ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_sys_cfg_pkt_fwd_ctl_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string

tool: D21: 
Usage : sys_cfg_pkt_fwd_ctl [0|1]


tool: D22: 
Options: 0     - Forward all packets to the host

tool: D15: 
         1     - Firmware handles intra-BSS packets

tool: D12: 
         empty - Get current packet forwarding setting


assistant: ```c
void print_sys_cfg_pkt_fwd_ctl_usage(void) {
  printf("\nUsage : sys_cfg_pkt_fwd_ctl [0|1]\n");
  printf("\nOptions: 0     - Forward all packets to the host");
  printf("\n         1     - Firmware handles intra-BSS packets");
  printf("\n         empty - Get current packet forwarding setting\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_sys_cfg_pkt_fwd_ctl_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D31
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: D31: 
Usage : sys_cfg_pkt_fwd_ctl [0|1]


tool: D6: 
Options: 0     - Forward all packets to the host

tool: D10: 
         1     - Firmware handles intra-BSS packets

tool: D0: 
         empty - Get current packet forwarding setting


assistant: ```c
void print_sys_cfg_pkt_fwd_ctl_usage(void) {
  printf("\nUsage : sys_cfg_pkt_fwd_ctl [0|1]\n");
  printf("\nOptions: 0     - Forward all packets to the host");
  printf("\n         1     - Firmware handles intra-BSS packets");
  printf("\n         empty - Get current packet forwarding setting\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gprs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <gprs_func@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D10: after  define


tool: D2: after the main  gprs_func


assistant: ```c
int gprs(int alarm_type, char *phone_num) {
  printf("after  define\n");
  gprs_func(phone_num, alarm_type);
  printf("after the main  gprs_func\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gprs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <gprs_func@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D5
type: string

tool: D0: after  define


tool: D5: after the main  gprs_func


assistant: ```c
int gprs(int alarm_type, char *phone_num) {
  printf("after  define\n");
  gprs_func(phone_num, alarm_type);
  printf("after the main  gprs_func\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gprs>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D11(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <gprs_func@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D11: after  define


tool: D15: after the main  gprs_func


assistant: ```c
int gprs(int alarm_type, char *phone_num) {
  printf("after  define\n");
  gprs_func(phone_num, alarm_type);
  printf("after the main  gprs_func\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gprs>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D8(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <gprs_func@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string

