ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  subss  0x10(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  subss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L14
  sqrtss %xmm0,%xmm0
L12:
  movss  0xc(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  jp     L19
  je     L43
L19:
  comiss %xmm1,%xmm0
  ja     L13
  comiss %xmm0,%xmm1
  jbe    L72
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L14:
  call   <sqrtf@plt>
  jmp    L12
L43:
  lea    D17(%rip),%rdi
  call   <printf@plt>
L72:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L13:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string

tool: D26: %f %f %f %f %f

tool: D28: Point is inside the Circle.

tool: D17: Point is on the Circle.

tool: D34: Point is outside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  float m = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  float d = sqrtf(m);
  if (d == r) {
    printf("Point is on the Circle.");
  } else if (d > r) {
    printf("Point is outside the Circle.");
  } else if (d < r) {
    printf("Point is inside the Circle.");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D6(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  subss  0x10(%rsp),%xmm0
  subss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L53
  sqrtss %xmm0,%xmm0
L69:
  movss  0xc(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  jp     L62
  je     L25
L62:
  comiss %xmm1,%xmm0
  ja     L50
  comiss %xmm0,%xmm1
  ja     L95
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L50:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L25:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L95:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L53:
  call   <sqrtf@plt>
  jmp    L69
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D14
type: string

tool: D6: %f %f %f %f %f

tool: D26: Point is outside the Circle.

tool: D11: Point is on the Circle.

tool: D14: Point is inside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  float m = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  float d = sqrtf(m);
  if (d == r) {
    printf("Point is on the Circle.");
  } else if (d > r) {
    printf("Point is outside the Circle.");
  } else if (d < r) {
    printf("Point is inside the Circle.");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  subss  0x10(%rsp),%xmm0
  subss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L53
  sqrtss %xmm0,%xmm0
L49:
  movss  0xc(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  jp     L52
  je     L31
L52:
  comiss %xmm1,%xmm0
  ja     L21
  comiss %xmm0,%xmm1
  ja     L15
L72:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L21:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L31:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L15:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L53:
  call   <sqrtf@plt>
  jmp    L49
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string

tool: D7: %f %f %f %f %f

tool: D38: Point is outside the Circle.

tool: D8: Point is on the Circle.

tool: D13: Point is inside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  float m = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  float d = sqrtf(m);
  if (d == r) {
    printf("Point is on the Circle.");
  } else if (d > r) {
    printf("Point is outside the Circle.");
  } else if (d < r) {
    printf("Point is inside the Circle.");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn4(int a, int b) {
  int tem1 = b & a;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn4>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn4(int a, int b) {
  int tem1 = b & a;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn4>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn4(int a, int b) {
  int tem1 = b & a;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<equal_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x1,%eax
  jmp    L7
L4:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *cs1 = (char *)s1;
  char *cs2 = (char *)s2;
  if (strcmp(cs1, cs2) == 0) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<equal_string>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *cs1 = (char *)s1;
  char *cs2 = (char *)s2;
  if (strcmp(cs1, cs2) == 0) {
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<equal_string>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *cs1 = (char *)s1;
  char *cs2 = (char *)s2;
  if (strcmp(cs1, cs2) == 0) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<equal_string>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *cs1 = (char *)s1;
  char *cs2 = (char *)s2;
  if (strcmp(cs1, cs2) == 0) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pca_cmp_matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int pca_cmp_matches(const void *v1, const void *v2) {
  const char **s1 = (const char **)v1;
  const char **s2 = (const char **)v2;
  return strcmp(*s1 + 1, *s2 + 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pca_cmp_matches>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  add    $0x1,%rsi
  mov    (%rdi),%rdi
  add    $0x1,%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pca_cmp_matches(const void *v1, const void *v2) {
  const char **s1 = (const char **)v1;
  const char **s2 = (const char **)v2;
  return strcmp(*s1 + 1, *s2 + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<pca_cmp_matches>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  add    $0x1,%rsi
  add    $0x1,%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int pca_cmp_matches(const void *v1, const void *v2) {
  const char **s1 = (const char **)v1;
  const char **s2 = (const char **)v2;
  return strcmp(*s1 + 1, *s2 + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_cp_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L26
L39:
  addq   $0x1,-0x10(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  je     L27
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  jmp    L8
L27:
  mov    $0x0,%eax
L8:
  mov    -0x10(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *str_cp_max(size_t n, char *dst, const char *src) {
  while ((*dst = n-- ? *src++ : '\0'))
    ++dst;
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_cp_max>:
  endbr64
  mov    %rsi,%rax
  add    %rdx,%rdi
  jmp    L13
L11:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  je     L25
  add    $0x1,%rax
L13:
  cmp    %rdi,%rdx
  jne    L11
  movb   $0x0,(%rax)
  ret
L25:
  ret
```

assistant: ```c
char *str_cp_max(size_t n, char *dst, const char *src) {
  while ((*dst = n-- ? *src++ : '\0'))
    ++dst;
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_cp_max>:
  endbr64
  lea    (%rsi,%rdi,1),%r8
  test   %rdi,%rdi
  je     L39
  nopl   (%rax)
L4:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  mov    %al,(%rsi)
  test   %al,%al
  je     L27
  add    $0x1,%rsi
  cmp    %rsi,%r8
  jne    L4
L22:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L39:
  mov    %rsi,%r8
  jmp    L22
  nopl   (%rax)
L27:
  mov    %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *str_cp_max(size_t n, char *dst, const char *src) {
  while ((*dst = n-- ? *src++ : '\0'))
    ++dst;
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_cp_max>:
  endbr64
  lea    (%rsi,%rdi,1),%r8
  test   %rdi,%rdi
  je     L35
  nopl   (%rax)
L39:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  mov    %al,(%rsi)
  test   %al,%al
  je     L22
  add    $0x1,%rsi
  cmp    %rsi,%r8
  jne    L39
L37:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L35:
  mov    %rsi,%r8
  jmp    L37
  nopl   (%rax)
L22:
  mov    %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *str_cp_max(size_t n, char *dst, const char *src) {
  while ((*dst = n-- ? *src++ : '\0'))
    ++dst;
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<update_titleline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <do_update_titleline@plt>
  mov    $0x0,%eax
  call   <post_update@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_titleline(void) {
  curs_set(0);
  do_update_titleline();
  post_update();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_titleline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <do_update_titleline@plt>
  mov    $0x0,%eax
  call   <post_update@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void update_titleline(void) {
  curs_set(0);
  do_update_titleline();
  post_update();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<update_titleline>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <curs_set@plt>
  xor    %eax,%eax
  call   <do_update_titleline@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <post_update@plt>
```

