ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<array_get>:
  endbr64
  movslq %edx,%rax
  test   %edx,%edx
  js     L2
  cmp    %rsi,%rax
  ja     L2
  mov    (%rdi,%rax,8),%rax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *array_get(void **base, size_t length, int position) {
  if (position > length)
    return (void *)0;
  if (position < 0)
    return (void *)0;
  return base[position];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<array_get>:
  endbr64
  movslq %edx,%rax
  test   %edx,%edx
  js     L3
  cmp    %rsi,%rax
  ja     L3
  mov    (%rdi,%rax,8),%rax
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *array_get(void **base, size_t length, int position) {
  if (position > length)
    return (void *)0;
  if (position < 0)
    return (void *)0;
  return base[position];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<array_get>:
  endbr64
  movslq %edx,%rax
  test   %edx,%edx
  js     L7
  cmp    %rsi,%rax
  ja     L7
  mov    (%rdi,%rax,8),%rax
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *array_get(void **base, size_t length, int position) {
  if (position > length)
    return (void *)0;
  if (position < 0)
    return (void *)0;
  return base[position];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  jmp    L5
L6:
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gcd>
L5:
  leave
  ret
```

assistant: ```c
long long int gcd(long long int a, long long int b) {
  if (b == 0) {
    return a;
  }
  return gcd(b, a % b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L4
  ret
L4:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cqto
  idiv   %rsi
  mov    %rdx,%rsi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long long int gcd(long long int a, long long int b) {
  if (b == 0) {
    return a;
  }
  return gcd(b, a % b);
}
```
user: What is the c source code of the assembly code below:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  test   %rsi,%rsi
  jne    L10
  jmp    L13
  nopl   0x0(%rax)
L16:
  mov    %rdx,%r8
L10:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L16
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L13:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long long int gcd(long long int a, long long int b) {
  if (b == 0) {
    return a;
  }
  return gcd(b, a % b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  test   %rsi,%rsi
  jne    L17
  jmp    L9
  nopl   0x0(%rax)
L21:
  mov    %rdx,%r8
L17:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L21
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long long int gcd(long long int a, long long int b) {
  if (b == 0) {
    return a;
  }
  return gcd(b, a % b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
type: string
name: disassemble_data
arguments: label: D7
type: string
name: disassemble_data
arguments: label: D12
type: string

tool: D18: Interstellar


tool: D7: /home/shahas/Desktop/

tool: D12: new_dir

assistant: ```c
int main() {
  int a;
  printf("Interstellar\n");
  chdir("/home/shahas/Desktop/");
  rmdir("new_dir");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <chdir@plt>
  lea    D18(%rip),%rdi
  call   <rmdir@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string

tool: D12: Interstellar


tool: D7: /home/shahas/Desktop/

tool: D18: new_dir

assistant: ```c
int main() {
  int a;
  printf("Interstellar\n");
  chdir("/home/shahas/Desktop/");
  rmdir("new_dir");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <chdir@plt>
  lea    D8(%rip),%rdi
  call   <rmdir@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D21: Interstellar


tool: D15: /home/shahas/Desktop/

tool: D8: new_dir

assistant: ```c
int main() {
  int a;
  printf("Interstellar\n");
  chdir("/home/shahas/Desktop/");
  rmdir("new_dir");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <chdir@plt>
  lea    D4(%rip),%rdi
  call   <rmdir@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D12
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string

