ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7f,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7f,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffff80,%esi
  lea    D64(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffff80,%esi
  lea    D62(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
data_type: string
name: extract_symbolic_data
arguments: tag: D60
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D59
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D64
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D62
data_type: string

tool: D20: 
Programm zum Berechnen der Addition von char 127 und 1.

tool: D60: 
Gebe Inhalt von 'zahl' aus...

tool: D18: 
Inhalt von 'zahl' als char: %c


tool: D17: 
Inhalt von 'zahl' als int: %i


tool: D59: 
Addiere 1 dazu...

tool: D14: 
Die neue Zahl als Typ char

tool: D64: 
Neu Zahl: %c


tool: D2: 
Die neue Zahl als Typ int

tool: D62: 
Neu Zahl: %i


assistant: ```c
int main(void) {
  printf("\nProgramm zum Berechnen der Addition von char 127 und 1.\n");
  char zahl = 0;
  zahl = 127;
  printf("\nGebe Inhalt von 'zahl' aus...");
  printf("\nInhalt von 'zahl' als char: %c\n", zahl);
  printf("\nInhalt von 'zahl' als int: %i\n", zahl);
  printf("\nAddiere 1 dazu...\n");
  zahl = zahl + 1;
  printf("\nDie neue Zahl als Typ char");
  printf("\nNeu Zahl: %c\n", zahl);
  printf("\nDie neue Zahl als Typ int");
  printf("\nNeu Zahl: %i\n", zahl);
}
```
user: What is the c source code of the assembly code below:

```asm
<load_dh_param>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_new_file@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <PEM_read_bio_DHparams@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L6
L17:
  nop
L6:
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
L7:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: r

assistant: ```c
DH *load_dh_param(char *dhfile) {
  DH *ret = NULL;
  BIO *bio;
  if ((bio = BIO_new_file(dhfile, "r")) == NULL)
    goto err;
  ret = PEM_read_bio_DHparams(bio, NULL, NULL, NULL);
err:
  if (bio != NULL)
    BIO_free(bio);
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<load_dh_param>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <BIO_new_file@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <PEM_read_bio_DHparams@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <BIO_free@plt>
L11:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rax,%rbp
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: r

assistant: ```c
DH *load_dh_param(char *dhfile) {
  DH *ret = NULL;
  BIO *bio;
  if ((bio = BIO_new_file(dhfile, "r")) == NULL)
    goto err;
  ret = PEM_read_bio_DHparams(bio, NULL, NULL, NULL);
err:
  if (bio != NULL)
    BIO_free(bio);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<load_dh_param>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <BIO_new_file@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <PEM_read_bio_DHparams@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <BIO_free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: r

assistant: ```c
DH *load_dh_param(char *dhfile) {
  DH *ret = NULL;
  BIO *bio;
  if ((bio = BIO_new_file(dhfile, "r")) == NULL)
    goto err;
  ret = PEM_read_bio_DHparams(bio, NULL, NULL, NULL);
err:
  if (bio != NULL)
    BIO_free(bio);
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<load_dh_param>:
  endbr64
  push   %r12
  lea    D9(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <BIO_new_file@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <PEM_read_bio_DHparams@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <BIO_free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: r

assistant: ```c
DH *load_dh_param(char *dhfile) {
  DH *ret = NULL;
  BIO *bio;
  if ((bio = BIO_new_file(dhfile, "r")) == NULL)
    goto err;
  ret = PEM_read_bio_DHparams(bio, NULL, NULL, NULL);
err:
  if (bio != NULL)
    BIO_free(bio);
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D53
type_guessed: string
name: parse_data
arguments: data_tag: D46
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D40
type_guessed: string

tool: D6: 
 Inserire A

tool: D53: %d

tool: D46: 
 Inserire B

tool: D3: 
 %d

tool: D40: PAUSE

assistant: ```c
main() {
  int A, B, C;
  printf("\n Inserire A");
  scanf("%d", &A);
  printf("\n Inserire B");
  scanf("%d", &B);
  C = A;
  A = B;
  B = C;
  printf("\n %d", A);
  printf("\n %d", B);
  system("PAUSE");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  mov    %esi,(%rsp)
  mov    %eax,0x4(%rsp)
  lea    D31(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D37
datatype: string
name: retrieve_data
arguments: label: D31
datatype: string
name: retrieve_data
arguments: label: D20
datatype: string

