ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <p@plt>
  cvtss2sd %xmm0,%xmm0
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D32(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D13
data_type: string
name: read_data
arguments: label: D32
data_type: string

tool: D4: input n & x:

tool: D6: %d %d

tool: D13: n=%d,x=%d


tool: D32: p%d(%d) = %f


assistant: ```c
int main() {
  float p(int, int);
  int n, x;
  printf("input n & x:");
  scanf("%d %d", &n, &x);
  printf("n=%d,x=%d\n", n, x);
  printf("p%d(%d) = %f\n", n, x, p(n, x));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <p@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D32(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D32
type_infered: string

tool: D18: input n & x:

tool: D27: %d %d

tool: D13: n=%d,x=%d


tool: D32: p%d(%d) = %f


assistant: ```c
int main() {
  float p(int, int);
  int n, x;
  printf("input n & x:");
  scanf("%d %d", &n, &x);
  printf("n=%d,x=%d\n", n, x);
  printf("p%d(%d) = %f\n", n, x, p(n, x));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <p@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D22
data_type: string
name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string

tool: D22: input n & x:

tool: D12: %d %d

tool: D29: n=%d,x=%d


tool: D17: p%d(%d) = %f


assistant: ```c
int main() {
  float p(int, int);
  int n, x;
  printf("input n & x:");
  scanf("%d %d", &n, &x);
  printf("n=%d,x=%d\n", n, x);
  printf("p%d(%d) = %f\n", n, x, p(n, x));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UpnpRemoteIOClient_RemoteInput_InputKeyPress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);


assistant: ```c
void UpnpRemoteIOClient_RemoteInput_InputKeyPress(void *upnptoken, int key) {
  printf("Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);\r\n", key);
  UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress(upnptoken);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UpnpRemoteIOClient_RemoteInput_InputKeyPress>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);


assistant: ```c
void UpnpRemoteIOClient_RemoteInput_InputKeyPress(void *upnptoken, int key) {
  printf("Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);\r\n", key);
  UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress(upnptoken);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UpnpRemoteIOClient_RemoteInput_InputKeyPress>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);


assistant: ```c
void UpnpRemoteIOClient_RemoteInput_InputKeyPress(void *upnptoken, int key) {
  printf("Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);\r\n", key);
  UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress(upnptoken);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UpnpRemoteIOClient_RemoteInput_InputKeyPress>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);


assistant: ```c
void UpnpRemoteIOClient_RemoteInput_InputKeyPress(void *upnptoken, int key) {
  printf("Invoke: UpnpRemoteIOClient_RemoteInput_InputKeyPress(%d);\r\n", key);
  UpnpResponse_RemoteIOClient_RemoteInput_InputKeyPress(upnptoken);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gaussian_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
L1:
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <randrange@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <randrange@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D1(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L1
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: f64
name: unpack_data
arguments: data_label: D0
type: byte[8]

tool: D1: 1

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double gaussian_rand() {
  double v1, v2, s;
  do {
    v1 = randrange(-1., 1.);
    v2 = randrange(-1., 1.);
    s = v1 * v1 + v2 * v2;
  } while (s >= 1.);
  return sqrt(-2. * log(s) / s) * v1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gaussian_rand>:
  endbr64
  sub    $0x18,%rsp
L9:
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <randrange@plt>
  movsd  %xmm0,(%rsp)
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <randrange@plt>
  movsd  (%rsp),%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  comisd D4(%rip),%xmm1
  jae    L9
  movapd %xmm1,%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D0(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: f64[2]
name: unpack_data
arguments: data_label: D0
type_infered: byte[8]

