ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<check_sum>:
  endbr64
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %eax,%edx
  add    $0x1,%eax
  addsd  (%rdi,%rdx,8),%xmm0
  cmp    %eax,%esi
  jae    L7
  xor    %edi,%edi
  comisd D3(%rip),%xmm0
  jbe    L15
  movsd  D12(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  seta   %dil
L15:
  jmp    1050 <assert@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: f64[2]
name: retrieve_data
arguments: tag: D12
type: f64

tool: {"D3": [0.999,1.001]}

tool: D12: 1.001

assistant: ```c
void check_sum(double *arr, unsigned int num) {
  unsigned int i;
  double sum = 0;
  for (i = 0; i <= num; i++)
    sum += arr[i];
  assert(sum > 0.999 && sum < 1.001);
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_sum>:
  endbr64
  lea    -0xf(%rsi),%eax
  cmp    $0xffffffef,%eax
  ja     L53
  lea    0x1(%rsi),%r8d
  sub    $0x1,%esi
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  shr    %esi
  lea    0x1(%rsi),%eax
  xchg   %ax,%ax
L14:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  shl    $0x4,%rcx
  movupd (%rdi,%rcx,1),%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %edx,%eax
  ja     L14
  add    %eax,%eax
  cmp    %eax,%r8d
  je     L46
  addsd  (%rdi,%rax,8),%xmm0
L46:
  xor    %edi,%edi
  comisd D0(%rip),%xmm0
  jbe    L15
  movsd  D17(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  seta   %dil
L15:
  jmp    1050 <assert@plt>
  nop
L53:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %eax,%edx
  add    $0x1,%eax
  addsd  (%rdi,%rdx,8),%xmm0
  cmp    %esi,%eax
  jbe    L31
  jmp    L46
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: f64[2]
name: disassemble_data
arguments: data_label: D17
datatype: f64

tool: {"D0": [0.999,1.001]}

tool: D17: 1.001

assistant: ```c
void check_sum(double *arr, unsigned int num) {
  unsigned int i;
  double sum = 0;
  for (i = 0; i <= num; i++)
    sum += arr[i];
  assert(sum > 0.999 && sum < 1.001);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  D0(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: f64

tool: D0: 1000000

assistant: ```c
double tic() {
  struct timeval now;
  gettimeofday(&now, NULL);
  return (double)now.tv_sec + (double)now.tv_usec / 1.0e6;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tic>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq (%rsp),%xmm0
  divsd  D2(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: f64

tool: D2: 1000000

assistant: ```c
double tic() {
  struct timeval now;
  gettimeofday(&now, NULL);
  return (double)now.tv_sec + (double)now.tv_usec / 1.0e6;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tic>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm1
  cvtsi2sdq (%rsp),%xmm0
  divsd  D1(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: f64

tool: D1: 1000000

assistant: ```c
double tic() {
  struct timeval now;
  gettimeofday(&now, NULL);
  return (double)now.tv_sec + (double)now.tv_usec / 1.0e6;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tic>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm1
  cvtsi2sdq (%rsp),%xmm0
  divsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: f64

tool: D0: 1000000

assistant: ```c
double tic() {
  struct timeval now;
  gettimeofday(&now, NULL);
  return (double)now.tv_sec + (double)now.tv_usec / 1.0e6;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x7b,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L46:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xdd,%al
  je     L86
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L86:
  addl   $0x1,-0xc(%rbp)
L25:
  cmpl   $0x7a,-0xc(%rbp)
  jle    L46
  mov    -0x8(%rbp),%rax
  mov    $0x1f4,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xdd,%al
  je     L4
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  addl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x1f3,-0xc(%rbp)
  jle    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L77
L30:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xee,%al
  je     L38
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L38:
  addl   $0x1,-0xc(%rbp)
L77:
  cmpl   $0x7a,-0xc(%rbp)
  jle    L30
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D25
data_type: string
name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D13: malloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D25: realloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D5: free: Freed memory is not initialized with 0xEE. offset %d


