ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bt_sendRoom>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x400,%edi
  push   %rbp
  call   <malloc@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D2(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <bt_send@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: PRIVMSG %s :%s


assistant: ```c
int bt_sendRoom(char *room, char *msg) {
  char *message = malloc(sizeof(char) * 1024);
  sprintf(message, "PRIVMSG %s :%s\r\n", room, msg);
  bt_send(message);
  free(message);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L6
  movl   $0xf,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fibo_lib@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo_lib(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L7
  mov    $0x0,%eax
  ret
L7:
  sub    $0x8,%rsp
  mov    $0xf,%edi
  call   <fibo_lib@plt>
  mov    %eax,%edx
  mov    $0xf,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string

tool: D7: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo_lib(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L6
  xor    %eax,%eax
  ret
L6:
  push   %rax
  mov    $0xf,%edi
  call   <fibo_lib@plt>
  mov    $0xf,%esi
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo_lib(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L9
  xor    %eax,%eax
  ret
L9:
  push   %rax
  mov    $0xf,%edi
  call   <fibo_lib@plt>
  mov    $0xf,%esi
  lea    D7(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo_lib(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__syscall0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  int    $0x95
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long __syscall0(long n) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n) : "memory");
  return __ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__syscall0>:
  endbr64
  mov    %rdi,%rax
  int    $0x95
  ret
```

assistant: ```c
long __syscall0(long n) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n) : "memory");
  return __ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__syscall0>:
  endbr64
  mov    %rdi,%rax
  int    $0x95
  ret
```

