ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<acha_palavra>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <acha_str@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  movslq %eax,%r13
  mov    %r13,%rbp
  test   %r12d,%r12d
  jns    L57
  jmp    L67
  nop
L14:
  cmpb   $0x20,(%r14,%r13,1)
  jle    L46
  xor    %eax,%eax
L8:
  lea    0x1(%r14,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <acha_str@plt>
  lea    0x1(%rax,%r12,1),%r12d
  test   %eax,%eax
  js     L67
L57:
  test   %r12d,%r12d
  je     L14
  movslq %r12d,%rax
  jle    L8
  cmpb   $0x20,-0x1(%r14,%rax,1)
  jg     L8
  lea    (%r12,%rbp,1),%edx
  movslq %edx,%rdx
  cmpb   $0x20,(%r14,%rdx,1)
  jg     L8
L46:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int acha_palavra(char *s1, char *s2) {
  int i, t, j;
  i = j = acha_str(s1, s2);
  t = strlen(s1);
  while (j >= 0) {
    if (i == 0 && s2[i + t] <= ' ') {
      return i;
    }
    if (i > 0) {
      if (s2[i - 1] <= ' ' && s2[i + t] <= ' ') {
        return i;
      }
    }
    j = acha_str(s1, &(s2[i + 1]));
    i += j + 1;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<acha_palavra>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <acha_str@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  movslq %eax,%r13
  mov    %r13,%rbp
  test   %r12d,%r12d
  jns    L34
  jmp    L6
  nop
L16:
  cmpb   $0x20,(%r14,%r13,1)
  jle    L65
  xor    %eax,%eax
L40:
  lea    0x1(%r14,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <acha_str@plt>
  lea    0x1(%rax,%r12,1),%r12d
  test   %eax,%eax
  js     L6
L34:
  test   %r12d,%r12d
  je     L16
  movslq %r12d,%rax
  jle    L40
  cmpb   $0x20,-0x1(%r14,%rax,1)
  jg     L40
  lea    (%r12,%rbp,1),%edx
  movslq %edx,%rdx
  cmpb   $0x20,(%r14,%rdx,1)
  jg     L40
L65:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int acha_palavra(char *s1, char *s2) {
  int i, t, j;
  i = j = acha_str(s1, s2);
  t = strlen(s1);
  while (j >= 0) {
    if (i == 0 && s2[i + t] <= ' ') {
      return i;
    }
    if (i > 0) {
      if (s2[i - 1] <= ' ' && s2[i + t] <= ' ') {
        return i;
      }
    }
    j = acha_str(s1, &(s2[i + 1]));
    i += j + 1;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L6
L27:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  cmpl   $0x0,-0xc(%rbp)
  jle    L1
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
L1:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int trim(char *s, int len) {
  while (len > 0 && isspace((unsigned char)s[len - 1]))
    s[--len] = '\0';
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L17
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rbx
L2:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L17
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  sub    $0x1,%ebp
  jne    L2
L17:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int trim(char *s, int len) {
  while (len > 0 && isspace((unsigned char)s[len - 1]))
    s[--len] = '\0';
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<trim>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L12
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rbx
  jmp    L18
  nopl   0x0(%rax)
L35:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  sub    $0x1,%r12d
  je     L12
L18:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
L12:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) int trim(char *s, int len) {
  while (len > 0 && isspace((unsigned char)s[len - 1]))
    s[--len] = '\0';
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L8
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rbx
  jmp    L30
  nopl   0x0(%rax)
L28:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  sub    $0x1,%r12d
  je     L8
L30:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) int trim(char *s, int len) {
  while (len > 0 && isspace((unsigned char)s[len - 1]))
    s[--len] = '\0';
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hello>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  addl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hello(int a) {
  int hello;
  a = a + 3;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hello>:
  endbr64
  lea    0x3(%rdi),%eax
  ret
```

assistant: ```c
int hello(int a) {
  int hello;
  a = a + 3;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hello>:
  endbr64
  lea    0x3(%rdi),%eax
  ret
```

