ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_str_to_buffer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
L4:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L9
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    $0x0,%esi
  call   <update_buffer@plt>
  test   %rax,%rax
  jne    L4
L9:
  pop    %rbx
  ret
```

assistant: ```c
char *copy_str_to_buffer(char *str) {
  char *new_str = NULL;
  while (*str != '\0') {
    new_str = update_buffer(*str++, false);
    if (new_str == NULL)
      return NULL;
  }
  return new_str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_str_to_buffer>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  jmp    L12
  nopl   0x0(%rax)
L1:
  xor    %esi,%esi
  add    $0x1,%rbx
  call   <update_buffer@plt>
  test   %rax,%rax
  je     L9
L12:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
L9:
  pop    %rbx
  ret
```

assistant: ```c
char *copy_str_to_buffer(char *str) {
  char *new_str = NULL;
  while (*str != '\0') {
    new_str = update_buffer(*str++, false);
    if (new_str == NULL)
      return NULL;
  }
  return new_str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_str_to_buffer>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  jmp    L14
  nopl   0x0(%rax)
L24:
  xor    %esi,%esi
  add    $0x1,%rbx
  call   <update_buffer@plt>
  test   %rax,%rax
  je     L18
L14:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L24
L18:
  pop    %rbx
  ret
```

assistant: ```c
char *copy_str_to_buffer(char *str) {
  char *new_str = NULL;
  while (*str != '\0') {
    new_str = update_buffer(*str++, false);
    if (new_str == NULL)
      return NULL;
  }
  return new_str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vectors_subtraction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vectors_subtraction(int n, double *vector1, double *vector2, double *result) {
  int i;
  for (i = 0; i < n; i++) {
    result[i] = vector1[i] - vector2[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vectors_subtraction>:
  endbr64
  test   %edi,%edi
  jle    L14
  mov    %edi,%edi
  mov    $0x0,%eax
L0:
  movsd  (%rsi,%rax,8),%xmm0
  subsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L0
L14:
  ret
```

assistant: ```c
void vectors_subtraction(int n, double *vector1, double *vector2, double *result) {
  int i;
  for (i = 0; i < n; i++) {
    result[i] = vector1[i] - vector2[i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vectors_subtraction>:
  endbr64
  test   %edi,%edi
  jle    L1
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L8:
  movsd  (%rsi,%rax,8),%xmm0
  subsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L8
L1:
  ret
```

assistant: ```c
void vectors_subtraction(int n, double *vector1, double *vector2, double *result) {
  int i;
  for (i = 0; i < n; i++) {
    result[i] = vector1[i] - vector2[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<vectors_subtraction>:
  endbr64
  mov    %edi,%r8d
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  test   %r8d,%r8d
  jle    L11
  lea    0x8(%rdi),%rax
  cmp    %rax,%rcx
  lea    0x8(%rsi),%rax
  setne  %cl
  cmp    %rax,%rdx
  setne  %al
  test   %al,%cl
  je     L14
  lea    -0x1(%r8),%eax
  cmp    $0x1,%eax
  jbe    L14
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L4:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdi,%rax,1),%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L4
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r8d
  je     L11
  movsd  (%rsi,%rax,8),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  ret
  nop
L14:
  mov    %r8d,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movsd  (%rsi,%rax,8),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L5
L11:
  ret
```

