ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<getmet>:
  endbr64
  andpd  D89(%rip),%xmm0
  movsd  D59(%rip),%xmm1
  mov    %rdi,%rdx
  comisd %xmm0,%xmm1
  jb     L49
  movsd  D72(%rip),%xmm0
  xor    %eax,%eax
  lea    D11(%rip),%rcx
  jmp    L25
L61:
  movsd  (%rcx,%rax,1),%xmm0
L25:
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x50,%rax
  jne    L61
  ret
  nopl   (%rax)
L49:
  comisd D37(%rip),%xmm0
  jb     L39
  movsd  D53(%rip),%xmm0
  xor    %eax,%eax
  lea    D7(%rip),%rcx
  jmp    L59
  nopl   (%rax)
L11:
  movsd  (%rcx,%rax,1),%xmm0
L59:
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x50,%rax
  jne    L11
  ret
  nopl   (%rax)
L39:
  movapd %xmm0,%xmm2
  movsd  D46(%rip),%xmm3
  lea    D11(%rip),%rcx
  divsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  sub    $0x1,%eax
  cltq
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  mulsd  %xmm1,%xmm2
  lea    (%rax,%rcx,1),%rsi
  lea    0x50(%rcx,%rax,1),%rcx
  xor    %eax,%eax
  subsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  nopl   0x0(%rax,%rax,1)
L14:
  movsd  (%rsi,%rax,1),%xmm1
  movsd  (%rcx,%rax,1),%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x50,%rax
  jne    L14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D89
type: qword[2]
name: extract_symbolic_data
arguments: data_label: D59
type: f64
name: extract_symbolic_data
arguments: data_label: D72
type: f64
name: extract_symbolic_data
arguments: data_label: D11
type: f64
name: extract_symbolic_data
arguments: data_label: D37
type: f64[2]
name: extract_symbolic_data
arguments: data_label: D53
type: f64
name: extract_symbolic_data
arguments: data_label: D7
type: f64
name: extract_symbolic_data
arguments: data_label: D46
type: f64

