ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<create_fs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D16(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  jne    L52
  mov    %r13,%rdi
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rsp,%rcx
  mov    %rax,%r13
  lea    (%r12,%r12,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xf(,%rax,8),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L37
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L37:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L7
L63:
  mov    %r13,%rcx
  mov    $0xc8,%edx
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <fwrite@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L6:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0xffffffff,%eax
  jmp    L6
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D16: r

tool: D9: w+

assistant: ```c
int create_fs(char *name, size_t blocksize) {
  FILE *fs = fopen(name, "r");
  if (fs != NULL) {
    fclose(fs);
    return -1;
  }
  fs = fopen(name, "w+");
  unsigned char arr[200 * blocksize];
  fwrite(arr, blocksize, 200, fs);
  fclose(fs);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<generate_delta_coefficients_with_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <generate_delta_coefficients@plt>
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void generate_delta_coefficients_with_base(double vetor[], double out[], int n, double delta) {
  generate_delta_coefficients(vetor, out, n, delta);
  int i;
  double base = out[0];
  for (i = 0; i < n; i++) {
    out[i] = out[i] / base;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<generate_delta_coefficients_with_base>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  call   <generate_delta_coefficients@plt>
  movsd  (%rbx),%xmm1
  test   %ebp,%ebp
  jle    L4
  mov    %rbx,%rax
  lea    -0x1(%rbp),%edx
  lea    0x8(%rbx,%rdx,8),%rdx
L11:
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L11
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void generate_delta_coefficients_with_base(double vetor[], double out[], int n, double delta) {
  generate_delta_coefficients(vetor, out, n, delta);
  int i;
  double base = out[0];
  for (i = 0; i < n; i++) {
    out[i] = out[i] / base;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generate_delta_coefficients_with_base>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <generate_delta_coefficients@plt>
  movsd  (%rbx),%xmm1
  test   %ebp,%ebp
  jle    L21
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rsi
  movapd %xmm1,%xmm0
  lea    0x8(%rbx,%rax,8),%rax
  jmp    L13
  nopl   (%rax)
L24:
  movsd  (%rsi),%xmm0
L13:
  divsd  %xmm1,%xmm0
  add    $0x8,%rsi
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rax,%rsi
  jne    L24
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void generate_delta_coefficients_with_base(double vetor[], double out[], int n, double delta) {
  generate_delta_coefficients(vetor, out, n, delta);
  int i;
  double base = out[0];
  for (i = 0; i < n; i++) {
    out[i] = out[i] / base;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<generate_delta_coefficients_with_base>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <generate_delta_coefficients@plt>
  movsd  (%rbx),%xmm1
  test   %ebp,%ebp
  jle    L49
  cmp    $0x1,%ebp
  je     L11
  mov    %ebp,%edx
  movapd %xmm1,%xmm2
  mov    %rbx,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbx,%rdx,1),%rdx
  nopl   0x0(%rax)
L31:
  movupd (%rax),%xmm0
  add    $0x10,%rax
  divpd  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L31
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ebp
  je     L49
L38:
  cltq
  lea    (%rbx,%rax,8),%rax
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  xor    %eax,%eax
  jmp    L38
```

assistant: ```c
void generate_delta_coefficients_with_base(double vetor[], double out[], int n, double delta) {
  generate_delta_coefficients(vetor, out, n, delta);
  int i;
  double base = out[0];
  for (i = 0; i < n; i++) {
    out[i] = out[i] / base;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memwipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L15
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <memwipe_inline@plt>
  jmp    L16
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <memwipe_noinline@plt>
L16:
  nop
  leave
  ret
```

assistant: ```c
void memwipe(void *ptr, size_t n) {
  if (__builtin_constant_p(n)) {
    memwipe_inline(ptr, n);
  } else {
    memwipe_noinline(ptr, n);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memwipe>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L3
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memwipe_inline@plt>
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memwipe_noinline@plt>
  jmp    L15
```

assistant: ```c
void memwipe(void *ptr, size_t n) {
  if (__builtin_constant_p(n)) {
    memwipe_inline(ptr, n);
  } else {
    memwipe_noinline(ptr, n);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memwipe>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  test   %rax,%rax
  je     L9
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1070 <memwipe_inline@plt>
