ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L53:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L48:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jne    L12
  mov    $0x1,%eax
  jmp    L39
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jge    L37
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jge    L37
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L48
L37:
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L53
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int isSubstring(char str1[], char str2[]) {
  int counter = 0;
  for (int i = 0; i < strlen(str2); i++) {
    int start = i;
    while (counter < strlen(str2) && start < strlen(str1) && str1[start++] == str2[counter++]) {
      if (counter == strlen(str2))
        return 1;
    }
    counter = 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isSubstring>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%r14d
  jmp    L8
L28:
  add    $0x1,%r14
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L12
  mov    %r14,%rbp
  mov    $0x0,%ebx
L33:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L28
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L28
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%r13,%rbp,1)
  jne    L28
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %ebx,%eax
  jne    L33
  mov    $0x1,%eax
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    $0x0,%eax
  jmp    L58
```

assistant: ```c
int isSubstring(char str1[], char str2[]) {
  int counter = 0;
  for (int i = 0; i < strlen(str2); i++) {
    int start = i;
    while (counter < strlen(str2) && start < strlen(str1) && str1[start++] == str2[counter++]) {
      if (counter == strlen(str2))
        return 1;
    }
    counter = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isSubstring>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L11
L61:
  mov    %r14,%rbp
  xor    %ebx,%ebx
  jmp    L58
  nopl   0x0(%rax)
L9:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L50
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%r13,%rbp,1)
  jne    L50
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <strlen@plt>
  cmp    %ebx,%eax
  je     L12
L58:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
L50:
  mov    %r12,%rdi
  add    $0x1,%r14
  call   <strlen@plt>
  cmp    %r14d,%eax
  jg     L61
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L12:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int isSubstring(char str1[], char str2[]) {
  int counter = 0;
  for (int i = 0; i < strlen(str2); i++) {
    int start = i;
    while (counter < strlen(str2) && start < strlen(str1) && str1[start++] == str2[counter++]) {
      if (counter == strlen(str2))
        return 1;
    }
    counter = 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isSubstring>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L49
L32:
  mov    %r14,%rbp
  xor    %ebx,%ebx
  jmp    L23
  nopl   0x0(%rax)
L25:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L21
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%r13,%rbp,1)
  jne    L21
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <strlen@plt>
  cmp    %ebx,%eax
  je     L45
L23:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L25
L21:
  mov    %r12,%rdi
  add    $0x1,%r14
  call   <strlen@plt>
  cmp    %r14d,%eax
  jg     L32
L49:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L45:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int isSubstring(char str1[], char str2[]) {
  int counter = 0;
  for (int i = 0; i < strlen(str2); i++) {
    int start = i;
    while (counter < strlen(str2) && start < strlen(str1) && str1[start++] == str2[counter++]) {
      if (counter == strlen(str2))
        return 1;
    }
    counter = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_letter_distribiton_diagram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L47:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  movl   $0x0,(%rdx,%rax,1)
  addl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x19,-0xc(%rbp)
  jle    L47
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L27:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L38:
  mov    -0x8(%rbp),%eax
  lea    0x61(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,%edx
  je     L69
  mov    -0x8(%rbp),%eax
  lea    0x41(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,%edx
  jne    L16
L69:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
L16:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L38
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x19,-0x8(%rbp)
  jle    L27
  lea    D11(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *create_letter_distribiton_diagram(int len, char s[]) {
  static int alphabet[26];
  int fill;
  for (fill = 0; fill < 26; fill++) {
    alphabet[fill] = 0;
  }
  int count_l;
  int count_s;
  for (count_l = 0; count_l < 26; count_l++) {
    for (count_s = 0; count_s < len; count_s++) {
      if (count_l + 'a' == *(s + count_s) || count_l + 'A' == *(s + count_s)) {
        alphabet[count_l]++;
      }
    }
  }
  return alphabet;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<create_letter_distribiton_diagram>:
  endbr64
  lea    D17(%rip),%rcx
  lea    0x68(%rcx),%rdx
  mov    %rcx,%rax
L76:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L76
