ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000058,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x20(%rsp)
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rsp,%rbx,4),%edx
L17:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L29
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: array[%d]=%d


assistant: ```c
int main(void) {
  int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int i;
  for (i = 10 - 1; i > 4; i--) {
    array[i] = array[i - 1];
  }
  array[4] = 88;
  for (i = 0; i < 10; i++) {
    printf("array[%d]=%d\n", i, array[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x14,%edx
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  movl   $0x9,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <memmove@plt>
  movl   $0x58,0x10(%rsp)
  nopl   (%rax)
L0:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type: string
name: disassemble_data
arguments: data_label: D14
type: byte[16]
name: disassemble_data
arguments: data_label: D23
type: byte[16]

tool: D12: array[%d]=%d


tool: {"D14": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D23": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int i;
  for (i = 10 - 1; i > 4; i--) {
    array[i] = array[i - 1];
  }
  array[4] = 88;
  for (i = 0; i < 10; i++) {
    printf("array[%d]=%d\n", i, array[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<default_heap_alloc_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  leave
  ret
```

assistant: ```c
void *default_heap_alloc_fn(size_t const size, void *context, char const *file, int const line, char const *fn) {
  ((void)(context));
  ((void)(file));
  ((void)(line));
  ((void)(fn));
  return malloc(size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<default_heap_alloc_fn>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *default_heap_alloc_fn(size_t const size, void *context, char const *file, int const line, char const *fn) {
  ((void)(context));
  ((void)(file));
  ((void)(line));
  ((void)(fn));
  return malloc(size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<default_heap_alloc_fn>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *default_heap_alloc_fn(size_t const size, void *context, char const *file, int const line, char const *fn) {
  ((void)(context));
  ((void)(file));
  ((void)(line));
  ((void)(fn));
  return malloc(size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<default_heap_alloc_fn>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *default_heap_alloc_fn(size_t const size, void *context, char const *file, int const line, char const *fn) {
  ((void)(context));
  ((void)(file));
  ((void)(line));
  ((void)(fn));
  return malloc(size);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,-0x14(%rbp)
  mov    %rax,-0x8(%rbp)
  jmp    L12
L1:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
L12:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L39
  mov    -0x14(%rbp),%edx
  lea    -0x1(%rdx),%esi
  mov    %esi,-0x14(%rbp)
  test   %edx,%edx
  jg     L1
  jmp    L39
L6:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movb   $0x0,(%rdx)
L39:
  mov    -0x14(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  mov    %ecx,-0x14(%rbp)
  test   %edx,%edx
  jg     L6
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(s1, s2, n)
register char *s1, *s2;
int n;
{
  char *original = s1;
  while (*s2 && n-- > 0)
    *s1++ = *s2++;
  while (n-- > 0)
    *s1++ = '\0';
  return (original);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L22
  lea    -0x1(%rdx),%ecx
  test   %edx,%edx
  jle    L19
  mov    %rdi,%rdx
L26:
  add    $0x1,%rsi
  add    $0x1,%rdx
  mov    %r8b,-0x1(%rdx)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L24
  sub    $0x1,%ecx
  cmp    $0xffffffff,%ecx
  jne    L26
  ret
L22:
  mov    %edx,%ecx
  mov    %rdi,%rdx
L24:
  test   %ecx,%ecx
  jle    L59
  mov    %ecx,%ecx
  add    %rdx,%rcx
L48:
  add    $0x1,%rdx
  movb   $0x0,-0x1(%rdx)
  cmp    %rdx,%rcx
  jne    L48
  ret
L19:
  mov    %rdi,%rdx
  jmp    L24
L59:
  ret
```

