ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mkpath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x38(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  add    $0x2,%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jae    L16
  mov    $0x1,%eax
  jmp    L15
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x2c(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L13:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s%s

assistant: ```c
int mkpath(char *out, char *dirname, const char *fname, const char div, size_t mxl) {
  int arlen = strlen(dirname);
  if (arlen + strlen(fname) + 2 > mxl)
    return 1;
  if (dirname[(arlen - 1)] != div) {
    dirname[(arlen)] = div;
    dirname[(arlen + 1)] = '\0';
  }
  snprintf(out, 128, "%s%s", dirname, fname);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mkpath>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %r8,%r15
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%eax
  cltq
  mov    $0x1,%edx
  cmp    %r15,%rax
  ja     L14
  movslq %ebx,%rbx
  cmp    %r13b,-0x1(%rbp,%rbx,1)
  je     L17
  mov    %r13b,0x0(%rbp,%rbx,1)
  movb   $0x0,0x1(%rbp,%rbx,1)
L17:
  mov    %r12,%r8
  mov    %rbp,%rcx
  lea    D6(%rip),%rdx
  mov    $0x80,%esi
  mov    %r14,%rdi
  call   <snprintf@plt>
  mov    $0x0,%edx
L14:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %s%s

assistant: ```c
int mkpath(char *out, char *dirname, const char *fname, const char div, size_t mxl) {
  int arlen = strlen(dirname);
  if (arlen + strlen(fname) + 2 > mxl)
    return 1;
  if (dirname[(arlen - 1)] != div) {
    dirname[(arlen)] = div;
    dirname[(arlen + 1)] = '\0';
  }
  snprintf(out, 128, "%s%s", dirname, fname);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mkpath>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rsi,%rdi
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    $0x1,%r8d
  lea    0x2(%rbx,%rax,1),%eax
  cltq
  cmp    %r14,%rax
  ja     L15
  cmp    %r13b,-0x1(%r12,%rbx,1)
  je     L10
  mov    %r13b,(%r12,%rbx,1)
  movb   $0x0,0x1(%r12,%rbx,1)
L10:
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D5(%rip),%rdx
  mov    %r15,%rdi
  mov    $0x80,%esi
  call   <snprintf@plt>
  xor    %r8d,%r8d
L15:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: %s%s

assistant: ```c
int mkpath(char *out, char *dirname, const char *fname, const char div, size_t mxl) {
  int arlen = strlen(dirname);
  if (arlen + strlen(fname) + 2 > mxl)
    return 1;
  if (dirname[(arlen - 1)] != div) {
    dirname[(arlen)] = div;
    dirname[(arlen + 1)] = '\0';
  }
  snprintf(out, 128, "%s%s", dirname, fname);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mkpath>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rsi,%rdi
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    $0x1,%r8d
  lea    0x2(%rbx,%rax,1),%eax
  cltq
  cmp    %r14,%rax
  ja     L5
  cmp    %r13b,-0x1(%r12,%rbx,1)
  je     L0
  mov    %r13b,(%r12,%rbx,1)
  movb   $0x0,0x1(%r12,%rbx,1)
L0:
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D0(%rip),%rdx
  mov    %r15,%rdi
  mov    $0x80,%esi
  call   <snprintf@plt>
  xor    %r8d,%r8d
L5:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s%s

assistant: ```c
int mkpath(char *out, char *dirname, const char *fname, const char div, size_t mxl) {
  int arlen = strlen(dirname);
  if (arlen + strlen(fname) + 2 > mxl)
    return 1;
  if (dirname[(arlen - 1)] != div) {
    dirname[(arlen)] = div;
    dirname[(arlen + 1)] = '\0';
  }
  snprintf(out, 128, "%s%s", dirname, fname);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xt_core_percentage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jp     L4
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  je     L17
L4:
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L22
L17:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L22:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double xt_core_percentage(double part, double whole) {
  double percent;
  if (0 != whole) {
    percent = part / whole;
  } else {
    percent = 0.0;
  }
  return percent;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xt_core_percentage>:
  endbr64
  ucomisd D3(%rip),%xmm1
  jp     L24
  pxor   %xmm2,%xmm2
  jne    L24
L16:
  movapd %xmm2,%xmm0
  ret
L24:
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: f64

