ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D62(%rip),%xmm4
  lea    D14(%rip),%rbp
  mov    $0x4,%eax
  movsd  D53(%rip),%xmm3
  movsd  D16(%rip),%xmm2
  mov    %rbp,%rdi
  movsd  D3(%rip),%xmm0
  movapd %xmm4,%xmm1
  call   <printf@plt>
  mov    D62(%rip),%rax
  mov    %rbp,%rdi
  pxor   %xmm3,%xmm3
  movsd  D45(%rip),%xmm0
  movq   %rax,%xmm2
  movq   %rax,%xmm1
  mov    $0x4,%eax
  call   <printf@plt>
  mov    D62(%rip),%rax
  movsd  D102(%rip),%xmm2
  lea    D43(%rip),%rdi
  movsd  D36(%rip),%xmm1
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D62
type_infered: f64
name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D53
type_infered: byte[8]
name: parse_data
arguments: tag: D16
type_infered: byte[8]
name: parse_data
arguments: tag: D3
type_infered: byte[8]
name: parse_data
arguments: tag: D45
type_infered: byte[8]
name: parse_data
arguments: tag: D102
type_infered: byte[8]
name: parse_data
arguments: tag: D43
type_infered: string
name: parse_data
arguments: tag: D36
type_infered: f64

tool: D62: 1

tool: D14: x=%le y=%le z=%le zz=%le


tool: {"D53": [0x00,0x00,0x00,0x00,0x00,0x00,0xd4,0x3c]}

tool: {"D16": [0x05,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D3": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xd2,0x3c]}

tool: {"D45": [0xbc,0x89,0xd8,0x97,0xb2,0xd2,0x9c,0x3c]}

tool: {"D102": [0x00,0x80,0xfa,0xca,0x73,0xf9,0xef,0x3f]}

tool: D43: u=%le v=%le w=%le


tool: D36: 1.00000000000001

assistant: ```c
int main(int argc, char *argv[]) {
  double x = 1.0e-15;
  double y = 1.0L;
  double z = x + y;
  double zz = z - y;
  printf("x=%le y=%le z=%le zz=%le\n", x, y, z, zz);
  x = 1.0e-16;
  y = 1.0L;
  z = x + y;
  zz = z - y;
  printf("x=%le y=%le z=%le zz=%le\n", x, y, z, zz);
  double u = 1.0L;
  double v = 1.00000000000001L;
  double w = (v - u) * 100000000000000.0L;
  printf("u=%le v=%le w=%le\n", u, v, w);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_list_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L14
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  movq   $0x0,-0x8(%rbp)
  jmp    L37
L26:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L37:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L26
  jmp    L34
L14:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
L34:
  nop
  leave
  ret
```

assistant: ```c
void string_list_init(char ***list, size_t length) {
  if (length > 0) {
    *list = malloc((length + 1) * sizeof(char *));
    size_t i;
    for (i = 0; i < length + 1; ++i)
      (*list)[i] = 0;
  } else
    *list = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_list_init>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rsi,%rsi
  jne    L1
  movq   $0x0,(%rdi)
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %rsi,%rbx
  lea    0x1(%rsi),%r12
  lea    0x0(,%r12,8),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %r12,%r12
  je     L22
  mov    $0x0,%eax
L10:
  mov    0x0(%rbp),%rdx
  movq   $0x0,(%rdx,%rax,8)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rbx
  jne    L10
  jmp    L22
```

assistant: ```c
void string_list_init(char ***list, size_t length) {
  if (length > 0) {
    *list = malloc((length + 1) * sizeof(char *));
    size_t i;
    for (i = 0; i < length + 1; ++i)
      (*list)[i] = 0;
  } else
    *list = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_list_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L0
  movq   $0x0,(%rdi)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    0x8(,%rsi,8),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void string_list_init(char ***list, size_t length) {
  if (length > 0) {
    *list = malloc((length + 1) * sizeof(char *));
    size_t i;
    for (i = 0; i < length + 1; ++i)
      (*list)[i] = 0;
  } else
    *list = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_list_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L5
  movq   $0x0,(%rdi)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    0x8(,%rsi,8),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void string_list_init(char ***list, size_t length) {
  if (length > 0) {
    *list = malloc((length + 1) * sizeof(char *));
    size_t i;
    for (i = 0; i < length + 1; ++i)
      (*list)[i] = 0;
  } else
    *list = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<win_scr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <header@plt>
  mov    -0x44(%rbp),%eax
  lea    0x1(%rax),%edx
  lea    -0x40(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <txt_ctrd@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <txt_ctrd@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D0: Congratulations Player %d, you win !