tool: D19: 
 Inserire A

tool: D1: %d

tool: D37: 
 Inserire B

tool: D31: 
 %d

tool: D20: PAUSE

assistant: ```c
main() {
  int A, B, C;
  printf("\n Inserire A");
  scanf("%d", &A);
  printf("\n Inserire B");
  scanf("%d", &B);
  C = A;
  A = B;
  B = C;
  printf("\n %d", A);
  printf("\n %d", B);
  system("PAUSE");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D29(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rbp
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D39
type: string
name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D25
type: string
name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D10
type: string

tool: D39: 
 Inserire A

tool: D29: %d

tool: D25: 
 Inserire B

tool: D11: 
 %d

tool: D10: PAUSE

assistant: ```c
main() {
  int A, B, C;
  printf("\n Inserire A");
  scanf("%d", &A);
  printf("\n Inserire B");
  scanf("%d", &B);
  C = A;
  A = B;
  B = C;
  printf("\n %d", A);
  printf("\n %d", B);
  system("PAUSE");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D43(%rip),%rbp
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D44
datatype: string
name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D46
datatype: string
name: read_data
arguments: tag: D43
datatype: string
name: read_data
arguments: tag: D45
datatype: string

tool: D44: 
 Inserire A

tool: D10: %d

tool: D46: 
 Inserire B

tool: D43: 
 %d

tool: D45: PAUSE

assistant: ```c
main() {
  int A, B, C;
  printf("\n Inserire A");
  scanf("%d", &A);
  printf("\n Inserire B");
  scanf("%d", &B);
  C = A;
  A = B;
  B = C;
  printf("\n %d", A);
  printf("\n %d", B);
  system("PAUSE");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  andl   $0xfffffffe,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swab(const void *src, void *dest, ssize_t nbytes) {
  ssize_t i;
  const char *s = src;
  char *d = dest;
  nbytes &= ~1;
  for (i = 0; i < nbytes; i += 2) {
    d[i] = s[i + 1];
    d[i + 1] = s[i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swab>:
  endbr64
  and    $0xfffffffe,%edx
  jle    L7
  mov    $0x0,%eax
L16:
  movzbl 0x1(%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,0x1(%rsi,%rax,1)
  add    $0x2,%rax
  cmp    %eax,%edx
  jg     L16
L7:
  ret
```

assistant: ```c
void swab(const void *src, void *dest, ssize_t nbytes) {
  ssize_t i;
  const char *s = src;
  char *d = dest;
  nbytes &= ~1;
  for (i = 0; i < nbytes; i += 2) {
    d[i] = s[i + 1];
    d[i + 1] = s[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swab>:
  endbr64
  and    $0xfffffffe,%edx
  jle    L11
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl 0x1(%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,0x1(%rsi,%rax,1)
  add    $0x2,%rax
  cmp    %eax,%edx
  jg     L12
L11:
  ret
```

