ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f2lei_clip_array>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x10,%rsp
  movss  D46(%rip),%xmm2
  test   %ecx,%ecx
  jne    L19
  movss  D21(%rip),%xmm2
L19:
  lea    0x0(,%rbp,4),%eax
  cltq
  lea    (%rsi,%rax,1),%rbx
  sub    $0x1,%ebp
  js     L10
  movsd  D9(%rip),%xmm3
  movslq %ebp,%rbp
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L3:
  movss  %xmm2,0xc(%rsp)
  call   <lrintf@plt>
  mov    D9(%rip),%rdi
  movss  0xc(%rsp),%xmm2
  mov    %eax,%edx
  mov    %eax,%esi
  movzbl %ah,%ecx
  shr    $0x18,%eax
  sar    $0x10,%edx
  movq   %rdi,%xmm3
L52:
  sub    $0x1,%rbp
  mov    %sil,(%rbx)
  mov    %cl,0x1(%rbx)
  mov    %dl,0x2(%rbx)
  mov    %al,0x3(%rbx)
  test   %ebp,%ebp
  js     L10
L72:
  movss  (%r12,%rbp,4),%xmm0
  pxor   %xmm1,%xmm1
  sub    $0x4,%rbx
  mulss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm1
  comisd %xmm3,%xmm1
  jae    L8
  movss  D26(%rip),%xmm4
  comiss %xmm0,%xmm4
  jb     L3
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xffffff80,%eax
  jmp    L52
  nopl   0x0(%rax)
L8:
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%ecx
  mov    $0xffffffff,%edx
  mov    $0x7f,%eax
  jmp    L52
  xchg   %ax,%ax
L10:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D46
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D21
type_infered: f32
name: extract_symbolic_data
arguments: data_label: D9
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D26
type_infered: byte[4]

tool: {"D46": [0x00,0x00,0x00,0x4f]}

tool: D21: 1

tool: {"D9": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

tool: {"D26": [0x00,0x00,0x00,0xcf]}

assistant: ```c
void f2lei_clip_array(float *src, int *dest, int count, int normalize) {
  unsigned char *ucptr;
  float normfact, scaled_value;
  int value;
  normfact = normalize ? (8.0 * 0x10000000) : 1.0;
  ucptr = ((unsigned char *)dest) + 4 * count;
  while (--count >= 0) {
    ucptr -= 4;
    scaled_value = src[count] * normfact;
    if (0 == 0 && scaled_value >= (1.0 * 0x7FFFFFFF)) {
      ucptr[0] = 0xFF;
      ucptr[1] = 0xFF;
      ucptr[2] = 0xFF;
      ucptr[3] = 0x7F;
      continue;
    };
    if (0 == 0 && scaled_value <= (-8.0 * 0x10000000)) {
      ucptr[0] = 0x00;
      ucptr[1] = 0x00;
      ucptr[2] = 0x00;
      ucptr[3] = 0x80;
      continue;
    };
    value = lrintf(scaled_value);
    ucptr[0] = value;
    ucptr[1] = value >> 8;
    ucptr[2] = value >> 16;
    ucptr[3] = value >> 24;
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Delta_ET>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D37(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D51(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D11(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D58(%rip),%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D46(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  D30(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D37
data_type: byte[8]
name: unpack_data
arguments: data_label: D51
data_type: f64
name: unpack_data
arguments: data_label: D11
data_type: f64
name: unpack_data
arguments: data_label: D58
data_type: byte[8]
name: unpack_data
arguments: data_label: D12
data_type: f64
name: unpack_data
arguments: data_label: D46
data_type: byte[8]
name: unpack_data
arguments: data_label: D30
data_type: f64

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D51: 0.747622

tool: D11: 26.465

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D12: 6.283185307179586

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: D30: 1.886913

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Delta_ET>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  subsd  D21(%rip),%xmm0
  mulsd  D40(%rip),%xmm0
  divsd  D10(%rip),%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  D68(%rip),%xmm0
  mulsd  D26(%rip),%xmm0
  addsd  D46(%rip),%xmm0
  mulsd  D3(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
datatype: byte[8]
name: parse_data
arguments: tag: D40
datatype: f64
name: parse_data
arguments: tag: D10
datatype: byte[8]
name: parse_data
arguments: tag: D68
datatype: byte[8]
name: parse_data
arguments: tag: D26
datatype: f64
name: parse_data
arguments: tag: D46
datatype: f64
name: parse_data
arguments: tag: D3
datatype: f64

