ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<readline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    (%rdx),%r13d
  call   <fo_size@plt>
  cmp    %eax,%r13d
  jge    L111
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    (%rbx),%esi
  mov    %r12d,%edi
  call   <lseek@plt>
  mov    %rsp,%rsi
  mov    $0x400,%edx
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jle    L1
  mov    %rbp,%rdx
  mov    %rsp,%rsi
  mov    $0x0,%eax
L110:
  movzbl (%rsi),%ecx
  mov    %cl,(%rdx)
  cmp    $0xa,%cl
  je     L12
  add    $0x1,%eax
  add    $0x1,%rdx
  add    $0x1,%rsi
  cmp    %eax,%edi
  jne    L110
  movslq %edi,%rax
  lea    -0x1(%rbp,%rax,1),%rcx
  mov    %edi,%eax
  cmpb   $0xd,(%rcx)
  je     L26
L23:
  mov    $0x1,%edx
  cmp    %eax,%edi
  jne    L68
  mov    $0x0,%edx
  jmp    L72
L12:
  movb   $0x0,(%rdx)
L58:
  movslq %eax,%rdx
  lea    -0x1(%rbp,%rdx,1),%rcx
  cmpb   $0xd,(%rcx)
  jne    L23
  cmp    %eax,%edi
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%edx
L72:
  sub    $0x1,%eax
  movb   $0x0,(%rcx)
L68:
  add    %eax,%edx
  add    %edx,(%rbx)
L33:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    $0x0,%eax
  jmp    L58
L26:
  mov    %edi,%eax
  mov    $0x0,%edx
  jmp    L72
L111:
  mov    $0xffffffff,%eax
  jmp    L33
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readline(int fd, char *buffer, int *position) {
  char tmp[1024];
  int i, ret;
  int split;
  if (*position >= fo_size(fd))
    return -1;
  lseek(fd, *position, SEEK_SET);
  ret = read(fd, tmp, 1024);
  for (i = 0; i < ret; i++) {
    buffer[i] = tmp[i];
    if (buffer[i] == '\n') {
      buffer[i] = 0;
      break;
    }
  }
  split = buffer[i - 1] == '\r' ? 2 : 1;
  if (i == ret)
    split = 0;
  if (i == ret || buffer[i - 1] == '\r') {
    i--;
    buffer[i] = 0;
  }
  *position += i + split;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readline>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x418,%rsp
  mov    (%rdx),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fo_size@plt>
  cmp    %eax,%ebp
  jge    L108
  mov    D7(%rip),%rax
  mov    (%r12),%esi
  mov    %r13d,%edi
  mov    %rsp,%rbp
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  jle    L53
  movslq %eax,%rdi
  xor    %edx,%edx
  jmp    L112
  cs nopw 0x0(%rax,%rax,1)
L1:
  lea    0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L73
L112:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %edx,%eax
  lea    (%rbx,%rdx,1),%rsi
  mov    %cl,(%rbx,%rdx,1)
  cmp    $0xa,%cl
  jne    L1
  movb   $0x0,(%rsi)
  sub    $0x1,%rdx
L86:
  add    %rdx,%rbx
  cmpb   $0xd,(%rbx)
  je     L31
L120:
  mov    $0x1,%edx
  cmp    %eax,%r8d
  je     L93
L92:
  add    %eax,%edx
  add    %edx,(%r12)
L65:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L73:
  movslq %eax,%rdx
  sub    $0x1,%rdx
  add    %rdx,%rbx
  cmpb   $0xd,(%rbx)
  jne    L120
L31:
  xor    %edx,%edx
  cmp    %eax,%r8d
  setne  %dl
  add    %edx,%edx
L54:
  movb   $0x0,(%rbx)
  sub    $0x1,%eax
  jmp    L92
  nopl   0x0(%rax)
L93:
  xor    %edx,%edx
  jmp    L54
L53:
  mov    $0xffffffffffffffff,%rdx
  xor    %eax,%eax
  jmp    L86
L108:
  mov    $0xffffffff,%eax
  jmp    L65
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readline(int fd, char *buffer, int *position) {
  char tmp[1024];
  int i, ret;
  int split;
  if (*position >= fo_size(fd))
    return -1;
  lseek(fd, *position, SEEK_SET);
  ret = read(fd, tmp, 1024);
  for (i = 0; i < ret; i++) {
    buffer[i] = tmp[i];
    if (buffer[i] == '\n') {
      buffer[i] = 0;
      break;
    }
  }
  split = buffer[i - 1] == '\r' ? 2 : 1;
  if (i == ret)
    split = 0;
  if (i == ret || buffer[i - 1] == '\r') {
    i--;
    buffer[i] = 0;
  }
