ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jbe    L84
  lea    -0x1(%rax),%r15d
  test   %eax,%eax
  je     L21
  mov    $0x1,%ebp
  lea    D19(%rip),%r14
  lea    D28(%rip),%r13
  jmp    L40
L84:
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L113
L11:
  test   %ebp,%ebp
  jle    L51
L10:
  mov    $0x0,%ebx
L93:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jl     L93
L51:
  lea    D81(%rip),%rdi
  call   <printf@plt>
  test   %r15d,%r15d
  je     L76
L3:
  sub    $0x1,%r15d
  add    $0x2,%ebp
L40:
  mov    %r15d,%r12d
  mov    $0x0,%ebx
  test   %r15d,%r15d
  jle    L11
L105:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L105
  test   %ebp,%ebp
  jg     L10
  lea    D81(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L76:
  cmpl   $0x1,0x4(%rsp)
  jle    L21
  mov    $0x0,%ebx
  lea    D19(%rip),%rbp
L12:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L12
L21:
  lea    D28(%rip),%rdi
  call   <printf@plt>
L113:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L137
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L137:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D19
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string
name: unpack_data
arguments: label: D46
type_guessed: string
name: unpack_data
arguments: label: D81
type_guessed: string

tool: D37: 
Enter the size of tree


tool: D7: %d

tool: D19:  

tool: D28: *

tool: D46: cannot build a three

tool: D81: 


assistant: ```c
main() {
  int size, spaces, stars = 1;
  int i;
  printf("\nEnter the size of tree\n");
  scanf("%d", &size);
  spaces = size - 1;
  if (size == 0 || size == 1) {
    printf("cannot build a three");
  } else {
    while (spaces != -1) {
      for (i = 0; i < spaces; i++) {
        printf(" ");
      }
      for (i = 0; i < stars; i++) {
        printf("*");
      }
      printf("\n");
      stars = stars + 2;
      spaces = spaces - 1;
    }
    if (spaces == -1) {
      for (i = 0; i < size - 1; i++) {
        printf(" ");
      }
      printf("*");
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D25(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jbe    L23
  lea    -0x1(%rax),%ebp
  mov    $0x1,%r13d
  lea    D41(%rip),%r14
  lea    D22(%rip),%r15
  lea    D68(%rip),%r12
  test   %eax,%eax
  je     L76
  xchg   %ax,%ax
L93:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  jle    L28
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L9
L28:
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L58:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L58
  mov    %r15,%rdi
  lea    0x2(%rbx),%r13d
  call   <printf@plt>
  sub    $0x1,%ebp
  jae    L93
  cmpl   $0x1,0x4(%rsp)
  jle    L76
  xor    %ebx,%ebx
  lea    D68(%rip),%r12
  nopl   0x0(%rax)
L20:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L20
L76:
  mov    %r14,%rdi
  call   <printf@plt>
L71:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D41
type: string
name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D68
type: string
name: unpack_data
arguments: tag: D51
type: string

tool: D25: 
Enter the size of tree


tool: D14: %d

tool: D41: *

tool: D22: 


tool: D68:  

tool: D51: cannot build a three

assistant: ```c
main() {
  int size, spaces, stars = 1;
  int i;
  printf("\nEnter the size of tree\n");
  scanf("%d", &size);
  spaces = size - 1;
  if (size == 0 || size == 1) {
    printf("cannot build a three");
  } else {
    while (spaces != -1) {
      for (i = 0; i < spaces; i++) {
        printf(" ");
      }
      for (i = 0; i < stars; i++) {
        printf("*");
      }
      printf("\n");
      stars = stars + 2;
      spaces = spaces - 1;
    }
    if (spaces == -1) {
      for (i = 0; i < size - 1; i++) {
        printf(" ");
      }
      printf("*");
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jbe    L90
  lea    -0x1(%rax),%ebp
  mov    $0x1,%r13d
  lea    D40(%rip),%r14
  lea    D34(%rip),%r15
  lea    D57(%rip),%r12
  test   %eax,%eax
  je     L3
  xchg   %ax,%ax
L43:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  jle    L82
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L37
L82:
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L42:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L42
  mov    %r15,%rdi
  lea    0x2(%rbx),%r13d
  call   <printf@plt>
  sub    $0x1,%ebp
  jae    L43
  cmpl   $0x1,0x4(%rsp)
  jle    L3
  xor    %ebx,%ebx
  lea    D57(%rip),%r12
  nopl   0x0(%rax)
L14:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L14
L3:
  mov    %r14,%rdi
  call   <printf@plt>
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L90:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D40
datatype: string
name: extract_symbolic_data
arguments: label: D34
datatype: string
name: extract_symbolic_data
arguments: label: D57
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D4: 
Enter the size of tree


