user: 这段汇编代码用C语言表示是什么样的：

```asm
<smtp_auth_plain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %r8,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  add    $0x2,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    -0x48(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L25:
  cmp    %rdx,%rsp
  je     L20
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L20:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movb   $0x0,(%rax)
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movb   $0x0,(%rax)
  mov    -0x78(%rbp),%rdx
  mov    -0x70(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    %rax,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L16
  mov    $0x1,%edi
  call   <exit@plt>
L16:
  mov    -0x30(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sock_sendmsg@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x58(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <smtp_get_msg@plt>
  mov    %rbx,%rsp
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: AUTH PLAIN %s

assistant: ```c
int smtp_auth_plain(struct sock *sock, const char *user, size_t user_size, const char *passwd, size_t passwd_size) {
  const size_t total_size = user_size + passwd_size + 2;
  unsigned char buf[total_size + 1], *p = buf;
  *p++ = '\0';
  p = mempcpy(p, user, user_size);
  *p++ = '\0';
  memcpy(p, passwd, passwd_size);
  char *encoded = base64_encode(buf, total_size, NULL);
  if (!encoded)
    exit(1);
  sock_sendmsg(sock, "AUTH PLAIN %s", encoded);
  free(encoded);
  return smtp_get_msg(sock, 1);
}
```