ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<perm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L66
  mov    $0x7b,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L40
L65:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L65
  mov    $0x7d,%edi
  call   <putchar@plt>
  jmp    L64
L66:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L23
L78:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L46
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L46:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <perm>
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L71
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L71:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L78
L64:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: %d 

assistant: ```c
void perm(int list[], int min_index, int count) {
  if (min_index == count - 1) {
    putchar('{');
    for (int i = 0; i < count; i++)
      printf("%d ", list[i]);
    putchar('}');
  } else {
    for (int i = min_index; i < count; i++) {
      int t;
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
      perm(list, min_index + 1, count);
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<perm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r14d
  lea    -0x1(%rdx),%eax
  cmp    %esi,%eax
  je     L44
  mov    %esi,%r12d
  cmp    %esi,%edx
  jle    L58
  movslq %esi,%rbx
  lea    (%rdi,%rbx,4),%r13
  mov    %edx,%eax
  sub    %esi,%eax
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r15
  lea    0x1(%rsi),%eax
  mov    %eax,0xc(%rsp)
  jmp    L18
L44:
  mov    $0x7b,%edi
  call   <putchar@plt>
  test   %r14d,%r14d
  jle    L0
  mov    %rbp,%rbx
  lea    -0x1(%r14),%eax
  lea    0x4(%rbp,%rax,4),%r12
  lea    D4(%rip),%rbp
L41:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L41
L0:
  mov    $0x7d,%edi
  call   <putchar@plt>
L58:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    0x0(%r13),%eax
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %edx,0x0(%r13)
  mov    %eax,0x0(%rbp,%rbx,4)
  mov    %r14d,%edx
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <perm>
  mov    0x0(%r13),%eax
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %edx,0x0(%r13)
  mov    %eax,0x0(%rbp,%rbx,4)
L32:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L58
L18:
  cmp    %ebx,%r12d
  jne    L25
  mov    %r14d,%edx
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <perm>
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %d 

assistant: ```c
void perm(int list[], int min_index, int count) {
  if (min_index == count - 1) {
    putchar('{');
    for (int i = 0; i < count; i++)
      printf("%d ", list[i]);
    putchar('}');
  } else {
    for (int i = min_index; i < count; i++) {
      int t;
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
      perm(list, min_index + 1, count);
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<perm>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x1(%rdx),%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  cmp    %esi,%ebp
  je     L6
  mov    %esi,%r13d
  cmp    %esi,%edx
  jle    L42
  mov    %edx,%ecx
  movslq %esi,%rbp
  sub    %esi,%ecx
  lea    0x1(%rbp),%r12
  lea    (%rdi,%rbp,4),%r15
  lea    -0x1(%rcx),%eax
  add    %r12,%rax
  mov    %rax,(%rsp)
  lea    0x1(%rsi),%eax
  mov    %eax,0xc(%rsp)
  cmp    %ebp,%r13d
  je     L54
L77:
  mov    (%rbx,%rbp,4),%esi
  mov    (%r15),%ecx
  mov    %r14d,%edx
  mov    %rbx,%rdi
  mov    %esi,(%r15)
  mov    0xc(%rsp),%esi
  mov    %ecx,(%rbx,%rbp,4)
  call   <perm>
  mov    (%rbx,%rbp,4),%esi
  mov    (%r15),%ecx
  mov    %esi,(%r15)
  mov    %ecx,(%rbx,%rbp,4)
