ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<logout>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <utmpname@plt>
  cmp    $0xffffffff,%eax
  je     L18
  xor    %eax,%eax
  call   <setutent@plt>
  mov    0x18(%rsp),%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <getutline_r@plt>
  test   %rax,%rax
  jns    L27
L35:
  xor    %eax,%eax
  call   <endutent@plt>
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L27:
  mov    0x8(%rsp),%rax
  mov    $0x4,%esi
  xor    %r12d,%r12d
  mov    0x4(%rax),%edi
  call   <bzero@plt>
  xor    %edi,%edi
  mov    0x8(%rsp),%rbp
  call   <time@plt>
  mov    0x8(%rsp),%rdi
  mov    %eax,0x0(%rbp)
  call   <pututline@plt>
  test   %rax,%rax
  setne  %r12b
  jmp    L35
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int logout(const char *line) {
  struct utmp tmp, utbuf;
  struct utmp *ut;
  int result = 0;
  if (utmpname(_PATH_UTMP) == -1)
    return 0;
  setutent();
  strncpy(tmp.ut_line, line, sizeof tmp.ut_line);
  if (getutline_r(&tmp, &utbuf, &ut) >= 0) {
    bzero(ut->ut_name, sizeof ut->ut_name);
    ut->ut_time = time(NULL);
    if (pututline(ut) != NULL)
      result = 1;
  }
  endutent();
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<logout>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <utmpname@plt>
  cmp    $0xffffffff,%eax
  je     L13
  xor    %eax,%eax
  call   <setutent@plt>
  mov    0x18(%rsp),%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <getutline_r@plt>
  test   %rax,%rax
  jns    L9
L18:
  xor    %eax,%eax
  call   <endutent@plt>
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L9:
  mov    0x8(%rsp),%rax
  mov    $0x4,%esi
  xor    %r12d,%r12d
  mov    0x4(%rax),%edi
  call   <bzero@plt>
  xor    %edi,%edi
  mov    0x8(%rsp),%rbp
  call   <time@plt>
  mov    0x8(%rsp),%rdi
  mov    %eax,0x0(%rbp)
  call   <pututline@plt>
  test   %rax,%rax
  setne  %r12b
  jmp    L18
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int logout(const char *line) {
  struct utmp tmp, utbuf;
  struct utmp *ut;
  int result = 0;
  if (utmpname(_PATH_UTMP) == -1)
    return 0;
  setutent();
  strncpy(tmp.ut_line, line, sizeof tmp.ut_line);
  if (getutline_r(&tmp, &utbuf, &ut) >= 0) {
    bzero(ut->ut_name, sizeof ut->ut_name);
    ut->ut_time = time(NULL);
    if (pututline(ut) != NULL)
      result = 1;
  }
  endutent();
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tsGetValueLatLon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  movsd  -0x30(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <tsLatLonToGridpoint@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <tsGetValue@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
float tsGetValueLatLon(double lat, double lon) {
  double ix, iy;
  tsLatLonToGridpoint(lat, lon, &ix, &iy);
  return (tsGetValue(ix, iy));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tsGetValueLatLon>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <tsLatLonToGridpoint@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <tsGetValue@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float tsGetValueLatLon(double lat, double lon) {
  double ix, iy;
  tsLatLonToGridpoint(lat, lon, &ix, &iy);
  return (tsGetValue(ix, iy));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tsGetValueLatLon>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <tsLatLonToGridpoint@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <tsGetValue@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float tsGetValueLatLon(double lat, double lon) {
  double ix, iy;
  tsLatLonToGridpoint(lat, lon, &ix, &iy);
  return (tsGetValue(ix, iy));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tsGetValueLatLon>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <tsLatLonToGridpoint@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <tsGetValue@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float tsGetValueLatLon(double lat, double lon) {
  double ix, iy;
  tsLatLonToGridpoint(lat, lon, &ix, &iy);
  return (tsGetValue(ix, iy));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<computeE>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %rsi,0x20(%rsp)
  movss  %xmm0,0x2c(%rsp)
  mov    %edx,%ebp
  mov    $0x0,%r15d
  pxor   %xmm5,%xmm5
  movss  %xmm5,0xc(%rsp)
  lea    -0x1(%rdx),%eax
  mov    %eax,0x18(%rsp)
  test   %edx,%edx
  jg     L40
L29:
  movss  0xc(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  mov    %eax,%ebx
L53:
