ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<deputy_nullcheck>:
  endbr64
  cmp    $0x2,%edx
  je     L119
  cmp    $0x4,%edx
  je     L71
  cmp    $0x1,%edx
  je     L95
  sub    $0x8,%rsp
  lea    D22(%rip),%r8
  xor    %eax,%eax
  mov    $0x6d,%ecx
  lea    D10(%rip),%rdx
  lea    D11(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <deputy_fail_mayreturn@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L119:
  mov    %esi,%esi
  lea    (%rdi,%rsi,2),%rax
  cmp    %rax,%rdi
  jb     L61
  jmp    L8
  nopl   (%rax)
L84:
  add    $0x2,%rdi
  cmp    %rdi,%rax
  jbe    L8
L61:
  cmpw   $0x0,(%rdi)
  jne    L84
L8:
  cmp    %rdi,%rax
  setbe  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L95:
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jb     L89
  jmp    L8
  nopl   (%rax)
L149:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L8
L89:
  cmpb   $0x0,(%rdi)
  jne    L149
  cmp    %rdi,%rax
  setbe  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %esi,%esi
  lea    (%rdi,%rsi,8),%rax
  cmp    %rax,%rdi
  jb     L140
  jmp    L8
  nopl   (%rax)
L131:
  add    $0x8,%rdi
  cmp    %rdi,%rax
  jbe    L8
L140:
  cmpq   $0x0,(%rdi)
  jne    L131
  cmp    %rdi,%rax
  setbe  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string

tool: D22: deputy_nullcheck

tool: D10: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/spl/ivy/refs/heads/master/deputy-include/deputy/checks.h

tool: 

tool: D14: Bug: Invalid byte size for nullcheck.


