ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<parse_uint32>:
  endbr64
  movzbl (%rdi),%eax
  mov    %edx,%r11d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L77
  mov    D1(%rip),%rdx
  push   %rbx
  mov    %rsi,%r10
  mov    %ecx,%ebx
  movslq (%rdx),%rsi
  mov    %rsi,%r9
  imul   $0x66666667,%rsi,%rsi
  mov    %r9d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  add    %edx,%edx
  sub    %edx,%r9d
  xor    %edx,%edx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L29:
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%edx
  cmp    %ebx,%edx
  jg     L32
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L9
L43:
  sub    $0x30,%eax
  movsbl %al,%eax
  cmp    %edx,%esi
  jl     L32
  jne    L29
  cmp    %eax,%r9d
  jge    L29
L32:
  mov    D20(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  cmp    %r11d,%edx
  jl     L32
  test   %r8,%r8
  je     L25
  mov    %rdi,(%r8)
L11:
  mov    %edx,(%r10)
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L77:
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  ret
L25:
  test   %al,%al
  je     L11
  mov    D30(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int parse_uint32(const char *str, uint32_t *result, uint32_t min_value, uint32_t max_value, const char **end) {
  uint32_t value = 0;
  char c = *str;
  if (c < '0' || c > '9')
    return EINVAL;
  do {
    uint32_t d = c - '0';
    if (value > UINT32_MAX / 10 || (value == UINT32_MAX / 10 && d > UINT32_MAX % 10))
      return ERANGE;
    value = value * 10 + d;
    if (value > max_value)
      return ERANGE;
    ++str;
    c = *str;
  } while (c >= '0' && c <= '9');
  if (value < min_value)
    return ERANGE;
  if (end)
    *end = str;
  else if (c)
    return EINVAL;
  *result = value;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_uint32>:
  endbr64
  movzbl (%rdi),%eax
  mov    %edx,%r11d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L27
  mov    D35(%rip),%rdx
  push   %rbx
  mov    %rsi,%r10
  mov    %ecx,%ebx
  movslq (%rdx),%rsi
  mov    %rsi,%r9
  imul   $0x66666667,%rsi,%rsi
  mov    %r9d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  add    %edx,%edx
  sub    %edx,%r9d
  xor    %edx,%edx
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L35:
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%edx
  cmp    %ebx,%edx
  jg     L44
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L93
L77:
  sub    $0x30,%eax
  movsbl %al,%eax
  cmp    %edx,%esi
  jl     L44
  jne    L35
  cmp    %eax,%r9d
  jge    L35
L44:
  mov    D16(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L93:
  cmp    %r11d,%edx
  jl     L44
  test   %r8,%r8
  je     L84
  mov    %rdi,(%r8)
L72:
  mov    %edx,(%r10)
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L27:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
L84:
  test   %al,%al
  je     L72
  mov    D9(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int parse_uint32(const char *str, uint32_t *result, uint32_t min_value, uint32_t max_value, const char **end) {
  uint32_t value = 0;
  char c = *str;
  if (c < '0' || c > '9')
    return EINVAL;
  do {
    uint32_t d = c - '0';
    if (value > UINT32_MAX / 10 || (value == UINT32_MAX / 10 && d > UINT32_MAX % 10))
      return ERANGE;
    value = value * 10 + d;
    if (value > max_value)
      return ERANGE;
    ++str;
    c = *str;
  } while (c >= '0' && c <= '9');
  if (value < min_value)
    return ERANGE;
  if (end)
    *end = str;
  else if (c)
    return EINVAL;
  *result = value;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <is_hex_string_valid@plt>
  test   %eax,%eax
  jne    L28
  mov    $0xffffffff,%eax
  jmp    L21
L28:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    $0x78,%al
  jne    L56
  mov    $0x2,%eax
  jmp    L38
L56:
  mov    $0x0,%eax
L38:
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L52
L15:
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hex_char_to_dec@plt>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L52:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x14(%rbp),%eax
L21:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int htoi(char string[]) {
  if (!is_hex_string_valid(string)) {
    return -1;
  }
  int index = (tolower(string[1]) == 'x' ? 2 : 0);
  int result = 0;
  for (; string[index] != '\0'; ++index) {
