ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L62
L32:
  subl   $0x1,-0x8(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L54
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L32
L54:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L31
L4:
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L29
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L4
L29:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L62:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L69
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low], i = low, j = high;
  while (i < j) {
    while (i < j && a[j] >= pivot)
      j = j - 1;
    a[i] = a[j];
    while (i < j && a[i] <= pivot)
      i = i + 1;
    a[j] = a[i];
  }
  a[i] = pivot;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<partition>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%eax
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%r8d
  cmp    %edx,%esi
  jl     L59
  jmp    L22
L90:
  movslq %eax,%rcx
  lea    (%r9,%rcx,4),%rcx
  mov    %edi,(%rcx)
  cmp    %eax,%edx
  jle    L10
L41:
  cmp    %r8d,(%rcx)
  jg     L42
  add    $0x1,%eax
  add    $0x4,%rcx
  cmp    %edx,%eax
  jne    L41
L56:
  movslq %edx,%rax
  mov    (%r9,%rax,4),%eax
  mov    %eax,(%rsi)
  mov    %edx,%eax
L22:
  movslq %eax,%rdx
  mov    %r8d,(%r9,%rdx,4)
  ret
L42:
  movslq %eax,%rcx
  mov    (%r9,%rcx,4),%ecx
  mov    %ecx,(%rsi)
  cmp    %edx,%eax
  jge    L22
L59:
  movslq %edx,%rcx
  lea    (%r9,%rcx,4),%rsi
  mov    (%rsi),%edi
  cmp    %r8d,%edi
  jl     L90
  sub    $0x1,%edx
  cmp    %eax,%edx
  jg     L59
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rsi
  mov    (%rsi),%ecx
  movslq %eax,%rdx
  mov    %ecx,(%r9,%rdx,4)
  mov    %eax,%edx
  jmp    L56
L10:
  mov    %eax,%edx
  jmp    L56
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low], i = low, j = high;
  while (i < j) {
    while (i < j && a[j] >= pivot)
      j = j - 1;
    a[i] = a[j];
    while (i < j && a[i] <= pivot)
      i = i + 1;
    a[j] = a[i];
  }
  a[i] = pivot;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<partition>:
  endbr64
  movslq %esi,%r10
  mov    %rdi,%r11
  lea    (%rdi,%r10,4),%rdi
  mov    %r10,%rcx
  mov    (%rdi),%r9d
  cmp    %edx,%r10d
  jge    L26
  push   %rbx
  movslq %edx,%rbx
  mov    %edx,%eax
  mov    (%r11,%rbx,4),%edx
  nopw   0x0(%rax,%rax,1)
L6:
  lea    -0x4(%r11,%rbx,4),%rsi
  nopl   (%rax)
L56:
  cmp    %edx,%r9d
  jg     L36
  mov    %rsi,%r8
  sub    $0x1,%eax
  lea    -0x4(%rsi),%rsi
  mov    0x4(%rsi),%edx
  cmp    %ecx,%eax
  jg     L56
  lea    (%r11,%r10,4),%rdi
  mov    %ecx,%eax
  mov    %edx,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L83:
  mov    %edx,(%r8)
L86:
  mov    %r9d,(%rdi)
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  lea    0x0(,%r10,4),%rsi
  movslq %eax,%rbx
  lea    (%r11,%rsi,1),%rdi
  lea    (%r11,%rbx,4),%r8
  mov    %edx,(%rdi)
  cmp    %eax,%ecx
  jge    L23
  lea    0x4(%r11,%rsi,1),%rsi
  xchg   %ax,%ax
L34:
  mov    %rsi,%rdi
  add    $0x1,%ecx
  lea    0x4(%rsi),%rsi
  mov    -0x4(%rsi),%edx
  cmp    %eax,%ecx
  je     L83
  cmp    %edx,%r9d
  jge    L34
  mov    %edx,(%r8)
  cmp    %eax,%ecx
  jge    L5
  movslq %ecx,%r10
  jmp    L6
L26:
  mov    %r9d,(%rdi)
  mov    %r10d,%eax
  ret
L23:
  mov    %ecx,%eax
  jmp    L83
L5:
  movslq %ecx,%rax
  lea    (%r11,%rax,4),%rdi
  mov    %ecx,%eax
  jmp    L86
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low], i = low, j = high;
  while (i < j) {
    while (i < j && a[j] >= pivot)
      j = j - 1;
    a[i] = a[j];
    while (i < j && a[i] <= pivot)
