ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gsw_kappa_t_exact>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  movq   %xmm2,%r12
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x0,%edi
  call   <gsw_gibbs@plt>
  movsd  %xmm0,(%rsp)
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <gsw_gibbs@plt>
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <gsw_gibbs@plt>
  mulsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm3
  subsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <gsw_gibbs@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double gsw_kappa_t_exact(double sa, double t, double p) {
  int n0, n1, n2;
  double g_tt, g_tp;
  n0 = 0;
  n1 = 1;
  n2 = 2;
  g_tt = gsw_gibbs(n0, n2, n0, sa, t, p);
  g_tp = gsw_gibbs(n0, n1, n1, sa, t, p);
  return ((g_tp * g_tp - g_tt * gsw_gibbs(n0, n0, n2, sa, t, p)) / (gsw_gibbs(n0, n0, n1, sa, t, p) * g_tt));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gsw_kappa_t_exact>:
  endbr64
  sub    $0x38,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  xor    %edi,%edi
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <gsw_gibbs@plt>
  movsd  0x10(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm2
  mov    $0x1,%edx
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  mov    $0x1,%esi
  xor    %edi,%edi
  movapd %xmm4,%xmm0
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movsd  %xmm4,0x18(%rsp)
  call   <gsw_gibbs@plt>
  movsd  0x18(%rsp),%xmm4
  xor    %esi,%esi
  xor    %edi,%edi
  movapd %xmm0,%xmm3
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  mov    $0x2,%edx
  mulsd  %xmm0,%xmm3
  movapd %xmm4,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <gsw_gibbs@plt>
  mulsd  0x8(%rsp),%xmm0
  xor    %esi,%esi
  xor    %edi,%edi
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm4
  mov    $0x1,%edx
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  subsd  %xmm0,%xmm3
  movapd %xmm4,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <gsw_gibbs@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double gsw_kappa_t_exact(double sa, double t, double p) {
  int n0, n1, n2;
  double g_tt, g_tp;
  n0 = 0;
  n1 = 1;
  n2 = 2;
  g_tt = gsw_gibbs(n0, n2, n0, sa, t, p);
  g_tp = gsw_gibbs(n0, n1, n1, sa, t, p);
  return ((g_tp * g_tp - g_tt * gsw_gibbs(n0, n0, n2, sa, t, p)) / (gsw_gibbs(n0, n0, n1, sa, t, p) * g_tt));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gsw_kappa_t_exact>:
  endbr64
  sub    $0x38,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  xor    %edi,%edi
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <gsw_gibbs@plt>
  movsd  0x10(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm2
  mov    $0x1,%edx
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  mov    $0x1,%esi
  xor    %edi,%edi
  movapd %xmm4,%xmm0
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movsd  %xmm4,0x18(%rsp)
  call   <gsw_gibbs@plt>
  movsd  0x18(%rsp),%xmm4
  xor    %esi,%esi
  xor    %edi,%edi
  movapd %xmm0,%xmm3
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  mov    $0x2,%edx
  mulsd  %xmm0,%xmm3
  movapd %xmm4,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <gsw_gibbs@plt>
  mulsd  0x8(%rsp),%xmm0
  xor    %esi,%esi
  xor    %edi,%edi
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm4
  mov    $0x1,%edx
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  subsd  %xmm0,%xmm3
  movapd %xmm4,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <gsw_gibbs@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double gsw_kappa_t_exact(double sa, double t, double p) {
  int n0, n1, n2;
  double g_tt, g_tp;
  n0 = 0;
  n1 = 1;
  n2 = 2;
  g_tt = gsw_gibbs(n0, n2, n0, sa, t, p);
  g_tp = gsw_gibbs(n0, n1, n1, sa, t, p);
  return ((g_tp * g_tp - g_tt * gsw_gibbs(n0, n0, n2, sa, t, p)) / (gsw_gibbs(n0, n0, n1, sa, t, p) * g_tt));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uGetNumIPs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    $0xff,%eax
  ja     L45
  mov    -0x1c(%rbp),%eax
  cmp    $0xff,%eax
  ja     L45
  mov    -0x18(%rbp),%eax
  cmp    $0xff,%eax
  ja     L45
  mov    -0x14(%rbp),%eax
  cmp    $0xff,%eax
  jbe    L77
L45:
  mov    $0x0,%eax
  jmp    L7
L77:
  lea    -0x14(%rbp),%r8
  lea    -0x18(%rbp),%rdi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x10(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  add    $0x10,%rsp
  mov    -0x10(%rbp),%edx
  mov    $0x1f,%eax
  sub    %edx,%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L42
  movl   $0x1,-0xc(%rbp)
  jmp    L16
L42:
  subl   $0x2,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: %u.%u.%u.%u/%u

