ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<decode_sample_filter>:
  endbr64
  and    $0x7,%edi
  cmp    $0x6,%edi
  ja     L4
  lea    D47(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
  lea    D10(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D11(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D37(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D14(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D51(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D18(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D87(%rip),%rax
  ret
L4:
  lea    D21(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D37
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string
name: parse_data
arguments: data_tag: D51
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D87
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string

tool: D10: linear

tool: D11: nearest

tool: D37: anisotropic

tool: D14: 4x4_1

tool: D51: 6x5_mono

tool: D18: 4x4_2

tool: D87: 4x4_flat

tool: 

assistant: ```c
const char *decode_sample_filter(uint32_t mode) {
  switch (mode & 0x7) {
  case 0:
    return "nearest";
  case 1:
    return "linear";
  case 2:
    return "anisotropic";
  case 3:
    return "4x4_1";
  case 4:
    return "4x4_2";
  case 5:
    return "4x4_flat";
  case 6:
    return "6x5_mono";
  }
  return "";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<decode_sample_filter>:
  endbr64
  and    $0x7,%edi
  cmp    $0x6,%edi
  ja     L7
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
  lea    D19(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D84(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D67(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D26(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D73(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D35(%rip),%rax
  ret
L7:
  lea    D30(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D84
type_infered: string
name: read_data
arguments: label: D67
type_infered: string
name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D73
type_infered: string
name: read_data
arguments: label: D35
type_infered: string
name: read_data
arguments: label: D30
type_infered: string

tool: D19: linear

tool: D28: nearest

tool: D84: anisotropic

tool: D67: 4x4_1

tool: D26: 6x5_mono

tool: D73: 4x4_2

tool: D35: 4x4_flat

tool: 

assistant: ```c
const char *decode_sample_filter(uint32_t mode) {
  switch (mode & 0x7) {
  case 0:
    return "nearest";
  case 1:
    return "linear";
  case 2:
    return "anisotropic";
  case 3:
    return "4x4_1";
  case 4:
    return "4x4_2";
  case 5:
    return "4x4_flat";
  case 6:
    return "6x5_mono";
  }
  return "";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<makeraw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D60(%rip),%rax
  mov    (%rax),%ecx
  mov    D75(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D80(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0xc(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    D91(%rip),%rax
  mov    (%rax),%ecx
  mov    D139(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D85(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D109(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    D176(%rip),%rax
  mov    (%rax),%ecx
  mov    D53(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x8(%rax)
  cmpl   $0x7,-0xc(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    D101(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x8(%rax)
L1:
  cmpl   $0x8,-0xc(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x8(%rax)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void makeraw(struct termios *termios_p, int bits) {
  termios_p->c_iflag &= ~(IGNBRK | BRKINT | PARMRK | ISTRIP | INLCR | IGNCR | ICRNL | IXON);
  termios_p->c_oflag &= ~OPOST;
  termios_p->c_lflag &= ~(ECHO | ECHONL | ICANON | ISIG | IEXTEN);
  termios_p->c_cflag &= ~(CSIZE | PARENB);
  if (bits == 7)
    termios_p->c_cflag |= CS7;
  if (bits == 8)
    termios_p->c_cflag |= CS8;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<makeraw>:
  endbr64
  mov    %esi,%ecx
  mov    D125(%rip),%rax
  mov    (%rax),%eax
  mov    D60(%rip),%rsi
  or     (%rsi),%eax
  mov    D99(%rip),%rsi
  or     (%rsi),%eax
  mov    D142(%rip),%rsi
  or     (%rsi),%eax
  mov    D63(%rip),%rsi
  or     (%rsi),%eax
  mov    D62(%rip),%rsi
  or     (%rsi),%eax
  mov    D11(%rip),%rsi
  or     (%rsi),%eax
  mov    D72(%rip),%rsi
  or     (%rsi),%eax
  not    %eax
  and    %eax,(%rdi)
  mov    D58(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,0xc(%rdi)
  mov    D57(%rip),%rax
  mov    (%rax),%eax
  mov    D8(%rip),%rsi
  or     (%rsi),%eax
  mov    D86(%rip),%rsi
  or     (%rsi),%eax
  mov    D6(%rip),%rsi
  or     (%rsi),%eax
  mov    D164(%rip),%rsi
  or     (%rsi),%eax
  not    %eax
  and    %eax,0x4(%rdi)
  mov    D107(%rip),%rax
  mov    (%rax),%eax
  mov    D177(%rip),%rsi
  or     (%rsi),%eax
  not    %eax
  and    0x8(%rdi),%eax
  mov    %eax,0x8(%rdi)
  cmp    $0x7,%ecx
  je     L2
  cmp    $0x8,%ecx
  jne    L6
  mov    D103(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,0x8(%rdi)
L6:
  ret
L2:
  mov    D158(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void makeraw(struct termios *termios_p, int bits) {
  termios_p->c_iflag &= ~(IGNBRK | BRKINT | PARMRK | ISTRIP | INLCR | IGNCR | ICRNL | IXON);
  termios_p->c_oflag &= ~OPOST;
  termios_p->c_lflag &= ~(ECHO | ECHONL | ICANON | ISIG | IEXTEN);
  termios_p->c_cflag &= ~(CSIZE | PARENB);
  if (bits == 7)
    termios_p->c_cflag |= CS7;
  if (bits == 8)
    termios_p->c_cflag |= CS8;
}
```
user: Translate the below assembly code into C programming language:

```asm
<makeraw>:
  endbr64
  mov    D109(%rip),%rax
  mov    %esi,%ecx
  mov    D98(%rip),%rsi
  mov    (%rax),%eax
  or     (%rsi),%eax
  mov    D99(%rip),%rsi
  or     (%rsi),%eax
  mov    D92(%rip),%rsi
  or     (%rsi),%eax
  mov    D88(%rip),%rsi
  or     (%rsi),%eax
  mov    D14(%rip),%rsi
  or     (%rsi),%eax
  mov    D42(%rip),%rsi
  or     (%rsi),%eax
  mov    D12(%rip),%rsi
  or     (%rsi),%eax
  mov    D20(%rip),%rsi
  not    %eax
  and    %eax,(%rdi)
  mov    D153(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,0xc(%rdi)
  mov    D175(%rip),%rax
  mov    (%rax),%eax
  or     (%rsi),%eax
  mov    D71(%rip),%rsi
  or     (%rsi),%eax
  mov    D129(%rip),%rsi
  or     (%rsi),%eax
  mov    D73(%rip),%rsi
  or     (%rsi),%eax
  not    %eax
  and    %eax,0x4(%rdi)
  mov    D130(%rip),%rax
  mov    D26(%rip),%rsi
  mov    (%rax),%eax
  or     (%rsi),%eax
  not    %eax
  and    0x8(%rdi),%eax
  mov    %eax,0x8(%rdi)
  cmp    $0x7,%ecx
  je     L18
  cmp    $0x8,%ecx
  jne    L1
  mov    D127(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,0x8(%rdi)
L1:
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    D142(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void makeraw(struct termios *termios_p, int bits) {
  termios_p->c_iflag &= ~(IGNBRK | BRKINT | PARMRK | ISTRIP | INLCR | IGNCR | ICRNL | IXON);
  termios_p->c_oflag &= ~OPOST;
  termios_p->c_lflag &= ~(ECHO | ECHONL | ICANON | ISIG | IEXTEN);
  termios_p->c_cflag &= ~(CSIZE | PARENB);
  if (bits == 7)
    termios_p->c_cflag |= CS7;
  if (bits == 8)
    termios_p->c_cflag |= CS8;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makeraw>:
  endbr64
  mov    D154(%rip),%rax
  mov    %esi,%ecx
  mov    D3(%rip),%rsi
  mov    %rdi,%rdx
  mov    D74(%rip),%rdi
  mov    (%rax),%eax
  or     (%rsi),%eax
  mov    D62(%rip),%rsi
  or     (%rsi),%eax
  mov    D69(%rip),%rsi
  or     (%rsi),%eax
  mov    D63(%rip),%rsi
  or     (%rsi),%eax
  mov    D147(%rip),%rsi
  or     (%rsi),%eax
  mov    D158(%rip),%rsi
  or     (%rsi),%eax
  mov    D129(%rip),%rsi
  or     (%rsi),%eax
  mov    D169(%rip),%rsi
  movd   %eax,%xmm0
  mov    D108(%rip),%rax
  mov    (%rax),%eax
  or     (%rsi),%eax
  mov    D66(%rip),%rsi
  or     (%rsi),%eax
  mov    D16(%rip),%rsi
  or     (%rsi),%eax
  mov    D17(%rip),%rsi
  or     (%rsi),%eax
  mov    D9(%rip),%rsi
  movd   %eax,%xmm3
  mov    (%rsi),%esi
  or     (%rdi),%esi
  punpckldq %xmm3,%xmm0
  mov    D58(%rip),%rdi
  movd   %esi,%xmm1
  mov    (%rdi),%edi
  movdqu (%rdx),%xmm4
  movd   %edi,%xmm2
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  pandn  %xmm4,%xmm0
  movdqa %xmm0,%xmm1
  movups %xmm0,(%rdx)
  punpckhdq %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    $0x7,%ecx
  je     L13
  cmp    $0x8,%ecx
  jne    L6
  mov    D85(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,0x8(%rdx)
L6:
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    D118(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,0x8(%rdx)
  ret
```

assistant: ```c
void makeraw(struct termios *termios_p, int bits) {
  termios_p->c_iflag &= ~(IGNBRK | BRKINT | PARMRK | ISTRIP | INLCR | IGNCR | ICRNL | IXON);
  termios_p->c_oflag &= ~OPOST;
  termios_p->c_lflag &= ~(ECHO | ECHONL | ICANON | ISIG | IEXTEN);
  termios_p->c_cflag &= ~(CSIZE | PARENB);
  if (bits == 7)
    termios_p->c_cflag |= CS7;
  if (bits == 8)
    termios_p->c_cflag |= CS8;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_common_substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L29:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L28
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L28:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_common_substr(const char *str1, const char *str2) {
  int len;
  for (len = 0; str1[len] == str2[len] && str1[len] != '\0'; len++)
    ;
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_common_substr>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L3
  test   %al,%al
  je     L3
  mov    $0x1,%eax
L0:
  mov    %eax,%r8d
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  sete   %cl
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L0
L24:
  mov    %r8d,%eax
  ret
L3:
  mov    $0x0,%r8d
  jmp    L24
```

