ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<x_atoi>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x2d,%cl
  je     L31
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  ja     L11
L16:
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L18:
  movzbl 0x1(%rdi),%esi
  movzbl %dl,%edx
  lea    (%rax,%rax,4),%rax
  add    $0x1,%rdi
  lea    (%rdx,%rax,2),%rax
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  jbe    L18
  cmp    $0x2d,%cl
  je     L21
  ret
L1:
  xor    %eax,%eax
L21:
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rax
  sub    $0x30,%edx
  cmp    $0x9,%dl
  ja     L1
  mov    %rax,%rdi
  jmp    L16
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int x_atoi(const char *src) {
  register const char *s;
  register long int dest = 0;
  register unsigned char c;
  s = src;
  if (*s == '-')
    ++s;
  while ((c = *s - '0') < 10) {
    ++s;
    dest = dest * 10 + c;
  }
  return (*src == '-') ? -dest : dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<x_atoi>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x2d,%cl
  je     L14
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  ja     L15
L43:
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rdi),%esi
  movzbl %dl,%edx
  lea    (%rax,%rax,4),%rax
  add    $0x1,%rdi
  lea    (%rdx,%rax,2),%rax
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  jbe    L19
  cmp    $0x2d,%cl
  je     L58
  ret
L34:
  xor    %eax,%eax
L58:
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rax
  sub    $0x30,%edx
  cmp    $0x9,%dl
  ja     L34
  mov    %rax,%rdi
  jmp    L43
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int x_atoi(const char *src) {
  register const char *s;
  register long int dest = 0;
  register unsigned char c;
  s = src;
  if (*s == '-')
    ++s;
  while ((c = *s - '0') < 10) {
    ++s;
    dest = dest * 10 + c;
  }
  return (*src == '-') ? -dest : dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<randinitint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L2:
  mov    $0x0,%eax
  call   <rand0to1@plt>
  imul   -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *randinitint(const int N, const int min, const int upto) {
  int i, *A;
  A = (int *)malloc(N * sizeof(int));
  for (i = 0; i < N; i++) {
    A[i] = min + (upto * rand0to1());
  }
  return A;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<randinitint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %edx,%r12d
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L14
  mov    %rax,%rbx
  mov    %r13d,%r13d
  lea    (%rax,%r13,4),%r13
L10:
  mov    $0x0,%eax
  call   <rand0to1@plt>
  imul   %r12d,%eax
  add    %ebp,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L10
L14:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *randinitint(const int N, const int min, const int upto) {
  int i, *A;
  A = (int *)malloc(N * sizeof(int));
  for (i = 0; i < N; i++) {
    A[i] = min + (upto * rand0to1());
  }
  return A;
}
```
user: What is the c source code of the assembly code below?

```asm
<randinitint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,4),%edi
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L8
  mov    %rax,%r14
  lea    (%rax,%r12,4),%r12
  nop
L7:
  xor    %eax,%eax
  add    $0x4,%r14
  call   <rand0to1@plt>
  imul   %ebp,%eax
  add    %ebx,%eax
  mov    %eax,-0x4(%r14)
  cmp    %r12,%r14
  jne    L7
L8:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *randinitint(const int N, const int min, const int upto) {
  int i, *A;
  A = (int *)malloc(N * sizeof(int));
  for (i = 0; i < N; i++) {
    A[i] = min + (upto * rand0to1());
  }
  return A;
}
```
user: Translate the below assembly code into C programming language:

```asm
<randinitint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,4),%edi
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L5
  mov    %rax,%r14
  lea    (%rax,%r12,4),%r12
  nop
L1:
  xor    %eax,%eax
  add    $0x4,%r14
  call   <rand0to1@plt>
  imul   %ebp,%eax
  add    %ebx,%eax
  mov    %eax,-0x4(%r14)
  cmp    %r12,%r14
  jne    L1
L5:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *randinitint(const int N, const int min, const int upto) {
  int i, *A;
  A = (int *)malloc(N * sizeof(int));
  for (i = 0; i < N; i++) {
    A[i] = min + (upto * rand0to1());
  }
  return A;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L14
L26:
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  movss  D57(%rip),%xmm1
  divss  %xmm1,%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L12
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L14
L12:
  movss  -0xc(%rbp),%xmm0
  movss  D33(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D48
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D57
data_type: byte[4]
name: parse_data
arguments: data_label: D35
data_type: string
name: parse_data
arguments: data_label: D33
data_type: byte[4]

