ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initMatrixInt>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r13
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  push   %r12
  lea    0x8(%rdi,%rax,8),%r13
  lea    0x0(,%rsi,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <random@plt>
  mov    0x0(%rbp),%rdx
  mov    %eax,(%rdx,%rbx,1)
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L3
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void initMatrixInt(int **m, int size) {
  int i = 0;
  int j = 0;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      m[i][j] = (int)random();
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<other_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L91
L8:
  mov    -0x10(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L42
  subq   $0x8,-0x10(%rbp)
L91:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L8
  jmp    L79
L42:
  nop
L79:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L5
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L29
L5:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  cmp    %rax,-0x8(%rbp)
  jae    L54
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L54
L94:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x8,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L94
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L72
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L72:
  nop
L29:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D34
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string

tool: D34: -all-zero

tool: D10: -unknown

tool: D5: .%02X

tool: D36: .00...

assistant: ```c
void other_print(u_char *bp, int length) {
  u_char *ep;
  u_char *zp;
  ep = bp + length;
  for (zp = ep; zp > bp; zp--) {
    if (zp[-1] != 0)
      break;
  }
  if (zp == bp) {
    printf("-all-zero");
    return;
  }
  printf("-unknown");
  if (zp + 2 > ep)
    zp = ep;
  while (bp < zp) {
    printf(".%02X", *bp);
    bp++;
  }
  if (zp < ep)
    printf(".00...");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<other_print>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%r13
  cmp    %r13,%rdi
  jae    L85
  mov    %r13,%rbx
L6:
  cmpq   $0x0,-0x8(%rbx)
  jne    L128
  sub    $0x8,%rbx
  cmp    %rbx,%rbp
  jb     L6
L128:
  cmp    %rbx,%rbp
  je     L59
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rbx),%rax
  cmp    %rax,%r13
  jb     L120
  cmp    %rbx,%rbp
  jae    L98
L31:
  lea    D9(%rip),%r12
L105:
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbp
  cmp    %rbp,%rbx
  ja     L105
L98:
  cmp    %r13,%rbx
  jb     L4
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L85:
  mov    %r13,%rbx
  jmp    L128
L59:
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L4:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L120:
  mov    %r13,%rbx
  cmp    %r13,%rbp
  jb     L31
  jmp    L12
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D38
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D7: -unknown

tool: D9: .%02X

tool: D38: -all-zero

tool: D16: .00...

assistant: ```c
void other_print(u_char *bp, int length) {
  u_char *ep;
  u_char *zp;
  ep = bp + length;
  for (zp = ep; zp > bp; zp--) {
    if (zp[-1] != 0)
      break;
  }
  if (zp == bp) {
    printf("-all-zero");
    return;
  }
  printf("-unknown");
  if (zp + 2 > ep)
    zp = ep;
  while (bp < zp) {
    printf(".%02X", *bp);
    bp++;
  }
  if (zp < ep)
    printf(".00...");
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<other_print>:
  endbr64
  push   %r13
  movslq %esi,%rsi
  push   %r12
  lea    (%rdi,%rsi,8),%r13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r13,%rbx
  sub    $0x8,%rsp
  cmp    %r13,%rdi
  jb     L73
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L96:
  sub    $0x8,%rbx
  cmp    %rbx,%rbp
  jae    L37
L73:
  cmpq   $0x0,-0x8(%rbx)
  je     L96
L37:
  lea    D7(%rip),%rdi
  cmp    %rbx,%rbp
  je     L16
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rbx),%rax
  cmp    %rax,%r13
  jb     L62
  cmp    %rbx,%rbp
  jae    L2
L76:
  lea    D24(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L33:
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %rbp,%rbx
  ja     L33
L2:
  cmp    %r13,%rbx
  jb     L36
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %r13,%rbx
  cmp    %r13,%rbp
  jb     L76
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L36:
  lea    D36(%rip),%rdi
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string

tool: D7: -all-zero

tool: D35: -unknown

tool: D24: .%02X

tool: D36: .00...

