ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<nullFilterApply>:
  endbr64
  ret
```

assistant: ```c
float nullFilterApply(void *filter, float input) {
  (void)(filter);
  return input;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nullFilterApply>:
  endbr64
  ret
```

assistant: ```c
float nullFilterApply(void *filter, float input) {
  (void)(filter);
  return input;
}
```
user: What is the c source code of the assembly code below?

```asm
<ramd>:
  endbr64
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jle    L20
  pxor   %xmm12,%xmm12
  cvtsi2sd %edi,%xmm12
  movsd  D85(%rip),%xmm3
  movsd  D104(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  movapd %xmm3,%xmm1
  movsd  D90(%rip),%xmm9
  movapd %xmm3,%xmm4
  movsd  D81(%rip),%xmm8
  movsd  D67(%rip),%xmm7
  movsd  D68(%rip),%xmm2
  movsd  D41(%rip),%xmm6
  movsd  D104(%rip),%xmm5
L16:
  movapd %xmm1,%xmm0
  mulsd  %xmm9,%xmm0
  movapd %xmm0,%xmm10
  subsd  %xmm4,%xmm10
  mulsd  %xmm0,%xmm10
  movapd %xmm0,%xmm11
  subsd  %xmm8,%xmm11
  mulsd  %xmm11,%xmm10
  subsd  %xmm7,%xmm0
  mulsd  %xmm0,%xmm10
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm10
  mulsd  %xmm10,%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm6,%xmm0
  addsd  %xmm5,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm4,%xmm1
  comisd %xmm1,%xmm12
  ja     L16
L9:
  mov    $0x2,%edi
  call   <sqrt@plt>
  add    %eax,%eax
  movslq %eax,%rdx
  imul   $0xffffffffd5f92819,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xd,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  0x8(%rsp),%xmm1
  movsd  D85(%rip),%xmm0
  divsd  %xmm1,%xmm0
  lea    D70(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
L20:
  movsd  D104(%rip),%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D85
type: byte[8]
name: unpack_data
arguments: data_label: D104
type: byte[8]
name: unpack_data
arguments: data_label: D90
type: byte[8]
name: unpack_data
arguments: data_label: D81
type: byte[8]
name: unpack_data
arguments: data_label: D67
type: byte[8]
name: unpack_data
arguments: data_label: D68
type: byte[8]
name: unpack_data
arguments: data_label: D41
type: byte[8]
name: unpack_data
arguments: data_label: D70
type: string

tool: {"D85": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D104": [0x00,0x00,0x00,0x00,0x00,0x3c,0x91,0x40]}

tool: {"D90": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D81": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D67": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D68": [0x00,0x00,0x00,0x00,0x00,0xc0,0x78,0x40]}

