ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D14(%rip),%rbp
  jmp    L29
L2:
  mov    %rbx,%rdi
  call   <tree_add@plt>
  mov    %rax,%rbx
L29:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L30
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jne    L2
L30:
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <tree_get_height@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <tree_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D14: %d

tool: D19: %zu


assistant: ```c
int main() {
  struct Node *tree = NULL;
  int x;
  while ((scanf("%d", &x) == 1) && (x != 0)) {
    tree = tree_add(tree, x);
  }
  printf("%zu\n", tree_get_height(tree, 0));
  tree_destroy(tree);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L4
  nopl   0x0(%rax)
L11:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L1
  mov    %rbp,%rdi
  call   <tree_add@plt>
  mov    %rax,%rbp
L4:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L11
L1:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <tree_get_height@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <tree_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D16: %d

tool: D4: %zu


assistant: ```c
int main() {
  struct Node *tree = NULL;
  int x;
  while ((scanf("%d", &x) == 1) && (x != 0)) {
    tree = tree_add(tree, x);
  }
  printf("%zu\n", tree_get_height(tree, 0));
  tree_destroy(tree);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L25
  nopl   0x0(%rax)
L18:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L6
  mov    %rbp,%rdi
  call   <tree_add@plt>
  mov    %rax,%rbp
L25:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L18
L6:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <tree_get_height@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <tree_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string

tool: D19: %d

tool: D18: %zu


assistant: ```c
int main() {
  struct Node *tree = NULL;
  int x;
  while ((scanf("%d", &x) == 1) && (x != 0)) {
    tree = tree_add(tree, x);
  }
  printf("%zu\n", tree_get_height(tree, 0));
  tree_destroy(tree);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x28(%rbp),%rdx
  add    %rsi,%rdx
  imul   %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vmul(int *a, int *b, int *c, int N) {
#pragma omp target teams map(to : a [0:N], b [0:N]) map(from : c [0:N])
#pragma omp distribute parallel for
  for (int i = 0; i < N; i++) {
    c[i] = a[i] * b[i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vmul>:
  endbr64
  test   %ecx,%ecx
  jle    L0
  mov    %ecx,%ecx
  mov    $0x0,%eax
L14:
  mov    (%rdi,%rax,4),%r8d
  imul   (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L14
L0:
  ret
```

assistant: ```c
void vmul(int *a, int *b, int *c, int N) {
#pragma omp target teams map(to : a [0:N], b [0:N]) map(from : c [0:N])
#pragma omp distribute parallel for
  for (int i = 0; i < N; i++) {
    c[i] = a[i] * b[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vmul>:
  endbr64
  test   %ecx,%ecx
  jle    L17
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L7:
  mov    (%rdi,%rax,4),%r8d
  imul   (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L7
L17:
  ret
```

assistant: ```c
void vmul(int *a, int *b, int *c, int N) {
#pragma omp target teams map(to : a [0:N], b [0:N]) map(from : c [0:N])
#pragma omp distribute parallel for
  for (int i = 0; i < N; i++) {
    c[i] = a[i] * b[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vmul>:
  endbr64
  test   %ecx,%ecx
  jle    L22
  lea    0x4(%rdi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  lea    -0x1(%rcx),%eax
  seta   %r8b
  cmp    $0x2,%eax
  seta   %al
  test   %al,%r8b
  je     L52
  lea    0x4(%rsi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L52
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   0x0(%rax)
L1:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  movdqu (%rdi,%rax,1),%xmm1
  movdqu (%rsi,%rax,1),%xmm3
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm2
  pmuludq %xmm3,%xmm1
  pmuludq %xmm2,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L1
  mov    %ecx,%r8d
  and    $0xfffffffc,%r8d
  test   $0x3,%cl
  je     L22
  mov    %r8d,%r9d
  mov    (%rdi,%r9,4),%r10d
  imul   (%rsi,%r9,4),%r10d
  lea    0x0(,%r9,4),%rax
  mov    %r10d,(%rdx,%r9,4)
  lea    0x1(%r8),%r9d
  cmp    %r9d,%ecx
  jle    L22
  mov    0x4(%rdi,%rax,1),%r9d
  imul   0x4(%rsi,%rax,1),%r9d
  add    $0x2,%r8d
  mov    %r9d,0x4(%rdx,%rax,1)
  cmp    %r8d,%ecx
  jle    L22
  mov    0x8(%rdi,%rax,1),%ecx
  imul   0x8(%rsi,%rax,1),%ecx
  mov    %ecx,0x8(%rdx,%rax,1)
  ret
  nopl   (%rax)
L52:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L41:
  mov    (%rdi,%rax,4),%r8d
  imul   (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L41
L22:
  ret
```

assistant: ```c
void vmul(int *a, int *b, int *c, int N) {
#pragma omp target teams map(to : a [0:N], b [0:N]) map(from : c [0:N])
#pragma omp distribute parallel for
  for (int i = 0; i < N; i++) {
    c[i] = a[i] * b[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D2(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: f64

tool: D2: 1000000

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec + tv.tv_usec / 1000000.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D7(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: f64

tool: D7: 1000000

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec + tv.tv_usec / 1000000.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D2(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f64

tool: D2: 1000000

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec + tv.tv_usec / 1000000.0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D2(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: f64

tool: D2: 1000000

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec + tv.tv_usec / 1000000.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L26:
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L8:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L51:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm1
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  movss  %xmm0,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L27:
  cmpl   $0x2,-0x4(%rbp)
  jle    L51
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x2,-0x8(%rbp)
  jle    L8
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiply(float A[10][3], float B[3][3], float C[10][3], int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < 3; j++) {
      C[i][j] = 0;
      for (k = 0; k < 3; k++)
        C[i][j] += A[i][k] * B[k][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<multiply>:
  endbr64
  test   %ecx,%ecx
  jle    L46
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%r9
  lea    0xc(%rdi),%r8
  mov    %rdx,%r10
  lea    -0x1(%rcx),%eax
  lea    (%rax,%rax,2),%rax
  lea    0x18(%rdi,%rax,4),%rbp
  lea    0xc(%rsi),%r11
  jmp    L25
L2:
  add    $0xc,%r9
  add    $0xc,%r8
  add    $0xc,%r10
  cmp    %rbp,%r8
  je     L38
L25:
  mov    %rbx,%rdi
  mov    %r10,%rsi
L59:
  mov    %rsi,%rcx
  movl   $0x0,(%rsi)
  mov    %rdi,%rdx
  mov    %r9,%rax
L0:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rax
  add    $0xc,%rdx
  cmp    %r8,%rax
  jne    L0
  add    $0x4,%rsi
  add    $0x4,%rdi
  cmp    %r11,%rdi
  jne    L59
  jmp    L2
L38:
  pop    %rbx
  pop    %rbp
  ret
L46:
  ret
```

