ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<libmds_headers_cherrypick_linear_sorted>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <libmds_headers_cherrypick_linear_sorted_v@plt>
  mov    D9(%rip),%rbp
  mov    %r13d,%edi
  mov    %rax,%r12
  mov    0x0(%rbp),%ebx
  call   <va_end@plt>
  mov    %r12,%rax
  mov    %ebx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t libmds_headers_cherrypick_linear_sorted(char **restrict headers, size_t header_count, ...) {
  va_list args;
  size_t r;
  int saved_errno;
  va_start(args, header_count);
  r = libmds_headers_cherrypick_linear_sorted_v(headers, header_count, args);
  saved_errno = errno;
  va_end(args);
  errno = saved_errno;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<binomial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L0
  pxor   %xmm0,%xmm0
  jmp    L16
L0:
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L37:
  mov    -0x14(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L37
  movsd  -0x10(%rbp),%xmm0
L16:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: f64

tool: D9: 1

assistant: ```c
double binomial(int x, int y, int x2) {
  if (y > x)
    return 0;
  double answer = 1.0;
  for (int n = x - y + 1; n <= x; n++) {
    double d = n - x + x2;
    answer *= n / d;
  }
  return answer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binomial>:
  endbr64
  pxor   %xmm1,%xmm1
  cmp    %edi,%esi
  jg     L6
  mov    %edi,%eax
  sub    %esi,%eax
  add    $0x1,%eax
  cmp    %eax,%edi
  jl     L2
  lea    0x1(%rdi),%esi
  movsd  D8(%rip),%xmm1
  sub    %edi,%edx
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  lea    (%rdx,%rax,1),%ecx
  pxor   %xmm2,%xmm2
  cvtsi2sd %ecx,%xmm2
  divsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L3
L6:
  movapd %xmm1,%xmm0
  ret
L2:
  movsd  D8(%rip),%xmm1
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: f64

tool: D8: 1

assistant: ```c
double binomial(int x, int y, int x2) {
  if (y > x)
    return 0;
  double answer = 1.0;
  for (int n = x - y + 1; n <= x; n++) {
    double d = n - x + x2;
    answer *= n / d;
  }
  return answer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binomial>:
  endbr64
  pxor   %xmm1,%xmm1
  cmp    %edi,%esi
  jg     L18
  mov    %edi,%eax
  sub    %esi,%eax
  add    $0x1,%eax
  cmp    %eax,%edi
  jl     L21
  movsd  D13(%rip),%xmm1
  lea    0x1(%rdi),%esi
  sub    %edi,%edx
  nopl   0x0(%rax)
L20:
  lea    (%rdx,%rax,1),%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x1,%eax
  cvtsi2sd %ecx,%xmm2
  divsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  cmp    %eax,%esi
  jne    L20
L18:
  movapd %xmm1,%xmm0
  ret
  nop
L21:
  movsd  D13(%rip),%xmm1
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: f64

