if (direction == 1) {
    AES_set_encrypt_key(key, key_length, akey);
  } else {
    AES_set_decrypt_key(key, key_length, akey);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L22
L45:
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x38(%rbp)
L22:
  mov    -0x40(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L45
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  lea    -0x30(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <binary_ser@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0xffffffff,-0x34(%rbp)
  jne    L23
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L47
L23:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L47:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D44
type: string
name: unpack_data
arguments: data_label: D56
type: string
name: unpack_data
arguments: data_label: D58
type: string
name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D76
type: string

tool: D3: Enter the size of array of numbers

tool: D44: %d

tool: D56: Enter %d numbers in increasing order


tool: D58: Enter the number to be searched in the array

tool: D18: The number is not present

tool: D76: The number is at position %d in the list


assistant: ```c
int main() {
  int i, arr[10];
  int n, num;
  int pos = 0;
  printf("Enter the size of array of numbers\n");
  scanf("%d", &n);
  printf("Enter %d numbers in increasing order\n", n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &arr[i]);
  }
  printf("Enter the number to be searched in the array\n");
  scanf("%d", &num);
  pos = binary_ser(num, arr, n);
  if (pos == -1) {
    printf("The number is not present\n");
  } else {
    printf("The number is at position %d in the list\n", pos + 1);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L17
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D45(%rip),%r12
L45:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L45
L17:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%edi
  call   <binary_ser@plt>
  cmp    $0xffffffff,%eax
  je     L49
  lea    0x1(%rax),%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L37:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  lea    D51(%rip),%rdi
  call   <puts@plt>
  jmp    L37
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D68
datatype: string
name: disassemble_data
arguments: data_tag: D45
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string
name: disassemble_data
arguments: data_tag: D39
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string
name: disassemble_data
arguments: data_tag: D51
datatype: string

tool: D68: Enter the size of array of numbers

tool: D45: %d

tool: D24: Enter %d numbers in increasing order


tool: D39: Enter the number to be searched in the array

tool: D7: The number is at position %d in the list


tool: D51: The number is not present

assistant: ```c
int main() {
  int i, arr[10];
  int n, num;
  int pos = 0;
  printf("Enter the size of array of numbers\n");
  scanf("%d", &n);
  printf("Enter %d numbers in increasing order\n", n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &arr[i]);
  }
  printf("Enter the number to be searched in the array\n");
  scanf("%d", &num);
  pos = binary_ser(num, arr, n);
  if (pos == -1) {
    printf("The number is not present\n");
  } else {
    printf("The number is at position %d in the list\n", pos + 1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  lea    D50(%rip),%rdi
  push   %r12
  lea    D58(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L0
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L33
L0:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%edi
  mov    %r13,%rsi
  call   <binary_ser@plt>
  cmp    $0xffffffff,%eax
  je     L5
  lea    0x1(%rax),%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L20:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  lea    D41(%rip),%rdi
  call   <puts@plt>
  jmp    L20
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D50
datatype: string
name: read_data
arguments: data_tag: D58
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D41
datatype: string

tool: D50: Enter the size of array of numbers

tool: D58: %d

tool: D3: Enter %d numbers in increasing order


tool: D12: Enter the number to be searched in the array

tool: D18: The number is at position %d in the list


tool: D41: The number is not present

assistant: ```c
int main() {
  int i, arr[10];
  int n, num;
  int pos = 0;
  printf("Enter the size of array of numbers\n");
  scanf("%d", &n);
  printf("Enter %d numbers in increasing order\n", n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &arr[i]);
  }
  printf("Enter the number to be searched in the array\n");
  scanf("%d", &num);
  pos = binary_ser(num, arr, n);
  if (pos == -1) {
    printf("The number is not present\n");
  } else {
    printf("The number is at position %d in the list\n", pos + 1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D53(%rip),%rdi
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L39
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L44
L39:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%edi
  mov    %r13,%rsi
  call   <binary_ser@plt>
  cmp    $0xffffffff,%eax
  je     L13
  lea    0x1(%rax),%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L46:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  jmp    L46
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D53
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D35
type_infered: string

tool: D53: Enter the size of array of numbers

tool: D17: %d

tool: D44: Enter %d numbers in increasing order


tool: D26: Enter the number to be searched in the array

tool: D25: The number is at position %d in the list


tool: D35: The number is not present

assistant: ```c
int main() {
  int i, arr[10];
  int n, num;
  int pos = 0;
  printf("Enter the size of array of numbers\n");
  scanf("%d", &n);
  printf("Enter %d numbers in increasing order\n", n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &arr[i]);
  }
  printf("Enter the number to be searched in the array\n");
  scanf("%d", &num);
  pos = binary_ser(num, arr, n);
  if (pos == -1) {
    printf("The number is not present\n");
  } else {
    printf("The number is at position %d in the list\n", pos + 1);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<logo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rsi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D68
type: string
name: unpack_data
arguments: tag: D34
type: string
name: unpack_data
arguments: tag: D59
type: string
name: unpack_data
arguments: tag: D83
type: string
name: unpack_data
arguments: tag: D41
type: string
name: unpack_data
arguments: tag: D65
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D95
type: string
name: unpack_data
arguments: tag: D90
type: string

tool: D68: 	    ***************************************************

tool: D34: 	    *            COMPOSERS DESKTOP PROJECT            *

tool: D59: GETCOL

tool: D83: 	                    %s $Revision: 1.2 $


tool: D41: 	    *                                                 *

tool: D65: 	    *   get Nth column from a file of columned data   *

tool: D19: 	    *      (skipping M lines at start of file).       *

tool: D95: 	    *                by TREVOR WISHART                *

tool: D90: 	    ***************************************************


assistant: ```c
void logo(void) {
  printf("\t    ***************************************************\n");
  printf("\t    *            COMPOSERS DESKTOP PROJECT            *\n");
  printf("\t                    %s $Revision: 1.2 $\n", "GETCOL");
  printf("\t    *                                                 *\n");
  printf("\t    *   get Nth column from a file of columned data   *\n");
  printf("\t    *      (skipping M lines at start of file).       *\n");
  printf("\t    *                                                 *\n");
  printf("\t    *                by TREVOR WISHART                *\n");
  printf("\t    ***************************************************\n\n");
}
```