ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L13
  mov    $0x0,%eax
  jmp    L3
L13:
  mov    $0x1,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int exists(char *fname) {
  struct stat stbuf;
  if (stat(fname, &stbuf) < 0) {
    return (0);
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  not    %rax
  shr    $0x3f,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exists(char *fname) {
  struct stat stbuf;
  if (stat(fname, &stbuf) < 0) {
    return (0);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  not    %rax
  shr    $0x3f,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exists(char *fname) {
  struct stat stbuf;
  if (stat(fname, &stbuf) < 0) {
    return (0);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  not    %rax
  shr    $0x3f,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exists(char *fname) {
  struct stat stbuf;
  if (stat(fname, &stbuf) < 0) {
    return (0);
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L2
L13:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L2:
  cmpl   $0x3,-0x18(%rbp)
  jle    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: a[%d] = %d


assistant: ```c
int main(void) {
  int a[] = {1, 2, 3};
  for (int i = 0; i < 4; i++)
    printf("a[%d] = %d\n", i, a[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L8:
  mov    0xc(%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L8
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: a[%d] = %d


assistant: ```c
int main(void) {
  int a[] = {1, 2, 3};
  for (int i = 0; i < 4; i++)
    printf("a[%d] = %d\n", i, a[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x10(%rsp)
L20:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L28
  mov    0xc(%rsp,%rbx,4),%edx
  jmp    L20
  nop
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: a[%d] = %d


assistant: ```c
int main(void) {
  int a[] = {1, 2, 3};
  for (int i = 0; i < 4; i++)
    printf("a[%d] = %d\n", i, a[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  movl   $0x3,0x10(%rsp)
  lea    0x8(%rsp),%r12
  mov    %rax,0x8(%rsp)
L3:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L3
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string
name: retrieve_data
arguments: data_tag: D15
type: byte[8]

tool: D1: a[%d] = %d


tool: {"D15": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int a[] = {1, 2, 3};
  for (int i = 0; i < 4; i++)
    printf("a[%d] = %d\n", i, a[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: %d


assistant: ```c
int main() {
  int i;
  srand((unsigned)time(NULL));
  i = rand();
  printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  int i;
  srand((unsigned)time(NULL));
  i = rand();
  printf("%d\n", i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main() {
  int i;
  srand((unsigned)time(NULL));
  i = rand();
  printf("%d\n", i);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  int i;
  srand((unsigned)time(NULL));
  i = rand();
  printf("%d\n", i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8_forbidden>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0xff,%eax
  je     L59
  cmp    $0xff,%eax
  jg     L37
  cmp    $0xc1,%eax
  jg     L21
  cmp    $0xc0,%eax
  jge    L59
  jmp    L37
L21:
  cmp    $0xf5,%eax
  jne    L37
L59:
  mov    $0xffffffff,%eax
  jmp    L49
L37:
  mov    $0x0,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int utf8_forbidden(unsigned char octet) {
  switch (octet) {
  case 0xc0:
  case 0xc1:
  case 0xf5:
  case 0xff:
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<utf8_forbidden>:
  endbr64
  cmp    $0xf5,%dil
  je     L19
  jbe    L9
  cmp    $0xff,%dil
  sete   %al
  movzbl %al,%eax
  neg    %eax
  ret
L9:
  add    $0x40,%edi
  cmp    $0x2,%dil
  sbb    %eax,%eax
  ret
L19:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utf8_forbidden(unsigned char octet) {
  switch (octet) {
  case 0xc0:
  case 0xc1:
  case 0xf5:
  case 0xff:
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_forbidden>:
  endbr64
  cmp    $0xf5,%dil
  je     L6
  jbe    L1
  xor    %eax,%eax
  cmp    $0xff,%dil
  sete   %al
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x40,%edi
  cmp    $0x2,%dil
  sbb    %eax,%eax
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utf8_forbidden(unsigned char octet) {
  switch (octet) {
  case 0xc0:
  case 0xc1:
  case 0xf5:
  case 0xff:
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utf8_forbidden>:
  endbr64
  cmp    $0xf5,%dil
  je     L5
  jbe    L12
  xor    %eax,%eax
  cmp    $0xff,%dil
  sete   %al
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x40,%edi
  cmp    $0x2,%dil
  sbb    %eax,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utf8_forbidden(unsigned char octet) {
  switch (octet) {
  case 0xc0:
  case 0xc1:
  case 0xf5:
  case 0xff:
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<I2SMasterClockSelect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x40054000,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x20(%rbp),%rax
  and    $0x30,%eax
  cmp    %rax,-0x20(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x18(%rbp),%rax
  add    $0xc00,%rax
  mov    (%rax),%rax
  and    $0xffffffffffffffcf,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc00,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  or     -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void I2SMasterClockSelect(unsigned long ulBase, unsigned long ulMClock) {
  unsigned long ulConfig;
  DEBUG_ASSERT(ulBase == 0x40054000);
  DEBUG_ASSERT((ulMClock & (0x00000010 | 0x00000020)) == ulMClock);
  ulConfig = (*((volatile unsigned long *)(ulBase + 0x00000C00))) & ~(0x00000010 | 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000C00))) = ulConfig | ulMClock;
}
```
user: Translate the below assembly code into C programming language:

