ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = a + b;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = a + b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = a + b;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = a + b;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<replay_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <get_game_counter@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L58
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <readchar@plt>
  jmp    L87
L58:
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L73
L13:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <print_game_information@plt>
  addl   $0x1,-0x14(%rbp)
L73:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L13
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <clean_buffer_keyboard@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L58
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  js     L58
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L58
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L87
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <loadLogs@plt>
L87:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D31
datatype: string
name: retrieve_data
arguments: data_label: D46
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D10: There are no games available.


tool: D31: Press any key to go back to main menu...

tool: D46: 
Games available to replay:



tool: D2: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D13: %d

assistant: ```c
void replay_menu() {
  int gameCounter = get_game_counter();
  int control;
  int i;
  int option;
  if (gameCounter == 0) {
    printf("There are no games available.\n");
    printf("Press any key to go back to main menu...");
    readchar();
  } else {
    do {
      printf("\nGames available to replay:\n\n");
      for (i = 1; i <= gameCounter; i++) {
        print_game_information(i);
      }
      printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
      control = scanf("%d", &option);
      clean_buffer_keyboard();
    } while (control == 0 || option < 0 || option > gameCounter);
    if (option != 0) {
      loadLogs(option);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<replay_menu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <get_game_counter@plt>
  mov    %eax,%ebp
  lea    D34(%rip),%r15
  lea    D32(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D39(%rip),%r12
  test   %eax,%eax
  je     L25
L14:
  mov    %r15,%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L9
  mov    $0x1,%ebx
L33:
  mov    %ebx,%edi
  call   <print_game_information@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L33
L9:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <clean_buffer_keyboard@plt>
  test   %ebx,%ebx
  je     L14
  mov    0x4(%rsp),%edi
  cmp    %ebp,%edi
  jg     L14
  test   %edi,%edi
  js     L14
  jne    L82
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <readchar@plt>
  jmp    L43
L82:
  call   <loadLogs@plt>
  jmp    L43
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
type: string
name: extract_symbolic_data
arguments: data_tag: D32
type: string
name: extract_symbolic_data
arguments: data_tag: D39
type: string
name: extract_symbolic_data
arguments: data_tag: D43
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string

tool: D34: 
Games available to replay:



tool: D32: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D39: %d

tool: D43: There are no games available.


tool: D31: Press any key to go back to main menu...

assistant: ```c
void replay_menu() {
  int gameCounter = get_game_counter();
  int control;
  int i;
  int option;
  if (gameCounter == 0) {
    printf("There are no games available.\n");
    printf("Press any key to go back to main menu...");
    readchar();
  } else {
    do {
      printf("\nGames available to replay:\n\n");
      for (i = 1; i <= gameCounter; i++) {
        print_game_information(i);
      }
      printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
      control = scanf("%d", &option);
      clean_buffer_keyboard();
    } while (control == 0 || option < 0 || option > gameCounter);
    if (option != 0) {
      loadLogs(option);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<replay_menu>:
  endbr64
  push   %r15
  lea    D37(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <get_game_counter@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L1
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %r15,%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L60
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L74:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <print_game_information@plt>
  cmp    %ebx,%ebp
  jge    L74
L60:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <clean_buffer_keyboard@plt>
  test   %ebx,%ebx
  je     L46
  mov    0x4(%rsp),%edi
  cmp    %ebp,%edi
  jg     L46
  test   %edi,%edi
  js     L46
  jne    L93
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  call   <loadLogs@plt>
  jmp    L88
L1:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <readchar@plt>
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D31
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string

tool: D37: 
Games available to replay:



tool: D15: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D6: %d

tool: D31: There are no games available.


tool: D22: Press any key to go back to main menu...

assistant: ```c
void replay_menu() {
  int gameCounter = get_game_counter();
  int control;
  int i;
  int option;
  if (gameCounter == 0) {
    printf("There are no games available.\n");
    printf("Press any key to go back to main menu...");
    readchar();
  } else {
    do {
      printf("\nGames available to replay:\n\n");
      for (i = 1; i <= gameCounter; i++) {
        print_game_information(i);
      }
      printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
      control = scanf("%d", &option);
      clean_buffer_keyboard();
    } while (control == 0 || option < 0 || option > gameCounter);
    if (option != 0) {
      loadLogs(option);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<replay_menu>:
  endbr64
  push   %r15
  lea    D41(%rip),%r15
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <get_game_counter@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L76
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r15,%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L24
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L51:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <print_game_information@plt>
  cmp    %ebx,%ebp
  jge    L51
L24:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <clean_buffer_keyboard@plt>
  test   %ebx,%ebx
  je     L42
  mov    0x4(%rsp),%edi
  cmp    %ebp,%edi
  jg     L42
  test   %edi,%edi
  js     L42
  jne    L98
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  call   <loadLogs@plt>
  jmp    L59
L76:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <readchar@plt>
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D41
type_infered: string
name: extract_symbolic_data
arguments: label: D45
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D33
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D41: 
Games available to replay:



tool: D45: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D14: %d

tool: D33: There are no games available.


