ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<swoole_hash_austin>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%edi
  cmp    $0x3,%esi
  jbe    L50
  lea    -0x4(%rsi),%eax
  shr    $0x2,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    (%rdx,%rax,4),%r8
L5:
  movsbl 0x3(%rdx),%ecx
  shl    $0x18,%ecx
  movsbl (%rdx),%eax
  or     %eax,%ecx
  movsbl 0x1(%rdx),%eax
  shl    $0x8,%eax
  movsbl 0x2(%rdx),%r9d
  shl    $0x10,%r9d
  or     %r9d,%eax
  or     %ecx,%eax
  imul   $0x5bd1e995,%eax,%eax
  mov    %eax,%ecx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  imul   $0x5bd1e995,%esi,%esi
  imul   $0x5bd1e995,%eax,%eax
  xor    %eax,%esi
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L5
  and    $0x3,%edi
L2:
  cmp    $0x2,%edi
  je     L0
  cmp    $0x3,%edi
  je     L25
  cmp    $0x1,%edi
  jne    L33
  jmp    L36
L50:
  mov    %rdx,%r8
  jmp    L2
L25:
  movsbl 0x2(%r8),%eax
  shl    $0x10,%eax
  xor    %eax,%esi
L0:
  movsbl 0x1(%r8),%eax
  shl    $0x8,%eax
  xor    %eax,%esi
L36:
  movsbl (%r8),%eax
  xor    %esi,%eax
  imul   $0x5bd1e995,%eax,%esi
L33:
  mov    %esi,%edx
  shr    $0xd,%edx
  xor    %esi,%edx
  imul   $0x5bd1e995,%edx,%edx
  mov    %edx,%eax
  shr    $0xf,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t swoole_hash_austin(char *key, unsigned int keylen) {
  unsigned int h, k;
  h = 0 ^ keylen;
  while (keylen >= 4) {
    k = key[0];
    k |= key[1] << 8;
    k |= key[2] << 16;
    k |= key[3] << 24;
    k *= 0x5bd1e995;
    k ^= k >> 24;
    k *= 0x5bd1e995;
    h *= 0x5bd1e995;
    h ^= k;
    key += 4;
    keylen -= 4;
  }
  switch (keylen) {
  case 3:
    h ^= key[2] << 16;
  case 2:
    h ^= key[1] << 8;
  case 1:
    h ^= key[0];
    h *= 0x5bd1e995;
  }
  h ^= h >> 13;
  h *= 0x5bd1e995;
  h ^= h >> 15;
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swoole_hash_austin>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%edi
  cmp    $0x3,%esi
  jbe    L67
  lea    -0x4(%rsi),%eax
  shr    $0x2,%eax
  add    $0x1,%eax
  lea    (%rdx,%rax,4),%r8
  nop
L41:
  movsbl 0x3(%rdx),%ecx
  movsbl (%rdx),%eax
  imul   $0x5bd1e995,%esi,%esi
  add    $0x4,%rdx
  movsbl -0x2(%rdx),%r9d
  shl    $0x18,%ecx
  or     %eax,%ecx
  movsbl -0x3(%rdx),%eax
  shl    $0x10,%r9d
  shl    $0x8,%eax
  or     %r9d,%eax
  or     %ecx,%eax
  imul   $0x5bd1e995,%eax,%eax
  mov    %eax,%ecx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  imul   $0x5bd1e995,%eax,%eax
  xor    %eax,%esi
  cmp    %r8,%rdx
  jne    L41
  and    $0x3,%edi
L50:
  cmp    $0x2,%edi
  je     L38
  cmp    $0x3,%edi
  je     L59
  cmp    $0x1,%edi
  je     L34
L58:
  mov    %esi,%edx
  shr    $0xd,%edx
  xor    %esi,%edx
  imul   $0x5bd1e995,%edx,%edx
  mov    %edx,%eax
  shr    $0xf,%eax
  xor    %edx,%eax
  ret
  nopl   0x0(%rax)
L59:
  movsbl 0x2(%r8),%eax
  shl    $0x10,%eax
  xor    %eax,%esi
L38:
  movsbl 0x1(%r8),%eax
  shl    $0x8,%eax
  xor    %eax,%esi
L34:
  movsbl (%r8),%eax
  xor    %esi,%eax
  imul   $0x5bd1e995,%eax,%esi
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %rdx,%r8
  jmp    L50
```

assistant: ```c
uint32_t swoole_hash_austin(char *key, unsigned int keylen) {
  unsigned int h, k;
  h = 0 ^ keylen;
  while (keylen >= 4) {
    k = key[0];
    k |= key[1] << 8;
    k |= key[2] << 16;
    k |= key[3] << 24;
    k *= 0x5bd1e995;
    k ^= k >> 24;
    k *= 0x5bd1e995;
    h *= 0x5bd1e995;
    h ^= k;
    key += 4;
    keylen -= 4;
  }
  switch (keylen) {
  case 3:
    h ^= key[2] << 16;
  case 2:
    h ^= key[1] << 8;
  case 1:
    h ^= key[0];
    h *= 0x5bd1e995;
  }
  h ^= h >> 13;
  h *= 0x5bd1e995;
  h ^= h >> 15;
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swoole_hash_austin>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%edi
  cmp    $0x3,%esi
  jbe    L24
  lea    -0x4(%rsi),%eax
  shr    $0x2,%eax
  add    $0x1,%eax
  lea    (%rdx,%rax,4),%r8
  nop
L36:
  movsbl 0x3(%rdx),%ecx
  movsbl (%rdx),%eax
  imul   $0x5bd1e995,%esi,%esi
  add    $0x4,%rdx
  movsbl -0x2(%rdx),%r9d
  shl    $0x18,%ecx
  or     %eax,%ecx
  movsbl -0x3(%rdx),%eax
  shl    $0x10,%r9d
  shl    $0x8,%eax
  or     %r9d,%eax
  or     %ecx,%eax
  imul   $0x5bd1e995,%eax,%eax
