ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<xrop3_111_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_111_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_111_1_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  mov    %edi,%edx
  or     %eax,%edx
  mov    %edx,%eax
  not    %eax
  movzbl %dl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_111_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_111_1_1>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  or     %esi,%eax
  or     %eax,%edx
  mov    %edx,%eax
  movzbl %dl,%edx
  not    %eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_111_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_111_1_1>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  or     %esi,%eax
  or     %eax,%edx
  mov    %edx,%eax
  movzbl %dl,%edx
  not    %eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_111_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D128(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L88
L53:
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L88:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L53
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L61
L70:
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L60:
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L60
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L61:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L70
  movl   $0x1,-0x10(%rbp)
  jmp    L84
L48:
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L84:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L48
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D128
type_infered: string
name: retrieve_data
arguments: tag: D74
type_infered: string
name: retrieve_data
arguments: tag: D86
type_infered: string
name: retrieve_data
arguments: tag: D84
type_infered: string
name: retrieve_data
arguments: tag: D75
type_infered: string
name: retrieve_data
arguments: tag: D97
type_infered: string

tool: D128: x: 

tool: D74: %d

tool: D86: y: 

tool: D84: 


tool: D75: x

tool: D97: *

assistant: ```c
int main() {
  int x, y, i, j;
  printf("x: ");
  scanf("%d", &x);
  printf("y: ");
  scanf("%d", &y);
  printf("\n");
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  for (i = 1; i <= x - 2; i++) {
    printf("x");
    for (j = 1; j <= x - 2; j++) {
      printf("*");
    }
    printf("x");
    printf("\n");
  }
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D46(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,(%rsp)
  jle    L81
  mov    $0x1,%ebx
  lea    D33(%rip),%rbp
L8:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L8
L81:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x2,(%rsp)
  jle    L52
  mov    $0x1,%r12d
  lea    D33(%rip),%r13
  lea    D57(%rip),%rbp
  lea    D32(%rip),%r14
L69:
  mov    %r13,%rdi
  call   <printf@plt>
  cmpl   $0x2,(%rsp)
  jle    L5
  mov    $0x1,%ebx
L46:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    (%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L46
L5:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  mov    (%rsp),%eax
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jg     L69
L52:
  cmpl   $0x0,(%rsp)
  jle    L4
  mov    $0x1,%ebx
  lea    D33(%rip),%rbp
L77:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L77
L4:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D46
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D33
type_infered: string
name: unpack_data
arguments: label: D57
type_infered: string

tool: D36: x: 

tool: D46: %d

tool: D14: y: 

tool: D32: 


tool: D33: x

tool: D57: *

assistant: ```c
int main() {
  int x, y, i, j;
  printf("x: ");
  scanf("%d", &x);
  printf("y: ");
  scanf("%d", &y);
  printf("\n");
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  for (i = 1; i <= x - 2; i++) {
    printf("x");
    for (j = 1; j <= x - 2; j++) {
      printf("*");
    }
    printf("x");
    printf("\n");
  }
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D35(%rip),%rdi
  push   %r13
  lea    D32(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    D46(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L39
  nopl   0x0(%rax)
L23:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L23
L39:
  mov    %r13,%rdi
  mov    $0x1,%r14d
  lea    D7(%rip),%r12
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D74(%rip),%rbp
  cmp    $0x2,%eax
  jle    L3
  nopl   0x0(%rax)
L88:
  mov    %r12,%rdi
  mov    $0x1,%ebx
  call   <printf@plt>
  cmpl   $0x2,(%rsp)
  jle    L60
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L46
L60:
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %r14d,%edx
  jg     L88
L3:
  mov    $0x1,%ebx
  lea    D7(%rip),%r12
  test   %eax,%eax
  jle    L79
  nopl   0x0(%rax)
L71:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L71
L79:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D32
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D46
type: string
name: parse_data
arguments: data_label: D5
type: string
name: parse_data
arguments: data_label: D74
type: string

tool: D35: x: 

tool: D32: 


tool: D7: x

tool: D46: %d

tool: D5: y: 

tool: D74: *

assistant: ```c
int main() {
  int x, y, i, j;
  printf("x: ");
  scanf("%d", &x);
  printf("y: ");
  scanf("%d", &y);
  printf("\n");
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  for (i = 1; i <= x - 2; i++) {
    printf("x");
    for (j = 1; j <= x - 2; j++) {
      printf("*");
    }
    printf("x");
    printf("\n");
  }
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D56(%rip),%rdi
  push   %r13
  lea    D65(%rip),%r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  lea    D41(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D71(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L80
  nopl   0x0(%rax)
L23:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L23
L80:
  mov    %r13,%rdi
  mov    $0x1,%r14d
  lea    D35(%rip),%r12
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D23(%rip),%rbp
  cmp    $0x2,%eax
  jle    L20
  nopl   0x0(%rax)
L4:
  mov    %r12,%rdi
  mov    $0x1,%ebx
  call   <printf@plt>
  cmpl   $0x2,(%rsp)
  jle    L78
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L21
L78:
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %r14d,%edx
  jg     L4
L20:
  mov    $0x1,%ebx
  lea    D35(%rip),%r12
  test   %eax,%eax
  jle    L29
  nopl   0x0(%rax)
L38:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L38
L29:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D56
data_type: string
name: disassemble_data
arguments: tag: D65
data_type: string
name: disassemble_data
arguments: tag: D35
data_type: string
name: disassemble_data
arguments: tag: D41
data_type: string
name: disassemble_data
arguments: tag: D71
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string

