ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D55(%rip),%rdi
  lea    D4(%rip),%r12
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D68(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x28,%edx
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x20,%esi
  lea    D61(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D55
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D68
type_infered: string
name: retrieve_data
arguments: data_label: D26
type_infered: string
name: retrieve_data
arguments: data_label: D22
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D61
type_infered: string

tool: D55: What's your name?

tool: D4: You are an extraordinary being.

tool: D68: %s

tool: D26: Hello, %s. %s


tool: D22: Your name of %u letters occupies %u memory cells.


tool: D5: The phrase of praise has %u letters


tool: D61: and occupies %d memory cells.


assistant: ```c
int main(void) {
  char name[40];
  printf("What's your name?\n");
  scanf("%s", name);
  printf("Hello, %s. %s\n", name, "You are an extraordinary being.");
  printf("Your name of %u letters occupies %u memory cells.\n", strlen(name), sizeof name);
  printf("The phrase of praise has %u letters\n", strlen("You are an extraordinary being."));
  printf("and occupies %d memory cells.\n", sizeof "You are an extraordinary being.");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_dynamic_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L6:
  cmp    %rdx,%rsp
  je     L2
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L2:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L13
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L13:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L24
L19:
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    D4(%rip),%rcx
  mov    %rcx,(%rax,%rdx,8)
  addl   $0x1,-0x2c(%rbp)
L24:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L19
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D5
datatype: string

tool: D4: Hello world

tool: D5: strcmp(a[size-1], "Hello world") == 0

assistant: ```c
int do_dynamic_array(int size) {
  char *a[size];
  int i;
  for (i = 0; i < size; ++i) {
    a[i] = "Hello world";
  }
  assertTrue("strcmp(a[size-1], \"Hello world\") == 0", strcmp(a[size - 1], "Hello world") == 0);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<do_dynamic_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L30:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L30
L28:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L26
  orq    $0x0,-0x8(%rsp,%rax,1)
L26:
  mov    %rsp,%rsi
  test   %edi,%edi
  jle    L8
  mov    %rsi,%rax
  mov    %edi,%edx
  lea    (%rsi,%rdx,8),%rcx
  lea    D14(%rip),%rdx
L19:
  mov    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L19
L8:
  sub    $0x1,%edi
  movslq %edi,%rdi
  mov    (%rsi,%rdi,8),%rdi
  lea    D14(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %sil
  movzbl %sil,%esi
  lea    D15(%rip),%rdi
  call   <assertTrue@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  leave
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D14: Hello world

tool: D15: strcmp(a[size-1], "Hello world") == 0

assistant: ```c
int do_dynamic_array(int size) {
  char *a[size];
  int i;
  for (i = 0; i < size; ++i) {
    a[i] = "Hello world";
  }
  assertTrue("strcmp(a[size-1], \"Hello world\") == 0", strcmp(a[size - 1], "Hello world") == 0);
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_dynamic_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L5
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L22
L5:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L41
L36:
  mov    %rsp,%rcx
  lea    D0(%rip),%rsi
  test   %edi,%edi
  jle    L53
  mov    %edi,%edx
  mov    %rcx,%rax
  lea    (%rcx,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %rsi,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L65
L53:
  sub    $0x1,%edi
  movslq %edi,%rdi
  mov    (%rcx,%rdi,8),%rdi
  call   <strcmp@plt>
  xor    %esi,%esi
  lea    D12(%rip),%rdi
  test   %rax,%rax
  sete   %sil
  call   <assertTrue@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  leave
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L36
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string

tool: D0: Hello world

tool: D12: strcmp(a[size-1], "Hello world") == 0

assistant: ```c
int do_dynamic_array(int size) {
  char *a[size];
  int i;
  for (i = 0; i < size; ++i) {
    a[i] = "Hello world";
  }
  assertTrue("strcmp(a[size-1], \"Hello world\") == 0", strcmp(a[size - 1], "Hello world") == 0);
  ;
}
```
user: What is the c source code of the assembly code below:

```asm
<do_dynamic_array>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rsi
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L82
L51:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L51
L82:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L73
L27:
  mov    %rsp,%rsi
  lea    D12(%rip),%r8
  test   %edx,%edx
  jle    L11
  cmp    $0x1,%edx
  je     L67
  mov    %edx,%ecx
  movq   %r8,%xmm0
  mov    %rsi,%rax
  shr    %ecx
  punpcklqdq %xmm0,%xmm0
  shl    $0x4,%rcx
  add    %rsi,%rcx
  nopl   (%rax)
L28:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L28
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%dl
  je     L11
L83:
  cltq
  mov    %r8,(%rsi,%rax,8)
L11:
  sub    $0x1,%edx
  movslq %edx,%rdx
  mov    (%rsi,%rdx,8),%rdi
  mov    %r8,%rsi
  call   <strcmp@plt>
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  test   %rax,%rax
  sete   %sil
  call   <assertTrue@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  leave
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L73:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L27
L67:
  xor    %eax,%eax
  jmp    L83
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D12: Hello world