assistant: ```c
unsigned uGetNumIPs(char *cCIDR4) {
  unsigned uNumIPs = 0;
  unsigned uA = 0;
  unsigned uB = 0;
  unsigned uC = 0;
  unsigned uD = 0;
  unsigned uE = 0;
  if ((uA > 255) || (uB > 255) || (uC > 255) || (uD > 255))
    return (0);
  sscanf(cCIDR4, "%u.%u.%u.%u/%u", &uA, &uB, &uC, &uD, &uE);
  uNumIPs = (unsigned)2 << (32 - uE - 1);
  if (!uNumIPs)
    uNumIPs = 1;
  else
    uNumIPs = uNumIPs - 2;
  return (uNumIPs);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uGetNumIPs>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x1f,%ecx
  sub    0x24(%rsp),%ecx
  mov    $0x2,%edx
  shl    %cl,%edx
  add    $0x10,%rsp
  lea    -0x2(%rdx),%eax
  test   %edx,%edx
  mov    $0x1,%edx
  cmove  %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: %u.%u.%u.%u/%u

assistant: ```c
unsigned uGetNumIPs(char *cCIDR4) {
  unsigned uNumIPs = 0;
  unsigned uA = 0;
  unsigned uB = 0;
  unsigned uC = 0;
  unsigned uD = 0;
  unsigned uE = 0;
  if ((uA > 255) || (uB > 255) || (uC > 255) || (uD > 255))
    return (0);
  sscanf(cCIDR4, "%u.%u.%u.%u/%u", &uA, &uB, &uC, &uD, &uE);
  uNumIPs = (unsigned)2 << (32 - uE - 1);
  if (!uNumIPs)
    uNumIPs = 1;
  else
    uNumIPs = uNumIPs - 2;
  return (uNumIPs);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uGetNumIPs>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  sub    $0x8,%rsp
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <sscanf@plt>
  mov    $0x1f,%ecx
  mov    $0x2,%edx
  sub    0x24(%rsp),%ecx
  shl    %cl,%edx
  pop    %rax
  pop    %rcx
  lea    -0x2(%rdx),%eax
  test   %edx,%edx
  mov    $0x1,%edx
  cmove  %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: %u.%u.%u.%u/%u

assistant: ```c
unsigned uGetNumIPs(char *cCIDR4) {
  unsigned uNumIPs = 0;
  unsigned uA = 0;
  unsigned uB = 0;
  unsigned uC = 0;
  unsigned uD = 0;
  unsigned uE = 0;
  if ((uA > 255) || (uB > 255) || (uC > 255) || (uD > 255))
    return (0);
  sscanf(cCIDR4, "%u.%u.%u.%u/%u", &uA, &uB, &uC, &uD, &uE);
  uNumIPs = (unsigned)2 << (32 - uE - 1);
  if (!uNumIPs)
    uNumIPs = 1;
  else
    uNumIPs = uNumIPs - 2;
  return (uNumIPs);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uGetNumIPs>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  sub    $0x8,%rsp
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <sscanf@plt>
  mov    $0x1f,%ecx
  mov    $0x2,%edx
  sub    0x24(%rsp),%ecx
  shl    %cl,%edx
  pop    %rax
  pop    %rcx
  lea    -0x2(%rdx),%eax
  test   %edx,%edx
  mov    $0x1,%edx
  cmove  %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string

