ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_mem>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D5(%rip),%rdi
  call   <os_error@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: Memory allocation failed

assistant: ```c
void *get_mem(size_t n) {
  void *p;
  p = (void *)malloc(n);
  if (p == NULL)
    os_error("Memory allocation failed");
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_mem>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  lea    D1(%rip),%rdi
  call   <os_error@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: Memory allocation failed

assistant: ```c
void *get_mem(size_t n) {
  void *p;
  p = (void *)malloc(n);
  if (p == NULL)
    os_error("Memory allocation failed");
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<d2s_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  jmp    L11
L18:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <lrint@plt>
  mov    %ax,(%rbx)
L11:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L18
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void d2s_array(double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<d2s_array>:
  endbr64
  sub    $0x1,%esi
  js     L7
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movq   %xmm0,%r13
  movslq %esi,%rbx
L12:
  movq   %r13,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  mov    %ax,(%r12,%rbx,2)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  ret
```

assistant: ```c
void d2s_array(double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<d2s_array>:
  endbr64
  sub    $0x1,%esi
  js     L6
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  movq   %r14,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  mov    %ax,(%r12,%rbx,2)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L6:
  ret
```

assistant: ```c
void d2s_array(double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<d2s_array>:
  endbr64
  sub    $0x1,%esi
  js     L0
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  movq   %r14,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  mov    %ax,(%r12,%rbx,2)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L0:
  ret
```

assistant: ```c
void d2s_array(double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<saturatemat>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cvtss2sd %xmm0,%xmm0
  movsd  D27(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm3
  mulsd  D18(%rip),%xmm3
  pxor   %xmm6,%xmm6
  cvtsd2ss %xmm3,%xmm6
  movapd %xmm1,%xmm2
  mulsd  D2(%rip),%xmm2
  pxor   %xmm5,%xmm5
  cvtsd2ss %xmm2,%xmm5
  mulsd  D3(%rip),%xmm1
  pxor   %xmm4,%xmm4
  cvtsd2ss %xmm1,%xmm4
  addsd  %xmm0,%xmm3
  cvtsd2ss %xmm3,%xmm3
  movss  %xmm3,(%rsp)
  movss  %xmm6,0x4(%rsp)
  movss  %xmm6,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movss  %xmm5,0x10(%rsp)
  addsd  %xmm0,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,0x14(%rsp)
  movss  %xmm5,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movss  %xmm4,0x20(%rsp)
  movss  %xmm4,0x24(%rsp)
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  movl   $0x0,0x38(%rsp)
  movl   $0x3f800000,0x3c(%rsp)
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  call   <matrixmult@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type: f64
name: unpack_data
arguments: data_tag: D18
type: byte[8]
name: unpack_data
arguments: data_tag: D2
type: byte[8]
name: unpack_data
arguments: data_tag: D3
type: byte[8]

tool: D27: 1

tool: {"D18": [0x00,0x00,0x00,0x40,0x1a,0xc0,0xd3,0x3f]}

tool: {"D2": [0x00,0x00,0x00,0x60,0x34,0x80,0xe3,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0xc0,0xf3,0xfd,0xb4,0x3f]}

assistant: ```c
void saturatemat(float mat[4][4], float sat) {
  float mmat[4][4];
