ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<MinHeapify>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L20:
  movslq %r12d,%rdx
  movslq %ebp,%rax
  mov    0x0(%r13,%rdx,4),%ecx
  cmp    %ecx,0x0(%r13,%rax,4)
  jge    L44
  cmp    %r14d,%ebx
  jl     L59
  mov    %ebp,%ebx
L35:
  cmp    %r12d,%ebx
  je     L75
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <Swap@plt>
L58:
  mov    %r12d,%edi
  call   <LeftChild@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <RightChild@plt>
  mov    %eax,%ebx
  cmp    %r14d,%ebp
  jl     L20
L44:
  cmp    %r14d,%ebx
  jge    L75
  movslq %r12d,%rdx
  movslq %ebx,%rax
  mov    0x0(%r13,%rdx,4),%ecx
  cmp    %ecx,0x0(%r13,%rax,4)
  jl     L35
L75:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  movslq %ebx,%rdx
  mov    0x0(%r13,%rax,4),%eax
  cmp    %eax,0x0(%r13,%rdx,4)
  cmovge %ebp,%ebx
  jmp    L35
```

assistant: ```c
int MinHeapify(int *Arr, int Root, int Size) {
  int Smallest = Root;
  int Left = LeftChild(Root);
  int Right = RightChild(Root);
  if ((Left < Size) && (Arr[Left] < Arr[Smallest]))
    Smallest = Left;
  if ((Right < Size) && (Arr[Right] < Arr[Smallest]))
    Smallest = Right;
  if (Smallest != Root) {
    Swap(Arr, Smallest, Root);
    MinHeapify(Arr, Smallest, Size);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MinHeapify>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L61:
  movslq %r12d,%rdx
  movslq %ebp,%rax
  mov    0x0(%r13,%rdx,4),%ecx
  cmp    %ecx,0x0(%r13,%rax,4)
  jge    L60
  cmp    %r14d,%ebx
  jl     L77
  mov    %ebp,%ebx
L15:
  cmp    %r12d,%ebx
  je     L78
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <Swap@plt>
L3:
  mov    %r12d,%edi
  call   <LeftChild@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <RightChild@plt>
  mov    %eax,%ebx
  cmp    %r14d,%ebp
  jl     L61
L60:
  cmp    %r14d,%ebx
  jge    L78
  movslq %r12d,%rdx
  movslq %ebx,%rax
  mov    0x0(%r13,%rdx,4),%ecx
  cmp    %ecx,0x0(%r13,%rax,4)
  jl     L15
L78:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  movslq %ebx,%rdx
  mov    0x0(%r13,%rax,4),%eax
  cmp    %eax,0x0(%r13,%rdx,4)
  cmovge %ebp,%ebx
  jmp    L15
```

assistant: ```c
int MinHeapify(int *Arr, int Root, int Size) {
  int Smallest = Root;
  int Left = LeftChild(Root);
  int Right = RightChild(Root);
  if ((Left < Size) && (Arr[Left] < Arr[Smallest]))
    Smallest = Left;
  if ((Right < Size) && (Arr[Right] < Arr[Smallest]))
    Smallest = Right;
  if (Smallest != Root) {
    Swap(Arr, Smallest, Root);
    MinHeapify(Arr, Smallest, Size);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<display_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <lc75710_display_hal_init@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <display_set_cursor@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void display_init(void) {
  lc75710_display_hal_init();
  display_set_cursor(0, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <lc75710_display_hal_init@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <display_set_cursor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void display_init(void) {
  lc75710_display_hal_init();
  display_set_cursor(0, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<display_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lc75710_display_hal_init@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <display_set_cursor@plt>
```

assistant: ```c
void display_init(void) {
  lc75710_display_hal_init();
  display_set_cursor(0, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_expect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc4(%rbp),%edx
  mov    -0xb4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <_vexpect@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void _expect(int dummy, ...) {
  va_list ap;
  va_start(ap, dummy);
  _vexpect(ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_expect>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edi
  call   <_vexpect@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  pop    %rbx
  ret
```

assistant: ```c
void _expect(int dummy, ...) {
  va_list ap;
  va_start(ap, dummy);
  _vexpect(ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_expect>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <_vexpect@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void _expect(int dummy, ...) {
  va_list ap;
  va_start(ap, dummy);
  _vexpect(ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_expect>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <_vexpect@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void _expect(int dummy, ...) {
  va_list ap;
  va_start(ap, dummy);
  _vexpect(ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L5
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  jmp    L10
L5:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  movzbl -0x9(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int get(void *arg) {
  const unsigned char **s = arg;
  unsigned char c = **s;
  if (!c)
    return EOF;
  (*s)++;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  movzbl %al,%eax
  ret
L0:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int get(void *arg) {
  const unsigned char **s = arg;
  unsigned char c = **s;
  if (!c)
    return EOF;
  (*s)++;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int get(void *arg) {
  const unsigned char **s = arg;
  unsigned char c = **s;
  if (!c)
    return EOF;
  (*s)++;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int get(void *arg) {
  const unsigned char **s = arg;
  unsigned char c = **s;
  if (!c)
    return EOF;
  (*s)++;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<testmain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <test_alignas@plt>
  mov    $0x0,%eax
  call   <test_alignof@plt>
  mov    $0x0,%eax
  call   <test_constexpr@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: alignment