tool: D8: after  define


tool: D7: after the main  gprs_func


assistant: ```c
int gprs(int alarm_type, char *phone_num) {
  printf("after  define\n");
  gprs_func(phone_num, alarm_type);
  printf("after the main  gprs_func\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parity5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L38:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x10,-0xc(%rbp)
  jmp    L22
L1:
  mov    -0xc(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
L22:
  cmpl   $0x0,-0xc(%rbp)
  jg     L1
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int parity5(unsigned *array, int len) {
  int i, j, val, result = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    result += x & 0x01;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parity5>:
  endbr64
  test   %esi,%esi
  jle    L45
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
  mov    $0x0,%edi
  mov    $0x10,%r9d
  jmp    L44
L43:
  and    $0x1,%eax
  add    %eax,%edi
  add    $0x4,%r8
  cmp    %r10,%r8
  je     L21
L44:
  mov    (%r8),%eax
  mov    $0x5,%edx
  mov    %r9d,%ecx
L22:
  mov    %eax,%esi
  shr    %cl,%esi
  xor    %esi,%eax
  mov    %ecx,%esi
  shr    $0x1f,%esi
  add    %esi,%ecx
  sar    %ecx
  sub    $0x1,%edx
  jne    L22
  jmp    L43
L45:
  mov    $0x0,%edi
L21:
  mov    %edi,%eax
  ret
```

assistant: ```c
int parity5(unsigned *array, int len) {
  int i, j, val, result = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    result += x & 0x01;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parity5>:
  endbr64
  test   %esi,%esi
  jle    L26
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%r9
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rdi),%eax
  mov    $0x5,%edx
  mov    $0x10,%ecx
L5:
  mov    %eax,%esi
  shr    %cl,%esi
  sar    %ecx
  xor    %esi,%eax
  sub    $0x1,%edx
  jne    L5
  and    $0x1,%eax
  add    $0x4,%rdi
  add    %eax,%r8d
  cmp    %rdi,%r9
  jne    L10
  mov    %r8d,%eax
  ret
L26:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity5(unsigned *array, int len) {
  int i, j, val, result = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    result += x & 0x01;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parity5>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  shr    %edx
  xor    %edx,%eax
  and    $0x1,%eax
  add    %eax,%r8d
  cmp    %rdi,%rcx
  jne    L18
  mov    %r8d,%eax
  ret
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity5(unsigned *array, int len) {
  int i, j, val, result = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    result += x & 0x01;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %edi,-0xfc4(%rbp)
  mov    %rsi,-0xfd0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfb8(%rbp)
  jmp    L52
L48:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb8(%rbp),%edx
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfb8(%rbp)
L52:
  cmpl   $0x3e7,-0xfb8(%rbp)
  jle    L48
  movl   $0x0,-0xfb4(%rbp)
  jmp    L19
L46:
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,-0xfb4(%rbp)
  je     L28
  mov    $0x0,%eax
  call   <abort@plt>
L28:
  addl   $0x1,-0xfb4(%rbp)
L19:
  cmpl   $0x3e7,-0xfb4(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c[1000];
#pragma omp parallel for
  for (int i = 0; i < 1000; i++) {
    c[i] = i;
  }
  {
    int i;
    for (i = 0; i < 1000; i++) {
      if (c[i] != i)
        abort();
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
L6:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L6
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L36
L54:
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  je     L13
L36:
  cmp    %ebx,0x0(%rbp,%rbx,4)
  je     L54
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L54
L13:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c[1000];
#pragma omp parallel for
  for (int i = 0; i < 1000; i++) {
    c[i] = i;
  }
  {
    int i;
    for (i = 0; i < 1000; i++) {
      if (c[i] != i)
        abort();
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L5
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  cmp    %ebx,0x0(%rbp,%rbx,4)
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  jne    L12
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0xfb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c[1000];
#pragma omp parallel for
  for (int i = 0; i < 1000; i++) {
    c[i] = i;
  }
  {
    int i;
    for (i = 0; i < 1000; i++) {
      if (c[i] != i)
        abort();
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  movdqa D7(%rip),%xmm0
  movdqa D11(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xfa0(%rsp),%rdx
  mov    %rbp,%rax
  xchg   %ax,%ax
L28:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L28
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    %ebx,0x0(%rbp,%rbx,4)
  je     L39
  xor    %eax,%eax
  call   <abort@plt>
L39:
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  jne    L0
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xfb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D11
data_type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  int c[1000];
#pragma omp parallel for
  for (int i = 0; i < 1000; i++) {
    c[i] = i;
  }
  {
    int i;
    for (i = 0; i < 1000; i++) {
      if (c[i] != i)
        abort();
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fault_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  leave
  ret
```

