ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D18
data_type: string

tool: D7: zmienna x = %d


tool: D18: adres   x = %p


assistant: ```c
int main(void) {
  int x = 10;
  printf("zmienna x = %d\n", x);
  printf("adres   x = %p\n", (void *)&x);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  mov    $0xa,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string

tool: D9: zmienna x = %d


tool: D17: adres   x = %p


assistant: ```c
int main(void) {
  int x = 10;
  printf("zmienna x = %d\n", x);
  printf("adres   x = %p\n", (void *)&x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%esi
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D17
type_infered: string

tool: D4: zmienna x = %d


tool: D17: adres   x = %p


assistant: ```c
int main(void) {
  int x = 10;
  printf("zmienna x = %d\n", x);
  printf("adres   x = %p\n", (void *)&x);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%esi
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D0
type: string

tool: D3: zmienna x = %d


tool: D0: adres   x = %p


assistant: ```c
int main(void) {
  int x = 10;
  printf("zmienna x = %d\n", x);
  printf("adres   x = %p\n", (void *)&x);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  or     %rdx,%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L33
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L24:
  mov    -0x8(%rbp),%rdx
  lea    0x8(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  mov    (%rdx),%rdx
  mov    %rdx,(%rax)
L8:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1010101(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  not    %rax
  and    %rdx,%rax
  and    $0x80808080,%eax
  test   %rax,%rax
  je     L24
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L33:
  nop
L28:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dst0, const char *src0) {
  char *dst = dst0;
  const char *src = src0;
  long *aligned_dst;
  const long *aligned_src;
  if (!(((long)src & (sizeof(long) - 1)) | ((long)dst & (sizeof(long) - 1)))) {
    aligned_dst = (long *)dst;
    aligned_src = (long *)src;
    while (!(((*aligned_src) - 0x01010101) & ~(*aligned_src) & 0x80808080)) {
      *aligned_dst++ = *aligned_src++;
    }
    dst = (char *)aligned_dst;
    src = (char *)aligned_src;
  }
  while ((*dst++ = *src++))
    ;
  return dst0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
  or     %rsi,%rdx
  mov    %rdi,%r8
  test   $0x7,%dl
  jne    L7
  mov    (%rsi),%rdx
  lea    -0x1010101(%rdx),%rcx
  mov    %rdx,%rdi
  not    %rdi
  and    %rdi,%rcx
  test   $0x80808080,%ecx
  jne    L47
L32:
  add    $0x8,%rsi
  add    $0x8,%r8
  mov    %rdx,-0x8(%r8)
  mov    (%rsi),%rdx
  lea    -0x1010101(%rdx),%rcx
  mov    %rdx,%r9
  not    %r9
  and    %r9,%rcx
  test   $0x80808080,%ecx
  je     L32
L7:
  mov    $0x0,%edx
L38:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L38
  ret
L47:
  mov    %rax,%r8
  jmp    L7
```

assistant: ```c
char *strcpy(char *dst0, const char *src0) {
  char *dst = dst0;
  const char *src = src0;
  long *aligned_dst;
  const long *aligned_src;
  if (!(((long)src & (sizeof(long) - 1)) | ((long)dst & (sizeof(long) - 1)))) {
    aligned_dst = (long *)dst;
    aligned_src = (long *)src;
    while (!(((*aligned_src) - 0x01010101) & ~(*aligned_src) & 0x80808080)) {
      *aligned_dst++ = *aligned_src++;
    }
    dst = (char *)aligned_dst;
    src = (char *)aligned_src;
  }
  while ((*dst++ = *src++))
    ;
  return dst0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rdx
  mov    %rdi,%rax
  mov    %rdi,%r8
  or     %rsi,%rdx
  and    $0x7,%edx
  jne    L13
  mov    (%rsi),%rdx
  mov    %rdx,%rdi
  lea    -0x1010101(%rdx),%rcx
  not    %rdi
  and    %rdi,%rcx
  test   $0x80808080,%ecx
  jne    L13
L18:
  add    $0x8,%rsi
  mov    %rdx,(%r8)
  add    $0x8,%r8
  mov    (%rsi),%rdx
  mov    %rdx,%r9
  lea    -0x1010101(%rdx),%rcx
  not    %r9
  and    %r9,%rcx
  test   $0x80808080,%ecx
  je     L18
L13:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L2
  ret
```

