ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<substr>:
  endbr64
  movslq %edx,%rdx
  add    %rdx,%rsi
  mov    %ecx,%r8d
  mov    $0x0,%eax
  test   %ecx,%ecx
  jne    L2
  movzbl (%rsi),%eax
  test   %al,%al
  je     L49
L1:
  mov    %al,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L1
L49:
  movb   $0x0,(%rdi)
  ret
L2:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L2
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdi,%rax,1),%rdi
  jmp    L49
```

assistant: ```c
void substr(char *dst, char *src, int begin, int len) {
  int tmplen = len;
  src += begin;
  if (!len) {
    while (*src) {
      *dst = *src;
      dst++;
      src++;
    }
  } else {
    while (tmplen) {
      *dst = *src;
      dst++;
      src++;
      tmplen--;
    }
  }
  *dst = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<substr>:
  endbr64
  movslq %edx,%rdx
  add    %rdx,%rsi
  movzbl (%rsi),%eax
  test   %ecx,%ecx
  jne    L0
  test   %al,%al
  je     L38
  nopl   (%rax)
L20:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L20
L38:
  movb   $0x0,(%rdi)
  ret
  nopl   (%rax)
L0:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L27:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L27
  add    %rcx,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void substr(char *dst, char *src, int begin, int len) {
  int tmplen = len;
  src += begin;
  if (!len) {
    while (*src) {
      *dst = *src;
      dst++;
      src++;
    }
  } else {
    while (tmplen) {
      *dst = *src;
      dst++;
      src++;
      tmplen--;
    }
  }
  *dst = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<substr>:
  endbr64
  movslq %edx,%rdx
  mov    %ecx,%r8d
  mov    %rdi,%rax
  lea    (%rsi,%rdx,1),%r9
  movzbl (%r9),%edi
  mov    %r9,%rcx
  test   %r8d,%r8d
  jne    L35
  test   %dil,%dil
  je     L119
  nopw   0x0(%rax,%rax,1)
L163:
  add    $0x1,%rcx
  mov    %dil,(%rax)
  add    $0x1,%rax
  movzbl (%rcx),%edi
  test   %dil,%dil
  jne    L163
L119:
  movb   $0x0,(%rax)
  ret
  nop
L35:
  lea    0x1(%rsi,%rdx,1),%rsi
  mov    %rax,%rdx
  lea    -0x1(%r8),%edi
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L144
  cmp    $0x6,%edi
  jbe    L144
  mov    %r8d,%r10d
  cmp    $0xe,%edi
  jbe    L168
  mov    %r8d,%ecx
  xor    %edx,%edx
  shr    $0x4,%ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L143:
  movdqu (%r9,%rdx,1),%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L143
  mov    %r8d,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%ecx
  sub    %edx,%r8d
  lea    (%rax,%rcx,1),%rsi
  add    %r9,%rcx
  cmp    %edx,%r10d
  je     L121
L59:
  sub    %edx,%r10d
  lea    -0x1(%r10),%r11d
  cmp    $0x6,%r11d
  jbe    L76
  mov    (%r9,%rdx,1),%r9
  mov    %r9,(%rax,%rdx,1)
  mov    %r10d,%edx
  and    $0xfffffff8,%edx
  mov    %edx,%r9d
  sub    %edx,%r8d
  add    %r9,%rsi
  add    %r9,%rcx
  cmp    %edx,%r10d
  je     L121
L76:
  movzbl (%rcx),%edx
  mov    %dl,(%rsi)
  cmp    $0x1,%r8d
  je     L121
  movzbl 0x1(%rcx),%edx
  mov    %dl,0x1(%rsi)
  cmp    $0x2,%r8d
  je     L121
  movzbl 0x2(%rcx),%edx
  mov    %dl,0x2(%rsi)
