ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f_rotate>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <f_strlen@plt>
  mov    %eax,%r13d
  mov    %r12d,%eax
  cltd
  mov    %r13d,%edi
  idiv   %r13d
  lea    (%rdx,%r13,1),%r14d
  test   %edx,%edx
  cmovns %edx,%r14d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13d,%ebp
  movslq %r14d,%rdi
  mov    %rbx,%rsi
  sub    %r14d,%ebp
  add    %rax,%rdi
  mov    %ebp,%edx
  call   <f_strncpy@plt>
  movslq %ebp,%rsi
  mov    %r12,%rdi
  mov    %r14d,%edx
  add    %rbx,%rsi
  call   <f_strncpy@plt>
  mov    %r12,%rsi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <f_strncpy@plt>
  mov    %r12,%rdi
  mov    %rbx,%r12
  call   <free@plt>
L5:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *f_rotate(char *s, int rot) {
  int n = f_strlen(s);
  int i;
  char *p;
  rot = rot % n;
  if (rot < 0)
    rot = n + rot;
  p = malloc(n);
  if (!p)
    return NULL;
  f_strncpy(&p[rot], &s[0], n - rot);
  f_strncpy(&p[0], &s[n - rot], rot);
  f_strncpy(s, p, n);
  free(p);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<IntToPpch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %rsi,-0x18(%rbp)
  cmp    $0x9,%ebx
  jle    L6
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <IntToPpch>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    %ebx,%edx
  mov    %edx,%ebx
L6:
  mov    %ebx,%eax
  lea    0x30(%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
IntToPpch(n, ppch) register int n;
char **ppch;
{
  if (n >= 10) {
    IntToPpch(n / 10, ppch);
    n %= 10;
  }
  *(*ppch)++ = '0' + n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IntToPpch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  cmp    $0x9,%edi
  jg     L3
L19:
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  add    $0x30,%ebx
  mov    %bl,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  movslq %edi,%r12
  imul   $0x66666667,%r12,%r12
  sar    $0x22,%r12
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <IntToPpch>
  lea    (%r12,%r12,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  jmp    L19
```

assistant: ```c
IntToPpch(n, ppch) register int n;
char **ppch;
{
  if (n >= 10) {
    IntToPpch(n / 10, ppch);
    n %= 10;
  }
  *(*ppch)++ = '0' + n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IntToPpch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x9,%edi
  jg     L39
L8:
  mov    (%rsi),%rax
  add    $0x30,%ebx
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    %bl,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  movslq %edi,%r12
  mov    %edi,%eax
  imul   $0x66666667,%r12,%r13
  sar    $0x1f,%eax
  sar    $0x22,%r13
  sub    %eax,%r13d
  cmp    $0x63,%edi
  jg     L35
L2:
  mov    (%rsi),%rax
  imul   $0x66666667,%r12,%r12
  add    $0x30,%r13d
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  sar    $0x22,%r12
  mov    %r13b,(%rax)
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  lea    (%r12,%r12,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  jmp    L8
  nopl   0x0(%rax)
L35:
  mov    %r13d,%r14d
  mov    $0xcccccccd,%eax
  mov    %r14,%r15
  imul   %rax,%r15
  shr    $0x23,%r15
  cmp    $0x3e7,%edi
  jg     L52
L44:
  mov    (%rsi),%rax
  add    $0x30,%r15d
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    %r15b,(%rax)
  mov    $0xcccccccd,%eax
  imul   %rax,%r14
  shr    $0x23,%r14
  lea    (%r14,%r14,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  jmp    L2
  nopl   0x0(%rax)
L52:
  mov    %r15d,%edx
  mov    %rsi,0x8(%rsp)
  imul   %rax,%rdx
  xor    %eax,%eax
  shr    $0x23,%rdx
  mov    %rdx,%rbp
  mov    %edx,%edi
  call   <IntToPpch>
  lea    0x0(%rbp,%rbp,4),%eax
  mov    0x8(%rsp),%rsi
  add    %eax,%eax
  sub    %eax,%r15d
  jmp    L44
```

assistant: ```c
IntToPpch(n, ppch) register int n;
char **ppch;
{
  if (n >= 10) {
    IntToPpch(n / 10, ppch);
    n %= 10;
  }
  *(*ppch)++ = '0' + n;
}
```
user: What is the c source code of the assembly code below?

