ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0x3(%rsp),%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string

tool: D33: Bitte geben Sie eine Zahl ein: 

tool: D18: %i

tool: D22: Geben Sie einen Zeichen ein: 

tool: D29: %c

assistant: ```c
int main(void) {
  int zahl1;
  char zeichen1;
  printf("Bitte geben Sie eine Zahl ein: ");
  scanf("%i", &zahl1);
  printf("Geben Sie einen Zeichen ein: ");
  scanf("%c", &zeichen1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x3(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D26
data_type: string

tool: D22: Bitte geben Sie eine Zahl ein: 

tool: D14: %i

tool: D8: Geben Sie einen Zeichen ein: 

tool: D26: %c

assistant: ```c
int main(void) {
  int zahl1;
  char zeichen1;
  printf("Bitte geben Sie eine Zahl ein: ");
  scanf("%i", &zahl1);
  printf("Geben Sie einen Zeichen ein: ");
  scanf("%c", &zeichen1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x3(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D35
type: string

tool: D9: Bitte geben Sie eine Zahl ein: 

tool: D17: %i

tool: D19: Geben Sie einen Zeichen ein: 

tool: D35: %c

assistant: ```c
int main(void) {
  int zahl1;
  char zeichen1;
  printf("Bitte geben Sie eine Zahl ein: ");
  scanf("%i", &zahl1);
  printf("Geben Sie einen Zeichen ein: ");
  scanf("%c", &zeichen1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CdAudioDeviceControl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L55
  cmpl   $0x3,-0x4(%rbp)
  je     L26
  cmpl   $0x1,-0x4(%rbp)
  je     L45
  cmpl   $0x7,-0x4(%rbp)
  jne    L48
  jmp    L60
L55:
  nop
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CdAudio535DeviceControl@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L22
L26:
  nop
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CdAudio435DeviceControl@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L22
L45:
  nop
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CdAudioAtapiDeviceControl@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L22
L60:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CdAudioHPCdrDeviceControl@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L22
L48:
  nop
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CdAudioSendToNextDriver@plt>
  mov    %eax,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int CdAudioDeviceControl(int DeviceObject, int Irp) {
  int deviceExtension__Active = __VERIFIER_nondet_int();
  int status;
  {
    if (deviceExtension__Active == 2) {
      goto switch_2_2;
    } else {
      if (deviceExtension__Active == 3) {
        goto switch_2_3;
      } else {
        if (deviceExtension__Active == 1) {
          goto switch_2_1;
        } else {
          if (deviceExtension__Active == 7) {
            goto switch_2_7;
          } else {
            goto switch_2_default;
            if (0) {
            switch_2_2 : { status = CdAudio535DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_3 : { status = CdAudio435DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_1 : { status = CdAudioAtapiDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_7 : { status = CdAudioHPCdrDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_default : {
              deviceExtension__Active = 0;
              status = CdAudioSendToNextDriver(DeviceObject, Irp);
            }
            } else {
            switch_2_break:;
            }
          }
        }
      }
    }
    return (status);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CdAudioDeviceControl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x2,%eax
  je     L4
  cmp    $0x3,%eax
  je     L72
  cmp    $0x1,%eax
  je     L71
  cmp    $0x7,%eax
  je     L40
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <CdAudioSendToNextDriver@plt>
L70:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <CdAudio535DeviceControl@plt>
  jmp    L70
L72:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <CdAudio435DeviceControl@plt>
  jmp    L70
L71:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <CdAudioAtapiDeviceControl@plt>
  jmp    L70
L40:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <CdAudioHPCdrDeviceControl@plt>
  jmp    L70
```

assistant: ```c
int CdAudioDeviceControl(int DeviceObject, int Irp) {
  int deviceExtension__Active = __VERIFIER_nondet_int();
  int status;
  {
    if (deviceExtension__Active == 2) {
      goto switch_2_2;
    } else {
      if (deviceExtension__Active == 3) {
        goto switch_2_3;
      } else {
        if (deviceExtension__Active == 1) {
          goto switch_2_1;
        } else {
          if (deviceExtension__Active == 7) {
            goto switch_2_7;
          } else {
            goto switch_2_default;
            if (0) {
            switch_2_2 : { status = CdAudio535DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_3 : { status = CdAudio435DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_1 : { status = CdAudioAtapiDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_7 : { status = CdAudioHPCdrDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_default : {
              deviceExtension__Active = 0;
              status = CdAudioSendToNextDriver(DeviceObject, Irp);
            }
            } else {
            switch_2_break:;
            }
          }
        }
      }
    }
    return (status);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<CdAudioDeviceControl>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  cmp    $0x2,%eax
  je     L39
  cmp    $0x3,%eax
  je     L11
  cmp    $0x1,%eax
  je     L0
  cmp    $0x7,%eax
  je     L16
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10a0 <CdAudioSendToNextDriver@plt>
  nopl   0x0(%rax)
L16:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10c0 <CdAudioHPCdrDeviceControl@plt>
  nopl   0x0(%rax)
L39:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10d0 <CdAudio535DeviceControl@plt>
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10b0 <CdAudio435DeviceControl@plt>
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10f0 <CdAudioAtapiDeviceControl@plt>
```

