ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getProcCmdLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  call   <getpid@plt>
  mov    %eax,%ecx
  mov    %rsp,%rbp
  lea    D10(%rip),%rdx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <__real_fopen@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <feof@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L21
  mov    $0x0,%r14d
L67:
  mov    %r14d,0x0(%r13)
  mov    %rbp,%rdi
  call   <__real_fclose@plt>
L10:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  mov    $0x1000,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbp,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  mov    (%rbx),%rdi
  call   <__real_fread@plt>
  test   %eax,%eax
  jle    L67
  mov    (%rbx),%r15
  mov    $0x1,%r12d
  cmpb   $0x0,(%r15)
  jne    L5
  jmp    L67
L73:
  add    $0x1,%r12
L5:
  mov    -0x8(%rbx,%r12,8),%rdi
  call   <strlen@plt>
  cltq
  lea    0x1(%r15,%rax,1),%rdx
  mov    (%rbx),%rax
  add    $0x1000,%rax
  cmp    %rax,%rdx
  jb     L109
L45:
  mov    %r12d,%r14d
  cmpb   $0x0,(%r15)
  je     L67
  test   %r12d,%r12d
  je     L73
  mov    %r15,(%rbx,%r12,8)
  mov    %r15,%rdx
  mov    %r14d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L73
L109:
  mov    -0x8(%rbx,%r12,8),%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  add    %rax,%r15
  jmp    L45
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D10: /proc/%d/cmdline

tool: D2: r

tool: D4: %d: %s


assistant: ```c
void getProcCmdLine(int *ac, char **av) {
  int i = 0, pid;
  int length = 0;
  char *inbuf;
  char file[64];
  FILE *infile;
  char *arg_ptr;
  *ac = 0;
  *av = NULL;
  pid = getpid();
  snprintf(file, 64, "/proc/%d/cmdline", pid);
  infile = __real_fopen(file, "r");
  if (infile != NULL) {
    if (!feof(infile)) {
      av[0] = malloc(4096);
      memset(av[0], 0, 4096);
      length = __real_fread(av[0], 1, 4096, infile);
      if (length > 0) {
        arg_ptr = av[0];
        while (*arg_ptr != '\0') {
          if (i != 0) {
            av[i] = arg_ptr;
            printf("%d: %s\n", i, arg_ptr);
          }
          if ((arg_ptr + strlen(av[i]) + 1) < av[0] + 4096)
            arg_ptr += strlen(av[i]) + 1;
          i++;
        }
      }
    }
    *ac = i;
    __real_fclose(infile);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getProcCmdLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %rsp,%rbp
  movq   $0x0,(%rsi)
  call   <getpid@plt>
  mov    $0x40,%esi
  mov    %rbp,%rdi
  lea    D25(%rip),%rdx
  mov    %eax,%ecx
  call   <snprintf@plt>
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <__real_fopen@plt>
  test   %rax,%rax
  je     L64
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <feof@plt>
  test   %eax,%eax
  je     L30
L3:
  xor    %esi,%esi
L11:
  mov    %esi,(%r12)
  mov    %rbp,%rdi
  call   <__real_fclose@plt>
L64:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0x1000,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    $0x1000,%edx
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <memset@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  call   <__real_fread@plt>
  test   %eax,%eax
  jle    L3
  mov    (%rbx),%r14
  mov    $0x1,%r13d
  lea    D15(%rip),%r15
  cmpb   $0x0,(%r14)
  mov    %r14,%rdi
  jne    L55
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L85:
  cmpb   $0x0,(%r14)
  mov    %r13d,%esi
  je     L11
  mov    %r14,(%rbx,%r13,8)
  mov    %r15,%rdi
  mov    %r14,%rdx
  call   <printf@plt>
  mov    (%rbx,%r13,8),%rdi
  add    $0x1,%r13
L55:
  call   <strlen@plt>
  cltq
  lea    0x1(%r14,%rax,1),%rdx
  mov    (%rbx),%rax
  add    $0x1000,%rax
  cmp    %rax,%rdx
  jae    L85
  mov    -0x8(%rbx,%r13,8),%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  add    %rax,%r14
  jmp    L85
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D15
type: string

