ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<alloc_matrix>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
  test   %rbp,%rbp
  je     L39
  imul   %rbx,%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L51:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,(%r12,%rbx,8)
  test   %rax,%rax
  je     L53
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L51
L39:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  test   %rbx,%rbx
  je     L66
  mov    %r12,%rbp
  lea    (%r12,%rbx,8),%rbx
L69:
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L69
L66:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L39
```

assistant: ```c
void **alloc_matrix(size_t height, size_t width, size_t elem_size) {
  size_t i;
  int j;
  void **result = calloc(height, sizeof(void *));
  if (result == NULL) {
    return NULL;
  }
  for (i = 0; i < height; i++) {
    result[i] = malloc(width * elem_size);
    if (result[i] == NULL) {
      for (j = 0; j < i; j++) {
        free(result[j]);
      }
      free(result);
      return NULL;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alloc_matrix>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L52
  test   %rbp,%rbp
  je     L52
  imul   %rbx,%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L59:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,(%r12,%rbx,8)
  test   %rax,%rax
  je     L61
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L59
L52:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  test   %rbx,%rbx
  je     L19
  mov    %r12,%rbp
  lea    (%r12,%rbx,8),%rbx
L9:
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L9
L19:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L52
```

assistant: ```c
void **alloc_matrix(size_t height, size_t width, size_t elem_size) {
  size_t i;
  int j;
  void **result = calloc(height, sizeof(void *));
  if (result == NULL) {
    return NULL;
  }
  for (i = 0; i < height; i++) {
    result[i] = malloc(width * elem_size);
    if (result[i] == NULL) {
      for (j = 0; j < i; j++) {
        free(result[j]);
      }
      free(result);
      return NULL;
    }
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mid_trunc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x2d2d2d,0x4(%rsp)
  cmp    $0x8,%rdx
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  je     L105
  cmpb   $0x0,0x0(%rbp)
  jne    L161
L105:
  test   %rbx,%rbx
  je     L74
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
L162:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  lea    0x4(%rsp),%rdi
  call   <mkstring@plt>
  jmp    L162
L161:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  cmp    %rax,%r12
  jb     L32
  test   %rbx,%rbx
  je     L108
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  jmp    L162
L108:
  mov    %rbp,%rdi
  call   <mkstring@plt>
  jmp    L162
L32:
  test   %rbx,%rbx
  je     L91
L52:
  mov    %r12,%rdi
  shr    %rdi
  mov    %rdi,%rcx
  sub    $0x3,%rcx
  je     L25
  mov    $0x0,%eax
L67:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L67
L25:
  movb   $0x2e,-0x3(%rbx,%rdi,1)
  movb   $0x2e,0x1(%rbx,%rcx,1)
  lea    0x3(%rcx),%rsi
  movb   $0x2e,0x2(%rbx,%rcx,1)
  sub    %rdi,%r13
  cmp    %rsi,%r12
  jbe    L93
  mov    %rsi,%rax
  sub    %rcx,%r13
  add    %r13,%rbp
L124:
  movzbl -0x3(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L124
  lea    -0x2(%rsi,%rdx,1),%rsi
  sub    %rcx,%rsi
L93:
  movb   $0x0,(%rbx,%rsi,1)
  mov    %rbx,%rax
  jmp    L162
L91:
  lea    0x1(%r12),%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  test   %rdx,%rdx
  je     L162
  mov    %rdx,%rbx
  jmp    L52
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *mid_trunc(char *str, const char *input, unsigned long len) {
  unsigned long ilen;
  unsigned long middle;
  unsigned long i, j;
  char defstr[4] = "---";
  assert(len > 8);
  if ((input == NULL) || (input[0] == 0)) {
    if (NULL == str) {
      return (mkstring(defstr));
    } else {
      strcpy(str, defstr);
      return (str);
    }
  }
  ilen = strlen(input);
  if (ilen <= len) {
    if (NULL == str)
      return (mkstring(input));
    else {
      strcpy(str, input);
      return (str);
    }
  } else {
    if (NULL == str) {
      if (NULL == (str = (char *)malloc(len + 1)))
        return (NULL);
    }
    middle = (len / 2) - 3;
    i = 0;
    while (i < middle) {
      str[i] = input[i];
      i++;
    }
    str[i++] = '.';
    str[i++] = '.';
    str[i++] = '.';
    j = ilen - (len / 2);
    while (i < len) {
      str[i] = input[j];
      i++;
      j++;
    }
    str[i] = 0;
    return (str);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<taa_h264_hadamard_2x2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x40(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x80(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0xc0(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    -0x18(%rbp),%rdx
  add    $0x40,%rdx
  sub    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    $0xffffffffffffff80,%rdx
  sub    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0xc0,%rax
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void taa_h264_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<taa_h264_hadamard_2x2>:
  endbr64
  mov    (%rdi),%eax
  mov    0x80(%rdi),%ecx
  mov    %eax,%edx
  add    0x40(%rdi),%edx
  lea    (%rdx,%rcx,1),%esi
  add    0xc0(%rdi),%esi
  mov    %esi,(%rdi)
  sub    0x40(%rdi),%eax
  lea    (%rax,%rcx,1),%esi
  sub    0xc0(%rdi),%esi
  mov    %esi,0x40(%rdi)
  sub    %ecx,%edx
  sub    0xc0(%rdi),%edx
  mov    %edx,0x80(%rdi)
  sub    %ecx,%eax
  add    0xc0(%rdi),%eax
  mov    %eax,0xc0(%rdi)
  ret
```

assistant: ```c
void taa_h264_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
}
```
user: What is the c source code of the assembly code below?

```asm
<taa_h264_hadamard_2x2>:
  endbr64
  mov    (%rdi),%eax
  mov    0x40(%rdi),%edx
  mov    0x80(%rdi),%ecx
  add    %eax,%edx
  sub    0x40(%rdi),%eax
  lea    (%rdx,%rcx,1),%esi
  add    0xc0(%rdi),%esi
  sub    %ecx,%edx
  sub    0xc0(%rdi),%edx
  mov    %esi,(%rdi)
  lea    (%rax,%rcx,1),%esi
  sub    %ecx,%eax
  sub    0xc0(%rdi),%esi
  add    0xc0(%rdi),%eax
  mov    %esi,0x40(%rdi)
  mov    %edx,0x80(%rdi)
  mov    %eax,0xc0(%rdi)
  ret
```

