ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<hamming84_enc_symbol>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  and    $0xd,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0xb,%edi
  mov    %eax,%ebx
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x8,%edi
  mov    %eax,0xc(%rsp)
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x7,%edi
  mov    %eax,0x8(%rsp)
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x4,%edi
  mov    %eax,%r14d
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x2,%edi
  mov    %eax,%r13d
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x1,%edi
  mov    %eax,%r12d
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0xe,%edi
  mov    %eax,%ebp
  call   <count_ones@plt>
  mov    %ebx,%edi
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  shr    $0x1f,%edi
  mov    %eax,%esi
  lea    (%rbx,%rdi,1),%eax
  and    $0x1,%eax
  sub    %edi,%eax
  mov    %ecx,%edi
  shr    $0x1f,%edi
  shl    $0x7,%eax
  add    %edi,%ecx
  and    $0x1,%ecx
  sub    %edi,%ecx
  shl    $0x6,%ecx
  or     %ecx,%eax
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%esi
  and    $0x1,%esi
  sub    %ecx,%esi
  mov    %edx,%ecx
  or     %esi,%eax
  shr    $0x1f,%ecx
  add    $0x18,%rsp
  add    %ecx,%edx
  pop    %rbx
  and    $0x1,%edx
  sub    %ecx,%edx
  shl    $0x5,%edx
  or     %edx,%eax
  mov    %r14d,%edx
  shr    $0x1f,%edx
  add    %edx,%r14d
  and    $0x1,%r14d
  sub    %edx,%r14d
  mov    %r13d,%edx
  shr    $0x1f,%edx
  shl    $0x4,%r14d
  add    %edx,%r13d
  or     %r14d,%eax
  and    $0x1,%r13d
  sub    %edx,%r13d
  mov    %r12d,%edx
  shr    $0x1f,%edx
  shl    $0x3,%r13d
  add    %edx,%r12d
  or     %r13d,%eax
  and    $0x1,%r12d
  sub    %edx,%r12d
  mov    %ebp,%edx
  shr    $0x1f,%edx
  shl    $0x2,%r12d
  add    %edx,%ebp
  or     %r12d,%eax
  and    $0x1,%ebp
  sub    %edx,%ebp
  add    %ebp,%ebp
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int hamming84_enc_symbol(unsigned int _p) {
  unsigned int x0 = count_ones(_p & 0x0d) % 2;
  unsigned int x1 = count_ones(_p & 0x0b) % 2;
  unsigned int x2 = count_ones(_p & 0x08) % 2;
  unsigned int x3 = count_ones(_p & 0x07) % 2;
  unsigned int x4 = count_ones(_p & 0x04) % 2;
  unsigned int x5 = count_ones(_p & 0x02) % 2;
  unsigned int x6 = count_ones(_p & 0x01) % 2;
  unsigned int x7 = count_ones(_p & 0x0e) % 2;
  unsigned int x = (x0 << 7) | (x1 << 6) | (x2 << 5) | (x3 << 4) | (x4 << 3) | (x5 << 2) | (x6 << 1) | (x7);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hamming84_enc_symbol>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  and    $0xd,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0xb,%edi
  mov    %eax,%ebx
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x8,%edi
  mov    %eax,0xc(%rsp)
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x7,%edi
  mov    %eax,0x8(%rsp)
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x4,%edi
  mov    %eax,%r14d
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x2,%edi
  mov    %eax,%r13d
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0x1,%edi
  mov    %eax,%r12d
  call   <count_ones@plt>
  mov    %r15d,%edi
  and    $0xe,%edi
  mov    %eax,%ebp
  call   <count_ones@plt>
  mov    %ebx,%edi
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  shr    $0x1f,%edi
  mov    %eax,%esi
  lea    (%rbx,%rdi,1),%eax
  and    $0x1,%eax
  sub    %edi,%eax
  mov    %ecx,%edi
  shr    $0x1f,%edi
  shl    $0x7,%eax
  add    %edi,%ecx
  and    $0x1,%ecx
  sub    %edi,%ecx
  shl    $0x6,%ecx
  or     %ecx,%eax
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%esi
  and    $0x1,%esi
  sub    %ecx,%esi
  mov    %edx,%ecx
  or     %esi,%eax
  shr    $0x1f,%ecx
  add    $0x18,%rsp
  add    %ecx,%edx
  pop    %rbx
  and    $0x1,%edx
  sub    %ecx,%edx
  shl    $0x5,%edx
  or     %edx,%eax
  mov    %r14d,%edx
  shr    $0x1f,%edx
  add    %edx,%r14d
  and    $0x1,%r14d
  sub    %edx,%r14d
  mov    %r13d,%edx
  shr    $0x1f,%edx
  shl    $0x4,%r14d
  add    %edx,%r13d
  or     %r14d,%eax
  and    $0x1,%r13d
  sub    %edx,%r13d
  mov    %r12d,%edx
  shr    $0x1f,%edx
  shl    $0x3,%r13d
  add    %edx,%r12d
  or     %r13d,%eax
  and    $0x1,%r12d
  sub    %edx,%r12d
  mov    %ebp,%edx
  shr    $0x1f,%edx
  shl    $0x2,%r12d
  add    %edx,%ebp
  or     %r12d,%eax
  and    $0x1,%ebp
  sub    %edx,%ebp
  add    %ebp,%ebp
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int hamming84_enc_symbol(unsigned int _p) {
  unsigned int x0 = count_ones(_p & 0x0d) % 2;
  unsigned int x1 = count_ones(_p & 0x0b) % 2;
  unsigned int x2 = count_ones(_p & 0x08) % 2;
  unsigned int x3 = count_ones(_p & 0x07) % 2;
  unsigned int x4 = count_ones(_p & 0x04) % 2;
  unsigned int x5 = count_ones(_p & 0x02) % 2;
  unsigned int x6 = count_ones(_p & 0x01) % 2;
  unsigned int x7 = count_ones(_p & 0x0e) % 2;
  unsigned int x = (x0 << 7) | (x1 << 6) | (x2 << 5) | (x3 << 4) | (x4 << 3) | (x5 << 2) | (x6 << 1) | (x7);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<password>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xf6,-0xc(%rbp)
L12:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L12
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D37
type_guessed: string
name: disassemble_data
arguments: data_tag: D12
type_guessed: string

