ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mylog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L2
  shll   -0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L16
L2:
  nop
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mylog>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%edx
  cmp    $0x1,%edi
  jle    L14
L4:
  add    %eax,%eax
  add    $0x1,%edx
  cmp    %eax,%edi
  jg     L4
L14:
  mov    %edx,%eax
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mylog>:
  endbr64
  mov    $0x1,%eax
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  jle    L0
  nopl   0x0(%rax)
L6:
  add    %eax,%eax
  add    $0x1,%r8d
  cmp    %eax,%edi
  jg     L6
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mylog>:
  endbr64
  mov    $0x1,%eax
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  jle    L2
  nopl   0x0(%rax)
L4:
  add    %eax,%eax
  add    $0x1,%r8d
  cmp    %eax,%edi
  jg     L4
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L50:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L53
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L49
L53:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L26
  cmpl   $0x7e,-0x4(%rbp)
  jg     L26
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L49
L26:
  cmpl   $0x1b,-0x4(%rbp)
  jne    L49
  nop
L85:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5b,-0x4(%rbp)
  je     L85
  cmpl   $0x2c,-0x4(%rbp)
  je     L85
  cmpl   $0x2f,-0x4(%rbp)
  jle    L117
  cmpl   $0x39,-0x4(%rbp)
  jle    L85
L117:
  cmpl   $0x3b,-0x4(%rbp)
  je     L85
L49:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L50
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int ch;
  do {
    if ((ch = getchar()) == '\n')
      putchar('\n');
    else if ((ch >= 32) && (ch < 127))
      putchar(ch);
    else if (ch == 27)
      while (((ch = getchar()) == '[') || (ch == ',') || ((ch >= '0') && (ch <= '9')) || (ch == ';'))
        ;
  } while (ch != EOF);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movabs $0xbff100000000000,%rbp
  jmp    L62
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L0
L33:
  mov    %ebx,%edi
  call   <putchar@plt>
L0:
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  je     L17
L62:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L16
  lea    -0x20(%rax),%eax
  cmp    $0x5e,%eax
  jbe    L33
  cmp    $0x1b,%ebx
  jne    L0
L29:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x5b,%eax
  je     L29
  cmp    $0x3b,%eax
  ja     L0
  bt     %rax,%rbp
  jb     L29
  jmp    L0
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int ch;
  do {
    if ((ch = getchar()) == '\n')
      putchar('\n');
    else if ((ch >= 32) && (ch < 127))
      putchar(ch);
    else if (ch == 27)
      while (((ch = getchar()) == '[') || (ch == ',') || ((ch >= '0') && (ch <= '9')) || (ch == ';'))
        ;
  } while (ch != EOF);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  movabs $0xbff100000000000,%r12
  push   %rbp
  mov    D1(%rip),%rbp
  push   %rbx
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    $0x1b,%ebx
  je     L92
L41:
  cmp    %ebx,0x0(%rbp)
  je     L24
L51:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L54
  lea    -0x20(%rax),%eax
  cmp    $0x5e,%eax
  ja     L44
  mov    %ebx,%edi
  call   <putchar@plt>
  cmp    %ebx,0x0(%rbp)
  jne    L51
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L92:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x5b,%eax
  je     L92
  cmp    $0x3b,%eax
  ja     L41
  bt     %rax,%r12
  jb     L92
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L54:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L41
```

assistant: ```c
int main() {
  int ch;
  do {
    if ((ch = getchar()) == '\n')
      putchar('\n');
    else if ((ch >= 32) && (ch < 127))
      putchar(ch);
    else if (ch == 27)
      while (((ch = getchar()) == '[') || (ch == ',') || ((ch >= '0') && (ch <= '9')) || (ch == ';'))
        ;
  } while (ch != EOF);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  movabs $0xbff100000000000,%r12
  push   %rbp
  mov    D2(%rip),%rbp
  push   %rbx
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L62:
  cmp    $0x1b,%ebx
  je     L1
L42:
  cmp    %ebx,0x0(%rbp)
  je     L107
L50:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L2
  lea    -0x20(%rax),%eax
  cmp    $0x5e,%eax
  ja     L62
  mov    %ebx,%edi
  call   <putchar@plt>
  cmp    %ebx,0x0(%rbp)
  jne    L50
L107:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x5b,%eax
  je     L1
  cmp    $0x3b,%eax
  ja     L42
  bt     %rax,%r12
  jb     L1
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L42
```

