ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
datatype: string
name: extract_symbolic_data
arguments: tag: D20
datatype: string
name: extract_symbolic_data
arguments: tag: D41
datatype: string
name: extract_symbolic_data
arguments: tag: D33
datatype: string
name: extract_symbolic_data
arguments: tag: D36
datatype: string

tool: D21: vc[0] = %d


tool: D20: vc[1] = %d


tool: D41: vc[2] = %d


tool: D33: vc[3] = %d


tool: D36: vc[4] = %d


assistant: ```c
int main(void) {
  int vc[5];
  vc[0] = 1;
  vc[1] = 2;
  vc[2] = 3;
  vc[3] = 4;
  vc[4] = 5;
  printf("vc[0] = %d\n", vc[0]);
  printf("vc[1] = %d\n", vc[1]);
  printf("vc[2] = %d\n", vc[2]);
  printf("vc[3] = %d\n", vc[3]);
  printf("vc[4] = %d\n", vc[4]);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sleep_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3e8,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  imul   $0xf4240,%rax,%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void sleep_ms(long milliseconds) {
  struct timespec ts;
  ts.tv_sec = milliseconds / 1000;
  ts.tv_nsec = (milliseconds % 1000) * 1000000;
  nanosleep(&ts, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sleep_ms>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,(%rsp)
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rdi
  imul   $0xf4240,%rdi,%rdi
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_ms(long milliseconds) {
  struct timespec ts;
  ts.tv_sec = milliseconds / 1000;
  ts.tv_nsec = (milliseconds % 1000) * 1000000;
  nanosleep(&ts, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sleep_ms>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  mov    %rdx,(%rsp)
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rdi
  imul   $0xf4240,%rdi,%rdi
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_ms(long milliseconds) {
  struct timespec ts;
  ts.tv_sec = milliseconds / 1000;
  ts.tv_nsec = (milliseconds % 1000) * 1000000;
  nanosleep(&ts, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sleep_ms>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  imul   $0x3e8,%rdx,%rax
  movq   %rdx,%xmm0
  sub    %rax,%rdi
  imul   $0xf4240,%rdi,%rdi
  movq   %rdi,%xmm1
  mov    %rsp,%rdi
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_ms(long milliseconds) {
  struct timespec ts;
  ts.tv_sec = milliseconds / 1000;
  ts.tv_nsec = (milliseconds % 1000) * 1000000;
  nanosleep(&ts, NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GROTER>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %edx,-0x74(%rbp)
  mov    %ecx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x70(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,-0x58(%rbp)
  cmpl   $0x3f,-0x58(%rbp)
  jle    L2
  movl   $0x3f,-0x58(%rbp)
L2:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x58(%rbp),%eax
  cltq
  movb   $0x0,-0x50(%rbp,%rax,1)
  lea    -0x50(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <open@plt>
  mov    %eax,-0x54(%rbp)
  cmpl   $0xffffffff,-0x54(%rbp)
  jne    L36
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L36:
  mov    -0x54(%rbp),%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int GROTER(cdev, ldev, w_cdev, w_ldev)
char *cdev;
long int *ldev;
int w_cdev, w_ldev;
{
  int fd, n;
  char name[64];
  n = *ldev;
  if (n > 63)
    n = 63;
  strncpy(name, cdev, n);
  name[n] = '\0';
  if ((fd = open(name, 2)) == -1) {
    perror(name);
    return -1;
  } else {
    return fd;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GROTER>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rbx
  mov    $0x3f,%eax
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  movslq %ebx,%rbx
  mov    %rsp,%rbp
  mov    %rbx,%rdx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rsp,%rbx,1)
