ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%r15
  push   %r14
  push   %r13
  lea    D36(%rip),%r13
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0xf(%rsp),%r12
  call   <initialize@plt>
  jmp    L63
  nop
L74:
  cmp    $0x1,%eax
  je     L56
L81:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x59,%al
  jne    L35
L63:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x2,%eax
  je     L44
  cmp    $0x3,%eax
  jne    L74
  xor    %eax,%eax
  call   <display@plt>
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  call   <dequeue@plt>
  jmp    L81
  nopl   0x0(%rax)
L56:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  lea    0x14(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <enqueue@plt>
  jmp    L81
  nopl   0x0(%rax)
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D32
datatype: string
name: read_data
arguments: label: D36
datatype: string
name: read_data
arguments: label: D28
datatype: string
name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D2
datatype: string

tool: D32: 1. Insert
2. Delete
3. Display
4. Exit

tool: D36: Continue?

tool: D28:  %c%*c

tool: D5:  %d%*c

tool: D2: Item?

assistant: ```c
int main() {
  int choice, item;
  char ans;
  initialize();
  do {
    puts("1. Insert\n2. Delete\n3. Display\n4. Exit");
    scanf(" %d%*c", &choice);
    switch (choice) {
    case 1:
      puts("Item?");
      scanf(" %d%*c", &item);
      enqueue(item);
      break;
    case 2:
      dequeue();
      break;
    case 3:
      display();
      break;
    }
    puts("Continue?");
    scanf(" %c%*c", &ans);
  } while (ans == 'Y' || ans == 'y');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RSHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x5c6b7,-0x4(%rbp)
  movl   $0xf8c9,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L5:
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L5
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int RSHash(char *str, unsigned int len) {
  unsigned int b = 378551;
  unsigned int a = 63689;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash * a + (unsigned char)(*str);
    a = a * b;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RSHash>:
  endbr64
  test   %esi,%esi
  je     L10
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rsi
  mov    $0x0,%eax
  mov    $0xf8c9,%edx
L18:
  imul   %edx,%eax
  movzbl (%rdi),%ecx
  add    %ecx,%eax
  imul   $0x5c6b7,%edx,%edx
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L18
  ret
L10:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int RSHash(char *str, unsigned int len) {
  unsigned int b = 378551;
  unsigned int a = 63689;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash * a + (unsigned char)(*str);
    a = a * b;
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RSHash>:
  endbr64
  test   %esi,%esi
  je     L18
  mov    %esi,%esi
  xor    %eax,%eax
  mov    $0xf8c9,%edx
  add    %rdi,%rsi
  nopl   0x0(%rax)
L13:
  imul   %edx,%eax
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  imul   $0x5c6b7,%edx,%edx
  add    %ecx,%eax
  cmp    %rdi,%rsi
  jne    L13
  ret
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int RSHash(char *str, unsigned int len) {
  unsigned int b = 378551;
  unsigned int a = 63689;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash * a + (unsigned char)(*str);
    a = a * b;
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RSHash>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    %esi,%esi
  xor    %eax,%eax
  mov    $0xf8c9,%edx
  add    %rdi,%rsi
  nopl   0x0(%rax)
L11:
  imul   %edx,%eax
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  imul   $0x5c6b7,%edx,%edx
  add    %ecx,%eax
  cmp    %rsi,%rdi
  jne    L11
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int RSHash(char *str, unsigned int len) {
  unsigned int b = 378551;
  unsigned int a = 63689;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash * a + (unsigned char)(*str);
    a = a * b;
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<func3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func3() {
  int local_var;
  static char my_static_local_l = 'a';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func3>:
  endbr64
  ret
```

assistant: ```c
void func3() {
  int local_var;
  static char my_static_local_l = 'a';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func3>:
  endbr64
  ret
```

assistant: ```c
void func3() {
  int local_var;
  static char my_static_local_l = 'a';
}
```
user: What is the c source code of the assembly code below?

