ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<runes_vwarn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  nop
  leave
  ret
```

assistant: ```c
void runes_vwarn(const char *fmt, va_list ap) {
  size_t fmt_len;
  char *fmt_with_nl;
  fmt_len = strlen(fmt);
  fmt_with_nl = malloc(fmt_len + 2);
  strcpy(fmt_with_nl, fmt);
  fmt_with_nl[fmt_len] = '\n';
  fmt_with_nl[fmt_len + 1] = '\0';
  vfprintf(stderr, fmt_with_nl, ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<runes_vwarn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x2(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movb   $0xa,(%rbx,%rbp,1)
  movb   $0x0,0x1(%rbx,%rbp,1)
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void runes_vwarn(const char *fmt, va_list ap) {
  size_t fmt_len;
  char *fmt_with_nl;
  fmt_len = strlen(fmt);
  fmt_with_nl = malloc(fmt_len + 2);
  strcpy(fmt_with_nl, fmt);
  fmt_with_nl[fmt_len] = '\n';
  fmt_with_nl[fmt_len + 1] = '\0';
  vfprintf(stderr, fmt_with_nl, ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<runes_vwarn>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x2(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  movb   $0xa,0x0(%rbp,%rbx,1)
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    D8(%rip),%rax
  movb   $0x0,0x1(%rbp,%rbx,1)
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <vfprintf@plt>
```

assistant: ```c
void runes_vwarn(const char *fmt, va_list ap) {
  size_t fmt_len;
  char *fmt_with_nl;
  fmt_len = strlen(fmt);
  fmt_with_nl = malloc(fmt_len + 2);
  strcpy(fmt_with_nl, fmt);
  fmt_with_nl[fmt_len] = '\n';
  fmt_with_nl[fmt_len + 1] = '\0';
  vfprintf(stderr, fmt_with_nl, ap);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<runes_vwarn>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x2(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  movb   $0xa,0x0(%rbp,%rbx,1)
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    D3(%rip),%rax
  movb   $0x0,0x1(%rbp,%rbx,1)
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <vfprintf@plt>
```

assistant: ```c
void runes_vwarn(const char *fmt, va_list ap) {
  size_t fmt_len;
  char *fmt_with_nl;
  fmt_len = strlen(fmt);
  fmt_with_nl = malloc(fmt_len + 2);
  strcpy(fmt_with_nl, fmt);
  fmt_with_nl[fmt_len] = '\n';
  fmt_with_nl[fmt_len + 1] = '\0';
  vfprintf(stderr, fmt_with_nl, ap);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nowarn_malloc_3_5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  jbe    L14
  cmpl   $0x5,-0x1c(%rbp)
  jbe    L3
L14:
  movl   $0x3,-0x1c(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *nowarn_malloc_3_5(const char *s, unsigned n) {
  if (n < 3 || 5 < n)
    n = 3;
  char *p = (char *)malloc(n);
  strncpy(p + 1, s, 4);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nowarn_malloc_3_5>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    -0x3(%rsi),%eax
  cmp    $0x3,%eax
  mov    $0x3,%eax
  cmovae %eax,%esi
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *nowarn_malloc_3_5(const char *s, unsigned n) {
  if (n < 3 || 5 < n)
    n = 3;
  char *p = (char *)malloc(n);
  strncpy(p + 1, s, 4);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nowarn_malloc_3_5>:
  endbr64
  push   %r12
  lea    -0x3(%rsi),%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    $0x3,%eax
  mov    $0x3,%eax
  cmovae %eax,%esi
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x4,%edx
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *nowarn_malloc_3_5(const char *s, unsigned n) {
  if (n < 3 || 5 < n)
    n = 3;
  char *p = (char *)malloc(n);
  strncpy(p + 1, s, 4);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nowarn_malloc_3_5>:
  endbr64
  push   %r12
  lea    -0x3(%rsi),%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    $0x3,%eax
  mov    $0x3,%eax
  cmovae %eax,%esi
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x4,%edx
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *nowarn_malloc_3_5(const char *s, unsigned n) {
  if (n < 3 || 5 < n)
    n = 3;
  char *p = (char *)malloc(n);
  strncpy(p + 1, s, 4);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zeroIt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L9:
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L17:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L31:
  cmpl   $0x7,-0x4(%rbp)
  jle    L17
  addl   $0x1,-0x8(%rbp)
L25:
  cmpl   $0x7,-0x8(%rbp)
  jle    L9
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zeroIt(int chess[][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      chess[i][j] = 0;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zeroIt>:
  endbr64
  lea    0x100(%rdi),%rax
L3:
  movl   $0x0,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0x0,0x10(%rdi)
  movl   $0x0,0x14(%rdi)
  movl   $0x0,0x18(%rdi)
  movl   $0x0,0x1c(%rdi)
  add    $0x20,%rdi
  cmp    %rdi,%rax
  jne    L3
  ret
```

