ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  lea    D19(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movl   $0x3f800000,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x14(%rsp),%esi
  pxor   %xmm3,%xmm3
  mov    $0x1,%eax
  movss  D14(%rip),%xmm2
  cvtsi2ss %esi,%xmm3
  movaps %xmm3,%xmm1
  nopl   0x0(%rax)
L23:
  mulss  %xmm3,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  add    $0x1,%eax
  mulss  %xmm0,%xmm2
  cmp    %eax,%ebx
  jne    L23
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebx
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  divss  %xmm2,%xmm1
  addss  0x4(%rsp),%xmm1
  movss  %xmm1,0x4(%rsp)
  cmp    $0x20,%ebx
  jne    L17
  pxor   %xmm0,%xmm0
  lea    D39(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D1
type: string
name: retrieve_data
arguments: tag: D14
type: f32
name: retrieve_data
arguments: tag: D39
type: string

tool: D20: 
Valor do expoente: 

tool: D19: %f/%10.10f


tool: D1: %i

tool: D14: 1

tool: D39: e = %f

assistant: ```c
int main() {
  float e = 1;
  int expoente;
  printf("\nValor do expoente: ");
  scanf("%i", &expoente);
  for (int i = 1; i < 31; i++) {
    float fatorial = 1;
    float xelevado = expoente;
    for (int j = 1; j <= i; j++) {
      fatorial *= j;
      xelevado *= expoente;
    }
    printf("%f/%10.10f\n", xelevado, expoente);
    e += (xelevado / fatorial);
  }
  printf("e = %f", e);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D40(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  movl   $0x3f800000,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x14(%rsp),%esi
  pxor   %xmm3,%xmm3
  mov    $0x1,%eax
  movss  D34(%rip),%xmm2
  cvtsi2ss %esi,%xmm3
  movaps %xmm3,%xmm1
  nopl   0x0(%rax)
L5:
  mulss  %xmm3,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  add    $0x1,%eax
  mulss  %xmm0,%xmm2
  cmp    %eax,%ebx
  jne    L5
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebx
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  divss  %xmm2,%xmm1
  addss  0x4(%rsp),%xmm1
  movss  %xmm1,0x4(%rsp)
  cmp    $0x20,%ebx
  jne    L2
  pxor   %xmm0,%xmm0
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
data_type: string
name: extract_symbolic_data
arguments: data_tag: D40
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D34
data_type: f32
name: extract_symbolic_data
arguments: data_tag: D43
data_type: string

tool: D28: 
Valor do expoente: 

tool: D40: %f/%10.10f


tool: D17: %i

tool: D34: 1

tool: D43: e = %f

assistant: ```c
int main() {
  float e = 1;
  int expoente;
  printf("\nValor do expoente: ");
  scanf("%i", &expoente);
  for (int i = 1; i < 31; i++) {
    float fatorial = 1;
    float xelevado = expoente;
    for (int j = 1; j <= i; j++) {
      fatorial *= j;
      xelevado *= expoente;
    }
    printf("%f/%10.10f\n", xelevado, expoente);
    e += (xelevado / fatorial);
  }
  printf("e = %f", e);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movabs $0x6564636261,%rax
  mov    $0x0,%edx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  movabs $0x64644a49484746,%rax
  mov    %rax,-0x3a(%rbp)
  movw   $0x0,-0x32(%rbp)
  lea    -0x3a(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lenStr@plt>
  mov    %eax,%ebx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lenStr@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3a(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3a(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <catStr@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lenStr@plt>
  mov    %eax,%ecx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D12
data_type: string

tool: D13: length of str1 is %d
length of str2 is %d


tool: D0: str1 is %s,str2 is %s

tool: D12: 
combined length is %d
After combination:%s

assistant: ```c
int main() {
  char str1[20] = "abcde", str2[10] = "FGHIJdd";
  printf("length of str1 is %d\nlength of str2 is %d\n", lenStr(str1), lenStr(str2));
  printf("str1 is %s,str2 is %s", str1, str2);
  catStr(str1, str2);
  printf("\ncombined length is %d\nAfter combination:%s", lenStr(str1), str1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6564636261,%rax
  mov    $0x0,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0x0,0x20(%rsp)
  movabs $0x64644a49484746,%rax
  mov    %rax,0x6(%rsp)
  movw   $0x0,0xe(%rsp)
  lea    0x6(%rsp),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <lenStr@plt>
  mov    %eax,%r12d
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <lenStr@plt>
  mov    %eax,%esi
  mov    %r12d,%edx
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <catStr@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <lenStr@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string