assistant: ```c
__attribute__((regparm(0))) int deputy_nullcheck(const volatile void *e, unsigned int len, unsigned int bytes) {
  int success = 0;
  switch (bytes) {
  case 1:
    do {
      char *p1 = (char *)e;
      char *p2 = ((char *)e) + len;
      while (p1 < p2 && *p1 != 0) {
        p1++;
      }
      success = (p1 >= p2);
    } while (0);
    break;
  case 2:
    do {
      short *p1 = (short *)e;
      short *p2 = ((short *)e) + len;
      while (p1 < p2 && *p1 != 0) {
        p1++;
      }
      success = (p1 >= p2);
    } while (0);
    break;
  case 4:
    do {
      long *p1 = (long *)e;
      long *p2 = ((long *)e) + len;
      while (p1 < p2 && *p1 != 0) {
        p1++;
      }
      success = (p1 >= p2);
    } while (0);
    break;
  default:
    deputy_fail_mayreturn("Bug: Invalid byte size for nullcheck.\n", "", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/spl/ivy/refs/heads/master/deputy-include/deputy/checks.h", 109, __FUNCTION__);
  }
  return success;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g_fork>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    $0x0,%edi
  call   <g_mk_temp_dir@plt>
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int g_fork(void) {
  int rv;
  rv = fork();
  if (rv == 0) {
    g_mk_temp_dir(0);
  }
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<g_fork>:
  endbr64
  push   %rbx
  call   <fork@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L13
L6:
  mov    %ebx,%eax
  pop    %rbx
  ret
L13:
  mov    $0x0,%edi
  call   <g_mk_temp_dir@plt>
  jmp    L6
```

assistant: ```c
int g_fork(void) {
  int rv;
  rv = fork();
  if (rv == 0) {
    g_mk_temp_dir(0);
  }
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g_fork>:
  endbr64
  push   %r12
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L4
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %edi,%edi
  call   <g_mk_temp_dir@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int g_fork(void) {
  int rv;
  rv = fork();
  if (rv == 0) {
    g_mk_temp_dir(0);
  }
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<g_fork>:
  endbr64
  push   %r12
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %edi,%edi
  call   <g_mk_temp_dir@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int g_fork(void) {
  int rv;
  rv = fork();
  if (rv == 0) {
    g_mk_temp_dir(0);
  }
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x1,-0x80(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L64
L6:
  movl   $0x0,-0x90(%rbp)
  jmp    L72
L103:
  cmpl   $0x3,-0x90(%rbp)
  je     L33
  mov    -0x90(%rbp),%eax
  and    $0x4,%eax
  mov    %eax,%eax
  mov    -0x40(%rbp,%rax,8),%rcx
  mov    -0x90(%rbp),%eax
  mov    -0x80(%rbp,%rax,8),%rdx
  mov    -0x90(%rbp),%eax
  and    $0x4,%eax
  mov    %eax,%esi
  lea    (%rcx,%rdx,1),%rax
  mov    %esi,%edx
  mov    %rax,-0x40(%rbp,%rdx,8)
  cmpl   $0x3,-0x90(%rbp)
  ja     L5
  mov    -0x20(%rbp),%rdx
  mov    -0x90(%rbp),%eax
  mov    -0x80(%rbp,%rax,8),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
L5:
  mov    -0x90(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L48
  mov    -0x90(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  mov    -0x40(%rbp,%rax,8),%rcx
  mov    -0x90(%rbp),%eax
  mov    -0x80(%rbp,%rax,8),%rdx
  mov    -0x90(%rbp),%eax
  lea    0x1(%rax),%esi
  lea    (%rcx,%rdx,1),%rax
  mov    %esi,%edx
  mov    %rax,-0x40(%rbp,%rdx,8)
  jmp    L48
L33:
  nop
L48:
  addl   $0x1,-0x90(%rbp)
L72:
  cmpl   $0x6,-0x90(%rbp)
  jbe    L103
  movl   $0x0,-0x8c(%rbp)
  jmp    L47
L73:
  mov    -0x8c(%rbp),%eax
  mov    -0x40(%rbp,%rax,8),%rdx
  mov    -0x8c(%rbp),%eax
  mov    %rdx,-0x80(%rbp,%rax,8)
  mov    -0x8c(%rbp),%eax
  movq   $0x0,-0x40(%rbp,%rax,8)
  addl   $0x1,-0x8c(%rbp)
L47:
  cmpl   $0x6,-0x8c(%rbp)
  jbe    L73
  addl   $0x1,-0x94(%rbp)
L64:
  mov    -0x94(%rbp),%eax
  cmp    -0xa4(%rbp),%eax
  jb     L6
  movl   $0x0,-0x88(%rbp)
  movl   $0x0,-0x84(%rbp)
  jmp    L114
L129:
  mov    -0x84(%rbp),%eax
  mov    -0x80(%rbp,%rax,8),%rax
  add    %eax,-0x88(%rbp)
  addl   $0x1,-0x84(%rbp)
L114:
  cmpl   $0x6,-0x84(%rbp)
  jbe    L129
  mov    -0x88(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

assistant: ```c
uint64_t solve(uint64_t n) {
  unsigned long bystate[(7)] = {1, 0};
  unsigned long bystate1[(7)] = {0};
  for (unsigned int i = 0; i < n; ++i) {
    for (unsigned int s = 0; s < (7); ++s) {
      if (s == 3)
        continue;
      bystate1[s & 4] += bystate[s];
      if (s < 4)
        bystate1[4] += bystate[s];
      if ((s & 3) < 2)
        bystate1[s + 1] += bystate[s];
    }
    for (unsigned int s = 0; s < (7); ++s) {
      bystate[s] = bystate1[s];
