ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sizecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L12
  mov    $0x1,%eax
  jmp    L6
L12:
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L4
  mov    $0xffffffff,%eax
  jmp    L6
L4:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <strcmp@plt>
L6:
  leave
  ret
```

assistant: ```c
int sizecmp(const FTSENT *p1, const FTSENT *p2) {
  if (p2->fts_statp->st_size > p1->fts_statp->st_size)
    return (1);
  else if (p2->fts_statp->st_size < p1->fts_statp->st_size)
    return (-1);
  else
    return (strcmp(p1->fts_name, p2->fts_name));
}
```
user: Translate the below assembly code into C programming language:

```asm
<sizecmp>:
  endbr64
  mov    0x8(%rsi),%rax
  mov    (%rax),%rcx
  mov    0x8(%rdi),%rax
  mov    (%rax),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L15
  jl     L3
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
L15:
  ret
```

assistant: ```c
int sizecmp(const FTSENT *p1, const FTSENT *p2) {
  if (p2->fts_statp->st_size > p1->fts_statp->st_size)
    return (1);
  else if (p2->fts_statp->st_size < p1->fts_statp->st_size)
    return (-1);
  else
    return (strcmp(p1->fts_name, p2->fts_name));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sizecmp>:
  endbr64
  mov    0x8(%rdi),%rax
  mov    0x8(%rsi),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jg     L15
  jl     L4
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  jmp    1050 <strcmp@plt>
  nop
L15:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sizecmp(const FTSENT *p1, const FTSENT *p2) {
  if (p2->fts_statp->st_size > p1->fts_statp->st_size)
    return (1);
  else if (p2->fts_statp->st_size < p1->fts_statp->st_size)
    return (-1);
  else
    return (strcmp(p1->fts_name, p2->fts_name));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sizecmp>:
  endbr64
  mov    0x8(%rdi),%rax
  mov    0x8(%rsi),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jg     L8
  jl     L0
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  jmp    1050 <strcmp@plt>
  nop
L8:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sizecmp(const FTSENT *p1, const FTSENT *p2) {
  if (p2->fts_statp->st_size > p1->fts_statp->st_size)
    return (1);
  else if (p2->fts_statp->st_size < p1->fts_statp->st_size)
    return (-1);
  else
    return (strcmp(p1->fts_name, p2->fts_name));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_numeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L23
  mov    $0x0,%eax
  jmp    L20
L23:
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L41
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L58
L41:
  mov    $0x0,%eax
  jmp    L20
L58:
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L7
  mov    $0x1,%eax
L20:
  leave
  ret
```

assistant: ```c
int is_numeric(char *str) {
  int i;
  if (strlen(str) == 0)
    return 0;
  for (i = 0; i < strlen(str); i++) {
    if ((str[i] < '0') || (str[i] > '9'))
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_numeric>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L34
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L20
  movzbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x30,%eax
  add    $0x1,%rbx
  cmp    $0x9,%al
  jbe    L12
  mov    $0x0,%eax
  jmp    L34
L20:
  mov    $0x1,%eax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_numeric(char *str) {
  int i;
  if (strlen(str) == 0)
    return 0;
  for (i = 0; i < strlen(str); i++) {
    if ((str[i] < '0') || (str[i] > '9'))
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_numeric>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jne    L18
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L15
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_numeric(char *str) {
  int i;
  if (strlen(str) == 0)
    return 0;
  for (i = 0; i < strlen(str); i++) {
    if ((str[i] < '0') || (str[i] > '9'))
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_numeric>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jne    L33
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L15
L33:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L8
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_numeric(char *str) {
  int i;
  if (strlen(str) == 0)
    return 0;
  for (i = 0; i < strlen(str); i++) {
    if ((str[i] < '0') || (str[i] > '9'))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dunno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: I don't know about that


assistant: ```c
void dunno(void) {
  printf("I don't know about that\n");
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dunno>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: I don't know about that


assistant: ```c
void dunno(void) {
  printf("I don't know about that\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dunno>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: I don't know about that


assistant: ```c
void dunno(void) {
  printf("I don't know about that\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dunno>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: I don't know about that


assistant: ```c
void dunno(void) {
  printf("I don't know about that\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x2,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <move@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int n = 3;
  move(n, 1, 3, 2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <move@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = 3;
  move(n, 1, 3, 2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <move@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = 3;
  move(n, 1, 3, 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <move@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = 3;
  move(n, 1, 3, 2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hweight_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L18:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  add    %rax,-0x8(%rbp)
  shrq   -0x18(%rbp)
L5:
  cmpq   $0x0,-0x18(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hweight_long(unsigned long w) {
  unsigned long count;
  for (count = 0; w; w >>= 1) {
    count += w & 1;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hweight_long>:
  endbr64
  test   %rdi,%rdi
  je     L17
  mov    $0x0,%eax
L6:
  mov    %rdi,%rdx
  and    $0x1,%edx
  add    %rdx,%rax
  shr    %rdi
  jne    L6
  ret
L17:
  mov    %rdi,%rax
  ret
```

