ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<audioFrameEnd>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <apuGetBuf@plt>
  mov    %rax,%r14
  cmp    $0x200,%r13d
  jle    L12
  lea    -0x201(%r13),%r12d
  mov    %rax,%rbx
  shr    $0x9,%r12d
  mov    %r12d,%r15d
  add    $0x1,%r15
  mov    %r15,%rbp
  shl    $0xc,%rbp
  add    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  mov    $0x200,%esi
  add    $0x1000,%rbx
  call   <audio_batch_cb@plt>
  cmp    %rbp,%rbx
  jne    L11
  neg    %r12d
  shl    $0xc,%r15
  shl    $0x9,%r12d
  add    %r15,%r14
  lea    -0x200(%r13,%r12,1),%r13d
L27:
  add    $0x8,%rsp
  mov    %r13d,%esi
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <audio_batch_cb@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  test   %r13d,%r13d
  jne    L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void audioFrameEnd(int samples) {
  uint16_t *buffer_in = (uint16_t *)apuGetBuf();
  while (samples > 512) {
    audio_batch_cb(buffer_in, 512);
    buffer_in += 1024;
    samples -= 512;
  }
  if (samples)
    audio_batch_cb(buffer_in, samples);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_uint24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_uint24(unsigned char *buf, int block, int value) {
  buf[block * 3 + 0] = (value & 0xff0000) >> 16;
  buf[block * 3 + 1] = (value & 0x00ff00) >> 8;
  buf[block * 3 + 2] = value & 0x0000ff;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_uint24>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  cltq
  mov    %edx,%ecx
  sar    $0x10,%ecx
  mov    %cl,(%rdi,%rax,1)
  movzbl %dh,%ecx
  mov    %cl,0x1(%rdi,%rax,1)
  mov    %dl,0x2(%rdi,%rax,1)
  ret
```

assistant: ```c
void set_uint24(unsigned char *buf, int block, int value) {
  buf[block * 3 + 0] = (value & 0xff0000) >> 16;
  buf[block * 3 + 1] = (value & 0x00ff00) >> 8;
  buf[block * 3 + 2] = value & 0x0000ff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_uint24>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  mov    %edx,%ecx
  cltq
  sar    $0x10,%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dh,0x1(%rdi,%rax,1)
  mov    %dl,0x2(%rdi,%rax,1)
  ret
```

