ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<socket_read_cb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdx,%r12
  mov    $0xfff,%edx
  mov    %r13,%rsi
  mov    %edi,%ebp
  call   <read@plt>
  test   %eax,%eax
  jle    L23
  cltq
  mov    %r13,%rsi
  lea    D30(%rip),%rdi
  movb   $0x0,(%rsp,%rax,1)
  xor    %eax,%eax
  lea    0x1000(%rsp),%r12
  call   <printf@plt>
  movdqa D36(%rip),%xmm0
  xor    %eax,%eax
  lea    0x1020(%rsp),%rdi
  mov    $0x1fc,%ecx
  rep stos %rax,%es:(%rdi)
  movaps %xmm0,0x1000(%rsp)
  mov    %r12,%rdi
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x1010(%rsp)
  call   <strlen@plt>
  mov    %r13,%rsi
  movslq %eax,%rdi
  add    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
L22:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x2010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <event_get_fd@plt>
  mov    %eax,%edi
  call   <close@plt>
  mov    %r12,%rdi
  call   <event_free@plt>
  jmp    L22
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
type_infered: string
name: retrieve_data
arguments: data_label: D36
type_infered: byte[16]
name: retrieve_data
arguments: data_label: D23
type_infered: byte[16]
name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D30: recv the client msg: %s

tool: {"D36": [0x49,0x20,0x68,0x61,0x76,0x65,0x20,0x72,0x65,0x63,0x76,0x69,0x65,0x63,0x65,0x64]}

tool: {"D23": [0x20,0x74,0x68,0x65,0x20,0x6d,0x73,0x67,0x3a,0x20,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D1: some error happen when read

assistant: ```c
void socket_read_cb(int fd, short events, void *arg) {
  char msg[4096];
  struct event *ev = (struct event *)arg;
  int len = read(fd, msg, sizeof(msg) - 1);
  if (len <= 0) {
    printf("some error happen when read\n");
    close(event_get_fd(ev));
    event_free(ev);
    return;
  }
  msg[len] = '\0';
  printf("recv the client msg: %s", msg);
  char reply_msg[4096] = "I have recvieced the msg: ";
  strcat(reply_msg + strlen(reply_msg), msg);
  write(fd, reply_msg, strlen(reply_msg));
}
```
user: Translate the below assembly code into C programming language:

```asm
<f1_if>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x4(%rbp)
  cmpw   $0x0,-0x4(%rbp)
  je     L27
  mov    $0xc8,%eax
  jmp    L4
L27:
  cmpw   $0x0,-0x4(%rbp)
  jg     L15
  mov    $0x64,%eax
  jmp    L4
L15:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
short f1_if(short x) {
  if (--x)
    return 200;
  if (x <= 0)
    return 100;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f1_if>:
  endbr64
  cmp    $0x1,%di
  mov    $0xc8,%eax
  mov    $0x64,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
short f1_if(short x) {
  if (--x)
    return 200;
  if (x <= 0)
    return 100;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f1_if>:
  endbr64
  cmp    $0x1,%di
  mov    $0x64,%edx
  mov    $0xc8,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
short f1_if(short x) {
  if (--x)
    return 200;
  if (x <= 0)
    return 100;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<f1_if>:
  endbr64
  cmp    $0x1,%di
  mov    $0x64,%edx
  mov    $0xc8,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
short f1_if(short x) {
  if (--x)
    return 200;
  if (x <= 0)
    return 100;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f1(int *restrict xp, int *restrict yp) {
  *xp = *xp + *yp;
  *xp = *xp + *yp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f1>:
  endbr64
  mov    (%rsi),%eax
  add    %eax,%eax
  add    %eax,(%rdi)
  ret
```

assistant: ```c
void f1(int *restrict xp, int *restrict yp) {
  *xp = *xp + *yp;
  *xp = *xp + *yp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f1>:
  endbr64
  mov    (%rsi),%eax
  add    %eax,%eax
  add    %eax,(%rdi)
  ret
```

