ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<blockToString>:
  endbr64
  push   %r14
  lea    0x20(%rsi),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L8:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r14,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  movb   $0x0,0x20(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: %02X

assistant: ```c
void blockToString(unsigned char block[16], char *str) {
  int i;
  for (i = 0; i < 16; i++) {
    sprintf(&str[2 * i], "%02X", (int)block[i]);
  }
  str[16 * 2] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isopp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x5e,%eax
  je     L57
  cmp    $0x5e,%eax
  jg     L27
  cmp    $0x2f,%eax
  je     L63
  cmp    $0x2f,%eax
  jg     L27
  cmp    $0x2d,%eax
  je     L117
  cmp    $0x2d,%eax
  jg     L27
  cmp    $0x2a,%eax
  je     L35
  cmp    $0x2b,%eax
  jne    L27
  mov    $0x1,%eax
  jmp    L91
L117:
  mov    $0x2,%eax
  jmp    L91
L35:
  mov    $0x3,%eax
  jmp    L91
L63:
  mov    $0x4,%eax
  jmp    L91
L57:
  mov    $0x5,%eax
  jmp    L91
L27:
  mov    $0x0,%eax
L91:
  pop    %rbp
  ret
```

assistant: ```c
int isopp(char c) {
  switch (c) {
  case '+':
    return 1;
  case '-':
    return 2;
  case '*':
    return 3;
  case '/':
    return 4;
  case '^':
    return 5;
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isopp>:
  endbr64
  cmp    $0x2d,%dil
  je     L28
  jle    L15
  mov    $0x4,%eax
  cmp    $0x2f,%dil
  je     L23
  cmp    $0x5e,%dil
  sete   %al
  movzbl %al,%eax
  lea    (%rax,%rax,4),%eax
  ret
L15:
  mov    $0x3,%eax
  cmp    $0x2a,%dil
  je     L23
  cmp    $0x2b,%dil
  sete   %al
  movzbl %al,%eax
  ret
L28:
  mov    $0x2,%eax
L23:
  ret
```

assistant: ```c
int isopp(char c) {
  switch (c) {
  case '+':
    return 1;
  case '-':
    return 2;
  case '*':
    return 3;
  case '/':
    return 4;
  case '^':
    return 5;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<isopp>:
  endbr64
  cmp    $0x2d,%dil
  je     L29
  jle    L18
  mov    $0x4,%eax
  cmp    $0x2f,%dil
  je     L5
  xor    %eax,%eax
  cmp    $0x5e,%dil
  sete   %al
  lea    (%rax,%rax,4),%eax
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x3,%eax
  cmp    $0x2a,%dil
  je     L5
  xor    %eax,%eax
  cmp    $0x2b,%dil
  sete   %al
  ret
  nopl   (%rax)
L29:
  mov    $0x2,%eax
L5:
  ret
```

assistant: ```c
int isopp(char c) {
  switch (c) {
  case '+':
    return 1;
  case '-':
    return 2;
  case '*':
    return 3;
  case '/':
    return 4;
  case '^':
    return 5;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isopp>:
  endbr64
  cmp    $0x2d,%dil
  je     L22
  jle    L20
  mov    $0x4,%eax
  cmp    $0x2f,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x5e,%dil
  sete   %al
  lea    (%rax,%rax,4),%eax
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x3,%eax
  cmp    $0x2a,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x2b,%dil
  sete   %al
  ret
  nopl   (%rax)
L22:
  mov    $0x2,%eax
L7:
  ret
```

