ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isHappy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L29
L73:
  mov    -0x3c(%rbp),%esi
  lea    0x1(%rsi),%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x38(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %esi,%rax
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x38(%rbp)
L37:
  cmpl   $0x0,-0x38(%rbp)
  jne    L73
  movl   $0x0,-0x38(%rbp)
  jmp    L68
L59:
  subl   $0x1,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,-0x38(%rbp)
L68:
  cmpl   $0x0,-0x3c(%rbp)
  jne    L59
  cmpl   $0x1,-0x38(%rbp)
  jne    L53
  mov    $0x1,%eax
  jmp    L8
L53:
  addl   $0x1,-0x34(%rbp)
L29:
  cmpl   $0x9,-0x34(%rbp)
  jle    L37
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
bool isHappy(int n) {
  int len = 0;
  int a[10];
  int sum = n;
  for (int i = 0; i < 10; i++) {
    while (sum) {
      a[len++] = sum % 10;
      sum /= 10;
    }
    sum = 0;
    while (len) {
      len--;
      sum += a[len] * a[len];
    }
    if (sum == 1) {
      return true;
    }
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isHappy>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    $0xa,%r8d
  lea    -0x4(%rsp),%r9
  jmp    L6
L39:
  mov    %edi,%eax
L84:
  sub    $0x1,%r8d
  je     L71
L6:
  mov    $0x1,%ecx
  test   %eax,%eax
  je     L84
L80:
  mov    %ecx,%edi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  mov    %eax,-0x4(%rsp,%rcx,4)
  mov    %edx,%eax
  mov    %rcx,%rsi
  add    $0x1,%rcx
  test   %edx,%edx
  jne    L80
  test   %edi,%edi
  je     L39
  movslq %edi,%rdi
  shl    $0x2,%rdi
  lea    (%rsp,%rdi,1),%rcx
  add    %r9,%rdi
  lea    -0x1(%rsi),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rdi
L37:
  mov    -0x4(%rcx),%edx
  imul   %edx,%edx
  add    %edx,%eax
  sub    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L37
  cmp    $0x1,%eax
  jne    L84
  jmp    L74
L71:
  mov    $0x0,%eax
L74:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L89
  add    $0x38,%rsp
  ret
L89:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isHappy(int n) {
  int len = 0;
  int a[10];
  int sum = n;
  for (int i = 0; i < 10; i++) {
    while (sum) {
      a[len++] = sum % 10;
      sum /= 10;
    }
    sum = 0;
    while (len) {
      len--;
      sum += a[len] * a[len];
    }
    if (sum == 1) {
      return true;
    }
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isHappy>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%r8d
  mov    $0xa,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    -0x4(%rsp),%r10
  nopl   0x0(%rax)
L53:
  test   %r8d,%r8d
  je     L60
  mov    $0x1,%edx
  xchg   %ax,%ax
L52:
  movslq %r8d,%rax
  mov    %r8d,%ecx
  mov    %edx,%r11d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %r8d,%eax
  add    %esi,%esi
  mov    %ecx,%r8d
  sub    %esi,%eax
  mov    %eax,-0x4(%rdi,%rdx,4)
  add    $0x1,%rdx
  test   %ecx,%ecx
  jne    L52
  movslq %r11d,%rsi
  lea    -0x1(%r11),%ecx
  shl    $0x2,%rsi
  shl    $0x2,%rcx
  lea    (%rdi,%rsi,1),%rdx
  add    %r10,%rsi
  sub    %rcx,%rsi
  xor    %ecx,%ecx
  jmp    L46
  nopl   0x0(%rax)
L24:
  mov    -0x4(%rdx),%eax
L46:
  imul   %eax,%eax
  sub    $0x4,%rdx
  add    %eax,%ecx
  cmp    %rsi,%rdx
  jne    L24
  cmp    $0x1,%ecx
  je     L2
  sub    $0x1,%r9d
  je     L27
  mov    %ecx,%r8d
  jmp    L53
L60:
  cmp    $0x1,%r9d
  je     L27
  sub    $0x2,%r9d
  jne    L60
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    %r8d,%eax
  add    $0x38,%rsp
  ret
L2:
  mov    $0x1,%r8d
  jmp    L27
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isHappy(int n) {
  int len = 0;
  int a[10];
  int sum = n;
  for (int i = 0; i < 10; i++) {
    while (sum) {
      a[len++] = sum % 10;
      sum /= 10;
    }
    sum = 0;
    while (len) {
      len--;
      sum += a[len] * a[len];
    }
    if (sum == 1) {
      return true;
    }