assistant: ```c
int main() {
  int ch;
  do {
    if ((ch = getchar()) == '\n')
      putchar('\n');
    else if ((ch >= 32) && (ch < 127))
      putchar(ch);
    else if (ch == 27)
      while (((ch = getchar()) == '[') || (ch == ',') || ((ch >= '0') && (ch <= '9')) || (ch == ';'))
        ;
  } while (ch != EOF);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<insertSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L17
L37:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L36:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L36
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertSort(int a[], int size) {
  int i = 1, j, tmp;
  for (; i < size; ++i) {
    tmp = a[i];
    j = i - 1;
    while (a[j] > tmp) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = tmp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L33
  lea    -0x1(%rsi),%r9d
  mov    $0x0,%r8d
L2:
  mov    0x4(%rdi,%r8,4),%ecx
  mov    (%rdi,%r8,4),%edx
  cmp    %edx,%ecx
  jge    L25
  lea    -0x1(%r8),%rax
L49:
  mov    %edx,0x8(%rdi,%rax,4)
  mov    %rax,%rsi
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L49
L18:
  mov    %ecx,0x4(%rdi,%rsi,4)
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L2
L33:
  ret
L25:
  mov    %r8,%rsi
  jmp    L18
```

assistant: ```c
void insertSort(int a[], int size) {
  int i = 1, j, tmp;
  for (; i < size; ++i) {
    tmp = a[i];
    j = i - 1;
    while (a[j] > tmp) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L31
  lea    0x4(%rdi),%r8
  lea    -0x1(%rsi),%r10d
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L8:
  mov    (%r8),%ecx
  mov    -0x4(%r8),%edx
  mov    %r8,%rax
  cmp    %edx,%ecx
  jge    L28
  lea    -0x1(%r9),%rax
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %edx,0x8(%rdi,%rax,4)
  mov    %rax,%rsi
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L20
  lea    0x4(%rdi,%rsi,4),%rax
L28:
  add    $0x1,%r9
  mov    %ecx,(%rax)
  add    $0x4,%r8
  cmp    %r9,%r10
  jne    L8
L31:
  ret
```