assistant: ```c
void set_uint24(unsigned char *buf, int block, int value) {
  buf[block * 3 + 0] = (value & 0xff0000) >> 16;
  buf[block * 3 + 1] = (value & 0x00ff00) >> 8;
  buf[block * 3 + 2] = value & 0x0000ff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_uint24>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  mov    %edx,%ecx
  cltq
  sar    $0x10,%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dh,0x1(%rdi,%rax,1)
  mov    %dl,0x2(%rdi,%rax,1)
  ret
```

assistant: ```c
void set_uint24(unsigned char *buf, int block, int value) {
  buf[block * 3 + 0] = (value & 0xff0000) >> 16;
  buf[block * 3 + 1] = (value & 0x00ff00) >> 8;
  buf[block * 3 + 2] = value & 0x0000ff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uds_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L11
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L4
L11:
  mov    -0x4(%rbp),%eax
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: read failed

assistant: ```c
int uds_read(int connection_fd, char *out, int size) {
  int nbytes;
  nbytes = read(connection_fd, out, size);
  if (nbytes < 0) {
    perror("read failed");
    return -1;
  }
  return nbytes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uds_read>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  test   %eax,%eax
  js     L7
L12:
  add    $0x8,%rsp
  ret
L7:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L12
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: read failed

assistant: ```c
int uds_read(int connection_fd, char *out, int size) {
  int nbytes;
  nbytes = read(connection_fd, out, size);
  if (nbytes < 0) {
    perror("read failed");
    return -1;
  }
  return nbytes;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uds_read>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  test   %eax,%eax
  js     L15
L8:
  add    $0x8,%rsp
  ret
L15:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L8
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: read failed

assistant: ```c
int uds_read(int connection_fd, char *out, int size) {
  int nbytes;
  nbytes = read(connection_fd, out, size);
  if (nbytes < 0) {
    perror("read failed");
    return -1;
  }
  return nbytes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uds_read>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  test   %eax,%eax
  js     L16
L11:
  add    $0x8,%rsp
  ret
L16:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: read failed

assistant: ```c
int uds_read(int connection_fd, char *out, int size) {
  int nbytes;
  nbytes = read(connection_fd, out, size);
  if (nbytes < 0) {
    perror("read failed");
    return -1;
  }
  return nbytes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<assaltolecito>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x1b4e81b5,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x96,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  imul   $0x1b4e81b5,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x4,%ecx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  imul   $0x96,%ecx,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x1b4e81b5,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x1b4e81b5,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  jg     L11
  mov    $0x1,%eax
  jmp    L1
L11:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int assaltolecito(int PosT, int PosC) {
  int x = PosT % 150 - PosC % 150;
  int y = PosT / 150 - PosC / 150;
  if (x * x + y * y <= 1)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<assaltolecito>:
  endbr64
  movslq %edi,%rax
  imul   $0x1b4e81b5,%rax,%rax
  sar    $0x24,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x96,%eax,%edx
  sub    %edx,%edi
  movslq %esi,%rdx
  imul   $0x1b4e81b5,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  mov    %edx,%r8d
  sub    %ecx,%r8d
  imul   $0x96,%r8d,%r8d
  sub    %r8d,%esi
  sub    %esi,%edi
  sub    %edx,%ecx
  add    %ecx,%eax
  imul   %edi,%edi
  imul   %eax,%eax
  add    %eax,%edi
  cmp    $0x1,%edi
  setle  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int assaltolecito(int PosT, int PosC) {
  int x = PosT % 150 - PosC % 150;
  int y = PosT / 150 - PosC / 150;
  if (x * x + y * y <= 1)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<assaltolecito>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %esi,%ecx
  imul   $0x1b4e81b5,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %edx,%eax
  imul   $0x96,%eax,%edx
  sub    %edx,%edi
  movslq %esi,%rdx
  imul   $0x1b4e81b5,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %edx,%r8d
  sub    %ecx,%r8d
  sub    %edx,%ecx
  imul   $0x96,%r8d,%r8d
  add    %ecx,%eax
  imul   %eax,%eax
  sub    %r8d,%esi
  sub    %esi,%edi
  imul   %edi,%edi
  add    %eax,%edi
  xor    %eax,%eax
  cmp    $0x1,%edi
  setle  %al
  ret
```

assistant: ```c
int assaltolecito(int PosT, int PosC) {
  int x = PosT % 150 - PosC % 150;
  int y = PosT / 150 - PosC / 150;
  if (x * x + y * y <= 1)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<assaltolecito>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %esi,%ecx
  imul   $0x1b4e81b5,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %edx,%eax
  imul   $0x96,%eax,%edx
  sub    %edx,%edi
  movslq %esi,%rdx
  imul   $0x1b4e81b5,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %edx,%r8d
  sub    %ecx,%r8d
  sub    %edx,%ecx
  imul   $0x96,%r8d,%r8d
  add    %ecx,%eax
  imul   %eax,%eax
  sub    %r8d,%esi
  sub    %esi,%edi
  imul   %edi,%edi
  add    %eax,%edi
  xor    %eax,%eax
  cmp    $0x1,%edi
  setle  %al
  ret
```

assistant: ```c
int assaltolecito(int PosT, int PosC) {
  int x = PosT % 150 - PosC % 150;
  int y = PosT / 150 - PosC / 150;
  if (x * x + y * y <= 1)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<win>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl 0x1(%rax),%eax
  cmp    %al,%dl
  jne    L108
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl 0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movzbl 0x2(%rax),%eax
  cmp    %al,%dl
  jne    L108
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl 0x1(%rax),%eax
  cmp    $0x5f,%al
  je     L108
  mov    $0x1,%eax
  jmp    L130
L108:
  mov    -0x28(%rbp),%rax
  movzbl 0x2(%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl 0x1(%rax),%eax
  cmp    %al,%dl
  jne    L167
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl 0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L167
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L167
  mov    $0x1,%eax
  jmp    L130
L167:
  movl   $0x0,-0x10(%rbp)
  jmp    L145
L31:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %al,-0x11(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L134
L116:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    %al,-0x12(%rbp)
  je     L180
  movl   $0x0,-0x8(%rbp)
L180:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    %al,-0x11(%rbp)
  je     L35
  movl   $0x0,-0x4(%rbp)
L35:
  addl   $0x1,-0xc(%rbp)
L134:
  cmpl   $0x2,-0xc(%rbp)
  jle    L116
  cmpl   $0x0,-0x8(%rbp)
  je     L24
  cmpb   $0x5f,-0x12(%rbp)
  jne    L102
L24:
  cmpl   $0x0,-0x4(%rbp)
  je     L20
  cmpb   $0x5f,-0x11(%rbp)
  je     L20
L102:
  mov    $0x1,%eax
  jmp    L130
L20:
  addl   $0x1,-0x10(%rbp)
L145:
  cmpl   $0x2,-0x10(%rbp)
  jle    L31
  mov    $0x0,%eax
L130:
  pop    %rbp
  ret
```

