ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<orderRow>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r15d
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%r14
  mov    $0x0,%edi
  mov    %rax,%r12
L1:
  lea    0x1(%rdi),%r13d
  cmp    %r13d,%ebx
  je     L32
  mov    %r14,%rcx
  mov    %edi,%edx
  mov    %r13d,%eax
L39:
  movslq %edx,%rsi
  lea    (%rsi,%rsi,4),%rsi
  lea    0x0(%rbp,%rsi,4),%rsi
  mov    (%rsi,%r12,4),%esi
  cmp    %esi,0x14(%rcx)
  cmovl  %eax,%edx
  add    $0x1,%eax
  add    $0x14,%rcx
  cmp    %eax,%ebx
  jne    L39
  mov    %r15d,%ecx
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <swapRow@plt>
  add    $0x14,%r14
  mov    %r13d,%edi
  jmp    L1
L32:
  mov    %r15d,%ecx
  mov    %edi,%edx
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <swapRow@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  ret
```

assistant: ```c
void orderRow(int matriz[4][5], int fils, int cols, int colSwap) {
  int i, j, minor, n;
  for (i = 0; i < fils; i++) {
    minor = i;
    for (j = (i + 1); j < fils; j++) {
      if (matriz[j][colSwap] < matriz[minor][colSwap]) {
        minor = j;
      }
    }
    swapRow(matriz, i, minor, cols);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<orderRow>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %r15
  xor    %r8d,%r8d
  mov    %rdi,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  lea    0x1(%r8),%r12d
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    (%rdi,%rbp,4),%r13
  sub    $0x8,%rsp
  cmp    %r12d,%ebx
  je     L22
  nopl   (%rax)
L12:
  mov    %r13,%rcx
  mov    %r8d,%edx
  mov    %r12d,%eax
  nopl   0x0(%rax)
L0:
  movslq %edx,%rsi
  lea    (%rsi,%rsi,4),%rsi
  lea    (%r15,%rsi,4),%rsi
  mov    (%rsi,%rbp,4),%edi
  cmp    %edi,0x14(%rcx)
  cmovl  %eax,%edx
  add    $0x1,%eax
  add    $0x14,%rcx
  cmp    %eax,%ebx
  jne    L0
  mov    %r8d,%esi
  mov    %r14d,%ecx
  mov    %r15,%rdi
  add    $0x14,%r13
  call   <swapRow@plt>
  mov    %r12d,%r8d
  lea    0x1(%r8),%r12d
  cmp    %r12d,%ebx
  jne    L12
L22:
  add    $0x8,%rsp
  mov    %r14d,%ecx
  mov    %r15,%rdi
  mov    %r8d,%edx
  pop    %rbx
  mov    %r8d,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <swapRow@plt>
L16:
  ret
```

assistant: ```c
void orderRow(int matriz[4][5], int fils, int cols, int colSwap) {
  int i, j, minor, n;
  for (i = 0; i < fils; i++) {
    minor = i;
    for (j = (i + 1); j < fils; j++) {
      if (matriz[j][colSwap] < matriz[minor][colSwap]) {
        minor = j;
      }
    }
    swapRow(matriz, i, minor, cols);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<orderRow>:
  endbr64
  test   %esi,%esi
  jle    L48
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x1,%esi
  je     L23
  movslq %ecx,%rcx
  mov    $0x1,%ebp
  lea    0x14(%rdi,%rcx,4),%r12
  xchg   %ax,%ax
L14:
  lea    -0x1(%rbp),%r9d
  mov    -0x14(%r12),%esi
  mov    %r12,%rdx
  mov    %ebp,%eax
  mov    %r9d,%r8d
  nopl   0x0(%rax)
L28:
  mov    (%rdx),%ecx
  cmp    %ecx,%esi
  jle    L32
  mov    %ecx,%esi
  mov    %eax,%r8d
L32:
  add    $0x1,%eax
  add    $0x14,%rdx
  cmp    %eax,%ebx
  jg     L28
  mov    %r13d,%ecx
  mov    %r8d,%edx
  mov    %r9d,%esi
  mov    %r14,%rdi
  call   <swapRow@plt>
  add    $0x1,%ebp
  add    $0x14,%r12
  cmp    %ebp,%ebx
  jne    L14
L23:
  lea    -0x1(%rbx),%esi
  mov    %r13d,%ecx
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  mov    %esi,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <swapRow@plt>
L48:
  ret
```

assistant: ```c
void orderRow(int matriz[4][5], int fils, int cols, int colSwap) {
  int i, j, minor, n;
  for (i = 0; i < fils; i++) {
    minor = i;
    for (j = (i + 1); j < fils; j++) {
      if (matriz[j][colSwap] < matriz[minor][colSwap]) {
        minor = j;
      }
    }
    swapRow(matriz, i, minor, cols);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<s_align_pmat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L11
L6:
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x30(%rbp)
  imul   -0x30(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %edx,%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  imul   -0x30(%rbp),%eax
