ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x42,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: %c


assistant: ```c
int main() {
  char c = 'A';
  c++;
  printf("%c\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x42,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: %c


assistant: ```c
int main() {
  char c = 'A';
  c++;
  printf("%c\n", c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x42,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: %c


assistant: ```c
int main() {
  char c = 'A';
  c++;
  printf("%c\n", c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TrimWhitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L59
L47:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L69
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L19
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L70
L19:
  addl   $0x1,-0x4(%rbp)
L69:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L12
  jmp    L70
L18:
  addl   $0x1,-0x8(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L47
L70:
  leave
  ret
```

assistant: ```c
void TrimWhitespace(char *str) {
  int i;
  int j;
  for (i = 0; i < strlen(str); i++) {
    if (!isspace(str[i])) {
      memmove(str, str + i, strlen(str) + 1);
      for (j = i + 1; j < strlen(str); j++) {
        if (isspace(str[j])) {
          str[j] = 0;
          return;
        }
      }
      return;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<TrimWhitespace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L21:
  mov    %ebx,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L37
  lea    (%rbx,%rbp,1),%r13
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L21
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  lea    0x1(%r12),%ebx
  movslq %ebx,%rbx
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L37
  lea    0x0(%rbp,%rbx,1),%r12
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  je     L14
  movb   $0x0,(%r12)
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void TrimWhitespace(char *str) {
  int i;
  int j;
  for (i = 0; i < strlen(str); i++) {
    if (!isspace(str[i])) {
      memmove(str, str + i, strlen(str) + 1);
      for (j = i + 1; j < strlen(str); j++) {
        if (isspace(str[j])) {
          str[j] = 0;
          return;
        }
      }
      return;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TrimWhitespace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L18
  nopl   (%rax)
L13:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    (%rbx,%rbp,1),%r13
  lea    0x1(%rbx),%r12d
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  je     L9
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L13
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  movslq %r12d,%rbx
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L53:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r12
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L53
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L38:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void TrimWhitespace(char *str) {
  int i;
  int j;
  for (i = 0; i < strlen(str); i++) {
    if (!isspace(str[i])) {
      memmove(str, str + i, strlen(str) + 1);
      for (j = i + 1; j < strlen(str); j++) {
        if (isspace(str[j])) {
          str[j] = 0;
          return;
        }
      }
      return;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TrimWhitespace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L37
  nopl   (%rax)
L14:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    (%rbx,%rbp,1),%r13
  lea    0x1(%rbx),%r12d
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  je     L2
L37:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L14
L60:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  movslq %r12d,%rbx
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L63:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r12
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
L39:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L63
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L21:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void TrimWhitespace(char *str) {
