ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Tween_BounceOutEasing>:
  endbr64
  movsd  D19(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L3
  movsd  D61(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L1
  movsd  D80(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L20
  subsd  D96(%rip),%xmm0
  movsd  D117(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D43(%rip),%xmm0
  ret
  nop
L1:
  subsd  D5(%rip),%xmm0
  movsd  D117(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D84(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L3:
  movsd  D117(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L20:
  subsd  D13(%rip),%xmm0
  movsd  D117(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D20(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
data_type: byte[8]
name: retrieve_data
arguments: tag: D61
data_type: byte[8]
name: retrieve_data
arguments: tag: D80
data_type: byte[8]
name: retrieve_data
arguments: tag: D96
data_type: byte[8]
name: retrieve_data
arguments: tag: D117
data_type: f64
name: retrieve_data
arguments: tag: D43
data_type: f64
name: retrieve_data
arguments: tag: D5
data_type: byte[8]
name: retrieve_data
arguments: tag: D84
data_type: f64
name: retrieve_data
arguments: tag: D13
data_type: byte[8]
name: retrieve_data
arguments: tag: D20
data_type: f64

tool: {"D19": [0x46,0x17,0x5d,0x74,0xd1,0x45,0xd7,0x3f]}

tool: {"D61": [0x46,0x17,0x5d,0x74,0xd1,0x45,0xe7,0x3f]}

tool: {"D80": [0x17,0x5d,0x74,0xd1,0x45,0x17,0xed,0x3f]}

tool: {"D96": [0x8c,0x2e,0xba,0xe8,0xa2,0x8b,0xee,0x3f]}

tool: D117: 7.5625

tool: D43: 0.984375

tool: {"D5": [0x74,0xd1,0x45,0x17,0x5d,0x74,0xe1,0x3f]}

tool: D84: 0.75

tool: {"D13": [0x2f,0xba,0xe8,0xa2,0x8b,0x2e,0xea,0x3f]}

tool: D20: 0.9375

assistant: ```c
double Tween_BounceOutEasing(double k) {
  if (k < (1 / 2.75)) {
    return 7.5625 * k * k;
  } else if (k < (2 / 2.75)) {
    k -= (1.5 / 2.75);
    return 7.5625 * k * k + 0.75;
  } else if (k < (2.5 / 2.75)) {
    k -= (2.25 / 2.75);
    return 7.5625 * k * k + 0.9375;
  }
  k -= (2.625 / 2.75);
  return 7.5625 * k * k + 0.984375;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mp_array_push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L6
L0:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x20(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,(%rbx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L6:
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L0
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: ,

assistant: ```c
void mp_array_push(char ***array, char *obj, int *num) {
  while (obj != NULL) {
    *array = realloc(*array, sizeof(char *) * ((*num) + 1));
    (*array)[*num] = strsep(&obj, ",");
    (*num)++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mp_array_push>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rsi,%rsi
  je     L5
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  lea    D2(%rip),%r13
L9:
  mov    (%rbx),%eax
  lea    0x8(,%rax,8),%esi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  movslq (%rbx),%rdx
  lea    (%rax,%rdx,8),%r12
  lea    0x8(%rsp),%rdi
  mov    %r13,%rsi
  call   <strsep@plt>
  mov    %rax,(%r12)
  addl   $0x1,(%rbx)
  cmpq   $0x0,0x8(%rsp)
  jne    L9
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: ,

assistant: ```c
void mp_array_push(char ***array, char *obj, int *num) {
  while (obj != NULL) {
    *array = realloc(*array, sizeof(char *) * ((*num) + 1));
    (*array)[*num] = strsep(&obj, ",");
    (*num)++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mp_array_push>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rsi,%rsi
  je     L13
  mov    (%rdx),%eax
  mov    %rdi,%rbx
  mov    %rdx,%r13
  lea    0x8(%rsp),%r12
  lea    D4(%rip),%rbp
  xchg   %ax,%ax
L16:
  mov    (%rbx),%rdi
  lea    0x8(,%rax,8),%esi
  call   <realloc@plt>
  movslq 0x0(%r13),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,(%rbx)
  lea    (%rax,%rdx,8),%r14
  call   <strsep@plt>
  mov    %rax,(%r14)
  mov    0x0(%r13),%eax
  add    $0x1,%eax
  cmpq   $0x0,0x8(%rsp)
  mov    %eax,0x0(%r13)
  jne    L16
L13:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: ,

