ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  nopl   0x0(%rax)
L28:
  test   %esi,%esi
  jle    L23
  mov    %rdi,%rax
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L3:
  mov    -0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jle    L22
  mov    %ecx,-0x4(%rax)
  mov    $0x1,%r9d
  mov    %edx,(%rax)
L22:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L3
  test   %r9d,%r9d
  jne    L28
L23:
  ret
```

assistant: ```c
void bubbleSort(int *A, int n) {
  bool isSwapped;
  int i, temp;
  do {
    isSwapped = false;
    for (i = 0; i < n; i++) {
      if (A[i - 1] > A[i]) {
        temp = A[i - 1];
        A[i - 1] = A[i];
        A[i] = temp;
        isSwapped = true;
      }
    }
  } while (isSwapped);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L12:
  test   %esi,%esi
  jle    L2
  lea    -0x4(%rdi),%rdx
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L22:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%eax
  movd   %xmm2,%ecx
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jge    L5
  movq   %xmm1,(%rdx)
  mov    $0x1,%r9d
L5:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L22
  test   %r9d,%r9d
  jne    L12
L2:
  ret
```

assistant: ```c
void bubbleSort(int *A, int n) {
  bool isSwapped;
  int i, temp;
  do {
    isSwapped = false;
    for (i = 0; i < n; i++) {
      if (A[i - 1] > A[i]) {
        temp = A[i - 1];
        A[i - 1] = A[i];
        A[i] = temp;
        isSwapped = true;
      }
    }
  } while (isSwapped);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L93:
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L60
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jg     L93
L60:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L50
  movl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L39
L50:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L39
  addq   $0x1,-0x18(%rbp)
  jmp    L39
L95:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L73
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L95
L73:
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L88
L16:
  mov    -0x8(%rbp),%rax
L88:
  pop    %rbp
  ret
```

assistant: ```c
long long atoll(number)
char *number;
{
  long long n = 0;
  int neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atoll>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  ja     L1
L49:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L49
L1:
  cmp    $0x2d,%al
  je     L19
  mov    $0x0,%esi
  cmp    $0x2b,%al
  je     L7
L62:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x9,%cl
  ja     L78
L8:
  lea    (%rdx,%rdx,4),%rdx
  add    $0x1,%rdi
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L8
L78:
  mov    %rdx,%rax
  neg    %rax
  test   %esi,%esi
  cmovne %rax,%rdx
  mov    %rdx,%rax
  ret
L19:
  add    $0x1,%rdi
  mov    $0x1,%esi
  jmp    L62
L7:
  add    $0x1,%rdi
  jmp    L62
```

assistant: ```c
long long atoll(number)
char *number;
{
  long long n = 0;
  int neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atoll>:
  endbr64
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L24:
  add    $0x1,%rdi
L68:
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L24
  cmp    $0x2d,%al
  je     L48
  cmp    $0x2b,%al
  je     L3
  movzbl (%rdi),%eax
  xor    %ecx,%ecx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L25
L76:
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L63:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  movsbq %al,%rax
  lea    (%rax,%rdx,2),%r8
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L63
  mov    %r8,%rax
  neg    %rax
  test   %ecx,%ecx
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L3:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L25
  mov    %rcx,%rdi
  xor    %ecx,%ecx
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L48:
  movzbl 0x1(%rdi),%eax
  mov    $0x1,%ecx
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L76
L25:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long atoll(number)
char *number;
{
  long long n = 0;
  int neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atoll>:
  endbr64
  jmp    L76
  cs nopw 0x0(%rax,%rax,1)
L46:
  add    $0x1,%rdi
L76:
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L46
  cmp    $0x2d,%al
  je     L89
  cmp    $0x2b,%al
  je     L19
  lea    -0x30(%rax),%edx
  xor    %ecx,%ecx
  cmp    $0x9,%dl
  ja     L35
L45:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L11:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  movsbq %al,%rax
  lea    (%rax,%rdx,2),%r8
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L11
  mov    %r8,%rax
  neg    %rax
  test   %ecx,%ecx
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L35
  mov    %rcx,%rdi
  xor    %ecx,%ecx
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L89:
  movzbl 0x1(%rdi),%eax
  mov    $0x1,%ecx
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L45
L35:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long atoll(number)
char *number;
{
  long long n = 0;
  int neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *fx(int *a, int sz) {
  int *b = a + sz;
  b = b - sz;
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fx>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *fx(int *a, int sz) {
  int *b = a + sz;
  b = b - sz;
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fx>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *fx(int *a, int sz) {
  int *b = a + sz;
  b = b - sz;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fx>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *fx(int *a, int sz) {
  int *b = a + sz;
  b = b - sz;
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L15
L23:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0xf4240,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L39:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L6:
  cmpl   $0x2,-0x14(%rbp)
  jle    L39
  addl   $0x1,-0x18(%rbp)
L15:
  cmpl   $0x6,-0x18(%rbp)
  jle    L23
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D14
type_guessed: string

