ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<matrix_mul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %ecx,0x3c(%rsp)
  mov    %r8d,(%rsp)
  mov    %r9d,0x4(%rsp)
  test   %ecx,%ecx
  jle    L25
  lea    -0x1(%r8),%eax
  movl   $0x0,0x14(%rsp)
  lea    0x1(%rdi,%rax,1),%rax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x38(%rsp)
  mov    %rax,0x30(%rsp)
  nopl   0x0(%rax)
L15:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L31
  sub    $0x1,%eax
  xor    %r13d,%r13d
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L36:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L24
  mov    0x14(%rsp),%eax
  movslq 0x10(%rsp),%rbp
  movslq 0x4(%rsp),%r12
  lea    (%rax,%r13,1),%ebx
  mov    0x20(%rsp),%rax
  movslq %ebx,%rbx
  add    0x28(%rsp),%rbx
  lea    (%rax,%r13,1),%r15
  mov    0x18(%rsp),%rax
  lea    (%rax,%rbp,1),%r14
  add    0x30(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L59:
  movzbl (%r15),%esi
  movzbl (%r14),%edi
  add    $0x1,%r14
  add    %r12,%r15
  call   <gf_mul@plt>
  movzbl (%rbx),%edi
  mov    %eax,%esi
  call   <gf_add@plt>
  mov    %al,(%rbx)
  cmp    %rbp,%r14
  jne    L59
L24:
  lea    0x1(%r13),%rax
  cmp    0x8(%rsp),%r13
  je     L31
  mov    %rax,%r13
  jmp    L36
  nopl   (%rax)
L31:
  mov    (%rsp),%edx
  addl   $0x1,0x38(%rsp)
  add    %edx,0x10(%rsp)
  mov    0x38(%rsp),%eax
  mov    0x4(%rsp),%edx
  add    %edx,0x14(%rsp)
  cmp    %eax,0x3c(%rsp)
  jne    L15
L25:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrix_mul(unsigned char *A, unsigned char *B, unsigned char *C, int n, int p, int m) {
  int i;
  int j;
  int k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      for (k = 0; k < p; k++) {
        C[i * m + j] = gf_add(C[i * m + j], gf_mul(A[i * p + k], B[k * m + j]));
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrix_mul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x20(%rsp)
  mov    %ecx,0x2c(%rsp)
  mov    %r8d,0x30(%rsp)
  mov    %r9d,0x34(%rsp)
  test   %ecx,%ecx
  jle    L43
  test   %r9d,%r9d
  jle    L43
  test   %r8d,%r8d
  jle    L43
  lea    -0x1(%r8),%eax
  movl   $0x0,0x28(%rsp)
  movslq %r9d,%rbp
  lea    0x1(%rdi,%rax,1),%rax
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x18(%rsp)
  mov    %rax,0x38(%rsp)
  nopw   0x0(%rax,%rax,1)
L57:
  movslq 0x28(%rsp),%rax
  mov    0x38(%rsp),%r12
  xor    %r13d,%r13d
  movslq 0x1c(%rsp),%rbx
  add    0x20(%rsp),%rbx
  mov    %rax,(%rsp)
  add    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%r14
  add    (%rsp),%r14
  lea    (%rax,%r13,1),%r15
  nopw   0x0(%rax,%rax,1)
L55:
  movzbl (%r15),%esi
  movzbl (%r14),%edi
  add    $0x1,%r14
  add    %rbp,%r15
  call   <gf_mul@plt>
  movzbl (%rbx),%edi
  mov    %eax,%esi
  call   <gf_add@plt>
  mov    %al,(%rbx)
  cmp    %r14,%r12
  jne    L55
  add    $0x1,%r13
  add    $0x1,%rbx
  cmp    %r13,%rbp
  jne    L36
  addl   $0x1,0x18(%rsp)
  mov    0x34(%rsp),%ecx
  mov    0x30(%rsp),%edx
  add    %ecx,0x1c(%rsp)
  add    %edx,0x28(%rsp)
  mov    0x18(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jne    L57
L43:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrix_mul(unsigned char *A, unsigned char *B, unsigned char *C, int n, int p, int m) {
  int i;
  int j;
  int k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      for (k = 0; k < p; k++) {
        C[i * m + j] = gf_add(C[i * m + j], gf_mul(A[i * p + k], B[k * m + j]));
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rdx
  add    $0x8,%rdx
  lea    -0x2c(%rbp),%rax
  add    $0x4,%rax
  lea    -0x2c(%rbp),%rsi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L27
L42:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x14(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  lea    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x3c(%rbp)
L27:
  cmpl   $0x2,-0x3c(%rbp)
  jle    L42
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <three_sort@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <three_sort@plt>
  movl   $0x0,-0x38(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L31
L3:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  setge  %al
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  setge  %al
  movzbl %al,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  setge  %al
  movzbl %al,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  setge  %al
  movzbl %al,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  setge  %al
  movzbl %al,%eax
  sub    %eax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  setge  %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x2c(%rbp,%rax,4),%eax
  imul   -0x30(%rbp),%eax
  add    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L3
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D27
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D22: %d %d %d

