ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<PreshiftDctMatrix>:
  endbr64
  lea    0x100(%rdi),%rax
L9:
  sub    %esi,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L9
  ret
```

assistant: ```c
void PreshiftDctMatrix(matrix, shift) int *matrix;
int shift;
{
  static char RoutineName[] = "PreshiftDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    *mptr -= shift;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PreshiftDctMatrix>:
  endbr64
  lea    0x100(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L8:
  sub    %esi,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L8
  ret
```

assistant: ```c
void PreshiftDctMatrix(matrix, shift) int *matrix;
int shift;
{
  static char RoutineName[] = "PreshiftDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    *mptr -= shift;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PreshiftDctMatrix>:
  endbr64
  movdqu (%rdi),%xmm1
  movd   %esi,%xmm2
  pshufd $0x0,%xmm2,%xmm0
  psubd  %xmm0,%xmm1
  movups %xmm1,(%rdi)
  movdqu 0x10(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x10(%rdi)
  movdqu 0x20(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x20(%rdi)
  movdqu 0x30(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x30(%rdi)
  movdqu 0x40(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x40(%rdi)
  movdqu 0x50(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x50(%rdi)
  movdqu 0x60(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x60(%rdi)
  movdqu 0x70(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x70(%rdi)
  movdqu 0x80(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x80(%rdi)
  movdqu 0x90(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0x90(%rdi)
  movdqu 0xa0(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0xa0(%rdi)
  movdqu 0xb0(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0xb0(%rdi)
  movdqu 0xc0(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0xc0(%rdi)
  movdqu 0xd0(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0xd0(%rdi)
  movdqu 0xe0(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0xe0(%rdi)
  movdqu 0xf0(%rdi),%xmm1
  psubd  %xmm0,%xmm1
  movups %xmm1,0xf0(%rdi)
  ret
```

assistant: ```c
void PreshiftDctMatrix(matrix, shift) int *matrix;
int shift;
{
  static char RoutineName[] = "PreshiftDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    *mptr -= shift;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <times@plt>
  imul   $0x2710,%rax,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
clock_t clock() {
  struct tms tms;
  return (unsigned long)times(&tms) * 10000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clock>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <times@plt>
  imul   $0x2710,%rax,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
clock_t clock() {
  struct tms tms;
  return (unsigned long)times(&tms) * 10000;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clock>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <times@plt>
  imul   $0x2710,%rax,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
clock_t clock() {
  struct tms tms;
  return (unsigned long)times(&tms) * 10000;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clock>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <times@plt>
  imul   $0x2710,%rax,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
clock_t clock() {
  struct tms tms;
  return (unsigned long)times(&tms) * 10000;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x0,-0x4(%rbp)
  jmp    L50
L17:
  movzwl -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %ax,-0x2(%rbp)
  movb   $0x0,-0x5(%rbp)
  jmp    L44
L47:
  movzwl -0x2(%rbp),%eax
  test   %ax,%ax
  jns    L8
  movzwl -0x2(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %ax,-0x2(%rbp)
  jmp    L36
L8:
  shlw   -0x2(%rbp)
L36:
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
L44:
  cmpb   $0x7,-0x5(%rbp)
  jbe    L47
  movzwl -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzwl -0x2(%rbp),%eax
  mov    %ax,(%rdx)
  movzwl -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4(%rbp)
L50:
  cmpw   $0xff,-0x4(%rbp)
  jbe    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((noipa)) void foo(unsigned short *x) {
  unsigned short i, v;
  unsigned char j;
  for (i = 0; i < 256; i++) {
    v = i << 8;
    for (j = 0; j < 8; j++)
      if (v & 0x8000)
        v = (v << 1) ^ 0x1021;
      else
        v = v << 1;
    x[i] = v;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  mov    %rdi,%r8
  mov    $0x0,%edi
  jmp    L35
L19:
  mov    %ax,(%r8,%rdi,2)
  add    $0x1,%rdi
  cmp    $0x100,%rdi
  je     L1
L35:
  mov    %edi,%eax
  shl    $0x8,%eax
  mov    $0x8,%ecx
L13:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  lea    (%rax,%rax,1),%esi
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%cl
  jne    L13
  jmp    L19
L1:
  ret
```

