ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<minCost>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %esi,0xc(%rsp)
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %eax,0x10(%rsp)
  test   %esi,%esi
  jle    L89
  mov    %eax,%edx
  add    0xc(%rdi),%edx
  mov    %edx,0x1c(%rsp)
  cmp    $0x1,%esi
  jle    L96
  add    0x18(%rdi),%edx
  mov    %edx,0x28(%rsp)
L96:
  test   %r12d,%r12d
  jle    L62
L83:
  add    0x4(%rdi),%eax
  mov    %eax,0x14(%rsp)
  cmp    $0x1,%r12d
  jle    L39
  add    0x8(%rdi),%eax
  mov    %eax,0x18(%rsp)
L39:
  cmpl   $0x0,0xc(%rsp)
  jle    L9
L62:
  lea    0x1c(%rsp),%r15
  lea    0xc(%rdi),%r13
  mov    $0x1,%r14d
  jmp    L93
L85:
  mov    %r13,(%rsp)
  mov    %r15,%rbx
  mov    $0x1,%ebp
L75:
  mov    -0x8(%rbx),%esi
  mov    -0xc(%rbx),%edi
  mov    (%rbx),%edx
  call   <min@plt>
  mov    (%rsp),%rcx
  add    (%rcx,%rbp,4),%eax
  mov    %eax,0x4(%rbx)
  add    $0x1,%rbp
  add    $0x4,%rbx
  cmp    %ebp,%r12d
  jge    L75
L114:
  add    $0x1,%r14d
  add    $0xc,%r15
  add    $0xc,%r13
  cmp    %r14d,0xc(%rsp)
  jl     L9
L93:
  test   %r12d,%r12d
  jg     L85
  jmp    L114
L89:
  test   %edx,%edx
  jg     L83
L9:
  movslq %r12d,%r12
  movslq 0xc(%rsp),%rax
  lea    (%rax,%rax,2),%rax
  add    %r12,%rax
  mov    0x10(%rsp,%rax,4),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L77
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int minCost(int cost[3][3], int m, int n) {
  int i, j;
  int travellingCost[3][3];
  travellingCost[0][0] = cost[0][0];
  for (i = 1; i <= m; i++)
    travellingCost[i][0] = travellingCost[i - 1][0] + cost[i][0];
  for (j = 1; j <= n; j++)
    travellingCost[0][j] = travellingCost[0][j - 1] + cost[0][j];
  for (i = 1; i <= m; i++)
    for (j = 1; j <= n; j++)
      travellingCost[i][j] = min(travellingCost[i - 1][j - 1], travellingCost[i - 1][j], travellingCost[i][j - 1]) + cost[i][j];
  return (travellingCost[m][n]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<minCost>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  mov    (%rdi),%eax
  mov    %eax,0x10(%rsp)
  test   %r12d,%r12d
  jle    L17
  mov    0xc(%rdi),%edx
  add    %eax,%edx
  mov    %edx,0x1c(%rsp)
  cmp    $0x1,%r12d
  je     L17
  add    0x18(%rdi),%edx
  mov    %edx,0x28(%rsp)
L17:
  test   %r14d,%r14d
  jle    L38
  add    0x4(%rdi),%eax
  mov    %eax,0x14(%rsp)
  cmp    $0x1,%r14d
  je     L38
  add    0x8(%rdi),%eax
  mov    %eax,0x18(%rsp)
L38:
  test   %r12d,%r12d
  jle    L36
  movl   $0x1,0x4(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0xc(%rdi),%rbp
L67:
  lea    0xc(%rbx),%rax
  mov    $0x1,%r15d
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  test   %r14d,%r14d
  jle    L34
L8:
  mov    0x4(%rbx),%esi
  mov    0x0(%r13),%edx
  add    $0x4,%rbx
  add    $0x4,%r13
  mov    -0x4(%rbx),%edi
  call   <min@plt>
  add    0x0(%rbp,%r15,4),%eax
  add    $0x1,%r15
  mov    %eax,0x0(%r13)
  cmp    %r15d,%r14d
  jge    L8
L34:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  add    $0xc,%rbp
  mov    0x8(%rsp),%rbx
  cmp    %eax,%r12d
  jge    L67
L36:
  movslq %r14d,%r8
  lea    (%r12,%r12,2),%rax
  add    %r8,%rax
  mov    0x10(%rsp,%rax,4),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int minCost(int cost[3][3], int m, int n) {
  int i, j;
  int travellingCost[3][3];
  travellingCost[0][0] = cost[0][0];
  for (i = 1; i <= m; i++)
    travellingCost[i][0] = travellingCost[i - 1][0] + cost[i][0];
  for (j = 1; j <= n; j++)
    travellingCost[0][j] = travellingCost[0][j - 1] + cost[0][j];
  for (i = 1; i <= m; i++)
    for (j = 1; j <= n; j++)
      travellingCost[i][j] = min(travellingCost[i - 1][j - 1], travellingCost[i - 1][j], travellingCost[i][j - 1]) + cost[i][j];
  return (travellingCost[m][n]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<minCost>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  mov    (%rdi),%eax
