ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<firstUniqChar>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x68,%edx
  mov    %eax,%ebx
  call   <memset@plt>
  test   %ebx,%ebx
  jle    L23
  lea    -0x1(%rbx),%eax
  mov    %rbp,%rdx
  lea    0x1(%rbp,%rax,1),%rcx
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl (%rdx),%eax
  add    $0x1,%rdx
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rcx
  jne    L0
  mov    %ebx,%eax
  xor    %ecx,%ecx
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L46:
  add    $0x1,%rcx
  cmp    %rcx,%rax
  je     L23
L59:
  movsbl 0x0(%rbp,%rcx,1),%edx
  mov    %ecx,%r8d
  sub    $0x61,%edx
  movslq %edx,%rdx
  cmpl   $0x1,(%rsp,%rdx,4)
  jne    L46
L16:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x78,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L23:
  mov    $0xffffffff,%r8d
  jmp    L16
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int firstUniqChar(char *s) {
  int cnt[26];
  int size = strlen(s);
  memset(cnt, 0, 26 * sizeof(int));
  for (int i = 0; i < size; i++) {
    cnt[s[i] - 'a']++;
  }
  for (int i = 0; i < size; i++) {
    if (cnt[s[i] - 'a'] == 1)
      return i;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  movss  D1(%rip),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D50(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  D1(%rip),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D50(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm0,%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D20
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: byte[4]
name: disassemble_data
arguments: label: D50
type_guessed: f64
name: disassemble_data
arguments: label: D22
type_guessed: string

tool: D20: %f %f

tool: {"D1": [0x00,0x00,0x34,0x43]}

tool: D50: 3.1415926

tool: D22: %f %f


assistant: ```c
int main() {
  float r, th, x, y;
  scanf("%f %f", &r, &th);
  x = r * cos(th / 180 * 3.1415926);
  y = r * sin(th / 180 * 3.1415926);
  printf("%f %f\n", x, y);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  divss  D12(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D19(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <cos@plt>
  mulss  0x10(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  movss  0x14(%rsp),%xmm0
  divss  D12(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D19(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <sin@plt>
  movaps %xmm0,%xmm1
  mulss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D50
data_type: string
name: unpack_data
arguments: label: D12
data_type: byte[4]
name: unpack_data
arguments: label: D19
data_type: f64
name: unpack_data
arguments: label: D37
data_type: string

tool: D50: %f %f

tool: {"D12": [0x00,0x00,0x34,0x43]}

tool: D19: 3.1415926

tool: D37: %f %f


assistant: ```c
int main() {
  float r, th, x, y;
  scanf("%f %f", &r, &th);
  x = r * cos(th / 180 * 3.1415926);
  y = r * sin(th / 180 * 3.1415926);
  printf("%f %f\n", x, y);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  divss  D51(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D41(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <cos@plt>
  movss  0x10(%rsp),%xmm2
  mulss  %xmm0,%xmm2
  movss  0x14(%rsp),%xmm0
  divss  D51(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D41(%rip),%xmm0
  movss  %xmm2,0xc(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <sin@plt>
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  lea    D58(%rip),%rdi
  mulss  %xmm0,%xmm1
  movaps %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string
name: disassemble_data
arguments: label: D51
type: byte[4]
name: disassemble_data
arguments: label: D41
type: f64
name: disassemble_data
arguments: label: D58
type: string

tool: D5: %f %f

tool: {"D51": [0x00,0x00,0x34,0x43]}

tool: D41: 3.1415926

tool: D58: %f %f


assistant: ```c
int main() {
  float r, th, x, y;
  scanf("%f %f", &r, &th);
  x = r * cos(th / 180 * 3.1415926);
  y = r * sin(th / 180 * 3.1415926);
  printf("%f %f\n", x, y);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  divss  D22(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D53(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <cos@plt>
  movss  0x10(%rsp),%xmm2
  mulss  %xmm0,%xmm2
  movss  0x14(%rsp),%xmm0
  divss  D22(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D53(%rip),%xmm0
  movss  %xmm2,0xc(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <sin@plt>
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  lea    D5(%rip),%rdi
  mulss  %xmm0,%xmm1
  movaps %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_infered: string
name: retrieve_data
arguments: data_tag: D22
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D53
type_infered: f64
name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D21: %f %f

