ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L28
  mov    %rsi,%rbp
  movslq %edi,%r13
  mov    $0x1,%ebx
  lea    D46(%rip),%r12
  nopl   (%rax)
L38:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L38
L28:
  lea    D49(%rip),%rax
  xor    %ebx,%ebx
  lea    D1(%rip),%rdx
  movq   $0x0,0x20(%rsp)
  mov    %rax,0x8(%rsp)
  lea    D17(%rip),%rax
  mov    %rsp,%rbp
  lea    D21(%rip),%r12
  mov    %rax,0x10(%rsp)
  lea    D55(%rip),%rax
  mov    %rdx,(%rsp)
  mov    %rax,0x18(%rsp)
  movq   $0x0,0x28(%rsp)
  jmp    L6
  nopl   0x0(%rax)
L48:
  mov    0x0(%rbp,%rbx,8),%rdx
L6:
  lea    0x0(%rbp,%rbx,8),%rcx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L48
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D46
type_infered: string
name: read_data
arguments: label: D49
type_infered: string
name: read_data
arguments: label: D1
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D55
type_infered: string

tool: D46: arg %d: %s


tool: D49: Oregon

tool: D1: California

tool: D17: Washington

tool: D21: state %d: %s, %p


tool: D55: Texas

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas", NULL, NULL};
  int num_states = 6;
  for (i = 0; i < num_states; i++) {
    printf("state %d: %s, %p\n", i, states[i], &(states[i]));
  };
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L17
  mov    %rsi,%r12
  movslq %edi,%rbp
  mov    $0x1,%ebx
  lea    D56(%rip),%r13
  nopl   (%rax)
L23:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L23
L17:
  lea    D6(%rip),%rax
  lea    D10(%rip),%rcx
  mov    %rsp,%rbp
  xor    %ebx,%ebx
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D45(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D4(%rip),%rax
  lea    D34(%rip),%r12
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x20(%rsp)
  nopw   0x0(%rax,%rax,1)
L12:
  mov    0x0(%rbp),%rdx
  mov    %rbp,%rcx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L12
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D56
datatype: string
name: retrieve_data
arguments: data_tag: D6
datatype: string
name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D45
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D34
datatype: string