tool: D13: 1

assistant: ```c
double binomial(int x, int y, int x2) {
  if (y > x)
    return 0;
  double answer = 1.0;
  for (int n = x - y + 1; n <= x; n++) {
    double d = n - x + x2;
    answer *= n / d;
  }
  return answer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binomial>:
  endbr64
  pxor   %xmm1,%xmm1
  cmp    %edi,%esi
  jg     L17
  mov    %edi,%eax
  sub    %esi,%eax
  add    $0x1,%eax
  cmp    %eax,%edi
  jl     L21
  movsd  D16(%rip),%xmm1
  lea    0x1(%rdi),%esi
  sub    %edi,%edx
  nopl   0x0(%rax)
L28:
  lea    (%rdx,%rax,1),%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x1,%eax
  cvtsi2sd %ecx,%xmm2
  divsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  cmp    %esi,%eax
  jne    L28
L17:
  movapd %xmm1,%xmm0
  ret
  nop
L21:
  movsd  D16(%rip),%xmm1
  jmp    L17
```

tool_calls: name: read_data
arguments: data_label: D16
type_infered: f64

tool: D16: 1

assistant: ```c
double binomial(int x, int y, int x2) {
  if (y > x)
    return 0;
  double answer = 1.0;
  for (int n = x - y + 1; n <= x; n++) {
    double d = n - x + x2;
    answer *= n / d;
  }
  return answer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strsign>:
  endbr64
  lea    D22(%rip),%rax
  test   %rsi,%rsi
  je     L2
  mov    $0x0,%eax
  lea    D22(%rip),%r9
  lea    D1(%rip),%rcx
  lea    0x1(%r9),%r8
L16:
  mov    (%rdi,%rax,4),%edx
  sar    $0x4,%edx
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r9,%rax,2)
  mov    (%rdi,%rax,4),%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L16
  lea    D22(%rip),%rax
  lea    (%rax,%rsi,2),%rax
L2:
  movb   $0x0,(%rax)
  lea    D22(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: 0123456789ABCDEF

assistant: ```c
char *strsign(const void *data, size_t len) {
  static char s[0x100];
  char *t = s;
  static const char *digits = "0123456789ABCDEF";
  const uint8_t *buf = data;
  while (len--) {
    *t++ = digits[*buf >> 4];
    *t++ = digits[*buf & 0x0F];
    buf++;
  }
  *t = '\0';
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strsign>:
  endbr64
  test   %rsi,%rsi
  je     L6
  lea    D16(%rip),%r8
  xor    %eax,%eax
  lea    D15(%rip),%rcx
  lea    0x1(%r8),%r9
  nopl   (%rax)
L12:
  mov    (%rdi,%rax,4),%edx
  sar    $0x4,%edx
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r8,%rax,2)
  mov    (%rdi,%rax,4),%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r9,%rax,2)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L12
  lea    (%r8,%rax,2),%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D16(%rip),%r8
  mov    %r8,%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type: string

tool: D15: 0123456789ABCDEF

assistant: ```c
char *strsign(const void *data, size_t len) {
  static char s[0x100];
  char *t = s;
  static const char *digits = "0123456789ABCDEF";
  const uint8_t *buf = data;
  while (len--) {
    *t++ = digits[*buf >> 4];
    *t++ = digits[*buf & 0x0F];
    buf++;
  }
  *t = '\0';
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strsign>:
  endbr64
  test   %rsi,%rsi
  je     L12
  lea    D23(%rip),%r8
  xor    %eax,%eax
  lea    D20(%rip),%rcx
  lea    0x1(%r8),%r9
  nopl   (%rax)
L10:
  mov    (%rdi,%rax,4),%edx
  sar    $0x4,%edx
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r8,%rax,2)
  mov    (%rdi,%rax,4),%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r9,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L10
  lea    (%r8,%rsi,2),%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  lea    D23(%rip),%r8
  mov    %r8,%rax
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
type: string

tool: D20: 0123456789ABCDEF

assistant: ```c
char *strsign(const void *data, size_t len) {
  static char s[0x100];
  char *t = s;
  static const char *digits = "0123456789ABCDEF";
  const uint8_t *buf = data;
  while (len--) {
    *t++ = digits[*buf >> 4];
    *t++ = digits[*buf & 0x0F];
    buf++;
  }
  *t = '\0';
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<toeplitz_cache_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L45
  mov    %rdi,%r13
  mov    %rdx,%rbx
  xor    %r14d,%r14d
  mov    $0x80000000,%r12d
L34:
  mov    D1(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r15
  movslq (%rax),%rax
  lea    0xf(,%rax,4),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rax
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rsi
  and    $0xfffffffffffffff0,%rax
  cmp    %rsi,%rsp
  je     L74
L81:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L81
L74:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L64
  orq    $0x0,-0x8(%rsp,%rax,1)
L64:
  mov    %rsp,%rdi
  lea    0x0(,%rdx,4),%esi
  mov    %rdi,-0x50(%rbp)
  call   <bzero@plt>
  mov    D1(%rip),%rax
  mov    -0x50(%rbp),%rdi
  mov    (%rax),%esi
  test   %esi,%esi
  jle    L122
  mov    %r14d,%r8d
  mov    %rdi,%r9
  imul   %esi,%r8d
  lea    (%rsi,%r8,1),%r10d
L15:
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L113:
  lea    (%rcx,%r8,1),%eax
  mov    %esi,%r11d
  cltd
  idiv   %esi
  cltq
  sub    %edx,%r11d
  mov    (%rbx,%rax,4),%eax
  sub    $0x1,%r11d
  bt     %r11d,%eax
  jae    L12
  mov    %r12d,%eax
  shr    %cl,%eax
  or     %eax,(%r9)
L12:
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L113
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%r10d
  jne    L15
L122:
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L13:
  mov    %r9d,%r8d
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  test   %esi,%esi
  jle    L111
  nop
L19:
  bt     %eax,%r8d
  jae    L41
  xor    (%rdx),%ecx
L41:
  sub    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0xffffffff,%eax
  jne    L19
L111:
  mov    %ecx,0x0(%r13,%r9,4)
  add    $0x1,%r9
  cmp    $0x100,%r9
  jne    L13
  add    $0x1,%r14d
  add    $0x400,%r13
  mov    %r15,%rsp
  cmp    %r14d,-0x44(%rbp)
  jne    L34
L45:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void toeplitz_cache_create(uint32_t cache[][256], int cache_len, const uint8_t key_str[], __attribute__((unused)) int key_strlen) {
