ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipv6_prefix_to_mask>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x80,%edi
  ja     L7
  mov    %rsp,%r12
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x8,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    %ebx,%edi
  test   %ebx,%ebx
  je     L34
  lea    -0x1(%rbx),%esi
  mov    %ebx,%edx
  lea    -0x8(%rbx),%ecx
  mov    (%rsp),%rax
  and    $0xfffffff8,%esi
  and    $0x7,%edx
  sub    %esi,%ecx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L56:
  sub    $0x8,%edi
  movl   $0xff,(%rax)
  add    $0x4,%rax
  cmp    %ecx,%edi
  je     L34
L15:
  cmp    %edi,%edx
  jne    L56
  mov    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0xff,%edx
  shl    %cl,%edx
  mov    %edx,(%rax)
L34:
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  xor    %eax,%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L1
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipv6_prefix_to_mask(unsigned prefix, struct in6_addr *mask) {
  struct in6_addr in6;
  int i, j;
  if (prefix > 128)
    return -1;
  memset(&in6, 0x0, sizeof(in6));
  for (i = prefix, j = 0; i > 0; i -= 8, j++) {
    if (i >= 8) {
      in6.s6_addr[j] = 0xff;
    } else {
      in6.s6_addr[j] = (unsigned long)(0xffU << (8 - i));
    }
  }
  memcpy(mask, &in6, sizeof(*mask));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x4(%rbp)
  nop
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((no)) foo(unsigned short *p) {
  int a = *p;
  asm volatile("nop");
  asm volatile("nop" : : "D"(a));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  movzwl (%rdi),%edi
  nop
  nop
  mov    $0x0,%eax
  ret
```

assistant: ```c
int __attribute__((no)) foo(unsigned short *p) {
  int a = *p;
  asm volatile("nop");
  asm volatile("nop" : : "D"(a));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  movzwl (%rdi),%edi
  nop
  nop
  xor    %eax,%eax
  ret
```

assistant: ```c
int __attribute__((no)) foo(unsigned short *p) {
  int a = *p;
  asm volatile("nop");
  asm volatile("nop" : : "D"(a));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  movzwl (%rdi),%edi
  nop
  nop
  xor    %eax,%eax
  ret
```

assistant: ```c
int __attribute__((no)) foo(unsigned short *p) {
  int a = *p;
  asm volatile("nop");
  asm volatile("nop" : : "D"(a));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
int f3() {
  enum E3 { D = 10, E, F };
  static enum E3 e;
  enum E3 e_which_stays;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
int f3() {
  enum E3 { D = 10, E, F };
  static enum E3 e;
  enum E3 e_which_stays;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
int f3() {
  enum E3 { D = 10, E, F };
  static enum E3 e;
  enum E3 e_which_stays;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
int f3() {
  enum E3 { D = 10, E, F };
  static enum E3 e;
  enum E3 e_which_stays;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L4
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partitioning@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
L4:
  nop
  leave
  ret
```

assistant: ```c
void quicksort(int *tab, int p, int r) {
  int q;
  if (p < r) {
    q = partitioning(tab, p, r);
    quicksort(tab, p, q);
    quicksort(tab, q + 1, r);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jl     L1
  ret
L1:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  call   <partitioning@plt>
  mov    %eax,%r13d
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x1(%r13),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quicksort(int *tab, int p, int r) {
  int q;
  if (p < r) {
    q = partitioning(tab, p, r);
    quicksort(tab, p, q);
    quicksort(tab, q + 1, r);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,0x14(%rsp)
  cmp    %esi,%edx
  jle    L21
  mov    %rdi,%rbp
  mov    %esi,%r14d
L80:
  mov    0x14(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,0x8(%rsp)
  cmp    %r14d,%eax
  jle    L29
L132:
  mov    0x8(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,0xc(%rsp)
  cmp    %r14d,%eax
  jle    L164
L12:
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,0x10(%rsp)
  cmp    %r14d,%eax
  jle    L94
L33:
  mov    0x10(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%r12d
  cmp    %r14d,%eax
  jle    L74
L172:
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%ebx
  cmp    %r14d,%eax
  jle    L6
L86:
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%r13d
  cmp    %r14d,%eax
  jle    L107
