ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x728(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L50
  mov    0x8(%rsi),%r12
  mov    %r12,%rdi
  call   <fsopen@plt>
  test   %rax,%rax
  je     L49
  cmpb   $0x2f,(%r12)
  je     L69
  mov    %rsp,%r13
  mov    $0x320,%esi
  lea    0x320(%rsp),%rbp
  mov    %r13,%rdi
  call   <getcwd@plt>
  mov    %rbp,%rdi
  mov    %r12,%rcx
  mov    %r13,%rdx
  lea    D49(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <storesetting@plt>
L53:
  lea    D44(%rip),%rsi
  lea    D57(%rip),%rdi
  call   <storesetting@plt>
  xor    %eax,%eax
L15:
  mov    0x728(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x730,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L69:
  mov    %r12,%rsi
  lea    D25(%rip),%rdi
  call   <storesetting@plt>
  jmp    L53
L50:
  mov    (%rsi),%rsi
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  jmp    L15
L49:
  mov    %r12,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  jmp    L15
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D49
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D44
data_type: string
name: retrieve_data
arguments: data_label: D57
data_type: string
name: retrieve_data
arguments: data_label: D55
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string

tool: D49: %s/%s

tool: D25: imagefile

tool: D44: /

tool: D57: cwd

tool: D55: Usage: %s <filename>


tool: D17: Unable to open %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *filename;
  struct filesystem *f;
  char fullpath[1024];
  char cwd[800];
  if (argc != 2) {
    printf("Usage: %s <filename>\n", argv[0]);
    return 10;
  }
  filename = argv[1];
  f = fsopen(filename);
  if (!f) {
    printf("Unable to open %s\n", filename);
    return 10;
  }
  if (filename[0] == '/') {
    storesetting("imagefile", filename);
  } else {
    getcwd(cwd, 800);
    sprintf(fullpath, "%s/%s", cwd, filename);
    storesetting("imagefile", fullpath);
  }
  storesetting("cwd", "/");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<longest_increasing_sequence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L3
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L8
  nop
  pop    %rbp
  ret
```

assistant: ```c
int longest_increasing_sequence(int *src, int *dst, int num) {
  int last = 0, cur = 1, next = 2;
  int index = 0;
  for (int i = 1; i < num; i++) {
    cur = i;
    {}
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<longest_increasing_sequence>:
  endbr64
  cmp    $0x1,%edx
  jle    L4
  mov    $0x1,%eax
L11:
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L11
L4:
  ret
```

assistant: ```c
int longest_increasing_sequence(int *src, int *dst, int num) {
  int last = 0, cur = 1, next = 2;
  int index = 0;
  for (int i = 1; i < num; i++) {
    cur = i;
    {}
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<longest_increasing_sequence>:
  endbr64
  ret
```

assistant: ```c
int longest_increasing_sequence(int *src, int *dst, int num) {
  int last = 0, cur = 1, next = 2;
  int index = 0;
  for (int i = 1; i < num; i++) {
    cur = i;
    {}
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<longest_increasing_sequence>:
  endbr64
  ret
```

