ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<asinh>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  call   <isfinite@plt>
  movsd  (%rsp),%xmm1
  test   %eax,%eax
  jne    L18
L4:
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L18:
  movapd %xmm1,%xmm2
  movsd  D29(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <__fast_sqrt@plt>
  movsd  (%rsp),%xmm2
  addsd  D29(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  andpd  D45(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  addsd  %xmm2,%xmm0
  call   <__fast_log1p@plt>
  movsd  (%rsp),%xmm1
  comisd D22(%rip),%xmm1
  movapd %xmm0,%xmm1
  ja     L4
  xorpd  D0(%rip),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D29
data_type: f64
name: read_data
arguments: tag: D45
data_type: qword[2]
name: read_data
arguments: tag: D22
data_type: f64[2]
name: read_data
arguments: tag: D0
data_type: byte[16]

tool: D29: 1

tool: {"D45": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D22": [0.0,-0.0]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double asinh(double x) {
  double z;
  if (!isfinite(x))
    return x;
  z = fabs(x);
  z = __fast_log1p(z + z * z / (__fast_sqrt(z * z + 1.0) + 1.0));
  return (x > 0.0 ? z : -z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<asinh>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  call   <isfinite@plt>
  movsd  (%rsp),%xmm1
  test   %eax,%eax
  jne    L9
L5:
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L9:
  movapd %xmm1,%xmm2
  movsd  D36(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <__fast_sqrt@plt>
  movsd  (%rsp),%xmm2
  addsd  D36(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  andpd  D26(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  addsd  %xmm2,%xmm0
  call   <__fast_log1p@plt>
  movsd  (%rsp),%xmm1
  comisd D33(%rip),%xmm1
  movapd %xmm0,%xmm1
  ja     L5
  xorpd  D12(%rip),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D36
type: f64
name: parse_data
arguments: data_tag: D26
type: qword[2]
name: parse_data
arguments: data_tag: D33
type: f64[2]
name: parse_data
arguments: data_tag: D12
type: byte[16]

