ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_report20>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L7
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    $0x0,%ebx
  lea    0x30(%rsp),%rbp
L15:
  mov    $0x28,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x48(%rsp)
  movl   $0x11,0x30(%rsp)
  movq   $0x0,0x50(%rsp)
  mov    %ebx,0x34(%rsp)
  movl   $0xff000001,0x38(%rsp)
  movzbl (%r14,%rbx,1),%eax
  mov    %al,0x3c(%rsp)
  mov    %rbp,%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L37
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L15
L7:
  mov    %rsp,%rbx
  mov    $0x28,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x18(%rsp)
  movl   $0x11,(%rsp)
  movl   $0x1,0x10(%rsp)
  mov    %rbx,%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <ioctl@plt>
L37:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_report20(int fd, const unsigned char *buf, size_t size) {
  struct hiddev_report_info rinfo;
  struct hiddev_usage_ref uref;
  int i, err;
  for (i = 0; i < size; i++) {
    memset(&uref, 0, sizeof(uref));
    uref.report_type = HID_REPORT_TYPE_OUTPUT;
    uref.report_id = 0x11;
    uref.field_index = 0;
    uref.usage_index = i;
    uref.usage_code = 0xff000001;
    uref.value = buf[i];
    err = ioctl(fd, HIDIOCSUSAGE, &uref);
    if (err < 0)
      return err;
  }
  memset(&rinfo, 0, sizeof(rinfo));
  rinfo.report_type = HID_REPORT_TYPE_OUTPUT;
  rinfo.report_id = 0x11;
  rinfo.num_fields = 1;
  err = ioctl(fd, HIDIOCSREPORT, &rinfo);
  return err;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_report20>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L57
  mov    D3(%rip),%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  xor    %r15d,%r15d
  lea    0x30(%rsp),%rbx
  jmp    L56
  nopl   0x0(%rax)
L54:
  add    $0x1,%r15
  cmp    %r12,%r15
  je     L13
L56:
  xor    %esi,%esi
  mov    $0x28,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    (%r14),%rax
  mov    %rbx,%rdx
  mov    %ebp,%edi
  movl   $0x11,0x30(%rsp)
  mov    %rax,0x48(%rsp)
  movzbl 0x0(%r13,%r15,1),%eax
  movq   $0x0,0x50(%rsp)
  mov    %al,0x3c(%rsp)
  mov    D32(%rip),%rax
  mov    %r15d,0x34(%rsp)
  mov    (%rax),%esi
  movl   $0xff000001,0x38(%rsp)
  call   <ioctl@plt>
  test   %eax,%eax
  jns    L54
L55:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  mov    D3(%rip),%r14
  nopl   (%rax)
L13:
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    $0x28,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    (%r14),%rax
  mov    %r12,%rdx
  mov    %ebp,%edi
  movl   $0x11,(%rsp)
  mov    %rax,0x18(%rsp)
  mov    D36(%rip),%rax
  movl   $0x1,0x10(%rsp)
  mov    (%rax),%esi
  call   <ioctl@plt>
  jmp    L55
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_report20(int fd, const unsigned char *buf, size_t size) {
  struct hiddev_report_info rinfo;
  struct hiddev_usage_ref uref;
  int i, err;
  for (i = 0; i < size; i++) {
    memset(&uref, 0, sizeof(uref));
    uref.report_type = HID_REPORT_TYPE_OUTPUT;
    uref.report_id = 0x11;
    uref.field_index = 0;
    uref.usage_index = i;
    uref.usage_code = 0xff000001;
    uref.value = buf[i];
    err = ioctl(fd, HIDIOCSUSAGE, &uref);
    if (err < 0)
      return err;
  }
  memset(&rinfo, 0, sizeof(rinfo));
  rinfo.report_type = HID_REPORT_TYPE_OUTPUT;
  rinfo.report_id = 0x11;
  rinfo.num_fields = 1;
  err = ioctl(fd, HIDIOCSREPORT, &rinfo);
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<send_report20>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L23
  mov    D21(%rip),%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  xor    %r15d,%r15d
  lea    0x30(%rsp),%rbx
  jmp    L11
  nopl   0x0(%rax)
L17:
  add    $0x1,%r15
  cmp    %r12,%r15
  je     L13
L11:
  xor    %esi,%esi
  mov    $0x28,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    (%r14),%rax
  mov    %rbx,%rdx
  mov    %ebp,%edi
  movl   $0x11,0x30(%rsp)
  mov    %rax,0x48(%rsp)
  movzbl 0x0(%r13,%r15,1),%eax
  movq   $0x0,0x50(%rsp)
  mov    %al,0x3c(%rsp)
  mov    D11(%rip),%rax
  mov    %r15d,0x34(%rsp)
  mov    (%rax),%esi
  movl   $0xff000001,0x38(%rsp)
  call   <ioctl@plt>
  test   %eax,%eax
  jns    L17
L52:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    D21(%rip),%r14
