ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_data_double>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x20(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L14
  movslq %edx,%rax
  shl    $0x3,%rax
  mov    %rax,0x10(%rsp)
  mov    %rdi,%r14
  add    %rax,%r14
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    -0x2(%rdx),%eax
  mov    %eax,0x24(%rsp)
  lea    0x8(%rdi),%rax
  mov    %rax,0x28(%rsp)
  lea    D13(%rip),%r12
  jmp    L52
L9:
  movslq %r15d,%rdx
  mov    0x18(%rsp),%rax
  lea    (%rax,%rdx,8),%rbx
  mov    0x24(%rsp),%eax
  add    %rdx,%rax
  mov    0x28(%rsp),%rcx
  lea    (%rcx,%rax,8),%rbp
L1:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L1
L57:
  movsd  -0x8(%r14),%xmm0
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    0x10(%rsp),%r14
  add    0xc(%rsp),%r15d
  cmp    %r13d,0x20(%rsp)
  je     L14
L52:
  cmpl   $0x1,0xc(%rsp)
  jg     L9
  jmp    L57
L14:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: string

tool: D13: %G 

tool: D11: %G

assistant: ```c
void print_data_double(double *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%G ", dat[i * M + j]);
    }
    printf("%G", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_data_double>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  test   %esi,%esi
  jle    L7
  movslq %edx,%r15
  mov    %rdi,%r12
  lea    D4(%rip),%rbp
  xor    %r13d,%r13d
  lea    0x0(,%r15,8),%rcx
  mov    %r15,%rax
  mov    %rcx,0x8(%rsp)
  sub    $0x2,%eax
  lea    0x8(%rdi,%rax,8),%rbx
  nopl   0x0(%rax)
L25:
  cmpl   $0x1,0x4(%rsp)
  mov    %r12,%r14
  jle    L28
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  (%r14),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r14
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L2
L28:
  movsd  -0x8(%r12,%r15,8),%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  add    %rax,%r12
  add    %rax,%rbx
  cmp    %r13d,(%rsp)
  jne    L25
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string

tool: D4: %G 

tool: D16: %G

assistant: ```c
void print_data_double(double *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%G ", dat[i * M + j]);
    }
    printf("%G", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_data_double>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  test   %esi,%esi
  jle    L13
  movslq %edx,%r15
  mov    %rdi,%r12
  lea    D16(%rip),%rbp
  xor    %r13d,%r13d
  lea    0x0(,%r15,8),%rcx
  mov    %r15,%rax
  mov    %rcx,0x8(%rsp)
  sub    $0x2,%eax
  lea    0x8(%rdi,%rax,8),%rbx
  nopl   0x0(%rax)
L5:
  cmpl   $0x1,0x4(%rsp)
  mov    %r12,%r14
  jle    L21
  nopw   0x0(%rax,%rax,1)
L3:
  movsd  (%r14),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r14
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L3
L21:
  movsd  -0x8(%r12,%r15,8),%xmm0
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  add    %rax,%r12
  add    %rax,%rbx
  cmp    %r13d,(%rsp)
  jne    L5
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: string
name: unpack_data
arguments: label: D6
data_type: string

tool: D16: %G 

tool: D6: %G

assistant: ```c
void print_data_double(double *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%G ", dat[i * M + j]);
    }
    printf("%G", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<qd_div_dd_qd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <qd_div@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void qd_div_dd_qd(const double *a, const double *b, double *c) {
  double qd_a[4];
  qd_a[0] = a[0];
  qd_a[1] = a[1];
  qd_a[2] = 0.0;
  qd_a[3] = 0.0;
  qd_div(qd_a, b, c);
}
```
user: What is the c source code of the assembly code below?

```asm
<qd_div_dd_qd>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsp)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rsp,%rdi
  call   <qd_div@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void qd_div_dd_qd(const double *a, const double *b, double *c) {
  double qd_a[4];
  qd_a[0] = a[0];
  qd_a[1] = a[1];
  qd_a[2] = 0.0;
  qd_a[3] = 0.0;
  qd_div(qd_a, b, c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qd_div_dd_qd>:
  endbr64
  sub    $0x38,%rsp
  movsd  (%rdi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movsd  %xmm0,(%rsp)
  movsd  0x8(%rdi),%xmm0
  mov    %rsp,%rdi
  movq   $0x0,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <qd_div@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void qd_div_dd_qd(const double *a, const double *b, double *c) {
  double qd_a[4];
  qd_a[0] = a[0];
  qd_a[1] = a[1];
  qd_a[2] = 0.0;
  qd_a[3] = 0.0;
  qd_div(qd_a, b, c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qd_div_dd_qd>:
  endbr64
  sub    $0x38,%rsp
  movupd (%rdi),%xmm1
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm1,(%rsp)
  call   <qd_div@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void qd_div_dd_qd(const double *a, const double *b, double *c) {
  double qd_a[4];
  qd_a[0] = a[0];
  qd_a[1] = a[1];
  qd_a[2] = 0.0;
  qd_a[3] = 0.0;
  qd_div(qd_a, b, c);
}
```
user: What is the c source code of the assembly code below?

