ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <speed_nothing@plt>
  xor    %eax,%eax
  call   <speed_empty@plt>
  xor    %eax,%eax
  call   <speed_bigint_mul136@plt>
  xor    %eax,%eax
  call   <speed_bigint_mul256@plt>
  xor    %eax,%eax
  call   <speed_salsa20@plt>
  xor    %eax,%eax
  call   <speed_poly1305@plt>
  xor    %eax,%eax
  call   <speed_sha512@plt>
  xor    %eax,%eax
  call   <speed_curve25519@plt>
  xor    %eax,%eax
  call   <speed_ed25519@plt>
  xor    %eax,%eax
  call   <avr_end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  speed_nothing();
  speed_empty();
  speed_bigint_mul136();
  speed_bigint_mul256();
  speed_salsa20();
  speed_poly1305();
  speed_sha512();
  speed_curve25519();
  speed_ed25519();
  avr_end();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <speed_nothing@plt>
  xor    %eax,%eax
  call   <speed_empty@plt>
  xor    %eax,%eax
  call   <speed_bigint_mul136@plt>
  xor    %eax,%eax
  call   <speed_bigint_mul256@plt>
  xor    %eax,%eax
  call   <speed_salsa20@plt>
  xor    %eax,%eax
  call   <speed_poly1305@plt>
  xor    %eax,%eax
  call   <speed_sha512@plt>
  xor    %eax,%eax
  call   <speed_curve25519@plt>
  xor    %eax,%eax
  call   <speed_ed25519@plt>
  xor    %eax,%eax
  call   <avr_end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  speed_nothing();
  speed_empty();
  speed_bigint_mul136();
  speed_bigint_mul256();
  speed_salsa20();
  speed_poly1305();
  speed_sha512();
  speed_curve25519();
  speed_ed25519();
  avr_end();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<insert_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L50
L21:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L31
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jg     L24
  jmp    L9
L31:
  nop
L9:
  addl   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  nop
  nop
  leave
  ret
```

assistant: ```c
void insert_sort(int *base, int num) {
  int i, j;
  for (i = 1; i < num; i++) {
    for (j = i; j > 0; j--) {
      if (base[j] < base[j - 1]) {
        swap(&base[j], &base[j - 1]);
      } else {
        break;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L47
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r14d
  lea    0x4(%rdi),%r13
  mov    $0x1,%r12d
  jmp    L12
L34:
  add    $0x1,%r12d
  add    $0x4,%r13
  cmp    %r12d,%r14d
  je     L4
L12:
  mov    %r13,%rbx
  test   %r12d,%r12d
  jle    L34
L43:
  lea    -0x4(%rbx),%rsi
  mov    -0x4(%rbx),%eax
  cmp    %eax,(%rbx)
  jge    L34
  mov    %rbx,%rdi
  call   <swap@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L43
  jmp    L34
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  ret
```

assistant: ```c
void insert_sort(int *base, int num) {
  int i, j;
  for (i = 1; i < num; i++) {
    for (j = i; j > 0; j--) {
      if (base[j] < base[j - 1]) {
        swap(&base[j], &base[j - 1]);
      } else {
        break;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L39
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    0x4(%rdi),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L5:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  sub    $0x4,%rbx
  mov    -0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L10
  mov    %rbx,%rsi
  call   <swap@plt>
  cmp    %rbp,%rbx
  jne    L4
L10:
  add    $0x1,%r12d
  add    $0x4,%r13
  cmp    %r12d,%r14d
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  ret
```

assistant: ```c
void insert_sort(int *base, int num) {
  int i, j;
  for (i = 1; i < num; i++) {
    for (j = i; j > 0; j--) {
      if (base[j] < base[j - 1]) {
        swap(&base[j], &base[j - 1]);
      } else {
        break;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L19
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    0x4(%rdi),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L23:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  sub    $0x4,%rbx
  mov    -0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L8
  mov    %rbx,%rsi
  call   <swap@plt>
  cmp    %rbp,%rbx
  jne    L2
L8:
  add    $0x1,%r12d
  add    $0x4,%r13
  cmp    %r12d,%r14d
  jne    L23
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  ret
```

