ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<modify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L33
L67:
  mov    -0x8(%rbp),%rax
  movb   $0x40,(%rax)
  movl   $0x1,-0xc(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  mov    $0x31,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L67
  jmp    L29
L75:
  mov    -0x8(%rbp),%rax
  movb   $0x25,(%rax)
  movl   $0x1,-0xc(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  mov    $0x30,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L75
  jmp    L11
L70:
  mov    -0x8(%rbp),%rax
  movb   $0x4c,(%rax)
  movl   $0x1,-0xc(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  mov    $0x6c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L70
  jmp    L58
L17:
  mov    -0x8(%rbp),%rax
  movb   $0x6f,(%rax)
  movl   $0x1,-0xc(%rbp)
L58:
  mov    -0x18(%rbp),%rax
  mov    $0x4f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int modify(char *str) {
  int ret = 0;
  char *pos = NULL;
  while ((pos = strchr(str, '1')) != NULL) {
    *pos = '@';
    ret = 1;
  }
  while ((pos = strchr(str, '0')) != NULL) {
    *pos = '%';
    ret = 1;
  }
  while ((pos = strchr(str, 'l')) != NULL) {
    *pos = 'L';
    ret = 1;
  }
  while ((pos = strchr(str, 'O')) != NULL) {
    *pos = 'o';
    ret = 1;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<modify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  mov    $0x1,%r12d
  jmp    L19
L72:
  movb   $0x40,(%rax)
  mov    %r12d,%ebp
L19:
  mov    $0x31,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L72
  mov    $0x1,%r12d
  jmp    L62
L40:
  movb   $0x25,(%rax)
  mov    %r12d,%ebp
L62:
  mov    $0x30,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L40
  mov    $0x1,%r12d
  jmp    L20
L61:
  movb   $0x4c,(%rax)
  mov    %r12d,%ebp
L20:
  mov    $0x6c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L61
  mov    $0x1,%r12d
  jmp    L30
L4:
  movb   $0x6f,(%rax)
  mov    %r12d,%ebp
L30:
  mov    $0x4f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int modify(char *str) {
  int ret = 0;
  char *pos = NULL;
  while ((pos = strchr(str, '1')) != NULL) {
    *pos = '@';
    ret = 1;
  }
  while ((pos = strchr(str, '0')) != NULL) {
    *pos = '%';
    ret = 1;
  }
  while ((pos = strchr(str, 'l')) != NULL) {
    *pos = 'L';
    ret = 1;
  }
  while ((pos = strchr(str, 'O')) != NULL) {
    *pos = 'o';
    ret = 1;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modify>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L27:
  movb   $0x40,(%rax)
  mov    $0x1,%r12d
L75:
  mov    $0x31,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L27
  jmp    L1
  nopl   (%rax)
L3:
  movb   $0x25,(%rax)
  mov    $0x1,%r12d
L1:
  mov    $0x30,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L3
  jmp    L7
  nopl   (%rax)
L43:
  movb   $0x4c,(%rax)
  mov    $0x1,%r12d
L7:
  mov    $0x6c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L43
  jmp    L13
  nopl   (%rax)
L34:
  movb   $0x6f,(%rax)
  mov    $0x1,%r12d
L13:
  mov    $0x4f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L34
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int modify(char *str) {
  int ret = 0;
  char *pos = NULL;
  while ((pos = strchr(str, '1')) != NULL) {
    *pos = '@';
    ret = 1;
  }
  while ((pos = strchr(str, '0')) != NULL) {
    *pos = '%';
    ret = 1;
  }
  while ((pos = strchr(str, 'l')) != NULL) {
    *pos = 'L';
    ret = 1;
  }
  while ((pos = strchr(str, 'O')) != NULL) {
    *pos = 'o';
    ret = 1;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<modify>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L27:
  movb   $0x40,(%rax)
  mov    $0x1,%r12d
L59:
  mov    $0x31,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L27
  jmp    L47
  nopl   (%rax)
L24:
  movb   $0x25,(%rax)
  mov    $0x1,%r12d
L47:
  mov    $0x30,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L24
  jmp    L9
  nopl   (%rax)
L74:
  movb   $0x4c,(%rax)
  mov    $0x1,%r12d
L9:
  mov    $0x6c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L74
  jmp    L17
  nopl   (%rax)
L0:
  movb   $0x6f,(%rax)
  mov    $0x1,%r12d
L17:
  mov    $0x4f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int modify(char *str) {
  int ret = 0;
  char *pos = NULL;
  while ((pos = strchr(str, '1')) != NULL) {
    *pos = '@';
    ret = 1;
  }
  while ((pos = strchr(str, '0')) != NULL) {
    *pos = '%';
    ret = 1;
  }
  while ((pos = strchr(str, 'l')) != NULL) {
    *pos = 'L';
    ret = 1;
  }
  while ((pos = strchr(str, 'O')) != NULL) {
    *pos = 'o';
    ret = 1;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _stat(uint8_t *file, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_stat>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _stat(uint8_t *file, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_stat>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int _stat(uint8_t *file, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_stat>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int _stat(uint8_t *file, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<u_get_first_byte_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x80,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int u_get_first_byte_mask(unsigned int len) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len < 2)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len > 4)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return (0x80 >> len) - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<u_get_first_byte_mask>:
  endbr64
  mov    $0x80,%eax
  mov    %edi,%ecx
  sar    %cl,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
unsigned int u_get_first_byte_mask(unsigned int len) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len < 2)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len > 4)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return (0x80 >> len) - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<u_get_first_byte_mask>:
  endbr64
  mov    %edi,%ecx
  mov    $0x80,%eax
  sar    %cl,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
unsigned int u_get_first_byte_mask(unsigned int len) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len < 2)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len > 4)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return (0x80 >> len) - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<u_get_first_byte_mask>:
  endbr64
  mov    %edi,%ecx
  mov    $0x80,%eax
  sar    %cl,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