tool: D18: Press any key to go back to main menu...

assistant: ```c
void replay_menu() {
  int gameCounter = get_game_counter();
  int control;
  int i;
  int option;
  if (gameCounter == 0) {
    printf("There are no games available.\n");
    printf("Press any key to go back to main menu...");
    readchar();
  } else {
    do {
      printf("\nGames available to replay:\n\n");
      for (i = 1; i <= gameCounter; i++) {
        print_game_information(i);
      }
      printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
      control = scanf("%d", &option);
      clean_buffer_keyboard();
    } while (control == 0 || option < 0 || option > gameCounter);
    if (option != 0) {
      loadLogs(option);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aeron_ipv4_netmask_from_prefixlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L11:
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  bswap  %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t aeron_ipv4_netmask_from_prefixlen(size_t prefixlen) {
  uint32_t value;
  if (0 == prefixlen) {
    value = ~(-1);
  } else {
    value = ~(((uint32_t)1 << (32 - prefixlen)) - 1);
  }
  value = __builtin_bswap32(value);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aeron_ipv4_netmask_from_prefixlen>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L5
  mov    $0x20,%ecx
  sub    %edi,%ecx
  mov    $0xffffffff,%eax
  shl    %cl,%eax
L5:
  bswap  %eax
  ret
```

assistant: ```c
uint32_t aeron_ipv4_netmask_from_prefixlen(size_t prefixlen) {
  uint32_t value;
  if (0 == prefixlen) {
    value = ~(-1);
  } else {
    value = ~(((uint32_t)1 << (32 - prefixlen)) - 1);
  }
  value = __builtin_bswap32(value);
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aeron_ipv4_netmask_from_prefixlen>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  mov    $0x20,%ecx
  mov    $0xffffffff,%eax
  sub    %edi,%ecx
  shl    %cl,%eax
  bswap  %eax
L1:
  ret
```

