ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<tk2rad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm2,%rbx
  movapd %xmm1,%xmm3
  mulsd  D58(%rip),%xmm3
  movapd %xmm0,%xmm1
  movsd  %xmm3,0x8(%rsp)
  mulsd  %xmm3,%xmm1
  movsd  D22(%rip),%xmm0
  divsd  %xmm1,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rbp
  mov    $0x5,%edi
  movsd  0x8(%rsp),%xmm0
  call   <pow@plt>
  movq   %rbx,%xmm2
  mulsd  D51(%rip),%xmm2
  mulsd  D28(%rip),%xmm0
  movq   %rbp,%xmm1
  subsd  D12(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm1
  mulsd  D54(%rip),%xmm1
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D58
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D22
type_infered: f64
name: retrieve_data
arguments: data_label: D51
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D28
type_infered: f64
name: retrieve_data
arguments: data_label: D12
type_infered: f64
name: retrieve_data
arguments: data_label: D54
type_infered: f64

tool: {"D58": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D22: 0.0143876912

tool: {"D51": [0x00,0x48,0x94,0x32,0xa5,0x45,0x7c,0x3b]}

tool: D28: 3.1415927

tool: D12: 1

tool: D54: 1000

assistant: ```c
double tk2rad(double tk, double lambda, double emiss) {
  double term, lam, rad;
  lam = lambda * 1e-6;
  term = exp(0.0143876912 / (lam * tk)) - 1.0;
  rad = (emiss * 3.741774922e-22 / ((pow(lam, 5)) * 3.1415927 * term)) * 1000.0;
  return (rad);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tk2rad>:
  endbr64
  sub    $0x28,%rsp
  movsd  D6(%rip),%xmm3
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm1,%xmm3
  movapd %xmm0,%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm3,%xmm1
  movsd  %xmm3,0x10(%rsp)
  divsd  %xmm1,%xmm0
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm3
  mov    $0x5,%edi
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm3,%xmm0
  call   <pow@plt>
  mulsd  D49(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  D1(%rip),%xmm1
  movsd  0x18(%rsp),%xmm2
  mulsd  D55(%rip),%xmm2
  mulsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  mulsd  D23(%rip),%xmm2
  add    $0x28,%rsp
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D22
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D49
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D1
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D55
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D23
data_type: f64

tool: {"D6": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D22: 0.0143876912

tool: D49: 3.1415927

tool: D1: 1

tool: {"D55": [0x00,0x48,0x94,0x32,0xa5,0x45,0x7c,0x3b]}

tool: D23: 1000

assistant: ```c
double tk2rad(double tk, double lambda, double emiss) {
  double term, lam, rad;
  lam = lambda * 1e-6;
  term = exp(0.0143876912 / (lam * tk)) - 1.0;
  rad = (emiss * 3.741774922e-22 / ((pow(lam, 5)) * 3.1415927 * term)) * 1000.0;
  return (rad);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tk2rad>:
  endbr64
  sub    $0x28,%rsp
  movsd  D13(%rip),%xmm3
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm1,%xmm3
  movapd %xmm0,%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm3,%xmm1
  movsd  %xmm3,0x10(%rsp)
  divsd  %xmm1,%xmm0
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm3
  mov    $0x5,%edi
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm3,%xmm0
  call   <pow@plt>
  mulsd  D46(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  D8(%rip),%xmm1
  movsd  0x18(%rsp),%xmm2
  mulsd  D24(%rip),%xmm2
  mulsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  mulsd  D0(%rip),%xmm2
  add    $0x28,%rsp
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: byte[8]
name: retrieve_data
arguments: data_tag: D3
type: f64
name: retrieve_data
arguments: data_tag: D46
type: f64
name: retrieve_data
arguments: data_tag: D8
type: f64
name: retrieve_data
arguments: data_tag: D24
type: byte[8]
name: retrieve_data
arguments: data_tag: D0
type: f64

tool: {"D13": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D3: 0.0143876912

