user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D33(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x668,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x658(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x1a0(%rsp),%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L90
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r15
  lea    0x8(%rsp),%r14
  lea    D48(%rip),%r13
  lea    0x10(%rsp),%rbp
  lea    0x1a0(%rsp),%r12
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L135:
  mov    %edx,0x0(%rbp,%rbx,4)
  mov    0x4(%rsp),%edx
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jle    L90
L26:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  jg     L135
  mov    %edx,(%r12,%rbx,4)
  mov    0x4(%rsp),%edx
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jg     L26
L90:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sort@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L84
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L120:
  mov    0x4(%rsp),%ecx
  add    $0x1,%ebx
  cmp    %ecx,%ebx
  jge    L131
L65:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <find_conflicts@plt>
  test   %eax,%eax
  jne    L120
  movslq %ebx,%rax
  movslq %r13d,%rcx
  mov    0x10(%rsp,%rax,4),%esi
  mov    0x1a0(%rsp,%rax,4),%edx
  mov    %esi,0x330(%rsp,%rcx,4)
  mov    %edx,0x4c0(%rsp,%rcx,4)
  mov    0x4(%rsp),%ecx
  cmp    %edx,%esi
  jge    L124
  lea    0x0(%rbp,%rax,4),%rax
  jmp    L129
  nopw   0x0(%rax,%rax,1)
L115:
  add    $0x4,%rax
  add    $0x1,%ebx
  cmp    (%rax),%edx
  jle    L124
L129:
  cmp    %ebx,%ecx
  jg     L115
L124:
  add    $0x1,%r13d
  cmp    %ecx,%ebx
  jl     L65
L131:
  xor    %eax,%eax
  mov    %r13d,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  test   %r13d,%r13d
  je     L108
  movslq %r13d,%r13
  xor    %ebx,%ebx
  lea    0x4c0(%rsp),%r14
  lea    0x330(%rsp),%r12
  lea    D20(%rip),%rbp
  nopl   0x0(%rax)
L22:
  mov    (%r14,%rbx,4),%edx
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L22
L108:
  mov    0x658(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x668,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L84:
  xor    %esi,%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L108
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D33
data_type: string
name: parse_data
arguments: label: D48
data_type: string
name: parse_data
arguments: label: D43
data_type: string
name: parse_data
arguments: label: D20
data_type: string

tool: D33: %d

tool: D48: %d%d

tool: D43: %d


tool: D20: %d %d


assistant: ```c
int main() {
  int list_1[100], list_2[100], flist_1[100], flist_2[100];
  int num_segs = 0, i, num1, num2;
  int fcounter = 0, fpointer = 0;
  int conflicts;
  scanf("%d", &num_segs);
  for (i = 0; i < num_segs; i++) {
    scanf("%d%d", &num1, &num2);
    if (num1 > num2) {
      list_1[i] = num2;
      list_2[i] = num1;
    } else {
      list_2[i] = num2;
      list_1[i] = num1;
    }
  }
  sort(list_1, list_2, num_segs);
  while (fpointer < num_segs) {
    int conflicts = find_conflicts(list_1, list_2, fpointer, num_segs);
    if (conflicts != 0) {
      fpointer++;
      continue;
    }
    flist_1[fcounter] = list_1[fpointer];
    flist_2[fcounter] = list_2[fpointer];
    while ((flist_2[fcounter] > list_1[fpointer]) && (fpointer < num_segs))
      fpointer++;
    fcounter++;
  }
  printf("%d\n", fcounter);
  for (i = 0; i < fcounter; i++)
    printf("%d %d\n", flist_1[i], flist_2[i]);
  return 0;
}
```