ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<mmap>:
  endbr64
  sub    $0x48,%rsp
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movslq %r8d,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  mov    %rdx,0x10(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x20(%rsp)
  mov    %r9,0x28(%rsp)
  call   <_mmap@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__ptr_t mmap(__ptr_t addr, size_t len, int prot, int flags, int fd, off_t off) {
  unsigned long buffer[6];
  buffer[0] = (unsigned long)addr;
  buffer[1] = (unsigned long)len;
  buffer[2] = (unsigned long)prot;
  buffer[3] = (unsigned long)flags;
  buffer[4] = (unsigned long)fd;
  buffer[5] = (unsigned long)off;
  return (__ptr_t)_mmap(buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mmap>:
  endbr64
  sub    $0x48,%rsp
  movq   %rdi,%xmm0
  movq   %rsi,%xmm1
  movslq %ecx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  punpcklqdq %xmm1,%xmm0
  movslq %edx,%rax
  movq   %rcx,%xmm2
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm0
  movslq %r8d,%rax
  movq   %r9,%xmm3
  punpcklqdq %xmm2,%xmm0
  mov    %rsp,%rdi
  movaps %xmm0,0x10(%rsp)
  movq   %rax,%xmm0
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <_mmap@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__ptr_t mmap(__ptr_t addr, size_t len, int prot, int flags, int fd, off_t off) {
  unsigned long buffer[6];
  buffer[0] = (unsigned long)addr;
  buffer[1] = (unsigned long)len;
  buffer[2] = (unsigned long)prot;
  buffer[3] = (unsigned long)flags;
  buffer[4] = (unsigned long)fd;
  buffer[5] = (unsigned long)off;
  return (__ptr_t)_mmap(buffer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isANumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L61
L62:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L25
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L12
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  movl   $0x1,-0x4(%rbp)
  jmp    L30
L12:
  mov    $0x0,%eax
  jmp    L31
L25:
  nop
L30:
  addl   $0x1,-0x8(%rbp)
L61:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L62
  mov    $0x1,%eax
L31:
  leave
  ret
```

assistant: ```c
int isANumber(char *num) {
  int i = 0;
  int check = 0;
  for (i = 0; i < strlen(num); ++i) {
    if (isdigit(num[i])) {
      continue;
    } else if (num[i] == '.' && check == 0) {
      check = 1;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isANumber>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x1,%r13d
  jmp    L18
L47:
  add    $0x1,%rbx
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L14
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L47
  cmpb   $0x2e,0x0(%rbp,%rbx,1)
  jne    L27
  test   %r12d,%r12d
  jne    L27
  mov    %r13d,%r12d
  jmp    L47
L14:
  mov    $0x1,%eax
  jmp    L22
L27:
  mov    $0x0,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int isANumber(char *num) {
  int i = 0;
  int check = 0;
  for (i = 0; i < strlen(num); ++i) {
    if (isdigit(num[i])) {
      continue;
    } else if (num[i] == '.' && check == 0) {
      check = 1;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isANumber>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L16:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L29
  cmpb   $0x2e,0x0(%rbp,%rbx,1)
  jne    L9
  test   %r12d,%r12d
  jne    L9
  mov    $0x1,%r12d
L29:
  add    $0x1,%rbx
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int isANumber(char *num) {
  int i = 0;
  int check = 0;
  for (i = 0; i < strlen(num); ++i) {
    if (isdigit(num[i])) {
      continue;
    } else if (num[i] == '.' && check == 0) {
      check = 1;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<isANumber>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L36:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L16
  cmpb   $0x2e,0x0(%rbp,%rbx,1)
  jne    L28
  test   %r12d,%r12d
  jne    L28
  mov    $0x1,%r12d
L16:
  add    $0x1,%rbx
L22:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L36
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int isANumber(char *num) {
  int i = 0;
  int check = 0;
  for (i = 0; i < strlen(num); ++i) {
    if (isdigit(num[i])) {
      continue;
    } else if (num[i] == '.' && check == 0) {
      check = 1;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kobject_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
struct kobject *kobject_get(struct kobject *x) {
  struct kobject *a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kobject_get>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct kobject *kobject_get(struct kobject *x) {
  struct kobject *a;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kobject_get>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct kobject *kobject_get(struct kobject *x) {
  struct kobject *a;
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kobject_get>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct kobject *kobject_get(struct kobject *x) {
  struct kobject *a;
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<asm_bts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  bts    %rdx,(%rax)
  sbb    %rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long asm_bts(unsigned long *f, unsigned long i) {
  unsigned long ret;
  asm("btsq %2, %1 \n"
      "sbbq %0, %0"
      : "=r"(ret)
      : "m"(*f), "r"(i));
