ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<updateRssItems>:
  endbr64
  push   %rbp
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %rdi,%rbp
  call   <isNumericOk@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L3
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <setConfigTextValue@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: web.rss.items

assistant: ```c
int updateRssItems(char *value) {
  if (isNumericOk(value, 1, 20)) {
    setConfigTextValue("web.rss.items", value);
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    $0x2f,%rax
  seta   %dl
  test   %dl,%dl
  jne    L9
  mov    %eax,%edx
  movabs $0x800010800408,%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L9
  mov    $0x0,%eax
  jmp    L15
L9:
  mov    $0x7b,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int wwrite(long long i) {
  switch (i) {
  case 3:
  case 10:
  case 23:
  case 28:
  case 47:
    return 0;
  default:
    return 123;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wwrite>:
  endbr64
  cmp    $0x2f,%rdi
  ja     L8
  movabs $0x800010800408,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x7b,%eax
  ret
L8:
  mov    $0x7b,%eax
  ret
```

assistant: ```c
int wwrite(long long i) {
  switch (i) {
  case 3:
  case 10:
  case 23:
  case 28:
  case 47:
    return 0;
  default:
    return 123;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wwrite>:
  endbr64
  cmp    $0x2f,%rdi
  ja     L6
  movabs $0x800010800408,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  and    $0x7b,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x7b,%eax
  ret
```

assistant: ```c
int wwrite(long long i) {
  switch (i) {
  case 3:
  case 10:
  case 23:
  case 28:
  case 47:
    return 0;
  default:
    return 123;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wwrite>:
  endbr64
  cmp    $0x2f,%rdi
  ja     L3
  movabs $0x800010800408,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  and    $0x7b,%eax
  ret
  nopl   0x0(%rax)
L3:
  mov    $0x7b,%eax
  ret
```

assistant: ```c
int wwrite(long long i) {
  switch (i) {
  case 3:
  case 10:
  case 23:
  case 28:
  case 47:
    return 0;
  default:
    return 123;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBModeGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x60,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x9d,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long USBModeGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned char *)(ulBase + 0x00000060))) & (0x00000080 | 0x00000004 | 0x00000001 | 0x00000018));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<USBModeGet>:
  endbr64
  movzbl 0x60(%rdi),%eax
  and    $0x9d,%eax
  ret
```

assistant: ```c
unsigned long USBModeGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned char *)(ulBase + 0x00000060))) & (0x00000080 | 0x00000004 | 0x00000001 | 0x00000018));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBModeGet>:
  endbr64
  movzbl 0x60(%rdi),%eax
  and    $0x9d,%eax
  ret
```

assistant: ```c
unsigned long USBModeGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned char *)(ulBase + 0x00000060))) & (0x00000080 | 0x00000004 | 0x00000001 | 0x00000018));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<USBModeGet>:
  endbr64
  movzbl 0x60(%rdi),%eax
  and    $0x9d,%eax
  ret
```

assistant: ```c
unsigned long USBModeGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned char *)(ulBase + 0x00000060))) & (0x00000080 | 0x00000004 | 0x00000001 | 0x00000018));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_param_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    $0x50,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_param@plt>
  mov    %eax,%edi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double get_param_float(const char *cmd) {
  char buf[80];
  return atof(get_param(cmd, buf, sizeof(buf)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_param_float>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x50,%edx
  call   <get_param@plt>
  mov    %eax,%edi
  call   <atof@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x68,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double get_param_float(const char *cmd) {
  char buf[80];
  return atof(get_param(cmd, buf, sizeof(buf)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_param_float>:
  endbr64
  sub    $0x68,%rsp
  mov    $0x50,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <get_param@plt>
  mov    %eax,%edi
  call   <atof@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double get_param_float(const char *cmd) {
  char buf[80];
  return atof(get_param(cmd, buf, sizeof(buf)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_param_float>:
  endbr64
  sub    $0x68,%rsp
  mov    $0x50,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <get_param@plt>
  mov    %eax,%edi
  call   <atof@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double get_param_float(const char *cmd) {
  char buf[80];
  return atof(get_param(cmd, buf, sizeof(buf)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<joe_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <joe_fatal@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: Memory exhausted at %s, line %s

