ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fd_write_n>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L38
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xchg   %ax,%ax
L6:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  js     L8
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L6
L38:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  mov    D4(%rip),%rax
  mov    D6(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L6
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t fd_write_n(int fd, const void *buf, size_t n) {
  const unsigned char *p;
  size_t nleft;
  ssize_t nwritten;
  p = buf;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, p, nleft)) < 0) {
      if (errno == EINTR)
        continue;
      else
        return (-1);
    }
    nleft -= nwritten;
    p += nwritten;
  }
  return (n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fd_write_n>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L17
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xchg   %ax,%ax
L36:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  js     L20
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L36
L17:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  mov    D13(%rip),%rax
  mov    D5(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L36
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t fd_write_n(int fd, const void *buf, size_t n) {
  const unsigned char *p;
  size_t nleft;
  ssize_t nwritten;
  p = buf;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, p, nleft)) < 0) {
      if (errno == EINTR)
        continue;
      else
        return (-1);
    }
    nleft -= nwritten;
    p += nwritten;
  }
  return (n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lt_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  shll   $0x3,-0x14(%rbp)
  movsbl -0x19(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  add    %ecx,%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movsbl -0x19(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L28
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  xor    %eax,-0x18(%rbp)
L28:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x14(%rbp),%eax
  xor    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    %edx,%ecx
  mov    $0x80088091,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  shr    $0xf,%eax
  imul   $0xffef,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int lt_hash(const char *s) {
  const char *p;
  char ch;
  unsigned int h = 0, h2 = 0, pos = 0, g;
  for (p = s; *p; p++) {
    ch = *p;
    h2 <<= 3;
    h2 -= ((unsigned int)ch + (pos++));
    h = (h << 4) + ch;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  h ^= h2;
  return (h % 65519);
}
```
user: What is the c source code of the assembly code below:

```asm
<lt_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L30
  mov    $0x0,%esi
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L1
L45:
  add    $0x1,%rsi
  movzbl (%rdi,%rsi,1),%edx
  test   %dl,%dl
  je     L2
L1:
  movsbl %dl,%edx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %esi,%ecx
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L45
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
  jmp    L45
L30:
  mov    $0x0,%ecx
  mov    $0x0,%eax
L2:
  xor    %ecx,%eax
  mov    %eax,%edx
  mov    $0x80088091,%ecx
  imul   %rcx,%rdx
  shr    $0x2f,%rdx
  imul   $0xffef,%edx,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int lt_hash(const char *s) {
  const char *p;
  char ch;
  unsigned int h = 0, h2 = 0, pos = 0, g;
  for (p = s; *p; p++) {
    ch = *p;
    h2 <<= 3;
    h2 -= ((unsigned int)ch + (pos++));
    h = (h << 4) + ch;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  h ^= h2;
  return (h % 65519);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lt_hash>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L3
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  shl    $0x4,%eax
  shl    $0x3,%ecx
  add    %edx,%eax
  sub    %edx,%ecx
  mov    %eax,%edx
  sub    %esi,%ecx
  and    $0xf0000000,%edx
  je     L27
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
L27:
  add    $0x1,%rsi
  movsbl (%rdi,%rsi,1),%edx
  test   %dl,%dl
  jne    L8
  xor    %ecx,%eax
  mov    $0x80088091,%edx
  mov    %eax,%r8d
  imul   %rdx,%r8
  shr    $0x2f,%r8
  imul   $0xffef,%r8d,%edx
  sub    %edx,%eax
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int lt_hash(const char *s) {
  const char *p;
  char ch;
  unsigned int h = 0, h2 = 0, pos = 0, g;
  for (p = s; *p; p++) {
    ch = *p;
    h2 <<= 3;
    h2 -= ((unsigned int)ch + (pos++));
    h = (h << 4) + ch;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  h ^= h2;
  return (h % 65519);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lt_hash>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  shl    $0x4,%eax
  shl    $0x3,%ecx
  add    %edx,%eax
  sub    %edx,%ecx
  mov    %eax,%edx
  sub    %esi,%ecx
  and    $0xf0000000,%edx
  je     L19
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
L19:
  add    $0x1,%rsi
  movsbl (%rdi,%rsi,1),%edx
  test   %dl,%dl
  jne    L8
  xor    %ecx,%eax
  mov    $0x80088091,%edx
  mov    %eax,%r8d
  imul   %rdx,%r8
  shr    $0x2f,%r8
  imul   $0xffef,%r8d,%edx
  sub    %edx,%eax
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int lt_hash(const char *s) {
  const char *p;
  char ch;
  unsigned int h = 0, h2 = 0, pos = 0, g;
  for (p = s; *p; p++) {
    ch = *p;
    h2 <<= 3;
    h2 -= ((unsigned int)ch + (pos++));
    h = (h << 4) + ch;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  h ^= h2;
  return (h % 65519);
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L48
  mov    $0x0,%eax
  jmp    L30
L48:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L7
L27:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L55
  mov    $0x0,%eax
  jmp    L30
L55:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L27
  mov    $0x1,%eax
L30:
  leave
  ret
```

assistant: ```c
int check_prime(int num) {
  int i, temp;
  if (num <= 1) {
    return 0;
  }
  temp = sqrt(num);
  for (i = 2; i <= temp; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L8
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L54
  test   $0x1,%bl
  je     L75
  mov    $0x2,%ecx
L48:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L50
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L48
  jmp    L71
L50:
  mov    $0x1,%eax
L71:
  pop    %rbx
  ret
L54:
  mov    $0x1,%eax
  jmp    L71
L75:
  mov    $0x0,%eax
  jmp    L71
L8:
  ret
```

