user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D86(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x34(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x34(%rsp),%eax
  mov    %eax,0x10(%rsp)
  test   $0x1,%al
  jne    L99
  add    $0x1,%eax
  mov    %eax,0x34(%rsp)
  mov    %eax,0x10(%rsp)
L99:
  mov    0x10(%rsp),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  mov    %eax,0x2c(%rsp)
  mov    %eax,%ecx
  mov    %esi,%eax
  test   %esi,%esi
  jle    L43
  sar    $0x2,%esi
  mov    %ecx,0x14(%rsp)
  xor    %r12d,%r12d
  mov    $0x1,%ebp
  mov    %esi,0x18(%rsp)
  lea    D105(%rip),%r15
  lea    D103(%rip),%r13
  nopl   0x0(%rax)
L188:
  mov    0x14(%rsp),%esi
  xor    %ebx,%ebx
  lea    0x1(%rsi),%ecx
  mov    %ecx,0xc(%rsp)
  jmp    L211
  nopw   0x0(%rax,%rax,1)
L114:
  add    $0x2,%eax
  cmp    %ebx,%eax
  je     L173
L150:
  cmp    %ebx,0xc(%rsp)
  je     L171
L319:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x34(%rsp),%eax
  lea    (%rax,%rax,1),%edx
  cmp    %ebx,%edx
  jl     L286
L211:
  cmp    %ebx,%r12d
  jne    L114
  lea    D45(%rip),%rdi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jne    L319
L171:
  test   %ebp,%ebp
  jle    L319
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L222:
  mov    %r13,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,%ebp
  jne    L222
  add    %ebp,%ebx
  jmp    L319
  nopl   (%rax)
L173:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L150
  xchg   %ax,%ax
L286:
  mov    0x14(%rsp),%edx
  mov    0x18(%rsp),%ebx
  lea    D9(%rip),%rdi
  sub    $0x1,%edx
  cmp    %r12d,%ebx
  cmovle 0xc(%rsp),%edx
  sub    $0x1,%eax
  mov    %eax,0x34(%rsp)
  add    $0x1,%r12d
  mov    %edx,0x14(%rsp)
  call   <printf@plt>
  mov    0x34(%rsp),%eax
  cmp    %r12d,%eax
  jle    L266
  lea    -0x2(%rbp),%edx
  add    $0x2,%ebp
  cmp    %r12d,%ebx
  cmovl  %edx,%ebp
  jmp    L188
L43:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L266:
  cmpl   $0x1,0x10(%rsp)
  jle    L43
  mov    0x10(%rsp),%eax
  mov    0x2c(%rsp),%esi
  movl   $0x1,0x14(%rsp)
  mov    $0x1,%ebp
  movl   $0x0,0x18(%rsp)
  lea    D103(%rip),%r12
  sar    $0x2,%eax
  mov    %esi,0x20(%rsp)
  lea    0x1(%rsi),%r13d
  mov    %eax,0x24(%rsp)
  mov    $0x1,%eax
  sub    %esi,%eax
  mov    %eax,0x1c(%rsp)
  nopw   0x0(%rax,%rax,1)
L303:
  mov    0x20(%rsp),%eax
  xor    %ebx,%ebx
  add    $0x2,%eax
  mov    %eax,0xc(%rsp)
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L276:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jle    L201
L56:
  cmp    %ebx,%r13d
  je     L219
L6:
  cmp    %ebx,0xc(%rsp)
  jne    L276
  test   %ebp,%ebp
  jle    L38
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,%ebp
  jne    L53
  add    %ebp,%ebx
L38:
  mov    0x18(%rsp),%edx
  test   %edx,%edx
  jne    L109
  add    $0x1,%ebx
L42:
  lea    D45(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L56
L201:
  mov    0x14(%rsp),%esi
  cmp    %esi,0x24(%rsp)
  jle    L257
  subl   $0x1,0x20(%rsp)
L83:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jl     L43
  lea    0x2(%rbp),%eax
  mov    0x14(%rsp),%ecx
  sub    $0x2,%ebp
  cmp    %ecx,0x24(%rsp)
  cmovge %eax,%ebp
  addl   $0x2,0x1c(%rsp)
  sub    $0x1,%r13d
  jmp    L303
  nopl   0x0(%rax,%rax,1)
L219:
  lea    D4(%rip),%rdi
  lea    0x1(%r13),%ebx
  call   <printf@plt>
  jmp    L6
  nopl   (%rax)
L109:
  mov    0x1c(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  js     L42
  mov    %ebx,0x28(%rsp)
  mov    %r14d,%ebx
  mov    0x1c(%rsp),%r14d
  nopl   0x0(%rax,%rax,1)
L282:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r14d,%ebx
  jle    L282
  mov    0x28(%rsp),%ebx
  jmp    L42
  nopl   0x0(%rax)
L257:
  addl   $0x1,0x20(%rsp)
  movl   $0x1,0x18(%rsp)
  jmp    L83
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D86
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D105
type_guessed: string
name: parse_data
arguments: tag: D103
type_guessed: string
name: parse_data
arguments: tag: D45
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string

tool: D86: Digite o tamanho da figura:

tool: D15: %d

tool: D105:  

tool: D103: #

tool: D45: \

tool: D4: /

tool: D9: 


assistant: ```c
int main() {
  printf("Digite o tamanho da figura:");
  int tam;
  scanf("%d", &tam);
  if (tam % 2 == 0) {
    tam++;
  }
  int tam2 = tam;
  int metade = (tam / 2);
  int meio = metade;
  int meio2 = meio;
  int teste = 1;
  int teste2 = 1;
  int gambi = 1;
  int gambi2 = 1;
  int tamanho = tam;
  int tamanho2 = tam;
  int temp2;
  for (int i = 0; i < tam; i++) {
    if (teste == 0) {
      if (i <= ((int)tamanho / 4)) {
        gambi = gambi + 2;
      } else
        gambi = gambi - 2;
    }
    teste = 0;
    for (int k = 0; k <= tam * 2; k++) {
      if (k == i)
        printf("\\");
      else if (k == tam + 2)
        printf("/");
      if (k == metade + 1) {
        for (temp2 = 0; temp2 < gambi; temp2++) {
          printf("#");
          k++;
        }
      }
      printf(" ");
    }
    if (i < ((int)(tamanho) / 4)) {
      metade--;
    } else {
      metade++;
    }
    tam--;
    printf("\n");
  }
  int c = 0;
  int temp3;
  for (int a = 1; a <= tam2 / 2; a++) {
    if (teste2 == 0) {
      if (a <= ((int)tamanho2 / 4)) {
        gambi2 = gambi2 + 2;
      } else
        gambi2 = gambi2 - 2;
    }
    teste2 = 0;
    for (int b = 0; b < tam2; b++) {
      if (b == meio2 + 1) {
        printf("/");
        b++;
      }
      if (b == meio + 2) {
        for (temp3 = 0; temp3 < gambi2; temp3++) {
          printf("#");
          b++;
        }
        if (c == 0) {
          printf("\\");
          b++;
        } else {
          for (int j = 0; j <= (a - meio2); j++) {
            printf(" ");
          }
          printf("\\");
        }
      } else
        printf(" ");
    }
    meio2--;
    if (a < ((int)tamanho2 / 4)) {
      meio--;
    } else {
      c = 1;
      meio++;
    }
    printf("\n");
  }
  return 0;
}
```