  mov    %eax,0x10(%rsp)
  test   %r12d,%r12d
  jle    L15
  mov    0xc(%rdi),%edx
  add    %eax,%edx
  mov    %edx,0x1c(%rsp)
  cmp    $0x1,%r12d
  je     L15
  add    0x18(%rdi),%edx
  mov    %edx,0x28(%rsp)
L15:
  test   %r14d,%r14d
  jle    L20
  add    0x4(%rdi),%eax
  mov    %eax,0x14(%rsp)
  cmp    $0x1,%r14d
  je     L20
  add    0x8(%rdi),%eax
  mov    %eax,0x18(%rsp)
L20:
  test   %r12d,%r12d
  jle    L37
  movl   $0x1,0x4(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0xc(%rdi),%rbp
L61:
  lea    0xc(%rbx),%rax
  mov    $0x1,%r15d
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  test   %r14d,%r14d
  jle    L86
L77:
  mov    0x4(%rbx),%esi
  mov    0x0(%r13),%edx
  add    $0x4,%rbx
  add    $0x4,%r13
  mov    -0x4(%rbx),%edi
  call   <min@plt>
  add    0x0(%rbp,%r15,4),%eax
  add    $0x1,%r15
  mov    %eax,0x0(%r13)
  cmp    %r15d,%r14d
  jge    L77
L86:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  add    $0xc,%rbp
  mov    0x8(%rsp),%rbx
  cmp    %eax,%r12d
  jge    L61
L37:
  movslq %r14d,%r8
  lea    (%r12,%r12,2),%rax
  add    %r8,%rax
  mov    0x10(%rsp,%rax,4),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int minCost(int cost[3][3], int m, int n) {
  int i, j;
  int travellingCost[3][3];
  travellingCost[0][0] = cost[0][0];
  for (i = 1; i <= m; i++)
    travellingCost[i][0] = travellingCost[i - 1][0] + cost[i][0];
  for (j = 1; j <= n; j++)
    travellingCost[0][j] = travellingCost[0][j - 1] + cost[0][j];
  for (i = 1; i <= m; i++)
    for (j = 1; j <= n; j++)
      travellingCost[i][j] = min(travellingCost[i - 1][j - 1], travellingCost[i - 1][j], travellingCost[i][j - 1]) + cost[i][j];
  return (travellingCost[m][n]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isanagram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x98(%rbp)
  je     L47
  cmpq   $0x0,-0xa0(%rbp)
  jne    L101
L47:
  mov    $0x0,%eax
  jmp    L86
L101:
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x88(%rbp)
  mov    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x84(%rbp)
  mov    -0x88(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  je     L79
  mov    $0x0,%eax
  jmp    L86
L79:
  movl   $0x0,-0x8c(%rbp)
  jmp    L51
L62:
  mov    -0x8c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa0(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8c(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x8c(%rbp)
L51:
  mov    -0x8c(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L62
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x80(%rbp)
  movl   $0x0,-0x8c(%rbp)
  jmp    L111
L129:
  mov    -0x8c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x88(%rbp),%edx
  mov    -0x80(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x78(%rbp)
  cmpq   $0x0,-0x78(%rbp)
  jne    L130
  mov    $0x0,%eax
  jmp    L86
L130:
  mov    -0x78(%rbp),%rax
  cmp    -0x80(%rbp),%rax
  jne    L110
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x80(%rbp)
  jmp    L21
L110:
  addq   $0x1,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x78(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L21:
  addl   $0x1,-0x8c(%rbp)
L111:
  mov    -0x8c(%rbp),%eax
  cmp    -0x88(%rbp),%eax
  jl     L129
  mov    $0x1,%eax
L86:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
bool isanagram(char a[], char b[]) {
  int k;
  int alen, blen;
  char *p;
  char *q;
  char c[100];
  if (a == NULL || b == NULL)
    return false;
  alen = strlen(a);
  blen = strlen(b);
  if (alen != blen)
    return false;
  for (k = 0; k < blen; k++)
    c[k] = b[k];
  q = c;
  for (k = 0; k < alen; k++) {
    p = memchr(q, a[k], alen);
    if (p == NULL)
      return false;
    if (p == q)
      q = p + 1;
    else {
      p++;
      *(p - 1) = '\0';
      strcat(q, p);
    }