tool: D48: %d

tool: D10: %d%d%d

tool: {"D57": [0x00,0x00,0x00,0x40]}

tool: D35: %.2f


tool: {"D33": [0x00,0x00,0x00,0x80]}

assistant: ```c
int main() {
  int t, a, b, c;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    float ans, a1, c1;
    a1 = a;
    c1 = c;
    ans = ((a1 + c1) / 2) - b;
    if (ans >= 0)
      printf("%.2f\n", (ans));
    else
      printf("%.2f\n", -ans);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L27
  lea    D58(%rip),%rbx
  jmp    L54
L23:
  lea    D21(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L27
L54:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x14(%rsp),%xmm1
  addss  %xmm1,%xmm0
  mulss  D23(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  comiss %xmm2,%xmm0
  jae    L23
  xorps  D24(%rip),%xmm0
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D59
datatype: string
name: parse_data
arguments: label: D58
datatype: string
name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D23
datatype: byte[4]
name: parse_data
arguments: label: D24
datatype: byte[16]

tool: D59: %d

tool: D58: %d%d%d

tool: D21: %.2f


tool: {"D23": [0x00,0x00,0x00,0x3f]}

tool: {"D24": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int t, a, b, c;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    float ans, a1, c1;
    a1 = a;
    c1 = c;
    ans = ((a1 + c1) / 2) - b;
    if (ans >= 0)
      printf("%.2f\n", (ans));
    else
      printf("%.2f\n", -ans);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L10
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D33(%rip),%rbx
  lea    D46(%rip),%r14
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ssl 0x14(%rsp),%xmm1
  cvtsi2ssl 0xc(%rsp),%xmm0
  addss  %xmm1,%xmm0
  mulss  D7(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  subss  %xmm1,%xmm0
  comiss %xmm2,%xmm0
  jae    L7
  xorps  D5(%rip),%xmm0
L7:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L1
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D46
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: byte[4]
name: read_data
arguments: tag: D5
type_guessed: byte[16]

tool: D18: %d

tool: D33: %d%d%d

tool: D46: %.2f


tool: {"D7": [0x00,0x00,0x00,0x3f]}

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int t, a, b, c;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    float ans, a1, c1;
    a1 = a;
    c1 = c;
    ans = ((a1 + c1) / 2) - b;
    if (ans >= 0)
      printf("%.2f\n", (ans));
    else
      printf("%.2f\n", -ans);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D43(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L2
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D21(%rip),%rbx
  lea    D39(%rip),%r14
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ssl 0x14(%rsp),%xmm1
  cvtsi2ssl 0xc(%rsp),%xmm0
  addss  %xmm1,%xmm0
  mulss  D10(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  subss  %xmm1,%xmm0
  comiss %xmm2,%xmm0
  jae    L20
  xorps  D9(%rip),%xmm0
L20:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L6
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D43
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D39
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: byte[4]
name: disassemble_data
arguments: tag: D9
type_infered: byte[16]

tool: D43: %d

tool: D21: %d%d%d

tool: D39: %.2f


tool: {"D10": [0x00,0x00,0x00,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int t, a, b, c;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    float ans, a1, c1;
    a1 = a;
    c1 = c;
    ans = ((a1 + c1) / 2) - b;
    if (ans >= 0)
      printf("%.2f\n", (ans));
    else
      printf("%.2f\n", -ans);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<curve25519_dh_keypair>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <randombytes@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <curve25519_crypto_scalarmult_base@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int curve25519_dh_keypair(unsigned char *pk, unsigned char *sk) {
  randombytes(sk, 32);
  curve25519_crypto_scalarmult_base(pk, sk);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<curve25519_dh_keypair>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <randombytes@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <curve25519_crypto_scalarmult_base@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int curve25519_dh_keypair(unsigned char *pk, unsigned char *sk) {
  randombytes(sk, 32);
  curve25519_crypto_scalarmult_base(pk, sk);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<curve25519_dh_keypair>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x20,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <randombytes@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <curve25519_crypto_scalarmult_base@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int curve25519_dh_keypair(unsigned char *pk, unsigned char *sk) {
  randombytes(sk, 32);
  curve25519_crypto_scalarmult_base(pk, sk);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x14(%rcx),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getrand() {
  srand(time(NULL));
  return rand() % 20 + 20;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getrand>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  add    $0x14,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int getrand() {
  srand(time(NULL));
  return rand() % 20 + 20;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getrand>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  add    $0x14,%eax
  ret
```

assistant: ```c
int getrand() {
  srand(time(NULL));
  return rand() % 20 + 20;
}
```
user: What is the c source code of the assembly code below?

```asm
<getrand>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  add    $0x14,%eax
  ret
```