      i = i + 1;
    a[j] = a[i];
  }
  a[i] = pivot;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<partition>:
  endbr64
  movslq %esi,%rcx
  mov    %rdi,%r9
  mov    %rcx,%rax
  lea    (%rdi,%rcx,4),%rcx
  mov    (%rcx),%r8d
  cmp    %edx,%eax
  jge    L47
  movslq %edx,%r10
  mov    (%rdi,%r10,4),%esi
  nop
L32:
  lea    -0x4(%r9,%r10,4),%rcx
  nopl   (%rax)
L3:
  cmp    %esi,%r8d
  jg     L36
  mov    %rcx,%rdi
  sub    $0x1,%edx
  lea    -0x4(%rcx),%rcx
  mov    0x4(%rcx),%esi
  cmp    %eax,%edx
  jg     L3
  movslq %eax,%rdx
  lea    (%r9,%rdx,4),%rcx
  mov    %esi,(%rcx)
  nopw   0x0(%rax,%rax,1)
L80:
  mov    %esi,(%rdi)
L47:
  mov    %r8d,(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  movslq %eax,%rcx
  movslq %edx,%r10
  lea    (%r9,%rcx,4),%rcx
  lea    (%r9,%r10,4),%rdi
  mov    %esi,(%rcx)
  cmp    %edx,%eax
  jl     L17
  jmp    L80
  cs nopw 0x0(%rax,%rax,1)
L53:
  add    $0x1,%eax
  add    $0x4,%rcx
  cmp    %edx,%eax
  je     L86
L17:
  mov    (%rcx),%esi
  cmp    %r8d,%esi
  jle    L53
  mov    %esi,(%rdi)
  cmp    %edx,%eax
  jl     L32
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L86:
  movslq %eax,%rdx
  lea    (%r9,%rdx,4),%rcx
  mov    (%rcx),%esi
  jmp    L80
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low], i = low, j = high;
  while (i < j) {
    while (i < j && a[j] >= pivot)
      j = j - 1;
    a[i] = a[j];
    while (i < j && a[i] <= pivot)
      i = i + 1;
    a[j] = a[i];
  }
  a[i] = pivot;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L6:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<Multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movb   $0x1,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L22
L28:
  movzbl -0x2(%rbp),%eax
  and    -0x18(%rbp),%al
  test   %al,%al
  je     L39
  movzbl -0x14(%rbp),%eax
  xor    %al,-0x1(%rbp)
L39:
  shlb   -0x2(%rbp)
  movzbl -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  test   %al,%al
  jns    L10
  mov    $0x1b,%eax
  jmp    L49
L10:
  mov    $0x0,%eax
L49:
  xor    %edx,%eax
  mov    %al,-0x14(%rbp)
L22:
  cmpb   $0x0,-0x2(%rbp)
  jne    L28
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char Multiply(unsigned char num, unsigned char factor) {
  unsigned char mask = 1;
  unsigned char result = 0;
  while (mask != 0) {
    if (mask & factor) {
      result ^= num;
    }
    mask <<= 1;
    num = (num << 1) ^ (num & 0x80 ? 0x1b : 0);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Multiply>:
  endbr64
  mov    $0x8,%ecx
  mov    $0x0,%eax
  mov    $0x1,%edx
L5:
  mov    %eax,%r8d
  xor    %edi,%r8d
  test   %dl,%sil
  cmovne %r8d,%eax
  add    %edx,%edx
  lea    (%rdi,%rdi,1),%r8d
  sar    $0x7,%dil
  and    $0x1b,%edi
  xor    %r8d,%edi
  sub    $0x1,%ecx
  jne    L5
  ret
```

assistant: ```c
unsigned char Multiply(unsigned char num, unsigned char factor) {
  unsigned char mask = 1;
  unsigned char result = 0;
  while (mask != 0) {
    if (mask & factor) {
      result ^= num;
    }
    mask <<= 1;
    num = (num << 1) ^ (num & 0x80 ? 0x1b : 0);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Multiply>:
  endbr64
  mov    $0x8,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  nopl   0x0(%rax)
L3:
  mov    %r8d,%eax
  xor    %edi,%eax
  test   %dl,%sil
  cmovne %eax,%r8d
  movzbl %dil,%eax
  add    %edx,%edx
  add    %eax,%eax
  mov    %eax,%r9d
  xor    $0x1b,%r9d
  test   %dil,%dil
  mov    %r9d,%edi
  cmovns %eax,%edi
  sub    $0x1,%ecx
  jne    L3
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char Multiply(unsigned char num, unsigned char factor) {
  unsigned char mask = 1;