  mov    $0x61,%r8d
  mov    $0x41,%r9d
  lea    -0x1(%rdi),%eax
  lea    0x1(%rsi,%rax,1),%r10
  jmp    L45
L85:
  addl   $0x1,(%rcx)
L56:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L82
L78:
  movsbl (%rax),%edx
  cmp    %r8d,%edx
  je     L85
  cmp    %r9d,%edx
  jne    L56
  jmp    L85
L82:
  add    $0x4,%rcx
  add    $0x1,%r9d
  add    $0x1,%r8d
  cmp    $0x5b,%r9d
  je     L50
L45:
  mov    %rsi,%rax
  test   %edi,%edi
  jg     L78
  jmp    L82
L50:
  lea    D17(%rip),%rax
  ret
```

assistant: ```c
int *create_letter_distribiton_diagram(int len, char s[]) {
  static int alphabet[26];
  int fill;
  for (fill = 0; fill < 26; fill++) {
    alphabet[fill] = 0;
  }
  int count_l;
  int count_s;
  for (count_l = 0; count_l < 26; count_l++) {
    for (count_s = 0; count_s < len; count_s++) {
      if (count_l + 'a' == *(s + count_s) || count_l + 'A' == *(s + count_s)) {
        alphabet[count_l]++;
      }
    }
  }
  return alphabet;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<create_letter_distribiton_diagram>:
  endbr64
  lea    D9(%rip),%r11
  mov    %edi,%r10d
  xor    %eax,%eax
  mov    %rsi,%r9
  mov    $0xd,%ecx
  mov    %r11,%rdi
  mov    $0x61,%esi
  mov    $0x41,%r8d
  rep stos %rax,%es:(%rdi)
  lea    -0x1(%r10),%eax
  mov    %r11,%rcx
  lea    0x1(%r9,%rax,1),%rdi
  nopl   (%rax)
L63:
  mov    %r9,%rax
  test   %r10d,%r10d
  jg     L16
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L50:
  cmp    %r8d,%edx
  je     L45
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L24
L16:
  movsbl (%rax),%edx
  cmp    %esi,%edx
  jne    L50
L45:
  add    $0x1,%rax
  addl   $0x1,(%rcx)
  cmp    %rax,%rdi
  jne    L16
L24:
  add    $0x1,%esi
  add    $0x1,%r8d
  add    $0x4,%rcx
  cmp    $0x7b,%esi
  jne    L63
  mov    %r11,%rax
  ret
```

assistant: ```c
int *create_letter_distribiton_diagram(int len, char s[]) {
  static int alphabet[26];
  int fill;
  for (fill = 0; fill < 26; fill++) {
    alphabet[fill] = 0;
  }
  int count_l;
  int count_s;
  for (count_l = 0; count_l < 26; count_l++) {
    for (count_s = 0; count_s < len; count_s++) {
      if (count_l + 'a' == *(s + count_s) || count_l + 'A' == *(s + count_s)) {
        alphabet[count_l]++;
      }
    }
  }
  return alphabet;
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_letter_distribiton_diagram>:
  endbr64
  lea    D5(%rip),%r10
  mov    %edi,%edx
  mov    $0xd,%ecx
  xor    %eax,%eax
  mov    %r10,%rdi
  mov    %rsi,%r9
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L32
  lea    -0x1(%rdx),%eax
  mov    %r10,%rcx
  mov    $0x61,%esi
  mov    $0x41,%r8d
  lea    0x1(%r9,%rax,1),%rdi
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r9,%rax
  jmp    L20
  nopl   (%rax)
L55:
  cmp    %r8d,%edx
  je     L31
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L68
L20:
  movsbl (%rax),%edx
  cmp    %esi,%edx
  jne    L55
L31:
  add    $0x1,%rax
  addl   $0x1,(%rcx)
  cmp    %rax,%rdi
  jne    L20
L68:
  add    $0x1,%esi
  add    $0x1,%r8d
  add    $0x4,%rcx
  cmp    $0x7b,%esi
  jne    L51
L32:
  mov    %r10,%rax
  ret
```

assistant: ```c
int *create_letter_distribiton_diagram(int len, char s[]) {
  static int alphabet[26];
  int fill;
  for (fill = 0; fill < 26; fill++) {
    alphabet[fill] = 0;
  }
  int count_l;
  int count_s;
  for (count_l = 0; count_l < 26; count_l++) {
    for (count_s = 0; count_s < len; count_s++) {
      if (count_l + 'a' == *(s + count_s) || count_l + 'A' == *(s + count_s)) {
        alphabet[count_l]++;
      }
    }
  }
  return alphabet;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clr_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L39
L11:
  mov    -0x24(%rbp),%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  je     L16
  mov    $0x0,%eax
  jmp    L29
L16:
  addl   $0x2,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L11
  mov    $0x1,%eax
L29:
  leave
  ret
```

assistant: ```c
int clr_row(const char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clr_row>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %ecx,%ebx
  and    $0x1,%ebx
  cmp    %edx,%ebx
  jge    L10
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %edx,%ebp
  mov    %ecx,%r12d
  lea    -0x1(%rdx),%eax
  sub    %ebx,%eax
  and    $0xfffffffe,%eax
  lea    0x2(%rbx,%rax,1),%r15d
L2:
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  jne    L21
  add    $0x2,%ebx
  cmp    %r15d,%ebx
  jne    L2
  mov    $0x1,%eax
  jmp    L39
L10:
  mov    $0x1,%eax
  jmp    L39
L21:
  mov    $0x0,%eax
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int clr_row(const char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<clr_row>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  and    $0x1,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%ebx
  jge    L22
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  sub    %ebx,%eax
  mov    %ecx,%r15d
  and    $0xfffffffe,%eax
  lea    0x2(%rbx,%rax,1),%r14d
  jmp    L11
  nopl   (%rax)
L34:
  add    $0x2,%ebx
  cmp    %r14d,%ebx
  je     L22
L11:
  mov    %r15d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  je     L34
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int clr_row(const char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clr_row>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  and    $0x1,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%ebx