tool: D17: %d

tool: D40: *

tool: D34: 


tool: D57:  

tool: D7: cannot build a three

assistant: ```c
main() {
  int size, spaces, stars = 1;
  int i;
  printf("\nEnter the size of tree\n");
  scanf("%d", &size);
  spaces = size - 1;
  if (size == 0 || size == 1) {
    printf("cannot build a three");
  } else {
    while (spaces != -1) {
      for (i = 0; i < spaces; i++) {
        printf(" ");
      }
      for (i = 0; i < stars; i++) {
        printf("*");
      }
      printf("\n");
      stars = stars + 2;
      spaces = spaces - 1;
    }
    if (spaces == -1) {
      for (i = 0; i < size - 1; i++) {
        printf(" ");
      }
      printf("*");
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<nextprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  jmp    L19
L52:
  addl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L32
L26:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L33
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L26
  mov    -0x14(%rbp),%eax
  jmp    L53
L33:
  nop
L19:
  cmpl   $0x1,-0x14(%rbp)
  jg     L52
  mov    $0x0,%eax
L53:
  leave
  ret
```

assistant: ```c
int nextprime(int n) {
  int i;
  while (n > 1) {
    n++;
    for (i = 2; i <= sqrt(n); i++)
      if (n % i == 0)
        goto ss;
    return n;
  ss:;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextprime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  cmp    $0x1,%edi
  jle    L32
L10:
  add    $0x1,%ebp
  mov    $0x2,%ebx
L42:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L41
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L14
  add    $0x1,%ebx
  jmp    L42
L14:
  cmp    $0x1,%ebp
  jg     L10
  mov    %edx,%ebp
  jmp    L41
L32:
  mov    $0x0,%ebp
L41:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int nextprime(int n) {
  int i;
  while (n > 1) {
    n++;
    for (i = 2; i <= sqrt(n); i++)
      if (n % i == 0)
        goto ss;
    return n;
  ss:;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextprime>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L36
  mov    %edi,%r12d
L33:
  add    $0x1,%r12d
  mov    $0x2,%ebx
  jmp    L48
  xchg   %ax,%ax
L23:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L33
  add    $0x1,%ebx
L48:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L23
L42:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L36:
  xor    %r12d,%r12d
  jmp    L42
```

