ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<lba_to_msf>:
  endbr64
  movslq %edi,%rcx
  mov    %edi,%eax
  imul   $0x7482296b,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x2b,%rcx
  sub    %eax,%ecx
  imul   $0xffffee6c,%ecx,%eax
  movslq %ecx,%rsi
  imul   $0x66666667,%rsi,%rsi
  add    %eax,%edi
  movslq %edi,%rdx
  mov    %edi,%eax
  sar    $0x22,%rsi
  imul   $0x1b4e81b5,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x23,%rdx
  sub    %eax,%edx
  imul   $0x4b,%edx,%eax
  sub    %eax,%edi
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %esi,%eax
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  shl    $0x14,%eax
  sub    %esi,%ecx
  movslq %edi,%rsi
  imul   $0x66666667,%rsi,%rsi
  shl    $0x10,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rsi
  sub    %ecx,%esi
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  or     %edi,%eax
  mov    %edx,%edi
  sar    $0x22,%rcx
  sar    $0x1f,%edi
  sub    %edi,%ecx
  mov    %ecx,%edi
  lea    (%rcx,%rcx,4),%ecx
  shl    $0xc,%edi
  add    %ecx,%ecx
  sub    %ecx,%edx
  or     %edi,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  mov    %esi,%edx
  shl    $0x4,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t lba_to_msf(uint32_t lba) {
  uint8_t m, s, f;
  m = lba / (60 * 75);
  lba -= m * (60 * 75);
  s = lba / 75;
  f = lba % 75;
  return ((m / 10) << 20) | ((m % 10) << 16) | ((s / 10) << 12) | ((s % 10) << 8) | ((f / 10) << 4) | ((f % 10) << 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lba_to_msf>:
  endbr64
  movslq %edi,%rcx
  mov    %edi,%eax
  imul   $0x7482296b,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x2b,%rcx
  sub    %eax,%ecx
  imul   $0xffffee6c,%ecx,%eax
  movslq %ecx,%rsi
  imul   $0x66666667,%rsi,%rsi
  add    %eax,%edi
  movslq %edi,%rdx
  mov    %edi,%eax
  sar    $0x22,%rsi
  imul   $0x1b4e81b5,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x23,%rdx
  sub    %eax,%edx
  imul   $0x4b,%edx,%eax
  sub    %eax,%edi
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %esi,%eax
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  shl    $0x14,%eax
  sub    %esi,%ecx
  movslq %edi,%rsi
  imul   $0x66666667,%rsi,%rsi
  shl    $0x10,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rsi
  sub    %ecx,%esi
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  or     %edi,%eax
  mov    %edx,%edi
  sar    $0x22,%rcx
  sar    $0x1f,%edi
  sub    %edi,%ecx
  mov    %ecx,%edi
  lea    (%rcx,%rcx,4),%ecx
  shl    $0xc,%edi
  add    %ecx,%ecx
  sub    %ecx,%edx
  or     %edi,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  mov    %esi,%edx
  shl    $0x4,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t lba_to_msf(uint32_t lba) {
  uint8_t m, s, f;
  m = lba / (60 * 75);
  lba -= m * (60 * 75);
  s = lba / 75;
  f = lba % 75;
  return ((m / 10) << 20) | ((m % 10) << 16) | ((s / 10) << 12) | ((s % 10) << 8) | ((f / 10) << 4) | ((f % 10) << 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<draw_text2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glRasterPos2i@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <glutBitmapCharacter@plt>
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void draw_text2d(int x, int y, char *string, void *font) {
  int len = 0, i = 0;
  glRasterPos2i(x, y);
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<draw_text2d>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <glRasterPos2i@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%r12
L7:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <glutBitmapCharacter@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L7
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void draw_text2d(int x, int y, char *string, void *font) {
  int len = 0, i = 0;
  glRasterPos2i(x, y);
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw_text2d>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <glRasterPos2i@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  cmp    %r12,%rbx
  jne    L10
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void draw_text2d(int x, int y, char *string, void *font) {
  int len = 0, i = 0;
  glRasterPos2i(x, y);
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<draw_text2d>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <glRasterPos2i@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L12:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  cmp    %r12,%rbx
  jne    L12
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void draw_text2d(int x, int y, char *string, void *font) {
  int len = 0, i = 0;
  glRasterPos2i(x, y);
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<my_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L3
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *my_strndup(const char *src, size_t n) {
  char *dst;
  dst = (char *)calloc(n + 1, sizeof(char));
  if (dst == NULL)
    return NULL;
  strncpy(dst, src, n);
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <strncpy@plt>
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strndup(const char *src, size_t n) {
  char *dst;
  dst = (char *)calloc(n + 1, sizeof(char));
  if (dst == NULL)
    return NULL;
  strncpy(dst, src, n);
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strndup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %rax,%rax
  je     L8
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strncpy@plt>
L8:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *my_strndup(const char *src, size_t n) {
  char *dst;
  dst = (char *)calloc(n + 1, sizeof(char));
  if (dst == NULL)
    return NULL;
  strncpy(dst, src, n);
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strndup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %rax,%rax
  je     L4
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strncpy@plt>
L4:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *my_strndup(const char *src, size_t n) {
  char *dst;
  dst = (char *)calloc(n + 1, sizeof(char));
  if (dst == NULL)
    return NULL;
  strncpy(dst, src, n);
  return dst;
}
```
user: What is the c source code of the assembly code below?

