ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_comm_schedule>:
  endbr64
  push   %r15
  mov    %esi,%ecx
  mov    %esi,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  and    $0x1,%ecx
  mov    %ecx,0x4(%rsp)
  jne    L108
  lea    -0x1(%rsi),%ebx
  test   %esi,%esi
  jle    L46
  xor    %ebp,%ebp
L65:
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <add_pair_to_comm_schedule@plt>
  cmp    %ebp,%r15d
  jne    L65
L46:
  mov    %r15d,%r14d
L36:
  test   %ebx,%ebx
  jle    L69
  lea    (%rbx,%rbx,1),%eax
  sar    %r14d
  xor    %r12d,%r12d
  mov    %eax,0x8(%rsp)
  mov    %r15d,%eax
  mov    %r14d,%ebp
  sub    $0x1,%eax
  neg    %ebp
  mov    %eax,0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L115:
  mov    0x4(%rsp),%eax
  mov    0xc(%rsp),%edx
  lea    0x0(%rbp,%r14,1),%esi
  mov    %r13,%rdi
  lea    -0x1(%r14,%rbp,1),%r15d
  test   %eax,%eax
  cmovne %esi,%edx
  call   <add_pair_to_comm_schedule@plt>
  cmp    $0x1,%r14d
  jle    L2
  nopl   (%rax)
L0:
  mov    %r12d,%eax
  sub    %r15d,%eax
  cltd
  idiv   %ebx
  test   %r15d,%r15d
  js     L92
  mov    %r15d,%esi
  mov    %r13,%rdi
  sub    $0x1,%r15d
  call   <add_pair_to_comm_schedule@plt>
  cmp    %ebp,%r15d
  jne    L0
L2:
  add    $0x2,%r12d
  add    $0x1,%ebp
  cmp    0x8(%rsp),%r12d
  jne    L115
L69:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L92:
  lea    (%r15,%rbx,1),%esi
  mov    %r13,%rdi
  sub    $0x1,%r15d
  call   <add_pair_to_comm_schedule@plt>
  cmp    %r15d,%ebp
  jne    L0
  add    $0x2,%r12d
  add    $0x1,%ebp
  cmp    0x8(%rsp),%r12d
  jne    L115
  jmp    L69
L108:
  mov    %esi,%ebx
  lea    0x1(%rsi),%r14d
  jmp    L36
```

assistant: ```c
void fill_comm_schedule(int **sched, int npes) {
  int pe, i, n;
  if (npes % 2 == 0) {
    n = npes;
    for (pe = 0; pe < npes; ++pe)
      add_pair_to_comm_schedule(sched, pe, pe);
  } else
    n = npes + 1;
  for (pe = 0; pe < n - 1; ++pe) {
    add_pair_to_comm_schedule(sched, pe, npes % 2 == 0 ? npes - 1 : pe);
    for (i = 1; i < n / 2; ++i) {
      int pe_a, pe_b;
      pe_a = pe - i;
      if (pe_a < 0)
        pe_a += n - 1;
      pe_b = (pe + i) % (n - 1);
      add_pair_to_comm_schedule(sched, pe_a, pe_b);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<populateQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xff676981,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x4,-0x4(%rbp)
  jle    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void populateQ(int *Q) {
  int i;
  for (i = 0; i < 5; i++)
    Q[i] = -9999999;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<populateQ>:
  endbr64
  movl   $0xff676981,(%rdi)
  movl   $0xff676981,0x4(%rdi)
  movl   $0xff676981,0x8(%rdi)
  movl   $0xff676981,0xc(%rdi)
  movl   $0xff676981,0x10(%rdi)
  ret
```

assistant: ```c
void populateQ(int *Q) {
  int i;
  for (i = 0; i < 5; i++)
    Q[i] = -9999999;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<populateQ>:
  endbr64
  movabs $0xff676981ff676981,%rax
  movl   $0xff676981,0x10(%rdi)
  mov    %rax,(%rdi)
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void populateQ(int *Q) {
  int i;
  for (i = 0; i < 5; i++)
    Q[i] = -9999999;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<populateQ>:
  endbr64
  movdqa D5(%rip),%xmm0
  movl   $0xff676981,0x10(%rdi)
  movups %xmm0,(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: byte[16]

