ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vtstrcspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L10:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L10
L4:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int vtstrcspn(s1, s2)
char *s1, *s2;
{
  char *p;
  for (p = s1; *p && !strchr(s2, *p); p++)
    ;
  return p - s1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vtstrcspn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movzbl (%rdi),%esi
  mov    %rdi,%rbx
  test   %sil,%sil
  je     L3
L26:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L3
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L26
L3:
  mov    %ebx,%eax
  sub    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vtstrcspn(s1, s2)
char *s1, *s2;
{
  char *p;
  for (p = s1; *p && !strchr(s2, *p); p++)
    ;
  return p - s1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vtstrcspn>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L4
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L22
  nopl   (%rax)
L15:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L5
L22:
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L15
L5:
  mov    %ebx,%eax
  sub    %ebp,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vtstrcspn(s1, s2)
char *s1, *s2;
{
  char *p;
  for (p = s1; *p && !strchr(s2, *p); p++)
    ;
  return p - s1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vtstrcspn>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L31
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L38
  nopl   (%rax)
L8:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L34
L38:
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
L34:
  mov    %ebx,%eax
  sub    %ebp,%eax
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vtstrcspn(s1, s2)
char *s1, *s2;
{
  char *p;
  for (p = s1; *p && !strchr(s2, *p); p++)
    ;
  return p - s1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_valid>:
  endbr64
  mov    %rdi,%rax
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%edi
  lea    (%rdx,%rdx,4),%ecx
  lea    (%rdi,%rcx,2),%ecx
  lea    -0xd(%rcx),%esi
  cmp    $0x7,%esi
  jbe    L13
  lea    -0x21(%rcx),%esi
  cmp    $0x7,%esi
  jbe    L13
  mov    0x10(%rax),%esi
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  mov    0x14(%rax),%r8d
  lea    (%rsi,%r8,1),%r9d
  cmp    $0x1f,%r9d
  jg     L10
  cmp    $0x34,%ecx
  jg     L10
  mov    0x4(%rax),%r9d
  mov    (%rax),%ecx
  lea    (%rcx,%r9,2),%ecx
  lea    (%rcx,%rdx,4),%ecx
  lea    (%rdi,%rdi,4),%edx
  lea    (%rdx,%rcx,2),%edx
  add    %esi,%edx
  lea    (%r8,%r8,8),%ecx
  add    %ecx,%edx
  mov    0x18(%rax),%ecx
  lea    (%rdx,%rcx,8),%edx
  sub    %ecx,%edx
  mov    0x1c(%rax),%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%edx
  mov    0x20(%rax),%ecx
  lea    (%rcx,%rcx,2),%ecx
  lea    (%rdx,%rcx,2),%ecx
  movslq %ecx,%rdx
  imul   $0x2e8ba2e9,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  lea    (%rdx,%rsi,2),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  cmp    $0xa,%edx
  mov    $0x0,%ecx
  cmove  %ecx,%edx
  cmp    %edx,0x24(%rax)
  sete   %al
  movzbl %al,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_valid(int *egn) {
  int valid_d, valid_m, control;
  control = (egn[0] * 2 + egn[1] * 4 + egn[2] * 8 + egn[3] * 5 + egn[4] * 10 + egn[5] * 9 + egn[6] * 7 + egn[7] * 3 + egn[8] * 6) % 11;
  valid_d = egn[4] * 10 + egn[5];
  valid_m = egn[2] * 10 + egn[3];
  if ((valid_m > 12 && valid_m < 21) || (valid_m > 32 && valid_m < 41) || (valid_m > 52) || (valid_d > 31)) {
    return 0;
  } else if (((control == 10) ? 0 : control) != egn[9]) {
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_valid>:
  endbr64
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%esi
  mov    %rdi,%rax
  lea    0x0(,%rdx,4),%edi
  add    %edi,%edx
  lea    (%rsi,%rdx,2),%edx
  lea    -0xd(%rdx),%ecx
  cmp    $0x7,%ecx
  jbe    L30
  lea    -0x21(%rdx),%ecx
  cmp    $0x7,%ecx
  jbe    L30
  mov    0x10(%rax),%ecx
  mov    0x14(%rax),%r8d
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  lea    (%rcx,%r8,1),%r9d
  cmp    $0x1f,%r9d
  jg     L30
  cmp    $0x34,%edx
  jg     L30
  mov    0x4(%rax),%r9d
  mov    (%rax),%edx
  lea    (%rsi,%rsi,4),%esi
