ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<readVarint>:
  endbr64
  test   %rdx,%rdx
  je     L10
  movzbl (%rdi),%eax
  cmp    $0xfc,%al
  jbe    L20
  cmp    $0xfd,%al
  je     L28
  cmp    $0xfe,%al
  jne    L10
  cmp    $0x4,%rdx
  jbe    L10
  movq   $0x5,(%rsi)
  mov    0x1(%rdi),%eax
  ret
  nopl   0x0(%rax)
L28:
  cmp    $0x2,%rdx
  jbe    L10
  movq   $0x3,(%rsi)
  movzwl 0x1(%rdi),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  movq   $0x1,(%rsi)
  movzbl (%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int readVarint(unsigned char *buffer, size_t *varintSize, size_t remainingSize) {
  if (remainingSize == 0) {
    return -1;
  }
  if (*buffer < 0xfd) {
    *varintSize = 1;
    return *buffer;
  } else if (*buffer == 0xfd) {
    if (remainingSize < 3) {
      return -1;
    }
    *varintSize = 3;
    return (*(buffer + 2) << 8) | (*(buffer + 1));
  } else if (*buffer == 0xfe) {
    if (remainingSize < 5) {
      return -1;
    }
    *varintSize = 5;
    return (*(buffer + 4) << 24) | (*(buffer + 3) << 16) | (*(buffer + 2) << 8) | (*(buffer + 1));
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L6:
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x28(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mul@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L6
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint32_t *test(unsigned size, uint32_t *a, uint32_t s) {
  unsigned i;
  for (i = 0; i < size; i++) {
    a[i] = mul(a[i], s);
  }
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  test   %edi,%edi
  je     L9
  mov    %edx,%ebp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r12
L13:
  mov    %ebp,%esi
  mov    (%rbx),%edi
  call   <mul@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L13
L9:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t *test(unsigned size, uint32_t *a, uint32_t s) {
  unsigned i;
  for (i = 0; i < size; i++) {
    a[i] = mul(a[i], s);
  }
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L8
  lea    -0x1(%rdi),%eax
  mov    %edx,%ebp
  mov    %rsi,%rbx
  lea    0x4(%rsi,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%edi
  mov    %ebp,%esi
  add    $0x4,%rbx
  call   <mul@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L2
L8:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t *test(unsigned size, uint32_t *a, uint32_t s) {
  unsigned i;
  for (i = 0; i < size; i++) {
    a[i] = mul(a[i], s);
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L9
  lea    -0x1(%rdi),%eax
  mov    %edx,%ebp
  mov    %rsi,%rbx
  lea    0x4(%rsi,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%edi
  mov    %ebp,%esi
  add    $0x4,%rbx
  call   <mul@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L18
L9:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t *test(unsigned size, uint32_t *a, uint32_t s) {
  unsigned i;
  for (i = 0; i < size; i++) {
    a[i] = mul(a[i], s);
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xbuffer_copyin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  cmpq   $0x0,-0x18(%rbp)
  jne    L27
L23:
  mov    $0x0,%eax
  jmp    L0
L27:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xbuffer_ensure_size@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
void *xbuffer_copyin(void *buf, int index, const void *data, int len) {
  if (!buf || !data) {
    return NULL;
  }
  buf = xbuffer_ensure_size(buf, index + len);
  memcpy(((uint8_t *)buf) + index, data, len);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xbuffer_copyin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L16
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  test   %rdx,%rdx
  je     L16
  lea    (%rsi,%rcx,1),%esi
  call   <xbuffer_ensure_size@plt>
  mov    %rax,%r13
  movslq %ebx,%rbx
  lea    (%rax,%rbx,4),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L29:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%r13d
  jmp    L29
```

assistant: ```c
void *xbuffer_copyin(void *buf, int index, const void *data, int len) {
  if (!buf || !data) {
    return NULL;
  }
  buf = xbuffer_ensure_size(buf, index + len);
  memcpy(((uint8_t *)buf) + index, data, len);
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xbuffer_copyin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L13
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L13
  movslq %esi,%rbx
  mov    %ecx,%r12d
  lea    (%rbx,%rcx,1),%esi
  call   <xbuffer_ensure_size@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    (%rax,%rbx,4),%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xbuffer_copyin(void *buf, int index, const void *data, int len) {
  if (!buf || !data) {
    return NULL;
  }
  buf = xbuffer_ensure_size(buf, index + len);
  memcpy(((uint8_t *)buf) + index, data, len);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xbuffer_copyin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L14
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L14
  movslq %esi,%rbx
  mov    %ecx,%r12d
  lea    (%rbx,%rcx,1),%esi
  call   <xbuffer_ensure_size@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    (%rax,%rbx,4),%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L14:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xbuffer_copyin(void *buf, int index, const void *data, int len) {
  if (!buf || !data) {
    return NULL;
  }
  buf = xbuffer_ensure_size(buf, index + len);
  memcpy(((uint8_t *)buf) + index, data, len);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fprintf(FILE *stream, const char *format, ...) {
  int n;
  va_list args;
  va_start(args, format);
  n = vfprintf(stream, format, args);
  va_end(args);
  return (n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fprintf(FILE *stream, const char *format, ...) {
  int n;
  va_list args;
  va_start(args, format);
  n = vfprintf(stream, format, args);
  va_end(args);
  return (n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fprintf(FILE *stream, const char *format, ...) {
  int n;
  va_list args;
  va_start(args, format);
  n = vfprintf(stream, format, args);
  va_end(args);
  return (n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fprintf(FILE *stream, const char *format, ...) {
  int n;
  va_list args;
  va_start(args, format);
  n = vfprintf(stream, format, args);
  va_end(args);
  return (n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DieError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
extern void DieError(int errval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  exit(errval);
}
```
user: What is the c source code of the assembly code below?

