ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  mov    %rdi,%r8
  mov    %rdi,%rcx
  test   $0x7,%dil
  jne    L31
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L74:
  add    $0x1,%rcx
  test   $0x7,%cl
  je     L25
L31:
  cmpb   $0x0,(%rcx)
  jne    L74
  mov    %rcx,%rax
  sub    %r8,%rax
  ret
  nopl   (%rax)
L25:
  mov    D6(%rip),%rax
  xor    %edx,%edx
  mov    (%rcx),%rsi
  mov    (%rax),%rdi
  mov    $0xffffffffffffffff,%rax
  div    %rdi
  shr    %rdi
  mov    %rsi,%rdx
  not    %rsi
  add    $0x1,%rdi
  imul   %rax,%rdi
  sub    %rax,%rdx
  and    %rsi,%rdx
  test   %rdi,%rdx
  jne    L43
  nopl   (%rax)
L64:
  mov    0x8(%rcx),%rdx
  add    $0x8,%rcx
  mov    %rdx,%rsi
  not    %rdx
  sub    %rax,%rsi
  and    %rsi,%rdx
  test   %rdi,%rdx
  je     L64
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rcx
L43:
  cmpb   $0x0,(%rcx)
  jne    L29
  mov    %rcx,%rax
  sub    %r8,%rax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *a = s;
  typedef size_t __attribute__((__may_alias__)) word;
  const word *w;
  for (; (uintptr_t)s % (sizeof(size_t)); s++)
    if (!*s)
      return s - a;
  for (w = (const void *)s; !((*w) - ((size_t)-1 / UCHAR_MAX) & ~(*w) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))); w++)
    ;
  s = (const void *)w;
  for (; *s; s++)
    ;
  return s - a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  mov    %rdi,%r8
  mov    %rdi,%rcx
  test   $0x7,%dil
  jne    L74
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rcx
  test   $0x7,%cl
  je     L8
L74:
  cmpb   $0x0,(%rcx)
  jne    L0
  mov    %rcx,%rax
  sub    %r8,%rax
  ret
  nopl   (%rax)
L8:
  mov    D5(%rip),%rax
  xor    %edx,%edx
  mov    (%rcx),%rsi
  mov    (%rax),%rdi
  mov    $0xffffffffffffffff,%rax
  div    %rdi
  shr    %rdi
  mov    %rsi,%rdx
  not    %rsi
  add    $0x1,%rdi
  imul   %rax,%rdi
  sub    %rax,%rdx
  and    %rsi,%rdx
  test   %rdi,%rdx
  jne    L77
  nopl   (%rax)
L47:
  mov    0x8(%rcx),%rdx
  add    $0x8,%rcx
  mov    %rdx,%rsi
  not    %rdx
  sub    %rax,%rsi
  and    %rsi,%rdx
  test   %rdi,%rdx
  je     L47
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x1,%rcx
L77:
  cmpb   $0x0,(%rcx)
  jne    L68
  mov    %rcx,%rax
  sub    %r8,%rax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *a = s;
  typedef size_t __attribute__((__may_alias__)) word;
  const word *w;
  for (; (uintptr_t)s % (sizeof(size_t)); s++)
    if (!*s)
      return s - a;
  for (w = (const void *)s; !((*w) - ((size_t)-1 / UCHAR_MAX) & ~(*w) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))); w++)
    ;
  s = (const void *)w;
  for (; *s; s++)
    ;
  return s - a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pick_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D6(%rip),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L23
L27:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L1
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L1:
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L27
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double pick_min(const double *samples, size_t count) {
  size_t i;
  double min = INFINITY;
  for (i = 0; i < count; i++) {
    if (samples[i] < min) {
      min = samples[i];
    }
  }
  return min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pick_min>:
  endbr64
  mov    D7(%rip),%rax
  movsd  (%rax),%xmm0
  test   %rsi,%rsi
  je     L17
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
L9:
  movsd  (%rax),%xmm1
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L9
L17:
  ret
```

assistant: ```c
double pick_min(const double *samples, size_t count) {
  size_t i;
  double min = INFINITY;
  for (i = 0; i < count; i++) {
    if (samples[i] < min) {
      min = samples[i];
    }
  }
  return min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pick_min>:
  endbr64
  mov    D3(%rip),%rax
  movsd  (%rax),%xmm0
  test   %rsi,%rsi
  je     L17
  lea    (%rdi,%rsi,8),%rax
  nopl   0x0(%rax,%rax,1)
L6:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L6
L17:
  ret
```

assistant: ```c
double pick_min(const double *samples, size_t count) {
  size_t i;
  double min = INFINITY;
  for (i = 0; i < count; i++) {
    if (samples[i] < min) {
      min = samples[i];
    }
  }
  return min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_min>:
  endbr64
  mov    D3(%rip),%rax
  movsd  (%rax),%xmm0
  test   %rsi,%rsi
  je     L19
  lea    (%rdi,%rsi,8),%rax
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L1
L19:
  ret
```

assistant: ```c
double pick_min(const double *samples, size_t count) {
  size_t i;
  double min = INFINITY;
  for (i = 0; i < count; i++) {
    if (samples[i] < min) {
      min = samples[i];
    }
  }
  return min;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D61
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D44
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D40
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D32
type_guessed: string

tool: D61: -----------------------------------------


tool: D44: Menu:
1. Set read lock at char.
2. Set write lock at char.


tool: D40: 3. Read all locks.


tool: D1: 4. Free lock.


tool: D8: 5. Read char from file.
6. Write char to file.
Close program with other key


tool: D32: Choice: 

assistant: ```c
void print_menu() {
  printf("-----------------------------------------\n");
  printf("Menu:\n1. Set read lock at char.\n2. Set write lock at char.\n");
  printf("3. Read all locks.\n");
  printf("4. Free lock.\n");
  printf("5. Read char from file.\n6. Write char to file.\nClose program with other key\n");
  printf("-----------------------------------------\n");
  printf("Choice: ");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_menu>:
  endbr64
  push   %rbx
  lea    D45(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D45
type_infered: string
name: read_data
arguments: label: D29
type_infered: string
name: read_data
arguments: label: D36
type_infered: string
name: read_data
arguments: label: D33
type_infered: string
name: read_data
arguments: label: D30
type_infered: string
name: read_data
arguments: label: D5
type_infered: string

tool: D45: -----------------------------------------


tool: D29: Menu:
1. Set read lock at char.
2. Set write lock at char.


tool: D36: 3. Read all locks.


tool: D33: 4. Free lock.


tool: D30: 5. Read char from file.
6. Write char to file.
Close program with other key


tool: D5: Choice: 

assistant: ```c
void print_menu() {
  printf("-----------------------------------------\n");
  printf("Menu:\n1. Set read lock at char.\n2. Set write lock at char.\n");
  printf("3. Read all locks.\n");
  printf("4. Free lock.\n");
  printf("5. Read char from file.\n6. Write char to file.\nClose program with other key\n");
  printf("-----------------------------------------\n");
  printf("Choice: ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_menu>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D44
datatype: string
name: disassemble_data
arguments: tag: D18
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D8: -----------------------------------------


tool: D22: Menu:
1. Set read lock at char.
2. Set write lock at char.


tool: D27: 3. Read all locks.


tool: D44: 4. Free lock.


tool: D18: 5. Read char from file.
6. Write char to file.
Close program with other key


tool: D7: Choice: 

assistant: ```c
void print_menu() {
  printf("-----------------------------------------\n");
  printf("Menu:\n1. Set read lock at char.\n2. Set write lock at char.\n");
  printf("3. Read all locks.\n");
  printf("4. Free lock.\n");
  printf("5. Read char from file.\n6. Write char to file.\nClose program with other key\n");
  printf("-----------------------------------------\n");
  printf("Choice: ");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_menu>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D56
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D58
type_guessed: string

tool: D29: -----------------------------------------


tool: D19: Menu:
1. Set read lock at char.
2. Set write lock at char.


tool: D56: 3. Read all locks.


tool: D28: 4. Free lock.


tool: D4: 5. Read char from file.
