ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<_DtGetDisplayResolution>:
  endbr64
  sub    $0x8,%rsp
  call   <XDisplayWidth@plt>
  mov    $0x4,%r8d
  cmp    $0x497,%eax
  jg     L11
  mov    $0x3,%r8d
  cmp    $0x352,%eax
  jg     L11
  xor    %r8d,%r8d
  cmp    $0x1ff,%eax
  setg   %r8b
L11:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _DtGetDisplayResolution(Display *disp, int screen) {
  int screenWidth = XDisplayWidth(disp, screen);
  if (screenWidth >= 1176) {
    return (4);
  }
  if (screenWidth >= 851) {
    return (3);
  }
  if (screenWidth >= 512) {
    return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x50(%rbp)
  movl   $0x5,-0x4c(%rbp)
  movl   $0x4,-0x48(%rbp)
  movl   $0x6,-0x44(%rbp)
  movl   $0xd,-0x40(%rbp)
  movl   $0x7,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x9,-0x34(%rbp)
  movl   $0xc,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0xa,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0xf,-0x1c(%rbp)
  movl   $0xe,-0x18(%rbp)
  movl   $0x13,-0x14(%rbp)
  movl   $0x11,-0x10(%rbp)
  movl   $0x1e,-0xc(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x12,%esi
  mov    %rax,%rdi
  call   <heap_sort_min_with_time_shown@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x12,%esi
  mov    %rax,%rdi
  call   <heap_sort_max_with_time_shown@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: 
-----------------------------------


assistant: ```c
int main() {
  int data[] = {8, 5, 4, 6, 13, 7, 2, 9, 12, 11, 3, 10, 1, 15, 14, 19, 17, 30};
  heap_sort_min_with_time_shown(data, 18);
  printf("\n-----------------------------------\n");
  heap_sort_max_with_time_shown(data, 18);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0xd,0x10(%rsp)
  movl   $0x7,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x9,0x1c(%rsp)
  movl   $0xc,0x20(%rsp)
  movl   $0xb,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0xa,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0xf,0x34(%rsp)
  movl   $0xe,0x38(%rsp)
  movl   $0x13,0x3c(%rsp)
  movl   $0x11,0x40(%rsp)
  movl   $0x1e,0x44(%rsp)
  mov    %rsp,%rbx
  mov    $0x12,%esi
  mov    %rbx,%rdi
  call   <heap_sort_min_with_time_shown@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x12,%esi
  mov    %rbx,%rdi
  call   <heap_sort_max_with_time_shown@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: 
-----------------------------------


assistant: ```c
int main() {
  int data[] = {8, 5, 4, 6, 13, 7, 2, 9, 12, 11, 3, 10, 1, 15, 14, 19, 17, 30};
  heap_sort_min_with_time_shown(data, 18);
  printf("\n-----------------------------------\n");
  heap_sort_max_with_time_shown(data, 18);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x12,%esi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x500000008,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x70000000d,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x900000002,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xb0000000c,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xa00000003,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xf00000001,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x130000000e,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x1e00000011,%rax
  mov    %rax,0x40(%rsp)
  call   <heap_sort_min_with_time_shown@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x12,%esi
  mov    %rbp,%rdi
  call   <heap_sort_max_with_time_shown@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: 
-----------------------------------


assistant: ```c
int main() {
  int data[] = {8, 5, 4, 6, 13, 7, 2, 9, 12, 11, 3, 10, 1, 15, 14, 19, 17, 30};
  heap_sort_min_with_time_shown(data, 18);
  printf("\n-----------------------------------\n");
  heap_sort_max_with_time_shown(data, 18);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x12,%esi
  sub    $0x50,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D29(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D47(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x40(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D38(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D58(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <heap_sort_min_with_time_shown@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    $0x12,%esi
  mov    %rbp,%rdi
  call   <heap_sort_max_with_time_shown@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D29
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D47
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D38
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D58
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D56
type_infered: string

