ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<payload>:
  endbr64
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L10:
  mov    $0xc,%edi
  xor    %r13d,%r13d
  call   <putchar@plt>
  nopl   (%rax)
L46:
  mov    %r12,%rdi
  mov    %r13d,%ebp
  add    $0x1,%r13d
  call   <puts@plt>
  mov    $0x64,%edi
  call   <delay@plt>
  cmp    $0xa,%r13d
  je     L50
  mov    $0xc,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L52:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L52
  jmp    L46
  nopl   (%rax)
L50:
  mov    $0xa,%ebp
  nopl   (%rax)
L37:
  mov    $0xc,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax)
L45:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jg     L45
  mov    %r12,%rdi
  call   <puts@plt>
  mov    $0x64,%edi
  call   <delay@plt>
  sub    $0x1,%ebp
  jne    L37
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: 
##     ##    ###     ######  ##    ## ######## ########  
##     ##   ## ##   ##    ## ##   ##  ##       ##     ## 
##     ##  ##   ##  ##       ##  ##   ##       ##     ## 
######### ##     ## ##       #####    ######   ##     ## 
##     ## ######### ##       ##  ##   ##       ##     ## 
##     ## ##     ## ##    ## ##   ##  ##       ##     ## 
##     ## ##     ##  ######  ##    ## ######## ########  

assistant: ```c
void payload(void) {
  const char *hacked = "\n"
                       "##     ##    ###     ######  ##    ## ######## ########  \n"
                       "##     ##   ## ##   ##    ## ##   ##  ##       ##     ## \n"
                       "##     ##  ##   ##  ##       ##  ##   ##       ##     ## \n"
                       "######### ##     ## ##       #####    ######   ##     ## \n"
                       "##     ## ######### ##       ##  ##   ##       ##     ## \n"
                       "##     ## ##     ## ##    ## ##   ##  ##       ##     ## \n"
                       "##     ## ##     ##  ######  ##    ## ######## ########  \n";
  for (;;) {
    for (int a = 0; a < 10; a++) {
      printf("\f");
      for (int i = 0; i < a; i++) {
        printf("\n");
      }
      printf("%s", hacked);
      delay(100);
    }
    for (int a = 10; a > 0; a--) {
      printf("\f");
      for (int i = 0; i < a; i++) {
        printf("\n");
      }
      printf("%s", hacked);
      delay(100);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FanChannelDutyGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  add    $0x14,%rax
  mov    (%rax),%rax
  and    $0x1ff0000,%eax
  mov    %rax,-0x8(%rbp)
  shrq   $0x10,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long FanChannelDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulDuty;
  ;
  ;
  ulDuty = (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) & 0x01FF0000;
  ulDuty >>= 16;
  return (ulDuty);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FanChannelDutyGet>:
  endbr64
  shl    $0x4,%rsi
  lea    0x14(%rsi,%rdi,1),%rax
  mov    (%rax),%rax
  shr    $0x10,%rax
  and    $0x1ff,%eax
  ret
```

assistant: ```c
unsigned long FanChannelDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulDuty;
  ;
  ;
  ulDuty = (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) & 0x01FF0000;
  ulDuty >>= 16;
  return (ulDuty);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<FanChannelDutyGet>:
  endbr64
  shl    $0x4,%rsi
  lea    0x14(%rsi,%rdi,1),%rax
  mov    (%rax),%rax
  shr    $0x10,%rax
  and    $0x1ff,%eax
  ret
```

