ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<build_post_bin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r14
  mov    %rcx,%r12
  mov    (%rsi),%r15
  lea    (%r15,%rcx,1),%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x0(%rbp),%rsi
  test   %rsi,%rsi
  je     L15
  mov    %r15,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
L19:
  mov    (%rbx),%rax
  lea    0x0(%r13,%rax,4),%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    %r12,(%rbx)
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L23
  call   <free@plt>
L23:
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  movq   $0x0,(%rbx)
  jmp    L19
```

assistant: ```c
void build_post_bin(uint8_t **post, size_t *post_len, uint8_t *newdata, size_t datalen) {
  uint8_t *newpost = NULL;
  newpost = malloc((*post_len + datalen) * sizeof(uint8_t));
  if (*post) {
    memcpy(newpost, *post, *post_len);
  } else {
    *post_len = 0;
  }
  memcpy(newpost + *post_len, newdata, datalen);
  *post_len += datalen;
  if (*post)
    free(*post);
  *post = newpost;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<build_post_bin>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%r15
  lea    (%r15,%rcx,1),%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    0x0(%rbp),%rsi
  mov    %rax,%r13
  test   %rsi,%rsi
  je     L4
  mov    %rax,%rdi
  mov    %r15,%rdx
  call   <memcpy@plt>
  mov    (%rbx),%rax
  lea    0x0(%r13,%rax,4),%rdi
L0:
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  mov    0x0(%rbp),%rdi
  add    %r12,(%rbx)
  test   %rdi,%rdi
  je     L28
  call   <free@plt>
L28:
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  movq   $0x0,(%rbx)
  mov    %rax,%rdi
  jmp    L0
```

assistant: ```c
void build_post_bin(uint8_t **post, size_t *post_len, uint8_t *newdata, size_t datalen) {
  uint8_t *newpost = NULL;
  newpost = malloc((*post_len + datalen) * sizeof(uint8_t));
  if (*post) {
    memcpy(newpost, *post, *post_len);
  } else {
    *post_len = 0;
  }
  memcpy(newpost + *post_len, newdata, datalen);
  *post_len += datalen;
  if (*post)
    free(*post);
  *post = newpost;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<build_post_bin>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%r15
  lea    (%r15,%rcx,1),%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    0x0(%rbp),%rsi
  mov    %rax,%r13
  test   %rsi,%rsi
  je     L2
  mov    %rax,%rdi
  mov    %r15,%rdx
  call   <memcpy@plt>
  mov    (%rbx),%rax
  lea    0x0(%r13,%rax,4),%rdi
L26:
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  mov    0x0(%rbp),%rdi
  add    %r12,(%rbx)
  test   %rdi,%rdi
  je     L11
  call   <free@plt>
L11:
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  movq   $0x0,(%rbx)
  mov    %rax,%rdi
  jmp    L26
```

assistant: ```c
void build_post_bin(uint8_t **post, size_t *post_len, uint8_t *newdata, size_t datalen) {
  uint8_t *newpost = NULL;
  newpost = malloc((*post_len + datalen) * sizeof(uint8_t));
  if (*post) {
    memcpy(newpost, *post, *post_len);
  } else {
    *post_len = 0;
  }
  memcpy(newpost + *post_len, newdata, datalen);
  *post_len += datalen;
  if (*post)
    free(*post);
  *post = newpost;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Kit_TruthNand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  not    %edx
  mov    %edx,(%rax)
  subl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void Kit_TruthNand(unsigned *pOut, unsigned *pIn0, unsigned *pIn1, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = ~(pIn0[w] & pIn1[w]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Kit_TruthNand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L14
  cltq
L4:
  mov    0x0(%rbp,%rax,4),%edx
  and    (%r12,%rax,4),%edx
  not    %edx
  mov    %edx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L4
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Kit_TruthNand(unsigned *pOut, unsigned *pIn0, unsigned *pIn1, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = ~(pIn0[w] & pIn1[w]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Kit_TruthNand>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ecx,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L10
  cltq
  nop
L7:
  mov    0x0(%rbp,%rax,4),%ecx
  and    (%r12,%rax,4),%ecx
  not    %ecx
  mov    %ecx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L7
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Kit_TruthNand(unsigned *pOut, unsigned *pIn0, unsigned *pIn1, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = ~(pIn0[w] & pIn1[w]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Kit_TruthNand>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ecx,%edi
