ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_match>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x2a,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  sub    %rbp,%rax
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strncmp@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %r13d,%eax
  lea    0x1(%rax,%rbx,1),%eax
  cltq
  lea    (%r12,%rax,1),%rsi
  movslq %ebx,%rax
  lea    0x1(%rbp,%rax,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  pop    %r13
  sete   %al
  pop    %r14
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  pop    %r13
  sete   %al
  pop    %r14
  movzbl %al,%eax
  ret
```

assistant: ```c
int string_match(const char *pattern, const char *text) {
  char *w;
  int headlen, taillen;
  w = strchr(pattern, '*');
  if (!w)
    return !strcmp(pattern, text);
  headlen = w - pattern;
  taillen = strlen(pattern) - headlen - 1;
  return !strncmp(pattern, text, headlen) && !strcmp(&pattern[headlen + 1], &text[strlen(text) - taillen]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<setBit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  or     -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int setBit(unsigned int byte, int i) {
  unsigned int mask = 1 << i;
  return (mask | byte);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<setBit>:
  endbr64
  mov    %edi,%eax
  bts    %esi,%eax
  ret
```

assistant: ```c
unsigned int setBit(unsigned int byte, int i) {
  unsigned int mask = 1 << i;
  return (mask | byte);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setBit>:
  endbr64
  mov    %edi,%eax
  bts    %esi,%eax
  ret
```

assistant: ```c
unsigned int setBit(unsigned int byte, int i) {
  unsigned int mask = 1 << i;
  return (mask | byte);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  int *aa = (int *)a;
  int *bb = (int *)b;
  return (*aa - *bb);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compare>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  int *aa = (int *)a;
  int *bb = (int *)b;
  return (*aa - *bb);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compare>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  int *aa = (int *)a;
  int *bb = (int *)b;
  return (*aa - *bb);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compare>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  int *aa = (int *)a;
  int *bb = (int *)b;
  return (*aa - *bb);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L15
L0:
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0x24(%rbp)
L15:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string

tool: D7: %d

tool: D13: %d %d %d


assistant: ```c
int main() {
  int x, y, z, rotation, n;
  int *a, *b, *c;
  a = &x;
  b = &y;
  c = &z;
  scanf("%d", &x);
  scanf("%d", &y);
  scanf("%d", &z);
  scanf("%d", &rotation);
  for (n = 0; n < rotation; n++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", *a, *b, *c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %rsi,0x10(%rsp)
  lea    0x4(%rsp),%r12
  mov    %r12,0x18(%rsp)
  lea    0x8(%rsp),%rbp
  mov    %rbp,0x20(%rsp)
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L3
  mov    $0x0,%ebx
  lea    0x20(%rsp),%rbp
L0:
  lea    0x18(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L0
L3:
  mov    0x20(%rsp),%rax
  mov    (%rax),%ecx
  mov    0x18(%rsp),%rax
  mov    (%rax),%edx
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D19
type: string

tool: D16: %d

tool: D19: %d %d %d


assistant: ```c
int main() {
  int x, y, z, rotation, n;
  int *a, *b, *c;
  a = &x;
  b = &y;
  c = &z;
  scanf("%d", &x);
  scanf("%d", &y);
  scanf("%d", &z);
  scanf("%d", &rotation);
  for (n = 0; n < rotation; n++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", *a, *b, *c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r13
  lea    0x8(%rsp),%r12
  mov    %rsi,0x10(%rsp)
  mov    %r13,0x18(%rsp)
  mov    %r12,0x20(%rsp)
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r13
  lea    0x18(%rsp),%r12
  lea    0x10(%rsp),%rbp
  nopl   (%rax)
L0:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L0
L27:
  mov    0x20(%rsp),%rax
  lea    D13(%rip),%rdi
  mov    (%rax),%ecx
  mov    0x18(%rsp),%rax
  mov    (%rax),%edx
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D13
type: string

tool: D15: %d

tool: D13: %d %d %d


assistant: ```c
int main() {
  int x, y, z, rotation, n;
  int *a, *b, *c;
  a = &x;
  b = &y;
  c = &z;
  scanf("%d", &x);
  scanf("%d", &y);
  scanf("%d", &z);
  scanf("%d", &rotation);
  for (n = 0; n < rotation; n++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", *a, *b, *c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r13
  lea    0x8(%rsp),%r12
  mov    %rsi,0x10(%rsp)
  mov    %r13,0x18(%rsp)
  mov    %r12,0x20(%rsp)
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L7
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r13
  lea    0x18(%rsp),%r12
  lea    0x10(%rsp),%rbp
  nopl   (%rax)
L23:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L23
L7:
  mov    0x20(%rsp),%rax
  lea    D14(%rip),%rdi
  mov    (%rax),%ecx
  mov    0x18(%rsp),%rax
  mov    (%rax),%edx
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D15: %d

tool: D14: %d %d %d


assistant: ```c
int main() {
  int x, y, z, rotation, n;
  int *a, *b, *c;
  a = &x;
  b = &y;
  c = &z;
  scanf("%d", &x);
  scanf("%d", &y);
  scanf("%d", &z);
  scanf("%d", &rotation);
  for (n = 0; n < rotation; n++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", *a, *b, *c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x3,%edi
  call   <f@plt>
  mov    -0x14(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x6,%edi
  call   <f@plt>
  mov    -0x14(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jg     L15
  mov    -0x4(%rbp),%eax
  jmp    L12
L15:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <f@plt>
  imul   -0x14(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int h(int n) {
  int m = n + f(3);
  {
    int x = n + f(6);
    if (x < 6)
      return x;
  }
  return n * f(n - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<h>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x6,%edi
  call   <f@plt>
  add    %ebx,%eax
  cmp    $0x5,%eax
  jg     L19
L2:
  pop    %rbx
  ret
L19:
  lea    -0x1(%rbx),%edi
  call   <f@plt>
  imul   %ebx,%eax
  jmp    L2
```