assistant: ```c
int find_common_substr(const char *str1, const char *str2) {
  int len;
  for (len = 0; str1[len] == str2[len] && str1[len] != '\0'; len++)
    ;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_common_substr>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L25
  test   %al,%al
  je     L25
  mov    $0x1,%eax
  nopl   0x0(%rax)
L17:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  mov    %eax,%r8d
  sete   %cl
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L17
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_common_substr(const char *str1, const char *str2) {
  int len;
  for (len = 0; str1[len] == str2[len] && str1[len] != '\0'; len++)
    ;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_common_substr>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L12
  test   %al,%al
  je     L12
  mov    $0x1,%eax
  nopl   0x0(%rax)
L8:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  mov    %eax,%r8d
  sete   %cl
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L8
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_common_substr(const char *str1, const char *str2) {
  int len;
  for (len = 0; str1[len] == str2[len] && str1[len] != '\0'; len++)
    ;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x3f,%rax
  sar    $0x3f,%rax
  xor    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long decode(long x, long y, long z) {
  long tmp = y - z;
  return (tmp * x) ^ (tmp << 63 >> 63);
}
```
user: What is the c source code of the assembly code below?

```asm
<decode>:
  endbr64
  sub    %rdx,%rsi
  mov    %rsi,%rax
  shl    $0x3f,%rax
  sar    $0x3f,%rax
  imul   %rdi,%rsi
  xor    %rsi,%rax
  ret
```

assistant: ```c
long decode(long x, long y, long z) {
  long tmp = y - z;
  return (tmp * x) ^ (tmp << 63 >> 63);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode>:
  endbr64
  sub    %rdx,%rsi
  mov    %rsi,%rax
  imul   %rdi,%rsi
  shl    $0x3f,%rax
  sar    $0x3f,%rax
  xor    %rsi,%rax
  ret
```

assistant: ```c
long decode(long x, long y, long z) {
  long tmp = y - z;
  return (tmp * x) ^ (tmp << 63 >> 63);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<decode>:
  endbr64
  sub    %rdx,%rsi
  mov    %rsi,%rax
  imul   %rdi,%rsi
  shl    $0x3f,%rax
  sar    $0x3f,%rax
  xor    %rsi,%rax
  ret
```

assistant: ```c
long decode(long x, long y, long z) {
  long tmp = y - z;
  return (tmp * x) ^ (tmp << 63 >> 63);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
  jmp    L19
L16:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  add    %edx,%ebx
L19:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L16
  movslq %ebx,%rax
  imul   $0x5254e78f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x6,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0xc7,%eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int hash(name)
register char *name;
{
  register int h = 0;
  while (*name)
    h += *name++;
  return (h % 199);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  mov    $0x0,%edx
L21:
  add    $0x1,%rdi
  movsbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L21
L1:
  movslq %edx,%rax
  imul   $0x5254e78f,%rax,%rax
  sar    $0x26,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xc7,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L1
```

assistant: ```c
int hash(name)
register char *name;
{
  register int h = 0;
  while (*name)
    h += *name++;
  return (h % 199);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L17
  xor    %edx,%edx
  nopl   (%rax)
L11:
  add    $0x1,%rdi
  add    %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L11
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x5254e78f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0xc7,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(name)