tool: D3: 0

assistant: ```c
double xt_core_percentage(double part, double whole) {
  double percent;
  if (0 != whole) {
    percent = part / whole;
  } else {
    percent = 0.0;
  }
  return percent;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xt_core_percentage>:
  endbr64
  pxor   %xmm3,%xmm3
  ucomisd %xmm3,%xmm1
  jp     L16
  pxor   %xmm2,%xmm2
  jne    L16
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L16:
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double xt_core_percentage(double part, double whole) {
  double percent;
  if (0 != whole) {
    percent = part / whole;
  } else {
    percent = 0.0;
  }
  return percent;
}
```
user: What is the c source code of the assembly code below:

```asm
<xt_core_percentage>:
  endbr64
  pxor   %xmm3,%xmm3
  ucomisd %xmm3,%xmm1
  jp     L14
  pxor   %xmm2,%xmm2
  jne    L14
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L14:
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double xt_core_percentage(double part, double whole) {
  double percent;
  if (0 != whole) {
    percent = part / whole;
  } else {
    percent = 0.0;
  }
  return percent;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MapsWithMe_UrlEncodeString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    0x1(%rsi,%rsi,2),%rdi
  call   <malloc@plt>
  mov    %rax,%r10
  mov    %rax,(%r12)
  test   %rbp,%rbp
  je     L83
  mov    %rbx,%rcx
  lea    (%rbx,%rbp,1),%rdi
  lea    D2(%rip),%r9
  movabs $0x170000002d,%r8
  jmp    L79
L94:
  cmp    $0x2c,%dl
  ja     L2
L72:
  movb   $0x25,(%rax)
  mov    %edx,%esi
  shr    $0x4,%sil
  and    $0xf,%esi
  movzbl (%r9,%rsi,1),%esi
  mov    %sil,0x1(%rax)
  and    $0xf,%edx
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,0x2(%rax)
  lea    0x3(%rax),%rax
L44:
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  je     L83
L79:
  movzbl (%rcx),%edx
  cmp    $0x5a,%dl
  jg     L36
  cmp    $0x2f,%dl
  je     L72
  jle    L94
  lea    -0x3a(%rdx),%esi
  cmp    $0x6,%sil
  ja     L2
  jmp    L72
L36:
  lea    -0x5b(%rdx),%esi
  bt     %rsi,%r8
  jb     L72
L2:
  mov    %dl,(%rax)
  lea    0x1(%rax),%rax
  jmp    L44
L83:
  movb   $0x0,(%rax)
  sub    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: 0123456789ABCDEF

