ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<fstrncpy>:
  endbr64
  test   %edx,%edx
  jle    L29
  mov    %edx,%edx
  mov    $0x0,%eax
L28:
  mov    %eax,%r8d
  movzbl (%rsi,%rax,1),%ecx
  cmp    $0x1,%cl
  jbe    L11
  mov    %cl,(%rdi,%rax,1)
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L28
L11:
  mov    %r8d,%eax
  ret
L29:
  mov    $0x0,%r8d
  jmp    L11
```

assistant: ```c
int fstrncpy(char *dest, const char *src, int n) {
  int i;
  for (i = 0; i < n && src[i] != 0x00 && src[i] != 0x01; i++)
    dest[i] = src[i];
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fstrncpy>:
  endbr64
  test   %edx,%edx
  jle    L40
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L12
  nop
L20:
  mov    %cl,(%rdi,%rax,1)
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L27
L12:
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%r8d
  cmp    $0x1,%cl
  ja     L20
L27:
  mov    %r8d,%eax
  ret
L40:
  xor    %r8d,%r8d
  jmp    L27
```

assistant: ```c
int fstrncpy(char *dest, const char *src, int n) {
  int i;
  for (i = 0; i < n && src[i] != 0x00 && src[i] != 0x01; i++)
    dest[i] = src[i];
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fstrncpy>:
  endbr64
  test   %edx,%edx
  jle    L35
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L3
  nop
L29:
  mov    %cl,(%rdi,%rax,1)
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L8
L3:
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%r8d
  cmp    $0x1,%cl
  ja     L29
L8:
  mov    %r8d,%eax
  ret
L35:
  xor    %r8d,%r8d
  jmp    L8
```

assistant: ```c
int fstrncpy(char *dest, const char *src, int n) {
  int i;
  for (i = 0; i < n && src[i] != 0x00 && src[i] != 0x01; i++)
    dest[i] = src[i];
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<drawDate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x2,%esi
  mov    $0x24,%edi
  call   <gotoxy@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x24,%edi
  call   <gotoxy@plt>
  mov    -0x18(%rbp),%rdx
  lea    -0xe(%rbp),%rax
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0xe(%rbp),%rax
  mov    $0x5,%ecx
  mov    $0x24,%edx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <drawStr@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D12: Today's date

tool: D3: %a%d

assistant: ```c
void drawDate(struct tm *timeinfo) {
  char buf[6];
  gotoxy(36, 2);
  printf("Today's date");
  gotoxy(36, 5);
  strftime(buf, 6, "%a%d", timeinfo);
  drawStr(buf, 6, 36, 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawDate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%esi
  mov    $0x24,%edi
  call   <gotoxy@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x24,%edi
  call   <gotoxy@plt>
  lea    0x2(%rsp),%rbp
  mov    %rbx,%rcx
  lea    D4(%rip),%rdx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    $0x5,%ecx
  mov    $0x24,%edx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <drawStr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D1: Today's date

tool: D4: %a%d

assistant: ```c
void drawDate(struct tm *timeinfo) {
  char buf[6];
  gotoxy(36, 2);
  printf("Today's date");
  gotoxy(36, 5);
  strftime(buf, 6, "%a%d", timeinfo);
  drawStr(buf, 6, 36, 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawDate>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  mov    %rdi,%r12
  mov    $0x24,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  call   <gotoxy@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x24,%edi
  call   <gotoxy@plt>
  mov    %r12,%rcx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  lea    D8(%rip),%rdx
  call   <strftime@plt>
  mov    $0x5,%ecx
  mov    $0x24,%edx
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <drawStr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D8
type: string

tool: D16: Today's date

tool: D8: %a%d

assistant: ```c
void drawDate(struct tm *timeinfo) {
  char buf[6];
  gotoxy(36, 2);
  printf("Today's date");
  gotoxy(36, 5);
  strftime(buf, 6, "%a%d", timeinfo);
  drawStr(buf, 6, 36, 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawDate>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  mov    %rdi,%r12
  mov    $0x24,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  call   <gotoxy@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x24,%edi
  call   <gotoxy@plt>
  mov    %r12,%rcx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  lea    D2(%rip),%rdx
  call   <strftime@plt>
  mov    $0x5,%ecx
  mov    $0x24,%edx
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <drawStr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D1: Today's date

tool: D2: %a%d

assistant: ```c
void drawDate(struct tm *timeinfo) {
  char buf[6];
  gotoxy(36, 2);
  printf("Today's date");
  gotoxy(36, 5);
  strftime(buf, 6, "%a%d", timeinfo);
  drawStr(buf, 6, 36, 5);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<normalize_vn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <len_squared_vn@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L23
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L17
L23:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L39
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L17
L39:
  movsd  D9(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <imul_vn_fl@plt>
L17:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: f64

tool: D9: 1

assistant: ```c
double normalize_vn(double v0[], const uint dims) {
  double d = len_squared_vn(v0, dims);
  if (d != 0.0 && ((d = sqrt(d)) != 0.0)) {
    imul_vn_fl(v0, 1.0 / d, dims);
  }
  return d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<normalize_vn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <len_squared_vn@plt>
  movq   %xmm0,%rbx
  ucomisd D22(%rip),%xmm0
  jp     L35
  jne    L35
L59:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm4
  ucomisd %xmm4,%xmm0
  ja     L47
  movq   %rbx,%xmm3
  sqrtsd %xmm3,%xmm3
  movq   %xmm3,%rbx
L66:
  movq   %rbx,%xmm5
  ucomisd D22(%rip),%xmm5
  jp     L64
  je     L59
L64:
  movsd  D8(%rip),%xmm0
  movq   %rbx,%xmm7
  divsd  %xmm7,%xmm0
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <imul_vn_fl@plt>
  jmp    L59
L47:
  movq   %rbx,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rbx
  jmp    L66
```

