ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<convertsizetolong>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rdi
  xor    %r8d,%r8d
  jmp    L76
  nopl   0x0(%rax)
L10:
  lea    -0x31(%rax),%ecx
  cmp    $0x8,%cl
  ja     L16
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rcx
  movsbq %al,%rax
  lea    (%rax,%rcx,2),%r8
L44:
  cmp    $0x47,%dl
  jne    L55
  shl    $0x1e,%r8
L55:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L52
L76:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x30,%al
  jne    L10
  lea    (%r8,%r8,4),%r8
  add    %r8,%r8
L32:
  cmp    $0x4d,%dl
  jne    L44
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  shl    $0x14,%r8
  test   %al,%al
  jne    L76
L52:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    $0x4b,%dl
  jne    L32
  shl    $0xa,%r8
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long unsigned int convertsizetolong(char *sizestr) {
  long unsigned int answer = 0;
  int i = 0;
  while (sizestr[i] != '\0') {
    if (sizestr[i] == '0')
      answer *= 10;
    if (sizestr[i] >= '1' && sizestr[i] <= '9') {
      answer *= 10;
      answer += (sizestr[i] - '1' + 1);
    }
    if (sizestr[i] == 'k' || sizestr[i] == 'K')
      answer *= 1024;
    if (sizestr[i] == 'm' || sizestr[i] == 'M')
      answer *= (1024 * 1024);
    if (sizestr[i] == 'g' || sizestr[i] == 'G')
      answer *= (1024 * 1024 * 1024);
    i++;
  }
  return answer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convertsizetolong>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L79
  add    $0x1,%rdi
  xor    %r8d,%r8d
  jmp    L21
  nopl   0x0(%rax)
L98:
  lea    -0x31(%rax),%ecx
  cmp    $0x8,%cl
  ja     L62
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rcx
  movsbq %al,%rax
  lea    (%rax,%rcx,2),%r8
L63:
  cmp    $0x47,%dl
  jne    L55
  shl    $0x1e,%r8
L55:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L48
L21:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x30,%al
  jne    L98
  lea    (%r8,%r8,4),%r8
  add    %r8,%r8
L66:
  cmp    $0x4d,%dl
  jne    L63
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  shl    $0x14,%r8
  test   %al,%al
  jne    L21
L48:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  cmp    $0x4b,%dl
  jne    L66
  shl    $0xa,%r8
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L79:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long unsigned int convertsizetolong(char *sizestr) {
  long unsigned int answer = 0;
  int i = 0;
  while (sizestr[i] != '\0') {
    if (sizestr[i] == '0')
      answer *= 10;
    if (sizestr[i] >= '1' && sizestr[i] <= '9') {
      answer *= 10;
      answer += (sizestr[i] - '1' + 1);
    }
    if (sizestr[i] == 'k' || sizestr[i] == 'K')
      answer *= 1024;
    if (sizestr[i] == 'm' || sizestr[i] == 'M')
      answer *= (1024 * 1024);
    if (sizestr[i] == 'g' || sizestr[i] == 'G')
      answer *= (1024 * 1024 * 1024);
    i++;
  }
  return answer;
}
```
user: What is the c source code of the assembly code below?