tool: D27: %d %d

tool: D5: %d


assistant: ```c
int main() {
  int prices[3];
  scanf("%d %d %d", prices, prices + 1, prices + 2);
  int min[3], max[3];
  for (int i = 0; i < 3; i++)
    scanf("%d %d", min + i, max + i);
  three_sort(min);
  three_sort(max);
  int sum = 0;
  for (int i = min[0]; i <= max[2]; i++) {
    int amount = (i >= min[0]) + (i >= min[1]) + (i >= min[2]) - (i >= max[0]) - (i >= max[1]) - (i >= max[2]);
    sum += prices[amount - 1] * amount;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  lea    0x1c(%rsp),%rbp
  mov    %rbp,%r13
  lea    D14(%rip),%r12
L1:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %r13,%rbx
  jne    L1
  lea    0x10(%rsp),%rdi
  call   <three_sort@plt>
  lea    0x1c(%rsp),%rdi
  call   <three_sort@plt>
  mov    0x10(%rsp),%ecx
  mov    0x24(%rsp),%edi
  cmp    %edi,%ecx
  jg     L15
  mov    0x14(%rsp),%ebx
  mov    0x18(%rsp),%r11d
  mov    0x1c(%rsp),%r10d
  mov    0x20(%rsp),%r9d
  lea    0x1(%rdi),%r8d
  mov    %ecx,%edx
  mov    $0x0,%esi
L26:
  cmp    %edx,%ecx
  setle  %al
  movzbl %al,%eax
  cmp    %edx,%ebx
  setle  %bpl
  movzbl %bpl,%ebp
  add    %ebp,%eax
  cmp    %edx,%r11d
  setle  %bpl
  movzbl %bpl,%ebp
  add    %ebp,%eax
  cmp    %edx,%r10d
  setle  %bpl
  movzbl %bpl,%ebp
  sub    %ebp,%eax
  cmp    %edx,%r9d
  setle  %bpl
  movzbl %bpl,%ebp
  sub    %ebp,%eax
  cmp    %edx,%edi
  setle  %bpl
  movzbl %bpl,%ebp
  sub    %ebp,%eax
  lea    -0x1(%rax),%ebp
  movslq %ebp,%rbp
  imul   0x4(%rsp,%rbp,4),%eax
  add    %eax,%esi
  add    $0x1,%edx
  cmp    %r8d,%edx
  jne    L26
L24:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x0,%esi
  jmp    L24
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D27
datatype: string

