ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  lea    D1(%rip),%rsi
  mov    %rdx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    (%r12),%edi
  imul   (%rbx),%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L24
  mov    (%r12),%edx
  xor    %ebx,%ebx
  lea    D4(%rip),%r14
  nop
L26:
  test   %edx,%edx
  jle    L24
  xor    %r13d,%r13d
  lea    0x24(%rsp),%rbp
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    (%r12),%edx
  mov    0x8(%rsp),%rcx
  pxor   %xmm0,%xmm0
  cvtss2sd 0x24(%rsp),%xmm0
  mov    %edx,%eax
  imul   %ebx,%eax
  add    %r13d,%eax
  add    $0x1,%r13d
  cltq
  movsd  %xmm0,(%rcx,%rax,8)
  cmp    %r13d,%edx
  jg     L2
  mov    0x10(%rsp),%rax
  add    $0x1,%ebx
  cmp    (%rax),%ebx
  jl     L26
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r15,%rdi
  call   <close@plt>
  mov    0x18(%rsp),%rax
  mov    0x8(%rsp),%rsi
  mov    %rsi,(%rax)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string

tool: D5: %d

tool: D1: r

tool: D4: %f

assistant: ```c
void read_matrix(const char *path, double **A, int *m, int *n) {
  int i, j;
  FILE *f = fopen(path, "r");
  fscanf(f, "%d", m);
  fscanf(f, "%d", n);
  double *t = (double *)malloc(sizeof(double) * (*m) * (*n));
  for (j = 0; j < *m; j++) {
    for (i = 0; i < *n; i++) {
      float fl;
      fscanf(f, "%f", &fl);
      t[i + (*n) * j] = fl;
    }
  }
  close(f);
  *A = t;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L31:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L11
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L21
L11:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  cmp    %rax,-0x10(%rbp)
  ja     L31
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  sar    $0x2,%rax
  pop    %rbp
  ret
```

assistant: ```c
int bsearch(const int *begin, const int *end, int x) {
  const int *left = begin - 1;
  const int *right = end;
  while (left + 1 < right) {
    const int *middle = left + (right - left) / 2;
    if (*middle <= x) {
      left = middle;
    } else {
      right = middle;
    }
  }
  return right - begin;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bsearch>:
  endbr64
  mov    %rdi,%r8
  lea    -0x4(%rdi),%rdi
  jmp    L18
L4:
  mov    %rsi,%rcx
  sub    %rdi,%rcx
  mov    %rcx,%rax
  sar    $0x2,%rax
  shr    $0x3f,%rcx
  add    %rax,%rcx
  sar    %rcx
  lea    (%rdi,%rcx,4),%rcx
  cmp    %edx,(%rcx)
  cmovg  %rcx,%rsi
  cmovle %rcx,%rdi
L18:
  lea    0x4(%rdi),%rax
  cmp    %rax,%rsi
  ja     L4
  mov    %rsi,%rax
  sub    %r8,%rax
  sar    $0x2,%rax
  ret
```

assistant: ```c
int bsearch(const int *begin, const int *end, int x) {
  const int *left = begin - 1;
  const int *right = end;
  while (left + 1 < right) {
    const int *middle = left + (right - left) / 2;
    if (*middle <= x) {
      left = middle;
    } else {
      right = middle;
    }
  }
  return right - begin;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bsearch>:
  endbr64
  mov    %rdi,%r9
  lea    -0x4(%rdi),%rdi
  mov    %r9,%rax
  jmp    L11
L32:
  mov    %rsi,%rcx
  sub    %rdi,%rcx
  mov    %rcx,%r8
  shr    $0x3f,%rcx
  sar    $0x2,%r8
  add    %r8,%rcx
  sar    %rcx
  lea    (%rdi,%rcx,4),%rcx
  cmp    %edx,(%rcx)
  jg     L30
  mov    %rcx,%rdi
  lea    0x4(%rcx),%rax
L11:
  cmp    %rax,%rsi
  ja     L32
  mov    %rsi,%rax
  sub    %r9,%rax
  sar    $0x2,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %rcx,%rsi
  jmp    L11
```

assistant: ```c
int bsearch(const int *begin, const int *end, int x) {
  const int *left = begin - 1;
  const int *right = end;
  while (left + 1 < right) {
    const int *middle = left + (right - left) / 2;
    if (*middle <= x) {
      left = middle;
    } else {
      right = middle;
    }
  }
  return right - begin;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bsearch>:
  endbr64
  mov    %rdi,%r9
  lea    -0x4(%rdi),%rdi
  mov    %r9,%rax
  jmp    L4
L30:
  mov    %rsi,%rcx
  sub    %rdi,%rcx
  mov    %rcx,%r8
  shr    $0x3f,%rcx
  sar    $0x2,%r8
  add    %r8,%rcx
  sar    %rcx
  lea    (%rdi,%rcx,4),%rcx
  cmp    %edx,(%rcx)
  jg     L31
  mov    %rcx,%rdi
  lea    0x4(%rcx),%rax
L4:
  cmp    %rax,%rsi
  ja     L30
  mov    %rsi,%rax
  sub    %r9,%rax
  sar    $0x2,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %rcx,%rsi
  jmp    L4
```

