ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<findPattern>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  mov    D22(%rip),%rbp
  mov    %edi,0x10(%rsp)
  lea    0x24(%rsp),%r14
  mov    %esi,0x14(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x24(%rsp)
L59:
  cmpl   $0x1,0xc(%rsp)
  jne    L101
  jmp    L78
  nopl   0x0(%rax)
L103:
  mov    %eax,%edi
  call   <legalChar@plt>
  mov    D17(%rip),%r10
  cmp    (%r10),%rax
  je     L80
  xor    %r12d,%r12d
  mov    $0x1,%ebx
L101:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r13d
  cmp    0x0(%rbp),%eax
  jne    L103
L95:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x38,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <printForDebug@plt>
  mov    %r13d,%edi
  call   <legalChar@plt>
  mov    D17(%rip),%r10
  cmp    (%r10),%rax
  je     L80
  xor    %r12d,%r12d
  mov    $0x1,%ebx
L78:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r13d
  cmp    %eax,0x0(%rbp)
  jne    L51
  jmp    L95
  nopw   0x0(%rax,%rax,1)
L80:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%edi
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %r13d,%esi
  mov    %r10,0x18(%rsp)
  call   <evaluateMatch@plt>
  mov    0x18(%rsp),%r10
  cmp    (%r10),%rax
  je     L11
  add    $0x1,%r15d
  mov    $0x1,%r12d
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%ebx
  jmp    L59
L89:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findPattern(int pattern, int index, int debugMode) {
  int counterFound = 0;
  int counterPosition = 1;
  int letter;
  int wasItCounted = 0;
  int stateEnter = 1;
  while ((letter = getchar()) != EOF) {
    if (debugMode == 1) {
      printForDebug(letter, &stateEnter, counterPosition);
    }
    if (legalChar(letter) == EXIT_SUCCESS) {
      if (evaluateMatch(pattern, letter, index, counterPosition, wasItCounted) != EXIT_SUCCESS) {
        counterFound++;
        wasItCounted = 1;
      } else {
        counterPosition++;
      }
    } else {
      wasItCounted = 0;
      counterPosition = 1;
    }
  }
  return counterFound;
}
```
user: What is the c source code of the assembly code below?

```asm
<signal_hook_sysCx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <lace_log_errorf@plt>
  mov    $0x0,%eax
  call   <lose_sysCx@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: Caught signal: %d

assistant: ```c
void signal_hook_sysCx(int sig) {
  lace_log_errorf("Caught signal: %d", sig);
  lose_sysCx();
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<signal_hook_sysCx>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <lace_log_errorf@plt>
  mov    $0x0,%eax
  call   <lose_sysCx@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string

tool: D0: Caught signal: %d

assistant: ```c
void signal_hook_sysCx(int sig) {
  lace_log_errorf("Caught signal: %d", sig);
  lose_sysCx();
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<signal_hook_sysCx>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <lace_log_errorf@plt>
  xor    %eax,%eax
  call   <lose_sysCx@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: Caught signal: %d

assistant: ```c
void signal_hook_sysCx(int sig) {
  lace_log_errorf("Caught signal: %d", sig);
  lose_sysCx();
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<signal_hook_sysCx>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <lace_log_errorf@plt>
  xor    %eax,%eax
  call   <lose_sysCx@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: Caught signal: %d