assistant: ```c
char *strncpy(s1, s2, n)
register char *s1, *s2;
int n;
{
  char *original = s1;
  while (*s2 && n-- > 0)
    *s1++ = *s2++;
  while (n-- > 0)
    *s1++ = '\0';
  return (original);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncpy>:
  endbr64
  push   %r12
  movzbl (%rsi),%eax
  mov    %rdi,%r12
  lea    -0x1(%rdx),%r8d
  test   %al,%al
  je     L16
  test   %edx,%edx
  jle    L20
  mov    %r8d,%ecx
  jmp    L7
  nopl   (%rax)
L4:
  cmp    $0xffffffff,%ecx
  je     L28
L7:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  mov    %ecx,%edx
  movzbl (%rsi),%eax
  lea    -0x1(%rcx),%ecx
  test   %al,%al
  jne    L4
  mov    %ecx,%r8d
L16:
  test   %edx,%edx
  jle    L28
  mov    %r8d,%edx
  xor    %esi,%esi
  add    $0x1,%rdx
  call   <memset@plt>
L28:
  mov    %r12,%rax
  pop    %r12
  ret
L20:
  mov    %r8d,%edx
  sub    $0x1,%r8d
  jmp    L16
```

assistant: ```c
char *strncpy(s1, s2, n)
register char *s1, *s2;
int n;
{
  char *original = s1;
  while (*s2 && n-- > 0)
    *s1++ = *s2++;
  while (n-- > 0)
    *s1++ = '\0';
  return (original);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strncpy>:
  endbr64
  push   %r12
  movzbl (%rsi),%ecx
  mov    %rdi,%r12
  test   %cl,%cl
  je     L9
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jg     L15
  jmp    L7
  nopl   0x0(%rax)
L62:
  cmp    $0xffffffff,%eax
  je     L55
L15:
  add    $0x1,%rsi
  mov    %cl,(%rdi)
  add    $0x1,%rdi
  mov    %eax,%edx
  movzbl (%rsi),%ecx
  sub    $0x1,%eax
  test   %cl,%cl
  jne    L62
L52:
  test   %edx,%edx
  jle    L55
  movslq %edx,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L55:
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  mov    %eax,%edx
L9:
  mov    %r12,%rdi
  jmp    L52
```

assistant: ```c
char *strncpy(s1, s2, n)
register char *s1, *s2;
int n;
{
  char *original = s1;
  while (*s2 && n-- > 0)
    *s1++ = *s2++;
  while (n-- > 0)
    *s1++ = '\0';
  return (original);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L17
L4:
  nop
L0:
  mov    $0x16000018,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x20,%eax
  test   %eax,%eax
  jne    L0
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    $0x16000000,%eax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L21
  nop
L59:
  mov    $0x16000018,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x20,%eax
  test   %eax,%eax
  jne    L59
  mov    $0x16000000,%eax
  movb   $0xd,(%rax)
L21:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
L8:
  mov    $0x16000018,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
      ;
    (*(volatile unsigned char *)0x16000000) = *s;
    if (*s == '\n') {
      while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
        ;
      (*(volatile unsigned char *)0x16000000) = '\r';
    }
    s++;
  }
  while ((*(volatile unsigned char *)0x16000018) & (1 << 3))
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puts>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L36
L43:
  movzbl 0x16000018,%eax