tool: D11: strcmp(a[size-1], "Hello world") == 0

assistant: ```c
int do_dynamic_array(int size) {
  char *a[size];
  int i;
  for (i = 0; i < size; ++i) {
    a[i] = "Hello world";
  }
  assertTrue("strcmp(a[size-1], \"Hello world\") == 0", strcmp(a[size - 1], "Hello world") == 0);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gengetopt_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L38
  mov    -0x8(%rbp),%rax
  jmp    L6
L38:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L6
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
char *gengetopt_strdup(const char *s) {
  char *result = 0;
  if (!s) {
    return result;
  }
  result = (char *)malloc(strlen(s) + 1);
  if (result == (char *)0) {
    return (char *)0;
  }
  strcpy(result, s);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gengetopt_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L20
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L10
  mov    %rax,%rbp
  mov    %rbx,%rsi
  call   <strcpy@plt>
L10:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    %rdi,%rbp
  jmp    L10
```

assistant: ```c
char *gengetopt_strdup(const char *s) {
  char *result = 0;
  if (!s) {
    return result;
  }
  result = (char *)malloc(strlen(s) + 1);
  if (result == (char *)0) {
    return (char *)0;
  }
  strcpy(result, s);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gengetopt_strdup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L7:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *gengetopt_strdup(const char *s) {
  char *result = 0;
  if (!s) {
    return result;
  }
  result = (char *)malloc(strlen(s) + 1);
  if (result == (char *)0) {
    return (char *)0;
  }
  strcpy(result, s);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gengetopt_strdup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L18
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L18:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *gengetopt_strdup(const char *s) {
  char *result = 0;
  if (!s) {
    return result;
  }
  result = (char *)malloc(strlen(s) + 1);
  if (result == (char *)0) {
    return (char *)0;
  }
  strcpy(result, s);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_buffer_chunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <buffer_chunk_cleanup@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_buffer_chunk(struct buffer_chunk *chunk) {
  buffer_chunk_cleanup(chunk);
  free(chunk);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_buffer_chunk>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <buffer_chunk_cleanup@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_buffer_chunk(struct buffer_chunk *chunk) {
  buffer_chunk_cleanup(chunk);
  free(chunk);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<free_buffer_chunk>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <buffer_chunk_cleanup@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void free_buffer_chunk(struct buffer_chunk *chunk) {
  buffer_chunk_cleanup(chunk);
  free(chunk);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<free_buffer_chunk>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <buffer_chunk_cleanup@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void free_buffer_chunk(struct buffer_chunk *chunk) {
  buffer_chunk_cleanup(chunk);
  free(chunk);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ec_resume_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ec_resume_status_long@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int ec_resume_status(void) {
  long dummy;
  return ec_resume_status_long(&dummy);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ec_resume_status>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <ec_resume_status_long@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ec_resume_status(void) {
  long dummy;
  return ec_resume_status_long(&dummy);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ec_resume_status>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <ec_resume_status_long@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ec_resume_status(void) {
  long dummy;
  return ec_resume_status_long(&dummy);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ec_resume_status>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <ec_resume_status_long@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ec_resume_status(void) {
  long dummy;
  return ec_resume_status_long(&dummy);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xe4(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xe0(%rbp)
  jmp    L94
L1:
  lea    -0xd0(%rbp),%rdx
  mov    -0xe0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xe0(%rbp)
L94:
  mov    -0xe8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xe0(%rbp)
  jl     L1
  movl   $0x0,-0xe0(%rbp)
  jmp    L82
L92:
  mov    -0xe0(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%edx
  mov    -0xe0(%rbp),%eax
  cltq
  mov    %edx,-0x80(%rbp,%rax,4)
  addl   $0x1,-0xe0(%rbp)
L82:
  cmpl   $0x0,-0xe0(%rbp)
  js     L51
