ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<si>:
  endbr64
  cmp    $0x1,%edi
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D9(%rip),%rdi
  jmp    1050 <console_print@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: usage: 'si [file]'


assistant: ```c
int si(int argc, char *argv[]) {
  if (argc != 1) {
    console_print("usage: 'si [file]'\n");
  } else {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<si>:
  endbr64
  cmp    $0x1,%edi
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D1(%rip),%rdi
  jmp    1050 <console_print@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: usage: 'si [file]'


assistant: ```c
int si(int argc, char *argv[]) {
  if (argc != 1) {
    console_print("usage: 'si [file]'\n");
  } else {
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pass_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %edx,-0xb0(%rbp)
  mov    %rcx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <getpass@plt>
  mov    %rax,-0x98(%rbp)
  cmpq   $0x0,-0x98(%rbp)
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L10
L16:
  mov    -0xac(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rcx
  mov    -0xa8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: "%s" passphrase: 

assistant: ```c
int pass_cb(char *buf, int size, int rwflag, void *u) {
  char *passphrase;
  char prompt[128];
  (void)&(rwflag);
  snprintf(prompt, sizeof(prompt), "\"%s\" passphrase: ", (char *)u);
  if ((passphrase = getpass(prompt)) == NULL) {
    return -1;
  }
  (void)memcpy(buf, passphrase, (size_t)size);
  return (int)strlen(passphrase);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pass_cb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D3(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <getpass@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rbx
  movslq %ebp,%rdx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
L21:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L21
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: "%s" passphrase: 

assistant: ```c
int pass_cb(char *buf, int size, int rwflag, void *u) {
  char *passphrase;
  char prompt[128];
  (void)&(rwflag);
  snprintf(prompt, sizeof(prompt), "\"%s\" passphrase: ", (char *)u);
  if ((passphrase = getpass(prompt)) == NULL) {
    return -1;
  }
  (void)memcpy(buf, passphrase, (size_t)size);
  return (int)strlen(passphrase);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pass_cb>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdx
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x80,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <getpass@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    %r12,%rdi
  movslq %ebx,%rdx
  mov    %rax,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
L4:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L4
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: "%s" passphrase: 

assistant: ```c
int pass_cb(char *buf, int size, int rwflag, void *u) {
  char *passphrase;
  char prompt[128];
  (void)&(rwflag);
  snprintf(prompt, sizeof(prompt), "\"%s\" passphrase: ", (char *)u);
  if ((passphrase = getpass(prompt)) == NULL) {
    return -1;
  }
  (void)memcpy(buf, passphrase, (size_t)size);
  return (int)strlen(passphrase);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pass_cb>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdx
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x80,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <getpass@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    %r12,%rdi
  movslq %ebx,%rdx
  mov    %rax,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
L1:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L1
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: "%s" passphrase: 

