ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<next_word>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  jmp    L58
L43:
  add    $0x1,%eax
  mov    %eax,(%rbx)
L58:
  movslq (%rbx),%rax
  movsbl 0x0(%rbp,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L13
  mov    (%rbx),%eax
  movslq %eax,%rdx
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L43
  mov    $0x0,%r12d
  jmp    L60
L19:
  mov    %al,0x0(%r13,%r12,1)
  addl   $0x1,(%rbx)
  add    $0x1,%r12
L60:
  mov    %r12d,%r14d
  movslq (%rbx),%rax
  movsbl 0x0(%rbp,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L50
  movslq (%rbx),%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L19
L50:
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    $0x0,%r12d
  jmp    L60
```

assistant: ```c
void next_word(char s[], char w[], int index[]) {
  int i;
  for (; isspace(s[index[0]]) && s[index[0]] != '\0'; ++index[0])
    ;
  for (i = 0; !isspace(s[index[0]]) && s[index[0]] != '\0'; ++index[0], ++i)
    w[i] = s[index[0]];
  w[i] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<next_word>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdx),%eax
  jmp    L26
  nopl   (%rax)
L59:
  movslq (%r12),%rdx
  movsbl (%rbx,%rdx,1),%edi
  mov    %rdx,%rax
  test   %dil,%dil
  je     L8
  add    $0x1,%eax
  mov    %eax,(%r12)
L26:
  cltq
  movsbl (%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L59
  movslq (%r12),%rax
  movsbl (%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L33
  nopl   0x0(%rax)
L4:
  movslq (%r12),%rax
  movzbl (%rbx,%rax,1),%eax
  test   %al,%al
  je     L33
  mov    %al,0x0(%rbp)
  mov    (%r12),%eax
  add    $0x1,%rbp
  add    $0x1,%eax
  mov    %eax,(%r12)
  cltq
  movsbl (%rbx,%rax,1),%edi
L8:
  call   <isspace@plt>
  test   %rax,%rax
  je     L4
L33:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void next_word(char s[], char w[], int index[]) {
  int i;
  for (; isspace(s[index[0]]) && s[index[0]] != '\0'; ++index[0])
    ;
  for (i = 0; !isspace(s[index[0]]) && s[index[0]] != '\0'; ++index[0], ++i)
    w[i] = s[index[0]];
  w[i] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<next_word>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdx),%eax
  jmp    L39
  nopl   (%rax)
L48:
  movslq (%r12),%rdx
  movsbl (%rbx,%rdx,1),%edi
  mov    %rdx,%rax
  test   %dil,%dil
  je     L34
  add    $0x1,%eax
  mov    %eax,(%r12)
L39:
  cltq
  movsbl (%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  movslq (%r12),%rax
  movsbl (%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  nopl   0x0(%rax)
L45:
  movslq (%r12),%rax
  movzbl (%rbx,%rax,1),%eax
  test   %al,%al
  je     L18
  mov    %al,0x0(%rbp)
  mov    (%r12),%eax
  add    $0x1,%rbp
  add    $0x1,%eax
  mov    %eax,(%r12)
  cltq
  movsbl (%rbx,%rax,1),%edi
L34:
  call   <isspace@plt>
  test   %rax,%rax
  je     L45
L18:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void next_word(char s[], char w[], int index[]) {
  int i;
  for (; isspace(s[index[0]]) && s[index[0]] != '\0'; ++index[0])
    ;
  for (i = 0; !isspace(s[index[0]]) && s[index[0]] != '\0'; ++index[0], ++i)
    w[i] = s[index[0]];
  w[i] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0xf,-0x4(%rbp)
  jle    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: %02x

assistant: ```c
void pt(unsigned char *md) {
  int i;
  for (i = 0; i < 16; i++)
    printf("%02x", md[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(%rdi),%r12
  lea    D1(%rip),%rbp
L6:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: %02x

assistant: ```c
void pt(unsigned char *md) {
  int i;
  for (i = 0; i < 16; i++)
    printf("%02x", md[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pt>:
  endbr64
  push   %r12
  lea    0x10(%rdi),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: %02x

assistant: ```c
void pt(unsigned char *md) {
  int i;
  for (i = 0; i < 16; i++)
    printf("%02x", md[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pt>:
  endbr64
  push   %r12
  lea    0x10(%rdi),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %02x

assistant: ```c
void pt(unsigned char *md) {
  int i;
  for (i = 0; i < 16; i++)
    printf("%02x", md[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gpio_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  subl   $0x60,-0x14(%rbp)
  cmpl   $0x1f,-0x14(%rbp)
  jle    L29
  subl   $0x20,-0x14(%rbp)
  movb   $0x5,-0x9(%rbp)
  mov    $0x20ac000,%edi
  call   <reg_read@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L64
L29:
  movb   $0x4,-0x9(%rbp)
  mov    $0x20a8000,%edi
  call   <reg_read@plt>
  mov    %rax,-0x8(%rbp)
L64:
  cmpl   $0x0,-0x18(%rbp)
  je     L66
  cmpb   $0x4,-0x9(%rbp)
  jne    L47
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20a8000,%edi
  call   <reg_write@plt>
  jmp    L31
L47:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20ac000,%edi
  call   <reg_write@plt>
  jmp    L31
L66:
  cmpb   $0x4,-0x9(%rbp)
  jne    L30
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  cltq
  and    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20a8000,%edi
  call   <reg_write@plt>
  jmp    L31
L30:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  cltq
  and    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20ac000,%edi
  call   <reg_write@plt>
L31:
  nop
  leave
  ret
```