```asm
<func3>:
  endbr64
  ret
```

assistant: ```c
void func3() {
  int local_var;
  static char my_static_local_l = 'a';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    %eax,%ebx
  mov    %ebx,%edx
  lea    (%r12,%rdx,1),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <inStr@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0xffffffff,-0x2c(%rbp)
  je     L12
  mov    -0x2c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <substring@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x2c(%rbp),%edx
  add    %edx,%eax
  sub    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x2c(%rbp),%edx
  lea    (%rax,%rdx,1),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ebx,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <substring@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str3cat@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <replace>
  jmp    L5
L12:
  mov    -0x38(%rbp),%rax
L5:
  add    $0x40,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *replace(char *text, char *from, char *to) {
  char *ret = (char *)calloc(strlen(text) + (strlen(to) - strlen(from)), sizeof(char));
  char *left;
  char *right;
  int pos = inStr(text, strlen(text), from);
  if (pos != -1) {
    left = substring(text, 0, pos);
    right = substring(text, pos + strlen(from), strlen(text) - (pos + strlen(from)));
    ret = str3cat(left, to, right);
    return replace(ret, from, to);
  }
  return text;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %eax,%ebp
  lea    0x0(%rbp,%r14,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <inStr@plt>
  cmp    $0xffffffff,%eax
  jne    L4
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %eax,%ebp
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <substring@plt>
  mov    %rax,%r15
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  sub    %eax,%r14d
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%rax,%rbp,1),%esi
  mov    %r14d,%edx
  mov    %rbx,%rdi
  call   <substring@plt>
  mov    %rax,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <str3cat@plt>
  mov    %rax,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <replace>
  mov    %rax,%rbx
  jmp    L1
```

assistant: ```c
char *replace(char *text, char *from, char *to) {
  char *ret = (char *)calloc(strlen(text) + (strlen(to) - strlen(from)), sizeof(char));
  char *left;
  char *right;
  int pos = inStr(text, strlen(text), from);
  if (pos != -1) {
    left = substring(text, 0, pos);
    right = substring(text, pos + strlen(from), strlen(text) - (pos + strlen(from)));
    ret = str3cat(left, to, right);
    return replace(ret, from, to);
  }
  return text;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L11
  nopl   (%rax)
L4:
  mov    %eax,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %rbp,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r12,%rdi
  add    %ebx,%eax
  sub    %eax,%r14d
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %r14d,%edx
  lea    (%rax,%rbx,1),%esi
  call   <substring@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    %rax,%rdx
  call   <str3cat@plt>
  mov    %rax,%rbp
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    $0x1,%esi
  sub    %eax,%ebx
  lea    (%rbx,%r14,1),%edi
  call   <calloc@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <inStr@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L4
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *replace(char *text, char *from, char *to) {
  char *ret = (char *)calloc(strlen(text) + (strlen(to) - strlen(from)), sizeof(char));
  char *left;
  char *right;
  int pos = inStr(text, strlen(text), from);
  if (pos != -1) {
    left = substring(text, 0, pos);
    right = substring(text, pos + strlen(from), strlen(text) - (pos + strlen(from)));
    ret = str3cat(left, to, right);
    return replace(ret, from, to);
  }
  return text;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L8
  nopl   (%rax)
L13:
  mov    %eax,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %rbp,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r12,%rdi
  add    %ebx,%eax
  sub    %eax,%r14d
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %r14d,%edx
  lea    (%rax,%rbx,1),%esi
  call   <substring@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    %rax,%rdx
  call   <str3cat@plt>
  mov    %rax,%rbp
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    $0x1,%esi
  sub    %eax,%ebx
  lea    (%rbx,%r14,1),%edi
  call   <calloc@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <inStr@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L13
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *replace(char *text, char *from, char *to) {
  char *ret = (char *)calloc(strlen(text) + (strlen(to) - strlen(from)), sizeof(char));
  char *left;
  char *right;
  int pos = inStr(text, strlen(text), from);
  if (pos != -1) {
    left = substring(text, 0, pos);
    right = substring(text, pos + strlen(from), strlen(text) - (pos + strlen(from)));
    ret = str3cat(left, to, right);
    return replace(ret, from, to);
  }
  return text;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test1@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test2@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test3@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test4@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test5@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test6@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <test7@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  char buf[10];
  test1(buf);
  test2(buf);
  test3(buf);
  test4(buf);
  test5(buf);
  test6(buf);
  test7(buf);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdi
  call   <test1@plt>
  mov    %rbx,%rdi
  call   <test2@plt>
  mov    %rbx,%rdi
  call   <test3@plt>
  mov    %rbx,%rdi
  call   <test4@plt>
  mov    %rbx,%rdi
  call   <test5@plt>
  mov    %rbx,%rdi
  call   <test6@plt>
  mov    %rbx,%rdi
  call   <test7@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char buf[10];
  test1(buf);
  test2(buf);
  test3(buf);
  test4(buf);
  test5(buf);
  test6(buf);
  test7(buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <test1@plt>
  mov    %rbp,%rdi
  call   <test2@plt>
  mov    %rbp,%rdi
  call   <test3@plt>
  mov    %rbp,%rdi
  call   <test4@plt>
  mov    %rbp,%rdi
  call   <test5@plt>
  mov    %rbp,%rdi
  call   <test6@plt>
  mov    %rbp,%rdi
  call   <test7@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char buf[10];
  test1(buf);
  test2(buf);
  test3(buf);
  test4(buf);
  test5(buf);
  test6(buf);
  test7(buf);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <test1@plt>
  mov    %rbp,%rdi
  call   <test2@plt>
  mov    %rbp,%rdi
  call   <test3@plt>
  mov    %rbp,%rdi
  call   <test4@plt>
  mov    %rbp,%rdi
  call   <test5@plt>
  mov    %rbp,%rdi
  call   <test6@plt>
  mov    %rbp,%rdi
  call   <test7@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char buf[10];
  test1(buf);
  test2(buf);
  test3(buf);
  test4(buf);
  test5(buf);
  test6(buf);
  test7(buf);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<build_rotmatrix>:
  endbr64
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  0x10(%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  0x10(%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x40(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x48(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x50(%rdi)
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movq   $0x0,0x70(%rdi)
  mov    D2(%rip),%rax
  mov    %rax,0x78(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: f64

