ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x2a,-0x2(%rbp)
  movb   $0x7b,-0x1(%rbp)
  movb   $0xa,-0x1(%rbp)
  movb   $0x73,-0x1(%rbp)
  movb   $0xa8,-0x1(%rbp)
  movb   $0x15,-0x1(%rbp)
  movb   $0xd5,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  or     $0x59,%eax
  mov    %al,-0x1(%rbp)
  andb   $0xda,-0x1(%rbp)
  xorb   $0x59,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  shl    $0x2,%eax
  mov    %al,-0x1(%rbp)
  sarb   -0x1(%rbp)
  notb   -0x1(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  char result, value = 42;
  result = 42 | 89;
  result = 42 & 218;
  result = 42 ^ 89;
  result = 42 << 2;
  result = 42 >> 1;
  result = ~42;
  result = value | 89;
  result = result & 218;
  result = result ^ 89;
  result = result << 2;
  result = result >> 1;
  result = ~result;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char result, value = 42;
  result = 42 | 89;
  result = 42 & 218;
  result = 42 ^ 89;
  result = 42 << 2;
  result = 42 >> 1;
  result = ~42;
  result = value | 89;
  result = result & 218;
  result = result ^ 89;
  result = result << 2;
  result = result >> 1;
  result = ~result;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char result, value = 42;
  result = 42 | 89;
  result = 42 & 218;
  result = 42 ^ 89;
  result = 42 << 2;
  result = 42 >> 1;
  result = ~42;
  result = value | 89;
  result = result & 218;
  result = result ^ 89;
  result = result << 2;
  result = result >> 1;
  result = ~result;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char result, value = 42;
  result = 42 | 89;
  result = 42 & 218;
  result = 42 ^ 89;
  result = 42 << 2;
  result = 42 >> 1;
  result = ~42;
  result = value | 89;
  result = result & 218;
  result = result ^ 89;
  result = result << 2;
  result = result >> 1;
  result = ~result;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<darwin_my_getsockopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <darwin_convert_sockopt_option@plt>
  test   %eax,%eax
  jne    L11
  mov    $0x0,%eax
  jmp    L9
L11:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <getsockopt@plt>
L9:
  leave
  ret
```

assistant: ```c
int darwin_my_getsockopt(int sockfd, int level, int optname, void *optval, socklen_t *optlen) {
  if (!darwin_convert_sockopt_option(&level, &optname))
    return 0;
  return getsockopt(sockfd, level, optname, optval, optlen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<darwin_my_getsockopt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %esi,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %rcx,%rbp
  mov    %r8,%r12
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <darwin_convert_sockopt_option@plt>
  test   %eax,%eax
  jne    L16
L7:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %ebx,%edi
  call   <getsockopt@plt>
  jmp    L7
```

assistant: ```c
int darwin_my_getsockopt(int sockfd, int level, int optname, void *optval, socklen_t *optlen) {
  if (!darwin_convert_sockopt_option(&level, &optname))
    return 0;
  return getsockopt(sockfd, level, optname, optval, optlen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<darwin_my_getsockopt>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  mov    %edx,0x8(%rsp)
  call   <darwin_convert_sockopt_option@plt>
  test   %eax,%eax
  je     L4
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %ebp,%edi
  call   <getsockopt@plt>
L4:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int darwin_my_getsockopt(int sockfd, int level, int optname, void *optval, socklen_t *optlen) {
  if (!darwin_convert_sockopt_option(&level, &optname))
    return 0;
  return getsockopt(sockfd, level, optname, optval, optlen);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<darwin_my_getsockopt>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  mov    %edx,0x8(%rsp)
  call   <darwin_convert_sockopt_option@plt>
  test   %eax,%eax
  je     L1
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %ebp,%edi
  call   <getsockopt@plt>
L1:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int darwin_my_getsockopt(int sockfd, int level, int optname, void *optval, socklen_t *optlen) {
