ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  je     L14
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L82
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L59
L82:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L59
L14:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  je     L2
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L55
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L59
L55:
  mov    -0x10(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  imul   $0x1f4,%eax,%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L2:
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  je     L33
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L24
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L59
L24:
  mov    -0x14(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L33:
  mov    $0x30,%edi
  call   <putchar@plt>
L59:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L119
  call   <__stack_chk_fail@plt>
L119:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D25
data_type: string
name: disassemble_data
arguments: label: D51
data_type: string

tool: D4: %d %d %d

tool: D26: 10000

tool: D25: 0

tool: D51: %d

assistant: ```c
int main() {
  int d1, m1, y1, d2, m2, y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  scanf("%d %d %d", &d1, &m1, &y1);
  if (y1 != y2) {
    if (y1 < y2)
      printf("10000\n");
    else
      printf("0\n");
  } else if (m1 != m2) {
    if (m1 > m2)
      printf("0");
    else
      printf("%d", (m2 - m1) * 500);
  } else if (d1 != d2) {
    if (d1 > d2)
      printf("0");
    else
      printf("%d", (d2 - d1) * 15);
  } else
    printf("0");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0x14(%rsp),%eax
  cmp    %eax,%edx
  je     L4
  jge    L83
  lea    D0(%rip),%rdi
  call   <puts@plt>
L81:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L83:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L81
L4:
  mov    0x4(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  je     L69
  jle    L106
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L81
L106:
  sub    %eax,%esi
  imul   $0x1f4,%esi,%esi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L69:
  mov    (%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  je     L102
  jle    L24
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L81
L24:
  sub    %eax,%esi
  imul   $0xf,%esi,%esi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L102:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L81
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D25
datatype: string
name: retrieve_data
arguments: data_tag: D42
datatype: string

tool: D7: %d %d %d

tool: D0: 10000

tool: D25: 0

tool: D42: %d

assistant: ```c
int main() {
  int d1, m1, y1, d2, m2, y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  scanf("%d %d %d", &d1, &m1, &y1);
  if (y1 != y2) {
    if (y1 < y2)
      printf("10000\n");
    else
      printf("0\n");
  } else if (m1 != m2) {
    if (m1 > m2)
      printf("0");
    else
      printf("%d", (m2 - m1) * 500);
  } else if (d1 != d2) {
    if (d1 > d2)
      printf("0");
    else
      printf("%d", (d2 - d1) * 15);
  } else
    printf("0");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  je     L82
  jl     L100
  lea    D1(%rip),%rdi
  call   <puts@plt>
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L100:
  lea    D37(%rip),%rdi
  call   <puts@plt>
  jmp    L63
L82:
  mov    0x4(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  je     L4
  jle    L78
L66:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L63
L78:
  sub    %eax,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  imul   $0x1f4,%esi,%esi
  call   <printf@plt>
  jmp    L63
L4:
  mov    (%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  je     L66
  jg     L66
  sub    %eax,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  imul   $0xf,%esi,%esi
  call   <printf@plt>
  jmp    L63
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D20
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D37
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string

tool: D20: %d %d %d

tool: D1: 0

tool: D37: 10000

tool: D15: %d

assistant: ```c
int main() {
  int d1, m1, y1, d2, m2, y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  scanf("%d %d %d", &d1, &m1, &y1);
  if (y1 != y2) {
    if (y1 < y2)
      printf("10000\n");
    else
      printf("0\n");
  } else if (m1 != m2) {
    if (m1 > m2)
      printf("0");
    else
      printf("%d", (m2 - m1) * 500);
  } else if (d1 != d2) {
    if (d1 > d2)
      printf("0");
    else
      printf("%d", (d2 - d1) * 15);
  } else
    printf("0");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  je     L28
  jl     L17
  lea    D1(%rip),%rdi
  call   <puts@plt>
L53:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L17:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L53
L28:
  mov    0x4(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  je     L108
  jle    L30
L96:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L53
L30:
  sub    %eax,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  imul   $0x1f4,%esi,%esi
  call   <printf@plt>
  jmp    L53
L108:
  mov    (%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  je     L96
  jg     L96
  sub    %eax,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  imul   $0xf,%esi,%esi
  call   <printf@plt>
  jmp    L53
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D49
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D18: %d %d %d

