ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<gr_filename>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rcx),%r14
  test   %r14,%r14
  je     L60
  mov    %rdi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    $0xffffffff,%r13d
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L66:
  mov    (%rbx),%rdi
  call   <strdup@plt>
L67:
  add    $0x8,%rbx
  mov    %rax,(%r15)
  add    $0x8,%r15
  mov    (%rbx),%r14
  test   %r14,%r14
  je     L2
L61:
  cmpb   $0x7b,(%r14)
  jne    L66
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x7d,-0x1(%r14,%rax,1)
  jne    L66
  mov    (%rbx),%rdi
  xor    %eax,%eax
  cmpb   $0x21,0x1(%rdi)
  sete   %al
  mov    %eax,0x0(%rbp)
  call   <strlen@plt>
  mov    0x0(%rbp),%ecx
  lea    -0x2(%rax),%edx
  sub    %ecx,%edx
  test   %edx,%edx
  jle    L5
  lea    0x1(%rcx),%esi
  mov    %r12,%rdi
  mov    $0x1,%r13d
  movslq %esi,%rsi
  add    (%rbx),%rsi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  jmp    L67
  nopl   0x0(%rax)
L60:
  mov    $0xffffffff,%r13d
L2:
  movq   $0x0,(%r15)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L5:
  lea    D6(%rip),%rdi
  xor    %r13d,%r13d
  call   <strdup@plt>
  jmp    L67
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: /tmp/default

assistant: ```c
int gr_filename(char *filename, char **outargs, int *force, char **inargs) {
  int fnlen = 0;
  int offset = 1;
  int returnv = -1;
  char **pain = inargs;
  char **paout = outargs;
  while (*pain) {
    if ((*pain)[0] == '{' && (*pain)[strlen(*pain) - 1] == '}') {
      if ((*pain)[1] == '!')
        *force = 1;
      else
        *force = 0;
      fnlen = strlen(*pain) - 2 - *force;
      offset = 1 + *force;
      if (fnlen <= 0) {
        *paout = strdup("/tmp/default");
        returnv = 0;
      } else {
        strncpy(filename, *pain + offset, fnlen);
        *paout = strdup(filename);
        returnv = 1;
      }
    } else
      *paout = strdup(*pain);
    paout++;
    pain++;
  }
  *paout = NULL;
  return returnv;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gr_filename>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rcx),%rbp
  test   %rbp,%rbp
  je     L62
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%r14
  mov    $0xffffffff,%r13d
  jmp    L71
  xchg   %ax,%ax
L47:
  mov    %rbp,%rdi
  call   <strdup@plt>
L55:
  add    $0x8,%r14
  mov    %rax,(%r15)
  add    $0x8,%r15
  mov    (%r14),%rbp
  test   %rbp,%rbp
  je     L24
L71:
  cmpb   $0x7b,0x0(%rbp)
  jne    L47
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x7d,-0x1(%rbp,%rax,1)
  je     L33
  mov    (%r14),%rbp
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L62:
  mov    $0xffffffff,%r13d
L24:
  movq   $0x0,(%r15)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L33:
  mov    (%r14),%rdi
  xor    %eax,%eax
  cmpb   $0x21,0x1(%rdi)
  sete   %al
  mov    %eax,(%rbx)
  call   <strlen@plt>
  mov    (%rbx),%esi
  lea    -0x2(%rax),%edx
  sub    %esi,%edx
  test   %edx,%edx
  jle    L29
  add    $0x1,%esi
  mov    %r12,%rdi
  mov    $0x1,%r13d
  movslq %esi,%rsi
  add    (%r14),%rsi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L29:
  lea    D7(%rip),%rdi
  xor    %r13d,%r13d
  call   <strdup@plt>
  jmp    L55
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: /tmp/default

