ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D47(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pcmpeqd %xmm3,%xmm3
  movdqa D34(%rip),%xmm2
  movd   %eax,%xmm4
  pshufd $0x0,%xmm4,%xmm0
  movdqa %xmm0,%xmm1
  pcmpeqd D18(%rip),%xmm0
  pcmpeqd D0(%rip),%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm3,%xmm1
  por    %xmm2,%xmm1
  movdqa D55(%rip),%xmm2
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x8,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  cmp    $0x7,%eax
  je     L56
  cmp    $0x1d,%eax
  je     L0
  movd   %xmm0,%esi
  cmp    $0xffffffff,%esi
  jne    L17
  lea    D1(%rip),%rdi
  call   <puts@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  mov    $0x9,%esi
L17:
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
L56:
  mov    $0x8,%esi
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D47
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D34
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D55
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D54
type_infered: string

tool: D47: Enter integer search key: 

tool: D2: %d

tool: {"D34": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x7c,0x00,0x00,0x00,0x5a,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x21,0x00,0x00,0x00]}

tool: {"D0": [0x04,0x00,0x00,0x00,0x24,0x00,0x00,0x00,0x59,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D55": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: D1: Value not found

tool: D54: Found value in element %d


assistant: ```c
int main(void) {
  int T[10] = {4, 36, 89, 11, 124, 90, 4, 33, 7, 29};
  int n;
  int searchKey;
  int element = -1;
  printf("Enter integer search key: ");
  scanf("%d", &searchKey);
  for (n = 0; n < 10; n++) {
    if (T[n] == searchKey) {
      element = n;
    }
  }
  if (element != -1) {
    printf("Found value in element %d\n", element);
  } else {
    printf("Value not found\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_combos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%edx
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  je     L18
  mov    $0xa,%edi
  call   <putchar@plt>
L18:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: %s=%d

assistant: ```c
void print_combos(char **combos, const int length, const int result) {
  for (int i = 0; i < length; i++) {
    printf("%s=%d", combos[i], result);
    if (i != length - 1) {
      printf("\n");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_combos>:
  endbr64
  test   %esi,%esi
  jle    L27
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %esi,%r15d
  mov    $0x0,%ebx
  lea    D8(%rip),%r14
  jmp    L29
L8:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L5
L29:
  mov    (%r12,%rbx,8),%rsi
  mov    %r13d,%edx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbp),%eax
  cmp    %ebx,%eax
  je     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L8
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: %s=%d

assistant: ```c
void print_combos(char **combos, const int length, const int result) {
  for (int i = 0; i < length; i++) {
    printf("%s=%d", combos[i], result);
    if (i != length - 1) {
      printf("\n");
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_combos>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L28:
  mov    (%r12,%rbx,8),%rsi
  xor    %eax,%eax
  mov    %r13d,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    %ebx,%r15d
  je     L4
  mov    $0xa,%edi
  call   <putchar@plt>
L4:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D5: %s=%d

assistant: ```c
void print_combos(char **combos, const int length, const int result) {
  for (int i = 0; i < length; i++) {
    printf("%s=%d", combos[i], result);
    if (i != length - 1) {
      printf("\n");
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_combos>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    (%r12,%rbx,8),%rsi
  xor    %eax,%eax
  mov    %r13d,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    %ebx,%r15d
  je     L27
  mov    $0xa,%edi
  call   <putchar@plt>
L27:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %s=%d

assistant: ```c
void print_combos(char **combos, const int length, const int result) {
  for (int i = 0; i < length; i++) {
    printf("%s=%d", combos[i], result);
    if (i != length - 1) {
      printf("\n");
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<emit_chesc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x22,-0xc(%rbp)
  jne    L27
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x77,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L24
L27:
  cmpl   $0x5c,-0xc(%rbp)
  jne    L3
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x78,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L24
L3:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
L24:
  pop    %rbp
  ret
```

assistant: ```c
char *emit_chesc(char *t, int v) {
  if (v == '\"') {
    *t++ = 'w';
    return (t);
  }
  if (v == '\\') {
    *t++ = 'x';
    return (t);
  }
  *t++ = v;
  return (t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_chesc>:
  endbr64
  lea    0x1(%rdi),%rax
  mov    $0x77,%edx
  cmp    $0x22,%esi
  je     L13
  lea    0x1(%rdi),%rax
  mov    %esi,%edx
  cmp    $0x5c,%esi
  je     L9
L13:
  mov    %dl,(%rdi)
  ret
L9:
  mov    $0x78,%edx
  jmp    L13
```

