ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GET_UAA16LE>:
  endbr64
  mov    %esi,%esi
  lea    (%rdi,%rsi,2),%rax
  movzbl 0x1(%rax),%edx
  shl    $0x8,%edx
  movzbl (%rax),%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned short GET_UAA16LE(void *p, unsigned int i) {
  unsigned char *_p = (unsigned char *)&((unsigned short *)p)[i];
  return (unsigned short)_p[0] | (unsigned short)_p[1] << 8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GET_UAA16LE>:
  endbr64
  mov    %esi,%esi
  movzwl (%rdi,%rsi,2),%eax
  ret
```

assistant: ```c
unsigned short GET_UAA16LE(void *p, unsigned int i) {
  unsigned char *_p = (unsigned char *)&((unsigned short *)p)[i];
  return (unsigned short)_p[0] | (unsigned short)_p[1] << 8;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GET_UAA16LE>:
  endbr64
  mov    %esi,%esi
  movzwl (%rdi,%rsi,2),%eax
  ret
```

assistant: ```c
unsigned short GET_UAA16LE(void *p, unsigned int i) {
  unsigned char *_p = (unsigned char *)&((unsigned short *)p)[i];
  return (unsigned short)_p[0] | (unsigned short)_p[1] << 8;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_both_positive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x18(%rbp)
  movl   $0x14,-0x14(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x1e,-0x10(%rbp)
  movl   $0x28,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap_bits@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x14,%eax
  jne    L0
  mov    -0x14(%rbp),%eax
  cmp    $0xa,%eax
  jne    L0
  mov    -0x10(%rbp),%eax
  cmp    $0x28,%eax
  jne    L0
  mov    -0xc(%rbp),%eax
  cmp    $0x1e,%eax
  jne    L0
  mov    $0x1,%eax
  jmp    L26
L0:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int test_both_positive() {
  int a = 10;
  int b = 20;
  swap(&a, &b);
  int c = 30;
  int d = 40;
  swap_bits(&c, &d);
  return a == 20 && b == 10 && c == 40 && d == 30;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_both_positive>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x8(%rsp)
  movl   $0x14,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <swap@plt>
  movl   $0x1e,0x10(%rsp)
  movl   $0x28,0x14(%rsp)
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <swap_bits@plt>
  mov    $0x0,%eax
  cmpl   $0x14,0x8(%rsp)
  je     L49
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x28,%rsp
  ret
L49:
  cmpl   $0xa,0xc(%rsp)
  jne    L21
  cmpl   $0x28,0x10(%rsp)
  jne    L21
  cmpl   $0x1e,0x14(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L21
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_both_positive() {
  int a = 10;
  int b = 20;
  swap(&a, &b);
  int c = 30;
  int d = 40;
  swap_bits(&c, &d);
  return a == 20 && b == 10 && c == 40 && d == 30;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_both_positive>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0xa,0x8(%rsp)
  movl   $0x14,0xc(%rsp)
  call   <swap@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movl   $0x1e,0x10(%rsp)
  movl   $0x28,0x14(%rsp)
  call   <swap_bits@plt>
  xor    %eax,%eax
  cmpl   $0x14,0x8(%rsp)
  je     L13
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L13:
  cmpl   $0xa,0xc(%rsp)
  jne    L29
  cmpl   $0x28,0x10(%rsp)
  jne    L29
  xor    %eax,%eax
  cmpl   $0x1e,0x14(%rsp)
  sete   %al
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_both_positive() {
  int a = 10;
  int b = 20;
  swap(&a, &b);
  int c = 30;
  int d = 40;
  swap_bits(&c, &d);
  return a == 20 && b == 10 && c == 40 && d == 30;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_both_positive>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0xa,0x8(%rsp)
  movl   $0x14,0xc(%rsp)
  call   <swap@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movl   $0x1e,0x10(%rsp)
  movl   $0x28,0x14(%rsp)
  call   <swap_bits@plt>
  xor    %eax,%eax
  cmpl   $0x14,0x8(%rsp)
  je     L42
L38:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L42:
  cmpl   $0xa,0xc(%rsp)
  jne    L38
  cmpl   $0x28,0x10(%rsp)
  jne    L38
  xor    %eax,%eax
  cmpl   $0x1e,0x14(%rsp)
  sete   %al
  jmp    L38
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_both_positive() {
  int a = 10;
  int b = 20;
  swap(&a, &b);
  int c = 30;
  int d = 40;
  swap_bits(&c, &d);
  return a == 20 && b == 10 && c == 40 && d == 30;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tun_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L7:
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L20
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x24(%rbp),%eax
  jmp    L11
L20:
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int tun_alloc(char *dev, int fd) {
  struct ifreq ifr;
  int err;
  memset(&ifr, 0, sizeof(ifr));
  ifr.ifr_flags = IFF_TUN;
  if (*dev) {
    strncpy(ifr.ifr_name, dev, IFNAMSIZ);
    ifr.ifr_name[IFNAMSIZ - 1] = '\0';
  }
  if ((err = ioctl(fd, TUNSETIFF, (void *)&ifr)) < 0) {
    close(fd);
    return err;
  }
  strcpy(dev, ifr.ifr_name);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tun_alloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  cmpb   $0x0,0x0(%rbp)
  jne    L24
L43:
  mov    %rsp,%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <ioctl@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L29
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%ebx
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    D10(%rip),%rbx
  mov    (%rbx),%edx
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <strncpy@plt>
  movslq (%rbx),%rax
  mov    (%rsp),%rdx
  movb   $0x0,-0x1(%rdx,%rax,1)
  jmp    L43
L29:
  mov    %r12d,%edi
  call   <close@plt>
  jmp    L40
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tun_alloc(char *dev, int fd) {
  struct ifreq ifr;
  int err;
  memset(&ifr, 0, sizeof(ifr));
  ifr.ifr_flags = IFF_TUN;
  if (*dev) {
    strncpy(ifr.ifr_name, dev, IFNAMSIZ);
    ifr.ifr_name[IFNAMSIZ - 1] = '\0';
  }
  if ((err = ioctl(fd, TUNSETIFF, (void *)&ifr)) < 0) {
    close(fd);
    return err;
  }
  strcpy(dev, ifr.ifr_name);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tun_alloc>:
  endbr64
  push   %r13
  mov    $0x10,%edx
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D7(%rip),%rax
  cmpb   $0x0,0x0(%rbp)
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  jne    L19
L45:
  mov    D22(%rip),%rax
  mov    %r12,%rdx
  mov    %r13d,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L21
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  xor    %r12d,%r12d
  call   <strcpy@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  mov    D27(%rip),%rbx
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  mov    (%rbx),%edx
  call   <strncpy@plt>
  movslq (%rbx),%rax
  mov    (%rsp),%rdx
  movb   $0x0,-0x1(%rdx,%rax,1)
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r13d,%edi
  call   <close@plt>
  jmp    L13
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tun_alloc(char *dev, int fd) {
  struct ifreq ifr;
  int err;
  memset(&ifr, 0, sizeof(ifr));
  ifr.ifr_flags = IFF_TUN;
  if (*dev) {
    strncpy(ifr.ifr_name, dev, IFNAMSIZ);
    ifr.ifr_name[IFNAMSIZ - 1] = '\0';
  }
  if ((err = ioctl(fd, TUNSETIFF, (void *)&ifr)) < 0) {
    close(fd);
    return err;
  }
  strcpy(dev, ifr.ifr_name);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tun_alloc>:
  endbr64
  push   %r13
  mov    $0x10,%edx
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D2(%rip),%rax
  cmpb   $0x0,0x0(%rbp)
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  jne    L2
L41:
  mov    D24(%rip),%rax
  mov    %r12,%rdx
  mov    %r13d,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L47
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  xor    %r12d,%r12d
  call   <strcpy@plt>
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  mov    D5(%rip),%rbx
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  mov    (%rbx),%edx
  call   <strncpy@plt>
  movslq (%rbx),%rax
  mov    (%rsp),%rdx
  movb   $0x0,-0x1(%rdx,%rax,1)
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r13d,%edi
  call   <close@plt>
  jmp    L24
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tun_alloc(char *dev, int fd) {
  struct ifreq ifr;
  int err;
  memset(&ifr, 0, sizeof(ifr));
  ifr.ifr_flags = IFF_TUN;
  if (*dev) {
    strncpy(ifr.ifr_name, dev, IFNAMSIZ);
    ifr.ifr_name[IFNAMSIZ - 1] = '\0';
  }
  if ((err = ioctl(fd, TUNSETIFF, (void *)&ifr)) < 0) {
    close(fd);
    return err;
  }
  strcpy(dev, ifr.ifr_name);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_isupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L8
  cmpl   $0x40,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void test_isupper(int x) {
  if (isupper(x))
    clang_analyzer_eval(x < 'A');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_isupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isupper@plt>
