ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x19,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D24(%rip),%rbp
  jmp    L13
L25:
  movslq %ebx,%rdx
  mov    %eax,0x10(%rsp,%rdx,4)
  add    $0x1,%ebx
L73:
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jle    L41
L13:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  je     L73
  jmp    L25
L41:
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  cmp    $0x1,%eax
  jle    L32
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L1:
  mov    %ebx,%eax
  not    %eax
  add    0x8(%rsp),%eax
  cltq
  mov    0x10(%rsp,%rbx,4),%esi
  sub    0x10(%rsp,%rax,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L1
L32:
  testb  $0x1,0x8(%rsp)
  jne    L21
L4:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  movslq %ebp,%rbp
  mov    0x10(%rsp,%rbp,4),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string

tool: D24: %d

tool: D4: 
%d

tool: D14: 
%d


assistant: ```c
int main() {
  int i, n, Num, Odd[50] = {0}, brOdd = 0, Middle;
  scanf("%d", &n);
  do {
    scanf("%d", &Num);
    if (Num % 2 != 0) {
      Odd[brOdd] = Num;
      brOdd++;
    }
  } while (brOdd < n);
  Middle = n / 2;
  for (i = 0; i < Middle; i++) {
    printf("\n%d", Odd[i] - Odd[n - i - 1]);
  }
  if (n % 2 != 0) {
    printf("\n%d\n", Odd[Middle]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x19,%ecx
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  lea    0xc(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <scanf@plt>
  nop
L15:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  je     L71
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %eax,0x10(%rsp,%rdx,4)
L71:
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  cmp    %ebx,%eax
  jg     L15
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  cmp    $0x1,%eax
  jle    L6
  xor    %r13d,%r13d
  lea    D19(%rip),%r12
  jmp    L52
  nopl   0x0(%rax)
L54:
  mov    0x8(%rsp),%eax
L52:
  sub    %r13d,%eax
  mov    0x0(%rbp,%r13,4),%esi
  mov    %r12,%rdi
  add    $0x1,%r13
  sub    $0x1,%eax
  cltq
  sub    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  cmp    %r13d,%ebx
  jg     L54
  mov    0x8(%rsp),%edx
L6:
  and    $0x1,%edx
  jne    L47
L12:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  movslq %ebx,%rbx
  lea    D26(%rip),%rdi
  mov    0x10(%rsp,%rbx,4),%esi
  call   <printf@plt>
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D26
data_type: string

tool: D7: %d

tool: D19: 
%d

tool: D26: 
%d


assistant: ```c
int main() {
  int i, n, Num, Odd[50] = {0}, brOdd = 0, Middle;
  scanf("%d", &n);
  do {
    scanf("%d", &Num);
    if (Num % 2 != 0) {
      Odd[brOdd] = Num;
      brOdd++;
    }
  } while (brOdd < n);
  Middle = n / 2;
  for (i = 0; i < Middle; i++) {
    printf("\n%d", Odd[i] - Odd[n - i - 1]);
  }
  if (n % 2 != 0) {
    printf("\n%d\n", Odd[Middle]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x19,%ecx
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  lea    0xc(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <scanf@plt>
  nop
L60:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  je     L87
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %eax,0x10(%rsp,%rdx,4)
  mov    0x8(%rsp),%edx
  mov    %edx,%eax
  cmp    %edx,%ebx
  jl     L60
L93:
  mov    %edx,%ebx
  shr    $0x1f,%ebx
  add    %edx,%ebx
  sar    %ebx
  cmp    $0x1,%edx
  jle    L26
  xor    %r13d,%r13d
  lea    D25(%rip),%r12
  jmp    L92
  nopl   (%rax)
L23:
  mov    0x8(%rsp),%eax
L92:
  sub    %r13d,%eax
  mov    0x0(%rbp,%r13,4),%esi
  mov    %r12,%rdi
  add    $0x1,%r13
  sub    $0x1,%eax
  cltq
  sub    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  cmp    %r13d,%ebx
  jg     L23
  mov    0x8(%rsp),%edx
L26:
  and    $0x1,%edx
  jne    L30
L70:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  mov    0x8(%rsp),%edx
  mov    %edx,%eax
  cmp    %ebx,%edx
  jg     L60
  jmp    L93
L30:
  movslq %ebx,%rbx
  lea    D6(%rip),%rdi
  mov    0x10(%rsp,%rbx,4),%esi
  call   <printf@plt>
  jmp    L70
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D6
type: string

