ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1f0,%rsp
  mov    %edi,-0x1e4(%rbp)
  mov    %rsi,-0x1f0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x1d8(%rbp)
  jmp    L22
L36:
  movl   $0x1,-0x1d4(%rbp)
  jmp    L10
L37:
  lea    -0x1a0(%rbp),%rcx
  mov    -0x1d4(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x1d8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1d4(%rbp)
L10:
  mov    -0x1e0(%rbp),%eax
  cmp    %eax,-0x1d4(%rbp)
  jle    L37
  addl   $0x1,-0x1d8(%rbp)
L22:
  mov    -0x1e0(%rbp),%eax
  cmp    %eax,-0x1d8(%rbp)
  jle    L36
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1dc(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1e0(%rbp),%ecx
  mov    -0x1dc(%rbp),%eax
  lea    -0x1d0(%rbp),%rdx
  lea    -0x1a0(%rbp),%rsi
  mov    %eax,%edi
  call   <dij@plt>
  mov    -0x1dc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x1d8(%rbp)
  jmp    L38
L53:
  mov    -0x1d8(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%edx
  mov    -0x1d8(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1d8(%rbp)
L38:
  mov    -0x1e0(%rbp),%eax
  cmp    %eax,-0x1d8(%rbp)
  jle    L53
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D30
data_type: string
name: parse_data
arguments: data_label: D35
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D32
data_type: string
name: parse_data
arguments: data_label: D34
data_type: string

tool: D30: Enter the number of vertices 

tool: D35: %d

tool: D21: Enter cost matrix:

tool: D20: Enter the source vertex

tool: D32: The Shortest path to source %d to other vertices are 


tool: D34: to %d = %d 


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, src, i, j, cost[10][10], dist[10];
  printf("Enter the number of vertices \n");
  scanf("%d", &n);
  printf("Enter cost matrix:\n");
  for (i = 1; i <= n; i++)
    for (j = 1; j <= n; j++)
      scanf("%d", &cost[i][j]);
  printf("Enter the source vertex\n");
  scanf("%d", &src);
  dij(src, cost, dist, n);
  printf("The Shortest path to source %d to other vertices are \n", src);
  for (i = 1; i <= n; i++)
    printf("to %d = %d \n", i, dist[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d8(%rsp)
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  lea    D67(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L23
  lea    0x6c(%rsp),%r14
  mov    $0x1,%r13d
  lea    D34(%rip),%r12
  jmp    L88
L40:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jge    L40
L27:
  add    $0x1,%r13d
  add    $0x28,%r14
  cmp    %r13d,0x8(%rsp)
  jl     L23
L88:
  mov    %r14,%rbp
  mov    $0x1,%ebx
  cmpl   $0x0,0x8(%rsp)
  jg     L40
  jmp    L27
L23:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdx
  lea    0x40(%rsp),%rsi
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%edi
  call   <dij@plt>
  mov    0xc(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L74
  mov    $0x1,%ebx
  lea    D42(%rip),%rbp
L26:
  mov    0x10(%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x8(%rsp)
  jge    L26
L74:
  mov    0x1d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    $0x0,%eax
  add    $0x1e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D52
datatype: string
name: retrieve_data
arguments: data_tag: D34
datatype: string
name: retrieve_data
arguments: data_tag: D67
datatype: string
name: retrieve_data
arguments: data_tag: D26
datatype: string
name: retrieve_data
arguments: data_tag: D11
datatype: string
name: retrieve_data
arguments: data_tag: D42
datatype: string

tool: D52: Enter the number of vertices 

tool: D34: %d

tool: D67: Enter cost matrix:

tool: D26: Enter the source vertex

tool: D11: The Shortest path to source %d to other vertices are 


tool: D42: to %d = %d 


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, src, i, j, cost[10][10], dist[10];
  printf("Enter the number of vertices \n");
  scanf("%d", &n);
  printf("Enter cost matrix:\n");
  for (i = 1; i <= n; i++)
    for (j = 1; j <= n; j++)
      scanf("%d", &cost[i][j]);
  printf("Enter the source vertex\n");
  scanf("%d", &src);
  dij(src, cost, dist, n);
  printf("The Shortest path to source %d to other vertices are \n", src);
  for (i = 1; i <= n; i++)
    printf("to %d = %d \n", i, dist[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D49(%rip),%rdi
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L20
  lea    0x6c(%rsp),%r14
  mov    $0x1,%r13d
  nopl   (%rax)
L25:
  mov    %r14,%rbp
  mov    $0x1,%ebx
L43:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jge    L43
  add    $0x1,%r13d
  add    $0x28,%r14
  cmp    %r13d,%eax
  jge    L25
L20:
  lea    D25(%rip),%rdi
  lea    0x10(%rsp),%rbp
  mov    $0x1,%ebx
  call   <puts@plt>
  mov    %r12,%rdi
  lea    0xc(%rsp),%rsi
  lea    D40(%rip),%r12
  call   <scanf@plt>
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%edi
  mov    %rbp,%rdx
  lea    0x40(%rsp),%rsi
  call   <dij@plt>
  mov    0xc(%rsp),%esi
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L24
L35:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x8(%rsp)
  jge    L35
L24:
  mov    0x1d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D49
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D40
type_guessed: string
name: unpack_data
arguments: data_tag: D53
type_guessed: string

tool: D49: Enter the number of vertices 

tool: D8: %d

tool: D22: Enter cost matrix:

tool: D25: Enter the source vertex

tool: D40: to %d = %d 


tool: D53: The Shortest path to source %d to other vertices are 


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, src, i, j, cost[10][10], dist[10];
  printf("Enter the number of vertices \n");
  scanf("%d", &n);
  printf("Enter cost matrix:\n");
  for (i = 1; i <= n; i++)
    for (j = 1; j <= n; j++)
      scanf("%d", &cost[i][j]);
  printf("Enter the source vertex\n");
  scanf("%d", &src);
  dij(src, cost, dist, n);
  printf("The Shortest path to source %d to other vertices are \n", src);
  for (i = 1; i <= n; i++)
    printf("to %d = %d \n", i, dist[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%rdi
  push   %r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L5
  lea    0x6c(%rsp),%rbx
  mov    $0x1,%r13d
  mov    %rbx,%r14
  nopl   0x0(%rax,%rax,1)
L51:
  mov    $0x1,%ebp
  nopl   (%rax)
L52:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    %ebp,%eax
  jge    L52
  add    $0x1,%r13d
  cmp    %r13d,%eax
  jl     L5
  lea    0x28(%r14),%rbx
  mov    %rbx,%r14
  jmp    L51
  nopl   0x0(%rax)
L5:
  lea    D59(%rip),%rdi
  lea    0x10(%rsp),%rbp
  mov    $0x1,%ebx
  call   <puts@plt>
  mov    %r12,%rdi
  lea    0xc(%rsp),%rsi
  lea    D43(%rip),%r12
  call   <scanf@plt>
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%edi
  mov    %rbp,%rdx
  lea    0x40(%rsp),%rsi
  call   <dij@plt>
  mov    0xc(%rsp),%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L32
  nopl   0x0(%rax)
L69:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x8(%rsp)
  jge    L69
L32:
  mov    0x1d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x1e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string
name: read_data
arguments: data_tag: D30
type_infered: string
name: read_data
arguments: data_tag: D59
type_infered: string
name: read_data
arguments: data_tag: D43
type_infered: string
name: read_data
arguments: data_tag: D49
type_infered: string

tool: D18: Enter the number of vertices 

tool: D20: %d

tool: D30: Enter cost matrix:

tool: D59: Enter the source vertex

tool: D43: to %d = %d 


tool: D49: The Shortest path to source %d to other vertices are 


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, src, i, j, cost[10][10], dist[10];
  printf("Enter the number of vertices \n");
  scanf("%d", &n);
  printf("Enter cost matrix:\n");
  for (i = 1; i <= n; i++)
    for (j = 1; j <= n; j++)
      scanf("%d", &cost[i][j]);
  printf("Enter the source vertex\n");
  scanf("%d", &src);
  dij(src, cost, dist, n);
  printf("The Shortest path to source %d to other vertices are \n", src);
  for (i = 1; i <= n; i++)
    printf("to %d = %d \n", i, dist[i]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aml_array_dbl_2d_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L19:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L24:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **aml_array_dbl_2d_new(int s1, int s2, double val) {
  int i, j;
  double **arr = (double **)malloc(s1 * sizeof(double *));
  for (i = 0; i < s1; i++) {
    arr[i] = (double *)malloc(s2 * sizeof(double));
    for (j = 0; j < s2; j++)
      arr[i][j] = val;
  }
  return arr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aml_array_dbl_2d_new>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  movq   %xmm0,%rbx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L4
  lea    0x0(,%r13,8),%r15d
  mov    %rax,%r12
  mov    %ebp,%ebp
  lea    (%rax,%rbp,8),%r14
  lea    -0x1(%r13),%eax
  lea    0x8(,%rax,8),%rbp
L21:
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rax,(%r12)
  test   %r13d,%r13d
  jle    L36
  mov    $0x0,%eax
L30:
  mov    (%rcx),%rdx
  mov    %rbx,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L30
L36:
  add    $0x8,%r12
  cmp    %r14,%r12
  jne    L21
L4:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **aml_array_dbl_2d_new(int s1, int s2, double val) {
  int i, j;
  double **arr = (double **)malloc(s1 * sizeof(double *));
  for (i = 0; i < s1; i++) {
    arr[i] = (double *)malloc(s2 * sizeof(double));
    for (j = 0; j < s2; j++)
      arr[i][j] = val;
  }
  return arr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aml_array_dbl_2d_new>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %esi,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L30
  lea    (%rax,%rbp,8),%r12
  movsd  0x8(%rsp),%xmm0
  lea    -0x1(%rbx),%ebp
  mov    %rax,%r15
  lea    0x0(,%rbx,8),%r13d
  add    $0x1,%rbp
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r13d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <malloc@plt>
  test   %ebx,%ebx
  movsd  0x8(%rsp),%xmm0
  mov    %rax,(%r15)
  jle    L4
  lea    (%rax,%rbp,8),%rdx
  nop
L22:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L22
L4:
  add    $0x8,%r15
  cmp    %r12,%r15
  jne    L29
L30:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **aml_array_dbl_2d_new(int s1, int s2, double val) {
  int i, j;
  double **arr = (double **)malloc(s1 * sizeof(double *));
  for (i = 0; i < s1; i++) {
    arr[i] = (double *)malloc(s2 * sizeof(double));
    for (j = 0; j < s2; j++)
      arr[i][j] = val;
  }
  return arr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aml_array_dbl_2d_new>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %ebx,%ebx
  jle    L22
  lea    (%rax,%rbx,8),%r12
  mov    %rax,%r14
  mov    %r15d,%eax
  movsd  0x10(%rsp),%xmm0
  shr    %eax
  mov    %r15d,%ebx
  lea    0x0(,%r15,8),%r13d
  lea    -0x1(%rax),%ebp
  movapd %xmm0,%xmm1
  and    $0xfffffffe,%ebx
  add    $0x1,%rbp
  unpcklpd %xmm1,%xmm1
  shl    $0x4,%rbp
  nopl   0x0(%rax)
L13:
  mov    %r13d,%edi
  movaps %xmm1,(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <malloc@plt>
  test   %r15d,%r15d
  movsd  0x10(%rsp),%xmm0
  movapd (%rsp),%xmm1
  mov    %rax,(%r14)
  jle    L37
  cmp    $0x1,%r15d
  je     L30
  mov    %rax,%rdx
  lea    0x0(%rbp,%rax,1),%rsi
  nopl   0x0(%rax,%rax,1)
L59:
  movups %xmm1,(%rdx)
  add    $0x10,%rdx
  cmp    %rdx,%rsi
  jne    L59
  movslq %ebx,%rdx
  cmp    %ebx,%r15d
  je     L37
L53:
  movsd  %xmm0,(%rax,%rdx,8)
L37:
  add    $0x8,%r14
  cmp    %r12,%r14
  jne    L13
L22:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  xor    %edx,%edx
  jmp    L53
```

assistant: ```c
double **aml_array_dbl_2d_new(int s1, int s2, double val) {
  int i, j;
  double **arr = (double **)malloc(s1 * sizeof(double *));
  for (i = 0; i < s1; i++) {
    arr[i] = (double *)malloc(s2 * sizeof(double));
    for (j = 0; j < s2; j++)
      arr[i][j] = val;
  }
  return arr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test41_Blink2_pollen__reset__E>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <amaret_local_Mcu_reset__E@plt>
  mov    $0x0,%eax
  call   <pollen_hardware_Led_off__E@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test41_Blink2_pollen__reset__E() {
  amaret_local_Mcu_reset__E();
  pollen_hardware_Led_off__E();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test41_Blink2_pollen__reset__E>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <amaret_local_Mcu_reset__E@plt>
  mov    $0x0,%eax
  call   <pollen_hardware_Led_off__E@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test41_Blink2_pollen__reset__E() {
  amaret_local_Mcu_reset__E();
  pollen_hardware_Led_off__E();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test41_Blink2_pollen__reset__E>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <amaret_local_Mcu_reset__E@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <pollen_hardware_Led_off__E@plt>
```

