ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<getFirstCharFromConsole>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %rdi,%rdi
  je     L8
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <getStringFromConsole@plt>
L8:
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getFirstCharFromConsole(const char *consoleStr) {
  char ret = 0;
  if (consoleStr != NULL) {
    getStringFromConsole(consoleStr, &ret, 1);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getFirstCharFromConsole>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %rdi,%rdi
  je     L4
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <getStringFromConsole@plt>
  movzbl 0x7(%rsp),%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getFirstCharFromConsole(const char *consoleStr) {
  char ret = 0;
  if (consoleStr != NULL) {
    getStringFromConsole(consoleStr, &ret, 1);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<getFirstCharFromConsole>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %rdi,%rdi
  je     L5
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <getStringFromConsole@plt>
  movzbl 0x7(%rsp),%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getFirstCharFromConsole(const char *consoleStr) {
  char ret = 0;
  if (consoleStr != NULL) {
    getStringFromConsole(consoleStr, &ret, 1);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_prefix_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_name_from_path@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L30
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L30
  cmpl   $0x0,-0x3c(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <my_str_malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    %rax,%rbx
  mov    %rbx,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L16
L30:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <my_str_malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *get_prefix_name(const char *fullname, int isfolder) {
  char *parse_name = NULL;
  char *p = NULL;
  char *filename = NULL;
  filename = parse_name_from_path(fullname);
  p = strrchr(filename, '.');
  if (p && filename[0] != '.' && !isfolder) {
    parse_name = my_str_malloc(strlen(filename) - strlen(p) + 1);
    strncpy(parse_name, filename, strlen(filename) - strlen(p));
  } else {
    parse_name = my_str_malloc(strlen(filename) + 1);
    strcpy(parse_name, filename);
  }
  free(filename);
  filename = NULL;
  ;
  return parse_name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_prefix_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <parse_name_from_path@plt>
  mov    %rax,%rbx
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L37
  mov    %rax,%r12
  cmpb   $0x2e,(%rbx)
  je     L37
  test   %ebp,%ebp
  je     L24
L37:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <my_str_malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L30:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %rax,%rbp
  lea    0x1(%rbp),%rdi
  call   <my_str_malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  sub    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L30
```

assistant: ```c
char *get_prefix_name(const char *fullname, int isfolder) {
  char *parse_name = NULL;
  char *p = NULL;
  char *filename = NULL;
  filename = parse_name_from_path(fullname);
  p = strrchr(filename, '.');
  if (p && filename[0] != '.' && !isfolder) {
    parse_name = my_str_malloc(strlen(filename) - strlen(p) + 1);
    strncpy(parse_name, filename, strlen(filename) - strlen(p));
  } else {
    parse_name = my_str_malloc(strlen(filename) + 1);
    strcpy(parse_name, filename);
  }
  free(filename);
  filename = NULL;
  ;
  return parse_name;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_prefix_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <parse_name_from_path@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L22
  cmpb   $0x2e,0x0(%rbp)
  je     L22
  test   %r12d,%r12d
  je     L24
L22:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <my_str_malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
L27:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  sub    %rax,%r12
  lea    0x1(%r12),%rdi
  call   <my_str_malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %rax,%rbx
  mov    %rbx,%rdx
  call   <strncpy@plt>
  jmp    L27
```

assistant: ```c
char *get_prefix_name(const char *fullname, int isfolder) {
  char *parse_name = NULL;
  char *p = NULL;
  char *filename = NULL;
  filename = parse_name_from_path(fullname);
  p = strrchr(filename, '.');
  if (p && filename[0] != '.' && !isfolder) {
    parse_name = my_str_malloc(strlen(filename) - strlen(p) + 1);
    strncpy(parse_name, filename, strlen(filename) - strlen(p));
  } else {
    parse_name = my_str_malloc(strlen(filename) + 1);
    strcpy(parse_name, filename);
  }
  free(filename);
  filename = NULL;
  ;