assistant: ```c
unsigned long hweight_long(unsigned long w) {
  unsigned long count;
  for (count = 0; w; w >>= 1) {
    count += w & 1;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hweight_long>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L12
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rdi,%rdx
  and    $0x1,%edx
  add    %rdx,%rax
  shr    %rdi
  jne    L4
  ret
  nop
L12:
  ret
```

assistant: ```c
unsigned long hweight_long(unsigned long w) {
  unsigned long count;
  for (count = 0; w; w >>= 1) {
    count += w & 1;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hweight_long>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rdi,%rdx
  and    $0x1,%edx
  add    %rdx,%rax
  shr    %rdi
  jne    L4
  ret
  nop
L10:
  ret
```

assistant: ```c
unsigned long hweight_long(unsigned long w) {
  unsigned long count;
  for (count = 0; w; w >>= 1) {
    count += w & 1;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L24
L23:
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x10(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  cmpq   $0x0,-0x10(%rbp)
  jne    L23
L34:
  cmpq   $0x0,-0x10(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L49
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
L49:
  pop    %rbp
  ret
```

assistant: ```c
const char *get_string(char **msgbuf, size_t *msglen) {
  char *cp = *msgbuf, *ret = *msgbuf;
  size_t len = *msglen;
  while (*cp && len) {
    cp++;
    len--;
  }
  if (!len)
    return NULL;
  *msgbuf = cp + 1;
  *msglen = len - 1;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_string>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rax
  cmpb   $0x0,(%rcx)
  je     L69
  test   %rax,%rax
  je     L69
  mov    %rcx,%rdx
L10:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmpb   $0x0,(%rdx)
  je     L8
  test   %rax,%rax
  jne    L10
L8:
  test   %rax,%rax
  je     L13
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  sub    $0x1,%rax
  mov    %rax,(%rsi)
L67:
  mov    %rcx,%rax
  ret
L69:
  mov    %rcx,%rdx
  jmp    L8
L13:
  mov    $0x0,%ecx
  jmp    L67
```

assistant: ```c
const char *get_string(char **msgbuf, size_t *msglen) {
  char *cp = *msgbuf, *ret = *msgbuf;
  size_t len = *msglen;
  while (*cp && len) {
    cp++;
    len--;
  }
  if (!len)
    return NULL;
  *msgbuf = cp + 1;
  *msglen = len - 1;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_string>:
  endbr64
  mov    (%rdi),%r8
  mov    (%rsi),%rax
  cmpb   $0x0,(%r8)
  je     L5
  test   %rax,%rax
  je     L57
  mov    %r8,%rdx
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L17:
  test   %rax,%rax
  je     L57
L46:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmpb   $0x0,(%rdx)
  jne    L17
L32:
  test   %rax,%rax
  je     L57
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L57:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L5:
  mov    %r8,%rdx
  jmp    L32
```

assistant: ```c
const char *get_string(char **msgbuf, size_t *msglen) {
  char *cp = *msgbuf, *ret = *msgbuf;
  size_t len = *msglen;
  while (*cp && len) {
    cp++;
    len--;
  }
  if (!len)
    return NULL;
  *msgbuf = cp + 1;
  *msglen = len - 1;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_string>:
  endbr64
  mov    (%rdi),%r8
  mov    (%rsi),%rax
  cmpb   $0x0,(%r8)
  je     L12
  test   %rax,%rax
  je     L48
  mov    %r8,%rdx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L57:
  test   %rax,%rax
  je     L48
L62:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmpb   $0x0,(%rdx)
  jne    L57
L7:
  test   %rax,%rax
  je     L48
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L48:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L12:
  mov    %r8,%rdx
  jmp    L7
```

