ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kmp_search>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x8,%edi
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x20,%esi
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L38
  lea    0x20(%rsp),%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <kmp_table@plt>
  test   %r14,%r14
  je     L129
  mov    $0x20,%r9d
  xor    %ebp,%ebp
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %eax,%eax
  lea    -0x1(%rbx),%r10
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L28:
  mov    0x20(%rsp),%rax
  mov    (%rax,%rdx,4),%ebp
  test   %ebp,%ebp
  js     L109
  movslq %ebp,%rdx
  mov    %ebp,%esi
  sub    (%rax,%rdx,4),%esi
  add    %esi,%ecx
  lea    0x0(%rbp,%rcx,1),%ebx
L47:
  movslq %ebx,%rax
  cmp    %r14,%rax
  jae    L61
L19:
  movslq %ebp,%rdx
  movzbl (%r15,%rax,1),%eax
  cmp    %al,(%r12,%rdx,1)
  jne    L28
  add    $0x1,%ebp
  lea    0x0(%rbp,%rcx,1),%ebx
  cmp    %r10,%rdx
  jne    L47
  lea    0x1(%r8),%edx
  mov    0x0(%r13),%rdi
  cmp    %r9d,%edx
  jge    L54
L138:
  movslq %ecx,%rax
  mov    %rax,(%rdi,%r8,8)
  movslq %ebx,%rax
  movslq %edx,%r8
  cmp    %r14,%rax
  jb     L19
  nop
L61:
  mov    0x20(%rsp),%rdi
  mov    %r8d,0x8(%rsp)
  call   <free@plt>
  mov    0x8(%rsp),%r8d
L39:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L132
  add    $0x38,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L109:
  add    $0x1,%ecx
  xor    %ebp,%ebp
  mov    %ecx,%ebx
  jmp    L47
  nopl   0x0(%rax)
L54:
  add    $0x8,%r9d
  mov    %r10,0x18(%rsp)
  lea    0x0(,%r9,8),%esi
  mov    %r8d,0x14(%rsp)
  mov    %ecx,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  call   <realloc@plt>
  mov    0x18(%rsp),%r10
  movslq 0x14(%rsp),%r8
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  mov    0x8(%rsp),%r9d
  jmp    L138
  nopl   0x0(%rax,%rax,1)
L129:
  xor    %r8d,%r8d
  jmp    L61
L38:
  mov    $0xffffffff,%r8d
  jmp    L39
L132:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kmp_search(const char *text, const char *term, size_t text_len, size_t term_len, size_t **pos_array) {
  int *table;
  int c = 0, m = 0, i = 0;
  int l = 32;
  if ((*pos_array = calloc(sizeof(size_t), l)) == NULL)
    return -1;
  kmp_table(&table, term, term_len);
  while ((m + i) < text_len) {
    if (term[i] == text[m + i]) {
      if (i++ == (term_len - 1)) {
        if ((c + 1) >= l) {
          l += 8;
          *pos_array = realloc(*pos_array, l * sizeof(size_t));
        }
        (*pos_array)[c++] = m;
      }
    } else {
      if (table[i] > -1) {
        i = table[i];
        m += (i - table[i]);
      } else {
        i = 0;
        m++;
      }
    }
  }
  free(table);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D46: a=%d,b=%d


tool: D27: %d


assistant: ```c
int main() {
  int a = 3, b = 4;
  printf("a=%d,b=%d\n", a, b);
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("%d\n", b ^ a);
  b = b ^ a;
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("a=%d,b=%d\n", a, b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%edx
  mov    $0x3,%esi
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D3
type: string

tool: D17: a=%d,b=%d


tool: D3: %d


assistant: ```c
int main() {
  int a = 3, b = 4;
  printf("a=%d,b=%d\n", a, b);
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("%d\n", b ^ a);
  b = b ^ a;
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("a=%d,b=%d\n", a, b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  mov    $0x4,%edx
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rdi
  lea    D14(%rip),%rbp
  mov    $0x3,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x3,%edx
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D7: a=%d,b=%d