assistant: ```c
void gpio_set(int gpio, int value) {
  unsigned long dr;
  unsigned char port;
  gpio -= 96;
  if (gpio > 31) {
    gpio -= 32;
    port = 5;
    dr = reg_read(0x20AC000);
  } else {
    port = 4;
    dr = reg_read(0x20A8000);
  }
  if (value) {
    if (port == 4)
      reg_write(0x20A8000, dr | (1 << gpio));
    else
      reg_write(0x20AC000, dr | (1 << gpio));
  } else {
    if (port == 4)
      reg_write(0x20A8000, dr & (~(1 << gpio)));
    else
      reg_write(0x20AC000, dr & (~(1 << gpio)));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gpio_set>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  lea    -0x60(%rdi),%ebx
  cmp    $0x1f,%ebx
  jle    L14
  lea    -0x80(%rdi),%ebx
  mov    $0x20ac000,%edi
  call   <reg_read@plt>
  test   %ebp,%ebp
  jne    L29
  mov    $0xfffffffe,%esi
  mov    %ebx,%ecx
  rol    %cl,%esi
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    $0x20ac000,%edi
  call   <reg_write@plt>
  jmp    L31
L14:
  mov    $0x20a8000,%edi
  call   <reg_read@plt>
  test   %ebp,%ebp
  jne    L57
  mov    $0xfffffffe,%esi
  mov    %ebx,%ecx
  rol    %cl,%esi
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    $0x20a8000,%edi
  call   <reg_write@plt>
  jmp    L31
L57:
  mov    $0x1,%esi
  mov    %ebx,%ecx
  shl    %cl,%esi
  movslq %esi,%rsi
  or     %rax,%rsi
  mov    $0x20a8000,%edi
  call   <reg_write@plt>
  jmp    L31
L29:
  mov    $0x1,%esi
  mov    %ebx,%ecx
  shl    %cl,%esi
  movslq %esi,%rsi
  or     %rax,%rsi
  mov    $0x20ac000,%edi
  call   <reg_write@plt>
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void gpio_set(int gpio, int value) {
  unsigned long dr;
  unsigned char port;
  gpio -= 96;
  if (gpio > 31) {
    gpio -= 32;
    port = 5;
    dr = reg_read(0x20AC000);
  } else {
    port = 4;
    dr = reg_read(0x20A8000);
  }
  if (value) {
    if (port == 4)
      reg_write(0x20A8000, dr | (1 << gpio));
    else
      reg_write(0x20AC000, dr | (1 << gpio));
  } else {
    if (port == 4)
      reg_write(0x20A8000, dr & (~(1 << gpio)));
    else
      reg_write(0x20AC000, dr & (~(1 << gpio)));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gpio_set>:
  endbr64
  push   %r12
  lea    -0x60(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x1f,%r12d
  jle    L27
  mov    %edi,%ebx
  mov    $0x20ac000,%edi
  call   <reg_read@plt>
  lea    -0x80(%rbx),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  test   %ebp,%ebp
  jne    L8
  not    %edx
  pop    %rbx
  mov    $0x20ac000,%edi
  pop    %rbp
  movslq %edx,%rsi
  pop    %r12
  and    %rax,%rsi
  jmp    1070 <reg_write@plt>
  nopl   0x0(%rax)
L27:
  mov    $0x20a8000,%edi
  call   <reg_read@plt>
  mov    $0x1,%esi
  mov    %r12d,%ecx
  shl    %cl,%esi
  test   %ebp,%ebp
  jne    L18
  not    %esi
  pop    %rbx
  mov    $0x20a8000,%edi
  pop    %rbp
  movslq %esi,%rsi
  pop    %r12
  and    %rax,%rsi
  jmp    1070 <reg_write@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  movslq %edx,%rsi
  pop    %rbx
  mov    $0x20ac000,%edi
  pop    %rbp
  or     %rax,%rsi
  pop    %r12
  jmp    1070 <reg_write@plt>
  nopl   0x0(%rax)
L18:
  movslq %esi,%rsi
  pop    %rbx
  mov    $0x20a8000,%edi
  pop    %rbp
  or     %rax,%rsi
  pop    %r12
  jmp    1070 <reg_write@plt>
```

assistant: ```c
void gpio_set(int gpio, int value) {
  unsigned long dr;
  unsigned char port;
  gpio -= 96;
  if (gpio > 31) {
    gpio -= 32;
    port = 5;
    dr = reg_read(0x20AC000);
  } else {
    port = 4;
    dr = reg_read(0x20A8000);
  }
  if (value) {
    if (port == 4)
      reg_write(0x20A8000, dr | (1 << gpio));
    else
      reg_write(0x20AC000, dr | (1 << gpio));
  } else {
    if (port == 4)
      reg_write(0x20A8000, dr & (~(1 << gpio)));
    else
      reg_write(0x20AC000, dr & (~(1 << gpio)));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gpio_set>:
  endbr64
  push   %r12
  lea    -0x60(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x1f,%r12d
  jle    L18
  mov    %edi,%ebx
  mov    $0x20ac000,%edi
  call   <reg_read@plt>
  lea    -0x80(%rbx),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  test   %ebp,%ebp
  jne    L7
  not    %edx
  pop    %rbx
  mov    $0x20ac000,%edi
  pop    %rbp
  movslq %edx,%rsi
  pop    %r12
  and    %rax,%rsi
  jmp    1070 <reg_write@plt>
  nopl   0x0(%rax)
L18:
  mov    $0x20a8000,%edi
  call   <reg_read@plt>
  mov    $0x1,%esi
  mov    %r12d,%ecx
  shl    %cl,%esi
  test   %ebp,%ebp
  jne    L12
  not    %esi
  pop    %rbx
  mov    $0x20a8000,%edi
  pop    %rbp
  movslq %esi,%rsi
  pop    %r12
  and    %rax,%rsi
  jmp    1070 <reg_write@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  movslq %edx,%rsi
  pop    %rbx
  mov    $0x20ac000,%edi
  pop    %rbp
  or     %rax,%rsi
  pop    %r12
  jmp    1070 <reg_write@plt>
  nopl   0x0(%rax)
L12:
  movslq %esi,%rsi
  pop    %rbx
  mov    $0x20a8000,%edi
  pop    %rbp
  or     %rax,%rsi
  pop    %r12
  jmp    1070 <reg_write@plt>
```

