ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_vl_dsift_new_kernel>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    -0x4(,%rdi,8),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <vl_malloc@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  pxor   %xmm3,%xmm3
  cvtsi2ss %ebx,%xmm2
  mulss  D23(%rip),%xmm2
  movsd  (%rsp),%xmm0
  mov    %rax,%r13
  cvtsi2ss %r12d,%xmm1
  mov    $0x1,%ebx
  cvtsi2ss %ebp,%xmm3
  cvtsd2ss %xmm0,%xmm0
  sub    %ebp,%ebx
  subss  %xmm2,%xmm1
  mulss  %xmm3,%xmm0
  mulss  %xmm3,%xmm1
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  cmp    %ebx,%ebp
  jle    L22
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%edi
  mov    %rax,%r14
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  D13(%rip),%xmm2
  cltd
  idiv   %ebp
  cvtsi2ss %eax,%xmm0
  subss  %xmm0,%xmm2
  test   %r12d,%r12d
  js     L27
  movss  D6(%rip),%xmm0
  pxor   %xmm1,%xmm1
  movss  %xmm2,(%rsp)
  cvtsi2ss %ebx,%xmm1
  subss  0x8(%rsp),%xmm1
  divss  0xc(%rsp),%xmm1
  mulss  %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  call   <expf@plt>
  movss  (%rsp),%xmm2
  mulss  %xmm0,%xmm2
L27:
  add    $0x1,%ebx
  lea    0x4(%r14),%rax
  movss  %xmm2,(%r14)
  cmp    %ebx,%ebp
  jne    L28
L22:
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D13
datatype: f32
name: extract_symbolic_data
arguments: data_tag: D6
datatype: byte[4]

tool: {"D23": [0x00,0x00,0x00,0x3f]}

tool: D13: 1

tool: {"D6": [0x00,0x00,0x00,0xbf]}

assistant: ```c
float *_vl_dsift_new_kernel(int binSize, int numBins, int binIndex, double windowSize) {
  int filtLen = 2 * binSize - 1;
  float *ker = (float *)vl_malloc(sizeof(float) * filtLen);
  float *kerIter = ker;
  float delta = binSize * (binIndex - 0.5F * (numBins - 1));
  float sigma = (float)binSize * (float)windowSize;
  int x;
  for (x = -binSize + 1; x <= +binSize - 1; ++x) {
    float z = (x - delta) / sigma;
    *kerIter++ = (1.0F - fabsf(x) / binSize) * ((binIndex >= 0) ? expf(-0.5F * z * z) : 1.0F);
  }
  return ker;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_vl_dsift_new_kernel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    -0x4(,%rdi,8),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <vl_malloc@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  pxor   %xmm3,%xmm3
  cvtsi2ss %ebx,%xmm2
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%ebx
  mov    %rax,%r12
  mulss  D26(%rip),%xmm2
  cvtsi2ss %r13d,%xmm1
  sub    %ebp,%ebx
  cvtsi2ss %ebp,%xmm3
  cvtsd2ss %xmm0,%xmm0
  subss  %xmm2,%xmm1
  mulss  %xmm3,%xmm0
  mulss  %xmm3,%xmm1
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0x4(%rsp)
  cmp    %ebx,%ebp
  jle    L13
  test   %r13d,%r13d
  jns    L27
  movss  D34(%rip),%xmm6
  mov    %rax,%r13
  movd   %xmm6,%r15d
  nopl   0x0(%rax)
L42:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fabsf@plt>
  pxor   %xmm1,%xmm1
  movd   %r15d,%xmm0
  mov    %r13,%rcx
  cltd
  add    $0x4,%r13
  idiv   %ebp
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
  cmp    %ebx,%ebp
  jne    L42
L13:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  movss  D34(%rip),%xmm7
  mov    %rax,%r14
  movd   %xmm7,%r15d
L19:
  mov    %ebx,%edi
  call   <fabsf@plt>
  movss  D32(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  subss  0x4(%rsp),%xmm1
  mov    %eax,%r13d
  add    $0x1,%ebx
  divss  0x8(%rsp),%xmm1
  mulss  %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  call   <expf@plt>
  mov    %r13d,%eax
  pxor   %xmm2,%xmm2
  mov    %r14,%rcx
  cltd
  movaps %xmm0,%xmm1
  movd   %r15d,%xmm0
  add    $0x4,%r14
  idiv   %ebp
  cvtsi2ss %eax,%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
  cmp    %ebx,%ebp
  jne    L19
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D34
type_guessed: f32
name: unpack_data
arguments: data_tag: D32
type_guessed: byte[4]

