ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rcx
  lea    0x13(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L115:
  cmp    %rdx,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L115
L55:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L58
  orq    $0x0,-0x8(%rsp,%rax,1)
L58:
  lea    0x3(%rsp),%rsi
  mov    %rsi,%rdx
  shr    $0x2,%rdx
  and    $0xfffffffffffffffc,%rsi
  test   %rcx,%rcx
  je     L73
  mov    $0x1,%eax
L62:
  movl   $0x1,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jae    L62
  movl   $0x0,0x4(,%rdx,4)
  cmp    $0x1,%rcx
  jbe    L135
  mov    $0x4,%edi
  mov    $0x2,%eax
  mov    $0x0,%r8d
  jmp    L123
L31:
  lea    0x1(%rax),%rdx
  add    $0x2,%rdi
  cmp    %rax,%rcx
  je     L52
  mov    %rdx,%rax
L123:
  cmpl   $0x1,(%rsi,%rax,4)
  jne    L31
  add    %rax,%r8
  cmp    %rdi,%rcx
  jb     L31
  mov    %rdi,%rdx
L80:
  movl   $0x0,(%rsi,%rdx,4)
  add    %rax,%rdx
  cmp    %rcx,%rdx
  jbe    L80
  jmp    L31
L73:
  mov    %rcx,%r8
L52:
  mov    %r8,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  mov    $0x0,%eax
  leave
  ret
L135:
  mov    $0x0,%r8d
  jmp    L52
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long int N = atol(argv[1]);
  unsigned long int sum = 0;
  bool array[N + 1];
  for (unsigned long int i = 1; i <= N; i++) {
    array[i] = true;
  }
  array[1] = false;
  for (unsigned long int i = 2; i <= N; i++) {
    if (array[i] == true) {
      sum += i;
      for (unsigned long int j = 2; j * i <= N; j++) {
        array[j * i] = false;
      }
    }
  }
  printf("%ld\n", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <atol@plt>
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0x13(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L63
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L4
L63:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L2
L40:
  lea    0x3(%rsp),%rsi
  mov    %rsi,%rdx
  and    $0xfffffffffffffffc,%rsi
  shr    $0x2,%rdx
  test   %rcx,%rcx
  je     L12
  mov    $0x1,%eax
  nopl   0x0(%rax)
L89:
  movl   $0x1,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jae    L89
  movl   $0x0,0x4(,%rdx,4)
  cmp    $0x1,%rcx
  jbe    L12
  mov    $0x4,%edi
  mov    $0x2,%eax
  xor    %r8d,%r8d
  jmp    L107
  nopl   0x0(%rax)
L21:
  lea    0x1(%rax),%rdx
  add    $0x2,%rdi
  cmp    %rax,%rcx
  je     L117
L3:
  mov    %rdx,%rax
L107:
  cmpl   $0x1,(%rsi,%rax,4)
  jne    L21
  add    %rax,%r8
  cmp    %rdi,%rcx
  jb     L21
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L144:
  movl   $0x0,(%rsi,%rdx,4)
  add    %rax,%rdx
  cmp    %rcx,%rdx
  jbe    L144
  lea    0x1(%rax),%rdx
  add    $0x2,%rdi
  cmp    %rax,%rcx
  jne    L3
  nopl   0x0(%rax)
L117:
  mov    %r8,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  leave
  xor    %eax,%eax
  ret
L2:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L12:
  xor    %r8d,%r8d
  jmp    L117
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long int N = atol(argv[1]);
  unsigned long int sum = 0;
  bool array[N + 1];
  for (unsigned long int i = 1; i <= N; i++) {
    array[i] = true;
  }
  array[1] = false;
  for (unsigned long int i = 2; i <= N; i++) {
    if (array[i] == true) {
      sum += i;
      for (unsigned long int j = 2; j * i <= N; j++) {
        array[j * i] = false;
      }
    }
  }
  printf("%ld\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <atol@plt>
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0x13(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L138
L44:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L44
L138:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L56
L33:
  lea    0x3(%rsp),%rsi
  mov    %rsi,%r8
  and    $0xfffffffffffffffc,%rsi
  shr    $0x2,%r8
  test   %rcx,%rcx
  je     L37
  lea    -0x1(%rcx),%rax
  cmp    $0x4,%rax
  jbe    L103
  cmp    $0xffffffffffffffff,%rcx
  je     L103
  mov    %rcx,%rdi
  movdqa D9(%rip),%xmm0
  xor    %eax,%eax
  shr    $0x2,%rdi
L203:
  mov    %rax,%rdx
  add    $0x1,%rax
  shl    $0x4,%rdx
  movups %xmm0,0x4(%rsi,%rdx,1)
  cmp    %rax,%rdi
  ja     L203
  mov    %rcx,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%cl
  je     L184
  lea    (%rsi,%rax,4),%rdx
  lea    0x2(%rax),%rdi
  movl   $0x1,0x4(%rdx)
  cmp    %rdi,%rcx
  jb     L52
  add    $0x3,%rax
  movl   $0x1,0x8(%rdx)
  cmp    %rax,%rcx
  jb     L184
  movl   $0x1,0xc(%rdx)
L184:
  movl   $0x0,0x4(,%r8,4)
L7:
  mov    $0x4,%edi
  mov    $0x2,%eax
  xor    %r8d,%r8d
  jmp    L170
  nopl   0x0(%rax,%rax,1)
L53:
  add    $0x1,%rax
  add    $0x2,%rdi
  cmp    %rax,%rcx
  jb     L140
L170:
  cmpl   $0x1,(%rsi,%rax,4)
  jne    L53
  add    %rax,%r8
  cmp    %rdi,%rcx
  jb     L53
  mov    %rdi,%rdx
  xchg   %ax,%ax
L43:
  movl   $0x0,(%rsi,%rdx,4)
  add    %rax,%rdx
  cmp    %rdx,%rcx
  jae    L43
  add    $0x1,%rax
  add    $0x2,%rdi
  cmp    %rax,%rcx
  jae    L170
  nopl   0x0(%rax)
L140:
  mov    %r8,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L133
  leave
  xor    %eax,%eax
  ret
L103:
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L179:
  movl   $0x1,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jbe    L179
L52:
  movl   $0x0,0x4(,%r8,4)
  cmp    $0x1,%rcx
  jne    L7
L37:
  xor    %r8d,%r8d
  jmp    L140
L56:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L33
L133:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: byte[16]
name: retrieve_data
arguments: data_label: D11
type_infered: string