assistant: ```c
unsigned long FanChannelDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulDuty;
  ;
  ;
  ulDuty = (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) & 0x01FF0000;
  ulDuty >>= 16;
  return (ulDuty);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FanChannelDutyGet>:
  endbr64
  shl    $0x4,%rsi
  lea    0x14(%rsi,%rdi,1),%rax
  mov    (%rax),%rax
  shr    $0x10,%rax
  and    $0x1ff,%eax
  ret
```

assistant: ```c
unsigned long FanChannelDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulDuty;
  ;
  ;
  ulDuty = (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) & 0x01FF0000;
  ulDuty >>= 16;
  return (ulDuty);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SHA224_Init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movl   $0xc1059ed8,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  movl   $0x367cd507,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  movl   $0x3070dd17,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0xc,%rax
  movl   $0xf70e5939,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x10,%rax
  movl   $0xffc00b31,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x14,%rax
  movl   $0x68581511,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x18,%rax
  movl   $0x64f98fa7,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1c,%rax
  movl   $0xbefa4fa4,(%rax)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int SHA224_Init(SHA256_CTX *c) {
  memset(c, 0, sizeof(*c));
  c->h[0] = 0xc1059ed8UL;
  c->h[1] = 0x367cd507UL;
  c->h[2] = 0x3070dd17UL;
  c->h[3] = 0xf70e5939UL;
  c->h[4] = 0xffc00b31UL;
  c->h[5] = 0x68581511UL;
  c->h[6] = 0x64f98fa7UL;
  c->h[7] = 0xbefa4fa4UL;
  c->md_len = SHA224_DIGEST_LENGTH;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SHA224_Init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    (%rbx),%rax
  movl   $0xc1059ed8,(%rax)
  mov    (%rbx),%rax
  movl   $0x367cd507,0x4(%rax)
  mov    (%rbx),%rax
  movl   $0x3070dd17,0x8(%rax)
  mov    (%rbx),%rax
  movl   $0xf70e5939,0xc(%rax)
  mov    (%rbx),%rax
  movl   $0xffc00b31,0x10(%rax)
  mov    (%rbx),%rax
  movl   $0x68581511,0x14(%rax)
  mov    (%rbx),%rax
  movl   $0x64f98fa7,0x18(%rax)
  mov    (%rbx),%rax
  movl   $0xbefa4fa4,0x1c(%rax)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int SHA224_Init(SHA256_CTX *c) {
  memset(c, 0, sizeof(*c));
  c->h[0] = 0xc1059ed8UL;
  c->h[1] = 0x367cd507UL;
  c->h[2] = 0x3070dd17UL;
  c->h[3] = 0xf70e5939UL;
  c->h[4] = 0xffc00b31UL;
  c->h[5] = 0x68581511UL;
  c->h[6] = 0x64f98fa7UL;
  c->h[7] = 0xbefa4fa4UL;
  c->md_len = SHA224_DIGEST_LENGTH;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SHA224_Init>:
  endbr64
  push   %rbx
  mov    $0x10,%edx
  mov    %rdi,%rbx
  xor    %esi,%esi
  call   <memset@plt>
  mov    (%rbx),%rax
  movabs $0x367cd507c1059ed8,%rcx
  movabs $0xf70e59393070dd17,%rdx
  movabs $0x68581511ffc00b31,%rsi
  mov    %rcx,(%rax)
  movabs $0xbefa4fa464f98fa7,%rcx
  mov    %rdx,0x8(%rax)
  mov    %rsi,0x10(%rax)
  mov    %rcx,0x18(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int SHA224_Init(SHA256_CTX *c) {
  memset(c, 0, sizeof(*c));
  c->h[0] = 0xc1059ed8UL;
  c->h[1] = 0x367cd507UL;
  c->h[2] = 0x3070dd17UL;
  c->h[3] = 0xf70e5939UL;
  c->h[4] = 0xffc00b31UL;
  c->h[5] = 0x68581511UL;
  c->h[6] = 0x64f98fa7UL;
  c->h[7] = 0xbefa4fa4UL;
  c->md_len = SHA224_DIGEST_LENGTH;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L3:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void test(int M) {
  int i;
  for (i = 0; i <= M + 1; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  cmp    $0xffffffff,%edi
  jl     L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L10:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jge    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  ret
```

assistant: ```c
void test(int M) {
  int i;
  for (i = 0; i <= M + 1; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  cmp    $0xffffffff,%edi
  jl     L4
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jge    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void test(int M) {
  int i;
  for (i = 0; i <= M + 1; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  cmp    $0xffffffff,%edi
  jl     L7
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jge    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
void test(int M) {
  int i;
  for (i = 0; i <= M + 1; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L36
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L41
L36:
  cmpl   $0x2,-0x14(%rbp)
  jle    L69
  cmpl   $0x5,-0x14(%rbp)
  jg     L69
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L42
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L30
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L41
L69:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L41:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string

tool: D6: There is one argument. U r bad.

