ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<_strstr>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  lea    D88(%rip),%rdx
  lea    D6(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D75(%rip),%rbp
  call   <printf@plt>
  xor    %edx,%edx
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  call   <_strstr_test@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <_strstr_test@plt>
  test   %rax,%rax
  jne    L5
  lea    D77(%rip),%r12
  mov    %rbp,%rsi
  mov    %r12,%rdx
  mov    %r12,%rdi
  call   <_strstr_test@plt>
  test   %rax,%rax
  jne    L5
  lea    D27(%rip),%r13
  mov    %rbp,%rsi
  mov    %r13,%rdx
  mov    %r13,%rdi
  call   <_strstr_test@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D73(%rip),%rdi
  call   <_strstr_test@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D62(%rip),%rdi
  call   <_strstr_test@plt>
  test   %rax,%rax
  jne    L5
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  call   <_strstr_test@plt>
  pop    %rbp
  pop    %r12
  neg    %rax
  pop    %r13
  sbb    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D88
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string
name: retrieve_data
arguments: data_tag: D75
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D77
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D73
type_infered: string
name: retrieve_data
arguments: data_tag: D62
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string

tool: D88: strstr()

tool: D6: %s: Testing %s


tool: D75: needle

tool: D30: haystack

tool: D77: needle 

tool: D27: needle again

tool: D73: haystack with a needle

tool: D62: haystack with a needle 

tool: D28: haystack with a needle again

assistant: ```c
int _strstr(char const *progname) {
  printf("%s: Testing %s\n", progname, "strstr()");
  if (_strstr_test("haystack", "needle", NULL) != 0 || _strstr_test("needle", "needle", "needle") != 0 || _strstr_test("needle ", "needle", "needle ") != 0 || _strstr_test("needle again", "needle", "needle again") != 0 || _strstr_test("haystack with a needle", "needle", "needle") != 0 || _strstr_test("haystack with a needle ", "needle", "needle ") != 0 || _strstr_test("haystack with a needle again", "needle", "needle again") != 0)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<whitespaceline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  jmp    L23
L17:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    $0x1,%eax
L23:
  leave
  ret
```

assistant: ```c
int whitespaceline(const char *s) {
  while (s[0] != '\0') {
    if (!isspace((unsigned char)*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<whitespaceline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L2:
  movzbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L23
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
  mov    $0x1,%eax
L23:
  pop    %rbx
  ret
L4:
  mov    $0x1,%eax
  jmp    L23
```

