ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L15
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L15:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xde6a,%si
  je     L35
L1:
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L35:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L1
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D0
type: string

tool: D24: Call this program with %i arguments


tool: D18: %u


tool: D0: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56938) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L14
  lea    D16(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L14:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xde6a,%si
  je     L28
L27:
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L27
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D16: Call this program with %i arguments


tool: D10: %u


tool: D19: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56938) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ustrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ustrlen(wchar_t *s) {
  int len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ustrlen>:
  endbr64
  lea    0x4(%rdi),%rax
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L4
  mov    $0x0,%edx
L14:
  add    $0x1,%edx
  add    $0x4,%rax
  cmpl   $0x0,-0x4(%rax)
  jne    L14
L4:
  mov    %edx,%eax
  ret
```

assistant: ```c
int ustrlen(wchar_t *s) {
  int len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<ustrlen>:
  endbr64
  mov    (%rdi),%r8d
  lea    0x4(%rdi),%rax
  test   %r8d,%r8d
  je     L0
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rax),%edx
  add    $0x4,%rax
  add    $0x1,%r8d
  test   %edx,%edx
  jne    L14
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ustrlen(wchar_t *s) {
  int len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ustrlen>:
  endbr64
  mov    (%rdi),%r8d
  lea    0x4(%rdi),%rax
  test   %r8d,%r8d
  je     L17
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L12:
  mov    (%rax),%edx
  add    $0x4,%rax
  add    $0x1,%r8d
  test   %edx,%edx
  jne    L12
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ustrlen(wchar_t *s) {
  int len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<restore_standard_solutions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x30,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int restore_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(48, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<restore_standard_solutions>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x30,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int restore_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(48, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<restore_standard_solutions>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x30,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int restore_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(48, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<restore_standard_solutions>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x30,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int restore_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(48, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xef34ca9f65fb16,%rdx
  imul   %rdx,%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0xf5440d9(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        state[local1] = state[0UL] + state[local1];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 447621010UL) + 0xfffffffff4a61947UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99ef50e3df5,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        state[local1] = state[0UL] + state[local1];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 447621010UL) + 0xfffffffff4a61947UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99ef50e3df5,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        state[local1] = state[0UL] + state[local1];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 447621010UL) + 0xfffffffff4a61947UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fork_listener>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <listen_socket@plt>
  test   %rax,%rax
  je     L33
  mov    $0x1,%eax
  jmp    L22
L33:
  cmpq   $0x0,-0x28(%rbp)
  je     L23
  call   <fork@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L38
L23:
  mov    -0xc(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <do_listener@plt>
  mov    %eax,%edi
  call   <exit@plt>
L38:
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: localhost

assistant: ```c
int fork_listener(const char *port, int backlog, pid_t *cpid, const char *dbname) {
  int sockfd;
  if (listen_socket("localhost", (char *)port, backlog, &sockfd)) {
    return 1;
  }
  if (cpid == NULL || !(*cpid = fork()))
    exit(do_listener(sockfd, dbname));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fork_listener>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <listen_socket@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L10
  test   %rbx,%rbx
  je     L16
  call   <fork@plt>
  mov    %eax,%edx
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L10
L16:
  mov    %rbp,%rsi
  mov    0x4(%rsp),%edi
  call   <do_listener@plt>
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: localhost

assistant: ```c
int fork_listener(const char *port, int backlog, pid_t *cpid, const char *dbname) {
  int sockfd;
  if (listen_socket("localhost", (char *)port, backlog, &sockfd)) {
    return 1;
  }
  if (cpid == NULL || !(*cpid = fork()))
    exit(do_listener(sockfd, dbname));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fork_listener>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  call   <listen_socket@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L12
  test   %rbx,%rbx
  je     L48
  call   <fork@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L48
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  call   <do_listener@plt>
  mov    %eax,%edi
  call   <exit@plt>
  xor    %eax,%eax
  jmp    L12
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D2: localhost

assistant: ```c
int fork_listener(const char *port, int backlog, pid_t *cpid, const char *dbname) {
  int sockfd;
  if (listen_socket("localhost", (char *)port, backlog, &sockfd)) {
    return 1;