tool: D56: x: 

tool: D65: 


tool: D35: x

tool: D41: %d

tool: D71: y: 

tool: D23: *

assistant: ```c
int main() {
  int x, y, i, j;
  printf("x: ");
  scanf("%d", &x);
  printf("y: ");
  scanf("%d", &y);
  printf("\n");
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  for (i = 1; i <= x - 2; i++) {
    printf("x");
    for (j = 1; j <= x - 2; j++) {
      printf("*");
    }
    printf("x");
    printf("\n");
  }
  for (i = 1; i <= x; i++) {
    printf("x");
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<extract_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %edx,%r13d
  mov    $0x0,%ebx
  mov    $0xffffffff,%r12d
  movl   $0x0,0xc(%rsp)
  jmp    L96
L55:
  cmpb   $0x22,(%r14,%rbx,1)
  je     L108
L17:
  add    $0x1,%rbx
L96:
  mov    %ebx,0x8(%rsp)
  mov    %ebx,%ebp
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  cmovg  %r13d,%eax
  cmp    %ebx,%eax
  jle    L47
  cmp    $0xffffffff,%r12d
  je     L55
  test   %r12d,%r12d
  js     L17
  cmpl   $0x1,0xc(%rsp)
  je     L52
  movzbl (%r14,%rbx,1),%eax
  cmp    $0x5c,%al
  je     L119
  cmp    $0x22,%al
  je     L28
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  mov    %al,(%r15,%rbp,1)
  jmp    L17
L108:
  mov    0x8(%rsp),%r12d
  add    $0x1,%r12d
  jmp    L17
L52:
  movzbl (%r14,%rbx,1),%eax
  cmp    $0x22,%al
  je     L146
  cmp    $0x5c,%al
  je     L146
L173:
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  mov    %al,(%r15,%rbp,1)
  movl   $0x0,0xc(%rsp)
  jmp    L17
L146:
  add    $0x1,%r12d
  jmp    L173
L119:
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  movb   $0x5c,(%r15,%rbp,1)
  movl   $0x1,0xc(%rsp)
  jmp    L17
L28:
  sub    %r12d,%ebp
  movslq %ebp,%rax
  movb   $0x0,(%r15,%rax,1)
  jmp    L141
L47:
  test   %r12d,%r12d
  js     L18
L141:
  mov    %r15,%rdi
  call   <strlen@plt>
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L30
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        switch (src[pos]) {
        case '"':
        case '\\':
          off++;
          break;
        }
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        dest[pos - off] = src[pos];
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extract_string>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L52
  nopl   (%rax)
L37:
  cmpl   $0x1,0x4(%rsp)
  je     L115
  sub    %r14d,%ebx
  movslq %ebx,%rbx
  add    0x8(%rsp),%rbx
  cmp    $0x5c,%al
  je     L23
  cmp    $0x22,%al
  je     L16
  mov    %al,(%rbx)
L119:
  add    $0x1,%r15
  add    $0x1,%r12d
L52:
  mov    %r13,%rdi
  mov    %r15d,%ebx
  call   <strlen@plt>
  cmp    %ebp,%eax
  cmovg  %ebp,%eax
  cmp    %r15d,%eax
  jle    L101
  movzbl 0x0(%r13,%r15,1),%eax
  cmp    $0xffffffff,%r14d
  jne    L37
  cmp    $0x22,%al
  cmove  %r12d,%r14d
  jmp    L119
  nopl   0x0(%rax)
L115:
  cmp    $0x22,%al
  je     L75
  cmp    $0x5c,%al
  je     L75
L133:
  mov    0x8(%rsp),%rdx
  sub    %r14d,%ebx
  movl   $0x0,0x4(%rsp)
  movslq %ebx,%rbx
  mov    %al,(%rdx,%rbx,1)
  jmp    L119
L23:
  movb   $0x5c,(%rbx)
  movl   $0x1,0x4(%rsp)
  jmp    L119
  nopl   (%rax)
L75:
  add    $0x1,%r14d
  jmp    L133
  cs nopw 0x0(%rax,%rax,1)
L101:
  cmp    $0xffffffff,%r14d
  je     L32
L47:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <strlen@plt>
L16:
  movb   $0x0,(%rbx)
  jmp    L47
L32:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        switch (src[pos]) {
        case '"':
        case '\\':
          off++;
          break;
        }
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        dest[pos - off] = src[pos];
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_string>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L123
