ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%edx
  mov    %rax,%rsi
  mov    $0xb,%edi
  call   <minSubArrayLen@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 2, 3, 4, 5};
  printf("%d\n", minSubArrayLen(11, a, 5));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    %rsp,%rsi
  mov    $0x5,%edx
  mov    $0xb,%edi
  call   <minSubArrayLen@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 2, 3, 4, 5};
  printf("%d\n", minSubArrayLen(11, a, 5));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xb,%edi
  mov    $0x5,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rsi
  movl   $0x5,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  call   <minSubArrayLen@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 2, 3, 4, 5};
  printf("%d\n", minSubArrayLen(11, a, 5));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xb,%edi
  mov    $0x5,%edx
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x5,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <minSubArrayLen@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: byte[16]
name: unpack_data
arguments: label: D10
datatype: string

tool: {"D6": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D10: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 2, 3, 4, 5};
  printf("%d\n", minSubArrayLen(11, a, 5));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x34(%rbp)
  je     L47
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L9
L47:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x28(%rbp),%rcx
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rbx
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  je     L3
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L9
L3:
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L9:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D21
type: string

tool: D26: Usage: hex_to_single <hex value>

tool: D29: Not a valid hexadecimal value.

tool: D21: %f


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Usage: hex_to_single <hex value>\n");
    return 1;
  }
  char *end;
  int input = strtol(argv[1], &end, 16);
  if (end != argv[1] + strlen(argv[1])) {
    printf("Not a valid hexadecimal value.\n");
    return 2;
  }
  float *floatValue = (float *)&input;
  printf("%f\n", *floatValue);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L42
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    0x10(%rsp),%rsi
  mov    0x8(%rbp),%rdi
  mov    $0x10,%edx
  call   <strtol@plt>
  mov    %eax,0xc(%rsp)
  mov    0x8(%rbp),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  cmp    %rbp,0x10(%rsp)
  jne    L44
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
L44:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  jmp    L13
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string
name: unpack_data
arguments: label: D21
type_guessed: string

tool: D5: Usage: hex_to_single <hex value>

tool: D14: %f


tool: D21: Not a valid hexadecimal value.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Usage: hex_to_single <hex value>\n");
    return 1;
  }
  char *end;
  int input = strtol(argv[1], &end, 16);
  if (end != argv[1] + strlen(argv[1])) {
    printf("Not a valid hexadecimal value.\n");
    return 2;
  }
  float *floatValue = (float *)&input;
  printf("%f\n", *floatValue);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L3
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L31:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  mov    %rsi,%rbx
  mov    $0x10,%edx
  lea    0x10(%rsp),%rsi
  mov    0x8(%rbx),%rdi
  call   <strtol@plt>
  mov    0x8(%rbx),%rbx
  mov    %eax,0xc(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  cmp    %rbx,0x10(%rsp)
  jne    L1
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L31
L1:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L31
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D5
type_infered: string

tool: D2: Usage: hex_to_single <hex value>

tool: D1: %f


tool: D5: Not a valid hexadecimal value.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Usage: hex_to_single <hex value>\n");
    return 1;
  }
  char *end;
  int input = strtol(argv[1], &end, 16);
  if (end != argv[1] + strlen(argv[1])) {
    printf("Not a valid hexadecimal value.\n");
    return 2;
  }
  float *floatValue = (float *)&input;
  printf("%f\n", *floatValue);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L7
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  mov    %rsi,%rbx
  mov    $0x10,%edx
  lea    0x10(%rsp),%rsi
  mov    0x8(%rbx),%rdi
  call   <strtol@plt>
  mov    0x8(%rbx),%rbx
  mov    %eax,0xc(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  cmp    %rbx,0x10(%rsp)
  jne    L15
  pxor   %xmm0,%xmm0
  lea    D25(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L11
L15:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L11
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D25
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string

