ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<calcFA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm2
  movsd  D30(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D24(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D24(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: byte[8]
name: retrieve_data
arguments: data_tag: D33
type: byte[8]
name: retrieve_data
arguments: data_tag: D30
type: byte[8]
name: retrieve_data
arguments: data_tag: D24
type: f32[2]

tool: {"D18": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xf2,0xbc]}

tool: {"D33": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xfb,0x3d]}

tool: {"D30": [0x69,0x1d,0x55,0x4d,0x10,0x75,0xff,0x3e]}

tool: {"D24": [0.0,1.875]}

assistant: ```c
double calcFA(double Altitude) {
  double fa = 0;
  fa = -4e-15 * pow(Altitude, 3) + 4e-10 * pow(Altitude, 2) - 3e-5 * Altitude + 1;
  return (1 / fa);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calcFA>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  mov    $0x3,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  mov    $0x2,%edi
  movq   %rbx,%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  mulsd  D12(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D38(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %rbx,%xmm0
  mulsd  D17(%rip),%xmm0
  subsd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: byte[8]
name: read_data
arguments: data_tag: D38
type_guessed: byte[8]
name: read_data
arguments: data_tag: D17
type_guessed: byte[8]
name: read_data
arguments: data_tag: D14
type_guessed: f32[2]

tool: {"D12": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xf2,0xbc]}

tool: {"D38": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xfb,0x3d]}

tool: {"D17": [0x69,0x1d,0x55,0x4d,0x10,0x75,0xff,0x3e]}

tool: {"D14": [0.0,1.875]}

assistant: ```c
double calcFA(double Altitude) {
  double fa = 0;
  fa = -4e-15 * pow(Altitude, 3) + 4e-10 * pow(Altitude, 2) - 3e-5 * Altitude + 1;
  return (1 / fa);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calcFA>:
  endbr64
  push   %rbx
  mov    $0x3,%edi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %ebx,%xmm1
  mulsd  D1(%rip),%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  D13(%rip),%xmm2
  mulsd  D9(%rip),%xmm0
  addsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  movsd  D18(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: byte[8]
name: unpack_data
arguments: tag: D13
type_guessed: byte[8]
name: unpack_data
arguments: tag: D9
type_guessed: byte[8]
name: unpack_data
arguments: tag: D18
type_guessed: f32[2]

tool: {"D1": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xf2,0xbc]}

tool: {"D13": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xfb,0x3d]}

tool: {"D9": [0x69,0x1d,0x55,0x4d,0x10,0x75,0xff,0x3e]}

tool: {"D18": [0.0,1.875]}

assistant: ```c
double calcFA(double Altitude) {
  double fa = 0;
  fa = -4e-15 * pow(Altitude, 3) + 4e-10 * pow(Altitude, 2) - 3e-5 * Altitude + 1;
  return (1 / fa);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcFA>:
  endbr64
  push   %rbx
  mov    $0x3,%edi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %ebx,%xmm1
  mulsd  D10(%rip),%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  D37(%rip),%xmm2
  mulsd  D26(%rip),%xmm0
  addsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  movsd  D33(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: byte[8]
name: parse_data
arguments: tag: D37
data_type: byte[8]
name: parse_data
arguments: tag: D26
data_type: byte[8]
name: parse_data
arguments: tag: D33
data_type: f32[2]

tool: {"D10": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xf2,0xbc]}

tool: {"D37": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xfb,0x3d]}

tool: {"D26": [0x69,0x1d,0x55,0x4d,0x10,0x75,0xff,0x3e]}

tool: {"D33": [0.0,1.875]}

assistant: ```c
double calcFA(double Altitude) {
  double fa = 0;
  fa = -4e-15 * pow(Altitude, 3) + 4e-10 * pow(Altitude, 2) - 3e-5 * Altitude + 1;
  return (1 / fa);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%edx
  sub    $0x25,%edx
  movzbl %dl,%eax
  test   $0x1,%dl
  je     L48
  mov    %edx,%ecx
  shr    $0x2,%cl
  test   $0x4,%dl
  je     L33
  test   $0x8,%dl
  je     L50
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  jmp    L18
L50:
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%dl
  lea    (%rdx,%rdx,1),%eax
  jmp    L18
L33:
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
  movzbl %al,%edx
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  shl    $0x3,%edx
  or     %edx,%eax
  jmp    L18
L48:
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %eax,%edx
  movzbl %dl,%eax
  imul   %eax,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
L18:
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
        } else {
          state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)2) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)2) & (unsigned char)15) | 1UL)));
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        state[0UL] |= ((state[0UL] << ((state[0UL] & (unsigned char)7) | 1UL)) & (unsigned char)31) << 3UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)15) << 3UL;
    }
    output[0UL] = (state[0UL] >> (unsigned char)3) | (state[0UL] << (unsigned char)5);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%edx
  sub    $0x25,%edx
  movzbl %dl,%eax
  test   $0x1,%dl
  je     L6
  mov    %edx,%ecx
  shr    $0x2,%cl
  test   $0x4,%dl
  je     L5
  test   $0x8,%dl
  je     L8
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %eax,%edx
  movzbl %dl,%eax
  imul   %eax,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
  nopl   0x0(%rax)
L5:
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
  mov    %eax,%ecx
  movzbl %al,%edx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  shl    $0x3,%edx
  or     %edx,%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
L8:
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%dl
  lea    (%rdx,%rdx,1),%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
        } else {
          state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)2) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)2) & (unsigned char)15) | 1UL)));
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        state[0UL] |= ((state[0UL] << ((state[0UL] & (unsigned char)7) | 1UL)) & (unsigned char)31) << 3UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)15) << 3UL;
    }
    output[0UL] = (state[0UL] >> (unsigned char)3) | (state[0UL] << (unsigned char)5);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%edx
  sub    $0x25,%edx
  movzbl %dl,%eax
  test   $0x1,%dl
  je     L29
  mov    %edx,%ecx
  shr    $0x2,%cl
  test   $0x4,%dl
  je     L19
  test   $0x8,%dl
  je     L11
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %eax,%edx
  movzbl %dl,%eax
  imul   %eax,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
  nopl   0x0(%rax)
L19:
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edx,%eax
  mov    %eax,%ecx
  movzbl %al,%edx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  shl    $0x3,%edx
  or     %edx,%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
L11:
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%dl
  lea    (%rdx,%rdx,1),%eax
  ror    $0x3,%al
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
          state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
        } else {
          state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)2) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)2) & (unsigned char)15) | 1UL)));
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
        state[0UL] |= ((state[0UL] << ((state[0UL] & (unsigned char)7) | 1UL)) & (unsigned char)31) << 3UL;
      }
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)15) << 3UL;
    }
    output[0UL] = (state[0UL] >> (unsigned char)3) | (state[0UL] << (unsigned char)5);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  cmpl   $0x3,-0x8(%rbp)
  jle    L4
  mov    $0x4,%eax
  jmp    L2
L4:
  mov    $0x6,%eax
L2:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 3;
  int b = a > 3 ? 1 < 2 ? 4 : 5 : 3 < 4 ? 6 : 7;
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int main() {
  int a = 3;
  int b = a > 3 ? 1 < 2 ? 4 : 5 : 3 < 4 ? 6 : 7;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int main() {
  int a = 3;
  int b = a > 3 ? 1 < 2 ? 4 : 5 : 3 < 4 ? 6 : 7;
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int main() {
  int a = 3;
  int b = a > 3 ? 1 < 2 ? 4 : 5 : 3 < 4 ? 6 : 7;
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <removeElement@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L8
L27:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L8:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string

