ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<series4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edi,%edi
  jle    L15
  pxor   %xmm4,%xmm4
  mov    %edi,%ebp
  mov    $0x1,%ebx
  movsd  %xmm4,0x8(%rsp)
  lea    D35(%rip),%r12
  nopl   0x0(%rax)
L55:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebx,%ebp
  je     L50
  mov    $0x2b,%edi
  call   <putchar@plt>
  pxor   %xmm1,%xmm1
  movsd  D10(%rip),%xmm0
  cvtsi2sd %ebx,%xmm1
  add    $0x1,%ebx
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,%ebx
  jle    L55
L23:
  add    $0x10,%rsp
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0x2e,%edi
  lea    0x1(%rbp),%ebx
  call   <putchar@plt>
  pxor   %xmm1,%xmm1
  movsd  D10(%rip),%xmm0
  cvtsi2sd %ebp,%xmm1
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebx,%ebp
  jge    L55
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L15:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
  movapd %xmm5,%xmm0
  jmp    L23
```

tool_calls: name: disassemble_data
arguments: tag: D35
datatype: string
name: disassemble_data
arguments: tag: D10
datatype: f64
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D35: 1/%d

tool: D10: 1

tool: D11: 
Sum of the above series is %f


assistant: ```c
void series4(int n) {
  int i;
  double sum = 0.0;
  for (i = 1; i <= n; i++) {
    printf("1/%d", i);
    i != n ? printf("+") : printf(".");
    sum += 1.0 / i;
  }
  printf("\nSum of the above series is %f\n", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L17
  addq   $0xf,-0x10(%rbp)
  shlq   -0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L5
L13:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L17:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int add_byte(int c, char **lineptr, size_t slen, size_t *n) {
  char *nline;
  size_t new_size = slen + 1;
  if (new_size > *n) {
    new_size += 16 - 1;
    new_size *= 2;
    nline = xrealloc(*lineptr, new_size);
    if (!nline)
      return -1;
    *lineptr = nline;
    *n = new_size;
  }
  (*lineptr)[slen] = c;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<add_byte>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  lea    0x1(%rdx),%rax
  cmp    %rax,(%rcx)
  jb     L15
L22:
  mov    0x0(%rbp),%rax
  mov    %r13b,(%rax,%rbx,1)
  mov    $0x0,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    %rcx,%r12
  lea    0x20(%rdx,%rdx,1),%r14
  mov    %r14,%rsi
  mov    0x0(%rbp),%rdi
  call   <xrealloc@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,0x0(%rbp)
  mov    %r14,(%r12)
  jmp    L22
L29:
  mov    $0xffffffff,%eax
  jmp    L26
```