assistant: ```c
int longest_increasing_sequence(int *src, int *dst, int num) {
  int last = 0, cur = 1, next = 2;
  int index = 0;
  for (int i = 1; i < num; i++) {
    cur = i;
    {}
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L1
  cmpl   $0x2,-0x4(%rbp)
  jg     L73
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  cmpl   $0x1,-0x4(%rbp)
  je     L40
  jmp    L73
L1:
  nop
  jmp    L76
L73:
  nop
  jmp    L76
L22:
  nop
  jmp    L76
L40:
  nop
L76:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<the_switch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L5
  cmpl   $0x3,-0x4(%rbp)
  jg     L22
  cmpl   $0x1,-0x4(%rbp)
  je     L43
  cmpl   $0x2,-0x4(%rbp)
  je     L17
  jmp    L22
L43:
  mov    $0xa,%eax
  jmp    L10
L17:
  mov    $0x14,%eax
  jmp    L10
L5:
  mov    $0x1e,%eax
  jmp    L10
L22:
  mov    $0x2a,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int the_switch(int key) {
  switch (key) {
  case 1:
    return 10;
  case 2:
    return 20;
  case 3:
    return 30;
  default:
    return 42;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<the_switch>:
  endbr64
  mov    $0x14,%eax
  cmp    $0x2,%edi
  je     L15
  mov    $0x1e,%eax
  cmp    $0x3,%edi
  je     L15
  cmp    $0x1,%edi
  mov    $0x2a,%eax
  mov    $0xa,%edx
  cmove  %edx,%eax
L15:
  ret
```

assistant: ```c
int the_switch(int key) {
  switch (key) {
  case 1:
    return 10;
  case 2:
    return 20;
  case 3:
    return 30;
  default:
    return 42;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<the_switch>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x2a,%eax
  cmp    $0x2,%edx
  ja     L7
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
L7:
  ret
```

assistant: ```c
int the_switch(int key) {
  switch (key) {
  case 1:
    return 10;
  case 2:
    return 20;
  case 3:
    return 30;
  default:
    return 42;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<the_switch>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x2a,%eax
  cmp    $0x2,%edx
  ja     L0
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
L0:
  ret
```

assistant: ```c
int the_switch(int key) {
  switch (key) {
  case 1:
    return 10;
  case 2:
    return 20;
  case 3:
    return 30;
  default:
    return 42;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rcxb_rawnamenode_hook_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <string_dup@plt>
  jmp    L4
L8:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
void *rcxb_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<rcxb_rawnamenode_hook_copy>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <string_dup@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void *rcxb_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rcxb_rawnamenode_hook_copy>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <string_dup@plt>
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *rcxb_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rcxb_rawnamenode_hook_copy>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <string_dup@plt>
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *rcxb_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x1,%eax
  jmp    L10
L17:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <factorial>
  imul   -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
long factorial(long n) {
  if (n == 0)
    return 1;
  return (n * factorial(n - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  jne    L5
  ret
L5:
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rdi
  call   <factorial>
  imul   %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long factorial(long n) {
  if (n == 0)
    return 1;
  return (n * factorial(n - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L4
  xchg   %ax,%ax
L13:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L13
L4:
  ret
```