assistant: ```c
__attribute__((noipa)) void foo(unsigned short *x) {
  unsigned short i, v;
  unsigned char j;
  for (i = 0; i < 256; i++) {
    v = i << 8;
    for (j = 0; j < 8; j++)
      if (v & 0x8000)
        v = (v << 1) ^ 0x1021;
      else
        v = v << 1;
    x[i] = v;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  mov    %rdi,%r8
  xor    %edi,%edi
  nopl   0x0(%rax)
L5:
  mov    %edi,%eax
  mov    $0x8,%ecx
  shl    $0x8,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  lea    (%rax,%rax,1),%edx
  lea    (%rax,%rax,1),%esi
  xor    $0x1021,%dx
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%cl
  jne    L19
  mov    %ax,(%r8,%rdi,2)
  add    $0x1,%rdi
  cmp    $0x100,%rdi
  jne    L5
  ret
```

assistant: ```c
__attribute__((noipa)) void foo(unsigned short *x) {
  unsigned short i, v;
  unsigned char j;
  for (i = 0; i < 256; i++) {
    v = i << 8;
    for (j = 0; j < 8; j++)
      if (v & 0x8000)
        v = (v << 1) ^ 0x1021;
      else
        v = v << 1;
    x[i] = v;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  movdqa D26(%rip),%xmm3
  movdqa D29(%rip),%xmm4
  mov    %rdi,%rax
  lea    0x200(%rdi),%rdx
  movdqa D24(%rip),%xmm2
  pxor   %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L3:
  movdqa %xmm3,%xmm5
  add    $0x10,%rax
  paddw  %xmm4,%xmm3
  movdqa %xmm5,%xmm0
  psllw  $0x9,%xmm5
  psllw  $0x8,%xmm0
  movdqa %xmm0,%xmm6
  pminsw %xmm1,%xmm0
  pcmpeqw %xmm1,%xmm0
  psllw  $0x1,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm0,%xmm5
  pandn  %xmm6,%xmm0
  por    %xmm5,%xmm0
  movdqa %xmm0,%xmm5
  pminsw %xmm1,%xmm0
  pcmpeqw %xmm1,%xmm0
  psllw  $0x1,%xmm5
  movdqa %xmm5,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm0,%xmm5
  pandn  %xmm6,%xmm0
  por    %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  movdqa %xmm0,%xmm7
  pcmpgtw %xmm0,%xmm5
  psllw  $0x1,%xmm7
  movdqa %xmm7,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm5,%xmm6
  pandn  %xmm7,%xmm5
  movdqa %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  por    %xmm6,%xmm0
  movdqa %xmm0,%xmm7
  pcmpgtw %xmm0,%xmm5
  movdqa %xmm1,%xmm0
  psllw  $0x1,%xmm7
  movdqa %xmm7,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm5,%xmm6
  pandn  %xmm7,%xmm5
  por    %xmm6,%xmm5
  movdqa %xmm5,%xmm7
  pcmpgtw %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  psllw  $0x1,%xmm7
  movdqa %xmm7,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm0,%xmm6
  pandn  %xmm7,%xmm0
  por    %xmm6,%xmm0
  movdqa %xmm0,%xmm7
  pcmpgtw %xmm0,%xmm5
  movdqa %xmm1,%xmm0
  psllw  $0x1,%xmm7
  movdqa %xmm7,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm5,%xmm6
  pandn  %xmm7,%xmm5
  por    %xmm6,%xmm5
  movdqa %xmm5,%xmm7
  pcmpgtw %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  psllw  $0x1,%xmm7
  movdqa %xmm7,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm0,%xmm6
  pandn  %xmm7,%xmm0
  por    %xmm6,%xmm0
  movdqa %xmm0,%xmm7
  pcmpgtw %xmm0,%xmm5
  psllw  $0x1,%xmm7
  movdqa %xmm7,%xmm6
  pxor   %xmm2,%xmm6
  pand   %xmm5,%xmm6
  pandn  %xmm7,%xmm5
  por    %xmm6,%xmm5
  movups %xmm5,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L3
  ret
```

tool_calls: name: read_data
arguments: data_label: D26
type: byte[16]
name: read_data
arguments: data_label: D29
type: byte[16]
name: read_data
arguments: data_label: D24
type: byte[16]

tool: {"D26": [0x00,0x00,0x01,0x00,0x02,0x00,0x03,0x00,0x04,0x00,0x05,0x00,0x06,0x00,0x07,0x00]}

tool: {"D29": [0x08,0x00,0x08,0x00,0x08,0x00,0x08,0x00,0x08,0x00,0x08,0x00,0x08,0x00,0x08,0x00]}