  cmp    $0x3,%r8d
  je     L121
  movzbl 0x3(%rcx),%edx
  mov    %dl,0x3(%rsi)
  cmp    $0x4,%r8d
  je     L121
  movzbl 0x4(%rcx),%edx
  mov    %dl,0x4(%rsi)
  cmp    $0x5,%r8d
  je     L121
  movzbl 0x5(%rcx),%edx
  mov    %dl,0x5(%rsi)
  cmp    $0x6,%r8d
  je     L121
  movzbl 0x6(%rcx),%edx
  mov    %dl,0x6(%rsi)
L121:
  mov    %edi,%edi
  lea    0x1(%rax,%rdi,1),%rax
L175:
  movb   $0x0,(%rax)
  ret
  nopl   0x0(%rax)
L144:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L80:
  movzbl (%r9,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L80
  mov    %edi,%edi
  lea    0x1(%rax,%rdi,1),%rax
  jmp    L175
L168:
  mov    %rax,%rsi
  xor    %edx,%edx
  jmp    L59
```

assistant: ```c
void substr(char *dst, char *src, int begin, int len) {
  int tmplen = len;
  src += begin;
  if (!len) {
    while (*src) {
      *dst = *src;
      dst++;
      src++;
    }
  } else {
    while (tmplen) {
      *dst = *src;
      dst++;
      src++;
      tmplen--;
    }
  }
  *dst = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BTIC2D_TransWHT_Stride8>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rax
  mov    %ecx,%r10d
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  lea    (%rdi,%rsi,1),%rbp
  lea    0x0(%rbp,%rsi,1),%r8
  lea    (%r8,%rsi,1),%r9
  lea    (%r9,%rsi,1),%rcx
  mov    (%rcx),%r12d
  add    %rsi,%rcx
  mov    (%rcx),%ebx
  add    %rsi,%rcx
  mov    (%rcx),%r11d
  mov    (%rcx,%rdx,4),%ecx
  mov    %r12d,%edx
  add    (%rdi),%edx
  mov    %ebx,%esi
  add    0x0(%rbp),%esi
  mov    %r11d,%edi
  add    (%r8),%edi
  mov    %edi,%r8d
  mov    %ecx,%r13d
  add    (%r9),%r13d
  mov    %edi,%r9d
  sar    %r9d
  sub    %r11d,%r9d
  mov    %r13d,%edi
  sar    %edi
  sub    %ecx,%edi
  lea    (%rdx,%r8,1),%ecx
  lea    (%rsi,%r13,1),%r11d
  mov    %r11d,%ebp
  sar    %ebp
  sub    %r13d,%ebp
  sar    %edx
  sub    %r12d,%edx
  add    %r9d,%edx
  sar    %esi
  sub    %ebx,%esi
  add    %edi,%esi
  mov    %esi,%ebx
  sar    %ebx
  sub    %edi,%ebx
  lea    (%rcx,%r11,1),%edi
  sar    %ecx
  sub    %r8d,%ecx
  add    %ebp,%ecx
  lea    (%rdx,%rsi,1),%r8d
  sar    %edx
  sub    %r9d,%edx
  add    %ebx,%edx
  mov    %edi,(%rax)
  movslq %r10d,%r10
  lea    0x0(,%r10,4),%r9
  add    %r9,%rax
  mov    %r8d,(%rax)
  add    %r9,%rax
  mov    %edx,(%rax)
  add    %r9,%rax
  mov    %ecx,(%rax)
  add    %r9,%rax
  sar    %ecx
  sub    %ebp,%ecx
  mov    %ecx,(%rax)
  add    %r9,%rax
  sar    %edx
  sub    %ebx,%edx
  mov    %edx,(%rax)
  add    %r9,%rax
  sar    %r8d
  sub    %esi,%r8d
  mov    %r8d,(%rax)
  sar    %edi
  sub    %r11d,%edi
  mov    %edi,(%rax,%r10,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void BTIC2D_TransWHT_Stride8(int *iblk, int *oblk, int istride, int ostride) {
  int ib0, ib1, ib2, ib3, ib4, ib5, ib6, ib7;
  int a0, a1, a2, a3, a4, a5, a6, a7;
  int b0, b1, b2, b3, b4, b5, b6, b7;
  int c0, c1, c2, c3, c4, c5, c6, c7;
  ib0 = iblk[istride * 0];
  ib1 = iblk[istride * 1];
  ib2 = iblk[istride * 2];
  ib3 = iblk[istride * 3];
  ib4 = iblk[istride * 4];
  ib5 = iblk[istride * 5];
  ib6 = iblk[istride * 6];