assistant: ```c
void *joe_malloc(size_t size, char *file, char *line) {
  void *new = malloc(size);
  if (!new)
    joe_fatal("Memory exhausted at %s, line %s", file, line);
  return new;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<joe_malloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L6:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <joe_fatal@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: Memory exhausted at %s, line %s

assistant: ```c
void *joe_malloc(size_t size, char *file, char *line) {
  void *new = malloc(size);
  if (!new)
    joe_fatal("Memory exhausted at %s, line %s", file, line);
  return new;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<joe_malloc>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
L1:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <joe_fatal@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: Memory exhausted at %s, line %s

assistant: ```c
void *joe_malloc(size_t size, char *file, char *line) {
  void *new = malloc(size);
  if (!new)
    joe_fatal("Memory exhausted at %s, line %s", file, line);
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<joe_malloc>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
L4:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <joe_fatal@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: Memory exhausted at %s, line %s

assistant: ```c
void *joe_malloc(size_t size, char *file, char *line) {
  void *new = malloc(size);
  if (!new)
    joe_fatal("Memory exhausted at %s, line %s", file, line);
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <intToStr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2e,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movss  -0x8(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movss  -0x8(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    -0x18(%rbp),%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <intToStr@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void ftoa(float n, char *res, int afterpoint) {
  int ipart = (int)n;
  float fpart = n - (float)ipart;
  int i = intToStr(ipart, res, 0);
  if (afterpoint != 0) {
    res[i] = '.';
    fpart = fpart * pow(10, afterpoint);
    intToStr((int)fpart, res + i + 1, afterpoint);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ftoa>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %rdi,%rbp
  mov    %esi,%ebx
  cvttss2si %xmm0,%r13d
  mov    $0x0,%edx
  mov    %rdi,%rsi
  mov    %r13d,%edi
  call   <intToStr@plt>
  test   %ebx,%ebx
  jne    L17
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  movslq %eax,%r12
  movb   $0x2e,0x0(%rbp,%r12,1)
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %r13d,%xmm2
  movss  0xc(%rsp),%xmm0
  subss  %xmm2,%xmm0
  lea    0x1(%rbp,%r12,1),%rsi
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%edi
  mov    %ebx,%edx
  call   <intToStr@plt>
  jmp    L19
```

assistant: ```c
void ftoa(float n, char *res, int afterpoint) {
  int ipart = (int)n;
  float fpart = n - (float)ipart;
  int i = intToStr(ipart, res, 0);
  if (afterpoint != 0) {
    res[i] = '.';
    fpart = fpart * pow(10, afterpoint);
    intToStr((int)fpart, res + i + 1, afterpoint);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ftoa>:
  endbr64
  push   %r14
  xor    %edx,%edx
  movd   %xmm0,%r14d
  push   %r13
  cvttss2si %xmm0,%r13d
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  call   <intToStr@plt>
  test   %r12d,%r12d
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %eax,%rbp
  mov    %r12d,%esi
  mov    $0xa,%edi
  movb   $0x2e,(%rbx,%rbp,1)
  call   <pow@plt>
  pxor   %xmm2,%xmm2
  lea    0x1(%rbx,%rbp,1),%rsi
  mov    %r12d,%edx
  cvtsi2ss %r13d,%xmm2
  movaps %xmm0,%xmm1
  movd   %r14d,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  subss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%edi
  jmp    1070 <intToStr@plt>
```

