ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<path_length>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rsi
  call   <strpbrk_or_eos@plt>
  sub    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: ?;#

assistant: ```c
int path_length(const char *url) {
  const char *q = strpbrk_or_eos(url, "?;#");
  return q - url;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_length>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rsi
  mov    %rdi,%rbx
  call   <strpbrk_or_eos@plt>
  sub    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: ?;#

assistant: ```c
int path_length(const char *url) {
  const char *q = strpbrk_or_eos(url, "?;#");
  return q - url;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<path_length>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rsi
  mov    %rdi,%rbx
  call   <strpbrk_or_eos@plt>
  sub    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: ?;#

assistant: ```c
int path_length(const char *url) {
  const char *q = strpbrk_or_eos(url, "?;#");
  return q - url;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_k_closest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,0xc(%rsp)
  mov    %ecx,%r14d
  lea    -0x1(%rsi),%r13d
  mov    %edx,%ecx
  mov    %r13d,%edx
  mov    $0x0,%esi
  call   <get_index@plt>
  test   %eax,%eax
  mov    $0x1,%edx
  cmovg  %eax,%edx
  lea    -0x1(%rdx),%ebx
  cmp    %eax,%r13d
  jle    L47
  lea    0x1(%rax),%ebp
  cmp    %ebp,%r13d
  jle    L116
  test   %ebx,%ebx
  jle    L116
  cltq
  lea    (%r12,%rax,4),%r15
  jmp    L188
L54:
  add    $0x1,%ebp
L103:
  cmp    %ebp,%r13d
  jle    L116
  test   %ebx,%ebx
  jle    L116
L188:
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%edi
  sub    (%r15),%edi
  call   <abs@plt>
  mov    %rax,(%rsp)
  movslq %ebp,%rax
  mov    (%r12,%rax,4),%edi
  sub    (%r15),%edi
  call   <abs@plt>
  cmp    %rax,(%rsp)
  jge    L54
  sub    $0x1,%ebx
  jmp    L103
L116:
  mov    %ebp,%eax
  sub    %ebx,%eax
  test   %ebx,%ebx
  jle    L6
  cmp    %r14d,%eax
  jge    L6
L78:
  sub    $0x1,%ebx
  add    $0x1,%eax
  test   %ebx,%ebx
  jle    L6
  cmp    %eax,%r14d
  jg     L78
L6:
  cmp    %eax,%r14d
  jle    L183
  cmp    %ebp,%r13d
  jle    L183
  mov    %ebp,%r15d
L107:
  add    $0x1,%r15d
  mov    %r15d,%edx
  sub    %ebp,%edx
  add    %eax,%edx
  cmp    %edx,%r14d
  jle    L148
  cmp    %r15d,%r13d
  jg     L107
L148:
  test   %ebx,%ebx
  js     L74
  cmp    %r15d,0xc(%rsp)
  jle    L74
L210:
  cmp    %r15d,%ebx
  jg     L212
  movslq %ebx,%rbx
  lea    D0(%rip),%rbp
L120:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jge    L120
L212:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L183:
  mov    %ebp,%r15d
  jmp    L148
L74:
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L210
L47:
  mov    0xc(%rsp),%eax
  sub    %edx,%eax
  test   %ebx,%ebx
  jle    L41
  mov    %r13d,%ebp
  cmp    %r14d,%eax
  jl     L78
L41:
  mov    %r13d,%r15d
  jmp    L148
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D0: %d 