```asm
<parity5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L20
L1:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x10,-0xc(%rbp)
  jmp    L14
L18:
  mov    -0xc(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
L14:
  cmpl   $0x0,-0xc(%rbp)
  jg     L18
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L1
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int parity5(unsigned *array, unsigned len) {
  int i, j, res = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    res += (x & 0x01);
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parity5>:
  endbr64
  test   %esi,%esi
  je     L49
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
  mov    $0x0,%edi
  mov    $0x10,%r9d
  jmp    L39
L22:
  and    $0x1,%eax
  add    %eax,%edi
  add    $0x4,%r8
  cmp    %r10,%r8
  je     L40
L39:
  mov    (%r8),%eax
  mov    $0x5,%edx
  mov    %r9d,%ecx
L46:
  mov    %eax,%esi
  shr    %cl,%esi
  xor    %esi,%eax
  mov    %ecx,%esi
  shr    $0x1f,%esi
  add    %esi,%ecx
  sar    %ecx
  sub    $0x1,%edx
  jne    L46
  jmp    L22
L49:
  mov    $0x0,%edi
L40:
  mov    %edi,%eax
  ret
```

assistant: ```c
int parity5(unsigned *array, unsigned len) {
  int i, j, res = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    res += (x & 0x01);
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parity5>:
  endbr64
  test   %esi,%esi
  je     L14
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%r9
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rdi),%eax
  mov    $0x5,%edx
  mov    $0x10,%ecx
L29:
  mov    %eax,%esi
  shr    %cl,%esi
  sar    %ecx
  xor    %esi,%eax
  sub    $0x1,%edx
  jne    L29
  and    $0x1,%eax
  add    $0x4,%rdi
  add    %eax,%r8d
  cmp    %rdi,%r9
  jne    L6
  mov    %r8d,%eax
  ret
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity5(unsigned *array, unsigned len) {
  int i, j, res = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    res += (x & 0x01);
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parity5>:
  endbr64
  test   %esi,%esi
  je     L14
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  shr    %edx
  xor    %edx,%eax
  and    $0x1,%eax
  add    %eax,%r8d
  cmp    %rdi,%rcx
  jne    L4
  mov    %r8d,%eax
  ret
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity5(unsigned *array, unsigned len) {
  int i, j, res = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    for (j = 16; j > 0; j /= 2)
      x ^= x >> j;
    res += (x & 0x01);
  }
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<getIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  js     L11
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x4(%rbp)
  jmp    L19
L11:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getIndex(int n, int index) {
  int ret = 0;
  if (0 <= index) {
    ret = index % n;
  } else {
    ret = index % n + n;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getIndex>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  js     L15
  cltd
  idiv   %edi
L18:
  mov    %edx,%eax
  ret
L15:
  cltd
  idiv   %edi
  add    %edi,%edx
  jmp    L18
```

assistant: ```c
int getIndex(int n, int index) {
  int ret = 0;
  if (0 <= index) {
    ret = index % n;
  } else {
    ret = index % n + n;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getIndex>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %edi
  add    %edx,%edi
  mov    %edx,%eax
  test   %esi,%esi
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int getIndex(int n, int index) {
  int ret = 0;
  if (0 <= index) {
    ret = index % n;
  } else {
    ret = index % n + n;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getIndex>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %edi
  add    %edx,%edi
  mov    %edx,%eax
  test   %esi,%esi
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int getIndex(int n, int index) {
  int ret = 0;
  if (0 <= index) {
    ret = index % n;
  } else {
    ret = index % n + n;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getOffset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x10(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: r