tool: {"D41": [0x00,0x00,0x00,0x00,0x80,0xc5,0xd9,0x40]}

tool: D70: %16g


assistant: ```c
void ramd(int times) {
  double n, pi, term, mult, tmp;
  pi = 1103;
  term = 0;
  mult = 1;
  tmp = 0;
  for (n = 1; n < times; n++) {
    tmp = ((4 * n) * (4 * n - 1) * (4 * n - 2) * (4 * n - 3)) / (n * n * n * n * 396 * 396 * 396 * 396);
    mult *= tmp;
    term = mult * (1103 + 26390 * n);
    pi += term;
  }
  pi *= (2 * sqrt(2)) / 9801;
  pi = 1 / pi;
  printf("%16g\n", pi);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ramd>:
  endbr64
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jle    L15
  pxor   %xmm13,%xmm13
  movsd  D47(%rip),%xmm0
  movsd  D97(%rip),%xmm6
  cvtsi2sd %edi,%xmm13
  movsd  D74(%rip),%xmm10
  movsd  D82(%rip),%xmm9
  movsd  D31(%rip),%xmm3
  movapd %xmm0,%xmm4
  movapd %xmm6,%xmm5
  movapd %xmm0,%xmm2
  movsd  D13(%rip),%xmm8
  movsd  D53(%rip),%xmm7
  nopw   0x0(%rax,%rax,1)
L29:
  movapd %xmm2,%xmm1
  mulsd  %xmm10,%xmm1
  movapd %xmm1,%xmm11
  movapd %xmm1,%xmm12
  subsd  %xmm0,%xmm11
  subsd  %xmm9,%xmm12
  mulsd  %xmm1,%xmm11
  subsd  %xmm8,%xmm1
  mulsd  %xmm12,%xmm11
  mulsd  %xmm1,%xmm11
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm11
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm2
  mulsd  %xmm7,%xmm1
  comisd %xmm2,%xmm13
  addsd  %xmm6,%xmm1
  mulsd  %xmm11,%xmm4
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm5
  ja     L29
L18:
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm0
  add    %eax,%eax
  lea    D66(%rip),%rdi
  add    $0x18,%rsp
  movslq %eax,%rdx
  imul   $0xffffffffd5f92819,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0xd,%edx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm5,%xmm1
  divsd  %xmm1,%xmm0
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L15:
  movsd  D97(%rip),%xmm5
  movsd  D47(%rip),%xmm0
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_tag: D47
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D97
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D74
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D82
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D31
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D13
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D53
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D66
datatype: string

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D97": [0x00,0x00,0x00,0x00,0x00,0x3c,0x91,0x40]}

tool: {"D74": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D82": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0xc0,0x78,0x40]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D53": [0x00,0x00,0x00,0x00,0x80,0xc5,0xd9,0x40]}

tool: D66: %16g


assistant: ```c
void ramd(int times) {
  double n, pi, term, mult, tmp;
  pi = 1103;
  term = 0;
  mult = 1;
  tmp = 0;
  for (n = 1; n < times; n++) {
    tmp = ((4 * n) * (4 * n - 1) * (4 * n - 2) * (4 * n - 3)) / (n * n * n * n * 396 * 396 * 396 * 396);
    mult *= tmp;
    term = mult * (1103 + 26390 * n);
    pi += term;
  }
  pi *= (2 * sqrt(2)) / 9801;
  pi = 1 / pi;
  printf("%16g\n", pi);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ramd>:
  endbr64
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jle    L28
  pxor   %xmm13,%xmm13
  movsd  D20(%rip),%xmm0
  movsd  D25(%rip),%xmm6
  cvtsi2sd %edi,%xmm13
  movsd  D88(%rip),%xmm10
  movsd  D35(%rip),%xmm9
  movsd  D6(%rip),%xmm3
  movapd %xmm0,%xmm4
  movapd %xmm6,%xmm5
  movapd %xmm0,%xmm2
  movsd  D87(%rip),%xmm8
  movsd  D49(%rip),%xmm7
  nopw   0x0(%rax,%rax,1)
L11:
  movapd %xmm2,%xmm1
  mulsd  %xmm10,%xmm1
  movapd %xmm1,%xmm11
  movapd %xmm1,%xmm12
  subsd  %xmm0,%xmm11
  subsd  %xmm9,%xmm12
  mulsd  %xmm1,%xmm11
  subsd  %xmm8,%xmm1
  mulsd  %xmm12,%xmm11
  mulsd  %xmm1,%xmm11
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm11
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm2
  mulsd  %xmm7,%xmm1
  comisd %xmm2,%xmm13
  addsd  %xmm6,%xmm1
  mulsd  %xmm11,%xmm4
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm5
  ja     L11
L23:
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm0
  add    %eax,%eax
  lea    D38(%rip),%rdi
  add    $0x18,%rsp
  movslq %eax,%rdx
  imul   $0xffffffffd5f92819,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0xd,%edx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm5,%xmm1
  divsd  %xmm1,%xmm0
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L28:
  movsd  D25(%rip),%xmm5
  movsd  D20(%rip),%xmm0
  jmp    L23
```

tool_calls: name: unpack_data
arguments: tag: D20
type_infered: byte[8]
name: unpack_data
arguments: tag: D25
type_infered: byte[8]
name: unpack_data
arguments: tag: D88
type_infered: byte[8]
name: unpack_data
arguments: tag: D35
type_infered: byte[8]
name: unpack_data
arguments: tag: D6
type_infered: byte[8]
name: unpack_data
arguments: tag: D87
type_infered: byte[8]
name: unpack_data
arguments: tag: D49
type_infered: byte[8]
name: unpack_data
arguments: tag: D38
type_infered: string

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x3c,0x91,0x40]}

tool: {"D88": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0xc0,0x78,0x40]}

tool: {"D87": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D49": [0x00,0x00,0x00,0x00,0x80,0xc5,0xd9,0x40]}

tool: D38: %16g


assistant: ```c
void ramd(int times) {
  double n, pi, term, mult, tmp;
  pi = 1103;
  term = 0;
  mult = 1;
  tmp = 0;
  for (n = 1; n < times; n++) {
    tmp = ((4 * n) * (4 * n - 1) * (4 * n - 2) * (4 * n - 3)) / (n * n * n * n * 396 * 396 * 396 * 396);
    mult *= tmp;
    term = mult * (1103 + 26390 * n);
    pi += term;
  }
  pi *= (2 * sqrt(2)) / 9801;
  pi = 1 / pi;
  printf("%16g\n", pi);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_splitpath2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x400,%edx
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x2f,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x5c,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
L11:
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    $0x400,%edx
  lea    D45(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%rax
  add    $0xff,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  movb   $0x0,(%rax)
  jmp    L8
L23:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    $0x80,%edx
  lea    D45(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  movb   $0x0,(%rax)
L8:
  nop
  leave
  ret
```

