ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x8,0x4(%rsp)
  call   <check_vect@plt>
  mov    0x4(%rsp),%edi
  lea    0x4(%rsp),%rsi
  call   <main1@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int m = 8;
  check_vect();
  return main1(m, &m);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<authmod_login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <auth_debug_login@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdx
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <auth_debug_login@plt>
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <authexit@plt>
L1:
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %eax,%edx
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcat@plt>
  mov    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcat@plt>
  mov    %eax,%edx
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rcx,%r8
  lea    D2(%rip),%rcx
  mov    %eax,%edi
  call   <authmod@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D22
data_type: string
name: retrieve_data
arguments: data_label: D51
data_type: string
name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D17: username=%s

tool: D22: password=%s

tool: D51: malloc

tool: D48: 


tool: D2: login

assistant: ```c
void authmod_login(int argc, char **argv, const char *service, const char *userid, const char *passwd) {
  char *p = malloc(strlen(userid) + strlen(passwd) + 3);
  auth_debug_login(1, "username=%s", userid);
  auth_debug_login(2, "password=%s", passwd);
  if (!p) {
    perror("malloc");
    authexit(1);
  }
  strcat(strcat(strcat(strcpy(p, userid), "\n"), passwd), "\n");
  authmod(argc, argv, service, "login", p);
}
```
user: What is the c source code of the assembly code below?

```asm
<authmod_login>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rcx,%r12
  mov    %r8,%rbp
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x3(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <auth_debug_login@plt>
  mov    %rbp,%rdx
  lea    D39(%rip),%rsi
  mov    $0x2,%edi
  call   <auth_debug_login@plt>
  test   %rbx,%rbx
  je     L15
L0:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %eax,%edi
  lea    D26(%rip),%r12
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <strcat@plt>
  mov    %eax,%edi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rbx,%r8
  lea    D1(%rip),%rcx
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <authmod@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  lea    D43(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <authexit@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D39
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D43
datatype: string

tool: D0: username=%s

tool: D39: password=%s

tool: D26: 


tool: D1: login

tool: D43: malloc

assistant: ```c
void authmod_login(int argc, char **argv, const char *service, const char *userid, const char *passwd) {
  char *p = malloc(strlen(userid) + strlen(passwd) + 3);
  auth_debug_login(1, "username=%s", userid);
  auth_debug_login(2, "password=%s", passwd);
  if (!p) {
    perror("malloc");
    authexit(1);
  }
  strcat(strcat(strcat(strcpy(p, userid), "\n"), passwd), "\n");
  authmod(argc, argv, service, "login", p);
}
```
user: What is the c source code of the assembly code below?

```asm
<authmod_login>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  mov    %rcx,%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x3(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    $0x1,%edi
  lea    D44(%rip),%rsi
  mov    %rax,%rbx
  call   <auth_debug_login@plt>
  mov    %rbp,%rdx
  mov    $0x2,%edi
  lea    D26(%rip),%rsi
  call   <auth_debug_login@plt>
  test   %rbx,%rbx
  je     L18
L14:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  lea    D32(%rip),%r12
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %rbx,%r8
  mov    %r15,%rdx
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  lea    D4(%rip),%rcx
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <authmod@plt>
L18:
  lea    D11(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <authexit@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: label: D44
type_guessed: string
name: disassemble_data
arguments: label: D26
type_guessed: string
name: disassemble_data
arguments: label: D32
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D44: username=%s

tool: D26: password=%s

tool: D32: 


tool: D4: login

tool: D11: malloc

assistant: ```c
void authmod_login(int argc, char **argv, const char *service, const char *userid, const char *passwd) {
  char *p = malloc(strlen(userid) + strlen(passwd) + 3);
  auth_debug_login(1, "username=%s", userid);
  auth_debug_login(2, "password=%s", passwd);
  if (!p) {
    perror("malloc");
    authexit(1);
  }
  strcat(strcat(strcat(strcpy(p, userid), "\n"), passwd), "\n");
  authmod(argc, argv, service, "login", p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<authmod_login>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  mov    %rcx,%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x3(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    $0x1,%edi
  lea    D13(%rip),%rsi
  mov    %rax,%rbx
  call   <auth_debug_login@plt>
  mov    %rbp,%rdx
  mov    $0x2,%edi
  lea    D25(%rip),%rsi
  call   <auth_debug_login@plt>
  test   %rbx,%rbx
  je     L4
L13:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  lea    D36(%rip),%r12
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %rbx,%r8
  mov    %r15,%rdx
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  lea    D11(%rip),%rcx
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <authmod@plt>
L4:
  lea    D27(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <authexit@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D25
type: string
name: extract_symbolic_data
arguments: tag: D36
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string