    result = 16 * result + hex_char_to_dec(string[index]);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<htoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <is_hex_string_valid@plt>
  test   %eax,%eax
  je     L35
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x78,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rax
  movzbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  je     L9
  lea    0x1(%rbx,%rax,1),%rbp
  mov    $0x0,%ebx
L43:
  shl    $0x4,%ebx
  movsbl %dil,%edi
  call   <hex_char_to_dec@plt>
  add    %eax,%ebx
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  test   %dil,%dil
  jne    L43
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0xffffffff,%ebx
  jmp    L3
L9:
  mov    $0x0,%ebx
  jmp    L3
```

assistant: ```c
int htoi(char string[]) {
  if (!is_hex_string_valid(string)) {
    return -1;
  }
  int index = (tolower(string[1]) == 'x' ? 2 : 0);
  int result = 0;
  for (; string[index] != '\0'; ++index) {
    result = 16 * result + hex_char_to_dec(string[index]);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<htoi>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <is_hex_string_valid@plt>
  test   %eax,%eax
  je     L8
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x78,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rax
  movsbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  je     L2
  lea    0x1(%rbx,%rax,1),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L16:
  call   <hex_char_to_dec@plt>
  movsbl 0x0(%rbp),%edi
  shl    $0x4,%ebx
  add    $0x1,%rbp
  add    %eax,%ebx
  test   %dil,%dil
  jne    L16
L15:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  xor    %ebx,%ebx
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0xffffffff,%ebx
  jmp    L15
```

assistant: ```c
int htoi(char string[]) {
  if (!is_hex_string_valid(string)) {
    return -1;
  }
  int index = (tolower(string[1]) == 'x' ? 2 : 0);
  int result = 0;
  for (; string[index] != '\0'; ++index) {
    result = 16 * result + hex_char_to_dec(string[index]);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<htoi>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <is_hex_string_valid@plt>
  test   %eax,%eax
  je     L20
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x78,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rax
  movsbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  je     L37
  lea    0x1(%rbx,%rax,1),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L32:
  call   <hex_char_to_dec@plt>
  movsbl 0x0(%rbp),%edi
  shl    $0x4,%ebx
  add    $0x1,%rbp
  add    %eax,%ebx
  test   %dil,%dil
  jne    L32
L12:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
L37:
  xor    %ebx,%ebx
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0xffffffff,%ebx
  jmp    L12
```

assistant: ```c
int htoi(char string[]) {
  if (!is_hex_string_valid(string)) {
    return -1;
  }
  int index = (tolower(string[1]) == 'x' ? 2 : 0);
  int result = 0;
  for (; string[index] != '\0'; ++index) {
    result = 16 * result + hex_char_to_dec(string[index]);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<obtenerTamanio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,-0x8(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,-0x4(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int obtenerTamanio(FILE *archivo) {
  int posActual, tamanio;
  posActual = ftell(archivo);
  fseek(archivo, 0, SEEK_END);
  tamanio = ftell(archivo);
  fseek(archivo, posActual, SEEK_SET);
  return tamanio;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<obtenerTamanio>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ftell@plt>
  mov    %eax,%r12d
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbx,%rdi
  call   <ftell@plt>
  mov    %eax,%ebp
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int obtenerTamanio(FILE *archivo) {
  int posActual, tamanio;
  posActual = ftell(archivo);
  fseek(archivo, 0, SEEK_END);
  tamanio = ftell(archivo);
  fseek(archivo, posActual, SEEK_SET);
  return tamanio;
}
```
user: What is the c source code of the assembly code below:

```asm
<obtenerTamanio>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ftell@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int obtenerTamanio(FILE *archivo) {
  int posActual, tamanio;
  posActual = ftell(archivo);
  fseek(archivo, 0, SEEK_END);
  tamanio = ftell(archivo);
  fseek(archivo, posActual, SEEK_SET);