tool: D39: Para ingresar al sistema, 


tool: D15: por favor ingresa la clave secreta: 

tool: D37: %d

tool: D12: Has accedido..


assistant: ```c
void password() {
  int clave_usuario, clave_secreta = 246;
  do {
    printf("Para ingresar al sistema, \n");
    printf("por favor ingresa la clave secreta: ");
    scanf("%d", &clave_usuario);
  } while (clave_usuario != clave_secreta);
  printf("Has accedido..\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<password>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%r13
  lea    D11(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D26(%rip),%rbx
L17:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0xf6,0x4(%rsp)
  jne    L17
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D20
datatype: string
name: disassemble_data
arguments: label: D11
datatype: string
name: disassemble_data
arguments: label: D26
datatype: string
name: disassemble_data
arguments: label: D18
datatype: string

tool: D20: Para ingresar al sistema, 


tool: D11: por favor ingresa la clave secreta: 

tool: D26: %d

tool: D18: Has accedido..


assistant: ```c
void password() {
  int clave_usuario, clave_secreta = 246;
  do {
    printf("Para ingresar al sistema, \n");
    printf("por favor ingresa la clave secreta: ");
    scanf("%d", &clave_usuario);
  } while (clave_usuario != clave_secreta);
  printf("Has accedido..\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<password>:
  endbr64
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0xf6,0x4(%rsp)
  jne    L18
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D39
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string

tool: D39: Para ingresar al sistema, 


tool: D9: por favor ingresa la clave secreta: 

tool: D7: %d

tool: D3: Has accedido..


assistant: ```c
void password() {
  int clave_usuario, clave_secreta = 246;
  do {
    printf("Para ingresar al sistema, \n");
    printf("por favor ingresa la clave secreta: ");
    scanf("%d", &clave_usuario);
  } while (clave_usuario != clave_secreta);
  printf("Has accedido..\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<password>:
  endbr64
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0xf6,0x4(%rsp)
  jne    L5
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D26: Para ingresar al sistema, 


tool: D15: por favor ingresa la clave secreta: 

tool: D7: %d

tool: D3: Has accedido..


