ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bicubic_interpolation_cell>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x40,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movsd  %xmm1,(%rsp)
  call   <cubic_interpolation_cell@plt>
  movsd  (%rsp),%xmm1
  lea    0x20(%rbx),%rdi
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm1,%xmm0
  call   <cubic_interpolation_cell@plt>
  movsd  (%rsp),%xmm1
  lea    0x40(%rbx),%rdi
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm1,%xmm0
  call   <cubic_interpolation_cell@plt>
  movsd  (%rsp),%xmm1
  lea    0x60(%rbx),%rdi
  movsd  %xmm0,0x20(%rsp)
  movapd %xmm1,%xmm0
  call   <cubic_interpolation_cell@plt>
  movsd  0x8(%rsp),%xmm2
  lea    0x10(%rsp),%rdi
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm2,%xmm0
  call   <cubic_interpolation_cell@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double bicubic_interpolation_cell(double p[4][4], double x, double y) {
  double v[4];
  v[0] = cubic_interpolation_cell(p[0], y);
  v[1] = cubic_interpolation_cell(p[1], y);
  v[2] = cubic_interpolation_cell(p[2], y);
  v[3] = cubic_interpolation_cell(p[3], y);
  return cubic_interpolation_cell(v, x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bicubic_interpolation_cell>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x40,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movsd  %xmm1,(%rsp)
  call   <cubic_interpolation_cell@plt>
  movsd  (%rsp),%xmm1
  lea    0x20(%rbx),%rdi
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm1,%xmm0
  call   <cubic_interpolation_cell@plt>
  movsd  (%rsp),%xmm1
  lea    0x40(%rbx),%rdi
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm1,%xmm0
  call   <cubic_interpolation_cell@plt>
  movsd  (%rsp),%xmm1
  lea    0x60(%rbx),%rdi
  movsd  %xmm0,0x20(%rsp)
  movapd %xmm1,%xmm0
  call   <cubic_interpolation_cell@plt>
  movsd  0x8(%rsp),%xmm2
  lea    0x10(%rsp),%rdi
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm2,%xmm0
  call   <cubic_interpolation_cell@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double bicubic_interpolation_cell(double p[4][4], double x, double y) {
  double v[4];
  v[0] = cubic_interpolation_cell(p[0], y);
  v[1] = cubic_interpolation_cell(p[1], y);
  v[2] = cubic_interpolation_cell(p[2], y);
  v[3] = cubic_interpolation_cell(p[3], y);
  return cubic_interpolation_cell(v, x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ewens_stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  D18(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L12
L11:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x4,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L11
  movsd  D18(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: f64

tool: D18: 1

assistant: ```c
double ewens_stat(int *r) {
  int *ipt;
  double coef;
  coef = 1.0;
  for (ipt = r + 1; *ipt; ipt++)
    coef *= *ipt;
  return 1.0 / coef;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ewens_stat>:
  endbr64
  lea    0x4(%rdi),%rdx
  mov    0x4(%rdi),%eax
  test   %eax,%eax
  je     L7
  movsd  D26(%rip),%xmm1
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm1
  add    $0x4,%rdx
  mov    (%rdx),%eax
  test   %eax,%eax
  jne    L14
L4:
  movsd  D26(%rip),%xmm0
  divsd  %xmm1,%xmm0
  ret
L7:
  movsd  D26(%rip),%xmm1
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_guessed: f64

tool: D26: 1

assistant: ```c
double ewens_stat(int *r) {
  int *ipt;
  double coef;
  coef = 1.0;
  for (ipt = r + 1; *ipt; ipt++)
    coef *= *ipt;
  return 1.0 / coef;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ewens_stat>:
  endbr64
  mov    0x4(%rdi),%eax
  movsd  D3(%rip),%xmm0
  lea    0x4(%rdi),%rdx
  test   %eax,%eax
  je     L1
  movapd %xmm0,%xmm1
  nopl   0x0(%rax,%rax,1)
L17:
  pxor   %xmm2,%xmm2
  add    $0x4,%rdx
  cvtsi2sd %eax,%xmm2
  mov    (%rdx),%eax
  mulsd  %xmm2,%xmm1
  test   %eax,%eax
  jne    L17
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: f64

tool: D3: 1

assistant: ```c
double ewens_stat(int *r) {
  int *ipt;
  double coef;
  coef = 1.0;
  for (ipt = r + 1; *ipt; ipt++)
    coef *= *ipt;
  return 1.0 / coef;
}
```
user: What is the c source code of the assembly code below:

