ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x5(%rbp)
  jmp    L28
L5:
  cmpl   $0x20,-0x4(%rbp)
  jne    L12
  cmpb   $0x0,-0x5(%rbp)
  jne    L35
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L35:
  cmpl   $0x20,-0x4(%rbp)
  sete   %al
  mov    %al,-0x5(%rbp)
L28:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L5
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  char lc = 0;
  while ((c = getchar()) != EOF) {
    if (c != ' ' || !lc) {
      putchar(c);
    }
    lc = c == ' ';
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  jmp    L37
L39:
  mov    %ebx,%edi
  call   <putchar@plt>
L6:
  cmp    $0x20,%ebx
  sete   %bpl
L37:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  je     L41
  cmp    $0x20,%ebx
  jne    L39
  test   %bpl,%bpl
  jne    L6
  jmp    L39
L41:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c;
  char lc = 0;
  while ((c = getchar()) != EOF) {
    if (c != ' ' || !lc) {
      putchar(c);
    }
    lc = c == ' ';
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    D0(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L6:
  cmp    $0x20,%ebx
  sete   %bpl
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  je     L9
  cmp    $0x20,%ebx
  jne    L25
  test   %bpl,%bpl
  jne    L6
L25:
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L6
  nopl   0x0(%rax)
L9:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int c;
  char lc = 0;
  while ((c = getchar()) != EOF) {
    if (c != ' ' || !lc) {
      putchar(c);
    }
    lc = c == ' ';
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    D8(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x20,%ebx
  sete   %bpl
L26:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  je     L0
  cmp    $0x20,%ebx
  jne    L40
  test   %bpl,%bpl
  jne    L20
L40:
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L20
  nopl   0x0(%rax)
L0:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int c;
  char lc = 0;
  while ((c = getchar()) != EOF) {
    if (c != ' ' || !lc) {
      putchar(c);
    }
    lc = c == ' ';
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  movq   $0x0,(%rdi)
  mov    %rsi,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L88
  mov    $0x2004,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L89
  movb   $0x0,(%rax)
  mov    %rax,%rbx
  mov    $0x0,%ebp
  mov    $0x2004,%r14d
  mov    $0x2004,%r13d
L129:
  mov    %r15,%rdx
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L172
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L76
  add    %r13d,%r13d
  mov    %r13d,%r14d
  sub    %ebp,%r14d
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L1
  movslq %ebp,%rbx
  add    %rax,%rbx
  mov    %rax,%r12
  jmp    L129
L76:
  mov    %rax,%rbp
  sub    %r12,%rbp
  add    $0x1,%ebp
L172:
  cmp    %r12,%rbx
  ja     L145
  jmp    L4
L1:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0xffffffff,%r13d
  jmp    L53
L157:
  movb   $0x0,(%rbx)
  sub    $0x1,%ebp
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L4
L145:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L157
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L157
L4:
  mov    %r12,%rbx
  add    %r12d,%ebp
  jmp    L170
L33:
  add    $0x1,%rbx
L170:
  mov    %ebp,%r13d
  sub    %ebx,%r13d
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L33
  lea    0x1(%r13),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x8(%rsp),%rax
  mov    %rdi,(%rax)
  test   %rdi,%rdi
  je     L141
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
L53:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L141:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0xffffffff,%r13d
  jmp    L53
L88:
  mov    $0xffffffff,%r13d
  jmp    L53
L89:
  mov    $0xffffffff,%r13d
  jmp    L53
```

assistant: ```c
int getLine(char **s, FILE *fd) {
  int len = 8196;
  int toread = len;
  int l = 0;
  char *ptr, *p, *q;
  *s = NULL;
  if (feof(fd))
    return -1;
  q = ptr = malloc(len);
  if (ptr == NULL)
    return -1;
  *q = 0;
  p = q = ptr;
  while (fgets(p, toread, fd) != NULL) {
    l = strlen(ptr);
    q = strchr(p, '\n');
    if (q != NULL) {
      l = q - ptr + 1;
      break;
    }
    len *= 2;
    toread = len - l;
    p = realloc(ptr, len);
    if (p == NULL) {
      free(ptr);
      return -1;
    }
    ptr = p;
    q = p = ptr + l;
  }
  while (q > ptr && (*q == '\0' || isspace(*q))) {
    *q = '\0';
    l--;
    q--;
  }
  for (p = ptr; isspace(*p); p++, l--)