  nopl   (%rax)
L113:
  cmpl   $0x1,0x4(%rsp)
  je     L125
  sub    %r14d,%ebx
  movslq %ebx,%rbx
  add    0x8(%rsp),%rbx
  cmp    $0x5c,%al
  je     L23
  cmp    $0x22,%al
  je     L45
  mov    %al,(%rbx)
L86:
  add    $0x1,%r15
  add    $0x1,%r12d
L123:
  mov    %r13,%rdi
  mov    %r15d,%ebx
  call   <strlen@plt>
  cmp    %ebp,%eax
  cmovg  %ebp,%eax
  cmp    %r15d,%eax
  jle    L116
  movzbl 0x0(%r13,%r15,1),%eax
  cmp    $0xffffffff,%r14d
  jne    L113
  cmp    $0x22,%al
  cmove  %r12d,%r14d
  jmp    L86
  nopl   0x0(%rax)
L125:
  cmp    $0x22,%al
  je     L134
  cmp    $0x5c,%al
  je     L134
L107:
  mov    0x8(%rsp),%rdx
  sub    %r14d,%ebx
  movl   $0x0,0x4(%rsp)
  movslq %ebx,%rbx
  mov    %al,(%rdx,%rbx,1)
  jmp    L86
L23:
  movb   $0x5c,(%rbx)
  movl   $0x1,0x4(%rsp)
  jmp    L86
  nopl   (%rax)
L134:
  add    $0x1,%r14d
  jmp    L107
  cs nopw 0x0(%rax,%rax,1)
L116:
  cmp    $0xffffffff,%r14d
  je     L61
L79:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <strlen@plt>
L45:
  movb   $0x0,(%rbx)
  jmp    L79
L61:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        switch (src[pos]) {
        case '"':
        case '\\':
          off++;
          break;
        }
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        dest[pos - off] = src[pos];
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x62,%edi
  call   <foo@plt>
  cmp    $0x12,%eax
  jne    L72
  mov    $0x61,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L72
  mov    $0x63,%edi
  call   <foo@plt>
  test   %eax,%eax
  je     L75
L72:
  mov    $0x0,%eax
  call   <abort@plt>
L75:
  mov    $0xffffffc2,%edi
  call   <foo@plt>
  cmp    $0x13,%eax
  jne    L86
  mov    $0xffffffc1,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L86
  mov    $0xffffffc3,%edi
  call   <foo@plt>
  test   %eax,%eax
  je     L67
L86:
  mov    $0x0,%eax
  call   <abort@plt>
L67:
  mov    $0x1c,%edi
  call   <foo@plt>
  cmp    $0x69,%eax
  jne    L60
  mov    $0x1b,%edi
  call   <foo@plt>
  cmp    $0x66,%eax
  jne    L60
  mov    $0x1d,%edi
  call   <foo@plt>
  cmp    $0x6f,%eax
  je     L15
L60:
  mov    $0x0,%eax
  call   <abort@plt>
L15:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo(98) != 18 || foo(97) != 0 || foo(99) != 0)
    abort();
  if (foo(-62) != 19 || foo(-63) != 0 || foo(-61) != 0)
    abort();
  if (foo(28) != 105 || foo(27) != 102 || foo(29) != 111)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%edi
  call   <foo@plt>
  cmp    $0x12,%eax
  je     L48
L63:
  mov    $0x0,%eax
  call   <abort@plt>
L47:
  mov    $0xffffffc2,%edi
  call   <foo@plt>
  cmp    $0x13,%eax
  je     L27
L100:
  mov    $0x0,%eax
  call   <abort@plt>
L78:
  mov    $0x1c,%edi
  call   <foo@plt>
  cmp    $0x69,%eax
  je     L105
L42:
  mov    $0x0,%eax
  call   <abort@plt>
L45:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L48:
  mov    $0x61,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L63
  mov    $0x63,%edi
  call   <foo@plt>
  test   %eax,%eax
  je     L47
  jmp    L63
L27:
  mov    $0xffffffc1,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L100
  mov    $0xffffffc3,%edi
  call   <foo@plt>
  test   %eax,%eax
  je     L78
  jmp    L100
L105:
  mov    $0x1b,%edi
  call   <foo@plt>
  cmp    $0x66,%eax
  jne    L42
  mov    $0x1d,%edi
  call   <foo@plt>
  cmp    $0x6f,%eax
  jne    L42
  jmp    L45
```

assistant: ```c
int main() {
  if (foo(98) != 18 || foo(97) != 0 || foo(99) != 0)
    abort();
  if (foo(-62) != 19 || foo(-63) != 0 || foo(-61) != 0)
    abort();
  if (foo(28) != 105 || foo(27) != 102 || foo(29) != 111)
    abort();
  return 0;
}
```