ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L23
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L23:
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D36
data_type: string

tool: D8: n : 

tool: D9: %d

tool: D3: %d est un nombre premier

tool: D36: %d n'est pas un nombre premier

assistant: ```c
int main(void) {
  unsigned int n = 0;
  printf("n : ");
  scanf("%d", &n);
  if (prime(n)) {
    printf("%d est un nombre premier", n);
  } else {
    printf("%d n'est pas un nombre premier", n);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <prime@plt>
  mov    0x4(%rsp),%esi
  test   %rax,%rax
  je     L0
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L29
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D38
type: string
name: disassemble_data
arguments: label: D29
type: string
name: disassemble_data
arguments: label: D24
type: string

tool: D14: n : 

tool: D38: %d

tool: D29: %d est un nombre premier

tool: D24: %d n'est pas un nombre premier

assistant: ```c
int main(void) {
  unsigned int n = 0;
  printf("n : ");
  scanf("%d", &n);
  if (prime(n)) {
    printf("%d est un nombre premier", n);
  } else {
    printf("%d n'est pas un nombre premier", n);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <prime@plt>
  mov    0x4(%rsp),%esi
  test   %rax,%rax
  je     L23
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string

tool: D13: n : 

tool: D12: %d

tool: D30: %d est un nombre premier

tool: D21: %d n'est pas un nombre premier

assistant: ```c
int main(void) {
  unsigned int n = 0;
  printf("n : ");
  scanf("%d", &n);
  if (prime(n)) {
    printf("%d est un nombre premier", n);
  } else {
    printf("%d n'est pas un nombre premier", n);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reads>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L26
L14:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L28
  mov    -0x4(%rbp),%eax
  jmp    L29
L28:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L26:
  cmpl   $0x0,-0x8(%rbp)
  jg     L14
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int reads(int sock, char *pbuf, int noc) {
  int nreste, nlit;
  nreste = noc;
  while (nreste > 0) {
    nlit = read(sock, pbuf, nreste);
    if (nlit < 0)
      return (nlit);
    nreste -= nlit;
    pbuf += nlit;
  }
  return (noc - nreste);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reads>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L0
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
L6:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L5
  sub    %eax,%ebx
  cltq
  add    %rax,%rbp
  test   %ebx,%ebx
  jg     L6
L10:
  mov    %r13d,%eax
  sub    %ebx,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %edx,%ebx
  jmp    L10
```

assistant: ```c
int reads(int sock, char *pbuf, int noc) {
  int nreste, nlit;
  nreste = noc;
  while (nreste > 0) {
    nlit = read(sock, pbuf, nreste);
    if (nlit < 0)
      return (nlit);
    nreste -= nlit;
    pbuf += nlit;
  }
  return (noc - nreste);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reads>:
  endbr64
  test   %edx,%edx
  jle    L28
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L36
  xchg   %ax,%ax
L33:
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jle    L5
L36:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L33
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
int reads(int sock, char *pbuf, int noc) {
  int nreste, nlit;
  nreste = noc;
  while (nreste > 0) {
    nlit = read(sock, pbuf, nreste);
    if (nlit < 0)
      return (nlit);
    nreste -= nlit;
    pbuf += nlit;
  }
  return (noc - nreste);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reads>:
  endbr64
  test   %edx,%edx
  jle    L23
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L36
  xchg   %ax,%ax
L8:
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jle    L26
L36:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  mov    %r12d,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int reads(int sock, char *pbuf, int noc) {
  int nreste, nlit;
  nreste = noc;
  while (nreste > 0) {
    nlit = read(sock, pbuf, nreste);
    if (nlit < 0)
      return (nlit);
    nreste -= nlit;
    pbuf += nlit;
  }
  return (noc - nreste);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<j>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L6:
  lea    -0x10(%rbp),%rax
  mov    %rax,%r10
  call   <nest.0>
  jmp    L6
```

assistant: ```c
void j(void) {
  auto void nest(void);
l:
  nest();
  void nest(void) {
  l:
    dummy();
  }
  goto l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<j>:
  endbr64
  sub    $0x8,%rsp
L1:
  mov    $0x0,%eax
  call   <dummy@plt>
  jmp    L1
```

assistant: ```c
void j(void) {
  auto void nest(void);
l:
  nest();
  void nest(void) {
  l:
    dummy();
  }
  goto l;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<j>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <dummy@plt>
  jmp    L7
```

assistant: ```c
void j(void) {
  auto void nest(void);
l:
  nest();
  void nest(void) {
  l:
    dummy();
  }
  goto l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<j>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <dummy@plt>
  jmp    L2
```

assistant: ```c
void j(void) {
  auto void nest(void);
l:
  nest();
  void nest(void) {
  l:
    dummy();
  }
  goto l;
}
```
user: What is the c source code of the assembly code below?

