ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  lea    -0x9000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0xc68,%rsp
  xor    %ecx,%ecx
  mov    $0x28,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  nopl   0x0(%rax)
L19:
  cmp    $0x28,%ecx
  mov    %esi,%eax
  cmovne 0xa0(%rsp),%eax
  add    $0x1,%ecx
  add    $0x4,%rdx
  mov    %eax,0xa0(%rsp)
  mov    0x4(%rdx),%eax
  add    (%rdx),%eax
  add    0x8(%rdx),%eax
  add    0xc(%rdx),%eax
  add    0x10(%rdx),%eax
  add    0x14(%rdx),%eax
  mov    %eax,-0x4(%rdx)
  cmp    $0x2710,%ecx
  jne    L19
  mov    0x50(%rsp),%eax
  mov    0x9c58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x9c68,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test() {
  int a[10000 + 6];
  unsigned i;
  for (i = 0; i < 10000; i++) {
    a[i] = i + 12;
    if (i == 40)
      a[i] = i;
    else
      a[i] = i + 1;
    a[i] = i + 12;
    a[i] = a[i + 1];
    a[i] += a[i + 2];
    a[i] += a[i + 3];
    a[i] += a[i + 4];
    a[i] += a[i + 5];
    a[i] += a[i + 6];
  }
  return a[20];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_request>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L33:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L46
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L53
L46:
  cmpl   $0x0,-0x4(%rbp)
  jne    L56
  mov    $0x1,%eax
  jmp    L53
L56:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L73
  mov    $0x0,%eax
  jmp    L53
L73:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L33
  mov    -0x18(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L53:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: Read error: 

assistant: ```c
int read_request(const int s, char *req, const int length) {
  int pos = 0;
  while (pos < length) {
    int r = read(s, req + pos, length - pos);
    req[length - 1] = '\0';
    if (r == -1) {
      perror("Read error: ");
      return -1;
    } else if (r == 0) {
      return 1;
    } else {
      if (strchr(req + pos, '\n')) {
        return 0;
      }
    }
    pos += r;
  }
  req[length - 1] = '\0';
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_request>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%r14
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L70
  mov    $0x0,%r12d
  movslq %edx,%r15
L55:
  movslq %r12d,%rbp
  add    %r14,%rbp
  mov    %r13d,%edx
  sub    %r12d,%edx
  mov    %rbp,%rsi
  mov    0xc(%rsp),%edi
  call   <read@plt>
  mov    %eax,%ebx
  movb   $0x0,-0x1(%r14,%r15,1)
  cmp    $0xffffffff,%eax
  je     L64
  test   %eax,%eax
  je     L48
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L2
  add    %ebx,%r12d
  cmp    %r12d,%r13d
  jg     L55
L70:
  movslq %r13d,%r13
  movb   $0x0,-0x1(%r14,%r13,1)
  mov    $0x1,%ebx
L12:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L12
L48:
  mov    $0x1,%ebx
  jmp    L12
L2:
  mov    $0x0,%ebx
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: Read error: 

assistant: ```c
int read_request(const int s, char *req, const int length) {
  int pos = 0;
  while (pos < length) {
    int r = read(s, req + pos, length - pos);
    req[length - 1] = '\0';
    if (r == -1) {
      perror("Read error: ");
      return -1;
    } else if (r == 0) {
      return 1;
    } else {
      if (strchr(req + pos, '\n')) {
        return 0;
      }
    }
    pos += r;
  }
  req[length - 1] = '\0';
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_request>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rax,%rbx
  lea    -0x1(%rsi,%rax,1),%rax
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  test   %ebx,%ebx
  jg     L71
  jmp    L11
  nopl   0x0(%rax)
L33:
  test   %r12d,%r12d
  je     L31
  mov    $0xa,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L20
  add    %r12d,%r14d
  cmp    %r14d,%ebx
  jle    L11
L71:
  movslq %r14d,%r15
  mov    %ebx,%edx
