ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<blkxor>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%r8
  lea    0x4(%rsi),%rdx
  mov    %rsi,%rdi
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L70
  cmp    $0x1,%r8
  je     L70
  lea    -0x1(%r8),%rax
  cmp    $0x2,%rax
  jbe    L49
  lea    -0x4(%r8),%rdx
  xor    %eax,%eax
  xor    %esi,%esi
  shr    $0x2,%rdx
  add    $0x1,%rdx
  nopl   0x0(%rax)
L80:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rcx,%rax,1),%xmm2
  add    $0x1,%rsi
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rdx
  ja     L80
  lea    0x0(,%rdx,4),%r9
  shl    $0x4,%rdx
  lea    (%rcx,%rdx,1),%rsi
  lea    (%rdi,%rdx,1),%rax
  cmp    %r9,%r8
  je     L51
  sub    %r9,%r8
  cmp    $0x1,%r8
  je     L67
L77:
  lea    (%rcx,%r9,4),%rdx
  movq   (%rdi,%r9,4),%xmm0
  movq   (%rdx),%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,(%rdx)
  mov    %r8,%rdx
  and    $0xfffffffffffffffe,%rdx
  lea    0x0(,%rdx,4),%rcx
  add    %rcx,%rsi
  add    %rcx,%rax
  cmp    %rdx,%r8
  je     L51
L67:
  mov    (%rax),%eax
  xor    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L70:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L79:
  mov    (%rdi,%rax,4),%edx
  xor    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L79
L51:
  ret
L49:
  mov    %rsi,%rax
  xor    %r9d,%r9d
  mov    %rcx,%rsi
  jmp    L77
```

assistant: ```c
void blkxor(uint32_t *dst, const uint32_t *src, size_t count) {
  do {
    *dst++ ^= *src++;
  } while (--count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_be64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <read_be32@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x20,%eax
  mov    %eax,%ecx
  shll   %cl,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <read_at_be32@plt>
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t read_be64(const void *src) {
  uint64_t val;
  val = read_be32(src);
  val <<= 32;
  val |= read_at_be32(src, sizeof(uint32_t));
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_be64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <read_be32@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <read_at_be32@plt>
  pop    %rbx
  ret
```

assistant: ```c
uint64_t read_be64(const void *src) {
  uint64_t val;
  val = read_be32(src);
  val <<= 32;
  val |= read_at_be32(src, sizeof(uint32_t));
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_be64>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <read_be32@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  pop    %rbp
  jmp    1060 <read_at_be32@plt>
```

assistant: ```c
uint64_t read_be64(const void *src) {
  uint64_t val;
  val = read_be32(src);
  val <<= 32;
  val |= read_at_be32(src, sizeof(uint32_t));
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_be64>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <read_be32@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  pop    %rbp
  jmp    1060 <read_at_be32@plt>
```

assistant: ```c
uint64_t read_be64(const void *src) {
  uint64_t val;
  val = read_be32(src);
  val <<= 32;
  val |= read_at_be32(src, sizeof(uint32_t));
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<newlines_off>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    -0xc(%rbp),%edx
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void newlines_off(void) {
  struct termios t;
  tcgetattr(0, &t);
  t.c_oflag &= ~(INLCR | OPOST);
  tcsetattr(0, TCSADRAIN, &t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<newlines_off>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    D19(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  mov    %rbx,%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void newlines_off(void) {
  struct termios t;
  tcgetattr(0, &t);
  t.c_oflag &= ~(INLCR | OPOST);
  tcsetattr(0, TCSADRAIN, &t);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<newlines_off>:
  endbr64
  push   %r12
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  mov    D6(%rip),%rdx
  mov    D23(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    %r12,%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  mov    D26(%rip),%rax
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void newlines_off(void) {
