user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  lea    D52(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x38(%rsp),%r14
  mov    %r13,%rbx
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%ebp
L14:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    D18(%rip),%rax
  add    $0x1,%ebp
  mov    %rax,-0x8(%rbx)
  cmp    %rbx,%r14
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L44
  mov    $0x1,%r12d
  lea    D9(%rip),%r14
  lea    D17(%rip),%rbp
L22:
  mov    %r12d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r13,%r15
  call   <printf@plt>
  xor    %ebx,%ebx
L27:
  movsd  (%r15),%xmm2
  mov    0x8(%rsp),%eax
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  add    $0x8,%r15
  add    %ebx,%eax
  movapd %xmm2,%xmm1
  add    $0x1,%ebx
  cvtsi2sd %eax,%xmm0
  divsd  D18(%rip),%xmm0
  mov    $0x1,%eax
  divsd  D47(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r15)
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L27
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,0xc(%rsp)
  jge    L22
L44:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D37
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D52
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string
name: retrieve_data
arguments: tag: D25
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: f64
name: retrieve_data
arguments: tag: D9
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: f64

tool: D37: Enter interest rate: 

tool: D16: %6d%%

tool: D52: %d

tool: D27: Enter number of years: 

tool: D25: 
Years

tool: D18: 100

tool: D9: %3d	

tool: D17: %7.2f

tool: D47: 12

assistant: ```c
int main(void) {
  int rate, higher_rate, num_years;
  double value[5];
  printf("Enter interest rate: ");
  scanf("%d", &rate);
  printf("Enter number of years: ");
  scanf("%d", &num_years);
  printf("\nYears");
  higher_rate = rate;
  for (int i = 0; i < ((int)(sizeof(value) / sizeof(value[0]))); i += 1) {
    printf("%6d%%", higher_rate);
    higher_rate += 1;
    value[i] = 100.00;
  }
  printf("\n");
  for (int year = 1; year <= num_years; year += 1) {
    printf("%3d\t", year);
    for (int i = 0; i < ((int)(sizeof(value) / sizeof(value[0]))); i += 1) {
      for (int j = 0; j < 12; j += 1) {
        value[i] += (rate + i) / 100.0 / 12.0 * value[i];
      }
      printf("%7.2f", value[i]);
    }
    printf("\n");
  }
  return 0;
}
```