ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%rdi
  push   %r14
  lea    D34(%rip),%r14
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L38
  cs nopw 0x0(%rax,%rax,1)
L40:
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jle    L21
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    $0xa,%edi
  call   <Delay@plt>
  mov    0x4(%rsp),%eax
  sub    %ebx,%eax
  cmp    %r15d,%eax
  jge    L51
L21:
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L45:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    $0xa,%edi
  call   <Delay@plt>
  cmp    %ebp,%r15d
  jne    L45
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x2,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L40
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D34
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D20
type_guessed: string

tool: D0: Enter the number of rows: 

tool: D34: 


tool: D24: *

tool: D23:  

tool: D20: %d

assistant: ```c
int main() {
  int i, space, rows, k = 0;
  printf("Enter the number of rows: ");
  scanf("%d", &rows);
  for (i = 1; i <= rows; ++i) {
    for (space = 1; space <= rows - i; ++space) {
      printf(" ");
      Delay(10);
    }
    while (k != 2 * i - 1) {
      printf("*");
      ++k;
      Delay(10);
    }
    k = 0;
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: test


assistant: ```c
int main() {
  puts("test\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: test


assistant: ```c
int main() {
  puts("test\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: test


assistant: ```c
int main() {
  puts("test\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: test


assistant: ```c
int main() {
  puts("test\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <strings_matrix@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  strings_matrix();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <strings_matrix@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  strings_matrix();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <strings_matrix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  strings_matrix();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <strings_matrix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  strings_matrix();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_brightness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jg     L30
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <logprintf@plt>
  jmp    L31
L30:
  cmpl   $0xff,-0x4(%rbp)
  jle    L8
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <logprintf@plt>
  jmp    L31
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <qfprintf@plt>
L31:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D38
data_type: string
name: extract_symbolic_data
arguments: data_label: D29
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string

