ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    D8(%rip),%r13
  cmp    %eax,0x0(%r13)
  je     L23
  mov    $0x51,%edi
  mov    %eax,%ebx
  call   <malloc_or_die@plt>
  mov    %rax,%r14
  cmp    $0xd,%ebx
  je     L76
  cmp    $0xa,%ebx
  je     L76
  mov    $0x50,%r15d
  xor    %ebp,%ebp
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L80:
  mov    %ebp,%eax
  mov    %r12,%rdi
  add    $0x1,%ebp
  mov    %bl,(%r14,%rax,1)
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L69
  cmp    $0xd,%eax
  je     L69
L17:
  cmp    %ebx,0x0(%r13)
  je     L69
  cmp    %r15d,%ebp
  jne    L80
  mov    %r14,%rdi
  lea    0x15(%rbp),%esi
  call   <realloc_or_die@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L23
  lea    0x14(%rbp),%r15d
  jmp    L80
  nopl   0x0(%rax)
L69:
  add    %r14,%rbp
L132:
  movb   $0x0,0x0(%rbp)
  cmp    $0xd,%ebx
  je     L102
L113:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %r14d,%r14d
  jmp    L113
  nopl   (%rax)
L102:
  mov    %r12,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L113
  cmp    %eax,0x0(%r13)
  je     L113
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  jmp    L113
L76:
  mov    %r14,%rbp
  jmp    L132
```

assistant: ```c
char *read_line(FILE *fpin) {
  char *line = NULL;
  unsigned len = 0;
  unsigned max_length;
  int ch;
  ch = getc(fpin);
  if (ch != EOF) {
    line = (char *)malloc_or_die(80 + 1);
    max_length = 80;
    while ((ch != '\n') && (ch != '\r') && (ch != EOF)) {
      if (len == max_length) {
        line = (char *)realloc_or_die((void *)line, max_length + 20 + 1);
        if (line == NULL) {
          return NULL;
        }
        max_length += 20;
      }
      line[len] = ch;
      len++;
      ch = getc(fpin);
    }
    line[len] = '\0';
    if (ch == '\r') {
      ch = getc(fpin);
      if (ch != '\n' && ch != EOF) {
        ungetc(ch, fpin);
      }
    }
  }
  return line;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flex_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void flex_free(ptr) void *ptr;
{
  if (ptr)
    free(ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flex_free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
void flex_free(ptr) void *ptr;
{
  if (ptr)
    free(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<flex_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void flex_free(ptr) void *ptr;
{
  if (ptr)
    free(ptr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<flex_free>:
  endbr64
  test   %rdi,%rdi
  je     L9
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L9:
  ret
```

