ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_specified_sring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L2
  mov    %rdx,%r13
  mov    %rdi,%rbx
L0:
  movsbl %sil,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L0
L4:
  sub    %rbp,%rbx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %rdi,%rbx
  jmp    L4
```

assistant: ```c
int get_specified_sring(const char *src, char *dst, const char *module) {
  const char *temp = src;
  while (*temp != '\0') {
    if (strchr(module, *temp) != NULL) {
      break;
    }
    temp++;
  }
  strncpy(dst, src, temp - src);
  dst[temp - src] = '\0';
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_specified_sring>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L23
  mov    %rdx,%r13
  mov    %rdi,%rbx
  jmp    L33
  nopl   0x0(%rax)
L9:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L48
L33:
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
L48:
  sub    %rbp,%rbx
  mov    %ebx,%edx
  add    %r12,%rbx
L30:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  mov    %r12,%rbx
  xor    %edx,%edx
  jmp    L30
```

assistant: ```c
int get_specified_sring(const char *src, char *dst, const char *module) {
  const char *temp = src;
  while (*temp != '\0') {
    if (strchr(module, *temp) != NULL) {
      break;
    }
    temp++;
  }
  strncpy(dst, src, temp - src);
  dst[temp - src] = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_specified_sring>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L27
  mov    %rdx,%r13
  mov    %rdi,%rbx
  jmp    L9
  nopl   0x0(%rax)
L46:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L32
L9:
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L46
L32:
  sub    %rbp,%rbx
  mov    %ebx,%edx
  add    %r12,%rbx
L48:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    %r12,%rbx
  xor    %edx,%edx
  jmp    L48
```

assistant: ```c
int get_specified_sring(const char *src, char *dst, const char *module) {
  const char *temp = src;
  while (*temp != '\0') {
    if (strchr(module, *temp) != NULL) {
      break;
    }
    temp++;
  }
  strncpy(dst, src, temp - src);
  dst[temp - src] = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<user_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <main@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sys_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void user_entry(void) {
  int ret = main();
  sys_exit(ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<user_entry>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <main@plt>
  mov    %eax,%edi
  call   <sys_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void user_entry(void) {
  int ret = main();
  sys_exit(ret);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<user_entry>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <main@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <sys_exit@plt>
```

assistant: ```c
void user_entry(void) {
  int ret = main();
  sys_exit(ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<user_entry>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <main@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <sys_exit@plt>
```

assistant: ```c
void user_entry(void) {
  int ret = main();
  sys_exit(ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x17447d68,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    -0x13520640(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy11;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
      local1++;
    }
    output[0UL] = state[0UL] - 324142656UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x2a9683a8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy11;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
      local1++;
    }
    output[0UL] = state[0UL] - 324142656UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x2a9683a8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy11;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
      local1++;
    }
    output[0UL] = state[0UL] - 324142656UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x2a9683a8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy11;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
      local1++;
    }
    output[0UL] = state[0UL] - 324142656UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L19
L4:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L19:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x63,%eax
  jle    L4
  mov    -0x18(%rbp),%rax
  movl   $0x5,(%rax)
  jmp    L3
L28:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x3(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L3:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x14,%eax
  jle    L28
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *c = 0;
  for (*i = 0; *i < 100; (*i)++)
    *c = *c + 1;
  for (*j = 5; *j < 21; *j += 3)
    *c = *c + 1;
  return *c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <alloca@plt>
  movl   $0x0,(%rax)
  movl   $0x0,(%r12)
L5:
  addl   $0x1,(%rax)
  mov    (%r12),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%r12)
  cmp    $0x63,%edx
  jle    L5
  movl   $0x5,(%rbx)
L15:
  addl   $0x1,(%rax)
  mov    (%rbx),%esi
  lea    0x3(%rsi),%edx
  mov    %edx,(%rbx)
  cmp    $0x14,%edx
  jle    L15
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *c = 0;
  for (*i = 0; *i < 100; (*i)++)
    *c = *c + 1;
  for (*j = 5; *j < 21; *j += 3)
    *c = *c + 1;
  return *c;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  movl   $0x0,(%rax)
  movl   $0x0,(%r12)
L29:
  addl   $0x1,(%rax)
  mov    (%r12),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%r12)
  cmp    $0x63,%edx
  jle    L29
  movl   $0x5,(%rbx)
  nopl   0x0(%rax)
L20:
  addl   $0x1,(%rax)
