ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test6>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  movb   $0x20,(%rdi)
  movb   $0x7a,0x2(%rdi)
  movb   $0x7a,0x1(%rdi)
  lea    0x8(%rsp),%rsi
  mov    $0x0,%edx
  call   <strtoll@plt>
  mov    %rax,%rbp
  cmp    %rbx,0x8(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test6(char *array, char *endptr) {
  array[0] = ' ';
  array[1] = array[2] = 'z';
  long long r = strtoll(array, &endptr, 0);
  assert(array == endptr);
  assert(r == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test6>:
  endbr64
  push   %rbp
  mov    $0x7a20,%eax
  xor    %edx,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %ax,(%rdi)
  movb   $0x7a,0x2(%rdi)
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  call   <strtoll@plt>
  xor    %edi,%edi
  cmp    %rbx,0x8(%rsp)
  mov    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test6(char *array, char *endptr) {
  array[0] = ' ';
  array[1] = array[2] = 'z';
  long long r = strtoll(array, &endptr, 0);
  assert(array == endptr);
  assert(r == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test6>:
  endbr64
  push   %rbp
  mov    $0x7a20,%eax
  xor    %edx,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %ax,(%rdi)
  movb   $0x7a,0x2(%rdi)
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  call   <strtoll@plt>
  xor    %edi,%edi
  cmp    %rbx,0x8(%rsp)
  mov    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test6(char *array, char *endptr) {
  array[0] = ' ';
  array[1] = array[2] = 'z';
  long long r = strtoll(array, &endptr, 0);
  assert(array == endptr);
  assert(r == 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x4b,-0x9(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0xa00000,-0x18(%rbp)
  jle    L5
  mov    -0x18(%rbp),%rax
  lea    0x3ff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0xa,%rax
  mov    %rax,-0x18(%rbp)
  movb   $0x4d,-0x9(%rbp)
L5:
  cmpq   $0xa00000,-0x18(%rbp)
  jle    L13
  mov    -0x18(%rbp),%rax
  lea    0x3ff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0xa,%rax
  mov    %rax,-0x18(%rbp)
  movb   $0x47,-0x9(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  add    $0x200,%rax
  lea    0x3ff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0xa,%rax
  mov    %rax,-0x8(%rbp)
  movsbl -0x9(%rbp),%edi
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rsi
  mov    %rsi,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  add    %rax,%rax
  mov    %rcx,%rsi
  sub    %rax,%rsi
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %edi,%ecx
  mov    %rsi,%rdx
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: %4lld.%1lld%c

assistant: ```c
void printsize(long long n) {
  char unit = 'K';
  long long t;
  n *= 10;
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'M';
  }
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'G';
  }
  t = (n + 512) / 1024;
  printf("%4lld.%1lld%c", t / 10, t % 10, unit);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printsize>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdi,%rdi,4),%rdx
  add    %rdx,%rdx
  mov    %rdx,%rax
  mov    $0x4b,%ecx
  cmp    $0xa00000,%rdx
  jle    L13
  movabs $0x2800003ff,%rcx
  cmp    %rcx,%rdx
  jle    L8
  lea    0xfffff(%rdx),%rax
  test   %rdx,%rdx
  cmovns %rdx,%rax
  sar    $0x14,%rax
  mov    $0x47,%ecx
L13:
  lea    0x5ff(%rax),%rdi
  add    $0x200,%rax
  cmovns %rax,%rdi
  mov    %rdi,%r8
  sar    $0xa,%r8
  movsbl %cl,%ecx
  movabs $0x6666666666666667,%rdx
  mov    %r8,%rax
  imul   %rdx
  mov    %rdx,%rsi
  sar    $0x2,%rsi
  sar    $0x3f,%rdi
  sub    %rdi,%rsi
  lea    (%rsi,%rsi,4),%rax
  add    %rax,%rax
  mov    %r8,%rdx
  sub    %rax,%rdx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L8:
  mov    $0x400,%ecx
  cqto
  idiv   %rcx
  mov    $0x4d,%ecx
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D6: %4lld.%1lld%c

