ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  movaps %xmm2,%xmm3
  addss  %xmm0,%xmm3
  comiss %xmm3,%xmm1
  jae    L38
  movaps %xmm2,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm3,%xmm0
  jae    L38
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm3,%xmm2
  jb     L42
L38:
  lea    D33(%rip),%rdi
  call   <puts@plt>
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L42:
  ucomiss %xmm1,%xmm0
  setnp  %al
  mov    $0x0,%ecx
  cmovne %ecx,%eax
  ucomiss %xmm0,%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %al,%al
  je     L51
  test   %dl,%dl
  jne    L74
L51:
  or     %dl,%al
  jne    L70
  ucomiss %xmm1,%xmm2
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  je     L109
L70:
  lea    D9(%rip),%rdi
  call   <puts@plt>
L82:
  movss  0xc(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  movss  0x14(%rsp),%xmm2
  movaps %xmm4,%xmm1
  addss  %xmm3,%xmm1
  addss  %xmm2,%xmm1
  mulss  D34(%rip),%xmm1
  movaps %xmm1,%xmm0
  subss  %xmm4,%xmm0
  mulss  %xmm1,%xmm0
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  mulss  %xmm4,%xmm0
  subss  %xmm2,%xmm1
  mulss  %xmm1,%xmm0
  call   <sqrt@plt>
  cvtss2sd %xmm0,%xmm0
  lea    D72(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L40
L74:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L82
L109:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L82
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D55
datatype: string
name: read_data
arguments: tag: D38
datatype: string
name: read_data
arguments: tag: D33
datatype: string
name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D34
datatype: byte[4]
name: read_data
arguments: tag: D72
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D19
datatype: string

tool: D55: Vnesi dolzini na strani: 

tool: D38: %f %f %f

tool: D33: Ne moze da se konstruira triagolnik.

tool: D9: Tragolnikot e ravnokrak.

tool: {"D34": [0x00,0x00,0x00,0x3f]}

tool: D72: Ploshtinata mu e %7.3f


tool: D18: Tragolnikot e ravnostran.

tool: D19: Tragolnikot e raznostran.

assistant: ```c
int main() {
  float a, b, c;
  printf("Vnesi dolzini na strani: \n");
  scanf("%f %f %f", &a, &b, &c);
  if ((a + b <= c) || (a + c <= b) || (b + c <= a))
    printf("Ne moze da se konstruira triagolnik.\n");
  else {
    if (a == b && b == c)
      printf("Tragolnikot e ravnostran.\n");
    else if (a == b || b == c || a == c)
      printf("Tragolnikot e ravnokrak.\n");
    else
      printf("Tragolnikot e raznostran.\n");
    float p, s = (a + b + c) / 2;
    p = sqrt(s * (s - a) * (s - b) * (s - c));
    printf("Ploshtinata mu e %7.3f\n", p);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  movaps %xmm2,%xmm3
  addss  %xmm0,%xmm3
  comiss %xmm3,%xmm1
  jae    L29
  movaps %xmm2,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm3,%xmm0
  jb     L76
L29:
  lea    D38(%rip),%rdi
  call   <puts@plt>
L92:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L76:
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm3,%xmm2
  jae    L29
  ucomiss %xmm1,%xmm0
  mov    $0x0,%ecx
  setnp  %al
  cmovne %ecx,%eax
  ucomiss %xmm0,%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %al,%al
  je     L1
  test   %dl,%dl
  jne    L37
L1:
  or     %dl,%al
  jne    L23
  ucomiss %xmm1,%xmm2
  setnp  %dl
  cmove  %edx,%eax
  test   %al,%al
  je     L69
L23:
  lea    D73(%rip),%rdi
  call   <puts@plt>
L109:
  movss  0xc(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  movss  0x14(%rsp),%xmm2
  movaps %xmm4,%xmm1
  addss  %xmm3,%xmm1
  addss  %xmm2,%xmm1
  mulss  D59(%rip),%xmm1
  movaps %xmm1,%xmm0
  subss  %xmm4,%xmm0
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  mulss  %xmm1,%xmm0
  subss  %xmm2,%xmm1
  mulss  %xmm4,%xmm0
  mulss  %xmm1,%xmm0
  call   <sqrt@plt>
  lea    D67(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L92
L37:
  lea    D56(%rip),%rdi
  call   <puts@plt>
  jmp    L109
L69:
  lea    D74(%rip),%rdi
  call   <puts@plt>
  jmp    L109
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
type: string
name: parse_data
arguments: tag: D35
type: string
name: parse_data
arguments: tag: D38
type: string
name: parse_data
arguments: tag: D73
type: string
name: parse_data
arguments: tag: D59
type: byte[4]
name: parse_data
arguments: tag: D67
type: string
name: parse_data
arguments: tag: D56
type: string
name: parse_data
arguments: tag: D74
type: string

tool: D25: Vnesi dolzini na strani: 

tool: D35: %f %f %f

tool: D38: Ne moze da se konstruira triagolnik.

