ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ioprint2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D12(%rip),%rdx
  cmp    (%rdx),%eax
  jne    L30
L73:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L66:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L72
L11:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L72
L37:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
L72:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L73
L30:
  cmp    $0x9,%eax
  je     L66
  cmp    $0x8,%eax
  je     L11
  cmp    $0x5c,%eax
  je     L37
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L72
```

assistant: ```c
int ioprint2() {
  int ch;
  ch = getchar();
  while (ch != EOF) {
    if (ch == '\t') {
      putchar('\\');
      putchar('t');
    } else if (ch == '\b') {
      putchar('\\');
      putchar('b');
    } else if (ch == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(ch);
    }
    ch = getchar();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ioprint2>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rbx
  cmp    (%rbx),%eax
  jne    L52
  jmp    L42
  nopl   0x0(%rax)
L69:
  mov    %eax,%edi
  call   <putchar@plt>
L40:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L42
L52:
  cmp    $0x9,%eax
  je     L66
  cmp    $0x8,%eax
  je     L4
  cmp    $0x5c,%eax
  jne    L69
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L52
L42:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L66:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L40
  xchg   %ax,%ax
L4:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L40
```

assistant: ```c
int ioprint2() {
  int ch;
  ch = getchar();
  while (ch != EOF) {
    if (ch == '\t') {
      putchar('\\');
      putchar('t');
    } else if (ch == '\b') {
      putchar('\\');
      putchar('b');
    } else if (ch == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(ch);
    }
    ch = getchar();
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ioprint2>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rbx
  cmp    (%rbx),%eax
  jne    L54
  jmp    L17
  nopl   0x0(%rax)
L36:
  mov    %eax,%edi
  call   <putchar@plt>
L30:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L17
L54:
  cmp    $0x9,%eax
  je     L64
  cmp    $0x8,%eax
  je     L60
  cmp    $0x5c,%eax
  jne    L36
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L54
L17:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L64:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L30
  xchg   %ax,%ax
L60:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L30
```

assistant: ```c
int ioprint2() {
  int ch;
  ch = getchar();
  while (ch != EOF) {
    if (ch == '\t') {
      putchar('\\');
      putchar('t');
    } else if (ch == '\b') {
      putchar('\\');
      putchar('b');
    } else if (ch == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(ch);
    }
    ch = getchar();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  foo(1, 1);
  foo(1, 2);
  foo(3, 2);
  foo(4, 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  foo(1, 1);
  foo(1, 2);
  foo(3, 2);
  foo(4, 4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  foo(1, 1);
  foo(1, 2);
  foo(3, 2);
  foo(4, 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  foo(1, 1);
  foo(1, 2);
  foo(3, 2);
  foo(4, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__dj_unimp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__libclog_printf@plt>
  mov    $0x1,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void __dj_unimp(const char *fn) {
  __libclog_printf(fn);
  _exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__dj_unimp>:
  endbr64
  sub    $0x8,%rsp
  call   <__libclog_printf@plt>
  mov    $0x1,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __dj_unimp(const char *fn) {
  __libclog_printf(fn);
  _exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__dj_unimp>:
  endbr64
  sub    $0x8,%rsp
  call   <__libclog_printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

assistant: ```c
void __dj_unimp(const char *fn) {
  __libclog_printf(fn);
  _exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__dj_unimp>:
  endbr64
  sub    $0x8,%rsp
  call   <__libclog_printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

assistant: ```c
void __dj_unimp(const char *fn) {
  __libclog_printf(fn);
  _exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L59
L81:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x20,%eax
  je     L44
  cmp    $0x20,%eax
  jg     L36
  cmp    $0x9,%eax
  je     L24
  cmp    $0xa,%eax
  je     L55
  jmp    L36
L44:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x53,%edi
  call   <fputc@plt>
  jmp    L36
L24:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x54,%edi
  call   <fputc@plt>
  jmp    L36
L55:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
L36:
  addq   $0x1,-0x10(%rbp)
L59:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L81
  nop
  nop
  leave
  ret
```