assistant: ```c
int hello(int a) {
  int hello;
  a = a + 3;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hello>:
  endbr64
  lea    0x3(%rdi),%eax
  ret
```

assistant: ```c
int hello(int a) {
  int hello;
  a = a + 3;
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L28
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L28:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D19
type_infered: string

tool: D15: Enter two numbers: 

tool: D7: %i%i

tool: D1: %i is not evenly divisible by %i


tool: D19: %i is evenly divisible by %i


assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value1 % value2)
    printf("%i is not evenly divisible by %i\n", value1, value2);
  else
    printf("%i is evenly divisible by %i\n", value1, value2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L22
  mov    %ecx,%edx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L22:
  mov    %ecx,%edx
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L26
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D36
data_type: string
name: retrieve_data
arguments: data_tag: D31
data_type: string
name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string

tool: D36: Enter two numbers: 

tool: D31: %i%i

tool: D13: %i is not evenly divisible by %i


tool: D19: %i is evenly divisible by %i


assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value1 % value2)
    printf("%i is not evenly divisible by %i\n", value1, value2);
  else
    printf("%i is evenly divisible by %i\n", value1, value2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  mov    %r8d,%edx
  je     L20
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D38
type_guessed: string
name: read_data
arguments: data_label: D24
type_guessed: string

tool: D21: Enter two numbers: 

tool: D27: %i%i

tool: D38: %i is not evenly divisible by %i


tool: D24: %i is evenly divisible by %i


assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value1 % value2)
    printf("%i is not evenly divisible by %i\n", value1, value2);
  else
    printf("%i is evenly divisible by %i\n", value1, value2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  mov    %r8d,%edx
  je     L1
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L14
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D39
type_infered: string
name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string

tool: D39: Enter two numbers: 

tool: D27: %i%i

tool: D12: %i is not evenly divisible by %i


tool: D21: %i is evenly divisible by %i


assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value1 % value2)
    printf("%i is not evenly divisible by %i\n", value1, value2);
  else
    printf("%i is evenly divisible by %i\n", value1, value2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <doubles_mat44_identity@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x10(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x20,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x28,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbp
  mov    %rdi,%rbx
  call   <doubles_mat44_identity@plt>
  movq   %rbp,%xmm0
  call   <sin@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movq   %xmm2,%r12
  movq   %rbp,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,(%rbx)
  movq   %r12,%xmm1
  xorpd  D6(%rip),%xmm1
  movsd  %xmm1,0x8(%rbx)
  mov    %r12,0x20(%rbx)
  movsd  %xmm0,0x28(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <doubles_mat44_identity@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  movsd  %xmm1,(%rsp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  movapd %xmm1,%xmm2
  xorpd  D8(%rip),%xmm2
  movsd  %xmm1,0x20(%rbx)
  movsd  %xmm2,0x8(%rbx)
  movsd  %xmm0,(%rbx)
  movsd  %xmm0,0x28(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <doubles_mat44_identity@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  movsd  %xmm1,(%rsp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  movapd %xmm1,%xmm3
  xorpd  D9(%rip),%xmm3
  movapd %xmm0,%xmm2
  unpcklpd %xmm0,%xmm1
  unpcklpd %xmm3,%xmm2
  movups %xmm1,0x20(%rbx)
  movups %xmm2,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<handle_flags_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <handle_zero_flag@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <handle_sign_flag@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <handle_carry_flag_add@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <handle_aux_carry_flag_add@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <handle_parity_flag@plt>
  nop
  leave
  ret
```