assistant: ```c
void multiply(float A[10][3], float B[3][3], float C[10][3], int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < 3; j++) {
      C[i][j] = 0;
      for (k = 0; k < 3; k++)
        C[i][j] += A[i][k] * B[k][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiply>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rsi,%r11
  lea    0xc(%rdi),%r9
  lea    (%rax,%rax,2),%rax
  lea    0xc(%rsi),%r10
  pxor   %xmm2,%xmm2
  lea    0x18(%rdi,%rax,4),%rbx
  nopl   0x0(%rax)
L28:
  mov    %r11,%r8
  mov    %rdx,%rsi
L13:
  movl   $0x0,(%rsi)
  mov    %r8,%rcx
  mov    %rdi,%rax
  movaps %xmm2,%xmm1
L32:
  movss  (%rax),%xmm0
  mulss  (%rcx),%xmm0
  add    $0x4,%rax
  add    $0xc,%rcx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rsi)
  cmp    %r9,%rax
  jne    L32
  add    $0x4,%r8
  add    $0x4,%rsi
  cmp    %r10,%r8
  jne    L13
  add    $0xc,%r9
  add    $0xc,%rdi
  add    $0xc,%rdx
  cmp    %rbx,%r9
  jne    L28
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
void multiply(float A[10][3], float B[3][3], float C[10][3], int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < 3; j++) {
      C[i][j] = 0;
      for (k = 0; k < 3; k++)
        C[i][j] += A[i][k] * B[k][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply>:
  endbr64
  mov    %rsi,%rax
  test   %ecx,%ecx
  jle    L19
  sub    $0x1,%ecx
  pxor   %xmm2,%xmm2
  lea    (%rcx,%rcx,2),%rcx
  lea    0xc(%rdx,%rcx,4),%rcx
  nop
L2:
  movl   $0x0,(%rdx)
  movss  (%rdi),%xmm1
  add    $0xc,%rdx
  add    $0xc,%rdi
  mulss  (%rax),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,-0xc(%rdx)
  movss  -0x8(%rdi),%xmm0
  mulss  0xc(%rax),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rdx)
  movss  -0x4(%rdi),%xmm1
  mulss  0x18(%rax),%xmm1
  movl   $0x0,-0x8(%rdx)
  addss  %xmm0,%xmm1
  movss  %xmm1,-0xc(%rdx)
  movss  -0xc(%rdi),%xmm1
  mulss  0x4(%rax),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,-0x8(%rdx)
  movss  -0x8(%rdi),%xmm0
  mulss  0x10(%rax),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rdx)
  movss  -0x4(%rdi),%xmm1
  mulss  0x1c(%rax),%xmm1
  movl   $0x0,-0x4(%rdx)
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x8(%rdx)
  movss  -0xc(%rdi),%xmm1
  mulss  0x8(%rax),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,-0x4(%rdx)
  movss  -0x8(%rdi),%xmm0
  mulss  0x14(%rax),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rdx)
  movss  -0x4(%rdi),%xmm1
  mulss  0x20(%rax),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x4(%rdx)
  cmp    %rdx,%rcx
  jne    L2
L19:
  ret
```

assistant: ```c
void multiply(float A[10][3], float B[3][3], float C[10][3], int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < 3; j++) {
      C[i][j] = 0;
      for (k = 0; k < 3; k++)
        C[i][j] += A[i][k] * B[k][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L78
L116:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L16
  cmpl   $0x1f3,-0x8(%rbp)
  jg     L118
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0xc7,-0x8(%rbp)
  jg     L92
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x1,-0x8(%rbp)
  je     L55
  cmpl   $0x2,-0x8(%rbp)
  je     L55
  cmpl   $0x3,-0x8(%rbp)
  jne    L118
L55:
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L118
L92:
  cmpl   $0x2a,-0x8(%rbp)
  jne    L118
L31:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L118:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L100
L16:
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L100:
  addl   $0x1,-0x8(%rbp)
L78:
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L116
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D52
type_infered: string
name: disassemble_data
arguments: label: D55
type_infered: string
name: disassemble_data
arguments: label: D66
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D34
type_infered: string
name: disassemble_data
arguments: label: D69
type_infered: string
name: disassemble_data