assistant: ```c
long __syscall0(long n) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n) : "memory");
  return __ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__syscall0>:
  endbr64
  mov    %rdi,%rax
  int    $0x95
  ret
```

assistant: ```c
long __syscall0(long n) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n) : "memory");
  return __ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skype_feat2code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L35
  mov    $0x0,%eax
  jmp    L60
L35:
  mov    -0x8(%rbp),%rax
  lea    D26(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L115
  mov    $0x1,%eax
  jmp    L60
L115:
  mov    -0x8(%rbp),%rax
  lea    D58(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L30
  mov    $0x2,%eax
  jmp    L60
L30:
  mov    -0x8(%rbp),%rax
  lea    D40(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L106
  mov    $0x3,%eax
  jmp    L60
L106:
  mov    -0x8(%rbp),%rax
  lea    D53(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L63
  mov    $0x4,%eax
  jmp    L60
L63:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x5,%eax
  jmp    L60
L8:
  mov    $0xffffffff,%eax
L60:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D58
data_type: string
name: read_data
arguments: tag: D40
data_type: string
name: read_data
arguments: tag: D53
data_type: string
name: read_data
arguments: tag: D14
data_type: string

tool: D22: PKTSIZE

tool: D26: MAXDELPKTSIZE

tool: D58: AVGIPG

tool: D40: PKTRATE

tool: D53: BITRATE

tool: D14: AVGPKT

assistant: ```c
int skype_feat2code(char *str) {
  if (!strcmp(str, "PKTSIZE"))
    return 0;
  if (!strcmp(str, "MAXDELPKTSIZE"))
    return 1;
  if (!strcmp(str, "AVGIPG"))
    return 2;
  if (!strcmp(str, "PKTRATE"))
    return 3;
  if (!strcmp(str, "BITRATE"))
    return 4;
  if (!strcmp(str, "AVGPKT"))
    return 5;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skype_feat2code>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D31(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L9
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L9
  lea    D55(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L9
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x3,%eax
  test   %edx,%edx
  je     L9
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x4,%eax
  test   %edx,%edx
  je     L9
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x6,%eax
  sub    $0x1,%eax
L9:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D31
data_type: string
name: disassemble_data
arguments: data_label: D17
data_type: string
name: disassemble_data
arguments: data_label: D55
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D7
data_type: string
name: disassemble_data
arguments: data_label: D28
data_type: string

tool: D31: PKTSIZE

tool: D17: MAXDELPKTSIZE

tool: D55: AVGIPG

tool: D29: PKTRATE

tool: D7: BITRATE

tool: D28: AVGPKT

assistant: ```c
int skype_feat2code(char *str) {
  if (!strcmp(str, "PKTSIZE"))
    return 0;
  if (!strcmp(str, "MAXDELPKTSIZE"))
    return 1;
  if (!strcmp(str, "AVGIPG"))
    return 2;
  if (!strcmp(str, "PKTRATE"))
    return 3;
  if (!strcmp(str, "BITRATE"))
    return 4;
  if (!strcmp(str, "AVGPKT"))
    return 5;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skype_feat2code>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L19
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L19
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8d,%r8d
  je     L19
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x3,%eax
  test   %r8d,%r8d
  je     L19
  lea    D52(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x4,%eax
  test   %r8d,%r8d
  je     L19
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x6,%eax
  sub    $0x1,%eax
L19:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D46
datatype: string
name: disassemble_data
arguments: data_tag: D30
datatype: string
name: disassemble_data
arguments: data_tag: D35
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D52
datatype: string
name: disassemble_data
arguments: data_tag: D44
datatype: string

tool: D46: PKTSIZE

tool: D30: MAXDELPKTSIZE

tool: D35: AVGIPG

tool: D2: PKTRATE

tool: D52: BITRATE

tool: D44: AVGPKT

assistant: ```c
int skype_feat2code(char *str) {
  if (!strcmp(str, "PKTSIZE"))
    return 0;
  if (!strcmp(str, "MAXDELPKTSIZE"))
    return 1;
  if (!strcmp(str, "AVGIPG"))
    return 2;
  if (!strcmp(str, "PKTRATE"))
    return 3;
  if (!strcmp(str, "BITRATE"))
    return 4;
  if (!strcmp(str, "AVGPKT"))
    return 5;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skype_feat2code>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L25
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L25
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8d,%r8d
  je     L25
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x3,%eax
  test   %r8d,%r8d
  je     L25
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x4,%eax
  test   %r8d,%r8d
  je     L25
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x6,%eax
  sub    $0x1,%eax
L25:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D45
datatype: string
name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D0
datatype: string

tool: D9: PKTSIZE

tool: D7: MAXDELPKTSIZE

tool: D16: AVGIPG

tool: D45: PKTRATE

tool: D20: BITRATE

tool: D0: AVGPKT

assistant: ```c
int skype_feat2code(char *str) {
  if (!strcmp(str, "PKTSIZE"))
    return 0;
  if (!strcmp(str, "MAXDELPKTSIZE"))
    return 1;
  if (!strcmp(str, "AVGIPG"))
    return 2;
  if (!strcmp(str, "PKTRATE"))
    return 3;
  if (!strcmp(str, "BITRATE"))
    return 4;
  if (!strcmp(str, "AVGPKT"))
    return 5;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L6
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fill_buffer@plt>
  mov    $0x0,%eax
  call   <print_buffer@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D3: printf => %f


tool: D4: FBSTP  => 

assistant: ```c
int main(int argc, char *argv[]) {
  double x;
  int i;
  for (i = 1; i < argc; i++) {
    x = atof(argv[i]);
    printf("printf => %f\n", x);
    printf("FBSTP  => ");
    fill_buffer(x);
    print_buffer();
    putchar('\n');
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r14
  lea    D17(%rip),%r13
  lea    D1(%rip),%r12
L0:
  mov    0x0(%rbp),%rdi
  call   <atof@plt>
  movq   %xmm0,%rbx
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  call   <fill_buffer@plt>
  mov    $0x0,%eax
  call   <print_buffer@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L0
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D17: printf => %f


tool: D1: FBSTP  => 

assistant: ```c
int main(int argc, char *argv[]) {
  double x;
  int i;
  for (i = 1; i < argc; i++) {
    x = atof(argv[i]);
    printf("printf => %f\n", x);
    printf("FBSTP  => ");
    fill_buffer(x);
    print_buffer();
    putchar('\n');
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L18
  push   %r13
  lea    -0x2(%rdi),%eax
  push   %r12
  lea    0x10(%rsi,%rax,8),%r13
  lea    D6(%rip),%r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atof@plt>
  mov    %r12,%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <fill_buffer@plt>
  xor    %eax,%eax
  call   <print_buffer@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D6: printf => %f


tool: D18: FBSTP  => 

assistant: ```c
int main(int argc, char *argv[]) {
  double x;
  int i;
  for (i = 1; i < argc; i++) {
    x = atof(argv[i]);
    printf("printf => %f\n", x);
    printf("FBSTP  => ");
    fill_buffer(x);
    print_buffer();
    putchar('\n');
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L19
  push   %r13
  lea    -0x2(%rdi),%eax
  push   %r12
  lea    0x10(%rsi,%rax,8),%r13
  lea    D14(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atof@plt>
  mov    %r12,%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <fill_buffer@plt>
  xor    %eax,%eax
  call   <print_buffer@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type_guessed: string
name: unpack_data
arguments: label: D19
type_guessed: string

tool: D14: printf => %f


tool: D19: FBSTP  => 

assistant: ```c
int main(int argc, char *argv[]) {
  double x;
  int i;
  for (i = 1; i < argc; i++) {
    x = atof(argv[i]);
    printf("printf => %f\n", x);
    printf("FBSTP  => ");
    fill_buffer(x);
    print_buffer();
    putchar('\n');
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<euler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <f@plt>
  add    $0x20,%rsp
  fstpt  -0x10(%rbp)
  fldl   -0x18(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fldt   0x20(%rbp)
  faddp  %st,%st(1)
  fstpt  0x20(%rbp)
  fldt   0x20(%rbp)
  leave
  ret
```