  imul   0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %edx,%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L27:
  mov    -0x14(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L27
  addl   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void s_align_pmat(int row, int col, int offset, int bs, float *A, int sda, float *B, int sdb) {
  int i, j;
  float *ptrA, *ptrB;
  for (i = 0; i < row; i++) {
    ptrA = A + ((offset + i) / bs) * bs * sda + ((offset + i) % bs);
    ptrB = B + (i / bs) * bs * sdb + (i % bs);
    for (j = 0; j < col; j++) {
      ptrB[j * bs] = ptrA[j * bs];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_align_pmat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r11d
  mov    0x30(%rsp),%r12
  mov    0x38(%rsp),%ebp
  test   %edi,%edi
  jle    L4
  mov    %edx,%ebx
  mov    %ecx,%edi
  movslq %ecx,%rcx
  shl    $0x2,%rcx
  mov    $0x0,%r10d
L31:
  lea    (%rbx,%r10,1),%eax
  cltd
  idiv   %edi
  imul   %edi,%eax
  imul   %r9d,%eax
  cltq
  movslq %edx,%rdx
  lea    (%rax,%rdx,1),%r13
  mov    %r10d,%eax
  cltd
  idiv   %edi
  imul   %edi,%eax
  imul   %ebp,%eax
  cltq
  movslq %edx,%rdx
  add    %rdx,%rax
  test   %esi,%esi
  jle    L35
  lea    (%r8,%r13,4),%r14
  lea    (%r12,%rax,4),%r13
  mov    $0x0,%eax
  mov    $0x0,%edx
L23:
  movss  (%r14,%rax,1),%xmm0
  movss  %xmm0,0x0(%r13,%rax,1)
  add    $0x1,%edx
  add    %rcx,%rax
  cmp    %edx,%esi
  jne    L23
L35:
  add    $0x1,%r10d
  cmp    %r10d,%r11d
  jne    L31
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void s_align_pmat(int row, int col, int offset, int bs, float *A, int sda, float *B, int sdb) {
  int i, j;
  float *ptrA, *ptrB;
  for (i = 0; i < row; i++) {
    ptrA = A + ((offset + i) / bs) * bs * sda + ((offset + i) % bs);
    ptrB = B + (i / bs) * bs * sdb + (i % bs);
    for (j = 0; j < col; j++) {
      ptrB[j * bs] = ptrA[j * bs];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<s_align_pmat>:
  endbr64
  push   %r14
  mov    %edi,%r11d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x30(%rsp),%r12
  mov    0x38(%rsp),%ebp
  test   %edi,%edi
  jle    L8
  mov    %ecx,%edi
  movslq %ecx,%rcx
  mov    %edx,%ebx
  xor    %r10d,%r10d
  shl    $0x2,%rcx
  nopw   0x0(%rax,%rax,1)
L31:
  lea    (%r10,%rbx,1),%eax
  cltd
  idiv   %edi
  imul   %edi,%eax
  movslq %edx,%rdx
  imul   %r9d,%eax
  cltq
  lea    (%rax,%rdx,1),%r13
  mov    %r10d,%eax
  cltd
  idiv   %edi
  imul   %edi,%eax
  movslq %edx,%rdx
  imul   %ebp,%eax
  cltq
  add    %rdx,%rax
  test   %esi,%esi
  jle    L1
  lea    (%r8,%r13,4),%r14
  xor    %edx,%edx
  lea    (%r12,%rax,4),%r13
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L34:
  movss  (%r14,%rax,1),%xmm0
  add    $0x1,%edx
  movss  %xmm0,0x0(%r13,%rax,1)
  add    %rcx,%rax
  cmp    %edx,%esi
  jne    L34
L1:
  add    $0x1,%r10d
  cmp    %r10d,%r11d
  jne    L31
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void s_align_pmat(int row, int col, int offset, int bs, float *A, int sda, float *B, int sdb) {
  int i, j;
  float *ptrA, *ptrB;
  for (i = 0; i < row; i++) {
    ptrA = A + ((offset + i) / bs) * bs * sda + ((offset + i) % bs);
    ptrB = B + (i / bs) * bs * sdb + (i % bs);
    for (j = 0; j < col; j++) {
      ptrB[j * bs] = ptrA[j * bs];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x7d(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L46
L25:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,-0x7d(%rbp)
  jne    L4
  addl   $0x1,-0x74(%rbp)
  mov    -0x7c(%rbp),%eax
  cltq
  lea    -0x70(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  lea    -0x70(%rbp),%rax
  add    %rax,%rcx
  mov    -0x7c(%rbp),%eax
  cltq
  lea    -0x70(%rbp),%rsi
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  subl   $0x1,-0x7c(%rbp)
  subl   $0x1,-0x78(%rbp)
L4:
  mov    -0x7c(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jne    L8
  movsbl -0x7d(%rbp),%eax
  mov    -0x74(%rbp),%edx
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x7d(%rbp)
  movl   $0xffffffff,-0x7c(%rbp)
  movl   $0x0,-0x74(%rbp)
L8:
  addl   $0x1,-0x7c(%rbp)
L46:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D18
datatype: string

tool: D28: Enter string

tool: D8: %s

tool: D18: ch=%c...cnt=%d


