user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D50(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x3c(%rbp),%rsi
  lea    D64(%rip),%rdi
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rcx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L169
L177:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L177
L169:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L106
L164:
  mov    %rsp,-0x48(%rbp)
  mov    %rax,%rcx
  mov    %rsp,%rsi
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rcx
  sub    %rax,%rsi
L61:
  cmp    %rsi,%rsp
  je     L112
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L61
L106:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L164
L112:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L147
L59:
  lea    (%rdx,%rdx,1),%eax
  mov    %rsp,%rcx
  mov    %rsp,%r14
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rcx
L167:
  cmp    %rcx,%rsp
  je     L56
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L167
L147:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L59
L56:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L109
  orq    $0x0,-0x8(%rsp,%rdx,1)
L109:
  lea    D39(%rip),%rdi
  mov    %rsp,%r12
  call   <printf@plt>
  cmpl   $0x0,-0x3c(%rbp)
  jle    L51
  mov    -0x48(%rbp),%r15
  xor    %ebx,%ebx
  lea    D8(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L132:
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x4(%r15),%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,-0x3c(%rbp)
  jg     L132
L51:
  lea    D52(%rip),%rdi
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jle    L88
  mov    %r14,%r15
  xor    %ebx,%ebx
  lea    D8(%rip),%r13
  nop
L42:
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    %ebx,-0x3c(%rbp)
  jg     L42
L88:
  lea    D88(%rip),%rdi
  call   <printf@plt>
  mov    -0x3c(%rbp),%esi
  mov    -0x48(%rbp),%rdi
  call   <PrintVetor@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    -0x3c(%rbp),%esi
  mov    %r14,%rdi
  call   <PrintVetor@plt>
  movslq -0x3c(%rbp),%r13
  test   %r13d,%r13d
  jle    L116
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L152:
  mov    (%r14,%rbx,4),%edi
  mov    %r13d,%edx
  mov    %r12,%rsi
  call   <Existe@plt>
  test   %eax,%eax
  jne    L19
  mov    (%r14,%rbx,4),%eax
  mov    %eax,(%r12,%r13,4)
L19:
  add    $0x1,%rbx
  add    $0x1,%r13
  cmp    %ebx,-0x3c(%rbp)
  jg     L152
L116:
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  mov    %r12,%rdi
  lea    (%rax,%rax,1),%esi
  call   <PrintVetor@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D50
type_infered: string
name: retrieve_data
arguments: data_label: D64
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D52
type_infered: string
name: retrieve_data
arguments: data_label: D88
type_infered: string
name: retrieve_data
arguments: data_label: D16
type_infered: string
name: retrieve_data
arguments: data_label: D72
type_infered: string

tool: D50: Qual o tamanho dos conjuntos?


tool: D64: %i

tool: D39: Preencha o Conjunto A


tool: D8: %d

tool: D52: Preencha o Conjunto B


tool: D88: Conjunto A: 

tool: D16: Conjunto B: 

tool: D72: Conjunto Uniao: 

assistant: ```c
int main() {
  int tamanho;
  printf("Qual o tamanho dos conjuntos?\n");
  scanf("%i", &tamanho);
  int conjA[tamanho];
  int conjB[tamanho];
  int uniao[tamanho * 2];
  printf("Preencha o Conjunto A\n");
  for (int i = 0; i < tamanho; i++) {
    scanf("%d", &conjA[i]);
    uniao[i] = conjA[i];
  }
  printf("Preencha o Conjunto B\n");
  for (int i = 0; i < tamanho; i++)
    scanf("%d", &conjB[i]);
  printf("Conjunto A: ");
  PrintVetor(conjA, tamanho);
  printf("Conjunto B: ");
  PrintVetor(conjB, tamanho);
  for (int i = 0, k = tamanho; i < tamanho; i++, k++)
    if (!Existe(conjB[i], uniao, k))
      uniao[k] = conjB[i];
  printf("Conjunto Uniao: ");
  PrintVetor(uniao, tamanho * 2);
}
```