tool: D36: 1

tool: {"D26": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D33": [0.0,-0.0]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double asinh(double x) {
  double z;
  if (!isfinite(x))
    return x;
  z = fabs(x);
  z = __fast_log1p(z + z * z / (__fast_sqrt(z * z + 1.0) + 1.0));
  return (x > 0.0 ? z : -z);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <setup_dir@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L29
  mov    -0x10(%rbp),%eax
  jmp    L42
L29:
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L56
  mov    $0xffffffff,%eax
  jmp    L42
L56:
  cmpl   $0x0,-0xc(%rbp)
  jle    L46
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
  mov    $0x0,%eax
  call   <remove_dir@plt>
  mov    -0x10(%rbp),%eax
  jmp    L42
L46:
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <test_logscan@plt>
  mov    $0x0,%eax
  call   <test_purge@plt>
  mov    $0x0,%eax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  pid_t child;
  ret = setup_dir();
  if (ret < 0) {
    return ret;
  }
  child = fork();
  if (child == -1) {
    return -1;
  } else if (child > 0) {
    int status = 0;
    waitpid(child, &status, 0);
    remove_dir();
    return ret;
  } else {
    assert(child == 0);
    test_logscan();
    test_purge();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <setup_dir@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L11
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L52
  test   %eax,%eax
  jg     L21
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <test_logscan@plt>
  mov    $0x0,%eax
  call   <test_purge@plt>
  mov    $0x0,%ebx
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L21:
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <waitpid@plt>
  mov    $0x0,%eax
  call   <remove_dir@plt>
  jmp    L11
L52:
  mov    %eax,%ebx
  jmp    L11
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  pid_t child;
  ret = setup_dir();
  if (ret < 0) {
    return ret;
  }
  child = fork();
  if (child == -1) {
    return -1;
  } else if (child > 0) {
    int status = 0;
    waitpid(child, &status, 0);
    remove_dir();
    return ret;
  } else {
    assert(child == 0);
    test_logscan();
    test_purge();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <setup_dir@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L46
  call   <fork@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L50
  test   %eax,%eax
  jg     L34
  sete   %dil
  xor    %r12d,%r12d
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  call   <test_logscan@plt>
  xor    %eax,%eax
  call   <test_purge@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L34:
  lea    0x4(%rsp),%rsi
  xor    %edx,%edx
  movl   $0x0,0x4(%rsp)
  call   <waitpid@plt>
  xor    %eax,%eax
  call   <remove_dir@plt>
  jmp    L46
L50:
  or     $0xffffffff,%r12d
  jmp    L46
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  pid_t child;
  ret = setup_dir();
  if (ret < 0) {
    return ret;
  }
  child = fork();
  if (child == -1) {
    return -1;
  } else if (child > 0) {
    int status = 0;
    waitpid(child, &status, 0);
    remove_dir();
    return ret;
  } else {
    assert(child == 0);
    test_logscan();
    test_purge();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <setup_dir@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L0
  call   <fork@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L32
  test   %eax,%eax
  jg     L55
  sete   %dil
  xor    %r12d,%r12d
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  call   <test_logscan@plt>
  xor    %eax,%eax
  call   <test_purge@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L55:
  lea    0x4(%rsp),%rsi
  xor    %edx,%edx
  movl   $0x0,0x4(%rsp)
  call   <waitpid@plt>
  xor    %eax,%eax
  call   <remove_dir@plt>
  jmp    L0
L32:
  or     $0xffffffff,%r12d
  jmp    L0
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  pid_t child;
  ret = setup_dir();
  if (ret < 0) {
    return ret;
  }
  child = fork();
  if (child == -1) {
    return -1;
  } else if (child > 0) {
    int status = 0;
    waitpid(child, &status, 0);
    remove_dir();
    return ret;
  } else {
    assert(child == 0);
    test_logscan();
    test_purge();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<y162uyvy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,%ebx
  mov    -0x38(%rbp),%rax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,%r12d
  jmp    L3
L9:
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%r14d
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  lea    (%r14,%rax,1),%edx
  mov    -0x3c(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%r14d
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%r13d
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  lea    0x0(%r13,%rax,1),%edx
  mov    -0x3c(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%r13d
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %r14d,%edx
  mov    %dl,(%rax)
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x80,(%rax)
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %r13d,%edx
  mov    %dl,(%rax)
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x80,(%rax)
L3:
  test   %ebx,%ebx
  jg     L9
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
void y162uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y1 = (y1 + (((int)src[i--]) << 8)) >> (bits - 8);
    y0 = src[i--];
    y0 = (y0 + (((int)src[i--]) << 8)) >> (bits - 8);
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
    dest[j--] = 128;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<y162uyvy>:
  endbr64
  mov    %rsi,%r8
  lea    -0x1(%rdx,%rdx,1),%eax
  test   %eax,%eax
  jle    L18
  cltq
  sub    $0x8,%ecx
L6:
  movzbl -0x1(%rdi,%rax,1),%esi
  shl    $0x8,%esi
  movzbl (%rdi,%rax,1),%edx
  add    %edx,%esi
  movzbl -0x3(%rdi,%rax,1),%edx
  shl    $0x8,%edx
  movzbl -0x2(%rdi,%rax,1),%r9d
  add    %r9d,%edx
  sar    %cl,%esi
  mov    %sil,(%r8,%rax,1)
  movb   $0x80,-0x1(%r8,%rax,1)
  sar    %cl,%edx
  mov    %dl,-0x2(%r8,%rax,1)
  movb   $0x80,-0x3(%r8,%rax,1)
  sub    $0x4,%rax
  test   %eax,%eax
  jg     L6
L18:
  ret
```

assistant: ```c
void y162uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y1 = (y1 + (((int)src[i--]) << 8)) >> (bits - 8);
    y0 = src[i--];
    y0 = (y0 + (((int)src[i--]) << 8)) >> (bits - 8);
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
    dest[j--] = 128;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<y162uyvy>:
  endbr64
  lea    -0x1(%rdx,%rdx,1),%edx
  mov    %rdi,%r8
  sub    $0x8,%ecx
  mov    %rsi,%rdi
  movslq %edx,%rax
  test   %edx,%edx
  jle    L1
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl -0x1(%r8,%rax,1),%esi
  movzbl (%r8,%rax,1),%edx
  movzbl -0x2(%r8,%rax,1),%r9d
  shl    $0x8,%esi
  add    %edx,%esi
  movzbl -0x3(%r8,%rax,1),%edx
  movb   $0x80,-0x1(%rdi,%rax,1)
  sar    %cl,%esi
  movb   $0x80,-0x3(%rdi,%rax,1)
  shl    $0x8,%edx
  mov    %sil,(%rdi,%rax,1)
  add    %r9d,%edx
  sar    %cl,%edx
  mov    %dl,-0x2(%rdi,%rax,1)
  sub    $0x4,%rax
  test   %eax,%eax
  jg     L12
L1:
  ret
```

