ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_match_double_hex>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <remove_leading_whitespace@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
  mov    $0x2,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <strtod@plt>
  movsd  %xmm0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L16:
  movq   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D10: :=

tool: D6: 0x

assistant: ```c
void find_match_double_hex(char *buffer, char *match, double *result) {
  char *position;
  remove_leading_whitespace(buffer);
  if (strstr(buffer, match) == strstr(buffer, buffer)) {
    position = strpbrk(buffer, ":=");
    if (position != NULL) {
      memcpy(position, "0x", 2);
      *result = strtod(position, NULL);
    } else
      *result = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L13
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L40
  movzbl -0x9(%rbp),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L34
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L0
L34:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L0
L40:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L0
L13:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L0:
  movzbl -0x9(%rbp),%eax
  lea    0x3c(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 984038296UL) + (unsigned char)164;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  lea    0x0(,%rax,4),%edx
  test   $0x10,%al
  add    $0x3c,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 984038296UL) + (unsigned char)164;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x6c(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 984038296UL) + (unsigned char)164;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x6c(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
        if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = (state[0UL] + 984038296UL) + (unsigned char)164;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solveTriangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jle    L20
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L3
  mov    -0x2c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x16(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x15(%rbp),%edx
  movzbl -0x16(%rbp),%eax
  cmp    %al,%dl
  cmovge %edx,%eax
  movsbl %al,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  jmp    L6
L3:
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <solveTriangle>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <solveTriangle>
  cmp    %eax,%ebx
  jle    L36
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <solveTriangle>
  jmp    L16
L36:
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <solveTriangle>
L16:
  mov    -0x14(%rbp),%edx
  add    %edx,%eax
  jmp    L6
L20:
  mov    -0x14(%rbp),%eax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int solveTriangle(char **triangle, int row, int column, int rows) {
  int total = triangle[row][column];
  if (rows > 1) {
    if (row == rows - 2) {
      char left = triangle[row + 1][column];
      char right = triangle[row + 1][column + 1];
      return total + (((left) > (right)) ? (left) : (right));
    }
    return total + (((solveTriangle(triangle, row + 1, column, rows)) > (solveTriangle(triangle, row + 1, column + 1, rows))) ? (solveTriangle(triangle, row + 1, column, rows)) : (solveTriangle(triangle, row + 1, column + 1, rows)));
  }
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solveTriangle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r12d
  mov    %ecx,%ebp
  movslq %esi,%rax
  lea    0x0(,%rax,8),%rcx
  movslq %edx,%rdx
  mov    (%rdi,%rax,8),%rax
  movsbl (%rax,%rdx,1),%r14d
  cmp    $0x1,%ebp
  jle    L20
  mov    %rdi,%r13
  lea    -0x2(%rbp),%eax
  cmp    %esi,%eax
  jne    L23
  mov    0x8(%rdi,%rcx,1),%rcx
  movzbl 0x1(%rcx,%rdx,1),%eax
  movzbl (%rcx,%rdx,1),%edx
  cmp    %dl,%al
  cmovl  %edx,%eax
  movsbl %al,%eax
  add    %eax,%r14d
L20:
  mov    %r14d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  lea    0x1(%rsi),%ebx
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  call   <solveTriangle>
  mov    %eax,%r15d
  lea    0x1(%r12),%edx
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <solveTriangle>
  cmp    %eax,%r15d
  cmovl  %eax,%r15d
  add    %r15d,%r14d
  jmp    L20
```

assistant: ```c
int solveTriangle(char **triangle, int row, int column, int rows) {
  int total = triangle[row][column];
  if (rows > 1) {
    if (row == rows - 2) {
      char left = triangle[row + 1][column];
      char right = triangle[row + 1][column + 1];
      return total + (((left) > (right)) ? (left) : (right));