tool: {"D26": [0x00,0x00,0x00,0x3f]}

tool: D34: 1

tool: {"D32": [0x00,0x00,0x00,0xbf]}

assistant: ```c
float *_vl_dsift_new_kernel(int binSize, int numBins, int binIndex, double windowSize) {
  int filtLen = 2 * binSize - 1;
  float *ker = (float *)vl_malloc(sizeof(float) * filtLen);
  float *kerIter = ker;
  float delta = binSize * (binIndex - 0.5F * (numBins - 1));
  float sigma = (float)binSize * (float)windowSize;
  int x;
  for (x = -binSize + 1; x <= +binSize - 1; ++x) {
    float z = (x - delta) / sigma;
    *kerIter++ = (1.0F - fabsf(x) / binSize) * ((binIndex >= 0) ? expf(-0.5F * z * z) : 1.0F);
  }
  return ker;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L49:
  cmp    %rcx,%rsp
  je     L88
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L49
L88:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L50
  orq    $0x0,-0x8(%rsp,%rax,1)
L50:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L77
  mov    $0x0,%ebx
  lea    D28(%rip),%r13
L54:
  movslq %ebx,%r14
  lea    (%r12,%r14,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%r12,%r14,4),%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%ebx
  jl     L54
  test   %eax,%eax
  jle    L77
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L76:
  sub    $0x1,%eax
  cmp    %ebx,%eax
  je     L20
  cltq
  mov    (%r12,%rbx,4),%esi
  sub    (%r12,%rax,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L76
  jmp    L77
L20:
  movslq %ebx,%rdx
  mov    (%r12,%rdx,4),%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L77:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D28: %d

tool: D5: 
%d

assistant: ```c
int main() {
  int n, i = 0;
  scanf("%d", &n);
  int numbers[n];
  while (i < n) {
    scanf("%d", &numbers[i]);
    if (numbers[i] % 2 != 0) {
      i++;
    }
  }
  for (i = 0; i < n; i++) {
    if (i == n - 1) {
      printf("\n%d", numbers[i]);
      break;
    }
    printf("\n%d", numbers[i] - numbers[n - 1]);
    n--;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D19(%rip),%r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L106
L49:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L49
L106:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L108
L60:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  test   %ecx,%ecx
  jle    L44
  nopl   0x0(%rax)
L76:
  movslq %ebx,%r14
  mov    %r13,%rdi
  lea    (%r12,%r14,4),%rsi
  call   <scanf@plt>
  mov    (%r12,%r14,4),%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  mov    -0x2c(%rbp),%eax
  sbb    $0xffffffff,%ebx
  cmp    %eax,%ebx
  jl     L76
  test   %eax,%eax
  jle    L44
  xor    %ebx,%ebx
  lea    D3(%rip),%r13
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L77:
  cltq
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  cmp    %ebx,%eax
  jle    L44
L25:
  sub    $0x1,%eax
  mov    (%r12,%rbx,4),%esi
  cmp    %ebx,%eax
  jne    L77
  mov    %r13,%rdi
  call   <printf@plt>
L44:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L108:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L60
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D19: %d

tool: D3: 
%d

assistant: ```c
int main() {
  int n, i = 0;
  scanf("%d", &n);
  int numbers[n];
  while (i < n) {
    scanf("%d", &numbers[i]);
    if (numbers[i] % 2 != 0) {
      i++;
    }
  }
  for (i = 0; i < n; i++) {
    if (i == n - 1) {
      printf("\n%d", numbers[i]);
      break;
    }
    printf("\n%d", numbers[i] - numbers[n - 1]);
    n--;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D7(%rip),%r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L92
L76:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L76
L92:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L16
L82:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  test   %ecx,%ecx
  jle    L34
  nopl   0x0(%rax)
L84:
  movslq %ebx,%r14
  mov    %r13,%rdi
  lea    (%r12,%r14,4),%rsi
  call   <scanf@plt>
  mov    (%r12,%r14,4),%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  mov    -0x2c(%rbp),%eax
  sbb    $0xffffffff,%ebx
  cmp    %eax,%ebx
  jl     L84
  test   %eax,%eax
  jle    L34
  xor    %ebx,%ebx
  lea    D11(%rip),%r13
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L0:
  cltq
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  cmp    %ebx,%eax
  jle    L34
L28:
  sub    $0x1,%eax
  mov    (%r12,%rbx,4),%esi
  cmp    %ebx,%eax
  jne    L0
  mov    %r13,%rdi
  call   <printf@plt>
L34:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L16:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L82
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string