assistant: ```c
int check_prime(int num) {
  int i, temp;
  if (num <= 1) {
    return 0;
  }
  temp = sqrt(num);
  for (i = 2; i <= temp; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L1
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L6
  test   $0x1,%r12b
  je     L29
  mov    $0x2,%ecx
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L29
L49:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L39
L6:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L29:
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i, temp;
  if (num <= 1) {
    return 0;
  }
  temp = sqrt(num);
  for (i = 2; i <= temp; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L1
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L19
  test   $0x1,%r12b
  je     L52
  mov    $0x2,%ecx
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L52
L44:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L11
L19:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L52:
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i, temp;
  if (num <= 1) {
    return 0;
  }
  temp = sqrt(num);
  for (i = 2; i <= temp; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<syscall_errno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__semihost_syscall@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L11
  mov    $0x0,%eax
  call   <__syscall_error@plt>
  jmp    L6
L11:
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
long syscall_errno(long id, long *data_block) {
  long res = __semihost_syscall(id, data_block);
  if (res < 0)
    return __syscall_error();
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<syscall_errno>:
  endbr64
  sub    $0x8,%rsp
  call   <__semihost_syscall@plt>
  test   %rax,%rax
  js     L17
L19:
  add    $0x8,%rsp
  ret
L17:
  mov    $0x0,%eax
  call   <__syscall_error@plt>
  jmp    L19
```

assistant: ```c
long syscall_errno(long id, long *data_block) {
  long res = __semihost_syscall(id, data_block);
  if (res < 0)
    return __syscall_error();
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<syscall_errno>:
  endbr64
  sub    $0x8,%rsp
  call   <__semihost_syscall@plt>
  test   %rax,%rax
  js     L9
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <__syscall_error@plt>
```

