ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L22
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L40
  mov    $0x0,%eax
  jmp    L22
L40:
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L51:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L51
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
char *ft_strdup(char *str) {
  int i;
  int j;
  char *str2;
  if (!str)
    return (NULL);
  i = ft_strlen(str);
  str2 = (char *)malloc(sizeof(*str) * (i + 1));
  if (!str2)
    return (NULL);
  j = 0;
  while (j < i) {
    str2[j] = str[j];
    j++;
  }
  str2[j] = '\0';
  return (str2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L29
  call   <ft_strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L35
  test   %ebx,%ebx
  jle    L69
  lea    -0x1(%rbx),%edx
  lea    0x1(%rax,%rdx,1),%rdi
  mov    %rax,%rdx
  mov    %rbp,%rsi
  sub    %rax,%rsi
L3:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L3
L50:
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L43:
  mov    %r8,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L69:
  mov    $0x0,%ebx
  jmp    L50
L29:
  mov    %rdi,%r8
  jmp    L43
L35:
  mov    $0x0,%r8d
  jmp    L43
```

assistant: ```c
char *ft_strdup(char *str) {
  int i;
  int j;
  char *str2;
  if (!str)
    return (NULL);
  i = ft_strlen(str);
  str2 = (char *)malloc(sizeof(*str) * (i + 1));
  if (!str2)
    return (NULL);
  j = 0;
  while (j < i) {
    str2[j] = str[j];
    j++;
  }
  str2[j] = '\0';
  return (str2);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strdup>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  movslq %eax,%rbp
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L42
  test   %ebp,%ebp
  jle    L41
  lea    -0x1(%rbp),%edx
  sub    %rax,%rbx
  lea    0x1(%rax,%rdx,1),%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  nopl   0x0(%rax)
L48:
  movzbl (%rdi,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L48
  add    %rax,%rbp
L14:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L42:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L41:
  mov    %rax,%rbp
  jmp    L14
  nopl   (%rax)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strdup(char *str) {
  int i;
  int j;
  char *str2;
  if (!str)
    return (NULL);
  i = ft_strlen(str);
  str2 = (char *)malloc(sizeof(*str) * (i + 1));
  if (!str2)
    return (NULL);
  j = 0;
  while (j < i) {
    str2[j] = str[j];
    j++;
  }
  str2[j] = '\0';
  return (str2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strdup>:
  endbr64
  test   %rdi,%rdi
  je     L136
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L38
  test   %ebx,%ebx
  jle    L131
  lea    0x1(%rbp),%rsi
  mov    %r8,%rdx
  lea    -0x1(%rbx),%eax
  mov    %ebx,%ecx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L138
  cmp    $0x6,%eax
  jbe    L138
  cmp    $0xe,%eax
  jbe    L110
  mov    %ebx,%eax
  mov    %rbp,%rdx
  shr    $0x4,%eax
  sub    %r8,%rdx
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%r8,%rax,1),%rcx
  mov    %r8,%rax
  nop
L171:
  movdqu (%rax,%rdx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rcx
  jne    L171
  mov    %ebx,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebx
  je     L104
  mov    %ebx,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L97
L28:
  mov    0x0(%rbp,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L104
L97:
  movslq %eax,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jle    L104
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L104
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L104
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L104
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L104
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%ebx
  jle    L104
  cltq
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L104:
  add    %r8,%rbx
L168:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L38:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L138:
  lea    0x1(%r8,%rax,1),%rcx
  sub    %r8,%rbp
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L182:
  movzbl 0x0(%rbp,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L182
  jmp    L104
  nopl   0x0(%rax,%rax,1)
L131:
  mov    %rax,%rbx
  jmp    L168
L110:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L136:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strdup(char *str) {
  int i;
  int j;
  char *str2;
  if (!str)
    return (NULL);
  i = ft_strlen(str);
  str2 = (char *)malloc(sizeof(*str) * (i + 1));
  if (!str2)
    return (NULL);
  j = 0;
  while (j < i) {
    str2[j] = str[j];
    j++;
  }
  str2[j] = '\0';
  return (str2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  leave
  ret
```

assistant: ```c
int strrcmp(const char *s, const char *sub) {
  int slen = strlen(s);
  int sublen = strlen(sub);
  return memcmp(s + slen - sublen, sub, sublen);
}
```
user: What is the c source code of the assembly code below:

```asm
<strrcmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  movslq %ebx,%rbx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <memcmp@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strrcmp(const char *s, const char *sub) {
  int slen = strlen(s);
  int sublen = strlen(sub);
  return memcmp(s + slen - sublen, sub, sublen);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strrcmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %eax,%edx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <memcmp@plt>
```

assistant: ```c
int strrcmp(const char *s, const char *sub) {
  int slen = strlen(s);
  int sublen = strlen(sub);
  return memcmp(s + slen - sublen, sub, sublen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrcmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %eax,%edx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <memcmp@plt>
```

assistant: ```c
int strrcmp(const char *s, const char *sub) {
  int slen = strlen(s);
  int sublen = strlen(sub);
  return memcmp(s + slen - sublen, sub, sublen);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ho_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L48:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  jmp    L2
L47:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  cmp    %eax,%edx
  jne    L5
  mov    -0x8(%rbp),%rax
  jmp    L43
L5:
  subq   $0x1,-0x8(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L47
  mov    $0x0,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
char *ho_strrchr(const char *s, int c) {
  const char *p;
  unsigned char cc = c;
  for (p = s; *p; p++)
    ;
  while (s <= p) {
    if (*p == cc)
      return (char *)p;
    p--;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ho_strrchr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L58
  mov    %rdi,%rax
L4:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L4
  cmp    %rax,%rdi
  ja     L11
L5:
  movzbl %sil,%esi
L41:
  movsbl (%rax),%edx
  cmp    %esi,%edx
  je     L48
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L41
  mov    $0x0,%eax
  ret
L58:
  mov    %rdi,%rax
  jmp    L5
L11:
  mov    $0x0,%eax
L48:
  ret
```

assistant: ```c
char *ho_strrchr(const char *s, int c) {
  const char *p;
  unsigned char cc = c;
  for (p = s; *p; p++)
    ;
  while (s <= p) {
    if (*p == cc)
      return (char *)p;
    p--;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ho_strrchr>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L48
  nopl   0x0(%rax)
L49:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L49
L48:
  movzbl %sil,%esi
  xor    %edx,%edx
  jmp    L5
  nopl   0x0(%rax)
L40:
  movsbl (%rax),%edx
L5:
  cmp    %esi,%edx
  je     L20
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L40
  xor    %eax,%eax
L20:
  ret
```

assistant: ```c
char *ho_strrchr(const char *s, int c) {
  const char *p;
  unsigned char cc = c;
  for (p = s; *p; p++)
    ;
  while (s <= p) {
    if (*p == cc)
      return (char *)p;
    p--;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<ho_strrchr>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L25
  nopl   0x0(%rax)
L16:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L16
L25:
  movzbl %sil,%esi
  nopl   (%rax)
L0:
  movsbl (%rax),%edx
  cmp    %esi,%edx
  je     L26
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L0
  xor    %eax,%eax
L26:
  ret
```

assistant: ```c
char *ho_strrchr(const char *s, int c) {
  const char *p;
  unsigned char cc = c;
  for (p = s; *p; p++)
    ;
  while (s <= p) {
    if (*p == cc)
      return (char *)p;
    p--;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<doubles_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L6
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
double *doubles_copy(double *v, int len) {
  if (!v)
    return NULL;
  double *r = malloc(len * sizeof(double));
  memcpy(r, v, len * sizeof(double));
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doubles_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L16
  lea    0x0(,%rsi,8),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %rdi,%r12
  jmp    L6
```