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L12
L27:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %ebx,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  jmp    L27
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GROTER(cdev, ldev, w_cdev, w_ldev)
char *cdev;
long int *ldev;
int w_cdev, w_ldev;
{
  int fd, n;
  char name[64];
  n = *ldev;
  if (n > 63)
    n = 63;
  strncpy(name, cdev, n);
  name[n] = '\0';
  if ((fd = open(name, 2)) == -1) {
    perror(name);
    return -1;
  } else {
    return fd;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GROTER>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    (%rsi),%rbx
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x3f,%eax
  mov    %rsp,%rbp
  cmp    %eax,%ebx
  mov    %rbp,%rdi
  cmovg  %eax,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdx
  call   <strncpy@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movb   $0x0,(%rsp,%rbx,1)
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L24
L0:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x50,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <perror@plt>
  jmp    L0
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GROTER(cdev, ldev, w_cdev, w_ldev)
char *cdev;
long int *ldev;
int w_cdev, w_ldev;
{
  int fd, n;
  char name[64];
  n = *ldev;
  if (n > 63)
    n = 63;
  strncpy(name, cdev, n);
  name[n] = '\0';
  if ((fd = open(name, 2)) == -1) {
    perror(name);
    return -1;
  } else {
    return fd;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GROTER>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    (%rsi),%rbx
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x3f,%eax
  mov    %rsp,%rbp
  cmp    %eax,%ebx
  mov    %rbp,%rdi
  cmovg  %eax,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdx
  call   <strncpy@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movb   $0x0,(%rsp,%rbx,1)
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L21
L25:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x50,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <perror@plt>
  jmp    L25
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GROTER(cdev, ldev, w_cdev, w_ldev)
char *cdev;
long int *ldev;
int w_cdev, w_ldev;
{
  int fd, n;
  char name[64];
  n = *ldev;
  if (n > 63)
    n = 63;
  strncpy(name, cdev, n);
  name[n] = '\0';
  if ((fd = open(name, 2)) == -1) {
    perror(name);
    return -1;
  } else {
    return fd;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<expand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x24(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %esi,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  shll   -0x24(%rbp)
  shll   -0x28(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x3,-0x4(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void expand(unsigned char *out, unsigned char *in, unsigned int x, unsigned int y) {
  for (int i = 0; i < 4; i++) {
    out[i] = (in[i] - x) ^ y;
    x = x << 1;
    y = y << 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<expand>:
  endbr64
  mov    $0x0,%r8d
L1:
  movzbl (%rsi,%r8,1),%eax
  sub    %edx,%eax
  xor    %ecx,%eax
  mov    %al,(%rdi,%r8,1)
  add    %edx,%edx
  add    %ecx,%ecx
  add    $0x1,%r8
  cmp    $0x4,%r8
  jne    L1
  ret
```

assistant: ```c
void expand(unsigned char *out, unsigned char *in, unsigned int x, unsigned int y) {
  for (int i = 0; i < 4; i++) {
    out[i] = (in[i] - x) ^ y;
    x = x << 1;
    y = y << 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<expand>:
  endbr64
  xor    %r8d,%r8d
L4:
  movzbl (%rsi,%r8,1),%eax
  sub    %edx,%eax
  add    %edx,%edx
  xor    %ecx,%eax
  add    %ecx,%ecx
  mov    %al,(%rdi,%r8,1)
  add    $0x1,%r8
  cmp    $0x4,%r8
  jne    L4
  ret
```