tool: D1: %u.%u.%u.%u/%u

assistant: ```c
unsigned uGetNumIPs(char *cCIDR4) {
  unsigned uNumIPs = 0;
  unsigned uA = 0;
  unsigned uB = 0;
  unsigned uC = 0;
  unsigned uD = 0;
  unsigned uE = 0;
  if ((uA > 255) || (uB > 255) || (uC > 255) || (uD > 255))
    return (0);
  sscanf(cCIDR4, "%u.%u.%u.%u/%u", &uA, &uB, &uC, &uD, &uE);
  uNumIPs = (unsigned)2 << (32 - uE - 1);
  if (!uNumIPs)
    uNumIPs = 1;
  else
    uNumIPs = uNumIPs - 2;
  return (uNumIPs);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %esi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L27
L1:
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x428(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L27:
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0x0,-0x414(%rbp)
  jg     L1
  mov    -0x428(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int copy(int in, int out) {
  char buff[1024];
  int reading;
  while ((reading = read(in, buff, sizeof(buff))) > 0)
    write(out, buff, reading);
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L27
L7:
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
L27:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L7
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    %ebp,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copy(int in, int out) {
  char buff[1024];
  int reading;
  while ((reading = read(in, buff, sizeof(buff))) > 0)
    write(out, buff, reading);
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L11
  nopl   0x0(%rax)
L7:
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
L11:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L7
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copy(int in, int out) {
  char buff[1024];
  int reading;
  while ((reading = read(in, buff, sizeof(buff))) > 0)
    write(out, buff, reading);
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L15
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
L15:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L5
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copy(int in, int out) {
  char buff[1024];
  int reading;
  while ((reading = read(in, buff, sizeof(buff))) > 0)
    write(out, buff, reading);
  return out;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<run_single_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <clock_mono_us@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L37
L38:
  movq   $0x0,-0x10(%rbp)
  jmp    L24
L8:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L8
  mov    $0x0,%eax
  call   <clock_mono_us@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L38
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: Single test: %ld runs of %ld iterations.


assistant: ```c
void run_single_test(long runs, long iters, double *times, uint64_t *gbg) {
  printf("Single test: %ld runs of %ld iterations.\n", runs, iters);
  double t0 = clock_mono_us();
  for (long run = 0; run < runs; run++) {
    for (long iter = 0; iter < iters; iter++) {
      gbg[iter]++;
    }
    double t1 = clock_mono_us();
    times[run] = t1 - t0;
    t0 = t1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run_single_test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r15
  mov    %rcx,%r14
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <clock_mono_us@plt>
  movsd  %xmm0,0x8(%rsp)
  test   %r12,%r12
  jle    L30
  lea    (%r14,%r13,4),%rbx
  mov    $0x0,%ebp
  jmp    L34
L47:
  addl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L47
L19:
  mov    $0x0,%eax
  call   <clock_mono_us@plt>
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  movsd  %xmm1,(%r15,%rbp,8)
  add    $0x1,%rbp
  cmp    %rbp,%r12
  je     L30
  movsd  %xmm0,0x8(%rsp)
L34:
  mov    %r14,%rax
  test   %r13,%r13
  jg     L47
  jmp    L19
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: Single test: %ld runs of %ld iterations.


assistant: ```c
void run_single_test(long runs, long iters, double *times, uint64_t *gbg) {
  printf("Single test: %ld runs of %ld iterations.\n", runs, iters);
  double t0 = clock_mono_us();
  for (long run = 0; run < runs; run++) {
    for (long iter = 0; iter < iters; iter++) {
      gbg[iter]++;
    }
    double t1 = clock_mono_us();
    times[run] = t1 - t0;
    t0 = t1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<run_single_test>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  mov    %rsi,%rdx
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <clock_mono_us@plt>
  movsd  %xmm0,0x8(%rsp)
  test   %rbp,%rbp
  jle    L6
  lea    0x0(%r13,%r12,4),%rbx
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rax
  test   %r12,%r12
  jle    L17
  nopl   0x0(%rax,%rax,1)
L36:
  addl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rbx
  jne    L36
L17:
  xor    %eax,%eax
  call   <clock_mono_us@plt>
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  movsd  %xmm1,(%r14,%r15,8)
  add    $0x1,%r15
  cmp    %r15,%rbp
  je     L6
  movsd  %xmm0,0x8(%rsp)
  jmp    L0
  nopl   0x0(%rax)
L6:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: Single test: %ld runs of %ld iterations.