tool: D6: length of str1 is %d
length of str2 is %d


tool: D10: str1 is %s,str2 is %s

tool: D28: 
combined length is %d
After combination:%s

assistant: ```c
int main() {
  char str1[20] = "abcde", str2[10] = "FGHIJdd";
  printf("length of str1 is %d\nlength of str2 is %d\n", lenStr(str1), lenStr(str2));
  printf("str1 is %s,str2 is %s", str1, str2);
  catStr(str1, str2);
  printf("\ncombined length is %d\nAfter combination:%s", lenStr(str1), str1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x6564636261,%rax
  lea    0x6(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rdx,0x18(%rsp)
  mov    %rbp,%rdi
  movl   $0x0,0x20(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x64644a49484746,%rax
  mov    %rax,0x6(%rsp)
  xor    %eax,%eax
  mov    %ax,0xe(%rsp)
  xor    %eax,%eax
  call   <lenStr@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <lenStr@plt>
  mov    %r13d,%edx
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <catStr@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <lenStr@plt>
  mov    %r12,%rdx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D10: length of str1 is %d
length of str2 is %d


tool: D2: str1 is %s,str2 is %s

tool: D19: 
combined length is %d
After combination:%s

assistant: ```c
int main() {
  char str1[20] = "abcde", str2[10] = "FGHIJdd";
  printf("length of str1 is %d\nlength of str2 is %d\n", lenStr(str1), lenStr(str2));
  printf("str1 is %s,str2 is %s", str1, str2);
  catStr(str1, str2);
  printf("\ncombined length is %d\nAfter combination:%s", lenStr(str1), str1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x6564636261,%rax
  lea    0x6(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rdx,0x18(%rsp)
  mov    %rbp,%rdi
  movl   $0x0,0x20(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x64644a49484746,%rax
  mov    %rax,0x6(%rsp)
  xor    %eax,%eax
  mov    %ax,0xe(%rsp)
  xor    %eax,%eax
  call   <lenStr@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <lenStr@plt>
  mov    %r13d,%edx
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <catStr@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <lenStr@plt>
  mov    %r12,%rdx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string

tool: D12: length of str1 is %d
length of str2 is %d


tool: D22: str1 is %s,str2 is %s

tool: D19: 
combined length is %d
After combination:%s

assistant: ```c
int main() {
  char str1[20] = "abcde", str2[10] = "FGHIJdd";
  printf("length of str1 is %d\nlength of str2 is %d\n", lenStr(str1), lenStr(str2));
  printf("str1 is %s,str2 is %s", str1, str2);
  catStr(str1, str2);
  printf("\ncombined length is %d\nAfter combination:%s", lenStr(str1), str1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memmove2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L16
  mov    -0x18(%rbp),%rax
  jmp    L40
L16:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L21
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L40
L20:
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L21:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L20
  mov    -0x18(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
void *memmove2(void *__dest, __const void *__src, size_t count) {
  unsigned char *d = __dest;
  const unsigned char *s = __src;
  if (__dest == __src)
    return __dest;
  if (__dest < __src)
    return memcpy(__dest, __src, count);
  while (count--)
    d[count] = s[count];
  return __dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memmove2>:
  endbr64
  cmp    %rsi,%rdi
  je     L21
  mov    %rdi,%rax
  jb     L26
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L0
L15:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L15
  ret
L0:
  ret
L26:
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
L21:
  mov    %rsi,%rax
  ret
```

assistant: ```c
void *memmove2(void *__dest, __const void *__src, size_t count) {
  unsigned char *d = __dest;
  const unsigned char *s = __src;
  if (__dest == __src)
    return __dest;
  if (__dest < __src)
    return memcpy(__dest, __src, count);
  while (count--)
    d[count] = s[count];
  return __dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memmove2>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  je     L16
  jb     L32
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L19
  nopw   0x0(%rax,%rax,1)
L33:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L33
L16:
  ret
  xchg   %ax,%ax
L32:
  jmp    1050 <memcpy@plt>
  nopl   (%rax)
L19:
  ret
```