tool: D2: 1

assistant: ```c
void build_rotmatrix(double m[4][4], double quat[4]) {
  m[0][0] = ((quat[3]) * (quat[3])) + ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) - ((quat[2]) * (quat[2]));
  m[0][1] = 2.0 * (quat[0] * quat[1] - quat[2] * quat[3]);
  m[0][2] = 2.0 * (quat[2] * quat[0] + quat[1] * quat[3]);
  m[0][3] = 0.0;
  m[1][0] = 2.0 * (quat[0] * quat[1] + quat[2] * quat[3]);
  m[1][1] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) + ((quat[1]) * (quat[1])) - ((quat[2]) * (quat[2]));
  m[1][2] = 2.0 * (quat[1] * quat[2] - quat[0] * quat[3]);
  m[1][3] = 0.0;
  m[2][0] = 2.0 * (quat[2] * quat[0] - quat[1] * quat[3]);
  m[2][1] = 2.0 * (quat[1] * quat[2] + quat[0] * quat[3]);
  m[2][2] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) + ((quat[2]) * (quat[2]));
  m[2][3] = 0.0;
  m[3][0] = 0.0;
  m[3][1] = 0.0;
  m[3][2] = 0.0;
  m[3][3] = 1.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<build_rotmatrix>:
  endbr64
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm3,%xmm3
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  (%rsi),%xmm0
  movsd  0x10(%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  movq   $0x0,0x18(%rdi)
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  (%rsi),%xmm0
  movsd  0x10(%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm3,%xmm3
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  subsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  movq   $0x0,0x38(%rdi)
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x30(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  (%rsi),%xmm0
  mov    D5(%rip),%rax
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x40(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x48(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mov    %rax,0x78(%rdi)
  mulsd  %xmm0,%xmm0
  movq   $0x0,0x58(%rdi)
  mulsd  %xmm3,%xmm3
  movq   $0x0,0x60(%rdi)
  mulsd  %xmm2,%xmm2
  movq   $0x0,0x68(%rdi)
  mulsd  %xmm1,%xmm1
  movq   $0x0,0x70(%rdi)
  subsd  %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x50(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: f64

tool: D5: 1

assistant: ```c
void build_rotmatrix(double m[4][4], double quat[4]) {
  m[0][0] = ((quat[3]) * (quat[3])) + ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) - ((quat[2]) * (quat[2]));
  m[0][1] = 2.0 * (quat[0] * quat[1] - quat[2] * quat[3]);
  m[0][2] = 2.0 * (quat[2] * quat[0] + quat[1] * quat[3]);
  m[0][3] = 0.0;
  m[1][0] = 2.0 * (quat[0] * quat[1] + quat[2] * quat[3]);
  m[1][1] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) + ((quat[1]) * (quat[1])) - ((quat[2]) * (quat[2]));
  m[1][2] = 2.0 * (quat[1] * quat[2] - quat[0] * quat[3]);
  m[1][3] = 0.0;
  m[2][0] = 2.0 * (quat[2] * quat[0] - quat[1] * quat[3]);
  m[2][1] = 2.0 * (quat[1] * quat[2] + quat[0] * quat[3]);
  m[2][2] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) + ((quat[2]) * (quat[2]));
  m[2][3] = 0.0;
  m[3][0] = 0.0;
  m[3][1] = 0.0;
  m[3][2] = 0.0;
  m[3][3] = 1.0;
}
```