ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%edx
  lea    D35(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x2,%edx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x2,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D35
type: string
name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D32
type: string
name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D39
type: string

tool: D35: A


tool: D2: B


tool: D32: C


tool: D1: D


tool: D39: E


assistant: ```c
int main(void) {
  char *x;
  char *y;
  write(1, "A\n", 2);
  x = malloc(8);
  write(1, "B\n", 2);
  free(x);
  write(1, "C\n", 2);
  y = malloc(16);
  write(1, "D\n", 2);
  free(y);
  write(1, "E\n", 2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2,%edx
  lea    D22(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x2,%edx
  lea    D35(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  lea    D10(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x2,%edx
  lea    D18(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  lea    D38(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
type_guessed: string
name: read_data
arguments: data_tag: D35
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string
name: read_data
arguments: data_tag: D38
type_guessed: string

tool: D22: A


tool: D35: B


tool: D10: C


tool: D18: D


tool: D38: E


assistant: ```c
int main(void) {
  char *x;
  char *y;
  write(1, "A\n", 2);
  x = malloc(8);
  write(1, "B\n", 2);
  free(x);
  write(1, "C\n", 2);
  y = malloc(16);
  write(1, "D\n", 2);
  free(y);
  write(1, "E\n", 2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D11(%rip),%rsi
  call   <write@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D20(%rip),%rsi
  mov    %rax,%rbp
  call   <write@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D30(%rip),%rsi
  call   <write@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D2(%rip),%rsi
  mov    %rax,%rbp
  call   <write@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D14(%rip),%rsi
  call   <write@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D20
data_type: string
name: disassemble_data
arguments: label: D30
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string

tool: D11: A


tool: D20: B


tool: D30: C


tool: D2: D


tool: D14: E


assistant: ```c
int main(void) {
  char *x;
  char *y;
  write(1, "A\n", 2);
  x = malloc(8);
  write(1, "B\n", 2);
  free(x);
  write(1, "C\n", 2);
  y = malloc(16);
  write(1, "D\n", 2);
  free(y);
  write(1, "E\n", 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D45(%rip),%rsi
  call   <write@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D10(%rip),%rsi
  mov    %rax,%rbp
  call   <write@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D38(%rip),%rsi
  call   <write@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D17(%rip),%rsi
  mov    %rax,%rbp
  call   <write@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x2,%edx
  mov    $0x1,%edi
  lea    D16(%rip),%rsi
  call   <write@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D45
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D38
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string

tool: D45: A


tool: D10: B


tool: D38: C


tool: D17: D


tool: D16: E


assistant: ```c
int main(void) {
  char *x;
  char *y;
  write(1, "A\n", 2);
  x = malloc(8);
  write(1, "B\n", 2);
  free(x);
  write(1, "C\n", 2);
  y = malloc(16);
  write(1, "D\n", 2);
  free(y);
  write(1, "E\n", 2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D33
type_infered: string
name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D3: Usage:udp_scan	dest	[-s start_port]


tool: D14: 			[-e end_port]


tool: D9: 			[-i interval]


tool: D33: 			[-a attempts]


tool: D24: 			[-p payload]


tool: D16: 			[-w time_to_exit]


tool: D6: 			[-h help]


assistant: ```c
void help(void) {
  printf("Usage:udp_scan\tdest\t[-s start_port]\n");
  printf("\t\t\t[-e end_port]\n");
  printf("\t\t\t[-i interval]\n");
  printf("\t\t\t[-a attempts]\n");
  printf("\t\t\t[-p payload]\n");
  printf("\t\t\t[-w time_to_exit]\n");
  printf("\t\t\t[-h help]\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_infered: string
name: extract_symbolic_data
arguments: label: D57
type_infered: string
name: extract_symbolic_data
arguments: label: D45
type_infered: string
name: extract_symbolic_data
arguments: label: D33
type_infered: string
name: extract_symbolic_data
arguments: label: D64
type_infered: string
name: extract_symbolic_data
arguments: label: D31
type_infered: string
name: extract_symbolic_data
arguments: label: D67
type_infered: string

tool: D11: Usage:udp_scan	dest	[-s start_port]


tool: D57: 			[-e end_port]


tool: D45: 			[-i interval]


tool: D33: 			[-a attempts]


tool: D64: 			[-p payload]


tool: D31: 			[-w time_to_exit]


tool: D67: 			[-h help]


assistant: ```c
void help(void) {
  printf("Usage:udp_scan\tdest\t[-s start_port]\n");
  printf("\t\t\t[-e end_port]\n");
  printf("\t\t\t[-i interval]\n");
  printf("\t\t\t[-a attempts]\n");
  printf("\t\t\t[-p payload]\n");
  printf("\t\t\t[-w time_to_exit]\n");
  printf("\t\t\t[-h help]\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D58
data_type: string
name: retrieve_data
arguments: label: D59
data_type: string
name: retrieve_data
arguments: label: D31
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string
name: retrieve_data
arguments: label: D50
data_type: string
name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D57
data_type: string

tool: D58: Usage:udp_scan	dest	[-s start_port]


tool: D59: 			[-e end_port]


