ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L0
  nopl   0x0(%rax)
L9:
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  imul   %eax,%esi
L10:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L46
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edx
  test   $0x1,%al
  jne    L9
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  imul   %edx,%esi
  jmp    L10
  nopl   0x0(%rax)
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
data_type: string
name: unpack_data
arguments: data_label: D4
data_type: string

tool: D14: %d


tool: D4: %d

assistant: ```c
int main() {
  int n, sum, i;
  while (scanf("%d", &n) == 1) {
    if (1 == (n & 1)) {
      sum = ((n + 1) / 2) * n;
    } else {
      sum = (n / 2) * (n + 1);
    }
    printf("%d\n", sum);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L17
  nopl   0x0(%rax)
L16:
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  imul   %eax,%esi
L28:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L17:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L40
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edx
  test   $0x1,%al
  jne    L16
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  imul   %edx,%esi
  jmp    L28
  nopl   0x0(%rax)
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string
name: parse_data
arguments: data_label: D16
type: string

tool: D8: %d


tool: D16: %d

assistant: ```c
int main() {
  int n, sum, i;
  while (scanf("%d", &n) == 1) {
    if (1 == (n & 1)) {
      sum = ((n + 1) / 2) * n;
    } else {
      sum = (n / 2) * (n + 1);
    }
    printf("%d\n", sum);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  movl   $0x2,-0x28(%rbp)
  mov    -0x28(%rbp),%ecx
  lea    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <maxDistance@plt>
  mov    %eax,-0x24(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main() {
  int **grid = (int **)malloc(sizeof(int *) * 2);
  int arr[2] = {0, 1};
  int arr1[2] = {0, 1};
  grid[0] = arr;
  grid[1] = arr1;
  int size = 2;
  int max = maxDistance(grid, size, &size);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movl   $0x0,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  lea    0x8(%rsp),%rax
  mov    %rax,(%rdi)
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rdi)
  movl   $0x2,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x2,%esi
  call   <maxDistance@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int **grid = (int **)malloc(sizeof(int *) * 2);
  int arr[2] = {0, 1};
  int arr1[2] = {0, 1};
  grid[0] = arr;
  grid[1] = arr1;
  int size = 2;
  int max = maxDistance(grid, size, &size);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x10,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0x4(%rsp),%rdx
  mov    $0x2,%esi
  mov    %rax,%rdi
  movabs $0x100000000,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  lea    0x8(%rsp),%rax
  mov    %rax,(%rdi)
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rdi)
  movl   $0x2,0x4(%rsp)
  call   <maxDistance@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int **grid = (int **)malloc(sizeof(int *) * 2);
  int arr[2] = {0, 1};
  int arr1[2] = {0, 1};
  grid[0] = arr;
  grid[1] = arr1;
  int size = 2;
  int max = maxDistance(grid, size, &size);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x10,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  movq   %rax,%xmm0
  lea    0x20(%rsp),%rax
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  movdqa (%rsp),%xmm0
  lea    0x14(%rsp),%rdx
  mov    $0x2,%esi
  mov    %rax,%rdi
  mov    D4(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    %rax,0x20(%rsp)
  movups %xmm0,(%rdi)
  movl   $0x2,0x14(%rsp)
  call   <maxDistance@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int **grid = (int **)malloc(sizeof(int *) * 2);
  int arr[2] = {0, 1};
  int arr1[2] = {0, 1};
  grid[0] = arr;
  grid[1] = arr1;
  int size = 2;
  int max = maxDistance(grid, size, &size);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lock_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int lock_reg(int fd, int cmd, int type, off_t offset, int whence, off_t len) {
  struct flock lock;
  lock.l_type = type;
  lock.l_start = offset;
  lock.l_whence = whence;
  lock.l_len = len;
  return (fcntl(fd, cmd, &lock));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lock_reg>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edx,(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %r8d,0x4(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %rsp,%rdx
  call   <fcntl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_reg(int fd, int cmd, int type, off_t offset, int whence, off_t len) {
  struct flock lock;
  lock.l_type = type;
  lock.l_start = offset;
  lock.l_whence = whence;
  lock.l_len = len;
  return (fcntl(fd, cmd, &lock));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lock_reg>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edx,(%rsp)
  mov    %rsp,%rdx
  mov    %rcx,0x10(%rsp)
  mov    %r8d,0x4(%rsp)
  mov    %r9,0x8(%rsp)
  call   <fcntl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_reg(int fd, int cmd, int type, off_t offset, int whence, off_t len) {
  struct flock lock;
  lock.l_type = type;
  lock.l_start = offset;
  lock.l_whence = whence;
  lock.l_len = len;
  return (fcntl(fd, cmd, &lock));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lock_reg>:
  endbr64
  movd   %edx,%xmm0
  movd   %r8d,%xmm1
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  movq   %rcx,%xmm2
  mov    %rsp,%rdx
  movq   %xmm0,(%rsp)
  movq   %r9,%xmm0
  punpcklqdq %xmm2,%xmm0
  movups %xmm0,0x8(%rsp)
  call   <fcntl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_reg(int fd, int cmd, int type, off_t offset, int whence, off_t len) {
  struct flock lock;
  lock.l_type = type;
  lock.l_start = offset;
  lock.l_whence = whence;
  lock.l_len = len;
  return (fcntl(fd, cmd, &lock));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<maxSumSubArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0xfffffc18,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L30
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L30:
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  movl   $0x0,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L8:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d


