ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<badalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: internal error: bad alloc


assistant: ```c
void badalloc() {
  printf("internal error: bad alloc\n");
  exit(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<badalloc>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: internal error: bad alloc


assistant: ```c
void badalloc() {
  printf("internal error: bad alloc\n");
  exit(-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<badalloc>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: internal error: bad alloc


assistant: ```c
void badalloc() {
  printf("internal error: bad alloc\n");
  exit(-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<badalloc>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: internal error: bad alloc


assistant: ```c
void badalloc() {
  printf("internal error: bad alloc\n");
  exit(-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  jmp    L18
L8:
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string

tool: D1: w

tool: D11: Wrap creating "%s"


tool: D0: int foo() { return 0; }


assistant: ```c
int main(int argc, const char *argv[]) {
  FILE *fout = fopen(argv[argc - 1], "w");
  printf("Wrap creating \"%s\"\n", argv[argc - 1]);
  if (fout) {
    fprintf(fout, "int foo() { return 0; }\n");
    fclose(fout);
  } else {
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %edi,%rdi
  lea    -0x8(%rsi,%rdi,8),%rbp
  lea    D15(%rip),%rsi
  mov    0x0(%rbp),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    0x0(%rbp),%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  test   %rbx,%rbx
  je     L3
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D5
type: string

tool: D15: w

tool: D18: Wrap creating "%s"


tool: D5: int foo() { return 0; }


assistant: ```c
int main(int argc, const char *argv[]) {
  FILE *fout = fopen(argv[argc - 1], "w");
  printf("Wrap creating \"%s\"\n", argv[argc - 1]);
  if (fout) {
    fprintf(fout, "int foo() { return 0; }\n");
    fclose(fout);
  } else {
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  push   %rbx
  lea    -0x8(%rsi,%rdi,8),%rbx
  lea    D19(%rip),%rsi
  sub    $0x8,%rsp
  mov    (%rbx),%rdi
  call   <fopen@plt>
  mov    (%rbx),%rsi
  lea    D17(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  test   %rbp,%rbp
  je     L7
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  or     $0xffffffff,%eax
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D19: w

tool: D17: Wrap creating "%s"


tool: D9: int foo() { return 0; }


assistant: ```c
int main(int argc, const char *argv[]) {
  FILE *fout = fopen(argv[argc - 1], "w");
  printf("Wrap creating \"%s\"\n", argv[argc - 1]);
  if (fout) {
    fprintf(fout, "int foo() { return 0; }\n");
    fclose(fout);
  } else {
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  push   %rbx
  lea    -0x8(%rsi,%rdi,8),%rbx
  lea    D25(%rip),%rsi
  sub    $0x8,%rsp
  mov    (%rbx),%rdi
  call   <fopen@plt>
  mov    (%rbx),%rsi
  lea    D14(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  test   %rbp,%rbp
  je     L7
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  or     $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D20
datatype: string

tool: D25: w

tool: D14: Wrap creating "%s"