assistant: ```c
int main() {
  unsigned char *ptr;
  int i;
  ptr = malloc(123);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xDD) {
      printf("malloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  ptr = realloc(ptr, 500);
  for (i = 0; i < 500; i++) {
    if (ptr[i] != 0xDD) {
      printf("realloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  free(ptr);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xEE) {
      printf("free: Freed memory is not initialized with 0xEE. offset %d\n", i);
      exit(1);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x7b,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D23(%rip),%r12
  jmp    L16
L115:
  add    $0x1,%rbx
  cmp    $0x7b,%rbx
  je     L66
L16:
  mov    %ebx,%esi
  cmpb   $0xdd,0x0(%rbp,%rbx,1)
  je     L115
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L115
L66:
  mov    $0x1f4,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D22(%rip),%r12
  jmp    L105
L100:
  add    $0x1,%rbx
  cmp    $0x1f4,%rbx
  je     L13
L105:
  mov    %ebx,%esi
  cmpb   $0xdd,0x0(%rbp,%rbx,1)
  je     L100
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L100
L13:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  lea    D24(%rip),%r12
  jmp    L113
L3:
  add    $0x1,%rbx
  cmp    $0x7b,%rbx
  je     L62
L113:
  mov    %ebx,%esi
  cmpb   $0xee,0x0(%rbp,%rbx,1)
  je     L3
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L3
L62:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string

tool: D23: malloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D22: realloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D24: free: Freed memory is not initialized with 0xEE. offset %d


assistant: ```c
int main() {
  unsigned char *ptr;
  int i;
  ptr = malloc(123);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xDD) {
      printf("malloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  ptr = realloc(ptr, 500);
  for (i = 0; i < 500; i++) {
    if (ptr[i] != 0xDD) {
      printf("realloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  free(ptr);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xEE) {
      printf("free: Freed memory is not initialized with 0xEE. offset %d\n", i);
      exit(1);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7b,%edi
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%rbp
  xchg   %ax,%ax
L24:
  cmpb   $0xdd,0x0(%rbp,%rbx,1)
  mov    %ebx,%esi
  je     L44
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L44:
  add    $0x1,%rbx
  cmp    $0x7b,%rbx
  jne    L24
  mov    %rbp,%rdi
  mov    $0x1f4,%esi
  xor    %ebx,%ebx
  call   <realloc@plt>
  lea    D19(%rip),%r12
  mov    %rax,%rbp
  xchg   %ax,%ax
L0:
  cmpb   $0xdd,0x0(%rbp,%rbx,1)
  mov    %ebx,%esi
  je     L28
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L28:
  add    $0x1,%rbx
  cmp    $0x1f4,%rbx
  jne    L0
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  lea    D24(%rip),%r12
  call   <free@plt>
  nopl   0x0(%rax)
L59:
  cmpb   $0xee,0x0(%rbp,%rbx,1)
  mov    %ebx,%esi
  je     L3
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L3:
  add    $0x1,%rbx
  cmp    $0x7b,%rbx
  jne    L59
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D19
type_infered: string
name: retrieve_data
arguments: data_tag: D24
type_infered: string

tool: D8: malloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D19: realloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D24: free: Freed memory is not initialized with 0xEE. offset %d


