ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L142
L74:
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L135:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L135
  cmpl   $0x1,-0x14(%rbp)
  je     L86
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L123
L86:
  movl   $0x1,-0x10(%rbp)
  jmp    L14
L39:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L39
  jmp    L37
L123:
  movl   $0x1,-0x10(%rbp)
  jmp    L132
L131:
  cmpl   $0x1,-0x10(%rbp)
  je     L83
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L32
L83:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L107
L32:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L107:
  addl   $0x1,-0x10(%rbp)
L132:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L131
L37:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L142:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L74
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D47
type: string
name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D37
type: string
name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D29
type: string

tool: D47: pelease input a number: 

tool: D6: %d

tool: D37:  

tool: D16: *

tool: D29: 


assistant: ```c
int main() {
  int n, i, j, k;
  printf("pelease input a number: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (k = 1; k <= n - i; k++) {
      printf(" ");
    }
    if (i == 1 || i == n) {
      for (j = 1; j <= i * 2 - 1; j++) {
        printf("*");
      }
    } else {
      for (j = 1; j <= i * 2 - 1; j++) {
        if (j == 1 || j == i * 2 - 1) {
          printf("*");
        } else
          printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  movl   $0x2,0xc(%rsp)
  mov    $0x1,%ebp
  lea    D22(%rip),%r12
  lea    D36(%rip),%r13
  cmpl   $0x0,0x14(%rsp)
  jg     L43
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    0xc(%rsp),%eax
  mov    %eax,%r14d
  cmp    $0x1,%eax
  jle    L41
  mov    $0x1,%ebx
L14:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jne    L14
L41:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  addl   $0x2,0xc(%rsp)
  cmp    %ebp,0x14(%rsp)
  jl     L45
L43:
  mov    0x14(%rsp),%eax
  mov    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L102
L18:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x14(%rsp),%eax
  mov    %eax,%edx
  sub    %ebp,%edx
  cmp    %ebx,%edx
  jge    L18
L102:
  cmp    %ebp,%eax
  je     L13
  cmp    $0x1,%ebp
  je     L13
  mov    0xc(%rsp),%eax
  mov    %eax,%r14d
  mov    $0x1,%ebx
  lea    -0x1(%rax),%r15d
  cmp    $0x1,%eax
  jg     L142
  jmp    L41
L4:
  mov    %r13,%rdi
  call   <printf@plt>
L53:
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  je     L41
L142:
  cmp    $0x1,%ebx
  je     L4
  cmp    %ebx,%r15d
  je     L4
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L53
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D43
type_guessed: string
name: retrieve_data
arguments: tag: D44
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D36
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D43: pelease input a number: 

tool: D44: %d

tool: D22:  

tool: D36: *

tool: D10: 


assistant: ```c
int main() {
  int n, i, j, k;
  printf("pelease input a number: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (k = 1; k <= n - i; k++) {
      printf(" ");
    }
    if (i == 1 || i == n) {
      for (j = 1; j <= i * 2 - 1; j++) {
        printf("*");
      }
    } else {
      for (j = 1; j <= i * 2 - 1; j++) {
        if (j == 1 || j == i * 2 - 1) {
          printf("*");
        } else
          printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L85
  mov    $0x1,%r14d
  mov    $0x2,%ebp
  mov    $0x1,%ebx
  lea    D46(%rip),%r12
  lea    D12(%rip),%r13
  nopl   0x0(%rax)
L14:
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jle    L34
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%ecx
  sub    %ebx,%ecx
  cmp    %r15d,%ecx
  jge    L52
L34:
  cmp    $0x1,%ebx
  je     L108
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jne    L62
  jmp    L108
  xchg   %ax,%ax
L126:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jge    L8
L62:
  cmp    $0x1,%r15d
  je     L30
  cmp    %r15d,%r14d
  jne    L126
L30:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jl     L62
L8:
  lea    D37(%rip),%rdi
  add    $0x1,%ebx
  add    $0x2,%ebp
  add    $0x2,%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L14
L85:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L108:
  mov    $0x1,%r15d
  cs nopw 0x0(%rax,%rax,1)
L137:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,%ebp
  jg     L137
  jmp    L8
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D46
data_type: string
name: unpack_data
arguments: data_tag: D12
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string

tool: D3: pelease input a number: 

tool: D15: %d

tool: D46:  

tool: D12: *

tool: D37: 