tool: D20: int foo() { return 0; }


assistant: ```c
int main(int argc, const char *argv[]) {
  FILE *fout = fopen(argv[argc - 1], "w");
  printf("Wrap creating \"%s\"\n", argv[argc - 1]);
  if (fout) {
    fprintf(fout, "int foo() { return 0; }\n");
    fclose(fout);
  } else {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<change_pattern_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L6
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *change_pattern_length(int *old_pattern, int num_tracks, int old_length, int new_length) {
  int old_sz = num_tracks * old_length;
  int new_sz = num_tracks * new_length;
  int *new_pattern = realloc(old_pattern, sizeof(int) * new_sz);
  if (new_pattern == NULL) {
  }
  if (new_length > old_length) {
    memset(new_pattern + old_sz, 0, sizeof(int) * (new_sz - old_sz));
  }
  return new_pattern;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<change_pattern_length>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %ecx,%ebp
  mov    %esi,%r13d
  imul   %ecx,%r13d
  lea    0x0(,%r13,4),%esi
  call   <realloc@plt>
  mov    %rax,%r14
  cmp    %ebp,%r12d
  jl     L11
L7:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  imul   %r12d,%ebx
  sub    %ebx,%r13d
  lea    0x0(,%r13,4),%edx
  movslq %ebx,%rbx
  lea    (%rax,%rbx,4),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  jmp    L7
```

assistant: ```c
int *change_pattern_length(int *old_pattern, int num_tracks, int old_length, int new_length) {
  int old_sz = num_tracks * old_length;
  int new_sz = num_tracks * new_length;
  int *new_pattern = realloc(old_pattern, sizeof(int) * new_sz);
  if (new_pattern == NULL) {
  }
  if (new_length > old_length) {
    memset(new_pattern + old_sz, 0, sizeof(int) * (new_sz - old_sz));
  }
  return new_pattern;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<change_pattern_length>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  imul   %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%r14,4),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  cmp    %ebp,%r13d
  jl     L0
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  imul   %r13d,%ebx
  xor    %esi,%esi
  sub    %ebx,%r14d
  movslq %ebx,%rbx
  lea    0x0(,%r14,4),%edx
  lea    (%rax,%rbx,4),%rdi
  call   <memset@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *change_pattern_length(int *old_pattern, int num_tracks, int old_length, int new_length) {
  int old_sz = num_tracks * old_length;
  int new_sz = num_tracks * new_length;
  int *new_pattern = realloc(old_pattern, sizeof(int) * new_sz);
  if (new_pattern == NULL) {
  }
  if (new_length > old_length) {
    memset(new_pattern + old_sz, 0, sizeof(int) * (new_sz - old_sz));
  }
  return new_pattern;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<change_pattern_length>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  imul   %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%r14,4),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  cmp    %ebp,%r13d
  jl     L7
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  imul   %r13d,%ebx
  xor    %esi,%esi
  sub    %ebx,%r14d
  movslq %ebx,%rbx
  lea    0x0(,%r14,4),%edx
  lea    (%rax,%rbx,4),%rdi
  call   <memset@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *change_pattern_length(int *old_pattern, int num_tracks, int old_length, int new_length) {
  int old_sz = num_tracks * old_length;
  int new_sz = num_tracks * new_length;
  int *new_pattern = realloc(old_pattern, sizeof(int) * new_sz);
  if (new_pattern == NULL) {
  }
  if (new_length > old_length) {
    memset(new_pattern + old_sz, 0, sizeof(int) * (new_sz - old_sz));
  }
  return new_pattern;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L101
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L58
  cmpb   $0x1,-0x1(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L24
L25:
  movb   $0x1,-0x1(%rbp)
  jmp    L4
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L66
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L4
L66:
  mov    $0x0,%eax
  jmp    L24
L4:
  addq   $0x1,-0x18(%rbp)
L101:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  cmpb   $0x0,-0x1(%rbp)
  jne    L27
  mov    $0x1,%eax
  jmp    L24
L27:
  mov    $0x2,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int isNumber(char *raw) {
  char decimal = 0;
  while (*raw != 0) {
    if (*raw == '.') {
      if (decimal == 1)
        return 0;
      decimal = 1;
    } else {
      if (*raw < '0' || *raw > '9')
        return 0;
    }
    ++raw;
  }
  return decimal == 0 ? 1 : 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isNumber>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L25
  mov    $0x0,%eax
  mov    $0x1,%ecx
  jmp    L11
L26:
  cmp    $0x1,%al
  je     L6
  mov    %ecx,%eax
L21:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
L11:
  cmp    $0x2e,%dl
  je     L26
  sub    $0x30,%edx
  cmp    $0x9,%dl
  jbe    L21
  mov    $0x0,%eax
  ret
L12:
  and    $0x1,%eax
  add    $0x1,%eax
  ret
L25:
  mov    $0x1,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isNumber(char *raw) {
  char decimal = 0;
  while (*raw != 0) {
    if (*raw == '.') {
      if (decimal == 1)
        return 0;
      decimal = 1;
    } else {
      if (*raw < '0' || *raw > '9')
        return 0;
    }
    ++raw;
  }
  return decimal == 0 ? 1 : 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isNumber>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L81
  xor    %ecx,%ecx
  jmp    L67
  nop
L41:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L74
L57:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%rdi
  test   %al,%al
  je     L66
L67:
  mov    %rdi,%rdx
  cmp    $0x2e,%al
  jne    L41
  cmp    $0x1,%cl
  je     L74
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L24
  cmp    $0x2e,%al
  je     L74
  sub    $0x30,%eax
  add    $0x1,%rdx
  mov    $0x1,%ecx
  cmp    $0x9,%al
  jbe    L57
L74:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L66:
  lea    0x1(%rcx),%eax
  movsbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x2,%eax
  ret
L81:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isNumber(char *raw) {
  char decimal = 0;
  while (*raw != 0) {
    if (*raw == '.') {
      if (decimal == 1)
        return 0;
      decimal = 1;
    } else {
      if (*raw < '0' || *raw > '9')
        return 0;
    }
    ++raw;
  }
  return decimal == 0 ? 1 : 2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isNumber>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  xor    %ecx,%ecx
  jmp    L42
  nop
L34:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L53
L89:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%rdi
  test   %al,%al
  je     L59
L42:
  mov    %rdi,%rdx
  cmp    $0x2e,%al
  jne    L34
  cmp    $0x1,%cl
  je     L53
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L14
  cmp    $0x2e,%al
  je     L53
  sub    $0x30,%eax
  add    $0x1,%rdx
  mov    $0x1,%ecx
  cmp    $0x9,%al
  jbe    L89
L53:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L59:
  lea    0x1(%rcx),%eax
  movsbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x2,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isNumber(char *raw) {
  char decimal = 0;
  while (*raw != 0) {
    if (*raw == '.') {
      if (decimal == 1)
        return 0;
      decimal = 1;
    } else {
      if (*raw < '0' || *raw > '9')
        return 0;
    }
    ++raw;
  }
  return decimal == 0 ? 1 : 2;
}
```
user: What is the c source code of the assembly code below?

```asm
<initb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L10
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L10:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getval@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffff8008,-0x4(%rbp)
  jne    L9
  nop
  leave
  ret
```

