ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  je     L15
  lea    D15(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  jne    L3
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string

tool: D9: %d

tool: D15: %d


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  while (num != 42) {
    printf("%d\n", num);
    scanf("%d", &num);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<load_u16_little>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t load_u16_little(const void *mem) {
  uint16_t ret;
  const uint8_t *x = (const uint8_t *)mem;
  ret = x[0] << 0 | x[1] << 8;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<load_u16_little>:
  endbr64
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint16_t load_u16_little(const void *mem) {
  uint16_t ret;
  const uint8_t *x = (const uint8_t *)mem;
  ret = x[0] << 0 | x[1] << 8;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load_u16_little>:
  endbr64
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint16_t load_u16_little(const void *mem) {
  uint16_t ret;
  const uint8_t *x = (const uint8_t *)mem;
  ret = x[0] << 0 | x[1] << 8;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<load_u16_little>:
  endbr64
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint16_t load_u16_little(const void *mem) {
  uint16_t ret;
  const uint8_t *x = (const uint8_t *)mem;
  ret = x[0] << 0 | x[1] << 8;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findExeNameStart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L8
L36:
  subl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x0,-0x4(%rbp)
  jle    L35
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L35
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L36
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L60
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L11
L60:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L27
L11:
  mov    -0x4(%rbp),%eax
L27:
  leave
  ret
```

assistant: ```c
int findExeNameStart(const char *exec_name) {
  int exename_start = (int)strlen(exec_name);
  while ((exename_start > 0) && (exec_name[exename_start] != '\\') && (exec_name[exename_start] != '/')) {
    exename_start--;
  }
  if (exec_name[exename_start] == '\\' || exec_name[exename_start] == '/') {
    return exename_start + 1;
  } else {
    return exename_start;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findExeNameStart>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jle    L5
  cltq
  add    %rbx,%rax
L42:
  movzbl (%rax),%ecx
  cmp    $0x2f,%cl
  je     L5
  cmp    $0x5c,%cl
  je     L5
  sub    $0x1,%rax
  sub    $0x1,%edx
  jne    L42
L5:
  movslq %edx,%rax
  movzbl (%rbx,%rax,1),%eax
  cmp    $0x5c,%al
  je     L32
  cmp    $0x2f,%al
  je     L32
L60:
  mov    %edx,%eax
  pop    %rbx
  ret
L32:
  add    $0x1,%edx
  jmp    L60
```

assistant: ```c
int findExeNameStart(const char *exec_name) {
  int exename_start = (int)strlen(exec_name);
  while ((exename_start > 0) && (exec_name[exename_start] != '\\') && (exec_name[exename_start] != '/')) {
    exename_start--;
  }
  if (exec_name[exename_start] == '\\' || exec_name[exename_start] == '/') {
    return exename_start + 1;
  } else {
    return exename_start;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findExeNameStart>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rcx
  mov    %eax,%r8d
  lea    (%rbx,%rcx,1),%rdx
  test   %eax,%eax
  jg     L54
  jmp    L22
  nopl   (%rax)
L42:
  cmp    $0x5c,%al
  je     L15
  sub    $0x1,%rdx
  sub    $0x1,%r8d
  je     L70
L54:
  movzbl (%rdx),%eax
  cmp    $0x2f,%al
  jne    L42
L53:
  cmp    $0x5c,%al
  je     L15
  cmp    $0x2f,%al
  je     L15
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x1,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L70:
  movzbl (%rbx),%eax
  jmp    L53
L22:
  movzbl (%rbx,%rcx,1),%eax
  jmp    L53
```

assistant: ```c
int findExeNameStart(const char *exec_name) {
  int exename_start = (int)strlen(exec_name);
  while ((exename_start > 0) && (exec_name[exename_start] != '\\') && (exec_name[exename_start] != '/')) {
    exename_start--;
  }
  if (exec_name[exename_start] == '\\' || exec_name[exename_start] == '/') {
    return exename_start + 1;
  } else {
    return exename_start;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findExeNameStart>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rcx
  mov    %eax,%r8d
  lea    (%rbx,%rcx,1),%rdx
  test   %eax,%eax
  jg     L38
  jmp    L39
  nopl   (%rax)
L53:
  cmp    $0x5c,%al
  je     L79
  sub    $0x1,%rdx
  sub    $0x1,%r8d
  je     L45
L38:
  movzbl (%rdx),%eax
  cmp    $0x2f,%al
  jne    L53
L26:
  cmp    $0x5c,%al
  je     L79
  cmp    $0x2f,%al
  je     L79
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  add    $0x1,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L45:
  movzbl (%rbx),%eax
  jmp    L26
L39:
  movzbl (%rbx,%rcx,1),%eax
  jmp    L26
```

assistant: ```c
int findExeNameStart(const char *exec_name) {
  int exename_start = (int)strlen(exec_name);
  while ((exename_start > 0) && (exec_name[exename_start] != '\\') && (exec_name[exename_start] != '/')) {
    exename_start--;
  }
  if (exec_name[exename_start] == '\\' || exec_name[exename_start] == '/') {
    return exename_start + 1;
  } else {
    return exename_start;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<machine_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <i8k_get_machine_id@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string

tool: D5: ?

