ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dummy@plt>
  xor    %eax,%eax
  call   <bye@plt>
  xor    %eax,%eax
  call   <dummy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dummy();
  bye();
  dummy();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dec_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <subtract_func@plt>
  leave
  ret
```

assistant: ```c
int dec_func(int src, int dest, int is_word) {
  (void)src;
  return subtract_func(1, dest, is_word, 0, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dec_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edi
  call   <subtract_func@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dec_func(int src, int dest, int is_word) {
  (void)src;
  return subtract_func(1, dest, is_word, 0, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dec_func>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edi
  jmp    1050 <subtract_func@plt>
```

assistant: ```c
int dec_func(int src, int dest, int is_word) {
  (void)src;
  return subtract_func(1, dest, is_word, 0, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dec_func>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edi
  jmp    1050 <subtract_func@plt>
```

assistant: ```c
int dec_func(int src, int dest, int is_word) {
  (void)src;
  return subtract_func(1, dest, is_word, 0, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L103:
  movl   $0x0,-0x10(%rbp)
  jmp    L56
L7:
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L56:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L7
  movl   $0x0,-0xc(%rbp)
  jmp    L50
L70:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L50:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L70
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L103
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L94:
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L125:
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L125
  movl   $0x1,-0xc(%rbp)
  jmp    L24
L35:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L35
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L5:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L94
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L105
  call   <__stack_chk_fail@plt>
L105:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D60
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string

tool: D14: enter the size of pattern: 

tool: D0: %d

tool: D60:   

tool: D32: * 

tool: D1: 


assistant: ```c
int main() {
  int i, j, k, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j < num - i - 1; j++) {
      printf("  ");
    }
    for (k = 0; k <= i * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  for (i = 0; i < num - 1; i++) {
    for (j = 0; j <= i; j++) {
      printf("  ");
    }
    for (k = 1; k < (num - i - 1) * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%r12d
  mov    $0x0,%ebp
  lea    D20(%rip),%r14
  lea    D59(%rip),%r13
  lea    D55(%rip),%r15
  cmpl   $0x0,0x4(%rsp)
  jg     L83
L25:
  mov    $0x0,%ebp
  lea    D20(%rip),%r13
  lea    D59(%rip),%r12
  lea    D55(%rip),%r14
  cmpl   $0x1,0x4(%rsp)
  jg     L143
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %ebp,%eax
  not    %eax
  add    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L76
L6:
  test   $0x40000000,%ebp
  jne    L14
  mov    $0x0,%ebx
L126:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L126
L14:
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x2,%r12d
  cmp    %ebp,0x4(%rsp)
  jle    L25
L83:
  mov    0x4(%rsp),%eax
  sub    %ebp,%eax
  mov    $0x0,%ebx
  cmp    $0x1,%eax
  jg     L76
  jmp    L6
L82:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L82
L44:
  mov    %ebp,%eax
  not    %eax
  add    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    $0x1,%eax
  jle    L15
  mov    $0x1,%ebx
L62:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %ebp,%eax
  not    %eax
  add    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jg     L62
L15:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jle    L5
L143:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jns    L82
  jmp    L44
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D59
datatype: string
name: unpack_data
arguments: data_label: D55
datatype: string

tool: D9: enter the size of pattern: 

tool: D7: %d

tool: D20:   

tool: D59: * 

tool: D55: 


assistant: ```c
int main() {
  int i, j, k, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j < num - i - 1; j++) {
      printf("  ");
    }