  mov    %r13d,%edi
  add    %rbp,%r15
  sub    %r14d,%edx
  mov    %r15,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  cmp    $0xffffffff,%r12d
  jne    L33
  lea    D8(%rip),%rdi
  call   <perror@plt>
L78:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L11:
  mov    0x8(%rsp),%rax
  mov    $0x1,%r12d
  movb   $0x0,(%rax)
  jmp    L78
L31:
  mov    $0x1,%r12d
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %r12d,%r12d
  jmp    L78
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: Read error: 

assistant: ```c
int read_request(const int s, char *req, const int length) {
  int pos = 0;
  while (pos < length) {
    int r = read(s, req + pos, length - pos);
    req[length - 1] = '\0';
    if (r == -1) {
      perror("Read error: ");
      return -1;
    } else if (r == 0) {
      return 1;
    } else {
      if (strchr(req + pos, '\n')) {
        return 0;
      }
    }
    pos += r;
  }
  req[length - 1] = '\0';
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_request>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rax,%rbx
  lea    -0x1(%rsi,%rax,1),%rax
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  test   %ebx,%ebx
  jg     L0
  jmp    L70
  nopl   0x0(%rax)
L19:
  test   %r12d,%r12d
  je     L40
  mov    $0xa,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L77
  add    %r12d,%r14d
  cmp    %r14d,%ebx
  jle    L70
L0:
  movslq %r14d,%r15
  mov    %ebx,%edx
  mov    %r13d,%edi
  add    %rbp,%r15
  sub    %r14d,%edx
  mov    %r15,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  cmp    $0xffffffff,%r12d
  jne    L19
  lea    D7(%rip),%rdi
  call   <perror@plt>
L13:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L70:
  mov    0x8(%rsp),%rax
  mov    $0x1,%r12d
  movb   $0x0,(%rax)
  jmp    L13
L40:
  mov    $0x1,%r12d
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L77:
  xor    %r12d,%r12d
  jmp    L13
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: Read error: 

assistant: ```c
int read_request(const int s, char *req, const int length) {
  int pos = 0;
  while (pos < length) {
    int r = read(s, req + pos, length - pos);
    req[length - 1] = '\0';
    if (r == -1) {
      perror("Read error: ");
      return -1;
    } else if (r == 0) {
      return 1;
    } else {
      if (strchr(req + pos, '\n')) {
        return 0;
      }
    }
    pos += r;
  }
  req[length - 1] = '\0';
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CarveMaze>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8d,0x4(%rsp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    $0x0,%ecx
  mov    $0x0,%r15d
  jmp    L78
L35:
  mov    %eax,%ebp
  mov    $0x0,%ebx
  jmp    L62
L45:
  mov    %r15d,%ebp
  mov    $0xffffffff,%ebx
  jmp    L62
L48:
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  add    $0x1,%ecx
  cmp    $0x3,%ecx
  jg     L17
L78:
  cmp    $0x1,%eax
  je     L35
  cmp    $0x2,%eax
  je     L45
  test   %eax,%eax
  mov    $0xffffffff,%ebp
  cmove  %eax,%ebp
  cmp    $0x1,%eax
  setb   %bl
  movzbl %bl,%ebx
L62:
  lea    (%rbx,%r13,1),%esi
  add    %esi,%ebx
  test   %ebx,%ebx
  jle    L48
  cmp    %r12d,%ebx
  jge    L48
  mov    0x4(%rsp),%edi
  lea    0x0(%rbp,%rdi,1),%edx
  add    %edx,%ebp
  test   %ebp,%ebp
  jle    L48
  cmp    %r14d,%ebp
  jge    L48
  imul   %r12d,%edx
  add    %esi,%edx
  movslq %edx,%rdx
  add    0x8(%rsp),%rdx
  cmpb   $0x1,(%rdx)
  jne    L48
  mov    %ebp,%esi
  imul   %r12d,%esi
  add    %ebx,%esi
  movslq %esi,%rsi
  add    0x8(%rsp),%rsi
  cmpb   $0x1,(%rsi)
  jne    L48
  movb   $0x0,(%rdx)
  movb   $0x0,(%rsi)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %ebp,0x4(%rsp)
  mov    %ebx,%r13d
  mov    $0x0,%ecx
  jmp    L78
L17:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CarveMaze(char *maze, int width, int height, int x, int y) {
  int x1, y1;