tool: D7: %d %d %d

tool: D14: %d %d

tool: D27: %d


assistant: ```c
int main() {
  int prices[3];
  scanf("%d %d %d", prices, prices + 1, prices + 2);
  int min[3], max[3];
  for (int i = 0; i < 3; i++)
    scanf("%d %d", min + i, max + i);
  three_sort(min);
  three_sort(max);
  int sum = 0;
  for (int i = min[0]; i <= max[2]; i++) {
    int amount = (i >= min[0]) + (i >= min[1]) + (i >= min[2]) - (i >= max[0]) - (i >= max[1]) - (i >= max[2]);
    sum += prices[amount - 1] * amount;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rbp,%r15
  mov    %rbp,%r13
  lea    0x10(%rsp),%r14
  mov    %r14,%rbx
  call   <scanf@plt>
L23:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %rbx,%r13
  jne    L23
  mov    %r14,%rdi
  call   <three_sort@plt>
  mov    %r15,%rdi
  call   <three_sort@plt>
  mov    0x10(%rsp),%edx
  mov    0x24(%rsp),%edi
  cmp    %edx,%edi
  jl     L27
  mov    0x14(%rsp),%ebx
  mov    0x18(%rsp),%r11d
  lea    0x1(%rdi),%r8d
  xor    %esi,%esi
  mov    0x1c(%rsp),%r10d
  mov    0x20(%rsp),%r9d
  nopl   (%rax)
L35:
  xor    %ecx,%ecx
  cmp    %edx,%ebx
  setle  %cl
  xor    %eax,%eax
  cmp    %edx,%r11d
  setle  %al
  lea    0x1(%rcx,%rax,1),%eax
  xor    %ecx,%ecx
  cmp    %edx,%r10d
  setle  %cl
  sub    %ecx,%eax
  xor    %ecx,%ecx
  cmp    %edx,%r9d
  setle  %cl
  sub    %ecx,%eax
  xor    %ecx,%ecx
  cmp    %edx,%edi
  setle  %cl
  add    $0x1,%edx
  sub    %ecx,%eax
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  imul   0x4(%rsp,%rcx,4),%eax
  add    %eax,%esi
  cmp    %r8d,%edx
  jne    L35
L30:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  xor    %esi,%esi
  jmp    L30
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D9: %d %d %d

tool: D7: %d %d

tool: D3: %d


assistant: ```c
int main() {
  int prices[3];
  scanf("%d %d %d", prices, prices + 1, prices + 2);
  int min[3], max[3];
  for (int i = 0; i < 3; i++)
    scanf("%d %d", min + i, max + i);
  three_sort(min);
  three_sort(max);
  int sum = 0;
  for (int i = min[0]; i <= max[2]; i++) {
    int amount = (i >= min[0]) + (i >= min[1]) + (i >= min[2]) - (i >= max[0]) - (i >= max[1]) - (i >= max[2]);
    sum += prices[amount - 1] * amount;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D1(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rbp,%r15
  mov    %rbp,%r13
  lea    0x10(%rsp),%r14
  mov    %r14,%rbx
  call   <scanf@plt>
L18:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %rbx,%r13
  jne    L18
  mov    %r14,%rdi
  call   <three_sort@plt>
  mov    %r15,%rdi
  call   <three_sort@plt>
  mov    0x10(%rsp),%edx
  mov    0x24(%rsp),%edi
  cmp    %edx,%edi
  jl     L24
  mov    0x14(%rsp),%ebx
  mov    0x18(%rsp),%r11d
  lea    0x1(%rdi),%r8d
  xor    %esi,%esi
  mov    0x1c(%rsp),%r10d
  mov    0x20(%rsp),%r9d
  nopl   (%rax)
L13:
  xor    %ecx,%ecx
  cmp    %edx,%ebx
  setle  %cl
  xor    %eax,%eax
  cmp    %edx,%r11d
  setle  %al
  lea    0x1(%rcx,%rax,1),%eax
  xor    %ecx,%ecx
  cmp    %edx,%r10d
  setle  %cl
  sub    %ecx,%eax
  xor    %ecx,%ecx
  cmp    %edx,%r9d
  setle  %cl
  sub    %ecx,%eax
  xor    %ecx,%ecx
  cmp    %edx,%edi
  setle  %cl
  add    $0x1,%edx
  sub    %ecx,%eax
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  imul   0x4(%rsp,%rcx,4),%eax
  add    %eax,%esi
  cmp    %r8d,%edx
  jne    L13
L27:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  xor    %esi,%esi
  jmp    L27
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D1: %d %d %d

