ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<functionR>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  pxor   %xmm0,%xmm0
  sub    $0x30,%rsp
  mov    (%rbx),%r8d
  mov    %rsp,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <toUint8@plt>
  mov    0x4(%rbx),%r8d
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <toUint8@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <toUint32@plt>
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  mov    %eax,(%rbx)
  call   <toUint32@plt>
  mov    %eax,0x4(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void functionR(uint32_t *buf) {
  uint8_t s[8] = {0x00};
  toUint8(s + 0, s + 1, s + 2, s + 3, buf[0]);
  toUint8(s + 4, s + 5, s + 6, s + 7, buf[1]);
  buf[0] = toUint32(s[4], s[5], s[2], s[3]);
  buf[1] = toUint32(s[0], s[1], s[6], s[7]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    0x18(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    0x20(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    0x28(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    0x30(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  mov    0x38(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  mov    0x40(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  mov    0x48(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    0x50(%rbp),%rax
  mov    %rax,-0x80(%rbp)
  mov    0x58(%rbp),%rax
  mov    %rax,-0x88(%rbp)
  mov    0x60(%rbp),%rax
  mov    %rax,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%r9
  mov    -0x38(%rbp),%r8
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  push   -0x48(%rbp)
  push   -0x78(%rbp)
  push   -0x80(%rbp)
  push   -0x30(%rbp)
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  lea    -0xc(%rbp),%rdi
  push   %rdi
  mov    0x68(%rbp),%edi
  push   %rdi
  push   $0x2
  push   -0x70(%rbp)
  push   -0x68(%rbp)
  push   -0x60(%rbp)
  push   -0x58(%rbp)
  push   -0x50(%rbp)
  push   -0x90(%rbp)
  push   -0x88(%rbp)
  mov    %rax,%rdi
  call   <calc_cons_u@plt>
  add    $0xa0,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int calc_code(const unsigned char *aa0, int n0, const unsigned char *aa1, int n1, struct a_struct *aln, struct a_res_str *a_res, struct pstruct *ppst, struct dyn_string_str *align_code_dyn, const unsigned char *ann_arr, const unsigned char *aa0a, const struct annot_str *annot0_p, const unsigned char *aa1a, const struct annot_str *annot1_p, struct dyn_string_str *annot_code_dyn, int *score_delta, struct f_struct *f_str, void *pstat_void, int display_code) {
  int nc;
  return calc_cons_u(aa0, n0, aa1, n1, a_res, ppst, f_str, pstat_void, ann_arr, aa0a, annot0_p, aa1a, annot1_p, 2, display_code, &nc, NULL, NULL, NULL, NULL, NULL, NULL, aln, score_delta, annot_code_dyn, align_code_dyn);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calc_code>:
  endbr64
  sub    $0x18,%rsp
  mov    %r9,%rax
  mov    %fs:0x28,%r9
  mov    %r9,0x8(%rsp)
  xor    %r9d,%r9d
  push   0x28(%rsp)
  push   0x60(%rsp)
  push   0x70(%rsp)
  push   %r8
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  lea    0x54(%rsp),%r8
  push   %r8
  mov    0xd0(%rsp),%r8d
  push   %r8
  push   $0x2
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0x100(%rsp)
  push   0x100(%rsp)
  mov    0xc0(%rsp),%r9
  mov    %rax,%r8
  call   <calc_cons_u@plt>
  add    $0xa0,%rsp