assistant: ```c
long syscall_errno(long id, long *data_block) {
  long res = __semihost_syscall(id, data_block);
  if (res < 0)
    return __syscall_error();
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<syscall_errno>:
  endbr64
  sub    $0x8,%rsp
  call   <__semihost_syscall@plt>
  test   %rax,%rax
  js     L5
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <__syscall_error@plt>
```

assistant: ```c
long syscall_errno(long id, long *data_block) {
  long res = __semihost_syscall(id, data_block);
  if (res < 0)
    return __syscall_error();
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checkAscending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L36:
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x8(%rbp)
  js     L8
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L8
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L36
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L55
  mov    $0x1,%eax
  jmp    L4
L55:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int checkAscending(int **board, int player, int board_size) {
  int total = 0;
  int i = board_size - 1;
  int j = 0;
  while (i >= 0 && j < board_size && player == board[i][j]) {
    total += 1;
    i -= 1;
    j += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkAscending>:
  endbr64
  test   %edx,%edx
  jle    L2
  lea    -0x2(%rdx),%eax
  cltq
  mov    $0x0,%r9d
  mov    $0x0,%r8d
L7:
  mov    0x8(%rdi,%rax,8),%rcx
  cmp    %esi,(%rcx,%r9,1)
  jne    L0
  add    $0x1,%r8d
  mov    %eax,%ecx
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %r8d,%edx
  setg   %r10b
  sub    $0x1,%rax
  add    $0x4,%r9
  test   %cl,%r10b
  jne    L7
L0:
  cmp    %r8d,%edx
  sete   %al
  movzbl %al,%eax
  ret
L2:
  mov    $0x0,%r8d
  jmp    L0
```

assistant: ```c
int checkAscending(int **board, int player, int board_size) {
  int total = 0;
  int i = board_size - 1;
  int j = 0;
  while (i >= 0 && j < board_size && player == board[i][j]) {
    total += 1;
    i -= 1;
    j += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkAscending>:
  endbr64
  test   %edx,%edx
  jle    L15
  lea    -0x2(%rdx),%eax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  cltq
  jmp    L7
  nopl   (%rax)
L4:
  mov    %eax,%ecx
  add    $0x1,%r8d
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %r8d,%edx
  setg   %r10b
  sub    $0x1,%rax
  add    $0x4,%r9
  test   %cl,%r10b
  je     L21
L7:
  mov    0x8(%rdi,%rax,8),%rcx
  cmp    %esi,(%rcx,%r9,1)
  je     L4
  xor    %eax,%eax
  ret
L15:
  xor    %r8d,%r8d
L21:
  xor    %eax,%eax
  cmp    %r8d,%edx
  sete   %al
  ret
```

assistant: ```c
int checkAscending(int **board, int player, int board_size) {
  int total = 0;
  int i = board_size - 1;
  int j = 0;
  while (i >= 0 && j < board_size && player == board[i][j]) {
    total += 1;
    i -= 1;
    j += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checkAscending>:
  endbr64
  test   %edx,%edx
  jle    L38
  lea    -0x2(%rdx),%eax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  cltq
  jmp    L34
  nopl   (%rax)
L6:
  mov    %eax,%ecx
  add    $0x1,%r8d
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %r8d,%edx
  setg   %r10b
  sub    $0x1,%rax
  add    $0x4,%r9
  test   %cl,%r10b
  je     L31
L34:
  mov    0x8(%rdi,%rax,8),%rcx
  cmp    %esi,(%rcx,%r9,1)
  je     L6
  xor    %eax,%eax
  ret
L38:
  xor    %r8d,%r8d
L31:
  xor    %eax,%eax
  cmp    %r8d,%edx
  sete   %al
  ret
```

assistant: ```c
int checkAscending(int **board, int player, int board_size) {
  int total = 0;
  int i = board_size - 1;
  int j = 0;
  while (i >= 0 && j < board_size && player == board[i][j]) {
    total += 1;
    i -= 1;
    j += 1;
  }
  if (total == board_size)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D70
type_guessed: string
name: retrieve_data
arguments: label: D73
type_guessed: string
name: retrieve_data
arguments: label: D92
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D51
type_guessed: string
name: retrieve_data
arguments: label: D97
type_guessed: string
name: retrieve_data
arguments: label: D53
type_guessed: string
name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D25
type_guessed: string
name: retrieve_data
arguments: label: D94
type_guessed: string

