ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x2,%r8d
  je     L1
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  ret
L1:
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <lcm@plt>
  lea    D14(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L15
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D14
type: string

tool: D2: %ld %ld

tool: D14: %ld


assistant: ```c
int main() {
  long a, b;
  long LCM;
  int K = scanf("%ld %ld", &a, &b);
  if (K != 2)
    return 1;
  LCM = lcm(a, b);
  printf("%ld\n", LCM);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<log2floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L5:
  shll   -0x8(%rbp)
L27:
  sarl   -0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L25
  shll   -0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int log2floor(int x) {
  int r = 1;
  int v = x;
  while (v >>= 1)
    r <<= 1;
  if (r < x)
    r <<= 1;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<log2floor>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  je     L15
  mov    $0x1,%edx
L11:
  add    %edx,%edx
  sar    %eax
  jne    L11
L17:
  lea    (%rdx,%rdx,1),%eax
  cmp    %edx,%edi
  cmovg  %eax,%edx
  mov    %edx,%eax
  ret
L15:
  mov    $0x1,%edx
  jmp    L17
```

assistant: ```c
int log2floor(int x) {
  int r = 1;
  int v = x;
  while (v >>= 1)
    r <<= 1;
  if (r < x)
    r <<= 1;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<log2floor>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  sar    %edx
  je     L5
  nop
L11:
  mov    %eax,%ecx
  add    %eax,%eax
  sar    %edx
  jne    L11
  shl    $0x2,%ecx
  cmp    %eax,%edi
  cmovg  %ecx,%eax
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
int log2floor(int x) {
  int r = 1;
  int v = x;
  while (v >>= 1)
    r <<= 1;
  if (r < x)
    r <<= 1;
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log2floor>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  sar    %edx
  je     L17
  nop
L12:
  mov    %eax,%ecx
  add    %eax,%eax
  sar    %edx
  jne    L12
  shl    $0x2,%ecx
  cmp    %eax,%edi
  cmovg  %ecx,%eax
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
int log2floor(int x) {
  int r = 1;
  int v = x;
  while (v >>= 1)
    r <<= 1;
  if (r < x)
    r <<= 1;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L19:
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L16
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L21:
  cmpq   $0x0,-0x10(%rbp)
  jg     L19
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_digits(signed long long value) {
  int count = 0;
  long digit = 0;
  signed long long temp = value;
  while ((temp > 0)) {
    digit = temp % 10;
    if (digit != 0) {
      if ((value % digit) == 0) {
        count++;
      }
    }
    temp /= 10;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_digits>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  jle    L37
  mov    %rdi,%rsi
  mov    $0x0,%r9d
  movabs $0x6666666666666667,%rdi
  jmp    L45
L11:
  mov    %rsi,%rax
  imul   %rdi
  sar    $0x2,%rdx
  mov    %rsi,%rcx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  cmp    $0x9,%rsi
  jle    L26
  mov    %rdx,%rsi
L45:
  mov    %rsi,%rax
  imul   %rdi
  sar    $0x2,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rdx
  add    %rdx,%rdx
  mov    %rsi,%rcx
  sub    %rdx,%rcx
  je     L11
  mov    %r8,%rax
  cqto
  idiv   %rcx
  cmp    $0x1,%rdx
  adc    $0x0,%r9d
  jmp    L11
L37:
  mov    $0x0,%r9d
L26:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int find_digits(signed long long value) {
  int count = 0;
  long digit = 0;
  signed long long temp = value;
  while ((temp > 0)) {
    digit = temp % 10;
    if (digit != 0) {
      if ((value % digit) == 0) {
        count++;
      }
    }
    temp /= 10;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_digits>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  jle    L14
  mov    %rdi,%rsi
  xor    %r9d,%r9d
  movabs $0xcccccccccccccccd,%rdi
  jmp    L15
  xchg   %ax,%ax
L13:
  mov    %rdx,%rsi
L15:
  mov    %rsi,%rax
  mul    %rdi
  mov    %rdx,%rcx
  shr    $0x3,%rcx
  lea    (%rcx,%rcx,4),%rdx
  mov    %rsi,%rcx
  add    %rdx,%rdx
  sub    %rdx,%rcx
  je     L23
  mov    %r8,%rax
  cqto
  idiv   %rcx
  cmp    $0x1,%rdx
  adc    $0x0,%r9d
L23:
  mov    %rsi,%rax
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x9,%rsi
  jg     L13
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int find_digits(signed long long value) {
  int count = 0;
  long digit = 0;
  signed long long temp = value;
  while ((temp > 0)) {
    digit = temp % 10;
    if (digit != 0) {
      if ((value % digit) == 0) {
        count++;
      }
    }
    temp /= 10;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_digits>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  jle    L4
  mov    %rdi,%rsi
  xor    %r9d,%r9d
  movabs $0xcccccccccccccccd,%rdi
  jmp    L29
  xchg   %ax,%ax
L17:
  mov    %rdx,%rsi
L29:
  mov    %rsi,%rax
  mul    %rdi
  mov    %rdx,%rcx
  shr    $0x3,%rcx
