ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D72(%rip),%rdi
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    %eax,%r12d
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  divsd  D77(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x28,%esi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D72
type_guessed: string
name: parse_data
arguments: data_tag: D51
type_guessed: string
name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D48
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D77
type_guessed: f64
name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D42
type_guessed: string

tool: D72: Hi! What's your first name?

tool: D51: %s

tool: D17: %s, what's your weight in pounds?


tool: D48: %f

tool: D19: Well, %s, your volume is %2.2f cubic feet.


tool: D77: 62.4

tool: D10: Also, your first name has %d letters, 


tool: D42: and we have %d bytes to store it in. 


assistant: ```c
int main() {
  float weight, volume;
  int size, letters;
  char name[40];
  printf("Hi! What's your first name?\n");
  scanf("%s", name);
  printf("%s, what's your weight in pounds?\n", name);
  scanf("%f", &weight);
  size = sizeof name;
  letters = strlen(name);
  volume = weight / 62.4;
  printf("Well, %s, your volume is %2.2f cubic feet.\n", name, volume);
  printf("Also, your first name has %d letters, \n", letters);
  printf("and we have %d bytes to store it in. \n", size);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D50(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    %eax,%r12d
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  divsd  D21(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x28,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D46
type_guessed: string
name: disassemble_data
arguments: label: D35
type_guessed: string
name: disassemble_data
arguments: label: D43
type_guessed: string
name: disassemble_data
arguments: label: D50
type_guessed: string
name: disassemble_data
arguments: label: D21
type_guessed: f64
name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D5: Hi! What's your first name?

tool: D46: %s

tool: D35: %s, what's your weight in pounds?


tool: D43: %f

tool: D50: Well, %s, your volume is %2.2f cubic feet.


tool: D21: 62.4

tool: D17: Also, your first name has %d letters, 


tool: D6: and we have %d bytes to store it in. 


assistant: ```c
int main() {
  float weight, volume;
  int size, letters;
  char name[40];
  printf("Hi! What's your first name?\n");
  scanf("%s", name);
  printf("%s, what's your weight in pounds?\n", name);
  scanf("%f", &weight);
  size = sizeof name;
  letters = strlen(name);
  volume = weight / 62.4;
  printf("Well, %s, your volume is %2.2f cubic feet.\n", name, volume);
  printf("Also, your first name has %d letters, \n", letters);
  printf("and we have %d bytes to store it in. \n", size);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D28(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D17: Digite o valor do raio do circulo!

tool: D16: %f

tool: {"D28": [0x00,0x00,0x40,0x40]}

tool: D1: %f


assistant: ```c
int main() {
  float raio, area, raio2;
  printf("Digite o valor do raio do circulo!\n");
  scanf("%f", &raio);
  raio2 = raio * raio;
  area = 3, 141592 * raio2;
  printf("%f\n", raio2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D16
type: string

tool: D25: Digite o valor do raio do circulo!

tool: D2: %f

tool: D16: %f


assistant: ```c
int main() {
  float raio, area, raio2;
  printf("Digite o valor do raio do circulo!\n");
  scanf("%f", &raio);
  raio2 = raio * raio;
  area = 3, 141592 * raio2;
  printf("%f\n", raio2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D3(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D0(%rip),%rdi
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D12: Digite o valor do raio do circulo!

tool: D3: %f

tool: D0: %f


assistant: ```c
int main() {
  float raio, area, raio2;
  printf("Digite o valor do raio do circulo!\n");
  scanf("%f", &raio);
  raio2 = raio * raio;
  area = 3, 141592 * raio2;
  printf("%f\n", raio2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D17(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D12(%rip),%rdi
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D12
type: string

tool: D21: Digite o valor do raio do circulo!