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int calc_code(const unsigned char *aa0, int n0, const unsigned char *aa1, int n1, struct a_struct *aln, struct a_res_str *a_res, struct pstruct *ppst, struct dyn_string_str *align_code_dyn, const unsigned char *ann_arr, const unsigned char *aa0a, const struct annot_str *annot0_p, const unsigned char *aa1a, const struct annot_str *annot1_p, struct dyn_string_str *annot_code_dyn, int *score_delta, struct f_struct *f_str, void *pstat_void, int display_code) {
  int nc;
  return calc_cons_u(aa0, n0, aa1, n1, a_res, ppst, f_str, pstat_void, ann_arr, aa0a, annot0_p, aa1a, annot1_p, 2, display_code, &nc, NULL, NULL, NULL, NULL, NULL, NULL, aln, score_delta, annot_code_dyn, align_code_dyn);
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_code>:
  endbr64
  sub    $0x18,%rsp
  mov    %r9,%rax
  mov    %fs:0x28,%r9
  mov    %r9,0x8(%rsp)
  xor    %r9d,%r9d
  push   0x28(%rsp)
  push   0x60(%rsp)
  push   0x70(%rsp)
  push   %r8
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  lea    0x54(%rsp),%r8
  push   %r8
  mov    0xd0(%rsp),%r8d
  push   %r8
  mov    %rax,%r8
  push   $0x2
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0x100(%rsp)
  push   0x100(%rsp)
  mov    0xc0(%rsp),%r9
  call   <calc_cons_u@plt>
  add    $0xa0,%rsp
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int calc_code(const unsigned char *aa0, int n0, const unsigned char *aa1, int n1, struct a_struct *aln, struct a_res_str *a_res, struct pstruct *ppst, struct dyn_string_str *align_code_dyn, const unsigned char *ann_arr, const unsigned char *aa0a, const struct annot_str *annot0_p, const unsigned char *aa1a, const struct annot_str *annot1_p, struct dyn_string_str *annot_code_dyn, int *score_delta, struct f_struct *f_str, void *pstat_void, int display_code) {
  int nc;
  return calc_cons_u(aa0, n0, aa1, n1, a_res, ppst, f_str, pstat_void, ann_arr, aa0a, annot0_p, aa1a, annot1_p, 2, display_code, &nc, NULL, NULL, NULL, NULL, NULL, NULL, aln, score_delta, annot_code_dyn, align_code_dyn);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_code>:
  endbr64
  sub    $0x18,%rsp
  mov    %r9,%rax
  mov    %fs:0x28,%r9
  mov    %r9,0x8(%rsp)
  xor    %r9d,%r9d
  push   0x28(%rsp)
  push   0x60(%rsp)
  push   0x70(%rsp)
  push   %r8
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  lea    0x54(%rsp),%r8
  push   %r8
  mov    0xd0(%rsp),%r8d
  push   %r8
  mov    %rax,%r8
  push   $0x2
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0xb8(%rsp)
  push   0x100(%rsp)
  push   0x100(%rsp)
  mov    0xc0(%rsp),%r9
  call   <calc_cons_u@plt>
  add    $0xa0,%rsp
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int calc_code(const unsigned char *aa0, int n0, const unsigned char *aa1, int n1, struct a_struct *aln, struct a_res_str *a_res, struct pstruct *ppst, struct dyn_string_str *align_code_dyn, const unsigned char *ann_arr, const unsigned char *aa0a, const struct annot_str *annot0_p, const unsigned char *aa1a, const struct annot_str *annot1_p, struct dyn_string_str *annot_code_dyn, int *score_delta, struct f_struct *f_str, void *pstat_void, int display_code) {
  int nc;
  return calc_cons_u(aa0, n0, aa1, n1, a_res, ppst, f_str, pstat_void, ann_arr, aa0a, annot0_p, aa1a, annot1_p, 2, display_code, &nc, NULL, NULL, NULL, NULL, NULL, NULL, aln, score_delta, annot_code_dyn, align_code_dyn);
}
```
user: What is the c source code of the assembly code below:

```asm
<log_nxdomain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <string@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ip@plt>
  mov    $0x0,%eax
  call   <space@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <number@plt>
  mov    $0x0,%eax
  call   <space@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <name@plt>
  mov    $0x0,%eax
  call   <line@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1:      nxdomain 

assistant: ```c
void log_nxdomain(const char server[4], const char *q, unsigned int ttl) {
  string("     nxdomain ");
  ip(server);
  space();
  number(ttl);
  space();
  name(q);
  line();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<log_nxdomain>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  lea    D5(%rip),%rdi
  call   <string@plt>
  mov    %r12,%rdi
  call   <ip@plt>
  mov    $0x0,%eax
  call   <space@plt>
  mov    %ebp,%edi
  call   <number@plt>
  mov    $0x0,%eax
  call   <space@plt>
  mov    %rbx,%rdi
  call   <name@plt>
  mov    $0x0,%eax
  call   <line@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string

tool: D5:      nxdomain 

assistant: ```c
void log_nxdomain(const char server[4], const char *q, unsigned int ttl) {
  string("     nxdomain ");
  ip(server);
  space();
  number(ttl);
  space();
  name(q);
  line();
}
```
user: What is the c source code of the assembly code below?

```asm
<log_nxdomain>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    D7(%rip),%rdi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  call   <string@plt>
  mov    %r13,%rdi
  call   <ip@plt>
  xor    %eax,%eax
  call   <space@plt>
  mov    %r12d,%edi
  call   <number@plt>
  xor    %eax,%eax
  call   <space@plt>
  mov    %rbp,%rdi
  call   <name@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10c0 <line@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7:      nxdomain 

assistant: ```c
void log_nxdomain(const char server[4], const char *q, unsigned int ttl) {
  string("     nxdomain ");
  ip(server);
  space();
  number(ttl);
  space();
  name(q);
  line();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_nxdomain>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    D8(%rip),%rdi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  call   <string@plt>
  mov    %r13,%rdi
  call   <ip@plt>
  xor    %eax,%eax
  call   <space@plt>
  mov    %r12d,%edi
  call   <number@plt>
  xor    %eax,%eax
  call   <space@plt>
  mov    %rbp,%rdi
  call   <name@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10c0 <line@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8:      nxdomain 

assistant: ```c
void log_nxdomain(const char server[4], const char *q, unsigned int ttl) {
  string("     nxdomain ");
  ip(server);
  space();
  number(ttl);
  space();
  name(q);
  line();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D5
type: string

tool: D1: a + b = %i + %i = %i


tool: D5: *ptr + b = %i + %i = %i


assistant: ```c
int main(char argc, char **argv) {
  void *ptr;
  int a, b;
  a = 5;
  b = 2;
  ptr = (int *)&a;
  printf("a + b = %i + %i = %i\n", a, b, a + b);
  printf("*ptr + b = %i + %i = %i\n", *(int *)ptr, b, *((int *)ptr) + b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D17: a + b = %i + %i = %i


tool: D5: *ptr + b = %i + %i = %i


assistant: ```c
int main(char argc, char **argv) {
  void *ptr;
  int a, b;
  a = 5;
  b = 2;
  ptr = (int *)&a;
  printf("a + b = %i + %i = %i\n", a, b, a + b);
  printf("*ptr + b = %i + %i = %i\n", *(int *)ptr, b, *((int *)ptr) + b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D13: a + b = %i + %i = %i


tool: D8: *ptr + b = %i + %i = %i


assistant: ```c
int main(char argc, char **argv) {
  void *ptr;
  int a, b;
  a = 5;
  b = 2;
  ptr = (int *)&a;
  printf("a + b = %i + %i = %i\n", a, b, a + b);
  printf("*ptr + b = %i + %i = %i\n", *(int *)ptr, b, *((int *)ptr) + b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D19
data_type: string

