ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D16(%rip),%rbp
  call   <br@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <ic@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <ic@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <br@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
type: string
name: disassemble_data
arguments: label: D10
type: string
name: disassemble_data
arguments: label: D3
type: string

tool: D16: 


tool: D10: , 

tool: D3: ,


assistant: ```c
int main(void) {
  br();
  printf(", ");
  ic();
  printf("\n");
  ic();
  printf(",\n");
  br();
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<muld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L12
  movsd  D43(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  jae    L20
L12:
  movsd  -0x20(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L88
  movsd  D43(%rip),%xmm0
  comisd -0x20(%rbp),%xmm0
  jae    L20
L88:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L104
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L104
  movsd  -0x18(%rbp),%xmm0
  movq   D27(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movq   D27(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  divsd  -0x20(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L20
L104:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L94
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L94
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L20
L94:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L30
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L30
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x18(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L20
L30:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L161
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L161
  movsd  -0x30(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L161
L20:
  mov    $0x1,%eax
  jmp    L62
L161:
  mov    $0x0,%eax
L62:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L174
  cmpl   $0x0,-0x34(%rbp)
  je     L174
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <warning@plt>
  movl   $0x1,-0x4(%rbp)
L174:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: byte[8]
name: unpack_data
arguments: label: D43
type_guessed: byte[8]
name: unpack_data
arguments: label: D27
type_guessed: byte[8]
name: unpack_data
arguments: label: D39
type_guessed: string

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D39: overflow in constant expression


assistant: ```c
int muld(double x, double y, double min, double max, int needconst) {
  int cond = (x >= -1 && x <= 1) || (y >= -1 && y <= 1) || (x < 0 && y < 0 && -x <= max / -y) || (x < 0 && y > 0 && x >= min / y) || (x > 0 && y < 0 && y >= min / x) || (x > 0 && y > 0 && x <= max / y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<muld>:
  endbr64
  movsd  D33(%rip),%xmm4
  comisd %xmm4,%xmm0
  jb     L89
  movsd  D40(%rip),%xmm5
  mov    $0x1,%eax
  comisd %xmm0,%xmm5
  jae    L60
L89:
  comisd %xmm4,%xmm1
  jb     L15
  movsd  D40(%rip),%xmm4
  mov    $0x1,%eax
  comisd %xmm1,%xmm4
  jae    L60
L15:
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  ja     L133
L10:
  comisd %xmm4,%xmm0
  jbe    L103
  comisd %xmm1,%xmm4
  ja     L148
L4:
  comisd %xmm4,%xmm1
  jbe    L103
  divsd  %xmm1,%xmm3
  mov    $0x1,%eax
  comisd %xmm0,%xmm3
  jae    L60
  nopl   (%rax)
L103:
  test   %edi,%edi
  je     L137
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L133:
  comisd %xmm1,%xmm4
  ja     L145
L5:
  comisd %xmm4,%xmm1
  jbe    L10
  movapd %xmm2,%xmm5
  mov    $0x1,%eax
  divsd  %xmm1,%xmm5
  comisd %xmm5,%xmm0
  jb     L10
L60:
  ret
L148:
  divsd  %xmm0,%xmm2
  mov    $0x1,%eax
  comisd %xmm2,%xmm1
  jb     L4
  ret
L145:
  movq   D28(%rip),%xmm5
  movapd %xmm0,%xmm6
  mov    $0x1,%eax
  xorpd  %xmm5,%xmm6
  xorpd  %xmm3,%xmm5
  divsd  %xmm1,%xmm5
  comisd %xmm6,%xmm5
  jb     L5
  ret
  nopl   0x0(%rax)
L137:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D33
data_type: byte[8]
name: unpack_data
arguments: data_tag: D40
data_type: byte[8]
name: unpack_data
arguments: data_tag: D38
data_type: string
name: unpack_data
arguments: data_tag: D28
data_type: byte[8]

