ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scramble_real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L21
L17:
  cmp    %ebx,%r12d
  jge    L6
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movslq %r12d,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  movslq %r12d,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
L6:
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%r13d
  jmp    L26
L32:
  sub    %r13d,%ebx
  sar    %r13d
L26:
  cmp    %ebx,%r13d
  jle    L32
  add    %r13d,%ebx
  add    $0x1,%r12d
L21:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,%r12d
  jl     L17
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void scramble_real(float *x, int n) {
  register int i, j, k;
  float tmp;
  for (i = 0, j = 0; i < n - 1; i++) {
    if (i < j) {
      tmp = x[j];
      x[j] = x[i];
      x[i] = tmp;
    }
    k = n / 2;
    while (k <= j) {
      j -= k;
      k >>= 1;
    }
    j += k;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scramble_real>:
  endbr64
  cmp    $0x1,%esi
  jle    L56
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  lea    -0x2(%rsi),%esi
  add    $0x1,%rsi
  mov    $0x1,%ecx
  mov    $0x0,%edx
  jmp    L40
L45:
  add    $0x1,%rcx
L40:
  cmp    %edx,%r8d
  jg     L48
  mov    %r8d,%eax
L74:
  sub    %eax,%edx
  sar    %eax
  cmp    %eax,%edx
  jge    L74
L12:
  add    %eax,%edx
  cmp    %rsi,%rcx
  je     L56
  cmp    %ecx,%edx
  jle    L45
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rax
  movss  (%rax),%xmm0
  movss  (%rdi,%rcx,4),%xmm1
  movss  %xmm1,(%rax)
  movss  %xmm0,(%rdi,%rcx,4)
  jmp    L45
L48:
  mov    %r8d,%eax
  jmp    L12
L56:
  ret
```

assistant: ```c
void scramble_real(float *x, int n) {
  register int i, j, k;
  float tmp;
  for (i = 0, j = 0; i < n - 1; i++) {
    if (i < j) {
      tmp = x[j];
      x[j] = x[i];
      x[i] = tmp;
    }
    k = n / 2;
    while (k <= j) {
      j -= k;
      k >>= 1;
    }
    j += k;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scramble_real>:
  endbr64
  cmp    $0x1,%esi
  jle    L25
  mov    %esi,%r8d
  sub    $0x2,%esi
  mov    $0x1,%ecx
  xor    %edx,%edx
  sar    %r8d
  add    $0x1,%rsi
  nopl   (%rax)
L27:
  mov    %r8d,%eax
  cmp    %edx,%r8d
  jg     L23
  nopl   0x0(%rax,%rax,1)
L16:
  sub    %eax,%edx
  sar    %eax
  cmp    %eax,%edx
  jge    L16
L23:
  add    %eax,%edx
  cmp    %rcx,%rsi
  je     L25
  cmp    %ecx,%edx
  jle    L30
  movslq %edx,%rax
  movss  (%rdi,%rcx,4),%xmm1
  lea    (%rdi,%rax,4),%rax
  movss  (%rax),%xmm0
  movss  %xmm1,(%rax)
  movss  %xmm0,(%rdi,%rcx,4)
L30:
  add    $0x1,%rcx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L25:
  ret
```

assistant: ```c
void scramble_real(float *x, int n) {
  register int i, j, k;
  float tmp;
  for (i = 0, j = 0; i < n - 1; i++) {
    if (i < j) {
      tmp = x[j];
      x[j] = x[i];
      x[i] = tmp;
    }
    k = n / 2;
    while (k <= j) {
      j -= k;
      k >>= 1;
    }
    j += k;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scramble_real>:
  endbr64
  cmp    $0x1,%esi
  jle    L22
  mov    %esi,%r8d
  sub    $0x2,%esi
  mov    $0x1,%ecx
  xor    %edx,%edx
  sar    %r8d
  add    $0x1,%rsi
  nopl   (%rax)
L7:
  mov    %r8d,%eax
  cmp    %edx,%r8d
  jg     L52
  nopl   0x0(%rax,%rax,1)
L43:
  sub    %eax,%edx
  sar    %eax
  cmp    %eax,%edx
  jge    L43
L52:
  add    %eax,%edx
  cmp    %rcx,%rsi
  je     L22
  cmp    %ecx,%edx
  jle    L18
  movslq %edx,%rax
  movss  (%rdi,%rcx,4),%xmm1
  lea    (%rdi,%rax,4),%rax
  movss  (%rax),%xmm0
  movss  %xmm1,(%rax)
  movss  %xmm0,(%rdi,%rcx,4)
L18:
  add    $0x1,%rcx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L22:
  ret
```

assistant: ```c
void scramble_real(float *x, int n) {
  register int i, j, k;
  float tmp;
  for (i = 0, j = 0; i < n - 1; i++) {
    if (i < j) {
      tmp = x[j];
      x[j] = x[i];
      x[i] = tmp;
    }
    k = n / 2;
    while (k <= j) {
      j -= k;
      k >>= 1;
    }
    j += k;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L46:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L46
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L49:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L49
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D35
datatype: string
name: parse_data
arguments: data_label: D39
datatype: string
name: parse_data
arguments: data_label: D25
datatype: string

tool: D17: How many numbers? 

