user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    D64(%rip),%r12
  lea    D104(%rip),%rbp
  lea    D57(%rip),%r13
L49:
  lea    D7(%rip),%rbx
L46:
  cmpl   $0xffffffff,0x14(%rsp)
  je     L6
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0xffffffff,0x14(%rsp)
  je     L6
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  subss  0x20(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  comiss 0x24(%rsp),%xmm0
  jbe    L46
  mov    0x14(%rsp),%esi
  lea    D87(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x24(%rsp),%xmm0
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D102(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D101(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D64
type_infered: string
name: retrieve_data
arguments: tag: D104
type_infered: string
name: retrieve_data
arguments: tag: D57
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D28
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D48
type_infered: string
name: retrieve_data
arguments: tag: D87
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D102
type_infered: string
name: retrieve_data
arguments: tag: D101
type_infered: string

tool: D64: Enter account number (-1 to end):

tool: D104: %d

tool: D57: Enter beginning balance:

tool: D7: %f

tool: D28: Enter total charges:

tool: D12: Enter total credits:

tool: D48: Enter  credit limit:

tool: D87: Account: %d

tool: D4: 
Credit:%f

tool: D102: 
Balance:%.2f 

tool: D101: 
Credit Limit Exceeded.


assistant: ```c
int main(void) {
  int account_number = 0;
  float beginning_balance, total_charge, total_credit, credit_limit, balance;
  while (account_number != -1) {
    printf("Enter account number (-1 to end):");
    scanf("%d", &account_number);
    if (account_number == -1) {
      break;
    }
    printf("Enter beginning balance:");
    scanf("%f", &beginning_balance);
    printf("Enter total charges:");
    scanf("%f", &total_charge);
    printf("Enter total credits:");
    scanf("%f", &total_credit);
    printf("Enter  credit limit:");
    scanf("%f", &credit_limit);
    balance = beginning_balance + total_charge - total_credit;
    if (balance > credit_limit) {
      printf("Account: %d", account_number);
      printf("\nCredit:%f", credit_limit);
      printf("\nBalance:%.2f ", balance);
      printf("\nCredit Limit Exceeded.\n\n");
    }
  }
  return 0;
}
```