ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D56(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D9(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D84
type_infered: string
name: read_data
arguments: label: D59
type_infered: string
name: read_data
arguments: label: D3
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D56
type_infered: f64
name: read_data
arguments: label: D9
type_infered: f64
name: read_data
arguments: label: D60
type_infered: string
name: read_data
arguments: label: D41
type_infered: string

tool: D84: 
Informe a idade em anos: 

tool: D59: %f

tool: D3: 
Informe a idade em meses: 

tool: D5: 
Informe a idade em dias: 

tool: D56: 365.25

tool: D9: 12

tool: D60: 
A idade informada e: %f dias.


tool: D41: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float ia, im, id, idias;
  printf("\nInforme a idade em anos: ");
  scanf("%f", &ia);
  printf("\nInforme a idade em meses: ");
  scanf("%f", &im);
  printf("\nInforme a idade em dias: ");
  scanf("%f", &id);
  idias = ia * 365.25 + im * 12.0 + id;
  printf("\nA idade informada e: %f dias.\n", idias);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D77(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D57(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  mulsd  D55(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x10(%rsp),%xmm1
  mulsd  D70(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D77
data_type: string
name: parse_data
arguments: data_tag: D57
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D55
data_type: f64
name: parse_data
arguments: data_tag: D70
data_type: f64
name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string

tool: D77: 
Informe a idade em anos: 

tool: D57: %f

tool: D30: 
Informe a idade em meses: 

tool: D5: 
Informe a idade em dias: 

tool: D55: 365.25

tool: D70: 12

tool: D20: 
A idade informada e: %f dias.


tool: D31: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float ia, im, id, idias;
  printf("\nInforme a idade em anos: ");
  scanf("%f", &ia);
  printf("\nInforme a idade em meses: ");
  scanf("%f", &im);
  printf("\nInforme a idade em dias: ");
  scanf("%f", &id);
  idias = ia * 365.25 + im * 12.0 + id;
  printf("\nA idade informada e: %f dias.\n", idias);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  lea    D73(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D72(%rip),%rdi
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd 0x10(%rsp),%xmm1
  mov    $0x1,%eax
  mulsd  D71(%rip),%xmm1
  mulsd  D56(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D73
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D72
datatype: string
name: retrieve_data
arguments: data_label: D71
datatype: f64
name: retrieve_data
arguments: data_label: D56
datatype: f64
name: retrieve_data
arguments: data_label: D33
datatype: string

tool: D27: 
Informe a idade em anos: 

tool: D73: %f

tool: D14: 
Informe a idade em meses: 

tool: D29: 
Informe a idade em dias: 

tool: D72: 
A idade informada e: %f dias.


tool: D71: 12

tool: D56: 365.25

tool: D33: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float ia, im, id, idias;
  printf("\nInforme a idade em anos: ");
  scanf("%f", &ia);
  printf("\nInforme a idade em meses: ");
  scanf("%f", &im);
  printf("\nInforme a idade em dias: ");
  scanf("%f", &id);
  idias = ia * 365.25 + im * 12.0 + id;
  printf("\nA idade informada e: %f dias.\n", idias);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D64(%rip),%rdi
  lea    D65(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D60(%rip),%rdi
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd 0x10(%rsp),%xmm1
  mov    $0x1,%eax
  mulsd  D73(%rip),%xmm1
  mulsd  D28(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D64
type_infered: string
name: read_data
arguments: data_tag: D65
type_infered: string
name: read_data
arguments: data_tag: D55
type_infered: string
name: read_data
arguments: data_tag: D69
type_infered: string
name: read_data
arguments: data_tag: D60
type_infered: string
name: read_data
arguments: data_tag: D73
type_infered: f64
name: read_data
arguments: data_tag: D28
type_infered: f64
name: read_data
arguments: data_tag: D33
type_infered: string

tool: D64: 
Informe a idade em anos: 

tool: D65: %f

tool: D55: 
Informe a idade em meses: 

tool: D69: 
Informe a idade em dias: 

tool: D60: 
A idade informada e: %f dias.


