ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<go_backward>:
  endbr64
  movzbl (%rcx),%r8d
  mov    %r8d,%eax
  sub    %edi,%eax
  cmp    %edi,%r8d
  jge    L3
  subq   $0x1,(%rsi)
  addw   $0x1,(%rdx)
  movzbl (%rcx),%eax
  sub    %edi,%eax
  add    $0x8,%eax
L3:
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void go_backward(int num_bits, unsigned char **data, unsigned short *len, unsigned char *bitpos) {
  if (*bitpos >= num_bits)
    *bitpos -= num_bits;
  else {
    (*data)--;
    (*len)++;
    *bitpos = 8 - (num_bits - *bitpos);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<go_backward>:
  endbr64
  movzbl (%rcx),%r8d
  mov    %r8d,%eax
  sub    %edi,%eax
  cmp    %edi,%r8d
  jge    L0
  subq   $0x1,(%rsi)
  addw   $0x1,(%rdx)
  movzbl (%rcx),%eax
  sub    %edi,%eax
  add    $0x8,%eax
L0:
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void go_backward(int num_bits, unsigned char **data, unsigned short *len, unsigned char *bitpos) {
  if (*bitpos >= num_bits)
    *bitpos -= num_bits;
  else {
    (*data)--;
    (*len)++;
    *bitpos = 8 - (num_bits - *bitpos);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <setrlimit@plt>
  test   %rax,%rax
  je     L3
  mov    $0x8f,%edx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x7,%edi
  call   <shutdown@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: setrlimit()

assistant: ```c
void setr(int type, struct rlimit *rlim) {
  if (setrlimit(type, rlim))
    shutdown(7, "setrlimit()", 144 - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setr>:
  endbr64
  sub    $0x8,%rsp
  call   <setrlimit@plt>
  test   %rax,%rax
  jne    L18
L14:
  add    $0x8,%rsp
  ret
L18:
  mov    $0x8f,%edx
  lea    D2(%rip),%rsi
  mov    $0x7,%edi
  call   <shutdown@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: setrlimit()

assistant: ```c
void setr(int type, struct rlimit *rlim) {
  if (setrlimit(type, rlim))
    shutdown(7, "setrlimit()", 144 - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setr>:
  endbr64
  sub    $0x8,%rsp
  call   <setrlimit@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x8f,%edx
  lea    D1(%rip),%rsi
  mov    $0x7,%edi
  add    $0x8,%rsp
  jmp    1060 <shutdown@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: setrlimit()

assistant: ```c
void setr(int type, struct rlimit *rlim) {
  if (setrlimit(type, rlim))
    shutdown(7, "setrlimit()", 144 - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setr>:
  endbr64
  sub    $0x8,%rsp
  call   <setrlimit@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x8f,%edx
  lea    D6(%rip),%rsi
  mov    $0x7,%edi
  add    $0x8,%rsp
  jmp    1060 <shutdown@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: setrlimit()

assistant: ```c
void setr(int type, struct rlimit *rlim) {
  if (setrlimit(type, rlim))
    shutdown(7, "setrlimit()", 144 - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_leastBitPos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L29
L9:
  shll   -0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L9
  mov    -0x4(%rbp),%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int test_leastBitPos(int x) {
  int mask = 1;
  if (x == 0)
    return 0;
  while (!(mask & x)) {
    mask = mask << 1;
  }
  return mask;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_leastBitPos>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L29
  and    $0x1,%eax
  jne    L29
  mov    $0x1,%eax
L22:
  add    %eax,%eax
  test   %eax,%edi
  je     L22
L29:
  ret
```

assistant: ```c
int test_leastBitPos(int x) {
  int mask = 1;
  if (x == 0)
    return 0;
  while (!(mask & x)) {
    mask = mask << 1;
  }
  return mask;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_leastBitPos>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L14
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L14