tool: {"D5": [0x81,0x69,0x67,0xff,0x81,0x69,0x67,0xff,0x81,0x69,0x67,0xff,0x81,0x69,0x67,0xff]}

assistant: ```c
void populateQ(int *Q) {
  int i;
  for (i = 0; i < 5; i++)
    Q[i] = -9999999;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ROL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %edx,%ecx
  rol    %cl,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned ROL(unsigned word, int i) {
  asm("roll %%cl, %0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ROL>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  rol    %cl,%eax
  ret
```

assistant: ```c
unsigned ROL(unsigned word, int i) {
  asm("roll %%cl, %0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ROL>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  rol    %cl,%eax
  ret
```

assistant: ```c
unsigned ROL(unsigned word, int i) {
  asm("roll %%cl, %0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ROL>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  rol    %cl,%eax
  ret
```

assistant: ```c
unsigned ROL(unsigned word, int i) {
  asm("roll %%cl, %0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <localeconv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string

tool: D13: lc->decimal_point = %s


tool: D10: lc->thousands_sep = %s


assistant: ```c
int main(void) {
  struct lconv *lc;
  lc = localeconv();
  printf("lc->decimal_point = %s\n", lc->decimal_point);
  printf("lc->thousands_sep = %s\n", lc->thousands_sep);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <localeconv@plt>
  mov    %rax,%rbx
  mov    (%rax),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rbx),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string
name: read_data
arguments: data_label: D8
datatype: string

tool: D0: lc->decimal_point = %s


tool: D8: lc->thousands_sep = %s


assistant: ```c
int main(void) {
  struct lconv *lc;
  lc = localeconv();
  printf("lc->decimal_point = %s\n", lc->decimal_point);
  printf("lc->thousands_sep = %s\n", lc->thousands_sep);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <localeconv@plt>
  lea    D16(%rip),%rdi
  mov    (%rax),%rsi
  mov    %rax,%rbx
  call   <printf@plt>
  mov    0x8(%rbx),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D16
data_type: string
name: read_data
arguments: tag: D14
data_type: string

tool: D16: lc->decimal_point = %s


tool: D14: lc->thousands_sep = %s


assistant: ```c
int main(void) {
  struct lconv *lc;
  lc = localeconv();
  printf("lc->decimal_point = %s\n", lc->decimal_point);
  printf("lc->thousands_sep = %s\n", lc->thousands_sep);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <localeconv@plt>
  lea    D4(%rip),%rdi
  mov    (%rax),%rsi
  mov    %rax,%rbx
  call   <printf@plt>
  mov    0x8(%rbx),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string

tool: D4: lc->decimal_point = %s


tool: D10: lc->thousands_sep = %s


assistant: ```c
int main(void) {
  struct lconv *lc;
  lc = localeconv();
  printf("lc->decimal_point = %s\n", lc->decimal_point);
  printf("lc->thousands_sep = %s\n", lc->thousands_sep);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<where_in_command_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L30
L26:
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L27
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L26
L27:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L40
  mov    $0xffffffff,%eax
  jmp    L23
L40:
  mov    -0x4(%rbp),%eax
L23:
  leave
  ret
```

assistant: ```c
int where_in_command_line(int argc, char *argv[], char *match) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return -1;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<where_in_command_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  test   %edi,%edi
  jle    L54
  mov    %rdx,%r12
  lea    0x8(%rsi),%rbx
  mov    $0x1,%ebp
L51:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L12
  add    $0x1,%ebp
  add    $0x8,%rbx
  cmp    %ebp,%r13d
  jge    L51
L12:
  add    $0x1,%r13d
  cmp    %ebp,%r13d
  je     L3
L14:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  mov    $0x1,%ebp
  jmp    L12
L3:
  mov    $0xffffffff,%ebp
  jmp    L14
```

assistant: ```c
int where_in_command_line(int argc, char *argv[], char *match) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return -1;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<where_in_command_line>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L39
  mov    %rdx,%rbp
  lea    0x8(%rsi),%rbx
  mov    $0x1,%r12d
  jmp    L14
  nopl   0x0(%rax)
L31:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%r13d
  jl     L19
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L31
L19:
  add    $0x1,%r13d
  cmp    %r12d,%r13d
  je     L6
L44:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x1,%r12d
  jmp    L19
L6:
  mov    $0xffffffff,%r12d
  jmp    L44
```

