ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<array_entry_remove>:
  endbr64
  push   %r14
  movslq %edi,%rax
  push   %r13
  mov    %rdx,%r13
  imul   %rsi,%rax
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    (%rcx),%ebp
  push   %rbx
  mov    (%rdx),%r14
  mov    %rsi,%rbx
  mov    %ebp,%edx
  sub    $0x1,%ebp
  sub    %edi,%edx
  lea    (%r14,%rax,1),%rdi
  sub    $0x1,%edx
  imul   %esi,%edx
  add    %rax,%rsi
  add    %r14,%rsi
  call   <memmove@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  imul   %ebx,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L5
L15:
  pop    %rbx
  mov    %rax,0x0(%r13)
  xor    %eax,%eax
  mov    %ebp,(%r12)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movslq %ebp,%rdx
  imul   %rbx,%rdx
  test   %rdx,%rdx
  je     L15
  mov    D1(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  pop    %r13
  pop    %r14
  neg    %eax
  ret
```

assistant: ```c
int array_entry_remove(int index, size_t elem_size, void **array_, int *array_count_) {
  void *array = *array_;
  int array_count = *array_count_;
  char *dst = array + elem_size * index;
  char *src = array + elem_size * (index + 1);
  memmove(array + elem_size * index, array + elem_size * (index + 1), (array_count - index - 1) * elem_size);
  array_count--;
  array = realloc(array, array_count * elem_size);
  if (!array && array_count * elem_size > 0) {
    return -ENOMEM;
  }
  *array_ = array;
  *array_count_ = array_count;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_entry_remove>:
  endbr64
  push   %r14
  movslq %edi,%rax
  push   %r13
  mov    %rdx,%r13
  imul   %rsi,%rax
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    (%rcx),%ebp
  push   %rbx
  mov    (%rdx),%r14
  mov    %rsi,%rbx
  mov    %ebp,%edx
  sub    $0x1,%ebp
  sub    %edi,%edx
  lea    (%r14,%rax,1),%rdi
  sub    $0x1,%edx
  imul   %esi,%edx
  add    %rax,%rsi
  add    %r14,%rsi
  call   <memmove@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  imul   %ebx,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L19
L3:
  pop    %rbx
  mov    %rax,0x0(%r13)
  xor    %eax,%eax
  mov    %ebp,(%r12)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movslq %ebp,%rdx
  imul   %rbx,%rdx
  test   %rdx,%rdx
  je     L3
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  pop    %r13
  pop    %r14
  neg    %eax
  ret
```