tool: D14: %d


assistant: ```c
int main() {
  int a = 3, b = 4;
  printf("a=%d,b=%d\n", a, b);
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("%d\n", b ^ a);
  b = b ^ a;
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("a=%d,b=%d\n", a, b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  mov    $0x4,%edx
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rdi
  lea    D18(%rip),%rbp
  mov    $0x3,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x3,%edx
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string

tool: D4: a=%d,b=%d


tool: D18: %d


assistant: ```c
int main() {
  int a = 3, b = 4;
  printf("a=%d,b=%d\n", a, b);
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("%d\n", b ^ a);
  b = b ^ a;
  printf("%d\n", a ^ b);
  a = a ^ b;
  printf("a=%d,b=%d\n", a, b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_ZSt13__copy_move_aILb0EPPiS1_ET1_T0_S3_S2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movb   $0x1,-0x51(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_ZNSt11__copy_moveILb0ELb1ESt26random_access_iterator_tagE8__copy_mIPiEEPT_PKS4_S7_S5_@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned int **_ZSt13__copy_move_aILb0EPPiS1_ET1_T0_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned char llvm_cbe___simple;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__44;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  *(&llvm_cbe___simple) = ((unsigned char)1);
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt11__copy_moveILb0ELb1ESt26random_access_iterator_tagE8__copy_mIPiEEPT_PKS4_S7_S5_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__44 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__44;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_ZSt13__copy_move_aILb0EPPiS1_ET1_T0_S3_S2_>:
  endbr64
  sub    $0x8,%rsp
  call   <_ZNSt11__copy_moveILb0ELb1ESt26random_access_iterator_tagE8__copy_mIPiEEPT_PKS4_S7_S5_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int **_ZSt13__copy_move_aILb0EPPiS1_ET1_T0_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned char llvm_cbe___simple;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__44;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  *(&llvm_cbe___simple) = ((unsigned char)1);
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt11__copy_moveILb0ELb1ESt26random_access_iterator_tagE8__copy_mIPiEEPT_PKS4_S7_S5_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__44 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__44;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_ZSt13__copy_move_aILb0EPPiS1_ET1_T0_S3_S2_>:
  endbr64
  jmp    1050 <_ZNSt11__copy_moveILb0ELb1ESt26random_access_iterator_tagE8__copy_mIPiEEPT_PKS4_S7_S5_@plt>
```

assistant: ```c
unsigned int **_ZSt13__copy_move_aILb0EPPiS1_ET1_T0_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned char llvm_cbe___simple;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__44;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  *(&llvm_cbe___simple) = ((unsigned char)1);
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt11__copy_moveILb0ELb1ESt26random_access_iterator_tagE8__copy_mIPiEEPT_PKS4_S7_S5_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__44 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__44;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L26
L10:
  lea    -0x40(%rbp),%rdx
  mov    -0x4c(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L45
  addl   $0x1,-0x48(%rbp)
  jmp    L68
L45:
  cmpl   $0x3,-0x48(%rbp)
  jne    L15
  addl   $0x1,-0x44(%rbp)
L15:
  movl   $0x0,-0x48(%rbp)
L68:
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L56
  addl   $0x1,-0x4c(%rbp)
L26:
  cmpl   $0x30,-0x4c(%rbp)
  jle    L10
  jmp    L59
L56:
  nop
L59:
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
data_type: string
name: parse_data
arguments: label: D37
data_type: string
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D27
data_type: string

tool: D28: This Program count words with 3 characters in a string


tool: D37: Please enter a string:

tool: D21: %c

tool: D27: The words with 3 characters count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count = 0, num = 0;
  printf("This Program count words with 3 characters in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] != ' ') {
      count++;
    } else {
      if (count == 3) {
        num++;
      }
      count = 0;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The words with 3 characters count is: %d\n", num);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x31(%rsp),%r13
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  lea    D27(%rip),%r12
  jmp    L15
L8:
  cmp    $0x3,%ebp
  sete   %al
  movzbl %al,%eax
  add    %eax,%r14d
  mov    $0x0,%ebp