assistant: ```c
void insert_sort(int *base, int num) {
  int i, j;
  for (i = 1; i < num; i++) {
    for (j = i; j > 0; j--) {
      if (base[j] < base[j - 1]) {
        swap(&base[j], &base[j - 1]);
      } else {
        break;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<select>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L7:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0xc(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  xor    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0xc(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  xor    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x3f,-0xc(%rbp)
  jbe    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void select(unsigned int p[64], unsigned int q[64], const unsigned int r[64], const unsigned int s[64], unsigned int b) {
  unsigned int j;
  unsigned int t;
  unsigned int bminus1;
  bminus1 = b - 1;
  for (j = 0; j < 64; ++j) {
    t = bminus1 & (r[j] ^ s[j]);
    p[j] = s[j] ^ t;
    q[j] = r[j] ^ t;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<select>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r10
  sub    $0x1,%r8d
  mov    $0x0,%eax
L9:
  mov    (%rcx,%rax,1),%edi
  mov    %edi,%esi
  xor    (%rdx,%rax,1),%esi
  and    %r8d,%esi
  xor    %esi,%edi
  mov    %edi,(%r9,%rax,1)
  xor    (%rdx,%rax,1),%esi
  mov    %esi,(%r10,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L9
  ret
```

assistant: ```c
void select(unsigned int p[64], unsigned int q[64], const unsigned int r[64], const unsigned int s[64], unsigned int b) {
  unsigned int j;
  unsigned int t;
  unsigned int bminus1;
  bminus1 = b - 1;
  for (j = 0; j < 64; ++j) {
    t = bminus1 & (r[j] ^ s[j]);
    p[j] = s[j] ^ t;
    q[j] = r[j] ^ t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<select>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r10
  sub    $0x1,%r8d
  xor    %eax,%eax
L2:
  mov    (%rcx,%rax,1),%edi
  mov    (%rdx,%rax,1),%esi
  xor    %edi,%esi
  and    %r8d,%esi
  xor    %esi,%edi
  mov    %edi,(%r9,%rax,1)
  xor    (%rdx,%rax,1),%esi
  mov    %esi,(%r10,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L2
  ret
```

assistant: ```c
void select(unsigned int p[64], unsigned int q[64], const unsigned int r[64], const unsigned int s[64], unsigned int b) {
  unsigned int j;
  unsigned int t;
  unsigned int bminus1;
  bminus1 = b - 1;
  for (j = 0; j < 64; ++j) {
    t = bminus1 & (r[j] ^ s[j]);
    p[j] = s[j] ^ t;
    q[j] = r[j] ^ t;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<u4_12_from_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jb     L13
  mov    $0x0,%eax
  jmp    L30
L13:
  movss  D25(%rip),%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jb     L12
  mov    $0xffff,%eax
  jmp    L30
L12:
  movss  D22(%rip),%xmm0
  mulss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D29(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
L30:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
data_type: byte[4]
name: parse_data
arguments: data_label: D22
data_type: byte[4]
name: parse_data
arguments: data_label: D29
data_type: f64

tool: {"D25": [0x00,0xff,0x7f,0x41]}

tool: {"D22": [0x00,0x00,0x80,0x45]}

tool: D29: 0.5

assistant: ```c
uint16_t u4_12_from_float(float f) {
  static const float scale = (float)(1 << 12);
  static const float limpos = 0xffff / scale;
  if (f <= 0.) {
    return 0;
  } else if (f >= limpos) {
    return 0xffff;
  }
  return f * scale + 0.5;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<u4_12_from_float>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  jae    L0
  mov    $0xffff,%eax
  comiss D22(%rip),%xmm0
  jae    L0
  mulss  D9(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  D24(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L0:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D22
data_type: byte[4]
name: unpack_data
arguments: tag: D9
data_type: byte[4]
name: unpack_data
arguments: tag: D24
data_type: f64

tool: {"D22": [0x00,0xff,0x7f,0x41]}

tool: {"D9": [0x00,0x00,0x80,0x45]}

tool: D24: 0.5

assistant: ```c
uint16_t u4_12_from_float(float f) {
  static const float scale = (float)(1 << 12);
  static const float limpos = 0xffff / scale;
  if (f <= 0.) {
    return 0;
  } else if (f >= limpos) {
    return 0xffff;
  }
  return f * scale + 0.5;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<u4_12_from_float>:
  endbr64
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  jae    L10
  comiss D1(%rip),%xmm0
  mov    $0xffff,%eax
  jae    L10
  mulss  D9(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  D7(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: byte[4]
name: disassemble_data
arguments: tag: D9
datatype: byte[4]
name: disassemble_data
arguments: tag: D7
datatype: f64

tool: {"D1": [0x00,0xff,0x7f,0x41]}

tool: {"D9": [0x00,0x00,0x80,0x45]}

tool: D7: 0.5

assistant: ```c
uint16_t u4_12_from_float(float f) {
  static const float scale = (float)(1 << 12);
  static const float limpos = 0xffff / scale;
  if (f <= 0.) {
    return 0;
  } else if (f >= limpos) {
    return 0xffff;
  }
  return f * scale + 0.5;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<u4_12_from_float>:
  endbr64
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  jae    L19
  comiss D24(%rip),%xmm0
  mov    $0xffff,%eax
  jae    L19
  mulss  D9(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L19:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D24
type_infered: byte[4]
name: unpack_data
arguments: tag: D9
type_infered: byte[4]
name: unpack_data
arguments: tag: D6
type_infered: f64