  float a, b, c, d, e, f, g, h, i;
  float rwgt, gwgt, bwgt;
  rwgt = (0.3086);
  gwgt = (0.6094);
  bwgt = (0.0820);
  a = (1.0 - sat) * rwgt + sat;
  b = (1.0 - sat) * rwgt;
  c = (1.0 - sat) * rwgt;
  d = (1.0 - sat) * gwgt;
  e = (1.0 - sat) * gwgt + sat;
  f = (1.0 - sat) * gwgt;
  g = (1.0 - sat) * bwgt;
  h = (1.0 - sat) * bwgt;
  i = (1.0 - sat) * bwgt + sat;
  mmat[0][0] = a;
  mmat[0][1] = b;
  mmat[0][2] = c;
  mmat[0][3] = 0.0;
  mmat[1][0] = d;
  mmat[1][1] = e;
  mmat[1][2] = f;
  mmat[1][3] = 0.0;
  mmat[2][0] = g;
  mmat[2][1] = h;
  mmat[2][2] = i;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<saturatemat>:
  endbr64
  sub    $0x58,%rsp
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm6,%xmm6
  movsd  D32(%rip),%xmm1
  movsd  D15(%rip),%xmm3
  pxor   %xmm5,%xmm5
  mov    %rdi,%rsi
  pxor   %xmm4,%xmm4
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  subsd  %xmm0,%xmm1
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  movsd  D12(%rip),%xmm2
  movl   $0x0,0xc(%rsp)
  movabs $0x3f80000000000000,%rax
  movl   $0x0,0x1c(%rsp)
  mulsd  %xmm1,%xmm3
  mov    %rax,0x38(%rsp)
  mulsd  %xmm1,%xmm2
  movl   $0x0,0x2c(%rsp)
  mulsd  D24(%rip),%xmm1
  movq   $0x0,0x30(%rsp)
  cvtsd2ss %xmm3,%xmm6
  addsd  %xmm0,%xmm3
  movss  %xmm6,0x4(%rsp)
  cvtsd2ss %xmm2,%xmm5
  addsd  %xmm0,%xmm2
  movss  %xmm6,0x8(%rsp)
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm1,%xmm4
  movss  %xmm5,0x10(%rsp)
  cvtsd2ss %xmm3,%xmm3
  movss  %xmm5,0x18(%rsp)
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm3,(%rsp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm2,0x14(%rsp)
  movss  %xmm4,0x20(%rsp)
  movss  %xmm4,0x24(%rsp)
  movss  %xmm0,0x28(%rsp)
  call   <matrixmult@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D32
data_type: f64
name: extract_symbolic_data
arguments: data_label: D15
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D12
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D24
data_type: byte[8]

tool: D32: 1

tool: {"D15": [0x00,0x00,0x00,0x40,0x1a,0xc0,0xd3,0x3f]}

tool: {"D12": [0x00,0x00,0x00,0x60,0x34,0x80,0xe3,0x3f]}

tool: {"D24": [0x00,0x00,0x00,0xc0,0xf3,0xfd,0xb4,0x3f]}

assistant: ```c
void saturatemat(float mat[4][4], float sat) {
  float mmat[4][4];
  float a, b, c, d, e, f, g, h, i;
  float rwgt, gwgt, bwgt;
  rwgt = (0.3086);
  gwgt = (0.6094);
  bwgt = (0.0820);
  a = (1.0 - sat) * rwgt + sat;
  b = (1.0 - sat) * rwgt;
  c = (1.0 - sat) * rwgt;
  d = (1.0 - sat) * gwgt;
  e = (1.0 - sat) * gwgt + sat;
  f = (1.0 - sat) * gwgt;
  g = (1.0 - sat) * bwgt;
  h = (1.0 - sat) * bwgt;
  i = (1.0 - sat) * bwgt + sat;
  mmat[0][0] = a;
  mmat[0][1] = b;
  mmat[0][2] = c;
  mmat[0][3] = 0.0;
  mmat[1][0] = d;
  mmat[1][1] = e;
  mmat[1][2] = f;
  mmat[1][3] = 0.0;
  mmat[2][0] = g;
  mmat[2][1] = h;
  mmat[2][2] = i;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<saturatemat>:
  endbr64
  sub    $0x58,%rsp
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm3
  pxor   %xmm5,%xmm5
  movsd  D26(%rip),%xmm1
  movsd  D9(%rip),%xmm2
  mov    %rdi,%rsi
  pxor   %xmm4,%xmm4
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  movl   $0x0,0xc(%rsp)
  subsd  %xmm0,%xmm1
  movl   $0x0,0x1c(%rsp)
  movabs $0x3f80000000000000,%rax
  movl   $0x0,0x2c(%rsp)
  movq   $0x0,0x30(%rsp)
  mulsd  %xmm1,%xmm2
  mov    %rax,0x38(%rsp)
  addsd  %xmm2,%xmm3
  unpcklpd %xmm2,%xmm3
  movsd  D24(%rip),%xmm2
  cvtpd2ps %xmm3,%xmm3
  movlps %xmm3,(%rsp)
  shufps $0xe5,%xmm3,%xmm3
  mulsd  %xmm1,%xmm2
  movss  %xmm3,0x8(%rsp)
  mulsd  D15(%rip),%xmm1
  cvtsd2ss %xmm2,%xmm5
  addsd  %xmm0,%xmm2
  movss  %xmm5,0x10(%rsp)
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm1,%xmm4
  movss  %xmm5,0x18(%rsp)
