ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_multi>:
  endbr64
  push   %r13
  mov    $0x7e,%ecx
  push   %r12
  push   %rbp
  sub    $0x810,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  lea    0x400(%rsp),%r12
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strcpy@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mempcpy@plt>
  xor    %esi,%esi
  mov    $0x64,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <stpcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <bcopy@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <bzero@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <strndup@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: byte[16]

tool: {"D7": [0x73,0x6f,0x75,0x72,0x63,0x65,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x00,0x00,0x00]}

assistant: ```c
void test_multi() {
  char src[1024] = "source string", dst[1024], *ptr;
  int len = strlen(src);
  strcpy(dst, src);
  memcpy(dst, src, len);
  memmove(dst, src, len);
  mempcpy(dst, src, len);
  memset(dst, 0, 100);
  strncpy(dst, src, 5);
  stpcpy(dst, src);
  strcat(dst, src);
  strncat(dst, src, 5);
  bcopy(src, dst, len);
  bzero(dst, 100);
  ptr = strdup(src);
  free(ptr);
  ptr = strndup(src, 5);
  free(ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clar_print_shutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <clar_report_all@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: 



assistant: ```c
void clar_print_shutdown(int test_count, int suite_count, int error_count) {
  (void)test_count;
  (void)suite_count;
  (void)error_count;
  printf("\n\n");
  clar_report_all();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clar_print_shutdown>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <clar_report_all@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: 



assistant: ```c
void clar_print_shutdown(int test_count, int suite_count, int error_count) {
  (void)test_count;
  (void)suite_count;
  (void)error_count;
  printf("\n\n");
  clar_report_all();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clar_print_shutdown>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <clar_report_all@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: 



assistant: ```c
void clar_print_shutdown(int test_count, int suite_count, int error_count) {
  (void)test_count;
  (void)suite_count;
  (void)error_count;
  printf("\n\n");
  clar_report_all();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clar_print_shutdown>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <clar_report_all@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: 



assistant: ```c
void clar_print_shutdown(int test_count, int suite_count, int error_count) {
  (void)test_count;
  (void)suite_count;
  (void)error_count;
  printf("\n\n");
  clar_report_all();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiply373>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L28
L5:
  movl   $0x0,-0x3c(%rbp)
  jmp    L30
L35:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L30:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L35
  addl   $0x1,-0x40(%rbp)
L28:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L5
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply373(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply373>:
  endbr64
  test   %edi,%edi
  jle    L17
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L6:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L15:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L15
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  ret
```

assistant: ```c
void multiply373(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply373>:
  endbr64
  test   %edi,%edi
  jle    L17
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L29
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L28
  pop    %rbx
  ret
L17:
  ret
```

assistant: ```c
void multiply373(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply373>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L40
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L30:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L11
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L11
  nopl   0x0(%rax)
L43:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L43
  cmp    -0x24(%rsp),%r11d
  je     L52
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L52
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L52
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L52:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L30
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L16:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L16
  mov    -0x18(%rsp),%r8
  jmp    L52
```

assistant: ```c
void multiply373(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<graf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  cmpl   $0xe,-0x4(%rbp)
  jg     L26
  mov    -0x8(%rbp),%eax
  jmp    L18
L26:
  cmpl   $0x1d,-0x4(%rbp)
  jg     L37
  mov    -0x4(%rbp),%eax
  lea    -0xf(%rax),%edx
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  jmp    L18
L37:
  cmpl   $0x2c,-0x4(%rbp)
  jg     L46
  mov    -0x4(%rbp),%eax
  lea    -0x1e(%rax),%edx
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  jmp    L18
L46:
  cmpl   $0x3b,-0x4(%rbp)
  jg     L99
  mov    -0x4(%rbp),%eax
  lea    -0x2d(%rax),%edx
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  jmp    L18
L99:
  cmpl   $0x4f,-0x4(%rbp)
  jg     L51
  mov    -0x4(%rbp),%eax
  lea    -0x3c(%rax),%edx
  mov    0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L18
L51:
  mov    0x18(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int graf(int age, int p0, int p1, int p2, int p3, int p4, int p5, int p6) {
  if (age < 15)
    return (p0);
  else if (age <= 29)
    return (int)(p1 + (((age - 15) * (p2 - p1)) / 15));
  else if (age <= 44)
    return (int)(p2 + (((age - 30) * (p3 - p2)) / 15));
  else if (age <= 59)
    return (int)(p3 + (((age - 45) * (p4 - p3)) / 15));
  else if (age <= 79)
    return (int)(p4 + (((age - 60) * (p5 - p4)) / 20));
  else
    return (p6);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<graf>:
  endbr64
  mov    %edx,%r10d
  mov    %ecx,%edx
  mov    %esi,%eax
  cmp    $0xe,%edi
  jle    L5
  cmp    $0x1d,%edi
  jle    L49
  cmp    $0x2c,%edi
  jle    L21
  cmp    $0x3b,%edi
  jle    L2
  mov    0x10(%rsp),%eax
  cmp    $0x4f,%edi
  jg     L5
  sub    $0x3c,%edi
  mov    0x8(%rsp),%eax
  sub    %r9d,%eax
  imul   %eax,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  add    %r9d,%eax
L5:
  ret
L49:
  sub    $0xf,%edi
  sub    %r10d,%edx
  imul   %edx,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x3,%eax
  sar    $0x1f,%edi
  sub    %edi,%eax
  add    %r10d,%eax
  ret
L21:
  sub    $0x1e,%edi
  sub    %ecx,%r8d
  imul   %r8d,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x3,%eax
  sar    $0x1f,%edi
  sub    %edi,%eax
  add    %ecx,%eax
  ret
L2:
  sub    $0x2d,%edi
  sub    %r8d,%r9d
  imul   %edi,%r9d
  movslq %r9d,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %r9d,%eax
  sar    $0x3,%eax
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  add    %r8d,%eax
  ret
```