tool: D10: 1can't set brightness < 4

tool: D38: 1can't set brightness > 255

tool: D29: %d

tool: D16: /sys/class/leds/lcd-backlight/brightness

assistant: ```c
void set_brightness(int bright) {
  if (bright < 4) {
    logprintf("1can't set brightness < 4");
    return;
  }
  if (bright > 255) {
    logprintf("1can't set brightness > 255");
    return;
  }
  qfprintf("/sys/class/leds/lcd-backlight/brightness", "%d", bright);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_brightness>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jle    L31
  cmp    $0xff,%edi
  jg     L34
  mov    %edi,%edx
  lea    D18(%rip),%rsi
  lea    D37(%rip),%rdi
  call   <qfprintf@plt>
L8:
  add    $0x8,%rsp
  ret
L31:
  lea    D25(%rip),%rdi
  call   <logprintf@plt>
  jmp    L8
L34:
  lea    D13(%rip),%rdi
  call   <logprintf@plt>
  jmp    L8
```

tool_calls: name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D37
datatype: string
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D13
datatype: string

tool: D18: %d

tool: D37: /sys/class/leds/lcd-backlight/brightness

tool: D25: 1can't set brightness < 4

tool: D13: 1can't set brightness > 255

assistant: ```c
void set_brightness(int bright) {
  if (bright < 4) {
    logprintf("1can't set brightness < 4");
    return;
  }
  if (bright > 255) {
    logprintf("1can't set brightness > 255");
    return;
  }
  qfprintf("/sys/class/leds/lcd-backlight/brightness", "%d", bright);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_brightness>:
  endbr64
  mov    %edi,%edx
  cmp    $0x3,%edi
  jle    L9
  cmp    $0xff,%edi
  jg     L16
  lea    D37(%rip),%rsi
  lea    D12(%rip),%rdi
  jmp    1070 <qfprintf@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  lea    D24(%rip),%rdi
  jmp    1060 <logprintf@plt>
  nopl   0x0(%rax)
L9:
  lea    D9(%rip),%rdi
  jmp    1060 <logprintf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D37
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D37: %d

tool: D12: /sys/class/leds/lcd-backlight/brightness

tool: D24: 1can't set brightness > 255

tool: D9: 1can't set brightness < 4

assistant: ```c
void set_brightness(int bright) {
  if (bright < 4) {
    logprintf("1can't set brightness < 4");
    return;
  }
  if (bright > 255) {
    logprintf("1can't set brightness > 255");
    return;
  }
  qfprintf("/sys/class/leds/lcd-backlight/brightness", "%d", bright);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<set_brightness>:
  endbr64
  mov    %edi,%edx
  cmp    $0x3,%edi
  jle    L13
  cmp    $0xff,%edi
  jg     L17
  lea    D10(%rip),%rsi
  lea    D26(%rip),%rdi
  jmp    1070 <qfprintf@plt>
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    D12(%rip),%rdi
  jmp    1060 <logprintf@plt>
  nopl   0x0(%rax)
L13:
  lea    D13(%rip),%rdi
  jmp    1060 <logprintf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D26
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D13
type: string

tool: D10: %d

tool: D26: /sys/class/leds/lcd-backlight/brightness

tool: D12: 1can't set brightness > 255

tool: D13: 1can't set brightness < 4

assistant: ```c
void set_brightness(int bright) {
  if (bright < 4) {
    logprintf("1can't set brightness < 4");
    return;
  }
  if (bright > 255) {
    logprintf("1can't set brightness > 255");
    return;
  }
  qfprintf("/sys/class/leds/lcd-backlight/brightness", "%d", bright);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %ecx,%eax
  mov    %dl,-0x20(%rbp)
  mov    %al,-0x24(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L14
  subl   $0x1,-0x8(%rbp)
  jmp    L28
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L28
  addl   $0x1,-0x8(%rbp)
L28:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_match(char *str, int pos, char what, char match) {
  int levels = 1;
  int i = pos;
  do {
    if (str[i] == what) {
      levels--;
    } else if (str[i] == match) {
      levels++;
    }
    i++;
  } while (levels != 0);
  return i - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_match>:
  endbr64
  movslq %esi,%rsi
  mov    $0x1,%eax
  jmp    L15
L31:
  cmp    %cl,%r8b
  sete   %r8b
  movzbl %r8b,%r8d
  add    %r8d,%eax
L23:
  add    $0x1,%rsi
  test   %eax,%eax
  je     L30
L15:
  mov    %esi,%r9d
  movzbl (%rdi,%rsi,1),%r8d
  cmp    %dl,%r8b
  jne    L31
  sub    $0x1,%eax
  jmp    L23
L30:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int find_match(char *str, int pos, char what, char match) {
  int levels = 1;
  int i = pos;
  do {
    if (str[i] == what) {
      levels--;
    } else if (str[i] == match) {
      levels++;
    }
    i++;
  } while (levels != 0);
  return i - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_match>:
  endbr64
  movslq %esi,%rsi
  mov    $0x1,%r8d
  jmp    L29
  nop
L7:
  cmp    %cl,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
L1:
  add    $0x1,%rsi
L29:
  movzbl (%rdi,%rsi,1),%eax
  cmp    %dl,%al
  jne    L7
  sub    $0x1,%r8d
  jne    L1
  mov    %esi,%eax
  ret
```