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isanagram>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L30
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L30
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%r12d
  jne    L39
  test   %eax,%eax
  jle    L120
  lea    -0x1(%rax),%ecx
  mov    $0x0,%eax
L3:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%rsp,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L3
L120:
  test   %r12d,%r12d
  jle    L24
  mov    %rbp,%rbx
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%r13
  mov    %rsp,%rbp
  jmp    L52
L56:
  add    $0x1,%rbp
L118:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L5
L52:
  movsbl (%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L17
  cmp    %rbp,%rax
  je     L56
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L118
L5:
  mov    $0x1,%edx
  jmp    L39
L30:
  mov    $0x0,%edx
L39:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L148
  mov    %edx,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    $0x1,%edx
  jmp    L39
L17:
  mov    $0x0,%edx
  jmp    L39
L148:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isanagram(char a[], char b[]) {
  int k;
  int alen, blen;
  char *p;
  char *q;
  char c[100];
  if (a == NULL || b == NULL)
    return false;
  alen = strlen(a);
  blen = strlen(b);
  if (alen != blen)
    return false;
  for (k = 0; k < blen; k++)
    c[k] = b[k];
  q = c;
  for (k = 0; k < alen; k++) {
    p = memchr(q, a[k], alen);
    if (p == NULL)
      return false;
    if (p == q)
      q = p + 1;
    else {
      p++;
      *(p - 1) = '\0';
      strcat(q, p);
    }
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isanagram>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L44
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L44
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jne    L44
  test   %ebp,%ebp
  jle    L30
  mov    %rsp,%rdi
  movslq %ebp,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L30
  lea    -0x1(%rbp),%eax
  mov    %rsp,%r13
  lea    0x1(%rbx,%rax,1),%r12
  jmp    L32
  nopl   0x0(%rax)
L71:
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <strcat@plt>
  cmp    %rbx,%r12
  je     L30
L32:
  movsbl (%rbx),%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L44
  cmp    %r13,%rax
  jne    L71
  add    $0x1,%rbx
  add    $0x1,%r13
  cmp    %rbx,%r12
  jne    L32
L30:
  mov    $0x1,%eax
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
L113:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L83
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isanagram(char a[], char b[]) {
  int k;
  int alen, blen;
  char *p;
  char *q;
  char c[100];
  if (a == NULL || b == NULL)
    return false;
  alen = strlen(a);
  blen = strlen(b);
  if (alen != blen)
    return false;
  for (k = 0; k < blen; k++)
    c[k] = b[k];
  q = c;
  for (k = 0; k < alen; k++) {
    p = memchr(q, a[k], alen);
    if (p == NULL)
      return false;
    if (p == q)
      q = p + 1;
    else {
      p++;
      *(p - 1) = '\0';
      strcat(q, p);
    }
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isanagram>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L32
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L32
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jne    L32
  test   %ebp,%ebp
  jle    L68
  mov    %rsp,%rdi
  movslq %ebp,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L68
  lea    -0x1(%rbp),%eax
  mov    %rsp,%r13
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L76:
  movsbl (%rbx),%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L32
  cmp    %r13,%rax
  je     L34
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <strcat@plt>
  cmp    %rbx,%r12
  jne    L76
L68:
  mov    $0x1,%eax
  jmp    L83
  xchg   %ax,%ax
L32:
  xor    %eax,%eax
L83:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L89
