ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<do_command_read>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  lea    D1(%rip),%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <popen@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  lea    D3(%rip),%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
L10:
  mov    %rbp,%rdi
  call   <pclose@plt>
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string

tool: D1: r

tool: D3: 


assistant: ```c
char *do_command_read(const char *cmd_str, char *buffer, int max_len) {
  FILE *fp;
  char *cp;
  fp = popen(cmd_str, "r");
  if (fp == NULL) {
    cp = NULL;
  } else {
    cp = fgets(buffer, max_len, fp);
    if (cp != NULL) {
      strtok(buffer, "\n");
    }
    pclose(fp);
  }
  return (cp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_command_read>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  lea    D16(%rip),%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <popen@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  lea    D7(%rip),%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
L15:
  mov    %rbp,%rdi
  call   <pclose@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D7
type: string

tool: D16: r

tool: D7: 


assistant: ```c
char *do_command_read(const char *cmd_str, char *buffer, int max_len) {
  FILE *fp;
  char *cp;
  fp = popen(cmd_str, "r");
  if (fp == NULL) {
    cp = NULL;
  } else {
    cp = fgets(buffer, max_len, fp);
    if (cp != NULL) {
      strtok(buffer, "\n");
    }
    pclose(fp);
  }
  return (cp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L64
  cmpq   $0x0,-0x30(%rbp)
  nop
L64:
  cmpq   $0x0,-0x28(%rbp)
  je     L74
  cmpq   $0x0,-0x30(%rbp)
  je     L74
  mov    $0x1,%eax
  jmp    L3
L74:
  mov    $0x0,%eax
L3:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mb_attempt_open_bracket@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L45
  mov    -0x18(%rbp),%eax
  jmp    L41
L45:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mb_attempt_close_bracket@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L10
  mov    -0x14(%rbp),%eax
  jmp    L41
L10:
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mb_gc@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L7
  mov    -0x10(%rbp),%eax
  jmp    L41
L7:
  mov    -0x20(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mb_push_int@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L124
  mov    -0xc(%rbp),%eax
  jmp    L41
L124:
  mov    -0x1c(%rbp),%eax
L41:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int gc(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  int collected = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_gc(s, &collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_push_int(s, l, collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_attempt_open_bracket@plt>
  test   %eax,%eax
  je     L11
L49:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_attempt_close_bracket@plt>
  test   %eax,%eax
  jne    L49
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <mb_gc@plt>
  test   %eax,%eax
  jne    L49
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_push_int@plt>
  jmp    L49
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gc(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  int collected = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_gc(s, &collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_push_int(s, l, collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  movl   $0x0,0x4(%rsp)
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_open_bracket@plt>
  test   %eax,%eax
  je     L4
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_close_bracket@plt>
  test   %eax,%eax
  jne    L36
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <mb_gc@plt>
  test   %eax,%eax
  jne    L36
  mov    0x4(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_push_int@plt>
  jmp    L36
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gc(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  int collected = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_gc(s, &collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_push_int(s, l, collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  movl   $0x0,0x4(%rsp)
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_open_bracket@plt>
  test   %eax,%eax
  je     L27
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_close_bracket@plt>
  test   %eax,%eax
  jne    L24
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <mb_gc@plt>
  test   %eax,%eax
  jne    L24
  mov    0x4(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_push_int@plt>
  jmp    L24
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gc(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  int collected = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_gc(s, &collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  do {
    int __hr = (mb_push_int(s, l, collected));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_open_connection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_open_tcp_connection@plt>
  jmp    L13
L6:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_open_serial_connection@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: tcp:

assistant: ```c
int _open_connection(char *name, char *option) {
  if (strncmp(name, "tcp:", strlen("tcp:")) == 0) {
    return _open_tcp_connection(name, option);
  } else {
    return _open_serial_connection(name, option);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_open_connection>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D6(%rip),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_open_tcp_connection@plt>
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_open_serial_connection@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: tcp:

assistant: ```c
int _open_connection(char *name, char *option) {
  if (strncmp(name, "tcp:", strlen("tcp:")) == 0) {
    return _open_tcp_connection(name, option);
  } else {
    return _open_serial_connection(name, option);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_open_connection>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L2
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <_open_tcp_connection@plt>
L2:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <_open_serial_connection@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: tcp:

assistant: ```c
int _open_connection(char *name, char *option) {
  if (strncmp(name, "tcp:", strlen("tcp:")) == 0) {
    return _open_tcp_connection(name, option);
  } else {
    return _open_serial_connection(name, option);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_open_connection>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L9
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <_open_tcp_connection@plt>
L9:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <_open_serial_connection@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: tcp:

assistant: ```c
int _open_connection(char *name, char *option) {
  if (strncmp(name, "tcp:", strlen("tcp:")) == 0) {
    return _open_tcp_connection(name, option);
  } else {
    return _open_serial_connection(name, option);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<toto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L84:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L84
  sub    $0xf80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x9f7c(%rbp)
  jmp    L8
L16:
  movl   $0x1,-0x9f78(%rbp)
  jmp    L36
L17:
  movl   $0x1,-0x9f74(%rbp)
  jmp    L48
L49:
  mov    -0x9f78(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x9f7c(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x9de0(%rbp,%rax,4),%eax
  lea    0x2(%rax),%ecx
  mov    -0x9f74(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9f78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    %ecx,-0x9de0(%rbp,%rax,4)
  addl   $0x1,-0x9f74(%rbp)
L48:
  cmpl   $0x63,-0x9f74(%rbp)
  jle    L49
  mov    -0x9f7c(%rbp),%eax
  add    %eax,-0x9f78(%rbp)
L36:
  cmpl   $0x63,-0x9f78(%rbp)
  jle    L17
  mov    -0x9f7c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x9f70(%rbp,%rax,4),%eax
  lea    0x2(%rax),%edx
  mov    -0x9f7c(%rbp),%eax
  cltq
  mov    %edx,-0x9f70(%rbp,%rax,4)
  movl   $0x1,-0x9f78(%rbp)
  jmp    L47
L29:
  mov    -0x9f78(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x9f7c(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x9de0(%rbp,%rax,4),%eax
  lea    0x2(%rax),%ecx
  mov    -0x9f7c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9f78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    %ecx,-0x9de0(%rbp,%rax,4)
  addl   $0x1,-0x9f78(%rbp)
L47:
  cmpl   $0x63,-0x9f78(%rbp)
  jle    L29
  mov    -0x9f7c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x9f70(%rbp,%rax,4),%eax
  lea    0x2(%rax),%edx
  mov    -0x9f7c(%rbp),%eax
  cltq
  mov    %edx,-0x9f70(%rbp,%rax,4)
  addl   $0x1,-0x9f7c(%rbp)
L8:
  cmpl   $0x63,-0x9f7c(%rbp)
  jle    L16
  mov    -0x991c(%rbp),%edx
  mov    -0x9f6c(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int toto() {
  int i, j, k;
  int a[101][100];
  int b[100];
  for (i = 1; i < 100; i++) {
    for (j = 1; j < 100; j += i)
      for (k = 1; k < 100; k++)
        a[j][k] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
  }
  return a[3][5] + b[1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toto>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L40:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L40
  sub    $0xf70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9f68(%rsp)
  xor    %eax,%eax
  lea    0x190(%rsp),%r12
  lea    0x9f60(%rsp),%rdi
  mov    $0x190,%r9d
  mov    $0x1,%r11d
  mov    $0x0,%ebp
  jmp    L44
L19:
  movslq %ebx,%rax
  mov    (%rsp,%rax,4),%eax
  add    $0x2,%eax
  mov    %eax,(%rsp,%r11,4)
  lea    -0x9ab0(%rdi),%rax
  mov    %r11,%rcx
  sub    %rbp,%rcx
L59:
  mov    (%rax),%esi
  lea    0x2(%rsi),%edx
  mov    %edx,-0x190(%rax,%rcx,4)
  add    $0x190,%rax
  cmp    %rdi,%rax
  jne    L59
  movslq %ebx,%rbx
  mov    (%rsp,%rbx,4),%eax
  add    $0x2,%eax
  mov    %eax,(%rsp,%r11,4)
  add    $0x1,%rbp
  add    $0x1,%r11
  add    $0x4,%rdi
  add    $0x190,%r9
  cmp    $0x64,%r11
  je     L55
L44:
  mov    %r11d,%r10d
  lea    -0x9dcc(%rdi),%rsi
  lea    0x320(%r12),%rcx
  mov    $0x1,%r8d
  lea    -0x1(%r11),%ebx
L21:
  lea    -0x18c(%rcx),%rax
L67:
  mov    0x31c(%rsi),%edx
  add    $0x2,%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L67
  add    %r10d,%r8d
  add    %r9,%rsi
  add    %r9,%rcx
  cmp    $0x63,%r8d
  jle    L21
  jmp    L19
L55:
  mov    0x4(%rsp),%eax
  add    0x654(%rsp),%eax
  mov    0x9f68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x9f70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto() {
  int i, j, k;
  int a[101][100];
  int b[100];
  for (i = 1; i < 100; i++) {
    for (j = 1; j < 100; j += i)
      for (k = 1; k < 100; k++)
        a[j][k] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
  }
  return a[3][5] + b[1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toto>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L53:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L53
