ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<portout16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <portout@plt>
  mov    %ebp,%esi
  sar    $0x8,%esi
  lea    0x1(%rbx),%edi
  call   <portout@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void portout16(uint16_t portnum, uint16_t value) {
  portout(portnum, (uint8_t)value);
  portout(portnum + 1, (uint8_t)(value >> 8));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<portout16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <portout@plt>
  mov    %ebp,%esi
  add    $0x8,%rsp
  lea    0x1(%rbx),%edi
  sar    $0x8,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <portout@plt>
```

assistant: ```c
void portout16(uint16_t portnum, uint16_t value) {
  portout(portnum, (uint8_t)value);
  portout(portnum + 1, (uint8_t)(value >> 8));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<portout16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <portout@plt>
  mov    %ebp,%esi
  add    $0x8,%rsp
  lea    0x1(%rbx),%edi
  sar    $0x8,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <portout@plt>
```

assistant: ```c
void portout16(uint16_t portnum, uint16_t value) {
  portout(portnum, (uint8_t)value);
  portout(portnum + 1, (uint8_t)(value >> 8));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    $0x7,%edi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  lea    0x7(%rax),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    0x7(%rdx),%r8d
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  add    $0x7,%eax
  mov    %edx,0x4(%rsp)
  movslq %r8d,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %r8d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  sub    %r9d,%r8d
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D16: Enter a four-digit integer number:

tool: D28: %d

tool: D14: The encrypted number is :%d%d%d%d

assistant: ```c
int main() {
  int counter, number, digit = 0;
  int first_digit, second_digit, third_digit, fourth_digit;
  printf("Enter a four-digit integer number:");
  scanf("%d", &number);
  for (counter = 0; counter < 4; counter++) {
    digit = number % 10;
    number = number / 10;
    digit = (digit + 7) % 10;
    switch (counter) {
    case 0:
      third_digit = digit;
      break;
    case 1:
      fourth_digit = digit;
      break;
    case 2:
      first_digit = digit;
      break;
    case 3:
      second_digit = digit;
    }
  }
  printf("The encrypted number is :%d%d%d%d", fourth_digit, third_digit, second_digit, first_digit);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdi
  imul   $0x66666667,%rax,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  add    %edx,%edx
  sar    $0x1f,%ecx
  sub    %edx,%edi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  add    $0x7,%edi
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %edx,%ecx
  lea    0x7(%rax),%esi
  movslq %edx,%rax
  sar    $0x1f,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  mov    %eax,%ecx
  lea    0x7(%rdx),%r8d
  movslq %eax,%rdx
  sar    $0x1f,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  mov    %r8d,%ecx
  mov    %edx,0x4(%rsp)
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  movslq %r8d,%rdx
  imul   $0x66666667,%rdx,%rdx
  add    $0x7,%eax
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %eax,%ecx
  lea    (%rdx,%rdx,4),%r9d
  movslq %eax,%rdx
  sar    $0x1f,%ecx
  imul   $0x66666667,%rdx,%rdx
  add    %r9d,%r9d
  sub    %r9d,%r8d
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %edi,%edx
  mov    %eax,%ecx
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  mov    %edi,%edx
  mov    %esi,%edi
  sar    $0x1f,%edi
  sar    $0x22,%rax
  sub    %edi,%eax
  lea    D21(%rip),%rdi
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D21
type: string

tool: D5: Enter a four-digit integer number:

tool: D11: %d

tool: D21: The encrypted number is :%d%d%d%d

assistant: ```c
int main() {
  int counter, number, digit = 0;
  int first_digit, second_digit, third_digit, fourth_digit;
  printf("Enter a four-digit integer number:");
  scanf("%d", &number);
  for (counter = 0; counter < 4; counter++) {
    digit = number % 10;
    number = number / 10;
    digit = (digit + 7) % 10;
    switch (counter) {
    case 0:
      third_digit = digit;
      break;
    case 1:
      fourth_digit = digit;
      break;
    case 2:
      first_digit = digit;
      break;
    case 3:
      second_digit = digit;
    }
  }
  printf("The encrypted number is :%d%d%d%d", fourth_digit, third_digit, second_digit, first_digit);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<WDT_GetPeriod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L12
  cmpl   $0x3e80,-0x4(%rbp)
  jle    L5
L12:
  mov    $0x0,%eax
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
extern uint32_t WDT_GetPeriod(uint32_t dwMs) {
  if ((dwMs < 4) || (dwMs > 16000)) {
    return 0;
  }
  return ((dwMs << 8) / 1000);
}
```
user: What is the c source code of the assembly code below:

```asm
<WDT_GetPeriod>:
  endbr64
  lea    -0x4(%rdi),%edx
  mov    $0x0,%eax
  cmp    $0x3e7c,%edx
  ja     L6
  shl    $0x8,%edi
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
L6:
  ret
```

assistant: ```c
extern uint32_t WDT_GetPeriod(uint32_t dwMs) {
  if ((dwMs < 4) || (dwMs > 16000)) {
    return 0;
  }
  return ((dwMs << 8) / 1000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<WDT_GetPeriod>:
  endbr64
  lea    -0x4(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x3e7c,%edx
  ja     L1
  shl    $0x8,%edi
  imul   $0x10624dd3,%rdi,%rax
  shr    $0x26,%rax
L1:
  ret
```

assistant: ```c
extern uint32_t WDT_GetPeriod(uint32_t dwMs) {
  if ((dwMs < 4) || (dwMs > 16000)) {
    return 0;
  }
  return ((dwMs << 8) / 1000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<WDT_GetPeriod>:
  endbr64
  lea    -0x4(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x3e7c,%edx
  ja     L8
  shl    $0x8,%edi
  imul   $0x10624dd3,%rdi,%rax
  shr    $0x26,%rax
L8:
  ret
```

assistant: ```c
extern uint32_t WDT_GetPeriod(uint32_t dwMs) {
  if ((dwMs < 4) || (dwMs > 16000)) {
    return 0;
  }
  return ((dwMs << 8) / 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L18
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D30(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L43
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L18
L43:
  mov    $0x0,%eax
  jmp    L49
L18:
  mov    $0x1,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
extern int file_exists(char *path) {
  int st;
  struct stat sbuf;
  st = stat(path, &sbuf);
  if (st == -1 && (errno == ENOENT || errno == ENOTDIR))
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0xffffffff,%edx
  jne    L5
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    $0x0,%eax
  mov    D9(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L5
  mov    D17(%rip),%rax
  cmp    %rdx,(%rax)
  setne  %al
  movzbl %al,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int file_exists(char *path) {
  int st;
  struct stat sbuf;
  st = stat(path, &sbuf);
  if (st == -1 && (errno == ENOENT || errno == ENOTDIR))
    return 0;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0xffffffff,%r8d
  jne    L15
  mov    D3(%rip),%rax
  mov    D15(%rip),%rcx
  mov    (%rax),%rdx
  xor    %eax,%eax
  cmp    (%rcx),%rdx
  je     L15
  mov    D23(%rip),%rax
  cmp    %rdx,(%rax)
  setne  %al
  movzbl %al,%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int file_exists(char *path) {
  int st;
  struct stat sbuf;
  st = stat(path, &sbuf);
  if (st == -1 && (errno == ENOENT || errno == ENOTDIR))
    return 0;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0xffffffff,%r8d
  jne    L19
  mov    D22(%rip),%rax
  mov    D10(%rip),%rcx
  mov    (%rax),%rdx
  xor    %eax,%eax
  cmp    (%rcx),%rdx
  je     L19
  mov    D15(%rip),%rax
  cmp    %rdx,(%rax)
  setne  %al
  movzbl %al,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int file_exists(char *path) {
  int st;
  struct stat sbuf;
  st = stat(path, &sbuf);
  if (st == -1 && (errno == ENOENT || errno == ENOTDIR))
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dMonodip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm3
  mulsd  -0x28(%rbp),%xmm3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  addsd  -0x38(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dMonodip(double sys[], double x[], double K, double Kt, double KMonod, double xMonod[], int NumCel) {
  int i;
  for (i = 0; i < NumCel; i++) {
    sys[i] = sys[i] + K * (x[i] - Kt) * (xMonod[i] / (KMonod + xMonod[i]));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dMonodip>:
  endbr64
  test   %ecx,%ecx
  jle    L12
  mov    %ecx,%ecx
  mov    $0x0,%eax
L8:
  movsd  (%rdx,%rax,8),%xmm4
  movsd  (%rsi,%rax,8),%xmm3
  subsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  movapd %xmm4,%xmm5
  addsd  %xmm2,%xmm5
  divsd  %xmm5,%xmm4
  mulsd  %xmm4,%xmm3
  addsd  (%rdi,%rax,8),%xmm3
  movsd  %xmm3,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L8
L12:
  ret
```