```asm
<ewens_stat>:
  endbr64
  mov    0x4(%rdi),%eax
  movsd  D9(%rip),%xmm0
  lea    0x4(%rdi),%rdx
  test   %eax,%eax
  je     L18
  movapd %xmm0,%xmm1
  nopl   0x0(%rax,%rax,1)
L16:
  pxor   %xmm2,%xmm2
  add    $0x4,%rdx
  cvtsi2sd %eax,%xmm2
  mov    (%rdx),%eax
  mulsd  %xmm2,%xmm1
  test   %eax,%eax
  jne    L16
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: f64

tool: D9: 1

assistant: ```c
double ewens_stat(int *r) {
  int *ipt;
  double coef;
  coef = 1.0;
  for (ipt = r + 1; *ipt; ipt++)
    coef *= *ipt;
  return 1.0 / coef;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: 

 Hello World 



assistant: ```c
int main() {
  printf("\n\n Hello World \n\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: 

 Hello World 



assistant: ```c
int main() {
  printf("\n\n Hello World \n\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: 

 Hello World 



assistant: ```c
int main() {
  printf("\n\n Hello World \n\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: 

 Hello World 



assistant: ```c
int main() {
  printf("\n\n Hello World \n\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_number@plt>
  test   %eax,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: Illegal number: %s

assistant: ```c
int number(const char *s) {
  if (!is_number(s))
    error("Illegal number: %s", s);
  return atoi(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<number>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <is_number@plt>
  test   %eax,%eax
  je     L8
L15:
  mov    %rbx,%rdi
  call   <atoi@plt>
  pop    %rbx
  ret
L8:
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <error@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: Illegal number: %s

assistant: ```c
int number(const char *s) {
  if (!is_number(s))
    error("Illegal number: %s", s);
  return atoi(s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<number>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <is_number@plt>
  test   %eax,%eax
  je     L6
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <error@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <atoi@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: Illegal number: %s

assistant: ```c
int number(const char *s) {
  if (!is_number(s))
    error("Illegal number: %s", s);
  return atoi(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<number>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <is_number@plt>
  test   %eax,%eax
  je     L1
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <error@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <atoi@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: Illegal number: %s