tool_calls: name: parse_data
arguments: data_label: D22
type_guessed: f64
name: parse_data
arguments: data_label: D8
type_guessed: f64

tool: D22: 0

tool: D8: 1

assistant: ```c
double normalize_vn(double v0[], const uint dims) {
  double d = len_squared_vn(v0, dims);
  if (d != 0.0 && ((d = sqrt(d)) != 0.0)) {
    imul_vn_fl(v0, 1.0 / d, dims);
  }
  return d;
}
```
user: What is the c source code of the assembly code below:

```asm
<normalize_vn>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  call   <len_squared_vn@plt>
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  movapd %xmm0,%xmm1
  jp     L52
  jne    L52
L59:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  ucomisd %xmm1,%xmm2
  ja     L14
  sqrtsd %xmm1,%xmm1
L8:
  ucomisd %xmm2,%xmm1
  jp     L24
  je     L59
L24:
  movsd  D0(%rip),%xmm0
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movsd  %xmm1,0x8(%rsp)
  divsd  %xmm1,%xmm0
  call   <imul_vn_fl@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  movapd %xmm1,%xmm0
  ret
L14:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: f64

tool: D0: 1

assistant: ```c
double normalize_vn(double v0[], const uint dims) {
  double d = len_squared_vn(v0, dims);
  if (d != 0.0 && ((d = sqrt(d)) != 0.0)) {
    imul_vn_fl(v0, 1.0 / d, dims);
  }
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<normalize_vn>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  call   <len_squared_vn@plt>
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  movapd %xmm0,%xmm1
  jp     L44
  jne    L44
L6:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  ucomisd %xmm1,%xmm2
  ja     L51
  sqrtsd %xmm1,%xmm1
L47:
  ucomisd %xmm2,%xmm1
  jp     L18
  je     L6
L18:
  movsd  D2(%rip),%xmm0
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movsd  %xmm1,0x8(%rsp)
  divsd  %xmm1,%xmm0
  call   <imul_vn_fl@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  movapd %xmm1,%xmm0
  ret
L51:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  jmp    L47
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: f64

