ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<get_tokval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x114(%rbp)
  jmp    L3
L29:
  mov    -0x114(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x114(%rbp),%eax
  cltq
  mov    %dl,-0x110(%rbp,%rax,1)
  addl   $0x1,-0x114(%rbp)
L3:
  cmpl   $0xff,-0x114(%rbp)
  jg     L6
  mov    -0x114(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L29
L6:
  mov    -0x114(%rbp),%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x130(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x114(%rbp),%eax
  add    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int get_tokval(const char *line, char **retdata) {
  int i;
  char tokval[256];
  for (i = 0; i < 256 && (*(line + i) != ')'); i++)
    tokval[i] = *(line + i);
  tokval[i] = '\0';
  *retdata = strdup(tokval);
  return i + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_tokval>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
L12:
  mov    %eax,%ebx
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x29,%dl
  je     L15
  mov    %dl,(%rsp,%rax,1)
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L12
L15:
  movslq %ebx,%rax
  movb   $0x0,(%rsp,%rax,1)
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  lea    0x1(%rbx),%eax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_tokval(const char *line, char **retdata) {
  int i;
  char tokval[256];
  for (i = 0; i < 256 && (*(line + i) != ')'); i++)
    tokval[i] = *(line + i);
  tokval[i] = '\0';
  *retdata = strdup(tokval);
  return i + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_tokval>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  jmp    L45
  nopl   0x0(%rax)
L24:
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x100,%rax
  je     L38
L45:
  movzbl (%rdi,%rax,1),%edx
  movslq %eax,%rcx
  lea    0x1(%rax),%r12d
  cmp    $0x29,%dl
  jne    L24
L42:
  mov    %r8,%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x118,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L38:
  mov    $0x101,%r12d
  mov    $0x100,%ecx
  jmp    L42
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_tokval(const char *line, char **retdata) {
  int i;
  char tokval[256];
  for (i = 0; i < 256 && (*(line + i) != ')'); i++)
    tokval[i] = *(line + i);
  tokval[i] = '\0';
  *retdata = strdup(tokval);
  return i + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_tokval>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  jmp    L48
  nopl   0x0(%rax)
L42:
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x100,%rax
  je     L30
L48:
  movzbl (%rdi,%rax,1),%edx
  movslq %eax,%rcx
  lea    0x1(%rax),%r12d
  cmp    $0x29,%dl
  jne    L42
L33:
  mov    %r8,%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x118,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L30:
  mov    $0x101,%r12d
  mov    $0x100,%ecx
  jmp    L33
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_tokval(const char *line, char **retdata) {
  int i;
  char tokval[256];
  for (i = 0; i < 256 && (*(line + i) != ')'); i++)
    tokval[i] = *(line + i);
  tokval[i] = '\0';
  *retdata = strdup(tokval);
  return i + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test25>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test25(int a, int b, int c, int d) {
  int x = a != b;
  int y = c == 0;
  return x - y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test25>:
  endbr64
  cmp    %esi,%edi
  setne  %al
  movzbl %al,%eax
  cmp    $0x1,%edx
  sbb    $0x0,%eax
  ret
```

assistant: ```c
int test25(int a, int b, int c, int d) {
  int x = a != b;
  int y = c == 0;
  return x - y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test25>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  setne  %al
  cmp    $0x1,%edx
  sbb    $0x0,%eax
  ret
```

assistant: ```c
int test25(int a, int b, int c, int d) {
  int x = a != b;
  int y = c == 0;
  return x - y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L6