  struct termios t;
  tcgetattr(0, &t);
  t.c_oflag &= ~(INLCR | OPOST);
  tcsetattr(0, TCSADRAIN, &t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<newlines_off>:
  endbr64
  push   %r12
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  mov    D3(%rip),%rdx
  mov    D19(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    %r12,%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void newlines_off(void) {
  struct termios t;
  tcgetattr(0, &t);
  t.c_oflag &= ~(INLCR | OPOST);
  tcsetattr(0, TCSADRAIN, &t);
}
```
user: What is the c source code of the assembly code below:

```asm
<csql_rand_fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L22
L11:
  mov    $0x0,%eax
  call   <csql_rand_get@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jb     L11
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void csql_rand_fill(char *buf) {
  unsigned int randint, i, times;
  times = 20 / sizeof(unsigned int);
  for (i = 0; i < times; i++) {
    randint = csql_rand_get();
    memcpy(buf + (i * sizeof(unsigned int)), &randint, sizeof(unsigned int));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<csql_rand_fill>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    0x14(%rdi),%rbp
  lea    0x4(%rsp),%r12
L13:
  mov    $0x0,%eax
  call   <csql_rand_get@plt>
  mov    %eax,0x4(%rsp)
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void csql_rand_fill(char *buf) {
  unsigned int randint, i, times;
  times = 20 / sizeof(unsigned int);
  for (i = 0; i < times; i++) {
    randint = csql_rand_get();
    memcpy(buf + (i * sizeof(unsigned int)), &randint, sizeof(unsigned int));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<csql_rand_fill>:
  endbr64
  push   %r12
  lea    0x14(%rdi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L13:
  xor    %eax,%eax
  call   <csql_rand_get@plt>
  mov    %rbx,%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  add    $0x4,%rbx
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void csql_rand_fill(char *buf) {
  unsigned int randint, i, times;
  times = 20 / sizeof(unsigned int);
  for (i = 0; i < times; i++) {
    randint = csql_rand_get();
    memcpy(buf + (i * sizeof(unsigned int)), &randint, sizeof(unsigned int));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<csql_rand_fill>:
  endbr64
  push   %r12
  lea    0x14(%rdi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L12:
  xor    %eax,%eax
  call   <csql_rand_get@plt>
  mov    %rbx,%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  add    $0x4,%rbx
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void csql_rand_fill(char *buf) {
  unsigned int randint, i, times;
  times = 20 / sizeof(unsigned int);
  for (i = 0; i < times; i++) {
    randint = csql_rand_get();
    memcpy(buf + (i * sizeof(unsigned int)), &randint, sizeof(unsigned int));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<kingdomCards>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    -0x28(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1c(%rax),%rdx
  mov    0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    0x20(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x24(%rax),%rdx
  mov    0x28(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *kingdomCards(int k1, int k2, int k3, int k4, int k5, int k6, int k7, int k8, int k9, int k10) {
  int *k = malloc(10 * sizeof(int));
  k[0] = k1;
  k[1] = k2;
  k[2] = k3;
  k[3] = k4;
  k[4] = k5;
  k[5] = k6;
  k[6] = k7;
  k[7] = k8;
  k[8] = k9;
  k[9] = k10;
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kingdomCards>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  mov    %r9d,%ebx
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %r15d,(%rax)
  mov    %r14d,0x4(%rax)
  mov    %r13d,0x8(%rax)
  mov    %r12d,0xc(%rax)
  mov    %ebp,0x10(%rax)
  mov    %ebx,0x14(%rax)
  mov    0x40(%rsp),%edx
  mov    %edx,0x18(%rax)
  mov    0x48(%rsp),%edx
  mov    %edx,0x1c(%rax)
  mov    0x50(%rsp),%edx
  mov    %edx,0x20(%rax)
  mov    0x58(%rsp),%edx
  mov    %edx,0x24(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *kingdomCards(int k1, int k2, int k3, int k4, int k5, int k6, int k7, int k8, int k9, int k10) {
  int *k = malloc(10 * sizeof(int));
  k[0] = k1;
