ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<ckAsmGetCr3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %cr3,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ckAsmGetCr3(void) {
  uint32_t ret;
  __asm__ __volatile__("mov %%cr3, %0 " : "=r"(ret));
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ckAsmGetCr3>:
  endbr64
  mov    %cr3,%rax
  ret
```

assistant: ```c
uint32_t ckAsmGetCr3(void) {
  uint32_t ret;
  __asm__ __volatile__("mov %%cr3, %0 " : "=r"(ret));
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ckAsmGetCr3>:
  endbr64
  mov    %cr3,%rax
  ret
```

assistant: ```c
uint32_t ckAsmGetCr3(void) {
  uint32_t ret;
  __asm__ __volatile__("mov %%cr3, %0 " : "=r"(ret));
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<ckAsmGetCr3>:
  endbr64
  mov    %cr3,%rax
  ret
```

assistant: ```c
uint32_t ckAsmGetCr3(void) {
  uint32_t ret;
  __asm__ __volatile__("mov %%cr3, %0 " : "=r"(ret));
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<monikor_log_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd8(%rbp),%rdx
  mov    -0xc0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_format_mod_log_message@plt>
  mov    %rax,-0xb8(%rbp)
  cmpq   $0x0,-0xb8(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L20
L14:
  mov    -0xc0(%rbp),%edx
  mov    -0xb8(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <monikor_vlog@plt>
  mov    %eax,-0xbc(%rbp)
  mov    -0xc0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xbc(%rbp),%eax
L20:
  leave
  ret
```

assistant: ```c
int monikor_log_mod(int prio, const char *mod_name, const char *message, ...) {
  int ret;
  va_list ap;
  char *full_msg;
  va_start(ap, message);
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  va_end(ap);
  free(full_msg);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<monikor_log_mod>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <_format_mod_log_message@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbx
  mov    %ebp,%edx
  mov    %rax,%rsi
  mov    %r12d,%edi
  call   <monikor_vlog@plt>
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <free@plt>
L0:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    $0xffffffff,%r12d
  jmp    L0
```

assistant: ```c
int monikor_log_mod(int prio, const char *mod_name, const char *message, ...) {
  int ret;
  va_list ap;
  char *full_msg;
  va_start(ap, message);
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  va_end(ap);
  free(full_msg);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<monikor_log_mod>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <_format_mod_log_message@plt>
  test   %rax,%rax
  je     L18
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %r14d,%edi
  mov    %rax,%rbp
  call   <monikor_vlog@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L10:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    $0xffffffff,%r13d
  jmp    L10
```

assistant: ```c
int monikor_log_mod(int prio, const char *mod_name, const char *message, ...) {
  int ret;
  va_list ap;
  char *full_msg;
  va_start(ap, message);
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  va_end(ap);
  free(full_msg);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<monikor_log_mod>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <_format_mod_log_message@plt>
  test   %rax,%rax
  je     L17
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %r14d,%edi
  mov    %rax,%rbp
  call   <monikor_vlog@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L5:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0xffffffff,%r13d
  jmp    L5
```

assistant: ```c
int monikor_log_mod(int prio, const char *mod_name, const char *message, ...) {
  int ret;
  va_list ap;
  char *full_msg;
  va_start(ap, message);
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  va_end(ap);
  free(full_msg);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testTortureExecute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void testTortureExecute(void) {
  foo(0, 0);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void testTortureExecute(void) {
  foo(0, 0);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<testTortureExecute>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
void testTortureExecute(void) {
  foo(0, 0);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<testTortureExecute>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
void testTortureExecute(void) {
  foo(0, 0);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <bplus_tree_normal_test@plt>
  mov    $0x0,%eax
  call   <bplus_tree_abnormal_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  bplus_tree_normal_test();
  bplus_tree_abnormal_test();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bplus_tree_normal_test@plt>
  mov    $0x0,%eax
  call   <bplus_tree_abnormal_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bplus_tree_normal_test();
  bplus_tree_abnormal_test();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bplus_tree_normal_test@plt>
  xor    %eax,%eax
  call   <bplus_tree_abnormal_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bplus_tree_normal_test();
  bplus_tree_abnormal_test();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bplus_tree_normal_test@plt>
  xor    %eax,%eax
  call   <bplus_tree_abnormal_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bplus_tree_normal_test();
  bplus_tree_abnormal_test();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<macro2len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0xe,%eax
  cmp    $0x54,%eax
  ja     L376
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D6(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0x11,%eax
  jmp    L399
  mov    $0xf,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0x10,%eax
  jmp    L399
  mov    $0x10,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0x10,%eax
  jmp    L399
  mov    $0x6,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0xe,%eax
  jmp    L399
  mov    $0x20,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0x10,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0x6,%eax
  jmp    L399
  mov    $0x10,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xc,%eax
  jmp    L399
  mov    $0xa,%eax
  jmp    L399
L376:
  nop
  mov    $0x0,%eax
L399:
  pop    %rbp
  ret
```

