ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fwrite_dmatrix>:
  endbr64
  push   %r15
  sub    %rcx,%r8
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %r9,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    0x1(%r8),%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L4
L26:
  cmp    %r12,%rbx
  jg     L22
  lea    0x0(,%rbx,8),%r14
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %r15,%rcx
  mov    %rbp,%rdx
  mov    $0x8,%esi
  add    $0x1,%rbx
  add    %r14,%rdi
  call   <fwrite@plt>
  cmp    %rbx,%r12
  jge    L7
L22:
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <fclose@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D4(%rip),%rdi
  call   <nrerror@plt>
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D0: wb

tool: D4: Can't open file in fwrite_dmatrix

assistant: ```c
void fwrite_dmatrix(double **m, long nrl, long nrh, long ncl, long nch, char *filename) {
  long i, ncol = nch - ncl + 1;
  FILE *f;
  f = fopen(filename, "wb");
  if (f == NULL)
    nrerror("Can't open file in fwrite_dmatrix");
  for (i = nrl; i <= nrh; i++) {
    fwrite(m[i] + nrl, sizeof(double), ncol, f);
  }
  fclose(f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<codeeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  movb   $0x0,-0x11(%rbp)
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movzbl (%rax),%ebx
  cmp    $0x5c,%bl
  je     L39
  mov    %ebx,%eax
  jmp    L46
L37:
  movsbl -0x11(%rbp),%eax
  shl    $0x3,%eax
  mov    %al,-0x11(%rbp)
  movsbl %bl,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <ctov@plt>
  mov    %eax,%edx
  movzbl -0x11(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x11(%rbp)
L39:
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movzbl (%rax),%ebx
  movsbl %bl,%eax
  and    $0xffffff80,%eax
  test   %eax,%eax
  jne    L29
  movsbl %bl,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L29
  cmp    $0x37,%bl
  jg     L29
  mov    $0x1,%eax
  jmp    L79
L29:
  mov    $0x0,%eax
L79:
  test   %eax,%eax
  jne    L37
  cmp    $0x3b,%bl
  je     L3
  mov    $0xc,%edi
  mov    $0x0,%eax
  call   <BUGreport@plt>
L3:
  movzbl -0x11(%rbp),%eax
L46:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char codeeval(sptr)
register char **sptr;
{
  register char c;
  char code = 0;
  if ((c = *(*sptr)++) != '\\')
    return (c);
  while (c = *(*sptr)++, (isascii(c) && (isdigit(c) && (c) < '8'))) {
    code <<= 3;
    code += ctov(c);
  }
  if (c != ';')
    BUGreport(12);
  return (code);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<codeeval>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%ebp
  cmp    $0x5c,%bpl
  jne    L22
  mov    %rdi,%rbx
  lea    0x2(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rax),%eax
  movsbl %al,%edi
  test   %al,%al
  js     L63
  mov    $0x0,%ebp
L47:
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L34
  mov    $0x0,%eax
  call   <ctov@plt>
  lea    (%rax,%rbp,8),%ebp
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movzbl (%rax),%eax
  movsbl %al,%edi
  test   %al,%al
  jns    L47
L34:
  cmp    $0x3b,%al
  jne    L13
L22:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L63:
  mov    $0x0,%ebp
  jmp    L34
L13:
  mov    $0xc,%edi
  mov    $0x0,%eax
  call   <BUGreport@plt>
  jmp    L22
```

assistant: ```c
char codeeval(sptr)
register char **sptr;
{
  register char c;
  char code = 0;
  if ((c = *(*sptr)++) != '\\')
    return (c);
  while (c = *(*sptr)++, (isascii(c) && (isdigit(c) && (c) < '8'))) {
    code <<= 3;
    code += ctov(c);
  }
  if (c != ';')
    BUGreport(12);
  return (code);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<codeeval>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%r12d
  cmp    $0x5c,%r12b
  jne    L46
  lea    0x2(%rax),%rdx
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  mov    %rdx,(%rdi)
  movsbl 0x1(%rax),%edi
  mov    %edi,%eax
  test   %dil,%dil
  jns    L44
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0xc,%edi
  xor    %eax,%eax
  call   <BUGreport@plt>
L46:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <ctov@plt>
  lea    (%rax,%r12,8),%r12d
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rax),%edi
  mov    %edi,%eax
  test   %dil,%dil
  js     L15
L44:
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  jbe    L11
  cmp    $0x3b,%al
  jne    L15
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char codeeval(sptr)
register char **sptr;
{
  register char c;
  char code = 0;
  if ((c = *(*sptr)++) != '\\')
    return (c);
  while (c = *(*sptr)++, (isascii(c) && (isdigit(c) && (c) < '8'))) {
    code <<= 3;
    code += ctov(c);
  }
  if (c != ';')
    BUGreport(12);
  return (code);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<codeeval>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%r12d
  cmp    $0x5c,%r12b
  jne    L11
  lea    0x2(%rax),%rdx
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  mov    %rdx,(%rdi)
  movsbl 0x1(%rax),%edi
  mov    %edi,%eax
  test   %dil,%dil
  jns    L0
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0xc,%edi
  xor    %eax,%eax
  call   <BUGreport@plt>
L11:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  call   <ctov@plt>
  lea    (%rax,%r12,8),%r12d
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rax),%edi
  mov    %edi,%eax
  test   %dil,%dil
  js     L20
L0:
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  jbe    L22
  cmp    $0x3b,%al
  jne    L20
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char codeeval(sptr)
register char **sptr;
{
  register char c;
  char code = 0;
  if ((c = *(*sptr)++) != '\\')
    return (c);
  while (c = *(*sptr)++, (isascii(c) && (isdigit(c) && (c) < '8'))) {
    code <<= 3;
    code += ctov(c);
  }
  if (c != ';')
    BUGreport(12);
  return (code);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<proc_ls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %esi,%r14d
  lea    D2(%rip),%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L49
  mov    %rax,%rbx
  mov    %rsp,%r12
  lea    D3(%rip),%r13
L45:
  mov    %rbx,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L42
  mov    (%rax),%rsi
  test   %r14d,%r14d
  je     L45
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L45
L42:
  mov    %rbx,%rdi
  call   <closedir@plt>
  mov    %r12,%rsp
  mov    $0x0,%eax
L30:
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L49:
  lea    D26(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L30
```