tool: D13: error

assistant: ```c
void find_k_closest(int a[], int len, int x, int k) {
  int index = get_index(a, 0, len - 1, x);
  int left = (index > 0) ? (index - 1) : 0;
  int right = (index < len - 1) ? index + 1 : len - 1;
  while (left > 0 && right < len - 1) {
    if (abs(a[left] - a[index]) < abs(a[right] - a[index])) {
      left--;
    } else {
      right++;
    }
  }
  int count = right - left;
  while (left > 0 && count < k) {
    left--;
    count++;
  }
  while (right < len - 1 && count < k) {
    right++;
    count++;
  }
  if (left < 0 || right > len - 1) {
    printf("error");
  }
  for (int i = left; i <= right; i++) {
    printf("%d ", a[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_k_closest>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  mov    %edx,%ecx
  mov    %r15d,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  xor    %esi,%esi
  call   <get_index@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  cmovg  %eax,%edx
  sub    $0x1,%edx
  cmp    %eax,%r15d
  jle    L35
  lea    0x1(%rax),%ebx
  test   %edx,%edx
  je     L218
  cmp    %ebx,%r15d
  jle    L29
  cltq
  lea    (%r12,%rax,4),%r14
  jmp    L126
  nopw   0x0(%rax,%rax,1)
L114:
  sub    $0x1,%edx
  je     L218
  cmp    %ebx,%r15d
  jle    L29
L126:
  movslq %edx,%rax
  mov    %edx,0x8(%rsp)
  mov    (%r12,%rax,4),%edi
  sub    (%r14),%edi
  call   <abs@plt>
  mov    %rax,%rbp
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%edi
  sub    (%r14),%edi
  call   <abs@plt>
  mov    0x8(%rsp),%edx
  cmp    %rax,%rbp
  jl     L114
  add    $0x1,%ebx
  cmp    %ebx,%r15d
  jg     L126
L29:
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    %r13d,%eax
  jge    L183
  nopl   0x0(%rax)
L225:
  add    $0x1,%eax
  sub    $0x1,%edx
  cmp    %eax,%r13d
  setg   %cl
  test   %edx,%edx
  jle    L72
  test   %cl,%cl
  jne    L225
L72:
  mov    %ebx,%ebp
  cmp    %ebx,%r15d
  jle    L36
  test   %cl,%cl
  jne    L121
  jmp    L36
  nopl   0x0(%rax)
L81:
  cmp    %ecx,%r13d
  jle    L36
L121:
  add    $0x1,%ebp
  lea    0x0(%rbp,%rax,1),%ecx
  sub    %ebx,%ecx
  cmp    %ebp,%r15d
  jg     L81
L36:
  cmp    %ebp,0xc(%rsp)
  jle    L30
L146:
  movslq %edx,%rbx
  lea    D1(%rip),%r13
  cmp    %edx,%ebp
  jl     L61
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L31
L61:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L35:
  mov    %r15d,%ebx
  test   %edx,%edx
  jne    L29
L218:
  cmp    %ebx,%r13d
  mov    %ebx,%eax
  setg   %cl
  xor    %edx,%edx
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L30:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  mov    %edx,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%edx
  jmp    L146
L183:
  mov    %ebx,%ebp
  jmp    L36
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D1: %d 

tool: D6: error

assistant: ```c
void find_k_closest(int a[], int len, int x, int k) {
  int index = get_index(a, 0, len - 1, x);
  int left = (index > 0) ? (index - 1) : 0;
  int right = (index < len - 1) ? index + 1 : len - 1;
  while (left > 0 && right < len - 1) {
    if (abs(a[left] - a[index]) < abs(a[right] - a[index])) {
      left--;
    } else {
      right++;
    }
  }
  int count = right - left;
  while (left > 0 && count < k) {
    left--;
    count++;
  }
  while (right < len - 1 && count < k) {
    right++;
    count++;
  }
  if (left < 0 || right > len - 1) {
    printf("error");
  }
  for (int i = left; i <= right; i++) {
    printf("%d ", a[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<find_k_closest>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  mov    %edx,%ecx
  mov    %r15d,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  xor    %esi,%esi
  call   <get_index@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  cmovg  %eax,%edx
  sub    $0x1,%edx
  cmp    %eax,%r15d
  jle    L80
  lea    0x1(%rax),%ebx
  test   %edx,%edx
  je     L24
  cmp    %ebx,%r15d
  jle    L73
  cltq
  lea    (%r12,%rax,4),%r14
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L47:
  sub    $0x1,%edx
  je     L24
  cmp    %ebx,%r15d
  jle    L73
L8:
  movslq %edx,%rax
  mov    %edx,0x8(%rsp)
  mov    (%r12,%rax,4),%edi
  sub    (%r14),%edi
  call   <abs@plt>
  mov    %rax,%rbp
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%edi
  sub    (%r14),%edi
  call   <abs@plt>
  mov    0x8(%rsp),%edx
  cmp    %rax,%rbp
  jl     L47
  add    $0x1,%ebx
  cmp    %ebx,%r15d
  jg     L8
L73:
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    %r13d,%eax
  jge    L172
  nopl   0x0(%rax)
L59:
  add    $0x1,%eax
  sub    $0x1,%edx
  cmp    %eax,%r13d
  setg   %cl
  test   %edx,%edx
  jle    L50
  test   %cl,%cl
  jne    L59
L50:
  mov    %ebx,%ebp
  cmp    %ebx,%r15d
  jle    L223
  test   %cl,%cl
  jne    L38
  jmp    L223
  nopl   0x0(%rax)
L63:
  cmp    %ecx,%r13d
  jle    L223
L38:
  add    $0x1,%ebp
  lea    0x0(%rbp,%rax,1),%ecx
  sub    %ebx,%ecx
  cmp    %ebp,%r15d
  jg     L63
L223:
  cmp    %ebp,0xc(%rsp)
  jle    L228
L62:
  movslq %edx,%rbx
  lea    D17(%rip),%r13
  cmp    %edx,%ebp
  jl     L71
  nopw   0x0(%rax,%rax,1)
L207:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L207
L71:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L80:
  mov    %r15d,%ebx
  test   %edx,%edx
  jne    L73
L24:
  cmp    %ebx,%r13d
  mov    %ebx,%eax
  setg   %cl
  xor    %edx,%edx
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L228:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  mov    %edx,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%edx
  jmp    L62
L172:
  mov    %ebx,%ebp
  jmp    L223
```

tool_calls: name: disassemble_data
arguments: data_label: D17
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D17: %d 

tool: D13: error

assistant: ```c
void find_k_closest(int a[], int len, int x, int k) {
  int index = get_index(a, 0, len - 1, x);
  int left = (index > 0) ? (index - 1) : 0;
  int right = (index < len - 1) ? index + 1 : len - 1;
  while (left > 0 && right < len - 1) {
    if (abs(a[left] - a[index]) < abs(a[right] - a[index])) {
      left--;
    } else {
      right++;
    }
  }
  int count = right - left;
  while (left > 0 && count < k) {
    left--;
    count++;
  }
  while (right < len - 1 && count < k) {
    right++;
    count++;
  }
  if (left < 0 || right > len - 1) {
    printf("error");
  }
  for (int i = left; i <= right; i++) {
    printf("%d ", a[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next_ch@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next_tok@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_prog@plt>
  leave
  ret
```