arguments: label: D51
type_infered: string

tool: D1: 1


tool: D52: 2


tool: D55: 3


tool: D66: 4


tool: D6: loooop!


tool: D34: continue!


tool: D69: 5


tool: D51: 6


assistant: ```c
int main() {
  int i = 0, j;
  for (i = 0; i < 1000; i++) {
    printf("1\n");
    j = rand();
    if (j == 1) {
      if (i < 500) {
        printf("2\n");
        if (i < 200) {
          printf("3\n");
          if (i == 1 || i == 2 || i == 3) {
            printf("4\n");
          }
        } else if (i == 42) {
          while (1) {
            printf("loooop!\n");
          }
        }
      }
      printf("continue!\n");
      continue;
    }
    printf("5\n");
  }
  printf("6\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
  lea    D15(%rip),%r13
  lea    D39(%rip),%r12
  lea    D20(%rip),%r14
  jmp    L8
L59:
  mov    %r12,%rdi
  call   <printf@plt>
L43:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L35
L8:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  cmp    $0x1,%eax
  jne    L27
  cmp    $0x1f3,%ebx
  jg     L59
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0xc7,%ebx
  jg     L59
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  ja     L59
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L27:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L43
L35:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D15
type_infered: string
name: retrieve_data
arguments: tag: D39
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: string
name: retrieve_data
arguments: tag: D54
type_infered: string
name: retrieve_data
arguments: tag: D32
type_infered: string

tool: D4: 1


tool: D15: 5


tool: D39: continue!


tool: D20: 2


tool: D47: 3


tool: D54: 4


tool: D32: 6


assistant: ```c
int main() {
  int i = 0, j;
  for (i = 0; i < 1000; i++) {
    printf("1\n");
    j = rand();
    if (j == 1) {
      if (i < 500) {
        printf("2\n");
        if (i < 200) {
          printf("3\n");
          if (i == 1 || i == 2 || i == 3) {
            printf("4\n");
          }
        } else if (i == 42) {
          while (1) {
            printf("loooop!\n");
          }
        }
      }
      printf("continue!\n");
      continue;
    }
    printf("5\n");
  }
  printf("6\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D54(%rip),%r15
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D43(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L5
  nopl   0x0(%rax)
L20:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x3e8,%ebx
  je     L39
L5:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <rand@plt>
  cmp    $0x1,%eax
  jne    L20
  cmp    $0x1f3,%ebx
  jg     L44
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0xc7,%ebx
  jle    L72
L44:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x3e8,%ebx
  jne    L5
L39:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L72:
  mov    %r15,%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  ja     L44
  lea    D42(%rip),%rdi
  call   <printf@plt>
  jmp    L44
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D54
data_type: string
name: extract_symbolic_data
arguments: data_tag: D28
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D43
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D42
data_type: string

tool: D54: 3


tool: D28: 2


tool: D13: continue!


tool: D3: 5


tool: D43: 1


tool: D12: 6


tool: D42: 4


assistant: ```c
int main() {
  int i = 0, j;
  for (i = 0; i < 1000; i++) {
    printf("1\n");
    j = rand();
    if (j == 1) {
      if (i < 500) {
        printf("2\n");
        if (i < 200) {
          printf("3\n");
          if (i == 1 || i == 2 || i == 3) {
            printf("4\n");
          }
        } else if (i == 42) {
          while (1) {
            printf("loooop!\n");
          }
        }
      }
      printf("continue!\n");
      continue;
    }
    printf("5\n");
  }
  printf("6\n");
  return 0;
}
```