  return tamanio;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<obtenerTamanio>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ftell@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int obtenerTamanio(FILE *archivo) {
  int posActual, tamanio;
  posActual = ftell(archivo);
  fseek(archivo, 0, SEEK_END);
  tamanio = ftell(archivo);
  fseek(archivo, posActual, SEEK_SET);
  return tamanio;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<epur_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_whitespaces@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L65
L55:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L50
  movl   $0x1,-0xc(%rbp)
L50:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L63
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L63:
  cmpl   $0x1,-0xc(%rbp)
  jne    L35
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L35
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L35
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  movl   $0x0,-0xc(%rbp)
L35:
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L55
  nop
  nop
  leave
  ret
```

assistant: ```c
void epur_str(char *str) {
  int i;
  char *head;
  int space = 1;
  head = ft_whitespaces(str);
  i = 0;
  while (head[i] != '\0') {
    if (head[i] < 33) {
      space = 1;
    }
    if (head[i] > 32) {
      ft_putchar(head[i]);
    }
    if (space == 1 && head[i] < 33 && head[i + 1] > 32) {
      ft_putchar(' ');
      space = 0;
    }
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<epur_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <ft_whitespaces@plt>
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L45
  mov    %rax,%rbx
  mov    $0x1,%ebp
  mov    $0x1,%r12d
  jmp    L56
L48:
  movsbl %dil,%edi
  call   <ft_putchar@plt>
  cmp    $0x1,%ebp
  je     L20
L9:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L45
L56:
  cmp    $0x20,%dil
  jg     L48
L20:
  mov    %r12d,%ebp
  cmpb   $0x20,(%rbx)
  jg     L9
  cmpb   $0x20,0x1(%rbx)
  jle    L9
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  mov    $0x0,%ebp
  jmp    L9
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void epur_str(char *str) {
  int i;
  char *head;
  int space = 1;
  head = ft_whitespaces(str);
  i = 0;
  while (head[i] != '\0') {
    if (head[i] < 33) {
      space = 1;
    }
    if (head[i] > 32) {
      ft_putchar(head[i]);
    }
    if (space == 1 && head[i] < 33 && head[i + 1] > 32) {
      ft_putchar(' ');
      space = 0;
    }
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<epur_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_whitespaces@plt>
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L16
  mov    %rax,%rbx
  mov    $0x1,%ebp
  jmp    L4
  nopl   0x0(%rax)
L83:
  cmpb   $0x20,(%rbx)
  mov    $0x1,%ebp
  jg     L26
  cmpb   $0x20,0x1(%rbx)
  jg     L46
L26:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L16
L4:
  cmp    $0x20,%dil
  jle    L83
  call   <ft_putchar@plt>
  cmp    $0x1,%ebp
  je     L83
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L4
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L46:
  mov    $0x20,%edi
  xor    %ebp,%ebp
  call   <ft_putchar@plt>
  jmp    L26
```

assistant: ```c
void epur_str(char *str) {
  int i;
  char *head;
  int space = 1;
  head = ft_whitespaces(str);
  i = 0;
  while (head[i] != '\0') {
    if (head[i] < 33) {
      space = 1;
    }
    if (head[i] > 32) {
      ft_putchar(head[i]);
    }
    if (space == 1 && head[i] < 33 && head[i + 1] > 32) {
      ft_putchar(' ');
      space = 0;
    }
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<epur_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_whitespaces@plt>
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L1
  mov    %rax,%rbx
  mov    $0x1,%ebp
  jmp    L6
  nopl   0x0(%rax)
L41:
  cmpb   $0x20,0x1(%rbx)
  mov    $0x1,%ebp
  jg     L50
  nopl   0x0(%rax,%rax,1)
L65:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L1
L6:
  cmp    $0x20,%dil
  jle    L41
  call   <ft_putchar@plt>
  cmp    $0x1,%ebp
  jne    L65
  cmpb   $0x20,(%rbx)
  jle    L41
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L6
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L50:
  mov    $0x20,%edi
  xor    %ebp,%ebp
  call   <ft_putchar@plt>
  jmp    L65
```

assistant: ```c
void epur_str(char *str) {
  int i;
  char *head;
