ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calday_to_date>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <calendar_dpy@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %r12d,%esi
  mov    %eax,%edi
  sub    $0x16d,%eax
  lea    0x14(%rsp),%r8
  cmp    $0x1,%eax
  jbe    L25
  cmp    $0x168,%edi
  jne    L19
L25:
  call   <decode_day@plt>
L28:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <cdiEncodeDate@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  mov    %ebp,%edi
  call   <decode_julday@plt>
  jmp    L28
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int calday_to_date(int calendar, int calday) {
  int date;
  int dpy;
  int year, month, day;
  dpy = calendar_dpy(calendar);
  if (dpy == 360 || dpy == 365 || dpy == 366)
    decode_day(dpy, calday, &year, &month, &day);
  else
    decode_julday(calendar, calday, &year, &month, &day);
  date = cdiEncodeDate(year, month, day);
  return (date);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<binarySearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  jmp    L24
L13:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <printRow@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L51
  mov    -0x4(%rbp),%eax
  jmp    L46
L51:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L23
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  jmp    L24
L23:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
L24:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L13
  mov    $0xffffffff,%eax
L46:
  leave
  ret
```

assistant: ```c
int binarySearch(const int b[], int searchKey, int low, int high) {
  int middle;
  while (low <= high) {
    middle = (low + high) / 2;
    printRow(b, low, middle, high);
    if (searchKey == b[middle]) {
      return middle;
    } else if (searchKey < b[middle]) {
      high = middle - 1;
    } else {
      low = middle + 1;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<binarySearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %edx,%r12d
  mov    %ecx,%ebp
  cmp    %ecx,%edx
  jle    L26
  mov    $0xffffffff,%r15d
  jmp    L24
L5:
  lea    0x1(%rbx),%r12d
L11:
  cmp    %ebp,%r12d
  jg     L4
L26:
  lea    (%r12,%rbp,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%r15d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printRow@plt>
  movslq %ebx,%rax
  mov    0x0(%r13,%rax,4),%eax
  cmp    %r14d,%eax
  je     L24
  jle    L5
  lea    -0x1(%rbx),%ebp
  jmp    L11
L4:
  mov    $0xffffffff,%r15d
L24:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int binarySearch(const int b[], int searchKey, int low, int high) {
  int middle;
  while (low <= high) {
    middle = (low + high) / 2;
    printRow(b, low, middle, high);
    if (searchKey == b[middle]) {
      return middle;
    } else if (searchKey < b[middle]) {
      high = middle - 1;
    } else {
      low = middle + 1;
    }
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binarySearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  jg     L50
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %ecx,%ebp
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L15:
  lea    -0x1(%rbx),%ebp
  cmp    %r13d,%ebp
  jl     L50
L28:
  lea    0x0(%r13,%rbp,1),%eax
  mov    %ebp,%ecx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%edx
  mov    %ebx,%r15d
  call   <printRow@plt>
  movslq %ebx,%rax
  cmp    %r12d,(%r14,%rax,4)
  je     L35
  jg     L15
  lea    0x1(%rbx),%r13d
  cmp    %r13d,%ebp
  jge    L28
L50:
  mov    $0xffffffff,%r15d
L35:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int binarySearch(const int b[], int searchKey, int low, int high) {
  int middle;
  while (low <= high) {
    middle = (low + high) / 2;
    printRow(b, low, middle, high);
    if (searchKey == b[middle]) {
      return middle;
    } else if (searchKey < b[middle]) {
      high = middle - 1;
    } else {
      low = middle + 1;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binarySearch>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  jg     L52
  nopl   0x0(%rax)
L58:
  lea    0x0(%r13,%rbp,1),%eax
  mov    %ebp,%ecx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%edx
  mov    %ebx,%r15d
  call   <printRow@plt>
  movslq %ebx,%rax
  cmp    %r12d,(%r14,%rax,4)
  je     L57
  jle    L45
  lea    -0x1(%rbx),%ebp
  cmp    %r13d,%ebp
  jge    L58
L52:
  mov    $0xffffffff,%r15d
L57:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  lea    0x1(%rbx),%r13d
  cmp    %ebp,%r13d
  jle    L58
  jmp    L52
```