```asm
<capi20_get_profile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <loadlib@plt>
  test   %rax,%rax
  jns    L9
  mov    $0x1009,%eax
  jmp    L15
L9:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fptr_capi20_get_profile@plt>
L15:
  leave
  ret
```

assistant: ```c
unsigned capi20_get_profile(unsigned Ctrl, unsigned char *Buf) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_get_profile(Ctrl, Buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<capi20_get_profile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <loadlib@plt>
  mov    %rax,%rdx
  mov    $0x1009,%eax
  test   %rdx,%rdx
  js     L6
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <fptr_capi20_get_profile@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned capi20_get_profile(unsigned Ctrl, unsigned char *Buf) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_get_profile(Ctrl, Buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<capi20_get_profile>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <loadlib@plt>
  test   %rax,%rax
  js     L6
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <fptr_capi20_get_profile@plt>
  nopl   (%rax)
L6:
  add    $0x8,%rsp
  mov    $0x1009,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned capi20_get_profile(unsigned Ctrl, unsigned char *Buf) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_get_profile(Ctrl, Buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<capi20_get_profile>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <loadlib@plt>
  test   %rax,%rax
  js     L4
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <fptr_capi20_get_profile@plt>
  nopl   (%rax)
L4:
  add    $0x8,%rsp
  mov    $0x1009,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned capi20_get_profile(unsigned Ctrl, unsigned char *Buf) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_get_profile(Ctrl, Buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <run_nonulls@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L11
L6:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addq   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L6
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t run(int moves[], size_t moves_len, int res[], size_t res_len) {
  size_t r = run_nonulls(moves, moves_len, res, res_len);
  for (size_t i = r; i < res_len; i++)
    res[i] = 0;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<run>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  call   <run_nonulls@plt>
  cmp    %rax,%rbx
  jbe    L16
  lea    0x0(%rbp,%rax,4),%rdx
  lea    0x0(%rbp,%rbx,4),%rcx
L17:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L17
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t run(int moves[], size_t moves_len, int res[], size_t res_len) {
  size_t r = run_nonulls(moves, moves_len, res, res_len);
  for (size_t i = r; i < res_len; i++)
    res[i] = 0;
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <run_nonulls@plt>
  mov    %rax,%r12
  cmp    %rax,%rbx
  jbe    L8
  sub    %rax,%rbx
  lea    0x0(%rbp,%rax,4),%rdi
  xor    %esi,%esi
  lea    0x0(,%rbx,4),%rdx
  call   <memset@plt>
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t run(int moves[], size_t moves_len, int res[], size_t res_len) {
  size_t r = run_nonulls(moves, moves_len, res, res_len);
  for (size_t i = r; i < res_len; i++)
    res[i] = 0;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<run>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <run_nonulls@plt>
  mov    %rax,%r12
  cmp    %rax,%rbx
  jbe    L1
  sub    %rax,%rbx
  lea    0x0(%rbp,%rax,4),%rdi
  xor    %esi,%esi
  lea    0x0(,%rbx,4),%rdx
  call   <memset@plt>
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t run(int moves[], size_t moves_len, int res[], size_t res_len) {
  size_t r = run_nonulls(moves, moves_len, res, res_len);
  for (size_t i = r; i < res_len; i++)
    res[i] = 0;
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<decryptStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L16:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  test   %al,%al
  je     L45
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L16
  jmp    L54
L45:
  nop
L54:
  addl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x4,-0x8(%rbp)
  jle    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decryptStrings(char strings[5][32], int key) {
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 32; j++) {
      if (strings[i][j] == '\0') {
        break;
      }
      strings[i][j] = strings[i][j] - key;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decryptStrings>:
  endbr64
  lea    0x20(%rdi),%rcx
  add    $0xc0,%rdi
  jmp    L45
L41:
  add    $0x20,%rcx
  cmp    %rdi,%rcx
  je     L4
L45:
  lea    -0x20(%rcx),%rax
L48:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L41
  sub    %esi,%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L48
  jmp    L41
L4:
  ret
```

assistant: ```c
void decryptStrings(char strings[5][32], int key) {
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 32; j++) {
      if (strings[i][j] == '\0') {
        break;
      }
      strings[i][j] = strings[i][j] - key;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decryptStrings>:
  endbr64
  lea    0x20(%rdi),%rcx
  add    $0xc0,%rdi
L34:
  lea    -0x20(%rcx),%rax
  jmp    L33
  nopl   (%rax)
L29:
  sub    %esi,%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  je     L5
L33:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L29
L5:
  add    $0x20,%rcx
  cmp    %rdi,%rcx
  jne    L34
  ret
```

assistant: ```c
void decryptStrings(char strings[5][32], int key) {
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 32; j++) {
      if (strings[i][j] == '\0') {
        break;
      }
      strings[i][j] = strings[i][j] - key;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<decryptStrings>:
  endbr64
  lea    0x20(%rdi),%rcx
  add    $0xc0,%rdi
L10:
  lea    -0x20(%rcx),%rax
  jmp    L0
  nopl   (%rax)
L37:
  sub    %esi,%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  je     L15
L0:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L37
L15:
  add    $0x20,%rcx
  cmp    %rdi,%rcx
  jne    L10
  ret
```