  test   %rax,%rax
  jne    L18
L17:
  pop    %rbx
  ret
L18:
  cmp    $0x40,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  jmp    L17
```

assistant: ```c
void test_isupper(int x) {
  if (isupper(x))
    clang_analyzer_eval(x < 'A');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_isupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isupper@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %edi,%edi
  cmp    $0x40,%ebx
  pop    %rbx
  setle  %dil
  jmp    1070 <clang_analyzer_eval@plt>
```

assistant: ```c
void test_isupper(int x) {
  if (isupper(x))
    clang_analyzer_eval(x < 'A');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_isupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isupper@plt>
  test   %rax,%rax
  jne    L5
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %edi,%edi
  cmp    $0x40,%ebx
  pop    %rbx
  setle  %dil
  jmp    1070 <clang_analyzer_eval@plt>
```

assistant: ```c
void test_isupper(int x) {
  if (isupper(x))
    clang_analyzer_eval(x < 'A');
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ns_name_uncompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %rdx,-0x438(%rbp)
  mov    %rcx,-0x440(%rbp)
  mov    %r8,-0x448(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rcx
  mov    -0x438(%rbp),%rdx
  mov    -0x430(%rbp),%rsi
  mov    -0x428(%rbp),%rax
  mov    $0x3fc,%r8d
  mov    %rax,%rdi
  call   <ns_name_unpack@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0xffffffff,-0x414(%rbp)
  jne    L39
  mov    $0xffffffff,%eax
  jmp    L0
L39:
  mov    -0x448(%rbp),%rdx
  mov    -0x440(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ns_name_ntop@plt>
  cmp    $0xffffffff,%eax
  jne    L48
  mov    $0xffffffff,%eax
  jmp    L0
L48:
  mov    -0x414(%rbp),%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int ns_name_uncompress(const u_char *msg, const u_char *eom, const u_char *src, char *dst, size_t dstsiz) {
  u_char tmp[255];
  int n;
  if ((n = ns_name_unpack(msg, eom, src, tmp, sizeof tmp)) == -1) {
    return -1;
  }
  if (ns_name_ntop(tmp, dst, dstsiz) == -1) {
    return -1;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ns_name_uncompress>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rcx,%rbp
  mov    %r8,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  mov    $0x3fc,%r8d
  call   <ns_name_unpack@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L11
  mov    %rsp,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <ns_name_ntop@plt>
  cmp    $0xffffffff,%eax
  cmove  %eax,%ebx
L11:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %ebx,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ns_name_uncompress(const u_char *msg, const u_char *eom, const u_char *src, char *dst, size_t dstsiz) {
  u_char tmp[255];
  int n;
  if ((n = ns_name_unpack(msg, eom, src, tmp, sizeof tmp)) == -1) {
    return -1;
  }
  if (ns_name_ntop(tmp, dst, dstsiz) == -1) {
    return -1;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ns_name_uncompress>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  mov    $0x3fc,%r8d
  push   %r12
  push   %rbp
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  call   <ns_name_unpack@plt>
  cmp    $0xffffffff,%eax
  je     L21
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <ns_name_ntop@plt>
  cmp    $0xffffffff,%eax
  je     L21
L39:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L21:
  mov    $0xffffffff,%r12d
  jmp    L39
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ns_name_uncompress(const u_char *msg, const u_char *eom, const u_char *src, char *dst, size_t dstsiz) {
  u_char tmp[255];
  int n;
  if ((n = ns_name_unpack(msg, eom, src, tmp, sizeof tmp)) == -1) {
    return -1;
  }
  if (ns_name_ntop(tmp, dst, dstsiz) == -1) {
    return -1;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ns_name_uncompress>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  mov    $0x3fc,%r8d
  push   %r12
  push   %rbp
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  call   <ns_name_unpack@plt>
  cmp    $0xffffffff,%eax
  je     L4
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <ns_name_ntop@plt>
  cmp    $0xffffffff,%eax
  je     L4
L38:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%r12d
  jmp    L38