tool: {"D89": [0x7fffffffffffffff,0x0000000000000000]}

tool: D59: 15

tool: D72: 1013.25

tool: D11: 1013.25

tool: {"D37": [75.0,1.0]}

tool: D53: 1013

tool: D7: 1013

tool: D46: 1

assistant: ```c
void getmet(double lat, double *met) {
  static const double metprm[][10] = {{1013.25, 299.65, 26.31, 6.30E-3, 2.77, 0.00, 0.00, 0.00, 0.00E-3, 0.00}, {1017.25, 294.15, 21.79, 6.05E-3, 3.15, -3.75, 7.00, 8.85, 0.25E-3, 0.33}, {1015.75, 283.15, 11.66, 5.58E-3, 2.57, -2.25, 11.00, 7.24, 0.32E-3, 0.46}, {1011.75, 272.15, 6.78, 5.39E-3, 1.81, -1.75, 15.00, 5.36, 0.81E-3, 0.74}, {1013.00, 263.65, 4.11, 4.53E-3, 1.55, -0.50, 14.50, 3.39, 0.62E-3, 0.30}};
  int i, j;
  double a;
  lat = fabs(lat);
  if (lat <= 15.0)
    for (i = 0; i < 10; i++)
      met[i] = metprm[0][i];
  else if (lat >= 75.0)
    for (i = 0; i < 10; i++)
      met[i] = metprm[4][i];
  else {
    j = (int)(lat / 15.0);
    a = (lat - j * 15.0) / 15.0;
    for (i = 0; i < 10; i++)
      met[i] = (1.0 - a) * metprm[j - 1][i] + a * metprm[j][i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L23:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <user_dialogue@plt>
L8:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int stop = 0;
  while (stop == 0) {
    user_dialogue(&stop);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L11:
  mov    %rbx,%rdi
  call   <user_dialogue@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int stop = 0;
  while (stop == 0) {
    user_dialogue(&stop);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <user_dialogue@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int stop = 0;
  while (stop == 0) {
    user_dialogue(&stop);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <user_dialogue@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int stop = 0;
  while (stop == 0) {
    user_dialogue(&stop);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hextochar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  cmpb   $0x39,-0x14(%rbp)
  jle    L7
  movzbl -0x14(%rbp),%eax
  sub    $0x57,%eax
  jmp    L9
L7:
  movzbl -0x14(%rbp),%eax
  sub    $0x30,%eax
L9:
  mov    %al,-0x2(%rbp)
  cmpb   $0x39,-0x18(%rbp)
  jle    L25
  movzbl -0x18(%rbp),%eax
  sub    $0x57,%eax
  jmp    L8
L25:
  movzbl -0x18(%rbp),%eax
  sub    $0x30,%eax
L8:
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char hextochar(char a, char b) {
  unsigned char hn, ln;
  hn = a > '9' ? a - 'a' + 10 : a - '0';
  ln = b > '9' ? b - 'a' + 10 : b - '0';
  return ((hn << 4) | ln);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hextochar>:
  endbr64
  lea    -0x57(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x3a,%dil
  cmovge %edx,%eax
  lea    -0x57(%rsi),%ecx
  lea    -0x30(%rsi),%edx
  cmp    $0x3a,%sil
  cmovge %ecx,%edx
  shl    $0x4,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char hextochar(char a, char b) {
  unsigned char hn, ln;
  hn = a > '9' ? a - 'a' + 10 : a - '0';
  ln = b > '9' ? b - 'a' + 10 : b - '0';
  return ((hn << 4) | ln);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hextochar>:
  endbr64
  lea    -0x57(%rdi),%edx
  cmp    $0x3a,%dil
  lea    -0x30(%rdi),%eax
  cmovge %edx,%eax
  lea    -0x57(%rsi),%ecx
  lea    -0x30(%rsi),%edx
  cmp    $0x3a,%sil
  cmovge %ecx,%edx
  shl    $0x4,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char hextochar(char a, char b) {
  unsigned char hn, ln;
  hn = a > '9' ? a - 'a' + 10 : a - '0';
  ln = b > '9' ? b - 'a' + 10 : b - '0';
  return ((hn << 4) | ln);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hextochar>:
  endbr64
  lea    -0x57(%rdi),%edx
  cmp    $0x3a,%dil
  lea    -0x30(%rdi),%eax
  cmovge %edx,%eax
  lea    -0x57(%rsi),%ecx
  lea    -0x30(%rsi),%edx
  cmp    $0x3a,%sil
  cmovge %ecx,%edx
  shl    $0x4,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char hextochar(char a, char b) {
  unsigned char hn, ln;
  hn = a > '9' ? a - 'a' + 10 : a - '0';
  ln = b > '9' ? b - 'a' + 10 : b - '0';
  return ((hn << 4) | ln);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tvin_powerdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <tvafe_hw_powerdown@plt>
  mov    $0x0,%eax
  call   <hdmi_hw_powerdown@plt>
  mov    $0x0,%edi
  call   <vdin_hw_powerdown@plt>
  mov    $0x70,%edi
  call   <vdin_hw_powerdown@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tvin_powerdown(void) {
  tvafe_hw_powerdown();
  hdmi_hw_powerdown();
  vdin_hw_powerdown(0x00);
  vdin_hw_powerdown(0x70);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tvin_powerdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tvafe_hw_powerdown@plt>
  mov    $0x0,%eax
  call   <hdmi_hw_powerdown@plt>
  mov    $0x0,%edi
  call   <vdin_hw_powerdown@plt>
  mov    $0x70,%edi
  call   <vdin_hw_powerdown@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void tvin_powerdown(void) {
  tvafe_hw_powerdown();
  hdmi_hw_powerdown();
  vdin_hw_powerdown(0x00);
  vdin_hw_powerdown(0x70);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tvin_powerdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tvafe_hw_powerdown@plt>
  xor    %eax,%eax
  call   <hdmi_hw_powerdown@plt>
  xor    %edi,%edi
  call   <vdin_hw_powerdown@plt>
  mov    $0x70,%edi
  add    $0x8,%rsp
  jmp    1090 <vdin_hw_powerdown@plt>
```

assistant: ```c
void tvin_powerdown(void) {
  tvafe_hw_powerdown();
  hdmi_hw_powerdown();
  vdin_hw_powerdown(0x00);
  vdin_hw_powerdown(0x70);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tvin_powerdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tvafe_hw_powerdown@plt>
  xor    %eax,%eax
  call   <hdmi_hw_powerdown@plt>
  xor    %edi,%edi
  call   <vdin_hw_powerdown@plt>
  mov    $0x70,%edi
  add    $0x8,%rsp
  jmp    1090 <vdin_hw_powerdown@plt>
```