tool: D35: %d

tool: D39: Enter %d numbers: 

tool: D25: %d	

assistant: ```c
int main() {
  int n;
  printf("How many numbers? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter %d numbers: ", n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &input[i]);
  }
  merge_sort(input, 0, n - 1);
  for (int i = 0; i < n; i++) {
    printf("%d\t", *(input + i));
  }
  free(input);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x4(%rsp),%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L24
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D30(%rip),%r13
L6:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jg     L6
L24:
  sub    $0x1,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <merge_sort@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L13
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D27(%rip),%r13
L12:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jg     L12
L13:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D30
type: string
name: disassemble_data
arguments: tag: D45
type: string
name: disassemble_data
arguments: tag: D27
type: string

tool: D2: How many numbers? 

tool: D30: %d

tool: D45: Enter %d numbers: 

tool: D27: %d	

assistant: ```c
int main() {
  int n;
  printf("How many numbers? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter %d numbers: ", n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &input[i]);
  }
  merge_sort(input, 0, n - 1);
  for (int i = 0; i < n; i++) {
    printf("%d\t", *(input + i));
  }
  free(input);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%esi
  lea    D33(%rip),%rdi
  mov    %rax,%r12
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L27
  mov    %r12,%rbp
  xor    %ebx,%ebx
L31:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L31
L27:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <merge_sort@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L24
  mov    %r12,%rbp
  xor    %ebx,%ebx
  lea    D20(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L10
L24:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D33
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string

tool: D15: How many numbers? 

tool: D14: %d

tool: D33: Enter %d numbers: 

tool: D20: %d	

assistant: ```c
int main() {
  int n;
  printf("How many numbers? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter %d numbers: ", n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &input[i]);
  }
  merge_sort(input, 0, n - 1);
  for (int i = 0; i < n; i++) {
    printf("%d\t", *(input + i));
  }
  free(input);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D26(%rip),%rdi
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%esi
  lea    D39(%rip),%rdi
  mov    %rax,%r12
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L28
  mov    %r12,%rbp
  xor    %ebx,%ebx
L7:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L7
L28:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <merge_sort@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L22
  mov    %r12,%rbp
  xor    %ebx,%ebx
  lea    D16(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L2
L22:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D26: How many numbers? 

tool: D19: %d

tool: D39: Enter %d numbers: 

tool: D16: %d	

assistant: ```c
int main() {
  int n;
  printf("How many numbers? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter %d numbers: ", n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &input[i]);
  }
  merge_sort(input, 0, n - 1);
  for (int i = 0; i < n; i++) {
    printf("%d\t", *(input + i));
  }
  free(input);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D31
type: string
name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D3
type: string

tool: D31: C:\Windows\System and stuff/bah, foo, baz/kk

tool: 

tool: D21: .

tool: D3: /etc/group-by-things/1rf/a/f/b/e/2/xx

assistant: ```c
int main(void) {
  test("C:\\Windows\\System and stuff/bah, foo, baz/kk");
  test("");
  test(".");
  test("/etc/group-by-things/1rf/a/f/b/e/2/xx");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <test@plt>
  lea    D5(%rip),%rdi
  call   <test@plt>
  lea    D22(%rip),%rdi
  call   <test@plt>
  lea    D29(%rip),%rdi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D29
data_type: string

tool: D28: C:\Windows\System and stuff/bah, foo, baz/kk

tool: 

tool: D22: .