assistant: ```c
void mp_array_push(char ***array, char *obj, int *num) {
  while (obj != NULL) {
    *array = realloc(*array, sizeof(char *) * ((*num) + 1));
    (*array)[*num] = strsep(&obj, ",");
    (*num)++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mp_array_push>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rsi,%rsi
  je     L10
  mov    (%rdx),%eax
  mov    %rdi,%rbx
  mov    %rdx,%r13
  lea    0x8(%rsp),%r12
  lea    D5(%rip),%rbp
  xchg   %ax,%ax
L18:
  mov    (%rbx),%rdi
  lea    0x8(,%rax,8),%esi
  call   <realloc@plt>
  movslq 0x0(%r13),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,(%rbx)
  lea    (%rax,%rdx,8),%r14
  call   <strsep@plt>
  mov    %rax,(%r14)
  mov    0x0(%r13),%eax
  add    $0x1,%eax
  cmpq   $0x0,0x8(%rsp)
  mov    %eax,0x0(%r13)
  jne    L18
L10:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: ,

assistant: ```c
void mp_array_push(char ***array, char *obj, int *num) {
  while (obj != NULL) {
    *array = realloc(*array, sizeof(char *) * ((*num) + 1));
    (*array)[*num] = strsep(&obj, ",");
    (*num)++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<leak_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void leak_memory(void) {
  int *const temporary = (int *)malloc(sizeof(int));
  *temporary = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<leak_memory>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void leak_memory(void) {
  int *const temporary = (int *)malloc(sizeof(int));
  *temporary = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<leak_memory>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void leak_memory(void) {
  int *const temporary = (int *)malloc(sizeof(int));
  *temporary = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<leak_memory>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void leak_memory(void) {
  int *const temporary = (int *)malloc(sizeof(int));
  *temporary = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <ptr@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  lea    -0x11(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  je     L4
  call   <abort@plt>
L4:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  char c;
  void *x = __builtin_call_with_static_chain(ptr(), &c);
  if (x != &c)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ptr@plt>
  call   <abort@plt>
```

assistant: ```c
int main() {
  char c;
  void *x = __builtin_call_with_static_chain(ptr(), &c);
  if (x != &c)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ptr@plt>
  call   <abort@plt>
```

assistant: ```c
int main() {
  char c;
  void *x = __builtin_call_with_static_chain(ptr(), &c);
  if (x != &c)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L26:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L40
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  lea    0x5a(%rax),%edx
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,%edx
  je     L49
  jmp    L15
L40:
  nop
L15:
  addl   $0x1,-0x4(%rbp)
L29:
  cmpl   $0xb,-0x4(%rbp)
  jle    L26
  jmp    L7
L49:
  nop
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D2
type: string

tool: D16: checking i = %d


tool: D2: The answer is %d.


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < 12; i++) {
    if (i % 3 == 0) {
      continue;
    }
    printf("checking i = %d\n", i);
    if (i + 90 == i * i) {
      break;
    }
  }
  printf("The answer is %d.\n", i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  lea    D2(%rip),%r12
  jmp    L6
L34:
  mov    %ebx,%ebp
L6:
  lea    0x1(%rbp),%ebx
  cmp    $0xb,%ebp
  je     L16
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L34
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  imul   %ebx,%eax
  add    $0x5b,%ebp
  cmp    %ebp,%eax
  jne    L34
L16:
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string

tool: D2: checking i = %d


tool: D16: The answer is %d.


