ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<handler>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xffffffff,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edx
  call   <waitpid@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handler(int signum) {
  int status;
  pid_t pid;
  pid = waitpid(-1, &status, WNOHANG);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handler>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xffffffff,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edx
  call   <waitpid@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handler(int signum) {
  int status;
  pid_t pid;
  pid = waitpid(-1, &status, WNOHANG);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imp_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L45
L43:
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L20:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L44
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L44:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L20
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L43
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: Valor[%d][%d]: %d


assistant: ```c
void imp_val(int *val, int tam, int dim) {
  for (int i = 0; i < tam; i++) {
    for (int j = 0; j < dim; j++) {
      if ((i + j) % 2 == 0) {
        printf("Valor[%d][%d]: %d\n", i, j, *(val + i + j * tam));
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<imp_val>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,(%rsp)
  test   %esi,%esi
  jle    L9
  mov    %rdi,%r15
  mov    %edx,%r12d
  mov    %esi,%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r14d
  jmp    L2
L10:
  add    $0x1,%ebx
  add    (%rsp),%ebp
  cmp    %ebx,%r12d
  je     L69
L30:
  lea    (%rbx,%r13,1),%eax
  test   $0x1,%al
  jne    L10
  movslq %ebp,%rax
  add    %r14,%rax
  mov    (%r15,%rax,4),%ecx
  mov    %ebx,%edx
  mov    0x4(%rsp),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L69:
  add    $0x1,%r14
  cmp    0x8(%rsp),%r14
  je     L9
L2:
  mov    %r14d,%r13d
  mov    %r14d,0x4(%rsp)
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L30
  jmp    L69
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: Valor[%d][%d]: %d


assistant: ```c
void imp_val(int *val, int tam, int dim) {
  for (int i = 0; i < tam; i++) {
    for (int j = 0; j < dim; j++) {
      if ((i + j) % 2 == 0) {
        printf("Valor[%d][%d]: %d\n", i, j, *(val + i + j * tam));
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<imp_val>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  test   %esi,%esi
  jle    L2
  movslq %esi,%rax
  mov    %esi,%r12d
  mov    %edx,%r15d
  xor    %r14d,%r14d
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L39:
  mov    %r14d,%r8d
  mov    %r14d,%r13d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  test   %r15d,%r15d
  jg     L34
  jmp    L3
  nopl   0x0(%rax)
L6:
  add    $0x1,%ebx
  add    %r12d,%ebp
  cmp    %ebx,%r15d
  je     L3
L34:
  lea    (%rbx,%r8,1),%eax
  test   $0x1,%al
  jne    L6
  mov    0x10(%rsp),%rdx
  movslq %ebp,%rax
  mov    %r13d,%esi
  mov    %r8d,0xc(%rsp)
  add    %r14,%rax
  lea    D9(%rip),%rdi
  add    %r12d,%ebp
  mov    (%rdx,%rax,4),%ecx
  mov    %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
  cmp    %ebx,%r15d
  jne    L34
L3:
  add    $0x1,%r14
  cmp    0x18(%rsp),%r14
  jne    L39
L2:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: Valor[%d][%d]: %d


assistant: ```c
void imp_val(int *val, int tam, int dim) {
  for (int i = 0; i < tam; i++) {
    for (int j = 0; j < dim; j++) {
      if ((i + j) % 2 == 0) {
        printf("Valor[%d][%d]: %d\n", i, j, *(val + i + j * tam));
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<imp_val>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  test   %esi,%esi
  jle    L13
  mov    %edx,%r14d
  test   %edx,%edx
  jle    L13
  movslq %esi,%rax
  mov    %esi,%r13d
  xor    %r15d,%r15d
  mov    %rax,0x18(%rsp)
L63:
  mov    %r15d,0xc(%rsp)
  mov    %r15d,%r12d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  jmp    L65
  xchg   %ax,%ax
L31:
  add    $0x1,%ebx
  add    %r13d,%ebp
  cmp    %ebx,%r14d
  je     L57
L65:
  lea    (%rbx,%r12,1),%eax
  test   $0x1,%al
  jne    L31
  mov    0x10(%rsp),%rdx
  movslq %ebp,%rax
  mov    0xc(%rsp),%esi
  lea    D0(%rip),%rdi
  add    %r15,%rax
  add    %r13d,%ebp
  mov    (%rdx,%rax,4),%ecx
  mov    %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r14d
  jne    L65
L57:
  add    $0x1,%r15
  cmp    %r15,0x18(%rsp)
  jne    L63
L13:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: Valor[%d][%d]: %d