assistant: ```c
int h(int n) {
  int m = n + f(3);
  {
    int x = n + f(6);
    if (x < 6)
      return x;
  }
  return n * f(n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x6,%edi
  call   <f@plt>
  add    %ebx,%eax
  cmp    $0x5,%eax
  jg     L4
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  lea    -0x1(%rbx),%edi
  call   <f@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int h(int n) {
  int m = n + f(3);
  {
    int x = n + f(6);
    if (x < 6)
      return x;
  }
  return n * f(n - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<h>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x6,%edi
  call   <f@plt>
  add    %ebx,%eax
  cmp    $0x5,%eax
  jg     L5
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  lea    -0x1(%rbx),%edi
  call   <f@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int h(int n) {
  int m = n + f(3);
  {
    int x = n + f(6);
    if (x < 6)
      return x;
  }
  return n * f(n - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *k = malloc(5);
  int j = foo(k[8]);
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    0x20(%rax),%edi
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *k = malloc(5);
  int j = foo(k[8]);
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    0x20(%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <foo@plt>
```

assistant: ```c
int main() {
  int *k = malloc(5);
  int j = foo(k[8]);
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    0x20(%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <foo@plt>
```

assistant: ```c
int main() {
  int *k = malloc(5);
  int j = foo(k[8]);
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *check(void *p) {
  if (!p)
    exit(1);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check>:
  endbr64
  test   %rdi,%rdi
  je     L4
  mov    %rdi,%rax
  ret
L4:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
char *check(void *p) {
  if (!p)
    exit(1);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check>:
  endbr64
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rax
  ret
L3:
  push   %rax
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
char *check(void *p) {
  if (!p)
    exit(1);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rax
  ret
L6:
  push   %rax
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
char *check(void *p) {
  if (!p)
    exit(1);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f_work>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L34
  mov    -0x8(%rbp),%rax
  movq   $0x2,(%rax)
L34:
  cmpq   $0x0,-0x10(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  movq   $0x2,(%rax)
L3:
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
L4:
  cmpq   $0x0,-0x20(%rbp)
  je     L35
  mov    -0x20(%rbp),%rax
  movq   $0x1,(%rax)
L35:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f_work(long long int *sz_arg, long long int *sz_res, long long int *sz_iw, long long int *sz_w) {
  if (sz_arg)
    *sz_arg = 2;
  if (sz_res)
    *sz_res = 2;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f_work>:
  endbr64
  test   %rdi,%rdi
  je     L32
  movq   $0x2,(%rdi)
L32:
  test   %rsi,%rsi
  je     L20
  movq   $0x2,(%rsi)
L20:
  test   %rdx,%rdx
  je     L16
  movq   $0x0,(%rdx)
L16:
  test   %rcx,%rcx
  je     L34
  movq   $0x1,(%rcx)
L34:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int f_work(long long int *sz_arg, long long int *sz_res, long long int *sz_iw, long long int *sz_w) {
  if (sz_arg)
    *sz_arg = 2;
  if (sz_res)
    *sz_res = 2;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f_work>:
  endbr64
  test   %rdi,%rdi
  je     L26
  movq   $0x2,(%rdi)
L26:
  test   %rsi,%rsi
  je     L32
  movq   $0x2,(%rsi)
L32:
  test   %rdx,%rdx
  je     L15
  movq   $0x0,(%rdx)
L15:
  test   %rcx,%rcx
  je     L17
  movq   $0x1,(%rcx)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int f_work(long long int *sz_arg, long long int *sz_res, long long int *sz_iw, long long int *sz_w) {
  if (sz_arg)
    *sz_arg = 2;
  if (sz_res)
    *sz_res = 2;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<f_work>:
  endbr64
  test   %rdi,%rdi
  je     L11
  movq   $0x2,(%rdi)
L11:
  test   %rsi,%rsi
  je     L12
  movq   $0x2,(%rsi)
L12:
  test   %rdx,%rdx
  je     L35
  movq   $0x0,(%rdx)
L35:
  test   %rcx,%rcx
  je     L7
  movq   $0x1,(%rcx)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int f_work(long long int *sz_arg, long long int *sz_res, long long int *sz_iw, long long int *sz_w) {
  if (sz_arg)
    *sz_arg = 2;
  if (sz_res)
    *sz_res = 2;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invalid_decoder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: Error!
There is no %s decoder! Exiting...