assistant: ```c
void ftoa(float n, char *res, int afterpoint) {
  int ipart = (int)n;
  float fpart = n - (float)ipart;
  int i = intToStr(ipart, res, 0);
  if (afterpoint != 0) {
    res[i] = '.';
    fpart = fpart * pow(10, afterpoint);
    intToStr((int)fpart, res + i + 1, afterpoint);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ftoa>:
  endbr64
  push   %r14
  xor    %edx,%edx
  movd   %xmm0,%r14d
  push   %r13
  cvttss2si %xmm0,%r13d
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  call   <intToStr@plt>
  test   %r12d,%r12d
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movslq %eax,%rbp
  mov    %r12d,%esi
  mov    $0xa,%edi
  movb   $0x2e,(%rbx,%rbp,1)
  call   <pow@plt>
  pxor   %xmm2,%xmm2
  lea    0x1(%rbx,%rbp,1),%rsi
  mov    %r12d,%edx
  cvtsi2ss %r13d,%xmm2
  movaps %xmm0,%xmm1
  movd   %r14d,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  subss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%edi
  jmp    1070 <intToStr@plt>
```

assistant: ```c
void ftoa(float n, char *res, int afterpoint) {
  int ipart = (int)n;
  float fpart = n - (float)ipart;
  int i = intToStr(ipart, res, 0);
  if (afterpoint != 0) {
    res[i] = '.';
    fpart = fpart * pow(10, afterpoint);
    intToStr((int)fpart, res + i + 1, afterpoint);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minimum_k1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L75
L106:
  movl   $0x0,-0x10(%rbp)
  jmp    L72
L69:
  addl   $0x1,-0x10(%rbp)
L72:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L12
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L69
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L50
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L105
L5:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L105:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L5
L50:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L76
  addl   $0x1,-0x14(%rbp)
L76:
  addl   $0x1,-0x18(%rbp)
L75:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L106
  movl   $0x0,-0x18(%rbp)
  jmp    L97
L13:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L97:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: %d


assistant: ```c
void minimum_k1(int *arr, int len, int k) {
  int *sorted = (int *)malloc(sizeof(int) * k);
  int i, sorted_bound = 0;
  for (i = 0; i < len; i++) {
    int j = 0;
    while (j < sorted_bound && sorted[j] <= arr[i])
      j++;
    if (sorted[j] > arr[i]) {
      int move = sorted_bound;
      while (j < move) {
        sorted[move] = sorted[move - 1];
        move--;
      }
    }
    sorted[j] = arr[i];
    if (sorted_bound < k)
      sorted_bound++;
  }
  for (i = 0; i < sorted_bound; i++)
    printf("%d\n", sorted[i]);
  free(sorted);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minimum_k1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  lea    0x0(,%rdx,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r12d,%r12d
  jle    L25
  mov    %r13,%rdi
  lea    -0x1(%r12),%eax
  lea    0x4(%r13,%rax,4),%r9
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  lea    -0x4(%rbx),%r10
  jmp    L60
L29:
  test   %ecx,%ecx
  jle    L25
  mov    %rbx,%rbp
  lea    -0x1(%rcx),%eax
  lea    0x4(%rbx,%rax,4),%r13
  lea    D0(%rip),%r12
L37:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %rbp,%r13
  jne    L37
L25:
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  movslq %eax,%rdx
  lea    (%rbx,%rdx,4),%r12
  cmp    %eax,%ecx
  jle    L82
  movslq %ecx,%rsi
  shl    $0x2,%rsi
  lea    (%rsi,%rbx,1),%rdx
  add    %r10,%rsi
  lea    -0x1(%rcx),%r13d
  sub    %eax,%r13d
  lea    0x0(,%r13,4),%rax
  sub    %rax,%rsi
L111:
  mov    -0x4(%rdx),%eax
  mov    %eax,(%rdx)
  sub    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L111
  jmp    L82
L84:
  mov    %r11d,%eax
L113:
  cltq
  lea    (%rbx,%rax,4),%r12
  mov    %rdi,%r8
L82:
  mov    (%r8),%eax
  mov    %eax,(%r12)
  cmp    %ecx,%ebp
  setg   %al
  movzbl %al,%eax
  add    %eax,%ecx
  add    $0x4,%rdi
  cmp    %r9,%rdi
  je     L29
L60:
  test   %ecx,%ecx
  jle    L84
  mov    %rdi,%r8
  mov    (%rdi),%esi
  mov    %rbx,%rdx
  mov    $0x0,%eax
L65:
  cmp    %esi,(%rdx)
  jg     L89
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L65
  mov    %ecx,%eax
  jmp    L113