assistant: ```c
size_t macro2len(int macro) {
  switch (macro) {
  case 14:
    return 12;
  case 53:
    return 12;
  case 15:
    return 12;
  case 54:
    return 12;
  case 16:
    return 12;
  case 58:
    return 12;
  case 59:
    return 12;
  case 17:
    return 12;
  case 18:
    return 10;
  case 64:
    return 10;
  case 65:
    return 12;
  case 19:
    return 12;
  case 69:
    return 12;
  case 68:
    return 10;
  case 20:
    return 17;
  case 21:
    return 15;
  case 23:
    return 12;
  case 25:
    return 10;
  case 96:
    return 16;
  case 26:
    return 16;
  case 28:
    return 10;
  case 30:
    return 16;
  case 71:
    return 6;
  case 32:
    return 10;
  case 72:
    return 12;
  case 98:
    return 10;
  case 33:
    return 14;
  case 35:
    return 32;
  case 77:
    return 12;
  case 78:
    return 12;
  case 79:
    return 12;
  case 81:
    return 16;
  case 82:
    return 12;
  case 87:
    return 12;
  case 88:
    return 12;
  case 91:
    return 6;
  case 90:
    return 16;
  case 92:
    return 10;
  case 38:
    return 12;
  case 39:
    return 12;
  case 40:
    return 10;
  default:
    break;
  };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<macro2len>:
  endbr64
  sub    $0xe,%edi
  xor    %eax,%eax
  cmp    $0x54,%edi
  ja     L2
  lea    D8(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L2:
  ret
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: 


assistant: ```c
size_t macro2len(int macro) {
  switch (macro) {
  case 14:
    return 12;
  case 53:
    return 12;
  case 15:
    return 12;
  case 54:
    return 12;
  case 16:
    return 12;
  case 58:
    return 12;
  case 59:
    return 12;
  case 17:
    return 12;
  case 18:
    return 10;
  case 64:
    return 10;
  case 65:
    return 12;
  case 19:
    return 12;
  case 69:
    return 12;
  case 68:
    return 10;
  case 20:
    return 17;
  case 21:
    return 15;
  case 23:
    return 12;
  case 25:
    return 10;
  case 96:
    return 16;
  case 26:
    return 16;
  case 28:
    return 10;
  case 30:
    return 16;
  case 71:
    return 6;
  case 32:
    return 10;
  case 72:
    return 12;
  case 98:
    return 10;
  case 33:
    return 14;
  case 35:
    return 32;
  case 77:
    return 12;
  case 78:
    return 12;
  case 79:
    return 12;
  case 81:
    return 16;
  case 82:
    return 12;
  case 87:
    return 12;
  case 88:
    return 12;
  case 91:
    return 6;
  case 90:
    return 16;
  case 92:
    return 10;
  case 38:
    return 12;
  case 39:
    return 12;
  case 40:
    return 10;
  default:
    break;
  };
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<macro2len>:
  endbr64
  sub    $0xe,%edi
  xor    %eax,%eax
  cmp    $0x54,%edi
  ja     L0
  lea    D1(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: 