tool: D7: %d

tool: D11: 
%d

assistant: ```c
int main() {
  int n, i = 0;
  scanf("%d", &n);
  int numbers[n];
  while (i < n) {
    scanf("%d", &numbers[i]);
    if (numbers[i] % 2 != 0) {
      i++;
    }
  }
  for (i = 0; i < n; i++) {
    if (i == n - 1) {
      printf("\n%d", numbers[i]);
      break;
    }
    printf("\n%d", numbers[i] - numbers[n - 1]);
    n--;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<est_base64_encode>:
  endbr64
  mov    %rdx,%r10
  test   %esi,%esi
  jle    L24
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r9d
  mov    $0x2,%ebx
  mov    $0x1,%r8d
  mov    $0x0,%eax
  mov    $0x0,%r13d
  lea    D1(%rip),%r12
  jmp    L63
L20:
  mov    %ebx,-0x4(%rsp)
  mov    %r13d,%r11d
  cmp    %ebx,%r9d
  jle    L5
  movzbl 0x2(%rsi),%r11d
L5:
  movslq %eax,%rbp
  mov    %edx,%esi
  sar    $0x2,%esi
  movslq %esi,%rsi
  movzbl (%r12,%rsi,1),%esi
  mov    %sil,(%r10,%rbp,1)
  lea    0x2(%rax),%esi
  lea    0x1(%rax),%ebp
  movslq %ebp,%rbp
  shl    $0x4,%edx
  and    $0x30,%edx
  mov    %ecx,%r15d
  sar    $0x4,%r15d
  or     %r15d,%edx
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%edx
  mov    %dl,(%r10,%rbp,1)
  cmp    %r14d,%r9d
  jle    L85
  movslq %esi,%rsi
  shl    $0x2,%ecx
  and    $0x3c,%ecx
  mov    %r11d,%edx
  sar    $0x6,%edx
  or     %edx,%ecx
  movslq %ecx,%rcx
  movzbl (%r12,%rcx,1),%edx
  mov    %dl,(%r10,%rsi,1)
  lea    0x3(%rax),%esi
L85:
  mov    %esi,%eax
  cmp    -0x4(%rsp),%r9d
  jle    L87
  lea    0x1(%rsi),%eax
  movslq %esi,%rsi
  and    $0x3f,%r11d
  movzbl (%r12,%r11,1),%edx
  mov    %dl,(%r10,%rsi,1)
L87:
  add    $0x3,%rdi
  lea    0x3(%r8),%edx
  add    $0x3,%ebx
  add    $0x2,%r8d
  cmp    %r8d,%r9d
  jle    L28
  mov    %edx,%r8d
L63:
  mov    %rdi,%rsi
  movzbl (%rdi),%edx
  mov    %r8d,%r14d
  mov    %r13d,%ecx
  cmp    %r8d,%r9d
  jle    L20
  movzbl 0x1(%rdi),%ecx
  jmp    L20
L28:
  test   $0x3,%al
  je     L93
  add    $0x1,%eax
  movslq %eax,%rdx
L35:
  mov    %edx,%eax
  movb   $0x3d,-0x1(%r10,%rdx,1)
  mov    %edx,%ecx
  and    $0x3,%ecx
  add    $0x1,%rdx
  test   %ecx,%ecx
  jne    L35
L93:
  cltq
  movb   $0x0,(%r10,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    $0x0,%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void est_base64_encode(const unsigned char *src, int src_len, char *dst) {
  static const char *b64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int i, j, a, b, c;
  for (i = j = 0; i < src_len; i += 3) {
    a = src[i];
    b = i + 1 >= src_len ? 0 : src[i + 1];
    c = i + 2 >= src_len ? 0 : src[i + 2];
    dst[j++] = b64[a >> 2];
    dst[j++] = b64[((a & 3) << 4) | (b >> 4)];
    if (i + 1 < src_len) {
      dst[j++] = b64[(b & 15) << 2 | (c >> 6)];
    }
    if (i + 2 < src_len) {
      dst[j++] = b64[c & 63];
    }
  }
  while (j % 4 != 0) {
    dst[j++] = '=';
  }
  dst[j++] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<est_base64_encode>:
  endbr64
  mov    %rdx,%r9
  test   %esi,%esi
  jle    L42
  push   %r13
  mov    %esi,%r8d
  mov    $0x2,%r11d
  mov    $0x1,%esi
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  jmp    L56
  xchg   %ax,%ax
L47:
  shl    $0x2,%ecx
  mov    %r10d,%edx
  movslq %r12d,%r12
  add    $0x3,%eax
  sar    $0x6,%edx
  and    $0x3c,%ecx
  or     %edx,%ecx
  movslq %ecx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%edx
  mov    %dl,(%r9,%r12,1)
L0:
  cmp    %r11d,%r8d
  jle    L1
  and    $0x3f,%r10d
  movslq %eax,%rdx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%r10,1),%ecx
  mov    %cl,(%r9,%rdx,1)
L1:
  lea    0x3(%rsi),%edx
  add    $0x2,%esi
  add    $0x3,%rdi
  add    $0x3,%r11d
  cmp    %esi,%r8d
  jle    L13
  mov    %edx,%esi
L56:
  movzbl (%rdi),%edx
  cmp    %esi,%r8d
  jle    L64
  movzbl 0x1(%rdi),%ecx
  mov    %ecx,%r13d
  sar    $0x4,%r13d
L53:
  xor    %r10d,%r10d
  cmp    %r11d,%r8d
  jle    L93
  movzbl 0x2(%rdi),%r10d
L93:
  mov    %edx,%ebx
  shl    $0x4,%edx
  movslq %eax,%r12
  sar    $0x2,%ebx
  and    $0x30,%edx
  movslq %ebx,%rbx
  or     %r13d,%edx
  movzbl 0x0(%rbp,%rbx,1),%ebx
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%edx
  mov    %bl,(%r9,%r12,1)
  lea    0x1(%rax),%ebx
  lea    0x2(%rax),%r12d
  movslq %ebx,%rbx
  mov    %dl,(%r9,%rbx,1)
  cmp    %esi,%r8d
  jg     L47
  mov    %r12d,%eax
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L64:
  xor    %r13d,%r13d
  xor    %ecx,%ecx
  jmp    L53
  nop
L13:
  test   $0x3,%al
  je     L81
  add    $0x1,%eax
  cltq
  nopl   0x0(%rax)
L52:
  mov    %eax,%edx
  movb   $0x3d,-0x1(%r9,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  and    $0x3,%edx
  test   %edx,%edx
  jne    L52
  add    %rcx,%r9
L78:
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r9)
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L42:
  movb   $0x0,(%rdx)