    ;
  if ((*s = malloc(l + 1)) == NULL) {
    free(ptr);
    return -1;
  }
  memcpy(*s, p, l + 1);
  free(ptr);
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getLine>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   $0x0,(%rdi)
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L9
  mov    $0x2004,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
  mov    %rax,%r12
  xor    %ebx,%ebx
  mov    $0x2004,%r15d
  mov    $0x2004,%r13d
  jmp    L126
  xchg   %ax,%ax
L63:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  mov    %eax,%ebx
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L56
  add    %r13d,%r13d
  mov    %r12,%rdi
  mov    %r13d,%r15d
  mov    %r13d,%esi
  sub    %ebx,%r15d
  call   <realloc@plt>
  test   %rax,%rax
  je     L27
  movslq %ebx,%rbp
  mov    %rax,%r12
  add    %rax,%rbp
L126:
  mov    %r14,%rdx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L63
L138:
  cmp    %rbp,%r12
  jb     L0
  jmp    L91
  nopl   0x0(%rax,%rax,1)
L154:
  movb   $0x0,0x0(%rbp)
  sub    $0x1,%rbp
  sub    $0x1,%ebx
  cmp    %rbp,%r12
  je     L91
L0:
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L154
  call   <isspace@plt>
  test   %rax,%rax
  jne    L154
L91:
  mov    %r12,%rbp
  add    %r12d,%ebx
  jmp    L131
  nopl   0x0(%rax,%rax,1)
L133:
  add    $0x1,%rbp
L131:
  movsbl 0x0(%rbp),%edi
  mov    %ebx,%r13d
  sub    %ebp,%r13d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L133
  lea    0x1(%r13),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x8(%rsp),%rax
  mov    %rdi,(%rax)
  test   %rdi,%rdi
  je     L27
  mov    %r14d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
L45:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L27:
  mov    %r12,%rdi
  call   <free@plt>
L9:
  mov    $0xffffffff,%r13d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %rax,%rbx
  sub    %r12,%rbx
  add    $0x1,%ebx
  jmp    L138
```

assistant: ```c
int getLine(char **s, FILE *fd) {
  int len = 8196;
  int toread = len;
  int l = 0;
  char *ptr, *p, *q;
  *s = NULL;
  if (feof(fd))
    return -1;
  q = ptr = malloc(len);
  if (ptr == NULL)
    return -1;
  *q = 0;
  p = q = ptr;
  while (fgets(p, toread, fd) != NULL) {
    l = strlen(ptr);
    q = strchr(p, '\n');
    if (q != NULL) {
      l = q - ptr + 1;
      break;
    }
    len *= 2;
    toread = len - l;
    p = realloc(ptr, len);
    if (p == NULL) {
      free(ptr);
      return -1;
    }
    ptr = p;
    q = p = ptr + l;
  }
  while (q > ptr && (*q == '\0' || isspace(*q))) {
    *q = '\0';
    l--;
    q--;
  }
  for (p = ptr; isspace(*p); p++, l--)
    ;
  if ((*s = malloc(l + 1)) == NULL) {
    free(ptr);
    return -1;
  }
  memcpy(*s, p, l + 1);
  free(ptr);
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getLine>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   $0x0,(%rdi)
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L64
  mov    $0x2004,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L64
  movb   $0x0,(%rax)
  mov    %rax,%r12
  xor    %ebx,%ebx
  mov    $0x2004,%r15d
  mov    $0x2004,%r13d
  jmp    L10
  xchg   %ax,%ax
L110:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  mov    %eax,%ebx
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L121
  add    %r13d,%r13d
  mov    %r12,%rdi
  mov    %r13d,%r15d
  mov    %r13d,%esi
  sub    %ebx,%r15d
  call   <realloc@plt>
  test   %rax,%rax
  je     L145
  movslq %ebx,%rbp
  mov    %rax,%r12
  add    %rax,%rbp
L10:
  mov    %r14,%rdx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L110
L146:
  cmp    %rbp,%r12
  jb     L92
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L132:
  movb   $0x0,0x0(%rbp)
  sub    $0x1,%rbp
  sub    $0x1,%ebx
  cmp    %rbp,%r12
  je     L2
L92:
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L132
  call   <isspace@plt>
  test   %rax,%rax
  jne    L132
L2:
  mov    %r12,%rbp
  add    %r12d,%ebx
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L57:
  add    $0x1,%rbp
L51:
  movsbl 0x0(%rbp),%edi
  mov    %ebx,%r13d
  sub    %ebp,%r13d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L57
  lea    0x1(%r13),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x8(%rsp),%rax
  mov    %rdi,(%rax)
  test   %rdi,%rdi
  je     L145
  mov    %r14d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
L74:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L145:
  mov    %r12,%rdi
  call   <free@plt>
L64:
  mov    $0xffffffff,%r13d