  mov    %eax,%ecx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  imul   $0x5bd1e995,%eax,%eax
  xor    %eax,%esi
  cmp    %r8,%rdx
  jne    L36
  and    $0x3,%edi
L32:
  cmp    $0x2,%edi
  je     L6
  cmp    $0x3,%edi
  je     L63
  cmp    $0x1,%edi
  je     L64
L45:
  mov    %esi,%edx
  shr    $0xd,%edx
  xor    %esi,%edx
  imul   $0x5bd1e995,%edx,%edx
  mov    %edx,%eax
  shr    $0xf,%eax
  xor    %edx,%eax
  ret
  nopl   0x0(%rax)
L63:
  movsbl 0x2(%r8),%eax
  shl    $0x10,%eax
  xor    %eax,%esi
L6:
  movsbl 0x1(%r8),%eax
  shl    $0x8,%eax
  xor    %eax,%esi
L64:
  movsbl (%r8),%eax
  xor    %esi,%eax
  imul   $0x5bd1e995,%eax,%esi
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rdx,%r8
  jmp    L32
```

assistant: ```c
uint32_t swoole_hash_austin(char *key, unsigned int keylen) {
  unsigned int h, k;
  h = 0 ^ keylen;
  while (keylen >= 4) {
    k = key[0];
    k |= key[1] << 8;
    k |= key[2] << 16;
    k |= key[3] << 24;
    k *= 0x5bd1e995;
    k ^= k >> 24;
    k *= 0x5bd1e995;
    h *= 0x5bd1e995;
    h ^= k;
    key += 4;
    keylen -= 4;
  }
  switch (keylen) {
  case 3:
    h ^= key[2] << 16;
  case 2:
    h ^= key[1] << 8;
  case 1:
    h ^= key[0];
    h *= 0x5bd1e995;
  }
  h ^= h >> 13;
  h *= 0x5bd1e995;
  h ^= h >> 15;
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ATIReduceRatio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L15:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ATIReduceRatio(int *Numerator, int *Denominator) {
  int Multiplier, Divider, Remainder;
  Multiplier = *Numerator;
  Divider = *Denominator;
  while ((Remainder = Multiplier % Divider)) {
    Multiplier = Divider;
    Divider = Remainder;
  }
  *Numerator /= Divider;
  *Denominator /= Divider;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ATIReduceRatio>:
  endbr64
  mov    (%rdi),%r9d
  mov    (%rsi),%ecx
  mov    %r9d,%eax
L1:
  mov    %ecx,%r8d
  cltd
  idiv   %ecx
  mov    %edx,%ecx
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L1
  mov    %r9d,%eax
  cltd
  idiv   %r8d
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  cltd
  idiv   %r8d
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ATIReduceRatio(int *Numerator, int *Denominator) {
  int Multiplier, Divider, Remainder;
  Multiplier = *Numerator;
  Divider = *Denominator;
  while ((Remainder = Multiplier % Divider)) {
    Multiplier = Divider;
    Divider = Remainder;
  }
  *Numerator /= Divider;
  *Denominator /= Divider;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ATIReduceRatio>:
  endbr64
  mov    (%rdi),%r9d
  mov    (%rsi),%edx
  mov    %r9d,%ecx
  nopl   0x0(%rax)
L2:
  mov    %ecx,%eax
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L2
  mov    %r9d,%eax
  cltd
  idiv   %ecx
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  cltd
  idiv   %ecx
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ATIReduceRatio(int *Numerator, int *Denominator) {
  int Multiplier, Divider, Remainder;
  Multiplier = *Numerator;
  Divider = *Denominator;
  while ((Remainder = Multiplier % Divider)) {
    Multiplier = Divider;
    Divider = Remainder;
  }
  *Numerator /= Divider;
  *Denominator /= Divider;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ATIReduceRatio>:
  endbr64
  mov    (%rdi),%r9d
  mov    (%rsi),%edx
  mov    %r9d,%ecx
  nopl   0x0(%rax)
L8:
  mov    %ecx,%eax
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L8
  mov    %r9d,%eax
  cltd
  idiv   %ecx
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  cltd
  idiv   %ecx
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ATIReduceRatio(int *Numerator, int *Denominator) {
  int Multiplier, Divider, Remainder;
  Multiplier = *Numerator;
  Divider = *Denominator;
  while ((Remainder = Multiplier % Divider)) {
    Multiplier = Divider;
    Divider = Remainder;
  }
  *Numerator /= Divider;
  *Denominator /= Divider;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_signed_msg_encoding@plt>
  mov    $0x0,%eax
  call   <test_signed_msg_encoding@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_signed_msg_encoding();
  test_signed_msg_encoding();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_signed_msg_encoding@plt>