tool_calls: name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D26
type: string

tool: D2: /proc

tool: D3: Received %s
.

tool: D26: Unable to open '/proc' directory.

assistant: ```c
int proc_ls(char **accept, bool verbose) {
  DIR *dir = opendir("/proc");
  struct dirent *ent;
  if (dir != NULL) {
    int ls_buf_len = 256;
    char *ls[ls_buf_len];
    int ls_i = 0;
    while ((ent = readdir(dir)) != NULL) {
      if (ls_i < ls_buf_len) {
        ls[ls_i] = (ent->d_name);
        if (verbose) {
          printf("Received %s\n.", ent->d_name);
        }
      }
    }
    closedir(dir);
    accept = ls;
    return 0;
  } else {
    perror("Unable to open '/proc' directory.");
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<proc_ls>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L60
  mov    %rsp,%r13
  mov    %rax,%r15
  cmp    %r13,%rsp
  je     L85
L19:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r13,%rsp
  jne    L19
L85:
  sub    $0x800,%rsp
  orq    $0x0,0x7f8(%rsp)
  lea    D10(%rip),%r14
  mov    %rsp,%r12
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L76:
  mov    (%rax),%rsi
  mov    %rsi,(%r12)
  test   %ebx,%ebx
  jne    L9
L67:
  mov    %r15,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L76
  mov    %r15,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
  mov    %r13,%rsp
L14:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L67
L60:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L14
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D24
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D24: /proc

tool: D10: Received %s
.

tool: D9: Unable to open '/proc' directory.