assistant: ```c
int binarySearch(const int b[], int searchKey, int low, int high) {
  int middle;
  while (low <= high) {
    middle = (low + high) / 2;
    printRow(b, low, middle, high);
    if (searchKey == b[middle]) {
      return middle;
    } else if (searchKey < b[middle]) {
      high = middle - 1;
    } else {
      low = middle + 1;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jbe    L0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
  mov    $0x1,%eax
  jmp    L5
L0:
  mov    $0x1,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: memory address wrong

assistant: ```c
int print_line(const char *begin, const char *end) {
  if (begin > end) {
    print_error("memory address wrong");
    return 1;
  }
  int len;
  char str[25];
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_line>:
  endbr64
  cmp    %rdi,%rsi
  jb     L6
  mov    $0x1,%eax
  ret
L6:
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <print_error@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: memory address wrong

assistant: ```c
int print_line(const char *begin, const char *end) {
  if (begin > end) {
    print_error("memory address wrong");
    return 1;
  }
  int len;
  char str[25];
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_line>:
  endbr64
  cmp    %rdi,%rsi
  jb     L9
  mov    $0x1,%eax
  ret
  nop
L9:
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <print_error@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: memory address wrong

assistant: ```c
int print_line(const char *begin, const char *end) {
  if (begin > end) {
    print_error("memory address wrong");
    return 1;
  }
  int len;
  char str[25];
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_line>:
  endbr64
  cmp    %rdi,%rsi
  jb     L8
  mov    $0x1,%eax
  ret
  nop
L8:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <print_error@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: memory address wrong

assistant: ```c
int print_line(const char *begin, const char *end) {
  if (begin > end) {
    print_error("memory address wrong");
    return 1;
  }
  int len;
  char str[25];
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_nan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    $0x1,%eax
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L9
  mov    $0x0,%eax
L9:
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_nan(float x) {
  float var = x;
  return (var != var) ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_nan>:
  endbr64
  ucomiss %xmm0,%xmm0
  setp   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_nan(float x) {
  float var = x;
  return (var != var) ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_nan>:
  endbr64
  xor    %eax,%eax
  ucomiss %xmm0,%xmm0
  setp   %al
  ret
```

assistant: ```c
int is_nan(float x) {
  float var = x;
  return (var != var) ? 1 : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_nan>:
  endbr64
  xor    %eax,%eax
  ucomiss %xmm0,%xmm0
  setp   %al
  ret
```