tool: D7: Press a key to quit...


assistant: ```c
void win_scr(int player) {
  header();
  char str[50];
  sprintf(str, "Congratulations Player %d, you win !\n", player + 1);
  txt_ctrd(str);
  txt_ctrd("Press a key to quit...\n");
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<win_scr>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <header@plt>
  lea    0x1(%rbx),%edx
  mov    %rsp,%rbx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <txt_ctrd@plt>
  lea    D10(%rip),%rdi
  call   <txt_ctrd@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x40,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string

tool: D11: Congratulations Player %d, you win !


tool: D10: Press a key to quit...


assistant: ```c
void win_scr(int player) {
  header();
  char str[50];
  sprintf(str, "Congratulations Player %d, you win !\n", player + 1);
  txt_ctrd(str);
  txt_ctrd("Press a key to quit...\n");
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<win_scr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <header@plt>
  lea    0x1(%rbx),%edx
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <txt_ctrd@plt>
  lea    D2(%rip),%rdi
  call   <txt_ctrd@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
type_infered: string
name: read_data
arguments: tag: D2
type_infered: string

tool: D13: Congratulations Player %d, you win !


tool: D2: Press a key to quit...


assistant: ```c
void win_scr(int player) {
  header();
  char str[50];
  sprintf(str, "Congratulations Player %d, you win !\n", player + 1);
  txt_ctrd(str);
  txt_ctrd("Press a key to quit...\n");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<win_scr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <header@plt>
  lea    0x1(%rbx),%edx
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <txt_ctrd@plt>
  lea    D8(%rip),%rdi
  call   <txt_ctrd@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D16: Congratulations Player %d, you win !


tool: D8: Press a key to quit...


assistant: ```c
void win_scr(int player) {
  header();
  char str[50];
  sprintf(str, "Congratulations Player %d, you win !\n", player + 1);
  txt_ctrd(str);
  txt_ctrd("Press a key to quit...\n");
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decompose>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  mov    %rdx,%r14
  test   %edi,%edi
  jle    L54
  mov    %edi,%r13d
  mov    %rsi,%r15
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L58
L17:
  xorpd  D38(%rip),%xmm1
  jmp    L116
L33:
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L52
L91:
  movsd  0x8(%rsp),%xmm6
  comisd %xmm0,%xmm6
  jae    L135
  lea    (%r14,%r12,1),%rdi
  movsd  (%rsp),%xmm0
  movq   %rbx,%xmm7
  divsd  %xmm7,%xmm0
  call   <modf@plt>
  movq   %rbx,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  %xmm3,(%rsp)
  add    $0x1,%ebp
  add    $0x8,%r12
  cmp    %ebp,%r13d
  je     L107
L58:
  mov    (%r15,%r12,1),%rbx
  movq   %rbx,%xmm1
  movsd  (%rsp),%xmm0
  call   <fmod@plt>
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm4,%xmm4
  comisd %xmm1,%xmm4
  ja     L17
L116:
  movq   %rbx,%xmm5
  comisd %xmm5,%xmm1
  jbe    L33
  pxor   %xmm1,%xmm1
  movq   %rbx,%xmm2
  xorpd  D38(%rip),%xmm2
  cmpltsd %xmm0,%xmm1
  andpd  %xmm1,%xmm2
  andnpd %xmm5,%xmm1
  orpd   %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  jmp    L33
L52:
  xorpd  D38(%rip),%xmm0
  jmp    L91
L135:
  pxor   %xmm0,%xmm0
  comisd (%rsp),%xmm0
  ja     L101
  movq   %rbx,%xmm0
  mulsd  D41(%rip),%xmm0
L35:
  lea    (%r14,%r12,1),%rdi
  addsd  (%rsp),%xmm0
  movq   %rbx,%xmm5
  divsd  %xmm5,%xmm0
  call   <modf@plt>
  cmp    %ebp,%r13d
  jle    L124
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jle    L25
  movslq %ebp,%rbp
L46:
  movq   $0x0,(%r14,%rbp,8)
  add    $0x1,%rbp
  cmp    %ebp,%r13d
  jg     L46
  jmp    L25
L101:
  movq   %rbx,%xmm0
  xorpd  D38(%rip),%xmm0
  mulsd  D41(%rip),%xmm0
  jmp    L35
L124:
  mov    %ebp,%r13d
  jmp    L107
L54:
  mov    $0x0,%r13d
L107:
  sub    $0x1,%r13d
  movslq %r13d,%r13
  lea    (%r14,%r13,8),%rax
  movsd  (%rsp),%xmm0
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D38
data_type: f32[4]
name: disassemble_data
arguments: data_label: D41
data_type: f32[2]

