ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L137:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L42:
  lea    -0x3f1(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x3f1(%rbp),%eax
  cmp    $0x63,%al
  je     L34
  movzbl -0x3f1(%rbp),%eax
  cmp    $0x71,%al
  je     L34
  movzbl -0x3f1(%rbp),%eax
  cmp    $0x64,%al
  je     L34
  jmp    L42
L34:
  movzbl -0x3f1(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x71,%eax
  je     L13
  cmp    $0x71,%eax
  jg     L51
  cmp    $0x63,%eax
  je     L21
  cmp    $0x64,%eax
  je     L103
  jmp    L51
L21:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <rot13@plt>
  jmp    L51
L103:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <rot13@plt>
  jmp    L51
L13:
  nop
L51:
  movzbl -0x3f1(%rbp),%eax
  cmp    $0x71,%al
  je     L105
  jmp    L137
L105:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D26
type: string
name: parse_data
arguments: label: D36
type: string

tool: D11: Enter option: 

tool: D26: %c

tool: D36: %1000s

assistant: ```c
int main() {
  char mas[1000];
  char opt;
  while (1) {
    printf("Enter option: ");
    do {
      scanf("%c", &opt);
      if ((opt == 'c') || (opt == 'q') || (opt == 'd'))
        break;
    } while (1);
    switch (opt) {
    case 'c':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'd':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'q':
      break;
    }
    if (opt == 'q')
      break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%r12
  lea    D10(%rip),%rbp
  lea    0xf(%rsp),%rbx
  lea    D20(%rip),%r13
  jmp    L44
L96:
  cmp    $0x63,%al
  je     L19
  cmp    $0x64,%al
  je     L10
L51:
  cmpb   $0x71,0xf(%rsp)
  je     L4
L44:
  mov    %r12,%rdi
  call   <printf@plt>
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  jbe    L96
  cmp    $0x71,%al
  jne    L0
  jmp    L96
L19:
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <rot13@plt>
  jmp    L51
L10:
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <rot13@plt>
  jmp    L51
L4:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D20
type_guessed: string

tool: D6: Enter option: 

tool: D10: %c

tool: D20: %1000s

assistant: ```c
int main() {
  char mas[1000];
  char opt;
  while (1) {
    printf("Enter option: ");
    do {
      scanf("%c", &opt);
      if ((opt == 'c') || (opt == 'q') || (opt == 'd'))
        break;
    } while (1);
    switch (opt) {
    case 'c':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'd':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'q':
      break;
    }
    if (opt == 'q')
      break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D27(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D21(%rip),%rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
L19:
  mov    %r13,%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x63,%al
  je     L24
  cmp    $0x71,%al
  je     L24
  cmp    $0x64,%al
  jne    L12
L42:
  lea    0x10(%rsp),%r12
  mov    %r14,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <rot13@plt>
  movzbl 0xf(%rsp),%eax
L29:
  cmp    $0x71,%al
  jne    L19
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  ja     L29
  jmp    L42
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string

tool: D27: %1000s

tool: D23: Enter option: 

tool: D21: %c

assistant: ```c
int main() {
  char mas[1000];
  char opt;
  while (1) {
    printf("Enter option: ");
    do {
      scanf("%c", &opt);
      if ((opt == 'c') || (opt == 'q') || (opt == 'd'))
        break;
    } while (1);
    switch (opt) {
    case 'c':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'd':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'q':
      break;
    }
    if (opt == 'q')
      break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
L48:
  mov    %r13,%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x63,%al
  je     L66
  cmp    $0x71,%al
  je     L66
  cmp    $0x64,%al
  jne    L24
L28:
  lea    0x10(%rsp),%r12
  mov    %r14,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <rot13@plt>
  movzbl 0xf(%rsp),%eax
L68:
  cmp    $0x71,%al
  jne    L48
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  ja     L68
  jmp    L28
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D0
type: string

tool: D20: %1000s

tool: D29: Enter option: 

tool: D0: %c

assistant: ```c
int main() {
  char mas[1000];
  char opt;
  while (1) {
    printf("Enter option: ");
    do {
      scanf("%c", &opt);
      if ((opt == 'c') || (opt == 'q') || (opt == 'd'))
        break;
    } while (1);
    switch (opt) {
    case 'c':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'd':
      scanf("%1000s", mas);
      rot13(mas);
      break;
    case 'q':
      break;
    }
    if (opt == 'q')
      break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  sub    $0x30,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string

tool: D19: 1. Add user


tool: D9: 2. Quit


assistant: ```c
int ask() {
  printf("1. Add user\n");
  printf("2. Quit\n");
  return getchar() - 48;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ask>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  sub    $0x30,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string

tool: D17: 1. Add user


tool: D10: 2. Quit


assistant: ```c
int ask() {
  printf("1. Add user\n");
  printf("2. Quit\n");
  return getchar() - 48;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ask>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  sub    $0x30,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D8: 1. Add user