tool: D9: %d

tool: D25: 
%d

tool: D6: 
%d


assistant: ```c
int main() {
  int i, n, Num, Odd[50] = {0}, brOdd = 0, Middle;
  scanf("%d", &n);
  do {
    scanf("%d", &Num);
    if (Num % 2 != 0) {
      Odd[brOdd] = Num;
      brOdd++;
    }
  } while (brOdd < n);
  Middle = n / 2;
  for (i = 0; i < Middle; i++) {
    printf("\n%d", Odd[i] - Odd[n - i - 1]);
  }
  if (n % 2 != 0) {
    printf("\n%d\n", Odd[Middle]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_cpu_clwb_present>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <is_cpu_genuine_intel@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L2
L8:
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    $0x7,%edi
  call   <is_cpu_feature_present@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int is_cpu_clwb_present(void) {
  if (!is_cpu_genuine_intel())
    return 0;
  int ret = is_cpu_feature_present(0x7, 1, (1 << 24));
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_cpu_clwb_present>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <is_cpu_genuine_intel@plt>
  test   %eax,%eax
  jne    L19
L3:
  add    $0x8,%rsp
  ret
L19:
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    $0x7,%edi
  call   <is_cpu_feature_present@plt>
  jmp    L3
```

assistant: ```c
int is_cpu_clwb_present(void) {
  if (!is_cpu_genuine_intel())
    return 0;
  int ret = is_cpu_feature_present(0x7, 1, (1 << 24));
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_cpu_clwb_present>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <is_cpu_genuine_intel@plt>
  test   %eax,%eax
  jne    L1
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    $0x7,%edi
  add    $0x8,%rsp
  jmp    1070 <is_cpu_feature_present@plt>
```

assistant: ```c
int is_cpu_clwb_present(void) {
  if (!is_cpu_genuine_intel())
    return 0;
  int ret = is_cpu_feature_present(0x7, 1, (1 << 24));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_cpu_clwb_present>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <is_cpu_genuine_intel@plt>
  test   %eax,%eax
  jne    L9
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    $0x7,%edi
  add    $0x8,%rsp
  jmp    1070 <is_cpu_feature_present@plt>
```

assistant: ```c
int is_cpu_clwb_present(void) {
  if (!is_cpu_genuine_intel())
    return 0;
  int ret = is_cpu_feature_present(0x7, 1, (1 << 24));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jle    L12
  cmpl   $0x23,-0x34(%rbp)
  jle    L30
L12:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L23
L30:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L5
  negq   -0x28(%rbp)
L5:
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <div@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  lea    D3(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L5
  cmpq   $0x0,-0x18(%rbp)
  jns    L41
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
L41:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strreverse@plt>
L23:
  leave
  ret
```