tool: D13: username=%s

tool: D25: password=%s

tool: D36: 


tool: D11: login

tool: D27: malloc

assistant: ```c
void authmod_login(int argc, char **argv, const char *service, const char *userid, const char *passwd) {
  char *p = malloc(strlen(userid) + strlen(passwd) + 3);
  auth_debug_login(1, "username=%s", userid);
  auth_debug_login(2, "password=%s", passwd);
  if (!p) {
    perror("malloc");
    authexit(1);
  }
  strcat(strcat(strcat(strcpy(p, userid), "\n"), passwd), "\n");
  authmod(argc, argv, service, "login", p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<secureWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L7:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L30
  mov    -0x4(%rbp),%eax
  jmp    L12
L30:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
ssize_t secureWrite(int fd, const void *buf, ssize_t txLen) {
  int i, acc = 0;
  while (acc < txLen) {
    i = write(fd, buf + acc, txLen - acc);
    if (i <= 0)
      return i;
    acc += i;
  }
  return (ssize_t)acc;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<secureWrite>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L19:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L1
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jg     L19
  mov    %ebx,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
ssize_t secureWrite(int fd, const void *buf, ssize_t txLen) {
  int i, acc = 0;
  while (acc < txLen) {
    i = write(fd, buf + acc, txLen - acc);
    if (i <= 0)
      return i;
    acc += i;
  }
  return (ssize_t)acc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<secureWrite>:
  endbr64
  test   %edx,%edx
  jle    L2
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L22
  xchg   %ax,%ax
L10:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L9
L22:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r12d,%edi
  sub    %ebx,%edx
  add    %r13,%rsi
  call   <write@plt>
  test   %eax,%eax
  jg     L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
ssize_t secureWrite(int fd, const void *buf, ssize_t txLen) {
  int i, acc = 0;
  while (acc < txLen) {
    i = write(fd, buf + acc, txLen - acc);
    if (i <= 0)
      return i;
    acc += i;
  }
  return (ssize_t)acc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<secureWrite>:
  endbr64
  test   %edx,%edx
  jle    L37
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L32
  xchg   %ax,%ax
L11:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L33
L32:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r12d,%edi
  sub    %ebx,%edx
  add    %r13,%rsi
  call   <write@plt>
  test   %eax,%eax
  jg     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
ssize_t secureWrite(int fd, const void *buf, ssize_t txLen) {
  int i, acc = 0;
  while (acc < txLen) {
    i = write(fd, buf + acc, txLen - acc);
    if (i <= 0)
      return i;
    acc += i;
  }
  return (ssize_t)acc;
}
```
user: What is the c source code of the assembly code below:

```asm
<checkint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    $0x34,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0x7ff,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3fe,-0x4(%rbp)
  jg     L38
  mov    $0x0,%eax
  jmp    L5
L38:
  cmpl   $0x433,-0x4(%rbp)
  jle    L36
  mov    $0x2,%eax
  jmp    L5
L36:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    $0x433,%eax
  sub    -0x4(%rbp),%eax
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    %rsi,%rax
  not    %rax
  and    %rdx,%rax
  test   %rax,%rax
  je     L50
  mov    $0x0,%eax
  jmp    L5
L50:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    $0x433,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L23
  mov    $0x1,%eax
  jmp    L5
L23:
  mov    $0x2,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int checkint(uint64_t iy) {
  int e = iy >> 52 & 0x7ff;
  if (e < 0x3ff)
    return 0;
  if (e > 0x3ff + 52)
    return 2;
  if (iy & ((1ULL << (0x3ff + 52 - e)) - 1))
    return 0;
  if (iy & (1ULL << (0x3ff + 52 - e)))
    return 1;
  return 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkint>:
  endbr64
  mov    %edi,%edx
  mov    $0x34,%ecx
  sar    %cl,%edx
  and    $0x7ff,%edx
  mov    $0x0,%eax
  cmp    $0x3fe,%edx
  jle    L2
  mov    $0x2,%eax
  cmp    $0x433,%edx
  jg     L2
  movslq %edi,%rdi
  mov    $0x433,%ecx
  sub    %edx,%ecx
  mov    $0xffffffffffffffff,%rax
  shl    %cl,%rax
  not    %rax
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdi,%rdx
  jne    L2
  shr    %cl,%rdi
  and    $0x1,%edi
  mov    $0x2,%eax
  sub    %edi,%eax
L2:
  ret
```

assistant: ```c
int checkint(uint64_t iy) {
  int e = iy >> 52 & 0x7ff;
  if (e < 0x3ff)
    return 0;
  if (e > 0x3ff + 52)
    return 2;
  if (iy & ((1ULL << (0x3ff + 52 - e)) - 1))
    return 0;
  if (iy & (1ULL << (0x3ff + 52 - e)))
    return 1;
  return 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkint>:
  endbr64
  mov    %edi,%edx
  mov    $0x34,%ecx
  xor    %eax,%eax
  sar    %cl,%edx
  and    $0x7ff,%edx
  cmp    $0x3fe,%edx
  jle    L3
  mov    $0x2,%eax
  cmp    $0x433,%edx
  jg     L3
  mov    $0x433,%ecx
  mov    $0xffffffffffffffff,%rax
  movslq %edi,%rdi
  sub    %edx,%ecx
  shl    %cl,%rax
  not    %rax
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdi,%rdx
  jne    L3
  shr    %cl,%rdi
  mov    $0x2,%eax
  and    $0x1,%edi
  sub    %edi,%eax
L3:
  ret
```