tool: D17: %f

tool: D12: %f


assistant: ```c
int main() {
  float raio, area, raio2;
  printf("Digite o valor do raio do circulo!\n");
  scanf("%f", &raio);
  raio2 = raio * raio;
  area = 3, 141592 * raio2;
  printf("%f\n", raio2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fill_ipv4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <load_word@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fill_word@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <update_hash_word@plt>
  nop
  leave
  ret
```

assistant: ```c
void fill_ipv4(struct __sk_buff *skb, int offset, __u8 *dst, __u64 *hash) {
  __u32 w = load_word(skb, offset);
  fill_word(w, dst, 12);
  update_hash_word(hash, w);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fill_ipv4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <load_word@plt>
  mov    %eax,%ebx
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <fill_word@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <update_hash_word@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fill_ipv4(struct __sk_buff *skb, int offset, __u8 *dst, __u64 *hash) {
  __u32 w = load_word(skb, offset);
  fill_word(w, dst, 12);
  update_hash_word(hash, w);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_ipv4>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  call   <load_word@plt>
  mov    %r13,%rsi
  mov    $0xc,%edx
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <fill_word@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <update_hash_word@plt>
```

assistant: ```c
void fill_ipv4(struct __sk_buff *skb, int offset, __u8 *dst, __u64 *hash) {
  __u32 w = load_word(skb, offset);
  fill_word(w, dst, 12);
  update_hash_word(hash, w);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fill_ipv4>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  call   <load_word@plt>
  mov    %r13,%rsi
  mov    $0xc,%edx
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <fill_word@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <update_hash_word@plt>
```

assistant: ```c
void fill_ipv4(struct __sk_buff *skb, int offset, __u8 *dst, __u64 *hash) {
  __u32 w = load_word(skb, offset);
  fill_word(w, dst, 12);
  update_hash_word(hash, w);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x3,-0x14(%rbp)
  jmp    L40
L42:
  movl   $0x2,-0x10(%rbp)
  jmp    L34
L63:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L21
  addl   $0x1,-0x10(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x10(%rbp)
  jle    L63
  jmp    L87
L21:
  nop
L87:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x10(%rbp)
  jle    L31
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L129
L112:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L59
  addl   $0x1,-0x10(%rbp)
L129:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x10(%rbp)
  jle    L112
  jmp    L15
L59:
  nop
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x10(%rbp)
  jle    L68
  mov    -0x18(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L68:
  addl   $0x2,-0x14(%rbp)
L40:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x14(%rbp)
  jle    L42
  jmp    L54
L31:
  nop
L54:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string

tool: D3: %d

tool: D4: %d = %d + %d


assistant: ```c
void main() {
  int a, b, c, d;
  scanf("%d", &a);
  for (b = 3; b <= a / 2; b += 2) {
    for (c = 2; c <= sqrt(b); c++)
      if (b % c == 0)
        break;
    if (c > sqrt(b))
      d = a - b;
    else
      break;
    for (c = 2; c <= sqrt(d); c++)
      if (d % c == 0)
        break;
    if (c > sqrt(d))
      printf("%d = %d + %d\n", a, b, d);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    $0x3,%ebp
  lea    D8(%rip),%r13
  cmpl   $0x5,0x4(%rsp)
  jg     L109
L63:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L75:
  add    $0x1,%ebx
L29:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L28
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L75
L28:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L63
  mov    0x4(%rsp),%r12d
  sub    %ebp,%r12d
  mov    $0x2,%ebx
L98:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L1
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L1
  add    $0x1,%ebx
  jmp    L98
L1:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L34
L110:
  add    $0x2,%ebp
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %ebp,%eax
  jl     L63
L109:
  mov    $0x2,%ebx
  jmp    L29
L34:
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L110
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D3: %d

tool: D8: %d = %d + %d


assistant: ```c
void main() {
  int a, b, c, d;
  scanf("%d", &a);
  for (b = 3; b <= a / 2; b += 2) {
    for (c = 2; c <= sqrt(b); c++)
      if (b % c == 0)
        break;
    if (c > sqrt(b))
      d = a - b;
    else
      break;
    for (c = 2; c <= sqrt(d); c++)
      if (d % c == 0)
        break;
    if (c > sqrt(d))
      printf("%d = %d + %d\n", a, b, d);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  jle    L44
  nopw   0x0(%rax,%rax,1)
L84:
  mov    $0x2,%ebx
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L14
  add    $0x1,%ebx
L50:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L6
L14:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L44
  mov    0x4(%rsp),%r13d
  mov    $0x2,%ebx
  sub    %r12d,%r13d
  jmp    L64
  nopl   0x0(%rax)
L37:
  mov    %r13d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L38
  add    $0x1,%ebx
L64:
  mov    %r13d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L37
L38:
  mov    %r13d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L106
L109:
  mov    0x4(%rsp),%edx
  add    $0x2,%r12d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jge    L84
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L106:
  mov    0x4(%rsp),%esi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L109
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string

tool: D8: %d

tool: D12: %d = %d + %d


assistant: ```c
void main() {
  int a, b, c, d;
  scanf("%d", &a);
  for (b = 3; b <= a / 2; b += 2) {
    for (c = 2; c <= sqrt(b); c++)
      if (b % c == 0)
        break;
    if (c > sqrt(b))
      d = a - b;
    else
      break;
    for (c = 2; c <= sqrt(d); c++)
      if (d % c == 0)
        break;
    if (c > sqrt(d))
      printf("%d = %d + %d\n", a, b, d);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%rdi
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  jle    L18
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x2,%ebx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L119:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L78
  add    $0x1,%ebx
L96:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L119
L78:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L18
  mov    0x4(%rsp),%r13d
  mov    $0x2,%ebx
  sub    %r12d,%r13d
  jmp    L26
  nopl   0x0(%rax)
L56:
  mov    %r13d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L34
  add    $0x1,%ebx
L26:
  mov    %r13d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L56
L34:
  mov    %r13d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L76
  mov    0x4(%rsp),%edx
  add    $0x2,%r12d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jge    L23
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L76:
  mov    0x4(%rsp),%esi
  mov    %r12d,%edx
  mov    %r13d,%ecx
  mov    %rbp,%rdi
  add    $0x2,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%r12d
  jle    L23
  jmp    L18
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D18: %d

tool: D19: %d = %d + %d


assistant: ```c
void main() {
  int a, b, c, d;
  scanf("%d", &a);
  for (b = 3; b <= a / 2; b += 2) {
    for (c = 2; c <= sqrt(b); c++)
      if (b % c == 0)
        break;
    if (c > sqrt(b))
      d = a - b;
    else
      break;
    for (c = 2; c <= sqrt(d); c++)
      if (d % c == 0)
        break;
    if (c > sqrt(d))
      printf("%d = %d + %d\n", a, b, d);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<U_WMRCORE_SIZE16_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <U_swap4@plt>
  nop
  leave
  ret
```

