ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x6a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x698(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rdi
  mov    %rbx,%rsi
  call   <ler_matriz@plt>
  mov    %rbx,%rdi
  lea    0xa0(%rsp),%rbp
  lea    0x6e0(%rsp),%r12
  mov    %rbp,%rcx
L32:
  mov    (%rdi),%esi
  lea    -0x50(%rcx),%rax
L1:
  mov    %esi,%edx
  imul   (%rax),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L1
  add    $0x4,%rdi
  add    $0x50,%rcx
  cmp    %r12,%rcx
  jne    L32
  lea    D0(%rip),%r13
L40:
  lea    -0x50(%rbp),%rbx
L46:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x50,%rbp
  cmp    %r12,%rbp
  jne    L40
  mov    0x698(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x6a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: %d 

assistant: ```c
void main() {
  int matriz[20][20], soma[20];
  int i, j;
  ler_matriz(matriz, soma);
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      matriz[i][j] *= soma[i];
    }
  }
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      printf("%d ", matriz[i][j]);
    }
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x6a8,%rsp
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rdi
  lea    0xa0(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x698(%rsp)
  xor    %eax,%eax
  mov    %rbx,%rsi
  lea    0x6e0(%rsp),%r12
  call   <ler_matriz@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rcx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    (%rdi),%esi
  lea    -0x50(%rcx),%rax
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    (%rax),%edx
  add    $0x4,%rax
  imul   %esi,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L0
  lea    0x50(%rax),%rcx
  add    $0x4,%rdi
  cmp    %r12,%rcx
  jne    L36
  lea    D7(%rip),%r13
  nopl   (%rax)
L14:
  lea    -0x50(%rbp),%rbx
  nopl   0x0(%rax)
L12:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L12
  mov    $0xa,%edi
  lea    0x50(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r12,%rbp
  jne    L14
  mov    0x698(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x6a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: %d 

assistant: ```c
void main() {
  int matriz[20][20], soma[20];
  int i, j;
  ler_matriz(matriz, soma);
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      matriz[i][j] *= soma[i];
    }
  }
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      printf("%d ", matriz[i][j]);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x6a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x698(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%r13
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <ler_matriz@plt>
  mov    %rbx,%rdx
  lea    0x690(%rsp),%rcx
  mov    %r13,%rax
  nopl   (%rax)
L13:
  movd   (%rdx),%xmm4
  movdqa (%rax),%xmm1
  add    $0x50,%rax
  add    $0x4,%rdx
  pshufd $0x0,%xmm4,%xmm0
  psrlq  $0x20,%xmm1
  movdqa %xmm0,%xmm2
  movdqa %xmm0,%xmm3
  pmuludq -0x50(%rax),%xmm3
  pshufd $0x8,%xmm3,%xmm3
  psrlq  $0x20,%xmm2
  pmuludq %xmm2,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm3
  movdqa -0x40(%rax),%xmm1
  movaps %xmm3,-0x50(%rax)
  movdqa %xmm0,%xmm3
  pmuludq -0x40(%rax),%xmm3
  pshufd $0x8,%xmm3,%xmm3
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm3
  movdqa -0x30(%rax),%xmm1
  movaps %xmm3,-0x40(%rax)
  movdqa %xmm0,%xmm3
  pmuludq -0x30(%rax),%xmm3
  pshufd $0x8,%xmm3,%xmm3
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm3
  movdqa -0x20(%rax),%xmm1
  movaps %xmm3,-0x30(%rax)
  movdqa %xmm0,%xmm3
  pmuludq -0x20(%rax),%xmm3
  pshufd $0x8,%xmm3,%xmm3
  psrlq  $0x20,%xmm1
  pmuludq -0x10(%rax),%xmm0
  pshufd $0x8,%xmm0,%xmm0
  pmuludq %xmm2,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm3
  movdqa -0x10(%rax),%xmm1
  movaps %xmm3,-0x20(%rax)
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  movaps %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L13
  lea    0x50(%r13),%rbp
  lea    D5(%rip),%r12
  add    $0x690,%r13
  nopl   (%rax)
L30:
  lea    -0x50(%rbp),%rbx
  nopl   0x0(%rax)
L7:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L7
  mov    $0xa,%edi
  add    $0x50,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L30
  mov    0x698(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x6a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
void main() {
  int matriz[20][20], soma[20];
  int i, j;
  ler_matriz(matriz, soma);
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      matriz[i][j] *= soma[i];
    }
  }
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      printf("%d ", matriz[i][j]);
    }
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<u_char_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xf(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <u_char_to_u@plt>
  movb   $0x0,-0xf(%rbp,%rax,1)
  lea    -0xf(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  jmp    L8
L11:
  mov    $0xffffffffffffffff,%rax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
size_t u_char_index(const char *str, uint32_t c) {
  char ch[7];
  ch[u_char_to_u(c, ch)] = '\0';
  char *p = strstr(str, ch);
  return (p != NULL) ? p - str : -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<u_char_index>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    %rbp,%rsi
  call   <u_char_to_u@plt>
  movb   $0x0,0x1(%rsp,%rax,1)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovne %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t u_char_index(const char *str, uint32_t c) {
  char ch[7];
  ch[u_char_to_u(c, ch)] = '\0';
  char *p = strstr(str, ch);
  return (p != NULL) ? p - str : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<u_char_index>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    %rbp,%rsi
  call   <u_char_to_u@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  movb   $0x0,0x1(%rsp,%rax,1)
  call   <strstr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovne %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t u_char_index(const char *str, uint32_t c) {
  char ch[7];
  ch[u_char_to_u(c, ch)] = '\0';
  char *p = strstr(str, ch);
  return (p != NULL) ? p - str : -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u_char_index>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    %rbp,%rsi
  call   <u_char_to_u@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  movb   $0x0,0x1(%rsp,%rax,1)
  call   <strstr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovne %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t u_char_index(const char *str, uint32_t c) {
  char ch[7];
  ch[u_char_to_u(c, ch)] = '\0';
  char *p = strstr(str, ch);
  return (p != NULL) ? p - str : -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_shifting_signed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0xfffffffff80817f4,-0x8(%rbp)
  jne    L27
  mov    $0x1,%eax
  jmp    L6
L27:
  orq    $0xfffffffff0000000,-0x8(%rbp)
  cmpq   $0xfffffffff80817f4,-0x8(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L6
L38:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D18
datatype: string

