ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rot13>:
  endbr64
  sub    $0xe8,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L13
  mov    $0x1,%edx
  lea    0x6f(%rsp),%r8
  lea    -0x1(%rsp),%rdi
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0xd,%eax
L46:
  mov    %al,(%r8,%rdx,1)
  movslq %edx,%rcx
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L40
L10:
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  lea    -0x41(%rcx),%esi
  cmp    $0xc,%sil
  jbe    L22
  sub    $0x4e,%ecx
  lea    -0xd(%rax),%esi
  cmp    $0xd,%cl
  cmovb  %esi,%eax
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L40:
  lea    0x70(%rsp),%rsi
  lea    D15(%rip),%rdi
  movb   $0x0,0x70(%rsp,%rcx,1)
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0xe8,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D15
type: string

tool: D6: %s

tool: D15: %s


assistant: ```c
void rot13() {
  int i;
  char a;
  char text[100];
  char text1[100];
  scanf("%s", text);
  a = text[1];
  for (i = 0; text[i] != '\0'; i++) {
    if ((text[i] >= 'A' && text[i] <= 'M') || (text[i] >= 'a' && text[i] <= 'm'))
      text1[i] = text[i] + 13;
    else if ((text[i] >= 'N' && text[i] <= 'Z') || (text[i] >= 'n' && text[i] <= 'z'))
      text1[i] = text[i] - 13;
    else
      text1[i] = text[i];
  }
  text1[i] = '\0';
  printf("%s\n", text1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rot13>:
  endbr64
  sub    $0xe8,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L50
  mov    $0x1,%edx
  lea    0x6f(%rsp),%r8
  lea    -0x1(%rsp),%rdi
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L54:
  add    $0xd,%eax
L30:
  mov    %al,(%r8,%rdx,1)
  movslq %edx,%rcx
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L51
L13:
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  lea    -0x41(%rcx),%esi
  cmp    $0xc,%sil
  jbe    L54
  sub    $0x4e,%ecx
  lea    -0xd(%rax),%esi
  cmp    $0xd,%cl
  cmovb  %esi,%eax
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L50:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L51:
  lea    0x70(%rsp),%rsi
  lea    D2(%rip),%rdi
  movb   $0x0,0x70(%rsp,%rcx,1)
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xe8,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D7: %s

tool: D2: %s


assistant: ```c
void rot13() {
  int i;
  char a;
  char text[100];
  char text1[100];
  scanf("%s", text);
  a = text[1];
  for (i = 0; text[i] != '\0'; i++) {
    if ((text[i] >= 'A' && text[i] <= 'M') || (text[i] >= 'a' && text[i] <= 'm'))
      text1[i] = text[i] + 13;
    else if ((text[i] >= 'N' && text[i] <= 'Z') || (text[i] >= 'n' && text[i] <= 'z'))
      text1[i] = text[i] - 13;
    else
      text1[i] = text[i];
  }
  text1[i] = '\0';
  printf("%s\n", text1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<doBreak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x62,%edi
  call   <match@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
L14:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fail@plt>
  jmp    L20
L24:
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <emitln@plt>
  nop
L20:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string
name: read_data
arguments: data_label: D8
data_type: string

tool: D3: No loop to break from

tool: D8: JMP	%s	#BREAK to %s

assistant: ```c
void doBreak(char *exitLabel) {
  match('b');
  if (NULL == exitLabel || 0 == strlen(exitLabel))
    fail("No loop to break from");
  else
    emitln("JMP\t%s\t#BREAK to %s", exitLabel, exitLabel);
}
```
user: What is the c source code of the assembly code below?

```asm
<doBreak>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x62,%edi
  call   <match@plt>
  test   %rbx,%rbx
  je     L15
  cmpb   $0x0,(%rbx)
  jne    L0
L15:
  lea    D9(%rip),%rdi
  call   <fail@plt>
L23:
  pop    %rbx
  ret
L0:
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <emitln@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string

tool: D9: No loop to break from

tool: D17: JMP	%s	#BREAK to %s

assistant: ```c
void doBreak(char *exitLabel) {
  match('b');
  if (NULL == exitLabel || 0 == strlen(exitLabel))
    fail("No loop to break from");
  else
    emitln("JMP\t%s\t#BREAK to %s", exitLabel, exitLabel);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<doBreak>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x62,%edi
  call   <match@plt>
  test   %rbp,%rbp
  je     L14
  cmpb   $0x0,0x0(%rbp)
  jne    L19
L14:
  lea    D19(%rip),%rdi
  pop    %rbp
  jmp    1070 <fail@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  pop    %rbp
  jmp    1080 <emitln@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D19: No loop to break from

