ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_read>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L23:
  add    %eax,%ebx
  cmp    %ebp,%ebx
  je     L29
L16:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %r12,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L23
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int do_read(int fd, unsigned char *buffer, int size) {
  int n, from = 0;
  while (1) {
    n = read(fd, &buffer[from], size - from);
    if (n <= 0)
      return -1;
    if (n + from == size)
      return 0;
    from += n;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<analyze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <analyze_utf@plt>
  nop
  leave
  ret
```

assistant: ```c
void analyze(FILE *infile, long offset, long file_length) {
  int indent = 0;
  analyze_utf(infile, offset, indent, 1, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<analyze>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  call   <analyze_utf@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void analyze(FILE *infile, long offset, long file_length) {
  int indent = 0;
  analyze_utf(infile, offset, indent, 1, NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<analyze>:
  endbr64
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  xor    %edx,%edx
  jmp    1050 <analyze_utf@plt>
```

assistant: ```c
void analyze(FILE *infile, long offset, long file_length) {
  int indent = 0;
  analyze_utf(infile, offset, indent, 1, NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<analyze>:
  endbr64
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  xor    %edx,%edx
  jmp    1050 <analyze_utf@plt>
```

assistant: ```c
void analyze(FILE *infile, long offset, long file_length) {
  int indent = 0;
  analyze_utf(infile, offset, indent, 1, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_from_stdin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20020(%rbp)
  movl   $0x0,-0x2001c(%rbp)
  jmp    L8
L38:
  mov    -0x20020(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x20018(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20020(%rbp),%eax
  and    $0xfffffffe,%eax
  cltq
  lea    -0x20010(%rbp),%rcx
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <convert_to_phi@plt>
  mov    -0x20018(%rbp),%eax
  add    %eax,-0x20020(%rbp)
  mov    -0x20020(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  mov    -0x2001c(%rbp),%edx
  lea    -0x20010(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <process_buffer@plt>
  mov    %eax,-0x20014(%rbp)
  mov    -0x20014(%rbp),%eax
  add    %eax,%eax
  sub    %eax,-0x20020(%rbp)
  mov    -0x20014(%rbp),%eax
  add    %eax,-0x2001c(%rbp)
  cmpl   $0x0,-0x20020(%rbp)
  jle    L8
  mov    -0x20014(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    -0x20010(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20020(%rbp),%edx
  lea    -0x20010(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L8:
  mov    -0x20020(%rbp),%edx
  mov    $0x20000,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x20020(%rbp),%eax
  cltq
  lea    -0x20010(%rbp),%rcx
  add    %rcx,%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x20018(%rbp)
  cmpl   $0x0,-0x20018(%rbp)
  jg     L38
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
void read_from_stdin(void) {
  char buffer[65536 * 2];
  int n;
  int used = 0;
  uint64_t offset = 0;
  while ((n = read(0, buffer + used, sizeof(buffer) - used)) > 0) {
    int processed;
    convert_to_phi((uint16_t *)(buffer + (used & ~1)), ((used & 1) + n) / 2);
    used += n;
    processed = process_buffer((uint16_t *)buffer, used / 2, offset);
    used -= processed * 2;
    offset += processed;
    if (used > 0) {
      memmove(buffer, buffer + processed * 2, used);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_from_stdin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L15:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L15
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  mov    $0x20000,%r14d
L19:
  mov    %r14d,%edx
  sub    %ebx,%edx
  movslq %ebx,%rax
  lea    (%rsp,%rax,1),%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L38
  mov    %ebx,%eax
  and    $0x1,%eax
  add    %ebp,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %rsp,%r13
  mov    %ebx,%edi
  and    $0xfffffffe,%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  call   <convert_to_phi@plt>
  add    %ebp,%ebx
  mov    %ebx,%esi
  shr    $0x1f,%esi
  add    %ebx,%esi
  sar    %esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <process_buffer@plt>
  lea    (%rax,%rax,1),%esi
  sub    %esi,%ebx
  add    %eax,%r12d
  test   %ebx,%ebx
  jle    L19
  mov    %rsp,%rdi
  movslq %esi,%rsi
  add    %r13,%rsi
  mov    %ebx,%edx
  call   <memmove@plt>
  jmp    L19
L38:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read_from_stdin(void) {
  char buffer[65536 * 2];
  int n;
  int used = 0;
  uint64_t offset = 0;
  while ((n = read(0, buffer + used, sizeof(buffer) - used)) > 0) {
    int processed;
    convert_to_phi((uint16_t *)(buffer + (used & ~1)), ((used & 1) + n) / 2);
    used += n;
    processed = process_buffer((uint16_t *)buffer, used / 2, offset);
    used -= processed * 2;
    offset += processed;
    if (used > 0) {
      memmove(buffer, buffer + processed * 2, used);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_from_stdin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L38:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L38
  sub    $0x10,%rsp
