ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<taka_tstring_delete_file_name_from_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  je     L0
L1:
  cmpb   $0x2f,(%rax)
  je     L2
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L1
  jmp    L0
L2:
  movb   $0x0,0x1(%rax)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void taka_tstring_delete_file_name_from_path(char *str) {
  char *p = str + strlen(str);
  for (; p != str; p--) {
    if (*p == '/') {
      p[1] = '\0';
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<taka_tstring_delete_file_name_from_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jne    L23
  jmp    L20
  nopl   0x0(%rax)
L12:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L20
L23:
  cmpb   $0x2f,(%rax)
  jne    L12
  movb   $0x0,0x1(%rax)
L20:
  pop    %rbx
  ret
```

assistant: ```c
void taka_tstring_delete_file_name_from_path(char *str) {
  char *p = str + strlen(str);
  for (; p != str; p--) {
    if (*p == '/') {
      p[1] = '\0';
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<taka_tstring_delete_file_name_from_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jne    L29
  jmp    L38
  nopl   0x0(%rax)
L36:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L38
L29:
  cmpb   $0x2f,(%rax)
  jne    L36
  movb   $0x0,0x1(%rax)
L38:
  pop    %rbx
  ret
```

assistant: ```c
void taka_tstring_delete_file_name_from_path(char *str) {
  char *p = str + strlen(str);
  for (; p != str; p--) {
    if (*p == '/') {
      p[1] = '\0';
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<execute>:
  endbr64
  mov    %rdi,%r8
  mov    (%rdi),%r11d
  cmp    $0x64,%r11d
  je     L17
  push   %rbp
  push   %rbx
  mov    %rsi,%rdi
  mov    $0x0,%esi
  mov    $0x0,%eax
  lea    D7(%rip),%r9
  jmp    L94
  movslq %ecx,%r10
  mov    %edx,(%rdi,%r10,4)
L98:
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%r10
  mov    (%r10),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %ecx,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%ecx
  mov    %ecx,(%r10)
L3:
  movslq %esi,%rdx
  mov    (%r8,%rdx,4),%r11d
  cmp    $0x64,%r11d
  je     L55
L94:
  movslq %r11d,%rdx
  imul   $0x51eb851f,%rdx,%r10
  sar    $0x25,%r10
  mov    %r11d,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%r10d
  imul   $0x64,%r10d,%ecx
  mov    %r11d,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  sar    $0x1f,%ebp
  sub    %ebp,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,4),%ebx
  add    %ebx,%ebx
  mov    %r11d,%edx
  sub    %ebx,%edx
  add    $0x1,%esi
  add    $0x1,%eax
  cmp    $0x9,%r10d
  ja     L98
  mov    %r10d,%r10d
  movslq (%r9,%r10,4),%r10
  add    %r9,%r10
  notrack jmp *%r10
  movslq %ecx,%r10
  add    %edx,(%rdi,%r10,4)
  jmp    L98
  movslq %ecx,%r10
  lea    (%rdi,%r10,4),%r10
  imul   (%r10),%edx
  mov    %edx,(%r10)
  jmp    L98
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%r10d
  movslq %ecx,%rdx
  mov    %r10d,(%rdi,%rdx,4)
  jmp    L98
  movslq %ecx,%r10
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%r11d
  add    %r11d,(%rdi,%r10,4)
  jmp    L98
  movslq %ecx,%r10
  lea    (%rdi,%r10,4),%r10
  movslq %edx,%r11
  mov    (%r10),%edx
  imul   (%rdi,%r11,4),%edx
  mov    %edx,(%r10)
  jmp    L98
  movslq %edx,%rdx
  movslq (%rdi,%rdx,4),%rdx
  mov    (%r8,%rdx,4),%r10d
  movslq %ecx,%rdx
  mov    %r10d,(%rdi,%rdx,4)
  jmp    L98
  movslq %ecx,%r10
  mov    (%rdi,%r10,4),%r10d
  movslq %edx,%rdx
  movslq (%rdi,%rdx,4),%rdx
  mov    %r10d,(%r8,%rdx,4)
  jmp    L98
  movslq %edx,%rdx
  cmpl   $0x0,(%rdi,%rdx,4)
  je     L98
  movslq %ecx,%rcx
  mov    (%rdi,%rcx,4),%esi
  jmp    L3
L17:
  mov    $0x0,%eax
  add    $0x1,%eax
  ret
L55:
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int execute(int *ram, int *reg) {
  int step = 0;
  int hi, mi, lo;
  int i = 0;
  int ip = 0;
  while (ram[ip] != 100) {
    hi = ram[ip] / 100;
    mi = (ram[ip] % 100) / 10;
    lo = ram[ip] % 10;
    ip++;
    step++;
    switch (hi) {
    case 1:
      break;
    case 2:
      reg[mi] = lo;
      break;
    case 3:
      reg[mi] += lo;
      break;
    case 4:
      reg[mi] *= lo;
      break;
    case 5:
      reg[mi] = reg[lo];
      break;
    case 6:
      reg[mi] += reg[lo];
      break;
    case 7:
      reg[mi] *= reg[lo];
      break;
    case 8:
      reg[mi] = ram[reg[lo]];
      break;
    case 9:
      ram[reg[lo]] = reg[mi];
      break;
    case 0:
      if (reg[lo]) {
        ip = reg[mi];
        continue;
      }
      break;
    }
    reg[mi] = reg[mi] % 1000;
  }