L138:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%r15d
  cmp    %eax,%r14d
  jge    L179
L126:
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%ecx
  cmp    %r14d,%eax
  jle    L136
L35:
  mov    %ecx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %ecx,0x1c(%rsp)
  call   <partitioning@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  mov    %eax,0x18(%rsp)
  call   <quicksort>
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%ecx
  lea    0x1(%rax),%r14d
  cmp    %r14d,%ecx
  jg     L35
L136:
  lea    0x1(%rcx),%r14d
  cmp    %r14d,%r15d
  jg     L126
L179:
  lea    0x1(%r15),%r14d
  cmp    %r14d,%r13d
  jg     L138
L107:
  lea    0x1(%r13),%r14d
  cmp    %r14d,%ebx
  jg     L86
L6:
  lea    0x1(%rbx),%r14d
  cmp    %r14d,%r12d
  jg     L172
L74:
  lea    0x1(%r12),%r14d
  cmp    %r14d,0x10(%rsp)
  jg     L33
L94:
  mov    0x10(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0xc(%rsp)
  jg     L12
L164:
  mov    0xc(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jg     L132
L29:
  mov    0x8(%rsp),%r14d
  add    $0x1,%r14d
  cmp    0x14(%rsp),%r14d
  jl     L80
L21:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort(int *tab, int p, int r) {
  int q;
  if (p < r) {
    q = partitioning(tab, p, r);
    quicksort(tab, p, q);
    quicksort(tab, q + 1, r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,0x14(%rsp)
  cmp    %esi,%edx
  jle    L138
  mov    %rdi,%rbp
  mov    %esi,%r14d
L30:
  mov    0x14(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,0x8(%rsp)
  cmp    %r14d,%eax
  jle    L3
L56:
  mov    0x8(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,0xc(%rsp)
  cmp    %r14d,%eax
  jle    L11
L177:
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,0x10(%rsp)
  cmp    %r14d,%eax
  jle    L148
L39:
  mov    0x10(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%r12d
  cmp    %r14d,%eax
  jle    L36
L65:
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%ebx
  cmp    %r14d,%eax
  jle    L90
L27:
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%r13d
  cmp    %r14d,%eax
  jle    L76
L111:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%r15d
  cmp    %eax,%r14d
  jge    L83
L101:
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <partitioning@plt>
  mov    %eax,%ecx
  cmp    %r14d,%eax
  jle    L42
L99:
  mov    %ecx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %ecx,0x1c(%rsp)
  call   <partitioning@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  mov    %eax,0x18(%rsp)
  call   <quicksort>
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%ecx
  lea    0x1(%rax),%r14d
  cmp    %r14d,%ecx
  jg     L99
L42:
  lea    0x1(%rcx),%r14d
  cmp    %r14d,%r15d
  jg     L101
L83:
  lea    0x1(%r15),%r14d
  cmp    %r14d,%r13d
  jg     L111
L76:
  lea    0x1(%r13),%r14d
  cmp    %r14d,%ebx
  jg     L27
L90:
  lea    0x1(%rbx),%r14d
  cmp    %r14d,%r12d
  jg     L65
L36:
  lea    0x1(%r12),%r14d
  cmp    %r14d,0x10(%rsp)
  jg     L39
L148:
  mov    0x10(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0xc(%rsp)
  jg     L177
L11:
  mov    0xc(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jg     L56
L3:
  mov    0x8(%rsp),%r14d
  add    $0x1,%r14d
  cmp    0x14(%rsp),%r14d
  jl     L30
L138:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort(int *tab, int p, int r) {
  int q;
  if (p < r) {
    q = partitioning(tab, p, r);
    quicksort(tab, p, q);
    quicksort(tab, q + 1, r);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zhsh_interactive_mode_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L28:
  mov    $0x0,%eax
  call   <wait_jobs@plt>
  mov    $0x0,%eax
  call   <promt@plt>
  nop
L0:
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L28
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <handle_char@plt>
  test   %rax,%rax
  jne    L0
  jmp    L28
```

assistant: ```c
void zhsh_interactive_mode_start(void) {
  char c;
  for (;;) {
    wait_jobs();
    promt();
    while (read(0, &c, 1) && handle_char(c))
      ;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zhsh_interactive_mode_start>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
L15:
  mov    $0x0,%eax
  call   <wait_jobs@plt>
  mov    $0x0,%eax
  call   <promt@plt>
L11:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L15
  movsbl 0x7(%rsp),%edi
  call   <handle_char@plt>
  test   %rax,%rax
  jne    L11
  jmp    L15
```

assistant: ```c
void zhsh_interactive_mode_start(void) {
  char c;
  for (;;) {
    wait_jobs();
