user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x0,-0x30(%rbp)
  jmp    L43
L142:
  movl   $0x1,-0x2c(%rbp)
  jmp    L225
L215:
  movl   $0x1,-0x28(%rbp)
  jmp    L221
L156:
  movl   $0x0,-0x24(%rbp)
  jmp    L118
L75:
  movl   $0x1,-0x20(%rbp)
  jmp    L271
L42:
  movl   $0x1,-0x1c(%rbp)
  jmp    L285
L261:
  movl   $0x0,-0x18(%rbp)
  jmp    L276
L144:
  movl   $0x1,-0x14(%rbp)
  jmp    L1
L79:
  movl   $0x1,-0x10(%rbp)
  jmp    L123
L232:
  movl   $0x0,-0xc(%rbp)
  jmp    L262
L153:
  movl   $0x1,-0x8(%rbp)
  jmp    L250
L278:
  movl   $0x1,-0x4(%rbp)
  jmp    L249
L19:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jg     L272
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jg     L272
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jg     L272
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jg     L272
  mov    -0x2c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  imul   -0x14(%rbp),%eax
  imul   -0x8(%rbp),%eax
  cmp    $0x1,%eax
  je     L272
  mov    -0x1c(%rbp),%r9d
  mov    -0x20(%rbp),%r8d
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x30(%rbp),%eax
  mov    -0x4(%rbp),%edi
  push   %rdi
  mov    -0x8(%rbp),%edi
  push   %rdi
  mov    -0xc(%rbp),%edi
  push   %rdi
  mov    -0x10(%rbp),%edi
  push   %rdi
  mov    -0x14(%rbp),%edi
  push   %rdi
  mov    -0x18(%rbp),%edi
  push   %rdi
  mov    %eax,%edi
  call   <test@plt>
  add    $0x30,%rsp
L272:
  addl   $0x1,-0x4(%rbp)
L249:
  cmpl   $0x4,-0x4(%rbp)
  jle    L19
  addl   $0x1,-0x8(%rbp)
L250:
  cmpl   $0x5,-0x8(%rbp)
  jle    L278
  addl   $0x1,-0xc(%rbp)
L262:
  cmpl   $0x4,-0xc(%rbp)
  jle    L153
  addl   $0x1,-0x10(%rbp)
L123:
  cmpl   $0x4,-0x10(%rbp)
  jle    L232
  addl   $0x1,-0x14(%rbp)
L1:
  cmpl   $0x5,-0x14(%rbp)
  jle    L79
  addl   $0x1,-0x18(%rbp)
L276:
  cmpl   $0x4,-0x18(%rbp)
  jle    L144
  addl   $0x1,-0x1c(%rbp)
L285:
  cmpl   $0x4,-0x1c(%rbp)
  jle    L261
  addl   $0x1,-0x20(%rbp)
L271:
  cmpl   $0x5,-0x20(%rbp)
  jle    L42
  addl   $0x1,-0x24(%rbp)
L118:
  cmpl   $0x4,-0x24(%rbp)
  jle    L75
  addl   $0x1,-0x28(%rbp)
L221:
  cmpl   $0x4,-0x28(%rbp)
  jle    L156
  addl   $0x1,-0x2c(%rbp)
L225:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L215
  addl   $0x1,-0x30(%rbp)
L43:
  cmpl   $0x4,-0x30(%rbp)
  jle    L142
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  for (int start0 = 0; start0 < 5; start0++) {
    for (int len0 = 1; len0 <= 5; len0++) {
      for (int stride0 = 1; stride0 < 5; stride0++) {
        for (int start1 = 0; start1 < 5; start1++) {
          for (int len1 = 1; len1 <= 5; len1++) {
            for (int stride1 = 1; stride1 < 5; stride1++) {
              for (int start2 = 0; start2 < 5; start2++) {
                for (int len2 = 1; len2 <= 5; len2++) {
                  for (int stride2 = 1; stride2 < 5; stride2++) {
                    for (int start3 = 0; start3 < 5; start3++) {
                      for (int len3 = 1; len3 <= 5; len3++) {
                        for (int stride3 = 1; stride3 < 5; stride3++) {
                          if (start0 + (len0 - 1) * stride0 < 5 && start1 + (len1 - 1) * stride1 < 5 && start2 + (len2 - 1) * stride2 < 5 && start3 + (len3 - 1) * stride3 < 5 && len0 * len1 * len2 * len3 != 1) {
                            test(start0, len0, stride0, start1, len1, stride1, start2, len2, stride2, start3, len3, stride3);
                          }
                        }
                      }
                    }
                  }
                }
              }
            }
          }
        }
      }
    }
  }
  return 0;
}
```