assistant: ```c
initb(char_ptr, string) char *char_ptr, *string;
{
  int n;
  while ((n = getval(&string)) != -32760)
    *char_ptr++ = n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  jmp    L12
L17:
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
L12:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <getval@plt>
  cmp    $0xffff8008,%eax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
initb(char_ptr, string) char *char_ptr, *string;
{
  int n;
  while ((n = getval(&string)) != -32760)
    *char_ptr++ = n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<initb>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  jmp    L4
  nopl   0x0(%rax)
L10:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L4:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <getval@plt>
  cmp    $0xffff8008,%eax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
initb(char_ptr, string) char *char_ptr, *string;
{
  int n;
  while ((n = getval(&string)) != -32760)
    *char_ptr++ = n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initb>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  jmp    L9
  nopl   0x0(%rax)
L11:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L9:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <getval@plt>
  cmp    $0xffff8008,%eax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
initb(char_ptr, string) char *char_ptr, *string;
{
  int n;
  while ((n = getval(&string)) != -32760)
    *char_ptr++ = n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<UARTBreakCtl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x4(%rbp),%eax
  add    $0x2c,%eax
  cltq
  mov    (%rax),%eax
  or     $0x1,%eax
  jmp    L10
L19:
  mov    -0x4(%rbp),%eax
  add    $0x2c,%eax
  cltq
  mov    (%rax),%eax
  and    $0xfffffffe,%eax
L10:
  mov    -0x4(%rbp),%edx
  add    $0x2c,%edx
  movslq %edx,%rdx
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTBreakCtl(uint32_t ui32Base, bool bBreakState) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000002C))) = (bBreakState ? ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) | 0x00000001) : ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) & ~(0x00000001)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTBreakCtl>:
  endbr64
  test   %esi,%esi
  je     L17
  lea    0x2c(%rdi),%eax
  cltq
  mov    (%rax),%eax
  or     $0x1,%eax
L5:
  add    $0x2c,%edi
  movslq %edi,%rdi
  mov    %eax,(%rdi)
  ret
L17:
  lea    0x2c(%rdi),%eax
  cltq
  mov    (%rax),%eax
  and    $0xfffffffe,%eax
  jmp    L5
```

assistant: ```c
void UARTBreakCtl(uint32_t ui32Base, bool bBreakState) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000002C))) = (bBreakState ? ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) | 0x00000001) : ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) & ~(0x00000001)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UARTBreakCtl>:
  endbr64
  add    $0x2c,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  test   %esi,%esi
  je     L7
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTBreakCtl(uint32_t ui32Base, bool bBreakState) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000002C))) = (bBreakState ? ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) | 0x00000001) : ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) & ~(0x00000001)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTBreakCtl>:
  endbr64
  add    $0x2c,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  test   %esi,%esi
  je     L2
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTBreakCtl(uint32_t ui32Base, bool bBreakState) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000002C))) = (bBreakState ? ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) | 0x00000001) : ((*((volatile uint32_t *)(ui32Base + 0x0000002C))) & ~(0x00000001)));
}
```
user: What is the c source code of the assembly code below?