  movss  %xmm4,0x20(%rsp)
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm4,0x24(%rsp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm2,0x14(%rsp)
  movss  %xmm0,0x28(%rsp)
  call   <matrixmult@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x58,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
type_infered: f64
name: retrieve_data
arguments: label: D9
type_infered: byte[8]
name: retrieve_data
arguments: label: D24
type_infered: byte[8]
name: retrieve_data
arguments: label: D15
type_infered: byte[8]

tool: D26: 1

tool: {"D9": [0x00,0x00,0x00,0x40,0x1a,0xc0,0xd3,0x3f]}

tool: {"D24": [0x00,0x00,0x00,0x60,0x34,0x80,0xe3,0x3f]}

tool: {"D15": [0x00,0x00,0x00,0xc0,0xf3,0xfd,0xb4,0x3f]}

assistant: ```c
void saturatemat(float mat[4][4], float sat) {
  float mmat[4][4];
  float a, b, c, d, e, f, g, h, i;
  float rwgt, gwgt, bwgt;
  rwgt = (0.3086);
  gwgt = (0.6094);
  bwgt = (0.0820);
  a = (1.0 - sat) * rwgt + sat;
  b = (1.0 - sat) * rwgt;
  c = (1.0 - sat) * rwgt;
  d = (1.0 - sat) * gwgt;
  e = (1.0 - sat) * gwgt + sat;
  f = (1.0 - sat) * gwgt;
  g = (1.0 - sat) * bwgt;
  h = (1.0 - sat) * bwgt;
  i = (1.0 - sat) * bwgt + sat;
  mmat[0][0] = a;
  mmat[0][1] = b;
  mmat[0][2] = c;
  mmat[0][3] = 0.0;
  mmat[1][0] = d;
  mmat[1][1] = e;
  mmat[1][2] = f;
  mmat[1][3] = 0.0;
  mmat[2][0] = g;
  mmat[2][1] = h;
  mmat[2][2] = i;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_Block_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L16
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_Block_release@plt>
  jmp    L14
L16:
  nop
L14:
  leave
  ret
```

assistant: ```c
void _Block_destroy(const void *arg) {
  struct Block_layout *aBlock;
  if (!arg)
    return;
  aBlock = (struct Block_layout *)arg;
  _Block_release(aBlock);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_Block_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <_Block_release@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void _Block_destroy(const void *arg) {
  struct Block_layout *aBlock;
  if (!arg)
    return;
  aBlock = (struct Block_layout *)arg;
  _Block_release(aBlock);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_Block_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <_Block_release@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void _Block_destroy(const void *arg) {
  struct Block_layout *aBlock;
  if (!arg)
    return;
  aBlock = (struct Block_layout *)arg;
  _Block_release(aBlock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_Block_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <_Block_release@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void _Block_destroy(const void *arg) {
  struct Block_layout *aBlock;
  if (!arg)
    return;
  aBlock = (struct Block_layout *)arg;
  _Block_release(aBlock);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_missing_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L17
L41:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L26
L8:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L30
L4:
  addl   $0x1,-0x24(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x24(%rbp)
  jle    L8
  addl   $0x1,-0x18(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x18(%rbp)
  jle    L41
  mov    $0x1,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int ft_missing_b(int k, int sudoku[9][9], int i, int j) {
  int ii;
  int jj;
  ii = i - (i % 3);
  jj = j - (j % 3);
  i = ii;
  while (i < ii + 3) {
    j = jj;
    while (j < jj + 3) {
      if (sudoku[i][j] == k)
        return (0);
      j++;
    }
    i++;
  }
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_missing_b>:
  endbr64
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r8d