6. Write char to file.
Close program with other key


tool: D58: Choice: 

assistant: ```c
void print_menu() {
  printf("-----------------------------------------\n");
  printf("Menu:\n1. Set read lock at char.\n2. Set write lock at char.\n");
  printf("3. Read all locks.\n");
  printf("4. Free lock.\n");
  printf("5. Read char from file.\n6. Write char to file.\nClose program with other key\n");
  printf("-----------------------------------------\n");
  printf("Choice: ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<make_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb8(%rbp),%rax
  mov    %rax,-0xa0(%rbp)
  movl   $0x0,-0xa8(%rbp)
L67:
  mov    -0xa0(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x98(%rbp)
  cmpq   $0x0,-0x98(%rbp)
  je     L88
  mov    -0x98(%rbp),%rax
  sub    -0xa0(%rbp),%rax
  mov    %eax,%edx
  mov    -0xa0(%rbp),%rcx
  lea    -0x90(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x98(%rbp),%rax
  sub    -0xa0(%rbp),%rax
  movb   $0x0,-0x90(%rbp,%rax,1)
  jmp    L34
L88:
  mov    -0xa0(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L34:
  lea    -0x90(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L1
  lea    -0x90(%rbp),%rax
  mov    $0x1ff,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  jns    L66
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L66:
  addl   $0x1,-0xa8(%rbp)
L1:
  cmpq   $0x0,-0x98(%rbp)
  je     L25
  mov    -0x98(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0xa0(%rbp)
  jmp    L67
L25:
  nop
  movl   $0x0,-0xa4(%rbp)
  jmp    L45
L7:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  addl   $0x1,-0xa4(%rbp)
L45:
  mov    -0xa4(%rbp),%eax
  cmp    -0xa8(%rbp),%eax
  jl     L7
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D20
datatype: string

tool: D9: .

tool: D16: mkdir+chdir

tool: D20: ..

assistant: ```c
void make_directory(char *dir) {
  char buf[128];
  char *t = dir;
  int depth = 0;
  while (1) {
    char *e = strstr(t, "/");
    if (e) {
      memcpy(buf, t, e - t);
      buf[e - t] = 0;
    } else {
      strcpy(buf, t);
    }
    if (strcmp(buf, ".") == 0) {
    } else {
      mkdir(buf, 0777);
      if (chdir(buf) < 0)
        die("mkdir+chdir");
      depth++;
    }
    if (e) {
      t = e + 1;
    } else {
      break;
    }
  }
  for (int i = 0; i < depth; i++)
    chdir("..");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_directory>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r14d
  mov    %rsp,%r12
  lea    D18(%rip),%r15
  jmp    L91
L107:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L104
  mov    $0x1ff,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  mov    %r12,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  jns    L103
L3:
  lea    D8(%rip),%rdi
  call   <die@plt>
  add    $0x1,%r14d
  test   %rbx,%rbx
  je     L104
L68:
  lea    0x1(%rbx),%rbp
L91:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L107
  mov    %rax,%r13
  sub    %rbp,%r13
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rsp,%r13,1)
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L68
  mov    $0x1ff,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  mov    %r12,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  js     L3
  add    $0x1,%r14d
  jmp    L68
L103:
  add    $0x1,%r14d
L104:
  mov    $0x0,%ebx
  lea    D16(%rip),%rbp
  test   %r14d,%r14d
  jle    L39
L88:
  mov    %rbp,%rdi
  call   <chdir@plt>
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jne    L88
L39:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D16
data_type: string

tool: D18: .

tool: D8: mkdir+chdir

tool: D16: ..