assistant: ```c
void y162uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y1 = (y1 + (((int)src[i--]) << 8)) >> (bits - 8);
    y0 = src[i--];
    y0 = (y0 + (((int)src[i--]) << 8)) >> (bits - 8);
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
    dest[j--] = 128;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<y162uyvy>:
  endbr64
  lea    -0x1(%rdx,%rdx,1),%edx
  mov    %rdi,%r8
  sub    $0x8,%ecx
  mov    %rsi,%rdi
  movslq %edx,%rax
  test   %edx,%edx
  jle    L4
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl -0x1(%r8,%rax,1),%esi
  movzbl (%r8,%rax,1),%edx
  movzbl -0x2(%r8,%rax,1),%r9d
  shl    $0x8,%esi
  add    %edx,%esi
  movzbl -0x3(%r8,%rax,1),%edx
  movb   $0x80,-0x1(%rdi,%rax,1)
  sar    %cl,%esi
  movb   $0x80,-0x3(%rdi,%rax,1)
  shl    $0x8,%edx
  mov    %sil,(%rdi,%rax,1)
  add    %r9d,%edx
  sar    %cl,%edx
  mov    %dl,-0x2(%rdi,%rax,1)
  sub    $0x4,%rax
  test   %eax,%eax
  jg     L18
L4:
  ret
```

assistant: ```c
void y162uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1;
  while (i > 0) {
    y1 = src[i--];
    y1 = (y1 + (((int)src[i--]) << 8)) >> (bits - 8);
    y0 = src[i--];
    y0 = (y0 + (((int)src[i--]) << 8)) >> (bits - 8);
    dest[j--] = y1;
    dest[j--] = 128;
    dest[j--] = y0;
    dest[j--] = 128;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getcelltype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0xc,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  sar    %eax
  xor    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L10
  mov    $0x5,%eax
  jmp    L2
L10:
  mov    $0x0,%eax
L2:
  add    %edx,%eax
  add    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int getcelltype(int flag) {
  int temp = flag >> 12;
  return (temp >> 2) * 2 + temp % 2 + ((temp & 1) != ((temp >> 1) & 1)) * 5 + 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getcelltype>:
  endbr64
  mov    %edi,%edx
  sar    $0xc,%edx
  mov    %edi,%esi
  sar    $0xe,%esi
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  lea    (%rax,%rsi,2),%eax
  sar    $0xd,%edi
  xor    %edx,%edi
  and    $0x1,%edi
  mov    $0x5,%edx
  cmovne %edx,%edi
  lea    0x2(%rax,%rdi,1),%eax
  ret
```

assistant: ```c
int getcelltype(int flag) {
  int temp = flag >> 12;
  return (temp >> 2) * 2 + temp % 2 + ((temp & 1) != ((temp >> 1) & 1)) * 5 + 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getcelltype>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  mov    %edi,%esi
  sar    $0xd,%edi
  sar    $0xc,%edx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  sar    $0xe,%esi
  xor    %edx,%edi
  and    $0x1,%eax
  sub    %ecx,%eax
  and    $0x1,%edi
  lea    (%rax,%rsi,2),%eax
  lea    0x5(%rax),%edx
  cmovne %edx,%eax
  add    $0x2,%eax
  ret
```

assistant: ```c
int getcelltype(int flag) {
  int temp = flag >> 12;
  return (temp >> 2) * 2 + temp % 2 + ((temp & 1) != ((temp >> 1) & 1)) * 5 + 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getcelltype>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  mov    %edi,%esi
  sar    $0xd,%edi
  sar    $0xc,%edx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  sar    $0xe,%esi
  xor    %edx,%edi
  and    $0x1,%eax
  sub    %ecx,%eax
  and    $0x1,%edi
  lea    (%rax,%rsi,2),%eax
  lea    0x5(%rax),%edx
  cmovne %edx,%eax
  add    $0x2,%eax
  ret
```

assistant: ```c
int getcelltype(int flag) {
  int temp = flag >> 12;
  return (temp >> 2) * 2 + temp % 2 + ((temp & 1) != ((temp >> 1) & 1)) * 5 + 2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <iothub_client_sample_amqp_websockets_run@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  iothub_client_sample_amqp_websockets_run();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <iothub_client_sample_amqp_websockets_run@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  iothub_client_sample_amqp_websockets_run();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <iothub_client_sample_amqp_websockets_run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  iothub_client_sample_amqp_websockets_run();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <iothub_client_sample_amqp_websockets_run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  iothub_client_sample_amqp_websockets_run();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<file_perm_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L4
  mov    $0x0,%eax
  jmp    L25
L4:
  mov    -0x4(%rbp),%eax
  not    %eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L15
  mov    $0x1,%eax
  jmp    L25
L15:
  mov    $0xffffffff,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int file_perm_compare(unsigned long a, unsigned long b) {
  int fperm = (int)a;
  int bperm = (int)b;
  if (fperm == bperm)
    return 0;
  return (fperm & (~bperm)) ? 1 : -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<file_perm_compare>:
  endbr64
  mov    $0x0,%eax
  cmp    %esi,%edi
  je     L0
  not    %esi
  and    %edi,%esi
  cmp    $0x1,%esi
  sbb    %eax,%eax
  or     $0x1,%eax
L0:
  ret
```

assistant: ```c
int file_perm_compare(unsigned long a, unsigned long b) {
  int fperm = (int)a;
  int bperm = (int)b;
  if (fperm == bperm)
    return 0;
  return (fperm & (~bperm)) ? 1 : -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<file_perm_compare>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  je     L0
  not    %esi
  and    %edi,%esi
  cmp    $0x1,%esi
  sbb    %eax,%eax
  or     $0x1,%eax
L0:
  ret
```