tool: D6: Interstellar


tool: D12: /home/shahas/Desktop/

tool: D4: new_dir

assistant: ```c
int main() {
  int a;
  printf("Interstellar\n");
  chdir("/home/shahas/Desktop/");
  rmdir("new_dir");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convolution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L73
L35:
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L70:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L70
  addl   $0x1,-0x10(%rbp)
L73:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  movl   $0x0,-0x8(%rbp)
  jmp    L67
L38:
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L68:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L68
  addl   $0x1,-0x8(%rbp)
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  nop
  pop    %rbp
  ret
```

assistant: ```c
void convolution(const double *input_a, const int a_len, const double *input_b, const int b_len, double *output) {
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] = 0.0;
    }
  }
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] += (input_a[i] * input_b[j]);
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convolution>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %rbx
  mov    %rdx,%r9
  mov    %ecx,%r11d
  lea    -0x1(%rcx),%r10d
  mov    %r8,%rdx
  lea    0x8(%r8,%r10,8),%rcx
  mov    $0x0,%r8d
  mov    %r10,%rbx
  not    %rbx
  shl    $0x3,%rbx
  jmp    L38
L11:
  ret
L60:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L60
L101:
  lea    0x1(%r8),%eax
  add    $0x8,%rcx
  cmp    %eax,%esi
  je     L77
  mov    %eax,%r8d
L38:
  lea    (%rbx,%rcx,1),%rax
  test   %r11d,%r11d
  jg     L60
  jmp    L101
L77:
  mov    %rdi,%rsi
  mov    $0x0,%edi
  jmp    L108
L55:
  movsd  (%rsi),%xmm0
  mulsd  (%r9,%rax,8),%xmm0
  addsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r10,%rcx
  jne    L55
L64:
  lea    0x1(%rdi),%eax
  add    $0x8,%rdx
  add    $0x8,%rsi
  cmp    %edi,%r8d
  je     L72
  mov    %eax,%edi
L108:
  mov    $0x0,%eax
  test   %r11d,%r11d
  jg     L55
  jmp    L64
L72:
  pop    %rbx
  ret
```