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%r9d
  lea    0x2(%r8),%r10d
  movslq %r8d,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%rsi,%rax,4),%rsi
  lea    0x2(%r9),%ecx
L25:
  mov    %rsi,%rdx
  movslq %r9d,%rax
L22:
  cmp    %edi,(%rdx,%rax,4)
  je     L26
  add    $0x1,%rax
  cmp    %eax,%ecx
  jge    L22
  add    $0x1,%r8d
  add    $0x24,%rsi
  cmp    %r10d,%r8d
  jle    L25
  mov    $0x1,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_missing_b(int k, int sudoku[9][9], int i, int j) {
  int ii;
  int jj;
  ii = i - (i % 3);
  jj = j - (j % 3);
  i = ii;
  while (i < ii + 3) {
    j = jj;
    while (j < jj + 3) {
      if (sudoku[i][j] == k)
        return (0);
      j++;
    }
    i++;
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_missing_b>:
  endbr64
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r8d
  movslq %ecx,%rax
  sar    $0x1f,%ecx
  imul   $0x55555556,%rax,%rax
  movslq %r8d,%rdx
  lea    0x2(%r8),%r9d
  lea    (%rdx,%rdx,8),%rdx
  lea    (%rsi,%rdx,4),%rdx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  lea    0x2(%rax),%ecx
  movslq %eax,%rsi
L25:
  mov    %rsi,%rax
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jl     L38
L18:
  cmp    %edi,(%rdx,%rax,4)
  jne    L26
  xor    %eax,%eax
  ret
L38:
  add    $0x1,%r8d
  add    $0x24,%rdx
  cmp    %r9d,%r8d
  jle    L25
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ft_missing_b(int k, int sudoku[9][9], int i, int j) {
  int ii;
  int jj;
  ii = i - (i % 3);
  jj = j - (j % 3);
  i = ii;
  while (i < ii + 3) {
    j = jj;
    while (j < jj + 3) {
      if (sudoku[i][j] == k)
        return (0);
      j++;
    }
    i++;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_missing_b>:
  endbr64
  mov    %rsi,%r9
  movslq %edx,%rsi
  sar    $0x1f,%edx
  push   %r15
  imul   $0x55555556,%rsi,%rsi
  push   %r14
  mov    %edi,%eax
  push   %r13
  push   %r12
  shr    $0x20,%rsi
  push   %rbp
  sub    %edx,%esi
  movslq %ecx,%rdx
  push   %rbx
  sar    $0x1f,%ecx
  imul   $0x55555556,%rdx,%rdx
  lea    (%rsi,%rsi,2),%edi
  lea    0x2(%rdi),%ebx
  mov    %ebx,-0x14(%rsp)
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%r8d
  movslq %edi,%rdx
  lea    0x5(%r8),%ebx
  movslq %r8d,%rcx
  lea    0x6(%r8),%ebp
  movslq %ebx,%r12
  lea    0x7(%r8),%r13d
  lea    (%rdx,%rdx,8),%rdx
  sub    %rcx,%r12
  lea    0x4(%r8),%r11d
  lea    0x3(%r8),%r10d
  add    %rcx,%rdx
  mov    %r12,-0x20(%rsp)
  movslq %ebp,%r12
  lea    (%r9,%rdx,4),%rdx
  lea    0xa(%r8),%r9d
  sub    %rcx,%r12
  mov    %r9d,-0x18(%rsp)
  lea    0x2(%r8),%esi
  lea    0x8(%r8),%r14d
  mov    %r12,-0x10(%rsp)
  movslq %r13d,%r12
  lea    0x9(%r8),%r15d
  movslq %r11d,%r9
  sub    %rcx,%r12
  movslq %r10d,%r8
  sub    %rcx,%r9
  mov    %r12,-0x8(%rsp)
  sub    %rcx,%r8
L29:
  cmp    (%rdx),%eax
  je     L54
  cmp    %eax,0x4(%rdx)
  je     L54
  cmp    0x8(%rdx),%eax
  je     L54
  cmp    %r10d,%esi
  jl     L3
  cmp    (%rdx,%r8,4),%eax
  je     L54
  cmp    %r11d,%esi
  jl     L3
  cmp    (%rdx,%r9,4),%eax
  je     L54
  cmp    %ebx,%esi
  jl     L3
  mov    -0x20(%rsp),%r12
  cmp    (%rdx,%r12,4),%eax
  je     L54
  cmp    %ebp,%esi
  jl     L3
  mov    -0x10(%rsp),%r12
  cmp    (%rdx,%r12,4),%eax
  je     L54
  cmp    %r13d,%esi
  jl     L3
  mov    -0x8(%rsp),%r12
  cmp    (%rdx,%r12,4),%eax
  je     L54
  cmp    %r14d,%esi
  jl     L3
  movslq %r14d,%r12
  sub    %rcx,%r12
  cmp    (%rdx,%r12,4),%eax
  je     L54
  cmp    %r15d,%esi
  jl     L3
  movslq %r15d,%r12
  sub    %rcx,%r12
  cmp    (%rdx,%r12,4),%eax
  je     L54
  cmp    -0x18(%rsp),%esi
  jl     L3
  movslq -0x18(%rsp),%r12
  sub    %rcx,%r12
  cmp    %eax,(%rdx,%r12,4)
  je     L54
L3:
  add    $0x1,%edi
  add    $0x24,%rdx