tool: D29: /etc/group-by-things/1rf/a/f/b/e/2/xx

assistant: ```c
int main(void) {
  test("C:\\Windows\\System and stuff/bah, foo, baz/kk");
  test("");
  test(".");
  test("/etc/group-by-things/1rf/a/f/b/e/2/xx");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <test@plt>
  lea    D5(%rip),%rdi
  call   <test@plt>
  lea    D21(%rip),%rdi
  call   <test@plt>
  lea    D18(%rip),%rdi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D38
type_infered: string
name: unpack_data
arguments: label: D5
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string

tool: D38: C:\Windows\System and stuff/bah, foo, baz/kk

tool: 

tool: D21: .

tool: D18: /etc/group-by-things/1rf/a/f/b/e/2/xx

assistant: ```c
int main(void) {
  test("C:\\Windows\\System and stuff/bah, foo, baz/kk");
  test("");
  test(".");
  test("/etc/group-by-things/1rf/a/f/b/e/2/xx");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <test@plt>
  lea    D6(%rip),%rdi
  call   <test@plt>
  lea    D15(%rip),%rdi
  call   <test@plt>
  lea    D21(%rip),%rdi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D21
datatype: string

tool: D7: C:\Windows\System and stuff/bah, foo, baz/kk

tool: 

tool: D15: .

tool: D21: /etc/group-by-things/1rf/a/f/b/e/2/xx

assistant: ```c
int main(void) {
  test("C:\\Windows\\System and stuff/bah, foo, baz/kk");
  test("");
  test(".");
  test("/etc/group-by-things/1rf/a/f/b/e/2/xx");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<log2i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0xffffffff,%eax
  cmp    %rax,-0x18(%rbp)
  jbe    L61
  mov    $0x20,%eax
  jmp    L42
L61:
  mov    $0x0,%eax
L42:
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  shrq   %cl,-0x18(%rbp)
  cmpq   $0xffff,-0x18(%rbp)
  jbe    L88
  mov    $0x10,%eax
  jmp    L32
L88:
  mov    $0x0,%eax
L32:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  shrq   %cl,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  or     %rax,-0x10(%rbp)
  cmpq   $0xff,-0x18(%rbp)
  jbe    L84
  mov    $0x8,%eax
  jmp    L46
L84:
  mov    $0x0,%eax
L46:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  shrq   %cl,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  or     %rax,-0x10(%rbp)
  cmpq   $0xf,-0x18(%rbp)
  jbe    L11
  mov    $0x4,%eax
  jmp    L65
L11:
  mov    $0x0,%eax
L65:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  shrq   %cl,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  or     %rax,-0x10(%rbp)
  cmpq   $0x3,-0x18(%rbp)
  jbe    L55
  mov    $0x2,%eax
  jmp    L45
L55:
  mov    $0x0,%eax
L45:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  shrq   %cl,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  or     %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shr    %rax
  or     -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long log2i(long long n) {
  unsigned long long v = (unsigned long long)n;
  unsigned long long r;
  unsigned long long s;
  r = (v > 0xFFFFFFFFULL) << 5;
  v >>= r;
  s = (v > 0xFFFFULL) << 4;
  v >>= s;
  r |= s;
  s = (v > 0xFFULL) << 3;
  v >>= s;
  r |= s;
  s = (v > 0xFULL) << 2;
  v >>= s;
  r |= s;
  s = (v > 0x3ULL) << 1;
  v >>= s;
  r |= s;
  return (long long)(r | (v >> 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log2i>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rsi
  shr    $0x20,%rsi
  setne  %dl
  movzbl %dl,%edx
  shl    $0x5,%rdx
  mov    %edx,%ecx
  shr    %cl,%rax
  cmp    $0xffff,%rax
  seta   %cl
  movzbl %cl,%ecx
  shl    $0x4,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  cmp    $0xff,%rax
  seta   %cl
  movzbl %cl,%ecx
  shl    $0x3,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  cmp    $0xf,%rax
  seta   %cl
  movzbl %cl,%ecx
  shl    $0x2,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  cmp    $0x3,%rax
  seta   %cl
  movzbl %cl,%ecx
  add    %rcx,%rcx
  shr    %cl,%rax
  shr    %rax
  or     %rcx,%rdx