assistant: ```c
char *emit_chesc(char *t, int v) {
  if (v == '\"') {
    *t++ = 'w';
    return (t);
  }
  if (v == '\\') {
    *t++ = 'x';
    return (t);
  }
  *t++ = v;
  return (t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_chesc>:
  endbr64
  lea    0x1(%rdi),%r8
  mov    $0x77,%eax
  cmp    $0x22,%esi
  je     L1
  cmp    $0x5c,%esi
  mov    $0x78,%eax
  cmovne %esi,%eax
L1:
  mov    %al,(%rdi)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *emit_chesc(char *t, int v) {
  if (v == '\"') {
    *t++ = 'w';
    return (t);
  }
  if (v == '\\') {
    *t++ = 'x';
    return (t);
  }
  *t++ = v;
  return (t);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<emit_chesc>:
  endbr64
  lea    0x1(%rdi),%r8
  mov    $0x77,%eax
  cmp    $0x22,%esi
  je     L2
  cmp    $0x5c,%esi
  mov    $0x78,%eax
  cmovne %esi,%eax
L2:
  mov    %al,(%rdi)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *emit_chesc(char *t, int v) {
  if (v == '\"') {
    *t++ = 'w';
    return (t);
  }
  if (v == '\\') {
    *t++ = 'x';
    return (t);
  }
  *t++ = v;
  return (t);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string

tool: D2: pid:%d


tool: D18: ppid:%d


assistant: ```c
int main() {
  pid_t pid = getpid();
  printf("pid:%d\n", pid);
  pid_t ppid = getppid();
  printf("ppid:%d\n", ppid);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string

tool: D5: pid:%d


tool: D8: ppid:%d


assistant: ```c
int main() {
  pid_t pid = getpid();
  printf("pid:%d\n", pid);
  pid_t ppid = getppid();
  printf("ppid:%d\n", ppid);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D17
data_type: string

tool: D9: pid:%d


tool: D17: ppid:%d


assistant: ```c
int main() {
  pid_t pid = getpid();
  printf("pid:%d\n", pid);
  pid_t ppid = getppid();
  printf("ppid:%d\n", ppid);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string

tool: D12: pid:%d


tool: D2: ppid:%d


assistant: ```c
int main() {
  pid_t pid = getpid();
  printf("pid:%d\n", pid);
  pid_t ppid = getppid();
  printf("ppid:%d\n", ppid);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<render_direct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L8
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <flush_push@plt>
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void render_direct(uint8_t symbol, uint8_t times) {
  for (uint8_t i = 0; i < times; ++i)
    flush_push(symbol);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<render_direct>:
  endbr64
  test   %rsi,%rsi
  jle    L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L4:
  mov    %r12,%rdi
  call   <flush_push@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  ret
```

assistant: ```c
void render_direct(uint8_t symbol, uint8_t times) {
  for (uint8_t i = 0; i < times; ++i)
    flush_push(symbol);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<render_direct>:
  endbr64
  test   %rsi,%rsi
  jle    L4
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L2:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <flush_push@plt>
  cmp    %rbx,%rbp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void render_direct(uint8_t symbol, uint8_t times) {
  for (uint8_t i = 0; i < times; ++i)
    flush_push(symbol);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<render_direct>:
  endbr64
  test   %rsi,%rsi
  jle    L6
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L12:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <flush_push@plt>
  cmp    %rbx,%rbp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void render_direct(uint8_t symbol, uint8_t times) {
  for (uint8_t i = 0; i < times; ++i)
    flush_push(symbol);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ivec_new_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ivecs_new_read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L23
  mov    $0x0,%eax
  jmp    L3
L23:
  cmpl   $0x1,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  je     L7
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L7:
  mov    -0x10(%rbp),%rax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int *ivec_new_read(const char *fname, int *d_out) {
  int d, n;
  int *vi;
  n = ivecs_new_read(fname, &d, &vi);
  if (n < 0)
    return NULL;
  assert(n == 1);
  if (d_out)
    *d_out = d;
  return vi;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ivec_new_read>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <ivecs_new_read@plt>
  mov    $0x0,%edx
  test   %eax,%eax
  js     L6
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L22
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
L22:
  mov    0x10(%rsp),%rdx
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %rdx,%rax
  add    $0x20,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *ivec_new_read(const char *fname, int *d_out) {
  int d, n;
  int *vi;
  n = ivecs_new_read(fname, &d, &vi);
  if (n < 0)
    return NULL;
  assert(n == 1);
  if (d_out)
    *d_out = d;
  return vi;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ivec_new_read>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <ivecs_new_read@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  js     L25
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  test   %rbx,%rbx
  je     L14
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
L14:
  mov    0x10(%rsp),%r8
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  mov    %r8,%rax
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *ivec_new_read(const char *fname, int *d_out) {
  int d, n;
  int *vi;
  n = ivecs_new_read(fname, &d, &vi);
  if (n < 0)
    return NULL;
  assert(n == 1);
  if (d_out)
    *d_out = d;
  return vi;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ivec_new_read>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <ivecs_new_read@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  js     L12
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  test   %rbx,%rbx
  je     L26
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
L26:
  mov    0x10(%rsp),%r8
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  mov    %r8,%rax
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *ivec_new_read(const char *fname, int *d_out) {
  int d, n;
  int *vi;
  n = ivecs_new_read(fname, &d, &vi);
  if (n < 0)
    return NULL;
  assert(n == 1);
  if (d_out)
    *d_out = d;
  return vi;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  assert('"' + '\"' == 68);
  assert('/*' == 12074);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  assert('"' + '\"' == 68);
  assert('/*' == 12074);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  assert('"' + '\"' == 68);
  assert('/*' == 12074);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  assert('"' + '\"' == 68);
  assert('/*' == 12074);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<randchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <rndchr@plt>
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!@#$%%^&*(_-)+=[]{}<>|\;:'",./?~` 

assistant: ```c
char randchar() {
  return rndchr("abcdefghijklmnopqrstuvwxyz"
                "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                "0123456789"
                "!@#$%%^&*(_-)+=[]{}<>|\\;:'\",./?~` ");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<randchar>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <rndchr@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!@#$%%^&*(_-)+=[]{}<>|\;:'",./?~` 

assistant: ```c
char randchar() {
  return rndchr("abcdefghijklmnopqrstuvwxyz"
                "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                "0123456789"
                "!@#$%%^&*(_-)+=[]{}<>|\\;:'\",./?~` ");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<randchar>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <rndchr@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!@#$%%^&*(_-)+=[]{}<>|\;:'",./?~` 

assistant: ```c
char randchar() {
  return rndchr("abcdefghijklmnopqrstuvwxyz"
                "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                "0123456789"
                "!@#$%%^&*(_-)+=[]{}<>|\\;:'\",./?~` ");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<randchar>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <rndchr@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!@#$%%^&*(_-)+=[]{}<>|\;:'",./?~` 

assistant: ```c
char randchar() {
  return rndchr("abcdefghijklmnopqrstuvwxyz"
                "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                "0123456789"
                "!@#$%%^&*(_-)+=[]{}<>|\\;:'\",./?~` ");
}
```
user: What is the c source code of the assembly code below?

```asm
<null_debug_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void null_debug_output(int type, void *param) {
  (void)type;
  (void)param;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<null_debug_output>:
  endbr64
  ret
```

