ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<josephus>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jne    L22
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  lea    -0x1(%rdi),%ebx
  cmp    $0x2,%edi
  je     L18
  lea    -0x2(%rdi),%ebp
  cmp    $0x3,%edi
  jne    L26
L3:
  lea    -0x1(%rbp,%rsi,1),%eax
  cltd
  idiv   %ebx
  lea    0x1(%rdx),%ebx
L18:
  lea    -0x1(%rbx,%rsi,1),%eax
  add    $0x18,%rsp
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  lea    0x1(%rdx),%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  lea    -0x3(%rdi),%r13d
  cmp    $0x4,%edi
  je     L1
  lea    -0x4(%rdi),%edi
  mov    %esi,0xc(%rsp)
  call   <josephus>
  mov    0xc(%rsp),%esi
  lea    -0x1(%rsi,%rax,1),%eax
  cltd
  idiv   %r13d
  lea    0x1(%rdx),%r13d
L1:
  lea    -0x1(%r13,%rsi,1),%eax
  cltd
  idiv   %ebp
  lea    0x1(%rdx),%ebp
  jmp    L3
```

assistant: ```c
int josephus(int n, int k) {
  if (n == 1)
    return 1;
  else
    return (josephus(n - 1, k) + k - 1) % n + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<josephus>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jne    L12
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  lea    -0x1(%rdi),%ebx
  cmp    $0x2,%edi
  je     L8
  lea    -0x2(%rdi),%ebp
  cmp    $0x3,%edi
  jne    L15
L37:
  lea    -0x1(%rbp,%rsi,1),%eax
  cltd
  idiv   %ebx
  lea    0x1(%rdx),%ebx
L8:
  lea    -0x1(%rbx,%rsi,1),%eax
  add    $0x18,%rsp
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  lea    0x1(%rdx),%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  lea    -0x3(%rdi),%r13d
  cmp    $0x4,%edi
  je     L19
  lea    -0x4(%rdi),%edi
  mov    %esi,0xc(%rsp)
  call   <josephus>
  mov    0xc(%rsp),%esi
  lea    -0x1(%rsi,%rax,1),%eax
  cltd
  idiv   %r13d
  lea    0x1(%rdx),%r13d
L19:
  lea    -0x1(%r13,%rsi,1),%eax
  cltd
  idiv   %ebp
  lea    0x1(%rdx),%ebp
  jmp    L37
```

assistant: ```c
int josephus(int n, int k) {
  if (n == 1)
    return 1;
  else
    return (josephus(n - 1, k) + k - 1) % n + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uninitvar_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <logf@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  call   <logl@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_log(void) {
  float f;
  (void)logf(f);
  double d;
  (void)log(d);
  long double ld;
  (void)logl(ld);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uninitvar_log>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <logf@plt>
  pxor   %xmm0,%xmm0
  call   <log@plt>
  push   $0x0
  push   $0x0
  call   <logl@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void uninitvar_log(void) {
  float f;
  (void)logf(f);
  double d;
  (void)log(d);
  long double ld;
  (void)logl(ld);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_log>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <logf@plt>
  pxor   %xmm0,%xmm0
  call   <log@plt>
  push   $0x0
  push   $0x0
  call   <logl@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void uninitvar_log(void) {
  float f;
  (void)logf(f);
  double d;
  (void)log(d);
  long double ld;
  (void)logl(ld);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uninitvar_log>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <logf@plt>
  pxor   %xmm0,%xmm0
  call   <log@plt>
  push   $0x0
  push   $0x0
  call   <logl@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void uninitvar_log(void) {
  float f;
  (void)logf(f);
  double d;
  (void)log(d);
  long double ld;
  (void)logl(ld);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L12
L8:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getLine@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: %s

assistant: ```c
int main(void) {
  int c, len;
  char line[1000];
  while ((len = getLine(line, 1000)) > 0) {
    reverse(line);
    printf("%s", line);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rbp
  jmp    L16
L10:
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L16:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getLine@plt>
  test   %eax,%eax
  jg     L10
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: %s

assistant: ```c
int main(void) {
  int c, len;
  char line[1000];
  while ((len = getLine(line, 1000)) > 0) {
    reverse(line);
    printf("%s", line);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L11
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L11:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getLine@plt>
  test   %eax,%eax
  jg     L14
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: %s

