ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fatal_error>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    %rdi,%rsi
  mov    (%rax),%edi
  call   <fprintf@plt>
  xor    %eax,%eax
  call   <nl@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

assistant: ```c
void fatal_error(const char *message) {
  fprintf(stderr, message);
  nl();
  exit(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Gen_comb_del>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L51:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    D40(%rip),%edx
  mov    (%rax),%eax
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    D109(%rip),%rdx
  mov    %eax,(%rcx,%rdx,1)
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    D40(%rip),%eax
  cmp    %eax,%edx
  jle    L37
  mov    D40(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D98(%rip)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Gen_comb_del>
  jmp    L17
L37:
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L38:
  mov    D98(%rip),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  lea    D109(%rip),%rax
  mov    (%rcx,%rax,1),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  mov    D98(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D80(%rip)
L17:
  addl   $0x1,-0x8(%rbp)
L25:
  cmpl   $0x1,-0x8(%rbp)
  jle    L51
  mov    D98(%rip),%eax
  sub    $0x1,%eax
  mov    %eax,D80(%rip)
  nop
  leave
  ret
```

assistant: ```c
void Gen_comb_del(int *cdel[], const int n, const int d[]) {
  static int i = 0;
  static int p = 0;
  static int del[128];
  int cont = 0;
  int t;
  while (cont < 2) {
    del[i] = d[cont];
    if (i < n - 1) {
      i++;
      Gen_comb_del(cdel, n, d);
    } else {
      for (t = 0; t < n; t++)
        cdel[p][t] = del[t];
      p++;
    }
    cont++;
  }
  i--;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Gen_comb_del>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r13d
  mov    %rdx,%r14
  lea    -0x1(%rsi),%eax
  lea    0x4(,%rax,4),%r12
  mov    $0x0,%ebp
  lea    D43(%rip),%rbx
  jmp    L23
L27:
  test   %r13d,%r13d
  jle    L31
  movslq D2(%rip),%rax
  lea    (%r15,%rax,8),%rsi
  mov    $0x0,%eax
L59:
  mov    (%rbx,%rax,1),%ecx
  mov    (%rsi),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L59
L31:
  addl   $0x1,D2(%rip)
L6:
  add    $0x1,%rbp
  cmp    $0x2,%rbp
  je     L53
L23:
  mov    D54(%rip),%eax
  mov    (%r14,%rbp,4),%ecx
  movslq %eax,%rdx
  mov    %ecx,(%rbx,%rdx,4)
  lea    -0x1(%r13),%edx
  cmp    %edx,%eax
  jge    L27
  add    $0x1,%eax
  mov    %eax,D23(%rip)
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <Gen_comb_del>
  jmp    L6
L53:
  subl   $0x1,D23(%rip)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Gen_comb_del(int *cdel[], const int n, const int d[]) {
  static int i = 0;
  static int p = 0;
  static int del[128];
  int cont = 0;
  int t;
  while (cont < 2) {
    del[i] = d[cont];
    if (i < n - 1) {
      i++;
      Gen_comb_del(cdel, n, d);
    } else {
      for (t = 0; t < n; t++)
        cdel[p][t] = del[t];
      p++;
    }
    cont++;
  }
  i--;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Gen_comb_del>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  lea    -0x1(%rbp),%r8d
  lea    D19(%rip),%rbx
  mov    %rbp,%r12
  sub    $0x18,%rsp
  mov    D41(%rip),%ecx
  mov    (%r14,%r13,4),%edx
  movslq %ecx,%rax
  mov    %edx,(%rbx,%rax,4)
  cmp    %ecx,%r8d
  jle    L45
L15:
  add    $0x1,%ecx
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    %r8d,0xc(%rsp)
  mov    %ecx,D7(%rip)
  call   <Gen_comb_del>
  mov    D7(%rip),%ecx
  mov    0xc(%rsp),%r8d
L46:
  cmp    $0x1,%r13
  jne    L53
  sub    $0x1,%ecx
  mov    %ecx,D7(%rip)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    $0x1,%r13d
  movslq %ecx,%rax
  mov    (%r14,%r13,4),%edx
  mov    %edx,(%rbx,%rax,4)
  cmp    %ecx,%r8d
  jg     L15
L45:
  mov    D7(%rip),%edi
  test   %r12d,%r12d
  jle    L55
  movslq %edi,%rax
  mov    (%r15,%rax,8),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L21:
  mov    (%rbx,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L21
L55:
  add    $0x1,%edi
  mov    %edi,D57(%rip)
  jmp    L46
```

assistant: ```c
void Gen_comb_del(int *cdel[], const int n, const int d[]) {
  static int i = 0;
  static int p = 0;
  static int del[128];
  int cont = 0;
  int t;
  while (cont < 2) {
    del[i] = d[cont];
    if (i < n - 1) {
      i++;
      Gen_comb_del(cdel, n, d);
    } else {
      for (t = 0; t < n; t++)
        cdel[p][t] = del[t];
      p++;
    }
    cont++;
  }
  i--;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L14
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L14:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x1d8(%rbp),%rdx
  mov    -0x1c8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x1c8(%rbp),%ecx
  mov    -0x1d8(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <vsnprintf_internal@plt>
  mov    %eax,-0x1c4(%rbp)
