user: 请从给定的汇编指令推导出C源代码:

```asm
<DIVIDER_32b_AUTOTEST>:
  endbr64
  push   %r15
  lea    D66(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <puts@plt>
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  lea    (%rax,%rdx,1),%ebp
  xor    %eax,%eax
  movzwl %bp,%ebp
  sub    %edx,%ebp
  call   <rand@plt>
  mov    %ebp,%edi
  cltd
  shr    $0x10,%edx
  lea    (%rax,%rdx,1),%r12d
  movzwl %r12w,%r12d
  sub    %edx,%r12d
  mov    %r12d,%esi
  call   <instr_fudiv@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r15d
  call   <instr_fudiv@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <instr_mod@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <instr_mod@plt>
  mov    %eax,%r8d
  cmp    %r14d,%r15d
  jne    L19
  cmp    %eax,%ebx
  jne    L19
  add    $0x1,%r13d
  cmp    $0xa,%r13d
  jne    L7
  lea    D46(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  lea    D4(%rip),%rdi
  mov    %r8d,0xc(%rsp)
  call   <puts@plt>
  mov    %r13d,%esi
  lea    D73(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D66
type_infered: string
name: retrieve_data
arguments: label: D46
type_infered: string
name: retrieve_data
arguments: label: D4
type_infered: string
name: retrieve_data
arguments: label: D73
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D76
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string

tool: D66: LAUNCHING THE (uDIV/MOD) RESOURCE TEST...

tool: D46: - TEST OF THE DIVIDER_32b RESOURCE => OK

tool: D4: - TEST OF THE DIVIDER_32b RESOURCE => FAILED !

tool: D73:   + %d COMPUTATION BEFORE ERROR... !


tool: D8:   + INSTRUCTION RESULT (%d udiv %d) => %d


tool: D29:   + C CODE RESULT      (%d udiv %d) => %d


tool: D76:   + INSTRUCTION RESULT (%d umod %d) => %d


tool: D21:   + C CODE RESULT      (%d umod %d) => %d


assistant: ```c
int DIVIDER_32b_AUTOTEST() {
  printf("LAUNCHING THE (uDIV/MOD) RESOURCE TEST...\n");
  int isOk1 = 1;
  int i, j;
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 65536;
    int op2 = rand() % 65536;
    int res1 = instr_fudiv(op1, op2);
    int res2 = instr_fudiv(op1, op2);
    int res3 = instr_mod(op1, op2);
    int res4 = instr_mod(op1, op2);
    if ((res1 != res2) || (res3 != res4)) {
      printf("- TEST OF THE DIVIDER_32b RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d udiv %d) => %d\n", op1, op2, res1);
      printf("  + C CODE RESULT      (%d udiv %d) => %d\n", op1, op2, res2);
      printf("  + INSTRUCTION RESULT (%d umod %d) => %d\n", op1, op2, res3);
      printf("  + C CODE RESULT      (%d umod %d) => %d\n", op1, op2, res4);
      return 0;
    }
  }
  printf("- TEST OF THE DIVIDER_32b RESOURCE => OK\n");
  return 1;
}
```