tool: {"D24": [0x00,0xff,0x7f,0x41]}

tool: {"D9": [0x00,0x00,0x80,0x45]}

tool: D6: 0.5

assistant: ```c
uint16_t u4_12_from_float(float f) {
  static const float scale = (float)(1 << 12);
  static const float limpos = 0xffff / scale;
  if (f <= 0.) {
    return 0;
  } else if (f >= limpos) {
    return 0xffff;
  }
  return f * scale + 0.5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: OS Rocks


assistant: ```c
int main() {
  printf("OS Rocks\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: OS Rocks


assistant: ```c
int main() {
  printf("OS Rocks\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: OS Rocks


assistant: ```c
int main() {
  printf("OS Rocks\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: OS Rocks


assistant: ```c
int main() {
  printf("OS Rocks\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<murmur_finish>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <murmur_fmix@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t murmur_finish(uint32_t state, int len) {
  state ^= len;
  state = murmur_fmix(state);
  return state;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<murmur_finish>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%edi
  call   <murmur_fmix@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t murmur_finish(uint32_t state, int len) {
  state ^= len;
  state = murmur_fmix(state);
  return state;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<murmur_finish>:
  endbr64
  xor    %esi,%edi
  jmp    1050 <murmur_fmix@plt>
```

assistant: ```c
uint32_t murmur_finish(uint32_t state, int len) {
  state ^= len;
  state = murmur_fmix(state);
  return state;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<murmur_finish>:
  endbr64
  xor    %esi,%edi
  jmp    1050 <murmur_fmix@plt>
```

assistant: ```c
uint32_t murmur_finish(uint32_t state, int len) {
  state ^= len;
  state = murmur_fmix(state);
  return state;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m68k_op_pea_32_aw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <m68ki_read_imm_16@plt>
  mov    %eax,%edi
  call   <MAKE_INT_16@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <m68ki_push_32@plt>
  nop
  leave
  ret
```

assistant: ```c
void m68k_op_pea_32_aw(void) {
  unsigned int ea = MAKE_INT_16(m68ki_read_imm_16());
  m68ki_push_32(ea);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m68k_op_pea_32_aw>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <m68ki_read_imm_16@plt>
  mov    %eax,%edi
  call   <MAKE_INT_16@plt>
  mov    %eax,%edi
  call   <m68ki_push_32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void m68k_op_pea_32_aw(void) {
  unsigned int ea = MAKE_INT_16(m68ki_read_imm_16());
  m68ki_push_32(ea);
}
```
user: What is the c source code of the assembly code below:

```asm
<m68k_op_pea_32_aw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <m68ki_read_imm_16@plt>
  mov    %eax,%edi
  call   <MAKE_INT_16@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <m68ki_push_32@plt>
```

