ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uninitvar_fwscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fwscanf@plt>
  lea    -0x24(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fwscanf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void uninitvar_fwscanf(void) {
  FILE *stream;
  wchar_t *format1, *format2;
  int i;
  (void)fwscanf(stream, format1);
  (void)fwscanf(stream, format2, &i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_fwscanf>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %rbx,%rdi
  call   <fwscanf@plt>
  lea    0x4(%rsp),%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fwscanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_fwscanf(void) {
  FILE *stream;
  wchar_t *format1, *format2;
  int i;
  (void)fwscanf(stream, format1);
  (void)fwscanf(stream, format2, &i);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<uninitvar_fwscanf>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fwscanf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  call   <fwscanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_fwscanf(void) {
  FILE *stream;
  wchar_t *format1, *format2;
  int i;
  (void)fwscanf(stream, format1);
  (void)fwscanf(stream, format2, &i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninitvar_fwscanf>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fwscanf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  call   <fwscanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_fwscanf(void) {
  FILE *stream;
  wchar_t *format1, *format2;
  int i;
  (void)fwscanf(stream, format1);
  (void)fwscanf(stream, format2, &i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kano_log_warning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void kano_log_warning(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  vsyslog(LOG_USER | LOG_WARNING, msg, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kano_log_warning>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  mov    D13(%rip),%rax
  or     (%rax),%edi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kano_log_warning(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  vsyslog(LOG_USER | LOG_WARNING, msg, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kano_log_warning>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  mov    D5(%rip),%rax
  or     (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void kano_log_warning(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  vsyslog(LOG_USER | LOG_WARNING, msg, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kano_log_warning>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D11(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  mov    D9(%rip),%rax
  or     (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void kano_log_warning(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  vsyslog(LOG_USER | LOG_WARNING, msg, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call_with_3_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x18(%rax),%r9
  mov    -0x28(%rbp),%rax
  lea    0x20(%rax),%r10
  mov    -0x28(%rbp),%rax
  lea    0x28(%rax),%r11
  mov    -0x18(%rbp),%r8
  mov    (%r11),%rdx
  mov    (%r10),%rsi
  mov    (%r9),%rdi
  xor    %rax,%rax
  call   *%r8
  mov    %rax,%r8
  mov    %r8,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long call_with_3_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("movq %4,%%rdx\n\t"
                       "movq %3,%%rsi\n\t"
                       "movq %2,%%rdi\n\t"
                       "xor %%rax,%%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func), "m"(argv[3]), "m"(argv[4]), "m"(argv[5])
                       : "rax", "rcx", "rdx", "rsi", "rdi");
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<call_with_3_arg>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%r9
  mov    0x28(%r9),%rdx
  mov    0x20(%r9),%rsi
  mov    0x18(%r9),%rdi
  xor    %rax,%rax
  call   *%r8
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long call_with_3_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("movq %4,%%rdx\n\t"
                       "movq %3,%%rsi\n\t"
                       "movq %2,%%rdi\n\t"
                       "xor %%rax,%%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func), "m"(argv[3]), "m"(argv[4]), "m"(argv[5])
                       : "rax", "rcx", "rdx", "rsi", "rdi");
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call_with_3_arg>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%r9
  mov    0x28(%r9),%rdx
  mov    0x20(%r9),%rsi
  mov    0x18(%r9),%rdi
  xor    %rax,%rax
  call   *%r8
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long call_with_3_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("movq %4,%%rdx\n\t"
                       "movq %3,%%rsi\n\t"