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D38: overflow in constant expression


tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int muld(double x, double y, double min, double max, int needconst) {
  int cond = (x >= -1 && x <= 1) || (y >= -1 && y <= 1) || (x < 0 && y < 0 && -x <= max / -y) || (x < 0 && y > 0 && x >= min / y) || (x > 0 && y < 0 && y >= min / x) || (x > 0 && y > 0 && x <= max / y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<muld>:
  endbr64
  movsd  D6(%rip),%xmm4
  comisd %xmm4,%xmm0
  jb     L32
  movsd  D38(%rip),%xmm5
  mov    $0x1,%eax
  comisd %xmm0,%xmm5
  jae    L114
L32:
  comisd %xmm4,%xmm1
  jb     L5
  movsd  D38(%rip),%xmm4
  mov    $0x1,%eax
  comisd %xmm1,%xmm4
  jae    L114
L5:
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  ja     L142
L116:
  comisd %xmm4,%xmm0
  jbe    L70
  comisd %xmm1,%xmm4
  ja     L41
L15:
  comisd %xmm4,%xmm1
  jbe    L70
  divsd  %xmm1,%xmm3
  mov    $0x1,%eax
  comisd %xmm0,%xmm3
  jae    L114
  nopl   (%rax)
L70:
  test   %edi,%edi
  je     L19
  sub    $0x8,%rsp
  lea    D32(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L142:
  comisd %xmm1,%xmm4
  ja     L137
L76:
  comisd %xmm4,%xmm1
  jbe    L116
  movapd %xmm2,%xmm5
  mov    $0x1,%eax
  divsd  %xmm1,%xmm5
  comisd %xmm5,%xmm0
  jb     L116
L114:
  ret
L41:
  divsd  %xmm0,%xmm2
  mov    $0x1,%eax
  comisd %xmm2,%xmm1
  jb     L15
  ret
L137:
  movq   D37(%rip),%xmm5
  movapd %xmm0,%xmm6
  mov    $0x1,%eax
  xorpd  %xmm5,%xmm6
  xorpd  %xmm3,%xmm5
  divsd  %xmm1,%xmm5
  comisd %xmm6,%xmm5
  jb     L76
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D32: overflow in constant expression


tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int muld(double x, double y, double min, double max, int needconst) {
  int cond = (x >= -1 && x <= 1) || (y >= -1 && y <= 1) || (x < 0 && y < 0 && -x <= max / -y) || (x < 0 && y > 0 && x >= min / y) || (x > 0 && y < 0 && y >= min / x) || (x > 0 && y > 0 && x <= max / y);
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x80,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x420(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x41c(%rbp)
  jmp    L25
L65:
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,8),%rax
  test   %rax,%rax
  je     L33
  mov    -0x420(%rbp),%eax
  cmp    -0x41c(%rbp),%eax
  jle    L22
  mov    -0x420(%rbp),%eax
  mov    %eax,-0x41c(%rbp)
L22:
  mov    -0x420(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x418(%rbp)
  jmp    L12
L73:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  movq   $0x0,-0x410(%rbp,%rax,8)
  addq   $0x1,-0x418(%rbp)
L12:
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,8),%rax
  cmp    %rax,-0x418(%rbp)
  jb     L73
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,8),%rdx
  mov    -0x428(%rbp),%rax
  sub    %rdx,%rax
  mov    %eax,-0x420(%rbp)
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x428(%rbp),%rdx
  mov    %rdx,-0x410(%rbp,%rax,8)
  jmp    L18
L33:
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x428(%rbp),%rdx
  mov    %rdx,-0x410(%rbp,%rax,8)
  addl   $0x1,-0x420(%rbp)
L18:
  addq   $0x1,-0x428(%rbp)
L25:
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  mov    -0x41c(%rbp),%eax
  cmp    -0x420(%rbp),%eax
  jge    L48
  mov    -0x420(%rbp),%eax
  mov    %eax,-0x41c(%rbp)
L48:
  mov    -0x41c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *hash[128] = {NULL};
  int len = 0, max = INT_MIN;
  char *w;
  while (*s) {
    if (hash[*s] != NULL) {
      if (len > max) {
        max = len;
      }
      w = s - len;
      while (w < hash[*s]) {
        hash[*w] = NULL;
        w++;
      }
      len = s - hash[*s];
      hash[*s] = s;
    } else {
      hash[*s] = s;
      len++;
    }
    s++;
  }
  if (max < len)
    max = len;
  return max;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lengthOfLongestSubstring>:
  endbr64
  sub    $0x418,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x80,%ecx
  rep stos %rax,%es:(%rdi)
  mov    D4(%rip),%rax
  mov    (%rax),%r9d
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L63
  mov    $0x0,%eax
  jmp    L78
L50:
  cmp    %eax,%r9d
  cmovl  %eax,%r9d
  cltq
  mov    %rsi,%rdx
  sub    %rax,%rdx
  cmp    %rdx,%rcx
  jbe    L71
  movslq %edi,%r8
L14:
  movsbq (%rdx),%rax
  movq   $0x0,(%rsp,%rax,8)
  add    $0x1,%rdx
  mov    (%rsp,%r8,8),%rcx
  cmp    %rdx,%rcx
  ja     L14
L71:
  mov    %esi,%eax
  sub    %ecx,%eax
L6:
  movslq %edi,%rdi
  mov    %rsi,(%rsp,%rdi,8)
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L16
L78:
  movsbl %dl,%edi
  movsbq %dl,%rdx
  mov    (%rsp,%rdx,8),%rcx
  test   %rcx,%rcx
  jne    L50
  add    $0x1,%eax
  jmp    L6
L63:
  mov    $0x0,%eax
L16:
  cmp    %r9d,%eax
  cmovl  %r9d,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x418,%rsp
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *hash[128] = {NULL};
  int len = 0, max = INT_MIN;
  char *w;
  while (*s) {
    if (hash[*s] != NULL) {
