ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memmove>:
  endbr64
  cmp    %rsi,%rdi
  jb     L77
  lea    (%rsi,%rdx,1),%rax
  cmp    %rax,%rdi
  jae    L77
  mov    %rdi,%rax
  xor    %rsi,%rax
  test   $0x7,%al
  je     L44
L129:
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L121
L59:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L59
  ret
L77:
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
L121:
  ret
L44:
  lea    (%rdi,%rdx,1),%rax
  test   $0x7,%al
  je     L23
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L95
L115:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  lea    (%rdi,%rax,1),%rdx
  test   $0x7,%dl
  je     L95
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L115
  mov    %rax,%rdx
  jmp    L31
L23:
  mov    %rdx,%rax
L95:
  mov    %rax,%rdx
  cmp    $0x7,%rax
  jbe    L129
L31:
  sub    $0x8,%rax
  mov    (%rsi,%rax,1),%rcx
  mov    %rcx,(%rdi,%rax,1)
  cmp    $0x7,%rax
  ja     L31
  and    $0x7,%edx
  jmp    L129
```

assistant: ```c
void memmove(void *dest, const void *src, size_t size) {
  if (dest < src || src + size <= dest) {
    return memcpy(dest, src, size);
  }
  char *destc = (char *)dest;
  const char *srcc = (const char *)src;
  if ((uintptr_t)srcc % sizeof(size_t) == (uintptr_t)destc % sizeof(size_t)) {
    while ((uintptr_t)(destc + size) % sizeof(size_t) && size--) {
      destc[size] = srcc[size];
    }
    while (size >= sizeof(size_t)) {
      size -= sizeof(size_t);
      *(size_t *)(destc + size) = *(size_t *)(srcc + size);
    }
  }
  while (size--) {
    destc[size] = srcc[size];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmove>:
  endbr64
  cmp    %rsi,%rdi
  jb     L137
  lea    (%rsi,%rdx,1),%rax
  cmp    %rax,%rdi
  jae    L137
  mov    %rdi,%rax
  xor    %rsi,%rax
  test   $0x7,%al
  jne    L13
  lea    (%rdi,%rdx,1),%rax
  test   $0x7,%al
  je     L110
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  jne    L15
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x1,%rax
  jb     L68
L15:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  lea    (%rdi,%rax,1),%rdx
  and    $0x7,%edx
  jne    L21
L48:
  cmp    $0x7,%rax
  jbe    L47
L17:
  mov    %rax,%rdx
  nop
L95:
  sub    $0x8,%rdx
  mov    (%rsi,%rdx,1),%rcx
  mov    %rcx,(%rdi,%rdx,1)
  cmp    $0x7,%rdx
  ja     L95
  and    $0x7,%eax
L47:
  mov    %rax,%rdx
L13:
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L123
  nopl   0x0(%rax)
L65:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  jae    L65
  ret
  cs nopw 0x0(%rax,%rax,1)
L137:
  jmp    1050 <memcpy@plt>
  nopl   (%rax)
L123:
  ret
  nopl   0x0(%rax)
L68:
  mov    $0xffffffffffffffff,%rax
  jmp    L17
L110:
  mov    %rdx,%rax
  jmp    L48
```

