ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L59
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L91
L59:
  mov    -0x14(%rbp),%eax
  cmp    $0xf,%eax
  jne    L109
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <next_line@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L61
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L44
L61:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L91
L44:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <next_line@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L70
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x63,%al
  jne    L44
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_cpu_v15@plt>
  test   %eax,%eax
  je     L44
  mov    $0xffffffff,%eax
  jmp    L91
L70:
  nop
  nop
  mov    $0x0,%eax
  jmp    L91
L109:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
L91:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type: string
name: extract_symbolic_data
arguments: label: D42
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D8
type: string

tool: D15: version %u


tool: D42: Could not parse version

tool: D10: timestamp %llu


tool: D19: Could not parse timestamp

tool: D8: Can not handle version %u


assistant: ```c
int parse(const char *b) {
  unsigned int version;
  unsigned long long ts;
  if (sscanf(b, "version %u\n", &version) != 1) {
    printf("Could not parse version\n");
    return -1;
  }
  switch (version) {
  case 15:
    b = next_line(b);
    if (!b || sscanf(b, "timestamp %llu\n", &ts) != 1) {
      printf("Could not parse timestamp\n");
      return -1;
    }
    while (1) {
      b = next_line(b);
      if (!b)
        break;
      if (b[0] == 'c') {
        if (parse_cpu_v15(b))
          return -1;
      }
    }
    break;
  default:
    printf("Can not handle version %u\n", version);
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L73
  mov    0xc(%rsp),%esi
  cmp    $0xf,%esi
  jne    L61
  mov    %rbx,%rdi
  call   <next_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L80
  lea    0x10(%rsp),%rdx
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L80
L70:
  mov    %rbx,%rdi
  call   <next_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
  cmpb   $0x63,(%rax)
  jne    L70
  mov    %rax,%rdi
  call   <parse_cpu_v15@plt>
  test   %eax,%eax
  je     L70
  mov    $0xffffffff,%eax
  jmp    L104
L73:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L104
L80:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L104
L61:
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L104
L37:
  mov    $0x0,%eax
L104:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L84
  add    $0x20,%rsp
  pop    %rbx
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D24
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D7: version %u


tool: D25: timestamp %llu


tool: D32: Could not parse version

tool: D24: Could not parse timestamp

tool: D0: Can not handle version %u


assistant: ```c
int parse(const char *b) {
  unsigned int version;
  unsigned long long ts;
  if (sscanf(b, "version %u\n", &version) != 1) {
    printf("Could not parse version\n");
    return -1;
  }
  switch (version) {
  case 15:
    b = next_line(b);
    if (!b || sscanf(b, "timestamp %llu\n", &ts) != 1) {
      printf("Could not parse timestamp\n");
      return -1;
    }
    while (1) {
      b = next_line(b);
      if (!b)
        break;
      if (b[0] == 'c') {
        if (parse_cpu_v15(b))
          return -1;
      }
    }
    break;
  default:
    printf("Can not handle version %u\n", version);
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rsi
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L57
  mov    0xc(%rsp),%esi
  cmp    $0xf,%esi
  jne    L97
  mov    %rbp,%rdi
  call   <next_line@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L25
  mov    %rax,%rdi
  lea    0x10(%rsp),%rdx
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L25
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <next_line@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L108
  cmpb   $0x63,(%rax)
  jne    L5
  mov    %rax,%rdi
  call   <parse_cpu_v15@plt>
  test   %eax,%eax
  je     L5
  mov    $0xffffffff,%eax
  jmp    L110
  nopl   0x0(%rax,%rax,1)
L108:
  xor    %eax,%eax
L110:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x20,%rsp
  pop    %rbp
  ret
L97:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L110
L25:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L110
L57:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L110
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D45
type: string
name: read_data
arguments: data_label: D9
type: string
name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D35
type: string
name: read_data
arguments: data_label: D34
type: string