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <C@plt>
  pxor   %xmm2,%xmm2
  cvtsi2ssl (%r14,%rax,4),%xmm2
  movss  %xmm2,0x10(%rsp)
  lea    0x1(%rbx),%edi
  cmp    %ebx,0x18(%rsp)
  mov    $0x0,%eax
  cmove  %eax,%edi
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    %r13d,%esi
  call   <C@plt>
  mov    (%r14,%rax,4),%r12d
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    0x1c(%rsp),%esi
  mov    %ebx,%edi
  call   <C@plt>
  add    (%r14,%rax,4),%r12d
  mov    %ebp,%ecx
  mov    0x28(%rsp),%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <C@plt>
  add    (%r14,%rax,4),%r12d
  pxor   %xmm3,%xmm3
  cvtsi2ss %r12d,%xmm3
  movss  %xmm3,0x14(%rsp)
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <C@plt>
  mov    0x20(%rsp),%rcx
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rcx,%rax,4),%xmm0
  mulss  0x2c(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  lea    0x1(%rbx),%eax
  cmp    %eax,%ebp
  jne    L59
  lea    0x1(%r13),%eax
  cmp    %ebx,%r13d
  je     L41
  mov    %eax,%r13d
L14:
  lea    0x1(%r13),%eax
  cmp    %r13d,0x18(%rsp)
  mov    $0x0,%esi
  cmove  %esi,%eax
  mov    %eax,0x1c(%rsp)
  mov    $0x0,%ebx
  jmp    L53
L41:
  lea    0x1(%r15),%eax
  cmp    %ebx,%r15d
  je     L29
  mov    %eax,%r15d
L40:
  lea    0x1(%r15),%eax
  cmp    %r15d,0x18(%rsp)
  mov    $0x0,%esi
  cmove  %esi,%eax
  mov    %eax,0x28(%rsp)
  mov    $0x0,%r13d
  jmp    L14
```

assistant: ```c
float computeE(const int *s, const int *H, float h, int L) {
  float e = 0;
  for (int z = 0; z < L; ++z) {
    for (int y = 0; y < L; ++y) {
      for (int x = 0; x < L; ++x) {
        e -= (float)s[C(x, y, z, L)] * ((float)(s[C((x == L - 1) ? 0 : x + 1, y, z, L)] + s[C(x, (y == L - 1) ? 0 : y + 1, z, L)] + s[C(x, y, (z == L - 1) ? 0 : z + 1, L)]) + h * (float)H[C(x, y, z, L)]);
      }
    }
  }
  return e;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<computeE>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  movss  %xmm0,0x24(%rsp)
  test   %edx,%edx
  jle    L10
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r15
  mov    %edx,%ebx
  xor    %r12d,%r12d
  mov    %eax,0x10(%rsp)
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax,%rax,1)
L40:
  lea    0x1(%r12),%eax
  xor    %esi,%esi
  cmp    %r12d,0x10(%rsp)
  cmovne %eax,%esi
  mov    %eax,0x2c(%rsp)
  xor    %ebp,%ebp
  mov    %esi,0x20(%rsp)
  nopl   0x0(%rax)
L29:
  lea    0x1(%rbp),%eax
  xor    %edx,%edx
  cmp    %ebp,0x10(%rsp)
  cmovne %eax,%edx
  mov    %eax,0x28(%rsp)
  xor    %r14d,%r14d
  mov    %edx,0x14(%rsp)
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r14d,%edi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  movss  %xmm1,0xc(%rsp)
  mov    %r14d,%r13d
  add    $0x1,%r14d
  call   <C@plt>
  pxor   %xmm2,%xmm2
  xor    %edi,%edi
  cmp    %r13d,0x10(%rsp)
  cvtsi2ssl (%r15,%rax,4),%xmm2
  cmovne %r14d,%edi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  movss  %xmm2,0x4(%rsp)
  call   <C@plt>
  mov    0x14(%rsp),%esi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    (%r15,%rax,4),%r9d
  mov    %r13d,%edi
  mov    %r9d,0x8(%rsp)
  call   <C@plt>
  mov    0x20(%rsp),%edx
  mov    0x8(%rsp),%r9d
  mov    %ebx,%ecx
  add    (%r15,%rax,4),%r9d
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    %r9d,0x8(%rsp)
  call   <C@plt>
  mov    0x8(%rsp),%r9d
  pxor   %xmm3,%xmm3
  mov    %ebx,%ecx
  add    (%r15,%rax,4),%r9d
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  cvtsi2ss %r9d,%xmm3
  movss  %xmm3,0x8(%rsp)
  call   <C@plt>
  mov    0x18(%rsp),%rcx
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ssl (%rcx,%rax,4),%xmm0
  mulss  0x24(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  subss  %xmm0,%xmm1
  cmp    %ebx,%r14d
  jne    L6
  mov    0x28(%rsp),%eax
  cmp    %eax,%ebx
  je     L50
  mov    %eax,%ebp
  jmp    L29
  nopl   0x0(%rax)
L50:
  cmp    %r12d,%ebp
  je     L56
  mov    0x2c(%rsp),%r12d
  jmp    L40
L10:
  pxor   %xmm1,%xmm1
L56:
  add    $0x38,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float computeE(const int *s, const int *H, float h, int L) {
  float e = 0;
  for (int z = 0; z < L; ++z) {
    for (int y = 0; y < L; ++y) {
      for (int x = 0; x < L; ++x) {
        e -= (float)s[C(x, y, z, L)] * ((float)(s[C((x == L - 1) ? 0 : x + 1, y, z, L)] + s[C(x, (y == L - 1) ? 0 : y + 1, z, L)] + s[C(x, y, (z == L - 1) ? 0 : z + 1, L)]) + h * (float)H[C(x, y, z, L)]);
      }
    }
  }