assistant: ```c
void password() {
  int clave_usuario, clave_secreta = 246;
  do {
    printf("Para ingresar al sistema, \n");
    printf("por favor ingresa la clave secreta: ");
    scanf("%d", &clave_usuario);
  } while (clave_usuario != clave_secreta);
  printf("Has accedido..\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LCS>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r15
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x28(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%r13d
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,0x20(%rsp)
  lea    0x1(%rax),%r15d
  mov    %r15d,0xc(%rsp)
  mov    %r15d,%edi
  imul   %r13d,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  imul   %r13d,%r15d
  mov    %r15d,0x24(%rsp)
  test   %r15d,%r15d
  jle    L83
  lea    -0x1(%r15),%edx
  lea    0x4(%rax,%rdx,4),%rdx
L33:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L33
L83:
  cmp    $0x1,%r13d
  jle    L99
  mov    0x20(%rsp),%esi
  mov    0xc(%rsp),%eax
  lea    0x1(%rsi,%rax,1),%r14d
  mov    0x10(%rsp),%rdi
  mov    %edi,%esi
  neg    %esi
  mov    %esi,0x4(%rsp)
  sub    %edi,%eax
  mov    %eax,%r15d
  mov    %rbx,%r13
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rax
  mov    %rax,0x18(%rsp)
  jmp    L109
L6:
  lea    -0x1(%rbp),%eax
  cltq
  mov    (%r12,%rax,4),%edx
  mov    0x8(%rsp),%eax
  add    %ebx,%eax
  cltq
  mov    (%r12,%rax,4),%eax
  cmp    %eax,%edx
  jle    L50
  movslq %ebp,%rax
  mov    %edx,(%r12,%rax,4)
L112:
  add    $0x1,%rbx
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  je     L41
L102:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L6
  lea    0x1(%r15,%rbx,1),%eax
  cltq
  mov    0x4(%rsp),%ecx
  lea    (%rcx,%rbx,1),%edx
  movslq %edx,%rdx
  mov    (%r12,%rdx,4),%edx
  add    $0x1,%edx
  mov    %edx,(%r12,%rax,4)
  jmp    L112
L50:
  movslq %ebp,%rdx
  mov    %eax,(%r12,%rdx,4)
  jmp    L112
L41:
  mov    0xc(%rsp),%eax
  add    %eax,%r14d
  add    %eax,0x4(%rsp)
  add    %eax,%r15d
  add    $0x1,%r13
  cmp    0x18(%rsp),%r13
  je     L99
L109:
  mov    %r14d,%ebp
  sub    0x20(%rsp),%ebp
  mov    0x10(%rsp),%rbx
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x8(%rsp)
  cmpl   $0x1,0xc(%rsp)
  jg     L102
  jmp    L41
L99:
  mov    0x28(%rsp),%rax
  mov    %r12,(%rax)
  movslq 0x24(%rsp),%rax
  mov    -0x4(%r12,%rax,4),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int LCS(char *a, char *b, int **mat) {
  int dim_a = strlen(a) + 1;
  int dim_b = strlen(b) + 1;
  int i, j, *m;
  m = (int *)malloc(sizeof(int) * dim_a * dim_b);
  for (i = 0; i < dim_a * dim_b; i++)
    m[i] = 0;
  for (i = 1; i < dim_a; i++) {
    for (j = 1; j < dim_b; j++) {
      if (strncmp(&a[i - 1], &b[j - 1], 1) == 0)
        m[i * dim_b + j] = m[(i - 1) * dim_b + (j - 1)] + 1;
      else if (m[i * dim_b + (j - 1)] > m[(i - 1) * dim_b + j])
        m[i * dim_b + j] = m[i * dim_b + (j - 1)];
      else
        m[i * dim_b + j] = m[(i - 1) * dim_b + j];
    }
  }
  *mat = m;
  return m[dim_a * dim_b - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LCS>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rdx,0x28(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  lea    0x1(%rax),%r13d
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%rax),%r15d
  mov    %eax,0x20(%rsp)
  mov    %r15d,0x8(%rsp)
  imul   %r13d,%r15d
  lea    0x0(,%r15,4),%edi
  mov    %r15d,0x24(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r15d,%r15d
  jle    L79
  mov    0x24(%rsp),%eax
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x1,%eax
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
L79:
  cmp    $0x1,%r13d
  jle    L40
  mov    0x8(%rsp),%ecx
  mov    %rbp,%r15
  mov    %ecx,%eax
  sub    0x18(%rsp),%eax
  mov    %ecx,0xc(%rsp)
  mov    %eax,0x4(%rsp)
  lea    -0x1(%r12),%eax
  mov    0x20(%rsp),%r12d
  lea    0x1(%rbp,%rax,1),%rax
  mov    %rax,0x10(%rsp)
  nopl   (%rax)
L57:
  cmpl   $0x1,0x8(%rsp)
  jle    L25
  movslq 0xc(%rsp),%rax
  mov    %r12d,%ebp
  mov    0x18(%rsp),%r14
  sub    0x20(%rsp),%ebp
  lea    0x4(%rbx,%rax,4),%r13
  jmp    L56
  nop
L3:
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    (%rbx,%rax,4),%eax
  add    $0x1,%eax
L17:
  mov    %eax,0x0(%r13)
  add    $0x1,%r14
  add    $0x4,%r13
  cmp    %ebp,%r12d
  je     L25
L56:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L3
  mov    0x4(%rsp),%eax
  add    $0x1,%ebp
  movslq %ebp,%rdx
  add    %r14d,%eax
  mov    (%rbx,%rdx,4),%edx
  cltq
  mov    (%rbx,%rax,4),%eax
  cmp    %edx,%eax
  cmovl  %edx,%eax
  jmp    L17
  xchg   %ax,%ax
