ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<simple_mmul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r14
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r15
  mov    0x60(%rsp),%r13d
  mov    %edi,-0x10(%rsp)
  mov    %rcx,-0x8(%rsp)
  mov    %r8d,-0xc(%rsp)
  test   %edi,%edi
  jle    L11
  movslq %r9d,%r8
  movl   $0x0,-0x14(%rsp)
  mov    %esi,%ebp
  mov    %edx,%edi
  movslq 0x40(%rsp),%r9
  movl   $0x0,-0x18(%rsp)
  shl    $0x3,%r8
  movl   $0x0,-0x1c(%rsp)
  shl    $0x3,%r9
  nopl   0x0(%rax)
L30:
  test   %ebp,%ebp
  jle    L46
  mov    -0x8(%rsp),%rbx
  movslq -0x14(%rsp),%rax
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  lea    (%rbx,%rax,8),%rax
  mov    -0x18(%rsp),%ebx
  mov    %rax,-0x28(%rsp)
  nopl   0x0(%rax)
L6:
  test   %edi,%edi
  jle    L42
  movslq %ebx,%rax
  mov    -0x28(%rsp),%rdx
  lea    (%r15,%rax,8),%rsi
  movslq %r11d,%rax
  movsd  (%rsi),%xmm1
  lea    (%r14,%rax,8),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L1:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x1,%eax
  add    %r8,%rdx
  add    %r9,%rcx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %eax,%edi
  jne    L1
L42:
  add    $0x1,%r10d
  add    %r12d,%r11d
  add    %r13d,%ebx
  cmp    %r10d,%ebp
  jne    L6
L46:
  mov    0x58(%rsp),%esi
  addl   $0x1,-0x1c(%rsp)
  add    %esi,-0x18(%rsp)
  mov    -0x1c(%rsp),%eax
  mov    -0xc(%rsp),%esi
  add    %esi,-0x14(%rsp)
  cmp    %eax,-0x10(%rsp)
  jne    L30
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void simple_mmul(int m, int n, int k, double *a, int a_row_stride, int a_col_stride, double *b, int b_row_stride, int b_col_stride, double *c, int c_row_stride, int c_col_stride) {
  int i, j, p;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      for (p = 0; p < k; p++) {
        c[(i)*c_row_stride + (j)*c_col_stride] += a[(i)*a_row_stride + (p)*a_col_stride] * b[(p)*b_row_stride + (j)*b_col_stride];
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simple_mmul>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  movslq 0x48(%rsp),%rcx
  movslq 0x60(%rsp),%rsi
  mov    %edi,-0x10(%rsp)
  movslq 0x40(%rsp),%rdi
  test   %r15d,%r15d
  jle    L51
  test   %ebx,%ebx
  jle    L51
  movslq %edx,%rax
  test   %eax,%eax
  jle    L51
  mov    %r8d,%r14d
  movslq %r9d,%rdx
  cmp    $0x1,%edi
  jne    L45
  cmp    $0x1,%edx
  jne    L45
  mov    0x58(%rsp),%r15d
  xor    %ebp,%ebp
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  lea    0x0(,%rsi,8),%r9