tool: D0: Here are your arguments:

tool: D20: %s 

tool: D30: Your have too many arguments(more than 5). You are bad.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 2) {
    printf("There is one argument. U r bad.\n");
  } else if (argc > 2 && argc < 6) {
    printf("Here are your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("Your have too many arguments(more than 5). You are bad.\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  je     L20
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    -0x3(%rdi),%eax
  cmp    $0x2,%eax
  ja     L19
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%r12),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x10(%r12,%rax,8),%r12
  lea    D25(%rip),%rbp
L4:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
L26:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L26
L19:
  lea    D31(%rip),%rdi
  call   <puts@plt>
  jmp    L26
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D11
datatype: string
name: disassemble_data
arguments: data_label: D31
datatype: string

tool: D15: Here are your arguments:

tool: D25: %s 

tool: D11: There is one argument. U r bad.

tool: D31: Your have too many arguments(more than 5). You are bad.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 2) {
    printf("There is one argument. U r bad.\n");
  } else if (argc > 2 && argc < 6) {
    printf("Here are your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("Your have too many arguments(more than 5). You are bad.\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  je     L18
  lea    -0x3(%rdi),%eax
  mov    %edi,%ebp
  cmp    $0x2,%eax
  ja     L19
  lea    D12(%rip),%rdi
  mov    %rsi,%r12
  call   <puts@plt>
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    D18(%rip),%rbp
  lea    0x10(%r12,%rax,8),%r12
L4:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L33
L19:
  lea    D32(%rip),%rdi
  call   <puts@plt>
L33:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L18:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L33
```

tool_calls: name: read_data
arguments: label: D12
datatype: string
name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D32
datatype: string
name: read_data
arguments: label: D19
datatype: string

tool: D12: Here are your arguments:

tool: D18: %s 

tool: D32: Your have too many arguments(more than 5). You are bad.

tool: D19: There is one argument. U r bad.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 2) {
    printf("There is one argument. U r bad.\n");
  } else if (argc > 2 && argc < 6) {
    printf("Here are your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("Your have too many arguments(more than 5). You are bad.\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  je     L36
  lea    -0x3(%rdi),%eax
  mov    %edi,%ebp
  cmp    $0x2,%eax
  ja     L29
  lea    D14(%rip),%rdi
  mov    %rsi,%r12
  call   <puts@plt>
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    D33(%rip),%rbp
  lea    0x10(%r12,%rax,8),%r12
L28:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L35
L29:
  lea    D10(%rip),%rdi
  call   <puts@plt>
L35:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L36:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  jmp    L35
```

tool_calls: name: unpack_data
arguments: tag: D14
type_infered: string
name: unpack_data
arguments: tag: D33
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D34
type_infered: string

tool: D14: Here are your arguments:

tool: D33: %s 

tool: D10: Your have too many arguments(more than 5). You are bad.

