ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<timestomp>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D6(%rip),%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <execute@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x70,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: /usr/bin/touch %s -r %s

assistant: ```c
void timestomp(char *sfile, char *dfile) {
  char cmd[100];
  snprintf(cmd, 100, "/usr/bin/touch %s -r %s", dfile, sfile);
  char *output = malloc(1024);
  execute(cmd, output);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timestomp>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    D9(%rip),%rdx
  mov    $0x64,%esi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <execute@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: /usr/bin/touch %s -r %s

assistant: ```c
void timestomp(char *sfile, char *dfile) {
  char cmd[100];
  snprintf(cmd, 100, "/usr/bin/touch %s -r %s", dfile, sfile);
  char *output = malloc(1024);
  execute(cmd, output);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<timestomp>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    D2(%rip),%rdx
  mov    $0x64,%esi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <execute@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: /usr/bin/touch %s -r %s

assistant: ```c
void timestomp(char *sfile, char *dfile) {
  char cmd[100];
  snprintf(cmd, 100, "/usr/bin/touch %s -r %s", dfile, sfile);
  char *output = malloc(1024);
  execute(cmd, output);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pvEnableMultiChannelROI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %esi,%eax
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    %edi,%edx
  mov    %dl,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: f

assistant: ```c
int pvEnableMultiChannelROI(char byBoardNum, short wNumChannels, short *pLefts, short *pRights, short *pBottoms, short *pTops) {
  notify_pvcall("f");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pvEnableMultiChannelROI>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: f

assistant: ```c
int pvEnableMultiChannelROI(char byBoardNum, short wNumChannels, short *pLefts, short *pRights, short *pBottoms, short *pTops) {
  notify_pvcall("f");
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pvEnableMultiChannelROI>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: f

assistant: ```c
int pvEnableMultiChannelROI(char byBoardNum, short wNumChannels, short *pLefts, short *pRights, short *pBottoms, short *pTops) {
  notify_pvcall("f");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pvEnableMultiChannelROI>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: f

assistant: ```c
int pvEnableMultiChannelROI(char byBoardNum, short wNumChannels, short *pLefts, short *pRights, short *pBottoms, short *pTops) {
  notify_pvcall("f");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x9,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <Myprintf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9:  WWW.FIRMCODES.COM 
 %d

assistant: ```c
int main() {
  Myprintf(" WWW.FIRMCODES.COM \n %d", 9);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  lea    D0(%rip),%rdi
  call   <Myprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0:  WWW.FIRMCODES.COM 
 %d

assistant: ```c
int main() {
  Myprintf(" WWW.FIRMCODES.COM \n %d", 9);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  lea    D0(%rip),%rdi
  call   <Myprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0:  WWW.FIRMCODES.COM 
 %d

assistant: ```c
int main() {
  Myprintf(" WWW.FIRMCODES.COM \n %d", 9);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  lea    D2(%rip),%rdi
  call   <Myprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2:  WWW.FIRMCODES.COM 
 %d

assistant: ```c
int main() {
  Myprintf(" WWW.FIRMCODES.COM \n %d", 9);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ptToChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char ptToChar(void *pt) {
  char *a = NULL, *b = pt;
  return b - a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ptToChar>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
char ptToChar(void *pt) {
  char *a = NULL, *b = pt;
  return b - a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ptToChar>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
char ptToChar(void *pt) {
  char *a = NULL, *b = pt;
  return b - a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ptToChar>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
char ptToChar(void *pt) {
  char *a = NULL, *b = pt;
  return b - a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rndt4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  D20(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
L2:
  mov    $0x0,%eax
  call   <rndu@plt>
  addsd  %xmm0,%xmm0
  movsd  D24(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    $0x0,%eax
  call   <rndu@plt>
  addsd  %xmm0,%xmm0
  movsd  D24(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D24(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  ja     L4
  jmp    L2
L4:
  nop
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    $0x4,%eax
  cltd
  idiv   %ecx
  sub    $0x4,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    $0x0,%eax
  call   <rndu@plt>
  movsd  D30(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L20
  movsd  -0x38(%rbp),%xmm0
  movq   D23(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
L20:
  movsd  -0x38(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type_guessed: f64
name: retrieve_data
arguments: data_label: D24
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D30
type_guessed: f64
name: retrieve_data
arguments: data_label: D23
type_guessed: byte[8]