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L34:
  add    $0x1,%rbx
  add    $0x1,%r13
  cmp    %r12,%rbx
  jne    L76
  jmp    L68
L89:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isanagram(char a[], char b[]) {
  int k;
  int alen, blen;
  char *p;
  char *q;
  char c[100];
  if (a == NULL || b == NULL)
    return false;
  alen = strlen(a);
  blen = strlen(b);
  if (alen != blen)
    return false;
  for (k = 0; k < blen; k++)
    c[k] = b[k];
  q = c;
  for (k = 0; k < alen; k++) {
    p = memchr(q, a[k], alen);
    if (p == NULL)
      return false;
    if (p == q)
      q = p + 1;
    else {
      p++;
      *(p - 1) = '\0';
      strcat(q, p);
    }
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<laplacian_u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x40(%rbp),%xmm0
  mov    -0x28(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rbx
  movsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   *%rdx
  addsd  %xmm0,%xmm0
  movq   %rbx,%xmm3
  subsd  %xmm0,%xmm3
  movsd  %xmm3,-0x48(%rbp)
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x40(%rbp),%xmm0
  mov    -0x28(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   *%rdx
  movsd  -0x48(%rbp),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rbx
  movsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   *%rdx
  addsd  %xmm0,%xmm0
  movq   %rbx,%xmm4
  subsd  %xmm0,%xmm4
  movsd  %xmm4,-0x48(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   *%rdx
  movsd  -0x48(%rbp),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double laplacian_u(double (*u)(double x, double y), double h, double x, double y) {
  double d2udx2 = (u(x + h, y) - 2 * u(x, y) + u(x - h, y)) / (h * h);
  double d2udy2 = (u(x, y + h) - 2 * u(x, y) + u(x, y - h)) / (h * h);
  return d2udy2 + d2udx2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<laplacian_u>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  movsd  %xmm1,(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm6
  movsd  %xmm0,0x10(%rsp)
  addsd  %xmm0,%xmm6
  movapd %xmm6,%xmm0
  movapd %xmm2,%xmm1
  call   *%rdi
  movq   %xmm0,%rbp
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  call   *%rbx
  addsd  %xmm0,%xmm0
  movq   %rbp,%xmm2
  subsd  %xmm0,%xmm2
  movsd  %xmm2,0x18(%rsp)
  movsd  (%rsp),%xmm7
  subsd  0x10(%rsp),%xmm7
  movapd %xmm7,%xmm0
  movsd  0x8(%rsp),%xmm1
  call   *%rbx
  movsd  0x10(%rsp),%xmm3
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  addsd  0x18(%rsp),%xmm0
  movapd %xmm0,%xmm6
  movsd  %xmm4,0x18(%rsp)
  divsd  %xmm4,%xmm6
  movsd  %xmm6,0x28(%rsp)
  movapd %xmm3,%xmm5
  addsd  0x8(%rsp),%xmm5
  movapd %xmm5,%xmm1
  movsd  (%rsp),%xmm0
  call   *%rbx
  movq   %xmm0,%rbp
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  call   *%rbx
  addsd  %xmm0,%xmm0
  movq   %rbp,%xmm7
  subsd  %xmm0,%xmm7
  movsd  %xmm7,0x20(%rsp)
  movsd  0x8(%rsp),%xmm1
  subsd  0x10(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  call   *%rbx
  addsd  0x20(%rsp),%xmm0
  divsd  0x18(%rsp),%xmm0
  addsd  0x28(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double laplacian_u(double (*u)(double x, double y), double h, double x, double y) {
  double d2udx2 = (u(x + h, y) - 2 * u(x, y) + u(x - h, y)) / (h * h);
  double d2udy2 = (u(x, y + h) - 2 * u(x, y) + u(x, y - h)) / (h * h);
  return d2udy2 + d2udx2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<laplacian_u>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mov    %rdi,%rbx
  addsd  %xmm3,%xmm0
  sub    $0x30,%rsp
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  movapd %xmm2,%xmm1
  call   *%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   *%rbx
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  addsd  %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm2
  movsd  (%rsp),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   *%rbx