tool: D19: %s


assistant: ```c
int machine_id() {
  char *machine_id;
  if ((machine_id = i8k_get_machine_id()) == NULL) {
    machine_id = "?";
  }
  printf("%s\n", machine_id);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<machine_id>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <i8k_get_machine_id@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  lea    D10(%rip),%rax
  cmove  %rax,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string

tool: D10: ?

tool: D1: %s


assistant: ```c
int machine_id() {
  char *machine_id;
  if ((machine_id = i8k_get_machine_id()) == NULL) {
    machine_id = "?";
  }
  printf("%s\n", machine_id);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<machine_id>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <i8k_get_machine_id@plt>
  lea    D7(%rip),%rdi
  test   %rax,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string

tool: D7: %s


tool: D18: ?

assistant: ```c
int machine_id() {
  char *machine_id;
  if ((machine_id = i8k_get_machine_id()) == NULL) {
    machine_id = "?";
  }
  printf("%s\n", machine_id);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<machine_id>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <i8k_get_machine_id@plt>
  lea    D1(%rip),%rdi
  test   %rax,%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D11
datatype: string

tool: D1: %s


tool: D11: ?

assistant: ```c
int machine_id() {
  char *machine_id;
  if ((machine_id = i8k_get_machine_id()) == NULL) {
    machine_id = "?";
  }
  printf("%s\n", machine_id);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vec_subtract(double A[3], double B[3], double output[3]) {
  output[0] = A[0] - B[0];
  output[1] = A[1] - B[1];
  output[2] = A[2] - B[2];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vec_subtract>:
  endbr64
  movsd  (%rdi),%xmm0
  subsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  subsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  subsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void vec_subtract(double A[3], double B[3], double output[3]) {
  output[0] = A[0] - B[0];
  output[1] = A[1] - B[1];
  output[2] = A[2] - B[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec_subtract>:
  endbr64
  movsd  (%rdi),%xmm0
  subsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  subsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  subsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void vec_subtract(double A[3], double B[3], double output[3]) {
  output[0] = A[0] - B[0];
  output[1] = A[1] - B[1];
  output[2] = A[2] - B[2];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movq   $0x1,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x2,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x24(%rbp)
  jmp    L35
L49:
  movq   $0x2,-0x20(%rbp)
  jmp    L118
L77:
  mov    -0x10(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  imul   %rax,%rax
  shr    $0x2,%rax
  mov    %rax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  js     L104
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L18
L104:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L18:
  subss  -0x24(%rbp),%xmm0
  movss  D7(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L75
  movss  D7(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  je     L95
L75:
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  js     L99
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  jmp    L102
L99:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm1
L102:
  movss  -0x24(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  D7(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L5
  movss  D7(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jne    L5
L95:
  pxor   %xmm2,%xmm2
  cvtss2sd -0x24(%rbp),%xmm2
  movq   %xmm2,%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    %rax,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L5:
  addq   $0x2,-0x20(%rbp)
L118:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  cmp    %rax,-0x20(%rbp)
  jb     L77
  addq   $0x1,-0x10(%rbp)
L35:
  cmpq   $0x5,-0x8(%rbp)
  jbe    L49
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: f32
name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D26
type_guessed: string

tool: D7: 1

tool: D24: found base %ld legs %ld and height %f 


tool: D26: %ld 


assistant: ```c
int main() {
  unsigned long int base = 1, sum = 0, legs = 2, count = 0;
  float height = 0;
  while (count < 6) {
    for (base = 2; base < 2 * legs; base += 2) {
      height = sqrt(legs * legs - base * base / 4);
      if (base - height == 1.0 || height - base == 1.0) {
        printf("found base %ld legs %ld and height %f \n", base, legs, height);
        sum += legs;
        count++;
      }
    }
    legs++;
  }
  printf("%ld \n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%r13d
  mov    $0x0,%r12d
  mov    $0x2,%ebp
  mov    $0x0,%r14d
  jmp    L59
L103:
  mov    %rbx,%rax
  shr    %rax
  mov    %rbx,%rdx
  and    $0x1,%edx
  or     %rdx,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L18
L107:
  cvtss2sd %xmm0,%xmm0
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    %rbp,%r14
  add    $0x1,%r12
L81:
  add    $0x2,%rbx
  cmp    %r13,%rbx
  jae    L23
L106:
  mov    %rbx,%rax
  imul   %rbx,%rax
  shr    $0x2,%rax
  mov    %r15,%rdi
  sub    %rax,%rdi
  call   <sqrt@plt>
  test   %rbx,%rbx
  js     L103
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbx,%xmm1
L18:
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  ucomiss D32(%rip),%xmm2
  jp     L61
  je     L107
L61:
  movaps %xmm0,%xmm2
  subss  %xmm1,%xmm2
  ucomiss D32(%rip),%xmm2
  jp     L81
  je     L107
  jmp    L81
L23:
  add    $0x1,%rbp
  add    $0x2,%r13
  cmp    $0x5,%r12
  ja     L16
L59:
  cmp    $0x2,%r13
  jbe    L23
  mov    %rbp,%r15
  imul   %rbp,%r15
  mov    $0x2,%ebx
  jmp    L106
L16:
  mov    %r14,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type: string
name: extract_symbolic_data
arguments: data_label: D32
type: f32
name: extract_symbolic_data
arguments: data_label: D12
type: string