  if (!darwin_convert_sockopt_option(&level, &optname))
    return 0;
  return getsockopt(sockfd, level, optname, optval, optlen);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    %eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L22
L67:
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jg     L67
  jmp    L72
L56:
  subl   $0x1,-0x4(%rbp)
L72:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jl     L56
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L18
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L22
  cmpl   $0x0,-0x4(%rbp)
  jle    L50
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <qsc>
L50:
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L37
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <qsc>
L37:
  nop
  leave
  ret
```

assistant: ```c
void qsc(char *a, int n) {
  int i, j;
  char temp, p;
  p = *(a + (n >> 1));
  i = 0;
  j = n;
  do {
    while (*(a + i) < p)
      i++;
    while (*(a + j) > p)
      j--;
    if (i <= j) {
      temp = *(a + i);
      *(a + i) = *(a + j);
      *(a + j) = temp;
      i++;
      j--;
    }
  } while (i <= j);
  if (j > 0)
    qsc(a, j);
  if (n > i)
    qsc(a + i, n - i);
}
```
user: What is the c source code of the assembly code below:

```asm
<qsc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%eax
  sar    %eax
  cltq
  movzbl (%rdi,%rax,1),%ecx
  mov    $0x1,%r10d
  mov    $0x0,%r9d
  jmp    L59
L91:
  mov    %dl,(%rbx,%r9,1)
  mov    %r11b,(%rdi)
  mov    %r10d,%ebp
  sub    $0x1,%esi
  cmp    %esi,%r10d
  jg     L10
L71:
  add    $0x1,%r9
  add    $0x1,%r10d
L59:
  mov    %r9d,%ebp
  movzbl (%rbx,%r9,1),%r11d
  cmp    %cl,%r11b
  jl     L71
  movslq %esi,%rax
  lea    (%rbx,%rax,1),%rdi
  movzbl (%rdi),%edx
  cmp    %dl,%cl
  jge    L65
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    %rdx,%rax
  lea    -0x1(%rsi),%r8d
  sub    %edx,%r8d
L77:
  lea    (%r8,%rax,1),%esi
  mov    %rax,%rdi
  sub    $0x1,%rax
  movzbl 0x1(%rax),%edx
  cmp    %cl,%dl
  jg     L77
L65:
  cmp    %r9d,%esi
  jge    L91
L10:
  test   %esi,%esi
  jg     L97
L73:
  cmp    %ebp,%r12d
  jg     L61
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L97:
  mov    %rbx,%rdi
  call   <qsc>
  jmp    L73
L61:
  mov    %r12d,%esi
  sub    %ebp,%esi
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rdi
  call   <qsc>
  jmp    L47
```

assistant: ```c
void qsc(char *a, int n) {
  int i, j;
  char temp, p;
  p = *(a + (n >> 1));
  i = 0;
  j = n;
  do {
    while (*(a + i) < p)
      i++;
    while (*(a + j) > p)
      j--;
    if (i <= j) {
      temp = *(a + i);
      *(a + i) = *(a + j);
      *(a + j) = temp;
      i++;
      j--;
    }
  } while (i <= j);
  if (j > 0)
    qsc(a, j);
  if (n > i)
    qsc(a + i, n - i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<qsc>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
L39:
  mov    %r12d,%eax
  mov    %r12d,%esi
  mov    $0x1,%r11d
  xor    %r9d,%r9d
  sar    %eax
  cltq
  movzbl (%rbx,%rax,1),%edi
  movslq %r12d,%rax
  nopl   0x0(%rax,%rax,1)
L92:
  movzbl (%rbx,%r9,1),%r10d
  lea    (%rbx,%rax,1),%rcx
  movslq %r9d,%rbp
  movzbl (%rcx),%edx
  cmp    %dil,%r10b
  jl     L24
  cmp    %dl,%dil
  jge    L35
  lea    -0x1(%rbx,%rax,1),%rax
  lea    -0x1(%rsi),%r8d
  sub    %eax,%r8d
  nopl   (%rax)
L68:
  lea    (%r8,%rax,1),%esi
  mov    %rax,%rcx
  movzbl (%rax),%edx
  sub    $0x1,%rax
  cmp    %dil,%dl
  jg     L68
L35:
  cmp    %r9d,%esi
  jge    L59
L7:
  test   %esi,%esi
  jg     L82
L51:
  cmp    %ebp,%r12d
  jle    L46
  sub    %ebp,%r12d
  add    %rbp,%rbx
  jmp    L39
  nopl   0x0(%rax)
L59:
  movslq %r11d,%rbp
  sub    $0x1,%esi
  mov    %dl,(%rbx,%r9,1)
  mov    %r10b,(%rcx)
  cmp    %esi,%ebp
  jg     L7
  movslq %esi,%rax
L24:
  add    $0x1,%r9
  add    $0x1,%r11d
  jmp    L92
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L82:
  mov    %rbx,%rdi
  call   <qsc>
  jmp    L51
```

assistant: ```c
void qsc(char *a, int n) {
  int i, j;
  char temp, p;
  p = *(a + (n >> 1));
  i = 0;
  j = n;
  do {
    while (*(a + i) < p)
      i++;
    while (*(a + j) > p)
      j--;
    if (i <= j) {
      temp = *(a + i);
      *(a + i) = *(a + j);
