ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<regexecs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rcx,%r13
  mov    %r8,%r14
  mov    %r9d,%r15d
  mov    $0x0,%ebp
L5:
  mov    %r15d,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <regexec@plt>
  test   %eax,%eax
  je     L3
  add    $0x1,%rbp
  add    $0x4,%rbx
  cmp    %rbp,%r12
  jne    L5
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int regexecs(regex_t *regex, size_t num_regex, const char *string, size_t nmatch, regmatch_t pmatch[], int eflags) {
  size_t i;
  int ret = REG_NOMATCH;
  for (i = 0; i < num_regex; i++)
    if (!(ret = regexec(&regex[i], string, nmatch, pmatch, eflags)))
      break;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<regexecs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D4(%rip),%rax
  mov    %rsi,0x8(%rsp)
  mov    (%rax),%eax
  test   %rsi,%rsi
  je     L37
  mov    %rdi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9d,%r14d
  xor    %ebx,%ebx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rbx
  add    $0x4,%r15
  cmp    %rbx,0x8(%rsp)
  je     L37
L28:
  mov    %r14d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <regexec@plt>
  test   %eax,%eax
  jne    L21
L37:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int regexecs(regex_t *regex, size_t num_regex, const char *string, size_t nmatch, regmatch_t pmatch[], int eflags) {
  size_t i;
  int ret = REG_NOMATCH;
  for (i = 0; i < num_regex; i++)
    if (!(ret = regexec(&regex[i], string, nmatch, pmatch, eflags)))
      break;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<regexecs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D1(%rip),%rax
  mov    %rsi,0x8(%rsp)
  mov    (%rax),%eax
  test   %rsi,%rsi
  je     L39
  mov    %rdi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9d,%r14d
  xor    %ebx,%ebx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rbx
  add    $0x4,%r15
  cmp    %rbx,0x8(%rsp)
  je     L39
L15:
  mov    %r14d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <regexec@plt>
  test   %eax,%eax
  jne    L23
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int regexecs(regex_t *regex, size_t num_regex, const char *string, size_t nmatch, regmatch_t pmatch[], int eflags) {
  size_t i;
  int ret = REG_NOMATCH;
  for (i = 0; i < num_regex; i++)
    if (!(ret = regexec(&regex[i], string, nmatch, pmatch, eflags)))
      break;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_variables@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string

tool: D4: UID: %d


tool: D10: PID: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("UID: %d\n", getuid());
  printf("PID: %d\n", getpid());
  print_variables(argv, argc);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <print_variables@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D11
datatype: string

tool: D14: UID: %d


tool: D11: PID: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("UID: %d\n", getuid());
  printf("PID: %d\n", getpid());
  print_variables(argv, argc);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <getuid@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <print_variables@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string

tool: D3: UID: %d


tool: D11: PID: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("UID: %d\n", getuid());
  printf("PID: %d\n", getpid());
  print_variables(argv, argc);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <getuid@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <print_variables@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D12
datatype: string

tool: D5: UID: %d


tool: D12: PID: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("UID: %d\n", getuid());
  printf("PID: %d\n", getpid());
  print_variables(argv, argc);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string

tool: D12: 
Sort : 

tool: D13: %d 

assistant: ```c
void display(int arr[100], int N) {
  printf("\nSort : \n");
  int i;
  for (i = 0; i < N; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<display>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D17(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L1
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D12(%rip),%rbp
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L13
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D17: 
Sort : 

tool: D12: %d 

assistant: ```c
void display(int arr[100], int N) {
  printf("\nSort : \n");
  int i;
  for (i = 0; i < N; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%eax
  lea    D4(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D0: 
Sort : 

tool: D4: %d 

assistant: ```c
void display(int arr[100], int N) {
  printf("\nSort : \n");
  int i;
  for (i = 0; i < N; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<display>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D12(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L3
  lea    -0x1(%rbp),%eax
  lea    D6(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type_guessed: string
name: read_data
arguments: data_label: D6
type_guessed: string

tool: D12: 
Sort : 

