ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmd_str>:
  endbr64
  cmp    $0x7,%edi
  ja     L6
  lea    D31(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D34(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D94(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D22(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D68(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D36(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D92(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D2(%rip),%rax
  ret
L6:
  lea    D72(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D31
data_type: string
name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D34
data_type: string
name: unpack_data
arguments: data_label: D94
data_type: string
name: unpack_data
arguments: data_label: D22
data_type: string
name: unpack_data
arguments: data_label: D68
data_type: string
name: unpack_data
arguments: data_label: D36
data_type: string
name: unpack_data
arguments: data_label: D92
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D72
data_type: string

tool: 

tool: D28: INW

tool: D34: INB

tool: D94: INTERRUPT

tool: D22: OUTSW

tool: D68: ERROR

tool: D36: INSW

tool: D92: OUTB

tool: D2: OUTW

tool: D72: ??

assistant: ```c
const char *cmd_str(int cmd) {
  switch (cmd) {
  case 0:
    return "INB";
  case 1:
    return "INW";
  case 2:
    return "INSW";
  case 3:
    return "OUTB";
  case 4:
    return "OUTW";
  case 5:
    return "OUTSW";
  case 6:
    return "ERROR";
  case 7:
    return "INTERRUPT";
  default:
    return "??";
  };
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x2cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L23
L16:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jne    L25
  movzwl -0xa(%rbp),%eax
  mov    %eax,%edi
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%edx
  movzwl -0xa(%rbp),%eax
  shr    %ax
  movzwl %ax,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%edx
  movzwl -0xa(%rbp),%eax
  shr    %ax
  movzwl %ax,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  mov    $0x10,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edi,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  shr    $0x3,%ax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  jmp    L29
L25:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%ecx
  movzwl -0xa(%rbp),%edx
  movzwl -0xc(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  mov    %eax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  add    %eax,%eax
  shl    $0x4,%eax
  and    $0x3e0,%ax
  or     %eax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
L29:
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L16
  movzwl -0xa(%rbp),%eax
  lea    -0x1d89(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] == local1) {
        state[0UL] |= (((state[local1] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[local1] <<= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      } else {
        state[local1] |= state[0UL];
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned short)7561;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%r9
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  movzwl 0x2(%rdi),%r8d
  test   %r8w,%r8w
  je     L7
  mov    $0x0,%edx
  mov    $0x10,%r10d
  jmp    L43
L10:
  movzwl %ax,%r11d
  mov    %eax,%edi
  shr    %di
  and    $0xe,%edi
  or     $0x1,%edi
  mov    %r10d,%ecx
  sub    %edi,%ecx
  mov    %r11d,%esi
  sar    %cl,%esi
  mov    %edi,%ecx
  shl    %cl,%r11d
  or     %r11d,%esi
  shl    $0x4,%esi
  and    $0x1f0,%si
  or     %esi,%eax
  mov    %eax,%ecx
  shr    $0x3,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
L42:
  add    $0x1,%edx
  cmp    %r8w,%dx
  je     L7
L43:
  cmp    %dx,%ax
  je     L10
  mov    %eax,%ecx
  shl    $0x5,%ecx
  and    $0x3e0,%cx
  or     %ecx,%eax
  jmp    L42
L7:
  sub    $0x1d89,%ax
  mov    %ax,(%r9)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] == local1) {
        state[0UL] |= (((state[local1] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[local1] <<= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      } else {
        state[local1] |= state[0UL];
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned short)7561;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%r8d
  mov    %rsi,%r9
  lea    0x2cdb(%rax),%edx
  test   %r8w,%r8w
  je     L44
  xor    %esi,%esi
  mov    $0x10,%r10d
