user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D75(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0x22,%edx
  jle    L6
  mov    0x8(%rsp),%eax
  cmp    $0x22,%eax
  jle    L6
  mov    0xc(%rsp),%ecx
  cmp    $0x22,%ecx
  jle    L6
  mov    0x10(%rsp),%esi
  cmp    $0x22,%esi
  jle    L6
  mov    0x14(%rsp),%edi
  cmp    $0x22,%edi
  jg     L105
L6:
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L105:
  lea    (%rdx,%rax,1),%ebx
  add    %ecx,%ebx
  add    %esi,%ebx
  add    %edi,%ebx
  mov    $0x5,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebp
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x18f,%ebx
  jg     L122
  cmp    $0x12b,%ebx
  jg     L33
  cmp    $0xe0,%ebx
  jle    L48
  mov    %ebp,%esi
  lea    D72(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L63
L122:
  mov    %ebp,%esi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L63
L33:
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L63
L48:
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L63
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D48
type_guessed: string
name: retrieve_data
arguments: tag: D75
type_guessed: string
name: retrieve_data
arguments: tag: D30
type_guessed: string
name: retrieve_data
arguments: tag: D42
type_guessed: string
name: retrieve_data
arguments: tag: D72
type_guessed: string
name: retrieve_data
arguments: tag: D57
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D48: Enter the marks of subjects: English, Nepali, Foit, Education, C programming respectively

tool: D75: %d %d %d %d %d

tool: D30: 
Sorry, You are failed !

tool: D42: 
Congrats, You are passed in 

tool: D72: 2nd Division with percentage %d

tool: D57: Distinction with percentage %d

tool: D12: 1st Division with percentage %d

tool: D10: 3rd Division with percentage %d

assistant: ```c
int main(void) {
  int e, n, f, ed, c, tot, per;
  printf("Enter the marks of subjects: English, Nepali, Foit, Education, C programming respectively\n");
  scanf("%d %d %d %d %d", &e, &n, &f, &ed, &c);
  if (e >= 35 && n >= 35 && f >= 35 && ed >= 35 && c >= 35) {
    tot = e + n + f + ed + c;
    per = tot / 5;
    printf("\nCongrats, You are passed in ");
    if (per >= 80)
      printf("Distinction with percentage %d", per);
    else if (per >= 60)
      printf("1st Division with percentage %d", per);
    else if (per >= 45)
      printf("2nd Division with percentage %d", per);
    else
      printf("3rd Division with percentage %d", per);
  } else
    printf("\nSorry, You are failed !");
  return 0;
}
```