ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<computeGradientOfBarycentricTriangle>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  call   <computeNormal2EdgeOfTriangle@plt>
  movss  0x0(%rbp),%xmm0
  subss  (%rbx),%xmm0
  movss  %xmm0,(%rsp)
  movss  0x4(%rbp),%xmm0
  subss  0x4(%rbx),%xmm0
  movss  %xmm0,0x4(%rsp)
  movss  0x8(%rbp),%xmm0
  subss  0x8(%rbx),%xmm0
  movss  %xmm0,0x8(%rsp)
  mov    %rsp,%rdi
  call   <magnitudeVector@plt>
  cvtss2sd %xmm0,%xmm0
  mulsd  D0(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%r12)
  pxor   %xmm1,%xmm1
  cvtss2sd 0x10(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x4(%r12)
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x8(%r12)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: f64

tool: D0: 0.5

assistant: ```c
void computeGradientOfBarycentricTriangle(const float *v0, const float *v1, const float *v2, float *grad) {
  float v0v1[3], norm2edge[3];
  float base;
  computeNormal2EdgeOfTriangle(v0, v1, v2, norm2edge);
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  base = magnitudeVector(v0v1);
  grad[0] = 0.5 * base * norm2edge[0];
  grad[1] = 0.5 * base * norm2edge[1];
  grad[2] = 0.5 * base * norm2edge[2];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<computeGradientOfBarycentricTriangle>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  call   <computeNormal2EdgeOfTriangle@plt>
  movss  0x0(%rbp),%xmm0
  subss  (%rbx),%xmm0
  mov    %rsp,%rdi
  movss  %xmm0,(%rsp)
  movss  0x4(%rbp),%xmm0
  subss  0x4(%rbx),%xmm0
  movss  %xmm0,0x4(%rsp)
  movss  0x8(%rbp),%xmm0
  subss  0x8(%rbx),%xmm0
  movss  %xmm0,0x8(%rsp)
  call   <magnitudeVector@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  D4(%rip),%xmm0
  cvtss2sd 0xc(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%r12)
  pxor   %xmm1,%xmm1
  cvtss2sd 0x10(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x4(%r12)
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x8(%r12)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: f64

tool: D4: 0.5

assistant: ```c
void computeGradientOfBarycentricTriangle(const float *v0, const float *v1, const float *v2, float *grad) {
  float v0v1[3], norm2edge[3];
  float base;
  computeNormal2EdgeOfTriangle(v0, v1, v2, norm2edge);
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  base = magnitudeVector(v0v1);
  grad[0] = 0.5 * base * norm2edge[0];
  grad[1] = 0.5 * base * norm2edge[1];
  grad[2] = 0.5 * base * norm2edge[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<computeGradientOfBarycentricTriangle>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  call   <computeNormal2EdgeOfTriangle@plt>
  movq   (%rbx),%xmm1
  movq   0x0(%rbp),%xmm0
  lea    0x8(%rsp),%rdi
  subps  %xmm1,%xmm0
  movlps %xmm0,0x8(%rsp)
  movss  0x8(%rbp),%xmm0
  subss  0x8(%rbx),%xmm0
  movss  %xmm0,0x10(%rsp)
  call   <magnitudeVector@plt>
  movq   0x18(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  D5(%rip),%xmm0
  cvtps2pd %xmm1,%xmm1
  movapd %xmm0,%xmm2
  unpcklpd %xmm2,%xmm2
  mulpd  %xmm2,%xmm1
  cvtpd2ps %xmm1,%xmm1
  movlps %xmm1,(%r12)
  pxor   %xmm1,%xmm1
  cvtss2sd 0x20(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x8(%r12)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: f64

