ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L130
  lea    0x1(%rdx),%edi
  cmp    $0x9,%edx
  jle    L141
  mov    %edi,%ecx
  movdqa D0(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D18(%rip),%xmm3
  shr    $0x2,%ecx
  nopl   0x0(%rax,%rax,1)
L10:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L10
  movdqa %xmm0,%xmm1
  mov    %edi,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  and    $0x3,%edi
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  je     L13
L117:
  lea    0x1(%rax),%ecx
  add    %eax,%esi
  cmp    %edx,%ecx
  jg     L13
  add    %ecx,%esi
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    %ecx,%esi
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    %ecx,%esi
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    %ecx,%esi
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    %ecx,%esi
  lea    0x6(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    %ecx,%esi
  lea    0x7(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    %ecx,%esi
  lea    0x8(%rax),%ecx
  cmp    %ecx,%edx
  jl     L13
  add    $0x9,%eax
  add    %ecx,%esi
  cmp    %eax,%edx
  jl     L13
  add    %eax,%esi
L13:
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L130:
  xor    %esi,%esi
  jmp    L13
L141:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L117
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D31
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D18
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D45
type_guessed: string

tool: D4: Enter n = 

tool: D31: %d

tool: {"D0": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D45: %d


assistant: ```c
int main() {
  int n, i = 0, s = 0;
  printf("Enter n = ");
  scanf("%d", &n);
  while (i <= n) {
    s = s + i;
    i++;
  }
  printf("%d\n", s);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<PWMOutputInvert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L12
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    (%rdx),%rcx
  add    $0xc,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  or     %rcx,%rax
  mov    %rax,(%rdx)
  jmp    L0
L12:
  mov    -0x10(%rbp),%rax
  not    %rax
  mov    %rax,%rsi
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    (%rdx),%rcx
  add    $0xc,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  and    %rcx,%rax
  mov    %rax,(%rdx)
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PWMOutputInvert(uint32_t ui32Base, uint32_t ui32PWMOutBits, bool bInvert) {
  ;

  ;
  if (bInvert == 1) {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) |= ui32PWMOutBits;
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32PWMOutBits);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PWMOutputInvert>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  cmp    $0x1,%edx
  je     L3
  mov    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdx
  mov    0xc(%rdx),%rcx
  not    %rax
  and    %rcx,%rax
  mov    %rax,0xc(%rdx)
  ret
L3:
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0xc(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0xc(%rdx)
  ret
```

assistant: ```c
void PWMOutputInvert(uint32_t ui32Base, uint32_t ui32PWMOutBits, bool bInvert) {
  ;

  ;
  if (bInvert == 1) {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) |= ui32PWMOutBits;
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32PWMOutBits);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PWMOutputInvert>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  cmp    $0x1,%edx
  je     L7
  mov    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdx
  mov    0xc(%rdx),%rcx
  not    %rax
  and    %rcx,%rax
  mov    %rax,0xc(%rdx)
  ret
  nopl   0x0(%rax)
L7:
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0xc(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0xc(%rdx)
  ret
```

assistant: ```c
void PWMOutputInvert(uint32_t ui32Base, uint32_t ui32PWMOutBits, bool bInvert) {
  ;

  ;
  if (bInvert == 1) {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) |= ui32PWMOutBits;
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32PWMOutBits);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PWMOutputInvert>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  cmp    $0x1,%edx
  je     L6
  mov    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdx
  mov    0xc(%rdx),%rcx
  not    %rax
  and    %rcx,%rax
  mov    %rax,0xc(%rdx)
  ret
  nopl   0x0(%rax)
L6:
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0xc(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0xc(%rdx)
  ret
```

assistant: ```c
void PWMOutputInvert(uint32_t ui32Base, uint32_t ui32PWMOutBits, bool bInvert) {
  ;

  ;
  if (bInvert == 1) {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) |= ui32PWMOutBits;
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32PWMOutBits);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    -0x10(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%edi
  call   <uitoa@plt>
  add    $0x1,%rax
  jmp    L16
L17:
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <uitoa@plt>
L16:
  leave
  ret
```