    }
    return total + (((solveTriangle(triangle, row + 1, column, rows)) > (solveTriangle(triangle, row + 1, column + 1, rows))) ? (solveTriangle(triangle, row + 1, column, rows)) : (solveTriangle(triangle, row + 1, column + 1, rows)));
  }
  return total;
}
```
user: Translate the below assembly code into C programming language:

```asm
<solveTriangle>:
  endbr64
  push   %r15
  movslq %esi,%r9
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    (%rdi,%r9,8),%rdx
  movsbl (%rdx,%r13,1),%r12d
  cmp    $0x1,%ecx
  jle    L29
  lea    -0x2(%rcx),%edx
  mov    %rdi,%rbp
  cmp    %edx,%r9d
  je     L55
  lea    -0x3(%rcx),%r10d
  mov    %ecx,0x8(%rsp)
  lea    0x1(%r9),%ebx
  xor    %r11d,%r11d
  sub    %r9d,%r10d
  mov    %r9,0x20(%rsp)
  movslq %ebx,%rbx
  mov    %r13d,%r15d
  mov    %r10,0x28(%rsp)
  lea    0x2(%r9,%r10,1),%r8
  mov    %r11d,%r9d
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rsp),%ecx
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %r8,0x10(%rsp)
  mov    %r9d,0x18(%rsp)
  call   <solveTriangle>
  mov    0x8(%rsp),%ecx
  lea    0x1(%r15),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  mov    %edx,0x1c(%rsp)
  call   <solveTriangle>
  mov    0x18(%rsp),%r9d
  mov    0x10(%rsp),%r8
  add    %r12d,%r9d
  cmp    %eax,0xc(%rsp)
  jle    L6
L54:
  mov    0x0(%rbp,%rbx,8),%rax
  add    $0x1,%rbx
  movsbl (%rax,%r13,1),%r12d
  cmp    %rbx,%r8
  jne    L0
  mov    0x28(%rsp),%r10
  mov    %r9d,%r11d
  mov    0x20(%rsp),%r9
  lea    0x1(%r9,%r10,1),%r9
L26:
  mov    0x8(%rbp,%r9,8),%rdx
  movsbl 0x1(%rdx,%r13,1),%eax
  movsbl (%rdx,%r13,1),%edx
  cmp    %dl,%al
  cmovl  %edx,%eax
  add    %r12d,%eax
  lea    (%rax,%r11,1),%r12d
L29:
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x1c(%rsp),%edx
  movslq %edx,%r13
  mov    %r13,%r15
  jmp    L54
  nopl   0x0(%rax)
L55:
  xor    %r11d,%r11d
  jmp    L26
```

assistant: ```c
int solveTriangle(char **triangle, int row, int column, int rows) {
  int total = triangle[row][column];
  if (rows > 1) {
    if (row == rows - 2) {
      char left = triangle[row + 1][column];
      char right = triangle[row + 1][column + 1];
      return total + (((left) > (right)) ? (left) : (right));
    }
    return total + (((solveTriangle(triangle, row + 1, column, rows)) > (solveTriangle(triangle, row + 1, column + 1, rows))) ? (solveTriangle(triangle, row + 1, column, rows)) : (solveTriangle(triangle, row + 1, column + 1, rows)));
  }
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solveTriangle>:
  endbr64
  push   %r15
  movslq %esi,%r8
  movslq %edx,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rdi,%r8,8),%rdx
  movsbl (%rdx,%rax,1),%r13d
  cmp    $0x1,%ecx
  jle    L0
  lea    -0x2(%rcx),%edx
  mov    %rdi,%rbp
  cmp    %edx,%esi
  je     L56
  lea    -0x3(%rcx),%r9d
  lea    0x1(%rsi),%ebx
  mov    %rax,%r12
  xor    %r11d,%r11d
  sub    %esi,%r9d
  movslq %ebx,%rbx
  lea    0x1(%rax),%r15d
  lea    0x2(%r8,%r9,1),%r14
  nopl   0x0(%rax)
L52:
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %r9,0x18(%rsp)
  mov    %r11d,0x14(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %ebx,0x10(%rsp)
  call   <solveTriangle>
  mov    0x4(%rsp),%ecx
  mov    0x10(%rsp),%esi
  mov    %r15d,%edx
  mov    %rbp,%rdi
  mov    %eax,(%rsp)
  call   <solveTriangle>
  mov    0x14(%rsp),%r11d
  mov    0x4(%rsp),%ecx
  mov    0x8(%rsp),%r8
  mov    0x18(%rsp),%r9
  add    %r13d,%r11d
  cmp    %eax,(%rsp)
  jg     L55
  mov    0x0(%rbp,%rbx,8),%rdx
  movslq %r15d,%rax
  add    $0x1,%rbx
  movsbl (%rdx,%rax,1),%r13d
  cmp    %r14,%rbx
  je     L49
  mov    %r15d,%r12d
  add    $0x1,%r15d
  jmp    L52
  nopl   0x0(%rax)
L55:
  mov    0x0(%rbp,%rbx,8),%rdx
  movslq %r12d,%rax
  add    $0x1,%rbx
  movsbl (%rdx,%rax,1),%r13d
  cmp    %rbx,%r14
  jne    L52
L49:
  lea    0x1(%r8,%r9,1),%r8
L41:
  mov    0x8(%rbp,%r8,8),%rcx
  movsbl 0x1(%rcx,%rax,1),%edx
  movsbl (%rcx,%rax,1),%eax
  cmp    %al,%dl
  cmovl  %eax,%edx
  add    %r13d,%edx
  lea    (%rdx,%r11,1),%r13d
L0:
  add    $0x28,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %r11d,%r11d
  jmp    L41
```

assistant: ```c
int solveTriangle(char **triangle, int row, int column, int rows) {
  int total = triangle[row][column];
  if (rows > 1) {
    if (row == rows - 2) {
      char left = triangle[row + 1][column];
      char right = triangle[row + 1][column + 1];
      return total + (((left) > (right)) ? (left) : (right));
    }
    return total + (((solveTriangle(triangle, row + 1, column, rows)) > (solveTriangle(triangle, row + 1, column + 1, rows))) ? (solveTriangle(triangle, row + 1, column, rows)) : (solveTriangle(triangle, row + 1, column + 1, rows)));