  lea    (%rdx,%r9,2),%edx
  add    %edi,%edx
  lea    (%rsi,%rdx,2),%edx
  add    %ecx,%edx
  lea    (%r8,%r8,8),%ecx
  add    %ecx,%edx
  mov    0x18(%rax),%ecx
  lea    (%rdx,%rcx,8),%edx
  sub    %ecx,%edx
  mov    0x1c(%rax),%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%edx
  mov    0x20(%rax),%ecx
  lea    (%rcx,%rcx,2),%ecx
  lea    (%rdx,%rcx,2),%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x2e8ba2e9,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x21,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  lea    (%rdx,%rsi,2),%esi
  sub    %esi,%ecx
  mov    %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0xa,%edx
  cmove  %ecx,%edx
  cmp    %edx,0x24(%rax)
  sete   %al
  movzbl %al,%eax
  ret
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_valid(int *egn) {
  int valid_d, valid_m, control;
  control = (egn[0] * 2 + egn[1] * 4 + egn[2] * 8 + egn[3] * 5 + egn[4] * 10 + egn[5] * 9 + egn[6] * 7 + egn[7] * 3 + egn[8] * 6) % 11;
  valid_d = egn[4] * 10 + egn[5];
  valid_m = egn[2] * 10 + egn[3];
  if ((valid_m > 12 && valid_m < 21) || (valid_m > 32 && valid_m < 41) || (valid_m > 52) || (valid_d > 31)) {
    return 0;
  } else if (((control == 10) ? 0 : control) != egn[9]) {
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_valid>:
  endbr64
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%esi
  mov    %rdi,%rax
  lea    0x0(,%rdx,4),%edi
  add    %edi,%edx
  lea    (%rsi,%rdx,2),%edx
  lea    -0xd(%rdx),%ecx
  cmp    $0x7,%ecx
  jbe    L27
  lea    -0x21(%rdx),%ecx
  cmp    $0x7,%ecx
  jbe    L27
  mov    0x10(%rax),%ecx
  mov    0x14(%rax),%r8d
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  lea    (%rcx,%r8,1),%r9d
  cmp    $0x1f,%r9d
  jg     L27
  cmp    $0x34,%edx
  jg     L27
  mov    0x4(%rax),%r9d
  mov    (%rax),%edx
  lea    (%rsi,%rsi,4),%esi
  lea    (%rdx,%r9,2),%edx
  add    %edi,%edx
  lea    (%rsi,%rdx,2),%edx
  add    %ecx,%edx
  lea    (%r8,%r8,8),%ecx
  add    %ecx,%edx
  mov    0x18(%rax),%ecx
  lea    (%rdx,%rcx,8),%edx
  sub    %ecx,%edx
  mov    0x1c(%rax),%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%edx
  mov    0x20(%rax),%ecx
  lea    (%rcx,%rcx,2),%ecx
  lea    (%rdx,%rcx,2),%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x2e8ba2e9,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x21,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  lea    (%rdx,%rsi,2),%esi
  sub    %esi,%ecx
  mov    %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0xa,%edx
  cmove  %ecx,%edx
  cmp    %edx,0x24(%rax)
  sete   %al
  movzbl %al,%eax
  ret
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_valid(int *egn) {
  int valid_d, valid_m, control;
  control = (egn[0] * 2 + egn[1] * 4 + egn[2] * 8 + egn[3] * 5 + egn[4] * 10 + egn[5] * 9 + egn[6] * 7 + egn[7] * 3 + egn[8] * 6) % 11;
  valid_d = egn[4] * 10 + egn[5];
  valid_m = egn[2] * 10 + egn[3];
  if ((valid_m > 12 && valid_m < 21) || (valid_m > 32 && valid_m < 41) || (valid_m > 52) || (valid_d > 31)) {
    return 0;
  } else if (((control == 10) ? 0 : control) != egn[9]) {
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  D53(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  D23(%rip),%xmm1
  andps  %xmm1,%xmm0
  ucomiss D53(%rip),%xmm0
  jp     L114
  ucomiss D53(%rip),%xmm0
  je     L63
L114:
  mov    $0x1,%eax
  jmp    L64
L63:
  movss  D28(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  movss  D23(%rip),%xmm1
  andps  %xmm1,%xmm0
  ucomiss D53(%rip),%xmm0
  jp     L18
  ucomiss D53(%rip),%xmm0
  je     L11
L18:
  mov    $0x1,%eax
  jmp    L64
L11:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L24
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L17
L24:
  mov    $0x1,%eax
  jmp    L64
L17:
  movss  D58(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L57
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L42
L57:
  mov    $0x1,%eax
  jmp    L64
L42:
  mov    $0x0,%eax
L64:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D53
type_infered: byte[4]
name: disassemble_data
arguments: tag: D23
type_infered: byte[4]
name: disassemble_data
arguments: tag: D28
type_infered: byte[4]
name: disassemble_data
arguments: tag: D58
type_infered: byte[4]

