ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<_wind_os_print_logo>:
  endbr64
  push   %r12
  lea    D30(%rip),%rdi
  push   %rbp
  lea    D39(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D23(%rip),%rax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    D22(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D44(%rip),%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <wind_printf@plt>
  lea    D5(%rip),%rsi
L10:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <wind_printf@plt>
  cmp    %r12,%rbx
  je     L2
  mov    (%rbx),%rsi
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D22
type_infered: string
name: retrieve_data
arguments: data_label: D44
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D30: 


tool: D39: %s


tool: D23:  \\  //\\  // 

tool: D22:   \\//  \\//  

tool: D44:    \/    \/   

tool: D5:  _    __    _

assistant: ```c
void _wind_os_print_logo(void) {
  int i;
  char *logo[4] = {" _    __    _", " \\\\  //\\\\  // ", "  \\\\//  \\\\//  ", "   \\/    \\/   "};
  wind_printf("\r\n");
  for (i = 0; i < 4; i++) {
    wind_printf("%s\r\n", logo[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_wind_os_print_logo>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdx
  lea    D0(%rip),%rcx
  push   %rbp
  movq   %rdx,%xmm0
  lea    D26(%rip),%rdi
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D14(%rip),%rax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  movq   %rax,%xmm1
  lea    D44(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <wind_printf@plt>
L15:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <wind_printf@plt>
  cmp    %r12,%rbx
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D44
type_guessed: string

tool: D5:  _    __    _

tool: D0:   \\//  \\//  

tool: D26: 


tool: D6: %s


tool: D14:  \\  //\\  // 

tool: D44:    \/    \/   

assistant: ```c
void _wind_os_print_logo(void) {
  int i;
  char *logo[4] = {" _    __    _", " \\\\  //\\\\  // ", "  \\\\//  \\\\//  ", "   \\/    \\/   "};
  wind_printf("\r\n");
  for (i = 0; i < 4; i++) {
    wind_printf("%s\r\n", logo[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prodDiagDir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  lea    0xa0(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  add    $0x2,%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  lea    0xf0(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  add    $0x3,%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int prodDiagDir(int matriz[][20], int linha, int coluna) {
  int produto;
  produto = matriz[linha][coluna];
  produto *= matriz[linha + 1][coluna + 1];
  produto *= matriz[linha + 2][coluna + 2];
  produto *= matriz[linha + 3][coluna + 3];
  return produto;
}
```
user: What is the c source code of the assembly code below?

```asm
<prodDiagDir>:
  endbr64
  movslq %esi,%rsi
  lea    (%rsi,%rsi,4),%rcx
  shl    $0x4,%rcx
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rax
  mov    (%rax,%rcx,1),%eax
  lea    0x1(%rdx),%esi
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rsi
  imul   0x50(%rcx,%rsi,1),%eax
  lea    0x2(%rdx),%esi
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rsi
  imul   0xa0(%rcx,%rsi,1),%eax
  add    $0x3,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rdx
  imul   0xf0(%rcx,%rdx,1),%eax
  ret
```

assistant: ```c
int prodDiagDir(int matriz[][20], int linha, int coluna) {
  int produto;
  produto = matriz[linha][coluna];
  produto *= matriz[linha + 1][coluna + 1];
  produto *= matriz[linha + 2][coluna + 2];
  produto *= matriz[linha + 3][coluna + 3];
  return produto;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prodDiagDir>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rsi,4),%rax
  shl    $0x4,%rax
  add    %rax,%rdi
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%eax
  imul   0x54(%rdx),%eax
  imul   0xa8(%rdx),%eax
  imul   0xfc(%rdx),%eax
  ret
```