  lea    (%rcx,%rcx,4),%rdx
  mov    %rsi,%rcx
  add    %rdx,%rdx
  sub    %rdx,%rcx
  je     L39
  mov    %r8,%rax
  cqto
  idiv   %rcx
  cmp    $0x1,%rdx
  adc    $0x0,%r9d
L39:
  mov    %rsi,%rax
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x9,%rsi
  jg     L17
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int find_digits(signed long long value) {
  int count = 0;
  long digit = 0;
  signed long long temp = value;
  while ((temp > 0)) {
    digit = temp % 10;
    if (digit != 0) {
      if ((value % digit) == 0) {
        count++;
      }
    }
    temp /= 10;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<primeCheckS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L41
L22:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L58
  cmpl   $0x1,-0x4(%rbp)
  je     L47
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L7
L47:
  movl   $0x1,-0x8(%rbp)
  jmp    L58
L7:
  movl   $0x0,-0x8(%rbp)
L58:
  addl   $0x1,-0x4(%rbp)
L41:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L22
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int primeCheckS(int numCheck) {
  int isPrime = 0;
  for (int i = 1; i <= ceil(sqrt(numCheck)); i++) {
    if (numCheck % i == 0) {
      if (i == 1 || i == numCheck) {
        isPrime = 1;
      } else {
        isPrime = 0;
      }
    }
  }
  return (isPrime);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<primeCheckS>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  jmp    L4
L5:
  add    $0x1,%ebx
L4:
  mov    %ebp,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    %ebx,%eax
  jl     L12
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L5
  cmp    $0x1,%ebx
  sete   %al
  cmp    %ebp,%ebx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%r12d
  jmp    L5
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int primeCheckS(int numCheck) {
  int isPrime = 0;
  for (int i = 1; i <= ceil(sqrt(numCheck)); i++) {
    if (numCheck % i == 0) {
      if (i == 1 || i == numCheck) {
        isPrime = 1;
      } else {
        isPrime = 0;
      }
    }
  }
  return (isPrime);
}
```
user: What is the c source code of the assembly code below:

```asm
<primeCheckS>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    $0x1,%ebx
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L25
  cmp    $0x1,%ebx
  sete   %al
  cmp    %r12d,%ebx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%r13d
L25:
  add    $0x1,%ebx
L0:
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    %ebx,%eax
  jge    L22
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int primeCheckS(int numCheck) {
  int isPrime = 0;
  for (int i = 1; i <= ceil(sqrt(numCheck)); i++) {
    if (numCheck % i == 0) {
      if (i == 1 || i == numCheck) {
        isPrime = 1;
      } else {
        isPrime = 0;
      }
    }
  }
  return (isPrime);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<primeCheckS>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    $0x1,%ebx
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L29
  cmp    $0x1,%ebx
  sete   %al
  cmp    %r12d,%ebx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%r13d
L29:
  add    $0x1,%ebx
L26:
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    %ebx,%eax
  jge    L19
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int primeCheckS(int numCheck) {
  int isPrime = 0;
  for (int i = 1; i <= ceil(sqrt(numCheck)); i++) {
    if (numCheck % i == 0) {
      if (i == 1 || i == numCheck) {
        isPrime = 1;
      } else {
        isPrime = 0;
      }
    }
  }
  return (isPrime);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FindNearbyPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mod_ui@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_size@plt>
  test   %rax,%rax
  jne    L20
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add_ui@plt>
L20:
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <IsPrime@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L40
L43:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add_ui@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <IsPrime@plt>
  mov    %eax,-0x8(%rbp)
L40:
  cmpl   $0x0,-0x8(%rbp)
  je     L43
  cmpl   $0x1,-0x8(%rbp)
  jne    L2
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mpz_get_str@plt>
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L2:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mpz_get_str@plt>
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D16
type: string

tool: D5: Trying new candidate (%i)


tool: D29: Probable prime:
%s


tool: D16: Prime:
%s


assistant: ```c
void FindNearbyPrime(mpz_t candidate, int timeout) {
  mpz_t remainder;
  mpz_init(remainder);
  mpz_mod_ui(remainder, candidate, 2);
  if (mpz_size(remainder) == 0) {
    mpz_add_ui(candidate, candidate, 1);
  }
  int candidate_counter = 1;
  int candidate_status = IsPrime(candidate, timeout);
  while (candidate_status == 0) {
    printf("Trying new candidate (%i)\n", candidate_counter);
    candidate_counter++;
