ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L16
  lea    D5(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  ret
L16:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string

tool: D1: Digite um numero: 

tool: D0: %d

tool: D5: Mensagem um.


tool: D28: Mensagem dois.


assistant: ```c
void main() {
  int num;
  printf("Digite um numero: ");
  scanf("%d", &num);
  if (num)
    printf("Mensagem um.\n");
  else
    printf("Mensagem dois.\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rBve99009253050923_br_find_etc_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <rBve99009253050923_br_find_prefix@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L11
  cmpq   $0x0,-0x18(%rbp)
  je     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L38
L17:
  mov    $0x0,%eax
  jmp    L38
L11:
  mov    -0x10(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L38:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: etc

assistant: ```c
char *rBve99009253050923_br_find_etc_dir(const char *default_etc_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_etc_dir != (const char *)((char *)0))
      return strdup(default_etc_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "etc");
  free(prefix);
  return dir;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rBve99009253050923_br_find_etc_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <rBve99009253050923_br_find_prefix@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rbx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <free@plt>
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %rbp,%r12
  test   %rbp,%rbp
  je     L18
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: etc

assistant: ```c
char *rBve99009253050923_br_find_etc_dir(const char *default_etc_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_etc_dir != (const char *)((char *)0))
      return strdup(default_etc_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "etc");
  free(prefix);
  return dir;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rBve99009253050923_br_find_etc_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <rBve99009253050923_br_find_prefix@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  test   %r12,%r12
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: etc

assistant: ```c
char *rBve99009253050923_br_find_etc_dir(const char *default_etc_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_etc_dir != (const char *)((char *)0))
      return strdup(default_etc_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "etc");
  free(prefix);
  return dir;
}
```
user: What is the c source code of the assembly code below:

```asm
<rBve99009253050923_br_find_etc_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <rBve99009253050923_br_find_prefix@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbp
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  test   %r12,%r12
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: etc