assistant: ```c
int pass_cb(char *buf, int size, int rwflag, void *u) {
  char *passphrase;
  char prompt[128];
  (void)&(rwflag);
  snprintf(prompt, sizeof(prompt), "\"%s\" passphrase: ", (char *)u);
  if ((passphrase = getpass(prompt)) == NULL) {
    return -1;
  }
  (void)memcpy(buf, passphrase, (size_t)size);
  return (int)strlen(passphrase);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L4
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <g_strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <g_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <g_strcpy@plt>
L14:
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
char *g_strdup(const char *in) {
  int len;
  char *p;
  if (in == 0) {
    return 0;
  }
  len = g_strlen(in);
  p = (char *)g_malloc(len + 1, 0);
  if (p != 0) {
    g_strcpy(p, in);
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<g_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L38
  call   <g_strlen@plt>
  lea    0x1(%rax),%edi
  mov    $0x0,%esi
  call   <g_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L31
L32:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <g_strcpy@plt>
  jmp    L32
L38:
  mov    %rdi,%rbp
  jmp    L32
```

assistant: ```c
char *g_strdup(const char *in) {
  int len;
  char *p;
  if (in == 0) {
    return 0;
  }
  len = g_strlen(in);
  p = (char *)g_malloc(len + 1, 0);
  if (p != 0) {
    g_strcpy(p, in);
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g_strdup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  mov    %rdi,%rbp
  call   <g_strlen@plt>
  xor    %esi,%esi
  lea    0x1(%rax),%edi
  call   <g_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L18
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <g_strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *g_strdup(const char *in) {
  int len;
  char *p;
  if (in == 0) {
    return 0;
  }
  len = g_strlen(in);
  p = (char *)g_malloc(len + 1, 0);
  if (p != 0) {
    g_strcpy(p, in);
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g_strdup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  mov    %rdi,%rbp
  call   <g_strlen@plt>
  xor    %esi,%esi
  lea    0x1(%rax),%edi
  call   <g_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L18
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <g_strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *g_strdup(const char *in) {
  int len;
  char *p;
  if (in == 0) {
    return 0;
  }
  len = g_strlen(in);
  p = (char *)g_malloc(len + 1, 0);
  if (p != 0) {
    g_strcpy(p, in);
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x1c(%rbp)
  jmp    L11
L6:
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D33(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D44(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D44(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D68
type_infered: string
name: parse_data
arguments: data_label: D49
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: byte[8]
name: parse_data
arguments: data_label: D33
type_infered: byte[8]
name: parse_data
arguments: data_label: D44
type_infered: byte[8]
name: parse_data
arguments: data_label: D25
type_infered: string

tool: D68: %d

tool: D49: %lf %lf

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D25: Case %d: %.2lf


assistant: ```c
int main() {
  int t, i;
  double c, f;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lf %lf", &c, &f);
    f = f + c * 9 / 5 + 32;
    c = 5 * (f - 32) / 9;
    printf("Case %d: %.2lf\n", i, c);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L12
  mov    $0x1,%ebx
  lea    D40(%rip),%rbp
L17:
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  D11(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D51(%rip),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  D48(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  subsd  D48(%rip),%xmm0
  mulsd  D51(%rip),%xmm0
  divsd  D11(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %ebx,%esi
  lea    D84(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L17
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D40
datatype: string
name: unpack_data
arguments: label: D11
datatype: byte[8]
name: unpack_data
arguments: label: D51
datatype: byte[8]
name: unpack_data
arguments: label: D48
datatype: byte[8]
name: unpack_data
arguments: label: D84
datatype: string

tool: D14: %d

tool: D40: %lf %lf

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D84: Case %d: %.2lf


assistant: ```c
int main() {
  int t, i;
  double c, f;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lf %lf", &c, &f);
    f = f + c * 9 / 5 + 32;
    c = 5 * (f - 32) / 9;
    printf("Case %d: %.2lf\n", i, c);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D64(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L0
  mov    $0x1,%r14d
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  lea    D40(%rip),%rbp
  lea    D57(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  D3(%rip),%xmm0
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mulsd  0x8(%rsp),%xmm0
  add    $0x1,%r14d
  divsd  D26(%rip),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  D38(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  subsd  D38(%rip),%xmm0
  mulsd  D26(%rip),%xmm0
  divsd  D3(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  cmp    %r14d,0x4(%rsp)
  jge    L7
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D64
type: string
name: read_data
arguments: tag: D40
type: string
name: read_data
arguments: tag: D57
type: string
name: read_data
arguments: tag: D3
type: byte[8]
name: read_data
arguments: tag: D26
type: byte[8]
name: read_data
arguments: tag: D38
type: byte[8]

tool: D64: %d

tool: D40: %lf %lf

tool: D57: Case %d: %.2lf


tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

assistant: ```c
int main() {
  int t, i;
  double c, f;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lf %lf", &c, &f);
    f = f + c * 9 / 5 + 32;
    c = 5 * (f - 32) / 9;
    printf("Case %d: %.2lf\n", i, c);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D45(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L13
  mov    $0x1,%r14d
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  lea    D39(%rip),%rbp
  lea    D37(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  D85(%rip),%xmm0
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mulsd  0x8(%rsp),%xmm0
  add    $0x1,%r14d
  divsd  D71(%rip),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  D0(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  subsd  D0(%rip),%xmm0
  mulsd  D71(%rip),%xmm0
  divsd  D85(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  cmp    %r14d,0x4(%rsp)
  jge    L18
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D45
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string
name: parse_data
arguments: data_tag: D37
data_type: string
name: parse_data
arguments: data_tag: D85
data_type: byte[8]
name: parse_data
arguments: data_tag: D71
data_type: byte[8]
name: parse_data
arguments: data_tag: D0
data_type: byte[8]

tool: D45: %d

tool: D39: %lf %lf

tool: D37: Case %d: %.2lf


tool: {"D85": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: {"D71": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

assistant: ```c
int main() {
  int t, i;
  double c, f;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lf %lf", &c, &f);
    f = f + c * 9 / 5 + 32;
    c = 5 * (f - 32) / 9;
    printf("Case %d: %.2lf\n", i, c);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<timer_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3ff6000,%eax
  movl   $0x0,(%rax)
  mov    $0x3ff4004,%eax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timer_init(void) {
  if (0 == 1) {
    *(volatile unsigned *)0x0A00000C = ~0;
    *(volatile unsigned *)0x0A800008 = 0;
    *(volatile unsigned *)0x0A80000C = 0;
  } else {
    *(volatile unsigned *)0x03ff6000 = 0;
    *(volatile unsigned *)0x03ff4004 = 0x00000000;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timer_init>:
  endbr64
  movl   $0x0,0x3ff6000
  movl   $0x0,0x3ff4004
  ret
```