  mov    $0x0,%eax
  call   <test_signed_msg_encoding@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_signed_msg_encoding();
  test_signed_msg_encoding();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_signed_msg_encoding@plt>
  xor    %eax,%eax
  call   <test_signed_msg_encoding@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_signed_msg_encoding();
  test_signed_msg_encoding();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_signed_msg_encoding@plt>
  xor    %eax,%eax
  call   <test_signed_msg_encoding@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_signed_msg_encoding();
  test_signed_msg_encoding();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mark_to_mark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mark_to_mark_noref@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mark_ref_copy@plt>
  nop
  leave
  ret
```

assistant: ```c
void mark_to_mark(struct mark *m, struct mark *target) {
  mark_to_mark_noref(m, target);
  mark_ref_copy(m, target);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mark_to_mark>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <mark_to_mark_noref@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mark_ref_copy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mark_to_mark(struct mark *m, struct mark *target) {
  mark_to_mark_noref(m, target);
  mark_ref_copy(m, target);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mark_to_mark>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <mark_to_mark_noref@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <mark_ref_copy@plt>
```

assistant: ```c
void mark_to_mark(struct mark *m, struct mark *target) {
  mark_to_mark_noref(m, target);
  mark_ref_copy(m, target);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mark_to_mark>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <mark_to_mark_noref@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <mark_ref_copy@plt>
```

assistant: ```c
void mark_to_mark(struct mark *m, struct mark *target) {
  mark_to_mark_noref(m, target);
  mark_ref_copy(m, target);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  add    %rax,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int hash2(char *llave) {
  unsigned long int hash = 0;
  while (*llave)
    hash += (int)*llave++;
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash2>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    $0x0,%edx
L18:
  add    $0x1,%rdi
  movsbq %al,%rax
  add    %rax,%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
L6:
  mov    %rdx,%rax
  ret
L5:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
unsigned long int hash2(char *llave) {
  unsigned long int hash = 0;
  while (*llave)
    hash += (int)*llave++;
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash2>:
  endbr64
  movsbq (%rdi),%rax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  nop
L14:
  add    $0x1,%rdi
  add    %rax,%r8
  movsbq (%rdi),%rax
  test   %al,%al
  jne    L14
L19:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long int hash2(char *llave) {
  unsigned long int hash = 0;
  while (*llave)
    hash += (int)*llave++;
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash2>:
  endbr64
  movsbq (%rdi),%rax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  nop
L15:
  add    $0x1,%rdi
  add    %rax,%r8
  movsbq (%rdi),%rax
  test   %al,%al
  jne    L15
L19:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long int hash2(char *llave) {
  unsigned long int hash = 0;
  while (*llave)
    hash += (int)*llave++;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<IsValid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x58b,-0x14(%rbp)
  jle    L59
  cmpl   $0x5aa,-0x14(%rbp)
  jle    L45
L59:
  movl   $0x0,-0x4(%rbp)
L45:
  cmpl   $0x0,-0x18(%rbp)
  jle    L25
  cmpl   $0xc,-0x18(%rbp)
  jle    L3
L25:
  movl   $0x0,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L9
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <HMonthLength@plt>
  cmp    %eax,-0x1c(%rbp)
  jle    L29
L9:
  movl   $0x0,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int IsValid(int yh, int mh, int dh) {
  int valid = 1;
  if ((yh < 1420) || (yh > 1450))