tool: D21: Usage: hex_to_single <hex value>

tool: D25: %f


tool: D10: Not a valid hexadecimal value.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Usage: hex_to_single <hex value>\n");
    return 1;
  }
  char *end;
  int input = strtol(argv[1], &end, 16);
  if (end != argv[1] + strlen(argv[1])) {
    printf("Not a valid hexadecimal value.\n");
    return 2;
  }
  float *floatValue = (float *)&input;
  printf("%f\n", *floatValue);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<heapsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L32
L6:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <siftDown@plt>
  subl   $0x1,-0x10(%rbp)
L32:
  cmpl   $0x0,-0x10(%rbp)
  jns    L6
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L35
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x18(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <siftDown@plt>
  subl   $0x1,-0xc(%rbp)
L35:
  cmpl   $0x0,-0xc(%rbp)
  jg     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapsort(double *a, int count) {
  int start, end;
  for (start = (count - 2) / 2; start >= 0; start--) {
    siftDown(a, start, count);
  }
  for (end = count - 1; end > 0; end--) {
    do {
      double t = a[end];
      a[end] = a[0];
      a[0] = t;
    } while (0);
    siftDown(a, 0, end);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<heapsort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    -0x2(%rsi),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  test   %esi,%esi
  jle    L30
L4:
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <siftDown@plt>
  sub    $0x1,%r12d
  jns    L4
L30:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L7
  movslq %ebx,%rbx
L21:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  movsd  0x0(%rbp),%xmm1
  movsd  %xmm1,0x0(%rbp,%rbx,8)
  movsd  %xmm0,0x0(%rbp)
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <siftDown@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L21
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapsort(double *a, int count) {
  int start, end;
  for (start = (count - 2) / 2; start >= 0; start--) {
    siftDown(a, start, count);
  }
  for (end = count - 1; end > 0; end--) {
    do {
      double t = a[end];
      a[end] = a[0];
      a[0] = t;
    } while (0);
    siftDown(a, 0, end);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapsort>:
  endbr64
  lea    -0x2(%rsi),%eax
  push   %r12
  mov    %eax,%r12d
  push   %rbp
  mov    %rdi,%rbp
  shr    $0x1f,%r12d
  push   %rbx
  mov    %esi,%ebx
  add    %eax,%r12d
  sar    %r12d
  test   %esi,%esi
  jle    L24
  nopl   0x0(%rax)
L37:
  mov    %r12d,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <siftDown@plt>
  sub    $0x1,%r12d
  jae    L37
L24:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L38
  movslq %ebx,%rbx
  nopl   (%rax)
L8:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  movsd  0x0(%rbp),%xmm1
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movsd  %xmm1,0x0(%rbp,%rbx,8)
  sub    $0x1,%rbx
  movsd  %xmm0,0x0(%rbp)
  call   <siftDown@plt>
  test   %ebx,%ebx
  jg     L8
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapsort(double *a, int count) {
  int start, end;
  for (start = (count - 2) / 2; start >= 0; start--) {
    siftDown(a, start, count);
  }
  for (end = count - 1; end > 0; end--) {
    do {
      double t = a[end];
      a[end] = a[0];
      a[0] = t;
    } while (0);
    siftDown(a, 0, end);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapsort>:
  endbr64
  lea    -0x2(%rsi),%eax
  push   %r12
  mov    %eax,%r12d
  push   %rbp
  mov    %rdi,%rbp
  shr    $0x1f,%r12d
  push   %rbx
  mov    %esi,%ebx
  add    %eax,%r12d
  sar    %r12d
  test   %esi,%esi
  jle    L35
  nopl   0x0(%rax)
L25:
  mov    %r12d,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <siftDown@plt>
  sub    $0x1,%r12d
  jae    L25
L35:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L15
  movslq %ebx,%rbx
  nopl   (%rax)
L18:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  movsd  0x0(%rbp),%xmm1
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movsd  %xmm1,0x0(%rbp,%rbx,8)
  sub    $0x1,%rbx
  movsd  %xmm0,0x0(%rbp)
  call   <siftDown@plt>
  test   %ebx,%ebx
  jg     L18
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapsort(double *a, int count) {
  int start, end;
  for (start = (count - 2) / 2; start >= 0; start--) {
    siftDown(a, start, count);
  }
  for (end = count - 1; end > 0; end--) {
    do {
      double t = a[end];
      a[end] = a[0];
      a[0] = t;
    } while (0);
    siftDown(a, 0, end);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matchbalance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  je     L5
  mov    $0x0,%eax
  jmp    L3
L5:
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x20(%rbp)
  jne    L37
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  jmp    L3
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L10
  addl   $0x1,-0x4(%rbp)
L10:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
char *matchbalance(char *s, int b, int e) {
  if (*s != b)
    return NULL;
  else {
    int cont = 1;
    while (*(++s)) {
      if (*s == e) {
        if (--cont == 0)
          return s + 1;
      } else if (*s == b)
        cont++;
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matchbalance>:
  endbr64
  movsbl (%rdi),%ecx
  mov    $0x0,%eax
  cmp    %esi,%ecx
  jne    L21
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L65
  mov    $0x1,%r8d
  jmp    L0
L45:
  sub    $0x1,%r8d
  je     L51
L31:
  add    $0x1,%rdi
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L8
L0:
  mov    %rdi,%rax
  movsbl %cl,%ecx
  cmp    %edx,%ecx
  je     L45
  cmp    %esi,%ecx
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  jmp    L31
L51:
  add    $0x2,%rax
  ret
L8:
  mov    $0x0,%eax
  ret
L65:
  mov    $0x0,%eax
L21:
  ret
```

assistant: ```c
char *matchbalance(char *s, int b, int e) {
  if (*s != b)
    return NULL;
  else {
    int cont = 1;
    while (*(++s)) {
      if (*s == e) {
        if (--cont == 0)
          return s + 1;
      } else if (*s == b)
        cont++;
    }
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<matchbalance>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    %esi,%eax
  jne    L21
  movsbl 0x1(%rdi),%eax
  test   %al,%al
  je     L21
  mov    $0x1,%ecx
  jmp    L50
  nopl   (%rax)
L10:
  cmp    %esi,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
L54:
  movsbl 0x2(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L24
L50:
  cmp    %edx,%eax
  jne    L10
  sub    $0x1,%ecx
  jne    L54
  lea    0x2(%rdi),%r8
L21:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *matchbalance(char *s, int b, int e) {
  if (*s != b)
    return NULL;
  else {
    int cont = 1;
    while (*(++s)) {
      if (*s == e) {
        if (--cont == 0)
          return s + 1;
      } else if (*s == b)
        cont++;
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matchbalance>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    %esi,%eax
  jne    L30
  movsbl 0x1(%rdi),%eax
  test   %al,%al
  je     L30
  mov    $0x1,%ecx
  jmp    L9
  nopl   (%rax)
L24:
  cmp    %esi,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
L4:
  movsbl 0x2(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L36
L9:
  cmp    %edx,%eax
  jne    L24
  sub    $0x1,%ecx
  jne    L4
  lea    0x2(%rdi),%r8
L30:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *matchbalance(char *s, int b, int e) {
  if (*s != b)
    return NULL;
  else {
    int cont = 1;
    while (*(++s)) {
      if (*s == e) {
        if (--cont == 0)
          return s + 1;
      } else if (*s == b)
        cont++;
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<url_has_scheme>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L92
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L92
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L92
L16:
  mov    $0x0,%eax
  jmp    L38
L92:
  addq   $0x1,-0x8(%rbp)
  jmp    L46
L48:
  addq   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L48
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  sete   %al
  movzbl %al,%eax
L38:
  leave
  ret
```

