ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  mov    %esi,%r8d
  sub    $0x2,%esi
  shr    %esi
  lea    0x1(%rsi),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L21:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L21
  neg    %esi
  lea    -0x2(%r8,%rsi,2),%esi
L23:
  test   %esi,%esi
  je     L3
  movzbl (%rcx),%edx
  add    %rdx,%rax
L3:
  mov    %rax,%rdx
  shr    $0x10,%rdx
  movzwl %ax,%eax
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L8:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L23
```

assistant: ```c
unsigned short checksum(unsigned short *buffer, int size) {
  unsigned long cksum = 0;
  while (size > 1) {
    cksum += *buffer++;
    size -= sizeof(unsigned short);
  }
  if (size)
    cksum += *(unsigned char *)buffer;
  cksum = (cksum >> 16) + (cksum & 0xffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L29
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L31:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L31
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L1:
  test   %esi,%esi
  je     L20
  movzbl (%rcx),%edx
  add    %rdx,%rax
L20:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
unsigned short checksum(unsigned short *buffer, int size) {
  unsigned long cksum = 0;
  while (size > 1) {
    cksum += *buffer++;
    size -= sizeof(unsigned short);
  }
  if (size)
    cksum += *(unsigned char *)buffer;
  cksum = (cksum >> 16) + (cksum & 0xffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checksum>:
  endbr64
  mov    %esi,%edx
  cmp    $0x1,%esi
  jle    L84
  lea    -0x2(%rsi),%esi
  mov    %esi,%r9d
  mov    %esi,%r10d
  shr    %r9d
  lea    0x1(%r9),%r8d
  cmp    $0xd,%esi
  jbe    L43
  mov    %r8d,%ecx
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  shr    $0x3,%ecx
  pxor   %xmm2,%xmm2
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax)
L112:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  punpckhwd %xmm4,%xmm0
  punpcklwd %xmm4,%xmm1
  movdqa %xmm1,%xmm5
  punpckhdq %xmm2,%xmm1
  punpckldq %xmm2,%xmm5
  paddq  %xmm5,%xmm1
  movdqa %xmm0,%xmm5
  punpckhdq %xmm2,%xmm0
  punpckldq %xmm2,%xmm5
  paddq  %xmm5,%xmm0
  paddq  %xmm0,%xmm1
  paddq  %xmm1,%xmm3
  cmp    %rcx,%rax
  jne    L112
  mov    %r8d,%esi
  movdqa %xmm3,%xmm0
  and    $0xfffffff8,%esi
  psrldq $0x8,%xmm0
  mov    %esi,%r11d
  paddq  %xmm0,%xmm3
  mov    %esi,%ecx
  neg    %r11d
  movq   %xmm3,%rax
  lea    (%rdi,%rcx,2),%rcx
  lea    (%rdx,%r11,2),%edx
  cmp    %esi,%r8d
  je     L99
  lea    -0x2(%rdx),%esi
L80:
  movzwl (%rcx),%r11d
  add    %r11,%rax
  cmp    $0x1,%esi
  jbe    L99
  movzwl 0x2(%rcx),%esi
  add    %rsi,%rax
  lea    -0x4(%rdx),%esi
  cmp    $0x1,%esi
  jbe    L99
  movzwl 0x4(%rcx),%esi
  add    %rsi,%rax
  lea    -0x6(%rdx),%esi
  cmp    $0x1,%esi
  jbe    L99
  movzwl 0x6(%rcx),%esi
  add    %rsi,%rax
  lea    -0x8(%rdx),%esi
  cmp    $0x1,%esi
  jbe    L99
  movzwl 0x8(%rcx),%esi
  add    %rsi,%rax
  lea    -0xa(%rdx),%esi
  cmp    $0x1,%esi
  jbe    L99
  movzwl 0xa(%rcx),%esi
  sub    $0xc,%edx
  add    %rsi,%rax
  cmp    $0x1,%edx
  jbe    L99
  movzwl 0xc(%rcx),%edx
  add    %rdx,%rax
L99:
  mov    %r9d,%edx
  lea    (%rdi,%r8,2),%rdi
  neg    %edx
  lea    (%r10,%rdx,2),%edx
L124:
  test   %edx,%edx
  je     L51
  movzbl (%rdi),%edx
  add    %rdx,%rax
L51:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L84:
  xor    %eax,%eax
  jmp    L124
L43:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L80
```

