ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<longestPalindrome>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,0x0(%r13)
  je     L53
  mov    %eax,%ebp
  cmp    $0x1,%eax
  je     L39
  mov    %r13,%rbx
  xor    %r12d,%r12d
  mov    $0x1,%r14d
  xor    %r15d,%r15d
  jmp    L78
  nopl   0x0(%rax)
L25:
  lea    (%r14,%r12,1),%eax
  cmp    %ebp,%eax
  je     L61
L78:
  mov    %ebp,%esi
  mov    %r14d,%edx
  mov    %rbx,%rdi
  sub    %r15d,%esi
  call   <getCurLongestPalindrom@plt>
  cmp    %r14d,%eax
  jle    L12
  movslq %r15d,%r12
  mov    %eax,%r14d
L12:
  add    $0x1,%rbx
  add    $0x1,%r15d
  cmpb   $0x0,(%rbx)
  jne    L25
L61:
  lea    0x1(%r14),%edi
  add    %r12,%r13
  movslq %r14d,%rbx
L28:
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  mov    $0x1,%ebx
  mov    $0x2,%edi
  mov    $0x1,%r14d
  jmp    L28
L39:
  mov    $0x1,%r14d
  mov    $0x1,%ebx
  mov    $0x2,%edi
  jmp    L28
```

assistant: ```c
char *longestPalindrome(char *s) {
  int i = 0;
  int lmax = 1;
  int imax = 0;
  int tmax = 0;
  int length = strlen(s);
  while (s[i] != '\0') {
    if (imax + lmax == length)
      break;
    tmax = getCurLongestPalindrom(&(s[i]), length - i, lmax);
    if (tmax > lmax) {
      lmax = tmax;
      imax = i;
    }
    i++;
  }
  char *p = (char *)malloc((lmax + 1) * sizeof(char));
  memmove(p, s + imax, lmax);
  p[lmax] = '\0';
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_semaphore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <osd_getkey@plt>
  mov    %rax,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  lea    0x1e8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <semget@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L12
  mov    $0x0,%eax
  jmp    L11
L12:
  mov    -0xc(%rbp),%eax
L11:
  leave
  ret
```

assistant: ```c
int create_semaphore(char *name) {
  int status;
  key_t key;
  key = (key_t)osd_getkey(name);
  status = semget(key, 4, 0750 + IPC_CREAT);
  if (status < 0)
    return (0);
  return status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<create_semaphore>:
  endbr64
  sub    $0x8,%rsp
  call   <osd_getkey@plt>
  mov    %rax,%rdi
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  add    $0x1e8,%rdx
  mov    $0x4,%esi
  call   <semget@plt>
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int create_semaphore(char *name) {
  int status;
  key_t key;
  key = (key_t)osd_getkey(name);
  status = semget(key, 4, 0750 + IPC_CREAT);
  if (status < 0)
    return (0);
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<create_semaphore>:
  endbr64
  sub    $0x8,%rsp
  call   <osd_getkey@plt>
  mov    $0x4,%esi
  mov    %rax,%rdi
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  add    $0x1e8,%rdx
  call   <semget@plt>
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int create_semaphore(char *name) {
  int status;
  key_t key;
  key = (key_t)osd_getkey(name);
  status = semget(key, 4, 0750 + IPC_CREAT);
  if (status < 0)
    return (0);
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<create_semaphore>:
  endbr64
  sub    $0x8,%rsp
  call   <osd_getkey@plt>
  mov    $0x4,%esi
  mov    %rax,%rdi
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  add    $0x1e8,%rdx
  call   <semget@plt>
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int create_semaphore(char *name) {
  int status;
  key_t key;
  key = (key_t)osd_getkey(name);
  status = semget(key, 4, 0750 + IPC_CREAT);
  if (status < 0)
    return (0);
  return status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yp_update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <yp_master@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L17
  mov    -0x14(%rbp),%eax
  jmp    L4
L17:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_free@plt>
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int yp_update(void) {
  char *master;
  int r;
  if ((r = yp_master(&master)) != 0)
    return r;
  __builtin_free(master);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yp_update>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <yp_master@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L28
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  mov    (%rsp),%rdi
  call   <__builtin_free@plt>
  jmp    L27
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yp_update(void) {
  char *master;
  int r;
  if ((r = yp_master(&master)) != 0)
    return r;
  __builtin_free(master);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yp_update>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <yp_master@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L5
  mov    (%rsp),%rdi
  call   <__builtin_free@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yp_update(void) {
  char *master;
  int r;
  if ((r = yp_master(&master)) != 0)
    return r;
  __builtin_free(master);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<yp_update>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <yp_master@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L13
  mov    (%rsp),%rdi
  call   <__builtin_free@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yp_update(void) {
  char *master;
  int r;
  if ((r = yp_master(&master)) != 0)
    return r;
  __builtin_free(master);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <exponenciar@plt>
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D35
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D46
type_guessed: string