  return e;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<computeE>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  movss  %xmm0,0x24(%rsp)
  test   %edx,%edx
  jle    L35
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r15
  mov    %edx,%ebx
  xor    %r12d,%r12d
  mov    %eax,0x10(%rsp)
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax,%rax,1)
L4:
  lea    0x1(%r12),%eax
  xor    %esi,%esi
  cmp    %r12d,0x10(%rsp)
  cmovne %eax,%esi
  mov    %eax,0x2c(%rsp)
  xor    %ebp,%ebp
  mov    %esi,0x20(%rsp)
  nopl   0x0(%rax)
L16:
  lea    0x1(%rbp),%eax
  xor    %edx,%edx
  cmp    %ebp,0x10(%rsp)
  cmovne %eax,%edx
  mov    %eax,0x28(%rsp)
  xor    %r14d,%r14d
  mov    %edx,0x14(%rsp)
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %r14d,%edi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  movss  %xmm1,0xc(%rsp)
  mov    %r14d,%r13d
  add    $0x1,%r14d
  call   <C@plt>
  pxor   %xmm2,%xmm2
  xor    %edi,%edi
  cmp    %r13d,0x10(%rsp)
  cvtsi2ssl (%r15,%rax,4),%xmm2
  cmovne %r14d,%edi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  movss  %xmm2,0x4(%rsp)
  call   <C@plt>
  mov    0x14(%rsp),%esi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    (%r15,%rax,4),%r9d
  mov    %r13d,%edi
  mov    %r9d,0x8(%rsp)
  call   <C@plt>
  mov    0x20(%rsp),%edx
  mov    0x8(%rsp),%r9d
  mov    %ebx,%ecx
  add    (%r15,%rax,4),%r9d
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    %r9d,0x8(%rsp)
  call   <C@plt>
  mov    0x8(%rsp),%r9d
  pxor   %xmm3,%xmm3
  mov    %ebx,%ecx
  add    (%r15,%rax,4),%r9d
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  cvtsi2ss %r9d,%xmm3
  movss  %xmm3,0x8(%rsp)
  call   <C@plt>
  mov    0x18(%rsp),%rcx
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ssl (%rcx,%rax,4),%xmm0
  mulss  0x24(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  subss  %xmm0,%xmm1
  cmp    %ebx,%r14d
  jne    L47
  mov    0x28(%rsp),%eax
  cmp    %eax,%ebx
  je     L30
  mov    %eax,%ebp
  jmp    L16
  nopl   0x0(%rax)
L30:
  cmp    %r12d,%ebp
  je     L8
  mov    0x2c(%rsp),%r12d
  jmp    L4
L35:
  pxor   %xmm1,%xmm1
L8:
  add    $0x38,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float computeE(const int *s, const int *H, float h, int L) {
  float e = 0;
  for (int z = 0; z < L; ++z) {
    for (int y = 0; y < L; ++y) {
      for (int x = 0; x < L; ++x) {
        e -= (float)s[C(x, y, z, L)] * ((float)(s[C((x == L - 1) ? 0 : x + 1, y, z, L)] + s[C(x, (y == L - 1) ? 0 : y + 1, z, L)] + s[C(x, y, (z == L - 1) ? 0 : z + 1, L)]) + h * (float)H[C(x, y, z, L)]);
      }
    }
  }
  return e;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L23
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <check_params@plt>
  cmp    $0x1,%eax
  jne    L23
  mov    $0x1,%eax
  jmp    L30
L23:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <game@plt>
  cmp    $0x1,%eax
  jne    L40
  mov    $0x1,%eax
  jmp    L30
L40:
  mov    $0x0,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int main(int ac, char **av) {
  int size;
  int mode;
  size = 4;
  mode = 1;
  if (ac > 1 && check_params(av, &size, &mode) == 1)
    return (1);
  if (game(size, mode) == 1)
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movl   $0x4,(%rsp)
  movl   $0x1,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L18
  mov    %rsi,%rdi
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <check_params@plt>
  cmp    $0x1,%eax
  je     L9
L18:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <game@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int ac, char **av) {
  int size;
  int mode;
  size = 4;
  mode = 1;
  if (ac > 1 && check_params(av, &size, &mode) == 1)
    return (1);
  if (game(size, mode) == 1)
    return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x1,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L9
  mov    %rsi,%rdi
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <check_params@plt>
  cmp    $0x1,%eax
  je     L3
L9:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <game@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int ac, char **av) {
  int size;
  int mode;
  size = 4;
  mode = 1;
  if (ac > 1 && check_params(av, &size, &mode) == 1)
    return (1);
  if (game(size, mode) == 1)
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x1,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L5
  mov    %rsi,%rdi
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <check_params@plt>
  cmp    $0x1,%eax