assistant: ```c
int main() {
  int n, i, j, k;
  printf("pelease input a number: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (k = 1; k <= n - i; k++) {
      printf(" ");
    }
    if (i == 1 || i == n) {
      for (j = 1; j <= i * 2 - 1; j++) {
        printf("*");
      }
    } else {
      for (j = 1; j <= i * 2 - 1; j++) {
        if (j == 1 || j == i * 2 - 1) {
          printf("*");
        } else
          printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L107
  mov    $0x1,%r14d
  mov    $0x2,%ebp
  mov    $0x1,%ebx
  lea    D15(%rip),%r12
  lea    D40(%rip),%r13
  nopl   0x0(%rax)
L132:
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jle    L105
  nopw   0x0(%rax,%rax,1)
L61:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%ecx
  sub    %ebx,%ecx
  cmp    %r15d,%ecx
  jge    L61
L105:
  cmp    $0x1,%ebx
  je     L127
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jne    L119
  jmp    L127
  xchg   %ax,%ax
L65:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jge    L35
L119:
  cmp    $0x1,%r15d
  je     L75
  cmp    %r15d,%r14d
  jne    L65
L75:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jl     L119
L35:
  lea    D29(%rip),%rdi
  add    $0x1,%ebx
  add    $0x2,%ebp
  add    $0x2,%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L132
L107:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L127:
  mov    $0x1,%r15d
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,%ebp
  jg     L30
  jmp    L35
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D44
type: string
name: read_data
arguments: data_tag: D39
type: string
name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D40
type: string
name: read_data
arguments: data_tag: D29
type: string

tool: D44: pelease input a number: 

tool: D39: %d

tool: D15:  

tool: D40: *

tool: D29: 


assistant: ```c
int main() {
  int n, i, j, k;
  printf("pelease input a number: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (k = 1; k <= n - i; k++) {
      printf(" ");
    }
    if (i == 1 || i == n) {
      for (j = 1; j <= i * 2 - 1; j++) {
        printf("*");
      }
    } else {
      for (j = 1; j <= i * 2 - 1; j++) {
        if (j == 1 || j == i * 2 - 1) {
          printf("*");
        } else
          printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xa9c000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0x180,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa9c120(%rbp),%rax
  mov    $0xa9c110,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x54e0840,-0xa9c120(%rbp)
  lea    -0xa9c120(%rbp),%rax
  mov    %rax,%rdi
  call   <Eratosthenes@plt>
  movq   $0x0,-0xa9c170(%rbp)
  movq   $0x0,-0xa9c168(%rbp)
  movq   $0x0,-0xa9c160(%rbp)
  movq   $0x0,-0xa9c158(%rbp)
  movq   $0x0,-0xa9c150(%rbp)
  movq   $0x0,-0xa9c148(%rbp)
  movq   $0x0,-0xa9c140(%rbp)
  movq   $0x0,-0xa9c138(%rbp)
  movq   $0x0,-0xa9c130(%rbp)
  movq   $0x0,-0xa9c128(%rbp)
  movl   $0xa,-0xa9c180(%rbp)
  mov    -0xa9c120(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0xa9c178(%rbp)
  jmp    L11
L64:
  mov    -0xa9c120(%rbp),%rax
  cmp    %rax,-0xa9c178(%rbp)
  jb     L80
  mov    -0xa9c120(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdx
  mov    -0xa9c178(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <FatalError@plt>
  mov    $0x1,%eax
  jmp    L42
L80:
  mov    -0xa9c178(%rbp),%rax
  shr    $0x6,%rax
  add    $0x1,%rax
  mov    -0xa9c120(%rbp,%rax,8),%rdx
  mov    -0xa9c178(%rbp),%rax
  and    $0x3f,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    %rsi,%rax
  and    %rdx,%rax
  test   %rax,%rax
  sete   %al
L42:
  test   %al,%al
  je     L54
  subl   $0x1,-0xa9c180(%rbp)
  mov    -0xa9c180(%rbp),%eax
  cltq
  mov    -0xa9c178(%rbp),%rdx
  mov    %rdx,-0xa9c170(%rbp,%rax,8)
L54:
  subq   $0x1,-0xa9c178(%rbp)
L11:
  cmpq   $0x1,-0xa9c178(%rbp)
  jbe    L57
  cmpl   $0x0,-0xa9c180(%rbp)
  jg     L64
L57:
  mov    -0xa9c180(%rbp),%eax
  mov    %eax,-0xa9c17c(%rbp)
  jmp    L76
L59:
  mov    -0xa9c17c(%rbp),%eax
  cltq
  mov    -0xa9c170(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xa9c17c(%rbp)
L76:
  cmpl   $0x9,-0xa9c17c(%rbp)
  jle    L59
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D11: Index %ld mimo rozsah 0..%ld

