user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  lea    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  call   <fork@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L4
  mov    $0x0,%edi
  call   <wait@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%eax
  imul   $0xf4240,%eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%eax
  imul   $0xf4240,%eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%eax
  imul   $0xf4240,%eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%eax
  imul   $0xf4240,%eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
L4:
  mov    $0x0,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <execvp@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L16:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D23
type: string
name: read_data
arguments: label: D7
type: string

tool: D5: crear un hijo y ejecutar la tarea tardo:%ld us 


tool: D11: ./salida

tool: D23: Realizar la misma tarea pero ejecutada con la llamada system sin crear otro hijo tardo:%ld us  


tool: D7: Return not expected. Must be an execv error 

assistant: ```c
int main() {
  struct timeval timeInicio, timeFin;
  long total, usegInicio, usegFin;
  int pid;
  total = 0;
  gettimeofday(&timeInicio, 0);
  pid = fork();
  if (pid != 0) {
    wait(0);
    gettimeofday(&timeFin, 0);
    usegInicio = ((timeInicio.tv_sec * 1000000) + timeInicio.tv_usec);
    usegFin = ((timeFin.tv_sec * 1000000) + timeFin.tv_usec);
    total = usegFin - usegInicio;
    printf("crear un hijo y ejecutar la tarea tardo:%ld us \n", total);
    gettimeofday(&timeInicio, 0);
    system("./salida");
    gettimeofday(&timeFin, 0);
    usegInicio = ((timeInicio.tv_sec * 1000000) + timeInicio.tv_usec);
    usegFin = ((timeFin.tv_sec * 1000000) + timeFin.tv_usec);
    total = usegFin - usegInicio;
    printf("Realizar la misma tarea pero ejecutada con la llamada system sin crear otro hijo tardo:%ld us  \n", total);
  } else {
    execvp("./salida", NULL);
    printf("Return not expected. Must be an execv error \n");
  }
  return 0;
}
```