assistant: ```c
void convolution(const double *input_a, const int a_len, const double *input_b, const int b_len, double *output) {
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] = 0.0;
    }
  }
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] += (input_a[i] * input_b[j]);
    }
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convolution>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L25
  mov    0x4(%rsp),%eax
  lea    -0x1(%rcx),%r14d
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %r8,%rbx
  lea    0x8(,%r14,8),%r15
  mov    %r8,%rdi
  sub    $0x1,%eax
  lea    0x8(%r8,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L43:
  test   %r12d,%r12d
  jle    L16
  mov    %r15,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rdi
L16:
  add    $0x8,%rdi
  cmp    %rbp,%rdi
  jne    L43
  mov    0x8(%rsp),%rbp
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  test   %r12d,%r12d
  jle    L8
  nop
L17:
  movsd  0x0(%rbp),%xmm0
  mulsd  0x0(%r13,%rax,8),%xmm0
  mov    %rax,%rdx
  addsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %r14,%rdx
  jne    L17
L8:
  add    $0x1,%esi
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %esi,0x4(%rsp)
  jne    L47
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convolution(const double *input_a, const int a_len, const double *input_b, const int b_len, double *output) {
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] = 0.0;
    }
  }
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] += (input_a[i] * input_b[j]);
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convolution>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L7
  mov    %ecx,%r12d
  test   %ecx,%ecx
  jle    L7
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r13
  mov    %rdx,%rbx
  mov    %r8,%rbp
  lea    0x8(%r8,%rax,8),%r15
  movslq %r12d,%rax
  mov    %r8,%rcx
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rax,8),%r14
  nopl   (%rax)
L87:
  mov    %rcx,%rdi
  mov    %r14,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
  add    $0x8,%rcx
  cmp    %r15,%rcx
  jne    L87
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    0x8(%rsp),%r11
  mov    %rbp,%rax
  shr    %edx
  and    $0xfffffffe,%esi
  lea    0x8(%rbx),%r9
  xor    %ecx,%ecx
  lea    -0x1(%rdx),%edi
  mov    %esi,%edx
  lea    0x0(,%r11,8),%r14
  add    $0x1,%rdi
  lea    (%rbx,%rdx,8),%r10
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r13,%rdx
  add    $0x8,%r13
  cmp    %r9,%rax
  setne  %r15b
  cmp    $0x1,%r12d
  setne  %r8b
  test   %r8b,%r15b
  je     L94
  lea    (%r14,%rax,1),%r8
  cmp    %r8,%rdx
  setae  %r15b
  cmp    %r13,%rax
  setae  %r8b
  or     %r15b,%r8b
  je     L94
  movsd  (%rdx),%xmm1
  xor    %r8d,%r8d
  unpcklpd %xmm1,%xmm1
  nopl   0x0(%rax)
L93:
  movupd (%rbx,%r8,1),%xmm0
  movupd (%rax,%r8,1),%xmm2
  mulpd  %xmm1,%xmm0
  addpd  %xmm2,%xmm0
  movups %xmm0,(%rax,%r8,1)
  add    $0x10,%r8
  cmp    %r8,%rdi
  jne    L93
  cmp    %esi,%r12d
  je     L48
  lea    (%rcx,%rsi,1),%r8d
  movsd  (%rdx),%xmm0
  mulsd  (%r10),%xmm0
  movslq %r8d,%r8
  lea    0x0(%rbp,%r8,8),%r8
  addsd  (%r8),%xmm0
  movsd  %xmm0,(%r8)
L48:
  add    $0x1,%ecx
  add    $0x8,%rax
  cmp    %ecx,0x4(%rsp)
  jne    L57
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L94:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L6:
  movsd  (%rdx),%xmm0
  mulsd  (%rbx,%r8,8),%xmm0
  addsd  (%rax,%r8,8),%xmm0
  movsd  %xmm0,(%rax,%r8,8)
  add    $0x1,%r8
  cmp    %r11,%r8
  jne    L6
  jmp    L48
```

assistant: ```c
void convolution(const double *input_a, const int a_len, const double *input_b, const int b_len, double *output) {
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] = 0.0;
    }
  }
  for (int i = 0; i < a_len; i++) {
    for (int j = 0; j < b_len; j++) {
      output[i + j] += (input_a[i] * input_b[j]);
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<marker_string_filename_get_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L27:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L25
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L25:
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  ja     L27
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *marker_string_filename_get_path(const char *filename) {
  size_t len = strlen(filename);
  const char *last_slash = filename;
  for (int i = 0; i < len; ++i) {
    if (filename[i] == '/') {
      last_slash = &filename[i];
    }
  }
  len = last_slash - filename;
  char *ret = (char *)malloc(len + 1);
  memset(ret, 0, len + 1);
  memcpy(ret, filename, len);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<marker_string_filename_get_path>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %rax,%rax
  je     L28
  mov    %rbp,%rdx
  add    %rbp,%rax
  mov    %rbp,%rcx
L7:
  cmpb   $0x2f,(%rdx)
  cmove  %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L7
L29:
  mov    %rcx,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r13,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    %rbp,%rcx
  jmp    L29
```

assistant: ```c
char *marker_string_filename_get_path(const char *filename) {
  size_t len = strlen(filename);
  const char *last_slash = filename;
  for (int i = 0; i < len; ++i) {
    if (filename[i] == '/') {
      last_slash = &filename[i];
    }
  }
  len = last_slash - filename;
  char *ret = (char *)malloc(len + 1);
  memset(ret, 0, len + 1);
  memcpy(ret, filename, len);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<marker_string_filename_get_path>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  lea    (%rax,%rbp,1),%rcx
  mov    %rbp,%rdx
  mov    %rbp,%rax
  nopl   0x0(%rax)
L2:
  cmpb   $0x2f,(%rdx)
  cmove  %rdx,%rax
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  jne    L2
  sub    %rbp,%rax
  mov    %rax,%r12
  lea    0x1(%rax),%r14
L11:
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %r14,%rdx
  xor    %esi,%esi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L15:
  mov    $0x1,%r14d
  jmp    L11
```

assistant: ```c
char *marker_string_filename_get_path(const char *filename) {
  size_t len = strlen(filename);
  const char *last_slash = filename;
  for (int i = 0; i < len; ++i) {
    if (filename[i] == '/') {
      last_slash = &filename[i];
    }
  }
  len = last_slash - filename;
  char *ret = (char *)malloc(len + 1);
  memset(ret, 0, len + 1);
  memcpy(ret, filename, len);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<marker_string_filename_get_path>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  lea    (%rax,%rbp,1),%rcx
  mov    %rbp,%rdx
  mov    %rbp,%rax
  nopl   0x0(%rax)
L9:
  cmpb   $0x2f,(%rdx)
  cmove  %rdx,%rax
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  jne    L9
  sub    %rbp,%rax
  mov    %rax,%r12
  lea    0x1(%rax),%r14
L4:
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %r14,%rdx
  xor    %esi,%esi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L6:
  mov    $0x1,%r14d
  jmp    L4
```