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  mov    $0x20000,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r13d,%edx
  movslq %r14d,%rsi
  xor    %edi,%edi
  sub    %r14d,%edx
  add    %rbp,%rsi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L15
  mov    %r14d,%esi
  mov    %r14d,%edi
  add    %ebx,%r14d
  and    $0x1,%esi
  and    $0xfffffffe,%edi
  add    %ebx,%esi
  movslq %edi,%rdi
  sar    %esi
  add    %rbp,%rdi
  call   <convert_to_phi@plt>
  mov    %r14d,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  shr    $0x1f,%esi
  add    %r14d,%esi
  sar    %esi
  call   <process_buffer@plt>
  lea    (%rax,%rax,1),%esi
  add    %eax,%r12d
  sub    %esi,%r14d
  test   %r14d,%r14d
  jle    L7
  movslq %esi,%rsi
  mov    %r14d,%edx
  mov    %rbp,%rdi
  add    %rbp,%rsi
  call   <memmove@plt>
  jmp    L7
  xchg   %ax,%ax
L15:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x20010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read_from_stdin(void) {
  char buffer[65536 * 2];
  int n;
  int used = 0;
  uint64_t offset = 0;
  while ((n = read(0, buffer + used, sizeof(buffer) - used)) > 0) {
    int processed;
    convert_to_phi((uint16_t *)(buffer + (used & ~1)), ((used & 1) + n) / 2);
    used += n;
    processed = process_buffer((uint16_t *)buffer, used / 2, offset);
    used -= processed * 2;
    offset += processed;
    if (used > 0) {
      memmove(buffer, buffer + processed * 2, used);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_from_stdin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L46:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L46
  sub    $0x10,%rsp
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  mov    $0x20000,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r13d,%edx
  movslq %r14d,%rsi
  xor    %edi,%edi
  sub    %r14d,%edx
  add    %rbp,%rsi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L25
  mov    %r14d,%esi
  mov    %r14d,%edi
  add    %ebx,%r14d
  and    $0x1,%esi
  and    $0xfffffffe,%edi
  add    %ebx,%esi
  movslq %edi,%rdi
  sar    %esi
  add    %rbp,%rdi
  call   <convert_to_phi@plt>
  mov    %r14d,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  shr    $0x1f,%esi
  add    %r14d,%esi
  sar    %esi
  call   <process_buffer@plt>
  lea    (%rax,%rax,1),%esi
  add    %eax,%r12d
  sub    %esi,%r14d
  test   %r14d,%r14d
  jle    L3
  movslq %esi,%rsi
  mov    %r14d,%edx
  mov    %rbp,%rdi
  add    %rbp,%rsi
  call   <memmove@plt>
  jmp    L3
  xchg   %ax,%ax
L25:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read_from_stdin(void) {
  char buffer[65536 * 2];
  int n;
  int used = 0;
  uint64_t offset = 0;
  while ((n = read(0, buffer + used, sizeof(buffer) - used)) > 0) {
    int processed;
    convert_to_phi((uint16_t *)(buffer + (used & ~1)), ((used & 1) + n) / 2);
    used += n;
    processed = process_buffer((uint16_t *)buffer, used / 2, offset);
    used -= processed * 2;
    offset += processed;
    if (used > 0) {
      memmove(buffer, buffer + processed * 2, used);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_dstring@plt>
  mov    $0x0,%eax
  call   <test_dlist@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_dstring();
  test_dlist();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_dstring@plt>
  mov    $0x0,%eax
  call   <test_dlist@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_dstring();
  test_dlist();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_dstring@plt>
  xor    %eax,%eax
  call   <test_dlist@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_dstring();
  test_dlist();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_dstring@plt>
  xor    %eax,%eax
  call   <test_dlist@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_dstring();
  test_dlist();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<systools_fileutils_get_temp_folder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *systools_fileutils_get_temp_folder() {
  char *result = strdup(P_tmpdir);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<systools_fileutils_get_temp_folder>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *systools_fileutils_get_temp_folder() {
  char *result = strdup(P_tmpdir);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<systools_fileutils_get_temp_folder>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <strdup@plt>
```

assistant: ```c
char *systools_fileutils_get_temp_folder() {
  char *result = strdup(P_tmpdir);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<systools_fileutils_get_temp_folder>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <strdup@plt>
```

assistant: ```c
char *systools_fileutils_get_temp_folder() {
  char *result = strdup(P_tmpdir);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rgdouMax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L7
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L33
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L23
L33:
  movsd  -0x8(%rbp),%xmm0
L23:
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double rgdouMax(const double *rgd, int len) {
  int i;
  double max = rgd[0];
  for (i = 1; i < len; ++i)
    max = (max < rgd[i]) ? rgd[i] : max;
  return max;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rgdouMax>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L15
  lea    0x8(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x10(%rdi,%rdx,8),%rdx
L11:
  movsd  (%rax),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L11
L15:
  ret
```

