ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<cycleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L4
L109:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L18:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L72:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L65
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jge    L65
  addl   $0x1,-0x10(%rbp)
L65:
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  jg     L72
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L96
  jmp    L30
L40:
  addl   $0x1,-0x10(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L12
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L40
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L96:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L18
  addl   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  jg     L109
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cycleSort(long array[], long n) {
  int i, j, k, temp, item, pos;
  for (i = 0; i < n; i++) {
    item = array[i];
    pos = i;
    do {
      k = 0;
      for (j = 0; j < n; j++) {
        if (pos != j && array[j] < item)
          k++;
      }
      if (pos != k) {
        while (pos != k && item == array[k])
          k++;
        temp = array[k];
        array[k] = item;
        item = temp;
        pos = k;
      }
    } while (pos != i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cycleSort>:
  endbr64
  mov    %rdi,%r8
  test   %rsi,%rsi
  jle    L129
  mov    $0x0,%r10d
  jmp    L35
L26:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L32
L125:
  cmp    %eax,%ecx
  je     L26
  cmp    %rdi,(%r8,%rax,8)
  jge    L26
  add    $0x1,%edx
  jmp    L26
L32:
  cmp    %ecx,%edx
  jne    L21
L120:
  cmp    %r10d,%ecx
  je     L71
L142:
  mov    $0x0,%eax
  mov    $0x0,%edx
  movslq %r9d,%rdi
  jmp    L125
L21:
  movslq %edx,%rax
  lea    (%r8,%rax,8),%rax
  movslq %r9d,%rdi
L124:
  cmp    (%rax),%rdi
  jne    L109
  add    $0x1,%edx
  add    $0x8,%rax
  cmp    %edx,%ecx
  jne    L124
  mov    %edx,%ecx
  jmp    L76
L109:
  mov    %edx,%ecx
L76:
  movslq %ecx,%rax
  lea    (%r8,%rax,8),%rax
  mov    (%rax),%r9d
  mov    %rdi,(%rax)
  jmp    L120
L71:
  add    $0x1,%r10
  cmp    %rsi,%r10
  je     L129
L35:
  mov    %r10d,%ecx
  mov    (%r8,%r10,8),%r9d
  jmp    L142
L129:
  ret
```

assistant: ```c
void cycleSort(long array[], long n) {
  int i, j, k, temp, item, pos;
  for (i = 0; i < n; i++) {
    item = array[i];
    pos = i;
    do {
      k = 0;
      for (j = 0; j < n; j++) {
        if (pos != j && array[j] < item)
          k++;
      }
      if (pos != k) {
        while (pos != k && item == array[k])
          k++;
        temp = array[k];
        array[k] = item;
        item = temp;
        pos = k;
      }
    } while (pos != i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cycleSort>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r8
  xor    %r11d,%r11d
  test   %rsi,%rsi
  jle    L21
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    (%r10,%r11,8),%edi
  mov    %r11d,%esi
  nopw   0x0(%rax,%rax,1)
L105:
  xor    %eax,%eax
  xor    %ecx,%ecx
  movslq %edi,%r9
  jmp    L107
  nopl   0x0(%rax)
L110:
  mov    %rdx,%rax
L107:
  cmp    %eax,%esi
  je     L125
  cmp    %r9,(%r10,%rax,8)
  jge    L125
  add    $0x1,%ecx
L125:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%r8
  jne    L110
  cmp    %esi,%ecx
  jne    L18
L33:
  cmp    %r11d,%esi
  jne    L105
  lea    0x1(%r11),%rdx
  cmp    %r11,%rax