assistant: ```c
int whitespaceline(const char *s) {
  while (s[0] != '\0') {
    if (!isspace((unsigned char)*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<whitespaceline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L0
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L33:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L21
L0:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L33
  pop    %rbx
  ret
L21:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int whitespaceline(const char *s) {
  while (s[0] != '\0') {
    if (!isspace((unsigned char)*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<whitespaceline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L8
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L34
L8:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L25
  pop    %rbx
  ret
L34:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int whitespaceline(const char *s) {
  while (s[0] != '\0') {
    if (!isspace((unsigned char)*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<argz_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L10
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  cmpq   $0x0,-0x20(%rbp)
  jne    L8
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t argz_count(const char *argz, size_t len) {
  size_t count = 0;
  while (len > 0) {
    size_t part_len = strlen(argz);
    argz += part_len + 1;
    len -= part_len + 1;
    count++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<argz_count>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L17
  mov    %rdi,%rbp
  mov    $0x0,%r12d
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rbp
  sub    %rax,%rbx
  mov    %rbx,%rsi
  add    $0x1,%r12
  sub    $0x1,%rsi
  mov    %rsi,%rbx
  jne    L3
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rsi,%r12
  jmp    L7
```

assistant: ```c
size_t argz_count(const char *argz, size_t len) {
  size_t count = 0;
  while (len > 0) {
    size_t part_len = strlen(argz);
    argz += part_len + 1;
    len -= part_len + 1;
    count++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<argz_count>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L17
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <strlen@plt>
  sub    %rax,%rbx
  lea    0x1(%rbp,%rax,1),%rbp
  mov    %rbx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,%rbx
  jne    L7
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t argz_count(const char *argz, size_t len) {
  size_t count = 0;
  while (len > 0) {
    size_t part_len = strlen(argz);
    argz += part_len + 1;
    len -= part_len + 1;
    count++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argz_count>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L5
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <strlen@plt>
  sub    %rax,%rbx
  lea    0x1(%rbp,%rax,1),%rbp
  mov    %rbx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,%rbx
  jne    L16
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t argz_count(const char *argz, size_t len) {
  size_t count = 0;
  while (len > 0) {
    size_t part_len = strlen(argz);
    argz += part_len + 1;
    len -= part_len + 1;
    count++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jbe    L0
  mov    -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L0:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_x(void *user, unsigned a, unsigned b, unsigned c) {
  unsigned *ptr = user;
  if (a > *ptr)
    *ptr = a;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_x>:
  endbr64
  cmp    %esi,(%rdi)
  jae    L5
  mov    %esi,(%rdi)
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int max_x(void *user, unsigned a, unsigned b, unsigned c) {
  unsigned *ptr = user;
  if (a > *ptr)
    *ptr = a;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<max_x>:
  endbr64
  cmp    %esi,(%rdi)
  jae    L9
  mov    %esi,(%rdi)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int max_x(void *user, unsigned a, unsigned b, unsigned c) {
  unsigned *ptr = user;
  if (a > *ptr)
    *ptr = a;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max_x>:
  endbr64
  cmp    %esi,(%rdi)
  jae    L0
  mov    %esi,(%rdi)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int max_x(void *user, unsigned a, unsigned b, unsigned c) {
  unsigned *ptr = user;
  if (a > *ptr)
    *ptr = a;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<concat_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movw   $0x0,-0x10(%rbp)
  mov    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: %s%s

assistant: ```c
void concat_char(char *str, char *x, char *sep) {
  char buf[50] = {};
  sprintf(buf, "%s%s", sep, x);
  strcat(str, buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movw   $0x0,0x30(%rsp)
  mov    %rsp,%rbp
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: %s%s

assistant: ```c
void concat_char(char *str, char *x, char *sep) {
  char buf[50] = {};
  sprintf(buf, "%s%s", sep, x);
  strcat(str, buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<concat_char>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %rsi,%rcx
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %r12,%rdi
  mov    %ax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %s%s

assistant: ```c
void concat_char(char *str, char *x, char *sep) {
  char buf[50] = {};
  sprintf(buf, "%s%s", sep, x);
  strcat(str, buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<concat_char>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %rsi,%rcx
  lea    D6(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %r12,%rdi
  mov    %ax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: %s%s

assistant: ```c
void concat_char(char *str, char *x, char *sep) {
  char buf[50] = {};
  sprintf(buf, "%s%s", sep, x);
  strcat(str, buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memchr2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x20(%rbp)
  ja     L39
  mov    $0x0,%eax
  jmp    L56
L52:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L33
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x28(%rbp)
  jne    L6
  mov    -0x10(%rbp),%rax
  jmp    L56
L6:
  addq   $0x2,-0x10(%rbp)
  jmp    L39
L33:
  addq   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L52
  mov    $0x0,%eax
L56:
  pop    %rbp
  ret
```