tool: D5: 0.5

assistant: ```c
void computeGradientOfBarycentricTriangle(const float *v0, const float *v1, const float *v2, float *grad) {
  float v0v1[3], norm2edge[3];
  float base;
  computeNormal2EdgeOfTriangle(v0, v1, v2, norm2edge);
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  base = magnitudeVector(v0v1);
  grad[0] = 0.5 * base * norm2edge[0];
  grad[1] = 0.5 * base * norm2edge[1];
  grad[2] = 0.5 * base * norm2edge[2];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<conver_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  cmp    $0x18,%eax
  ja     L39
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D12(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  jmp    L88
  mov    $0x3,%eax
  jmp    L88
  mov    $0x4,%eax
  jmp    L88
  mov    $0x5,%eax
  jmp    L88
  mov    $0x6,%eax
  jmp    L88
  mov    $0x7,%eax
  jmp    L88
  mov    $0x8,%eax
  jmp    L88
  mov    $0x9,%eax
  jmp    L88
L39:
  mov    $0x0,%eax
L88:
  pop    %rbp
  ret
```

assistant: ```c
int conver_num(char c) {
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
    return 2;
  case 'D':
  case 'E':
  case 'F':
    return 3;
  case 'G':
  case 'H':
  case 'I':
    return 4;
  case 'J':
  case 'K':
  case 'L':
    return 5;
  case 'M':
  case 'N':
  case 'O':
    return 6;
  case 'P':
  case 'R':
  case 'S':
    return 7;
  case 'T':
  case 'U':
  case 'V':
    return 8;
  case 'W':
  case 'X':
  case 'Y':
    return 9;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<conver_num>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x18,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
  mov    $0x2,%eax
  ret
```

assistant: ```c
int conver_num(char c) {
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
    return 2;
  case 'D':
  case 'E':
  case 'F':
    return 3;
  case 'G':
  case 'H':
  case 'I':
    return 4;
  case 'J':
  case 'K':
  case 'L':
    return 5;
  case 'M':
  case 'N':
  case 'O':
    return 6;
  case 'P':
  case 'R':
  case 'S':
    return 7;
  case 'T':
  case 'U':
  case 'V':
    return 8;
  case 'W':
  case 'X':
  case 'Y':
    return 9;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<conver_num>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x18,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L1:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: 

assistant: ```c
int conver_num(char c) {
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
    return 2;
  case 'D':
  case 'E':
  case 'F':
    return 3;
  case 'G':
  case 'H':
  case 'I':
    return 4;
  case 'J':
  case 'K':
  case 'L':
    return 5;
  case 'M':
  case 'N':
  case 'O':
    return 6;
  case 'P':
  case 'R':
  case 'S':
    return 7;
  case 'T':
  case 'U':
  case 'V':
    return 8;
  case 'W':
  case 'X':
  case 'Y':
    return 9;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<conver_num>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x18,%dil
  ja     L2
  movzbl %dil,%edi
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: 

assistant: ```c
int conver_num(char c) {
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
    return 2;
  case 'D':
  case 'E':
  case 'F':
    return 3;
  case 'G':
  case 'H':
  case 'I':
    return 4;
  case 'J':
  case 'K':
  case 'L':
    return 5;
  case 'M':
  case 'N':
  case 'O':
    return 6;
  case 'P':
  case 'R':
  case 'S':
    return 7;
  case 'T':
  case 'U':
  case 'V':
    return 8;
  case 'W':
  case 'X':
  case 'Y':
    return 9;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L67
L61:
  movl   $0x0,-0x14(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L16
L9:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L73
  addl   $0x1,-0x14(%rbp)
  jmp    L76
L73:
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0xc(%rbp)
  jle    L9
L76:
  cmpl   $0x0,-0x14(%rbp)
  jne    L58
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L48
L58:
  subl   $0x1,-0x10(%rbp)
L67:
  cmpl   $0x1,-0x10(%rbp)
  jg     L61
L48:
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_infered: string
name: extract_symbolic_data
arguments: label: D24
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D22: digite um nume:

tool: D24: %i

tool: D5: O maior numero primo entre 0 e %d sera %d

assistant: ```c
int main() {
  int num, aux, cont;
  aux = 0;
  printf("digite um nume:\n");
  scanf("%i", &num);
  for (int i = num; i >= 2; --i) {
    cont = 0;
    for (int j = 2; j < sqrt(i) + 1; ++j) {
      if (i % j == 0) {
        cont++;
        break;
      }
    }
    if (cont == 0) {
      aux = i;
      break;
    }
  }
  printf("O maior numero primo entre 0 e %d sera %d", num, aux);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cmp    $0x1,%ebp
  jg     L42
  mov    $0x0,%ebp
  jmp    L11
L14:
  sub    $0x1,%ebp
  cmp    $0x1,%ebp
  je     L41
L42:
  mov    $0x2,%ebx
L64:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L11
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L14
  add    $0x1,%ebx
  jmp    L64
L41:
  mov    %edx,%ebp
L11:
  mov    %ebp,%edx
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string

tool: D0: digite um nume:

tool: D1: %i

tool: D2: O maior numero primo entre 0 e %d sera %d

assistant: ```c
int main() {
  int num, aux, cont;
  aux = 0;
  printf("digite um nume:\n");
  scanf("%i", &num);
  for (int i = num; i >= 2; --i) {
    cont = 0;
    for (int j = 2; j < sqrt(i) + 1; ++j) {
      if (i % j == 0) {
        cont++;
        break;
      }
    }
    if (cont == 0) {
      aux = i;
      break;
    }
  }
  printf("O maior numero primo entre 0 e %d sera %d", num, aux);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%r12d
  cmp    $0x1,%esi
  jle    L12
  nopl   0x0(%rax)
L32:
  mov    $0x2,%ebx
  jmp    L0
  nop
L14:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L40
  add    $0x1,%ebx
L0:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L14
  mov    0x4(%rsp),%esi
L20:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  sub    $0x1,%r12d
  cmp    $0x1,%r12d
  jne    L32
  mov    0x4(%rsp),%esi
L12:
  xor    %r12d,%r12d
  jmp    L20
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D29: digite um nume:

tool: D19: %i

tool: D9: O maior numero primo entre 0 e %d sera %d

assistant: ```c
int main() {
  int num, aux, cont;
  aux = 0;
  printf("digite um nume:\n");
  scanf("%i", &num);
  for (int i = num; i >= 2; --i) {
    cont = 0;
    for (int j = 2; j < sqrt(i) + 1; ++j) {
      if (i % j == 0) {
        cont++;
        break;
      }
    }
    if (cont == 0) {
      aux = i;
      break;
    }
  }
  printf("O maior numero primo entre 0 e %d sera %d", num, aux);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%r12d
  cmp    $0x1,%esi
  jle    L11
  nopl   0x0(%rax)
L22:
  mov    $0x2,%ebx
  jmp    L55
  nop
L6:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L36
  add    $0x1,%ebx
L55:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L6
  mov    0x4(%rsp),%esi
L17:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  sub    $0x1,%r12d
  cmp    $0x1,%r12d
  jne    L22
  mov    0x4(%rsp),%esi
L11:
  xor    %r12d,%r12d
  jmp    L17
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D25
data_type: string

tool: D18: digite um nume:

tool: D10: %i

tool: D25: O maior numero primo entre 0 e %d sera %d

assistant: ```c
int main() {
  int num, aux, cont;
  aux = 0;
  printf("digite um nume:\n");
  scanf("%i", &num);
  for (int i = num; i >= 2; --i) {
    cont = 0;
    for (int j = 2; j < sqrt(i) + 1; ++j) {
      if (i % j == 0) {
        cont++;
        break;
      }
    }
    if (cont == 0) {
      aux = i;
      break;
    }
  }
  printf("O maior numero primo entre 0 e %d sera %d", num, aux);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xfa,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L9
L14:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <get_num_divisors@plt>
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main() {
  int last = 500 >> 1;
  int num = 0;
  int i = 0;
  int j = 1;
  while (num < last) {
    i = i + j;
    num = get_num_divisors(i);
    j++;
  }
  printf("%d\n", i);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebp
  mov    $0x0,%ebx
L2:
  add    %ebp,%ebx
  mov    %ebx,%edi
  call   <get_num_divisors@plt>
  add    $0x1,%ebp
  cmp    $0xf9,%eax
  jle    L2
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int last = 500 >> 1;
  int num = 0;
  int i = 0;
  int j = 1;
  while (num < last) {
    i = i + j;
    num = get_num_divisors(i);
    j++;
  }
  printf("%d\n", i);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  add    %ebx,%ebp
  add    $0x1,%ebx
  mov    %ebp,%edi
  call   <get_num_divisors@plt>
  cmp    $0xf9,%eax
  jle    L0
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: %d