assistant: ```c
int array_entry_remove(int index, size_t elem_size, void **array_, int *array_count_) {
  void *array = *array_;
  int array_count = *array_count_;
  char *dst = array + elem_size * index;
  char *src = array + elem_size * (index + 1);
  memmove(array + elem_size * index, array + elem_size * (index + 1), (array_count - index - 1) * elem_size);
  array_count--;
  array = realloc(array, array_count * elem_size);
  if (!array && array_count * elem_size > 0) {
    return -ENOMEM;
  }
  *array_ = array;
  *array_count_ = array_count;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_timespec_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  jns    L3
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x3b9aca00(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _timespec_sub(struct timespec *a, const struct timespec *b) {
  a->tv_sec -= b->tv_sec;
  a->tv_nsec -= b->tv_nsec;
  if (a->tv_nsec < 0) {
    a->tv_nsec += 1000000000;
    a->tv_sec -= 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_timespec_sub>:
  endbr64
  mov    (%rdi),%edx
  sub    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  js     L2
  mov    %rax,0x8(%rdi)
  ret
L2:
  add    $0x3b9aca00,%rax
  mov    %rax,0x8(%rdi)
  sub    $0x1,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void _timespec_sub(struct timespec *a, const struct timespec *b) {
  a->tv_sec -= b->tv_sec;
  a->tv_nsec -= b->tv_nsec;
  if (a->tv_nsec < 0) {
    a->tv_nsec += 1000000000;
    a->tv_sec -= 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_timespec_sub>:
  endbr64
  mov    (%rdi),%edx
  sub    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  js     L0
  mov    %rax,0x8(%rdi)
  ret
  nopl   0x0(%rax)
L0:
  add    $0x3b9aca00,%rax
  sub    $0x1,%edx
  mov    %rax,0x8(%rdi)
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void _timespec_sub(struct timespec *a, const struct timespec *b) {
  a->tv_sec -= b->tv_sec;
  a->tv_nsec -= b->tv_nsec;
  if (a->tv_nsec < 0) {
    a->tv_nsec += 1000000000;
    a->tv_sec -= 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_timespec_sub>:
  endbr64
  mov    (%rdi),%edx
  sub    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  js     L6
  mov    %rax,0x8(%rdi)
  ret
  nopl   0x0(%rax)
L6:
  add    $0x3b9aca00,%rax
  sub    $0x1,%edx
  mov    %rax,0x8(%rdi)
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void _timespec_sub(struct timespec *a, const struct timespec *b) {
  a->tv_sec -= b->tv_sec;
  a->tv_nsec -= b->tv_nsec;
  if (a->tv_nsec < 0) {
    a->tv_nsec += 1000000000;
    a->tv_sec -= 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <pci_locate_device@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x12,%esi
  mov    %rax,%rdi
  call   <__builtin_outl@plt>
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  unsigned long addr;
  addr = pci_locate_device(0);
  __builtin_outl(addr, 0x12);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <pci_locate_device@plt>
  mov    %rax,%rdi
  mov    $0x12,%esi
  call   <__builtin_outl@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main(void) {
  unsigned long addr;
  addr = pci_locate_device(0);
  __builtin_outl(addr, 0x12);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <pci_locate_device@plt>
  mov    $0x12,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <__builtin_outl@plt>
```

assistant: ```c
void main(void) {
  unsigned long addr;
  addr = pci_locate_device(0);
  __builtin_outl(addr, 0x12);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <pci_locate_device@plt>
  mov    $0x12,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <__builtin_outl@plt>
```

assistant: ```c
void main(void) {
  unsigned long addr;
  addr = pci_locate_device(0);
  __builtin_outl(addr, 0x12);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nuc_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L63
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x54,%eax
  je     L7
  cmp    $0x54,%eax
  jg     L10
  cmp    $0x47,%eax
  je     L72
  cmp    $0x47,%eax
  jg     L10
  cmp    $0x41,%eax
  je     L59
  cmp    $0x43,%eax
  je     L47
  jmp    L10
L59:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x54,(%rax)
  jmp    L10
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x41,(%rax)
  jmp    L10
L47:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x47,(%rax)
  jmp    L10
L72:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x43,(%rax)
  nop
L10:
  addl   $0x1,-0x4(%rbp)
L63:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *nuc_comp(char *s, int n) {
  int i = 0;
  while (i < n) {
    switch (s[i]) {
    case 'A':
      s[i] = 'T';
      break;
    case 'T':
      s[i] = 'A';
      break;
    case 'C':
      s[i] = 'G';
      break;
    case 'G':
      s[i] = 'C';
      break;
    }
    i++;
  }
  *(s + n) = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<nuc_comp>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L27
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%r9
  jmp    L50
L72:
  cmp    $0x54,%dl
  jne    L88
  movb   $0x41,(%rcx)
  jmp    L88
L92:
  movb   $0x54,(%rcx)
L88:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  je     L27
L50:
  movzbl (%rcx),%edx
  cmp    $0x47,%dl
  je     L30
  jg     L72
  cmp    $0x41,%dl
  je     L92
  cmp    $0x43,%dl
  jne    L88
  movb   $0x47,(%rcx)
  jmp    L88
L30:
  movb   $0x43,(%rcx)
  jmp    L88
L27:
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  ret
```

assistant: ```c
char *nuc_comp(char *s, int n) {
  int i = 0;
  while (i < n) {
    switch (s[i]) {
    case 'A':
      s[i] = 'T';
      break;
    case 'T':
      s[i] = 'A';
      break;
    case 'C':
      s[i] = 'G';
      break;
    case 'G':
      s[i] = 'C';
      break;
    }
    i++;
  }
  *(s + n) = '\0';
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nuc_comp>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L84
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rcx
  lea    0x1(%rdi,%rdx,1),%r8
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L30:
  cmp    $0x43,%dl
  jne    L1
  movb   $0x47,(%rcx)
L1:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L84
L11:
  movzbl (%rcx),%edx
  cmp    $0x47,%dl
  je     L61
  jg     L6
  cmp    $0x41,%dl
  jne    L30
  movb   $0x54,(%rcx)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L11
L84:
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  ret
  nopl   0x0(%rax)
L6:
  cmp    $0x54,%dl
  jne    L1
  movb   $0x41,(%rcx)
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L61:
  movb   $0x43,(%rcx)
  jmp    L1
```

