user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x168,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L23
  nopw   0x0(%rax,%rax,1)
L95:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L95
L23:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  lea    0x60(%rsp),%rbx
  xor    %ebp,%ebp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    %rbx,%r12
  test   %eax,%eax
  jle    L110
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebp,%edx
  jg     L62
  mov    0x8(%rsp),%r12d
  test   %r12d,%r12d
  jle    L1
  test   %edx,%edx
  jle    L41
  mov    $0x1,%eax
  xor    %edi,%edi
  xor    %esi,%esi
  lea    0xb0(%rsp),%rbp
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %r8d,%ecx
  add    $0x1,%esi
  mov    %ecx,-0x4(%rbp,%rax,4)
  cmp    %r12d,%esi
  jge    L133
L43:
  add    $0x1,%rax
  cmp    %edi,%edx
  jle    L40
L78:
  movslq %esi,%rcx
  movslq %eax,%r9
  mov    0x10(%rsp,%rcx,4),%r8d
  movslq %edi,%rcx
  mov    0x60(%rsp,%rcx,4),%ecx
  cmp    %ecx,%r8d
  jl     L31
  mov    %ecx,-0x4(%rbp,%rax,4)
  add    $0x1,%edi
  cmp    %r12d,%esi
  jl     L43
L133:
  cmp    %edi,%edx
  jle    L144
  sub    $0x1,%edx
  lea    0xb0(%rsp,%r9,4),%r8
  sub    %edi,%edx
  movslq %edi,%rdi
  lea    (%rbx,%rdi,4),%rsi
  lea    0x4(,%rdx,4),%rdx
  mov    %r8,%rdi
  call   <memcpy@plt>
L4:
  mov    0xc(%rsp),%edx
  jmp    L144
L110:
  mov    0x8(%rsp),%r12d
  test   %r12d,%r12d
  jle    L4
L41:
  xor    %r9d,%r9d
  xor    %esi,%esi
  lea    0xb0(%rsp),%rbp
L40:
  lea    -0x1(%r12),%eax
  lea    0x0(%rbp,%r9,4),%rdi
  sub    %esi,%eax
  cmp    %r12d,%esi
  movslq %esi,%rsi
  lea    0x4(,%rax,4),%rdx
  mov    $0x4,%eax
  lea    0x10(%rsp,%rsi,4),%rsi
  cmovge %rax,%rdx
  call   <memcpy@plt>
  mov    0xc(%rsp),%edx
L144:
  add    %r12d,%edx
  xor    %ebx,%ebx
  lea    0xb0(%rsp),%rbp
  lea    D7(%rip),%r12
  test   %edx,%edx
  jle    L94
L127:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  add    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L127
L94:
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x168,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  xor    %r9d,%r9d
  xor    %edi,%edi
  jmp    L133
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D7
type: string

tool: D8: %d

tool: D7: %d


assistant: ```c
int main() {
  int i, j, k;
  int a[20];
  int b[20];
  int c[40];
  int n1, n2;
  k = 0;
  scanf("%d", &n1);
  for (i = 0; i < n1; i = i + 1)
    scanf("%d", &a[i]);
  scanf("%d", &n2);
  for (j = 0; j < n2; j = j + 1)
    scanf("%d", &b[j]);
  i = 0, j = 0;
  while ((i < n1) && (j < n2)) {
    if (a[i] < b[j]) {
      c[k] = a[i];
      i = i + 1;
      k++;
    } else {
      c[k] = b[j];
      j = j + 1;
      k++;
    }
  }
  if (i < n1) {
    for (; i < n1; i = i + 1) {
      c[k++] = a[i];
    }
  } else {
    for (; j < n2; j = j + 1) {
      c[k++] = b[j];
    }
  }
  for (k = 0; k < (n1 + n2); k = k + 1) {
    printf("%d\n", c[k]);
  }
  return 0;
}
```