assistant: ```c
void test41_Blink2_pollen__reset__E() {
  amaret_local_Mcu_reset__E();
  pollen_hardware_Led_off__E();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test41_Blink2_pollen__reset__E>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <amaret_local_Mcu_reset__E@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <pollen_hardware_Led_off__E@plt>
```

assistant: ```c
void test41_Blink2_pollen__reset__E() {
  amaret_local_Mcu_reset__E();
  pollen_hardware_Led_off__E();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fsend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L15
L4:
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void fsend(FILE *in, FILE *out) {
  int c;
  while ((c = getc(in)) != EOF)
    putc(c, out);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fsend>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  jmp    L6
L9:
  mov    %rbp,%rsi
  call   <putc@plt>
L6:
  mov    %rbx,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  mov    D8(%rip),%rax
  cmp    %edi,(%rax)
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fsend(FILE *in, FILE *out) {
  int c;
  while ((c = getc(in)) != EOF)
    putc(c, out);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fsend>:
  endbr64
  push   %r12
  mov    D9(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rsi
  call   <putc@plt>
L17:
  mov    %rbx,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  cmp    %eax,(%r12)
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fsend(FILE *in, FILE *out) {
  int c;
  while ((c = getc(in)) != EOF)
    putc(c, out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fsend>:
  endbr64
  push   %r12
  mov    D6(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rsi
  call   <putc@plt>
L1:
  mov    %rbx,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  cmp    %eax,(%r12)
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fsend(FILE *in, FILE *out) {
  int c;
  while ((c = getc(in)) != EOF)
    putc(c, out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_goodbye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D2(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: Goodbye World!


assistant: ```c
void print_goodbye(void) {
  const char *msg = "Goodbye World!\n";
  int printf_res = printf(msg);
  if (printf_res < strlen(msg)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_goodbye>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D8: Goodbye World!

assistant: ```c
void print_goodbye(void) {
  const char *msg = "Goodbye World!\n";
  int printf_res = printf(msg);
  if (printf_res < strlen(msg)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_goodbye>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: Goodbye World!

assistant: ```c
void print_goodbye(void) {
  const char *msg = "Goodbye World!\n";
  int printf_res = printf(msg);
  if (printf_res < strlen(msg)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_goodbye>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: Goodbye World!

assistant: ```c
void print_goodbye(void) {
  const char *msg = "Goodbye World!\n";
  int printf_res = printf(msg);
  if (printf_res < strlen(msg)) {
    return 1;
  } else {
    return 0;
  }
}
```