  *position += i + split;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readline>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x418,%rsp
  mov    (%rdx),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fo_size@plt>
  cmp    %eax,%ebp
  jge    L0
  mov    D6(%rip),%rax
  mov    (%r12),%esi
  mov    %r13d,%edi
  mov    %rsp,%rbp
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  jle    L20
  movslq %eax,%rdi
  xor    %edx,%edx
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L94:
  lea    0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L67
L3:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %edx,%eax
  lea    (%rbx,%rdx,1),%rsi
  mov    %cl,(%rbx,%rdx,1)
  cmp    $0xa,%cl
  jne    L94
  movb   $0x0,(%rsi)
  sub    $0x1,%rdx
L125:
  add    %rdx,%rbx
  cmpb   $0xd,(%rbx)
  je     L50
L59:
  mov    $0x1,%edx
  cmp    %eax,%r8d
  je     L23
L16:
  add    %eax,%edx
  add    %edx,(%r12)
L121:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L67:
  movslq %eax,%rdx
  sub    $0x1,%rdx
  add    %rdx,%rbx
  cmpb   $0xd,(%rbx)
  jne    L59
L50:
  xor    %edx,%edx
  cmp    %eax,%r8d
  setne  %dl
  add    %edx,%edx
L25:
  movb   $0x0,(%rbx)
  sub    $0x1,%eax
  jmp    L16
  nopl   0x0(%rax)
L23:
  xor    %edx,%edx
  jmp    L25
L20:
  mov    $0xffffffffffffffff,%rdx
  xor    %eax,%eax
  jmp    L125
L0:
  mov    $0xffffffff,%eax
  jmp    L121
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readline(int fd, char *buffer, int *position) {
  char tmp[1024];
  int i, ret;
  int split;
  if (*position >= fo_size(fd))
    return -1;
  lseek(fd, *position, SEEK_SET);
  ret = read(fd, tmp, 1024);
  for (i = 0; i < ret; i++) {
    buffer[i] = tmp[i];
    if (buffer[i] == '\n') {
      buffer[i] = 0;
      break;
    }
  }
  split = buffer[i - 1] == '\r' ? 2 : 1;
  if (i == ret)
    split = 0;
  if (i == ret || buffer[i - 1] == '\r') {
    i--;
    buffer[i] = 0;
  }
  *position += i + split;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x63,-0x4(%rbp)
  jle    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_func2(int dev_a[100]) {
  int i;
#pragma acc parallel loop deviceptr(dev_a)
  for (i = 0; i < 100; i++) {
    dev_a[i] = i * 3;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_func2>:
  endbr64
  mov    $0x0,%eax
L3:
  mov    %eax,(%rdi)
  add    $0x3,%eax
  add    $0x4,%rdi
  cmp    $0x12c,%eax
  jne    L3
  ret
```

assistant: ```c
void test_func2(int dev_a[100]) {
  int i;
#pragma acc parallel loop deviceptr(dev_a)
  for (i = 0; i < 100; i++) {
    dev_a[i] = i * 3;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_func2>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %eax,(%rdi)
  add    $0x3,%eax
  add    $0x4,%rdi
  cmp    $0x12c,%eax
  jne    L6
  ret
```

assistant: ```c
void test_func2(int dev_a[100]) {
  int i;
#pragma acc parallel loop deviceptr(dev_a)
  for (i = 0; i < 100; i++) {
    dev_a[i] = i * 3;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_func2>:
  endbr64
  movdqa D4(%rip),%xmm1
  movdqa D16(%rip),%xmm3
  lea    0x190(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L0:
  movdqa %xmm1,%xmm2
  add    $0x10,%rdi
  paddd  %xmm3,%xmm1
  movdqa %xmm2,%xmm0
  pslld  $0x1,%xmm0
  paddd  %xmm2,%xmm0
  movups %xmm0,-0x10(%rdi)
  cmp    %rdi,%rax
  jne    L0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: byte[16]
name: unpack_data
arguments: tag: D16
type_infered: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D16": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void test_func2(int dev_a[100]) {
  int i;
#pragma acc parallel loop deviceptr(dev_a)
  for (i = 0; i < 100; i++) {
    dev_a[i] = i * 3;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stricmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L37