tool: D20: %d %d

tool: D6: %d


assistant: ```c
int main() {
  int prices[3];
  scanf("%d %d %d", prices, prices + 1, prices + 2);
  int min[3], max[3];
  for (int i = 0; i < 3; i++)
    scanf("%d %d", min + i, max + i);
  three_sort(min);
  three_sort(max);
  int sum = 0;
  for (int i = min[0]; i <= max[2]; i++) {
    int amount = (i >= min[0]) + (i >= min[1]) + (i >= min[2]) - (i >= max[0]) - (i >= max[1]) - (i >= max[2]);
    sum += prices[amount - 1] * amount;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<stk_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xf,-0x4(%rbp)
  jmp    L0
L1:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stk_line@plt>
  subl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: 


assistant: ```c
void stk_dump(int *stk) {
  int i;
  for (i = 15; i >= 0; i--)
    stk_line(stk, i);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<stk_dump>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0xf,%ebx
L3:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <stk_line@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L3
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: 


assistant: ```c
void stk_dump(int *stk) {
  int i;
  for (i = 15; i >= 0; i--)
    stk_line(stk, i);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stk_dump>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <stk_line@plt>
  sub    $0x1,%ebx
  jae    L7
  add    $0x8,%rsp
  lea    D5(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: 


assistant: ```c
void stk_dump(int *stk) {
  int i;
  for (i = 15; i >= 0; i--)
    stk_line(stk, i);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stk_dump>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <stk_line@plt>
  sub    $0x1,%ebx
  jae    L9
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: 


assistant: ```c
void stk_dump(int *stk) {
  int i;
  for (i = 15; i >= 0; i--)
    stk_line(stk, i);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rot13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x0,-0xe4(%rbp)
  jmp    L10
L72:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  cmp    $0x4d,%al
  jle    L85
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  cmp    $0x6d,%al
  jg     L52
L85:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  add    $0xd,%eax
  mov    %eax,%edx
  mov    -0xe4(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  jmp    L45
L52:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  cmp    $0x4d,%al
  jg     L11
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  cmp    $0x6d,%al
  jle    L80
L11:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  sub    $0xd,%eax
  mov    %eax,%edx
  mov    -0xe4(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  jmp    L45
L80:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%edx
  mov    -0xe4(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
L45:
  addl   $0x1,-0xe4(%rbp)
L10:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L72
  mov    -0xe4(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D2
type: string

tool: D12: %s

tool: D2: %s


assistant: ```c
void rot13() {
  int br;
  char message[100], NewMessage[100];
  scanf("%s", message);
  getchar();
  for (br = 0; message[br] != '\0'; br++) {
    if (message[br] - 'A' <= 12 || message[br] - 'a' <= 12) {
      NewMessage[br] = message[br] + 13;
    } else {
      if (message[br] - 'A' > 12 || message[br] - 'a' > 12) {
        NewMessage[br] = message[br] - 13;
      } else {
        NewMessage[br] = message[br];
      }
    }
  }
  NewMessage[br] = '\0';
  printf("%s\n", NewMessage);
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rot13>:
  endbr64
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L31
  mov    $0x1,%edx
  lea    0x6f(%rsp),%r8
  lea    -0x1(%rsp),%rdi
L20:
  lea    0xd(%rax),%esi
  lea    -0xd(%rax),%ecx
  cmp    $0x6d,%al
  mov    %esi,%eax
  cmovg  %ecx,%eax
  mov    %al,(%r8,%rdx,1)
  mov    %edx,%ecx
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L20
L1:
  movslq %ecx,%rcx
  movb   $0x0,0x70(%rsp,%rcx,1)
  lea    0x70(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xe8,%rsp
  ret
L31:
  mov    $0x0,%ecx
  jmp    L1
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string