  lea    0x0(,%rcx,8),%r8
L54:
  mov    0x50(%rsp),%rdi
  movslq %r11d,%rdx
  mov    0x38(%rsp),%rsi
  xor    %r12d,%r12d
  lea    (%rdi,%rdx,8),%rcx
  movslq %ebp,%rdx
  lea    0x0(%r13,%rdx,8),%rdi
  cs nopw 0x0(%rax,%rax,1)
L99:
  movsd  (%rcx),%xmm1
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L49:
  movsd  (%rsi,%rdx,8),%xmm0
  mulsd  (%rdi,%rdx,8),%xmm0
  add    $0x1,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rdx
  jne    L49
  add    $0x1,%r12d
  add    %r9,%rcx
  add    %r8,%rsi
  cmp    %r12d,%ebx
  jne    L99
  add    $0x1,%r10d
  add    %r15d,%r11d
  add    %r14d,%ebp
  cmp    %r10d,-0x10(%rsp)
  jne    L54
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  movl   $0x0,-0x4(%rsp)
  lea    0x0(,%rsi,8),%r11
  lea    0x0(,%rcx,8),%r10
  movl   $0x0,-0x8(%rsp)
  lea    0x0(,%rdx,8),%r8
  lea    0x0(,%rdi,8),%r9
  movl   $0x0,-0xc(%rsp)
L65:
  movslq -0x8(%rsp),%rdx
  mov    0x50(%rsp),%rdi
  xor    %ebp,%ebp
  mov    0x38(%rsp),%r12
  lea    (%rdi,%rdx,8),%rdi
  movslq -0x4(%rsp),%rdx
  lea    0x0(%r13,%rdx,8),%r15
  nopl   (%rax)
L77:
  movsd  (%rdi),%xmm1
  mov    %r12,%rsi
  mov    %r15,%rcx
  xor    %edx,%edx
  nopl   0x0(%rax)
L2:
  movsd  (%rcx),%xmm0
  mulsd  (%rsi),%xmm0
  add    $0x1,%edx
  add    %r8,%rcx
  add    %r9,%rsi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  cmp    %edx,%eax
  jne    L2
  add    $0x1,%ebp
  add    %r11,%rdi
  add    %r10,%r12
  cmp    %ebp,%ebx
  jne    L77
  addl   $0x1,-0xc(%rsp)
  mov    0x58(%rsp),%ecx
  add    %r14d,-0x4(%rsp)
  mov    -0xc(%rsp),%edi
  add    %ecx,-0x8(%rsp)
  cmp    %edi,-0x10(%rsp)
  jne    L65
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void simple_mmul(int m, int n, int k, double *a, int a_row_stride, int a_col_stride, double *b, int b_row_stride, int b_col_stride, double *c, int c_row_stride, int c_col_stride) {
  int i, j, p;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      for (p = 0; p < k; p++) {
        c[(i)*c_row_stride + (j)*c_col_stride] += a[(i)*a_row_stride + (p)*a_col_stride] * b[(p)*b_row_stride + (j)*b_col_stride];
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_hotplug2_event_action>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  jmp    L31
L4:
  mov    -0x8(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L28
  mov    $0x1,%eax
  jmp    L31
L28:
  mov    $0xffffffff,%eax
L31:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string