assistant: ```c
void insertSort(int a[], int size) {
  int i = 1, j, tmp;
  for (; i < size; ++i) {
    tmp = a[i];
    j = i - 1;
    while (a[j] > tmp) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = tmp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L10
  lea    0x4(%rdi),%r8
  lea    -0x1(%rsi),%r10d
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L32:
  mov    (%r8),%ecx
  mov    -0x4(%r8),%edx
  mov    %r8,%rax
  cmp    %edx,%ecx
  jge    L21
  lea    -0x1(%r9),%rax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %edx,0x8(%rdi,%rax,4)
  mov    %rax,%rsi
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L13
  lea    0x4(%rdi,%rsi,4),%rax
L21:
  add    $0x1,%r9
  mov    %ecx,(%rax)
  add    $0x4,%r8
  cmp    %r9,%r10
  jne    L32
L10:
  ret
```

assistant: ```c
void insertSort(int a[], int size) {
  int i = 1, j, tmp;
  for (; i < size; ++i) {
    tmp = a[i];
    j = i - 1;
    while (a[j] > tmp) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = tmp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<libMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x9,-0x4(%rbp)
  jle    L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void libMat(char **mat) {
  int i;
  for (i = 0; i < 10; i++)
    free(mat[i]);
  free(mat);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<libMat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbx
  lea    0x50(%rdi),%rbp
L3:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void libMat(char **mat) {
  int i;
  for (i = 0; i < 10; i++)
    free(mat[i]);
  free(mat);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<libMat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x50(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L0
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void libMat(char **mat) {
  int i;
  for (i = 0; i < 10; i++)
    free(mat[i]);
  free(mat);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<libMat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x50(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L0
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void libMat(char **mat) {
  int i;
  for (i = 0; i < 10; i++)
    free(mat[i]);
  free(mat);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_HT@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_HT();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_HT@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_HT();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_HT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_HT();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_HT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_HT();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SetUpMemBanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <InitATTList@plt>
  mov    $0x0,%eax
  call   <SetUp_address@plt>
  mov    $0x0,%eax
  call   <FinishATTList@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SetUpMemBanks(void) {
  InitATTList();
  SetUp_address();
  FinishATTList();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SetUpMemBanks>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <InitATTList@plt>
  mov    $0x0,%eax
  call   <SetUp_address@plt>
  mov    $0x0,%eax
  call   <FinishATTList@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SetUpMemBanks(void) {
  InitATTList();
  SetUp_address();
  FinishATTList();
}
```
user: Translate the below assembly code into C programming language:

```asm
<SetUpMemBanks>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <InitATTList@plt>
  xor    %eax,%eax
  call   <SetUp_address@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <FinishATTList@plt>
```

assistant: ```c
void SetUpMemBanks(void) {
  InitATTList();
  SetUp_address();
  FinishATTList();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SetUpMemBanks>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <InitATTList@plt>
  xor    %eax,%eax
  call   <SetUp_address@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <FinishATTList@plt>
```

assistant: ```c
void SetUpMemBanks(void) {
  InitATTList();
  SetUp_address();
  FinishATTList();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    -0x20(%rbp),%rbx
  jmp    L9
L7:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  mov    %r12b,(%rax)
  add    $0x1,%rbx
L9:
  cmp    %r13,%rbx
  jb     L7
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void test_sort() {
  char *base;
  register char c, *i, *hi;
  for (i = base; i < hi; i++)
    *i++ = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_sort>:
  endbr64
  ret
```

assistant: ```c
void test_sort() {
  char *base;
  register char c, *i, *hi;
  for (i = base; i < hi; i++)
    *i++ = c;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_sort>:
  endbr64
  ret
```

assistant: ```c
void test_sort() {
  char *base;
  register char c, *i, *hi;
  for (i = base; i < hi; i++)
    *i++ = c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(int a, int b, int c) {
  int x, y;
  x = a + b + c;
  y = x * 5;
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func>:
  endbr64
  add    %esi,%edi
  add    %edx,%edi
  lea    (%rdi,%rdi,4),%eax
  ret
```

assistant: ```c
int func(int a, int b, int c) {
  int x, y;
  x = a + b + c;
  y = x * 5;
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  add    %esi,%edi
  add    %edx,%edi
  lea    (%rdi,%rdi,4),%eax
  ret
```

assistant: ```c
int func(int a, int b, int c) {
  int x, y;
  x = a + b + c;
  y = x * 5;
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func>:
  endbr64
  add    %esi,%edi
  add    %edx,%edi
  lea    (%rdi,%rdi,4),%eax
  ret
```

assistant: ```c
int func(int a, int b, int c) {
  int x, y;
  x = a + b + c;
  y = x * 5;
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<part2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D6(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L14:
  movss  -0xc(%rbp),%xmm0
  addss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x9,-0x8(%rbp)
  jle    L14
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movq   %xmm1,%rdx
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  D29(%rip),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  setnp  %al
  mov    $0x0,%edx
  movss  D29(%rip),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: byte[4]
name: parse_data
arguments: data_label: D33
data_type: string
name: parse_data
arguments: data_label: D29
data_type: byte[4]
name: parse_data
arguments: data_label: D49
data_type: string