assistant: ```c
int main(void) {
  int c, len;
  char line[1000];
  while ((len = getLine(line, 1000)) > 0) {
    reverse(line);
    printf("%s", line);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L23
  nopl   0x0(%rax)
L26:
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L23:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getLine@plt>
  test   %eax,%eax
  jg     L26
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: %s

assistant: ```c
int main(void) {
  int c, len;
  char line[1000];
  while ((len = getLine(line, 1000)) > 0) {
    reverse(line);
    printf("%s", line);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<texel_squared_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <texel_error@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double texel_squared_error(double score, double result) {
  double error;
  error = texel_error(score, result);
  return error * error;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<texel_squared_error>:
  endbr64
  sub    $0x8,%rsp
  call   <texel_error@plt>
  mulsd  %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

assistant: ```c
double texel_squared_error(double score, double result) {
  double error;
  error = texel_error(score, result);
  return error * error;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<texel_squared_error>:
  endbr64
  sub    $0x8,%rsp
  call   <texel_error@plt>
  add    $0x8,%rsp
  mulsd  %xmm0,%xmm0
  ret
```

assistant: ```c
double texel_squared_error(double score, double result) {
  double error;
  error = texel_error(score, result);
  return error * error;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<texel_squared_error>:
  endbr64
  sub    $0x8,%rsp
  call   <texel_error@plt>
  add    $0x8,%rsp
  mulsd  %xmm0,%xmm0
  ret
```

assistant: ```c
double texel_squared_error(double score, double result) {
  double error;
  error = texel_error(score, result);
  return error * error;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L1
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  imul   $0x2a446707,%eax,%eax
  lea    0x3e03d65d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] - 515147141UL) * 709125895U;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  lea    (%rax,%rax,1),%edx
  test   $0x10,%al
  cmovne %edx,%eax
  imul   $0x2a446707,%eax,%eax
  add    $0x3e03d65d,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] - 515147141UL) * 709125895U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  test   $0x10,%al
  lea    (%rax,%rax,1),%edx
  cmovne %edx,%eax
  imul   $0x2a446707,%eax,%eax
  add    $0x3e03d65d,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] - 515147141UL) * 709125895U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  test   $0x10,%al
  lea    (%rax,%rax,1),%edx
  cmovne %edx,%eax
  imul   $0x2a446707,%eax,%eax
  add    $0x3e03d65d,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] - 515147141UL) * 709125895U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isRunning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rsi
  mov    $0x29,%edi
  call   <int80@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L6
  lea    D23(%rip),%rax
  jmp    L11
L6:
  lea    D10(%rip),%rax
L11:
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D23
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D21
datatype: string

tool: D23: No

tool: D10: Yes

tool: D21: %s


assistant: ```c
void isRunning(int cargs, void **pargs) {
  char *psName = (((char **)pargs)[1]);
  int ret;
  int80(41, psName, &ret, 0, 0, 0);
  printf("%s\n", ret == 0 ? "No" : "Yes");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isRunning>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    0x8(%rsi),%rsi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x29,%edi
  call   <int80@plt>
  cmpl   $0x0,0x4(%rsp)
  lea    D23(%rip),%rsi
  lea    D29(%rip),%rax
  cmovne %rax,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D23
type: string
name: unpack_data
arguments: data_label: D29
type: string
name: unpack_data
arguments: data_label: D19
type: string

tool: D23: No

tool: D29: Yes

tool: D19: %s


assistant: ```c
void isRunning(int cargs, void **pargs) {
  char *psName = (((char **)pargs)[1]);
  int ret;
  int80(41, psName, &ret, 0, 0, 0);
  printf("%s\n", ret == 0 ? "No" : "Yes");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isRunning>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rsi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %ecx,%ecx
  mov    $0x29,%edi
  lea    0x4(%rsp),%rdx
  call   <int80@plt>
  mov    0x4(%rsp),%eax
  lea    D4(%rip),%rsi
  lea    D18(%rip),%rdi
  test   %eax,%eax
  lea    D2(%rip),%rax
  cmovne %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D2
data_type: string

tool: D4: No

tool: D18: %s


tool: D2: Yes

assistant: ```c
void isRunning(int cargs, void **pargs) {
  char *psName = (((char **)pargs)[1]);
  int ret;
  int80(41, psName, &ret, 0, 0, 0);
  printf("%s\n", ret == 0 ? "No" : "Yes");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isRunning>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rsi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %ecx,%ecx
  mov    $0x29,%edi
  lea    0x4(%rsp),%rdx
  call   <int80@plt>
  mov    0x4(%rsp),%eax
  lea    D16(%rip),%rsi
  lea    D18(%rip),%rdi
  test   %eax,%eax
  lea    D8(%rip),%rax
  cmovne %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string

tool: D16: No

tool: D18: %s


tool: D8: Yes

assistant: ```c
void isRunning(int cargs, void **pargs) {
  char *psName = (((char **)pargs)[1]);
  int ret;
  int80(41, psName, &ret, 0, 0, 0);
  printf("%s\n", ret == 0 ? "No" : "Yes");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: What is 1 divided by 0?


