user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    D143(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D141(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D108(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%esi
  add    0xc(%rsp),%esi
  add    0x14(%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  sub    0xc(%rsp),%esi
  lea    D80(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  sub    0xc(%rsp),%esi
  lea    D142(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  imul   0x14(%rsp),%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  imul   0x14(%rsp),%esi
  lea    D96(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  lea    (%rdx,%rcx,2),%esi
  sub    %eax,%esi
  lea    D95(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  lea    0xa(%rax,%rdx,1),%esi
  imul   %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  mov    %eax,%esi
  imul   %edx,%esi
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%esi
  lea    D144(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  lea    (%rax,%rdx,1),%esi
  imul   %edx,%eax
  sub    %eax,%esi
  add    %esi,%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D50
type_infered: string
name: unpack_data
arguments: label: D143
type_infered: string
name: unpack_data
arguments: label: D141
type_infered: string
name: unpack_data
arguments: label: D108
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D56
type_infered: string
name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D80
type_infered: string
name: unpack_data
arguments: label: D142
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D96
type_infered: string
name: unpack_data
arguments: label: D95
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D144
type_infered: string
name: unpack_data
arguments: label: D55
type_infered: string

tool: D50: This program needs 3 initial digit(s) to provide different calculations:


tool: D143: Please enter 1st number: 

tool: D141: %d

tool: D108: Please enter 2nd number: 

tool: D11: Please enter 3rd number: 

tool: D56: 
Pay attention to below results:

tool: D26: Summation of these 3 numbers result is: %d


tool: D80: Differences between 1st and 2nd is: %d


tool: D142: Differences between 1st and 3rd is: %d


tool: D21: 2nd number multiply by 3rd number result is: %d


tool: D96: Product of these 3 numbers is: %d


tool: D95: E= 2AB+A-B %d


tool: D3: F= A+B+10-4AB %d


tool: D144: G= AB-2(A+B) %d


tool: D55: H= 2A+2B-2AB %d


assistant: ```c
int main() {
  printf("This program needs 3 initial digit(s) to provide different calculations:\n\n");
  int a, b, c;
  printf("Please enter 1st number: ");
  scanf("%d", &a);
  printf("Please enter 2nd number: ");
  scanf("%d", &b);
  printf("Please enter 3rd number: ");
  scanf("%d", &c);
  printf("\nPay attention to below results:\n");
  printf("Summation of these 3 numbers result is: %d\n", a + b + c);
  printf("Differences between 1st and 2nd is: %d\n", b - a);
  printf("Differences between 1st and 3rd is: %d\n", c - a);
  printf("2nd number multiply by 3rd number result is: %d\n", b * c);
  printf("Product of these 3 numbers is: %d\n", a * b * c);
  printf("E= 2AB+A-B %d\n", 2 * a * b + a - b);
  printf("F= A+B+10-4AB %d\n", a + b + 10 - (4 * a * b));
  printf("G= AB-2(A+B) %d\n", a * b - 2 * (a + b));
  printf("H= 2A+2B-2AB %d\n", 2 * a + 2 * b - (2 * a * b));
  return 0;
}
```