assistant: ```c
int prodDiagDir(int matriz[][20], int linha, int coluna) {
  int produto;
  produto = matriz[linha][coluna];
  produto *= matriz[linha + 1][coluna + 1];
  produto *= matriz[linha + 2][coluna + 2];
  produto *= matriz[linha + 3][coluna + 3];
  return produto;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prodDiagDir>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rsi,4),%rax
  shl    $0x4,%rax
  add    %rax,%rdi
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%eax
  imul   0x54(%rdx),%eax
  imul   0xa8(%rdx),%eax
  imul   0xfc(%rdx),%eax
  ret
```

assistant: ```c
int prodDiagDir(int matriz[][20], int linha, int coluna) {
  int produto;
  produto = matriz[linha][coluna];
  produto *= matriz[linha + 1][coluna + 1];
  produto *= matriz[linha + 2][coluna + 2];
  produto *= matriz[linha + 3][coluna + 3];
  return produto;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L7
L39:
  addq   $0x1,-0x18(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L1
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L39
  jmp    L1
L44:
  subq   $0x1,-0x10(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L29
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L44
L29:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  int len;
  char *result;
  char *start = str;
  char *end = strchr(start, '\0');
  while (start < end && isspace(*start))
    start++;
  while (start < end && isspace(*(end - 1)))
    end--;
  len = end - start;
  result = malloc(len + 1);
  strncpy(result, start, len);
  result[len] = '\0';
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  cmp    %rax,%rbp
  jae    L46
L29:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L68
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L29
  mov    %rbx,%rbp
  jmp    L46
L68:
  cmp    %rbp,%rbx
  jbe    L46
L25:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L46
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L25
  mov    %rbp,%rbx
L46:
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim(char *str) {
  int len;
  char *result;
  char *start = str;
  char *end = strchr(start, '\0');
  while (start < end && isspace(*start))
    start++;
  while (start < end && isspace(*(end - 1)))
    end--;
  len = end - start;
  result = malloc(len + 1);
  strncpy(result, start, len);
  result[len] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %rax,%rbx
  cmp    %rax,%rbp
  jb     L21
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L74:
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  je     L13
L21:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L74
  cmp    %rbp,%rbx
  ja     L40
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L37:
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L13
L40:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
L13:
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim(char *str) {
  int len;
  char *result;
  char *start = str;
  char *end = strchr(start, '\0');
  while (start < end && isspace(*start))
    start++;
  while (start < end && isspace(*(end - 1)))
    end--;
  len = end - start;
  result = malloc(len + 1);
  strncpy(result, start, len);
  result[len] = '\0';
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %rax,%rbx
  cmp    %rax,%rbp
  jb     L16
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L63:
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  je     L57
L16:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L63
  cmp    %rbp,%rbx
  ja     L2
  jmp    L57
  cs nopw 0x0(%rax,%rax,1)
L77:
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L57
L2:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L77
L57:
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim(char *str) {
  int len;
  char *result;
  char *start = str;
  char *end = strchr(start, '\0');
  while (start < end && isspace(*start))
    start++;
  while (start < end && isspace(*(end - 1)))
    end--;
  len = end - start;
  result = malloc(len + 1);
  strncpy(result, start, len);
  result[len] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stuffdouble>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rdx
  movq   %xmm0,%rax
  movzwl (%rsi),%esi
  mov    %al,(%rdi,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  movzbl %ah,%ebx
  mov    %bl,(%rdi,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  movq   %xmm0,%rdi
  shr    $0x10,%rdi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  movq   %xmm0,%rdi
  shr    $0x18,%rdi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  movq   %xmm0,%rdi
  shr    $0x20,%rdi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  movq   %xmm0,%rdi
  shr    $0x28,%rdi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  movq   %xmm0,%rdi
  shr    $0x30,%rdi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  shr    $0x38,%rax
  mov    %al,(%rcx,%rsi,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int stuffdouble(double data, unsigned char *buffer, unsigned short *index) {
  unsigned long long *tempp, temp;
  tempp = (unsigned long long *)&data;
  temp = *tempp;
  buffer[*index] = (temp >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 8) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 16) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 24) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 32) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 40) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 48) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 56) & 0xff;
  *index += 1;
  return (*index);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stuffdouble>:
  endbr64
  mov    %rsi,%rdx
  push   %rbx
  movzwl (%rsi),%esi
  movq   %xmm0,%rax
  mov    %rdi,%rcx
  mov    %al,(%rdi,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %ah,(%rdi,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x38,%rax
  shr    $0x10,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x18,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x20,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x28,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x30,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  pop    %rbx
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %al,(%rcx,%rsi,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  ret
```