  nopl   (%rax)
L13:
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    $0x28,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    (%r14),%rax
  mov    %r12,%rdx
  mov    %ebp,%edi
  movl   $0x11,(%rsp)
  mov    %rax,0x18(%rsp)
  mov    D1(%rip),%rax
  movl   $0x1,0x10(%rsp)
  mov    (%rax),%esi
  call   <ioctl@plt>
  jmp    L52
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_report20(int fd, const unsigned char *buf, size_t size) {
  struct hiddev_report_info rinfo;
  struct hiddev_usage_ref uref;
  int i, err;
  for (i = 0; i < size; i++) {
    memset(&uref, 0, sizeof(uref));
    uref.report_type = HID_REPORT_TYPE_OUTPUT;
    uref.report_id = 0x11;
    uref.field_index = 0;
    uref.usage_index = i;
    uref.usage_code = 0xff000001;
    uref.value = buf[i];
    err = ioctl(fd, HIDIOCSUSAGE, &uref);
    if (err < 0)
      return err;
  }
  memset(&rinfo, 0, sizeof(rinfo));
  rinfo.report_type = HID_REPORT_TYPE_OUTPUT;
  rinfo.report_id = 0x11;
  rinfo.num_fields = 1;
  err = ioctl(fd, HIDIOCSREPORT, &rinfo);
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  jmp    L5
L57:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L19
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  shl    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L23
L19:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%edi
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%esi
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,%ecx
  movslq %edx,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  or     %ecx,%edi
  mov    %edi,%edx
  mov    %dl,(%rax)
L23:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x1,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x80000,%eax
  jne    L5
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x10000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    $0x10000,%eax
  je     L29
  mov    $0x1,%eax
  jmp    L32
L29:
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
L5:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
  mov    $0x0,%eax
L32:
  leave
  ret
```

assistant: ```c
int write_bits(FILE *f, char *bitbuf, int *bits, char *code) {
  while (*code) {
    int b = (*bits) % 8;
    if (!b)
      bitbuf[(*bits) / 8] = ((*code) - '0') << 7;
    else
      bitbuf[(*bits) / 8] |= (((*code) - '0') << (7 - b));
    (*bits)++;
    code++;
    if (*bits == 65536 * 8) {
      if (65536 != fwrite(bitbuf, 1, 65536, f))
        return 1;
      *bits = 0;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<write_bits>:
  endbr64
  movzbl (%rcx),%eax
  test   %al,%al
  je     L16
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    $0x7,%r13d
  jmp    L26
L47:
  lea    0x7(%rdx),%esi
  test   %edx,%edx
  cmovns %edx,%esi
  sar    $0x3,%esi
  movslq %esi,%rsi
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%edx
  and    $0x7,%edx
  sub    %ecx,%edx
  mov    %r13d,%ecx
  sub    %edx,%ecx
  shl    %cl,%eax
  or     %al,(%r12,%rsi,1)
L81:
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x1,%rbp
  cmp    $0x80000,%eax
  je     L71
L7:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L30
L26:
  mov    (%rbx),%edx
  test   $0x7,%dl
  jne    L47
  lea    0x7(%rdx),%ecx
  test   %edx,%edx
  cmovs  %ecx,%edx
  sar    $0x3,%edx
  movslq %edx,%rdx
  movsbl %al,%eax
  sub    $0x30,%eax
  shl    $0x7,%eax
  mov    %al,(%r12,%rdx,1)
  jmp    L81
L71:
  mov    %r14,%rcx
  mov    $0x10000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  cmp    $0x10000,%eax
  jne    L15
  movl   $0x0,(%rbx)
  jmp    L7
L30:
  mov    $0x0,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    $0x0,%eax
  ret
L15:
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
int write_bits(FILE *f, char *bitbuf, int *bits, char *code) {
  while (*code) {
    int b = (*bits) % 8;
    if (!b)
      bitbuf[(*bits) / 8] = ((*code) - '0') << 7;
    else
      bitbuf[(*bits) / 8] |= (((*code) - '0') << (7 - b));
    (*bits)++;
    code++;
    if (*bits == 65536 * 8) {
      if (65536 != fwrite(bitbuf, 1, 65536, f))
        return 1;
      *bits = 0;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_bits>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  movsbl (%rcx),%edx
  test   %dl,%dl
  je     L5