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D0: %d


assistant: ```c
void minimum_k1(int *arr, int len, int k) {
  int *sorted = (int *)malloc(sizeof(int) * k);
  int i, sorted_bound = 0;
  for (i = 0; i < len; i++) {
    int j = 0;
    while (j < sorted_bound && sorted[j] <= arr[i])
      j++;
    if (sorted[j] > arr[i]) {
      int move = sorted_bound;
      while (j < move) {
        sorted[move] = sorted[move - 1];
        move--;
      }
    }
    sorted[j] = arr[i];
    if (sorted_bound < k)
      sorted_bound++;
  }
  for (i = 0; i < sorted_bound; i++)
    printf("%d\n", sorted[i]);
  free(sorted);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<minimum_k1>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%rdx,4),%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L27
  lea    -0x1(%rbx),%eax
  xor    %ebp,%ebp
  lea    0x4(%r13,%rax,4),%r15
  nopl   0x0(%rax,%rax,1)
L59:
  mov    0x0(%r13),%edx
  mov    %r12,%rbx
  test   %ebp,%ebp
  jle    L17
  xor    %eax,%eax
  jmp    L28
  nop
L89:
  add    $0x1,%eax
  add    $0x4,%rbx
  cmp    %ebp,%eax
  je     L50
L28:
  cmp    %edx,(%rbx)
  jle    L89
  cmp    %ebp,%eax
  jge    L17
  mov    %ebp,%edx
  sub    %eax,%edx
  lea    -0x1(%rdx),%ecx
  movslq %ebp,%rdx
  mov    %rcx,%rax
  shl    $0x2,%rdx
  lea    0x4(,%rcx,4),%r8
  neg    %rax
  shl    $0x2,%rax
  lea    -0x4(%rdx,%rax,1),%rsi
  add    %rdx,%rax
  mov    %r8,%rdx
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <memmove@plt>
  mov    0x0(%r13),%edx
L17:
  xor    %eax,%eax
  cmp    %ebp,%r14d
  mov    %edx,(%rbx)
  setg   %al
  add    $0x4,%r13
  add    %eax,%ebp
  cmp    %r15,%r13
  jne    L59
  test   %ebp,%ebp
  jle    L27
  lea    -0x1(%rbp),%eax
  mov    %r12,%rbx
  lea    D7(%rip),%rbp
  lea    0x4(%r12,%rax,4),%r13
  nopl   (%rax)
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L2
L27:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
  nopl   0x0(%rax)
L50:
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rbx
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
void minimum_k1(int *arr, int len, int k) {
  int *sorted = (int *)malloc(sizeof(int) * k);
  int i, sorted_bound = 0;
  for (i = 0; i < len; i++) {
    int j = 0;
    while (j < sorted_bound && sorted[j] <= arr[i])
      j++;
    if (sorted[j] > arr[i]) {
      int move = sorted_bound;
      while (j < move) {
        sorted[move] = sorted[move - 1];
        move--;
      }
    }
    sorted[j] = arr[i];
    if (sorted_bound < k)
      sorted_bound++;
  }
  for (i = 0; i < sorted_bound; i++)
    printf("%d\n", sorted[i]);
  free(sorted);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<detach_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <nvme_attach_ns@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: Detach the given namespace from the given controller; de-activates the given namespace's ID. A namespace must be attached to a controller before IO commands may be directed to that namespace.

assistant: ```c
int detach_ns(int argc, char **argv, struct command *cmd, struct plugin *plugin) {
  const char *desc = "Detach the given namespace from the "
                     "given controller; de-activates the given namespace's ID. A "
                     "namespace must be attached to a controller before IO "
                     "commands may be directed to that namespace.";
  return nvme_attach_ns(argc, argv, 0, desc, cmd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<detach_ns>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%r8
  lea    D2(%rip),%rcx
  mov    $0x0,%edx
  call   <nvme_attach_ns@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: Detach the given namespace from the given controller; de-activates the given namespace's ID. A namespace must be attached to a controller before IO commands may be directed to that namespace.

assistant: ```c
int detach_ns(int argc, char **argv, struct command *cmd, struct plugin *plugin) {
  const char *desc = "Detach the given namespace from the "
                     "given controller; de-activates the given namespace's ID. A "
                     "namespace must be attached to a controller before IO "
                     "commands may be directed to that namespace.";
  return nvme_attach_ns(argc, argv, 0, desc, cmd);
}
```