assistant: ```c
int find_match(char *str, int pos, char what, char match) {
  int levels = 1;
  int i = pos;
  do {
    if (str[i] == what) {
      levels--;
    } else if (str[i] == match) {
      levels++;
    }
    i++;
  } while (levels != 0);
  return i - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_match>:
  endbr64
  movslq %esi,%rsi
  mov    $0x1,%r8d
  jmp    L2
  nop
L5:
  cmp    %cl,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
L8:
  add    $0x1,%rsi
L2:
  movzbl (%rdi,%rsi,1),%eax
  cmp    %dl,%al
  jne    L5
  sub    $0x1,%r8d
  jne    L8
  mov    %esi,%eax
  ret
```

assistant: ```c
int find_match(char *str, int pos, char what, char match) {
  int levels = 1;
  int i = pos;
  do {
    if (str[i] == what) {
      levels--;
    } else if (str[i] == match) {
      levels++;
    }
    i++;
  } while (levels != 0);
  return i - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  jmp    L17
L3:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int find_pos(char c, char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if (str[i] == c)
      return (i);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_pos>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L11
  mov    $0x0,%eax
L14:
  mov    %eax,%ecx
  cmp    %dl,%dil
  je     L6
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L14
  mov    $0x0,%ecx
L6:
  mov    %ecx,%eax
  ret
L11:
  mov    $0x0,%ecx
  jmp    L6
```

assistant: ```c
int find_pos(char c, char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if (str[i] == c)
      return (i);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<find_pos>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L27
  xor    %eax,%eax
  jmp    L0
  nop
L7:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L27
L0:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L7
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_pos(char c, char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if (str[i] == c)
      return (i);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<find_pos>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L30
  xor    %eax,%eax
  jmp    L35
  nop
L29:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L30
L35:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L29
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_pos(char c, char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if (str[i] == c)
      return (i);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memccpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L10:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x24(%rbp)
  jne    L24
  mov    -0x10(%rbp),%rax
  jmp    L21
L24:
  addq   $0x1,-0x8(%rbp)
L34:
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t count) {
  char *a = dst;
  char *b = src;
  while (count--) {
    *a++ = *b;
    if (*b == c) {
      return (void *)a;
    }
    b++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memccpy>:
  endbr64
  mov    %rdi,%rax
  test   %rcx,%rcx
  je     L1
  add    %rdi,%rcx
L27:
  add    $0x1,%rax
  movzbl (%rsi),%r8d
  mov    %r8b,-0x1(%rax)
  movsbl %r8b,%r8d
  cmp    %edx,%r8d
  je     L19
  add    $0x1,%rsi
  cmp    %rax,%rcx
  jne    L27
  mov    $0x0,%eax
  ret
L1:
  mov    $0x0,%eax
L19:
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t count) {
  char *a = dst;
  char *b = src;
  while (count--) {
    *a++ = *b;
    if (*b == c) {
      return (void *)a;
    }
    b++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memccpy>:
  endbr64
  mov    %rdi,%rax
  test   %rcx,%rcx
  je     L28
  add    %rdi,%rcx
  jmp    L27
  nopl   0x0(%rax)
L24:
  add    $0x1,%rsi
  cmp    %rax,%rcx
  je     L28
L27:
  movsbl (%rsi),%r8d
  add    $0x1,%rax
  mov    %r8b,-0x1(%rax)
  cmp    %edx,%r8d
  jne    L24
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t count) {
  char *a = dst;
  char *b = src;
  while (count--) {
    *a++ = *b;
    if (*b == c) {
      return (void *)a;
    }
    b++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memccpy>:
  endbr64
  mov    %rdi,%rax
  test   %rcx,%rcx
  je     L23
  add    %rdi,%rcx
  jmp    L29
  nopl   0x0(%rax)
L21:
  add    $0x1,%rsi
  cmp    %rax,%rcx
  je     L23
L29:
  movsbl (%rsi),%r8d
  add    $0x1,%rax
  mov    %r8b,-0x1(%rax)
  cmp    %edx,%r8d
  jne    L21
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t count) {
  char *a = dst;
  char *b = src;
  while (count--) {
    *a++ = *b;
    if (*b == c) {
      return (void *)a;
    }
    b++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__getrusage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __getrusage(enum __rusage_who who, struct rusage *usage) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__getrusage>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __getrusage(enum __rusage_who who, struct rusage *usage) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__getrusage>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __getrusage(enum __rusage_who who, struct rusage *usage) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__getrusage>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __getrusage(enum __rusage_who who, struct rusage *usage) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tm_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x8(%rbp)
  mov    %r8d,-0x1c(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L18
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <nsrl_print@plt>
  jmp    L8
L18:
  cmpl   $0x2,-0x4(%rbp)
  jne    L14
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <md5sum_print@plt>
  jmp    L8
L14:
  cmpl   $0x3,-0x4(%rbp)
  jne    L8
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <hk_print@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void tm_print(int type, char *db_file, char *hash, off_t db_off, int flags) {
  if (type == 1) {
    nsrl_print(db_file, hash, db_off, flags);
  } else if (type == 2) {
    md5sum_print(db_file, hash, db_off, flags);
  } else if (type == 3) {
    hk_print(db_file, hash, db_off, flags);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tm_print>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  cmp    $0x1,%eax
  je     L56
  cmp    $0x2,%eax
  je     L49
  cmp    $0x3,%eax
  je     L50
L23:
  add    $0x8,%rsp
  ret
L56:
  mov    %r8d,%ecx
  call   <nsrl_print@plt>
  jmp    L23
L49:
  mov    %r8d,%ecx
  call   <md5sum_print@plt>
  jmp    L23
L50:
  mov    %r8d,%ecx
  call   <hk_print@plt>
  jmp    L23
```

assistant: ```c
void tm_print(int type, char *db_file, char *hash, off_t db_off, int flags) {
  if (type == 1) {
    nsrl_print(db_file, hash, db_off, flags);
  } else if (type == 2) {
    md5sum_print(db_file, hash, db_off, flags);
  } else if (type == 3) {
    hk_print(db_file, hash, db_off, flags);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tm_print>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  cmp    $0x1,%eax
  je     L2
  cmp    $0x2,%eax
  je     L0
  cmp    $0x3,%eax
  je     L12
  ret
  xchg   %ax,%ax
L2:
  mov    %r8d,%ecx
  jmp    1070 <nsrl_print@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r8d,%ecx
  jmp    1080 <md5sum_print@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %r8d,%ecx
  jmp    1090 <hk_print@plt>
```