assistant: ```c
int nextprime(int n) {
  int i;
  while (n > 1) {
    n++;
    for (i = 2; i <= sqrt(n); i++)
      if (n % i == 0)
        goto ss;
    return n;
  ss:;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextprime>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L45
  mov    %edi,%r12d
L15:
  add    $0x1,%r12d
  mov    $0x2,%ebx
  jmp    L49
  xchg   %ax,%ax
L39:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L15
  add    $0x1,%ebx
L49:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L39
L29:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L45:
  xor    %r12d,%r12d
  jmp    L29
```

assistant: ```c
int nextprime(int n) {
  int i;
  while (n > 1) {
    n++;
    for (i = 2; i <= sqrt(n); i++)
      if (n % i == 0)
        goto ss;
    return n;
  ss:;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<days_in_month>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1f,-0x40(%rbp)
  movl   $0x1c,-0x3c(%rbp)
  movl   $0x1f,-0x38(%rbp)
  movl   $0x1e,-0x34(%rbp)
  movl   $0x1f,-0x30(%rbp)
  movl   $0x1e,-0x2c(%rbp)
  movl   $0x1f,-0x28(%rbp)
  movl   $0x1f,-0x24(%rbp)
  movl   $0x1e,-0x20(%rbp)
  movl   $0x1f,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  cmpl   $0x1,-0x44(%rbp)
  jne    L7
  mov    -0x48(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L76
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  jmp    L39
L76:
  mov    -0x48(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L69
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  add    $0x1,%eax
  jmp    L39
L69:
  mov    -0x48(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L44
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  jmp    L39
L44:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  add    $0x1,%eax
  jmp    L39
L7:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

assistant: ```c
int days_in_month(int mon, int year) {
  const int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  if (mon == 1) {
    if (year % 4)
      return days[mon];
    if (year % 100)
      return days[mon] + 1;
    if (year % 400)
      return days[mon];
    return days[mon] + 1;
  } else
    return days[mon];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<days_in_month>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x38(%rsp)
  xor    %edx,%edx
  movl   $0x1f,(%rsp)
  movl   $0x1c,0x4(%rsp)
  movl   $0x1f,0x8(%rsp)
  movl   $0x1e,0xc(%rsp)
  movl   $0x1f,0x10(%rsp)
  movl   $0x1e,0x14(%rsp)
  movl   $0x1f,0x18(%rsp)
  movl   $0x1f,0x1c(%rsp)
  movl   $0x1e,0x20(%rsp)
  movl   $0x1f,0x24(%rsp)
  movl   $0x1e,0x28(%rsp)
  movl   $0x1f,0x2c(%rsp)
  cmp    $0x1,%edi
  jne    L30
  mov    %esi,%eax
  mov    $0x1c,%ecx
  test   $0x3,%al
  jne    L18
  movslq %esi,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  mov    $0x1d,%ecx
  cmp    %edx,%esi
  jne    L18
  movslq %esi,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x190,%edx,%edx
  cmp    %edx,%esi
  sete   %cl
  movzbl %cl,%ecx
  add    $0x1c,%ecx
  jmp    L18
L30:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%ecx
L18:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %ecx,%eax
  add    $0x48,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int days_in_month(int mon, int year) {
  const int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  if (mon == 1) {
    if (year % 4)
      return days[mon];
    if (year % 100)
      return days[mon] + 1;
    if (year % 400)
      return days[mon];
    return days[mon] + 1;
  } else
    return days[mon];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<days_in_month>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x1c0000001f,%rax
  mov    %rax,(%rsp)
  movabs $0x1e0000001f,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x1f0000001f,%rax
  mov    %rax,0x18(%rsp)
  sub    $0x1,%rax
  mov    %rax,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  cmp    $0x1,%edi
  jne    L23
  mov    $0x1c,%eax
  test   $0x3,%sil
  jne    L25
  imul   $0xc28f5c29,%esi,%esi
  mov    $0x1d,%eax
  add    $0x51eb850,%esi
  mov    %esi,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L25
  ror    $0x4,%esi
  xor    %eax,%eax
  cmp    $0xa3d70b,%esi
  setb   %al
  add    $0x1c,%eax
L25:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x48,%rsp
  ret
  nopl   0x0(%rax)
L23:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  jmp    L25
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int days_in_month(int mon, int year) {
  const int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  if (mon == 1) {
    if (year % 4)
      return days[mon];
    if (year % 100)
      return days[mon] + 1;
    if (year % 400)
      return days[mon];
    return days[mon] + 1;
  } else
    return days[mon];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<days_in_month>:
  endbr64
  sub    $0x48,%rsp
  movdqa D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D29(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D12(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  cmp    $0x1,%edi
  jne    L47
  mov    $0x1c,%eax
  test   $0x3,%sil
  jne    L22
  imul   $0xc28f5c29,%esi,%esi
