ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<fcitx_utils_set_str_with_len>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rdx),%rsi
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L8
  call   <fcitx_utils_realloc@plt>
  mov    %rax,%r12
L0:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rsi,%rdi
  call   <fcitx_utils_malloc@plt>
  mov    %rax,%r12
  jmp    L0
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_set_str_with_len(char *res, const char *str, size_t len) {
  if (res) {
    res = fcitx_utils_realloc(res, len + 1);
  } else {
    res = fcitx_utils_malloc(len + 1);
  }
  memcpy(res, str, len);
  res[len] = '\0';
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fcitx_utils_set_str_with_len>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rdx),%rsi
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L13
  call   <fcitx_utils_realloc@plt>
  mov    %rax,%r12
L4:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rsi,%rdi
  call   <fcitx_utils_malloc@plt>
  mov    %rax,%r12
  jmp    L4
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_set_str_with_len(char *res, const char *str, size_t len) {
  if (res) {
    res = fcitx_utils_realloc(res, len + 1);
  } else {
    res = fcitx_utils_malloc(len + 1);
  }
  memcpy(res, str, len);
  res[len] = '\0';
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strcf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L16
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  jmp    L15
L16:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    $0xffffffff,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcf(char *str, char c) {
  int i;
  i = -1;
  while (*(str + (++i))) {
    if (*(str + i) == c)
      return (i);
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strcf>:
  endbr64
  mov    $0x0,%eax
L15:
  mov    %eax,%ecx
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L24
  add    $0x1,%rax
  cmp    %sil,%dl
  jne    L15
  jmp    L10
L24:
  mov    $0xffffffff,%ecx
L10:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int ft_strcf(char *str, char c) {
  int i;
  i = -1;
  while (*(str + (++i))) {
    if (*(str + i) == c)
      return (i);
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strcf>:
  endbr64
  xor    %eax,%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  cmp    %sil,%dl
  je     L27
L28:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  test   %dl,%dl
  jne    L6
  mov    $0xffffffff,%r8d
L27:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strcf(char *str, char c) {
  int i;
  i = -1;
  while (*(str + (++i))) {
    if (*(str + i) == c)
      return (i);
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strcf>:
  endbr64
  xor    %eax,%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rax
  cmp    %sil,%dl
  je     L16
L28:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  test   %dl,%dl
  jne    L25
  mov    $0xffffffff,%r8d
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strcf(char *str, char c) {
  int i;
  i = -1;
  while (*(str + (++i))) {
    if (*(str + i) == c)
      return (i);
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<latex_output_indented_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %rdi,-0x1a8(%rbp)
  mov    %rsi,-0x1b0(%rbp)
  mov    %rdx,-0x1b8(%rbp)
  mov    %rcx,-0x1c0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x1c0(%rbp),%rcx
  lea    -0xa0(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <latex_escape_data@plt>
  mov    %rax,%r12
  mov    -0x1b8(%rbp),%rcx
  lea    -0x120(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <latex_escape_data@plt>
  mov    %rax,%rbx
  mov    -0x1b0(%rbp),%rcx
  lea    -0x1a0(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <latex_escape_data@plt>
  mov    %rax,%rdx
  mov    -0x1a8(%rbp),%rax
  mov    %r12,%r8
  mov    %rbx,%rcx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: \begin{tabular}{p{0.5in}l}
& %s\\
& %s\\
& %s
\end{tabular}



assistant: ```c
void latex_output_indented_address(FILE *output_stream, char *full_name, char *street_address, char *city_state_zip) {
  char full_name_buffer[128];
  char street_address_buffer[128];
  char city_state_zip_buffer[128];
  fprintf(output_stream,
          "\\begin{tabular}{p{0.5in}l}\n"
          "& %s\\\\\n"
          "& %s\\\\\n"
          "& %s\n"
          "\\end{tabular}\n\n",
          latex_escape_data(full_name_buffer, full_name, 128), latex_escape_data(street_address_buffer, street_address, 128), latex_escape_data(city_state_zip_buffer, city_state_zip, 128));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<latex_output_indented_address>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x198,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rcx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  lea    0x100(%rsp),%rdi
  mov    $0x80,%edx
  call   <latex_escape_data@plt>
  mov    %rax,%r12
  lea    0x80(%rsp),%rdi
  mov    $0x80,%edx
  mov    %rbp,%rsi
  call   <latex_escape_data@plt>
  mov    %rax,%rbp
  mov    %rsp,%rdi
  mov    $0x80,%edx
  mov    %r13,%rsi
  call   <latex_escape_data@plt>
  mov    %rax,%rdx
  mov    %r12,%r8
  mov    %rbp,%rcx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x198,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: \begin{tabular}{p{0.5in}l}
& %s\\
& %s\\
& %s
\end{tabular}