                       "movq %2,%%rdi\n\t"
                       "xor %%rax,%%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func), "m"(argv[3]), "m"(argv[4]), "m"(argv[5])
                       : "rax", "rcx", "rdx", "rsi", "rdi");
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<call_with_3_arg>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%r9
  mov    0x28(%r9),%rdx
  mov    0x20(%r9),%rsi
  mov    0x18(%r9),%rdi
  xor    %rax,%rax
  call   *%r8
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long call_with_3_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("movq %4,%%rdx\n\t"
                       "movq %3,%%rsi\n\t"
                       "movq %2,%%rdi\n\t"
                       "xor %%rax,%%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func), "m"(argv[3]), "m"(argv[4]), "m"(argv[5])
                       : "rax", "rcx", "rdx", "rsi", "rdi");
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<can_map_water>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x5,%eax
  cmp    $0x2,%eax
  ja     L10
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L17
L10:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int can_map_water(int terrain) {
  switch (terrain) {
  case 7:
  case 6:
  case 5:
    return FALSE;
  default:
    return TRUE;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<can_map_water>:
  endbr64
  sub    $0x5,%edi
  cmp    $0x2,%edi
  ja     L5
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  ret
L5:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int can_map_water(int terrain) {
  switch (terrain) {
  case 7:
  case 6:
  case 5:
    return FALSE;
  default:
    return TRUE;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<can_map_water>:
  endbr64
  sub    $0x5,%edi
  cmp    $0x2,%edi
  ja     L6
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int can_map_water(int terrain) {
  switch (terrain) {
  case 7:
  case 6:
  case 5:
    return FALSE;
  default:
    return TRUE;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<can_map_water>:
  endbr64
  sub    $0x5,%edi
  cmp    $0x2,%edi
  ja     L0
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int can_map_water(int terrain) {
  switch (terrain) {
  case 7:
  case 6:
  case 5:
    return FALSE;
  default:
    return TRUE;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L29:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L2
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L2:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L29
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int minValue(int arr[], size_t sz) {
  int min = arr[0];
  for (size_t i = 0; i < sz; i++)
    if (arr[i] < min)
      min = arr[i];
  return min;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<minValue>:
  endbr64
  mov    (%rdi),%edx
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rax
  lea    (%rdi,%rsi,4),%rsi
L9:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L9
L4:
  mov    %edx,%eax
  ret
```

assistant: ```c
int minValue(int arr[], size_t sz) {
  int min = arr[0];
  for (size_t i = 0; i < sz; i++)
    if (arr[i] < min)
      min = arr[i];
  return min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minValue>:
  endbr64
  mov    (%rdi),%r8d
  test   %rsi,%rsi
  je     L21
  lea    0x4(%rdi),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    %r8d,%edx
  jmp    L6
  nopl   0x0(%rax)
L26:
  mov    (%rax),%edx
  add    $0x4,%rax
L6:
  cmp    %edx,%r8d
  cmovg  %edx,%r8d
  cmp    %rcx,%rax
  jne    L26
L21:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int minValue(int arr[], size_t sz) {
  int min = arr[0];
  for (size_t i = 0; i < sz; i++)
    if (arr[i] < min)
      min = arr[i];
  return min;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<minValue>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L15
  lea    -0x1(%rsi),%rdx
  cmp    $0x2,%rdx
  jbe    L2
  mov    %rsi,%rdx
  movd   %eax,%xmm4
  mov    %rdi,%rax
  shr    $0x2,%rdx
  pshufd $0x0,%xmm4,%xmm0
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L30:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L30
  movdqa %xmm0,%xmm2
  mov    %rsi,%rdx
  psrldq $0x8,%xmm2
  and    $0xfffffffffffffffc,%rdx
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%sil
  je     L28
L35:
  mov    (%rcx,%rdx,4),%edi
  lea    0x0(,%rdx,4),%r8
  cmp    %edi,%eax
  cmovg  %edi,%eax
  lea    0x1(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L15
  mov    0x4(%rcx,%r8,1),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  add    $0x2,%rdx
  cmp    %rdx,%rsi
  jbe    L15
  mov    0x8(%rcx,%r8,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L15:
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  ret
L2:
  xor    %edx,%edx
  jmp    L35
```