tool: D45: version %u


tool: D9: timestamp %llu


tool: D11: Can not handle version %u


tool: D35: Could not parse timestamp

tool: D34: Could not parse version

assistant: ```c
int parse(const char *b) {
  unsigned int version;
  unsigned long long ts;
  if (sscanf(b, "version %u\n", &version) != 1) {
    printf("Could not parse version\n");
    return -1;
  }
  switch (version) {
  case 15:
    b = next_line(b);
    if (!b || sscanf(b, "timestamp %llu\n", &ts) != 1) {
      printf("Could not parse timestamp\n");
      return -1;
    }
    while (1) {
      b = next_line(b);
      if (!b)
        break;
      if (b[0] == 'c') {
        if (parse_cpu_v15(b))
          return -1;
      }
    }
    break;
  default:
    printf("Can not handle version %u\n", version);
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rsi
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L74
  mov    0xc(%rsp),%esi
  cmp    $0xf,%esi
  jne    L114
  mov    %rbp,%rdi
  call   <next_line@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L34
  mov    %rax,%rdi
  lea    0x10(%rsp),%rdx
  lea    D13(%rip),%rsi
  xor    %eax,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L34
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  call   <next_line@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L30
  cmpb   $0x63,(%rax)
  jne    L20
  mov    %rax,%rdi
  call   <parse_cpu_v15@plt>
  test   %eax,%eax
  je     L20
  mov    $0xffffffff,%eax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
L12:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L114:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L12
L34:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L12
L74:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L12
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
data_type: string
name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D39
data_type: string
name: retrieve_data
arguments: data_label: D43
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: string

tool: D22: version %u


tool: D13: timestamp %llu


tool: D39: Can not handle version %u


tool: D43: Could not parse timestamp

tool: D27: Could not parse version

assistant: ```c
int parse(const char *b) {
  unsigned int version;
  unsigned long long ts;
  if (sscanf(b, "version %u\n", &version) != 1) {
    printf("Could not parse version\n");
    return -1;
  }
  switch (version) {
  case 15:
    b = next_line(b);
    if (!b || sscanf(b, "timestamp %llu\n", &ts) != 1) {
      printf("Could not parse timestamp\n");
      return -1;
    }
    while (1) {
      b = next_line(b);
      if (!b)
        break;
      if (b[0] == 'c') {
        if (parse_cpu_v15(b))
          return -1;
      }
    }
    break;
  default:
    printf("Can not handle version %u\n", version);
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fetchByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char fetchByte(inbuf)
unsigned char **inbuf;
{
  unsigned char byte = **inbuf;
  (*inbuf)++;
  return (byte);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fetchByte>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  add    $0x1,%rax
  mov    %rax,(%rdi)
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned char fetchByte(inbuf)
unsigned char **inbuf;
{
  unsigned char byte = **inbuf;
  (*inbuf)++;
  return (byte);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fetchByte>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%r8d
  add    $0x1,%rax
  mov    %rax,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char fetchByte(inbuf)
unsigned char **inbuf;
{
  unsigned char byte = **inbuf;
  (*inbuf)++;
  return (byte);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <cmpxchg_reg2reg@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edi
  mov    -0xc(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x6,-0x18(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0xa,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <cmpxchg_reg2reg@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edi
  mov    -0xc(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <xadd_reg2reg@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D28
type: string

tool: D1: CMPXCHG (%li == %li) new = %li -> %i loc = %li


tool: D28: XADD old_loc = %li new = %li loc = %li


assistant: ```c
int main() {
  uint64_t test, new, old_loc, loc;
  int res;
  test = 0;
  loc = 0;
  new = 1;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  test = 6;
  loc = 5;
  new = 10;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  old_loc = xadd_reg2reg(new, &loc);
  printf("XADD old_loc = %li new = %li loc = %li\n", old_loc, new, loc);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <cmpxchg_reg2reg@plt>
  mov    %eax,%r8d
  mov    0x4(%rsp),%r9d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,0x4(%rsp)
  mov    %rbx,%rdx
  mov    $0xa,%esi
  mov    $0x6,%edi
  call   <cmpxchg_reg2reg@plt>
  mov    %eax,%r8d
  mov    0x4(%rsp),%r9d
  mov    $0xa,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <xadd_reg2reg@plt>
  mov    %eax,%esi
  mov    0x4(%rsp),%ecx
  mov    $0xa,%edx
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string

tool: D4: CMPXCHG (%li == %li) new = %li -> %i loc = %li


tool: D18: XADD old_loc = %li new = %li loc = %li


assistant: ```c
int main() {
  uint64_t test, new, old_loc, loc;
  int res;
  test = 0;
  loc = 0;
  new = 1;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  test = 6;
  loc = 5;
  new = 10;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  old_loc = xadd_reg2reg(new, &loc);
  printf("XADD old_loc = %li new = %li loc = %li\n", old_loc, new, loc);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  mov    $0x1,%esi
  lea    D1(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  mov    %rbp,%rdx
  call   <cmpxchg_reg2reg@plt>
  mov    0x4(%rsp),%r9d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %eax,%r8d
  mov    $0x1,%ecx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    $0xa,%esi
  mov    $0x6,%edi
  movl   $0x5,0x4(%rsp)
  call   <cmpxchg_reg2reg@plt>
  mov    0x4(%rsp),%r9d
  mov    $0xa,%ecx
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    $0x6,%edx
  mov    $0x5,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <xadd_reg2reg@plt>
  mov    0x4(%rsp),%ecx
  mov    $0xa,%edx
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string