assistant: ```c
void *memmove2(void *__dest, __const void *__src, size_t count) {
  unsigned char *d = __dest;
  const unsigned char *s = __src;
  if (__dest == __src)
    return __dest;
  if (__dest < __src)
    return memcpy(__dest, __src, count);
  while (count--)
    d[count] = s[count];
  return __dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memmove2>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  je     L1
  jb     L15
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L20
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L27
L1:
  ret
  xchg   %ax,%ax
L15:
  jmp    1050 <memcpy@plt>
  nopl   (%rax)
L20:
  ret
```

assistant: ```c
void *memmove2(void *__dest, __const void *__src, size_t count) {
  unsigned char *d = __dest;
  const unsigned char *s = __src;
  if (__dest == __src)
    return __dest;
  if (__dest < __src)
    return memcpy(__dest, __src, count);
  while (count--)
    d[count] = s[count];
  return __dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<i_bsearch_seq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%r8
  lea    -0x14(%rbp),%rdi
  mov    -0x28(%rbp),%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <isearch_seq@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <bsearch_seq@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
unsigned int i_bsearch_seq(unsigned int key, unsigned int *D, unsigned int D_size, unsigned int *I, unsigned int I_size) {
  int hi, lo;
  unsigned int region = isearch_seq(key, I, I_size, D_size, &hi, &lo);
  return bsearch_seq(key, D, D_size, lo, hi);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i_bsearch_seq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %rcx,%rsi
  mov    %r8d,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r9
  mov    %rsp,%r8
  mov    %ebp,%ecx
  call   <isearch_seq@plt>
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bsearch_seq@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int i_bsearch_seq(unsigned int key, unsigned int *D, unsigned int D_size, unsigned int *I, unsigned int I_size) {
  int hi, lo;
  unsigned int region = isearch_seq(key, I, I_size, D_size, &hi, &lo);
  return bsearch_seq(key, D, D_size, lo, hi);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<i_bsearch_seq>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rcx,%rsi
  push   %r12
  mov    %edx,%r12d
  mov    %r8d,%edx
  push   %rbp
  mov    %r12d,%ecx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  lea    0x4(%rsp),%r9
  call   <isearch_seq@plt>
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <bsearch_seq@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int i_bsearch_seq(unsigned int key, unsigned int *D, unsigned int D_size, unsigned int *I, unsigned int I_size) {
  int hi, lo;
  unsigned int region = isearch_seq(key, I, I_size, D_size, &hi, &lo);
  return bsearch_seq(key, D, D_size, lo, hi);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<i_bsearch_seq>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rcx,%rsi
  push   %r12
  mov    %edx,%r12d
  mov    %r8d,%edx
  push   %rbp
  mov    %r12d,%ecx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  lea    0x4(%rsp),%r9
  call   <isearch_seq@plt>
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <bsearch_seq@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int i_bsearch_seq(unsigned int key, unsigned int *D, unsigned int D_size, unsigned int *I, unsigned int I_size) {
  int hi, lo;
  unsigned int region = isearch_seq(key, I, I_size, D_size, &hi, &lo);
  return bsearch_seq(key, D, D_size, lo, hi);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sigp_busy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
L6:
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sigp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sigp_busy(uint16_t addr, uint8_t order, uint32_t parm, uint32_t *status) {
  int cc;
  do {
    cc = sigp(addr, order, parm, status);
  } while (cc == 2);
  return cc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigp_busy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %rcx,%rbx
L3:
  mov    %rbx,%rcx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <sigp@plt>
  cmp    $0x2,%eax
  je     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sigp_busy(uint16_t addr, uint8_t order, uint32_t parm, uint32_t *status) {
  int cc;
  do {
    cc = sigp(addr, order, parm, status);
  } while (cc == 2);
  return cc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigp_busy>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rcx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <sigp@plt>
  cmp    $0x2,%eax
  je     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sigp_busy(uint16_t addr, uint8_t order, uint32_t parm, uint32_t *status) {
  int cc;
  do {
    cc = sigp(addr, order, parm, status);
  } while (cc == 2);
  return cc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sigp_busy>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rcx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <sigp@plt>
  cmp    $0x2,%eax
  je     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sigp_busy(uint16_t addr, uint8_t order, uint32_t parm, uint32_t *status) {
  int cc;
  do {
    cc = sigp(addr, order, parm, status);
  } while (cc == 2);
  return cc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<arrayPrint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: %i 

assistant: ```c
void arrayPrint(int *arr, int size) {
  for (int i = 0; i < size; i++) {
    printf("%i ", arr[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<arrayPrint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D7(%rip),%rbp
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L10
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %i 

assistant: ```c
void arrayPrint(int *arr, int size) {
  for (int i = 0; i < size; i++) {
    printf("%i ", arr[i]);
  }
  printf("\n");
}
```