      bystate1[s] = 0;
    }
  }
  uint64_t result = 0;
  for (unsigned int s = 0; s < (7); ++s) {
    result += bystate[s];
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solve>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x1,(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  mov    $0x0,%r10d
  lea    0x78(%rsp),%r9
  test   %edi,%edi
  jne    L56
L15:
  mov    %rsp,%rax
  lea    0x38(%rsp),%rcx
  mov    $0x0,%edx
L114:
  add    (%rax),%edx
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L114
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  mov    %edx,%eax
  add    $0x88,%rsp
  ret
L70:
  test   $0x2,%al
  jne    L67
L62:
  add    %rcx,0x48(%rsp,%rax,8)
L67:
  cmp    $0x6,%edx
  ja     L71
L14:
  add    $0x1,%rax
  add    $0x1,%edx
L72:
  cmp    $0x3,%eax
  je     L14
  mov    (%rsp,%rax,8),%rcx
  mov    %rax,%rsi
  and    $0x4,%esi
  add    %rcx,0x40(%rsp,%rsi,8)
  cmp    $0x3,%eax
  ja     L70
  add    %rcx,0x60(%rsp)
  test   $0x2,%al
  je     L62
  jmp    L14
L71:
  lea    0x40(%rsp),%rax
  mov    %rsp,%rdx
L87:
  mov    (%rax),%rcx
  mov    %rcx,(%rdx)
  movq   $0x0,(%rax)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %r9,%rax
  jne    L87
  add    $0x1,%r10d
  cmp    %r10d,%edi
  je     L15
L56:
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L72
L101:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t solve(uint64_t n) {
  unsigned long bystate[(7)] = {1, 0};
  unsigned long bystate1[(7)] = {0};
  for (unsigned int i = 0; i < n; ++i) {
    for (unsigned int s = 0; s < (7); ++s) {
      if (s == 3)
        continue;
      bystate1[s & 4] += bystate[s];
      if (s < 4)
        bystate1[4] += bystate[s];
      if ((s & 3) < 2)
        bystate1[s + 1] += bystate[s];
    }
    for (unsigned int s = 0; s < (7); ++s) {
      bystate[s] = bystate1[s];
      bystate1[s] = 0;
    }
  }
  uint64_t result = 0;
  for (unsigned int s = 0; s < (7); ++s) {
    result += bystate[s];
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solve>:
  endbr64
  sub    $0x88,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movq   $0x1,(%rsp)
  movq   $0x0,0x70(%rsp)
  movups %xmm0,0x8(%rsp)
  movups %xmm0,0x18(%rsp)
  movups %xmm0,0x28(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  test   %edi,%edi
  je     L31
  xor    %r10d,%r10d
  mov    %rsp,%r9
  lea    0x40(%rsp),%r8
  nopl   0x0(%rax)
L87:
  xor    %eax,%eax
  jmp    L4
  nopl   0x0(%rax)
L94:
  add    %rdx,0x60(%rsp)
  test   $0x2,%al
  jne    L80
L43:
  add    %rdx,0x8(%r8,%rax,8)
  cmp    $0x6,%esi
  je     L11
L80:
  add    $0x1,%rax
L4:
  mov    %eax,%esi
  cmp    $0x3,%rax
  je     L80
  mov    %rax,%rcx
  mov    (%r9,%rax,8),%rdx
  and    $0x4,%ecx
  add    %rdx,0x40(%rsp,%rcx,8)
  cmp    $0x3,%eax
  jbe    L94
  test   $0x2,%al
  je     L43
  cmp    $0x6,%esi
  jne    L80
L11:
  movdqa 0x40(%rsp),%xmm1
  movdqa 0x50(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  add    $0x1,%r10d
  movdqa 0x60(%rsp),%xmm3
  mov    0x70(%rsp),%rax
  movaps %xmm0,(%r8)
  movq   $0x0,0x30(%r8)
  mov    %rax,0x30(%rsp)
  movaps %xmm1,(%rsp)
  movaps %xmm2,0x10(%rsp)
  movaps %xmm3,0x20(%rsp)
  movaps %xmm0,0x10(%r8)
  movaps %xmm0,0x20(%r8)
  cmp    %r10d,%edi
  jne    L87
  mov    (%rsp),%rdx
L25:
  lea    0x8(%rsp),%rax
  lea    0x38(%rsp),%rcx
  xor    %r8d,%r8d
  jmp    L37
L119:
  mov    (%rax),%rdx
  add    $0x8,%rax
L37:
  add    %edx,%r8d
  cmp    %rax,%rcx
  jne    L119
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    %r8d,%eax
  add    $0x88,%rsp
  ret
L31:
  mov    $0x1,%edx
  jmp    L25
L79:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t solve(uint64_t n) {
  unsigned long bystate[(7)] = {1, 0};
  unsigned long bystate1[(7)] = {0};
  for (unsigned int i = 0; i < n; ++i) {
    for (unsigned int s = 0; s < (7); ++s) {
      if (s == 3)
        continue;
      bystate1[s & 4] += bystate[s];
      if (s < 4)
        bystate1[4] += bystate[s];
      if ((s & 3) < 2)
        bystate1[s + 1] += bystate[s];
    }
    for (unsigned int s = 0; s < (7); ++s) {
      bystate[s] = bystate1[s];
      bystate1[s] = 0;
    }
  }
  uint64_t result = 0;
  for (unsigned int s = 0; s < (7); ++s) {
    result += bystate[s];
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<solve>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x1,(%rsp)
  movups %xmm0,0x8(%rsp)
  movups %xmm0,0x18(%rsp)
  movups %xmm0,0x28(%rsp)
  test   %edi,%edi
  je     L8
  mov    %edi,%ebx
  xor    %r8d,%r8d
  xor    %edi,%edi
  xor    %r10d,%r10d
  xor    %edx,%edx
  xor    %r9d,%r9d
  mov    $0x1,%ecx
  xor    %esi,%esi
  jmp    L15
L38:
  mov    %r10,%r8
  mov    %rcx,%r9
  mov    %rax,%r10