assistant: ```c
int gr_filename(char *filename, char **outargs, int *force, char **inargs) {
  int fnlen = 0;
  int offset = 1;
  int returnv = -1;
  char **pain = inargs;
  char **paout = outargs;
  while (*pain) {
    if ((*pain)[0] == '{' && (*pain)[strlen(*pain) - 1] == '}') {
      if ((*pain)[1] == '!')
        *force = 1;
      else
        *force = 0;
      fnlen = strlen(*pain) - 2 - *force;
      offset = 1 + *force;
      if (fnlen <= 0) {
        *paout = strdup("/tmp/default");
        returnv = 0;
      } else {
        strncpy(filename, *pain + offset, fnlen);
        *paout = strdup(filename);
        returnv = 1;
      }
    } else
      *paout = strdup(*pain);
    paout++;
    pain++;
  }
  *paout = NULL;
  return returnv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x6,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x9,%ebx
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L13
L18:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
L13:
  cmpl   $0x0,-0x24(%rbp)
  jne    L18
  movslq %ebx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *itoa(int number) {
  char *buffer = malloc(6);
  int register i = 9;
  buffer[i--] = '\0';
  while (number) {
    buffer[i--] = number - (number / 10) * 10 + 48;
    number /= 10;
  }
  return buffer + i + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x6,%edi
  call   <malloc@plt>
  movb   $0x0,0x9(%rax)
  test   %ebx,%ebx
  je     L13
  mov    $0x7,%ecx
L28:
  mov    %ecx,%edi
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ebx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rax,%rcx,1)
  mov    %edx,%ebx
  sub    $0x1,%rcx
  test   %edx,%edx
  jne    L28
L23:
  add    $0x1,%edi
  movslq %edi,%rdi
  add    %rdi,%rax
  pop    %rbx
  ret
L13:
  mov    $0x8,%edi
  jmp    L23
```

assistant: ```c
char *itoa(int number) {
  char *buffer = malloc(6);
  int register i = 9;
  buffer[i--] = '\0';
  while (number) {
    buffer[i--] = number - (number / 10) * 10 + 48;
    number /= 10;
  }
  return buffer + i + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itoa>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x6,%edi
  call   <malloc@plt>
  movb   $0x0,0x9(%rax)
  test   %ebx,%ebx
  je     L2
  add    $0x8,%rax
  nopl   (%rax)
L3:
  movslq %ebx,%rdx
  mov    %ebx,%ecx
  mov    %rax,%r8
  sub    $0x1,%rax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rax)
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L3
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  lea    0x9(%rax),%r8
  pop    %rbx
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int number) {
  char *buffer = malloc(6);
  int register i = 9;
  buffer[i--] = '\0';
  while (number) {
    buffer[i--] = number - (number / 10) * 10 + 48;
    number /= 10;
  }
  return buffer + i + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x6,%edi
  call   <malloc@plt>
  movb   $0x0,0x9(%rax)
  test   %ebx,%ebx
  je     L15
  add    $0x8,%rax
  nopl   (%rax)
L4:
  movslq %ebx,%rdx
  mov    %ebx,%ecx
  mov    %rax,%r8
  sub    $0x1,%rax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rax)
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L4
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L15:
  lea    0x9(%rax),%r8
  pop    %rbx
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int number) {
  char *buffer = malloc(6);
  int register i = 9;
  buffer[i--] = '\0';
  while (number) {
    buffer[i--] = number - (number / 10) * 10 + 48;
    number /= 10;
  }
  return buffer + i + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_long@plt>
  test   %rax,%rax
  je     L17
  mov    $0xffffffff,%eax
  jmp    L16
L17:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int read_uid(const char *str, uid_t *uid_p) {
  long val;
  if (read_long(str, &val) != 0) {
    return -1;
  }
  *uid_p = (uid_t)val;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_uid>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <read_long@plt>
  test   %rax,%rax
  jne    L15
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x0,%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L25
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_uid(const char *str, uid_t *uid_p) {
  long val;
  if (read_long(str, &val) != 0) {
    return -1;
  }
  *uid_p = (uid_t)val;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_uid>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <read_long@plt>
  test   %rax,%rax
  jne    L9
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  jmp    L4
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_uid(const char *str, uid_t *uid_p) {
  long val;
  if (read_long(str, &val) != 0) {
    return -1;
  }
  *uid_p = (uid_t)val;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_uid>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <read_long@plt>
  test   %rax,%rax
  jne    L27
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%eax
  jmp    L19
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_uid(const char *str, uid_t *uid_p) {
  long val;
  if (read_long(str, &val) != 0) {
    return -1;
  }
  *uid_p = (uid_t)val;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lineout>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebp
  movslq %esi,%rax
  add    %rdi,%rax
  mov    %rax,%rbx
  sub    %eax,%ebp
L33:
  lea    0x0(%rbp,%rbx,1),%r12d
  mov    %rbx,%r13
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L33
  cmpb   $0x0,0x0(%r13)
  jne    L85
L50:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    $0x12,%ebx
  movslq %r12d,%rbp
  add    %r14,%rbp
  cmp    $0x11,%eax
  jle    L16
L24:
  mov    %ebx,%r15d
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  not    %eax
  shr    $0x1f,%eax
  test   %rdx,%rdx
  sete   %dl
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L24
  test   %r15d,%r15d
  js     L100
  mov    %r13,%rcx
  mov    %r15d,%edx
  mov    $0x12,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printw@plt>
  lea    0x1(%r15,%r12,1),%r12d
  jmp    L50
L16:
  mov    %r13,%rdx
  mov    $0x12,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printw@plt>
  add    %r15d,%r12d
  jmp    L50
L100:
  mov    %r13,%rdx
  mov    $0x12,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printw@plt>
  add    $0x12,%r12d
  movslq %r12d,%rax
  add    %rax,%r14
  movzbl (%r14),%edi
  test   %dil,%dil
  je     L50
L54:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L50
  add    $0x1,%r12d
  add    $0x1,%r14
  movzbl (%r14),%edi
  test   %dil,%dil
  jne    L54
  jmp    L50
```

