user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L73
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L24
  addl   $0x1,-0x24(%rbp)
  jmp    L6
L24:
  cmpl   $0x2,-0xc(%rbp)
  jne    L124
  addl   $0x1,-0x20(%rbp)
  jmp    L6
L124:
  cmpl   $0x3,-0xc(%rbp)
  jne    L49
  addl   $0x1,-0x1c(%rbp)
  jmp    L6
L49:
  cmpl   $0x4,-0xc(%rbp)
  jne    L106
  addl   $0x1,-0x18(%rbp)
  jmp    L6
L106:
  cmpl   $0x5,-0xc(%rbp)
  jne    L21
  addl   $0x1,-0x14(%rbp)
  jmp    L6
L21:
  cmpl   $0x6,-0xc(%rbp)
  jne    L6
  addl   $0x1,-0x10(%rbp)
L6:
  addl   $0x1,-0x28(%rbp)
L73:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jle    L0
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L104
  call   <__stack_chk_fail@plt>
L104:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D60
datatype: string
name: disassemble_data
arguments: label: D31
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D44
datatype: string
name: disassemble_data
arguments: label: D53
datatype: string
name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D34
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string

tool: D60: How many times do you wish to roll the die?

tool: D31: %d

tool: D5: Ones: %d


tool: D44: Twos: %d


tool: D53: Threes: %d


tool: D36: Fours: %d


tool: D34: Fives: %d


tool: D28: Sixes: %d


assistant: ```c
int main() {
  int x;
  int counter = 1;
  int r = 0;
  int ones = 0;
  int twos = 0;
  int threes = 0;
  int fours = 0;
  int fives = 0;
  int sixes = 0;
  srand(time(NULL));
  printf("How many times do you wish to roll the die?\n");
  scanf("%d", &x);
  while (counter <= x) {
    r = rand() % 6 + 1;
    if (r == 1) {
      ones++;
    } else if (r == 2) {
      twos++;
    } else if (r == 3) {
      threes++;
    } else if (r == 4) {
      fours++;
    } else if (r == 5) {
      fives++;
    } else if (r == 6) {
      sixes++;
    }
    counter++;
  }
  printf("Ones: %d\n", ones);
  printf("Twos: %d\n", twos);
  printf("Threes: %d\n", threes);
  printf("Fours: %d\n", fours);
  printf("Fives: %d\n", fives);
  printf("Sixes: %d\n", sixes);
  return 0;
}
```