  call   <Kit_TruthWordNum@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L6
  movslq %eax,%rcx
  mov    %eax,%esi
  shl    $0x2,%rcx
  lea    -0x4(%rbx,%rcx,1),%rax
  lea    -0x8(%rcx),%r8
  lea    0x0(%rbp,%r8,1),%r9
  mov    %rax,%rdi
  sub    %r9,%rdi
  lea    (%r12,%r8,1),%r9
  add    $0x8,%rdi
  cmp    $0x8,%rdi
  seta   %dil
  sub    %r9,%rax
  add    $0x8,%rax
  cmp    $0x8,%rax
  seta   %al
  test   %al,%dil
  je     L47
  cmp    $0x1,%esi
  je     L47
  mov    %esi,%edi
  cmp    $0x2,%edx
  jbe    L49
  shr    $0x2,%edi
  sub    $0x10,%rcx
  pcmpeqd %xmm2,%xmm2
  xor    %eax,%eax
  neg    %rdi
  lea    0x0(%rbp,%rcx,1),%r10
  lea    (%r12,%rcx,1),%r9
  add    %rbx,%rcx
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L88:
  movdqu (%r10,%rax,1),%xmm3
  movdqu (%r9,%rax,1),%xmm4
  pshufd $0x1b,%xmm3,%xmm0
  pshufd $0x1b,%xmm4,%xmm1
  pand   %xmm1,%xmm0
  pxor   %xmm2,%xmm0
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  sub    $0x10,%rax
  cmp    %rdi,%rax
  jne    L88
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edx
  cmp    %eax,%esi
  je     L6
  sub    %eax,%esi
  mov    %esi,%edi
  cmp    $0x1,%esi
  je     L93
L56:
  neg    %rax
  lea    (%r8,%rax,4),%rax
  movq   0x0(%rbp,%rax,1),%xmm0
  movq   (%r12,%rax,1),%xmm1
  pshufd $0xe1,%xmm0,%xmm0
  pshufd $0xe1,%xmm1,%xmm1
  pand   %xmm1,%xmm0
  movq   D9(%rip),%xmm1
  pxor   %xmm1,%xmm0
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rbx,%rax,1)
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  sub    %eax,%edx
  cmp    %eax,%edi
  je     L6
L93:
  movslq %edx,%rdx
  mov    0x0(%rbp,%rdx,4),%eax
  and    (%r12,%rdx,4),%eax
  not    %eax
  mov    %eax,(%rbx,%rdx,4)
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  movslq %edx,%rax
  nopl   0x0(%rax,%rax,1)
L91:
  mov    0x0(%rbp,%rax,4),%edx
  and    (%r12,%rax,4),%edx
  not    %edx
  mov    %edx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L91
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  xor    %eax,%eax
  jmp    L56
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: byte[8]

tool: {"D9": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

assistant: ```c
void Kit_TruthNand(unsigned *pOut, unsigned *pIn0, unsigned *pIn1, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = ~(pIn0[w] & pIn1[w]);
}
```
user: What is the c source code of the assembly code below:

```asm
<strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L9
  mov    -0x8(%rbp),%rax
  jmp    L15
L9:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L17
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
L15:
  leave
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t size) {
  size_t srclen;
  size_t dstlen;
  dstlen = strlen(dst);
  size -= dstlen + 1;
  if (!size)
    return (dstlen);
  srclen = strlen(src);
  if (srclen > size)
    srclen = size;
  memcpy(dst + dstlen, src, srclen);
  dst[dstlen + srclen] = '\0';
  return (dstlen + srclen);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  call   <strlen@plt>
  lea    -0x1(%rbx),%rdx
  mov    %rdx,%rbx
  sub    %rax,%rbx
  jne    L14
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    %rax,%r13
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  cmova  %rax,%rbx
  lea    0x0(%rbp,%r13,1),%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,1),%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  jmp    L16
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t size) {
  size_t srclen;
  size_t dstlen;
  dstlen = strlen(dst);
  size -= dstlen + 1;
  if (!size)
    return (dstlen);
  srclen = strlen(src);
  if (srclen > size)
    srclen = size;
  memcpy(dst + dstlen, src, srclen);
  dst[dstlen + srclen] = '\0';
  return (dstlen + srclen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlcat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    -0x1(%rbx),%rdx
  mov    %rdx,%rbx
  mov    %rax,%r13
  sub    %rax,%rbx
  je     L5
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%r13,1),%rdi
  mov    %r12,%rsi
  cmp    %rax,%rbx
  cmova  %rax,%rbx
  mov    %rbx,%rdx
  add    %rbx,%r13
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r13,1)
L5:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t size) {
  size_t srclen;
  size_t dstlen;
  dstlen = strlen(dst);
  size -= dstlen + 1;
  if (!size)
    return (dstlen);
  srclen = strlen(src);
  if (srclen > size)
    srclen = size;
  memcpy(dst + dstlen, src, srclen);
  dst[dstlen + srclen] = '\0';
  return (dstlen + srclen);
}
```
user: What is the c source code of the assembly code below?