assistant: ```c
void decryptStrings(char strings[5][32], int key) {
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 32; j++) {
      if (strings[i][j] == '\0') {
        break;
      }
      strings[i][j] = strings[i][j] - key;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bio_phys_segments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bio_phys_segments(struct request_queue *x, struct bio *y) {
  int a;
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bio_phys_segments>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int bio_phys_segments(struct request_queue *x, struct bio *y) {
  int a;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bio_phys_segments>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int bio_phys_segments(struct request_queue *x, struct bio *y) {
  int a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bio_phys_segments>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int bio_phys_segments(struct request_queue *x, struct bio *y) {
  int a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<single_digit_bin_to_oct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L74
  mov    $0x30,%eax
  jmp    L24
L74:
  mov    -0x8(%rbp),%rax
  lea    D42(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
  mov    $0x31,%eax
  jmp    L24
L26:
  mov    -0x8(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L99
  mov    $0x32,%eax
  jmp    L24
L99:
  mov    -0x8(%rbp),%rax
  lea    D35(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x33,%eax
  jmp    L24
L7:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L78
  mov    $0x34,%eax
  jmp    L24
L78:
  mov    -0x8(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L52
  mov    $0x35,%eax
  jmp    L24
L52:
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L110
  mov    $0x36,%eax
  jmp    L24
L110:
  mov    $0x37,%eax
L24:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D42
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D35
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D30: 000

tool: D42: 001

tool: D28: 010

tool: D35: 011

tool: D14: 100

tool: D29: 101

tool: D9: 110

assistant: ```c
char single_digit_bin_to_oct(char *bin_dig) {
  if (strcmp(bin_dig, "000") == 0) {
    return '0';
  } else if (strcmp(bin_dig, "001") == 0) {
    return '1';
  } else if (strcmp(bin_dig, "010") == 0) {
    return '2';
  } else if (strcmp(bin_dig, "011") == 0) {
    return '3';
  } else if (strcmp(bin_dig, "100") == 0) {
    return '4';
  } else if (strcmp(bin_dig, "101") == 0) {
    return '5';
  } else if (strcmp(bin_dig, "110") == 0) {
    return '6';
  } else {
    return '7';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<single_digit_bin_to_oct>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x30,%eax
  test   %rdx,%rdx
  jne    L39
L61:
  pop    %rbx
  ret
L39:
  lea    D64(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x31,%eax
  test   %rdx,%rdx
  je     L61
  lea    D40(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x32,%eax
  test   %rdx,%rdx
  je     L61
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x33,%eax
  test   %rdx,%rdx
  je     L61
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x34,%eax
  test   %rdx,%rdx
  je     L61
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x35,%eax
  test   %rdx,%rdx
  je     L61
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  mov    $0x36,%eax
  sbb    $0xff,%al
  jmp    L61
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D64
type_infered: string
name: read_data
arguments: label: D40
type_infered: string
name: read_data
arguments: label: D11
type_infered: string
name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D21
type_infered: string

