ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xc,(%rsp)
  movl   $0x22,0x4(%rsp)
  movl   $0x36,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <shellsort@plt>
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%r12
  lea    D14(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string

tool: D6: 
 Sorted array is: 

tool: D14: %d 

assistant: ```c
int main() {
  int arr[] = {12, 34, 54, 2, 3}, i;
  int n = sizeof(arr) / sizeof(arr[0]);
  shellsort(arr, n);
  printf("\n Sorted array is: ");
  for (i = 0; i < n; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x220000000c,%rax
  mov    %rsp,%rbx
  movl   $0x3,0x10(%rsp)
  lea    0x14(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x200000036,%rax
  mov    %rax,0x8(%rsp)
  call   <shellsort@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string

tool: D16: %d 

tool: D17: 
 Sorted array is: 

assistant: ```c
int main() {
  int arr[] = {12, 34, 54, 2, 3}, i;
  int n = sizeof(arr) / sizeof(arr[0]);
  shellsort(arr, n);
  printf("\n Sorted array is: ");
  for (i = 0; i < n; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movl   $0x3,0x10(%rsp)
  lea    0x14(%rsp),%r12
  mov    %rbx,%rdi
  movaps %xmm0,(%rsp)
  call   <shellsort@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D0
type: byte[16]
name: parse_data
arguments: data_label: D17
type: string

tool: D20: %d 

tool: {"D0": [0x0c,0x00,0x00,0x00,0x22,0x00,0x00,0x00,0x36,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D17: 
 Sorted array is: 

assistant: ```c
int main() {
  int arr[] = {12, 34, 54, 2, 3}, i;
  int n = sizeof(arr) / sizeof(arr[0]);
  shellsort(arr, n);
  printf("\n Sorted array is: ");
  for (i = 0; i < n; i++)
    printf("%d ", arr[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_seq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D14
datatype: string

tool: D0: len = %d 


tool: D14: %d 

assistant: ```c
void print_seq(int seq[], int len) {
  printf("len = %d \n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", seq[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_seq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L17
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D7(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D14: len = %d 


tool: D7: %d 

assistant: ```c
void print_seq(int seq[], int len) {
  printf("len = %d \n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", seq[i]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_seq>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D16(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L7
  lea    -0x1(%rbp),%eax
  lea    D13(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  xchg   %ax,%ax
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
L7:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string

tool: D16: len = %d 


tool: D13: %d 

assistant: ```c
void print_seq(int seq[], int len) {
  printf("len = %d \n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", seq[i]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_seq>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L16
  lea    -0x1(%rbp),%eax
  lea    D15(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  xchg   %ax,%ax
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
L16:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string

tool: D13: len = %d 


tool: D15: %d 

assistant: ```c
void print_seq(int seq[], int len) {
  printf("len = %d \n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", seq[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L17:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mark_process_status@plt>
  test   %eax,%eax
  je     L17
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void update_status(void) {
  int status;
  pid_t pid;
  do
    pid = waitpid(WAIT_ANY, &status, WUNTRACED | WNOHANG);
  while (!mark_process_status(pid, status));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<update_status>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D21(%rip),%rbx
L6:
  mov    (%rbx),%edx
  mov    D16(%rip),%rax
  or     (%rax),%edx
  lea    0x4(%rsp),%rsi
  mov    D28(%rip),%rax
  mov    (%rax),%edi
  call   <waitpid@plt>
  mov    %eax,%edi
  mov    0x4(%rsp),%esi
  call   <mark_process_status@plt>
  test   %eax,%eax
  je     L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void update_status(void) {
  int status;
  pid_t pid;
  do
    pid = waitpid(WAIT_ANY, &status, WUNTRACED | WNOHANG);
  while (!mark_process_status(pid, status));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<update_status>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D6(%rip),%r13
  mov    D29(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rbx
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%edi
  mov    0x0(%r13),%edx
  mov    %rbp,%rsi
  or     (%r12),%edx
  call   <waitpid@plt>
  mov    0x4(%rsp),%esi
  mov    %eax,%edi
  call   <mark_process_status@plt>
  test   %eax,%eax
  je     L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void update_status(void) {
  int status;
  pid_t pid;
  do
    pid = waitpid(WAIT_ANY, &status, WUNTRACED | WNOHANG);
  while (!mark_process_status(pid, status));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<update_status>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D20(%rip),%r13
  mov    D28(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rbx
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%edi
  mov    0x0(%r13),%edx
  mov    %rbp,%rsi
  or     (%r12),%edx
  call   <waitpid@plt>
  mov    0x4(%rsp),%esi
  mov    %eax,%edi
  call   <mark_process_status@plt>
  test   %eax,%eax
  je     L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void update_status(void) {
  int status;
  pid_t pid;
  do
    pid = waitpid(WAIT_ANY, &status, WUNTRACED | WNOHANG);
  while (!mark_process_status(pid, status));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<util_timeval_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rsi
  mov    -0x20(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  lea    (%rsi,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x20(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3e8,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  imul   $0x3e8,%rax,%rax
  add    %rsi,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0xf4240,-0x8(%rbp)
  jle    L30
  mov    -0x8(%rbp),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4240,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  jmp    L38
L30:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L38
L6:
  nop
L38:
  pop    %rbp
  ret
```

assistant: ```c
void util_timeval_add(struct timeval *tv, long interval) {
  long usec;
  if (!tv)
    return;
  tv->tv_sec += (interval / 1000);
  usec = tv->tv_usec + ((interval % 1000) * 1000);
  if (usec > 1000000) {
    tv->tv_usec = usec % 1000000;
    tv->tv_sec++;
  } else
    tv->tv_usec = usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<util_timeval_add>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  je     L17
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rdi
  add    0x8(%rcx),%rdi
  mov    %rdi,0x8(%rcx)
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rsi
  imul   $0x3e8,%rsi,%rsi
  add    (%rcx),%rsi
  cmp    $0xf4240,%rsi
  jle    L5
  movabs $0x431bde82d7b634db,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rcx)
  add    $0x1,%rdi
  mov    %rdi,0x8(%rcx)
  ret
L5:
  mov    %rsi,(%rcx)
L17:
  ret
```