assistant: ```c
void testmain() {
  print("alignment");
  test_alignas();
  test_alignof();
  test_constexpr();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<testmain>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <test_alignas@plt>
  mov    $0x0,%eax
  call   <test_alignof@plt>
  mov    $0x0,%eax
  call   <test_constexpr@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: alignment

assistant: ```c
void testmain() {
  print("alignment");
  test_alignas();
  test_alignof();
  test_constexpr();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testmain>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <print@plt>
  xor    %eax,%eax
  call   <test_alignas@plt>
  xor    %eax,%eax
  call   <test_alignof@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <test_constexpr@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: alignment

assistant: ```c
void testmain() {
  print("alignment");
  test_alignas();
  test_alignof();
  test_constexpr();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<testmain>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <print@plt>
  xor    %eax,%eax
  call   <test_alignas@plt>
  xor    %eax,%eax
  call   <test_alignof@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <test_constexpr@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: alignment

assistant: ```c
void testmain() {
  print("alignment");
  test_alignas();
  test_alignof();
  test_constexpr();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  jmp    L49
L13:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
L49:
  cmpb   $0xa,-0x1(%rbp)
  je     L13
  movsbl -0x1(%rbp),%eax
  cmp    $0x33,%eax
  je     L50
  cmp    $0x33,%eax
  jg     L44
  cmp    $0x31,%eax
  je     L104
  cmp    $0x32,%eax
  je     L51
  jmp    L44
L104:
  mov    $0x0,%eax
  call   <bist@plt>
  jmp    L40
L51:
  mov    $0x0,%eax
  call   <dump_registers@plt>
  jmp    L40
L50:
  mov    $0x0,%eax
  call   <write_register@plt>
  jmp    L40
L44:
  mov    $0x1,%eax
  jmp    L10
L40:
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type: string
name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D47
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D13
type: string

tool: D24: 1. Run BIST (No stat)


tool: D11: 2. Dump registers


tool: D47: 3. Write Registers


tool: D0: 4. Quit


tool: D13: Enter command : 