tool_calls: name: parse_data
arguments: label: D21
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string

tool: D21: %*.*s

tool: D28: %*s

tool: D26: %.*s

assistant: ```c
int lineout(char const *str, int index) {
  int n;
  while (isspace(str[index]))
    ++index;
  if (str[index]) {
    n = strlen(str + index);
    if (n < 18) {
      printw("%*s", 18, str + index);
      index += n;
    } else {
      if (n > 18)
        n = 18;
      while (!isspace(str[index + n]) && n >= 0)
        --n;
      if (n < 0) {
        printw("%.*s", 18, str + index);
        index += 18;
        while (str[index] && !isspace(str[index]))
          ++index;
      } else {
        printw("%*.*s", 18, n, str + index);
        index += n + 1;
      }
    }
  }
  return index;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lineout>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %rbx,%rbp
  add    %rdi,%rbx
  sub    %ebx,%ebp
  sub    $0x8,%rsp
L40:
  movsbl (%rbx),%edi
  lea    0x0(%rbp,%rbx,1),%r12d
  mov    %rbx,%r14
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L40
  cmpb   $0x0,(%r14)
  jne    L82
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L82:
  mov    %r14,%rdi
  movslq %r12d,%rbp
  mov    $0x12,%ebx
  call   <strlen@plt>
  add    %r13,%rbp
  mov    %eax,%r15d
  cmp    $0x11,%eax
  jg     L111
  jmp    L129
  nopl   (%rax)
L38:
  sub    $0x1,%rbx
  cmp    $0xfffffffffffffffe,%rbx
  je     L107
L111:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L38
  cmp    $0xffffffff,%ebx
  je     L107
  mov    %r14,%rcx
  mov    %ebx,%edx
  mov    $0x12,%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  lea    0x1(%rbx,%r12,1),%r12d
  call   <printw@plt>
  jmp    L2
  nopl   (%rax)
L129:
  mov    %r14,%rdx
  mov    $0x12,%esi
  xor    %eax,%eax
  add    %r15d,%r12d
  lea    D26(%rip),%rdi
  call   <printw@plt>
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L107:
  lea    D16(%rip),%rdi
  mov    %r14,%rdx
  xor    %eax,%eax
  add    $0x12,%r12d
  mov    $0x12,%esi
  call   <printw@plt>
  movslq %r12d,%rax
  add    %rax,%r13
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L104
  jmp    L2
  nop
L57:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  add    $0x1,%r12d
  test   %dil,%dil
  je     L2
L104:
  call   <isspace@plt>
  test   %rax,%rax
  je     L57
  jmp    L2
```

tool_calls: name: read_data
arguments: data_tag: D27
type: string
name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D27: %*.*s

tool: D26: %*s

tool: D16: %.*s

assistant: ```c
int lineout(char const *str, int index) {
  int n;
  while (isspace(str[index]))
    ++index;
  if (str[index]) {
    n = strlen(str + index);
    if (n < 18) {
      printw("%*s", 18, str + index);
      index += n;
    } else {
      if (n > 18)
        n = 18;
      while (!isspace(str[index + n]) && n >= 0)
        --n;
