ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<preenche>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L22:
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int **preenche(int **m, int tam) {
  int i, j;
  for (i = 0; i < tam; i++)
    for (j = 0; j < tam; j++)
      m[i][j] = tam;
  return (m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<preenche>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r9
  mov    %esi,%r8d
  shl    $0x2,%r8
L13:
  mov    $0x0,%eax
L2:
  mov    (%rcx),%rdx
  mov    %esi,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r8
  jne    L2
  add    $0x8,%rcx
  cmp    %r9,%rcx
  jne    L13
L29:
  mov    %rdi,%rax
  ret
```

assistant: ```c
int **preenche(int **m, int tam) {
  int i, j;
  for (i = 0; i < tam; i++)
    for (j = 0; j < tam; j++)
      m[i][j] = tam;
  return (m);
}
```
user: What is the c source code of the assembly code below:

```asm
<preenche>:
  endbr64
  mov    %rdi,%r10
  test   %esi,%esi
  jle    L22
  lea    -0x1(%rsi),%eax
  mov    %esi,%r8d
  mov    %rdi,%rcx
  lea    0x8(%rdi,%rax,8),%r9
  shl    $0x2,%r8
  nopl   (%rax)
L20:
  mov    (%rcx),%rax
  lea    (%r8,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %esi,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L25
  add    $0x8,%rcx
  cmp    %r9,%rcx
  jne    L20
L22:
  mov    %r10,%rax
  ret
```

assistant: ```c
int **preenche(int **m, int tam) {
  int i, j;
  for (i = 0; i < tam; i++)
    for (j = 0; j < tam; j++)
      m[i][j] = tam;
  return (m);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<preenche>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  test   %esi,%esi
  jle    L71
  lea    -0x1(%rsi),%eax
  mov    %esi,%r9d
  movd   %esi,%xmm1
  mov    %esi,%ecx
  mov    %rax,%r11
  lea    0x8(%rdi,%rax,8),%rbx
  mov    %esi,%eax
  and    $0xfffffffc,%r9d
  shr    $0x2,%eax
  pshufd $0x0,%xmm1,%xmm0
  lea    -0x1(%rax),%r10d
  add    $0x1,%r10
  shl    $0x4,%r10
L29:
  mov    (%rdi),%rsi
  cmp    $0x2,%r11d
  jbe    L21
  mov    %rsi,%rax
  lea    (%r10,%rsi,1),%rdx
L79:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L79
  mov    %r9d,%eax
  cmp    %ecx,%r9d
  je     L37
L74:
  movslq %eax,%rdx
  mov    %ecx,(%rsi,%rdx,4)
  lea    0x0(,%rdx,4),%r8
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jle    L37
  add    $0x2,%eax
  mov    %ecx,0x4(%rsi,%r8,1)
  cmp    %eax,%ecx
  jle    L37
  mov    %ecx,0x8(%rsi,%r8,1)
L37:
  add    $0x8,%rdi
  cmp    %rbx,%rdi
  jne    L29
L71:
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  jmp    L74
```

assistant: ```c
int **preenche(int **m, int tam) {
  int i, j;
  for (i = 0; i < tam; i++)
    for (j = 0; j < tam; j++)
      m[i][j] = tam;
  return (m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x9,-0x30(%rbp)
  jg     L8
  mov    $0x5,%eax
  jmp    L69
L8:
  mov    -0x30(%rbp),%rax
  lea    -0xa(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x6,-0x14(%rbp)
  je     L32
  mov    $0x5,%eax
  jmp    L69
L32:
  mov    -0x30(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <rl_crc64@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L44
  mov    $0x0,%eax
  jmp    L69
L44:
  mov    $0x5,%eax
L69:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int verify(unsigned char *data, long datalen) {
  unsigned char *footer;
  uint16_t rdbver;
  uint64_t crc;
  if (datalen < 10)
    return 5;
  footer = data + (datalen - 10);
  rdbver = (footer[1] << 8) | footer[0];
  if (rdbver != 6)
    return 5;
  crc = rl_crc64(0, data, datalen - 8);
  ;
  return (memcmp(&crc, footer + 2, 8) == 0) ? 0 : 5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<verify>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x5,%edx
  cmp    $0x9,%rsi
  jle    L32
  lea    -0xa(%rdi,%rsi,1),%rbx
  movzbl 0x1(%rbx),%eax
  shl    $0x8,%eax
  movzbl (%rbx),%edx
  or     %edx,%eax
  mov    $0x5,%edx
  cmp    $0x6,%eax
  je     L18
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L18:
  lea    -0x8(%rsi),%rdx
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <rl_crc64@plt>
  mov    %eax,0x4(%rsp)
  lea    0x2(%rbx),%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x8,%edx
  call   <memcmp@plt>
  neg    %rax
  sbb    %edx,%edx
  and    $0x5,%edx
  jmp    L32
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int verify(unsigned char *data, long datalen) {
  unsigned char *footer;
  uint16_t rdbver;