assistant: ```c
char *rBve99009253050923_br_find_etc_dir(const char *default_etc_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_etc_dir != (const char *)((char *)0))
      return strdup(default_etc_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "etc");
  free(prefix);
  return dir;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L15:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *a) {
  int ans = 0;
  while (*a++)
    ans++;
  return ans;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L4
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L19:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L19
L26:
  mov    %ecx,%eax
  ret
L4:
  mov    $0x0,%ecx
  jmp    L26
```

assistant: ```c
int strlen(const char *a) {
  int ans = 0;
  while (*a++)
    ans++;
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L13
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L0:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L0
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *a) {
  int ans = 0;
  while (*a++)
    ans++;
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L0
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L3:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *a) {
  int ans = 0;
  while (*a++)
    ans++;
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_transposition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L53
L39:
  mov    -0x2c(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L53:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L39
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L10:
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **matrix_transposition(double **mat, int mat_row, int mat_col) {
  double **transpo = (double **)calloc(mat_col, sizeof(double *));
  for (int i = 0; i < mat_col; i++)
    transpo[i] = (double *)calloc(mat_row, sizeof(double));
  for (int i = 0; i < mat_col; i++)
    for (int j = 0; j < mat_row; j++)
      transpo[i][j] = mat[j][i];
  return transpo;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_transposition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    $0x8,%esi
  mov    %edx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L34
  mov    %r14d,%eax
  lea    (%r12,%rax,8),%r15
  mov    %r12,%r13
L40:
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%r13)
  add    $0x8,%r13
  cmp    %r15,%r13
  jne    L40
  mov    %r14d,%r8d
  shl    $0x3,%r8
  lea    -0x1(%rbp),%eax
  lea    0x8(,%rax,8),%rdi
  mov    $0x0,%ecx
  jmp    L65
L20:
  mov    (%rbx,%rax,1),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mov    (%rsi),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rdi
  jne    L20
L63:
  add    $0x8,%rcx
  cmp    %r8,%rcx
  je     L34
L65:
  lea    (%rcx,%r12,1),%rsi
  mov    $0x0,%eax
  test   %ebp,%ebp
  jg     L20
  jmp    L63
L34:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **matrix_transposition(double **mat, int mat_row, int mat_col) {
  double **transpo = (double **)calloc(mat_col, sizeof(double *));
  for (int i = 0; i < mat_col; i++)
    transpo[i] = (double *)calloc(mat_row, sizeof(double));
  for (int i = 0; i < mat_col; i++)
    for (int j = 0; j < mat_row; j++)
      transpo[i][j] = mat[j][i];
  return transpo;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<matrix_transposition>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14d,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L47
  lea    (%rax,%r14,8),%r15
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L36:
  mov    $0x8,%esi
  mov    %r13d,%edi
  add    $0x8,%rbp
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r15,%rbp
  jne    L36
  shl    $0x3,%r14
  xor    %ecx,%ecx
  movslq %r13d,%rdi
  nopl   0x0(%rax,%rax,1)
L5:
  test   %r13d,%r13d
  jle    L26
  mov    (%r12,%rcx,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L0
L26:
  add    $0x8,%rcx
  cmp    %r14,%rcx
  jne    L5
L47:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **matrix_transposition(double **mat, int mat_row, int mat_col) {
  double **transpo = (double **)calloc(mat_col, sizeof(double *));
  for (int i = 0; i < mat_col; i++)
    transpo[i] = (double *)calloc(mat_row, sizeof(double));
  for (int i = 0; i < mat_col; i++)
    for (int j = 0; j < mat_row; j++)
      transpo[i][j] = mat[j][i];
  return transpo;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_transposition>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14d,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L15
  lea    (%rax,%r14,8),%r15
  mov    %rax,%r13
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    $0x8,%esi
  mov    %ebx,%edi
  add    $0x8,%r13
  call   <calloc@plt>
  mov    %rax,-0x8(%r13)
  cmp    %r15,%r13
  jne    L22
  test   %ebx,%ebx
  jle    L15
  shl    $0x3,%r14
  xor    %ecx,%ecx
  movslq %ebx,%rsi
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    (%r12,%rcx,1),%rdi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L29
  add    $0x8,%rcx
  cmp    %rcx,%r14
  jne    L35
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **matrix_transposition(double **mat, int mat_row, int mat_col) {
  double **transpo = (double **)calloc(mat_col, sizeof(double *));
  for (int i = 0; i < mat_col; i++)
    transpo[i] = (double *)calloc(mat_row, sizeof(double));
  for (int i = 0; i < mat_col; i++)
    for (int j = 0; j < mat_row; j++)
      transpo[i][j] = mat[j][i];
  return transpo;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strmnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    -0x1c(%rbp),%eax
  jmp    L30
L37:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L31
L20:
  addl   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L12
L31:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x1c(%rbp)
L47:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L54
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L37
L54:
  mov    -0x14(%rbp),%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int strmnstr(char *buf, char *sub, int len) {
  char *bp;
  char *sp;
  int i;
  int j;
  int k;
  i = 0;
  if (!*sub) {
    return i;
  }
  while (*buf && (i < len)) {
    bp = buf;
    sp = sub;
    j = 0;
    do {
      if (!*sp) {
        k = (i + j);
        break;
      }
      j++;
    } while (*bp++ == *sp++);
    buf++;
    i++;
  }
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strmnstr>:
  endbr64
  movzbl (%rsi),%r10d
  mov    $0x0,%r11d
  test   %r10b,%r10b
  je     L74
  cmpb   $0x0,(%rdi)
  je     L74
  test   %edx,%edx
  jle    L74
  mov    $0x0,%r9d
  jmp    L18
L50:
  add    $0x1,%rdi
  add    $0x1,%r9d
  cmpb   $0x0,(%rdi)
  je     L74
  cmp    %r9d,%edx
  jle    L74
L18:
  mov    %r10d,%ecx
  mov    $0x0,%eax
L6:
  lea    0x1(%rax),%r8d
  cmp    %cl,(%rdi,%rax,1)
  jne    L50
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L6
  lea    (%r9,%r8,1),%r11d
  jmp    L50
L74:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int strmnstr(char *buf, char *sub, int len) {
  char *bp;
  char *sp;
  int i;
  int j;
  int k;
  i = 0;
  if (!*sub) {
    return i;
  }
  while (*buf && (i < len)) {
    bp = buf;
    sp = sub;
    j = 0;
    do {
      if (!*sp) {
        k = (i + j);
        break;
      }
      j++;
    } while (*bp++ == *sp++);
    buf++;
    i++;
  }
  return k;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strmnstr>:
  endbr64
  movzbl (%rsi),%r11d
  push   %r12
  xor    %r12d,%r12d
  test   %r11b,%r11b
  je     L41
  movzbl (%rdi),%r8d
  test   %edx,%edx
  jle    L41
  test   %r8b,%r8b
  je     L41
  xor    %r10d,%r10d
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %r11d,%ecx
  mov    $0x1,%eax
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rdi,%rax,1),%r8d
  add    $0x1,%rax
L59:
  mov    %eax,%r9d
  cmp    %r8b,%cl
  jne    L36
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L19
  lea    (%r9,%r10,1),%r12d
L36:
  add    $0x1,%r10d
  add    $0x1,%rdi
  movzbl (%rdi),%r8d
  cmp    %r10d,%edx
  jle    L41
  test   %r8b,%r8b
  jne    L65
L41:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int strmnstr(char *buf, char *sub, int len) {
  char *bp;
  char *sp;
  int i;
  int j;
  int k;
  i = 0;
  if (!*sub) {
    return i;
  }
  while (*buf && (i < len)) {
    bp = buf;
    sp = sub;
    j = 0;
    do {
      if (!*sp) {
        k = (i + j);
        break;
      }
      j++;
    } while (*bp++ == *sp++);
    buf++;
    i++;
  }
  return k;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strmnstr>:
  endbr64
  movzbl (%rsi),%r10d
  xor    %r11d,%r11d
  test   %r10b,%r10b
  je     L64
  cmpb   $0x0,(%rdi)
  je     L64
  test   %edx,%edx
  jle    L64
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L13:
  mov    %r10d,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L69:
  lea    0x1(%rax),%r8d
  cmp    %cl,(%rdi,%rax,1)
  jne    L67
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L69
  lea    (%r8,%r9,1),%r11d
L67:
  add    $0x1,%rdi
  add    $0x1,%r9d
  cmpb   $0x0,(%rdi)
  je     L64
  cmp    %r9d,%edx
  jg     L13
L64:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int strmnstr(char *buf, char *sub, int len) {
  char *bp;
  char *sp;
  int i;
  int j;
  int k;
  i = 0;
  if (!*sub) {
    return i;
  }
  while (*buf && (i < len)) {
    bp = buf;
    sp = sub;
    j = 0;
    do {
      if (!*sp) {
        k = (i + j);
        break;
      }
      j++;
    } while (*bp++ == *sp++);
    buf++;
    i++;
  }
  return k;
}
```
user: Translate the below assembly code into C programming language:

```asm
<host_word_parity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L0:
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  xor    %eax,-0x8(%rbp)
  sarl   $0x5,-0x14(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: byte[4]

tool: {"D8": [0x96,0x69,0x69,0x96]}

assistant: ```c
uint32_t host_word_parity(uint32_t w) {
  static const uint32_t p32 = 0x96696996;
  uint32_t parity = 0;
  while (w) {
    uint8_t bits = w & 037;
    parity ^= (p32 >> bits) & 1;
    w >>= 5;
  }
  return parity;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<host_word_parity>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  je     L22
  mov    $0x0,%edx
  mov    $0x96696996,%esi
L26:
  mov    %esi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  xor    %eax,%edx
  sar    $0x5,%ecx
  jne    L26
L24:
  mov    %edx,%eax
  ret
L22:
  mov    %edi,%edx
  jmp    L24
```

