ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getCurrentHour@plt>
  mov    %eax,%esi
  cmp    $0xb,%eax
  jbe    L2
  lea    -0xc(%rax),%eax
  cmp    $0x5,%eax
  jbe    L8
  lea    -0x12(%rsi),%eax
  cmp    $0x5,%eax
  ja     L3
  lea    D3(%rip),%rdi
  pop    %rdx
  jmp    1070 <printf@plt>
L8:
  lea    D2(%rip),%rdi
  pop    %rcx
  jmp    1070 <printf@plt>
L2:
  lea    D9(%rip),%rdi
  pop    %r8
  jmp    1070 <printf@plt>
L3:
  pop    %rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string

tool: D3: Good evening, the hour is: %i

tool: D2: Good afternoon, the hour is: %i

tool: D9: Good morning, the hour is: %i

assistant: ```c
void main() {
  int currentHour = getCurrentHour();
  if (currentHour >= 0 && currentHour < 12) {
    printf("Good morning, the hour is: %i", currentHour);
  }
  if (currentHour >= 12 && currentHour < 18) {
    printf("Good afternoon, the hour is: %i", currentHour);
  }
  if (currentHour >= 18 && currentHour < 24) {
    printf("Good evening, the hour is: %i", currentHour);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getCurrentHour@plt>
  mov    %eax,%esi
  cmp    $0xb,%eax
  jbe    L28
  lea    -0xc(%rax),%eax
  cmp    $0x5,%eax
  jbe    L17
  lea    -0x12(%rsi),%eax
  cmp    $0x5,%eax
  ja     L15
  lea    D15(%rip),%rdi
  pop    %rdx
  jmp    1070 <printf@plt>
L17:
  lea    D20(%rip),%rdi
  pop    %rcx
  jmp    1070 <printf@plt>
L28:
  lea    D7(%rip),%rdi
  pop    %r8
  jmp    1070 <printf@plt>
L15:
  pop    %rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D15: Good evening, the hour is: %i

tool: D20: Good afternoon, the hour is: %i

tool: D7: Good morning, the hour is: %i

assistant: ```c
void main() {
  int currentHour = getCurrentHour();
  if (currentHour >= 0 && currentHour < 12) {
    printf("Good morning, the hour is: %i", currentHour);
  }
  if (currentHour >= 12 && currentHour < 18) {
    printf("Good afternoon, the hour is: %i", currentHour);
  }
  if (currentHour >= 18 && currentHour < 24) {
    printf("Good evening, the hour is: %i", currentHour);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<potencia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L16:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: f64

tool: D7: 1

assistant: ```c
double potencia(int x, int n) {
  int i;
  double potencia = 1;
  for (i = 0; i < n; i++)
    potencia = potencia * x;
  return potencia;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<potencia>:
  endbr64
  test   %esi,%esi
  jle    L9
  movsd  D13(%rip),%xmm0
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
L5:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L5
  ret
L9:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: f64

tool: D13: 1

assistant: ```c
double potencia(int x, int n) {
  int i;
  double potencia = 1;
  for (i = 0; i < n; i++)
    potencia = potencia * x;
  return potencia;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<potencia>:
  endbr64
  test   %esi,%esi
  jle    L19
  pxor   %xmm1,%xmm1
  movsd  D13(%rip),%xmm0
  xor    %eax,%eax
  cvtsi2sd %edi,%xmm1
  nopw   0x0(%rax,%rax,1)
L11:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L11
  ret
  nopl   0x0(%rax)
L19:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
datatype: f64

tool: D13: 1

assistant: ```c
double potencia(int x, int n) {
  int i;
  double potencia = 1;
  for (i = 0; i < n; i++)
    potencia = potencia * x;
  return potencia;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<potencia>:
  endbr64
  test   %esi,%esi
  jle    L2
  pxor   %xmm1,%xmm1
  movsd  D13(%rip),%xmm0
  xor    %eax,%eax
  cvtsi2sd %edi,%xmm1
  nopw   0x0(%rax,%rax,1)
L11:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L11
  ret
  nopl   0x0(%rax)
L2:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type: f64