assistant: ```c
void flex_free(ptr) void *ptr;
{
  if (ptr)
    free(ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L144
L191:
  addq   $0x1,-0x28(%rbp)
L144:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L191
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x2d,-0x11(%rbp)
  je     L12
  cmpb   $0x2b,-0x11(%rbp)
  jne    L25
L12:
  cmpb   $0x2d,-0x11(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  addq   $0x1,-0x28(%rbp)
L25:
  cmpl   $0x0,-0x34(%rbp)
  jne    L106
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L125
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L46
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L125
L46:
  addq   $0x2,-0x28(%rbp)
  movl   $0x10,-0x34(%rbp)
  jmp    L118
L125:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L103
  addq   $0x1,-0x28(%rbp)
  movl   $0x8,-0x34(%rbp)
  jmp    L67
L103:
  movl   $0xa,-0x34(%rbp)
  jmp    L67
L106:
  cmpl   $0x10,-0x34(%rbp)
  jne    L67
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L67
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L22
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L67
L22:
  addq   $0x2,-0x28(%rbp)
L118:
  jmp    L67
L13:
  mov    -0x34(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x28(%rbp)
L67:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <digitval@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L161
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L13
L161:
  cmpq   $0x0,-0x30(%rbp)
  je     L71
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
L71:
  cmpl   $0x0,-0x10(%rbp)
  je     L209
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L14
L209:
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  int minus = 0;
  unsigned long v = 0;
  int d;
  while (isspace((unsigned char)*nptr)) {
    nptr++;
  }
  {
    char c = *nptr;
    if (c == '-' || c == '+') {
      minus = (c == '-');
      nptr++;
    }
  }
  if (base == 0) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
      base = 16;
    } else if (nptr[0] == '0') {
      nptr++;
      base = 8;
    } else {
      base = 10;
    }
  } else if (base == 16) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
    }
  }
  while ((d = digitval(*nptr)) >= 0 && d < base) {
    v = v * base + d;
    nptr++;
  }
  if (endptr)
    *endptr = (char *)nptr;
  return minus ? -v : v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtoul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %edx,%r12d
  jmp    L127
L38:
  add    $0x1,%rbx
L127:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  movzbl (%rbx),%eax
  lea    -0x2b(%rax),%edx
  mov    $0x0,%r15d
  test   $0xfd,%dl
  jne    L116
  cmp    $0x2d,%al
  sete   %r15b
  movzbl %r15b,%r15d
  add    $0x1,%rbx
L116:
  test   %r12d,%r12d
  jne    L145
  mov    $0xa,%r12d
  cmpb   $0x30,(%rbx)
  je     L115
L97:
  mov    $0x0,%ebp
  movslq %r12d,%r13
L135:
  movsbl (%rbx),%edi
  call   <digitval@plt>
  cmp    %r12d,%eax
  jge    L96
  test   %eax,%eax
  js     L96
  imul   %r13,%rbp
  cltq
  add    %rax,%rbp
  add    $0x1,%rbx
  jmp    L135
L115:
  movzbl 0x1(%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L49
  add    $0x2,%rbx
  mov    $0x10,%r12d
  jmp    L97
L49:
  add    $0x1,%rbx
  mov    $0x8,%r12d
  jmp    L97
L145:
  cmp    $0x10,%r12d
  jne    L97
  cmpb   $0x30,(%rbx)
  jne    L97
  movzbl 0x1(%rbx),%eax
  and    $0xffffffdf,%eax
  lea    0x2(%rbx),%rdx
  cmp    $0x58,%al
  cmove  %rdx,%rbx
  jmp    L97
L96:
  test   %r14,%r14
  je     L66
  mov    %rbx,(%r14)
L66:
  mov    %rbp,%rax
  neg    %rax
  test   %r15d,%r15d
  cmovne %rax,%rbp
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  int minus = 0;
  unsigned long v = 0;
  int d;
  while (isspace((unsigned char)*nptr)) {
    nptr++;
  }
  {
    char c = *nptr;
    if (c == '-' || c == '+') {
      minus = (c == '-');
      nptr++;
    }
  }
  if (base == 0) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
      base = 16;
    } else if (nptr[0] == '0') {
      nptr++;
      base = 8;
    } else {
      base = 10;
    }
  } else if (base == 16) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
    }
  }
  while ((d = digitval(*nptr)) >= 0 && d < base) {
    v = v * base + d;
    nptr++;
  }
  if (endptr)
    *endptr = (char *)nptr;
  return minus ? -v : v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strtoul>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax)