assistant: ```c
void swab(const void *src, void *dest, ssize_t nbytes) {
  ssize_t i;
  const char *s = src;
  char *d = dest;
  nbytes &= ~1;
  for (i = 0; i < nbytes; i += 2) {
    d[i] = s[i + 1];
    d[i + 1] = s[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat4_perspective>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  movss  %xmm1,0x4(%rsp)
  movss  %xmm2,0x8(%rsp)
  movss  %xmm3,0xc(%rsp)
  mulss  D2(%rip),%xmm0
  call   <tanf@plt>
  movaps %xmm0,%xmm1
  movss  D13(%rip),%xmm0
  movaps %xmm0,%xmm6
  divss  %xmm1,%xmm6
  movaps %xmm0,%xmm7
  divss  0x4(%rsp),%xmm7
  movaps %xmm7,%xmm1
  mulss  %xmm6,%xmm1
  movss  %xmm1,(%rbx)
  movl   $0x0,0x4(%rbx)
  movl   $0x0,0x8(%rbx)
  movl   $0x0,0xc(%rbx)
  movl   $0x0,0x10(%rbx)
  divss  %xmm6,%xmm0
  movss  %xmm0,0x14(%rbx)
  movl   $0x0,0x18(%rbx)
  movl   $0x0,0x1c(%rbx)
  movl   $0x0,0x20(%rbx)
  movl   $0x0,0x24(%rbx)
  movss  0x8(%rsp),%xmm5
  movaps %xmm5,%xmm1
  movss  0xc(%rsp),%xmm4
  subss  %xmm4,%xmm1
  movaps %xmm4,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x28(%rbx)
  movl   $0xbf800000,0x2c(%rbx)
  movl   $0x0,0x30(%rbx)
  movl   $0x0,0x34(%rbx)
  movaps %xmm5,%xmm1
  mulss  %xmm4,%xmm1
  xorps  D5(%rip),%xmm1
  subss  %xmm5,%xmm4
  divss  %xmm4,%xmm1
  movss  %xmm1,0x38(%rbx)
  movl   $0x0,0x3c(%rbx)
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D13
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D5
type_guessed: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

tool: {"D13": [0x00,0x00,0x80,0x3f]}

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float *mat4_perspective(float *result, float fov_y, float aspect, float n, float f) {
  float tan_half_fov_y = 1.0f / tanf(fov_y * 0.5f);
  result[0] = 1.0f / aspect * tan_half_fov_y;
  result[1] = 0.0f;
  result[2] = 0.0f;
  result[3] = 0.0f;
  result[4] = 0.0f;
  result[5] = 1.0f / tan_half_fov_y;
  result[6] = 0.0f;
  result[7] = 0.0f;
  result[8] = 0.0f;
  result[9] = 0.0f;
  result[10] = f / (n - f);
  result[11] = -1.0f;
  result[12] = 0.0f;
  result[13] = 0.0f;
  result[14] = -(f * n) / (f - n);
  result[15] = 0.0f;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mat4_perspective>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mulss  D12(%rip),%xmm0
  movss  %xmm1,0x4(%rsp)
  movss  %xmm2,0xc(%rsp)
  movss  %xmm3,0x8(%rsp)
  call   <tanf@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x8(%rsp),%xmm3
  mov    $0xbf800000,%eax
  movaps %xmm0,%xmm1
  mov    %rax,0x2c(%r12)
  movss  D14(%rip),%xmm0
  mov    %r12,%rax
  movq   $0x0,0x4(%r12)
  movq   $0x0,0xc(%r12)
  movaps %xmm0,%xmm4
  movaps %xmm0,%xmm5
  divss  0x4(%rsp),%xmm5
  movq   $0x0,0x18(%r12)
  divss  %xmm1,%xmm4
  movaps %xmm5,%xmm1
  movq   $0x0,0x20(%r12)
  movl   $0x0,0x34(%r12)
  movl   $0x0,0x3c(%r12)
  divss  %xmm4,%xmm0
  mulss  %xmm4,%xmm1
  movss  %xmm1,(%r12)
  movaps %xmm2,%xmm1
  subss  %xmm3,%xmm1
  movss  %xmm0,0x14(%r12)
  movaps %xmm3,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x28(%r12)
  movaps %xmm2,%xmm0
  mulss  %xmm3,%xmm0
  subss  %xmm2,%xmm3
  xorps  D22(%rip),%xmm0
  divss  %xmm3,%xmm0
  movss  %xmm0,0x38(%r12)
  add    $0x10,%rsp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D14
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D22
datatype: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x3f]}