assistant: ```c
char *strcpy(char *dst0, const char *src0) {
  char *dst = dst0;
  const char *src = src0;
  long *aligned_dst;
  const long *aligned_src;
  if (!(((long)src & (sizeof(long) - 1)) | ((long)dst & (sizeof(long) - 1)))) {
    aligned_dst = (long *)dst;
    aligned_src = (long *)src;
    while (!(((*aligned_src) - 0x01010101) & ~(*aligned_src) & 0x80808080)) {
      *aligned_dst++ = *aligned_src++;
    }
    dst = (char *)aligned_dst;
    src = (char *)aligned_src;
  }
  while ((*dst++ = *src++))
    ;
  return dst0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rdx
  mov    %rdi,%rax
  mov    %rdi,%r8
  or     %rsi,%rdx
  and    $0x7,%edx
  jne    L27
  mov    (%rsi),%rdx
  mov    %rdx,%rdi
  lea    -0x1010101(%rdx),%rcx
  not    %rdi
  and    %rdi,%rcx
  test   $0x80808080,%ecx
  jne    L27
L8:
  add    $0x8,%rsi
  mov    %rdx,(%r8)
  add    $0x8,%r8
  mov    (%rsi),%rdx
  mov    %rdx,%r9
  lea    -0x1010101(%rdx),%rcx
  not    %r9
  and    %r9,%rcx
  test   $0x80808080,%ecx
  je     L8
L27:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L4
  ret
```

assistant: ```c
char *strcpy(char *dst0, const char *src0) {
  char *dst = dst0;
  const char *src = src0;
  long *aligned_dst;
  const long *aligned_src;
  if (!(((long)src & (sizeof(long) - 1)) | ((long)dst & (sizeof(long) - 1)))) {
    aligned_dst = (long *)dst;
    aligned_src = (long *)src;
    while (!(((*aligned_src) - 0x01010101) & ~(*aligned_src) & 0x80808080)) {
      *aligned_dst++ = *aligned_src++;
    }
    dst = (char *)aligned_dst;
    src = (char *)aligned_src;
  }
  while ((*dst++ = *src++))
    ;
  return dst0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: %s 


assistant: ```c
void error(char *s) {
  printf("%s \n", s);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %s 


assistant: ```c
void error(char *s) {
  printf("%s \n", s);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: string

tool: D4: %s 


assistant: ```c
void error(char *s) {
  printf("%s \n", s);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: %s 


assistant: ```c
void error(char *s) {
  printf("%s \n", s);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uninitvar_btowc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <btowc@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_btowc(void) {
  int c;
  (void)btowc(c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_btowc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <btowc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_btowc(void) {
  int c;
  (void)btowc(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninitvar_btowc>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <btowc@plt>
```

assistant: ```c
void uninitvar_btowc(void) {
  int c;
  (void)btowc(c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uninitvar_btowc>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <btowc@plt>
```

assistant: ```c
void uninitvar_btowc(void) {
  int c;
  (void)btowc(c);
}
```
user: What is the c source code of the assembly code below:

```asm
<div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L6
L3:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
L6:
  pop    %rbp
  ret
```

assistant: ```c
int div(int a, int b) {
  if (0 == b)
    return 0;
  return a / b;
}
```
user: What is the c source code of the assembly code below?

```asm
<div>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L3
  mov    %edi,%eax
  cltd
  idiv   %esi
L3:
  ret
```

assistant: ```c
int div(int a, int b) {
  if (0 == b)
    return 0;
  return a / b;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<div>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L1
  mov    %edi,%eax
  cltd
  idiv   %esi
L1:
  ret
```

assistant: ```c
int div(int a, int b) {
  if (0 == b)
    return 0;
  return a / b;
}
```
user: What is the c source code of the assembly code below?