assistant: ```c
int isopp(char c) {
  switch (c) {
  case '+':
    return 1;
  case '-':
    return 2;
  case '*':
    return 3;
  case '/':
    return 4;
  case '^':
    return 5;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scan_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L70:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %eax,%eax
  jne    L11
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L11
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x4(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x4(%rbp)
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L33
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  jmp    L13
L33:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L30
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L70
L30:
  cmpl   $0x0,-0x4(%rbp)
  jne    L66
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L66:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
L13:
  leave
  ret
```

assistant: ```c
int scan_string(char *dest, char *val, int n) {
  int i = 0;
  while (*val != 0 && i < n - 1) {
    if (!isblank(*val) && *val != '\n') {
      dest[i++] = *val++;
    } else {
      dest[i] = 0;
      return i;
    }
  }
  if (i == 0)
    dest[i++] = 0;
  return i - 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scan_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L18
  mov    %rsi,%r12
  lea    -0x2(%rdx),%r15d
  mov    $0x0,%ebx
  cmp    $0x1,%edx
  jg     L62
L18:
  movb   $0x0,0x0(%r13)
  mov    $0x1,%ebp
  jmp    L76
L37:
  mov    %rax,%rbx
L62:
  mov    %ebx,%ebp
  mov    %ebx,%r14d
  movsbl %dil,%edi
  call   <isblank@plt>
  test   %eax,%eax
  jne    L65
  movzbl (%r12,%rbx,1),%eax
  cmp    $0xa,%al
  je     L65
  add    $0x1,%ebp
  mov    %al,0x0(%r13,%rbx,1)
  movzbl 0x1(%r12,%rbx,1),%edi
  test   %dil,%dil
  je     L88
  lea    0x1(%rbx),%rax
  cmp    %r15,%rbx
  jne    L37
L88:
  test   %ebp,%ebp
  je     L18
L76:
  lea    -0x1(%rbp),%r14d
L60:
  mov    %r14d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  movslq %r14d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  jmp    L60
```

assistant: ```c
int scan_string(char *dest, char *val, int n) {
  int i = 0;
  while (*val != 0 && i < n - 1) {
    if (!isblank(*val) && *val != '\n') {
      dest[i++] = *val++;
    } else {
      dest[i] = 0;
      return i;
    }
  }
  if (i == 0)
    dest[i++] = 0;
  return i - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scan_string>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  movsbl (%rsi),%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %dil,%dil
  je     L7
  mov    %rsi,%r13
  lea    -0x2(%rdx),%ebp
  xor    %ebx,%ebx
  cmp    $0x1,%edx
  jg     L1
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0xa,%al
  je     L29
  mov    %al,(%r14,%rbx,1)
  movsbl 0x1(%r13,%rbx,1),%edi
  test   %dil,%dil
  je     L61
  lea    0x1(%rbx),%rax
  cmp    %rbp,%rbx
  je     L61
  mov    %rax,%rbx
L1:
  call   <isblank@plt>
  mov    %ebx,%r12d
  lea    (%r14,%rbx,1),%rdx
  test   %eax,%eax
  je     L8
L29:
  movb   $0x0,(%rdx)
L61:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r14)
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int scan_string(char *dest, char *val, int n) {
  int i = 0;
  while (*val != 0 && i < n - 1) {
    if (!isblank(*val) && *val != '\n') {
      dest[i++] = *val++;
    } else {
      dest[i] = 0;
      return i;
    }
  }
  if (i == 0)
    dest[i++] = 0;
  return i - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<scan_string>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  movsbl (%rsi),%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %dil,%dil
  je     L45
  mov    %rsi,%r13
  lea    -0x2(%rdx),%ebp
  xor    %ebx,%ebx
  cmp    $0x1,%edx
  jg     L18
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L58:
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0xa,%al
  je     L52
  mov    %al,(%r14,%rbx,1)
  movsbl 0x1(%r13,%rbx,1),%edi
  test   %dil,%dil
  je     L22
  lea    0x1(%rbx),%rax
  cmp    %rbp,%rbx
  je     L22
  mov    %rax,%rbx
L18:
  call   <isblank@plt>
  mov    %ebx,%r12d
  lea    (%r14,%rbx,1),%rdx
  test   %eax,%eax
  je     L58
L52:
  movb   $0x0,(%rdx)
L22:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r14)
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int scan_string(char *dest, char *val, int n) {
  int i = 0;
  while (*val != 0 && i < n - 1) {
    if (!isblank(*val) && *val != '\n') {
      dest[i++] = *val++;
    } else {
      dest[i] = 0;
      return i;
    }
  }
  if (i == 0)
    dest[i++] = 0;
  return i - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<init_bit_count_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L18:
  movl   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L27:
  mov    -0xc(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L19
  addl   $0x1,-0x8(%rbp)
L19:
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0x7,-0xc(%rbp)
  jle    L27
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L11:
  cmpl   $0xff,-0x10(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_bit_count_table(int *bit_count_table) {
  int i, j;
  for (i = 0; i < 256; i++) {
    int count = 0;
    int compared_num = i;
    for (j = 0; j < 8; j++) {
      if ((compared_num >> j & 1) == 1) {
        count++;
      }
    }
    bit_count_table[i] = count;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_bit_count_table>:
  endbr64
  mov    %rdi,%r8
  mov    $0x0,%edi
  jmp    L35
L25:
  mov    %edx,(%r8,%rdi,4)
  add    $0x1,%rdi
  cmp    $0x100,%rdi
  je     L39
L35:
  mov    %edi,%esi
  mov    $0x0,%edx
  mov    $0x0,%ecx
L5:
  mov    %esi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%edx
  add    $0x1,%ecx
  cmp    $0x8,%ecx
  jne    L5
  jmp    L25
L39:
  ret
```

assistant: ```c
void init_bit_count_table(int *bit_count_table) {
  int i, j;
  for (i = 0; i < 256; i++) {
    int count = 0;
    int compared_num = i;
    for (j = 0; j < 8; j++) {
      if ((compared_num >> j & 1) == 1) {
        count++;
      }
    }
    bit_count_table[i] = count;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_bit_count_table>:
  endbr64
  mov    %rdi,%r8
  xor    %edi,%edi
  nopl   0x0(%rax)
L15:
  mov    %edi,%esi
  xor    %edx,%edx
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %esi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%edx
  add    $0x1,%ecx
  cmp    $0x8,%ecx
  jne    L19
  mov    %edx,(%r8,%rdi,4)
  add    $0x1,%rdi
  cmp    $0x100,%rdi
  jne    L15
  ret
```