assistant: ```c
double *doubles_copy(double *v, int len) {
  if (!v)
    return NULL;
  double *r = malloc(len * sizeof(double));
  memcpy(r, v, len * sizeof(double));
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doubles_copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L9
  lea    0x0(,%rsi,8),%r12d
  mov    %rdi,%rbp
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13,%rax
  pop    %r13
  ret
```

assistant: ```c
double *doubles_copy(double *v, int len) {
  if (!v)
    return NULL;
  double *r = malloc(len * sizeof(double));
  memcpy(r, v, len * sizeof(double));
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doubles_copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L0
  lea    0x0(,%rsi,8),%r12d
  mov    %rdi,%rbp
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13,%rax
  pop    %r13
  ret
```

assistant: ```c
double *doubles_copy(double *v, int len) {
  if (!v)
    return NULL;
  double *r = malloc(len * sizeof(double));
  memcpy(r, v, len * sizeof(double));
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<how_many_percent_life>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  movd   %eax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %f / %d Sante


assistant: ```c
int how_many_percent_life(int vie_tot, int vie_rest) {
  float vie_actu;
  vie_actu = vie_rest / 100;
  printf("%f / %d Sante\n", vie_actu, vie_tot);
  return (vie_actu);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<how_many_percent_life>:
  endbr64
  sub    $0x18,%rsp
  movslq %esi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    %edi,%esi
  movss  %xmm1,0xc(%rsp)
  movaps %xmm1,%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  cvttss2si 0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %f / %d Sante


assistant: ```c
int how_many_percent_life(int vie_tot, int vie_rest) {
  float vie_actu;
  vie_actu = vie_rest / 100;
  printf("%f / %d Sante\n", vie_actu, vie_tot);
  return (vie_actu);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<how_many_percent_life>:
  endbr64
  movslq %esi,%rax
  sar    $0x1f,%esi
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sub    %esi,%eax
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %f / %d Sante


assistant: ```c
int how_many_percent_life(int vie_tot, int vie_rest) {
  float vie_actu;
  vie_actu = vie_rest / 100;
  printf("%f / %d Sante\n", vie_actu, vie_tot);
  return (vie_actu);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<how_many_percent_life>:
  endbr64
  movslq %esi,%rax
  sar    $0x1f,%esi
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sub    %esi,%eax
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: %f / %d Sante