assistant: ```c
int is_nan(float x) {
  float var = x;
  return (var != var) ? 1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<psvec4i_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vec4i_zero@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_zero(struct vec4i *result) {
  vec4i_zero((int32_t *)result);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<psvec4i_zero>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec4i_zero@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_zero(struct vec4i *result) {
  vec4i_zero((int32_t *)result);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<psvec4i_zero>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4i_zero@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_zero(struct vec4i *result) {
  vec4i_zero((int32_t *)result);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<psvec4i_zero>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4i_zero@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_zero(struct vec4i *result) {
  vec4i_zero((int32_t *)result);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jelio_litostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L62
  cmpl   $0x24,-0x20(%rbp)
  jbe    L64
L62:
  movl   $0xa,-0x20(%rbp)
L64:
  movl   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jns    L95
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  neg    %rdx
  cmovns %rdx,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x1,-0xc(%rbp)
L95:
  cmpq   $0x0,-0x28(%rbp)
  jne    L63
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
  movl   $0x1,-0x10(%rbp)
  jmp    L63
L10:
  subq   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x7,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L48:
  mov    -0x20(%rbp),%esi
  mov    -0x28(%rbp),%rax
  cqto
  idiv   %rsi
  mov    %rax,-0x28(%rbp)
  addl   $0x1,-0x10(%rbp)
L63:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L66
  cmpq   $0x0,-0x28(%rbp)
  jne    L10
L66:
  cmpl   $0x0,-0xc(%rbp)
  je     L65
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L65
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int jelio_litostr(char *s, unsigned int size, long int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = labs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jelio_litostr>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%eax
  mov    %rdx,%rsi
  lea    -0x1(%rax),%r9d
  add    %rdi,%r9
  movb   $0x0,(%r9)
  lea    -0x1(%rcx),%eax
  cmp    $0x24,%eax
  mov    $0xa,%eax
  cmovae %eax,%ecx
  test   %rdx,%rdx
  js     L43
  jne    L62
  lea    -0x1(%r9),%rsi
  movb   $0x30,-0x1(%r9)
  mov    $0x1,%ebx
L111:
  lea    0x1(%rbx),%edx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L43:
  mov    %rdx,%rax
  neg    %rax
  cmovns %rax,%rsi
  mov    $0x1,%r10d
L112:
  cmp    %r8,%r9
  seta   %dl
  test   %rsi,%rsi
  je     L95
  test   %dl,%dl
  je     L95
  mov    %r9,%rdi
  mov    %ecx,%ecx
L63:
  sub    $0x1,%rdi
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  lea    0x30(%rdx),%eax
  add    $0x37,%edx
  cmp    $0x3a,%al
  cmovge %edx,%eax
  mov    %al,(%rdi)
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  mov    %rax,%rsi
  mov    %r9d,%ebx
  sub    %edi,%ebx
  cmp    %rdi,%r8
  setb   %dl
  test   %rax,%rax
  je     L99
  test   %dl,%dl
  jne    L63
L99:
  test   %r10d,%r10d
  je     L20
  test   %dl,%dl
  je     L20
  lea    -0x1(%rdi),%rsi
  movb   $0x2d,-0x1(%rdi)
  add    $0x1,%ebx
  jmp    L111
L62:
  mov    $0x0,%r10d
  jmp    L112
L95:
  mov    %r9,%rdi
  mov    $0x0,%ebx
  jmp    L99
L20:
  mov    %rdi,%rsi
  jmp    L111
```

assistant: ```c
int jelio_litostr(char *s, unsigned int size, long int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = labs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jelio_litostr>:
  endbr64
  mov    %rdx,%rax
  lea    -0x1(%rsi),%r9d
  lea    -0x1(%rcx),%edx
  push   %r12
  add    %rdi,%r9
  cmp    $0x24,%edx
  mov    $0xa,%edx
  mov    %rdi,%r8
  movb   $0x0,(%r9)
  cmovae %edx,%ecx
  test   %rax,%rax
  js     L48
  jne    L86
  movb   $0x30,-0x1(%r9)
  lea    -0x1(%r9),%rsi
  mov    $0x1,%r12d
  mov    $0x2,%edx
L44:
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  neg    %rax
  cmp    %rdi,%r9
  mov    $0x1,%r10d
  seta   %dl
  jbe    L49
L88:
  mov    %ecx,%edi
  mov    %r9,%rcx
  xchg   %ax,%ax
L55:
  cqto
  sub    $0x1,%rcx
  idiv   %rdi
  lea    0x30(%rdx),%esi
  add    $0x37,%edx
  cmp    $0x3a,%sil
  cmovae %edx,%esi
  mov    %sil,(%rcx)
  mov    %r9d,%esi
  sub    %ecx,%esi
  cmp    %rcx,%r8
  setb   %dl
  test   %rax,%rax
  je     L105
  test   %dl,%dl
  jne    L55
L105:
  lea    0x1(%rsi),%eax
L10:
  test   %dl,%dl
  je     L91
  test   %r10b,%r10b
  je     L91
  movb   $0x2d,-0x1(%rcx)
  mov    %eax,%r12d
  lea    -0x1(%rcx),%rsi
  lea    0x1(%rax),%edx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L86:
  cmp    %rdi,%r9
  jbe    L42
  xor    %r10d,%r10d
  jmp    L88
L49:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L10
L42:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
L91:
  mov    %esi,%r12d
  mov    %eax,%edx
  mov    %rcx,%rsi
  jmp    L44
```

