ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<predec_arg_idx>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
  prefetchnta (%rdi,%rsi,4)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int predec_arg_idx(int *p, int i) {
  int j = i - 1;
  __builtin_prefetch(&p[--i], 0, 0);
  return i == j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<predec_arg_idx>:
  endbr64
  sub    $0x1,%esi
  mov    $0x1,%eax
  movslq %esi,%rsi
  prefetchnta (%rdi,%rsi,4)
  ret
```

assistant: ```c
int predec_arg_idx(int *p, int i) {
  int j = i - 1;
  __builtin_prefetch(&p[--i], 0, 0);
  return i == j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_perfect_cube>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <cbrt@plt>
  mov    %eax,%edi
  call   <round@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  imul   -0x4(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int is_perfect_cube(int n) {
  int root = round(cbrt(n));
  return n == root * root * root;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_perfect_cube>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <cbrt@plt>
  mov    %eax,%edi
  call   <round@plt>
  mov    %eax,%edx
  imul   %eax,%eax
  imul   %edx,%eax
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_perfect_cube(int n) {
  int root = round(cbrt(n));
  return n == root * root * root;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_perfect_cube>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <cbrt@plt>
  mov    %eax,%edi
  call   <round@plt>
  mov    %eax,%r8d
  imul   %eax,%eax
  imul   %r8d,%eax
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_perfect_cube(int n) {
  int root = round(cbrt(n));
  return n == root * root * root;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_perfect_cube>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <cbrt@plt>
  mov    %eax,%edi
  call   <round@plt>
  mov    %eax,%r8d
  imul   %eax,%eax
  imul   %r8d,%eax
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_perfect_cube(int n) {
  int root = round(cbrt(n));
  return n == root * root * root;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4018(%rbp)
  jmp    L28
L24:
  mov    -0x4018(%rbp),%eax
  cltq
  mov    -0x4010(%rbp,%rax,4),%eax
  mov    %eax,-0x4014(%rbp)
  mov    -0x4018(%rbp),%eax
  cltq
  mov    -0x4014(%rbp),%edx
  mov    %edx,-0x2010(%rbp,%rax,4)
  addl   $0x1,-0x4018(%rbp)
L28:
  cmpl   $0x7ff,-0x4018(%rbp)
  jle    L24
  mov    -0x3010(%rbp),%edx
  mov    -0x1010(%rbp),%eax
  cmp    %eax,%edx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(void) {
  int A[2048];
  int B[2048];
  int i;
  int tmp;
  for (i = 0; i < 2048; i++) {
    tmp = A[i];
    B[i] = tmp;
  }
  __VERIFIER_assert(A[2048 / 2] != B[2048 / 2]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  lea    -0x4000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
L28:
  mov    (%rsp,%rax,1),%edx
  mov    %edx,0x2000(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x2000,%rax
  jne    L28
  mov    0x3000(%rsp),%eax
  cmp    %eax,0x1000(%rsp)
  setne  %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assert@plt>
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x4018,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int A[2048];
  int B[2048];
  int i;
  int tmp;
  for (i = 0; i < 2048; i++) {
    tmp = A[i];
    B[i] = tmp;
  }
  __VERIFIER_assert(A[2048 / 2] != B[2048 / 2]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int A[2048];
  int B[2048];
  int i;
  int tmp;
  for (i = 0; i < 2048; i++) {
    tmp = A[i];
    B[i] = tmp;
  }
  __VERIFIER_assert(A[2048 / 2] != B[2048 / 2]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int A[2048];
  int B[2048];
  int i;
  int tmp;
  for (i = 0; i < 2048; i++) {
    tmp = A[i];
    B[i] = tmp;
  }
  __VERIFIER_assert(A[2048 / 2] != B[2048 / 2]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<translate_mtu_discover_type_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x10,%edi
  call   <x_msg@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: --mtu-disc is not supported on this OS

assistant: ```c
int translate_mtu_discover_type_name(const char *name) {
  x_msg((1 << 4), "--mtu-disc is not supported on this OS");
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<translate_mtu_discover_type_name>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  mov    $0x10,%edi
  call   <x_msg@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string

tool: D5: --mtu-disc is not supported on this OS

assistant: ```c
int translate_mtu_discover_type_name(const char *name) {
  x_msg((1 << 4), "--mtu-disc is not supported on this OS");
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<translate_mtu_discover_type_name>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  mov    $0x10,%edi
  call   <x_msg@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: --mtu-disc is not supported on this OS

assistant: ```c
int translate_mtu_discover_type_name(const char *name) {
  x_msg((1 << 4), "--mtu-disc is not supported on this OS");
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<translate_mtu_discover_type_name>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  mov    $0x10,%edi
  call   <x_msg@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: --mtu-disc is not supported on this OS

assistant: ```c
int translate_mtu_discover_type_name(const char *name) {
  x_msg((1 << 4), "--mtu-disc is not supported on this OS");
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D15: Hello shell!

tool: D27: Here are args: 

tool: D19: 	%s


assistant: ```c
main(int argc, char **argv) {
  printf("Hello shell!\n");
  printf("Here are args: \n");
  int i = 0;
  for (i = 0; i < argc; i++) {
    printf("\t%s\n", argv[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L3
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D9(%rip),%rbp
L16:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L16
L3:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type: string
name: parse_data
arguments: data_label: D28
type: string
name: parse_data
arguments: data_label: D9
type: string

tool: D16: Hello shell!

tool: D28: Here are args: 

tool: D9: 	%s


assistant: ```c
main(int argc, char **argv) {
  printf("Hello shell!\n");
  printf("Here are args: \n");
  int i = 0;
  for (i = 0; i < argc; i++) {
    printf("\t%s\n", argv[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D15(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L4
  lea    -0x1(%rbp),%eax
  lea    D5(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D15: Hello shell!

tool: D25: Here are args: 

tool: D5: 	%s


assistant: ```c
main(int argc, char **argv) {
  printf("Hello shell!\n");
  printf("Here are args: \n");
  int i = 0;
  for (i = 0; i < argc; i++) {
    printf("\t%s\n", argv[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D12(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L16
  lea    -0x1(%rbp),%eax
  lea    D28(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
L16:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D28
type: string

tool: D12: Hello shell!

tool: D13: Here are args: 

tool: D28: 	%s


assistant: ```c
main(int argc, char **argv) {
  printf("Hello shell!\n");
  printf("Here are args: \n");
  int i = 0;
  for (i = 0; i < argc; i++) {
    printf("\t%s\n", argv[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L3
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  printf("\n");
  for (i = 1; i <= n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<display>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L15
  mov    $0x1,%ebx
  lea    D7(%rip),%r13
L17:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L17
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  printf("\n");
  for (i = 1; i <= n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<display>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L1
  mov    $0x1,%ebx
  lea    D1(%rip),%r13
  nopl   (%rax)
L10:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L10
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  printf("\n");
  for (i = 1; i <= n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<display>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L13
  mov    $0x1,%ebx
  lea    D0(%rip),%r13
  nopl   (%rax)
L4:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L4
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  printf("\n");
  for (i = 1; i <= n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L48
  mov    $0x0,%eax
  jmp    L17
L48:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  jne    L46
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L14
  jmp    L37
L46:
  nop
L37:
  mov    -0x28(%rbp),%rax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int bcmp(const void *b1, const void *b2, size_t length) {
  char *p1, *p2;
  if (length == 0)
    return (0);
  p1 = (char *)b1;
  p2 = (char *)b2;
  do
    if (*p1++ != *p2++)
      break;
  while (--length);
  return (length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bcmp>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L7
  mov    $0x0,%ecx
L8:
  mov    %rdx,%rax
  sub    %rcx,%rax
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,(%rdi,%rcx,1)
  jne    L7
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L8
  mov    $0x0,%eax
L7:
  ret
```

