ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D43(%rip),%rdi
  lea    D35(%rip),%r12
  push   %rbp
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movl   $0x0,0x70(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm2
  movapd %xmm2,%xmm0
  jb     L31
  ja     L16
  lea    D13(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L32:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D15(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L32
L31:
  lea    D50(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L32
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D43
type: string
name: parse_data
arguments: tag: D35
type: string
name: parse_data
arguments: tag: D44
type: string
name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D50
type: string

tool: D43: 
Enter number 1 :

tool: D35: %s

tool: D44: 
Enter number 2 :

tool: D13: 
%g is equal to %g.


tool: D15: 
%g is greater than %g.


tool: D50: 
%g is less than %g.


assistant: ```c
int main() {
  double num1 = 0, num2 = 0;
  char str[100] = {'\0'};
  printf("\nEnter number 1 :");
  scanf("%s", str);
  num1 = atof(str);
  printf("\nEnter number 2 :");
  scanf("%s", str);
  num2 = atof(str);
  { ((num1) >= (num2)) ? (((num1) > (num2)) ? (printf("\n%g is greater than %g.\n", (num1), (num2))) : (printf("\n%g is equal to %g.\n", (num1), (num2)))) : (printf("\n%g is less than %g.\n", (num1), (num2))); };
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D25(%rip),%rdi
  lea    D48(%rip),%r12
  push   %rbp
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movl   $0x0,0x70(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm2
  movapd %xmm2,%xmm0
  jb     L2
  ja     L40
  lea    D8(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L43:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L40:
  lea    D44(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L43
L2:
  lea    D30(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L43
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
type_guessed: string
name: retrieve_data
arguments: tag: D48
type_guessed: string
name: retrieve_data
arguments: tag: D53
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D44
type_guessed: string
name: retrieve_data
arguments: tag: D30
type_guessed: string

tool: D25: 
Enter number 1 :

tool: D48: %s

tool: D53: 
Enter number 2 :

tool: D8: 
%g is equal to %g.


tool: D44: 
%g is greater than %g.


tool: D30: 
%g is less than %g.


assistant: ```c
int main() {
  double num1 = 0, num2 = 0;
  char str[100] = {'\0'};
  printf("\nEnter number 1 :");
  scanf("%s", str);
  num1 = atof(str);
  printf("\nEnter number 2 :");
  scanf("%s", str);
  num2 = atof(str);
  { ((num1) >= (num2)) ? (((num1) > (num2)) ? (printf("\n%g is greater than %g.\n", (num1), (num2))) : (printf("\n%g is equal to %g.\n", (num1), (num2)))) : (printf("\n%g is less than %g.\n", (num1), (num2))); };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  nop
L44:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L55
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L44
L55:
  movl   $0x0,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L1
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L54
L19:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L54:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L19
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getword(char *word, int maxlen) {
  int c;
  int i;
  while ((c = getchar()) != EOF && isspace(c) != 0) {
    ;
  }
  i = 0;
  if (c != EOF) {
    word[i++] = c;
    while ((c = getchar()) != EOF && isspace(c) == 0) {
      word[i++] = c;
    }
    word[i] = '\0';
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getword>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
L54:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D7(%rip),%rax
  cmp    %ebx,(%rax)
  je     L53
  mov    %ebx,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L54
  mov    D7(%rip),%rax
  cmp    %ebx,(%rax)
  je     L26
  mov    %bl,(%r12)
  mov    $0x1,%ebp
  jmp    L32
L12:
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L32:
  mov    %ebp,%r13d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D7(%rip),%rax
  cmp    %ebx,(%rax)
  je     L39
  mov    %ebx,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L12
L39:
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
L73:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  mov    $0x0,%r13d
  jmp    L73
L26:
  mov    $0x0,%r13d
  jmp    L73
```

assistant: ```c
int getword(char *word, int maxlen) {
  int c;
  int i;
  while ((c = getchar()) != EOF && isspace(c) != 0) {
    ;
  }
  i = 0;
  if (c != EOF) {
    word[i++] = c;
    while ((c = getchar()) != EOF && isspace(c) == 0) {
      word[i++] = c;
    }
    word[i] = '\0';
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getword>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    D1(%rip),%r12
  push   %rbp
  push   %rbx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L43
L30:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L15
L42:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  cmp    %ebx,(%r12)
  je     L42
  mov    %bl,0x0(%r13)
  lea    0x1(%r13),%rbp
  neg    %r13d
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
L26:
  xor    %eax,%eax
  lea    0x0(%r13,%rbp,1),%r14d
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L32
L68:
  movb   $0x0,0x0(%rbp)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getword(char *word, int maxlen) {
  int c;
  int i;
  while ((c = getchar()) != EOF && isspace(c) != 0) {
    ;
  }
  i = 0;
  if (c != EOF) {
    word[i++] = c;
    while ((c = getchar()) != EOF && isspace(c) == 0) {
      word[i++] = c;
    }
    word[i] = '\0';
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<getword>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    D5(%rip),%r12
  push   %rbp
  push   %rbx
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L57
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L47
L31:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    %ebx,(%r12)
  je     L31
  mov    %bl,0x0(%r13)
  lea    0x1(%r13),%rbp
  neg    %r13d
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
L68:
  xor    %eax,%eax
  lea    0x0(%r13,%rbp,1),%r14d
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L66
L28:
  movb   $0x0,0x0(%rbp)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getword(char *word, int maxlen) {
  int c;
  int i;
  while ((c = getchar()) != EOF && isspace(c) != 0) {
    ;
  }
  i = 0;
  if (c != EOF) {
    word[i++] = c;
    while ((c = getchar()) != EOF && isspace(c) == 0) {
      word[i++] = c;
    }
    word[i] = '\0';
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L61
  addq   $0x1,-0x18(%rbp)
  jmp    L42
L61:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L42
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi>
  neg    %eax
  jmp    L38
L52:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L32
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  movsbl -0x5(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,-0x4(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  jmp    L41
L32:
  nop
L41:
  mov    -0x4(%rbp),%eax
L38:
  leave
  ret
```