L93:
  add    $0x1,%r14
L37:
  movzbl (%r14),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L93
  movsbl (%r14),%edi
  xor    %r13d,%r13d
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L94
  xor    %r13d,%r13d
  cmp    $0x2d,%dil
  movsbl 0x1(%r14),%edi
  sete   %r13b
  add    $0x1,%r14
L94:
  test   %ebx,%ebx
  jne    L16
  mov    $0xa,%ebx
  cmp    $0x30,%dil
  je     L96
L92:
  xor    %r15d,%r15d
  movslq %ebx,%rbp
  jmp    L149
  nop
L115:
  test   %eax,%eax
  js     L91
  imul   %rbp,%r15
  cltq
  movsbl 0x1(%r14),%edi
  add    $0x1,%r14
  add    %rax,%r15
L149:
  call   <digitval@plt>
  cmp    %ebx,%eax
  jl     L115
L91:
  test   %r12,%r12
  je     L22
  mov    %r14,(%r12)
L22:
  mov    %r15,%rax
  neg    %rax
  test   %r13d,%r13d
  cmovne %rax,%r15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r15,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    $0x10,%ebx
  jne    L92
  cmp    $0x30,%dil
  jne    L92
  movzbl 0x1(%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L92
  movsbl 0x2(%r14),%edi
  add    $0x2,%r14
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L96:
  movsbl 0x1(%r14),%edi
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L126
  movsbl 0x2(%r14),%edi
  mov    $0x10,%ebx
  add    $0x2,%r14
  jmp    L92
L126:
  add    $0x1,%r14
  mov    $0x8,%ebx
  jmp    L92
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  int minus = 0;
  unsigned long v = 0;
  int d;
  while (isspace((unsigned char)*nptr)) {
    nptr++;
  }
  {
    char c = *nptr;
    if (c == '-' || c == '+') {
      minus = (c == '-');
      nptr++;
    }
  }
  if (base == 0) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
      base = 16;
    } else if (nptr[0] == '0') {
      nptr++;
      base = 8;
    } else {
      base = 10;
    }
  } else if (base == 16) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
    }
  }
  while ((d = digitval(*nptr)) >= 0 && d < base) {
    v = v * base + d;
    nptr++;
  }
  if (endptr)
    *endptr = (char *)nptr;
  return minus ? -v : v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtoul>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L124
  nopl   0x0(%rax)
L108:
  add    $0x1,%r14
L124:
  movzbl (%r14),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L108
  movzbl (%r14),%eax
  xor    %r13d,%r13d
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  jne    L58
  xor    %r13d,%r13d
  cmp    $0x2d,%al
  movzbl 0x1(%r14),%eax
  sete   %r13b
  add    $0x1,%r14
L58:
  test   %ebx,%ebx
  jne    L47
  mov    $0xa,%ebx
  cmp    $0x30,%al
  je     L88
L6:
  xor    %r15d,%r15d
  movslq %ebx,%rbp
  jmp    L96
  nopl   0x0(%rax,%rax,1)
L11:
  test   %eax,%eax
  js     L45
  imul   %rbp,%r15
  cltq
  add    $0x1,%r14
  add    %rax,%r15
L96:
  movsbl (%r14),%edi
  call   <digitval@plt>
  cmp    %ebx,%eax
  jl     L11
L45:
  test   %r12,%r12
  je     L4
  mov    %r14,(%r12)
L4:
  mov    %r15,%rax
  neg    %rax
  test   %r13d,%r13d
  cmovne %rax,%r15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r15,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L47:
  cmp    $0x10,%ebx
  jne    L6
  cmp    $0x30,%al
  jne    L6
  movzbl 0x1(%r14),%eax
  lea    0x2(%r14),%rdx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  cmove  %rdx,%r14
  jmp    L6
  nopl   (%rax)
L88:
  movzbl 0x1(%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L0
  add    $0x2,%r14
  mov    $0x10,%ebx
  jmp    L6
L0:
  add    $0x1,%r14
  mov    $0x8,%ebx
  jmp    L6
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  int minus = 0;
  unsigned long v = 0;
  int d;
  while (isspace((unsigned char)*nptr)) {
    nptr++;
  }
  {
    char c = *nptr;
    if (c == '-' || c == '+') {
      minus = (c == '-');
      nptr++;
    }
  }
  if (base == 0) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
      base = 16;
    } else if (nptr[0] == '0') {
      nptr++;
      base = 8;
    } else {
      base = 10;
    }
  } else if (base == 16) {
    if (nptr[0] == '0' && (nptr[1] == 'x' || nptr[1] == 'X')) {
      nptr += 2;
    }
  }
  while ((d = digitval(*nptr)) >= 0 && d < base) {
    v = v * base + d;
    nptr++;
  }
  if (endptr)
    *endptr = (char *)nptr;
  return minus ? -v : v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D4: 
Usage: %s [-r] [-c] [-h] [-v]