tool: {"D9": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D11: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long int N = atol(argv[1]);
  unsigned long int sum = 0;
  bool array[N + 1];
  for (unsigned long int i = 1; i <= N; i++) {
    array[i] = true;
  }
  array[1] = false;
  for (unsigned long int i = 2; i <= N; i++) {
    if (array[i] == true) {
      sum += i;
      for (unsigned long int j = 2; j * i <= N; j++) {
        array[j * i] = false;
      }
    }
  }
  printf("%ld\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x860,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2858(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x2850(%rbp),%rax
  mov    $0x27d9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x2854(%rbp)
  jmp    L24
L8:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x2850(%rbp),%rcx
  mov    -0x2854(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rsi
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    (%rcx,%rax,1),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  addl   $0x1,-0x2854(%rbp)
L24:
  mov    -0x2858(%rbp),%eax
  cmp    %eax,-0x2854(%rbp)
  jl     L8
  mov    -0x2858(%rbp),%eax
  lea    -0x2850(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <displayPathtoPrincess@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string

tool: D8: %d

tool: D13: %s

assistant: ```c
int main(void) {
  int m;
  scanf("%d", &m);
  char grid[101][101] = {};
  char line[101];
  for (int i = 0; i < m; i++) {
    scanf("%s", line);
    strcpy(grid[i], line);
  }
  displayPathtoPrincess(m, grid);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x868,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2858(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x27d9,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  jle    L13
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D17(%rip),%r13
L19:
  lea    0x27f0(%rsp),%r12
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%edi
  add    $0x65,%rbp
  cmp    %ebx,%edi
  jg     L19
L13:
  lea    0x10(%rsp),%rsi
  call   <displayPathtoPrincess@plt>
  mov    0x2858(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x2868,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D11: %d

tool: D17: %s

assistant: ```c
int main(void) {
  int m;
  scanf("%d", &m);
  char grid[101][101] = {};
  char line[101];
  for (int i = 0; i < m; i++) {
    scanf("%s", line);
    strcpy(grid[i], line);
  }
  displayPathtoPrincess(m, grid);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x860,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2858(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r14
  call   <scanf@plt>
  mov    %r14,%rdi
  mov    $0x27d9,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  jle    L19
  mov    %r14,%rbp
  xor    %ebx,%ebx
  lea    0x27f0(%rsp),%r12
  lea    D4(%rip),%r13
  nop
L15:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  add    $0x65,%rbp
  call   <strcpy@plt>
  mov    0xc(%rsp),%edi
  cmp    %ebx,%edi
  jg     L15
L19:
  mov    %r14,%rsi
  call   <displayPathtoPrincess@plt>
  mov    0x2858(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x2860,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: string

tool: D6: %d

tool: D4: %s

assistant: ```c
int main(void) {
  int m;
  scanf("%d", &m);
  char grid[101][101] = {};
  char line[101];
  for (int i = 0; i < m; i++) {
    scanf("%s", line);
    strcpy(grid[i], line);
  }
  displayPathtoPrincess(m, grid);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x860,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2858(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r14
  call   <scanf@plt>
  mov    %r14,%rdi
  mov    $0x27d9,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  jle    L16
  mov    %r14,%rbp
  xor    %ebx,%ebx
  lea    0x27f0(%rsp),%r12
  lea    D8(%rip),%r13
  nop
L20:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  add    $0x65,%rbp
  call   <strcpy@plt>
  mov    0xc(%rsp),%edi
  cmp    %ebx,%edi
  jg     L20
L16:
  mov    %r14,%rsi
  call   <displayPathtoPrincess@plt>
  mov    0x2858(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x2860,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D7: %d

