ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pseudo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L73
L89:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L92
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <code@plt>
  mov    -0x20(%rbp,%rax,4),%edx
  add    $0x1,%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  jmp    L63
L92:
  nop
L63:
  addl   $0x1,-0x2c(%rbp)
L73:
  mov    -0x2c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L89
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L88
L5:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L11
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <code@plt>
  mov    -0x20(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L2
  addl   $0x1,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <code@plt>
  mov    -0x20(%rbp,%rax,4),%edx
  sub    $0x1,%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  jmp    L2
L11:
  nop
L2:
  addl   $0x1,-0x24(%rbp)
L88:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L5
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  leave
  ret
```

assistant: ```c
int pseudo(char actual[], char guess[], int size) {
  int freq[4] = {0};
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    freq[code(guess[i])]++;
  }
  int pseudo = 0;
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    if (freq[code(actual[i])] > 0) {
      pseudo++;
      freq[code(actual[i])]--;
    }
  }
  return pseudo;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pseudo>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  test   %edx,%edx
  jle    L62
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    -0x1(%rdx),%r13d
  mov    %edx,%r14d
  mov    $0x0,%ebx
  jmp    L8
L51:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L66
L8:
  movzbl 0x0(%rbp,%rbx,1),%edi
  cmp    %dil,(%r12,%rbx,1)
  je     L51
  movsbl %dil,%edi
  call   <code@plt>
  addl   $0x1,(%rsp,%rax,4)
  jmp    L51
L66:
  mov    %r12,%rbx
  lea    0x1(%r12,%r13,1),%r13
  mov    $0x0,%r14d
  jmp    L40
L26:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  je     L48
L40:
  movzbl (%rbx),%edi
  cmp    0x0(%rbp),%dil
  je     L26
  movsbl %dil,%edi
  call   <code@plt>
  cmpl   $0x0,(%rsp,%rax,4)
  jle    L26
  add    $0x1,%r14d
  movsbl (%rbx),%edi
  call   <code@plt>
  subl   $0x1,(%rsp,%rax,4)
  jmp    L26
L62:
  mov    $0x0,%r14d
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    %r14d,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pseudo(char actual[], char guess[], int size) {
  int freq[4] = {0};
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    freq[code(guess[i])]++;
  }
  int pseudo = 0;
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    if (freq[code(actual[i])] > 0) {
      pseudo++;
      freq[code(actual[i])]--;
    }
  }
  return pseudo;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pseudo>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  test   %edx,%edx
  jle    L20
  mov    %rdi,%rbx
  mov    %rsi,%r12
  lea    -0x1(%rdx),%r13d
  mov    %edx,%r14d
  xor    %ebp,%ebp
  nop
L63:
  movsbl (%r12,%rbp,1),%edi
  cmp    %dil,(%rbx,%rbp,1)
  je     L48
  call   <code@plt>
  addl   $0x1,(%rsp,%rax,4)
L48:
  add    $0x1,%rbp
  cmp    %r14,%rbp
  jne    L63
  mov    %r12,%rbp
  lea    0x1(%rbx,%r13,1),%r12
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L22:
  movsbl (%rbx),%edi
  cmp    0x0(%rbp),%dil
  je     L72
  call   <code@plt>
  mov    (%rsp,%rax,4),%eax
  test   %eax,%eax
  jle    L72
  movsbl (%rbx),%edi
  add    $0x1,%r13d
  call   <code@plt>
  subl   $0x1,(%rsp,%rax,4)
L72:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  jne    L22
L67:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %r13d,%r13d
  jmp    L67
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pseudo(char actual[], char guess[], int size) {
  int freq[4] = {0};
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    freq[code(guess[i])]++;
  }
  int pseudo = 0;
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    if (freq[code(actual[i])] > 0) {
      pseudo++;
      freq[code(actual[i])]--;
    }
  }
  return pseudo;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pseudo>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  test   %edx,%edx
  jle    L27
  mov    %rdi,%rbx
  mov    %rsi,%r12
  lea    -0x1(%rdx),%r13d
  mov    %edx,%r14d
  xor    %ebp,%ebp
  nop
L22:
  movsbl (%r12,%rbp,1),%edi
  cmp    %dil,(%rbx,%rbp,1)
  je     L21
  call   <code@plt>