assistant: ```c
void expand(unsigned char *out, unsigned char *in, unsigned int x, unsigned int y) {
  for (int i = 0; i < 4; i++) {
    out[i] = (in[i] - x) ^ y;
    x = x << 1;
    y = y << 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expand>:
  endbr64
  mov    %ecx,%eax
  movzbl (%rsi),%ecx
  lea    (%rdx,%rdx,1),%r8d
  sub    %edx,%ecx
  xor    %eax,%ecx
  mov    %cl,(%rdi)
  movzbl 0x1(%rsi),%ecx
  sub    %r8d,%ecx
  lea    (%rax,%rax,1),%r8d
  xor    %r8d,%ecx
  lea    0x0(,%rdx,4),%r8d
  shl    $0x3,%edx
  mov    %cl,0x1(%rdi)
  movzbl 0x2(%rsi),%ecx
  sub    %r8d,%ecx
  lea    0x0(,%rax,4),%r8d
  shl    $0x3,%eax
  xor    %r8d,%ecx
  mov    %cl,0x2(%rdi)
  movzbl 0x3(%rsi),%ecx
  sub    %edx,%ecx
  xor    %ecx,%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void expand(unsigned char *out, unsigned char *in, unsigned int x, unsigned int y) {
  for (int i = 0; i < 4; i++) {
    out[i] = (in[i] - x) ^ y;
    x = x << 1;
    y = y << 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extractnz_boundaries_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <extractnz_boundaries_ivector@plt>
  mov    -0x40(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L28
L31:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rdi
  lea    -0x28(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <extractnz_boundaries_ivector@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jge    L36
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L36:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jle    L40
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L40:
  addl   $0x1,-0x2c(%rbp)
L28:
  mov    -0x2c(%rbp),%eax
  cltq
  cmp    %rax,-0x48(%rbp)
  jge    L31
  mov    -0x18(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void extractnz_boundaries_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long *nclnz, long *nchnz) {
  int i;
  long a, b;
  long left, right;
  extractnz_boundaries_ivector(m[nrl], ncl, nch, &left, &right);
  for (i = nrl + 1; i <= nrh; i++) {
    extractnz_boundaries_ivector(m[i], ncl, nch, &a, &b);
    if (a < left)
      left = a;
    if (b > right)
      right = b;
  }
  *nclnz = left;
  *nchnz = right;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<extractnz_boundaries_imatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%r14
  mov    %r9,(%rsp)
  mov    0x80(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rcx
  mov    (%rdi,%rsi,8),%rdi
  lea    0x30(%rsp),%r8
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <extractnz_boundaries_ivector@plt>
  add    $0x1,%ebx
  movslq %ebx,%rax
  cmp    %rax,%r12
  jl     L59
  mov    %rax,%rbx
  lea    0x20(%rsp),%r15
  jmp    L41
L26:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jl     L59
L41:
  lea    0x18(%rsp),%rcx
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r15,%r8
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <extractnz_boundaries_ivector@plt>
  mov    0x18(%rsp),%rax
  cmp    0x28(%rsp),%rax
  jge    L58
  mov    %rax,0x28(%rsp)
L58:
  mov    0x20(%rsp),%rax
  cmp    0x30(%rsp),%rax
  jle    L26
  mov    %rax,0x30(%rsp)
  jmp    L26
L59:
  mov    0x28(%rsp),%rax
  mov    (%rsp),%rdx
  mov    %rax,(%rdx)
  mov    0x30(%rsp),%rax
  mov    0x8(%rsp),%rsi
  mov    %rax,(%rsi)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void extractnz_boundaries_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long *nclnz, long *nchnz) {
  int i;
  long a, b;
  long left, right;
  extractnz_boundaries_ivector(m[nrl], ncl, nch, &left, &right);
  for (i = nrl + 1; i <= nrh; i++) {
    extractnz_boundaries_ivector(m[i], ncl, nch, &a, &b);
    if (a < left)
      left = a;
    if (b > right)
      right = b;
  }
  *nclnz = left;
  *nchnz = right;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extractnz_boundaries_imatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x58,%rsp
  mov    (%rdi,%rsi,8),%rdi
  mov    %rbp,%rsi
  mov    %rdx,0x8(%rsp)
  mov    0x90(%rsp),%rax
  lea    0x38(%rsp),%rcx
  mov    %r12,%rdx
  mov    %r9,0x10(%rsp)
  lea    0x40(%rsp),%r8
  mov    %rax,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <extractnz_boundaries_ivector@plt>
  lea    0x1(%r13),%r9d
  movslq %r9d,%r9
  cmp    %r9,%r14
  jl     L47
  mov    %r9,%r15
  lea    0x30(%rsp),%r14
  lea    0x28(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%rbx,%r15,8),%rdi
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <extractnz_boundaries_ivector@plt>
  mov    0x28(%rsp),%rax
  cmp    0x38(%rsp),%rax
  jge    L23
  mov    %rax,0x38(%rsp)
L23:
  mov    0x30(%rsp),%rax
  cmp    0x40(%rsp),%rax
  jle    L12
  mov    %rax,0x40(%rsp)
L12:
  add    $0x1,%r15
  cmp    %r15,0x8(%rsp)
