ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<dup_at_least_3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  jmp    L61
L44:
  mov    %ebx,0xc(%rsp,%rbp,4)
  lea    0x1(%rbp),%rax
  cmp    $0x2,%ebx
  jg     L41
  mov    %rax,%rbp
L61:
  mov    %ebp,%r12d
  mov    %ebx,%edi
  call   <dup@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L41
  cmp    $0x2,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x2,%ebp
  jle    L44
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L44
L41:
  mov    D2(%rip),%rax
  mov    (%rax),%r14d
  test   %r12d,%r12d
  je     L52
  lea    -0x1(%r12),%r13d
  movslq %r13d,%r13
  movslq %r12d,%r12
  sub    $0x2,%r12
  lea    -0x1(%rbp),%eax
  sub    %rax,%r12
L54:
  mov    0xc(%rsp,%r13,4),%edi
  call   <close@plt>
  sub    $0x1,%r13
  cmp    %r12,%r13
  jne    L54
L52:
  mov    D2(%rip),%rax
  mov    %r14d,(%rax)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dup_at_least_3(int old) {
  int intermediary[3];
  int i = 0, saved_errno;
  do {
    if (old = dup(old), old == -1)
      goto fail;
    assert(i < 3);
    if (i >= 3)
      abort();
    intermediary[i++] = old;
  } while (old < 3);
  i--;
fail:
  saved_errno = errno;
  while (i--)
    close(intermediary[i]);
  errno = saved_errno;
  return old;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dup_at_least_3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebp,0xc(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x2,%ebp
  jg     L75
L44:
  mov    %ebp,%edi
  mov    %ebx,%r13d
  movslq %ebx,%r12
  call   <dup@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L75
  xor    %edi,%edi
  cmp    $0x2,%ebx
  setle  %dil
  call   <assert@plt>
  cmp    $0x3,%rbx
  jne    L8
  xor    %eax,%eax
  call   <abort@plt>
  mov    %ebp,0xc(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x2,%ebp
  jle    L44
  nopl   0x0(%rax)
L75:
  mov    D6(%rip),%rbx
  mov    (%rbx),%r14d
  test   %r12d,%r12d
  je     L22
  lea    -0x1(%r12),%r15d
  lea    -0x1(%r13),%eax
  sub    $0x2,%r12
  movslq %r15d,%r15
  sub    %rax,%r12
  lea    0xc(%rsp),%r13
L12:
  mov    0x0(%r13,%r15,4),%edi
  sub    $0x1,%r15
  call   <close@plt>
  cmp    %r12,%r15
  jne    L12
L22:
  mov    %r14d,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x28,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dup_at_least_3(int old) {
  int intermediary[3];
  int i = 0, saved_errno;
  do {
    if (old = dup(old), old == -1)
      goto fail;
    assert(i < 3);
    if (i >= 3)
      abort();
    intermediary[i++] = old;
  } while (old < 3);
  i--;
fail:
  saved_errno = errno;
  while (i--)
    close(intermediary[i]);
  errno = saved_errno;
  return old;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dup_at_least_3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L40:
  mov    %ebp,%edi
  mov    %ebx,%r13d
  movslq %ebx,%r12
  call   <dup@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L1
  xor    %edi,%edi
  cmp    $0x2,%ebx
  setle  %dil
  call   <assert@plt>
  cmp    $0x3,%rbx
  je     L49
  mov    %ebp,0xc(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x2,%ebp
  jle    L40
L1:
  mov    D7(%rip),%rbx
  mov    (%rbx),%r14d
  test   %r12d,%r12d
  je     L4
  lea    -0x1(%r12),%r15d
  lea    -0x1(%r13),%eax
  sub    $0x2,%r12
  movslq %r15d,%r15
  sub    %rax,%r12
  lea    0xc(%rsp),%r13
L37:
  mov    0x0(%r13,%r15,4),%edi
  sub    $0x1,%r15
  call   <close@plt>
  cmp    %r12,%r15
  jne    L37
L4:
  mov    %r14d,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x28,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %ebp,0xc(%rsp,%rbx,4)
  mov    $0x4,%ebx
  cmp    $0x2,%ebp
  jle    L40
  jmp    L1
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dup_at_least_3(int old) {
  int intermediary[3];
  int i = 0, saved_errno;
  do {
    if (old = dup(old), old == -1)
      goto fail;
    assert(i < 3);
    if (i >= 3)
      abort();
    intermediary[i++] = old;
  } while (old < 3);
  i--;
fail:
  saved_errno = errno;
  while (i--)
    close(intermediary[i]);
  errno = saved_errno;
  return old;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare_int_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_int_dec(void const *a, void const *b) {
  int const *pa = a;
  int const *pb = b;
  return *pb - *pa;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compare_int_dec>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  ret
```

assistant: ```c
int compare_int_dec(void const *a, void const *b) {
  int const *pa = a;
  int const *pb = b;
  return *pb - *pa;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_int_dec>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  ret
```