assistant: ```c
int fault_function() {
  char *x = (char *)malloc(10 * sizeof(char));
  free(x);
  return x[5];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fault_function>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  movsbl 0x5(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int fault_function() {
  char *x = (char *)malloc(10 * sizeof(char));
  free(x);
  return x[5];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fault_function>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  movsbl 0x5(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int fault_function() {
  char *x = (char *)malloc(10 * sizeof(char));
  free(x);
  return x[5];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fault_function>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  movsbl 0x5(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int fault_function() {
  char *x = (char *)malloc(10 * sizeof(char));
  free(x);
  return x[5];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %rdx,-0x60(%rbp)
  mov    %ecx,-0x64(%rbp)
  mov    %r8d,-0x68(%rbp)
  mov    %r9,-0x70(%rbp)
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x68(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x68(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x48(%rbp)
  jmp    L38
L43:
  movl   $0x0,-0x40(%rbp)
  jmp    L50
L17:
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L2
L10:
  mov    -0x48(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%edi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%r8
  movslq %edx,%rsi
  imul   %r8,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    -0x70(%rbp),%rsi
  add    %rsi,%r8
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  mov    (%r8,%rsi,4),%esi
  imul   %edi,%esi
  add    %esi,-0x44(%rbp)
  addl   $0x1,-0x3c(%rbp)
L2:
  mov    -0x3c(%rbp),%esi
  cmp    -0x64(%rbp),%esi
  jl     L10
  mov    -0x48(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    0x10(%rbp),%rsi
  lea    (%rdi,%rsi,1),%r8
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  mov    -0x44(%rbp),%edi
  mov    %edi,(%r8,%rsi,4)
  addl   $0x1,-0x40(%rbp)
L50:
  mov    -0x40(%rbp),%esi
  cmp    -0x68(%rbp),%esi
  jl     L17
  addl   $0x1,-0x48(%rbp)
L38:
  mov    -0x48(%rbp),%esi
  cmp    -0x54(%rbp),%esi
  jl     L43
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply(int row_1, int col_1, int matrix_1[row_1][col_1], int row_2, int col_2, int matrix_2[row_2][col_2], int res[row_1][col_2]) {
  int r = 0;
  int sum, c;
  while (r < row_1) {
    c = 0;
    while (c < col_2) {
      sum = 0;
      for (int r_inner = 0; r_inner < row_2; ++r_inner)
        sum += matrix_1[r][r_inner] * matrix_2[r_inner][c];
      res[r][c] = sum;
      c++;
    }
    r++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x4(%rsp)
  test   %edi,%edi
  jle    L44
  mov    %rdx,%rax
  mov    %ecx,%ebx
  mov    %r8d,%r14d
  mov    %r9,%rbp
  movslq %esi,%rsi
  movslq %r8d,%r8
  shl    $0x2,%r8
  mov    0x38(%rsp),%r15
  lea    0x0(,%rsi,4),%rdi
  mov    %rdi,-0x10(%rsp)
  mov    %rdx,%r10
  lea    -0x1(%rcx),%edx
  lea    0x4(%rax,%rdx,4),%rdi
  lea    -0x1(%r14),%eax
  lea    0x4(,%rax,4),%r12
  mov    $0x0,%r13d
  jmp    L55
L66:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    %edx,%esi
  add    $0x4,%rax
  add    %r8,%rcx
  cmp    %rdi,%rax
  jne    L66
L88:
  mov    %esi,(%r11,%r9,1)
  add    $0x4,%r9
  cmp    %r12,%r9
  je     L19
L82:
  lea    0x0(%rbp,%r9,1),%rcx
  mov    %r10,%rax
  mov    $0x0,%esi
  test   %ebx,%ebx
  jg     L66
  jmp    L88
L19:
  add    $0x1,%r13d
  add    %r8,%r15
  mov    -0x10(%rsp),%rax
  add    %rax,%r10
  add    %rax,%rdi
  cmp    %r13d,-0x4(%rsp)
  je     L44
L55:
  test   %r14d,%r14d
  jle    L19
  mov    %r15,%r11
  mov    $0x0,%r9d
  jmp    L82
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void multiply(int row_1, int col_1, int matrix_1[row_1][col_1], int row_2, int col_2, int matrix_2[row_2][col_2], int res[row_1][col_2]) {
  int r = 0;
  int sum, c;
  while (r < row_1) {
    c = 0;