  jge    L10
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  sub    %ebx,%eax
  mov    %ecx,%r15d
  and    $0xfffffffe,%eax
  lea    0x2(%rbx,%rax,1),%r14d
  jmp    L11
  nopl   (%rax)
L12:
  add    $0x2,%ebx
  cmp    %r14d,%ebx
  je     L10
L11:
  mov    %r15d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  je     L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int clr_row(const char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sancus_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
L11:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L10
  mov    -0x8(%rbp),%rax
  jmp    L13
L10:
  mov    D28(%rip),%rax
  mov    (%rax),%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L11
  mov    D28(%rip),%rax
  mov    (%rax),%rax
  neg    %rax
L13:
  leave
  ret
```

assistant: ```c
ssize_t sancus_read(int fd, char *buf, size_t count) {
  while (1) {
    ssize_t rc = read(fd, buf, count);
    if (rc >= 0)
      return rc;
    else if (errno != EINTR)
      return -errno;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sancus_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
L16:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  jns    L14
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  mov    D5(%rip),%rdx
  cmp    (%rdx),%rax
  je     L16
  neg    %rax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t sancus_read(int fd, char *buf, size_t count) {
  while (1) {
    ssize_t rc = read(fd, buf, count);
    if (rc >= 0)
      return rc;
    else if (errno != EINTR)
      return -errno;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sancus_read>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D14(%rip),%rax
  mov    D10(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  jne    L7
L2:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  js     L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  pop    %rbx
  neg    %rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t sancus_read(int fd, char *buf, size_t count) {
  while (1) {
    ssize_t rc = read(fd, buf, count);
    if (rc >= 0)
      return rc;
    else if (errno != EINTR)
      return -errno;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sancus_read>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L11:
  mov    D14(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  jne    L23
L16:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  js     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  pop    %rbx
  neg    %rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t sancus_read(int fd, char *buf, size_t count) {
  while (1) {
    ssize_t rc = read(fd, buf, count);
    if (rc >= 0)
      return rc;
    else if (errno != EINTR)
      return -errno;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tp_get_sec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <tp_sub@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <tp_to_sec@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
float tp_get_sec(clockid_t clock_id, struct timespec *tp) {
  struct timespec now;
  assert(0 == clock_gettime(clock_id, &now));
  struct timespec delta;
  tp_sub(&now, tp, &delta);
  return tp_to_sec(&delta);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tp_get_sec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <clock_gettime@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <tp_sub@plt>
  mov    %rbp,%rdi
  call   <tp_to_sec@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float tp_get_sec(clockid_t clock_id, struct timespec *tp) {
  struct timespec now;
  assert(0 == clock_gettime(clock_id, &now));
  struct timespec delta;
  tp_sub(&now, tp, &delta);
  return tp_to_sec(&delta);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tp_get_sec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x4(%rsp),%r12
  mov    %r13,%rsi
  call   <clock_gettime@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <tp_sub@plt>
  mov    %r12,%rdi
  call   <tp_to_sec@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float tp_get_sec(clockid_t clock_id, struct timespec *tp) {
  struct timespec now;
  assert(0 == clock_gettime(clock_id, &now));
  struct timespec delta;
  tp_sub(&now, tp, &delta);
  return tp_to_sec(&delta);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tp_get_sec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x4(%rsp),%r12
  mov    %r13,%rsi
  call   <clock_gettime@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <tp_sub@plt>
  mov    %r12,%rdi
  call   <tp_to_sec@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float tp_get_sec(clockid_t clock_id, struct timespec *tp) {
  struct timespec now;
  assert(0 == clock_gettime(clock_id, &now));
  struct timespec delta;
  tp_sub(&now, tp, &delta);
  return tp_to_sec(&delta);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ovtpvt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void ovtpvt(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vfprintf(stdout, format, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ovtpvt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ovtpvt(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vfprintf(stdout, format, ap);
  va_end(ap);
}
```