assistant: ```c
int graf(int age, int p0, int p1, int p2, int p3, int p4, int p5, int p6) {
  if (age < 15)
    return (p0);
  else if (age <= 29)
    return (int)(p1 + (((age - 15) * (p2 - p1)) / 15));
  else if (age <= 44)
    return (int)(p2 + (((age - 30) * (p3 - p2)) / 15));
  else if (age <= 59)
    return (int)(p3 + (((age - 45) * (p4 - p3)) / 15));
  else if (age <= 79)
    return (int)(p4 + (((age - 60) * (p5 - p4)) / 20));
  else
    return (p6);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<graf>:
  endbr64
  mov    %edx,%r10d
  mov    %esi,%eax
  mov    %ecx,%edx
  cmp    $0xe,%edi
  jle    L48
  cmp    $0x1d,%edi
  jle    L20
  cmp    $0x2c,%edi
  jle    L26
  cmp    $0x3b,%edi
  jle    L13
  mov    0x10(%rsp),%eax
  cmp    $0x4f,%edi
  jg     L48
  mov    0x8(%rsp),%eax
  sub    $0x3c,%edi
  sub    %r9d,%eax
  imul   %eax,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sub    %edi,%eax
  add    %r9d,%eax
L48:
  ret
L20:
  sub    $0xf,%edi
  sub    %r10d,%edx
  imul   %edx,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x1f,%edi
  sar    $0x3,%eax
  sub    %edi,%eax
  add    %r10d,%eax
  ret
  nopl   (%rax)
L13:
  sub    $0x2d,%edi
  sub    %r8d,%r9d
  imul   %edi,%r9d
  movslq %r9d,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %r9d,%eax
  sar    $0x1f,%r9d
  sar    $0x3,%eax
  sub    %r9d,%eax
  add    %r8d,%eax
  ret
  nopl   0x0(%rax)
L26:
  sub    $0x1e,%edi
  sub    %ecx,%r8d
  imul   %r8d,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x1f,%edi
  sar    $0x3,%eax
  sub    %edi,%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int graf(int age, int p0, int p1, int p2, int p3, int p4, int p5, int p6) {
  if (age < 15)
    return (p0);
  else if (age <= 29)
    return (int)(p1 + (((age - 15) * (p2 - p1)) / 15));
  else if (age <= 44)
    return (int)(p2 + (((age - 30) * (p3 - p2)) / 15));
  else if (age <= 59)
    return (int)(p3 + (((age - 45) * (p4 - p3)) / 15));
  else if (age <= 79)
    return (int)(p4 + (((age - 60) * (p5 - p4)) / 20));
  else
    return (p6);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<graf>:
  endbr64
  mov    %edx,%r10d
  mov    %esi,%eax
  mov    %ecx,%edx
  cmp    $0xe,%edi
  jle    L19
  cmp    $0x1d,%edi
  jle    L24
  cmp    $0x2c,%edi
  jle    L10
  cmp    $0x3b,%edi
  jle    L14
  mov    0x10(%rsp),%eax
  cmp    $0x4f,%edi
  jg     L19
  mov    0x8(%rsp),%eax
  sub    $0x3c,%edi
  sub    %r9d,%eax
  imul   %eax,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sub    %edi,%eax
  add    %r9d,%eax
L19:
  ret
L24:
  sub    $0xf,%edi
  sub    %r10d,%edx
  imul   %edx,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x1f,%edi
  sar    $0x3,%eax
  sub    %edi,%eax
  add    %r10d,%eax
  ret
  nopl   (%rax)
L14:
  sub    $0x2d,%edi
  sub    %r8d,%r9d
  imul   %edi,%r9d
  movslq %r9d,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %r9d,%eax
  sar    $0x1f,%r9d
  sar    $0x3,%eax
  sub    %r9d,%eax
  add    %r8d,%eax
  ret
  nopl   0x0(%rax)
L10:
  sub    $0x1e,%edi
  sub    %ecx,%r8d
  imul   %r8d,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x1f,%edi
  sar    $0x3,%eax
  sub    %edi,%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int graf(int age, int p0, int p1, int p2, int p3, int p4, int p5, int p6) {
  if (age < 15)
    return (p0);
  else if (age <= 29)
    return (int)(p1 + (((age - 15) * (p2 - p1)) / 15));
  else if (age <= 44)
    return (int)(p2 + (((age - 30) * (p3 - p2)) / 15));
  else if (age <= 59)
    return (int)(p3 + (((age - 45) * (p4 - p3)) / 15));
  else if (age <= 79)
    return (int)(p4 + (((age - 60) * (p5 - p4)) / 20));
  else
    return (p6);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<expand_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D8(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  cmpl   $0x0,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: %d