assistant: ```c
uint32_t aeron_ipv4_netmask_from_prefixlen(size_t prefixlen) {
  uint32_t value;
  if (0 == prefixlen) {
    value = ~(-1);
  } else {
    value = ~(((uint32_t)1 << (32 - prefixlen)) - 1);
  }
  value = __builtin_bswap32(value);
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aeron_ipv4_netmask_from_prefixlen>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  mov    $0x20,%ecx
  mov    $0xffffffff,%eax
  sub    %edi,%ecx
  shl    %cl,%eax
  bswap  %eax
L1:
  ret
```

assistant: ```c
uint32_t aeron_ipv4_netmask_from_prefixlen(size_t prefixlen) {
  uint32_t value;
  if (0 == prefixlen) {
    value = ~(-1);
  } else {
    value = ~(((uint32_t)1 << (32 - prefixlen)) - 1);
  }
  value = __builtin_bswap32(value);
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L19
L29:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x2,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L29
  mov    $0x100,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  andl   $0xff,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x38(%rbp),%rax
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string

tool: D12: %2x%*s

tool: D18: %2X

assistant: ```c
int checksum(char asciiHex[], int from, int to, char *checksumAscii) {
  int i, sum;
  unsigned int b;
  sum = 0;
  for (i = from; i < to; i += 2) {
    sscanf(asciiHex + i, "%2x%*s", &b);
    sum += b;
  }
  sum = 0x100 - sum;
  sum &= 0xFF;
  sprintf(checksumAscii, "%2X", sum);
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    %edx,%esi
  jge    L7
  movslq %esi,%rcx
  lea    (%rdi,%rcx,1),%rbx
  lea    -0x1(%rdx),%eax
  sub    %esi,%eax
  shr    %eax
  mov    %eax,%eax
  lea    0x2(%rdi,%rcx,1),%rdx
  lea    (%rdx,%rax,2),%r14
  mov    $0x0,%ebp
  lea    D11(%rip),%r13
L29:
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x2,%rbx
  cmp    %r14,%rbx
  jne    L29
L20:
  neg    %ebp
  movzbl %bpl,%ebp
  mov    %ebp,%edx
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    $0x0,%ebp
  jmp    L20
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D14
data_type: string

tool: D11: %2x%*s

tool: D14: %2X

assistant: ```c
int checksum(char asciiHex[], int from, int to, char *checksumAscii) {
  int i, sum;
  unsigned int b;
  sum = 0;
  for (i = from; i < to; i += 2) {
    sscanf(asciiHex + i, "%2x%*s", &b);
    sum += b;
  }
  sum = 0x100 - sum;
  sum &= 0xFF;
  sprintf(checksumAscii, "%2X", sum);
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checksum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x8(%rsp)
  xor    %ecx,%ecx
  cmp    %edx,%esi
  jge    L19
  lea    -0x1(%rdx),%r12d
  movslq %esi,%rcx
  lea    0x4(%rsp),%r15
  xor    %ebp,%ebp
  sub    %rsi,%r12
  lea    0x2(%rdi,%rcx,1),%rax
  lea    (%rdi,%rcx,1),%rbx
  and    $0xfffffffe,%r12d
  lea    D1(%rip),%r14
  add    %rax,%r12
  nopl   (%rax)
L39:
  mov    %rbx,%rdi
  mov    %r15,%rdx
  mov    %r14,%rsi
  add    $0x2,%rbx
  call   <sscanf@plt>
  add    0x4(%rsp),%ebp
  cmp    %r12,%rbx
  jne    L39
  neg    %ebp
  movzbl %bpl,%r12d
L18:
  mov    %r12d,%edx
  lea    D9(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L19:
  xor    %r12d,%r12d
  jmp    L18
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D1: %2x%*s

tool: D9: %2X

assistant: ```c
int checksum(char asciiHex[], int from, int to, char *checksumAscii) {
  int i, sum;
  unsigned int b;
  sum = 0;
  for (i = from; i < to; i += 2) {
    sscanf(asciiHex + i, "%2x%*s", &b);
    sum += b;
  }
  sum = 0x100 - sum;
  sum &= 0xFF;
  sprintf(checksumAscii, "%2X", sum);
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checksum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x8(%rsp)
  xor    %ecx,%ecx
  cmp    %edx,%esi
  jge    L11
  lea    -0x1(%rdx),%r12d
  movslq %esi,%rcx
  lea    0x4(%rsp),%r15
  xor    %ebp,%ebp
  sub    %rsi,%r12
  lea    0x2(%rdi,%rcx,1),%rax
  lea    (%rdi,%rcx,1),%rbx
  and    $0xfffffffe,%r12d
  lea    D10(%rip),%r14
  add    %rax,%r12
  nopl   (%rax)
L34:
  mov    %rbx,%rdi
  mov    %r15,%rdx
  mov    %r14,%rsi
  add    $0x2,%rbx
  call   <sscanf@plt>
  add    0x4(%rsp),%ebp
  cmp    %r12,%rbx
  jne    L34
  neg    %ebp
  movzbl %bpl,%r12d
L18:
  mov    %r12d,%edx
  lea    D4(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L11:
  xor    %r12d,%r12d
  jmp    L18
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
data_type: string
name: disassemble_data
arguments: tag: D4
data_type: string

tool: D10: %2x%*s

tool: D4: %2X

assistant: ```c
int checksum(char asciiHex[], int from, int to, char *checksumAscii) {
  int i, sum;
  unsigned int b;
  sum = 0;
  for (i = from; i < to; i += 2) {
    sscanf(asciiHex + i, "%2x%*s", &b);
    sum += b;
  }
  sum = 0x100 - sum;
  sum &= 0xFF;
  sprintf(checksumAscii, "%2X", sum);
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<strzcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L17
L66:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L64
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
L64:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    $0x0,%eax
  jmp    L34
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L4
  mov    $0xffffffff,%eax
  jmp    L34
L4:
  mov    $0x1,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strzcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  test   %dl,%dl
  je     L9
  cmp    %cl,%dl
  jne    L9
  mov    $0x1,%eax
L41:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  test   %dl,%dl
  je     L9
  cmp    %cl,%dl
  je     L41
L9:
  mov    $0x0,%eax
  test   %cl,%cl
  je     L37
  cmp    %cl,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
L37:
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strzcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L22
  jmp    L7
  nopl   (%rax)
L18:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L7
L22:
  test   %dl,%dl
  jne    L18
L7:
  xor    %eax,%eax
  test   %cl,%cl
  je     L24
  cmp    %cl,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
L24:
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strzcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L9
  jmp    L48
  nopl   (%rax)
L34:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L48
L9:
  test   %dl,%dl
  jne    L34
L48:
  xor    %eax,%eax
  test   %cl,%cl
  je     L25
  cmp    %cl,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
L25:
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```