tool: D30: found base %ld legs %ld and height %f 


tool: D32: 1

tool: D12: %ld 


assistant: ```c
int main() {
  unsigned long int base = 1, sum = 0, legs = 2, count = 0;
  float height = 0;
  while (count < 6) {
    for (base = 2; base < 2 * legs; base += 2) {
      height = sqrt(legs * legs - base * base / 4);
      if (base - height == 1.0 || height - base == 1.0) {
        printf("found base %ld legs %ld and height %f \n", base, legs, height);
        sum += legs;
        count++;
      }
    }
    legs++;
  }
  printf("%ld \n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D30(%rip),%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x4,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L59:
  cmp    $0x2,%r12
  jbe    L26
  mov    %rbx,%rax
  mov    $0x2,%r14d
  imul   %rbx,%rax
  mov    %rax,0x8(%rsp)
  jmp    L84
  xchg   %ax,%ax
L70:
  pxor   %xmm1,%xmm1
  cvtsi2ss %r14,%xmm1
L3:
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  ucomiss D8(%rip),%xmm2
  jp     L88
  je     L65
L88:
  movaps %xmm0,%xmm2
  subss  %xmm1,%xmm2
  ucomiss D8(%rip),%xmm2
  jp     L16
  jne    L16
L65:
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  add    %rbx,%r13
  add    $0x1,%rbp
L16:
  add    $0x2,%r14
  cmp    %r14,%r12
  jbe    L26
L84:
  mov    %r14,%rax
  mov    0x8(%rsp),%rdi
  imul   %r14,%rax
  shr    $0x2,%rax
  sub    %rax,%rdi
  call   <sqrt@plt>
  test   %r14,%r14
  jns    L70
  mov    %r14,%rax
  mov    %r14,%rdx
  pxor   %xmm1,%xmm1
  shr    %rax
  and    $0x1,%edx
  or     %rdx,%rax
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rbx
  add    $0x2,%r12
  cmp    $0x5,%rbp
  jbe    L59
  mov    %r13,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: f32
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D30: found base %ld legs %ld and height %f 


tool: D8: 1

tool: D7: %ld 


assistant: ```c
int main() {
  unsigned long int base = 1, sum = 0, legs = 2, count = 0;
  float height = 0;
  while (count < 6) {
    for (base = 2; base < 2 * legs; base += 2) {
      height = sqrt(legs * legs - base * base / 4);
      if (base - height == 1.0 || height - base == 1.0) {
        printf("found base %ld legs %ld and height %f \n", base, legs, height);
        sum += legs;
        count++;
      }
    }
    legs++;
  }
  printf("%ld \n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x4,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L93:
  cmp    $0x2,%r12
  jbe    L70
  mov    %rbx,%rax
  mov    $0x2,%r14d
  imul   %rbx,%rax
  mov    %rax,0x8(%rsp)
  jmp    L86
  xchg   %ax,%ax
L13:
  pxor   %xmm1,%xmm1
  cvtsi2ss %r14,%xmm1
L84:
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  ucomiss D38(%rip),%xmm2
  jp     L30
  je     L12
L30:
  movaps %xmm0,%xmm2
  subss  %xmm1,%xmm2
  ucomiss D38(%rip),%xmm2
  jp     L19
  jne    L19
L12:
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  add    %rbx,%r13
  add    $0x1,%rbp
L19:
  add    $0x2,%r14
  cmp    %r14,%r12
  jbe    L70
L86:
  mov    %r14,%rax
  mov    0x8(%rsp),%rdi
  imul   %r14,%rax
  shr    $0x2,%rax
  sub    %rax,%rdi
  call   <sqrt@plt>
  test   %r14,%r14
  jns    L13
  mov    %r14,%rax
  mov    %r14,%rdx
  pxor   %xmm1,%xmm1
  shr    %rax
  and    $0x1,%edx
  or     %rdx,%rax
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L70:
  add    $0x1,%rbx
  add    $0x2,%r12
  cmp    $0x5,%rbp
  jbe    L93
  mov    %r13,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D38
type: f32
name: unpack_data
arguments: tag: D6
type: string

tool: D28: found base %ld legs %ld and height %f 


tool: D38: 1

tool: D6: %ld 


assistant: ```c
int main() {
  unsigned long int base = 1, sum = 0, legs = 2, count = 0;
  float height = 0;
  while (count < 6) {
    for (base = 2; base < 2 * legs; base += 2) {
      height = sqrt(legs * legs - base * base / 4);
      if (base - height == 1.0 || height - base == 1.0) {
        printf("found base %ld legs %ld and height %f \n", base, legs, height);
        sum += legs;
        count++;
      }
    }
    legs++;
  }
  printf("%ld \n", sum);
  return 0;
}
```