ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inst>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  lea    D8(%rip),%rbp
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  lea    D36(%rip),%rdi
  pop    %rbp
  jmp    1070 <system@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D5
type: string
name: unpack_data
arguments: data_label: D45
type: string
name: unpack_data
arguments: data_label: D74
type: string
name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D33
type: string
name: unpack_data
arguments: data_label: D36
type: string

tool: D6: 
 <Informacoes>


tool: D8:  +---+---+---+


tool: D5:  /---+X;Y+---\


tool: D45:  |0;0|0;1|0;2|


tool: D74:  |1;0|1;1|1;2|


tool: D4:  |2;0|2;1|2;2|


tool: D33:  \---+---+---/


tool: D36: cls

assistant: ```c
void inst() {
  printf("\n <Informacoes>\n");
  printf(" /---+X;Y+---\\\n");
  printf(" |0;0|0;1|0;2|\n");
  printf(" +---+---+---+\n");
  printf(" |1;0|1;1|1;2|\n");
  printf(" +---+---+---+\n");
  printf(" |2;0|2;1|2;2|\n");
  printf(" \\---+---+---/\n");
  getch();
  system("cls");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inst>:
  endbr64
  push   %rbp
  lea    D32(%rip),%rdi
  lea    D3(%rip),%rbp
  call   <printf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  lea    D77(%rip),%rdi
  pop    %rbp
  jmp    1070 <system@plt>
```

tool_calls: name: parse_data
arguments: data_label: D32
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D74
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D51
datatype: string
name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D39
datatype: string
name: parse_data
arguments: data_label: D77
datatype: string

tool: D32: 
 <Informacoes>


tool: D3:  +---+---+---+


tool: D74:  /---+X;Y+---\


tool: D37:  |0;0|0;1|0;2|


tool: D51:  |1;0|1;1|1;2|


tool: D18:  |2;0|2;1|2;2|


tool: D39:  \---+---+---/


tool: D77: cls

assistant: ```c
void inst() {
  printf("\n <Informacoes>\n");
  printf(" /---+X;Y+---\\\n");
  printf(" |0;0|0;1|0;2|\n");
  printf(" +---+---+---+\n");
  printf(" |1;0|1;1|1;2|\n");
  printf(" +---+---+---+\n");
  printf(" |2;0|2;1|2;2|\n");
  printf(" \\---+---+---/\n");
  getch();
  system("cls");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vpx_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <check_size_argument_overflow@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L22
L8:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <vpx_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L13:
  mov    -0x8(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
void *vpx_calloc(size_t num, size_t size) {
  void *x;
  if (!check_size_argument_overflow(num, size))
    return NULL;
  x = vpx_malloc(num * size);
  if (x)
    memset(x, 0, num * size);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vpx_calloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <check_size_argument_overflow@plt>
  mov    $0x0,%ebp
  test   %eax,%eax
  je     L8
  imul   %r12,%rbx
  mov    %rbx,%rdi
  call   <vpx_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L8:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *vpx_calloc(size_t num, size_t size) {
  void *x;
  if (!check_size_argument_overflow(num, size))
    return NULL;
  x = vpx_malloc(num * size);
  if (x)
    memset(x, 0, num * size);
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<vpx_calloc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  call   <check_size_argument_overflow@plt>
  test   %eax,%eax
  je     L19
  imul   %rbx,%r12
  mov    %r12,%rdi
  call   <vpx_malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L19
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L19:
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *vpx_calloc(size_t num, size_t size) {
  void *x;
  if (!check_size_argument_overflow(num, size))
    return NULL;
  x = vpx_malloc(num * size);
  if (x)
    memset(x, 0, num * size);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vpx_calloc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  call   <check_size_argument_overflow@plt>
  test   %eax,%eax
  je     L10
  imul   %rbx,%r12
  mov    %r12,%rdi
  call   <vpx_malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L10
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L10:
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *vpx_calloc(size_t num, size_t size) {
  void *x;
  if (!check_size_argument_overflow(num, size))
    return NULL;
  x = vpx_malloc(num * size);
  if (x)
    memset(x, 0, num * size);
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pl_crc32_for_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L31:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L27
  mov    $0x0,%edx
  jmp    L22
L27:
  mov    $0xedb88320,%edx
L22:
  mov    -0x14(%rbp),%eax
  sar    %eax
  xor    %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x7,-0x4(%rbp)
  jle    L31
  mov    -0x14(%rbp),%eax
  xor    $0xff000000,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t pl_crc32_for_byte(uint32_t r) {
  for (int j = 0; j < 8; ++j)
    r = (r & 1 ? 0 : (uint32_t)0xEDB88320L) ^ r >> 1;
  return r ^ (uint32_t)0xFF000000L;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pl_crc32_for_byte>:
  endbr64
  mov    %edi,%eax
  mov    $0x8,%ecx
L8:
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xedb88320,%edx
  sar    %eax
  xor    %edx,%eax
  sub    $0x1,%ecx
  jne    L8
  xor    $0xff000000,%eax
  ret
```