assistant: ```c
void update_titleline(void) {
  curs_set(0);
  do_update_titleline();
  post_update();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<update_titleline>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <curs_set@plt>
  xor    %eax,%eax
  call   <do_update_titleline@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <post_update@plt>
```

assistant: ```c
void update_titleline(void) {
  curs_set(0);
  do_update_titleline();
  post_update();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L9:
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L9
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D9
datatype: string

tool: D17: %lld

tool: D9: %d


assistant: ```c
int main() {
  long long N;
  scanf("%lld", &N);
  int count = 0;
  while (N) {
    count += N / 5;
    N /= 5;
  }
  printf("%d\n", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  test   %rcx,%rcx
  je     L0
  mov    $0x0,%esi
  movabs $0x6666666666666667,%rdi
L26:
  mov    %rcx,%rax
  imul   %rdi
  sar    %rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  mov    %rdx,%rcx
  add    %edx,%esi
  test   %rdx,%rdx
  jne    L26
  movq   $0x0,(%rsp)
L32:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  mov    $0x0,%esi
  jmp    L32
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D13: %lld

tool: D18: %d


assistant: ```c
int main() {
  long long N;
  scanf("%lld", &N);
  int count = 0;
  while (N) {
    count += N / 5;
    N /= 5;
  }
  printf("%d\n", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  xor    %esi,%esi
  test   %rcx,%rcx
  je     L28
  movabs $0x6666666666666667,%rdi
  nopl   0x0(%rax)
L18:
  mov    %rcx,%rax
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  mov    %rdx,%rcx
  add    %edx,%esi
  test   %rdx,%rdx
  jne    L18
  movq   $0x0,(%rsp)
L28:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D15: %lld

tool: D14: %d


assistant: ```c
int main() {
  long long N;
  scanf("%lld", &N);
  int count = 0;
  while (N) {
    count += N / 5;
    N /= 5;
  }
  printf("%d\n", count);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  xor    %esi,%esi
  test   %rcx,%rcx
  je     L26
  movabs $0x6666666666666667,%rdi
  nopl   0x0(%rax)
L24:
  mov    %rcx,%rax
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  mov    %rdx,%rcx
  add    %edx,%esi
  test   %rdx,%rdx
  jne    L24
  movq   $0x0,(%rsp)
L26:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D4: %lld

tool: D15: %d


assistant: ```c
int main() {
  long long N;
  scanf("%lld", &N);
  int count = 0;
  while (N) {
    count += N / 5;
    N /= 5;
  }
  printf("%d\n", count);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rcx,%rbp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x18(%rsp)
  xor    %ecx,%ecx
  mov    %rsp,%rcx
  lea    0xf(%rsp),%rsi
L33:
  movb   $0x20,(%rcx)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L33
  movb   $0x0,0xf(%rsp)
  test   %rax,%rax
  jns    L32
  mov    $0xffffffffffffffff,%r10
  cmp    $0xa,%edx
  jne    L32
L102:
  imul   %r10,%rax
  mov    $0xe,%ebx
  movslq %edx,%rsi
  mov    $0xf,%r11d
  jmp    L27
L32:
  mov    $0x1,%r10d
  jmp    L102
L132:
  sub    $0x1,%rbx
  cmp    $0xffffffffffffffff,%rbx
  je     L44
L27:
  mov    %rax,%r8
  mov    $0x0,%edx
  div    %rsi
  lea    0x30(%rdx),%r9d
  lea    0x57(%rdx),%ecx
  cmp    $0x9,%rdx
  cmovle %r9d,%ecx
  mov    %cl,(%rsp,%rbx,1)
  cmp    %r8,%rsi
  jbe    L132