assistant: ```c
int CdAudioDeviceControl(int DeviceObject, int Irp) {
  int deviceExtension__Active = __VERIFIER_nondet_int();
  int status;
  {
    if (deviceExtension__Active == 2) {
      goto switch_2_2;
    } else {
      if (deviceExtension__Active == 3) {
        goto switch_2_3;
      } else {
        if (deviceExtension__Active == 1) {
          goto switch_2_1;
        } else {
          if (deviceExtension__Active == 7) {
            goto switch_2_7;
          } else {
            goto switch_2_default;
            if (0) {
            switch_2_2 : { status = CdAudio535DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_3 : { status = CdAudio435DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_1 : { status = CdAudioAtapiDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_7 : { status = CdAudioHPCdrDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_default : {
              deviceExtension__Active = 0;
              status = CdAudioSendToNextDriver(DeviceObject, Irp);
            }
            } else {
            switch_2_break:;
            }
          }
        }
      }
    }
    return (status);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CdAudioDeviceControl>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  cmp    $0x2,%eax
  je     L24
  cmp    $0x3,%eax
  je     L26
  cmp    $0x1,%eax
  je     L9
  cmp    $0x7,%eax
  je     L16
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10a0 <CdAudioSendToNextDriver@plt>
  nopl   0x0(%rax)
L16:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10c0 <CdAudioHPCdrDeviceControl@plt>
  nopl   0x0(%rax)
L24:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10d0 <CdAudio535DeviceControl@plt>
  nopl   0x0(%rax)
L26:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10b0 <CdAudio435DeviceControl@plt>
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10f0 <CdAudioAtapiDeviceControl@plt>
```

assistant: ```c
int CdAudioDeviceControl(int DeviceObject, int Irp) {
  int deviceExtension__Active = __VERIFIER_nondet_int();
  int status;
  {
    if (deviceExtension__Active == 2) {
      goto switch_2_2;
    } else {
      if (deviceExtension__Active == 3) {
        goto switch_2_3;
      } else {
        if (deviceExtension__Active == 1) {
          goto switch_2_1;
        } else {
          if (deviceExtension__Active == 7) {
            goto switch_2_7;
          } else {
            goto switch_2_default;
            if (0) {
            switch_2_2 : { status = CdAudio535DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_3 : { status = CdAudio435DeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_1 : { status = CdAudioAtapiDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_7 : { status = CdAudioHPCdrDeviceControl(DeviceObject, Irp); }
              goto switch_2_break;
            switch_2_default : {
              deviceExtension__Active = 0;
              status = CdAudioSendToNextDriver(DeviceObject, Irp);
            }
            } else {
            switch_2_break:;
            }
          }
        }
      }
    }
    return (status);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReadFileWrapper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%r8
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%rdi
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%r9
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%r10
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  push   %r8
  push   %rdi
  mov    %r10,%r8
  mov    %rax,%rdi
  call   <ReadFile@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
void ReadFileWrapper(void *vargs) {
  unsigned long long *args = vargs;
  ReadFile(args[0], args[1], args[2], args[3], args[4], args[5], args[6], args[7]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ReadFileWrapper>:
  endbr64
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rcx
  mov    0x10(%rdi),%rdx
  mov    0x8(%rdi),%rsi
  push   0x38(%rdi)
  push   0x30(%rdi)
  mov    0x28(%rdi),%r9
  mov    0x20(%rdi),%r8
  mov    (%rdi),%rdi
  call   <ReadFile@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void ReadFileWrapper(void *vargs) {
  unsigned long long *args = vargs;
  ReadFile(args[0], args[1], args[2], args[3], args[4], args[5], args[6], args[7]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ReadFileWrapper>:
  endbr64
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rcx
  mov    0x10(%rdi),%rdx
  mov    0x8(%rdi),%rsi
  push   0x38(%rdi)
  push   0x30(%rdi)
  mov    0x28(%rdi),%r9
  mov    0x20(%rdi),%r8
  mov    (%rdi),%rdi
  call   <ReadFile@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void ReadFileWrapper(void *vargs) {
  unsigned long long *args = vargs;
  ReadFile(args[0], args[1], args[2], args[3], args[4], args[5], args[6], args[7]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bucketed>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    $0xd0,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
L60:
  movl   $0x0,0x20(%rsp,%rax,1)
  movl   $0x0,0x90(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x68,%rax
  jne    L60
  mov    %rbx,%rbp
  lea    0xa158(%rbx),%r14
  mov    %rbx,%rdx
L20:
  mov    (%rdx),%rax
  movsbl (%rax),%eax
  sub    $0x41,%eax
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
  addl   $0x1,0x90(%rsp,%rax,4)
  add    $0x8,%rdx
  cmp    %r14,%rdx
  jne    L20
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %r15,0x10(%rsp)
  lea    0x88(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L38
L73:
  addq   $0x4,0x8(%rsp)
  mov    0x8(%rsp),%rax
  addq   $0x8,0x10(%rsp)
  cmp    0x18(%rsp),%rax
  je     L78
L38:
  mov    0x8(%rsp),%rax
  mov    (%rax),%r12d
  lea    0x0(,%r12,8),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%rcx
  mov    %rcx,%r13
  mov    %rax,(%rcx)
  test   %r12d,%r12d
  jle    L73
  mov    %r12d,%r12d
  shl    $0x3,%r12
  mov    $0x0,%ebx
L79:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    0x0(%r13),%rdx
  mov    %rax,(%rdx,%rbx,1)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L79
  jmp    L73
L78:
  mov    0x0(%rbp),%rsi
  movzbl (%rsi),%edx
  movsbl %dl,%eax
  sub    $0x41,%eax
  movsbq %dl,%rcx
  cltq
  mov    0x20(%rsp,%rax,4),%edx
  sub    0x90(%rsp,%rax,4),%edx
  mov    %edx,%eax
  cltq
  mov    -0x208(%r15,%rcx,8),%rdx
  mov    (%rdx,%rax,8),%rdi
  call   <strcpy@plt>
  mov    0x0(%rbp),%rax
  movsbl (%rax),%eax
  sub    $0x41,%eax
  cltq
  subl   $0x1,0x90(%rsp,%rax,4)
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L78
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    %r15,%rax
  add    $0x108,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char ***bucketed(char **arr) {
  char ***buckets = (char ***)malloc(26 * sizeof(char **));
  int count[26], count_iter[26];
  char iter = 'A';
  int i, j;
  for (i = 0; i < 26; i++) {
    count[i] = 0;
    count_iter[i] = 0;
  }
  for (i = 0; i < 5163; i++) {
    count[arr[i][0] - 'A']++;
    count_iter[arr[i][0] - 'A']++;
  }
  for (i = 0; i < 26; i++) {
    buckets[i] = (char **)malloc(count[i] * sizeof(char *));
    for (j = 0; j < count[i]; j++) {
      buckets[i][j] = (char *)malloc(13 * sizeof(char));
    }
  }
  for (i = 0; i < 5163; i++) {
    strcpy(buckets[arr[i][0] - 'A'][(count[arr[i][0] - 'A'] - count_iter[arr[i][0] - 'A'])], arr[i]);
    count_iter[arr[i][0] - 'A']--;
  }
  return buckets;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bucketed>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xd0,%edi
  lea    0xa158(%rbx),%rbp
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <malloc@plt>
  lea    0x80(%rsp),%rdx
  mov    $0xd,%ecx
  mov    %r14,%rdi
  mov    %rax,%r12
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rdx,%rdi
  mov    $0xd,%ecx
  mov    %rbx,%rdx
  rep stos %rax,%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L51:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  movsbl (%rax),%eax
  sub    $0x41,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  addl   $0x1,0x80(%rsp,%rax,4)
  cmp    %rdx,%rbp
  jne    L51
  lea    0x78(%rsp),%rax
  mov    %r14,(%rsp)
  mov    %r12,%r15
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rsp),%rax
  movslq (%rax),%r13
  lea    0x0(,%r13,8),%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  test   %r13d,%r13d
  jle    L0
  shl    $0x3,%r13
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L44:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    (%r15),%rdx
  mov    %rax,(%rdx,%r14,1)
  add    $0x8,%r14
  cmp    %r14,%r13
  jne    L44
L0:
  addq   $0x4,(%rsp)
  add    $0x8,%r15
  mov    (%rsp),%rax
  cmp    %rax,0x8(%rsp)
  jne    L39
  xchg   %ax,%ax