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L37
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  jmp    L49
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
L49:
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L29
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L29
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  jmp    L56
L29:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
L56:
  mov    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  cmpb   $0x0,-0x2(%rbp)
  je     L21
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L27
L21:
  movsbl -0x2(%rbp),%eax
  movsbl -0x1(%rbp),%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  char f, l;
  do {
    f = ((*s1 <= 'Z') && (*s1 >= 'A')) ? *s1 + 'a' - 'A' : *s1;
    l = ((*s2 <= 'Z') && (*s2 >= 'A')) ? *s2 + 'a' - 'A' : *s2;
    s1++;
    s2++;
  } while ((f) && (f == l));
  return (int)(f - l);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stricmp>:
  endbr64
  mov    $0x0,%ecx
L1:
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x41(%rax),%r8d
  lea    0x20(%rax),%edx
  cmp    $0x1a,%r8b
  cmovb  %edx,%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x41(%rdx),%r9d
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  add    $0x1,%rcx
  test   %al,%al
  je     L12
  cmp    %dl,%al
  je     L1
L12:
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  char f, l;
  do {
    f = ((*s1 <= 'Z') && (*s1 >= 'A')) ? *s1 + 'a' - 'A' : *s1;
    l = ((*s2 <= 'Z') && (*s2 >= 'A')) ? *s2 + 'a' - 'A' : *s2;
    s1++;
    s2++;
  } while ((f) && (f == l));
  return (int)(f - l);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stricmp>:
  endbr64
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x41(%rax),%r8d
  lea    0x20(%rax),%edx
  cmp    $0x1a,%r8b
  cmovb  %edx,%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x41(%rdx),%r9d
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  add    $0x1,%rcx
  test   %al,%al
  je     L12
  cmp    %dl,%al
  je     L5
L12:
  movsbl %dl,%edx
  movsbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  char f, l;
  do {
    f = ((*s1 <= 'Z') && (*s1 >= 'A')) ? *s1 + 'a' - 'A' : *s1;
    l = ((*s2 <= 'Z') && (*s2 >= 'A')) ? *s2 + 'a' - 'A' : *s2;
    s1++;
    s2++;
  } while ((f) && (f == l));
  return (int)(f - l);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stricmp>:
  endbr64
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x41(%rax),%r8d
  lea    0x20(%rax),%edx
  cmp    $0x1a,%r8b
  cmovb  %edx,%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x41(%rdx),%r9d
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  add    $0x1,%rcx
  test   %al,%al
  je     L9
  cmp    %al,%dl
  je     L7
L9:
  movsbl %dl,%edx
  movsbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  char f, l;
  do {
    f = ((*s1 <= 'Z') && (*s1 >= 'A')) ? *s1 + 'a' - 'A' : *s1;
    l = ((*s2 <= 'Z') && (*s2 >= 'A')) ? *s2 + 'a' - 'A' : *s2;
    s1++;
    s2++;
  } while ((f) && (f == l));
  return (int)(f - l);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init_test@plt>
  test   %rax,%rax
  je     L10
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L10:
  mov    $0x0,%eax
  call   <measure_clocks@plt>
  test   %rax,%rax
  je     L6
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L6:
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D11: init_test

tool: D5: measure_clocks

assistant: ```c
int main(void) {
  if (init_test() != 0) {
    printf("init_test");
    return -1;
  }
  if (measure_clocks() != 0) {
    printf("measure_clocks");
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_test@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
  call   <measure_clocks@plt>
  test   %rax,%rax