tool: D10: JMP	%s	#BREAK to %s

assistant: ```c
void doBreak(char *exitLabel) {
  match('b');
  if (NULL == exitLabel || 0 == strlen(exitLabel))
    fail("No loop to break from");
  else
    emitln("JMP\t%s\t#BREAK to %s", exitLabel, exitLabel);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<doBreak>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x62,%edi
  call   <match@plt>
  test   %rbp,%rbp
  je     L4
  cmpb   $0x0,0x0(%rbp)
  jne    L12
L4:
  lea    D6(%rip),%rdi
  pop    %rbp
  jmp    1070 <fail@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  pop    %rbp
  jmp    1080 <emitln@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D6: No loop to break from

tool: D19: JMP	%s	#BREAK to %s

assistant: ```c
void doBreak(char *exitLabel) {
  match('b');
  if (NULL == exitLabel || 0 == strlen(exitLabel))
    fail("No loop to break from");
  else
    emitln("JMP\t%s\t#BREAK to %s", exitLabel, exitLabel);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,%eax
  mov    %al,-0x34(%rbp)
  movl   $0x64,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buffer_allocate@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L55
L60:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x34(%rbp)
  jne    L62
  addl   $0x1,-0x10(%rbp)
  jmp    L31
L62:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L30
  addl   $0xb,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buffer_allocate@plt>
  mov    %rax,-0x8(%rbp)
L30:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L55:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
L31:
  cmpl   $0x0,-0xc(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L50
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
L50:
  leave
  ret
```

assistant: ```c
char *parse_field(const char *line, int *line_position, const char field_delimiter) {
  int buffer_len = (100);
  int line_counter = *line_position;
  int field_counter = 0;
  char *field = NULL;
  field = buffer_allocate(field, buffer_len + 1);
  while (line[line_counter] != '\0') {
    if (line[line_counter] == field_delimiter) {
      line_counter++;
      break;
    }
    if (field_counter + 1 == buffer_len) {
      buffer_len += (10) + 1;
      field = buffer_allocate(field, buffer_len);
    }
    field[field_counter++] = line[line_counter++];
  }
  if (field_counter == 0) {
    return NULL;
  }
  field[field_counter] = '\0';
  *line_position = line_counter;
  return field;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_field>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r15d
  mov    (%rsi),%r13d
  mov    $0x65,%esi
  mov    $0x0,%edi
  call   <buffer_allocate@plt>
  mov    %rax,%rdi
  movslq %r13d,%rax
  add    %rax,%r12
  movzbl (%r12),%edx
  test   %dl,%dl
  je     L74
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x64,%r14d
  jmp    L79
L41:
  add    $0x1,%r13d
L15:
  test   %ebp,%ebp
  je     L77
  movslq %ebp,%rbp
  movb   $0x0,(%rdi,%rbp,1)
  mov    0x8(%rsp),%rax
  mov    %r13d,(%rax)
L28:
  mov    %rdi,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  add    $0x1,%r13d
  movzbl (%r12,%rbx,1),%eax
  mov    %al,(%rdi,%rbx,1)
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%edx
  test   %dl,%dl
  je     L15
L79:
  cmp    %dl,%r15b
  je     L41
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  jne    L37
  add    $0xb,%r14d
  mov    %r14d,%esi
  call   <buffer_allocate@plt>
  mov    %rax,%rdi
  jmp    L37
L74:
  mov    $0x0,%edi
  jmp    L28
L77:
  mov    $0x0,%edi
  jmp    L28
```