  ib7 = iblk[istride * 7];
  a0 = ib0 + ib4;
  a1 = ib1 + ib5;
  a2 = ib2 + ib6;
  a3 = ib3 + ib7;
  a4 = (a0 >> 1) - ib4;
  a5 = (a1 >> 1) - ib5;
  a6 = (a2 >> 1) - ib6;
  a7 = (a3 >> 1) - ib7;
  b0 = a0 + a2;
  b1 = a1 + a3;
  b2 = (b0 >> 1) - a2;
  b3 = (b1 >> 1) - a3;
  b4 = a4 + a6;
  b5 = a5 + a7;
  b6 = (b4 >> 1) - a6;
  b7 = (b5 >> 1) - a7;
  c0 = b0 + b1;
  c1 = (c0 >> 1) - b1;
  c2 = b2 + b3;
  c3 = (c2 >> 1) - b3;
  c4 = b4 + b5;
  c5 = (c4 >> 1) - b5;
  c6 = b6 + b7;
  c7 = (c6 >> 1) - b7;
  oblk[ostride * 0] = c0;
  oblk[ostride * 1] = c4;
  oblk[ostride * 2] = c6;
  oblk[ostride * 3] = c2;
  oblk[ostride * 4] = c3;
  oblk[ostride * 5] = c7;
  oblk[ostride * 6] = c5;
  oblk[ostride * 7] = c1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BTIC2D_TransWHT_Stride8>:
  endbr64
  movslq %edx,%rdx
  mov    %rsi,%rax
  push   %r13
  movslq %ecx,%r10
  lea    0x0(,%rdx,4),%rsi
  push   %r12
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  lea    0x0(%rbp,%rsi,1),%r8
  push   %rbx
  lea    (%r8,%rsi,1),%r9
  lea    (%r9,%rsi,1),%rcx
  mov    (%r9),%r13d
  mov    (%rcx),%r12d
  add    %rsi,%rcx
  mov    (%rcx),%ebx
  add    %rsi,%rcx
  mov    0x0(%rbp),%esi
  mov    (%rcx),%r11d
  mov    (%rcx,%rdx,4),%ecx
  mov    (%rdi),%edx
  mov    (%r8),%edi
  add    %ebx,%esi
  add    %ecx,%r13d
  add    %r11d,%edi
  add    %r12d,%edx
  mov    %edi,%r9d
  mov    %edi,%r8d
  mov    %r13d,%edi
  sar    %r9d
  sar    %edi
  sub    %r11d,%r9d
  lea    (%rsi,%r13,1),%r11d
  sar    %esi
  sub    %ecx,%edi
  sub    %ebx,%esi
  lea    (%rdx,%r8,1),%ecx
  sar    %edx
  mov    %r11d,%ebp
  add    %edi,%esi
  sub    %r12d,%edx
  sar    %ebp
  mov    %esi,%ebx
  add    %r9d,%edx
  sub    %r13d,%ebp
  sar    %ebx
  sub    %edi,%ebx
  lea    (%rcx,%r11,1),%edi
  sar    %ecx
  sub    %r8d,%ecx
  lea    (%rdx,%rsi,1),%r8d
  sar    %edx
  mov    %edi,(%rax)
  sub    %r9d,%edx
  lea    0x0(,%r10,4),%r9
  add    %ebp,%ecx
  add    %r9,%rax
  add    %ebx,%edx
  mov    %r8d,(%rax)
  add    %r9,%rax
  mov    %edx,(%rax)
  add    %r9,%rax
  mov    %ecx,(%rax)
  sar    %ecx
  add    %r9,%rax
  sub    %ebp,%ecx
  mov    %ecx,(%rax)
  add    %r9,%rax
  sar    %edx
  sar    %r8d
  sub    %ebx,%edx
  sar    %edi
  mov    %edx,(%rax)
  sub    %esi,%r8d
  add    %r9,%rax
  sub    %r11d,%edi
  mov    %r8d,(%rax)
  mov    %edi,(%rax,%r10,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void BTIC2D_TransWHT_Stride8(int *iblk, int *oblk, int istride, int ostride) {
  int ib0, ib1, ib2, ib3, ib4, ib5, ib6, ib7;
  int a0, a1, a2, a3, a4, a5, a6, a7;
  int b0, b1, b2, b3, b4, b5, b6, b7;
  int c0, c1, c2, c3, c4, c5, c6, c7;
  ib0 = iblk[istride * 0];
  ib1 = iblk[istride * 1];
  ib2 = iblk[istride * 2];
  ib3 = iblk[istride * 3];
  ib4 = iblk[istride * 4];
  ib5 = iblk[istride * 5];
  ib6 = iblk[istride * 6];
  ib7 = iblk[istride * 7];
  a0 = ib0 + ib4;
  a1 = ib1 + ib5;
  a2 = ib2 + ib6;
  a3 = ib3 + ib7;
  a4 = (a0 >> 1) - ib4;
  a5 = (a1 >> 1) - ib5;
  a6 = (a2 >> 1) - ib6;
  a7 = (a3 >> 1) - ib7;
  b0 = a0 + a2;
  b1 = a1 + a3;
  b2 = (b0 >> 1) - a2;
  b3 = (b1 >> 1) - a3;