tool: {"D4": [1.0,-2.0]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double gaussian_rand() {
  double v1, v2, s;
  do {
    v1 = randrange(-1., 1.);
    v2 = randrange(-1., 1.);
    s = v1 * v1 + v2 * v2;
  } while (s >= 1.);
  return sqrt(-2. * log(s) / s) * v1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gaussian_rand>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <randrange@plt>
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  movsd  %xmm0,(%rsp)
  call   <randrange@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  comisd D12(%rip),%xmm0
  jae    L7
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <log@plt>
  pxor   %xmm2,%xmm2
  movsd  (%rsp),%xmm0
  cvtsi2sd %eax,%xmm2
  mulsd  D6(%rip),%xmm2
  divsd  %xmm0,%xmm2
  cvttsd2si %xmm2,%edi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: f64[2]
name: disassemble_data
arguments: label: D6
data_type: byte[8]

tool: {"D12": [1.0,-2.0]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double gaussian_rand() {
  double v1, v2, s;
  do {
    v1 = randrange(-1., 1.);
    v2 = randrange(-1., 1.);
    s = v1 * v1 + v2 * v2;
  } while (s >= 1.);
  return sqrt(-2. * log(s) / s) * v1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gaussian_rand>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <randrange@plt>
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  movsd  %xmm0,(%rsp)
  call   <randrange@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  comisd D5(%rip),%xmm0
  jae    L4
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <log@plt>
  pxor   %xmm2,%xmm2
  movsd  (%rsp),%xmm0
  cvtsi2sd %eax,%xmm2
  mulsd  D13(%rip),%xmm2
  divsd  %xmm0,%xmm2
  cvttsd2si %xmm2,%edi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: f64[2]
name: extract_symbolic_data
arguments: data_label: D13
type: byte[8]

tool: {"D5": [1.0,-2.0]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double gaussian_rand() {
  double v1, v2, s;
  do {
    v1 = randrange(-1., 1.);
    v2 = randrange(-1., 1.);
    s = v1 * v1 + v2 * v2;
  } while (s >= 1.);
  return sqrt(-2. * log(s) / s) * v1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_bitrev_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  jmp    L73
L104:
  mov    -0x414(%rbp),%eax
  cltq
  movl   $0x0,-0x410(%rbp,%rax,4)
  addl   $0x1,-0x414(%rbp)
L73:
  cmpl   $0xff,-0x414(%rbp)
  jle    L104
  movl   $0x80,-0x41c(%rbp)
  movl   $0x1,-0x418(%rbp)
  jmp    L10
L86:
  movl   $0x0,-0x414(%rbp)
  jmp    L99
L65:
  mov    -0x414(%rbp),%eax
  and    -0x418(%rbp),%eax
  test   %eax,%eax
  je     L46
  mov    -0x414(%rbp),%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%edx
  mov    -0x41c(%rbp),%eax
  add    %eax,%edx
  mov    -0x414(%rbp),%eax
  cltq
  mov    %edx,-0x410(%rbp,%rax,4)
L46:
  addl   $0x1,-0x414(%rbp)
L99:
  cmpl   $0xff,-0x414(%rbp)
  jle    L65
  sarl   -0x41c(%rbp)
  shll   -0x418(%rbp)
L10:
  cmpl   $0x0,-0x41c(%rbp)
  jne    L86
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x414(%rbp)
  jmp    L27
L37:
  mov    -0x414(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L97
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L97:
  mov    -0x414(%rbp),%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x414(%rbp)
L27:
  cmpl   $0xff,-0x414(%rbp)
  jle    L37
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: string

tool: D17: const int bitrev[256] = {

tool: D30: 
   

tool: D22:  %d,

tool: D38: 
};