assistant: ```c
size_t itoa(int nb, char *nb_str, unsigned int base) {
  if (nb < 0) {
    *nb_str = '-';
    return 1 + uitoa(nb * -1, nb_str + 1, base);
  }
  return uitoa(nb, nb_str, base);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<itoa>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L1
  call   <uitoa@plt>
L17:
  add    $0x8,%rsp
  ret
L1:
  movb   $0x2d,(%rsi)
  add    $0x1,%rsi
  neg    %edi
  call   <uitoa@plt>
  add    $0x1,%rax
  jmp    L17
```

assistant: ```c
size_t itoa(int nb, char *nb_str, unsigned int base) {
  if (nb < 0) {
    *nb_str = '-';
    return 1 + uitoa(nb * -1, nb_str + 1, base);
  }
  return uitoa(nb, nb_str, base);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  test   %edi,%edi
  js     L4
  jmp    1050 <uitoa@plt>
  nopl   (%rax)
L4:
  sub    $0x8,%rsp
  movb   $0x2d,(%rsi)
  neg    %edi
  add    $0x1,%rsi
  call   <uitoa@plt>
  add    $0x8,%rsp
  add    $0x1,%rax
  ret
```

assistant: ```c
size_t itoa(int nb, char *nb_str, unsigned int base) {
  if (nb < 0) {
    *nb_str = '-';
    return 1 + uitoa(nb * -1, nb_str + 1, base);
  }
  return uitoa(nb, nb_str, base);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  test   %edi,%edi
  js     L2
  jmp    1050 <uitoa@plt>
  nopl   (%rax)
L2:
  sub    $0x8,%rsp
  movb   $0x2d,(%rsi)
  neg    %edi
  add    $0x1,%rsi
  call   <uitoa@plt>
  add    $0x8,%rsp
  add    $0x1,%rax
  ret
```

assistant: ```c
size_t itoa(int nb, char *nb_str, unsigned int base) {
  if (nb < 0) {
    *nb_str = '-';
    return 1 + uitoa(nb * -1, nb_str + 1, base);
  }
  return uitoa(nb, nb_str, base);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L9:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_swap@plt>
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x8(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_strrev(char *str) {
  char *end;
  end = str + ft_strlen(str) - 1;
  while (str < end) {
    ft_swap(str, end);
    str++;
    end--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_strrev>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L14
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <ft_swap@plt>
  add    $0x1,%rbx
  sub    $0x1,%rbp
  cmp    %rbp,%rbx
  jb     L19
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_strrev(char *str) {
  char *end;
  end = str + ft_strlen(str) - 1;
  while (str < end) {
    ft_swap(str, end);
    str++;
    end--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strrev>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L16
  xchg   %ax,%ax
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  sub    $0x1,%rbp
  add    $0x1,%rbx
  call   <ft_swap@plt>
  cmp    %rbp,%rbx
  jb     L19
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_strrev(char *str) {
  char *end;
  end = str + ft_strlen(str) - 1;
  while (str < end) {
    ft_swap(str, end);
    str++;
    end--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strrev>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L16
  xchg   %ax,%ax
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  sub    $0x1,%rbp
  add    $0x1,%rbx
  call   <ft_swap@plt>
  cmp    %rbp,%rbx
  jb     L15
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_strrev(char *str) {
  char *end;
  end = str + ft_strlen(str) - 1;
  while (str < end) {
    ft_swap(str, end);
    str++;
    end--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L35
L2:
  movb   $0x0,-0xb(%rbp)
  jmp    L54
L66:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  movzbl -0xb(%rbp),%edx
  movzbl -0xa(%rbp),%ecx
  sub    %ecx,%edx
  cmp    %edx,%eax
  je     L68
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0x9(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L40
L68:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L40:
  movzbl -0xb(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb(%rbp)
L54:
  cmpb   $0x0,-0xb(%rbp)
  je     L66
  addb   $0x2,-0xa(%rbp)
L35:
  cmpb   $0x0,-0xa(%rbp)
  je     L2
  movzbl -0x9(%rbp),%eax
  mov    $0x4e,%edx
  imul   %edx,%eax
  lea    0x7(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] += state[local2];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 787080526UL + (unsigned char)7;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  lea    (%rax,%rax,1),%edx
  test   %al,%al
  cmovne %edx,%eax
  mov    $0x4e,%edx
  imul   %edx,%eax
  add    $0x7,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] += state[local2];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 787080526UL + (unsigned char)7;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffff9c,%edx
  sub    $0x6a,%eax
  imul   %edx,%eax
  add    $0x7,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] += state[local2];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 787080526UL + (unsigned char)7;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffff9c,%edx
  sub    $0x6a,%eax
  imul   %edx,%eax
  add    $0x7,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] += state[local2];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 787080526UL + (unsigned char)7;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_ensure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_exit_errno@plt>
L8:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _ensure(int line, int retval) {
  if (retval == -1)
    _exit_errno(line);
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ensure>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0xffffffff,%esi
  je     L8
L7:
  mov    %ebx,%eax
  pop    %rbx
  ret
L8:
  call   <_exit_errno@plt>
  jmp    L7
```