tool: D5: 000

tool: D64: 001

tool: D40: 010

tool: D11: 011

tool: D0: 100

tool: D26: 101

tool: D21: 110

assistant: ```c
char single_digit_bin_to_oct(char *bin_dig) {
  if (strcmp(bin_dig, "000") == 0) {
    return '0';
  } else if (strcmp(bin_dig, "001") == 0) {
    return '1';
  } else if (strcmp(bin_dig, "010") == 0) {
    return '2';
  } else if (strcmp(bin_dig, "011") == 0) {
    return '3';
  } else if (strcmp(bin_dig, "100") == 0) {
    return '4';
  } else if (strcmp(bin_dig, "101") == 0) {
    return '5';
  } else if (strcmp(bin_dig, "110") == 0) {
    return '6';
  } else {
    return '7';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<single_digit_bin_to_oct>:
  endbr64
  push   %rbp
  lea    D53(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x30,%eax
  test   %r8,%r8
  jne    L15
L55:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x31,%eax
  test   %r8,%r8
  je     L55
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x32,%eax
  test   %r8,%r8
  je     L55
  lea    D41(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x33,%eax
  test   %r8,%r8
  je     L55
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x34,%eax
  test   %r8,%r8
  je     L55
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x35,%eax
  test   %r8,%r8
  je     L55
  mov    %rbp,%rdi
  lea    D56(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  mov    $0x36,%eax
  sbb    $0xff,%al
  ret
```

tool_calls: name: unpack_data
arguments: tag: D53
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D41
type: string
name: unpack_data
arguments: tag: D21
type: string
name: unpack_data
arguments: tag: D23
type: string
name: unpack_data
arguments: tag: D56
type: string

tool: D53: 000

tool: D19: 001

tool: D12: 010

tool: D41: 011

tool: D21: 100

tool: D23: 101

tool: D56: 110

assistant: ```c
char single_digit_bin_to_oct(char *bin_dig) {
  if (strcmp(bin_dig, "000") == 0) {
    return '0';
  } else if (strcmp(bin_dig, "001") == 0) {
    return '1';
  } else if (strcmp(bin_dig, "010") == 0) {
    return '2';
  } else if (strcmp(bin_dig, "011") == 0) {
    return '3';
  } else if (strcmp(bin_dig, "100") == 0) {
    return '4';
  } else if (strcmp(bin_dig, "101") == 0) {
    return '5';
  } else if (strcmp(bin_dig, "110") == 0) {
    return '6';
  } else {
    return '7';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<single_digit_bin_to_oct>:
  endbr64
  push   %rbp
  lea    D51(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x30,%eax
  test   %r8,%r8
  jne    L4
L16:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D69(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x31,%eax
  test   %r8,%r8
  je     L16
  lea    D49(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x32,%eax
  test   %r8,%r8
  je     L16
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x33,%eax
  test   %r8,%r8
  je     L16
  lea    D61(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x34,%eax
  test   %r8,%r8
  je     L16
  lea    D66(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x35,%eax
  test   %r8,%r8
  je     L16
  mov    %rbp,%rdi
  lea    D26(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  mov    $0x36,%eax
  sbb    $0xff,%al
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D51
datatype: string
name: disassemble_data
arguments: data_label: D69
datatype: string
name: disassemble_data
arguments: data_label: D49
datatype: string
name: disassemble_data
arguments: data_label: D9
datatype: string
name: disassemble_data
arguments: data_label: D61
datatype: string
name: disassemble_data
arguments: data_label: D66
datatype: string
name: disassemble_data
arguments: data_label: D26
datatype: string

tool: D51: 000

tool: D69: 001

tool: D49: 010

tool: D9: 011

tool: D61: 100

tool: D66: 101

tool: D26: 110

assistant: ```c
char single_digit_bin_to_oct(char *bin_dig) {
  if (strcmp(bin_dig, "000") == 0) {
    return '0';
  } else if (strcmp(bin_dig, "001") == 0) {
    return '1';
  } else if (strcmp(bin_dig, "010") == 0) {
    return '2';
  } else if (strcmp(bin_dig, "011") == 0) {
    return '3';
  } else if (strcmp(bin_dig, "100") == 0) {
    return '4';
  } else if (strcmp(bin_dig, "101") == 0) {
    return '5';
  } else if (strcmp(bin_dig, "110") == 0) {
    return '6';
  } else {
    return '7';
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L14
L11:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D1: Enter a number: 

tool: D19: %d

tool: D3: %d


assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  for (int i = 2; i * i <= num; i += 2) {
    printf("%d\n", i * i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L16
  mov    $0x2,%ebx
  mov    $0x4,%esi
  lea    D26(%rip),%rbp
L21:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  mov    %ebx,%esi
  imul   %ebx,%esi
  cmp    0x4(%rsp),%esi
  jle    L21
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D26
data_type: string

tool: D4: Enter a number: 

tool: D18: %d

tool: D26: %d


assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  for (int i = 2; i * i <= num; i += 2) {
    printf("%d\n", i * i);
  }
  return 0;
}
```