tool: D1: CMPXCHG (%li == %li) new = %li -> %i loc = %li


tool: D16: XADD old_loc = %li new = %li loc = %li


assistant: ```c
int main() {
  uint64_t test, new, old_loc, loc;
  int res;
  test = 0;
  loc = 0;
  new = 1;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  test = 6;
  loc = 5;
  new = 10;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  old_loc = xadd_reg2reg(new, &loc);
  printf("XADD old_loc = %li new = %li loc = %li\n", old_loc, new, loc);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  mov    $0x1,%esi
  lea    D10(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  mov    %rbp,%rdx
  call   <cmpxchg_reg2reg@plt>
  mov    0x4(%rsp),%r9d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %eax,%r8d
  mov    $0x1,%ecx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    $0xa,%esi
  mov    $0x6,%edi
  movl   $0x5,0x4(%rsp)
  call   <cmpxchg_reg2reg@plt>
  mov    0x4(%rsp),%r9d
  mov    $0xa,%ecx
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    $0x6,%edx
  mov    $0x5,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <xadd_reg2reg@plt>
  mov    0x4(%rsp),%ecx
  mov    $0xa,%edx
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string

tool: D10: CMPXCHG (%li == %li) new = %li -> %i loc = %li


tool: D13: XADD old_loc = %li new = %li loc = %li


assistant: ```c
int main() {
  uint64_t test, new, old_loc, loc;
  int res;
  test = 0;
  loc = 0;
  new = 1;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  test = 6;
  loc = 5;
  new = 10;
  old_loc = loc;
  res = cmpxchg_reg2reg(test, new, &loc);
  printf("CMPXCHG (%li == %li) new = %li -> %i loc = %li\n", old_loc, test, new, res, loc);
  old_loc = xadd_reg2reg(new, &loc);
  printf("XADD old_loc = %li new = %li loc = %li\n", old_loc, new, loc);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swift_flush_dcache>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <swift_inv_data_tag@plt>
  addq   $0x10,-0x8(%rbp)
L18:
  cmpq   $0x1fff,-0x8(%rbp)
  jbe    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void swift_flush_dcache(void) {
  unsigned long addr;
  for (addr = 0; addr < 0x2000; addr += 0x10)
    swift_inv_data_tag(addr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<swift_flush_dcache>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L7:
  mov    %rbx,%rdi
  call   <swift_inv_data_tag@plt>
  add    $0x10,%rbx
  cmp    $0x2000,%rbx
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void swift_flush_dcache(void) {
  unsigned long addr;
  for (addr = 0; addr < 0x2000; addr += 0x10)
    swift_inv_data_tag(addr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swift_flush_dcache>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  add    $0x10,%rbx
  call   <swift_inv_data_tag@plt>
  cmp    $0x2000,%rbx
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
void swift_flush_dcache(void) {
  unsigned long addr;
  for (addr = 0; addr < 0x2000; addr += 0x10)
    swift_inv_data_tag(addr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swift_flush_dcache>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  add    $0x10,%rbx
  call   <swift_inv_data_tag@plt>
  cmp    $0x2000,%rbx
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
void swift_flush_dcache(void) {
  unsigned long addr;
  for (addr = 0; addr < 0x2000; addr += 0x10)
    swift_inv_data_tag(addr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getPathWithoutFinalSlash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L9
  mov    -0x20(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    -0x20(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
L12:
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L26
L14:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L26
L9:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L26:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getPathWithoutFinalSlash(char *const aoDestination, char const *const aSource) {
  char const *lTmp;
  if (aSource) {
    lTmp = strrchr(aSource, '/');
    if (!lTmp) {
      lTmp = strrchr(aSource, '\\');
    }
    if (lTmp) {
      strncpy(aoDestination, aSource, lTmp - aSource);
      aoDestination[lTmp - aSource] = '\0';
    } else {
      *aoDestination = '\0';
    }
  } else {
    *aoDestination = '\0';
  }
  return aoDestination;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getPathWithoutFinalSlash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L8
  mov    %rsi,%rbx
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L24
L41:
  sub    %rbx,%rax
  mov    %rax,%r12
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  jmp    L1
L24:
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L41
  movb   $0x0,0x0(%rbp)
  jmp    L1
L8:
  movb   $0x0,(%rdi)
L1:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getPathWithoutFinalSlash(char *const aoDestination, char const *const aSource) {
  char const *lTmp;
  if (aSource) {
    lTmp = strrchr(aSource, '/');
    if (!lTmp) {
      lTmp = strrchr(aSource, '\\');
    }
    if (lTmp) {
      strncpy(aoDestination, aSource, lTmp - aSource);
      aoDestination[lTmp - aSource] = '\0';
    } else {
      *aoDestination = '\0';
    }
  } else {
    *aoDestination = '\0';
  }
  return aoDestination;
}
```