assistant: ```c
void other_print(u_char *bp, int length) {
  u_char *ep;
  u_char *zp;
  ep = bp + length;
  for (zp = ep; zp > bp; zp--) {
    if (zp[-1] != 0)
      break;
  }
  if (zp == bp) {
    printf("-all-zero");
    return;
  }
  printf("-unknown");
  if (zp + 2 > ep)
    zp = ep;
  while (bp < zp) {
    printf(".%02X", *bp);
    bp++;
  }
  if (zp < ep)
    printf(".00...");
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<other_print>:
  endbr64
  push   %r13
  movslq %esi,%rsi
  push   %r12
  lea    (%rdi,%rsi,8),%r13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r13,%rbx
  sub    $0x8,%rsp
  cmp    %r13,%rdi
  jb     L53
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L86:
  sub    $0x8,%rbx
  cmp    %rbx,%rbp
  jae    L69
L53:
  cmpq   $0x0,-0x8(%rbx)
  je     L86
L69:
  lea    D11(%rip),%rdi
  cmp    %rbx,%rbp
  je     L107
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rbx),%rax
  cmp    %rax,%r13
  jb     L15
  cmp    %rbx,%rbp
  jae    L46
L58:
  lea    D16(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L71:
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %rbp,%rbx
  ja     L71
L46:
  cmp    %r13,%rbx
  jb     L48
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r13,%rbx
  cmp    %r13,%rbp
  jb     L58
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L48:
  lea    D36(%rip),%rdi
L107:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D16
type_infered: string
name: extract_symbolic_data
arguments: tag: D36
type_infered: string

tool: D11: -all-zero

tool: D13: -unknown

tool: D16: .%02X

tool: D36: .00...

assistant: ```c
void other_print(u_char *bp, int length) {
  u_char *ep;
  u_char *zp;
  ep = bp + length;
  for (zp = ep; zp > bp; zp--) {
    if (zp[-1] != 0)
      break;
  }
  if (zp == bp) {
    printf("-all-zero");
    return;
  }
  printf("-unknown");
  if (zp + 2 > ep)
    zp = ep;
  while (bp < zp) {
    printf(".%02X", *bp);
    bp++;
  }
  if (zp < ep)
    printf(".00...");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foster_1981>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: f64
name: extract_symbolic_data
arguments: data_label: D13
data_type: f64
name: extract_symbolic_data
arguments: data_label: D2
data_type: f64

tool: D1: 0.276

tool: D13: 75

tool: D2: 100

assistant: ```c
double foster_1981(double annual_pmm) {
  double result;
  result = ((annual_pmm * 0.276 * 75.0) / 100.0);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foster_1981>:
  endbr64
  mulsd  D8(%rip),%xmm0
  mulsd  D5(%rip),%xmm0
  divsd  D12(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: f64
name: unpack_data
arguments: tag: D5
data_type: f64
name: unpack_data
arguments: tag: D12
data_type: f64

tool: D8: 0.276

tool: D5: 75

tool: D12: 100

assistant: ```c
double foster_1981(double annual_pmm) {
  double result;
  result = ((annual_pmm * 0.276 * 75.0) / 100.0);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foster_1981>:
  endbr64
  mulsd  D22(%rip),%xmm0
  mulsd  D1(%rip),%xmm0
  divsd  D23(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_infered: f64
name: retrieve_data
arguments: data_label: D1
type_infered: f64
name: retrieve_data
arguments: data_label: D23
type_infered: f64

tool: D22: 0.276

tool: D1: 75

tool: D23: 100

assistant: ```c
double foster_1981(double annual_pmm) {
  double result;
  result = ((annual_pmm * 0.276 * 75.0) / 100.0);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<foster_1981>:
  endbr64
  mulsd  D14(%rip),%xmm0
  mulsd  D15(%rip),%xmm0
  divsd  D11(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: f64
name: retrieve_data
arguments: label: D15
type_infered: f64
name: retrieve_data
arguments: label: D11
type_infered: f64

