ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x4,0x4(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    D55(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  movl   $0x200,(%rsp)
  movl   $0x200,0x4(%rsp)
  mov    %rbx,%rsi
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  movl   $0x200,(%rsp)
  movl   $0x200,0x4(%rsp)
  mov    %rbx,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  movl   $0xffff,(%rsp)
  movl   $0xffff,0x4(%rsp)
  mov    %rbx,%rsi
  mov    D38(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    %rbx,%rsi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    %rbx,%rsi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    $0x8,%edi
  call   <alarm@plt>
  lea    0x8(%rbp),%rsi
  mov    0x8(%rbp),%rdi
  call   <execvp@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct rlimit limit;
  limit.rlim_cur = 4;
  limit.rlim_max = 4;
  setrlimit(RLIMIT_CPU, &limit);
  limit.rlim_cur = 512;
  limit.rlim_max = 512;
  setrlimit(RLIMIT_NPROC, &limit);
  limit.rlim_cur = 512;
  limit.rlim_max = 512;
  setrlimit(RLIMIT_NOFILE, &limit);
  limit.rlim_cur = 65535;
  limit.rlim_max = 65535;
  setrlimit(RLIMIT_FSIZE, &limit);
  setrlimit(RLIMIT_MEMLOCK, &limit);
  setrlimit(RLIMIT_STACK, &limit);
  alarm(8);
  execvp(argv[1], &argv[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  movabs $0x20000000200,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000004,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    D41(%rip),%rax
  mov    %rbp,%rsi
  mov    %r12,(%rsp)
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    D43(%rip),%rax
  mov    %rbp,%rsi
  mov    %r12,(%rsp)
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    %rbp,%rsi
  movabs $0xffff0000ffff,%rax
  mov    %rax,(%rsp)
  mov    D50(%rip),%rax
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    D11(%rip),%rax
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    D4(%rip),%rax
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <setrlimit@plt>
  mov    $0x8,%edi
  call   <alarm@plt>
  mov    0x8(%rbx),%rdi
  lea    0x8(%rbx),%rsi
  call   <execvp@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct rlimit limit;
  limit.rlim_cur = 4;
  limit.rlim_max = 4;
  setrlimit(RLIMIT_CPU, &limit);
  limit.rlim_cur = 512;
  limit.rlim_max = 512;
  setrlimit(RLIMIT_NPROC, &limit);
  limit.rlim_cur = 512;
  limit.rlim_max = 512;
  setrlimit(RLIMIT_NOFILE, &limit);
  limit.rlim_cur = 65535;
  limit.rlim_max = 65535;
  setrlimit(RLIMIT_FSIZE, &limit);
  setrlimit(RLIMIT_MEMLOCK, &limit);
  setrlimit(RLIMIT_STACK, &limit);
  alarm(8);
  execvp(argv[1], &argv[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<E>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <T@plt>
  mov    $0x0,%eax
  call   <EPRIME@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void E() {
  T();
  EPRIME();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<E>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <T@plt>
  mov    $0x0,%eax
  call   <EPRIME@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void E() {
  T();
  EPRIME();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<E>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <T@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <EPRIME@plt>
```

assistant: ```c
void E() {
  T();
  EPRIME();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<E>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <T@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <EPRIME@plt>
```

assistant: ```c
void E() {
  T();
  EPRIME();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x7de,%ecx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string
name: disassemble_data
arguments: data_tag: D34
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string

tool: D21: Course: EG1302A - Spring 2014

tool: D29: Name: Fernando Urbina

tool: D34: Date Created: %d/%d/%d


tool: D17: Assignment: Assignment 05

assistant: ```c
int main() {
  printf("Course: EG1302A - Spring 2014\n");
  printf("Name: Fernando Urbina\n");
  printf("Date Created: %d/%d/%d\n", 1, 28, 2014);
  printf("Assignment: Assignment 05\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x7de,%ecx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D31
type: string
name: parse_data
arguments: data_label: D9
type: string
name: parse_data
arguments: data_label: D28
type: string

tool: D15: Course: EG1302A - Spring 2014

tool: D31: Name: Fernando Urbina

tool: D9: Date Created: %d/%d/%d


tool: D28: Assignment: Assignment 05

assistant: ```c
int main() {
  printf("Course: EG1302A - Spring 2014\n");
  printf("Name: Fernando Urbina\n");
  printf("Date Created: %d/%d/%d\n", 1, 28, 2014);
  printf("Assignment: Assignment 05\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x7de,%ecx
  xor    %eax,%eax
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D34
type: string
name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D3
type: string

tool: D19: Course: EG1302A - Spring 2014

tool: D34: Name: Fernando Urbina

tool: D1: Date Created: %d/%d/%d


tool: D3: Assignment: Assignment 05

assistant: ```c
int main() {
  printf("Course: EG1302A - Spring 2014\n");
  printf("Name: Fernando Urbina\n");
  printf("Date Created: %d/%d/%d\n", 1, 28, 2014);
  printf("Assignment: Assignment 05\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x7de,%ecx
  xor    %eax,%eax
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D22
type_guessed: string

tool: D12: Course: EG1302A - Spring 2014

tool: D2: Name: Fernando Urbina

tool: D38: Date Created: %d/%d/%d


tool: D22: Assignment: Assignment 05

assistant: ```c
int main() {
  printf("Course: EG1302A - Spring 2014\n");
  printf("Name: Fernando Urbina\n");
  printf("Date Created: %d/%d/%d\n", 1, 28, 2014);
  printf("Assignment: Assignment 05\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x8,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D1
data_type: string

tool: D4: %ld


tool: D1: Machine is 64 bit

assistant: ```c
int main() {
  int *p = NULL;
  printf("%ld\n", sizeof(p));
  if (sizeof(p) == 4)
    printf("Machine is 32 bit\n");
  else
    printf("Machine is 64 bit\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string

