ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gf8mul_10100011>:
  endbr64
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm1
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm0
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm1
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm3
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm1,%xmm0
  pxor   %xmm3,%xmm1
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm1
  ret
```

assistant: ```c
void gf8mul_10100011(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm3\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm1\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: %d 

assistant: ```c
void print_array(int *nums, int sz) {
  for (int i = 0; i < sz; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D3(%rip),%rbp
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L1
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: %d 

assistant: ```c
void print_array(int *nums, int sz) {
  for (int i = 0; i < sz; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: %d 

assistant: ```c
void print_array(int *nums, int sz) {
  for (int i = 0; i < sz; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
void print_array(int *nums, int sz) {
  for (int i = 0; i < sz; i++) {
    printf("%d ", nums[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_trie_string_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L1:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L1
L3:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int _trie_string_cmp(const char *a, const char *b) {
  size_t bytes = 0;
  while (a[bytes] != '\0' && b[bytes] != '\0' && a[bytes] == b[bytes]) {
    bytes++;
  }
  return bytes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_trie_string_cmp>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L27
L14:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  jne    L32
  test   %cl,%cl
  je     L32
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L14
L32:
  ret
L27:
  ret
```

assistant: ```c
int _trie_string_cmp(const char *a, const char *b) {
  size_t bytes = 0;
  while (a[bytes] != '\0' && b[bytes] != '\0' && a[bytes] == b[bytes]) {
    bytes++;
  }
  return bytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_trie_string_cmp>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L4
  jmp    L30
  nop
L37:
  test   %cl,%cl
  je     L1
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L1
L4:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  je     L37
L1:
  ret
L30:
  ret
```

assistant: ```c
int _trie_string_cmp(const char *a, const char *b) {
  size_t bytes = 0;
  while (a[bytes] != '\0' && b[bytes] != '\0' && a[bytes] == b[bytes]) {
    bytes++;
  }
  return bytes;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_trie_string_cmp>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L34
  jmp    L29
  nop
L3:
  test   %cl,%cl
  je     L4
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L4
L34:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  je     L3
L4:
  ret
L29:
  ret
```

assistant: ```c
int _trie_string_cmp(const char *a, const char *b) {
  size_t bytes = 0;
  while (a[bytes] != '\0' && b[bytes] != '\0' && a[bytes] == b[bytes]) {
    bytes++;
  }
  return bytes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wCharCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <wMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *wCharCopy(char *text) {
  int len;
  char *buffer;
  len = strlen(text);
  buffer = (char *)wMalloc(len + 1);
  memmove((void *)buffer, (void *)text, len + 1);
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wCharCopy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <wMalloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *wCharCopy(char *text) {
  int len;
  char *buffer;
  len = strlen(text);
  buffer = (char *)wMalloc(len + 1);
  memmove((void *)buffer, (void *)text, len + 1);
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wCharCopy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <wMalloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *wCharCopy(char *text) {
  int len;
  char *buffer;
  len = strlen(text);
  buffer = (char *)wMalloc(len + 1);
  memmove((void *)buffer, (void *)text, len + 1);
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wCharCopy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <wMalloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *wCharCopy(char *text) {
  int len;
  char *buffer;
  len = strlen(text);
  buffer = (char *)wMalloc(len + 1);
  memmove((void *)buffer, (void *)text, len + 1);
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<br>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L11
  cmpl   $0x0,-0x10(%rbp)
  jne    L17
L11:
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
L17:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x10(%rbp),%xmm1