assistant: ```c
char *nuc_comp(char *s, int n) {
  int i = 0;
  while (i < n) {
    switch (s[i]) {
    case 'A':
      s[i] = 'T';
      break;
    case 'T':
      s[i] = 'A';
      break;
    case 'C':
      s[i] = 'G';
      break;
    case 'G':
      s[i] = 'C';
      break;
    }
    i++;
  }
  *(s + n) = '\0';
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nuc_comp>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L40
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rcx
  lea    0x1(%rdi,%rdx,1),%r8
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L78:
  cmp    $0x43,%dl
  jne    L81
  movb   $0x47,(%rcx)
L81:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L40
L100:
  movzbl (%rcx),%edx
  cmp    $0x47,%dl
  je     L60
  jg     L10
  cmp    $0x41,%dl
  jne    L78
  movb   $0x54,(%rcx)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L100
L40:
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  ret
  nopl   0x0(%rax)
L10:
  cmp    $0x54,%dl
  jne    L81
  movb   $0x41,(%rcx)
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L60:
  movb   $0x43,(%rcx)
  jmp    L81
```

assistant: ```c
char *nuc_comp(char *s, int n) {
  int i = 0;
  while (i < n) {
    switch (s[i]) {
    case 'A':
      s[i] = 'T';
      break;
    case 'T':
      s[i] = 'A';
      break;
    case 'C':
      s[i] = 'G';
      break;
    case 'G':
      s[i] = 'C';
      break;
    }
    i++;
  }
  *(s + n) = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<rbreadlist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L16
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rb_readlist@plt>
L16:
  leave
  ret
```

assistant: ```c
const void *rbreadlist(struct rblists *rblistp) {
  if (rblistp == NULL) {
    return (NULL);
  }
  return (rb_readlist(rblistp));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rbreadlist>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  call   <rb_readlist@plt>
  add    $0x8,%rsp
  ret
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const void *rbreadlist(struct rblists *rblistp) {
  if (rblistp == NULL) {
    return (NULL);
  }
  return (rb_readlist(rblistp));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rbreadlist>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <rb_readlist@plt>
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
const void *rbreadlist(struct rblists *rblistp) {
  if (rblistp == NULL) {
    return (NULL);
  }
  return (rb_readlist(rblistp));
}
```
user: What is the c source code of the assembly code below?

```asm
<rbreadlist>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <rb_readlist@plt>
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
const void *rbreadlist(struct rblists *rblistp) {
  if (rblistp == NULL) {
    return (NULL);
  }
  return (rb_readlist(rblistp));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<time_to_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D28(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
type_guessed: f64
name: retrieve_data
arguments: data_tag: D2
type_guessed: f64
name: retrieve_data
arguments: data_tag: D28
type_guessed: f64

tool: D33: 5

tool: D2: 1000

tool: D28: 2.302585093

assistant: ```c
double time_to_val(double value) {
  double x = exp(2.302585093 * (5. * value - 1. * 1000) / 1000);
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<time_to_val>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D11(%rip),%xmm0
  movsd  D12(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  call   <exp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
type_guessed: f64
name: read_data
arguments: data_tag: D12
type_guessed: f64
name: read_data
arguments: data_tag: D1
type_guessed: f64

tool: D11: 5

tool: D12: 1000

tool: D1: 2.302585093

assistant: ```c
double time_to_val(double value) {
  double x = exp(2.302585093 * (5. * value - 1. * 1000) / 1000);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<time_to_val>:
  endbr64
  mulsd  D8(%rip),%xmm0
  movsd  D0(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D6(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    1050 <exp@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: f64
name: disassemble_data
arguments: data_label: D0
datatype: f64
name: disassemble_data
arguments: data_label: D6
datatype: f64

