user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L2
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L45
L17:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L45:
  mov    -0x10(%rbp),%eax
  cmp    $0xa,%eax
  jg     L17
  mov    -0x10(%rbp),%eax
  neg    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L42:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L42
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D41
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D36
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D30: 
Enter an integer > 

tool: D41: %d

tool: D38: %d


tool: D36: %d
That's all, have a nice day!


tool: D9: That's all, have a nice day!

assistant: ```c
int main(void) {
  int number, rem;
  printf("\nEnter an integer > ");
  scanf("%d", &number);
  printf("\n");
  if (number < 0) {
    number = abs(number);
    while (number > 10) {
      rem = number % 10;
      printf("%d\n", rem);
      number = number / 10;
    }
    number = number - 2 * number;
    printf("%d\nThat's all, have a nice day!\n", number);
  } else {
    while (number != 0) {
      rem = number % 10;
      printf("%d\n", rem);
      number = number / 10;
    }
    printf("That's all, have a nice day!\n");
  }
  return (0);
}
```