unsigned int u_get_first_byte_mask(unsigned int len) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len < 2)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((len > 4)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return (0x80 >> len) - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L17
  mov    $0xffffffff,%eax
  jmp    L33
L17:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jge    L27
  mov    $0x1,%eax
  jmp    L33
L27:
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int sortcmp(const void *e1, const void *e2) {
  uint64_t c1, c2;
  c1 = **((uint64_t **)e1);
  c2 = **((uint64_t **)e2);
  if (c1 > c2) {
    return (-1);
  } else if (c1 < c2) {
    return (1);
  } else {
    return (0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sortcmp>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%rcx
  mov    (%rsi),%rax
  mov    (%rax),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jg     L0
  setl   %al
  movzbl %al,%eax
L0:
  ret
```

assistant: ```c
int sortcmp(const void *e1, const void *e2) {
  uint64_t c1, c2;
  c1 = **((uint64_t **)e1);
  c2 = **((uint64_t **)e2);
  if (c1 > c2) {
    return (-1);
  } else if (c1 < c2) {
    return (1);
  } else {
    return (0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortcmp>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rsi),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int sortcmp(const void *e1, const void *e2) {
  uint64_t c1, c2;
  c1 = **((uint64_t **)e1);
  c2 = **((uint64_t **)e2);
  if (c1 > c2) {
    return (-1);
  } else if (c1 < c2) {
    return (1);
  } else {
    return (0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sortcmp>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rsi),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int sortcmp(const void *e1, const void *e2) {
  uint64_t c1, c2;
  c1 = **((uint64_t **)e1);
  c2 = **((uint64_t **)e2);
  if (c1 > c2) {
    return (-1);
  } else if (c1 < c2) {
    return (1);
  } else {
    return (0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x4,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  subl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: y = %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int y, *p, x;
  y = 0;
  p = &y;
  x = *p;
  x = 4;
  (*p)++;
  x--;
  (*p) += x;
  printf("y = %d\n", y);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: y = %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int y, *p, x;
  y = 0;
  p = &y;
  x = *p;
  x = 4;
  (*p)++;
  x--;
  (*p) += x;
  printf("y = %d\n", y);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: y = %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int y, *p, x;
  y = 0;
  p = &y;
  x = *p;
  x = 4;
  (*p)++;
  x--;
  (*p) += x;
  printf("y = %d\n", y);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: y = %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int y, *p, x;
  y = 0;
  p = &y;
  x = *p;
  x = 4;
  (*p)++;
  x--;
  (*p) += x;
  printf("y = %d\n", y);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L8:
  mov    $0x0,%eax
  call   <popc@plt>
  cmp    $0xa,%al
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flush() {
  while (popc() != '\n')
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<flush>:
  endbr64
  sub    $0x8,%rsp
L1:
  mov    $0x0,%eax
  call   <popc@plt>
  cmp    $0xa,%al
  jne    L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void flush() {
  while (popc() != '\n')
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<flush>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <popc@plt>
  cmp    $0xa,%al
  jne    L5
  add    $0x8,%rsp
  ret
```

assistant: ```c
void flush() {
  while (popc() != '\n')
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<flush>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <popc@plt>
  cmp    $0xa,%al
  jne    L2
  add    $0x8,%rsp
  ret
```

assistant: ```c
void flush() {
  while (popc() != '\n')
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%r8
  test   %r8,%r8
  je     L41
  mov    %rsp,%rax
  mov    $0x0,%edx
L20:
  mov    (%rsp),%rdi
  cmp    %rdx,%rdi
  jbe    L9
  mov    %edi,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rdi
  mov    %rdi,(%rax)
L34:
  add    $0x2,%rdx
  add    $0x10,%rax
  cmp    %r8,%rdx
  jb     L20
L41:
  mov    (%rsp),%rax
  and    $0x205b028,%eax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  ret
L9:
  movzwl (%rax),%ecx
  movzwl 0x4(%rax),%edi
  mov    %di,(%rax)
  mov    %cx,0x4(%rax)
  jmp    L34
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy12;
  unsigned short copy13;
  unsigned short copy14;
  unsigned short copy15;
  unsigned short copy16;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & 7UL) | 1UL);
        } else {
          copy12 = *((char *)(&state[local1]) + 7);
          *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = copy12;
          copy13 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = copy13;
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy14;
        copy14 = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy14;
        copy15 = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy15;
      } else {
        state[local1] |= state[0UL];
        copy16 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy16;
        copy16 = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy16;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 536195496UL) & 34582586UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  test   %rdi,%rdi
  je     L1
  xor    %edx,%edx
L24:
  cmp    %rdx,%rax
  jbe    L25
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
L25:
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  jb     L24
L1:
  and    $0x205b028,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy12;
  unsigned short copy13;
  unsigned short copy14;
  unsigned short copy15;
  unsigned short copy16;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & 7UL) | 1UL);
        } else {
          copy12 = *((char *)(&state[local1]) + 7);
          *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = copy12;
          copy13 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = copy13;
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy14;
        copy14 = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy14;
        copy15 = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy15;
      } else {
        state[local1] |= state[0UL];
        copy16 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy16;
        copy16 = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy16;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 536195496UL) & 34582586UL;
  }
}
```