assistant: ```c
void m68k_op_pea_32_aw(void) {
  unsigned int ea = MAKE_INT_16(m68ki_read_imm_16());
  m68ki_push_32(ea);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m68k_op_pea_32_aw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <m68ki_read_imm_16@plt>
  mov    %eax,%edi
  call   <MAKE_INT_16@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <m68ki_push_32@plt>
```

assistant: ```c
void m68k_op_pea_32_aw(void) {
  unsigned int ea = MAKE_INT_16(m68ki_read_imm_16());
  m68ki_push_32(ea);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dfsConnect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x590,%rsp
  mov    %rdi,-0x1588(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1574(%rbp)
  jmp    L94
L8:
  mov    -0x1574(%rbp),%eax
  cltq
  movl   $0x0,-0x1570(%rbp,%rax,4)
  addl   $0x1,-0x1574(%rbp)
L94:
  cmpl   $0x558,-0x1574(%rbp)
  jle    L8
  movl   $0x26,-0x1574(%rbp)
  jmp    L59
L104:
  mov    -0x1574(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1588(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L85
  mov    -0x1574(%rbp),%eax
  cltq
  mov    -0x1570(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L85
  mov    -0x1574(%rbp),%edx
  mov    -0x1588(%rbp),%rcx
  lea    -0x1570(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dfs@plt>
L85:
  addl   $0x1,-0x1574(%rbp)
L59:
  cmpl   $0x48,-0x1574(%rbp)
  jle    L104
  movl   $0x510,-0x1574(%rbp)
  jmp    L55
L30:
  mov    -0x1574(%rbp),%eax
  cltq
  mov    -0x1570(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L20
  mov    $0x1,%eax
  jmp    L60
L20:
  addl   $0x1,-0x1574(%rbp)
L55:
  cmpl   $0x532,-0x1574(%rbp)
  jle    L30
  mov    $0x0,%eax
L60:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
int dfsConnect(int fatV[]) {
  int Mark[((35 + 2) * (35 + 2))];
  int j;
  for (j = 0; j < ((35 + 2) * (35 + 2)); j++)
    Mark[j] = 0;
  for (j = (35 + 3); j < 35 + (35 + 3); j++)
    if ((1 == fatV[j]) && (!Mark[j]))
      dfs(Mark, fatV, j);
  for (j = (35 + 1) * (35 + 1); j < (35 + 1) * (35 + 1) + 35; j++)
    if (Mark[j])
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dfsConnect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x578,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x1568(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1564(%rsp),%rdx
  mov    %r12,%rax
L87:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L87
  mov    $0x26,%ebx
  mov    %rsp,%r13
  jmp    L93
L52:
  add    $0x1,%rbx
  cmp    $0x49,%rbx
  je     L20
L93:
  mov    %ebx,%edx
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  jne    L52
  cmpl   $0x0,0x0(%r13,%rbx,4)
  jne    L52
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <dfs@plt>
  jmp    L52
L20:
  lea    0x1440(%rsp),%rax
  add    $0x14cc,%r12
L27:
  mov    (%rax),%edx
  test   %edx,%edx
  jne    L55
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L27
  jmp    L46
L55:
  mov    $0x1,%edx
L46:
  mov    0x1568(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    %edx,%eax
  add    $0x1578,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dfsConnect(int fatV[]) {
  int Mark[((35 + 2) * (35 + 2))];
  int j;
  for (j = 0; j < ((35 + 2) * (35 + 2)); j++)
    Mark[j] = 0;
  for (j = (35 + 3); j < 35 + (35 + 3); j++)
    if ((1 == fatV[j]) && (!Mark[j]))
      dfs(Mark, fatV, j);
  for (j = (35 + 1) * (35 + 1); j < (35 + 1) * (35 + 1) + 35; j++)
    if (Mark[j])
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dfsConnect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x570,%rsp
  mov    $0x2ac,%ecx
  mov    $0x26,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1568(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  jmp    L53
  nopl   0x0(%rax)
L55:
  add    $0x1,%rbx
  cmp    $0x49,%rbx
  je     L61
L53:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  mov    %ebx,%edx
  jne    L55
  mov    (%r12,%rbx,4),%eax
  test   %eax,%eax
  jne    L55
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <dfs@plt>
  cmp    $0x49,%rbx
  jne    L53
L61:
  lea    0x1440(%rsp),%rax
  lea    0x14cc(%rsp),%rdx
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x4,%rax
  cmp    %rax,%rdx
  je     L42
L54:
  mov    (%rax),%r8d
  test   %r8d,%r8d
  je     L29
  mov    $0x1,%r8d
L42:
  mov    0x1568(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1570,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dfsConnect(int fatV[]) {
  int Mark[((35 + 2) * (35 + 2))];
  int j;
  for (j = 0; j < ((35 + 2) * (35 + 2)); j++)
    Mark[j] = 0;
  for (j = (35 + 3); j < 35 + (35 + 3); j++)
    if ((1 == fatV[j]) && (!Mark[j]))
      dfs(Mark, fatV, j);
  for (j = (35 + 1) * (35 + 1); j < (35 + 1) * (35 + 1) + 35; j++)
    if (Mark[j])
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dfsConnect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x570,%rsp
  mov    $0x2ac,%ecx
  mov    $0x26,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1568(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  jmp    L17
  nopl   0x0(%rax)
L18:
  add    $0x1,%rbx
  cmp    $0x49,%rbx
  je     L52
L17:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  mov    %ebx,%edx
  jne    L18
  mov    (%r12,%rbx,4),%eax
  test   %eax,%eax
  jne    L18
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <dfs@plt>
  cmp    $0x49,%rbx
  jne    L17
L52:
  lea    0x1440(%rsp),%rax
  lea    0x14cc(%rsp),%rdx
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x4,%rax
  cmp    %rax,%rdx
  je     L56
L74:
  mov    (%rax),%r8d
  test   %r8d,%r8d
  je     L11
  mov    $0x1,%r8d
L56:
  mov    0x1568(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x1570,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dfsConnect(int fatV[]) {
  int Mark[((35 + 2) * (35 + 2))];
  int j;
  for (j = 0; j < ((35 + 2) * (35 + 2)); j++)
    Mark[j] = 0;
  for (j = (35 + 3); j < 35 + (35 + 3); j++)
    if ((1 == fatV[j]) && (!Mark[j]))
      dfs(Mark, fatV, j);
  for (j = (35 + 1) * (35 + 1); j < (35 + 1) * (35 + 1) + 35; j++)
    if (Mark[j])
      return 1;
  return 0;
}
```