  ret
L81:
  cltq
  add    %rax,%r9
  jmp    L78
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void est_base64_encode(const unsigned char *src, int src_len, char *dst) {
  static const char *b64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int i, j, a, b, c;
  for (i = j = 0; i < src_len; i += 3) {
    a = src[i];
    b = i + 1 >= src_len ? 0 : src[i + 1];
    c = i + 2 >= src_len ? 0 : src[i + 2];
    dst[j++] = b64[a >> 2];
    dst[j++] = b64[((a & 3) << 4) | (b >> 4)];
    if (i + 1 < src_len) {
      dst[j++] = b64[(b & 15) << 2 | (c >> 6)];
    }
    if (i + 2 < src_len) {
      dst[j++] = b64[c & 63];
    }
  }
  while (j % 4 != 0) {
    dst[j++] = '=';
  }
  dst[j++] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<est_base64_encode>:
  endbr64
  mov    %rdx,%r9
  test   %esi,%esi
  jle    L72
  push   %r13
  mov    %esi,%r8d
  mov    $0x2,%r11d
  mov    $0x1,%esi
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  jmp    L21
  xchg   %ax,%ax
L50:
  shl    $0x2,%ecx
  mov    %r10d,%edx
  movslq %r12d,%r12
  add    $0x3,%eax
  sar    $0x6,%edx
  and    $0x3c,%ecx
  or     %edx,%ecx
  movslq %ecx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%edx
  mov    %dl,(%r9,%r12,1)
L46:
  cmp    %r11d,%r8d
  jle    L61
  and    $0x3f,%r10d
  movslq %eax,%rdx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%r10,1),%ecx
  mov    %cl,(%r9,%rdx,1)
L61:
  lea    0x3(%rsi),%edx
  add    $0x2,%esi
  add    $0x3,%rdi
  add    $0x3,%r11d
  cmp    %esi,%r8d
  jle    L52
  mov    %edx,%esi
L21:
  movzbl (%rdi),%edx
  cmp    %esi,%r8d
  jle    L31
  movzbl 0x1(%rdi),%ecx
  mov    %ecx,%r13d
  sar    $0x4,%r13d
L11:
  xor    %r10d,%r10d
  cmp    %r11d,%r8d
  jle    L79
  movzbl 0x2(%rdi),%r10d
L79:
  mov    %edx,%ebx
  shl    $0x4,%edx
  movslq %eax,%r12
  sar    $0x2,%ebx
  and    $0x30,%edx
  movslq %ebx,%rbx
  or     %r13d,%edx
  movzbl 0x0(%rbp,%rbx,1),%ebx
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%edx
  mov    %bl,(%r9,%r12,1)
  lea    0x1(%rax),%ebx
  lea    0x2(%rax),%r12d
  movslq %ebx,%rbx
  mov    %dl,(%r9,%rbx,1)
  cmp    %esi,%r8d
  jg     L50
  mov    %r12d,%eax
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %r13d,%r13d
  xor    %ecx,%ecx
  jmp    L11
  nop
L52:
  test   $0x3,%al
  je     L59
  add    $0x1,%eax
  cltq
  nopl   0x0(%rax)
L18:
  mov    %eax,%edx
  movb   $0x3d,-0x1(%r9,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  and    $0x3,%edx
  test   %edx,%edx
  jne    L18
  add    %rcx,%r9
L106:
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r9)
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L72:
  movb   $0x0,(%rdx)
  ret
L59:
  cltq
  add    %rax,%r9
  jmp    L106
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void est_base64_encode(const unsigned char *src, int src_len, char *dst) {
  static const char *b64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int i, j, a, b, c;
  for (i = j = 0; i < src_len; i += 3) {
    a = src[i];
    b = i + 1 >= src_len ? 0 : src[i + 1];
    c = i + 2 >= src_len ? 0 : src[i + 2];
    dst[j++] = b64[a >> 2];
    dst[j++] = b64[((a & 3) << 4) | (b >> 4)];
    if (i + 1 < src_len) {
      dst[j++] = b64[(b & 15) << 2 | (c >> 6)];
    }
    if (i + 2 < src_len) {
      dst[j++] = b64[c & 63];
    }
  }
  while (j % 4 != 0) {
    dst[j++] = '=';
  }
  dst[j++] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<env_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L6
L48:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x8(%rbp),%rax
  jmp    L6
L22:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L48
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
char *env_name(char *env) {
  int i;
  char *ret;
  i = 0;
  if ((ret = malloc(sizeof(char) * my_strlen(env))) == NULL)
    return (NULL);
  while (env[i] != '=') {
    ret[i] = env[i];
    i++;
    if (env[i] == '\0')
      return (ret);
  }
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<env_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    $0x0,%edx
L18:
  movzbl (%rbx,%rdx,1),%ecx
  cmp    $0x3d,%cl
  je     L6
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmpb   $0x0,(%rbx,%rdx,1)
  jne    L18
L6:
  pop    %rbx
  ret
```

assistant: ```c
char *env_name(char *env) {
  int i;
  char *ret;
  i = 0;
  if ((ret = malloc(sizeof(char) * my_strlen(env))) == NULL)
    return (NULL);
  while (env[i] != '=') {
    ret[i] = env[i];
    i++;
    if (env[i] == '\0')
      return (ret);
  }
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<env_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L38
  movzbl (%rbx),%edx
  xor    %ecx,%ecx
  jmp    L24
L16:
  mov    %dl,(%rax,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%edx
  test   %dl,%dl
  je     L38
L24:
  cmp    $0x3d,%dl
  jne    L16
L38:
  pop    %rbx
  ret
```