L25:
  mov    0x8(%rsp),%eax
  add    $0x1,%r15
  add    %eax,0x4(%rsp)
  add    %eax,0xc(%rsp)
  add    %eax,%r12d
  cmp    0x10(%rsp),%r15
  jne    L57
L40:
  mov    0x28(%rsp),%rax
  mov    %rbx,(%rax)
  movslq 0x24(%rsp),%rax
  mov    -0x4(%rbx,%rax,4),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int LCS(char *a, char *b, int **mat) {
  int dim_a = strlen(a) + 1;
  int dim_b = strlen(b) + 1;
  int i, j, *m;
  m = (int *)malloc(sizeof(int) * dim_a * dim_b);
  for (i = 0; i < dim_a * dim_b; i++)
    m[i] = 0;
  for (i = 1; i < dim_a; i++) {
    for (j = 1; j < dim_b; j++) {
      if (strncmp(&a[i - 1], &b[j - 1], 1) == 0)
        m[i * dim_b + j] = m[(i - 1) * dim_b + (j - 1)] + 1;
      else if (m[i * dim_b + (j - 1)] > m[(i - 1) * dim_b + j])
        m[i * dim_b + j] = m[i * dim_b + (j - 1)];
      else
        m[i * dim_b + j] = m[(i - 1) * dim_b + j];
    }
  }
  *mat = m;
  return m[dim_a * dim_b - 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<LCS>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x28(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  lea    0x1(%rax),%r13d
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  mov    %eax,0x20(%rsp)
  mov    %r14d,0xc(%rsp)
  imul   %r13d,%r14d
  lea    0x0(,%r14,4),%edi
  mov    %r14d,0x24(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r14d,%r14d
  jle    L8
  mov    0x24(%rsp),%eax
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x1,%eax
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
L8:
  cmp    $0x1,%r13d
  jle    L32
  mov    0xc(%rsp),%edi
  cmp    $0x1,%edi
  jle    L32
  mov    %edi,%eax
  sub    0x10(%rsp),%eax
  mov    %edi,0x8(%rsp)
  mov    %eax,0x4(%rsp)
  lea    -0x1(%r12),%eax
  mov    0x20(%rsp),%r12d
  lea    0x1(%rbp,%rax,1),%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L65:
  movslq 0x8(%rsp),%rax
  mov    %r12d,%r13d
  mov    0x10(%rsp),%r15
  sub    0x20(%rsp),%r13d
  lea    0x4(%rbx,%rax,4),%r14
  jmp    L41
  nopl   0x0(%rax)
L71:
  movslq %r13d,%rax
  add    $0x1,%r13d
  add    $0x1,%r15
  add    $0x4,%r14
  mov    (%rbx,%rax,4),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%r14)
  cmp    %r13d,%r12d
  je     L0
L41:
  mov    $0x1,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L71
  mov    0x4(%rsp),%ecx
  add    $0x1,%r13d
  movslq %r13d,%rax
  lea    (%rcx,%r15,1),%edx
  mov    (%rbx,%rax,4),%eax
  movslq %edx,%rdx
  mov    (%rbx,%rdx,4),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x1,%r15
  add    $0x4,%r14
  mov    %eax,-0x4(%r14)
  cmp    %r13d,%r12d
  jne    L41
L0:
  mov    0xc(%rsp),%eax
  add    $0x1,%rbp
  add    %eax,0x8(%rsp)
  add    %eax,0x4(%rsp)
  add    %eax,%r12d
  cmp    %rbp,0x18(%rsp)
  jne    L65
L32:
  mov    0x28(%rsp),%rax
  mov    %rbx,(%rax)
  movslq 0x24(%rsp),%rax
  mov    -0x4(%rbx,%rax,4),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int LCS(char *a, char *b, int **mat) {
  int dim_a = strlen(a) + 1;
  int dim_b = strlen(b) + 1;
  int i, j, *m;
  m = (int *)malloc(sizeof(int) * dim_a * dim_b);
  for (i = 0; i < dim_a * dim_b; i++)
    m[i] = 0;
  for (i = 1; i < dim_a; i++) {
    for (j = 1; j < dim_b; j++) {
      if (strncmp(&a[i - 1], &b[j - 1], 1) == 0)
        m[i * dim_b + j] = m[(i - 1) * dim_b + (j - 1)] + 1;
      else if (m[i * dim_b + (j - 1)] > m[(i - 1) * dim_b + j])
        m[i * dim_b + j] = m[i * dim_b + (j - 1)];
      else
        m[i * dim_b + j] = m[(i - 1) * dim_b + j];
    }
  }
  *mat = m;
  return m[dim_a * dim_b - 1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<rpl_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L41
  cmpq   $0x0,-0x20(%rbp)
  jne    L46
L41:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  jmp    L32
L46:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  cmp    %rax,-0x18(%rbp)
  je     L40
  mov    $0x0,%eax
  jmp    L32
L40:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
L32:
  leave
  ret
```

assistant: ```c
void *rpl_calloc(size_t n, size_t s) {
  size_t bytes;
  if (n == 0 || s == 0)
    return calloc(1, 1);
  bytes = n * s;
  if (bytes / s != n)
    return NULL;
  return calloc(n, s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rpl_calloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  test   %rsi,%rsi
  je     L1
  mov    %rdi,%rax
  imul   %rsi,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    $0x0,%edx
  cmp    %rdi,%rax
  jne    L2
  call   <calloc@plt>
  mov    %rax,%rdx
L2:
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
L1:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  jmp    L2
```