  mov    %r11,%rdx
  sub    %rbx,%rdx
  cmp    %rdx,0x0(%rbp)
  jg     L132
L44:
  cmp    $0xffffffffffffffff,%r10
  je     L104
L18:
  mov    0x0(%rbp),%rax
  test   %rax,%rax
  je     L25
  mov    $0xf,%edx
  sub    %rbx,%rdx
  cmp    %rdx,%rax
  jge    L84
L25:
  lea    (%rsp,%rbx,1),%rsi
  call   <strcpy2@plt>
  mov    $0xf,%eax
  sub    %rbx,%rax
  mov    %rax,0x0(%rbp)
L66:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L104:
  sub    $0x1,%rbx
  movb   $0x2d,(%rsp,%rbx,1)
  jmp    L18
L84:
  mov    $0xf,%edx
  sub    %rax,%rdx
  lea    (%rsp,%rdx,1),%rsi
  call   <strcpy2@plt>
  jmp    L66
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa2(long n, char *s, int base, long *digits) {
  long i, j, sign;
  unsigned long n2;
  char number[20];
  for (i = 0; i < 15; ++i) {
    number[i] = ' ';
  }
  number[15] = 0;
  if (n >= 0 || base != 10) {
    sign = 1;
  } else {
    sign = -1;
  }
  n2 = n * sign;
  for (j = 14; j >= 0; --j) {
    i = n2 % base;
    n2 /= base;
    number[j] = i < 10 ? '0' + i : 'a' + i - 10;
    if (n2 == 0 && 15 - j >= *digits)
      break;
  }
  if (sign == -1) {
    number[--j] = '-';
  }
  if (*digits == 0 || *digits < 15 - j) {
    strcpy2(s, &number[j]);
    *digits = 15 - j;
  } else {
    strcpy2(s, &number[15 - *digits]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa2>:
  endbr64
  push   %r13
  mov    %rdi,%rax
  mov    %rsi,%r10
  movabs $0x2020202020202020,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x18(%rsp)
  xor    %ecx,%ecx
  mov    $0x2020,%ecx
  mov    %rdi,(%rsp)
  movl   $0x20202020,0x8(%rsp)
  mov    %cx,0xc(%rsp)
  movb   $0x20,0xe(%rsp)
  movb   $0x0,0xf(%rsp)
  test   %rax,%rax
  jns    L41
  cmp    $0xa,%edx
  jne    L41
  neg    %rax
  mov    $0xffffffffffffffff,%r12
L11:
  mov    (%rbx),%r11
  movslq %edx,%rdi
  mov    $0xe,%esi
  mov    %rsp,%r9
  mov    $0xf,%ebp
L73:
  xor    %edx,%edx
  mov    %rax,%r8
  div    %rdi
  lea    0x30(%rdx),%r13d
  lea    0x57(%rdx),%ecx
  cmp    $0x9,%rdx
  cmovle %r13d,%ecx
  mov    %cl,(%r9,%rsi,1)
  cmp    %r8,%rdi
  jbe    L36
  mov    %rbp,%rdx
  sub    %rsi,%rdx
  cmp    %rdx,%r11
  jle    L67
L36:
  sub    $0x1,%rsi
  jae    L73
L67:
  cmp    $0xffffffffffffffff,%r12
  jne    L92
  sub    $0x1,%rsi
  movb   $0x2d,(%rsp,%rsi,1)
L92:
  mov    $0xf,%eax
  mov    %rax,%rbp
  sub    %rsi,%rbp
  test   %r11,%r11
  je     L39
  cmp    %rbp,%r11
  jge    L38
L39:
  add    %r9,%rsi
  mov    %r10,%rdi
  call   <strcpy2@plt>
  mov    %rbp,(%rbx)
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L41:
  mov    $0x1,%r12d
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L38:
  sub    %r11,%rax
  mov    %r10,%rdi
  lea    (%r9,%rax,1),%rsi
  call   <strcpy2@plt>
  jmp    L17
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa2(long n, char *s, int base, long *digits) {
  long i, j, sign;
  unsigned long n2;
  char number[20];
  for (i = 0; i < 15; ++i) {
    number[i] = ' ';
  }
  number[15] = 0;
  if (n >= 0 || base != 10) {
    sign = 1;
  } else {
    sign = -1;
  }
  n2 = n * sign;
  for (j = 14; j >= 0; --j) {
    i = n2 % base;
    n2 /= base;
    number[j] = i < 10 ? '0' + i : 'a' + i - 10;
    if (n2 == 0 && 15 - j >= *digits)
      break;
  }
  if (sign == -1) {
    number[--j] = '-';
  }
  if (*digits == 0 || *digits < 15 - j) {
    strcpy2(s, &number[j]);
    *digits = 15 - j;
  } else {
    strcpy2(s, &number[15 - *digits]);
  }
}
```