  mov    %r12,%rbp
  cmp    (%rsp),%r12
  je     L42
L68:
  add    $0x1,%r12
  cmp    %ebp,%r13d
  jne    L77
L54:
  mov    0xc(%rsp),%esi
  mov    %r14d,%edx
  mov    %rbx,%rdi
  mov    %r12,%rbp
  call   <perm>
  cmp    (%rsp),%r12
  jne    L68
L42:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L6:
  mov    $0x7b,%edi
  lea    0x4(%rbx,%rbp,4),%r12
  lea    D1(%rip),%rbp
  call   <putchar@plt>
  test   %r14d,%r14d
  jle    L53
  nopl   0x0(%rax,%rax,1)
L38:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L38
L53:
  add    $0x18,%rsp
  mov    $0x7d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: %d 

assistant: ```c
void perm(int list[], int min_index, int count) {
  if (min_index == count - 1) {
    putchar('{');
    for (int i = 0; i < count; i++)
      printf("%d ", list[i]);
    putchar('}');
  } else {
    for (int i = min_index; i < count; i++) {
      int t;
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
      perm(list, min_index + 1, count);
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<perm>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x1(%rdx),%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  cmp    %esi,%ebp
  je     L30
  mov    %esi,%r13d
  cmp    %esi,%edx
  jle    L73
  mov    %edx,%ecx
  movslq %esi,%rbp
  lea    0x1(%rsi),%eax
  sub    %esi,%ecx
  mov    %eax,0xc(%rsp)
  lea    0x1(%rbp),%r12
  lea    (%rdi,%rbp,4),%r15
  lea    -0x1(%rcx),%eax
  add    %r12,%rax
  mov    %rax,(%rsp)
  cmp    %ebp,%r13d
  je     L78
L21:
  mov    (%rbx,%rbp,4),%esi
  mov    (%r15),%ecx
  mov    %r14d,%edx
  mov    %rbx,%rdi
  mov    %esi,(%r15)
  mov    0xc(%rsp),%esi
  mov    %ecx,(%rbx,%rbp,4)
  call   <perm>
  mov    (%rbx,%rbp,4),%esi
  mov    (%r15),%ecx
  mov    %esi,(%r15)
  mov    %ecx,(%rbx,%rbp,4)
  mov    %r12,%rbp
  cmp    (%rsp),%r12
  je     L73
L31:
  add    $0x1,%r12
  cmp    %ebp,%r13d
  jne    L21
L78:
  mov    0xc(%rsp),%esi
  mov    %r14d,%edx
  mov    %rbx,%rdi
  mov    %r12,%rbp
  call   <perm>
  cmp    (%rsp),%r12
  jne    L31
L73:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L30:
  mov    $0x7b,%edi
  lea    0x4(%rbx,%rbp,4),%r12
  lea    D9(%rip),%rbp
  call   <putchar@plt>
  test   %r14d,%r14d
  jle    L1
  nopl   0x0(%rax,%rax,1)
L64:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L64
L1:
  add    $0x18,%rsp
  mov    $0x7d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: %d 

assistant: ```c
void perm(int list[], int min_index, int count) {
  if (min_index == count - 1) {
    putchar('{');
    for (int i = 0; i < count; i++)
      printf("%d ", list[i]);
    putchar('}');
  } else {
    for (int i = min_index; i < count; i++) {
      int t;
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
      perm(list, min_index + 1, count);
      if (i != min_index) {
        t = list[min_index];
        list[min_index] = list[i];
        list[i] = t;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1f5c(%rbp)
  jmp    L85
L23:
  mov    -0x1f5c(%rbp),%eax
  cltq
  mov    -0x1f5c(%rbp),%edx
  mov    %edx,-0x1f50(%rbp,%rax,4)
  addl   $0x1,-0x1f5c(%rbp)
L85:
  cmpl   $0x3e7,-0x1f5c(%rbp)
  jle    L23
  movl   $0x0,-0x1f58(%rbp)
  jmp    L1
L27:
  mov    -0x1f58(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <add_one@plt>
  mov    %eax,%edi
  call   <add_one@plt>
  mov    -0x1f58(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0xfb0(%rbp,%rdx,4)
  addl   $0x1,-0x1f58(%rbp)
L1:
  cmpl   $0x3e6,-0x1f58(%rbp)
  jle    L27
  movl   $0x0,-0x1f54(%rbp)
  jmp    L66
L25:
  mov    -0x1f54(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0x1f54(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  add    $0x2,%eax