assistant: ```c
void signal_hook_sysCx(int sig) {
  lace_log_errorf("Caught signal: %d", sig);
  lose_sysCx();
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<auth_simple_pack_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <xorshift128plus@plt>
  and    $0xf,%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  add    $0x6,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0x5(%rbp),%eax
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fillcrc32@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int auth_simple_pack_data(char *data, int datalength, char *outdata) {
  unsigned char rand_len = (xorshift128plus() & 0xF) + 1;
  int out_size = rand_len + datalength + 6;
  outdata[0] = out_size >> 8;
  outdata[1] = out_size;
  outdata[2] = rand_len;
  memmove(outdata + rand_len + 2, data, datalength);
  fillcrc32((unsigned char *)outdata, out_size);
  return out_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<auth_simple_pack_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    $0x0,%eax
  call   <xorshift128plus@plt>
  and    $0xf,%eax
  lea    0x1(%rax),%edx
  movzbl %dl,%ecx
  lea    0x6(%r12,%rcx,1),%ebp
  mov    %ebp,%ecx
  movzbl %ch,%ecx
  mov    %cl,(%rbx)
  mov    %bpl,0x1(%rbx)
  mov    %dl,0x2(%rbx)
  lea    0x3(%rax),%edi
  movzbl %dil,%edi
  add    %rbx,%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memmove@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fillcrc32@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int auth_simple_pack_data(char *data, int datalength, char *outdata) {
  unsigned char rand_len = (xorshift128plus() & 0xF) + 1;
  int out_size = rand_len + datalength + 6;
  outdata[0] = out_size >> 8;
  outdata[1] = out_size;
  outdata[2] = rand_len;
  memmove(outdata + rand_len + 2, data, datalength);
  fillcrc32((unsigned char *)outdata, out_size);
  return out_size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<auth_simple_pack_data>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <xorshift128plus@plt>
  mov    %r14,%rsi
  and    $0xf,%eax
  lea    0x1(%rax),%edx
  lea    0x3(%rax),%edi
  movzbl %dl,%ecx
  mov    %dl,0x2(%rbp)
  movzbl %dil,%edi
  mov    %r12d,%edx
  lea    0x6(%r12,%rcx,1),%r13d
  add    %rbp,%rdi
  mov    %r13d,%ecx
  rol    $0x8,%cx
  mov    %cx,0x0(%rbp)
  call   <memmove@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <fillcrc32@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int auth_simple_pack_data(char *data, int datalength, char *outdata) {
  unsigned char rand_len = (xorshift128plus() & 0xF) + 1;
  int out_size = rand_len + datalength + 6;
  outdata[0] = out_size >> 8;
  outdata[1] = out_size;
  outdata[2] = rand_len;
  memmove(outdata + rand_len + 2, data, datalength);
  fillcrc32((unsigned char *)outdata, out_size);
  return out_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<auth_simple_pack_data>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <xorshift128plus@plt>
  mov    %r14,%rsi
  and    $0xf,%eax
  lea    0x1(%rax),%edx
  lea    0x3(%rax),%edi
  movzbl %dl,%ecx
  mov    %dl,0x2(%rbp)
  movzbl %dil,%edi
  mov    %r12d,%edx
  lea    0x6(%r12,%rcx,1),%r13d
  add    %rbp,%rdi
  mov    %r13d,%ecx
  rol    $0x8,%cx
  mov    %cx,0x0(%rbp)
  call   <memmove@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <fillcrc32@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int auth_simple_pack_data(char *data, int datalength, char *outdata) {
  unsigned char rand_len = (xorshift128plus() & 0xF) + 1;
  int out_size = rand_len + datalength + 6;
  outdata[0] = out_size >> 8;
  outdata[1] = out_size;
  outdata[2] = rand_len;
  memmove(outdata + rand_len + 2, data, datalength);
  fillcrc32((unsigned char *)outdata, out_size);
  return out_size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Cast_Definition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: struct Cast {
  var (*cast)(var, var);
};


assistant: ```c
const char *Cast_Definition(void) {
  return "struct Cast {\n"
         "  var (*cast)(var, var);\n"
         "};\n";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Cast_Definition>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: struct Cast {
  var (*cast)(var, var);
};


assistant: ```c
const char *Cast_Definition(void) {
  return "struct Cast {\n"
         "  var (*cast)(var, var);\n"
         "};\n";
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cast_Definition>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: struct Cast {
  var (*cast)(var, var);
};