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < 12; i++) {
    if (i % 3 == 0) {
      continue;
    }
    printf("checking i = %d\n", i);
    if (i + 90 == i * i) {
      break;
    }
  }
  printf("The answer is %d.\n", i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  lea    0x1(%rbx),%ebp
  cmp    $0xb,%ebx
  je     L0
  nopl   0x0(%rax)
L16:
  imul   $0xaaaaaaab,%ebp,%eax
  cmp    $0x55555555,%eax
  jbe    L15
  mov    %ebp,%esi
  mov    %r12,%rdi
  add    $0x5b,%ebx
  call   <printf@plt>
  mov    %ebp,%eax
  imul   %ebp,%eax
  cmp    %ebx,%eax
  je     L0
L15:
  mov    %ebp,%ebx
  lea    0x1(%rbx),%ebp
  cmp    $0xb,%ebx
  jne    L16
L0:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D5
type: string

tool: D10: checking i = %d


tool: D5: The answer is %d.


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < 12; i++) {
    if (i % 3 == 0) {
      continue;
    }
    printf("checking i = %d\n", i);
    if (i + 90 == i * i) {
      break;
    }
  }
  printf("The answer is %d.\n", i);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  lea    0x1(%rbx),%ebp
  cmp    $0xb,%ebx
  je     L15
  nopl   0x0(%rax)
L25:
  imul   $0xaaaaaaab,%ebp,%eax
  cmp    $0x55555555,%eax
  jbe    L32
  mov    %ebp,%esi
  mov    %r12,%rdi
  add    $0x5b,%ebx
  call   <printf@plt>
  mov    %ebp,%eax
  imul   %ebp,%eax
  cmp    %ebx,%eax
  je     L15
L32:
  mov    %ebp,%ebx
  lea    0x1(%rbx),%ebp
  cmp    $0xb,%ebx
  jne    L25
L15:
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D3
datatype: string

tool: D11: checking i = %d


tool: D3: The answer is %d.