assistant: ```c
int atoi(const char *s) {
  int i;
  char c;
  i = 0;
  if (*s == '+')
    s++;
  else if (*s == '-')
    return -atoi(++s);
  while (*s) {
    c = *s++;
    if (isdigit(c)) {
      i = i * 10;
      i += c - '0';
    } else
      break;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L14
  cmp    $0x2d,%al
  je     L9
L12:
  movzbl 0x0(%rbp),%eax
  mov    $0x0,%r12d
  test   %al,%al
  je     L64
L43:
  add    $0x1,%rbp
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L64
  lea    (%r12,%r12,4),%eax
  lea    -0x30(%rbx,%rax,2),%r12d
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L43
L64:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  add    $0x1,%rbp
  jmp    L12
L9:
  lea    0x1(%rdi),%rdi
  call   <atoi>
  neg    %eax
  mov    %eax,%r12d
  jmp    L64
```

assistant: ```c
int atoi(const char *s) {
  int i;
  char c;
  i = 0;
  if (*s == '+')
    s++;
  else if (*s == '-')
    return -atoi(++s);
  while (*s) {
    c = *s++;
    if (isdigit(c)) {
      i = i * 10;
      i += c - '0';
    } else
      break;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atoi>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  jne    L66
  jmp    L97
L95:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  neg    %r13d
  cmp    $0x2b,%al
  je     L97
L66:
  cmp    $0x2d,%al
  je     L95
L89:
  movzbl (%rbx),%eax
  xor    %r12d,%r12d
  test   %al,%al
  jne    L38
  jmp    L72
  nop
L60:
  lea    (%r12,%r12,4),%eax
  lea    -0x30(%rbp,%rax,2),%r12d
  movzbl (%rbx),%eax
  test   %al,%al
  je     L68
L38:
  movsbl %al,%ebp
  add    $0x1,%rbx
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L60
L68:
  mov    %r12d,%eax
  imul   %r13d,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L97:
  add    $0x1,%rbx
  jmp    L89
L72:
  xor    %eax,%eax
  jmp    L18
```