tool: D18: %ld


tool: D0: Machine is 64 bit

assistant: ```c
int main() {
  int *p = NULL;
  printf("%ld\n", sizeof(p));
  if (sizeof(p) == 4)
    printf("Machine is 32 bit\n");
  else
    printf("Machine is 64 bit\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string

tool: D0: %ld


tool: D17: Machine is 64 bit

assistant: ```c
int main() {
  int *p = NULL;
  printf("%ld\n", sizeof(p));
  if (sizeof(p) == 4)
    printf("Machine is 32 bit\n");
  else
    printf("Machine is 64 bit\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D12
datatype: string

tool: D9: %ld


tool: D12: Machine is 64 bit

assistant: ```c
int main() {
  int *p = NULL;
  printf("%ld\n", sizeof(p));
  if (sizeof(p) == 4)
    printf("Machine is 32 bit\n");
  else
    printf("Machine is 64 bit\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<randomizeArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x8,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void randomizeArray(unsigned char *pArray, int len) {
  int i;
  for (i = 0; i < len; i++) {
    pArray[i] = rand() % 255;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<randomizeArray>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  ret
```

assistant: ```c
void randomizeArray(unsigned char *pArray, int len) {
  int i;
  for (i = 0; i < len; i++) {
    pArray[i] = rand() % 255;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<randomizeArray>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %rbp
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %al,-0x1(%rbp)
  cmp    %rbx,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  ret
```

assistant: ```c
void randomizeArray(unsigned char *pArray, int len) {
  int i;
  for (i = 0; i < len; i++) {
    pArray[i] = rand() % 255;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<randomizeArray>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %rbp
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %al,-0x1(%rbp)
  cmp    %rbx,%rbp
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
void randomizeArray(unsigned char *pArray, int len) {
  int i;
  for (i = 0; i < len; i++) {
    pArray[i] = rand() % 255;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ringbuffer_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <normalize@plt>
  leave
  ret
```

assistant: ```c
unsigned int ringbuffer_normalize(unsigned int a, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return normalize(a, end - begin);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ringbuffer_normalize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  cmp    %esi,%edx
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r12d,%ebp
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    %ebp,%ebx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <normalize@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int ringbuffer_normalize(unsigned int a, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return normalize(a, end - begin);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ringbuffer_normalize>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  cmp    %esi,%edx
  push   %rbp
  setae  %dil
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12d,%ebp
  setbe  %dil
  sub    %ebp,%ebx
  call   <assert@plt>
  mov    %ebx,%esi
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <normalize@plt>
```

assistant: ```c
unsigned int ringbuffer_normalize(unsigned int a, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return normalize(a, end - begin);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ringbuffer_normalize>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  cmp    %esi,%edx
  push   %rbp
  setae  %dil
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12d,%ebp
  setbe  %dil
  sub    %ebp,%ebx
  call   <assert@plt>
  mov    %ebx,%esi
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <normalize@plt>
```

assistant: ```c
unsigned int ringbuffer_normalize(unsigned int a, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return normalize(a, end - begin);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__fdimf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x8(%rbp)
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L61
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L61
  pxor   %xmm0,%xmm0
  comiss -0x18(%rbp),%xmm0
  jbe    L83
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L83
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L83
L61:
  movss  -0x14(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  jmp    L47
L83:
  movss  -0x18(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L89
  pxor   %xmm0,%xmm0
  jmp    L47
L89:
  movss  -0x14(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <fpclassify@plt>
  mov    D13(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jne    L68
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
L68:
  movss  -0x4(%rbp),%xmm0
L47:
  leave
  ret
```

assistant: ```c
float __fdimf(float x, float y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0f;
  float r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    __set_errno(ERANGE);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__fdimf>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <fpclassify@plt>
  movss  0x8(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <fpclassify@plt>
  mov    D36(%rip),%rdx
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  mov    (%rdx),%edx
  cmp    %eax,%edx
  je     L9
  cmp    %ebx,%edx
  je     L9
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L41
L74:
  comiss %xmm2,%xmm1
  jb     L55
L20:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0x8(%rsp)
  call   <fpclassify@plt>
  mov    D38(%rip),%rdx
  movss  0x8(%rsp),%xmm0
  cmp    (%rdx),%eax
  jne    L20
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  movss  0x8(%rsp),%xmm0
  jmp    L20
  nopl   0x0(%rax)
L41:
  mov    D38(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  jne    L74
  cmp    %ebx,%edx
  jne    L74
L9:
  subss  %xmm1,%xmm2
  add    $0x10,%rsp
  pop    %rbx
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float __fdimf(float x, float y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0f;
  float r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    __set_errno(ERANGE);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<__fdimf>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <fpclassify@plt>
  movss  0x8(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <fpclassify@plt>
  mov    D4(%rip),%rdx
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  mov    (%rdx),%edx
  cmp    %eax,%edx
  je     L5
  cmp    %ebx,%edx
  je     L5
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L69
L64:
  comiss %xmm2,%xmm1
  jb     L3
L1:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0x8(%rsp)
  call   <fpclassify@plt>
  mov    D0(%rip),%rdx
  movss  0x8(%rsp),%xmm0
  cmp    (%rdx),%eax
  jne    L1
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  movss  0x8(%rsp),%xmm0
  jmp    L1
  nopl   0x0(%rax)
L69:
  mov    D0(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  jne    L64
  cmp    %ebx,%edx
  jne    L64
L5:
  subss  %xmm1,%xmm2
  add    $0x10,%rsp
  pop    %rbx
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float __fdimf(float x, float y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0f;
  float r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    __set_errno(ERANGE);
  return r;
}
```