assistant: ```c
char *parse_field(const char *line, int *line_position, const char field_delimiter) {
  int buffer_len = (100);
  int line_counter = *line_position;
  int field_counter = 0;
  char *field = NULL;
  field = buffer_allocate(field, buffer_len + 1);
  while (line[line_counter] != '\0') {
    if (line[line_counter] == field_delimiter) {
      line_counter++;
      break;
    }
    if (field_counter + 1 == buffer_len) {
      buffer_len += (10) + 1;
      field = buffer_allocate(field, buffer_len);
    }
    field[field_counter++] = line[line_counter++];
  }
  if (field_counter == 0) {
    return NULL;
  }
  field[field_counter] = '\0';
  *line_position = line_counter;
  return field;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_field>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  mov    $0x64,%r13d
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    (%rsi),%r14d
  mov    %rsi,0x8(%rsp)
  mov    $0x65,%esi
  call   <buffer_allocate@plt>
  mov    %rax,%rdi
  movslq %r14d,%rax
  add    %rax,%r12
  movzbl (%r12),%edx
  test   %dl,%dl
  jne    L35
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L55:
  movzbl (%r12,%rbx,1),%eax
  add    $0x1,%r14d
  mov    %al,(%rdi,%rbx,1)
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%edx
  test   %dl,%dl
  je     L18
L35:
  cmp    %dl,%r15b
  je     L44
  add    $0x1,%ebp
  cmp    %r13d,%ebp
  jne    L55
  lea    0xb(%rbp),%r13d
  mov    %r13d,%esi
  call   <buffer_allocate@plt>
  mov    %rax,%rdi
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%r14d
  test   %ebp,%ebp
  je     L2
L18:
  mov    0x8(%rsp),%rax
  movslq %ebp,%rbp
  movb   $0x0,(%rdi,%rbp,1)
  mov    %r14d,(%rax)
L51:
  add    $0x18,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  xor    %edi,%edi
  jmp    L51
```

assistant: ```c
char *parse_field(const char *line, int *line_position, const char field_delimiter) {
  int buffer_len = (100);
  int line_counter = *line_position;
  int field_counter = 0;
  char *field = NULL;
  field = buffer_allocate(field, buffer_len + 1);
  while (line[line_counter] != '\0') {
    if (line[line_counter] == field_delimiter) {
      line_counter++;
      break;
    }
    if (field_counter + 1 == buffer_len) {
      buffer_len += (10) + 1;
      field = buffer_allocate(field, buffer_len);
    }
    field[field_counter++] = line[line_counter++];
  }
  if (field_counter == 0) {
    return NULL;
  }
  field[field_counter] = '\0';
  *line_position = line_counter;
  return field;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_field>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    (%rsi),%r15d
  mov    %rsi,0x8(%rsp)
  mov    $0x65,%esi
  call   <buffer_allocate@plt>
  mov    $0x64,%edx
  mov    %rax,%rdi
  movslq %r15d,%rax
  add    %rax,%r12
  movzbl (%r12),%eax
  test   %al,%al
  je     L45
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    %al,%r13b
  je     L64
L71:
  add    $0x1,%ebp
  cmp    %edx,%ebp
  je     L79
  movzbl (%r12,%rbx,1),%eax
  add    $0x1,%r15d
  mov    %al,(%rdi,%rbx,1)
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%eax
  test   %al,%al
  jne    L33
L46:
  mov    0x8(%rsp),%rax
  movslq %ebp,%rbp
  movb   $0x0,(%rdi,%rbp,1)
  mov    %r15d,(%rax)
L8:
  add    $0x18,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L79:
  lea    0xb(%rbp),%r14d
  add    $0x1,%r15d
  mov    %r14d,%esi
  call   <buffer_allocate@plt>
  mov    %rax,%rdi
  movzbl (%r12,%rbx,1),%eax
  mov    %al,(%rdi,%rbx,1)
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%eax
  test   %al,%al
  je     L46
  mov    %r14d,%edx
  cmp    %al,%r13b
  jne    L71
L64:
  add    $0x1,%r15d
  test   %ebp,%ebp
  jne    L46
L45:
  xor    %edi,%edi
  jmp    L8
```

assistant: ```c
char *parse_field(const char *line, int *line_position, const char field_delimiter) {
  int buffer_len = (100);
  int line_counter = *line_position;
  int field_counter = 0;
  char *field = NULL;
  field = buffer_allocate(field, buffer_len + 1);
  while (line[line_counter] != '\0') {
    if (line[line_counter] == field_delimiter) {
      line_counter++;
      break;
    }
    if (field_counter + 1 == buffer_len) {
      buffer_len += (10) + 1;
      field = buffer_allocate(field, buffer_len);
    }
    field[field_counter++] = line[line_counter++];
  }
  if (field_counter == 0) {
    return NULL;
  }
  field[field_counter] = '\0';
  *line_position = line_counter;
  return field;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<argz_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L57
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L56
L14:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rcx
  movslq %edx,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L57:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L14
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L67
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L56
L67:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L64
L32:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L64:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L32
  mov    $0x0,%eax
L56:
  leave
  ret
```

assistant: ```c
error_t argz_create(char *const argv[], char **argz, size_t *argz_len) {
  int argc = 0;
  int i = 0;
  int len = 0;
  char *iter;
  *argz_len = 0;
  if (*argv == NULL) {
    *argz = NULL;
    return 0;
  }
  while (argv[argc]) {
    *argz_len += (strlen(argv[argc]) + 1);
    argc++;
  }
  if (!(*argz = (char *)malloc(*argz_len)))
    return ENOMEM;
  iter = *argz;
  for (i = 0; i < argc; i++) {
    len = strlen(argv[i]) + 1;
    memcpy(iter, argv[i], len);
    iter += len;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<argz_create>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r15
  movq   $0x0,(%rdx)
  mov    (%rdi),%rax
  test   %rax,%rax
  je     L33
  mov    %rdi,%r13
  mov    %rdx,%r12
  lea    0x8(%rdi),%rbp
  mov    $0x0,%ebx
L64:
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  add    (%r12),%rdi
  mov    %rdi,(%r12)
  mov    %ebx,%r14d
  add    $0x1,%ebx
  add    $0x8,%rbp
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  jne    L64
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L25
  mov    $0x0,%r12d
  mov    $0x0,%eax
  test   %ebx,%ebx
  jle    L6
L31:
  mov    0x0(%r13,%r12,8),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    0x0(%r13,%r12,8),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  add    %rbx,%rbp
  add    $0x1,%r12
  lea    -0x1(%r12),%eax
  cmp    %eax,%r14d
  jg     L31
  mov    $0x0,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  movq   $0x0,(%rsi)
  mov    $0x0,%eax
  jmp    L6
L25:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  jmp    L6
```