```asm
<strlcat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    -0x1(%rbx),%rdx
  mov    %rdx,%rbx
  mov    %rax,%r13
  sub    %rax,%rbx
  je     L0
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%r13,1),%rdi
  mov    %r12,%rsi
  cmp    %rax,%rbx
  cmova  %rax,%rbx
  mov    %rbx,%rdx
  add    %rbx,%r13
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r13,1)
L0:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t size) {
  size_t srclen;
  size_t dstlen;
  dstlen = strlen(dst);
  size -= dstlen + 1;
  if (!size)
    return (dstlen);
  srclen = strlen(src);
  if (srclen > size)
    srclen = size;
  memcpy(dst + dstlen, src, srclen);
  dst[dstlen + srclen] = '\0';
  return (dstlen + srclen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edi
  call   <get_value@plt>
  mov    $0x2,%edi
  call   <get_value@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  get_value(3);
  get_value(2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <get_value@plt>
  mov    $0x2,%edi
  call   <get_value@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  get_value(3);
  get_value(2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <get_value@plt>
  mov    $0x2,%edi
  call   <get_value@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  get_value(3);
  get_value(2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mus_bdouble_to_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x7(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x6(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x5(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x4(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x5(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x7(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mus_bdouble_to_char(unsigned char *j, double x) {
  unsigned char *ox = (unsigned char *)&x;
  j[0] = ox[7];
  j[1] = ox[6];
  j[2] = ox[5];
  j[3] = ox[4];
  j[4] = ox[3];
  j[5] = ox[2];
  j[6] = ox[1];
  j[7] = ox[0];
}
```
user: What is the c source code of the assembly code below:

```asm
<mus_bdouble_to_char>:
  endbr64
  movq   %xmm0,%rax
  movq   %xmm0,%rdx
  shr    $0x38,%rdx
  mov    %dl,(%rdi)
  movq   %xmm0,%rdx
  shr    $0x30,%rdx
  mov    %dl,0x1(%rdi)
  movq   %xmm0,%rdx
  shr    $0x28,%rdx
  mov    %dl,0x2(%rdi)
  movq   %xmm0,%rdx
  shr    $0x20,%rdx
  mov    %dl,0x3(%rdi)
  movq   %xmm0,%rdx
  shr    $0x18,%rdx
  mov    %dl,0x4(%rdi)
  movq   %xmm0,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x5(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rdi)
  mov    %al,0x7(%rdi)
  ret
```

assistant: ```c
void mus_bdouble_to_char(unsigned char *j, double x) {
  unsigned char *ox = (unsigned char *)&x;
  j[0] = ox[7];
  j[1] = ox[6];
  j[2] = ox[5];
  j[3] = ox[4];
  j[4] = ox[3];
  j[5] = ox[2];
  j[6] = ox[1];
  j[7] = ox[0];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mus_bdouble_to_char>:
  endbr64
  movq   %xmm0,%rdx
  movq   %xmm0,%rax
  shr    $0x38,%rdx
  mov    %ah,0x6(%rdi)
  mov    %dl,(%rdi)
  movq   %xmm0,%rdx
  shr    $0x30,%rdx
  mov    %al,0x7(%rdi)
  mov    %dl,0x1(%rdi)
  movq   %xmm0,%rdx
  shr    $0x28,%rdx
  mov    %dl,0x2(%rdi)
  movq   %xmm0,%rdx
  shr    $0x20,%rdx
  mov    %dl,0x3(%rdi)
  movq   %xmm0,%rdx
  shr    $0x18,%rdx
  mov    %dl,0x4(%rdi)
  movq   %xmm0,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x5(%rdi)
  ret
```

assistant: ```c
void mus_bdouble_to_char(unsigned char *j, double x) {
  unsigned char *ox = (unsigned char *)&x;
  j[0] = ox[7];
  j[1] = ox[6];
  j[2] = ox[5];
  j[3] = ox[4];
  j[4] = ox[3];
  j[5] = ox[2];
  j[6] = ox[1];
  j[7] = ox[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<mus_bdouble_to_char>:
  endbr64
  movq   %xmm0,%rdx
  push   %rbx
  movq   %xmm0,%r10
  movq   %xmm0,%r9
  movzbl %dl,%eax
  movzbl %dh,%ebx
  shr    $0x10,%r10
  movq   %xmm0,%r8
  shl    $0x8,%rax
  movzbl %r10b,%r10d
  shr    $0x18,%r9
  movq   %xmm0,%rsi
  or     %rbx,%rax
  movzbl %r9b,%r9d
  shr    $0x20,%r8
  movq   %xmm0,%rcx
  shl    $0x8,%rax
  movzbl %r8b,%r8d
  shr    $0x28,%rsi
  pop    %rbx
  shr    $0x30,%rcx
  or     %r10,%rax
  movzbl %sil,%esi
  shr    $0x38,%rdx
  shl    $0x8,%rax
  movzbl %cl,%ecx
  or     %r9,%rax
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void mus_bdouble_to_char(unsigned char *j, double x) {
  unsigned char *ox = (unsigned char *)&x;
  j[0] = ox[7];
  j[1] = ox[6];
  j[2] = ox[5];
  j[3] = ox[4];
  j[4] = ox[3];