tool: D35: Insira o valor de X: 

tool: D27: %d

tool: D18: Insira o valor de Z: 

tool: D46: X: %d ^ %d :Z = %d


assistant: ```c
int main() {
  int X, Z;
  printf("Insira o valor de X: ");
  scanf("%d", &X);
  printf("Insira o valor de Z: ");
  scanf("%d", &Z);
  printf("X: %d ^ %d :Z = %d\n", X, Z, exponenciar(X, Z));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D27(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <exponenciar@plt>
  mov    %eax,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D27
type_infered: string
name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D4: Insira o valor de X: 

tool: D27: %d

tool: D24: Insira o valor de Z: 

tool: D9: X: %d ^ %d :Z = %d


assistant: ```c
int main() {
  int X, Z;
  printf("Insira o valor de X: ");
  scanf("%d", &X);
  printf("Insira o valor de Z: ");
  scanf("%d", &Z);
  printf("X: %d ^ %d :Z = %d\n", X, Z, exponenciar(X, Z));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  lea    D20(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <exponenciar@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D5(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D20
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D18: Insira o valor de X: 

tool: D20: %d

tool: D24: Insira o valor de Z: 

tool: D5: X: %d ^ %d :Z = %d


assistant: ```c
int main() {
  int X, Z;
  printf("Insira o valor de X: ");
  scanf("%d", &X);
  printf("Insira o valor de Z: ");
  scanf("%d", &Z);
  printf("X: %d ^ %d :Z = %d\n", X, Z, exponenciar(X, Z));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  lea    D36(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <exponenciar@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D0(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D36
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D0
type_infered: string

tool: D13: Insira o valor de X: 

tool: D36: %d

tool: D25: Insira o valor de Z: 

tool: D0: X: %d ^ %d :Z = %d


assistant: ```c
int main() {
  int X, Z;
  printf("Insira o valor de X: ");
  scanf("%d", &X);
  printf("Insira o valor de Z: ");
  scanf("%d", &Z);
  printf("X: %d ^ %d :Z = %d\n", X, Z, exponenciar(X, Z));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fillArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void fillArray(int arr[], int arrSize) {
  int i = 0;
  for (i = 0; i < arrSize; i++) {
    arr[i] = rand();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fillArray>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L16:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