tool: {"D9": [0x08,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D29": [0x11,0x00,0x00,0x00,0x1e,0x00,0x00,0x00]}

tool: {"D47": [0x0d,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D38": [0x0c,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D58": [0x01,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x13,0x00,0x00,0x00]}

tool: D56: 
-----------------------------------


assistant: ```c
int main() {
  int data[] = {8, 5, 4, 6, 13, 7, 2, 9, 12, 11, 3, 10, 1, 15, 14, 19, 17, 30};
  heap_sort_min_with_time_shown(data, 18);
  printf("\n-----------------------------------\n");
  heap_sort_max_with_time_shown(data, 18);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D2(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D15(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D22(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D30(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: f64
name: unpack_data
arguments: data_label: D15
data_type: f64
name: unpack_data
arguments: data_label: D22
data_type: f64
name: unpack_data
arguments: data_label: D30
data_type: f64

tool: D2: 3

tool: D15: 5

tool: D22: 6

tool: D30: 1

assistant: ```c
double f(double x) {
  double result;
  result = 1.0 / (5.0 * pow(x, 3.0) + 6.0);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  movsd  D36(%rip),%xmm1
  call   <pow@plt>
  movapd %xmm0,%xmm1
  mulsd  D39(%rip),%xmm1
  addsd  D16(%rip),%xmm1
  movsd  D24(%rip),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D36
datatype: f64
name: disassemble_data
arguments: tag: D39
datatype: f64
name: disassemble_data
arguments: tag: D16
datatype: f64
name: disassemble_data
arguments: tag: D24
datatype: f64

tool: D36: 3

tool: D39: 5

tool: D16: 6

tool: D24: 1

assistant: ```c
double f(double x) {
  double result;
  result = 1.0 / (5.0 * pow(x, 3.0) + 6.0);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  movsd  D27(%rip),%xmm1
  call   <pow@plt>
  movsd  D31(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D11(%rip),%xmm0
  addsd  D13(%rip),%xmm1
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
type_guessed: f64
name: parse_data
arguments: data_label: D31
type_guessed: f64
name: parse_data
arguments: data_label: D11
type_guessed: f64
name: parse_data
arguments: data_label: D13
type_guessed: f64

tool: D27: 3

tool: D31: 5

tool: D11: 1

tool: D13: 6

assistant: ```c
double f(double x) {
  double result;
  result = 1.0 / (5.0 * pow(x, 3.0) + 6.0);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  movsd  D16(%rip),%xmm1
  call   <pow@plt>
  movsd  D9(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  addsd  D23(%rip),%xmm1
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
data_type: f64
name: unpack_data
arguments: data_label: D9
data_type: f64
name: unpack_data
arguments: data_label: D17
data_type: f64
name: unpack_data
arguments: data_label: D23
data_type: f64

