ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<take_wager>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L9
  add    %eax,%ebp
  cmp    %ebp,%ebx
  jl     L22
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D44(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L44
L22:
  mov    %ebp,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L44
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D41
type_infered: string
name: unpack_data
arguments: tag: D32
type_infered: string
name: unpack_data
arguments: tag: D44
type_infered: string
name: unpack_data
arguments: tag: D36
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string

tool: D41: How many of your %d credits would you like to wager? 

tool: D32: %d

tool: D44: Nice try, but you must wager a positive number!

tool: D36: Your total wager of %d is more than you have!


tool: D28: You only have %d available credits, try again.


assistant: ```c
int take_wager(int available_credits, int previous_wager) {
  int wager, total_wager;
  printf("How many of your %d credits would you like to wager? ", available_credits);
  scanf("%d", &wager);
  if (wager < 1) {
    printf("Nice try, but you must wager a positive number!\n");
    return -1;
  }
  total_wager = previous_wager + wager;
  if (total_wager > available_credits) {
    printf("Your total wager of %d is more than you have!\n", total_wager);
    printf("You only have %d available credits, try again.\n", available_credits);
    return -1;
  }
  return wager;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<take_wager>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L48
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jl     L31
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L48:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string
name: retrieve_data
arguments: data_label: D23
type_guessed: string
name: retrieve_data
arguments: data_label: D2
type_guessed: string
name: retrieve_data
arguments: data_label: D40
type_guessed: string
name: retrieve_data
arguments: data_label: D20
type_guessed: string

tool: D0: How many of your %d credits would you like to wager? 

tool: D23: %d

tool: D2: Your total wager of %d is more than you have!


tool: D40: You only have %d available credits, try again.


tool: D20: Nice try, but you must wager a positive number!

assistant: ```c
int take_wager(int available_credits, int previous_wager) {
  int wager, total_wager;
  printf("How many of your %d credits would you like to wager? ", available_credits);
  scanf("%d", &wager);
  if (wager < 1) {
    printf("Nice try, but you must wager a positive number!\n");
    return -1;
  }
  total_wager = previous_wager + wager;
  if (total_wager > available_credits) {
    printf("Your total wager of %d is more than you have!\n", total_wager);
    printf("You only have %d available credits, try again.\n", available_credits);
    return -1;
  }
  return wager;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<take_wager>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  lea    D45(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L33
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jl     L11
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L36
L33:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L36
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D45
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string

tool: D45: How many of your %d credits would you like to wager? 

tool: D7: %d

tool: D4: Your total wager of %d is more than you have!


tool: D49: You only have %d available credits, try again.


tool: D12: Nice try, but you must wager a positive number!

assistant: ```c
int take_wager(int available_credits, int previous_wager) {
  int wager, total_wager;
  printf("How many of your %d credits would you like to wager? ", available_credits);
  scanf("%d", &wager);
  if (wager < 1) {
    printf("Nice try, but you must wager a positive number!\n");
    return -1;
  }
  total_wager = previous_wager + wager;
  if (total_wager > available_credits) {
    printf("Your total wager of %d is more than you have!\n", total_wager);
    printf("You only have %d available credits, try again.\n", available_credits);
    return -1;
  }
  return wager;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IOdebug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void IOdebug(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<IOdebug>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void IOdebug(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IOdebug>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void IOdebug(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<IOdebug>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void IOdebug(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<irmo_string_nocase_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x1505,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L5
L2:
  mov    -0x1c(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%ebx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  add    %ebx,%eax
  mov    %eax,-0x1c(%rbp)
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int irmo_string_nocase_hash(void *string) {
  unsigned int result = 5381;
  unsigned char *p;
  p = (unsigned char *)string;
  while (*p != '\0') {
    result = (result << 5) + result + (unsigned int)tolower(*p);
    ++p;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<irmo_string_nocase_hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L26
  mov    $0x1505,%eax
L27:
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    (%rdx,%rax,1),%ebx
  movzbl %dil,%edi
  call   <tolower@plt>
  add    %ebx,%eax
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L27
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    $0x1505,%eax
  jmp    L29
```

assistant: ```c
unsigned int irmo_string_nocase_hash(void *string) {
  unsigned int result = 5381;
  unsigned char *p;
  p = (unsigned char *)string;
  while (*p != '\0') {
    result = (result << 5) + result + (unsigned int)tolower(*p);
    ++p;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<irmo_string_nocase_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1505,%eax
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L16
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %eax,%edx
  add    $0x1,%rbp
  shl    $0x5,%edx
  lea    (%rdx,%rax,1),%ebx
  call   <tolower@plt>
  movzbl 0x0(%rbp),%edi
  add    %ebx,%eax
  test   %dil,%dil
  jne    L14
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int irmo_string_nocase_hash(void *string) {
  unsigned int result = 5381;
  unsigned char *p;
  p = (unsigned char *)string;
  while (*p != '\0') {
    result = (result << 5) + result + (unsigned int)tolower(*p);
    ++p;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<irmo_string_nocase_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1505,%eax
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %eax,%edx
  add    $0x1,%rbp
  shl    $0x5,%edx
  lea    (%rdx,%rax,1),%ebx
  call   <tolower@plt>
  movzbl 0x0(%rbp),%edi
  add    %ebx,%eax
  test   %dil,%dil
  jne    L1
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int irmo_string_nocase_hash(void *string) {
  unsigned int result = 5381;
  unsigned char *p;
  p = (unsigned char *)string;
  while (*p != '\0') {
    result = (result << 5) + result + (unsigned int)tolower(*p);
    ++p;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ByteSwap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    $0x0,%r12d
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%ebx
  jmp    L17
L5:
  movslq %r12d,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movslq %ebx,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movslq %r12d,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movslq %ebx,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  add    $0x1,%r12d
  sub    $0x1,%ebx
L17:
  cmp    %ebx,%r12d
  jl     L5
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void ByteSwap(unsigned char *b, int n) {
  register int i = 0;
  register int j = n - 1;
  unsigned char temp;
  while (i < j) {
    temp = b[i];
    b[i] = b[j];
    b[j] = temp;
    i++, j--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ByteSwap>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L9
  movslq %esi,%rsi
  mov    $0x0,%eax
L2:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L2
L9:
  ret
```