assistant: ```c
void memmove(void *dest, const void *src, size_t size) {
  if (dest < src || src + size <= dest) {
    return memcpy(dest, src, size);
  }
  char *destc = (char *)dest;
  const char *srcc = (const char *)src;
  if ((uintptr_t)srcc % sizeof(size_t) == (uintptr_t)destc % sizeof(size_t)) {
    while ((uintptr_t)(destc + size) % sizeof(size_t) && size--) {
      destc[size] = srcc[size];
    }
    while (size >= sizeof(size_t)) {
      size -= sizeof(size_t);
      *(size_t *)(destc + size) = *(size_t *)(srcc + size);
    }
  }
  while (size--) {
    destc[size] = srcc[size];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove>:
  endbr64
  cmp    %rsi,%rdi
  jb     L4
  lea    (%rsi,%rdx,1),%rax
  cmp    %rax,%rdi
  jae    L4
  mov    %rdi,%rcx
  xor    %rsi,%rcx
  and    $0x7,%ecx
  jne    L50
  lea    (%rdi,%rdx,1),%rax
  test   $0x7,%al
  je     L115
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  jne    L182
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L145:
  sub    $0x1,%rax
  jb     L57
L182:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  lea    (%rdi,%rax,1),%rdx
  and    $0x7,%edx
  jne    L145
L48:
  cmp    $0x7,%rax
  jbe    L5
L44:
  lea    -0x8(%rax),%rdx
  lea    -0x10(%rax),%r9
  lea    (%rsi,%r9,1),%r10
  lea    (%rdi,%rdx,1),%r8
  cmp    %r8,%r10
  je     L21
  cmp    $0x17,%rdx
  jbe    L21
  mov    %rdx,%r11
  add    %rdi,%r9
  shr    $0x3,%r11
  add    $0x1,%r11
  mov    %r11,%r8
  shr    %r8
  neg    %r8
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L94:
  movdqu (%r10,%rcx,1),%xmm0
  movups %xmm0,(%r9,%rcx,1)
  sub    $0x10,%rcx
  cmp    %r8,%rcx
  jne    L94
  mov    %r11,%r8
  and    $0xfffffffffffffffe,%r8
  mov    %r8,%rcx
  neg    %rcx
  shl    $0x3,%rcx
  cmp    %r8,%r11
  je     L35
  add    %rcx,%rdx
  mov    (%rsi,%rdx,1),%rcx
  mov    %rcx,(%rdi,%rdx,1)
L35:
  and    $0x7,%eax
L5:
  mov    %rax,%rdx
L50:
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L98
  nopl   0x0(%rax)
L128:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  jae    L128
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  jmp    1050 <memcpy@plt>
  nopl   (%rax)
L98:
  ret
  nopl   0x0(%rax)
L57:
  mov    $0xffffffffffffffff,%rax
  jmp    L44
L21:
  mov    %rax,%rdx
  nop
L176:
  sub    $0x8,%rdx
  mov    (%rsi,%rdx,1),%rcx
  mov    %rcx,(%rdi,%rdx,1)
  cmp    $0x7,%rdx
  ja     L176
  jmp    L35
L115:
  mov    %rdx,%rax
  jmp    L48
```

assistant: ```c
void memmove(void *dest, const void *src, size_t size) {
  if (dest < src || src + size <= dest) {
    return memcpy(dest, src, size);
  }
  char *destc = (char *)dest;
  const char *srcc = (const char *)src;
  if ((uintptr_t)srcc % sizeof(size_t) == (uintptr_t)destc % sizeof(size_t)) {
    while ((uintptr_t)(destc + size) % sizeof(size_t) && size--) {
      destc[size] = srcc[size];
    }
    while (size >= sizeof(size_t)) {
      size -= sizeof(size_t);
      *(size_t *)(destc + size) = *(size_t *)(srcc + size);
    }
  }
  while (size--) {
    destc[size] = srcc[size];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<retesave_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L11
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <retesave_one_byte@plt>
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    $0x0,%edi
  call   <retesave_one_byte@plt>
  nop
  leave
  ret
```

assistant: ```c
void retesave_string(char *s) {
  while (*s) {
    retesave_one_byte(*s);
    s++;
  }
  retesave_one_byte(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<retesave_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L1
L2:
  movsbl %dil,%edi
  call   <retesave_one_byte@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
L1:
  mov    $0x0,%edi
  call   <retesave_one_byte@plt>
  pop    %rbx
  ret
```

assistant: ```c
void retesave_string(char *s) {
  while (*s) {
    retesave_one_byte(*s);
    s++;
  }
  retesave_one_byte(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<retesave_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
L19:
  call   <retesave_one_byte@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L19
L3:
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <retesave_one_byte@plt>
```

assistant: ```c
void retesave_string(char *s) {
  while (*s) {
    retesave_one_byte(*s);
    s++;
  }
  retesave_one_byte(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<retesave_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L18:
  call   <retesave_one_byte@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L6:
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <retesave_one_byte@plt>
```

assistant: ```c
void retesave_string(char *s) {
  while (*s) {
    retesave_one_byte(*s);
    s++;
  }
  retesave_one_byte(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GRCTER>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
int GRCTER(fd, w_fd)
int *fd;
int w_fd;
{ close(*fd); }
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GRCTER>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  mov    $0x0,%eax
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int GRCTER(fd, w_fd)
int *fd;
int w_fd;
{ close(*fd); }
```
user: What is the c source code of the assembly code below:

```asm
<GRCTER>:
  endbr64
  mov    (%rdi),%edi
  xor    %eax,%eax
  jmp    1050 <close@plt>
```