  test   $0x8,%al
  jne    L43
  ret
L11:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L43
L36:
  movzbl 0x16000018,%eax
  test   $0x20,%al
  jne    L36
  mov    %dl,0x16000000
  cmpb   $0xa,(%rdi)
  jne    L11
L10:
  movzbl 0x16000018,%eax
  test   $0x20,%al
  jne    L10
  movb   $0xd,0x16000000
  jmp    L11
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
      ;
    (*(volatile unsigned char *)0x16000000) = *s;
    if (*s == '\n') {
      while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
        ;
      (*(volatile unsigned char *)0x16000000) = '\r';
    }
    s++;
  }
  while ((*(volatile unsigned char *)0x16000018) & (1 << 3))
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<puts>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L22
  nopl   0x0(%rax,%rax,1)
L62:
  movzbl 0x16000018,%eax
  test   $0x20,%al
  jne    L62
  mov    %dl,0x16000000
  cmpb   $0xa,(%rdi)
  je     L43
L52:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L62
  nopl   0x0(%rax)
L22:
  movzbl 0x16000018,%eax
  test   $0x8,%al
  jne    L22
  ret
  nopl   (%rax)
L43:
  movzbl 0x16000018,%eax
  test   $0x20,%al
  jne    L43
  movb   $0xd,0x16000000
  jmp    L52
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
      ;
    (*(volatile unsigned char *)0x16000000) = *s;
    if (*s == '\n') {
      while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
        ;
      (*(volatile unsigned char *)0x16000000) = '\r';
    }
    s++;
  }
  while ((*(volatile unsigned char *)0x16000018) & (1 << 3))
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L3
  nopl   0x0(%rax,%rax,1)
L32:
  movzbl 0x16000018,%eax
  test   $0x20,%al
  jne    L32
  mov    %dl,0x16000000
  cmpb   $0xa,(%rdi)
  je     L42
L40:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L32
  nopl   0x0(%rax)
L3:
  movzbl 0x16000018,%eax
  test   $0x8,%al
  jne    L3
  ret
  nopl   (%rax)
L42:
  movzbl 0x16000018,%eax
  test   $0x20,%al
  jne    L42
  movb   $0xd,0x16000000
  jmp    L40
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
      ;
    (*(volatile unsigned char *)0x16000000) = *s;
    if (*s == '\n') {
      while ((*(volatile unsigned char *)0x16000018) & (1 << 5))
        ;
      (*(volatile unsigned char *)0x16000000) = '\r';
    }
    s++;
  }
  while ((*(volatile unsigned char *)0x16000018) & (1 << 3))
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip_nl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x18(%rbp),%rax
  mov    $0xd,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
L9:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L12:
  nop
  leave
  ret
```

assistant: ```c
void strip_nl(char *ptr) {
  char *nl;
  if ((nl = strchr(ptr, '\n')) != NULL || (nl = strchr(ptr, '\r')) != NULL) {
    *nl = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip_nl>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
L21:
  movb   $0x0,(%rax)
L13:
  pop    %rbx
  ret
L12:
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L21
  jmp    L13
```

