ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<our_open>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
L6:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  jne    L17
  mov    D3(%rip),%rcx
  mov    D12(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L6
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int our_open(const char *const path, const int flags, const int mode) {
  do {
    const int fd = open(path, flags, mode);
    if (fd != -1) {
      return fd;
    }
  } while (errno == EINTR);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<our_open>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  jmp    L22
  nopl   0x0(%rax)
L18:
  mov    D15(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L28
L22:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L18
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int our_open(const char *const path, const int flags, const int mode) {
  do {
    const int fd = open(path, flags, mode);
    if (fd != -1) {
      return fd;
    }
  } while (errno == EINTR);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<our_open>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  jmp    L0
  nopl   0x0(%rax)
L27:
  mov    D0(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L17
L0:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L27
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int our_open(const char *const path, const int flags, const int mode) {
  do {
    const int fd = open(path, flags, mode);
    if (fd != -1) {
      return fd;
    }
  } while (errno == EINTR);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<decimalvalue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x36,%eax
  ja     L133
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L34
  mov    $0x1,%eax
  jmp    L34
  mov    $0x2,%eax
  jmp    L34
  mov    $0x3,%eax
  jmp    L34
  mov    $0x4,%eax
  jmp    L34
  mov    $0x5,%eax
  jmp    L34
  mov    $0x6,%eax
  jmp    L34
  mov    $0x7,%eax
  jmp    L34
  mov    $0x8,%eax
  jmp    L34
  mov    $0x9,%eax
  jmp    L34
  mov    $0xa,%eax
  jmp    L34
  mov    $0xb,%eax
  jmp    L34
  mov    $0xc,%eax
  jmp    L34
  mov    $0xd,%eax
  jmp    L34
  mov    $0xe,%eax
  jmp    L34
  mov    $0xf,%eax
  jmp    L34
L133:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int decimalvalue(char hex) {
  switch (hex) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  case 'a':
    return 10;
    break;
  case 'b':
    return 11;
    break;
  case 'c':
    return 12;
    break;
  case 'd':
    return 13;
    break;
  case 'e':
    return 14;
    break;
  case 'f':
    return 15;
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decimalvalue>:
  endbr64
  sub    $0x31,%edi
  cmp    $0x35,%dil
  ja     L0
  movzbl %dil,%edi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xf,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int decimalvalue(char hex) {
  switch (hex) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  case 'a':
    return 10;
    break;
  case 'b':
    return 11;
    break;
  case 'c':
    return 12;
    break;
  case 'd':
    return 13;
    break;
  case 'e':
    return 14;
    break;
  case 'f':
    return 15;
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decimalvalue>:
  endbr64
  sub    $0x31,%edi
  xor    %eax,%eax
  cmp    $0x35,%dil
  ja     L8
  movzbl %dil,%edi
  lea    D4(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: 	

assistant: ```c
int decimalvalue(char hex) {
  switch (hex) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  case 'a':
    return 10;
    break;
  case 'b':
    return 11;
    break;
  case 'c':
    return 12;
    break;
  case 'd':
    return 13;
    break;
  case 'e':
    return 14;
    break;
  case 'f':
    return 15;
    break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decimalvalue>:
  endbr64
  sub    $0x31,%edi
  xor    %eax,%eax
  cmp    $0x35,%dil
  ja     L7
  movzbl %dil,%edi
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L7:
  ret
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: 	

assistant: ```c
int decimalvalue(char hex) {
  switch (hex) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  case 'a':
    return 10;
    break;
  case 'b':
    return 11;
    break;
  case 'c':
    return 12;
    break;
  case 'd':
    return 13;
    break;
  case 'e':
    return 14;
    break;
  case 'f':
    return 15;
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testLsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testLsrImplied@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrZeropage@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrZeropageX@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrAbsolute@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrAbsoluteX@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D33
type_infered: string
name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D31
type_infered: string

tool: D6: testLsrImplied: %d


tool: D33: testLsrZeropage: %d


tool: D7: testLdyZeropageX: %d


tool: D16: testLsrAbsolute: %d


tool: D31: testLsrAbsoluteX: %d


assistant: ```c
void testLsr() {
  printf("testLsrImplied: %d\r\n", testLsrImplied());
  printf("testLsrZeropage: %d\r\n", testLsrZeropage());
  printf("testLdyZeropageX: %d\r\n", testLsrZeropageX());
  printf("testLsrAbsolute: %d\r\n", testLsrAbsolute());
  printf("testLsrAbsoluteX: %d\r\n", testLsrAbsoluteX());
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testLsr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testLsrImplied@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrZeropage@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrZeropageX@plt>
  mov    %eax,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrAbsolute@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testLsrAbsoluteX@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D28
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D35
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D44
type_guessed: string