  uint64_t crc;
  if (datalen < 10)
    return 5;
  footer = data + (datalen - 10);
  rdbver = (footer[1] << 8) | footer[0];
  if (rdbver != 6)
    return 5;
  crc = rl_crc64(0, data, datalen - 8);
  ;
  return (memcmp(&crc, footer + 2, 8) == 0) ? 0 : 5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<verify>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%rsi
  jle    L7
  lea    -0xa(%rdi,%rsi,1),%rbx
  cmpw   $0x6,(%rbx)
  je     L3
L7:
  mov    $0x5,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L3:
  lea    -0x8(%rsi),%rdx
  mov    %rdi,%rsi
  xor    %edi,%edi
  call   <rl_crc64@plt>
  lea    0x2(%rbx),%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x8,%edx
  mov    %eax,0x4(%rsp)
  call   <memcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L24
  jmp    L7
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int verify(unsigned char *data, long datalen) {
  unsigned char *footer;
  uint16_t rdbver;
  uint64_t crc;
  if (datalen < 10)
    return 5;
  footer = data + (datalen - 10);
  rdbver = (footer[1] << 8) | footer[0];
  if (rdbver != 6)
    return 5;
  crc = rl_crc64(0, data, datalen - 8);
  ;
  return (memcmp(&crc, footer + 2, 8) == 0) ? 0 : 5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<verify>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%rsi
  jle    L47
  lea    -0xa(%rdi,%rsi,1),%rbx
  cmpw   $0x6,(%rbx)
  je     L46
L47:
  mov    $0x5,%eax
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L46:
  lea    -0x8(%rsi),%rdx
  mov    %rdi,%rsi
  xor    %edi,%edi
  call   <rl_crc64@plt>
  lea    0x2(%rbx),%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x8,%edx
  mov    %eax,0x4(%rsp)
  call   <memcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L33
  jmp    L47
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int verify(unsigned char *data, long datalen) {
  unsigned char *footer;
  uint16_t rdbver;
  uint64_t crc;
  if (datalen < 10)
    return 5;
  footer = data + (datalen - 10);
  rdbver = (footer[1] << 8) | footer[0];
  if (rdbver != 6)
    return 5;
  crc = rl_crc64(0, data, datalen - 8);
  ;
  return (memcmp(&crc, footer + 2, 8) == 0) ? 0 : 5;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<palindromeTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rax,-0x48(%rbp)
  lea    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <stringReverse@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: %lu

assistant: ```c
int palindromeTest(unsigned long int a) {
  char forward[20];
  char backward[20];
  size_t size;
  size = sprintf(forward, "%lu", a);
  strcpy(backward, forward);
  stringReverse(backward);
  return !strcmp(forward, backward);
}
```
user: Translate the below assembly code into C programming language:

```asm
<palindromeTest>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    0x20(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <stringReverse@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: %lu

assistant: ```c
int palindromeTest(unsigned long int a) {
  char forward[20];
  char backward[20];
  size_t size;
  size = sprintf(forward, "%lu", a);
  strcpy(backward, forward);
  stringReverse(backward);
  return !strcmp(forward, backward);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<palindromeTest>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  lea    D4(%rip),%rsi
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r12
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <stringReverse@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x48,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: %lu

assistant: ```c
int palindromeTest(unsigned long int a) {
  char forward[20];
  char backward[20];
  size_t size;
  size = sprintf(forward, "%lu", a);
  strcpy(backward, forward);
  stringReverse(backward);
  return !strcmp(forward, backward);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<palindromeTest>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  lea    D5(%rip),%rsi
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r12
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <stringReverse@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x48,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: %lu

assistant: ```c
int palindromeTest(unsigned long int a) {
  char forward[20];
  char backward[20];
  size_t size;
  size = sprintf(forward, "%lu", a);
