ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ex_int_iisort>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq (%rsi),%rax
  mov    (%rdi,%rax,4),%ecx
  cmp    $0x1,%edx
  jle    L47
  mov    %rdi,%rbx
  mov    %edx,%r12d
  movslq %edx,%rsi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L7:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    (%rbx,%rdx,4),%edx
  cmp    %ecx,%edx
  jge    L8
  mov    %edx,%ecx
  mov    %eax,%r8d
L8:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L7
  mov    %r8d,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <ex_swap@plt>
  mov    $0x4,%edi
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L10:
  movslq 0x0(%rbp,%rdi,1),%rdx
  movslq -0x4(%rbp,%rdi,1),%rcx
  lea    0x0(%rbp,%rdi,1),%rax
  lea    (%rbx,%rdx,4),%rsi
  mov    %rdx,%r9
  mov    %rcx,%rdx
  mov    (%rbx,%rcx,4),%ecx
  cmp    %ecx,(%rsi)
  jge    L3
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %edx,0x0(%rbp,%rax,1)
  sub    $0x4,%rax
  movslq -0x4(%rbp,%rax,1),%rcx
  mov    %rcx,%rdx
  mov    (%rbx,%rcx,4),%ecx
  cmp    %ecx,(%rsi)
  jl     L29
  add    %rbp,%rax
L3:
  add    $0x1,%r8d
  mov    %r9d,(%rax)
  add    $0x4,%rdi
  cmp    %r8d,%r12d
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  pop    %rbx
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  xor    %esi,%esi
  pop    %r12
  jmp    1050 <ex_swap@plt>
```

assistant: ```c
void ex_int_iisort(int v[], int iv[], int N) {
  int i, j;
  int ndx = 0;
  int small;
  int tmp;
  small = v[iv[0]];
  for (i = 1; i < N; i++) {
    if (v[iv[i]] < small) {
      small = v[iv[i]];
      ndx = i;
    }
  }
  ex_swap(iv, 0, ndx);
  for (i = 1; i < N; i++) {
    tmp = iv[i];
    for (j = i; v[tmp] < v[iv[j - 1]]; j--) {
      iv[j] = iv[j - 1];
    }
    iv[j] = tmp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ex_int_iisort>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq (%rsi),%rax
  mov    (%rdi,%rax,4),%ecx
  cmp    $0x1,%edx
  jle    L10
  mov    %rdi,%rbx
  mov    %edx,%r12d
  movslq %edx,%rsi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L27:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    (%rbx,%rdx,4),%edx
  cmp    %ecx,%edx
  jge    L18
  mov    %edx,%ecx
  mov    %eax,%r8d
L18:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L27
  mov    %r8d,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <ex_swap@plt>
  mov    $0x4,%edi
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L54:
  movslq 0x0(%rbp,%rdi,1),%rdx
  movslq -0x4(%rbp,%rdi,1),%rcx
  lea    0x0(%rbp,%rdi,1),%rax
  lea    (%rbx,%rdx,4),%rsi
  mov    %rdx,%r9
  mov    %rcx,%rdx
  mov    (%rbx,%rcx,4),%ecx
  cmp    %ecx,(%rsi)
  jge    L20
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %edx,0x0(%rbp,%rax,1)
  sub    $0x4,%rax
  movslq -0x4(%rbp,%rax,1),%rcx
  mov    %rcx,%rdx
  mov    (%rbx,%rcx,4),%ecx
  cmp    %ecx,(%rsi)
  jl     L19
  add    %rbp,%rax
L20:
  add    $0x1,%r8d
  mov    %r9d,(%rax)
  add    $0x4,%rdi
  cmp    %r8d,%r12d
  jne    L54
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  pop    %rbx
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  xor    %esi,%esi
  pop    %r12
  jmp    1050 <ex_swap@plt>
```

assistant: ```c
void ex_int_iisort(int v[], int iv[], int N) {
  int i, j;
  int ndx = 0;
  int small;
  int tmp;
  small = v[iv[0]];
  for (i = 1; i < N; i++) {
    if (v[iv[i]] < small) {
      small = v[iv[i]];
      ndx = i;
    }
  }
  ex_swap(iv, 0, ndx);
  for (i = 1; i < N; i++) {
    tmp = iv[i];
    for (j = i; v[tmp] < v[iv[j - 1]]; j--) {
      iv[j] = iv[j - 1];
    }
    iv[j] = tmp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rotl16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %ax,-0x4(%rbp)
  andl   $0xf,-0x8(%rbp)
  movzwl -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  movzwl -0x4(%rbp),%edx
  mov    $0x10,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short rotl16(unsigned short val, int count) {
  count &= 15;
  return (val << count) | (val >> (16 - count));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotl16>:
  endbr64
  mov    %esi,%ecx
  and    $0xf,%ecx
  mov    %edi,%eax
  rol    %cl,%ax
  ret
```

assistant: ```c
unsigned short rotl16(unsigned short val, int count) {
  count &= 15;
  return (val << count) | (val >> (16 - count));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rotl16>:
  endbr64
  mov    %esi,%ecx
  mov    %edi,%eax
  and    $0xf,%ecx
  rol    %cl,%ax
  ret
```