      if (len > max) {
        max = len;
      }
      w = s - len;
      while (w < hash[*s]) {
        hash[*w] = NULL;
        w++;
      }
      len = s - hash[*s];
      hash[*s] = s;
    } else {
      hash[*s] = s;
      len++;
    }
    s++;
  }
  if (max < len)
    max = len;
  return max;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lengthOfLongestSubstring>:
  endbr64
  sub    $0x418,%rsp
  mov    %rdi,%r8
  mov    $0x80,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movsbq (%r8),%rsi
  rep stos %rax,%es:(%rdi)
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  xor    %eax,%eax
  test   %sil,%sil
  jne    L16
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L71:
  add    $0x1,%eax
L54:
  mov    %r8,(%rsp,%rsi,8)
  movsbq 0x1(%r8),%rsi
  add    $0x1,%r8
  test   %sil,%sil
  je     L75
L16:
  mov    (%rsp,%rsi,8),%rcx
  test   %rcx,%rcx
  je     L71
  cmp    %eax,%edi
  mov    %r8,%rdx
  cmovl  %eax,%edi
  cltq
  sub    %rax,%rdx
  cmp    %rdx,%rcx
  jbe    L59
  nopl   0x0(%rax,%rax,1)
L57:
  movsbq (%rdx),%rax
  add    $0x1,%rdx
  movq   $0x0,(%rsp,%rax,8)
  mov    (%rsp,%rsi,8),%rcx
  cmp    %rdx,%rcx
  ja     L57
L59:
  mov    %r8d,%eax
  sub    %ecx,%eax
  jmp    L54
L75:
  cmp    %edi,%eax
  cmovl  %edi,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x418,%rsp
  ret
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *hash[128] = {NULL};
  int len = 0, max = INT_MIN;
  char *w;
  while (*s) {
    if (hash[*s] != NULL) {
      if (len > max) {
        max = len;
      }
      w = s - len;
      while (w < hash[*s]) {
        hash[*w] = NULL;
        w++;
      }
      len = s - hash[*s];
      hash[*s] = s;
    } else {
      hash[*s] = s;
      len++;
    }
    s++;
  }
  if (max < len)
    max = len;
  return max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lengthOfLongestSubstring>:
  endbr64
  sub    $0x418,%rsp
  mov    %rdi,%r8
  mov    $0x80,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movsbq (%r8),%rsi
  rep stos %rax,%es:(%rdi)
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  xor    %eax,%eax
  test   %sil,%sil
  jne    L19
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%eax
L23:
  mov    %r8,(%rsp,%rsi,8)
  movsbq 0x1(%r8),%rsi
  add    $0x1,%r8
  test   %sil,%sil
  je     L28
L19:
  mov    (%rsp,%rsi,8),%rcx
  test   %rcx,%rcx
  je     L51
  cmp    %eax,%edi
  mov    %r8,%rdx
  cmovl  %eax,%edi
  cltq
  sub    %rax,%rdx
  cmp    %rdx,%rcx
  jbe    L8
  nopl   0x0(%rax,%rax,1)
L59:
  movsbq (%rdx),%rax
  add    $0x1,%rdx
  movq   $0x0,(%rsp,%rax,8)
  mov    (%rsp,%rsi,8),%rcx
  cmp    %rdx,%rcx
  ja     L59
L8:
  mov    %r8d,%eax
  sub    %ecx,%eax
  jmp    L23
L28:
  cmp    %edi,%eax
  cmovl  %edi,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x418,%rsp
  ret
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *hash[128] = {NULL};
  int len = 0, max = INT_MIN;
  char *w;
  while (*s) {
    if (hash[*s] != NULL) {
      if (len > max) {
        max = len;
      }
      w = s - len;
      while (w < hash[*s]) {
        hash[*w] = NULL;
        w++;
      }
      len = s - hash[*s];
      hash[*s] = s;
    } else {
      hash[*s] = s;
      len++;
    }
    s++;
  }
  if (max < len)
    max = len;
  return max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string

