ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__kernel_sin>:
  endbr64
  movq   %xmm0,%rax
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm6
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3e3fffff,%eax
  jg     L17
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  je     L22
L17:
  movapd %xmm4,%xmm3
  movsd  D7(%rip),%xmm2
  mulsd  %xmm4,%xmm3
  mulsd  %xmm3,%xmm2
  movapd %xmm3,%xmm5
  subsd  D20(%rip),%xmm2
  mulsd  %xmm4,%xmm5
  mulsd  %xmm3,%xmm2
  addsd  D6(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  D5(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  D72(%rip),%xmm2
  test   %edi,%edi
  jne    L2
  mulsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  subsd  D62(%rip),%xmm0
  mulsd  %xmm5,%xmm0
  addsd  %xmm4,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  D57(%rip),%xmm0
  mulsd  %xmm5,%xmm2
  mulsd  D62(%rip),%xmm5
  mulsd  %xmm6,%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm6,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
L22:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: byte[8]
name: parse_data
arguments: data_label: D20
datatype: byte[8]
name: parse_data
arguments: data_label: D6
datatype: byte[8]
name: parse_data
arguments: data_label: D5
datatype: byte[8]
name: parse_data
arguments: data_label: D72
datatype: byte[8]
name: parse_data
arguments: data_label: D62
datatype: byte[8]
name: parse_data
arguments: data_label: D57
datatype: byte[8]

tool: {"D7": [0x7c,0xd5,0xcf,0x5a,0x3a,0xd9,0xe5,0x3d]}

tool: {"D20": [0xeb,0x9c,0x2b,0x8a,0xe6,0xe5,0x5a,0x3e]}

tool: {"D6": [0x7d,0xfe,0xb1,0x57,0xe3,0x1d,0xc7,0x3e]}

tool: {"D5": [0xd5,0x61,0xc1,0x19,0xa0,0x01,0x2a,0x3f]}

tool: {"D72": [0xa6,0xf8,0x10,0x11,0x11,0x11,0x81,0x3f]}

tool: {"D62": [0x49,0x55,0x55,0x55,0x55,0x55,0xc5,0x3f]}

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double __kernel_sin(double x, double y, int iy) {
  double z, r, v;
  int ix;
  ix = *(1 + (const int *)&x) & 0x7fffffff;
  if (ix < 0x3e400000) {
    if ((int)x == 0) {
      return x;
    }
  }
  z = x * x;
  v = z * x;
  r = 8.33333333332248946124e-03 + z * (-1.98412698298579493134e-04 + z * (2.75573137070700676789e-06 + z * (-2.50507602534068634195e-08 + z * 1.58969099521155010221e-10)));
  if (iy == 0) {
    return x + v * (-1.66666666666666324348e-01 + z * r);
  } else {
    return x - ((z * (5.00000000000000000000e-01 * y - v * r) - y) - v * -1.66666666666666324348e-01);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__kernel_sin>:
  endbr64
  movq   %xmm0,%rax
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm6
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3e3fffff,%eax
  jg     L14
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  je     L21
L14:
  movapd %xmm4,%xmm3
  movsd  D19(%rip),%xmm2
  mulsd  %xmm4,%xmm3
  mulsd  %xmm3,%xmm2
  movapd %xmm3,%xmm5
  subsd  D14(%rip),%xmm2
  mulsd  %xmm4,%xmm5
  mulsd  %xmm3,%xmm2
  addsd  D45(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  D62(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  D41(%rip),%xmm2
  test   %edi,%edi
  jne    L23
  mulsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  subsd  D77(%rip),%xmm0
  mulsd  %xmm5,%xmm0
  addsd  %xmm4,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  movsd  D31(%rip),%xmm0
  mulsd  %xmm5,%xmm2
  mulsd  D77(%rip),%xmm5
  mulsd  %xmm6,%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm6,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
L21:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D14
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D45
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D62
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D41
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D77
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D31
type_guessed: byte[8]

tool: {"D19": [0x7c,0xd5,0xcf,0x5a,0x3a,0xd9,0xe5,0x3d]}

tool: {"D14": [0xeb,0x9c,0x2b,0x8a,0xe6,0xe5,0x5a,0x3e]}

tool: {"D45": [0x7d,0xfe,0xb1,0x57,0xe3,0x1d,0xc7,0x3e]}

tool: {"D62": [0xd5,0x61,0xc1,0x19,0xa0,0x01,0x2a,0x3f]}

tool: {"D41": [0xa6,0xf8,0x10,0x11,0x11,0x11,0x81,0x3f]}

tool: {"D77": [0x49,0x55,0x55,0x55,0x55,0x55,0xc5,0x3f]}

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double __kernel_sin(double x, double y, int iy) {
  double z, r, v;
  int ix;
  ix = *(1 + (const int *)&x) & 0x7fffffff;
  if (ix < 0x3e400000) {
    if ((int)x == 0) {
      return x;
    }
  }
  z = x * x;
  v = z * x;
  r = 8.33333333332248946124e-03 + z * (-1.98412698298579493134e-04 + z * (2.75573137070700676789e-06 + z * (-2.50507602534068634195e-08 + z * 1.58969099521155010221e-10)));
  if (iy == 0) {
    return x + v * (-1.66666666666666324348e-01 + z * r);
  } else {
    return x - ((z * (5.00000000000000000000e-01 * y - v * r) - y) - v * -1.66666666666666324348e-01);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L4
  mov    $0x1,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L4:
  movl   $0x0,-0x14(%rbp)
  jmp    L54
L33:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %ax,-0x16(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzwl -0x16(%rbp),%edx
  mov    %dx,-0xc(%rbp,%rax,2)
  addl   $0x1,-0x14(%rbp)
L54:
  cmpl   $0x0,-0x14(%rbp)
  jle    L33
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzwl -0xa(%rbp),%eax
  cmp    $0x8362,%ax
  jne    L2
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L2:
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L41:
  mov    -0x10(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x0,-0x10(%rbp)
  jle    L41
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D21
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string

tool: D13: Call this program with %i arguments


tool: D21: You win!