assistant: ```c
void fillArray(int arr[], int arrSize) {
  int i = 0;
  for (i = 0; i < arrSize; i++) {
    arr[i] = rand();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fillArray>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void fillArray(int arr[], int arrSize) {
  int i = 0;
  for (i = 0; i < arrSize; i++) {
    arr[i] = rand();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fillArray>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void fillArray(int arr[], int arrSize) {
  int i = 0;
  for (i = 0; i < arrSize; i++) {
    arr[i] = rand();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heap_sortv_ui>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1,%esi
  jbe    L148
  mov    %esi,%edi
  mov    $0x1,%r11d
  jmp    L44
L118:
  mov    %r10d,(%r8)
L57:
  add    $0x1,%r11
  cmp    %rdi,%r11
  je     L1
L44:
  mov    %r11d,%edx
  mov    (%rcx,%r11,4),%r10d
  lea    -0x1(%r11),%eax
  shr    %eax
  mov    %eax,%r8d
  cmp    %r10d,(%rcx,%r8,4)
  jae    L57
L88:
  mov    %eax,%r8d
  lea    (%rcx,%r8,4),%r8
  mov    (%r8),%r9d
  mov    %edx,%edx
  mov    %r9d,(%rcx,%rdx,4)
  lea    -0x1(%rax),%r9d
  mov    %eax,%edx
  mov    %r9d,%eax
  shr    %eax
  test   %edx,%edx
  je     L118
  mov    %eax,%r9d
  cmp    %r10d,(%rcx,%r9,4)
  jb     L88
  jmp    L118
L148:
  mov    %esi,%edi
  sub    $0x1,%edi
  jne    L52
  ret
L74:
  cmp    %edi,%esi
  jae    L97
L156:
  mov    %esi,%eax
  mov    (%rcx,%rax,4),%eax
  cmp    %r9d,%eax
  jbe    L97
  mov    %edx,%edx
  mov    %eax,(%rcx,%rdx,4)
  mov    %esi,%edx
L122:
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rax),%esi
  add    $0x2,%eax
  cmp    %edi,%eax
  jae    L74
  mov    %esi,%r8d
  mov    %eax,%r10d
  mov    (%rcx,%r10,4),%r10d
  cmp    %r10d,(%rcx,%r8,4)
  jae    L74
  mov    %eax,%esi
  jmp    L156
L97:
  mov    %edx,%edx
  mov    %r9d,(%rcx,%rdx,4)
  sub    $0x1,%edi
  je     L66
L50:
  mov    %edi,%eax
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%r9d
  mov    (%rcx),%edx
  mov    %edx,(%rax)
  mov    %r11d,%edx
  jmp    L122
L66:
  ret
L1:
  lea    -0x1(%rsi),%edi
L52:
  mov    $0x0,%r11d
  jmp    L50
```

assistant: ```c
void heap_sortv_ui(unsigned int *const restrict A, unsigned n) {
  unsigned i;
  for (i = 1; i < n; ++i) {
    unsigned int item = A[i];
    unsigned h = i, p = (h - 1) >> 1;
    if (A[p] >= item)
      continue;
    do
      A[h] = A[p], h = p, p = (p - 1) >> 1;
    while (h && A[p] < item);
    A[h] = item;
  }
  for (i = n - 1; i; --i) {
    unsigned int item = A[i];
    unsigned h = 0;
    A[i] = A[0];
    for (;;) {
      unsigned ch = 1 + (h << 1), r = ch + 1;
      if (r < i && A[ch] < A[r])
        ch = r;
      if (ch >= i || item >= A[ch])
        break;
      A[h] = A[ch], h = ch;
    }
    A[h] = item;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heap_sortv_ui>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jbe    L90
  mov    %esi,%r10d
  mov    $0x1,%r9d
  nopl   (%rax)
L18:
  lea    -0x1(%r9),%edx
  mov    (%rcx,%r9,4),%edi
  mov    %r9d,%eax
  shr    %edx
  mov    %edx,%esi
  mov    (%rcx,%rsi,4),%esi
  cmp    %edi,%esi
  jb     L64
  add    $0x1,%r9
  cmp    %r9,%r10
  jne    L18
  nop
L96:
  mov    (%rcx),%edx
  mov    %r8d,%eax
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%r9d
  mov    %edx,(%rax)
  xor    %edx,%edx
  jmp    L108
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %eax,%edi
  mov    %esi,%r10d
  mov    (%rcx,%rdi,4),%edi
  cmp    %edi,(%rcx,%r10,4)
  jae    L30
  mov    %eax,%esi
  lea    (%rcx,%rdx,4),%rax
  cmp    %edi,%r9d
  jae    L42
L21:
  mov    %edi,(%rax)
  mov    %esi,%edx
L108:
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rax),%esi
  add    $0x2,%eax
  cmp    %r8d,%eax
  jb     L47
L30:
  cmp    %r8d,%esi
  jae    L42
  mov    %esi,%eax
  mov    (%rcx,%rax,4),%edi
  lea    (%rcx,%rdx,4),%rax
  cmp    %edi,%r9d
  jb     L21
L42:
  mov    %r9d,(%rcx,%rdx,4)
  sub    $0x1,%r8d
  jne    L96
  ret
  nopl   0x0(%rax)
L109:
  mov    %edx,%esi
  mov    (%rcx,%rsi,4),%esi
  cmp    %edi,%esi
  jae    L132
L64:
  mov    %esi,(%rcx,%rax,4)
  lea    -0x1(%rdx),%esi
  mov    %edx,%eax
  mov    %esi,%edx
  shr    %edx
  test   %eax,%eax
  jne    L109
L132:
  add    $0x1,%r9
  mov    %edi,(%rcx,%rax,4)
  cmp    %r9,%r10
  jne    L18
  jmp    L96
L90:
  test   %r8d,%r8d
  jne    L96
  ret
```