tool: D6: %d 

assistant: ```c
void display(int arr[100], int N) {
  printf("\nSort : \n");
  int i;
  for (i = 0; i < N; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LCD_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movswl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <reg_data@plt>
  mov    $0x40000,%edi
  call   <gpio_set@plt>
  mov    $0x800000,%edi
  call   <gpio_clr@plt>
  mov    $0x1,%edi
  call   <usleep@plt>
  mov    $0x800000,%edi
  call   <gpio_set@plt>
  nop
  leave
  ret
```

assistant: ```c
void LCD_command(short command) {
  reg_data(command);
  gpio_set(1 << 18);
  gpio_clr(1 << 23);
  usleep(1);
  gpio_set(1 << 23);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LCD_command>:
  endbr64
  sub    $0x8,%rsp
  movswl %di,%edi
  call   <reg_data@plt>
  mov    $0x40000,%edi
  call   <gpio_set@plt>
  mov    $0x800000,%edi
  call   <gpio_clr@plt>
  mov    $0x1,%edi
  call   <usleep@plt>
  mov    $0x800000,%edi
  call   <gpio_set@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LCD_command(short command) {
  reg_data(command);
  gpio_set(1 << 18);
  gpio_clr(1 << 23);
  usleep(1);
  gpio_set(1 << 23);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<LCD_command>:
  endbr64
  sub    $0x8,%rsp
  movswl %di,%edi
  call   <reg_data@plt>
  mov    $0x40000,%edi
  call   <gpio_set@plt>
  mov    $0x800000,%edi
  call   <gpio_clr@plt>
  mov    $0x1,%edi
  call   <usleep@plt>
  mov    $0x800000,%edi
  add    $0x8,%rsp
  jmp    1090 <gpio_set@plt>
```

assistant: ```c
void LCD_command(short command) {
  reg_data(command);
  gpio_set(1 << 18);
  gpio_clr(1 << 23);
  usleep(1);
  gpio_set(1 << 23);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LCD_command>:
  endbr64
  sub    $0x8,%rsp
  movswl %di,%edi
  call   <reg_data@plt>
  mov    $0x40000,%edi
  call   <gpio_set@plt>
  mov    $0x800000,%edi
  call   <gpio_clr@plt>
  mov    $0x1,%edi
  call   <usleep@plt>
  mov    $0x800000,%edi
  add    $0x8,%rsp
  jmp    1090 <gpio_set@plt>
```

assistant: ```c
void LCD_command(short command) {
  reg_data(command);
  gpio_set(1 << 18);
  gpio_clr(1 << 23);
  usleep(1);
  gpio_set(1 << 23);
}
```
user: What is the c source code of the assembly code below:

```asm
<asctime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <asctime_r@plt>
  leave
  ret
```

assistant: ```c
char *asctime(const struct tm *t) {
  static char cbuf[30];
  return asctime_r(t, cbuf);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<asctime>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  call   <asctime_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *asctime(const struct tm *t) {
  static char cbuf[30];
  return asctime_r(t, cbuf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<asctime>:
  endbr64
  lea    D2(%rip),%rsi
  jmp    1050 <asctime_r@plt>
```

assistant: ```c
char *asctime(const struct tm *t) {
  static char cbuf[30];
  return asctime_r(t, cbuf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<asctime>:
  endbr64
  lea    D0(%rip),%rsi
  jmp    1050 <asctime_r@plt>
```

assistant: ```c
char *asctime(const struct tm *t) {
  static char cbuf[30];
  return asctime_r(t, cbuf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L1:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L11
L48:
  mov    $0x0,%eax
L11:
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int str_to_int(char *s) {
  int value;
  char *temp;
  value = 0;
  for (temp = s; *temp != '\0'; temp++) {
    value = value * 10 + (((*temp >= '0') && (*temp <= '9')) ? (*temp) - '0' : 0);
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_to_int>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  mov    $0x0,%edx
  mov    $0x0,%esi
L13:
  lea    (%rdx,%rdx,4),%edx
  lea    -0x30(%rax),%ecx
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0xa,%cl
  cmovae %esi,%eax
  lea    (%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L13
L27:
  mov    %edx,%eax
  ret
L23:
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
int str_to_int(char *s) {
  int value;
  char *temp;
  value = 0;
  for (temp = s; *temp != '\0'; temp++) {
    value = value * 10 + (((*temp >= '0') && (*temp <= '9')) ? (*temp) - '0' : 0);
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_to_int>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L3
  nopl   (%rax)
L17:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  movsbl %dl,%eax
  add    %ecx,%eax
  cmp    $0xa,%dl
  cmovae %ecx,%eax
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L17
  ret
L3:
  ret
```

assistant: ```c
int str_to_int(char *s) {
  int value;
  char *temp;
  value = 0;
  for (temp = s; *temp != '\0'; temp++) {
    value = value * 10 + (((*temp >= '0') && (*temp <= '9')) ? (*temp) - '0' : 0);
  }
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_to_int>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L16
  nopl   (%rax)
L17:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  movsbl %dl,%eax
  add    %ecx,%eax
  cmp    $0xa,%dl
  cmovae %ecx,%eax
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L17
  ret
L16:
  ret
```