assistant: ```c
void tvin_powerdown(void) {
  tvafe_hw_powerdown();
  hdmi_hw_powerdown();
  vdin_hw_powerdown(0x00);
  vdin_hw_powerdown(0x70);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  xor    $0x29be1cdb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L20:
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0xc(%rbp),%rdx
  add    $0x2,%rdx
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x2,-0x10(%rbp)
L1:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L20
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  and    $0x1c1e9340,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 595841640UL) << 3U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  mov    (%rdi),%edx
  xor    $0x29be1cdb,%edx
  mov    %edx,%ebx
  mov    0x4(%rdi),%r8d
  test   %r8d,%r8d
  je     L23
  movsbl %dh,%ecx
  shl    $0x8,%edx
  shr    $0x18,%edx
  mov    $0x0,%eax
  jmp    L12
L2:
  mov    %ecx,%edi
  mov    %edx,%ecx
  mov    %edi,%edx
L12:
  add    $0x2,%eax
  cmp    %r8d,%eax
  jb     L2
  mov    %dl,%bh
  movzbl %cl,%ecx
  shl    $0x10,%ecx
  and    $0xff00ffff,%ebx
  or     %ecx,%ebx
L23:
  shl    $0x3,%ebx
  and    $0x1c1e9340,%ebx
  mov    %ebx,(%rsi)
  pop    %rbx
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 595841640UL) << 3U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r8d
  xor    $0x29be1cdb,%eax
  test   %r8d,%r8d
  je     L28
  push   %rbx
  mov    %eax,%ebx
  xor    %edx,%edx
  movsbl %ah,%eax
  mov    %ebx,%ecx
  shl    $0x8,%ecx
  shr    $0x18,%ecx
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %eax,%edi
  mov    %ecx,%eax
  mov    %edi,%ecx
L5:
  add    $0x2,%edx
  cmp    %r8d,%edx
  jb     L21
  mov    %cl,%bh
  movzbl %al,%eax
  and    $0xff00ffff,%ebx
  shl    $0x10,%eax
  or     %ebx,%eax
  pop    %rbx
  shl    $0x3,%eax
  and    $0x1c1e9340,%eax
  mov    %eax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  shl    $0x3,%eax
  and    $0x1c1e9340,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 595841640UL) << 3U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r8d
  xor    $0x29be1cdb,%eax
  test   %r8d,%r8d
  je     L13
  push   %rbx
  mov    %eax,%ebx
  xor    %edx,%edx
  movsbl %ah,%eax
  mov    %ebx,%ecx
  shl    $0x8,%ecx
  shr    $0x18,%ecx
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %eax,%edi
  mov    %ecx,%eax
  mov    %edi,%ecx
L14:
  add    $0x2,%edx
  cmp    %r8d,%edx
  jb     L27
  mov    %cl,%bh
  movzbl %al,%eax
  and    $0xff00ffff,%ebx
  shl    $0x10,%eax
  or     %ebx,%eax
  pop    %rbx
  shl    $0x3,%eax
  and    $0x1c1e9340,%eax
  mov    %eax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  shl    $0x3,%eax
  and    $0x1c1e9340,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 595841640UL) << 3U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getChoice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string
name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D45
data_type: string
name: retrieve_data
arguments: label: D34
data_type: string

tool: D16: 
Please select an option:


tool: D25:  0) Exit
 1) Create a new task
 2) Execute a task


tool: D1:  3) insert ID task and execute
 4) Delete a task
 5) Modify the PRIORITY of a task