assistant: ```c
void vectors_subtraction(int n, double *vector1, double *vector2, double *result) {
  int i;
  for (i = 0; i < n; i++) {
    result[i] = vector1[i] - vector2[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L43
L2:
  addl   $0x1,-0x10(%rbp)
L58:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L2
  jmp    L69
L34:
  subl   $0x1,-0xc(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L34
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L43
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L43:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L58
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L53
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L53:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L50
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L50:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(int arr[10000], int low, int high) {
  int i = low, j = high;
  int pivot = arr[(i + j) / 2];
  while (i <= j) {
    while (arr[i] < pivot)
      i++;
    while (arr[j] > pivot)
      j--;
    if (i <= j) {
      int temp = arr[i];
      arr[i] = arr[j];
      arr[j] = temp;
      i++;
      j--;
    }
  }
  if (low < j)
    quick_sort(arr, low, j);
  if (i < high)
    quick_sort(arr, i, high);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quick_sort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r10d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%esi
  mov    %r12d,%edx
  mov    %r10d,%ebx
  jmp    L105
L116:
  mov    %edi,(%r8)
  mov    %ecx,(%r9)
  add    $0x1,%ebx
  sub    $0x1,%edx
  jmp    L105
L71:
  cmp    %r10d,%edx
  jg     L136
L5:
  cmp    %r12d,%ebx
  jl     L56
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L136:
  mov    %r10d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  jmp    L5
L56:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  jmp    L10
L114:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%r9
  mov    (%r9),%edi
  cmp    %edi,%esi
  jge    L116
L85:
  movslq %edx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
L119:
  sub    $0x1,%edx
  mov    %rax,%r9
  sub    $0x4,%rax
  mov    0x4(%rax),%edi
  cmp    %esi,%edi
  jg     L119
L29:
  cmp    %ebx,%edx
  jge    L116
L105:
  cmp    %edx,%ebx
  jg     L71
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    0x0(%rbp,%rax,1),%r8
  mov    (%r8),%ecx
  lea    0x4(%rbp,%rax,1),%rax
  cmp    %ecx,%esi
  jle    L114
L112:
  add    $0x1,%ebx
  mov    %rax,%r8
  add    $0x4,%rax
  mov    -0x4(%rax),%ecx
  cmp    %esi,%ecx
  jl     L112
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%r9
  mov    (%r9),%edi
  cmp    %edi,%esi
  jl     L85
  jmp    L29
```

assistant: ```c
void quick_sort(int arr[10000], int low, int high) {
  int i = low, j = high;
  int pivot = arr[(i + j) / 2];
  while (i <= j) {
    while (arr[i] < pivot)
      i++;
    while (arr[j] > pivot)
      j--;
    if (i <= j) {
      int temp = arr[i];
      arr[i] = arr[j];
      arr[j] = temp;
      i++;
      j--;
    }
  }
  if (low < j)
    quick_sort(arr, low, j);
  if (i < high)
    quick_sort(arr, i, high);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quick_sort>:
  endbr64
  push   %r12
  mov    %esi,%r10d
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
L7:
  lea    (%r10,%rbp,1),%edx
  mov    %r10d,%ebx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    %ebp,%edx
  sar    %eax
  cltq
  mov    (%r12,%rax,4),%edi
  nopl   0x0(%rax,%rax,1)
L29:
  cmp    %edx,%ebx
  jg     L54
L71:
  movslq %ebx,%rax
  movslq %edx,%r11
  shl    $0x2,%rax
  lea    (%r12,%r11,4),%r9
  lea    (%r12,%rax,1),%rcx
  mov    (%r9),%r8d
  lea    0x4(%r12,%rax,1),%rax
  mov    (%rcx),%esi
  cmp    %edi,%esi
  jge    L44
  nopl   0x0(%rax)
L13:
  mov    %rax,%rcx
  mov    (%rax),%esi
  lea    0x4(%rax),%rax
  add    $0x1,%ebx
  cmp    %edi,%esi
  jl     L13
  cmp    %r8d,%edi
  jge    L58
L121:
  lea    -0x4(%r12,%r11,4),%rax
  nopw   0x0(%rax,%rax,1)
L84:
  mov    %rax,%r9
  mov    (%rax),%r8d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %edi,%r8d
  jg     L84
L58:
  cmp    %ebx,%edx
  jl     L29
  mov    %r8d,(%rcx)
  add    $0x1,%ebx
  sub    $0x1,%edx
  mov    %esi,(%r9)
L33:
  cmp    %edx,%ebx
  jle    L71
L54:
  cmp    %r10d,%edx
  jg     L11
L14:
  cmp    %ebp,%ebx
  jge    L99
  mov    %ebx,%r10d
  jmp    L7
  nop
L44:
  cmp    %r8d,%edi
  jl     L121
  mov    %r8d,(%rcx)
  add    $0x1,%ebx
  sub    $0x1,%edx
  mov    %esi,(%r9)
  jmp    L33
L99:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %r10d,%esi
  mov    %r12,%rdi
  call   <quick_sort>
  jmp    L14
```