assistant: ```c
char *env_name(char *env) {
  int i;
  char *ret;
  i = 0;
  if ((ret = malloc(sizeof(char) * my_strlen(env))) == NULL)
    return (NULL);
  while (env[i] != '=') {
    ret[i] = env[i];
    i++;
    if (env[i] == '\0')
      return (ret);
  }
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<env_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L23
  xor    %edx,%edx
  jmp    L34
  nopl   (%rax)
L26:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmpb   $0x0,(%rbx,%rdx,1)
  je     L23
L34:
  movzbl (%rbx,%rdx,1),%ecx
  cmp    $0x3d,%cl
  jne    L26
L23:
  pop    %rbx
  ret
```

assistant: ```c
char *env_name(char *env) {
  int i;
  char *ret;
  i = 0;
  if ((ret = malloc(sizeof(char) * my_strlen(env))) == NULL)
    return (NULL);
  while (env[i] != '=') {
    ret[i] = env[i];
    i++;
    if (env[i] == '\0')
      return (ret);
  }
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scanChild>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scan@plt>
L1:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: /Users/tomoaki/Develop.localized/Sebastian/plugin

assistant: ```c
void scanChild() {
  int i;
  scan("/Users/tomoaki/Develop.localized/Sebastian/plugin");
  for (;;)
    sleep(1);
  exit(EXIT_SUCCESS);
}
```