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int foo(int y) {
  volatile int a = y;
  volatile int *volatile b = &a;
  return *b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    (%rax),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int y) {
  volatile int a = y;
  volatile int *volatile b = &a;
  return *b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  mov    %edi,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    (%rax),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int y) {
  volatile int a = y;
  volatile int *volatile b = &a;
  return *b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  mov    %edi,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    (%rax),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int y) {
  volatile int a = y;
  volatile int *volatile b = &a;
  return *b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0x96a,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L26
L36:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jbe    L9
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl -0xc(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%edx
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  imul   %edx,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L39
L9:
  movzwl -0xa(%rbp),%edx
  movzwl -0xa(%rbp),%eax
  imul   %edx,%eax
  mov    %ax,-0xa(%rbp)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xe(%rbp),%edx
  mov    %dl,(%rax)
L39:
  addw   $0x2,-0xc(%rbp)
L26:
  cmpw   $0x0,-0xc(%rbp)
  je     L36
  movzwl -0xa(%rbp),%eax
  imul   $0x6e29,%ax,%ax
  lea    -0x3ca6(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] *= state[0UL];
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 943156777UL + (unsigned short)50010;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x96a,%ax
  imul   %eax,%eax
  mov    $0x0,%edx
  mov    %al,%dh
  movsbl %ah,%eax
  mov    %al,%dl
  imul   $0x6e29,%dx,%dx
  sub    $0x3ca6,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] *= state[0UL];
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 943156777UL + (unsigned short)50010;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x96a,%ax
  imul   %eax,%eax
  rol    $0x8,%ax
  imul   $0x6e29,%ax,%ax
  sub    $0x3ca6,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] *= state[0UL];
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 943156777UL + (unsigned short)50010;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x96a,%ax
  imul   %eax,%eax
  rol    $0x8,%ax
  imul   $0x6e29,%ax,%ax
  sub    $0x3ca6,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] *= state[0UL];
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 943156777UL + (unsigned short)50010;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<LEDS_off>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x400000,%eax
  test   %eax,%eax
  je     L0
  mov    $0x116,%edi
  call   <IO_output_high@plt>
L0:
  mov    -0x4(%rbp),%eax
  and    $0x200000,%eax
  test   %eax,%eax
  je     L1
  mov    $0x115,%edi
  call   <IO_output_high@plt>
L1:
  mov    -0x4(%rbp),%eax
  and    $0x100000,%eax
  test   %eax,%eax
  je     L25
  mov    $0x114,%edi
  call   <IO_output_high@plt>
L25:
  nop
  leave
  ret
```

assistant: ```c
void LEDS_off(int mask) {
  if (mask & (1 << 22))
    IO_output_high((22 | (1 << 8)));
  if (mask & (1 << 21))
    IO_output_high((21 | (1 << 8)));
  if (mask & (1 << 20))
    IO_output_high((20 | (1 << 8)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LEDS_off>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   $0x400000,%edi
  jne    L19
L31:
  test   $0x200000,%ebx
  jne    L4
L32:
  test   $0x100000,%ebx
  jne    L26
L50:
  pop    %rbx
  ret
L19:
  mov    $0x116,%edi
  call   <IO_output_high@plt>
  jmp    L31
L4:
  mov    $0x115,%edi
  call   <IO_output_high@plt>
  jmp    L32
L26:
  mov    $0x114,%edi
  call   <IO_output_high@plt>
  jmp    L50
```

assistant: ```c
