ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_get_task_launcher_file>:
  endbr64
  push   %r13
  lea    D22(%rip),%rsi
  lea    D47(%rip),%rdx
  push   %r12
  lea    D25(%rip),%rdi
  lea    D9(%rip),%r13
  push   %rbp
  call   <get_job_directory@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <get_task_launcher_file@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
L6:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <free@plt>
  nopl   (%rax)
L14:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D47
type: string
name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D3
type: string

tool: D22: user

tool: D47: job_200906101234_0001

tool: D25: /tmp

tool: D9: /tmp/taskTracker/user/jobcache/job_200906101234_0001/taskjvm.sh

tool: D3: failure to match expected task file %s vs %s


assistant: ```c
void test_get_task_launcher_file() {
  char *expected_file = ("/tmp/taskTracker/user/jobcache/job_200906101234_0001"
                         "/taskjvm.sh");
  char *job_dir = get_job_directory("/tmp", "user", "job_200906101234_0001");
  char *task_file = get_task_launcher_file(job_dir);
  if (strcmp(task_file, expected_file) != 0) {
    printf("failure to match expected task file %s vs %s\n", task_file, expected_file);
    exit(1);
  }
  free(job_dir);
  free(task_file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<euler_problem_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movabs $0x8be589eac7,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L11
L18:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fmod@plt>
  movq   %xmm0,%rax
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L10
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm2
  ucomisd %xmm0,%xmm2
  jne    L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L10:
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %rax,-0x18(%rbp)
  jl     L18
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
long euler_problem_3() {
  long target = 600851475143;
  long i, max = 0;
  for (i = 0; i < sqrt(target); ++i) {
    if (fmod(target, i) == 0.0 && is_prime(i)) {
      max = i;
    }
  }
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<euler_problem_3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  movabs $0x8be589eac7,%rbp
  jmp    L48
L21:
  add    $0x1,%rbx
L48:
  mov    %rbp,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L44
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fmod@plt>
  ucomisd D2(%rip),%xmm0
  jp     L21
  jne    L21
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  cmovne %rbx,%r12
  jmp    L21
L44:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f64

tool: D2: 0

assistant: ```c
long euler_problem_3() {
  long target = 600851475143;
  long i, max = 0;
  for (i = 0; i < sqrt(target); ++i) {
    if (fmod(target, i) == 0.0 && is_prime(i)) {
      max = i;
    }
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<euler_problem_3>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  movabs $0x8be589eac7,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L6
  nopl   0x0(%rax)
L30:
  add    $0x1,%rbx
L6:
  mov    %rbp,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L13
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fmod@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L30
  jne    L30
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  cmovne %rbx,%r12
  jmp    L30
  nopl   0x0(%rax)
L13:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long euler_problem_3() {
  long target = 600851475143;
  long i, max = 0;
  for (i = 0; i < sqrt(target); ++i) {
    if (fmod(target, i) == 0.0 && is_prime(i)) {
      max = i;
    }
  }
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<euler_problem_3>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  movabs $0x8be589eac7,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopl   0x0(%rax)
L18:
  add    $0x1,%rbx
L16:
  mov    %rbp,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L26
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fmod@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L18
  jne    L18
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  cmovne %rbx,%r12
  jmp    L18
  nopl   0x0(%rax)
L26:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long euler_problem_3() {
  long target = 600851475143;
  long i, max = 0;
  for (i = 0; i < sqrt(target); ++i) {
    if (fmod(target, i) == 0.0 && is_prime(i)) {
      max = i;
    }
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L87
L3:
  cmpl   $0x0,-0x2c(%rbp)
  jns    L48
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x2c(%rbp)
L48:
  cmpl   $0x0,-0x2c(%rbp)
  jns    L52
  movl   $0x0,-0x2c(%rbp)
L52:
  cmpl   $0x0,-0x30(%rbp)
  jns    L28
  movl   $0x0,-0x30(%rbp)
L28:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jbe    L10
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
L10:
  mov    -0x30(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jbe    L88
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x30(%rbp)
L88:
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L29
  mov    $0x0,%eax
  jmp    L87
L29:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L87:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *substring(const char *str, int begin, int len) {
  char *buffer;
  if (str == NULL)
    return NULL;
  if (begin < 0)
    begin = strlen(str) + begin;
  if (begin < 0)
    begin = 0;
  if (len < 0)
    len = 0;
  if (((size_t)begin) > strlen(str))
    begin = strlen(str);
  if (((size_t)len) > strlen(&str[begin]))
    len = strlen(&str[begin]);
  if ((buffer = xmalloc(len + 1)) == NULL)
    return NULL;
  memcpy(buffer, &(str[begin]), len);
  buffer[len] = '\0';
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<substring>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L20
  mov    %esi,%ebp
  mov    %edx,%r14d
  test   %esi,%esi
  js     L35
L26:
  test   %ebp,%ebp
  mov    $0x0,%r12d
  cmovns %ebp,%r12d
  test   %r14d,%r14d
  mov    $0x0,%r13d
  cmovns %r14d,%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %r12d,%r12
  test   %ebp,%ebp
  mov    $0x0,%edx
  cmovs  %edx,%ebp
  cmp    %rax,%r12
  cmova  %eax,%ebp
  movslq %ebp,%r12
  add    %rbx,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %r13d,%r13
  test   %r14d,%r14d
  mov    $0x0,%edx
  cmovs  %edx,%r14d
  cmp    %rax,%r13
  cmova  %eax,%r14d
  lea    0x1(%r14),%edi
  call   <xmalloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L20
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %r14d,%r13
  movb   $0x0,(%rbx,%r13,1)
L20:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  call   <strlen@plt>
  add    %eax,%ebp
  jmp    L26
```

assistant: ```c
char *substring(const char *str, int begin, int len) {
  char *buffer;
  if (str == NULL)
    return NULL;
  if (begin < 0)
    begin = strlen(str) + begin;
  if (begin < 0)
    begin = 0;
  if (len < 0)
    len = 0;
  if (((size_t)begin) > strlen(str))
    begin = strlen(str);
  if (((size_t)len) > strlen(&str[begin]))
    len = strlen(&str[begin]);
  if ((buffer = xmalloc(len + 1)) == NULL)
    return NULL;
  memcpy(buffer, &(str[begin]), len);
  buffer[len] = '\0';
  return buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %ebx,%ebx
  lea    (%rbx,%rax,1),%edx
  cmovs  %edx,%ebx
  xor    %edx,%edx
  test   %ebp,%ebp
  cmovs  %edx,%ebp
  test   %ebx,%ebx
  cmovs  %edx,%ebx
  movslq %ebx,%rbx
  cmp    %rax,%rbx
  cmova  %rax,%rbx
  add    %rbx,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %ebp,%rdx
  cmp    %rax,%rdx
  cmova  %eax,%ebp
  lea    0x1(%rbp),%edi
  call   <xmalloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L25
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  movslq %ebp,%rbp
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L25:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  xor    %r13d,%r13d
  jmp    L25
```