```asm
<IntToPpch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x9,%edi
  jg     L30
L31:
  mov    (%rsi),%rax
  add    $0x30,%ebx
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    %bl,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  movslq %edi,%r12
  mov    %edi,%eax
  imul   $0x66666667,%r12,%r13
  sar    $0x1f,%eax
  sar    $0x22,%r13
  sub    %eax,%r13d
  cmp    $0x63,%edi
  jg     L33
L34:
  mov    (%rsi),%rax
  imul   $0x66666667,%r12,%r12
  add    $0x30,%r13d
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  sar    $0x22,%r12
  mov    %r13b,(%rax)
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  lea    (%r12,%r12,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  jmp    L31
  nopl   0x0(%rax)
L33:
  mov    %r13d,%r14d
  mov    $0xcccccccd,%eax
  mov    %r14,%r15
  imul   %rax,%r15
  shr    $0x23,%r15
  cmp    $0x3e7,%edi
  jg     L40
L0:
  mov    (%rsi),%rax
  add    $0x30,%r15d
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    %r15b,(%rax)
  mov    $0xcccccccd,%eax
  imul   %rax,%r14
  shr    $0x23,%r14
  lea    (%r14,%r14,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  jmp    L34
  nopl   0x0(%rax)
L40:
  mov    %r15d,%edx
  mov    %rsi,0x8(%rsp)
  imul   %rax,%rdx
  xor    %eax,%eax
  shr    $0x23,%rdx
  mov    %rdx,%rbp
  mov    %edx,%edi
  call   <IntToPpch>
  lea    0x0(%rbp,%rbp,4),%eax
  mov    0x8(%rsp),%rsi
  add    %eax,%eax
  sub    %eax,%r15d
  jmp    L0
```

assistant: ```c
IntToPpch(n, ppch) register int n;
char **ppch;
{
  if (n >= 10) {
    IntToPpch(n / 10, ppch);
    n %= 10;
  }
  *(*ppch)++ = '0' + n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SleepMs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void SleepMs(int ms) {
  usleep(ms * 1000);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SleepMs>:
  endbr64
  sub    $0x8,%rsp
  imul   $0x3e8,%edi,%edi
  call   <usleep@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SleepMs(int ms) {
  usleep(ms * 1000);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SleepMs>:
  endbr64
  imul   $0x3e8,%edi,%edi
  jmp    1050 <usleep@plt>
```

assistant: ```c
void SleepMs(int ms) {
  usleep(ms * 1000);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SleepMs>:
  endbr64
  imul   $0x3e8,%edi,%edi
  jmp    1050 <usleep@plt>
```

assistant: ```c
void SleepMs(int ms) {
  usleep(ms * 1000);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xb,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: sizeof("0123456789") = [%u]


assistant: ```c
int main(void) {
  printf("sizeof(\"0123456789\") = [%u]\n", (unsigned)sizeof("0123456789"));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: sizeof("0123456789") = [%u]


assistant: ```c
int main(void) {
  printf("sizeof(\"0123456789\") = [%u]\n", (unsigned)sizeof("0123456789"));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: sizeof("0123456789") = [%u]


assistant: ```c
int main(void) {
  printf("sizeof(\"0123456789\") = [%u]\n", (unsigned)sizeof("0123456789"));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: sizeof("0123456789") = [%u]


assistant: ```c
int main(void) {
  printf("sizeof(\"0123456789\") = [%u]\n", (unsigned)sizeof("0123456789"));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<process_is_running>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pidof@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  setne  %al
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  movzbl -0x9(%rbp),%eax
  leave
  ret
```

