ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ts2mst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <ts2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <jd2mst@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double ts2mst(tsec)
double tsec;
{
  double dj;
  dj = ts2jd(tsec);
  return (jd2mst(dj));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ts2mst>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  call   <ts2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <jd2mst@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    $0x8,%rsp
  ret
```

assistant: ```c
double ts2mst(tsec)
double tsec;
{
  double dj;
  dj = ts2jd(tsec);
  return (jd2mst(dj));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ts2mst>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  call   <ts2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <jd2mst@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double ts2mst(tsec)
double tsec;
{
  double dj;
  dj = ts2jd(tsec);
  return (jd2mst(dj));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ts2mst>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  call   <ts2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <jd2mst@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double ts2mst(tsec)
double tsec;
{
  double dj;
  dj = ts2jd(tsec);
  return (jd2mst(dj));
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapItems>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <push@plt>
  nop
  leave
  ret
```

assistant: ```c
void swapItems() {
  double temp1 = pop();
  double temp2 = pop();
  push(temp1);
  push(temp2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swapItems>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rbp
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rbx
  movq   %rbp,%xmm0
  call   <push@plt>
  movq   %rbx,%xmm0
  call   <push@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void swapItems() {
  double temp1 = pop();
  double temp2 = pop();
  push(temp1);
  push(temp2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swapItems>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  call   <push@plt>
  movsd  (%rsp),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  jmp    1070 <push@plt>
```

assistant: ```c
void swapItems() {
  double temp1 = pop();
  double temp2 = pop();
  push(temp1);
  push(temp2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swapItems>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  call   <push@plt>
  movsd  (%rsp),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  jmp    1070 <push@plt>
```

assistant: ```c
void swapItems() {
  double temp1 = pop();
  double temp2 = pop();
  push(temp1);
  push(temp2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<merge_sort_sub_unboxed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L1
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort_sub_unboxed>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort_sub_unboxed>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge_unboxed@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void merge_sort_sub_unboxed(int *array, int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
    merge_sort_sub_unboxed(array, low, mid);
    merge_sort_sub_unboxed(array, mid + 1, high);
    merge_unboxed(array, low, mid, high);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<merge_sort_sub_unboxed>:
  endbr64
  cmp    %edx,%esi
  jl     L1
  ret
L1:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <merge_sort_sub_unboxed>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <merge_sort_sub_unboxed>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge_unboxed@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void merge_sort_sub_unboxed(int *array, int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
    merge_sort_sub_unboxed(array, low, mid);
    merge_sort_sub_unboxed(array, mid + 1, high);
    merge_unboxed(array, low, mid, high);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tty_putw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  jmp    L23
L20:
  mov    -0x24(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  lea    0x30(%rax),%edx
  mov    $0x9,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%eax
  mov    %dl,-0x12(%rbp,%rax,1)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x24(%rbp)
  addl   $0x1,-0x18(%rbp)
L23:
  cmpl   $0x9,-0x18(%rbp)
  jbe    L20
  lea    -0x12(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0xa,%edx
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <sys_call@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
unsigned int tty_putw(unsigned int val) {
  char buf[10];
  unsigned int i;
  for (i = 0; i < 10; i++) {
    buf[9 - i] = (val % 10) + 0x30;
    val = val / 10;
  }
  return sys_call(0x02, (unsigned int)buf, 10, 0, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tty_putw>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r8
  lea    0x17(%rsp),%rdx
  mov    $0xcccccccd,%esi
L4:
  mov    %edi,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,(%rdx)
  mov    %eax,%edi
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmp    %r8,%rax
  jne    L4
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0xa,%edx
  lea    0xe(%rsp),%esi
  mov    $0x2,%edi
  call   <sys_call@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int tty_putw(unsigned int val) {
  char buf[10];
  unsigned int i;
  for (i = 0; i < 10; i++) {
    buf[9 - i] = (val % 10) + 0x30;
    val = val / 10;
  }
  return sys_call(0x02, (unsigned int)buf, 10, 0, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<tty_putw>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xcccccccd,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rsi
  lea    0x17(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %edi,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,(%rdx)
  mov    %eax,%edi
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L8
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0xa,%edx
  mov    $0x2,%edi
  call   <sys_call@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x28,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int tty_putw(unsigned int val) {
  char buf[10];
  unsigned int i;
  for (i = 0; i < 10; i++) {
    buf[9 - i] = (val % 10) + 0x30;
    val = val / 10;
  }
  return sys_call(0x02, (unsigned int)buf, 10, 0, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tty_putw>:
  endbr64
  mov    $0xcccccccd,%ecx
  mov    %edi,%esi
  push   %rbx
  xor    %ebx,%ebx
  mov    %rsi,%rdx
  imul   %rcx,%rsi
  sub    $0x20,%rsp
  movq   D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  shr    $0x23,%rsi
  mov    %esi,%eax
  mov    %esi,%edi
  lea    (%rsi,%rsi,4),%esi
  imul   %rcx,%rax
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  shr    $0x23,%rax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%r8d
  imul   %rcx,%rsi
  add    %r8d,%r8d
  sub    %r8d,%edi
  add    $0x30,%edi
  shr    $0x23,%rsi
  mov    %dil,%bl
  mov    %esi,%r8d
  mov    %dl,%bh
  imul   %rcx,%r8
  mov    %bx,0x10(%rsp)
  shr    $0x23,%r8
  mov    %r8d,%r10d
  imul   %rcx,%r10
  shr    $0x23,%r10
  mov    %r10d,%r11d
  imul   %rcx,%r11
  shr    $0x23,%r11
  mov    %r11d,%r9d
  imul   %rcx,%r9
  shr    $0x23,%r9
  mov    %r9d,%edi
  imul   %rcx,%rdi
  shr    $0x23,%rdi
  mov    %edi,%edx
  imul   %rcx,%rdx
  mov    %edi,%ecx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ebx
  movzbl %dl,%edx
  add    %ebx,%ebx
  sub    %ebx,%ecx
  lea    (%rdi,%rdi,4),%ebx
  mov    %r9d,%edi
  add    %ebx,%ebx
  movzbl %cl,%ecx
  sub    %ebx,%edi
  lea    (%r9,%r9,4),%ebx
  mov    %r11d,%r9d
  add    %ebx,%ebx
  movzbl %dil,%edi
  sub    %ebx,%r9d
  lea    (%r11,%r11,4),%ebx
  mov    %r10d,%r11d
  add    %ebx,%ebx
  movzbl %r9b,%r9d
  sub    %ebx,%r11d
  lea    (%r10,%r10,4),%ebx
  mov    %r8d,%r10d
  add    %ebx,%ebx
  sub    %ebx,%r10d
  lea    (%r8,%r8,4),%ebx
  mov    %esi,%r8d
  lea    (%rsi,%rsi,4),%esi
  add    %ebx,%ebx
  add    %esi,%esi
  sub    %ebx,%r8d
  sub    %esi,%eax
  movzbl %r8b,%esi
  xor    %r8d,%r8d
  movzbl %al,%eax
  shl    $0x8,%rax
  or     %rsi,%rax
  movzbl %r10b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  movzbl %r11b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  lea    0x8(%rsp),%esi
  shl    $0x8,%rax
  or     %r9,%rax
  shl    $0x8,%rax
  or     %rdi,%rax
  mov    $0x2,%edi
  shl    $0x8,%rax
  or     %rcx,%rax
  xor    %ecx,%ecx
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    $0xa,%edx
  movq   %rax,%xmm1
  paddb  %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  call   <sys_call@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: byte[8]