assistant: ```c
void print_bitrev_table(void) {
  int i, j, k;
  int br[256];
  for (k = 0; k < 256; k++)
    br[k] = 0;
  for (i = 128, j = 1; i != 0; i >>= 1, j <<= 1)
    for (k = 0; k < 256; k++)
      if (k & j)
        br[k] += i;
  printf("const int bitrev[256] = {");
  for (k = 0; k < 256; k++) {
    if (k % 8 == 0)
      printf("\n   ");
    printf(" %d,", br[k]);
  }
  printf("\n};\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_bitrev_table>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x400(%rsp),%rdx
L18:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L18
  mov    $0x8,%edi
  mov    $0x1,%ecx
  mov    $0x80,%esi
  jmp    L66
L45:
  add    %esi,(%rdx)
L99:
  add    $0x4,%rdx
L69:
  add    $0x1,%eax
  cmp    $0x100,%eax
  je     L91
  test   %ecx,%eax
  jne    L45
  jmp    L99
L91:
  sar    %esi
  add    %ecx,%ecx
  sub    $0x1,%edi
  je     L14
L66:
  lea    0x4(%rsp),%rdx
  mov    $0x0,%eax
  jmp    L69
L14:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D29(%rip),%r12
  lea    D30(%rip),%rbp
  jmp    L92
L68:
  mov    (%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x100,%rbx
  je     L1
L92:
  test   $0x7,%bl
  jne    L68
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L68
L1:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D29
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D2: const int bitrev[256] = {

tool: D29: 
   

tool: D30:  %d,

tool: D14: 
};


assistant: ```c
void print_bitrev_table(void) {
  int i, j, k;
  int br[256];
  for (k = 0; k < 256; k++)
    br[k] = 0;
  for (i = 128, j = 1; i != 0; i >>= 1, j <<= 1)
    for (k = 0; k < 256; k++)
      if (k & j)
        br[k] += i;
  printf("const int bitrev[256] = {");
  for (k = 0; k < 256; k++) {
    if (k % 8 == 0)
      printf("\n   ");
    printf(" %d,", br[k]);
  }
  printf("\n};\n\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_bitrev_table>:
  endbr64
  push   %r13
  mov    $0x80,%ecx
  mov    $0x80,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r8
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x8,%edi
  mov    $0x1,%ecx
L20:
  mov    %r8,%rdx
  xor    %eax,%eax
  jmp    L38
  nopl   (%rax)
L65:
  test   %ecx,%eax
  je     L45
  add    %esi,(%rdx)
L45:
  add    $0x4,%rdx
L38:
  add    $0x1,%eax
  cmp    $0x100,%eax
  jne    L65
  sar    %esi
  add    %ecx,%ecx
  sub    $0x1,%edi
  jne    L20
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  lea    D13(%rip),%r12
  lea    D26(%rip),%r13
  jmp    L7
  nopl   (%rax)
L80:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x100,%rbx
  je     L12
L7:
  test   $0x7,%bl
  jne    L80
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L80
L12:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x418,%rsp
  lea    D25(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <puts@plt>
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string

tool: D37: const int bitrev[256] = {

tool: D13:  %d,

tool: D26: 
   

tool: D25: 
};


assistant: ```c
void print_bitrev_table(void) {
  int i, j, k;
  int br[256];
  for (k = 0; k < 256; k++)
    br[k] = 0;
  for (i = 128, j = 1; i != 0; i >>= 1, j <<= 1)
    for (k = 0; k < 256; k++)
      if (k & j)
        br[k] += i;
  printf("const int bitrev[256] = {");
  for (k = 0; k < 256; k++) {
    if (k % 8 == 0)
      printf("\n   ");
    printf(" %d,", br[k]);
  }
  printf("\n};\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_bitrev_table>:
  endbr64
  push   %r13
  mov    $0x80,%ecx
  mov    $0x80,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r8
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x8,%edi
  mov    $0x1,%ecx
L61:
  mov    %r8,%rdx
  mov    $0x1,%eax
  xchg   %ax,%ax
L68:
  test   %ecx,%eax
  je     L15
  add    %esi,(%rdx)
L15:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0x100,%eax
  jne    L68
  sar    %esi
  add    %ecx,%ecx
  sub    $0x1,%edi
  jne    L61
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  lea    D26(%rip),%r12
  lea    D30(%rip),%r13
  jmp    L51
  nopl   (%rax)
L45:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x100,%rbx
  je     L26
L51:
  test   $0x7,%bl
  jne    L45
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L45
L26:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x418,%rsp
  lea    D1(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <puts@plt>
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
data_type: string
name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D36: const int bitrev[256] = {

