user: 请从给定的汇编指令推导出C源代码:

```asm
<modify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L1
L159:
  mov    -0x60(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x60(%rbp)
L1:
  cmpl   $0x4,-0x60(%rbp)
  jle    L159
  movl   $0x0,-0x5c(%rbp)
  jmp    L140
L95:
  mov    -0x5c(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x5c(%rbp)
L140:
  cmpl   $0x4,-0x5c(%rbp)
  jle    L95
  movl   $0x0,-0x58(%rbp)
  jmp    L25
L42:
  movl   $0x0,-0x54(%rbp)
  jmp    L35
L91:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x54(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L17
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x54(%rbp),%edx
  mov    %edx,-0x40(%rbp,%rax,4)
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x58(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x64(%rbp)
L17:
  addl   $0x1,-0x54(%rbp)
L35:
  cmpl   $0x4,-0x54(%rbp)
  jle    L91
  addl   $0x1,-0x58(%rbp)
L25:
  cmpl   $0x4,-0x58(%rbp)
  jle    L42
  movl   $0x0,-0x50(%rbp)
  jmp    L188
L39:
  mov    -0x50(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    $0xffffffff,%eax
  je     L102
  movl   $0x0,-0x4c(%rbp)
  jmp    L135
L66:
  mov    -0x50(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4c(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  addl   $0x1,-0x4c(%rbp)
L135:
  cmpl   $0x4,-0x4c(%rbp)
  jle    L66
  addl   $0x1,-0x50(%rbp)
L188:
  cmpl   $0x4,-0x50(%rbp)
  jle    L39
  jmp    L43
L102:
  nop
L43:
  movl   $0x0,-0x48(%rbp)
  jmp    L46
L20:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    $0xffffffff,%eax
  je     L22
  movl   $0x0,-0x44(%rbp)
  jmp    L137
L126:
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  addl   $0x1,-0x44(%rbp)
L137:
  cmpl   $0x4,-0x44(%rbp)
  jle    L126
  addl   $0x1,-0x48(%rbp)
L46:
  cmpl   $0x4,-0x48(%rbp)
  jle    L20
  jmp    L68
L22:
  nop
L68:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L174
  call   <__stack_chk_fail@plt>
L174:
  leave
  ret
```

assistant: ```c
void modify(int arr[5][5]) {
  int index = 0;
  int rows[5];
  int cols[5];
  for (int i = 0; i < 5; i++)
    rows[i] = -1;
  for (int i = 0; i < 5; i++)
    cols[i] = -1;
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
      if (arr[i][j] == 0) {
        rows[index] = j;
        cols[index] = i;
        index++;
      }
    }
  }
  for (int i = 0; i < 5; i++) {
    if (rows[i] != -1) {
      for (int j = 0; j < 5; j++)
        arr[rows[i]][j] = 0;
    } else
      break;
  }
  for (int i = 0; i < 5; i++) {
    if (cols[i] != -1) {
      for (int j = 0; j < 5; j++)
        arr[j][cols[i]] = 0;
    } else
      break;
  }
}
```