assistant: ```c
void ByteSwap(unsigned char *b, int n) {
  register int i = 0;
  register int j = n - 1;
  unsigned char temp;
  while (i < j) {
    temp = b[i];
    b[i] = b[j];
    b[j] = temp;
    i++, j--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ByteSwap>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L6
  movslq %esi,%rsi
  xor    %eax,%eax
L14:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L14
L6:
  ret
```

assistant: ```c
void ByteSwap(unsigned char *b, int n) {
  register int i = 0;
  register int j = n - 1;
  unsigned char temp;
  while (i < j) {
    temp = b[i];
    b[i] = b[j];
    b[j] = temp;
    i++, j--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ByteSwap>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L13
  movslq %esi,%rsi
  xor    %eax,%eax
L10:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L10
L13:
  ret
```

assistant: ```c
void ByteSwap(unsigned char *b, int n) {
  register int i = 0;
  register int j = n - 1;
  unsigned char temp;
  while (i < j) {
    temp = b[i];
    b[i] = b[j];
    b[j] = temp;
    i++, j--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<round_shift_8x8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x10,%edi
  call   <_mm_set1_epi16@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  mov    (%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %eax,(%rbx)
  mov    0x4(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x4(%rbx)
  mov    0x8(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x8(%rbx)
  mov    0xc(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0xc(%rbx)
  mov    0x10(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x10(%rbx)
  mov    0x14(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x14(%rbx)
  mov    0x18(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x18(%rbx)
  mov    0x1c(%r12),%edi
  mov    %ebp,%esi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x1c(%rbx)
  mov    $0x5,%esi
  mov    (%rbx),%edi
  call   <_mm_srai_epi16@plt>
  mov    %eax,(%rbx)
  mov    0x4(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x4(%rbx)
  mov    0x8(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x8(%rbx)
  mov    0xc(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0xc(%rbx)
  mov    0x10(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x10(%rbx)
  mov    0x14(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x14(%rbx)
  mov    0x18(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x18(%rbx)
  mov    0x1c(%rbx),%edi
  mov    $0x5,%esi
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x1c(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void round_shift_8x8(const __m128i *const in, __m128i *const out) {
  const __m128i final_rounding = _mm_set1_epi16(1 << 4);
  out[0] = _mm_add_epi16(in[0], final_rounding);
  out[1] = _mm_add_epi16(in[1], final_rounding);
  out[2] = _mm_add_epi16(in[2], final_rounding);
  out[3] = _mm_add_epi16(in[3], final_rounding);
  out[4] = _mm_add_epi16(in[4], final_rounding);
  out[5] = _mm_add_epi16(in[5], final_rounding);
  out[6] = _mm_add_epi16(in[6], final_rounding);
  out[7] = _mm_add_epi16(in[7], final_rounding);
  out[0] = _mm_srai_epi16(out[0], 5);
  out[1] = _mm_srai_epi16(out[1], 5);
  out[2] = _mm_srai_epi16(out[2], 5);
  out[3] = _mm_srai_epi16(out[3], 5);
  out[4] = _mm_srai_epi16(out[4], 5);
  out[5] = _mm_srai_epi16(out[5], 5);
  out[6] = _mm_srai_epi16(out[6], 5);
  out[7] = _mm_srai_epi16(out[7], 5);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<round_shift_8x8>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x10,%edi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <_mm_set1_epi16@plt>
  mov    (%r12),%edi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,(%rbx)
  mov    0x4(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x4(%rbx)
  mov    0x8(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x8(%rbx)
  mov    0xc(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0xc(%rbx)
  mov    0x10(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x10(%rbx)
  mov    0x14(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x14(%rbx)
  mov    0x18(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x18(%rbx)