assistant: ```c
void dMonodip(double sys[], double x[], double K, double Kt, double KMonod, double xMonod[], int NumCel) {
  int i;
  for (i = 0; i < NumCel; i++) {
    sys[i] = sys[i] + K * (x[i] - Kt) * (xMonod[i] / (KMonod + xMonod[i]));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dMonodip>:
  endbr64
  test   %ecx,%ecx
  jle    L7
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L19:
  movsd  (%rdx,%rax,8),%xmm4
  movsd  (%rsi,%rax,8),%xmm3
  movapd %xmm4,%xmm5
  subsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm5
  mulsd  %xmm0,%xmm3
  divsd  %xmm5,%xmm4
  mulsd  %xmm4,%xmm3
  addsd  (%rdi,%rax,8),%xmm3
  movsd  %xmm3,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L19
L7:
  ret
```

assistant: ```c
void dMonodip(double sys[], double x[], double K, double Kt, double KMonod, double xMonod[], int NumCel) {
  int i;
  for (i = 0; i < NumCel; i++) {
    sys[i] = sys[i] + K * (x[i] - Kt) * (xMonod[i] / (KMonod + xMonod[i]));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dMonodip>:
  endbr64
  movapd %xmm0,%xmm4
  test   %ecx,%ecx
  jle    L50
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %r8b
  cmp    %rax,%rdi
  setne  %al
  test   %al,%r8b
  je     L30
  cmp    $0x1,%ecx
  je     L30
  mov    %ecx,%r8d
  movapd %xmm1,%xmm8
  movapd %xmm0,%xmm7
  xor    %eax,%eax
  movapd %xmm2,%xmm6
  shr    %r8d
  unpcklpd %xmm8,%xmm8
  unpcklpd %xmm7,%xmm7
  unpcklpd %xmm6,%xmm6
  shl    $0x4,%r8
  nopl   (%rax)
L46:
  movupd (%rdx,%rax,1),%xmm5
  movupd (%rdx,%rax,1),%xmm3
  movupd (%rsi,%rax,1),%xmm0
  addpd  %xmm6,%xmm5
  subpd  %xmm8,%xmm0
  divpd  %xmm5,%xmm3
  movupd (%rdi,%rax,1),%xmm5
  mulpd  %xmm7,%xmm0
  mulpd  %xmm3,%xmm0
  addpd  %xmm5,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L46
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L50
  movsd  (%rdx,%rax,8),%xmm3
  movsd  (%rsi,%rax,8),%xmm0
  lea    (%rdi,%rax,8),%rcx
  addsd  %xmm3,%xmm2
  subsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm3
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  ret
  nop
L30:
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L39:
  movsd  (%rdx,%rax,8),%xmm3
  movapd %xmm2,%xmm5
  movsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm3,%xmm5
  subsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm3
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L39
L50:
  ret
```

assistant: ```c
void dMonodip(double sys[], double x[], double K, double Kt, double KMonod, double xMonod[], int NumCel) {
  int i;
  for (i = 0; i < NumCel; i++) {
    sys[i] = sys[i] + K * (x[i] - Kt) * (xMonod[i] / (KMonod + xMonod[i]));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<psd_freeif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <psd_free@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL)
    psd_free(block);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<psd_freeif>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <psd_free@plt>
  add    $0x8,%rsp
  ret
L9:
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL)
    psd_free(block);
}
```
user: What is the c source code of the assembly code below:

```asm
<psd_freeif>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <psd_free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL)
    psd_free(block);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<psd_freeif>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <psd_free@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL)
    psd_free(block);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readint16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  shll   $0x8,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t readint16(const uint8_t *c) {
  uint16_t total = c[1];
  total *= 0x100;
  total += c[0];
  return total;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readint16>:
  endbr64
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  ret
```

assistant: ```c
uint16_t readint16(const uint8_t *c) {
  uint16_t total = c[1];
  total *= 0x100;
  total += c[0];
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readint16>:
  endbr64
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  ret
```

assistant: ```c
uint16_t readint16(const uint8_t *c) {
  uint16_t total = c[1];
  total *= 0x100;
  total += c[0];
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readint16>:
  endbr64
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  ret
```

assistant: ```c
uint16_t readint16(const uint8_t *c) {
  uint16_t total = c[1];
  total *= 0x100;
  total += c[0];
  return total;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strbequ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  cmpq   $0x0,-0x10(%rbp)
  jne    L48
L38:
  mov    $0x0,%eax
  jmp    L70
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L75
  mov    $0x0,%eax
  jmp    L70
L75:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L48:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L79:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
  mov    $0x1,%eax
  jmp    L70
L72:
  mov    $0x0,%eax
L70:
  pop    %rbp
  ret
```

assistant: ```c
int strbequ(const char *s1, const char *s2) {
  if (!s1 || !s2)
    return (0);
  for (; *s1 && *s2; s1++, s2++)
    if (*s1 != *s2)
      return (0);
  if (!*s2)
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strbequ>:
  endbr64
  test   %rdi,%rdi
  je     L21
  test   %rsi,%rsi
  je     L21
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L7:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L3
  cmp    %al,%dl
  jne    L33
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L3:
  cmpb   $0x0,(%rsi)
  sete   %al
  movzbl %al,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
L33:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strbequ(const char *s1, const char *s2) {
  if (!s1 || !s2)
    return (0);
  for (; *s1 && *s2; s1++, s2++)
    if (*s1 != *s2)
      return (0);
  if (!*s2)
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strbequ>:
  endbr64
  test   %rdi,%rdi
  je     L11
  test   %rsi,%rsi
  je     L11
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L29
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L3:
  cmp    %dl,%al
  jne    L11
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  lea    0x1(%rsi),%rax
  test   %dl,%dl
  je     L19
  mov    %rax,%rsi
L29:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L3
L7:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L10:
  movzbl (%rsi),%eax
  jmp    L7
```

assistant: ```c
int strbequ(const char *s1, const char *s2) {
  if (!s1 || !s2)
    return (0);
  for (; *s1 && *s2; s1++, s2++)
    if (*s1 != *s2)
      return (0);
  if (!*s2)
    return (1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strbequ>:
  endbr64
  test   %rdi,%rdi
  je     L30
  test   %rsi,%rsi
  je     L30
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L4
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L11:
  cmp    %dl,%al
  jne    L30
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  lea    0x1(%rsi),%rax
  test   %dl,%dl
  je     L31
  mov    %rax,%rsi
L4:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L11
L53:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L44:
  movzbl (%rsi),%eax
  jmp    L53
```

assistant: ```c
int strbequ(const char *s1, const char *s2) {
  if (!s1 || !s2)
    return (0);
  for (; *s1 && *s2; s1++, s2++)
    if (*s1 != *s2)
      return (0);
  if (!*s2)
    return (1);
  return (0);
}
```