  cmp    -0x14(%rsp),%edi
  jle    L29
  mov    $0x1,%eax
  jmp    L144
  xchg   %ax,%ax
L54:
  xor    %eax,%eax
L144:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ft_missing_b(int k, int sudoku[9][9], int i, int j) {
  int ii;
  int jj;
  ii = i - (i % 3);
  jj = j - (j % 3);
  i = ii;
  while (i < ii + 3) {
    j = jj;
    while (j < jj + 3) {
      if (sudoku[i][j] == k)
        return (0);
      j++;
    }
    i++;
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x20(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x2c(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L29
  ucomisd -0x8(%rbp),%xmm0
  jne    L29
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L9
L29:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0xc(%rbp),%xmm2
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
L9:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double getValue(double *segment, int n, double segmentLen, int filterLen, int nPoints) {
  double x;
  int i;
  x = n * segmentLen / filterLen + nPoints - segmentLen;
  i = (int)x;
  if (i == x)
    return (segment[i]);
  else
    return ((segment[i + 1] - segment[i]) * (x - i) + segment[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getValue>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm2
  divsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %ecx,%xmm2
  addsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  ucomisd %xmm1,%xmm2
  jp     L8
  jne    L8
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  ret
L8:
  cltq
  add    $0x1,%rax
  movsd  -0x8(%rdi,%rax,8),%xmm3
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm3,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

assistant: ```c
double getValue(double *segment, int n, double segmentLen, int filterLen, int nPoints) {
  double x;
  int i;
  x = n * segmentLen / filterLen + nPoints - segmentLen;
  i = (int)x;
  if (i == x)
    return (segment[i]);
  else
    return ((segment[i + 1] - segment[i]) * (x - i) + segment[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getValue>:
  endbr64
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sd %esi,%xmm1
  cvtsi2sd %edx,%xmm2
  mulsd  %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %ecx,%xmm2
  addsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  cvtsi2sd %eax,%xmm3
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  lea    0x0(,%rax,8),%rdx
  ucomisd %xmm1,%xmm3
  jp     L12
  jne    L12
  ret
L12:
  movsd  0x8(%rdi,%rdx,1),%xmm2
  subsd  %xmm3,%xmm1
  subsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double getValue(double *segment, int n, double segmentLen, int filterLen, int nPoints) {
  double x;
  int i;
  x = n * segmentLen / filterLen + nPoints - segmentLen;
  i = (int)x;
  if (i == x)
    return (segment[i]);
  else
    return ((segment[i + 1] - segment[i]) * (x - i) + segment[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getValue>:
  endbr64
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sd %esi,%xmm1
  cvtsi2sd %edx,%xmm2
  mulsd  %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %ecx,%xmm2
  addsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  cvtsi2sd %eax,%xmm3
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  lea    0x0(,%rax,8),%rdx
  ucomisd %xmm1,%xmm3
  jp     L3
  jne    L3
  ret
L3:
  movsd  0x8(%rdi,%rdx,1),%xmm2
  subsd  %xmm3,%xmm1
  subsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double getValue(double *segment, int n, double segmentLen, int filterLen, int nPoints) {
  double x;
  int i;
  x = n * segmentLen / filterLen + nPoints - segmentLen;
  i = (int)x;
  if (i == x)
    return (segment[i]);
  else
    return ((segment[i + 1] - segment[i]) * (x - i) + segment[i]);
}
```