  mov    0x1c(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    (%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x1c(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x4(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x8(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x4(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0xc(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x8(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x10(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0xc(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x14(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x10(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x18(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x14(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x1c(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x18(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x1c(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void round_shift_8x8(const __m128i *const in, __m128i *const out) {
  const __m128i final_rounding = _mm_set1_epi16(1 << 4);
  out[0] = _mm_add_epi16(in[0], final_rounding);
  out[1] = _mm_add_epi16(in[1], final_rounding);
  out[2] = _mm_add_epi16(in[2], final_rounding);
  out[3] = _mm_add_epi16(in[3], final_rounding);
  out[4] = _mm_add_epi16(in[4], final_rounding);
  out[5] = _mm_add_epi16(in[5], final_rounding);
  out[6] = _mm_add_epi16(in[6], final_rounding);
  out[7] = _mm_add_epi16(in[7], final_rounding);
  out[0] = _mm_srai_epi16(out[0], 5);
  out[1] = _mm_srai_epi16(out[1], 5);
  out[2] = _mm_srai_epi16(out[2], 5);
  out[3] = _mm_srai_epi16(out[3], 5);
  out[4] = _mm_srai_epi16(out[4], 5);
  out[5] = _mm_srai_epi16(out[5], 5);
  out[6] = _mm_srai_epi16(out[6], 5);
  out[7] = _mm_srai_epi16(out[7], 5);
}
```
user: What is the c source code of the assembly code below:

```asm
<round_shift_8x8>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x10,%edi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <_mm_set1_epi16@plt>
  mov    (%r12),%edi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,(%rbx)
  mov    0x4(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x4(%rbx)
  mov    0x8(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x8(%rbx)
  mov    0xc(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0xc(%rbx)
  mov    0x10(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x10(%rbx)
  mov    0x14(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x14(%rbx)
  mov    0x18(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    %ebp,%esi
  mov    %eax,0x18(%rbx)
  mov    0x1c(%r12),%edi
  call   <_mm_add_epi16@plt>
  mov    (%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x1c(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x4(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x8(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x4(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0xc(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x8(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x10(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0xc(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x14(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x10(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x18(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x14(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    0x1c(%rbx),%edi
  mov    $0x5,%esi
  mov    %eax,0x18(%rbx)
  call   <_mm_srai_epi16@plt>
  mov    %eax,0x1c(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void round_shift_8x8(const __m128i *const in, __m128i *const out) {
  const __m128i final_rounding = _mm_set1_epi16(1 << 4);
  out[0] = _mm_add_epi16(in[0], final_rounding);
  out[1] = _mm_add_epi16(in[1], final_rounding);
  out[2] = _mm_add_epi16(in[2], final_rounding);
  out[3] = _mm_add_epi16(in[3], final_rounding);
  out[4] = _mm_add_epi16(in[4], final_rounding);
  out[5] = _mm_add_epi16(in[5], final_rounding);
  out[6] = _mm_add_epi16(in[6], final_rounding);
  out[7] = _mm_add_epi16(in[7], final_rounding);
  out[0] = _mm_srai_epi16(out[0], 5);
  out[1] = _mm_srai_epi16(out[1], 5);
  out[2] = _mm_srai_epi16(out[2], 5);
  out[3] = _mm_srai_epi16(out[3], 5);
  out[4] = _mm_srai_epi16(out[4], 5);
  out[5] = _mm_srai_epi16(out[5], 5);
  out[6] = _mm_srai_epi16(out[6], 5);
  out[7] = _mm_srai_epi16(out[7], 5);
}
```