  je     L120
  mov    %rdx,%r11
  jmp    L9
L18:
  movslq %ecx,%rdx
  movslq %edi,%r9
  lea    (%r10,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rdx),%rdi
  cmp    %r9,%rdi
  jne    L15
  add    $0x1,%ecx
  add    $0x8,%rdx
  cmp    %ecx,%esi
  jne    L1
  movslq %esi,%rdx
  lea    (%r10,%rdx,8),%rdx
  mov    (%rdx),%rdi
L122:
  mov    %r9,(%rdx)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ecx,%esi
  jmp    L122
L120:
  ret
L21:
  ret
```

assistant: ```c
void cycleSort(long array[], long n) {
  int i, j, k, temp, item, pos;
  for (i = 0; i < n; i++) {
    item = array[i];
    pos = i;
    do {
      k = 0;
      for (j = 0; j < n; j++) {
        if (pos != j && array[j] < item)
          k++;
      }
      if (pos != k) {
        while (pos != k && item == array[k])
          k++;
        temp = array[k];
        array[k] = item;
        item = temp;
        pos = k;
      }
    } while (pos != i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cycleSort>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r8
  xor    %r11d,%r11d
  test   %rsi,%rsi
  jle    L74
  cs nopw 0x0(%rax,%rax,1)
L73:
  mov    (%r10,%r11,8),%edi
  mov    %r11d,%esi
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  xor    %ecx,%ecx
  movslq %edi,%r9
  jmp    L38
  nopl   0x0(%rax)
L32:
  mov    %rdx,%rax
L38:
  cmp    %eax,%esi
  je     L69
  cmp    %r9,(%r10,%rax,8)
  jge    L69
  add    $0x1,%ecx
L69:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%r8
  jne    L32
  cmp    %esi,%ecx
  jne    L91
L77:
  cmp    %r11d,%esi
  jne    L33
  lea    0x1(%r11),%rdx
  cmp    %rax,%r11
  je     L124
  mov    %rdx,%r11
  jmp    L73
L91:
  movslq %ecx,%rdx
  movslq %edi,%r9
  lea    (%r10,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    (%rdx),%rdi
  cmp    %r9,%rdi
  jne    L31
  add    $0x1,%ecx
  add    $0x8,%rdx
  cmp    %ecx,%esi
  jne    L36
  movslq %esi,%rdx
  lea    (%r10,%rdx,8),%rdx
  mov    (%rdx),%rdi
L56:
  mov    %r9,(%rdx)
  jmp    L77
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %ecx,%esi
  jmp    L56
L124:
  ret
L74:
  ret
```

assistant: ```c
void cycleSort(long array[], long n) {
  int i, j, k, temp, item, pos;
  for (i = 0; i < n; i++) {
    item = array[i];
    pos = i;
    do {
      k = 0;
      for (j = 0; j < n; j++) {
        if (pos != j && array[j] < item)
          k++;
      }
      if (pos != k) {
        while (pos != k && item == array[k])
          k++;
        temp = array[k];
        array[k] = item;
        item = temp;
        pos = k;
      }
    } while (pos != i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x41,-0x1(%rbp)
  movsbl -0x1(%rbp),%edx
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: The code for %c is %i.


assistant: ```c
int main(void) {
  char ch;
  ch = 'A';
  printf("The code for %c is %i.\n", ch, ch);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edx
  mov    $0x41,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: The code for %c is %i.


assistant: ```c
int main(void) {
  char ch;
  ch = 'A';
  printf("The code for %c is %i.\n", ch, ch);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edx
  mov    $0x41,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: The code for %c is %i.


assistant: ```c
int main(void) {
  char ch;
  ch = 'A';
  printf("The code for %c is %i.\n", ch, ch);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edx
  mov    $0x41,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8: The code for %c is %i.


