ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<greedy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x19,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  movl   $0x1,0x2c(%rsp)
  lea    D21(%rip),%rbp
  lea    D26(%rip),%rbx
L66:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L66
  ucomiss %xmm1,%xmm0
  jp     L66
  jne    L66
  mulss  D13(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <round@plt>
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  lea    0x34(%rsp),%r10
L1:
  mov    (%rdi),%ecx
  cmp    %eax,%ecx
  jg     L58
  mov    %r8,%r9
  mov    (%r8),%ebx
  lea    0x1(%rbx),%edx
L53:
  mov    %edx,%esi
  sub    %ecx,%eax
  add    $0x1,%edx
  cmp    %ecx,%eax
  jge    L53
  mov    %esi,(%r9)
L58:
  add    $0x4,%rdi
  add    $0x4,%r8
  cmp    %r10,%rdi
  jne    L1
  mov    0x1c(%rsp),%r8d
  mov    0x18(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D21
data_type: string
name: read_data
arguments: data_tag: D26
data_type: string
name: read_data
arguments: data_tag: D13
data_type: byte[4]
name: read_data
arguments: data_tag: D12
data_type: string

tool: D21: Enter amount of change:

tool: D26: %f.2

tool: {"D13": [0x00,0x00,0xc8,0x42]}

tool: D12: %d quarters, %d dimes, %d nickel, and %d pennies

assistant: ```c
void greedy(void) {
  int i;
  int coins[4] = {0, 0, 0, 0};
  int coinValues[4] = {25, 10, 5, 1};
  int balance;
  float change;
  do {
    printf("Enter amount of change:");
    scanf("%f.2", &change);
  } while (change < 0 || change);
  change *= 100;
  balance = round(change);
  for (i = 0; i < 5; i++) {
    while (balance >= coinValues[i]) {
      coins[i]++;
      balance -= coinValues[i];
    }
  }
  printf("%d quarters, %d dimes, %d nickel, and %d pennies", coins[0], coins[1], coins[2], coins[3]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<greedy>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x24(%rsp)
  lea    0xc(%rsp),%rbp
  movabs $0x100000005,%rax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L57
  ucomiss %xmm1,%xmm0
  jp     L57
  jne    L57
  mulss  D35(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <round@plt>
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  mov    $0x19,%ecx
  lea    0x34(%rsp),%r9
L17:
  cmp    %eax,%ecx
  jg     L35
  mov    (%r8),%ebx
  lea    0x1(%rbx),%edx
  nopl   0x0(%rax)
L71:
  sub    %ecx,%eax
  mov    %edx,%esi
  add    $0x1,%edx
  cmp    %ecx,%eax
  jge    L71
  mov    %esi,(%r8)
L35:
  add    $0x4,%rdi
  add    $0x4,%r8
  cmp    %r9,%rdi
  je     L37
  mov    (%rdi),%ecx
  jmp    L17
  nop
L37:
  mov    0x1c(%rsp),%r8d
  mov    0x18(%rsp),%ecx
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D35
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_tag: D30
type_guessed: string

tool: D2: Enter amount of change:

tool: D4: %f.2

tool: {"D35": [0x00,0x00,0xc8,0x42]}

tool: D30: %d quarters, %d dimes, %d nickel, and %d pennies

assistant: ```c
void greedy(void) {
  int i;
  int coins[4] = {0, 0, 0, 0};
  int coinValues[4] = {25, 10, 5, 1};
  int balance;
  float change;
  do {
    printf("Enter amount of change:");
    scanf("%f.2", &change);
  } while (change < 0 || change);
  change *= 100;
  balance = round(change);
  for (i = 0; i < 5; i++) {
    while (balance >= coinValues[i]) {
      coins[i]++;
      balance -= coinValues[i];
    }
  }
  printf("%d quarters, %d dimes, %d nickel, and %d pennies", coins[0], coins[1], coins[2], coins[3]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<greedy>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D46(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D24(%rip),%xmm0
  lea    0xc(%rsp),%rbp
  movaps %xmm0,0x20(%rsp)
  nopl   (%rax)
L49:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L49
  ucomiss %xmm1,%xmm0
  jp     L49
  jne    L49
  mulss  D13(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <round@plt>
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  lea    0x34(%rsp),%r9
L36:
  mov    (%rdi),%ecx
  cmp    %eax,%ecx
  jg     L46
  mov    (%r8),%ebx
  lea    0x1(%rbx),%edx
  nopl   0x0(%rax)
L31:
  sub    %ecx,%eax
  mov    %edx,%esi
  add    $0x1,%edx
  cmp    %eax,%ecx
  jle    L31
  mov    %esi,(%r8)
L46:
  add    $0x4,%rdi
  add    $0x4,%r8
  cmp    %r9,%rdi
  jne    L36
  mov    0x1c(%rsp),%r8d
  mov    0x18(%rsp),%ecx
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D46
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: byte[16]
name: parse_data
arguments: tag: D13
type_infered: byte[4]
name: parse_data
arguments: tag: D23
type_infered: string

tool: D46: Enter amount of change:

tool: D3: %f.2

tool: {"D24": [0x19,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0xc8,0x42]}

tool: D23: %d quarters, %d dimes, %d nickel, and %d pennies

assistant: ```c
void greedy(void) {
  int i;
  int coins[4] = {0, 0, 0, 0};
  int coinValues[4] = {25, 10, 5, 1};
  int balance;
  float change;
  do {
    printf("Enter amount of change:");
    scanf("%f.2", &change);
  } while (change < 0 || change);
  change *= 100;
  balance = round(change);
  for (i = 0; i < 5; i++) {
    while (balance >= coinValues[i]) {
      coins[i]++;
      balance -= coinValues[i];
    }
  }
  printf("%d quarters, %d dimes, %d nickel, and %d pennies", coins[0], coins[1], coins[2], coins[3]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<intCompTrap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <f@plt>
  addsd  %xmm0,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <f@plt>
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: f32[2]

tool: {"D4": [0.0,2.0]}

assistant: ```c
double intCompTrap(double *X, double h, int n) {
  double integral = f(X[0]);
  int i;
  for (i = 1; i < n; i++)
    integral += 2 * f(X[i]);
  integral += f(X[n]);
  return (integral * (h / 2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intCompTrap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  movq   %xmm0,%r12
  mov    %esi,%r13d
  movsd  (%rdi),%xmm0
  call   <f@plt>
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x1,%r13d
  jle    L16
  lea    0x8(%r14),%rbx
  lea    -0x2(%r13),%eax
  lea    0x10(%r14,%rax,8),%rbp
L0:
  movsd  (%rbx),%xmm0
  call   <f@plt>
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L0
L16:
  movslq %r13d,%r13
  movsd  (%r14,%r13,8),%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  movq   %r12,%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: f32[2]

tool: {"D5": [0.0,1.75]}

assistant: ```c
double intCompTrap(double *X, double h, int n) {
  double integral = f(X[0]);
  int i;
  for (i = 1; i < n; i++)
    integral += 2 * f(X[i]);
  integral += f(X[n]);
  return (integral * (h / 2));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<intCompTrap>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  (%rdi),%xmm0
  call   <f@plt>
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x1,%r12d
  jle    L5
  lea    -0x2(%r12),%eax
  lea    0x8(%r13),%rbx
  lea    0x10(%r13,%rax,8),%rbp
  xchg   %ax,%ax
L16:
  movsd  (%rbx),%xmm0
  add    $0x8,%rbx
  call   <f@plt>
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %rbp,%rbx
  jne    L16
L5:
  movsd  0x0(%r13,%r12,8),%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  addsd  0x8(%rsp),%xmm1
  mulsd  D4(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: f32[2]