tool: {"D53": [0x00,0x00,0x00,0x3e]}

tool: {"D23": [0xff,0xff,0xff,0x7f]}

tool: {"D28": [0x00,0x00,0x00,0xbe]}

tool: {"D58": [0x00,0x00,0x00,0x80]}

assistant: ```c
int main() {
  volatile float a = 0.125f;
  if (__builtin_fabs(a) != 0.125f) {
    return 1;
  }
  volatile float b = -0.125f;
  if (__builtin_fabs(b) != 0.125f) {
    return 1;
  }
  volatile float c = 0.f;
  if (__builtin_fabs(c) != 0.f) {
    return 1;
  }
  volatile float d = -0.f;
  if (__builtin_fabs(d) != 0.f) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  movss  D53(%rip),%xmm0
  movss  %xmm0,-0x10(%rsp)
  movss  -0x10(%rsp),%xmm0
  andps  D46(%rip),%xmm0
  ucomiss D53(%rip),%xmm0
  jp     L49
  jne    L49
  movss  D12(%rip),%xmm0
  movss  %xmm0,-0xc(%rsp)
  movss  -0xc(%rsp),%xmm0
  andps  D46(%rip),%xmm0
  ucomiss D53(%rip),%xmm0
  jp     L10
  jne    L10
  movl   $0x0,-0x8(%rsp)
  movss  -0x8(%rsp),%xmm0
  ucomiss D39(%rip),%xmm0
  jp     L34
  jne    L34
  movss  D28(%rip),%xmm0
  movss  %xmm0,-0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ucomiss D39(%rip),%xmm0
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
L49:
  mov    $0x1,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
L34:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D53
type: byte[4]
name: parse_data
arguments: data_label: D46
type: byte[16]
name: parse_data
arguments: data_label: D12
type: byte[4]
name: parse_data
arguments: data_label: D39
type: byte[4]
name: parse_data
arguments: data_label: D28
type: byte[4]

tool: {"D53": [0x00,0x00,0x00,0x3e]}

tool: {"D46": [0xff,0xff,0xff,0x7f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D12": [0x00,0x00,0x00,0xbe]}