assistant: ```c
void printsize(long long n) {
  char unit = 'K';
  long long t;
  n *= 10;
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'M';
  }
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'G';
  }
  t = (n + 512) / 1024;
  printf("%4lld.%1lld%c", t / 10, t % 10, unit);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printsize>:
  endbr64
  lea    (%rdi,%rdi,4),%rax
  mov    $0x4b,%r8d
  add    %rax,%rax
  cmp    $0xa00000,%rax
  jle    L4
  mov    %rax,%rdx
  sar    $0xa,%rdx
  cmp    $0xa00000,%rdx
  jle    L10
  sar    $0x14,%rax
  mov    $0x47,%r8d
L4:
  lea    0x5ff(%rax),%rcx
  add    $0x200,%rax
  movabs $0x6666666666666667,%rdx
  cmovns %rax,%rcx
  mov    %rcx,%rdi
  sar    $0x3f,%rcx
  sar    $0xa,%rdi
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdx,%rsi
  mov    %rdi,%rdx
  lea    D2(%rip),%rdi
  sar    $0x2,%rsi
  sub    %rcx,%rsi
  mov    %r8d,%ecx
  lea    (%rsi,%rsi,4),%rax
  add    %rax,%rax
  sub    %rax,%rdx
  jmp    1050 <printf@plt>
L10:
  mov    %rdx,%rax
  mov    $0x4d,%r8d
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: %4lld.%1lld%c

assistant: ```c
void printsize(long long n) {
  char unit = 'K';
  long long t;
  n *= 10;
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'M';
  }
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'G';
  }
  t = (n + 512) / 1024;
  printf("%4lld.%1lld%c", t / 10, t % 10, unit);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printsize>:
  endbr64
  lea    (%rdi,%rdi,4),%rax
  mov    $0x4b,%r8d
  add    %rax,%rax
  cmp    $0xa00000,%rax
  jle    L7
  mov    %rax,%rdx
  sar    $0xa,%rdx
  cmp    $0xa00000,%rdx
  jle    L3
  sar    $0x14,%rax
  mov    $0x47,%r8d
L7:
  lea    0x5ff(%rax),%rcx
  add    $0x200,%rax
  movabs $0x6666666666666667,%rdx
  cmovns %rax,%rcx
  mov    %rcx,%rdi
  sar    $0x3f,%rcx
  sar    $0xa,%rdi
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdx,%rsi
  mov    %rdi,%rdx
  lea    D9(%rip),%rdi
  sar    $0x2,%rsi
  sub    %rcx,%rsi
  mov    %r8d,%ecx
  lea    (%rsi,%rsi,4),%rax
  add    %rax,%rax
  sub    %rax,%rdx
  jmp    1050 <printf@plt>
L3:
  mov    %rdx,%rax
  mov    $0x4d,%r8d
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: %4lld.%1lld%c

assistant: ```c
void printsize(long long n) {
  char unit = 'K';
  long long t;
  n *= 10;
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'M';
  }
  if (n > 1024 * 1024 * 10) {
    n /= 1024;
    unit = 'G';
  }
  t = (n + 512) / 1024;
  printf("%4lld.%1lld%c", t / 10, t % 10, unit);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L9:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x5,-0x8(%rbp)
  jne    L9
  cmpl   $0xa,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = 0, y = 0;
  while (x != 5) {
    y = y + x;
    x = x + 1;
  }
  assert(y == 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 0, y = 0;
  while (x != 5) {
    y = y + x;
    x = x + 1;
  }
  assert(y == 10);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 0, y = 0;
  while (x != 5) {
    y = y + x;
    x = x + 1;
  }
  assert(y == 10);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 0, y = 0;
  while (x != 5) {
    y = y + x;
    x = x + 1;
  }
  assert(y == 10);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Write32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Write32(unsigned char *pByte, unsigned long value) {
  pByte[0] = (unsigned char)value;
  pByte[1] = (unsigned char)(value >> 8);
  pByte[2] = (unsigned char)(value >> 16);
  pByte[3] = (unsigned char)(value >> 24);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Write32>:
  endbr64
  mov    %rsi,%rax
  mov    %sil,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %rsi,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x2(%rdi)
  shr    $0x18,%rax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void Write32(unsigned char *pByte, unsigned long value) {
  pByte[0] = (unsigned char)value;
  pByte[1] = (unsigned char)(value >> 8);
  pByte[2] = (unsigned char)(value >> 16);
  pByte[3] = (unsigned char)(value >> 24);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Write32>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void Write32(unsigned char *pByte, unsigned long value) {
  pByte[0] = (unsigned char)value;
  pByte[1] = (unsigned char)(value >> 8);
  pByte[2] = (unsigned char)(value >> 16);
  pByte[3] = (unsigned char)(value >> 24);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Write32>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void Write32(unsigned char *pByte, unsigned long value) {
  pByte[0] = (unsigned char)value;
  pByte[1] = (unsigned char)(value >> 8);
  pByte[2] = (unsigned char)(value >> 16);
  pByte[3] = (unsigned char)(value >> 24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_swap_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_swap_int(int *p1, int *p2) {
  int tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_swap_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ft_swap_int(int *p1, int *p2) {
  int tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_swap_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ft_swap_int(int *p1, int *p2) {
  int tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_swap_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ft_swap_int(int *p1, int *p2) {
  int tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <prnitf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: hello world!