tool: D7: 2. Quit


assistant: ```c
int ask() {
  printf("1. Add user\n");
  printf("2. Quit\n");
  return getchar() - 48;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ask>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  sub    $0x30,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string

tool: D1: 1. Add user


tool: D12: 2. Quit


assistant: ```c
int ask() {
  printf("1. Add user\n");
  printf("2. Quit\n");
  return getchar() - 48;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x68(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x64(%rbp)
  movl   $0x0,-0x70(%rbp)
  mov    -0x64(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x6c(%rbp)
  jmp    L30
L0:
  mov    -0x70(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%edx
  mov    -0x6c(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L41
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L37
L41:
  addl   $0x1,-0x70(%rbp)
  subl   $0x1,-0x6c(%rbp)
L30:
  mov    -0x70(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  jl     L0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L37:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D18
type: string
name: read_data
arguments: label: D9
type: string

tool: D18: NO

tool: D9: YES

assistant: ```c
int main() {
  char str[80];
  int i, len, flag = 0;
  int left, right;
  gets(str);
  len = strlen(str);
  left = 0;
  right = len - 1;
  while (left < right) {
    if (str[left] != str[right]) {
      puts("NO");
      return 0;
    }
    left++;
    right--;
  }
  puts("YES");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L33
  cltq
  mov    $0x0,%edx
  mov    %rsp,%rcx
L41:
  movzbl (%rcx,%rax,1),%esi
  cmp    %sil,(%rcx,%rdx,1)
  jne    L48
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L41
L33:
  lea    D5(%rip),%rdi
  call   <puts@plt>
L43:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  ret
L48:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  jmp    L43
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D13
datatype: string

tool: D5: YES

tool: D13: NO

assistant: ```c
int main() {
  char str[80];
  int i, len, flag = 0;
  int left, right;
  gets(str);
  len = strlen(str);
  left = 0;
  right = len - 1;
  while (left < right) {
    if (str[left] != str[right]) {
      puts("NO");
      return 0;
    }
    left++;
    right--;
  }
  puts("YES");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L9
  cltq
  xor    %edx,%edx
  jmp    L30
  nopl   0x0(%rax)
L41:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jge    L9
L30:
  movzbl (%rbx,%rax,1),%ecx
  cmp    %cl,(%rbx,%rdx,1)
  je     L41
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L43
L9:
  lea    D1(%rip),%rdi
  call   <puts@plt>
L43:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string

tool: D11: NO

tool: D1: YES

assistant: ```c
int main() {
  char str[80];
  int i, len, flag = 0;
  int left, right;
  gets(str);
  len = strlen(str);
  left = 0;
  right = len - 1;
  while (left < right) {
    if (str[left] != str[right]) {
      puts("NO");
      return 0;
    }
    left++;
    right--;
  }
  puts("YES");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L53
  cltq
  xor    %edx,%edx
  jmp    L26
  nopl   0x0(%rax)
L2:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jge    L53
L26:
  movzbl (%rbx,%rax,1),%ecx
  cmp    %cl,(%rbx,%rdx,1)
  je     L2
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L29
L53:
  lea    D14(%rip),%rdi
  call   <puts@plt>
L29:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string