assistant: ```c
uint32_t pl_crc32_for_byte(uint32_t r) {
  for (int j = 0; j < 8; ++j)
    r = (r & 1 ? 0 : (uint32_t)0xEDB88320L) ^ r >> 1;
  return r ^ (uint32_t)0xFF000000L;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pl_crc32_for_byte>:
  endbr64
  mov    %edi,%eax
  mov    $0x8,%ecx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  sar    %eax
  and    $0xedb88320,%edx
  xor    %edx,%eax
  sub    $0x1,%ecx
  jne    L5
  xor    $0xff000000,%eax
  ret
```

assistant: ```c
uint32_t pl_crc32_for_byte(uint32_t r) {
  for (int j = 0; j < 8; ++j)
    r = (r & 1 ? 0 : (uint32_t)0xEDB88320L) ^ r >> 1;
  return r ^ (uint32_t)0xFF000000L;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pl_crc32_for_byte>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  sar    %edi
  and    $0xedb88320,%eax
  xor    %edi,%eax
  and    $0x1,%edi
  cmp    $0x1,%edi
  mov    %eax,%edx
  sbb    %eax,%eax
  sar    %edx
  and    $0xedb88320,%eax
  xor    %edx,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  mov    %eax,%ecx
  sbb    %eax,%eax
  sar    %ecx
  and    $0xedb88320,%eax
  xor    %ecx,%eax
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %eax,%edx
  sbb    %eax,%eax
  sar    %edx
  and    $0xedb88320,%eax
  xor    %edx,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  mov    %eax,%ecx
  sbb    %eax,%eax
  sar    %ecx
  and    $0xedb88320,%eax
  xor    %ecx,%eax
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %eax,%edx
  sbb    %eax,%eax
  sar    %edx
  and    $0xedb88320,%eax
  xor    %edx,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  sar    %eax
  and    $0xedb88320,%edx
  xor    %eax,%edx
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  sar    %edx
  and    $0xedb88320,%eax
  xor    %edx,%eax
  xor    $0xff000000,%eax
  ret
```

