ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ExtendString>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rbp
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  add    $0x400,%esi
  call   <Realloc@plt>
  mov    %rax,(%r14)
  mov    %rax,%rbp
  addl   $0x400,(%r12)
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    (%r12),%esi
  add    %eax,%ebx
  cmp    %esi,%ebx
  jge    L1
  pop    %rbx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <strcat@plt>
```

assistant: ```c
void ExtendString(char **ToExtend, char *ByThis, int *AllocatedLength) {
  while ((int)strlen(*ToExtend) + (int)strlen(ByThis) + 1 > *AllocatedLength) {
    *ToExtend = (char *)Realloc((void *)*ToExtend, *AllocatedLength + 1024);
    *AllocatedLength += 1024;
  }
  strcat(*ToExtend, ByThis);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<backup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  lea    -0x70(%rbp),%rax
  add    %rdx,%rax
  movw   $0x7e,(%rax)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <unlink@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <rename@plt>
  nop
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
backup(name) register char *name;
{
  char back[80];
  char *p;
  strcpy(back, name);
  strcat(back, "~");
  unlink(back);
  rename(name, back);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<backup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movw   $0x7e,(%rbx,%rax,1)
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <unlink@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <rename@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
backup(name) register char *name;
{
  char back[80];
  char *p;
  strcpy(back, name);
  strcat(back, "~");
  unlink(back);
  rename(name, back);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<backup>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x7e,%edx
  mov    %rbp,%rdi
  mov    %dx,0x0(%rbp,%rax,1)
  xor    %eax,%eax
  call   <unlink@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <rename@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
backup(name) register char *name;
{
  char back[80];
  char *p;
  strcpy(back, name);
  strcat(back, "~");
  unlink(back);
  rename(name, back);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<backup>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x7e,%edx
  mov    %rbp,%rdi
  mov    %dx,0x0(%rbp,%rax,1)
  xor    %eax,%eax
  call   <unlink@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <rename@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
backup(name) register char *name;
{
  char back[80];
  char *p;
  strcpy(back, name);
  strcat(back, "~");
  unlink(back);
  rename(name, back);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<distance_client>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  add    %edx,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L2
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L2:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: f64

tool: D0: 0.0625

assistant: ```c
int distance_client(int dx, int dy) {
  double temp_dist = sqrt((double)(dx * dx + dy * dy));
  temp_dist -= 0.0625;
  if (temp_dist < 0)
    temp_dist = 0;
  return ((int)temp_dist);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<distance_client>:
  endbr64
  sub    $0x8,%rsp
  imul   %edi,%edi
  imul   %esi,%esi
  add    %esi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L39
  sqrtsd %xmm0,%xmm0
L8:
  subsd  D7(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L13
L19:
  cvttsd2si %xmm0,%eax
  add    $0x8,%rsp
  ret
L39:
  call   <sqrt@plt>
  jmp    L8
L13:
  movapd %xmm1,%xmm0
  jmp    L19
```

tool_calls: name: parse_data
arguments: label: D7
datatype: f64

tool: D7: 0.0625

assistant: ```c
int distance_client(int dx, int dy) {
  double temp_dist = sqrt((double)(dx * dx + dy * dy));
  temp_dist -= 0.0625;
  if (temp_dist < 0)
    temp_dist = 0;
  return ((int)temp_dist);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<distance_client>:
  endbr64
  imul   %edi,%edi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sub    $0x8,%rsp
  imul   %esi,%esi
  add    %esi,%edi
  cvtsi2sd %edi,%xmm0
  ucomisd %xmm0,%xmm1
  ja     L10
  sqrtsd %xmm0,%xmm0
L14:
  subsd  D9(%rip),%xmm0
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L13
  cvttsd2si %xmm0,%eax
L13:
  add    $0x8,%rsp
  ret
L10:
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: f64

tool: D9: 0.0625

assistant: ```c
int distance_client(int dx, int dy) {
  double temp_dist = sqrt((double)(dx * dx + dy * dy));
  temp_dist -= 0.0625;
  if (temp_dist < 0)
    temp_dist = 0;
  return ((int)temp_dist);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<distance_client>:
  endbr64
  imul   %edi,%edi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sub    $0x8,%rsp
  imul   %esi,%esi
  add    %esi,%edi
  cvtsi2sd %edi,%xmm0
  ucomisd %xmm0,%xmm1
  ja     L20
  sqrtsd %xmm0,%xmm0
L5:
  subsd  D8(%rip),%xmm0
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L13
  cvttsd2si %xmm0,%eax
L13:
  add    $0x8,%rsp
  ret
L20:
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  jmp    L5
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: f64

