ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<drawMaze>:
  endbr64
  push   %r15
  lea    D2(%rip),%r15
  push   %r14
  lea    0x2d8(%rdi),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  lea    0x34(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L25:
  lea    -0x34(%rbp),%rbx
  jmp    L48
  xchg   %ax,%ax
L41:
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L11
L48:
  cmpl   $0x1,(%rbx)
  jne    L41
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L48
L11:
  mov    %r15,%rdi
  lea    0x34(%rbx),%rbp
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L25
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D26
type: string

tool: D2: 


tool: D19: # 

tool: D26:   

assistant: ```c
void drawMaze(int (*maze)[13]) {
  int i, j;
  for (i = 0; i < 13; i++) {
    for (j = 0; j < 13; j++) {
      if (maze[i][j] == 1)
        printf("# ");
      else
        printf("  ");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<drawMaze>:
  endbr64
  push   %r15
  lea    D20(%rip),%r15
  push   %r14
  lea    0x2d8(%rdi),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    0x34(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L23:
  lea    -0x34(%rbp),%rbx
  jmp    L0
  xchg   %ax,%ax
L36:
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L22
L0:
  cmpl   $0x1,(%rbx)
  jne    L36
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L0
L22:
  mov    %r15,%rdi
  lea    0x34(%rbx),%rbp
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L23
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D20
type_guessed: string
name: read_data
arguments: data_label: D21
type_guessed: string
name: read_data
arguments: data_label: D4
type_guessed: string

tool: D20: 


tool: D21: # 

tool: D4:   

assistant: ```c
void drawMaze(int (*maze)[13]) {
  int i, j;
  for (i = 0; i < 13; i++) {
    for (j = 0; j < 13; j++) {
      if (maze[i][j] == 1)
        printf("# ");
      else
        printf("  ");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<wait_for_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x2c(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x20(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  je     L46
  cmpl   $0x0,-0x24(%rbp)
  je     L31
  jmp    L30
L46:
  mov    $0xffffffff,%eax
  jmp    L29
L31:
  mov    $0x0,%eax
  jmp    L29
L30:
  lea    -0x2c(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_ISSET@plt>
  test   %eax,%eax
  je     L74
  mov    -0x34(%rbp),%eax
  jmp    L29
L74:
  mov    $0xffffffff,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int wait_for_read(int s, long sec) {
  fd_set fds;
  int n, nfd;
  struct timeval tv;
  tv.tv_sec = sec;
  tv.tv_usec = 0;
  nfd = s;
  FD_ZERO(&fds);
  FD_SET(s, &fds);
  n = select(nfd + 1, &fds, 0, 0, &tv);
  switch (n) {
  case -1:
    return (-1);
  case 0:
    return (0);
  default:
    if (FD_ISSET(s, &fds))
      return (s);
    else
      return (-1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wait_for_read>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  je     L21
  test   %eax,%eax
  je     L21
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovne %ebx,%eax
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wait_for_read(int s, long sec) {
  fd_set fds;
  int n, nfd;
  struct timeval tv;
  tv.tv_sec = sec;
  tv.tv_usec = 0;
  nfd = s;
  FD_ZERO(&fds);
  FD_SET(s, &fds);
  n = select(nfd + 1, &fds, 0, 0, &tv);
  switch (n) {
  case -1:
    return (-1);
  case 0:
    return (0);
  default:
    if (FD_ISSET(s, &fds))
      return (s);
    else
      return (-1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wait_for_read>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rsi,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    %rbp,%rsi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  je     L10
  test   %eax,%eax
  je     L10
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovne %ebx,%eax
L10:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wait_for_read(int s, long sec) {
  fd_set fds;
  int n, nfd;
  struct timeval tv;
  tv.tv_sec = sec;
  tv.tv_usec = 0;
  nfd = s;
  FD_ZERO(&fds);
  FD_SET(s, &fds);
  n = select(nfd + 1, &fds, 0, 0, &tv);
  switch (n) {
  case -1:
    return (-1);
  case 0:
    return (0);
  default:
    if (FD_ISSET(s, &fds))
      return (s);
    else
      return (-1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wait_for_read>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rsi,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    %rbp,%rsi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  je     L19
  test   %eax,%eax
  je     L19
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovne %ebx,%eax
L19:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wait_for_read(int s, long sec) {
  fd_set fds;
  int n, nfd;
  struct timeval tv;
  tv.tv_sec = sec;
  tv.tv_usec = 0;
  nfd = s;
  FD_ZERO(&fds);
  FD_SET(s, &fds);
  n = select(nfd + 1, &fds, 0, 0, &tv);
  switch (n) {
  case -1:
    return (-1);
  case 0:
    return (0);
  default:
    if (FD_ISSET(s, &fds))
      return (s);
    else
      return (-1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gm_time_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x3c,%eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  lea    (%rcx,%rdx,1),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L15
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L13
L15:
  mov    -0x4(%rbp),%eax
L13:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x3c,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
time_t gm_time_t(unsigned long time, int tz) {
  int minutes;
  minutes = tz < 0 ? -tz : tz;
  minutes = (minutes / 100) * 60 + (minutes % 100);
  minutes = tz < 0 ? -minutes : minutes;
  return time + minutes * 60;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gm_time_t>:
  endbr64
  mov    %esi,%ecx
  neg    %ecx
  cmovs  %esi,%ecx
  movslq %ecx,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  imul   $0x64,%edx,%edx
  sub    %edx,%ecx
  add    %ecx,%eax
  mov    %eax,%edx
  neg    %edx
  test   %esi,%esi
  cmovs  %edx,%eax
  imul   $0x3c,%eax,%eax
  cltq
  add    %rdi,%rax
  ret
```

assistant: ```c
time_t gm_time_t(unsigned long time, int tz) {
  int minutes;
  minutes = tz < 0 ? -tz : tz;
  minutes = (minutes / 100) * 60 + (minutes % 100);
  minutes = tz < 0 ? -minutes : minutes;
  return time + minutes * 60;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gm_time_t>:
  endbr64
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0xffffffd8,%eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  test   %esi,%esi
  cmovs  %edx,%eax
  imul   $0x3c,%eax,%eax
  cltq
  add    %rdi,%rax
  ret
```