tool: D25: /proc/%d/cmdline

tool: D17: r

tool: D15: %d: %s


assistant: ```c
void getProcCmdLine(int *ac, char **av) {
  int i = 0, pid;
  int length = 0;
  char *inbuf;
  char file[64];
  FILE *infile;
  char *arg_ptr;
  *ac = 0;
  *av = NULL;
  pid = getpid();
  snprintf(file, 64, "/proc/%d/cmdline", pid);
  infile = __real_fopen(file, "r");
  if (infile != NULL) {
    if (!feof(infile)) {
      av[0] = malloc(4096);
      memset(av[0], 0, 4096);
      length = __real_fread(av[0], 1, 4096, infile);
      if (length > 0) {
        arg_ptr = av[0];
        while (*arg_ptr != '\0') {
          if (i != 0) {
            av[i] = arg_ptr;
            printf("%d: %s\n", i, arg_ptr);
          }
          if ((arg_ptr + strlen(av[i]) + 1) < av[0] + 4096)
            arg_ptr += strlen(av[i]) + 1;
          i++;
        }
      }
    }
    *ac = i;
    __real_fclose(infile);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getProcCmdLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %rsp,%rbp
  movq   $0x0,(%rsi)
  call   <getpid@plt>
  mov    $0x40,%esi
  mov    %rbp,%rdi
  lea    D1(%rip),%rdx
  mov    %eax,%ecx
  call   <snprintf@plt>
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <__real_fopen@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <feof@plt>
  test   %eax,%eax
  je     L66
L13:
  xor    %esi,%esi
L10:
  mov    %esi,(%r12)
  mov    %rbp,%rdi
  call   <__real_fclose@plt>
L8:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  mov    $0x1000,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    $0x1000,%edx
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <memset@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  call   <__real_fread@plt>
  test   %eax,%eax
  jle    L13
  mov    (%rbx),%r14
  mov    $0x1,%r13d
  lea    D6(%rip),%r15
  cmpb   $0x0,(%r14)
  jne    L29
  jmp    L13
L9:
  cmpb   $0x0,(%r14)
  mov    %r13d,%esi
  je     L10
L58:
  mov    %r14,(%rbx,%r13,8)
  mov    %r14,%rdx
  mov    %r15,%rdi
  add    $0x1,%r13
  call   <printf@plt>
L29:
  mov    -0x8(%rbx,%r13,8),%rdi
  call   <strlen@plt>
  cltq
  lea    0x1(%r14,%rax,1),%rdx
  mov    (%rbx),%rax
  add    $0x1000,%rax
  cmp    %rax,%rdx
  jae    L9
  mov    -0x8(%rbx,%r13,8),%rdi
  call   <strlen@plt>
  mov    %r13d,%esi
  add    $0x1,%eax
  cltq
  add    %rax,%r14
  cmpb   $0x0,(%r14)
  jne    L58
  jmp    L10
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D6
type: string

tool: D1: /proc/%d/cmdline

tool: D13: r

tool: D6: %d: %s


assistant: ```c
void getProcCmdLine(int *ac, char **av) {
  int i = 0, pid;
  int length = 0;
  char *inbuf;
  char file[64];
  FILE *infile;
  char *arg_ptr;
  *ac = 0;
  *av = NULL;
  pid = getpid();
  snprintf(file, 64, "/proc/%d/cmdline", pid);
  infile = __real_fopen(file, "r");
  if (infile != NULL) {
    if (!feof(infile)) {
      av[0] = malloc(4096);
      memset(av[0], 0, 4096);
      length = __real_fread(av[0], 1, 4096, infile);
      if (length > 0) {
        arg_ptr = av[0];
        while (*arg_ptr != '\0') {
          if (i != 0) {
            av[i] = arg_ptr;
            printf("%d: %s\n", i, arg_ptr);
          }
          if ((arg_ptr + strlen(av[i]) + 1) < av[0] + 4096)
            arg_ptr += strlen(av[i]) + 1;
          i++;
        }
      }
    }
    *ac = i;
    __real_fclose(infile);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<symbolic_region>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  lea    -0x24(%rbp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %eax,-0x1c(%rbp)
  lea    -0x28(%rbp),%rax
  cmp    %rax,-0x38(%rbp)
  jae    L6
  lea    -0x20(%rbp),%rax
  lea    -0x24(%rbp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %eax,-0x18(%rbp)
L6:
  lea    -0x28(%rbp),%rax
  cmp    %rax,-0x38(%rbp)
  jbe    L22
  lea    -0x20(%rbp),%rax
  lea    -0x24(%rbp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %eax,-0x14(%rbp)
L22:
  lea    -0x28(%rbp),%rax
  cmp    %rax,-0x38(%rbp)
  ja     L37
  lea    -0x20(%rbp),%rax
  lea    -0x24(%rbp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %eax,-0x10(%rbp)
L37:
  lea    -0x28(%rbp),%rax
  cmp    %rax,-0x38(%rbp)
  jb     L40
  lea    -0x20(%rbp),%rax
  lea    -0x24(%rbp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %eax,-0xc(%rbp)
L40:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void symbolic_region(int *p) {
  int a;
  if (&a == p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a != p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a > p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a < p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a >= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a <= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<symbolic_region>:
  endbr64
  ret
```

assistant: ```c
void symbolic_region(int *p) {
  int a;
  if (&a == p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a != p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a > p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a < p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a >= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a <= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<symbolic_region>:
  endbr64
  ret
```

