ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D26(%rip),%rdi
  lea    D3(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  nopl   0x0(%rax,%rax,1)
L1:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  cltd
  sar    $0x22,%rsi
  sub    %edx,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string

tool: D26: Enter a number: 

tool: D3: %d

tool: D28: The reversal is: 

assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  printf("The reversal is: ");
  do {
    printf("%d", num % 10);
    num = num / 10;
  } while (num > 0);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  cmp    $0x33,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  cmp    $0x22,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  cmp    $0x11,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffdd,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffcc,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffbb,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffaa,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(xbyte(0x00112233, 0) == 0x33);
  assert(xbyte(0x00112233, 1) == 0x22);
  assert(xbyte(0x00112233, 2) == 0x11);
  assert(xbyte(0x00112233, 3) == 0x00);
  assert(xbyte(0xAABBCCDD, 0) == 0xFFFFFFDD);
  assert(xbyte(0xAABBCCDD, 1) == 0xFFFFFFCC);
  assert(xbyte(0xAABBCCDD, 2) == 0xFFFFFFBB);
  assert(xbyte(0xAABBCCDD, 3) == 0xFFFFFFAA);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  cmp    $0x33,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  cmp    $0x22,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  cmp    $0x11,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffdd,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffcc,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffbb,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  cmp    $0xffffffaa,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(xbyte(0x00112233, 0) == 0x33);
  assert(xbyte(0x00112233, 1) == 0x22);
  assert(xbyte(0x00112233, 2) == 0x11);
  assert(xbyte(0x00112233, 3) == 0x00);
  assert(xbyte(0xAABBCCDD, 0) == 0xFFFFFFDD);
  assert(xbyte(0xAABBCCDD, 1) == 0xFFFFFFCC);
  assert(xbyte(0xAABBCCDD, 2) == 0xFFFFFFBB);
  assert(xbyte(0xAABBCCDD, 3) == 0xFFFFFFAA);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0x33,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0x22,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0x11,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffdd,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffcc,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffbb,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffaa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(xbyte(0x00112233, 0) == 0x33);
  assert(xbyte(0x00112233, 1) == 0x22);
  assert(xbyte(0x00112233, 2) == 0x11);
  assert(xbyte(0x00112233, 3) == 0x00);
  assert(xbyte(0xAABBCCDD, 0) == 0xFFFFFFDD);
  assert(xbyte(0xAABBCCDD, 1) == 0xFFFFFFCC);
  assert(xbyte(0xAABBCCDD, 2) == 0xFFFFFFBB);
  assert(xbyte(0xAABBCCDD, 3) == 0xFFFFFFAA);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0x33,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0x22,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0x11,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0x112233,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffdd,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffcc,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffbb,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%esi
  mov    $0xaabbccdd,%edi
  call   <xbyte@plt>
  xor    %edi,%edi
  cmp    $0xffffffaa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(xbyte(0x00112233, 0) == 0x33);
  assert(xbyte(0x00112233, 1) == 0x22);
  assert(xbyte(0x00112233, 2) == 0x11);
  assert(xbyte(0x00112233, 3) == 0x00);
  assert(xbyte(0xAABBCCDD, 0) == 0xFFFFFFDD);
  assert(xbyte(0xAABBCCDD, 1) == 0xFFFFFFCC);
  assert(xbyte(0xAABBCCDD, 2) == 0xFFFFFFBB);
  assert(xbyte(0xAABBCCDD, 3) == 0xFFFFFFAA);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RMsgSndReset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x72,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <TCPIPMsgSend@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  je     L30
  mov    $0xffffffff,%eax
  jmp    L40
L30:
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <TCPIPMsgRecv@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  je     L25
  mov    -0xc(%rbp),%eax
  jmp    L40
L25:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L6
  mov    $0xffffffff,%eax
  jmp    L40
L6:
  mov    $0x0,%eax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