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <memwipe_noinline@plt>
```

assistant: ```c
void memwipe(void *ptr, size_t n) {
  if (__builtin_constant_p(n)) {
    memwipe_inline(ptr, n);
  } else {
    memwipe_noinline(ptr, n);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memwipe>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1070 <memwipe_inline@plt>
L5:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <memwipe_noinline@plt>
```

assistant: ```c
void memwipe(void *ptr, size_t n) {
  if (__builtin_constant_p(n)) {
    memwipe_inline(ptr, n);
  } else {
    memwipe_noinline(ptr, n);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<qadd_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x555555,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L36
  lea    D6(%rip),%rax
  jmp    L30
L36:
  lea    D19(%rip),%rax
L30:
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L22
L7:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x7,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edx
  cmpl   $0x0,-0x24(%rbp)
  setne  %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    $0x155555,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L38
  mov    $0x6,%eax
  jmp    L59
L38:
  mov    $0x3,%eax
L59:
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0xf,%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    $0x8,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edx
  cmpl   $0x0,-0x24(%rbp)
  setne  %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edi
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L22:
  cmpl   $0x33,-0x1c(%rbp)
  jle    L7
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D25
data_type: string

tool: D6: inter

tool: D19: intra

tool: D25: qp = %2d	 div6 = %d	q_add = %7d	 new = %7d old = %7d


assistant: ```c
void qadd_table(int inter) {
  const int max_q_add = 5592405;
  printf("%s\n", inter ? "inter" : "intra");
  for (int qp = 0; qp < 52; qp++) {
    int qp_div_6 = qp / 6;
    int old = 1398101 >> (7 - qp_div_6 + (inter ? 1 : 0));
    int div = inter ? 6 : 3;
    int q_add = (2 << (15 + (qp_div_6))) / div;
    int new_q_add = max_q_add >> (8 - qp_div_6 + (inter ? 1 : 0));
    printf("qp = %2d\t div6 = %d\tq_add = %7d\t new = %7d old = %7d\n", qp, qp_div_6, q_add, new_q_add, old);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<qadd_table>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  test   %edi,%edi
  lea    D27(%rip),%rdi
  lea    D28(%rip),%rax
  cmove  %rax,%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  sbb    %ebp,%ebp
  and    $0xfffffffd,%ebp
  add    $0x6,%ebp
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L7:
  movslq %ebx,%rsi
  imul   $0x2aaaaaab,%rsi,%rsi
  shr    $0x20,%rsi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  test   %r12d,%r12d
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edx
  sub    %esi,%edx
  lea    0x7(%rdx),%r8d
  lea    0x8(%rdx),%edi
  lea    0xf(%rsi),%ecx
  mov    $0x2,%eax
  shl    %cl,%eax
  cltd
  idiv   %ebp
  mov    $0x155555,%r9d
  mov    %r8d,%ecx
  sar    %cl,%r9d
  mov    $0x555555,%r8d
  mov    %edi,%ecx
  sar    %cl,%r8d
  mov    %eax,%ecx
  mov    %esi,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x34,%ebx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D27: inter

tool: D28: intra

tool: D9: qp = %2d	 div6 = %d	q_add = %7d	 new = %7d old = %7d


assistant: ```c
void qadd_table(int inter) {
  const int max_q_add = 5592405;
  printf("%s\n", inter ? "inter" : "intra");
  for (int qp = 0; qp < 52; qp++) {
    int qp_div_6 = qp / 6;
    int old = 1398101 >> (7 - qp_div_6 + (inter ? 1 : 0));
    int div = inter ? 6 : 3;
    int q_add = (2 << (15 + (qp_div_6))) / div;
    int new_q_add = max_q_add >> (8 - qp_div_6 + (inter ? 1 : 0));
    printf("qp = %2d\t div6 = %d\tq_add = %7d\t new = %7d old = %7d\n", qp, qp_div_6, q_add, new_q_add, old);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<qadd_table>:
  endbr64
  push   %r14
  test   %edi,%edi
  lea    D5(%rip),%rax
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D7(%rip),%rdi
  push   %rbx
  cmove  %rax,%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  sbb    %ebx,%ebx
  and    $0xfffffffd,%ebx
  add    $0x6,%ebx
  test   %ebp,%ebp
  setne  %bpl
  xor    %r14d,%r14d
  movzbl %bpl,%ebp
  nopl   0x0(%rax)
L0:
  mov    %r14d,%r10d
  mov    %ebp,%eax
  mov    $0x155555,%r9d
  mov    $0x555555,%r8d
  imul   %r12,%r10
  shr    $0x22,%r10
  sub    %r10d,%eax
  lea    0xf(%r10),%ecx
  lea    0x7(%rax),%edi
  mov    %ebp,%eax
  sub    %r10d,%eax
  lea    0x8(%rax),%esi
  mov    $0x2,%eax
  shl    %cl,%eax
  mov    %edi,%ecx
  mov    %r13,%rdi
  cltd
  sar    %cl,%r9d
  mov    %esi,%ecx
  mov    %r14d,%esi
  idiv   %ebx
  sar    %cl,%r8d
  mov    %r10d,%edx
  add    $0x1,%r14d
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x34,%r14d
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D5: intra

tool: D23: qp = %2d	 div6 = %d	q_add = %7d	 new = %7d old = %7d


tool: D7: inter

assistant: ```c
void qadd_table(int inter) {
  const int max_q_add = 5592405;
  printf("%s\n", inter ? "inter" : "intra");
  for (int qp = 0; qp < 52; qp++) {
    int qp_div_6 = qp / 6;
    int old = 1398101 >> (7 - qp_div_6 + (inter ? 1 : 0));