assistant: ```c
void gpio_set(int gpio, int value) {
  unsigned long dr;
  unsigned char port;
  gpio -= 96;
  if (gpio > 31) {
    gpio -= 32;
    port = 5;
    dr = reg_read(0x20AC000);
  } else {
    port = 4;
    dr = reg_read(0x20A8000);
  }
  if (value) {
    if (port == 4)
      reg_write(0x20A8000, dr | (1 << gpio));
    else
      reg_write(0x20AC000, dr | (1 << gpio));
  } else {
    if (port == 4)
      reg_write(0x20A8000, dr & (~(1 << gpio)));
    else
      reg_write(0x20AC000, dr & (~(1 << gpio)));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L15
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *util_toupper(char *buffer) {
  int i;
  for (i = 0; i < strlen(buffer); i++) {
    buffer[i] = toupper((unsigned char)buffer[i]);
  }
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_toupper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L18
L4:
  movzbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L4
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *util_toupper(char *buffer) {
  int i;
  for (i = 0; i < strlen(buffer); i++) {
    buffer[i] = toupper((unsigned char)buffer[i]);
  }
  return buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<util_toupper>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *util_toupper(char *buffer) {
  int i;
  for (i = 0; i < strlen(buffer); i++) {
    buffer[i] = toupper((unsigned char)buffer[i]);
  }
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_toupper>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L2:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *util_toupper(char *buffer) {
  int i;
  for (i = 0; i < strlen(buffer); i++) {
    buffer[i] = toupper((unsigned char)buffer[i]);
  }
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<toprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L7
  mov    -0x4(%rbp),%eax
  jmp    L35
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L18
  mov    -0x4(%rbp),%eax
  jmp    L35
L18:
  mov    $0x2e,%eax
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: 	


