user: 请从给定的汇编指令推导出C源代码：

```asm
<enable_prefetch_core2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D13(%rip),%rdi
  sub    $0x18,%rsp
  call   <puts@plt>
  cmp    $0xffffffff,%ebx
  je     L55
  mov    %ebx,0xc(%rsp)
L8:
  movabs $0x8000000000,%r12
  lea    D15(%rip),%r15
  movabs $0x2000000000,%rbp
  nopl   0x0(%rax,%rax,1)
L69:
  mov    %ebx,%edi
  call   <open_msr@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  js     L63
  mov    $0x1a0,%esi
  mov    %eax,%edi
  call   <read_msr@plt>
  mov    %r15,%rdi
  mov    %rax,%r14
  and    %r12,%rax
  cmp    $0x1,%rax
  mov    %r14,%rax
  mov    %r14,%rdx
  sbb    %esi,%esi
  and    %rbp,%rax
  and    $0xb,%esi
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x80000,%edx
  lea    0x4e(%rsi),%r9d
  mov    %ebx,%esi
  and    $0xb,%eax
  cmp    $0x1,%rdx
  mov    %r14,%rdx
  sbb    %ecx,%ecx
  and    $0x200,%edx
  lea    0x4e(%rax),%r8d
  and    $0xb,%ecx
  add    $0x4e,%ecx
  cmp    $0x1,%rdx
  sbb    %edx,%edx
  xor    %eax,%eax
  and    $0xb,%edx
  add    $0x4e,%edx
  call   <printf@plt>
  mov    $0x1a0,%esi
  mov    %r13d,%edi
  movabs $0xffffff5ffff7fdff,%rdx
  and    %r14,%rdx
  call   <write_msr@plt>
  mov    $0x1a0,%esi
  mov    %r13d,%edi
  call   <read_msr@plt>
  mov    %rax,%rdx
  and    %r12,%rdx
  cmp    $0x1,%rdx
  mov    %rax,%rdx
  sbb    %r9d,%r9d
  and    %rbp,%rdx
  and    $0xb,%r9d
  add    $0x4e,%r9d
  cmp    $0x1,%rdx
  mov    %rax,%rdx
  sbb    %r8d,%r8d
  and    $0x80000,%edx
  and    $0xb,%r8d
  add    $0x4e,%r8d
  cmp    $0x1,%rdx
  sbb    %ecx,%ecx
  and    $0xb,%ecx
  add    $0x4e,%ecx
  test   $0x2,%ah
  je     L5
  mov    %ebx,%esi
  mov    $0x4e,%edx
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    0xc(%rsp),%ebx
  jle    L69
L63:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    %ebx,%esi
  mov    $0x59,%edx
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L69
  jmp    L63
  nopl   0x0(%rax)
L55:
  movl   $0x400,0xc(%rsp)
  xor    %ebx,%ebx
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: label: D13
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string

tool: D13: Enable all prefetch

tool: D15: 	Core %d old : L2HW=%c L2ADJ=%c DCU=%c DCUIP=%c


tool: D16: 	Core %d new : L2HW=%c L2ADJ=%c DCU=%c DCUIP=%c


assistant: ```c
int enable_prefetch_core2(int core) {
  int fd;
  uint64_t result;
  int begin, end, c;
  printf("Enable all prefetch\n");
  if (core == -1) {
    begin = 0;
    end = 1024;
  } else {
    begin = core;
    end = core;
  }
  for (c = begin; c <= end; c++) {
    fd = open_msr(c);
    if (fd < 0)
      break;
    result = read_msr(fd, 0x1a0);
    printf("\tCore %d old : L2HW=%c L2ADJ=%c DCU=%c DCUIP=%c\n", c, result & (1ULL << 9) ? 'N' : 'Y', result & (1ULL << 19) ? 'N' : 'Y', result & (1ULL << 37) ? 'N' : 'Y', result & (1ULL << 39) ? 'N' : 'Y');
    result &= ~((1ULL << 9) | (1ULL << 19) | (1ULL << 37) | (1ULL << 39));
    result = write_msr(fd, 0x1a0, result);
    result = read_msr(fd, 0x1a0);
    printf("\tCore %d new : L2HW=%c L2ADJ=%c DCU=%c DCUIP=%c\n", c, result & (1ULL << 9) ? 'N' : 'Y', result & (1ULL << 19) ? 'N' : 'Y', result & (1ULL << 37) ? 'N' : 'Y', result & (1ULL << 39) ? 'N' : 'Y');
    close(fd);
  }
  return 0;
}
```