  mov    %r11,%rcx
L15:
  lea    (%rcx,%r8,1),%rax
  add    %r9,%rdx
  add    $0x1,%esi
  add    %r10,%rax
  lea    (%rcx,%rdx,1),%r11
  add    %rdx,%rax
  mov    %r9,%rdx
  add    %rdi,%rax
  mov    %r8,%rdi
  cmp    %esi,%ebx
  jne    L38
  movq   %r11,%xmm0
  movq   %rcx,%xmm2
  movq   %r10,%xmm3
  mov    %r9,0x10(%rsp)
  punpcklqdq %xmm2,%xmm0
  mov    %r8,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm0
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
L8:
  movdqa (%rsp),%xmm0
  shufps $0x88,0x10(%rsp),%xmm0
  movdqa %xmm0,%xmm1
  mov    0x28(%rsp),%rax
  psrldq $0x8,%xmm1
  add    0x20(%rsp),%eax
  add    0x30(%rsp),%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  add    %edx,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x40,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t solve(uint64_t n) {
  unsigned long bystate[(7)] = {1, 0};
  unsigned long bystate1[(7)] = {0};
  for (unsigned int i = 0; i < n; ++i) {
    for (unsigned int s = 0; s < (7); ++s) {
      if (s == 3)
        continue;
      bystate1[s & 4] += bystate[s];
      if (s < 4)
        bystate1[4] += bystate[s];
      if ((s & 3) < 2)
        bystate1[s + 1] += bystate[s];
    }
    for (unsigned int s = 0; s < (7); ++s) {
      bystate[s] = bystate1[s];
      bystate1[s] = 0;
    }
  }
  uint64_t result = 0;
  for (unsigned int s = 0; s < (7); ++s) {
    result += bystate[s];
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<displayAccountingInfo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r14d
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r15d
  mov    %esi,%r13d
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L38:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    0x10(%rax),%ecx
  mov    0xc(%rax),%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  mov    (%rax),%esi
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x8(%rax),%xmm1
  mov    %r12,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L38
  pxor   %xmm3,%xmm3
  cvtsi2ss %r14d,%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  divss  %xmm3,%xmm0
  mov    %rbp,%rdx
  lea    0x8(%rbp,%r15,8),%rsi
  pxor   %xmm1,%xmm1
L6:
  mov    (%rdx),%rcx
  mov    0x10(%rcx),%eax
  sub    0x8(%rcx),%eax
  sub    (%rcx),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  addss  %xmm2,%xmm1
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L6
L9:
  divss  %xmm3,%xmm1
  lea    D0(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  pxor   %xmm3,%xmm3
  cvtsi2ss %esi,%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  divss  %xmm3,%xmm0
  pxor   %xmm1,%xmm1
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D4: pid: %d arrival_time: %d burst_time: %d start_time: %d end_time: %d 


tool: D0: 
 ThroughPut : %f  average_wait_time : %f 


assistant: ```c
int displayAccountingInfo(int **info, int jobs, int timeUnit) {
  for (int i = 0; i < jobs; i++) {
    printf("pid: %d arrival_time: %d burst_time: %d start_time: %d end_time: %d \n", i, info[i][2], info[i][0], info[i][3], info[i][4]);
  }
  float throughPut = (float)timeUnit / (float)jobs;
  float average_wait_time = 0;
  for (int i = 0; i < jobs; i++) {
    average_wait_time += (info[i][4] - info[i][2]) - info[i][0];
  }
  average_wait_time /= jobs;
  printf("\n ThroughPut : %f  average_wait_time : %f \n", throughPut, average_wait_time);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<displayAccountingInfo>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  mov    %esi,%r12d
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  lea    D17(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rbx,%r14,8),%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %rbp,%rdi
  cvtsi2ss %r14d,%xmm0
  add    $0x1,%r14
  cvtsi2ssl 0x8(%rax),%xmm1
  mov    0x10(%rax),%ecx
  mov    0xc(%rax),%edx
  mov    (%rax),%esi
  mov    $0x2,%eax
  call   <printf@plt>
  cmp    %r14,%r12
  jne    L37
  pxor   %xmm3,%xmm3
  pxor   %xmm0,%xmm0
  mov    0x8(%rsp),%rax
  mov    %rbx,%rdx
  cvtsi2ss %r13d,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2ss %r15d,%xmm0
  lea    0x8(%rbx,%rax,8),%rsi
  divss  %xmm3,%xmm0
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%rdx),%rcx
  pxor   %xmm2,%xmm2
  add    $0x8,%rdx
  mov    0x10(%rcx),%eax
  sub    0x8(%rcx),%eax
  sub    (%rcx),%eax
  cvtsi2ss %eax,%xmm2
  addss  %xmm2,%xmm1
  cmp    %rdx,%rsi
  jne    L29
L5:
  add    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divss  %xmm3,%xmm1
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  pxor   %xmm3,%xmm3
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm3
  cvtsi2ss %edx,%xmm0
  divss  %xmm3,%xmm0
  jmp    L5
```