tool: {"D14": [0x00,0x00,0x80,0x3f]}

tool: {"D22": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float *mat4_perspective(float *result, float fov_y, float aspect, float n, float f) {
  float tan_half_fov_y = 1.0f / tanf(fov_y * 0.5f);
  result[0] = 1.0f / aspect * tan_half_fov_y;
  result[1] = 0.0f;
  result[2] = 0.0f;
  result[3] = 0.0f;
  result[4] = 0.0f;
  result[5] = 1.0f / tan_half_fov_y;
  result[6] = 0.0f;
  result[7] = 0.0f;
  result[8] = 0.0f;
  result[9] = 0.0f;
  result[10] = f / (n - f);
  result[11] = -1.0f;
  result[12] = 0.0f;
  result[13] = 0.0f;
  result[14] = -(f * n) / (f - n);
  result[15] = 0.0f;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat4_perspective>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mulss  D19(%rip),%xmm0
  movss  %xmm1,0x4(%rsp)
  movss  %xmm2,0xc(%rsp)
  movss  %xmm3,0x8(%rsp)
  call   <tanf@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x8(%rsp),%xmm3
  mov    $0xbf800000,%eax
  movaps %xmm0,%xmm1
  mov    %rax,0x2c(%r12)
  movss  D14(%rip),%xmm0
  mov    %r12,%rax
  movq   $0x0,0x4(%r12)
  movq   $0x0,0xc(%r12)
  movaps %xmm0,%xmm4
  movaps %xmm0,%xmm5
  divss  0x4(%rsp),%xmm5
  movq   $0x0,0x18(%r12)
  divss  %xmm1,%xmm4
  movaps %xmm5,%xmm1
  movq   $0x0,0x20(%r12)
  movl   $0x0,0x34(%r12)
  movl   $0x0,0x3c(%r12)
  divss  %xmm4,%xmm0
  mulss  %xmm4,%xmm1
  movss  %xmm1,(%r12)
  movaps %xmm2,%xmm1
  subss  %xmm3,%xmm1
  movss  %xmm0,0x14(%r12)
  movaps %xmm3,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x28(%r12)
  movaps %xmm2,%xmm0
  mulss  %xmm3,%xmm0
  subss  %xmm2,%xmm3
  xorps  D8(%rip),%xmm0
  divss  %xmm3,%xmm0
  movss  %xmm0,0x38(%r12)
  add    $0x10,%rsp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D14
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D8
type_guessed: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x3f]}

tool: {"D14": [0x00,0x00,0x80,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float *mat4_perspective(float *result, float fov_y, float aspect, float n, float f) {
  float tan_half_fov_y = 1.0f / tanf(fov_y * 0.5f);
  result[0] = 1.0f / aspect * tan_half_fov_y;
  result[1] = 0.0f;
  result[2] = 0.0f;
  result[3] = 0.0f;
  result[4] = 0.0f;
  result[5] = 1.0f / tan_half_fov_y;
  result[6] = 0.0f;
  result[7] = 0.0f;
  result[8] = 0.0f;
  result[9] = 0.0f;
  result[10] = f / (n - f);
  result[11] = -1.0f;
  result[12] = 0.0f;
  result[13] = 0.0f;
  result[14] = -(f * n) / (f - n);
  result[15] = 0.0f;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strtoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L7
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L7
L20:
  addq   $0x1,-0x10(%rbp)
L7:
  cmpq   $0x0,-0x10(%rbp)
  je     L118
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L118
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L20
L118:
  cmpq   $0x0,-0x10(%rbp)
  je     L26
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
L26:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  jmp    L112
L60:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L83:
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L83
L64:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  jmp    L120
L22:
  movq   $0x0,-0x10(%rbp)
L120:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
L112:
  leave
  ret
```

assistant: ```c
char *strtoken(char **save, char *str, char *fs) {
  char *pos = *save;
  char *tmp;
  if (str)
    pos = str;
  while (pos && *pos && strchr(fs, *pos) != NULL)
    ++pos;
  if (!pos || !*pos)
    return (pos = *save = NULL);
  tmp = pos;
  while (*pos && strchr(fs, *pos) == NULL)
    ++pos;
  if (*pos)
    *pos++ = '\0';
  else
    pos = NULL;
  *save = pos;
  return tmp;
}
```