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D40: 6.283185307179586

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: {"D68": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D26: 0.747622

tool: D46: 26.465

tool: D3: 1.886913

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Delta_ET>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  subsd  D24(%rip),%xmm0
  mulsd  D22(%rip),%xmm0
  divsd  D21(%rip),%xmm0
  call   <sin@plt>
  mulsd  D57(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  D46(%rip),%xmm1
  mulsd  D16(%rip),%xmm1
  addsd  D6(%rip),%xmm1
  add    $0x18,%rsp
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_infered: byte[8]
name: read_data
arguments: label: D22
type_infered: f64
name: read_data
arguments: label: D21
type_infered: byte[8]
name: read_data
arguments: label: D57
type_infered: f64
name: read_data
arguments: label: D46
type_infered: byte[8]
name: read_data
arguments: label: D16
type_infered: f64
name: read_data
arguments: label: D6
type_infered: f64

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D22: 6.283185307179586

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: D57: 1.886913

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D16: 0.747622

tool: D6: 26.465

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: What is the c source code of the assembly code below:

```asm
<Delta_ET>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  subsd  D13(%rip),%xmm0
  mulsd  D1(%rip),%xmm0
  divsd  D22(%rip),%xmm0
  call   <sin@plt>
  mulsd  D21(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  D58(%rip),%xmm1
  mulsd  D3(%rip),%xmm1
  addsd  D62(%rip),%xmm1
  add    $0x18,%rsp
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: byte[8]
name: unpack_data
arguments: data_label: D1
data_type: f64
name: unpack_data
arguments: data_label: D22
data_type: byte[8]
name: unpack_data
arguments: data_label: D21
data_type: f64
name: unpack_data
arguments: data_label: D58
data_type: byte[8]
name: unpack_data
arguments: data_label: D3
data_type: f64
name: unpack_data
arguments: data_label: D62
data_type: f64

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D1: 6.283185307179586

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: D21: 1.886913

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D3: 0.747622

tool: D62: 26.465

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mypow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0x1,%eax
  jmp    L37
L25:
  cmpl   $0x1,-0x18(%rbp)
  jne    L45
  mov    -0x14(%rbp),%eax
  jmp    L37
L21:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L21
  mov    -0x4(%rbp),%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int mypow(int n1, int n2) {
  int p = 2;
  int num = n1;
  if (n2 == 0) {
    return 1;
  }
  if (n2 == 1) {
    return n1;
  }
  while (p <= n2) {
    num = num * n1;
    p += 1;
  }
  return num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mypow>:
  endbr64
  mov    $0x1,%edx
  test   %esi,%esi
  je     L30
  cmp    $0x1,%esi
  jle    L15
  add    $0x1,%esi
  mov    %edi,%edx
  mov    $0x2,%eax
L14:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L14
L30:
  mov    %edx,%eax
  ret
L15:
  mov    %edi,%edx
  jmp    L30
```

assistant: ```c
int mypow(int n1, int n2) {
  int p = 2;
  int num = n1;
  if (n2 == 0) {
    return 1;
  }
  if (n2 == 1) {
    return n1;
  }
  while (p <= n2) {
    num = num * n1;
    p += 1;
  }
  return num;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mypow>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L27
  cmp    $0x1,%esi
  jle    L16
  add    $0x1,%esi
  mov    %edi,%r8d
  mov    $0x2,%eax
  xchg   %ax,%ax
L2:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L2
L27:
  mov    %r8d,%eax
  ret
  nop
L16:
  mov    %edi,%r8d
  jmp    L27
```

assistant: ```c
int mypow(int n1, int n2) {
  int p = 2;
  int num = n1;
  if (n2 == 0) {
    return 1;
  }
  if (n2 == 1) {
    return n1;
  }
  while (p <= n2) {
    num = num * n1;
    p += 1;
  }
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mypow>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L15
  cmp    $0x1,%esi
  jle    L10
  add    $0x1,%esi
  mov    %edi,%r8d
  mov    $0x2,%eax
  xchg   %ax,%ax
L39:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L39
L15:
  mov    %r8d,%eax
  ret
  nop
L10:
  mov    %edi,%r8d
  jmp    L15
```