assistant: ```c
int main() {
  unsigned char *ptr;
  int i;
  ptr = malloc(123);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xDD) {
      printf("malloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  ptr = realloc(ptr, 500);
  for (i = 0; i < 500; i++) {
    if (ptr[i] != 0xDD) {
      printf("realloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  free(ptr);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xEE) {
      printf("free: Freed memory is not initialized with 0xEE. offset %d\n", i);
      exit(1);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7b,%edi
  lea    D23(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%rbp
  xchg   %ax,%ax
L50:
  cmpb   $0xdd,0x0(%rbp,%rbx,1)
  mov    %ebx,%esi
  je     L33
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L33:
  add    $0x1,%rbx
  cmp    $0x7b,%rbx
  jne    L50
  mov    %rbp,%rdi
  mov    $0x1f4,%esi
  xor    %ebx,%ebx
  call   <realloc@plt>
  lea    D7(%rip),%r12
  mov    %rax,%rbp
  xchg   %ax,%ax
L38:
  cmpb   $0xdd,0x0(%rbp,%rbx,1)
  mov    %ebx,%esi
  je     L53
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L53:
  add    $0x1,%rbx
  cmp    $0x1f4,%rbx
  jne    L38
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  lea    D21(%rip),%r12
  call   <free@plt>
  nopl   0x0(%rax)
L55:
  cmpb   $0xee,0x0(%rbp,%rbx,1)
  mov    %ebx,%esi
  je     L19
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L19:
  add    $0x1,%rbx
  cmp    $0x7b,%rbx
  jne    L55
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D21
type_guessed: string

tool: D23: malloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D7: realloc: Allocated memory is not initialized with 0xDD. offset %d


tool: D21: free: Freed memory is not initialized with 0xEE. offset %d


assistant: ```c
int main() {
  unsigned char *ptr;
  int i;
  ptr = malloc(123);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xDD) {
      printf("malloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  ptr = realloc(ptr, 500);
  for (i = 0; i < 500; i++) {
    if (ptr[i] != 0xDD) {
      printf("realloc: Allocated memory is not initialized with 0xDD. offset %d\n", i);
      exit(1);
    }
  }
  free(ptr);
  for (i = 0; i < 123; i++) {
    if (ptr[i] != 0xEE) {
      printf("free: Freed memory is not initialized with 0xEE. offset %d\n", i);
      exit(1);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x11(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(void) {
  char x;
  _Alignas(32) int *p = (int *)&x;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char x;
  _Alignas(32) int *p = (int *)&x;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char x;
  _Alignas(32) int *p = (int *)&x;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char x;
  _Alignas(32) int *p = (int *)&x;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void my_strcpy(char *news, char *olds) {
  int i = 0;
  do {
    news[i] = olds[i];
    i++;
  } while (olds[i] != '\0');
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strcpy>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L8
  ret
```

assistant: ```c
void my_strcpy(char *news, char *olds) {
  int i = 0;
  do {
    news[i] = olds[i];
    i++;
  } while (olds[i] != '\0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L2:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L2
  ret
```

assistant: ```c
void my_strcpy(char *news, char *olds) {
  int i = 0;
  do {
    news[i] = olds[i];
    i++;
  } while (olds[i] != '\0');
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_strcpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L3
  ret
```

assistant: ```c
void my_strcpy(char *news, char *olds) {
  int i = 0;
  do {
    news[i] = olds[i];
    i++;
  } while (olds[i] != '\0');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L57
  movl   $0x1,-0xc(%rbp)
  negl   -0x24(%rbp)
L57:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L25:
  addl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L17:
  cmpl   $0x0,-0x8(%rbp)
  jne    L25
  cmpl   $0x0,-0xc(%rbp)
  je     L12
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L14
L32:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    D31(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
L14:
  cmpl   $0x0,-0x24(%rbp)
  jne    L32
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    D31(%rip),%rdx
  movb   $0x2d,(%rax,%rdx,1)
L1:
  mov    -0x10(%rbp),%eax
  cltq
  lea    D31(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D31(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *itoa(int num) {
  int i, rem = 0, strlen = 0;
  int isNegative = 0;
  int num_cpy;
  if (num < 0) {
    isNegative = 1;
    num = -num;
  }
  for (num_cpy = num; num_cpy != 0; num_cpy /= 10)
    strlen++;
  if (isNegative)
    strlen++;
  static char str[20];
  i = strlen - 1;
  while (num != 0) {
    rem = num % 10;
    str[i--] = rem + '0';
    num = num / 10;
  }
  if (isNegative)
    str[i--] = '-';
  str[strlen] = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  js     L46
  je     L2
  mov    $0x0,%esi
L88:
  mov    %edx,%ecx
  mov    $0x0,%edi
L97:
  mov    %edi,%r9d
  add    $0x1,%edi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  jne    L97
  test   %esi,%esi
  je     L85
  add    $0x2,%r9d
  test   %edx,%edx
  je     L83
L40:
  lea    -0x1(%rdi),%ecx
  movslq %ecx,%rcx
  lea    D5(%rip),%r10
L107:
  mov    %ecx,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,(%rcx,%r10,1)
  mov    %eax,%edx
  sub    $0x1,%rcx
  test   %eax,%eax
  jne    L107
  test   %esi,%esi
  je     L68
L83:
  movslq %edi,%rdi
  lea    D27(%rip),%rax
  movb   $0x2d,(%rax,%rdi,1)
L68:
  lea    D27(%rip),%rax
  movslq %r9d,%r9
  movb   $0x0,(%rax,%r9,1)
  ret
L46:
  neg    %edx
  mov    $0x1,%esi
  jmp    L88
L2:
  mov    %edi,%esi
  mov    %edi,%r9d
  jmp    L47
L85:
  mov    %edi,%r9d
L47:
  lea    -0x1(%r9),%edi
  test   %edx,%edx
  jne    L40
  jmp    L68
```