assistant: ```c
const char *Cast_Definition(void) {
  return "struct Cast {\n"
         "  var (*cast)(var, var);\n"
         "};\n";
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Cast_Definition>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: struct Cast {
  var (*cast)(var, var);
};


assistant: ```c
const char *Cast_Definition(void) {
  return "struct Cast {\n"
         "  var (*cast)(var, var);\n"
         "};\n";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xattr_data_hash_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x1505,%eax,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x4,-0x20(%rbp)
  subl   $0x1,-0x18(%rbp)
L7:
  cmpl   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x4(%rbp),%eax
  and    $0x7ffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t xattr_data_hash_fn(uint32_t inode, uint8_t anleng, const uint8_t *attrname) {
  uint32_t hash = inode * 5381U;
  while (anleng) {
    hash = (hash * 33U) + (*attrname);
    attrname++;
    anleng--;
  }
  return (hash & (524288 - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xattr_data_hash_fn>:
  endbr64
  imul   $0x1505,%edi,%eax
  test   %esi,%esi
  je     L10
  mov    %esi,%esi
  lea    (%rdx,%rsi,4),%rsi
L1:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  add    %ecx,%eax
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L1
L10:
  and    $0x7ffff,%eax
  ret
```

assistant: ```c
uint32_t xattr_data_hash_fn(uint32_t inode, uint8_t anleng, const uint8_t *attrname) {
  uint32_t hash = inode * 5381U;
  while (anleng) {
    hash = (hash * 33U) + (*attrname);
    attrname++;
    anleng--;
  }
  return (hash & (524288 - 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xattr_data_hash_fn>:
  endbr64
  imul   $0x1505,%edi,%eax
  test   %esi,%esi
  je     L15
  mov    %esi,%esi
  lea    (%rdx,%rsi,4),%rsi
  nopl   0x0(%rax)
L6:
  mov    %eax,%ecx
  add    $0x4,%rdx
  shl    $0x5,%ecx
  add    %ecx,%eax
  add    -0x4(%rdx),%eax
  cmp    %rdx,%rsi
  jne    L6
L15:
  and    $0x7ffff,%eax
  ret
```