assistant: ```c
int RMsgSndReset(int sock) {
  int s;
  int msg = 'r';
  s = TCPIPMsgSend(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return -1;
  s = TCPIPMsgRecv(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return s;
  if (msg != 0)
    return -1;
  return 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RMsgSndReset>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x72,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  call   <TCPIPMsgSend@plt>
  cmp    $0x4,%eax
  jne    L24
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  call   <TCPIPMsgRecv@plt>
  cmp    $0x4,%eax
  jne    L2
  mov    0x4(%rsp),%eax
  neg    %eax
  sbb    %eax,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L2
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int RMsgSndReset(int sock) {
  int s;
  int msg = 'r';
  s = TCPIPMsgSend(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return -1;
  s = TCPIPMsgRecv(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return s;
  if (msg != 0)
    return -1;
  return 0;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RMsgSndReset>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  movl   $0x72,0x4(%rsp)
  mov    %r12,%rsi
  call   <TCPIPMsgSend@plt>
  cmp    $0x4,%eax
  jne    L49
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <TCPIPMsgRecv@plt>
  cmp    $0x4,%eax
  je     L15
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x4(%rsp),%eax
  neg    %eax
  sbb    %eax,%eax
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L49:
  mov    $0xffffffff,%eax
  jmp    L23
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int RMsgSndReset(int sock) {
  int s;
  int msg = 'r';
  s = TCPIPMsgSend(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return -1;
  s = TCPIPMsgRecv(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return s;
  if (msg != 0)
    return -1;
  return 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RMsgSndReset>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  movl   $0x72,0x4(%rsp)
  mov    %r12,%rsi
  call   <TCPIPMsgSend@plt>
  cmp    $0x4,%eax
  jne    L6
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <TCPIPMsgRecv@plt>
  cmp    $0x4,%eax
  je     L37
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    0x4(%rsp),%eax
  neg    %eax
  sbb    %eax,%eax
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%eax
  jmp    L15
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int RMsgSndReset(int sock) {
  int s;
  int msg = 'r';
  s = TCPIPMsgSend(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return -1;
  s = TCPIPMsgRecv(sock, &msg, sizeof(int));
  if (s != sizeof(int))
    return s;
  if (msg != 0)
    return -1;
  return 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nextPermutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L74
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L30
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L29
L37:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L5
  subl   $0x1,-0x8(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L37
  jmp    L71
L5:
  nop
L71:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L22
L30:
  subl   $0x1,-0xc(%rbp)
L74:
  cmpl   $0x0,-0xc(%rbp)
  jns    L0
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
L22:
  leave
  ret
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i, j;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      for (j = numsSize - 1; j > i - 1; j--) {
        if (nums[i] < nums[j]) {
          break;
        }
      }
      int temp = nums[i];
      nums[i] = nums[j];
      nums[j] = temp;
      reverse(nums, i + 1, numsSize - 1);
      return;
    }
  }
  reverse(nums, 0, numsSize - 1);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextPermutation>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %esi,%ecx
  sub    $0x2,%ecx
  js     L39
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%rax
L2:
  mov    %rax,%r9
  mov    (%rax),%edi
  cmp    0x4(%rax),%edi
  jl     L38
  sub    $0x1,%ecx
  sub    $0x4,%rax
  cmp    $0xffffffff,%ecx
  jne    L2
L39:
  lea    -0x1(%rsi),%edx
  mov    $0x0,%esi
  mov    %r8,%rdi
  call   <reverse@plt>
L16:
  add    $0x8,%rsp
  ret
L38:
  lea    -0x1(%rsi),%r10d
  cmp    %ecx,%r10d
  jl     L9
  movslq %r10d,%rax
L60:
  mov    %eax,%edx
  cmp    (%r8,%rax,4),%edi
  jl     L57
  lea    -0x1(%rax),%edx
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jle    L60
L57:
  movslq %edx,%rdx
  lea    (%r8,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%r9)
  mov    %edi,(%rax)
  lea    0x1(%rcx),%esi
  mov    %r10d,%edx
  mov    %r8,%rdi
  call   <reverse@plt>
  jmp    L16
L9:
  mov    %r10d,%edx
  jmp    L57
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i, j;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      for (j = numsSize - 1; j > i - 1; j--) {
        if (nums[i] < nums[j]) {
          break;
        }
      }
      int temp = nums[i];
      nums[i] = nums[j];
      nums[j] = temp;
      reverse(nums, i + 1, numsSize - 1);
      return;
    }
  }
  reverse(nums, 0, numsSize - 1);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextPermutation>:
  endbr64
  mov    %esi,%ecx
  mov    %rdi,%r10
  sub    $0x2,%ecx
  js     L78
  movslq %ecx,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L61:
  sub    $0x1,%ecx
  sub    $0x4,%rax
  cmp    $0xffffffff,%ecx
  je     L78
L63:
  mov    (%rax),%edi
  cmp    0x4(%rax),%edi
  jge    L61
  lea    0x4(%r10,%rdx,1),%rdx
  lea    -0x1(%rsi),%r9d
  mov    (%rdx),%r8d
  cmp    %r9d,%ecx
  jg     L35
  mov    %r9d,%esi
  jmp    L24
  nopl   0x0(%rax)
L41:
  sub    $0x1,%esi
  sub    $0x4,%rdx
  cmp    %esi,%ecx
  jg     L86
L24:
  mov    (%rdx),%r8d
  cmp    %r8d,%edi
  jge    L41
L35:
  mov    %r8d,(%rax)
  lea    0x1(%rcx),%esi
  mov    %edi,(%rdx)
  mov    %r9d,%edx
  mov    %r10,%rdi
  jmp    1050 <reverse@plt>
  cs nopw 0x0(%rax,%rax,1)
L78:
  lea    -0x1(%rsi),%edx
  mov    %r10,%rdi
  xor    %esi,%esi
  jmp    1050 <reverse@plt>
  nopl   (%rax)
L86:
  movslq %esi,%rsi
  lea    (%r10,%rsi,4),%rdx
  mov    (%rdx),%r8d
  jmp    L35
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i, j;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      for (j = numsSize - 1; j > i - 1; j--) {
        if (nums[i] < nums[j]) {
          break;
        }
      }
      int temp = nums[i];
      nums[i] = nums[j];
      nums[j] = temp;
      reverse(nums, i + 1, numsSize - 1);
      return;
    }
  }
  reverse(nums, 0, numsSize - 1);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nextPermutation>:
  endbr64
  mov    %esi,%ecx
  mov    %rdi,%r9
  sub    $0x2,%ecx
  js     L11
  movslq %esi,%rdx
  shl    $0x2,%rdx
  mov    -0x4(%rdi,%rdx,1),%eax
  lea    -0x8(%rdi,%rdx,1),%rdi
  jmp    L3
L89:
  sub    $0x1,%ecx
  sub    $0x4,%rdi
  cmp    $0xffffffff,%ecx
  je     L11
L3:
  mov    %eax,%r8d
  mov    (%rdi),%eax
  cmp    %r8d,%eax
  jge    L89
  lea    -0x4(%r9,%rdx,1),%rdx
  lea    -0x1(%rsi),%r8d
  mov    (%rdx),%r10d
  cmp    %r8d,%ecx
  jg     L12
  mov    %r8d,%esi
  jmp    L52
  nopl   0x0(%rax)
L63:
  sub    $0x1,%esi
  sub    $0x4,%rdx
  cmp    %esi,%ecx
  jg     L16
L52:
  mov    (%rdx),%r10d
  cmp    %r10d,%eax
  jge    L63
L12:
  mov    %r10d,(%rdi)
  lea    0x1(%rcx),%esi
  mov    %r9,%rdi
  mov    %eax,(%rdx)
  mov    %r8d,%edx
  jmp    1050 <reverse@plt>
  cs nopw 0x0(%rax,%rax,1)
L11:
  lea    -0x1(%rsi),%edx
  mov    %r9,%rdi
  xor    %esi,%esi
  jmp    1050 <reverse@plt>
  nopl   (%rax)
L16:
  movslq %esi,%rsi
  lea    (%r9,%rsi,4),%rdx
  mov    (%rdx),%r10d
  jmp    L12
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i, j;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      for (j = numsSize - 1; j > i - 1; j--) {
        if (nums[i] < nums[j]) {
          break;
        }
      }
      int temp = nums[i];
      nums[i] = nums[j];
      nums[j] = temp;
      reverse(nums, i + 1, numsSize - 1);
      return;
    }
  }
  reverse(nums, 0, numsSize - 1);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uStrInsertChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <uStrLen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L14
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L15
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void uStrInsertChar(char *dest, char iChar, int insertLocation) {
  int i;
  int len = uStrLen(dest);
  for (i = len + 1; i > insertLocation; i--) {
    dest[i] = dest[i - 1];
  }
  dest[insertLocation] = iChar;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uStrInsertChar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  call   <uStrLen@plt>
  lea    0x1(%rax),%edx
  cmp    %ebx,%edx
  jle    L1
  movslq %edx,%rdx
  add    %rbp,%rdx
  movslq %eax,%rcx
  add    %rbp,%rcx
  sub    %ebx,%eax
  sub    %rax,%rcx
L6:
  movzbl -0x1(%rdx),%eax
  mov    %al,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L6
L1:
  movslq %ebx,%rbx
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void uStrInsertChar(char *dest, char iChar, int insertLocation) {
  int i;
  int len = uStrLen(dest);
  for (i = len + 1; i > insertLocation; i--) {
    dest[i] = dest[i - 1];
  }
  dest[insertLocation] = iChar;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uStrInsertChar>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  call   <uStrLen@plt>
  lea    0x1(%rax),%edx
  cmp    %ebx,%edx
  jle    L9
  movslq %edx,%rdx
  sub    %ebx,%eax
  lea    -0x1(%rdx),%rsi
  lea    0x1(%rax),%r8
  sub    %rax,%rdx
  sub    %rax,%rsi
  lea    (%r12,%rdx,1),%rdi
  mov    %r8,%rdx
  add    %r12,%rsi
  call   <memmove@plt>
L9:
  mov    %bpl,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void uStrInsertChar(char *dest, char iChar, int insertLocation) {
  int i;
  int len = uStrLen(dest);
  for (i = len + 1; i > insertLocation; i--) {
    dest[i] = dest[i - 1];
  }
  dest[insertLocation] = iChar;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uStrInsertChar>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  call   <uStrLen@plt>
  lea    0x1(%rax),%edx
  cmp    %ebx,%edx
  jle    L9
  movslq %edx,%rdx
  sub    %ebx,%eax
  lea    -0x1(%rdx),%rsi
  lea    0x1(%rax),%r8
  sub    %rax,%rdx
  sub    %rax,%rsi
  lea    (%r12,%rdx,1),%rdi
  mov    %r8,%rdx
  add    %r12,%rsi
  call   <memmove@plt>
L9:
  mov    %bpl,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void uStrInsertChar(char *dest, char iChar, int insertLocation) {
  int i;
  int len = uStrLen(dest);
  for (i = len + 1; i > insertLocation; i--) {
    dest[i] = dest[i - 1];
  }
  dest[insertLocation] = iChar;
}
```