tool: D73: 12

tool: D28: 365.25

tool: D33: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float ia, im, id, idias;
  printf("\nInforme a idade em anos: ");
  scanf("%f", &ia);
  printf("\nInforme a idade em meses: ");
  scanf("%f", &im);
  printf("\nInforme a idade em dias: ");
  scanf("%f", &id);
  idias = ia * 365.25 + im * 12.0 + id;
  printf("\nA idade informada e: %f dias.\n", idias);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmpx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print_c_hex_string@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D4: 
unsigned char %s[] ={


tool: D14: 
};

assistant: ```c
void cmpx(m, buf, len) char *m, *buf;
int len;
{
  printf("\nunsigned char %s[] ={\n", m);
  print_c_hex_string(buf, len);
  printf("\n};\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmpx>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %rdi,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print_c_hex_string@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D5
datatype: string

tool: D18: 
unsigned char %s[] ={


tool: D5: 
};

assistant: ```c
void cmpx(m, buf, len) char *m, *buf;
int len;
{
  printf("\nunsigned char %s[] ={\n", m);
  print_c_hex_string(buf, len);
  printf("\n};\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<cmpx>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D10(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <print_c_hex_string@plt>
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string

tool: D10: 
unsigned char %s[] ={


tool: D7: 
};

assistant: ```c
void cmpx(m, buf, len) char *m, *buf;
int len;
{
  printf("\nunsigned char %s[] ={\n", m);
  print_c_hex_string(buf, len);
  printf("\n};\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmpx>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <print_c_hex_string@plt>
  add    $0x8,%rsp
  lea    D15(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type: string
name: read_data
arguments: tag: D15
type: string

tool: D9: 
unsigned char %s[] ={


tool: D15: 
};

assistant: ```c
void cmpx(m, buf, len) char *m, *buf;
int len;
{
  printf("\nunsigned char %s[] ={\n", m);
  print_c_hex_string(buf, len);
  printf("\n};\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D6
type_infered: f64
name: read_data
arguments: data_label: D14
type_infered: string

tool: D2: Enter your age in years: 

tool: D37: %d

tool: D6: 31560000

tool: D14: %d years in seconds is %e seconds.


assistant: ```c
int main(void) {
  int year;
  printf("Enter your age in years: ");
  scanf("%d", &year);
  printf("%d years in seconds is %e seconds.\n", year, 3.156E7 * year);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  mulsd  D39(%rip),%xmm0
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D24
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: f64
name: unpack_data
arguments: data_tag: D26
datatype: string

tool: D5: Enter your age in years: 

tool: D24: %d

tool: D39: 31560000

tool: D26: %d years in seconds is %e seconds.


assistant: ```c
int main(void) {
  int year;
  printf("Enter your age in years: ");
  scanf("%d", &year);
  printf("%d years in seconds is %e seconds.\n", year, 3.156E7 * year);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm0,%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2sd %esi,%xmm0
  mulsd  D27(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D8
datatype: string
name: retrieve_data
arguments: label: D30
datatype: string
name: retrieve_data
arguments: label: D27
datatype: f64

tool: D6: Enter your age in years: 

tool: D8: %d

tool: D30: %d years in seconds is %e seconds.


tool: D27: 31560000

assistant: ```c
int main(void) {
  int year;
  printf("Enter your age in years: ");
  scanf("%d", &year);
  printf("%d years in seconds is %e seconds.\n", year, 3.156E7 * year);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm0,%xmm0
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2sd %esi,%xmm0
  mulsd  D37(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D30
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D37
type_guessed: f64

tool: D23: Enter your age in years: 

tool: D30: %d

tool: D6: %d years in seconds is %e seconds.