assistant: ```c
void imp_val(int *val, int tam, int dim) {
  for (int i = 0; i < tam; i++) {
    for (int j = 0; j < dim; j++) {
      if ((i + j) % 2 == 0) {
        printf("Valor[%d][%d]: %d\n", i, j, *(val + i + j * tam));
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sleep_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <select@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tv;
  tv.tv_sec = nusecs / 1000000;
  tv.tv_usec = nusecs % 1000000;
  (void)select(0, NULL, NULL, NULL, &tv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sleep_us>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  mov    %eax,(%rsp)
  imul   $0xf4240,%eax,%eax
  sub    %eax,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <select@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tv;
  tv.tv_sec = nusecs / 1000000;
  tv.tv_usec = nusecs % 1000000;
  (void)select(0, NULL, NULL, NULL, &tv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sleep_us>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  mov    %rsp,%r8
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  mov    %eax,(%rsp)
  imul   $0xf4240,%eax,%eax
  sub    %eax,%edi
  mov    %edi,0x4(%rsp)
  xor    %edi,%edi
  call   <select@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tv;
  tv.tv_sec = nusecs / 1000000;
  tv.tv_usec = nusecs % 1000000;
  (void)select(0, NULL, NULL, NULL, &tv);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sleep_us>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  mov    %rsp,%r8
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  imul   $0xf4240,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  xor    %edx,%edx
  movd   %edi,%xmm1
  xor    %edi,%edi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <select@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tv;
  tv.tv_sec = nusecs / 1000000;
  tv.tv_usec = nusecs % 1000000;
  (void)select(0, NULL, NULL, NULL, &tv);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<x35_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x1,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x35_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x35_setup>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x1,%edx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x35_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<x35_setup>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x35_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<x35_setup>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D1(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x35_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UnsafePrint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string

tool: D5: %d


assistant: ```c
void UnsafePrint(const char *string, int integer) {
COFLO_NOT_THREADSAFE:
  printf(string);
  printf("%d\n", integer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UnsafePrint>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
void UnsafePrint(const char *string, int integer) {
COFLO_NOT_THREADSAFE:
  printf(string);
  printf("%d\n", integer);
}
```
user: What is the c source code of the assembly code below:

```asm
<UnsafePrint>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: %d


assistant: ```c
void UnsafePrint(const char *string, int integer) {
COFLO_NOT_THREADSAFE:
  printf(string);
  printf("%d\n", integer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UnsafePrint>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d


assistant: ```c
void UnsafePrint(const char *string, int integer) {
COFLO_NOT_THREADSAFE:
  printf(string);
  printf("%d\n", integer);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strtrimr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strtriml@plt>
  leave
  ret
```

assistant: ```c
char *strtrim(char *pstr) {
  char *p;
  p = strtrimr(pstr);
  return strtriml(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtrim>:
  endbr64
  sub    $0x8,%rsp
  call   <strtrimr@plt>
  mov    %rax,%rdi
  call   <strtriml@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *strtrim(char *pstr) {
  char *p;
  p = strtrimr(pstr);
  return strtriml(p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtrim>:
  endbr64
  sub    $0x8,%rsp
  call   <strtrimr@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <strtriml@plt>
```

assistant: ```c
char *strtrim(char *pstr) {
  char *p;
  p = strtrimr(pstr);
  return strtriml(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rcc_enableperipherals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <rcc_enableahb@plt>
  mov    $0x0,%eax
  call   <rcc_enableapb2@plt>
  mov    $0x0,%eax
  call   <rcc_enableapb1@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rcc_enableperipherals(void) {
  rcc_enableahb();
  rcc_enableapb2();
  rcc_enableapb1();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rcc_enableperipherals>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rcc_enableahb@plt>
  mov    $0x0,%eax
  call   <rcc_enableapb2@plt>
  mov    $0x0,%eax
  call   <rcc_enableapb1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void rcc_enableperipherals(void) {
  rcc_enableahb();
  rcc_enableapb2();
  rcc_enableapb1();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rcc_enableperipherals>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rcc_enableahb@plt>
  xor    %eax,%eax
  call   <rcc_enableapb2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <rcc_enableapb1@plt>
```

assistant: ```c
void rcc_enableperipherals(void) {
  rcc_enableahb();
  rcc_enableapb2();
  rcc_enableapb1();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rcc_enableperipherals>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rcc_enableahb@plt>
  xor    %eax,%eax
  call   <rcc_enableapb2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <rcc_enableapb1@plt>
```