      *(a + j) = temp;
      i++;
      j--;
    }
  } while (i <= j);
  if (j > 0)
    qsc(a, j);
  if (n > i)
    qsc(a + i, n - i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrix1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *matrix1() {
  static int arr[][2] = {{11, 12}, {21, 22}, {31, 32}, {41, 42}, {51, 52}};
  return *arr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix1>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

assistant: ```c
int *matrix1() {
  static int arr[][2] = {{11, 12}, {21, 22}, {31, 32}, {41, 42}, {51, 52}};
  return *arr;
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix1>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

assistant: ```c
int *matrix1() {
  static int arr[][2] = {{11, 12}, {21, 22}, {31, 32}, {41, 42}, {51, 52}};
  return *arr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrix1>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

assistant: ```c
int *matrix1() {
  static int arr[][2] = {{11, 12}, {21, 22}, {31, 32}, {41, 42}, {51, 52}};
  return *arr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L13:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <permute>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L20
L27:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: %s


assistant: ```c
void permute(char *a, int i, int n) {
  int j;
  if (i == n)
    printf("%s\n", a);
  else {
    for (j = i; j <= n; j++) {
      swap((a + i), (a + j));
      permute(a, i + 1, n);
      swap((a + i), (a + j));
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  cmp    %edx,%esi
  je     L12
  mov    %esi,%r13d
  mov    %edx,%r12d
  jg     L0
  movslq %esi,%rbp
  add    %rdi,%rbp
  mov    %rbp,%rbx
  lea    0x1(%rsi),%r15d
L32:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <permute>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  mov    %r13d,%eax
  sub    %ebp,%eax
  add    %ebx,%eax
  cmp    %eax,%r12d
  jge    L32
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: %s


assistant: ```c
void permute(char *a, int i, int n) {
  int j;
  if (i == n)
    printf("%s\n", a);
  else {
    for (j = i; j <= n; j++) {
      swap((a + i), (a + j));
      permute(a, i + 1, n);
      swap((a + i), (a + j));
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  je     L23
  jg     L4
  movslq %esi,%r12
  lea    0x1(%rsi),%r14d
  mov    %edx,%ebp
  add    %rdi,%r12
  sub    %r12d,%esi
  mov    %r12,%rbx
  mov    %esi,%r15d
L2:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <permute>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  lea    (%r15,%rbx,1),%eax
  cmp    %eax,%ebp
  jge    L2
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L23:
  add    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: %s


assistant: ```c
void permute(char *a, int i, int n) {
  int j;
  if (i == n)
    printf("%s\n", a);
  else {
    for (j = i; j <= n; j++) {
      swap((a + i), (a + j));
      permute(a, i + 1, n);
      swap((a + i), (a + j));
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %edi,-0x414(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L14
L8:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_line@plt>
L14:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[1024];
  while (fgets(buf, 1024, stdin) != NULL) {
    parse_line(buf);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rbx
  jmp    L2
L12:
  mov    %rsp,%rdi
  call   <parse_line@plt>
L2:
  mov    %rsp,%rdi
  mov    (%rbx),%edx
  mov    $0x400,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L12
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[1024];
  while (fgets(buf, 1024, stdin) != NULL) {
    parse_line(buf);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    D1(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L28
  nopl   0x0(%rax)
L20:
  mov    %rbx,%rdi
  call   <parse_line@plt>
L28:
  mov    0x0(%rbp),%edx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L20
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[1024];
  while (fgets(buf, 1024, stdin) != NULL) {
    parse_line(buf);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    D3(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L21