tool: D1: NO

tool: D14: YES

assistant: ```c
int main() {
  char str[80];
  int i, len, flag = 0;
  int left, right;
  gets(str);
  len = strlen(str);
  left = 0;
  right = len - 1;
  while (left < right) {
    if (str[left] != str[right]) {
      puts("NO");
      return 0;
    }
    left++;
    right--;
  }
  puts("YES");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sio_string_found>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L48
L65:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L79
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L65
  jmp    L71
L79:
  nop
L71:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L26
  mov    -0x10(%rbp),%eax
  jmp    L58
L26:
  addl   $0x1,-0x10(%rbp)
L52:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  mov    $0xffffffff,%eax
L58:
  leave
  ret
```

assistant: ```c
int sio_string_found(buf, idex, ss)
char *buf;
int idex;
char *ss;
{
  int i, j, lss, bss;
  lss = (int)strlen(ss);
  bss = idex - lss + 1;
  for (i = 0; i < bss; i++) {
    for (j = 0; j < lss; j++)
      if (ss[j] != buf[i + j])
        break;
    if (j == lss)
      return (i);
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sio_string_found>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %r12d,%r10d
  sub    %eax,%r10d
  js     L79
  mov    %eax,%r9d
  mov    %rbx,%rsi
  mov    $0x0,%r8d
  lea    -0x1(%rax),%edi
  mov    $0x0,%r11d
  mov    $0x0,%ebx
  jmp    L72
L73:
  mov    %rcx,%rax
L59:
  mov    %eax,%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,0x0(%rbp,%rax,1)
  jne    L0
  lea    0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  jne    L73
L0:
  cmp    %edx,%r9d
  je     L55
  add    $0x1,%r8d
  add    $0x1,%rsi
  cmp    %r8d,%r10d
  jl     L61
L72:
  mov    %r11,%rax
  mov    %ebx,%edx
  test   %r9d,%r9d
  jg     L59
  jmp    L0
L79:
  mov    $0xffffffff,%r8d
  jmp    L55
L61:
  mov    $0xffffffff,%r8d
L55:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sio_string_found(buf, idex, ss)
char *buf;
int idex;
char *ss;
{
  int i, j, lss, bss;
  lss = (int)strlen(ss);
  bss = idex - lss + 1;
  for (i = 0; i < bss; i++) {
    for (j = 0; j < lss; j++)
      if (ss[j] != buf[i + j])
        break;
    if (j == lss)
      return (i);
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sio_string_found>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %r12d,%r9d
  sub    %eax,%r9d
  js     L31
  lea    -0x1(%rax),%esi
  mov    %eax,%edi
  mov    %rbx,%rcx
  xor    %r8d,%r8d
  add    $0x2,%rsi
L86:
  mov    $0x1,%eax
  xor    %edx,%edx
  test   %edi,%edi
  jg     L67
  jmp    L28
  nopl   (%rax)
L73:
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L28
L67:
  movzbl -0x1(%rax,%rcx,1),%ebx
  cmp    %bl,-0x1(%rbp,%rax,1)
  je     L73
  add    $0x1,%r8d
  add    $0x1,%rcx
  cmp    %r8d,%r9d
  jge    L86
L31:
  mov    $0xffffffff,%r8d
L44:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  cmp    %edx,%edi
  je     L44
  add    $0x1,%r8d
  add    $0x1,%rcx
  cmp    %r8d,%r9d
  jge    L86
  jmp    L31
```

assistant: ```c
int sio_string_found(buf, idex, ss)
char *buf;
int idex;
char *ss;
{
  int i, j, lss, bss;
  lss = (int)strlen(ss);
  bss = idex - lss + 1;
  for (i = 0; i < bss; i++) {
    for (j = 0; j < lss; j++)
      if (ss[j] != buf[i + j])
        break;
    if (j == lss)
      return (i);
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sio_string_found>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %r12d,%r9d
  sub    %eax,%r9d
  js     L24
  lea    -0x1(%rax),%esi
  mov    %eax,%edi
  mov    %rbx,%rcx
  xor    %r8d,%r8d
  add    $0x2,%rsi
L40:
  mov    $0x1,%eax
  xor    %edx,%edx
  test   %edi,%edi
  jg     L0
  jmp    L80
  nopl   (%rax)
L59:
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L80
L0:
  movzbl -0x1(%rcx,%rax,1),%ebx
  cmp    %bl,-0x1(%rbp,%rax,1)
  je     L59
  add    $0x1,%r8d
  add    $0x1,%rcx
  cmp    %r8d,%r9d
  jge    L40
L24:
  mov    $0xffffffff,%r8d
L34:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L80:
  cmp    %edx,%edi
  je     L34
  add    $0x1,%r8d
  add    $0x1,%rcx
  cmp    %r8d,%r9d
  jge    L40
  jmp    L24
```

assistant: ```c
int sio_string_found(buf, idex, ss)
char *buf;
int idex;
char *ss;
{
  int i, j, lss, bss;
  lss = (int)strlen(ss);
  bss = idex - lss + 1;
  for (i = 0; i < bss; i++) {
    for (j = 0; j < lss; j++)
      if (ss[j] != buf[i + j])
        break;
    if (j == lss)
      return (i);
  }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testSecImplied@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testSedImplied@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testSeiImplied@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D4: testSecImplied: %d


tool: D29: testSedImplied: %d


tool: D8: testSeiImplied: %d


assistant: ```c
void testSet() {
  printf("testSecImplied: %d\r\n", testSecImplied());
  printf("testSedImplied: %d\r\n", testSedImplied());
  printf("testSeiImplied: %d\r\n", testSeiImplied());
}
```
user: Translate the below assembly code into C programming language:

```asm
<testSet>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testSecImplied@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testSedImplied@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <testSeiImplied@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D2: testSecImplied: %d


tool: D10: testSedImplied: %d


tool: D14: testSeiImplied: %d


assistant: ```c
void testSet() {
  printf("testSecImplied: %d\r\n", testSecImplied());
  printf("testSedImplied: %d\r\n", testSedImplied());
  printf("testSeiImplied: %d\r\n", testSeiImplied());
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<testSet>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testSecImplied@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testSedImplied@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <testSeiImplied@plt>
  lea    D22(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1080 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string

tool: D7: testSecImplied: %d


tool: D0: testSedImplied: %d


tool: D22: testSeiImplied: %d


assistant: ```c
void testSet() {
  printf("testSecImplied: %d\r\n", testSecImplied());
  printf("testSedImplied: %d\r\n", testSedImplied());
  printf("testSeiImplied: %d\r\n", testSeiImplied());
}
```