tool: D16: 3

tool: D9: 5

tool: D17: 1

tool: D23: 6

assistant: ```c
double f(double x) {
  double result;
  result = 1.0 / (5.0 * pow(x, 3.0) + 6.0);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d_max_mat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %ecx,0x10(%rsp)
  test   %edi,%edi
  jle    L40
  mov    %edi,%ebp
  mov    %rdx,%r13
  test   %esi,%esi
  jle    L40
  pxor   %xmm0,%xmm0
  cvtsd2ss (%rdx),%xmm0
  movss  %xmm0,D35(%rip)
  movss  %xmm0,D142(%rip)
  movss  %xmm0,D104(%rip)
  movss  %xmm0,D83(%rip)
  lea    -0x4(%rdi),%eax
  shr    $0x2,%eax
  mov    %eax,%edx
  lea    0x0(,%rdx,4),%rcx
  mov    %rcx,0x18(%rsp)
  lea    0x4(,%rax,4),%eax
  mov    %eax,0x14(%rsp)
  mov    $0x0,%r12d
  mov    $0x0,%r14d
  jmp    L68
L70:
  movslq %ebx,%rbx
  movslq %r12d,%rax
  lea    0x0(%r13,%rax,8),%r15
L23:
  pxor   %xmm1,%xmm1
  cvtsd2ss (%r15,%rbx,8),%xmm1
  movss  D35(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L23
L79:
  add    $0x1,%r14d
  add    0x10(%rsp),%r12d
  cmp    %r14d,0xc(%rsp)
  jle    L69
L68:
  mov    $0x0,%ebx
  cmp    $0x3,%ebp
  jle    L70
  movslq %r12d,%rax
  lea    0x0(%r13,%rax,8),%rbx
  add    0x18(%rsp),%rax
  lea    0x20(%r13,%rax,8),%r15
L29:
  pxor   %xmm1,%xmm1
  cvtsd2ss (%rbx),%xmm1
  movss  D123(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
  pxor   %xmm1,%xmm1
  cvtsd2ss 0x8(%rbx),%xmm1
  movss  D142(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
  pxor   %xmm1,%xmm1
  cvtsd2ss 0x10(%rbx),%xmm1
  movss  D104(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
  pxor   %xmm1,%xmm1
  cvtsd2ss 0x18(%rbx),%xmm1
  movss  D83(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
  add    $0x20,%rbx
  cmp    %r15,%rbx
  jne    L29
  mov    0x14(%rsp),%eax
  cmp    %eax,%ebp
  jle    L79
  mov    %eax,%ebx
  jmp    L70
L69:
  movss  D123(%rip),%xmm1
  movss  D123(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
  movss  D123(%rip),%xmm1
  movss  D123(%rip),%xmm0
  call   <fmax@plt>
  movaps %xmm0,%xmm1
  movss  %xmm0,D123(%rip)
  movss  D123(%rip),%xmm0
  call   <fmax@plt>
  movss  %xmm0,D123(%rip)
L28:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  pxor   %xmm0,%xmm0
  jmp    L28
```

assistant: ```c
float d_max_mat(int row, int col, double *A, int lda) {
  if (row <= 0 || col <= 0)
    return 0.0;
  int i, j;
  static float max_vec[4];
  max_vec[0] = A[0];
  max_vec[1] = A[0];
  max_vec[2] = A[0];
  max_vec[3] = A[0];
  for (j = 0; j < col; j++) {
    i = 0;
    for (; i < row - 3; i += 4) {
      max_vec[0] = fmax(max_vec[0], A[i + 0 + j * lda]);
      max_vec[1] = fmax(max_vec[1], A[i + 1 + j * lda]);
      max_vec[2] = fmax(max_vec[2], A[i + 2 + j * lda]);
      max_vec[3] = fmax(max_vec[3], A[i + 3 + j * lda]);
    }
    for (; i < row; i++) {
      max_vec[0] = fmax(max_vec[0], A[i + j * lda]);
    }
  }
  max_vec[0] = fmax(max_vec[0], max_vec[2]);
  max_vec[1] = fmax(max_vec[1], max_vec[3]);
  max_vec[0] = fmax(max_vec[0], max_vec[1]);
  return max_vec[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<kmap_atomic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *kmap_atomic(struct page *page) {
  assert(0);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kmap_atomic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *kmap_atomic(struct page *page) {
  assert(0);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kmap_atomic>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *kmap_atomic(struct page *page) {
  assert(0);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kmap_atomic>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *kmap_atomic(struct page *page) {
  assert(0);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D26(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D26
type: string

tool: D3: w+

tool: D22: toto

tool: D26: Hello world


assistant: ```c
int main() {
  FILE *d = fopen("toto", "w+");
  fprintf(d, "Hello world\n");
  fclose(d);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D27(%rip),%rsi
  lea    D22(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D27: w+

tool: D22: toto

tool: D2: Hello world


assistant: ```c
int main() {
  FILE *d = fopen("toto", "w+");
  fprintf(d, "Hello world\n");
  fclose(d);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <fopen@plt>
  lea    D7(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D4: w+

tool: D14: toto

tool: D7: Hello world


assistant: ```c
int main() {
  FILE *d = fopen("toto", "w+");
  fprintf(d, "Hello world\n");
  fclose(d);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  lea    D14(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D2: w+

tool: D6: toto

tool: D14: Hello world


assistant: ```c
int main() {
  FILE *d = fopen("toto", "w+");
  fprintf(d, "Hello world\n");
  fclose(d);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<send_msg2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void send_msg2(void) {
  static char msg[] = "Goodnight Irene\r\n";
  write(1, msg, strlen(msg));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_msg2>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  pop    %rbx
  ret
```