```asm
<I2SMasterClockSelect>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmp    $0x40054000,%rdi
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  test   $0xffffffffffffffcf,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0xc00(%rbx),%rsi
  and    $0xffffffffffffffcf,%rsi
  or     %rbp,%rsi
  mov    %rsi,0xc00(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void I2SMasterClockSelect(unsigned long ulBase, unsigned long ulMClock) {
  unsigned long ulConfig;
  DEBUG_ASSERT(ulBase == 0x40054000);
  DEBUG_ASSERT((ulMClock & (0x00000010 | 0x00000020)) == ulMClock);
  ulConfig = (*((volatile unsigned long *)(ulBase + 0x00000C00))) & ~(0x00000010 | 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000C00))) = ulConfig | ulMClock;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<I2SMasterClockSelect>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x40054000,%rbx
  sete   %dil
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  test   $0xffffffffffffffcf,%rbp
  sete   %dil
  call   <DEBUG_ASSERT@plt>
  mov    0xc00(%rbx),%rsi
  and    $0xffffffffffffffcf,%rsi
  or     %rbp,%rsi
  mov    %rsi,0xc00(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void I2SMasterClockSelect(unsigned long ulBase, unsigned long ulMClock) {
  unsigned long ulConfig;
  DEBUG_ASSERT(ulBase == 0x40054000);
  DEBUG_ASSERT((ulMClock & (0x00000010 | 0x00000020)) == ulMClock);
  ulConfig = (*((volatile unsigned long *)(ulBase + 0x00000C00))) & ~(0x00000010 | 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000C00))) = ulConfig | ulMClock;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xil_fpo_exp_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <xip_fpo_exp_d@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double xil_fpo_exp_d(double a) {
  double res_d;
  xip_fpo_exp_d(&res_d, a);
  return res_d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xil_fpo_exp_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_exp_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_exp_d(double a) {
  double res_d;
  xip_fpo_exp_d(&res_d, a);
  return res_d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xil_fpo_exp_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_exp_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_exp_d(double a) {
  double res_d;
  xip_fpo_exp_d(&res_d, a);
  return res_d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xil_fpo_exp_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_exp_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_exp_d(double a) {
  double res_d;
  xip_fpo_exp_d(&res_d, a);
  return res_d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pow_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L2:
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: f64

tool: D9: 1

assistant: ```c
double pow_(double x, int e) {
  int i;
  double r = 1;
  for (i = 0; i < e; i++) {
    r *= x;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pow_>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  jle    L2
  movsd  D14(%rip),%xmm0
  mov    $0x0,%eax
L8:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L8
  ret
L2:
  movsd  D14(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: f64

tool: D14: 1

assistant: ```c
double pow_(double x, int e) {
  int i;
  double r = 1;
  for (i = 0; i < e; i++) {
    r *= x;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pow_>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D9(%rip),%xmm0
  test   %edi,%edi
  jle    L8
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L1
  ret
  nopl   0x0(%rax)
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: f64