    for (k = 0; k <= i * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  for (i = 0; i < num - 1; i++) {
    for (j = 0; j <= i; j++) {
      printf("  ");
    }
    for (k = 1; k < (num - i - 1) * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D52(%rip),%rdi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  lea    D56(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L76
  nopl   0x0(%rax,%rax,1)
L7:
  sub    %ebx,%eax
  xor    %r15d,%r15d
  cmp    $0x1,%eax
  jle    L89
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    %ebx,%eax
  not    %eax
  add    0x4(%rsp),%eax
  cmp    %r15d,%eax
  jg     L56
L89:
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L84:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r14d,%r15d
  jne    L84
  mov    %r13,%rdi
  add    $0x1,%ebx
  lea    0x2(%r15),%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L7
  cmp    $0x1,%eax
  jle    L76
  xor    %ebx,%ebx
  lea    D5(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L80:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L101:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L101
  mov    %ebx,%eax
  mov    $0x1,%r14d
  not    %eax
  add    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    $0x1,%eax
  jle    L50
  xchg   %ax,%ax
L6:
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    %ebx,%eax
  not    %eax
  add    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %r14d,%eax
  jg     L6
L50:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L80
L76:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D52
type: string
name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D56
type: string
name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D20
type: string

tool: D52: enter the size of pattern: 

tool: D3: 


tool: D56: * 

tool: D5:   

tool: D20: %d

assistant: ```c
int main() {
  int i, j, k, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j < num - i - 1; j++) {
      printf("  ");
    }
    for (k = 0; k <= i * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  for (i = 0; i < num - 1; i++) {
    for (j = 0; j <= i; j++) {
      printf("  ");
    }
    for (k = 1; k < (num - i - 1) * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%rdi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L8
  nopl   0x0(%rax,%rax,1)
L92:
  sub    %ebx,%eax
  xor    %r15d,%r15d
  cmp    $0x1,%eax
  jle    L93
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    %ebx,%eax
  not    %eax
  add    0x4(%rsp),%eax
  cmp    %r15d,%eax
  jg     L26
L93:
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L52:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r14d,%r15d
  jne    L52
  mov    %r13,%rdi
  add    $0x1,%ebx
  lea    0x2(%r15),%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L92
  cmp    $0x1,%eax
  jle    L8
  xor    %ebx,%ebx
  lea    D6(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L107:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L29
  mov    %ebx,%eax
  mov    $0x1,%r14d
  not    %eax
  add    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    $0x1,%eax
  jle    L19
  xchg   %ax,%ax
L16:
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    %ebx,%eax
  not    %eax
  add    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %r14d,%eax
  jg     L16
L19:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L107
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D20
data_type: string
name: extract_symbolic_data
arguments: data_label: D34
data_type: string
name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D35
data_type: string

tool: D13: enter the size of pattern: 

tool: D20: 


tool: D34: * 

tool: D6:   

tool: D35: %d

assistant: ```c
int main() {
  int i, j, k, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j < num - i - 1; j++) {
      printf("  ");
    }
    for (k = 0; k <= i * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  for (i = 0; i < num - 1; i++) {
    for (j = 0; j <= i; j++) {
      printf("  ");
    }
    for (k = 1; k < (num - i - 1) * 2; k++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string

tool: D28: Enter value: 

tool: D9: %f

tool: D16: Value = %f


assistant: ```c
int main(void) {
  float a;
  printf("Enter value: ");
  scanf("%f", &a);
  printf("Value = %f\n", a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D26: Enter value: 

tool: D4: %f

tool: D2: Value = %f


assistant: ```c
int main(void) {
  float a;
  printf("Enter value: ");
  scanf("%f", &a);
  printf("Value = %f\n", a);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D28(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D28