assistant: ```c
void quick_sort(int arr[10000], int low, int high) {
  int i = low, j = high;
  int pivot = arr[(i + j) / 2];
  while (i <= j) {
    while (arr[i] < pivot)
      i++;
    while (arr[j] > pivot)
      j--;
    if (i <= j) {
      int temp = arr[i];
      arr[i] = arr[j];
      arr[j] = temp;
      i++;
      j--;
    }
  }
  if (low < j)
    quick_sort(arr, low, j);
  if (i < high)
    quick_sort(arr, i, high);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Fread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L9
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: Can't read a file


assistant: ```c
void Fread(void *ptr, size_t size, FILE *stream) {
  size_t r = fread(ptr, 1, size, stream);
  if (r != size)
    error("Can't read a file\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Fread>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    %rax,%rbx
  jne    L5
L11:
  pop    %rbx
  ret
L5:
  lea    D9(%rip),%rdi
  call   <error@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: Can't read a file


assistant: ```c
void Fread(void *ptr, size_t size, FILE *stream) {
  size_t r = fread(ptr, 1, size, stream);
  if (r != size)
    error("Can't read a file\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Fread>:
  endbr64
  push   %rbx
  mov    %rdx,%rcx
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    %rax,%rbx
  jne    L9
  pop    %rbx
  ret
  nop
L9:
  lea    D7(%rip),%rdi
  pop    %rbx
  jmp    1070 <error@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: Can't read a file


assistant: ```c
void Fread(void *ptr, size_t size, FILE *stream) {
  size_t r = fread(ptr, 1, size, stream);
  if (r != size)
    error("Can't read a file\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<Fread>:
  endbr64
  push   %rbx
  mov    %rdx,%rcx
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    %rax,%rbx
  jne    L3
  pop    %rbx
  ret
  nop
L3:
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1070 <error@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Can't read a file


assistant: ```c
void Fread(void *ptr, size_t size, FILE *stream) {
  size_t r = fread(ptr, 1, size, stream);
  if (r != size)
    error("Can't read a file\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<attente>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <attente>
L1:
  nop
  leave
  ret
```

assistant: ```c
void attente(int n) {
  if (n)
    attente(n - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<attente>:
  endbr64
  test   %edi,%edi
  jne    L5
  ret
L5:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <attente>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void attente(int n) {
  if (n)
    attente(n - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<attente>:
  endbr64
  ret
```

assistant: ```c
void attente(int n) {
  if (n)
    attente(n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<attente>:
  endbr64
  ret
```

assistant: ```c
void attente(int n) {
  if (n)
    attente(n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<core_spinlock_lock_private>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L37
L6:
  movl   $0x8,-0x4(%rbp)
  jmp    L5
L14:
  subl   $0x1,-0x4(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L37
  cmpl   $0x0,-0x4(%rbp)
  jg     L14
L37:
  mov    -0x18(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1,%ecx
  lock cmpxchg %ecx,(%rdx)
  sete   %al
  test   %al,%al
  jne    L6
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int core_spinlock_lock_private(int *lock) {
  int reads;
  while (__sync_bool_compare_and_swap(lock, 0, 1) != 0) {
    if (8 > 0) {
      reads = 8;
      while (*lock != 0 && reads > 0) {
        --reads;
      }
    } else {
      while (*lock != 0) {
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<core_spinlock_lock_private>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x0,%esi
  mov    $0x1,%ecx
L3:
  mov    %esi,%eax
  lock cmpxchg %ecx,(%rdx)
  je     L3
  mov    $0x0,%eax
  ret
```