  movsd  0x18(%rsp),%xmm3
  addsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movapd %xmm3,%xmm4
  movsd  %xmm3,0x20(%rsp)
  mulsd  %xmm3,%xmm4
  movapd %xmm0,%xmm5
  addsd  %xmm3,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm4,%xmm5
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm5,0x18(%rsp)
  call   *%rbx
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   *%rbx
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  movsd  0x20(%rsp),%xmm3
  subsd  %xmm3,%xmm1
  subsd  %xmm0,%xmm2
  movsd  (%rsp),%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   *%rbx
  addsd  0x10(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm4
  divsd  %xmm4,%xmm0
  addsd  0x18(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double laplacian_u(double (*u)(double x, double y), double h, double x, double y) {
  double d2udx2 = (u(x + h, y) - 2 * u(x, y) + u(x - h, y)) / (h * h);
  double d2udy2 = (u(x, y + h) - 2 * u(x, y) + u(x, y - h)) / (h * h);
  return d2udy2 + d2udx2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<laplacian_u>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mov    %rdi,%rbx
  addsd  %xmm3,%xmm0
  sub    $0x30,%rsp
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  movapd %xmm2,%xmm1
  call   *%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   *%rbx
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  addsd  %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm2
  movsd  (%rsp),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   *%rbx
  movsd  0x18(%rsp),%xmm3
  addsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movapd %xmm3,%xmm4
  movsd  %xmm3,0x20(%rsp)
  mulsd  %xmm3,%xmm4
  movapd %xmm0,%xmm5
  addsd  %xmm3,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm4,%xmm5
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm5,0x18(%rsp)
  call   *%rbx
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   *%rbx
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  movsd  0x20(%rsp),%xmm3
  subsd  %xmm3,%xmm1
  subsd  %xmm0,%xmm2
  movsd  (%rsp),%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   *%rbx
  addsd  0x10(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm4
  divsd  %xmm4,%xmm0
  addsd  0x18(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double laplacian_u(double (*u)(double x, double y), double h, double x, double y) {
  double d2udx2 = (u(x + h, y) - 2 * u(x, y) + u(x - h, y)) / (h * h);
  double d2udy2 = (u(x, y + h) - 2 * u(x, y) + u(x, y - h)) / (h * h);
  return d2udy2 + d2udx2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<amsp_legendrePoly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L22
  movsd  D43(%rip),%xmm0
  jmp    L48
L22:
  cmpl   $0x1,-0x34(%rbp)
  jne    L6
  movsd  -0x40(%rbp),%xmm0
  jmp    L48
L6:
  movsd  D43(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x2,-0x24(%rbp)
  jmp    L25
L46:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  movsd  D43(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  D43(%rip),%xmm1
  subsd  %xmm1,%xmm0
  divsd  -0x8(%rbp),%xmm0
  mulsd  -0x40(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  movsd  D43(%rip),%xmm2
  subsd  %xmm2,%xmm1
  divsd  -0x8(%rbp),%xmm1
  mulsd  -0x10(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L25:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x24(%rbp)
  jle    L46
  movsd  -0x20(%rbp),%xmm0
L48:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D43
type: f64

tool: D43: 1

assistant: ```c
double amsp_legendrePoly(int n, double v) {
  double p = 0, pn1, pn2, k;
  int i;
  if (n == 0)
    return 1.;
  if (n == 1)
    return v;
  pn1 = 1;
  pn2 = 0;
  for (i = 2; i <= n + 1; ++i) {
    k = (double)(i - 1.);
    p = ((2 * k - 1) / k) * v * pn1 - ((k - 1) / k) * pn2;
    pn2 = pn1;
    pn1 = p;
  }
  return p;
}
```