```asm
<DieError>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
extern void DieError(int errval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  exit(errval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DieError>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %r12d,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
extern void DieError(int errval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  exit(errval);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DieError>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %r12d,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
extern void DieError(int errval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  exit(errval);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getIOPS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movq   $0x5f5e100,-0x30(%rbp)
  movq   $0xa,-0x28(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x38(%rbp)
  jmp    L8
L0:
  mov    -0x38(%rbp),%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,-0x8(%rbp)
  addq   $0x1,-0x38(%rbp)
L8:
  mov    -0x38(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L0
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D0(%rip),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x30(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long getIOPS(void) {
  long i, j, k, lim;
  double result;
  lim = 100000000;
  clock_t begin, end;
  j = 10;
  begin = clock();
  for (i = 0; i < lim; i++) {
    k = i % j;
  }
  end = clock();
  result = (double)(end - begin) / CLOCKS_PER_SEC;
  k = (long)lim / result;
  return k;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sbdm_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x6,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long sbdm_hash(unsigned char *str) {
  unsigned long hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sbdm_hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  mov    $0x0,%eax
L12:
  imul   $0x1003f,%rax,%rax
  movzbl %dl,%edx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L12
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long sbdm_hash(unsigned char *str) {
  unsigned long hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sbdm_hash>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %dl,%dl
  je     L6
  nopl   0x0(%rax)
L10:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L10
  ret
  nop
L6:
  ret
```

assistant: ```c
unsigned long sbdm_hash(unsigned char *str) {
  unsigned long hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sbdm_hash>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %dl,%dl
  je     L3
  nopl   0x0(%rax)
L14:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L14
  ret
  nop
L3:
  ret
```

assistant: ```c
unsigned long sbdm_hash(unsigned char *str) {
  unsigned long hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<markSection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L6:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mark@plt>
  addq   $0x1000,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void markSection(uintptr_t start, uintptr_t end, uint32_t used) {
  uintptr_t it = start;
  while (it < end) {
    mark(it, used);
    it += 0x1000;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<markSection>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    %rsi,%rdi
  jae    L16
L10:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <mark@plt>
  add    $0x1000,%rbx
  cmp    %rbx,%rbp
  ja     L10
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void markSection(uintptr_t start, uintptr_t end, uint32_t used) {
  uintptr_t it = start;
  while (it < end) {
    mark(it, used);
    it += 0x1000;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<markSection>:
  endbr64
  cmp    %rsi,%rdi
  jae    L18
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  mov    %r12d,%esi
  add    $0x1000,%rbx
  call   <mark@plt>
  cmp    %rbx,%rbp
  ja     L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void markSection(uintptr_t start, uintptr_t end, uint32_t used) {
  uintptr_t it = start;
  while (it < end) {
    mark(it, used);
    it += 0x1000;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<markSection>:
  endbr64
  cmp    %rsi,%rdi
  jae    L10
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  mov    %r12d,%esi
  add    $0x1000,%rbx
  call   <mark@plt>
  cmp    %rbx,%rbp
  ja     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void markSection(uintptr_t start, uintptr_t end, uint32_t used) {
  uintptr_t it = start;
  while (it < end) {
    mark(it, used);
    it += 0x1000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<baud_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x9,%eax
  ja     L13
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D61(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D61(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D45(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D60(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D94(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D125(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D40(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D127(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D120(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D58(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
  lea    D82(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
L13:
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
L71:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D45
type_infered: string
name: parse_data
arguments: data_label: D60
type_infered: string
name: parse_data
arguments: data_label: D94
type_infered: string
name: parse_data
arguments: data_label: D125
type_infered: string
name: parse_data
arguments: data_label: D40
type_infered: string
name: parse_data
arguments: data_label: D127
type_infered: string
name: parse_data
arguments: data_label: D120
type_infered: string
name: parse_data
arguments: data_label: D58
type_infered: string
name: parse_data
arguments: data_label: D82
type_infered: string
name: parse_data
arguments: data_label: D9
type_infered: string

tool: D16: 300

tool: D45: 600

tool: D60: 1200

tool: D94: 2400

tool: D125: 4800

tool: D40: 9600

tool: D127: 19200

tool: D120: 38400

tool: D58: 57600

tool: D82: 115200

tool: D9: unknown speed

assistant: ```c
char *baud_string(int speed) {
  char *str;
  switch (speed) {
  case B300:
    str = "300";
    break;
  case B600:
    str = "600";
    break;
  case B1200:
    str = "1200";
    break;
  case B2400:
    str = "2400";
    break;
  case B4800:
    str = "4800";
    break;
  case B9600:
    str = "9600";
    break;
  case B19200:
    str = "19200";
    break;
  case B38400:
    str = "38400";
    break;
  case B57600:
    str = "57600";
    break;
  case B115200:
    str = "115200";
    break;
  default:
    str = "unknown speed";
  }
  return str;
}
```