  strcpy(backward, forward);
  stringReverse(backward);
  return !strcmp(forward, backward);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<manhattan_distance_erode_1D>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  imul   %esi,%ebx
  test   %ebx,%ebx
  je     L90
  mov    %esi,%r8d
  mov    %edx,%r11d
  mov    %rdi,%rcx
  mov    %esi,%ebp
  mov    %esi,%r9d
  neg    %r9d
  mov    $0x0,%esi
  lea    (%rdx,%r8,1),%r12d
  jmp    L10
L53:
  mov    %r12d,(%rcx)
  cmp    %esi,%r8d
  ja     L91
  mov    %r9d,%eax
  mov    (%rdi,%rax,4),%eax
  add    $0x1,%eax
  cmp    %r12d,%eax
  cmova  %r12d,%eax
  mov    %eax,(%rcx)
L91:
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %ebp
  test   %edx,%edx
  je     L47
  lea    -0x1(%rsi),%eax
  mov    (%rdi,%rax,4),%eax
  lea    0x1(%rax),%eax
  mov    (%r10),%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
  mov    %eax,(%r10)
L47:
  add    $0x1,%esi
  add    $0x4,%rcx
  add    $0x1,%r9d
  cmp    %ebx,%esi
  je     L12
L10:
  mov    %rcx,%r10
  cmpl   $0x0,(%rcx)
  je     L53
  movl   $0x0,(%rcx)
  jmp    L47
L12:
  cmp    $0x1,%ebx
  jne    L90
  cmp    $0x1,%r11d
  jbe    L93
  mov    %r8d,%eax
  mov    (%rdi,%rax,4),%eax
  lea    0x1(%rax),%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
  mov    %eax,(%rdi)
L93:
  cmp    $0x1,%r8d
  jbe    L90
  mov    0x4(%rdi),%eax
  lea    0x1(%rax),%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
  mov    %eax,(%rdi)
L90:
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int manhattan_distance_erode_1D(unsigned int *image_data_uint, int width, int height) {
  unsigned int idx = 0;
  for (idx = 0; idx < (height * width); idx++) {
    if (image_data_uint[idx])
      image_data_uint[idx] = 0;
    else {
      image_data_uint[idx] = height + width;
      if ((idx / width) > 0)
        image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx - width] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx - width] + 1));
      if ((idx % width) > 0)
        image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx - 1] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx - 1] + 1));
    }
  }
  for (idx = (height * width) - 1; idx <= 0; idx--) {
    if ((idx / width) + 1 < height)
      image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx + width] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx + width] + 1));
    if ((idx % width) + 1 < width)
      image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx + 1] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx + 1] + 1));
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<manhattan_distance_erode_1D>:
  endbr64
  mov    %edx,%r11d
  mov    %esi,%r10d
  push   %rbx
  mov    %esi,%ecx
  imul   %esi,%r11d
  neg    %r10d
  lea    (%rdx,%rsi,1),%ebx
  test   %r11d,%r11d
  je     L81
  mov    %edx,%r9d
  mov    %rdi,%r8
  xor    %esi,%esi
  jmp    L80
  nopw   0x0(%rax,%rax,1)
L15:
  movl   $0x0,(%r8)
L19:
  add    $0x1,%esi
  add    $0x4,%r8
  add    $0x1,%r10d
  cmp    %r11d,%esi
  je     L64
L80:
  mov    (%r8),%eax
  test   %eax,%eax
  jne    L15
  mov    %ebx,(%r8)
  cmp    %esi,%ecx
  ja     L47
  mov    %r10d,%eax
  mov    (%rdi,%rax,4),%eax
  add    $0x1,%eax
  cmp    %ebx,%eax
  cmova  %ebx,%eax
  mov    %eax,(%r8)
L47:
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L19
  lea    -0x1(%rsi),%eax
  mov    (%r8),%edx
  mov    (%rdi,%rax,4),%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmova  %edx,%eax
  add    $0x1,%esi
  add    $0x4,%r8
  add    $0x1,%r10d
  mov    %eax,-0x4(%r8)
  cmp    %r11d,%esi
  jne    L80
L64:
  cmp    $0x1,%esi
  jne    L81
  cmp    $0x1,%r9d
  jbe    L95
  mov    %ecx,%eax
  mov    (%rdi),%edx
  mov    (%rdi,%rax,4),%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  cmova  %edx,%eax
  mov    %eax,(%rdi)
L95:
  cmp    $0x1,%ecx
  ja     L29
L81:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L29:
  mov    0x4(%rdi),%eax
  mov    (%rdi),%edx
  pop    %rbx
  add    $0x1,%eax
  cmp    %edx,%eax
  cmova  %edx,%eax
  mov    %eax,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int manhattan_distance_erode_1D(unsigned int *image_data_uint, int width, int height) {
  unsigned int idx = 0;
  for (idx = 0; idx < (height * width); idx++) {
    if (image_data_uint[idx])
      image_data_uint[idx] = 0;
    else {
      image_data_uint[idx] = height + width;
