ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<streqci>:
  endbr64
  xor    %ecx,%ecx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rcx
  test   %al,%al
  je     L24
L15:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  cmp    $0x1a,%r9b
  lea    -0x61(%rdx),%r9d
  cmovb  %r8d,%eax
  lea    -0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  je     L10
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int streqci(const char *s1, const char *s2) {
  for (;;) {
    char c1 = *s1++;
    char c2 = *s2++;
    if ('a' <= c1 && c1 <= 'z')
      c1 += 'A' - 'a';
    if ('a' <= c2 && c2 <= 'z')
      c2 += 'A' - 'a';
    if (c1 != c2)
      return 0;
    if (!c1)
      break;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<streqci>:
  endbr64
  xor    %ecx,%ecx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rcx
  test   %al,%al
  je     L6
L12:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  cmp    $0x1a,%r9b
  lea    -0x61(%rdx),%r9d
  cmovb  %r8d,%eax
  lea    -0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  je     L29
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int streqci(const char *s1, const char *s2) {
  for (;;) {
    char c1 = *s1++;
    char c2 = *s2++;
    if ('a' <= c1 && c1 <= 'z')
      c1 += 'A' - 'a';
    if ('a' <= c2 && c2 <= 'z')
      c2 += 'A' - 'a';
    if (c1 != c2)
      return 0;
    if (!c1)
      break;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nibble_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x1c,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x14,%eax
  and    $0xf0,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0xc,%eax
  and    $0xf00,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf000,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf0000,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0xc,%eax
  and    $0xf00000,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x14,%eax
  and    $0xf000000,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x1c,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int nibble_swap(unsigned int number) {
  unsigned int new_number = 0;
  new_number |= ((number & 0xF0000000) >> (28 - 0));
  new_number |= ((number & 0x0F000000) >> (24 - 4));
  new_number |= ((number & 0x00F00000) >> (20 - 8));
  new_number |= ((number & 0x000F0000) >> (16 - 12));
  new_number |= ((number & 0x0000F000) << (16 - 12));
  new_number |= ((number & 0x00000F00) << (20 - 8));
  new_number |= ((number & 0x000000F0) << (24 - 4));
  new_number |= ((number & 0x0000000F) << (28 - 0));
  return new_number;
}
```
user: What is the c source code of the assembly code below:

```asm
<nibble_swap>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shr    $0x1c,%eax
  mov    %edi,%ecx
  shl    $0x1c,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x14,%ecx
  and    $0xf0,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0xc,%ecx
  and    $0xf00,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x4,%ecx
  and    $0xf000,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x4,%ecx
  and    $0xf0000,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0xc,%ecx
  and    $0xf00000,%ecx
  or     %ecx,%eax
  shl    $0x14,%edx
  and    $0xf000000,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int nibble_swap(unsigned int number) {
  unsigned int new_number = 0;
  new_number |= ((number & 0xF0000000) >> (28 - 0));
  new_number |= ((number & 0x0F000000) >> (24 - 4));
  new_number |= ((number & 0x00F00000) >> (20 - 8));
  new_number |= ((number & 0x000F0000) >> (16 - 12));
  new_number |= ((number & 0x0000F000) << (16 - 12));
  new_number |= ((number & 0x00000F00) << (20 - 8));
  new_number |= ((number & 0x000000F0) << (24 - 4));
  new_number |= ((number & 0x0000000F) << (28 - 0));
  return new_number;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nibble_swap>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  mov    %edi,%edx
  shl    $0x1c,%ecx
  shr    $0x1c,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x14,%edx
  shr    $0x14,%ecx
  and    $0xf000000,%edx
  and    $0xf0,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0xc,%ecx
  and    $0xf00,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x4,%ecx
  and    $0xf000,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x4,%ecx
  and    $0xf0000,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0xc,%ecx
  and    $0xf00000,%ecx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int nibble_swap(unsigned int number) {
  unsigned int new_number = 0;
  new_number |= ((number & 0xF0000000) >> (28 - 0));
  new_number |= ((number & 0x0F000000) >> (24 - 4));
  new_number |= ((number & 0x00F00000) >> (20 - 8));
  new_number |= ((number & 0x000F0000) >> (16 - 12));
  new_number |= ((number & 0x0000F000) << (16 - 12));
  new_number |= ((number & 0x00000F00) << (20 - 8));
  new_number |= ((number & 0x000000F0) << (24 - 4));
  new_number |= ((number & 0x0000000F) << (28 - 0));
  return new_number;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nibble_swap>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  mov    %edi,%edx
  shl    $0x1c,%ecx
  shr    $0x1c,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x14,%edx
  shr    $0x14,%ecx
  and    $0xf000000,%edx
  and    $0xf0,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0xc,%ecx
  and    $0xf00,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x4,%ecx
  and    $0xf000,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x4,%ecx
  and    $0xf0000,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0xc,%ecx
  and    $0xf00000,%ecx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int nibble_swap(unsigned int number) {
  unsigned int new_number = 0;
  new_number |= ((number & 0xF0000000) >> (28 - 0));
  new_number |= ((number & 0x0F000000) >> (24 - 4));
  new_number |= ((number & 0x00F00000) >> (20 - 8));
  new_number |= ((number & 0x000F0000) >> (16 - 12));
  new_number |= ((number & 0x0000F000) << (16 - 12));
  new_number |= ((number & 0x00000F00) << (20 - 8));
  new_number |= ((number & 0x000000F0) << (24 - 4));
  new_number |= ((number & 0x0000000F) << (28 - 0));
  return new_number;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<long2ape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void long2ape(unsigned char *p, const unsigned long value) {
  p[0] = (unsigned char)(value >> 0);
  p[1] = (unsigned char)(value >> 8);
  p[2] = (unsigned char)(value >> 16);
  p[3] = (unsigned char)(value >> 24);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<long2ape>:
  endbr64
  mov    %rsi,%rax
  mov    %sil,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %rsi,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x2(%rdi)
  shr    $0x18,%rax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void long2ape(unsigned char *p, const unsigned long value) {
  p[0] = (unsigned char)(value >> 0);
  p[1] = (unsigned char)(value >> 8);
  p[2] = (unsigned char)(value >> 16);
  p[3] = (unsigned char)(value >> 24);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<long2ape>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void long2ape(unsigned char *p, const unsigned long value) {
  p[0] = (unsigned char)(value >> 0);
  p[1] = (unsigned char)(value >> 8);
  p[2] = (unsigned char)(value >> 16);
  p[3] = (unsigned char)(value >> 24);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<long2ape>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void long2ape(unsigned char *p, const unsigned long value) {
  p[0] = (unsigned char)(value >> 0);
  p[1] = (unsigned char)(value >> 8);
  p[2] = (unsigned char)(value >> 16);
  p[3] = (unsigned char)(value >> 24);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_bool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  test   %eax,%eax
  jg     L6
  mov    $0x0,%eax
  jmp    L27
L6:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: =%d 

assistant: ```c
bool read_bool(FILE *file, bool *out) {
  int value;
  if (fscanf(file, "=%d ", &value) < 1)
    return false;
  *out = (bool)value;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_bool>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D1(%rip),%rsi
  call   <fscanf@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L9
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: =%d 

assistant: ```c
bool read_bool(FILE *file, bool *out) {
  int value;
  if (fscanf(file, "=%d ", &value) < 1)
    return false;
  *out = (bool)value;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_bool>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D7(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <fscanf@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L13
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: =%d 

assistant: ```c
bool read_bool(FILE *file, bool *out) {
  int value;
  if (fscanf(file, "=%d ", &value) < 1)
    return false;
  *out = (bool)value;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_bool>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D8(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <fscanf@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L14
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: =%d 

assistant: ```c
bool read_bool(FILE *file, bool *out) {
  int value;
  if (fscanf(file, "=%d ", &value) < 1)
    return false;
  *out = (bool)value;
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L15
L3:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: %s

assistant: ```c
int main() {
  char str[1000];
  while (getline(str, 1000) != 0)
    printf("%s", str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rbx
  jmp    L28
L14:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L28:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getline@plt>
  test   %rax,%rax
  jne    L14
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: %s

assistant: ```c
int main() {
  char str[1000];
  while (getline(str, 1000) != 0)
    printf("%s", str);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L22
  nopl   0x0(%rax)
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L22:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L13
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: %s

assistant: ```c
int main() {
  char str[1000];
  while (getline(str, 1000) != 0)
    printf("%s", str);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L29
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L29:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L5
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: %s

assistant: ```c
int main() {
  char str[1000];
  while (getline(str, 1000) != 0)
    printf("%s", str);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string

tool: D1: 1.11-1

tool: D2: powertop version %s


assistant: ```c
void version() {
  printf(((const char *)("powertop version %s\n")), "1.11-1");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D0: 1.11-1