tool: {"D4": [0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30]}

assistant: ```c
unsigned int tty_putw(unsigned int val) {
  char buf[10];
  unsigned int i;
  for (i = 0; i < 10; i++) {
    buf[9 - i] = (val % 10) + 0x30;
    val = val / 10;
  }
  return sys_call(0x02, (unsigned int)buf, 10, 0, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fn_test1@plt>
  mov    $0x0,%eax
  call   <fn_test2@plt>
  mov    $0x0,%eax
  call   <fn_test3@plt>
  mov    $0x0,%eax
  call   <fn_test4@plt>
  mov    $0x0,%eax
  call   <fn_extern@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  fn_test1();
  fn_test2();
  fn_test3();
  fn_test4();
  fn_extern();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fn_test1@plt>
  mov    $0x0,%eax
  call   <fn_test2@plt>
  mov    $0x0,%eax
  call   <fn_test3@plt>
  mov    $0x0,%eax
  call   <fn_test4@plt>
  mov    $0x0,%eax
  call   <fn_extern@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fn_test1();
  fn_test2();
  fn_test3();
  fn_test4();
  fn_extern();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn_test1@plt>
  xor    %eax,%eax
  call   <fn_test2@plt>
  xor    %eax,%eax
  call   <fn_test3@plt>
  xor    %eax,%eax
  call   <fn_test4@plt>
  xor    %eax,%eax
  call   <fn_extern@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fn_test1();
  fn_test2();
  fn_test3();
  fn_test4();
  fn_extern();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn_test1@plt>
  xor    %eax,%eax
  call   <fn_test2@plt>
  xor    %eax,%eax
  call   <fn_test3@plt>
  xor    %eax,%eax
  call   <fn_test4@plt>
  xor    %eax,%eax
  call   <fn_extern@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fn_test1();
  fn_test2();
  fn_test3();
  fn_test4();
  fn_extern();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<skip_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L8
L4:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_spaces(const char *str) {
  while (isspace((unsigned char)*str)) {
    str++;
  }
  return (char *)str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L3
L13:
  add    $0x1,%rbx
L3:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skip_spaces(const char *str) {
  while (isspace((unsigned char)*str)) {
    str++;
  }
  return (char *)str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skip_spaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12
L8:
  movzbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_spaces(const char *str) {
  while (isspace((unsigned char)*str)) {
    str++;
  }
  return (char *)str;
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_spaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%r12
L13:
  movzbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_spaces(const char *str) {
  while (isspace((unsigned char)*str)) {
    str++;
  }
  return (char *)str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sphsn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x18(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
double sphsn(double a, double es, double sphi) {
  double sinSphi = sin(sphi);
  return a / sqrt(1.0 - es * (sinSphi * sinSphi));
}
```
user: Translate the below assembly code into C programming language:

```asm
<sphsn>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  movapd %xmm2,%xmm0
  call   <sin@plt>
  mulsd  %xmm0,%xmm0
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm0
  movsd  D9(%rip),%xmm2
  subsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L2
  sqrtsd %xmm2,%xmm2
L15:
  movq   %rbx,%xmm0
  divsd  %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
L2:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: f64

tool: D9: 1

assistant: ```c
double sphsn(double a, double es, double sphi) {
  double sinSphi = sin(sphi);
  return a / sqrt(1.0 - es * (sinSphi * sinSphi));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sphsn>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  movapd %xmm2,%xmm0
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  D6(%rip),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  0x8(%rsp),%xmm0
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L11
  sqrtsd %xmm1,%xmm1
L17:
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  divsd  %xmm1,%xmm0
  pop    %rbx
  ret
L11:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: f64

tool: D6: 1

assistant: ```c
double sphsn(double a, double es, double sphi) {
  double sinSphi = sin(sphi);
  return a / sqrt(1.0 - es * (sinSphi * sinSphi));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sphsn>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  movapd %xmm2,%xmm0
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  D1(%rip),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  0x8(%rsp),%xmm0
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L3
  sqrtsd %xmm1,%xmm1
L13:
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  divsd  %xmm1,%xmm0
  pop    %rbx
  ret
L3:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L13
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: f64

tool: D1: 1

assistant: ```c
double sphsn(double a, double es, double sphi) {
  double sinSphi = sin(sphi);
  return a / sqrt(1.0 - es * (sinSphi * sinSphi));
}
```
user: What is the c source code of the assembly code below?

```asm
<fmt_usergroup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L25
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  jmp    L30
L25:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
L30:
  mov    -0x2c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <putc@plt>
L16:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L6
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d

assistant: ```c
void fmt_usergroup(FILE *out, id_t id, const char *n, int w, int mw) {
  if (n)
    fputs(n, out);
  else
    fprintf(out, "%d", id);
  for (int n = mw - w + 1; n--;)
    putc(' ', out);
}
```
user: What is the c source code of the assembly code below:

```asm
<fmt_usergroup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %ecx,%r12d
  mov    %r8d,%ebx
  test   %rdx,%rdx
  je     L17
  mov    %rdx,%rdi
  mov    %rbp,%rsi
  call   <fputs@plt>
L38:
  sub    %r12d,%ebx
  cmp    $0xffffffff,%ebx
  je     L25
L15:
  mov    %rbp,%rsi
  mov    $0x20,%edi
  call   <putc@plt>
  mov    %ebx,%eax
  sub    $0x1,%ebx
  test   %eax,%eax
  jne    L15
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %esi,%edx
  lea    D8(%rip),%rsi
  call   <fprintf@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: %d

assistant: ```c
void fmt_usergroup(FILE *out, id_t id, const char *n, int w, int mw) {
  if (n)
    fputs(n, out);
  else
    fprintf(out, "%d", id);
  for (int n = mw - w + 1; n--;)
    putc(' ', out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fmt_usergroup>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  test   %rdx,%rdx
  je     L37
  mov    %rdx,%rdi
  mov    %rbp,%rsi
  call   <fputs@plt>
L12:
  sub    %r12d,%ebx
  cmp    $0xffffffff,%ebx
  je     L16
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rsi
  mov    $0x20,%edi
  call   <putc@plt>
  sub    $0x1,%ebx
  jae    L3
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %esi,%edx
  lea    D9(%rip),%rsi
  call   <fprintf@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: %d

assistant: ```c
void fmt_usergroup(FILE *out, id_t id, const char *n, int w, int mw) {
  if (n)
    fputs(n, out);
  else
    fprintf(out, "%d", id);
  for (int n = mw - w + 1; n--;)
    putc(' ', out);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fmt_usergroup>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  test   %rdx,%rdx
  je     L6
  mov    %rdx,%rdi
  mov    %rbp,%rsi
  call   <fputs@plt>
L20:
  sub    %r12d,%ebx
  cmp    $0xffffffff,%ebx
  je     L32
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rsi
  mov    $0x20,%edi
  call   <putc@plt>
  sub    $0x1,%ebx
  jae    L13
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %esi,%edx
  lea    D3(%rip),%rsi
  call   <fprintf@plt>
  jmp    L20
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d

assistant: ```c
void fmt_usergroup(FILE *out, id_t id, const char *n, int w, int mw) {
  if (n)
    fputs(n, out);
  else
    fprintf(out, "%d", id);
  for (int n = mw - w + 1; n--;)
    putc(' ', out);
}
```