assistant: ```c
int main(void) {
  char ch;
  ch = 'A';
  printf("The code for %c is %i.\n", ch, ch);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x61,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *p;
  printf("\n [%c]\n", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  movb   $0x61,(%rax)
  mov    $0x61,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *p;
  printf("\n [%c]\n", c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    $0x61,%esi
  lea    D5(%rip),%rdi
  movb   $0x61,(%rax)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *p;
  printf("\n [%c]\n", c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    $0x61,%esi
  lea    D7(%rip),%rdi
  movb   $0x61,(%rax)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *p;
  printf("\n [%c]\n", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<zh_nstr_time33>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zh_nstr_time33(unsigned int type, const char *key, unsigned int key_len) {
  unsigned int i = 0;
  unsigned int hash = type;
  for (i = 0; i < key_len; ++i) {
    hash = hash * 33 + key[i];
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zh_nstr_time33>:
  endbr64
  mov    %edi,%eax
  test   %edx,%edx
  je     L1
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%edx
  lea    0x1(%rsi,%rdx,1),%rsi
L3:
  mov    %eax,%edx
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl (%rcx),%edx
  add    %edx,%eax
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L3
L1:
  ret
```

assistant: ```c
unsigned int zh_nstr_time33(unsigned int type, const char *key, unsigned int key_len) {
  unsigned int i = 0;
  unsigned int hash = type;
  for (i = 0; i < key_len; ++i) {
    hash = hash * 33 + key[i];
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zh_nstr_time33>:
  endbr64
  mov    %edi,%eax
  test   %edx,%edx
  je     L18
  sub    $0x1,%edx
  lea    0x1(%rsi,%rdx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %eax,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl -0x1(%rsi),%edx
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L19
L18:
  ret
```

assistant: ```c
unsigned int zh_nstr_time33(unsigned int type, const char *key, unsigned int key_len) {
  unsigned int i = 0;
  unsigned int hash = type;
  for (i = 0; i < key_len; ++i) {
    hash = hash * 33 + key[i];
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zh_nstr_time33>:
  endbr64
  mov    %edi,%eax
  test   %edx,%edx
  je     L6
  sub    $0x1,%edx
  lea    0x1(%rsi,%rdx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %eax,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl -0x1(%rsi),%edx
  add    %edx,%eax
  cmp    %rsi,%rcx
  jne    L18
L6:
  ret
```

assistant: ```c
unsigned int zh_nstr_time33(unsigned int type, const char *key, unsigned int key_len) {
  unsigned int i = 0;
  unsigned int hash = type;
  for (i = 0; i < key_len; ++i) {
    hash = hash * 33 + key[i];
  }
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ADD_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x1,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  or     $0xc0,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  nop
  leave
  ret
```

assistant: ```c
void ADD_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x01);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ADD_HOST_REG_L>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x1,%edi
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  or     %ebp,%edi
  or     $0xc0,%dil
  call   <addbyte@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADD_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x01);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: What is the c source code of the assembly code below?

```asm
<ADD_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void ADD_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x01);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ADD_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void ADD_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x01);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DecryptFinalTransfomation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x1c(%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%ebx
  mov    -0x30(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x1c,%rax
  xor    %ebx,%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%ebx
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %ebx,%ecx
  sub    %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x14(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%ebx
  mov    -0x30(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  xor    %ebx,%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %ebx,%ecx
  sub    %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void DecryptFinalTransfomation(uint8_t *x, const uint8_t *wk) {