  int i;
  for (i = 0; i < cache_len; ++i) {
    uint32_t key[NBBY];
    int j, b, shift, val;
    bzero(key, sizeof(key));
    for (b = 0; b < NBBY; ++b) {
      for (j = 0; j < 32; ++j) {
        uint8_t k;
        int bit;
        bit = (i * NBBY) + b + j;
        k = key_str[bit / NBBY];
        shift = NBBY - (bit % NBBY) - 1;
        if (k & (1 << shift))
          key[b] |= 1 << (31 - j);
      }
    }
    for (val = 0; val < 256; ++val) {
      uint32_t res = 0;
      for (b = 0; b < NBBY; ++b) {
        shift = NBBY - b - 1;
        if (val & (1 << shift))
          res ^= key[b];
      }
      cache[i][val] = res;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<toeplitz_cache_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L75
  mov    %rdi,%r13
  mov    %rdx,%rbx
  xor    %r14d,%r14d
  mov    $0x80000000,%r12d
L6:
  mov    D8(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r15
  movslq (%rax),%rax
  lea    0xf(,%rax,4),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rax
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rsi
  and    $0xfffffffffffffff0,%rax
  cmp    %rsi,%rsp
  je     L10
L64:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L64
L10:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L9
  orq    $0x0,-0x8(%rsp,%rax,1)
L9:
  mov    %rsp,%rdi
  lea    0x0(,%rdx,4),%esi
  mov    %rdi,-0x50(%rbp)
  call   <bzero@plt>
  mov    D8(%rip),%rax
  mov    -0x50(%rbp),%rdi
  mov    (%rax),%esi
  test   %esi,%esi
  jle    L82
  mov    %r14d,%r8d
  mov    %rdi,%r9
  imul   %esi,%r8d
  lea    (%rsi,%r8,1),%r10d
L44:
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L47:
  lea    (%rcx,%r8,1),%eax
  mov    %esi,%r11d
  cltd
  idiv   %esi
  cltq
  sub    %edx,%r11d
  mov    (%rbx,%rax,4),%eax
  sub    $0x1,%r11d
  bt     %r11d,%eax
  jae    L98
  mov    %r12d,%eax
  shr    %cl,%eax
  or     %eax,(%r9)
L98:
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L47
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%r10d
  jne    L44
L82:
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L91:
  mov    %r9d,%r8d
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  test   %esi,%esi
  jle    L49
  nop
L103:
  bt     %eax,%r8d
  jae    L57
  xor    (%rdx),%ecx
L57:
  sub    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0xffffffff,%eax
  jne    L103
L49:
  mov    %ecx,0x0(%r13,%r9,4)
  add    $0x1,%r9
  cmp    $0x100,%r9
  jne    L91
  add    $0x1,%r14d
  add    $0x400,%r13
  mov    %r15,%rsp
  cmp    %r14d,-0x44(%rbp)
  jne    L6
L75:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void toeplitz_cache_create(uint32_t cache[][256], int cache_len, const uint8_t key_str[], __attribute__((unused)) int key_strlen) {
  int i;
  for (i = 0; i < cache_len; ++i) {
    uint32_t key[NBBY];
    int j, b, shift, val;
    bzero(key, sizeof(key));
    for (b = 0; b < NBBY; ++b) {
      for (j = 0; j < 32; ++j) {
        uint8_t k;
        int bit;
        bit = (i * NBBY) + b + j;
        k = key_str[bit / NBBY];
        shift = NBBY - (bit % NBBY) - 1;
        if (k & (1 << shift))
          key[b] |= 1 << (31 - j);
      }
    }
    for (val = 0; val < 256; ++val) {
      uint32_t res = 0;
      for (b = 0; b < NBBY; ++b) {
        shift = NBBY - b - 1;
        if (val & (1 << shift))
          res ^= key[b];
      }
      cache[i][val] = res;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <vassert@plt>
  jmp    L25
L13:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L25
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: str == NULL

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *pos = NULL;
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      pos = (char *)(str - 1);
  }
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <vassert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L16
  mov    $0x0,%edx
L17:
  mov    %rbx,%rcx
  add    $0x1,%rbx
  movsbl %al,%eax
  cmp    %ebp,%eax
  cmove  %rcx,%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L17
L4:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x0,%edx
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: str == NULL

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *pos = NULL;
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      pos = (char *)(str - 1);
  }
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  lea    D1(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <vassert@plt>
  movsbl (%rbx),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L17
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rdx
  add    $0x1,%rbx
  cmp    %ebp,%eax
  movsbl (%rbx),%eax
  cmove  %rdx,%r8
  test   %al,%al
  jne    L19
L17:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: str == NULL

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *pos = NULL;
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      pos = (char *)(str - 1);
  }
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  lea    D2(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <vassert@plt>
  movsbl (%rbx),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L7
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbx,%rdx
  add    $0x1,%rbx
  cmp    %eax,%ebp
  movsbl (%rbx),%eax
  cmove  %rdx,%r8
  test   %al,%al
  jne    L15
L7:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: str == NULL

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *pos = NULL;
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      pos = (char *)(str - 1);
  }
  return pos;
}
```
user: What is the c source code of the assembly code below:

```asm
<strdupl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdupl(char *str) {
  char *point_word;
  point_word = (char *)malloc(strlen(str) + 1);
  if (point_word != NULL)
    strcpy(point_word, str);
  return point_word;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strdupl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L3
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L2
```