assistant: ```c
void f1(int *restrict xp, int *restrict yp) {
  *xp = *xp + *yp;
  *xp = *xp + *yp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  mov    (%rsi),%eax
  add    %eax,%eax
  add    %eax,(%rdi)
  ret
```

assistant: ```c
void f1(int *restrict xp, int *restrict yp) {
  *xp = *xp + *yp;
  *xp = *xp + *yp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  movss  D2(%rip),%xmm0
  subss  -0x2c(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x2c(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void interpolate(float *out, float *in1, float *in2, float coef, int length) {
  int i;
  float invcoef;
  invcoef = 1.0f - coef;
  for (i = 0; i < length; i++)
    out[i] = coef * in1[i] + invcoef * in2[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolate>:
  endbr64
  movss  D8(%rip),%xmm3
  subss  %xmm0,%xmm3
  test   %ecx,%ecx
  jle    L6
  mov    %ecx,%ecx
  mov    $0x0,%eax
L3:
  movaps %xmm0,%xmm1
  mulss  (%rsi,%rax,4),%xmm1
  movaps %xmm3,%xmm2
  mulss  (%rdx,%rax,4),%xmm2
  addss  %xmm2,%xmm1
  movss  %xmm1,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L3
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: byte[4]

tool: {"D8": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void interpolate(float *out, float *in1, float *in2, float coef, int length) {
  int i;
  float invcoef;
  invcoef = 1.0f - coef;
  for (i = 0; i < length; i++)
    out[i] = coef * in1[i] + invcoef * in2[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolate>:
  endbr64
  movss  D3(%rip),%xmm3
  subss  %xmm0,%xmm3
  test   %ecx,%ecx
  jle    L16
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L6:
  movss  (%rsi,%rax,4),%xmm1
  movss  (%rdx,%rax,4),%xmm2
  mulss  %xmm0,%xmm1
  mulss  %xmm3,%xmm2
  addss  %xmm2,%xmm1
  movss  %xmm1,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L6
L16:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void interpolate(float *out, float *in1, float *in2, float coef, int length) {
  int i;
  float invcoef;
  invcoef = 1.0f - coef;
  for (i = 0; i < length; i++)
    out[i] = coef * in1[i] + invcoef * in2[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolate>:
  endbr64
  movss  D3(%rip),%xmm2
  mov    %rsi,%r8
  mov    %rdx,%rsi
  movslq %ecx,%rdx
  subss  %xmm0,%xmm2
  test   %edx,%edx
  jle    L37
  lea    0x4(%rsi),%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  seta   %cl
  cmp    $0x1,%edx
  setne  %al
  test   %al,%cl
  je     L51
  lea    0x4(%r8),%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L51
  lea    -0x1(%rdx),%eax
  mov    %edx,%r9d
  cmp    $0x2,%eax
  jbe    L8
  mov    %edx,%ecx
  movaps %xmm0,%xmm5
  movaps %xmm2,%xmm4
  xor    %eax,%eax
  shr    $0x2,%ecx
  shufps $0x0,%xmm5,%xmm5
  shufps $0x0,%xmm4,%xmm4
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L43:
  movups (%r8,%rax,1),%xmm1
  movups (%rsi,%rax,1),%xmm3
  mulps  %xmm5,%xmm1
  mulps  %xmm4,%xmm3
  addps  %xmm3,%xmm1
  movups %xmm1,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L43
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%edx
  je     L37
  sub    %ecx,%edx
  mov    %edx,%r9d
  cmp    $0x1,%edx
  je     L67
L75:
  mov    %ecx,%edx
  movaps %xmm0,%xmm3
  movaps %xmm2,%xmm4
  movq   (%r8,%rdx,4),%xmm1
  shufps $0xe0,%xmm3,%xmm3
  shufps $0xe0,%xmm4,%xmm4
  mulps  %xmm3,%xmm1
  movq   (%rsi,%rdx,4),%xmm3
  mulps  %xmm4,%xmm3
  addps  %xmm3,%xmm1
  movlps %xmm1,(%rdi,%rdx,4)
  mov    %r9d,%edx
  and    $0xfffffffe,%edx
  add    %edx,%eax
  cmp    %edx,%r9d
  je     L37
L67:
  cltq
  mulss  (%r8,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm2
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  ret
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L77:
  movss  (%r8,%rax,4),%xmm1
  movss  (%rsi,%rax,4),%xmm3
  mulss  %xmm0,%xmm1
  mulss  %xmm2,%xmm3
  addss  %xmm3,%xmm1
  movss  %xmm1,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L77
L37:
  ret
L8:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L75
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void interpolate(float *out, float *in1, float *in2, float coef, int length) {
  int i;
  float invcoef;
  invcoef = 1.0f - coef;
  for (i = 0; i < length; i++)
    out[i] = coef * in1[i] + invcoef * in2[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_alpha_mirror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L28
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L74
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L74
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    $0xffffffdb,%eax
  sub    %edx,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  jmp    L5
L74:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L44
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L44
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    $0xffffff9b,%eax
  sub    %edx,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  jmp    L5
L44:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L5:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_alpha_mirror(char *ch) {
  while (*ch) {
    if (*ch >= 'a' && *ch <= 'z') {
      ft_putchar('m' - (*ch - 'n'));
    } else if (*ch >= 'A' && *ch <= 'Z') {
      ft_putchar('M' - (*ch - 'N'));
    } else
      ft_putchar(*ch);
    ch++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_alpha_mirror>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0xffffff9b,%ebp
  jmp    L10
L14:
  mov    $0xffffffdb,%edi
  sub    %eax,%edi
  movsbl %dil,%edi
  call   <ft_putchar@plt>
  jmp    L11
L58:
  movsbl %al,%edi
  call   <ft_putchar@plt>
L11:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L33
L10:
  mov    %eax,%ecx
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L14
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L58
  mov    %ebp,%edi
  sub    %ecx,%edi
  movsbl %dil,%edi
  call   <ft_putchar@plt>
  jmp    L11
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  ret
```