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xce4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<equal_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *s1a = (char *)s1;
  char *s2a = (char *)s2;
  return (strcmp(s1a, s2a) == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<equal_string>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *s1a = (char *)s1;
  char *s2a = (char *)s2;
  return (strcmp(s1a, s2a) == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<equal_string>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *s1a = (char *)s1;
  char *s2a = (char *)s2;
  return (strcmp(s1a, s2a) == 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<equal_string>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_string(void *s1, void *s2) {
  char *s1a = (char *)s1;
  char *s2a = (char *)s2;
  return (strcmp(s1a, s2a) == 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L23
L4:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L4
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2 && tolower(*s1) == tolower(*s2); s1++, s2++)
    ;
  return tolower(*s1) - tolower(*s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L21:
  cmpb   $0x0,(%rbx)
  je     L19
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L19
  add    $0x1,%r12
  add    $0x1,%rbx
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L21
L19:
  movsbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2 && tolower(*s1) == tolower(*s2); s1++, s2++)
    ;
  return tolower(*s1) - tolower(*s2);
}
```
user: What is the c source code of the assembly code below:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  jne    L7
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L0:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L42
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbx
  test   %dil,%dil
  je     L38
L7:
  cmpb   $0x0,(%rbx)
  jne    L0
L42:
  movsbl (%r12),%edi
L38:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  pop    %rbx
  mov    %eax,%r8d
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2 && tolower(*s1) == tolower(*s2); s1++, s2++)
    ;
  return tolower(*s1) - tolower(*s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  jne    L29
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L45:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L56
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbx
  test   %dil,%dil
  je     L27
L29:
  cmpb   $0x0,(%rbx)
  jne    L45
L27:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  pop    %rbx
  mov    %eax,%r8d
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  movsbl (%r12),%edi
  jmp    L27
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2 && tolower(*s1) == tolower(*s2); s1++, s2++)
    ;
  return tolower(*s1) - tolower(*s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  xor    $0x1cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L28
L31:
  movw   $0x0,-0xe(%rbp)
  jmp    L25
L50:
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  movzwl -0xe(%rbp),%esi
  movzwl -0xc(%rbp),%edx
  shr    $0x4,%dx
  movzwl %dx,%edx
  and    $0x6,%edx
  or     $0x1,%edx
  mov    %edx,%ecx
  shl    %cl,%esi
  mov    %esi,%edx
  cmp    %edx,%eax
  je     L3
  movzwl -0xe(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%edx
  movzwl -0xe(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  movzwl -0xe(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
L3:
  addw   $0x2,-0xe(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xe(%rbp)
  jb     L50
  addw   $0x2,-0xc(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L31
  movzwl -0xa(%rbp),%eax
  or     $0xb1c6,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (!(state[0UL] == local2 << (((local1 >> (unsigned short)4) & (unsigned short)7) | 1UL))) {
          state[local2] <<= (state[local2] & (unsigned short)7) | 1UL;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 293908934UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%r11
  movzwl (%rdi),%eax
  xor    $0x1cdb,%ax
  movzwl 0x2(%rdi),%r9d
  mov    $0x0,%r10d
  test   %r9w,%r9w
  jne    L54
L58:
  or     $0xb1c6,%ax
  mov    %ax,(%r11)
  ret
L52:
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  mov    %edi,%eax
  shl    %cl,%eax
L37:
  add    $0x2,%edx
  cmp    %r9w,%dx
  jae    L24
L29:
  movzwl %ax,%edi
  movzwl %dx,%esi
  mov    %r8d,%ecx
  shl    %cl,%esi
  cmp    %esi,%edi
