ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_flush>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x4,%edi
  ja     L19
  mov    $0x2,%eax
  cmp    $0x4,%esi
  ja     L19
  mov    $0x3,%eax
  cmp    $0x4,%edx
  ja     L19
  xor    %eax,%eax
  cmp    $0x4,%ecx
  seta   %al
  shl    $0x2,%eax
L19:
  ret
```

assistant: ```c
unsigned is_flush(const unsigned CHITS, const unsigned DHITS, const unsigned HHITS, const unsigned SHITS) {
  if (CHITS >= 5) {
    return 1;
  }
  if (DHITS >= 5) {
    return 2;
  }
  if (HHITS >= 5) {
    return 3;
  }
  if (SHITS >= 5) {
    return 4;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mkpasswd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2e2e2e2e2e243624,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x2e2e2e,-0xc(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x40(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x30(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  shr    $0xe,%rax
  and    $0x30000,%eax
  xor    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L16
L20:
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rsi
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x2,%ecx
  add    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  shr    %cl,%rsi
  mov    %rsi,%rax
  and    $0x3f,%eax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    -0x44(%rbp),%edx
  lea    0x3(%rdx),%ecx
  movzbl (%rax),%edx
  movslq %ecx,%rax
  mov    %dl,-0x14(%rbp,%rax,1)
  addl   $0x1,-0x44(%rbp)
L16:
  cmpl   $0x7,-0x44(%rbp)
  jle    L20
  lea    -0x14(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypt@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *mkpasswd(const char *words) {
  unsigned long seed[2];
  char salt[] = "$6$........";
  const char *const seedchars = "./0123456789ABCDEFGHIJKLMNOPQRST"
                                "UVWXYZabcdefghijklmnopqrstuvwxyz";
  char *password;
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++) {
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  }
  password = crypt(words, salt);
  return password;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mkpasswd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x2e2e2e2e2e243624,%rax
  mov    %rax,0x1c(%rsp)
  movl   $0x2e2e2e,0x24(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rbp
  mov    %rax,(%rsp)
  mov    $0x0,%eax
  call   <getpid@plt>
  shr    $0xe,%rbp
  and    $0x30000,%ebp
  xor    %rax,%rbp
  mov    %rbp,0x8(%rsp)
  mov    $0x0,%edx
  lea    0x1f(%rsp),%rdi
  lea    D9(%rip),%rsi
L13:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  movslq %eax,%r8
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  add    %ecx,%ecx
  mov    (%rsp,%r8,8),%rax
  shr    %cl,%rax
  and    $0x3f,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x8,%rdx
  jne    L13
  lea    0x1c(%rsp),%rsi
  mov    %rbx,%rdi
  call   <crypt@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *mkpasswd(const char *words) {
  unsigned long seed[2];
  char salt[] = "$6$........";
  const char *const seedchars = "./0123456789ABCDEFGHIJKLMNOPQRST"
                                "UVWXYZabcdefghijklmnopqrstuvwxyz";
  char *password;
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++) {
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  }
  password = crypt(words, salt);
  return password;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mkpasswd>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2e2e2e2e2e243624,%rax
  movl   $0x2e2e2e,0x24(%rsp)
  mov    %rax,0x1c(%rsp)
  call   <time@plt>
  mov    %rax,(%rsp)
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getpid@plt>
  lea    0x1f(%rsp),%rsi
  xor    %edx,%edx
  mov    $0xcccccccd,%edi
  mov    %rax,%r8
  mov    %rbx,%rax
  shr    $0xe,%rax
  and    $0x30000,%eax
  xor    %r8,%rax
  lea    D5(%rip),%r8
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  jmp    L9
  nopl   (%rax)
L27:
  mov    %edx,%eax
  mov    %rax,%rcx
  imul   %rdi,%rcx
  shr    $0x22,%rcx
  mov    (%rsp,%rcx,8),%rbx
L9:
  imul   %rdi,%rax
  add    $0x1,%rsi
  shr    $0x22,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  add    $0x1,%edx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  add    %ecx,%ecx
  shr    %cl,%rbx
  and    $0x3f,%ebx
  movzbl (%r8,%rbx,1),%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x8,%edx
  jne    L27
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <crypt@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *mkpasswd(const char *words) {
  unsigned long seed[2];
  char salt[] = "$6$........";
  const char *const seedchars = "./0123456789ABCDEFGHIJKLMNOPQRST"
                                "UVWXYZabcdefghijklmnopqrstuvwxyz";
  char *password;
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++) {
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  }
  password = crypt(words, salt);
  return password;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mkpasswd>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2e2e2e2e2e243624,%rax
  movl   $0x2e2e2e,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <time@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %rbx,%rdi
  mov    %rbx,%rcx
  mov    %rbx,%rsi
  shr    $0xe,%rdi
  mov    %rbx,%r8
  mov    %rbx,%r9
  shr    $0x18,%rbx
  and    $0x30000,%edi
  and    $0x3f,%ebx
  shr    $0x12,%r9
  and    $0x3f,%ecx
  shr    $0xc,%r8
  xor    %rax,%rdi
  and    $0x3f,%eax
  and    $0x3f,%r9d
  mov    %rdi,%r11
  shr    $0xc,%rdi
  mov    %rax,%r10
  and    $0x3f,%r8d
  lea    D1(%rip),%rdx
  shr    $0x6,%r11
  and    $0x3f,%edi
  shr    $0x6,%rsi
  movzbl (%rdx,%rdi,1),%eax
  and    $0x3f,%r11d
  and    $0x3f,%esi
  movzbl (%rdx,%r11,1),%edi
  movzbl (%rdx,%rsi,1),%esi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%r10,1),%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%rbx,1),%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%r9,1),%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%r8,1),%edi
  movzbl (%rdx,%rcx,1),%edx
  shl    $0x8,%rax
  or     %rdi,%rax
  mov    %rbp,%rdi
  shl    $0x8,%rax
  or     %rsi,%rax
  lea    0x8(%rsp),%rsi
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,0xb(%rsp)
  call   <crypt@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *mkpasswd(const char *words) {
  unsigned long seed[2];
  char salt[] = "$6$........";
  const char *const seedchars = "./0123456789ABCDEFGHIJKLMNOPQRST"
                                "UVWXYZabcdefghijklmnopqrstuvwxyz";
  char *password;
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++) {
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  }
  password = crypt(words, salt);
  return password;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<drawmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mvwprintw@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void drawmsg(WINDOW *w, int y, int x, int lines, char **msg) {
  int c;
  for (c = 0; c < lines; c++)
    mvwprintw(w, y + c, x, msg[c]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<drawmsg>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %edx,%r14d
  mov    %r8,%rbp
  mov    %esi,%ebx
  lea    (%rcx,%rsi,1),%r12d
L0:
  mov    0x0(%rbp),%rcx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <mvwprintw@plt>
  add    $0x8,%rbp
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  ret
```