assistant: ```c
int win(char mat[3][4]) {
  int i, j;
  if (mat[0][0] == mat[1][1] && mat[1][1] == mat[2][2] && mat[1][1] != '_')
    return 1;
  if (mat[0][2] == mat[1][1] && mat[1][1] == mat[2][0] && mat[2][0] != '_')
    return 1;
  for (i = 0; i < 3; ++i) {
    char prow = mat[i][0];
    char pcol = mat[0][i];
    int flag_prow = 1;
    int flag_pcol = 1;
    for (j = 0; j < 3; ++j) {
      if (mat[i][j] != prow) {
        flag_prow = 0;
      }
      if (mat[j][i] != pcol) {
        flag_pcol = 0;
      }
    }
    if ((flag_prow && prow != '_') || (flag_pcol && pcol != '_'))
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<win>:
  endbr64
  movzbl 0x5(%rdi),%edx
  cmp    %dl,(%rdi)
  je     L75
L7:
  mov    $0x0,%eax
  cmp    0x2(%rdi),%dl
  je     L90
L35:
  mov    $0x0,%r9d
  jmp    L64
L75:
  cmp    %dl,0xa(%rdi)
  jne    L7
  mov    $0x1,%eax
  cmp    $0x5f,%dl
  je     L7
L79:
  ret
L90:
  movzbl 0x8(%rdi),%ecx
  cmp    $0x5f,%cl
  je     L111
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L79
L111:
  mov    $0x0,%eax
  jmp    L35
L27:
  test   %edx,%edx
  je     L11
  cmp    $0x5f,%cl
  jne    L10
L11:
  test   %r8d,%r8d
  je     L152
  cmp    $0x5f,%sil
  jne    L81
L152:
  add    $0x1,%rax
  cmp    $0x3,%rax
  je     L5
L64:
  movzbl (%rdi,%rax,4),%ecx
  movzbl (%rdi,%rax,1),%esi
  cmp    %cl,0x1(%rdi,%rax,4)
  sete   %dl
  movzbl %dl,%edx
  cmp    %sil,0x4(%rdi,%rax,1)
  sete   %r8b
  movzbl %r8b,%r8d
  cmp    0x2(%rdi,%rax,4),%cl
  cmovne %r9d,%edx
  cmp    %sil,0x8(%rdi,%rax,1)
  je     L27
  test   %edx,%edx
  je     L152
  cmp    $0x5f,%cl
  je     L152
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
L81:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int win(char mat[3][4]) {
  int i, j;
  if (mat[0][0] == mat[1][1] && mat[1][1] == mat[2][2] && mat[1][1] != '_')
    return 1;
  if (mat[0][2] == mat[1][1] && mat[1][1] == mat[2][0] && mat[2][0] != '_')
    return 1;
  for (i = 0; i < 3; ++i) {
    char prow = mat[i][0];
    char pcol = mat[0][i];
    int flag_prow = 1;
    int flag_pcol = 1;
    for (j = 0; j < 3; ++j) {
      if (mat[i][j] != prow) {
        flag_prow = 0;
      }
      if (mat[j][i] != pcol) {
        flag_pcol = 0;
      }
    }
    if ((flag_prow && prow != '_') || (flag_pcol && pcol != '_'))
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<win>:
  endbr64
  movzbl (%rdi),%edx
  movzbl 0x5(%rdi),%ecx
  cmp    %cl,%dl
  je     L28
L17:
  mov    %edx,%esi
  xor    %eax,%eax
  cmp    0x2(%rdi),%cl
  je     L39
L115:
  xor    %r8d,%r8d
L145:
  xor    %ecx,%ecx
  cmp    %dl,0x1(%rdi,%rax,4)
  sete   %cl
  cmp    %sil,0x4(%rdi,%rax,1)
  sete   %r9b
  cmp    0x2(%rdi,%rax,4),%dl
  cmovne %r8d,%ecx
  cmp    0x8(%rdi,%rax,1),%sil
  je     L105
  cmp    $0x5f,%dl
  je     L136
  test   %ecx,%ecx
  jne    L107
L136:
  add    $0x1,%rax
  cmp    $0x3,%rax
  je     L66
  movzbl (%rdi,%rax,4),%edx
  movzbl (%rdi,%rax,1),%esi
  jmp    L145
  nopl   (%rax)
L105:
  cmp    $0x5f,%dl
  je     L21
  test   %ecx,%ecx
  jne    L107