  mov    -0xe8(%rbp),%eax
  cmp    %eax,-0xe0(%rbp)
  jl     L92
L51:
  mov    -0xe8(%rbp),%eax
  mov    %eax,-0xe0(%rbp)
  jmp    L20
L42:
  movl   $0x0,-0xdc(%rbp)
  mov    -0xe8(%rbp),%edx
  mov    -0xe0(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0xd4(%rbp)
  mov    -0xe0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xd8(%rbp)
  jmp    L91
L38:
  mov    -0xd8(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,4),%eax
  add    %eax,-0xdc(%rbp)
  subl   $0x1,-0xd8(%rbp)
L91:
  mov    -0xd8(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jge    L38
  mov    -0xe0(%rbp),%eax
  cltq
  mov    -0xdc(%rbp),%edx
  mov    %edx,-0x80(%rbp,%rax,4)
  addl   $0x1,-0xe0(%rbp)
L20:
  mov    -0xe4(%rbp),%eax
  cmp    %eax,-0xe0(%rbp)
  jle    L42
  mov    -0xe4(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D38
type_infered: string

tool: D10: %d 

tool: D28: %d


tool: D38: %d

assistant: ```c
int main() {
  int d;
  scanf("%d ", &d);
  int N;
  scanf("%d\n", &N);
  int i;
  int b[20];
  for (i = 0; i < d - 1; i = i + 1)
    scanf("%d", &b[i]);
  int a[30];
  for (i = 0; i >= 0 && i < d; i = i + 1) {
    a[i] = b[i];
  }
  for (i = d; i <= N; i = i + 1) {
    int sum;
    sum = 0;
    int c;
    c = i - d;
    int j;
    for (j = i - 1; j >= c; j--)
      sum = sum + a[j];
    a[i] = sum;
  }
  printf("%d", a[N]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  cmp    $0x1,%esi
  jle    L13
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L75:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x8(%rsp),%esi
  add    $0x4,%rbp
  lea    -0x1(%rsi),%eax
  cmp    %ebx,%eax
  jg     L75
L13:
  test   %esi,%esi
  jle    L2
  mov    $0x1,%eax
L38:
  mov    0xc(%rsp,%rax,4),%edx
  mov    %edx,0x5c(%rsp,%rax,4)
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    %edx,%esi
  jle    L2
  test   %edx,%edx
  jns    L38
L2:
  mov    0xc(%rsp),%r11d
  cmp    %esi,%r11d
  jl     L94
  lea    -0x1(%rsi),%r8d
  movslq %esi,%rax
  shl    $0x2,%rax
  lea    0x60(%rsp,%rax,1),%rdi
  lea    0x5c(%rsp,%rax,1),%rcx
  mov    %r8d,%eax
  shl    $0x2,%rax
  sub    %rax,%rcx
  lea    0x1(%r11),%r9d
  sub    %esi,%r9d
  mov    $0x0,%esi
  mov    $0x0,%r10d
  jmp    L64
L77:
  mov    %r10d,%edx
L74:
  mov    %edx,(%rdi)
  add    $0x1,%esi
  add    $0x1,%r8d
  add    $0x4,%rdi
  add    $0x4,%rcx
  cmp    %r9d,%esi
  je     L94
L64:
  cmp    %esi,%r8d
  jl     L77
  mov    %rdi,%rax
  mov    %r10d,%edx
L15:
  add    -0x4(%rax),%edx
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
  jmp    L74
L94:
  movslq %r11d,%r11
  mov    0x60(%rsp,%r11,4),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string
name: disassemble_data
arguments: label: D25
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D2: %d 

tool: D25: %d


tool: D0: %d

assistant: ```c
int main() {
  int d;
  scanf("%d ", &d);
  int N;
  scanf("%d\n", &N);
  int i;
  int b[20];
  for (i = 0; i < d - 1; i = i + 1)
    scanf("%d", &b[i]);
  int a[30];
  for (i = 0; i >= 0 && i < d; i = i + 1) {
    a[i] = b[i];
  }
  for (i = d; i <= N; i = i + 1) {
    int sum;
    sum = 0;
    int c;
    c = i - d;
    int j;
    for (j = i - 1; j >= c; j--)
      sum = sum + a[j];
    a[i] = sum;
  }
  printf("%d", a[N]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r12d
  cmp    $0x1,%r12d
  jle    L6
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L19:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%r12d
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  jg     L19
L6:
  test   %r12d,%r12d
  jle    L46
  movslq %r12d,%rdx
  lea    0x60(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L46:
  movslq 0xc(%rsp),%r10
  cmp    %r12d,%r10d
  jl     L63
  movslq %r12d,%rax
  lea    -0x1(%r12),%r8d
  lea    0x1(%r10),%r9d
  xor    %esi,%esi
  shl    $0x2,%rax
  sub    %r12d,%r9d
  lea    0x5c(%rsp,%rax,1),%rcx
  lea    0x60(%rsp,%rax,1),%rdi
  mov    %r8d,%eax
  shl    $0x2,%rax
  sub    %rax,%rcx
  xchg   %ax,%ax
L24:
  cmp    %esi,%r8d
  jl     L77
  mov    %rdi,%rax
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L18:
  add    -0x4(%rax),%edx
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L18
L37:
  add    $0x1,%esi
  mov    %edx,(%rdi)
  add    $0x1,%r8d
  add    $0x4,%rdi
  add    $0x4,%rcx
  cmp    %r9d,%esi
  jne    L24
L63:
  mov    0x60(%rsp,%r10,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L77:
  xor    %edx,%edx
  jmp    L37
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D17
datatype: string

tool: D27: %d 

tool: D14: %d

tool: D17: %d


assistant: ```c
int main() {
  int d;
  scanf("%d ", &d);
  int N;
  scanf("%d\n", &N);
  int i;
  int b[20];
  for (i = 0; i < d - 1; i = i + 1)
    scanf("%d", &b[i]);
  int a[30];
  for (i = 0; i >= 0 && i < d; i = i + 1) {
    a[i] = b[i];
  }
  for (i = d; i <= N; i = i + 1) {
    int sum;
    sum = 0;
    int c;
    c = i - d;
    int j;
    for (j = i - 1; j >= c; j--)
      sum = sum + a[j];
    a[i] = sum;
  }
  printf("%d", a[N]);
  return 0;
}
```