```asm
<fn5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn5(int a, int b) {
  int tem1 = a ^ b;
  int tem2 = a & b;
  return tem1 ^ tem2;
}
```
user: What is the c source code of the assembly code below:

```asm
<fn5>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int fn5(int a, int b) {
  int tem1 = a ^ b;
  int tem2 = a & b;
  return tem1 ^ tem2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fn5>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int fn5(int a, int b) {
  int tem1 = a ^ b;
  int tem2 = a & b;
  return tem1 ^ tem2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn5>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int fn5(int a, int b) {
  int tem1 = a ^ b;
  int tem2 = a & b;
  return tem1 ^ tem2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L18:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L18
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int sum = 0;
  int val;
  for (int i = 0; i < n; i++) {
    scanf("%d", &val);
    sum += val;
  }
  printf("%d", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L9
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D27(%rip),%r12
L29:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L29
L32:
  mov    %ebp,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    $0x0,%ebp
  jmp    L32
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D27
datatype: string

tool: D27: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int sum = 0;
  int val;
  for (int i = 0; i < n; i++) {
    scanf("%d", &val);
    sum += val;
  }
  printf("%d", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L12
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r13
L21:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  cmp    %ebx,(%rsp)
  jg     L21
L33:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  xor    %ebp,%ebp
  jmp    L33
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int sum = 0;
  int val;
  for (int i = 0; i < n; i++) {
    scanf("%d", &val);
    sum += val;
  }
  printf("%d", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L7
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r13
L14:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  cmp    %ebx,(%rsp)
  jg     L14
L36:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  xor    %ebp,%ebp
  jmp    L36
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int sum = 0;
  int val;
  for (int i = 0; i < n; i++) {
    scanf("%d", &val);
    sum += val;
  }
  printf("%d", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x18(%rbp)
  mov    %al,-0xc(%rbp)
  jmp    L1
L19:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xc(%rbp),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mset(char *dst, char c, size_t z) {
  while (z--)
    *dst++ = c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mset>:
  endbr64
  test   %rdx,%rdx
  je     L5
  add    %rdi,%rdx
L18:
  add    $0x1,%rdi
  mov    %sil,-0x1(%rdi)
  cmp    %rdi,%rdx
  jne    L18
L5:
  ret
```

assistant: ```c
void mset(char *dst, char c, size_t z) {
  while (z--)
    *dst++ = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mset>:
  endbr64
  test   %rdx,%rdx
  je     L8
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void mset(char *dst, char c, size_t z) {
  while (z--)
    *dst++ = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mset>:
  endbr64
  test   %rdx,%rdx
  je     L7
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void mset(char *dst, char c, size_t z) {
  while (z--)
    *dst++ = c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<largestSumContinousSubarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L11
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L11:
  cmpl   $0x0,-0x8(%rbp)
  jns    L6
  movl   $0x0,-0x8(%rbp)
L6:
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int largestSumContinousSubarray(int arr[], int size) {
  int max_till = 0;
  int max_int = 0;
  for (int i = 0; i < size; i++) {
    max_int = max_int + arr[i];
    if (max_till < max_int) {
      max_till = max_int;
    }
    if (max_int < 0) {
      max_int = 0;
    }
  }
  return max_till;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<largestSumContinousSubarray>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    $0x0,%eax
  mov    $0x0,%ecx
L10:
  add    (%rdx),%eax
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  test   %eax,%eax
  mov    $0x0,%esi
  cmovs  %esi,%eax
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L10
L8:
  mov    %ecx,%eax
  ret
L6:
  mov    $0x0,%ecx
  jmp    L8
```

assistant: ```c
int largestSumContinousSubarray(int arr[], int size) {
  int max_till = 0;
  int max_int = 0;
  for (int i = 0; i < size; i++) {
    max_int = max_int + arr[i];
    if (max_till < max_int) {
      max_till = max_int;
    }
    if (max_int < 0) {
      max_int = 0;
    }
  }
  return max_till;
}
```
user: Translate the below assembly code into C programming language:

```asm
<largestSumContinousSubarray>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L11:
  add    (%rdi),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L11
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int largestSumContinousSubarray(int arr[], int size) {
  int max_till = 0;
  int max_int = 0;
  for (int i = 0; i < size; i++) {
    max_int = max_int + arr[i];
    if (max_till < max_int) {
      max_till = max_int;
    }
    if (max_int < 0) {
      max_int = 0;
    }
  }
  return max_till;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<largestSumContinousSubarray>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  add    (%rdi),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x4,%rdi
  cmp    %rdi,%rcx
  jne    L8
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int largestSumContinousSubarray(int arr[], int size) {
  int max_till = 0;
  int max_int = 0;
  for (int i = 0; i < size; i++) {
    max_int = max_int + arr[i];
    if (max_till < max_int) {
      max_till = max_int;
    }
    if (max_int < 0) {
      max_int = 0;
    }
  }
  return max_till;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<FixedMul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  add    $0x8000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t FixedMul(int32_t a, int32_t b) {
  int64_t scratch1 = (int64_t)a * (int64_t)b + (int64_t)0x8000;
  return (scratch1 >> 16) & 0xffffffff;
}
```
user: What is the c source code of the assembly code below?

```asm
<FixedMul>:
  endbr64
  imul   %esi,%edi
  lea    0x8000(%rdi),%eax
  sar    $0x10,%eax
  ret
```

assistant: ```c
int32_t FixedMul(int32_t a, int32_t b) {
  int64_t scratch1 = (int64_t)a * (int64_t)b + (int64_t)0x8000;
  return (scratch1 >> 16) & 0xffffffff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FixedMul>:
  endbr64
  imul   %esi,%edi
  lea    0x8000(%rdi),%eax
  sar    $0x10,%eax
  ret
```

assistant: ```c
int32_t FixedMul(int32_t a, int32_t b) {
  int64_t scratch1 = (int64_t)a * (int64_t)b + (int64_t)0x8000;
  return (scratch1 >> 16) & 0xffffffff;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FixedMul>:
  endbr64
  imul   %esi,%edi
  lea    0x8000(%rdi),%eax
  sar    $0x10,%eax
  ret
```

assistant: ```c
int32_t FixedMul(int32_t a, int32_t b) {
  int64_t scratch1 = (int64_t)a * (int64_t)b + (int64_t)0x8000;
  return (scratch1 >> 16) & 0xffffffff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L2
  cmpl   $0x0,-0x20(%rbp)
  js     L2
  jmp    L24
L45:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x20(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L45
  jmp    L12
L2:
  nop
L12:
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *s, int l, int r) {
  if (l < 0 || r < 0)
    return;
  while (l < r) {
    char t = s[l];
    s[l] = s[r];
    s[r] = t;
    l++;
    r--;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  mov    %esi,%eax
  or     %edx,%eax
  js     L0
  cmp    %edx,%esi
  jge    L0
  movslq %esi,%rsi
  movslq %edx,%rdx
L22:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rsi
  sub    $0x1,%rdx
  cmp    %edx,%esi
  jl     L22
L0:
  ret
```

assistant: ```c
void reverse(char *s, int l, int r) {
  if (l < 0 || r < 0)
    return;
  while (l < r) {
    char t = s[l];
    s[l] = s[r];
    s[r] = t;
    l++;
    r--;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  mov    %esi,%eax
  or     %edx,%eax
  js     L24
  cmp    %edx,%esi
  jge    L24
  movslq %esi,%rsi
  movslq %edx,%rdx
  nopl   0x0(%rax)
L17:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  add    $0x1,%rsi
  mov    %al,(%rdi,%rdx,1)
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jg     L17
L24:
  ret
```

assistant: ```c
void reverse(char *s, int l, int r) {
  if (l < 0 || r < 0)
    return;
  while (l < r) {
    char t = s[l];
    s[l] = s[r];
    s[r] = t;
    l++;
    r--;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reverse>:
  endbr64
  mov    %esi,%eax
  or     %edx,%eax
  js     L18
  cmp    %edx,%esi
  jge    L18
  movslq %esi,%rsi
  movslq %edx,%rdx
  nopl   0x0(%rax)
L0:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  add    $0x1,%rsi
  mov    %al,(%rdi,%rdx,1)
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jg     L0
L18:
  ret
```

assistant: ```c
void reverse(char *s, int l, int r) {
  if (l < 0 || r < 0)
    return;
  while (l < r) {
    char t = s[l];
    s[l] = s[r];
    s[r] = t;
    l++;
    r--;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L7:
  mov    $0x0,%eax
  call   <test@plt>
  addq   $0x1,-0x8(%rbp)
L16:
  cmpq   $0x5f5e0ff,-0x8(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    test();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
L5:
  mov    $0x0,%eax
  call   <test@plt>
  sub    $0x1,%rbx
  jne    L5
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    test();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <test@plt>
  sub    $0x1,%rbx
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    test();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <test@plt>
  sub    $0x1,%rbx
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    test();
  }
  return 0;
}
```