assistant: ```c
void ft_alpha_mirror(char *ch) {
  while (*ch) {
    if (*ch >= 'a' && *ch <= 'z') {
      ft_putchar('m' - (*ch - 'n'));
    } else if (*ch >= 'A' && *ch <= 'Z') {
      ft_putchar('M' - (*ch - 'N'));
    } else
      ft_putchar(*ch);
    ch++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_alpha_mirror>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  push   %rbp
  mov    $0xffffff9b,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebp,%edi
  sub    %eax,%edi
  movzbl %dil,%edi
  call   <ft_putchar@plt>
L4:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L28
L58:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L35
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L12
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <ft_putchar@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L58
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0xffffffdb,%edi
  sub    %eax,%edi
  movzbl %dil,%edi
  call   <ft_putchar@plt>
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void ft_alpha_mirror(char *ch) {
  while (*ch) {
    if (*ch >= 'a' && *ch <= 'z') {
      ft_putchar('m' - (*ch - 'n'));
    } else if (*ch >= 'A' && *ch <= 'Z') {
      ft_putchar('M' - (*ch - 'N'));
    } else
      ft_putchar(*ch);
    ch++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_alpha_mirror>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L63
  push   %rbp
  mov    $0xffffff9b,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebp,%edi
  sub    %eax,%edi
  movzbl %dil,%edi
  call   <ft_putchar@plt>
L62:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L0
L54:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L38
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L7
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <ft_putchar@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L54
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffdb,%edi
  sub    %eax,%edi
  movzbl %dil,%edi
  call   <ft_putchar@plt>
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L63:
  ret
```

assistant: ```c
void ft_alpha_mirror(char *ch) {
  while (*ch) {
    if (*ch >= 'a' && *ch <= 'z') {
      ft_putchar('m' - (*ch - 'n'));
    } else if (*ch >= 'A' && *ch <= 'Z') {
      ft_putchar('M' - (*ch - 'N'));
    } else
      ft_putchar(*ch);
    ch++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  jmp    L38
L39:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L29
  mov    $0x0,%eax
  jmp    L33
L29:
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L39
  mov    $0x1,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int i = 1, div;
  div = num % i;
  while (i <= num - 1) {
    div = num % i;
    if (div == 0)
      return 0;
    else
      i = i + 1;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_prime>:
  endbr64
  cmp    $0x1,%edi
  setle  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i = 1, div;
  div = num % i;
  while (i <= num - 1) {
    div = num % i;
    if (div == 0)
      return 0;
    else
      i = i + 1;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_prime>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  setle  %al
  ret
```

assistant: ```c
int check_prime(int num) {
  int i = 1, div;
  div = num % i;
  while (i <= num - 1) {
    div = num % i;
    if (div == 0)
      return 0;
    else
      i = i + 1;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_prime>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  setle  %al
  ret
```

assistant: ```c
int check_prime(int num) {
  int i = 1, div;
  div = num % i;
  while (i <= num - 1) {
    div = num % i;
    if (div == 0)
      return 0;
    else
      i = i + 1;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getlinex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L28
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L28
  cmpl   $0xa,-0x8(%rbp)
  jne    L30
L28:
  cmpl   $0xa,-0x8(%rbp)
  jne    L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getlinex(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; i++) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getlinex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L51
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L44:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D8(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L32
  cmp    $0xa,%eax
  je     L32
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L44
  mov    %r12d,%ebx
  jmp    L59
L51:
  mov    $0x0,%ebx
L32:
  cmp    $0xa,%eax
  je     L39
L59:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  add    $0x1,%ebx
  jmp    L59
```

assistant: ```c
int getlinex(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; i++) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getlinex>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L59
  mov    D8(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L3:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L36
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L18
  mov    %edx,%r14d
L43:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L3
  cmp    $0xa,%eax
  je     L2
L59:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  lea    0x1(%r14),%edx
L36:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L18:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getlinex(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; i++) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getlinex>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L57
  mov    D4(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L48:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L4
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L33
  mov    %edx,%r14d
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L48
  cmp    $0xa,%eax
  je     L20
L57:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  lea    0x1(%r14),%edx
L4:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L33:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getlinex(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; i++) {
    s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  nop
  leave
  ret
```

assistant: ```c
void send_message(int sock, char *message) {
  int message_length;
  message_length = strlen(message);
  send(sock, message, message_length, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_message>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void send_message(int sock, char *message) {
  int message_length;
  message_length = strlen(message);
  send(sock, message, message_length, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_message>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%edx
  xor    %ecx,%ecx
  pop    %r12
  jmp    1070 <send@plt>
```

assistant: ```c
void send_message(int sock, char *message) {
  int message_length;
  message_length = strlen(message);
  send(sock, message, message_length, 0);
}
```