  return ++step;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %edi,-0x1a4(%rbp)
  mov    %rsi,-0x1b0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <check_vect@plt>
  movl   $0x0,-0x198(%rbp)
  jmp    L32
L15:
  movl   $0x0,-0x194(%rbp)
  jmp    L44
L24:
  mov    -0x194(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x198(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  movw   $0x0,-0x190(%rbp,%rax,2)
  addl   $0x1,-0x194(%rbp)
L44:
  cmpl   $0x17,-0x194(%rbp)
  jle    L24
  addl   $0x1,-0x198(%rbp)
L32:
  cmpl   $0x7,-0x198(%rbp)
  jle    L15
  lea    -0x190(%rbp),%rax
  mov    %rax,%rdi
  call   <VecBug@plt>
  lea    -0x190(%rbp),%rax
  mov    %rax,%rdi
  call   <VecBug2@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  check_vect();
  short Kernel[8][24] __attribute__((__aligned__(16)));
  int k, i;
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernel[k][i] = 0;
  VecBug(Kernel);
  VecBug2(Kernel);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x190,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  call   <check_vect@plt>
  lea    0x30(%rsp),%rdx
  lea    0x1b0(%rsp),%rcx
L21:
  lea    -0x30(%rdx),%rax
L10:
  movw   $0x0,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L10
  add    $0x30,%rdx
  cmp    %rcx,%rdx
  jne    L21
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <VecBug@plt>
  mov    %rbx,%rdi
  call   <VecBug2@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x190,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  check_vect();
  short Kernel[8][24] __attribute__((__aligned__(16)));
  int k, i;
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernel[k][i] = 0;
  VecBug(Kernel);
  VecBug2(Kernel);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x190,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <check_vect@plt>
  xor    %eax,%eax
  mov    $0x30,%ecx
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <VecBug@plt>
  mov    %rbp,%rdi
  call   <VecBug2@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x190,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  check_vect();
  short Kernel[8][24] __attribute__((__aligned__(16)));
  int k, i;
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernel[k][i] = 0;
  VecBug(Kernel);
  VecBug2(Kernel);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x190,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <check_vect@plt>
  xor    %eax,%eax
  mov    $0x30,%ecx
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <VecBug@plt>
  mov    %rbp,%rdi
  call   <VecBug2@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x190,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  check_vect();
  short Kernel[8][24] __attribute__((__aligned__(16)));
  int k, i;
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernel[k][i] = 0;
  VecBug(Kernel);
  VecBug2(Kernel);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L12:
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L44:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jbe    L20
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L20:
  addl   $0x1,-0x10(%rbp)
L46:
  mov    $0x9,%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L44
  addl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x8,-0x14(%rbp)
  jle    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void sort(char *s[]) {
  int i, j, n;
  char *temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (s[j + n] > s[j + n + 1]) {
        strcpy(temp, s[j + n]);
        strcpy(s[j + n], s[j + n + 1]);
        strcpy(s[j + n + 1], temp);
      }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x40,%eax
  lea    0x8(%rdi,%rax,1),%rbp
  lea    -0x40(%rdi,%rax,1),%r14
  mov    $0x9,%r13d
  jmp    L31
L49:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L61
L44:
  mov    (%rbx),%rsi
  cmp    0x8(%rbx),%rsi
  jbe    L49
  mov    $0x0,%r12d
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  jmp    L49
L61:
  sub    $0x8,%rbp
  sub    $0x1,%r13d
  je     L37
L31:
  mov    %r14,%rbx
  test   %r13d,%r13d
  jg     L44
  jmp    L61
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void sort(char *s[]) {
  int i, j, n;
  char *temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (s[j + n] > s[j + n + 1]) {
        strcpy(temp, s[j + n]);
        strcpy(s[j + n], s[j + n + 1]);
        strcpy(s[j + n + 1], temp);
      }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort>:
  endbr64
  push   %r13
  mov    $0x40,%eax
  push   %r12
  lea    -0x40(%rdi,%rax,1),%r13
  push   %rbp
  lea    0x8(%rdi,%rax,1),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L40:
  mov    %r13,%rbx
  jmp    L21
  nopl   (%rax)
L28:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L39
L21:
  mov    (%rbx),%rsi
  cmp    0x8(%rbx),%rsi
  jbe    L28
  xor    %r12d,%r12d
  add    $0x8,%rbx
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rsi
  mov    -0x8(%rbx),%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  cmp    %rbp,%rbx
  jne    L21
L39:
  lea    -0x8(%rbx),%rbp
  cmp    %r13,%rbp
  jne    L40
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sort(char *s[]) {
  int i, j, n;
  char *temp;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9 - i; j++)
      if (s[j + n] > s[j + n + 1]) {
        strcpy(temp, s[j + n]);
        strcpy(s[j + n], s[j + n + 1]);
        strcpy(s[j + n + 1], temp);
      }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L3:
  mov    $0x0,%eax
  call   <callFunction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L3
  cmpl   $0x1e8480,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 1000; i++) {
    sum += callFunction();
  }
  return sum == 2000000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3e8,%ebx
  mov    $0x0,%ebp
L7:
  mov    $0x0,%eax
  call   <callFunction@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L7
  cmp    $0x1e8480,%ebp
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 1000; i++) {
    sum += callFunction();
  }
  return sum == 2000000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <callFunction@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L7
  xor    %eax,%eax
  cmp    $0x1e8480,%ebp
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 1000; i++) {
    sum += callFunction();
  }
  return sum == 2000000;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <callFunction@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L1
  xor    %eax,%eax
  cmp    $0x1e8480,%ebp
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 1000; i++) {
    sum += callFunction();
  }
  return sum == 2000000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_resolution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x4,%esi
  mov    $0x2,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,-0xd(%rbp)
  jmp    L44
L33:
  movsbl -0xd(%rbp),%eax
  cmp    $0x78,%eax
  je     L25
  cmp    $0x78,%eax
  jg     L66
  cmp    $0x39,%eax
  jg     L98
  cmp    $0x30,%eax
  jge    L54
  jmp    L66
L98:
  cmp    $0x58,%eax
  je     L25
  jmp    L66
L54:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0xd(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  sub    $0x30,%edx
  mov    %edx,(%rax)
  jmp    L63
L25:
  addl   $0x1,-0xc(%rbp)
  jmp    L63
L66:
  nop
L63:
  cmpl   $0x1,-0xc(%rbp)
  jg     L1
L44:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L33
  jmp    L43
L1:
  nop
L43:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *parse_resolution(char *str) {
  int *res = (int *)calloc(2, sizeof(int));
  int n = 0;
  char c = 0;
  while ((c = *(str++))) {
    switch (c) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      res[n] = res[n] * 10 + c - '0';
      break;
    case 'x':
    case 'X':
      n++;
      break;
    default:
      break;
    }
    if (n > 1)
      break;
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parse_resolution>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%esi
  mov    $0x2,%edi
  call   <calloc@plt>
  mov    $0x0,%ecx
  jmp    L20
L32:
  cmp    $0x78,%dl
  je     L30
L71:
  cmp    $0x1,%ecx
  jg     L8
L20:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edx
  test   %dl,%dl
  je     L8
  cmp    $0x58,%dl
  je     L30
  jg     L32
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  ja     L71
  movslq %ecx,%rsi
  lea    (%rax,%rsi,4),%rsi
  mov    (%rsi),%edi
  lea    (%rdi,%rdi,4),%edi
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rdi,2),%edx
  mov    %edx,(%rsi)
  jmp    L71
L30:
  add    $0x1,%ecx
  jmp    L71
L8:
  pop    %rbx
  ret
```

assistant: ```c
void *parse_resolution(char *str) {
  int *res = (int *)calloc(2, sizeof(int));
  int n = 0;
  char c = 0;
  while ((c = *(str++))) {
    switch (c) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      res[n] = res[n] * 10 + c - '0';
      break;
    case 'x':
    case 'X':
      n++;
      break;
    default:
      break;
    }
    if (n > 1)
      break;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_resolution>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <calloc@plt>
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L62
  lea    0x1(%rbx),%rcx
  xor    %r8d,%r8d
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L68:
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  ja     L48
  movslq %r8d,%rsi
  lea    (%rax,%rsi,4),%rsi
  mov    (%rsi),%edi
  lea    (%rdi,%rdi,4),%edi
  lea    -0x30(%rdx,%rdi,2),%edx
  mov    %edx,(%rsi)
L48:
  movsbl (%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L62
L33:
  cmp    $0x58,%dl
  je     L31
  jle    L68
  cmp    $0x78,%dl
  jne    L48
L31:
  cmp    $0x1,%r8d
  jne    L4
L62:
  pop    %rbx
  ret
L4:
  mov    $0x1,%r8d
  jmp    L48
```

assistant: ```c
void *parse_resolution(char *str) {
  int *res = (int *)calloc(2, sizeof(int));
  int n = 0;
  char c = 0;
  while ((c = *(str++))) {
    switch (c) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      res[n] = res[n] * 10 + c - '0';
      break;
    case 'x':
    case 'X':
      n++;
      break;
    default:
      break;
    }
    if (n > 1)
      break;
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_resolution>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <calloc@plt>
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L69
  lea    0x1(%rbx),%rcx
  xor    %r8d,%r8d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L36:
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  ja     L7
  movslq %r8d,%rsi
  lea    (%rax,%rsi,4),%rsi
  mov    (%rsi),%edi
  lea    (%rdi,%rdi,4),%edi
  lea    -0x30(%rdx,%rdi,2),%edx
  mov    %edx,(%rsi)
L7:
  movsbl (%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L69
L10:
  cmp    $0x58,%dl
  je     L39
  jle    L36
  cmp    $0x78,%dl
  jne    L7
L39:
  cmp    $0x1,%r8d
  jne    L65
L69:
  pop    %rbx
  ret
L65:
  mov    $0x1,%r8d
  jmp    L7
```

assistant: ```c
void *parse_resolution(char *str) {
  int *res = (int *)calloc(2, sizeof(int));
  int n = 0;
  char c = 0;
  while ((c = *(str++))) {
    switch (c) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      res[n] = res[n] * 10 + c - '0';
      break;
    case 'x':
    case 'X':
      n++;
      break;
    default:
      break;
    }
    if (n > 1)
      break;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<displayInstructions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D45(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <nxtDisplayCenteredBigTextLine@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D55(%rip),%rax
  mov    %rax,%rsi
  mov    $0x6,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rsi
  mov    $0x7,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  mov    $0x7d0,%edi
  call   <wait1Msec@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D45
type_guessed: string
name: disassemble_data
arguments: label: D43
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D55
type_guessed: string
name: disassemble_data
arguments: label: D52
type_guessed: string

tool: D45: HiTechnic

tool: D43: IR Seekr

tool: D24: Test 1

tool: D12: Press enter to

tool: D55: switch between

tool: D52: 600 and 1200 Hz

assistant: ```c
void displayInstructions() {
  nxtDisplayCenteredTextLine(0, "HiTechnic");
  nxtDisplayCenteredBigTextLine(1, "IR Seekr");
  nxtDisplayCenteredTextLine(3, "Test 1");
  nxtDisplayCenteredTextLine(5, "Press enter to");
  nxtDisplayCenteredTextLine(6, "switch between");
  nxtDisplayCenteredTextLine(7, "600 and 1200 Hz");
  wait1Msec(2000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<displayInstructions>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rsi
  mov    $0x0,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D12(%rip),%rsi
  mov    $0x1,%edi
  call   <nxtDisplayCenteredBigTextLine@plt>
  lea    D35(%rip),%rsi
  mov    $0x3,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D14(%rip),%rsi
  mov    $0x5,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D44(%rip),%rsi
  mov    $0x6,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  lea    D30(%rip),%rsi
  mov    $0x7,%edi
  call   <nxtDisplayCenteredTextLine@plt>
  mov    $0x7d0,%edi
  call   <wait1Msec@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D35
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D44
type: string
name: read_data
arguments: label: D30
type: string

tool: D16: HiTechnic

tool: D12: IR Seekr

tool: D35: Test 1

tool: D14: Press enter to

tool: D44: switch between

tool: D30: 600 and 1200 Hz

assistant: ```c
void displayInstructions() {
  nxtDisplayCenteredTextLine(0, "HiTechnic");
  nxtDisplayCenteredBigTextLine(1, "IR Seekr");
  nxtDisplayCenteredTextLine(3, "Test 1");
  nxtDisplayCenteredTextLine(5, "Press enter to");
  nxtDisplayCenteredTextLine(6, "switch between");
  nxtDisplayCenteredTextLine(7, "600 and 1200 Hz");
  wait1Msec(2000);
}
```