assistant: ```c
void symbolic_region(int *p) {
  int a;
  if (&a == p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a != p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a > p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a < p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a >= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a <= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<symbolic_region>:
  endbr64
  ret
```

assistant: ```c
void symbolic_region(int *p) {
  int a;
  if (&a == p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a != p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a > p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a < p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a >= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
  if (&a <= p)
    do {
      int a, b;
      int c = &b - &a;
    } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<escribir_palabra>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <escribir_reversa@plt>
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void escribir_palabra(FILE *fp, char *palabra, int *seek) {
  int largo = strlen(palabra);
  int i;
  for (i = 0; i < largo; ++i) {
    escribir_reversa(fp, palabra[i], seek);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<escribir_palabra>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  mov    %r13,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r13,%rax,1),%r13
L9:
  movsbl (%rbx),%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <escribir_reversa@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L9
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void escribir_palabra(FILE *fp, char *palabra, int *seek) {
  int largo = strlen(palabra);
  int i;
  for (i = 0; i < largo; ++i) {
    escribir_reversa(fp, palabra[i], seek);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<escribir_palabra>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <escribir_reversa@plt>
  cmp    %r13,%rbx
  jne    L5
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void escribir_palabra(FILE *fp, char *palabra, int *seek) {
  int largo = strlen(palabra);
  int i;
  for (i = 0; i < largo; ++i) {
    escribir_reversa(fp, palabra[i], seek);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<escribir_palabra>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rbx),%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <escribir_reversa@plt>
  cmp    %r13,%rbx
  jne    L9
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void escribir_palabra(FILE *fp, char *palabra, int *seek) {
  int largo = strlen(palabra);
  int i;
  for (i = 0; i < largo; ++i) {
    escribir_reversa(fp, palabra[i], seek);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %ecx,-0x40(%rbp)
  cmpl   $0x1,-0x40(%rbp)
  jg     L0
  mov    -0x3c(%rbp),%eax
  cltq
  shr    $0x3,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%r12
  mov    -0x38(%rbp),%rbx
L1:
  mov    (%r12),%r13
  mov    %r12,%rax
  lea    0x8(%rax),%r12
  mov    (%rbx),%rdx
  mov    %rdx,(%rax)
  mov    %rbx,%rax
  lea    0x8(%rax),%rbx
  mov    %r13,(%rax)
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jg     L1
  jmp    L18
L0:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%r12
  mov    -0x38(%rbp),%rbx
L2:
  movzbl (%r12),%r13d
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rbx),%edx
  mov    %dl,(%rax)
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  mov    %r13b,(%rax)
  subq   $0x1,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jg     L2
L18:
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void swapfunc(char *a, char *b, int n, int swaptype) {
  if (swaptype <= 1) {
    long i = (n) / sizeof(long);
    register long *pi = (long *)(a);
    register long *pj = (long *)(b);
    do {
      register long t = *pi;
      *pi++ = *pj;
      *pj++ = t;
    } while (--i > 0);
  } else {
    long i = (n) / sizeof(char);
    register char *pi = (char *)(a);
    register char *pj = (char *)(b);
    do {
      register char t = *pi;
      *pi++ = *pj;
      *pj++ = t;
    } while (--i > 0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swapfunc>:
  endbr64
  mov    %rsi,%rax
  mov    %ecx,%esi
  mov    %rdi,%rcx
  movslq %edx,%r8
  add    %rdi,%r8
  cmp    $0x1,%esi
  jle    L22
L10:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  movzbl (%rax),%esi
  mov    %sil,-0x1(%rcx)
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  mov    %r8,%rdx
  sub    %rcx,%rdx
  test   %rdx,%rdx
  jg     L10
  ret
L22:
  movslq %edx,%rdx
  shr    $0x3,%rdx
L9:
  mov    (%rdi),%rcx
  add    $0x8,%rdi
  mov    (%rax),%rsi
  mov    %rsi,-0x8(%rdi)
  add    $0x8,%rax
  mov    %rcx,-0x8(%rax)
  sub    $0x1,%rdx
  test   %rdx,%rdx
  jg     L9
  ret
```

