user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  flds   0xfa9(%rip)        # 20d0 <_fini+0xe20>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  flds   0xf9a(%rip)        # 20d4 <_fini+0xe24>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D60(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  flds   0xf79(%rip)        # 20d8 <_fini+0xe28>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  flds   0xf6a(%rip)        # 20dc <_fini+0xe2c>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  fldl   0xf51(%rip)        # 20e8 <_fini+0xe38>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  fldl   0xf46(%rip)        # 20f0 <_fini+0xe40>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  fldl   0xf19(%rip)        # 20e8 <_fini+0xe38>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  fldl   0xf0e(%rip)        # 20f0 <_fini+0xe40>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  flds   0xed9(%rip)        # 20e0 <_fini+0xe30>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  flds   0xeca(%rip)        # 20e4 <_fini+0xe34>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  fldl   0xeb9(%rip)        # 20f8 <_fini+0xe48>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  fldl   0xeae(%rip)        # 2100 <_fini+0xe50>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  fldl   0xe81(%rip)        # 20f8 <_fini+0xe48>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  fldl   0xe7e(%rip)        # 2108 <_fini+0xe58>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D60
type: string
name: disassemble_data
arguments: tag: D34
type: string
name: disassemble_data
arguments: tag: D21
type: string
name: disassemble_data
arguments: tag: D36
type: string
name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D53
type: string

tool: D60: Short: %i + 10 = %i


tool: D34: Int: %i + 1000000000 = %i


tool: D21: Long: %li + 1000000000000000000 = %li


tool: D36: Long long: %lli + 1000000000000000000 = %lli


tool: D17: Float: %f / 2 = %f


tool: D0: Double: %f / 4 = %f


tool: D53: Long double: %Lf / 4 = %Lf


assistant: ```c
int main() {
  short shr = 32767;
  short shr2 = shr + 10;
  printf("Short: %i + 10 = %i\n", shr, shr2);
  int in = 2000000000;
  int in2 = in + 1000000000;
  printf("Int: %i + 1000000000 = %i\n", in, in2);
  long lg = 9000000000000000000;
  long lg2 = lg + 1000000000000000000;
  printf("Long: %li + 1000000000000000000 = %li\n", lg, lg2);
  long long llg = 9000000000000000000;
  long long llg2 = llg + 1000000000000000000;
  printf("Long long: %lli + 1000000000000000000 = %lli\n", llg, llg2);
  float fl = 0.000001;
  float fl2 = fl / 2.0;
  printf("Float: %f / 2 = %f\n", fl, fl2);
  double dl = 0.000003;
  double dl2 = dl / 4.0;
  printf("Double: %f / 4 = %f\n", dl, dl2);
  long double ldl = 0.00000000000000005;
  long double ldl2 = dl / 4.0;
  printf("Long double: %Lf / 4 = %Lf\n", ldl, ldl2);
  return 0;
}
```