tool: D20: 0.707106781

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D30: 0.5

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double rndt4(void) {
  double u, v, w, c2, r2, t4, sqrt2 = 0.707106781;
  for (;;) {
    u = 2 * rndu() - 1;
    v = 2 * rndu() - 1;
    w = u * u + v * v;
    if (w < 1)
      break;
  }
  c2 = u * u / w;
  r2 = 4 / sqrt(w) - 4;
  t4 = sqrt(r2 * c2);
  if (rndu() < 0.5)
    t4 = -t4;
  return t4 * sqrt2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rndt4>:
  endbr64
  sub    $0x18,%rsp
L19:
  mov    $0x0,%eax
  call   <rndu@plt>
  addsd  %xmm0,%xmm0
  subsd  D32(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%eax
  call   <rndu@plt>
  addsd  %xmm0,%xmm0
  subsd  D32(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D32(%rip),%xmm2
  comisd %xmm0,%xmm2
  jbe    L19
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    $0x4,%eax
  cltd
  idiv   %ecx
  sub    $0x4,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  movsd  %xmm3,0x8(%rsp)
  mov    $0x0,%eax
  call   <rndu@plt>
  movsd  D6(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L8
  movsd  0x8(%rsp),%xmm3
  xorpd  D36(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
L8:
  movsd  0x8(%rsp),%xmm0
  mulsd  D42(%rip),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D32
type_guessed: byte[8]
name: unpack_data
arguments: tag: D6
type_guessed: f64
name: unpack_data
arguments: tag: D36
type_guessed: byte[16]
name: unpack_data
arguments: tag: D42
type_guessed: f64

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D6: 0.5

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D42: 0.707106781

assistant: ```c
double rndt4(void) {
  double u, v, w, c2, r2, t4, sqrt2 = 0.707106781;
  for (;;) {
    u = 2 * rndu() - 1;
    v = 2 * rndu() - 1;
    w = u * u + v * v;
    if (w < 1)
      break;
  }
  c2 = u * u / w;
  r2 = 4 / sqrt(w) - 4;
  t4 = sqrt(r2 * c2);
  if (rndu() < 0.5)
    t4 = -t4;
  return t4 * sqrt2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rndt4>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <rndu@plt>
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  subsd  D33(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <rndu@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  D33(%rip),%xmm3
  addsd  %xmm0,%xmm0
  subsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  jbe    L14
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  mov    %eax,%r8d
  mov    $0x4,%eax
  cltd
  idiv   %r8d
  sub    $0x4,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <rndu@plt>
  movsd  D29(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm2
  jbe    L17
  xorpd  D51(%rip),%xmm1
L17:
  mulsd  D23(%rip),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D33
data_type: byte[8]
name: read_data
arguments: data_label: D29
data_type: f64
name: read_data
arguments: data_label: D51
data_type: byte[16]
name: read_data
arguments: data_label: D23
data_type: f64

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D29: 0.5

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D23: 0.707106781

assistant: ```c
double rndt4(void) {
  double u, v, w, c2, r2, t4, sqrt2 = 0.707106781;
  for (;;) {
    u = 2 * rndu() - 1;
    v = 2 * rndu() - 1;
    w = u * u + v * v;
    if (w < 1)
      break;
  }
  c2 = u * u / w;
  r2 = 4 / sqrt(w) - 4;
  t4 = sqrt(r2 * c2);
  if (rndu() < 0.5)
    t4 = -t4;
  return t4 * sqrt2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rndt4>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  call   <rndu@plt>
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  subsd  D33(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <rndu@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  D33(%rip),%xmm3
  addsd  %xmm0,%xmm0
  subsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  jbe    L19
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  mov    %eax,%r8d
  mov    $0x4,%eax
  cltd
  idiv   %r8d
  sub    $0x4,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <rndu@plt>
  movsd  D46(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm2
  jbe    L1
  xorpd  D57(%rip),%xmm1
L1:
  mulsd  D44(%rip),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D33
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D46
type_guessed: f64
name: parse_data
arguments: data_tag: D57
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D44
type_guessed: f64