assistant: ```c
void swapfunc(char *a, char *b, int n, int swaptype) {
  if (swaptype <= 1) {
    long i = (n) / sizeof(long);
    register long *pi = (long *)(a);
    register long *pj = (long *)(b);
    do {
      register long t = *pi;
      *pi++ = *pj;
      *pj++ = t;
    } while (--i > 0);
  } else {
    long i = (n) / sizeof(char);
    register char *pi = (char *)(a);
    register char *pj = (char *)(b);
    do {
      register char t = *pi;
      *pi++ = *pj;
      *pj++ = t;
    } while (--i > 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swapfunc>:
  endbr64
  movslq %edx,%rdx
  mov    %rdi,%rax
  lea    (%rdi,%rdx,1),%r8
  cmp    $0x1,%ecx
  jle    L14
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rax),%edx
  movzbl (%rsi),%ecx
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  mov    %dl,-0x1(%rsi)
  mov    %r8,%rdx
  sub    %rax,%rdx
  test   %rdx,%rdx
  jg     L7
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  shr    $0x3,%rdx
  nopl   0x0(%rax)
L10:
  mov    (%rdi),%rax
  mov    (%rsi),%rcx
  sub    $0x1,%rdx
  add    $0x8,%rsi
  add    $0x8,%rdi
  mov    %rcx,-0x8(%rdi)
  mov    %rax,-0x8(%rsi)
  test   %rdx,%rdx
  jg     L10
  ret
```

assistant: ```c
void swapfunc(char *a, char *b, int n, int swaptype) {
  if (swaptype <= 1) {
    long i = (n) / sizeof(long);
    register long *pi = (long *)(a);
    register long *pj = (long *)(b);
    do {
      register long t = *pi;
      *pi++ = *pj;
      *pj++ = t;
    } while (--i > 0);
  } else {
    long i = (n) / sizeof(char);
    register char *pi = (char *)(a);
    register char *pj = (char *)(b);
    do {
      register char t = *pi;
      *pi++ = *pj;
      *pj++ = t;
    } while (--i > 0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rwx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L49
  mov    $0x72,%edx
  jmp    L16
L49:
  mov    $0x2d,%edx
L16:
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  movzwl -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L48
  mov    $0x77,%edx
  jmp    L54
L48:
  mov    $0x2d,%edx
L54:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  movzwl -0x4(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L17
  mov    $0x78,%edx
  jmp    L58
L17:
  mov    $0x2d,%edx
L58:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rwx(bits, chars) unsigned short bits;
char *chars;
{
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rwx>:
  endbr64
  mov    %edi,%eax
  and    $0x100,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x80,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffb6,%eax
  add    $0x77,%eax
  mov    %al,0x1(%rsi)
  and    $0x40,%edi
  cmp    $0x1,%di
  sbb    %eax,%eax
  and    $0xffffffb5,%eax
  add    $0x78,%eax
  mov    %al,0x2(%rsi)
  ret
```

assistant: ```c
void rwx(bits, chars) unsigned short bits;
char *chars;
{
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rwx>:
  endbr64
  mov    %edi,%eax
  and    $0x100,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x80,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0x40,%edi
  and    $0xffffffb6,%eax
  add    $0x77,%eax
  cmp    $0x1,%di
  mov    %al,0x1(%rsi)
  sbb    %eax,%eax
  and    $0xffffffb5,%eax
  add    $0x78,%eax
  mov    %al,0x2(%rsi)
  ret
```

assistant: ```c
void rwx(bits, chars) unsigned short bits;
char *chars;
{
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rwx>:
  endbr64
  mov    %edi,%eax
  and    $0x100,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x80,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0x40,%edi
  and    $0xffffffb6,%eax
  add    $0x77,%eax
  cmp    $0x1,%di
  mov    %al,0x1(%rsi)
  sbb    %eax,%eax
  and    $0xffffffb5,%eax
  add    $0x78,%eax
  mov    %al,0x2(%rsi)
  ret
```

assistant: ```c
void rwx(bits, chars) unsigned short bits;
char *chars;
{
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```