    valid = 0;
  if ((mh < 1) || (mh > 12))
    valid = 0;
  if ((dh < 1) || (dh > HMonthLength(yh, mh)))
    valid = 0;
  return (valid);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<IsValid>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  lea    -0x1(%rsi),%eax
  mov    $0x0,%ebp
  cmp    $0xb,%eax
  ja     L18
  lea    -0x58c(%rdi),%eax
  cmp    $0x1e,%eax
  setbe  %bpl
  movzbl %bpl,%ebp
L18:
  test   %ebx,%ebx
  jg     L12
  mov    $0x0,%ebp
L9:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <HMonthLength@plt>
  cmp    %ebx,%eax
  mov    $0x0,%eax
  cmovl  %eax,%ebp
  jmp    L9
```

assistant: ```c
int IsValid(int yh, int mh, int dh) {
  int valid = 1;
  if ((yh < 1420) || (yh > 1450))
    valid = 0;
  if ((mh < 1) || (mh > 12))
    valid = 0;
  if ((dh < 1) || (dh > HMonthLength(yh, mh)))
    valid = 0;
  return (valid);
}
```
user: What is the c source code of the assembly code below?

```asm
<IsValid>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%eax
  xor    %r12d,%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    $0xb,%eax
  ja     L21
  lea    -0x58c(%rdi),%eax
  xor    %r12d,%r12d
  cmp    $0x1e,%eax
  setbe  %r12b
L21:
  test   %ebx,%ebx
  jg     L15
L25:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  call   <HMonthLength@plt>
  cmp    %ebx,%eax
  jl     L25
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int IsValid(int yh, int mh, int dh) {
  int valid = 1;
  if ((yh < 1420) || (yh > 1450))
    valid = 0;
  if ((mh < 1) || (mh > 12))
    valid = 0;
  if ((dh < 1) || (dh > HMonthLength(yh, mh)))
    valid = 0;
  return (valid);
}
```
user: What is the c source code of the assembly code below:

```asm
<IsValid>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%eax
  xor    %r12d,%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    $0xb,%eax
  ja     L2
  lea    -0x58c(%rdi),%eax
  xor    %r12d,%r12d
  cmp    $0x1e,%eax
  setbe  %r12b
L2:
  test   %ebx,%ebx
  jg     L28
L22:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  call   <HMonthLength@plt>
  cmp    %ebx,%eax
  jl     L22
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int IsValid(int yh, int mh, int dh) {
  int valid = 1;
  if ((yh < 1420) || (yh > 1450))
    valid = 0;
  if ((mh < 1) || (mh > 12))
    valid = 0;
  if ((dh < 1) || (dh > HMonthLength(yh, mh)))
    valid = 0;
  return (valid);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void *__attribute__((always_)) realloc(void *ptr, unsigned long size) {
  void *rc;
  __asm__ __volatile__("call  realloc\n\t" : "=a"((unsigned long)rc) : "a"((unsigned long)ptr), "d"((unsigned long)size) : "ebx", "ecx", "memory");
  return rc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<realloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdx
  call   <realloc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *__attribute__((always_)) realloc(void *ptr, unsigned long size) {
  void *rc;
  __asm__ __volatile__("call  realloc\n\t" : "=a"((unsigned long)rc) : "a"((unsigned long)ptr), "d"((unsigned long)size) : "ebx", "ecx", "memory");
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<realloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdx
  call   <realloc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *__attribute__((always_)) realloc(void *ptr, unsigned long size) {
  void *rc;
  __asm__ __volatile__("call  realloc\n\t" : "=a"((unsigned long)rc) : "a"((unsigned long)ptr), "d"((unsigned long)size) : "ebx", "ecx", "memory");
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<vrz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    $0x2,%eax
  je     L76
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sgn@plt>
  test   %eax,%eax
  je     L48
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sgn@plt>
  cmp    $0x1,%eax
  je     L50
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sgn@plt>
  cmp    $0xffffffff,%eax
  jne    L60
  mov    $0x2d,%eax
  jmp    L22
L60:
  mov    $0x3f,%eax
  jmp    L22
L50:
  mov    $0x2b,%eax
  jmp    L22
L48:
  mov    $0x30,%eax
  jmp    L22
L76:
  mov    $0x3f,%eax
L22:
  leave
  ret
```

assistant: ```c
char vrz(int x) {
  return ((abs(x) == 2)    ? '?'
