user: 这段汇编代码用C语言表示是什么样的?

```asm
<smoother>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r8d,%esi
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %r8d,%edi
  mov    %rdx,0x10(%rsp)
  mov    %r9,0x18(%rsp)
  call   <mat@plt>
  mov    %r15d,%esi
  mov    %r15d,%edi
  mov    %rax,%r14
  call   <mat@plt>
  mov    $0x1,%esi
  mov    %r15d,%edi
  mov    %rax,%rbp
  call   <mat@plt>
  test   %r14,%r14
  mov    %rax,%r12
  sete   %al
  test   %rbp,%rbp
  sete   %dl
  or     %dl,%al
  jne    L79
  test   %r12,%r12
  je     L79
  mov    %r15d,%ecx
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <matcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r15d,%ecx
  mov    %r15d,%edx
  call   <matcpy@plt>
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <matinv@plt>
  test   %eax,%eax
  je     L57
L47:
  mov    $0xffffffff,%r13d
L74:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
L70:
  add    $0x28,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L57:
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <matinv@plt>
  test   %eax,%eax
  jne    L47
  mov    %r15d,%edx
  imul   %r15d,%edx
  test   %edx,%edx
  je     L75
  movslq %edx,%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L31:
  movsd  (%r14,%rax,8),%xmm0
  addsd  0x0(%rbp,%rax,8),%xmm0
  mov    0x60(%rsp),%rbx
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L31
L75:
  mov    0x60(%rsp),%rdi
  mov    %r15d,%esi
  call   <matinv@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jne    L74
  sub    $0x8,%rsp
  pxor   %xmm1,%xmm1
  mov    %r14,%r8
  mov    %r15d,%ecx
  push   %r12
  lea    D32(%rip),%rbx
  mov    0x18(%rsp),%r9
  mov    %r15d,%esi
  movsd  D12(%rip),%xmm0
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <matmul@plt>
  mov    0x20(%rsp),%r9
  mov    %rbp,%r8
  mov    %r15d,%ecx
  mov    $0x1,%edx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %r12,(%rsp)
  mov    D12(%rip),%rax
  movq   %rax,%xmm0
  movq   %rax,%xmm1
  call   <matmul@plt>
  pop    %rax
  mov    D12(%rip),%rax
  mov    %r15d,%ecx
  push   0x20(%rsp)
  mov    0x70(%rsp),%r8
  pxor   %xmm1,%xmm1
  mov    %r12,%r9
  mov    $0x1,%edx
  movq   %rax,%xmm0
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <matmul@plt>
  pop    %rdx
  pop    %rcx
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L79:
  mov    $0xffffffff,%r13d
  jmp    L70
```

tool_calls: name: retrieve_data
arguments: tag: D32
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: f64

tool: D32: NN

tool: D12: 1

assistant: ```c
extern int smoother(const double *xf, const double *Qf, const double *xb, const double *Qb, int n, double *xs, double *Qs) {
  double *invQf = mat(n, n), *invQb = mat(n, n), *xx = mat(n, 1);
  int i, info = -1;
  if (!invQf || !invQb || !xx) {
    return info;
  }
  matcpy(invQf, Qf, n, n);
  matcpy(invQb, Qb, n, n);
  if (!matinv(invQf, n) && !matinv(invQb, n)) {
    for (i = 0; i < n * n; ++i) {
      Qs[i] = invQf[i] + invQb[i];
    }
    if (!(info = matinv(Qs, n))) {
      matmul("NN", n, 1, n, 1.0, invQf, xf, 0.0, xx);
      matmul("NN", n, 1, n, 1.0, invQb, xb, 1.0, xx);
      matmul("NN", n, 1, n, 1.0, Qs, xx, 0.0, xs);
    }
  }
  free(invQf);
  free(invQb);
  free(xx);
  return info;
}
```