assistant: ```c
int bsearch(const int *begin, const int *end, int x) {
  const int *left = begin - 1;
  const int *right = end;
  while (left + 1 < right) {
    const int *middle = left + (right - left) / 2;
    if (*middle <= x) {
      left = middle;
    } else {
      right = middle;
    }
  }
  return right - begin;
}
```
user: What is the c source code of the assembly code below:

```asm
<feed_screen_iterator_tab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <feed_screen_iterator_get_cursor_x@plt>
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <feed_screen_iterator_test_write@plt>
  test   %rax,%rax
  je     L11
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <feed_screen_iterator_write@plt>
  jmp    L15
L11:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <feed_screen_iterator_clear@plt>
  mov    %rax,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long int feed_screen_iterator_tab(struct feed_screen_info const *const p_screen_info, struct feed_screen_iterator *const p_screen_iterator) {
  unsigned long int i_width;
  unsigned short int i_cursor_x;
  i_cursor_x = feed_screen_iterator_get_cursor_x(p_screen_info, p_screen_iterator);
  i_width = (unsigned long int)(8u - (i_cursor_x & 7u));
  if (feed_screen_iterator_test_write(p_screen_info, p_screen_iterator, i_width)) {
    feed_screen_iterator_write(p_screen_info, p_screen_iterator, i_width);
  } else {
    i_width = feed_screen_iterator_clear(p_screen_info, p_screen_iterator);
  }
  return i_width;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<feed_screen_iterator_tab>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <feed_screen_iterator_get_cursor_x@plt>
  and    $0x7,%eax
  mov    $0x8,%ebx
  sub    %eax,%ebx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <feed_screen_iterator_test_write@plt>
  test   %rax,%rax
  je     L13
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <feed_screen_iterator_write@plt>
L9:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <feed_screen_iterator_clear@plt>
  mov    %rax,%rbx
  jmp    L9
```

assistant: ```c
unsigned long int feed_screen_iterator_tab(struct feed_screen_info const *const p_screen_info, struct feed_screen_iterator *const p_screen_iterator) {
  unsigned long int i_width;
  unsigned short int i_cursor_x;
  i_cursor_x = feed_screen_iterator_get_cursor_x(p_screen_info, p_screen_iterator);
  i_width = (unsigned long int)(8u - (i_cursor_x & 7u));
  if (feed_screen_iterator_test_write(p_screen_info, p_screen_iterator, i_width)) {
    feed_screen_iterator_write(p_screen_info, p_screen_iterator, i_width);
  } else {
    i_width = feed_screen_iterator_clear(p_screen_info, p_screen_iterator);
  }
  return i_width;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<feed_screen_iterator_tab>:
  endbr64
  push   %r13
  mov    $0x8,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <feed_screen_iterator_get_cursor_x@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  and    $0x7,%eax
  sub    %eax,%r13d
  mov    %r13,%rdx
  call   <feed_screen_iterator_test_write@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <feed_screen_iterator_clear@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <feed_screen_iterator_write@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long int feed_screen_iterator_tab(struct feed_screen_info const *const p_screen_info, struct feed_screen_iterator *const p_screen_iterator) {
  unsigned long int i_width;
  unsigned short int i_cursor_x;
  i_cursor_x = feed_screen_iterator_get_cursor_x(p_screen_info, p_screen_iterator);
  i_width = (unsigned long int)(8u - (i_cursor_x & 7u));
  if (feed_screen_iterator_test_write(p_screen_info, p_screen_iterator, i_width)) {
    feed_screen_iterator_write(p_screen_info, p_screen_iterator, i_width);
  } else {
    i_width = feed_screen_iterator_clear(p_screen_info, p_screen_iterator);
  }
  return i_width;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<feed_screen_iterator_tab>:
  endbr64
  push   %r13
  mov    $0x8,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <feed_screen_iterator_get_cursor_x@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  and    $0x7,%eax
  sub    %eax,%r13d
  mov    %r13,%rdx
  call   <feed_screen_iterator_test_write@plt>
  test   %rax,%rax
  jne    L6
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <feed_screen_iterator_clear@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <feed_screen_iterator_write@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long int feed_screen_iterator_tab(struct feed_screen_info const *const p_screen_info, struct feed_screen_iterator *const p_screen_iterator) {
  unsigned long int i_width;
  unsigned short int i_cursor_x;
  i_cursor_x = feed_screen_iterator_get_cursor_x(p_screen_info, p_screen_iterator);
  i_width = (unsigned long int)(8u - (i_cursor_x & 7u));
  if (feed_screen_iterator_test_write(p_screen_info, p_screen_iterator, i_width)) {
    feed_screen_iterator_write(p_screen_info, p_screen_iterator, i_width);
  } else {
    i_width = feed_screen_iterator_clear(p_screen_info, p_screen_iterator);
  }
  return i_width;
}
```
user: What is the c source code of the assembly code below:

```asm
<ctime_nonl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ctime_nonl(time_t *date) {
  char *d = ctime(date);
  d[strlen(d) - 1] = '\0';
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ctime_nonl>:
  endbr64
  push   %rbx
  call   <ctime@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ctime_nonl(time_t *date) {
  char *d = ctime(date);
  d[strlen(d) - 1] = '\0';
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ctime_nonl>:
  endbr64
  push   %r12
  call   <ctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ctime_nonl(time_t *date) {
  char *d = ctime(date);
  d[strlen(d) - 1] = '\0';
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ctime_nonl>:
  endbr64
  push   %r12
  call   <ctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ctime_nonl(time_t *date) {
  char *d = ctime(date);
  d[strlen(d) - 1] = '\0';
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<render_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
void *render_byte(int byte, void *dest) {
  *(unsigned char *)dest = (unsigned char)byte;
  return dest + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<render_byte>:
  endbr64
  mov    %dil,(%rsi)
  lea    0x1(%rsi),%rax
  ret
```