assistant: ```c
int how_many_percent_life(int vie_tot, int vie_rest) {
  float vie_actu;
  vie_actu = vie_rest / 100;
  printf("%f / %d Sante\n", vie_actu, vie_tot);
  return (vie_actu);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<zsbh32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,-0x24(%rbp)
  mov    $0x43,%edi
  mov    $0x0,%eax
  call   <xsendline@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <zsendline@plt>
  mov    $0xffffffff,%ebx
  mov    -0x24(%rbp),%eax
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <UPDC32@plt>
  movslq %eax,%rbx
  mov    $0x4,%r12d
  jmp    L6
L37:
  movzbl 0x0(%r13),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <UPDC32@plt>
  movslq %eax,%rbx
  movzbl 0x0(%r13),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <zsendline@plt>
  add    $0x1,%r13
L6:
  sub    $0x1,%r12d
  test   %r12d,%r12d
  jns    L37
  not    %rbx
  mov    $0x4,%r12d
  jmp    L4
L7:
  mov    %ebx,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <zsendline@plt>
  sar    $0x8,%rbx
L4:
  sub    $0x1,%r12d
  test   %r12d,%r12d
  jns    L7
  nop
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
zsbh32(hdr, type) register char *hdr;
{
  register n;
  register long crc;
  xsendline('C');
  zsendline(type);
  crc = 0xFFFFFFFFL;
  crc = UPDC32(type, crc);
  for (n = 4; --n >= 0; ++hdr) {
    crc = UPDC32((0377 & *hdr), crc);
    zsendline(*hdr);
  }
  crc = ~crc;
  for (n = 4; --n >= 0;) {
    zsendline((int)crc);
    crc >>= 8;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<zsbh32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x43,%edi
  mov    $0x0,%eax
  call   <xsendline@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <zsendline@plt>
  mov    $0xffffffff,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <UPDC32@plt>
  movslq %eax,%rbx
  lea    0x4(%rbp),%r12
L15:
  movzbl 0x0(%rbp),%edi
  mov    %rbx,%rsi
  mov    $0x0,%eax
  call   <UPDC32@plt>
  movslq %eax,%rbx
  movsbl 0x0(%rbp),%edi
  mov    $0x0,%eax
  call   <zsendline@plt>
  add    $0x1,%rbp
  cmp    %rbp,%r12
  jne    L15
  not    %rbx
  mov    $0x4,%ebp
L0:
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <zsendline@plt>
  sar    $0x8,%rbx
  sub    $0x1,%ebp
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
zsbh32(hdr, type) register char *hdr;
{
  register n;
  register long crc;
  xsendline('C');
  zsendline(type);
  crc = 0xFFFFFFFFL;
  crc = UPDC32(type, crc);
  for (n = 4; --n >= 0; ++hdr) {
    crc = UPDC32((0377 & *hdr), crc);
    zsendline(*hdr);
  }
  crc = ~crc;
  for (n = 4; --n >= 0;) {
    zsendline((int)crc);
    crc >>= 8;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zsbh32>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x43,%edi
  lea    0x4(%rbx),%r12
  call   <xsendline@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <zsendline@plt>
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  xor    %eax,%eax
  call   <UPDC32@plt>
  movslq %eax,%rbp
L9:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <UPDC32@plt>
  movsbl -0x1(%rbx),%edi
  movslq %eax,%rbp
  xor    %eax,%eax
  call   <zsendline@plt>
  cmp    %rbx,%r12
  jne    L9
  mov    %rbp,%rbx
  mov    $0x4,%ebp
  not    %rbx
L17:
  mov    %ebx,%edi
  xor    %eax,%eax
  sar    $0x8,%rbx
  call   <zsendline@plt>
  sub    $0x1,%ebp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
zsbh32(hdr, type) register char *hdr;
{
  register n;
  register long crc;
  xsendline('C');
  zsendline(type);
  crc = 0xFFFFFFFFL;
  crc = UPDC32(type, crc);
  for (n = 4; --n >= 0; ++hdr) {
    crc = UPDC32((0377 & *hdr), crc);
    zsendline(*hdr);
  }
  crc = ~crc;
  for (n = 4; --n >= 0;) {
    zsendline((int)crc);
    crc >>= 8;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zsbh32>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x43,%edi
  lea    0x4(%rbx),%r12
  call   <xsendline@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <zsendline@plt>
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  xor    %eax,%eax
  call   <UPDC32@plt>
  movslq %eax,%rbp
L8:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <UPDC32@plt>
  movsbl -0x1(%rbx),%edi
  movslq %eax,%rbp
  xor    %eax,%eax
  call   <zsendline@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    %rbp,%rbx
  mov    $0x4,%ebp
  not    %rbx
L15:
  mov    %ebx,%edi
  xor    %eax,%eax
  sar    $0x8,%rbx
  call   <zsendline@plt>
  sub    $0x1,%ebp
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
zsbh32(hdr, type) register char *hdr;
{
  register n;
  register long crc;
  xsendline('C');
  zsendline(type);
  crc = 0xFFFFFFFFL;
  crc = UPDC32(type, crc);
  for (n = 4; --n >= 0; ++hdr) {
    crc = UPDC32((0377 & *hdr), crc);
    zsendline(*hdr);
  }
  crc = ~crc;
  for (n = 4; --n >= 0;) {
    zsendline((int)crc);
    crc >>= 8;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %rax,%rbx
  jmp    L24
L7:
  add    $0x1,%rax
L24:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L7
  nop
L10:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L10
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strcat(s, add)
register char *s, *add;
{
  register char *ret = s;
  while (*s)
    s++;
  while ((*s++ = *add++) != 0)
    ;
  return ret;
}
```