assistant: ```c
void *rpl_calloc(size_t n, size_t s) {
  size_t bytes;
  if (n == 0 || s == 0)
    return calloc(1, 1);
  bytes = n * s;
  if (bytes / s != n)
    return NULL;
  return calloc(n, s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rpl_calloc>:
  endbr64
  test   %rdi,%rdi
  je     L20
  test   %rsi,%rsi
  je     L20
  mov    %rdi,%rax
  mul    %rsi
  jo     L2
  jmp    1050 <calloc@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%esi
  mov    $0x1,%edi
  jmp    1050 <calloc@plt>
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *rpl_calloc(size_t n, size_t s) {
  size_t bytes;
  if (n == 0 || s == 0)
    return calloc(1, 1);
  bytes = n * s;
  if (bytes / s != n)
    return NULL;
  return calloc(n, s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rpl_calloc>:
  endbr64
  test   %rdi,%rdi
  je     L18
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%rax
  mul    %rsi
  jo     L10
  jmp    1050 <calloc@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%esi
  mov    $0x1,%edi
  jmp    1050 <calloc@plt>
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *rpl_calloc(size_t n, size_t s) {
  size_t bytes;
  if (n == 0 || s == 0)
    return calloc(1, 1);
  bytes = n * s;
  if (bytes / s != n)
    return NULL;
  return calloc(n, s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<collect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L20
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L27
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x2,-0x8(%rbp)
  jmp    L20
L27:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L40
L50:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x8(%rbp),%rax
L40:
  pop    %rbp
  ret
```

assistant: ```c
char *collect(char *s, char *d) {
  while (*s) {
    if (*s == '\'')
      if (*(s + 1) == '\'') {
        *d++ = *s;
        s += 2;
      } else {
        *d++ = '\0';
        *d++ = '\0';
        *d++ = '\0';
        *d++ = '\0';
        return ++s;
      }
    else
      *d++ = *s++;
  }
  return s;
}
```