ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  test   %esi,%esi
  je     L130
  test   %ecx,%ecx
  je     L2
  lea    (%rsi,%rcx,1),%r14d
  mov    %esi,%r11d
  mov    %rsp,%rsi
  movslq %r14d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L74
L13:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L13
L74:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L176
  orq    $0x0,-0x8(%rsp,%rdx,1)
L176:
  mov    %rsp,%r13
  test   %r14d,%r14d
  jle    L2
  mov    %r14d,%r14d
  mov    %r13,%rax
  xor    %esi,%esi
  xor    %edi,%edi
  lea    0x0(%r13,%r14,4),%r12
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L107:
  movslq %edi,%rdx
  movslq %esi,%r8
  mov    (%r9,%rdx,4),%edx
  mov    (%r10,%r8,4),%r8d
  cmp    %r8d,%edx
  jge    L101
  add    $0x1,%edi
  mov    %edx,%r8d
L49:
  mov    %r8d,(%rax)
  add    $0x4,%rax
  cmp    %rax,%r12
  je     L97
L17:
  cmp    %edi,%r11d
  setg   %r8b
  cmp    %esi,%ecx
  jle    L151
  test   %r8b,%r8b
  jne    L107
  cmp    %esi,%ecx
  jle    L151
L58:
  movslq %esi,%rdx
  mov    (%r10,%rdx,4),%r8d
L101:
  mov    %r8d,(%rax)
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %rax,%r12
  jne    L17
L97:
  lea    0x0(,%r14,4),%rdx
  mov    %r13,%rsi
  mov    %r9,%rdi
  call   <memcpy@plt>
L2:
  mov    %rbx,%rsp
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L130:
  test   %ecx,%ecx
  jle    L2
  movslq %ecx,%rcx
  nop
L54:
  mov    (%r10,%rax,4),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L54
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L151:
  test   %r8b,%r8b
  je     L58
  movslq %edi,%rdx
  add    $0x1,%edi
  mov    (%r9,%rdx,4),%r8d
  jmp    L49
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int *nums1, int m, int *nums2, int n) {
  int i = 0;
  int j = 0;
  int k = 0;
  if (m == 0) {
    for (; i < n; i++) {
      nums1[i] = nums2[i];
    }
    return;
  }
  if (n == 0) {
    return;
  }
  int temp[m + n];
  for (; i < m + n; i++) {
    if (j < m && k < n) {
      if (nums1[j] < nums2[k]) {
        temp[i] = nums1[j];
        j++;
      } else {
        temp[i] = nums2[k];
        k++;
      }
    } else if (j < m && k >= n) {
      temp[i] = nums1[j];
      j++;
    } else {
      temp[i] = nums2[k];
      k++;
    }
  }
  i = 0;
  for (; i < m + n; i++) {
    nums1[i] = temp[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mylog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L14
  shll   -0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L17
L14:
  nop
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mylog>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%edx
  cmp    $0x1,%edi
  jle    L1
L8:
  add    %eax,%eax
  add    $0x1,%edx
  cmp    %eax,%edi
  jg     L8
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mylog>:
  endbr64
  mov    $0x1,%eax
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  jle    L0
  nopl   0x0(%rax)
L11:
  add    %eax,%eax
  add    $0x1,%r8d
  cmp    %eax,%edi
  jg     L11
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mylog>:
  endbr64
  mov    $0x1,%eax
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  jle    L15
  nopl   0x0(%rax)
L7:
  add    %eax,%eax
  add    $0x1,%r8d
  cmp    %eax,%edi
  jg     L7
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mylog(int num) {
  int j;
  int k;
  {
    j = 0;
    k = 1;
    {
      while (1) {
      while_0_continue:;
        if (k < num) {
        } else {
          goto while_0_break;
        }
        k = k * 2;
        j = j + 1;
      }
    while_0_break:;
    }