assistant: ```c
void zeroIt(int chess[][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      chess[i][j] = 0;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zeroIt>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0xf0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x100(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void zeroIt(int chess[][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      chess[i][j] = 0;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zeroIt>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movups %xmm0,0x40(%rdi)
  movups %xmm0,0x50(%rdi)
  movups %xmm0,0x60(%rdi)
  movups %xmm0,0x70(%rdi)
  movups %xmm0,0x80(%rdi)
  movups %xmm0,0x90(%rdi)
  movups %xmm0,0xa0(%rdi)
  movups %xmm0,0xb0(%rdi)
  movups %xmm0,0xc0(%rdi)
  movups %xmm0,0xd0(%rdi)
  movups %xmm0,0xe0(%rdi)
  movups %xmm0,0xf0(%rdi)
  ret
```

assistant: ```c
void zeroIt(int chess[][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      chess[i][j] = 0;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bitmask_from_cells>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  or     %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x4,-0xc(%rbp)
  jle    L11
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long bitmask_from_cells(char *cell) {
  unsigned long long piece_mask = 0ULL;
  int i;
  for (i = 0; i < 5; i++)
    piece_mask |= 1ULL << cell[i];
  return piece_mask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmask_from_cells>:
  endbr64
  lea    0x5(%rdi),%r8
  mov    $0x0,%eax
  mov    $0x1,%esi
L3:
  movsbl (%rdi),%ecx
  mov    %rsi,%rdx
  shl    %cl,%rdx
  or     %rdx,%rax
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L3
  ret
```

assistant: ```c
unsigned long long bitmask_from_cells(char *cell) {
  unsigned long long piece_mask = 0ULL;
  int i;
  for (i = 0; i < 5; i++)
    piece_mask |= 1ULL << cell[i];
  return piece_mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmask_from_cells>:
  endbr64
  lea    0x5(%rdi),%r8
  xor    %eax,%eax
  mov    $0x1,%esi
L6:
  movsbl (%rdi),%ecx
  mov    %rsi,%rdx
  add    $0x1,%rdi
  shl    %cl,%rdx
  or     %rdx,%rax
  cmp    %r8,%rdi
  jne    L6
  ret
```

assistant: ```c
unsigned long long bitmask_from_cells(char *cell) {
  unsigned long long piece_mask = 0ULL;
  int i;
  for (i = 0; i < 5; i++)
    piece_mask |= 1ULL << cell[i];
  return piece_mask;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitmask_from_cells>:
  endbr64
  movsbl 0x2(%rdi),%ecx
  movsbl 0x1(%rdi),%edx
  mov    $0x1,%eax
  shl    %cl,%rax
  bts    %rdx,%rax
  movsbl (%rdi),%edx
  bts    %rdx,%rax
  movsbl 0x3(%rdi),%edx
  bts    %rdx,%rax
  movsbl 0x4(%rdi),%edx
  bts    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long bitmask_from_cells(char *cell) {
  unsigned long long piece_mask = 0ULL;
  int i;
  for (i = 0; i < 5; i++)
    piece_mask |= 1ULL << cell[i];
  return piece_mask;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rand_perm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <dl_malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x1,%edi
  call   <usleep@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  not    %rax
  shr    $0x3f,%rax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  imul   $0x75bcd15,%eax,%edx
  mov    -0x20(%rbp),%rax
  imul   $0x3ade68b1,%eax,%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L11
L17:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x2c(%rbp),%edx
  lea    0x1(%rdx),%esi
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idiv   %esi
  mov    %edx,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0x2c(%rbp)
L11:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L17
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int *rand_perm(int n) {
  int *v = dl_malloc((size_t)n * sizeof(int)), i;
  usleep(1);
  struct timespec tv;
  assert(clock_gettime(CLOCK_REALTIME, &tv) >= 0);
  srand((unsigned int)tv.tv_nsec * 123456789u + (unsigned int)tv.tv_sec * 987654321u);
  for (i = 0; i < n; i++) {
    v[i] = rand() % (i + 1);
  }
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rand_perm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  shl    $0x2,%rdi
  call   <dl_malloc@plt>
  mov    %rax,%rbp
  mov    $0x1,%edi
  call   <usleep@plt>
  mov    %rsp,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  not    %rax
  mov    %rax,%rdi
  shr    $0x3f,%rdi
  call   <assert@plt>
  imul   $0x75bcd15,0x8(%rsp),%edi
  imul   $0x3ade68b1,(%rsp),%eax
  add    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L10
  lea    0x1(%rbx),%r12d
  mov    $0x1,%ebx
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,-0x4(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L12
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbp,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *rand_perm(int n) {
  int *v = dl_malloc((size_t)n * sizeof(int)), i;
  usleep(1);
  struct timespec tv;
  assert(clock_gettime(CLOCK_REALTIME, &tv) >= 0);
  srand((unsigned int)tv.tv_nsec * 123456789u + (unsigned int)tv.tv_sec * 987654321u);
  for (i = 0; i < n; i++) {
    v[i] = rand() % (i + 1);
  }
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rand_perm>:
  endbr64
  push   %r12
  movslq %edi,%rdi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x2,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <dl_malloc@plt>
  mov    $0x1,%edi
  mov    %rax,%r12
  call   <usleep@plt>
  mov    D5(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  not    %rax
  mov    %rax,%rdi
  shr    $0x3f,%rdi
  call   <assert@plt>
  imul   $0x75bcd15,0x8(%rsp),%edi
  imul   $0x3ade68b1,(%rsp),%eax
  add    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L24
  lea    0x1(%rbx),%ebp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,-0x4(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *rand_perm(int n) {
  int *v = dl_malloc((size_t)n * sizeof(int)), i;
  usleep(1);
  struct timespec tv;
  assert(clock_gettime(CLOCK_REALTIME, &tv) >= 0);
  srand((unsigned int)tv.tv_nsec * 123456789u + (unsigned int)tv.tv_sec * 987654321u);
  for (i = 0; i < n; i++) {
    v[i] = rand() % (i + 1);
  }
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rand_perm>:
  endbr64
  push   %r12
  movslq %edi,%rdi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x2,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <dl_malloc@plt>
  mov    $0x1,%edi
  mov    %rax,%r12
  call   <usleep@plt>
  mov    D3(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  not    %rax
  mov    %rax,%rdi
  shr    $0x3f,%rdi
  call   <assert@plt>
  imul   $0x75bcd15,0x8(%rsp),%edi
  imul   $0x3ade68b1,(%rsp),%eax
  add    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L18
  lea    0x1(%rbx),%ebp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,-0x4(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L25
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *rand_perm(int n) {
  int *v = dl_malloc((size_t)n * sizeof(int)), i;
  usleep(1);
  struct timespec tv;
  assert(clock_gettime(CLOCK_REALTIME, &tv) >= 0);
  srand((unsigned int)tv.tv_nsec * 123456789u + (unsigned int)tv.tv_sec * 987654321u);
  for (i = 0; i < n; i++) {
    v[i] = rand() % (i + 1);
  }
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convert_BGR_ARGB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L17:
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
  addq   $0x18,-0x10(%rbp)
  addq   $0x20,-0x8(%rbp)
L12:
  mov    -0x34(%rbp),%eax
  imul   -0x38(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L17
  nop
  pop    %rbp
  ret
```