assistant: ```c
uint32_t pl_crc32_for_byte(uint32_t r) {
  for (int j = 0; j < 8; ++j)
    r = (r & 1 ? 0 : (uint32_t)0xEDB88320L) ^ r >> 1;
  return r ^ (uint32_t)0xFF000000L;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
L89:
  movl   $0x0,0x20(%rsp,%rax,1)
  movl   $0x1,0x40(%rsp,%rax,1)
  movl   $0x2,(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L89
  mov    $0x4,%ebp
  mov    %rsp,%rbx
  jmp    L93
L67:
  lea    0x40(%rsp),%rcx
  mov    $0x1,%edx
L45:
  negl   (%rcx)
  mov    %edx,%r9d
  mov    0x4(%rcx),%eax
  add    0x20(%rsp,%rdx,4),%eax
  cmp    %eax,(%rbx,%rdx,4)
  setle  %sil
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    $0x1,%rdx
  add    $0x4,%rcx
  or     %dil,%sil
  jne    L45
L55:
  movslq %r9d,%r9
  mov    %eax,0x20(%rsp,%r9,4)
  mov    $0x0,%eax
  lea    0x60(%rsp),%rdx
L15:
  add    0x20(%rsp,%rax,1),%r8d
  sub    (%rdx,%rax,1),%r8d
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L15
  add    $0x1,%r8d
  test   $0xfffffffd,%r8d
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%ebp
  je     L34
L93:
  mov    0x30(%rsp),%r8d
  test   %r8d,%r8d
  jne    L34
  mov    0x20(%rsp),%eax
  mov    %eax,0x60(%rsp)
  mov    0x24(%rsp),%edx
  mov    %edx,0x64(%rsp)
  mov    0x28(%rsp),%edx
  mov    %edx,0x68(%rsp)
  mov    0x2c(%rsp),%edx
  mov    %edx,0x6c(%rsp)
  movl   $0x0,0x70(%rsp)
  add    0x40(%rsp),%eax
  cmp    (%rsp),%eax
  jge    L67
  test   %eax,%eax
  js     L67
  mov    %r8d,%r9d
  jmp    L55
L34:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int M = 2;
  int K = 4;
  int N = 4;
  int n[K + 1];
  int g[K + 1];
  int u[K + 1];
  int t[K + 1];
  int i, j, h, c, diff;
  for (i = 0; i <= K; i++) {
    g[i] = 0;
    u[i] = 1;
    n[i] = M;
  }
  c = 0;
  while (c < N && g[K] == 0) {
    for (h = 0; h <= K; h++)
      t[h] = g[h];
    i = 0;
    j = g[0] + u[0];
    while (j >= n[i] || j < 0) {
      u[i] = -u[i];
      i++;
      j = g[i] + u[i];
    }
    g[i] = j;
    diff = 0;
    for (h = 0; h <= K - 1; h++)
      diff += g[h] - t[h];
    assert(diff == 1 || diff == -1);
    c++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x30(%rsp)
  mov    %rsp,%rbp
  movabs $0x100000001,%rax
  mov    %rax,0x40(%rsp)
  mov    %rax,0x48(%rsp)
  movabs $0x200000002,%rax
  movl   $0x1,0x50(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  movl   $0x2,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
L58:
  mov    0x30(%rsp),%r10d
  test   %r10d,%r10d
  jne    L0
  mov    0x40(%rsp),%edx
  mov    0x20(%rsp),%ecx
  movl   $0x0,0x70(%rsp)
  movdqa 0x20(%rsp),%xmm1
  add    %edx,%ecx
  movaps %xmm1,0x60(%rsp)
  cmp    $0x1,%ecx
  jg     L53
  test   %ecx,%ecx
  jns    L8
L53:
  mov    $0x1,%eax
  lea    0x40(%rsp),%rdi
  lea    0x20(%rsp),%r9
  nopl   0x0(%rax)
L31:
  neg    %edx
  mov    (%r9,%rax,4),%ecx
  movslq %eax,%r11
  mov    %edx,-0x4(%rdi,%rax,4)
  mov    (%rdi,%rax,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  mov    %ecx,%r8d
  setle  %sil
  add    $0x1,%rax
  shr    $0x1f,%r8d
  or     %r8b,%sil
  jne    L31
L61:
  mov    %ecx,0x20(%rsp,%r11,4)
  xor    %eax,%eax
  lea    0x60(%rsp),%rdx
L73:
  add    (%r9,%rax,1),%r10d
  sub    (%rdx,%rax,1),%r10d
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L73
  add    $0x1,%r10d
  xor    %edi,%edi
  and    $0xfffffffd,%r10d
  sete   %dil
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L58
L0:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  xor    %r11d,%r11d
  lea    0x20(%rsp),%r9
  jmp    L61
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int M = 2;
  int K = 4;
  int N = 4;
  int n[K + 1];
  int g[K + 1];
  int u[K + 1];
  int t[K + 1];
  int i, j, h, c, diff;
  for (i = 0; i <= K; i++) {
    g[i] = 0;
    u[i] = 1;
    n[i] = M;
  }
  c = 0;
  while (c < N && g[K] == 0) {
    for (h = 0; h <= K; h++)
      t[h] = g[h];
    i = 0;
    j = g[0] + u[0];
    while (j >= n[i] || j < 0) {
      u[i] = -u[i];
      i++;
      j = g[i] + u[i];
    }
    g[i] = j;
    diff = 0;
    for (h = 0; h <= K - 1; h++)
      diff += g[h] - t[h];
    assert(diff == 1 || diff == -1);
    c++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  mov    %rsp,%rbp
  movdqa D17(%rip),%xmm0
  movl   $0x0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movdqa D19(%rip),%xmm0
  movl   $0x1,0x50(%rsp)
  movl   $0x2,0x10(%rsp)
  movaps %xmm0,(%rsp)
L2:
  movslq 0x30(%rsp),%r14
  test   %r14d,%r14d
  jne    L26
  mov    0x20(%rsp),%r10d
  mov    0x40(%rsp),%edx
  mov    $0x1,%eax
  lea    0x40(%rsp),%rdi
  mov    0x24(%rsp),%r11d
  mov    0x28(%rsp),%r12d
  lea    0x20(%rsp),%r9
  lea    (%rdx,%r10,1),%ecx
  mov    0x2c(%rsp),%r13d
  cmp    $0x1,%ecx
  jbe    L4
L27:
  neg    %edx
  mov    (%r9,%rax,4),%ecx
  movslq %eax,%r14
  mov    %edx,-0x4(%rdi,%rax,4)
  mov    (%rdi,%rax,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  mov    %ecx,%r8d
  setle  %sil
  add    $0x1,%rax
  shr    $0x1f,%r8d
  or     %r8b,%sil
  jne    L27
L4:
  mov    %ecx,0x20(%rsp,%r14,4)
  mov    0x20(%rsp),%eax
  xor    %edi,%edi
  mov    0x24(%rsp),%edx
  sub    %r10d,%eax
  sub    %r11d,%edx
  add    %edx,%eax
  add    0x28(%rsp),%eax
  sub    %r12d,%eax
  add    0x2c(%rsp),%eax
  sub    %r13d,%eax
  add    $0x1,%eax
  and    $0xfffffffd,%eax
  sete   %dil
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L2
L26:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D19
type_guessed: byte[16]