tool: D3: sminsorted

tool: D24: # c::%s:len=%d


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sminsorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r15d
  lea    D9(%rip),%r14
  lea    D21(%rip),%r13
  jmp    L1
L11:
  add    $0x1,%r15d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L23
L1:
  lea    -0x3(%r12),%ebx
  mov    %r15d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
L7:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    $0xf4240,%edi
  call   <benchmark@plt>
  mov    $0xf4240,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L7
  jmp    L11
L23:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D26
datatype: string

tool: D9: sminsorted

tool: D21: # c::%s:len=%d


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sminsorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L0:
  mov    0xc(%rsp),%esi
  mov    $0xa,%edi
  lea    -0x3(%rbp),%r15d
  call   <pow@plt>
  mov    %eax,%ebx
L19:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    $0xf4240,%edi
  add    $0x1,%r15d
  call   <benchmark@plt>
  mov    $0xf4240,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebp,%r15d
  jne    L19
  addl   $0x1,0xc(%rsp)
  lea    0x3(%r15),%ebp
  cmp    $0x12,%r15d
  jne    L0
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string
name: parse_data
arguments: label: D26
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D4: sminsorted

tool: D26: # c::%s:len=%d


tool: D8: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sminsorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D14(%rip),%r15
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x1,0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L19:
  mov    0xc(%rsp),%esi
  mov    $0xa,%edi
  lea    -0x3(%r12),%ebx
  call   <pow@plt>
  mov    %eax,%ebp
L0:
  mov    %ebp,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    $0xf4240,%edi
  add    $0x1,%ebx
  call   <benchmark@plt>
  mov    $0xf4240,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L0
  add    $0x3,%r12d
  addl   $0x1,0xc(%rsp)
  cmp    $0x15,%r12d
  jne    L19
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string

tool: D14: sminsorted

tool: D28: # c::%s:len=%d


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sminsorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <calcc@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7: asdf

assistant: ```c
int main(void) {
  calcc("asdf");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <calcc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: asdf

assistant: ```c
int main(void) {
  calcc("asdf");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <calcc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: asdf

assistant: ```c
int main(void) {
  calcc("asdf");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <calcc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: asdf

