user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x2,-0x44(%rbp)
  jne    L0
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D118(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L66
L36:
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L66:
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x34(%rbp)
  jl     L36
  cmpl   $0x4f4,-0x38(%rbp)
  jne    L34
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D109(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L26
L34:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L56
L0:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L56:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D77
type: string
name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D56
type: string
name: parse_data
arguments: label: D74
type: string
name: parse_data
arguments: label: D118
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D52
type: string
name: parse_data
arguments: label: D83
type: string
name: parse_data
arguments: label: D109
type: string
name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D29
type: string
name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D90
type: string

tool: D77: Welcome to the iOS Reverse Engineering Level 3! 

tool: D13: Created by GeoSn0w (@FCE365)


tool: D56: The challenge is to hack this application so that you can use it without any serial number and obtain the flag! 


tool: D74: **************** START **************** 


tool: D118: Preparing to check access key: %s


tool: D9: Welcome! F.C.E. 365 Tool v36.1

tool: D52: Blimey! You're not a good man! You've hacked the app!
 

tool: D83: Flag: 0x038948FFFF83--DS 

tool: D109: System Identity:

tool: D0: %s Release %s (Version %s) on %s


tool: D8: The serial number is not correct!

tool: D29: The application is locked!

tool: D6: This application requires a serial number to work! You can validate it with <key>

tool: D90: Or you can do what hackers do the best...

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Welcome to the iOS Reverse Engineering Level 3! \n");
  printf("Created by GeoSn0w (@FCE365)\n\n");
  printf("The challenge is to hack this application so that you can use it without any serial number and obtain the flag! \n\n");
  printf("**************** START **************** \n\n");
  if (argc == 2) {
    printf("Preparing to check access key: %s\n", argv[1]);
    int hex = 0;
    for (int access = 0; access < strlen(argv[1]); access++) {
      hex += (int)argv[1][access];
    }
    if (hex == 1268) {
      printf("Welcome! F.C.E. 365 Tool v36.1\n");
      printf("\n");
      printf("Blimey! You're not a good man! You've hacked the app!\n \n");
      printf("Flag: 0x038948FFFF83--DS \n");
      printf("System Identity:\n");
      struct utsname u;
      uname(&u);
      printf("%s Release %s (Version %s) on %s\n", u.sysname, u.release, u.version, u.machine);
      return 0;
    } else {
      printf("The serial number is not correct!\n");
      printf("The application is locked!\n");
    }
  } else {
    printf("This application requires a serial number to work! You can validate it with <key>\n");
    printf("Or you can do what hackers do the best...\n");
  }
  return 0;
}
```