assistant: ```c
uint32_t xattr_data_hash_fn(uint32_t inode, uint8_t anleng, const uint8_t *attrname) {
  uint32_t hash = inode * 5381U;
  while (anleng) {
    hash = (hash * 33U) + (*attrname);
    attrname++;
    anleng--;
  }
  return (hash & (524288 - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xattr_data_hash_fn>:
  endbr64
  imul   $0x1505,%edi,%eax
  test   %esi,%esi
  je     L0
  mov    %esi,%esi
  lea    (%rdx,%rsi,4),%rsi
  nopl   0x0(%rax)
L4:
  mov    %eax,%ecx
  add    $0x4,%rdx
  shl    $0x5,%ecx
  add    %ecx,%eax
  add    -0x4(%rdx),%eax
  cmp    %rdx,%rsi
  jne    L4
L0:
  and    $0x7ffff,%eax
  ret
```

assistant: ```c
uint32_t xattr_data_hash_fn(uint32_t inode, uint8_t anleng, const uint8_t *attrname) {
  uint32_t hash = inode * 5381U;
  while (anleng) {
    hash = (hash * 33U) + (*attrname);
    attrname++;
    anleng--;
  }
  return (hash & (524288 - 1));
}
```
user: What is the c source code of the assembly code below:

```asm
<check_crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crc32_c@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
bool check_crc(const unsigned char *buf, size_t size) {
  uint32_t read_crc = *((unsigned long *)(buf + size));
  uint32_t comp_crc;
  comp_crc = crc32_c(buf, size, 0);
  return read_crc == comp_crc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_crc>:
  endbr64
  push   %rbx
  mov    (%rdi,%rsi,1),%rbx
  mov    $0x0,%edx
  call   <crc32_c@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool check_crc(const unsigned char *buf, size_t size) {
  uint32_t read_crc = *((unsigned long *)(buf + size));
  uint32_t comp_crc;
  comp_crc = crc32_c(buf, size, 0);
  return read_crc == comp_crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_crc>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    (%rdi,%rsi,1),%rbx
  call   <crc32_c@plt>
  cmp    %rax,%rbx
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool check_crc(const unsigned char *buf, size_t size) {
  uint32_t read_crc = *((unsigned long *)(buf + size));
  uint32_t comp_crc;
  comp_crc = crc32_c(buf, size, 0);
  return read_crc == comp_crc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_crc>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    (%rdi,%rsi,1),%rbx
  call   <crc32_c@plt>
  cmp    %rax,%rbx
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool check_crc(const unsigned char *buf, size_t size) {
  uint32_t read_crc = *((unsigned long *)(buf + size));
  uint32_t comp_crc;
  comp_crc = crc32_c(buf, size, 0);
  return read_crc == comp_crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convertToSimulationTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D4(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: f64
name: disassemble_data
arguments: data_tag: D11
data_type: f32[2]

tool: D4: 600

tool: {"D11": [0.0,4.4765625]}

assistant: ```c
int convertToSimulationTime(int seconds) {
  double converted_time_in_ms = 0;
  converted_time_in_ms = ((seconds) / 600.0) * 1000;
  return (int)converted_time_in_ms;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<convertToSimulationTime>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D9(%rip),%xmm0
  mulsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: f64
name: retrieve_data
arguments: data_label: D3
type: f32[2]

tool: D9: 600

tool: {"D3": [0.0,4.4765625]}

assistant: ```c
int convertToSimulationTime(int seconds) {
  double converted_time_in_ms = 0;
  converted_time_in_ms = ((seconds) / 600.0) * 1000;
  return (int)converted_time_in_ms;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convertToSimulationTime>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D7(%rip),%xmm0
  mulsd  D15(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: f64
name: unpack_data
arguments: tag: D15
type_guessed: f32[2]

tool: D7: 600

tool: {"D15": [0.0,4.4765625]}

assistant: ```c
int convertToSimulationTime(int seconds) {
  double converted_time_in_ms = 0;
  converted_time_in_ms = ((seconds) / 600.0) * 1000;
  return (int)converted_time_in_ms;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convertToSimulationTime>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D18(%rip),%xmm0
  mulsd  D15(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: f64
name: parse_data
arguments: data_tag: D15
datatype: f32[2]

tool: D18: 600

tool: {"D15": [0.0,4.4765625]}

assistant: ```c
int convertToSimulationTime(int seconds) {
  double converted_time_in_ms = 0;
  converted_time_in_ms = ((seconds) / 600.0) * 1000;
  return (int)converted_time_in_ms;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Camelback2DownLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L3
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L43
L3:
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L44
L6:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  cmpb   $0x40,-0x15(%rbp)
  jle    L12
  cmpb   $0x5a,-0x15(%rbp)
  jg     L12
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %al,-0x15(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x15(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L44:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L6
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string

tool: D8: src == NULL


assistant: ```c
char *Camelback2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c = src[i] + 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Camelback2DownLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L33
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    (%rax,%rax,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L60
  mov    %rbp,%rdx
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%rdi
  mov    $0x0,%eax
  jmp    L21
L33:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rbx
  jmp    L42
L65:
  movslq %eax,%rsi
  mov    %cl,(%rbx,%rsi,1)
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L61
L21:
  movzbl (%rdx),%ecx
  lea    -0x41(%rcx),%esi
  cmp    $0x19,%sil
  ja     L65
  movslq %eax,%rcx
  movb   $0x5f,(%rbx,%rcx,1)
  add    $0x1,%eax
  movzbl (%rdx),%esi
  lea    0x20(%rsi),%ecx
  jmp    L65
L60:
  mov    $0x0,%eax
L61:
  cltq
  movb   $0x0,(%rbx,%rax,1)
L42:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: src == NULL


assistant: ```c
char *Camelback2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c = src[i] + 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```