assistant: ```c
int main() {
  int last = 500 >> 1;
  int num = 0;
  int i = 0;
  int j = 1;
  while (num < last) {
    i = i + j;
    num = get_num_divisors(i);
    j++;
  }
  printf("%d\n", i);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  add    %ebx,%ebp
  add    $0x1,%ebx
  mov    %ebp,%edi
  call   <get_num_divisors@plt>
  cmp    $0xf9,%eax
  jle    L8
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main() {
  int last = 500 >> 1;
  int num = 0;
  int i = 0;
  int j = 1;
  while (num < last) {
    i = i + j;
    num = get_num_divisors(i);
    j++;
  }
  printf("%d\n", i);
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcpy_strlen_Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x74736574,-0x17(%rbp)
  movb   $0x0,-0x13(%rbp)
  lea    -0x17(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movl   $0x0,-0x30(%rbp,%rax,4)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void strcpy_strlen_Bad() {
  char src[5] = "test";
  char dst[10];
  strcpy(dst, src);
  int a[4];
  a[strlen(dst)] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcpy_strlen_Bad>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x74736574,0x9(%rsp)
  movb   $0x0,0xd(%rsp)
  lea    0x9(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strcpy_strlen_Bad() {
  char src[5] = "test";
  char dst[10];
  strcpy(dst, src);
  int a[4];
  a[strlen(dst)] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy_strlen_Bad>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  movl   $0x74736574,0x9(%rsp)
  movb   $0x0,0xd(%rsp)
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strcpy_strlen_Bad() {
  char src[5] = "test";
  char dst[10];
  strcpy(dst, src);
  int a[4];
  a[strlen(dst)] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcpy_strlen_Bad>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  movl   $0x74736574,0x9(%rsp)
  movb   $0x0,0xd(%rsp)
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strcpy_strlen_Bad() {
  char src[5] = "test";
  char dst[10];
  strcpy(dst, src);
  int a[4];
  a[strlen(dst)] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L4:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L4
  nop
L30:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L37
  cmpl   $0x18,-0x18(%rbp)
  jle    L30
L37:
  subl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
datatype: string

tool: D9: Name: 

assistant: ```c
int get_name(char name[]) {
  int err = 0;
  int i = 0;
  printf("Name: ");
  while (isspace(name[i] = getchar()) || i++)
    ;
  for (i = i; ((name[i++] = getchar()) != '\n') && i < 25;)
    ;
  name[--i] = '\0';
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_name>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  movsbl %al,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  lea    0x1(%rbx),%rdi
  mov    %rdi,%rbx
  mov    $0x2,%ebp
  sub    %edi,%ebp
L12:
  mov    %rbx,%r12
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  lea    0x0(%rbp,%rbx,1),%edx
  cmp    $0x18,%edx
  setle  %dl
  cmp    $0xa,%al
  setne  %al
  add    $0x1,%rbx
  test   %al,%dl
  jne    L12
  movb   $0x0,(%r12)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: Name: 

assistant: ```c
int get_name(char name[]) {
  int err = 0;
  int i = 0;
  printf("Name: ");
  while (isspace(name[i] = getchar()) || i++)
    ;
  for (i = i; ((name[i++] = getchar()) != '\n') && i < 25;)
    ;
  name[--i] = '\0';
  return err;
}
```