assistant: ```c
void latex_output_indented_address(FILE *output_stream, char *full_name, char *street_address, char *city_state_zip) {
  char full_name_buffer[128];
  char street_address_buffer[128];
  char city_state_zip_buffer[128];
  fprintf(output_stream,
          "\\begin{tabular}{p{0.5in}l}\n"
          "& %s\\\\\n"
          "& %s\\\\\n"
          "& %s\n"
          "\\end{tabular}\n\n",
          latex_escape_data(full_name_buffer, full_name, 128), latex_escape_data(street_address_buffer, street_address, 128), latex_escape_data(city_state_zip_buffer, city_state_zip, 128));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<latex_output_indented_address>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rcx,%rsi
  push   %r12
  mov    %rdx,%r12
  mov    $0x80,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x198,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  lea    0x100(%rsp),%rdi
  call   <latex_escape_data@plt>
  mov    %r12,%rsi
  mov    $0x80,%edx
  lea    0x80(%rsp),%rdi
  mov    %rax,%rbx
  call   <latex_escape_data@plt>
  mov    %rsp,%rdi
  mov    $0x80,%edx
  mov    %r13,%rsi
  mov    %rax,%r12
  call   <latex_escape_data@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    %rax,%rdx
  lea    D9(%rip),%rsi
  call   <fprintf@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x198,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: \begin{tabular}{p{0.5in}l}
& %s\\
& %s\\
& %s
\end{tabular}



assistant: ```c
void latex_output_indented_address(FILE *output_stream, char *full_name, char *street_address, char *city_state_zip) {
  char full_name_buffer[128];
  char street_address_buffer[128];
  char city_state_zip_buffer[128];
  fprintf(output_stream,
          "\\begin{tabular}{p{0.5in}l}\n"
          "& %s\\\\\n"
          "& %s\\\\\n"
          "& %s\n"
          "\\end{tabular}\n\n",
          latex_escape_data(full_name_buffer, full_name, 128), latex_escape_data(street_address_buffer, street_address, 128), latex_escape_data(city_state_zip_buffer, city_state_zip, 128));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<latex_output_indented_address>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rcx,%rsi
  push   %r12
  mov    %rdx,%r12
  mov    $0x80,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x198,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  lea    0x100(%rsp),%rdi
  call   <latex_escape_data@plt>
  mov    %r12,%rsi
  mov    $0x80,%edx
  lea    0x80(%rsp),%rdi
  mov    %rax,%rbx
  call   <latex_escape_data@plt>
  mov    %rsp,%rdi
  mov    $0x80,%edx
  mov    %r13,%rsi
  mov    %rax,%r12
  call   <latex_escape_data@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    %rax,%rdx
  lea    D0(%rip),%rsi
  call   <fprintf@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x198,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: \begin{tabular}{p{0.5in}l}
& %s\\
& %s\\
& %s
\end{tabular}



