ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x7c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] -= state[0UL];
          state[local1] = state[0UL] + state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x7c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] -= state[0UL];
          state[local1] = state[0UL] + state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x7c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] -= state[0UL];
          state[local1] = state[0UL] + state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L13:
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x2,-0xc(%rbp)
  jle    L13
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D23
datatype: string
name: parse_data
arguments: tag: D22
datatype: string

tool: D9: float64_set_low_word

tool: D23: # c::native::%s


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_set_low_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D1(%rip),%r13
  lea    D28(%rip),%r12
  lea    D14(%rip),%rbp
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D28
type: string
name: parse_data
arguments: tag: D14
type: string

tool: D1: float64_set_low_word

tool: D28: # c::native::%s


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_set_low_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D23(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D16
type_guessed: string

tool: D23: float64_set_low_word

tool: D1: # c::native::%s


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_set_low_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D6(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L6
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string

tool: D6: float64_set_low_word

tool: D4: # c::native::%s


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_set_low_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x34333231,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <myatoi@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d


assistant: ```c
main() {
  char a[] = "1234";
  printf("%d\n", atoi(a));
  printf("%d\n", myatoi(a));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x34333231,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x3(%rsp),%rbp
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <myatoi@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2: %d


assistant: ```c
main() {
  char a[] = "1234";
  printf("%d\n", atoi(a));
  printf("%d\n", myatoi(a));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  movl   $0x34333231,0x3(%rsp)
  mov    %r12,%rdi
  movb   $0x0,0x7(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <myatoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
main() {
  char a[] = "1234";
  printf("%d\n", atoi(a));
  printf("%d\n", myatoi(a));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  movl   $0x34333231,0x3(%rsp)
  mov    %r12,%rdi
  movb   $0x0,0x7(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <myatoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: %d


assistant: ```c
main() {
  char a[] = "1234";
  printf("%d\n", atoi(a));
  printf("%d\n", myatoi(a));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %eax,%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <cbrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm2
  movss  -0x10(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mov    -0x18(%rbp),%eax
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D2
datatype: string

tool: D16: %d

tool: D2: %.1f %.1f %.1f %.1f


assistant: ```c
int main() {
  int number = 0;
  float quadrado = 0.0;
  float cubo = 0.0;
  float raizq = 0.0;
  float raizc = 0.0;
  scanf("%d", &number);
  quadrado = number * number;
  cubo = number * number * number;
  raizq = sqrt(number);
  raizc = cbrt(number);
  printf("%.1f %.1f %.1f %.1f\n", quadrado, cubo, raizq, raizc);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    0x14(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ebx
  mov    %ebx,%ebp
  imul   %ebx,%ebp
  mov    %ebx,%edi
  call   <sqrt@plt>
  movss  %xmm0,0xc(%rsp)
  mov    0x14(%rsp),%edi
  call   <cbrt@plt>
  movaps %xmm0,%xmm3
  imul   %ebp,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D13
data_type: string

tool: D19: %d

tool: D13: %.1f %.1f %.1f %.1f


assistant: ```c
int main() {
  int number = 0;
  float quadrado = 0.0;
  float cubo = 0.0;
  float raizq = 0.0;
  float raizc = 0.0;
  scanf("%d", &number);
  quadrado = number * number;
  cubo = number * number * number;
  raizq = sqrt(number);
  raizc = cbrt(number);
  printf("%.1f %.1f %.1f %.1f\n", quadrado, cubo, raizq, raizc);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  movl   $0x0,0x14(%rsp)
  call   <scanf@plt>
  mov    0x14(%rsp),%ebx
  mov    %ebx,%ebp
  mov    %ebx,%edi
  call   <sqrt@plt>
  imul   %ebx,%ebp
  mov    0x14(%rsp),%edi
  movss  %xmm0,0xc(%rsp)
  call   <cbrt@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm2
  lea    D12(%rip),%rdi
  imul   %ebp,%ebx
  movaps %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %ebx,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D12
data_type: string

