ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_voidList@plt>
  mov    $0x0,%eax
  call   <test_readDataList@plt>
  mov    $0x0,%eax
  call   <test_removeDataList@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidList();
  test_readDataList();
  test_removeDataList();
  return EXIT_SUCCESS;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_voidList@plt>
  mov    $0x0,%eax
  call   <test_readDataList@plt>
  mov    $0x0,%eax
  call   <test_removeDataList@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidList();
  test_readDataList();
  test_removeDataList();
  return EXIT_SUCCESS;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_voidList@plt>
  xor    %eax,%eax
  call   <test_readDataList@plt>
  xor    %eax,%eax
  call   <test_removeDataList@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidList();
  test_readDataList();
  test_removeDataList();
  return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_voidList@plt>
  xor    %eax,%eax
  call   <test_readDataList@plt>
  xor    %eax,%eax
  call   <test_removeDataList@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidList();
  test_readDataList();
  test_removeDataList();
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<directory_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L64
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L10
L64:
  cmpq   $0x0,-0x8(%rbp)
  jne    L45
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L30
L45:
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L89
  addq   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
  jmp    L101
L1:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x1,%eax
  jmp    L101
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L1
L89:
  mov    $0x2,%eax
L101:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: man

assistant: ```c
int directory_type(char *dir) {
  char *p;
  for (;;) {
    p = strrchr(dir, '/');
    if (p == NULL || p[1] != '\0')
      break;
    *p = '\0';
  }
  if (p == NULL)
    p = dir;
  else
    p++;
  if (strncmp(p, "man", 3) == 0) {
    p += 3;
    if (*p == '\0')
      return 0;
    while (isalnum((unsigned char)*p) || *p == '_') {
      if (*++p == '\0')
        return 1;
    }
  }
  return 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<directory_type>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L96
L0:
  movb   $0x0,(%rax)
L96:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L95
  cmpb   $0x0,0x1(%rax)
  je     L0
  lea    0x1(%rax),%rbx
L95:
  mov    $0x3,%edx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  jne    L16
  mov    $0x0,%eax
  cmpb   $0x0,0x3(%rbx)
  je     L16
  add    $0x3,%rbx
  jmp    L69
L36:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L10
L69:
  movzbl (%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L36
  cmpb   $0x5f,(%rbx)
  je     L36
  mov    $0x2,%eax
  jmp    L16
L10:
  mov    $0x1,%eax
L16:
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: man

assistant: ```c
int directory_type(char *dir) {
  char *p;
  for (;;) {
    p = strrchr(dir, '/');
    if (p == NULL || p[1] != '\0')
      break;
    *p = '\0';
  }
  if (p == NULL)
    p = dir;
  else
    p++;
  if (strncmp(p, "man", 3) == 0) {
    p += 3;
    if (*p == '\0')
      return 0;
    while (isalnum((unsigned char)*p) || *p == '_') {
      if (*++p == '\0')
        return 1;
    }
  }
  return 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<directory_type>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L5:
  cmpb   $0x0,0x1(%rax)
  jne    L80
  movb   $0x0,(%rax)
L40:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L5
L83:
  mov    $0x3,%edx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L68
  movzbl 0x3(%rbx),%edi
  xor    %eax,%eax
  add    $0x3,%rbx
  test   %dil,%dil
  je     L60
  nopl   0x0(%rax,%rax,1)
L59:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L65
  cmpb   $0x5f,(%rbx)
  jne    L68
L65:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L59
  mov    $0x1,%eax
L60:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  lea    0x1(%rax),%rbx
  jmp    L83
  cs nopw 0x0(%rax,%rax,1)
L68:
  mov    $0x2,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: man

assistant: ```c
int directory_type(char *dir) {
  char *p;
  for (;;) {
    p = strrchr(dir, '/');
    if (p == NULL || p[1] != '\0')
      break;
    *p = '\0';
  }
  if (p == NULL)
    p = dir;
  else
    p++;
  if (strncmp(p, "man", 3) == 0) {
    p += 3;
    if (*p == '\0')
      return 0;
    while (isalnum((unsigned char)*p) || *p == '_') {
      if (*++p == '\0')
        return 1;
    }
  }
  return 2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<directory_type>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L71:
  cmpb   $0x0,0x1(%rax)
  jne    L82
  movb   $0x0,(%rax)
L32:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L71
L64:
  mov    $0x3,%edx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L17
  xor    %eax,%eax
  cmpb   $0x0,0x3(%rbx)
  je     L7
  add    $0x3,%rbx
L65:
  movzbl (%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L31
  cmpb   $0x5f,(%rbx)
  jne    L17
L31:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L65
  mov    $0x1,%eax
L7:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  lea    0x1(%rax),%rbx
  jmp    L64
  xchg   %ax,%ax
L17:
  mov    $0x2,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: man