assistant: ```c
void run_single_test(long runs, long iters, double *times, uint64_t *gbg) {
  printf("Single test: %ld runs of %ld iterations.\n", runs, iters);
  double t0 = clock_mono_us();
  for (long run = 0; run < runs; run++) {
    for (long iter = 0; iter < iters; iter++) {
      gbg[iter]++;
    }
    double t1 = clock_mono_us();
    times[run] = t1 - t0;
    t0 = t1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<run_single_test>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x10(%rsp)
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <clock_mono_us@plt>
  movsd  %xmm0,0x8(%rsp)
  test   %rbp,%rbp
  jle    L14
  lea    -0x1(%r13),%rax
  mov    %r13,%rbx
  mov    %r13,%r12
  xor    %r14d,%r14d
  shr    $0x2,%rbx
  mov    %rax,0x18(%rsp)
  movdqa D24(%rip),%xmm1
  and    $0xfffffffffffffffc,%r12
  shl    $0x4,%rbx
  add    %r15,%rbx
  nopl   0x0(%rax)
L34:
  test   %r13,%r13
  jle    L29
  cmpq   $0x2,0x18(%rsp)
  jbe    L85
  mov    %r15,%rax
  nopl   0x0(%rax)
L58:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rbx,%rax
  jne    L58
  mov    %r12,%rcx
  cmp    %r12,%r13
  je     L29
L45:
  lea    0x0(,%rcx,4),%rax
  lea    0x1(%rcx),%rsi
  addl   $0x1,(%r15,%rax,1)
  cmp    %rsi,%r13
  jle    L29
  add    $0x2,%rcx
  addl   $0x1,0x4(%r15,%rax,1)
  cmp    %rcx,%r13
  jle    L29
  addl   $0x1,0x8(%r15,%rax,1)
L29:
  xor    %eax,%eax
  call   <clock_mono_us@plt>
  mov    0x10(%rsp),%rax
  movapd %xmm0,%xmm2
  subsd  0x8(%rsp),%xmm2
  movsd  %xmm2,(%rax,%r14,8)
  add    $0x1,%r14
  cmp    %r14,%rbp
  je     L14
  movdqa D24(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  jmp    L34
L14:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  xor    %ecx,%ecx
  jmp    L45
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type: string
name: unpack_data
arguments: data_tag: D24
type: byte[16]

tool: D26: Single test: %ld runs of %ld iterations.


tool: {"D24": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void run_single_test(long runs, long iters, double *times, uint64_t *gbg) {
  printf("Single test: %ld runs of %ld iterations.\n", runs, iters);
  double t0 = clock_mono_us();
  for (long run = 0; run < runs; run++) {
    for (long iter = 0; iter < iters; iter++) {
      gbg[iter]++;
    }
    double t1 = clock_mono_us();
    times[run] = t1 - t0;
    t0 = t1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_pmu_motion_img>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe204,%edx
  mov    $0x17,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xe204,%edx
  mov    $0x17,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xe242,%edx
  mov    $0x18,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x2208,%edx
  mov    $0x19,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x355f,%edx
  mov    $0x1a,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xe204,%edx
  mov    $0x15,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xffff,%edx
  mov    $0x16,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xeae,%edx
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x1,%edx
  mov    $0x36,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x11f4,%edx
  mov    $0x37,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_pmu_motion_img(void) {
  mbus_remote_register_write(0x8, 0x17, ((3 << 14) | (1 << 13) | (1 << 9) | (0 << 5) | (4)));
  delay(200);
  mbus_remote_register_write(0x8, 0x17, ((3 << 14) | (1 << 13) | (1 << 9) | (0 << 5) | (4)));
  delay(200);
  mbus_remote_register_write(0x8, 0x18, ((3 << 14) | (1 << 13) | (1 << 9) | (2 << 5) | (2)));
  delay(200);
  mbus_remote_register_write(0x8, 0x19, ((1 << 13) | (1 << 9) | (0 << 5) | (8)));
  delay(200);
  mbus_remote_register_write(0x8, 0x1A, ((1 << 13) | (10 << 9) | (10 << 5) | (31)));
  delay(200);
  mbus_remote_register_write(0x8, 0x15, ((0 << 19) | (0 << 18) | (0 << 17) | (3 << 14) | (1 << 13) | (1 << 9) | (0 << 5) | (4)));
  delay(200);
  mbus_remote_register_write(0x8, 0x16, ((0 << 19) | (0 << 18) | (0 << 17) | (3 << 14) | (1 << 13) | (15 << 9) | (15 << 5) | (31)));
  delay(200);
  mbus_remote_register_write(0x8, 0x05, ((1 << 11) | (1 << 10) | (1 << 9) | (0 << 8) | (1 << 7) | (46)));
  delay(200);
  mbus_remote_register_write(0x8, 0x36, 0x000001);
  delay(200);
  mbus_remote_register_write(0x8, 0x37, 0x0011F4);
  delay(200);
}
```