user: 请从给定的汇编指令推导出C源代码:

```asm
<read_test_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <rewind_tape@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x2000,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <space_forward_filemark@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x10000,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <space_back_block@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x10000,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D116(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <space_forward_block@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read_block_position@plt>
  mov    %eax,%edx
  lea    D155(%rip),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D155
type: string
name: unpack_data
arguments: data_tag: D52
type: string
name: unpack_data
arguments: data_tag: D116
type: string

tool: D155: read_test_3

tool: D52: %s: Block %d


tool: D116: %s: Note: following space_forward_block() should error


assistant: ```c
int read_test_3(int fd) {
  rewind_tape(fd);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  read_block(fd, 8 * 1024);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  space_forward_filemark(fd, 3);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  read_block(fd, 64 * 1024);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  space_back_block(fd, 1);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  read_block(fd, 64 * 1024);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  printf("%s: Note: following space_forward_block() should error\n", __func__);
  space_forward_block(fd, 1);
  printf("%s: Block %d\n", __func__, read_block_position(fd));
  return 0;
}
```