ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_ultoa>:
  endbr64
  mov    %edx,%r8d
  mov    %rsi,%rcx
  lea    D6(%rip),%r10
  nopl   0x0(%rax)
L16:
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %rcx,%r9
  add    $0x1,%rcx
  div    %r8
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%rcx)
  mov    %rdi,%rdx
  mov    %rax,%rdi
  cmp    %r8,%rdx
  jae    L16
  movb   $0x0,(%rcx)
  add    $0x2,%r9
  cmp    %rcx,%rsi
  jae    L15
  cs nopw 0x0(%rax,%rax,1)
L24:
  movzbl (%rsi),%edx
  movzbl -0x1(%rcx),%eax
  sub    $0x1,%rcx
  add    $0x1,%rsi
  mov    %dl,(%rcx)
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rcx
  ja     L24
L15:
  mov    %r9,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
char *my_ultoa(unsigned long val, char *buf, unsigned int base) {
  static char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  char *strt = buf, *end;
  do {
    *buf++ = digits[val % base];
    val /= base;
  } while (val != 0);
  *buf = 0;
  end = buf + 1;
  while (buf > strt) {
    char temp;
    temp = *--buf;
    *buf = *strt;
    *strt++ = temp;
  }
  return end;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xrop3_143_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_143_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_143_0_0>:
  endbr64
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  not    %eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_143_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xrop3_143_0_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_143_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_143_0_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_143_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<From2iToMono_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x24(%rbp)
  movzwl -0x24(%rbp),%eax
  mov    %ax,-0xa(%rbp)
  jmp    L3
L16:
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  movswq %ax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  movswq %ax,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sar    %rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dx,(%rax)
  movzwl -0xa(%rbp),%eax
  sub    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L3:
  cmpw   $0x0,-0xa(%rbp)
  jne    L16
  nop
  pop    %rbp
  ret
```

assistant: ```c
void From2iToMono_16(const short *src, short *dst, short n) {
  short ii;
  long Temp;
  for (ii = n; ii != 0; ii--) {
    Temp = (long)*(src++);
    Temp += (long)*(src++);
    *(dst++) = (short)(Temp >> 1);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<From2iToMono_16>:
  endbr64
  test   %dx,%dx
  je     L15
  movzwl %dx,%edx
  lea    (%rdi,%rdx,4),%rcx
L14:
  movswq (%rdi),%rdx
  add    $0x4,%rdi
  add    $0x2,%rsi
  movswq -0x2(%rdi),%rax
  add    %rdx,%rax
  sar    %rax
  mov    %ax,-0x2(%rsi)
  cmp    %rdi,%rcx
  jne    L14
L15:
  ret
```