assistant: ```c
unsigned short rotl16(unsigned short val, int count) {
  count &= 15;
  return (val << count) | (val >> (16 - count));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotl16>:
  endbr64
  mov    %esi,%ecx
  mov    %edi,%eax
  and    $0xf,%ecx
  rol    %cl,%ax
  ret
```

assistant: ```c
unsigned short rotl16(unsigned short val, int count) {
  count &= 15;
  return (val << count) | (val >> (16 - count));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<send_bye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <uart_send_string@plt>
  mov    $0x0,%eax
  call   <uart_send_crlf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: BYE

assistant: ```c
void send_bye(void) {
  uart_send_string("BYE");
  uart_send_crlf();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_bye>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <uart_send_string@plt>
  mov    $0x0,%eax
  call   <uart_send_crlf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: BYE

assistant: ```c
void send_bye(void) {
  uart_send_string("BYE");
  uart_send_crlf();
}
```
user: What is the c source code of the assembly code below:

```asm
<send_bye>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <uart_send_string@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <uart_send_crlf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: BYE

assistant: ```c
void send_bye(void) {
  uart_send_string("BYE");
  uart_send_crlf();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_bye>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <uart_send_string@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <uart_send_crlf@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: BYE

assistant: ```c
void send_bye(void) {
  uart_send_string("BYE");
  uart_send_crlf();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3e,%edi
  call   <ft_find_next_prime@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  ft_find_next_prime(62);
  ft_putchar('\n');
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e,%edi
  call   <ft_find_next_prime@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ft_find_next_prime(62);
  ft_putchar('\n');
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e,%edi
  call   <ft_find_next_prime@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ft_find_next_prime(62);
  ft_putchar('\n');
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e,%edi
  call   <ft_find_next_prime@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ft_find_next_prime(62);
  ft_putchar('\n');
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L4
  mov    $0x0,%eax
  jmp    L4
L4:
  pop    %rbp
  ret
```

assistant: ```c
int checksum(int arr[], int size, int sum, int j) {
  if (j > size)
    return 0;
  else {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksum>:
  endbr64
  cmp    %esi,%ecx
  jg     L4
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int checksum(int arr[], int size, int sum, int j) {
  if (j > size)
    return 0;
  else {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checksum>:
  endbr64
  cmp    %esi,%ecx
  jg     L4
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int checksum(int arr[], int size, int sum, int j) {
  if (j > size)
    return 0;
  else {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checksum>:
  endbr64
  cmp    %esi,%ecx
  jg     L1
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int checksum(int arr[], int size, int sum, int j) {
  if (j > size)
    return 0;
  else {
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<core_iterami_path>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%r13
  cmpb   $0x0,(%r12)
  je     L62
  mov    $0x0,%ebp
L8:
  add    $0x1,%rbp
  cmpb   $0x0,(%r12,%rbp,1)
  jne    L8
L49:
  cmpb   $0x0,0x0(%r13)
  je     L52
  mov    $0x0,%ebx
L91:
  mov    %rbx,%r15
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%r13,%rbx,1)
  jne    L91
  lea    (%rbx,%rbp,1),%r14
  lea    0x11(%r14),%rdi
  call   <malloc@plt>
  movb   $0x2f,(%rax)
  movb   $0x68,0x1(%rax)
  movb   $0x6f,0x2(%rax)
  movb   $0x6d,0x3(%rax)
  movb   $0x65,0x4(%rax)
  movb   $0x2f,0x5(%rax)
  test   %rbx,%rbx
  je     L22
  mov    $0x0,%ebx
L10:
  movzbl 0x0(%r13,%rbx,1),%edx
  mov    %dl,0x6(%rax,%rbx,1)
  mov    %rbx,%rdx
  add    $0x1,%rbx
  cmp    %rdx,%r15
  jne    L10
L22:
  movb   $0x2f,0x6(%rax,%rbx,1)
  movb   $0x2e,0x7(%rax,%rbx,1)
  movb   $0x69,0x8(%rax,%rbx,1)
  movb   $0x74,0x9(%rax,%rbx,1)
  movb   $0x65,0xa(%rax,%rbx,1)
  movb   $0x72,0xb(%rax,%rbx,1)
  movb   $0x61,0xc(%rax,%rbx,1)
  movb   $0x6d,0xd(%rax,%rbx,1)
  movb   $0x69,0xe(%rax,%rbx,1)
  movb   $0x2f,0xf(%rax,%rbx,1)
  test   %rbp,%rbp
  je     L26
  mov    $0x0,%edx
  add    %rax,%rbx
L60:
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,0x10(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbp
  jne    L60
L26:
  movb   $0x0,0x10(%rax,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    $0x0,%ebp
  jmp    L49
L52:
  lea    0x11(%rbp),%rdi
  call   <malloc@plt>
  movb   $0x2f,(%rax)
  movb   $0x68,0x1(%rax)
  movb   $0x6f,0x2(%rax)
  movb   $0x6d,0x3(%rax)
  movb   $0x65,0x4(%rax)
  movb   $0x2f,0x5(%rax)
  mov    %rbp,%r14
  mov    $0x0,%ebx
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: USER