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    %eax,%eax
  test   %eax,%edi
  je     L18
L14:
  ret
```

assistant: ```c
int test_leastBitPos(int x) {
  int mask = 1;
  if (x == 0)
    return 0;
  while (!(mask & x)) {
    mask = mask << 1;
  }
  return mask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_leastBitPos>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L13
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L13
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L24:
  add    %eax,%eax
  test   %eax,%edi
  je     L24
L13:
  ret
```

assistant: ```c
int test_leastBitPos(int x) {
  int mask = 1;
  if (x == 0)
    return 0;
  while (!(mask & x)) {
    mask = mask << 1;
  }
  return mask;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdup_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strdup_vprintf@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup_printf(const char *format, ...) {
  char *buffer;
  va_list ap;
  va_start(ap, format);
  buffer = strdup_vprintf(format, ap);
  va_end(ap);
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdup_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <strdup_vprintf@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdup_printf(const char *format, ...) {
  char *buffer;
  va_list ap;
  va_start(ap, format);
  buffer = strdup_vprintf(format, ap);
  va_end(ap);
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strdup_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <strdup_vprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup_printf(const char *format, ...) {
  char *buffer;
  va_list ap;
  va_start(ap, format);
  buffer = strdup_vprintf(format, ap);
  va_end(ap);
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strdup_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <strdup_vprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup_printf(const char *format, ...) {
  char *buffer;
  va_list ap;
  va_start(ap, format);
  buffer = strdup_vprintf(format, ap);
  va_end(ap);
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__get_one_smt_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <__sysattr_is_readable@plt>
  test   %eax,%eax
  jne    L6
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xfffffffe,%eax
  jmp    L13
L6:
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L10:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <cpu_online@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  mov    -0xc(%rbp),%eax
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D6: online

tool: D1: Cannot retrieve smt state

assistant: ```c
int __get_one_smt_state(int core, int threads_per_cpu) {
  int primary_thread = core * threads_per_cpu;
  int smt_state = 0;
  int i;
  if (!__sysattr_is_readable("online", threads_per_cpu)) {
    perror("Cannot retrieve smt state");
    return -2;
  }
  for (i = 0; i < threads_per_cpu; i++) {
    smt_state += cpu_online(primary_thread + i);
  }
  return smt_state;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__get_one_smt_state>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  imul   %esi,%edi
  mov    %edi,%r12d
  lea    D18(%rip),%rdi
  call   <__sysattr_is_readable@plt>
  test   %eax,%eax
  je     L38
  mov    %r12d,%ebx
  add    %r13d,%r12d
  mov    $0x0,%ebp
  test   %r13d,%r13d
  jle    L5
L8:
  mov    %ebx,%edi
  call   <cpu_online@plt>
  add    %eax,%ebp
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L8
L5:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  lea    D19(%rip),%rdi
  call   <perror@plt>
  mov    $0xfffffffe,%ebp
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string

tool: D18: online

tool: D19: Cannot retrieve smt state

assistant: ```c
int __get_one_smt_state(int core, int threads_per_cpu) {
  int primary_thread = core * threads_per_cpu;