  jne    L52
  jmp    L37
L24:
  add    $0x2,%r10d
  cmp    %r9w,%r10w
  jae    L58
L54:
  mov    %r10d,%r8d
  shr    $0x4,%r8w
  and    $0x6,%r8d
  or     $0x1,%r8d
  mov    $0x0,%edx
  jmp    L29
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (!(state[0UL] == local2 << (((local1 >> (unsigned short)4) & (unsigned short)7) | 1UL))) {
          state[local2] <<= (state[local2] & (unsigned short)7) | 1UL;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 293908934UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%r9d
  mov    %rsi,%r11
  xor    %r10d,%r10d
  xor    $0x1cdb,%ax
  test   %r9w,%r9w
  je     L11
  nopl   0x0(%rax)
L31:
  mov    %r10d,%r8d
  xor    %edx,%edx
  shr    $0x4,%r8w
  and    $0x6,%r8d
  or     $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L22:
  movzwl %dx,%esi
  mov    %r8d,%ecx
  movzwl %ax,%edi
  shl    %cl,%esi
  cmp    %esi,%edi
  je     L2
  mov    %eax,%ecx
  mov    %edi,%eax
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
L2:
  add    $0x2,%edx
  cmp    %r9w,%dx
  jb     L22
  add    $0x2,%r10d
  cmp    %r9w,%r10w
  jb     L31
L11:
  or     $0xb1c6,%ax
  mov    %ax,(%r11)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (!(state[0UL] == local2 << (((local1 >> (unsigned short)4) & (unsigned short)7) | 1UL))) {
          state[local2] <<= (state[local2] & (unsigned short)7) | 1UL;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 293908934UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%r9d
  mov    %rsi,%r11
  xor    $0x1cdb,%ax
  test   %r9w,%r9w
  je     L32
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L30:
  mov    %r10d,%r8d
  xor    %edx,%edx
  shr    $0x4,%r8w
  and    $0x6,%r8d
  or     $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L12:
  movzwl %dx,%esi
  mov    %r8d,%ecx
  movzwl %ax,%edi
  shl    %cl,%esi
  cmp    %esi,%edi
  je     L28
  mov    %eax,%ecx
  mov    %edi,%eax
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
L28:
  add    $0x2,%edx
  cmp    %dx,%r9w
  ja     L12
  add    $0x2,%r10d
  cmp    %r10w,%r9w
  ja     L30
L32:
  or     $0xb1c6,%ax
  mov    %ax,(%r11)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (!(state[0UL] == local2 << (((local1 >> (unsigned short)4) & (unsigned short)7) | 1UL))) {
          state[local2] <<= (state[local2] & (unsigned short)7) | 1UL;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 293908934UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arrkeys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getch@plt>
  cmp    $0x105,%eax
  je     L105
  cmp    $0x105,%eax
  jg     L12
  cmp    $0x104,%eax
  je     L126
  cmp    $0x104,%eax
  jg     L12
  cmp    $0x103,%eax
  je     L154
  cmp    $0x103,%eax
  jg     L12
  cmp    $0x102,%eax
  je     L82
  cmp    $0x102,%eax
  jg     L12
  cmp    $0xa,%eax
  je     L125
  cmp    $0x1b,%eax
  je     L0
  jmp    L12
L154:
  mov    $0x75,%eax
  jmp    L31
L105:
  mov    $0x72,%eax
  jmp    L31
L126:
  mov    $0x6c,%eax
  jmp    L31
L82:
  mov    $0x64,%eax
  jmp    L31
L125:
  mov    $0x71,%eax
  jmp    L31
L0:
  mov    $0x78,%eax
  jmp    L31
L12:
  mov    $0x65,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char arrkeys() {
  switch (getch()) {
  case 259:
    return 'u';
    break;
  case 261:
    return 'r';
    break;
  case 260:
    return 'l';
    break;
  case 258:
    return 'd';
    break;
  case 10:
    return 'q';
    break;
  case 27:
    return 'x';
    break;
  default:
    return 'e';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<arrkeys>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getch@plt>
  cmp    $0x103,%eax
  je     L9
  mov    %eax,%edx
  jg     L57
  mov    $0x78,%eax
  cmp    $0x1b,%edx
  je     L63
  mov    $0x64,%eax
  cmp    $0x102,%edx
  je     L63
  cmp    $0xa,%edx
  mov    $0x65,%eax
  mov    $0x71,%edx
  cmove  %edx,%eax
L63:
  add    $0x8,%rsp
  ret
L57:
  mov    $0x6c,%eax
  cmp    $0x104,%edx
  je     L63
  cmp    $0x105,%edx
  mov    $0x65,%eax
  mov    $0x72,%edx
  cmove  %edx,%eax
  jmp    L63
L9:
  mov    $0x75,%eax
  jmp    L63
```

assistant: ```c
char arrkeys() {
  switch (getch()) {
  case 259:
    return 'u';
    break;
  case 261:
    return 'r';
    break;
  case 260:
    return 'l';
    break;
  case 258:
    return 'd';
    break;
  case 10:
    return 'q';
    break;
  case 27:
    return 'x';
    break;
  default:
    return 'e';
  }
}
```