assistant: ```c
void taa_h264_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<taa_h264_hadamard_2x2>:
  endbr64
  mov    (%rdi),%eax
  mov    0x40(%rdi),%edx
  mov    0x80(%rdi),%ecx
  add    %eax,%edx
  sub    0x40(%rdi),%eax
  lea    (%rdx,%rcx,1),%esi
  add    0xc0(%rdi),%esi
  sub    %ecx,%edx
  sub    0xc0(%rdi),%edx
  mov    %esi,(%rdi)
  lea    (%rax,%rcx,1),%esi
  sub    %ecx,%eax
  sub    0xc0(%rdi),%esi
  add    0xc0(%rdi),%eax
  mov    %esi,0x40(%rdi)
  mov    %edx,0x80(%rdi)
  mov    %eax,0xc0(%rdi)
  ret
```

assistant: ```c
void taa_h264_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compare_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L84:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  jmp    L50
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L33
  mov    $0x0,%eax
  jmp    L50
L33:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L48
  addq   $0x1,-0x20(%rbp)
  jmp    L56
L48:
  mov    $0x0,%eax
  jmp    L50
L56:
  addq   $0x1,-0x18(%rbp)
L16:
  cmpq   $0x0,-0x18(%rbp)
  jne    L84
  mov    $0x0,%eax
L50:
  pop    %rbp
  ret
```