  int x2, y2;
  int dx, dy;
  int dir, count;
  dir = rand() % 4;
  count = 0;
  while (count < 4) {
    dx = 0;
    dy = 0;
    switch (dir) {
    case 0:
      dx = 1;
      break;
    case 1:
      dy = 1;
      break;
    case 2:
      dx = -1;
      break;
    default:
      dy = -1;
      break;
    }
    x1 = x + dx;
    y1 = y + dy;
    x2 = x1 + dx;
    y2 = y1 + dy;
    if (x2 > 0 && x2 < width && y2 > 0 && y2 < height && maze[y1 * width + x1] == 1 && maze[y2 * width + x2] == 1) {
      maze[y1 * width + x1] = 0;
      maze[y2 * width + x2] = 0;
      x = x2;
      y = y2;
      dir = rand() % 4;
      count = 0;
    } else {
      dir = (dir + 1) % 4;
      count += 1;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CarveMaze>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  call   <rand@plt>
  mov    0xc(%rsp),%r8d
  xor    %esi,%esi
  lea    D0(%rip),%rcx
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  jmp    L19
  nopl   (%rax)
L8:
  mov    $0x1,%ebx
  mov    %eax,%edx
  sub    %eax,%ebx
  mov    (%rcx,%rdx,4),%ebp
  lea    (%rbx,%r12,1),%edi
  add    %edi,%ebx
L102:
  test   %ebx,%ebx
  jle    L2
  cmp    %r14d,%ebx
  jge    L2
  lea    0x0(%rbp,%r8,1),%edx
  add    %edx,%ebp
  test   %ebp,%ebp
  jle    L2
  cmp    %r15d,%ebp
  jge    L2
  imul   %r14d,%edx
  add    %edi,%edx
  movslq %edx,%rdx
  add    %r13,%rdx
  cmpb   $0x1,(%rdx)
  je     L83
  nopl   0x0(%rax)
L2:
  add    $0x1,%eax
  add    $0x1,%esi
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x4,%esi
  je     L65
L19:
  cmp    $0x2,%eax
  jbe    L8
  mov    %r12d,%ebx
  mov    %r12d,%edi
  mov    $0xffffffff,%ebp
  jmp    L102
L65:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L83:
  mov    %ebp,%edi
  imul   %r14d,%edi
  add    %ebx,%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  cmpb   $0x1,(%rdi)
  jne    L2
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  mov    %ebx,%r12d
  movb   $0x0,(%rdi)
  call   <rand@plt>
  mov    %ebp,%r8d
  xor    %esi,%esi
  lea    D0(%rip),%rcx
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  jmp    L19
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: 

assistant: ```c
void CarveMaze(char *maze, int width, int height, int x, int y) {
  int x1, y1;
  int x2, y2;
  int dx, dy;
  int dir, count;
  dir = rand() % 4;
  count = 0;
  while (count < 4) {
    dx = 0;
    dy = 0;
    switch (dir) {
    case 0:
      dx = 1;
      break;
    case 1:
      dy = 1;
      break;
    case 2:
      dx = -1;
      break;
    default:
      dy = -1;
      break;
    }
    x1 = x + dx;
    y1 = y + dy;
    x2 = x1 + dx;
    y2 = y1 + dy;
    if (x2 > 0 && x2 < width && y2 > 0 && y2 < height && maze[y1 * width + x1] == 1 && maze[y2 * width + x2] == 1) {
      maze[y1 * width + x1] = 0;
      maze[y2 * width + x2] = 0;
      x = x2;
      y = y2;
      dir = rand() % 4;
      count = 0;
    } else {
      dir = (dir + 1) % 4;
      count += 1;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CarveMaze>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  call   <rand@plt>
  mov    0xc(%rsp),%r8d
  xor    %esi,%esi
  lea    D14(%rip),%rcx
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  jmp    L50
  nopl   (%rax)
L4:
  mov    $0x1,%ebx
  mov    %eax,%edx
  sub    %eax,%ebx
  mov    (%rcx,%rdx,4),%ebp
  lea    (%rbx,%r12,1),%edi
  add    %edi,%ebx
L102:
  test   %ebx,%ebx
  jle    L95
  cmp    %ebx,%r14d
  jle    L95
  lea    0x0(%rbp,%r8,1),%edx
  add    %edx,%ebp
  test   %ebp,%ebp
  jle    L95
  cmp    %r15d,%ebp
  jge    L95
  imul   %r14d,%edx
  add    %edi,%edx
  movslq %edx,%rdx
  add    %r13,%rdx
  cmpb   $0x1,(%rdx)
  je     L106
  nopl   0x0(%rax)
L95:
  add    $0x1,%eax
  add    $0x1,%esi
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x4,%esi
  je     L19
L50:
  cmp    $0x2,%eax
  jbe    L4
  mov    %r12d,%ebx