tool: D46: 3.1415927

tool: D8: 1

tool: {"D24": [0x00,0x48,0x94,0x32,0xa5,0x45,0x7c,0x3b]}

tool: D0: 1000

assistant: ```c
double tk2rad(double tk, double lambda, double emiss) {
  double term, lam, rad;
  lam = lambda * 1e-6;
  term = exp(0.0143876912 / (lam * tk)) - 1.0;
  rad = (emiss * 3.741774922e-22 / ((pow(lam, 5)) * 3.1415927 * term)) * 1000.0;
  return (rad);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__tiger__substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <llvm_gc_allocate@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *__tiger__substring(char *s, int off, int len) {
  char *s1 = llvm_gc_allocate(len + 1);
  strncpy(s1, &s[off], len + 1);
  return s1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__tiger__substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    0x1(%rdx),%r13d
  mov    %r13d,%edi
  call   <llvm_gc_allocate@plt>
  mov    %rax,%r12
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *__tiger__substring(char *s, int off, int len) {
  char *s1 = llvm_gc_allocate(len + 1);
  strncpy(s1, &s[off], len + 1);
  return s1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__tiger__substring>:
  endbr64
  push   %r13
  lea    0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <llvm_gc_allocate@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *__tiger__substring(char *s, int off, int len) {
  char *s1 = llvm_gc_allocate(len + 1);
  strncpy(s1, &s[off], len + 1);
  return s1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__tiger__substring>:
  endbr64
  push   %r13
  lea    0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <llvm_gc_allocate@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *__tiger__substring(char *s, int off, int len) {
  char *s1 = llvm_gc_allocate(len + 1);
  strncpy(s1, &s[off], len + 1);
  return s1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L10
L8:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D30
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string

tool: D14: This program prints a table of squares.

tool: D23: Enter number of entries in table:

tool: D30: %d

tool: D18: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  i = 1;
  while (i <= n) {
    printf("%10d%10d\n", i, i * i);
    i++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L21
  mov    $0x1,%ebx
  lea    D24(%rip),%rbp
L1:
  mov    %ebx,%edx
  imul   %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L1
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: string
name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D30
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string

tool: D10: This program prints a table of squares.

tool: D5: Enter number of entries in table:

tool: D30: %d

tool: D24: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  i = 1;
  while (i <= n) {
    printf("%10d%10d\n", i, i * i);
    i++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L29
  mov    $0x1,%ebx
  lea    D39(%rip),%rbp
  nopl   0x0(%rax)
L11:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L11
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D35
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: string

tool: D29: This program prints a table of squares.

tool: D35: Enter number of entries in table:

tool: D3: %d

tool: D39: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  i = 1;
  while (i <= n) {
    printf("%10d%10d\n", i, i * i);
    i++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L5
  mov    $0x1,%ebx
  lea    D24(%rip),%rbp
  nopl   0x0(%rax)
L13:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L13
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D24
datatype: string

tool: D23: This program prints a table of squares.

tool: D5: Enter number of entries in table:

tool: D7: %d

tool: D24: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  i = 1;
  while (i <= n) {
    printf("%10d%10d\n", i, i * i);
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  addl   $0x65,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
hash(name) char *name;
{
  int sum;
  for (sum = 0; *name != '\0'; name++)
    sum += (sum + *name);
  sum %= 101;
  if (sum < 0)
    sum += 101;
  return (sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  mov    $0x0,%edx
L19:
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
  movslq %edx,%rax
  imul   $0x288df0cb,%rax,%rax
  sar    $0x24,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x65,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x65(%rax),%edx
  cmovs  %edx,%eax
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
hash(name) char *name;
{
  int sum;
  for (sum = 0; *name != '\0'; name++)
    sum += (sum + *name);
  sum %= 101;
  if (sum < 0)
    sum += 101;
  return (sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L19
  xor    %edx,%edx
  nopl   (%rax)
L9:
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L9
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x288df0cb,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  imul   $0x65,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x65(%rax),%edx
  cmovs  %edx,%eax
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
hash(name) char *name;
{
  int sum;
  for (sum = 0; *name != '\0'; name++)
    sum += (sum + *name);
  sum %= 101;
  if (sum < 0)
    sum += 101;
  return (sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L12
  xor    %edx,%edx
  nopl   (%rax)
L16:
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L16
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x288df0cb,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  imul   $0x65,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x65(%rax),%edx
  cmovs  %edx,%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
hash(name) char *name;
{
  int sum;
  for (sum = 0; *name != '\0'; name++)
    sum += (sum + *name);
  sum %= 101;
  if (sum < 0)
    sum += 101;
  return (sum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dumb_read_misc_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <dumb_read_line@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void dumb_read_misc_line(char *s, char *prompt) {
  dumb_read_line(s, prompt, 0, 0, 0, 0);
  s[strlen(s) - 1] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dumb_read_misc_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  call   <dumb_read_line@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void dumb_read_misc_line(char *s, char *prompt) {
  dumb_read_line(s, prompt, 0, 0, 0, 0);
  s[strlen(s) - 1] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dumb_read_misc_line>:
  endbr64
  push   %rbx
  xor    %r9d,%r9d
  mov    %rdi,%rbx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  call   <dumb_read_line@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void dumb_read_misc_line(char *s, char *prompt) {
  dumb_read_line(s, prompt, 0, 0, 0, 0);
  s[strlen(s) - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dumb_read_misc_line>:
  endbr64
  push   %rbx
  xor    %r9d,%r9d
  mov    %rdi,%rbx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  call   <dumb_read_line@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void dumb_read_misc_line(char *s, char *prompt) {
  dumb_read_line(s, prompt, 0, 0, 0, 0);
  s[strlen(s) - 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mp_mulh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9d,-0x24(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    0x10(%rbp),%r9
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <mp_mul_i2d@plt>
  mov    0x18(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <mp_mul_i2d@plt>
  mov    0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    0x10(%rbp),%rsi
  mov    %eax,%edi
  call   <mp_mul_cmul@plt>
  mov    -0x20(%rbp),%rdi
  mov    0x18(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <mp_mul_d2i@plt>
  nop
  leave
  ret
```

assistant: ```c
void mp_mulh(int n, int radix, int in1[], int in2[], int out[], int nfft, double in1fft[], double outfft[]) {
  void mp_mul_i2d(int n, int radix, int nfft, int shift, int in[], double dout[]);
  void mp_mul_cmul(int nfft, double d1[], double d2[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_i2d(n, radix, nfft, 0, in1, in1fft);
  mp_mul_i2d(n, radix, nfft, 0, in2, outfft);
  mp_mul_cmul(nfft, in1fft, outfft);
  mp_mul_d2i(n, radix, nfft, outfft, out);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mp_mulh>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %rcx,%r15
  mov    %r8,%r14
  mov    %r9d,%ebx
  mov    0x48(%rsp),%r13
  mov    0x40(%rsp),%r9
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    %ebx,%edx
  call   <mp_mul_i2d@plt>
  mov    %r13,%r9
  mov    %r15,%r8
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mp_mul_i2d@plt>
  mov    %r13,%rdx
  mov    0x40(%rsp),%rsi
  mov    %ebx,%edi
  call   <mp_mul_cmul@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mp_mul_d2i@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mp_mulh(int n, int radix, int in1[], int in2[], int out[], int nfft, double in1fft[], double outfft[]) {
  void mp_mul_i2d(int n, int radix, int nfft, int shift, int in[], double dout[]);
  void mp_mul_cmul(int nfft, double d1[], double d2[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_i2d(n, radix, nfft, 0, in1, in1fft);
  mp_mul_i2d(n, radix, nfft, 0, in2, outfft);
  mp_mul_cmul(nfft, in1fft, outfft);
  mp_mul_d2i(n, radix, nfft, outfft, out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mp_mulh>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  xor    %ecx,%ecx
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  mov    %rdx,%r8
  mov    %r12d,%edx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r10
  mov    0x58(%rsp),%r14
  mov    %r10,%r9
  mov    %r10,0x8(%rsp)
  call   <mp_mul_i2d@plt>
  mov    %r15,%r8
  mov    %r14,%r9
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mp_mul_i2d@plt>
  mov    0x8(%rsp),%rsi
  mov    %r14,%rdx
  mov    %r12d,%edi
  call   <mp_mul_cmul@plt>
  add    $0x18,%rsp
  mov    %rbx,%r8
  mov    %r14,%rcx
  pop    %rbx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <mp_mul_d2i@plt>
```

assistant: ```c
void mp_mulh(int n, int radix, int in1[], int in2[], int out[], int nfft, double in1fft[], double outfft[]) {
  void mp_mul_i2d(int n, int radix, int nfft, int shift, int in[], double dout[]);
  void mp_mul_cmul(int nfft, double d1[], double d2[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_i2d(n, radix, nfft, 0, in1, in1fft);
  mp_mul_i2d(n, radix, nfft, 0, in2, outfft);
  mp_mul_cmul(nfft, in1fft, outfft);
  mp_mul_d2i(n, radix, nfft, outfft, out);
}
```