tool: {"D39": [0x00,0x00,0x00,0x00]}

tool: {"D28": [0x00,0x00,0x00,0x80]}

assistant: ```c
int main() {
  volatile float a = 0.125f;
  if (__builtin_fabs(a) != 0.125f) {
    return 1;
  }
  volatile float b = -0.125f;
  if (__builtin_fabs(b) != 0.125f) {
    return 1;
  }
  volatile float c = 0.f;
  if (__builtin_fabs(c) != 0.f) {
    return 1;
  }
  volatile float d = -0.f;
  if (__builtin_fabs(d) != 0.f) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  movss  D27(%rip),%xmm0
  movss  D11(%rip),%xmm1
  movss  %xmm0,-0x10(%rsp)
  movss  -0x10(%rsp),%xmm0
  andps  %xmm1,%xmm0
  ucomiss D27(%rip),%xmm0
  jp     L39
  jne    L39
  movss  D57(%rip),%xmm0
  movss  %xmm0,-0xc(%rsp)
  movss  -0xc(%rsp),%xmm0
  andps  %xmm1,%xmm0
  ucomiss D27(%rip),%xmm0
  jp     L39
  jne    L39
  movl   $0x0,-0x8(%rsp)
  movss  -0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  ucomiss %xmm0,%xmm1
  jp     L39
  jne    L39
  movss  D12(%rip),%xmm1
  xor    %eax,%eax
  mov    $0x1,%edx
  movss  %xmm1,-0x4(%rsp)
  movss  -0x4(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  setp   %al
  cmovne %edx,%eax
  ret
  xchg   %ax,%ax
L39:
  mov    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
type_infered: byte[4]
name: read_data
arguments: data_label: D11
type_infered: byte[4]
name: read_data
arguments: data_label: D57
type_infered: byte[4]
name: read_data
arguments: data_label: D12
type_infered: byte[4]

tool: {"D27": [0x00,0x00,0x00,0x3e]}

tool: {"D11": [0xff,0xff,0xff,0x7f]}

tool: {"D57": [0x00,0x00,0x00,0xbe]}

tool: {"D12": [0x00,0x00,0x00,0x80]}

assistant: ```c
int main() {
  volatile float a = 0.125f;
  if (__builtin_fabs(a) != 0.125f) {
    return 1;
  }
  volatile float b = -0.125f;
  if (__builtin_fabs(b) != 0.125f) {
    return 1;
  }
  volatile float c = 0.f;
  if (__builtin_fabs(c) != 0.f) {
    return 1;
  }
  volatile float d = -0.f;
  if (__builtin_fabs(d) != 0.f) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  movss  D1(%rip),%xmm0
  movss  D36(%rip),%xmm1
  movss  %xmm0,-0x10(%rsp)
  movss  -0x10(%rsp),%xmm0
  andps  %xmm1,%xmm0
  ucomiss D1(%rip),%xmm0
  jp     L51
  jne    L51
  movss  D59(%rip),%xmm0
  movss  %xmm0,-0xc(%rsp)
  movss  -0xc(%rsp),%xmm0
  andps  %xmm1,%xmm0
  ucomiss D1(%rip),%xmm0
  jp     L51
  jne    L51
  movl   $0x0,-0x8(%rsp)
  movss  -0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  ucomiss %xmm0,%xmm1
  jp     L51
  jne    L51
  movss  D37(%rip),%xmm1
  xor    %eax,%eax
  mov    $0x1,%edx
  movss  %xmm1,-0x4(%rsp)
  movss  -0x4(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  setp   %al
  cmovne %edx,%eax
  ret
  xchg   %ax,%ax
L51:
  mov    $0x1,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: byte[4]
name: disassemble_data
arguments: data_tag: D36
type: byte[4]
name: disassemble_data
arguments: data_tag: D59
type: byte[4]
name: disassemble_data
arguments: data_tag: D37
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3e]}