tool: D14: 0.276

tool: D15: 75

tool: D11: 100

assistant: ```c
double foster_1981(double annual_pmm) {
  double result;
  result = ((annual_pmm * 0.276 * 75.0) / 100.0);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x88(%rbp)
  jmp    L79
L115:
  mov    -0x88(%rbp),%eax
  cltq
  movl   $0x0,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x88(%rbp)
L79:
  cmpl   $0x18,-0x88(%rbp)
  jle    L115
  movl   $0x0,-0x80(%rbp)
  mov    -0x80(%rbp),%eax
  mov    %eax,-0x84(%rbp)
  movl   $0x0,-0x78(%rbp)
  mov    -0x78(%rbp),%eax
  mov    %eax,-0x7c(%rbp)
  jmp    L51
L62:
  addl   $0x1,-0x80(%rbp)
  cmpl   $0x20,-0x74(%rbp)
  je     L63
  cmpl   $0xa,-0x74(%rbp)
  je     L63
  cmpl   $0x9,-0x74(%rbp)
  jne    L51
L63:
  mov    -0x80(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x84(%rbp),%eax
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x84(%rbp)
  movl   $0x0,-0x80(%rbp)
L51:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x74(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x74(%rbp)
  jne    L62
  movl   $0x14,-0x7c(%rbp)
  jmp    L82
L37:
  movl   $0x0,-0x78(%rbp)
  jmp    L66
L70:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  cmp    %eax,-0x7c(%rbp)
  jg     L43
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L92
L43:
  mov    $0x20,%edi
  call   <putchar@plt>
L92:
  addl   $0x1,-0x78(%rbp)
L66:
  mov    -0x78(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jle    L70
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x7c(%rbp)
L82:
  cmpl   $0x0,-0x7c(%rbp)
  jg     L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
main() {
  int words[25];
  int c, i, nw, nc;
  int row, col;
  for (i = 0; i < 25; ++i)
    words[i] = 0;
  nw = nc = 0;
  row = col = 0;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ' || c == '\n' || c == '\t') {
      words[nw] = nc - 1;
      ++nw;
      nc = 0;
    }
  }
  for (row = 20; row >= 1; --row) {
    for (col = 0; col <= nw; ++col) {
      if (row <= words[col])
        putchar('*');
      else
        putchar(' ');
    }
    putchar('\n');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x64(%rsp),%rdx
L68:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L68
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L45
L72:
  mov    %ebp,(%rsp,%rbx,4)
  add    $0x1,%rbx
L45:
  mov    %ebx,%r12d
  mov    %r13d,%ebp
L97:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L112
  lea    0x1(%rbp),%ecx
  lea    -0x9(%rax),%edx
  cmp    $0x1,%edx
  jbe    L72
  cmp    $0x20,%eax
  je     L72
  mov    %ecx,%ebp
  jmp    L97
L112:
  mov    $0x14,%ebp
  mov    %rsp,%r13
  jmp    L127
L13:
  mov    $0x20,%edi
  call   <putchar@plt>
L85:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L74
L48:
  cmp    %ebp,0x0(%r13,%rbx,4)
  jl     L13
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L85
L74:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L79
L127:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jns    L48
  jmp    L74
L79:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int words[25];
  int c, i, nw, nc;
  int row, col;
  for (i = 0; i < 25; ++i)
    words[i] = 0;
  nw = nc = 0;
  row = col = 0;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ' || c == '\n' || c == '\t') {
      words[nw] = nc - 1;
      ++nw;
      nc = 0;
    }
  }
  for (row = 20; row >= 1; --row) {
    for (col = 0; col <= nw; ++col) {
      if (row <= words[col])
        putchar('*');
      else
        putchar(' ');
    }
    putchar('\n');
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xc,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    D7(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  nopl   (%rax)
L109:
  xor    %eax,%eax
  xor    %r14d,%r14d
  mov    %ebx,%r13d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  je     L61
L77:
  lea    -0x9(%rax),%edx
  lea    0x1(%r14),%ecx
  cmp    $0x1,%edx
  jbe    L74
  cmp    $0x20,%eax
  je     L74
  xor    %eax,%eax
  mov    %ecx,%r14d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L77
L61:
  mov    $0x14,%ebp
  nop
L99:
  xor    %ebx,%ebx
  jmp    L42
  nopl   0x0(%rax)
L33:
  mov    $0x2a,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jl     L26