tool: D13: 1

assistant: ```c
double potencia(int x, int n) {
  int i;
  double potencia = 1;
  for (i = 0; i < n; i++)
    potencia = potencia * x;
  return potencia;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<changendian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <changendian32@plt>
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdi
  call   <changendian32@plt>
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <changendian32@plt>
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %rax,%rdi
  call   <changendian32@plt>
  nop
  leave
  ret
```

assistant: ```c
void changendian(void *a) {
  changendian32((uint32_t *)(&(((uint32_t *)a)[0])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[1])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[2])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[3])));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<changendian>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <changendian32@plt>
  lea    0x4(%rbx),%rdi
  call   <changendian32@plt>
  lea    0x8(%rbx),%rdi
  call   <changendian32@plt>
  lea    0xc(%rbx),%rdi
  call   <changendian32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void changendian(void *a) {
  changendian32((uint32_t *)(&(((uint32_t *)a)[0])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[1])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[2])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[3])));
}
```
user: Translate the below assembly code into C programming language:

```asm
<changendian>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <changendian32@plt>
  lea    0x4(%rbx),%rdi
  call   <changendian32@plt>
  lea    0x8(%rbx),%rdi
  call   <changendian32@plt>
  lea    0xc(%rbx),%rdi
  pop    %rbx
  jmp    1050 <changendian32@plt>
```

assistant: ```c
void changendian(void *a) {
  changendian32((uint32_t *)(&(((uint32_t *)a)[0])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[1])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[2])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[3])));
}
```
user: What is the c source code of the assembly code below?