tool: {"D17": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D19": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int M = 2;
  int K = 4;
  int N = 4;
  int n[K + 1];
  int g[K + 1];
  int u[K + 1];
  int t[K + 1];
  int i, j, h, c, diff;
  for (i = 0; i <= K; i++) {
    g[i] = 0;
    u[i] = 1;
    n[i] = M;
  }
  c = 0;
  while (c < N && g[K] == 0) {
    for (h = 0; h <= K; h++)
      t[h] = g[h];
    i = 0;
    j = g[0] + u[0];
    while (j >= n[i] || j < 0) {
      u[i] = -u[i];
      i++;
      j = g[i] + u[i];
    }
    g[i] = j;
    diff = 0;
    for (h = 0; h <= K - 1; h++)
      diff += g[h] - t[h];
    assert(diff == 1 || diff == -1);
    c++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<plus2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%ecx
  mov    %rax,%rdi
  call   <vvp@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void plus2D(double **a, double **b, double **c, int nrows, int ncols) {
  int x;
  for (x = 0; x < nrows; ++x) {
    vvp(a[x], b[x], c[x], ncols);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<plus2D>:
  endbr64
  test   %ecx,%ecx
  jle    L1
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %r8d,%r15d
  mov    %ecx,%ebp
  mov    $0x0,%ebx
L4:
  mov    (%r14,%rbx,8),%rdx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    (%r12,%rbx,8),%rdi
  mov    %r15d,%ecx
  call   <vvp@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  ret
```

assistant: ```c
void plus2D(double **a, double **b, double **c, int nrows, int ncols) {
  int x;
  for (x = 0; x < nrows; ++x) {
    vvp(a[x], b[x], c[x], ncols);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<plus2D>:
  endbr64
  test   %ecx,%ecx
  jle    L4
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%r15,%rbx,8),%rdx
  mov    (%r14,%rbx,8),%rsi
  mov    %r12d,%ecx
  mov    0x0(%r13,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <vvp@plt>
  cmp    %rbx,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
void plus2D(double **a, double **b, double **c, int nrows, int ncols) {
  int x;
  for (x = 0; x < nrows; ++x) {
    vvp(a[x], b[x], c[x], ncols);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<plus2D>:
  endbr64
  test   %ecx,%ecx
  jle    L12
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%r15,%rbx,8),%rdx
  mov    (%r14,%rbx,8),%rsi
  mov    %r12d,%ecx
  mov    0x0(%r13,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <vvp@plt>
  cmp    %rbx,%rbp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
void plus2D(double **a, double **b, double **c, int nrows, int ncols) {
  int x;
  for (x = 0; x < nrows; ++x) {
    vvp(a[x], b[x], c[x], ncols);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L74
L105:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L74:
  mov    -0xc(%rbp),%eax
  cmp    $0x64,%eax
  jg     L105
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L105
  mov    -0xc(%rbp),%eax
  cmp    $0x5a,%eax
  jle    L37
  movb   $0x41,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L48
L37:
  mov    -0xc(%rbp),%eax
  cmp    $0x4f,%eax
  jle    L57
  movb   $0x42,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L48
L57:
  mov    -0xc(%rbp),%eax
  cmp    $0x45,%eax
  jle    L41
  movb   $0x43,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L48
L41:
  mov    -0xc(%rbp),%eax
  cmp    $0x3b,%eax
  jle    L24
  movb   $0x44,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L48
L24:
  movb   $0x45,-0xd(%rbp)
L48:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L87
  call   <__stack_chk_fail@plt>
L87:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D51
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D57
datatype: string
name: parse_data
arguments: data_label: D49
datatype: string

tool: D51: input the score:

tool: D12: %f

tool: D57: error!

tool: D49: the grade is %c


assistant: ```c
int main() {
  int i;
  char n;
  printf("input the score:");
  scanf("%f", &i);
  while (i > 100 || i < 0) {
    printf("error!");
  }
  if (i > 90) {
    n = 'A';
    printf("the grade is %c\n", n);
  } else if (i >= 80) {
    n = 'B';
    printf("the grade is %c\n", n);
  } else if (i >= 70) {
    n = 'C';
    printf("the grade is %c\n", n);
  } else if (i >= 60) {
    n = 'D';
    printf("the grade is %c\n", n);
  } else
    n = 'E';
  printf("the grade is %c\n", n);
  return 0;
}
```