assistant: ```c
char *substring(const char *str, int begin, int len) {
  char *buffer;
  if (str == NULL)
    return NULL;
  if (begin < 0)
    begin = strlen(str) + begin;
  if (begin < 0)
    begin = 0;
  if (len < 0)
    len = 0;
  if (((size_t)begin) > strlen(str))
    begin = strlen(str);
  if (((size_t)len) > strlen(&str[begin]))
    len = strlen(&str[begin]);
  if ((buffer = xmalloc(len + 1)) == NULL)
    return NULL;
  memcpy(buffer, &(str[begin]), len);
  buffer[len] = '\0';
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %ebx,%ebx
  lea    (%rbx,%rax,1),%edx
  cmovs  %edx,%ebx
  xor    %edx,%edx
  test   %ebp,%ebp
  cmovs  %edx,%ebp
  test   %ebx,%ebx
  cmovs  %edx,%ebx
  movslq %ebx,%rbx
  cmp    %rax,%rbx
  cmova  %rax,%rbx
  add    %rbx,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %ebp,%rdx
  cmp    %rax,%rdx
  cmova  %eax,%ebp
  lea    0x1(%rbp),%edi
  call   <xmalloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L16
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  movslq %ebp,%rbp
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L16:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  xor    %r13d,%r13d
  jmp    L16
```

assistant: ```c
char *substring(const char *str, int begin, int len) {
  char *buffer;
  if (str == NULL)
    return NULL;
  if (begin < 0)
    begin = strlen(str) + begin;
  if (begin < 0)
    begin = 0;
  if (len < 0)
    len = 0;
  if (((size_t)begin) > strlen(str))
    begin = strlen(str);
  if (((size_t)len) > strlen(&str[begin]))
    len = strlen(&str[begin]);
  if ((buffer = xmalloc(len + 1)) == NULL)
    return NULL;
  memcpy(buffer, &(str[begin]), len);
  buffer[len] = '\0';
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<first_patch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L0
  mov    $0x1,%eax
  jmp    L22
L0:
  mov    $0x0,%eax
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: pre

assistant: ```c
int first_patch(char const *version) {
  int l = strlen(version);
  if (l > 3 && !strcmp(version + l - 3, "pre")) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<first_patch>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    $0x3,%eax
  jle    L0
  cltq
  lea    -0x3(%rbx,%rax,1),%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
L0:
  mov    %edx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: pre

assistant: ```c
int first_patch(char const *version) {
  int l = strlen(version);
  if (l > 3 && !strcmp(version + l - 3, "pre")) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<first_patch>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x3,%eax
  jle    L8
  cltq
  lea    D0(%rip),%rsi
  lea    -0x3(%rbx,%rax,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
L8:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: pre

assistant: ```c
int first_patch(char const *version) {
  int l = strlen(version);
  if (l > 3 && !strcmp(version + l - 3, "pre")) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<first_patch>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x3,%eax
  jle    L5
  cltq
  lea    D3(%rip),%rsi
  lea    -0x3(%rbx,%rax,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
L5:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: pre

assistant: ```c
int first_patch(char const *version) {
  int l = strlen(version);
  if (l > 3 && !strcmp(version + l - 3, "pre")) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putnbr_unsgned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x9,%eax
  ja     L3
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  lea    -0x4(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,%edi
  call   <ft_putnbr@plt>
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <ft_putnbr@plt>
L17:
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbr_unsgned(unsigned int n) {
  if (n < 10) {
    n = n + 48;
    write(1, &n, 1);
  } else {
    ft_putnbr(n / 10);
    ft_putnbr(n % 10);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_putnbr_unsgned>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %edi,0xc(%rsp)
  cmp    $0x9,%edi
  ja     L4
  add    $0x30,%eax
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
L7:
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  mov    %edi,%edi
  mov    $0xcccccccd,%ebx
  imul   %rbx,%rdi
  shr    $0x23,%rdi
  call   <ft_putnbr@plt>
  mov    0xc(%rsp),%edi
  mov    %edi,%eax
  imul   %rbx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <ft_putnbr@plt>
  jmp    L7
```