assistant: ```c
int _ensure(int line, int retval) {
  if (retval == -1)
    _exit_errno(line);
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ensure>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  cmp    $0xffffffff,%esi
  je     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  call   <_exit_errno@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int _ensure(int line, int retval) {
  if (retval == -1)
    _exit_errno(line);
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_ensure>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  cmp    $0xffffffff,%esi
  je     L0
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  call   <_exit_errno@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int _ensure(int line, int retval) {
  if (retval == -1)
    _exit_errno(line);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_fork_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2a,%edi
  call   <exit@plt>
  jmp    L8
L0:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <WIFEXITED@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <WEXITSTATUS@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2a,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L8:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string

tool: D26: This is child, my pid is %d!


tool: D10: This is parent, my pid is %d, I was told child is %d!


tool: D28: Child exit status is %d, exit code %d.


assistant: ```c
int test_fork_wait(void) {
  int n = fork();
  if (n == 0) {
    printf("This is child, my pid is %d!\n", getpid());
    exit(42);
  } else {
    printf("This is parent, my pid is %d, I was told child is %d!\n", getpid(), n);
    int status, exitcode;
    int p = wait(&status);
    assert(WIFEXITED(status));
    exitcode = WEXITSTATUS(status);
    printf("Child exit status is %d, exit code %d.\n", status, exitcode);
    assert(exitcode == 42);
    assert(p == n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_fork_wait>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2a,%edi
  call   <exit@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    %eax,%r12d
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%edi
  call   <WEXITSTATUS@plt>
  mov    %eax,%ebp
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x2a,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r12d,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L20
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D4: This is child, my pid is %d!


tool: D28: This is parent, my pid is %d, I was told child is %d!


tool: D14: Child exit status is %d, exit code %d.


assistant: ```c
int test_fork_wait(void) {
  int n = fork();
  if (n == 0) {
    printf("This is child, my pid is %d!\n", getpid());
    exit(42);
  } else {
    printf("This is parent, my pid is %d, I was told child is %d!\n", getpid(), n);
    int status, exitcode;
    int p = wait(&status);
    assert(WIFEXITED(status));
    exitcode = WEXITSTATUS(status);
    printf("Child exit status is %d, exit code %d.\n", status, exitcode);
    assert(exitcode == 42);
    assert(p == n);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_fork_wait>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %eax,%eax
  jne    L20
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2a,%edi
  call   <exit@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L20:
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%r12d
  call   <WIFEXITED@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%edi
  call   <WEXITSTATUS@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  mov    %eax,%edx
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  cmp    $0x2a,%ebp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12d,%ebx
  sete   %dil
  call   <assert@plt>
  jmp    L12
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string

tool: D3: This is child, my pid is %d!


tool: D20: This is parent, my pid is %d, I was told child is %d!


tool: D27: Child exit status is %d, exit code %d.


assistant: ```c
int test_fork_wait(void) {
  int n = fork();
  if (n == 0) {
    printf("This is child, my pid is %d!\n", getpid());
    exit(42);
  } else {
    printf("This is parent, my pid is %d, I was told child is %d!\n", getpid(), n);
    int status, exitcode;
    int p = wait(&status);
    assert(WIFEXITED(status));
    exitcode = WEXITSTATUS(status);
    printf("Child exit status is %d, exit code %d.\n", status, exitcode);
    assert(exitcode == 42);
    assert(p == n);
  }
  return 0;
}
```