tool: {"D36": [0xff,0xff,0xff,0x7f]}

tool: {"D59": [0x00,0x00,0x00,0xbe]}

tool: {"D37": [0x00,0x00,0x00,0x80]}

assistant: ```c
int main() {
  volatile float a = 0.125f;
  if (__builtin_fabs(a) != 0.125f) {
    return 1;
  }
  volatile float b = -0.125f;
  if (__builtin_fabs(b) != 0.125f) {
    return 1;
  }
  volatile float c = 0.f;
  if (__builtin_fabs(c) != 0.f) {
    return 1;
  }
  volatile float d = -0.f;
  if (__builtin_fabs(d) != 0.f) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ReadName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  movl   $0x1,(%rdx)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movb   $0x0,(%rax)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L121
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%edi
  jmp    L122
L34:
  lea    0x1(%rdx),%esi
  mov    %edx,%edx
  mov    %al,0x0(%rbp,%rdx,1)
  add    $0x1,%rbx
  test   %ecx,%ecx
  jne    L39
  addl   $0x1,(%r12)
  mov    %esi,%edx
L132:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L103
L122:
  cmp    $0xbf,%al
  jbe    L34
  movzbl %al,%eax
  shl    $0x8,%eax
  movzbl 0x1(%rbx),%ecx
  lea    -0xc000(%rax,%rcx,1),%ebx
  add    %r13,%rbx
  mov    %edi,%ecx
  jmp    L132
L39:
  mov    %esi,%edx
  jmp    L132
L103:
  mov    %edx,%edx
  movb   $0x0,0x0(%rbp,%rdx,1)
  cmp    $0x1,%ecx
  je     L76
L121:
  mov    $0x0,%ebx
  lea    0x1(%rbp),%r13
  lea    0x2(%rbp),%r12
  jmp    L10
L76:
  addl   $0x1,(%r12)
  jmp    L121
L81:
  movslq %ebx,%rax
  movb   $0x2e,0x0(%rbp,%rax,1)
  add    $0x1,%ebx
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jge    L86
  movslq %ebx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%edx
  test   %dl,%dl
  je     L81
  lea    0x0(%r13,%rcx,1),%rax
  movzbl %dl,%esi
  add    %r12,%rcx
  lea    -0x1(%rsi),%edx
  add    %rdx,%rcx
L130:
  movzbl (%rax),%edx
  mov    %dl,-0x1(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L130
  add    %esi,%ebx
  jmp    L81
L86:
  movslq %ebx,%rbx
  movb   $0x0,-0x1(%rbp,%rbx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
u_char *ReadName(unsigned char *reader, unsigned char *buffer, int *count) {
  unsigned char *name;
  unsigned int p = 0, jumped = 0, offset;
  int i, j;
  *count = 1;
  name = (unsigned char *)malloc(256);
  name[0] = '\0';
  while (*reader != 0) {
    if (*reader >= 192) {
      offset = (*reader) * 256 + *(reader + 1) - 49152;
      reader = buffer + offset - 1;
      jumped = 1;
    } else {
      name[p++] = *reader;
    }
    reader = reader + 1;
    if (jumped == 0) {
      *count = *count + 1;
    }
  }
  name[p] = '\0';
  if (jumped == 1) {
    *count = *count + 1;
  }
  for (i = 0; i < (int)strlen((const char *)name); i++) {
    p = name[i];
    for (j = 0; j < (int)p; j++) {
      name[i] = name[i + 1];
      i = i + 1;
    }
    name[i] = '.';
  }
  name[i - 1] = '\0';
  return name;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ReadName>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x8,%rsp
  movl   $0x1,(%rdx)
  call   <malloc@plt>
  movb   $0x0,(%rax)
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L21
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl 0x1(%rbx),%ecx
  shl    $0x8,%eax
  add    %ecx,%eax
  mov    $0x1,%ecx
  cltq
  lea    -0xc000(%r13,%rax,1),%rbx
L68:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L35
L96:
  cmp    $0xbf,%al
  ja     L8
  lea    0x1(%rdx),%esi
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%rbx
  mov    %esi,%edx
  test   %ecx,%ecx
  jne    L68
  addl   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  mov    %esi,%edx
  test   %al,%al
  jne    L96
L35:
  movb   $0x0,(%r12,%rdx,1)
  cmp    $0x1,%ecx
  je     L109
L21:
  xor    %ebx,%ebx
  jmp    L59
  nop
L78:
  lea    (%r12,%rax,1),%rdi
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L102
  movzbl %bpl,%edx
  lea    0x1(%r12,%rax,1),%rsi
  add    %ebp,%ebx
  call   <memmove@plt>
  movslq %ebx,%rdi
  add    %r12,%rdi
L102:
  movb   $0x2e,(%rdi)
  add    $0x1,%ebx
L59:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r8
  movslq %ebx,%rax
  cmp    %r8d,%ebx
  jl     L78
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L109:
  addl   $0x1,0x0(%rbp)
  jmp    L21
```

assistant: ```c
u_char *ReadName(unsigned char *reader, unsigned char *buffer, int *count) {
  unsigned char *name;
  unsigned int p = 0, jumped = 0, offset;
  int i, j;
  *count = 1;
  name = (unsigned char *)malloc(256);
  name[0] = '\0';
  while (*reader != 0) {
    if (*reader >= 192) {
      offset = (*reader) * 256 + *(reader + 1) - 49152;
      reader = buffer + offset - 1;
      jumped = 1;
    } else {
      name[p++] = *reader;
    }
    reader = reader + 1;
    if (jumped == 0) {
      *count = *count + 1;
    }
  }
  name[p] = '\0';
  if (jumped == 1) {
    *count = *count + 1;
  }
  for (i = 0; i < (int)strlen((const char *)name); i++) {
    p = name[i];
    for (j = 0; j < (int)p; j++) {
      name[i] = name[i + 1];
      i = i + 1;
    }
    name[i] = '.';
  }
  name[i - 1] = '\0';
  return name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReadName>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x8,%rsp
  movl   $0x1,(%rdx)
  call   <malloc@plt>
  movb   $0x0,(%rax)
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L20
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl 0x1(%rbx),%ecx
  shl    $0x8,%eax
  add    %ecx,%eax
  mov    $0x1,%ecx
  cltq
  lea    -0xc000(%r13,%rax,1),%rbx
L65:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L60
L15:
  cmp    $0xbf,%al
  ja     L12
  lea    0x1(%rdx),%esi
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%rbx
  mov    %esi,%edx
  test   %ecx,%ecx
  jne    L65
  addl   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  mov    %esi,%edx
  test   %al,%al
  jne    L15
L60:
  movb   $0x0,(%r12,%rdx,1)
  cmp    $0x1,%ecx
  je     L50
L20:
  xor    %ebx,%ebx
  jmp    L66
  nop
L11:
  lea    (%r12,%rax,1),%rdi
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L74
  movzbl %bpl,%edx
  lea    0x1(%r12,%rax,1),%rsi
  add    %ebp,%ebx
  call   <memmove@plt>
  movslq %ebx,%rdi
  add    %r12,%rdi
L74:
  movb   $0x2e,(%rdi)
  add    $0x1,%ebx
L66:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r8
  movslq %ebx,%rax
  cmp    %r8d,%ebx
  jl     L11
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  addl   $0x1,0x0(%rbp)
  jmp    L20
```