assistant: ```c
time_t gm_time_t(unsigned long time, int tz) {
  int minutes;
  minutes = tz < 0 ? -tz : tz;
  minutes = (minutes / 100) * 60 + (minutes % 100);
  minutes = tz < 0 ? -minutes : minutes;
  return time + minutes * 60;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gm_time_t>:
  endbr64
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0xffffffd8,%eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  test   %esi,%esi
  cmovs  %edx,%eax
  imul   $0x3c,%eax,%eax
  cltq
  add    %rdi,%rax
  ret
```

assistant: ```c
time_t gm_time_t(unsigned long time, int tz) {
  int minutes;
  minutes = tz < 0 ? -tz : tz;
  minutes = (minutes / 100) * 60 + (minutes % 100);
  minutes = tz < 0 ? -minutes : minutes;
  return time + minutes * 60;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spcLockFile>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    D7(%rip),%r13
  jmp    L110
L30:
  sub    $0x1,%ebp
  mov    %r12,%rdi
  call   <unlink@plt>
  jmp    L99
L96:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L99
L77:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  call   <writeData@plt>
  test   %eax,%eax
  je     L66
  mov    %ebx,%edi
  call   <close@plt>
  sub    $0x1,%ebp
L99:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  jg     L26
L110:
  mov    D34(%rip),%rax
  mov    (%rax),%esi
  mov    D76(%rip),%rax
  or     (%rax),%esi
  mov    D65(%rip),%rax
  or     (%rax),%esi
  mov    0x0(%r13),%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L77
  mov    D60(%rip),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L54
  mov    D37(%rip),%rax
  mov    (%rax),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L54
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %eax,%edi
  call   <readData@plt>
  mov    %eax,%r14d
  mov    %ebx,%edi
  call   <close@plt>
  test   %r14d,%r14d
  je     L96
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    0x4(%rsp),%edi
  cmp    %edi,%eax
  je     L44
  mov    $0x0,%esi
  call   <kill@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L96
  mov    D60(%rip),%rdx
  mov    D62(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L30
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L54
L26:
  mov    $0x0,%ebx
  jmp    L54
L44:
  mov    $0x1,%ebx
  jmp    L54
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spcLockFile(const char *lfpath) {
  int attempt;
  int fd;
  int result;
  pid_t pid;
  for (attempt = 0; attempt < 3; attempt++) {
    if ((fd = open(lfpath, O_RDWR | O_CREAT | O_EXCL, S_IRWXU)) == -1) {
      if (errno != EEXIST)
        return -1;
      if ((fd = open(lfpath, O_RDONLY)) == -1)
        return -1;
      result = readData(fd, &pid, sizeof(pid));
      close(fd);
      if (result) {
        if (pid == getpid())
          return 1;
        if (kill(pid, 0) == -1) {
          if (errno != ESRCH)
            return -1;
          attempt--;
          unlink(lfpath);
          continue;
        }
      }
      sleep(1);
      continue;
    }
    pid = getpid();
    if (!writeData(fd, &pid, sizeof(pid))) {
      close(fd);
      return -1;
    }
    close(fd);
    attempt--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<spcLockFile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    D85(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r15
  nopl   0x0(%rax)
L112:
  mov    D38(%rip),%rax
  mov    0x0(%r13),%esi
  mov    %rbx,%rdi
  or     (%rax),%esi
  mov    D8(%rip),%rax
  or     (%rax),%esi