tool: {"D22": [0x00,0x00,0x34,0x43]}

tool: D53: 3.1415926

tool: D5: %f %f


assistant: ```c
int main() {
  float r, th, x, y;
  scanf("%f %f", &r, &th);
  x = r * cos(th / 180 * 3.1415926);
  y = r * sin(th / 180 * 3.1415926);
  printf("%f %f\n", x, y);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sumNumbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L15
L6:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sumNumbersSub@plt>
L15:
  leave
  ret
```

assistant: ```c
int sumNumbers(struct TreeNode *root) {
  if (!root)
    return 0;
  else
    return sumNumbersSub(root, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sumNumbers>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <sumNumbersSub@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
int sumNumbers(struct TreeNode *root) {
  if (!root)
    return 0;
  else
    return sumNumbersSub(root, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sumNumbers>:
  endbr64
  test   %rdi,%rdi
  je     L8
  xor    %esi,%esi
  jmp    1050 <sumNumbersSub@plt>
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumNumbers(struct TreeNode *root) {
  if (!root)
    return 0;
  else
    return sumNumbersSub(root, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sumNumbers>:
  endbr64
  test   %rdi,%rdi
  je     L1
  xor    %esi,%esi
  jmp    1050 <sumNumbersSub@plt>
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumNumbers(struct TreeNode *root) {
  if (!root)
    return 0;
  else
    return sumNumbersSub(root, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<speck_back>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  sar    $0x3,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  shl    $0x1d,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shl    $0x8,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sar    $0x18,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void speck_back(uint32_t *a, uint32_t *b, const uint32_t key) {
  *b = (((*b ^ *a) >> ((3) & 0x1F)) | ((*b ^ *a) << (0x20 - ((3) & 0x1F))));
  *a = ((((key ^ *a) - *b) << ((8) & 0x1F)) | (((key ^ *a) - *b) >> (0x20 - ((8) & 0x1F))));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<speck_back>:
  endbr64
  mov    %rdi,%rcx
  mov    (%rsi),%eax
  xor    (%rdi),%eax
  mov    %eax,%edi
  sar    $0x3,%edi
  shl    $0x1d,%eax
  or     %edi,%eax
  mov    %eax,(%rsi)
  xor    (%rcx),%edx
  sub    %eax,%edx
  mov    %edx,%eax
  shl    $0x8,%eax
  sar    $0x18,%edx
  or     %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void speck_back(uint32_t *a, uint32_t *b, const uint32_t key) {
  *b = (((*b ^ *a) >> ((3) & 0x1F)) | ((*b ^ *a) << (0x20 - ((3) & 0x1F))));
  *a = ((((key ^ *a) - *b) << ((8) & 0x1F)) | (((key ^ *a) - *b) >> (0x20 - ((8) & 0x1F))));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<speck_back>:
  endbr64
  mov    (%rsi),%eax
  xor    (%rdi),%eax
  mov    %rdi,%rcx
  mov    %eax,%edi
  shl    $0x1d,%eax
  sar    $0x3,%edi
  or     %edi,%eax
  mov    %eax,(%rsi)
  xor    (%rcx),%edx
  sub    %eax,%edx
  mov    %edx,%eax
  sar    $0x18,%edx
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void speck_back(uint32_t *a, uint32_t *b, const uint32_t key) {
  *b = (((*b ^ *a) >> ((3) & 0x1F)) | ((*b ^ *a) << (0x20 - ((3) & 0x1F))));
  *a = ((((key ^ *a) - *b) << ((8) & 0x1F)) | (((key ^ *a) - *b) >> (0x20 - ((8) & 0x1F))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<speck_back>:
  endbr64
  mov    (%rsi),%eax
  xor    (%rdi),%eax
  mov    %rdi,%rcx
  mov    %eax,%edi
  shl    $0x1d,%eax
  sar    $0x3,%edi
  or     %edi,%eax
  mov    %eax,(%rsi)
  xor    (%rcx),%edx
  sub    %eax,%edx
  mov    %edx,%eax
  sar    $0x18,%edx
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void speck_back(uint32_t *a, uint32_t *b, const uint32_t key) {
  *b = (((*b ^ *a) >> ((3) & 0x1F)) | ((*b ^ *a) << (0x20 - ((3) & 0x1F))));
  *a = ((((key ^ *a) - *b) << ((8) & 0x1F)) | (((key ^ *a) - *b) >> (0x20 - ((8) & 0x1F))));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<max_radix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long max_radix(int len) {
