ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L264
L97:
  addl   $0x1,-0x4(%rbp)
L264:
  cmpl   $0x63,-0x4(%rbp)
  jle    L97
  movl   $0x0,-0x4(%rbp)
  jmp    L155
L255:
  addl   $0x1,-0x4(%rbp)
L155:
  cmpl   $0x63,-0x4(%rbp)
  jle    L255
  movl   $0x0,-0x4(%rbp)
  jmp    L267
L226:
  addl   $0x1,-0x4(%rbp)
L267:
  cmpl   $0x63,-0x4(%rbp)
  jle    L226
  movl   $0x0,-0x4(%rbp)
  jmp    L303
L295:
  addl   $0x1,-0x4(%rbp)
L303:
  cmpl   $0x63,-0x4(%rbp)
  jle    L295
  movl   $0x0,-0x4(%rbp)
  jmp    L214
L50:
  addl   $0x1,-0x4(%rbp)
L214:
  cmpl   $0x63,-0x4(%rbp)
  jle    L50
  movl   $0x0,-0x4(%rbp)
  jmp    L126
L234:
  addl   $0x1,-0x4(%rbp)
L126:
  cmpl   $0x63,-0x4(%rbp)
  jle    L234
  movl   $0x0,-0x4(%rbp)
  jmp    L257
L247:
  addl   $0x1,-0x4(%rbp)
L257:
  cmpl   $0x63,-0x4(%rbp)
  jle    L247
  movl   $0x0,-0x4(%rbp)
  jmp    L254
L129:
  addl   $0x1,-0x4(%rbp)
L254:
  cmpl   $0x63,-0x4(%rbp)
  jle    L129
  movl   $0x0,-0x4(%rbp)
  jmp    L147
L282:
  addl   $0x1,-0x4(%rbp)
L147:
  cmpl   $0x63,-0x4(%rbp)
  jle    L282
  movl   $0x0,-0x4(%rbp)
  jmp    L85
L278:
  addl   $0x1,-0x4(%rbp)
L85:
  cmpl   $0x63,-0x4(%rbp)
  jle    L278
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L89:
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x63,-0x4(%rbp)
  jle    L89
  movl   $0x0,-0x4(%rbp)
  jmp    L81
L223:
  addl   $0x1,-0x4(%rbp)
L81:
  cmpl   $0x63,-0x4(%rbp)
  jle    L223
  movl   $0x0,-0x4(%rbp)
  jmp    L112
L240:
  addl   $0x1,-0x4(%rbp)
L112:
  cmpl   $0x63,-0x4(%rbp)
  jle    L240
  movl   $0x0,-0x4(%rbp)
  jmp    L105
L176:
  addl   $0x1,-0x4(%rbp)
L105:
  cmpl   $0x63,-0x4(%rbp)
  jle    L176
  movl   $0x0,-0x4(%rbp)
  jmp    L191
L106:
  addl   $0x1,-0x4(%rbp)
L191:
  cmpl   $0x63,-0x4(%rbp)
  jle    L106
  movl   $0x0,-0x4(%rbp)
  jmp    L274
L195:
  addl   $0x1,-0x4(%rbp)
L274:
  cmpl   $0x63,-0x4(%rbp)
  jle    L195
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, *a, b;
#pragma acc parallel loop tile(10)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *, i)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile()
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, , )
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1.1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, -3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-100, 10, 5)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, 2.0, true)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*a, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, *a, b)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(b, 1, *a)
  for (i = 0; i < 100; i++)
    ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x64,%eax
L38:
  sub    $0x1,%eax
  jne    L38
  mov    $0x64,%eax
L23:
  sub    $0x1,%eax
  jne    L23
  mov    $0x64,%eax
L142:
  sub    $0x1,%eax
  jne    L142
  mov    $0x64,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  mov    $0x64,%eax
L39:
  sub    $0x1,%eax
  jne    L39
  mov    $0x64,%eax
L156:
  sub    $0x1,%eax
  jne    L156
  mov    $0x64,%eax
L8:
  sub    $0x1,%eax
  jne    L8
  mov    $0x64,%eax
L81:
  sub    $0x1,%eax
  jne    L81
  mov    $0x64,%eax
L18:
  sub    $0x1,%eax
  jne    L18
  mov    $0x64,%eax
L140:
  sub    $0x1,%eax
  jne    L140
  mov    $0x64,%eax
L86:
  sub    $0x1,%eax
  jne    L86
  mov    $0x64,%eax
L45:
  sub    $0x1,%eax
  jne    L45
  mov    $0x64,%eax
L50:
  sub    $0x1,%eax
  jne    L50
  mov    $0x64,%eax
L43:
  sub    $0x1,%eax
  jne    L43
  mov    $0x64,%eax
L42:
  sub    $0x1,%eax
  jne    L42
  mov    $0x64,%eax
L150:
  sub    $0x1,%eax
  jne    L150
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int i, *a, b;
#pragma acc parallel loop tile(10)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *, i)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile()
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, , )
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1.1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, -3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-100, 10, 5)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, 2.0, true)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*a, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, *a, b)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(b, 1, *a)
  for (i = 0; i < 100; i++)
    ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i, *a, b;
#pragma acc parallel loop tile(10)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *, i)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile()
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, , )
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1.1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, -3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-100, 10, 5)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, 2.0, true)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*a, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, *a, b)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(b, 1, *a)
  for (i = 0; i < 100; i++)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i, *a, b;
#pragma acc parallel loop tile(10)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, *, i)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile()
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(, , )
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1.1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(10, -3)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(-100, 10, 5)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, 2.0, true)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(*a, 1)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(1, *a, b)
  for (i = 0; i < 100; i++)
    ;
#pragma acc parallel loop tile(b, 1, *a)
  for (i = 0; i < 100; i++)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ed_swap_4p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ed_swap_4@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *ed_swap_4p(void *x) {
  *(uint32_t *)x = ed_swap_4(*(uint32_t *)x);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ed_swap_4p>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <ed_swap_4@plt>
  mov    %eax,(%rbx)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *ed_swap_4p(void *x) {
  *(uint32_t *)x = ed_swap_4(*(uint32_t *)x);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ed_swap_4p>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    (%rdi),%edi
  call   <ed_swap_4@plt>
  mov    %eax,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *ed_swap_4p(void *x) {
  *(uint32_t *)x = ed_swap_4(*(uint32_t *)x);
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ed_swap_4p>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    (%rdi),%edi
  call   <ed_swap_4@plt>
  mov    %eax,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *ed_swap_4p(void *x) {
  *(uint32_t *)x = ed_swap_4(*(uint32_t *)x);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mapif_load_merc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <mercdb_sql_load@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <mapif_merc_info@plt>
  jmp    L3
L17:
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: inter merc: data load error %d %d %d