tool: D8: 0.0625

assistant: ```c
int distance_client(int dx, int dy) {
  double temp_dist = sqrt((double)(dx * dx + dy * dy));
  temp_dist -= 0.0625;
  if (temp_dist < 0)
    temp_dist = 0;
  return ((int)temp_dist);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L2
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L16
L2:
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int *tmp;
  {
    if (x) {
      tmp = &y;
    } else {
      tmp = &z;
    }
    x++;
    return ((int)(tmp - &x));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  cmpl   $0x0,0xc(%rsp)
  jne    L7
  lea    0x14(%rsp),%rax
L7:
  lea    0xc(%rsp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int *tmp;
  {
    if (x) {
      tmp = &y;
    } else {
      tmp = &z;
    }
    x++;
    return ((int)(tmp - &x));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L3
  lea    0x14(%rsp),%rax
L12:
  lea    0xc(%rsp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x28,%rsp
  ret
L3:
  lea    0x10(%rsp),%rax
  jmp    L12
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int *tmp;
  {
    if (x) {
      tmp = &y;
    } else {
      tmp = &z;
    }
    x++;
    return ((int)(tmp - &x));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L8
  lea    0x14(%rsp),%rax
L7:
  lea    0xc(%rsp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x28,%rsp
  ret
L8:
  lea    0x10(%rsp),%rax
  jmp    L7
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int *tmp;
  {
    if (x) {
      tmp = &y;
    } else {
      tmp = &z;
    }
    x++;
    return ((int)(tmp - &x));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sw_one_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <assert_int_equal@plt>
  mov    $0x4081020,%esi
  mov    $0x4081020,%edi
  call   <assert_int_equal@plt>
  nop
  leave
  ret
```

assistant: ```c
void sw_one_test(void **state) {
  assert_int_equal((((0x200ul) >> 9) & ~0x8080808080808080ul), 1ul);
  assert_int_equal((((0x0102040810204080ul) >> 9) & ~0x8080808080808080ul), 0x0000010204081020ul);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sw_one_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <assert_int_equal@plt>
  mov    $0x4081020,%esi
  mov    $0x4081020,%edi
  call   <assert_int_equal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sw_one_test(void **state) {
  assert_int_equal((((0x200ul) >> 9) & ~0x8080808080808080ul), 1ul);
  assert_int_equal((((0x0102040810204080ul) >> 9) & ~0x8080808080808080ul), 0x0000010204081020ul);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sw_one_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <assert_int_equal@plt>
  mov    $0x4081020,%esi
  mov    $0x4081020,%edi
  add    $0x8,%rsp
  jmp    1050 <assert_int_equal@plt>
```

assistant: ```c
void sw_one_test(void **state) {
  assert_int_equal((((0x200ul) >> 9) & ~0x8080808080808080ul), 1ul);
  assert_int_equal((((0x0102040810204080ul) >> 9) & ~0x8080808080808080ul), 0x0000010204081020ul);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sw_one_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <assert_int_equal@plt>
  mov    $0x4081020,%esi
  mov    $0x4081020,%edi
  add    $0x8,%rsp
  jmp    1050 <assert_int_equal@plt>
```

assistant: ```c
void sw_one_test(void **state) {
  assert_int_equal((((0x200ul) >> 9) & ~0x8080808080808080ul), 1ul);
  assert_int_equal((((0x0102040810204080ul) >> 9) & ~0x8080808080808080ul), 0x0000010204081020ul);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rle4b_unpackVRam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x3c(%rbp)
  mov    $0x2,%edi
  call   <VDP_setAutoInc@plt>
  movq   $0xc00004,-0x18(%rbp)
  movq   $0xc00000,-0x10(%rbp)
  movzwl -0x3c(%rbp),%eax
  and    $0x3fff,%eax
  add    $0x4000,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  movzwl -0x3c(%rbp),%eax
  shr    $0xe,%ax
  movzwl %ax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x2e(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movw   $0x7,-0x2c(%rbp)
  jmp    L24
L38:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x2f(%rbp)
  movzbl -0x2f(%rbp),%eax
  and    $0xf,%eax
  mov    %rax,-0x8(%rbp)
  movzbl -0x2f(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  add    $0x1,%eax
  mov    %ax,-0x2a(%rbp)
  jmp    L0
L21:
  shlq   $0x4,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  or     %rax,-0x20(%rbp)
  movzwl -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x2c(%rbp)
  test   %ax,%ax
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  movw   $0x7,-0x2c(%rbp)
L0:
  movzwl -0x2a(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x2a(%rbp)
  test   %ax,%ax
  jne    L21
L24:
  movzwl -0x2e(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x2e(%rbp)
  test   %ax,%ax
  jne    L38
  nop
  nop
  leave
  ret
```