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D46: 0.5

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D44: 0.707106781

assistant: ```c
double rndt4(void) {
  double u, v, w, c2, r2, t4, sqrt2 = 0.707106781;
  for (;;) {
    u = 2 * rndu() - 1;
    v = 2 * rndu() - 1;
    w = u * u + v * v;
    if (w < 1)
      break;
  }
  c2 = u * u / w;
  r2 = 4 / sqrt(w) - 4;
  t4 = sqrt(r2 * c2);
  if (rndu() < 0.5)
    t4 = -t4;
  return t4 * sqrt2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<testExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L52
L25:
  mov    -0x118(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  jmp    L64
L2:
  mov    -0x118(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x118(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x118(%rbp)
L64:
  mov    -0x118(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  lea    -0x110(%rbp),%rdx
  mov    -0x130(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L41
  mov    $0x0,%eax
  jmp    L52
L41:
  mov    $0x1,%eax
L52:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
int testExt(char *path, char *ext) {
  char *ptr = strrchr(path, '.');
  if (!ptr)
    return 0;
  char buf[255];
  strcpy(buf, ptr + 1);
  ptr = buf;
  while (*ptr) {
    *ptr = tolower(*ptr);
    ptr++;
  }
  if (strcmp(ext, buf))
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testExt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  movzbl (%rsp),%edi
  test   %dil,%dil
  je     L29
  mov    %rsp,%rbx
L34:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L34
L29:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
L2:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %edx,%eax
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int testExt(char *path, char *ext) {
  char *ptr = strrchr(path, '.');
  if (!ptr)
    return 0;
  char buf[255];
  strcpy(buf, ptr + 1);
  ptr = buf;
  while (*ptr) {
    *ptr = tolower(*ptr);
    ptr++;
  }
  if (strcmp(ext, buf))
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<testExt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2e,%esi
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strrchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L13
  mov    %rsp,%r12
  lea    0x1(%rax),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  movsbl (%rsp),%edi
  test   %dil,%dil
  je     L26
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L13:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x110,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int testExt(char *path, char *ext) {
  char *ptr = strrchr(path, '.');
  if (!ptr)
    return 0;
  char buf[255];
  strcpy(buf, ptr + 1);
  ptr = buf;
  while (*ptr) {
    *ptr = tolower(*ptr);
    ptr++;
  }
  if (strcmp(ext, buf))
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<testExt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2e,%esi
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strrchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L8
  mov    %rsp,%r12
  lea    0x1(%rax),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  movsbl (%rsp),%edi
  test   %dil,%dil
  je     L25
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L35:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L35
L25:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L8:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x110,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int testExt(char *path, char *ext) {
  char *ptr = strrchr(path, '.');
  if (!ptr)
    return 0;
  char buf[255];
  strcpy(buf, ptr + 1);
  ptr = buf;
  while (*ptr) {
    *ptr = tolower(*ptr);
    ptr++;
  }
  if (strcmp(ext, buf))
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fs_mr_archchg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rdi
  mov    -0x48(%rbp),%rsi
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x18(%rbp),%rcx
  push   %rcx
  lea    -0x20(%rbp),%rcx
  push   %rcx
  lea    -0x28(%rbp),%rcx
  push   %rcx
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rdx,%rcx
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fs_univ_archchg@plt>
  add    $0x20,%rsp
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L4
  mov    -0x10(%rbp),%rax
  jmp    L31
L4:
  mov    -0x28(%rbp),%rax
  cmp    %rax,-0x58(%rbp)
  jne    L5
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x60(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  cmp    %rax,0x10(%rbp)
  je     L36
L5:
  mov    $0x20,%eax
  jmp    L31
L36:
  mov    $0x0,%eax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
uint8_t fs_mr_archchg(uint32_t ts, uint32_t inode, uint32_t uid, uint8_t cmd, uint64_t chgchunks, uint64_t notchgchunks, uint32_t nsinodes) {
  uint64_t cc, ncc;
  uint32_t nsi;
  uint8_t status;
  status = fs_univ_archchg(ts, 0, 0x80, inode, uid, cmd, &cc, &ncc, &nsi);
  if (status != 0) {
    return status;
  }
  if (cc != chgchunks || ncc != notchgchunks || nsi != nsinodes) {
    return 32;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fs_mr_archchg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rax
  mov    %r8,%rbx
  mov    %r9,%rbp
  mov    %fs:0x28,%rsi
  mov    %rsi,0x20(%rsp)
  xor    %esi,%esi
  lea    0x18(%rsp),%rsi
  push   %rsi
  lea    0x18(%rsp),%rsi
  push   %rsi
  lea    0x18(%rsp),%rsi
  push   %rsi
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    %rax,%rcx
  mov    $0x80,%edx
  mov    $0x0,%esi
  call   <fs_univ_archchg@plt>
  add    $0x20,%rsp
  test   %rax,%rax
  jne    L3
  mov    $0x20,%eax
  cmp    %rbx,(%rsp)
  jne    L3
  cmp    %rbp,0x8(%rsp)
  jne    L3
  mov    0x40(%rsp),%rax
  cmp    %rax,0x10(%rsp)
  setne  %al
  movzbl %al,%eax
  shl    $0x5,%rax
L3:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t fs_mr_archchg(uint32_t ts, uint32_t inode, uint32_t uid, uint8_t cmd, uint64_t chgchunks, uint64_t notchgchunks, uint32_t nsinodes) {
  uint64_t cc, ncc;
  uint32_t nsi;
  uint8_t status;
  status = fs_univ_archchg(ts, 0, 0x80, inode, uid, cmd, &cc, &ncc, &nsi);
  if (status != 0) {
    return status;
  }
  if (cc != chgchunks || ncc != notchgchunks || nsi != nsinodes) {
    return 32;
  }
  return 0;
}
```