user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rsi
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x214(%rbp)
  jmp    L80
L7:
  movl   $0x1,-0x210(%rbp)
  jmp    L125
L5:
  lea    -0x1a0(%rbp),%rcx
  mov    -0x210(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x214(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x210(%rbp)
L125:
  mov    -0x21c(%rbp),%eax
  cmp    %eax,-0x210(%rbp)
  jle    L5
  addl   $0x1,-0x214(%rbp)
L80:
  mov    -0x21c(%rbp),%eax
  cmp    %eax,-0x214(%rbp)
  jle    L7
  movl   $0x1,-0x214(%rbp)
  jmp    L57
L41:
  mov    -0x214(%rbp),%eax
  cltq
  movl   $0x0,-0x200(%rbp,%rax,4)
  addl   $0x1,-0x214(%rbp)
L57:
  mov    -0x21c(%rbp),%eax
  cmp    %eax,-0x214(%rbp)
  jle    L41
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x218(%rbp),%rax
  mov    %rax,%rsi
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x208(%rbp)
  mov    -0x208(%rbp),%eax
  mov    %eax,-0x20c(%rbp)
  mov    -0x218(%rbp),%eax
  cltq
  movl   $0x1,-0x200(%rbp,%rax,4)
  mov    -0x208(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x208(%rbp)
  mov    -0x218(%rbp),%edx
  cltq
  mov    %edx,-0x1d0(%rbp,%rax,4)
  mov    -0x218(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L50
L109:
  mov    -0x20c(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%eax
  mov    %eax,-0x204(%rbp)
  movl   $0x1,-0x214(%rbp)
  jmp    L15
L54:
  mov    -0x214(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x204(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L119
  mov    -0x214(%rbp),%eax
  cltq
  mov    -0x200(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L119
  mov    -0x214(%rbp),%eax
  cltq
  movl   $0x1,-0x200(%rbp,%rax,4)
  mov    -0x208(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x208(%rbp)
  cltq
  mov    -0x214(%rbp),%edx
  mov    %edx,-0x1d0(%rbp,%rax,4)
  mov    -0x214(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L119:
  addl   $0x1,-0x20c(%rbp)
  addl   $0x1,-0x214(%rbp)
L15:
  mov    -0x21c(%rbp),%eax
  cmp    %eax,-0x214(%rbp)
  jle    L54
L50:
  mov    -0x20c(%rbp),%eax
  cmp    -0x208(%rbp),%eax
  jne    L109
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L116
  call   <__stack_chk_fail@plt>
L116:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D44
type_infered: string
name: disassemble_data
arguments: tag: D88
type_infered: string
name: disassemble_data
arguments: tag: D33
type_infered: string
name: disassemble_data
arguments: tag: D56
type_infered: string
name: disassemble_data
arguments: tag: D52
type_infered: string
name: disassemble_data
arguments: tag: D59
type_infered: string

tool: D44: Enter the number of vertices in the graph: 

tool: D88: %d

tool: D33: Enter the adjacency matrix:

tool: D56: Enter the source of the graph: 

tool: D52: The BFS traversal of graph is: 

tool: D59: %d 

assistant: ```c
int main() {
  int n, adj[10][10], i, j, visited[10], source, queue[10], front, rear, root;
  printf("Enter the number of vertices in the graph: ");
  scanf("%d", &n);
  printf("Enter the adjacency matrix:\n");
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      scanf("%d", &adj[i][j]);
    }
  }
  for (i = 1; i <= n; i++)
    visited[i] = 0;
  printf("Enter the source of the graph: ");
  scanf("%d", &source);
  printf("The BFS traversal of graph is: ");
  front = rear = 0;
  visited[source] = 1;
  queue[rear++] = source;
  printf("%d ", source);
  while (front != rear) {
    root = queue[front];
    for (i = 1; i <= n; i++) {
      if (adj[root][i] && !visited[i]) {
        visited[i] = 1;
        queue[rear++] = i;
        printf("%d ", i);
      }
      front++;
    }
  }
  return 0;
}
```