    promt();
    while (read(0, &c, 1) && handle_char(c))
      ;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zhsh_interactive_mode_start>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  xchg   %ax,%ax
L18:
  xor    %eax,%eax
  call   <wait_jobs@plt>
  xor    %eax,%eax
  call   <promt@plt>
  xchg   %ax,%ax
L12:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  je     L18
  movsbl 0x7(%rsp),%edi
  call   <handle_char@plt>
  test   %rax,%rax
  jne    L12
  jmp    L18
```

assistant: ```c
void zhsh_interactive_mode_start(void) {
  char c;
  for (;;) {
    wait_jobs();
    promt();
    while (read(0, &c, 1) && handle_char(c))
      ;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zhsh_interactive_mode_start>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  xchg   %ax,%ax
L20:
  xor    %eax,%eax
  call   <wait_jobs@plt>
  xor    %eax,%eax
  call   <promt@plt>
  xchg   %ax,%ax
L15:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  je     L20
  movsbl 0x7(%rsp),%edi
  call   <handle_char@plt>
  test   %rax,%rax
  jne    L15
  jmp    L20
```

assistant: ```c
void zhsh_interactive_mode_start(void) {
  char c;
  for (;;) {
    wait_jobs();
    promt();
    while (read(0, &c, 1) && handle_char(c))
      ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Get_grid_rank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L23
  mov    -0x18(%rbp),%rax
  movl   $0x2,(%rax)
  mov    $0x0,%eax
  jmp    L38
L23:
  cmpl   $0x1,-0xc(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L38
L5:
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
  mov    $0x1,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int Get_grid_rank(void *self, int grid, int *rank) {
  if (grid == 0) {
    *rank = 2;
    return (0);
  } else if (grid == 1) {
    *rank = 0;
    return (0);
  } else {
    *rank = -1;
    return (1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Get_grid_rank>:
  endbr64
  test   %esi,%esi
  je     L9
  cmp    $0x1,%esi
  sete   %cl
  movzbl %cl,%ecx
  sub    $0x1,%ecx
  cmp    $0x1,%esi
  setne  %al
  movzbl %al,%eax
L4:
  mov    %ecx,(%rdx)
  ret
L9:
  mov    %esi,%eax
  mov    $0x2,%ecx
  jmp    L4
```

assistant: ```c
int Get_grid_rank(void *self, int grid, int *rank) {
  if (grid == 0) {
    *rank = 2;
    return (0);
  } else if (grid == 1) {
    *rank = 0;
    return (0);
  } else {
    *rank = -1;
    return (1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Get_grid_rank>:
  endbr64
  test   %esi,%esi
  je     L6
  xor    %eax,%eax
  cmp    $0x1,%esi
  sete   %al
  xor    %r8d,%r8d
  sub    $0x1,%eax
  cmp    $0x1,%esi
  setne  %r8b
  mov    %eax,(%rdx)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    $0x2,%eax
  mov    %eax,(%rdx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Get_grid_rank(void *self, int grid, int *rank) {
  if (grid == 0) {
    *rank = 2;
    return (0);
  } else if (grid == 1) {
    *rank = 0;
    return (0);
  } else {
    *rank = -1;
    return (1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Get_grid_rank>:
  endbr64
  test   %esi,%esi
  je     L3
  xor    %eax,%eax
  cmp    $0x1,%esi
  sete   %al
  xor    %r8d,%r8d
  sub    $0x1,%eax
  cmp    $0x1,%esi
  setne  %r8b
  mov    %eax,(%rdx)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    $0x2,%eax
  mov    %eax,(%rdx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Get_grid_rank(void *self, int grid, int *rank) {
  if (grid == 0) {
    *rank = 2;
    return (0);
  } else if (grid == 1) {
    *rank = 0;
    return (0);
  } else {
    *rank = -1;
    return (1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x41,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  cmp    $0x41,%eax
  je     L23
  cmp    $0x42,%eax
  je     L13
  jmp    L19
L23:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L13:
  movzbl -0x1(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x1(%rbp)
  nop
L19:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char val = 'A';
  switch (val) {
  case 'A':
    val++;
    __attribute__((fallthrough));
  case 'B':
    val *= 2;
    break;
  default:
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  char val = 'A';
  switch (val) {
  case 'A':
    val++;
    __attribute__((fallthrough));
  case 'B':
    val *= 2;
    break;
  default:
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char val = 'A';
  switch (val) {
  case 'A':
    val++;
    __attribute__((fallthrough));
  case 'B':
    val *= 2;
    break;