  int space = 1;
  head = ft_whitespaces(str);
  i = 0;
  while (head[i] != '\0') {
    if (head[i] < 33) {
      space = 1;
    }
    if (head[i] > 32) {
      ft_putchar(head[i]);
    }
    if (space == 1 && head[i] < 33 && head[i + 1] > 32) {
      ft_putchar(' ');
      space = 0;
    }
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csc_gettoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
  jmp    L19
L15:
  subl   $0x1,-0x14(%rbp)
  jmp    L38
L32:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x14(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  cmpl   $0x0,-0x14(%rbp)
  je     L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <csc_isdelim@plt>
  test   %eax,%eax
  je     L32
L48:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L36
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
char *csc_gettoken(char *sour, char *buffer, int blen, char *delim) {
  if (*sour == 0) {
    return NULL;
  }
  blen--;
  while (*sour && blen && !csc_isdelim(delim, *sour)) {
    *buffer++ = *sour++;
    blen--;
  }
  *buffer++ = 0;
  if (*sour != 0) {
    sour++;
  }
  return sour;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csc_gettoken>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L20
  mov    %rdi,%r12
  mov    %rcx,%r13
  mov    %rdi,%rbx
  lea    -0x1(%rdx),%r14d
  cmp    $0x1,%edx
  je     L38
L7:
  movsbl %sil,%esi
  mov    %r13,%rdi
  call   <csc_isdelim@plt>
  test   %eax,%eax
  jne    L38
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl -0x1(%rbx),%eax
  mov    %al,-0x1(%rbp)
  movzbl (%rbx),%esi
  lea    (%r14,%r12,1),%eax
  cmp    %ebx,%eax
  je     L38
  test   %sil,%sil
  jne    L7
L38:
  movb   $0x0,0x0(%rbp)
  cmpb   $0x1,(%rbx)
  sbb    $0xffffffffffffffff,%rbx
L39:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    $0x0,%ebx
  jmp    L39
```

assistant: ```c
char *csc_gettoken(char *sour, char *buffer, int blen, char *delim) {
  if (*sour == 0) {
    return NULL;
  }
  blen--;
  while (*sour && blen && !csc_isdelim(delim, *sour)) {
    *buffer++ = *sour++;
    blen--;
  }
  *buffer++ = 0;
  if (*sour != 0) {
    sour++;
  }
  return sour;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<csc_gettoken>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L13
  mov    %rdi,%r12
  mov    %rcx,%r13
  lea    -0x1(%rdx),%r14d
  mov    %rdi,%rbp
  cmp    $0x1,%edx
  jne    L12
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  lea    (%r14,%r12,1),%eax
  movsb  %ds:(%rsi),%es:(%rdi)
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  movsbl (%rsi),%esi
  cmp    %ebp,%eax
  je     L15
  test   %sil,%sil
  je     L15
L12:
  mov    %r13,%rdi
  call   <csc_isdelim@plt>
  test   %eax,%eax
  je     L7
L15:
  movb   $0x0,(%rbx)
  cmpb   $0x1,0x0(%rbp)
  sbb    $0xffffffffffffffff,%rbp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  xor    %ebp,%ebp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *csc_gettoken(char *sour, char *buffer, int blen, char *delim) {
  if (*sour == 0) {
    return NULL;
  }
  blen--;
  while (*sour && blen && !csc_isdelim(delim, *sour)) {
    *buffer++ = *sour++;
    blen--;
  }
  *buffer++ = 0;
  if (*sour != 0) {
    sour++;
  }
  return sour;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<csc_gettoken>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L19
  mov    %rdi,%r12
  mov    %rcx,%r13
  lea    -0x1(%rdx),%r14d
  mov    %rdi,%rbp
  cmp    $0x1,%edx
  jne    L0
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  lea    (%r14,%r12,1),%eax
  movsb  %ds:(%rsi),%es:(%rdi)
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  movsbl (%rsi),%esi
  cmp    %ebp,%eax
  je     L53
  test   %sil,%sil
  je     L53
L0:
  mov    %r13,%rdi
  call   <csc_isdelim@plt>
  test   %eax,%eax
  je     L13
L53:
  movb   $0x0,(%rbx)
  cmpb   $0x1,0x0(%rbp)
  sbb    $0xffffffffffffffff,%rbp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  xor    %ebp,%ebp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *csc_gettoken(char *sour, char *buffer, int blen, char *delim) {
  if (*sour == 0) {
    return NULL;
  }
  blen--;
  while (*sour && blen && !csc_isdelim(delim, *sour)) {
    *buffer++ = *sour++;
    blen--;
  }
  *buffer++ = 0;
  if (*sour != 0) {
    sour++;
  }
  return sour;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<swap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```