assistant: ```c
int parse(struct parse_ctx *pctx) {
  next_ch(pctx);
  next_tok(pctx);
  return parse_prog(pctx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <next_ch@plt>
  mov    %rbx,%rdi
  call   <next_tok@plt>
  mov    %rbx,%rdi
  call   <parse_prog@plt>
  pop    %rbx
  ret
```

assistant: ```c
int parse(struct parse_ctx *pctx) {
  next_ch(pctx);
  next_tok(pctx);
  return parse_prog(pctx);
}
```
user: What is the c source code of the assembly code below?

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <next_ch@plt>
  mov    %rbp,%rdi
  call   <next_tok@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <parse_prog@plt>
```

assistant: ```c
int parse(struct parse_ctx *pctx) {
  next_ch(pctx);
  next_tok(pctx);
  return parse_prog(pctx);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <next_ch@plt>
  mov    %rbp,%rdi
  call   <next_tok@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <parse_prog@plt>
```

assistant: ```c
int parse(struct parse_ctx *pctx) {
  next_ch(pctx);
  next_tok(pctx);
  return parse_prog(pctx);
}
```
user: What is the c source code of the assembly code below:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  size_t offset = strlen(dst);
  strcpy(dst + offset, src);
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  size_t offset = strlen(dst);
  strcpy(dst + offset, src);
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  size_t offset = strlen(dst);
  strcpy(dst + offset, src);
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  size_t offset = strlen(dst);
  strcpy(dst + offset, src);
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <quicksort@plt>
  mov    $0x0,%eax
  call   <print_array@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argv, char *argc[]) {
  quicksort(0, 8);
  print_array();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <quicksort@plt>
  mov    $0x0,%eax
  call   <print_array@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argv, char *argc[]) {
  quicksort(0, 8);
  print_array();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  xor    %edi,%edi
  call   <quicksort@plt>
  xor    %eax,%eax
  call   <print_array@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argv, char *argc[]) {
  quicksort(0, 8);
  print_array();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  xor    %edi,%edi
  call   <quicksort@plt>
  xor    %eax,%eax
  call   <print_array@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argv, char *argc[]) {
  quicksort(0, 8);
  print_array();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<detcoef2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %r8,%r14
  mov    %r9d,%r13d
  lea    0x0(,%r9,4),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rax,%r8
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rdx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <matrix_locate@plt>
  lea    D13(%rip),%rsi
  mov    0x58(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L48
  mov    %r13d,%eax
  sub    0x50(%rsp),%eax
  cltq
  mov    (%rsp),%rdi
  mov    (%rdi,%rax,4),%r12d
L48:
  lea    D22(%rip),%rsi
  mov    0x58(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    %r13d,%eax
  sub    0x50(%rsp),%eax
  cltq
  mov    0x8(%rsp),%rdi
  mov    (%rdi,%rax,4),%r12d
L22:
  lea    D29(%rip),%rsi
  mov    0x58(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L16
  mov    %r13d,%eax
  sub    0x50(%rsp),%eax
  cltq
  mov    (%r15,%rax,4),%r12d
L16:
  sub    0x50(%rsp),%r13d
  lea    0x2(%r13,%r13,1),%eax
  cltq
  lea    (%r14,%rax,4),%r8
  cmpl   $0x0,(%r8)
  jle    L40
  lea    0x4(%r14,%rax,4),%rdi
  mov    $0x0,%esi
  jmp    L35
L89:
  imul   %esi,%eax
  lea    (%rcx,%r12,1),%edx
  add    %eax,%edx
  movslq %edx,%rdx
  movsd  (%rbx,%rdx,8),%xmm0
  add    %ecx,%eax
  cltq
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%ecx
  mov    (%rdi),%eax
  cmp    %ecx,%eax
  jg     L89
L29:
  add    $0x1,%esi
  cmp    %esi,(%r8)
  jle    L40
L35:
  mov    (%rdi),%eax
  mov    $0x0,%ecx
  test   %eax,%eax
  jg     L89
  jmp    L29
L40:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string

tool: D13: h

tool: D22: v

tool: D29: d

assistant: ```c
void detcoef2(double *coef, int sigInLength, double *coefOut, int sigOutLength, int *pLen, int stride, int level, char *coefType) {
  int row, col, sta;
  int *pH, *pV, *pD;
  pH = malloc(stride * sizeof(int));