tool: D73: Tragolnikot e ravnokrak.

tool: {"D59": [0x00,0x00,0x00,0x3f]}

tool: D67: Ploshtinata mu e %7.3f


tool: D56: Tragolnikot e ravnostran.

tool: D74: Tragolnikot e raznostran.

assistant: ```c
int main() {
  float a, b, c;
  printf("Vnesi dolzini na strani: \n");
  scanf("%f %f %f", &a, &b, &c);
  if ((a + b <= c) || (a + c <= b) || (b + c <= a))
    printf("Ne moze da se konstruira triagolnik.\n");
  else {
    if (a == b && b == c)
      printf("Tragolnikot e ravnostran.\n");
    else if (a == b || b == c || a == c)
      printf("Tragolnikot e ravnokrak.\n");
    else
      printf("Tragolnikot e raznostran.\n");
    float p, s = (a + b + c) / 2;
    p = sqrt(s * (s - a) * (s - b) * (s - c));
    printf("Ploshtinata mu e %7.3f\n", p);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fn0000000000402DC0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fn0000000000401540@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fn0000000000402DC0() {
  fn0000000000401540();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fn0000000000402DC0>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fn0000000000401540@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fn0000000000402DC0() {
  fn0000000000401540();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fn0000000000402DC0>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fn0000000000401540@plt>
```

assistant: ```c
void fn0000000000402DC0() {
  fn0000000000401540();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn0000000000402DC0>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fn0000000000401540@plt>
```

assistant: ```c
void fn0000000000402DC0() {
  fn0000000000401540();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subtraction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  subss  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  movss  %xmm0,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L17
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L35
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subtraction(float a[50][50], float b[50][50], int row, int col) {
  int i, j;
  for (i = 0; i < row; i++)
    for (j = 0; j < col; j++)
      a[i][j] = a[i][j] - b[i][j];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subtraction>:
  endbr64
  test   %edx,%edx
  jle    L53
  mov    %rdi,%r9
  lea    -0x1(%rdx),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xc8(%rdi,%rax,8),%r10
  mov    %ecx,%r8d
  jmp    L9
L15:
  movss  (%rdx,%rax,4),%xmm0
  subss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L15
L21:
  add    $0xc8,%r9
  add    $0xc8,%rsi
  cmp    %r10,%r9
  je     L53
L9:
  mov    %r9,%rdx
  mov    %rsi,%rdi
  mov    $0x0,%eax
  test   %ecx,%ecx
  jg     L15
  jmp    L21
L53:
  ret
```

assistant: ```c
void subtraction(float a[50][50], float b[50][50], int row, int col) {
  int i, j;
  for (i = 0; i < row; i++)
    for (j = 0; j < col; j++)
      a[i][j] = a[i][j] - b[i][j];
}
```
user: What is the c source code of the assembly code below?

```asm
<subtraction>:
  endbr64
  test   %edx,%edx
  jle    L36
  lea    -0x1(%rdx),%eax
  movslq %ecx,%rdx
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xc8(%rdi,%rax,8),%r8
  xchg   %ax,%ax
L18:
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L17
  cs nopw 0x0(%rax,%rax,1)
L37:
  movss  (%rdi,%rax,4),%xmm0
  subss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L37
L17:
  add    $0xc8,%rdi
  add    $0xc8,%rsi
  cmp    %r8,%rdi
  jne    L18
L36:
  ret
```