  j[5] = ox[2];
  j[6] = ox[1];
  j[7] = ox[0];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L18:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen1(const char *s) {
  size_t len = 0;
  while (s[len])
    len++;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen1>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
  mov    $0x0,%eax
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L13
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen1(const char *s) {
  size_t len = 0;
  while (s[len])
    len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlen1>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L0
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
size_t strlen1(const char *s) {
  size_t len = 0;
  while (s[len])
    len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen1>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L8
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L11
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
size_t strlen1(const char *s) {
  size_t len = 0;
  while (s[len])
    len++;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L7:
  cmpl   $0x2f,-0x4(%rbp)
  jle    L43
  cmpl   $0x39,-0x4(%rbp)
  jle    L18
L43:
  mov    $0xffffffff,%eax
  jmp    L49
L18:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L31:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    -0x8(%rbp),%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int atoi(p)
char *p;
{
  int c, n;
  n = 0;
  while (c = *p++) {
    if (c < '0' || c > '9')
      return (-1);
    n = 10 * n + (c - '0');
  }
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atoi>:
  endbr64
  lea    0x1(%rdi),%rsi
  movzbl (%rdi),%eax
  movsbl %al,%ecx
  test   %ecx,%ecx
  je     L38
  mov    $0x0,%edx
L27:
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L33
  lea    (%rdx,%rdx,4),%eax
  lea    -0x30(%rcx,%rax,2),%edx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  movsbl %al,%ecx
  test   %ecx,%ecx
  jne    L27
  jmp    L1
L38:
  mov    %ecx,%edx
  jmp    L1
L33:
  mov    $0xffffffff,%edx
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
int atoi(p)
char *p;
{
  int c, n;
  n = 0;
  while (c = *p++) {
    if (c < '0' || c > '9')
      return (-1);
    n = 10 * n + (c - '0');
  }
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  test   %eax,%eax
  jne    L35
  jmp    L7
  nopl   0x0(%rax)
L3:
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  lea    (%rax,%rcx,2),%r8d
  movsbl -0x1(%rdx),%eax
  test   %eax,%eax
  je     L7
L35:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L3
  mov    $0xffffffff,%r8d
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(p)
char *p;
{
  int c, n;
  n = 0;
  while (c = *p++) {
    if (c < '0' || c > '9')
      return (-1);
    n = 10 * n + (c - '0');
  }
  return (n);
}
```
user: What is the c source code of the assembly code below?

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  test   %eax,%eax
  jne    L25
  jmp    L19
  nopl   0x0(%rax)
L29:
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  lea    (%rax,%rcx,2),%r8d
  movsbl -0x1(%rdx),%eax
  test   %eax,%eax
  je     L19
L25:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L29
  mov    $0xffffffff,%r8d
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(p)
char *p;
{
  int c, n;
  n = 0;
  while (c = *p++) {
    if (c < '0' || c > '9')
      return (-1);
    n = 10 * n + (c - '0');
  }
  return (n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_reverse_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L14
  mov    -0x4(%rbp),%eax
  shr    $0x1f,%eax
  jmp    L12
L14:
  mov    $0xffffffff,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int int_reverse_cmp(const void *a, const void *b) {
  int c = ((int *)a)[1] - ((int *)b)[1];
  return c > 0 ? -1 : (c < 0 ? 1 : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_reverse_cmp>:
  endbr64
  mov    0x4(%rdi),%edx
  sub    0x4(%rsi),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int int_reverse_cmp(const void *a, const void *b) {
  int c = ((int *)a)[1] - ((int *)b)[1];
  return c > 0 ? -1 : (c < 0 ? 1 : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<int_reverse_cmp>:
  endbr64
  mov    0x4(%rdi),%edx
  sub    0x4(%rsi),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int int_reverse_cmp(const void *a, const void *b) {
  int c = ((int *)a)[1] - ((int *)b)[1];
  return c > 0 ? -1 : (c < 0 ? 1 : 0);
}
```