      if ((idx / width) > 0)
        image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx - width] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx - width] + 1));
      if ((idx % width) > 0)
        image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx - 1] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx - 1] + 1));
    }
  }
  for (idx = (height * width) - 1; idx <= 0; idx--) {
    if ((idx / width) + 1 < height)
      image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx + width] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx + width] + 1));
    if ((idx % width) + 1 < width)
      image_data_uint[idx] = ((image_data_uint[idx]) <= (image_data_uint[idx + 1] + 1) ? (image_data_uint[idx]) : (image_data_uint[idx + 1] + 1));
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x1,-0x14(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L10
L26:
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L10
L17:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fib>
  add    %ebx,%eax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n, int *ptr) {
  *ptr = *ptr + 1;
  if (n == 1) {
    return 1;
  }
  if (n == 0) {
    return 0;
  }
  return fib(n - 1, ptr) + fib(n - 2, ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<fib>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  addl   $0x1,(%rsi)
  cmp    $0x1,%edi
  je     L3
  mov    %rsi,%rbp
  test   %edi,%edi
  jne    L27
L3:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%r12d
  lea    -0x2(%rbx),%edi
  mov    %rbp,%rsi
  call   <fib>
  lea    (%r12,%rax,1),%ebx
  jmp    L3
```

assistant: ```c
int fib(int n, int *ptr) {
  *ptr = *ptr + 1;
  if (n == 1) {
    return 1;
  }
  if (n == 0) {
    return 0;
  }
  return fib(n - 1, ptr) + fib(n - 2, ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<antohs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L3
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    %eax,(%rbx)
  subl   $0x1,-0x14(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  jns    L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void antohs(uint16_t *t, int len) {
  int pos = len - 1;
  while (pos >= 0) {
    t[pos] = ntohs(t[pos]);
    pos--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<antohs>:
  endbr64
  sub    $0x1,%esi
  js     L0
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movslq %esi,%rbx
L1:
  mov    0x0(%rbp,%rbx,4),%edi
  call   <ntohs@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
void antohs(uint16_t *t, int len) {
  int pos = len - 1;
  while (pos >= 0) {
    t[pos] = ntohs(t[pos]);
    pos--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<antohs>:
  endbr64
  sub    $0x1,%esi
  js     L18
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L10:
  mov    0x0(%rbp,%rbx,4),%edi
  call   <ntohs@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void antohs(uint16_t *t, int len) {
  int pos = len - 1;
  while (pos >= 0) {
    t[pos] = ntohs(t[pos]);
    pos--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<antohs>:
  endbr64
  sub    $0x1,%esi
  js     L9
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L15:
  mov    0x0(%rbp,%rbx,4),%edi
  call   <ntohs@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void antohs(uint16_t *t, int len) {
  int pos = len - 1;
  while (pos >= 0) {
    t[pos] = ntohs(t[pos]);
    pos--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<oui_append_nb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t oui_append_nb(unsigned char *cp, const unsigned char *data, const size_t nlen) {
  memcpy(cp, data, nlen);
  return nlen;
}
```
user: What is the c source code of the assembly code below:

```asm
<oui_append_nb>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t oui_append_nb(unsigned char *cp, const unsigned char *data, const size_t nlen) {
  memcpy(cp, data, nlen);
  return nlen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<oui_append_nb>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t oui_append_nb(unsigned char *cp, const unsigned char *data, const size_t nlen) {
  memcpy(cp, data, nlen);
  return nlen;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<oui_append_nb>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t oui_append_nb(unsigned char *cp, const unsigned char *data, const size_t nlen) {
  memcpy(cp, data, nlen);
  return nlen;
}
```