assistant: ```c
void subtraction(float a[50][50], float b[50][50], int row, int col) {
  int i, j;
  for (i = 0; i < row; i++)
    for (j = 0; j < col; j++)
      a[i][j] = a[i][j] - b[i][j];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<subtraction>:
  endbr64
  test   %edx,%edx
  jle    L19
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  test   %ecx,%ecx
  jle    L63
  movslq %edx,%rdx
  mov    %rdi,%r12
  mov    %rdi,%rax
  mov    %ecx,%r14d
  lea    (%rdx,%rdx,4),%rdx
  mov    %ecx,%r15d
  mov    %rsi,%r13
  and    $0xfffffffc,%r14d
  lea    (%rdx,%rdx,4),%rdx
  lea    0x4(%rsi),%r9
  xor    %r8d,%r8d
  and    $0x3,%r15d
  lea    (%rdx,%rdx,1),%rdi
  mov    %ecx,%edx
  mov    %ecx,%ebp
  mov    %rdi,-0x18(%rsp)
  shr    $0x2,%edx
  lea    -0x1(%rcx),%edi
  mov    %edi,-0xc(%rsp)
  lea    -0x1(%rdx),%edi
  add    $0x1,%rdi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %rax,%rdx
  lea    -0x4(%r9),%rcx
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  jbe    L5
  cmp    $0x1,%ebx
  je     L5
  cmpl   $0x2,-0xc(%rsp)
  jbe    L37
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L40:
  movups (%rax,%rdx,1),%xmm0
  movups (%rcx,%rdx,1),%xmm2
  subps  %xmm2,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdi,%rdx
  jne    L40
  cmp    %r14d,%ebx
  je     L90
  mov    %r15d,%r11d
  cmp    $0x1,%r15d
  je     L110
  mov    %r14d,%esi
  mov    %r14d,%edx
L20:
  add    %r8,%rsi
  lea    (%r12,%rsi,4),%r10
  movq   0x0(%r13,%rsi,4),%xmm1
  mov    %r11d,%esi
  movq   (%r10),%xmm0
  and    $0xfffffffe,%esi
  add    %esi,%edx
  subps  %xmm1,%xmm0
  movlps %xmm0,(%r10)
  cmp    %esi,%r11d
  je     L90
L77:
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm0
  subss  (%rcx,%rdx,4),%xmm0
  movss  %xmm0,(%rax,%rdx,4)
L90:
  add    $0xc8,%rax
  add    $0xc8,%r9
  add    $0x32,%r8
  cmp    -0x18(%rsp),%r8
  jne    L93
L63:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L14:
  movss  (%rax,%rdx,4),%xmm0
  subss  (%rcx,%rdx,4),%xmm0
  movss  %xmm0,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%rbp
  jne    L14
  jmp    L90
L37:
  mov    %ebx,%r11d
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L20
L110:
  mov    %r14d,%edx
  jmp    L77
L19:
  ret
```

assistant: ```c
void subtraction(float a[50][50], float b[50][50], int row, int col) {
  int i, j;
  for (i = 0; i < row; i++)
    for (j = 0; j < col; j++)
      a[i][j] = a[i][j] - b[i][j];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getPortBySock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <getpeername@plt>
  test   %rax,%rax
  jns    L16
  mov    $0xffffffff,%eax
  jmp    L28
L16:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int getPortBySock(int sock) {
  struct sockaddr_in local_address;
  int addr_size = sizeof(local_address);
  if (getpeername(sock, (struct sockaddr *)&local_address, (unsigned int *)&addr_size) < 0) {
    return (int)-1;
  } else {
    return ((int)ntohs(local_address.sin_port));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getPortBySock>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <getpeername@plt>
  test   %rax,%rax
  js     L3
  mov    (%rsp),%edi
  call   <ntohs@plt>
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L26
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getPortBySock(int sock) {
  struct sockaddr_in local_address;
  int addr_size = sizeof(local_address);
  if (getpeername(sock, (struct sockaddr *)&local_address, (unsigned int *)&addr_size) < 0) {
    return (int)-1;
  } else {
    return ((int)ntohs(local_address.sin_port));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getPortBySock>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  movl   $0x4,0x4(%rsp)
  call   <getpeername@plt>
  test   %rax,%rax
  js     L26
  mov    (%rsp),%edi
  call   <ntohs@plt>
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
  nop
L26:
  mov    $0xffffffff,%eax
  jmp    L8
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getPortBySock(int sock) {
  struct sockaddr_in local_address;
  int addr_size = sizeof(local_address);
  if (getpeername(sock, (struct sockaddr *)&local_address, (unsigned int *)&addr_size) < 0) {
    return (int)-1;
  } else {
    return ((int)ntohs(local_address.sin_port));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getPortBySock>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  movl   $0x4,0x4(%rsp)
  call   <getpeername@plt>
  test   %rax,%rax
  js     L3
  mov    (%rsp),%edi
  call   <ntohs@plt>
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nop
L3:
  mov    $0xffffffff,%eax
  jmp    L5