L21:
  cmp    $0x5f,%sil
  je     L136
  test   %r9b,%r9b
  je     L136
L107:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  cmp    %dl,0xa(%rdi)
  jne    L17
  mov    $0x1,%eax
  cmp    $0x5f,%dl
  je     L17
L1:
  ret
  nopl   0x0(%rax)
L39:
  movzbl 0x8(%rdi),%esi
  cmp    %sil,%cl
  jne    L106
  mov    $0x1,%eax
  cmp    $0x5f,%sil
  jne    L1
L106:
  mov    %edx,%esi
  xor    %eax,%eax
  jmp    L115
```

assistant: ```c
int win(char mat[3][4]) {
  int i, j;
  if (mat[0][0] == mat[1][1] && mat[1][1] == mat[2][2] && mat[1][1] != '_')
    return 1;
  if (mat[0][2] == mat[1][1] && mat[1][1] == mat[2][0] && mat[2][0] != '_')
    return 1;
  for (i = 0; i < 3; ++i) {
    char prow = mat[i][0];
    char pcol = mat[0][i];
    int flag_prow = 1;
    int flag_pcol = 1;
    for (j = 0; j < 3; ++j) {
      if (mat[i][j] != prow) {
        flag_prow = 0;
      }
      if (mat[j][i] != pcol) {
        flag_pcol = 0;
      }
    }
    if ((flag_prow && prow != '_') || (flag_pcol && pcol != '_'))
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<win>:
  endbr64
  movzbl (%rdi),%edx
  movzbl 0x5(%rdi),%ecx
  mov    %rdi,%rax
  cmp    %cl,%dl
  je     L118
L303:
  movzbl 0x2(%rax),%edi
  cmp    %dil,%cl
  je     L68
L215:
  cmp    %dil,%dl
  je     L168
  cmp    0x8(%rax),%dl
  je     L241
L263:
  movzbl 0x4(%rax),%edx
  movzbl 0x6(%rax),%r9d
  movzbl 0x1(%rax),%esi
  cmp    %r9b,%dl
  je     L134
  cmp    0x9(%rax),%sil
  je     L200
L59:
  movzbl 0xa(%rax),%edx
  cmp    0x8(%rax),%dl
  je     L34
L33:
  xor    %r8d,%r8d
  cmp    %dl,%dil
  je     L116
L55:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L168:
  cmp    %dl,0x1(%rax)
  sete   %sil
  cmp    $0x5f,%dl
  setne  %r8b
  and    %r8d,%esi
  cmp    0x8(%rax),%dl
  jne    L152
  test   %sil,%sil
  jne    L199
L241:
  cmp    %dl,0x4(%rax)
  jne    L263
  cmp    $0x5f,%dl
  je     L263
L199:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L134:
  cmp    $0x5f,%dl
  setne  %r8b
  cmp    %dl,%cl
  sete   %dl
  and    %edx,%r8d
  cmp    0x9(%rax),%sil
  jne    L298
  test   %r8b,%r8b
  jne    L199
L200:
  cmp    $0x5f,%sil
  je     L59
  cmp    %sil,%cl
  je     L199
  movzbl 0xa(%rax),%edx
  cmp    0x8(%rax),%dl
  jne    L33
  nopw   0x0(%rax,%rax,1)
L34:
  cmp    %dl,0x9(%rax)
  sete   %al
  cmp    $0x5f,%dl
  setne  %cl
  and    %ecx,%eax
  mov    %eax,%r8d
  and    $0x1,%r8d
  cmp    %dl,%dil
  jne    L55
  test   %al,%al
  jne    L199
L116:
  cmp    $0x5f,%dil
  je     L64
  cmp    %r9b,%dil
  je     L199
L64:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L118:
  cmp    %dl,0xa(%rdi)
  jne    L303
  mov    $0x1,%r8d
  cmp    $0x5f,%dl
  jne    L55
  movzbl 0x2(%rax),%edi
  cmp    %dil,%cl
  jne    L215
  nopl   (%rax)
L68:
  movzbl 0x8(%rax),%esi
  cmp    $0x5f,%sil
  je     L215
  mov    $0x1,%r8d
  cmp    %sil,%cl
  jne    L215
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L152:
  test   %sil,%sil
  je     L263
  jmp    L199
  xchg   %ax,%ax
L298:
  test   %r8b,%r8b
  je     L59
  jmp    L199
```