  b4 = a4 + a6;
  b5 = a5 + a7;
  b6 = (b4 >> 1) - a6;
  b7 = (b5 >> 1) - a7;
  c0 = b0 + b1;
  c1 = (c0 >> 1) - b1;
  c2 = b2 + b3;
  c3 = (c2 >> 1) - b3;
  c4 = b4 + b5;
  c5 = (c4 >> 1) - b5;
  c6 = b6 + b7;
  c7 = (c6 >> 1) - b7;
  oblk[ostride * 0] = c0;
  oblk[ostride * 1] = c4;
  oblk[ostride * 2] = c6;
  oblk[ostride * 3] = c2;
  oblk[ostride * 4] = c3;
  oblk[ostride * 5] = c7;
  oblk[ostride * 6] = c5;
  oblk[ostride * 7] = c1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BTIC2D_TransWHT_Stride8>:
  endbr64
  movslq %edx,%rdx
  mov    %rsi,%rax
  push   %r13
  movslq %ecx,%r10
  lea    0x0(,%rdx,4),%rsi
  push   %r12
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  lea    0x0(%rbp,%rsi,1),%r8
  push   %rbx
  lea    (%r8,%rsi,1),%r9
  lea    (%r9,%rsi,1),%rcx
  mov    (%r9),%r13d
  mov    (%rcx),%r12d
  add    %rsi,%rcx
  mov    (%rcx),%ebx
  add    %rsi,%rcx
  mov    0x0(%rbp),%esi
  mov    (%rcx),%r11d
  mov    (%rcx,%rdx,4),%ecx
  mov    (%rdi),%edx
  mov    (%r8),%edi
  add    %ebx,%esi
  add    %ecx,%r13d
  add    %r11d,%edi
  add    %r12d,%edx
  mov    %edi,%r9d
  mov    %edi,%r8d
  mov    %r13d,%edi
  sar    %r9d
  sar    %edi
  sub    %r11d,%r9d
  lea    (%rsi,%r13,1),%r11d
  sar    %esi
  sub    %ecx,%edi
  sub    %ebx,%esi
  lea    (%rdx,%r8,1),%ecx
  sar    %edx
  mov    %r11d,%ebp
  add    %edi,%esi
  sub    %r12d,%edx
  sar    %ebp
  mov    %esi,%ebx
  add    %r9d,%edx
  sub    %r13d,%ebp
  sar    %ebx
  sub    %edi,%ebx
  lea    (%rcx,%r11,1),%edi
  sar    %ecx
  sub    %r8d,%ecx
  lea    (%rdx,%rsi,1),%r8d
  sar    %edx
  mov    %edi,(%rax)
  sub    %r9d,%edx
  lea    0x0(,%r10,4),%r9
  add    %ebp,%ecx
  add    %r9,%rax
  add    %ebx,%edx
  mov    %r8d,(%rax)
  add    %r9,%rax
  mov    %edx,(%rax)
  add    %r9,%rax
  mov    %ecx,(%rax)
  sar    %ecx
  add    %r9,%rax
  sub    %ebp,%ecx
  mov    %ecx,(%rax)
  add    %r9,%rax
  sar    %edx
  sar    %r8d
  sub    %ebx,%edx
  sar    %edi
  mov    %edx,(%rax)
  sub    %esi,%r8d
  add    %r9,%rax
  sub    %r11d,%edi
  mov    %r8d,(%rax)
  mov    %edi,(%rax,%r10,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void BTIC2D_TransWHT_Stride8(int *iblk, int *oblk, int istride, int ostride) {
  int ib0, ib1, ib2, ib3, ib4, ib5, ib6, ib7;
  int a0, a1, a2, a3, a4, a5, a6, a7;
  int b0, b1, b2, b3, b4, b5, b6, b7;
  int c0, c1, c2, c3, c4, c5, c6, c7;
  ib0 = iblk[istride * 0];
  ib1 = iblk[istride * 1];
  ib2 = iblk[istride * 2];
  ib3 = iblk[istride * 3];
  ib4 = iblk[istride * 4];
  ib5 = iblk[istride * 5];
  ib6 = iblk[istride * 6];
  ib7 = iblk[istride * 7];
  a0 = ib0 + ib4;
  a1 = ib1 + ib5;
  a2 = ib2 + ib6;
  a3 = ib3 + ib7;
  a4 = (a0 >> 1) - ib4;
  a5 = (a1 >> 1) - ib5;
  a6 = (a2 >> 1) - ib6;
  a7 = (a3 >> 1) - ib7;
  b0 = a0 + a2;
  b1 = a1 + a3;
  b2 = (b0 >> 1) - a2;
  b3 = (b1 >> 1) - a3;
  b4 = a4 + a6;
  b5 = a5 + a7;
  b6 = (b4 >> 1) - a6;
  b7 = (b5 >> 1) - a7;
  c0 = b0 + b1;
  c1 = (c0 >> 1) - b1;
  c2 = b2 + b3;
  c3 = (c2 >> 1) - b3;
  c4 = b4 + b5;
  c5 = (c4 >> 1) - b5;
  c6 = b6 + b7;
  c7 = (c6 >> 1) - b7;
  oblk[ostride * 0] = c0;