assistant: ```c
int checkint(uint64_t iy) {
  int e = iy >> 52 & 0x7ff;
  if (e < 0x3ff)
    return 0;
  if (e > 0x3ff + 52)
    return 2;
  if (iy & ((1ULL << (0x3ff + 52 - e)) - 1))
    return 0;
  if (iy & (1ULL << (0x3ff + 52 - e)))
    return 1;
  return 2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checkint>:
  endbr64
  mov    %edi,%edx
  mov    $0x34,%ecx
  xor    %eax,%eax
  sar    %cl,%edx
  and    $0x7ff,%edx
  cmp    $0x3fe,%edx
  jle    L0
  mov    $0x2,%eax
  cmp    $0x433,%edx
  jg     L0
  mov    $0x433,%ecx
  mov    $0xffffffffffffffff,%rax
  movslq %edi,%rdi
  sub    %edx,%ecx
  shl    %cl,%rax
  not    %rax
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdi,%rdx
  jne    L0
  shr    %cl,%rdi
  mov    $0x2,%eax
  and    $0x1,%edi
  sub    %edi,%eax
L0:
  ret
```

assistant: ```c
int checkint(uint64_t iy) {
  int e = iy >> 52 & 0x7ff;
  if (e < 0x3ff)
    return 0;
  if (e > 0x3ff + 52)
    return 2;
  if (iy & ((1ULL << (0x3ff + 52 - e)) - 1))
    return 0;
  if (iy & (1ULL << (0x3ff + 52 - e)))
    return 1;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pgheader_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_version@plt>
  and    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_variant@plt>
  and    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_predef@plt>
  and    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_number@plt>
  and    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  mov    $0x0,%eax
  jmp    L0
L13:
  mov    $0x7,%eax
L0:
  leave
  ret
```

assistant: ```c
int pgheader_test() {
  int ret;
  ret = 1;
  ret &= test_version();
  ret &= test_variant();
  ret &= test_predef();
  ret &= test_number();
  if (ret) {
    return 0;
  } else {
    return 7;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pgheader_test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <test_version@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <test_variant@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <test_predef@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <test_number@plt>
  and    %eax,%ebx
  and    %r12d,%ebx
  and    %ebp,%ebx
  and    $0x1,%ebx
  cmp    $0x1,%ebx
  sbb    %eax,%eax
  and    $0x7,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int pgheader_test() {
  int ret;
  ret = 1;
  ret &= test_version();
  ret &= test_variant();
  ret &= test_predef();
  ret &= test_number();
  if (ret) {
    return 0;
  } else {
    return 7;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pgheader_test>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <test_version@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <test_variant@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <test_predef@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <test_number@plt>
  and    %eax,%ebx
  and    %r12d,%ebx
  and    %ebp,%ebx
  and    $0x1,%ebx
  cmp    $0x1,%ebx
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  and    $0x7,%eax
  ret
```

assistant: ```c
int pgheader_test() {
  int ret;
  ret = 1;
  ret &= test_version();
  ret &= test_variant();
  ret &= test_predef();
  ret &= test_number();
  if (ret) {
    return 0;
  } else {
    return 7;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pgheader_test>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <test_version@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <test_variant@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <test_predef@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <test_number@plt>
  and    %eax,%ebx
  and    %r12d,%ebx
  and    %ebp,%ebx
  and    $0x1,%ebx
  cmp    $0x1,%ebx
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  and    $0x7,%eax
  ret
```