  addl   $0x1,(%rsp,%rax,4)
L21:
  add    $0x1,%rbp
  cmp    %r14,%rbp
  jne    L22
  mov    %r12,%rbp
  lea    0x1(%rbx,%r13,1),%r12
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%edi
  cmp    0x0(%rbp),%dil
  je     L14
  call   <code@plt>
  mov    (%rsp,%rax,4),%eax
  test   %eax,%eax
  jle    L14
  movsbl (%rbx),%edi
  add    $0x1,%r13d
  call   <code@plt>
  subl   $0x1,(%rsp,%rax,4)
L14:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  jne    L19
L61:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %r13d,%r13d
  jmp    L61
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pseudo(char actual[], char guess[], int size) {
  int freq[4] = {0};
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    freq[code(guess[i])]++;
  }
  int pseudo = 0;
  for (int i = 0; i < size; i++) {
    if (actual[i] == guess[i])
      continue;
    if (freq[code(actual[i])] > 0) {
      pseudo++;
      freq[code(actual[i])]--;
    }
  }
  return pseudo;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prumeruj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    -0x1c(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int prumeruj(unsigned int pole[], uint8_t len) {
  int i;
  uint32_t suma = 0;
  for (i = 0; i < len; i++) {
    suma += pole[i];
  }
  return (suma / len);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prumeruj>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  mov    $0x0,%eax
L15:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L15
L20:
  mov    $0x0,%edx
  div    %esi
  ret
L6:
  mov    $0x0,%eax
  jmp    L20
```

assistant: ```c
unsigned int prumeruj(unsigned int pole[], uint8_t len) {
  int i;
  uint32_t suma = 0;
  for (i = 0; i < len; i++) {
    suma += pole[i];
  }
  return (suma / len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prumeruj>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  jne    L5
  xor    %edx,%edx
  div    %esi
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int prumeruj(unsigned int pole[], uint8_t len) {
  int i;
  uint32_t suma = 0;
  for (i = 0; i < len; i++) {
    suma += pole[i];
  }
  return (suma / len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prumeruj>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L47
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L31:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L31
  movdqa %xmm0,%xmm1
  mov    %ecx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%cl
  je     L10
L46:
  movslq %edx,%rsi
  lea    0x0(,%rsi,4),%r8
  add    (%rdi,%rsi,4),%eax
  lea    0x1(%rdx),%esi
  cmp    %esi,%ecx
  jle    L10
  add    $0x2,%edx
  add    0x4(%rdi,%r8,1),%eax
  cmp    %edx,%ecx
  jle    L10
  add    0x8(%rdi,%r8,1),%eax
L10:
  xor    %edx,%edx
  div    %ecx
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
L47:
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L46
```

assistant: ```c
unsigned int prumeruj(unsigned int pole[], uint8_t len) {
  int i;
  uint32_t suma = 0;
  for (i = 0; i < len; i++) {
    suma += pole[i];
  }
  return (suma / len);
}
```
user: What is the c source code of the assembly code below?

```asm
<output_person>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L59:
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  jmp    L20
L85:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L66
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  jne    L85
L66:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  jne    L60
  addq   $0x1,-0x20(%rbp)
L60:
  cmpl   $0x0,-0x8(%rbp)
  jne    L29
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2c,%edi
  call   <fputc@plt>
  jmp    L52
L29:
  cmpl   $0x1,-0x4(%rbp)
  jne    L52
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2e,%edi
  call   <fputc@plt>
L52:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  nop
  nop
  leave
  ret
```

assistant: ```c
void output_person(FILE *fp, char *p) {
  int nseps = 0, nch;
  while (*p) {
    nch = 0;
    if (nseps)
      fprintf(fp, " ");
    while (*p && *p != '|') {
      fprintf(fp, "%c", *p++);
      nch++;
    }
    if (*p == '|')
      p++;
    if (nseps == 0)
      fprintf(fp, ",");
    else if (nch == 1)
      fprintf(fp, ".");
    nseps++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<output_person>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%r13d
  cmpb   $0x0,(%rsi)
  jne    L18
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    $0x0,%ebp
L53:
  cmp    $0x7c,%dil