assistant: ```c
int win(char mat[3][4]) {
  int i, j;
  if (mat[0][0] == mat[1][1] && mat[1][1] == mat[2][2] && mat[1][1] != '_')
    return 1;
  if (mat[0][2] == mat[1][1] && mat[1][1] == mat[2][0] && mat[2][0] != '_')
    return 1;
  for (i = 0; i < 3; ++i) {
    char prow = mat[i][0];
    char pcol = mat[0][i];
    int flag_prow = 1;
    int flag_pcol = 1;
    for (j = 0; j < 3; ++j) {
      if (mat[i][j] != prow) {
        flag_prow = 0;
      }
      if (mat[j][i] != pcol) {
        flag_pcol = 0;
      }
    }
    if ((flag_prow && prow != '_') || (flag_pcol && pcol != '_'))
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pass@plt>
  jmp    L5
L0:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fail@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <diag@plt>
L5:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: got %d but expected %d

assistant: ```c
void is(int got, int expected, const char *description) {
  if (got == expected)
    pass(description);
  else {
    fail(description);
    diag("got %d but expected %d", got, expected);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rdx,%rdi
  cmp    %esi,%ebx
  je     L4
  mov    %esi,%ebp
  call   <fail@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <diag@plt>
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <pass@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: got %d but expected %d

assistant: ```c
void is(int got, int expected, const char *description) {
  if (got == expected)
    pass(description);
  else {
    fail(description);
    diag("got %d but expected %d", got, expected);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  cmp    %esi,%ebp
  je     L9
  mov    %esi,%r12d
  call   <fail@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <diag@plt>
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <pass@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: got %d but expected %d

assistant: ```c
void is(int got, int expected, const char *description) {
  if (got == expected)
    pass(description);
  else {
    fail(description);
    diag("got %d but expected %d", got, expected);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  cmp    %esi,%ebp
  je     L0
  mov    %esi,%r12d
  call   <fail@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <diag@plt>
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <pass@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: got %d but expected %d

assistant: ```c
void is(int got, int expected, const char *description) {
  if (got == expected)
    pass(description);
  else {
    fail(description);
    diag("got %d but expected %d", got, expected);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<makedev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: >>> makedev, maj - %d, min - %d


assistant: ```c
dev_t makedev(int maj, int min) {
  printf(">>> makedev, maj - %d, min - %d\n", maj, min);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<makedev>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string

tool: D6: >>> makedev, maj - %d, min - %d


assistant: ```c
dev_t makedev(int maj, int min) {
  printf(">>> makedev, maj - %d, min - %d\n", maj, min);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<makedev>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: >>> makedev, maj - %d, min - %d


assistant: ```c
dev_t makedev(int maj, int min) {
  printf(">>> makedev, maj - %d, min - %d\n", maj, min);
  return -1;
}
```