L23:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    $0x20,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L32
  mov    $0x31,%eax
  jmp    L39
L32:
  mov    $0x30,%eax
L39:
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L27
  mov    $0x20,%edi
  call   <putchar@plt>
L27:
  addq   $0x1,-0x8(%rbp)
L6:
  cmpq   $0x20,-0x8(%rbp)
  jbe    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void print32(uint32_t n) {
  for (size_t bit = 1; bit <= 32; bit++) {
    char c = ((n) & (1UL << (32 - (bit)))) ? '1' : '0';
    putchar(c);
    if (bit % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  movslq %edi,%rbp
  jmp    L29
L18:
  add    $0x1,%rbx
  cmp    $0x21,%rbx
  je     L16
L29:
  mov    $0x20,%ecx
  sub    %ebx,%ecx
  mov    %rbp,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  test   $0x7,%bl
  jne    L18
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L18
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void print32(uint32_t n) {
  for (size_t bit = 1; bit <= 32; bit++) {
    char c = ((n) & (1UL << (32 - (bit)))) ? '1' : '0';
    putchar(c);
    if (bit % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print32>:
  endbr64
  push   %r12
  mov    $0x20,%r12d
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rbp,%rax
  mov    $0x1,%ebx
  shr    $0x3f,%rax
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  nopl   (%rax)
L22:
  add    $0x1,%rbx
  cmp    $0x21,%rbx
  je     L8
L12:
  mov    %r12d,%ecx
  mov    %rbp,%rax
  sub    %ebx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  test   $0x7,%bl
  jne    L22
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    $0x21,%rbx
  jne    L12
L8:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
```

assistant: ```c
void print32(uint32_t n) {
  for (size_t bit = 1; bit <= 32; bit++) {
    char c = ((n) & (1UL << (32 - (bit)))) ? '1' : '0';
    putchar(c);
    if (bit % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print32>:
  endbr64
  push   %r12
  mov    $0x20,%r12d
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rbp,%rax
  mov    $0x2,%ebx
  shr    $0x3f,%rax
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  nopl   (%rax)
L14:
  mov    %r12d,%ecx
  mov    %rbp,%rax
  sub    %ebx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  test   $0x7,%bl
  jne    L7
  mov    $0x20,%edi
  call   <putchar@plt>
L7:
  add    $0x1,%rbx
  cmp    $0x21,%rbx
  jne    L14
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
```

assistant: ```c
void print32(uint32_t n) {
  for (size_t bit = 1; bit <= 32; bit++) {
    char c = ((n) & (1UL << (32 - (bit)))) ? '1' : '0';
    putchar(c);
    if (bit % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gen_cvin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x1c,%eax
  and    $0x30000000,%eax
  mov    %eax,-0x4(%rbp)
  orl    $0xc0000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_cvin(cvin) {
  int r = ((cvin & 2) ? (1 << 29) : 0) | ((cvin & 1) ? (1 << 28) : 0);
  r |= (1 << 31) | (1 << 30);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gen_cvin>:
  endbr64
  mov    %edi,%eax
  shl    $0x1c,%eax
  and    $0x30000000,%eax
  or     $0xc0000000,%eax
  ret
```

assistant: ```c
int gen_cvin(cvin) {
  int r = ((cvin & 2) ? (1 << 29) : 0) | ((cvin & 1) ? (1 << 28) : 0);
  r |= (1 << 31) | (1 << 30);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gen_cvin>:
  endbr64
  mov    %edi,%eax
  shl    $0x1c,%eax
  and    $0x30000000,%eax
  or     $0xc0000000,%eax
  ret
```

assistant: ```c
int gen_cvin(cvin) {
  int r = ((cvin & 2) ? (1 << 29) : 0) | ((cvin & 1) ? (1 << 28) : 0);
  r |= (1 << 31) | (1 << 30);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_cvin>:
  endbr64
  mov    %edi,%eax
  shl    $0x1c,%eax
  and    $0x30000000,%eax
  or     $0xc0000000,%eax
  ret
```

assistant: ```c
int gen_cvin(cvin) {
  int r = ((cvin & 2) ? (1 << 29) : 0) | ((cvin & 1) ? (1 << 28) : 0);
