user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_next_number>:
  endbr64
  mov    %rdx,%r8
  movsbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L24
  cmp    $0x9,%dl
  jne    L112
L24:
  mov    $0x1,%eax
  nopl   (%rax)
L7:
  movsbl (%rdi,%rax,1),%edx
  mov    %eax,%ecx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L7
  cmp    $0x9,%dl
  je     L7
L157:
  mov    $0x1,%r9d
  test   %dl,%dl
  je     L208
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L37
  movslq %ecx,%r9
  lea    0x1(%rdi,%r9,1),%r10
L28:
  movzbl (%r10),%eax
  add    $0x1,%r10
  lea    -0x30(%rax),%r11d
  cmp    $0x9,%r11b
  jbe    L28
  and    $0xffffffdf,%eax
  lea    -0x41(%rax),%r10d
  cmp    $0x5,%r10b
  jbe    L284
  cmp    $0x48,%al
  jne    L314
L284:
  xor    %eax,%eax
  jmp    L179
L128:
  shl    $0x4,%eax
  lea    -0x30(%rax,%rdx,1),%eax
L91:
  add    $0x1,%r9
L179:
  movsbl (%rdi,%r9,1),%edx
  mov    %r9d,%r10d
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L128
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L260
  shl    $0x4,%eax
  lea    -0x57(%rax,%rdx,1),%eax
  jmp    L91
  nopl   0x0(%rax)
L138:
  test   $0xdf,%dl
  je     L165
  cmp    $0x9,%dl
  jne    L242
L165:
  mov    %eax,(%rsi)
  xor    %r9d,%r9d
  add    %r10d,(%r8)
L208:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  cmp    $0x24,%dl
  jne    L208
  add    $0x1,%ecx
  xor    %eax,%eax
  movslq %ecx,%rcx
  jmp    L186
  nop
L99:
  shl    $0x4,%eax
  lea    -0x30(%rax,%rdx,1),%eax
L244:
  add    $0x1,%rcx
L186:
  movsbl (%rdi,%rcx,1),%edx
  mov    %ecx,%r10d
  lea    -0x30(%rdx),%r9d
  cmp    $0x9,%r9b
  jbe    L99
  lea    -0x61(%rdx),%r9d
  cmp    $0x5,%r9b
  ja     L100
  shl    $0x4,%eax
  lea    -0x57(%rax,%rdx,1),%eax
  jmp    L244
  nop
L112:
  xor    %ecx,%ecx
  jmp    L157
  nopw   0x0(%rax,%rax,1)
L260:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L110
  shl    $0x4,%eax
  lea    -0x37(%rax,%rdx,1),%eax
  jmp    L91
  nopl   0x0(%rax)
L100:
  lea    -0x41(%rdx),%r9d
  cmp    $0x5,%r9b
  ja     L138
  shl    $0x4,%eax
  lea    -0x37(%rax,%rdx,1),%eax
  jmp    L244
  nop
L110:
  mov    %edx,%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x48,%cl
  je     L165
  cmp    $0x20,%dl
  ja     L242
  movabs $0x100000201,%rcx
  bt     %rdx,%rcx
  jb     L165
L242:
  mov    $0x1,%r9d
  mov    %r9d,%eax
  ret
L314:
  add    $0x1,%ecx
  xor    %eax,%eax
  movslq %ecx,%rcx
  nopl   0x0(%rax)
L193:
  lea    (%rax,%rax,4),%eax
  mov    %ecx,%r10d
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl (%rdi,%rcx,1),%edx
  add    $0x1,%rcx
  lea    -0x30(%rdx),%r9d
  cmp    $0x9,%r9b
  jbe    L193
  test   $0xdf,%dl
  je     L165
  mov    $0x1,%r9d
  cmp    $0x9,%dl
  je     L165
  jmp    L208
```

assistant: ```c
int get_next_number(char *in, int *out, int *pos) {
  int i, o, n;
  for (i = 0; in[i] == ' ' || in[i] == 0x09; i++)
    ;
  if (in[i] == 0)
    return 1;
  if (in[i] >= '0' && in[i] <= '9') {
    n = 0;
    for (o = 0; 1; o++) {
      if (in[i + o] >= '0' && in[i + o] <= '9')
        continue;
      if (in[i + o] >= 'a' && in[i + o] <= 'f') {
        n = 1;
        break;
      }
      if (in[i + o] >= 'A' && in[i + o] <= 'F') {
        n = 1;
        break;
      }
      if (in[i + o] == 'h' || in[i + o] == 'H') {
        n = 1;
        break;
      }
      break;
    }
    if (n == 1) {
      o = 0;
      while (1) {
        if (in[i] >= '0' && in[i] <= '9')
          o = (o * 16) + in[i] - '0';
        else if (in[i] >= 'a' && in[i] <= 'f')
          o = (o * 16) + in[i] - 'a' + 0xA;
        else if (in[i] >= 'A' && in[i] <= 'F')
          o = (o * 16) + in[i] - 'A' + 0xA;
        else if (in[i] == 'h' || in[i] == 'H')
          break;
        else if (in[i] == ' ' || in[i] == 0x09 || in[i] == 0)
          break;
        else
          return 1;
        i++;
      }
    } else {
      for (o = 0; in[i] >= '0' && in[i] <= '9'; i++)
        o = (o * 10) + in[i] - '0';
      if (!(in[i] == ' ' || in[i] == 0x09 || in[i] == 0))
        return 1;
    }
  } else if (in[i] == '$') {
    i++;
    o = 0;
    while (1) {
      if (in[i] >= '0' && in[i] <= '9')
        o = (o * 16) + in[i] - '0';
      else if (in[i] >= 'a' && in[i] <= 'f')
        o = (o * 16) + in[i] - 'a' + 0xA;
      else if (in[i] >= 'A' && in[i] <= 'F')
        o = (o * 16) + in[i] - 'A' + 0xA;
      else if (in[i] == ' ' || in[i] == 0x09 || in[i] == 0)
        break;
      else
        return 1;
      i++;
    }
  } else
    return 1;
  *out = o;
  *pos += i;
  return 0;
}
```