assistant: ```c
void send_msg2(void) {
  static char msg[] = "Goodnight Irene\r\n";
  write(1, msg, strlen(msg));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_msg2>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <write@plt>
```

assistant: ```c
void send_msg2(void) {
  static char msg[] = "Goodnight Irene\r\n";
  write(1, msg, strlen(msg));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_msg2>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <write@plt>
```

assistant: ```c
void send_msg2(void) {
  static char msg[] = "Goodnight Irene\r\n";
  write(1, msg, strlen(msg));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<security_sql_injection_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0x20,%rsp
  mov    %rdi,-0x20018(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x20018(%rbp)
  je     L11
  mov    -0x20018(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
L11:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L40
L45:
  mov    -0x20018(%rbp),%rcx
  lea    -0x20010(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <string_escape_character_array@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string

tool: 

tool: D18: `'$;%&=

assistant: ```c
char *security_sql_injection_escape(char *data) {
  char destination[131072];
  if (!data || !*data)
    return strdup("");
  return strdup(string_escape_character_array(destination, data, "`'$;%&="));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<security_sql_injection_escape>:
  endbr64
  lea    -0x20000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L32
  mov    %rdi,%rsi
  cmpb   $0x0,(%rdi)
  jne    L37
L32:
  lea    D18(%rip),%rdi
  call   <strdup@plt>
L43:
  mov    0x20008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20018,%rsp
  ret
L37:
  mov    %rsp,%rdi
  lea    D1(%rip),%rdx
  call   <string_escape_character_array@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L43
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: 

tool: D1: `'$;%&=

assistant: ```c
char *security_sql_injection_escape(char *data) {
  char destination[131072];
  if (!data || !*data)
    return strdup("");
  return strdup(string_escape_character_array(destination, data, "`'$;%&="));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<security_sql_injection_escape>:
  endbr64
  lea    -0x20000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rsi
  jne    L29
L5:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  lea    D9(%rip),%rdi
  add    $0x20018,%rsp
  jmp    1090 <strdup@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rsp,%rdi
  lea    D17(%rip),%rdx
  call   <string_escape_character_array@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    0x20008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x20018,%rsp
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string

tool: 

tool: D17: `'$;%&=

assistant: ```c
char *security_sql_injection_escape(char *data) {
  char destination[131072];
  if (!data || !*data)
    return strdup("");
  return strdup(string_escape_character_array(destination, data, "`'$;%&="));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<security_sql_injection_escape>:
  endbr64
  lea    -0x20000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L47
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rsi
  jne    L21
L47:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  lea    D14(%rip),%rdi
  add    $0x20018,%rsp
  jmp    1090 <strdup@plt>
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rsp,%rdi
  lea    D15(%rip),%rdx
  call   <string_escape_character_array@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    0x20008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x20018,%rsp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: 

tool: D15: `'$;%&=

assistant: ```c
char *security_sql_injection_escape(char *data) {
  char destination[131072];
  if (!data || !*data)
    return strdup("");
  return strdup(string_escape_character_array(destination, data, "`'$;%&="));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  andw   $0x8fff,-0x4(%rbp)
  sarw   $0x2,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short test7(short a) {
  a &= 0x8fff;
  a >>= 2;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test7>:
  endbr64
  mov    %edi,%eax
  sar    $0x2,%ax
  and    $0xe3,%ah
  ret
```

assistant: ```c
short test7(short a) {
  a &= 0x8fff;
  a >>= 2;
  return a;
}
```