tool: D31: 			[-i interval]


tool: D25: 			[-a attempts]


tool: D50: 			[-p payload]


tool: D26: 			[-w time_to_exit]


tool: D57: 			[-h help]


assistant: ```c
void help(void) {
  printf("Usage:udp_scan\tdest\t[-s start_port]\n");
  printf("\t\t\t[-e end_port]\n");
  printf("\t\t\t[-i interval]\n");
  printf("\t\t\t[-a attempts]\n");
  printf("\t\t\t[-p payload]\n");
  printf("\t\t\t[-w time_to_exit]\n");
  printf("\t\t\t[-h help]\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D60(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D64
type: string
name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D60
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D53
type: string
name: parse_data
arguments: tag: D35
type: string

tool: D64: Usage:udp_scan	dest	[-s start_port]


tool: D29: 			[-e end_port]


tool: D60: 			[-i interval]


tool: D12: 			[-a attempts]


tool: D5: 			[-p payload]


tool: D53: 			[-w time_to_exit]


tool: D35: 			[-h help]


assistant: ```c
void help(void) {
  printf("Usage:udp_scan\tdest\t[-s start_port]\n");
  printf("\t\t\t[-e end_port]\n");
  printf("\t\t\t[-i interval]\n");
  printf("\t\t\t[-a attempts]\n");
  printf("\t\t\t[-p payload]\n");
  printf("\t\t\t[-w time_to_exit]\n");
  printf("\t\t\t[-h help]\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Insertion_Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L5
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L62
L40:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0x14(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  subl   $0x1,-0x4(%rbp)
L62:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L40
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  jmp    L53
L5:
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
L53:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L52
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0x14(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L52:
  nop
  leave
  ret
```

assistant: ```c
void Insertion_Sort(char (*str_arr)[20], char *str, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    if (strcmp(str, str_arr[i]) < 0) {
      for (int j = count - 1; j > i; j--) {
        strcpy(str_arr[j], str_arr[j - 1]);
      }
      strcpy(str_arr[i], str);
      break;
    }
  }
  if (i == count)
    strcpy(str_arr[i - 1], str);
}
```
user: What is the c source code of the assembly code below?

```asm
<Insertion_Sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r13
  mov    %edx,%r12d
  test   %edx,%edx
  jle    L17
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L39:
  mov    %rbp,%r14
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L3
  add    $0x1,%ebx
  add    $0x14,%rbp
  cmp    %ebx,%r12d
  jne    L39
L88:
  movslq %r12d,%r12
  lea    (%r12,%r12,4),%rax
  mov    0x8(%rsp),%rdx
  lea    -0x14(%rdx,%rax,4),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  jmp    L56
L3:
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  jle    L69
  cltq
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,1),%rdi
  lea    -0x14(%rcx,%rax,1),%r15
  lea    -0x2(%r12),%eax
  sub    %ebx,%eax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  sub    %rax,%r15
L4:
  lea    -0x14(%rdi),%rbp
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  cmp    %r15,%rbp
  jne    L4
L69:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L19:
  cmp    %ebx,%r12d
  je     L20
L56:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0x0,%ebx
  jmp    L19
L20:
  mov    %ebx,%r12d
  jmp    L88
```

assistant: ```c
void Insertion_Sort(char (*str_arr)[20], char *str, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    if (strcmp(str, str_arr[i]) < 0) {
      for (int j = count - 1; j > i; j--) {
        strcpy(str_arr[j], str_arr[j - 1]);
      }
      strcpy(str_arr[i], str);
      break;
    }
  }
  if (i == count)
    strcpy(str_arr[i - 1], str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Insertion_Sort>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r13d,%r13d
  jle    L29
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ebx
  add    $0x14,%rbp
  cmp    %ebx,%r13d
  je     L20
L61:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L34
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jle    L3
  cltq
  sub    $0x2,%r13d
  sub    %ebx,%r13d
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  lea    0x0(%r13,%r13,4),%rdx
  lea    (%r15,%rax,1),%r12
  shl    $0x2,%rdx
  lea    -0x14(%r15,%rax,1),%rax
  sub    %rdx,%rax
  mov    %rax,%rbx
  nopl   0x0(%rax)
L48:
  mov    %r12,%rdi
  sub    $0x14,%r12
  mov    %r12,%rsi
  call   <strcpy@plt>
  cmp    %rbx,%r12
  jne    L48
L3:
  mov    %r14,%rsi
  mov    %rbp,%rdi
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <strcpy@plt>
L29:
  je     L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    0x0(%r13,%r13,4),%rax
  mov    %r14,%rsi
  lea    -0x14(%r15,%rax,4),%rdi
  jmp    L38
```

assistant: ```c
void Insertion_Sort(char (*str_arr)[20], char *str, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    if (strcmp(str, str_arr[i]) < 0) {
      for (int j = count - 1; j > i; j--) {
        strcpy(str_arr[j], str_arr[j - 1]);
      }
      strcpy(str_arr[i], str);
      break;
    }
  }
  if (i == count)
    strcpy(str_arr[i - 1], str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Insertion_Sort>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r13d,%r13d
  jle    L49
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebx
  add    $0x14,%rbp
  cmp    %ebx,%r13d
  je     L27
L57:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L17
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jle    L71
  cltq
  sub    $0x2,%r13d
  sub    %ebx,%r13d
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  lea    0x0(%r13,%r13,4),%rdx
  lea    (%r15,%rax,1),%r12
  shl    $0x2,%rdx
  lea    -0x14(%r15,%rax,1),%rax
  sub    %rdx,%rax
  mov    %rax,%rbx
  nopl   0x0(%rax)
L47:
  mov    %r12,%rdi
  sub    $0x14,%r12
  mov    %r12,%rsi
  call   <strcpy@plt>
  cmp    %rbx,%r12
  jne    L47
L71:
  mov    %r14,%rsi
  mov    %rbp,%rdi
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <strcpy@plt>
L49:
  je     L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  lea    0x0(%r13,%r13,4),%rax
  mov    %r14,%rsi
  lea    -0x14(%r15,%rax,4),%rdi
  jmp    L12
```