assistant: ```c
int directory_type(char *dir) {
  char *p;
  for (;;) {
    p = strrchr(dir, '/');
    if (p == NULL || p[1] != '\0')
      break;
    *p = '\0';
  }
  if (p == NULL)
    p = dir;
  else
    p++;
  if (strncmp(p, "man", 3) == 0) {
    p += 3;
    if (*p == '\0')
      return 0;
    while (isalnum((unsigned char)*p) || *p == '_') {
      if (*++p == '\0')
        return 1;
    }
  }
  return 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D17(%rip),%rax
  movq   %rax,%xmm0
  call   <nthPrime@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: f64
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D17: 10001

tool: D3: %.1f


assistant: ```c
int main() {
  printf("%.1f\n", nthPrime(10001.0));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  call   <nthPrime@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: f64
name: parse_data
arguments: label: D12
data_type: string

tool: D3: 10001

tool: D12: %.1f


assistant: ```c
int main() {
  printf("%.1f\n", nthPrime(10001.0));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D13(%rip),%xmm0
  call   <nthPrime@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: f64
name: read_data
arguments: data_tag: D6
type_infered: string

tool: D13: 10001

tool: D6: %.1f


assistant: ```c
int main() {
  printf("%.1f\n", nthPrime(10001.0));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D12(%rip),%xmm0
  call   <nthPrime@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type: f64
name: read_data
arguments: data_label: D11
type: string

tool: D12: 10001

tool: D11: %.1f


assistant: ```c
int main() {
  printf("%.1f\n", nthPrime(10001.0));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L8:
  nop
  leave
  ret
```

assistant: ```c
void trim(char *s) {
  int n = strlen(s) - 1;
  if ((n > 0) && (s[n] == '\n')) {
    s[n] = '\0';
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L9
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L15
L9:
  pop    %rbx
  ret
L15:
  movb   $0x0,(%rbx)
  jmp    L9
```