    return (j);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<leapyear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movw   $0x0,-0x2(%rbp)
  cmpw   $0x63,-0x14(%rbp)
  ja     L18
  addw   $0x76c,-0x14(%rbp)
L18:
  cmpw   $0x3e7,-0x14(%rbp)
  ja     L3
  addw   $0x7d0,-0x14(%rbp)
L3:
  movzwl -0x14(%rbp),%eax
  movzwl -0x14(%rbp),%edx
  shr    $0x2,%dx
  movzwl %dx,%edx
  shl    $0x2,%edx
  cmp    %edx,%eax
  jne    L47
  movw   $0x1,-0x2(%rbp)
L47:
  movzwl -0x14(%rbp),%edx
  movzwl -0x14(%rbp),%eax
  shr    $0x2,%ax
  movzwl %ax,%eax
  imul   $0x147b,%eax,%eax
  shr    $0x10,%eax
  shr    %ax
  movzwl %ax,%eax
  imul   $0x64,%eax,%eax
  cmp    %eax,%edx
  jne    L8
  movw   $0x0,-0x2(%rbp)
L8:
  movzwl -0x14(%rbp),%edx
  movzwl -0x14(%rbp),%eax
  shr    $0x4,%ax
  movzwl %ax,%eax
  imul   $0xa3e,%eax,%eax
  shr    $0x10,%eax
  movzwl %ax,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edx
  jne    L20
  movw   $0x1,-0x2(%rbp)
L20:
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short leapyear(yr)
unsigned short yr;
{
  unsigned short lyr = 0;
  if (yr < 100)
    yr += 1900;
  if (yr < 1000)
    yr += 2000;
  if (yr == (4 * (yr / 4)))
    lyr = 1;
  if (yr == (100 * (yr / 100)))
    lyr = 0;
  if (yr == (400 * (yr / 400)))
    lyr = 1;
  return (lyr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<leapyear>:
  endbr64
  mov    %edi,%eax
  cmp    $0x63,%di
  ja     L11
  lea    0x76c(%rdi),%eax
  movzwl %ax,%ecx
  mov    %eax,%edx
  shr    $0x2,%dx
  movzwl %dx,%edx
  imul   $0x147b,%edx,%edx
  shr    $0x11,%edx
  imul   $0x64,%edx,%edx
  mov    $0x0,%esi
  cmp    %edx,%ecx
  je     L2
L9:
  mov    %eax,%edx
  shr    $0x2,%dx
  movzwl %dx,%edx
  shl    $0x2,%edx
  cmp    %ecx,%edx
  sete   %sil
  movzbl %sil,%esi
L29:
  shr    $0x4,%ax
  movzwl %ax,%eax
  imul   $0xa3e,%eax,%eax
  shr    $0x10,%eax
  imul   $0x190,%eax,%eax
  cmp    %ecx,%eax
  mov    $0x1,%eax
  cmove  %eax,%esi
L2:
  mov    %esi,%eax
  ret
L11:
  cmp    $0x3e7,%di
  ja     L48
  lea    0x7d0(%rdi),%eax
L48:
  movzwl %ax,%ecx
  mov    %eax,%edx
  shr    $0x2,%dx
  movzwl %dx,%edx
  imul   $0x147b,%edx,%edx
  shr    $0x11,%edx
  imul   $0x64,%edx,%edx
  mov    $0x0,%esi
  cmp    %edx,%ecx
  jne    L9
  jmp    L29
```

assistant: ```c
unsigned short leapyear(yr)
unsigned short yr;
{
  unsigned short lyr = 0;
  if (yr < 100)
    yr += 1900;
  if (yr < 1000)
    yr += 2000;
  if (yr == (4 * (yr / 4)))
    lyr = 1;
  if (yr == (100 * (yr / 100)))
    lyr = 0;
  if (yr == (400 * (yr / 400)))
    lyr = 1;
  return (lyr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<leapyear>:
  endbr64
  mov    %edi,%eax
  cmp    $0x63,%di
  ja     L33
  add    $0x76c,%di
  xor    %r8d,%r8d
  movzwl %di,%eax
  cmp    $0x76c,%di
  je     L35
  shr    $0x2,%di
  xor    %r8d,%r8d
  movzwl %di,%edi
  shl    $0x2,%edi
  cmp    %eax,%edi
  sete   %r8b
L35:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L33:
  cmp    $0x3e7,%di
  ja     L0
  lea    0x7d0(%rdi),%eax
L0:
  mov    %eax,%ecx
  movzwl %ax,%esi
  xor    %r8d,%r8d
  shr    $0x2,%cx
  movzwl %cx,%ecx
  imul   $0x147b,%ecx,%edx
  shr    $0x11,%edx
  imul   $0x64,%edx,%edx
  cmp    %edx,%esi
  je     L15
  shl    $0x2,%ecx
  xor    %r8d,%r8d
  cmp    %esi,%ecx
  sete   %r8b
L15:
  shr    $0x4,%ax
  movzwl %ax,%eax
  imul   $0xa3e,%eax,%eax
  shr    $0x10,%eax
  imul   $0x190,%eax,%eax
  cmp    %esi,%eax
  mov    $0x1,%eax
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short leapyear(yr)
unsigned short yr;
{
  unsigned short lyr = 0;
  if (yr < 100)
    yr += 1900;
  if (yr < 1000)
    yr += 2000;