tool: D56: arg %d: %s


tool: D6: Oregon

tool: D10: California

tool: D45: Washington

tool: D4: Texas

tool: D34: state %d: %s, %p


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas", NULL, NULL};
  int num_states = 6;
  for (i = 0; i < num_states; i++) {
    printf("state %d: %s, %p\n", i, states[i], &(states[i]));
  };
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uni_to_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x7f,-0x8(%rbp)
  ja     L46
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x1,%eax
  jmp    L35
L46:
  cmpq   $0x7ff,-0x8(%rbp)
  ja     L42
  mov    -0x8(%rbp),%rax
  shr    $0x6,%rax
  and    $0x1f,%eax
  or     $0xffffffc0,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    $0x2,%eax
  jmp    L35
L42:
  cmpq   $0xffff,-0x8(%rbp)
  ja     L70
  mov    -0x8(%rbp),%rax
  shr    $0xc,%rax
  and    $0xf,%eax
  or     $0xffffffe0,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x6,%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    $0x3,%eax
  jmp    L35
L70:
  cmpq   $0x10ffff,-0x8(%rbp)
  ja     L73
  mov    -0x8(%rbp),%rax
  shr    $0x12,%rax
  and    $0x7,%eax
  or     $0xfffffff0,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0xc,%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x6,%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    $0x4,%eax
  jmp    L35
L73:
  mov    $0x0,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int uni_to_utf8(unsigned long uc, unsigned char *utf8) {
  if (uc <= 0x007FUL) {
    utf8[0] = uc;
    return 1;
  }
  if (uc <= 0x07FFUL) {
    utf8[0] = 0xC0 | ((uc >> 6) & 0x1F);
    utf8[1] = 0x80 | ((uc >> 0) & 0x3F);
    return 2;
  }
  if (uc <= 0xFFFFUL) {
    utf8[0] = 0xE0 | ((uc >> 12) & 0x0F);
    utf8[1] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 0) & 0x3F);
    return 3;
  }
  if (uc <= 0x10FFFFUL) {
    utf8[0] = 0xF0 | ((uc >> 18) & 0x07);
    utf8[1] = 0x80 | ((uc >> 12) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[3] = 0x80 | ((uc >> 0) & 0x3F);
    return 4;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uni_to_utf8>:
  endbr64
  mov    %rdi,%rax
  cmp    $0x7f,%rdi
  jbe    L60
  cmp    $0x7ff,%rdi
  jbe    L19
  cmp    $0xffff,%rdi
  jbe    L41
  mov    $0x0,%edx
  cmp    $0x10ffff,%rdi
  ja     L67
  mov    %rdi,%rdx
  shr    $0x12,%rdx
  or     $0xfffffff0,%edx
  mov    %dl,(%rsi)
  mov    %rdi,%rdx
  shr    $0xc,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x3(%rsi)
  mov    $0x4,%edx
  jmp    L67
L60:
  mov    %dil,(%rsi)
  mov    $0x1,%edx
L67:
  mov    %edx,%eax
  ret
L19:
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  or     $0xffffffc0,%edx
  mov    %dl,(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x1(%rsi)
  mov    $0x2,%edx
  jmp    L67
L41:
  mov    %rdi,%rdx
  shr    $0xc,%rdx
  or     $0xffffffe0,%edx
  mov    %dl,(%rsi)
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x2(%rsi)
  mov    $0x3,%edx
  jmp    L67
```

assistant: ```c
int uni_to_utf8(unsigned long uc, unsigned char *utf8) {
  if (uc <= 0x007FUL) {
    utf8[0] = uc;
    return 1;
  }
  if (uc <= 0x07FFUL) {
    utf8[0] = 0xC0 | ((uc >> 6) & 0x1F);
    utf8[1] = 0x80 | ((uc >> 0) & 0x3F);
    return 2;
  }
  if (uc <= 0xFFFFUL) {
    utf8[0] = 0xE0 | ((uc >> 12) & 0x0F);
    utf8[1] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 0) & 0x3F);
    return 3;
  }
  if (uc <= 0x10FFFFUL) {
    utf8[0] = 0xF0 | ((uc >> 18) & 0x07);
    utf8[1] = 0x80 | ((uc >> 12) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[3] = 0x80 | ((uc >> 0) & 0x3F);
    return 4;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uni_to_utf8>:
  endbr64
  mov    %rdi,%rax
  cmp    $0x7f,%rdi
  jbe    L45
  cmp    $0x7ff,%rdi
  jbe    L41
  cmp    $0xffff,%rdi
  jbe    L1
  xor    %r8d,%r8d
  cmp    $0x10ffff,%rdi
  jbe    L10
L39:
  mov    %r8d,%eax
  ret
  nop
L45:
  mov    $0x1,%r8d
  mov    %dil,(%rsi)
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L1:
  mov    %rdi,%rdx
  and    $0x3f,%eax
  mov    $0x3,%r8d
  shr    $0xc,%rdx
  or     $0xffffff80,%eax
  or     $0xffffffe0,%edx
  mov    %al,0x2(%rsi)
  mov    %r8d,%eax
  mov    %dl,(%rsi)
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  ret
  nop
L41:
  mov    %rdi,%rdx
  and    $0x3f,%eax
  mov    $0x2,%r8d
  shr    $0x6,%rdx
  or     $0xffffff80,%eax
  or     $0xffffffc0,%edx
  mov    %al,0x1(%rsi)
  mov    %r8d,%eax
  mov    %dl,(%rsi)
  ret
  nop
L10:
  mov    %rdi,%rdx
  and    $0x3f,%eax
  mov    $0x4,%r8d
  shr    $0x12,%rdx
  or     $0xffffff80,%eax
  or     $0xfffffff0,%edx
  mov    %al,0x3(%rsi)
  mov    %dl,(%rsi)
  mov    %rdi,%rdx
  shr    $0xc,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  jmp    L39
```