  }
  if (cpid == NULL || !(*cpid = fork()))
    exit(do_listener(sockfd, dbname));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fork_listener>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  call   <listen_socket@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L43
  test   %rbx,%rbx
  je     L7
  call   <fork@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L7
  xor    %eax,%eax
L43:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  call   <do_listener@plt>
  mov    %eax,%edi
  call   <exit@plt>
  xor    %eax,%eax
  jmp    L43
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: localhost

assistant: ```c
int fork_listener(const char *port, int backlog, pid_t *cpid, const char *dbname) {
  int sockfd;
  if (listen_socket("localhost", (char *)port, backlog, &sockfd)) {
    return 1;
  }
  if (cpid == NULL || !(*cpid = fork()))
    exit(do_listener(sockfd, dbname));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x5000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x6f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x56f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x56ec(%rbp)
  jmp    L72
L48:
  lea    -0x56e0(%rbp),%rdx
  mov    -0x56ec(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x56ec(%rbp)
L72:
  mov    -0x56f0(%rbp),%eax
  cmp    %eax,-0x56ec(%rbp)
  jl     L48
  movl   $0x0,-0x56e8(%rbp)
  jmp    L39
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x56e4(%rbp)
  jmp    L65
L67:
  mov    -0x56f0(%rbp),%eax
  sub    -0x56e4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x56e0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x56e4(%rbp)
L65:
  mov    -0x56e4(%rbp),%eax
  cmp    -0x56e8(%rbp),%eax
  jle    L67
  addl   $0x1,-0x56e8(%rbp)
L39:
  mov    -0x56f0(%rbp),%eax
  cmp    %eax,-0x56e8(%rbp)
  jl     L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D18: %d

assistant: ```c
int main() {
  int arr[5555], n, i, j, k;
  scanf("%d", &n);
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  for (j = 0; j <= n - 1; j++) {
    printf("\n");
    {
      for (k = 0; k <= j; k++)
        printf("%d", arr[n - k - 1]);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L79:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L79
  sub    $0x6f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x56e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L13
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L28
  test   %eax,%eax
  jle    L13
  mov    $0x0,%ebp
  lea    D10(%rip),%r12
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  js     L37
  mov    $0x0,%ebx
L25:
  mov    %ebx,%eax
  not    %eax
  add    0xc(%rsp),%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L25
L37:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L61
L13:
  mov    0x56e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x0,%eax
  add    $0x56f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
type: string

tool: D10: %d

assistant: ```c
int main() {
  int arr[5555], n, i, j, k;
  scanf("%d", &n);
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  for (j = 0; j <= n - 1; j++) {
    printf("\n");
    {
      for (k = 0; k <= j; k++)
        printf("%d", arr[n - k - 1]);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L41:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L41
  sub    $0x6f0,%rsp
  lea    D0(%rip),%r12
  xor    %ebx,%ebx
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x56e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L25
  xchg   %ax,%ax
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L23
  test   %eax,%eax
  jle    L25
  xor    %ebp,%ebp
L5:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax)
L67:
  mov    %ebx,%eax
  mov    %r12,%rdi
  add    $0x1,%ebx
  not    %eax
  add    0xc(%rsp),%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L67
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L5
L25:
  mov    0x56e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x56f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: %d

assistant: ```c
int main() {
  int arr[5555], n, i, j, k;
  scanf("%d", &n);
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  for (j = 0; j <= n - 1; j++) {
    printf("\n");
    {
      for (k = 0; k <= j; k++)
        printf("%d", arr[n - k - 1]);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L64:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L64
  sub    $0x6f0,%rsp
  lea    D7(%rip),%r12
  xor    %ebx,%ebx
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x56e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L20
  xchg   %ax,%ax
L29:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L29
  test   %eax,%eax
  jle    L20
  xor    %ebp,%ebp
L32:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax)
L54:
  mov    %ebx,%eax
  mov    %r12,%rdi
  add    $0x1,%ebx
  not    %eax
  add    0xc(%rsp),%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L54
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L32
L20:
  mov    0x56e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x56f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: %d

assistant: ```c
int main() {
  int arr[5555], n, i, j, k;
  scanf("%d", &n);
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  for (j = 0; j <= n - 1; j++) {
    printf("\n");
    {
      for (k = 0; k <= j; k++)
        printf("%d", arr[n - k - 1]);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string_poschar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L20:
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L20
  cmpl   $0x0,-0xc(%rbp)
  je     L24
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  jmp    L29
L24:
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int string_poschar(char *str, char c) {
  int pos = 0;
  char *p = str;
  while (*p == c) {
    ++pos;
    ++p;
  }
  return ((pos == 0) ? 0 : (pos - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<string_poschar>:
  endbr64
  mov    %esi,%edx
  cmp    (%rdi),%sil
  jne    L7
  mov    $0x0,%eax
L3:
  mov    %eax,%ecx
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %dl,(%rdi)
  je     L3
  test   %eax,%eax
  cmovne %ecx,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int string_poschar(char *str, char c) {
  int pos = 0;
  char *p = str;
  while (*p == c) {
    ++pos;
    ++p;
  }
  return ((pos == 0) ? 0 : (pos - 1));
}
```