assistant: ```c
int core_spinlock_lock_private(int *lock) {
  int reads;
  while (__sync_bool_compare_and_swap(lock, 0, 1) != 0) {
    if (8 > 0) {
      reads = 8;
      while (*lock != 0 && reads > 0) {
        --reads;
      }
    } else {
      while (*lock != 0) {
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<core_spinlock_lock_private>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ecx,%eax
  lock cmpxchg %edx,(%rdi)
  je     L5
  xor    %eax,%eax
  ret
```

assistant: ```c
int core_spinlock_lock_private(int *lock) {
  int reads;
  while (__sync_bool_compare_and_swap(lock, 0, 1) != 0) {
    if (8 > 0) {
      reads = 8;
      while (*lock != 0 && reads > 0) {
        --reads;
      }
    } else {
      while (*lock != 0) {
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<core_spinlock_lock_private>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ecx,%eax
  lock cmpxchg %edx,(%rdi)
  je     L4
  xor    %eax,%eax
  ret
```

assistant: ```c
int core_spinlock_lock_private(int *lock) {
  int reads;
  while (__sync_bool_compare_and_swap(lock, 0, 1) != 0) {
    if (8 > 0) {
      reads = 8;
      while (*lock != 0 && reads > 0) {
        --reads;
      }
    } else {
      while (*lock != 0) {
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  mov    $0x1,%edx
  mov    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1e,%edi
  call   <glutTimerFunc@plt>
  nop
  leave
  ret
```

assistant: ```c
void timer(int val) {
  glutPostRedisplay();
  glutTimerFunc(30, timer, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<timer>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  mov    $0x1,%edx
  mov    D9(%rip),%rsi
  mov    $0x1e,%edi
  call   <glutTimerFunc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void timer(int val) {
  glutPostRedisplay();
  glutTimerFunc(30, timer, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<timer>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <glutPostRedisplay@plt>
  mov    $0x1,%edx
  mov    $0x1e,%edi
  mov    D2(%rip),%rsi
  add    $0x8,%rsp
  jmp    1070 <glutTimerFunc@plt>
```

assistant: ```c
void timer(int val) {
  glutPostRedisplay();
  glutTimerFunc(30, timer, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<timer>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <glutPostRedisplay@plt>
  mov    $0x1,%edx
  mov    $0x1e,%edi
  mov    D1(%rip),%rsi
  add    $0x8,%rsp
  jmp    1070 <glutTimerFunc@plt>
```

assistant: ```c
void timer(int val) {
  glutPostRedisplay();
  glutTimerFunc(30, timer, 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x12,-0x20(%rbp)
  movl   $0x13,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <binary_search@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int array[] = {1, 2, 5, 6, 18, 19, 30};
  binary_search(array, 5);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x12,0x10(%rsp)
  movl   $0x13,0x14(%rsp)
  movl   $0x1e,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <binary_search@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int array[] = {1, 2, 5, 6, 18, 19, 30};
  binary_search(array, 5);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  movl   $0x1e,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1300000012,%rax
  mov    %rax,0x10(%rsp)
  call   <binary_search@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int array[] = {1, 2, 5, 6, 18, 19, 30};
  binary_search(array, 5);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D16(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rdi
  movl   $0x1e,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <binary_search@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type: byte[16]
name: retrieve_data
arguments: tag: D0
type: byte[8]

tool: {"D16": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D0": [0x12,0x00,0x00,0x00,0x13,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  int array[] = {1, 2, 5, 6, 18, 19, 30};
  binary_search(array, 5);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_generation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L7
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L7:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L1
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D20: 


tool: D7: *

tool: D6: .

assistant: ```c
void print_generation(int *current, int lenght) {
  int j;
  printf("\n");
  for (j = 0; j <= lenght - 1; j++) {
    if (current[j] == 1)
      printf("*");
    else
      printf(".");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_generation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L33
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%rbp
  lea    D21(%rip),%r12
  lea    D27(%rip),%r13
  jmp    L16
L11:
  mov    %r13,%rdi
  call   <printf@plt>
L31:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L33
L16:
  cmpl   $0x1,(%rbx)
  je     L11
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L31
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string

tool: D8: 


tool: D21: .

tool: D27: *

assistant: ```c
void print_generation(int *current, int lenght) {
  int j;
  printf("\n");
  for (j = 0; j <= lenght - 1; j++) {
    if (current[j] == 1)
      printf("*");
    else
      printf(".");
  }
}
```