ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<doHelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D65
type_guessed: string
name: extract_symbolic_data
arguments: label: D51
type_guessed: string
name: extract_symbolic_data
arguments: label: D42
type_guessed: string
name: extract_symbolic_data
arguments: label: D41
type_guessed: string
name: extract_symbolic_data
arguments: label: D69
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D2: 
Commands available:

tool: D65: 
Morse <text>         English to Morse

tool: D51: 
English <morse>      Morse to English

tool: D42: 
Quit or Exit         Exit Program

tool: D41: 
Help or Info         Display this text

tool: D69: 

Commands are case-insensitive,


tool: D1: eg., Morse and morse are the same

assistant: ```c
int doHelp(char *s) {
  (void)(&s);
  printf("\nCommands available:");
  printf("\nMorse <text>         English to Morse");
  printf("\nEnglish <morse>      Morse to English");
  printf("\nQuit or Exit         Exit Program");
  printf("\nHelp or Info         Display this text");
  printf("\n\nCommands are case-insensitive,\n");
  printf("eg., Morse and morse are the same");
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doHelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D65
datatype: string
name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D43
datatype: string
name: parse_data
arguments: label: D61
datatype: string
name: parse_data
arguments: label: D28
datatype: string

tool: D12: 
Commands available:

tool: D18: 
Morse <text>         English to Morse

tool: D65: 
English <morse>      Morse to English

tool: D15: 
Quit or Exit         Exit Program

tool: D43: 
Help or Info         Display this text

tool: D61: 

Commands are case-insensitive,


tool: D28: eg., Morse and morse are the same

assistant: ```c
int doHelp(char *s) {
  (void)(&s);
  printf("\nCommands available:");
  printf("\nMorse <text>         English to Morse");
  printf("\nEnglish <morse>      Morse to English");
  printf("\nQuit or Exit         Exit Program");
  printf("\nHelp or Info         Display this text");
  printf("\n\nCommands are case-insensitive,\n");
  printf("eg., Morse and morse are the same");
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<doHelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D61
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D32
data_type: string
name: disassemble_data
arguments: tag: D69
data_type: string
name: disassemble_data
arguments: tag: D63
data_type: string
name: disassemble_data
arguments: tag: D56
data_type: string

tool: D16: 
Commands available:

tool: D61: 
Morse <text>         English to Morse

tool: D6: 
English <morse>      Morse to English

tool: D32: 
Quit or Exit         Exit Program

tool: D69: 
Help or Info         Display this text

tool: D63: 

Commands are case-insensitive,


tool: D56: eg., Morse and morse are the same

assistant: ```c
int doHelp(char *s) {
  (void)(&s);
  printf("\nCommands available:");
  printf("\nMorse <text>         English to Morse");
  printf("\nEnglish <morse>      Morse to English");
  printf("\nQuit or Exit         Exit Program");
  printf("\nHelp or Info         Display this text");
  printf("\n\nCommands are case-insensitive,\n");
  printf("eg., Morse and morse are the same");
  return (-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<doHelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D31
datatype: string
name: retrieve_data
arguments: label: D53
datatype: string
name: retrieve_data
arguments: label: D43
datatype: string
name: retrieve_data
arguments: label: D21
datatype: string
name: retrieve_data
arguments: label: D34
datatype: string
name: retrieve_data
arguments: label: D47
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string

tool: D31: 
Commands available:

tool: D53: 
Morse <text>         English to Morse

tool: D43: 
English <morse>      Morse to English

tool: D21: 
Quit or Exit         Exit Program

tool: D34: 
Help or Info         Display this text

tool: D47: 