  int smt_state = 0;
  int i;
  if (!__sysattr_is_readable("online", threads_per_cpu)) {
    perror("Cannot retrieve smt state");
    return -2;
  }
  for (i = 0; i < threads_per_cpu; i++) {
    smt_state += cpu_online(primary_thread + i);
  }
  return smt_state;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__get_one_smt_state>:
  endbr64
  push   %r13
  imul   %esi,%edi
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D11(%rip),%rdi
  sub    $0x8,%rsp
  call   <__sysattr_is_readable@plt>
  test   %eax,%eax
  je     L38
  lea    0x0(%r13,%rbx,1),%ebp
  xor    %r12d,%r12d
  test   %r13d,%r13d
  jle    L27
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <cpu_online@plt>
  add    %eax,%r12d
  cmp    %ebp,%ebx
  jne    L13
L27:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  lea    D16(%rip),%rdi
  mov    $0xfffffffe,%r12d
  call   <perror@plt>
  jmp    L27
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string

tool: D11: online

tool: D16: Cannot retrieve smt state

assistant: ```c
int __get_one_smt_state(int core, int threads_per_cpu) {
  int primary_thread = core * threads_per_cpu;
  int smt_state = 0;
  int i;
  if (!__sysattr_is_readable("online", threads_per_cpu)) {
    perror("Cannot retrieve smt state");
    return -2;
  }
  for (i = 0; i < threads_per_cpu; i++) {
    smt_state += cpu_online(primary_thread + i);
  }
  return smt_state;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__get_one_smt_state>:
  endbr64
  push   %r13
  imul   %esi,%edi
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <__sysattr_is_readable@plt>
  test   %eax,%eax
  je     L33
  lea    0x0(%r13,%rbx,1),%ebp
  xor    %r12d,%r12d
  test   %r13d,%r13d
  jle    L3
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <cpu_online@plt>
  add    %eax,%r12d
  cmp    %ebp,%ebx
  jne    L19
L3:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  lea    D5(%rip),%rdi
  mov    $0xfffffffe,%r12d
  call   <perror@plt>
  jmp    L3
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D5
data_type: string

tool: D13: online

tool: D5: Cannot retrieve smt state

assistant: ```c
int __get_one_smt_state(int core, int threads_per_cpu) {
  int primary_thread = core * threads_per_cpu;
  int smt_state = 0;
  int i;
  if (!__sysattr_is_readable("online", threads_per_cpu)) {
    perror("Cannot retrieve smt state");
    return -2;
  }
  for (i = 0; i < threads_per_cpu; i++) {
    smt_state += cpu_online(primary_thread + i);
  }
  return smt_state;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<half2single>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  sar    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0xa,%eax
  and    $0x1f,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L29
  movl   $0xffffff90,-0x10(%rbp)
L29:
  cmpl   $0x1f,-0x10(%rbp)
  jne    L37
  mov    -0x24(%rbp),%eax
  and    $0x3ff,%eax
  test   %eax,%eax
  je     L43
  movl   $0x7fc00000,-0x14(%rbp)
  jmp    L47
L43:
  cmpl   $0x0,-0xc(%rbp)
  je     L4
  mov    $0xff800000,%eax
  jmp    L10
L4:
  mov    $0x7f800000,%eax
L10:
  mov    %eax,-0x14(%rbp)
  jmp    L47
L37:
  mov    -0xc(%rbp),%eax
  shl    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    $0x70,%eax
  shl    $0x17,%eax
  or     %eax,%edx
  mov    -0x24(%rbp),%eax
  shl    $0xd,%eax
  and    $0x7fe000,%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
L47:
  lea    -0x14(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

assistant: ```c
float half2single(uint16_t number) {
  uint32_t fp32;
  uint32_t s = number >> 15;
  uint32_t e = (number >> 10) & 0x01F;
  if (e == 0)
    e = 15 - 127;
  if (e == 0x1F) {
    if (number & 0x03FF)
      fp32 = 0x7FC00000;
    else
      fp32 = s ? 0xFF800000 : 0x7F800000;
  } else
    fp32 = (s << 31) | ((e + 127 - 15) << 23) | ((number & 0x3ff) << 13);