assistant: ```c
void strip_nl(char *ptr) {
  char *nl;
  if ((nl = strchr(ptr, '\n')) != NULL || (nl = strchr(ptr, '\r')) != NULL) {
    *nl = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strip_nl>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
L17:
  movb   $0x0,(%rax)
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L17
  pop    %rbp
  ret
```

assistant: ```c
void strip_nl(char *ptr) {
  char *nl;
  if ((nl = strchr(ptr, '\n')) != NULL || (nl = strchr(ptr, '\r')) != NULL) {
    *nl = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strip_nl>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
L5:
  movb   $0x0,(%rax)
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L5
  pop    %rbp
  ret
```

assistant: ```c
void strip_nl(char *ptr) {
  char *nl;
  if ((nl = strchr(ptr, '\n')) != NULL || (nl = strchr(ptr, '\r')) != NULL) {
    *nl = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %esi,%edx
  mov    %edx,%ebx
  mov    %ebx,%ecx
  sub    $0x1,%ecx
  cmp    $0x1,%ecx
  jbe    L9
  lea    0x2(%rax),%rcx
  movzbl (%rcx),%ecx
  movzbl %cl,%ecx
  movslq %ecx,%rcx
  lea    D27(%rip),%rsi
  movzbl (%rcx,%rsi,1),%ecx
  movzbl %cl,%ecx
  add    %ecx,%ebx
L9:
  movzbl (%rax),%ecx
  movzbl %cl,%ecx
  movslq %ecx,%rcx
  lea    D27(%rip),%rsi
  movzbl (%rcx,%rsi,1),%ecx
  movzbl %cl,%ecx
  add    %ecx,%ebx
  nop
  sub    $0x1,%edx
  mov    %edx,%edx
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cltq
  lea    D27(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movzbl %al,%eax
  add    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int hash(str, len)
register const char *str;
register unsigned int len;
{
  static const unsigned char asso_values[] = {51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 26, 51, 51, 14, 51, 16, 8, 11, 13, 51, 51, 51, 51, 10, 51, 13, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 11, 51, 13, 1, 26, 4, 1, 8, 28, 51, 23, 51, 1, 1, 27, 5, 19, 21, 51, 8, 3, 3, 11, 51, 21, 24, 16, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51};
  register int hval = len;
  switch (hval) {
  default:
    hval += asso_values[(unsigned char)str[2]];
  case 2:
  case 1:
    hval += asso_values[(unsigned char)str[0]];
    break;
  }
  return hval + asso_values[(unsigned char)str[len - 1]];
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0x1,%eax
  jbe    L7
  movzbl 0x2(%rdi),%edx
  lea    D2(%rip),%rcx
  movzbl (%rcx,%rdx,1),%edx
  add    %edx,%esi
L7:
  lea    D2(%rip),%rdx
  mov    %eax,%eax
  movzbl (%rdi,%rax,1),%eax
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdi),%ecx
  movzbl (%rdx,%rcx,1),%edx
  add    %esi,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash(str, len)
register const char *str;
register unsigned int len;
{
  static const unsigned char asso_values[] = {51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 26, 51, 51, 14, 51, 16, 8, 11, 13, 51, 51, 51, 51, 10, 51, 13, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 11, 51, 13, 1, 26, 4, 1, 8, 28, 51, 23, 51, 1, 1, 27, 5, 19, 21, 51, 8, 3, 3, 11, 51, 21, 24, 16, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51};
  register int hval = len;
  switch (hval) {
  default:
    hval += asso_values[(unsigned char)str[2]];
  case 2:
  case 1:
    hval += asso_values[(unsigned char)str[0]];
    break;
  }
  return hval + asso_values[(unsigned char)str[len - 1]];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    D6(%rip),%rdx
  cmp    $0x1,%eax
  jbe    L9
  movzbl 0x2(%rdi),%ecx
  movzbl (%rdx,%rcx,1),%ecx
  add    %ecx,%esi
L9:
  movzbl (%rdi,%rax,1),%eax
  movzbl (%rdi),%ecx
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdx,%rcx,1),%edx
  add    %esi,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash(str, len)
register const char *str;
register unsigned int len;
{
  static const unsigned char asso_values[] = {51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 26, 51, 51, 14, 51, 16, 8, 11, 13, 51, 51, 51, 51, 10, 51, 13, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 11, 51, 13, 1, 26, 4, 1, 8, 28, 51, 23, 51, 1, 1, 27, 5, 19, 21, 51, 8, 3, 3, 11, 51, 21, 24, 16, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51};
  register int hval = len;
  switch (hval) {
  default:
    hval += asso_values[(unsigned char)str[2]];
  case 2:
  case 1:
    hval += asso_values[(unsigned char)str[0]];
    break;
  }
  return hval + asso_values[(unsigned char)str[len - 1]];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hash>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    D6(%rip),%rdx
  cmp    $0x1,%eax
  jbe    L8
  movzbl 0x2(%rdi),%ecx
  movzbl (%rdx,%rcx,1),%ecx
  add    %ecx,%esi
L8:
  movzbl (%rdi,%rax,1),%eax
  movzbl (%rdi),%ecx
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdx,%rcx,1),%edx
  add    %esi,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash(str, len)
register const char *str;
register unsigned int len;
{
  static const unsigned char asso_values[] = {51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 26, 51, 51, 14, 51, 16, 8, 11, 13, 51, 51, 51, 51, 10, 51, 13, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 11, 51, 13, 1, 26, 4, 1, 8, 28, 51, 23, 51, 1, 1, 27, 5, 19, 21, 51, 8, 3, 3, 11, 51, 21, 24, 16, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51};
  register int hval = len;
  switch (hval) {
  default:
    hval += asso_values[(unsigned char)str[2]];
  case 2:
  case 1:
    hval += asso_values[(unsigned char)str[0]];
    break;
  }
  return hval + asso_values[(unsigned char)str[len - 1]];
}
```