ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<destroy_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <constructs_destroy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int destroy_tests(void) {
  constructs_destroy();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<destroy_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <constructs_destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int destroy_tests(void) {
  constructs_destroy();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <constructs_destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int destroy_tests(void) {
  constructs_destroy();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L49
  mov    $0x1,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L49:
  movl   $0x0,-0x1c(%rbp)
  jmp    L41
L42:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L41:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L42
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x4cf7fc78,%eax
  jne    L25
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L25:
  movl   $0x0,-0x18(%rbp)
  jmp    L35
L32:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L35:
  cmpl   $0x0,-0x18(%rbp)
  jle    L32
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D4: Call this program with %i arguments


tool: D26: You win!

tool: D9: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1291320440U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L35
L31:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x4cf7fc78,0x4(%rsp)
  je     L30
L39:
  mov    0x4(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L31
L30:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L39
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D29
type: string

tool: D10: %u


tool: D4: Call this program with %i arguments


tool: D29: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1291320440U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L31
  lea    D29(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L31:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x4cf7fc78,%esi
  je     L11
L36:
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L36
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D29: Call this program with %i arguments


tool: D21: %u


tool: D4: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1291320440U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L0
  lea    D4(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L0:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x4cf7fc78,%esi
  je     L27
L37:
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L37
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string

