ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<merge>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%esi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  movl   $0x0,0x4(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x4(%rsp),%rsi
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  sub    $0x8,%rsp
  mov    %rbp,%r8
  movl   $0x0,0x10(%rsp)
  lea    0x0(%r13,%rbx,1),%edx
  movl   $0x0,0x14(%rsp)
  push   %r13
  push   %rbx
  push   %r12
  lea    0x28(%rsp),%r9
  call   <sort_extra@plt>
  add    $0x20,%rsp
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *merge(int *arr1, int *arr2, int size_a, int size_b) {
  int *merged_arr = (int *)calloc(1, sizeof(int));
  int i, j, k;
  i = 0;
  j = 0;
  k = 0;
  sort_extra(&merged_arr, &i, size_a + size_b, &k, arr2, &j, arr1, size_b, size_a);
  free(arr1);
  free(arr2);
  return merged_arr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L27
  mov    -0xc(%rbp),%eax
  jmp    L15
L27:
  mov    $0x0,%eax
  call   <cpu_count@plt>
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: STRM_THREAD_MAX

assistant: ```c
int thread_count() {
  char *e = getenv("STRM_THREAD_MAX");
  int n;
  if (e) {
    n = atoi(e);
    if (n > 0)
      return n;
  }
  return cpu_count();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<thread_count>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jg     L0
L13:
  mov    $0x0,%eax
  call   <cpu_count@plt>
L0:
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: STRM_THREAD_MAX

assistant: ```c
int thread_count() {
  char *e = getenv("STRM_THREAD_MAX");
  int n;
  if (e) {
    n = atoi(e);
    if (n > 0)
      return n;
  }
  return cpu_count();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread_count>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jg     L12
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <cpu_count@plt>
L12:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: STRM_THREAD_MAX

assistant: ```c
int thread_count() {
  char *e = getenv("STRM_THREAD_MAX");
  int n;
  if (e) {
    n = atoi(e);
    if (n > 0)
      return n;
  }
  return cpu_count();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread_count>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jg     L7
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <cpu_count@plt>
L7:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: STRM_THREAD_MAX

assistant: ```c
int thread_count() {
  char *e = getenv("STRM_THREAD_MAX");
  int n;
  if (e) {
    n = atoi(e);
    if (n > 0)
      return n;
  }
  return cpu_count();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_strlenchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L20:
  addl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L22
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
L22:
  mov    -0x20(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strlenchr(char const *s, char c, int i) {
  int n;
  n = 0;
  while (s[i] != c && s[i] != '\0') {
    i++;
    n++;
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_strlenchr>:
  endbr64
  mov    %esi,%r8d
  movslq %edx,%rax
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L37
  cmp    %sil,%al
  je     L37
  add    $0x1,%edx
  movslq %edx,%rax
L32:
  mov    %eax,%edx
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L37
  cmp    %r8b,%cl
  jne    L32
L37:
  mov    %edx,%eax
  ret
```

assistant: ```c
int ft_strlenchr(char const *s, char c, int i) {
  int n;
  n = 0;
  while (s[i] != c && s[i] != '\0') {
    i++;
    n++;
  }
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strlenchr>:
  endbr64
  movslq %edx,%rax
  mov    %esi,%r9d
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L3
  cmp    %sil,%al
  je     L3
  add    $0x1,%edx
  movslq %edx,%rax
  jmp    L45
  nop
L11:
  cmp    %r9b,%cl
  je     L43
L45:
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%r8d
  add    $0x1,%rax
  test   %cl,%cl
  jne    L11
L43:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strlenchr(char const *s, char c, int i) {
  int n;
  n = 0;
  while (s[i] != c && s[i] != '\0') {
    i++;
    n++;
  }
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strlenchr>:
  endbr64
  movslq %edx,%rax
  mov    %esi,%r9d
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L36
  cmp    %sil,%al
  je     L36
  add    $0x1,%edx
  movslq %edx,%rax
  jmp    L37
  nop
L33:
  cmp    %r9b,%cl
  je     L32
L37:
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%r8d
  add    $0x1,%rax
  test   %cl,%cl
  jne    L33
L32:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strlenchr(char const *s, char c, int i) {
  int n;
  n = 0;
  while (s[i] != c && s[i] != '\0') {
    i++;
    n++;
  }
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L9
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L15
L9:
  mov    -0x4(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return (c - 'a' + 'A');
  else
    return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<toupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <islower@plt>
  mov    %rax,%rdx
  lea    -0x20(%rbx),%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return (c - 'a' + 'A');
  else
    return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <islower@plt>
  mov    %rax,%r8
  lea    -0x20(%r12),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return (c - 'a' + 'A');
  else
    return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <islower@plt>
  mov    %rax,%r8
  lea    -0x20(%r12),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return (c - 'a' + 'A');
  else
    return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <func@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  i = func(10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <func@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  i = func(10);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  i = func(10);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  i = func(10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<url_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L81
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L85
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L85
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L85
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L85
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jne    L2
L85:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L39
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L21
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2b,(%rax)
  jmp    L39
L21:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x25,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sar    $0x4,%al
  movsbl %al,%eax
  mov    %eax,%edi
  call   <to_hex@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <to_hex@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L39:
  addq   $0x1,-0x18(%rbp)
L81:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *url_encode(char *str) {
  char *pstr = str, *buf = malloc(strlen(str) * 3 + 1), *pbuf = buf;
  while (*pstr) {
    if (isalnum(*pstr) || *pstr == '-' || *pstr == '_' || *pstr == '.' || *pstr == '~')
      *pbuf++ = *pstr;
    else if (*pstr == ' ')
      *pbuf++ = '+';
    else
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex((char)(*pstr & 15));
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<url_encode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,2),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L71
  mov    %rax,%rbp
  jmp    L8
L49:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
L21:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L53
L8:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L49
  movzbl (%rbx),%eax
  cmp    $0x5f,%al
  sete   %dl
  cmp    $0x7e,%al
  sete   %cl
  or     %cl,%dl
  jne    L49
  lea    -0x2d(%rax),%edx
  cmp    $0x1,%dl
  jbe    L49
  cmp    $0x20,%al
  jne    L1
  movb   $0x2b,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L21
L1:
  movb   $0x25,0x0(%rbp)
  movzbl (%rbx),%edi
  sar    $0x4,%dil
  movsbl %dil,%edi
  call   <to_hex@plt>
  mov    %al,0x1(%rbp)
  movzbl (%rbx),%edi
  and    $0xf,%edi
  call   <to_hex@plt>
  mov    %al,0x2(%rbp)
  lea    0x3(%rbp),%rbp
  jmp    L21
L71:
  mov    %rax,%rbp
L53:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *url_encode(char *str) {
  char *pstr = str, *buf = malloc(strlen(str) * 3 + 1), *pbuf = buf;
  while (*pstr) {
    if (isalnum(*pstr) || *pstr == '-' || *pstr == '_' || *pstr == '.' || *pstr == '~')
      *pbuf++ = *pstr;
    else if (*pstr == ' ')
      *pbuf++ = '+';
    else
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex((char)(*pstr & 15));
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<url_encode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,2),%edi