assistant: ```c
int proc_ls(char **accept, bool verbose) {
  DIR *dir = opendir("/proc");
  struct dirent *ent;
  if (dir != NULL) {
    int ls_buf_len = 256;
    char *ls[ls_buf_len];
    int ls_i = 0;
    while ((ent = readdir(dir)) != NULL) {
      if (ls_i < ls_buf_len) {
        ls[ls_i] = (ent->d_name);
        if (verbose) {
          printf("Received %s\n.", ent->d_name);
        }
      }
    }
    closedir(dir);
    accept = ls;
    return 0;
  } else {
    perror("Unable to open '/proc' directory.");
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<proc_ls>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L58
  mov    %rsp,%r13
  mov    %rax,%r12
  cmp    %r13,%rsp
  je     L38
L25:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r13,%rsp
  jne    L25
L38:
  sub    $0x800,%rsp
  orq    $0x0,0x7f8(%rsp)
  lea    D6(%rip),%r14
  mov    %rsp,%r15
L29:
  test   %ebx,%ebx
  jne    L55
  nopl   0x0(%rax)
L16:
  mov    %r12,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L16
L41:
  mov    %r12,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
  mov    %r13,%rsp
L62:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L55:
  mov    %r12,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L41
  mov    (%rax),%rsi
  mov    %r14,%rdi
  mov    %rsi,(%r15)
  call   <printf@plt>
  jmp    L29
L58:
  lea    D12(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L62
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D21: /proc

tool: D6: Received %s
.

tool: D12: Unable to open '/proc' directory.