tool: D4: Call this program with %i arguments


tool: D14: %u


tool: D22: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1291320440U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<chooseRegs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,(%rdx)
L58:
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L58
L52:
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L52
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L52
L54:
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L54
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L54
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L54
  nop
  nop
  leave
  ret
```

assistant: ```c
void chooseRegs(int *r1, int *r2, int *r3, int *r4) {
  *r1 = chooseReg();
  do {
    *r2 = chooseReg();
  } while (*r2 == *r1);
  do {
    *r3 = chooseReg();
  } while (*r3 == *r2 || *r3 == *r1);
  do {
    *r4 = chooseReg();
  } while (*r4 == *r3 || *r4 == *r2 || *r4 == *r1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chooseRegs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    %eax,(%r12)
L32:
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    %eax,(%rbx)
  cmp    (%r12),%eax
  je     L32
L29:
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    %eax,0x0(%rbp)
  cmp    (%rbx),%eax
  je     L29
  cmp    (%r12),%eax
  je     L29
L38:
  mov    $0x0,%eax
  call   <chooseReg@plt>
  mov    %eax,0x0(%r13)
  cmp    0x0(%rbp),%eax
  je     L38
  cmp    (%rbx),%eax
  je     L38
  cmp    (%r12),%eax
  je     L38
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void chooseRegs(int *r1, int *r2, int *r3, int *r4) {
  *r1 = chooseReg();
  do {
    *r2 = chooseReg();
  } while (*r2 == *r1);
  do {
    *r3 = chooseReg();
  } while (*r3 == *r2 || *r3 == *r1);
  do {
    *r4 = chooseReg();
  } while (*r4 == *r3 || *r4 == *r2 || *r4 == *r1);
}
```
user: What is the c source code of the assembly code below?

```asm
<chooseRegs>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <chooseReg@plt>
  mov    %eax,(%r12)
  nopl   (%rax)
L51:
  xor    %eax,%eax
  call   <chooseReg@plt>
  mov    %eax,(%rbx)
  cmp    (%r12),%eax
  je     L51
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <chooseReg@plt>
  mov    %eax,0x0(%rbp)
  cmp    (%rbx),%eax
  je     L7
  cmp    (%r12),%eax
  je     L7
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  call   <chooseReg@plt>
  mov    %eax,0x0(%r13)
  cmp    0x0(%rbp),%eax
  je     L42
  cmp    (%rbx),%eax
  je     L42
  cmp    (%r12),%eax
  je     L42
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void chooseRegs(int *r1, int *r2, int *r3, int *r4) {
  *r1 = chooseReg();
  do {
    *r2 = chooseReg();
  } while (*r2 == *r1);
  do {
    *r3 = chooseReg();
  } while (*r3 == *r2 || *r3 == *r1);
  do {
    *r4 = chooseReg();
  } while (*r4 == *r3 || *r4 == *r2 || *r4 == *r1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<chooseRegs>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <chooseReg@plt>
  mov    %eax,(%r12)
  nopl   (%rax)
L39:
  xor    %eax,%eax
  call   <chooseReg@plt>
  mov    %eax,(%rbx)
  cmp    (%r12),%eax
  je     L39
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  call   <chooseReg@plt>
  mov    %eax,0x0(%rbp)
  cmp    (%rbx),%eax
  je     L37
  cmp    (%r12),%eax
  je     L37
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
  call   <chooseReg@plt>
  mov    %eax,0x0(%r13)
  cmp    0x0(%rbp),%eax
  je     L41
  cmp    (%rbx),%eax
  je     L41
  cmp    (%r12),%eax
  je     L41
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void chooseRegs(int *r1, int *r2, int *r3, int *r4) {
  *r1 = chooseReg();
  do {
    *r2 = chooseReg();
  } while (*r2 == *r1);
  do {
    *r3 = chooseReg();
  } while (*r3 == *r2 || *r3 == *r1);
  do {
    *r4 = chooseReg();
  } while (*r4 == *r3 || *r4 == *r2 || *r4 == *r1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putSubstr0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    $0x1,%r8d
  mov    %rax,%rdi
  call   <getBuckets@plt>
  movq   $0x0,-0x18(%rbp)
  jmp    L39
L9:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jl     L9
  movq   $0x0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  sub    $0x2,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L57
L76:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jb     L26
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L38
  cmpq   $0x1,-0x10(%rbp)
  jne    L38
L26:
  mov    $0x1,%eax
  jmp    L29
L38:
  mov    $0x0,%eax
L29:
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L44
  cmpq   $0x1,-0x10(%rbp)
  jne    L44
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x1(%rdx),%rcx
  mov    %rcx,(%rax)
  mov    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
L44:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L57:
  cmpq   $0x0,-0x18(%rbp)
  jg     L76
  mov    -0x40(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void putSubstr0(long *SA, unsigned char *s, long *bkt, long n, long K) {
  long i, cur_t, succ_t;
  getBuckets(s, bkt, n, K, 1);
  for (i = 0; i < n; i++)
    SA[i] = 0;
  succ_t = 0;
  for (i = n - 2; i > 0; i--) {
    cur_t = (s[i - 1] < s[i] || (s[i - 1] == s[i] && succ_t == 1)) ? 1 : 0;
    if (cur_t == 0 && succ_t == 1)
      SA[bkt[s[i]]--] = i;
    succ_t = cur_t;
  }
  SA[0] = n - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putSubstr0>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    %r8,%rcx
  mov    $0x1,%r8d
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <getBuckets@plt>
  test   %rbp,%rbp
  jle    L67
  mov    %r12,%rax
  lea    (%r12,%rbp,8),%rdx
L86:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L86
L67:
  lea    -0x2(%rbp),%rax
  test   %rax,%rax
  jle    L48
  mov    $0x0,%esi
  mov    $0x1,%r8d
  mov    $0x0,%edi
  jmp    L10
L12:
  mov    %r8,%rsi
L54:
  sub    $0x1,%rax
  je     L48
L10:
  movzbl -0x1(%rbx,%rax,1),%ecx
  movzbl (%rbx,%rax,1),%edx
  cmp    %dl,%cl
  jb     L12
  mov    %esi,%r9d
  sete   %cl
  and    %r9d,%ecx
  movzbl %cl,%esi
  test   %cl,%cl
  jne    L54
  test   %r9b,%r9b
  je     L54
  movzbl %dl,%edx
  lea    0x0(%r13,%rdx,8),%rcx
  mov    (%rcx),%rdx
  lea    -0x1(%rdx),%rsi
  mov    %rsi,(%rcx)
  mov    %rax,(%r12,%rdx,8)
  mov    %rdi,%rsi
  jmp    L54
L48:
  sub    $0x1,%rbp
  mov    %rbp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void putSubstr0(long *SA, unsigned char *s, long *bkt, long n, long K) {
  long i, cur_t, succ_t;
  getBuckets(s, bkt, n, K, 1);
  for (i = 0; i < n; i++)
    SA[i] = 0;
  succ_t = 0;
  for (i = n - 2; i > 0; i--) {
    cur_t = (s[i - 1] < s[i] || (s[i - 1] == s[i] && succ_t == 1)) ? 1 : 0;
    if (cur_t == 0 && succ_t == 1)
      SA[bkt[s[i]]--] = i;
    succ_t = cur_t;
  }
  SA[0] = n - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<putSubstr0>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  mov    %r8,%rcx
  mov    $0x1,%r8d
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <getBuckets@plt>
  test   %rbp,%rbp
  jle    L13
  lea    0x0(,%rbp,8),%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L13:
  lea    -0x2(%rbp),%rax
  test   %rax,%rax
  jle    L23
  xor    %ecx,%ecx
  jmp    L12
  nopl   (%rax)
L39:
  jne    L50
  test   %rcx,%rcx
  jne    L37
L28:
  sub    $0x1,%rax
  je     L23
L12:
  movzbl (%rbx,%rax,1),%edx
  cmp    %dl,-0x1(%rbx,%rax,1)
  jae    L39
L37:
  mov    $0x1,%ecx
  sub    $0x1,%rax
  jne    L12
L23:
  sub    $0x1,%rbp
  mov    %rbp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L50:
  test   %rcx,%rcx
  je     L28
  lea    0x0(%r13,%rdx,8),%rcx
  mov    (%rcx),%rdx
  lea    -0x1(%rdx),%rsi
  mov    %rsi,(%rcx)
  xor    %ecx,%ecx
  mov    %rax,(%r12,%rdx,8)
  jmp    L28
```

