user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ILLutil_linked_radixsort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  movslq %ecx,%rax
  mov    %rdi,%r10
  sub    %rdi,%rsi
  mov    %fs:0x28,%rcx
  mov    %rcx,0x1018(%rsp)
  xor    %ecx,%ecx
  mov    %rdx,%rcx
  mov    %eax,%edx
  sub    %rdi,%rcx
  sub    $0x1,%edx
  js     L29
  pxor   %xmm4,%xmm4
  lea    0x10(%rsp),%r8
  movslq %edx,%rbx
  mov    %edx,%edx
  movdqa %xmm4,%xmm5
  lea    -0x2(%rcx,%rax,1),%r12
  movq   %r8,%xmm6
  xor    %eax,%eax
  movdqa D19(%rip),%xmm2
  mov    %rsi,%rbp
  add    %rcx,%rbx
  sub    %rdx,%r12
  movdqa D8(%rip),%xmm8
  movdqa D17(%rip),%xmm7
  lea    0x810(%rsp),%r9
  lea    0x1010(%rsp),%r11
  pcmpgtd %xmm2,%xmm5
  lea    0x8(%rsp),%r13
  punpcklqdq %xmm6,%xmm6
L31:
  mov    $0x100,%ecx
  mov    %r8,%rdi
  movdqa %xmm8,%xmm3
  mov    %r9,%rdx
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L56:
  movdqa %xmm3,%xmm0
  movdqa %xmm4,%xmm9
  paddd  %xmm7,%xmm3
  add    $0x20,%rdx
  movdqa %xmm0,%xmm1
  movdqa %xmm5,%xmm10
  punpckldq %xmm0,%xmm1
  punpckhdq %xmm0,%xmm0
  pcmpgtd %xmm1,%xmm9
  pmuludq %xmm1,%xmm10
  pmuludq %xmm2,%xmm1
  pmuludq %xmm2,%xmm9
  paddq  %xmm10,%xmm9
  psllq  $0x20,%xmm9
  paddq  %xmm9,%xmm1
  movdqa %xmm5,%xmm9
  paddq  %xmm6,%xmm1
  pmuludq %xmm0,%xmm9
  movaps %xmm1,-0x20(%rdx)
  movdqa %xmm4,%xmm1
  pcmpgtd %xmm0,%xmm1
  pmuludq %xmm2,%xmm0
  pmuludq %xmm2,%xmm1
  paddq  %xmm9,%xmm1
  psllq  $0x20,%xmm1
  paddq  %xmm1,%xmm0
  paddq  %xmm6,%xmm0
  movaps %xmm0,-0x10(%rdx)
  cmp    %r11,%rdx
  jne    L56
  test   %r10,%r10
  je     L1
  nopl   0x0(%rax,%rax,1)
L34:
  movzbl (%r10,%rbx,1),%edx
  mov    0x810(%rsp,%rdx,8),%rcx
  mov    %r10,(%rcx)
  add    %rbp,%r10
  mov    %r10,0x810(%rsp,%rdx,8)
  mov    (%r10),%r10
  test   %r10,%r10
  jne    L34
L1:
  xor    %edx,%edx
  mov    %r13,%rsi
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%r8,%rdx,1),%rcx
  test   %rcx,%rcx
  je     L5
  mov    %rcx,(%rsi)
  mov    (%r9,%rdx,1),%rsi
L5:
  add    $0x8,%rdx
  cmp    $0x800,%rdx
  jne    L4
  sub    $0x1,%rbx
  movq   $0x0,(%rsi)
  mov    0x8(%rsp),%r10
  cmp    %r12,%rbx
  jne    L31
L29:
  mov    0x1018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x1028,%rsp
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D8
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D17
data_type: byte[16]

tool: {"D19": [0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
char *ILLutil_linked_radixsort(char *data, char *datanext, char *dataval, int valsize) {
  size_t nextoff = datanext - data;
  size_t valoff = dataval - data;
  int i;
  char *head[(1 << (8))];
  char **tail[(1 << (8))];
  char *p;
  char **last;
  int j;
  int v;
  for (j = valsize - 1; j >= 0; j--) {
    for (i = 0; i < (1 << (8)); i++) {
      head[i] = (char *)NULL;
      tail[i] = &head[i];
    }
    for (p = data; p; p = *(char **)(p + nextoff)) {
      v = (unsigned char)p[valoff + j];
      *tail[v] = p;
      tail[v] = (char **)(p + nextoff);
    }
    last = &data;
    for (i = 0; i < (1 << (8)); i++) {
      if (head[i]) {
        *last = head[i];
        last = tail[i];
      }
    }
    *last = (char *)NULL;
  }
  return data;
}
```