assistant: ```c
int mypow(int n1, int n2) {
  int p = 2;
  int num = n1;
  if (n2 == 0) {
    return 1;
  }
  if (n2 == 1) {
    return n1;
  }
  while (p <= n2) {
    num = num * n1;
    p += 1;
  }
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getCTS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0xc(%rbp),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int getCTS(int fd) {
  int s;
  ioctl(fd, TIOCMGET, &s);
  return (s & TIOCM_CTS) != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getCTS>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    D18(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getCTS(int fd) {
  int s;
  ioctl(fd, TIOCMGET, &s);
  return (s & TIOCM_CTS) != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getCTS>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    D14(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getCTS(int fd) {
  int s;
  ioctl(fd, TIOCMGET, &s);
  return (s & TIOCM_CTS) != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getCTS>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    D14(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getCTS(int fd) {
  int s;
  ioctl(fd, TIOCMGET, &s);
  return (s & TIOCM_CTS) != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<util_number_is_power_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L1
L3:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  xor    -0x4(%rbp),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int util_number_is_power_2(unsigned input) {
  unsigned minus1;
  if (!input)
    return 0;
  minus1 = input - 1;
  return ((input | minus1) == (input ^ minus1)) ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_number_is_power_2>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  je     L5
  lea    -0x1(%rdi),%eax
  mov    %edi,%edx
  or     %eax,%edx
  xor    %eax,%edi
  cmp    %edi,%edx
  sete   %al
  movzbl %al,%eax
L5:
  ret
```

assistant: ```c
int util_number_is_power_2(unsigned input) {
  unsigned minus1;
  if (!input)
    return 0;
  minus1 = input - 1;
  return ((input | minus1) == (input ^ minus1)) ? 1 : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<util_number_is_power_2>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L0
  lea    -0x1(%rdi),%eax
  mov    %edi,%edx
  or     %eax,%edx
  xor    %eax,%edi
  xor    %eax,%eax
  cmp    %edi,%edx
  sete   %al
L0:
  ret
```