assistant: ```c
void putSubstr0(long *SA, unsigned char *s, long *bkt, long n, long K) {
  long i, cur_t, succ_t;
  getBuckets(s, bkt, n, K, 1);
  for (i = 0; i < n; i++)
    SA[i] = 0;
  succ_t = 0;
  for (i = n - 2; i > 0; i--) {
    cur_t = (s[i - 1] < s[i] || (s[i - 1] == s[i] && succ_t == 1)) ? 1 : 0;
    if (cur_t == 0 && succ_t == 1)
      SA[bkt[s[i]]--] = i;
    succ_t = cur_t;
  }
  SA[0] = n - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<putSubstr0>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  mov    %r8,%rcx
  mov    $0x1,%r8d
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <getBuckets@plt>
  test   %rbp,%rbp
  jle    L99
  lea    0x0(,%rbp,8),%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L99:
  lea    -0x2(%rbp),%rax
  test   %rax,%rax
  jle    L31
  xor    %ecx,%ecx
  jmp    L22
  nopl   (%rax)
L2:
  jne    L90
  test   %rcx,%rcx
  jne    L96
L29:
  sub    $0x1,%rax
  je     L31
L22:
  movzbl (%rbx,%rax,1),%edx
  cmp    %dl,-0x1(%rbx,%rax,1)
  jae    L2
L96:
  mov    $0x1,%ecx
  sub    $0x1,%rax
  jne    L22
L31:
  sub    $0x1,%rbp
  mov    %rbp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L90:
  test   %rcx,%rcx
  je     L29
  lea    0x0(%r13,%rdx,8),%rcx
  mov    (%rcx),%rdx
  lea    -0x1(%rdx),%rsi
  mov    %rsi,(%rcx)
  xor    %ecx,%ecx
  mov    %rax,(%r12,%rdx,8)
  jmp    L29
```

assistant: ```c
void putSubstr0(long *SA, unsigned char *s, long *bkt, long n, long K) {
  long i, cur_t, succ_t;
  getBuckets(s, bkt, n, K, 1);
  for (i = 0; i < n; i++)
    SA[i] = 0;
  succ_t = 0;
  for (i = n - 2; i > 0; i--) {
    cur_t = (s[i - 1] < s[i] || (s[i - 1] == s[i] && succ_t == 1)) ? 1 : 0;
    if (cur_t == 0 && succ_t == 1)
      SA[bkt[s[i]]--] = i;
    succ_t = cur_t;
  }
  SA[0] = n - 1;
}
```