ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  jle    L3
  mov    0x8(%rsi),%rbx
  mov    %rbx,%rdi
  call   <doTest@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  mov    %rbx,%rdi
  call   <doTest@plt>
  mov    $0x0,%eax
L13:
  pop    %rbx
  ret
L3:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L13
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: Please enter the filename 


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Please enter the filename \r\n");
    return 1;
  }
  char *file = argv[1];
  doTest(file);
  setuid(getuid());
  doTest(file);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  cmp    $0x1,%edi
  jle    L7
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <doTest@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  mov    %rbp,%rdi
  call   <doTest@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: Please enter the filename 


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Please enter the filename \r\n");
    return 1;
  }
  char *file = argv[1];
  doTest(file);
  setuid(getuid());
  doTest(file);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  cmp    $0x1,%edi
  jle    L6
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <doTest@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  mov    %rbp,%rdi
  call   <doTest@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: Please enter the filename 


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Please enter the filename \r\n");
    return 1;
  }
  char *file = argv[1];
  doTest(file);
  setuid(getuid());
  doTest(file);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test(int j) {
  int i;
  i = j * 4;
  return i + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  lea    0x1(,%rdi,4),%eax
  ret
```

assistant: ```c
int test(int j) {
  int i;
  i = j * 4;
  return i + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  lea    0x1(,%rdi,4),%eax
  ret
```