  }
  return total;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <bubbleSort@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: C - Sorted array:


assistant: ```c
int main(int argc, char **argv) {
  int arr[10] = {5, 9, 4, 8, 1, 2, 6, 7, 3, 10};
  bubbleSort(arr, 10);
  printf("C - Sorted array:\n");
  printArray(arr, 10);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <bubbleSort@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: C - Sorted array:


assistant: ```c
int main(int argc, char **argv) {
  int arr[10] = {5, 9, 4, 8, 1, 2, 6, 7, 3, 10};
  bubbleSort(arr, 10);
  printf("C - Sorted array:\n");
  printArray(arr, 10);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000005,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x800000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000003,%rax
  mov    %rax,0x20(%rsp)
  call   <bubbleSort@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: C - Sorted array:


assistant: ```c
int main(int argc, char **argv) {
  int arr[10] = {5, 9, 4, 8, 1, 2, 6, 7, 3, 10};
  bubbleSort(arr, 10);
  printf("C - Sorted array:\n");
  printArray(arr, 10);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  movdqa D20(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D36(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <bubbleSort@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
type: byte[16]
name: read_data
arguments: data_tag: D36
type: byte[8]
name: read_data
arguments: data_tag: D8
type: byte[16]
name: read_data
arguments: data_tag: D30
type: string

tool: {"D20": [0x05,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D36": [0x03,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D8": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: D30: C - Sorted array:


assistant: ```c
int main(int argc, char **argv) {
  int arr[10] = {5, 9, 4, 8, 1, 2, 6, 7, 3, 10};
  bubbleSort(arr, 10);
  printf("C - Sorted array:\n");
  printArray(arr, 10);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_limit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D61(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L16
  movsd  D61(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L125
L27:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L178
  movsd  -0x8(%rbp),%xmm0
  jmp    L47
L178:
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L137
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  jmp    L47
L137:
  movsd  -0x8(%rbp),%xmm1
  movsd  D80(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L83
  movsd  -0x8(%rbp),%xmm1
  movsd  D80(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  jmp    L47
L83:
  movsd  -0x8(%rbp),%xmm1
  movsd  D45(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L125:
  cmpl   $0x14,-0xc(%rbp)
  jle    L27
  movsd  -0x18(%rbp),%xmm0
  jmp    L47
L16:
  movsd  D61(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L152
L74:
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  comisd D20(%rip),%xmm0
  jbe    L133
  movsd  D61(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  jmp    L47
L133:
  movsd  -0x8(%rbp),%xmm1
  movsd  D45(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  comisd D11(%rip),%xmm0
  jbe    L112
  movsd  D80(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  jmp    L47
L112:
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  D61(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L103
  movsd  D11(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  jmp    L47
L103:
  addl   $0x1,-0xc(%rbp)
L152:
  cmpl   $0x14,-0xc(%rbp)
  jle    L74
  movsd  -0x18(%rbp),%xmm0
L47:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D61
type: f64
name: retrieve_data
arguments: data_label: D80
type: f64
name: retrieve_data
arguments: data_label: D45
type: f64
name: retrieve_data
arguments: data_label: D20
type: f64[2]
name: retrieve_data
arguments: data_label: D11
type: f64

tool: D61: 1

tool: D80: 5

tool: D45: 10

tool: {"D20": [0.5,2.0]}

tool: D11: 2

assistant: ```c
double get_limit(double value) {
  int i;
  double limit;
  if (value >= 1.0) {
    limit = 1.0;
    for (i = 0; i <= 20; i++) {
      if (limit >= value)
        return (limit);
      if (2.0 * limit >= value)
        return (2.0 * limit);
      if (5.0 * limit >= value)
        return (5.0 * limit);
      limit *= 10.0;
    }
    return (value);
  }
  limit = 1.0;
  for (i = 0; i <= 20; i++) {
    if (0.5 < value * limit)
      return (1.0 / limit);
    limit *= 10.0;
    if (2.0 < value * limit)
      return (5.0 / limit);
    if (1.0 < value * limit)
      return (2.0 / limit);
  }
  return (value);
}
```