  return *(float *)&fp32;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<half2single>:
  endbr64
  mov    %edi,%edx
  sar    $0xf,%edx
  mov    %edi,%eax
  sar    $0xa,%eax
  and    $0x1f,%eax
  je     L35
  cmp    $0x1f,%eax
  jne    L16
  mov    $0x7fc00000,%eax
  test   $0x3ff,%edi
  jne    L2
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0x80000000,%eax
  sub    $0x800000,%eax
  jmp    L2
L35:
  mov    $0xffffff90,%eax
L16:
  shl    $0xd,%edi
  and    $0x7fe000,%edi
  shl    $0x1f,%edx
  or     %edx,%edi
  add    $0x70,%eax
  shl    $0x17,%eax
  or     %edi,%eax
L2:
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float half2single(uint16_t number) {
  uint32_t fp32;
  uint32_t s = number >> 15;
  uint32_t e = (number >> 10) & 0x01F;
  if (e == 0)
    e = 15 - 127;
  if (e == 0x1F) {
    if (number & 0x03FF)
      fp32 = 0x7FC00000;
    else
      fp32 = s ? 0xFF800000 : 0x7F800000;
  } else
    fp32 = (s << 31) | ((e + 127 - 15) << 23) | ((number & 0x3ff) << 13);
  return *(float *)&fp32;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<half2single>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0xa,%eax
  sar    $0xf,%edx
  and    $0x1f,%eax
  je     L21
  cmp    $0x1f,%eax
  je     L28
  add    $0x70,%eax
  shl    $0x17,%eax
L21:
  shl    $0xd,%edi
  shl    $0x1f,%edx
  and    $0x7fe000,%edi
  or     %edx,%edi
  or     %eax,%edi
  movd   %edi,%xmm0
L23:
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  and    $0x3ff,%edi
  movss  D28(%rip),%xmm0
  jne    L23
  movss  D1(%rip),%xmm0
  test   %edx,%edx
  jne    L23
  movss  D22(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_guessed: byte[4]
name: unpack_data
arguments: data_label: D1
type_guessed: byte[4]
name: unpack_data
arguments: data_label: D22
type_guessed: byte[4]

tool: {"D28": [0x00,0x00,0xc0,0x7f]}

tool: {"D1": [0x00,0x00,0x80,0xff]}

tool: {"D22": [0x00,0x00,0x80,0x7f]}

assistant: ```c
float half2single(uint16_t number) {
  uint32_t fp32;
  uint32_t s = number >> 15;
  uint32_t e = (number >> 10) & 0x01F;
  if (e == 0)
    e = 15 - 127;
  if (e == 0x1F) {
    if (number & 0x03FF)
      fp32 = 0x7FC00000;
    else
      fp32 = s ? 0xFF800000 : 0x7F800000;
  } else
    fp32 = (s << 31) | ((e + 127 - 15) << 23) | ((number & 0x3ff) << 13);
  return *(float *)&fp32;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<half2single>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0xa,%eax
  sar    $0xf,%edx
  and    $0x1f,%eax
  je     L1
  cmp    $0x1f,%eax
  je     L3
  add    $0x70,%eax
  shl    $0x17,%eax
L1:
  shl    $0xd,%edi
  shl    $0x1f,%edx
  and    $0x7fe000,%edi
  or     %edx,%edi
  or     %eax,%edi
  movd   %edi,%xmm0
L8:
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  and    $0x3ff,%edi
  movss  D9(%rip),%xmm0
  jne    L8
  movss  D12(%rip),%xmm0
  test   %edx,%edx
  jne    L8
  movss  D3(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: byte[4]
name: unpack_data
arguments: tag: D12
type: byte[4]
name: unpack_data
arguments: tag: D3
type: byte[4]

tool: {"D9": [0x00,0x00,0xc0,0x7f]}

tool: {"D12": [0x00,0x00,0x80,0xff]}

tool: {"D3": [0x00,0x00,0x80,0x7f]}

assistant: ```c
float half2single(uint16_t number) {
  uint32_t fp32;
  uint32_t s = number >> 15;
  uint32_t e = (number >> 10) & 0x01F;
  if (e == 0)
    e = 15 - 127;
  if (e == 0x1F) {
    if (number & 0x03FF)
      fp32 = 0x7FC00000;
    else
      fp32 = s ? 0xFF800000 : 0x7F800000;
  } else
    fp32 = (s << 31) | ((e + 127 - 15) << 23) | ((number & 0x3ff) << 13);
  return *(float *)&fp32;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deckbum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <sm@plt>
  jmp    L14
L1:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <rm@plt>
L14:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: ?68