assistant: ```c
void From2iToMono_16(const short *src, short *dst, short n) {
  short ii;
  long Temp;
  for (ii = n; ii != 0; ii--) {
    Temp = (long)*(src++);
    Temp += (long)*(src++);
    *(dst++) = (short)(Temp >> 1);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<From2iToMono_16>:
  endbr64
  test   %dx,%dx
  je     L5
  movzwl %dx,%edx
  lea    (%rdi,%rdx,4),%rcx
L11:
  movswq (%rdi),%rdx
  movswq 0x2(%rdi),%rax
  add    $0x4,%rdi
  add    $0x2,%rsi
  add    %rdx,%rax
  sar    %rax
  mov    %ax,-0x2(%rsi)
  cmp    %rcx,%rdi
  jne    L11
L5:
  ret
```

assistant: ```c
void From2iToMono_16(const short *src, short *dst, short n) {
  short ii;
  long Temp;
  for (ii = n; ii != 0; ii--) {
    Temp = (long)*(src++);
    Temp += (long)*(src++);
    *(dst++) = (short)(Temp >> 1);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<From2iToMono_16>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,%r8d
  test   %dx,%dx
  je     L85
  movzwl %dx,%edx
  lea    (%rdi,%rdx,4),%rsi
  lea    (%rcx,%rdx,2),%rdi
  cmp    %rsi,%rcx
  setae  %sil
  cmp    %rdi,%rax
  setae  %dil
  or     %dil,%sil
  je     L105
  lea    -0x1(%r8),%esi
  cmp    $0x6,%si
  jbe    L105
  lea    -0x8(%r8),%edi
  xor    %edx,%edx
  pxor   %xmm4,%xmm4
  xor    %esi,%esi
  shr    $0x3,%di
  add    $0x1,%edi
  nopl   0x0(%rax)
L83:
  movdqu (%rax,%rdx,2),%xmm0
  movdqu 0x10(%rax,%rdx,2),%xmm3
  add    $0x1,%esi
  movdqa %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  punpcklwd %xmm3,%xmm0
  punpcklwd %xmm3,%xmm2
  punpckhwd %xmm3,%xmm1
  movdqa %xmm4,%xmm3
  movdqa %xmm2,%xmm5
  punpcklwd %xmm1,%xmm0
  punpcklwd %xmm1,%xmm2
  punpckhwd %xmm1,%xmm5
  punpcklwd %xmm5,%xmm2
  punpckhwd %xmm5,%xmm0
  movdqa %xmm4,%xmm5
  pcmpgtw %xmm2,%xmm5
  pcmpgtw %xmm0,%xmm3
  movdqa %xmm2,%xmm6
  movdqa %xmm0,%xmm1
  punpckhwd %xmm5,%xmm2
  punpcklwd %xmm5,%xmm6
  punpcklwd %xmm3,%xmm1
  punpckhwd %xmm3,%xmm0
  paddd  %xmm6,%xmm1
  paddd  %xmm2,%xmm0
  psrad  $0x1,%xmm1
  psrad  $0x1,%xmm0
  movdqa %xmm1,%xmm2
  punpcklwd %xmm0,%xmm1
  punpckhwd %xmm0,%xmm2
  movdqa %xmm1,%xmm0
  punpcklwd %xmm2,%xmm1
  punpckhwd %xmm2,%xmm0
  punpcklwd %xmm0,%xmm1
  movups %xmm1,(%rcx,%rdx,1)
  add    $0x10,%rdx
  cmp    %si,%di
  ja     L83
  shl    $0x3,%edi
  mov    %r8d,%esi
  movzwl %di,%edx
  sub    %edi,%esi
  lea    (%rax,%rdx,4),%rax
  lea    (%rcx,%rdx,2),%rdx
  cmp    %di,%r8w
  je     L85
  movswq (%rax),%rdi
  movswq 0x2(%rax),%rcx
  add    %rdi,%rcx
  sar    %rcx
  mov    %cx,(%rdx)
  cmp    $0x1,%si
  je     L85
  movswq 0x4(%rax),%rdi
  movswq 0x6(%rax),%rcx
  add    %rdi,%rcx
  sar    %rcx
  mov    %cx,0x2(%rdx)
  cmp    $0x2,%si
  je     L85
  movswq 0x8(%rax),%rdi
  movswq 0xa(%rax),%rcx
  add    %rdi,%rcx
  sar    %rcx
  mov    %cx,0x4(%rdx)
  cmp    $0x3,%si
  je     L85
  movswq 0xc(%rax),%rdi
  movswq 0xe(%rax),%rcx
  add    %rdi,%rcx
  sar    %rcx
  mov    %cx,0x6(%rdx)
  cmp    $0x4,%si
  je     L85
  movswq 0x10(%rax),%rdi
  movswq 0x12(%rax),%rcx
  add    %rdi,%rcx
  sar    %rcx
  mov    %cx,0x8(%rdx)
  cmp    $0x5,%si
  je     L85
  movswq 0x14(%rax),%rdi
  movswq 0x16(%rax),%rcx
  add    %rdi,%rcx
  sar    %rcx
  mov    %cx,0xa(%rdx)
  cmp    $0x6,%si
  je     L85
  movswq 0x18(%rax),%rcx
  movswq 0x1a(%rax),%rax
  add    %rcx,%rax
  sar    %rax
  mov    %ax,0xc(%rdx)
  ret
  nopl   0x0(%rax)
L105:
  lea    (%rax,%rdx,4),%rdi
  nopl   0x0(%rax)
L109:
  movswq (%rax),%rsi
  movswq 0x2(%rax),%rdx
  add    $0x4,%rax
  add    $0x2,%rcx
  add    %rsi,%rdx
  sar    %rdx
  mov    %dx,-0x2(%rcx)
  cmp    %rdi,%rax
  jne    L109
L85:
  ret
```