assistant: ```c
void trim(char *s) {
  int n = strlen(s) - 1;
  if ((n > 0) && (s[n] == '\n')) {
    s[n] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L15
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L9
L15:
  pop    %rbx
  ret
L9:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void trim(char *s) {
  int n = strlen(s) - 1;
  if ((n > 0) && (s[n] == '\n')) {
    s[n] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L5
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L4
L5:
  pop    %rbx
  ret
L4:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void trim(char *s) {
  int n = strlen(s) - 1;
  if ((n > 0) && (s[n] == '\n')) {
    s[n] = '\0';
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<transpose_64x64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x55555555,0x20(%rsp)
  movl   $0xaaaaaaaa,0x24(%rsp)
  movl   $0x33333333,0x28(%rsp)
  movl   $0xcccccccc,0x2c(%rsp)
  movl   $0xf0f0f0f,0x30(%rsp)
  movl   $0xf0f0f0f0,0x34(%rsp)
  movl   $0xff00ff,0x38(%rsp)
  movl   $0xff00ff00,0x3c(%rsp)
  movl   $0xffff,0x40(%rsp)
  movl   $0xffff0000,0x44(%rsp)
  movl   $0xffffffff,0x48(%rsp)
  movl   $0x0,0x4c(%rsp)
L89:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L89
  lea    0x20(%rsp),%r15
  movl   $0x5,0x14(%rsp)
  lea    0x4(%rdi),%rax
  mov    %rax,0x18(%rsp)
  jmp    L45
L18:
  mov    0x28(%r15),%r9d
  mov    0x2c(%r15),%r8d
  lea    (%r14,%rbx,1),%rdx
L19:
  mov    (%rdx),%eax
  mov    (%rdx,%r11,4),%esi
  mov    %r9d,%edi
  and    %esi,%edi
  shl    %cl,%edi
  mov    %eax,%r10d
  and    %r9d,%r10d
  or     %r10d,%edi
  mov    %edi,(%rdx)
  and    %r8d,%eax
  sar    %cl,%eax
  and    %r8d,%esi
  or     %esi,%eax
  mov    %eax,(%rdx,%r11,4)
  add    $0x4,%rdx
  cmp    %rbx,%rdx
  jne    L19
L50:
  add    %r13d,%ebp
  add    %r13d,%r12d
  add    0x8(%rsp),%rbx
  cmp    $0x3f,%ebp
  jg     L86
L81:
  cmp    %r12d,%ebp
  jl     L18
  jmp    L50
L86:
  subl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  sub    $0x8,%r15
  cmp    $0xffffffff,%eax
  je     L7
L45:
  mov    $0x1,%r10d
  mov    0x14(%rsp),%eax
  mov    %eax,%ecx
  shl    %cl,%r10d
  mov    $0x2,%r13d
  shl    %cl,%r13d
  mov    %r10d,%r12d
  movslq %r13d,%rax
  shl    $0x2,%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r10),%r14d
  mov    0x18(%rsp),%rax
  lea    (%rax,%r14,4),%rbx
  mov    $0x0,%ebp
  not    %r14
  shl    $0x2,%r14
  movslq %r10d,%r11
  mov    %r10d,%ecx
  jmp    L81
L7:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void transpose_64x64(uint64_t *out, uint64_t *in) {
  int i, j, s, d;
  uint64_t x, y;
  uint64_t masks[6][2] = {{0x5555555555555555, 0xAAAAAAAAAAAAAAAA}, {0x3333333333333333, 0xCCCCCCCCCCCCCCCC}, {0x0F0F0F0F0F0F0F0F, 0xF0F0F0F0F0F0F0F0}, {0x00FF00FF00FF00FF, 0xFF00FF00FF00FF00}, {0x0000FFFF0000FFFF, 0xFFFF0000FFFF0000}, {0x00000000FFFFFFFF, 0xFFFFFFFF00000000}};
  for (i = 0; i < 64; i++)
    out[i] = in[i];
  for (d = 5; d >= 0; d--) {
    s = 1 << d;
    for (i = 0; i < 64; i += s * 2)
      for (j = i; j < i + s; j++) {
        x = (out[j] & masks[d][0]) | ((out[j + s] & masks[d][0]) << s);
        y = ((out[j] & masks[d][1]) >> s) | (out[j + s] & masks[d][1]);
        out[j + 0] = x;
        out[j + s] = y;
      }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transpose_64x64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0xaaaaaaaa55555555,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xcccccccc33333333,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xf0f0f0f00f0f0f0f,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xff00ff0000ff00ff,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xffff00000000ffff,%rax
  mov    %rax,0x40(%rsp)
  mov    $0xffffffff,%eax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L55:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L55
  lea    0x4(%rdi),%rax
  movl   $0x5,0x14(%rsp)
  lea    0x20(%rsp),%r15
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L47:
  mov    0x14(%rsp),%eax
  mov    $0x1,%r10d
  mov    $0x2,%r13d
  xor    %ebp,%ebp
  mov    0x18(%rsp),%rbx
  mov    %eax,%ecx
  shl    %cl,%r10d
  shl    %cl,%r13d
  mov    $0xfffffffffffffffc,%rcx
  lea    -0x1(%r10),%eax
  movslq %r13d,%r14
  mov    %r10d,%r12d
  movslq %r10d,%r11
  shl    $0x2,%rax
  shl    $0x2,%r14
  sub    %rax,%rcx
  add    %rax,%rbx
  mov    %rcx,0x8(%rsp)
  mov    %r10d,%ecx
  nopl   0x0(%rax)
L54:
  cmp    %r12d,%ebp
  jge    L58
  mov    0x8(%rsp),%rax
  mov    0x28(%r15),%r9d
  mov    0x2c(%r15),%r8d
  lea    (%rax,%rbx,1),%rdx
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    (%rdx),%eax
  mov    (%rdx,%r11,4),%esi
  mov    %r9d,%edi
  and    %esi,%edi
  mov    %eax,%r10d
  and    %r8d,%eax
  and    %r8d,%esi
  shl    %cl,%edi
  and    %r9d,%r10d
  sar    %cl,%eax
  or     %r10d,%edi
  or     %esi,%eax
  mov    %edi,(%rdx)
  mov    %eax,(%rdx,%r11,4)
  add    $0x4,%rdx
  cmp    %rdx,%rbx
  jne    L24
L58:
  add    %r13d,%ebp
  add    %r13d,%r12d
  add    %r14,%rbx
  cmp    $0x3f,%ebp
  jle    L54
  subl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  sub    $0x8,%r15
  cmp    $0xffffffff,%eax
  jne    L47
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void transpose_64x64(uint64_t *out, uint64_t *in) {
  int i, j, s, d;
  uint64_t x, y;
  uint64_t masks[6][2] = {{0x5555555555555555, 0xAAAAAAAAAAAAAAAA}, {0x3333333333333333, 0xCCCCCCCCCCCCCCCC}, {0x0F0F0F0F0F0F0F0F, 0xF0F0F0F0F0F0F0F0}, {0x00FF00FF00FF00FF, 0xFF00FF00FF00FF00}, {0x0000FFFF0000FFFF, 0xFFFF0000FFFF0000}, {0x00000000FFFFFFFF, 0xFFFFFFFF00000000}};
  for (i = 0; i < 64; i++)
    out[i] = in[i];
  for (d = 5; d >= 0; d--) {
    s = 1 << d;
    for (i = 0; i < 64; i += s * 2)
      for (j = i; j < i + s; j++) {
        x = (out[j] & masks[d][0]) | ((out[j + s] & masks[d][0]) << s);
        y = ((out[j] & masks[d][1]) >> s) | (out[j + s] & masks[d][1]);
        out[j + 0] = x;
        out[j + s] = y;
      }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CRYPTO_get_locked_mem_ex_functions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L19:
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  mov    D9(%rip),%rdx
  mov    %rdx,(%rax)
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CRYPTO_get_locked_mem_ex_functions(void *(**m)(size_t, const char *, int), void (**f)(void *)) {
  if (m != NULL)
    *m = NULL;
  if (f != NULL)
    *f = free;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CRYPTO_get_locked_mem_ex_functions>:
  endbr64
  test   %rdi,%rdi
  je     L0
  movq   $0x0,(%rdi)
L0:
  test   %rsi,%rsi
  je     L11
  mov    D6(%rip),%rax
  mov    %rax,(%rsi)
L11:
  ret
```

assistant: ```c
void CRYPTO_get_locked_mem_ex_functions(void *(**m)(size_t, const char *, int), void (**f)(void *)) {
  if (m != NULL)
    *m = NULL;
  if (f != NULL)
    *f = free;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CRYPTO_get_locked_mem_ex_functions>:
  endbr64
  test   %rdi,%rdi
  je     L4
  movq   $0x0,(%rdi)
L4:
  test   %rsi,%rsi
  je     L6
  mov    D5(%rip),%rax
  mov    %rax,(%rsi)
L6:
  ret
```