assistant: ```c
error_t argz_create(char *const argv[], char **argz, size_t *argz_len) {
  int argc = 0;
  int i = 0;
  int len = 0;
  char *iter;
  *argz_len = 0;
  if (*argv == NULL) {
    *argz = NULL;
    return 0;
  }
  while (argv[argc]) {
    *argz_len += (strlen(argv[argc]) + 1);
    argc++;
  }
  if (!(*argz = (char *)malloc(*argz_len)))
    return ENOMEM;
  iter = *argz;
  for (i = 0; i < argc; i++) {
    len = strlen(argv[i]) + 1;
    memcpy(iter, argv[i], len);
    iter += len;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<argz_create>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%r8
  movq   $0x0,(%rdx)
  test   %r8,%r8
  je     L21
  mov    %rdi,%rbx
  mov    %rdx,%r13
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %r8,%rdi
  mov    %r12,%r14
  add    $0x1,%r12
  call   <strlen@plt>
  mov    (%rbx,%r12,8),%r8
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  add    0x0(%r13),%rdi
  mov    %rdi,0x0(%r13)
  test   %r8,%r8
  jne    L17
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  lea    0x8(%rbx,%r14,8),%r13
  nopl   0x0(%rax)
L7:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%ebp
  mov    %ebp,%edx
  movslq %ebp,%rbp
  call   <memcpy@plt>
  add    %rbp,%r12
  cmp    %r13,%rbx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  movq   $0x0,(%rsi)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
error_t argz_create(char *const argv[], char **argz, size_t *argz_len) {
  int argc = 0;
  int i = 0;
  int len = 0;
  char *iter;
  *argz_len = 0;
  if (*argv == NULL) {
    *argz = NULL;
    return 0;
  }
  while (argv[argc]) {
    *argz_len += (strlen(argv[argc]) + 1);
    argc++;
  }
  if (!(*argz = (char *)malloc(*argz_len)))
    return ENOMEM;
  iter = *argz;
  for (i = 0; i < argc; i++) {
    len = strlen(argv[i]) + 1;
    memcpy(iter, argv[i], len);
    iter += len;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<argz_create>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%r8
  movq   $0x0,(%rdx)
  test   %r8,%r8
  je     L37
  mov    %rdi,%rbx
  mov    %rdx,%r13
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r8,%rdi
  mov    %r12,%r14
  add    $0x1,%r12
  call   <strlen@plt>
  mov    (%rbx,%r12,8),%r8
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  add    0x0(%r13),%rdi
  mov    %rdi,0x0(%r13)
  test   %r8,%r8
  jne    L34
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  lea    0x8(%rbx,%r14,8),%r13
  nopl   0x0(%rax)
L38:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%ebp
  mov    %ebp,%edx
  movslq %ebp,%rbp
  call   <memcpy@plt>
  add    %rbp,%r12
  cmp    %r13,%rbx
  jne    L38
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  movq   $0x0,(%rsi)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
error_t argz_create(char *const argv[], char **argz, size_t *argz_len) {
  int argc = 0;
  int i = 0;
  int len = 0;
  char *iter;
  *argz_len = 0;
  if (*argv == NULL) {
    *argz = NULL;
    return 0;
  }
  while (argv[argc]) {
    *argz_len += (strlen(argv[argc]) + 1);
    argc++;
  }
  if (!(*argz = (char *)malloc(*argz_len)))
    return ENOMEM;
  iter = *argz;
  for (i = 0; i < argc; i++) {
    len = strlen(argv[i]) + 1;
    memcpy(iter, argv[i], len);
    iter += len;
  }
  return 0;
}
```