    while (c < col_2) {
      sum = 0;
      for (int r_inner = 0; r_inner < row_2; ++r_inner)
        sum += matrix_1[r][r_inner] * matrix_2[r_inner][c];
      res[r][c] = sum;
      c++;
    }
    r++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x4(%rsp)
  test   %edi,%edi
  jle    L2
  movslq %r8d,%r8
  lea    -0x1(%rcx),%eax
  movslq %esi,%rsi
  mov    0x38(%rsp),%r11
  mov    %r8,%r14
  lea    0x4(%rdx,%rax,4),%rdi
  mov    %rdx,%r10
  mov    %ecx,%ebx
  lea    -0x1(%r14),%eax
  mov    %r9,%rbp
  shl    $0x2,%r8
  xor    %r13d,%r13d
  lea    0x0(,%rsi,4),%r15
  lea    0x4(,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L58:
  test   %r14d,%r14d
  jle    L54
  xor    %r9d,%r9d
L9:
  lea    0x0(%rbp,%r9,1),%rcx
  mov    %r10,%rax
  xor    %esi,%esi
  test   %ebx,%ebx
  jle    L4
  xchg   %ax,%ax
L26:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    $0x4,%rax
  add    %r8,%rcx
  add    %edx,%esi
  cmp    %rdi,%rax
  jne    L26
L4:
  mov    %esi,(%r11,%r9,1)
  add    $0x4,%r9
  cmp    %r12,%r9
  jne    L9
L54:
  add    $0x1,%r13d
  add    %r8,%r11
  add    %r15,%r10
  add    %r15,%rdi
  cmp    %r13d,-0x4(%rsp)
  jne    L58
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void multiply(int row_1, int col_1, int matrix_1[row_1][col_1], int row_2, int col_2, int matrix_2[row_2][col_2], int res[row_1][col_2]) {
  int r = 0;
  int sum, c;
  while (r < row_1) {
    c = 0;
    while (c < col_2) {
      sum = 0;
      for (int r_inner = 0; r_inner < row_2; ++r_inner)
        sum += matrix_1[r][r_inner] * matrix_2[r_inner][c];
      res[r][c] = sum;
      c++;
    }
    r++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply>:
  endbr64
  mov    %edi,%r11d
  test   %edi,%edi
  jle    L50
  movslq %r8d,%rdi
  test   %edi,%edi
  jle    L50
  push   %r14
  movslq %esi,%rsi
  lea    -0x1(%rcx),%eax
  mov    %rdx,%r10
  push   %r13
  shl    $0x2,%rdi
  lea    0x4(%rdx,%rax,4),%r8
  xor    %r13d,%r13d
  push   %r12
  lea    0x0(,%rsi,4),%r14
  mov    %r9,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    0x30(%rsp),%rbx
  nopl   0x0(%rax)
L17:
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L21:
  lea    (%r12,%r9,1),%rcx
  mov    %r10,%rax
  xor    %esi,%esi
  test   %ebp,%ebp
  jle    L3
  nopl   (%rax)
L58:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    $0x4,%rax
  add    %rdi,%rcx
  add    %edx,%esi
  cmp    %r8,%rax
  jne    L58
L3:
  mov    %esi,(%rbx,%r9,1)
  add    $0x4,%r9
  cmp    %r9,%rdi
  jne    L21
  add    $0x1,%r13d
  add    %rdi,%rbx
  add    %r14,%r10
  add    %r14,%r8
  cmp    %r13d,%r11d
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  ret
```

assistant: ```c
void multiply(int row_1, int col_1, int matrix_1[row_1][col_1], int row_2, int col_2, int matrix_2[row_2][col_2], int res[row_1][col_2]) {
  int r = 0;
  int sum, c;
  while (r < row_1) {
    c = 0;
    while (c < col_2) {
      sum = 0;
      for (int r_inner = 0; r_inner < row_2; ++r_inner)
        sum += matrix_1[r][r_inner] * matrix_2[r_inner][c];
      res[r][c] = sum;
      c++;
    }
    r++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L83:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0xc(%rbp)
  je     L88
L24:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L98
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L83
  jmp    L98
L88:
  nop
L98:
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L53
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L55
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L53
  mov    $0x0,%eax
  jmp    L67
L55:
  mov    $0x0,%eax
  jmp    L67
L53:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L67:
  leave
  ret
```

assistant: ```c
char *fgets(char *s, int n, FILE *stream) {
  int ch = EOF;
  char *ptr;
  ptr = s;
  while (--n > 0 && (ch = getc(stream)) != EOF) {
    *ptr++ = ch;
    if (ch == '\n')
      break;
  }
  if (ch == EOF) {
    if (feof(stream)) {
      if (ptr == s)
        return (NULL);
    } else
      return (NULL);
  }
  *ptr = '\0';
  return (s);
}
```