tool: D19: %d

tool: D12: %.1f %.1f %.1f %.1f


assistant: ```c
int main() {
  int number = 0;
  float quadrado = 0.0;
  float cubo = 0.0;
  float raizq = 0.0;
  float raizc = 0.0;
  scanf("%d", &number);
  quadrado = number * number;
  cubo = number * number * number;
  raizq = sqrt(number);
  raizc = cbrt(number);
  printf("%.1f %.1f %.1f %.1f\n", quadrado, cubo, raizq, raizc);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  movl   $0x0,0x14(%rsp)
  call   <scanf@plt>
  mov    0x14(%rsp),%ebx
  mov    %ebx,%ebp
  mov    %ebx,%edi
  call   <sqrt@plt>
  imul   %ebx,%ebp
  mov    0x14(%rsp),%edi
  movss  %xmm0,0xc(%rsp)
  call   <cbrt@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm2
  lea    D7(%rip),%rdi
  imul   %ebp,%ebx
  movaps %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %ebx,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D1: %d

tool: D7: %.1f %.1f %.1f %.1f


assistant: ```c
int main() {
  int number = 0;
  float quadrado = 0.0;
  float cubo = 0.0;
  float raizq = 0.0;
  float raizc = 0.0;
  scanf("%d", &number);
  quadrado = number * number;
  cubo = number * number * number;
  raizq = sqrt(number);
  raizc = cbrt(number);
  printf("%.1f %.1f %.1f %.1f\n", quadrado, cubo, raizq, raizc);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<allocateLongVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  mov    $0x0,%eax
  call   <memoryCheck@plt>
L29:
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long int *allocateLongVector(int n) {
  int i;
  long int *vector;
  if ((vector = (long int *)calloc(n, sizeof(long int))) == NULL)
    memoryCheck();
  for (i = 0; i < n; i++)
    vector[i] = 0.0;
  return vector;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<allocateLongVector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L18
L1:
  test   %ebx,%ebx
  jle    L30
  mov    %rbp,%rax
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,8),%rdx
L27:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L27
L30:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0x0,%eax
  call   <memoryCheck@plt>
  jmp    L1
```

assistant: ```c
long int *allocateLongVector(int n) {
  int i;
  long int *vector;
  if ((vector = (long int *)calloc(n, sizeof(long int))) == NULL)
    memoryCheck();
  for (i = 0; i < n; i++)
    vector[i] = 0.0;
  return vector;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<allocateLongVector>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L28:
  test   %ebx,%ebx
  jle    L17
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L15:
  xor    %eax,%eax
  call   <memoryCheck@plt>
  jmp    L28
```

assistant: ```c
long int *allocateLongVector(int n) {
  int i;
  long int *vector;
  if ((vector = (long int *)calloc(n, sizeof(long int))) == NULL)
    memoryCheck();
  for (i = 0; i < n; i++)
    vector[i] = 0.0;
  return vector;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<allocateLongVector>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L16:
  test   %ebx,%ebx
  jle    L4
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L11:
  xor    %eax,%eax
  call   <memoryCheck@plt>
  jmp    L16
```

assistant: ```c
long int *allocateLongVector(int n) {
  int i;
  long int *vector;
  if ((vector = (long int *)calloc(n, sizeof(long int))) == NULL)
    memoryCheck();
  for (i = 0; i < n; i++)
    vector[i] = 0.0;
  return vector;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L34
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L10
L34:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_pow_ui@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  jmp    L47
L45:
  mov    -0x4(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mul_ui@plt>
  mov    -0x8(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add_ui@plt>
L47:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  js     L45
  mov    -0x4(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add_ui@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L36
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L36:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D2: usage : fermat n


tool: D1: OK


tool: D10: NG


assistant: ```c
int main(int ac, char *av[]) {
  int n;
  mpz_t f, p, i;
  if (ac < 2) {
    printf("usage : fermat n\n");
    return (1);
  }
  n = strtol(av[1], NULL, 10);
  mpz_init_set_ui(p, 2);
  mpz_pow_ui(p, p, n);
  mpz_init_set_ui(i, 1);
  mpz_init_set_ui(f, 2);
  while (mpz_cmp(i, p) < 0) {
    mpz_mul_ui(f, f, 2);
    mpz_add_ui(i, i, 1);
  }
  mpz_add_ui(f, f, 1);
  if (isprime(f))
    printf("OK\n");
  else
    printf("NG\n");
  mpz_clear(f);
  mpz_clear(p);
  mpz_clear(i);
  return (0);
}
```