assistant: ```c
char process_is_running(const char *procname) {
  char resx = 0;
  int *listx = pidof((char *)procname);
  if (listx) {
    resx = listx[0] != -1;
    free(listx);
  }
  return resx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_is_running>:
  endbr64
  push   %rbx
  call   <pidof@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L1
  cmpl   $0xffffffff,(%rax)
  setne  %bl
  mov    %rax,%rdi
  call   <free@plt>
L1:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char process_is_running(const char *procname) {
  char resx = 0;
  int *listx = pidof((char *)procname);
  if (listx) {
    resx = listx[0] != -1;
    free(listx);
  }
  return resx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_is_running>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  call   <pidof@plt>
  test   %rax,%rax
  je     L7
  cmpl   $0xffffffff,(%rax)
  mov    %rax,%rdi
  setne  %r12b
  call   <free@plt>
L7:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char process_is_running(const char *procname) {
  char resx = 0;
  int *listx = pidof((char *)procname);
  if (listx) {
    resx = listx[0] != -1;
    free(listx);
  }
  return resx;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<process_is_running>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  call   <pidof@plt>
  test   %rax,%rax
  je     L4
  cmpl   $0xffffffff,(%rax)
  mov    %rax,%rdi
  setne  %r12b
  call   <free@plt>
L4:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char process_is_running(const char *procname) {
  char resx = 0;
  int *listx = pidof((char *)procname);
  if (listx) {
    resx = listx[0] != -1;
    free(listx);
  }
  return resx;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<st_perm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  movsd  D18(%rip),%xmm0
  jmp    L14
L6:
  mov    $0x6,%edi
  call   <sqrt@plt>
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  test   %rax,%rax
  js     L24
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L39
L24:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L39:
  movsd  D27(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L19
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L69
L19:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L69:
  movsd  D18(%rip),%xmm1
  divsd  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  test   %rax,%rax
  js     L50
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L40
L50:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L40:
  subsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mulsd  -0x10(%rbp),%xmm0
L14:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type: f64
name: extract_symbolic_data
arguments: label: D27
type: f64

tool: D18: 1

tool: D27: 0.5

assistant: ```c
double st_perm(unsigned int n) {
  if (n == 0)
    return 1;
  return sqrt(2 * 3.1415926) * pow(n, n + 0.5) * exp(-(double)n + 1.0 / (12 * n));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<st_perm>:
  endbr64
  movsd  D10(%rip),%xmm0
  test   %edi,%edi
  jne    L4
  ret
L4:
  push   %r15
  push   %r14
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    $0x6,%edi
  call   <sqrt@plt>
  movq   %xmm0,%r14
  mov    %ebx,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm0
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%rsi
  mov    %ebx,%edi
  call   <pow@plt>
  movq   %xmm0,%r15
  lea    (%rbx,%rbx,2),%eax
  shl    $0x2,%eax
  mov    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  D10(%rip),%xmm0
  divsd  %xmm1,%xmm0
  subsd  0x8(%rsp),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  movq   %r15,%xmm3
  mulsd  %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type: f64
name: retrieve_data
arguments: tag: D6
type: f64

tool: D10: 1

tool: D6: 0.5

assistant: ```c
double st_perm(unsigned int n) {
  if (n == 0)
    return 1;
  return sqrt(2 * 3.1415926) * pow(n, n + 0.5) * exp(-(double)n + 1.0 / (12 * n));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<st_perm>:
  endbr64
  movsd  D5(%rip),%xmm1
  test   %edi,%edi
  jne    L6
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L6:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x6,%edi
  sub    $0x20,%rsp
  movsd  %xmm1,0x18(%rsp)
  call   <sqrt@plt>
  mov    %ebx,%eax
  pxor   %xmm2,%xmm2
  mov    %ebx,%edi
  cvtsi2sd %rax,%xmm2
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm4
  addsd  D9(%rip),%xmm4
  movsd  %xmm2,0x10(%rsp)
  cvttsd2si %xmm4,%rsi
  call   <pow@plt>
  lea    (%rbx,%rbx,2),%eax
  pxor   %xmm3,%xmm3
  movsd  0x18(%rsp),%xmm1
  shl    $0x2,%eax
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  cvtsi2sd %rax,%xmm3
  divsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  mulsd  0x8(%rsp),%xmm1
  add    $0x20,%rsp
  pop    %rbx
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: f64
name: disassemble_data
arguments: tag: D9
datatype: f64