assistant: ```c
int add_byte(int c, char **lineptr, size_t slen, size_t *n) {
  char *nline;
  size_t new_size = slen + 1;
  if (new_size > *n) {
    new_size += 16 - 1;
    new_size *= 2;
    nline = xrealloc(*lineptr, new_size);
    if (!nline)
      return -1;
    *lineptr = nline;
    *n = new_size;
  }
  (*lineptr)[slen] = c;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_byte>:
  endbr64
  push   %r14
  lea    0x1(%rdx),%rax
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rsi),%rdi
  cmp    %rax,(%rcx)
  jb     L21
L20:
  mov    %r13b,(%rdi,%rbx,1)
  xor    %eax,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L21:
  lea    0x20(%rdx,%rdx,1),%r14
  mov    %rsi,%r12
  mov    %rcx,%rbp
  mov    %r14,%rsi
  call   <xrealloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L1
  mov    %rax,(%r12)
  mov    %r14,0x0(%rbp)
  jmp    L20
L1:
  mov    $0xffffffff,%eax
  jmp    L24
```

assistant: ```c
int add_byte(int c, char **lineptr, size_t slen, size_t *n) {
  char *nline;
  size_t new_size = slen + 1;
  if (new_size > *n) {
    new_size += 16 - 1;
    new_size *= 2;
    nline = xrealloc(*lineptr, new_size);
    if (!nline)
      return -1;
    *lineptr = nline;
    *n = new_size;
  }
  (*lineptr)[slen] = c;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_byte>:
  endbr64
  push   %r14
  lea    0x1(%rdx),%rax
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rsi),%rdi
  cmp    %rax,(%rcx)
  jb     L22
L15:
  mov    %r13b,(%rdi,%rbx,1)
  xor    %eax,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L22:
  lea    0x20(%rdx,%rdx,1),%r14
  mov    %rsi,%r12
  mov    %rcx,%rbp
  mov    %r14,%rsi
  call   <xrealloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L5
  mov    %rax,(%r12)
  mov    %r14,0x0(%rbp)
  jmp    L15
L5:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int add_byte(int c, char **lineptr, size_t slen, size_t *n) {
  char *nline;
  size_t new_size = slen + 1;
  if (new_size > *n) {
    new_size += 16 - 1;
    new_size *= 2;
    nline = xrealloc(*lineptr, new_size);
    if (!nline)
      return -1;
    *lineptr = nline;
    *n = new_size;
  }
  (*lineptr)[slen] = c;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<infinite_for_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L8:
  mov    $0x0,%eax
  call   <A@plt>
  jmp    L8
```

assistant: ```c
void infinite_for_test(void) {
  for (;;) {
    A();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<infinite_for_test>:
  endbr64
  sub    $0x8,%rsp
L4:
  mov    $0x0,%eax
  call   <A@plt>
  jmp    L4
```

assistant: ```c
void infinite_for_test(void) {
  for (;;) {
    A();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<infinite_for_test>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <A@plt>
  jmp    L6
```

assistant: ```c
void infinite_for_test(void) {
  for (;;) {
    A();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<infinite_for_test>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <A@plt>
  jmp    L5
```

assistant: ```c
void infinite_for_test(void) {
  for (;;) {
    A();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bs_conv_14be_16le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bs_conv_14be_8@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bs_conv_swab16@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bs_conv_14be_16le(const unsigned char *in_buf, int size, unsigned char *out_buf) {
  size = bs_conv_14be_8(in_buf, size, out_buf);
  size = bs_conv_swab16(out_buf, size, out_buf);
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bs_conv_14be_16le>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <bs_conv_14be_8@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  mov    %rbx,%rdi
  call   <bs_conv_swab16@plt>
  pop    %rbx
  ret
```

assistant: ```c
int bs_conv_14be_16le(const unsigned char *in_buf, int size, unsigned char *out_buf) {
  size = bs_conv_14be_8(in_buf, size, out_buf);
  size = bs_conv_swab16(out_buf, size, out_buf);
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bs_conv_14be_16le>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  call   <bs_conv_14be_8@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <bs_conv_swab16@plt>
```

assistant: ```c
int bs_conv_14be_16le(const unsigned char *in_buf, int size, unsigned char *out_buf) {
  size = bs_conv_14be_8(in_buf, size, out_buf);
  size = bs_conv_swab16(out_buf, size, out_buf);
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bs_conv_14be_16le>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  call   <bs_conv_14be_8@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <bs_conv_swab16@plt>
```