  unsigned char result = 0;
  while (mask != 0) {
    if (mask & factor) {
      result ^= num;
    }
    mask <<= 1;
    num = (num << 1) ^ (num & 0x80 ? 0x1b : 0);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Multiply>:
  endbr64
  mov    %esi,%eax
  movzbl %dil,%ecx
  mov    %esi,%edx
  and    $0x1,%eax
  cmovne %edi,%eax
  add    %ecx,%ecx
  mov    %ecx,%esi
  xor    $0x1b,%esi
  test   %dil,%dil
  cmovs  %esi,%ecx
  mov    %eax,%esi
  xor    %ecx,%esi
  test   $0x2,%dl
  cmovne %esi,%eax
  movzbl %cl,%esi
  add    %esi,%esi
  mov    %esi,%edi
  xor    $0x1b,%edi
  test   %cl,%cl
  mov    %eax,%ecx
  cmovs  %edi,%esi
  xor    %esi,%ecx
  test   $0x4,%dl
  cmovne %ecx,%eax
  movzbl %sil,%ecx
  add    %ecx,%ecx
  mov    %ecx,%edi
  xor    $0x1b,%edi
  test   %sil,%sil
  mov    %eax,%esi
  cmovs  %edi,%ecx
  xor    %ecx,%esi
  test   $0x8,%dl
  cmovne %esi,%eax
  movzbl %cl,%esi
  add    %esi,%esi
  mov    %esi,%edi
  xor    $0x1b,%edi
  test   %cl,%cl
  mov    %eax,%ecx
  cmovs  %edi,%esi
  xor    %esi,%ecx
  test   $0x10,%dl
  cmovne %ecx,%eax
  movzbl %sil,%ecx
  add    %ecx,%ecx
  mov    %ecx,%edi
  xor    $0x1b,%edi
  test   %sil,%sil
  mov    %eax,%esi
  cmovs  %edi,%ecx
  xor    %ecx,%esi
  test   $0x20,%dl
  cmovne %esi,%eax
  movzbl %cl,%esi
  add    %esi,%esi
  mov    %esi,%edi
  xor    $0x1b,%edi
  test   %cl,%cl
  mov    %eax,%ecx
  cmovs  %edi,%esi
  xor    %esi,%ecx
  test   $0x40,%dl
  cmovne %ecx,%eax
  movzbl %sil,%ecx
  add    %ecx,%ecx
  mov    %ecx,%edi
  xor    $0x1b,%edi
  test   %sil,%sil
  cmovs  %edi,%ecx
  xor    %eax,%ecx
  test   %dl,%dl
  cmovs  %ecx,%eax
  ret
```

assistant: ```c
unsigned char Multiply(unsigned char num, unsigned char factor) {
  unsigned char mask = 1;
  unsigned char result = 0;
  while (mask != 0) {
    if (mask & factor) {
      result ^= num;
    }
    mask <<= 1;
    num = (num << 1) ^ (num & 0x80 ? 0x1b : 0);
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L26
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L30
L48:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L26:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  cmp    $0x1,%rax
  jne    L48
  jmp    L47
L49:
  nop
L47:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
L30:
  leave
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  size_t n = size;
  const char *s = src;
  if (size == 0) {
    return strlen(src);
  }
  while (n-- != 1) {
    if (*s == '\0') {
      break;
    }
    *dst++ = *s++;
  }
  *dst = '\0';
  return s - src;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L33
  mov    %rsi,%rax
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,1),%r8
  cmp    $0x1,%rdx
  je     L1
L27:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L1
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  mov    %r8,%rdx
  sub    %rcx,%rdx
  cmp    $0x1,%rdx
  jne    L27
L1:
  movb   $0x0,(%rcx)
  sub    %rsi,%rax
  ret
L33:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  size_t n = size;
  const char *s = src;
  if (size == 0) {
    return strlen(src);
  }
  while (n-- != 1) {
    if (*s == '\0') {
      break;
    }
    *dst++ = *s++;
  }
  *dst = '\0';
  return s - src;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L29
  mov    %rsi,%rax
  lea    (%rdi,%rdx,1),%rcx
  cmp    $0x1,%rdx
  jne    L48
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  mov    %rcx,%rdx
  add    $0x1,%rax
  sub    %rdi,%rdx
  cmp    $0x1,%rdx
  je     L40
L48:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L12
L40:
  sub    %rsi,%rax
L0:
  movb   $0x0,(%rdi)
  ret
  nopl   (%rax)