  mov    -0x1c8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x1c4(%rbp),%edx
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    -0x1c4(%rbp),%eax
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int printf(const char *string, ...) {
  char buffer[256];
  int result;
  va_list argp;
  va_start(argp, string);
  result = vsnprintf_internal(buffer, 256, string, argp);
  va_end(argp);
  write(1, buffer, result);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <vsnprintf_internal@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %ebx,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printf(const char *string, ...) {
  char buffer[256];
  int result;
  va_list argp;
  va_start(argp, string);
  result = vsnprintf_internal(buffer, 256, string, argp);
  va_end(argp);
  write(1, buffer, result);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %ebp,%ecx
  mov    %r13,%rdi
  call   <vsnprintf_internal@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x110,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printf(const char *string, ...) {
  char buffer[256];
  int result;
  va_list argp;
  va_start(argp, string);
  result = vsnprintf_internal(buffer, 256, string, argp);
  va_end(argp);
  write(1, buffer, result);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %ebp,%ecx
  mov    %r13,%rdi
  call   <vsnprintf_internal@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x110,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printf(const char *string, ...) {
  char buffer[256];
  int result;
  va_list argp;
  va_start(argp, string);
  result = vsnprintf_internal(buffer, 256, string, argp);
  va_end(argp);
  write(1, buffer, result);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<mysubstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  jmp    L3
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subl   $0x1,-0x18(%rbp)
L3:
  cmpl   $0x0,-0x18(%rbp)
  jg     L15
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mysubstr(char *dest, char *src, int position, int length) {
  while (length > 0) {
    *dest = *(src + position);
    dest++;
    src++;
    length--;
  }
  *dest = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mysubstr>:
  endbr64
  test   %ecx,%ecx
  jle    L5
  mov    %ecx,%r8d
  mov    $0x0,%eax
  movslq %edx,%rdx
  add    %rdx,%rsi
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L4
  mov    %ecx,%ecx
  add    %rcx,%rdi
L5:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void mysubstr(char *dest, char *src, int position, int length) {
  while (length > 0) {
    *dest = *(src + position);
    dest++;
    src++;
    length--;
  }
  *dest = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mysubstr>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  movslq %edx,%rdx
  movslq %ecx,%rcx
  xor    %eax,%eax
  add    %rdx,%rsi
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L16
  add    %rax,%rdi
L9:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void mysubstr(char *dest, char *src, int position, int length) {
  while (length > 0) {
    *dest = *(src + position);
    dest++;
    src++;
    length--;
  }
  *dest = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<mysubstr>:
  endbr64
  test   %ecx,%ecx
  jle    L100
  movslq %edx,%rdx
  mov    %rdi,%r8
  lea    -0x1(%rcx),%eax
  lea    0x1(%rsi,%rdx,1),%r9
  sub    %r9,%r8
  cmp    $0xe,%r8
  jbe    L149
  cmp    $0x6,%eax
  jbe    L149
  cmp    $0xe,%eax
  jbe    L30
  mov    %ecx,%r8d
  lea    (%rsi,%rdx,1),%r9
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L113:
  movdqu (%r9,%rax,1),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L113
  mov    %ecx,%eax
  mov    %ecx,%r11d
  and    $0xfffffff0,%eax
  mov    %eax,%r8d
  sub    %eax,%r11d
  lea    (%rdi,%r8,1),%r10
  add    %rsi,%r8
  cmp    %eax,%ecx
  je     L117
L98:
  mov    %ecx,%r9d
  push   %rbx
  sub    %eax,%r9d
  lea    -0x1(%r9),%ebx
  cmp    $0x6,%ebx
  jbe    L26
  add    %rdx,%rsi
  mov    (%rsi,%rax,1),%rsi
  mov    %rsi,(%rdi,%rax,1)
  mov    %r9d,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%esi
  sub    %eax,%r11d
  add    %rsi,%r10
  add    %rsi,%r8
  cmp    %eax,%r9d
  je     L0
L26:
  movzbl (%r8,%rdx,1),%eax
  mov    %al,(%r10)
  cmp    $0x1,%r11d
  je     L0
  movzbl 0x1(%r8,%rdx,1),%eax
  mov    %al,0x1(%r10)
  cmp    $0x2,%r11d
  je     L0
  movzbl 0x2(%r8,%rdx,1),%eax
  mov    %al,0x2(%r10)
  cmp    $0x3,%r11d
  je     L0
  movzbl 0x3(%r8,%rdx,1),%eax
  mov    %al,0x3(%r10)
  cmp    $0x4,%r11d
  je     L0
  movzbl 0x4(%r8,%rdx,1),%eax
  mov    %al,0x4(%r10)
  cmp    $0x5,%r11d
  je     L0
  movzbl 0x5(%r8,%rdx,1),%eax
  mov    %al,0x5(%r10)
  cmp    $0x6,%r11d
  je     L0
  movzbl 0x6(%r8,%rdx,1),%eax
  mov    %al,0x6(%r10)
L0:
  movslq %ecx,%rcx
  pop    %rbx
  add    %rcx,%rdi
  movb   $0x0,(%rdi)
  ret
  nopl   0x0(%rax)
L149:
  movslq %ecx,%rcx
  xor    %eax,%eax
  add    %rdx,%rsi
