ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<open_pty>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    D0(%rip),%r13
  mov    D16(%rip),%r12
  mov    0x0(%r13),%edi
  or     (%r12),%edi
  call   <posix_openpt@plt>
  mov    %eax,(%rbx)
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x0(%r13),%eax
  or     (%r12),%eax
  mov    %eax,%r12d
  mov    (%rbx),%edi
  call   <ptsname@plt>
  mov    %eax,%edi
  mov    %r12d,%esi
  call   <open@plt>
  mov    %eax,0x0(%rbp)
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void open_pty(int *master_fd, int *slave_fd) {
  *master_fd = posix_openpt(O_NOCTTY | O_RDWR);
  assert(*master_fd >= 0);
  *slave_fd = open(ptsname(*master_fd), O_NOCTTY | O_RDWR);
  assert(*slave_fd >= 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<open_pty>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D11(%rip),%r13
  mov    D13(%rip),%rbp
  mov    0x0(%r13),%edi
  or     0x0(%rbp),%edi
  call   <posix_openpt@plt>
  mov    %eax,(%rbx)
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    (%rbx),%edi
  mov    0x0(%r13),%esi
  or     0x0(%rbp),%esi
  mov    %esi,%ebp
  call   <ptsname@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <open@plt>
  mov    %eax,(%r12)
  not    %eax
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  jmp    1090 <assert@plt>
```

assistant: ```c
void open_pty(int *master_fd, int *slave_fd) {
  *master_fd = posix_openpt(O_NOCTTY | O_RDWR);
  assert(*master_fd >= 0);
  *slave_fd = open(ptsname(*master_fd), O_NOCTTY | O_RDWR);
  assert(*slave_fd >= 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<open_pty>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%r13
  mov    D11(%rip),%rbp
  mov    0x0(%r13),%edi
  or     0x0(%rbp),%edi
  call   <posix_openpt@plt>
  mov    %eax,(%rbx)
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    (%rbx),%edi
  mov    0x0(%r13),%esi
  or     0x0(%rbp),%esi
  mov    %esi,%ebp
  call   <ptsname@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <open@plt>
  mov    %eax,(%r12)
  not    %eax
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  jmp    1090 <assert@plt>
```

assistant: ```c
void open_pty(int *master_fd, int *slave_fd) {
  *master_fd = posix_openpt(O_NOCTTY | O_RDWR);
  assert(*master_fd >= 0);
  *slave_fd = open(ptsname(*master_fd), O_NOCTTY | O_RDWR);
  assert(*slave_fd >= 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_some_integers@plt>
  mov    $0x0,%eax
  call   <test_more_integers@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_some_integers();
  test_more_integers();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_some_integers@plt>
  mov    $0x0,%eax
  call   <test_more_integers@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_some_integers();
  test_more_integers();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_some_integers@plt>
  xor    %eax,%eax
  call   <test_more_integers@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_some_integers();
  test_more_integers();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_some_integers@plt>
  xor    %eax,%eax
  call   <test_more_integers@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_some_integers();
  test_more_integers();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Utf8ToStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  test   %al,%al
  js     L25
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L23
L25:
  movzbl -0x11(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%esi
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  and    $0x3f,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
L23:
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L24
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *Utf8ToStr(unsigned char *in) {
  int n, i = 0;
  char *result = NULL;
  result = (char *)malloc(strlen(in) + 1);
  for (n = 0; n < strlen(in); n++) {
    unsigned char c = in[n];
    if (c < 128) {
      result[i++] = (char)c;
    } else {
      result[i++] = (c << 6) | (in[++n] & 63);
    }
  }
  result[i] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Utf8ToStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%r12
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L21
L25:
  mov    %al,(%r12)
L34:
  add    $0x1,%ebx
  add    $0x1,%ebp
  add    $0x1,%r12
L21:
  lea    -0x1(%rbp),%r15d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L30
  movslq %ebx,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  test   %al,%al
  jns    L25
  add    $0x1,%ebx
  movslq %ebx,%rdx
  movzbl 0x0(%r13,%rdx,1),%edx
  and    $0x3f,%edx
  shl    $0x6,%eax
  or     %edx,%eax
  mov    %al,(%r12)
  jmp    L34
L30:
  movslq %r15d,%r15
  movb   $0x0,(%r14,%r15,1)
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *Utf8ToStr(unsigned char *in) {
  int n, i = 0;
  char *result = NULL;
  result = (char *)malloc(strlen(in) + 1);
  for (n = 0; n < strlen(in); n++) {
    unsigned char c = in[n];
    if (c < 128) {
      result[i++] = (char)c;
    } else {
      result[i++] = (c << 6) | (in[++n] & 63);
    }
  }
  result[i] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Utf8ToStr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L15:
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jns    L2
  add    $0x1,%ebx
  shl    $0x6,%eax
  movslq %ebx,%rdx
  movzbl (%r12,%rdx,1),%edx
  and    $0x3f,%edx
  or     %edx,%eax
L2:
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
L23:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *Utf8ToStr(unsigned char *in) {
  int n, i = 0;
  char *result = NULL;
  result = (char *)malloc(strlen(in) + 1);
  for (n = 0; n < strlen(in); n++) {
    unsigned char c = in[n];
    if (c < 128) {
      result[i++] = (char)c;
    } else {
      result[i++] = (c << 6) | (in[++n] & 63);
    }
  }
  result[i] = '\0';
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Utf8ToStr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L3:
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jns    L9
  add    $0x1,%ebx
  shl    $0x6,%eax
  movslq %ebx,%rdx
  movzbl (%r12,%rdx,1),%edx
  and    $0x3f,%edx
  or     %edx,%eax
L9:
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *Utf8ToStr(unsigned char *in) {
  int n, i = 0;
  char *result = NULL;
  result = (char *)malloc(strlen(in) + 1);
  for (n = 0; n < strlen(in); n++) {
    unsigned char c = in[n];
    if (c < 128) {
      result[i++] = (char)c;
    } else {
      result[i++] = (c << 6) | (in[++n] & 63);
    }
  }
  result[i] = '\0';
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D5: %d %lf