assistant: ```c
void maxSumSubArray(int *arr, int len) {
  int maxSumSoFar = -1000;
  int currSum = 0;
  int a, b, s;
  a = b = s = 0;
  for (int i = 0; i < len; i++) {
    currSum += arr[i];
    if (currSum > maxSumSoFar) {
      maxSumSoFar = currSum;
      a = s;
      b = i;
    }
    if (currSum < 0) {
      currSum = 0;
      s = i + 1;
    }
  }
  printf("Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d\n", maxSumSoFar, a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxSumSubArray>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L17
  mov    %esi,%r8d
  mov    $0x0,%eax
  mov    $0x0,%r10d
  mov    $0x0,%ebx
  mov    $0x0,%r11d
  mov    $0x0,%ecx
  mov    $0xfffffc18,%esi
  mov    $0x0,%ebp
  jmp    L62
L27:
  test   %edx,%edx
  js     L3
L5:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L42
L62:
  mov    %eax,%r9d
  add    (%rdi,%rax,4),%ecx
  mov    %ecx,%edx
  cmp    %esi,%ecx
  jle    L27
  mov    %eax,%ebx
  mov    %r10d,%r11d
  mov    %ecx,%esi
  jmp    L27
L3:
  lea    0x1(%r9),%r10d
  mov    %ebp,%ecx
  jmp    L5
L17:
  mov    $0x0,%ebx
  mov    $0x0,%r11d
  mov    $0xfffffc18,%esi
L42:
  mov    %ebx,%ecx
  mov    %r11d,%edx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d


assistant: ```c
void maxSumSubArray(int *arr, int len) {
  int maxSumSoFar = -1000;
  int currSum = 0;
  int a, b, s;
  a = b = s = 0;
  for (int i = 0; i < len; i++) {
    currSum += arr[i];
    if (currSum > maxSumSoFar) {
      maxSumSoFar = currSum;
      a = s;
      b = i;
    }
    if (currSum < 0) {
      currSum = 0;
      s = i + 1;
    }
  }
  printf("Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d\n", maxSumSoFar, a, b);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maxSumSubArray>:
  endbr64
  mov    %esi,%r8d
  test   %esi,%esi
  jle    L8
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  xor    %eax,%eax
  mov    $0xfffffc18,%esi
  xor    %r9d,%r9d
  nop
L22:
  add    (%rdi),%eax
  cmp    %esi,%eax
  jle    L16
  mov    %edx,%r11d
  mov    %ecx,%r10d
  mov    %eax,%esi
L16:
  add    $0x1,%edx
  test   %eax,%eax
  cmovs  %edx,%ecx
  cmovs  %r9d,%eax
  add    $0x4,%rdi
  cmp    %edx,%r8d
  jne    L22
L24:
  mov    %r11d,%ecx
  mov    %r10d,%edx
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L8:
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  mov    $0xfffffc18,%esi
  jmp    L24
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d


assistant: ```c
void maxSumSubArray(int *arr, int len) {
  int maxSumSoFar = -1000;
  int currSum = 0;
  int a, b, s;
  a = b = s = 0;
  for (int i = 0; i < len; i++) {
    currSum += arr[i];
    if (currSum > maxSumSoFar) {
      maxSumSoFar = currSum;
      a = s;
      b = i;
    }
    if (currSum < 0) {
      currSum = 0;
      s = i + 1;
    }
  }
  printf("Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d\n", maxSumSoFar, a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<maxSumSubArray>:
  endbr64
  mov    %esi,%r8d
  test   %esi,%esi
  jle    L37
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  xor    %eax,%eax
  mov    $0xfffffc18,%esi
  xor    %r9d,%r9d
  nop
L10:
  add    (%rdi),%eax
  cmp    %eax,%esi
  jge    L6
  mov    %edx,%r11d
  mov    %ecx,%r10d
  mov    %eax,%esi
L6:
  add    $0x1,%edx
  test   %eax,%eax
  cmovs  %edx,%ecx
  cmovs  %r9d,%eax
  add    $0x4,%rdi
  cmp    %edx,%r8d
  jne    L10
L19:
  mov    %r11d,%ecx
  mov    %r10d,%edx
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L37:
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  mov    $0xfffffc18,%esi
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d