  sub    $0xf70,%rsp
  mov    $0x190,%r9d
  mov    $0x1,%ebx
  xor    %r11d,%r11d
  mov    %fs:0x28,%rax
  mov    %rax,0x9f68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x9f60(%rsp),%rdi
  lea    0x4b0(%rsp),%r12
L52:
  mov    %ebx,%r10d
  lea    -0x9dd0(%rdi),%rsi
  mov    %r12,%rcx
  mov    $0x1,%r8d
L41:
  lea    -0x18c(%rcx),%rax
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    0x320(%rsi),%edx
  add    $0x4,%rax
  add    $0x2,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L57
  add    %r10d,%r8d
  add    %r9,%rsi
  lea    (%rax,%r9,1),%rcx
  cmp    $0x63,%r8d
  jle    L41
  mov    0x0(%rbp),%eax
  mov    %rbx,%rcx
  sub    %r11,%rcx
  add    $0x2,%eax
  mov    %eax,0x4(%rbp)
  lea    -0x9ab0(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rax),%esi
  lea    0x2(%rsi),%edx
  mov    %edx,-0x190(%rax,%rcx,4)
  add    $0x190,%rax
  cmp    %rdi,%rax
  jne    L5
  add    $0x1,%r11
  add    $0x1,%rbx
  lea    0x4(%rax),%rdi
  add    $0x4,%rbp
  add    $0x190,%r9
  cmp    $0x63,%r11
  jne    L52
  mov    0x4(%rsp),%eax
  add    0x654(%rsp),%eax
  mov    0x9f68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x9f70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto() {
  int i, j, k;
  int a[101][100];
  int b[100];
  for (i = 1; i < 100; i++) {
    for (j = 1; j < 100; j += i)
      for (k = 1; k < 100; k++)
        a[j][k] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
  }
  return a[3][5] + b[1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toto>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L68:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L68
  sub    $0xfa8,%rsp
  mov    $0x190,%r8d
  mov    $0x1,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x9f98(%rsp)
  xor    %eax,%eax
  lea    0x4d4(%rsp),%rax
  lea    0x30(%rsp),%r13
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x28(%rsp)
  lea    0x354(%rsp),%rax
  mov    0x8(%rsp),%rbx
  lea    0x9f90(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  lea    0x4e0(%rsp),%rax
  mov    %rax,0x20(%rsp)
L28:
  add    $0x1,%rbx
  mov    0x28(%rsp),%rdx
  mov    0x10(%rsp),%r11
  mov    %r14d,%ebp
  mov    0x20(%rsp),%rsi
  lea    0x0(,%rbx,4),%r12
  mov    %rbx,0x18(%rsp)
  lea    -0x9dd0(%rdi),%rax
  lea    0x188(%r12),%rbx
  mov    $0x194,%r9d
  mov    $0x1,%r10d
  add    $0x18c,%r12
L10:
  lea    0x18c(%r9),%r15
  lea    (%rbx,%r9,1),%rcx
  cmp    %rcx,%r15
  jle    L18
  lea    (%r12,%r9,1),%rcx
  cmp    %rcx,%r9
  jl     L63
L18:
  mov    0x320(%rax),%r15d
  mov    %r11,%rcx
  add    $0x2,%r15d
  movd   %r15d,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  nopl   0x0(%rax)
L98:
  movups %xmm0,(%rcx)
  add    $0x10,%rcx
  cmp    %rdx,%rcx
  jne    L98
  mov    0x320(%rax),%ecx
  add    $0x2,%ecx
  movd   %ecx,%xmm0
  pshufd $0xe0,%xmm0,%xmm0
  movq   %xmm0,(%rdx)
  mov    0x320(%rax),%ecx
  add    $0x2,%ecx
  mov    %ecx,0x8(%rdx)
L43:
  add    %ebp,%r10d
  add    %r8,%r9
  add    %r8,%rax
  add    %r8,%rdx
  add    %r8,%r11
  add    %r8,%rsi
  cmp    $0x63,%r10d
  jle    L10
  mov    0x0(%r13),%eax
  mov    %r14,%rcx
  sub    0x8(%rsp),%rcx
  add    $0x2,%eax
  mov    %eax,0x4(%r13)
  lea    -0x9ab0(%rdi),%rax
  nopl   0x0(%rax)
L84:
  mov    (%rax),%ebx
  lea    0x2(%rbx),%edx
  mov    %edx,-0x190(%rax,%rcx,4)
  add    $0x190,%rax
  cmp    %rdi,%rax
  jne    L84
  mov    0x18(%rsp),%rax
  add    $0x1,%r14
  add    $0x4,%r13
  add    $0x4,%rdi
  add    $0x190,%r8
  cmp    $0x63,%rax
  je     L83
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbx
  jmp    L28
L63:
  mov    %r11,%rcx
  nopl   (%rax)
L25:
  mov    0x320(%rax),%r15d
  add    $0x4,%rcx
  add    $0x2,%r15d
  mov    %r15d,-0x4(%rcx)
  cmp    %rsi,%rcx
  jne    L25
  jmp    L43
L83:
  mov    0x34(%rsp),%eax
  add    0x684(%rsp),%eax
  mov    0x9f98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  add    $0x9fa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto() {
  int i, j, k;
  int a[101][100];
  int b[100];
  for (i = 1; i < 100; i++) {
    for (j = 1; j < 100; j += i)
      for (k = 1; k < 100; k++)
        a[j][k] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
  }
  return a[3][5] + b[1];
}
```