assistant: ```c
void *render_byte(int byte, void *dest) {
  *(unsigned char *)dest = (unsigned char)byte;
  return dest + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<render_byte>:
  endbr64
  mov    %dil,(%rsi)
  lea    0x1(%rsi),%rax
  ret
```

assistant: ```c
void *render_byte(int byte, void *dest) {
  *(unsigned char *)dest = (unsigned char)byte;
  return dest + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<render_byte>:
  endbr64
  mov    %dil,(%rsi)
  lea    0x1(%rsi),%rax
  ret
```

assistant: ```c
void *render_byte(int byte, void *dest) {
  *(unsigned char *)dest = (unsigned char)byte;
  return dest + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse_breaks_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse_breaks_list(float *breaks, int nBreaks, float *reverseBreaks) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks[nBreaks - i - 1] = breaks[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse_breaks_list>:
  endbr64
  sub    $0x1,%esi
  js     L9
  movslq %esi,%rsi
L19:
  movss  (%rdi,%rsi,4),%xmm0
  movss  %xmm0,(%rdx)
  sub    $0x1,%rsi
  add    $0x4,%rdx
  test   %esi,%esi
  jns    L19
L9:
  ret
```

assistant: ```c
void reverse_breaks_list(float *breaks, int nBreaks, float *reverseBreaks) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks[nBreaks - i - 1] = breaks[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse_breaks_list>:
  endbr64
  sub    $0x1,%esi
  js     L11
  movslq %esi,%rsi
  nopl   0x0(%rax)
L19:
  movss  (%rdi,%rsi,4),%xmm0
  sub    $0x1,%rsi
  add    $0x4,%rdx
  movss  %xmm0,-0x4(%rdx)
  test   %esi,%esi
  jns    L19
L11:
  ret
```