Commands are case-insensitive,


tool: D13: eg., Morse and morse are the same

assistant: ```c
int doHelp(char *s) {
  (void)(&s);
  printf("\nCommands available:");
  printf("\nMorse <text>         English to Morse");
  printf("\nEnglish <morse>      Morse to English");
  printf("\nQuit or Exit         Exit Program");
  printf("\nHelp or Info         Display this text");
  printf("\n\nCommands are case-insensitive,\n");
  printf("eg., Morse and morse are the same");
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UpperCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L19:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L19
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void UpperCase(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++)
    s[i] = toupper(s[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UpperCase>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L7
L16:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void UpperCase(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++)
    s[i] = toupper(s[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UpperCase>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax)
L7:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void UpperCase(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++)
    s[i] = toupper(s[i]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UpperCase>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L10
  nopl   0x0(%rax)
L9:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void UpperCase(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++)
    s[i] = toupper(s[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_both_bases_are_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r9d
  mov    %rdx,%r8
  mov    $0xfffffff9,%ecx
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0xfffffffe,%edi
  call   <test_rebase@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void test_both_bases_are_negative(void) {
  int8_t input[] = {1};
  int8_t expected[] = {0};
  test_rebase(-2, input, (sizeof(input) / sizeof(input[0])), -7, expected, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_both_bases_are_negative>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%r9d
  lea    0x4(%rsp),%r8
  mov    $0xfffffff9,%ecx
  mov    $0x1,%edx
  mov    $0xfffffffe,%edi
  call   <test_rebase@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_both_bases_are_negative(void) {
  int8_t input[] = {1};
  int8_t expected[] = {0};
  test_rebase(-2, input, (sizeof(input) / sizeof(input[0])), -7, expected, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_both_bases_are_negative>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  mov    $0xfffffff9,%ecx
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r8
  mov    $0xfffffffe,%edi
  movl   $0x1,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <test_rebase@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_both_bases_are_negative(void) {
  int8_t input[] = {1};
  int8_t expected[] = {0};
  test_rebase(-2, input, (sizeof(input) / sizeof(input[0])), -7, expected, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_both_bases_are_negative>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  mov    $0xfffffff9,%ecx
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r8
  mov    $0xfffffffe,%edi
  movl   $0x1,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <test_rebase@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_both_bases_are_negative(void) {
  int8_t input[] = {1};
  int8_t expected[] = {0};
  test_rebase(-2, input, (sizeof(input) / sizeof(input[0])), -7, expected, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CE_CCCP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  %xmm6,-0x48(%rbp)
  movsd  %xmm7,-0x50(%rbp)
  movsd  -0x50(%rbp),%xmm4
  movsd  -0x40(%rbp),%xmm3
  movsd  -0x38(%rbp),%xmm2
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  mov    $0x7,%edi
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <CE_MP_pH@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x48(%rbp),%xmm6
  movsd  -0x40(%rbp),%xmm5
  movsd  -0x38(%rbp),%xmm4
  movsd  -0x30(%rbp),%xmm3
  movsd  -0x28(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  push   0x10(%rbp)
  push   -0x50(%rbp)
  movapd %xmm6,%xmm7
  movapd %xmm5,%xmm6
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x0,%edi
  call   <finddCa@plt>
  add    $0x10,%rsp
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double CE_CCCP(double Ca, double M, double P, double K1, double K2, double Kw, double Ks, double f0, double IB0) {
  double pH0;
  pH0 = CE_MP_pH(M, P, K1, K2, Kw, f0, 7);
  return finddCa(0, pH0, Ca, M, P, K1, K2, Kw, Ks, f0, IB0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CE_CCCP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  movq   %xmm2,%rbp
  movq   %xmm3,%r12
  movq   %xmm4,%r13
  movq   %xmm5,%r14
  movq   %xmm6,%r15
  movq   %xmm7,%rbx
  mov    $0x7,%edi
  movapd %xmm7,%xmm5
  movq   %r14,%xmm4
  movq   %r13,%xmm3
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movsd  (%rsp),%xmm0
  call   <CE_MP_pH@plt>
  push   0x50(%rsp)
  push   %rbx
  movq   %r15,%xmm7
  movq   %r14,%xmm6
  movq   %r13,%xmm5
  movq   %r12,%xmm4
  movq   %rbp,%xmm3
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  mov    $0x0,%edi
  call   <finddCa@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double CE_CCCP(double Ca, double M, double P, double K1, double K2, double Kw, double Ks, double f0, double IB0) {
  double pH0;
  pH0 = CE_MP_pH(M, P, K1, K2, Kw, f0, 7);
  return finddCa(0, pH0, Ca, M, P, K1, K2, Kw, Ks, f0, IB0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CE_CCCP>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm1,%xmm8
  mov    $0x7,%edi
  movsd  %xmm0,0x38(%rsp)
  movapd %xmm2,%xmm1
  movapd %xmm8,%xmm0
  movapd %xmm3,%xmm2
  movapd %xmm4,%xmm3
  movapd %xmm5,%xmm4
  movapd %xmm7,%xmm5
  movsd  %xmm7,0x28(%rsp)
  movsd  %xmm6,0x30(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm8,(%rsp)
  call   <CE_MP_pH@plt>
  push   0x50(%rsp)
  movsd  0x30(%rsp),%xmm5
  xor    %edi,%edi
  sub    $0x8,%rsp
  movsd  0x40(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm4
  movsd  %xmm5,(%rsp)
  movsd  0x28(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm8
  movapd %xmm6,%xmm7
  movapd %xmm4,%xmm6
  movsd  0x48(%rsp),%xmm9
  movapd %xmm3,%xmm5
  movapd %xmm2,%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm8,%xmm2
  movapd %xmm9,%xmm1
  call   <finddCa@plt>
  add    $0x58,%rsp
  ret
```

assistant: ```c
double CE_CCCP(double Ca, double M, double P, double K1, double K2, double Kw, double Ks, double f0, double IB0) {
  double pH0;
  pH0 = CE_MP_pH(M, P, K1, K2, Kw, f0, 7);
  return finddCa(0, pH0, Ca, M, P, K1, K2, Kw, Ks, f0, IB0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CE_CCCP>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm1,%xmm8
  mov    $0x7,%edi
  movsd  %xmm0,0x38(%rsp)
  movapd %xmm2,%xmm1
  movapd %xmm8,%xmm0
  movapd %xmm3,%xmm2
  movapd %xmm4,%xmm3
  movapd %xmm5,%xmm4
  movapd %xmm7,%xmm5
  movsd  %xmm7,0x28(%rsp)
  movsd  %xmm6,0x30(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm8,(%rsp)
  call   <CE_MP_pH@plt>
  push   0x50(%rsp)
  movsd  0x30(%rsp),%xmm5
  xor    %edi,%edi
  sub    $0x8,%rsp
  movsd  0x40(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm4
  movsd  %xmm5,(%rsp)
  movsd  0x28(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm8
  movapd %xmm6,%xmm7
  movapd %xmm4,%xmm6
  movsd  0x48(%rsp),%xmm9
  movapd %xmm3,%xmm5
  movapd %xmm2,%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm8,%xmm2
  movapd %xmm9,%xmm1
  call   <finddCa@plt>
  add    $0x58,%rsp
  ret
```