    mpz_add_ui(candidate, candidate, 2);
    candidate_status = IsPrime(candidate, timeout);
  }
  if (candidate_status == 1) {
    printf("Probable prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  } else {
    printf("Prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<FindNearbyPrime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mpz_mod_ui@plt>
  mov    %ebp,%edi
  call   <mpz_size@plt>
  test   %rax,%rax
  je     L57
L12:
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <IsPrime@plt>
  test   %eax,%eax
  jne    L44
  mov    $0x1,%ebp
  lea    D24(%rip),%r13
L0:
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_add_ui@plt>
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <IsPrime@plt>
  test   %eax,%eax
  je     L0
L44:
  cmp    $0x1,%eax
  je     L58
  mov    %ebx,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mpz_get_str@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L57:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_add_ui@plt>
  jmp    L12
L58:
  mov    %ebx,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mpz_get_str@plt>
  mov    %rax,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string

tool: D24: Trying new candidate (%i)


tool: D9: Prime:
%s


tool: D19: Probable prime:
%s


assistant: ```c
void FindNearbyPrime(mpz_t candidate, int timeout) {
  mpz_t remainder;
  mpz_init(remainder);
  mpz_mod_ui(remainder, candidate, 2);
  if (mpz_size(remainder) == 0) {
    mpz_add_ui(candidate, candidate, 1);
  }
  int candidate_counter = 1;
  int candidate_status = IsPrime(candidate, timeout);
  while (candidate_status == 0) {
    printf("Trying new candidate (%i)\n", candidate_counter);
    candidate_counter++;
    mpz_add_ui(candidate, candidate, 2);
    candidate_status = IsPrime(candidate, timeout);
  }
  if (candidate_status == 1) {
    printf("Probable prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  } else {
    printf("Prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FindNearbyPrime>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <mpz_init@plt>
  mov    %r13d,%edi
  mov    $0x2,%edx
  mov    %r12d,%esi
  call   <mpz_mod_ui@plt>
  mov    %r13d,%edi
  call   <mpz_size@plt>
  test   %rax,%rax
  je     L51
L10:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <IsPrime@plt>
  test   %eax,%eax
  jne    L58
  mov    $0x1,%ebx
  lea    D15(%rip),%r13
  nopl   0x0(%rax)
L13:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %r12d,%edi
  mov    $0x2,%edx
  call   <mpz_add_ui@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <IsPrime@plt>
  test   %eax,%eax
  je     L13
L58:
  mov    %r12d,%edx
  mov    $0xa,%esi
  xor    %edi,%edi
  cmp    $0x1,%eax
  je     L1
  call   <mpz_get_str@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rsi
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <printf@plt>
  nopl   0x0(%rax)
L1:
  call   <mpz_get_str@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  jmp    L19
  nopl   0x0(%rax)
L51:
  mov    $0x1,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <mpz_add_ui@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D15: Trying new candidate (%i)


tool: D3: Prime:
%s


tool: D0: Probable prime:
%s


assistant: ```c
void FindNearbyPrime(mpz_t candidate, int timeout) {
  mpz_t remainder;
  mpz_init(remainder);
  mpz_mod_ui(remainder, candidate, 2);
  if (mpz_size(remainder) == 0) {
    mpz_add_ui(candidate, candidate, 1);
  }
  int candidate_counter = 1;
  int candidate_status = IsPrime(candidate, timeout);
  while (candidate_status == 0) {
    printf("Trying new candidate (%i)\n", candidate_counter);
    candidate_counter++;
    mpz_add_ui(candidate, candidate, 2);
    candidate_status = IsPrime(candidate, timeout);
  }
  if (candidate_status == 1) {
    printf("Probable prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  } else {
    printf("Prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FindNearbyPrime>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <mpz_init@plt>
  mov    %r13d,%edi
  mov    $0x2,%edx
  mov    %r12d,%esi
  call   <mpz_mod_ui@plt>
  mov    %r13d,%edi
  call   <mpz_size@plt>
  test   %rax,%rax
  je     L37
L54:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <IsPrime@plt>
  test   %eax,%eax
  jne    L55
  mov    $0x1,%ebx
  lea    D28(%rip),%r13
  nopl   0x0(%rax)
L8:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %r12d,%edi
  mov    $0x2,%edx
  call   <mpz_add_ui@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <IsPrime@plt>
  test   %eax,%eax
  je     L8
L55:
  mov    %r12d,%edx
  mov    $0xa,%esi
  xor    %edi,%edi
  cmp    $0x1,%eax
  je     L15
  call   <mpz_get_str@plt>
  lea    D1(%rip),%rdi
  mov    %rax,%rsi
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <printf@plt>
  nopl   0x0(%rax)
L15:
  call   <mpz_get_str@plt>
  lea    D13(%rip),%rdi
  mov    %rax,%rsi
  jmp    L2
  nopl   0x0(%rax)
L37:
  mov    $0x1,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <mpz_add_ui@plt>
  jmp    L54
```