assistant: ```c
int getOffset(char *filename) {
  FILE *fp;
  int n, int_var, offset;
  fp = fopen(filename, "r");
  fseek(fp, 10, 0);
  n = fread(&int_var, sizeof(int), 1, fp);
  offset = int_var;
  fclose(fp);
  return offset;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getOffset>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    0x4(%rsp),%ebp
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: r

assistant: ```c
int getOffset(char *filename) {
  FILE *fp;
  int n, int_var, offset;
  fp = fopen(filename, "r");
  fseek(fp, 10, 0);
  n = fread(&int_var, sizeof(int), 1, fp);
  offset = int_var;
  fclose(fp);
  return offset;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getOffset>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  xor    %edx,%edx
  mov    $0xa,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fseek@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  mov    0x4(%rsp),%r12d
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: r

assistant: ```c
int getOffset(char *filename) {
  FILE *fp;
  int n, int_var, offset;
  fp = fopen(filename, "r");
  fseek(fp, 10, 0);
  n = fread(&int_var, sizeof(int), 1, fp);
  offset = int_var;
  fclose(fp);
  return offset;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getOffset>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  xor    %edx,%edx
  mov    $0xa,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fseek@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  mov    0x4(%rsp),%r12d
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: r

assistant: ```c
int getOffset(char *filename) {
  FILE *fp;
  int n, int_var, offset;
  fp = fopen(filename, "r");
  fseek(fp, 10, 0);
  n = fread(&int_var, sizeof(int), 1, fp);
  offset = int_var;
  fclose(fp);
  return offset;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bindump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <binwrite@plt>
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L6
  mov    $0x20,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L69
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x1f,-0x5(%rbp)
  jbe    L43
  movzbl -0x5(%rbp),%eax
  test   %al,%al
  js     L43
  movzbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L61
L43:
  mov    $0x2e,%edi
  call   <putchar@plt>
L61:
  addl   $0x1,-0x4(%rbp)
L69:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L12
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: %04x  

assistant: ```c
void bindump(unsigned char *bytes, int offset, int num) {
  int i;
  unsigned char c;
  printf("%04x  ", offset);
  for (i = 0; i < num; i++) {
    binwrite(bytes[i]);
  };
  printf(" ");
  for (i = 0; i < num; i++) {
    c = bytes[i];
    if ((c > 31) && (c < 128))
      printf("%c", c);
    else
      printf(".");
  };
  printf("\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bindump>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r12d
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L13
  mov    %rbx,%rbp
  lea    -0x1(%r12),%eax
  lea    0x1(%rbx,%rax,1),%r12
L26:
  movzbl (%rbx),%edi
  call   <binwrite@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L26
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L19
L23:
  mov    $0x2e,%edi
  call   <putchar@plt>
L41:
  add    $0x1,%rbp
  cmp    %r12,%rbp
  je     L45
L19:
  movzbl 0x0(%rbp),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5f,%al
  ja     L23
  movzbl %dil,%edi
  call   <putchar@plt>
  jmp    L41
L13:
  mov    $0x20,%edi
  call   <putchar@plt>
L45:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %04x  

assistant: ```c
void bindump(unsigned char *bytes, int offset, int num) {
  int i;
  unsigned char c;
  printf("%04x  ", offset);
  for (i = 0; i < num; i++) {
    binwrite(bytes[i]);
  };
  printf(" ");
  for (i = 0; i < num; i++) {
    c = bytes[i];
    if ((c > 31) && (c < 128))
      printf("%c", c);
    else
      printf(".");
  };
  printf("\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bindump>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L4
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rbp
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  call   <binwrite@plt>
  cmp    %r12,%rbp
  jne    L26
  mov    $0x20,%edi
  call   <putchar@plt>
  nopl   0x0(%rax)
L7:
  movzbl (%rbx),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5f,%al
  jbe    L32
  mov    $0x2e,%edi
L32:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x20,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3: %04x  

assistant: ```c
void bindump(unsigned char *bytes, int offset, int num) {
  int i;
  unsigned char c;
  printf("%04x  ", offset);
  for (i = 0; i < num; i++) {
    binwrite(bytes[i]);
  };
  printf(" ");
  for (i = 0; i < num; i++) {
    c = bytes[i];
    if ((c > 31) && (c < 128))
      printf("%c", c);
    else
      printf(".");
  };
  printf("\n");
  return;
}
```