  pV = malloc(stride * sizeof(int));
  pD = malloc(stride * sizeof(int));
  matrix_locate(stride, pLen, pH, pV, pD);
  if (strcmp(coefType, "h") == 0) {
    sta = pH[stride - level];
  }
  if (strcmp(coefType, "v") == 0) {
    sta = pV[stride - level];
  }
  if (strcmp(coefType, "d") == 0) {
    sta = pD[stride - level];
  }
  for (row = 0; row < pLen[(stride - level + 1) * 2]; row++) {
    for (col = 0; col < pLen[(stride - level + 1) * 2 + 1]; col++)
      coefOut[col + row * (pLen[(stride - level + 1) * 2 + 1])] = coef[sta + col + row * (pLen[(stride - level + 1) * 2 + 1])];
  }
  free(pH);
  free(pV);
  free(pD);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L46
  jmp    L32
L43:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  subq   $0x1,-0x8(%rbp)
  jmp    L21
L23:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x8(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L23
L46:
  nop
  leave
  ret
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  if (str) {
    while (*end)
      end++;
    end--;
    while (str < end) {
      swap(str, end);
      str++;
      end--;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  test   %rdi,%rdi
  je     L23
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmpb   $0x0,(%rdi)
  je     L37
  mov    %rdi,%rbx
L28:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L28
L20:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jae    L47
L31:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x1,%rbp
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jb     L31
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    %rdi,%rbx
  jmp    L20
L23:
  ret
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  if (str) {
    while (*end)
      end++;
    end--;
    while (str < end) {
      swap(str, end);
      str++;
      end--;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverse>:
  endbr64
  test   %rdi,%rdi
  je     L36
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L56
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %rax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L40
L8:
  cmp    %rbp,%rbx
  jbe    L34
  nopl   0x0(%rax)
L48:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  add    $0x1,%rbp
  call   <swap@plt>
  cmp    %rbx,%rbp
  jb     L48
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  ret
  nopl   0x0(%rax)
L56:
  lea    -0x1(%rdi),%rbx
  jmp    L8
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  if (str) {
    while (*end)
      end++;
    end--;
    while (str < end) {
      swap(str, end);
      str++;
      end--;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L30
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %rax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L31
L9:
  cmp    %rbp,%rbx
  jbe    L20
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  add    $0x1,%rbp
  call   <swap@plt>
  cmp    %rbx,%rbp
  jb     L14
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
  nopl   0x0(%rax)
L30:
  lea    -0x1(%rdi),%rbx
  jmp    L9
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  if (str) {
    while (*end)
      end++;
    end--;
    while (str < end) {
      swap(str, end);
      str++;
      end--;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void free2(void *p) {
  if (p != NULL) {
    free(p);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<free2>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
void free2(void *p) {
  if (p != NULL) {
    free(p);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free2>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void free2(void *p) {
  if (p != NULL) {
    free(p);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free2>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void free2(void *p) {
  if (p != NULL) {
    free(p);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_putendl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  mov    $0x1,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: 


assistant: ```c
void ft_putendl(char const *s) {
  int i;
  ft_putstr(s);
  write(1, "\n", 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putendl>:
  endbr64
  sub    $0x8,%rsp
  call   <ft_putstr@plt>
  mov    $0x1,%edx
  lea    D5(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string

tool: D5: 


assistant: ```c
void ft_putendl(char const *s) {
  int i;
  ft_putstr(s);
  write(1, "\n", 1);
}
```