L29:
  mov    %rsi,%rdi
  jmp    1050 <strlen@plt>
L53:
  xor    %eax,%eax
  jmp    L0
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  size_t n = size;
  const char *s = src;
  if (size == 0) {
    return strlen(src);
  }
  while (n-- != 1) {
    if (*s == '\0') {
      break;
    }
    *dst++ = *s++;
  }
  *dst = '\0';
  return s - src;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L19
  mov    %rsi,%rax
  lea    (%rdi,%rdx,1),%rcx
  cmp    $0x1,%rdx
  jne    L49
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L51:
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  mov    %rcx,%rdx
  add    $0x1,%rax
  sub    %rdi,%rdx
  cmp    $0x1,%rdx
  je     L10
L49:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L51
L10:
  sub    %rsi,%rax
L1:
  movb   $0x0,(%rdi)
  ret
  nopl   (%rax)
L19:
  mov    %rsi,%rdi
  jmp    1050 <strlen@plt>
L28:
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  size_t n = size;
  const char *s = src;
  if (size == 0) {
    return strlen(src);
  }
  while (n-- != 1) {
    if (*s == '\0') {
      break;
    }
    *dst++ = *s++;
  }
  *dst = '\0';
  return s - src;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L28
  cmpb   $0x7a,-0x4(%rbp)
  jg     L28
  movsbl -0x4(%rbp),%eax
  sub    $0x61,%eax
  jmp    L90
L28:
  cmpb   $0x40,-0x4(%rbp)
  jle    L91
  cmpb   $0x5a,-0x4(%rbp)
  jg     L91
  movsbl -0x4(%rbp),%eax
  sub    $0x27,%eax
  jmp    L90
L91:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L44
  cmpb   $0x39,-0x4(%rbp)
  jg     L44
  movsbl -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L90
L44:
  cmpb   $0x5f,-0x4(%rbp)
  jne    L60
  mov    $0x3e,%eax
  jmp    L90
L60:
  cmpb   $0x2d,-0x4(%rbp)
  jne    L20
  mov    $0x3f,%eax
  jmp    L90
L20:
  mov    $0xffffffff,%eax
L90:
  pop    %rbp
  ret
```

assistant: ```c
int decode(char code) {
  if ('a' <= code && code <= 'z')
    return code - 'a';
  else if ('A' <= code && code <= 'Z')
    return code - 'A' + 26;
  else if ('0' <= code && code <= '9')
    return code - '0' + 52;
  else if (code == '_')
    return 62;
  else if (code == '-')
    return 63;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L8
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L20
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L33
  cmp    $0x5f,%dil
  je     L21
  cmp    $0x2d,%dil
  mov    $0x3f,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
L8:
  movsbl %dil,%edi
  lea    -0x61(%rdi),%eax
  ret
L20:
  movsbl %dil,%edi
  lea    -0x27(%rdi),%eax
  ret
L33:
  movsbl %dil,%edi
  lea    0x4(%rdi),%eax
  ret
L21:
  mov    $0x3e,%eax
  ret
```

assistant: ```c
int decode(char code) {
  if ('a' <= code && code <= 'z')
    return code - 'a';
  else if ('A' <= code && code <= 'Z')
    return code - 'A' + 26;
  else if ('0' <= code && code <= '9')
    return code - '0' + 52;
  else if (code == '_')
    return 62;
  else if (code == '-')
    return 63;
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decode>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L1
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L24
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L35
  cmp    $0x5f,%dil
  je     L36
  cmp    $0x2d,%dil
  mov    $0xffffffff,%edx
  mov    $0x3f,%eax
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L24:
  sub    $0x27,%edi
  movsbl %dil,%eax
  ret
L1:
  movsbl %al,%eax
  ret
  nopl   0x0(%rax)
L35:
  add    $0x4,%edi
  movsbl %dil,%eax
  ret
L36:
  mov    $0x3e,%eax
  ret
```

assistant: ```c
int decode(char code) {
  if ('a' <= code && code <= 'z')
    return code - 'a';