assistant: ```c
int proc_ls(char **accept, bool verbose) {
  DIR *dir = opendir("/proc");
  struct dirent *ent;
  if (dir != NULL) {
    int ls_buf_len = 256;
    char *ls[ls_buf_len];
    int ls_i = 0;
    while ((ent = readdir(dir)) != NULL) {
      if (ls_i < ls_buf_len) {
        ls[ls_i] = (ent->d_name);
        if (verbose) {
          printf("Received %s\n.", ent->d_name);
        }
      }
    }
    closedir(dir);
    accept = ls;
    return 0;
  } else {
    perror("Unable to open '/proc' directory.");
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_perm_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  jmp    L105
L44:
  mov    -0x74(%rbp),%eax
  cltq
  movl   $0x0,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x74(%rbp)
L105:
  mov    -0x74(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L44
  movl   $0x0,-0x74(%rbp)
  jmp    L0
L15:
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L74
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x84(%rbp)
  jg     L29
L74:
  mov    $0x1,%eax
  jmp    L20
L29:
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x74(%rbp)
L0:
  mov    -0x74(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L15
  movl   $0x0,-0x74(%rbp)
  jmp    L71
L91:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  je     L63
  mov    $0x1,%eax
  jmp    L20
L63:
  addl   $0x1,-0x74(%rbp)
L71:
  mov    -0x74(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L91
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int check_perm_n(nn, array_in)
int nn, array_in[];
{
  int count[24], ii;
  for (ii = 0; ii < nn; ii++)
    count[ii] = 0;
  for (ii = 0; ii < nn; ii++) {
    if (array_in[ii] < 0 || array_in[ii] >= nn)
      return 1;
    count[array_in[ii]]++;
  }
  for (ii = 0; ii < nn; ii++)
    if (count[ii] != 1)
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_perm_n>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L67
  mov    %rsp,%rcx
  lea    -0x1(%rdi),%r9d
  shl    $0x2,%r9
  lea    0x4(%rsp,%r9,1),%r8
  mov    %rcx,%rax
L69:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L69
  mov    %rsi,%rdx
  lea    0x4(%rsi,%r9,1),%rsi
L41:
  mov    (%rdx),%eax
  cmp    %edi,%eax
  jge    L78
  test   %eax,%eax
  js     L78
  cltq
  addl   $0x1,(%rsp,%rax,4)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L41
L30:
  cmpl   $0x1,(%rcx)
  jne    L106
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L30
  mov    $0x0,%eax
  jmp    L56
L67:
  mov    $0x0,%eax
  jmp    L56
L78:
  mov    $0x1,%eax
L56:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L90
  add    $0x78,%rsp
  ret
L106:
  mov    $0x1,%eax
  jmp    L56
L90:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_perm_n(nn, array_in)
int nn, array_in[];
{
  int count[24], ii;
  for (ii = 0; ii < nn; ii++)
    count[ii] = 0;
  for (ii = 0; ii < nn; ii++) {
    if (array_in[ii] < 0 || array_in[ii] >= nn)
      return 1;
    count[array_in[ii]]++;
  }
  for (ii = 0; ii < nn; ii++)
    if (count[ii] != 1)
      return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_perm_n>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L9
  mov    %rsp,%rcx
  mov    %edi,%edx
  mov    %rsi,%rbx
  mov    %edi,%ebp
  shl    $0x2,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  lea    -0x1(%rbp),%edi
  mov    %rbx,%rsi
  shl    $0x2,%rdi
  mov    %rax,%rcx
  lea    0x4(%rbx,%rdi,1),%rdx
  jmp    L104
  xchg   %ax,%ax
L43:
  test   %eax,%eax
  js     L101
  add    $0x4,%rsi
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rsi
  je     L69
L104:
  movslq (%rsi),%rax
  cmp    %ebp,%eax
  jl     L43
L101:
  mov    $0x1,%eax
L61:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L69:
  mov    %rcx,%rax
  lea    0x4(%rsp,%rdi,1),%rdx
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L86:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L9
L37:
  cmpl   $0x1,(%rax)
  je     L86
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  jmp    L61
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_perm_n(nn, array_in)
int nn, array_in[];
{
  int count[24], ii;
  for (ii = 0; ii < nn; ii++)
    count[ii] = 0;
  for (ii = 0; ii < nn; ii++) {
    if (array_in[ii] < 0 || array_in[ii] >= nn)
      return 1;
    count[array_in[ii]]++;
  }
  for (ii = 0; ii < nn; ii++)
    if (count[ii] != 1)
      return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_perm_n>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  mov    %rsp,%rcx
  mov    %edi,%edx
  mov    %rsi,%rbx
  mov    %edi,%ebp
  shl    $0x2,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  lea    -0x1(%rbp),%edi
  mov    %rbx,%rsi
  shl    $0x2,%rdi
  mov    %rax,%rcx
  lea    0x4(%rbx,%rdi,1),%rdx
  jmp    L90
  xchg   %ax,%ax
L40:
  test   %eax,%eax
  js     L5
  add    $0x4,%rsi
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rsi
  je     L3
L90:
  movslq (%rsi),%rax
  cmp    %ebp,%eax
  jl     L40
L5:
  mov    $0x1,%eax
L97:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L70
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  mov    %rcx,%rax
  lea    0x4(%rsp,%rdi,1),%rdx
  jmp    L82
  nopw   0x0(%rax,%rax,1)
L60:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L6
L82:
  cmpl   $0x1,(%rax)
  je     L60
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  jmp    L97
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_perm_n(nn, array_in)
int nn, array_in[];
{
  int count[24], ii;
  for (ii = 0; ii < nn; ii++)
    count[ii] = 0;
  for (ii = 0; ii < nn; ii++) {
    if (array_in[ii] < 0 || array_in[ii] >= nn)
      return 1;
    count[array_in[ii]]++;
  }
  for (ii = 0; ii < nn; ii++)
    if (count[ii] != 1)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L0
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: What is the c source code of the assembly code below:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L0
L7:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L7
L0:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L1
L0:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L0
L1:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L1
L15:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L1:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_recput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x9,-0x8(%rbp)
  jbe    L6
  mov    -0x8(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,%rdi
  call   <ft_recput>
L6:
  mov    -0x8(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  lea    0x30(%rdx),%rax
  mov    %rax,%rdi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_recput(unsigned long long n) {
  if (n >= 10)
    ft_recput(n / 10);
  ft_putchar(n % 10 + '0');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_recput>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x9,%rdi
  ja     L17
L11:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  call   <ft_putchar@plt>
  pop    %rbx
  ret
L17:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <ft_recput>
  jmp    L11
```

assistant: ```c
void ft_recput(unsigned long long n) {
  if (n >= 10)
    ft_recput(n / 10);
  ft_putchar(n % 10 + '0');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_recput>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x9,%rdi
  ja     L7
L17:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  nopl   0x0(%rax)
L7:
  movabs $0xcccccccccccccccd,%rcx
  mov    %rdi,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%rbp
  cmp    $0x63,%rdi
  ja     L49
L23:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbp,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbp
  lea    0x30(%rbp),%rdi
  call   <ft_putchar@plt>
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r12
  cmp    $0x3e7,%rdi
  ja     L11
L41:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%rdi
  call   <ft_putchar@plt>
  jmp    L23
L11:
  mov    %rdx,%rax
  mul    %rcx
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <ft_recput>
  jmp    L41
```

assistant: ```c
void ft_recput(unsigned long long n) {
  if (n >= 10)
    ft_recput(n / 10);
  ft_putchar(n % 10 + '0');
}
```