tool: {"D24": [0x21,0x10,0x21,0x10,0x21,0x10,0x21,0x10,0x21,0x10,0x21,0x10,0x21,0x10,0x21,0x10]}

assistant: ```c
__attribute__((noipa)) void foo(unsigned short *x) {
  unsigned short i, v;
  unsigned char j;
  for (i = 0; i < 256; i++) {
    v = i << 8;
    for (j = 0; j < 8; j++)
      if (v & 0x8000)
        v = (v << 1) ^ 0x1021;
      else
        v = v << 1;
    x[i] = v;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recv_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L22
L19:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L22:
  cmpq   $0x0,-0x28(%rbp)
  jle    L17
  cmpq   $0x0,-0x8(%rbp)
  jg     L19
L17:
  mov    -0x10(%rbp),%rax
  sub    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t recv_full(int fd, void *buf, ssize_t len) {
  char *p = buf;
  ssize_t recvd;
  for (recvd = 1; len > 0 && recvd > 0; len -= recvd, p += recvd)
    recvd = recv(fd, p, len, 0);
  return p - (char *)buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<recv_full>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  test   %rdx,%rdx
  jle    L15
  mov    %edi,%ebp
  mov    %rdx,%rbx
  mov    %rsi,%r13
L2:
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  sub    %rax,%rbx
  add    %rax,%r13
  test   %rbx,%rbx
  jle    L23
  test   %rax,%rax
  jg     L2
L23:
  mov    %r13,%rax
  sub    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %rsi,%r13
  jmp    L23
```

assistant: ```c
ssize_t recv_full(int fd, void *buf, ssize_t len) {
  char *p = buf;
  ssize_t recvd;
  for (recvd = 1; len > 0 && recvd > 0; len -= recvd, p += recvd)
    recvd = recv(fd, p, len, 0);
  return p - (char *)buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recv_full>:
  endbr64
  test   %rdx,%rdx
  jle    L12
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L15:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  xor    %ecx,%ecx
  mov    %ebp,%edi
  call   <recv@plt>
  sub    %rax,%rbx
  add    %rax,%r13
  test   %rbx,%rbx
  jle    L13
  test   %rax,%rax
  jg     L15
L13:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  sub    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
ssize_t recv_full(int fd, void *buf, ssize_t len) {
  char *p = buf;
  ssize_t recvd;
  for (recvd = 1; len > 0 && recvd > 0; len -= recvd, p += recvd)
    recvd = recv(fd, p, len, 0);
  return p - (char *)buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recv_full>:
  endbr64
  test   %rdx,%rdx
  jle    L0
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L4:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  xor    %ecx,%ecx
  mov    %ebp,%edi
  call   <recv@plt>
  sub    %rax,%rbx
  add    %rax,%r13
  test   %rbx,%rbx
  jle    L23
  test   %rax,%rax
  jg     L4
L23:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  sub    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
ssize_t recv_full(int fd, void *buf, ssize_t len) {
  char *p = buf;
  ssize_t recvd;
  for (recvd = 1; len > 0 && recvd > 0; len -= recvd, p += recvd)
    recvd = recv(fd, p, len, 0);
  return p - (char *)buf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<base64_encode_urlsafe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L20:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L30
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
  jmp    L32
L30:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L41
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L32
L41:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L32
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
L32:
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L20
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int base64_encode_urlsafe(char *encoded, const char *string, int len) {
  int i, k = 0;
  int encode_len = base64_encode(encoded, string, len);
  for (i = 0; i < encode_len; i++) {
    if (encoded[i] == '=') {
      encoded[i] = '\0';
      k++;
    } else if (encoded[i] == '+')
      encoded[i] = '-';
    else if (encoded[i] == '/')
      encoded[i] = '_';
  }
  return encode_len - k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<base64_encode_urlsafe>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <base64_encode@plt>
  test   %eax,%eax
  jle    L11
  mov    %rbx,%rdx
  lea    -0x1(%rax),%ecx
  lea    0x1(%rbx,%rcx,1),%rdi
  mov    $0x0,%r8d
  jmp    L27
L51:
  movb   $0x0,(%rdx)
  add    $0x1,%r8d
L67:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L59
L27:
  movzbl (%rdx),%ecx
  cmp    $0x3d,%cl
  je     L51
  cmp    $0x2b,%cl
  je     L38
  cmp    $0x2f,%cl
  jne    L67
  movb   $0x5f,(%rdx)
  jmp    L67
L38:
  movb   $0x2d,(%rdx)
  jmp    L67
L11:
  mov    $0x0,%r8d
L59:
  sub    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int base64_encode_urlsafe(char *encoded, const char *string, int len) {
  int i, k = 0;
  int encode_len = base64_encode(encoded, string, len);
  for (i = 0; i < encode_len; i++) {
    if (encoded[i] == '=') {
      encoded[i] = '\0';
      k++;
    } else if (encoded[i] == '+')
      encoded[i] = '-';
    else if (encoded[i] == '/')
      encoded[i] = '_';
  }
  return encode_len - k;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<base64_encode_urlsafe>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <base64_encode@plt>
  test   %eax,%eax
  jle    L2
  lea    -0x1(%rax),%edx
  mov    %rbx,%rdi
  xor    %esi,%esi
  lea    0x1(%rbx,%rdx,1),%rcx
  jmp    L8
L70:
  cmp    $0x2b,%dl
  je     L73
  cmp    $0x2f,%dl
  jne    L10
  movb   $0x5f,(%rdi)
L10:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  je     L44
L8:
  movzbl (%rdi),%edx
  cmp    $0x3d,%dl
  jne    L70
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%esi
  cmp    %rcx,%rdi
  jne    L8
L44:
  sub    %esi,%eax
L2:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L73:
  movb   $0x2d,(%rdi)
  jmp    L10
```