assistant: ```c
void init_bit_count_table(int *bit_count_table) {
  int i, j;
  for (i = 0; i < 256; i++) {
    int count = 0;
    int compared_num = i;
    for (j = 0; j < 8; j++) {
      if ((compared_num >> j & 1) == 1) {
        count++;
      }
    }
    bit_count_table[i] = count;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_bit_count_table>:
  endbr64
  mov    %rdi,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L11
  nopl   (%rax)
L12:
  mov    %edx,%esi
  mov    %edx,%eax
  and    $0x2,%esi
  and    $0x1,%eax
  cmp    $0x1,%esi
  sbb    $0xffffffff,%eax
  add    $0x4,%rcx
L11:
  mov    %edx,%esi
  and    $0x4,%esi
  cmp    $0x1,%esi
  mov    %edx,%esi
  sbb    $0xffffffff,%eax
  and    $0x8,%esi
  cmp    $0x1,%esi
  mov    %edx,%esi
  sbb    $0xffffffff,%eax
  and    $0x10,%esi
  cmp    $0x1,%esi
  mov    %edx,%esi
  sbb    $0xffffffff,%eax
  and    $0x20,%esi
  cmp    $0x1,%esi
  mov    %edx,%esi
  sbb    $0xffffffff,%eax
  and    $0x40,%esi
  cmp    $0x1,%esi
  mov    %edx,%esi
  sbb    $0xffffffff,%eax
  sar    $0x7,%esi
  cmp    $0x1,%esi
  sbb    $0xffffffff,%eax
  add    $0x1,%edx
  mov    %eax,(%rcx)
  cmp    $0x100,%edx
  jne    L12
  ret
```

assistant: ```c
void init_bit_count_table(int *bit_count_table) {
  int i, j;
  for (i = 0; i < 256; i++) {
    int count = 0;
    int compared_num = i;
    for (j = 0; j < 8; j++) {
      if ((compared_num >> j & 1) == 1) {
        count++;
      }
    }
    bit_count_table[i] = count;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<findN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L16
  shll   -0x8(%rbp)
  jmp    L2
L16:
  nop
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <search@plt>
  leave
  ret
```

assistant: ```c
int findN(unsigned int *a) {
  int i = 0, x = 1;
  while (1) {
    i = x - 1;
    if (!a[i])
      break;
    x = x * 2;
  }
  return search(x / 2, a);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<findN>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  cmpl   $0x0,(%rdi)
  je     L12
  mov    $0x1,%edx
L6:
  add    %edx,%edx
  lea    -0x1(%rdx),%eax
  cltq
  cmpl   $0x0,(%rsi,%rax,4)
  jne    L6
L15:
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  call   <search@plt>
  add    $0x8,%rsp
  ret
L12:
  mov    $0x1,%edx
  jmp    L15
```

assistant: ```c
int findN(unsigned int *a) {
  int i = 0, x = 1;
  while (1) {
    i = x - 1;
    if (!a[i])
      break;
    x = x * 2;
  }
  return search(x / 2, a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<findN>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rsi
  test   %edx,%edx
  je     L2
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L6:
  add    %edx,%edx
  lea    -0x1(%rdx),%eax
  cltq
  mov    (%rsi,%rax,4),%eax
  test   %eax,%eax
  jne    L6
  mov    %edx,%edi
  sar    %edi
  jmp    1050 <search@plt>
  nop
L2:
  xor    %edi,%edi
  jmp    1050 <search@plt>
```