tool: D8: %s

assistant: ```c
int main(void) {
  int m;
  scanf("%d", &m);
  char grid[101][101] = {};
  char line[101];
  for (int i = 0; i < m; i++) {
    scanf("%s", line);
    strcpy(grid[i], line);
  }
  displayPathtoPrincess(m, grid);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0xa,-0x8(%rbp)
L12:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L4
  mov    -0x4(%rbp),%eax
  jmp    L1
L4:
  mov    D13(%rip),%rax
  mov    (%rax),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L22
  subl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L12
  jmp    L23
L22:
  nop
L23:
  mov    $0xffffffff,%eax
L1:
  leave
  ret
```

assistant: ```c
int xopen(const char *name, int flags, mode_t mode) {
  unsigned int retry = 10;
  do {
    int fd = open(name, flags, mode);
    if (__builtin_expect(fd >= 0, 1))
      return fd;
    if (EINTR != errno)
      break;
  } while (--retry > 0);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xopen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    $0xa,%ebp
L25:
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  not    %edi
  shr    $0x1f,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L10
  mov    D10(%rip),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L27
  sub    $0x1,%ebp
  jne    L25
  mov    $0xffffffff,%ebx
L10:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    $0xffffffff,%ebx
  jmp    L10
```

assistant: ```c
int xopen(const char *name, int flags, mode_t mode) {
  unsigned int retry = 10;
  do {
    int fd = open(name, flags, mode);
    if (__builtin_expect(fd >= 0, 1))
      return fd;
    if (EINTR != errno)
      break;
  } while (--retry > 0);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xopen>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L19:
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %ebp,%edx
  call   <open@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  not    %edi
  shr    $0x1f,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L22
  mov    D18(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L21
  sub    $0x1,%ebx
  jne    L19
L21:
  mov    $0xffffffff,%r12d
L22:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int xopen(const char *name, int flags, mode_t mode) {
  unsigned int retry = 10;
  do {
    int fd = open(name, flags, mode);
    if (__builtin_expect(fd >= 0, 1))
      return fd;
    if (EINTR != errno)
      break;
  } while (--retry > 0);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xopen>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L13:
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %ebp,%edx
  call   <open@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  not    %edi
  shr    $0x1f,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L5
  mov    D0(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L24
  sub    $0x1,%ebx
  jne    L13
L24:
  mov    $0xffffffff,%r12d
L5:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int xopen(const char *name, int flags, mode_t mode) {
  unsigned int retry = 10;
  do {
    int fd = open(name, flags, mode);
    if (__builtin_expect(fd >= 0, 1))
      return fd;
    if (EINTR != errno)
      break;
  } while (--retry > 0);
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<MakeSegv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x9,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void MakeSegv() {
  volatile int *p;
  int i;
  p = (volatile int *)0x9;
  i = *p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MakeSegv>:
  endbr64
  mov    0x9,%eax
  ret
```

assistant: ```c
void MakeSegv() {
  volatile int *p;
  int i;
  p = (volatile int *)0x9;
  i = *p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MakeSegv>:
  endbr64
  mov    0x9,%eax
  ret
```

assistant: ```c
void MakeSegv() {
  volatile int *p;
  int i;
  p = (volatile int *)0x9;
  i = *p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MakeSegv>:
  endbr64
  mov    0x9,%eax
  ret
```

assistant: ```c
void MakeSegv() {
  volatile int *p;
  int i;
  p = (volatile int *)0x9;
  i = *p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xffffffd6,-0x8(%rbp)
  movl   $0xffffffdd,-0x4(%rbp)
  movl   $0xfffffff8,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  int a = -42;
  int b = -35;
  if (a = -8)
    return a;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  mov    $0xfffffff8,%eax
  ret
```

assistant: ```c
int f() {
  int a = -42;
  int b = -35;
  if (a = -8)
    return a;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  mov    $0xfffffff8,%eax
  ret
```

assistant: ```c
int f() {
  int a = -42;
  int b = -35;
  if (a = -8)
    return a;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  mov    $0xfffffff8,%eax
  ret
```

assistant: ```c
int f() {
  int a = -42;
  int b = -35;
  if (a = -8)
    return a;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<knot_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  jmp    L6
L4:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
L6:
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  jmp    L20
L57:
  nop
L20:
  cmpq   $0x0,-0x8(%rbp)
  jne    L39
  cmpq   $0x0,-0x38(%rbp)
  je     L0
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L0:
  nop
L47:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
L39:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t knot_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<knot_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L57
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
L42:
  cmp    %rcx,%rdi
  je     L2
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L42
  jmp    L9
L57:
  mov    %rsi,%rax
L46:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L46
L9:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L2:
  movb   $0x0,(%rdi)
  jmp    L46
```

assistant: ```c
size_t knot_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<knot_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L41
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L33:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L5
L17:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L33
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L37
L5:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L37
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t knot_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<knot_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L25
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L20:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L29
L0:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L20
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L9
L29:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L9
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t knot_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```