assistant: ```c
char *core_iterami_path(const char *filename) {
  const char *name = getenv("USER");
  size_t length_file = 0;
  size_t length_name = 0;
  while (filename[length_file] != '\0') {
    length_file++;
  }
  while (name[length_name] != '\0') {
    length_name++;
  }
  char *path = malloc(length_name + length_file + 17);
  path[0] = '/';
  path[1] = 'h';
  path[2] = 'o';
  path[3] = 'm';
  path[4] = 'e';
  path[5] = '/';
  int i = 0;
  while (i < length_name) {
    path[i + 6] = name[i];
    i++;
  }
  path[length_name + 6] = '/';
  path[length_name + 7] = '.';
  path[length_name + 8] = 'i';
  path[length_name + 9] = 't';
  path[length_name + 10] = 'e';
  path[length_name + 11] = 'r';
  path[length_name + 12] = 'a';
  path[length_name + 13] = 'm';
  path[length_name + 14] = 'i';
  path[length_name + 15] = '/';
  i = 0;
  while (i < length_file) {
    path[i + length_name + 16] = filename[i];
    i++;
  }
  path[length_name + length_file + 16] = '\0';
  return path;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getline_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L39:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L59:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  je     L16
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L16
  cmpb   $0xa,-0x5(%rbp)
  jne    L39
L16:
  cmpb   $0xa,-0x5(%rbp)
  jne    L63
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  jmp    L38
L63:
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x4(%rbp),%eax
L38:
  leave
  ret
```

assistant: ```c
int getline_my(char *line) {
  char c = 0;
  int i = 0;
  while ((c = getchar()) != '\0' && c != EOF && c != '\n') {
    *line++ = c;
    i++;
  }
  if (c == '\n') {
    *line = '\0';
    return i;
  } else {
    if (c == EOF)
      *line = '\0';
    return i;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getline_my>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L64:
  mov    $0x0,%eax
  call   <getchar@plt>
  test   %al,%al
  je     L42
  mov    D15(%rip),%rdx
  cmp    %al,(%rdx)
  je     L58
  cmp    $0xa,%al
  je     L58
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  add    $0x1,%ebp
  jmp    L64
L58:
  cmp    $0xa,%al
  jne    L42
  movb   $0x0,(%rbx)
  jmp    L23
L42:
  mov    D15(%rip),%rdx
  cmp    %al,(%rdx)
  je     L70
L23:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L70:
  movb   $0x0,(%rbx)
  jmp    L23
```