```asm
<changendian>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <changendian32@plt>
  lea    0x4(%rbx),%rdi
  call   <changendian32@plt>
  lea    0x8(%rbx),%rdi
  call   <changendian32@plt>
  lea    0xc(%rbx),%rdi
  pop    %rbx
  jmp    1050 <changendian32@plt>
```

assistant: ```c
void changendian(void *a) {
  changendian32((uint32_t *)(&(((uint32_t *)a)[0])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[1])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[2])));
  changendian32((uint32_t *)(&(((uint32_t *)a)[3])));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L5
L19:
  movl   $0x2,-0x4(%rbp)
  jmp    L8
L0:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x9,-0x4(%rbp)
  jle    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x9,-0x8(%rbp)
  jle    L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: %1d * %1d = %2d		

assistant: ```c
int main() {
  int x, y;
  for (x = 1; x <= 9; x++) {
    for (y = 2; y <= 9; y++)
      printf("%1d * %1d = %2d\t\t", y, x, x * y);
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%r12d
  lea    D9(%rip),%r14
  jmp    L29
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  je     L39
L29:
  mov    %r12d,%r13d
  lea    (%r12,%r12,1),%ebp
  mov    $0x2,%ebx
L22:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13d,%ebp
  cmp    $0xa,%ebx
  jne    L22
  jmp    L17
L39:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: %1d * %1d = %2d		

assistant: ```c
int main() {
  int x, y;
  for (x = 1; x <= 9; x++) {
    for (y = 2; y <= 9; y++)
      printf("%1d * %1d = %2d\t\t", y, x, x * y);
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  lea    (%r12,%r12,1),%ebp
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L19:
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %r12d,%ebp
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L19
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0xa,%r12d
  jne    L13
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: %1d * %1d = %2d		

assistant: ```c
int main() {
  int x, y;
  for (x = 1; x <= 9; x++) {
    for (y = 2; y <= 9; y++)
      printf("%1d * %1d = %2d\t\t", y, x, x * y);
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  lea    (%r12,%r12,1),%ebp
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L2:
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %r12d,%ebp
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L2
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0xa,%r12d
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: %1d * %1d = %2d		

assistant: ```c
int main() {
  int x, y;
  for (x = 1; x <= 9; x++) {
    for (y = 2; y <= 9; y++)
      printf("%1d * %1d = %2d\t\t", y, x, x * y);
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rdi
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <somar@plt>
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D43
type: string
name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D37
type: string

tool: D43: digite um numero: 

tool: D31: %f

tool: D37: %.2f


assistant: ```c
int main() {
  float n1;
  float n2;
  float n3;
  float r;
  printf("digite um numero: ");
  scanf("%f", &n1);
  printf("digite um numero: ");
  scanf("%f", &n2);
  somar(n1, n2, &r);
  printf("%.2f\n", r);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rdi
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <somar@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x14(%rsp),%xmm0
  lea    D28(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D28
type_infered: string

tool: D22: digite um numero: 

tool: D6: %f

tool: D28: %.2f


assistant: ```c
int main() {
  float n1;
  float n2;
  float n3;
  float r;
  printf("digite um numero: ");
  scanf("%f", &n1);
  printf("digite um numero: ");
  scanf("%f", &n2);
  somar(n1, n2, &r);
  printf("%.2f\n", r);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D7(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  lea    0x14(%rsp),%rdi
  call   <somar@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D13(%rip),%rdi
  cvtss2sd 0x14(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D11: digite um numero: 

tool: D7: %f

tool: D13: %.2f


assistant: ```c
int main() {
  float n1;
  float n2;
  float n3;
  float r;
  printf("digite um numero: ");
  scanf("%f", &n1);
  printf("digite um numero: ");
  scanf("%f", &n2);
  somar(n1, n2, &r);
  printf("%.2f\n", r);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D3(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  lea    0x14(%rsp),%rdi
  call   <somar@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D27(%rip),%rdi
  cvtss2sd 0x14(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string

tool: D18: digite um numero: 

tool: D3: %f

tool: D27: %.2f


assistant: ```c
int main() {
  float n1;
  float n2;
  float n3;
  float r;
  printf("digite um numero: ");
  scanf("%f", &n1);
  printf("digite um numero: ");
  scanf("%f", &n2);
  somar(n1, n2, &r);
  printf("%.2f\n", r);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_path_aux>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%r14
  mov    %r9,0x8(%rsp)
  lea    -0x1(%rdx),%rax
  cmp    %rdi,%rax
  je     L56
  jbe    L2
  lea    0x1(%rdi),%r15
  mov    %r15,%rax
  imul   %rcx,%rax
  lea    (%r8,%rsi,1),%rdx
  cmpb   $0x0,(%rdx,%rax,1)