tool: D9: 1

assistant: ```c
double pow_(double x, int e) {
  int i;
  double r = 1;
  for (i = 0; i < e; i++) {
    r *= x;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pow_>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D9(%rip),%xmm0
  test   %edi,%edi
  jle    L19
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L14:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L14
  ret
  nopl   0x0(%rax)
L19:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: f64

tool: D9: 1

assistant: ```c
double pow_(double x, int e) {
  int i;
  double r = 1;
  for (i = 0; i < e; i++) {
    r *= x;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gemini_processor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffeffe20,%eax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L8
  movzbl -0x1(%rbp),%eax
  and    $0x3,%eax
  jmp    L4
L8:
  mov    $0x4,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int gemini_processor(void) {
  unsigned char cpu = *(unsigned char *)((0xffeffe20));
  return (int)((cpu == 0) ? 4 : (cpu & 0x03));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gemini_processor>:
  endbr64
  movabs 0xffeffe20,%al
  mov    %eax,%edx
  and    $0x3,%edx
  test   %al,%al
  mov    $0x4,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int gemini_processor(void) {
  unsigned char cpu = *(unsigned char *)((0xffeffe20));
  return (int)((cpu == 0) ? 4 : (cpu & 0x03));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gemini_processor>:
  endbr64
  movabs 0xffeffe20,%al
  mov    %eax,%edx
  and    $0x3,%edx
  test   %al,%al
  mov    $0x4,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int gemini_processor(void) {
  unsigned char cpu = *(unsigned char *)((0xffeffe20));
  return (int)((cpu == 0) ? 4 : (cpu & 0x03));
}
```
user: What is the c source code of the assembly code below?

```asm
<gemini_processor>:
  endbr64
  movabs 0xffeffe20,%al
  mov    %eax,%edx
  and    $0x3,%edx
  test   %al,%al
  mov    $0x4,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int gemini_processor(void) {
  unsigned char cpu = *(unsigned char *)((0xffeffe20));
  return (int)((cpu == 0) ? 4 : (cpu & 0x03));
}
```
user: What is the c source code of the assembly code below:

```asm
<COSStyleStrDupPrintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xc0(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc4(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc0(%rbp),%rax
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
char *COSStyleStrDupPrintf(const char *format, ...) {
  char *ptr = NULL;
  va_list ap;
  va_start(ap, format);
  vasprintf(&ptr, format, ap);
  va_end(ap);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<COSStyleStrDupPrintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <vasprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *COSStyleStrDupPrintf(const char *format, ...) {
  char *ptr = NULL;
  va_list ap;
  va_start(ap, format);
  vasprintf(&ptr, format, ap);
  va_end(ap);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<COSStyleStrDupPrintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *COSStyleStrDupPrintf(const char *format, ...) {
  char *ptr = NULL;
  va_list ap;
  va_start(ap, format);
  vasprintf(&ptr, format, ap);
  va_end(ap);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<COSStyleStrDupPrintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *COSStyleStrDupPrintf(const char *format, ...) {
  char *ptr = NULL;
  va_list ap;
  va_start(ap, format);
  vasprintf(&ptr, format, ap);
  va_end(ap);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<time_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rsi,%rax
  mov    %rdi,%r8
  mov    %r8,%rsi
  mov    %r9,%rdi
  mov    %rax,%rdi
  mov    %rsi,-0x10(%rbp)
  mov    %rdi,-0x8(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jge    L23
  mov    $0xffffffff,%eax
  jmp    L66
L23:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jle    L62
  mov    $0x1,%eax
  jmp    L66
L62:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jge    L28
  mov    $0xffffffff,%eax
  jmp    L66
L28:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jle    L21
  mov    $0x1,%eax
  jmp    L66
L21:
  mov    $0x0,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int time_cmp(struct timespec a, struct timespec b) {
  if (a.tv_sec < b.tv_sec)
    return -1;
  if (a.tv_sec > b.tv_sec)
    return 1;
  if (a.tv_nsec < b.tv_nsec)
    return -1;
  if (a.tv_nsec > b.tv_nsec)
    return 1;
  return 0;
}
```