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  movsd  D15(%rip),%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
data_type: byte[8]
name: retrieve_data
arguments: data_label: D15
data_type: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0xcc,0xbf,0xa9,0x41]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double br(int packetsize, int ip_int, int normal_ip, int big_ip) {
  if ((normal_ip == 0) || (big_ip == 0)) {
    normal_ip = 1;
    big_ip = 0;
  }
  return 270000000 * 0.8 * packetsize / (packetsize + ip_int + (double)big_ip / (normal_ip + big_ip) + 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<br>:
  endbr64
  test   %edx,%edx
  je     L6
  test   %ecx,%ecx
  jne    L11
L6:
  mov    $0x0,%ecx
  mov    $0x1,%edx
L11:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D10(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  add    %ecx,%edx
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm2
  divsd  %xmm2,%xmm1
  add    %esi,%edi
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  addsd  %xmm2,%xmm1
  addsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D7
type_infered: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0xcc,0xbf,0xa9,0x41]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double br(int packetsize, int ip_int, int normal_ip, int big_ip) {
  if ((normal_ip == 0) || (big_ip == 0)) {
    normal_ip = 1;
    big_ip = 0;
  }
  return 270000000 * 0.8 * packetsize / (packetsize + ip_int + (double)big_ip / (normal_ip + big_ip) + 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<br>:
  endbr64
  test   %edx,%edx
  je     L17
  test   %ecx,%ecx
  je     L17
  pxor   %xmm2,%xmm2
  add    %ecx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm2
  cvtsi2sd %edx,%xmm0
  divsd  %xmm0,%xmm2
L0:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm0
  mulsd  D2(%rip),%xmm0
  add    %esi,%edi
  cvtsi2sd %edi,%xmm1
  addsd  %xmm2,%xmm1
  addsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L17:
  pxor   %xmm2,%xmm2
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: byte[8]
name: retrieve_data
arguments: tag: D0
type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0xcc,0xbf,0xa9,0x41]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double br(int packetsize, int ip_int, int normal_ip, int big_ip) {
  if ((normal_ip == 0) || (big_ip == 0)) {
    normal_ip = 1;
    big_ip = 0;
  }
  return 270000000 * 0.8 * packetsize / (packetsize + ip_int + (double)big_ip / (normal_ip + big_ip) + 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<br>:
  endbr64
  test   %edx,%edx
  je     L7
  test   %ecx,%ecx
  je     L7
  pxor   %xmm2,%xmm2
  add    %ecx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm2
  cvtsi2sd %edx,%xmm0
  divsd  %xmm0,%xmm2
L11:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm0
  mulsd  D0(%rip),%xmm0
  add    %esi,%edi
  cvtsi2sd %edi,%xmm1
  addsd  %xmm2,%xmm1
  addsd  D15(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L7:
  pxor   %xmm2,%xmm2
  jmp    L11
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: byte[8]
name: read_data
arguments: data_tag: D15
data_type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0xcc,0xbf,0xa9,0x41]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double br(int packetsize, int ip_int, int normal_ip, int big_ip) {
  if ((normal_ip == 0) || (big_ip == 0)) {
    normal_ip = 1;
    big_ip = 0;
  }
  return 270000000 * 0.8 * packetsize / (packetsize + ip_int + (double)big_ip / (normal_ip + big_ip) + 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isModuleStored>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L24:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L34
  mov    $0x1,%eax
  jmp    L2
L34:
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L24
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
bool isModuleStored(char **sequence, const char *last, unsigned int index) {
  for (unsigned int i = 0; i < index; i++) {
    if (strcmp(sequence[i], last) == 0) {
      return true;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isModuleStored>:
  endbr64
  test   %edx,%edx
  je     L27
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rdi,%rax,8),%r12
L1:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L18
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    $0x0,%eax
  jmp    L30
L27:
  mov    $0x0,%eax
  ret
L18:
  mov    $0x1,%eax
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool isModuleStored(char **sequence, const char *last, unsigned int index) {
  for (unsigned int i = 0; i < index; i++) {
    if (strcmp(sequence[i], last) == 0) {
      return true;
    }
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isModuleStored>:
  endbr64
  test   %edx,%edx
  je     L5
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L11
  nopl   0x0(%rax)
L8:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L21
L11:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isModuleStored(char **sequence, const char *last, unsigned int index) {