tool: D9: Right shift isn't acting as I expect it to.


tool: D18: I fear the JPEG software will not work at all.



assistant: ```c
int is_shifting_signed(long arg) {
  long res = arg >> 4;
  if (res == -0x7F7E80CL) {
    return 1;
  }
  res |= (~0L) << (32 - 4);
  if (res == -0x7F7E80CL) {
    return 0;
  }
  printf("Right shift isn't acting as I expect it to.\n");
  printf("I fear the JPEG software will not work at all.\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_shifting_signed>:
  endbr64
  sar    $0x4,%rdi
  mov    $0x1,%eax
  cmp    $0xfffffffff80817f4,%rdi
  je     L8
  or     $0xfffffffff0000000,%rdi
  mov    $0x0,%eax
  cmp    $0xfffffffff80817f4,%rdi
  je     L8
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string

tool: D7: Right shift isn't acting as I expect it to.


tool: D10: I fear the JPEG software will not work at all.



assistant: ```c
int is_shifting_signed(long arg) {
  long res = arg >> 4;
  if (res == -0x7F7E80CL) {
    return 1;
  }
  res |= (~0L) << (32 - 4);
  if (res == -0x7F7E80CL) {
    return 0;
  }
  printf("Right shift isn't acting as I expect it to.\n");
  printf("I fear the JPEG software will not work at all.\n\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_shifting_signed>:
  endbr64
  sar    $0x4,%rdi
  push   %r12
  mov    $0x1,%r12d
  cmp    $0xfffffffff80817f4,%rdi
  je     L16
  or     $0xfffffffff0000000,%rdi
  xor    %r12d,%r12d
  cmp    $0xfffffffff80817f4,%rdi
  je     L16
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
L16:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string

tool: D1: Right shift isn't acting as I expect it to.


tool: D14: I fear the JPEG software will not work at all.



assistant: ```c
int is_shifting_signed(long arg) {
  long res = arg >> 4;
  if (res == -0x7F7E80CL) {
    return 1;
  }
  res |= (~0L) << (32 - 4);
  if (res == -0x7F7E80CL) {
    return 0;
  }
  printf("Right shift isn't acting as I expect it to.\n");
  printf("I fear the JPEG software will not work at all.\n\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_shifting_signed>:
  endbr64
  sar    $0x4,%rdi
  push   %r12
  mov    $0x1,%r12d
  cmp    $0xfffffffff80817f4,%rdi
  je     L0
  or     $0xfffffffff0000000,%rdi
  xor    %r12d,%r12d
  cmp    $0xfffffffff80817f4,%rdi
  je     L0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
L0:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D8: Right shift isn't acting as I expect it to.


tool: D3: I fear the JPEG software will not work at all.