tool: D2: %d


tool: D4: %d 

assistant: ```c
int main(void) {
  int nums[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6};
  int len = removeElement(nums, 10, 1);
  printf("%d\n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x4,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  movl   $0x5,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%edx
  mov    $0xa,%esi
  call   <removeElement@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L27
  mov    %rsp,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%rsp,%rax,4),%r12
  lea    D2(%rip),%rbp
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L9
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D13: %d


tool: D2: %d 

assistant: ```c
int main(void) {
  int nums[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6};
  int len = removeElement(nums, 10, 1);
  printf("%d\n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  mov    $0x1,%edx
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x400000004,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x20(%rsp)
  call   <removeElement@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  lea    -0x1(%rbp),%eax
  lea    D11(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  xchg   %ax,%ax
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string

tool: D16: %d


tool: D11: %d 

assistant: ```c
int main(void) {
  int nums[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6};
  int len = removeElement(nums, 10, 1);
  printf("%d\n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  mov    $0x1,%edx
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D29(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D48(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D10(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <removeElement@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L7
  lea    -0x1(%rbp),%eax
  lea    D27(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L29
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
datatype: byte[16]
name: read_data
arguments: label: D48
datatype: byte[8]
name: read_data
arguments: label: D10
datatype: byte[16]
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D27
datatype: string

tool: {"D29": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D48": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D10": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D25: %d


tool: D27: %d 

assistant: ```c
int main(void) {
  int nums[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6};
  int len = removeElement(nums, 10, 1);
  printf("%d\n", len);
  for (int i = 0; i < len; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<fprintStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void fprintStr(FILE *fp, char *szStr) {
  int i;
  for (i = 0; i < (int)strlen(szStr); i++)
    fputc(szStr[i], fp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fprintStr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  jmp    L17
L15:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  add    $0x1,%rbx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fprintStr(FILE *fp, char *szStr) {
  int i;
  for (i = 0; i < (int)strlen(szStr); i++)
    fputc(szStr[i], fp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fprintStr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L3:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fprintStr(FILE *fp, char *szStr) {
  int i;
  for (i = 0; i < (int)strlen(szStr); i++)
    fputc(szStr[i], fp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fprintStr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L12:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fprintStr(FILE *fp, char *szStr) {
  int i;
  for (i = 0; i < (int)strlen(szStr); i++)
    fputc(szStr[i], fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D4(%rip),%ecx
  mov    $0x1f4,%eax
  cltd
  idiv   %ecx
  mov    %eax,D17(%rip)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func4() {
  static int multiple_static_locals = 0, msl2, msl3 = 10;
  msl2 = 500 / msl3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func4>:
  endbr64
  ret
```

assistant: ```c
void func4() {
  static int multiple_static_locals = 0, msl2, msl3 = 10;
  msl2 = 500 / msl3;
}
```
user: What is the c source code of the assembly code below:

```asm
<func4>:
  endbr64
  ret
```

assistant: ```c
void func4() {
  static int multiple_static_locals = 0, msl2, msl3 = 10;
  msl2 = 500 / msl3;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func4>:
  endbr64
  ret
```

assistant: ```c
void func4() {
  static int multiple_static_locals = 0, msl2, msl3 = 10;
  msl2 = 500 / msl3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printout_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    $0xf423f,%eax
  jle    L12
  mov    $0x1,%eax
  jmp    L20
L12:
  cmpl   $0x0,-0x4(%rbp)
  jns    L5
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  negl   -0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <printout_number_under1000000@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string

tool: D2: minus 

tool: D16: 


assistant: ```c
int printout_number(int N) {
  if (((N) > 0 ? (N) : -(N)) >= 1000000)
    return 1;
  if (N < 0) {
    printf("minus ");
    N = -N;
  }
  printout_number_under1000000(N, 1);
  printf("\n");
  return 0;
}
```