  r |= (1 << 31) | (1 << 30);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uart_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x20215004,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215060,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x2021504c,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215050,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  mov    $0xc6,%esi
  mov    $0x20215048,%edi
  call   <PUT32@plt>
  mov    $0x10e,%esi
  mov    $0x20215068,%edi
  call   <PUT32@plt>
  mov    $0x20200004,%edi
  call   <GET32@plt>
  mov    %eax,-0x4(%rbp)
  andl   $0xffff8fff,-0x4(%rbp)
  orl    $0x2000,-0x4(%rbp)
  andl   $0xfffc7fff,-0x4(%rbp)
  orl    $0x10000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x20200004,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20200094,%edi
  call   <PUT32@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L35:
  mov    $0x0,%eax
  call   <NOP@plt>
  addl   $0x1,-0xc(%rbp)
L28:
  cmpl   $0x95,-0xc(%rbp)
  jle    L35
  mov    $0xc000,%esi
  mov    $0x20200098,%edi
  call   <PUT32@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L5:
  mov    $0x0,%eax
  call   <NOP@plt>
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x95,-0x8(%rbp)
  jle    L5
  mov    $0x0,%esi
  mov    $0x20200098,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x20215060,%edi
  call   <PUT32@plt>
  nop
  leave
  ret
```

assistant: ```c
void uart_init() {
  unsigned int ra;
  PUT32(0x20215004, 1);
  PUT32(0x20215044, 0);
  PUT32(0x20215060, 0);
  PUT32(0x2021504C, 3);
  PUT32(0x20215050, 0);
  PUT32(0x20215044, 0);
  PUT32(0x20215048, 0xC6);
  PUT32(0x20215068, 270);
  ra = GET32(((0x20000000 + 0x200000) + 4));
  ra &= ~(7 << 12);
  ra |= 2 << 12;
  ra &= ~(7 << 15);
  ra |= 2 << 15;
  PUT32(((0x20000000 + 0x200000) + 4), ra);
  PUT32(((0x20000000 + 0x200000) + 0x94), 0);
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), (1 << 14) | (1 << 15));
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), 0);
  PUT32(0x20215060, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uart_init>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    $0x20215004,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215060,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x2021504c,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215050,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  mov    $0xc6,%esi
  mov    $0x20215048,%edi
  call   <PUT32@plt>
  mov    $0x10e,%esi
  mov    $0x20215068,%edi
  call   <PUT32@plt>
  mov    $0x20200004,%edi
  call   <GET32@plt>
  and    $0xfffc0fff,%eax
  mov    %eax,%esi
  or     $0x12000,%esi
  mov    $0x20200004,%edi
  call   <PUT32@plt>
  mov    $0x0,%esi
  mov    $0x20200094,%edi
  call   <PUT32@plt>
  mov    $0x96,%ebx
L10:
  mov    $0x0,%eax
  call   <NOP@plt>
  sub    $0x1,%ebx
  jne    L10
  mov    $0xc000,%esi
  mov    $0x20200098,%edi
  call   <PUT32@plt>
  mov    $0x96,%ebx
L14:
  mov    $0x0,%eax
  call   <NOP@plt>
  sub    $0x1,%ebx
  jne    L14
  mov    $0x0,%esi
  mov    $0x20200098,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x20215060,%edi
  call   <PUT32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void uart_init() {
  unsigned int ra;
  PUT32(0x20215004, 1);
  PUT32(0x20215044, 0);
  PUT32(0x20215060, 0);
  PUT32(0x2021504C, 3);
  PUT32(0x20215050, 0);
  PUT32(0x20215044, 0);
  PUT32(0x20215048, 0xC6);
  PUT32(0x20215068, 270);
  ra = GET32(((0x20000000 + 0x200000) + 4));
  ra &= ~(7 << 12);
  ra |= 2 << 12;
  ra &= ~(7 << 15);
  ra |= 2 << 15;
  PUT32(((0x20000000 + 0x200000) + 4), ra);
  PUT32(((0x20000000 + 0x200000) + 0x94), 0);
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), (1 << 14) | (1 << 15));
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), 0);
  PUT32(0x20215060, 3);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uart_init>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    $0x20215004,%edi
  mov    $0x96,%ebx
