user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jle    L104
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%r13
  shr    %eax
  lea    D42(%rip),%rbx
  shl    $0x4,%rax
  lea    0x18(%rsi,%rax,1),%r12
L130:
  mov    0x0(%r13),%rdi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L106
  mov    0x8(%r13),%rdi
  add    $0x10,%r13
  call   <atoi@plt>
  mov    %eax,%ebp
  cmp    %r12,%r13
  jne    L130
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  jle    L133
L5:
  test   %ebp,%ebp
  mov    $0x1,%eax
  movslq %ebp,%rdx
  mov    %rbx,%rdi
  cmovle %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  call   <D2MCE_Mtime@plt>
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x3,%ebp
  jle    L73
  mov    $0x6,%ecx
  mov    $0x3,%edx
  jmp    L26
  nopl   (%rax)
L19:
  add    $0x2,%rdx
  add    $0x4,%ecx
  cmp    %edx,%ebp
  jle    L11
L26:
  cmpb   $0x1,(%rbx,%rdx,1)
  je     L19
  mov    %edx,%eax
  imul   %edx,%eax
  cmp    %ebp,%eax
  jg     L11
  cmp    %ebp,%ecx
  jge    L19
  movslq %ecx,%rax
  nopl   0x0(%rax)
L37:
  movb   $0x1,(%rbx,%rax,1)
  add    %rdx,%rax
  cmp    %eax,%ebp
  jg     L37
  add    $0x2,%rdx
  add    $0x4,%ecx
  cmp    %edx,%ebp
  jg     L26
L11:
  xor    %eax,%eax
  call   <D2MCE_Mtime@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %ebp,%esi
  sub    $0x4,%ebp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  shr    %ebp
  movq   %xmm0,%r12
  call   <printf@plt>
  mov    %ebp,%edx
  lea    0x3(%rbx),%rax
  mov    $0x1,%esi
  add    %rdx,%rdx
  lea    0x5(%rbx,%rdx,1),%rdx
L32:
  cmpb   $0x1,(%rax)
  adc    $0x0,%esi
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L32
L29:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movq   %r12,%xmm0
  mov    $0x1,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
L84:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L106:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L84
L104:
  mov    $0x64,%edi
  mov    $0x64,%ebp
  call   <malloc@plt>
  mov    %rax,%rbx
  jmp    L5
L133:
  xor    %eax,%eax
  call   <D2MCE_Mtime@plt>
  movsd  %xmm0,0x8(%rsp)
L73:
  xor    %eax,%eax
  call   <D2MCE_Mtime@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  movq   %xmm0,%r12
  call   <printf@plt>
  mov    $0x1,%esi
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_tag: D42
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D44
type_guessed: string
name: unpack_data
arguments: data_tag: D35
type_guessed: string
name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D42: -s

tool: D13: 
data size:%d


tool: D10: 
find prime count:%d

tool: D44: 
process time=%f


tool: D35: the argument only have:

tool: D6: -s: the size of vector ex: -s 256

assistant: ```c
int main(int argc, char *argv[]) {
  char *_n;
  int i, j, k;
  int prime = 2;
  int _number_count = 100;
  double time;
  int count = 1;
  if (argc > 1) {
    for (i = 1; i < argc;) {
      if (strcmp(argv[i], "-s") == 0) {
        _number_count = atoi(argv[i + 1]);
        i += 2;
      } else {
        printf("the argument only have:\n");
        printf("-s: the size of vector ex: -s 256\n");
        return 0;
      }
    }
  }
  _n = (char *)malloc(sizeof(char) * _number_count);
  for (i = 0; i < _number_count; i++)
    _n[i] = 0;
  time = -D2MCE_Mtime();
  for (i = 3; i < _number_count; i += 2) {
    if (_n[i] != 1) {
      prime = i;
      if (prime * prime > _number_count)
        break;
      for (j = prime + prime; j < _number_count; j += prime)
        _n[j] = 1;
    }
  }
  time += D2MCE_Mtime();
  printf("\ndata size:%d\n", _number_count);
  for (i = 3; i < _number_count; i += 2) {
    if (_n[i] == 0) {
      count++;
    }
  }
  printf("\nfind prime count:%d", count);
  printf("\nprocess time=%f\n", time);
  return 0;
}
```