assistant: ```c
int GRCTER(fd, w_fd)
int *fd;
int w_fd;
{ close(*fd); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GRCTER>:
  endbr64
  mov    (%rdi),%edi
  xor    %eax,%eax
  jmp    1050 <close@plt>
```

assistant: ```c
int GRCTER(fd, w_fd)
int *fd;
int w_fd;
{ close(*fd); }
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L24
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L24:
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip_chars(const char *string, const char *chars) {
  char *newstr = malloc(strlen(string) + 1);
  int counter = 0;
  for (; *string; string++) {
    if (!strchr(chars, *string)) {
      newstr[counter] = *string;
      ++counter;
    }
  }
  newstr[counter] = 0;
  return newstr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip_chars>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L31
  mov    $0x0,%ebp
  jmp    L9
L10:
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L44
L9:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L10
  movslq %ebp,%rax
  movzbl (%rbx),%edx
  mov    %dl,0x0(%r13,%rax,1)
  add    $0x1,%ebp
  jmp    L10
L31:
  mov    $0x0,%ebp
L44:
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strip_chars(const char *string, const char *chars) {
  char *newstr = malloc(strlen(string) + 1);
  int counter = 0;
  for (; *string; string++) {
    if (!strchr(chars, *string)) {
      newstr[counter] = *string;
      ++counter;
    }
  }
  newstr[counter] = 0;
  return newstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_chars>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movsbl (%rbx),%esi
  mov    %rax,%r12
  test   %sil,%sil
  je     L39
  xor    %ebp,%ebp
  nop
L14:
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L23
  movzbl (%rbx),%edx
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %dl,(%r12,%rax,1)
L23:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L14
  movslq %ebp,%rbp
  add    %r12,%rbp
L10:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L39:
  mov    %rax,%rbp
  jmp    L10
```

assistant: ```c
char *strip_chars(const char *string, const char *chars) {
  char *newstr = malloc(strlen(string) + 1);
  int counter = 0;
  for (; *string; string++) {
    if (!strchr(chars, *string)) {
      newstr[counter] = *string;
      ++counter;
    }
  }
  newstr[counter] = 0;
  return newstr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strip_chars>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movsbl (%rbx),%esi
  mov    %rax,%r12
  test   %sil,%sil
  je     L12
  xor    %ebp,%ebp
  nop
L51:
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L38
  movzbl (%rbx),%edx
  movsbl 0x1(%rbx),%esi
  movslq %ebp,%rax
  add    $0x1,%rbx
  add    $0x1,%ebp
  mov    %dl,(%r12,%rax,1)
  test   %sil,%sil
  jne    L51
L5:
  movslq %ebp,%rbp
  add    %r12,%rbp
L57:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L38:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L51
  jmp    L5
  nop
L12:
  mov    %rax,%rbp
  jmp    L57
```

assistant: ```c
char *strip_chars(const char *string, const char *chars) {
  char *newstr = malloc(strlen(string) + 1);
  int counter = 0;
  for (; *string; string++) {
    if (!strchr(chars, *string)) {
      newstr[counter] = *string;
      ++counter;
    }
  }
  newstr[counter] = 0;
  return newstr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <test2@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  test2(argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  test2(argc, argv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  test2(argc, argv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  test2(argc, argv);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<af_filter_pfir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%r12
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rbx
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%r13d
  jmp    L10
L18:
  mov    -0x24(%rbp),%eax
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <af_filter_fir@plt>
  movd   %xmm0,%eax
  mov    -0x48(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,%rbx
  movslq %r13d,%rax
  shl    $0x2,%rax
  add    %rax,%r12
  mov    0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,-0x48(%rbp)
L10:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  test   %eax,%eax
  jne    L18
  mov    -0x48(%rbp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
float *af_filter_pfir(unsigned int n, unsigned int d, unsigned int xi, const float **w, const float **x, float *y, unsigned int s) {
  register const float *xt = *x + xi;
  register const float *wt = *w;
  register int nt = 2 * n;
  while (d-- > 0) {
    *y = af_filter_fir(n, wt, xt);
    wt += n;
    xt += nt;
    y += s;
  }
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<af_filter_pfir>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,%eax
  mov    %r9,0x10(%rsp)
  mov    %edx,%edx
  mov    (%r8),%rsi
  lea    (%rsi,%rdx,4),%rbp
  mov    (%rcx),%rbx
  lea    -0x1(%rax),%r13d
  mov    %r13d,0x1c(%rsp)
  test   %eax,%eax
  je     L11
  mov    %edi,%r14d
  lea    (%rdi,%rdi,1),%edx
  mov    %edi,%eax
  shl    $0x2,%rax
  mov    %rax,(%rsp)
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  mov    %rax,0x8(%rsp)
  mov    0x60(%rsp),%r15d
  shl    $0x2,%r15
  mov    %r9,%r12
L15:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <af_filter_fir@plt>
  movss  %xmm0,(%r12)
  add    (%rsp),%rbx
  add    0x8(%rsp),%rbp
  add    %r15,%r12
  sub    $0x1,%r13d
  cmp    $0xffffffff,%r13d
  jne    L15
  mov    0x1c(%rsp),%eax
  add    $0x1,%rax
  imul   %r15,%rax
  add    0x10(%rsp),%rax
L1:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    0x10(%rsp),%rax
  jmp    L1
```