  jmp    L35
  nopl   (%rax)
L7:
  shl    $0x5,%eax
  add    $0x1,%esi
  and    $0x3e0,%ax
  or     %eax,%edx
  cmp    %r8w,%si
  je     L44
L35:
  movzwl %dx,%eax
  cmp    %si,%dx
  jne    L7
  mov    %edx,%r11d
  mov    %r10d,%ecx
  mov    %eax,%edi
  add    $0x1,%esi
  shr    %r11w
  and    $0xe,%r11d
  or     $0x1,%r11d
  sub    %r11d,%ecx
  sar    %cl,%edi
  mov    %r11d,%ecx
  shl    %cl,%eax
  or     %edi,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edx,%eax
  mov    %eax,%ecx
  shr    $0x3,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  cmp    %r8w,%si
  jne    L35
L44:
  sub    $0x1d89,%dx
  mov    %dx,(%r9)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] == local1) {
        state[0UL] |= (((state[local1] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[local1] <<= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      } else {
        state[local1] |= state[0UL];
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned short)7561;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  mov    %rsi,%r8
  add    $0x2cdb,%ax
  test   %di,%di
  je     L8
  xor    %esi,%esi
  mov    $0x10,%r9d
  nop
L4:
  movzwl %ax,%edx
  cmp    %ax,%si
  je     L7
  shl    $0x5,%edx
  add    $0x1,%esi
  and    $0x3e0,%dx
  or     %edx,%eax
  cmp    %si,%di
  jne    L4
L8:
  sub    $0x1d89,%ax
  mov    %ax,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %esi,%r10d
  mov    %r9d,%ecx
  mov    %edx,%eax
  shr    %r10w
  and    $0xe,%r10d
  or     $0x1,%r10d
  sub    %r10d,%ecx
  sar    %cl,%eax
  mov    %r10d,%ecx
  shl    %cl,%edx
  or     %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %esi,%eax
  add    $0x1,%esi
  mov    %eax,%ecx
  shr    $0x3,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  cmp    %si,%di
  jne    L4
  sub    $0x1d89,%ax
  mov    %ax,(%r8)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] == local1) {
        state[0UL] |= (((state[local1] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[local1] <<= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      } else {
        state[local1] |= state[0UL];
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned short)7561;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<regress_fit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L10
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,(%rdx)
  movl   $0x2,-0x8(%rbp)
  jmp    L17
L28:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L28
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void regress_fit(data, a, ndata, ivar) float **data, *a;
int ndata, ivar;
{
  int i, j, ma = ivar + 1;
  for (i = 1; i <= ndata; i++) {
    data[i][ma] = a[1];
    for (j = 2; j <= ma; j++)
      data[i][ma] += data[i][j - 1] * a[j];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<regress_fit>:
  endbr64
  test   %edx,%edx
  jle    L22
  push   %rbx
  lea    0x1(%rcx),%r11d
  movslq %r11d,%r8
  shl    $0x2,%r8
  lea    0x8(%rdi),%r10
  lea    -0x1(%rdx),%eax
  lea    0x10(%rdi,%rax,8),%rbx
  lea    -0x1(%rcx),%eax
  lea    0x8(,%rax,4),%r9
L21:
  mov    %r10,%rdi
  movss  0x4(%rsi),%xmm0
  mov    (%r10),%rax
  movss  %xmm0,(%rax,%r8,1)
  cmp    $0x1,%r11d
  jle    L16
  mov    $0x4,%eax
L39:
  mov    (%rdi),%rcx
  lea    (%rcx,%r8,1),%rdx
  movss  (%rcx,%rax,1),%xmm0
  mulss  0x4(%rsi,%rax,1),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L39
L16:
  add    $0x8,%r10
  cmp    %rbx,%r10
  jne    L21
  pop    %rbx
  ret
L22:
  ret
```

assistant: ```c
void regress_fit(data, a, ndata, ivar) float **data, *a;
int ndata, ivar;
{
  int i, j, ma = ivar + 1;
  for (i = 1; i <= ndata; i++) {
    data[i][ma] = a[1];
    for (j = 2; j <= ma; j++)
      data[i][ma] += data[i][j - 1] * a[j];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<regress_fit>:
  endbr64
  lea    0x1(%rcx),%r10d
  test   %edx,%edx
  jle    L10
  lea    -0x1(%rdx),%eax
  movslq %r10d,%r9
  lea    0x8(%rdi),%r8
  lea    0x10(%rdi,%rax,8),%r11
  lea    -0x1(%rcx),%edi
  shl    $0x2,%r9
  add    $0x3,%rdi
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    (%r8),%rcx
  movss  0x4(%rsi),%xmm1
  mov    $0x2,%eax
  lea    (%rcx,%r9,1),%rdx
  movss  %xmm1,(%rdx)
  cmp    $0x1,%r10d
  jle    L6
  nopl   0x0(%rax,%rax,1)
L11:
  movss  -0x4(%rcx,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rdi,%rax
  jne    L11
L6:
  add    $0x8,%r8
  cmp    %r8,%r11
  jne    L25
  ret
L10:
  ret
```