tool: D3: %lu


assistant: ```c
int main(void) {
  unsigned long pole[(89000000L - 1L) / (sizeof(unsigned long) * 8) + 2L] = {0};
  pole[0] = (unsigned long)89000000L;
  Eratosthenes(pole);
  unsigned long prims[10] = {0};
  int primIndex = 10;
  for (unsigned long i = (pole[0]) - 1L; (i > 1L && primIndex > 0); i--)
    if ((i < 0 || i >= pole[0]) ? (FatalError("Index %ld mimo rozsah 0..%ld", (long)i, (long)(pole[0] - 1)), 2) : ((pole[((i) / (sizeof(pole[0]) * 8) + 1L)] & (1L << (i - ((i / (sizeof(pole[0]) * 8)) * (sizeof(pole[0]) * 8))))) ? 1 : 0) == 0)
      prims[--primIndex] = i;
  for (int i = primIndex; i < 10; i++)
    printf("%lu\n", prims[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa9c000(%rsp),%r11
L96:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L96
  sub    $0x170,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa9c168(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbx
  mov    $0xa9c110,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movq   $0x54e0840,0x50(%rsp)
  mov    %rbx,%rdi
  call   <Eratosthenes@plt>
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  mov    0x50(%rsp),%rax
  lea    -0x1(%rax),%rbx
  cmp    $0x1,%rbx
  jbe    L39
  mov    $0xa,%ebp
  lea    D15(%rip),%r12
  jmp    L100
L99:
  sub    $0x1,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <FatalError@plt>
L109:
  sub    $0x1,%ebp
  movslq %ebp,%rax
  mov    %rbx,(%rsp,%rax,8)
L95:
  sub    $0x1,%rbx
  cmp    $0x1,%rbx
  jbe    L22
  test   %ebp,%ebp
  jle    L22
L100:
  mov    0x50(%rsp),%rdx
  cmp    %rbx,%rdx
  jbe    L99
  mov    %rbx,%rdx
  shr    $0x6,%rdx
  mov    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%rax
  and    0x58(%rsp,%rdx,8),%rax
  jne    L95
  jmp    L109
L22:
  cmp    $0x9,%ebp
  jg     L39
  movslq %ebp,%rdx
  lea    (%rsp,%rdx,8),%rbx
  mov    $0x9,%eax
  sub    %ebp,%eax
  add    %rdx,%rax
  lea    0x8(%rsp,%rax,8),%r12
  lea    D9(%rip),%rbp
L13:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
L39:
  mov    0xa9c168(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0xa9c170,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
data_type: string
name: parse_data
arguments: label: D9
data_type: string

tool: D15: Index %ld mimo rozsah 0..%ld

tool: D9: %lu


assistant: ```c
int main(void) {
  unsigned long pole[(89000000L - 1L) / (sizeof(unsigned long) * 8) + 2L] = {0};
  pole[0] = (unsigned long)89000000L;
  Eratosthenes(pole);
  unsigned long prims[10] = {0};
  int primIndex = 10;
  for (unsigned long i = (pole[0]) - 1L; (i > 1L && primIndex > 0); i--)
    if ((i < 0 || i >= pole[0]) ? (FatalError("Index %ld mimo rozsah 0..%ld", (long)i, (long)(pole[0] - 1)), 2) : ((pole[((i) / (sizeof(pole[0]) * 8) + 1L)] & (1L << (i - ((i / (sizeof(pole[0]) * 8)) * (sizeof(pole[0]) * 8))))) ? 1 : 0) == 0)
      prims[--primIndex] = i;
  for (int i = primIndex; i < 10; i++)
    printf("%lu\n", prims[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa9c000(%rsp),%r11
L33:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L33
  sub    $0x170,%rsp
  mov    $0xa9c110,%edx
  xor    %esi,%esi
  mov    $0xa,%ebx
  lea    D15(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xa9c168(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rdi
  call   <memset@plt>
  movq   $0x54e0840,0x50(%rsp)
  mov    %rax,%rdi
  call   <Eratosthenes@plt>
  mov    0x50(%rsp),%rdx
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  lea    -0x1(%rdx),%r12
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  cmp    $0x1,%r12
  ja     L94
  jmp    L53
  nopl   0x0(%rax)
L41:
  mov    %r12,%rdx
  mov    $0x1,%eax
  mov    %r12d,%ecx
  shr    $0x6,%rdx
  shl    %cl,%rax
  and    0x58(%rsp,%rdx,8),%rax
  jne    L36
L46:
  sub    $0x1,%ebx
  movslq %ebx,%rax
  mov    %r12,(%rsp,%rax,8)
L36:
  sub    $0x1,%r12
  cmp    $0x1,%r12
  jbe    L86
  test   %ebx,%ebx
  jle    L86
  mov    0x50(%rsp),%rdx
L94:
  cmp    %r12,%rdx
  ja     L41
  sub    $0x1,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <FatalError@plt>
  jmp    L46
  nopl   0x0(%rax)
L86:
  cmp    $0xa,%ebx
  je     L53
  mov    $0x9,%eax
  movslq %ebx,%rdx
  sub    %ebx,%eax
  lea    (%rsp,%rdx,8),%r12
  lea    D16(%rip),%rbx
  add    %rdx,%rax
  lea    0x8(%rsp,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L83:
  mov    (%r12),%rsi
  mov    %rbx,%rdi
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L83
L53:
  mov    0xa9c168(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xa9c170,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D15: Index %ld mimo rozsah 0..%ld