assistant: ```c
unsigned short checksum(unsigned short *buffer, int size) {
  unsigned long cksum = 0;
  while (size > 1) {
    cksum += *buffer++;
    size -= sizeof(unsigned short);
  }
  if (size)
    cksum += *(unsigned char *)buffer;
  cksum = (cksum >> 16) + (cksum & 0xffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L46
L42:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L6
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L32
L41:
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dx,(%rax)
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L26
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x40(%rbp),%rdi
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <fill_array>
  mov    %rax,-0x28(%rbp)
L26:
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L41
L6:
  addl   $0x2,-0x10(%rbp)
L46:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L42
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
short *fill_array(short *list, int access_inx, int loop_dim, int ranges[], int limits[]) {
  int i, j;
  int istart, istop;
  int inx;
  inx = access_inx * 2;
  for (j = 1; j <= ranges[0]; j += 2) {
    istart = (((ranges[j]) > (limits[inx])) ? (ranges[j]) : (limits[inx]));
    istop = (((ranges[j + 1]) < (limits[inx + 1])) ? (ranges[j + 1]) : (limits[inx + 1]));
    if (istart <= istop) {
      for (i = istart; i <= istop; i++) {
        *list++ = access_inx;
        *list++ = i + 1;
        if (access_inx < loop_dim)
          list = fill_array(list, access_inx + 1, loop_dim, ranges + ranges[0] + 1, limits);
      }
    }
  }
  return list;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %rcx,%r13
  mov    %r8,0x10(%rsp)
  mov    %rdi,%rax
  cmpl   $0x0,(%rcx)
  jle    L23
  lea    (%rsi,%rsi,1),%edx
  movslq %edx,%rax
  lea    (%r8,%rax,4),%r15
  lea    0x4(%r8,%rax,4),%r14
  mov    %rdi,%rax
  mov    $0x1,%r12d
  lea    0x1(%rsi),%edi
  mov    %edi,0x1c(%rsp)
L29:
  mov    (%r15),%ebx
  mov    0x0(%r13,%r12,4),%edx
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  mov    (%r14),%ebp
  mov    0x4(%r13,%r12,4),%edx
  cmp    %edx,%ebp
  cmovg  %edx,%ebp
  cmp    %ebp,%ebx
  jle    L14
L10:
  add    $0x2,%r12
  cmp    %r12d,0x0(%r13)
  jge    L29
L23:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L10
L14:
  mov    0x18(%rsp),%esi
  mov    %si,(%rax)
  lea    0x4(%rax),%rdi
  lea    0x1(%rbx),%edx
  mov    %dx,0x2(%rax)
  mov    %rdi,%rax
  mov    0xc(%rsp),%ecx
  cmp    %ecx,%esi
  jge    L7
  movslq 0x0(%r13),%rax
  lea    0x4(%r13,%rax,4),%rcx
  mov    0x10(%rsp),%r8
  mov    0xc(%rsp),%edx
  mov    0x1c(%rsp),%esi
  call   <fill_array>
  jmp    L7
```

assistant: ```c
short *fill_array(short *list, int access_inx, int loop_dim, int ranges[], int limits[]) {
  int i, j;
  int istart, istop;
  int inx;
  inx = access_inx * 2;
  for (j = 1; j <= ranges[0]; j += 2) {
    istart = (((ranges[j]) > (limits[inx])) ? (ranges[j]) : (limits[inx]));
    istop = (((ranges[j + 1]) < (limits[inx + 1])) ? (ranges[j + 1]) : (limits[inx + 1]));
    if (istart <= istop) {
      for (i = istart; i <= istop; i++) {
        *list++ = access_inx;
        *list++ = i + 1;
        if (access_inx < loop_dim)
          list = fill_array(list, access_inx + 1, loop_dim, ranges + ranges[0] + 1, limits);
      }
    }
  }
  return list;
}
```
user: What is the c source code of the assembly code below?

```asm
<fill_array>:
  endbr64
  mov    (%rcx),%r10d
  mov    %rdi,%rax
  test   %r10d,%r10d
  jle    L0
  push   %r15
  mov    %esi,%r9d
  add    %esi,%esi
  push   %r14
  movslq %esi,%rsi
  mov    %r9d,%r11d
  push   %r13
  mov    %rcx,%r13
  movslq %r10d,%rcx
  push   %r12
  lea    0x4(%r13,%rcx,4),%rcx
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    (%r8,%rsi,4),%r15d
  mov    0x4(%r8,%rsi,4),%r14d
  lea    0x1(%r9),%esi
L59:
  mov    0x0(%r13,%r12,4),%ebx
  mov    0x4(%r13,%r12,4),%ebp
  cmp    %ebx,%r15d
  cmovge %r15d,%ebx
  cmp    %ebp,%r14d
  cmovle %r14d,%ebp
  cmp    %ebp,%ebx
  jle    L14
L62:
  add    $0x2,%r12
  cmp    %r12d,%r10d
  jge    L59
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L14:
  mov    %r12,0x10(%rsp)
  mov    %rax,%rdi
  mov    %edx,%r12d
  mov    %r10d,0x1c(%rsp)
  mov    %rcx,%r10
  mov    %r15d,0x20(%rsp)
  mov    %r9d,%r15d
  mov    %r14d,0x24(%rsp)
  mov    %esi,%r14d
  mov    %r13,0x28(%rsp)
  mov    %r11d,%r13d
L52:
  lea    0x1(%rbx),%edx
  mov    %r13w,(%rdi)
  add    $0x4,%rdi
  mov    %dx,-0x2(%rdi)
  cmp    %r12d,%r15d
  jl     L39
L18:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L52
  mov    %r10,%rcx
  mov    %r15d,%r9d
  mov    %r12d,%edx
  mov    %r13d,%r11d
  mov    %r14d,%esi
  mov    0x1c(%rsp),%r10d
  mov    0x20(%rsp),%r15d
  mov    %rdi,%rax
  mov    0x10(%rsp),%r12
  mov    0x28(%rsp),%r13
  mov    0x24(%rsp),%r14d
  jmp    L62
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    %r10,%rcx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r8,0x8(%rsp)
  mov    %r10,(%rsp)
  call   <fill_array>
  mov    0x8(%rsp),%r8
  mov    (%rsp),%r10
  mov    %rax,%rdi
  jmp    L18
  nopl   (%rax)
L0:
  ret
```