assistant: ```c
void convert_BGR_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t *p_src = src, *p_dst = dst;
  for (i = 0; i < w * h; i++, p_src += 3, p_dst += 4) {
    p_dst[0] = 0;
    p_dst[1] = p_src[2];
    p_dst[2] = p_src[1];
    p_dst[3] = p_src[0];
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convert_BGR_ARGB>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  shl    $0x5,%rdx
  lea    (%rsi,%rdx,1),%rax
L18:
  movq   $0x0,(%rsi)
  mov    0x10(%rdi),%rdx
  mov    %rdx,0x8(%rsi)
  mov    0x8(%rdi),%rdx
  mov    %rdx,0x10(%rsi)
  mov    (%rdi),%rdx
  mov    %rdx,0x18(%rsi)
  add    $0x18,%rdi
  add    $0x20,%rsi
  cmp    %rax,%rsi
  jne    L18
L17:
  ret
```

assistant: ```c
void convert_BGR_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t *p_src = src, *p_dst = dst;
  for (i = 0; i < w * h; i++, p_src += 3, p_dst += 4) {
    p_dst[0] = 0;
    p_dst[1] = p_src[2];
    p_dst[2] = p_src[1];
    p_dst[3] = p_src[0];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_BGR_ARGB>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  shl    $0x5,%rdx
  lea    (%rsi,%rdx,1),%rax
  cs nopw 0x0(%rax,%rax,1)
L15:
  movq   $0x0,(%rsi)
  mov    0x10(%rdi),%rdx
  add    $0x20,%rsi
  add    $0x18,%rdi
  mov    %rdx,-0x18(%rsi)
  mov    -0x10(%rdi),%rdx
  mov    %rdx,-0x10(%rsi)
  mov    -0x18(%rdi),%rdx
  mov    %rdx,-0x8(%rsi)
  cmp    %rax,%rsi
  jne    L15
L14:
  ret
```