assistant: ```c
int main(void) {
  calcc("asdf");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L36
  mov    -0x18(%rbp),%rax
  jmp    L7
L36:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L16
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  add    %rax,-0x8(%rbp)
  jmp    L21
L17:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L21:
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  jmp    L53
L1:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L16:
  cmpq   $0x0,-0x28(%rbp)
  jne    L1
L53:
  mov    -0x18(%rbp),%rax
L7:
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t num) {
  char *sp = (char *)source;
  char *dp = (char *)destination;
  if (sp == dp) {
    return destination;
  }
  if (sp < dp) {
    sp = sp + (num - 1);
    dp = dp + (num - 1);
    for (; num != 0; num--) {
      *dp-- = *sp--;
    }
  } else {
    for (; num != 0; num--) {
      *dp++ = *sp++;
    }
  }
  return destination;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  je     L35
  jb     L1
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L56
L3:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L3
L35:
  ret
L56:
  ret
L1:
  test   %rdx,%rdx
  je     L35
L48:
  movzbl -0x1(%rsi,%rdx,1),%ecx
  mov    %cl,-0x1(%rax,%rdx,1)
  sub    $0x1,%rdx
  jne    L48
  ret
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t num) {
  char *sp = (char *)source;
  char *dp = (char *)destination;
  if (sp == dp) {
    return destination;
  }
  if (sp < dp) {
    sp = sp + (num - 1);
    dp = dp + (num - 1);
    for (; num != 0; num--) {
      *dp-- = *sp--;
    }
  } else {
    for (; num != 0; num--) {
      *dp++ = *sp++;
    }
  }
  return destination;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  je     L7
  jae    L23
  test   %rdx,%rdx
  je     L7
  lea    -0x1(%rsi),%rdi
  lea    -0x1(%rax),%rsi
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  jne    L5
  ret
  xchg   %ax,%ax
L23:
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L17
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L2
L7:
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t num) {
  char *sp = (char *)source;
  char *dp = (char *)destination;
  if (sp == dp) {
    return destination;
  }
  if (sp < dp) {
    sp = sp + (num - 1);
    dp = dp + (num - 1);
    for (; num != 0; num--) {
      *dp-- = *sp--;
    }
  } else {
    for (; num != 0; num--) {
      *dp++ = *sp++;
    }
  }
  return destination;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %rdx,%rax
  cmp    %rdi,%rsi
  je     L136
  jb     L27
  test   %rdx,%rdx
  je     L136
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rdx
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L204
  cmp    $0x6,%rdx
  jbe    L204
  cmp    $0xe,%rdx
  jbe    L72
  mov    %rax,%rsi
  xor    %edx,%edx
  and    $0xfffffffffffffff0,%rsi
  nopw   0x0(%rax,%rax,1)
L33:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rsi
  jne    L33
  mov    %rax,%r9
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%r9
  and    $0xf,%edx
  lea    (%rcx,%r9,1),%rdi
  lea    (%r8,%r9,1),%rsi
  cmp    %r9,%rax
  je     L136
  lea    -0x1(%rdx),%r10
  mov    %rdx,%rax
  cmp    $0x6,%r10
  jbe    L70
L194:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%r8,%r9,1)
  mov    %rax,%rcx
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %rcx,%rdi
  add    %rcx,%rsi
  cmp    %rcx,%rax
  je     L136
  lea    -0x1(%rdx),%r10
L70:
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %r10,%r10
  je     L136
  movzbl 0x1(%rdi),%eax
  mov    %al,0x1(%rsi)
  cmp    $0x2,%rdx
  je     L136
  movzbl 0x2(%rdi),%eax
  mov    %al,0x2(%rsi)
  cmp    $0x3,%rdx
  je     L136
  movzbl 0x3(%rdi),%eax
  mov    %al,0x3(%rsi)
  cmp    $0x4,%rdx
  je     L136
  movzbl 0x4(%rdi),%eax
  mov    %al,0x4(%rsi)
  cmp    $0x5,%rdx
  je     L136
  movzbl 0x5(%rdi),%eax
  mov    %al,0x5(%rsi)
  cmp    $0x6,%rdx
  je     L136
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%rsi)
L136:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L27:
  test   %rdx,%rdx
  je     L136
  lea    -0x1(%rsi),%rsi
  lea    -0x1(%rdi),%rcx
  nopl   (%rax)
L47:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  sub    $0x1,%rax
  jne    L47
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L204:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L185:
  movzbl (%rcx,%rdx,1),%esi
  mov    %sil,(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L185
  jmp    L136
L72:
  mov    %r8,%rsi
  mov    %rcx,%rdi
  mov    %rax,%rdx
  xor    %r9d,%r9d
  jmp    L194
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t num) {
  char *sp = (char *)source;
  char *dp = (char *)destination;
  if (sp == dp) {
    return destination;
  }
  if (sp < dp) {
    sp = sp + (num - 1);
    dp = dp + (num - 1);
    for (; num != 0; num--) {
      *dp-- = *sp--;
    }
  } else {
    for (; num != 0; num--) {
      *dp++ = *sp++;
    }
  }
  return destination;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mpeg2_detect_accel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int mpeg2_detect_accel(void) {
  unsigned int accel;
  accel = 0;
  return accel;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mpeg2_detect_accel>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int mpeg2_detect_accel(void) {
  unsigned int accel;
  accel = 0;
  return accel;
}
```