assistant: ```c
const char *memchr2(const char *haystack, size_t haystack_len, char c0, char c1) {
  const char *cur = haystack;
  const char *last = haystack + haystack_len - 1;
  if (haystack_len < 2) {
    return NULL;
  }
  while (cur < last) {
    if (cur[0] == c0) {
      if (cur[1] == c1) {
        return cur;
      } else {
        cur += 2;
      }
    } else {
      cur += 1;
    }
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memchr2>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    $0x1,%rsi
  jbe    L40
  cmp    %rax,%rdi
  jb     L51
  mov    $0x0,%eax
  ret
L52:
  add    $0x1,%rdi
L21:
  cmp    %rdi,%rax
  jbe    L33
L51:
  cmp    %dl,(%rdi)
  jne    L52
  cmp    %cl,0x1(%rdi)
  je     L9
  add    $0x2,%rdi
  jmp    L21
L33:
  mov    $0x0,%eax
  ret
L40:
  mov    $0x0,%eax
  ret
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *memchr2(const char *haystack, size_t haystack_len, char c0, char c1) {
  const char *cur = haystack;
  const char *last = haystack + haystack_len - 1;
  if (haystack_len < 2) {
    return NULL;
  }
  while (cur < last) {
    if (cur[0] == c0) {
      if (cur[1] == c1) {
        return cur;
      } else {
        cur += 2;
      }
    } else {
      cur += 1;
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memchr2>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    $0x1,%rsi
  jbe    L29
  cmp    %rax,%rdi
  jb     L40
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  jbe    L29
L40:
  cmp    %dl,(%rdi)
  jne    L15
  cmp    %cl,0x1(%rdi)
  je     L35
  add    $0x2,%rdi
  cmp    %rdi,%rax
  ja     L40
L29:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L35:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *memchr2(const char *haystack, size_t haystack_len, char c0, char c1) {
  const char *cur = haystack;
  const char *last = haystack + haystack_len - 1;
  if (haystack_len < 2) {
    return NULL;
  }
  while (cur < last) {
    if (cur[0] == c0) {
      if (cur[1] == c1) {
        return cur;
      } else {
        cur += 2;
      }
    } else {
      cur += 1;
    }
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memchr2>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    $0x1,%rsi
  jbe    L18
  cmp    %rax,%rdi
  jb     L51
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L65:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  jbe    L18
L51:
  cmp    %dl,(%rdi)
  jne    L65
  cmp    %cl,0x1(%rdi)
  je     L23
  add    $0x2,%rdi
  cmp    %rdi,%rax
  ja     L51
L18:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L23:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *memchr2(const char *haystack, size_t haystack_len, char c0, char c1) {
  const char *cur = haystack;
  const char *last = haystack + haystack_len - 1;
  if (haystack_len < 2) {
    return NULL;
  }
  while (cur < last) {
    if (cur[0] == c0) {
      if (cur[1] == c1) {
        return cur;
      } else {
        cur += 2;
      }
    } else {
      cur += 1;
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chaz_ConfWriterPerl_quotify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L79
  mov    $0x0,%eax
  jmp    L87
L79:
  movq   $0x3,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L113
L117:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L107
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L2
L107:
  addq   $0x2,-0x18(%rbp)
  jmp    L75
L2:
  addq   $0x1,-0x18(%rbp)
L75:
  addq   $0x1,-0x20(%rbp)
L113:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L117
  mov    -0x18(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jbe    L86
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
L86:
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x27,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L44
L46:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L8
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L12
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x5c,(%rax)
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L44:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x27,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
L87:
  leave
  ret
```

assistant: ```c
char *chaz_ConfWriterPerl_quotify(const char *string, char *buf, size_t buf_size) {
  char *quoted = buf;
  if (!string) {
    return NULL;
  }
  {
    const char *ptr;
    size_t space = 3;
    for (ptr = string; *ptr; ptr++) {
      if (*ptr == '\'' || *ptr == '\\') {
        space += 2;
      } else {
        space += 1;
      }
    }
    if (space > buf_size) {
      quoted = (char *)malloc(space);
    }
  }
  {
    const char *ptr;
    size_t pos = 0;
    quoted[pos++] = '\'';
    for (ptr = string; *ptr; ptr++) {
      if (*ptr == '\'' || *ptr == '\\') {
        quoted[pos++] = '\\';
      }
      quoted[pos++] = *ptr;
    }
    quoted[pos++] = '\'';
    quoted[pos++] = '\0';
  }
  return quoted;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chaz_ConfWriterPerl_quotify>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L129
  mov    %rsi,%rax
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L110
  mov    $0x3,%esi
  jmp    L50
L148:
  add    $0x2,%rsi
L152:
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L22
L50:
  cmp    $0x27,%cl
  je     L148
  cmp    $0x5c,%cl
  je     L148
  add    $0x1,%rsi
  jmp    L152
L110:
  mov    $0x3,%esi
L22:
  cmp    %rsi,%rdx
  jb     L47
L112:
  movb   $0x27,(%rax)
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L43
  mov    $0x1,%edi
  jmp    L65
L47:
  mov    %rsi,%rdi
  call   <malloc@plt>
  jmp    L112
L128:
  lea    0x1(%rdi),%rcx
  movb   $0x5c,(%rax,%rdi,1)
L0:
  lea    0x1(%rcx),%rdi
  movzbl (%rbx),%edx
  mov    %dl,(%rax,%rcx,1)
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L122
L65:
  cmp    $0x27,%dl
  je     L128
  mov    %rdi,%rcx
  cmp    $0x5c,%dl
  jne    L0
  jmp    L128
L43:
  mov    $0x1,%edi
L122:
  movb   $0x27,(%rax,%rdi,1)
  movb   $0x0,0x1(%rax,%rdi,1)
L64:
  pop    %rbx
  ret
L129:
  mov    %rdi,%rax
  jmp    L64
```

assistant: ```c
char *chaz_ConfWriterPerl_quotify(const char *string, char *buf, size_t buf_size) {
  char *quoted = buf;
  if (!string) {
    return NULL;
  }
  {
    const char *ptr;
    size_t space = 3;
    for (ptr = string; *ptr; ptr++) {
      if (*ptr == '\'' || *ptr == '\\') {
        space += 2;
      } else {
        space += 1;
      }
    }
    if (space > buf_size) {
      quoted = (char *)malloc(space);
    }
  }
  {
    const char *ptr;
    size_t pos = 0;
    quoted[pos++] = '\'';
    for (ptr = string; *ptr; ptr++) {
      if (*ptr == '\'' || *ptr == '\\') {
        quoted[pos++] = '\\';
      }
      quoted[pos++] = *ptr;
    }
    quoted[pos++] = '\'';
    quoted[pos++] = '\0';
  }
  return quoted;
}
```