  jge    L28
L47:
  mov    0x38(%rsp),%rax
  mov    0x10(%rsp),%rbx
  mov    0x18(%rsp),%rdx
  mov    %rax,(%rbx)
  mov    0x40(%rsp),%rax
  mov    %rax,(%rdx)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void extractnz_boundaries_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long *nclnz, long *nchnz) {
  int i;
  long a, b;
  long left, right;
  extractnz_boundaries_ivector(m[nrl], ncl, nch, &left, &right);
  for (i = nrl + 1; i <= nrh; i++) {
    extractnz_boundaries_ivector(m[i], ncl, nch, &a, &b);
    if (a < left)
      left = a;
    if (b > right)
      right = b;
  }
  *nclnz = left;
  *nchnz = right;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extractnz_boundaries_imatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x58,%rsp
  mov    (%rdi,%rsi,8),%rdi
  mov    %rbp,%rsi
  mov    %rdx,0x8(%rsp)
  mov    0x90(%rsp),%rax
  lea    0x38(%rsp),%rcx
  mov    %r12,%rdx
  mov    %r9,0x10(%rsp)
  lea    0x40(%rsp),%r8
  mov    %rax,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <extractnz_boundaries_ivector@plt>
  lea    0x1(%r13),%r9d
  movslq %r9d,%r9
  cmp    %r9,%r14
  jl     L51
  mov    %r9,%r15
  lea    0x30(%rsp),%r14
  lea    0x28(%rsp),%r13
  xchg   %ax,%ax
L19:
  mov    (%rbx,%r15,8),%rdi
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <extractnz_boundaries_ivector@plt>
  mov    0x28(%rsp),%rax
  cmp    0x38(%rsp),%rax
  jge    L10
  mov    %rax,0x38(%rsp)
L10:
  mov    0x30(%rsp),%rax
  mov    0x40(%rsp),%rdx
  cmp    %rdx,%rax
  jle    L36
  mov    %rax,0x40(%rsp)
  mov    %rax,%rdx
L36:
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  jle    L19
L59:
  mov    0x38(%rsp),%rax
  mov    0x10(%rsp),%rbx
  mov    %rax,(%rbx)
  mov    0x18(%rsp),%rax
  mov    %rdx,(%rax)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L51:
  mov    0x40(%rsp),%rdx
  jmp    L59
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void extractnz_boundaries_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long *nclnz, long *nchnz) {
  int i;
  long a, b;
  long left, right;
  extractnz_boundaries_ivector(m[nrl], ncl, nch, &left, &right);
  for (i = nrl + 1; i <= nrh; i++) {
    extractnz_boundaries_ivector(m[i], ncl, nch, &a, &b);
    if (a < left)
      left = a;
    if (b > right)
      right = b;
  }
  *nclnz = left;
  *nchnz = right;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<slaRvlsrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x28(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sla_rvlsrk_@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
float slaRvlsrk(float ra, float dec) {
  float RA;
  float DEC;
  float result;
  RA = ra;
  DEC = dec;
  result = sla_rvlsrk_(&RA, &DEC);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<slaRvlsrk>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movss  %xmm0,(%rsp)
  movss  %xmm1,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <sla_rvlsrk_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float slaRvlsrk(float ra, float dec) {
  float RA;
  float DEC;
  float result;
  RA = ra;
  DEC = dec;
  result = sla_rvlsrk_(&RA, &DEC);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<slaRvlsrk>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movss  %xmm0,(%rsp)
  movss  %xmm1,0x4(%rsp)
  call   <sla_rvlsrk_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float slaRvlsrk(float ra, float dec) {
  float RA;
  float DEC;
  float result;
  RA = ra;
  DEC = dec;
  result = sla_rvlsrk_(&RA, &DEC);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slaRvlsrk>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movss  %xmm0,(%rsp)
  movss  %xmm1,0x4(%rsp)
  call   <sla_rvlsrk_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float slaRvlsrk(float ra, float dec) {
  float RA;
  float DEC;
  float result;
  RA = ra;
  DEC = dec;
  result = sla_rvlsrk_(&RA, &DEC);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L36:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x60,-0x1(%rbp)
  jle    L37
  cmpb   $0x7a,-0x1(%rbp)
  jle    L28
L37:
  cmpb   $0x40,-0x1(%rbp)
  jle    L36
  cmpb   $0x5a,-0x1(%rbp)
  jg     L36
L28:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char read_char() {
  char ch;
  do {
    ch = getchar();
  } while (!((((ch) >= 'a') && ((ch) <= 'z')) || (((ch) >= 'A') && ((ch) <= 'Z'))));
  return ch;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_char>:
  endbr64
  sub    $0x8,%rsp
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L2
  add    $0x8,%rsp
  ret
```

assistant: ```c
char read_char() {
  char ch;
  do {
    ch = getchar();
  } while (!((((ch) >= 'a') && ((ch) <= 'z')) || (((ch) >= 'A') && ((ch) <= 'Z'))));
  return ch;
}
```