assistant: ```c
void itoa(intptr_t value, char *str, int base) {
  static char num[] = "0123456789abcdefghijklmnopqrstuvwxyz";
  char *wstr = str;
  intptr_t sign;
  div_t res;
  if (base < 2 || base > 35) {
    *wstr = '\0';
    return;
  }
  if ((sign = value) < 0)
    value = -value;
  do {
    res = div(value, base);
    *wstr++ = num[res.rem];
  } while ((value = res.quot));
  if (sign < 0)
    *wstr++ = '-';
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%ebp
  lea    -0x2(%rdx),%eax
  neg    %rdi
  cmovs  %r13,%rdi
  mov    %rsi,%rbx
  lea    D9(%rip),%r12
  cmp    $0x21,%eax
  ja     L3
L7:
  mov    %ebp,%esi
  call   <div@plt>
  mov    %rbx,%rcx
  add    $0x1,%rbx
  movzbl (%r12,%rdx,1),%edx
  mov    %dl,-0x1(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L7
  test   %r13,%r13
  js     L36
L42:
  movb   $0x0,(%rbx)
  lea    -0x1(%rbx),%rsi
  mov    %r14,%rdi
  call   <strreverse@plt>
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  movb   $0x0,(%rsi)
  jmp    L26
L36:
  movb   $0x2d,(%rbx)
  lea    0x2(%rcx),%rbx
  jmp    L42
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
void itoa(intptr_t value, char *str, int base) {
  static char num[] = "0123456789abcdefghijklmnopqrstuvwxyz";
  char *wstr = str;
  intptr_t sign;
  div_t res;
  if (base < 2 || base > 35) {
    *wstr = '\0';
    return;
  }
  if ((sign = value) < 0)
    value = -value;
  do {
    res = div(value, base);
    *wstr++ = num[res.rem];
  } while ((value = res.quot));
  if (sign < 0)
    *wstr++ = '-';
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itoa>:
  endbr64
  push   %r14
  lea    -0x2(%rdx),%eax
  lea    D1(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  neg    %rdi
  push   %rbx
  cmovs  %rbp,%rdi
  mov    %edx,%ebx
  cmp    $0x21,%eax
  ja     L8
  nopl   (%rax)
L26:
  mov    %ebx,%esi
  call   <div@plt>
  mov    %r13,%rsi
  add    $0x1,%r13
  movzbl (%r14,%rdx,1),%edx
  mov    %rax,%rdi
  mov    %dl,-0x1(%r13)
  test   %rax,%rax
  jne    L26
  test   %rbp,%rbp
  js     L31
L38:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <strreverse@plt>
  nopl   0x0(%rax)
L31:
  lea    0x2(%rsi),%rax
  movb   $0x2d,0x0(%r13)
  mov    %r13,%rsi
  mov    %rax,%r13
  jmp    L38
  nopl   0x0(%rax)
L8:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
void itoa(intptr_t value, char *str, int base) {
  static char num[] = "0123456789abcdefghijklmnopqrstuvwxyz";
  char *wstr = str;
  intptr_t sign;
  div_t res;
  if (base < 2 || base > 35) {
    *wstr = '\0';
    return;
  }
  if ((sign = value) < 0)
    value = -value;
  do {
    res = div(value, base);
    *wstr++ = num[res.rem];
  } while ((value = res.quot));
  if (sign < 0)
    *wstr++ = '-';
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itoa>:
  endbr64
  push   %r14
  lea    -0x2(%rdx),%eax
  lea    D9(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  neg    %rdi
  push   %rbx
  cmovs  %rbp,%rdi
  mov    %edx,%ebx
  cmp    $0x21,%eax
  ja     L35
  nopl   (%rax)
L4:
  mov    %ebx,%esi
  call   <div@plt>
  mov    %r13,%rsi
  add    $0x1,%r13
  movzbl (%r14,%rdx,1),%edx
  mov    %rax,%rdi
  mov    %dl,-0x1(%r13)
  test   %rax,%rax
  jne    L4
  test   %rbp,%rbp
  js     L16
L30:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <strreverse@plt>
  nopl   0x0(%rax)
L16:
  lea    0x2(%rsi),%rax
  movb   $0x2d,0x0(%r13)
  mov    %r13,%rsi
  mov    %rax,%r13
  jmp    L30
  nopl   0x0(%rax)
L35:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
void itoa(intptr_t value, char *str, int base) {
  static char num[] = "0123456789abcdefghijklmnopqrstuvwxyz";
  char *wstr = str;
  intptr_t sign;
  div_t res;
  if (base < 2 || base > 35) {
    *wstr = '\0';
    return;
  }
  if ((sign = value) < 0)
    value = -value;
  do {
    res = div(value, base);
    *wstr++ = num[res.rem];
  } while ((value = res.quot));
  if (sign < 0)
    *wstr++ = '-';
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_remove_complex_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x58(%rbp)
  movl   $0x2c,-0x30(%rbp)
  movl   $0x60,-0x2c(%rbp)
  movl   $0x4c,-0x28(%rbp)
  movl   $0x2d,-0x24(%rbp)
  movl   $0x14,-0x20(%rbp)
  movl   $0x10,-0x1c(%rbp)
  movl   $0x1c,-0x18(%rbp)
  movq   $0x0,-0x50(%rbp)
  jmp    L18
L7:
  mov    -0x50(%rbp),%rax
  mov    -0x30(%rbp,%rax,4),%edx
  lea    -0x58(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  addq   $0x1,-0x50(%rbp)
L18:
  cmpq   $0x6,-0x50(%rbp)
  jbe    L7
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <test_tree_properties@plt>
  movl   $0x14,-0x40(%rbp)
  movl   $0x2d,-0x3c(%rbp)
  movl   $0x1c,-0x38(%rbp)
  movl   $0x4c,-0x34(%rbp)
  movq   $0x0,-0x48(%rbp)
  jmp    L28
L29:
  mov    -0x48(%rbp),%rax
  mov    -0x40(%rbp,%rax,4),%edx
  lea    -0x58(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <remove_node@plt>
  addq   $0x1,-0x48(%rbp)
L28:
  cmpq   $0x3,-0x48(%rbp)
  jbe    L29
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <test_tree_properties@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <free_tree@plt>
  movq   $0x0,-0x58(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void test_remove_complex_4() {
  struct Node *root = NULL;
  int items[] = {44, 96, 76, 45, 20, 16, 28};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {20, 45, 28, 76};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_remove_complex_4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x2c,0x20(%rsp)
  movl   $0x60,0x24(%rsp)
  movl   $0x4c,0x28(%rsp)
  movl   $0x2d,0x2c(%rsp)
  movl   $0x14,0x30(%rsp)
  movl   $0x10,0x34(%rsp)
  movl   $0x1c,0x38(%rsp)
  lea    0x20(%rsp),%rbx
  lea    0x3c(%rsp),%r12
  lea    0x8(%rsp),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  movl   $0x14,0x10(%rsp)
  movl   $0x2d,0x14(%rsp)
  movl   $0x1c,0x18(%rsp)
  movl   $0x4c,0x1c(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0x20(%rsp),%r12
  lea    0x8(%rsp),%rbp
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <remove_node@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    0x8(%rsp),%rdi
  call   <free_tree@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_remove_complex_4() {
  struct Node *root = NULL;
  int items[] = {44, 96, 76, 45, 20, 16, 28};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {20, 45, 28, 76};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_remove_complex_4>:
  endbr64
  push   %r12
  mov    $0x2c,%esi
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rbx
  lea    0x3c(%rsp),%r12
  movabs $0x4c00000060,%rax
  mov    %rax,0x24(%rsp)
  lea    0x8(%rsp),%rbp
  movabs $0x140000002d,%rax
  mov    %rax,0x2c(%rsp)
  movabs $0x1c00000010,%rax
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x34(%rsp)
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L43:
  mov    (%rbx),%esi
  add    $0x4,%rbx
L34:
  mov    %rbp,%rdi
  call   <insert@plt>
  cmp    %r12,%rbx
  jne    L43
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rbx
  lea    0x20(%rsp),%r12
  call   <test_tree_properties@plt>
  movl   $0x2d,0x14(%rsp)
  mov    $0x14,%esi
  movabs $0x4c0000001c,%rax
  mov    %rax,0x18(%rsp)
L20:
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <remove_node@plt>
  cmp    %rbx,%r12
  je     L45
  mov    (%rbx),%esi
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L45:
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    0x8(%rsp),%rdi
  call   <free_tree@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_remove_complex_4() {
  struct Node *root = NULL;
  int items[] = {44, 96, 76, 45, 20, 16, 28};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {20, 45, 28, 76};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_remove_complex_4>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r13
  lea    0x3c(%rsp),%r12
  mov    D29(%rip),%rax
  movl   $0x1c,0x38(%rsp)
  mov    %r13,%rbx
  lea    0x8(%rsp),%rbp
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <insert@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rbx
  call   <test_tree_properties@plt>
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <remove_node@plt>
  cmp    %rbx,%r13
  jne    L14
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    0x8(%rsp),%rdi
  call   <free_tree@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D29
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D9
datatype: byte[16]