assistant: ```c
int bcmp(const void *b1, const void *b2, size_t length) {
  char *p1, *p2;
  if (length == 0)
    return (0);
  p1 = (char *)b1;
  p2 = (char *)b2;
  do
    if (*p1++ != *p2++)
      break;
  while (--length);
  return (length);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bcmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L9
  xor    %ecx,%ecx
  jmp    L13
  nop
L16:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L29
L13:
  mov    %rdx,%rax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %rcx,%rax
  cmp    %r8b,(%rdi,%rcx,1)
  je     L16
L9:
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bcmp(const void *b1, const void *b2, size_t length) {
  char *p1, *p2;
  if (length == 0)
    return (0);
  p1 = (char *)b1;
  p2 = (char *)b2;
  do
    if (*p1++ != *p2++)
      break;
  while (--length);
  return (length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bcmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L16
  xor    %ecx,%ecx
  jmp    L34
  nop
L13:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L26
L34:
  mov    %rdx,%rax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %rcx,%rax
  cmp    %r8b,(%rdi,%rcx,1)
  je     L13
L16:
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bcmp(const void *b1, const void *b2, size_t length) {
  char *p1, *p2;
  if (length == 0)
    return (0);
  p1 = (char *)b1;
  p2 = (char *)b2;
  do
    if (*p1++ != *p2++)
      break;
  while (--length);
  return (length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<teststrtok2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7c(%rbp)
  movabs $0x686f4a2c64657246,%rax
  mov    %rax,-0x16(%rbp)
  movl   $0x6e412c6e,-0xe(%rbp)
  movw   $0x6e,-0xa(%rbp)
  lea    -0x16(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  jmp    L9
L21:
  mov    -0x7c(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x7c(%rbp)
  movq   $0x0,-0x78(%rbp)
L9:
  mov    -0x78(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    -0x7c(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x70(%rbp,%rdx,8)
  mov    -0x7c(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,8),%rax
  test   %rax,%rax
  jne    L21
  mov    -0x7c(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
datatype: string
name: disassemble_data
arguments: label: D14
datatype: string