tool: D1: 0

tool: D49: 10000

tool: D7: %d

assistant: ```c
int main() {
  int d1, m1, y1, d2, m2, y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  scanf("%d %d %d", &d1, &m1, &y1);
  if (y1 != y2) {
    if (y1 < y2)
      printf("10000\n");
    else
      printf("0\n");
  } else if (m1 != m2) {
    if (m1 > m2)
      printf("0");
    else
      printf("%d", (m2 - m1) * 500);
  } else if (d1 != d2) {
    if (d1 > d2)
      printf("0");
    else
      printf("%d", (d2 - d1) * 15);
  } else
    printf("0");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<D_GGX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x18(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x18(%rbp),%xmm1
  movss  D8(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movsd  D12(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: f32
name: retrieve_data
arguments: tag: D12
data_type: f64

tool: D8: 1

tool: D12: 3.14159

assistant: ```c
float D_GGX(float roughness, float NdH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float d = (NdH * a2 - NdH) * NdH + 1;
  return a2 / (3.14159 * d * d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<D_GGX>:
  endbr64
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  addss  D3(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  movapd %xmm1,%xmm2
  mulsd  D15(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: f32
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: f64

tool: D3: 1

tool: D15: 3.14159

assistant: ```c
float D_GGX(float roughness, float NdH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float d = (NdH * a2 - NdH) * NdH + 1;
  return a2 / (3.14159 * d * d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<D_GGX>:
  endbr64
  mulss  %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm2
  cvtss2sd %xmm0,%xmm0
  mulss  %xmm1,%xmm2
  subss  %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  addss  D12(%rip),%xmm2
  cvtss2sd %xmm2,%xmm1
  movsd  D17(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
data_type: f32
name: disassemble_data
arguments: data_tag: D17
data_type: f64

tool: D12: 1

tool: D17: 3.14159

assistant: ```c
float D_GGX(float roughness, float NdH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float d = (NdH * a2 - NdH) * NdH + 1;
  return a2 / (3.14159 * d * d);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<D_GGX>:
  endbr64
  mulss  %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm2
  cvtss2sd %xmm0,%xmm0
  mulss  %xmm1,%xmm2
  subss  %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  addss  D19(%rip),%xmm2
  cvtss2sd %xmm2,%xmm1
  movsd  D14(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: f32
name: read_data
arguments: tag: D14
type_guessed: f64