assistant: ```c
int compare_int_dec(void const *a, void const *b) {
  int const *pa = a;
  int const *pb = b;
  return *pb - *pa;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compare_int_dec>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  ret
```

assistant: ```c
int compare_int_dec(void const *a, void const *b) {
  int const *pa = a;
  int const *pb = b;
  return *pb - *pa;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<freep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L6
L15:
  nop
L6:
  leave
  ret
```

assistant: ```c
void freep(void *p) {
  if (!p)
    return;
  free(*(void **)p);
  *(void **)p = NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<freep>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
void freep(void *p) {
  if (!p)
    return;
  free(*(void **)p);
  *(void **)p = NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<freep>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void freep(void *p) {
  if (!p)
    return;
  free(*(void **)p);
  *(void **)p = NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<freep>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void freep(void *p) {
  if (!p)
    return;
  free(*(void **)p);
  *(void **)p = NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ElfHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L7
L26:
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  xor    %rax,-0x10(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  not    %rax
  and    %rax,-0x10(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long ElfHash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    g = h & 0xF0000000;
    if (g)
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ElfHash>:
  endbr64
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  movzbl %cl,%edx
  mov    $0x0,%eax
  test   %cl,%cl
  jne    L15
  ret
L11:
  shl    $0x4,%rax
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %rax,%rdx
  mov    %rdx,%rax
  and    $0xf0000000,%eax
  mov    %rax,%rcx
  shr    $0x18,%rcx
  xor    %rdx,%rcx
  test   %rax,%rax
  cmovne %rcx,%rdx
L15:
  not    %rax
  and    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L11
  ret
```

assistant: ```c
unsigned long ElfHash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    g = h & 0xF0000000;
    if (g)
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ElfHash>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L21
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L17:
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rax,%rdx
  mov    %rdx,%rax
  and    $0xf0000000,%eax
  mov    %rax,%rcx
  shr    $0x18,%rcx
  xor    %rdx,%rcx
  test   %rax,%rax
  cmovne %rcx,%rdx
L21:
  not    %rax
  and    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  ret
```

assistant: ```c
unsigned long ElfHash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    g = h & 0xF0000000;
    if (g)
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ElfHash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L16
  nopw   0x0(%rax,%rax,1)
L9:
  shl    $0x4,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L21
  mov    %rdx,%rsi
  not    %rdx
  shr    $0x18,%rsi
  xor    %rsi,%rax
  and    %rdx,%rax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L9
  ret
  xchg   %ax,%ax
L21:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L9
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
  nopl   0x0(%rax)
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long ElfHash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    g = h & 0xF0000000;
    if (g)
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<write_dmatrix_T_k>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x150,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %rcx,-0x130(%rbp)
  mov    %r8,-0x138(%rbp)
  mov    %r9,-0x140(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x148(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    0x18(%rbp),%ecx
  mov    -0x148(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x140(%rbp),%r9
  mov    -0x138(%rbp),%r8
  mov    -0x130(%rbp),%rcx
  mov    -0x128(%rbp),%rdx
  mov    -0x120(%rbp),%rsi
  mov    -0x118(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x110(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <write_dmatrix_T@plt>
  add    $0x10,%rsp
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: %s%02d.txt

assistant: ```c
void write_dmatrix_T_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_T(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_dmatrix_T_k>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  mov    0x168(%rsp),%ecx
  mov    0x160(%rsp),%rdx
  lea    D8(%rip),%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  push   %r15
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    0x18(%rsp),%rdi
  call   <write_dmatrix_T@plt>
  add    $0x10,%rsp
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: %s%02d.txt

assistant: ```c
void write_dmatrix_T_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_T(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_dmatrix_T_k>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D7(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    0x168(%rsp),%ecx
  mov    0x160(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rdi,0x8(%rsp)
  call   <sprintf@plt>
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r15,%r9
  mov    0x10(%rsp),%rdi
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r12,%rsi
  push   %rdi
  mov    %rbp,%rdi
  call   <write_dmatrix_T@plt>
  pop    %rax
  pop    %rdx
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: %s%02d.txt

assistant: ```c
void write_dmatrix_T_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_T(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_dmatrix_T_k>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    0x168(%rsp),%ecx
  mov    0x160(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rdi,0x8(%rsp)
  call   <sprintf@plt>
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r15,%r9
  mov    0x10(%rsp),%rdi
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r12,%rsi
  push   %rdi
  mov    %rbp,%rdi
  call   <write_dmatrix_T@plt>
  pop    %rax
  pop    %rdx
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: %s%02d.txt