  int i;
  int j;
  for (i = 0; i < strlen(str); i++) {
    if (!isspace(str[i])) {
      memmove(str, str + i, strlen(str) + 1);
      for (j = i + 1; j < strlen(str); j++) {
        if (isspace(str[j])) {
          str[j] = 0;
          return;
        }
      }
      return;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetRSSHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    D28(%rip),%eax
  test   %eax,%eax
  je     L80
  mov    $0x60,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <BuildKeyCache@plt>
  movl   $0x0,D28(%rip)
L80:
  movl   $0x0,-0x4(%rbp)
  jmp    L62
L109:
  cmpl   $0x0,-0x14(%rbp)
  jns    L74
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  xor    %eax,-0x8(%rbp)
L74:
  shll   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L62:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L109
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L86:
  cmpl   $0x0,-0x18(%rbp)
  jns    L11
  mov    -0x4(%rbp),%eax
  add    $0x20,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  xor    %eax,-0x8(%rbp)
L11:
  shll   -0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L86
  movl   $0x0,-0x4(%rbp)
  jmp    L119
L124:
  mov    -0x1c(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L49
  mov    -0x4(%rbp),%eax
  add    $0x40,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  xor    %eax,-0x8(%rbp)
L49:
  shll   -0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L119:
  cmpl   $0xf,-0x4(%rbp)
  jle    L124
  movl   $0x0,-0x4(%rbp)
  jmp    L52
L39:
  mov    -0x20(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L15
  mov    -0x4(%rbp),%eax
  add    $0x50,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  xor    %eax,-0x8(%rbp)
L15:
  shll   -0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L52:
  cmpl   $0xf,-0x4(%rbp)
  jle    L39
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t GetRSSHash(in_addr_t sip, in_addr_t dip, in_port_t sp, in_port_t dp) {
  uint32_t res = 0;
  int i;
  static int first = 1;
  static uint32_t key_cache[96] = {0};
  if (first) {
    BuildKeyCache(key_cache, 96);
    first = 0;
  }
  for (i = 0; i < 32; i++) {
    if (sip & 0x80000000)
      res ^= key_cache[i];
    sip <<= 1;
  }
  for (i = 0; i < 32; i++) {
    if (dip & 0x80000000)
      res ^= key_cache[32 + i];
    dip <<= 1;
  }
  for (i = 0; i < 16; i++) {
    if (sp & 0x8000)
      res ^= key_cache[64 + i];
    sp <<= 1;
  }
  for (i = 0; i < 16; i++) {
    if (dp & 0x8000)
      res ^= key_cache[80 + i];
    dp <<= 1;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetRSSHash>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%r12d
  cmpl   $0x0,D62(%rip)
  jne    L132
L44:
  lea    D33(%rip),%rcx
  lea    -0x80(%rcx),%rax
  mov    $0x0,%edx
  jmp    L46
L132:
  mov    $0x60,%esi
  lea    D34(%rip),%rdi
  call   <BuildKeyCache@plt>
  movl   $0x0,D62(%rip)
  jmp    L44
L77:
  add    %ebp,%ebp
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L28
L46:
  test   %ebp,%ebp
  jns    L77
  xor    (%rax),%edx
  jmp    L77
L28:
  lea    D33(%rip),%rax
  lea    0x80(%rax),%rcx
  jmp    L94
L79:
  add    %ebx,%ebx
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L164
L94:
  test   %ebx,%ebx
  jns    L79
  xor    (%rax),%edx
  jmp    L79
L164:
  lea    D31(%rip),%rax
  lea    0x40(%rax),%rcx
  jmp    L59
L167:
  add    %r13d,%r13d
  add    $0x4,%rax
  cmp    %rax,%rcx
  je     L158
L59:
  test   $0x8000,%r13d
  je     L167
  xor    (%rax),%edx
  jmp    L167
L158:
  lea    D58(%rip),%rax
  lea    0x40(%rax),%rcx
  jmp    L163
L145:
  add    %r12d,%r12d
  add    $0x4,%rax
  cmp    %rax,%rcx
  je     L149
L163:
  test   $0x8000,%r12d
  je     L145
  xor    (%rax),%edx
  jmp    L145
L149:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t GetRSSHash(in_addr_t sip, in_addr_t dip, in_port_t sp, in_port_t dp) {
  uint32_t res = 0;
  int i;
  static int first = 1;
  static uint32_t key_cache[96] = {0};
  if (first) {
    BuildKeyCache(key_cache, 96);
    first = 0;
  }
  for (i = 0; i < 32; i++) {