tool: D9: %.3lf km/l


assistant: ```c
int main() {
  int x;
  double y;
  scanf("%d %lf", &x, &y);
  printf("%.3lf km/l\n", x / y);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0xc(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D12
type: string

tool: D17: %d %lf

tool: D12: %.3lf km/l


assistant: ```c
int main() {
  int x;
  double y;
  scanf("%d %lf", &x, &y);
  printf("%.3lf km/l\n", x / y);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  cvtsi2sdl 0xc(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D0: %d %lf

tool: D16: %.3lf km/l


assistant: ```c
int main() {
  int x;
  double y;
  scanf("%d %lf", &x, &y);
  printf("%.3lf km/l\n", x / y);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  cvtsi2sdl 0xc(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string

tool: D5: %d %lf

tool: D12: %.3lf km/l


assistant: ```c
int main() {
  int x;
  double y;
  scanf("%d %lf", &x, &y);
  printf("%.3lf km/l\n", x / y);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<back_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L10
L5:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jg     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: 

assistant: ```c
void back_up(int num) {
  for (; num > 0; num--)
    printf("\b");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<back_up>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    D6(%rip),%rbp
L19:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: 

assistant: ```c
void back_up(int num) {
  for (; num > 0; num--)
    printf("\b");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<back_up>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: 

assistant: ```c
void back_up(int num) {
  for (; num > 0; num--)
    printf("\b");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<back_up>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: 

assistant: ```c
void back_up(int num) {
  for (; num > 0; num--)
    printf("\b");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<combine_g1_and_g2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x3fe,-0x4(%rbp)
  jle    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void combine_g1_and_g2(unsigned char *g1, unsigned char *g2, unsigned char *out) {
  int i;
  for (i = 0; i < 1023; i++) {
    out[i] = g1[i] ^ g2[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<combine_g1_and_g2>:
  endbr64
  mov    $0x0,%eax
L0:
  movzbl (%rdi,%rax,1),%ecx
  xor    (%rsi,%rax,1),%cl
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x3ff,%rax
  jne    L0
  ret
```

assistant: ```c
void combine_g1_and_g2(unsigned char *g1, unsigned char *g2, unsigned char *out) {
  int i;
  for (i = 0; i < 1023; i++) {
    out[i] = g1[i] ^ g2[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<combine_g1_and_g2>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rdi,%rax,1),%ecx
  xor    (%rsi,%rax,1),%cl
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x3ff,%rax
  jne    L4
  ret
```