tool: {"D38": [0.0,-0.0,0.0,0.0]}

tool: {"D41": [0.0,1.75]}

assistant: ```c
void decompose(value, uncer, nbasis, basis, count) double value;
double uncer;
int nbasis;
double *basis;
double *count;
{
  int i;
  for (i = 0; i < nbasis; i++) {
    double r = fmod(value, basis[i]);
    if (((2 * r) < 0 ? -(2 * r) : (2 * r)) > basis[i])
      r += r > 0 ? -basis[i] : basis[i];
    if (((r) < 0 ? -(r) : (r)) <= uncer) {
      double half = value < 0 ? -basis[i] / 2 : basis[i] / 2;
      modf((value + half) / basis[i], count + i);
      break;
    }
    value = basis[i] * modf(value / basis[i], count + i);
  }
  if (i >= nbasis) {
    count[--i] += value;
  } else {
    for (i++; i < nbasis; i++)
      count[i] = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <question_one@plt>
  mov    $0x0,%eax
  call   <question_two@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  question_one();
  question_two();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <question_one@plt>
  mov    $0x0,%eax
  call   <question_two@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  question_one();
  question_two();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <question_one@plt>
  xor    %eax,%eax
  call   <question_two@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  question_one();
  question_two();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<updateXside>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x2,-0x18(%rbp)
  jmp    L2
L4:
  movl   $0x2,-0x14(%rbp)
  jmp    L13
L33:
  mov    -0x18(%rbp),%r9d
  mov    -0x30(%rbp),%r8d
  mov    -0x38(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  sub    $0x8,%rsp
  mov    -0x14(%rbp),%edi
  push   %rdi
  mov    %eax,%edi
  call   <count@plt>
  add    $0x10,%rsp
  mov    %al,-0x1a(%rbp)
  mov    -0x28(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
  imul   %edx,%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
  imul   -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  movzbl -0x19(%rbp),%edx
  movzbl -0x1a(%rbp),%eax
  mov    -0x28(%rbp),%ecx
  lea    0x2(%rcx),%esi
  mov    -0x2c(%rbp),%ecx
  add    $0x2,%ecx
  imul   %esi,%ecx
  mov    %ecx,%esi
  imul   -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%ecx
  add    $0x2,%ecx
  imul   -0x18(%rbp),%ecx
  add    %ecx,%esi
  mov    -0x14(%rbp),%ecx
  add    %esi,%ecx
  movslq %ecx,%rsi
  mov    -0x40(%rbp),%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <transition@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L33
  addl   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L4
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void updateXside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int x, int rank) {
  int y, z;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (z = 2; z < Iz; z++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<updateXside>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x10(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L2
  mov    %esi,%r14d
  mov    %rcx,%r12
  mov    %edx,%ecx
  lea    0x2(%rdx),%esi
  mov    %esi,0x1c(%rsp)
  mov    %r9d,%eax
  imul   %esi,%eax
  lea    0x2(%r14),%edx