assistant: ```c
double CE_CCCP(double Ca, double M, double P, double K1, double K2, double Kw, double Ks, double f0, double IB0) {
  double pH0;
  pH0 = CE_MP_pH(M, P, K1, K2, Kw, f0, 7);
  return finddCa(0, pH0, Ca, M, P, K1, K2, Kw, Ks, f0, IB0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crossprod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void crossprod(double A[3], double B[3], double C[3]) {
  C[0] = A[1] * B[2] - A[2] * B[1];
  C[1] = A[2] * B[0] - A[0] * B[2];
  C[2] = A[0] * B[1] - A[1] * B[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crossprod>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void crossprod(double A[3], double B[3], double C[3]) {
  C[0] = A[1] * B[2] - A[2] * B[1];
  C[1] = A[2] * B[0] - A[0] * B[2];
  C[2] = A[0] * B[1] - A[1] * B[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crossprod>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void crossprod(double A[3], double B[3], double C[3]) {
  C[0] = A[1] * B[2] - A[2] * B[1];
  C[1] = A[2] * B[0] - A[0] * B[2];
  C[2] = A[0] * B[1] - A[1] * B[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crossprod>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void crossprod(double A[3], double B[3], double C[3]) {
  C[0] = A[1] * B[2] - A[2] * B[1];
  C[1] = A[2] * B[0] - A[0] * B[2];
  C[2] = A[0] * B[1] - A[1] * B[0];
}
```
user: What is the c source code of the assembly code below?

```asm
<z_param>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x14(%rbp)
  jg     L35
  jmp    L25
L19:
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L25:
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L19
L35:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
void z_param(int ac) {
  char buf;
  if (ac < 2)
    while (read(0, &buf, 1) != 0)
      write(1, &buf, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<z_param>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  cmp    $0x1,%edi
  jle    L36
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L36:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L28
  jmp    L13
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void z_param(int ac) {
  char buf;
  if (ac < 2)
    while (read(0, &buf, 1) != 0)
      write(1, &buf, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<z_param>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  cmp    $0x1,%edi
  jle    L39
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L38:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L39:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  jne    L38
  jmp    L14
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void z_param(int ac) {
  char buf;
  if (ac < 2)
    while (read(0, &buf, 1) != 0)
      write(1, &buf, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<z_param>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  cmp    $0x1,%edi
  jle    L33
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L33:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  jne    L11
  jmp    L13
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void z_param(int ac) {
  char buf;
  if (ac < 2)
    while (read(0, &buf, 1) != 0)
      write(1, &buf, 1);
}
```