assistant: ```c
int util_number_is_power_2(unsigned input) {
  unsigned minus1;
  if (!input)
    return 0;
  minus1 = input - 1;
  return ((input | minus1) == (input ^ minus1)) ? 1 : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<util_number_is_power_2>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L2
  lea    -0x1(%rdi),%eax
  mov    %edi,%edx
  or     %eax,%edx
  xor    %eax,%edi
  xor    %eax,%eax
  cmp    %edi,%edx
  sete   %al
L2:
  ret
```

assistant: ```c
int util_number_is_power_2(unsigned input) {
  unsigned minus1;
  if (!input)
    return 0;
  minus1 = input - 1;
  return ((input | minus1) == (input ^ minus1)) ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<serve_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x418(%rbp)
  movl   $0x1,-0x41c(%rbp)
  movb   $0x41,-0x410(%rbp)
  movb   $0x0,-0x40f(%rbp)
  jmp    L41
L2:
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <get_line@plt>
  mov    %eax,-0x41c(%rbp)
L41:
  cmpl   $0x0,-0x41c(%rbp)
  jle    L49
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
L49:
  mov    -0x430(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L24
  mov    -0x424(%rbp),%eax
  mov    %eax,%edi
  call   <not_found@plt>
  jmp    L46
L24:
  mov    -0x430(%rbp),%rdx
  mov    -0x424(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <headers@plt>
  mov    -0x418(%rbp),%rdx
  mov    -0x424(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cat@plt>
L46:
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string

tool: D13: 


tool: D18: r

assistant: ```c
void serve_file(int client, const char *filename) {
  FILE *resource = ((void *)0);
  int numchars = 1;
  char buf[1024];
  buf[0] = 'A';
  buf[1] = '\0';
  while ((numchars > 0) && strcmp("\n", buf))
    numchars = get_line(client, buf, sizeof(buf));
  resource = fopen(filename, "r");
  if (resource == ((void *)0))
    not_found(client);
  else {
    headers(client, filename);
    cat(client, resource);
  }
  fclose(resource);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serve_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movb   $0x41,(%rsp)
  movb   $0x0,0x1(%rsp)
  lea    D5(%rip),%rbp
L15:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  mov    %rsp,%rsi
  mov    $0x400,%edx
  mov    %ebx,%edi
  call   <get_line@plt>
  test   %eax,%eax
  jg     L15
L48:
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <headers@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <cat@plt>
L24:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    %ebx,%edi
  call   <not_found@plt>
  jmp    L24
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D5: 


tool: D7: r

assistant: ```c
void serve_file(int client, const char *filename) {
  FILE *resource = ((void *)0);
  int numchars = 1;
  char buf[1024];
  buf[0] = 'A';
  buf[1] = '\0';
  while ((numchars > 0) && strcmp("\n", buf))
    numchars = get_line(client, buf, sizeof(buf));
  resource = fopen(filename, "r");
  if (resource == ((void *)0))
    not_found(client);
  else {
    headers(client, filename);
    cat(client, resource);
  }
  fclose(resource);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<serve_file>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x41,%eax
  mov    %rsp,%rbx
  mov    %ax,(%rsp)
  nopl   0x0(%rax)
L40:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <get_line@plt>
  test   %eax,%eax
  jg     L40
L9:
  lea    D13(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <headers@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <cat@plt>
L18:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebp,%edi
  call   <not_found@plt>
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string

tool: D19: 


tool: D13: r

assistant: ```c
void serve_file(int client, const char *filename) {
  FILE *resource = ((void *)0);
  int numchars = 1;
  char buf[1024];
  buf[0] = 'A';
  buf[1] = '\0';
  while ((numchars > 0) && strcmp("\n", buf))
    numchars = get_line(client, buf, sizeof(buf));
  resource = fopen(filename, "r");
  if (resource == ((void *)0))
    not_found(client);
  else {
    headers(client, filename);
    cat(client, resource);
  }
  fclose(resource);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serve_file>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x41,%eax
  mov    %rsp,%rbx
  mov    %ax,(%rsp)
  nopl   0x0(%rax)
L21:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L39
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <get_line@plt>
  test   %eax,%eax
  jg     L21
L39:
  lea    D16(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L46
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <headers@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <cat@plt>
L43:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %ebp,%edi
  call   <not_found@plt>
  jmp    L43
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D16
type: string

tool: D2: 


tool: D16: r

assistant: ```c
void serve_file(int client, const char *filename) {
  FILE *resource = ((void *)0);
  int numchars = 1;
  char buf[1024];
  buf[0] = 'A';
  buf[1] = '\0';
  while ((numchars > 0) && strcmp("\n", buf))
    numchars = get_line(client, buf, sizeof(buf));
  resource = fopen(filename, "r");
  if (resource == ((void *)0))
    not_found(client);
  else {
    headers(client, filename);
    cat(client, resource);
  }
  fclose(resource);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<got_connection_er>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <end_conn@plt>
  mov    -0x10(%rbp),%rax
  mov    %eax,%edi
  call   <end_conn@plt>
  nop
  leave
  ret
```

assistant: ```c
void got_connection_er(int fd, void *data) {
  end_conn(fd);
  end_conn(((int)(intptr_t)(data)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<got_connection_er>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <end_conn@plt>
  mov    %ebx,%edi
  call   <end_conn@plt>
  pop    %rbx
  ret
```

assistant: ```c
void got_connection_er(int fd, void *data) {
  end_conn(fd);
  end_conn(((int)(intptr_t)(data)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<got_connection_er>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <end_conn@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1050 <end_conn@plt>
```

assistant: ```c
void got_connection_er(int fd, void *data) {
  end_conn(fd);
  end_conn(((int)(intptr_t)(data)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<got_connection_er>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <end_conn@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1050 <end_conn@plt>
```

assistant: ```c
void got_connection_er(int fd, void *data) {
  end_conn(fd);
  end_conn(((int)(intptr_t)(data)));
}
```