tool: D8: a + b = %i + %i = %i


tool: D19: *ptr + b = %i + %i = %i


assistant: ```c
int main(char argc, char **argv) {
  void *ptr;
  int a, b;
  a = 5;
  b = 2;
  ptr = (int *)&a;
  printf("a + b = %i + %i = %i\n", a, b, a + b);
  printf("*ptr + b = %i + %i = %i\n", *(int *)ptr, b, *((int *)ptr) + b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  mov    $0x1,%eax
  jmp    L4
L9:
  cmpw   $0x0,-0x4(%rbp)
  je     L38
  mov    $0x1,%eax
  jmp    L4
L38:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int t3(unsigned short a) {
  if (a & 1)
    return 1;
  else if (a)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<t3>:
  endbr64
  test   %di,%di
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int t3(unsigned short a) {
  if (a & 1)
    return 1;
  else if (a)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<t3>:
  endbr64
  xor    %eax,%eax
  test   %di,%di
  setne  %al
  ret
```

assistant: ```c
int t3(unsigned short a) {
  if (a & 1)
    return 1;
  else if (a)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<t3>:
  endbr64
  xor    %eax,%eax
  test   %di,%di
  setne  %al
  ret
```

assistant: ```c
int t3(unsigned short a) {
  if (a & 1)
    return 1;
  else if (a)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char check_code(const char *buffer, size_t size) {
  unsigned int crc = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    crc = (crc + buffer[i]) % 0x100;
  }
  return crc & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_code>:
  endbr64
  test   %rsi,%rsi
  je     L8
  mov    %rdi,%rdx
  add    %rsi,%rdi
  mov    $0x0,%eax
L3:
  add    (%rdx),%al
  movzbl %al,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L3
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char check_code(const char *buffer, size_t size) {
  unsigned int crc = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    crc = (crc + buffer[i]) % 0x100;
  }
  return crc & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_code>:
  endbr64
  test   %rsi,%rsi
  je     L15
  add    %rdi,%rsi
  xor    %edx,%edx
  xchg   %ax,%ax
L12:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl %al,%edx
  cmp    %rdi,%rsi
  jne    L12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char check_code(const char *buffer, size_t size) {
  unsigned int crc = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    crc = (crc + buffer[i]) % 0x100;
  }
  return crc & 0xff;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_code>:
  endbr64
  test   %rsi,%rsi
  je     L4
  add    %rdi,%rsi
  xor    %edx,%edx
  xchg   %ax,%ax
L10:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl %al,%edx
  cmp    %rdi,%rsi
  jne    L10
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char check_code(const char *buffer, size_t size) {
  unsigned int crc = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    crc = (crc + buffer[i]) % 0x100;
  }
  return crc & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdi
  lea    -0x10(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <smallest@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <largest@plt>
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string

tool: D31: Input five different integers: 

tool: D38: %d%d%d%d%d

tool: D0: Smallest is %d


tool: D26: Largest is %d


assistant: ```c
int main() {
  int num1, num2, num3, num4, num5;
  printf("Input five different integers: ");
  scanf("%d%d%d%d%d", &num1, &num2, &num3, &num4, &num5);
  printf("Smallest is %d\n", smallest(num1, num2, num3, num4, num5));
  printf("Largest is %d\n", largest(num1, num2, num3, num4, num5));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <smallest@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <largest@plt>
  mov    %eax,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string

tool: D1: Input five different integers: 

tool: D17: %d%d%d%d%d

tool: D25: Smallest is %d


tool: D27: Largest is %d


assistant: ```c
int main() {
  int num1, num2, num3, num4, num5;
  printf("Input five different integers: ");
  scanf("%d%d%d%d%d", &num1, &num2, &num3, &num4, &num5);
  printf("Smallest is %d\n", smallest(num1, num2, num3, num4, num5));
  printf("Largest is %d\n", largest(num1, num2, num3, num4, num5));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%r9
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <smallest@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0x4(%rsp),%edi
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  call   <largest@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string

tool: D28: Input five different integers: 

tool: D19: %d%d%d%d%d

tool: D23: Smallest is %d


tool: D32: Largest is %d


assistant: ```c
int main() {
  int num1, num2, num3, num4, num5;
  printf("Input five different integers: ");
  scanf("%d%d%d%d%d", &num1, &num2, &num3, &num4, &num5);
  printf("Smallest is %d\n", smallest(num1, num2, num3, num4, num5));
  printf("Largest is %d\n", largest(num1, num2, num3, num4, num5));
  return 0;
}
```