  default:
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char val = 'A';
  switch (val) {
  case 'A':
    val++;
    __attribute__((fallthrough));
  case 'B':
    val *= 2;
    break;
  default:
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DCode_mime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L29
L21:
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L14
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L29:
  movzbl -0x1(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jg     L21
  jmp    L10
L14:
  nop
L10:
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char DCode_mime(unsigned char code, const unsigned char *pMimiArray, int len) {
  unsigned char index = 0;
  for (index = 0; index < len; index++) {
    if (pMimiArray[index] == code) {
      break;
    }
  }
  return index;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DCode_mime>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    $0x0,%eax
L15:
  movzbl %al,%ecx
  cmp    %dil,(%rsi,%rcx,1)
  je     L18
  add    $0x1,%eax
  movzbl %al,%ecx
  cmp    %edx,%ecx
  jl     L15
  ret
L2:
  mov    $0x0,%eax
L18:
  ret
```

assistant: ```c
unsigned char DCode_mime(unsigned char code, const unsigned char *pMimiArray, int len) {
  unsigned char index = 0;
  for (index = 0; index < len; index++) {
    if (pMimiArray[index] == code) {
      break;
    }
  }
  return index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DCode_mime>:
  endbr64
  xor    %eax,%eax
  test   %edx,%edx
  jg     L36
  jmp    L18
  nopl   0x0(%rax)
L39:
  add    $0x1,%eax
  movzbl %al,%ecx
  cmp    %edx,%ecx
  jge    L6
L36:
  movzbl %al,%ecx
  cmp    %dil,(%rsi,%rcx,1)
  jne    L39
L18:
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
unsigned char DCode_mime(unsigned char code, const unsigned char *pMimiArray, int len) {
  unsigned char index = 0;
  for (index = 0; index < len; index++) {
    if (pMimiArray[index] == code) {
      break;
    }
  }
  return index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DCode_mime>:
  endbr64
  xor    %eax,%eax
  test   %edx,%edx
  jg     L3
  jmp    L18
  nopl   0x0(%rax)
L17:
  add    $0x1,%eax
  movzbl %al,%ecx
  cmp    %edx,%ecx
  jge    L20
L3:
  movzbl %al,%ecx
  cmp    %dil,(%rsi,%rcx,1)
  jne    L17
L18:
  ret
  nopl   0x0(%rax)
L20:
  ret
```

assistant: ```c
unsigned char DCode_mime(unsigned char code, const unsigned char *pMimiArray, int len) {
  unsigned char index = 0;
  for (index = 0; index < len; index++) {
    if (pMimiArray[index] == code) {
      break;
    }
  }
  return index;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <hoedown_version@plt>
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: Built with Hoedown v%d.%d.%d.%d.


assistant: ```c
void print_version() {
  int major, minor, revision, extras;
  hoedown_version(&major, &minor, &revision, &extras);
  printf("Built with Hoedown v%d.%d.%d.%d.\n", major, minor, revision, extras);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_version>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <hoedown_version@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: Built with Hoedown v%d.%d.%d.%d.


assistant: ```c
void print_version() {
  int major, minor, revision, extras;
  hoedown_version(&major, &minor, &revision, &extras);
  printf("Built with Hoedown v%d.%d.%d.%d.\n", major, minor, revision, extras);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_version>:
  endbr64
  sub    $0x28,%rsp
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <hoedown_version@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  lea    D6(%rip),%rdi
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: Built with Hoedown v%d.%d.%d.%d.


assistant: ```c
void print_version() {
  int major, minor, revision, extras;
  hoedown_version(&major, &minor, &revision, &extras);
  printf("Built with Hoedown v%d.%d.%d.%d.\n", major, minor, revision, extras);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_version>:
  endbr64
  sub    $0x28,%rsp
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <hoedown_version@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%ecx
  lea    D5(%rip),%rdi
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D5: Built with Hoedown v%d.%d.%d.%d.


assistant: ```c
void print_version() {
  int major, minor, revision, extras;
  hoedown_version(&major, &minor, &revision, &extras);
  printf("Built with Hoedown v%d.%d.%d.%d.\n", major, minor, revision, extras);
}
```