assistant: ```c
int number(const char *s) {
  if (!is_number(s))
    error("Illegal number: %s", s);
  return atoi(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ilog10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x9,-0x14(%rbp)
  ja     L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned ilog10(unsigned n) {
  int r = 0;
  while (n >= 10)
    n /= 10, r++;
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<ilog10>:
  endbr64
  cmp    $0x9,%edi
  jbe    L15
  mov    $0x0,%eax
  mov    $0xcccccccd,%ecx
L4:
  mov    %edi,%edx
  mov    %edi,%edi
  imul   %rcx,%rdi
  shr    $0x23,%rdi
  add    $0x1,%eax
  cmp    $0x63,%edx
  ja     L4
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned ilog10(unsigned n) {
  int r = 0;
  while (n >= 10)
    n /= 10, r++;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ilog10>:
  endbr64
  xor    %eax,%eax
  cmp    $0x9,%edi
  jbe    L17
  mov    $0xcccccccd,%ecx
L6:
  mov    %edi,%edi
  add    $0x1,%eax
  mov    %rdi,%rdx
  imul   %rcx,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%edx
  ja     L6
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
unsigned ilog10(unsigned n) {
  int r = 0;
  while (n >= 10)
    n /= 10, r++;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ilog10>:
  endbr64
  xor    %eax,%eax
  cmp    $0x9,%edi
  jbe    L2
  mov    $0xcccccccd,%ecx
L12:
  mov    %edi,%edi
  add    $0x1,%eax
  mov    %rdi,%rdx
  imul   %rcx,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%edx
  ja     L12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
unsigned ilog10(unsigned n) {
  int r = 0;
  while (n >= 10)
    n /= 10, r++;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L30
  mov    $0x1,%eax
  jmp    L2
L30:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L14
  mov    $0x1,%eax
  jmp    L2
L14:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x1,(%rax)
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L42
  mov    $0x0,%eax
  jmp    L2
L42:
  mov    $0x1,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
int main() {
  int x;
  int *p;
  int **pp;
  x = 0;
  p = &x;
  pp = &p;
  if (*p)
    return 1;
  if (**pp)
    return 1;
  else
    **pp = 1;
  if (x)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  int *p;
  int **pp;
  x = 0;
  p = &x;
  pp = &p;
  if (*p)
    return 1;
  if (**pp)
    return 1;
  else
    **pp = 1;
  if (x)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  int *p;
  int **pp;
  x = 0;
  p = &x;
  pp = &p;
  if (*p)
    return 1;
  if (**pp)
    return 1;
  else
    **pp = 1;
  if (x)
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  int *p;
  int **pp;
  x = 0;
  p = &x;
  pp = &p;
  if (*p)
    return 1;
  if (**pp)
    return 1;
  else
    **pp = 1;
  if (x)
    return 0;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<generate_shift_group>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L17
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  imul   -0x14(%rbp),%eax
  add    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L13
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L15
L23:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,%esi
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    (%rcx,%rsi,1),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void generate_shift_group(int *inin, int radix, int n) {
  int *in = inin;
  int nrad = n / radix;
  int nrad2 = nrad / 2;
  for (int i = 0; i < (radix); i++) {
    int val = in[i];
    in[i] = (val % (nrad)) / 2 + (val % 2) * (nrad) + (val / nrad) * (nrad);
  }
  for (int i = radix; i < n; i++) {
    in[i] = in[i % radix] + (i / radix);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<generate_shift_group>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %edx,%ebx
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %esi,%esi
  jle    L25
  mov    %eax,%r10d
  mov    %eax,%r11d
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L4:
  mov    (%rdi),%ecx
  mov    %ecx,%eax
  cltd
  idiv   %r11d
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %edx,%ecx
  and    $0x1,%ecx
  sub    %edx,%ecx
  imul   %r10d,%ecx
  add    %ecx,%esi
  imul   %r10d,%eax
  add    %eax,%esi
  mov    %esi,(%rdi)
  add    $0x4,%rdi
  cmp    %rbp,%rdi
  jne    L4
L25:
  cmp    %r8d,%ebx
  jle    L1
  movslq %r8d,%rcx
L20:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  add    (%r9,%rdx,4),%eax
  mov    %eax,(%r9,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jg     L20
L1:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void generate_shift_group(int *inin, int radix, int n) {
  int *in = inin;
  int nrad = n / radix;
  int nrad2 = nrad / 2;
  for (int i = 0; i < (radix); i++) {
    int val = in[i];
    in[i] = (val % (nrad)) / 2 + (val % 2) * (nrad) + (val / nrad) * (nrad);
  }
  for (int i = radix; i < n; i++) {
    in[i] = in[i % radix] + (i / radix);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<generate_shift_group>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%r10d
  push   %rbx
  mov    %rdi,%r9
  cltd
  mov    %esi,%r8d
  idiv   %esi
  test   %esi,%esi
  jle    L0
  mov    %eax,%edi
  lea    -0x1(%r8),%eax
  mov    %r9,%rsi
  lea    0x4(%r9,%rax,4),%r11
  nopl   (%rax)
L3:
  mov    (%rsi),%ecx
  add    $0x4,%rsi
  mov    %ecx,%eax
  mov    %ecx,%ebx
  cltd
  shr    $0x1f,%ebx
  idiv   %edi
  add    %ebx,%ecx
  and    $0x1,%ecx
  sub    %ebx,%ecx
  imul   %edi,%ecx
  mov    %edx,%ebx
  imul   %edi,%eax
  shr    $0x1f,%ebx
  add    %edx,%ebx
  sar    %ebx
  add    %ebx,%ecx
  add    %eax,%ecx
  mov    %ecx,-0x4(%rsi)
  cmp    %rsi,%r11
  jne    L3
L0:
  cmp    %r8d,%r10d
  jle    L39
  movslq %r8d,%rcx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  add    (%r9,%rdx,4),%eax
  mov    %eax,(%r9,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%r10d
  jg     L19
L39:
  pop    %rbx
  ret
```

assistant: ```c
void generate_shift_group(int *inin, int radix, int n) {
  int *in = inin;
  int nrad = n / radix;
  int nrad2 = nrad / 2;
  for (int i = 0; i < (radix); i++) {
    int val = in[i];
    in[i] = (val % (nrad)) / 2 + (val % 2) * (nrad) + (val / nrad) * (nrad);
  }
  for (int i = radix; i < n; i++) {
    in[i] = in[i % radix] + (i / radix);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generate_shift_group>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%r10d
  push   %rbx
  mov    %rdi,%r9
  cltd
  mov    %esi,%r8d
  idiv   %esi
  test   %esi,%esi
  jle    L28
  mov    %eax,%edi
  lea    -0x1(%r8),%eax
  mov    %r9,%rsi
  lea    0x4(%r9,%rax,4),%r11
  nopl   (%rax)
L22:
  mov    (%rsi),%ecx
  add    $0x4,%rsi
  mov    %ecx,%eax
  mov    %ecx,%ebx
  cltd
  shr    $0x1f,%ebx
  idiv   %edi
  add    %ebx,%ecx
  and    $0x1,%ecx
  sub    %ebx,%ecx
  imul   %edi,%ecx
  mov    %edx,%ebx
  imul   %edi,%eax
  shr    $0x1f,%ebx
  add    %edx,%ebx
  sar    %ebx
  add    %ebx,%ecx
  add    %eax,%ecx
  mov    %ecx,-0x4(%rsi)
  cmp    %rsi,%r11
  jne    L22
L28:
  cmp    %r8d,%r10d
  jle    L17
  movslq %r8d,%rcx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  add    (%r9,%rdx,4),%eax
  mov    %eax,(%r9,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%r10d
  jg     L36
L17:
  pop    %rbx
  ret
```