assistant: ```c
void timer_init(void) {
  if (0 == 1) {
    *(volatile unsigned *)0x0A00000C = ~0;
    *(volatile unsigned *)0x0A800008 = 0;
    *(volatile unsigned *)0x0A80000C = 0;
  } else {
    *(volatile unsigned *)0x03ff6000 = 0;
    *(volatile unsigned *)0x03ff4004 = 0x00000000;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timer_init>:
  endbr64
  movl   $0x0,0x3ff6000
  movl   $0x0,0x3ff4004
  ret
```

assistant: ```c
void timer_init(void) {
  if (0 == 1) {
    *(volatile unsigned *)0x0A00000C = ~0;
    *(volatile unsigned *)0x0A800008 = 0;
    *(volatile unsigned *)0x0A80000C = 0;
  } else {
    *(volatile unsigned *)0x03ff6000 = 0;
    *(volatile unsigned *)0x03ff4004 = 0x00000000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<timer_init>:
  endbr64
  movl   $0x0,0x3ff6000
  movl   $0x0,0x3ff4004
  ret
```

assistant: ```c
void timer_init(void) {
  if (0 == 1) {
    *(volatile unsigned *)0x0A00000C = ~0;
    *(volatile unsigned *)0x0A800008 = 0;
    *(volatile unsigned *)0x0A80000C = 0;
  } else {
    *(volatile unsigned *)0x03ff6000 = 0;
    *(volatile unsigned *)0x03ff4004 = 0x00000000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<verif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  lea    -0x20(%rbp),%rdi
  lea    -0x1c(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x10(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L74
  mov    -0x20(%rbp),%eax
  cmp    $0x1,%eax
  je     L70
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jne    L74
L70:
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L28
L1:
  mov    $0xfffffffe,%eax
  jmp    L28
L74:
  mov    $0xffffffff,%eax
  jmp    L28
L6:
  mov    $0xffffffff,%eax
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D35
type: string

tool: D11: %s %s HTTP/%d.%d

tool: D33: GET

tool: D1: /

tool: D35: OK 


assistant: ```c
int verif(char buf[], char get[], char slash[], int M, int m) {
  sscanf(buf, "%s %s HTTP/%d.%d", get, slash, &M, &m);
  if (strcmp(get, "GET") == 0) {
    if (M == 1 && (m == 1 || m == 0)) {
      if (strcmp(slash, "/") == 0) {
        printf("OK \n");
        return 0;
      } else {
        return -2;
      }
    } else {
      return -1;
    }
  } else {
    return -1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<verif>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x8(%rsp)
  lea    0x8(%rsp),%r9
  lea    0xc(%rsp),%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D26(%rip),%rsi
  call   <sscanf@plt>
  lea    D33(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  cmpl   $0x1,0xc(%rsp)
  jne    L77
  cmpl   $0x1,0x8(%rsp)
  ja     L78
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L66:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L64:
  mov    $0xffffffff,%eax
  jmp    L66
L77:
  mov    $0xffffffff,%eax
  jmp    L66
L78:
  mov    $0xffffffff,%eax
  jmp    L66
L17:
  mov    $0xfffffffe,%eax
  jmp    L66
```

tool_calls: name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D33
data_type: string
name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D16
data_type: string

tool: D26: %s %s HTTP/%d.%d

tool: D33: GET

tool: D21: /

tool: D16: OK 


assistant: ```c
int verif(char buf[], char get[], char slash[], int M, int m) {
  sscanf(buf, "%s %s HTTP/%d.%d", get, slash, &M, &m);
  if (strcmp(get, "GET") == 0) {
    if (M == 1 && (m == 1 || m == 0)) {
      if (strcmp(slash, "/") == 0) {
        printf("OK \n");
        return 0;
      } else {
        return -2;
      }
    } else {
      return -1;
    }
  } else {
    return -1;
  }
}
```