assistant: ```c
void filter(FILE *fp, const char *code) {
  for (; *code != '\0'; code++) {
    switch (*code) {
    case ' ':
      fputc('S', fp);
      break;
    case '\t':
      fputc('T', fp);
      break;
    case '\n':
      fputc('\n', fp);
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<filter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L37
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  mov    %rbp,%rsi
  mov    $0x53,%edi
  call   <fputc@plt>
L14:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L49
L37:
  cmp    $0xa,%al
  je     L15
  cmp    $0x20,%al
  je     L58
  cmp    $0x9,%al
  jne    L14
  mov    %rbp,%rsi
  mov    $0x54,%edi
  call   <fputc@plt>
  jmp    L14
L15:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L14
```

assistant: ```c
void filter(FILE *fp, const char *code) {
  for (; *code != '\0'; code++) {
    switch (*code) {
    case ' ':
      fputc('S', fp);
      break;
    case '\t':
      fputc('T', fp);
      break;
    case '\n':
      fputc('\n', fp);
      break;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<filter>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L78
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L71
  nopl   0x0(%rax)
L6:
  cmp    $0x9,%al
  je     L16
L46:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L12
L71:
  cmp    $0xa,%al
  je     L85
  cmp    $0x20,%al
  jne    L6
  mov    %rbp,%rsi
  mov    $0x53,%edi
  add    $0x1,%rbx
  call   <fputc@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L71
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L46
  nop
L16:
  mov    %rbp,%rsi
  mov    $0x54,%edi
  call   <fputc@plt>
  jmp    L46
  nop
L78:
  ret
```

assistant: ```c
void filter(FILE *fp, const char *code) {
  for (; *code != '\0'; code++) {
    switch (*code) {
    case ' ':
      fputc('S', fp);
      break;
    case '\t':
      fputc('T', fp);
      break;
    case '\n':
      fputc('\n', fp);
      break;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<filter>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L43
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L75
  nopl   0x0(%rax)
L10:
  cmp    $0x9,%al
  je     L84
L30:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L15
L75:
  cmp    $0xa,%al
  je     L52
  cmp    $0x20,%al
  jne    L10
  mov    %rbp,%rsi
  mov    $0x53,%edi
  add    $0x1,%rbx
  call   <fputc@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L75
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L30
  nop
L84:
  mov    %rbp,%rsi
  mov    $0x54,%edi
  call   <fputc@plt>
  jmp    L30
  nop
L43:
  ret
```

assistant: ```c
void filter(FILE *fp, const char *code) {
  for (; *code != '\0'; code++) {
    switch (*code) {
    case ' ':
      fputc('S', fp);
      break;
    case '\t':
      fputc('T', fp);
      break;
    case '\n':
      fputc('\n', fp);
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x24(%rbp)
  jmp    L87
L48:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D82(%rip),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <ran4@plt>
  movd   %xmm0,%eax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x20(%rbp,%rdx,4)
  addl   $0x1,-0x24(%rbp)
L87:
  cmpl   $0x4,-0x24(%rbp)
  jle    L48
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L9
L62:
  mov    -0x24(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L9:
  cmpl   $0x4,-0x24(%rbp)
  jle    L62
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L8
L71:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D31(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L8:
  cmpl   $0x4,-0x24(%rbp)
  jle    L71
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L46
L43:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D21(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L46:
  cmpl   $0x4,-0x24(%rbp)
  jle    L43
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D30
type_infered: string
name: read_data
arguments: data_tag: D61
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string
name: read_data
arguments: data_tag: D59
type_infered: string

tool: D12: ran4 gets values: 

tool: D30: %15.6f

tool: D61: 
    IEEE answers: 

tool: D11: %15s

tool: D59: 
     VAX answers: 

assistant: ```c
int main(void) {
  int i;
  static long idum[5] = {0, -1, 99, -99, 99};
  static char *ansvax[5] = {"", "0.275898", "0.208204", "0.034307", "0.838676"};
  static char *ansiee[5] = {"", "0.219120", "0.849246", "0.375290", "0.457334"};
  float random[5];
  for (i = 1; i <= 4; i++)
    random[i] = ran4(&idum[i]);
  printf("ran4 gets values: ");
  for (i = 1; i <= 4; i++)
    printf("%15.6f", random[i]);
  printf("\n    IEEE answers: ");
  for (i = 1; i <= 4; i++)
    printf("%15s", ansiee[i]);
  printf("\n     VAX answers: ");
  for (i = 1; i <= 4; i++)
    printf("%15s", ansvax[i]);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L13
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
L13:
  cmpl   $0x9,-0x4(%rbp)
  jbe    L4
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ft_putnbr_fd>
L4:
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    $0x30,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ft_putchar_fd@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbr_fd(const int nb, int fd) {
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  if (nb < 0)
    ft_putchar_fd('-', fd);
  if (n >= 10)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edi,%ebx
  neg    %ebx
  cmovs  %edi,%ebx
  test   %edi,%edi
  js     L29
L22:
  cmp    $0x9,%ebx
  ja     L33
L23:
  mov    %ebx,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  jmp    L22
L33:
  mov    %ebx,%edi
  mov    $0xcccccccd,%eax
  imul   %rax,%rdi
  shr    $0x23,%rdi
  mov    %ebp,%esi
  call   <ft_putnbr_fd>
  jmp    L23
```