      if (n < 0) {
        printw("%.*s", 18, str + index);
        index += 18;
        while (str[index] && !isspace(str[index]))
          ++index;
      } else {
        printw("%*.*s", 18, n, str + index);
        index += n + 1;
      }
    }
  }
  return index;
}
```
user: What is the c source code of the assembly code below:

```asm
<lineout>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %rbx,%rbp
  add    %rdi,%rbx
  sub    %ebx,%ebp
  sub    $0x8,%rsp
L83:
  movsbl (%rbx),%edi
  lea    0x0(%rbp,%rbx,1),%r12d
  mov    %rbx,%r14
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L83
  cmpb   $0x0,(%r14)
  jne    L67
L47:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L67:
  mov    %r14,%rdi
  movslq %r12d,%rbp
  mov    $0x12,%ebx
  call   <strlen@plt>
  add    %r13,%rbp
  mov    %eax,%r15d
  cmp    $0x11,%eax
  jg     L97
  jmp    L117
  nopl   (%rax)
L63:
  sub    $0x1,%rbx
  cmp    $0xfffffffffffffffe,%rbx
  je     L103
L97:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L63
  cmp    $0xffffffff,%ebx
  je     L103
  mov    %r14,%rcx
  mov    %ebx,%edx
  mov    $0x12,%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  lea    0x1(%rbx,%r12,1),%r12d
  call   <printw@plt>
  jmp    L47
  nopl   (%rax)
L117:
  mov    %r14,%rdx
  mov    $0x12,%esi
  xor    %eax,%eax
  add    %r15d,%r12d
  lea    D2(%rip),%rdi
  call   <printw@plt>
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L103:
  lea    D16(%rip),%rdi
  mov    %r14,%rdx
  xor    %eax,%eax
  add    $0x12,%r12d
  mov    $0x12,%esi
  call   <printw@plt>
  movslq %r12d,%rax
  add    %rax,%r13
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L115
  jmp    L47
  nop
L89:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  add    $0x1,%r12d
  test   %dil,%dil
  je     L47
L115:
  call   <isspace@plt>
  test   %rax,%rax
  je     L89
  jmp    L47
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D17: %*.*s

tool: D2: %*s

tool: D16: %.*s

assistant: ```c
int lineout(char const *str, int index) {
  int n;
  while (isspace(str[index]))
    ++index;
  if (str[index]) {
    n = strlen(str + index);
    if (n < 18) {
      printw("%*s", 18, str + index);
      index += n;
    } else {
      if (n > 18)
        n = 18;
      while (!isspace(str[index + n]) && n >= 0)
        --n;
      if (n < 0) {
        printw("%.*s", 18, str + index);
        index += 18;
        while (str[index] && !isspace(str[index]))
          ++index;
      } else {
        printw("%*.*s", 18, n, str + index);
        index += n + 1;
      }
    }
  }
  return index;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reversible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <intrev@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    $0x0,%eax
  jmp    L11
L8:
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <onlyodds@plt>
L11:
  leave
  ret
```