assistant: ```c
void Insertion_Sort(char (*str_arr)[20], char *str, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    if (strcmp(str, str_arr[i]) < 0) {
      for (int j = count - 1; j > i; j--) {
        strcpy(str_arr[j], str_arr[j - 1]);
      }
      strcpy(str_arr[i], str);
      break;
    }
  }
  if (i == count)
    strcpy(str_arr[i - 1], str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L28:
  movl   $0x0,-0xc(%rbp)
  jmp    L27
L29:
  movl   $0x0,-0x8(%rbp)
  jmp    L48
L47:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L48:
  cmpl   $0x7,-0x8(%rbp)
  jle    L47
  addl   $0x1,-0xc(%rbp)
L27:
  cmpl   $0x8,-0xc(%rbp)
  jle    L29
  addl   $0x1,-0x10(%rbp)
L24:
  cmpl   $0x4,-0x10(%rbp)
  jle    L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int i, j, k;
  int sum = 0;
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 9; ++j) {
      for (k = 0; k < 8; ++k) {
        sum += i + j + k;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int i, j, k;
  int sum = 0;
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 9; ++j) {
      for (k = 0; k < 8; ++k) {
        sum += i + j + k;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int i, j, k;
  int sum = 0;
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 9; ++j) {
      for (k = 0; k < 8; ++k) {
        sum += i + j + k;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int i, j, k;
  int sum = 0;
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 9; ++j) {
      for (k = 0; k < 8; ++k) {
        sum += i + j + k;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<append_filetype_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0xffff,-0xc(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L19
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2c,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edi
  call   <hex_asc_lo@plt>
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%edi
  call   <hex_asc_lo@plt>
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <hex_asc_lo@plt>
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    $0x4,%eax
L19:
  leave
  ret
```

assistant: ```c
int append_filetype_suffix(char *buf, __u16 filetype) {
  if (filetype == 0xffff)
    return 0;
  *buf++ = ',';
  *buf++ = hex_asc_lo(filetype >> 8);
  *buf++ = hex_asc_lo(filetype >> 4);
  *buf++ = hex_asc_lo(filetype >> 0);
  return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<append_filetype_suffix>:
  endbr64
  mov    $0x0,%eax
  cmp    $0xffff,%esi
  jne    L2
  ret
L2:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movb   $0x2c,(%rdi)
  mov    %esi,%edi
  sar    $0x8,%edi
  call   <hex_asc_lo@plt>
  mov    %al,0x1(%rbp)
  mov    %ebx,%edi
  sar    $0x4,%edi
  call   <hex_asc_lo@plt>
  mov    %al,0x2(%rbp)
  mov    %ebx,%edi
  call   <hex_asc_lo@plt>
  mov    %al,0x3(%rbp)
  mov    $0x4,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int append_filetype_suffix(char *buf, __u16 filetype) {
  if (filetype == 0xffff)
    return 0;
  *buf++ = ',';
  *buf++ = hex_asc_lo(filetype >> 8);
  *buf++ = hex_asc_lo(filetype >> 4);
  *buf++ = hex_asc_lo(filetype >> 0);
  return 4;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<append_filetype_suffix>:
  endbr64
  cmp    $0xffff,%esi
  jne    L0
  xor    %eax,%eax
  ret
  nop
L0:
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movb   $0x2c,(%rdi)
  mov    %esi,%edi
  sar    $0x8,%edi
  call   <hex_asc_lo@plt>
  mov    %ebp,%edi
  mov    %al,0x1(%rbx)
  sar    $0x4,%edi
  call   <hex_asc_lo@plt>
  mov    %ebp,%edi
  mov    %al,0x2(%rbx)
  call   <hex_asc_lo@plt>
  mov    %al,0x3(%rbx)
  add    $0x8,%rsp
  mov    $0x4,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int append_filetype_suffix(char *buf, __u16 filetype) {
  if (filetype == 0xffff)
    return 0;
  *buf++ = ',';
  *buf++ = hex_asc_lo(filetype >> 8);
  *buf++ = hex_asc_lo(filetype >> 4);
  *buf++ = hex_asc_lo(filetype >> 0);
  return 4;
}
```