assistant: ```c
double rgdouMax(const double *rgd, int len) {
  int i;
  double max = rgd[0];
  for (i = 1; i < len; ++i)
    max = (max < rgd[i]) ? rgd[i] : max;
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<rgdouMax>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L16
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L17:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L17
L16:
  ret
```

assistant: ```c
double rgdouMax(const double *rgd, int len) {
  int i;
  double max = rgd[0];
  for (i = 1; i < len; ++i)
    max = (max < rgd[i]) ? rgd[i] : max;
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rgdouMax>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L3
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L6:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L6
L3:
  ret
```

assistant: ```c
double rgdouMax(const double *rgd, int len) {
  int i;
  double max = rgd[0];
  for (i = 1; i < len; ++i)
    max = (max < rgd[i]) ? rgd[i] : max;
  return max;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int a = 1;
  int b = 2;
  int c = 3;
  a = (b = c, -b, ~c, c = (b--), b > c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int a = 1;
  int b = 2;
  int c = 3;
  a = (b = c, -b, ~c, c = (b--), b > c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int a = 1;
  int b = 2;
  int c = 3;
  a = (b = c, -b, ~c, c = (b--), b > c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int a = 1;
  int b = 2;
  int c = 3;
  a = (b = c, -b, ~c, c = (b--), b > c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x4,-0x4(%rbp)
  jle    L2
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D7
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D19
type_guessed: string

tool: D13: 
Executar 5 viagens 

tool: D7: 
Viagem Completa!!!

tool: D17: 
Contador = %d

tool: D8: 
Fim do programa 

tool: D19: pause

assistant: ```c
int main() {
  int contador = 0;
  printf("\nExecutar 5 viagens ");
  do {
    printf("\nViagem Completa!!!");
    contador = contador + 1;
    printf("\nContador = %d", contador);
  } while (contador < 5);
  printf("\nFim do programa ");
  system("pause");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D46(%rip),%r12
  lea    D25(%rip),%rbp
L7:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L7
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D41
datatype: string
name: disassemble_data
arguments: tag: D46
datatype: string
name: disassemble_data
arguments: tag: D25
datatype: string
name: disassemble_data
arguments: tag: D29
datatype: string
name: disassemble_data
arguments: tag: D39
datatype: string

tool: D41: 
Executar 5 viagens 

tool: D46: 
Viagem Completa!!!

tool: D25: 
Contador = %d

tool: D29: 
Fim do programa 

tool: D39: pause

assistant: ```c
int main() {
  int contador = 0;
  printf("\nExecutar 5 viagens ");
  do {
    printf("\nViagem Completa!!!");
    contador = contador + 1;
    printf("\nContador = %d", contador);
  } while (contador < 5);
  printf("\nFim do programa ");
  system("pause");
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  lea    D9(%rip),%r12
  push   %rbp
  lea    D36(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <printf@plt>
L3:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L3
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <system@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D36
datatype: string
name: parse_data
arguments: tag: D47
datatype: string
name: parse_data
arguments: tag: D30
datatype: string

tool: D10: 
Executar 5 viagens 

tool: D9: 
Viagem Completa!!!

tool: D36: 
Contador = %d

tool: D47: 
Fim do programa 

tool: D30: pause

assistant: ```c
int main() {
  int contador = 0;
  printf("\nExecutar 5 viagens ");
  do {
    printf("\nViagem Completa!!!");
    contador = contador + 1;
    printf("\nContador = %d", contador);
  } while (contador < 5);
  printf("\nFim do programa ");
  system("pause");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  lea    D44(%rip),%r12
  push   %rbp
  lea    D46(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <printf@plt>
L0:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L0
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D49
type: string
name: extract_symbolic_data
arguments: label: D44
type: string
name: extract_symbolic_data
arguments: label: D46
type: string
name: extract_symbolic_data
arguments: label: D22
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D49: 
Executar 5 viagens 

tool: D44: 
Viagem Completa!!!

tool: D46: 
Contador = %d

tool: D22: 
Fim do programa 

tool: D3: pause

assistant: ```c
int main() {
  int contador = 0;
  printf("\nExecutar 5 viagens ");
  do {
    printf("\nViagem Completa!!!");
    contador = contador + 1;
    printf("\nContador = %d", contador);
  } while (contador < 5);
  printf("\nFim do programa ");
  system("pause");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<makeint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L12:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L9
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L12
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int makeint(char *p) {
  int val = 0;
  while ((*p >= '0') && (*p <= '9')) {
    val = 10 * val + (*p - '0');
    ++p;
  }
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<makeint>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L5
  mov    $0x0,%edx
L8:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L8
L13:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L13
```

assistant: ```c
int makeint(char *p) {
  int val = 0;
  while ((*p >= '0') && (*p <= '9')) {
    val = 10 * val + (*p - '0');
    ++p;
  }
  return val;
}
```