assistant: ```c
short *fill_array(short *list, int access_inx, int loop_dim, int ranges[], int limits[]) {
  int i, j;
  int istart, istop;
  int inx;
  inx = access_inx * 2;
  for (j = 1; j <= ranges[0]; j += 2) {
    istart = (((ranges[j]) > (limits[inx])) ? (ranges[j]) : (limits[inx]));
    istop = (((ranges[j + 1]) < (limits[inx + 1])) ? (ranges[j + 1]) : (limits[inx + 1]));
    if (istart <= istop) {
      for (i = istart; i <= istop; i++) {
        *list++ = access_inx;
        *list++ = i + 1;
        if (access_inx < loop_dim)
          list = fill_array(list, access_inx + 1, loop_dim, ranges + ranges[0] + 1, limits);
      }
    }
  }
  return list;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<argStartsWith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L57
  cmpq   $0x0,-0x28(%rbp)
  je     L57
  movl   $0x1,-0xc(%rbp)
  jmp    L21
L62:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L69
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jg     L69
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <startsWith@plt>
  test   %rax,%rax
  je     L69
  mov    -0xc(%rbp),%eax
  jmp    L35
L69:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L62
L57:
  mov    $0xffffffff,%eax
L35:
  leave
  ret
```

assistant: ```c
int argStartsWith(int argc, char **argv, char *argstring, int minlen) {
  int i;
  if (argv && argstring)
    for (i = 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && (strlen(arg) >= minlen) && startsWith(arg, argstring)) {
        return i;
      }
    }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<argStartsWith>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rsi,%rsi
  je     L54
  mov    %rsi,%r13
  mov    %ecx,%r15d
  test   %rdx,%rdx
  je     L54
  cmp    $0x1,%edi
  jle    L60
  mov    %edi,%r12d
  mov    $0x1,%ebx
  jmp    L16
L100:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L17
L16:
  mov    %ebx,%r14d
  mov    0x0(%r13,%rbx,8),%rbp
  test   %rbp,%rbp
  je     L100
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jl     L100
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <startsWith@plt>
  test   %rax,%rax
  je     L100
  jmp    L78
L17:
  mov    $0xffffffff,%r14d
L78:
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  mov    $0xffffffff,%r14d
  jmp    L78
L60:
  mov    $0xffffffff,%r14d
  jmp    L78
```