assistant: ```c
void combine_g1_and_g2(unsigned char *g1, unsigned char *g2, unsigned char *out) {
  int i;
  for (i = 0; i < 1023; i++) {
    out[i] = g1[i] ^ g2[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<combine_g1_and_g2>:
  endbr64
  mov    %rdx,%rcx
  lea    0x1(%rdi),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0xe,%rax
  jbe    L28
  lea    0x1(%rsi),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0xe,%rax
  jbe    L28
  xor    %eax,%eax
  nopl   0x0(%rax)
L25:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    $0x3f0,%rax
  jne    L25
  movq   0x3f0(%rdi),%xmm0
  movq   0x3f0(%rsi),%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,0x3f0(%rcx)
  movzbl 0x3f8(%rdi),%eax
  xor    0x3f8(%rsi),%al
  mov    %al,0x3f8(%rcx)
  movzbl 0x3f9(%rdi),%eax
  xor    0x3f9(%rsi),%al
  mov    %al,0x3f9(%rcx)
  movzbl 0x3fa(%rdi),%eax
  xor    0x3fa(%rsi),%al
  mov    %al,0x3fa(%rcx)
  movzbl 0x3fb(%rdi),%eax
  xor    0x3fb(%rsi),%al
  mov    %al,0x3fb(%rcx)
  movzbl 0x3fc(%rdi),%eax
  xor    0x3fc(%rsi),%al
  mov    %al,0x3fc(%rcx)
  movzbl 0x3fd(%rdi),%eax
  xor    0x3fd(%rsi),%al
  mov    %al,0x3fd(%rcx)
  movzbl 0x3fe(%rdi),%eax
  xor    0x3fe(%rsi),%al
  mov    %al,0x3fe(%rcx)
  ret
L28:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L37:
  movzbl (%rdi,%rax,1),%edx
  xor    (%rsi,%rax,1),%dl
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    $0x3ff,%rax
  jne    L37
  ret
```

assistant: ```c
void combine_g1_and_g2(unsigned char *g1, unsigned char *g2, unsigned char *out) {
  int i;
  for (i = 0; i < 1023; i++) {
    out[i] = g1[i] ^ g2[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%r8
  mov    (%rdi),%rax
  sub    $0x3f60a4d,%rax
  mov    0x8(%rdi),%rsi
  test   %rsi,%rsi
  je     L37
  push   %rbx
  mov    $0x0,%edx
  movabs $0xffff0000ffffffff,%r10
  movabs $0xffffffffffffff,%r9
  jmp    L1
L43:
  mov    %rax,%rdi
  shr    $0x20,%rdi
  movzwl %ax,%ecx
  shl    $0x20,%rcx
  and    %r10,%rax
  or     %rcx,%rax
  mov    %di,%ax
L32:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L34
L1:
  cmp    %rdx,%rax
  jae    L43
  lea    (%rax,%rax,1),%rcx
  mov    %rcx,%rax
  mov    %rcx,%rbx
  sar    $0x38,%rbx
  mov    %bl,%ah
  movzbl %ch,%ecx
  shl    $0x38,%rcx
  and    %r9,%rax
  or     %rcx,%rax
  jmp    L32
L34:
  sub    $0x34ab128b,%rax
  mov    %rax,(%r8)
  pop    %rbx
  ret
L37:
  sub    $0x34ab128b,%rax
  mov    %rax,(%r8)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
          *((char *)(&state[0UL]) + 7) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 6);
          *((char *)(&state[local1]) + 6) = copy12;
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 307931096UL) + 0xffffffffddaf954dUL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%r9
  mov    0x8(%rdi),%rsi
  lea    -0x3f60a4d(%rax),%rdx
  test   %rsi,%rsi
  je     L31
  movabs $0xffff0000ffffffff,%r10
  push   %rbx
  mov    %rdx,%rax
  xor    %ecx,%ecx
  movabs $0xffffffffffffff,%r8
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L9:
  add    %rdx,%rdx
  add    $0x1,%rcx
  mov    %rdx,%rbx
  mov    %rdx,%rax
  movzbl %dh,%edx
  sar    $0x38,%rbx
  shl    $0x38,%rdx
  mov    %bl,%ah
  and    %r8,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  cmp    %rsi,%rcx
  je     L14
L6:
  cmp    %rdx,%rcx
  ja     L9
  movzwl %ax,%edx
  mov    %rax,%rdi
  and    %r10,%rax
  add    $0x1,%rcx
  shl    $0x20,%rdx
  shr    $0x20,%rdi
  or     %rdx,%rax
  mov    %di,%ax
  mov    %rax,%rdx
  cmp    %rsi,%rcx
  jne    L6
L14:
  sub    $0x34ab128b,%rdx
  pop    %rbx
  mov    %rdx,(%r9)
  ret
  nopl   0x0(%rax)
L31:
  sub    $0x34ab128b,%rdx
  mov    %rdx,(%r9)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
          *((char *)(&state[0UL]) + 7) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 6);
          *((char *)(&state[local1]) + 6) = copy12;
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 307931096UL) + 0xffffffffddaf954dUL;
  }
}
```