assistant: ```c
size_t MapsWithMe_UrlEncodeString(char const *s, size_t size, char **res) {
  size_t i;
  char *out;
  *res = malloc(size * 3 + 1);
  out = *res;
  for (i = 0; i < size; ++i) {
    unsigned char c = (unsigned char)(s[i]);
    switch (c) {
    case 0x00:
    case 0x01:
    case 0x02:
    case 0x03:
    case 0x04:
    case 0x05:
    case 0x06:
    case 0x07:
    case 0x08:
    case 0x09:
    case 0x0A:
    case 0x0B:
    case 0x0C:
    case 0x0D:
    case 0x0E:
    case 0x0F:
    case 0x10:
    case 0x11:
    case 0x12:
    case 0x13:
    case 0x14:
    case 0x15:
    case 0x16:
    case 0x17:
    case 0x18:
    case 0x19:
    case 0x1A:
    case 0x1B:
    case 0x1C:
    case 0x1D:
    case 0x1E:
    case 0x1F:
    case 0x7F:
    case ' ':
    case '<':
    case '>':
    case '#':
    case '%':
    case '"':
    case '!':
    case '*':
    case '\'':
    case '(':
    case ')':
    case ';':
    case ':':
    case '@':
    case '&':
    case '=':
    case '+':
    case '$':
    case ',':
    case '/':
    case '?':
    case '[':
    case ']':
    case '{':
    case '}':
    case '|':
    case '^':
    case '`':
      *(out++) = '%';
      *(out++) = "0123456789ABCDEF"[c >> 4];
      *(out++) = "0123456789ABCDEF"[c & 15];
      break;
    default:
      *(out++) = s[i];
    }
  }
  *(out++) = 0;
  return out - *res - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<MapsWithMe_UrlEncodeString>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi,%rsi,2),%rdi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    %rax,%r10
  test   %rbp,%rbp
  je     L109
  mov    %rbx,%rcx
  lea    (%rbx,%rbp,1),%rsi
  lea    D6(%rip),%r9
  movabs $0x170000002d,%r8
  jmp    L78
  nopl   0x0(%rax)
L71:
  cmp    $0x2f,%dl
  je     L58
  jle    L21
  lea    -0x3a(%rdx),%edi
  cmp    $0x6,%dil
  jbe    L58
L54:
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rsi
  je     L109
L78:
  movzbl (%rcx),%edx
  cmp    $0x5a,%dl
  jle    L71
  lea    -0x5b(%rdx),%edi
  bt     %rdi,%r8
  jae    L54
L58:
  mov    %edx,%edi
  and    $0xf,%edx
  add    $0x1,%rcx
  movb   $0x25,(%rax)
  shr    $0x4,%dil
  movzbl (%r9,%rdx,1),%edx
  add    $0x3,%rax
  and    $0xf,%edi
  movzbl (%r9,%rdi,1),%edi
  mov    %dl,-0x1(%rax)
  mov    %dil,-0x2(%rax)
  cmp    %rcx,%rsi
  jne    L78
L109:
  movb   $0x0,(%rax)
  sub    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  cmp    $0x2c,%dl
  ja     L54
  jmp    L58
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: 0123456789ABCDEF

assistant: ```c
size_t MapsWithMe_UrlEncodeString(char const *s, size_t size, char **res) {
  size_t i;
  char *out;
  *res = malloc(size * 3 + 1);
  out = *res;
  for (i = 0; i < size; ++i) {
    unsigned char c = (unsigned char)(s[i]);
    switch (c) {
    case 0x00:
    case 0x01:
    case 0x02:
    case 0x03:
    case 0x04:
    case 0x05:
    case 0x06:
    case 0x07:
    case 0x08:
    case 0x09:
    case 0x0A:
    case 0x0B:
    case 0x0C:
    case 0x0D:
    case 0x0E:
    case 0x0F:
    case 0x10:
    case 0x11:
    case 0x12:
    case 0x13:
    case 0x14:
    case 0x15:
    case 0x16:
    case 0x17:
    case 0x18:
    case 0x19:
    case 0x1A:
    case 0x1B:
    case 0x1C:
    case 0x1D:
    case 0x1E:
    case 0x1F:
    case 0x7F:
    case ' ':
    case '<':
    case '>':
    case '#':
    case '%':
    case '"':
    case '!':
    case '*':
    case '\'':
    case '(':
    case ')':
    case ';':
    case ':':
    case '@':
    case '&':
    case '=':
    case '+':
    case '$':
    case ',':
    case '/':
    case '?':
    case '[':
    case ']':
    case '{':
    case '}':
    case '|':
    case '^':
    case '`':
      *(out++) = '%';
      *(out++) = "0123456789ABCDEF"[c >> 4];
      *(out++) = "0123456789ABCDEF"[c & 15];
      break;
    default:
      *(out++) = s[i];
    }
  }
  *(out++) = 0;
  return out - *res - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MapsWithMe_UrlEncodeString>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi,%rsi,2),%rdi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    %rax,%r10
  test   %rbp,%rbp
  je     L0
  mov    %rbx,%rcx
  lea    (%rbx,%rbp,1),%rsi
  lea    D3(%rip),%r9
  movabs $0x170000002d,%r8
  jmp    L24
  nopl   0x0(%rax)
L56:
  cmp    $0x2f,%dl
  je     L10
  jle    L58
  lea    -0x3a(%rdx),%edi
  cmp    $0x6,%dil
  jbe    L10
L27:
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rsi
  je     L0
L24:
  movzbl (%rcx),%edx
  cmp    $0x5a,%dl
  jle    L56
  lea    -0x5b(%rdx),%edi
  bt     %rdi,%r8
  jae    L27
L10:
  mov    %edx,%edi
  and    $0xf,%edx
  add    $0x1,%rcx
  movb   $0x25,(%rax)
  shr    $0x4,%dil
  movzbl (%r9,%rdx,1),%edx
  add    $0x3,%rax
  and    $0xf,%edi
  movzbl (%r9,%rdi,1),%edi
  mov    %dl,-0x1(%rax)
  mov    %dil,-0x2(%rax)
  cmp    %rcx,%rsi
  jne    L24
L0:
  movb   $0x0,(%rax)
  sub    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  cmp    $0x2c,%dl
  ja     L27
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: 0123456789ABCDEF