assistant: ```c
main() {
  int i, j, cnt = 0;
  char str[100], ch;
  printf("Enter string\n");
  scanf("%s", &str);
  j = strlen(str) - 1;
  ch = str[j];
  for (i = 0; str[i]; i++) {
    if (ch == str[i]) {
      cnt++;
      memmove(str + i, str + i + 1, strlen(str + i) + 1);
      --i;
      --j;
    }
    if (i == j) {
      printf("ch=%c...cnt=%d\n", ch, cnt);
      ch = str[j];
      i = -1;
      cnt = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  movslq %ebp,%rax
  movzbl 0x10(%rsp,%rax,1),%r12d
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L2
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  jmp    L23
L63:
  cmp    %ebp,%ebx
  je     L64
L25:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x10(%rsp,%rax,1),%eax
  test   %al,%al
  je     L2
L23:
  cmp    %r12b,%al
  jne    L63
  add    $0x1,%r13d
  movslq %ebx,%r14
  lea    0x10(%rsp),%r15
  lea    (%r15,%r14,1),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  lea    0x1(%r15,%r14,1),%rsi
  mov    0x8(%rsp),%rdi
  call   <memmove@plt>
  sub    $0x1,%ebx
  sub    $0x1,%ebp
  jmp    L63
L64:
  movsbl %r12b,%esi
  mov    %r13d,%edx
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebp,%rax
  movzbl 0x10(%rsp,%rax,1),%r12d
  mov    $0x0,%r13d
  mov    $0xffffffff,%ebx
  jmp    L25
L2:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D0
datatype: string

tool: D3: Enter string

tool: D29: %s

tool: D0: ch=%c...cnt=%d


assistant: ```c
main() {
  int i, j, cnt = 0;
  char str[100], ch;
  printf("Enter string\n");
  scanf("%s", &str);
  j = strlen(str) - 1;
  ch = str[j];
  for (i = 0; str[i]; i++) {
    if (ch == str[i]) {
      cnt++;
      memmove(str + i, str + i + 1, strlen(str + i) + 1);
      --i;
      --j;
    }
    if (i == j) {
      printf("ch=%c...cnt=%d\n", ch, cnt);
      ch = str[j];
      i = -1;
      cnt = 0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D19(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%r14d
  movslq %r14d,%rax
  movzbl 0x10(%rsp,%rax,1),%ebp
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  jne    L31
  jmp    L73
L66:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x10(%rsp,%rax,1),%eax
  test   %al,%al
  je     L73
L31:
  cmp    %bpl,%al
  je     L8
L39:
  cmp    %r14d,%ebx
  jne    L66
  movsbl %bpl,%esi
  mov    %r15d,%edx
  movslq %ebx,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
  movzbl 0x10(%rsp,%rbx,1),%ebp
  xor    %ebx,%ebx
  movslq %ebx,%rax
  movzbl 0x10(%rsp,%rax,1),%eax
  test   %al,%al
  jne    L31
  nopl   0x0(%rax,%rax,1)
L73:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  movslq %ebx,%rcx
  add    $0x1,%r15d
  sub    $0x1,%ebx
  sub    $0x1,%r14d
  lea    (%r12,%rcx,1),%rdi
  mov    %rcx,0x8(%rsp)
  mov    %rdi,(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rdi
  lea    0x1(%rax),%edx
  lea    0x1(%r12,%rcx,1),%rsi
  call   <memmove@plt>
  jmp    L39
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string

tool: D19: Enter string

tool: D6: ch=%c...cnt=%d


tool: D21: %s

assistant: ```c
main() {
  int i, j, cnt = 0;
  char str[100], ch;
  printf("Enter string\n");
  scanf("%s", &str);
  j = strlen(str) - 1;
  ch = str[j];
  for (i = 0; str[i]; i++) {
    if (ch == str[i]) {
      cnt++;
      memmove(str + i, str + i + 1, strlen(str + i) + 1);
      --i;
      --j;
    }
    if (i == j) {
      printf("ch=%c...cnt=%d\n", ch, cnt);
      ch = str[j];
      i = -1;
      cnt = 0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D23(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  mov    %r13,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%r12d
  movslq %r12d,%rax
  movzbl 0x10(%rsp,%rax,1),%ebp
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L50
  xchg   %ax,%ax
L15:
  cmp    %bpl,%al
  je     L37
L36:
  cmp    %r12d,%ebx
  je     L53
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x10(%rsp,%rax,1),%eax
  test   %al,%al
  jne    L15
L50:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L53:
  movsbl %bpl,%esi
  mov    %r15d,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x10(%rsp),%eax
  movslq %ebx,%rbx
  movzbl 0x10(%rsp,%rbx,1),%ebp
  test   %al,%al
  je     L50