  if (yr == (4 * (yr / 4)))
    lyr = 1;
  if (yr == (100 * (yr / 100)))
    lyr = 0;
  if (yr == (400 * (yr / 400)))
    lyr = 1;
  return (lyr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<leapyear>:
  endbr64
  mov    %edi,%eax
  cmp    $0x63,%di
  ja     L2
  add    $0x76c,%di
  xor    %r8d,%r8d
  movzwl %di,%eax
  cmp    $0x76c,%di
  je     L8
  shr    $0x2,%di
  xor    %r8d,%r8d
  movzwl %di,%edi
  shl    $0x2,%edi
  cmp    %eax,%edi
  sete   %r8b
L8:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L2:
  cmp    $0x3e7,%di
  ja     L35
  lea    0x7d0(%rdi),%eax
L35:
  mov    %eax,%ecx
  movzwl %ax,%esi
  xor    %r8d,%r8d
  shr    $0x2,%cx
  movzwl %cx,%ecx
  imul   $0x147b,%ecx,%edx
  shr    $0x11,%edx
  imul   $0x64,%edx,%edx
  cmp    %edx,%esi
  je     L7
  shl    $0x2,%ecx
  xor    %r8d,%r8d
  cmp    %esi,%ecx
  sete   %r8b
L7:
  shr    $0x4,%ax
  movzwl %ax,%eax
  imul   $0xa3e,%eax,%eax
  shr    $0x10,%eax
  imul   $0x190,%eax,%eax
  cmp    %esi,%eax
  mov    $0x1,%eax
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short leapyear(yr)
unsigned short yr;
{
  unsigned short lyr = 0;
  if (yr < 100)
    yr += 1900;
  if (yr < 1000)
    yr += 2000;
  if (yr == (4 * (yr / 4)))
    lyr = 1;
  if (yr == (100 * (yr / 100)))
    lyr = 0;
  if (yr == (400 * (yr / 400)))
    lyr = 1;
  return (lyr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Truncate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <truncate@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L6
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_failure@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: truncate

assistant: ```c
void Truncate(const char *path, off_t length) {
  int retval;
  assert(path != NULL);
  retval = truncate(path, length);
  if (retval == -1)
    Sys_failure("truncate");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Truncate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <truncate@plt>
  cmp    $0xffffffff,%eax
  je     L3
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  lea    D1(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: truncate

assistant: ```c
void Truncate(const char *path, off_t length) {
  int retval;
  assert(path != NULL);
  retval = truncate(path, length);
  if (retval == -1)
    Sys_failure("truncate");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Truncate>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <truncate@plt>
  cmp    $0xffffffff,%eax
  je     L0
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <Sys_failure@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: truncate

assistant: ```c
void Truncate(const char *path, off_t length) {
  int retval;
  assert(path != NULL);
  retval = truncate(path, length);
  if (retval == -1)
    Sys_failure("truncate");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Truncate>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <truncate@plt>
  cmp    $0xffffffff,%eax
  je     L8
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <Sys_failure@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: truncate

assistant: ```c
void Truncate(const char *path, off_t length) {
  int retval;
  assert(path != NULL);
  retval = truncate(path, length);
  if (retval == -1)
    Sys_failure("truncate");
}
```
user: Translate the below assembly code into C programming language:

```asm
<getword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L13:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x20,-0x5(%rbp)
  je     L13
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isword@plt>