assistant: ```c
void regress_fit(data, a, ndata, ivar) float **data, *a;
int ndata, ivar;
{
  int i, j, ma = ivar + 1;
  for (i = 1; i <= ndata; i++) {
    data[i][ma] = a[1];
    for (j = 2; j <= ma; j++)
      data[i][ma] += data[i][j - 1] * a[j];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<regress_fit>:
  endbr64
  lea    0x1(%rcx),%r10d
  test   %edx,%edx
  jle    L5
  lea    -0x1(%rdx),%eax
  movslq %r10d,%r9
  lea    0x8(%rdi),%r8
  lea    0x10(%rdi,%rax,8),%r11
  lea    -0x1(%rcx),%edi
  shl    $0x2,%r9
  add    $0x3,%rdi
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    (%r8),%rcx
  movss  0x4(%rsi),%xmm1
  mov    $0x2,%eax
  lea    (%rcx,%r9,1),%rdx
  movss  %xmm1,(%rdx)
  cmp    $0x1,%r10d
  jle    L21
  nopl   0x0(%rax,%rax,1)
L39:
  movss  -0x4(%rcx,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rax,%rdi
  jne    L39
L21:
  add    $0x8,%r8
  cmp    %r8,%r11
  jne    L38
  ret
L5:
  ret
```

assistant: ```c
void regress_fit(data, a, ndata, ivar) float **data, *a;
int ndata, ivar;
{
  int i, j, ma = ivar + 1;
  for (i = 1; i <= ndata; i++) {
    data[i][ma] = a[1];
    for (j = 2; j <= ma; j++)
      data[i][ma] += data[i][j - 1] * a[j];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char s[128];
  gets(s);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x98,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char s[128];
  gets(s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char s[128];
  gets(s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char s[128];
  gets(s);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<q__uhashf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L18:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  imul   $0x83,%eax,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L18
  mov    -0x10(%rbp),%edx
  mov    %edx,%ecx
  mov    $0xfa232cf3,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  shr    $0x7,%eax
  imul   $0x83,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int q__uhashf(void *str, unsigned int size) {
  unsigned int tmpr = 0;
  unsigned char *cstr = str;
  for (unsigned int i = 0; i < size; i++) {
    tmpr += cstr[i];
    tmpr *= 131;
  }
  return tmpr % 131;
}
```
user: Translate the below assembly code into C programming language:

```asm
<q__uhashf>:
  endbr64
  test   %esi,%esi
  je     L11
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  add    %rdx,%rdi
  mov    $0x0,%esi
L9:
  movzbl (%rax),%edx
  add    %edx,%esi
  imul   $0x83,%esi,%esi
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rdx
  jne    L9
L11:
  mov    %esi,%eax
  mov    $0xfa232cf3,%edx
  imul   %rdx,%rax
  shr    $0x27,%rax
  imul   $0x83,%eax,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int q__uhashf(void *str, unsigned int size) {
  unsigned int tmpr = 0;
  unsigned char *cstr = str;
  for (unsigned int i = 0; i < size; i++) {
    tmpr += cstr[i];
    tmpr *= 131;
  }
  return tmpr % 131;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<q__uhashf>:
  endbr64
  test   %esi,%esi
  je     L1
  lea    -0x1(%rsi),%ecx
  xor    %edx,%edx
  add    %rdi,%rcx
L7:
  movzbl (%rdi),%eax
  add    %eax,%edx
  mov    %rdi,%rax
  add    $0x1,%rdi
  imul   $0x83,%edx,%edx
  cmp    %rax,%rcx
  jne    L7
  mov    %edx,%eax
  mov    $0xfa232cf3,%ecx
  imul   %rcx,%rax
  shr    $0x27,%rax
  imul   $0x83,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int q__uhashf(void *str, unsigned int size) {
  unsigned int tmpr = 0;
  unsigned char *cstr = str;
  for (unsigned int i = 0; i < size; i++) {
    tmpr += cstr[i];
    tmpr *= 131;
  }
  return tmpr % 131;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<q__uhashf>:
  endbr64
  test   %esi,%esi
  je     L13
  lea    -0x1(%rsi),%ecx
  xor    %edx,%edx
  add    %rdi,%rcx
L15:
  movzbl (%rdi),%eax
  add    %eax,%edx
  mov    %rdi,%rax
  add    $0x1,%rdi
  imul   $0x83,%edx,%edx
  cmp    %rax,%rcx
  jne    L15
  mov    %edx,%eax
  mov    $0xfa232cf3,%ecx
  imul   %rcx,%rax
  shr    $0x27,%rax
  imul   $0x83,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int q__uhashf(void *str, unsigned int size) {
  unsigned int tmpr = 0;
  unsigned char *cstr = str;
  for (unsigned int i = 0; i < size; i++) {
    tmpr += cstr[i];
    tmpr *= 131;
  }
  return tmpr % 131;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<substringOf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L11:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substringOf(int i, int j, char *ch) {
  int n, k = 0;
  char *ch1;
  ch1 = (char *)malloc((j - i + 1) * 1);
  n = j - i + 1;
  while (k < n) {
    ch1[k] = ch[i];
    i++;
    k++;
  }
  return (char *)ch1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<substringOf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rdx,%rbx
  sub    %edi,%esi
  mov    %esi,%r12d
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  js     L14
  lea    0x1(%r12),%edi
  add    %rax,%rdi
  mov    %rax,%rdx
  movslq %ebp,%rbp
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rsi
L6:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L6
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substringOf(int i, int j, char *ch) {
  int n, k = 0;
  char *ch1;
  ch1 = (char *)malloc((j - i + 1) * 1);
  n = j - i + 1;
  while (k < n) {
    ch1[k] = ch[i];
    i++;
    k++;
  }
  return (char *)ch1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substringOf>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    %ebp,%esi
  mov    %rdx,%rbx
  movslq %esi,%r12
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  js     L0
  sub    %rax,%rbp
  lea    0x1(%rax,%r12,1),%r8
  mov    %rax,%rdx
  lea    (%rbx,%rbp,1),%rsi
  nopl   0x0(%rax)
L9:
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %r8,%rdx
  jne    L9
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substringOf(int i, int j, char *ch) {
  int n, k = 0;
  char *ch1;
  ch1 = (char *)malloc((j - i + 1) * 1);
  n = j - i + 1;
  while (k < n) {
    ch1[k] = ch[i];
    i++;
    k++;
  }
  return (char *)ch1;
}
```