assistant: ```c
const char *get_string(char **msgbuf, size_t *msglen) {
  char *cp = *msgbuf, *ret = *msgbuf;
  size_t len = *msglen;
  while (*cp && len) {
    cp++;
    len--;
  }
  if (!len)
    return NULL;
  *msgbuf = cp + 1;
  *msglen = len - 1;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<higher_prime_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L34
L15:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x3,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L39
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L34
L39:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L15
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_guessed: string

tool: D16: 

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: Translate the below assembly code into C programming language:

```asm
<higher_prime_number>:
  endbr64
  lea    D9(%rip),%rcx
  lea    -0xf0(%rcx),%rdx
L2:
  cmp    %rdx,%rcx
  je     L19
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  sar    $0x3,%rsi
  shr    $0x3f,%rax
  add    %rsi,%rax
  sar    %rax
  lea    (%rdx,%rax,8),%rax
  cmp    %rdi,(%rax)
  jb     L27
  mov    %rax,%rcx
  jmp    L2
L27:
  lea    0x8(%rax),%rdx
  jmp    L2
L19:
  mov    (%rdx),%rax
  ret
```

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<higher_prime_number>:
  endbr64
  lea    D4(%rip),%rcx
  lea    -0xf0(%rcx),%rdx
  jmp    L19
  nopl   0x0(%rax)
L33:
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rax
  sar    $0x3,%rsi
  add    %rsi,%rax
  sar    %rax
  lea    (%rdx,%rax,8),%rax
  cmp    %rdi,(%rax)
  jb     L10
  mov    %rax,%rcx
L19:
  cmp    %rdx,%rcx
  jne    L33
  mov    (%rcx),%rax
  ret
  nopl   0x0(%rax)
L10:
  lea    0x8(%rax),%rdx
  jmp    L19
```

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<higher_prime_number>:
  endbr64
  lea    D0(%rip),%rcx
  lea    -0xf0(%rcx),%rdx
  jmp    L20
  nopl   0x0(%rax)
L24:
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rax
  sar    $0x3,%rsi
  add    %rsi,%rax
  sar    %rax
  lea    (%rdx,%rax,8),%rax
  cmp    %rdi,(%rax)
  jb     L14
  mov    %rax,%rcx
L20:
  cmp    %rdx,%rcx
  jne    L24
  mov    (%rcx),%rax
  ret
  nopl   0x0(%rax)
L14:
  lea    0x8(%rax),%rdx
  jmp    L20
```

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: What is the c source code of the assembly code below?

```asm
<skip_lws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,-0x18(%rbp)
L62:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L64
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L54
  addq   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L39
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L64
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  nop
  jmp    L62
L64:
  nop
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string

tool: D8:  	

tool: D0: 


assistant: ```c
char *skip_lws(char *str) {
  str += strspn(str, " \t");
  for (;;) {
    if (*str && strchr("\r\n", *str)) {
      char *p = str;
      if (*p == '\r')
        p++;
      if (*p == '\n')
        p++;
      if (*p && strchr(" \t", *p)) {
        str = p + strspn(p, " \t");
        continue;
      }
    }
    break;
  }
  return str;
}
```