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L121:
  mov    %rax,%rbx
  sub    %r12,%rbx
  add    $0x1,%ebx
  jmp    L146
```

assistant: ```c
int getLine(char **s, FILE *fd) {
  int len = 8196;
  int toread = len;
  int l = 0;
  char *ptr, *p, *q;
  *s = NULL;
  if (feof(fd))
    return -1;
  q = ptr = malloc(len);
  if (ptr == NULL)
    return -1;
  *q = 0;
  p = q = ptr;
  while (fgets(p, toread, fd) != NULL) {
    l = strlen(ptr);
    q = strchr(p, '\n');
    if (q != NULL) {
      l = q - ptr + 1;
      break;
    }
    len *= 2;
    toread = len - l;
    p = realloc(ptr, len);
    if (p == NULL) {
      free(ptr);
      return -1;
    }
    ptr = p;
    q = p = ptr + l;
  }
  while (q > ptr && (*q == '\0' || isspace(*q))) {
    *q = '\0';
    l--;
    q--;
  }
  for (p = ptr; isspace(*p); p++, l--)
    ;
  if ((*s = malloc(l + 1)) == NULL) {
    free(ptr);
    return -1;
  }
  memcpy(*s, p, l + 1);
  free(ptr);
  return l;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move@plt>
  jmp    L36
L26:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  cmpl   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <attron@plt>
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <addch@plt>
  addq   $0x1,-0x10(%rbp)
  cmpl   $0x0,0x10(%rbp)
  je     L36
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    0x10(%rbp),%edi
  call   <napms@plt>
L36:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  cmpl   $0x0,-0x18(%rbp)
  je     L57
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <attroff@plt>
L57:
  nop
  leave
  ret
```

assistant: ```c
void print_text(int x, int y, char *text, int color, int style, int align, int display_speed) {
  if (align == 1)
    x = (x - strlen(text)) / 2;
  move(y, x);
  while (*text) {
    attrset(COLOR_PAIR(color));
    if (style != 0)
      attron(style);
    addch(*text);
    text++;
    if (display_speed != 0) {
      refresh();
      napms(display_speed);
    }
  }
  attrset(COLOR_PAIR(color));
  if (style != 0)
    attroff(style);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_text>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  mov    0x40(%rsp),%r13d
  cmp    $0x1,%r9d
  je     L47
L98:
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <move@plt>
  cmpb   $0x0,(%rbx)
  jne    L48
L10:
  mov    %r12d,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  test   %ebp,%ebp
  jne    L74
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  mov    %rdx,%rdi
  call   <strlen@plt>
  sub    %eax,%r14d
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  mov    %eax,%r14d
  jmp    L98
L36:
  mov    %ebp,%edi
  call   <attron@plt>
  jmp    L43
L14:
  cmpb   $0x0,(%rbx)
  je     L10
L48:
  mov    %r12d,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  test   %ebp,%ebp
  jne    L36
L43:
  movsbl (%rbx),%edi
  call   <addch@plt>
  add    $0x1,%rbx
  test   %r13d,%r13d
  je     L14
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    %r13d,%edi
  call   <napms@plt>
  jmp    L14
L74:
  mov    %ebp,%edi
  call   <attroff@plt>
  jmp    L8
```

assistant: ```c
void print_text(int x, int y, char *text, int color, int style, int align, int display_speed) {
  if (align == 1)
    x = (x - strlen(text)) / 2;
  move(y, x);
  while (*text) {
    attrset(COLOR_PAIR(color));
    if (style != 0)
      attron(style);
    addch(*text);
    text++;
    if (display_speed != 0) {
      refresh();
      napms(display_speed);
    }
  }
  attrset(COLOR_PAIR(color));
  if (style != 0)
    attroff(style);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_text>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r13d
  cmp    $0x1,%r9d
  je     L73
L43:
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <move@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  cmpb   $0x0,(%rbx)
  mov    %r12d,%edi
  je     L31
L39:
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  test   %ebp,%ebp
  jne    L25
L54:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <addch@plt>
  test   %r13d,%r13d
  je     L20
  xor    %eax,%eax
  call   <refresh@plt>
  mov    %r13d,%edi
  call   <napms@plt>
  cmpb   $0x0,(%rbx)
  mov    %r12d,%edi
  jne    L39
L31:
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  test   %ebp,%ebp
  jne    L23
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L25:
  mov    %ebp,%edi
  call   <attron@plt>
  jmp    L54
  nopl   0x0(%rax)
L23:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10d0 <attroff@plt>