assistant: ```c
int reversible(uint32_t i) {
  uint32_t rev = intrev(i);
  if (rev & 1)
    return 0;
  return onlyodds(rev + i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reversible>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <intrev@plt>
  mov    $0x0,%edx
  test   $0x1,%al
  je     L5
L14:
  mov    %edx,%eax
  pop    %rbx
  ret
L5:
  lea    (%rbx,%rax,1),%edi
  call   <onlyodds@plt>
  mov    %eax,%edx
  jmp    L14
```

assistant: ```c
int reversible(uint32_t i) {
  uint32_t rev = intrev(i);
  if (rev & 1)
    return 0;
  return onlyodds(rev + i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reversible>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <intrev@plt>
  test   $0x1,%al
  je     L3
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  lea    (%rbx,%rax,1),%edi
  pop    %rbx
  jmp    1060 <onlyodds@plt>
```

assistant: ```c
int reversible(uint32_t i) {
  uint32_t rev = intrev(i);
  if (rev & 1)
    return 0;
  return onlyodds(rev + i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reversible>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <intrev@plt>
  test   $0x1,%al
  je     L2
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  lea    (%rbx,%rax,1),%edi
  pop    %rbx
  jmp    1060 <onlyodds@plt>
```

assistant: ```c
int reversible(uint32_t i) {
  uint32_t rev = intrev(i);
  if (rev & 1)
    return 0;
  return onlyodds(rev + i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L2:
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L44
  movsd  -0x28(%rbp),%xmm0
  movq   D18(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  jmp    L67
L44:
  movsd  -0x28(%rbp),%xmm0
L67:
  mulsd  -0x10(%rbp),%xmm0
  addl   $0x1,-0x1c(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L2
  movsd  -0x18(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L53
  jmp    L2
L53:
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L25
  movsd  D14(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  jmp    L23
L25:
  movsd  -0x18(%rbp),%xmm0
L23:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: f64
name: retrieve_data
arguments: label: D18
type_infered: byte[8]

tool: D14: 1

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double exp(double x) {
  int n = 0;
  double psum, sum = 1.0, item = 1.0;
  do {
    psum = sum;
    sum += item = item * (x < 0 ? -x : x) / ++n;
  } while (sum != psum);
  return x < 0 ? 1 / sum : sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exp>:
  endbr64
  movapd %xmm0,%xmm4
  pxor   %xmm1,%xmm1
  movapd %xmm0,%xmm3
  xorpd  D9(%rip),%xmm3
  cmpltsd %xmm1,%xmm0
  andpd  %xmm0,%xmm3
  andnpd %xmm4,%xmm0
  orpd   %xmm0,%xmm3
  movsd  D0(%rip),%xmm1
  movapd %xmm1,%xmm0
  mov    $0x0,%eax
L30:
  mulsd  %xmm3,%xmm1
  add    $0x1,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  jp     L30
  jne    L30
  pxor   %xmm1,%xmm1
  comisd %xmm4,%xmm1
  ja     L18
L19:
  ret
L18:
  movsd  D0(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: f64

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D0: 1

assistant: ```c
double exp(double x) {
  int n = 0;
  double psum, sum = 1.0, item = 1.0;
  do {
    psum = sum;
    sum += item = item * (x < 0 ? -x : x) / ++n;
  } while (sum != psum);
  return x < 0 ? 1 / sum : sum;
}
```