assistant: ```c
int bs_conv_14be_16le(const unsigned char *in_buf, int size, unsigned char *out_buf) {
  size = bs_conv_14be_8(in_buf, size, out_buf);
  size = bs_conv_swab16(out_buf, size, out_buf);
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x13,%esi
  mov    $0x11,%edi
  call   <multu_variants@plt>
  cmp    $0x143,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x18697,%esi
  mov    $0x12fcd,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x12309ce5,%esi
  mov    $0xba43b7,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x7fffffff,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x80000000,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  assert(multu_variants(17, 19) == 323);
  assert(multu_variants(77773, 99991) == 7776600043);
  assert(multu_variants(12207031, 305175781) == 3725290219116211);
  assert(multu_variants(0x80000000U, 0x7FFFFFFF) == 0x3FFFFFFF80000000);
  assert(multu_variants(0x80000000U, 0x80000000U) == 0x4000000000000000);
  assert(multu_variants(0xFFFFFFFFU, 0xFFFFFFFFU) == 0xFFFFFFFE00000001U);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%esi
  mov    $0x11,%edi
  call   <multu_variants@plt>
  cmp    $0x143,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x18697,%esi
  mov    $0x12fcd,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x12309ce5,%esi
  mov    $0xba43b7,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x7fffffff,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x80000000,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <multu_variants@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(multu_variants(17, 19) == 323);
  assert(multu_variants(77773, 99991) == 7776600043);
  assert(multu_variants(12207031, 305175781) == 3725290219116211);
  assert(multu_variants(0x80000000U, 0x7FFFFFFF) == 0x3FFFFFFF80000000);
  assert(multu_variants(0x80000000U, 0x80000000U) == 0x4000000000000000);
  assert(multu_variants(0xFFFFFFFFU, 0xFFFFFFFFU) == 0xFFFFFFFE00000001U);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%esi
  mov    $0x11,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  cmp    $0x143,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x18697,%esi
  mov    $0x12fcd,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x12309ce5,%esi
  mov    $0xba43b7,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x7fffffff,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x80000000,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(multu_variants(17, 19) == 323);
  assert(multu_variants(77773, 99991) == 7776600043);
  assert(multu_variants(12207031, 305175781) == 3725290219116211);
  assert(multu_variants(0x80000000U, 0x7FFFFFFF) == 0x3FFFFFFF80000000);
  assert(multu_variants(0x80000000U, 0x80000000U) == 0x4000000000000000);
  assert(multu_variants(0xFFFFFFFFU, 0xFFFFFFFFU) == 0xFFFFFFFE00000001U);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%esi
  mov    $0x11,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  cmp    $0x143,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x18697,%esi
  mov    $0x12fcd,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x12309ce5,%esi
  mov    $0xba43b7,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x7fffffff,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x80000000,%esi
  mov    $0x80000000,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <multu_variants@plt>
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(multu_variants(17, 19) == 323);
  assert(multu_variants(77773, 99991) == 7776600043);
  assert(multu_variants(12207031, 305175781) == 3725290219116211);
  assert(multu_variants(0x80000000U, 0x7FFFFFFF) == 0x3FFFFFFF80000000);
  assert(multu_variants(0x80000000U, 0x80000000U) == 0x4000000000000000);
  assert(multu_variants(0xFFFFFFFFU, 0xFFFFFFFFU) == 0xFFFFFFFE00000001U);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L64
L3:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L8
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L64
L8:
  cmpl   $0x0,-0x8(%rbp)
  jne    L65
  mov    $0x0,%eax
  jmp    L64
L65:
  subl   $0x1,-0x8(%rbp)
  jmp    L20
L64:
  leave
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  unsigned int i;
  unsigned int n = strlen(s);
  if (n == 0)
    return NULL;
  for (i = n - 1;; i--) {
    if (s[i] == c) {
      return (char *)&s[i];
    } else if (i == 0) {
      return NULL;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  test   %eax,%eax
  je     L8
  lea    -0x1(%rax),%edx
  mov    %edx,%ecx
  add    %rbx,%rcx
  movsbl (%rcx),%esi
  cmp    %esi,%ebp
  je     L51
  test   %edx,%edx
  je     L20
  lea    -0x2(%rax),%eax
  add    %rbx,%rax
L3:
  mov    %rax,%rcx
  movsbl (%rax),%edx
  cmp    %ebp,%edx
  je     L51
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  je     L33
  mov    %rdx,%rax
  jmp    L3
L8:
  mov    $0x0,%ecx
  jmp    L51
L20:
  mov    $0x0,%ecx
  jmp    L51
L33:
  mov    $0x0,%ecx
L51:
  mov    %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  unsigned int i;
  unsigned int n = strlen(s);
  if (n == 0)
    return NULL;
  for (i = n - 1;; i--) {
    if (s[i] == c) {
      return (char *)&s[i];
    } else if (i == 0) {
      return NULL;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L43
  lea    -0x1(%rax),%r8d
  mov    %r8,%rdx
  add    %rbx,%r8
  movsbl (%r8),%ecx
  cmp    %ecx,%ebp
  je     L23
  test   %edx,%edx
  je     L43
  sub    $0x2,%eax
  add    %rbx,%rax
  jmp    L50
  cs nopw 0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  je     L43
  mov    %rdx,%rax
L50:
  movsbl (%rax),%edx
  mov    %rax,%r8
  cmp    %ebp,%edx
  jne    L19
L23:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L43:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  unsigned int i;
  unsigned int n = strlen(s);
  if (n == 0)
    return NULL;
  for (i = n - 1;; i--) {
    if (s[i] == c) {
      return (char *)&s[i];
    } else if (i == 0) {
      return NULL;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L15
  lea    -0x1(%rax),%r8d
  mov    %r8,%rdx
  add    %rbx,%r8
  movsbl (%r8),%ecx
  cmp    %ecx,%ebp
  je     L33
  test   %edx,%edx
  je     L15
  sub    $0x2,%eax
  add    %rbx,%rax
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L45:
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  je     L15
  mov    %rdx,%rax
L26:
  movsbl (%rax),%edx
  mov    %rax,%r8
  cmp    %ebp,%edx
  jne    L45
L33:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L15:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  unsigned int i;
  unsigned int n = strlen(s);
  if (n == 0)
    return NULL;
  for (i = n - 1;; i--) {
    if (s[i] == c) {
      return (char *)&s[i];
    } else if (i == 0) {
      return NULL;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mod(int k, int n) {
  int j = k % n;
  if (j < 0) {
    j = j + n;
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  test   %edx,%edx
  mov    %edx,%eax
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int k, int n) {
  int j = k % n;
  if (j < 0) {
    j = j + n;
  }
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int k, int n) {
  int j = k % n;
  if (j < 0) {
    j = j + n;
  }
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int k, int n) {
  int j = k % n;
  if (j < 0) {
    j = j + n;
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<free3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L29
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L29:
  cmpq   $0x0,-0x10(%rbp)
  je     L5
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void free3(void *data0, void *data1, void *data2) {
  if (data0)
    free(data0);
  if (data1)
    free(data1);
  if (data2)
    free(data2);
}
```
user: What is the c source code of the assembly code below?