assistant: ```c
int main(int argc, char **argv) {
  prnitf("hello world!");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <prnitf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: hello world!

assistant: ```c
int main(int argc, char **argv) {
  prnitf("hello world!");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <prnitf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: hello world!

assistant: ```c
int main(int argc, char **argv) {
  prnitf("hello world!");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <prnitf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: hello world!

assistant: ```c
int main(int argc, char **argv) {
  prnitf("hello world!");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L44
L39:
  movl   $0x1,-0xc(%rbp)
  jmp    L23
L69:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L69
  movl   $0x1,-0xc(%rbp)
  jmp    L67
L21:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L67:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L21
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L44:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D39
type: string
name: unpack_data
arguments: tag: D27
type: string

tool: D4: %d

tool: D0:  

tool: D39: #

tool: D27: 


assistant: ```c
int main() {
  int n;
  int i, j;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n - i; j++) {
      printf(" ");
    }
    for (j = 1; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebp
  lea    D37(%rip),%r13
  lea    D16(%rip),%r12
  lea    D0(%rip),%r14
  cmpl   $0x0,0x4(%rsp)
  jg     L4
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L6
L44:
  test   %ebp,%ebp
  jle    L69
  mov    $0x1,%ebx
L8:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L8
L69:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jl     L0
L4:
  mov    $0x1,%ebx
  cmp    %ebp,0x4(%rsp)
  jg     L6
  jmp    L44
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D38
data_type: string
name: disassemble_data
arguments: label: D37
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D38: %d

tool: D37:  

tool: D16: #

tool: D0: 


assistant: ```c
int main() {
  int n;
  int i, j;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n - i; j++) {
      printf(" ");
    }
    for (j = 1; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D30(%rip),%rdi
  lea    D38(%rip),%r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L34
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L38
  nopl   0x0(%rax)
L27:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L27
L38:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L4
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jge    L16
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_infered: string
name: extract_symbolic_data
arguments: tag: D38
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D37
type_infered: string

tool: D30: %d

tool: D38: 


tool: D10: #

tool: D37:  

assistant: ```c
int main() {
  int n;
  int i, j;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n - i; j++) {
      printf(" ");
    }
    for (j = 1; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D8(%rip),%rdi
  lea    D7(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D36(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L32
  nopl   0x0(%rax,%rax,1)
L33:
  mov    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L26
  nopl   0x0(%rax)
L56:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L56
L26:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L23
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jge    L33
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D7
data_type: string
name: unpack_data
arguments: tag: D25
data_type: string
name: unpack_data
arguments: tag: D36
data_type: string

tool: D8: %d

tool: D7: 


tool: D25: #

tool: D36:  

assistant: ```c
int main() {
  int n;
  int i, j;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n - i; j++) {
      printf(" ");
    }
    for (j = 1; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x80,%esi
  mov    $0x1312d00,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x1312d00,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    $0x1312d00,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D3: ERROR allocating %d


tool: D13: Currently allocating %d


assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  int count = 0;
  myblock = (void *)calloc(20000000, 128);
  if (!myblock) {
    printf("ERROR allocating %d\n", 20000000);
  }
  printf("Currently allocating %d\n", 20000000);
  free(myblock);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x80,%esi
  mov    $0x1312d00,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L8:
  mov    $0x1312d00,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L10:
  mov    $0x1312d00,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D0: Currently allocating %d


tool: D12: ERROR allocating %d


assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  int count = 0;
  myblock = (void *)calloc(20000000, 128);
  if (!myblock) {
    printf("ERROR allocating %d\n", 20000000);
  }
  printf("Currently allocating %d\n", 20000000);
  free(myblock);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80,%esi
  mov    $0x1312d00,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L2
L18:
  mov    $0x1312d00,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  mov    $0x1312d00,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string

tool: D12: Currently allocating %d


tool: D17: ERROR allocating %d


assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  int count = 0;
  myblock = (void *)calloc(20000000, 128);
  if (!myblock) {
    printf("ERROR allocating %d\n", 20000000);
  }
  printf("Currently allocating %d\n", 20000000);
  free(myblock);
  exit(0);
}
```