tool: D19: 1

tool: D14: 3.14159

assistant: ```c
float D_GGX(float roughness, float NdH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float d = (NdH * a2 - NdH) * NdH + 1;
  return a2 / (3.14159 * d * d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<edge_matrix_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %r8d,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x44(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x48(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L26
L6:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L39
L61:
  movl   $0x0,-0x24(%rbp)
  jmp    L9
L66:
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x24(%rbp)
L9:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L66
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L47
L28:
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x20(%rbp)
L47:
  mov    -0x20(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L28
  mov    -0x44(%rbp),%eax
  add    %eax,-0x28(%rbp)
L39:
  mov    -0x28(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L61
  mov    -0x8(%rbp),%rax
L26:
  leave
  ret
```

assistant: ```c
uint8_t *edge_matrix_left(uint8_t *data, int y, int x, int width, int size) {
  int median = size / 2;
  int index = 0;
  int yl = (y - median) * width;
  int yh = (y + median) * width;
  int xl = x;
  int xh = x + median;
  uint8_t *matrix = malloc(size * size);
  if (!matrix) {
    return NULL;
  }
  for (int row = yl; row <= yh; row += width) {
    for (int i = 0; i < median; ++i) {
      matrix[index] = data[row + xl];
      index++;
    }
    for (int col = xl; col <= xh; ++col) {
      matrix[index] = data[row + col];
      index++;
    }
  }
  return matrix;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<edge_matrix_left>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,%r14d
  mov    %r8d,%r13d
  mov    %r8d,%ebx
  shr    $0x1f,%ebx
  add    %r8d,%ebx
  sar    %ebx
  mov    %esi,%r12d
  sub    %ebx,%r12d
  imul   %ecx,%r12d
  lea    (%rbx,%rsi,1),%r15d
  mov    %ecx,0x18(%rsp)
  imul   %ecx,%r15d
  lea    (%rbx,%rdx,1),%ebp
  mov    %r8d,%eax
  imul   %r8d,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L9
  cmp    %r15d,%r12d
  jg     L9
  movslq 0x18(%rsp),%rax
  shl    $0x2,%rax
  mov    %rax,0x10(%rsp)
  movslq %r12d,%rax
  mov    0x8(%rsp),%rdi
  lea    (%rdi,%rax,4),%rdx
  movslq %r14d,%r10
  mov    %r10,%r9
  neg    %r9
  shl    $0x2,%r9
  mov    $0x0,%edi
  mov    %ebp,%eax
  sub    %r14d,%eax
  lea    0x1(%rax),%eax
  mov    %eax,0x1c(%rsp)
  jmp    L26
L50:
  lea    (%r14,%r12,1),%eax
  cltq
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,4),%rsi
  movslq %edi,%rax
  lea    (%r8,%rax,4),%rcx
  mov    $0x0,%eax
L16:
  mov    (%rsi),%r11d
  mov    %r11d,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L16
  lea    -0x1(%rbx),%eax
  cmp    $0x1,%r13d
  mov    $0x0,%ecx
  cmovle %ecx,%eax
  lea    0x1(%rdi,%rax,1),%edi
L42:
  cmp    %ebp,%r14d
  jg     L46
  movslq %edi,%rax
  lea    (%r9,%rax,4),%rcx
  add    %r8,%rcx
  mov    %r10,%rax
L88:
  mov    (%rdx,%rax,4),%esi
  mov    %esi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L88
  add    0x1c(%rsp),%edi
L46:
  add    0x18(%rsp),%r12d
  add    0x10(%rsp),%rdx
  cmp    %r12d,%r15d
  jl     L9
L26:
  cmp    $0x1,%r13d
  jg     L50
  jmp    L42
L9:
  mov    %r8,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint8_t *edge_matrix_left(uint8_t *data, int y, int x, int width, int size) {
  int median = size / 2;
  int index = 0;
  int yl = (y - median) * width;
  int yh = (y + median) * width;
  int xl = x;
  int xh = x + median;
  uint8_t *matrix = malloc(size * size);
  if (!matrix) {
    return NULL;
  }
  for (int row = yl; row <= yh; row += width) {
    for (int i = 0; i < median; ++i) {
      matrix[index] = data[row + xl];
      index++;
    }
    for (int col = xl; col <= xh; ++col) {
      matrix[index] = data[row + col];
      index++;
    }
  }
  return matrix;
}
```
user: What is the c source code of the assembly code below?

```asm
<edge_matrix_left>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %r14d,%edi
  push   %r12
  imul   %r14d,%edi
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  shr    $0x1f,%ebx
  add    %r8d,%ebx
  sar    %ebx
  sub    $0x28,%rsp
  lea    (%rbx,%rsi,1),%r8d
  sub    %ebx,%r12d
  mov    %ecx,(%rsp)
  lea    (%rbx,%rdx,1),%ebp
  imul   %ecx,%r8d
  imul   %ecx,%r12d
  mov    %r8d,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,%r10
  test   %rax,%rax
  je     L12
  cmp    0xc(%rsp),%r12d
  jg     L12
  movslq %r12d,%rax
  movslq (%rsp),%r11
  xor    %edi,%edi
  lea    0x0(%r13,%rax,4),%rdx
  movslq %r15d,%rax
  mov    %rax,0x10(%rsp)
  neg    %rax
  mov    %r11,%r9
  shl    $0x2,%r11
  shl    $0x2,%rax
  mov    %rax,0x18(%rsp)
  mov    %ebp,%eax
  sub    %r15d,%eax
  lea    0x1(%rax),%r8d
  nopl   0x0(%rax,%rax,1)
L47:
  cmp    $0x1,%r14d
  jle    L33
  lea    (%r15,%r12,1),%eax
  mov    %rdx,(%rsp)
  cltq
  lea    0x0(%r13,%rax,4),%rsi
  movslq %edi,%rax
  lea    (%r10,%rax,4),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L25:
  mov    (%rsi),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L25
  xor    %ecx,%ecx
  lea    -0x1(%rbx),%eax
  cmp    $0x1,%r14d
  mov    (%rsp),%rdx
  cmovle %ecx,%eax
  lea    0x1(%rdi,%rax,1),%edi
L33:
  cmp    %ebp,%r15d
  jg     L63
  mov    0x18(%rsp),%rcx
  movslq %edi,%rax
  lea    (%rcx,%rax,4),%rcx
  mov    0x10(%rsp),%rax
  add    %r10,%rcx
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rdx,%rax,4),%esi
  mov    %esi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L15
  add    %r8d,%edi
L63:
  add    %r9d,%r12d
  add    %r11,%rdx
  cmp    %r12d,0xc(%rsp)
  jge    L47
L12:
  add    $0x28,%rsp
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint8_t *edge_matrix_left(uint8_t *data, int y, int x, int width, int size) {
  int median = size / 2;
  int index = 0;
  int yl = (y - median) * width;
  int yh = (y + median) * width;
  int xl = x;
  int xh = x + median;
  uint8_t *matrix = malloc(size * size);
  if (!matrix) {
    return NULL;
  }
  for (int row = yl; row <= yh; row += width) {
    for (int i = 0; i < median; ++i) {
      matrix[index] = data[row + xl];
      index++;
    }
    for (int col = xl; col <= xh; ++col) {
      matrix[index] = data[row + col];
      index++;
    }
  }
  return matrix;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<card_can_be_stacked>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L64
  mov    $0x1,%eax
  jmp    L46
L64:
  cmpl   $0xfffffffe,-0x4(%rbp)
  jne    L23
  mov    $0x0,%eax
  jmp    L46
L23:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L75
  mov    $0x0,%eax
  jmp    L46
L75:
  cmpl   $0xfffffffe,-0x8(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L46
L38:
  cmpl   $0xfffffffd,-0x4(%rbp)
  jne    L43
  mov    $0x0,%eax
  jmp    L46
L43:
  cmpl   $0xfffffffd,-0x8(%rbp)
  jne    L106
  mov    $0x0,%eax
  jmp    L46
L106:
  mov    -0x4(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  cmp    %eax,%ecx
  sete   %al
  movzbl %al,%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
bool card_can_be_stacked(int top, int bot) {
  if (top == -1)
    return true;
  if (top == -2)
    return false;
  if (bot == -1)
    return false;
  if (bot == -2)
    return false;
  if (top == -3)
    return false;
  if (bot == -3)
    return false;
  return ((top / 4) == (bot / 4));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<card_can_be_stacked>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffffff,%edi
  je     L16
  lea    0x3(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L22
  lea    0x3(%rsi),%eax
  cmp    $0x2,%eax
  ja     L1
L22:
  mov    $0x0,%eax
L16:
  ret
L1:
  lea    0x3(%rdi),%edx
  test   %edi,%edi
  cmovns %edi,%edx
  sar    $0x2,%edx
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool card_can_be_stacked(int top, int bot) {
  if (top == -1)
    return true;
  if (top == -2)
    return false;
  if (bot == -1)
    return false;
  if (bot == -2)
    return false;
  if (top == -3)
    return false;
  if (bot == -3)
    return false;
  return ((top / 4) == (bot / 4));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<card_can_be_stacked>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffffff,%edi
  je     L11
  lea    0x3(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L0
  lea    0x3(%rsi),%edx
  cmp    $0x2,%edx
  ja     L22
L0:
  xor    %eax,%eax
L11:
  ret
  nopl   0x0(%rax)
L22:
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x2,%eax
  test   %esi,%esi
  cmovns %esi,%edx
  sar    $0x2,%edx
  cmp    %edx,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool card_can_be_stacked(int top, int bot) {
  if (top == -1)
    return true;
  if (top == -2)
    return false;
  if (bot == -1)
    return false;
  if (bot == -2)
    return false;
  if (top == -3)
    return false;
  if (bot == -3)
    return false;
  return ((top / 4) == (bot / 4));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<card_can_be_stacked>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffffff,%edi
  je     L24
  lea    0x3(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L8
  lea    0x3(%rsi),%edx
  cmp    $0x2,%edx
  ja     L21
L8:
  xor    %eax,%eax
L24:
  ret
  nopl   0x0(%rax)
L21:
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x2,%eax
  test   %esi,%esi
  cmovns %esi,%edx
  sar    $0x2,%edx
  cmp    %edx,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool card_can_be_stacked(int top, int bot) {
  if (top == -1)
    return true;
  if (top == -2)
    return false;
  if (bot == -1)
    return false;
  if (bot == -2)
    return false;
  if (top == -3)
    return false;
  if (bot == -3)
    return false;
  return ((top / 4) == (bot / 4));
}
```