  return parse_name;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_prefix_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <parse_name_from_path@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L14
  cmpb   $0x2e,0x0(%rbp)
  je     L14
  test   %r12d,%r12d
  je     L31
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <my_str_malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
L15:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  sub    %rax,%r12
  lea    0x1(%r12),%rdi
  call   <my_str_malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %rax,%rbx
  mov    %rbx,%rdx
  call   <strncpy@plt>
  jmp    L15
```

assistant: ```c
char *get_prefix_name(const char *fullname, int isfolder) {
  char *parse_name = NULL;
  char *p = NULL;
  char *filename = NULL;
  filename = parse_name_from_path(fullname);
  p = strrchr(filename, '.');
  if (p && filename[0] != '.' && !isfolder) {
    parse_name = my_str_malloc(strlen(filename) - strlen(p) + 1);
    strncpy(parse_name, filename, strlen(filename) - strlen(p));
  } else {
    parse_name = my_str_malloc(strlen(filename) + 1);
    strcpy(parse_name, filename);
  }
  free(filename);
  filename = NULL;
  ;
  return parse_name;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L22
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  cmpl   $0x0,-0xc(%rbp)
  je     L17
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D34
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D2: Ingrese el numero a verificar.: 

tool: D34: %i

tool: D7: El numero es par


tool: D11: El numero es impar


assistant: ```c
int main(void) {
  int numero_A_Probar, residuo;
  printf("Ingrese el numero a verificar.: ");
  scanf("%i", &numero_A_Probar);
  residuo = numero_A_Probar % 2;
  if (residuo == 0) {
    printf("El numero es par\n");
  }
  if (residuo != 0) {
    printf("El numero es impar\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  je     L26
  lea    D3(%rip),%rdi
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D34
type_guessed: string

tool: D20: Ingrese el numero a verificar.: 

tool: D13: %i

tool: D3: El numero es impar


tool: D34: El numero es par


assistant: ```c
int main(void) {
  int numero_A_Probar, residuo;
  printf("Ingrese el numero a verificar.: ");
  scanf("%i", &numero_A_Probar);
  residuo = numero_A_Probar % 2;
  if (residuo == 0) {
    printf("El numero es par\n");
  }
  if (residuo != 0) {
    printf("El numero es impar\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  je     L18
  lea    D16(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L18:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D32
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string

tool: D8: Ingrese el numero a verificar.: 

tool: D32: %i

tool: D16: El numero es impar


tool: D17: El numero es par


assistant: ```c
int main(void) {
  int numero_A_Probar, residuo;
  printf("Ingrese el numero a verificar.: ");
  scanf("%i", &numero_A_Probar);
  residuo = numero_A_Probar % 2;
  if (residuo == 0) {
    printf("El numero es par\n");
  }
  if (residuo != 0) {
    printf("El numero es impar\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  je     L6
  lea    D25(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string

tool: D8: Ingrese el numero a verificar.: 

tool: D38: %i

tool: D25: El numero es impar


tool: D13: El numero es par


assistant: ```c
int main(void) {
  int numero_A_Probar, residuo;
  printf("Ingrese el numero a verificar.: ");
  scanf("%i", &numero_A_Probar);
  residuo = numero_A_Probar % 2;
  if (residuo == 0) {
    printf("El numero es par\n");
  }
  if (residuo != 0) {
    printf("El numero es impar\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <fahrenheitFromCelcius@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: Water freezes at %f degrees Fahrenheit.


assistant: ```c
int main(int argc, const char *argv[]) {
  float freezeInC = 0;
  float freezeInF = fahrenheitFromCelcius(freezeInC);
  printf("Water freezes at %f degrees Fahrenheit.\n", freezeInF);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <fahrenheitFromCelcius@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: Water freezes at %f degrees Fahrenheit.


assistant: ```c
int main(int argc, const char *argv[]) {
  float freezeInC = 0;
  float freezeInF = fahrenheitFromCelcius(freezeInC);
  printf("Water freezes at %f degrees Fahrenheit.\n", freezeInF);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <fahrenheitFromCelcius@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: Water freezes at %f degrees Fahrenheit.


assistant: ```c
int main(int argc, const char *argv[]) {
  float freezeInC = 0;
  float freezeInF = fahrenheitFromCelcius(freezeInC);
  printf("Water freezes at %f degrees Fahrenheit.\n", freezeInF);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <fahrenheitFromCelcius@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: Water freezes at %f degrees Fahrenheit.