  mov    %r12d,%edi
  mov    $0xffffffff,%ebp
  jmp    L102
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L106:
  mov    %ebp,%edi
  imul   %r14d,%edi
  add    %ebx,%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  cmpb   $0x1,(%rdi)
  jne    L95
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  mov    %ebx,%r12d
  movb   $0x0,(%rdi)
  call   <rand@plt>
  mov    %ebp,%r8d
  xor    %esi,%esi
  lea    D14(%rip),%rcx
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  jmp    L50
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string

tool: 

assistant: ```c
void CarveMaze(char *maze, int width, int height, int x, int y) {
  int x1, y1;
  int x2, y2;
  int dx, dy;
  int dir, count;
  dir = rand() % 4;
  count = 0;
  while (count < 4) {
    dx = 0;
    dy = 0;
    switch (dir) {
    case 0:
      dx = 1;
      break;
    case 1:
      dy = 1;
      break;
    case 2:
      dx = -1;
      break;
    default:
      dy = -1;
      break;
    }
    x1 = x + dx;
    y1 = y + dy;
    x2 = x1 + dx;
    y2 = y1 + dy;
    if (x2 > 0 && x2 < width && y2 > 0 && y2 < height && maze[y1 * width + x1] == 1 && maze[y2 * width + x2] == 1) {
      maze[y1 * width + x1] = 0;
      maze[y2 * width + x2] = 0;
      x = x2;
      y = y2;
      dir = rand() % 4;
      count = 0;
    } else {
      dir = (dir + 1) % 4;
      count += 1;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<clp2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned clp2(unsigned x) {
  x = x - 1;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  return x + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clp2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  shr    %eax
  or     %edi,%eax
  mov    %eax,%edi
  shr    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  shr    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
unsigned clp2(unsigned x) {
  x = x - 1;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  return x + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clp2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  shr    %eax
  or     %edi,%eax
  mov    %eax,%edi
  shr    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  shr    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
unsigned clp2(unsigned x) {
  x = x - 1;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  return x + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clp2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  shr    %eax
  or     %edi,%eax
  mov    %eax,%edi
  shr    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  shr    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
unsigned clp2(unsigned x) {
  x = x - 1;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  return x + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<utf8char>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jns    L33
  cmp    $0xbf,%al
  jbe    L46
  cmp    $0xdf,%al
  jbe    L41
  cmp    $0xef,%al
  jbe    L17
  cmp    $0xf7,%al
  jbe    L24
  cmp    $0xfb,%al
  jbe    L32
  movzbl 0x1(%rdi),%ecx
  shl    $0x18,%ecx
  and    $0x3f000000,%ecx
  shl    $0x1e,%eax
  and    $0x40000000,%eax
  or     %eax,%ecx
  movzbl 0x5(%rdi),%eax
  and    $0x3f,%eax
  or     %eax,%ecx
  movzbl 0x2(%rdi),%eax
  shl    $0x12,%eax
  and    $0xfc0000,%eax
  or     %eax,%ecx
  movzbl 0x3(%rdi),%eax
  shl    $0xc,%eax
  and    $0x3f000,%eax
  or     %eax,%ecx
  movzbl 0x4(%rdi),%eax
  shl    $0x6,%eax
  and    $0xfc0,%eax
  or     %ecx,%eax
  ret
L33:
  movzbl %al,%eax
  ret
L41:
  shl    $0x6,%eax
  and    $0x7c0,%eax
  movzbl 0x1(%rdi),%edx
  and    $0x3f,%edx
  or     %edx,%eax
  ret
L17:
  movzbl 0x1(%rdi),%ecx
  shl    $0x6,%ecx
  and    $0xfc0,%ecx
  shl    $0xc,%eax
  and    $0xf000,%eax
  or     %eax,%ecx
  movzbl 0x2(%rdi),%eax
  and    $0x3f,%eax
  or     %ecx,%eax
  ret