tool: D7: add

tool: D11: remove

assistant: ```c
int get_hotplug2_event_action(char *action) {
  if (!strcmp(action, "add"))
    return 0;
  if (!strcmp(action, "remove"))
    return 1;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_hotplug2_event_action>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L3
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L3:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D5
type: string

tool: D3: add

tool: D5: remove

assistant: ```c
int get_hotplug2_event_action(char *action) {
  if (!strcmp(action, "add"))
    return 0;
  if (!strcmp(action, "remove"))
    return 1;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_hotplug2_event_action>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L5
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L5:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string

tool: D1: add

tool: D17: remove

assistant: ```c
int get_hotplug2_event_action(char *action) {
  if (!strcmp(action, "add"))
    return 0;
  if (!strcmp(action, "remove"))
    return 1;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_hotplug2_event_action>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L2
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L2:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string
name: disassemble_data
arguments: label: D11
type: string

tool: D8: add

tool: D11: remove

assistant: ```c
int get_hotplug2_event_action(char *action) {
  if (!strcmp(action, "add"))
    return 0;
  if (!strcmp(action, "remove"))
    return 1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<label_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L35
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L13
  mov    $0xffffffff,%eax
  jmp    L22
L13:
  mov    $0x0,%eax
  jmp    L22
L35:
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int label_cmp(const void *a, const void *b) {
  uint32_t aa = *((const uint32_t *)a);
  uint32_t bb = *((const uint32_t *)b);
  return (aa < bb) ? 1 : (aa > bb) ? -1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<label_cmp>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jl     L4
  setg   %al
  movzbl %al,%eax
  neg    %eax
L4:
  ret
```

assistant: ```c
int label_cmp(const void *a, const void *b) {
  uint32_t aa = *((const uint32_t *)a);
  uint32_t bb = *((const uint32_t *)b);
  return (aa < bb) ? 1 : (aa > bb) ? -1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<label_cmp>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jl     L8
  setg   %al
  movzbl %al,%eax
  neg    %eax
L8:
  ret
```

assistant: ```c
int label_cmp(const void *a, const void *b) {
  uint32_t aa = *((const uint32_t *)a);
  uint32_t bb = *((const uint32_t *)b);
  return (aa < bb) ? 1 : (aa > bb) ? -1 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<label_cmp>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jl     L6
  setg   %al
  movzbl %al,%eax
  neg    %eax
L6:
  ret
```

assistant: ```c
int label_cmp(const void *a, const void *b) {
  uint32_t aa = *((const uint32_t *)a);
  uint32_t bb = *((const uint32_t *)b);
  return (aa < bb) ? 1 : (aa > bb) ? -1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ansiescape_graphics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ansiescape_vgraphics@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void ansiescape_graphics(char *buffer, const char *sequence, ...) {
  *buffer = 0;
  va_list args;
  va_start(args, sequence);
  ansiescape_vgraphics(buffer, sequence, args);
  va_end(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ansiescape_graphics>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movb   $0x0,(%rdi)
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <ansiescape_vgraphics@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ansiescape_graphics(char *buffer, const char *sequence, ...) {
  *buffer = 0;
  va_list args;
  va_start(args, sequence);
  ansiescape_vgraphics(buffer, sequence, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ansiescape_graphics>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  movb   $0x0,(%rdi)
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <ansiescape_vgraphics@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ansiescape_graphics(char *buffer, const char *sequence, ...) {
  *buffer = 0;
  va_list args;
  va_start(args, sequence);
  ansiescape_vgraphics(buffer, sequence, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fgetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L28
  mov    $0xffffffff,%eax
  jmp    L37
L28:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,D44(%rip)
  mov    D44(%rip),%rax
  test   %rax,%rax
  jne    L34
  mov    $0xffffffff,%eax
  jmp    L37
L34:
  mov    D44(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,D51(%rip)
  mov    D51(%rip),%rdx
  mov    D44(%rip),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <chop@plt>
  mov    %rax,D1(%rip)
  mov    D1(%rip),%rax
L37:
  leave
  ret
```

assistant: ```c
int fgetline(FILE *fh_in, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(fh_in))
    return -1;
  buffptr = fgets(buffer, size, fh_in);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgetline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L34
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <chop@plt>
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L27
L5:
  mov    $0xffffffff,%eax
  jmp    L27
```

assistant: ```c
int fgetline(FILE *fh_in, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(fh_in))
    return -1;
  buffptr = fgets(buffer, size, fh_in);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fgetline>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <chop@plt>
L12:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int fgetline(FILE *fh_in, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(fh_in))
    return -1;
  buffptr = fgets(buffer, size, fh_in);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgetline>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <chop@plt>
L9:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int fgetline(FILE *fh_in, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(fh_in))
    return -1;
  buffptr = fgets(buffer, size, fh_in);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x2e,-0x1(%rbp)
  jmp    L5
L1:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <now@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <mill_sleep@plt>
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((no)) void dot(int *done) {
  char c = '.';
  while (!*done) {
    printf("%c", c);
    mill_sleep(now() + 1);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dot>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpl   $0x0,(%rdi)
  jne    L7
L2:
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <now@plt>
  lea    0x1(%rax),%rdi
  call   <mill_sleep@plt>
  cmpl   $0x0,(%rbx)
  je     L2
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((no)) void dot(int *done) {
  char c = '.';
  while (!*done) {
    printf("%c", c);
    mill_sleep(now() + 1);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dot>:
  endbr64
  mov    (%rdi),%edx
  test   %edx,%edx
  jne    L15
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    $0x2e,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <now@plt>
  lea    0x1(%rax),%rdi
  call   <mill_sleep@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L3
  mov    $0xa,%edi
  pop    %rbx
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xa,%edi
  jmp    1070 <putchar@plt>
```