type: string

tool: D9: Enter value: 

tool: D15: %f

tool: D28: Value = %f


assistant: ```c
int main(void) {
  float a;
  printf("Enter value: ");
  scanf("%f", &a);
  printf("Value = %f\n", a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D20(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D20
type: string

tool: D29: Enter value: 

tool: D14: %f

tool: D20: Value = %f


assistant: ```c
int main(void) {
  float a;
  printf("Enter value: ");
  scanf("%f", &a);
  printf("Value = %f\n", a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_tok2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L47
  cmpq   $0x0,-0x30(%rbp)
  je     L47
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  cmpl   $0x0,-0x34(%rbp)
  jg     L52
L47:
  mov    $0xffffffff,%eax
  jmp    L3
L52:
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L44
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L44:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L78
L7:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L78:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int str_tok2(char *dest, char **src, int dest_size, const char *needle) {
  char *psrc, *p;
  int len;
  if (!dest || !src || !**src || dest_size < 1) {
    return -1;
  }
  memset(dest, 0, dest_size);
  psrc = *src;
  p = strstr(psrc, needle);
  if (p) {
    len = p - psrc;
    if (len >= dest_size) {
      len = dest_size - 1;
    }
    memcpy(dest, psrc, len);
    *src = p + strlen(needle);
  } else {
    len = dest_size - 1;
    memcpy(dest, psrc, len);
    *src = psrc + strlen(psrc);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_tok2>:
  endbr64
  test   %rdi,%rdi
  je     L48
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %rcx,%r15
  test   %rsi,%rsi
  je     L41
  mov    (%rsi),%rax
  cmpb   $0x0,(%rax)
  je     L62
  test   %edx,%edx
  jle    L62
  mov    $0x0,%esi
  call   <memset@plt>
  mov    (%r12),%r14
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L75
  mov    %rax,%rdx
  sub    %r14,%rdx
  lea    -0x1(%rbp),%eax
  cmp    %edx,%ebp
  cmovle %eax,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  mov    %rbx,(%r12)
  mov    $0x0,%eax
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  lea    -0x1(%rbp),%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r14
  mov    %r14,(%r12)
  mov    $0x0,%eax
  jmp    L46
L41:
  mov    $0xffffffff,%eax
  jmp    L46
L62:
  mov    $0xffffffff,%eax
  jmp    L46
L48:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int str_tok2(char *dest, char **src, int dest_size, const char *needle) {
  char *psrc, *p;
  int len;
  if (!dest || !src || !**src || dest_size < 1) {
    return -1;
  }
  memset(dest, 0, dest_size);
  psrc = *src;
  p = strstr(psrc, needle);
  if (p) {
    len = p - psrc;
    if (len >= dest_size) {
      len = dest_size - 1;
    }
    memcpy(dest, psrc, len);
    *src = p + strlen(needle);
  } else {
    len = dest_size - 1;
    memcpy(dest, psrc, len);
    *src = psrc + strlen(psrc);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_tok2>:
  endbr64
  test   %rdi,%rdi
  je     L33
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L56
  mov    (%rsi),%rax
  cmpb   $0x0,(%rax)
  je     L56
  mov    %edx,%ebp
  test   %edx,%edx
  jle    L56
  xor    %esi,%esi
  mov    %rcx,%r14
  mov    %rdi,%r13
  call   <memset@plt>
  mov    (%r12),%r15
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L52
  mov    %rax,%rdx
  lea    -0x1(%rbp),%eax
  mov    %r15,%rsi
  mov    %r13,%rdi
  sub    %r15,%rdx
  cmp    %edx,%ebp
  cmovle %eax,%edx
  call   <memcpy@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  xor    %eax,%eax
  mov    %rbx,(%r12)
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L52:
  lea    -0x1(%rbp),%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r15
  xor    %eax,%eax
  mov    %r15,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  mov    $0xffffffff,%eax
  jmp    L47
L33:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int str_tok2(char *dest, char **src, int dest_size, const char *needle) {
  char *psrc, *p;
  int len;
  if (!dest || !src || !**src || dest_size < 1) {
    return -1;
  }
  memset(dest, 0, dest_size);
  psrc = *src;
  p = strstr(psrc, needle);
  if (p) {
    len = p - psrc;
    if (len >= dest_size) {
      len = dest_size - 1;
    }
    memcpy(dest, psrc, len);
    *src = p + strlen(needle);
  } else {
    len = dest_size - 1;
    memcpy(dest, psrc, len);
    *src = psrc + strlen(psrc);
  }
  return 0;
}
```