assistant: ```c
int test(int j) {
  int i;
  i = j * 4;
  return i + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  lea    0x1(,%rdi,4),%eax
  ret
```

assistant: ```c
int test(int j) {
  int i;
  i = j * 4;
  return i + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clGetKernelWorkGroupInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x412,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
cl_int clGetKernelWorkGroupInfo(cl_kernel kernel, cl_device_id device, cl_kernel_work_group_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[6];
  sys_args[0] = (unsigned int)kernel;
  sys_args[1] = (unsigned int)device;
  sys_args[2] = (unsigned int)param_name;
  sys_args[3] = (unsigned int)param_value_size;
  sys_args[4] = (unsigned int)param_value;
  sys_args[5] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1042, sys_args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clGetKernelWorkGroupInfo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %r9d,0x14(%rsp)
  mov    %rsp,%rdx
  mov    $0x412,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetKernelWorkGroupInfo(cl_kernel kernel, cl_device_id device, cl_kernel_work_group_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[6];
  sys_args[0] = (unsigned int)kernel;
  sys_args[1] = (unsigned int)device;
  sys_args[2] = (unsigned int)param_name;
  sys_args[3] = (unsigned int)param_value_size;
  sys_args[4] = (unsigned int)param_value;
  sys_args[5] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1042, sys_args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clGetKernelWorkGroupInfo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x145,%edi
  mov    %esi,0x4(%rsp)
  mov    $0x412,%esi
  mov    %edx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %r9d,0x14(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetKernelWorkGroupInfo(cl_kernel kernel, cl_device_id device, cl_kernel_work_group_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[6];
  sys_args[0] = (unsigned int)kernel;
  sys_args[1] = (unsigned int)device;
  sys_args[2] = (unsigned int)param_name;
  sys_args[3] = (unsigned int)param_value_size;
  sys_args[4] = (unsigned int)param_value;
  sys_args[5] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1042, sys_args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clGetKernelWorkGroupInfo>:
  endbr64
  movd   %edx,%xmm1
  movd   %edi,%xmm0
  movd   %esi,%xmm3
  sub    $0x28,%rsp
  movd   %ecx,%xmm2
  punpckldq %xmm3,%xmm0
  movd   %r9d,%xmm4
  mov    %rsp,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpckldq %xmm2,%xmm1
  mov    $0x412,%esi
  mov    $0x145,%edi
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  movd   %r8d,%xmm0
  punpckldq %xmm4,%xmm0
  movq   %xmm0,0x10(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetKernelWorkGroupInfo(cl_kernel kernel, cl_device_id device, cl_kernel_work_group_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[6];
  sys_args[0] = (unsigned int)kernel;
  sys_args[1] = (unsigned int)device;
  sys_args[2] = (unsigned int)param_name;
  sys_args[3] = (unsigned int)param_value_size;
  sys_args[4] = (unsigned int)param_value;
  sys_args[5] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1042, sys_args);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_bench>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L26
L16:
  mov    -0x34(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x34(%rbp),%eax
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x34(%rbp)
L26:
  cmpl   $0x16,-0x34(%rbp)
  ja     L43
  mov    -0x34(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
L43:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  mov    %eax,%eax
  movb   $0x3a,-0x30(%rbp,%rax,1)
  jmp    L49
L72:
  mov    -0x34(%rbp),%eax
  movb   $0x20,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x34(%rbp)
L49:
  cmpl   $0x17,-0x34(%rbp)
  jbe    L72
  mov    -0x34(%rbp),%eax
  movb   $0x0,-0x30(%rbp,%rax,1)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L6
L53:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  lea    0x0(,%rax,8),%rcx
  mov    -0x50(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x34(%rbp),%eax
  lea    0x0(,%rax,8),%rsi
  mov    -0x50(%rbp),%rax
  add    %rsi,%rax
  sub    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x34(%rbp)
L6:
  mov    -0x54(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  jb     L53
  mov    -0x54(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <median@plt>
  mov    %eax,%edi
  call   <printllu@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: 


assistant: ```c
void print_bench(const char *s, unsigned long long *t, unsigned int tlen) {
  char outs[25];
  unsigned int i = 0;
  while ((i < 23) && (s[i] != 0)) {
    outs[i] = s[i];
    i++;
  }
  outs[i++] = ':';
  for (; i < 24; i++)
    outs[i] = ' ';
  outs[i] = 0;
  print(outs);
  for (i = 0; i < tlen - 1; i++)
    t[i] = t[i + 1] - t[i];
  printllu(median(t, tlen - 1));
  print("\r\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_bench>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
L53:
  mov    %eax,%ecx
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L28
  mov    %dl,(%rsp,%rax,1)
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    $0x17,%rax
  jne    L53
L28:
  lea    0x1(%rcx),%eax
  mov    %ecx,%edx
  movb   $0x3a,(%rsp,%rdx,1)
  cmp    $0x17,%eax
  ja     L7
  mov    %eax,%edx
  lea    (%rsp,%rdx,1),%rax
  lea    0x1(%rsp,%rdx,1),%rdx
  mov    $0x16,%esi
  sub    %ecx,%esi
  add    %rsi,%rdx
L57:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L57
  mov    $0x18,%eax
L7:
  mov    %eax,%eax
  movb   $0x0,(%rsp,%rax,1)
  mov    %rsp,%rdi
  call   <print@plt>
  mov    %ebp,%esi
  sub    $0x1,%esi
  je     L10
  mov    %rbx,%rax
  lea    -0x2(%rbp),%edx
  lea    0x8(%rbx,%rdx,8),%rcx
L18:
  mov    0x8(%rax),%rdx
  sub    (%rax),%rdx
  mov    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L18
L10:
  mov    %rbx,%rdi
  call   <median@plt>
  mov    %eax,%edi
  call   <printllu@plt>
  lea    D2(%rip),%rdi
  call   <print@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: 


assistant: ```c
void print_bench(const char *s, unsigned long long *t, unsigned int tlen) {
  char outs[25];
  unsigned int i = 0;
  while ((i < 23) && (s[i] != 0)) {
    outs[i] = s[i];
    i++;
  }
  outs[i++] = ':';
  for (; i < 24; i++)
    outs[i] = ' ';
  outs[i] = 0;
  print(outs);
  for (i = 0; i < tlen - 1; i++)
    t[i] = t[i + 1] - t[i];
  printllu(median(t, tlen - 1));
  print("\r\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_bench>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  jmp    L46