assistant: ```c
int expand_num(char buf[], size_t buf_len, int val) {
  snprintf(buf, buf_len, "%d", val);
  return (val == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<expand_num>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  mov    %edx,%ecx
  lea    D8(%rip),%rdx
  call   <snprintf@plt>
  test   %ebx,%ebx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int expand_num(char buf[], size_t buf_len, int val) {
  snprintf(buf, buf_len, "%d", val);
  return (val == 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<expand_num>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  mov    %edx,%ebx
  lea    D0(%rip),%rdx
  call   <snprintf@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  pop    %rbx
  sete   %al
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int expand_num(char buf[], size_t buf_len, int val) {
  snprintf(buf, buf_len, "%d", val);
  return (val == 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<expand_num>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  mov    %edx,%ebx
  lea    D3(%rip),%rdx
  call   <snprintf@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  pop    %rbx
  sete   %al
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int expand_num(char buf[], size_t buf_len, int val) {
  snprintf(buf, buf_len, "%d", val);
  return (val == 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pointerSample>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x8(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string
name: extract_symbolic_data
arguments: data_label: D19
type_infered: string

tool: D7: valor yy: %d, valor pointer *a: %d


tool: D19: valor xx: %d, valor pointer *a: %d



assistant: ```c
void pointerSample() {
  int yy = 10;
  int *a = &yy;
  int xx = yy;
  printf("valor yy: %d, valor pointer *a: %d\n", yy, *a);
  printf("valor xx: %d, valor pointer *a: %d\n\n", xx, *a);
  *a += 8;
  printf("valor yy: %d, valor pointer *a: %d\n", yy, *a);
  printf("valor xx: %d, valor pointer *a: %d\n\n", xx, *a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pointerSample>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x12,%edx
  mov    $0x12,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x12,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string

tool: D4: valor yy: %d, valor pointer *a: %d


tool: D12: valor xx: %d, valor pointer *a: %d



assistant: ```c
void pointerSample() {
  int yy = 10;
  int *a = &yy;
  int xx = yy;
  printf("valor yy: %d, valor pointer *a: %d\n", yy, *a);
  printf("valor xx: %d, valor pointer *a: %d\n\n", xx, *a);
  *a += 8;
  printf("valor yy: %d, valor pointer *a: %d\n", yy, *a);
  printf("valor xx: %d, valor pointer *a: %d\n\n", xx, *a);
}
```