assistant: ```c
void rcc_enableperipherals(void) {
  rcc_enableahb();
  rcc_enableapb2();
  rcc_enableapb1();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_vsub_i16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x7,-0x4(%rbp)
  jle    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_vsub_i16(int16_t *dest, int16_t *a, int16_t *b) {
  int i;
  for (i = 0; i < 8; i++) {
    dest[i] = a[i] - b[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_vsub_i16>:
  endbr64
  mov    $0x0,%eax
L4:
  mov    (%rsi,%rax,1),%rcx
  sub    (%rdx,%rax,1),%rcx
  mov    %rcx,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x40,%rax
  jne    L4
  ret
```

assistant: ```c
void test_vsub_i16(int16_t *dest, int16_t *a, int16_t *b) {
  int i;
  for (i = 0; i < 8; i++) {
    dest[i] = a[i] - b[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_vsub_i16>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    (%rsi,%rax,1),%rcx
  sub    (%rdx,%rax,1),%rcx
  mov    %rcx,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x40,%rax
  jne    L8
  ret
```

assistant: ```c
void test_vsub_i16(int16_t *dest, int16_t *a, int16_t *b) {
  int i;
  for (i = 0; i < 8; i++) {
    dest[i] = a[i] - b[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_vsub_i16>:
  endbr64
  lea    0x8(%rdx),%rcx
  mov    %rdi,%rax
  cmp    %rcx,%rdi
  je     L6
  lea    0x8(%rsi),%rcx
  cmp    %rcx,%rdi
  je     L6
  movdqu (%rsi),%xmm0
  movdqu (%rdx),%xmm2
  psubq  %xmm2,%xmm0
  movups %xmm0,(%rdi)
  movdqu 0x10(%rsi),%xmm0
  movdqu 0x10(%rdx),%xmm3
  psubq  %xmm3,%xmm0
  movups %xmm0,0x10(%rdi)
  movdqu 0x20(%rsi),%xmm0
  movdqu 0x20(%rdx),%xmm4
  psubq  %xmm4,%xmm0
  movups %xmm0,0x20(%rdi)
  movdqu 0x30(%rsi),%xmm0
  movdqu 0x30(%rdx),%xmm1
  psubq  %xmm1,%xmm0
  movups %xmm0,0x30(%rdi)
  ret
  nop
L6:
  mov    (%rsi),%rcx
  sub    (%rdx),%rcx
  mov    %rcx,(%rax)
  mov    0x8(%rsi),%rcx
  sub    0x8(%rdx),%rcx
  mov    %rcx,0x8(%rax)
  mov    0x10(%rsi),%rcx
  sub    0x10(%rdx),%rcx
  mov    %rcx,0x10(%rax)
  mov    0x18(%rsi),%rcx
  sub    0x18(%rdx),%rcx
  mov    %rcx,0x18(%rax)
  mov    0x20(%rsi),%rcx
  sub    0x20(%rdx),%rcx
  mov    %rcx,0x20(%rax)
  mov    0x28(%rsi),%rcx
  sub    0x28(%rdx),%rcx
  mov    %rcx,0x28(%rax)
  mov    0x30(%rsi),%rcx
  sub    0x30(%rdx),%rcx
  mov    %rcx,0x30(%rax)
  mov    0x38(%rsi),%rcx
  sub    0x38(%rdx),%rcx
  mov    %rcx,0x38(%rax)
  ret
```

assistant: ```c
void test_vsub_i16(int16_t *dest, int16_t *a, int16_t *b) {
  int i;
  for (i = 0; i < 8; i++) {
    dest[i] = a[i] - b[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unpack_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int unpack_byte(int jb, int index) {
  int shift = (index - 1) * 8;
  return (jb >> shift) & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unpack_byte>:
  endbr64
  lea    -0x8(,%rsi,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
int unpack_byte(int jb, int index) {
  int shift = (index - 1) * 8;
  return (jb >> shift) & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<unpack_byte>:
  endbr64
  lea    -0x8(,%rsi,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
int unpack_byte(int jb, int index) {
  int shift = (index - 1) * 8;
  return (jb >> shift) & 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unpack_byte>:
  endbr64
  lea    -0x8(,%rsi,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
int unpack_byte(int jb, int index) {
  int shift = (index - 1) * 8;
  return (jb >> shift) & 0xff;
}
```