assistant: ```c
size_t MapsWithMe_UrlEncodeString(char const *s, size_t size, char **res) {
  size_t i;
  char *out;
  *res = malloc(size * 3 + 1);
  out = *res;
  for (i = 0; i < size; ++i) {
    unsigned char c = (unsigned char)(s[i]);
    switch (c) {
    case 0x00:
    case 0x01:
    case 0x02:
    case 0x03:
    case 0x04:
    case 0x05:
    case 0x06:
    case 0x07:
    case 0x08:
    case 0x09:
    case 0x0A:
    case 0x0B:
    case 0x0C:
    case 0x0D:
    case 0x0E:
    case 0x0F:
    case 0x10:
    case 0x11:
    case 0x12:
    case 0x13:
    case 0x14:
    case 0x15:
    case 0x16:
    case 0x17:
    case 0x18:
    case 0x19:
    case 0x1A:
    case 0x1B:
    case 0x1C:
    case 0x1D:
    case 0x1E:
    case 0x1F:
    case 0x7F:
    case ' ':
    case '<':
    case '>':
    case '#':
    case '%':
    case '"':
    case '!':
    case '*':
    case '\'':
    case '(':
    case ')':
    case ';':
    case ':':
    case '@':
    case '&':
    case '=':
    case '+':
    case '$':
    case ',':
    case '/':
    case '?':
    case '[':
    case ']':
    case '{':
    case '}':
    case '|':
    case '^':
    case '`':
      *(out++) = '%';
      *(out++) = "0123456789ABCDEF"[c >> 4];
      *(out++) = "0123456789ABCDEF"[c & 15];
      break;
    default:
      *(out++) = s[i];
    }
  }
  *(out++) = 0;
  return out - *res - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  foo();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  foo();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  foo();
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  foo();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findsum(int a[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += a[i];
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findsum>:
  endbr64
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L8:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
L5:
  mov    %edx,%eax
  ret
L19:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
int findsum(int a[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += a[i];
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<findsum>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L4:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L4
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int findsum(int a[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += a[i];
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findsum>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L55
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L46
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L9
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L67
L56:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L14
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L14
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L55:
  xor    %eax,%eax
L14:
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  ret
L46:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L56
```

assistant: ```c
int findsum(int a[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += a[i];
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_multprec_target_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1ec,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int write_multprec_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(492, a, b, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_multprec_target_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1ec,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int write_multprec_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(492, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_multprec_target_system>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1ec,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int write_multprec_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(492, a, b, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_multprec_target_system>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1ec,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int write_multprec_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(492, a, b, c);
  return fail;
}
```