tool: {"D4": [0.0,1.75]}

assistant: ```c
double intCompTrap(double *X, double h, int n) {
  double integral = f(X[0]);
  int i;
  for (i = 1; i < n; i++)
    integral += 2 * f(X[i]);
  integral += f(X[n]);
  return (integral * (h / 2));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<intCompTrap>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  (%rdi),%xmm0
  call   <f@plt>
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x1,%r12d
  jle    L19
  lea    -0x2(%r12),%eax
  lea    0x8(%r13),%rbx
  lea    0x10(%r13,%rax,8),%rbp
  xchg   %ax,%ax
L10:
  movsd  (%rbx),%xmm0
  add    $0x8,%rbx
  call   <f@plt>
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %rbp,%rbx
  jne    L10
L19:
  movsd  0x0(%r13,%r12,8),%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  addsd  0x8(%rsp),%xmm1
  mulsd  D5(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: f32[2]

tool: {"D5": [0.0,1.75]}

assistant: ```c
double intCompTrap(double *X, double h, int n) {
  double integral = f(X[0]);
  int i;
  for (i = 1; i < n; i++)
    integral += 2 * f(X[i]);
  integral += f(X[n]);
  return (integral * (h / 2));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_packh2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _packh2(unsigned int src1, unsigned int src2) {
  unsigned v0 = src1 & 0xffff0000;
  unsigned v1 = src2 >> 16;
  unsigned v = v0 | v1;
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_packh2>:
  endbr64
  mov    $0x0,%di
  shr    $0x10,%esi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int _packh2(unsigned int src1, unsigned int src2) {
  unsigned v0 = src1 & 0xffff0000;
  unsigned v1 = src2 >> 16;
  unsigned v = v0 | v1;
  return v;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_packh2>:
  endbr64
  xor    %di,%di
  shr    $0x10,%esi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int _packh2(unsigned int src1, unsigned int src2) {
  unsigned v0 = src1 & 0xffff0000;
  unsigned v1 = src2 >> 16;
  unsigned v = v0 | v1;
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_packh2>:
  endbr64
  xor    %di,%di
  shr    $0x10,%esi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int _packh2(unsigned int src1, unsigned int src2) {
  unsigned v0 = src1 & 0xffff0000;
  unsigned v1 = src2 >> 16;
  unsigned v = v0 | v1;
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wrd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parallel@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vertical@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <angle_d@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <angle_u@plt>
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <checker@plt>
  nop
  leave
  ret
```

assistant: ```c
void wrd(char *a, char *b) {
  parallel(a, b);
  vertical(a, b);
  angle_d(a, b);
  angle_u(a, b);
  checker(0, 0, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <parallel@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vertical@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <angle_d@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <angle_u@plt>
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <checker@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wrd(char *a, char *b) {
  parallel(a, b);
  vertical(a, b);
  angle_d(a, b);
  angle_u(a, b);
  checker(0, 0, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wrd>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <parallel@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vertical@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <angle_d@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <angle_u@plt>
  add    $0x8,%rsp
  mov    $0x1,%edx
  xor    %esi,%esi
  pop    %rbp
  xor    %edi,%edi
  pop    %r12
  jmp    10b0 <checker@plt>
```