assistant: ```c
void write_dmatrix_T_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_T(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cost_iteration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L6
L20:
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L16
L18:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L16:
  cmpl   $0xd,-0x24(%rbp)
  jle    L18
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  0x68(%rax),%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
L6:
  cmpl   $0x1f9,-0x28(%rbp)
  jle    L20
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void cost_iteration(double data[][14], double coeff[14], double cost_fn[10000], int index) {
  int i, j;
  double hypothesis = 0.0;
  double err = 0.0;
  for (i = 0; i < 506; i++) {
    hypothesis = coeff[0];
    for (j = 1; j < 14; j++) {
      hypothesis = hypothesis + coeff[j] * data[i][j - 1];
    }
    err = err + pow((hypothesis - data[i][14 - 1]), 2);
  }
  cost_fn[index] = sqrt(err);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cost_iteration>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %ecx,%r14d
  mov    %rdi,%rbp
  add    $0xdd60,%r12
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L42
L54:
  subsd  0x68(%rdx),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x70,%rbp
  cmp    %r12,%rbp
  je     L15
L42:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdx
  mov    $0x0,%eax
L9:
  movsd  0x8(%rbx,%rax,1),%xmm1
  mulsd  (%rdx,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    $0x68,%rax
  jne    L9
  jmp    L54
L15:
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,8),%rbx
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm3
  ucomisd %xmm3,%xmm0
  ja     L14
  sqrtsd %xmm3,%xmm3
  movapd %xmm3,%xmm0
L53:
  movsd  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L53
```

assistant: ```c
void cost_iteration(double data[][14], double coeff[14], double cost_fn[10000], int index) {
  int i, j;
  double hypothesis = 0.0;
  double err = 0.0;
  for (i = 0; i < 506; i++) {
    hypothesis = coeff[0];
    for (j = 1; j < 14; j++) {
      hypothesis = hypothesis + coeff[j] * data[i][j - 1];
    }
    err = err + pow((hypothesis - data[i][14 - 1]), 2);
  }
  cost_fn[index] = sqrt(err);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cost_iteration>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    0xdd60(%rdi),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movq   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L33:
  movsd  (%r14),%xmm0
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  movsd  0x8(%r14,%rax,1),%xmm1
  mulsd  (%rbx,%rax,1),%xmm1
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  cmp    $0x68,%rax
  jne    L14
  subsd  0x68(%rbx),%xmm0
  mov    $0x2,%edi
  add    $0x70,%rbx
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %rbx,%r13
  jne    L33
  pxor   %xmm4,%xmm4
  lea    (%r12,%rbp,8),%rbx
  movapd %xmm0,%xmm3
  ucomisd %xmm0,%xmm4
  ja     L7
  sqrtsd %xmm3,%xmm3
  movapd %xmm3,%xmm0
L20:
  movsd  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L20
```

assistant: ```c
void cost_iteration(double data[][14], double coeff[14], double cost_fn[10000], int index) {
  int i, j;
  double hypothesis = 0.0;
  double err = 0.0;
  for (i = 0; i < 506; i++) {
    hypothesis = coeff[0];
    for (j = 1; j < 14; j++) {
      hypothesis = hypothesis + coeff[j] * data[i][j - 1];
    }
    err = err + pow((hypothesis - data[i][14 - 1]), 2);
  }
  cost_fn[index] = sqrt(err);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cost_iteration>:
  endbr64
  push   %r14
  lea    0xdd60(%rdi),%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movq   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L15:
  movsd  0x10(%rbp),%xmm1
  mulsd  0x8(%rbx),%xmm1
  mov    $0x2,%edi
  add    $0x70,%rbx
  movsd  0x8(%rbp),%xmm0
  mulsd  -0x70(%rbx),%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  0x60(%rbp),%xmm2
  mulsd  -0x18(%rbx),%xmm2
  addsd  %xmm0,%xmm1
  movsd  0x18(%rbp),%xmm0
  mulsd  -0x60(%rbx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x20(%rbp),%xmm1
  mulsd  -0x58(%rbx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x28(%rbp),%xmm0
  mulsd  -0x50(%rbx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x30(%rbp),%xmm1
  mulsd  -0x48(%rbx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x38(%rbp),%xmm0
  mulsd  -0x40(%rbx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x40(%rbp),%xmm1
  mulsd  -0x38(%rbx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x48(%rbp),%xmm0
  mulsd  -0x30(%rbx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x50(%rbp),%xmm1
  mulsd  -0x28(%rbx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x58(%rbp),%xmm0
  mulsd  -0x20(%rbx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x68(%rbp),%xmm1
  mulsd  -0x10(%rbx),%xmm1
  addsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  subsd  -0x8(%rbx),%xmm0
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %rbx,%r14
  jne    L15
  pxor   %xmm5,%xmm5
  lea    0x0(%r13,%r12,8),%rbx
  movapd %xmm0,%xmm4
  ucomisd %xmm0,%xmm5
  ja     L17
  sqrtsd %xmm4,%xmm4
  movapd %xmm4,%xmm0
L16:
  movsd  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L16
```

assistant: ```c
void cost_iteration(double data[][14], double coeff[14], double cost_fn[10000], int index) {
  int i, j;
  double hypothesis = 0.0;
  double err = 0.0;
  for (i = 0; i < 506; i++) {
    hypothesis = coeff[0];
    for (j = 1; j < 14; j++) {
      hypothesis = hypothesis + coeff[j] * data[i][j - 1];
    }
    err = err + pow((hypothesis - data[i][14 - 1]), 2);
  }
  cost_fn[index] = sqrt(err);
}
```