  mov    D84(%rip),%rax
  mov    (%rax),%edx
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  jne    L81
  mov    D70(%rip),%rax
  mov    D50(%rip),%rcx
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  jne    L21
  mov    D71(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L21
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %eax,0xc(%rsp)
  call   <readData@plt>
  mov    0xc(%rsp),%edi
  mov    %eax,%r14d
  call   <close@plt>
  test   %r14d,%r14d
  je     L68
  xor    %eax,%eax
  call   <getpid@plt>
  mov    0x14(%rsp),%edi
  cmp    %edi,%eax
  je     L71
  xor    %esi,%esi
  call   <kill@plt>
  cmp    $0xffffffff,%eax
  jne    L68
  mov    D73(%rip),%rax
  mov    D50(%rip),%rcx
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  je     L38
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x28,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L81:
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebp,%edi
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %eax,0x14(%rsp)
  call   <writeData@plt>
  mov    %ebp,%edi
  test   %eax,%eax
  je     L131
  call   <close@plt>
L87:
  cmp    $0x3,%r12d
  jne    L112
  xor    %ebp,%ebp
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L68:
  mov    $0x1,%edi
  add    $0x1,%r12d
  call   <sleep@plt>
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %rbx,%rdi
  call   <unlink@plt>
  jmp    L87
L131:
  call   <close@plt>
  mov    $0xffffffff,%ebp
  jmp    L21
L71:
  mov    $0x1,%ebp
  jmp    L21
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spcLockFile(const char *lfpath) {
  int attempt;
  int fd;
  int result;
  pid_t pid;
  for (attempt = 0; attempt < 3; attempt++) {
    if ((fd = open(lfpath, O_RDWR | O_CREAT | O_EXCL, S_IRWXU)) == -1) {
      if (errno != EEXIST)
        return -1;
      if ((fd = open(lfpath, O_RDONLY)) == -1)
        return -1;
      result = readData(fd, &pid, sizeof(pid));
      close(fd);
      if (result) {
        if (pid == getpid())
          return 1;
        if (kill(pid, 0) == -1) {
          if (errno != ESRCH)
            return -1;
          attempt--;
          unlink(lfpath);
          continue;
        }
      }
      sleep(1);
      continue;
    }
    pid = getpid();
    if (!writeData(fd, &pid, sizeof(pid))) {
      close(fd);
      return -1;
    }
    close(fd);
    attempt--;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<spcLockFile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    D40(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r15
  nopl   0x0(%rax)
L41:
  mov    D7(%rip),%rax
  mov    0x0(%r13),%esi
  mov    %rbx,%rdi
  or     (%rax),%esi
  mov    D73(%rip),%rax
  or     (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  jne    L143
  mov    D80(%rip),%rax
  mov    D11(%rip),%rcx
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  jne    L19
  mov    D58(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L19
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %eax,0xc(%rsp)
  call   <readData@plt>
  mov    0xc(%rsp),%edi
  mov    %eax,%r14d
  call   <close@plt>
  test   %r14d,%r14d
  je     L73
  xor    %eax,%eax
  call   <getpid@plt>
  mov    0x14(%rsp),%edi
  cmp    %edi,%eax
  je     L38
  xor    %esi,%esi
  call   <kill@plt>
  cmp    $0xffffffff,%eax
  jne    L73
  mov    D78(%rip),%rax
  mov    D11(%rip),%rcx
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  je     L104