  for (unsigned int i = 0; i < index; i++) {
    if (strcmp(sequence[i], last) == 0) {
      return true;
    }
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isModuleStored>:
  endbr64
  test   %edx,%edx
  je     L10
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L32
  nopl   0x0(%rax)
L4:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L9
L32:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isModuleStored(char **sequence, const char *last, unsigned int index) {
  for (unsigned int i = 0; i < index; i++) {
    if (strcmp(sequence[i], last) == 0) {
      return true;
    }
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtoull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L41
L67:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L67
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L66
  movl   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L66:
  mov    -0x24(%rbp),%edx
  lea    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strtoul_base@plt>
  mov    %eax,-0x24(%rbp)
L62:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <strtoul_charval@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jae    L52
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L62
L52:
  nop
  cmpl   $0x0,-0x10(%rbp)
  je     L55
  negq   -0x8(%rbp)
L55:
  cmpq   $0x0,-0x20(%rbp)
  je     L29
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L29:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long strtoull(const char *p, char **endp, int base) {
  unsigned long long ret = 0;
  int negative = 0;
  unsigned int charval;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    negative = 1;
    p++;
  }
  base = strtoul_base(&p, base);
  while (1) {
    charval = strtoul_charval(*p);
    if (charval >= (unsigned int)base)
      break;
    ret = ((ret * base) + charval);
    p++;
  }
  if (negative)
    ret = -ret;
  if (endp)
    *endp = (char *)p;
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strtoull>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r13
  mov    %edx,%ebx
  jmp    L22
L35:
  addq   $0x1,0x8(%rsp)
L22:
  mov    0x8(%rsp),%rax
  movsbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
  mov    0x8(%rsp),%rax
  mov    $0x0,%r14d
  cmpb   $0x2d,(%rax)
  je     L61
L1:
  lea    0x8(%rsp),%rdi
  mov    %ebx,%esi
  call   <strtoul_base@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
  movslq %eax,%r12
  jmp    L40
L61:
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x1,%r14d
  jmp    L1
L56:
  imul   %r12,%rbx
  mov    %eax,%eax
  add    %rax,%rbx
  addq   $0x1,0x8(%rsp)
L40:
  mov    0x8(%rsp),%rax
  movsbl (%rax),%edi
  call   <strtoul_charval@plt>
  cmp    %eax,%ebp
  ja     L56
  mov    %rbx,%rax
  neg    %rax
  test   %r14d,%r14d
  cmovne %rax,%rbx
  test   %r13,%r13
  je     L64
  mov    0x8(%rsp),%rax
  mov    %rax,0x0(%r13)
L64:
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long long strtoull(const char *p, char **endp, int base) {
  unsigned long long ret = 0;
  int negative = 0;
  unsigned int charval;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    negative = 1;
    p++;
  }
  base = strtoul_base(&p, base);
  while (1) {
    charval = strtoul_charval(*p);
    if (charval >= (unsigned int)base)
      break;
    ret = ((ret * base) + charval);
    p++;
  }
  if (negative)
    ret = -ret;
  if (endp)
    *endp = (char *)p;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtoull>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  jmp    L7
  nop
L43:
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
L7:
  movsbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  mov    0x8(%rsp),%rax
  jne    L43
  xor    %r13d,%r13d
  cmpb   $0x2d,(%rax)
  jne    L50
  add    $0x1,%rax
  mov    $0x1,%r13d
  mov    %rax,0x8(%rsp)
L50:
  mov    %ebp,%esi
  lea    0x8(%rsp),%rdi
  xor    %r14d,%r14d
  call   <strtoul_base@plt>
  movslq %eax,%rbp
  mov    0x8(%rsp),%rax
  mov    %rbp,%rbx
  jmp    L30
  xchg   %ax,%ax
L53:
  imul   %rbp,%r14
  mov    %eax,%eax
  add    %rax,%r14
  mov    0x8(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
L30:
  movsbl (%rax),%edi
  call   <strtoul_charval@plt>
  cmp    %ebx,%eax
  jb     L53
  mov    %r14,%rax
  neg    %rax
  test   %r13d,%r13d
  cmovne %rax,%r14
  test   %r12,%r12
  je     L51
  mov    0x8(%rsp),%rax
  mov    %rax,(%r12)
L51:
  add    $0x10,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long long strtoull(const char *p, char **endp, int base) {
  unsigned long long ret = 0;
  int negative = 0;
  unsigned int charval;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    negative = 1;
    p++;
  }
  base = strtoul_base(&p, base);
  while (1) {
    charval = strtoul_charval(*p);
    if (charval >= (unsigned int)base)
      break;
    ret = ((ret * base) + charval);
    p++;
  }
  if (negative)
    ret = -ret;
  if (endp)
    *endp = (char *)p;
  return (ret);
}
```