assistant: ```c
int uni_to_utf8(unsigned long uc, unsigned char *utf8) {
  if (uc <= 0x007FUL) {
    utf8[0] = uc;
    return 1;
  }
  if (uc <= 0x07FFUL) {
    utf8[0] = 0xC0 | ((uc >> 6) & 0x1F);
    utf8[1] = 0x80 | ((uc >> 0) & 0x3F);
    return 2;
  }
  if (uc <= 0xFFFFUL) {
    utf8[0] = 0xE0 | ((uc >> 12) & 0x0F);
    utf8[1] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 0) & 0x3F);
    return 3;
  }
  if (uc <= 0x10FFFFUL) {
    utf8[0] = 0xF0 | ((uc >> 18) & 0x07);
    utf8[1] = 0x80 | ((uc >> 12) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[3] = 0x80 | ((uc >> 0) & 0x3F);
    return 4;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<uni_to_utf8>:
  endbr64
  mov    %rdi,%rax
  cmp    $0x7f,%rdi
  jbe    L28
  cmp    $0x7ff,%rdi
  jbe    L9
  cmp    $0xffff,%rdi
  jbe    L46
  xor    %r8d,%r8d
  cmp    $0x10ffff,%rdi
  jbe    L11
L0:
  mov    %r8d,%eax
  ret
  nop
L28:
  mov    $0x1,%r8d
  mov    %dil,(%rsi)
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L46:
  mov    %rdi,%rdx
  and    $0x3f,%eax
  mov    $0x3,%r8d
  shr    $0xc,%rdx
  or     $0xffffff80,%eax
  or     $0xffffffe0,%edx
  mov    %al,0x2(%rsi)
  mov    %r8d,%eax
  mov    %dl,(%rsi)
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  ret
  nop
L9:
  mov    %rdi,%rdx
  and    $0x3f,%eax
  mov    $0x2,%r8d
  shr    $0x6,%rdx
  or     $0xffffff80,%eax
  or     $0xffffffc0,%edx
  mov    %al,0x1(%rsi)
  mov    %r8d,%eax
  mov    %dl,(%rsi)
  ret
  nop
L11:
  mov    %rdi,%rdx
  and    $0x3f,%eax
  mov    $0x4,%r8d
  shr    $0x12,%rdx
  or     $0xffffff80,%eax
  or     $0xfffffff0,%edx
  mov    %al,0x3(%rsi)
  mov    %dl,(%rsi)
  mov    %rdi,%rdx
  shr    $0xc,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %rdi,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  jmp    L0
```

assistant: ```c
int uni_to_utf8(unsigned long uc, unsigned char *utf8) {
  if (uc <= 0x007FUL) {
    utf8[0] = uc;
    return 1;
  }
  if (uc <= 0x07FFUL) {
    utf8[0] = 0xC0 | ((uc >> 6) & 0x1F);
    utf8[1] = 0x80 | ((uc >> 0) & 0x3F);
    return 2;
  }
  if (uc <= 0xFFFFUL) {
    utf8[0] = 0xE0 | ((uc >> 12) & 0x0F);
    utf8[1] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 0) & 0x3F);
    return 3;
  }
  if (uc <= 0x10FFFFUL) {
    utf8[0] = 0xF0 | ((uc >> 18) & 0x07);
    utf8[1] = 0x80 | ((uc >> 12) & 0x3F);
    utf8[2] = 0x80 | ((uc >> 6) & 0x3F);
    utf8[3] = 0x80 | ((uc >> 0) & 0x3F);
    return 4;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call_bad_if_not_alias_Good>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bad_if_not_alias@plt>
  nop
  leave
  ret
```

assistant: ```c
void call_bad_if_not_alias_Good() {
  int x;
  bad_if_not_alias(x, x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<call_bad_if_not_alias_Good>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  mov    %edi,%esi
  call   <bad_if_not_alias@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void call_bad_if_not_alias_Good() {
  int x;
  bad_if_not_alias(x, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call_bad_if_not_alias_Good>:
  endbr64
  xor    %edi,%edi
  mov    %edi,%esi
  jmp    1050 <bad_if_not_alias@plt>
```

assistant: ```c
void call_bad_if_not_alias_Good() {
  int x;
  bad_if_not_alias(x, x);
}
```
user: What is the c source code of the assembly code below?

```asm
<call_bad_if_not_alias_Good>:
  endbr64
  xor    %edi,%edi
  mov    %edi,%esi
  jmp    1050 <bad_if_not_alias@plt>
```