    if (sip & 0x80000000)
      res ^= key_cache[i];
    sip <<= 1;
  }
  for (i = 0; i < 32; i++) {
    if (dip & 0x80000000)
      res ^= key_cache[32 + i];
    dip <<= 1;
  }
  for (i = 0; i < 16; i++) {
    if (sp & 0x8000)
      res ^= key_cache[64 + i];
    sp <<= 1;
  }
  for (i = 0; i < 16; i++) {
    if (dp & 0x8000)
      res ^= key_cache[80 + i];
    dp <<= 1;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetRSSHash>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D21(%rip),%eax
  test   %eax,%eax
  jne    L97
L20:
  lea    D12(%rip),%rdx
  xor    %r8d,%r8d
  lea    -0x80(%rdx),%rax
  nopl   0x0(%rax)
L29:
  test   %ebp,%ebp
  jns    L80
  xor    (%rax),%r8d
L80:
  add    $0x4,%rax
  add    %ebp,%ebp
  cmp    %rax,%rdx
  jne    L29
  lea    D12(%rip),%rax
  lea    0x80(%rax),%rdx
  nopl   0x0(%rax,%rax,1)
L32:
  test   %ebx,%ebx
  jns    L57
  xor    (%rax),%r8d
L57:
  add    $0x4,%rax
  add    %ebx,%ebx
  cmp    %rax,%rdx
  jne    L32
  lea    D20(%rip),%rax
  lea    0x40(%rax),%rdx
  nopl   (%rax)
L35:
  test   $0x8000,%r13d
  je     L88
  xor    (%rax),%r8d
L88:
  add    $0x4,%rax
  add    %r13d,%r13d
  cmp    %rax,%rdx
  jne    L35
  lea    D35(%rip),%rax
  lea    0x40(%rax),%rdx
  nopl   0x0(%rax,%rax,1)
L76:
  test   $0x8000,%r12d
  je     L72
  xor    (%rax),%r8d
L72:
  add    $0x4,%rax
  add    %r12d,%r12d
  cmp    %rax,%rdx
  jne    L76
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L97:
  mov    $0x60,%esi
  lea    D6(%rip),%rdi
  call   <BuildKeyCache@plt>
  movl   $0x0,D21(%rip)
  jmp    L20
```

assistant: ```c
uint32_t GetRSSHash(in_addr_t sip, in_addr_t dip, in_port_t sp, in_port_t dp) {
  uint32_t res = 0;
  int i;
  static int first = 1;
  static uint32_t key_cache[96] = {0};
  if (first) {
    BuildKeyCache(key_cache, 96);
    first = 0;
  }
  for (i = 0; i < 32; i++) {
    if (sip & 0x80000000)
      res ^= key_cache[i];
    sip <<= 1;
  }
  for (i = 0; i < 32; i++) {
    if (dip & 0x80000000)
      res ^= key_cache[32 + i];
    dip <<= 1;
  }
  for (i = 0; i < 16; i++) {
    if (sp & 0x8000)
      res ^= key_cache[64 + i];
    sp <<= 1;
  }
  for (i = 0; i < 16; i++) {
    if (dp & 0x8000)
      res ^= key_cache[80 + i];
    dp <<= 1;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *chomp(char *str) {
  int str_len = strlen(str);
  char *pos = strrchr(str, '.');
  if (pos != NULL) {
    int suf_len = strlen(pos);
    str = strdup(str);
    str[str_len - suf_len] = 0;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chomp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rdi
  mov    %rbx,%rax
  test   %rdi,%rdi
  je     L5
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strdup@plt>
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *chomp(char *str) {
  int str_len = strlen(str);
  char *pos = strrchr(str, '.');
  if (pos != NULL) {
    int suf_len = strlen(pos);
    str = strdup(str);
    str[str_len - suf_len] = 0;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chomp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strdup@plt>
  sub    %ebx,%ebp
  movslq %ebp,%rbp
  mov    %rax,%r12
  movb   $0x0,(%rax,%rbp,1)
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *chomp(char *str) {
  int str_len = strlen(str);
  char *pos = strrchr(str, '.');
  if (pos != NULL) {
    int suf_len = strlen(pos);
    str = strdup(str);
    str[str_len - suf_len] = 0;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<chomp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strdup@plt>
  sub    %ebx,%ebp
  movslq %ebp,%rbp
  mov    %rax,%r12
  movb   $0x0,(%rax,%rbp,1)
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *chomp(char *str) {
  int str_len = strlen(str);
  char *pos = strrchr(str, '.');
  if (pos != NULL) {
    int suf_len = strlen(pos);
    str = strdup(str);
    str[str_len - suf_len] = 0;
  }
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L26
L10:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %edi
  test   %eax,%eax
  jne    L10
  cmpl   $0x9,-0x14(%rbp)
  jg     L8
  mov    -0x14(%rbp),%eax
  jmp    L29