assistant: ```c
float *af_filter_pfir(unsigned int n, unsigned int d, unsigned int xi, const float **w, const float **x, float *y, unsigned int s) {
  register const float *xt = *x + xi;
  register const float *wt = *w;
  register int nt = 2 * n;
  while (d-- > 0) {
    *y = af_filter_fir(n, wt, xt);
    wt += n;
    xt += nt;
    y += s;
  }
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<af_filter_pfir>:
  endbr64
  push   %r15
  mov    %edx,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%r8),%rax
  mov    (%rcx),%r13
  mov    %esi,0x1c(%rsp)
  mov    %r9,0x10(%rsp)
  lea    (%rax,%rdx,4),%r12
  test   %esi,%esi
  je     L9
  mov    %edi,%eax
  lea    (%rdi,%rdi,1),%ebp
  mov    %edi,%r14d
  mov    %r9,%r15
  shl    $0x2,%rax
  movslq %ebp,%rbp
  lea    -0x1(%rsi),%ebx
  mov    %rax,0x8(%rsp)
  mov    0x60(%rsp),%eax
  shl    $0x2,%rbp
  shl    $0x2,%rax
  mov    %rax,(%rsp)
  nopl   (%rax)
L12:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  add    %rbp,%r12
  call   <af_filter_fir@plt>
  add    0x8(%rsp),%r13
  movss  %xmm0,(%r15)
  add    (%rsp),%r15
  sub    $0x1,%ebx
  jae    L12
  mov    0x1c(%rsp),%r14d
  imul   (%rsp),%r14
  mov    0x10(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  add    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L9:
  mov    0x10(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float *af_filter_pfir(unsigned int n, unsigned int d, unsigned int xi, const float **w, const float **x, float *y, unsigned int s) {
  register const float *xt = *x + xi;
  register const float *wt = *w;
  register int nt = 2 * n;
  while (d-- > 0) {
    *y = af_filter_fir(n, wt, xt);
    wt += n;
    xt += nt;
    y += s;
  }
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<af_filter_pfir>:
  endbr64
  push   %r15
  mov    %edx,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%r8),%rax
  mov    (%rcx),%r13
  mov    %esi,0x1c(%rsp)
  mov    %r9,0x10(%rsp)
  lea    (%rax,%rdx,4),%r12
  test   %esi,%esi
  je     L19
  mov    %edi,%eax
  lea    (%rdi,%rdi,1),%ebp
  mov    %edi,%r14d
  mov    %r9,%r15
  shl    $0x2,%rax
  movslq %ebp,%rbp
  lea    -0x1(%rsi),%ebx
  mov    %rax,0x8(%rsp)
  mov    0x60(%rsp),%eax
  shl    $0x2,%rbp
  shl    $0x2,%rax
  mov    %rax,(%rsp)
  nopl   (%rax)
L2:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  add    %rbp,%r12
  call   <af_filter_fir@plt>
  add    0x8(%rsp),%r13
  movss  %xmm0,(%r15)
  add    (%rsp),%r15
  sub    $0x1,%ebx
  jae    L2
  mov    0x1c(%rsp),%r14d
  imul   (%rsp),%r14
  mov    0x10(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  add    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L19:
  add    $0x28,%rsp
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float *af_filter_pfir(unsigned int n, unsigned int d, unsigned int xi, const float **w, const float **x, float *y, unsigned int s) {
  register const float *xt = *x + xi;
  register const float *wt = *w;
  register int nt = 2 * n;
  while (d-- > 0) {
    *y = af_filter_fir(n, wt, xt);
    wt += n;
    xt += nt;
    y += s;
  }
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<genmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gentext@plt>
  mov    $0x0,%eax
  call   <cgpop2@plt>
  mov    $0x0,%eax
  call   <cgmul@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void genmul(void) {
  gentext();
  cgpop2();
  cgmul();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<genmul>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gentext@plt>
  mov    $0x0,%eax
  call   <cgpop2@plt>
  mov    $0x0,%eax
  call   <cgmul@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void genmul(void) {
  gentext();
  cgpop2();
  cgmul();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<genmul>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gentext@plt>
  xor    %eax,%eax
  call   <cgpop2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <cgmul@plt>
```

assistant: ```c
void genmul(void) {
  gentext();
  cgpop2();
  cgmul();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<genmul>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gentext@plt>
  xor    %eax,%eax
  call   <cgpop2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <cgmul@plt>
```

assistant: ```c
void genmul(void) {
  gentext();
  cgpop2();
  cgmul();
}
```