assistant: ```c
char *marker_string_filename_get_path(const char *filename) {
  size_t len = strlen(filename);
  const char *last_slash = filename;
  for (int i = 0; i < len; ++i) {
    if (filename[i] == '/') {
      last_slash = &filename[i];
    }
  }
  len = last_slash - filename;
  char *ret = (char *)malloc(len + 1);
  memset(ret, 0, len + 1);
  memcpy(ret, filename, len);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L23:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L23
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L4
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *itoa(int a, char *buf) {
  int num = a;
  int i = 0;
  int len = 0;
  do {
    buf[i++] = num % 10 + '0';
    num /= 10;
  } while (num);
  buf[i] = '\0';
  len = i;
  for (i = 0; i < len / 2; i++) {
    char tmp;
    tmp = buf[i];
    buf[i] = buf[len - i - 1];
    buf[len - i - 1] = tmp;
  }
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa>:
  endbr64
  mov    $0x1,%edx
L7:
  mov    %edx,%r9d
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rsi,%rdx,1)
  mov    %eax,%edi
  add    $0x1,%rdx
  test   %eax,%eax
  jne    L7
  movslq %r9d,%rax
  movb   $0x0,(%rsi,%rax,1)
  mov    %r9d,%r8d
  shr    $0x1f,%r8d
  add    %r9d,%r8d
  sar    %r8d
  cmp    $0x1,%r9d
  jle    L24
  lea    -0x1(%rsi,%rax,1),%rdx
  mov    $0x0,%eax
L13:
  movzbl (%rsi,%rax,1),%ecx
  movzbl (%rdx),%edi
  mov    %dil,(%rsi,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%r8d
  jg     L13
L24:
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *itoa(int a, char *buf) {
  int num = a;
  int i = 0;
  int len = 0;
  do {
    buf[i++] = num % 10 + '0';
    num /= 10;
  } while (num);
  buf[i] = '\0';
  len = i;
  for (i = 0; i < len / 2; i++) {
    char tmp;
    tmp = buf[i];
    buf[i] = buf[len - i - 1];
    buf[len - i - 1] = tmp;
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  mov    %rsi,%r8
  mov    $0x1,%edx
  nopl   0x0(%rax)
L27:
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%r8,%rdx,1)
  mov    %eax,%edi
  add    $0x1,%rdx
  test   %eax,%eax
  jne    L27
  movslq %esi,%rcx
  sar    %esi
  movb   $0x0,(%r8,%rcx,1)
  je     L22
  lea    -0x2(%r8,%rcx,1),%rdi
  lea    -0x1(%r8,%rcx,1),%rax
  mov    %r8,%rdx
  lea    -0x1(%rsi),%ecx
  sub    %rcx,%rdi
  nop
L24:
  movzbl (%rdx),%ecx
  movzbl (%rax),%esi
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  mov    %cl,0x1(%rax)
  cmp    %rdi,%rax
  jne    L24
L22:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int a, char *buf) {
  int num = a;
  int i = 0;
  int len = 0;
  do {
    buf[i++] = num % 10 + '0';
    num /= 10;
  } while (num);
  buf[i] = '\0';
  len = i;
  for (i = 0; i < len / 2; i++) {
    char tmp;
    tmp = buf[i];
    buf[i] = buf[len - i - 1];
    buf[len - i - 1] = tmp;
  }
  return buf;
}
```