L16:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L33
L15:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L8
  add    $0x1,%ebp
  cmp    $0xa,%al
  jne    L16
L33:
  mov    %r14d,%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string
name: parse_data
arguments: tag: D32
type_infered: string

tool: D5: This Program count words with 3 characters in a string


tool: D17: Please enter a string:

tool: D27: %c

tool: D32: The words with 3 characters count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count = 0, num = 0;
  printf("This Program count words with 3 characters in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] != ' ') {
      count++;
    } else {
      if (count == 3) {
        num++;
      }
      count = 0;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The words with 3 characters count is: %d\n", num);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D27(%rip),%rdi
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x31(%rsp),%r13
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L51
  xchg   %ax,%ax
L32:
  add    $0x1,%ebp
  cmp    $0xa,%al
  je     L17
L38:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L17
L51:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L32
  cmp    $0x3,%ebp
  je     L12
  add    $0x1,%rbx
  xor    %ebp,%ebp
  cmp    %r13,%rbx
  jne    L51
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  mov    %r14d,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%r14d
  xor    %ebp,%ebp
  jmp    L38
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string

tool: D27: This Program count words with 3 characters in a string


tool: D4: %c

tool: D25: Please enter a string:

tool: D13: The words with 3 characters count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count = 0, num = 0;
  printf("This Program count words with 3 characters in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] != ' ') {
      count++;
    } else {
      if (count == 3) {
        num++;
      }
      count = 0;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The words with 3 characters count is: %d\n", num);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%rdi
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x31(%rsp),%r13
  call   <puts@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  jmp    L50
  xchg   %ax,%ax
L70:
  add    $0x1,%ebp
  cmp    $0xa,%al
  je     L61
L45:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L61
L50:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L70
  cmp    $0x3,%ebp
  je     L2
  add    $0x1,%rbx
  xor    %ebp,%ebp
  cmp    %r13,%rbx
  jne    L50
  nopw   0x0(%rax,%rax,1)
L61:
  xor    %eax,%eax
  mov    %r14d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r14d
  xor    %ebp,%ebp
  jmp    L45
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D31
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D2: This Program count words with 3 characters in a string


tool: D15: %c

tool: D31: Please enter a string:

tool: D18: The words with 3 characters count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count = 0, num = 0;
  printf("This Program count words with 3 characters in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] != ' ') {
      count++;
    } else {
      if (count == 3) {
        num++;
      }
      count = 0;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The words with 3 characters count is: %d\n", num);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rysuj_gwiazdki_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x9,-0x4(%rbp)
  jle    L5
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string

tool: D18: * 

tool: D14: 


assistant: ```c
void rysuj_gwiazdki_1() {
  int i = 0;
  while (i < 10) {
    printf("* ");
    ++i;
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rysuj_gwiazdki_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%ebx
  lea    D19(%rip),%rbp
L6:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D19: * 

tool: D15: 


assistant: ```c
void rysuj_gwiazdki_1() {
  int i = 0;
  while (i < 10) {
    printf("* ");
    ++i;
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rysuj_gwiazdki_1>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  lea    D18(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string

tool: D10: * 

tool: D18: 


assistant: ```c
void rysuj_gwiazdki_1() {
  int i = 0;
  while (i < 10) {
    printf("* ");
    ++i;
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rysuj_gwiazdki_1>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  lea    D15(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string

tool: D11: * 

tool: D15: 


assistant: ```c
void rysuj_gwiazdki_1() {
  int i = 0;
  while (i < 10) {
    printf("* ");
    ++i;
  }
  printf("\n");
}
```