assistant: ```c
int base64_encode_urlsafe(char *encoded, const char *string, int len) {
  int i, k = 0;
  int encode_len = base64_encode(encoded, string, len);
  for (i = 0; i < encode_len; i++) {
    if (encoded[i] == '=') {
      encoded[i] = '\0';
      k++;
    } else if (encoded[i] == '+')
      encoded[i] = '-';
    else if (encoded[i] == '/')
      encoded[i] = '_';
  }
  return encode_len - k;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<base64_encode_urlsafe>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <base64_encode@plt>
  test   %eax,%eax
  jle    L53
  lea    -0x1(%rax),%edx
  mov    %rbx,%rdi
  xor    %esi,%esi
  lea    0x1(%rbx,%rdx,1),%rcx
  jmp    L50
L2:
  cmp    $0x2b,%dl
  je     L6
  cmp    $0x2f,%dl
  jne    L59
  movb   $0x5f,(%rdi)
L59:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  je     L24
L50:
  movzbl (%rdi),%edx
  cmp    $0x3d,%dl
  jne    L2
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%esi
  cmp    %rcx,%rdi
  jne    L50
L24:
  sub    %esi,%eax
L53:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  movb   $0x2d,(%rdi)
  jmp    L59
```

assistant: ```c
int base64_encode_urlsafe(char *encoded, const char *string, int len) {
  int i, k = 0;
  int encode_len = base64_encode(encoded, string, len);
  for (i = 0; i < encode_len; i++) {
    if (encoded[i] == '=') {
      encoded[i] = '\0';
      k++;
    } else if (encoded[i] == '+')
      encoded[i] = '-';
    else if (encoded[i] == '/')
      encoded[i] = '_';
  }
  return encode_len - k;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L2
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
L2:
  nop
  leave
  ret
```

assistant: ```c
void quicksort(int A[], int p, int r) {
  int q = 0;
  if (p < r) {
    q = partition(A, p, r);
    quicksort(A, p, q - 1);
    quicksort(A, q + 1, r);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jl     L7
  ret
L7:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quicksort(int A[], int p, int r) {
  int q = 0;
  if (p < r) {
    q = partition(A, p, r);
    quicksort(A, p, q - 1);
    quicksort(A, q + 1, r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  fputc('\n', stderr);
  va_end(ap);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<die>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D8(%rip),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    (%r12),%edi
  call   <vfprintf@plt>
  mov    (%r12),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  fputc('\n', stderr);
  va_end(ap);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D7(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  fputc('\n', stderr);
  va_end(ap);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D3(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  fputc('\n', stderr);
  va_end(ap);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<key_esc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0x1b,-0x4(%rbp)
  jne    L2
  mov    $0x0,%edi
  call   <exit@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void key_esc(unsigned char key, int x, int y) {
  if (key == 27)
    exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<key_esc>:
  endbr64
  cmp    $0x1b,%dil
  je     L7
  ret
L7:
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void key_esc(unsigned char key, int x, int y) {
  if (key == 27)
    exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<key_esc>:
  endbr64
  cmp    $0x1b,%dil
  je     L5
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void key_esc(unsigned char key, int x, int y) {
  if (key == 27)
    exit(0);
}
```