          : (sgn(x) == 0)  ? '0'
          : (sgn(x) == 1)  ? '+'
          : (sgn(x) == -1) ? '-'
                           : '?');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vrz>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  mov    $0x3f,%edx
  cmp    $0x2,%eax
  jne    L10
  mov    %edx,%eax
  ret
L10:
  push   %rbx
  mov    %edi,%ebx
  call   <sgn@plt>
  mov    $0x30,%edx
  test   %eax,%eax
  jne    L34
L16:
  mov    %edx,%eax
  pop    %rbx
  ret
L34:
  mov    %ebx,%edi
  call   <sgn@plt>
  mov    $0x2b,%edx
  cmp    $0x1,%eax
  je     L16
  mov    %ebx,%edi
  call   <sgn@plt>
  cmp    $0xffffffff,%eax
  mov    $0x2d,%edx
  mov    $0x3f,%eax
  cmovne %eax,%edx
  jmp    L16
```

assistant: ```c
char vrz(int x) {
  return ((abs(x) == 2)    ? '?'
          : (sgn(x) == 0)  ? '0'
          : (sgn(x) == 1)  ? '+'
          : (sgn(x) == -1) ? '-'
                           : '?');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vrz>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  cmp    $0x2,%eax
  jne    L32
  mov    $0x3f,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  push   %rbp
  mov    %edi,%ebp
  call   <sgn@plt>
  mov    %eax,%r8d
  mov    $0x30,%eax
  test   %r8d,%r8d
  jne    L31
L0:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %ebp,%edi
  call   <sgn@plt>
  mov    %eax,%r8d
  mov    $0x2b,%eax
  cmp    $0x1,%r8d
  je     L0
  mov    %ebp,%edi
  call   <sgn@plt>
  mov    %eax,%r8d
  mov    $0x2d,%eax
  cmp    $0xffffffff,%r8d
  je     L0
  mov    $0x3f,%eax
  pop    %rbp
  ret
```

assistant: ```c
char vrz(int x) {
  return ((abs(x) == 2)    ? '?'
          : (sgn(x) == 0)  ? '0'
          : (sgn(x) == 1)  ? '+'
          : (sgn(x) == -1) ? '-'
                           : '?');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vrz>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  cmp    $0x2,%eax
  jne    L17
  mov    $0x3f,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  push   %rbp
  mov    %edi,%ebp
  call   <sgn@plt>
  mov    %eax,%r8d
  mov    $0x30,%eax
  test   %r8d,%r8d
  jne    L10
L25:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebp,%edi
  call   <sgn@plt>
  mov    %eax,%r8d
  mov    $0x2b,%eax
  cmp    $0x1,%r8d
  je     L25
  mov    %ebp,%edi
  call   <sgn@plt>
  mov    %eax,%r8d
  mov    $0x2d,%eax
  cmp    $0xffffffff,%r8d
  je     L25
  mov    $0x3f,%eax
  pop    %rbp
  ret
```

assistant: ```c
char vrz(int x) {
  return ((abs(x) == 2)    ? '?'
          : (sgn(x) == 0)  ? '0'
          : (sgn(x) == 1)  ? '+'
          : (sgn(x) == -1) ? '-'
                           : '?');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L4
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <quickSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <quickSort>
L4:
  nop
  leave
  ret
```

assistant: ```c
void quickSort(void **ar, int (*cmp)(const void *, const void *), int left, int right) {
  if (left < right) {
    int p = partition(ar, cmp, left, right);
    quickSort(ar, cmp, left, p - 1);
    quickSort(ar, cmp, p + 1, right);
  }
}
```