assistant: ```c
long factorial(long n) {
  if (n == 0)
    return 1;
  return (n * factorial(n - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L5
  xchg   %ax,%ax
L9:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L9
L5:
  ret
```

assistant: ```c
long factorial(long n) {
  if (n == 0)
    return 1;
  return (n * factorial(n - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ts_set_valueiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xcc(%rbp),%edx
  mov    -0xb8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xcc(%rbp),%ecx
  mov    -0xc8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <ts_set_valueiv_va@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ts_set_valueiv(struct ts_value *tsv, int count, ...) {
  int res;
  va_list ap;
  va_start(ap, count);
  res = ts_set_valueiv_va(tsv, count, ap);
  va_end(ap);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ts_set_valueiv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <ts_set_valueiv_va@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ts_set_valueiv(struct ts_value *tsv, int count, ...) {
  int res;
  va_list ap;
  va_start(ap, count);
  res = ts_set_valueiv_va(tsv, count, ap);
  va_end(ap);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ts_set_valueiv>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %esi,%ebp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <ts_set_valueiv_va@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ts_set_valueiv(struct ts_value *tsv, int count, ...) {
  int res;
  va_list ap;
  va_start(ap, count);
  res = ts_set_valueiv_va(tsv, count, ap);
  va_end(ap);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ts_set_valueiv>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %esi,%ebp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <ts_set_valueiv_va@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ts_set_valueiv(struct ts_value *tsv, int count, ...) {
  int res;
  va_list ap;
  va_start(ap, count);
  res = ts_set_valueiv_va(tsv, count, ap);
  va_end(ap);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__jrand48_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__drand48_iterate@plt>
  test   %rax,%rax
  jns    L18
  mov    $0xffffffff,%eax
  jmp    L12
L18:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  or     %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int __jrand48_r(unsigned short int xsubi[3], struct drand48_data *buffer, long int *result) {
  if (__drand48_iterate(xsubi, buffer) < 0)
    return -1;
  *result = (int32_t)((xsubi[2] << 16) | xsubi[1]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__jrand48_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  call   <__drand48_iterate@plt>
  test   %rax,%rax
  js     L9
  movzwl 0x4(%rbx),%eax
  shl    $0x10,%eax
  movzwl 0x2(%rbx),%edx
  or     %edx,%eax
  cltq
  mov    %rax,0x0(%rbp)
  mov    $0x0,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int __jrand48_r(unsigned short int xsubi[3], struct drand48_data *buffer, long int *result) {
  if (__drand48_iterate(xsubi, buffer) < 0)
    return -1;
  *result = (int32_t)((xsubi[2] << 16) | xsubi[1]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__jrand48_r>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <__drand48_iterate@plt>
  test   %rax,%rax
  js     L15
  movslq 0x2(%rbx),%rax
  mov    %rax,0x0(%rbp)
  xor    %eax,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int __jrand48_r(unsigned short int xsubi[3], struct drand48_data *buffer, long int *result) {
  if (__drand48_iterate(xsubi, buffer) < 0)
    return -1;
  *result = (int32_t)((xsubi[2] << 16) | xsubi[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__jrand48_r>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <__drand48_iterate@plt>
  test   %rax,%rax
  js     L6
  movslq 0x2(%rbx),%rax
  mov    %rax,0x0(%rbp)
  xor    %eax,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int __jrand48_r(unsigned short int xsubi[3], struct drand48_data *buffer, long int *result) {
  if (__drand48_iterate(xsubi, buffer) < 0)
    return -1;
  *result = (int32_t)((xsubi[2] << 16) | xsubi[1]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<troca_linha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L19
L25:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0x18(%rbp),%eax
  cltq
  mov    %edx,-0x14(%rbp,%rax,4)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%eax
  cltq
  mov    (%rsi,%rax,4),%edx
  mov    -0x18(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%edx
  mov    -0x18(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  addl   $0x1,-0x18(%rbp)