  imul   %edx,%eax
  lea    (%rax,%rsi,2),%eax
  mov    %eax,0x18(%rsp)
  mov    $0x2,%r13d
  mov    %ecx,%r15d
  jmp    L35
L24:
  sub    $0x8,%rsp
  push   %rbx
  mov    %r13d,%r9d
  mov    0x24(%rsp),%r8d
  mov    %r12,%rcx
  mov    0x14(%rsp),%edx
  mov    %r14d,%esi
  mov    0x20(%rsp),%edi
  call   <count@plt>
  lea    (%r12,%rbp,1),%rdx
  movzbl (%rdx,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    %eax,%edx
  mov    0x18(%rsp),%rax
  add    %rbp,%rax
  mov    %dl,(%rax,%rbx,1)
  add    $0x1,%rbx
  add    $0x10,%rsp
  cmp    %r15,%rbx
  jne    L24
L47:
  add    $0x1,%r13d
  mov    0x1c(%rsp),%ecx
  add    %ecx,0x18(%rsp)
  cmp    %r13d,%r14d
  je     L2
L35:
  mov    0x18(%rsp),%ebp
  mov    $0x2,%ebx
  movslq %ebp,%rbp
  cmpl   $0x2,0x4(%rsp)
  jg     L24
  jmp    L47
L2:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateXside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int x, int rank) {
  int y, z;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (z = 2; z < Iz; z++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<updateXside>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x20(%rsp)
  mov    %r8,0x18(%rsp)
  cmp    $0x2,%esi
  jle    L25
  mov    %rcx,%r14
  lea    0x2(%rdx),%ecx
  mov    %edx,%r13d
  mov    %esi,%r12d
  mov    %ecx,%eax
  lea    0x2(%rsi),%edx
  mov    %ecx,0x28(%rsp)
  mov    $0x2,%r15d
  imul   %r9d,%eax
  mov    %r9d,%ebp
  imul   %edx,%eax
  lea    (%rax,%rcx,2),%eax
  mov    %eax,0x24(%rsp)
  lea    -0x3(%r13),%eax
  mov    %eax,0x2c(%rsp)
  nopl   0x0(%rax,%rax,1)
L38:
  cmp    $0x2,%r13d
  jle    L15
  mov    0x2c(%rsp),%eax
  mov    $0x2,%ebx
  add    $0x3,%rax
  mov    %rax,(%rsp)
  movslq 0x24(%rsp),%rax
  mov    %rax,0x10(%rsp)
  add    %r14,%rax
  mov    %rax,0x8(%rsp)
  mov    %ebp,%eax
  mov    %rbx,%rbp
  mov    %eax,%ebx
L7:
  sub    $0x8,%rsp
  mov    %r15d,%r9d
  mov    %r13d,%edx
  mov    %ebx,%r8d
  push   %rbp
  mov    0x30(%rsp),%edi
  mov    %r14,%rcx
  mov    %r12d,%esi
  call   <count@plt>
  mov    0x18(%rsp),%rcx
  movzbl %al,%edi
  movzbl (%rcx,%rbp,1),%esi
  call   <transition@plt>
  mov    %eax,%r9d
  mov    0x28(%rsp),%rax
  add    0x20(%rsp),%rax
  mov    %r9b,(%rax,%rbp,1)
  add    $0x1,%rbp
  pop    %rax
  pop    %rdx
  cmp    (%rsp),%rbp
  jne    L7
  mov    %ebx,%ebp
L15:
  add    $0x1,%r15d
  mov    0x28(%rsp),%edx
  add    %edx,0x24(%rsp)
  cmp    %r15d,%r12d
  jne    L38
L25:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateXside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int x, int rank) {
  int y, z;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (z = 2; z < Iz; z++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<updateXside>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x1c(%rsp)
  cmp    $0x2,%esi
  jle    L13
  lea    0x2(%rdx),%eax
  mov    %edx,%r13d
  mov    %r9d,%edx
  mov    %rcx,%r14
  imul   %eax,%edx
  lea    0x2(%rsi),%ecx
  mov    %esi,%r12d
  imul   %ecx,%edx
  cmp    $0x2,%r13d
  jle    L13
  movslq %eax,%rcx
  add    %eax,%eax
  movslq %edx,%rdx
  mov    $0x2,%ebx
  cltq
  mov    %rcx,0x28(%rsp)
  mov    %r9d,%r15d
  add    %rdx,%rax