  test   %rax,%rax
  je     L52
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L52
L7:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L52:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    D15(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L25
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isword@plt>
  test   %rax,%rax
  jne    L7
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x4(%rbp)
  jg     L28
  mov    D15(%rip),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L35
L28:
  mov    -0x4(%rbp),%eax
L35:
  leave
  ret
```

assistant: ```c
int getword(char *s, char maxWord) {
  char c;
  int i = 0;
  while ((c = getchar()) == ' ')
    ;
  if (isword(c)) {
    *(s + i++) = c;
  }
  while ((c = getchar()) != EOF && isword(c)) {
    *(s + i++) = c;
  }
  *(s + i) = '\0';
  return i > 0 ? i : EOF;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getword>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L20:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%al
  je     L20
  movsbl %al,%edi
  call   <isword@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L14
  mov    %bl,0x0(%rbp)
  mov    $0x1,%r12d
L14:
  movslq %r12d,%r12
  jmp    L17
L36:
  mov    %bl,0x0(%rbp,%r12,1)
  add    $0x1,%r12
L17:
  mov    %r12d,%r13d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D3(%rip),%rax
  cmp    %bl,(%rax)
  je     L39
  movsbl %bl,%edi
  call   <isword@plt>
  test   %rax,%rax
  jne    L36
L39:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  test   %r13d,%r13d
  jle    L49
L12:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  mov    D3(%rip),%rax
  movsbl (%rax),%r13d
  jmp    L12
```

assistant: ```c
int getword(char *s, char maxWord) {
  char c;
  int i = 0;
  while ((c = getchar()) == ' ')
    ;
  if (isword(c)) {
    *(s + i++) = c;
  }
  while ((c = getchar()) != EOF && isword(c)) {
    *(s + i++) = c;
  }
  *(s + i) = '\0';
  return i > 0 ? i : EOF;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getword>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nop
L5:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%al
  je     L5
  movsbl %al,%edi
  xor    %r12d,%r12d
  call   <isword@plt>
  test   %rax,%rax
  je     L39
  mov    %bl,0x0(%rbp)
  mov    $0x1,%r12d
L39:
  movslq %r12d,%rax
  mov    D9(%rip),%r14
  add    %rax,%rbp
  sub    %ebp,%r12d
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl %al,%edi
  call   <isword@plt>
  test   %rax,%rax
  je     L22
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
L37:
  xor    %eax,%eax
  lea    (%r12,%rbp,1),%r13d
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %al,(%r14)
  jne    L2
L22:
  movb   $0x0,0x0(%rbp)
  test   %r13d,%r13d
  jne    L28
  movsbl (%r14),%r13d
L28:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getword(char *s, char maxWord) {
  char c;
  int i = 0;
  while ((c = getchar()) == ' ')
    ;
  if (isword(c)) {
    *(s + i++) = c;
  }
  while ((c = getchar()) != EOF && isword(c)) {
    *(s + i++) = c;
  }
  *(s + i) = '\0';
  return i > 0 ? i : EOF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getword>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nop
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%al
  je     L41
  movsbl %al,%edi
  xor    %r12d,%r12d
  call   <isword@plt>
  test   %rax,%rax
  je     L33
  mov    %bl,0x0(%rbp)
  mov    $0x1,%r12d
L33:
  movslq %r12d,%rax
  mov    D2(%rip),%r14
  add    %rax,%rbp
  sub    %ebp,%r12d
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl %al,%edi
  call   <isword@plt>
  test   %rax,%rax