L8:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x8(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <rev>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L29:
  leave
  ret
```

assistant: ```c
int rev(int number) {
  int base = 1;
  while (number / (base * 10)) {
    base *= 10;
  }
  if (number <= 9) {
    return number;
  } else {
    int revNum = (number % 10) * base;
    return rev(number / 10) + revNum;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rev>:
  endbr64
  mov    $0x1,%ecx
L11:
  mov    %ecx,%esi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %eax,%eax
  jne    L11
  cmp    $0x9,%edi
  jg     L7
  mov    %edi,%eax
  ret
L7:
  push   %rbx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  mov    %edi,%ebx
  imul   %esi,%ebx
  mov    %eax,%edi
  call   <rev>
  lea    (%rax,%rbx,1),%edi
  mov    %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rev(int number) {
  int base = 1;
  while (number / (base * 10)) {
    base *= 10;
  }
  if (number <= 9) {
    return number;
  } else {
    int revNum = (number % 10) * base;
    return rev(number / 10) + revNum;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rev>:
  endbr64
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%ecx
  nopl   (%rax)
L5:
  mov    %edi,%eax
  mov    %ecx,%esi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  cltd
  idiv   %ecx
  test   %eax,%eax
  jne    L5
  cmp    $0x9,%edi
  jle    L20
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edi,%edx
  mov    %eax,%edi
  imul   %esi,%edx
  add    %edx,%r8d
  jmp    L11
  nopl   (%rax)
L20:
  lea    (%rdi,%r8,1),%eax
  ret
```

assistant: ```c
int rev(int number) {
  int base = 1;
  while (number / (base * 10)) {
    base *= 10;
  }
  if (number <= 9) {
    return number;
  } else {
    int revNum = (number % 10) * base;
    return rev(number / 10) + revNum;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rev>:
  endbr64
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%ecx
  nopl   (%rax)
L25:
  mov    %edi,%eax
  mov    %ecx,%esi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  cltd
  idiv   %ecx
  test   %eax,%eax
  jne    L25
  cmp    $0x9,%edi
  jle    L9
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edi,%edx
  mov    %eax,%edi
  imul   %esi,%edx
  add    %edx,%r8d
  jmp    L4
  nopl   (%rax)
L9:
  lea    (%rdi,%r8,1),%eax
  ret
```

assistant: ```c
int rev(int number) {
  int base = 1;
  while (number / (base * 10)) {
    base *= 10;
  }
  if (number <= 9) {
    return number;
  } else {
    int revNum = (number % 10) * base;
    return rev(number / 10) + revNum;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L107
  movss  D7(%rip),%xmm0
  jmp    L65
L107:
  cmpq   $0x0,-0x18(%rbp)
  jne    L52
  pxor   %xmm0,%xmm0
  jmp    L65
L52:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <min_match_length@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L102
  pxor   %xmm0,%xmm0
  jmp    L65
L102:
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  js     L53
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L105
L53:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L105:
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  js     L62
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  jmp    L37
L62:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2ss %rdx,%xmm1
  addss  %xmm1,%xmm1
L37:
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  js     L29
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  jmp    L39
L29:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm1
L39:
  divss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
L65:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float score(char *string, char *query) {
  size_t string_length, query_length, match_length;
  string_length = strlen(string);
  query_length = strlen(query);
  if (query_length == 0) {
    return 1;
  }
  if (string_length == 0) {
    return 0;
  }
  match_length = min_match_length(string, query);
  if (match_length == 0) {
    return 0;
  }
  return (float)query_length / (float)match_length / (float)string_length;
}
```