  call   <malloc@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %dil,%dil
  je     L71
  nopw   0x0(%rax,%rax,1)
L45:
  call   <isalnum@plt>
  test   %rax,%rax
  movzbl (%rbx),%eax
  jne    L73
  cmp    $0x5f,%al
  sete   %dl
  cmp    $0x7e,%al
  sete   %cl
  or     %cl,%dl
  jne    L73
  lea    -0x2d(%rax),%edx
  cmp    $0x1,%dl
  ja     L20
L73:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
L40:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L45
L71:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x20,%al
  jne    L70
  movb   $0x2b,0x0(%rbp)
  add    $0x1,%rbp
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L70:
  movb   $0x25,0x0(%rbp)
  movzbl (%rbx),%edi
  add    $0x3,%rbp
  sar    $0x4,%dil
  movsbl %dil,%edi
  call   <to_hex@plt>
  mov    %al,-0x2(%rbp)
  movzbl (%rbx),%edi
  and    $0xf,%edi
  call   <to_hex@plt>
  mov    %al,-0x1(%rbp)
  jmp    L40
```

assistant: ```c
char *url_encode(char *str) {
  char *pstr = str, *buf = malloc(strlen(str) * 3 + 1), *pbuf = buf;
  while (*pstr) {
    if (isalnum(*pstr) || *pstr == '-' || *pstr == '_' || *pstr == '.' || *pstr == '~')
      *pbuf++ = *pstr;
    else if (*pstr == ' ')
      *pbuf++ = '+';
    else
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex((char)(*pstr & 15));
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<url_encode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,2),%edi
  call   <malloc@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %dil,%dil
  je     L60
  nopw   0x0(%rax,%rax,1)
L70:
  call   <isalnum@plt>
  test   %rax,%rax
  movzbl (%rbx),%eax
  jne    L61
  cmp    $0x5f,%al
  sete   %dl
  cmp    $0x7e,%al
  sete   %cl
  or     %cl,%dl
  jne    L61
  lea    -0x2d(%rax),%edx
  cmp    $0x1,%dl
  ja     L30
L61:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
L58:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L70
L60:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  cmp    $0x20,%al
  jne    L51
  movb   $0x2b,0x0(%rbp)
  add    $0x1,%rbp
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L51:
  movb   $0x25,0x0(%rbp)
  movzbl (%rbx),%edi
  add    $0x3,%rbp
  sar    $0x4,%dil
  movsbl %dil,%edi
  call   <to_hex@plt>
  mov    %al,-0x2(%rbp)
  movzbl (%rbx),%edi
  and    $0xf,%edi
  call   <to_hex@plt>
  mov    %al,-0x1(%rbp)
  jmp    L58
```

assistant: ```c
char *url_encode(char *str) {
  char *pstr = str, *buf = malloc(strlen(str) * 3 + 1), *pbuf = buf;
  while (*pstr) {
    if (isalnum(*pstr) || *pstr == '-' || *pstr == '_' || *pstr == '.' || *pstr == '~')
      *pbuf++ = *pstr;
    else if (*pstr == ' ')
      *pbuf++ = '+';
    else
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex((char)(*pstr & 15));
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<atohex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L57
L1:
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L1
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L45
L147:
  shll   $0x4,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x2f,-0xd(%rbp)
  jle    L33
  cmpb   $0x39,-0xd(%rbp)
  jg     L33
  movsbl -0xd(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,-0xc(%rbp)
  jmp    L148
L33:
  cmpb   $0x60,-0xd(%rbp)
  jle    L108
  cmpb   $0x66,-0xd(%rbp)
  jg     L108
  movsbl -0xd(%rbp),%eax
  sub    $0x57,%eax
  add    %eax,-0xc(%rbp)
  jmp    L148
L108:
  cmpb   $0x40,-0xd(%rbp)
  jle    L94
  cmpb   $0x46,-0xd(%rbp)
  jg     L94
  movsbl -0xd(%rbp),%eax
  sub    $0x37,%eax
  add    %eax,-0xc(%rbp)
  jmp    L148
L94:
  mov    $0xffffffff,%eax
  jmp    L46
L148:
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L61
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    $0x7,%eax
  jle    L147
L61:
  mov    -0xc(%rbp),%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int atohex(char *str) {
  int val, i, mi;
  char c;
  val = i = 0;
  while (str[i] <= ' ')
    i++;
  mi = i;
  while (str[i] > ' ' && (i - mi) < 8) {
    val <<= 4;
    c = str[i];
    if (c >= '0' && c <= '9') {
      val += c - '0';
    } else if (c >= 'a' && c <= 'f') {
      val += c - 'a' + 10;
    } else if (c >= 'A' && c <= 'F') {
      val += c - 'A' + 10;
    } else {
      return -1;
    }
    i++;
  }
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atohex>:
  endbr64
  cmpb   $0x20,(%rdi)
  jg     L12
  mov    $0x1,%eax