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  test   %r13d,%r13d
  je     L72
  cmp    $0x1,%ebp
  je     L67
L57:
  add    $0x1,%r13d
  cmpb   $0x0,(%rbx)
  je     L52
  test   %r13d,%r13d
  jne    L71
L18:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L22
  cmp    $0x7c,%dil
  je     L22
  mov    $0x0,%ebp
L25:
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  add    $0x1,%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L53
  cmp    $0x7c,%dil
  jne    L25
  jmp    L53
L72:
  mov    %r12,%rsi
  mov    $0x2c,%edi
  call   <fputc@plt>
  add    $0x1,%r13d
  cmpb   $0x0,(%rbx)
  je     L52
L71:
  mov    %r12,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  jmp    L18
L67:
  mov    %r12,%rsi
  mov    $0x2e,%edi
  call   <fputc@plt>
  jmp    L57
```

assistant: ```c
void output_person(FILE *fp, char *p) {
  int nseps = 0, nch;
  while (*p) {
    nch = 0;
    if (nseps)
      fprintf(fp, " ");
    while (*p && *p != '|') {
      fprintf(fp, "%c", *p++);
      nch++;
    }
    if (*p == '|')
      p++;
    if (nseps == 0)
      fprintf(fp, ",");
    else if (nch == 1)
      fprintf(fp, ".");
    nseps++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<output_person>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L47
  nop
L45:
  xor    %ebp,%ebp
  cmp    $0x7c,%dil
  je     L70
  test   %dil,%dil
  je     L70
  nopl   (%rax)
L75:
  add    $0x1,%rbx
  mov    %r12,%rsi
  add    $0x1,%ebp
  call   <fputc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L70
  cmp    $0x7c,%dil
  jne    L75
L70:
  xor    %eax,%eax
  cmp    $0x7c,%dil
  sete   %al
  add    %rax,%rbx
  test   %r13d,%r13d
  je     L85
  cmp    $0x1,%ebp
  je     L5
L109:
  add    $0x1,%r13d
  cmpb   $0x0,(%rbx)
  je     L47
L51:
  mov    $0x20,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  movsbl (%rbx),%edi
  jmp    L45
  xchg   %ax,%ax
L85:
  mov    %r12,%rsi
  mov    $0x2c,%edi
  add    $0x1,%r13d
  call   <fputc@plt>
  cmpb   $0x0,(%rbx)
  jne    L51
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %r12,%rsi
  mov    $0x2e,%edi
  call   <fputc@plt>
  jmp    L109
```

assistant: ```c
void output_person(FILE *fp, char *p) {
  int nseps = 0, nch;
  while (*p) {
    nch = 0;
    if (nseps)
      fprintf(fp, " ");
    while (*p && *p != '|') {
      fprintf(fp, "%c", *p++);
      nch++;
    }
    if (*p == '|')
      p++;
    if (nseps == 0)
      fprintf(fp, ",");
    else if (nch == 1)
      fprintf(fp, ".");
    nseps++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<output_person>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L23
  nop
L101:
  xor    %ebp,%ebp
  cmp    $0x7c,%dil
  je     L64
  test   %dil,%dil
  je     L64
  nopl   (%rax)
L42:
  add    $0x1,%rbx
  mov    %r12,%rsi
  add    $0x1,%ebp
  call   <fputc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L64
  cmp    $0x7c,%dil
  jne    L42
L64:
  xor    %eax,%eax
  cmp    $0x7c,%dil
  sete   %al
  add    %rax,%rbx
  test   %r13d,%r13d
  je     L50
  cmp    $0x1,%ebp
  je     L41
L93:
  add    $0x1,%r13d
  cmpb   $0x0,(%rbx)
  je     L23
L26:
  mov    $0x20,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  movsbl (%rbx),%edi
  jmp    L101
  xchg   %ax,%ax
L50:
  mov    %r12,%rsi
  mov    $0x2c,%edi
  add    $0x1,%r13d
  call   <fputc@plt>
  cmpb   $0x0,(%rbx)
  jne    L26
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L41:
  mov    %r12,%rsi
  mov    $0x2e,%edi
  call   <fputc@plt>
  jmp    L93
```

assistant: ```c
void output_person(FILE *fp, char *p) {
  int nseps = 0, nch;
  while (*p) {
    nch = 0;
    if (nseps)
      fprintf(fp, " ");
    while (*p && *p != '|') {
      fprintf(fp, "%c", *p++);
      nch++;
    }
    if (*p == '|')
      p++;
    if (nseps == 0)
      fprintf(fp, ",");
    else if (nch == 1)
      fprintf(fp, ".");
    nseps++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_covar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_covar(argc, argv);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_covar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_covar(argc, argv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_covar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_covar(argc, argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    $0x1,%eax
  jmp    L6
L17:
  cmpq   $0x0,-0x18(%rbp)
  jns    L9
  negq   -0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L9
L37:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  cmpq   $0x0,-0x18(%rbp)