assistant: ```c
size_t macro2len(int macro) {
  switch (macro) {
  case 14:
    return 12;
  case 53:
    return 12;
  case 15:
    return 12;
  case 54:
    return 12;
  case 16:
    return 12;
  case 58:
    return 12;
  case 59:
    return 12;
  case 17:
    return 12;
  case 18:
    return 10;
  case 64:
    return 10;
  case 65:
    return 12;
  case 19:
    return 12;
  case 69:
    return 12;
  case 68:
    return 10;
  case 20:
    return 17;
  case 21:
    return 15;
  case 23:
    return 12;
  case 25:
    return 10;
  case 96:
    return 16;
  case 26:
    return 16;
  case 28:
    return 10;
  case 30:
    return 16;
  case 71:
    return 6;
  case 32:
    return 10;
  case 72:
    return 12;
  case 98:
    return 10;
  case 33:
    return 14;
  case 35:
    return 32;
  case 77:
    return 12;
  case 78:
    return 12;
  case 79:
    return 12;
  case 81:
    return 16;
  case 82:
    return 12;
  case 87:
    return 12;
  case 88:
    return 12;
  case 91:
    return 6;
  case 90:
    return 16;
  case 92:
    return 10;
  case 38:
    return 12;
  case 39:
    return 12;
  case 40:
    return 10;
  default:
    break;
  };
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  movabs $0x3af83a70f,%rsi
  lea    D115(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%edx
  mov    $0x2,%esi
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6fd,%ecx
  mov    $0xe,%edx
  mov    $0x7,%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D76(%rip),%xmm0
  call   <atan@plt>
  shl    $0x2,%eax
  pxor   %xmm6,%xmm6
  cvtsi2sd %eax,%xmm6
  movapd %xmm6,%xmm5
  movq   %xmm6,%rbx
  movapd %xmm6,%xmm4
  movapd %xmm6,%xmm3
  movapd %xmm6,%xmm2
  movapd %xmm6,%xmm1
  movapd %xmm6,%xmm0
  lea    D11(%rip),%rdi
  mov    $0x6,%eax
  call   <printf@plt>
  movq   %rbx,%xmm5
  movq   %rbx,%xmm4
  movq   %rbx,%xmm3
  movq   %rbx,%xmm2
  movq   %rbx,%xmm1
  movq   %rbx,%xmm0
  lea    D73(%rip),%rdi
  mov    $0x6,%eax
  call   <printf@plt>
  movsd  D54(%rip),%xmm0
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  lea    D117(%rip),%rdi
  mov    $0x5,%eax
  call   <printf@plt>
  lea    D20(%rip),%rbx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D115
data_type: string
name: extract_symbolic_data
arguments: label: D67
data_type: string
name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D33
data_type: string
name: extract_symbolic_data
arguments: label: D76
data_type: f64
name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D73
data_type: string
name: extract_symbolic_data
arguments: label: D54
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D117
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string
name: extract_symbolic_data
arguments: label: D14
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D115: %ld

tool: D67: 
%2d
%2d*


tool: D8: %3%


tool: D33: %.2d/%.2d/%.4d


tool: D76: 1

tool: D11: %.0f %.1f %.2f %.3f %.6f %.10f


tool: D73: %.0e %.1e %.2e %.10e


tool: {"D54": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0x0a,0x40]}

tool: D117: %.g %.1g %.2g %.4g %.8g


tool: D20: name.xls

tool: D14: ...%.14s...


tool: D2: ...%14.14s...

assistant: ```c
int main() {
  printf("%ld", 15829542671);
  printf("\n%2d\n%2d*\n", 2, 100);
  printf("%3%\n");
  printf("%.2d/%.2d/%.4d\n", 7, 14, 1789);
  double pi;
  pi = 4 * atan(1.0);
  printf("%.0f %.1f %.2f %.3f %.6f %.10f\n", pi, pi, pi, pi, pi, pi);
  printf("%.0e %.1e %.2e %.10e\n", pi, pi, pi, pi, pi, pi);
  printf("%.g %.1g %.2g %.4g %.8g\n", 10 / 3.0, 10 / 3.0, 10 / 3.0, 10 / 3.0, 10 / 3.0);
  char *name = "name.xls";
  printf("...%.14s...\n", name);
  printf("...%14.14s...", name);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D99(%rip),%rdi
  xor    %eax,%eax
  movabs $0x3af83a70f,%rsi
  lea    D48(%rip),%rbp
  sub    $0x10,%rsp
  call   <printf@plt>
  mov    $0x64,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  lea    D83(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6fd,%ecx
  xor    %eax,%eax
  mov    $0xe,%edx
  mov    $0x7,%esi
  lea    D50(%rip),%rdi
  call   <printf@plt>
  movsd  D18(%rip),%xmm0
  call   <atan@plt>
  pxor   %xmm1,%xmm1
  lea    D118(%rip),%rdi
  shl    $0x2,%eax
  cvtsi2sd %eax,%xmm1
  mov    $0x6,%eax
  movapd %xmm1,%xmm5
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm3
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x6,%eax
  lea    D85(%rip),%rdi
  movapd %xmm1,%xmm5
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  call   <printf@plt>
  movsd  D29(%rip),%xmm0
  mov    $0x5,%eax
  lea    D41(%rip),%rdi
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D82(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D99
datatype: string
name: disassemble_data
arguments: data_tag: D48
datatype: string
name: disassemble_data
arguments: data_tag: D83
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D50
datatype: string
name: disassemble_data
arguments: data_tag: D18
datatype: f64
name: disassemble_data
arguments: data_tag: D118
datatype: string
name: disassemble_data
arguments: data_tag: D85
datatype: string
name: disassemble_data
arguments: data_tag: D29
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D41
datatype: string
name: disassemble_data
arguments: data_tag: D82
datatype: string
name: disassemble_data
arguments: data_tag: D88
datatype: string