assistant: ```c
int getline_my(char *line) {
  char c = 0;
  int i = 0;
  while ((c = getchar()) != '\0' && c != EOF && c != '\n') {
    *line++ = c;
    i++;
  }
  if (c == '\n') {
    *line = '\0';
    return i;
  } else {
    if (c == EOF)
      *line = '\0';
    return i;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getline_my>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    %al,0x0(%rbp)
  je     L6
  cmp    $0xa,%al
  je     L6
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%r12d
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L16
  cmpb   $0x0,0x0(%rbp)
  jne    L21
  nopl   0x0(%rax)
L6:
  movb   $0x0,(%rbx)
L21:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getline_my(char *line) {
  char c = 0;
  int i = 0;
  while ((c = getchar()) != '\0' && c != EOF && c != '\n') {
    *line++ = c;
    i++;
  }
  if (c == '\n') {
    *line = '\0';
    return i;
  } else {
    if (c == EOF)
      *line = '\0';
    return i;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<getline_my>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    %al,0x0(%rbp)
  je     L46
  cmp    $0xa,%al
  je     L46
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%r12d
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L27
  cmpb   $0x0,0x0(%rbp)
  jne    L24
  nopl   0x0(%rax)
L46:
  movb   $0x0,(%rbx)
L24:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getline_my(char *line) {
  char c = 0;
  int i = 0;
  while ((c = getchar()) != '\0' && c != EOF && c != '\n') {
    *line++ = c;
    i++;
  }
  if (c == '\n') {
    *line = '\0';
    return i;
  } else {
    if (c == EOF)
      *line = '\0';
    return i;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fsfr_fgetxattr_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x4,%ecx
  mov    %eax,%edi
  call   <fgetxattr@plt>
  test   %rax,%rax
  jle    L2
  mov    -0xc(%rbp),%eax
  jmp    L28
L2:
  mov    $0xffffffff,%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int fsfr_fgetxattr_int(int fd, const char *name) {
  int64_t rtn = -1;
  if (fgetxattr(fd, name, &rtn, sizeof(rtn)) > 0)
    return (int)rtn;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fsfr_fgetxattr_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  call   <fgetxattr@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovg  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fsfr_fgetxattr_int(int fd, const char *name) {
  int64_t rtn = -1;
  if (fgetxattr(fd, name, &rtn, sizeof(rtn)) > 0)
    return (int)rtn;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fsfr_fgetxattr_int>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <fgetxattr@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovg  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fsfr_fgetxattr_int(int fd, const char *name) {
  int64_t rtn = -1;
  if (fgetxattr(fd, name, &rtn, sizeof(rtn)) > 0)
    return (int)rtn;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fsfr_fgetxattr_int>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <fgetxattr@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovg  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fsfr_fgetxattr_int(int fd, const char *name) {
  int64_t rtn = -1;
  if (fgetxattr(fd, name, &rtn, sizeof(rtn)) > 0)
    return (int)rtn;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdi
  mov    %eax,%ecx
  sar    %cl,%rdi
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string

tool: D4: 0x%llx op %d:


tool: D9:   ashr: 0x%llx
  lshr: 0x%llx
  shl: 0x%llx


assistant: ```c
void Test(long long Val, int Amt) {
  printf("0x%llx op %d:\n", Val, Amt);
  printf("  ashr: 0x%llx\n  lshr: 0x%llx\n  shl: 0x%llx\n", Val >> Amt, (unsigned long long)Val >> Amt, Val << Amt);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  movslq %esi,%rdx
  mov    %rdi,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  mov    %ebp,%ecx
  shl    %cl,%rax
  mov    %rbx,%rdx
  shr    %cl,%rdx
  sar    %cl,%rbx
  mov    %rbx,%rsi
  mov    %rax,%rcx
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D15: 0x%llx op %d:


tool: D11:   ashr: 0x%llx
  lshr: 0x%llx
  shl: 0x%llx


assistant: ```c
void Test(long long Val, int Amt) {
  printf("0x%llx op %d:\n", Val, Amt);
  printf("  ashr: 0x%llx\n  lshr: 0x%llx\n  shl: 0x%llx\n", Val >> Amt, (unsigned long long)Val >> Amt, Val << Amt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Test>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  xor    %eax,%eax
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdx,%rbp
  mov    %rdi,%rbx
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebp,%ecx
  mov    %rbx,%r8
  mov    %rbx,%rdx
  add    $0x8,%rsp
  sar    %cl,%rbx
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  shl    %cl,%r8
  shr    %cl,%rdx
  mov    %rbx,%rsi
  pop    %rbx
  mov    %r8,%rcx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string

tool: D13: 0x%llx op %d:


tool: D15:   ashr: 0x%llx
  lshr: 0x%llx
  shl: 0x%llx


assistant: ```c
void Test(long long Val, int Amt) {
  printf("0x%llx op %d:\n", Val, Amt);
  printf("  ashr: 0x%llx\n  lshr: 0x%llx\n  shl: 0x%llx\n", Val >> Amt, (unsigned long long)Val >> Amt, Val << Amt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Test>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  xor    %eax,%eax
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdx,%rbp
  mov    %rdi,%rbx
  lea    D16(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebp,%ecx
  mov    %rbx,%r8
  mov    %rbx,%rdx
  add    $0x8,%rsp
  sar    %cl,%rbx
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  shl    %cl,%r8
  shr    %cl,%rdx
  mov    %rbx,%rsi
  pop    %rbx
  mov    %r8,%rcx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D16: 0x%llx op %d:


tool: D1:   ashr: 0x%llx
  lshr: 0x%llx
  shl: 0x%llx


assistant: ```c
void Test(long long Val, int Amt) {
  printf("0x%llx op %d:\n", Val, Amt);
  printf("  ashr: 0x%llx\n  lshr: 0x%llx\n  shl: 0x%llx\n", Val >> Amt, (unsigned long long)Val >> Amt, Val << Amt);
}
```