assistant: ```c
void util_timeval_add(struct timeval *tv, long interval) {
  long usec;
  if (!tv)
    return;
  tv->tv_sec += (interval / 1000);
  usec = tv->tv_usec + ((interval % 1000) * 1000);
  if (usec > 1000000) {
    tv->tv_usec = usec % 1000000;
    tv->tv_sec++;
  } else
    tv->tv_usec = usec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_timeval_add>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  je     L11
  mov    %rsi,%rax
  mov    0x8(%rdi),%rdi
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  add    %rdx,%rdi
  imul   $0x3e8,%rdx,%rdx
  mov    %rdi,0x8(%rcx)
  sub    %rdx,%rsi
  imul   $0x3e8,%rsi,%rsi
  add    (%rcx),%rsi
  cmp    $0xf4240,%rsi
  jle    L1
  mov    %rsi,%rax
  add    $0x1,%rdi
  movabs $0x431bde82d7b634db,%rdx
  imul   %rdx
  mov    %rsi,%rax
  mov    %rdi,0x8(%rcx)
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rsi,(%rcx)
L11:
  ret
```

assistant: ```c
void util_timeval_add(struct timeval *tv, long interval) {
  long usec;
  if (!tv)
    return;
  tv->tv_sec += (interval / 1000);
  usec = tv->tv_usec + ((interval % 1000) * 1000);
  if (usec > 1000000) {
    tv->tv_usec = usec % 1000000;
    tv->tv_sec++;
  } else
    tv->tv_usec = usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<util_timeval_add>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%rax
  mov    0x8(%rdi),%rdi
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  add    %rdx,%rdi
  imul   $0x3e8,%rdx,%rdx
  mov    %rdi,0x8(%rcx)
  sub    %rdx,%rsi
  imul   $0x3e8,%rsi,%rsi
  add    (%rcx),%rsi
  cmp    $0xf4240,%rsi
  jle    L7
  mov    %rsi,%rax
  add    $0x1,%rdi
  movabs $0x431bde82d7b634db,%rdx
  imul   %rdx
  mov    %rsi,%rax
  movq   %rdi,%xmm1
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  movq   %rsi,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rcx)
  ret
  nopl   0x0(%rax)
L7:
  mov    %rsi,(%rcx)
L18:
  ret
```