tool: D2: 1

assistant: ```c
double normalize_vn(double v0[], const uint dims) {
  double d = len_squared_vn(v0, dims);
  if (d != 0.0 && ((d = sqrt(d)) != 0.0)) {
    imul_vn_fl(v0, 1.0 / d, dims);
  }
  return d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<time_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rsi,%rax
  mov    %rdi,%r8
  mov    %r8,%rsi
  mov    %r9,%rdi
  mov    %rax,%rdi
  mov    %rsi,-0x20(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rax,%rdx
  jle    L16
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x3b9aca00,%rax
  mov    -0x20(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L16:
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
struct timespec time_diff(struct timespec start, struct timespec end) {
  struct timespec diff;
  if (start.tv_nsec > end.tv_nsec) {
    diff.tv_sec = end.tv_sec - start.tv_sec - 1;
    diff.tv_nsec = 1000000000 + end.tv_nsec - start.tv_nsec;
  } else {
    diff.tv_sec = end.tv_sec - start.tv_sec;
    diff.tv_nsec = end.tv_nsec - start.tv_nsec;
  }
  return diff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<time_diff>:
  endbr64
  mov    %rdx,%rax
  mov    %rcx,%rdx
  cmp    %rax,%rdi
  jle    L8
  sub    %rsi,%rdx
  sub    $0x1,%rdx
  add    $0x3b9aca00,%rax
  sub    %rdi,%rax
  ret
L8:
  sub    %rsi,%rdx
  sub    %rdi,%rax
  ret
```

assistant: ```c
struct timespec time_diff(struct timespec start, struct timespec end) {
  struct timespec diff;
  if (start.tv_nsec > end.tv_nsec) {
    diff.tv_sec = end.tv_sec - start.tv_sec - 1;
    diff.tv_nsec = 1000000000 + end.tv_nsec - start.tv_nsec;
  } else {
    diff.tv_sec = end.tv_sec - start.tv_sec;
    diff.tv_nsec = end.tv_nsec - start.tv_nsec;
  }
  return diff;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<time_diff>:
  endbr64
  mov    %rsi,%r8
  mov    %rdx,%rsi
  sub    %r8,%rcx
  mov    %rsi,%rax
  mov    %rcx,%rdx
  sub    %rdi,%rax
  cmp    %rsi,%rdi
  jle    L8
  lea    0x3b9aca00(%rsi),%rax
  sub    $0x1,%rdx
  sub    %rdi,%rax
L8:
  ret
```