assistant: ```c
int findN(unsigned int *a) {
  int i = 0, x = 1;
  while (1) {
    i = x - 1;
    if (!a[i])
      break;
    x = x * 2;
  }
  return search(x / 2, a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findN>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rsi
  test   %edx,%edx
  je     L0
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L2:
  add    %edx,%edx
  lea    -0x1(%rdx),%eax
  cltq
  mov    (%rsi,%rax,4),%eax
  test   %eax,%eax
  jne    L2
  mov    %edx,%edi
  sar    %edi
  jmp    1050 <search@plt>
  nop
L0:
  xor    %edi,%edi
  jmp    1050 <search@plt>
```

assistant: ```c
int findN(unsigned int *a) {
  int i = 0, x = 1;
  while (1) {
    i = x - 1;
    if (!a[i])
      break;
    x = x * 2;
  }
  return search(x / 2, a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fn6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a & b;
  return tem1 + tem2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn6>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a & b;
  return tem1 + tem2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fn6>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a & b;
  return tem1 + tem2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn6>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a & b;
  return tem1 + tem2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L40
L29:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L40:
  cmpl   $0x9,-0x34(%rbp)
  jle    L29
  movl   $0x9,-0x34(%rbp)
  jmp    L34
L54:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L30
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  subl   $0x1,-0x34(%rbp)
L34:
  cmpl   $0x0,-0x34(%rbp)
  jns    L54
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D34
data_type: string
name: parse_data
arguments: data_label: D19
data_type: string

tool: D11: Inserire il numero dell'array 

tool: D6: %d

tool: D34: 
Il numero dell'array e' %d


tool: D19: PAUSE

assistant: ```c
int main() {
  int x, num[10];
  for (x = 0; x < 10; x++) {
    printf("Inserire il numero dell'array ");
    scanf("%d", &num[x]);
  }
  for (x = 9; x >= 0; x--) {
    if (num[x] != 0) {
      printf("\nIl numero dell'array e' %d\n", num[x]);
    }
  }
  system("PAUSE");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x28(%rsp),%r14
  mov    %rbp,%rbx
  lea    D28(%rip),%r13
  lea    D19(%rip),%r12
L18:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L18
  lea    0x24(%rsp),%rbx
  lea    D6(%rip),%r12
  jmp    L1
L50:
  lea    -0x4(%rbx),%rax
  cmp    %rbp,%rbx
  je     L52
  mov    %rax,%rbx
L1:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L50
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L50
L52:
  lea    D36(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D36
data_type: string

tool: D28: Inserire il numero dell'array 

tool: D19: %d

tool: D6: 
Il numero dell'array e' %d


tool: D36: PAUSE

assistant: ```c
int main() {
  int x, num[10];
  for (x = 0; x < 10; x++) {
    printf("Inserire il numero dell'array ");
    scanf("%d", &num[x]);
  }
  for (x = 9; x >= 0; x--) {
    if (num[x] != 0) {
      printf("\nIl numero dell'array e' %d\n", num[x]);
    }
  }
  system("PAUSE");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x28(%rsp),%r14
  mov    %rbp,%rbx
  nopl   0x0(%rax)
L2:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r14,%rbx
  jne    L2
  lea    0x24(%rsp),%rbx
  lea    D15(%rip),%r12
  jmp    L31
  nopl   0x0(%rax)
L51:
  lea    -0x4(%rbx),%rax
  cmp    %rbp,%rbx
  je     L55
L57:
  mov    %rax,%rbx
L31:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L51
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x4(%rbx),%rax
  cmp    %rbp,%rbx
  jne    L57
L55:
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string

tool: D17: Inserire il numero dell'array 

tool: D12: %d

tool: D15: 
Il numero dell'array e' %d


tool: D3: PAUSE

assistant: ```c
int main() {
  int x, num[10];
  for (x = 0; x < 10; x++) {
    printf("Inserire il numero dell'array ");
    scanf("%d", &num[x]);
  }
  for (x = 9; x >= 0; x--) {
    if (num[x] != 0) {
      printf("\nIl numero dell'array e' %d\n", num[x]);
    }
  }
  system("PAUSE");
}
```