assistant: ```c
int is_shifting_signed(long arg) {
  long res = arg >> 4;
  if (res == -0x7F7E80CL) {
    return 1;
  }
  res |= (~0L) << (32 - 4);
  if (res == -0x7F7E80CL) {
    return 0;
  }
  printf("Right shift isn't acting as I expect it to.\n");
  printf("I fear the JPEG software will not work at all.\n\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <compute_square@plt>
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <compute_square@plt>
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xc,-0x4(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L1
L4:
  nop
  mov    $0xffffffff,%eax
L1:
  leave
  ret
```

assistant: ```c
int main() {
  int x = 2;
  x = compute_square(x) + 2;
  x = compute_square(x) + 2;
  if (x != 12) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <compute_square@plt>
  lea    0x2(%rax),%edi
  call   <compute_square@plt>
  cmp    $0xa,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 2;
  x = compute_square(x) + 2;
  x = compute_square(x) + 2;
  if (x != 12) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <compute_square@plt>
  lea    0x2(%rax),%edi
  call   <compute_square@plt>
  cmp    $0xa,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int main() {
  int x = 2;
  x = compute_square(x) + 2;
  x = compute_square(x) + 2;
  if (x != 12) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <compute_square@plt>
  lea    0x2(%rax),%edi
  call   <compute_square@plt>
  cmp    $0xa,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int main() {
  int x = 2;
  x = compute_square(x) + 2;
  x = compute_square(x) + 2;
  if (x != 12) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L14:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jbe    L39
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
  jmp    L9
L39:
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  movzwl -0x12(%rbp),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0x13(%rbp)
  lea    -0xc(%rbp),%rdx
  add    $0x2,%rdx
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl -0x13(%rbp),%edx
  mov    %dl,(%rax)
L9:
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L14
  mov    -0xc(%rbp),%eax
  lea    -0x1e3dc72c(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%edi
  test   %edi,%edi
  je     L19
  lea    0x4(%rsp),%rax
  mov    $0x0,%edx
L29:
  mov    0x4(%rsp),%ecx
  cmp    %edx,%ecx
  jae    L17
  add    %ecx,%ecx
  mov    %ecx,(%rax)
L5:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edi,%edx
  jne    L29
L19:
  mov    0x4(%rsp),%eax
  sub    $0x1e3dc72c,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  ret
L17:
  movzwl (%rax),%ecx
  movzwl 0x2(%rax),%r8d
  mov    %r8w,(%rax)
  mov    %cx,0x2(%rax)
  movzbl 0x5(%rsp),%ecx
  movzbl 0x6(%rsp),%r8d
  mov    %r8b,0x5(%rsp)
  mov    %cl,0x6(%rsp)
  jmp    L5
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edi
  sub    $0x3f60a4d,%eax
  mov    %eax,0x4(%rsp)
  test   %edi,%edi
  je     L35
  lea    0x4(%rsp),%rdx
  xor    %ecx,%ecx
L27:
  cmp    %eax,%ecx
  jbe    L40
  add    %eax,%eax
  mov    %eax,(%rdx)
L48:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %edi,%ecx
  jne    L27
L35:
  sub    $0x1e3dc72c,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L40:
  movzwl (%rdx),%eax
  movzwl 0x2(%rdx),%r8d
  mov    %ax,0x2(%rdx)
  mov    %r8w,(%rdx)
  rolw   $0x8,0x5(%rsp)
  mov    0x4(%rsp),%eax
  jmp    L48
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%ecx
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  sub    $0x3f60a4d,%eax
  test   %ecx,%ecx
  je     L63
  mov    %eax,%esi
  mov    %eax,%edi
  rol    $0x10,%esi
  mov    %esi,0x4(%rsp)
  mov    %eax,%esi
  sar    $0x18,%esi
  mov    %al,0x5(%rsp)
  mov    %sil,0x6(%rsp)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%ecx
  jne    L30
L63:
  sub    $0x1e3dc72c,%eax
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L30:
  test   %eax,%eax
  je     L19
  movzwl 0x8(%rsp),%r8d
  movzwl 0xa(%rsp),%eax
  mov    %sil,0x5(%rsp)
  mov    %dil,0x6(%rsp)
  shl    $0x10,%r8d
  or     %r8d,%eax
  mov    %eax,0x8(%rsp)
  mov    0x4(%rsp),%eax
L57:
  cmp    $0x2,%ecx
  je     L63
  lea    0x4(%rsp),%rdi
  mov    $0x2,%esi
L32:
  cmp    %eax,%esi
  jbe    L6
  add    %eax,%eax
  mov    %eax,0x8(%rdi)
L43:
  add    $0x1,%esi
  add    $0x4,%rdi
  cmp    %ecx,%esi
  jne    L32
  jmp    L63
  nopl   (%rax)
L19:
  movl   $0x0,0x8(%rsp)
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L6:
  movzwl 0x8(%rdi),%r8d
  movzwl 0xa(%rdi),%eax
  shl    $0x10,%r8d
  or     %r8d,%eax
  mov    %eax,0x8(%rdi)
  rolw   $0x8,0x5(%rsp)
  mov    0x4(%rsp),%eax
  jmp    L43
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```