assistant: ```c
void U_WMRCORE_SIZE16_swap(char *record, int torev) {
  (void)(torev);
  U_swap4(record, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<U_WMRCORE_SIZE16_swap>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <U_swap4@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void U_WMRCORE_SIZE16_swap(char *record, int torev) {
  (void)(torev);
  U_swap4(record, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<U_WMRCORE_SIZE16_swap>:
  endbr64
  mov    $0x1,%esi
  jmp    1050 <U_swap4@plt>
```

assistant: ```c
void U_WMRCORE_SIZE16_swap(char *record, int torev) {
  (void)(torev);
  U_swap4(record, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<U_WMRCORE_SIZE16_swap>:
  endbr64
  mov    $0x1,%esi
  jmp    1050 <U_swap4@plt>
```

assistant: ```c
void U_WMRCORE_SIZE16_swap(char *record, int torev) {
  (void)(torev);
  U_swap4(record, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<endian_islittle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x4321,-0xa(%rbp)
  lea    -0xa(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  je     L14
  mov    $0x0,%eax
  jmp    L8
L14:
  mov    $0x1,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int endian_islittle(void) {
  short word = 0x4321;
  if ((*(char *)&word) != 0x21)
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<endian_islittle>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int endian_islittle(void) {
  short word = 0x4321;
  if ((*(char *)&word) != 0x21)
    return 0;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<endian_islittle>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int endian_islittle(void) {
  short word = 0x4321;
  if ((*(char *)&word) != 0x21)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<endian_islittle>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int endian_islittle(void) {
  short word = 0x4321;
  if ((*(char *)&word) != 0x21)
    return 0;
  else
    return 1;
}
```