assistant: ```c
int minValue(int arr[], size_t sz) {
  int min = arr[0];
  for (size_t i = 0; i < sz; i++)
    if (arr[i] < min)
      min = arr[i];
  return min;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  mov    $0x0,%eax
  call   <foo2@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int foo1() {
  int b1 = 2;
  return foo2() + b1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo2@plt>
  add    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int foo1() {
  int b1 = 2;
  return foo2() + b1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo2@plt>
  add    $0x8,%rsp
  add    $0x2,%eax
  ret
```

assistant: ```c
int foo1() {
  int b1 = 2;
  return foo2() + b1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo2@plt>
  add    $0x8,%rsp
  add    $0x2,%eax
  ret
```

assistant: ```c
int foo1() {
  int b1 = 2;
  return foo2() + b1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sys_writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L50
L33:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L0
  cmpl   $0x0,-0xc(%rbp)
  jns    L53
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L53
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L53:
  mov    $0xffffffff,%eax
  jmp    L57
L0:
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L50:
  cmpl   $0x0,-0x10(%rbp)
  jg     L33
  mov    -0x18(%rbp),%eax
L57:
  leave
  ret
```

assistant: ```c
int sys_writen(int fd, const void *vptr, int n) {
  int nleft;
  int nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sys_writen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r14d
  test   %edx,%edx
  jle    L17
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    $0x0,%r13d
  jmp    L67
L53:
  sub    %eax,%ebx
  cltq
  add    %rax,%rbp
  test   %ebx,%ebx
  jle    L17
L67:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L53
  jns    L57
  mov    D2(%rip),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L7
  mov    %r13d,%eax
  jmp    L53
L57:
  mov    $0xffffffff,%r14d
L17:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    $0xffffffff,%r14d
  jmp    L17
```

assistant: ```c
int sys_writen(int fd, const void *vptr, int n) {
  int nleft;
  int nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sys_writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L47
  nopl   0x0(%rax)
L20:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L33
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jg     L20
L47:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  je     L43
  mov    D0(%rip),%rax
  mov    D14(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L20
L43:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sys_writen(int fd, const void *vptr, int n) {
  int nleft;
  int nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sys_writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L13
  nopl   0x0(%rax)
L31:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L1
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jg     L31
L13:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  je     L14
  mov    D16(%rip),%rax
  mov    D11(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L31
L14:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sys_writen(int fd, const void *vptr, int n) {
  int nleft;
  int nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<num2nibble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L6
  cmpl   $0x10,-0x4(%rbp)
  jle    L26
L6:
  mov    $0x30,%eax
  jmp    L19
L26:
  cmpl   $0x9,-0x4(%rbp)
  jg     L1
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  jmp    L19
L1:
  mov    -0x4(%rbp),%eax
  add    $0x37,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
char num2nibble(int num) {
  if (num < 0 || num > 16)
    return ('0');
  if (num < 10)
    return (num + '0');
  return (num - 10 + 'A');
}
```
user: What is the c source code of the assembly code below?

```asm
<num2nibble>:
  endbr64
  mov    $0x30,%eax
  cmp    $0x10,%edi
  ja     L9
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
L9:
  ret
```

assistant: ```c
char num2nibble(int num) {
  if (num < 0 || num > 16)
    return ('0');
  if (num < 10)
    return (num + '0');
  return (num - 10 + 'A');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num2nibble>:
  endbr64
  mov    $0x30,%eax
  cmp    $0x10,%edi
  ja     L9
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
L9:
  ret
```

assistant: ```c
char num2nibble(int num) {
  if (num < 0 || num > 16)
    return ('0');
  if (num < 10)
    return (num + '0');
  return (num - 10 + 'A');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<num2nibble>:
  endbr64
  mov    $0x30,%eax
  cmp    $0x10,%edi
  ja     L7
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
L7:
  ret
```

assistant: ```c
char num2nibble(int num) {
  if (num < 0 || num > 16)
    return ('0');
  if (num < 10)
    return (num + '0');
  return (num - 10 + 'A');
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_nsap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_nsap(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_nsap>:
  endbr64
  ret
```

assistant: ```c
void do_nsap(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_nsap>:
  endbr64
  ret
```

assistant: ```c
void do_nsap(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_nsap>:
  endbr64
  ret
```

assistant: ```c
void do_nsap(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiplicacion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L2:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L2
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int multiplicacion(int a, int b) {
  int resultado;
  int i;
  for (i = 1; i <= b; i = i + 1) {
    resultado = resultado + a;
  }
  return resultado;
}
```