  oblk[ostride * 1] = c4;
  oblk[ostride * 2] = c6;
  oblk[ostride * 3] = c2;
  oblk[ostride * 4] = c3;
  oblk[ostride * 5] = c7;
  oblk[ostride * 6] = c5;
  oblk[ostride * 7] = c1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sortName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  jmp    L26
L4:
  movl   $0x0,-0x24(%rbp)
  jmp    L14
L17:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L39
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L39:
  addl   $0x1,-0x24(%rbp)
L14:
  cmpl   $0x9,-0x24(%rbp)
  jle    L17
  addl   $0x1,-0x28(%rbp)
L26:
  cmpl   $0x9,-0x28(%rbp)
  jle    L4
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void sortName(char name[][20]) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      if (strcmp(*(name + i), *(name + j)) < 0) {
        char temp[20];
        strcpy(temp, *(name + i));
        strcpy(*(name + i), *(name + j));
        strcpy(*(name + j), temp);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sortName>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc8(%rdi),%r12
  mov    %rdi,%r14
  mov    %rsp,%r13
  jmp    L26
L33:
  add    $0x14,%rbx
  cmp    %r12,%rbx
  je     L48
L30:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L33
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L33
L48:
  add    $0x14,%r14
  cmp    %r12,%r14
  je     L67
L26:
  mov    %r14,%rbp
  mov    %r15,%rbx
  jmp    L30
L67:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sortName(char name[][20]) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      if (strcmp(*(name + i), *(name + j)) < 0) {
        char temp[20];
        strcpy(temp, *(name + i));
        strcpy(*(name + i), *(name + j));
        strcpy(*(name + j), temp);
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sortName>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    0xc8(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L9:
  mov    %r14,%rbx
  jmp    L19
  nopl   (%rax)
L54:
  add    $0x14,%rbx
  cmp    %r12,%rbx
  je     L53
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L54
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x14,%rbx
  call   <strcpy@plt>
  cmp    %r12,%rbx
  jne    L19
L53:
  add    $0x14,%rbp
  cmp    %rbx,%rbp
  jne    L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sortName(char name[][20]) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      if (strcmp(*(name + i), *(name + j)) < 0) {
        char temp[20];
        strcpy(temp, *(name + i));
        strcpy(*(name + i), *(name + j));
        strcpy(*(name + j), temp);
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortName>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    0xc8(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L2:
  mov    %r14,%rbx
  jmp    L57
  nopl   (%rax)
L47:
  add    $0x14,%rbx
  cmp    %r12,%rbx
  je     L56
L57:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L47
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x14,%rbx
  call   <strcpy@plt>
  cmp    %r12,%rbx
  jne    L57
L56:
  add    $0x14,%rbp
  cmp    %rbx,%rbp