tool: D11: %s

tool: D17: %s


assistant: ```c
void rot13() {
  int br;
  char message[100], NewMessage[100];
  scanf("%s", message);
  getchar();
  for (br = 0; message[br] != '\0'; br++) {
    if (message[br] - 'A' <= 12 || message[br] - 'a' <= 12) {
      NewMessage[br] = message[br] + 13;
    } else {
      if (message[br] - 'A' > 12 || message[br] - 'a' > 12) {
        NewMessage[br] = message[br] - 13;
      } else {
        NewMessage[br] = message[br];
      }
    }
  }
  NewMessage[br] = '\0';
  printf("%s\n", NewMessage);
  getchar();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rot13>:
  endbr64
  sub    $0xe8,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L7
  mov    $0x1,%edx
  lea    0x6f(%rsp),%r8
  lea    -0x1(%rsp),%rdi
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0xd(%rax),%esi
  lea    -0xd(%rax),%ecx
  cmp    $0x6d,%al
  mov    %esi,%eax
  cmovg  %ecx,%eax
  movslq %edx,%rcx
  mov    %al,(%r8,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L21
L26:
  lea    0x70(%rsp),%rsi
  lea    D16(%rip),%rdi
  movb   $0x0,0x70(%rsp,%rcx,1)
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xe8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %ecx,%ecx
  jmp    L26
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D7: %s

tool: D16: %s


assistant: ```c
void rot13() {
  int br;
  char message[100], NewMessage[100];
  scanf("%s", message);
  getchar();
  for (br = 0; message[br] != '\0'; br++) {
    if (message[br] - 'A' <= 12 || message[br] - 'a' <= 12) {
      NewMessage[br] = message[br] + 13;
    } else {
      if (message[br] - 'A' > 12 || message[br] - 'a' > 12) {
        NewMessage[br] = message[br] - 13;
      } else {
        NewMessage[br] = message[br];
      }
    }
  }
  NewMessage[br] = '\0';
  printf("%s\n", NewMessage);
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rot13>:
  endbr64
  sub    $0xe8,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L45
  mov    $0x1,%edx
  lea    0x6f(%rsp),%rdi
  lea    -0x1(%rsp),%rsi
  jmp    L2
  nopl   (%rax)
L59:
  add    $0xd,%eax
L41:
  mov    %al,(%rdi,%rdx,1)
  movslq %edx,%rcx
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%eax
  test   %al,%al
  je     L55
L2:
  cmp    $0x6d,%al
  jle    L59
  sub    $0xd,%eax
  jmp    L41
  xchg   %ax,%ax
L45:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L55:
  lea    0x70(%rsp),%rsi
  lea    D10(%rip),%rdi
  movb   $0x0,0x70(%rsp,%rcx,1)
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0xe8,%rsp
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D10
datatype: string

tool: D9: %s

tool: D10: %s


assistant: ```c
void rot13() {
  int br;
  char message[100], NewMessage[100];
  scanf("%s", message);
  getchar();
  for (br = 0; message[br] != '\0'; br++) {
    if (message[br] - 'A' <= 12 || message[br] - 'a' <= 12) {
      NewMessage[br] = message[br] + 13;
    } else {
      if (message[br] - 'A' > 12 || message[br] - 'a' > 12) {
        NewMessage[br] = message[br] - 13;
      } else {
        NewMessage[br] = message[br];
      }
    }
  }
  NewMessage[br] = '\0';
  printf("%s\n", NewMessage);
  getchar();
}
```