L19:
  cmpl   $0x2,-0x18(%rbp)
  jle    L25
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <mostrar_mat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D15: Troca da linha %d com a linha %d!


tool: D0: 
Matriz alterada: 

assistant: ```c
void troca_linha(int mat[3][3], int origem, int destino) {
  int i = 0, aux[3];
  printf("Troca da linha %d com a linha %d!\n", origem, destino);
  for (i = 0; i < 3; i++) {
    aux[i] = mat[origem][i];
    mat[origem][i] = mat[destino][i];
    mat[destino][i] = aux[i];
  }
  printf("\nMatriz alterada: \n");
  mostrar_mat(mat);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<troca_linha>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rbp,2),%rax
  lea    (%r12,%rax,4),%rdx
  movslq %ebx,%rbx
  lea    (%rbx,%rbx,2),%rax
  lea    (%r12,%rax,4),%rax
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%ecx
  mov    0x4(%rax),%esi
  mov    %esi,0x4(%rdx)
  mov    %ecx,0x4(%rax)
  mov    0x8(%rdx),%ecx
  mov    0x8(%rax),%esi
  mov    %esi,0x8(%rdx)
  mov    %ecx,0x8(%rax)
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <mostrar_mat@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
data_type: string
name: unpack_data
arguments: data_label: D9
data_type: string

tool: D18: Troca da linha %d com a linha %d!


tool: D9: 
Matriz alterada: 

assistant: ```c
void troca_linha(int mat[3][3], int origem, int destino) {
  int i = 0, aux[3];
  printf("Troca da linha %d com a linha %d!\n", origem, destino);
  for (i = 0; i < 3; i++) {
    aux[i] = mat[origem][i];
    mat[origem][i] = mat[destino][i];
    mat[destino][i] = aux[i];
  }
  printf("\nMatriz alterada: \n");
  mostrar_mat(mat);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<troca_linha>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    D1(%rip),%rdi
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  movslq %edx,%rbx
  mov    %ebp,%esi
  mov    %ebx,%edx
  call   <printf@plt>
  lea    0x0(%rbp,%rbp,2),%rax
  lea    D12(%rip),%rdi
  lea    (%r12,%rax,4),%rdx
  lea    (%rbx,%rbx,2),%rax
  lea    (%r12,%rax,4),%rax
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    0x4(%rax),%esi
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%ecx
  mov    %esi,0x4(%rdx)
  mov    0x8(%rax),%esi
  mov    %ecx,0x4(%rax)
  mov    0x8(%rdx),%ecx
  mov    %esi,0x8(%rdx)
  mov    %ecx,0x8(%rax)
  call   <puts@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <mostrar_mat@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D12
type: string

tool: D1: Troca da linha %d com a linha %d!


tool: D12: 
Matriz alterada: 

assistant: ```c
void troca_linha(int mat[3][3], int origem, int destino) {
  int i = 0, aux[3];
  printf("Troca da linha %d com a linha %d!\n", origem, destino);
  for (i = 0; i < 3; i++) {
    aux[i] = mat[origem][i];
    mat[origem][i] = mat[destino][i];
    mat[destino][i] = aux[i];
  }
  printf("\nMatriz alterada: \n");
  mostrar_mat(mat);
}
```
user: What is the c source code of the assembly code below:

```asm
<troca_linha>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    D2(%rip),%rdi
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  movslq %edx,%rbx
  mov    %ebp,%esi
  mov    %ebx,%edx
  call   <printf@plt>
  lea    0x0(%rbp,%rbp,2),%rsi
  lea    (%rbx,%rbx,2),%rdx
  shl    $0x2,%rsi
  shl    $0x2,%rdx
  lea    0x8(%rsi),%rdi
  lea    (%r12,%rsi,1),%rcx
  lea    (%r12,%rdx,1),%rax
  cmp    %rdx,%rdi
  jle    L14
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jg     L24
L14:
  mov    (%rcx),%rdx
  mov    (%rax),%rsi
  mov    %rsi,(%rcx)
  mov    0x8(%rax),%esi
  mov    %rdx,(%rax)
  mov    0x8(%rcx),%edx
  mov    %esi,0x8(%rcx)
  mov    %edx,0x8(%rax)
L26:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <mostrar_mat@plt>
  xchg   %ax,%ax
L24:
  mov    (%rcx),%edx
  mov    (%rax),%esi
  mov    %esi,(%rcx)
  mov    0x4(%rax),%esi
  mov    %edx,(%rax)
  mov    0x4(%rcx),%edx
  mov    %esi,0x4(%rcx)
  mov    0x8(%rax),%esi
  mov    %edx,0x4(%rax)
  mov    0x8(%rcx),%edx
  mov    %esi,0x8(%rcx)
  mov    %edx,0x8(%rax)
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D16
datatype: string

tool: D2: Troca da linha %d com a linha %d!


tool: D16: 
Matriz alterada: 

assistant: ```c
void troca_linha(int mat[3][3], int origem, int destino) {
  int i = 0, aux[3];
  printf("Troca da linha %d com a linha %d!\n", origem, destino);
  for (i = 0; i < 3; i++) {
    aux[i] = mat[origem][i];
    mat[origem][i] = mat[destino][i];
    mat[destino][i] = aux[i];
  }
  printf("\nMatriz alterada: \n");
  mostrar_mat(mat);
}
```