assistant: ```c
void handle_flags_add(const int final_value, const int value1, const int value2) {
  handle_zero_flag(final_value);
  handle_sign_flag(final_value);
  handle_carry_flag_add(value1, value2);
  handle_aux_carry_flag_add(value1, value2);
  handle_parity_flag(final_value);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<handle_flags_add>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <handle_zero_flag@plt>
  mov    %ebx,%edi
  call   <handle_sign_flag@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <handle_carry_flag_add@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <handle_aux_carry_flag_add@plt>
  mov    %ebx,%edi
  call   <handle_parity_flag@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void handle_flags_add(const int final_value, const int value1, const int value2) {
  handle_zero_flag(final_value);
  handle_sign_flag(final_value);
  handle_carry_flag_add(value1, value2);
  handle_aux_carry_flag_add(value1, value2);
  handle_parity_flag(final_value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_flags_add>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <handle_zero_flag@plt>
  mov    %ebp,%edi
  call   <handle_sign_flag@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <handle_carry_flag_add@plt>
  mov    %r12d,%edi
  mov    %r13d,%esi
  call   <handle_aux_carry_flag_add@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <handle_parity_flag@plt>
```

assistant: ```c
void handle_flags_add(const int final_value, const int value1, const int value2) {
  handle_zero_flag(final_value);
  handle_sign_flag(final_value);
  handle_carry_flag_add(value1, value2);
  handle_aux_carry_flag_add(value1, value2);
  handle_parity_flag(final_value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_flags_add>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <handle_zero_flag@plt>
  mov    %ebp,%edi
  call   <handle_sign_flag@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <handle_carry_flag_add@plt>
  mov    %r12d,%edi
  mov    %r13d,%esi
  call   <handle_aux_carry_flag_add@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <handle_parity_flag@plt>
```

assistant: ```c
void handle_flags_add(const int final_value, const int value1, const int value2) {
  handle_zero_flag(final_value);
  handle_sign_flag(final_value);
  handle_carry_flag_add(value1, value2);
  handle_aux_carry_flag_add(value1, value2);
  handle_parity_flag(final_value);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<randev1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x58(%rbp),%xmm0
  movsd  D33(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  -0x58(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D51(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x48(%rbp)
L25:
  mov    $0x0,%eax
  call   <drand2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x40(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x38(%rbp),%xmm0
  jae    L54
  movsd  -0x40(%rbp),%xmm0
  movsd  D21(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movsd  -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm4
  divsd  -0x38(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mulsd  -0x60(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x50(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jae    L61
  mov    $0x0,%eax
  call   <drand2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D59(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm2
  divsd  -0x28(%rbp),%xmm2
  movsd  D33(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jb     L30
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rbx
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x50(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x50(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movq   %rbx,%xmm5
  comisd %xmm0,%xmm5
  jae    L55
L30:
  movsd  -0x28(%rbp),%xmm0
  jmp    L45
L54:
  nop
  jmp    L25
L61:
  nop
  jmp    L25
L55:
  nop
  jmp    L25
L45:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D33
data_type: f64
name: read_data
arguments: data_label: D4
data_type: f64
name: read_data
arguments: data_label: D51
data_type: f64
name: read_data
arguments: data_label: D21
data_type: f64
name: read_data
arguments: data_label: D59
data_type: f64

tool: D33: 1

tool: D4: 3

tool: D51: 0.75

tool: D21: 0.5

tool: D59: 64

assistant: ```c
double randev1(double a) {
  double x, d, e, c, g, f, r1, r2;
  e = a - 1.0;
  c = 3.0 * a - 0.75;
  for (;;) {
    r1 = (drand2());
    g = r1 - (r1 * r1);
    if (g <= 0.0)
      continue;
    f = (r1 - 0.5) * sqrt(c / g);
    x = e + f;
    if (x <= 0.0)
      continue;
    r2 = (drand2());
    d = 64.0 * r2 * r2 * g * g * g;
    if ((d >= 1.0 - 2.0 * f * f / x) && (log(d) >= 2.0 * (e * log(x / e) - f)))
      continue;
    return (x);
  }
}
```