```asm
<free3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L22
  call   <free@plt>
L22:
  test   %rbp,%rbp
  je     L27
  mov    %rbp,%rdi
  call   <free@plt>
L27:
  test   %rbx,%rbx
  je     L0
  mov    %rbx,%rdi
  call   <free@plt>
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free3(void *data0, void *data1, void *data2) {
  if (data0)
    free(data0);
  if (data1)
    free(data1);
  if (data2)
    free(data2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free3>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  call   <free@plt>
L6:
  test   %r12,%r12
  je     L0
  mov    %r12,%rdi
  call   <free@plt>
L0:
  test   %rbp,%rbp
  je     L16
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
  nopl   0x0(%rax)
L16:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free3(void *data0, void *data1, void *data2) {
  if (data0)
    free(data0);
  if (data1)
    free(data1);
  if (data2)
    free(data2);
}
```
user: What is the c source code of the assembly code below?

```asm
<free3>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L16
  call   <free@plt>
L16:
  test   %r12,%r12
  je     L19
  mov    %r12,%rdi
  call   <free@plt>
L19:
  test   %rbp,%rbp
  je     L17
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
  nopl   0x0(%rax)
L17:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free3(void *data0, void *data1, void *data2) {
  if (data0)
    free(data0);
  if (data1)
    free(data1);
  if (data2)
    free(data2);
}
```