  mov    $0x1d,%eax
  add    $0x51eb850,%esi
  mov    %esi,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L22
  ror    $0x4,%esi
  xor    %eax,%eax
  cmp    $0xa3d70b,%esi
  setb   %al
  add    $0x1c,%eax
L22:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x48,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  jmp    L22
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D29
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D12
type_guessed: byte[16]

tool: {"D15": [0x1f,0x00,0x00,0x00,0x1c,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00]}

tool: {"D29": [0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

tool: {"D12": [0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

assistant: ```c
int days_in_month(int mon, int year) {
  const int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  if (mon == 1) {
    if (year % 4)
      return days[mon];
    if (year % 100)
      return days[mon] + 1;
    if (year % 400)
      return days[mon];
    return days[mon] + 1;
  } else
    return days[mon];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  jmp    L31
L38:
  movl   $0x0,-0x74(%rbp)
  jmp    L40
L8:
  lea    -0x70(%rbp),%rcx
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x74(%rbp)
L40:
  cmpl   $0x4,-0x74(%rbp)
  jle    L8
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <getscore@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L31:
  cmpl   $0x8,-0x78(%rbp)
  jle    L38
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string

tool: D14: %s

tool: D12: %d



assistant: ```c
int main() {
  int ROUND, i;
  char playera[5][20];
  for (ROUND = 0; ROUND < 9; ROUND++) {
    for (i = 0; i < 5; i++) {
      scanf("%s", playera[i]);
    }
    printf("%d\n\n", getscore(&playera[0][0]));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x9,%r13d
  lea    0x64(%rsp),%r12
  lea    D13(%rip),%rbp
  mov    %rsp,%r15
  lea    D2(%rip),%r14
  jmp    L8
L12:
  mov    %r15,%rdi
  call   <getscore@plt>
  mov    %eax,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%r13d
  je     L10
L8:
  mov    %rsp,%rbx
L18:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x14,%rbx
  cmp    %r12,%rbx
  jne    L18
  jmp    L12
L10:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D13: %s

tool: D2: %d



assistant: ```c
int main() {
  int ROUND, i;
  char playera[5][20];
  for (ROUND = 0; ROUND < 9; ROUND++) {
    for (i = 0; i < 5; i++) {
      scanf("%s", playera[i]);
    }
    printf("%d\n\n", getscore(&playera[0][0]));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%r15
  push   %r14
  push   %r13
  mov    $0x9,%r13d
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x64(%rsp),%rbp
  xchg   %ax,%ax
L29:
  mov    %r14,%rbx
L7:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x14,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L7
  mov    %r14,%rdi
  call   <getscore@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L29
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D7
type: string

tool: D14: %d



tool: D7: %s

assistant: ```c
int main() {
  int ROUND, i;
  char playera[5][20];
  for (ROUND = 0; ROUND < 9; ROUND++) {
    for (i = 0; i < 5; i++) {
      scanf("%s", playera[i]);
    }
    printf("%d\n\n", getscore(&playera[0][0]));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%r15
  push   %r14
  push   %r13
  mov    $0x9,%r13d
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x64(%rsp),%rbp
  xchg   %ax,%ax
L15:
  mov    %r14,%rbx
L12:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x14,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L12
  mov    %r14,%rdi
  call   <getscore@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L15
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D3: %d



tool: D1: %s

assistant: ```c
int main() {
  int ROUND, i;
  char playera[5][20];
  for (ROUND = 0; ROUND < 9; ROUND++) {
    for (i = 0; i < 5; i++) {
      scanf("%s", playera[i]);
    }
    printf("%d\n\n", getscore(&playera[0][0]));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__stdfix_smul_lr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L22
  mov    D25(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L22
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  jmp    L7
L22:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  imul   %edx,%eax
  sar    $0x1f,%eax
  mov    %eax,%edi
  call   <__stdfix_sat_lr@plt>
L7:
  leave
  ret
```

assistant: ```c
int32_t __stdfix_smul_lr(int32_t x, int32_t y) {
  if (x == INT32_MIN && y == INT32_MIN)
    return (INT32_MAX);
  return (__stdfix_sat_lr(((int64_t)x * (int64_t)y) >> 31));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__stdfix_smul_lr>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rsi,%rax
  jne    L7
  cmp    %rdi,%rax
  je     L3
L7:
  sub    $0x8,%rsp
  imul   %esi,%edi
  sar    $0x1f,%edi
  call   <__stdfix_sat_lr@plt>
  add    $0x8,%rsp
  ret
L3:
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
int32_t __stdfix_smul_lr(int32_t x, int32_t y) {
  if (x == INT32_MIN && y == INT32_MIN)
    return (INT32_MAX);
  return (__stdfix_sat_lr(((int64_t)x * (int64_t)y) >> 31));
}
```