tool: D5: 1

tool: D9: 0.5

assistant: ```c
double st_perm(unsigned int n) {
  if (n == 0)
    return 1;
  return sqrt(2 * 3.1415926) * pow(n, n + 0.5) * exp(-(double)n + 1.0 / (12 * n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<st_perm>:
  endbr64
  movsd  D0(%rip),%xmm1
  test   %edi,%edi
  jne    L0
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L0:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x6,%edi
  sub    $0x20,%rsp
  movsd  %xmm1,0x18(%rsp)
  call   <sqrt@plt>
  mov    %ebx,%eax
  pxor   %xmm2,%xmm2
  mov    %ebx,%edi
  cvtsi2sd %rax,%xmm2
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm4
  addsd  D1(%rip),%xmm4
  movsd  %xmm2,0x10(%rsp)
  cvttsd2si %xmm4,%rsi
  call   <pow@plt>
  lea    (%rbx,%rbx,2),%eax
  pxor   %xmm3,%xmm3
  movsd  0x18(%rsp),%xmm1
  shl    $0x2,%eax
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  cvtsi2sd %rax,%xmm3
  divsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  mulsd  0x8(%rsp),%xmm1
  add    $0x20,%rsp
  pop    %rbx
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: f64
name: retrieve_data
arguments: data_tag: D1
type: f64

tool: D0: 1

tool: D1: 0.5

assistant: ```c
double st_perm(unsigned int n) {
  if (n == 0)
    return 1;
  return sqrt(2 * 3.1415926) * pow(n, n + 0.5) * exp(-(double)n + 1.0 / (12 * n));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hello>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D0
datatype: string

tool: D10: Hello world!


tool: D0: sadlf;jsdfl;as

assistant: ```c
void hello(void) {
  printf("Hello world!\n");
  printf("sadlf;jsdfl;as");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D19
datatype: string

tool: D16: Hello world!


tool: D19: sadlf;jsdfl;as

assistant: ```c
void hello(void) {
  printf("Hello world!\n");
  printf("sadlf;jsdfl;as");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D8: Hello world!


tool: D2: sadlf;jsdfl;as

assistant: ```c
void hello(void) {
  printf("Hello world!\n");
  printf("sadlf;jsdfl;as");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D17
type: string

tool: D10: Hello world!


tool: D17: sadlf;jsdfl;as

assistant: ```c
void hello(void) {
  printf("Hello world!\n");
  printf("sadlf;jsdfl;as");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <run_shell@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  run_shell();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <run_shell@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  run_shell();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run_shell@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  run_shell();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run_shell@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  run_shell();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skipSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L9
L11:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isWhite@plt>
  test   %rax,%rax
  jne    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void skipSpace(char **s) {
  for (; isWhite(**s); (*s)++)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L17
L9:
  addq   $0x1,(%rbx)
L17:
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <isWhite@plt>
  test   %rax,%rax
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
void skipSpace(char **s) {
  for (; isWhite(**s); (*s)++)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  jmp    L10
  nopl   (%rax)
L8:
  mov    (%rbx),%rax
  add    $0x1,%rax
  mov    %rax,(%rbx)
L10:
  movsbl (%rax),%edi
  call   <isWhite@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void skipSpace(char **s) {
  for (; isWhite(**s); (*s)++)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skipSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  jmp    L2
  nopl   (%rax)
L18:
  mov    (%rbx),%rax
  add    $0x1,%rax
  mov    %rax,(%rbx)
L2:
  movsbl (%rax),%edi
  call   <isWhite@plt>
  test   %rax,%rax
  jne    L18
  pop    %rbx
  ret
```

assistant: ```c
void skipSpace(char **s) {
  for (; isWhite(**s); (*s)++)
    ;
}
```