assistant: ```c
void ft_putnbr_unsgned(unsigned int n) {
  if (n < 10) {
    n = n + 48;
    write(1, &n, 1);
  } else {
    ft_putnbr(n / 10);
    ft_putnbr(n % 10);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putnbr_unsgned>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  cmp    $0x9,%edi
  ja     L0
  add    $0x30,%eax
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  mov    %eax,0xc(%rsp)
  call   <write@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L0:
  mov    $0xcccccccd,%ebx
  mov    %edi,%edi
  imul   %rbx,%rdi
  shr    $0x23,%rdi
  call   <ft_putnbr@plt>
  mov    0xc(%rsp),%eax
  mov    %rax,%rdi
  imul   %rbx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <ft_putnbr@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void ft_putnbr_unsgned(unsigned int n) {
  if (n < 10) {
    n = n + 48;
    write(1, &n, 1);
  } else {
    ft_putnbr(n / 10);
    ft_putnbr(n % 10);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_putnbr_unsgned>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  cmp    $0x9,%edi
  ja     L5
  add    $0x30,%eax
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  mov    %eax,0xc(%rsp)
  call   <write@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L5:
  mov    $0xcccccccd,%ebx
  mov    %edi,%edi
  imul   %rbx,%rdi
  shr    $0x23,%rdi
  call   <ft_putnbr@plt>
  mov    0xc(%rsp),%eax
  mov    %rax,%rdi
  imul   %rbx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <ft_putnbr@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void ft_putnbr_unsgned(unsigned int n) {
  if (n < 10) {
    n = n + 48;
    write(1, &n, 1);
  } else {
    ft_putnbr(n / 10);
    ft_putnbr(n % 10);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strappend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jb     L6
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void strappend(char **dst, size_t *size, const char *src) {
  size_t len = strlcpy(*dst, src, *size);
  if (len >= *size)
    len = *size;
  *dst += len;
  *size -= len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strappend>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    (%rbx),%rdx
  mov    (%rdi),%rdi
  call   <strlcpy@plt>
  mov    (%rbx),%rdx
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  add    %rax,0x0(%rbp)
  sub    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strappend(char **dst, size_t *size, const char *src) {
  size_t len = strlcpy(*dst, src, *size);
  if (len >= *size)
    len = *size;
  *dst += len;
  *size -= len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strappend>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  mov    (%rbx),%rdx
  mov    (%rdi),%rdi
  call   <strlcpy@plt>
  mov    (%rbx),%rdx
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  add    %rax,0x0(%rbp)
  sub    %rax,%rdx
  mov    %rdx,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strappend(char **dst, size_t *size, const char *src) {
  size_t len = strlcpy(*dst, src, *size);
  if (len >= *size)
    len = *size;
  *dst += len;
  *size -= len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strappend>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  mov    (%rbx),%rdx
  mov    (%rdi),%rdi
  call   <strlcpy@plt>
  mov    (%rbx),%rdx
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  add    %rax,0x0(%rbp)
  sub    %rax,%rdx
  mov    %rdx,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strappend(char **dst, size_t *size, const char *src) {
  size_t len = strlcpy(*dst, src, *size);
  if (len >= *size)
    len = *size;
  *dst += len;
  *size -= len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L18:
  subq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L21
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
L21:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rtrim(char *s) {
  char *end = s + strlen(s);
  while ((end != s) && isspace(*(end - 1)))
    --end;
  *end = '\0';
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtrim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmp    %rbx,%rbp
  je     L26
L10:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L26
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
L26:
  movb   $0x0,(%rbx)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *rtrim(char *s) {
  char *end = s + strlen(s);
  while ((end != s) && isspace(*(end - 1)))
    --end;
  *end = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  cmp    %rbx,%r12
  jne    L14
  jmp    L29
L7:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L29
L14:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
L29:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(char *s) {
  char *end = s + strlen(s);
  while ((end != s) && isspace(*(end - 1)))
    --end;
  *end = '\0';
  return s;
}
```