tool: D17: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 33634) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L7
L4:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %ax,0x4(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpw   $0x8362,0x6(%rsp)
  je     L37
L9:
  movzwl 0x6(%rsp),%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L4
L37:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string

tool: D16: %u


tool: D11: Call this program with %i arguments


tool: D5: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 33634) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L21
  lea    D9(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L21:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0x8362,%si
  je     L38
L5:
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L38:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L5
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D9: Call this program with %i arguments


tool: D2: %u


tool: D5: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 33634) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L22
  lea    D26(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L22:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0x8362,%si
  je     L20
L11:
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L11
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D26: Call this program with %i arguments


tool: D17: %u


tool: D18: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 33634) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x4,%esi
  mov    $0x64,%edi
  call   <mycalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L15
L28:
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L29:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  jne    L49
  mov    $0xa,%edi
  call   <putchar@plt>
L49:
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x63,-0xc(%rbp)
  jle    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L15:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string

tool: D18: mycalloc returned NULL.

tool: D17: %08X 

assistant: ```c
int main(void) {
  int *p = NULL;
  int i = 0;
  p = mycalloc(100, sizeof *p);
  if (NULL == p) {
    printf("mycalloc returned NULL.\n");
  } else {
    for (i = 0; i < 100; i++) {
      printf("%08X ", p[i]);
      if (i % 8 == 7) {
        printf("\n");
      }
    }
    printf("\n");
    free(p);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%esi
  mov    $0x64,%edi
  call   <mycalloc@plt>
  test   %rax,%rax
  je     L42
  mov    %rax,%rbp
  mov    (%rax),%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D9(%rip),%r12
  jmp    L54
L42:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L46
L21:
  add    $0x1,%rbx
L54:
  cmp    $0x64,%rbx
  je     L55
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L21
L55:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L46:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string

tool: D9: %08X 

tool: D22: mycalloc returned NULL.

assistant: ```c
int main(void) {
  int *p = NULL;
  int i = 0;
  p = mycalloc(100, sizeof *p);
  if (NULL == p) {
    printf("mycalloc returned NULL.\n");
  } else {
    for (i = 0; i < 100; i++) {
      printf("%08X ", p[i]);
      if (i % 8 == 7) {
        printf("\n");
      }
    }
    printf("\n");
    free(p);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  mov    $0x64,%edi
  push   %rbp
  push   %rbx
  call   <mycalloc@plt>
  test   %rax,%rax
  je     L23
  mov    (%rax),%esi
  lea    D15(%rip),%r12
  mov    %rax,%rbp
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    $0x1,%ebx
  call   <printf@plt>
  jmp    L40
  nopl   0x0(%rax)
L36:
  add    $0x1,%rbx
L40:
  cmp    $0x64,%rbx
  je     L52
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x7,%eax
  cmp    $0x7,%eax
  jne    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L36
L52:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L13:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L23:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D15: %08X 

tool: D17: mycalloc returned NULL.

assistant: ```c
int main(void) {
  int *p = NULL;
  int i = 0;
  p = mycalloc(100, sizeof *p);
  if (NULL == p) {
    printf("mycalloc returned NULL.\n");
  } else {
    for (i = 0; i < 100; i++) {
      printf("%08X ", p[i]);
      if (i % 8 == 7) {
        printf("\n");
      }
    }
    printf("\n");
    free(p);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  mov    $0x64,%edi
  push   %rbp
  push   %rbx
  call   <mycalloc@plt>
  test   %rax,%rax
  je     L52
  mov    (%rax),%esi
  lea    D15(%rip),%r12
  mov    %rax,%rbp
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    $0x1,%ebx
  call   <printf@plt>
  jmp    L28
  nopl   0x0(%rax)
L34:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L10
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x7,%eax
  cmp    $0x7,%eax
  jne    L34
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    $0x64,%rbx
  jne    L28
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L52:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L37
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D15: %08X 

tool: D10: mycalloc returned NULL.

assistant: ```c
int main(void) {
  int *p = NULL;
  int i = 0;
  p = mycalloc(100, sizeof *p);
  if (NULL == p) {
    printf("mycalloc returned NULL.\n");
  } else {
    for (i = 0; i < 100; i++) {
      printf("%08X ", p[i]);
      if (i % 8 == 7) {
        printf("\n");
      }
    }
    printf("\n");
    free(p);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x4c(%rbp)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L36:
  cmp    %rdx,%rsp
  je     L72
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L72:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L16
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L16:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L61
L17:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L61:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L17
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  jmp    L44
L39:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4c(%rbp)
L44:
  cmpl   $0x0,-0x4c(%rbp)
  jns    L39
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string

tool: D4: %d

tool: D28: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i = 0;
  int array[n];
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &*(array + i));
  }
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", *(array + i));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ebx
  movslq %ebx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L67
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L67:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L0
  orq    $0x0,-0x8(%rsp,%rax,1)
L0:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L66
  mov    %r13,%r14
  mov    $0x0,%r12d
  lea    D13(%rip),%r15
L50:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x3c(%rbp),%ebx
  add    $0x4,%r14
  cmp    %r12d,%ebx
  jg     L50
L66:
  sub    $0x1,%ebx
  js     L13
  movslq %ebx,%rbx
  lea    D11(%rip),%r12
L19:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L19
L13:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string

tool: D13: %d

tool: D11: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i = 0;
  int array[n];
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &*(array + i));
  }
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", *(array + i));
  }
  return 0;
}
```