L24:
  movzbl 0x1(%rdi),%ecx
  shl    $0xc,%ecx
  and    $0x3f000,%ecx
  shl    $0x12,%eax
  and    $0x1c0000,%eax
  or     %eax,%ecx
  movzbl 0x3(%rdi),%eax
  and    $0x3f,%eax
  or     %eax,%ecx
  movzbl 0x2(%rdi),%eax
  shl    $0x6,%eax
  and    $0xfc0,%eax
  or     %ecx,%eax
  ret
L32:
  movzbl 0x1(%rdi),%ecx
  shl    $0x12,%ecx
  and    $0xfc0000,%ecx
  shl    $0x18,%eax
  and    $0x3000000,%eax
  or     %eax,%ecx
  movzbl 0x4(%rdi),%eax
  and    $0x3f,%eax
  or     %eax,%ecx
  movzbl 0x2(%rdi),%eax
  shl    $0xc,%eax
  and    $0x3f000,%eax
  or     %eax,%ecx
  movzbl 0x3(%rdi),%eax
  shl    $0x6,%eax
  and    $0xfc0,%eax
  or     %ecx,%eax
  ret
L46:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utf8char(const char *const ss) {
  const unsigned char *const s = (const unsigned char *)ss;
  if (s[0] < 0x80)
    return s[0];
  if (s[0] < 0xC0)
    return -1;
  if (s[0] < 0xE0)
    return (s[0] & 0x1F) << 6 | s[1] & 0x3F;
  if (s[0] < 0xF0)
    return (s[0] & 0xF) << 12 | (s[1] & 0x3F) << 6 | (s[2] & 0x3F);
  if (s[0] < 0xF8)
    return (s[0] & 0x7) << 18 | (s[1] & 0x3F) << 12 | (s[2] & 0x3F) << 6 | (s[3] & 0x3F);
  if (s[0] < 0xFC)
    return (s[0] & 0x3) << 24 | (s[1] & 0x3F) << 18 | (s[2] & 0x3F) << 12 | (s[3] & 0x3F) << 6 | (s[4] & 0x3F);
  return (s[0] & 0x1) << 30 | (s[1] & 0x3F) << 24 | (s[2] & 0x3F) << 18 | (s[3] & 0x3F) << 12 | (s[4] & 0x3F) << 6 | (s[5] & 0x3F);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8char>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jns    L5
  cmp    $0xbf,%cl
  jbe    L24
  movzbl 0x1(%rdi),%edx
  movzbl %cl,%eax
  cmp    $0xdf,%cl
  jbe    L7
  movzbl 0x2(%rdi),%esi
  movzbl %dl,%r9d
  cmp    $0xef,%cl
  jbe    L37
  movzbl %sil,%edx
  movzbl 0x3(%rdi),%esi
  cmp    $0xf7,%cl
  jbe    L9
  movzbl 0x4(%rdi),%r8d
  cmp    $0xfb,%cl
  jbe    L50
  movzbl 0x5(%rdi),%ecx
  shl    $0x1e,%eax
  shl    $0x18,%r9d
  and    $0x40000000,%eax
  and    $0x3f000000,%r9d
  shl    $0x12,%edx
  or     %r9d,%eax
  and    $0x3f,%ecx
  and    $0xfc0000,%edx
  shl    $0xc,%esi
  or     %ecx,%eax
  and    $0x3f000,%esi
  shl    $0x6,%r8d
  or     %edx,%eax
  and    $0xfc0,%r8d
  or     %esi,%eax
  or     %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  movzbl %cl,%eax
  ret
  nopl   0x0(%rax)
L7:
  shl    $0x6,%eax
  and    $0x3f,%edx
  and    $0x7c0,%eax
  or     %edx,%eax
  ret
  xchg   %ax,%ax
L9:
  shl    $0x12,%eax
  shl    $0xc,%r9d
  and    $0x3f,%esi
  and    $0x1c0000,%eax
  and    $0x3f000,%r9d
  shl    $0x6,%edx
  or     %r9d,%eax
  and    $0xfc0,%edx
  or     %esi,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r9d,%edx
  shl    $0xc,%eax
  shl    $0x6,%edx
  movzwl %ax,%eax
  and    $0xfc0,%edx
  or     %edx,%eax
  mov    %esi,%edx
  and    $0x3f,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L50:
  shl    $0x18,%eax
  shl    $0x12,%r9d
  and    $0x3f,%r8d
  and    $0x3000000,%eax
  and    $0xfc0000,%r9d
  shl    $0xc,%edx
  or     %r9d,%eax
  and    $0x3f000,%edx
  shl    $0x6,%esi
  or     %r8d,%eax
  and    $0xfc0,%esi
  or     %edx,%eax
  or     %esi,%eax
  ret
L24:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utf8char(const char *const ss) {
  const unsigned char *const s = (const unsigned char *)ss;
  if (s[0] < 0x80)
    return s[0];
  if (s[0] < 0xC0)
    return -1;
  if (s[0] < 0xE0)
    return (s[0] & 0x1F) << 6 | s[1] & 0x3F;
  if (s[0] < 0xF0)
    return (s[0] & 0xF) << 12 | (s[1] & 0x3F) << 6 | (s[2] & 0x3F);
  if (s[0] < 0xF8)
    return (s[0] & 0x7) << 18 | (s[1] & 0x3F) << 12 | (s[2] & 0x3F) << 6 | (s[3] & 0x3F);
  if (s[0] < 0xFC)
    return (s[0] & 0x3) << 24 | (s[1] & 0x3F) << 18 | (s[2] & 0x3F) << 12 | (s[3] & 0x3F) << 6 | (s[4] & 0x3F);
  return (s[0] & 0x1) << 30 | (s[1] & 0x3F) << 24 | (s[2] & 0x3F) << 18 | (s[3] & 0x3F) << 12 | (s[4] & 0x3F) << 6 | (s[5] & 0x3F);
}
```