  k[1] = k2;
  k[2] = k3;
  k[3] = k4;
  k[4] = k5;
  k[5] = k6;
  k[6] = k7;
  k[7] = k8;
  k[8] = k9;
  k[9] = k10;
  return k;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kingdomCards>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  mov    $0x28,%edi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    0x40(%rsp),%edx
  mov    %r13d,(%rax)
  mov    %edx,0x18(%rax)
  mov    0x48(%rsp),%edx
  mov    %r14d,0x4(%rax)
  mov    %edx,0x1c(%rax)
  mov    0x50(%rsp),%edx
  mov    %r15d,0x8(%rax)
  mov    %edx,0x20(%rax)
  mov    0x58(%rsp),%edx
  mov    %r12d,0xc(%rax)
  mov    %ebp,0x10(%rax)
  mov    %ebx,0x14(%rax)
  mov    %edx,0x24(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *kingdomCards(int k1, int k2, int k3, int k4, int k5, int k6, int k7, int k8, int k9, int k10) {
  int *k = malloc(10 * sizeof(int));
  k[0] = k1;
  k[1] = k2;
  k[2] = k3;
  k[3] = k4;
  k[4] = k5;
  k[5] = k6;
  k[6] = k7;
  k[7] = k8;
  k[8] = k9;
  k[9] = k10;
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kingdomCards>:
  endbr64
  movd   %edx,%xmm0
  movd   %ecx,%xmm5
  movd   %edi,%xmm1
  sub    $0x38,%rsp
  movd   0x58(%rsp),%xmm4
  movd   0x50(%rsp),%xmm2
  movd   %esi,%xmm6
  punpckldq %xmm5,%xmm0
  movd   0x40(%rsp),%xmm3
  movd   0x48(%rsp),%xmm7
  punpckldq %xmm6,%xmm1
  mov    $0x28,%edi
  punpckldq %xmm4,%xmm2
  punpcklqdq %xmm0,%xmm1
  movd   %r9d,%xmm4
  movd   %r8d,%xmm0
  punpckldq %xmm7,%xmm3
  movaps %xmm1,0x10(%rsp)
  punpckldq %xmm4,%xmm0
  movq   %xmm2,0x28(%rsp)
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  movdqa 0x10(%rsp),%xmm1
  movdqa (%rsp),%xmm0
  movq   0x28(%rsp),%xmm2
  movups %xmm1,(%rax)
  movups %xmm0,0x10(%rax)
  movq   %xmm2,0x20(%rax)
  add    $0x38,%rsp
  ret
```

assistant: ```c
int *kingdomCards(int k1, int k2, int k3, int k4, int k5, int k6, int k7, int k8, int k9, int k10) {
  int *k = malloc(10 * sizeof(int));
  k[0] = k1;
  k[1] = k2;
  k[2] = k3;
  k[3] = k4;
  k[4] = k5;
  k[5] = k6;
  k[6] = k7;
  k[7] = k8;
  k[8] = k9;
  k[9] = k10;
  return k;
}
```
user: What is the c source code of the assembly code below?

```asm
<norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x24(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  D8(%rip),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L0
L1:
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  addq   $0x4,-0x18(%rbp)
L0:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: f32

tool: D8: 1

assistant: ```c
void norm(g, dt, nt) float *g, *dt;
int nt;
{
  float fac;
  fac = 1.0 / ((*dt) * nt);
  while (nt--) {
    g[0] = g[0] * fac;
    g++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<norm>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  mulss  (%rsi),%xmm0
  movss  D8(%rip),%xmm1
  divss  %xmm0,%xmm1
  test   %edx,%edx
  je     L7
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rax
L4:
  movaps %xmm1,%xmm0
  mulss  (%rdi),%xmm0
  movss  %xmm0,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L4
L7:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: f32

tool: D8: 1

assistant: ```c
void norm(g, dt, nt) float *g, *dt;
int nt;
{
  float fac;
  fac = 1.0 / ((*dt) * nt);
  while (nt--) {
    g[0] = g[0] * fac;
    g++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<norm>:
  endbr64
  pxor   %xmm0,%xmm0
  movss  D6(%rip),%xmm1
  cvtsi2ss %edx,%xmm0
  mulss  (%rsi),%xmm0
  divss  %xmm0,%xmm1
  test   %edx,%edx
  je     L8
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L5:
  movss  (%rdi),%xmm0
  add    $0x4,%rdi
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L5
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: f32

tool: D6: 1

assistant: ```c
void norm(g, dt, nt) float *g, *dt;
int nt;
{
  float fac;
  fac = 1.0 / ((*dt) * nt);
  while (nt--) {
    g[0] = g[0] * fac;
    g++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<norm>:
  endbr64
  pxor   %xmm2,%xmm2
  movss  D8(%rip),%xmm0
  lea    -0x1(%rdx),%eax
  cvtsi2ss %edx,%xmm2
  mulss  (%rsi),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  test   %edx,%edx
  je     L45
  cmp    $0x2,%eax
  jbe    L48
  mov    %edx,%ecx
  movaps %xmm1,%xmm2
  mov    %rdi,%rax
  shr    $0x2,%ecx
  shufps $0x0,%xmm2,%xmm2