  long long ans = INT64_MAX / 50;
  for (int i = 0; i < len - 2; ++i) {
    ans = sqrt(ans);
  }
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_radix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x24,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  movslq %eax,%rdi
  cmp    $0x2,%ebp
  jle    L7
  sub    $0x2,%ebp
  mov    $0x0,%ebx
L0:
  call   <sqrt@plt>
  mov    %rax,%rdi
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L0
L7:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long max_radix(int len) {
  long long ans = INT64_MAX / 50;
  for (int i = 0; i < len - 2; ++i) {
    ans = sqrt(ans);
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_radix>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x2,%ebp
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  movslq (%rax),%rdi
  mov    %rdi,%rax
  imul   $0x51eb851f,%rdi,%rdi
  sar    $0x1f,%eax
  sar    $0x24,%rdi
  sub    %eax,%edi
  movslq %edi,%rdi
  test   %ebp,%ebp
  jle    L16
  xor    %ebx,%ebx
  nopl   (%rax)
L18:
  call   <sqrt@plt>
  add    $0x1,%ebx
  mov    %rax,%rdi
  cmp    %ebp,%ebx
  jne    L18
L16:
  add    $0x8,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long max_radix(int len) {
  long long ans = INT64_MAX / 50;
  for (int i = 0; i < len - 2; ++i) {
    ans = sqrt(ans);
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_radix>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x2,%ebp
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  movslq (%rax),%rdi
  mov    %rdi,%rax
  imul   $0x51eb851f,%rdi,%rdi
  sar    $0x1f,%eax
  sar    $0x24,%rdi
  sub    %eax,%edi
  movslq %edi,%rdi
  test   %ebp,%ebp
  jle    L17
  xor    %ebx,%ebx
  nopl   (%rax)
L10:
  call   <sqrt@plt>
  add    $0x1,%ebx
  mov    %rax,%rdi
  cmp    %ebp,%ebx
  jne    L10
L17:
  add    $0x8,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long max_radix(int len) {
  long long ans = INT64_MAX / 50;
  for (int i = 0; i < len - 2; ++i) {
    ans = sqrt(ans);
  }
  return ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfc0(%rbp)
  movl   $0x0,-0xfbc(%rbp)
  jmp    L63
L39:
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfbc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    $0x2a,%eax
  je     L84
  addl   $0x1,-0xfc0(%rbp)
  addl   $0x1,-0xfbc(%rbp)
L63:
  cmpl   $0x3e7,-0xfc0(%rbp)
  jle    L39
  jmp    L61
L84:
  nop
L61:
  movl   $0x0,-0xfbc(%rbp)
  jmp    L113
L15:
  mov    -0xfbc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xfb8(%rbp)
  jmp    L6
L28:
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L71
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,-0xfb4(%rbp)
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb4(%rbp),%edx
  mov    %edx,-0xfb0(%rbp,%rax,4)
L71:
  addl   $0x1,-0xfb8(%rbp)
L6:
  mov    -0xfb8(%rbp),%eax
  cmp    -0xfc0(%rbp),%eax
  jl     L28
  addl   $0x1,-0xfbc(%rbp)
L113:
  mov    -0xfbc(%rbp),%eax
  cmp    -0xfc0(%rbp),%eax
  jl     L15
  movl   $0x0,-0xfbc(%rbp)
  jmp    L40
L104:
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xfbc(%rbp)
L40:
  mov    -0xfbc(%rbp),%eax
  cmp    -0xfc0(%rbp),%eax
  jl     L104
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L92
  call   <__stack_chk_fail@plt>
L92:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D15: %d

tool: D4: %d 


assistant: ```c
int main() {
  int a[1000];
  int s = 0, i = 0, j, temp;
  while (s < 1000) {
    scanf("%d", &a[i]);
    if (a[i] == 42) {
      break;
    }
    s++;
    i++;
  }
  for (i = 0; i < s; i++) {
    for (j = i + 1; j < s; j++) {
      if (a[i] > a[j]) {
        temp = a[i];
        a[i] = a[j];
        a[j] = temp;
      }
    }
  }
  for (i = 0; i < s; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rbp
  mov    $0x0,%r12d
  lea    D17(%rip),%r13
L58:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x2a,0x0(%rbp)
  je     L78
  add    $0x1,%r12d
  add    $0x4,%rbp
  cmp    $0x3e8,%r12d
  jne    L58
  jmp    L14
L91:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L90
L34:
  mov    (%rsi),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L91
  mov    %ecx,(%rsi)
  mov    %edx,0x4(%rax)