assistant: ```c
void latex_output_indented_address(FILE *output_stream, char *full_name, char *street_address, char *city_state_zip) {
  char full_name_buffer[128];
  char street_address_buffer[128];
  char city_state_zip_buffer[128];
  fprintf(output_stream,
          "\\begin{tabular}{p{0.5in}l}\n"
          "& %s\\\\\n"
          "& %s\\\\\n"
          "& %s\n"
          "\\end{tabular}\n\n",
          latex_escape_data(full_name_buffer, full_name, 128), latex_escape_data(street_address_buffer, street_address, 128), latex_escape_data(city_state_zip_buffer, city_state_zip, 128));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_02>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x14(%rbp),%eax
  jmp    L21
L0:
  mov    -0x18(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int test_02(unsigned char *a, unsigned char *b, int c, int d) {
  if (*a != 0 && *b == 0)
    return c;
  return d;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_02>:
  endbr64
  mov    %ecx,%eax
  cmpb   $0x0,(%rdi)
  je     L8
  cmpb   $0x0,(%rsi)
  cmove  %edx,%eax
L8:
  ret
```

assistant: ```c
int test_02(unsigned char *a, unsigned char *b, int c, int d) {
  if (*a != 0 && *b == 0)
    return c;
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_02>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %ecx,%eax
  je     L2
  cmpb   $0x0,(%rsi)
  cmove  %edx,%eax
L2:
  ret
```

assistant: ```c
int test_02(unsigned char *a, unsigned char *b, int c, int d) {
  if (*a != 0 && *b == 0)
    return c;
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_02>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %ecx,%eax
  je     L1
  cmpb   $0x0,(%rsi)
  cmove  %edx,%eax
L1:
  ret
```

assistant: ```c
int test_02(unsigned char *a, unsigned char *b, int c, int d) {
  if (*a != 0 && *b == 0)
    return c;
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_indexof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L32
  mov    $0xffffffff,%eax
  jmp    L51
L32:
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L4:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L49
  mov    -0xc(%rbp),%eax
  jmp    L51
L49:
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L4
  mov    $0xffffffff,%eax
L51:
  leave
  ret
```

assistant: ```c
int str_indexof(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  int hlen = (int)strlen(haystack);
  int nlen = (int)strlen(needle);
  if (nlen > hlen)
    return -1;
  for (int i = 0; i <= hlen - nlen; i++) {
    if (!strncmp(&haystack[i], needle, nlen))
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_indexof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r13,%r13
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebp
  jl     L32
  mov    %eax,%r15d
  sub    %eax,%ebp
  mov    $0x0,%ebx
L25:
  mov    %ebx,%r14d
  lea    (%r12,%rbx,1),%rdi
  mov    %r15d,%edx
  mov    %r13,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L33
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L25
  mov    $0xffffffff,%r14d
L33:
  mov    %r14d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0xffffffff,%r14d
  jmp    L33
```

assistant: ```c
int str_indexof(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  int hlen = (int)strlen(haystack);
  int nlen = (int)strlen(needle);
  if (nlen > hlen)
    return -1;
  for (int i = 0; i <= hlen - nlen; i++) {
    if (!strncmp(&haystack[i], needle, nlen))
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_indexof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jl     L37
  mov    %eax,%r15d
  sub    %eax,%ebp
  xor    %ebx,%ebx
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L37
L21:
  lea    (%r12,%rbx,1),%rdi
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %ebx,%r14d
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L10
L42:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    $0xffffffff,%r14d
  jmp    L42
```

assistant: ```c
int str_indexof(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  int hlen = (int)strlen(haystack);
  int nlen = (int)strlen(needle);
  if (nlen > hlen)
    return -1;
  for (int i = 0; i <= hlen - nlen; i++) {
    if (!strncmp(&haystack[i], needle, nlen))
      return i;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_indexof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jl     L26
  mov    %eax,%r15d
  sub    %eax,%ebp
  xor    %ebx,%ebx
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L26
L8:
  lea    (%r12,%rbx,1),%rdi
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %ebx,%r14d
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L10
L5:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  mov    $0xffffffff,%r14d
  jmp    L5
```

assistant: ```c
int str_indexof(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  int hlen = (int)strlen(haystack);
  int nlen = (int)strlen(needle);
  if (nlen > hlen)
    return -1;
  for (int i = 0; i <= hlen - nlen; i++) {
    if (!strncmp(&haystack[i], needle, nlen))
      return i;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <instructionCycles@plt>
  mov    $0x0,%eax
  call   <displayRegisters@plt>
  nop
  leave
  ret
```