  lea    (%r14,%rax,1),%rdx
  add    %r8,%rax
  mov    %rax,0x10(%rsp)
  lea    -0x3(%r13),%eax
  add    $0x3,%rax
  mov    %rdx,0x8(%rsp)
  mov    %rax,0x20(%rsp)
  nopl   0x0(%rax)
L0:
  mov    %r15d,%eax
  mov    $0x2,%ebp
  mov    %r14,%r15
  mov    %r13d,%r14d
  mov    %r12d,%r13d
  mov    %eax,%r12d
  nopl   0x0(%rax)
L32:
  sub    $0x8,%rsp
  mov    %r14d,%edx
  mov    %ebx,%r9d
  mov    %r12d,%r8d
  push   %rbp
  mov    0x2c(%rsp),%edi
  mov    %r15,%rcx
  mov    %r13d,%esi
  call   <count@plt>
  mov    0x18(%rsp),%rcx
  movzbl %al,%edi
  movzbl (%rcx,%rbp,1),%esi
  call   <transition@plt>
  mov    0x20(%rsp),%rdx
  mov    %al,(%rdx,%rbp,1)
  add    $0x1,%rbp
  pop    %rax
  pop    %rdx
  cmp    0x20(%rsp),%rbp
  jne    L32
  mov    %r12d,%eax
  add    $0x1,%ebx
  mov    %r13d,%r12d
  mov    0x28(%rsp),%rcx
  mov    %r14d,%r13d
  add    %rcx,0x8(%rsp)
  mov    %r15,%r14
  mov    %eax,%r15d
  add    %rcx,0x10(%rsp)
  cmp    %ebx,%r12d
  jne    L0
L13:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateXside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int x, int rank) {
  int y, z;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (z = 2; z < Iz; z++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<input_line_and_echo_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dl,-0x64(%rbp)
  mov    %ecx,%edx
  mov    %dl,-0x68(%rbp)
  mov    %al,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x52(%rbp)
  movb   $0x0,-0x51(%rbp)
  movb   $0x0,-0x50(%rbp)
  jmp    L53
L71:
  movzbl -0x68(%rbp),%ecx
  movzbl -0x64(%rbp),%edx
  movzbl -0x6c(%rbp),%esi
  movzbl -0x51(%rbp),%eax
  mov    %eax,%edi
  call   <terminal_get_and_echo_char@plt>
  mov    %al,-0x52(%rbp)
  movzbl -0x52(%rbp),%eax
  mov    %eax,%edi
  call   <is_a_backspace@plt>
  cmp    $0x1,%eax
  jne    L89
  cmpb   $0x0,-0x51(%rbp)
  je     L53
  subb   $0x1,-0x51(%rbp)
  movzbl -0x51(%rbp),%eax
  cltq
  movb   $0x0,-0x50(%rbp,%rax,1)
  jmp    L53
L89:
  movzbl -0x52(%rbp),%eax
  mov    %eax,%edi
  call   <is_a_return@plt>
  test   %rax,%rax
  jne    L53
  movzbl -0x51(%rbp),%eax
  cmp    -0x6c(%rbp),%al
  jae    L28
  movzbl -0x51(%rbp),%eax
  cltq
  movzbl -0x52(%rbp),%edx
  mov    %dl,-0x50(%rbp,%rax,1)
  addb   $0x1,-0x51(%rbp)
  movzbl -0x51(%rbp),%eax
  cltq
  movb   $0x0,-0x50(%rbp,%rax,1)
  jmp    L53
L28:
  movzbl -0x51(%rbp),%eax
  cltq
  movzbl -0x52(%rbp),%edx
  mov    %dl,-0x50(%rbp,%rax,1)
L53:
  movzbl -0x52(%rbp),%eax
  mov    %eax,%edi
  call   <is_a_return@plt>
  test   %rax,%rax
  je     L71
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
char *input_line_and_echo_char(unsigned char e, unsigned char rubout, unsigned char size) {
  unsigned char c = 0;
  unsigned char i = 0;
  unsigned char buf[64];
  buf[0] = '\0';
  while (is_a_return(c) == 0) {
    c = terminal_get_and_echo_char(i, size, e, rubout);
    if (is_a_backspace(c) == 1) {
      if (i > 0) {
        --i;
        buf[i] = '\0';
      }
    } else if (is_a_return(c) == 0) {
      if (i < size) {
        buf[i] = c;
        ++i;
        buf[i] = '\0';
      } else {
        buf[i] = c;
      }
    }
  }
  return strdup(buf);
}
```