void LEDS_off(int mask) {
  if (mask & (1 << 22))
    IO_output_high((22 | (1 << 8)));
  if (mask & (1 << 21))
    IO_output_high((21 | (1 << 8)));
  if (mask & (1 << 20))
    IO_output_high((20 | (1 << 8)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LEDS_off>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  and    $0x400000,%edi
  jne    L36
  test   $0x200000,%ebx
  jne    L20
L22:
  and    $0x100000,%ebx
  jne    L9
L24:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L36:
  mov    $0x116,%edi
  call   <IO_output_high@plt>
  test   $0x200000,%ebx
  je     L22
L20:
  mov    $0x115,%edi
  call   <IO_output_high@plt>
  and    $0x100000,%ebx
  je     L24
L9:
  mov    $0x114,%edi
  pop    %rbx
  jmp    1050 <IO_output_high@plt>
```

assistant: ```c
void LEDS_off(int mask) {
  if (mask & (1 << 22))
    IO_output_high((22 | (1 << 8)));
  if (mask & (1 << 21))
    IO_output_high((21 | (1 << 8)));
  if (mask & (1 << 20))
    IO_output_high((20 | (1 << 8)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<LEDS_off>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  and    $0x400000,%edi
  jne    L39
  test   $0x200000,%ebx
  jne    L29
L37:
  and    $0x100000,%ebx
  jne    L33
L8:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L39:
  mov    $0x116,%edi
  call   <IO_output_high@plt>
  test   $0x200000,%ebx
  je     L37
L29:
  mov    $0x115,%edi
  call   <IO_output_high@plt>
  and    $0x100000,%ebx
  je     L8
L33:
  mov    $0x114,%edi
  pop    %rbx
  jmp    1050 <IO_output_high@plt>
```

assistant: ```c
void LEDS_off(int mask) {
  if (mask & (1 << 22))
    IO_output_high((22 | (1 << 8)));
  if (mask & (1 << 21))
    IO_output_high((21 | (1 << 8)));
  if (mask & (1 << 20))
    IO_output_high((20 | (1 << 8)));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_GETPMC2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <GETPMC@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%ebx
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__setsv1type@plt>
L8:
  movslq %ebx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long _GETPMC2(pmctable, pmtname)
struct mctable *pmctable;
char *pmtname;
{
  register int i;
  i = GETPMC(pmctable, pmtname);
  if (i == -1) {
    __setsv1type(pmctable);
  }
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_GETPMC2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <GETPMC@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L7
L4:
  movslq %ebx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <__setsv1type@plt>
  jmp    L4
```

assistant: ```c
long _GETPMC2(pmctable, pmtname)
struct mctable *pmctable;
char *pmtname;
{
  register int i;
  i = GETPMC(pmctable, pmtname);
  if (i == -1) {
    __setsv1type(pmctable);
  }
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_GETPMC2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <GETPMC@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L6
  add    $0x8,%rsp
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <__setsv1type@plt>
  add    $0x8,%rsp
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long _GETPMC2(pmctable, pmtname)
struct mctable *pmctable;
char *pmtname;
{
  register int i;
  i = GETPMC(pmctable, pmtname);
  if (i == -1) {
    __setsv1type(pmctable);
  }
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_GETPMC2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <GETPMC@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L0
  add    $0x8,%rsp
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L0:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <__setsv1type@plt>
  add    $0x8,%rsp
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long _GETPMC2(pmctable, pmtname)
struct mctable *pmctable;
char *pmtname;
{
  register int i;
  i = GETPMC(pmctable, pmtname);
  if (i == -1) {
    __setsv1type(pmctable);
  }
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<free_aligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void free_aligned(void *ptr) {