assistant: ```c
void fun0() {
  char buf0[100];
  printf("What is 1 divided by 0?\n");
  gets(buf0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fun0>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: What is 1 divided by 0?


assistant: ```c
void fun0() {
  char buf0[100];
  printf("What is 1 divided by 0?\n");
  gets(buf0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun0>:
  endbr64
  sub    $0x78,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: What is 1 divided by 0?


assistant: ```c
void fun0() {
  char buf0[100];
  printf("What is 1 divided by 0?\n");
  gets(buf0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fun0>:
  endbr64
  sub    $0x78,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x78,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: What is 1 divided by 0?


assistant: ```c
void fun0() {
  char buf0[100];
  printf("What is 1 divided by 0?\n");
  gets(buf0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qstrtrim_tail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L76
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L36:
  subl   $0x1,-0x4(%rbp)
L27:
  cmpl   $0x0,-0x4(%rbp)
  js     L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L36
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L36
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L36
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L36
L33:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L76:
  leave
  ret
```

assistant: ```c
char *qstrtrim_tail(char *str) {
  int i;
  if (str == NULL)
    return NULL;
  for (i = strlen(str) - 1; (i >= 0) && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'); i--)
    ;
  str[i + 1] = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qstrtrim_tail>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L22
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L14
  movslq %eax,%rdx
  add    %rbx,%rdx
  movabs $0x100002600,%rsi
  jmp    L12
L45:
  bt     %rcx,%rsi
  jae    L14
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L14
L12:
  movzbl (%rdx),%ecx
  cmp    $0x20,%cl
  jbe    L45
L14:
  cltq
  movb   $0x0,0x1(%rbx,%rax,1)
L22:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *qstrtrim_tail(char *str) {
  int i;
  if (str == NULL)
    return NULL;
  for (i = strlen(str) - 1; (i >= 0) && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'); i--)
    ;
  str[i + 1] = '\0';
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qstrtrim_tail>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L57
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L62
  movabs $0xfffffffeffffd9ff,%rdi
  movslq %edx,%rax
  add    %r12,%rax
  nopw   0x0(%rax,%rax,1)
L66:
  movzbl (%rax),%ecx
  mov    %rax,%rsi
  cmp    $0x20,%cl
  jbe    L5
L45:
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    (%r12,%rdx,1),%rsi
L37:
  movb   $0x0,(%rsi)
L57:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L5:
  bt     %rcx,%rdi
  jb     L45
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  jne    L66
  jmp    L37
L62:
  cltq
  lea    (%r12,%rax,1),%rsi
  jmp    L37
```

assistant: ```c
char *qstrtrim_tail(char *str) {
  int i;
  if (str == NULL)
    return NULL;
  for (i = strlen(str) - 1; (i >= 0) && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'); i--)
    ;
  str[i + 1] = '\0';
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<qstrtrim_tail>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L52
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L13
  movabs $0xfffffffeffffd9ff,%rdi
  movslq %edx,%rax
  add    %r12,%rax
  nopw   0x0(%rax,%rax,1)
L37:
  movzbl (%rax),%ecx
  mov    %rax,%rsi
  cmp    $0x20,%cl
  jbe    L6
L26:
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    (%r12,%rdx,1),%rsi
L64:
  movb   $0x0,(%rsi)
L52:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L6:
  bt     %rcx,%rdi
  jb     L26
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  jne    L37
  jmp    L64
L13:
  cltq
  lea    (%r12,%rax,1),%rsi
  jmp    L64
```

assistant: ```c
char *qstrtrim_tail(char *str) {
  int i;
  if (str == NULL)
    return NULL;
  for (i = strlen(str) - 1; (i >= 0) && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'); i--)
    ;
  str[i + 1] = '\0';
  return str;
}
```