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rcx,%rbp
  mov    $0x7,%r12d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L63:
  shl    $0x7,%edx
L38:
  mov    %dl,(%rax)
  mov    (%rbx),%eax
  add    $0x1,%rbp
  add    $0x1,%eax
  mov    %eax,(%rbx)
  cmp    $0x80000,%eax
  je     L21
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L5
L12:
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  lea    0x7(%rcx),%eax
  cmovns %ecx,%eax
  sub    $0x30,%edx
  sar    $0x3,%eax
  cltq
  add    %r14,%rax
  test   $0x7,%cl
  je     L63
  mov    %ecx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  lea    (%rcx,%rdi,1),%esi
  mov    %r12d,%ecx
  and    $0x7,%esi
  sub    %edi,%esi
  sub    %esi,%ecx
  shl    %cl,%edx
  or     (%rax),%dl
  jmp    L38
  nopl   0x0(%rax)
L21:
  mov    %r13,%rcx
  mov    $0x10000,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <fwrite@plt>
  cmp    $0x10000,%eax
  jne    L77
  movl   $0x0,(%rbx)
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  jne    L12
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L77:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int write_bits(FILE *f, char *bitbuf, int *bits, char *code) {
  while (*code) {
    int b = (*bits) % 8;
    if (!b)
      bitbuf[(*bits) / 8] = ((*code) - '0') << 7;
    else
      bitbuf[(*bits) / 8] |= (((*code) - '0') << (7 - b));
    (*bits)++;
    code++;
    if (*bits == 65536 * 8) {
      if (65536 != fwrite(bitbuf, 1, 65536, f))
        return 1;
      *bits = 0;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_bits>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  movsbl (%rcx),%edx
  test   %dl,%dl
  je     L69
  mov    0x0(%rbp),%eax
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rcx,%rbx
  mov    $0x7,%r12d
  jmp    L51
  xchg   %ax,%ax
L9:
  shl    $0x7,%edx
L4:
  mov    %dl,(%rsi)
  mov    0x0(%rbp),%eax
  add    $0x1,%rbx
  add    $0x1,%eax
  mov    %eax,0x0(%rbp)
  cmp    $0x80000,%eax
  je     L20
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L69
L51:
  test   %eax,%eax
  lea    0x7(%rax),%ecx
  cmovns %eax,%ecx
  sub    $0x30,%edx
  sar    $0x3,%ecx
  movslq %ecx,%rcx
  lea    (%r14,%rcx,1),%rsi
  test   $0x7,%al
  je     L9
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%eax
  and    $0x7,%eax
  sub    %ecx,%eax
  mov    %r12d,%ecx
  sub    %eax,%ecx
  shl    %cl,%edx
  or     (%rsi),%dl
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r13,%rcx
  mov    $0x10000,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <fwrite@plt>
  cmp    $0x10000,%eax
  jne    L28
  movl   $0x0,0x0(%rbp)
  movsbl (%rbx),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L51
L69:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L28:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int write_bits(FILE *f, char *bitbuf, int *bits, char *code) {
  while (*code) {
    int b = (*bits) % 8;
    if (!b)
      bitbuf[(*bits) / 8] = ((*code) - '0') << 7;
    else
      bitbuf[(*bits) / 8] |= (((*code) - '0') << (7 - b));
    (*bits)++;
    code++;
    if (*bits == 65536 * 8) {
      if (65536 != fwrite(bitbuf, 1, 65536, f))
        return 1;
      *bits = 0;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<intCalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %edi,-0x134(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x134(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <superlu_malloc@plt>
  mov    %rax,-0x128(%rbp)
  cmpq   $0x0,-0x128(%rbp)
  jne    L29
  lea    -0x120(%rbp),%rax
  lea    D3(%rip),%r8
  mov    $0x94,%ecx
  lea    D5(%rip),%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <superlu_abort_and_exit@plt>
L29:
  mov    $0x0,%ebx
  jmp    L37
L7:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  add    $0x1,%ebx
L37:
  cmp    -0x134(%rbp),%ebx
  jl     L7
  mov    -0x128(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D0
type: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c

tool: D5: SUPERLU_MALLOC fails for buf in intCalloc()

tool: D0: %s at line %d in file %s


assistant: ```c
int *intCalloc(int n) {
  int *buf;
  register int i;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in intCalloc()", 148, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; ++i)