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<asm_bts>:
  endbr64
  bts    %rsi,(%rdi)
  sbb    %rax,%rax
  ret
```

assistant: ```c
unsigned long asm_bts(unsigned long *f, unsigned long i) {
  unsigned long ret;
  asm("btsq %2, %1 \n"
      "sbbq %0, %0"
      : "=r"(ret)
      : "m"(*f), "r"(i));
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<asm_bts>:
  endbr64
  bts    %rsi,(%rdi)
  sbb    %rax,%rax
  ret
```

assistant: ```c
unsigned long asm_bts(unsigned long *f, unsigned long i) {
  unsigned long ret;
  asm("btsq %2, %1 \n"
      "sbbq %0, %0"
      : "=r"(ret)
      : "m"(*f), "r"(i));
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<asm_bts>:
  endbr64
  bts    %rsi,(%rdi)
  sbb    %rax,%rax
  ret
```

assistant: ```c
unsigned long asm_bts(unsigned long *f, unsigned long i) {
  unsigned long ret;
  asm("btsq %2, %1 \n"
      "sbbq %0, %0"
      : "=r"(ret)
      : "m"(*f), "r"(i));
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L27:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L31
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jbe    L31
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jbe    L27
L31:
  mov    -0x4(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int n_digits(const unsigned char source[], const int position, const int length) {
  int i;
  for (i = position; (i < length) && ((source[i] >= '0') && (source[i] <= '9')); i++)
    ;
  return i - position;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<n_digits>:
  endbr64
  cmp    %edx,%esi
  jge    L18
  movslq %esi,%rax
  add    %rax,%rdi
  mov    %esi,%eax
L0:
  movzbl (%rdi),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L1
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%edx
  jne    L0
  mov    %edx,%eax
L1:
  sub    %esi,%eax
  ret
L18:
  mov    %esi,%eax
  jmp    L1
```

assistant: ```c
int n_digits(const unsigned char source[], const int position, const int length) {
  int i;
  for (i = position; (i < length) && ((source[i] >= '0') && (source[i] <= '9')); i++)
    ;
  return i - position;
}
```
user: What is the c source code of the assembly code below?

```asm
<n_digits>:
  endbr64
  movslq %esi,%rax
  add    %rax,%rdi
  mov    %esi,%eax
  cmp    %edx,%esi
  jl     L26
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%edx
  je     L29
L26:
  movzbl (%rdi),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  jbe    L11
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L29:
  mov    %edx,%eax
  sub    %esi,%eax
  ret
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int n_digits(const unsigned char source[], const int position, const int length) {
  int i;
  for (i = position; (i < length) && ((source[i] >= '0') && (source[i] <= '9')); i++)
    ;
  return i - position;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_digits>:
  endbr64
  movslq %esi,%rax
  add    %rax,%rdi
  mov    %esi,%eax
  cmp    %edx,%esi
  jl     L27
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%edx
  je     L33
L27:
  movzbl (%rdi),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  jbe    L24
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L33:
  mov    %edx,%eax
  sub    %esi,%eax
  ret
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int n_digits(const unsigned char source[], const int position, const int length) {
  int i;
  for (i = position; (i < length) && ((source[i] >= '0') && (source[i] <= '9')); i++)
    ;
  return i - position;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<MexicanHatFun_real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    $0x3,%edi
  call   <sqrt@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x48(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    $0x2,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  movsd  D30(%rip),%xmm0
  divsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x3c(%rbp),%eax
  shr    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x18(%rbp)
  jmp    L19
L17:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movsd  -0x48(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D30(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   D33(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  D35(%rip),%xmm1
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mulsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L19:
  mov    -0x3c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L17
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D30
type: byte[8]
name: unpack_data
arguments: data_tag: D33
type: byte[8]
name: unpack_data
arguments: data_tag: D35
type: byte[8]

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
void MexicanHatFun_real(double *w, int *center, double dump, unsigned int Ls, double scale) {
  double k, daux;
  int u, u0;
  k = 2 / sqrt(3 * sqrt(3.14159265358979328) * scale);
  *center = Ls / 2;
  scale = 1 / scale;
  u0 = Ls / 2;
  for (u = -u0; u < (signed)Ls - u0; u++) {
    daux = scale * u;
    daux *= daux;
    *w++ = k * (daux - 1) * exp(-daux / 2);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MexicanHatFun_real>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  movsd  %xmm1,0x8(%rsp)
  mov    $0x3,%edi
  call   <sqrt@plt>
  lea    (%rax,%rax,2),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    $0x2,%eax
  cltd
  idiv   %ecx
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm5