L78:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x20,-0x1(%rdi,%rax,1)
  jle    L78
L50:
  movslq %edx,%rax
  lea    (%rdi,%rax,1),%rcx
  movzbl (%rcx),%edx
  lea    0x8(%rdi,%rax,1),%r8
  mov    $0x0,%eax
  jmp    L69
L72:
  lea    -0x61(%rdx),%esi
  cmp    $0x5,%sil
  ja     L40
  movsbl %dl,%edx
  lea    -0x57(%rax,%rdx,1),%eax
L58:
  movzbl 0x1(%rcx),%edx
  cmp    $0x20,%dl
  jle    L28
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L62
L69:
  shl    $0x4,%eax
  mov    %edx,%edi
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  ja     L72
  movsbl %dl,%edx
  lea    -0x30(%rax,%rdx,1),%eax
  jmp    L58
L40:
  sub    $0x41,%edi
  cmp    $0x5,%dil
  ja     L10
  movsbl %dl,%edx
  lea    -0x37(%rax,%rdx,1),%eax
  jmp    L58
L62:
  ret
L10:
  mov    $0xffffffff,%eax
  ret
L12:
  mov    $0x0,%edx
  jmp    L50
L28:
  ret
```

assistant: ```c
int atohex(char *str) {
  int val, i, mi;
  char c;
  val = i = 0;
  while (str[i] <= ' ')
    i++;
  mi = i;
  while (str[i] > ' ' && (i - mi) < 8) {
    val <<= 4;
    c = str[i];
    if (c >= '0' && c <= '9') {
      val += c - '0';
    } else if (c >= 'a' && c <= 'f') {
      val += c - 'a' + 10;
    } else if (c >= 'A' && c <= 'F') {
      val += c - 'A' + 10;
    } else {
      return -1;
    }
    i++;
  }
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atohex>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jg     L62
  mov    $0x1,%eax
  nopl   (%rax)
L45:
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  jle    L45
L0:
  movslq %ecx,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    0x8(%rdi,%rax,1),%rdi
  xor    %eax,%eax
  jmp    L91
  nopl   0x0(%rax,%rax,1)
L28:
  movsbl %sil,%esi
  add    %esi,%eax
L57:
  movzbl 0x1(%rcx),%edx
  cmp    $0x20,%dl
  jle    L52
L41:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  je     L31
L91:
  lea    -0x30(%rdx),%esi
  shl    $0x4,%eax
  cmp    $0x9,%sil
  jbe    L28
  lea    -0x61(%rdx),%esi
  cmp    $0x5,%sil
  ja     L76
  sub    $0x57,%edx
  movsbl %dl,%edx
  add    %edx,%eax
  movzbl 0x1(%rcx),%edx
  cmp    $0x20,%dl
  jg     L41
L52:
  ret
  nop
L76:
  lea    -0x41(%rdx),%esi
  cmp    $0x5,%sil
  ja     L53
  sub    $0x37,%edx
  movsbl %dl,%edx
  add    %edx,%eax
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L31:
  ret
  nopl   0x0(%rax)
L62:
  xor    %ecx,%ecx
  jmp    L0
L53:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int atohex(char *str) {
  int val, i, mi;
  char c;
  val = i = 0;
  while (str[i] <= ' ')
    i++;
  mi = i;
  while (str[i] > ' ' && (i - mi) < 8) {
    val <<= 4;
    c = str[i];
    if (c >= '0' && c <= '9') {
      val += c - '0';
    } else if (c >= 'a' && c <= 'f') {
      val += c - 'a' + 10;
    } else if (c >= 'A' && c <= 'F') {
      val += c - 'A' + 10;
    } else {
      return -1;
    }
    i++;
  }
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_C_identifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x22,-0xc(%rbp)
  jne    L194
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L188
  cmpl   $0x5f,-0xc(%rbp)
  je     L188
  cmpl   $0x24,-0xc(%rbp)
  je     L188
  mov    $0x0,%eax
  jmp    L128
L92:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L188
  cmpl   $0x5f,-0xc(%rbp)
  je     L188
  cmpl   $0x24,-0xc(%rbp)
  je     L188
  mov    $0x0,%eax
  jmp    L128
L188:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x22,-0xc(%rbp)
  jne    L92
  mov    $0x1,%eax
  jmp    L128
L194:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L111
  cmpl   $0x5f,-0xc(%rbp)
  je     L111
  cmpl   $0x24,-0xc(%rbp)
  je     L111
  mov    $0x0,%eax
  jmp    L128
L77:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L111
  cmpl   $0x5f,-0xc(%rbp)
  je     L111
  cmpl   $0x24,-0xc(%rbp)
  je     L111
  mov    $0x0,%eax
  jmp    L128
L111:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L77
  mov    $0x1,%eax
L128:
  leave
  ret
```

assistant: ```c
int is_C_identifier(char *name) {
  char *s;
  int c;
  s = name;
  c = *s;
  if (c == '"') {
    c = *++s;
    if (!isalpha(c) && c != '_' && c != '$')
      return (0);
    while ((c = *++s) != '"') {
      if (!isalnum(c) && c != '_' && c != '$')
        return (0);
    }
    return (1);
  }
  if (!isalpha(c) && c != '_' && c != '$')
    return (0);
  while ((c = *++s) != 0) {
    if (!isalnum(c) && c != '_' && c != '$')
      return (0);
  }
  return (1);
}
```