user: 这段汇编代码用C语言表示是什么样的：

```asm
<find2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    $0xb,%ebx
  lea    D27(%rip),%r12
  jmp    L57
L41:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L89
  orq    $0x0,-0x8(%rsp,%rax,1)
L89:
  mov    %rsp,%rsi
  test   %r9d,%r9d
  jle    L86
  mov    %rsi,%rcx
  mov    %r8d,%eax
  lea    0x4(%rsi,%rax,4),%rdi
  mov    %ebx,%edx
L112:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%eax
  lea    (%rax,%rax,4),%r10d
  add    %r10d,%r10d
  sub    %r10d,%edx
  mov    %edx,(%rcx)
  mov    %eax,%edx
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L112
L86:
  mov    %r9d,%ecx
  shr    $0x1f,%ecx
  add    %r9d,%ecx
  sar    %ecx
  cmp    $0x1,%r9d
  jle    L18
  movslq %r8d,%r8
  lea    (%rsi,%r8,4),%rdx
  mov    $0x0,%eax
L107:
  mov    (%rdx),%edi
  cmp    %edi,(%rsi,%rax,4)
  jne    L85
  add    $0x1,%rax
  sub    $0x4,%rdx
  cmp    %eax,%ecx
  jg     L107
L18:
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L85:
  mov    %r14,%rsp
L10:
  add    $0x1,%ebx
  cmp    $0x989680,%ebx
  je     L14
L57:
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  mov    %ebx,%edi
  call   <pow@plt>
  cvttsd2si %xmm0,%r13d
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm1
  subsd  %xmm1,%xmm0
  andpd  D23(%rip),%xmm0
  movsd  D29(%rip),%xmm2
  comisd %xmm0,%xmm2
  jbe    L10
  mov    %rsp,%r14
  mov    %ebx,%edi
  call   <log10@plt>
  mov    %rax,%r8
  lea    0x1(%rax),%r9d
  movslq %r9d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L32:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L32
L14:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D7
data_type: f64
name: read_data
arguments: tag: D23
data_type: qword[2]
name: read_data
arguments: tag: D29
data_type: f64

tool: D27: %7d,  %4d, reverse


tool: D7: 0.5

tool: {"D23": [0x7fffffffffffffff,0x0000000000000000]}

tool: D29: 1e-05

assistant: ```c
void find2() {
  int number;
  for (number = 11; number <= 9999999; number++) {
    double root = pow(number, 0.5);
    if (fabs(root - (double)(int)root) < 0.00001) {
      int tempNumber = number;
      int length = (int)log10(number) + 1;
      int digits[length];
      int i;
      for (i = 0; i < length; i++) {
        digits[i] = tempNumber % 10;
        tempNumber /= 10;
      }
      int match = 1;
      for (i = 0; i < length / 2; i++) {
        if (digits[i] != digits[length - i - 1]) {
          match = 0;
          break;
        }
      }
      if (match == 1) {
        printf("%7d,  %4d, reverse\n", number, (int)root);
      }
    }
  }
}
```