tool: D26:  %d,

tool: D30: 
   

tool: D1: 
};


assistant: ```c
void print_bitrev_table(void) {
  int i, j, k;
  int br[256];
  for (k = 0; k < 256; k++)
    br[k] = 0;
  for (i = 128, j = 1; i != 0; i >>= 1, j <<= 1)
    for (k = 0; k < 256; k++)
      if (k & j)
        br[k] += i;
  printf("const int bitrev[256] = {");
  for (k = 0; k < 256; k++) {
    if (k % 8 == 0)
      printf("\n   ");
    printf(" %d,", br[k]);
  }
  printf("\n};\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getCounts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L16
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L59:
  cmpl   $0x4,-0x2c(%rbp)
  jne    L41
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  jmp    L45
L41:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x2,%rax
L45:
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L59
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getCounts(const unsigned char *T, int *C, int n, int k, int cs) {
  int i;
  for (i = 0; i < k; ++i) {
    C[i] = 0;
  }
  for (i = 0; i < n; ++i) {
    ++C[(cs == sizeof(int) ? ((const int *)T)[i] : ((const unsigned char *)T)[i])];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getCounts>:
  endbr64
  test   %ecx,%ecx
  jle    L54
  mov    %rsi,%rax
  lea    -0x1(%rcx),%ecx
  lea    0x4(%rsi,%rcx,4),%rcx
L46:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L46
L54:
  test   %edx,%edx
  jle    L55
  mov    %edx,%edx
  mov    $0x0,%ecx
  jmp    L17
L19:
  movslq (%rdi,%rcx,4),%rax
  shl    $0x2,%rax
L66:
  addl   $0x1,(%rsi,%rax,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L55
L17:
  cmp    $0x4,%r8d
  je     L19
  movzbl (%rdi,%rcx,1),%eax
  shl    $0x2,%rax
  jmp    L66
L55:
  ret
```

assistant: ```c
void getCounts(const unsigned char *T, int *C, int n, int k, int cs) {
  int i;
  for (i = 0; i < k; ++i) {
    C[i] = 0;
  }
  for (i = 0; i < n; ++i) {
    ++C[(cs == sizeof(int) ? ((const int *)T)[i] : ((const unsigned char *)T)[i])];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getCounts>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %r8d,%ebx
  test   %ecx,%ecx
  jle    L5
  movslq %ecx,%rcx
  xor    %esi,%esi
  lea    0x0(,%rcx,4),%rdx
  call   <memset@plt>
  mov    %rax,%rdi
L5:
  movslq %r12d,%rcx
  xor    %edx,%edx
  test   %r12d,%r12d
  jg     L18
  jmp    L37
  nopl   0x0(%rax)
L4:
  movzbl 0x0(%rbp,%rdx,1),%eax
  add    $0x1,%rdx
  shl    $0x2,%rax
  addl   $0x1,(%rdi,%rax,1)
  cmp    %rdx,%rcx
  je     L37
L18:
  cmp    $0x4,%ebx
  jne    L4
  movslq 0x0(%rbp,%rdx,4),%rax
  add    $0x1,%rdx
  shl    $0x2,%rax
  addl   $0x1,(%rdi,%rax,1)
  cmp    %rdx,%rcx
  jne    L18
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void getCounts(const unsigned char *T, int *C, int n, int k, int cs) {
  int i;
  for (i = 0; i < k; ++i) {
    C[i] = 0;
  }
  for (i = 0; i < n; ++i) {
    ++C[(cs == sizeof(int) ? ((const int *)T)[i] : ((const unsigned char *)T)[i])];
  }
}
```