  je     L26
L5:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <game@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int ac, char **av) {
  int size;
  int mode;
  size = 4;
  mode = 1;
  if (ac > 1 && check_params(av, &size, &mode) == 1)
    return (1);
  if (game(size, mode) == 1)
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L19
L16:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D3(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <stdlib_base_is_nan@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x1,-0x20(%rbp)
  je     L28
  cmpl   $0x0,-0x20(%rbp)
  je     L28
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L61
L28:
  addl   $0x1,-0x1c(%rbp)
L19:
  cmpl   $0xf423f,-0x1c(%rbp)
  jle    L16
L61:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x1,-0x20(%rbp)
  je     L51
  cmpl   $0x0,-0x20(%rbp)
  je     L51
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: f64
name: retrieve_data
arguments: data_tag: D9
datatype: f64
name: retrieve_data
arguments: data_tag: D23
datatype: string

tool: D3: 10000000

tool: D9: 5000000

tool: D23: should return either true or false


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  bool b;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (rand_double() * 1.0e7) - 5.0e6;
    b = stdlib_base_is_nan(x);
    if (b != true && b != false) {
      printf("should return either true or false\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (b != true && b != false) {
    printf("should return either true or false\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L23:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D23(%rip),%xmm0
  subsd  D18(%rip),%xmm0
  call   <stdlib_base_is_nan@plt>
  cmp    $0x1,%eax
  ja     L18
  sub    $0x1,%ebx
  jne    L23
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L21
L18:
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L21:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: f64
name: unpack_data
arguments: label: D18
datatype: f64
name: unpack_data
arguments: label: D16
datatype: string

tool: D23: 10000000

tool: D18: 5000000

tool: D16: should return either true or false


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  bool b;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (rand_double() * 1.0e7) - 5.0e6;
    b = stdlib_base_is_nan(x);
    if (b != true && b != false) {
      printf("should return either true or false\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (b != true && b != false) {
    printf("should return either true or false\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L13
  xchg   %ax,%ax
L21:
  sub    $0x1,%ebx
  je     L3
L13:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D24(%rip),%xmm0
  subsd  D25(%rip),%xmm0
  call   <stdlib_base_is_nan@plt>
  cmp    $0x1,%eax
  jbe    L21
  lea    D28(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D24
type_guessed: f64
name: retrieve_data
arguments: tag: D25
type_guessed: f64
name: retrieve_data
arguments: tag: D28
type_guessed: string

tool: D24: 10000000

tool: D25: 5000000

tool: D28: should return either true or false


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  bool b;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (rand_double() * 1.0e7) - 5.0e6;
    b = stdlib_base_is_nan(x);
    if (b != true && b != false) {
      printf("should return either true or false\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (b != true && b != false) {
    printf("should return either true or false\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L1
  xchg   %ax,%ax
L12:
  sub    $0x1,%ebx
  je     L26
L1:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D19(%rip),%xmm0
  subsd  D22(%rip),%xmm0
  call   <stdlib_base_is_nan@plt>
  cmp    $0x1,%eax
  jbe    L12
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L26:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D22
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D19: 10000000

tool: D22: 5000000

tool: D6: should return either true or false


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  bool b;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (rand_double() * 1.0e7) - 5.0e6;
    b = stdlib_base_is_nan(x);
    if (b != true && b != false) {
      printf("should return either true or false\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (b != true && b != false) {
    printf("should return either true or false\n");
  }
  return elapsed;
}
```