tool: D28: testLsrImplied: %d


tool: D13: testLsrZeropage: %d


tool: D35: testLdyZeropageX: %d


tool: D4: testLsrAbsolute: %d


tool: D44: testLsrAbsoluteX: %d


assistant: ```c
void testLsr() {
  printf("testLsrImplied: %d\r\n", testLsrImplied());
  printf("testLsrZeropage: %d\r\n", testLsrZeropage());
  printf("testLdyZeropageX: %d\r\n", testLsrZeropageX());
  printf("testLsrAbsolute: %d\r\n", testLsrAbsolute());
  printf("testLsrAbsoluteX: %d\r\n", testLsrAbsoluteX());
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testLsr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testLsrImplied@plt>
  lea    D40(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrZeropage@plt>
  lea    D42(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrZeropageX@plt>
  lea    D35(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrAbsolute@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrAbsoluteX@plt>
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    10b0 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D40
data_type: string
name: extract_symbolic_data
arguments: data_label: D42
data_type: string
name: extract_symbolic_data
arguments: data_label: D35
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string

tool: D40: testLsrImplied: %d


tool: D42: testLsrZeropage: %d


tool: D35: testLdyZeropageX: %d


tool: D1: testLsrAbsolute: %d


tool: D11: testLsrAbsoluteX: %d


assistant: ```c
void testLsr() {
  printf("testLsrImplied: %d\r\n", testLsrImplied());
  printf("testLsrZeropage: %d\r\n", testLsrZeropage());
  printf("testLdyZeropageX: %d\r\n", testLsrZeropageX());
  printf("testLsrAbsolute: %d\r\n", testLsrAbsolute());
  printf("testLsrAbsoluteX: %d\r\n", testLsrAbsoluteX());
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testLsr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testLsrImplied@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrZeropage@plt>
  lea    D47(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrZeropageX@plt>
  lea    D28(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrAbsolute@plt>
  lea    D43(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testLsrAbsoluteX@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    10b0 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D47
datatype: string
name: read_data
arguments: data_label: D28
datatype: string
name: read_data
arguments: data_label: D43
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D4: testLsrImplied: %d