assistant: ```c
char *compare_str(char *main, char *substr) {
  char *tmp_sub = substr;
  while (main) {
    if (*substr == '\n') {
      return tmp_sub;
    } else if (*main == '\n') {
      return NULL;
    } else if (*substr == *main) {
      substr++;
    } else {
      return NULL;
    }
    main++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compare_str>:
  endbr64
  test   %rdi,%rdi
  je     L9
  mov    $0x0,%edx
L8:
  movzbl (%rsi,%rdx,1),%ecx
  cmp    $0xa,%cl
  je     L37
  movzbl (%rdi,%rdx,1),%r8d
  add    $0x1,%rdx
  cmp    %r8b,%cl
  jne    L39
  cmp    $0xa,%r8b
  jne    L8
L39:
  mov    $0x0,%eax
  ret
L9:
  mov    %rdi,%rax
  ret
L37:
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *compare_str(char *main, char *substr) {
  char *tmp_sub = substr;
  while (main) {
    if (*substr == '\n') {
      return tmp_sub;
    } else if (*main == '\n') {
      return NULL;
    } else if (*substr == *main) {
      substr++;
    } else {
      return NULL;
    }
    main++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_str>:
  endbr64
  test   %rdi,%rdi
  je     L12
  xor    %edx,%edx
  jmp    L35
  nopl   (%rax)
L13:
  movzbl (%rdi,%rdx,1),%r8d
  add    $0x1,%rdx
  cmp    $0xa,%r8b
  je     L12
  cmp    %r8b,%cl
  jne    L12
L35:
  movzbl (%rsi,%rdx,1),%ecx
  cmp    $0xa,%cl
  jne    L13
  mov    %rsi,%rax
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *compare_str(char *main, char *substr) {
  char *tmp_sub = substr;
  while (main) {
    if (*substr == '\n') {
      return tmp_sub;
    } else if (*main == '\n') {
      return NULL;
    } else if (*substr == *main) {
      substr++;
    } else {
      return NULL;
    }
    main++;
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compare_str>:
  endbr64
  test   %rdi,%rdi
  je     L21
  xor    %edx,%edx
  jmp    L30
  nopl   (%rax)
L49:
  movzbl (%rdi,%rdx,1),%r8d
  add    $0x1,%rdx
  cmp    $0xa,%r8b
  je     L21
  cmp    %r8b,%cl
  jne    L21
L30:
  movzbl (%rsi,%rdx,1),%ecx
  cmp    $0xa,%cl
  jne    L49
  mov    %rsi,%rax
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *compare_str(char *main, char *substr) {
  char *tmp_sub = substr;
  while (main) {
    if (*substr == '\n') {
      return tmp_sub;
    } else if (*main == '\n') {
      return NULL;
    } else if (*substr == *main) {
      substr++;
    } else {
      return NULL;
    }
    main++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x149,-0x30(%rbp)
  movl   $0x1c9,-0x2c(%rbp)
  movl   $0x291,-0x28(%rbp)
  movl   $0x347,-0x24(%rbp)
  movl   $0x1b4,-0x20(%rbp)
  movl   $0x2d0,-0x1c(%rbp)
  movl   $0x163,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <RADIX_SORT@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L0
L3:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L0:
  cmpl   $0x6,-0x34(%rbp)
  jle    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: %d	

assistant: ```c
int main(void) {
  int i;
  int A[] = {329, 457, 657, 839, 436, 720, 355};
  RADIX_SORT(A, 7, 3);
  for (i = 0; i < 7; i++)
    printf("%d\t", A[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x149,(%rsp)
  movl   $0x1c9,0x4(%rsp)
  movl   $0x291,0x8(%rsp)
  movl   $0x347,0xc(%rsp)
  movl   $0x1b4,0x10(%rsp)
  movl   $0x2d0,0x14(%rsp)
  movl   $0x163,0x18(%rsp)
  mov    %rsp,%rbx
  mov    $0x3,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <RADIX_SORT@plt>
  lea    0x1c(%rsp),%r12
  lea    D6(%rip),%rbp
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: %d	

assistant: ```c
int main(void) {
  int i;
  int A[] = {329, 457, 657, 839, 436, 720, 355};
  RADIX_SORT(A, 7, 3);
  for (i = 0; i < 7; i++)
    printf("%d\t", A[i]);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edx
  mov    $0x7,%esi
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x1c900000149,%rax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  movl   $0x163,0x18(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x34700000291,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2d0000001b4,%rax
  mov    %rax,0x10(%rsp)
  call   <RADIX_SORT@plt>
  nop
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: %d	

assistant: ```c
int main(void) {
  int i;
  int A[] = {329, 457, 657, 839, 436, 720, 355};
  RADIX_SORT(A, 7, 3);
  for (i = 0; i < 7; i++)
    printf("%d\t", A[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edx
  mov    $0x7,%esi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    D19(%rip),%rax
  mov    %rbx,%rdi
  movl   $0x163,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <RADIX_SORT@plt>
  nopl   (%rax)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D1
type: byte[16]
name: unpack_data
arguments: data_label: D19
type: byte[8]