assistant: ```c
__attribute__((no)) void dot(int *done) {
  char c = '.';
  while (!*done) {
    printf("%c", c);
    mill_sleep(now() + 1);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dot>:
  endbr64
  mov    (%rdi),%edx
  test   %edx,%edx
  jne    L10
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L13:
  mov    $0x2e,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <now@plt>
  lea    0x1(%rax),%rdi
  call   <mill_sleep@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L13
  mov    $0xa,%edi
  pop    %rbx
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xa,%edi
  jmp    1070 <putchar@plt>
```

assistant: ```c
__attribute__((no)) void dot(int *done) {
  char c = '.';
  while (!*done) {
    printf("%c", c);
    mill_sleep(now() + 1);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<di_irq_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <DI_Set_Irq_Enable@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int di_irq_enable(unsigned int enable) {
  DI_Set_Irq_Enable(enable);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<di_irq_enable>:
  endbr64
  sub    $0x8,%rsp
  call   <DI_Set_Irq_Enable@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int di_irq_enable(unsigned int enable) {
  DI_Set_Irq_Enable(enable);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<di_irq_enable>:
  endbr64
  sub    $0x8,%rsp
  call   <DI_Set_Irq_Enable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int di_irq_enable(unsigned int enable) {
  DI_Set_Irq_Enable(enable);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<di_irq_enable>:
  endbr64
  sub    $0x8,%rsp
  call   <DI_Set_Irq_Enable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int di_irq_enable(unsigned int enable) {
  DI_Set_Irq_Enable(enable);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bit_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L29:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L21
  addl   $0x1,-0x4(%rbp)
L21:
  sarl   -0x14(%rbp)
  shrl   -0x8(%rbp)
L24:
  cmpl   $0x0,-0x8(%rbp)
  jne    L29
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bit_count(int flag) {
  unsigned int i = ~0;
  int c = 0;
  while (i) {
    if (flag & ((unsigned int)0x01 << (0)))
      c++;
    flag = flag >> 1;
    i = i >> 1;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bit_count>:
  endbr64
  mov    $0x20,%eax
  mov    $0x0,%edx
L3:
  mov    %edi,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  sbb    $0xffffffff,%edx
  sar    %edi
  sub    $0x1,%eax
  jne    L3
  mov    %edx,%eax
  ret
```

assistant: ```c
int bit_count(int flag) {
  unsigned int i = ~0;
  int c = 0;
  while (i) {
    if (flag & ((unsigned int)0x01 << (0)))
      c++;
    flag = flag >> 1;
    i = i >> 1;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bit_count>:
  endbr64
  mov    $0x20,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L0:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r8d
  sar    %edi
  sub    $0x1,%eax
  jne    L0
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bit_count(int flag) {
  unsigned int i = ~0;
  int c = 0;
  while (i) {
    if (flag & ((unsigned int)0x01 << (0)))
      c++;
    flag = flag >> 1;
    i = i >> 1;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bit_count>:
  endbr64
  mov    $0x20,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r8d
  sar    %edi
  sub    $0x1,%eax
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bit_count(int flag) {
  unsigned int i = ~0;
  int c = 0;
  while (i) {
    if (flag & ((unsigned int)0x01 << (0)))
      c++;
    flag = flag >> 1;
    i = i >> 1;
  }
  return c;
}
```