user: 请从给定的汇编指令推导出C源代码:

```asm
<setzero>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  lea    0x0(,%rsi,4),%edi
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  call   <malloc@plt>
  lea    0x0(,%r13,4),%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L104
  mov    %rax,%r12
  test   %rax,%rax
  je     L104
  test   %ebx,%ebx
  jle    L164
  mov    %ebx,%ecx
  mov    %rbp,%rax
  lea    0x0(%rbp,%rcx,4),%rdx
  nopl   (%rax)
L201:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L201
  test   %r13d,%r13d
  jle    L80
L172:
  mov    %r13d,%edx
  mov    %r12,%rax
  lea    (%r12,%rdx,4),%rdx
  xchg   %ax,%ax
L297:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L297
  test   %ebx,%ebx
  jle    L42
  mov    %ebx,%ecx
L80:
  lea    -0x1(%r13),%edx
  mov    %rbp,%rax
  lea    0x0(%rbp,%rcx,4),%r14
  mov    %rbp,%rsi
  mov    %edx,0x1c(%rsp)
  neg    %rax
  lea    0x1(%rdx),%rdi
  lea    (%r15,%rax,2),%r9
  lea    (%r12,%rdi,4),%rcx
  nopl   0x0(%rax,%rax,1)
L76:
  test   %r13d,%r13d
  jle    L238
  mov    (%r9,%rsi,2),%rdx
  mov    %r12,%rax
  sub    %r12,%rdx
  nop
L102:
  mov    (%rdx,%rax,1),%r8d
  test   %r8d,%r8d
  jne    L243
  movl   $0x0,(%rsi)
  movl   $0x0,(%rax)
L243:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L102
L238:
  add    $0x4,%rsi
  cmp    %r14,%rsi
  jne    L76
  lea    0x0(,%rdi,4),%rdx
  jmp    L94
  nopl   0x0(%rax)
L24:
  add    $0x4,%rbp
  cmp    %r14,%rbp
  je     L142
L94:
  mov    0x0(%rbp),%ecx
  test   %ecx,%ecx
  jne    L24
  test   %r13d,%r13d
  jle    L24
  mov    (%r9,%rbp,2),%rdi
  xor    %esi,%esi
  add    $0x4,%rbp
  mov    %r9,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  call   <memset@plt>
  mov    0x10(%rsp),%r9
  mov    0x8(%rsp),%rdx
  cmp    %r14,%rbp
  jne    L94
  nopl   (%rax)
L142:
  lea    -0x1(%rbx),%r9d
  lea    0x8(%r15),%r10
  test   %r13d,%r13d
  jle    L308
L165:
  lea    -0x1(%rbx),%eax
  movslq %r13d,%rdi
  lea    0x8(%r15),%r10
  xor    %edx,%edx
  shl    $0x2,%rdi
  mov    %rax,%r9
  lea    (%r10,%rax,8),%rsi
  jmp    L179
  xchg   %ax,%ax
L58:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L264
L179:
  mov    (%r12,%rdx,1),%eax
  test   %eax,%eax
  jne    L58
  test   %ebx,%ebx
  jle    L58
  mov    %r15,%rax
  nopl   0x0(%rax,%rax,1)
L88:
  mov    (%rax),%rcx
  add    $0x8,%rax
  movl   $0x0,(%rcx,%rdx,1)
  cmp    %rax,%rsi
  jne    L88
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L179
L264:
  test   %ebx,%ebx
  jle    L101
  lea    -0x1(%r13),%eax
  mov    %eax,0x1c(%rsp)
L308:
  mov    0x1c(%rsp),%ebx
  lea    (%r10,%r9,8),%r14
  lea    D6(%rip),%rbp
  lea    0x4(,%rbx,4),%r12
  nop
L280:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L36
  nopw   0x0(%rax,%rax,1)
L244:
  mov    (%r15),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L244
L36:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    %r15,%r14
  jne    L280
L101:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
L104:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L164:
  test   %r13d,%r13d
  jg     L172
  jmp    L101
L42:
  test   %r13d,%r13d
  jg     L165
  jmp    L101
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: %d 

assistant: ```c
void setzero(int **A, int m, int n) {
  int i, j;
  int *B, *C;
  B = (int *)malloc(sizeof(int) * m);
  C = (int *)malloc(sizeof(int) * n);
  if (NULL == B || NULL == C)
    return;
  for (i = 0; i < m; i++) {
    B[i] = 1;
  }
  for (j = 0; j < n; j++) {
    C[j] = 1;
  }
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      if (A[i][j] == 0) {
        B[i] = 0;
        C[j] = 0;
      }
    }
  }
  for (i = 0; i < m; i++) {
    if (B[i] == 0) {
      for (j = 0; j < n; j++) {
        A[i][j] = 0;
      }
    }
  }
  for (j = 0; j < n; j++) {
    if (C[j] == 0) {
      for (i = 0; i < m; i++) {
        A[i][j] = 0;
      }
    }
  }
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%d ", A[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return;
}
```