assistant: ```c
int argStartsWith(int argc, char **argv, char *argstring, int minlen) {
  int i;
  if (argv && argstring)
    for (i = 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && (strlen(arg) >= minlen) && startsWith(arg, argstring)) {
        return i;
      }
    }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<argStartsWith>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rsi,%rsi
  je     L57
  test   %rdx,%rdx
  je     L57
  cmp    $0x1,%edi
  jle    L57
  mov    %rsi,%r12
  mov    %ecx,%r14d
  movslq %edi,%rbp
  mov    $0x1,%ebx
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L46:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L57
L12:
  mov    (%r12,%rbx,8),%r15
  mov    %ebx,%r13d
  test   %r15,%r15
  je     L46
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jl     L46
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdi
  call   <startsWith@plt>
  test   %rax,%rax
  je     L46
L23:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    $0xffffffff,%r13d
  jmp    L23
```

assistant: ```c
int argStartsWith(int argc, char **argv, char *argstring, int minlen) {
  int i;
  if (argv && argstring)
    for (i = 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && (strlen(arg) >= minlen) && startsWith(arg, argstring)) {
        return i;
      }
    }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<argStartsWith>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rsi,%rsi
  je     L54
  test   %rdx,%rdx
  je     L54
  cmp    $0x1,%edi
  jle    L54
  mov    %rsi,%r12
  mov    %ecx,%r14d
  movslq %edi,%rbp
  mov    $0x1,%ebx
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L54
L32:
  mov    (%r12,%rbx,8),%r15
  mov    %ebx,%r13d
  test   %r15,%r15
  je     L8
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jl     L8
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdi
  call   <startsWith@plt>
  test   %rax,%rax
  je     L8
L71:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    $0xffffffff,%r13d
  jmp    L71
```

assistant: ```c
int argStartsWith(int argc, char **argv, char *argstring, int minlen) {
  int i;
  if (argv && argstring)
    for (i = 1; i < argc; i++) {
      char *arg = argv[i];
      if (arg && (strlen(arg) >= minlen) && startsWith(arg, argstring)) {
        return i;
      }
    }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <factorise@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string

tool: D27: Enter the number to print and find its distinct prime factors: 

tool: D22: %d

tool: D16: Total number of distinct prime factors of %d is %d

assistant: ```c
int main() {
  int num;
  printf("Enter the number to print and find its distinct prime factors: ");
  scanf("%d", &num);
  printf("Total number of distinct prime factors of %d is %d", num, factorise(num));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <factorise@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D16: Enter the number to print and find its distinct prime factors: 

tool: D9: %d

tool: D5: Total number of distinct prime factors of %d is %d

assistant: ```c
int main() {
  int num;
  printf("Enter the number to print and find its distinct prime factors: ");
  scanf("%d", &num);
  printf("Total number of distinct prime factors of %d is %d", num, factorise(num));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <factorise@plt>
  mov    0x4(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: string

tool: D21: Enter the number to print and find its distinct prime factors: 

tool: D8: %d

tool: D22: Total number of distinct prime factors of %d is %d

assistant: ```c
int main() {
  int num;
  printf("Enter the number to print and find its distinct prime factors: ");
  scanf("%d", &num);
  printf("Total number of distinct prime factors of %d is %d", num, factorise(num));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <factorise@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D6: Enter the number to print and find its distinct prime factors: 

tool: D27: %d

tool: D1: Total number of distinct prime factors of %d is %d

assistant: ```c
int main() {
  int num;
  printf("Enter the number to print and find its distinct prime factors: ");
  scanf("%d", &num);
  printf("Total number of distinct prime factors of %d is %d", num, factorise(num));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x80000000,-0x4(%rbp)
  jne    L23
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  mov    $0x32,%edi
  call   <ft_putchar@plt>
  mov    $0x31,%edi
  call   <ft_putchar@plt>
  mov    $0x34,%edi
  call   <ft_putchar@plt>
  mov    $0x37,%edi
  call   <ft_putchar@plt>
  mov    $0x34,%edi
  call   <ft_putchar@plt>
  mov    $0x38,%edi
  call   <ft_putchar@plt>
  mov    $0x33,%edi
  call   <ft_putchar@plt>
  mov    $0x36,%edi
  call   <ft_putchar@plt>
  mov    $0x34,%edi
  call   <ft_putchar@plt>
  mov    $0x38,%edi
  call   <ft_putchar@plt>
  jmp    L4
L23:
  cmpl   $0x0,-0x4(%rbp)
  jns    L22
  negl   -0x4(%rbp)
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
L22:
  cmpl   $0x9,-0x4(%rbp)
  jle    L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <ft_putnbr>
L33:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L4:
  leave
  ret
```

assistant: ```c
void ft_putnbr(int i) {
  if (i == -2147483648) {
    ft_putchar('-');
    ft_putchar('2');
    ft_putchar('1');
    ft_putchar('4');
    ft_putchar('7');
    ft_putchar('4');
    ft_putchar('8');
    ft_putchar('3');
    ft_putchar('6');
    ft_putchar('4');
    ft_putchar('8');
    return;
  }
  if (i < 0) {
    i = -i;
    ft_putchar('-');
  }
  if (i >= 10)
    ft_putnbr(i / 10);
  ft_putchar(i % 10 + '0');
}
```