assistant: ```c
long double euler(long double x, long double y, double h) {
  long double k1;
  k1 = f(x, y);
  y = y + h * k1;
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<euler>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <f@plt>
  fmull  0x28(%rsp)
  fldt   0x50(%rsp)
  faddp  %st,%st(1)
  add    $0x38,%rsp
  ret
```

assistant: ```c
long double euler(long double x, long double y, double h) {
  long double k1;
  k1 = f(x, y);
  y = y + h * k1;
  return y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<euler>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <f@plt>
  fmull  0x28(%rsp)
  fldt   0x50(%rsp)
  add    $0x38,%rsp
  faddp  %st,%st(1)
  ret
```

assistant: ```c
long double euler(long double x, long double y, double h) {
  long double k1;
  k1 = f(x, y);
  y = y + h * k1;
  return y;
}
```
user: What is the c source code of the assembly code below?

```asm
<euler>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <f@plt>
  fmull  0x28(%rsp)
  fldt   0x50(%rsp)
  add    $0x38,%rsp
  faddp  %st,%st(1)
  ret
```

assistant: ```c
long double euler(long double x, long double y, double h) {
  long double k1;
  k1 = f(x, y);
  y = y + h * k1;
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x39,-0x9(%rbp)
  lea    -0x11(%rbp),%rax
  mov    $0x9,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <crc32c@plt>
  cmp    $0xe3069283,%eax
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char test[] = {'1', '2', '3', '4', '5', '6', '7', '8', '9'};
  return crc32c(0, test, sizeof(test)) == 0xe3069283 ? 0 : 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x39,0x17(%rsp)
  lea    0xf(%rsp),%rsi
  mov    $0x9,%edx
  mov    $0x0,%edi
  call   <crc32c@plt>
  cmp    $0xe3069283,%eax
  setne  %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char test[] = {'1', '2', '3', '4', '5', '6', '7', '8', '9'};
  return crc32c(0, test, sizeof(test)) == 0xe3069283 ? 0 : 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %edi,%edi
  mov    $0x9,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3837363534333231,%rax
  lea    0xf(%rsp),%rsi
  movb   $0x39,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  call   <crc32c@plt>
  cmp    $0xe3069283,%eax
  setne  %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char test[] = {'1', '2', '3', '4', '5', '6', '7', '8', '9'};
  return crc32c(0, test, sizeof(test)) == 0xe3069283 ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %edi,%edi
  mov    $0x9,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3837363534333231,%rax
  lea    0xf(%rsp),%rsi
  movb   $0x39,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  call   <crc32c@plt>
  cmp    $0xe3069283,%eax
  setne  %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char test[] = {'1', '2', '3', '4', '5', '6', '7', '8', '9'};
  return crc32c(0, test, sizeof(test)) == 0xe3069283 ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 4;
  a /= 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 4;
  a /= 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 4;
  a /= 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 4;
  a /= 2;
}
```