assistant: ```c
int url_has_scheme(const char *url) {
  const char *p = url;
  if (!*p || !(isalnum(*p) || (*p) == '-' || (*p) == '+'))
    return 0;
  ++p;
  while (*p && (isalnum(*p) || (*p) == '-' || (*p) == '+'))
    ++p;
  return *p == ':';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<url_has_scheme>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  mov    $0x0,%eax
  test   %dil,%dil
  jne    L32
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L1
  movzbl 0x0(%rbp),%eax
  lea    -0x2b(%rax),%edx
  mov    $0x0,%eax
  test   $0xfd,%dl
  jne    L45
L1:
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%edi
  test   %dil,%dil
  jne    L81
  jmp    L28
L44:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L28
L81:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L44
  movzbl (%rbx),%eax
  sub    $0x2b,%eax
  test   $0xfd,%al
  je     L44
L28:
  cmpb   $0x3a,(%rbx)
  sete   %al
  movzbl %al,%eax
  jmp    L45
```

assistant: ```c
int url_has_scheme(const char *url) {
  const char *p = url;
  if (!*p || !(isalnum(*p) || (*p) == '-' || (*p) == '+'))
    return 0;
  ++p;
  while (*p && (isalnum(*p) || (*p) == '-' || (*p) == '+'))
    ++p;
  return *p == ':';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<url_has_scheme>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L63
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L63:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L68
  movzbl 0x0(%rbp),%eax
  sub    $0x2b,%eax
  test   $0xfd,%al
  jne    L5
L68:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  test   %dil,%dil
  je     L8
  nopw   0x0(%rax,%rax,1)
L64:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L61
  movzbl (%rbx),%edi
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L8
L61:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L64
L8:
  xor    %eax,%eax
  cmp    $0x3a,%dil
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int url_has_scheme(const char *url) {
  const char *p = url;
  if (!*p || !(isalnum(*p) || (*p) == '-' || (*p) == '+'))
    return 0;
  ++p;
  while (*p && (isalnum(*p) || (*p) == '-' || (*p) == '+'))
    ++p;
  return *p == ':';
}
```
user: What is the c source code of the assembly code below:

```asm
<url_has_scheme>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L19
L48:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L19:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L68
  movzbl 0x0(%rbp),%eax
  sub    $0x2b,%eax
  test   $0xfd,%al
  jne    L48
L68:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  test   %dil,%dil
  je     L14
  nopw   0x0(%rax,%rax,1)
L49:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L10
  movzbl (%rbx),%edi
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L14
L10:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L49
L14:
  xor    %eax,%eax
  cmp    $0x3a,%dil
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int url_has_scheme(const char *url) {
  const char *p = url;
  if (!*p || !(isalnum(*p) || (*p) == '-' || (*p) == '+'))
    return 0;
  ++p;
  while (*p && (isalnum(*p) || (*p) == '-' || (*p) == '+'))
    ++p;
  return *p == ':';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_an_allocation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *do_an_allocation() {
  int *a = malloc(sizeof(int));
  int *b = a;
  *a = 4;
  return b;
}
```