  movsd  %xmm5,0x10(%rsp)
  mov    %r12d,%eax
  shr    %eax
  mov    %eax,(%rbx)
  movsd  D18(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x18(%rsp)
  mov    %eax,%ebx
  neg    %ebx
  sub    %eax,%r12d
  cmp    %r12d,%ebx
  jge    L10
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x18(%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rsp)
  xorpd  D29(%rip),%xmm0
  mulsd  D28(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  add    $0x8,%rbp
  movsd  0x8(%rsp),%xmm0
  subsd  D18(%rip),%xmm0
  mulsd  0x10(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L14
L10:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D29
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D28
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void MexicanHatFun_real(double *w, int *center, double dump, unsigned int Ls, double scale) {
  double k, daux;
  int u, u0;
  k = 2 / sqrt(3 * sqrt(3.14159265358979328) * scale);
  *center = Ls / 2;
  scale = 1 / scale;
  u0 = Ls / 2;
  for (u = -u0; u < (signed)Ls - u0; u++) {
    daux = scale * u;
    daux *= daux;
    *w++ = k * (daux - 1) * exp(-daux / 2);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MexicanHatFun_real>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x3,%edi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  lea    (%rax,%rax,2),%eax
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  pxor   %xmm7,%xmm7
  movsd  D0(%rip),%xmm6
  divsd  0x8(%rsp),%xmm6
  mov    %eax,%r8d
  mov    $0x2,%eax
  movsd  %xmm6,0x18(%rsp)
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm7
  mov    %ebp,%eax
  shr    %eax
  mov    %eax,(%rbx)
  mov    %eax,%ebx
  sub    %eax,%ebp
  neg    %ebx
  movsd  %xmm7,0x10(%rsp)
  cmp    %ebp,%ebx
  jge    L8
  nopl   0x0(%rax)
L2:
  pxor   %xmm0,%xmm0
  add    $0x8,%r12
  cvtsi2sd %ebx,%xmm0
  mulsd  0x18(%rsp),%xmm0
  add    $0x1,%ebx
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  xorpd  D12(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  D16(%rip),%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  subsd  D0(%rip),%xmm1
  movapd %xmm0,%xmm2
  movsd  0x10(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,-0x8(%r12)
  cmp    %ebp,%ebx
  jne    L2
L8:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: byte[8]
name: retrieve_data
arguments: tag: D12
datatype: byte[16]
name: retrieve_data
arguments: tag: D16
datatype: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void MexicanHatFun_real(double *w, int *center, double dump, unsigned int Ls, double scale) {
  double k, daux;
  int u, u0;
  k = 2 / sqrt(3 * sqrt(3.14159265358979328) * scale);
  *center = Ls / 2;
  scale = 1 / scale;
  u0 = Ls / 2;
  for (u = -u0; u < (signed)Ls - u0; u++) {
    daux = scale * u;
    daux *= daux;
    *w++ = k * (daux - 1) * exp(-daux / 2);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<MexicanHatFun_real>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x3,%edi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  lea    (%rax,%rax,2),%eax
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  pxor   %xmm7,%xmm7
  movsd  D36(%rip),%xmm6
  divsd  0x8(%rsp),%xmm6
  mov    %eax,%r8d
  mov    $0x2,%eax
  movsd  %xmm6,0x18(%rsp)
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm7
  mov    %ebp,%eax
  shr    %eax
  mov    %eax,(%rbx)
  mov    %eax,%ebx
  sub    %eax,%ebp
  neg    %ebx
  movsd  %xmm7,0x10(%rsp)
  cmp    %ebp,%ebx
  jge    L9
  nopl   0x0(%rax)
L10:
  pxor   %xmm0,%xmm0
  add    $0x8,%r12
  cvtsi2sd %ebx,%xmm0
  mulsd  0x18(%rsp),%xmm0
  add    $0x1,%ebx
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  xorpd  D15(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  D14(%rip),%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  subsd  D36(%rip),%xmm1
  movapd %xmm0,%xmm2
  movsd  0x10(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,-0x8(%r12)
  cmp    %ebp,%ebx
  jne    L10
L9:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D36
datatype: byte[8]
name: disassemble_data
arguments: label: D15
datatype: byte[16]
name: disassemble_data
arguments: label: D14
datatype: byte[8]

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void MexicanHatFun_real(double *w, int *center, double dump, unsigned int Ls, double scale) {
  double k, daux;
  int u, u0;
  k = 2 / sqrt(3 * sqrt(3.14159265358979328) * scale);
  *center = Ls / 2;
  scale = 1 / scale;
  u0 = Ls / 2;
  for (u = -u0; u < (signed)Ls - u0; u++) {
    daux = scale * u;
    daux *= daux;
    *w++ = k * (daux - 1) * exp(-daux / 2);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MwChomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L3:
  nop
  leave
  ret
```

assistant: ```c
void MwChomp(char *p) {
  if ((p = strchr(p, '\n')))
    *p = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<MwChomp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  movb   $0x0,(%rax)
L1:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MwChomp(char *p) {
  if ((p = strchr(p, '\n')))
    *p = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MwChomp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MwChomp(char *p) {
  if ((p = strchr(p, '\n')))
    *p = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<MwChomp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MwChomp(char *p) {
  if ((p = strchr(p, '\n')))
    *p = '\0';
}
```