tool: D11:  6) Switch policy (default : PRIORITY)
 7) Modify the REMAINING EXECUTIONS of a task

tool: D45: 
> 

tool: D34: %i

assistant: ```c
int getChoice() {
  printf("\n\rPlease select an option:\n\r");
  printf(" 0) Exit\n\r 1) Create a new task\n\r 2) Execute a task\n\r");
  printf(" 3) insert ID task and execute\n\r 4) Delete a task\n\r 5) Modify the PRIORITY of a task\n\r");
  printf(" 6) Switch policy (default : PRIORITY)\n\r 7) Modify the REMAINING EXECUTIONS of a task");
  int res = 0;
  printf("\n\r> ");
  scanf("%i", &res);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getChoice>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  movl   $0x0,0x4(%rsp)
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D40
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D49
datatype: string
name: parse_data
arguments: data_tag: D22
datatype: string

tool: D10: 
Please select an option:


tool: D40:  0) Exit
 1) Create a new task
 2) Execute a task


tool: D7:  3) insert ID task and execute
 4) Delete a task
 5) Modify the PRIORITY of a task


tool: D26:  6) Switch policy (default : PRIORITY)
 7) Modify the REMAINING EXECUTIONS of a task

tool: D49: 
> 

tool: D22: %i

assistant: ```c
int getChoice() {
  printf("\n\rPlease select an option:\n\r");
  printf(" 0) Exit\n\r 1) Create a new task\n\r 2) Execute a task\n\r");
  printf(" 3) insert ID task and execute\n\r 4) Delete a task\n\r 5) Modify the PRIORITY of a task\n\r");
  printf(" 6) Switch policy (default : PRIORITY)\n\r 7) Modify the REMAINING EXECUTIONS of a task");
  int res = 0;
  printf("\n\r> ");
  scanf("%i", &res);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getChoice>:
  endbr64
  sub    $0x18,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D37
datatype: string
name: retrieve_data
arguments: tag: D31
datatype: string
name: retrieve_data
arguments: tag: D45
datatype: string
name: retrieve_data
arguments: tag: D51
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string

tool: D37: 
Please select an option:


tool: D31:  0) Exit
 1) Create a new task
 2) Execute a task


tool: D45:  3) insert ID task and execute
 4) Delete a task
 5) Modify the PRIORITY of a task


tool: D51:  6) Switch policy (default : PRIORITY)
 7) Modify the REMAINING EXECUTIONS of a task

tool: D10: 
> 

tool: D39: %i

assistant: ```c
int getChoice() {
  printf("\n\rPlease select an option:\n\r");
  printf(" 0) Exit\n\r 1) Create a new task\n\r 2) Execute a task\n\r");
  printf(" 3) insert ID task and execute\n\r 4) Delete a task\n\r 5) Modify the PRIORITY of a task\n\r");
  printf(" 6) Switch policy (default : PRIORITY)\n\r 7) Modify the REMAINING EXECUTIONS of a task");
  int res = 0;
  printf("\n\r> ");
  scanf("%i", &res);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getChoice>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D23
type_guessed: string
name: read_data
arguments: label: D34
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D56
type_guessed: string

tool: D23: 
Please select an option:


tool: D34:  0) Exit
 1) Create a new task
 2) Execute a task


tool: D11:  3) insert ID task and execute
 4) Delete a task
 5) Modify the PRIORITY of a task


tool: D26:  6) Switch policy (default : PRIORITY)
 7) Modify the REMAINING EXECUTIONS of a task

tool: D29: 
> 

tool: D56: %i

assistant: ```c
int getChoice() {
  printf("\n\rPlease select an option:\n\r");
  printf(" 0) Exit\n\r 1) Create a new task\n\r 2) Execute a task\n\r");
  printf(" 3) insert ID task and execute\n\r 4) Delete a task\n\r 5) Modify the PRIORITY of a task\n\r");
  printf(" 6) Switch policy (default : PRIORITY)\n\r 7) Modify the REMAINING EXECUTIONS of a task");
  int res = 0;
  printf("\n\r> ");
  scanf("%i", &res);
  return res;
}
```