assistant: ```c
int file_perm_compare(unsigned long a, unsigned long b) {
  int fperm = (int)a;
  int bperm = (int)b;
  if (fperm == bperm)
    return 0;
  return (fperm & (~bperm)) ? 1 : -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<file_perm_compare>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  je     L5
  not    %esi
  and    %edi,%esi
  cmp    $0x1,%esi
  sbb    %eax,%eax
  or     $0x1,%eax
L5:
  ret
```

assistant: ```c
int file_perm_compare(unsigned long a, unsigned long b) {
  int fperm = (int)a;
  int bperm = (int)b;
  if (fperm == bperm)
    return 0;
  return (fperm & (~bperm)) ? 1 : -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rpl_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L22
L6:
  cmpq   $0x0,-0x10(%rbp)
  jne    L30
  cmpq   $0x0,-0x8(%rbp)
  je     L43
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L43:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L22
L30:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L22:
  leave
  ret
```

assistant: ```c
void *rpl_realloc(void *ptr, size_t size) {
  if (!ptr)
    return malloc(size);
  if (!size) {
    if (ptr)
      free(ptr);
    return malloc(size);
  }
  return realloc(ptr, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rpl_realloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L29
  test   %rsi,%rsi
  je     L22
  call   <realloc@plt>
L25:
  add    $0x8,%rsp
  ret
L29:
  mov    %rsi,%rdi
  call   <malloc@plt>
  jmp    L25
L22:
  call   <free@plt>
  mov    $0x0,%edi
  call   <malloc@plt>
  jmp    L25
```

assistant: ```c
void *rpl_realloc(void *ptr, size_t size) {
  if (!ptr)
    return malloc(size);
  if (!size) {
    if (ptr)
      free(ptr);
    return malloc(size);
  }
  return realloc(ptr, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rpl_realloc>:
  endbr64
  test   %rdi,%rdi
  je     L9
  test   %rsi,%rsi
  je     L18
  jmp    1090 <realloc@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <malloc@plt>
  nopl   0x0(%rax)
L9:
  mov    %rsi,%rdi
  jmp    1080 <malloc@plt>
```

assistant: ```c
void *rpl_realloc(void *ptr, size_t size) {
  if (!ptr)
    return malloc(size);
  if (!size) {
    if (ptr)
      free(ptr);
    return malloc(size);
  }
  return realloc(ptr, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rpl_realloc>:
  endbr64
  test   %rdi,%rdi
  je     L9
  test   %rsi,%rsi
  je     L14
  jmp    1090 <realloc@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <malloc@plt>
  nopl   0x0(%rax)
L9:
  mov    %rsi,%rdi
  jmp    1080 <malloc@plt>
```

assistant: ```c
void *rpl_realloc(void *ptr, size_t size) {
  if (!ptr)
    return malloc(size);
  if (!size) {
    if (ptr)
      free(ptr);
    return malloc(size);
  }
  return realloc(ptr, size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<roundfnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L18
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x4(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <roundf@plt>
  jmp    L18
L18:
  leave
  ret
```

assistant: ```c
float roundfnd(float number, int digit) {
  int N = pow(10, digit);
  if (digit > 0) {
    return roundf((number * N) / N);
  } else {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<roundfnd>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %edi,%ebx
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  test   %ebx,%ebx
  jg     L7
L5:
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  0xc(%rsp),%xmm0
  mulss  %xmm1,%xmm0
  divss  %xmm1,%xmm0
  call   <roundf@plt>
  jmp    L5
```

assistant: ```c
float roundfnd(float number, int digit) {
  int N = pow(10, digit);
  if (digit > 0) {
    return roundf((number * N) / N);
  } else {
  }
}
```