assistant: ```c
void util_timeval_add(struct timeval *tv, long interval) {
  long usec;
  if (!tv)
    return;
  tv->tv_sec += (interval / 1000);
  usec = tv->tv_usec + ((interval % 1000) * 1000);
  if (usec > 1000000) {
    tv->tv_usec = usec % 1000000;
    tv->tv_sec++;
  } else
    tv->tv_usec = usec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tokencmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  jmp    L14
L5:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
char tokencmp(char **pnt, char *token) {
  int n = strlen(token);
  if (!strncmp(*pnt, token, n)) {
    *pnt += n;
    return 1;
  } else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tokencmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    0x0(%rbp),%rdi
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L4
  movslq %ebx,%rbx
  add    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char tokencmp(char **pnt, char *token) {
  int n = strlen(token);
  if (!strncmp(*pnt, token, n)) {
    *pnt += n;
    return 1;
  } else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tokencmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <strncmp@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L6
  add    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char tokencmp(char **pnt, char *token) {
  int n = strlen(token);
  if (!strncmp(*pnt, token, n)) {
    *pnt += n;
    return 1;
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tokencmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <strncmp@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L1
  add    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char tokencmp(char **pnt, char *token) {
  int n = strlen(token);
  if (!strncmp(*pnt, token, n)) {
    *pnt += n;
    return 1;
  } else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shiftleft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x20(%rbp)
  mov    D47(%rip),%rax
  movzwl (%rax),%eax
  cmp    %ax,-0x20(%rbp)
  jb     L36
  mov    D47(%rip),%rax
  movzwl (%rax),%edi
  movzwl -0x20(%rbp),%eax
  mov    $0x0,%edx
  div    %di
  movzwl %ax,%eax
  sub    %eax,-0x1c(%rbp)
  mov    D47(%rip),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  lea    -0x1(%rax),%ecx
  mov    D47(%rip),%rax
  movzwl (%rax),%eax
  movzwl %ax,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%esi
  mov    D47(%rip),%rax
  movzwl (%rax),%edi
  movzwl -0x20(%rbp),%eax
  mov    $0x0,%edx
  div    %di
  movzwl %ax,%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    %esi,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    D47(%rip),%rax
  movzwl (%rax),%ecx
  movzwl -0x20(%rbp),%eax
  mov    $0x0,%edx
  div    %cx
  mov    %dx,-0x20(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L28:
  cmpl   $0x0,-0x1c(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    D47(%rip),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  movzwl -0x20(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L4
L35:
  movb   $0x0,-0x9(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  movzwl -0x20(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x9(%rbp),%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L34:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void shiftleft(unsigned char *data, int size, unsigned short left) {
  unsigned char *byte;
  if (left >= CHAR_BIT) {
    size -= left / CHAR_BIT;
    memmove(data, data + left / CHAR_BIT, (size + CHAR_BIT - 1) / CHAR_BIT);
    left %= CHAR_BIT;
  }
  for (byte = data; size--; ++byte) {
    unsigned char bits;
    if (size)
      bits = byte[1] >> (CHAR_BIT - left);
    else
      bits = 0;
    *byte <<= left;
    *byte |= bits;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shiftleft>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    D5(%rip),%rax
  movzwl (%rax),%ecx
  cmp    %dx,%cx
  jbe    L13
L36:
  lea    -0x1(%r12),%r9d
  test   %r12d,%r12d
  je     L7
  lea    -0x1(%r12),%r8d
  add    %rbx,%r8
  mov    %rbx,%rax
  movzwl %bp,%edi
L15:
  cmp    %rax,%r8
  je     L48
  movzbl 0x1(%rax),%edx
  mov    D5(%rip),%rcx
  movzwl (%rcx),%ecx
  sub    %edi,%ecx
  sar    %cl,%edx
  movzbl (%rax),%esi
  mov    %edi,%ecx
  shl    %cl,%esi
  or     %esi,%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  jmp    L15
L13:
  mov    %edx,%eax
  mov    $0x0,%edx
  div    %cx
  mov    %eax,%esi
  movzwl %ax,%eax
  sub    %eax,%r12d
  movzwl %cx,%ecx
  lea    -0x1(%rcx,%r12,1),%eax
  cltd
  idiv   %ecx
  movzwl %si,%esi
  add    %rdi,%rsi
  mov    %eax,%edx
  call   <memmove@plt>
  mov    D5(%rip),%rdi
  mov    %ebp,%eax
  mov    $0x0,%edx
  divw   (%rdi)
  mov    %edx,%ebp
  jmp    L36
L48:
  mov    %r9d,%r9d
  add    %r9,%rbx
  movzbl (%rbx),%eax
  mov    %ebp,%ecx
  shl    %cl,%eax
  mov    %al,(%rbx)
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void shiftleft(unsigned char *data, int size, unsigned short left) {
  unsigned char *byte;
  if (left >= CHAR_BIT) {
    size -= left / CHAR_BIT;
    memmove(data, data + left / CHAR_BIT, (size + CHAR_BIT - 1) / CHAR_BIT);
    left %= CHAR_BIT;
  }
  for (byte = data; size--; ++byte) {
    unsigned char bits;
    if (size)
      bits = byte[1] >> (CHAR_BIT - left);
    else
      bits = 0;
    *byte <<= left;
    *byte |= bits;
  }
}
```