assistant: ```c
void ft_putnbr_fd(const int nb, int fd) {
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  if (nb < 0)
    ft_putchar_fd('-', fd);
  if (n >= 10)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  cmovs  %edi,%ebx
  test   %edi,%edi
  js     L33
L60:
  mov    %ebx,%r13d
  cmp    $0x9,%ebx
  jg     L12
L11:
  mov    $0xcccccccd,%eax
  mov    %ebp,%esi
  imul   %r13,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <ft_putchar_fd@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xcccccccd,%r12d
  imul   %r13,%r12
  shr    $0x23,%r12
  cmp    $0x63,%ebx
  ja     L31
L17:
  mov    %r12d,%eax
  mov    $0xcccccccd,%edx
  mov    %ebp,%esi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  lea    0x30(%r12),%edi
  call   <ft_putchar_fd@plt>
  jmp    L11
  nopl   0x0(%rax)
L33:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  jmp    L60
  nop
L31:
  imul   $0x51eb851f,%r13,%r14
  shr    $0x25,%r14
  cmp    $0x3e7,%ebx
  ja     L61
L26:
  mov    %r14d,%eax
  mov    $0xcccccccd,%edx
  mov    %ebp,%esi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  lea    0x30(%r14),%edi
  call   <ft_putchar_fd@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L61:
  imul   $0x10624dd3,%r13,%rdi
  mov    %ebp,%esi
  shr    $0x26,%rdi
  call   <ft_putnbr_fd>
  jmp    L26
```

assistant: ```c
void ft_putnbr_fd(const int nb, int fd) {
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  if (nb < 0)
    ft_putchar_fd('-', fd);
  if (n >= 10)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  cmovs  %edi,%ebx
  test   %edi,%edi
  js     L76
L59:
  mov    %ebx,%r13d
  cmp    $0x9,%ebx
  jg     L8
L75:
  mov    $0xcccccccd,%eax
  mov    %ebp,%esi
  imul   %r13,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <ft_putchar_fd@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xcccccccd,%r12d
  imul   %r13,%r12
  shr    $0x23,%r12
  cmp    $0x63,%ebx
  ja     L6
L43:
  mov    %r12d,%eax
  mov    $0xcccccccd,%edx
  mov    %ebp,%esi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  lea    0x30(%r12),%edi
  call   <ft_putchar_fd@plt>
  jmp    L75
  nopl   0x0(%rax)
L76:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  jmp    L59
  nop
L6:
  imul   $0x51eb851f,%r13,%r14
  shr    $0x25,%r14
  cmp    $0x3e7,%ebx
  ja     L77
L7:
  mov    %r14d,%eax
  mov    $0xcccccccd,%edx
  mov    %ebp,%esi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  lea    0x30(%r14),%edi
  call   <ft_putchar_fd@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L77:
  imul   $0x10624dd3,%r13,%rdi
  mov    %ebp,%esi
  shr    $0x26,%rdi
  call   <ft_putnbr_fd>
  jmp    L7
```

assistant: ```c
void ft_putnbr_fd(const int nb, int fd) {
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  if (nb < 0)
    ft_putchar_fd('-', fd);
  if (n >= 10)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ailog_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L46
L50:
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L28:
  mov    -0x4(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
  jmp    L11
L12:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
L11:
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L28
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L50
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string
name: extract_symbolic_data
arguments: label: D36
type_infered: string
name: extract_symbolic_data
arguments: label: D31
type_infered: string

tool: D9: X

tool: D36: _

tool: D31: 


assistant: ```c
void ailog_matrix(char *campo, int alt, int larg) {
  int x, y;
  for (y = 0; y < alt; y++) {
    for (x = 0; x < larg; x++) {
      if (campo[(((y) * (larg)) + (x))])
        ailog("X");
      else
        ailog("_");
    }
    ailog("\n");
  }
  ailog("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ailog_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  test   %esi,%esi
  jle    L49
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  mov    %rax,0x18(%rsp)
  jmp    L16
L77:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
L15:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L79
L20:
  cmpb   $0x0,(%rbx)
  je     L77
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
  jmp    L15
L79:
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
  add    $0x1,%r14d
  add    0x8(%rsp),%r15d
  cmp    %r14d,0xc(%rsp)
  je     L49
L16:
  cmpl   $0x0,0x8(%rsp)
  jle    L79
  movslq %r15d,%rbp
  mov    0x10(%rsp),%rax
  lea    (%rax,%rbp,1),%rbx
  add    0x18(%rsp),%rbp
  lea    D13(%rip),%r13
  lea    D34(%rip),%r12
  jmp    L20
L49:
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <ailog@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D34
type_infered: string

tool: D0: 


tool: D13: _

tool: D34: X

assistant: ```c
void ailog_matrix(char *campo, int alt, int larg) {
  int x, y;
  for (y = 0; y < alt; y++) {
    for (x = 0; x < larg; x++) {
      if (campo[(((y) * (larg)) + (x))])
        ailog("X");
      else
        ailog("_");
    }
    ailog("\n");
  }
  ailog("\n");
}
```