assistant: ```c
int atoi(const char *s) {
  int i;
  char c;
  i = 0;
  if (*s == '+')
    s++;
  else if (*s == '-')
    return -atoi(++s);
  while (*s) {
    c = *s++;
    if (isdigit(c)) {
      i = i * 10;
      i += c - '0';
    } else
      break;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atoi>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  jne    L78
  jmp    L94
L18:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  neg    %r13d
  cmp    $0x2b,%al
  je     L94
L78:
  cmp    $0x2d,%al
  je     L18
L86:
  xor    %r12d,%r12d
  test   %al,%al
  jne    L21
  jmp    L23
  nopl   0x0(%rax)
L61:
  lea    (%r12,%r12,4),%eax
  lea    -0x30(%rbx,%rax,2),%r12d
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L63
L21:
  movsbl %al,%ebx
  add    $0x1,%rbp
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L61
L63:
  mov    %r12d,%eax
  imul   %r13d,%eax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L94:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  jmp    L86
L23:
  xor    %eax,%eax
  jmp    L28
```

assistant: ```c
int atoi(const char *s) {
  int i;
  char c;
  i = 0;
  if (*s == '+')
    s++;
  else if (*s == '-')
    return -atoi(++s);
  while (*s) {
    c = *s++;
    if (isdigit(c)) {
      i = i * 10;
      i += c - '0';
    } else
      break;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x5c(%rbp)
  jmp    L117
L126:
  mov    -0x5c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L62
L114:
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x5c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x58(%rbp)
L62:
  cmpl   $0x3,-0x58(%rbp)
  jle    L114
  addl   $0x1,-0x5c(%rbp)
L117:
  cmpl   $0x3,-0x5c(%rbp)
  jle    L126
  movl   $0x1,-0x5c(%rbp)
  jmp    L42
L122:
  movl   $0x0,-0x58(%rbp)
  jmp    L119
L109:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x5c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,-0x54(%rbp)
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  mov    -0x58(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x5c(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x50(%rbp,%rdx,4)
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x50(%rbp,%rdx,4)
  addl   $0x1,-0x58(%rbp)
L119:
  mov    -0x58(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L109
  addl   $0x1,-0x5c(%rbp)
L42:
  cmpl   $0x3,-0x5c(%rbp)
  jle    L122
  movl   $0x0,-0x5c(%rbp)
  jmp    L64
L107:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L22
L48:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x5c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x58(%rbp)
L22:
  cmpl   $0x3,-0x58(%rbp)
  jle    L48
  addl   $0x1,-0x5c(%rbp)
L64:
  cmpl   $0x3,-0x5c(%rbp)
  jle    L107
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D25: Vavedi red %d:


tool: D15: %d

tool: D13: %2d 

assistant: ```c
void main() {
  int x[4][4], a, b, y;
  for (a = 0; a < 4; a++) {
    printf("Vavedi red %d:\n", a + 1);
    for (b = 0; b < 4; b++)
      scanf("%d", &x[a][b]);
  }
  for (a = 1; a < 4; a++)
    for (b = 0; b < a; b++) {
      y = x[a][b];
      x[a][b] = x[b][a];
      x[b][a] = y;
    }
  for (a = 0; a < 4; a++) {
    printf("\n");
    for (b = 0; b < 4; b++)
      printf("%2d ", x[a][b]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rbp
  mov    %rbp,%r12
  mov    $0x0,%r14d
  lea    D16(%rip),%r15
  lea    D2(%rip),%r13
L12:
  add    $0x1,%r14d
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%r12),%rbx
L37:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L37
  add    $0x10,%r12
  cmp    $0x4,%r14d
  jne    L12
  lea    0x20(%rsp),%r10
  lea    0x14(%rsp),%r9
  mov    0x8(%rsp),%rax
  lea    0x14(%rax),%rdi
  mov    $0x1,%r8d
  jmp    L98
L19:
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  add    $0x4,%rdx
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L19
L40:
  add    $0x1,%r8d
  add    $0x10,%r10
  add    $0x4,%r9
  add    $0x14,%rdi
  cmp    $0x4,%r8d
  je     L5
L98:
  mov    %r9,%rax
  mov    %r10,%rdx
  test   %r8d,%r8d
  jg     L19
  jmp    L40
L5:
  mov    0x8(%rsp),%r13
  add    $0x50,%r13
  lea    D23(%rip),%r12
L80:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x10(%rbp),%rbx
L89:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L89
  add    $0x10,%rbp
  cmp    %r13,%rbp
  jne    L80
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D23
type_guessed: string

tool: D16: Vavedi red %d:


tool: D2: %d

tool: D23: %2d 

assistant: ```c
void main() {
  int x[4][4], a, b, y;
  for (a = 0; a < 4; a++) {
    printf("Vavedi red %d:\n", a + 1);
    for (b = 0; b < 4; b++)
      scanf("%d", &x[a][b]);
  }
  for (a = 1; a < 4; a++)
    for (b = 0; b < a; b++) {
      y = x[a][b];
      x[a][b] = x[b][a];
      x[b][a] = y;
    }
  for (a = 0; a < 4; a++) {
    printf("\n");
    for (b = 0; b < 4; b++)
      printf("%2d ", x[a][b]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,(%rsp)
  mov    %rax,%rbp
  mov    %rax,%rbx
L42:
  add    $0x1,%r13d
  mov    %r15,%rdi
  lea    -0x10(%rbp),%r14
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <printf@plt>
L15:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %rbp,%r14
  jne    L15
  lea    0x10(%r14),%rbp
  cmp    $0x4,%r13d
  jne    L42
  mov    0x8(%rsp),%rax
  mov    (%rsp),%r9
  lea    0x14(%rsp),%r8
  lea    0x14(%rax),%rdi
L13:
  mov    %r8,%rax
  mov    %r9,%rdx
L18:
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  add    $0x10,%rax
  add    $0x4,%rdx
  mov    %esi,-0x4(%rdx)
  mov    %ecx,-0x10(%rax)
  cmp    %rdi,%rax
  jne    L18
  add    $0x10,%r9
  add    $0x4,%r8
  lea    0x14(%rax),%rdi
  cmp    (%rsp),%r8
  jne    L13
  mov    0x8(%rsp),%r13
  lea    D12(%rip),%r12
  add    $0x50,%r13
L5:
  mov    $0xa,%edi
  lea    -0x10(%rbx),%rbp
  call   <putchar@plt>
L46:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L46
  lea    0x10(%rbp),%rbx
  cmp    %r13,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D16: Vavedi red %d:


tool: D28: %d

tool: D12: %2d 

assistant: ```c
void main() {
  int x[4][4], a, b, y;
  for (a = 0; a < 4; a++) {
    printf("Vavedi red %d:\n", a + 1);
    for (b = 0; b < 4; b++)
      scanf("%d", &x[a][b]);
  }
  for (a = 1; a < 4; a++)
    for (b = 0; b < a; b++) {
      y = x[a][b];
      x[a][b] = x[b][a];
      x[b][a] = y;
    }
  for (a = 0; a < 4; a++) {
    printf("\n");
    for (b = 0; b < 4; b++)
      printf("%2d ", x[a][b]);
  }
  printf("\n");
}
```