assistant: ```c
int toprint(int c) {
  if (isprint(c))
    return c;
  return strchr("\t\n\r", c) ? c : '.';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<toprint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isprint@plt>
  test   %rax,%rax
  je     L18
L16:
  mov    %ebx,%eax
  pop    %rbx
  ret
L18:
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <strchr@plt>
  test   %rax,%rax
  mov    $0x2e,%eax
  cmove  %eax,%ebx
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: 	


assistant: ```c
int toprint(int c) {
  if (isprint(c))
    return c;
  return strchr("\t\n\r", c) ? c : '.';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toprint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isprint@plt>
  test   %rax,%rax
  je     L11
L4:
  mov    %ebx,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L11:
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x2e,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: 	


assistant: ```c
int toprint(int c) {
  if (isprint(c))
    return c;
  return strchr("\t\n\r", c) ? c : '.';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<toprint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isprint@plt>
  test   %rax,%rax
  je     L7
L17:
  mov    %ebx,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L7:
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L17
  mov    $0x2e,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: 	


assistant: ```c
int toprint(int c) {
  if (isprint(c))
    return c;
  return strchr("\t\n\r", c) ? c : '.';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_wtmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L7
  mov    -0x18(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void do_wtmp(struct utmp *utmp) {
  int fd;
  if ((fd = open(_PATH_WTMP, O_WRONLY | O_APPEND)) >= 0) {
    write(fd, utmp, sizeof(struct utmp));
    close(fd);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_wtmp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  mov    D24(%rip),%rax
  or     (%rax),%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <open@plt>
  test   %eax,%eax
  jns    L18
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %eax,%ebx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %ebx,%edi
  call   <close@plt>
  jmp    L0
```

assistant: ```c
void do_wtmp(struct utmp *utmp) {
  int fd;
  if ((fd = open(_PATH_WTMP, O_WRONLY | O_APPEND)) >= 0) {
    write(fd, utmp, sizeof(struct utmp));
    close(fd);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_wtmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  mov    D28(%rip),%rax
  or     (%rax),%esi
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <open@plt>
  test   %eax,%eax
  jns    L0
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    $0x4,%edx
  mov    %eax,%ebp
  call   <write@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <close@plt>
```

assistant: ```c
void do_wtmp(struct utmp *utmp) {
  int fd;
  if ((fd = open(_PATH_WTMP, O_WRONLY | O_APPEND)) >= 0) {
    write(fd, utmp, sizeof(struct utmp));
    close(fd);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_wtmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    D16(%rip),%rax
  or     (%rax),%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <open@plt>
  test   %eax,%eax
  jns    L3
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    $0x4,%edx
  mov    %eax,%ebp
  call   <write@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <close@plt>
```

assistant: ```c
void do_wtmp(struct utmp *utmp) {
  int fd;
  if ((fd = open(_PATH_WTMP, O_WRONLY | O_APPEND)) >= 0) {
    write(fd, utmp, sizeof(struct utmp));
    close(fd);
  }
}
```