  cmp    %eax,%edx
  je     L10
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L10:
  addl   $0x1,-0x1f54(%rbp)
L66:
  cmpl   $0x3e6,-0x1f54(%rbp)
  jle    L25
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
int main() {
  int a[1000], b[1000];
  for (int i = 0; i < 1000; ++i)
    a[i] = i;
#pragma scop
  for (int i = 0; i < 999; ++i)
    b[i] = add_one(add_one(a[i]));
#pragma endscop
  for (int i = 0; i < 999; ++i)
    if (b[i] != a[i] + 2)
      return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
L36:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L36
  mov    $0x0,%ebx
L18:
  mov    (%rsp,%rbx,1),%edi
  call   <add_one@plt>
  mov    %eax,%edi
  call   <add_one@plt>
  mov    %eax,0xfa0(%rsp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0xf9c,%rbx
  jne    L18
  mov    $0x0,%eax
  lea    0xfa0(%rsp),%rcx
L45:
  mov    (%rsp,%rax,1),%esi
  lea    0x2(%rsi),%edx
  cmp    %edx,(%rax,%rcx,1)
  jne    L19
  add    $0x4,%rax
  cmp    $0xf9c,%rax
  jne    L45
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L25
L19:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
L25:
  mov    0x1f48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x1f50,%rsp
  pop    %rbx
  ret
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[1000], b[1000];
  for (int i = 0; i < 1000; ++i)
    a[i] = i;
#pragma scop
  for (int i = 0; i < 999; ++i)
    b[i] = add_one(add_one(a[i]));
#pragma endscop
  for (int i = 0; i < 999; ++i)
    if (b[i] != a[i] + 2)
      return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L35:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L35
  xor    %ebx,%ebx
  lea    0xfa0(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp,%rbx,1),%edi
  call   <add_one@plt>
  mov    %eax,%edi
  call   <add_one@plt>
  mov    %eax,(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0xf9c,%rbx
  jne    L10
  xor    %eax,%eax
  jmp    L58
  nopl   (%rax)
L47:
  add    $0x4,%rax
  cmp    $0xf9c,%rax
  je     L45
L58:
  mov    0x0(%rbp,%rax,1),%ecx
  lea    0x2(%rcx),%edx
  cmp    %edx,(%r12,%rax,1)
  je     L47
  mov    D7(%rip),%rax
  mov    (%rax),%eax
L68:
  mov    0x1f48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x1f50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  jmp    L68
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[1000], b[1000];
  for (int i = 0; i < 1000; ++i)
    a[i] = i;
#pragma scop
  for (int i = 0; i < 999; ++i)
    b[i] = add_one(add_one(a[i]));
#pragma endscop
  for (int i = 0; i < 999; ++i)
    if (b[i] != a[i] + 2)
      return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below?

```asm
<build_request_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x12,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %ax,-0x36(%rbp)
  movq   $0x1000001,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  lea    -0x36(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  addq   $0x2,-0x30(%rbp)
  lea    -0x12(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  addq   $0xa,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L22
L18:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %al,-0x37(%rbp)
  lea    -0x37(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  addq   $0x1,-0x30(%rbp)
  movzbl -0x37(%rbp),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
  movzbl -0x37(%rbp),%eax
  movsbq %al,%rax
  add    %rax,-0x30(%rbp)
L22:
  cmpq   $0x0,-0x28(%rbp)
  jne    L18
  addq   $0x1,-0x30(%rbp)
  movl   $0x1000100,-0x16(%rbp)
  lea    -0x16(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x50(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: .