  if (ptr) {
    free(*((void **)ptr - 1));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_aligned>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  mov    -0x8(%rdi),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
L9:
  ret
```

assistant: ```c
void free_aligned(void *ptr) {
  if (ptr) {
    free(*((void **)ptr - 1));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_aligned>:
  endbr64
  test   %rdi,%rdi
  je     L7
  mov    -0x8(%rdi),%rdi
  jmp    1050 <free@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void free_aligned(void *ptr) {
  if (ptr) {
    free(*((void **)ptr - 1));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<free_aligned>:
  endbr64
  test   %rdi,%rdi
  je     L2
  mov    -0x8(%rdi),%rdi
  jmp    1050 <free@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void free_aligned(void *ptr) {
  if (ptr) {
    free(*((void **)ptr - 1));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wcscchrnul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L36
  mov    -0x8(%rbp),%rax
  jmp    L18
L36:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L42
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L7
L42:
  mov    -0x8(%rbp),%rax
  jmp    L18
L7:
  addq   $0x8,-0x8(%rbp)
  jmp    L0
L18:
  pop    %rbp
  ret
```

assistant: ```c
wchar_t *(wcscchrnul)(const wchar_t *string, wchar_t c, wchar_t stop) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop))
      return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wcscchrnul>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rcx
  test   %rcx,%rcx
  sete   %dil
  cmp    %rcx,%rsi
  sete   %r8b
  or     %r8b,%dil
  jne    L25
  cmp    %rcx,%rdx
  je     L25
L18:
  add    $0x8,%rax
  mov    (%rax),%rcx
  test   %rcx,%rcx
  sete   %dil
  cmp    %rdx,%rcx
  sete   %r8b
  or     %r8b,%dil
  jne    L25
  cmp    %rsi,%rcx
  jne    L18
L25:
  ret
```

assistant: ```c
wchar_t *(wcscchrnul)(const wchar_t *string, wchar_t c, wchar_t stop) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop))
      return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcscchrnul>:
  endbr64
  mov    (%rdi),%rcx
  mov    %rdi,%rax
  test   %rcx,%rcx
  sete   %dil
  cmp    %rcx,%rsi
  sete   %r8b
  or     %r8b,%dil
  jne    L24
  cmp    %rcx,%rdx
  jne    L21
  jmp    L24
  nopl   0x0(%rax)
L5:
  cmp    %rsi,%rcx
  je     L24
L21:
  mov    0x8(%rax),%rcx
  add    $0x8,%rax
  test   %rcx,%rcx
  sete   %dil
  cmp    %rdx,%rcx
  sete   %r8b
  or     %r8b,%dil
  je     L5
L24:
  ret
```

assistant: ```c
wchar_t *(wcscchrnul)(const wchar_t *string, wchar_t c, wchar_t stop) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop))
      return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wcscchrnul>:
  endbr64
  mov    (%rdi),%rcx
  mov    %rdi,%rax
  test   %rcx,%rcx
  sete   %dil
  cmp    %rcx,%rsi
  sete   %r8b
  or     %r8b,%dil
  jne    L43
  cmp    %rcx,%rdx
  jne    L4
  jmp    L43
  nopl   0x0(%rax)
L44:
  cmp    %rsi,%rcx
  je     L43
L4:
  mov    0x8(%rax),%rcx
  add    $0x8,%rax
  test   %rcx,%rcx
  sete   %dil
  cmp    %rdx,%rcx
  sete   %r8b
  or     %r8b,%dil
  je     L44
L43:
  ret
```

assistant: ```c
wchar_t *(wcscchrnul)(const wchar_t *string, wchar_t c, wchar_t stop) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop))
      return string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x424(%rbp)
  movl   $0x0,-0x420(%rbp)
  jmp    L5
L13:
  movl   $0x7,-0x41c(%rbp)
  subl   $0x1,-0x424(%rbp)
L5:
  cmpl   $0x1,-0x424(%rbp)
  jg     L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int main(void) {
  int arr[260];
  int n;
  n = 5;
  arr[0] = 0;
  while (n > 1) {
    arr[1] = 7;
    n--;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int arr[260];
  int n;
  n = 5;
  arr[0] = 0;
  while (n > 1) {
    arr[1] = 7;
    n--;
  }
  return 0;
}
```