assistant: ```c
int jelio_litostr(char *s, unsigned int size, long int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = labs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jelio_litostr>:
  endbr64
  mov    %rdx,%rax
  lea    -0x1(%rsi),%r9d
  lea    -0x1(%rcx),%edx
  push   %r12
  add    %rdi,%r9
  cmp    $0x24,%edx
  mov    $0xa,%edx
  mov    %rdi,%r8
  movb   $0x0,(%r9)
  cmovae %edx,%ecx
  test   %rax,%rax
  js     L66
  jne    L8
  movb   $0x30,-0x1(%r9)
  lea    -0x1(%r9),%rsi
  mov    $0x1,%r12d
  mov    $0x2,%edx
L69:
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  neg    %rax
  cmp    %rdi,%r9
  mov    $0x1,%r10d
  seta   %dl
  jbe    L101
L19:
  mov    %ecx,%edi
  mov    %r9,%rcx
  xchg   %ax,%ax
L38:
  cqto
  sub    $0x1,%rcx
  idiv   %rdi
  lea    0x30(%rdx),%esi
  add    $0x37,%edx
  cmp    $0x39,%sil
  cmovbe %esi,%edx
  mov    %r9d,%esi
  sub    %ecx,%esi
  cmp    %rcx,%r8
  mov    %dl,(%rcx)
  setb   %dl
  test   %rax,%rax
  je     L16
  test   %dl,%dl
  jne    L38
L16:
  lea    0x1(%rsi),%eax
  test   %r10b,%r10b
  je     L104
L79:
  test   %dl,%dl
  je     L104
  movb   $0x2d,-0x1(%rcx)
  mov    %eax,%r12d
  lea    -0x1(%rcx),%rsi
  lea    0x1(%rax),%edx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L8:
  cmp    %rdi,%r9
  jbe    L46
  xor    %r10d,%r10d
  jmp    L19
L101:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L79
L46:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
L104:
  mov    %esi,%r12d
  mov    %eax,%edx
  mov    %rcx,%rsi
  jmp    L69
```

assistant: ```c
int jelio_litostr(char *s, unsigned int size, long int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = labs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<abs_v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L9
  movss  -0x4(%rbp),%xmm0
  movss  D5(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L9:
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x80]}

assistant: ```c
float abs_v(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<abs_v>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L5
L17:
  ret
L5:
  xorps  D9(%rip),%xmm0
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float abs_v(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<abs_v>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L0
  ret
  xchg   %ax,%ax
L0:
  xorps  D3(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float abs_v(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<abs_v>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L2
  ret
  xchg   %ax,%ax
L2:
  xorps  D7(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float abs_v(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rbits16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  shr    %ax
  and    $0x5555,%ax
  mov    %eax,%edx
  movzwl -0x4(%rbp),%eax
  add    %eax,%eax
  and    $0xaaaa,%ax
  or     %edx,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  shr    $0x2,%ax
  and    $0x3333,%ax
  mov    %eax,%edx
  movzwl -0x4(%rbp),%eax
  shl    $0x2,%eax
  and    $0xcccc,%ax
  or     %edx,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  shr    $0x4,%ax
  and    $0xf0f,%ax
  mov    %eax,%edx
  movzwl -0x4(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf0f0,%ax
  or     %edx,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  movzwl -0x4(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
extern unsigned short rbits16(unsigned short w) {
  w = ((w >> 1) & 0x5555) | ((w << 1) & 0xaaaa);
  w = ((w >> 2) & 0x3333) | ((w << 2) & 0xcccc);
  w = ((w >> 4) & 0x0f0f) | ((w << 4) & 0xf0f0);
  w = ((w >> 8) & 0x00ff) | ((w << 8) & 0xff00);
  return w;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rbits16>:
  endbr64
  mov    %edi,%eax
  shr    %di
  and    $0x5555,%di
  add    %eax,%eax
  and    $0xaaaa,%ax
  or     %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%dx
  and    $0x3333,%dx
  shl    $0x2,%edi
  and    $0xcccc,%di
  or     %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%ax
  and    $0xf0f,%ax
  shl    $0x4,%edx
  and    $0xf0f0,%dx
  or     %edx,%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
extern unsigned short rbits16(unsigned short w) {
  w = ((w >> 1) & 0x5555) | ((w << 1) & 0xaaaa);
  w = ((w >> 2) & 0x3333) | ((w << 2) & 0xcccc);
  w = ((w >> 4) & 0x0f0f) | ((w << 4) & 0xf0f0);
  w = ((w >> 8) & 0x00ff) | ((w << 8) & 0xff00);
  return w;
}
```