tool: D70: Content-type: text/html


tool: D73: 


tool: D92: <html>


tool: D18:   <head>


tool: D51:     <title>form action.cgi</title>


tool: D97:   </head>


tool: D53:   <body>


tool: D9:     <a href="http://bgstation0.com/">B.G-STATION</a>


tool: D25:   </body>


tool: D94: </html>


assistant: ```c
int main(void) {
  printf("Content-type: text/html\n");
  printf("\n");
  printf("<html>\n");
  printf("  <head>\n");
  printf("    <title>form action.cgi</title>\n");
  printf("  </head>\n");
  printf("  <body>\n");
  printf("    <a href=\"http://bgstation0.com/\">B.G-STATION</a>\n");
  printf("  </body>\n");
  printf("</html>\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D91(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D59
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D66
type: string
name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D67
type: string
name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D91
type: string

tool: D59: Content-type: text/html


tool: D23: 


tool: D66: <html>


tool: D3:   <head>


tool: D10:     <title>form action.cgi</title>


tool: D34:   </head>


tool: D67:   <body>


tool: D15:     <a href="http://bgstation0.com/">B.G-STATION</a>


tool: D22:   </body>


tool: D91: </html>


assistant: ```c
int main(void) {
  printf("Content-type: text/html\n");
  printf("\n");
  printf("<html>\n");
  printf("  <head>\n");
  printf("    <title>form action.cgi</title>\n");
  printf("  </head>\n");
  printf("  <body>\n");
  printf("    <a href=\"http://bgstation0.com/\">B.G-STATION</a>\n");
  printf("  </body>\n");
  printf("</html>\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D88(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D85(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D88
type: string
name: retrieve_data
arguments: data_tag: D46
type: string
name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D49
type: string
name: retrieve_data
arguments: data_tag: D74
type: string
name: retrieve_data
arguments: data_tag: D62
type: string
name: retrieve_data
arguments: data_tag: D42
type: string
name: retrieve_data
arguments: data_tag: D85
type: string

tool: D16: Content-type: text/html


tool: D88: 


tool: D46: <html>


tool: D26:   <head>


tool: D3:     <title>form action.cgi</title>


tool: D49:   </head>


tool: D74:   <body>


tool: D62:     <a href="http://bgstation0.com/">B.G-STATION</a>


tool: D42:   </body>


tool: D85: </html>


assistant: ```c
int main(void) {
  printf("Content-type: text/html\n");
  printf("\n");
  printf("<html>\n");
  printf("  <head>\n");
  printf("    <title>form action.cgi</title>\n");
  printf("  </head>\n");
  printf("  <body>\n");
  printf("    <a href=\"http://bgstation0.com/\">B.G-STATION</a>\n");
  printf("  </body>\n");
  printf("</html>\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D86(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D31
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D32
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D48
type_guessed: string
name: parse_data
arguments: tag: D47
type_guessed: string
name: parse_data
arguments: tag: D61
type_guessed: string
name: parse_data
arguments: tag: D86
type_guessed: string
name: parse_data
arguments: tag: D52
type_guessed: string
name: parse_data
arguments: tag: D74
type_guessed: string

tool: D31: Content-type: text/html


tool: D1: 


tool: D32: <html>


tool: D20:   <head>


tool: D48:     <title>form action.cgi</title>


tool: D47:   </head>


tool: D61:   <body>


tool: D86:     <a href="http://bgstation0.com/">B.G-STATION</a>


tool: D52:   </body>


tool: D74: </html>


assistant: ```c
int main(void) {
  printf("Content-type: text/html\n");
  printf("\n");
  printf("<html>\n");
  printf("  <head>\n");
  printf("    <title>form action.cgi</title>\n");
  printf("  </head>\n");
  printf("  <body>\n");
  printf("    <a href=\"http://bgstation0.com/\">B.G-STATION</a>\n");
  printf("  </body>\n");
  printf("</html>\n");
  return 0;
}
```