assistant: ```c
void invalid_decoder(const char *decoder) {
  printf("Error!\nThere is no %s decoder! Exiting...\n", decoder);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<invalid_decoder>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: Error!
There is no %s decoder! Exiting...


assistant: ```c
void invalid_decoder(const char *decoder) {
  printf("Error!\nThere is no %s decoder! Exiting...\n", decoder);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invalid_decoder>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: Error!
There is no %s decoder! Exiting...


assistant: ```c
void invalid_decoder(const char *decoder) {
  printf("Error!\nThere is no %s decoder! Exiting...\n", decoder);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<invalid_decoder>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: Error!
There is no %s decoder! Exiting...


assistant: ```c
void invalid_decoder(const char *decoder) {
  printf("Error!\nThere is no %s decoder! Exiting...\n", decoder);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nrand32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x20,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <shuffle_signed@plt>
  jmp    L19
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L16
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int32_t nrand32(int n) {
  int32_t v = 0;
  static signed pos[32] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  shuffle_signed(pos, 32);
  while (n--)
    v |= (1 << pos[n]);
  return v;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nrand32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x20,%esi
  lea    D29(%rip),%rdi
  call   <shuffle_signed@plt>
  test   %ebx,%ebx
  je     L5
  movslq %ebx,%rax
  lea    D29(%rip),%rdx
  lea    (%rdx,%rax,4),%rdx
  lea    -0x1(%rbx),%ecx
  sub    %rcx,%rax
  lea    D15(%rip),%rcx
  lea    (%rcx,%rax,4),%rdi
  mov    $0x0,%eax
  mov    $0x1,%esi
L13:
  mov    -0x4(%rdx),%ecx
  mov    %esi,%ebx
  shl    %cl,%ebx
  or     %ebx,%eax
  sub    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L13
L27:
  pop    %rbx
  ret
L5:
  mov    %ebx,%eax
  jmp    L27
```

assistant: ```c
int32_t nrand32(int n) {
  int32_t v = 0;
  static signed pos[32] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  shuffle_signed(pos, 32);
  while (n--)
    v |= (1 << pos[n]);
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nrand32>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    $0x20,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <shuffle_signed@plt>
  test   %ebx,%ebx
  je     L10
  movslq %ebx,%rdx
  lea    -0x1(%rbx),%ecx
  xor    %r8d,%r8d
  mov    $0x1,%esi
  lea    0x0(%rbp,%rdx,4),%rax
  sub    %rcx,%rdx
  lea    -0x4(%rbp),%rcx
  lea    (%rcx,%rdx,4),%rdi
  nopw   0x0(%rax,%rax,1)
L9:
  mov    -0x4(%rax),%ecx
  mov    %esi,%edx
  sub    $0x4,%rax
  shl    %cl,%edx
  or     %edx,%r8d
  cmp    %rdi,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int32_t nrand32(int n) {
  int32_t v = 0;
  static signed pos[32] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  shuffle_signed(pos, 32);
  while (n--)
    v |= (1 << pos[n]);
  return v;
}
```
user: What is the c source code of the assembly code below?

```asm
<nrand32>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    $0x20,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <shuffle_signed@plt>
  test   %ebx,%ebx
  je     L2
  movslq %ebx,%rdx
  lea    -0x1(%rbx),%ecx
  xor    %r8d,%r8d
  mov    $0x1,%esi
  lea    0x0(%rbp,%rdx,4),%rax
  sub    %rcx,%rdx
  lea    -0x4(%rbp),%rcx
  lea    (%rcx,%rdx,4),%rdi
  nopw   0x0(%rax,%rax,1)
L11:
  mov    -0x4(%rax),%ecx
  mov    %esi,%edx
  sub    $0x4,%rax
  shl    %cl,%edx
  or     %edx,%r8d
  cmp    %rdi,%rax
  jne    L11
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int32_t nrand32(int n) {
  int32_t v = 0;
  static signed pos[32] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  shuffle_signed(pos, 32);
  while (n--)
    v |= (1 << pos[n]);
  return v;
}
```