tool: D8: Li Muyuan


tool: D21: Li
Muyuan


tool: D2: Li

tool: D38:  Muyuan


assistant: ```c
int main(void) {
  printf("Li Muyuan\n");
  printf("Li\nMuyuan\n");
  printf("Li");
  printf(" Muyuan\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string
name: parse_data
arguments: data_label: D1
type_guessed: string
name: parse_data
arguments: data_label: D34
type_guessed: string

tool: D38: Li Muyuan


tool: D36: Li
Muyuan


tool: D1: Li

tool: D34:  Muyuan


assistant: ```c
int main(void) {
  printf("Li Muyuan\n");
  printf("Li\nMuyuan\n");
  printf("Li");
  printf(" Muyuan\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D24: Li Muyuan


tool: D16: Li
Muyuan


tool: D32: Li

tool: D4:  Muyuan


assistant: ```c
int main(void) {
  printf("Li Muyuan\n");
  printf("Li\nMuyuan\n");
  printf("Li");
  printf(" Muyuan\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D35
type_infered: string
name: disassemble_data
arguments: data_tag: D25
type_infered: string

tool: D15: Li Muyuan


tool: D18: Li
Muyuan


tool: D35: Li

tool: D25:  Muyuan


assistant: ```c
int main(void) {
  printf("Li Muyuan\n");
  printf("Li\nMuyuan\n");
  printf("Li");
  printf(" Muyuan\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<translate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %rdi,-0x2028(%rbp)
  mov    %rsi,-0x2030(%rbp)
  mov    %edx,-0x2034(%rbp)
  mov    %rcx,-0x2040(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2028(%rbp),%rax
  mov    %rax,-0x2018(%rbp)
  mov    -0x2018(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x2020(%rbp)
  jmp    L103
L101:
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2030(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2020(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x2018(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x2020(%rbp)
L103:
  mov    -0x2020(%rbp),%eax
  cmp    %eax,-0x2034(%rbp)
  ja     L101
  movl   $0x0,-0x2020(%rbp)
  jmp    L4
L59:
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x2020(%rbp)
  je     L11
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jg     L68
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0xff,%eax
  cmp    %eax,-0x2020(%rbp)
  je     L11
L68:
  movl   $0x0,-0x201c(%rbp)
  jmp    L88
L26:
  mov    -0x201c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2030(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x2020(%rbp)
  je     L34
  mov    -0x201c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2030(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x100,%eax
  cmp    %eax,-0x2020(%rbp)
  jne    L55
L34:
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  mov    -0x201c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x2018(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L55:
  addl   $0x1,-0x201c(%rbp)
L88:
  mov    -0x201c(%rbp),%eax
  cmp    %eax,-0x2034(%rbp)
  ja     L26
L11:
  addl   $0x1,-0x2020(%rbp)
L4:
  cmpl   $0xff,-0x2020(%rbp)
  jle    L59
  mov    -0x2018(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L105
  call   <__stack_chk_fail@plt>
L105:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: 

assistant: ```c
char *translate(char *dst, const char *target, const unsigned int size, const char *table) {
  char hxtostrTemp[8192];
  char output[8192];
  char *ret = dst;
  strcpy(ret, "");
  char temp[3];
  int i, j;
  for (i = 0; i < size; i++) {
    ret[i] = target[i];
  }
  for (i = 0; i < 256; i++) {
    if ((int)(table[i]) != i && ((int)(table[i]) > 0 || (255 + (int)(table[i])) != i)) {
      for (j = 0; j < size; j++) {
        if ((int)target[j] == i || (256 + (int)target[j]) == i) {
          ret[j] = table[i];
        }
      }
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<translate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %rcx,%rbp
  lea    D2(%rip),%rsi
  call   <strcpy@plt>
  test   %r13d,%r13d
  je     L126
  mov    %r13d,%ecx
  mov    $0x0,%eax
L20:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L20
L126:
  mov    $0x0,%ecx
  mov    %r13d,%edi
  jmp    L43
L90:
  movzbl 0x0(%rbp,%rcx,1),%edx
  mov    %dl,(%r12,%rax,1)
L124:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L23
L111:
  movsbl (%rbx,%rax,1),%edx
  cmp    %esi,%edx
  je     L90
  add    $0x100,%edx
  cmp    %esi,%edx
  jne    L124
  jmp    L90
L23:
  add    $0x1,%rcx
  cmp    $0x100,%rcx
  je     L108
L43:
  movzbl 0x0(%rbp,%rcx,1),%edx
  movsbl %dl,%eax
  mov    %ecx,%esi
  cmp    %ecx,%eax
  je     L23
  test   %dl,%dl
  jg     L52
  add    $0xff,%eax
  cmp    %ecx,%eax
  je     L23
L52:
  mov    $0x0,%eax
  test   %r13d,%r13d
  jne    L111
  jmp    L23
L108:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: 

assistant: ```c
char *translate(char *dst, const char *target, const unsigned int size, const char *table) {
  char hxtostrTemp[8192];
  char output[8192];
  char *ret = dst;
  strcpy(ret, "");
  char temp[3];
  int i, j;
  for (i = 0; i < size; i++) {
    ret[i] = target[i];
  }
  for (i = 0; i < 256; i++) {
    if ((int)(table[i]) != i && ((int)(table[i]) > 0 || (255 + (int)(table[i])) != i)) {
      for (j = 0; j < size; j++) {
        if ((int)target[j] == i || (256 + (int)target[j]) == i) {
          ret[j] = table[i];
        }
      }
    }
  }
  return ret;
}
```