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  cmp    %bpl,%al
  jne    L36
  nopl   0x0(%rax)
L37:
  movslq %ebx,%rcx
  add    $0x1,%r15d
  sub    $0x1,%ebx
  sub    $0x1,%r12d
  lea    0x0(%r13,%rcx,1),%rdi
  mov    %rcx,0x8(%rsp)
  mov    %rdi,(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rdi
  lea    0x1(%rax),%edx
  lea    0x1(%r13,%rcx,1),%rsi
  call   <memmove@plt>
  jmp    L36
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D23: Enter string

tool: D25: ch=%c...cnt=%d


tool: D13: %s

assistant: ```c
main() {
  int i, j, cnt = 0;
  char str[100], ch;
  printf("Enter string\n");
  scanf("%s", &str);
  j = strlen(str) - 1;
  ch = str[j];
  for (i = 0; str[i]; i++) {
    if (ch == str[i]) {
      cnt++;
      memmove(str + i, str + i + 1, strlen(str + i) + 1);
      --i;
      --j;
    }
    if (i == j) {
      printf("ch=%c...cnt=%d\n", ch, cnt);
      ch = str[j];
      i = -1;
      cnt = 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L1
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L7
L1:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_pow_ui@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_sub_ui@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <LucasLehmerTest@plt>
  test   %rax,%rax
  je     L32
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L32:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    $0x0,%eax
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D29
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string

tool: D29: usage : mersenne p


tool: D3: OK


tool: D19: NG


assistant: ```c
int main(int ac, char *av[]) {
  int p;
  mpz_t m;
  if (ac < 2) {
    printf("usage : mersenne p\n");
    return (1);
  }
  p = strtol(av[1], NULL, 10);
  mpz_init_set_ui(m, 2);
  mpz_pow_ui(m, m, p);
  mpz_sub_ui(m, m, 1);
  if (LucasLehmerTest(m, p))
    printf("OK\n");
  else
    printf("NG\n");
  mpz_clear(m);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L11
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebp
  mov    $0x2,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init_set_ui@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_pow_ui@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <LucasLehmerTest@plt>
  test   %rax,%rax
  je     L17
  lea    D25(%rip),%rdi
  call   <printf@plt>
L1:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_clear@plt>
  mov    $0x0,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L2
L17:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string
name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D25: OK


tool: D1: usage : mersenne p


tool: D5: NG


assistant: ```c
int main(int ac, char *av[]) {
  int p;
  mpz_t m;
  if (ac < 2) {
    printf("usage : mersenne p\n");
    return (1);
  }
  p = strtol(av[1], NULL, 10);
  mpz_init_set_ui(m, 2);
  mpz_pow_ui(m, m, p);
  mpz_sub_ui(m, m, 1);
  if (LucasLehmerTest(m, p))
    printf("OK\n");
  else
    printf("NG\n");
  mpz_clear(m);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L20
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  xor    %ebp,%ebp
  call   <strtol@plt>
  mov    $0x2,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <mpz_init_set_ui@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_pow_ui@plt>
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    $0x1,%edx
  call   <mpz_sub_ui@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <LucasLehmerTest@plt>
  test   %rax,%rax
  jne    L4
  lea    D26(%rip),%rdi
  call   <printf@plt>
L2:
  xor    %edi,%edi
  call   <mpz_clear@plt>
  xor    %eax,%eax
L27:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L20:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L27
```

tool_calls: name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D22
data_type: string

tool: D26: NG


tool: D17: OK


tool: D22: usage : mersenne p


assistant: ```c
int main(int ac, char *av[]) {
  int p;
  mpz_t m;
  if (ac < 2) {
    printf("usage : mersenne p\n");
    return (1);
  }
  p = strtol(av[1], NULL, 10);
  mpz_init_set_ui(m, 2);
  mpz_pow_ui(m, m, p);
  mpz_sub_ui(m, m, 1);
  if (LucasLehmerTest(m, p))
    printf("OK\n");
  else
    printf("NG\n");
  mpz_clear(m);
  return (0);
}
```