assistant: ```c
void maxSumSubArray(int *arr, int len) {
  int maxSumSoFar = -1000;
  int currSum = 0;
  int a, b, s;
  a = b = s = 0;
  for (int i = 0; i < len; i++) {
    currSum += arr[i];
    if (currSum > maxSumSoFar) {
      maxSumSoFar = currSum;
      a = s;
      b = i;
    }
    if (currSum < 0) {
      currSum = 0;
      s = i + 1;
    }
  }
  printf("Maximum Sum SubArray >>> Sum : %d, start : %d, end : %d\n", maxSumSoFar, a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<unique_no_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L42:
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L31
  mov    $0x0,%eax
  jmp    L48
L31:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L4
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    $0x1,%eax
L48:
  pop    %rbp
  ret
```

assistant: ```c
bool unique_no_array(char *str) {
  for (int i = 0; str[i] != '\0'; i++) {
    for (int j = 0; j < i; j++) {
      if (str[j] == str[i]) {
        return false;
      }
    }
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unique_no_array>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L56
  lea    0x1(%rdi),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  sub    %eax,%esi
L31:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L16
  lea    (%rsi,%rdx,1),%eax
  test   %eax,%eax
  jle    L9
  mov    %rdi,%rax
L51:
  cmp    %cl,(%rax)
  je     L49
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L51
L9:
  add    $0x1,%rdx
  jmp    L31
L56:
  mov    $0x1,%eax
  ret
L49:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool unique_no_array(char *str) {
  for (int i = 0; str[i] != '\0'; i++) {
    for (int j = 0; j < i; j++) {
      if (str[j] == str[i]) {
        return false;
      }
    }
  }
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<unique_no_array>:
  endbr64
  movzbl (%rdi),%r9d
  test   %r9b,%r9b
  je     L62
  add    $0x1,%rdi
  mov    $0x1,%r8d
  mov    %rdi,%rcx
  sub    %edi,%r8d
L22:
  movzbl (%rcx),%esi
  test   %sil,%sil
  je     L62
  lea    (%r8,%rcx,1),%eax
  test   %eax,%eax
  jle    L52
  mov    %rdi,%rax
  mov    %r9d,%edx
  jmp    L40
  nopl   (%rax)
L60:
  cmp    %rcx,%rax
  je     L52
  movzbl (%rax),%edx
  add    $0x1,%rax
L40:
  cmp    %dl,%sil
  jne    L60
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L52:
  add    $0x1,%rcx
  jmp    L22
L62:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool unique_no_array(char *str) {
  for (int i = 0; str[i] != '\0'; i++) {
    for (int j = 0; j < i; j++) {
      if (str[j] == str[i]) {
        return false;
      }
    }
  }
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<unique_no_array>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  mov    %edi,%esi
  lea    0x1(%rdi),%rdx
  neg    %esi
L20:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L10
  lea    (%rsi,%rdx,1),%eax
  test   %eax,%eax
  jle    L23
  mov    %rdi,%rax
  jmp    L24
  nopl   0x0(%rax)
L15:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L23
L24:
  cmp    %cl,(%rax)
  jne    L15
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rdx
  jmp    L20
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool unique_no_array(char *str) {
  for (int i = 0; str[i] != '\0'; i++) {
    for (int j = 0; j < i; j++) {
      if (str[j] == str[i]) {
        return false;
      }
    }
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <string@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <string@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x4,%rax
  movl   $0x5,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strprint@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *x = string();
  int *y = string();
  *(y - 1) = 5;
  strprint(x);
  free(x);
  free(y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <string@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <string@plt>
  mov    %rax,%rbx
  movl   $0x5,-0x4(%rax)
  mov    %rbp,%rdi
  call   <strprint@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *x = string();
  int *y = string();
  *(y - 1) = 5;
  strprint(x);
  free(x);
  free(y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <string@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <string@plt>
  mov    %r12,%rdi
  movl   $0x5,-0x4(%rax)
  mov    %rax,%rbp
  call   <strprint@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int *x = string();
  int *y = string();
  *(y - 1) = 5;
  strprint(x);
  free(x);
  free(y);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <string@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <string@plt>
  mov    %r12,%rdi
  movl   $0x5,-0x4(%rax)
  mov    %rax,%rbp
  call   <strprint@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int *x = string();
  int *y = string();
  *(y - 1) = 5;
  strprint(x);
  free(x);
  free(y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L52:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L16
  mov    $0xffffffff,%eax
  jmp    L2
L16:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L18
  mov    $0x1,%eax
  jmp    L2
L18:
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  ja     L52
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  char *s, *t;
  int i;
  s = (char *)s1;
  t = (char *)s2;
  for (i = 0; i < n; i++) {
    if (s[i] < t[i])
      return -1;
    if (s[i] > t[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L7
  mov    $0x0,%eax
L12:
  movzbl (%rdi,%rax,1),%r8d
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%r8b
  jl     L0
  jg     L37
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L0:
  mov    $0xffffffff,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  char *s, *t;
  int i;
  s = (char *)s1;
  t = (char *)s2;
  for (i = 0; i < n; i++) {
    if (s[i] < t[i])
      return -1;
    if (s[i] > t[i])
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L33
  xor    %eax,%eax
  jmp    L14
  nopl   (%rax)
L27:
  jg     L18
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L33
L14:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jge    L27
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  char *s, *t;
  int i;
  s = (char *)s1;
  t = (char *)s2;
  for (i = 0; i < n; i++) {
    if (s[i] < t[i])
      return -1;
    if (s[i] > t[i])
      return 1;
  }
  return 0;
}
```