assistant: ```c
void _splitpath2(const char *constpath, char *dir, char *fname) {
  static char pathcopy[1024 + 1];
  char *slash;
  strncpy(pathcopy, constpath, 1024);
  slash = strrchr(pathcopy, '/');
  if (!slash)
    slash = strrchr(pathcopy, (int)'\\');
  if (slash != NULL) {
    slash[0] = 0;
    strncpy(dir, pathcopy, 1024);
    dir[255] = 0;
    strncpy(fname, slash + 1, 128);
    fname[128] = 0;
  } else {
    dir[0] = 0;
    strncpy(fname, pathcopy, 128);
    fname[128] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_splitpath2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x400,%edx
  mov    %rdi,%rsi
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L9:
  movb   $0x0,(%rbx)
  mov    $0x400,%edx
  lea    D38(%rip),%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0xff(%r12)
  lea    0x1(%rbx),%rsi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
L11:
  movb   $0x0,0x80(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    $0x5c,%esi
  lea    D38(%rip),%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L9
  movb   $0x0,(%r12)
  mov    $0x80,%edx
  lea    D38(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L11
```

assistant: ```c
void _splitpath2(const char *constpath, char *dir, char *fname) {
  static char pathcopy[1024 + 1];
  char *slash;
  strncpy(pathcopy, constpath, 1024);
  slash = strrchr(pathcopy, '/');
  if (!slash)
    slash = strrchr(pathcopy, (int)'\\');
  if (slash != NULL) {
    slash[0] = 0;
    strncpy(dir, pathcopy, 1024);
    dir[255] = 0;
    strncpy(fname, slash + 1, 128);
    fname[128] = 0;
  } else {
    dir[0] = 0;
    strncpy(fname, pathcopy, 128);
    fname[128] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_splitpath2>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  mov    %r13,%rdi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x400,%edx
  push   %rbx
  sub    $0x8,%rsp
  call   <strncpy@plt>
  mov    $0x2f,%esi
  mov    %r13,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L1:
  movb   $0x0,(%rbx)
  mov    $0x400,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  lea    0x1(%rbx),%rsi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  movb   $0x0,0xff(%r12)
  call   <strncpy@plt>
L2:
  movb   $0x0,0x80(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L7:
  mov    $0x5c,%esi
  mov    %r13,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L1
  movb   $0x0,(%r12)
  mov    $0x80,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L2
```