assistant: ```c
char *build_request_data(char *hostname, int *ret_size) {
  int size = 12 + strlen(hostname) + 1 + 1 + 4;
  char *buffer = (char *)malloc(size);
  char *pbuf = buffer;
  bzero(buffer, size);
  unsigned short seq = rand();
  char header[] = {0x01, 0x00, 0x00, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  memcpy(pbuf, &seq, 2);
  pbuf += 2;
  memcpy(pbuf, header, 10);
  pbuf += 10;
  char *pstr = strtok(hostname, ".");
  while (pstr != NULL) {
    char len = strlen(pstr);
    memcpy(pbuf, &len, 1);
    pbuf += 1;
    memcpy(pbuf, pstr, len);
    pstr = strtok(NULL, ".");
    pbuf += len;
  }
  pbuf += 1;
  char extra_data[] = {0x00, 0x01, 0x00, 0x01};
  memcpy(pbuf, extra_data, 4);
  *ret_size = size;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<build_request_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x12(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %ax,0x8(%rsp)
  movq   $0x1000001,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  lea    0x8(%rsp),%rsi
  mov    $0x2,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  lea    0xe(%rsp),%rsi
  lea    0x2(%r12),%rdi
  mov    $0xa,%edx
  mov    $0x0,%eax
  call   <memcpy@plt>
  lea    0xc(%r12),%rbp
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  lea    D11(%rip),%r15
L23:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %al,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  add    $0x1,%rbp
  movsbl 0x7(%rsp),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    %r15,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  movsbq 0x7(%rsp),%rdi
  add    %rdi,%rbp
  test   %rax,%rax
  jne    L23
L18:
  movl   $0x1000100,0xa(%rsp)
  lea    0xa(%rsp),%rsi
  lea    0x1(%rbp),%rdi
  mov    $0x4,%edx
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    %r13d,(%r14)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %r12,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: string

tool: D11: .

assistant: ```c
char *build_request_data(char *hostname, int *ret_size) {
  int size = 12 + strlen(hostname) + 1 + 1 + 4;
  char *buffer = (char *)malloc(size);
  char *pbuf = buffer;
  bzero(buffer, size);
  unsigned short seq = rand();
  char header[] = {0x01, 0x00, 0x00, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  memcpy(pbuf, &seq, 2);
  pbuf += 2;
  memcpy(pbuf, header, 10);
  pbuf += 10;
  char *pstr = strtok(hostname, ".");
  while (pstr != NULL) {
    char len = strlen(pstr);
    memcpy(pbuf, &len, 1);
    pbuf += 1;
    memcpy(pbuf, pstr, len);
    pstr = strtok(NULL, ".");
    pbuf += len;
  }
  pbuf += 1;
  char extra_data[] = {0x00, 0x01, 0x00, 0x01};
  memcpy(pbuf, extra_data, 4);
  *ret_size = size;
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<build_request_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x12(%rax),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <bzero@plt>
  xor    %eax,%eax
  lea    0xc(%r13),%rbx
  call   <rand@plt>
  lea    0x18(%rsp),%rsi
  mov    $0x2,%edx
  mov    %r13,%rdi
  mov    %ax,0x18(%rsp)
  xor    %eax,%eax
  mov    %ax,0x26(%rsp)
  xor    %eax,%eax
  movq   $0x1000001,0x1e(%rsp)
  call   <memcpy@plt>
  lea    0x1e(%rsp),%rsi
  lea    0x2(%r13),%rdi
  xor    %eax,%eax
  mov    $0xa,%edx
  call   <memcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%r15
  lea    0x17(%rsp),%r12
  nopl   0x0(%rax)
L8:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %al,0x17(%rsp)
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r15
  movsbq 0x17(%rsp),%rax
  add    %rax,%rbx
  test   %r15,%r15
  jne    L8
L12:
  lea    0x1a(%rsp),%rsi
  lea    0x1(%rbx),%rdi
  mov    $0x4,%edx
  xor    %eax,%eax
  movl   $0x1000100,0x1a(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: .

assistant: ```c
char *build_request_data(char *hostname, int *ret_size) {
  int size = 12 + strlen(hostname) + 1 + 1 + 4;
  char *buffer = (char *)malloc(size);
  char *pbuf = buffer;
  bzero(buffer, size);
  unsigned short seq = rand();
  char header[] = {0x01, 0x00, 0x00, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  memcpy(pbuf, &seq, 2);
  pbuf += 2;
  memcpy(pbuf, header, 10);
  pbuf += 10;
  char *pstr = strtok(hostname, ".");
  while (pstr != NULL) {
    char len = strlen(pstr);
    memcpy(pbuf, &len, 1);
    pbuf += 1;
    memcpy(pbuf, pstr, len);
    pstr = strtok(NULL, ".");
    pbuf += len;
  }
  pbuf += 1;
  char extra_data[] = {0x00, 0x01, 0x00, 0x01};
  memcpy(pbuf, extra_data, 4);
  *ret_size = size;
  return buffer;
}
```