user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L3
L16:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L18
  lea    0x0(,%rax,4),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,0x8(%rsp)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,0x10(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rdx
  mov    $0x0,%eax
L74:
  add    $0x1,%eax
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  cmp    %ebp,%eax
  jne    L74
  mov    %ebp,%eax
  shl    $0x2,%rax
  mov    %rax,0x18(%rsp)
  lea    (%rbx,%rax,1),%r15
  mov    $0x0,%r12d
  lea    D35(%rip),%r14
L26:
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    (%rbx),%r12d
  add    $0x4,%rbx
  cmp    %rbx,%r15
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r13,%rcx
  mov    $0x0,%eax
L4:
  add    $0x1,%eax
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  cmp    %ebp,%eax
  jne    L4
  add    0x18(%rsp),%r13
  mov    $0x0,%eax
L9:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %r13,%rdx
  jne    L9
L35:
  mov    %eax,%edx
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L16
L18:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  lea    0x0(,%rbp,4),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%edx
  mov    %ebp,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L35
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
data_type: string
name: retrieve_data
arguments: data_tag: D26
data_type: string
name: retrieve_data
arguments: data_tag: D28
data_type: string
name: retrieve_data
arguments: data_tag: D30
data_type: string
name: retrieve_data
arguments: data_tag: D39
data_type: string

tool: D35: tid %d || 

tool: D26:   PARALLEL: The sum of the array [1,2,..,%d] is %d


tool: D28: SEQUENTIAL: The sum of the array [1,2,..,%d] is %d


tool: D30: Usage: ./arraysum <arraySize>

tool: D39: <arraySize> must be greater than 0

assistant: ```c
int main(int argc, char **argv) {
  int *array, i, size, sum = 0;
  int *array2;
  if (argc < 2) {
    printf("Usage: ./arraysum <arraySize>\n");
    exit(0);
  }
  if ((size = atoi(argv[1])) < 1) {
    printf("<arraySize> must be greater than 0\n");
    exit(0);
  }
  array = (int *)malloc(sizeof(int) * size);
  array2 = (int *)malloc(sizeof(int) * size);
  for (i = 0; i < size; i++)
    array[i] = i + 1;
  int tid;
#pragma omp parallel for num_threads(4) private(tid)
  for (i = 0; i < size; i++) {
    tid = omp_get_thread_num();
    printf("tid %d || ", tid);
    sum = sum + array[i];
  }
  printf("\n");
  printf("  PARALLEL: The sum of the array [1,2,..,%d] is %d\n", size, sum);
  sum = 0;
  for (i = 0; i < size; i++)
    array2[i] = i + 1;
  for (i = 0; i < size; i++) {
    sum += array2[i];
  }
  printf("SEQUENTIAL: The sum of the array [1,2,..,%d] is %d\n", size, sum);
  free(array);
  free(array2);
  return;
}
```