user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L13
L40:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L40
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L19
L168:
  mov    %rsp,%r14
  test   %ecx,%ecx
  jle    L89
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L130:
  movslq %ebx,%r13
  mov    %r12,%rdi
  lea    (%r14,%r13,4),%rsi
  call   <scanf@plt>
  mov    (%r14,%r13,4),%eax
  movslq -0x3c(%rbp),%rcx
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  cmp    %ecx,%ebx
  jl     L130
  mov    %ecx,%esi
  mov    %rsp,%r8
  shr    $0x1f,%esi
  add    %ecx,%esi
  sar    %esi
  movslq %esi,%rdx
  mov    %esi,%eax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rdi
  and    $0xfffffffffffff000,%rdx
  and    $0xfffffffffffffff0,%rdi
  sub    %rdx,%r8
L82:
  cmp    %r8,%rsp
  je     L142
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L82
L142:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L73
L124:
  mov    %rsp,%r15
  cmp    $0x1,%ecx
  jle    L3
  lea    (%r14,%rcx,4),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L52:
  mov    (%r14,%rax,4),%edx
  sub    -0x4(%rcx),%edx
  sub    $0x4,%rcx
  mov    %edx,(%r15,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L52
  xor    %ebx,%ebx
  lea    D18(%rip),%r13
L116:
  mov    (%r15,%rbx,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    -0x3c(%rbp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L116
L3:
  and    $0x1,%ecx
  jne    L79
L120:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L118
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L79:
  cltq
  mov    %r12,%rdi
  mov    (%r14,%rax,4),%esi
  call   <printf@plt>
  jmp    L120
L19:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L168
L73:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L124
L89:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L3
L118:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string

tool: D13: %d

tool: D18: %d


assistant: ```c
int main() {
  int n, count;
  scanf("%d", &n);
  int arr[n];
  for (count = 0; count < n;) {
    scanf("%d", &arr[count]);
    if (arr[count] % 2 != 0) {
      count++;
    }
  }
  int count2;
  int sum[n / 2], i;
  for (i = 0; i < n / 2; i++) {
    count2 = (n - 1) - i;
    sum[i] = arr[i] - arr[count2];
  }
  for (i = 0; i < n / 2; i++) {
    printf("%d\n", sum[i]);
  }
  if (n % 2 != 0) {
    printf("%d", arr[n / 2]);
  }
  return 0;
}
```