assistant: ```c
char *itoa(int num) {
  int i, rem = 0, strlen = 0;
  int isNegative = 0;
  int num_cpy;
  if (num < 0) {
    isNegative = 1;
    num = -num;
  }
  for (num_cpy = num; num_cpy != 0; num_cpy /= 10)
    strlen++;
  if (isNegative)
    strlen++;
  static char str[20];
  i = strlen - 1;
  while (num != 0) {
    rem = num % 10;
    str[i--] = rem + '0';
    num = num / 10;
  }
  if (isNegative)
    str[i--] = '-';
  str[strlen] = '\0';
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  js     L40
  mov    $0x0,%r8d
  je     L74
L50:
  mov    %eax,%edx
  xor    %edi,%edi
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %edx,%edx
  mov    %edi,%ecx
  add    $0x1,%edi
  imul   %rsi,%rdx
  shr    $0x23,%rdx
  test   %edx,%edx
  jne    L31
  test   %r8d,%r8d
  je     L10
  lea    0x2(%rcx),%edx
  mov    %edi,%ecx
  mov    %edx,%edi
L10:
  sub    $0x1,%ecx
  lea    D22(%rip),%r11
  mov    $0xcccccccd,%r10d
  movslq %ecx,%rcx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %eax,%edx
  movslq %ecx,%r9
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x30,%eax
  mov    %al,(%r11,%rcx,1)
  mov    %edx,%eax
  sub    $0x1,%rcx
  test   %edx,%edx
  jne    L11
  lea    D19(%rip),%rax
  test   %r8d,%r8d
  je     L34
  movb   $0x2d,(%rax,%r9,1)
L34:
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  ret
  xchg   %ax,%ax
L40:
  neg    %eax
  mov    $0x1,%r8d
  jmp    L50
L74:
  xor    %edi,%edi
  lea    D19(%rip),%rax
  jmp    L34
```

assistant: ```c
char *itoa(int num) {
  int i, rem = 0, strlen = 0;
  int isNegative = 0;
  int num_cpy;
  if (num < 0) {
    isNegative = 1;
    num = -num;
  }
  for (num_cpy = num; num_cpy != 0; num_cpy /= 10)
    strlen++;
  if (isNegative)
    strlen++;
  static char str[20];
  i = strlen - 1;
  while (num != 0) {
    rem = num % 10;
    str[i--] = rem + '0';
    num = num / 10;
  }
  if (isNegative)
    str[i--] = '-';
  str[strlen] = '\0';
  return str;
}
```