  je     L99
L2:
  lea    -0x1(%r12),%rdx
  mov    $0x0,%eax
  cmp    %rbx,%rdx
  jbe    L22
  add    $0x1,%rbx
  mov    %r12,%rdx
  imul   %rbp,%rdx
  lea    (%r14,%rbx,1),%rcx
  cmpb   $0x0,(%rcx,%rdx,1)
  je     L36
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  lea    -0x1(%rcx),%rax
  cmp    %rsi,%rax
  jne    L2
  mov    0x50(%rsp),%rsi
  movb   $0x0,(%r9,%rsi,1)
  mov    $0x1,%eax
  jmp    L22
L99:
  mov    0x8(%rsp),%rdi
  add    0x50(%rsp),%rdi
  mov    %rsi,%rcx
  mov    %r15,%rdx
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  cltq
  add    0x58(%rsp),%rax
  push   %rax
  mov    0x18(%rsp),%r9
  mov    %r14,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <find_path_aux>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L22
  jmp    L2
L36:
  mov    0x8(%rsp),%r15
  mov    %r15,%rdi
  add    0x50(%rsp),%rdi
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  cltq
  add    0x58(%rsp),%rax
  push   %rax
  mov    %r15,%r9
  mov    %r14,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <find_path_aux>
  add    $0x10,%rsp
  jmp    L22
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2:  -> (%zu, %zu)

assistant: ```c
int find_path_aux(size_t curr_x, size_t curr_y, size_t x, size_t y, unsigned char bad_pos[x][y], char *path, size_t path_i) {
  if (curr_x == x - 1 && curr_y == y - 1) {
    path[path_i] = '\0';
    return 1;
  }
  int found_path = 0;
  if (curr_x < x - 1 && !bad_pos[curr_x + 1][curr_y]) {
    int written = sprintf(path + path_i, " -> (%zu, %zu)", curr_x + 1, curr_y);
    found_path = find_path_aux(curr_x + 1, curr_y, x, y, bad_pos, path, path_i + written);
  }
  if (!found_path && curr_y < y - 1 && !bad_pos[curr_x][curr_y + 1]) {
    int written = sprintf(path + path_i, " -> (%zu, %zu)", curr_x, curr_y + 1);
    found_path = find_path_aux(curr_x, curr_y + 1, x, y, bad_pos, path, path_i + written);
  }
  return found_path;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_path_aux>:
  endbr64
  push   %r15
  mov    %rcx,%rax
  lea    D7(%rip),%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%rsi
  sub    $0x48,%rsp
  mov    %rbp,0x20(%rsp)
  imul   %rcx,%rbp
  mov    %rcx,0x30(%rsp)
  mov    %rdx,0x28(%rsp)
  lea    (%r8,%rbp,1),%rcx
  sub    %rax,%rbp
  sub    $0x1,%rax
  mov    %r8,0x38(%rsp)
  add    %r8,%rbp
  mov    %rcx,0x18(%rsp)
  mov    %rbp,%r14
  mov    %rsi,0x10(%rsp)
  mov    0x80(%rsp),%rbp
  mov    %rax,0x8(%rsp)
  jmp    L6
  nop
L49:
  jae    L62
  mov    0x18(%rsp),%rax
  cmpb   $0x0,(%rax,%rbx,1)
  je     L32
L62:
  cmp    0x8(%rsp),%rbx
  jae    L4
L12:
  add    $0x1,%rbx
  cmpb   $0x0,(%r14,%rbx,1)
  jne    L4
  lea    (%r12,%rbp,1),%rdi
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  call   <sprintf@plt>
  cltq
  add    %rax,%rbp
L6:
  cmp    0x10(%rsp),%r13
  jne    L49
  cmp    0x8(%rsp),%rbx
  jne    L62
  movb   $0x0,(%r12,%rbp,1)
  mov    $0x1,%eax
L51:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L32:
  mov    0x20(%rsp),%rdx
  lea    (%r12,%rbp,1),%rdi
  mov    %rbx,%rcx
  mov    %r15,%rsi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  mov    %r12,%r9
  mov    %rbx,%rsi
  cltq
  add    %rbp,%rax
  push   %rax
  mov    0x48(%rsp),%r8
  mov    0x40(%rsp),%rcx
  mov    0x38(%rsp),%rdx
  mov    0x30(%rsp),%rdi
  call   <find_path_aux>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  jne    L51
  cmp    0x8(%rsp),%rbx
  jb     L12
L4:
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7:  -> (%zu, %zu)

assistant: ```c
int find_path_aux(size_t curr_x, size_t curr_y, size_t x, size_t y, unsigned char bad_pos[x][y], char *path, size_t path_i) {
  if (curr_x == x - 1 && curr_y == y - 1) {
    path[path_i] = '\0';
    return 1;
  }
  int found_path = 0;
  if (curr_x < x - 1 && !bad_pos[curr_x + 1][curr_y]) {
    int written = sprintf(path + path_i, " -> (%zu, %zu)", curr_x + 1, curr_y);
    found_path = find_path_aux(curr_x + 1, curr_y, x, y, bad_pos, path, path_i + written);
  }
  if (!found_path && curr_y < y - 1 && !bad_pos[curr_x][curr_y + 1]) {
    int written = sprintf(path + path_i, " -> (%zu, %zu)", curr_x, curr_y + 1);
    found_path = find_path_aux(curr_x, curr_y + 1, x, y, bad_pos, path, path_i + written);
  }
  return found_path;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hdr_gettoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x0,-0xd(%rbp)
  mov    $0x0,%eax
  call   <get8@plt>
  mov    %al,-0xd(%rbp)
  jmp    L38
L48:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  cmpl   $0x3ff,-0xc(%rbp)
  jne    L58
  nop
L17:
  mov    $0x0,%eax
  call   <at_eof@plt>
  test   %eax,%eax
  jne    L11
  mov    $0x0,%eax
  call   <get8@plt>
  cmp    $0xa,%al
  jne    L17
  jmp    L11
L58:
  mov    $0x0,%eax
  call   <get8@plt>
  mov    %al,-0xd(%rbp)
L38:
  mov    $0x0,%eax
  call   <at_eof@plt>
  test   %eax,%eax
  jne    L33
  cmpb   $0xa,-0xd(%rbp)
  jne    L48
  jmp    L33
L11:
  nop
L33:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *hdr_gettoken(char *buffer) {
  int len = 0;
  char *s = buffer, c = '\0';
  c = get8();
  while (!at_eof() && c != '\n') {
    buffer[len++] = c;
    if (len == 1024 - 1) {
      while (!at_eof() && get8() != '\n')
        ;
      break;
    }
    c = get8();
  }
  buffer[len] = 0;
  return buffer;
}
```