assistant: ```c
void null_debug_output(int type, void *param) {
  (void)type;
  (void)param;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<null_debug_output>:
  endbr64
  ret
```

assistant: ```c
void null_debug_output(int type, void *param) {
  (void)type;
  (void)param;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<null_debug_output>:
  endbr64
  ret
```

assistant: ```c
void null_debug_output(int type, void *param) {
  (void)type;
  (void)param;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<path_030_expected_6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jg     L48
  cmpl   $0x9,-0x14(%rbp)
  jge    L51
  cmpl   $0x2,-0x14(%rbp)
  je     L36
  cmpl   $0x2,-0x14(%rbp)
  jg     L48
  cmpl   $0x0,-0x14(%rbp)
  je     L51
  cmpl   $0x1,-0x14(%rbp)
  je     L46
  jmp    L48
L51:
  movl   $0x1,-0x4(%rbp)
L46:
  addl   $0x1,-0x4(%rbp)
  jmp    L48
L36:
  movl   $0x11,-0x4(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int path_030_expected_6(int y) {
  int x = 0;
  switch (y) {
  case 10:
  case 9:
  case 0:
    x = 1;
  case 1:
    if (y) {
    }
    x++;
    break;
  case 2:
    x = 17;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<path_030_expected_6>:
  endbr64
  mov    $0x11,%eax
  cmp    $0x2,%edi
  je     L42
  jg     L18
  test   %edi,%edi
  je     L17
  cmp    $0x1,%edi
  jne    L25
  mov    $0x0,%eax
L16:
  add    $0x1,%eax
L42:
  ret
L25:
  mov    $0x0,%eax
  ret
L18:
  sub    $0x9,%edi
  mov    $0x0,%eax
  cmp    $0x1,%edi
  ja     L42
  mov    $0x1,%eax
  jmp    L16
L17:
  mov    $0x1,%eax
  jmp    L16
```

assistant: ```c
int path_030_expected_6(int y) {
  int x = 0;
  switch (y) {
  case 10:
  case 9:
  case 0:
    x = 1;
  case 1:
    if (y) {
    }
    x++;
    break;
  case 2:
    x = 17;
  }
  return x;
}
```