assistant: ```c
void call_bad_if_not_alias_Good() {
  int x;
  bad_if_not_alias(x, x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<linux_base64_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rdx,%rsi
  jae    L10
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r15
  movl   $0x0,0xc(%rsp)
  jmp    L38
L6:
  add    $0x1,%rbx
  jmp    L119
L36:
  addl   $0x1,0xc(%rsp)
  jmp    L31
L71:
  shl    $0x6,%r12d
  or     %edx,%r12d
  mov    %r12b,0x2(%r13)
  addl   $0x3,0xc(%rsp)
  mov    %r14,%rbx
  lea    0x3(%r13),%r13
L119:
  cmp    %rbx,%r15
  jbe    L31
L38:
  movzbl (%rbx),%edi
  cmp    $0xa,%dil
  je     L6
  lea    0x4(%rbx),%r14
  cmp    %r15,%r14
  ja     L22
  movsbl %dil,%edi
  call   <decode_bits@plt>
  mov    %eax,0x8(%rsp)
  movsbl 0x1(%rbx),%edi
  call   <decode_bits@plt>
  mov    %eax,%ebp
  movsbl 0x2(%rbx),%edi
  call   <decode_bits@plt>
  mov    %eax,%r12d
  movsbl 0x3(%rbx),%edi
  call   <decode_bits@plt>
  mov    %eax,%edx
  mov    0x8(%rsp),%esi
  mov    %esi,%eax
  or     %ebp,%eax
  or     %r12d,%eax
  or     %edx,%eax
  js     L61
  mov    %esi,%eax
  shl    $0x2,%eax
  mov    %ebp,%ecx
  sar    $0x4,%ecx
  or     %ecx,%eax
  mov    %al,0x0(%r13)
  cmpb   $0x3d,0x2(%rbx)
  je     L36
  shl    $0x4,%ebp
  mov    %r12d,%eax
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r13)
  cmpb   $0x3d,0x3(%rbx)
  jne    L71
  addl   $0x2,0xc(%rsp)
  jmp    L31
L10:
  movl   $0x0,0xc(%rsp)
  jmp    L31
L22:
  movl   $0xffffffea,0xc(%rsp)
L31:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  movl   $0xffffffea,0xc(%rsp)
  jmp    L31
```

assistant: ```c
int linux_base64_decode(char *dst, const char *src, const char *end) {
  int olen = 0;
  while (src < end) {
    int a, b, c, d;
    if (src[0] == '\n') {
      src++;
      continue;
    }
    if (src + 4 > end)
      return -22;
    a = decode_bits(src[0]);
    b = decode_bits(src[1]);
    c = decode_bits(src[2]);
    d = decode_bits(src[3]);
    if (a < 0 || b < 0 || c < 0 || d < 0)
      return -22;
    *dst++ = (a << 2) | (b >> 4);
    if (src[2] == '=')
      return olen + 1;
    *dst++ = ((b & 15) << 4) | (c >> 2);
    if (src[3] == '=')
      return olen + 2;
    *dst++ = ((c & 3) << 6) | d;
    olen += 3;
    src += 4;
  }
  return olen;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<linux_base64_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rdx,%rsi
  jae    L84
  movl   $0x0,0xc(%rsp)
  mov    %rdi,%r15
  mov    %rsi,%rbx
  mov    %rdx,%r13
  jmp    L116
  nopl   0x0(%rax)
L47:
  lea    0x4(%rbx),%rdx
  cmp    %r13,%rdx
  ja     L114
  mov    %rdx,(%rsp)
  call   <decode_bits@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <decode_bits@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <decode_bits@plt>
  movsbl 0x3(%rbx),%edi
  mov    %eax,%r14d
  call   <decode_bits@plt>
  mov    %eax,%esi
  mov    %r12d,%eax
  or     %ebp,%eax
  or     %r14d,%eax
  or     %esi,%eax
  js     L114
  mov    %ebp,%eax
  shl    $0x2,%r12d
  mov    (%rsp),%rdx
  sar    $0x4,%eax
  or     %eax,%r12d
  mov    %r12b,(%r15)
  cmpb   $0x3d,0x2(%rbx)
  je     L21
  mov    %r14d,%eax
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r15)
  cmpb   $0x3d,0x3(%rbx)
  je     L123
  shl    $0x6,%r14d
  mov    %rdx,%rbx
  addl   $0x3,0xc(%rsp)
  add    $0x3,%r15
  or     %esi,%r14d
  mov    %r14b,-0x1(%r15)
  cmp    %rbx,%r13
  jbe    L125
L116:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  jne    L47
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L116
L125:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L114:
  movl   $0xffffffea,0xc(%rsp)
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L21:
  addl   $0x1,0xc(%rsp)
  jmp    L125
  nop
L123:
  addl   $0x2,0xc(%rsp)
  jmp    L125
L84:
  movl   $0x0,0xc(%rsp)
  jmp    L125
```

assistant: ```c
int linux_base64_decode(char *dst, const char *src, const char *end) {
  int olen = 0;
  while (src < end) {
    int a, b, c, d;
    if (src[0] == '\n') {
      src++;
      continue;
    }
    if (src + 4 > end)
      return -22;
    a = decode_bits(src[0]);
    b = decode_bits(src[1]);
    c = decode_bits(src[2]);
    d = decode_bits(src[3]);
    if (a < 0 || b < 0 || c < 0 || d < 0)
      return -22;
    *dst++ = (a << 2) | (b >> 4);
    if (src[2] == '=')
      return olen + 1;
    *dst++ = ((b & 15) << 4) | (c >> 2);
    if (src[3] == '=')
      return olen + 2;
    *dst++ = ((c & 3) << 6) | d;
    olen += 3;
    src += 4;
  }
  return olen;
}
```
user: What is the c source code of the assembly code below?