assistant: ```c
int mapif_load_merc(int fd, int account_id, int char_id, int merc_id) {
  const struct mmo_mercstatus *m = mercdb_sql_load(merc_id);
  if (m != NULL) {
    mapif_merc_info(fd, account_id, char_id, m, 0);
  } else {
    printf("inter merc: data load error %d %d %d\n", account_id, char_id, merc_id);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mapif_load_merc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%ebx
  mov    %ecx,%edi
  call   <mercdb_sql_load@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rcx
  mov    $0x0,%r8d
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <mapif_merc_info@plt>
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: inter merc: data load error %d %d %d


assistant: ```c
int mapif_load_merc(int fd, int account_id, int char_id, int merc_id) {
  const struct mmo_mercstatus *m = mercdb_sql_load(merc_id);
  if (m != NULL) {
    mapif_merc_info(fd, account_id, char_id, m, 0);
  } else {
    printf("inter merc: data load error %d %d %d\n", account_id, char_id, merc_id);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mapif_load_merc>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    %ecx,%edi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <mercdb_sql_load@plt>
  test   %rax,%rax
  je     L3
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r14d,%edi
  mov    %rax,%rcx
  xor    %r8d,%r8d
  call   <mapif_merc_info@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%ecx
  mov    %r13d,%edx
  lea    D5(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: inter merc: data load error %d %d %d


assistant: ```c
int mapif_load_merc(int fd, int account_id, int char_id, int merc_id) {
  const struct mmo_mercstatus *m = mercdb_sql_load(merc_id);
  if (m != NULL) {
    mapif_merc_info(fd, account_id, char_id, m, 0);
  } else {
    printf("inter merc: data load error %d %d %d\n", account_id, char_id, merc_id);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mapif_load_merc>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    %ecx,%edi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <mercdb_sql_load@plt>
  test   %rax,%rax
  je     L7
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r14d,%edi
  mov    %rax,%rcx
  xor    %r8d,%r8d
  call   <mapif_merc_info@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r12d,%ecx
  mov    %r13d,%edx
  lea    D5(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: inter merc: data load error %d %d %d


assistant: ```c
int mapif_load_merc(int fd, int account_id, int char_id, int merc_id) {
  const struct mmo_mercstatus *m = mercdb_sql_load(merc_id);
  if (m != NULL) {
    mapif_merc_info(fd, account_id, char_id, m, 0);
  } else {
    printf("inter merc: data load error %d %d %d\n", account_id, char_id, merc_id);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ECsinh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sinh@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double ECsinh(double x) {
  double y;
  double r;
  y = x;
  r = sinh(y);
  return (r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ECsinh>:
  endbr64
  sub    $0x8,%rsp
  call   <sinh@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double ECsinh(double x) {
  double y;
  double r;
  y = x;
  r = sinh(y);
  return (r);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ECsinh>:
  endbr64
  jmp    1050 <sinh@plt>
```

assistant: ```c
double ECsinh(double x) {
  double y;
  double r;
  y = x;
  r = sinh(y);
  return (r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ECsinh>:
  endbr64
  jmp    1050 <sinh@plt>
```