Launch an alarm on your computer to wake up early on the morning.

optional arguments:
	   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time
	   -r   --robot       don't launch the challenge, don't stop the current alarm
	   -h   --help        print this help
	   -v   --version     get version and compile option



assistant: ```c
void usage(const char *prg_name) {
  printf("\nUsage: %s [-r] [-c] [-h] [-v]"
         "\n\n"
         "Launch an alarm on your computer to wake up early on the morning.\n\n"
         "optional arguments:\n"
         "\t   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time\n"
         "\t   -r   --robot       don't launch the challenge, don't stop the current alarm\n"
         "\t   -h   --help        print this help\n"
         "\t   -v   --version     get version and compile option\n"
         "\n",
         prg_name);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: 
Usage: %s [-r] [-c] [-h] [-v]

Launch an alarm on your computer to wake up early on the morning.

optional arguments:
	   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time
	   -r   --robot       don't launch the challenge, don't stop the current alarm
	   -h   --help        print this help
	   -v   --version     get version and compile option



assistant: ```c
void usage(const char *prg_name) {
  printf("\nUsage: %s [-r] [-c] [-h] [-v]"
         "\n\n"
         "Launch an alarm on your computer to wake up early on the morning.\n\n"
         "optional arguments:\n"
         "\t   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time\n"
         "\t   -r   --robot       don't launch the challenge, don't stop the current alarm\n"
         "\t   -h   --help        print this help\n"
         "\t   -v   --version     get version and compile option\n"
         "\n",
         prg_name);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: 
Usage: %s [-r] [-c] [-h] [-v]

Launch an alarm on your computer to wake up early on the morning.

optional arguments:
	   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time
	   -r   --robot       don't launch the challenge, don't stop the current alarm
	   -h   --help        print this help
	   -v   --version     get version and compile option



assistant: ```c
void usage(const char *prg_name) {
  printf("\nUsage: %s [-r] [-c] [-h] [-v]"
         "\n\n"
         "Launch an alarm on your computer to wake up early on the morning.\n\n"
         "optional arguments:\n"
         "\t   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time\n"
         "\t   -r   --robot       don't launch the challenge, don't stop the current alarm\n"
         "\t   -h   --help        print this help\n"
         "\t   -v   --version     get version and compile option\n"
         "\n",
         prg_name);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: 
Usage: %s [-r] [-c] [-h] [-v]

Launch an alarm on your computer to wake up early on the morning.

optional arguments:
	   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time
	   -r   --robot       don't launch the challenge, don't stop the current alarm
	   -h   --help        print this help
	   -v   --version     get version and compile option



assistant: ```c
void usage(const char *prg_name) {
  printf("\nUsage: %s [-r] [-c] [-h] [-v]"
         "\n\n"
         "Launch an alarm on your computer to wake up early on the morning.\n\n"
         "optional arguments:\n"
         "\t   -c   --challenge   switch challenge off. Only with god mod enabled ad compile time\n"
         "\t   -r   --robot       don't launch the challenge, don't stop the current alarm\n"
         "\t   -h   --help        print this help\n"
         "\t   -v   --version     get version and compile option\n"
         "\n",
         prg_name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_board>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x20,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L64:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl 0x6(%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x6,-0x8(%rbp)
  jle    L64
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x5,-0x4(%rbp)
  jmp    L19
L40:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L46:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x6,-0x8(%rbp)
  jle    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jns    L40
  mov    $0x20,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L18:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L15:
  cmpl   $0x6,-0x8(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D40
data_type: string
name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D27:  %d

tool: D40: %d 

tool: D24: %c 

tool: D2: ----------------

assistant: ```c
void print_board(char b[7][6 + 1]) {
  int i, j;
  putchar(' ');
  for (i = 0; i < 7; i++)
    printf(" %d", b[i][6]);
  putchar('\n');
  for (j = 6 - 1; j >= 0; j--) {
    printf("%d ", j);
    for (i = 0; i < 7; i++)
      printf("%c ", b[i][j]);
    putchar('\n');
  }
  putchar(' ');
  for (i = 0; i < 7; i++)
    printf(" %d", i);
  putchar('\n');
  printf("----------------\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_board>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x20,%edi
  call   <putchar@plt>
  lea    0x6(%rbp),%rbx
  lea    0x37(%rbp),%r13
  lea    D5(%rip),%r12
L23:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x7,%rbx
  cmp    %r13,%rbx
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x36,%rbp
  mov    $0x5,%r13d
  lea    D37(%rip),%r14
  lea    D1(%rip),%r12
L11:
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x31(%rbp),%rbx
L25:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x7,%rbx
  cmp    %rbp,%rbx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  sub    $0x1,%rbp
  cmp    $0xffffffff,%r13d
  jne    L11
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x7,%ebx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D23
type: string

tool: D5:  %d

tool: D37: %d 

tool: D1: %c 

tool: D23: ----------------

assistant: ```c
void print_board(char b[7][6 + 1]) {
  int i, j;
  putchar(' ');
  for (i = 0; i < 7; i++)
    printf(" %d", b[i][6]);
  putchar('\n');
  for (j = 6 - 1; j >= 0; j--) {
    printf("%d ", j);
    for (i = 0; i < 7; i++)
      printf("%c ", b[i][j]);
    putchar('\n');
  }
  putchar(' ');
  for (i = 0; i < 7; i++)
    printf(" %d", i);
  putchar('\n');
  printf("----------------\n");
}
```