    buf[i] = 0;
  return (buf);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<intCalloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rdi,4),%edi
  call   <superlu_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
L16:
  test   %ebx,%ebx
  jle    L3
  mov    %rbp,%rax
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,4),%rdx
L42:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L42
L3:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %rbp,%rax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    %rsp,%r12
  lea    D19(%rip),%r8
  mov    $0x94,%ecx
  lea    D6(%rip),%rdx
  lea    D22(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L16
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D22
datatype: string

tool: D19: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c

tool: D6: SUPERLU_MALLOC fails for buf in intCalloc()

tool: D22: %s at line %d in file %s


assistant: ```c
int *intCalloc(int n) {
  int *buf;
  register int i;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in intCalloc()", 148, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; ++i)
    buf[i] = 0;
  return (buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<intCalloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L36:
  test   %ebx,%ebx
  jle    L25
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L25:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rsp,%rbp
  lea    D26(%rip),%r8
  mov    $0x94,%ecx
  mov    %rbp,%rdi
  lea    D12(%rip),%rdx
  lea    D18(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L36
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D26: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c

tool: D12: SUPERLU_MALLOC fails for buf in intCalloc()

tool: D18: %s at line %d in file %s


assistant: ```c
int *intCalloc(int n) {
  int *buf;
  register int i;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in intCalloc()", 148, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; ++i)
    buf[i] = 0;
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<intCalloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L36
L23:
  test   %ebx,%ebx
  jle    L30
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L30:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rsp,%rbp
  lea    D29(%rip),%r8
  mov    $0x94,%ecx
  mov    %rbp,%rdi
  lea    D1(%rip),%rdx
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L23
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D1
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D29: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c

tool: D1: SUPERLU_MALLOC fails for buf in intCalloc()

tool: D9: %s at line %d in file %s


assistant: ```c
int *intCalloc(int n) {
  int *buf;
  register int i;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in intCalloc()", 148, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Narrat/eispice/refs/heads/master/libs/superlu/SRC/memory.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; ++i)
    buf[i] = 0;
  return (buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<doubles_2d_scalar_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%edx
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <doubles_scalar_add@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void doubles_2d_scalar_add(double **tdarr1, double **tdarr2, int rows, int cols, double alpha, double **res_tdarr) {
  int i;
  for (i = 0; i < rows; i++)
    doubles_scalar_add(tdarr1[i], tdarr2[i], cols, alpha, res_tdarr[i]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<doubles_2d_scalar_add>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  jle    L16
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %ecx,%r14d
  mov    %r8,%r15
  mov    %edx,%ebp
  mov    $0x0,%ebx
L10:
  mov    (%r15,%rbx,8),%rcx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    (%r12,%rbx,8),%rdi
  movsd  0x8(%rsp),%xmm0
  mov    %r14d,%edx
  call   <doubles_scalar_add@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void doubles_2d_scalar_add(double **tdarr1, double **tdarr2, int rows, int cols, double alpha, double **res_tdarr) {
  int i;
  for (i = 0; i < rows; i++)
    doubles_scalar_add(tdarr1[i], tdarr2[i], cols, alpha, res_tdarr[i]);
}
```