tool: D8: 5

tool: D0: 1000

tool: D6: 2.302585093

assistant: ```c
double time_to_val(double value) {
  double x = exp(2.302585093 * (5. * value - 1. * 1000) / 1000);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<time_to_val>:
  endbr64
  mulsd  D2(%rip),%xmm0
  movsd  D11(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D12(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    1050 <exp@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: f64
name: parse_data
arguments: data_tag: D11
data_type: f64
name: parse_data
arguments: data_tag: D12
data_type: f64

tool: D2: 5

tool: D11: 1000

tool: D12: 2.302585093

assistant: ```c
double time_to_val(double value) {
  double x = exp(2.302585093 * (5. * value - 1. * 1000) / 1000);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xvasprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  test   %rax,%rax
  jns    L14
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L23
  mov    $0x0,%eax
  call   <oom_die@plt>
L23:
  mov    $0x0,%eax
  jmp    L12
L14:
  mov    -0x10(%rbp),%rax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
char *xvasprintf(const char *fmt, va_list ap) {
  char *ret;
  if (vasprintf(&ret, fmt, ap) < 0) {
    if (errno == ENOMEM)
      oom_die();
    return NULL;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xvasprintf>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  mov    %rax,%rdx
  mov    (%rsp),%rax
  test   %rdx,%rdx
  js     L28
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x18,%rsp
  ret
L28:
  mov    $0x0,%eax
  mov    D7(%rip),%rcx
  mov    D2(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L9
  call   <oom_die@plt>
  mov    $0x0,%eax
  jmp    L9
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *xvasprintf(const char *fmt, va_list ap) {
  char *ret;
  if (vasprintf(&ret, fmt, ap) < 0) {
    if (errno == ENOMEM)
      oom_die();
    return NULL;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xvasprintf>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %r8,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <vasprintf@plt>
  mov    (%rsp),%r12
  test   %rax,%rax
  js     L38
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L38:
  mov    D17(%rip),%rax
  mov    D12(%rip),%rdx
  xor    %r12d,%r12d
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L5
  xor    %eax,%eax
  call   <oom_die@plt>
  jmp    L5
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *xvasprintf(const char *fmt, va_list ap) {
  char *ret;
  if (vasprintf(&ret, fmt, ap) < 0) {
    if (errno == ENOMEM)
      oom_die();
    return NULL;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xvasprintf>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %r8,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <vasprintf@plt>
  mov    (%rsp),%r12
  test   %rax,%rax
  js     L28
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L28:
  mov    D0(%rip),%rax
  mov    D18(%rip),%rdx
  xor    %r12d,%r12d
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L20
  xor    %eax,%eax
  call   <oom_die@plt>
  jmp    L20
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *xvasprintf(const char *fmt, va_list ap) {
  char *ret;
  if (vasprintf(&ret, fmt, ap) < 0) {
    if (errno == ENOMEM)
      oom_die();
    return NULL;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L21
L27:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L21:
  cmpl   $0x9,-0x34(%rbp)
  jle    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int value[10] = {4, 2, 3, 5, 8, 6, 7, 0, 9, 1};
  quickSort(value, 0, 9);
  for (int i = 0; i < 10; i++) {
    printf("%d", value[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x8,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quickSort@plt>
  lea    0x28(%rsp),%r12
  lea    D0(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int value[10] = {4, 2, 3, 5, 8, 6, 7, 0, 9, 1};
  quickSort(value, 0, 9);
  for (int i = 0; i < 10; i++) {
    printf("%d", value[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000004,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  movq   $0x7,0x18(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x500000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000008,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000009,%rax
  mov    %rax,0x20(%rsp)
  call   <quickSort@plt>
  nopl   0x0(%rax)
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int value[10] = {4, 2, 3, 5, 8, 6, 7, 0, 9, 1};
  quickSort(value, 0, 9);
  for (int i = 0; i < 10; i++) {
    printf("%d", value[i]);
  }
  printf("\n");
}
```