  jne    L12
  mov    $0x0,%eax
L19:
  add    $0x8,%rsp
  ret
L16:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L12:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
```

tool_calls: name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D6: init_test

tool: D16: measure_clocks

assistant: ```c
int main(void) {
  if (init_test() != 0) {
    printf("init_test");
    return -1;
  }
  if (measure_clocks() != 0) {
    printf("measure_clocks");
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_test@plt>
  test   %rax,%rax
  jne    L30
  xor    %eax,%eax
  call   <measure_clocks@plt>
  test   %rax,%rax
  jne    L31
  xor    %eax,%eax
L25:
  add    $0x8,%rsp
  ret
L30:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L25
L31:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D9
datatype: string

tool: D6: init_test

tool: D9: measure_clocks

assistant: ```c
int main(void) {
  if (init_test() != 0) {
    printf("init_test");
    return -1;
  }
  if (measure_clocks() != 0) {
    printf("measure_clocks");
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_test@plt>
  test   %rax,%rax
  jne    L22
  xor    %eax,%eax
  call   <measure_clocks@plt>
  test   %rax,%rax
  jne    L2
  xor    %eax,%eax
L1:
  add    $0x8,%rsp
  ret
L22:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L1
L2:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L1
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D2: init_test

tool: D9: measure_clocks

assistant: ```c
int main(void) {
  if (init_test() != 0) {
    printf("init_test");
    return -1;
  }
  if (measure_clocks() != 0) {
    printf("measure_clocks");
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum_ints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L17:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L17
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_ints(int *integers, size_t count) {
  size_t i;
  int s = 0;
  for (i = 0; i < count; i++)
    s += integers[i];
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_ints>:
  endbr64
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    $0x0,%edx
L3:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L3
L28:
  mov    %edx,%eax
  ret
L15:
  mov    $0x0,%edx
  jmp    L28
```

assistant: ```c
int sum_ints(int *integers, size_t count) {
  size_t i;
  int s = 0;
  for (i = 0; i < count; i++)
    s += integers[i];
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum_ints>:
  endbr64
  test   %rsi,%rsi
  je     L13
  lea    (%rdi,%rsi,4),%rdx
  xor    %eax,%eax
  nop
L12:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L12
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum_ints(int *integers, size_t count) {
  size_t i;
  int s = 0;
  for (i = 0; i < count; i++)
    s += integers[i];
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum_ints>:
  endbr64
  test   %rsi,%rsi
  je     L50
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L15
  mov    %rsi,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
L30:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L30
  movdqa %xmm0,%xmm1
  mov    %rsi,%rdx
  psrldq $0x8,%xmm1
  and    $0xfffffffffffffffc,%rdx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L6
L7:
  lea    0x1(%rdx),%r8
  lea    0x0(,%rdx,4),%rcx
  add    (%rdi,%rdx,4),%eax
  cmp    %r8,%rsi
  jbe    L69
  add    $0x2,%rdx
  add    0x4(%rdi,%rcx,1),%eax
  cmp    %rdx,%rsi
  jbe    L69
  add    0x8(%rdi,%rcx,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
L69:
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
L15:
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L7
```

assistant: ```c
int sum_ints(int *integers, size_t count) {
  size_t i;
  int s = 0;
  for (i = 0; i < count; i++)