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ns_name_uncompress(const u_char *msg, const u_char *eom, const u_char *src, char *dst, size_t dstsiz) {
  u_char tmp[255];
  int n;
  if ((n = ns_name_unpack(msg, eom, src, tmp, sizeof tmp)) == -1) {
    return -1;
  }
  if (ns_name_ntop(tmp, dst, dstsiz) == -1) {
    return -1;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x8,-0x54(%rbp)
  jne    L98
  mov    $0x0,%eax
  jmp    L93
L98:
  movl   $0x0,-0x34(%rbp)
  jmp    L78
L15:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L78:
  cmpl   $0x6,-0x34(%rbp)
  jle    L15
  movl   $0x0,-0x34(%rbp)
  jmp    L77
L61:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp,%rdx,4),%edx
  sub    $0x1,%edx
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <data_iszerocost@plt>
  test   %rax,%rax
  je     L44
  mov    $0x1,%eax
  jmp    L93
L44:
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <recurse>
  test   %eax,%eax
  je     L84
  mov    $0x1,%eax
  jmp    L93
L84:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L77:
  cmpl   $0x3,-0x34(%rbp)
  jg     L91
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L61
L91:
  mov    $0x0,%eax
L93:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

assistant: ```c
int recurse(int *cost, int **indef, int c) {
  if (c == 8)
    return 0;
  int i;
  int ncost[7];
  for (i = 0; i < 7; i++)
    ncost[i] = cost[i];
  for (i = 0; i < 4 && indef[c][i] != -1; i++) {
    ncost[indef[c][i]]--;
    if (data_iszerocost(ncost))
      return 1;
    if (recurse(ncost, indef, c + 1))
      return 1;
    ncost[indef[c][i]]++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recurse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x8,%edx
  je     L93
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%eax
L87:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x1c,%rax
  jne    L87
  movslq %ebp,%rax
  lea    (%r12,%rax,8),%r13
  mov    $0x0,%ebx
  mov    %rsp,%r14
  jmp    L73
L77:
  mov    0x0(%r13),%rdx
  movslq (%rdx,%rbx,1),%rdx
  addl   $0x1,(%rsp,%rdx,4)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  je     L93
L73:
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%eax
  cmp    $0xffffffff,%eax
  je     L98
  cltq
  subl   $0x1,(%rsp,%rax,4)
  mov    %r14,%rdi
  call   <data_iszerocost@plt>
  test   %rax,%rax
  jne    L34
  lea    0x1(%rbp),%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <recurse>
  test   %eax,%eax
  je     L77
  mov    $0x1,%eax
  jmp    L93
L98:
  mov    $0x0,%eax
L93:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  mov    $0x1,%eax
  jmp    L93
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recurse(int *cost, int **indef, int c) {
  if (c == 8)
    return 0;
  int i;
  int ncost[7];
  for (i = 0; i < 7; i++)
    ncost[i] = cost[i];
  for (i = 0; i < 4 && indef[c][i] != -1; i++) {
    ncost[indef[c][i]]--;
    if (data_iszerocost(ncost))
      return 1;
    if (recurse(ncost, indef, c + 1))
      return 1;
    ncost[indef[c][i]]++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<recurse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x8,%edx
  je     L22
  mov    0x10(%rdi),%rax
  movdqu (%rdi),%xmm0
  mov    %rsi,%rbp
  mov    %edx,%ebx
  xor    %r14d,%r14d
  mov    %rsp,%r12
  mov    %rax,0x10(%rsp)
  mov    0x18(%rdi),%eax
  movaps %xmm0,(%rsp)
  mov    %eax,0x18(%rsp)
  movslq %edx,%rax
  lea    (%rsi,%rax,8),%r13
  mov    0x0(%r13),%rax
L38:
  movslq (%rax,%r14,1),%rax
  cmp    $0xffffffff,%eax
  je     L22
  mov    %r12,%rdi
  subl   $0x1,(%rsp,%rax,4)
  call   <data_iszerocost@plt>
  test   %rax,%rax
  jne    L35
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <recurse>
  test   %eax,%eax
  jne    L35
  mov    0x0(%r13),%rax
  movslq (%rax,%r14,1),%rdx
  add    $0x4,%r14
  addl   $0x1,(%rsp,%rdx,4)
  cmp    $0x10,%r14
  jne    L38
L22:
  xor    %eax,%eax
L15:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L35:
  mov    $0x1,%eax
  jmp    L15
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recurse(int *cost, int **indef, int c) {
  if (c == 8)
    return 0;
  int i;
  int ncost[7];
  for (i = 0; i < 7; i++)
    ncost[i] = cost[i];
  for (i = 0; i < 4 && indef[c][i] != -1; i++) {
    ncost[indef[c][i]]--;
    if (data_iszerocost(ncost))
      return 1;
    if (recurse(ncost, indef, c + 1))
      return 1;
    ncost[indef[c][i]]++;
  }
  return 0;
}
```