tool: D13: ,

tool: D14: Total results = %d


assistant: ```c
void teststrtok2() {
  int in = 0;
  char buffer[] = "Fred,John,Ann";
  char *p[10];
  char *buf = buffer;
  while ((p[in] = strtok(buf, ",")) != NULL) {
    printf("%s\n", p[in]);
    in++;
    buf = NULL;
  }
  printf("Total results = %d\n", in);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<teststrtok2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x686f4a2c64657246,%rax
  mov    %rax,0xa(%rsp)
  movl   $0x6e412c6e,0x12(%rsp)
  movw   $0x6e,0x16(%rsp)
  lea    0xa(%rsp),%rdi
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
  jmp    L16
L20:
  call   <puts@plt>
  add    $0x1,%ebx
  mov    $0x0,%edi
L16:
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L20
  mov    %ebx,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string

tool: D6: ,

tool: D11: Total results = %d


assistant: ```c
void teststrtok2() {
  int in = 0;
  char buffer[] = "Fred,John,Ann";
  char *p[10];
  char *buf = buffer;
  while ((p[in] = strtok(buf, ",")) != NULL) {
    printf("%s\n", p[in]);
    in++;
    buf = NULL;
  }
  printf("Total results = %d\n", in);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<teststrtok2>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x686f4a2c64657246,%rax
  lea    0xa(%rsp),%rdi
  movl   $0x6e412c6e,0x12(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0x6e,%eax
  mov    %ax,0x16(%rsp)
  jmp    L25
  nopl   0x0(%rax)
L14:
  call   <puts@plt>
  add    $0x1,%ebp
  xor    %edi,%edi
L25:
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L14
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string

tool: D1: ,

tool: D9: Total results = %d


assistant: ```c
void teststrtok2() {
  int in = 0;
  char buffer[] = "Fred,John,Ann";
  char *p[10];
  char *buf = buffer;
  while ((p[in] = strtok(buf, ",")) != NULL) {
    printf("%s\n", p[in]);
    in++;
    buf = NULL;
  }
  printf("Total results = %d\n", in);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<teststrtok2>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x686f4a2c64657246,%rax
  lea    0xa(%rsp),%rdi
  movl   $0x6e412c6e,0x12(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0x6e,%eax
  mov    %ax,0x16(%rsp)
  jmp    L11
  nopl   0x0(%rax)
L17:
  call   <puts@plt>
  add    $0x1,%ebp
  xor    %edi,%edi
L11:
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L17
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D16: ,

tool: D9: Total results = %d


assistant: ```c
void teststrtok2() {
  int in = 0;
  char buffer[] = "Fred,John,Ann";
  char *p[10];
  char *buf = buffer;
  while ((p[in] = strtok(buf, ",")) != NULL) {
    printf("%s\n", p[in]);
    in++;
    buf = NULL;
  }
  printf("Total results = %d\n", in);
}
```