  je     L56
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
L10:
  xor    %eax,%eax
  lea    (%r12,%rbp,1),%r13d
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %al,(%r14)
  jne    L9
L56:
  movb   $0x0,0x0(%rbp)
  test   %r13d,%r13d
  jne    L16
  movsbl (%r14),%r13d
L16:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getword(char *s, char maxWord) {
  char c;
  int i = 0;
  while ((c = getchar()) == ' ')
    ;
  if (isword(c)) {
    *(s + i++) = c;
  }
  while ((c = getchar()) != EOF && isword(c)) {
    *(s + i++) = c;
  }
  *(s + i) = '\0';
  return i > 0 ? i : EOF;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readInfixExpression>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char *readInfixExpression() {
  char *buff = NULL;
  ssize_t len;
  size_t buffLen = 0;
  len = getline(&buff, &buffLen, stdin);
  char *line = malloc(len);
  strncpy(line, buff, len);
  line[len - 1] = '\0';
  return line;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readInfixExpression>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  call   <getline@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    0x8(%rsp),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,-0x1(%rbp,%rbx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *readInfixExpression() {
  char *buff = NULL;
  ssize_t len;
  size_t buffLen = 0;
  len = getline(&buff, &buffLen, stdin);
  char *line = malloc(len);
  strncpy(line, buff, len);
  line[len - 1] = '\0';
  return line;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readInfixExpression>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    (%rax),%edx
  call   <getline@plt>
  movslq %eax,%rbx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *readInfixExpression() {
  char *buff = NULL;
  ssize_t len;
  size_t buffLen = 0;
  len = getline(&buff, &buffLen, stdin);
  char *line = malloc(len);
  strncpy(line, buff, len);
  line[len - 1] = '\0';
  return line;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readInfixExpression>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    (%rax),%edx
  call   <getline@plt>
  movslq %eax,%rbx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *readInfixExpression() {
  char *buff = NULL;
  ssize_t len;
  size_t buffLen = 0;
  len = getline(&buff, &buffLen, stdin);
  char *line = malloc(len);
  strncpy(line, buff, len);
  line[len - 1] = '\0';
  return line;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <t1@plt>
  mov    $0x0,%eax
  call   <t2@plt>
  mov    $0x0,%eax
  call   <t4@plt>
  mov    $0x0,%eax
  call   <t5@plt>
  mov    $0x0,%eax
  call   <t7@plt>
  mov    $0x0,%eax
  call   <t8@plt>
  mov    $0x0,%eax
  call   <t9@plt>
  mov    $0x0,%eax
  call   <t10@plt>
  mov    $0x0,%eax
  call   <t11@plt>
  mov    $0x0,%eax
  call   <t12@plt>
  mov    $0x0,%eax
  call   <t13@plt>
  mov    $0x0,%eax
  call   <t16@plt>
  mov    $0x0,%eax
  call   <t17@plt>
  mov    $0x0,%eax
  call   <t18@plt>
  mov    $0x0,%eax
  call   <t19@plt>
  mov    $0x0,%eax
  call   <t20@plt>
  mov    $0x0,%eax
  call   <t21@plt>
  mov    $0x0,%eax
  call   <t22@plt>
  mov    $0x0,%eax
  call   <t23@plt>
  mov    $0x0,%eax
  call   <t24@plt>
  mov    $0x0,%eax
  call   <t25@plt>
  mov    $0x0,%eax
  call   <t27@plt>
  mov    $0x0,%eax
  call   <t28@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  t1();
  t2();
  t4();
  t5();
  t7();
  t8();
  t9();
  t10();
  t11();
  t12();
  t13();
  t16();
  t17();
  t18();
  t19();
  t20();
  t21();
  t22();
  t23();
  t24();
  t25();
  t27();
  t28();
  return 0;
}
```