L42:
  cmp    %ebp,(%r12,%rbx,4)
  jge    L33
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jge    L42
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L99
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %r14d,(%r12,%rbx,4)
  add    $0x1,%rbx
  jmp    L109
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int words[25];
  int c, i, nw, nc;
  int row, col;
  for (i = 0; i < 25; ++i)
    words[i] = 0;
  nw = nc = 0;
  row = col = 0;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ' || c == '\n' || c == '\t') {
      words[nw] = nc - 1;
      ++nw;
      nc = 0;
    }
  }
  for (row = 20; row >= 1; --row) {
    for (col = 0; col <= nw; ++col) {
      if (row <= words[col])
        putchar('*');
      else
        putchar(' ');
    }
    putchar('\n');
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xc,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    D1(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  nopl   (%rax)
L21:
  xor    %eax,%eax
  xor    %r14d,%r14d
  mov    %ebx,%r13d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  je     L13
L53:
  lea    -0x9(%rax),%edx
  lea    0x1(%r14),%ecx
  cmp    $0x1,%edx
  jbe    L15
  cmp    $0x20,%eax
  je     L15
  xor    %eax,%eax
  mov    %ecx,%r14d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L53
L13:
  mov    $0x14,%ebp
  nop
L86:
  xor    %ebx,%ebx
  jmp    L38
  nopl   0x0(%rax)
L3:
  mov    $0x2a,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jl     L49
L38:
  cmp    %ebp,(%r12,%rbx,4)
  jge    L3
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jge    L38
L49:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L86
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r14d,(%r12,%rbx,4)
  add    $0x1,%rbx
  jmp    L21
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int words[25];
  int c, i, nw, nc;
  int row, col;
  for (i = 0; i < 25; ++i)
    words[i] = 0;
  nw = nc = 0;
  row = col = 0;
  while ((c = getchar()) != EOF) {
    ++nc;
    if (c == ' ' || c == '\n' || c == '\t') {
      words[nw] = nc - 1;
      ++nw;
      nc = 0;
    }
  }
  for (row = 20; row >= 1; --row) {
    for (col = 0; col <= nw; ++col) {
      if (row <= words[col])
        putchar('*');
      else
        putchar(' ');
    }
    putchar('\n');
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L9:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L3:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L9
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  unsigned char *s1 = (unsigned char *)s;
  while (n--)
    *s1++ = c;
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L0
  add    %rdi,%rdx
  mov    %rdi,%rcx
L1:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L1
L0:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  unsigned char *s1 = (unsigned char *)s;
  while (n--)
    *s1++ = c;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L4
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  unsigned char *s1 = (unsigned char *)s;
  while (n--)
    *s1++ = c;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L0
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  unsigned char *s1 = (unsigned char *)s;
  while (n--)
    *s1++ = c;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L45
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L23
L45:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L18
L23:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L15
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L18:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L15:
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L13
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L50
L5:
  mov    -0x4(%rbp),%eax
L50:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: Invalid input!

assistant: ```c
int my_atoi(char num[]) {
  int i;
  int n;
  n = 0;
  for (i = 0; i < str_len(num); i++) {
    if (((num[i] >= '0') && (num[i] <= '9')) || (num[i] == '-')) {
      if (num[i] != '-') {
        n = n * 10 + (num[i] - '0');
      }
    } else {
      printf("Invalid input!");
      exit(0);
    }
  }
  if (num[0] == '-') {
    return (~(n) + 1);
  } else {
    return n;
  }
}
```