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < 12; i++) {
    if (i % 3 == 0) {
      continue;
    }
    printf("checking i = %d\n", i);
    if (i + 90 == i * i) {
      break;
    }
  }
  printf("The answer is %d.\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<buddy_check_alloc_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L10:
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L0:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buddy_check_alloc@plt>
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L0
  shll   -0x1c(%rbp)
  shll   -0x4(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <buddy_map_size@plt>
  cmp    %eax,-0x1c(%rbp)
  jb     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void buddy_check_alloc_down(struct buddy *b, unsigned int node) {
  unsigned int i, count = 1;
  while (node < buddy_map_size(b)) {
    for (i = 0; i < count; i++)
      buddy_check_alloc(b, node + i);
    node <<= 1;
    count <<= 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buddy_check_alloc_down>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    $0x1,%r14d
  jmp    L7
L28:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <buddy_check_alloc@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L28
L16:
  add    %r13d,%r13d
  add    %r14d,%r14d
L7:
  mov    %rbp,%rdi
  call   <buddy_map_size@plt>
  cmp    %r13d,%eax
  jbe    L13
  lea    0x0(%r13,%r14,1),%r12d
  mov    %r13d,%ebx
  test   %r14d,%r14d
  jne    L28
  jmp    L16
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void buddy_check_alloc_down(struct buddy *b, unsigned int node) {
  unsigned int i, count = 1;
  while (node < buddy_map_size(b)) {
    for (i = 0; i < count; i++)
      buddy_check_alloc(b, node + i);
    node <<= 1;
    count <<= 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<buddy_check_alloc_down>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  call   <buddy_map_size@plt>
  cmp    %r13d,%eax
  jbe    L36
  nopl   (%rax)
L19:
  lea    0x0(%r13,%r14,1),%r12d
  mov    %r13d,%ebx
  test   %r14d,%r14d
  je     L24
  nopl   (%rax)
L30:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <buddy_check_alloc@plt>
  cmp    %ebx,%r12d
  jne    L30
L24:
  mov    %rbp,%rdi
  add    %r13d,%r13d
  add    %r14d,%r14d
  call   <buddy_map_size@plt>
  cmp    %r13d,%eax
  ja     L19
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void buddy_check_alloc_down(struct buddy *b, unsigned int node) {
  unsigned int i, count = 1;
  while (node < buddy_map_size(b)) {
    for (i = 0; i < count; i++)
      buddy_check_alloc(b, node + i);
    node <<= 1;
    count <<= 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<buddy_check_alloc_down>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  call   <buddy_map_size@plt>
  cmp    %r13d,%eax
  jbe    L0
  nopl   (%rax)
L9:
  lea    0x0(%r13,%r14,1),%r12d
  mov    %r13d,%ebx
  test   %r14d,%r14d
  je     L15
  nopl   (%rax)
L33:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <buddy_check_alloc@plt>
  cmp    %ebx,%r12d
  jne    L33
L15:
  mov    %rbp,%rdi
  add    %r13d,%r13d
  add    %r14d,%r14d
  call   <buddy_map_size@plt>
  cmp    %r13d,%eax
  ja     L9
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void buddy_check_alloc_down(struct buddy *b, unsigned int node) {
  unsigned int i, count = 1;
  while (node < buddy_map_size(b)) {
    for (i = 0; i < count; i++)
      buddy_check_alloc(b, node + i);
    node <<= 1;
    count <<= 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<totalNQueens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jg     L16
  mov    $0x0,%eax
  jmp    L7
L16:
  movl   $0x0,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <function@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int totalNQueens(int n) {
  if (n <= 0)
    return 0;
  int result = 0;
  int *temp = (int *)malloc(sizeof(int) * n);
  function(n, temp, 0, &result);
  free(temp);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<totalNQueens>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L5
  mov    %edi,%ebx
  movl   $0x0,0x4(%rsp)
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x4(%rsp),%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    %ebx,%edi
  call   <function@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x4(%rsp),%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int totalNQueens(int n) {
  if (n <= 0)
    return 0;
  int result = 0;
  int *temp = (int *)malloc(sizeof(int) * n);
  function(n, temp, 0, &result);
  free(temp);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<totalNQueens>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L13
  mov    %edi,%ebp
  lea    0x0(,%rdi,4),%edi
  movl   $0x0,0x4(%rsp)
  call   <malloc@plt>
  lea    0x4(%rsp),%rcx
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <function@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x4(%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int totalNQueens(int n) {
  if (n <= 0)
    return 0;
  int result = 0;
  int *temp = (int *)malloc(sizeof(int) * n);
  function(n, temp, 0, &result);
  free(temp);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<totalNQueens>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L10
  mov    %edi,%ebp
  lea    0x0(,%rdi,4),%edi
  movl   $0x0,0x4(%rsp)
  call   <malloc@plt>
  lea    0x4(%rsp),%rcx
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <function@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x4(%rsp),%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int totalNQueens(int n) {
  if (n <= 0)
    return 0;
  int result = 0;
  int *temp = (int *)malloc(sizeof(int) * n);
  function(n, temp, 0, &result);
  free(temp);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L62:
  movl   $0x0,-0x34(%rbp)
  jmp    L6
L22:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L6:
  cmpl   $0x9,-0x34(%rbp)
  jle    L22
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <isOrdered@plt>
  test   %rax,%rax
  je     L5
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L5:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x38(%rbp)
L18:
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jne    L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D40
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D3: %d

tool: D10: Lumberjacks:


tool: D40: Ordered


tool: D26: Unordered


assistant: ```c
int main(void) {
  int arr[10], T, i;
  scanf("%d", &T);
  printf("Lumberjacks:\n");
  while (T) {
    for (i = 0; i < 10; i++)
      scanf("%d", &arr[i]);
    if (isOrdered(arr, 10))
      printf("Ordered\n");
    else
      printf("Unordered\n");
    T--;
  }
  return 0;
}
```