assistant: ```c
void generate_shift_group(int *inin, int radix, int n) {
  int *in = inin;
  int nrad = n / radix;
  int nrad2 = nrad / 2;
  for (int i = 0; i < (radix); i++) {
    int val = in[i];
    in[i] = (val % (nrad)) / 2 + (val % 2) * (nrad) + (val / nrad) * (nrad);
  }
  for (int i = radix; i < n; i++) {
    in[i] = in[i % radix] + (i / radix);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<config_read>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rbx
  mov    $0x0,%ebp
  lea    0x7(%rsp),%r14
  movabs $0x100002400,%r15
  jmp    L135
L122:
  cmp    $0x20,%al
  ja     L162
  bt     %rax,%r15
  jae    L162
  movl   $0x0,(%rbx)
  jmp    L127
  movl   $0x1,(%rbx)
L127:
  add    $0x1,%ebp
  add    $0x4,%rbx
L135:
  mov    %r12,%rdi
  call   <feof@plt>
  cmp    %r13d,%ebp
  jge    L75
  test   %eax,%eax
  jne    L75
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <fread@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x7a,%al
  jg     L162
  cmp    $0x30,%al
  jle    L122
  sub    $0x31,%eax
  cmp    $0x49,%al
  ja     L162
  movzbl %al,%eax
  lea    D3(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  movl   $0x2,(%rbx)
  jmp    L127
  movl   $0x4,(%rbx)
  jmp    L127
  movl   $0x8,(%rbx)
  jmp    L127
  movl   $0x10,(%rbx)
  jmp    L127
  movl   $0x20,(%rbx)
  jmp    L127
  movl   $0x40,(%rbx)
  jmp    L127
  movl   $0x80,(%rbx)
  jmp    L127
  movl   $0x200,(%rbx)
  jmp    L127
  movl   $0x100,(%rbx)
  jmp    L127
L162:
  mov    $0xffffffff,%eax
L167:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L117
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    $0x0,%eax
  jmp    L167
L117:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int config_read(FILE *f, int n, int *joymap) {
  for (int i = 0; !feof(f) && i < n; i++) {
    char c;
    fread(&c, sizeof(char), 1, f);
    switch (c) {
    case 'a':
      joymap[i] = (0x1);
      break;
    case 'q':
      joymap[i] = (0x1 << 1);
      break;
    case 'w':
      joymap[i] = (0x1 << 2);
      break;
    case 'e':
      joymap[i] = (0x1 << 3);
      break;
    case 'd':
      joymap[i] = (0x1 << 4);
      break;
    case 'c':
      joymap[i] = (0x1 << 5);
      break;
    case 'x':
      joymap[i] = (0x1 << 6);
      break;
    case 'z':
      joymap[i] = (0x1 << 7);
      break;
    case '1':
      joymap[i] = (0x1 << 9);
      break;
    case '3':
      joymap[i] = (0x1 << 8);
      break;
    case ' ':
    case '\r':
    case '\n':
      joymap[i] = 0x0;
      break;
    default:
      return -1;
    }
  }
  return 0;
}
```