assistant: ```c
void make_directory(char *dir) {
  char buf[128];
  char *t = dir;
  int depth = 0;
  while (1) {
    char *e = strstr(t, "/");
    if (e) {
      memcpy(buf, t, e - t);
      buf[e - t] = 0;
    } else {
      strcpy(buf, t);
    }
    if (strcmp(buf, ".") == 0) {
    } else {
      mkdir(buf, 0777);
      if (chdir(buf) < 0)
        die("mkdir+chdir");
      depth++;
    }
    if (e) {
      t = e + 1;
    } else {
      break;
    }
  }
  for (int i = 0; i < depth; i++)
    chdir("..");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_directory>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    D34(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L124
  nopw   0x0(%rax,%rax,1)
L94:
  mov    %rax,%r14
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%r14
  mov    %r14d,%edx
  call   <memcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%r14,1)
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L88
L39:
  lea    0x1(%rbx),%r15
L124:
  mov    $0x2f,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L94
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L98
  mov    %rbp,%rdi
  mov    $0x1ff,%esi
  call   <mkdir@plt>
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  js     L46
L128:
  add    $0x1,%r12d
  jmp    L27
  nopl   (%rax)
L88:
  mov    %rbp,%rdi
  mov    $0x1ff,%esi
  call   <mkdir@plt>
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  js     L22
L29:
  add    $0x1,%r12d
  jmp    L39
L98:
  test   %r12d,%r12d
  je     L111
L27:
  xor    %ebx,%ebx
  lea    D13(%rip),%rbp
  xchg   %ax,%ax
L14:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <chdir@plt>
  cmp    %r12d,%ebx
  jl     L14
L111:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L22:
  lea    D8(%rip),%rdi
  call   <die@plt>
  jmp    L29
L46:
  lea    D8(%rip),%rdi
  call   <die@plt>
  jmp    L128
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D34
data_type: string
name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D34: .

tool: D13: ..

tool: D8: mkdir+chdir

assistant: ```c
void make_directory(char *dir) {
  char buf[128];
  char *t = dir;
  int depth = 0;
  while (1) {
    char *e = strstr(t, "/");
    if (e) {
      memcpy(buf, t, e - t);
      buf[e - t] = 0;
    } else {
      strcpy(buf, t);
    }
    if (strcmp(buf, ".") == 0) {
    } else {
      mkdir(buf, 0777);
      if (chdir(buf) < 0)
        die("mkdir+chdir");
      depth++;
    }
    if (e) {
      t = e + 1;
    } else {
      break;
    }
  }
  for (int i = 0; i < depth; i++)
    chdir("..");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<make_directory>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %rax,%r14
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%r14
  mov    %r14d,%edx
  call   <memcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%r14,1)
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L78
L100:
  lea    0x1(%rbx),%r15
L68:
  mov    $0x2f,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L45
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L112
  mov    %rbp,%rdi
  mov    $0x1ff,%esi
  call   <mkdir@plt>
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  js     L90
L49:
  add    $0x1,%r12d
  jmp    L25
  nopl   (%rax)
L78:
  mov    %rbp,%rdi
  mov    $0x1ff,%esi
  call   <mkdir@plt>
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  js     L52
L74:
  add    $0x1,%r12d
  jmp    L100
L112:
  test   %r12d,%r12d
  je     L64
L25:
  xor    %ebx,%ebx
  lea    D16(%rip),%rbp
  xchg   %ax,%ax
L43:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <chdir@plt>
  cmp    %r12d,%ebx
  jl     L43
L64:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L52:
  lea    D32(%rip),%rdi
  call   <die@plt>
  jmp    L74
L90:
  lea    D32(%rip),%rdi
  call   <die@plt>
  jmp    L49
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string

tool: D23: .

tool: D16: ..

tool: D32: mkdir+chdir

assistant: ```c
void make_directory(char *dir) {
  char buf[128];
  char *t = dir;
  int depth = 0;
  while (1) {
    char *e = strstr(t, "/");
    if (e) {
      memcpy(buf, t, e - t);
      buf[e - t] = 0;
    } else {
      strcpy(buf, t);
    }
    if (strcmp(buf, ".") == 0) {
    } else {
      mkdir(buf, 0777);
      if (chdir(buf) < 0)
        die("mkdir+chdir");
      depth++;
    }
    if (e) {
      t = e + 1;
    } else {
      break;
    }
  }
  for (int i = 0; i < depth; i++)
    chdir("..");
}
```
user: What is the c source code of the assembly code below:

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L22
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L22:
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L10:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <remove_at@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <permute>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jb     L10
L8:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: %s


assistant: ```c
void permute(char *cs, char *buf, int last) {
  if (strlen(cs) == 0) {
    buf[last] = '\0';
    printf("%s\n", buf);
  } else {
    for (unsigned i = 0; i < strlen(cs); i++) {
      buf[last] = cs[i];
      char *rest = remove_at(cs, i);
      permute(rest, buf, last + 1);
      free(rest);
    }
  }
}
```