  uint8_t temp = x[7];
  x[7] = x[6] ^ READ_ROUND_KEY_BYTE(wk[7]);
  x[6] = x[5];
  x[5] = (x[4] - READ_ROUND_KEY_BYTE(wk[6])) & 0xFF;
  x[4] = x[3];
  x[3] = x[2] ^ READ_ROUND_KEY_BYTE(wk[5]);
  x[2] = x[1];
  x[1] = (x[0] - READ_ROUND_KEY_BYTE(wk[4])) & 0xFF;
  x[0] = temp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<DecryptFinalTransfomation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    0x1c(%rdi),%r13d
  mov    0x18(%rdi),%r12d
  mov    0x1c(%rsi),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%r12d
  mov    %r12d,0x1c(%rbx)
  mov    0x14(%rbx),%eax
  mov    %eax,0x18(%rbx)
  mov    0x10(%rbx),%r12d
  mov    0x18(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  sub    %eax,%r12d
  and    $0xff,%r12d
  mov    %r12d,0x14(%rbx)
  mov    0xc(%rbx),%eax
  mov    %eax,0x10(%rbx)
  mov    0x8(%rbx),%r12d
  mov    0x14(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%r12d
  mov    %r12d,0xc(%rbx)
  mov    0x4(%rbx),%eax
  mov    %eax,0x8(%rbx)
  mov    (%rbx),%r12d
  mov    0x10(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  sub    %eax,%r12d
  and    $0xff,%r12d
  mov    %r12d,0x4(%rbx)
  mov    %r13d,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void DecryptFinalTransfomation(uint8_t *x, const uint8_t *wk) {
  uint8_t temp = x[7];
  x[7] = x[6] ^ READ_ROUND_KEY_BYTE(wk[7]);
  x[6] = x[5];
  x[5] = (x[4] - READ_ROUND_KEY_BYTE(wk[6])) & 0xFF;
  x[4] = x[3];
  x[3] = x[2] ^ READ_ROUND_KEY_BYTE(wk[5]);
  x[2] = x[1];
  x[1] = (x[0] - READ_ROUND_KEY_BYTE(wk[4])) & 0xFF;
  x[0] = temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DecryptFinalTransfomation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x1c(%rdi),%r13d
  mov    0x18(%rdi),%r12d
  mov    0x1c(%rsi),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%r12d
  mov    0x14(%rbx),%eax
  mov    %r12d,0x1c(%rbx)
  mov    0x10(%rbx),%r12d
  mov    %eax,0x18(%rbx)
  mov    0x18(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  sub    %eax,%r12d
  mov    0xc(%rbx),%eax
  and    $0xff,%r12d
  mov    %r12d,0x14(%rbx)
  mov    0x8(%rbx),%r12d
  mov    %eax,0x10(%rbx)
  mov    0x14(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%r12d
  mov    0x4(%rbx),%eax
  mov    %r12d,0xc(%rbx)
  mov    (%rbx),%r12d
  mov    %eax,0x8(%rbx)
  mov    0x10(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %r13d,(%rbx)
  sub    %eax,%r12d
  and    $0xff,%r12d
  mov    %r12d,0x4(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void DecryptFinalTransfomation(uint8_t *x, const uint8_t *wk) {
  uint8_t temp = x[7];
  x[7] = x[6] ^ READ_ROUND_KEY_BYTE(wk[7]);
  x[6] = x[5];
  x[5] = (x[4] - READ_ROUND_KEY_BYTE(wk[6])) & 0xFF;
  x[4] = x[3];
  x[3] = x[2] ^ READ_ROUND_KEY_BYTE(wk[5]);
  x[2] = x[1];
  x[1] = (x[0] - READ_ROUND_KEY_BYTE(wk[4])) & 0xFF;
  x[0] = temp;
}
```
user: What is the c source code of the assembly code below:

```asm
<DecryptFinalTransfomation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x1c(%rdi),%r13d
  mov    0x18(%rdi),%r12d
  mov    0x1c(%rsi),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  movd   0x14(%rbx),%xmm0
  xor    %eax,%r12d
  movd   %r12d,%xmm1
  mov    0x10(%rbx),%r12d
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x18(%rbx)
  mov    0x18(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  movd   0xc(%rbx),%xmm0
  sub    %eax,%r12d
  movzbl %r12b,%r12d
  movd   %r12d,%xmm2
  mov    0x8(%rbx),%r12d
  punpckldq %xmm2,%xmm0
  movq   %xmm0,0x10(%rbx)
  mov    0x14(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  movd   0x4(%rbx),%xmm0
  xor    %eax,%r12d
  movd   %r12d,%xmm3
  mov    (%rbx),%r12d
  punpckldq %xmm3,%xmm0
  movq   %xmm0,0x8(%rbx)
  mov    0x10(%rbp),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  movd   %r13d,%xmm0
  sub    %eax,%r12d
  movzbl %r12b,%r12d
  movd   %r12d,%xmm4
  punpckldq %xmm4,%xmm0
  movq   %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void DecryptFinalTransfomation(uint8_t *x, const uint8_t *wk) {
  uint8_t temp = x[7];
  x[7] = x[6] ^ READ_ROUND_KEY_BYTE(wk[7]);
  x[6] = x[5];
  x[5] = (x[4] - READ_ROUND_KEY_BYTE(wk[6])) & 0xFF;
  x[4] = x[3];
  x[3] = x[2] ^ READ_ROUND_KEY_BYTE(wk[5]);
  x[2] = x[1];
  x[1] = (x[0] - READ_ROUND_KEY_BYTE(wk[4])) & 0xFF;
  x[0] = temp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <good_echo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  good_echo();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <good_echo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  good_echo();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <good_echo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  good_echo();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <good_echo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  good_echo();
  return 0;
}
```