```asm
<linux_base64_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rdx,%rsi
  jae    L7
  movl   $0x0,0xc(%rsp)
  mov    %rdi,%r15
  mov    %rsi,%rbx
  mov    %rdx,%r13
  jmp    L34
  nopl   0x0(%rax)
L39:
  lea    0x4(%rbx),%rdx
  cmp    %r13,%rdx
  ja     L105
  mov    %rdx,(%rsp)
  call   <decode_bits@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <decode_bits@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <decode_bits@plt>
  movsbl 0x3(%rbx),%edi
  mov    %eax,%r14d
  call   <decode_bits@plt>
  mov    %eax,%esi
  mov    %r12d,%eax
  or     %ebp,%eax
  or     %r14d,%eax
  or     %esi,%eax
  js     L105
  mov    %ebp,%eax
  shl    $0x2,%r12d
  mov    (%rsp),%rdx
  sar    $0x4,%eax
  or     %eax,%r12d
  mov    %r12b,(%r15)
  cmpb   $0x3d,0x2(%rbx)
  je     L52
  mov    %r14d,%eax
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r15)
  cmpb   $0x3d,0x3(%rbx)
  je     L101
  shl    $0x6,%r14d
  mov    %rdx,%rbx
  addl   $0x3,0xc(%rsp)
  add    $0x3,%r15
  or     %esi,%r14d
  mov    %r14b,-0x1(%r15)
  cmp    %rbx,%r13
  jbe    L117
L34:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  jne    L39
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L34
L117:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  movl   $0xffffffea,0xc(%rsp)
  jmp    L117
  nopw   0x0(%rax,%rax,1)
L52:
  addl   $0x1,0xc(%rsp)
  jmp    L117
  nop
L101:
  addl   $0x2,0xc(%rsp)
  jmp    L117
L7:
  movl   $0x0,0xc(%rsp)
  jmp    L117
```

assistant: ```c
int linux_base64_decode(char *dst, const char *src, const char *end) {
  int olen = 0;
  while (src < end) {
    int a, b, c, d;
    if (src[0] == '\n') {
      src++;
      continue;
    }
    if (src + 4 > end)
      return -22;
    a = decode_bits(src[0]);
    b = decode_bits(src[1]);
    c = decode_bits(src[2]);
    d = decode_bits(src[3]);
    if (a < 0 || b < 0 || c < 0 || d < 0)
      return -22;
    *dst++ = (a << 2) | (b >> 4);
    if (src[2] == '=')
      return olen + 1;
    *dst++ = ((b & 15) << 4) | (c >> 2);
    if (src[3] == '=')
      return olen + 2;
    *dst++ = ((c & 3) << 6) | d;
    olen += 3;
    src += 4;
  }
  return olen;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<null_write_urgent_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int null_write_urgent_data(const char *a, int n) {
  (void)a;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<null_write_urgent_data>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int null_write_urgent_data(const char *a, int n) {
  (void)a;
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<null_write_urgent_data>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int null_write_urgent_data(const char *a, int n) {
  (void)a;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<null_write_urgent_data>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int null_write_urgent_data(const char *a, int n) {
  (void)a;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atomicio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L87
L7:
  mov    -0x18(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x2c(%rbp),%eax
  mov    -0x28(%rbp),%rcx
  mov    %eax,%edi
  call   *%rcx
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  je     L91
  cmpq   $0x0,-0x8(%rbp)
  je     L68
  jmp    L85
L91:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L87
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L68
  jmp    L87
L68:
  cmpq   $0x0,-0x18(%rbp)
  je     L50
  mov    -0x18(%rbp),%rax
  jmp    L24
L50:
  mov    -0x8(%rbp),%rax
  jmp    L24
L85:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
L87:
  mov    -0x40(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jl     L7
  mov    -0x18(%rbp),%rax
L24:
  leave
  ret
```

assistant: ```c
ssize_t atomicio(ssize_t (*f)(int, void *, size_t), int fd, void *_s, size_t n) {
  char *s = _s;
  ssize_t res, pos = 0;
  while ((ssize_t)n > pos) {
    res = (f)(fd, s + pos, n - pos);
    switch (res) {
    case -1:
      if (errno == EINTR || errno == EAGAIN)
        continue;
    case 0:
      if (pos != 0)
        return pos;
      return res;
    default:
      pos += res;
    }
  }
  return pos;
}
```