assistant: ```c
struct timespec time_diff(struct timespec start, struct timespec end) {
  struct timespec diff;
  if (start.tv_nsec > end.tv_nsec) {
    diff.tv_sec = end.tv_sec - start.tv_sec - 1;
    diff.tv_nsec = 1000000000 + end.tv_nsec - start.tv_nsec;
  } else {
    diff.tv_sec = end.tv_sec - start.tv_sec;
    diff.tv_nsec = end.tv_nsec - start.tv_nsec;
  }
  return diff;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<time_diff>:
  endbr64
  mov    %rsi,%r8
  mov    %rdx,%rsi
  sub    %r8,%rcx
  mov    %rsi,%rax
  mov    %rcx,%rdx
  sub    %rdi,%rax
  cmp    %rsi,%rdi
  jle    L8
  lea    0x3b9aca00(%rsi),%rax
  sub    $0x1,%rdx
  sub    %rdi,%rax
L8:
  ret
```

assistant: ```c
struct timespec time_diff(struct timespec start, struct timespec end) {
  struct timespec diff;
  if (start.tv_nsec > end.tv_nsec) {
    diff.tv_sec = end.tv_sec - start.tv_sec - 1;
    diff.tv_nsec = 1000000000 + end.tv_nsec - start.tv_nsec;
  } else {
    diff.tv_sec = end.tv_sec - start.tv_sec;
    diff.tv_nsec = end.tv_nsec - start.tv_nsec;
  }
  return diff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usmatrix_map_2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L0:
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L4
L16:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L16
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: allocation failure 1 in usmatrix_map()

assistant: ```c
ushort **usmatrix_map_2D(long nrl, long nrh, long ncl, long nch, void **data_2D) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  ushort **m;
  m = (ushort **)malloc((size_t)((nrow + 0) * sizeof(ushort *)));
  if (!m)
    nrerror("allocation failure 1 in usmatrix_map()");
  m += 0;
  m -= nrl;
  m[nrl] = (ushort *)data_2D[0];
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usmatrix_map_2D>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %r8,%r15
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x8(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
L2:
  lea    0x0(,%r14,8),%rax
  mov    %rbx,%rdi
  sub    %rax,%rdi
  shl    $0x2,%r12
  mov    (%r15),%rax
  sub    %r12,%rax
  mov    %rax,(%rbx)
  cmp    %r14,%r13
  jle    L33
  lea    0x0(,%rbp,4),%rcx
  mov    %rbx,%rax
  lea    (%rdi,%r13,8),%rsi
L18:
  mov    %rcx,%rdx
  add    (%rax),%rdx
  mov    %rdx,0x8(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L18
L33:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  lea    D9(%rip),%rdi
  call   <nrerror@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: allocation failure 1 in usmatrix_map()

assistant: ```c
ushort **usmatrix_map_2D(long nrl, long nrh, long ncl, long nch, void **data_2D) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  ushort **m;
  m = (ushort **)malloc((size_t)((nrow + 0) * sizeof(ushort *)));
  if (!m)
    nrerror("allocation failure 1 in usmatrix_map()");
  m += 0;
  m -= nrl;
  m[nrl] = (ushort *)data_2D[0];
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usmatrix_map_2D>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  mov    %rsi,%r15
  push   %r14
  sub    %rdi,%rax
  mov    %rdi,%r14
  push   %r13
  lea    0x8(,%rax,8),%rdi
  mov    %r8,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L21
L38:
  lea    0x0(,%r14,8),%rax
  mov    %rbx,%r8
  shl    $0x2,%r12
  sub    %rax,%r8
  mov    0x0(%r13),%rax
  sub    %r12,%rax
  mov    %rax,(%rbx)
  cmp    %r14,%r15
  jle    L35
  lea    0x0(,%rbp,4),%rcx
  mov    %rbx,%rax
  lea    (%r8,%r15,8),%rsi
L0:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L0
L35:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: allocation failure 1 in usmatrix_map()

assistant: ```c
ushort **usmatrix_map_2D(long nrl, long nrh, long ncl, long nch, void **data_2D) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  ushort **m;
  m = (ushort **)malloc((size_t)((nrow + 0) * sizeof(ushort *)));
  if (!m)
    nrerror("allocation failure 1 in usmatrix_map()");
  m += 0;
  m -= nrl;
  m[nrl] = (ushort *)data_2D[0];
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usmatrix_map_2D>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  mov    %rdi,%r15
  push   %r14
  sub    %rdi,%rax
  mov    %r8,%r14
  push   %r13
  lea    0x8(,%rax,8),%rdi
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L15:
  mov    (%r14),%rdx
  shl    $0x2,%r12
  lea    0x0(,%r15,8),%rax
  mov    %rbx,%r8
  sub    %rax,%r8
  sub    %r12,%rdx
  mov    %rdx,(%rbx)
  cmp    %r15,%r13
  jle    L20
  lea    0x0(,%rbp,4),%rcx
  lea    0x8(%rbx),%rax
  lea    0x8(%r8,%r13,8),%rsi
  nopl   0x0(%rax)
L4:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L4
L20:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D8(%rip),%rdi
  call   <nrerror@plt>
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: allocation failure 1 in usmatrix_map()

assistant: ```c
ushort **usmatrix_map_2D(long nrl, long nrh, long ncl, long nch, void **data_2D) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  ushort **m;
  m = (ushort **)malloc((size_t)((nrow + 0) * sizeof(ushort *)));
  if (!m)
    nrerror("allocation failure 1 in usmatrix_map()");
  m += 0;
  m -= nrl;
  m[nrl] = (ushort *)data_2D[0];
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L36
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L36
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L36:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L52
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L52
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L52:
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L55
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L55
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L55:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D27
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D27: Enter three numbers: 

tool: D22: %lf %lf %lf

tool: D8: %.2f is the largest number.

assistant: ```c
int main() {
  double n1, n2, n3;
  printf("Enter three numbers: ");
  scanf("%lf %lf %lf", &n1, &n2, &n3);
  if (n1 >= n2 && n1 >= n3)
    printf("%.2f is the largest number.", n1);
  if (n2 >= n1 && n2 >= n3)
    printf("%.2f is the largest number.", n2);
  if (n3 >= n1 && n3 >= n2)
    printf("%.2f is the largest number.", n3);
  return 0;
}
```