assistant: ```c
int getrand() {
  srand(time(NULL));
  return rand() % 20 + 20;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x470,%rsp
  mov    %edi,-0x464(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x454(%rbp)
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <login_input@plt>
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <packet_pack_login_req@plt>
  mov    %eax,-0x454(%rbp)
  mov    -0x454(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x464(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <send_fix_len@plt>
  mov    %eax,-0x454(%rbp)
  cmpl   $0xffffffff,-0x454(%rbp)
  je     L13
  lea    -0x410(%rbp),%rdx
  mov    -0x464(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <recv_packet@plt>
  mov    %eax,-0x454(%rbp)
  cmpl   $0x0,-0x454(%rbp)
  jle    L22
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <packet_unpack_login_resp@plt>
  mov    %eax,-0x454(%rbp)
  cmpl   $0x0,-0x454(%rbp)
  jne    L46
  movl   $0x1,-0x454(%rbp)
  jmp    L24
L46:
  mov    -0x454(%rbp),%eax
  mov    %eax,%edi
  call   <packet_disp_err@plt>
  movl   $0x2,-0x454(%rbp)
  jmp    L24
L13:
  nop
  jmp    L24
L22:
  nop
L24:
  mov    -0x454(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int do_login(int sockfd) {
  int ret = 0;
  char name[32];
  char password[32];
  char packet[1024];
  login_input(name, password);
  ret = packet_pack_login_req(packet, name, password);
  ret = send_fix_len(sockfd, packet, ret);
  if (-1 == ret) {
    goto exit;
  }
  ret = recv_packet(sockfd, packet);
  if (ret <= 0) {
    goto exit;
  }
  ret = packet_unpack_login_resp(packet);
  if (0 == ret) {
    ret = 1;
  } else {
    packet_disp_err(ret);
    ret = 2;
  }
exit:
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_login>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x458,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r13
  mov    %rsp,%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <login_input@plt>
  lea    0x40(%rsp),%rbp
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <packet_pack_login_req@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_fix_len@plt>
  cmp    $0xffffffff,%eax
  je     L24
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <recv_packet@plt>
  test   %eax,%eax
  jle    L24
  mov    %rbp,%rdi
  call   <packet_unpack_login_resp@plt>
  mov    %eax,%edi
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L15
L24:
  mov    0x448(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x458,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <packet_disp_err@plt>
  mov    $0x2,%eax
  jmp    L24
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_login(int sockfd) {
  int ret = 0;
  char name[32];
  char password[32];
  char packet[1024];
  login_input(name, password);
  ret = packet_pack_login_req(packet, name, password);
  ret = send_fix_len(sockfd, packet, ret);
  if (-1 == ret) {
    goto exit;
  }
  ret = recv_packet(sockfd, packet);
  if (ret <= 0) {
    goto exit;
  }
  ret = packet_unpack_login_resp(packet);
  if (0 == ret) {
    ret = 1;
  } else {
    packet_disp_err(ret);
    ret = 2;
  }
exit:
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<do_login>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x458,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  mov    %rsp,%r13
  lea    0x40(%rsp),%r12
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <login_input@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <packet_pack_login_req@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <send_fix_len@plt>
  cmp    $0xffffffff,%eax
  je     L21
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv_packet@plt>
  test   %eax,%eax
  jle    L21
  mov    %r12,%rdi
  call   <packet_unpack_login_resp@plt>
  mov    %eax,%edi
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L41
L21:
  mov    0x448(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x458,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L41:
  call   <packet_disp_err@plt>
  mov    $0x2,%eax
  jmp    L21
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_login(int sockfd) {
  int ret = 0;
  char name[32];
  char password[32];
  char packet[1024];
  login_input(name, password);
  ret = packet_pack_login_req(packet, name, password);
  ret = send_fix_len(sockfd, packet, ret);
  if (-1 == ret) {
    goto exit;
  }
  ret = recv_packet(sockfd, packet);
  if (ret <= 0) {
    goto exit;
  }
  ret = packet_unpack_login_resp(packet);
  if (0 == ret) {
    ret = 1;
  } else {
    packet_disp_err(ret);
    ret = 2;
  }
exit:
  return ret;
}
```