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rdx,%r14
  mov    %ecx,%r12d
  lea    (%rsi,%rcx,1),%r15d
  lea    0x0(,%r15,4),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %r15d,%ecx
  shr    $0x1f,%ecx
  add    %r15d,%ecx
  sar    %ecx
  cmp    $0xffffffff,%r15d
  jl     L0
  mov    $0x0,%eax
  mov    $0x0,%r9d
  mov    $0x0,%edx
  jmp    L14
L49:
  add    $0x1,%r9d
L39:
  mov    %ebx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jl     L31
L14:
  cmp    %edx,%ebp
  jle    L84
  cmp    %r9d,%r12d
  jle    L84
  movslq %edx,%rdi
  mov    0x0(%r13,%rdi,4),%edi
  movslq %r9d,%r8
  mov    (%r14,%r8,4),%ebx
  cmp    %ebx,%edi
  jge    L49
  add    $0x1,%edx
  mov    %edi,%ebx
  jmp    L39
L84:
  cmp    %edx,%ebp
  jle    L102
  movslq %edx,%rdi
  mov    0x0(%r13,%rdi,4),%ebx
  lea    0x1(%rdx),%edx
  jmp    L39
L102:
  cmp    %r9d,%r12d
  jle    L39
  movslq %r9d,%rdi
  mov    (%r14,%rdi,4),%ebx
  lea    0x1(%r9),%r9d
  jmp    L39
L31:
  test   %ecx,%ecx
  mov    $0x0,%eax
  cmovs  %eax,%ecx
  add    $0x1,%ecx
L127:
  test   $0x1,%r15b
  je     L52
  movslq %ecx,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rsi,%rcx,4),%xmm0
L97:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    $0x0,%ecx
  jmp    L127
L52:
  movslq %ecx,%rcx
  mov    -0x4(%rsi,%rcx,4),%eax
  add    -0x8(%rsi,%rcx,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D6(%rip),%xmm0
  jmp    L97
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1Size, int *nums2, int nums2Size) {
  int sum = nums1Size + nums2Size;
  int *nums = malloc(sizeof(int) * sum);
  int i = 0, j = 0, k = 0;
  int half = sum / 2 + 1;
  while (k < half) {
    int n;
    if (i < nums1Size && j < nums2Size) {
      n = (nums1[i] < nums2[j]) ? nums1[i++] : nums2[j++];
    } else if (i < nums1Size) {
      n = nums1[i++];
    } else if (j < nums2Size) {
      n = nums2[j++];
    }
    nums[k++] = n;
  }
  if (sum % 2) {
    return nums[k - 1];
  } else {
    return (nums[k - 1] + nums[k - 2]) / 2.0;
  }
}
```