user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edx
  mov    $0x1,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L56
L46:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x5397829d,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x31,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  add    $0x1,%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  cmpl   $0x0,-0x24(%rbp)
  jne    L62
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L62:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    -0x24(%rbp),%edx
  lea    0x2(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  addl   $0x1,-0x24(%rbp)
L56:
  cmpl   $0x5,-0x24(%rbp)
  jle    L46
  mov    $0x1f,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L9:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L11:
  cmpl   $0x5,-0x24(%rbp)
  jle    L9
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D75
type_infered: string
name: read_data
arguments: label: D77
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D57
type_infered: string
name: read_data
arguments: label: D59
type_infered: string
name: read_data
arguments: label: D40
type_infered: string

tool: D75: 			Loteria fantastica



tool: D77: 		Extragere direct in direct



tool: D17: Apasa balamuc pentru a incepe %c %c

tool: D25: Primul numar este %d.



tool: D24: Al %dlea numar este %d.



tool: D57: Numerele extrase in aceasta seara sunt %c
	

tool: D59: %d, 

tool: D40: 




assistant: ```c
int main() {
  int nr;
  int r[6];
  puts("\t\t\tLoteria fantastica\n\n");
  puts("\t\tExtragere direct in direct\n\n");
  printf("Apasa balamuc pentru a incepe %c %c", 1, 10);
  getchar();
  srand((unsigned)time(NULL));
  for (nr = 0; nr < 6; nr++) {
    r[nr] = rand() % 49 + 1;
    if (nr == 0)
      printf("Primul numar este %d.\n\n", r[nr]);
    else
      printf("Al %dlea numar este %d.\n\n", nr + 2, r[nr]);
  }
  printf("Numerele extrase in aceasta seara sunt %c\n\t", 31);
  for (nr = 0; nr < 6; nr++)
    printf("%d, ", r[nr]);
  printf("\n\n\n\r");
  return 0;
}
```