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rdi
  call   <parse_line@plt>
L21:
  mov    0x0(%rbp),%edx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L5
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[1024];
  while (fgets(buf, 1024, stdin) != NULL) {
    parse_line(buf);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  test   %eax,%eax
  je     L24
  mov    $0x4f,%eax
  jmp    L36
L24:
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%edi
  call   <nlz16@plt>
  mov    %eax,%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L25
  mov    -0x10(%rbp),%eax
  add    $0x3,%eax
  jmp    L7
L25:
  mov    $0x4,%eax
L7:
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x10(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x7,-0x8(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
L36:
  leave
  ret
```

assistant: ```c
unsigned int calc_index(uint32_t alloc_size) {
  if ((alloc_size >> (9 + 3 + 4)) != 0) {
    return ((9 + 1) * (1 << 3)) - 1;
  }
  unsigned int fli = 16 - nlz16(alloc_size >> (3 + 4));
  unsigned int shift = (fli == 0) ? 4 : (4 - 1 + fli);
  unsigned int sli = (alloc_size >> shift) & ((1 << 3) - 1);
  unsigned int index = (fli << 3) + sli;
  assert(fli <= 9);
  assert(sli <= (1 << 3) - 1);
  return index;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calc_index>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4f,%ebp
  mov    %edi,%eax
  shr    $0x10,%eax
  jne    L1
  mov    %edi,%ebx
  sar    $0x7,%edi
  call   <nlz16@plt>
  mov    $0x10,%edx
  mov    $0x13,%ecx
  sub    %eax,%ecx
  sub    %eax,%edx
  mov    $0x4,%eax
  cmove  %eax,%ecx
  sar    %cl,%ebx
  and    $0x7,%ebx
  lea    (%rbx,%rdx,8),%ebp
  cmp    $0x9,%edx
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
L1:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int calc_index(uint32_t alloc_size) {
  if ((alloc_size >> (9 + 3 + 4)) != 0) {
    return ((9 + 1) * (1 << 3)) - 1;
  }
  unsigned int fli = 16 - nlz16(alloc_size >> (3 + 4));
  unsigned int shift = (fli == 0) ? 4 : (4 - 1 + fli);
  unsigned int sli = (alloc_size >> shift) & ((1 << 3) - 1);
  unsigned int index = (fli << 3) + sli;
  assert(fli <= 9);
  assert(sli <= (1 << 3) - 1);
  return index;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calc_index>:
  endbr64
  push   %r12
  mov    %edi,%eax
  mov    $0x4f,%r12d
  push   %rbx
  sub    $0x8,%rsp
  shr    $0x10,%eax
  jne    L5
  mov    %edi,%ebx
  sar    $0x7,%edi
  call   <nlz16@plt>
  mov    $0x10,%edx
  mov    $0x13,%ecx
  sub    %eax,%ecx
  sub    %eax,%edx
  mov    $0x4,%eax
  cmove  %eax,%ecx
  xor    %edi,%edi
  sar    %cl,%ebx
  and    $0x7,%ebx
  cmp    $0x9,%edx
  setbe  %dil
  lea    (%rbx,%rdx,8),%r12d
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int calc_index(uint32_t alloc_size) {
  if ((alloc_size >> (9 + 3 + 4)) != 0) {
    return ((9 + 1) * (1 << 3)) - 1;
  }
  unsigned int fli = 16 - nlz16(alloc_size >> (3 + 4));
  unsigned int shift = (fli == 0) ? 4 : (4 - 1 + fli);
  unsigned int sli = (alloc_size >> shift) & ((1 << 3) - 1);
  unsigned int index = (fli << 3) + sli;
  assert(fli <= 9);
  assert(sli <= (1 << 3) - 1);
  return index;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_index>:
  endbr64
  push   %r12
  mov    %edi,%eax
  mov    $0x4f,%r12d
  push   %rbx
  sub    $0x8,%rsp
  shr    $0x10,%eax
  jne    L6
  mov    %edi,%ebx
  sar    $0x7,%edi
  call   <nlz16@plt>
  mov    $0x10,%edx
  mov    $0x13,%ecx
  sub    %eax,%ecx
  sub    %eax,%edx
  mov    $0x4,%eax
  cmove  %eax,%ecx
  xor    %edi,%edi
  sar    %cl,%ebx
  and    $0x7,%ebx
  cmp    $0x9,%edx
  setbe  %dil
  lea    (%rbx,%rdx,8),%r12d
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int calc_index(uint32_t alloc_size) {
  if ((alloc_size >> (9 + 3 + 4)) != 0) {
    return ((9 + 1) * (1 << 3)) - 1;
  }
  unsigned int fli = 16 - nlz16(alloc_size >> (3 + 4));
  unsigned int shift = (fli == 0) ? 4 : (4 - 1 + fli);
  unsigned int sli = (alloc_size >> shift) & ((1 << 3) - 1);
  unsigned int index = (fli << 3) + sli;
  assert(fli <= 9);
  assert(sli <= (1 << 3) - 1);
  return index;
}
```