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sortName(char name[][20]) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      if (strcmp(*(name + i), *(name + j)) < 0) {
        char temp[20];
        strcpy(temp, *(name + i));
        strcpy(*(name + i), *(name + j));
        strcpy(*(name + j), temp);
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mced_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <mced_vlog@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mced_log(int level, const char *fmt, ...) {
  va_list args;
  int r;
  va_start(args, fmt);
  r = mced_vlog(level, fmt, args);
  va_end(args);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mced_log>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <mced_vlog@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mced_log(int level, const char *fmt, ...) {
  va_list args;
  int r;
  va_start(args, fmt);
  r = mced_vlog(level, fmt, args);
  va_end(args);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mced_log>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <mced_vlog@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mced_log(int level, const char *fmt, ...) {
  va_list args;
  int r;
  va_start(args, fmt);
  r = mced_vlog(level, fmt, args);
  va_end(args);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mced_log>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <mced_vlog@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mced_log(int level, const char *fmt, ...) {
  va_list args;
  int r;
  va_start(args, fmt);
  r = mced_vlog(level, fmt, args);
  va_end(args);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L0:
  addl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getSize(long palindrome) {
  int size = 0;
  do {
    size++;
  } while (palindrome /= 10);
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getSize>:
  endbr64
  mov    $0x0,%ecx
  movabs $0x6666666666666667,%rsi
L3:
  add    $0x1,%ecx
  mov    %rdi,%rax
  imul   %rsi
  sar    $0x2,%rdx
  sar    $0x3f,%rdi
  sub    %rdi,%rdx
  mov    %rdx,%rdi
  jne    L3
  mov    %ecx,%eax
  ret
```

assistant: ```c
int getSize(long palindrome) {
  int size = 0;
  do {
    size++;
  } while (palindrome /= 10);
  return size;
}
```
user: What is the c source code of the assembly code below:

```asm
<getSize>:
  endbr64
  movabs $0x6666666666666667,%rcx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L2:
  mov    %rdi,%rax
  add    $0x1,%r8d
  imul   %rcx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rdi
  sub    %rax,%rdi
  jne    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getSize(long palindrome) {
  int size = 0;
  do {
    size++;
  } while (palindrome /= 10);
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getSize>:
  endbr64
  movabs $0x6666666666666667,%rcx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L5:
  mov    %rdi,%rax
  add    $0x1,%r8d
  imul   %rcx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rdi
  sub    %rax,%rdi
  jne    L5
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getSize(long palindrome) {
  int size = 0;
  do {
    size++;
  } while (palindrome /= 10);
  return size;
}
```