user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0xa,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ecx
  mov    $0x0,%edx
  div    %rcx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L23:
  cmp    %rdx,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L33:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L57
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L57:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x9,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x4,0x4(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x1,0x8(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0xffffffee,0xc(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x3,0x10(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x6,0x14(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x7,0x18(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x2,0x1c(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x0,0x20(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0xfffffffe,0x24(%rax)
  movl   $0x0,-0x34(%rbp)
  jmp    L68
L7:
  mov    -0x20(%rbp),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L68:
  mov    -0x34(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <msort@plt>
  movl   $0x0,-0x30(%rbp)
  jmp    L9
L28:
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x30(%rbp)
L9:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rsp
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
datatype: string

tool: D13: %d 

assistant: ```c
int main(void) {
  int n = 10;
  int test[n];
  test[0] = 9;
  test[1] = 4;
  test[2] = 1;
  test[3] = -18;
  test[4] = 3;
  test[5] = 6;
  test[6] = 7;
  test[7] = 2;
  test[8] = 0;
  test[9] = -2;
  for (int i = 0; i < n; i++) {
    printf("%d ", test[i]);
  }
  printf("\n");
  msort(test, 0, n - 1);
  for (int i = 0; i < n; i++) {
    printf("%d ", test[i]);
  }
  printf("\n");
}
```