assistant: ```c
void deckbum(int flag) {
  if (flag)
    sm("?68");
  else
    rm("?68");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deckbum>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L14
  lea    D8(%rip),%rdi
  call   <sm@plt>
L11:
  add    $0x8,%rsp
  ret
L14:
  lea    D8(%rip),%rdi
  call   <rm@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: ?68

assistant: ```c
void deckbum(int flag) {
  if (flag)
    sm("?68");
  else
    rm("?68");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deckbum>:
  endbr64
  test   %edi,%edi
  lea    D3(%rip),%rdi
  je     L9
  jmp    1070 <sm@plt>
  nopl   0x0(%rax)
L9:
  jmp    1060 <rm@plt>
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: ?68

assistant: ```c
void deckbum(int flag) {
  if (flag)
    sm("?68");
  else
    rm("?68");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<deckbum>:
  endbr64
  test   %edi,%edi
  lea    D8(%rip),%rdi
  je     L0
  jmp    1070 <sm@plt>
  nopl   0x0(%rax)
L0:
  jmp    1060 <rm@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: ?68

assistant: ```c
void deckbum(int flag) {
  if (flag)
    sm("?68");
  else
    rm("?68");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<translate_unknown>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L82
  sub    $0x4,%eax
  mov    %r14d,%ebx
  lea    0x2(%r14),%rbp
  lea    0x3(%r14,%rax,1),%r12
  not    %ebx
  jmp    L78
L123:
  add    $0x1,%rbp
  cmp    %rbp,%r12
  je     L82
L78:
  movsbl -0x2(%rbp),%edi
  lea    (%rbx,%rbp,1),%r13d
  call   <is_consonant_not_r@plt>
  test   %rax,%rax
  je     L17
  cmpb   $0x72,-0x1(%rbp)
  je     L52
L17:
  movsbl -0x2(%rbp),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L123
  movsbl 0x0(%rbp),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L123
  movzbl -0x2(%rbp),%eax
  movzbl -0x1(%rbp),%edx
  cmp    $0x6e,%al
  je     L23
  cmp    $0x72,%al
  jne    L111
  cmpb   $0x6e,0x0(%rbp)
  je     L114
L111:
  cmp    $0x6e,%dl
  jne    L123
L152:
  lea    -0x1(%r13),%ecx
  xor    %eax,%eax
  lea    D6(%rip),%r12
  nopl   (%rax)
L92:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L92
  movb   $0x0,0x1(%r12,%rcx,1)
  mov    %r12,%rdi
  call   <translate_lujvo@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D2(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D23(%rip),%rsi
  call   <strcat@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  movsbl 0x0(%rbp),%edi
  call   <is_consonant_not_r@plt>
  test   %rax,%rax
  je     L17
  jmp    L152
  nopw   0x0(%rax,%rax,1)
L23:
  cmpb   $0x72,0x0(%rbp)
  jne    L111
L114:
  cmp    $0x6c,%dl
  jne    L111
  jmp    L152
  nopl   0x0(%rax,%rax,1)
L82:
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <translate_lujvo@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D23
datatype: string

tool: D2: -[

tool: D23: ]

assistant: ```c
char *translate_unknown(char *w) {
  static char buf[2048];
  int len, i;
  int hyph;
  char *p, *q;
  char *ltrans;
  len = strlen(w);
  hyph = 0;
  for (i = 1; i < len - 2; i++) {
    if (is_consonant_not_r(w[i - 1]) && (w[i] == 'r') && is_consonant_not_r(w[i + 1])) {
      hyph = i;
      break;
    }
    if (is_consonant(w[i - 1]) && is_consonant(w[i + 1])) {
      if ((w[i - 1] == 'n') && (w[i + 1] == 'r') && (w[i] == 'l')) {
        hyph = i;
        break;
      } else if ((w[i - 1] == 'r') && (w[i + 1] == 'n') && (w[i] == 'l')) {
        hyph = i;
        break;
      } else if (w[i] == 'n') {
        hyph = i;
        break;
      }
    }
  }
  if (hyph) {
    for (p = w, q = buf, i = 0; i < hyph; p++, q++, i++) {
      *q = *p;
    }
    *q = 0;
    ltrans = translate_lujvo(buf);
    strcpy(buf, ltrans);
    strcat(buf, "-[");
    strcat(buf, w + hyph + 1);
    strcat(buf, "]");
    return buf;
  } else {
    return translate_lujvo(w);
  }
}
```