  mov    (%rbx),%esi
  lea    0x3(%rsi),%edx
  mov    %edx,(%rbx)
  cmp    $0x14,%edx
  jle    L20
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *c = 0;
  for (*i = 0; *i < 100; (*i)++)
    *c = *c + 1;
  for (*j = 5; *j < 21; *j += 3)
    *c = *c + 1;
  return *c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  movl   $0x0,(%rax)
  movl   $0x0,(%r12)
L26:
  addl   $0x1,(%rax)
  mov    (%r12),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%r12)
  cmp    $0x63,%edx
  jle    L26
  movl   $0x5,(%rbx)
  nopl   0x0(%rax)
L12:
  addl   $0x1,(%rax)
  mov    (%rbx),%esi
  lea    0x3(%rsi),%edx
  mov    %edx,(%rbx)
  cmp    $0x14,%edx
  jle    L12
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *c = 0;
  for (*i = 0; *i < 100; (*i)++)
    *c = *c + 1;
  for (*j = 5; *j < 21; *j += 3)
    *c = *c + 1;
  return *c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_mq_setattr_prototype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mq_setattr@plt>
  mov    %eax,-0x14(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void test_mq_setattr_prototype(void) {
  mqd_t mqdes;
  struct mq_attr mqs, omqs;
  int err;
  mqdes = 0;
  err = mq_setattr(mqdes, &mqs, &omqs);
  (void)err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_mq_setattr_prototype>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    $0x0,%edi
  call   <mq_setattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_mq_setattr_prototype(void) {
  mqd_t mqdes;
  struct mq_attr mqs, omqs;
  int err;
  mqdes = 0;
  err = mq_setattr(mqdes, &mqs, &omqs);
  (void)err;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_mq_setattr_prototype>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <mq_setattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_mq_setattr_prototype(void) {
  mqd_t mqdes;
  struct mq_attr mqs, omqs;
  int err;
  mqdes = 0;
  err = mq_setattr(mqdes, &mqs, &omqs);
  (void)err;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_mq_setattr_prototype>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <mq_setattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_mq_setattr_prototype(void) {
  mqd_t mqdes;
  struct mq_attr mqs, omqs;
  int err;
  mqdes = 0;
  err = mq_setattr(mqdes, &mqs, &omqs);
  (void)err;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dox_para>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <startpara@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *dox_para(const char *p, struct cnode **pcnode, const struct cnodefuncs *type, const char *filename, unsigned int linenum, const char *cmdname) {
  *pcnode = startpara(*pcnode, type);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dox_para>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    (%rbx),%rdi
  call   <startpara@plt>
  mov    %rax,(%rbx)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *dox_para(const char *p, struct cnode **pcnode, const struct cnodefuncs *type, const char *filename, unsigned int linenum, const char *cmdname) {
  *pcnode = startpara(*pcnode, type);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dox_para>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  mov    (%rbx),%rdi
  call   <startpara@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *dox_para(const char *p, struct cnode **pcnode, const struct cnodefuncs *type, const char *filename, unsigned int linenum, const char *cmdname) {
  *pcnode = startpara(*pcnode, type);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dox_para>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  mov    (%rbx),%rdi
  call   <startpara@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *dox_para(const char *p, struct cnode **pcnode, const struct cnodefuncs *type, const char *filename, unsigned int linenum, const char *cmdname) {
  *pcnode = startpara(*pcnode, type);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_readings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L6:
  mov    $0x0,%eax
  call   <adc_read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <delay_ms@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: Read: %d


assistant: ```c
void show_readings(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = adc_read();
    printf("Read: %d\n", val);
    delay_ms(delay);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<show_readings>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L16:
  mov    $0x0,%eax
  call   <adc_read@plt>
  mov    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <delay_ms@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: Read: %d


assistant: ```c
void show_readings(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = adc_read();
    printf("Read: %d\n", val);
    delay_ms(delay);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<show_readings>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L13:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <adc_read@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <delay_ms@plt>
  cmp    %ebx,%ebp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: Read: %d


assistant: ```c
void show_readings(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = adc_read();
    printf("Read: %d\n", val);
    delay_ms(delay);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<show_readings>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L2:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <adc_read@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <delay_ms@plt>
  cmp    %ebx,%ebp
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D7: Read: %d


assistant: ```c
void show_readings(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = adc_read();
    printf("Read: %d\n", val);
    delay_ms(delay);
  }
}
```