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215060,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x2021504c,%edi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215050,%edi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  mov    $0xc6,%esi
  mov    $0x20215048,%edi
  call   <PUT32@plt>
  mov    $0x10e,%esi
  mov    $0x20215068,%edi
  call   <PUT32@plt>
  mov    $0x20200004,%edi
  call   <GET32@plt>
  mov    $0x20200004,%edi
  and    $0xfffc0fff,%eax
  mov    %eax,%esi
  or     $0x12000,%esi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20200094,%edi
  call   <PUT32@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  call   <NOP@plt>
  sub    $0x1,%ebx
  jne    L19
  mov    $0xc000,%esi
  mov    $0x20200098,%edi
  mov    $0x96,%ebx
  call   <PUT32@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <NOP@plt>
  sub    $0x1,%ebx
  jne    L18
  xor    %esi,%esi
  mov    $0x20200098,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x20215060,%edi
  pop    %rbx
  jmp    1080 <PUT32@plt>
```

assistant: ```c
void uart_init() {
  unsigned int ra;
  PUT32(0x20215004, 1);
  PUT32(0x20215044, 0);
  PUT32(0x20215060, 0);
  PUT32(0x2021504C, 3);
  PUT32(0x20215050, 0);
  PUT32(0x20215044, 0);
  PUT32(0x20215048, 0xC6);
  PUT32(0x20215068, 270);
  ra = GET32(((0x20000000 + 0x200000) + 4));
  ra &= ~(7 << 12);
  ra |= 2 << 12;
  ra &= ~(7 << 15);
  ra |= 2 << 15;
  PUT32(((0x20000000 + 0x200000) + 4), ra);
  PUT32(((0x20000000 + 0x200000) + 0x94), 0);
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), (1 << 14) | (1 << 15));
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), 0);
  PUT32(0x20215060, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uart_init>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    $0x20215004,%edi
  mov    $0x96,%ebx
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215060,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x2021504c,%edi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215050,%edi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20215044,%edi
  call   <PUT32@plt>
  mov    $0xc6,%esi
  mov    $0x20215048,%edi
  call   <PUT32@plt>
  mov    $0x10e,%esi
  mov    $0x20215068,%edi
  call   <PUT32@plt>
  mov    $0x20200004,%edi
  call   <GET32@plt>
  mov    $0x20200004,%edi
  and    $0xfffc0fff,%eax
  mov    %eax,%esi
  or     $0x12000,%esi
  call   <PUT32@plt>
  xor    %esi,%esi
  mov    $0x20200094,%edi
  call   <PUT32@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <NOP@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    $0xc000,%esi
  mov    $0x20200098,%edi
  mov    $0x96,%ebx
  call   <PUT32@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <NOP@plt>
  sub    $0x1,%ebx
  jne    L0
  xor    %esi,%esi
  mov    $0x20200098,%edi
  call   <PUT32@plt>
  mov    $0x3,%esi
  mov    $0x20215060,%edi
  pop    %rbx
  jmp    1080 <PUT32@plt>
```

assistant: ```c
void uart_init() {
  unsigned int ra;
  PUT32(0x20215004, 1);
  PUT32(0x20215044, 0);
  PUT32(0x20215060, 0);
  PUT32(0x2021504C, 3);
  PUT32(0x20215050, 0);
  PUT32(0x20215044, 0);
  PUT32(0x20215048, 0xC6);
  PUT32(0x20215068, 270);
  ra = GET32(((0x20000000 + 0x200000) + 4));
  ra &= ~(7 << 12);
  ra |= 2 << 12;
  ra &= ~(7 << 15);
  ra |= 2 << 15;
  PUT32(((0x20000000 + 0x200000) + 4), ra);
  PUT32(((0x20000000 + 0x200000) + 0x94), 0);
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), (1 << 14) | (1 << 15));
  for (int i = 0; i < 150; i++) {
    NOP();
  }
  PUT32(((0x20000000 + 0x200000) + 0x98), 0);
  PUT32(0x20215060, 3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ati_wait_vsync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L3:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x1e847f,-0x4(%rbp)
  jle    L3
  jmp    L17
L8:
  nop
L17:
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L21:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  and    $0x1,%eax
  test   %eax,%eax
  jne    L74
  addl   $0x1,-0x4(%rbp)
L45:
  cmpl   $0x1e847f,-0x4(%rbp)
  jle    L21
  jmp    L75
L74:
  nop
L75:
  nop
  leave
  ret
```

assistant: ```c
void ati_wait_vsync(void) {
  int i;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001) == 0)
      break;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001))
      break;
}
```
user: What is the c source code of the assembly code below:

```asm
<ati_wait_vsync>:
  endbr64
  push   %rbx
  mov    $0x1e8480,%ebx
L22:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  test   $0x1,%al
  je     L29
  sub    $0x1,%ebx
  jne    L22
  mov    $0x1e8480,%ebx
  jmp    L36
L29:
  mov    $0x1e8480,%ebx
L36:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  test   $0x1,%al
  jne    L21
  sub    $0x1,%ebx
  jne    L36
L21:
  pop    %rbx
  ret
```

assistant: ```c
void ati_wait_vsync(void) {
  int i;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001) == 0)
      break;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001))
      break;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ati_wait_vsync>:
  endbr64
  push   %rbx
  mov    $0x1e8480,%ebx
  jmp    L26
  nopl   0x0(%rax)
L0:
  sub    $0x1,%ebx
  je     L21
L26:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  test   $0x1,%al
  jne    L0
L21:
  mov    $0x1e8480,%ebx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x1,%ebx
  je     L33
L3:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  test   $0x1,%al
  je     L6
L33:
  pop    %rbx
  ret
```

assistant: ```c
void ati_wait_vsync(void) {
  int i;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001) == 0)
      break;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001))
      break;
}
```
user: What is the c source code of the assembly code below:

```asm
<ati_wait_vsync>:
  endbr64
  push   %rbx
  mov    $0x1e8480,%ebx
  jmp    L49
  nopl   0x0(%rax)
L44:
  sub    $0x1,%ebx
  je     L29
L49:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  test   $0x1,%al
  jne    L44
L29:
  mov    $0x1e8480,%ebx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L55:
  sub    $0x1,%ebx
  je     L4
L32:
  mov    $0x18,%edi
  call   <aty_ld_le32@plt>
  test   $0x1,%al
  je     L55
L4:
  pop    %rbx
  ret
```

assistant: ```c
void ati_wait_vsync(void) {
  int i;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001) == 0)
      break;
  for (i = 0; i < 2000000; i++)
    if ((aty_ld_le32(0x0018) & 0x00000001))
      break;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9abcdeff,-0x10(%rbp)
  movl   $0x12345678,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movabs $0x123456789abcdeff,%rdx
  cmp    %rdx,%rax
  je     L3
  mov    $0xffffffff,%edi
  call   <_exit@plt>
L3:
  mov    $0x0,%edi
  call   <_exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  unsigned int a[] = {0x9abcdeff, 0x12345678};
  if (*((unsigned long long *)&a) != 0x123456789abcdeffLL) {
    _exit(-1);
  }
  _exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <_exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned int a[] = {0x9abcdeff, 0x12345678};
  if (*((unsigned long long *)&a) != 0x123456789abcdeffLL) {
    _exit(-1);
  }
  _exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned int a[] = {0x9abcdeff, 0x12345678};
  if (*((unsigned long long *)&a) != 0x123456789abcdeffLL) {
    _exit(-1);
  }
  _exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LZ4HC_sequencePrice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <LZ4HC_literalsPrice@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x12,-0x18(%rbp)
  jle    L6
  mov    -0x18(%rbp),%eax
  sub    $0x13,%eax
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  add    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int LZ4HC_sequencePrice(int litlen, int mlen) {
  int price = 1 + 2;
  ((void)0);
  ((void)0);
  price += LZ4HC_literalsPrice(litlen);
  if (mlen >= (int)(((1U << 4) - 1) + 4))
    price += 1 + ((mlen - (int)(((1U << 4) - 1) + 4)) / 255);
  return price;
}
```