assistant: ```c
void tm_print(int type, char *db_file, char *hash, off_t db_off, int flags) {
  if (type == 1) {
    nsrl_print(db_file, hash, db_off, flags);
  } else if (type == 2) {
    md5sum_print(db_file, hash, db_off, flags);
  } else if (type == 3) {
    hk_print(db_file, hash, db_off, flags);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tm_print>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  cmp    $0x1,%eax
  je     L14
  cmp    $0x2,%eax
  je     L6
  cmp    $0x3,%eax
  je     L5
  ret
  xchg   %ax,%ax
L14:
  mov    %r8d,%ecx
  jmp    1070 <nsrl_print@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r8d,%ecx
  jmp    1080 <md5sum_print@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r8d,%ecx
  jmp    1090 <hk_print@plt>
```

assistant: ```c
void tm_print(int type, char *db_file, char *hash, off_t db_off, int flags) {
  if (type == 1) {
    nsrl_print(db_file, hash, db_off, flags);
  } else if (type == 2) {
    md5sum_print(db_file, hash, db_off, flags);
  } else if (type == 3) {
    hk_print(db_file, hash, db_off, flags);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x1312000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0xd20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1312d14(%rbp)
  jmp    L35
L20:
  mov    -0x1312d14(%rbp),%eax
  cltq
  movl   $0x0,-0x1312d10(%rbp,%rax,4)
  addl   $0x1,-0x1312d14(%rbp)
L35:
  cmpl   $0x4c4b3f,-0x1312d14(%rbp)
  jle    L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
main() {
  int i, a[5000000];
  for (i = 0; i < 5000000; i++) {
    a[i] = 0;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x4c4b40,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int i, a[5000000];
  for (i = 0; i < 5000000; i++) {
    a[i] = 0;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int i, a[5000000];
  for (i = 0; i < 5000000; i++) {
    a[i] = 0;
  }
  return (0);
}
```