assistant: ```c
void _splitpath2(const char *constpath, char *dir, char *fname) {
  static char pathcopy[1024 + 1];
  char *slash;
  strncpy(pathcopy, constpath, 1024);
  slash = strrchr(pathcopy, '/');
  if (!slash)
    slash = strrchr(pathcopy, (int)'\\');
  if (slash != NULL) {
    slash[0] = 0;
    strncpy(dir, pathcopy, 1024);
    dir[255] = 0;
    strncpy(fname, slash + 1, 128);
    fname[128] = 0;
  } else {
    dir[0] = 0;
    strncpy(fname, pathcopy, 128);
    fname[128] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_splitpath2>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  mov    %r13,%rdi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x400,%edx
  push   %rbx
  sub    $0x8,%rsp
  call   <strncpy@plt>
  mov    $0x2f,%esi
  mov    %r13,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L2:
  movb   $0x0,(%rbx)
  mov    $0x400,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  lea    0x1(%rbx),%rsi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  movb   $0x0,0xff(%r12)
  call   <strncpy@plt>
L23:
  movb   $0x0,0x80(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L7:
  mov    $0x5c,%esi
  mov    %r13,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L2
  movb   $0x0,(%r12)
  mov    $0x80,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L23
```

assistant: ```c
void _splitpath2(const char *constpath, char *dir, char *fname) {
  static char pathcopy[1024 + 1];
  char *slash;
  strncpy(pathcopy, constpath, 1024);
  slash = strrchr(pathcopy, '/');
  if (!slash)
    slash = strrchr(pathcopy, (int)'\\');
  if (slash != NULL) {
    slash[0] = 0;
    strncpy(dir, pathcopy, 1024);
    dir[255] = 0;
    strncpy(fname, slash + 1, 128);
    fname[128] = 0;
  } else {
    dir[0] = 0;
    strncpy(fname, pathcopy, 128);
    fname[128] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L7
  lea    0x20(%rsp),%rbp
  mov    D62(%rip),%r12d
  mov    $0x0,%ebx
  lea    D16(%rip),%r14
  lea    D64(%rip),%r13
L13:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movd   %r12d,%xmm2
  addss  0x0(%rbp),%xmm2
  movd   %xmm2,%r12d
  mov    0x1c(%rsp),%eax
  add    $0x4,%rbp
  cmp    %eax,%ebx
  jl     L13
L22:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movd   %r12d,%xmm4
  divss  %xmm0,%xmm4
  movss  %xmm4,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm4,%xmm0
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmpl   $0x0,0x1c(%rsp)
  jle    L5
  lea    0x20(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D65(%rip),%r12
L11:
  movss  0x0(%rbp),%xmm0
  add    $0x1,%ebx
  movaps %xmm0,%xmm1
  subss  0xc(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    0x1c(%rsp),%ebx
  jl     L11
L5:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x1c0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    D62(%rip),%r12d
  jmp    L22
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D40
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D62
type_guessed: f32
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D64
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D65
type_guessed: string

tool: D25: How many numbers? 

tool: D40: %d

tool: D62: 0

tool: D16: i = %d x = 

tool: D64: %f

tool: D2: 
Average is: %5.2f



tool: D65: i = %d x = %5.2f d = %5.2f


assistant: ```c
int main() {
  int n, count;
  float avg, d, sum = 0;
  float num[100];
  printf("How many numbers? ");
  scanf("%d", &n);
  printf("\n");
  for (count = 0; count < n; count++) {
    printf("i = %d x = ", count + 1);
    scanf("%f", &num[count]);
    sum += num[count];
  }
  avg = sum / n;
  printf("\nAverage is: %5.2f\n\n", avg);
  for (count = 0; count < n; count++) {
    d = num[count] - avg;