```asm
<div>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L7
  mov    %edi,%eax
  cltd
  idiv   %esi
L7:
  ret
```

assistant: ```c
int div(int a, int b) {
  if (0 == b)
    return 0;
  return a / b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Iq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movsd  -0x40(%rbp),%xmm3
  movsd  -0x38(%rbp),%xmm2
  mov    -0xc(%rbp),%edx
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  mov    %edx,%edi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <linear_pearls_kernel@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: f64

tool: D9: 0.5

assistant: ```c
double Iq(double q, double radius, double edge_sep, double fp_num_pearls, double pearl_sld, double solvent_sld) {
  int num_pearls = (int)(fp_num_pearls + 0.5);
  double result = linear_pearls_kernel(q, radius, edge_sep, num_pearls, pearl_sld, solvent_sld);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Iq>:
  endbr64
  sub    $0x8,%rsp
  movapd %xmm3,%xmm6
  movapd %xmm4,%xmm3
  movapd %xmm5,%xmm4
  addsd  D3(%rip),%xmm6
  cvttsd2si %xmm6,%edi
  call   <linear_pearls_kernel@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: f64

tool: D3: 0.5

assistant: ```c
double Iq(double q, double radius, double edge_sep, double fp_num_pearls, double pearl_sld, double solvent_sld) {
  int num_pearls = (int)(fp_num_pearls + 0.5);
  double result = linear_pearls_kernel(q, radius, edge_sep, num_pearls, pearl_sld, solvent_sld);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Iq>:
  endbr64
  addsd  D5(%rip),%xmm3
  movapd %xmm4,%xmm7
  movapd %xmm5,%xmm4
  cvttsd2si %xmm3,%edi
  movapd %xmm7,%xmm3
  jmp    1050 <linear_pearls_kernel@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 0.5

assistant: ```c
double Iq(double q, double radius, double edge_sep, double fp_num_pearls, double pearl_sld, double solvent_sld) {
  int num_pearls = (int)(fp_num_pearls + 0.5);
  double result = linear_pearls_kernel(q, radius, edge_sep, num_pearls, pearl_sld, solvent_sld);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Iq>:
  endbr64
  addsd  D3(%rip),%xmm3
  movapd %xmm4,%xmm7
  movapd %xmm5,%xmm4
  cvttsd2si %xmm3,%edi
  movapd %xmm7,%xmm3
  jmp    1050 <linear_pearls_kernel@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: f64

tool: D3: 0.5

assistant: ```c
double Iq(double q, double radius, double edge_sep, double fp_num_pearls, double pearl_sld, double solvent_sld) {
  int num_pearls = (int)(fp_num_pearls + 0.5);
  double result = linear_pearls_kernel(q, radius, edge_sep, num_pearls, pearl_sld, solvent_sld);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_really_remove_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    $0xffffffff,%eax
  jmp    L39
L2:
  mov    $0x1,%eax
L39:
  leave
  ret
```