tool: D3: %d	

tool: {"D1": [0x49,0x01,0x00,0x00,0xc9,0x01,0x00,0x00,0x91,0x02,0x00,0x00,0x47,0x03,0x00,0x00]}

tool: {"D19": [0xb4,0x01,0x00,0x00,0xd0,0x02,0x00,0x00]}

assistant: ```c
int main(void) {
  int i;
  int A[] = {329, 457, 657, 839, 436, 720, 355};
  RADIX_SORT(A, 7, 3);
  for (i = 0; i < 7; i++)
    printf("%d\t", A[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<integer_to_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L23
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    -0x4(%rbp),%eax
  jmp    L10
L2:
  negl   -0x14(%rbp)
L23:
  mov    -0x18(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <int_to_words@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: minus 

assistant: ```c
int integer_to_words(int number, char *buffer, int buflen) {
  int rc = 0;
  if (number < 0) {
    rc = snprintf(buffer, buflen, "minus ");
    if (rc < 0)
      return rc;
    number = -number;
  }
  rc = int_to_words(number, &buffer[rc], buflen - rc);
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<integer_to_words>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    $0x0,%eax
  test   %edi,%edi
  js     L0
L10:
  mov    %ebp,%edx
  sub    %eax,%edx
  cltq
  lea    (%rbx,%rax,1),%rsi
  mov    %r12d,%edi
  call   <int_to_words@plt>
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  lea    D5(%rip),%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  test   %eax,%eax
  js     L2
  neg    %r12d
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: minus 

assistant: ```c
int integer_to_words(int number, char *buffer, int buflen) {
  int rc = 0;
  if (number < 0) {
    rc = snprintf(buffer, buflen, "minus ");
    if (rc < 0)
      return rc;
    number = -number;
  }
  rc = int_to_words(number, &buffer[rc], buflen - rc);
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<integer_to_words>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  test   %edi,%edi
  js     L24
L4:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <int_to_words@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  lea    D3(%rip),%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  test   %eax,%eax
  js     L16
  sub    %eax,%r13d
  cltq
  neg    %ebp
  add    %rax,%r12
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L16:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: minus 

assistant: ```c
int integer_to_words(int number, char *buffer, int buflen) {
  int rc = 0;
  if (number < 0) {
    rc = snprintf(buffer, buflen, "minus ");
    if (rc < 0)
      return rc;
    number = -number;
  }
  rc = int_to_words(number, &buffer[rc], buflen - rc);
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<integer_to_words>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  test   %edi,%edi
  js     L2
L20:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <int_to_words@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D6(%rip),%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  test   %eax,%eax
  js     L3
  sub    %eax,%r13d
  cltq
  neg    %ebp
  add    %rax,%r12
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L3:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: minus 

assistant: ```c
int integer_to_words(int number, char *buffer, int buflen) {
  int rc = 0;
  if (number < 0) {
    rc = snprintf(buffer, buflen, "minus ");
    if (rc < 0)
      return rc;
    number = -number;
  }
  rc = int_to_words(number, &buffer[rc], buflen - rc);
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerUpdateConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  and    $0xfffffffffffffffd,%rdx
  mov    %rdx,(%rax)
  jmp    L8
L5:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  or     $0x2,%rdx
  mov    %rdx,(%rax)
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerUpdateConfigure(unsigned long ulBase, unsigned long ulUpdate) {

  ;

  ;
  if (ulUpdate == 0x00000000) {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) &= ~0x00000002;
  } else {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000002;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<TimerUpdateConfigure>:
  endbr64
  test   %rsi,%rsi
  jne    L4
  mov    (%rdi),%rax
  and    $0xfffffffffffffffd,%rax
  mov    %rax,(%rdi)
  ret
L4:
  mov    (%rdi),%rax
  or     $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void TimerUpdateConfigure(unsigned long ulBase, unsigned long ulUpdate) {

  ;

  ;
  if (ulUpdate == 0x00000000) {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) &= ~0x00000002;
  } else {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000002;
  }
}
```