user: 这段汇编代码用C语言表示是什么样的？

```asm
<rl_redisPopcount>:
  endbr64
  mov    %rdi,%r8
  mov    %rdi,%rdx
  and    $0x3,%r8d
  je     L74
  xor    %r8d,%r8d
  test   %rsi,%rsi
  je     L38
  lea    D5(%rip),%rax
  jmp    L23
  nopl   (%rax)
L34:
  test   %rsi,%rsi
  je     L38
L23:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  sub    $0x1,%rsi
  movzbl (%rax,%rcx,1),%ecx
  add    %rcx,%r8
  test   $0x3,%dl
  jne    L34
L74:
  push   %rbp
  mov    %rdx,%rdi
  push   %rbx
  cmp    $0xf,%rsi
  jle    L2
  sub    $0x10,%rsi
  mov    %rsi,%r9
  shr    $0x4,%r9
  lea    0x1(%r9),%rdi
  shl    $0x4,%rdi
  add    %rdx,%rdi
  nopl   (%rax)
L8:
  mov    (%rdx),%r11d
  mov    0x4(%rdx),%r10d
  add    $0x10,%rdx
  mov    -0x8(%rdx),%ecx
  mov    -0x4(%rdx),%eax
  mov    %r11d,%ebx
  sar    %ebx
  and    $0x55555555,%ebx
  sub    %ebx,%r11d
  mov    %r11d,%ebp
  sar    $0x2,%r11d
  and    $0x33333333,%r11d
  and    $0x33333333,%ebp
  add    %r11d,%ebp
  mov    %r10d,%r11d
  sar    %r11d
  and    $0x55555555,%r11d
  sub    %r11d,%r10d
  mov    %r10d,%ebx
  sar    $0x2,%r10d
  and    $0x33333333,%r10d
  and    $0x33333333,%ebx
  add    %r10d,%ebx
  mov    %ecx,%r10d
  sar    %r10d
  and    $0x55555555,%r10d
  sub    %r10d,%ecx
  mov    %ecx,%r11d
  sar    $0x2,%ecx
  and    $0x33333333,%ecx
  and    $0x33333333,%r11d
  add    %ecx,%r11d
  mov    %eax,%ecx
  sar    %ecx
  and    $0x55555555,%ecx
  sub    %ecx,%eax
  mov    %ebx,%ecx
  mov    %eax,%r10d
  sar    $0x2,%eax
  and    $0x33333333,%eax
  and    $0x33333333,%r10d
  add    %eax,%r10d
  mov    %ebp,%eax
  sar    $0x4,%eax
  add    %ebp,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x4,%ecx
  add    %ebx,%ecx
  and    $0xf0f0f0f,%ecx
  imul   $0x1010101,%ecx,%ecx
  sar    $0x18,%eax
  sar    $0x18,%ecx
  add    %ecx,%eax
  mov    %r11d,%ecx
  sar    $0x4,%ecx
  add    %r11d,%ecx
  and    $0xf0f0f0f,%ecx
  imul   $0x1010101,%ecx,%ecx
  sar    $0x18,%ecx
  add    %ecx,%eax
  mov    %r10d,%ecx
  sar    $0x4,%ecx
  add    %r10d,%ecx
  and    $0xf0f0f0f,%ecx
  imul   $0x1010101,%ecx,%ecx
  sar    $0x18,%ecx
  add    %ecx,%eax
  cltq
  add    %rax,%r8
  cmp    %rdi,%rdx
  jne    L8
  shl    $0x4,%r9
  sub    %r9,%rsi
L2:
  test   %rsi,%rsi
  je     L54
  add    %rdi,%rsi
  lea    D5(%rip),%rax
  nopl   0x0(%rax)
L12:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  movzbl (%rax,%rdx,1),%edx
  add    %rdx,%r8
  cmp    %rsi,%rdi
  jne    L12
L54:
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L38:
  mov    %r8,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: 

assistant: ```c
size_t rl_redisPopcount(void *s, long count) {
  size_t bits = 0;
  unsigned char *p = s;
  uint32_t *p4;
  static const unsigned char bitsinbyte[256] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8};
  while ((unsigned long)p & 3 && count) {
    bits += bitsinbyte[*p++];
    count--;
  }
  p4 = (uint32_t *)p;
  while (count >= 16) {
    uint32_t aux1, aux2, aux3, aux4;
    aux1 = *p4++;
    aux2 = *p4++;
    aux3 = *p4++;
    aux4 = *p4++;
    count -= 16;
    aux1 = aux1 - ((aux1 >> 1) & 0x55555555);
    aux1 = (aux1 & 0x33333333) + ((aux1 >> 2) & 0x33333333);
    aux2 = aux2 - ((aux2 >> 1) & 0x55555555);
    aux2 = (aux2 & 0x33333333) + ((aux2 >> 2) & 0x33333333);
    aux3 = aux3 - ((aux3 >> 1) & 0x55555555);
    aux3 = (aux3 & 0x33333333) + ((aux3 >> 2) & 0x33333333);
    aux4 = aux4 - ((aux4 >> 1) & 0x55555555);
    aux4 = (aux4 & 0x33333333) + ((aux4 >> 2) & 0x33333333);
    bits += ((((aux1 + (aux1 >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24) + ((((aux2 + (aux2 >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24) + ((((aux3 + (aux3 >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24) + ((((aux4 + (aux4 >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24);
  }
  p = (unsigned char *)p4;
  while (count--)
    bits += bitsinbyte[*p++];
  return bits;
}
```