assistant: ```c
void reverse_breaks_list(float *breaks, int nBreaks, float *reverseBreaks) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks[nBreaks - i - 1] = breaks[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse_breaks_list>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  mov    %esi,%r10d
  mov    %rdx,%r9
  sub    $0x1,%edi
  js     L11
  movslq %esi,%rcx
  mov    %esi,%esi
  shl    $0x2,%rcx
  shl    $0x2,%rsi
  mov    %rcx,%rax
  lea    (%rdx,%rsi,1),%rdx
  sub    %rsi,%rax
  add    %r8,%rax
  cmp    %rax,%rdx
  lea    (%r8,%rcx,1),%rdx
  setbe  %al
  cmp    %rdx,%r9
  setae  %dl
  or     %dl,%al
  je     L35
  cmp    $0x2,%edi
  jbe    L35
  mov    %r10d,%esi
  lea    -0x10(%r8,%rcx,1),%rcx
  mov    %r9,%rdx
  shr    $0x2,%esi
  lea    -0x10(%rcx),%rax
  lea    -0x1(%rsi),%r11d
  mov    %rax,%rsi
  shl    $0x4,%r11
  sub    %r11,%rsi
  jmp    L32
  nopl   (%rax)
L47:
  sub    $0x10,%rax
L32:
  movups (%rcx),%xmm0
  add    $0x10,%rdx
  mov    %rax,%rcx
  shufps $0x1b,%xmm0,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rsi,%rax
  jne    L47
  mov    %r10d,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edi
  cmp    %eax,%r10d
  je     L11
  movslq %edi,%rax
  lea    -0x1(%rdi),%ecx
  movss  (%r8,%rax,4),%xmm0
  mov    %r10d,%eax
  sub    %edi,%eax
  cltq
  movss  %xmm0,-0x4(%r9,%rax,4)
  test   %edi,%edi
  je     L11
  movslq %ecx,%rax
  movss  (%r8,%rax,4),%xmm0
  lea    0x0(,%rax,4),%rsi
  mov    %r10d,%eax
  sub    %ecx,%eax
  cltq
  movss  %xmm0,-0x4(%r9,%rax,4)
  lea    -0x2(%rdi),%eax
  cmp    $0x1,%edi
  je     L11
  mov    %r10d,%edx
  movss  -0x4(%r8,%rsi,1),%xmm0
  sub    %eax,%edx
  movslq %edx,%rdx
  movss  %xmm0,-0x4(%r9,%rdx,4)
  ret
L35:
  movslq %edi,%rdx
  mov    %r9,%rax
  cs nopw 0x0(%rax,%rax,1)
L58:
  movss  (%r8,%rdx,4),%xmm0
  sub    $0x1,%rdx
  add    $0x4,%rax
  movss  %xmm0,-0x4(%rax)
  test   %edx,%edx
  jns    L58
L11:
  ret
```

assistant: ```c
void reverse_breaks_list(float *breaks, int nBreaks, float *reverseBreaks) {
  int i;
  for (i = (nBreaks - 1); i >= 0; --i) {
    reverseBreaks[nBreaks - i - 1] = breaks[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x34(%rbp),%esi
  mov    -0x30(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L33
L43:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  cltq
  mov    -0x38(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
L33:
  mov    -0x38(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L43
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L21
L39:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x38(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
L21:
  mov    -0x38(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L39
  movl   $0x1,-0x38(%rbp)
  nop
L24:
  shll   -0x38(%rbp)
  mov    -0x38(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L24
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string
name: disassemble_data
arguments: data_tag: D34
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string

tool: D8: A. Wartosci: %d %d %d %d


tool: D34: %d 

tool: D23: 
%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = b = c = d = 0;
  printf("A. Wartosci: %d %d %d %d\n", a, b, c, d);
  int i, N = 5, tab[5] = {0, 1, 2, 3, 4};
  for (i = 0; i < N; tab[i++] = i)
    printf("%d ", tab[i]);
  printf("\n");
  for (i = 0; i < N; tab[++i] = i)
    printf("%d ", tab[i]);
  i = 1;
  while ((i *= 2) < N)
    ;
  printf("\n%d\n", i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D6(%rip),%r13
L0:
  mov    (%r12),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    %ebp,(%r12)
  add    $0x4,%r12
  cmp    $0x5,%ebp
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebp
  lea    D6(%rip),%r12
L2:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    %ebp,0x4(%rbx)
  add    $0x4,%rbx
  cmp    $0x5,%ebp
  jne    L2
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D20: A. Wartosci: %d %d %d %d


tool: D6: %d 

tool: D8: 
%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = b = c = d = 0;
  printf("A. Wartosci: %d %d %d %d\n", a, b, c, d);
  int i, N = 5, tab[5] = {0, 1, 2, 3, 4};
  for (i = 0; i < N; tab[i++] = i)
    printf("%d ", tab[i]);
  printf("\n");
  for (i = 0; i < N; tab[++i] = i)
    printf("%d ", tab[i]);
  i = 1;
  while ((i *= 2) < N)
    ;
  printf("\n%d\n", i);
  return 0;
}
```