user: 这段汇编代码用C语言表示是什么样的?

```asm
<uphipbs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x40(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    -0x40(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    -0x40(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L83
L46:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L119
L74:
  mov    -0x3c(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L69:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jge    L74
  jmp    L71
L75:
  mov    -0x3c(%rbp),%eax
  add    %eax,-0x1c(%rbp)
L71:
  cmpl   $0x0,-0x1c(%rbp)
  js     L75
  mov    -0x20(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L119:
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L69
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L58
L113:
  mov    -0x3c(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jge    L113
  jmp    L0
L16:
  mov    -0x3c(%rbp),%eax
  add    %eax,-0x1c(%rbp)
L0:
  cmpl   $0x0,-0x1c(%rbp)
  js     L16
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L58:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L7
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L83:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L46
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uphipbs(x, n, hpf, m, y) double x[], hpf[], y[];
int n, m;
{
  int meven, modd, pos, i, h, j, k;
  double s;
  meven = (m + 1) / 2;
  modd = m / 2;
  k = meven + 2 * n - m;
  j = (int)(k / 2);
  pos = k - 2 * j;
  k = j;
  for (i = 0; i < n; i++) {
    s = 0;
    j = k + pos;
    for (h = 0; h < meven - pos; h++) {
      while (j >= n)
        j -= n;
      while (j < 0)
        j += n;
      s += hpf[2 * h + pos] * x[j];
      j++;
    }
    y[2 * i + 1] = s;
    s = 0;
    j = k;
    for (h = 0; h < modd + pos; h++) {
      while (j >= n)
        j -= n;
      while (j < 0)
        j += n;
      s += hpf[2 * h + 1 - pos] * x[j];
      j++;
    }
    y[2 * i] = s;
    k++;
  }
}
```