  else if ('A' <= code && code <= 'Z')
    return code - 'A' + 26;
  else if ('0' <= code && code <= '9')
    return code - '0' + 52;
  else if (code == '_')
    return 62;
  else if (code == '-')
    return 63;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decode>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L31
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L34
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L26
  cmp    $0x5f,%dil
  je     L11
  cmp    $0x2d,%dil
  mov    $0xffffffff,%edx
  mov    $0x3f,%eax
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L34:
  sub    $0x27,%edi
  movsbl %dil,%eax
  ret
L31:
  movsbl %al,%eax
  ret
  nopl   0x0(%rax)
L26:
  add    $0x4,%edi
  movsbl %dil,%eax
  ret
L11:
  mov    $0x3e,%eax
  ret
```

assistant: ```c
int decode(char code) {
  if ('a' <= code && code <= 'z')
    return code - 'a';
  else if ('A' <= code && code <= 'Z')
    return code - 'A' + 26;
  else if ('0' <= code && code <= '9')
    return code - '0' + 52;
  else if (code == '_')
    return 62;
  else if (code == '-')
    return 63;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<dsign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L46
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L46
  mov    $0x0,%eax
  jmp    L36
L46:
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L47
  mov    $0x1,%eax
  jmp    L36
L47:
  mov    $0xffffffff,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int dsign(double x) {
  if (0 == x) {
    return 0;
  } else if (x > 0) {
    return 1;
  } else {
    return -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dsign>:
  endbr64
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L11
  mov    $0x0,%eax
  je     L12
L11:
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
L12:
  ret
```

assistant: ```c
int dsign(double x) {
  if (0 == x) {
    return 0;
  } else if (x > 0) {
    return 1;
  } else {
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dsign>:
  endbr64
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L9
  mov    $0x0,%eax
  je     L12
L9:
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
L12:
  ret
```

assistant: ```c
int dsign(double x) {
  if (0 == x) {
    return 0;
  } else if (x > 0) {
    return 1;
  } else {
    return -1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_sigignore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigaction@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int _sigignore(int sig) {
  struct sigaction action;
  action.sa_handler = SIG_IGN;
  return sigaction(sig, &action, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_sigignore>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  call   <sigaction@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _sigignore(int sig) {
  struct sigaction action;
  action.sa_handler = SIG_IGN;
  return sigaction(sig, &action, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sigignore>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <sigaction@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _sigignore(int sig) {
  struct sigaction action;
  action.sa_handler = SIG_IGN;
  return sigaction(sig, &action, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sigignore>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <sigaction@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _sigignore(int sig) {
  struct sigaction action;
  action.sa_handler = SIG_IGN;
  return sigaction(sig, &action, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int result;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int result;
  return 0;
}
```