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L4
L89:
  add    %rcx,%rdi
L100:
  movb   $0x0,(%rdi)
  ret
L30:
  mov    %ecx,%r11d
  mov    %rsi,%r8
  mov    %rdi,%r10
  xor    %eax,%eax
  jmp    L98
L117:
  movslq %ecx,%rcx
  jmp    L89
```

assistant: ```c
void mysubstr(char *dest, char *src, int position, int length) {
  while (length > 0) {
    *dest = *(src + position);
    dest++;
    src++;
    length--;
  }
  *dest = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<evtag_marshal_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  lea    -0xd(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <encode_int_internal@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <evtag_encode_tag@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <evtag_encode_int@plt>
  mov    -0x14(%rbp),%edx
  lea    -0xd(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void evtag_marshal_int(struct evbuffer *evbuf, unsigned long tag, unsigned long integer) {
  unsigned char data[5];
  int len = encode_int_internal(data, integer);
  evtag_encode_tag(evbuf, tag);
  evtag_encode_int(evbuf, len);
  evbuffer_add(evbuf, data, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<evtag_marshal_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r13
  mov    %r13,%rdi
  call   <encode_int_internal@plt>
  mov    %eax,%ebp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <evtag_encode_tag@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <evtag_encode_int@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <evbuffer_add@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void evtag_marshal_int(struct evbuffer *evbuf, unsigned long tag, unsigned long integer) {
  unsigned char data[5];
  int len = encode_int_internal(data, integer);
  evtag_encode_tag(evbuf, tag);
  evtag_encode_int(evbuf, len);
  evbuffer_add(evbuf, data, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<evtag_marshal_int>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r14
  mov    %r14,%rdi
  call   <encode_int_internal@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <evtag_encode_tag@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <evtag_encode_int@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <evbuffer_add@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void evtag_marshal_int(struct evbuffer *evbuf, unsigned long tag, unsigned long integer) {
  unsigned char data[5];
  int len = encode_int_internal(data, integer);
  evtag_encode_tag(evbuf, tag);
  evtag_encode_int(evbuf, len);
  evbuffer_add(evbuf, data, len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<evtag_marshal_int>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r14
  mov    %r14,%rdi
  call   <encode_int_internal@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <evtag_encode_tag@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <evtag_encode_int@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <evbuffer_add@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void evtag_marshal_int(struct evbuffer *evbuf, unsigned long tag, unsigned long integer) {
  unsigned char data[5];
  int len = encode_int_internal(data, integer);
  evtag_encode_tag(evbuf, tag);
  evtag_encode_int(evbuf, len);
  evbuffer_add(evbuf, data, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: This is text.


assistant: ```c
int main(int argc, char **argv) {
  printf("This is text.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: This is text.


assistant: ```c
int main(int argc, char **argv) {
  printf("This is text.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: This is text.


assistant: ```c
int main(int argc, char **argv) {
  printf("This is text.\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: This is text.


assistant: ```c
int main(int argc, char **argv) {
  printf("This is text.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_n_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L5:
  mov    $0x0,%eax
  call   <no_op@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void do_n_times(int n) {
  for (int i = 0; i < n; i++) {
    no_op();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_n_times>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L1:
  mov    $0x0,%eax
  call   <no_op@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  ret
```

assistant: ```c
void do_n_times(int n) {
  for (int i = 0; i < n; i++) {
    no_op();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_n_times>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <no_op@plt>
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  ret
```

assistant: ```c
void do_n_times(int n) {
  for (int i = 0; i < n; i++) {
    no_op();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_n_times>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <no_op@plt>
  cmp    %ebx,%ebp
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
void do_n_times(int n) {
  for (int i = 0; i < n; i++) {
    no_op();
  }
}
```