assistant: ```c
u_char *ReadName(unsigned char *reader, unsigned char *buffer, int *count) {
  unsigned char *name;
  unsigned int p = 0, jumped = 0, offset;
  int i, j;
  *count = 1;
  name = (unsigned char *)malloc(256);
  name[0] = '\0';
  while (*reader != 0) {
    if (*reader >= 192) {
      offset = (*reader) * 256 + *(reader + 1) - 49152;
      reader = buffer + offset - 1;
      jumped = 1;
    } else {
      name[p++] = *reader;
    }
    reader = reader + 1;
    if (jumped == 0) {
      *count = *count + 1;
    }
  }
  name[p] = '\0';
  if (jumped == 1) {
    *count = *count + 1;
  }
  for (i = 0; i < (int)strlen((const char *)name); i++) {
    p = name[i];
    for (j = 0; j < (int)p; j++) {
      name[i] = name[i + 1];
      i = i + 1;
    }
    name[i] = '.';
  }
  name[i - 1] = '\0';
  return name;
}
```
user: What is the c source code of the assembly code below:

```asm
<strtoip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inet_aton@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
uint32_t strtoip(const char *ipstr) {
  struct in_addr in;
  inet_aton(ipstr, &in);
  return in.s_addr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtoip>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <inet_aton@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t strtoip(const char *ipstr) {
  struct in_addr in;
  inet_aton(ipstr, &in);
  return in.s_addr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtoip>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <inet_aton@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t strtoip(const char *ipstr) {
  struct in_addr in;
  inet_aton(ipstr, &in);
  return in.s_addr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtoip>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <inet_aton@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t strtoip(const char *ipstr) {
  struct in_addr in;
  inet_aton(ipstr, &in);
  return in.s_addr;
}
```