assistant: ```c
void From2iToMono_16(const short *src, short *dst, short n) {
  short ii;
  long Temp;
  for (ii = n; ii != 0; ii--) {
    Temp = (long)*(src++);
    Temp += (long)*(src++);
    *(dst++) = (short)(Temp >> 1);
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Fmod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fmod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  -0x18(%rbp),%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D41
type_guessed: string
name: retrieve_data
arguments: tag: D42
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: D41: Enter the divisor: 

tool: D42: %lf

tool: D22: Enter the dividend: 

tool: D19: Residue of %f / %f is %lf


assistant: ```c
double Fmod(double a, double b, double resultado) {
  printf("Enter the divisor: ");
  scanf("%lf", &a);
  printf("Enter the dividend: ");
  scanf("%lf", &b);
  resultado = fmod(a, b);
  printf("Residue of %f / %f is %lf\n", a, b, resultado);
  return (resultado);
}
```
user: What is the c source code of the assembly code below?

```asm
<Fmod>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D30(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%r12
  mov    0x8(%rsp),%rbp
  movq   %r12,%xmm1
  movq   %rbp,%xmm0
  call   <fmod@plt>
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm2
  movq   %r12,%xmm1
  movq   %rbp,%xmm0
  lea    D6(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string

tool: D12: Enter the divisor: 

tool: D30: %lf

tool: D14: Enter the dividend: 

tool: D6: Residue of %f / %f is %lf


assistant: ```c
double Fmod(double a, double b, double resultado) {
  printf("Enter the divisor: ");
  scanf("%lf", &a);
  printf("Enter the dividend: ");
  scanf("%lf", &b);
  resultado = fmod(a, b);
  printf("Residue of %f / %f is %lf\n", a, b, resultado);
  return (resultado);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Fmod>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  lea    D31(%rip),%rbp
  xor    %eax,%eax
  sub    $0x30,%rsp
  movsd  %xmm0,0x28(%rsp)
  movsd  %xmm1,0x20(%rsp)
  call   <printf@plt>
  lea    0x28(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x28(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm1
  movapd %xmm3,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  call   <fmod@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm1
  lea    D38(%rip),%rdi
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x8(%rsp)
  mov    $0x3,%eax
  movapd %xmm3,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x30,%rsp
  pop    %rbp
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D34
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D38
data_type: string

tool: D34: Enter the divisor: 

tool: D31: %lf

tool: D9: Enter the dividend: 

tool: D38: Residue of %f / %f is %lf


assistant: ```c
double Fmod(double a, double b, double resultado) {
  printf("Enter the divisor: ");
  scanf("%lf", &a);
  printf("Enter the dividend: ");
  scanf("%lf", &b);
  resultado = fmod(a, b);
  printf("Residue of %f / %f is %lf\n", a, b, resultado);
  return (resultado);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Fmod>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  lea    D23(%rip),%rbp
  xor    %eax,%eax
  sub    $0x30,%rsp
  movsd  %xmm0,0x28(%rsp)
  movsd  %xmm1,0x20(%rsp)
  call   <printf@plt>
  lea    0x28(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x28(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm1
  movapd %xmm3,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  call   <fmod@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm1
  lea    D2(%rip),%rdi
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x8(%rsp)
  mov    $0x3,%eax
  movapd %xmm3,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x30,%rsp
  pop    %rbp
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D9: Enter the divisor: 