assistant: ```c
void wrd(char *a, char *b) {
  parallel(a, b);
  vertical(a, b);
  angle_d(a, b);
  angle_u(a, b);
  checker(0, 0, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrd>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <parallel@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vertical@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <angle_d@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <angle_u@plt>
  add    $0x8,%rsp
  mov    $0x1,%edx
  xor    %esi,%esi
  pop    %rbp
  xor    %edi,%edi
  pop    %r12
  jmp    10b0 <checker@plt>
```

assistant: ```c
void wrd(char *a, char *b) {
  parallel(a, b);
  vertical(a, b);
  angle_d(a, b);
  angle_u(a, b);
  checker(0, 0, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<One_Pass_Signature_Packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdx
  mov    $0x3,%esi
  mov    $0xffffffff,%edi
  call   <ver@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <signature_type@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <hash_algs@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <pub_algs@plt>
  mov    $0x0,%eax
  call   <key_id@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  test   %rax,%rax
  jne    L13
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L13:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D37
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D38
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D37: 	Next packet - 

tool: D13: another one pass signature

tool: D38: other than one pass signature

tool: D1: 


assistant: ```c
extern void One_Pass_Signature_Packet(int len) {
  ver(-1, 3, Getc());
  signature_type(Getc());
  hash_algs(Getc());
  pub_algs(Getc());
  key_id();
  printf("\tNext packet - ");
  if (Getc() == 0)
    printf("another one pass signature");
  else
    printf("other than one pass signature");
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<One_Pass_Signature_Packet>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdx
  mov    $0x3,%esi
  mov    $0xffffffff,%edi
  call   <ver@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <signature_type@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <hash_algs@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <pub_algs@plt>
  mov    $0x0,%eax
  call   <key_id@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  test   %rax,%rax
  jne    L13
  lea    D6(%rip),%rdi
  call   <printf@plt>
L14:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L13:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D36
datatype: string

tool: D25: 	Next packet - 

tool: D6: another one pass signature

tool: D28: 


tool: D36: other than one pass signature

assistant: ```c
extern void One_Pass_Signature_Packet(int len) {
  ver(-1, 3, Getc());
  signature_type(Getc());
  hash_algs(Getc());
  pub_algs(Getc());
  key_id();
  printf("\tNext packet - ");
  if (Getc() == 0)
    printf("another one pass signature");
  else
    printf("other than one pass signature");
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<One_Pass_Signature_Packet>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Getc@plt>
  mov    $0x3,%esi
  mov    $0xffffffff,%edi
  mov    %rax,%rdx
  call   <ver@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <signature_type@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <hash_algs@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <pub_algs@plt>
  xor    %eax,%eax
  call   <key_id@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  test   %rax,%rax
  jne    L9
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  add    $0x8,%rsp
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L9:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  add    $0x8,%rsp
  jmp    10b0 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string
name: read_data
arguments: tag: D42
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string

tool: D0: 	Next packet - 

tool: D13: another one pass signature

tool: D42: 


tool: D24: other than one pass signature

assistant: ```c
extern void One_Pass_Signature_Packet(int len) {
  ver(-1, 3, Getc());
  signature_type(Getc());
  hash_algs(Getc());
  pub_algs(Getc());
  key_id();
  printf("\tNext packet - ");
  if (Getc() == 0)
    printf("another one pass signature");
  else
    printf("other than one pass signature");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<One_Pass_Signature_Packet>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Getc@plt>
  mov    $0x3,%esi
  mov    $0xffffffff,%edi
  mov    %rax,%rdx
  call   <ver@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <signature_type@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <hash_algs@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %rax,%rdi
  call   <pub_algs@plt>
  xor    %eax,%eax
  call   <key_id@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  test   %rax,%rax
  jne    L1
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  add    $0x8,%rsp
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L1:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  add    $0x8,%rsp
  jmp    10b0 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D49
datatype: string
name: retrieve_data
arguments: tag: D3
datatype: string

tool: D4: 	Next packet - 

tool: D39: another one pass signature

tool: D49: 


tool: D3: other than one pass signature

assistant: ```c
extern void One_Pass_Signature_Packet(int len) {
  ver(-1, 3, Getc());
  signature_type(Getc());
  hash_algs(Getc());
  pub_algs(Getc());
  key_id();
  printf("\tNext packet - ");
  if (Getc() == 0)
    printf("another one pass signature");
  else
    printf("other than one pass signature");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<R_unif_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L17
  pxor   %xmm0,%xmm0
  jmp    L16
L17:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <rbits@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jae    L14
  movsd  -0x8(%rbp),%xmm0
L16:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double R_unif_index(double dn) {
  if (dn <= 0)
    return 0.0;
  int bits = (int)ceil(log2(dn));
  double dv;
  do {
    dv = rbits(bits);
  } while (dn <= dv);
  return dv;
}
```