register char *name;
{
  register int h = 0;
  while (*name)
    h += *name++;
  return (h % 199);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L13
  xor    %edx,%edx
  nopl   (%rax)
L12:
  add    $0x1,%rdi
  add    %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L12
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x5254e78f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0xc7,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(name)
register char *name;
{
  register int h = 0;
  while (*name)
    h += *name++;
  return (h % 199);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(void) {
  double x = 0.0;
  asm volatile("" : "+gw"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  mov    D3(%rip),%rax
  movq   %rax,%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: f64

tool: D3: 0

assistant: ```c
int foo(void) {
  double x = 0.0;
  asm volatile("" : "+gw"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: f64

tool: D9: 0

assistant: ```c
int foo(void) {
  double x = 0.0;
  asm volatile("" : "+gw"(x));
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  mov    D0(%rip),%rax
  movq   %rax,%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: f64

tool: D0: 0

assistant: ```c
int foo(void) {
  double x = 0.0;
  asm volatile("" : "+gw"(x));
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L5:
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    $0x3a,%edi
  call   <putchar@plt>
L8:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %02X

assistant: ```c
void print_hex(const unsigned char *data, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (i > 0) {
      printf(":");
    }
    printf("%02X", data[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
  test   %rsi,%rsi
  je     L33
L4:
  movzbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L33
  test   %rbx,%rbx
  je     L4
  mov    $0x3a,%edi
  call   <putchar@plt>
  jmp    L4
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: %02X

assistant: ```c
void print_hex(const unsigned char *data, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (i > 0) {
      printf(":");
    }
    printf("%02X", data[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_hex>:
  endbr64
  test   %rsi,%rsi
  je     L7
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L23
  nopl   0x0(%rax)
L4:
  mov    $0x3a,%edi
  call   <putchar@plt>
L23:
  movzbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3: %02X

assistant: ```c
void print_hex(const unsigned char *data, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (i > 0) {
      printf(":");
    }
    printf("%02X", data[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_hex>:
  endbr64
  test   %rsi,%rsi
  je     L19
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L24
  nopl   0x0(%rax)
L1:
  mov    $0x3a,%edi
  call   <putchar@plt>
L24:
  movzbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L19:
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %02X

assistant: ```c
void print_hex(const unsigned char *data, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (i > 0) {
      printf(":");
    }
    printf("%02X", data[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xfree_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L1
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <panic@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: xfree: NULL pointer given as argument


assistant: ```c
__attribute__((visibility("hidden"))) void xfree_func(void *ptr) {
  if (__builtin_expect(!!(ptr == NULL), 0))
    panic("xfree: NULL pointer given as argument\n");
  free(ptr);
}
```