assistant: ```c
int util_really_remove_file(char *path) {
  int deleted = 0;
  deleted = unlink(path);
  if (deleted < 0) {
    sleep(2);
    deleted = unlink(path);
    if (deleted < 0) {
      sleep(3);
      deleted = unlink(path);
      if (deleted < 0) {
        return -1;
      }
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_really_remove_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <unlink@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  js     L20
L9:
  pop    %rbx
  ret
L20:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jns    L9
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  sar    $0x1f,%eax
  or     $0x1,%eax
  jmp    L9
```

assistant: ```c
int util_really_remove_file(char *path) {
  int deleted = 0;
  deleted = unlink(path);
  if (deleted < 0) {
    sleep(2);
    deleted = unlink(path);
    if (deleted < 0) {
      sleep(3);
      deleted = unlink(path);
      if (deleted < 0) {
        return -1;
      }
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<util_really_remove_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <unlink@plt>
  test   %eax,%eax
  js     L4
L14:
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  test   %eax,%eax
  jns    L14
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  test   %eax,%eax
  jns    L14
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int util_really_remove_file(char *path) {
  int deleted = 0;
  deleted = unlink(path);
  if (deleted < 0) {
    sleep(2);
    deleted = unlink(path);
    if (deleted < 0) {
      sleep(3);
      deleted = unlink(path);
      if (deleted < 0) {
        return -1;
      }
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<util_really_remove_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <unlink@plt>
  test   %eax,%eax
  js     L28
L2:
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  test   %eax,%eax
  jns    L2
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  test   %eax,%eax
  jns    L2
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int util_really_remove_file(char *path) {
  int deleted = 0;
  deleted = unlink(path);
  if (deleted < 0) {
    sleep(2);
    deleted = unlink(path);
    if (deleted < 0) {
      sleep(3);
      deleted = unlink(path);
      if (deleted < 0) {
        return -1;
      }
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utarray_str_dtor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L5
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <MPIU_Free@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    MPIU_Free(*eltc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utarray_str_dtor>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  call   <MPIU_Free@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    MPIU_Free(*eltc);
}
```
user: What is the c source code of the assembly code below:

```asm
<utarray_str_dtor>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  jmp    1050 <MPIU_Free@plt>
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    MPIU_Free(*eltc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utarray_str_dtor>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  jmp    1050 <MPIU_Free@plt>
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    MPIU_Free(*eltc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<seatest_assert_string_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x18000(%rsp),%r11
L81:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L81
  sub    $0x6e0,%rsp
  mov    %rdi,-0x186c8(%rbp)
  mov    %rsi,-0x186d0(%rbp)
  mov    %rdx,-0x186d8(%rbp)
  mov    %ecx,-0x186dc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x186c8(%rbp)
  jne    L42
  cmpq   $0x0,-0x186d0(%rbp)
  jne    L42
  lea    -0x186b0(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movl   $0x1,-0x186b4(%rbp)
  jmp    L39
L42:
  cmpq   $0x0,-0x186c8(%rbp)
  jne    L48
  mov    -0x186d0(%rbp),%rdx
  lea    -0x186b0(%rbp),%rax
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movl   $0x0,-0x186b4(%rbp)
  jmp    L39
L48:
  cmpq   $0x0,-0x186d0(%rbp)
  jne    L28
  mov    -0x186c8(%rbp),%rdx
  lea    -0x186b0(%rbp),%rax
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movl   $0x0,-0x186b4(%rbp)
  jmp    L39
L28:
  mov    -0x186d0(%rbp),%rdx
  mov    -0x186c8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x186b4(%rbp)
  mov    -0x186d0(%rbp),%rcx
  mov    -0x186c8(%rbp),%rdx
  lea    -0x186b0(%rbp),%rax
  lea    D39(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L39:
  mov    -0x186dc(%rbp),%ecx
  mov    -0x186d8(%rbp),%rdx
  lea    -0x186b0(%rbp),%rsi
  mov    -0x186b4(%rbp),%eax
  mov    %eax,%edi
  call   <seatest_simple_test_result@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D30
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D39
type_guessed: string

tool: D30: Expected <NULL> but was <NULL>

tool: D14: Expected <NULL> but was "%s"

tool: D12: Expected "%s" but was <NULL>

tool: D39: Expected "%s" but was "%s"

assistant: ```c
void seatest_assert_string_equal(const char *expected, const char *actual, const char *function, unsigned int line) {
  int comparison;
  char s[100000];
  if ((expected == (char *)0) && (actual == (char *)0)) {
    sprintf(s, "Expected <NULL> but was <NULL>");
    comparison = 1;
  } else if (expected == (char *)0) {
    sprintf(s, "Expected <NULL> but was \"%s\"", actual);
    comparison = 0;
  } else if (actual == (char *)0) {
    sprintf(s, "Expected \"%s\" but was <NULL>", expected);
    comparison = 0;
  } else {
    comparison = strcmp(expected, actual) == 0;
    sprintf(s, "Expected \"%s\" but was \"%s\"", expected, actual);
  }
  seatest_simple_test_result(comparison, s, function, line);
}
```