  jne    L37
  mov    -0x4(%rbp),%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int digits(long number, int radix) {
  int ans = 0;
  if (number == 0)
    return 1;
  if (number < 0) {
    number *= -1;
    ans++;
  }
  while (number != 0) {
    number /= radix;
    ans++;
  }
  return ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<digits>:
  endbr64
  mov    $0x1,%ecx
  test   %rdi,%rdi
  je     L4
  mov    $0x0,%ecx
  js     L7
L18:
  movslq %esi,%rsi
L12:
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  mov    %rax,%rdi
  add    $0x1,%ecx
  test   %rax,%rax
  jne    L12
L4:
  mov    %ecx,%eax
  ret
L7:
  neg    %rdi
  mov    $0x1,%ecx
  jmp    L18
```

assistant: ```c
int digits(long number, int radix) {
  int ans = 0;
  if (number == 0)
    return 1;
  if (number < 0) {
    number *= -1;
    ans++;
  }
  while (number != 0) {
    number /= radix;
    ans++;
  }
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<digits>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%r8d
  test   %rdi,%rdi
  je     L29
  mov    $0x0,%r8d
  js     L33
L32:
  movslq %esi,%rsi
  nopl   (%rax)
L3:
  cqto
  add    $0x1,%r8d
  idiv   %rsi
  test   %rax,%rax
  jne    L3
L29:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  neg    %rax
  mov    $0x1,%r8d
  jmp    L32
```

assistant: ```c
int digits(long number, int radix) {
  int ans = 0;
  if (number == 0)
    return 1;
  if (number < 0) {
    number *= -1;
    ans++;
  }
  while (number != 0) {
    number /= radix;
    ans++;
  }
  return ans;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<digits>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%r8d
  test   %rdi,%rdi
  je     L31
  mov    $0x0,%r8d
  js     L17
L19:
  movslq %esi,%rsi
  nopl   (%rax)
L2:
  cqto
  add    $0x1,%r8d
  idiv   %rsi
  test   %rax,%rax
  jne    L2
L31:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  neg    %rax
  mov    $0x1,%r8d
  jmp    L19
```

assistant: ```c
int digits(long number, int radix) {
  int ans = 0;
  if (number == 0)
    return 1;
  if (number < 0) {
    number *= -1;
    ans++;
  }
  while (number != 0) {
    number /= radix;
    ans++;
  }
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L16
L8:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cmp    %eax,0x18(%rbp)
  je     L18
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x18(%rbp)
L16:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L8
  jmp    L11
L18:
  nop
L11:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void comment(char **suboptionpp, int *i, int *Item_Ptr, char *subwrdptr, int *subnext, char **wrdpp, double vals[], int nwrd, int *N_Cntr) {
  *subnext = 1;
  while (*subnext) {
    if ((*i) + 1 == nwrd)
      break;
    (*i)++;
    Item_Ptr++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<comment>:
  endbr64
  mov    0x10(%rsp),%edx
  movl   $0x1,(%r8)
L3:
  mov    (%rsi),%eax
  add    $0x1,%eax
  cmp    %edx,%eax
  je     L17
  mov    %eax,(%rsi)
  cmpl   $0x0,(%r8)
  jne    L3
L17:
  ret
```

assistant: ```c
void comment(char **suboptionpp, int *i, int *Item_Ptr, char *subwrdptr, int *subnext, char **wrdpp, double vals[], int nwrd, int *N_Cntr) {
  *subnext = 1;
  while (*subnext) {
    if ((*i) + 1 == nwrd)
      break;
    (*i)++;
    Item_Ptr++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comment>:
  endbr64
  movl   $0x1,(%r8)
  mov    0x10(%rsp),%edx
  mov    (%rsi),%eax
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %eax,(%rsi)
  mov    (%r8),%ecx
  test   %ecx,%ecx
  je     L3
L11:
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L8
L3:
  ret
```

assistant: ```c
void comment(char **suboptionpp, int *i, int *Item_Ptr, char *subwrdptr, int *subnext, char **wrdpp, double vals[], int nwrd, int *N_Cntr) {
  *subnext = 1;
  while (*subnext) {
    if ((*i) + 1 == nwrd)
      break;
    (*i)++;
    Item_Ptr++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comment>:
  endbr64
  movl   $0x1,(%r8)
  mov    0x10(%rsp),%edx
  mov    (%rsi),%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,(%rsi)
  mov    (%r8),%ecx
  test   %ecx,%ecx
  je     L3
L29:
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L5
L3:
  ret
```

assistant: ```c
void comment(char **suboptionpp, int *i, int *Item_Ptr, char *subwrdptr, int *subnext, char **wrdpp, double vals[], int nwrd, int *N_Cntr) {
  *subnext = 1;
  while (*subnext) {
    if ((*i) + 1 == nwrd)
      break;
    (*i)++;
    Item_Ptr++;
  }
}
```