assistant: ```c
int str_to_int(char *s) {
  int value;
  char *temp;
  value = 0;
  for (temp = s; *temp != '\0'; temp++) {
    value = value * 10 + (((*temp >= '0') && (*temp <= '9')) ? (*temp) - '0' : 0);
  }
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nombreAleatoire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L3
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int nombreAleatoire(int nombreMax) {
  int nb1, nb2, nbr;
  srand(time(NULL));
  do {
    nb1 = (rand() % nombreMax);
    nb2 = (rand() % nombreMax);
    nbr = nb1 * nb2;
  } while (nbr > nombreMax);
  return nbr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nombreAleatoire>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  imul   %ebp,%edx
  cmp    %edx,%ebx
  jl     L7
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int nombreAleatoire(int nombreMax) {
  int nb1, nb2, nbr;
  srand(time(NULL));
  do {
    nb1 = (rand() % nombreMax);
    nb2 = (rand() % nombreMax);
    nbr = nb1 * nb2;
  } while (nbr > nombreMax);
  return nbr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nombreAleatoire>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,%ebp
  call   <rand@plt>
  cltd
  idiv   %ebx
  imul   %ebp,%edx
  cmp    %edx,%ebx
  jl     L7
  add    $0x8,%rsp
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int nombreAleatoire(int nombreMax) {
  int nb1, nb2, nbr;
  srand(time(NULL));
  do {
    nb1 = (rand() % nombreMax);
    nb2 = (rand() % nombreMax);
    nbr = nb1 * nb2;
  } while (nbr > nombreMax);
  return nbr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nombreAleatoire>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,%ebp
  call   <rand@plt>
  cltd
  idiv   %ebx
  imul   %ebp,%edx
  cmp    %edx,%ebx
  jl     L5
  add    $0x8,%rsp
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int nombreAleatoire(int nombreMax) {
  int nb1, nb2, nbr;
  srand(time(NULL));
  do {
    nb1 = (rand() % nombreMax);
    nb2 = (rand() % nombreMax);
    nbr = nb1 * nb2;
  } while (nbr > nombreMax);
  return nbr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<json_is_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <json_parse_string@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
L21:
  mov    $0x0,%eax
  jmp    L22
L15:
  mov    $0x1,%eax
L22:
  leave
  ret
```

assistant: ```c
bool json_is_string(const char *str) {
  size_t len;
  len = json_parse_string(str);
  if (!len || str[len] != '\0')
    return false;
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<json_is_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <json_parse_string@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L2
  cmpb   $0x0,(%rbx,%rax,1)
  sete   %dl
  movzbl %dl,%edx
L2:
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool json_is_string(const char *str) {
  size_t len;
  len = json_parse_string(str);
  if (!len || str[len] != '\0')
    return false;
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<json_is_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <json_parse_string@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L0
  xor    %r8d,%r8d
  cmpb   $0x0,(%rbx,%rax,1)
  sete   %r8b
L0:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool json_is_string(const char *str) {
  size_t len;
  len = json_parse_string(str);
  if (!len || str[len] != '\0')
    return false;
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<json_is_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <json_parse_string@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L0
  xor    %r8d,%r8d
  cmpb   $0x0,(%rbx,%rax,1)
  sete   %r8b
L0:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool json_is_string(const char *str) {
  size_t len;
  len = json_parse_string(str);
  if (!len || str[len] != '\0')
    return false;
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<map_ihas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <map_get_node@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    $0x1,%eax
  jmp    L12
L5:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int map_ihas(struct map *m, char *key, size_t len) {
  assert(m != NULL);
  assert(key != NULL);
  struct map_node *node = map_get_node(m, key, len);
  if (node != NULL)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<map_ihas>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <map_get_node@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int map_ihas(struct map *m, char *key, size_t len) {
  assert(m != NULL);
  assert(key != NULL);
  struct map_node *node = map_get_node(m, key, len);
  if (node != NULL)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<map_ihas>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <map_get_node@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int map_ihas(struct map *m, char *key, size_t len) {
  assert(m != NULL);
  assert(key != NULL);
  struct map_node *node = map_get_node(m, key, len);
  if (node != NULL)
    return 1;
  return 0;
}
```