assistant: ```c
void rle4b_unpackVRam(unsigned char *src, unsigned short dest) {
  volatile unsigned long *plctrl;
  volatile unsigned long *pldata;
  unsigned char *s;
  unsigned long data;
  unsigned short blocnum;
  unsigned short data_cnt;
  VDP_setAutoInc(2);
  plctrl = (unsigned long *)0xC00004;
  pldata = (unsigned long *)0xC00000;
  *plctrl = ((0x4000 + ((dest)&0x3FFF)) << 16) + (((dest) >> 14) | 0x00);
  blocnum = *((unsigned short *)src);
  s = src + 2;
  data = 0;
  data_cnt = 7;
  while (blocnum--) {
    const unsigned char v8 = *s++;
    const unsigned long d4 = v8 & 0xF;
    unsigned short len = (v8 >> 4) + 1;
    while (len--) {
      data <<= 4;
      data |= d4;
      if (!data_cnt--) {
        *pldata = data;
        data_cnt = 7;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rle4b_unpackVRam>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x2,%edi
  call   <VDP_setAutoInc@plt>
  mov    %ebp,%eax
  and    $0x3fff,%ax
  add    $0x4000,%ax
  shl    $0x10,%eax
  shr    $0xe,%bp
  movzwl %bp,%edx
  add    %edx,%eax
  cltq
  mov    %rax,0xc00004
  movzwl (%rbx),%edx
  test   %dx,%dx
  je     L30
  lea    0x2(%rbx),%rdi
  lea    -0x1(%rdx),%eax
  movzwl %ax,%eax
  lea    0x3(%rbx,%rax,1),%r8
  mov    $0x7,%ecx
  mov    $0x0,%eax
  jmp    L2
L21:
  mov    %rax,0xc00000
  mov    $0x7,%ecx
L20:
  sub    $0x1,%edx
  cmp    $0xffff,%dx
  je     L49
L55:
  shl    $0x4,%rax
  or     %rsi,%rax
  test   %cx,%cx
  je     L21
  sub    $0x1,%ecx
  jmp    L20
L49:
  cmp    %r8,%rdi
  je     L30
L2:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  mov    %rdx,%rsi
  and    $0xf,%esi
  shr    $0x4,%dl
  movzbl %dl,%edx
  jmp    L55
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rle4b_unpackVRam(unsigned char *src, unsigned short dest) {
  volatile unsigned long *plctrl;
  volatile unsigned long *pldata;
  unsigned char *s;
  unsigned long data;
  unsigned short blocnum;
  unsigned short data_cnt;
  VDP_setAutoInc(2);
  plctrl = (unsigned long *)0xC00004;
  pldata = (unsigned long *)0xC00000;
  *plctrl = ((0x4000 + ((dest)&0x3FFF)) << 16) + (((dest) >> 14) | 0x00);
  blocnum = *((unsigned short *)src);
  s = src + 2;
  data = 0;
  data_cnt = 7;
  while (blocnum--) {
    const unsigned char v8 = *s++;
    const unsigned long d4 = v8 & 0xF;
    unsigned short len = (v8 >> 4) + 1;
    while (len--) {
      data <<= 4;
      data |= d4;
      if (!data_cnt--) {
        *pldata = data;
        data_cnt = 7;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rle4b_unpackVRam>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x2,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <VDP_setAutoInc@plt>
  mov    %ebx,%eax
  shr    $0xe,%bx
  and    $0x3fff,%ax
  movzwl %bx,%edx
  add    $0x4000,%ax
  shl    $0x10,%eax
  add    %edx,%eax
  movzwl 0x0(%rbp),%edx
  cltq
  mov    %rax,0xc00004
  test   %dx,%dx
  je     L58
  lea    -0x1(%rdx),%eax
  lea    0x2(%rbp),%rdi
  mov    $0x7,%ecx
  movzwl %ax,%eax
  lea    0x3(%rbp,%rax,1),%r8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %rdx,%rsi
  shr    $0x4,%dl
  add    $0x1,%edx
  and    $0xf,%esi
  movzbl %dl,%edx
  sub    $0x1,%edx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L54:
  sub    $0x1,%edx
  sub    $0x1,%ecx
  cmp    $0xffff,%dx
  je     L52
L19:
  shl    $0x4,%rax
  or     %rsi,%rax
  test   %cx,%cx
  jne    L54
  sub    $0x1,%edx
  mov    %rax,0xc00000
  mov    $0x7,%ecx
  cmp    $0xffff,%dx
  jne    L19
L52:
  cmp    %r8,%rdi
  jne    L18
L58:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rle4b_unpackVRam(unsigned char *src, unsigned short dest) {
  volatile unsigned long *plctrl;
  volatile unsigned long *pldata;
  unsigned char *s;
  unsigned long data;
  unsigned short blocnum;
  unsigned short data_cnt;
  VDP_setAutoInc(2);
  plctrl = (unsigned long *)0xC00004;
  pldata = (unsigned long *)0xC00000;
  *plctrl = ((0x4000 + ((dest)&0x3FFF)) << 16) + (((dest) >> 14) | 0x00);
  blocnum = *((unsigned short *)src);
  s = src + 2;
  data = 0;
  data_cnt = 7;
  while (blocnum--) {
    const unsigned char v8 = *s++;
    const unsigned long d4 = v8 & 0xF;