    int div = inter ? 6 : 3;
    int q_add = (2 << (15 + (qp_div_6))) / div;
    int new_q_add = max_q_add >> (8 - qp_div_6 + (inter ? 1 : 0));
    printf("qp = %2d\t div6 = %d\tq_add = %7d\t new = %7d old = %7d\n", qp, qp_div_6, q_add, new_q_add, old);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<qadd_table>:
  endbr64
  push   %r14
  test   %edi,%edi
  lea    D14(%rip),%rax
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D19(%rip),%rdi
  push   %rbx
  cmove  %rax,%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  sbb    %ebx,%ebx
  and    $0xfffffffd,%ebx
  add    $0x6,%ebx
  test   %ebp,%ebp
  setne  %bpl
  xor    %r14d,%r14d
  movzbl %bpl,%ebp
  nopl   0x0(%rax)
L6:
  mov    %r14d,%r10d
  mov    %ebp,%eax
  mov    $0x155555,%r9d
  mov    $0x555555,%r8d
  imul   %r12,%r10
  shr    $0x22,%r10
  sub    %r10d,%eax
  lea    0xf(%r10),%ecx
  lea    0x7(%rax),%edi
  mov    %ebp,%eax
  sub    %r10d,%eax
  lea    0x8(%rax),%esi
  mov    $0x2,%eax
  shl    %cl,%eax
  mov    %edi,%ecx
  mov    %r13,%rdi
  cltd
  sar    %cl,%r9d
  mov    %esi,%ecx
  mov    %r14d,%esi
  idiv   %ebx
  sar    %cl,%r8d
  mov    %r10d,%edx
  add    $0x1,%r14d
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x34,%r14d
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string

tool: D14: intra

tool: D15: qp = %2d	 div6 = %d	q_add = %7d	 new = %7d old = %7d


tool: D19: inter

assistant: ```c
void qadd_table(int inter) {
  const int max_q_add = 5592405;
  printf("%s\n", inter ? "inter" : "intra");
  for (int qp = 0; qp < 52; qp++) {
    int qp_div_6 = qp / 6;
    int old = 1398101 >> (7 - qp_div_6 + (inter ? 1 : 0));
    int div = inter ? 6 : 3;
    int q_add = (2 << (15 + (qp_div_6))) / div;
    int new_q_add = max_q_add >> (8 - qp_div_6 + (inter ? 1 : 0));
    printf("qp = %2d\t div6 = %d\tq_add = %7d\t new = %7d old = %7d\n", qp, qp_div_6, q_add, new_q_add, old);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string

tool: D0: x: 

tool: D29: %lf

tool: D20: log10(%lf) = %lf


assistant: ```c
int main(void) {
  double x;
  double result;
  printf("x: ");
  scanf("%lf", &x);
  result = log10(x);
  printf("log10(%lf) = %lf\n", x, result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rbx
  movq   %rbx,%xmm0
  call   <log10@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  lea    D15(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D14: x: 

tool: D22: %lf

tool: D15: log10(%lf) = %lf


assistant: ```c
int main(void) {
  double x;
  double result;
  printf("x: ");
  scanf("%lf", &x);
  result = log10(x);
  printf("log10(%lf) = %lf\n", x, result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm2
  mov    $0x2,%eax
  lea    D13(%rip),%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D13
datatype: string

tool: D28: x: 

tool: D9: %lf

tool: D13: log10(%lf) = %lf


assistant: ```c
int main(void) {
  double x;
  double result;
  printf("x: ");
  scanf("%lf", &x);
  result = log10(x);
  printf("log10(%lf) = %lf\n", x, result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D23(%rip),%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm2
  mov    $0x2,%eax
  lea    D24(%rip),%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D23
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string

tool: D11: x: 

tool: D23: %lf

tool: D24: log10(%lf) = %lf


assistant: ```c
int main(void) {
  double x;
  double result;
  printf("x: ");
  scanf("%lf", &x);
  result = log10(x);
  printf("log10(%lf) = %lf\n", x, result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy_walk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void memcpy_walk(void *dst, char **src, size_t n) {
  memcpy(dst, *src, n);
  *src = *src + n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memcpy_walk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    (%rsi),%rsi
  call   <memcpy@plt>
  add    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void memcpy_walk(void *dst, char **src, size_t n) {
  memcpy(dst, *src, n);
  *src = *src + n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcpy_walk>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  call   <memcpy@plt>
  add    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void memcpy_walk(void *dst, char **src, size_t n) {
  memcpy(dst, *src, n);
  *src = *src + n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy_walk>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  call   <memcpy@plt>
  add    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void memcpy_walk(void *dst, char **src, size_t n) {
  memcpy(dst, *src, n);
  *src = *src + n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fmt_u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L1:
  mov    -0x18(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x20(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
L29:
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L18
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x30,(%rax)
L18:
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *fmt_u(unsigned long u, char *s) {
  char *prev = s;
  for (; u; u /= 10)
    *--s = '0' + (u % 10);
  if (s == prev)
    *--s = '0';
  ;
  return s;
}
```