tool: D37: 31560000

assistant: ```c
int main(void) {
  int year;
  printf("Enter your age in years: ");
  scanf("%d", &year);
  printf("%d years in seconds is %e seconds.\n", year, 3.156E7 * year);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generate_prime_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x2,-0x10(%rbp)
  jmp    L22
L24:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L69
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  addl   $0x1,-0x10(%rbp)
  jmp    L49
L1:
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L22
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L1
L22:
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L24
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
bool *generate_prime_array(int n) {
  bool *candidates = malloc(n * sizeof(bool));
  memset(candidates, true, n);
  for (int i = 2; i * i < n;) {
    for (int j = i + i; j < n; j += i) {
      candidates[j] = false;
    }
    for (++i; !candidates[i] && i * i < n; ++i)
      ;
  }
  return candidates;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generate_prime_array>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmp    $0x4,%ebx
  jle    L81
  mov    $0x2,%eax
  jmp    L52
L16:
  mov    %edx,%eax
L77:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebx,%edx
  jge    L81
L52:
  lea    (%rax,%rax,1),%edx
  cmp    %edx,%ebx
  jle    L5
  movslq %eax,%rcx
  movslq %edx,%rdx
L66:
  movl   $0x0,0x0(%rbp,%rdx,4)
  add    %rcx,%rdx
  cmp    %edx,%ebx
  jg     L66
L5:
  lea    0x1(%rax),%edx
  movslq %edx,%rcx
  cmpl   $0x0,0x0(%rbp,%rcx,4)
  jne    L16
  imul   %edx,%edx
  cmp    %edx,%ebx
  jle    L81
  add    $0x2,%eax
  movslq %eax,%rdx
L18:
  mov    %edx,%eax
  cmpl   $0x0,0x0(%rbp,%rdx,4)
  jne    L77
  add    $0x1,%rdx
  imul   %eax,%eax
  cmp    %ebx,%eax
  jl     L18
L81:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool *generate_prime_array(int n) {
  bool *candidates = malloc(n * sizeof(bool));
  memset(candidates, true, n);
  for (int i = 2; i * i < n;) {
    for (int j = i + i; j < n; j += i) {
      candidates[j] = false;
    }
    for (++i; !candidates[i] && i * i < n; ++i)
      ;
  }
  return candidates;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generate_prime_array>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  cmp    $0x4,%ebx
  jle    L80
  mov    $0x2,%ecx
  nopl   0x0(%rax)
L7:
  lea    (%rcx,%rcx,1),%esi
  movslq %ecx,%rdx
  movslq %esi,%rax
  cmp    %esi,%ebx
  jle    L72
  nopl   (%rax)
L88:
  movl   $0x0,(%r12,%rax,4)
  add    %rdx,%rax
  cmp    %eax,%ebx
  jg     L88
L72:
  lea    0x1(%rcx),%eax
  movslq %eax,%rsi
  mov    %eax,%edx
  mov    (%r12,%rsi,4),%edi
  imul   %eax,%edx
  test   %edi,%edi
  jne    L35
  cmp    %edx,%ebx
  jle    L80
  add    $0x2,%ecx
  movslq %ecx,%rax
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L109:
  add    $0x1,%rax
  cmp    %edx,%ebx
  jle    L80
L28:
  mov    (%r12,%rax,4),%esi
  mov    %eax,%edx
  mov    %eax,%ecx
  imul   %eax,%edx
  test   %esi,%esi
  je     L109
  cmp    %edx,%ebx
  jg     L7
L80:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L35:
  mov    %eax,%ecx
  cmp    %edx,%ebx
  jg     L7
  jmp    L80
```

assistant: ```c
bool *generate_prime_array(int n) {
  bool *candidates = malloc(n * sizeof(bool));
  memset(candidates, true, n);
  for (int i = 2; i * i < n;) {
    for (int j = i + i; j < n; j += i) {
      candidates[j] = false;
    }
    for (++i; !candidates[i] && i * i < n; ++i)
      ;
  }
  return candidates;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generate_prime_array>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  cmp    $0x4,%ebx
  jle    L41
  mov    $0x2,%ecx
  nopl   0x0(%rax)
L83:
  lea    (%rcx,%rcx,1),%esi
  movslq %ecx,%rdx
  movslq %esi,%rax
  cmp    %esi,%ebx
  jle    L18
  nopl   (%rax)
L93:
  movl   $0x0,(%r12,%rax,4)
  add    %rdx,%rax
  cmp    %eax,%ebx
  jg     L93
L18:
  lea    0x1(%rcx),%eax
  movslq %eax,%rsi
  mov    %eax,%edx
  mov    (%r12,%rsi,4),%edi
  imul   %eax,%edx
  test   %edi,%edi
  jne    L103
  cmp    %edx,%ebx
  jle    L41
  add    $0x2,%ecx
  movslq %ecx,%rax
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmp    %edx,%ebx
  jle    L41
L22:
  mov    (%r12,%rax,4),%esi
  mov    %eax,%edx
  mov    %eax,%ecx
  imul   %eax,%edx
  test   %esi,%esi
  je     L9
  cmp    %edx,%ebx
  jg     L83
L41:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L103:
  mov    %eax,%ecx
  cmp    %edx,%ebx
  jg     L83
  jmp    L41
```

assistant: ```c
bool *generate_prime_array(int n) {
  bool *candidates = malloc(n * sizeof(bool));
  memset(candidates, true, n);
  for (int i = 2; i * i < n;) {
    for (int j = i + i; j < n; j += i) {
      candidates[j] = false;
    }
    for (++i; !candidates[i] && i * i < n; ++i)
      ;
  }
  return candidates;
}
```