    printf("i = %d x = %5.2f d = %5.2f\n", count + 1, num[count], d);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D50(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L21
  lea    0x20(%rsp),%rbp
  pxor   %xmm0,%xmm0
  xor    %ebx,%ebx
  lea    D14(%rip),%r13
  lea    D48(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L48:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  add    $0x4,%rbp
  movss  0xc(%rsp),%xmm0
  addss  -0x4(%rbp),%xmm0
  cmp    %eax,%ebx
  jl     L48
L45:
  pxor   %xmm1,%xmm1
  lea    D41(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L5
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D42(%rip),%r12
  xchg   %ax,%ax
L56:
  movss  0x0(%rbp),%xmm0
  add    $0x1,%ebx
  mov    %r12,%rdi
  mov    $0x2,%eax
  mov    %ebx,%esi
  add    $0x4,%rbp
  movaps %xmm0,%xmm1
  subss  0xc(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  cmp    0x1c(%rsp),%ebx
  jl     L56
L5:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  pxor   %xmm0,%xmm0
  jmp    L45
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D50
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D48
type_infered: string
name: extract_symbolic_data
arguments: label: D41
type_infered: string
name: extract_symbolic_data
arguments: label: D42
type_infered: string

tool: D50: How many numbers? 

tool: D25: %d

tool: D14: i = %d x = 

tool: D48: %f

tool: D41: 
Average is: %5.2f



tool: D42: i = %d x = %5.2f d = %5.2f


assistant: ```c
int main() {
  int n, count;
  float avg, d, sum = 0;
  float num[100];
  printf("How many numbers? ");
  scanf("%d", &n);
  printf("\n");
  for (count = 0; count < n; count++) {
    printf("i = %d x = ", count + 1);
    scanf("%f", &num[count]);
    sum += num[count];
  }
  avg = sum / n;
  printf("\nAverage is: %5.2f\n\n", avg);
  for (count = 0; count < n; count++) {
    d = num[count] - avg;
    printf("i = %d x = %5.2f d = %5.2f\n", count + 1, num[count], d);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D43(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L4
  lea    0x20(%rsp),%rbp
  pxor   %xmm0,%xmm0
  xor    %ebx,%ebx
  lea    D21(%rip),%r13
  lea    D36(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  add    $0x4,%rbp
  movss  0xc(%rsp),%xmm0
  addss  -0x4(%rbp),%xmm0
  cmp    %eax,%ebx
  jl     L51
L50:
  pxor   %xmm1,%xmm1
  lea    D49(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L21
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D44(%rip),%r12
  xchg   %ax,%ax
L12:
  movss  0x0(%rbp),%xmm0
  add    $0x1,%ebx
  mov    %r12,%rdi
  mov    $0x2,%eax
  mov    %ebx,%esi
  add    $0x4,%rbp
  movaps %xmm0,%xmm1
  subss  0xc(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  cmp    0x1c(%rsp),%ebx
  jl     L12
L21:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  pxor   %xmm0,%xmm0
  jmp    L50
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D43
type_guessed: string
name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string
name: parse_data
arguments: data_label: D49
type_guessed: string
name: parse_data
arguments: data_label: D44
type_guessed: string

tool: D43: How many numbers? 

tool: D28: %d

tool: D21: i = %d x = 

tool: D36: %f

tool: D49: 
Average is: %5.2f



tool: D44: i = %d x = %5.2f d = %5.2f


assistant: ```c
int main() {
  int n, count;
  float avg, d, sum = 0;
  float num[100];
  printf("How many numbers? ");
  scanf("%d", &n);
  printf("\n");
  for (count = 0; count < n; count++) {
    printf("i = %d x = ", count + 1);
    scanf("%f", &num[count]);
    sum += num[count];
  }
  avg = sum / n;
  printf("\nAverage is: %5.2f\n\n", avg);
  for (count = 0; count < n; count++) {
    d = num[count] - avg;
    printf("i = %d x = %5.2f d = %5.2f\n", count + 1, num[count], d);
  }
  return 0;
}
```