tool: D10: powertop version %s


assistant: ```c
void version() {
  printf(((const char *)("powertop version %s\n")), "1.11-1");
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  lea    D14(%rip),%rsi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D10: powertop version %s


tool: D14: 1.11-1

assistant: ```c
void version() {
  printf(((const char *)("powertop version %s\n")), "1.11-1");
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  lea    D1(%rip),%rsi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type: string
name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D13: powertop version %s


tool: D1: 1.11-1

assistant: ```c
void version() {
  printf(((const char *)("powertop version %s\n")), "1.11-1");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L1
  movl   $0x2a,-0x8(%rbp)
  jmp    L11
L1:
  movl   $0x7,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x;
  int r = rand();
  if (!(0 > r)) {
    x = 42;
  } else {
    x = 7;
  }
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  sar    $0x1f,%eax
  and    $0xffffffdd,%eax
  add    $0x2a,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x;
  int r = rand();
  if (!(0 > r)) {
    x = 42;
  } else {
    x = 7;
  }
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  sar    $0x1f,%eax
  and    $0xffffffdd,%eax
  add    $0x2a,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x;
  int r = rand();
  if (!(0 > r)) {
    x = 42;
  } else {
    x = 7;
  }
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rdx,%r15
  mov    %ecx,%r13d
  mov    %r8d,%ebp
  mov    %r9d,%r14d
  mov    %ecx,%edi
  call   <KeySchedule@plt>
  cmp    $0x2eec0,%r13d
  je     L53
  jg     L138
  cmp    $0x1f4c0,%r13d
  je     L17
  jle    L218
  cmp    $0x1f500,%r13d
  je     L84
  cmp    $0x2ee80,%r13d
  jne    L0
  mov    $0x2,%r14d
  mov    $0x4,%ebp
L217:
  mov    $0x0,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <AddRoundKey@plt>
  add    $0x9,%r14d
L33:
  mov    $0x1,%ebx
L109:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <ByteSub_ShiftRow@plt>
  mov    %ebx,%ecx
  mov    %r15,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <MixColumn_AddRoundKey@plt>
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jle    L109
L93:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <ByteSub_ShiftRow@plt>
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <AddRoundKey@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L218:
  cmp    $0x1f480,%r13d
  jne    L0
  mov    $0x0,%r14d
  mov    $0x4,%ebp
  jmp    L217
L138:
  cmp    $0x3e8c0,%r13d
  je     L4
  jle    L221
  cmp    $0x3e900,%r13d
  jne    L0
  mov    $0x4,%r14d
  mov    $0x8,%ebp
  jmp    L217
L221:
  cmp    $0x2ef00,%r13d
  je     L32
  cmp    $0x3e880,%r13d
  jne    L0
  mov    $0x4,%r14d
  mov    $0x4,%ebp
  jmp    L217
L0:
  mov    $0x0,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <AddRoundKey@plt>
  add    $0x9,%r14d
  mov    $0x1,%ebx
  test   %r14d,%r14d
  jle    L93
  jmp    L33
L53:
  mov    $0x2,%r14d
  mov    $0x6,%ebp
  jmp    L217
L17:
  mov    $0x2,%r14d
  mov    $0x6,%ebp
  jmp    L217
L84:
  mov    $0x4,%r14d
  mov    $0x8,%ebp
  jmp    L217
L4:
  mov    $0x4,%r14d
  mov    $0x6,%ebp
  jmp    L217
L32:
  mov    $0x4,%r14d
  mov    $0x8,%ebp
  jmp    L217
```

assistant: ```c
int encrypt(int statemt[32], int key[32], int word[4][120], int type, int nb, int round) {
  int i;
  KeySchedule(type, key, word);
  switch (type) {
  case 128128:
    round = 0;
    nb = 4;
    break;
  case 192128:
    round = 2;
    nb = 4;
    break;
  case 256128:
    round = 4;
    nb = 4;
    break;
  case 128192:
  case 192192:
    round = 2;
    nb = 6;
    break;
  case 256192:
    round = 4;
    nb = 6;
    break;
  case 128256:
  case 192256:
  case 256256:
    round = 4;
    nb = 8;
    break;
  }
#pragma unroll
  AddRoundKey(statemt, word, type, 0);
  for (i = 1; i <= round + 9; ++i) {
    ByteSub_ShiftRow(statemt, nb);
    MixColumn_AddRoundKey(statemt, nb, word, i);
  }
  ByteSub_ShiftRow(statemt, nb);
  AddRoundKey(statemt, word, type, i);
  return 0;
}
```