assistant: ```c
int pgheader_test() {
  int ret;
  ret = 1;
  ret &= test_version();
  ret &= test_variant();
  ret &= test_predef();
  ret &= test_number();
  if (ret) {
    return 0;
  } else {
    return 7;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<alaw_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  xorl   $0x55,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  mov    %eax,-0xc(%rbp)
  andl   $0x7f,-0x14(%rbp)
  cmpl   $0xf,-0x14(%rbp)
  jbe    L2
  mov    -0x14(%rbp),%eax
  shr    $0x4,%eax
  and    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%esi
  mov    -0x8(%rbp),%eax
  add    $0x3,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %esi,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L10
L2:
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  add    $0x8,%eax
  mov    %eax,-0x10(%rbp)
L10:
  cmpl   $0x0,-0xc(%rbp)
  jne    L28
  negl   -0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int alaw_decode(unsigned int Alawbyte) {
  static int exp_lut[8] = {0, 264, 528, 1056, 2112, 4224, 8448, 16896};
  int sign, exponent, mantissa, sample;
  Alawbyte ^= 0x55;
  sign = (Alawbyte & 0x80);
  Alawbyte &= 0x7f;
  if (Alawbyte >= 16) {
    exponent = (Alawbyte >> 4) & 0x07;
    mantissa = Alawbyte & 0x0F;
    sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  } else
    sample = (Alawbyte << 4) + 8;
  if (sign == 0)
    sample = -sample;
  return sample;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<alaw_decode>:
  endbr64
  mov    %edi,%edx
  xor    $0x55,%edx
  and    $0x80,%edi
  mov    %edx,%eax
  and    $0x7f,%eax
  test   $0x70,%dl
  je     L18
  mov    %eax,%edx
  shr    $0x4,%edx
  and    $0xf,%eax
  lea    0x3(%rdx),%ecx
  shl    %cl,%eax
  movslq %edx,%rdx
  lea    D8(%rip),%rcx
  add    (%rcx,%rdx,4),%eax
L3:
  mov    %eax,%edx
  neg    %edx
  test   %edi,%edi
  cmove  %edx,%eax
  ret
L18:
  shl    $0x4,%eax
  add    $0x8,%eax
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string

tool: 

assistant: ```c
int alaw_decode(unsigned int Alawbyte) {
  static int exp_lut[8] = {0, 264, 528, 1056, 2112, 4224, 8448, 16896};
  int sign, exponent, mantissa, sample;
  Alawbyte ^= 0x55;
  sign = (Alawbyte & 0x80);
  Alawbyte &= 0x7f;
  if (Alawbyte >= 16) {
    exponent = (Alawbyte >> 4) & 0x07;
    mantissa = Alawbyte & 0x0F;
    sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  } else
    sample = (Alawbyte << 4) + 8;
  if (sign == 0)
    sample = -sample;
  return sample;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<alaw_decode>:
  endbr64
  mov    %edi,%eax
  and    $0x80,%edi
  xor    $0x55,%eax
  mov    %eax,%edx
  and    $0x7f,%edx
  test   $0x70,%al
  je     L4
  shr    $0x4,%edx
  and    $0xf,%eax
  lea    0x3(%rdx),%ecx
  shl    %cl,%eax
  lea    D2(%rip),%rcx
  add    (%rcx,%rdx,4),%eax
  mov    %eax,%edx
  neg    %edx
  test   %edi,%edi
  cmove  %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  shl    $0x4,%edx
  lea    0x8(%rdx),%eax
  mov    %eax,%edx
  neg    %edx
  test   %edi,%edi
  cmove  %edx,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: 

assistant: ```c
int alaw_decode(unsigned int Alawbyte) {
  static int exp_lut[8] = {0, 264, 528, 1056, 2112, 4224, 8448, 16896};
  int sign, exponent, mantissa, sample;
  Alawbyte ^= 0x55;
  sign = (Alawbyte & 0x80);
  Alawbyte &= 0x7f;
  if (Alawbyte >= 16) {
    exponent = (Alawbyte >> 4) & 0x07;
    mantissa = Alawbyte & 0x0F;
    sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  } else
    sample = (Alawbyte << 4) + 8;
  if (sign == 0)
    sample = -sample;
  return sample;
}
```