assistant: ```c
void drawmsg(WINDOW *w, int y, int x, int lines, char **msg) {
  int c;
  for (c = 0; c < lines; c++)
    mvwprintw(w, y + c, x, msg[c]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<drawmsg>:
  endbr64
  test   %ecx,%ecx
  jle    L8
  push   %r14
  lea    (%rcx,%rsi,1),%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %esi,%ebx
  nop
L19:
  mov    0x0(%rbp),%rcx
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <mvwprintw@plt>
  cmp    %r14d,%ebx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void drawmsg(WINDOW *w, int y, int x, int lines, char **msg) {
  int c;
  for (c = 0; c < lines; c++)
    mvwprintw(w, y + c, x, msg[c]);
}
```
user: What is the c source code of the assembly code below:

```asm
<drawmsg>:
  endbr64
  test   %ecx,%ecx
  jle    L11
  push   %r14
  lea    (%rcx,%rsi,1),%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %esi,%ebx
  nop
L14:
  mov    0x0(%rbp),%rcx
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <mvwprintw@plt>
  cmp    %r14d,%ebx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void drawmsg(WINDOW *w, int y, int x, int lines, char **msg) {
  int c;
  for (c = 0; c < lines; c++)
    mvwprintw(w, y + c, x, msg[c]);
}
```
user: What is the c source code of the assembly code below?

```asm
<PrintTreeTabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L6:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: %s

assistant: ```c
void PrintTreeTabs(FILE *f, char *separator, int count) {
  int i;
  for (i = 0; i < count; i++)
    fprintf(f, "%s", separator);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PrintTreeTabs>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  lea    D7(%rip),%r14
L2:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: %s

assistant: ```c
void PrintTreeTabs(FILE *f, char *separator, int count) {
  int i;
  for (i = 0; i < count; i++)
    fprintf(f, "%s", separator);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PrintTreeTabs>:
  endbr64
  test   %edx,%edx
  jle    L4
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L12:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: %s

assistant: ```c
void PrintTreeTabs(FILE *f, char *separator, int count) {
  int i;
  for (i = 0; i < count; i++)
    fprintf(f, "%s", separator);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrintTreeTabs>:
  endbr64
  test   %edx,%edx
  jle    L0
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L12:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: %s

assistant: ```c
void PrintTreeTabs(FILE *f, char *separator, int count) {
  int i;
  for (i = 0; i < count; i++)
    fprintf(f, "%s", separator);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fizzbuzz@plt>
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string