assistant: ```c
int do_menu() {
  printf("1. Run BIST (No stat)\n");
  printf("2. Dump registers\n");
  printf("3. Write Registers\n");
  printf("4. Quit\n");
  printf("Enter command : ");
  char c = getchar();
  while (c == '\n')
    c = getchar();
  switch (c) {
  case '1':
    bist();
    break;
  case '2':
    dump_registers();
    break;
  case '3':
    write_register();
    break;
  default:
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L21
L22:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L22
L21:
  cmp    $0x32,%al
  je     L58
  cmp    $0x33,%al
  je     L29
  mov    $0x1,%edx
  cmp    $0x31,%al
  je     L3
L66:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <bist@plt>
  mov    $0x0,%edx
  jmp    L66
L58:
  mov    $0x0,%eax
  call   <dump_registers@plt>
  mov    $0x0,%edx
  jmp    L66
L29:
  mov    $0x0,%eax
  call   <write_register@plt>
  mov    $0x0,%edx
  jmp    L66
```

tool_calls: name: disassemble_data
arguments: tag: D35
type: string
name: disassemble_data
arguments: tag: D28
type: string
name: disassemble_data
arguments: tag: D48
type: string
name: disassemble_data
arguments: tag: D34
type: string
name: disassemble_data
arguments: tag: D17
type: string

tool: D35: 1. Run BIST (No stat)


tool: D28: 2. Dump registers


tool: D48: 3. Write Registers


tool: D34: 4. Quit


tool: D17: Enter command : 

assistant: ```c
int do_menu() {
  printf("1. Run BIST (No stat)\n");
  printf("2. Dump registers\n");
  printf("3. Write Registers\n");
  printf("4. Quit\n");
  printf("Enter command : ");
  char c = getchar();
  while (c == '\n')
    c = getchar();
  switch (c) {
  case '1':
    bist();
    break;
  case '2':
    dump_registers();
    break;
  case '3':
    write_register();
    break;
  default:
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L20
  cmp    $0x32,%al
  je     L7
  cmp    $0x33,%al
  je     L0
  mov    $0x1,%r8d
  cmp    $0x31,%al
  je     L8
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <dump_registers@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <bist@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <write_register@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D34
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D23
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string

tool: D12: 1. Run BIST (No stat)


tool: D34: 2. Dump registers


tool: D7: 3. Write Registers


tool: D23: 4. Quit


tool: D9: Enter command : 

assistant: ```c
int do_menu() {
  printf("1. Run BIST (No stat)\n");
  printf("2. Dump registers\n");
  printf("3. Write Registers\n");
  printf("4. Quit\n");
  printf("Enter command : ");
  char c = getchar();
  while (c == '\n')
    c = getchar();
  switch (c) {
  case '1':
    bist();
    break;
  case '2':
    dump_registers();
    break;
  case '3':
    write_register();
    break;
  default:
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L14
  cmp    $0x32,%al
  je     L25
  cmp    $0x33,%al
  je     L13
  mov    $0x1,%r8d
  cmp    $0x31,%al
  je     L2
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L25:
  xor    %eax,%eax
  call   <dump_registers@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <bist@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <write_register@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D48
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D0: 1. Run BIST (No stat)


tool: D48: 2. Dump registers


tool: D1: 3. Write Registers


tool: D4: 4. Quit


tool: D9: Enter command : 

assistant: ```c
int do_menu() {
  printf("1. Run BIST (No stat)\n");
  printf("2. Dump registers\n");
  printf("3. Write Registers\n");
  printf("4. Quit\n");
  printf("Enter command : ");
  char c = getchar();
  while (c == '\n')
    c = getchar();
  switch (c) {
  case '1':
    bist();
    break;
  case '2':
    dump_registers();
    break;
  case '3':
    write_register();
    break;
  default:
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_sgml>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L19
L5:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <parse_line@plt>
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x3e8,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void parse_sgml(FILE *in, char *input_name) {
  static char line[1000];
  while (fgets(line, 1000, in)) {
    parse_line(line, input_name);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_sgml>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  lea    D0(%rip),%rbx
  jmp    L13
L2:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <parse_line@plt>
L13:
  mov    %rbp,%rdx
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void parse_sgml(FILE *in, char *input_name) {
  static char line[1000];
  while (fgets(line, 1000, in)) {
    parse_line(line, input_name);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_sgml>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D1(%rip),%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <parse_line@plt>
L13:
  mov    %rbp,%rdx
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void parse_sgml(FILE *in, char *input_name) {
  static char line[1000];
  while (fgets(line, 1000, in)) {
    parse_line(line, input_name);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_sgml>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D6(%rip),%rbx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <parse_line@plt>
L6:
  mov    %rbp,%rdx
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void parse_sgml(FILE *in, char *input_name) {
  static char line[1000];
  while (fgets(line, 1000, in)) {
    parse_line(line, input_name);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc4(%rbp)
  jmp    L90
L83:
  movl   $0x0,-0xc0(%rbp)
  jmp    L70
L68:
  lea    -0xa0(%rbp),%rcx
  mov    -0xc0(%rbp),%eax
  movslq %eax,%rsi
  mov    -0xc4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xc0(%rbp)
L70:
  cmpl   $0x5,-0xc0(%rbp)
  jle    L68
  addl   $0x1,-0xc4(%rbp)
L90:
  cmpl   $0x5,-0xc4(%rbp)
  jle    L83
  movl   $0x0,-0xb0(%rbp)
  movl   $0xffffffd2,-0xbc(%rbp)
  movl   $0x0,-0xb8(%rbp)
  jmp    L40
L36:
  movl   $0x0,-0xb4(%rbp)
  jmp    L3
L51:
  mov    -0xb8(%rbp),%edx
  mov    -0xb4(%rbp),%ecx
  lea    -0xa0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <get_sum@plt>
  mov    %eax,-0xac(%rbp)
  mov    -0xac(%rbp),%eax
  cmp    -0xbc(%rbp),%eax
  jle    L65
  mov    -0xac(%rbp),%eax
  mov    %eax,-0xbc(%rbp)
  mov    -0xb4(%rbp),%eax
  mov    %eax,-0xa8(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,-0xa4(%rbp)
L65:
  addl   $0x1,-0xb4(%rbp)
L3:
  cmpl   $0x3,-0xb4(%rbp)
  jle    L51
  addl   $0x1,-0xb8(%rbp)
L40:
  cmpl   $0x3,-0xb8(%rbp)
  jle    L36
  mov    -0xbc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D5: %d

tool: D18: %d


assistant: ```c
int main() {
  int arr[6][6];
  for (int i = 0; i < 6; i++) {
    for (int j = 0; j < 6; j++) {
      scanf("%d", &(arr[i][j]));
    }
  }
  int curr = 0;
  int max_sum = -46;
  int max_x;
  int max_y;
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      int hsum = get_sum(arr, j, i);
      if (hsum > max_sum) {
        max_sum = hsum;
        max_x = j;
        max_y = i;
      }
    }
  }
  printf("%d\n", max_sum);
  return 0;
}
```