L18:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  movsbl (%rsi),%eax
  mov    %eax,%edx
  sub    $0x41,%eax
  cltq
  movsbq %dl,%rcx
  mov    0x10(%rsp,%rax,4),%edx
  sub    0x80(%rsp,%rax,4),%edx
  movslq %edx,%rax
  mov    -0x208(%r12,%rcx,8),%rdx
  mov    (%rdx,%rax,8),%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbx),%rax
  movsbl (%rax),%eax
  sub    $0x41,%eax
  cltq
  subl   $0x1,0x80(%rsp,%rax,4)
  cmp    %rbp,%rbx
  jne    L18
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xf8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char ***bucketed(char **arr) {
  char ***buckets = (char ***)malloc(26 * sizeof(char **));
  int count[26], count_iter[26];
  char iter = 'A';
  int i, j;
  for (i = 0; i < 26; i++) {
    count[i] = 0;
    count_iter[i] = 0;
  }
  for (i = 0; i < 5163; i++) {
    count[arr[i][0] - 'A']++;
    count_iter[arr[i][0] - 'A']++;
  }
  for (i = 0; i < 26; i++) {
    buckets[i] = (char **)malloc(count[i] * sizeof(char *));
    for (j = 0; j < count[i]; j++) {
      buckets[i][j] = (char *)malloc(13 * sizeof(char));
    }
  }
  for (i = 0; i < 5163; i++) {
    strcpy(buckets[arr[i][0] - 'A'][(count[arr[i][0] - 'A'] - count_iter[arr[i][0] - 'A'])], arr[i]);
    count_iter[arr[i][0] - 'A']--;
  }
  return buckets;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bucketed>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xd0,%edi
  lea    0xa158(%rbx),%rbp
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <malloc@plt>
  lea    0x80(%rsp),%rdx
  mov    $0xd,%ecx
  mov    %r14,%rdi
  mov    %rax,%r12
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rdx,%rdi
  mov    $0xd,%ecx
  mov    %rbx,%rdx
  rep stos %rax,%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L57:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  movsbl (%rax),%eax
  sub    $0x41,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  addl   $0x1,0x80(%rsp,%rax,4)
  cmp    %rdx,%rbp
  jne    L57
  lea    0x78(%rsp),%rax
  mov    %r14,(%rsp)
  mov    %r12,%r15
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L50:
  mov    (%rsp),%rax
  movslq (%rax),%r13
  lea    0x0(,%r13,8),%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  test   %r13d,%r13d
  jle    L43
  shl    $0x3,%r13
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    (%r15),%rdx
  mov    %rax,(%rdx,%r14,1)
  add    $0x8,%r14
  cmp    %r14,%r13
  jne    L48
L43:
  addq   $0x4,(%rsp)
  add    $0x8,%r15
  mov    (%rsp),%rax
  cmp    %rax,0x8(%rsp)
  jne    L50
  xchg   %ax,%ax
L13:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  movsbl (%rsi),%eax
  mov    %eax,%edx
  sub    $0x41,%eax
  cltq
  movsbq %dl,%rcx
  mov    0x10(%rsp,%rax,4),%edx
  sub    0x80(%rsp,%rax,4),%edx
  movslq %edx,%rax
  mov    -0x208(%r12,%rcx,8),%rdx
  mov    (%rdx,%rax,8),%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbx),%rax
  movsbl (%rax),%eax
  sub    $0x41,%eax
  cltq
  subl   $0x1,0x80(%rsp,%rax,4)
  cmp    %rbp,%rbx
  jne    L13
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xf8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char ***bucketed(char **arr) {
  char ***buckets = (char ***)malloc(26 * sizeof(char **));
  int count[26], count_iter[26];
  char iter = 'A';
  int i, j;
  for (i = 0; i < 26; i++) {
    count[i] = 0;
    count_iter[i] = 0;
  }
  for (i = 0; i < 5163; i++) {
    count[arr[i][0] - 'A']++;
    count_iter[arr[i][0] - 'A']++;
  }
  for (i = 0; i < 26; i++) {
    buckets[i] = (char **)malloc(count[i] * sizeof(char *));
    for (j = 0; j < count[i]; j++) {
      buckets[i][j] = (char *)malloc(13 * sizeof(char));
    }
  }
  for (i = 0; i < 5163; i++) {
    strcpy(buckets[arr[i][0] - 'A'][(count[arr[i][0] - 'A'] - count_iter[arr[i][0] - 'A'])], arr[i]);
    count_iter[arr[i][0] - 'A']--;
  }
  return buckets;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<command_secure_display_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%r8
  lea    D8(%rip),%rax
  mov    %rax,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <gui_chat_printf_date_tags@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8:   %s

assistant: ```c
void command_secure_display_data(void *data, struct t_hashtable *hashtable, const void *key, const void *value) {
  (void)data;
  (void)hashtable;
  (void)value;
  if (key)
    gui_chat_printf_date_tags(NULL, 0, NULL, "  %s", key);
}
```