assistant: ```c
int stuffdouble(double data, unsigned char *buffer, unsigned short *index) {
  unsigned long long *tempp, temp;
  tempp = (unsigned long long *)&data;
  temp = *tempp;
  buffer[*index] = (temp >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 8) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 16) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 24) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 32) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 40) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 48) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 56) & 0xff;
  *index += 1;
  return (*index);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stuffdouble>:
  endbr64
  mov    %rsi,%rdx
  push   %rbx
  movzwl (%rsi),%esi
  movq   %xmm0,%rax
  mov    %rdi,%rcx
  mov    %al,(%rdi,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %ah,(%rdi,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x38,%rax
  shr    $0x10,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x18,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x20,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x28,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  movq   %xmm0,%rdi
  shr    $0x30,%rdi
  lea    0x1(%rbx),%esi
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %dil,(%rcx,%rsi,1)
  movzwl (%rdx),%ebx
  lea    0x1(%rbx),%esi
  pop    %rbx
  mov    %si,(%rdx)
  movzwl %si,%esi
  mov    %al,(%rcx,%rsi,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  ret
```

assistant: ```c
int stuffdouble(double data, unsigned char *buffer, unsigned short *index) {
  unsigned long long *tempp, temp;
  tempp = (unsigned long long *)&data;
  temp = *tempp;
  buffer[*index] = (temp >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 8) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 16) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 24) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 32) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 40) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 48) & 0xff;
  *index += 1;
  buffer[*index] = (temp >> 56) & 0xff;
  *index += 1;
  return (*index);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<telldir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

assistant: ```c
long telldir(DIR *dirp) {
  errno = EPERM;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<telldir>:
  endbr64
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long telldir(DIR *dirp) {
  errno = EPERM;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<telldir>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long telldir(DIR *dirp) {
  errno = EPERM;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<telldir>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long telldir(DIR *dirp) {
  errno = EPERM;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<goodbye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D41
type_infered: string
name: parse_data
arguments: tag: D75
type_infered: string
name: parse_data
arguments: tag: D72
type_infered: string
name: parse_data
arguments: tag: D45
type_infered: string
name: parse_data
arguments: tag: D49
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D53
type_infered: string
name: parse_data
arguments: tag: D89
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D41: 
TNC version 2.5.


tool: D75: (C)Copyrights TNC


tool: D72: Paul Taylor,2005.


tool: D45: TNC is GNU GPL'd.


tool: D49: Thanx to Jesse


tool: D31: for the TNC idea.


tool: D53: iPod port done by


tool: D89: Brandon Holland.


tool: D18: Modified by Keripo



assistant: ```c
void goodbye() {
  printf("\nTNC version 2.5.\n");
  printf("(C)Copyrights TNC\n");
  printf("Paul Taylor,2005.\n");
  printf("TNC is GNU GPL'd.\n");
  printf("Thanx to Jesse\n");
  printf("for the TNC idea.\n");
  printf("iPod port done by\n");
  printf("Brandon Holland.\n");
  printf("Modified by Keripo\n\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<goodbye>:
  endbr64
  sub    $0x8,%rsp
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D40
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D54
type_guessed: string
name: unpack_data
arguments: data_label: D56
type_guessed: string
name: unpack_data
arguments: data_label: D33
type_guessed: string
name: unpack_data
arguments: data_label: D43
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D51
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string

tool: D40: 
TNC version 2.5.


tool: D41: (C)Copyrights TNC


tool: D54: Paul Taylor,2005.


tool: D56: TNC is GNU GPL'd.


tool: D33: Thanx to Jesse


tool: D43: for the TNC idea.


tool: D12: iPod port done by


tool: D51: Brandon Holland.


tool: D23: Modified by Keripo



assistant: ```c
void goodbye() {
  printf("\nTNC version 2.5.\n");
  printf("(C)Copyrights TNC\n");
  printf("Paul Taylor,2005.\n");
  printf("TNC is GNU GPL'd.\n");
  printf("Thanx to Jesse\n");
  printf("for the TNC idea.\n");
  printf("iPod port done by\n");
  printf("Brandon Holland.\n");
  printf("Modified by Keripo\n\n");
  return;
}
```