  nopl   0x0(%rax)
L83:
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x17,%rax
  je     L141
L46:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  lea    0x1(%rax),%ecx
  test   %dl,%dl
  jne    L83
  mov    $0x18,%eax
  movb   $0x3a,(%rsp,%rsi,1)
  movabs $0x2020202020202020,%rsi
  sub    %ecx,%eax
  add    %r8,%rcx
  cmp    $0x8,%eax
  jb     L13
  lea    0x8(%rcx),%rdi
  mov    %eax,%edx
  mov    %rsi,(%rcx)
  and    $0xfffffffffffffff8,%rdi
  mov    %rsi,-0x8(%rcx,%rdx,1)
  sub    %rdi,%rcx
  add    %ecx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L56
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L129:
  mov    %edx,%ecx
  add    $0x8,%edx
  mov    %rsi,(%rdi,%rcx,1)
  cmp    %eax,%edx
  jb     L129
L56:
  mov    %r8,%rdi
  movb   $0x0,0x18(%rsp)
  call   <print@plt>
  mov    %ebx,%esi
  sub    $0x1,%esi
  je     L54
  lea    -0x2(%rbx),%edx
  mov    %rbp,%rax
  lea    0x8(%rbp,%rdx,8),%rcx
  nopl   0x0(%rax,%rax,1)
L71:
  mov    0x8(%rax),%rdx
  sub    (%rax),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L71
L54:
  mov    %rbp,%rdi
  call   <median@plt>
  mov    %eax,%edi
  call   <printllu@plt>
  lea    D3(%rip),%rdi
  call   <print@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  test   $0x4,%al
  jne    L19
  test   %eax,%eax
  je     L56
  movb   $0x20,(%rcx)
  test   $0x2,%al
  je     L56
  mov    $0x2020,%edx
  mov    %dx,-0x2(%rcx,%rax,1)
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L141:
  movb   $0x3a,0x17(%rsp)
  jmp    L56
L19:
  movl   $0x20202020,(%rcx)
  movl   $0x20202020,-0x4(%rcx,%rax,1)
  jmp    L56
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: 


assistant: ```c
void print_bench(const char *s, unsigned long long *t, unsigned int tlen) {
  char outs[25];
  unsigned int i = 0;
  while ((i < 23) && (s[i] != 0)) {
    outs[i] = s[i];
    i++;
  }
  outs[i++] = ':';
  for (; i < 24; i++)
    outs[i] = ' ';
  outs[i] = 0;
  print(outs);
  for (i = 0; i < tlen - 1; i++)
    t[i] = t[i + 1] - t[i];
  printllu(median(t, tlen - 1));
  print("\r\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_bench>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  jmp    L6
  nopl   0x0(%rax)
L123:
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x17,%rax
  je     L178
L6:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  lea    0x1(%rax),%ecx
  test   %dl,%dl
  jne    L123
  mov    $0x18,%eax
  movb   $0x3a,(%rsp,%rsi,1)
  movabs $0x2020202020202020,%rsi
  sub    %ecx,%eax
  add    %r8,%rcx
  cmp    $0x8,%eax
  jb     L76
  lea    0x8(%rcx),%rdi
  mov    %eax,%edx
  mov    %rsi,(%rcx)
  and    $0xfffffffffffffff8,%rdi
  mov    %rsi,-0x8(%rcx,%rdx,1)
  sub    %rdi,%rcx
  add    %ecx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L58
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L94:
  mov    %edx,%ecx
  add    $0x8,%edx
  mov    %rsi,(%rdi,%rcx,1)
  cmp    %eax,%edx
  jb     L94
L58:
  mov    %r8,%rdi
  movb   $0x0,0x18(%rsp)
  call   <print@plt>
  mov    %ebx,%esi
  sub    $0x1,%esi
  je     L152
  cmp    $0x2,%ebx
  je     L43
  mov    %esi,%edx
  mov    %rbp,%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbp,%rdx,1),%rdx
  nopl   0x0(%rax)
L79:
  movdqu 0x8(%rax),%xmm0
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  psubq  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L79
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L152
L27:
  mov    %eax,%edx
  add    $0x1,%eax
  lea    0x0(%rbp,%rdx,8),%rdx
  mov    0x0(%rbp,%rax,8),%rax
  sub    (%rdx),%rax
  mov    %rax,(%rdx)
L152:
  mov    %rbp,%rdi
  call   <median@plt>
  mov    %eax,%edi
  call   <printllu@plt>
  lea    D3(%rip),%rdi
  call   <print@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L76:
  test   $0x4,%al
  jne    L20
  test   %eax,%eax
  je     L58
  movb   $0x20,(%rcx)
  test   $0x2,%al
  je     L58
  mov    $0x2020,%edx
  mov    %dx,-0x2(%rcx,%rax,1)
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L178:
  movb   $0x3a,0x17(%rsp)
  jmp    L58
L43:
  xor    %eax,%eax
  jmp    L27
L20:
  movl   $0x20202020,(%rcx)
  movl   $0x20202020,-0x4(%rcx,%rax,1)
  jmp    L58
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: 


assistant: ```c
void print_bench(const char *s, unsigned long long *t, unsigned int tlen) {
  char outs[25];
  unsigned int i = 0;
  while ((i < 23) && (s[i] != 0)) {
    outs[i] = s[i];
    i++;
  }
  outs[i++] = ':';
  for (; i < 24; i++)
    outs[i] = ' ';
  outs[i] = 0;
  print(outs);
  for (i = 0; i < tlen - 1; i++)
    t[i] = t[i + 1] - t[i];
  printllu(median(t, tlen - 1));
  print("\r\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<multiply89>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L4
L26:
  movl   $0x0,-0x3c(%rbp)
  jmp    L38
L11:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L38:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L11
  addl   $0x1,-0x40(%rbp)
L4:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L26
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply89(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiply89>:
  endbr64
  test   %edi,%edi
  jle    L23
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L0:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L13:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L13
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  ret
```

assistant: ```c
void multiply89(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<multiply89>:
  endbr64
  test   %edi,%edi
  jle    L26
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L27
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L9
  pop    %rbx
  ret
L26:
  ret
```

assistant: ```c
void multiply89(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<multiply89>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L16
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L10:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L99
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L99
  nopl   0x0(%rax)
L77:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L77
  cmp    -0x24(%rsp),%r11d
  je     L87
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L87
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L87
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L87:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L10
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L99:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L68:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L68
  mov    -0x18(%rsp),%r8
  jmp    L87
```

assistant: ```c
void multiply89(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```