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x28,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L143:
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebp,%edi
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %eax,0x14(%rsp)
  call   <writeData@plt>
  mov    %ebp,%edi
  test   %eax,%eax
  je     L59
  call   <close@plt>
L118:
  cmp    $0x3,%r12d
  jne    L41
  xor    %ebp,%ebp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L73:
  mov    $0x1,%edi
  add    $0x1,%r12d
  call   <sleep@plt>
  jmp    L118
  nopl   0x0(%rax,%rax,1)
L104:
  mov    %rbx,%rdi
  call   <unlink@plt>
  jmp    L118
L59:
  call   <close@plt>
  mov    $0xffffffff,%ebp
  jmp    L19
L38:
  mov    $0x1,%ebp
  jmp    L19
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spcLockFile(const char *lfpath) {
  int attempt;
  int fd;
  int result;
  pid_t pid;
  for (attempt = 0; attempt < 3; attempt++) {
    if ((fd = open(lfpath, O_RDWR | O_CREAT | O_EXCL, S_IRWXU)) == -1) {
      if (errno != EEXIST)
        return -1;
      if ((fd = open(lfpath, O_RDONLY)) == -1)
        return -1;
      result = readData(fd, &pid, sizeof(pid));
      close(fd);
      if (result) {
        if (pid == getpid())
          return 1;
        if (kill(pid, 0) == -1) {
          if (errno != ESRCH)
            return -1;
          attempt--;
          unlink(lfpath);
          continue;
        }
      }
      sleep(1);
      continue;
    }
    pid = getpid();
    if (!writeData(fd, &pid, sizeof(pid))) {
      close(fd);
      return -1;
    }
    close(fd);
    attempt--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dayofweek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x2,-0x8(%rbp)
  setle  %al
  movzbl %al,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x7d0(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x7d0,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    $0x7d0,%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  lea    0x5(%rax),%ecx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L1
  mov    $0x7,%eax
  jmp    L5
L1:
  mov    -0xc(%rbp),%eax
L5:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: 

assistant: ```c
uint8_t dayofweek(uint8_t y, uint8_t m, uint8_t d) {
  static const uint8_t dayofweek_table[] = {0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4};
  y -= m < 3;
  d = (((y + 2000) + ((y + 2000) / 4) - ((y + 2000) / 100) + 2000 / 400 + dayofweek_table[m - 1] + d) % 7);
  if (d == 0) {
    return 7;
  } else {
    return d;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dayofweek>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%ecx
  cmp    $0x2,%esi
  setle  %dl
  movzbl %dl,%edx
  sub    %edx,%edi
  lea    0x7d3(%rdi),%edx
  add    $0x7d0,%edi
  cmovns %edi,%edx
  sar    $0x2,%edx
  add    %edi,%edx
  movslq %edi,%rsi
  imul   $0x51eb851f,%rsi,%rsi
  sar    $0x25,%rsi
  sar    $0x1f,%edi
  sub    %esi,%edi
  lea    0x5(%rdx,%rdi,1),%edx
  sub    $0x1,%eax
  cltq
  lea    D3(%rip),%rsi
  add    (%rsi,%rax,4),%edx
  add    %ecx,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x7,%edx
  cmove  %edx,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: 

assistant: ```c
uint8_t dayofweek(uint8_t y, uint8_t m, uint8_t d) {
  static const uint8_t dayofweek_table[] = {0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4};
  y -= m < 3;
  d = (((y + 2000) + ((y + 2000) / 4) - ((y + 2000) / 100) + 2000 / 400 + dayofweek_table[m - 1] + d) % 7);
  if (d == 0) {
    return 7;
  } else {
    return d;
  }
}
```