user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  js     L12
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D48(%rip),%r12
L42:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jge    L42
L12:
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  js     L124
  lea    0x60(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D34(%rip),%r12
L95:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jge    L95
L124:
  add    0x8(%rsp),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%r10d
  mov    0xc(%rsp),%r11d
  mov    %r10d,%ebx
  add    %r11d,%ebx
  js     L6
  lea    0xb0(%rsp),%rax
  mov    %ebx,%edx
  lea    0xb4(%rsp,%rdx,4),%rdx
L84:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L84
  test   %r10d,%r10d
  js     L122
L27:
  mov    %r11d,%r9d
  lea    0xb4(%rsp,%r9,4),%rsi
  mov    $0x0,%r8d
  not    %r9
  shl    $0x2,%r9
  jmp    L64
L16:
  mov    0x10(%rsp,%r8,4),%edi
  lea    (%r9,%rsi,1),%rax
  lea    0x60(%rsp),%rdx
L125:
  mov    %edi,%ecx
  imul   (%rdx),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rsi,%rax
  jne    L125
L145:
  add    $0x1,%r8
  add    $0x4,%rsi
  cmp    %r8d,%r10d
  jl     L161
L64:
  test   %r11d,%r11d
  jns    L16
  jmp    L145
L161:
  test   %ebx,%ebx
  js     L100
L122:
  mov    $0x0,%ebx
  lea    D48(%rip),%rbp
L47:
  mov    0xb0(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  mov    0xc(%rsp),%eax
  add    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jge    L47
L100:
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x160,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  test   %r10d,%r10d
  jns    L27
  jmp    L100
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string
name: unpack_data
arguments: tag: D42
type_guessed: string
name: unpack_data
arguments: tag: D34
type_guessed: string
name: unpack_data
arguments: tag: D26
type_guessed: string

tool: D5: %d %d


tool: D48: %d 

tool: D42: 


tool: D34: %d

tool: D26: %d


assistant: ```c
int main() {
  int n1, n2, a[20], b[20];
  scanf("%d %d\n", &n1, &n2);
  for (int i = 1; i <= n1 + 1; i++) {
    scanf("%d ", &a[i - 1]);
  }
  scanf("\n");
  for (int j = 1; j <= n2 + 1; j++) {
    scanf("%d", &b[j - 1]);
  }
  printf("%d\n", n1 + n2);
  int m[40];
  for (int q = 0; q <= n1 + n2; q++) {
    m[q] = 0;
  }
  for (int k = 0; k <= n1; k++) {
    for (int l = 0; l <= n2; l++) {
      m[k + l] = m[k + l] + (a[k] * b[l]);
    }
  }
  for (int z = 0; z <= n1 + n2; z++) {
    printf("%d ", m[z]);
  }
  return 0;
}
```