tool: D23: %lf

tool: D21: Enter the dividend: 

tool: D2: Residue of %f / %f is %lf


assistant: ```c
double Fmod(double a, double b, double resultado) {
  printf("Enter the divisor: ");
  scanf("%lf", &a);
  printf("Enter the dividend: ");
  scanf("%lf", &b);
  resultado = fmod(a, b);
  printf("Residue of %f / %f is %lf\n", a, b, resultado);
  return (resultado);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D14
type: string

tool: D15: ----------------------------------------------------------

tool: D14: | Hash Table Implementation (c) 2016 Michael P. Nitowski |

assistant: ```c
void header() {
  puts("----------------------------------------------------------");
  puts("| Hash Table Implementation (c) 2016 Michael P. Nitowski |");
  puts("----------------------------------------------------------");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<header>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string

tool: D2: ----------------------------------------------------------

tool: D13: | Hash Table Implementation (c) 2016 Michael P. Nitowski |

assistant: ```c
void header() {
  puts("----------------------------------------------------------");
  puts("| Hash Table Implementation (c) 2016 Michael P. Nitowski |");
  puts("----------------------------------------------------------");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<header>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D17: ----------------------------------------------------------

tool: D0: | Hash Table Implementation (c) 2016 Michael P. Nitowski |

assistant: ```c
void header() {
  puts("----------------------------------------------------------");
  puts("| Hash Table Implementation (c) 2016 Michael P. Nitowski |");
  puts("----------------------------------------------------------");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<header>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: D16: ----------------------------------------------------------

tool: D12: | Hash Table Implementation (c) 2016 Michael P. Nitowski |

assistant: ```c
void header() {
  puts("----------------------------------------------------------");
  puts("| Hash Table Implementation (c) 2016 Michael P. Nitowski |");
  puts("----------------------------------------------------------");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  movzbl %al,%eax
  or     %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned short get_2(FILE *fp) {
  unsigned short result;
  result = (unsigned char)fgetc(fp) << 8;
  result |= (unsigned char)fgetc(fp);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <fgetc@plt>
  mov    %eax,%ebp
  shl    $0x8,%ebp
  mov    %rbx,%rdi
  call   <fgetc@plt>
  movzbl %al,%eax
  or     %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short get_2(FILE *fp) {
  unsigned short result;
  result = (unsigned char)fgetc(fp) << 8;
  result |= (unsigned char)fgetc(fp);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_2>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  shl    $0x8,%ebx
  add    $0x8,%rsp
  movzbl %al,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short get_2(FILE *fp) {
  unsigned short result;
  result = (unsigned char)fgetc(fp) << 8;
  result |= (unsigned char)fgetc(fp);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_2>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  shl    $0x8,%ebx
  add    $0x8,%rsp
  movzbl %al,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short get_2(FILE *fp) {
  unsigned short result;
  result = (unsigned char)fgetc(fp) << 8;
  result |= (unsigned char)fgetc(fp);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x4(%rbp)
  movl   $0x2,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo() {
  int x = 1;
label:
  x = 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  int x = 1;
label:
  x = 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  int x = 1;
label:
  x = 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  int x = 1;
label:
  x = 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 1 ^ 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 1 ^ 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 1 ^ 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 1 ^ 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <produce_dirs_below@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(argc == 2);
  produce_dirs_below(argv[1]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rbx),%rdi
  call   <produce_dirs_below@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(argc == 2);
  produce_dirs_below(argv[1]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  mov    %rsi,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rbx),%rdi
  call   <produce_dirs_below@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  assert(argc == 2);
  produce_dirs_below(argv[1]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L2
L14:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  add    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L14
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count(int n, int c, int m) {
  int i;
  int j = 0;
  int r;
  j = n / c;
  n = j;
  while (n >= m) {
    j += n / m;
    r = n % m;
    n = n / m;
    n = n + r;
  }
  return j;
}
```