assistant: ```c
void trace(void *memptr) {
  instructionCycles(&memptr);
  displayRegisters();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trace>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <instructionCycles@plt>
  mov    $0x0,%eax
  call   <displayRegisters@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void trace(void *memptr) {
  instructionCycles(&memptr);
  displayRegisters();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trace>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <instructionCycles@plt>
  xor    %eax,%eax
  call   <displayRegisters@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void trace(void *memptr) {
  instructionCycles(&memptr);
  displayRegisters();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trace>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <instructionCycles@plt>
  xor    %eax,%eax
  call   <displayRegisters@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void trace(void *memptr) {
  instructionCycles(&memptr);
  displayRegisters();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fmt_u32_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x1,-0x18(%rbp)
  cmpq   $0x3b9ac9ff,-0x30(%rbp)
  jbe    L8
  movq   $0xa,-0x18(%rbp)
  jmp    L1
L8:
  movq   $0xa,-0x10(%rbp)
  jmp    L23
L58:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jbe    L58
L1:
  cmpq   $0x0,-0x28(%rbp)
  je     L9
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L49:
  mov    -0x30(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x30(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L49
L9:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t fmt_u32_dec(char *out, uint32_t val) {
  size_t len = 1;
  if (val >= 1000000000ul) {
    len = 10;
  } else {
    for (uint32_t tmp = 10; tmp <= val; len++) {
      tmp *= 10;
    }
  }
  if (out) {
    char *ptr = out + len;
    do {
      *--ptr = (val % 10) + '0';
    } while ((val /= 10));
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fmt_u32_dec>:
  endbr64
  mov    %rsi,%rcx
  mov    $0xa,%r8d
  cmp    $0x3b9ac9ff,%rsi
  ja     L32
  cmp    $0x9,%rsi
  jbe    L49
  mov    $0xa,%edx
  mov    $0x1,%r8d
L4:
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rax,%rdx
  add    $0x1,%r8
  cmp    %rax,%rcx
  jae    L4
L32:
  test   %rdi,%rdi
  je     L10
  add    %r8,%rdi
  movabs $0xcccccccccccccccd,%r9
L17:
  sub    $0x1,%rdi
  mov    %rcx,%rax
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  mov    %rcx,%rax
  sub    %rsi,%rax
  add    $0x30,%eax
  mov    %al,(%rdi)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  ja     L17
L10:
  mov    %r8,%rax
  ret
L49:
  mov    $0x1,%r8d
  jmp    L32
```

assistant: ```c
size_t fmt_u32_dec(char *out, uint32_t val) {
  size_t len = 1;
  if (val >= 1000000000ul) {
    len = 10;
  } else {
    for (uint32_t tmp = 10; tmp <= val; len++) {
      tmp *= 10;
    }
  }
  if (out) {
    char *ptr = out + len;
    do {
      *--ptr = (val % 10) + '0';
    } while ((val /= 10));
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fmt_u32_dec>:
  endbr64
  mov    %rsi,%rcx
  mov    $0xa,%r8d
  cmp    $0x3b9ac9ff,%rsi
  ja     L27
  cmp    $0x9,%rsi
  jbe    L11
  mov    $0xa,%eax
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L45:
  lea    (%rax,%rax,4),%rax
  add    $0x1,%r8
  add    %rax,%rax
  cmp    %rax,%rcx
  jae    L45
L27:
  test   %rdi,%rdi
  je     L37
  movabs $0xcccccccccccccccd,%r9
  add    %r8,%rdi
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rcx,%rax
  sub    $0x1,%rdi
  mul    %r9
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  add    $0x30,%eax
  mov    %al,(%rdi)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  ja     L14
L37:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%r8d
  jmp    L27
```

assistant: ```c
size_t fmt_u32_dec(char *out, uint32_t val) {
  size_t len = 1;
  if (val >= 1000000000ul) {
    len = 10;
  } else {
    for (uint32_t tmp = 10; tmp <= val; len++) {
      tmp *= 10;
    }
  }
  if (out) {
    char *ptr = out + len;
    do {
      *--ptr = (val % 10) + '0';
    } while ((val /= 10));
  }
  return len;
}
```