    s += integers[i];
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<inl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int inl(short port) {
  int res;
  __asm__("inl %%dx,%%eax" : "=a"(res) : "d"(port));
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inl>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%eax
  ret
```

assistant: ```c
int inl(short port) {
  int res;
  __asm__("inl %%dx,%%eax" : "=a"(res) : "d"(port));
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inl>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%eax
  ret
```

assistant: ```c
int inl(short port) {
  int res;
  __asm__("inl %%dx,%%eax" : "=a"(res) : "d"(port));
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inl>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%eax
  ret
```

assistant: ```c
int inl(short port) {
  int res;
  __asm__("inl %%dx,%%eax" : "=a"(res) : "d"(port));
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x40,-0x24(%rbp)
  jle    L6
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L3
L6:
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
L3:
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int n, int c, int s) {
  int a2, a3, a4, x1, x2, x3, x4;
  x1 = c + s;
  x2 = x3 = x4 = c;
  if (n > 64) {
    a2 = 2 * s;
    x2 = c + a2;
    a3 = 3 * s;
    x3 = c + a3;
  } else {
    a4 = 2 * s;
    x4 = c + a4;
  }
  return x1 + x2 + x3 + x4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  lea    (%rsi,%rdx,1),%ecx
  cmp    $0x40,%edi
  jle    L13
  lea    (%rdx,%rcx,1),%eax
  lea    (%rdx,%rax,1),%edi
L14:
  add    %ecx,%eax
  add    %edi,%eax
  add    %esi,%eax
  ret
L13:
  mov    %esi,%edi
  mov    %esi,%eax
  lea    (%rdx,%rcx,1),%esi
  jmp    L14
```

assistant: ```c
int f(int n, int c, int s) {
  int a2, a3, a4, x1, x2, x3, x4;
  x1 = c + s;
  x2 = x3 = x4 = c;
  if (n > 64) {
    a2 = 2 * s;
    x2 = c + a2;
    a3 = 3 * s;
    x3 = c + a3;
  } else {
    a4 = 2 * s;
    x4 = c + a4;
  }
  return x1 + x2 + x3 + x4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  mov    %edi,%r8d
  lea    (%rsi,%rdx,1),%eax
  mov    %esi,%edi
  lea    (%rdx,%rax,1),%ecx
  cmp    $0x40,%r8d
  jle    L4
  lea    (%rdx,%rcx,1),%edi
  mov    %esi,%edx
  mov    %ecx,%esi
  mov    %edx,%ecx
L4:
  add    %esi,%eax
  add    %edi,%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int f(int n, int c, int s) {
  int a2, a3, a4, x1, x2, x3, x4;
  x1 = c + s;
  x2 = x3 = x4 = c;
  if (n > 64) {
    a2 = 2 * s;
    x2 = c + a2;
    a3 = 3 * s;
    x3 = c + a3;
  } else {
    a4 = 2 * s;
    x4 = c + a4;
  }
  return x1 + x2 + x3 + x4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    %edi,%r8d
  lea    (%rsi,%rdx,1),%eax
  mov    %esi,%edi
  lea    (%rdx,%rax,1),%ecx
  cmp    $0x40,%r8d
  jle    L4
  lea    (%rdx,%rcx,1),%edi
  mov    %esi,%edx
  mov    %ecx,%esi
  mov    %edx,%ecx
L4:
  add    %esi,%eax
  add    %edi,%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int f(int n, int c, int s) {
  int a2, a3, a4, x1, x2, x3, x4;
  x1 = c + s;
  x2 = x3 = x4 = c;
  if (n > 64) {
    a2 = 2 * s;
    x2 = c + a2;
    a3 = 3 * s;
    x3 = c + a3;
  } else {
    a4 = 2 * s;
    x4 = c + a4;
  }
  return x1 + x2 + x3 + x4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int int_pow(int x, int y) {
  int num = (int)pow(x, y);
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<int_pow>:
  endbr64
  sub    $0x8,%rsp
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int int_pow(int x, int y) {
  int num = (int)pow(x, y);
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_pow>:
  endbr64
  sub    $0x8,%rsp
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int int_pow(int x, int y) {
  int num = (int)pow(x, y);
  return num;
}
```