tool: {"D12": [0x2c,0x00,0x00,0x00,0x60,0x00,0x00,0x00,0x4c,0x00,0x00,0x00,0x2d,0x00,0x00,0x00]}

tool: {"D29": [0x14,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: {"D9": [0x14,0x00,0x00,0x00,0x2d,0x00,0x00,0x00,0x1c,0x00,0x00,0x00,0x4c,0x00,0x00,0x00]}

assistant: ```c
void test_remove_complex_4() {
  struct Node *root = NULL;
  int items[] = {44, 96, 76, 45, 20, 16, 28};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {20, 45, 28, 76};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L29
L22:
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L23
L46:
  shll   -0x8(%rbp)
  sarl   -0x4(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L46
L18:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L18
  mov    -0x4(%rbp),%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int isqrt(int x) {
  int s, t;
  if (x == 0)
    return 0;
  s = 1;
  t = x;
  while (s < t) {
    s <<= 1;
    t >>= 1;
  }
  do {
    t = s;
    s = (x / s + s) >> 1;
  } while (s < t);
  return (t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isqrt>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  je     L12
  cmp    $0x1,%edi
  jle    L6
  mov    %edi,%eax
  mov    $0x1,%ecx
L1:
  add    %ecx,%ecx
  sar    %eax
  cmp    %eax,%ecx
  jl     L1
L4:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %ecx,%edx
  sar    %eax
  mov    %eax,%ecx
  cmp    %eax,%edx
  jg     L4
L12:
  mov    %edx,%eax
  ret
L6:
  mov    $0x1,%ecx
  jmp    L4
```

assistant: ```c
int isqrt(int x) {
  int s, t;
  if (x == 0)
    return 0;
  s = 1;
  t = x;
  while (s < t) {
    s <<= 1;
    t >>= 1;
  }
  do {
    t = s;
    s = (x / s + s) >> 1;
  } while (s < t);
  return (t);
}
```