assistant: ```c
int where_in_command_line(int argc, char *argv[], char *match) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return -1;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<where_in_command_line>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L60
  mov    %rdx,%rbp
  lea    0x8(%rsi),%rbx
  mov    $0x1,%r12d
  jmp    L5
  nopl   0x0(%rax)
L49:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%r13d
  jl     L58
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L49
L58:
  add    $0x1,%r13d
  cmp    %r12d,%r13d
  je     L25
L54:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  mov    $0x1,%r12d
  jmp    L58
L25:
  mov    $0xffffffff,%r12d
  jmp    L54
```

assistant: ```c
int where_in_command_line(int argc, char *argv[], char *match) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return -1;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <count@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D0: %d

tool: D15: cnt %d


assistant: ```c
int main() {
  int x;
  scanf("%d", &x);
  int cnt = count(x);
  printf("cnt %d\n", cnt);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <count@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D14: %d

tool: D0: cnt %d


assistant: ```c
int main() {
  int x;
  scanf("%d", &x);
  int cnt = count(x);
  printf("cnt %d\n", cnt);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <count@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string

tool: D10: %d

tool: D17: cnt %d


assistant: ```c
int main() {
  int x;
  scanf("%d", &x);
  int cnt = count(x);
  printf("cnt %d\n", cnt);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <count@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string

tool: D11: %d

tool: D14: cnt %d


assistant: ```c
int main() {
  int x;
  scanf("%d", &x);
  int cnt = count(x);
  printf("cnt %d\n", cnt);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L8
L11:
  mov    -0x8(%rbp),%rax
L8:
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <reversesub@plt>
  nop
  leave
  ret
```

assistant: ```c
void reverse(char *s) {
  char *send = s + strlen(s) - 1;
  reversesub(s, (*send == '\n') ? --send : send);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rsi
  cmpb   $0xa,(%rsi)
  sete   %al
  movzbl %al,%eax
  sub    %rax,%rsi
  mov    %rbx,%rdi
  call   <reversesub@plt>
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  char *send = s + strlen(s) - 1;
  reversesub(s, (*send == '\n') ? --send : send);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  cltq
  lea    -0x1(%rbp,%rax,1),%rsi
  xor    %eax,%eax
  pop    %rbp
  cmpb   $0xa,(%rsi)
  sete   %al
  sub    %rax,%rsi
  jmp    1070 <reversesub@plt>
```

assistant: ```c
void reverse(char *s) {
  char *send = s + strlen(s) - 1;
  reversesub(s, (*send == '\n') ? --send : send);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  cltq
  lea    -0x1(%rbp,%rax,1),%rsi
  xor    %eax,%eax
  pop    %rbp
  cmpb   $0xa,(%rsi)
  sete   %al
  sub    %rax,%rsi
  jmp    1070 <reversesub@plt>
```

assistant: ```c
void reverse(char *s) {
  char *send = s + strlen(s) - 1;
  reversesub(s, (*send == '\n') ? --send : send);
}
```
user: Translate the below assembly code into C programming language:

```asm
<setbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L18
  mov    $0x0,%eax
  jmp    L19
L18:
  addq   $0x4,-0x10(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L35
  mov    -0x4(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  or     %ecx,%edx
  mov    %dl,(%rax)
  jmp    L9
L35:
  mov    -0x4(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
L9:
  mov    $0x1,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
setbit(unsigned c, char *map, unsigned val) {
  if (c >= *(unsigned *)map)
    return 0;
  map += sizeof(unsigned);
  if (val)
    map[c >> 3] |= 1 << (c & 0x07);
  else
    map[c >> 3] &= ~(1 << (c & 0x07));
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setbit>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    %edi,(%rsi)
  jbe    L3
  add    $0x4,%rsi
  test   %edx,%edx
  je     L16
  mov    %edi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  and    $0x7,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  or     %dl,(%rsi,%rax,1)
  mov    $0x1,%eax
  ret
L16:
  mov    %edi,%edx
  shr    $0x3,%edx
  mov    %edx,%edx
  and    $0x7,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  not    %eax
  and    %al,(%rsi,%rdx,1)
  mov    $0x1,%eax
L3:
  ret
```

assistant: ```c
setbit(unsigned c, char *map, unsigned val) {
  if (c >= *(unsigned *)map)
    return 0;
  map += sizeof(unsigned);
  if (val)
    map[c >> 3] |= 1 << (c & 0x07);
  else
    map[c >> 3] &= ~(1 << (c & 0x07));
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setbit>:
  endbr64
  mov    %edi,%ecx
  xor    %eax,%eax
  cmp    %edi,(%rsi)
  jbe    L7
  mov    %edi,%eax
  and    $0x7,%ecx
  shr    $0x3,%eax
  add    $0x4,%eax
  add    %rax,%rsi
  mov    $0x1,%eax
  movzbl (%rsi),%edi
  shl    %cl,%eax
  test   %edx,%edx
  je     L1
  or     %eax,%edi
  mov    $0x1,%eax
  mov    %dil,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  not    %eax
  and    %edi,%eax
  mov    %al,(%rsi)
  mov    $0x1,%eax
L7:
  ret
```

assistant: ```c
setbit(unsigned c, char *map, unsigned val) {
  if (c >= *(unsigned *)map)
    return 0;
  map += sizeof(unsigned);
  if (val)
    map[c >> 3] |= 1 << (c & 0x07);
  else
    map[c >> 3] &= ~(1 << (c & 0x07));
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<setbit>:
  endbr64
  mov    %edi,%ecx
  xor    %eax,%eax
  cmp    %edi,(%rsi)
  jbe    L10
  mov    %edi,%eax
  and    $0x7,%ecx
  shr    $0x3,%eax
  add    $0x4,%eax
  add    %rax,%rsi
  mov    $0x1,%eax
  movzbl (%rsi),%edi
  shl    %cl,%eax
  test   %edx,%edx
  je     L16
  or     %eax,%edi
  mov    $0x1,%eax
  mov    %dil,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  not    %eax
  and    %edi,%eax
  mov    %al,(%rsi)
  mov    $0x1,%eax
L10:
  ret
```

assistant: ```c
setbit(unsigned c, char *map, unsigned val) {
  if (c >= *(unsigned *)map)
    return 0;
  map += sizeof(unsigned);
  if (val)
    map[c >> 3] |= 1 << (c & 0x07);
  else
    map[c >> 3] &= ~(1 << (c & 0x07));
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prs_max_compressed_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  addq   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  je     L1
  mov    $0x1,%eax
  jmp    L0
L1:
  mov    $0x0,%eax
L0:
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t prs_max_compressed_size(size_t len) {
  len += 2;
  return len + (len >> 3) + ((len & 0x07) ? 1 : 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<prs_max_compressed_size>:
  endbr64
  add    $0x2,%rdi
  mov    %rdi,%rax
  shr    $0x3,%rax
  add    %rdi,%rax
  and    $0x7,%edi
  cmp    $0x1,%rdi
  sbb    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
size_t prs_max_compressed_size(size_t len) {
  len += 2;
  return len + (len >> 3) + ((len & 0x07) ? 1 : 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prs_max_compressed_size>:
  endbr64
  add    $0x2,%rdi
  mov    %rdi,%rax
  shr    $0x3,%rax
  add    %rdi,%rax
  and    $0x7,%edi
  cmp    $0x1,%rdi
  sbb    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
size_t prs_max_compressed_size(size_t len) {
  len += 2;
  return len + (len >> 3) + ((len & 0x07) ? 1 : 0);
}
```