assistant: ```c
void convert_BGR_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t *p_src = src, *p_dst = dst;
  for (i = 0; i < w * h; i++, p_src += 3, p_dst += 4) {
    p_dst[0] = 0;
    p_dst[1] = p_src[2];
    p_dst[2] = p_src[1];
    p_dst[3] = p_src[0];
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_BGR_ARGB>:
  endbr64
  imul   %edx,%ecx
  test   %ecx,%ecx
  jle    L52
  movslq %ecx,%rax
  mov    %rax,%rdx
  lea    (%rax,%rax,2),%rax
  shl    $0x5,%rdx
  lea    (%rdi,%rax,8),%rax
  add    %rsi,%rdx
  cmp    %rdx,%rdi
  setae  %dl
  cmp    %rax,%rsi
  setae  %al
  or     %al,%dl
  je     L8
  lea    -0x1(%rcx),%eax
  cmp    $0x2,%eax
  jbe    L8
  mov    %ecx,%r8d
  mov    %rdi,%rdx
  pxor   %xmm5,%xmm5
  mov    %rsi,%rax
  shr    %r8d
  sub    $0x1,%r8d
  shl    $0x6,%r8
  lea    0x40(%rsi,%r8,1),%r8
  nopl   0x0(%rax)
L4:
  movdqu (%rdx),%xmm2
  movdqu 0x10(%rdx),%xmm6
  add    $0x40,%rax
  add    $0x30,%rdx
  movdqu -0x10(%rdx),%xmm7
  movdqa %xmm2,%xmm1
  movdqa %xmm6,%xmm0
  movdqa %xmm2,%xmm4
  shufpd $0x1,%xmm2,%xmm1
  punpcklqdq %xmm7,%xmm1
  punpcklqdq %xmm2,%xmm0
  movdqa %xmm5,%xmm2
  movdqa %xmm1,%xmm3
  psrldq $0x8,%xmm1
  shufpd $0x2,%xmm7,%xmm0
  shufpd $0x2,%xmm6,%xmm4
  punpcklqdq %xmm1,%xmm2
  pslldq $0x8,%xmm3
  movdqa %xmm0,%xmm1
  punpcklqdq %xmm4,%xmm1
  punpckhqdq %xmm4,%xmm0
  movdqa %xmm3,%xmm4
  punpcklqdq %xmm1,%xmm4
  punpckhqdq %xmm1,%xmm3
  movdqa %xmm2,%xmm1
  punpcklqdq %xmm0,%xmm1
  punpckhqdq %xmm0,%xmm2
  movups %xmm4,-0x40(%rax)
  movups %xmm3,-0x30(%rax)
  movups %xmm1,-0x20(%rax)
  movups %xmm2,-0x10(%rax)
  cmp    %rax,%r8
  jne    L4
  mov    %ecx,%r8d
  and    $0xfffffffe,%r8d
  mov    %r8d,%eax
  lea    (%rax,%rax,2),%rdx
  shl    $0x5,%rax
  lea    (%rdi,%rdx,8),%rdx
  add    %rsi,%rax
  cmp    %r8d,%ecx
  je     L52
  movq   $0x0,(%rax)
  mov    0x10(%rdx),%rcx
  mov    %rcx,0x8(%rax)
  mov    0x8(%rdx),%rcx
  mov    %rcx,0x10(%rax)
  mov    (%rdx),%rdx
  mov    %rdx,0x18(%rax)
  ret
  nopl   0x0(%rax)
L8:
  mov    %ecx,%ecx
  shl    $0x5,%rcx
  lea    (%rsi,%rcx,1),%rax
  nopw   0x0(%rax,%rax,1)
L28:
  movq   $0x0,(%rsi)
  mov    0x10(%rdi),%rdx
  add    $0x20,%rsi
  add    $0x18,%rdi
  mov    %rdx,-0x18(%rsi)
  mov    -0x10(%rdi),%rdx
  mov    %rdx,-0x10(%rsi)
  mov    -0x18(%rdi),%rdx
  mov    %rdx,-0x8(%rsi)
  cmp    %rax,%rsi
  jne    L28
L52:
  ret
```

assistant: ```c
void convert_BGR_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t *p_src = src, *p_dst = dst;
  for (i = 0; i < w * h; i++, p_src += 3, p_dst += 4) {
    p_dst[0] = 0;
    p_dst[1] = p_src[2];
    p_dst[2] = p_src[1];
    p_dst[3] = p_src[0];
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<cpuset_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  nop
  leave
  ret
```

assistant: ```c
int cpuset_create(void) {
  int fd;
  fd = open();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpuset_create>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <open@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cpuset_create(void) {
  int fd;
  fd = open();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cpuset_create>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <open@plt>
```

assistant: ```c
int cpuset_create(void) {
  int fd;
  fd = open();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cpuset_create>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <open@plt>
```

assistant: ```c
int cpuset_create(void) {
  int fd;
  fd = open();
}
```