  jmp    L91
L90:
  add    $0x1,%r8
  add    $0x4,%rsi
L25:
  cmp    %r12,%r8
  je     L115
  mov    %r9d,%eax
  sub    %r8d,%eax
  lea    -0x1(%r8,%rax,1),%rax
  lea    (%r10,%rax,4),%rdi
  mov    %rsi,%rax
  jmp    L34
L78:
  test   %r12d,%r12d
  jle    L1
L14:
  lea    -0x1(%r12),%r9d
  mov    %r9d,%r11d
  mov    %r12d,%r12d
  mov    %rbx,%rsi
  mov    $0x1,%r8d
  lea    0x4(%rbx),%r10
  jmp    L25
L115:
  lea    0x4(%rbx,%r11,4),%r12
  lea    D4(%rip),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L18
L1:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
data_type: string
name: retrieve_data
arguments: tag: D4
data_type: string

tool: D17: %d

tool: D4: %d 


assistant: ```c
int main() {
  int a[1000];
  int s = 0, i = 0, j, temp;
  while (s < 1000) {
    scanf("%d", &a[i]);
    if (a[i] == 42) {
      break;
    }
    s++;
    i++;
  }
  for (i = 0; i < s; i++) {
    for (j = i + 1; j < s; j++) {
      if (a[i] > a[j]) {
        temp = a[i];
        a[i] = a[j];
        a[j] = temp;
      }
    }
  }
  for (i = 0; i < s; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  jmp    L36
  nopl   (%rax)
L19:
  add    $0x1,%ebp
  add    $0x4,%r12
  cmp    $0x3e8,%ebp
  je     L83
L36:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x2a,(%r12)
  jne    L19
  test   %ebp,%ebp
  je     L86
L83:
  mov    $0x1,%r8d
  lea    -0x1(%rbp),%r10d
  lea    0x4(%rbx),%r9
  mov    %rbx,%rsi
  cmp    %r8d,%ebp
  jle    L94
  nopl   0x0(%rax,%rax,1)
L80:
  mov    %r10d,%eax
  sub    %r8d,%eax
  lea    -0x1(%r8,%rax,1),%rax
  lea    (%r9,%rax,4),%rdi
  mov    %rsi,%rax
  nopw   0x0(%rax,%rax,1)
L67:
  mov    (%rsi),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L96
  mov    %ecx,(%rsi)
  mov    %edx,0x4(%rax)
L96:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L67
  add    $0x1,%r8
  add    $0x4,%rsi
  cmp    %r8d,%ebp
  jg     L80
L94:
  xor    %r12d,%r12d
  lea    D13(%rip),%r13
  xchg   %ax,%ax
L84:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,%ebp
  jg     L84
L86:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0xfb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D15: %d

tool: D13: %d 


assistant: ```c
int main() {
  int a[1000];
  int s = 0, i = 0, j, temp;
  while (s < 1000) {
    scanf("%d", &a[i]);
    if (a[i] == 42) {
      break;
    }
    s++;
    i++;
  }
  for (i = 0; i < s; i++) {
    for (j = i + 1; j < s; j++) {
      if (a[i] > a[j]) {
        temp = a[i];
        a[i] = a[j];
        a[j] = temp;
      }
    }
  }
  for (i = 0; i < s; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
  jmp    L53
  nopl   (%rax)
L85:
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    $0x3e8,%ebx
  je     L100
L53:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x2a,(%r12)
  jne    L85
  test   %ebx,%ebx
  je     L80
  cmp    $0x1,%ebx
  je     L29
L100:
  lea    0x4(%rsp),%rdi
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L99:
  mov    %rdi,%rax
  mov    %r8d,%edx
  xchg   %ax,%ax
L101:
  mov    -0x4(%rdi),%ecx
  mov    (%rax),%esi
  cmp    %esi,%ecx
  jle    L81
  mov    %esi,-0x4(%rdi)
  mov    %ecx,(%rax)
L81:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%ebx
  jg     L101
  add    $0x1,%r8d
  add    $0x4,%rdi
  cmp    %r8d,%ebx
  jne    L99
  xor    %r12d,%r12d
  lea    D18(%rip),%r13
L15:
  mov    0x0(%rbp,%r12,4),%esi
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,%ebx
  jg     L15
L80:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0xfb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    (%rsp),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L80
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string

tool: D15: %d

tool: D18: %d 


assistant: ```c
int main() {
  int a[1000];
  int s = 0, i = 0, j, temp;
  while (s < 1000) {
    scanf("%d", &a[i]);
    if (a[i] == 42) {
      break;
    }
    s++;
    i++;
  }
  for (i = 0; i < s; i++) {
    for (j = i + 1; j < s; j++) {
      if (a[i] > a[j]) {
        temp = a[i];
        a[i] = a[j];
        a[j] = temp;
      }
    }
  }
  for (i = 0; i < s; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```