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L50:
  movups (%rax),%xmm0
  add    $0x10,%rax
  mulps  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L50
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  lea    (%rdi,%rax,4),%rax
  cmp    %ecx,%edx
  je     L17
L15:
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L20
  lea    (%rdi,%rcx,4),%rcx
  movaps %xmm1,%xmm2
  movq   (%rcx),%xmm0
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm0
  movlps %xmm0,(%rcx)
  mov    %edx,%ecx
  and    $0xfffffffe,%ecx
  mov    %ecx,%esi
  lea    (%rax,%rsi,4),%rax
  cmp    %ecx,%edx
  je     L45
L20:
  mulss  (%rax),%xmm1
  movss  %xmm1,(%rax)
L45:
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  ret
L48:
  mov    %rdi,%rax
  xor    %ecx,%ecx
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: f32

tool: D8: 1

assistant: ```c
void norm(g, dt, nt) float *g, *dt;
int nt;
{
  float fac;
  fac = 1.0 / ((*dt) * nt);
  while (nt--) {
    g[0] = g[0] * fac;
    g++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: Generates a sinus dataset
Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>
	-> frequs and amplitudes are double vales, time is int in sec
	-> prints to stdout


assistant: ```c
void usage() {
  printf("Generates a sinus dataset\n"
         "Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>\n"
         "\t-> frequs and amplitudes are double vales, time is int in sec\n"
         "\t-> prints to stdout\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: Generates a sinus dataset
Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>
	-> frequs and amplitudes are double vales, time is int in sec
	-> prints to stdout


assistant: ```c
void usage() {
  printf("Generates a sinus dataset\n"
         "Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>\n"
         "\t-> frequs and amplitudes are double vales, time is int in sec\n"
         "\t-> prints to stdout\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: Generates a sinus dataset
Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>
	-> frequs and amplitudes are double vales, time is int in sec
	-> prints to stdout


assistant: ```c
void usage() {
  printf("Generates a sinus dataset\n"
         "Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>\n"
         "\t-> frequs and amplitudes are double vales, time is int in sec\n"
         "\t-> prints to stdout\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Generates a sinus dataset
Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>
	-> frequs and amplitudes are double vales, time is int in sec
	-> prints to stdout


assistant: ```c
void usage() {
  printf("Generates a sinus dataset\n"
         "Usage: sinus_gen  <frequ> <frequ amplitude> <parasitic frequ> <amplitude> <fsample> <sampling time>\n"
         "\t-> frequs and amplitudes are double vales, time is int in sec\n"
         "\t-> prints to stdout\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L7
L19:
  mov    -0x1c(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  add    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L19
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <powl@plt>
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fabsl@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long solve(int N) {
  unsigned long res_s = 0;
  unsigned long s_res = 0;
  for (int i = 1; i <= N; ++i) {
    res_s += (unsigned long)pow(i, 2);
    s_res += i;
  }
  unsigned long res = fabsl(powl(s_res, 2) - res_s);
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L13
  mov    %edi,%r13d
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L15:
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <pow@plt>
  add    %rax,%rbp
  add    %rbx,%r12
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L15
L28:
  mov    $0x2,%esi
  mov    %r12,%rdi
  call   <powl@plt>
  sub    %rbp,%rax
  mov    %rax,%rdi
  call   <fabsl@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L28
```

assistant: ```c
unsigned long solve(int N) {
  unsigned long res_s = 0;
  unsigned long s_res = 0;
  for (int i = 1; i <= N; ++i) {
    res_s += (unsigned long)pow(i, 2);
    s_res += i;
  }
  unsigned long res = fabsl(powl(s_res, 2) - res_s);
  return res;
}
```