tool: D16: %lu


assistant: ```c
int main(void) {
  unsigned long pole[(89000000L - 1L) / (sizeof(unsigned long) * 8) + 2L] = {0};
  pole[0] = (unsigned long)89000000L;
  Eratosthenes(pole);
  unsigned long prims[10] = {0};
  int primIndex = 10;
  for (unsigned long i = (pole[0]) - 1L; (i > 1L && primIndex > 0); i--)
    if ((i < 0 || i >= pole[0]) ? (FatalError("Index %ld mimo rozsah 0..%ld", (long)i, (long)(pole[0] - 1)), 2) : ((pole[((i) / (sizeof(pole[0]) * 8) + 1L)] & (1L << (i - ((i / (sizeof(pole[0]) * 8)) * (sizeof(pole[0]) * 8))))) ? 1 : 0) == 0)
      prims[--primIndex] = i;
  for (int i = primIndex; i < 10; i++)
    printf("%lu\n", prims[i]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa9c000(%rsp),%r11
L46:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L46
  sub    $0x170,%rsp
  mov    $0xa9c110,%edx
  xor    %esi,%esi
  mov    $0xa,%ebx
  lea    D1(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xa9c168(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rdi
  call   <memset@plt>
  movq   $0x54e0840,0x50(%rsp)
  mov    %rax,%rdi
  call   <Eratosthenes@plt>
  mov    0x50(%rsp),%rdx
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  lea    -0x1(%rdx),%r12
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  cmp    $0x1,%r12
  ja     L101
  jmp    L63
  nopl   0x0(%rax)
L95:
  mov    %r12,%rdx
  mov    $0x1,%eax
  mov    %r12d,%ecx
  shr    $0x6,%rdx
  shl    %cl,%rax
  and    0x58(%rsp,%rdx,8),%rax
  jne    L35
L36:
  sub    $0x1,%ebx
  movslq %ebx,%rax
  mov    %r12,(%rsp,%rax,8)
L35:
  sub    $0x1,%r12
  cmp    $0x1,%r12
  jbe    L72
  test   %ebx,%ebx
  jle    L72
  mov    0x50(%rsp),%rdx
L101:
  cmp    %r12,%rdx
  ja     L95
  sub    $0x1,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <FatalError@plt>
  jmp    L36
  nopl   0x0(%rax)
L72:
  cmp    $0xa,%ebx
  je     L63
  mov    $0x9,%eax
  movslq %ebx,%rdx
  sub    %ebx,%eax
  lea    (%rsp,%rdx,8),%r12
  lea    D15(%rip),%rbx
  add    %rdx,%rax
  lea    0x8(%rsp,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L71:
  mov    (%r12),%rsi
  mov    %rbx,%rdi
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L71
L63:
  mov    0xa9c168(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0xa9c170,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D1: Index %ld mimo rozsah 0..%ld

tool: D15: %lu


assistant: ```c
int main(void) {
  unsigned long pole[(89000000L - 1L) / (sizeof(unsigned long) * 8) + 2L] = {0};
  pole[0] = (unsigned long)89000000L;
  Eratosthenes(pole);
  unsigned long prims[10] = {0};
  int primIndex = 10;
  for (unsigned long i = (pole[0]) - 1L; (i > 1L && primIndex > 0); i--)
    if ((i < 0 || i >= pole[0]) ? (FatalError("Index %ld mimo rozsah 0..%ld", (long)i, (long)(pole[0] - 1)), 2) : ((pole[((i) / (sizeof(pole[0]) * 8) + 1L)] & (1L << (i - ((i / (sizeof(pole[0]) * 8)) * (sizeof(pole[0]) * 8))))) ? 1 : 0) == 0)
      prims[--primIndex] = i;
  for (int i = primIndex; i < 10; i++)
    printf("%lu\n", prims[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <server@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  server();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <server@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  server();
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <server@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  server();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <server@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  server();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clar_print_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D5
type: string

tool: D8: Loaded %d suites: %s


tool: D5: Started

assistant: ```c
void clar_print_init(int test_count, int suite_count, const char *suite_names) {
  (void)test_count;
  printf("Loaded %d suites: %s\n", (int)suite_count, suite_names);
  printf("Started\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clar_print_init>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D10
type: string

tool: D6: Loaded %d suites: %s


tool: D10: Started

assistant: ```c
void clar_print_init(int test_count, int suite_count, const char *suite_names) {
  (void)test_count;
  printf("Loaded %d suites: %s\n", (int)suite_count, suite_names);
  printf("Started\n");
}
```