assistant: ```c
int main(int argc, const char *argv[]) {
  float freezeInC = 0;
  float freezeInF = fahrenheitFromCelcius(freezeInC);
  printf("Water freezes at %f degrees Fahrenheit.\n", freezeInF);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mod_mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x7fffffff,-0x14(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x7fffffff,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x7fffffff,-0x1c(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x1f,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7fffffff,-0x4(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  sub    $0x7fffffff,%eax
  jmp    L7
L0:
  mov    -0x4(%rbp),%eax
L7:
  leave
  ret
```

assistant: ```c
uint_fast32_t mod_mac(uint_fast32_t sum, uint_fast32_t a, uint_fast32_t b) {
  uint_fast64_t temp;
  uint_fast32_t temp2;
  assert(sum <= 0x7FFFFFFE);
  assert(a <= 0x7FFFFFFE);
  assert(b <= 0x7FFFFFFE);
  temp = (uint_fast64_t)a * b + sum;
  temp2 = (uint_fast32_t)(temp & 0x7FFFFFFF) + (uint_fast32_t)(temp >> 31);
  return (temp2 >= 0x7FFFFFFF) ? (temp2 - 0x7FFFFFFF) : temp2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mod_mac>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  cmp    $0x7fffffff,%edi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x7fffffff,%ebx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x7fffffff,%r12d
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  imul   %r12d,%ebx
  add    %ebp,%ebx
  mov    %ebx,%eax
  and    $0x7fffffff,%eax
  sar    $0x1f,%ebx
  add    %ebx,%eax
  cmp    $0x7fffffff,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint_fast32_t mod_mac(uint_fast32_t sum, uint_fast32_t a, uint_fast32_t b) {
  uint_fast64_t temp;
  uint_fast32_t temp2;
  assert(sum <= 0x7FFFFFFE);
  assert(a <= 0x7FFFFFFE);
  assert(b <= 0x7FFFFFFE);
  temp = (uint_fast64_t)a * b + sum;
  temp2 = (uint_fast32_t)(temp & 0x7FFFFFFF) + (uint_fast32_t)(temp >> 31);
  return (temp2 >= 0x7FFFFFFF) ? (temp2 - 0x7FFFFFFF) : temp2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mod_mac>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  cmp    $0x7fffffff,%ebp
  mov    %esi,%ebx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7fffffff,%ebx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7fffffff,%r12d
  setne  %dil
  imul   %r12d,%ebx
  call   <assert@plt>
  xor    %edx,%edx
  add    %ebp,%ebx
  mov    %ebx,%eax
  sar    $0x1f,%ebx
  and    $0x7fffffff,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  cmp    $0x7fffffff,%eax
  pop    %r12
  cmove  %edx,%eax
  ret
```

assistant: ```c
uint_fast32_t mod_mac(uint_fast32_t sum, uint_fast32_t a, uint_fast32_t b) {
  uint_fast64_t temp;
  uint_fast32_t temp2;
  assert(sum <= 0x7FFFFFFE);
  assert(a <= 0x7FFFFFFE);
  assert(b <= 0x7FFFFFFE);
  temp = (uint_fast64_t)a * b + sum;
  temp2 = (uint_fast32_t)(temp & 0x7FFFFFFF) + (uint_fast32_t)(temp >> 31);
  return (temp2 >= 0x7FFFFFFF) ? (temp2 - 0x7FFFFFFF) : temp2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mod_mac>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  cmp    $0x7fffffff,%ebp
  mov    %esi,%ebx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7fffffff,%ebx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7fffffff,%r12d
  setne  %dil
  imul   %r12d,%ebx
  call   <assert@plt>
  xor    %edx,%edx
  add    %ebp,%ebx
  mov    %ebx,%eax
  sar    $0x1f,%ebx
  and    $0x7fffffff,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  cmp    $0x7fffffff,%eax
  pop    %r12
  cmove  %edx,%eax
  ret
```

assistant: ```c
uint_fast32_t mod_mac(uint_fast32_t sum, uint_fast32_t a, uint_fast32_t b) {
  uint_fast64_t temp;
  uint_fast32_t temp2;
  assert(sum <= 0x7FFFFFFE);
  assert(a <= 0x7FFFFFFE);
  assert(b <= 0x7FFFFFFE);
  temp = (uint_fast64_t)a * b + sum;
  temp2 = (uint_fast32_t)(temp & 0x7FFFFFFF) + (uint_fast32_t)(temp >> 31);
  return (temp2 >= 0x7FFFFFFF) ? (temp2 - 0x7FFFFFFF) : temp2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addRoundKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L10
L4:
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl -0x1(%rbp),%esi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L10:
  cmpb   $0x7,-0x1(%rbp)
  jbe    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void addRoundKey(unsigned char *block, unsigned char *roundKey) {
  unsigned char i;
  for (i = 0; i < 8; i++) {
    block[i] ^= roundKey[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addRoundKey>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl (%rsi,%rax,1),%edx
  xor    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L8
  ret
```

assistant: ```c
void addRoundKey(unsigned char *block, unsigned char *roundKey) {
  unsigned char i;
  for (i = 0; i < 8; i++) {
    block[i] ^= roundKey[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<addRoundKey>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rax,1),%edx
  xor    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L4
  ret
```

assistant: ```c
void addRoundKey(unsigned char *block, unsigned char *roundKey) {
  unsigned char i;
  for (i = 0; i < 8; i++) {
    block[i] ^= roundKey[i];
  }
}
```