assistant: ```c
uint32_t host_word_parity(uint32_t w) {
  static const uint32_t p32 = 0x96696996;
  uint32_t parity = 0;
  while (w) {
    uint8_t bits = w & 037;
    parity ^= (p32 >> bits) & 1;
    w >>= 5;
  }
  return parity;
}
```
user: Translate the below assembly code into C programming language:

```asm
<host_word_parity>:
  endbr64
  mov    %edi,%ecx
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L14
  mov    $0x96696996,%edx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  xor    %eax,%r8d
  sar    $0x5,%ecx
  jne    L19
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t host_word_parity(uint32_t w) {
  static const uint32_t p32 = 0x96696996;
  uint32_t parity = 0;
  while (w) {
    uint8_t bits = w & 037;
    parity ^= (p32 >> bits) & 1;
    w >>= 5;
  }
  return parity;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<host_word_parity>:
  endbr64
  mov    %edi,%ecx
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L1
  mov    $0x96696996,%edx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  xor    %eax,%r8d
  sar    $0x5,%ecx
  jne    L6
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t host_word_parity(uint32_t w) {
  static const uint32_t p32 = 0x96696996;
  uint32_t parity = 0;
  while (w) {
    uint8_t bits = w & 037;
    parity ^= (p32 >> bits) & 1;
    w >>= 5;
  }
  return parity;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L19
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L19:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <my_readdir@plt>
  test   %rax,%rax
  jns    L0
  mov    $0x1,%edi
  call   <exit@plt>
L0:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: usage: %s <target path>


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("usage: %s <target path>\n", argv[0]);
    exit(1);
  }
  if (my_readdir(argv[1]) < 0) {
    exit(1);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L38
L18:
  mov    0x8(%rbx),%rdi
  call   <my_readdir@plt>
  test   %rax,%rax
  js     L26
L24:
  mov    $0x0,%eax
  pop    %rbx
  ret
L38:
  mov    (%rsi),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L26:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: usage: %s <target path>


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("usage: %s <target path>\n", argv[0]);
    exit(1);
  }
  if (my_readdir(argv[1]) < 0) {
    exit(1);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L22
L11:
  mov    0x8(%rbx),%rdi
  call   <my_readdir@plt>
  test   %rax,%rax
  js     L24
L26:
  xor    %eax,%eax
  pop    %rbx
  ret
L22:
  mov    (%rsi),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L11
L24:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: usage: %s <target path>


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("usage: %s <target path>\n", argv[0]);
    exit(1);
  }
  if (my_readdir(argv[1]) < 0) {
    exit(1);
  }
  return 0;
}
```