assistant: ```c
char *strdupl(char *str) {
  char *point_word;
  point_word = (char *)malloc(strlen(str) + 1);
  if (point_word != NULL)
    strcpy(point_word, str);
  return point_word;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strdupl>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdupl(char *str) {
  char *point_word;
  point_word = (char *)malloc(strlen(str) + 1);
  if (point_word != NULL)
    strcpy(point_word, str);
  return point_word;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdupl>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L9:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdupl(char *str) {
  char *point_word;
  point_word = (char *)malloc(strlen(str) + 1);
  if (point_word != NULL)
    strcpy(point_word, str);
  return point_word;
}
```
user: What is the c source code of the assembly code below:

```asm
<process_events>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <server_process_events@plt>
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <server_is_running@plt>
  test   %rax,%rax
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void process_events(void *data) {
  struct server *s = (struct server *)data;
  while (server_is_running(s)) {
    server_process_events(s);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<process_events>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L8
L1:
  mov    %rbx,%rdi
  call   <server_process_events@plt>
L8:
  mov    %rbx,%rdi
  call   <server_is_running@plt>
  test   %rax,%rax
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void process_events(void *data) {
  struct server *s = (struct server *)data;
  while (server_is_running(s)) {
    server_process_events(s);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<process_events>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  call   <server_process_events@plt>
L10:
  mov    %rbx,%rdi
  call   <server_is_running@plt>
  test   %rax,%rax
  jne    L11
  pop    %rbx
  ret
```

assistant: ```c
void process_events(void *data) {
  struct server *s = (struct server *)data;
  while (server_is_running(s)) {
    server_process_events(s);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_events>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbx,%rdi
  call   <server_process_events@plt>
L18:
  mov    %rbx,%rdi
  call   <server_is_running@plt>
  test   %rax,%rax
  jne    L10
  pop    %rbx
  ret
```

assistant: ```c
void process_events(void *data) {
  struct server *s = (struct server *)data;
  while (server_is_running(s)) {
    server_process_events(s);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_fail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: --- FAIL: %s


assistant: ```c
void test_fail(const char *test_name) {
  printf("--- FAIL: %s\n", test_name);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_fail>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: --- FAIL: %s


assistant: ```c
void test_fail(const char *test_name) {
  printf("--- FAIL: %s\n", test_name);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_fail>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: --- FAIL: %s


assistant: ```c
void test_fail(const char *test_name) {
  printf("--- FAIL: %s\n", test_name);
  exit(1);
}
```