tool: D99: %ld

tool: D48: name.xls

tool: D83: 
%2d
%2d*


tool: D1: %3%


tool: D50: %.2d/%.2d/%.4d


tool: D18: 1

tool: D118: %.0f %.1f %.2f %.3f %.6f %.10f


tool: D85: %.0e %.1e %.2e %.10e


tool: {"D29": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0x0a,0x40]}

tool: D41: %.g %.1g %.2g %.4g %.8g


tool: D82: ...%.14s...


tool: D88: ...%14.14s...

assistant: ```c
int main() {
  printf("%ld", 15829542671);
  printf("\n%2d\n%2d*\n", 2, 100);
  printf("%3%\n");
  printf("%.2d/%.2d/%.4d\n", 7, 14, 1789);
  double pi;
  pi = 4 * atan(1.0);
  printf("%.0f %.1f %.2f %.3f %.6f %.10f\n", pi, pi, pi, pi, pi, pi);
  printf("%.0e %.1e %.2e %.10e\n", pi, pi, pi, pi, pi, pi);
  printf("%.g %.1g %.2g %.4g %.8g\n", 10 / 3.0, 10 / 3.0, 10 / 3.0, 10 / 3.0, 10 / 3.0);
  char *name = "name.xls";
  printf("...%.14s...\n", name);
  printf("...%14.14s...", name);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D94(%rip),%rdi
  xor    %eax,%eax
  movabs $0x3af83a70f,%rsi
  lea    D119(%rip),%rbp
  sub    $0x10,%rsp
  call   <printf@plt>
  mov    $0x64,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6fd,%ecx
  xor    %eax,%eax
  mov    $0xe,%edx
  mov    $0x7,%esi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  movsd  D1(%rip),%xmm0
  call   <atan@plt>
  pxor   %xmm1,%xmm1
  lea    D33(%rip),%rdi
  shl    $0x2,%eax
  cvtsi2sd %eax,%xmm1
  mov    $0x6,%eax
  movapd %xmm1,%xmm5
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm3
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x6,%eax
  lea    D15(%rip),%rdi
  movapd %xmm1,%xmm5
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  call   <printf@plt>
  movsd  D48(%rip),%xmm0
  mov    $0x5,%eax
  lea    D84(%rip),%rdi
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D83(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D94
type_infered: string
name: read_data
arguments: label: D119
type_infered: string
name: read_data
arguments: label: D31
type_infered: string
name: read_data
arguments: label: D79
type_infered: string
name: read_data
arguments: label: D66
type_infered: string
name: read_data
arguments: label: D1
type_infered: f64
name: read_data
arguments: label: D33
type_infered: string
name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D48
type_infered: byte[8]
name: read_data
arguments: label: D84
type_infered: string
name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D83
type_infered: string

tool: D94: %ld

tool: D119: name.xls

tool: D31: 
%2d
%2d*


tool: D79: %3%


tool: D66: %.2d/%.2d/%.4d


tool: D1: 1

tool: D33: %.0f %.1f %.2f %.3f %.6f %.10f


tool: D15: %.0e %.1e %.2e %.10e


tool: {"D48": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0x0a,0x40]}

tool: D84: %.g %.1g %.2g %.4g %.8g


tool: D4: ...%.14s...


tool: D83: ...%14.14s...

assistant: ```c
int main() {
  printf("%ld", 15829542671);
  printf("\n%2d\n%2d*\n", 2, 100);
  printf("%3%\n");
  printf("%.2d/%.2d/%.4d\n", 7, 14, 1789);
  double pi;
  pi = 4 * atan(1.0);
  printf("%.0f %.1f %.2f %.3f %.6f %.10f\n", pi, pi, pi, pi, pi, pi);
  printf("%.0e %.1e %.2e %.10e\n", pi, pi, pi, pi, pi, pi);
  printf("%.g %.1g %.2g %.4g %.8g\n", 10 / 3.0, 10 / 3.0, 10 / 3.0, 10 / 3.0, 10 / 3.0);
  char *name = "name.xls";
  printf("...%.14s...\n", name);
  printf("...%14.14s...", name);
  return 0;
}
```