  or     %rdx,%rax
  ret
```

assistant: ```c
long long log2i(long long n) {
  unsigned long long v = (unsigned long long)n;
  unsigned long long r;
  unsigned long long s;
  r = (v > 0xFFFFFFFFULL) << 5;
  v >>= r;
  s = (v > 0xFFFFULL) << 4;
  v >>= s;
  r |= s;
  s = (v > 0xFFULL) << 3;
  v >>= s;
  r |= s;
  s = (v > 0xFULL) << 2;
  v >>= s;
  r |= s;
  s = (v > 0x3ULL) << 1;
  v >>= s;
  r |= s;
  return (long long)(r | (v >> 1));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<log2i>:
  endbr64
  mov    %rdi,%rsi
  xor    %edx,%edx
  mov    %rdi,%rax
  shr    $0x20,%rsi
  setne  %dl
  shl    $0x5,%rdx
  mov    %edx,%ecx
  shr    %cl,%rax
  xor    %ecx,%ecx
  cmp    $0xffff,%rax
  seta   %cl
  shl    $0x4,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  xor    %ecx,%ecx
  cmp    $0xff,%rax
  seta   %cl
  shl    $0x3,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  xor    %ecx,%ecx
  cmp    $0xf,%rax
  seta   %cl
  shl    $0x2,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  xor    %ecx,%ecx
  cmp    $0x3,%rax
  seta   %cl
  add    %rcx,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  shr    %rax
  or     %rdx,%rax
  ret
```

assistant: ```c
long long log2i(long long n) {
  unsigned long long v = (unsigned long long)n;
  unsigned long long r;
  unsigned long long s;
  r = (v > 0xFFFFFFFFULL) << 5;
  v >>= r;
  s = (v > 0xFFFFULL) << 4;
  v >>= s;
  r |= s;
  s = (v > 0xFFULL) << 3;
  v >>= s;
  r |= s;
  s = (v > 0xFULL) << 2;
  v >>= s;
  r |= s;
  s = (v > 0x3ULL) << 1;
  v >>= s;
  r |= s;
  return (long long)(r | (v >> 1));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log2i>:
  endbr64
  mov    %rdi,%rsi
  xor    %edx,%edx
  mov    %rdi,%rax
  shr    $0x20,%rsi
  setne  %dl
  shl    $0x5,%rdx
  mov    %edx,%ecx
  shr    %cl,%rax
  xor    %ecx,%ecx
  cmp    $0xffff,%rax
  seta   %cl
  shl    $0x4,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  xor    %ecx,%ecx
  cmp    $0xff,%rax
  seta   %cl
  shl    $0x3,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  xor    %ecx,%ecx
  cmp    $0xf,%rax
  seta   %cl
  shl    $0x2,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  xor    %ecx,%ecx
  cmp    $0x3,%rax
  seta   %cl
  add    %rcx,%rcx
  shr    %cl,%rax
  or     %rcx,%rdx
  shr    %rax
  or     %rdx,%rax
  ret
```

assistant: ```c
long long log2i(long long n) {
  unsigned long long v = (unsigned long long)n;
  unsigned long long r;
  unsigned long long s;
  r = (v > 0xFFFFFFFFULL) << 5;
  v >>= r;
  s = (v > 0xFFFFULL) << 4;
  v >>= s;
  r |= s;
  s = (v > 0xFFULL) << 3;
  v >>= s;
  r |= s;
  s = (v > 0xFULL) << 2;
  v >>= s;
  r |= s;
  s = (v > 0x3ULL) << 1;
  v >>= s;
  r |= s;
  return (long long)(r | (v >> 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L30
  mov    $0x1,%eax
  jmp    L9
L30:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L44
L18:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  jmp    L9
L10:
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L18
  mov    $0x1,%eax
L9:
  leave
  ret
```

assistant: ```c
int check_prime(int num) {
  int temp, i;
  if (num == 1) {
    return 1;
  }
  temp = sqrt(num);
  for (i = 2; i <= temp; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_prime>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  je     L37
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L63
  test   $0x1,%bl
  je     L65
  mov    $0x2,%ecx
L72:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L14
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L72
  jmp    L61
L14:
  mov    $0x1,%eax
L61:
  pop    %rbx
  ret
L63:
  mov    $0x1,%eax
  jmp    L61
L65:
  mov    $0x0,%eax
  jmp    L61
L37:
  ret
```

assistant: ```c
int check_prime(int num) {
  int temp, i;
  if (num == 1) {
    return 1;
  }
  temp = sqrt(num);
  for (i = 2; i <= temp; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```