    unsigned short len = (v8 >> 4) + 1;
    while (len--) {
      data <<= 4;
      data |= d4;
      if (!data_cnt--) {
        *pldata = data;
        data_cnt = 7;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rle4b_unpackVRam>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x2,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <VDP_setAutoInc@plt>
  mov    %ebx,%eax
  shr    $0xe,%bx
  and    $0x3fff,%ax
  movzwl %bx,%edx
  add    $0x4000,%ax
  shl    $0x10,%eax
  add    %edx,%eax
  movzwl 0x0(%rbp),%edx
  cltq
  mov    %rax,0xc00004
  test   %dx,%dx
  je     L5
  lea    -0x1(%rdx),%eax
  lea    0x2(%rbp),%rdi
  mov    $0x7,%ecx
  movzwl %ax,%eax
  lea    0x3(%rbp,%rax,1),%r8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %rdx,%rsi
  shr    $0x4,%dl
  add    $0x1,%edx
  and    $0xf,%esi
  movzbl %dl,%edx
  sub    $0x1,%edx
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%edx
  sub    $0x1,%ecx
  cmp    $0xffff,%dx
  je     L12
L32:
  shl    $0x4,%rax
  or     %rsi,%rax
  test   %cx,%cx
  jne    L2
  sub    $0x1,%edx
  mov    %rax,0xc00000
  mov    $0x7,%ecx
  cmp    $0xffff,%dx
  jne    L32
L12:
  cmp    %r8,%rdi
  jne    L3
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rle4b_unpackVRam(unsigned char *src, unsigned short dest) {
  volatile unsigned long *plctrl;
  volatile unsigned long *pldata;
  unsigned char *s;
  unsigned long data;
  unsigned short blocnum;
  unsigned short data_cnt;
  VDP_setAutoInc(2);
  plctrl = (unsigned long *)0xC00004;
  pldata = (unsigned long *)0xC00000;
  *plctrl = ((0x4000 + ((dest)&0x3FFF)) << 16) + (((dest) >> 14) | 0x00);
  blocnum = *((unsigned short *)src);
  s = src + 2;
  data = 0;
  data_cnt = 7;
  while (blocnum--) {
    const unsigned char v8 = *s++;
    const unsigned long d4 = v8 & 0xF;
    unsigned short len = (v8 >> 4) + 1;
    while (len--) {
      data <<= 4;
      data |= d4;
      if (!data_cnt--) {
        *pldata = data;
        data_cnt = 7;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %edi,-0x134(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D72(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x120(%rbp)
  cmpq   $0x0,-0x120(%rbp)
  jne    L3
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L54
L3:
  lea    D62(%rip),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L17
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L54
L17:
  movl   $0x0,-0x128(%rbp)
  lea    -0x128(%rbp),%rdx
  mov    -0x120(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  jmp    L43
L16:
  lea    -0x110(%rbp),%rcx
  mov    -0x120(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  lea    -0x90(%rbp),%rcx
  mov    -0x120(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strindex@plt>
  mov    %eax,-0x124(%rbp)
  mov    -0x124(%rbp),%esi
  lea    -0x90(%rbp),%rcx
  lea    -0x110(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  mov    %esi,%r8d
  lea    D52(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
L43:
  mov    -0x128(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x128(%rbp)
  test   %eax,%eax
  jne    L16
  mov    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L54:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D72
type: string
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D62
type: string
name: parse_data
arguments: tag: D68
type: string
name: parse_data
arguments: tag: D4
type: string
name: parse_data
arguments: tag: D52
type: string

tool: D72: r

tool: D8: input.dat

tool: D62: w

tool: D68: output.dat

tool: D4: %d

tool: D52: strindex(
'%s', 
'%s')
	 is %d



assistant: ```c
int main(int argc, char *argv[]) {
  FILE *in, *out;
  in = fopen("input.dat", "r");
  if (in == NULL) {
    perror("input.dat");
    return 1;
  }
  out = fopen("output.dat", "w");
  if (out == NULL) {
    perror("output.dat");
    return 1;
  }
  char s[128], t[128];
  int i;
  int n = 0;
  fscanf(in, "%d", &n);
  fgetc(in);
  while (n--) {
    getline(in, s, 128);
    getline(in, t, 128);
    i = strindex(s, t);
    fprintf(out, "strindex(\n'%s', \n'%s')\n\t is %d\n\n", s, t, i);
  }
  fclose(in);
  fclose(out);
  return 0;
}
```