assistant: ```c
void CRYPTO_get_locked_mem_ex_functions(void *(**m)(size_t, const char *, int), void (**f)(void *)) {
  if (m != NULL)
    *m = NULL;
  if (f != NULL)
    *f = free;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CRYPTO_get_locked_mem_ex_functions>:
  endbr64
  test   %rdi,%rdi
  je     L7
  movq   $0x0,(%rdi)
L7:
  test   %rsi,%rsi
  je     L19
  mov    D2(%rip),%rax
  mov    %rax,(%rsi)
L19:
  ret
```

assistant: ```c
void CRYPTO_get_locked_mem_ex_functions(void *(**m)(size_t, const char *, int), void (**f)(void *)) {
  if (m != NULL)
    *m = NULL;
  if (f != NULL)
    *f = free;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fputx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%esi
  lea    -0x30(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x10,%edx
  mov    %rax,%rdi
  call   <fmtint@plt>
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int fputx(unsigned d, FILE *f) {
  char buff[32];
  fmtint(buff, d, 16, 0);
  return fputs(buff, f);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fputx>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ecx
  mov    $0x10,%edx
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <fmtint@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fputs@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fputx(unsigned d, FILE *f) {
  char buff[32];
  fmtint(buff, d, 16, 0);
  return fputs(buff, f);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fputx>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    $0x10,%edx
  push   %rbp
  mov    %rsi,%rbp
  mov    %edi,%esi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <fmtint@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fputs@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fputx(unsigned d, FILE *f) {
  char buff[32];
  fmtint(buff, d, 16, 0);
  return fputs(buff, f);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fputx>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    $0x10,%edx
  push   %rbp
  mov    %rsi,%rbp
  mov    %edi,%esi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <fmtint@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fputs@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fputx(unsigned d, FILE *f) {
  char buff[32];
  fmtint(buff, d, 16, 0);
  return fputs(buff, f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xp_sem_unlink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int xp_sem_unlink(const char *name) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xp_sem_unlink>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int xp_sem_unlink(const char *name) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xp_sem_unlink>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int xp_sem_unlink(const char *name) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xp_sem_unlink>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int xp_sem_unlink(const char *name) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Command_GetValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
data_type: string

tool: D12:  

assistant: ```c
char *Command_GetValue(char *expression) {
  char *value;
  value = strtok(expression, " ");
  value = strtok(NULL, " ");
  return value;
}
```