assistant: ```c
void heap_sortv_ui(unsigned int *const restrict A, unsigned n) {
  unsigned i;
  for (i = 1; i < n; ++i) {
    unsigned int item = A[i];
    unsigned h = i, p = (h - 1) >> 1;
    if (A[p] >= item)
      continue;
    do
      A[h] = A[p], h = p, p = (p - 1) >> 1;
    while (h && A[p] < item);
    A[h] = item;
  }
  for (i = n - 1; i; --i) {
    unsigned int item = A[i];
    unsigned h = 0;
    A[i] = A[0];
    for (;;) {
      unsigned ch = 1 + (h << 1), r = ch + 1;
      if (r < i && A[ch] < A[r])
        ch = r;
      if (ch >= i || item >= A[ch])
        break;
      A[h] = A[ch], h = ch;
    }
    A[h] = item;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heap_sortv_ui>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jbe    L114
  mov    %esi,%r10d
  mov    $0x1,%r9d
  nopl   (%rax)
L76:
  lea    -0x1(%r9),%edx
  mov    (%rcx,%r9,4),%edi
  mov    %r9d,%eax
  shr    %edx
  mov    %edx,%esi
  mov    (%rcx,%rsi,4),%esi
  cmp    %edi,%esi
  jb     L136
  add    $0x1,%r9
  cmp    %r9,%r10
  jne    L76
  nop
L110:
  mov    (%rcx),%edx
  mov    %r8d,%eax
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%r9d
  mov    %edx,(%rax)
  xor    %edx,%edx
  jmp    L145
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %eax,%edi
  mov    %esi,%r10d
  mov    (%rcx,%rdi,4),%edi
  cmp    %edi,(%rcx,%r10,4)
  jae    L92
  mov    %eax,%esi
  lea    (%rcx,%rdx,4),%rax
  cmp    %edi,%r9d
  jae    L54
L125:
  mov    %edi,(%rax)
  mov    %esi,%edx
L145:
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rax),%esi
  add    $0x2,%eax
  cmp    %r8d,%eax
  jb     L22
L92:
  cmp    %r8d,%esi
  jae    L54
  mov    %esi,%eax
  mov    (%rcx,%rax,4),%edi
  lea    (%rcx,%rdx,4),%rax
  cmp    %edi,%r9d
  jb     L125
L54:
  mov    %r9d,(%rcx,%rdx,4)
  sub    $0x1,%r8d
  jne    L110
  ret
  nopl   0x0(%rax)
L62:
  mov    %edx,%esi
  mov    (%rcx,%rsi,4),%esi
  cmp    %edi,%esi
  jae    L100
L136:
  mov    %esi,(%rcx,%rax,4)
  lea    -0x1(%rdx),%esi
  mov    %edx,%eax
  mov    %esi,%edx
  shr    %edx
  test   %eax,%eax
  jne    L62
L100:
  add    $0x1,%r9
  mov    %edi,(%rcx,%rax,4)
  cmp    %r9,%r10
  jne    L76
  jmp    L110
L114:
  test   %r8d,%r8d
  jne    L110
  ret
```

assistant: ```c
void heap_sortv_ui(unsigned int *const restrict A, unsigned n) {
  unsigned i;
  for (i = 1; i < n; ++i) {
    unsigned int item = A[i];
    unsigned h = i, p = (h - 1) >> 1;
    if (A[p] >= item)
      continue;
    do
      A[h] = A[p], h = p, p = (p - 1) >> 1;
    while (h && A[p] < item);
    A[h] = item;
  }
  for (i = n - 1; i; --i) {
    unsigned int item = A[i];
    unsigned h = 0;
    A[i] = A[0];
    for (;;) {
      unsigned ch = 1 + (h << 1), r = ch + 1;
      if (r < i && A[ch] < A[r])
        ch = r;
      if (ch >= i || item >= A[ch])
        break;
      A[h] = A[ch], h = ch;
    }
    A[h] = item;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <print_welcome@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <parse_args@plt>
  test   %rax,%rax
  je     L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <print_usage@plt>
  mov    $0x1,%eax
  jmp    L9
L10:
  mov    $0x0,%edi
  call   <search@plt>
  mov    $0x1,%edi
  call   <search@plt>
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  print_welcome(stdout);
  if (parse_args(argc, argv)) {
    print_usage(argv);
    return 1;
  }
  search(0);
  search(1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <print_welcome@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <parse_args@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x0,%edi
  call   <search@plt>
  mov    $0x1,%edi
  call   <search@plt>
  mov    $0x0,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rbx,%rdi
  call   <print_usage@plt>
  mov    $0x1,%eax
  jmp    L2
```

assistant: ```c
int main(int argc, char **argv) {
  print_welcome(stdout);
  if (parse_args(argc, argv)) {
    print_usage(argv);
    return 1;
  }
  search(0);
  search(1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <print_welcome@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <parse_args@plt>
  test   %rax,%rax
  jne    L18
  xor    %edi,%edi
  call   <search@plt>
  mov    $0x1,%edi
  call   <search@plt>
  xor    %eax,%eax
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbp,%rdi
  call   <print_usage@plt>
  mov    $0x1,%eax
  jmp    L0
```

assistant: ```c
int main(int argc, char **argv) {
  print_welcome(stdout);
  if (parse_args(argc, argv)) {
    print_usage(argv);
    return 1;
  }
  search(0);
  search(1);
  return 0;
}
```