tool: D34: There is one argument. U r bad.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 2) {
    printf("There is one argument. U r bad.\n");
  } else if (argc > 2 && argc < 6) {
    printf("Here are your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("Your have too many arguments(more than 5). You are bad.\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ConstructDataHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D50(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x14(%rbp),%eax
  and    $0xf0,%eax
  cmp    $0x40,%eax
  je     L23
  cmp    $0x40,%eax
  jg     L11
  cmp    $0x10,%eax
  je     L50
  cmp    $0x20,%eax
  je     L14
  jmp    L11
L50:
  mov    -0x8(%rbp),%rax
  lea    D65(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L11
L14:
  mov    -0x8(%rbp),%rax
  lea    D61(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L11
L23:
  mov    -0x8(%rbp),%rax
  lea    D66(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L57
L11:
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  cmp    $0x3,%eax
  je     L92
  cmp    $0x3,%eax
  jg     L57
  cmp    $0x1,%eax
  je     L101
  cmp    $0x2,%eax
  je     L110
  jmp    L57
L101:
  mov    -0x8(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L57
L110:
  mov    -0x8(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L57
L92:
  mov    -0x8(%rbp),%rax
  lea    D63(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
L57:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D50
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D65
type: string
name: extract_symbolic_data
arguments: data_label: D61
type: string
name: extract_symbolic_data
arguments: data_label: D66
type: string
name: extract_symbolic_data
arguments: data_label: D33
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string
name: extract_symbolic_data
arguments: data_label: D63
type: string

tool: D50: !

tool: D9:  

tool: D65: single

tool: D61: array

tool: D66: table

tool: D33: int

tool: D28: dbl

tool: D63: str

assistant: ```c
void ConstructDataHeader(char *sLine, char *sName, int iType) {
  strcpy(sLine, "!");
  strcat(sLine, sName);
  strcat(sLine, " ");
  switch (iType & 0x000000F0) {
  case 0x00000010:
    strcat(sLine, "single");
    break;
  case 0x00000020:
    strcat(sLine, "array");
    break;
  case 0x00000040:
    strcat(sLine, "table");
    return;
  }
  strcat(sLine, " ");
  switch (iType & 0x0000000F) {
  case 0x00000001:
    strcat(sLine, "int");
    break;
  case 0x00000002:
    strcat(sLine, "dbl");
    break;
  case 0x00000003:
    strcat(sLine, "str");
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ConstructDataHeader>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  lea    D82(%rip),%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D58(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %ebp,%eax
  and    $0xf0,%eax
  cmp    $0x20,%eax
  je     L107
  cmp    $0x40,%eax
  je     L96
  cmp    $0x10,%eax
  je     L44
L90:
  lea    D58(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %ebp,%eax
  and    $0xf,%eax
  cmp    $0x2,%eax
  je     L79
  cmp    $0x3,%eax
  je     L28
  cmp    $0x1,%eax
  je     L22
L109:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L90
L107:
  lea    D71(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L90
L96:
  lea    D63(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L109
L22:
  lea    D46(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L109
L79:
  lea    D20(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L109
L28:
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L109
```

tool_calls: name: parse_data
arguments: label: D82
type_guessed: string
name: parse_data
arguments: label: D58
type_guessed: string
name: parse_data
arguments: label: D47
type_guessed: string
name: parse_data
arguments: label: D71
type_guessed: string
name: parse_data
arguments: label: D63
type_guessed: string
name: parse_data
arguments: label: D46
type_guessed: string
name: parse_data
arguments: label: D20
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string

tool: D82: !

tool: D58:  

tool: D47: single

tool: D71: array

tool: D63: table

tool: D46: int

tool: D20: dbl

tool: D9: str

assistant: ```c
void ConstructDataHeader(char *sLine, char *sName, int iType) {
  strcpy(sLine, "!");
  strcat(sLine, sName);
  strcat(sLine, " ");
  switch (iType & 0x000000F0) {
  case 0x00000010:
    strcat(sLine, "single");
    break;
  case 0x00000020:
    strcat(sLine, "array");
    break;
  case 0x00000040:
    strcat(sLine, "table");
    return;
  }
  strcat(sLine, " ");
  switch (iType & 0x0000000F) {
  case 0x00000001:
    strcat(sLine, "int");
    break;
  case 0x00000002:
    strcat(sLine, "dbl");
    break;
  case 0x00000003:
    strcat(sLine, "str");
    break;
  }
}
```