tool: D9: %d: %s


assistant: ```c
int main() {
  for (int i = 0; i < 32; i++) {
    printf("%d: %s\n", i, fizzbuzz(i));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L7:
  mov    %ebx,%edi
  call   <fizzbuzz@plt>
  mov    %rax,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9: %d: %s


assistant: ```c
int main() {
  for (int i = 0; i < 32; i++) {
    printf("%d: %s\n", i, fizzbuzz(i));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <fizzbuzz@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  call   <printf@plt>
  cmp    $0x20,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: %d: %s


assistant: ```c
int main() {
  for (int i = 0; i < 32; i++) {
    printf("%d: %s\n", i, fizzbuzz(i));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <fizzbuzz@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  call   <printf@plt>
  cmp    $0x20,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %d: %s


assistant: ```c
int main() {
  for (int i = 0; i < 32; i++) {
    printf("%d: %s\n", i, fizzbuzz(i));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getScaledValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  %xmm4,-0x48(%rbp)
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x48(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double getScaledValue(double oldValue, double oldMin, double oldMax, double newMin, double newMax) {
  double oldRange = (oldMax - oldMin);
  double newRange = (newMax - newMin);
  double newValue = (((oldValue - oldMin) * newRange) / oldRange) + newMin;
  return newValue;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getScaledValue>:
  endbr64
  subsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm4
  mulsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

assistant: ```c
double getScaledValue(double oldValue, double oldMin, double oldMax, double newMin, double newMax) {
  double oldRange = (oldMax - oldMin);
  double newRange = (newMax - newMin);
  double newValue = (((oldValue - oldMin) * newRange) / oldRange) + newMin;
  return newValue;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getScaledValue>:
  endbr64
  subsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm4
  subsd  %xmm1,%xmm2
  mulsd  %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

assistant: ```c
double getScaledValue(double oldValue, double oldMin, double oldMax, double newMin, double newMax) {
  double oldRange = (oldMax - oldMin);
  double newRange = (newMax - newMin);
  double newValue = (((oldValue - oldMin) * newRange) / oldRange) + newMin;
  return newValue;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getScaledValue>:
  endbr64
  subsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm4
  subsd  %xmm1,%xmm2
  mulsd  %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

assistant: ```c
double getScaledValue(double oldValue, double oldMin, double oldMax, double newMin, double newMax) {
  double oldRange = (oldMax - oldMin);
  double newRange = (newMax - newMin);
  double newValue = (((oldValue - oldMin) * newRange) / oldRange) + newMin;
  return newValue;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nextMove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L87
L61:
  movl   $0x0,-0x1c(%rbp)
  jmp    L76
L8:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    $0x64,%al
  jne    L10
  mov    -0x20(%rbp),%eax
  mov    %ax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %ax,-0xa(%rbp)
  movl   $0x0,-0x18(%rbp)
L10:
  addl   $0x1,-0x1c(%rbp)
L76:
  cmpl   $0x4,-0x1c(%rbp)
  jle    L8
  addl   $0x1,-0x20(%rbp)
L87:
  cmpl   $0x4,-0x20(%rbp)
  jle    L61
  cmpl   $0x1,-0x18(%rbp)
  je     L91
  movzwl -0xc(%rbp),%eax
  cwtl
  cmp    %eax,-0x24(%rbp)
  jne    L44
  movzwl -0xa(%rbp),%eax
  cwtl
  cmp    %eax,-0x28(%rbp)
  jne    L44
L91:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L44:
  movzwl -0xa(%rbp),%eax
  cwtl
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L57
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L57:
  cmpl   $0x0,-0x14(%rbp)
  jle    L7
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L7:
  movzwl -0xc(%rbp),%eax
  cwtl
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L94
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L94:
  cmpl   $0x0,-0x10(%rbp)
  jle    L35
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L35:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L72
  call   <__stack_chk_fail@plt>
L72:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D47
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D11
type_infered: string
name: read_data
arguments: data_label: D46
type_infered: string
name: read_data
arguments: data_label: D32
type_infered: string

tool: D47: CLEAN


tool: D7: LEFT


tool: D11: RIGHT


tool: D46: UP


tool: D32: DOWN


assistant: ```c
void nextMove(int posr, int posc, char board[5][5]) {
  int i, j, up, left, flag = 1;
  short princess[2];
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 5; ++j) {
      if (board[i][j] == 'd') {
        princess[0] = i;
        princess[1] = j;
        flag = 0;
      }
    }
  }
  if (flag == 1 || princess[0] == posr && princess[1] == posc)
    printf("CLEAN\n");
  if ((left = princess[1] - posc) < 0) {
    printf("LEFT\n");
    return;
  } else if (left > 0) {
    printf("RIGHT\n");
    return;
  }
  if ((up = princess[0] - posr) < 0) {
    printf("UP\n");
    return;
  } else if (up > 0) {
    printf("DOWN\n");
    return;
  }
}
```