tool_calls: name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string

tool: D28: Trying new candidate (%i)


tool: D1: Prime:
%s


tool: D13: Probable prime:
%s


assistant: ```c
void FindNearbyPrime(mpz_t candidate, int timeout) {
  mpz_t remainder;
  mpz_init(remainder);
  mpz_mod_ui(remainder, candidate, 2);
  if (mpz_size(remainder) == 0) {
    mpz_add_ui(candidate, candidate, 1);
  }
  int candidate_counter = 1;
  int candidate_status = IsPrime(candidate, timeout);
  while (candidate_status == 0) {
    printf("Trying new candidate (%i)\n", candidate_counter);
    candidate_counter++;
    mpz_add_ui(candidate, candidate, 2);
    candidate_status = IsPrime(candidate, timeout);
  }
  if (candidate_status == 1) {
    printf("Probable prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  } else {
    printf("Prime:\n%s\n", mpz_get_str(NULL, 10, candidate));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0xffffffffffff0000,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0xffffffff80000000,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
data_type: string

tool: D23: %d


assistant: ```c
int main() {
  long i = 65536 << 16;
  printf("%d\n", i);
  i = 65535 << 16;
  printf("%d\n", i);
  i = -2147483648;
  printf("%d\n", i);
  --i;
  printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffffffff0000,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffff80000000,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  movabs $0xffffffff7fffffff,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: %d


assistant: ```c
int main() {
  long i = 65536 << 16;
  printf("%d\n", i);
  i = 65535 << 16;
  printf("%d\n", i);
  i = -2147483648;
  printf("%d\n", i);
  --i;
  printf("%d\n", i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffffffff0000,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffff80000000,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  movabs $0xffffffff7fffffff,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  long i = 65536 << 16;
  printf("%d\n", i);
  i = 65535 << 16;
  printf("%d\n", i);
  i = -2147483648;
  printf("%d\n", i);
  --i;
  printf("%d\n", i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffffffff0000,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffff80000000,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  movabs $0xffffffff7fffffff,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main() {
  long i = 65536 << 16;
  printf("%d\n", i);
  i = 65535 << 16;
  printf("%d\n", i);
  i = -2147483648;
  printf("%d\n", i);
  --i;
  printf("%d\n", i);
  return 0;
}
```