tool: D47: testLsrZeropage: %d


tool: D28: testLdyZeropageX: %d


tool: D43: testLsrAbsolute: %d


tool: D14: testLsrAbsoluteX: %d


assistant: ```c
void testLsr() {
  printf("testLsrImplied: %d\r\n", testLsrImplied());
  printf("testLsrZeropage: %d\r\n", testLsrZeropage());
  printf("testLdyZeropageX: %d\r\n", testLsrZeropageX());
  printf("testLsrAbsolute: %d\r\n", testLsrAbsolute());
  printf("testLsrAbsoluteX: %d\r\n", testLsrAbsoluteX());
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stringsMatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L1
L31:
  movswq -0x2(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movswq -0x2(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L49
  mov    $0x0,%eax
  jmp    L8
L49:
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L1:
  movswq -0x2(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  movswq -0x2(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
L14:
  mov    $0x1,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
char stringsMatch(const char *str1, const char *str2) {
  short i;
  for (i = 0; str1[i] && str2[i]; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stringsMatch>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  test   %al,%al
  je     L14
L36:
  movzbl (%rsi,%rdx,1),%edx
  test   %dl,%dl
  je     L32
  cmp    %al,%dl
  jne    L15
  add    $0x1,%ecx
  movswq %cx,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L36
  mov    $0x1,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
L32:
  mov    $0x1,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char stringsMatch(const char *str1, const char *str2) {
  short i;
  for (i = 0; str1[i] && str2[i]; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringsMatch>:
  endbr64
  movzbl (%rdi),%eax
  xor    %ecx,%ecx
  xor    %edx,%edx
  test   %al,%al
  jne    L49
  jmp    L2
  nopl   0x0(%rax)
L43:
  cmp    %al,%dl
  jne    L23
  add    $0x1,%ecx
  movswq %cx,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L2
L49:
  movzbl (%rsi,%rdx,1),%edx
  test   %dl,%dl
  jne    L43
L2:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
char stringsMatch(const char *str1, const char *str2) {
  short i;
  for (i = 0; str1[i] && str2[i]; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stringsMatch>:
  endbr64
  movzbl (%rdi),%eax
  xor    %ecx,%ecx
  xor    %edx,%edx
  test   %al,%al
  jne    L34
  jmp    L24
  nopl   0x0(%rax)
L39:
  cmp    %al,%dl
  jne    L42
  add    $0x1,%ecx
  movswq %cx,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L24
L34:
  movzbl (%rsi,%rdx,1),%edx
  test   %dl,%dl
  jne    L39
L24:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
char stringsMatch(const char *str1, const char *str2) {
  short i;
  for (i = 0; str1[i] && str2[i]; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_standard_state_to_silent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x27,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int set_standard_state_to_silent(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(39, a, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_standard_state_to_silent>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x27,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int set_standard_state_to_silent(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(39, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_standard_state_to_silent>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x27,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int set_standard_state_to_silent(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(39, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_standard_state_to_silent>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x27,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int set_standard_state_to_silent(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(39, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<int_ripples>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x1a1d232b23262b31,%rax
  movabs $0x710192310151d26,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L49
L64:
  mov    $0x0,%edi
  call   <fill@plt>
  movb   $0x0,-0x28(%rbp)
  jmp    L48
L68:
  movb   $0x0,-0x27(%rbp)
  jmp    L19
L36:
  movzbl -0x28(%rbp),%edx
  movzbl -0x27(%rbp),%eax
  shl    $0x2,%eax
  add    %edx,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,-0x26(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x26(%rbp),%eax
  add    %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <totty_sin@plt>
  add    $0xc4,%eax
  movslq %eax,%rdx
  imul   $0x5397829d,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %al,-0x25(%rbp)
  movzbl -0x25(%rbp),%edx
  movzbl -0x27(%rbp),%ecx
  movzbl -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <setvoxel@plt>
  movzbl -0x25(%rbp),%edx
  movzbl -0x27(%rbp),%eax
  movzbl -0x28(%rbp),%esi
  mov    $0x7,%ecx
  sub    %esi,%ecx
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <setvoxel@plt>
  movzbl -0x25(%rbp),%edx
  movzbl -0x27(%rbp),%eax
  mov    $0x7,%ecx
  sub    %eax,%ecx
  movzbl -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <setvoxel@plt>
  movzbl -0x25(%rbp),%eax
  movzbl -0x27(%rbp),%edx
  mov    $0x7,%ecx
  mov    %ecx,%esi
  sub    %edx,%esi
  movzbl -0x28(%rbp),%edx
  mov    $0x7,%ecx
  sub    %edx,%ecx
  mov    %eax,%edx
  mov    %ecx,%edi
  call   <setvoxel@plt>
  movzbl -0x27(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x27(%rbp)
L19:
  cmpb   $0x3,-0x27(%rbp)
  jbe    L36
  movzbl -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x28(%rbp)
L48:
  cmpb   $0x3,-0x28(%rbp)
  jbe    L68
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <delay_ms@plt>
  addl   $0x4,-0x24(%rbp)
L49:
  mov    -0x34(%rbp),%eax
  shl    $0x2,%eax
  cmp    %eax,-0x24(%rbp)
  jl     L64
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void int_ripples(int iterations, int delay) {
  unsigned char sqrt_LUT[] = {49, 43, 38, 35, 43, 35, 29, 26, 38, 29, 21, 16, 35, 25, 16, 7};
  unsigned char x, y, height, distance;
  int i;
  for (i = 0; i < iterations * 4; i += 4) {
    fill(0x00);
    for (x = 0; x < 4; x++)
      for (y = 0; y < 4; y++) {
        distance = sqrt_LUT[x + y * 4];
        height = (196 + totty_sin(distance + i)) / 49;
        setvoxel(x, y, height);
        setvoxel(7 - x, y, height);
        setvoxel(x, 7 - y, height);
        setvoxel(7 - x, 7 - y, height);
      }
    delay_ms(delay);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int_ripples>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x1a1d232b23262b31,%rax
  movabs $0x710192310151d26,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x0(,%rdi,4),%eax
  mov    %eax,0x8(%rsp)
  test   %eax,%eax
  jle    L10
  movl   $0x0,0x4(%rsp)
  jmp    L29
L7:
  mov    0xc(%rsp),%edi
  call   <delay_ms@plt>
  addl   $0x4,0x4(%rsp)
  mov    0x4(%rsp),%eax
  cmp    0x8(%rsp),%eax
  jge    L10
L29:
  mov    $0x0,%edi
  call   <fill@plt>
  lea    0x10(%rsp),%r15
  mov    $0x7,%r14d
  mov    $0x0,%r13d
L13:
  mov    $0x0,%ebp
L60:
  movzbl 0x4(%rsp),%edi
  add    (%r15,%rbp,4),%dil
  movzbl %dil,%edi
  call   <totty_sin@plt>
  add    $0xc4,%eax
  movslq %eax,%rbx
  imul   $0x5397829d,%rbx,%rbx
  sar    $0x24,%rbx
  sar    $0x1f,%eax
  sub    %eax,%ebx
  movzbl %bl,%ebx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <setvoxel@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <setvoxel@plt>
  mov    $0x7,%r12d
  sub    %ebp,%r12d
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <setvoxel@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <setvoxel@plt>
  add    $0x1,%rbp
  cmp    $0x4,%rbp
  jne    L60
  add    $0x1,%r13d
  add    $0x1,%r15
  sub    $0x1,%r14d
  cmp    $0x4,%r13d
  jne    L13
  jmp    L7
L10:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void int_ripples(int iterations, int delay) {
  unsigned char sqrt_LUT[] = {49, 43, 38, 35, 43, 35, 29, 26, 38, 29, 21, 16, 35, 25, 16, 7};
  unsigned char x, y, height, distance;
  int i;
  for (i = 0; i < iterations * 4; i += 4) {
    fill(0x00);
    for (x = 0; x < 4; x++)
      for (y = 0; y < 4; y++) {
        distance = sqrt_LUT[x + y * 4];
        height = (196 + totty_sin(distance + i)) / 49;
        setvoxel(x, y, height);
        setvoxel(7 - x, y, height);
        setvoxel(x, 7 - y, height);
        setvoxel(7 - x, 7 - y, height);
      }
    delay_ms(delay);
  }
}
```