  nopl   (%rax)
L73:
  mov    %rdx,%rdi
  call   <strlen@plt>
  sub    %eax,%r14d
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  mov    %eax,%r14d
  jmp    L43
```

assistant: ```c
void print_text(int x, int y, char *text, int color, int style, int align, int display_speed) {
  if (align == 1)
    x = (x - strlen(text)) / 2;
  move(y, x);
  while (*text) {
    attrset(COLOR_PAIR(color));
    if (style != 0)
      attron(style);
    addch(*text);
    text++;
    if (display_speed != 0) {
      refresh();
      napms(display_speed);
    }
  }
  attrset(COLOR_PAIR(color));
  if (style != 0)
    attroff(style);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_text>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r13d
  cmp    $0x1,%r9d
  je     L27
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <move@plt>
  cmpb   $0x0,(%rbx)
  je     L87
L114:
  test   %r12d,%r12d
  jne    L13
  test   %r13d,%r13d
  jne    L17
  nopl   0x0(%rax)
L58:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  movsbl -0x1(%rbx),%edi
  call   <addch@plt>
  cmpb   $0x0,(%rbx)
  jne    L58
L122:
  mov    %ebp,%edi
  call   <COLOR_PAIR@plt>
  add    $0x8,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1130 <attrset@plt>
  nopl   0x0(%rax)
L17:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  movsbl -0x1(%rbx),%edi
  call   <addch@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  mov    %r13d,%edi
  call   <napms@plt>
  cmpb   $0x0,(%rbx)
  jne    L17
  jmp    L122
  nopl   0x0(%rax)
L13:
  test   %r13d,%r13d
  jne    L117
  nopl   (%rax)
L94:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  mov    %r12d,%edi
  call   <attron@plt>
  movsbl -0x1(%rbx),%edi
  call   <addch@plt>
  cmpb   $0x0,(%rbx)
  jne    L94
L64:
  mov    %ebp,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
L73:
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10d0 <attroff@plt>
  nopl   0x0(%rax)
L117:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  mov    %r12d,%edi
  call   <attron@plt>
  movsbl -0x1(%rbx),%edi
  call   <addch@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  mov    %r13d,%edi
  call   <napms@plt>
  cmpb   $0x0,(%rbx)
  jne    L117
  jmp    L64
  nopl   0x0(%rax)
L27:
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %r15d,%edi
  sub    %eax,%r14d
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  mov    %eax,%r14d
  mov    %r14d,%esi
  call   <move@plt>
  cmpb   $0x0,(%rbx)
  jne    L114
L87:
  mov    %ebp,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  test   %r12d,%r12d
  jne    L73
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void print_text(int x, int y, char *text, int color, int style, int align, int display_speed) {
  if (align == 1)
    x = (x - strlen(text)) / 2;
  move(y, x);
  while (*text) {
    attrset(COLOR_PAIR(color));
    if (style != 0)
      attron(style);
    addch(*text);
    text++;
    if (display_speed != 0) {
      refresh();
      napms(display_speed);
    }
  }
  attrset(COLOR_PAIR(color));
  if (style != 0)
    attroff(style);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x7,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <maxSum@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: Sum of maximum sum increasing subsequence is %d 


assistant: ```c
int main() {
  int arr[] = {4, 6, 1, 3, 8, 4, 6};
  int n = sizeof(arr) / sizeof(arr[0]);
  printf("Sum of maximum sum increasing subsequence is %d \n", maxSum(arr, n));
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x6,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x8,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x7,%esi
  call   <maxSum@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: Sum of maximum sum increasing subsequence is %d 


assistant: ```c
int main() {
  int arr[] = {4, 6, 1, 3, 8, 4, 6};
  int n = sizeof(arr) / sizeof(arr[0]);
  printf("Sum of maximum sum increasing subsequence is %d \n", maxSum(arr, n));
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000004,%rax
  mov    %rsp,%rdi
  movl   $0x6,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000008,%rax
  mov    %rax,0x10(%rsp)
  call   <maxSum@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: Sum of maximum sum increasing subsequence is %d 


assistant: ```c
int main() {
  int arr[] = {4, 6, 1, 3, 8, 4, 6};
  int n = sizeof(arr) / sizeof(arr[0]);
  printf("Sum of maximum sum increasing subsequence is %d \n", maxSum(arr, n));
  return (0);
}
```