tool: {"D6": [0xcd,0xcc,0xcc,0x3d]}

tool: D33: 
Part 2 -- f is %e,  sum is %e


tool: {"D29": [0x00,0x00,0x80,0x3f]}

tool: D49: Part 2B?  sum == 1.0F IS false (%d)


assistant: ```c
void part2() {
  float f = 0.1F;
  float sum = 0;
  int i;
  for (i = 0; i < 10; i++) {
    sum = sum + f;
  }
  printf("\nPart 2 -- f is %e,  sum is %e\n", f, sum);
  printf("Part 2B?  sum == 1.0F IS false (%d)\n", sum == 1.0F);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<part2>:
  endbr64
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm0
  mov    $0x0,%esi
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string

tool: {"D9": [0x00,0x00,0x00,0x20,0x00,0x00,0xf0,0x3f]}

tool: D15: 
Part 2 -- f is %e,  sum is %e


tool: D24: Part 2B?  sum == 1.0F IS false (%d)


assistant: ```c
void part2() {
  float f = 0.1F;
  float sum = 0;
  int i;
  for (i = 0; i < 10; i++) {
    sum = sum + f;
  }
  printf("\nPart 2 -- f is %e,  sum is %e\n", f, sum);
  printf("Part 2B?  sum == 1.0F IS false (%d)\n", sum == 1.0F);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<part2>:
  endbr64
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm0
  xor    %esi,%esi
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: byte[8]
name: read_data
arguments: tag: D18
type_infered: string
name: read_data
arguments: tag: D2
type_infered: string

tool: {"D9": [0x00,0x00,0x00,0x20,0x00,0x00,0xf0,0x3f]}

tool: D18: 
Part 2 -- f is %e,  sum is %e


tool: D2: Part 2B?  sum == 1.0F IS false (%d)


assistant: ```c
void part2() {
  float f = 0.1F;
  float sum = 0;
  int i;
  for (i = 0; i < 10; i++) {
    sum = sum + f;
  }
  printf("\nPart 2 -- f is %e,  sum is %e\n", f, sum);
  printf("Part 2B?  sum == 1.0F IS false (%d)\n", sum == 1.0F);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<part2>:
  endbr64
  sub    $0x8,%rsp
  movsd  D1(%rip),%xmm0
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string

tool: {"D1": [0x00,0x00,0x00,0x20,0x00,0x00,0xf0,0x3f]}

tool: D11: 
Part 2 -- f is %e,  sum is %e


tool: D25: Part 2B?  sum == 1.0F IS false (%d)


assistant: ```c
void part2() {
  float f = 0.1F;
  float sum = 0;
  int i;
  for (i = 0; i < 10; i++) {
    sum = sum + f;
  }
  printf("\nPart 2 -- f is %e,  sum is %e\n", f, sum);
  printf("Part 2B?  sum == 1.0F IS false (%d)\n", sum == 1.0F);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mfm_kv_ins>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L55
L29:
  subl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
L55:
  cmpl   $0x0,-0x1c(%rbp)
  je     L23
  cmpl   $0x0,-0x18(%rbp)
  je     L23
  cmpl   $0x0,-0x14(%rbp)
  je     L29
L23:
  cmpl   $0x0,-0x14(%rbp)
  je     L22
  mov    -0x14(%rbp),%eax
  jmp    L12
L22:
  mov    -0x1c(%rbp),%eax
  sub    -0x18(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int mfm_kv_ins(const void *one, const void *two) {
  unsigned char *s1 = ((unsigned char **)one)[0];
  unsigned char *s2 = ((unsigned char **)two)[0];
  int l1 = strlen(s1);
  int l2 = strlen(s2);
  int res = 0;
  while (l1 && l2 && !res) {
    l1--;
    l2--;
    res = (int)s1[l1] - (int)s2[l2];
  }
  if (res) {
    return res;
  }
  return l1 - l2;
}
```