assistant: ```c
double ECsinh(double x) {
  double y;
  double r;
  y = x;
  r = sinh(y);
  return (r);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L12
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void strlwr(str) char *str;
{
  for (; *str; str++)
    *str = tolower(*str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlwr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L8:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
L4:
  pop    %rbx
  ret
```

assistant: ```c
void strlwr(str) char *str;
{
  for (; *str; str++)
    *str = tolower(*str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlwr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L12:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L2:
  pop    %rbx
  ret
```

assistant: ```c
void strlwr(str) char *str;
{
  for (; *str; str++)
    *str = tolower(*str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlwr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L19:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L6:
  pop    %rbx
  ret
```

assistant: ```c
void strlwr(str) char *str;
{
  for (; *str; str++)
    *str = tolower(*str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lastSubstring_timeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L96
L82:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x21(%rbp)
  jge    L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L18:
  addq   $0x1,-0x18(%rbp)
L96:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L82
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  test   %rax,%rax
  jne    L16
  mov    -0x20(%rbp),%rax
  jmp    L108
L16:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L69
L17:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L75
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  test   %rax,%rax
  jne    L34
  mov    -0x10(%rbp),%rax
  jmp    L108
L34:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
L75:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  test   %rax,%rax
  jne    L7
  mov    -0x10(%rbp),%rax
  jmp    L108
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
L69:
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    -0x10(%rbp),%rax
L108:
  leave
  ret
```

assistant: ```c
char *lastSubstring_timeout(char *s) {
  char max = *s;
  char *m = s;
  char *p = s;
  while (*p) {
    if (*p > max) {
      max = *p;
      m = p;
    }
    p++;
  }
  if (m + 1 == NULL)
    return m;
  char *p1 = m;
  char *p2 = strchr(p1 + 1, *p1);
  while (p2) {
    if (strcmp(p1, p2) < 0) {
      p1 = p2;
      if (p1 + 1 == NULL)
        return p1;
      p2 = strchr(p1 + 1, *p1);
    }
    if (p2 + 1 == NULL)
      return p1;
    p2 = strchr(p2 + 1, *p1);
  }
  return p1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lastSubstring_timeout>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L55
L64:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L55
  cmp    %cl,%dl
  jle    L64
  mov    %rax,%rbp
  mov    %edx,%ecx
  jmp    L64
L55:
  movsbl 0x0(%rbp),%esi
  lea    0x1(%rbp),%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L0
  mov    %rbp,%rax
  jmp    L68
L21:
  lea    0x1(%rbx),%rdi
  movsbl 0x0(%rbp),%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L80
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L21
  lea    0x1(%rbx),%rdi
  movsbl (%rbx),%esi
  call   <strchr@plt>
  mov    %rbx,%rbp
  mov    %rax,%rbx
  jmp    L21
L80:
  mov    %rbp,%rax
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *lastSubstring_timeout(char *s) {
  char max = *s;
  char *m = s;
  char *p = s;
  while (*p) {
    if (*p > max) {
      max = *p;
      m = p;
    }
    p++;
  }
  if (m + 1 == NULL)
    return m;
  char *p1 = m;
  char *p2 = strchr(p1 + 1, *p1);
  while (p2) {
    if (strcmp(p1, p2) < 0) {
      p1 = p2;
      if (p1 + 1 == NULL)
        return p1;
      p2 = strchr(p1 + 1, *p1);
    }
    if (p2 + 1 == NULL)
      return p1;
    p2 = strchr(p2 + 1, *p1);
  }
  return p1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lastSubstring_timeout>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L9
L45:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L43
L71:
  cmp    %sil,%al
  jle    L45
  mov    %rdi,%r12
  add    $0x1,%rdi
  mov    %eax,%esi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L71
L43:
  movsbl (%r12),%esi
L9:
  lea    0x1(%r12),%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L31
  jmp    L44
L74:
  movsbl (%r12),%esi
  lea    0x1(%rbx),%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L44
L31:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L74
  movsbl (%rbx),%esi
  lea    0x1(%rbx),%rdi
  mov    %rbx,%r12
  call   <strchr@plt>
  mov    %rax,%rbx
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *lastSubstring_timeout(char *s) {
  char max = *s;
  char *m = s;
  char *p = s;
  while (*p) {
    if (*p > max) {
      max = *p;
      m = p;
    }
    p++;
  }
  if (m + 1 == NULL)
    return m;
  char *p1 = m;
  char *p2 = strchr(p1 + 1, *p1);
  while (p2) {
    if (strcmp(p1, p2) < 0) {
      p1 = p2;
      if (p1 + 1 == NULL)
        return p1;
      p2 = strchr(p1 + 1, *p1);
    }
    if (p2 + 1 == NULL)
      return p1;
    p2 = strchr(p2 + 1, *p1);
  }
  return p1;
}
```