tool_calls: name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D10
datatype: string

tool: D17: pid: %d arrival_time: %d burst_time: %d start_time: %d end_time: %d 


tool: D10: 
 ThroughPut : %f  average_wait_time : %f 


assistant: ```c
int displayAccountingInfo(int **info, int jobs, int timeUnit) {
  for (int i = 0; i < jobs; i++) {
    printf("pid: %d arrival_time: %d burst_time: %d start_time: %d end_time: %d \n", i, info[i][2], info[i][0], info[i][3], info[i][4]);
  }
  float throughPut = (float)timeUnit / (float)jobs;
  float average_wait_time = 0;
  for (int i = 0; i < jobs; i++) {
    average_wait_time += (info[i][4] - info[i][2]) - info[i][0];
  }
  average_wait_time /= jobs;
  printf("\n ThroughPut : %f  average_wait_time : %f \n", throughPut, average_wait_time);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<displayAccountingInfo>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  mov    %esi,%r12d
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  lea    D5(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rbx,%r14,8),%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %rbp,%rdi
  cvtsi2ss %r14d,%xmm0
  add    $0x1,%r14
  cvtsi2ssl 0x8(%rax),%xmm1
  mov    0x10(%rax),%ecx
  mov    0xc(%rax),%edx
  mov    (%rax),%esi
  mov    $0x2,%eax
  call   <printf@plt>
  cmp    %r14,%r12
  jne    L23
  pxor   %xmm3,%xmm3
  pxor   %xmm0,%xmm0
  mov    0x8(%rsp),%rax
  mov    %rbx,%rdx
  cvtsi2ss %r13d,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2ss %r15d,%xmm0
  lea    0x8(%rbx,%rax,8),%rsi
  divss  %xmm3,%xmm0
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rdx),%rcx
  pxor   %xmm2,%xmm2
  add    $0x8,%rdx
  mov    0x10(%rcx),%eax
  sub    0x8(%rcx),%eax
  sub    (%rcx),%eax
  cvtsi2ss %eax,%xmm2
  addss  %xmm2,%xmm1
  cmp    %rdx,%rsi
  jne    L10
L25:
  add    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divss  %xmm3,%xmm1
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  pxor   %xmm3,%xmm3
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm3
  cvtsi2ss %edx,%xmm0
  divss  %xmm3,%xmm0
  jmp    L25
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string

tool: D5: pid: %d arrival_time: %d burst_time: %d start_time: %d end_time: %d 


tool: D8: 
 ThroughPut : %f  average_wait_time : %f 


assistant: ```c
int displayAccountingInfo(int **info, int jobs, int timeUnit) {
  for (int i = 0; i < jobs; i++) {
    printf("pid: %d arrival_time: %d burst_time: %d start_time: %d end_time: %d \n", i, info[i][2], info[i][0], info[i][3], info[i][4]);
  }
  float throughPut = (float)timeUnit / (float)jobs;
  float average_wait_time = 0;
  for (int i = 0; i < jobs; i++) {
    average_wait_time += (info[i][4] - info[i][2]) - info[i][0];
  }
  average_wait_time /= jobs;
  printf("\n ThroughPut : %f  average_wait_time : %f \n", throughPut, average_wait_time);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_linkmode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L36
  mov    -0x4(%rbp),%eax
  jmp    L20
L36:
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <rtnl_send_linkmode@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L8
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <rtnl_recv@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L38
L8:
  nop
L38:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x8(%rbp),%eax
L20:
  leave
  ret
```

assistant: ```c
int set_linkmode(int ifindex, const char *ifname, __u8 linkmode) {
  int s;
  int rc;
  s = socket(PF_NETLINK, SOCK_DGRAM, 0);
  if (s < 0)
    return s;
  rc = rtnl_send_linkmode(s, ifindex, ifname, linkmode);
  if (rc < 0)
    goto out;
  rc = rtnl_recv(s, NULL, NULL);
out:
  close(s);
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_linkmode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0x0,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L4
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <rtnl_send_linkmode@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L17
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <rtnl_recv@plt>
  mov    %eax,%ebp
L17:
  mov    %ebx,%edi
  call   <close@plt>
  mov    %ebp,%ebx
L4:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int set_linkmode(int ifindex, const char *ifname, __u8 linkmode) {
  int s;
  int rc;
  s = socket(PF_NETLINK, SOCK_DGRAM, 0);
  if (s < 0)
    return s;
  rc = rtnl_send_linkmode(s, ifindex, ifname, linkmode);
  if (rc < 0)
    goto out;
  rc = rtnl_recv(s, NULL, NULL);
out:
  close(s);
  return rc;
}
```