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getPortBySock(int sock) {
  struct sockaddr_in local_address;
  int addr_size = sizeof(local_address);
  if (getpeername(sock, (struct sockaddr *)&local_address, (unsigned int *)&addr_size) < 0) {
    return (int)-1;
  } else {
    return ((int)ntohs(local_address.sin_port));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L51
L4:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L65
L55:
  mov    -0x10(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    %edx,-0x14(%rbp)
  jne    L56
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L65:
  cmpl   $0x0,-0x10(%rbp)
  jg     L55
  cmpl   $0x0,-0xc(%rbp)
  je     L57
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L57:
  addl   $0x1,-0x14(%rbp)
L51:
  cmpl   $0x9,-0x14(%rbp)
  jle    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D22
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string

tool: D18: A:

tool: D22: %d

tool: D3: %d puti %d


assistant: ```c
int main() {
  int s = 0, a, acp, br;
  printf("A:");
  scanf("%d", &a);
  while (s < 10) {
    br = 0;
    acp = a;
    while (acp >= 1) {
      if (acp % 10 == s)
        br++;
      acp /= 10;
    }
    if (br != 0)
      printf("%d puti %d\n", br, s);
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
  jmp    L24
L3:
  mov    %eax,%edx
L76:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  cmp    %ebx,%ecx
  sete   %al
  movzbl %al,%eax
  add    %eax,%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  cmp    $0x9,%edx
  jg     L3
  test   %esi,%esi
  jne    L54
L68:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L42
L24:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L68
  mov    $0x0,%esi
  jmp    L76
L54:
  mov    %ebx,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L68
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D26: A:

tool: D7: %d

tool: D17: %d puti %d


assistant: ```c
int main() {
  int s = 0, a, acp, br;
  printf("A:");
  scanf("%d", &a);
  while (s < 10) {
    br = 0;
    acp = a;
    while (acp >= 1) {
      if (acp % 10 == s)
        br++;
      acp /= 10;
    }
    if (br != 0)
      printf("%d puti %d\n", br, s);
    s++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L30
  xor    %esi,%esi
  jmp    L57
  nopl   0x0(%rax)
L17:
  mov    %eax,%edx
L57:
  mov    %edx,%eax
  mov    %edx,%edi
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  xor    %ecx,%ecx
  cmp    %r12d,%edi
  sete   %cl
  add    %ecx,%esi
  cmp    $0x9,%edx
  jg     L17
  test   %esi,%esi
  je     L30
  mov    %r12d,%edx
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L30:
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L3
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type: string
name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D5
type: string

tool: D7: A:

tool: D13: %d puti %d


tool: D5: %d

assistant: ```c
int main() {
  int s = 0, a, acp, br;
  printf("A:");
  scanf("%d", &a);
  while (s < 10) {
    br = 0;
    acp = a;
    while (acp >= 1) {
      if (acp % 10 == s)
        br++;
      acp /= 10;
    }
    if (br != 0)
      printf("%d puti %d\n", br, s);
    s++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L30:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L36
  xor    %esi,%esi
  jmp    L20
  nopl   0x0(%rax)
L49:
  mov    %eax,%edx
L20:
  mov    %edx,%eax
  mov    %edx,%edi
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  xor    %ecx,%ecx
  cmp    %edi,%r12d
  sete   %cl
  add    %ecx,%esi
  cmp    $0x9,%edx
  jg     L49
  test   %esi,%esi
  je     L31
  mov    %r12d,%edx
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L31:
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L30
  nop
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D28
type_guessed: string
name: retrieve_data
arguments: data_label: D24
type_guessed: string
name: retrieve_data
arguments: data_label: D23
type_guessed: string

tool: D28: A:

tool: D24: %d puti %d


tool: D23: %d

assistant: ```c
int main() {
  int s = 0, a, acp, br;
  printf("A:");
  scanf("%d", &a);
  while (s < 10) {
    br = 0;
    acp = a;
    while (acp >= 1) {
      if (acp % 10 == s)
        br++;
      acp /= 10;
    }
    if (br != 0)
      printf("%d puti %d\n", br, s);
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <f@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: hello world


assistant: ```c
int main(int argc, char **argv) {
  f();
  printf("hello world\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: hello world


assistant: ```c
int main(int argc, char **argv) {
  f();
  printf("hello world\n");
  return 0;
}
```