ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<hermint>:
  endbr64
  push   %rbx
  mov    %rdx,%r11
  mov    %rcx,%rbx
  mov    %rsi,%r10
  lea    -0x1(%rdi),%ecx
  xor    %edx,%edx
  jmp    L0
  nopl   (%rax)
L4:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%rsi
  movsd  (%r10,%rsi,8),%xmm1
  comisd %xmm0,%xmm1
  cmovbe %eax,%edx
  cmova  %eax,%ecx
L0:
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jg     L4
  movslq %edx,%rdx
  subsd  (%r10,%rdx,8),%xmm0
  movsd  (%r9,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r8,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rbx,%rdx,8),%xmm1
  pop    %rbx
  mulsd  %xmm1,%xmm0
  addsd  (%r11,%rdx,8),%xmm0
  ret
```

assistant: ```c
double hermint(double xbar, int n, double *x, double *yc1, double *yc2, double *yc3, double *yc4) {
  int klo, khi, k;
  double dx;
  double result;
  klo = 0;
  khi = n - 1;
  while (khi - klo > 1) {
    k = (khi + klo) >> 1;
    if (x[k] > xbar)
      khi = k;
    else
      klo = k;
  }
  dx = xbar - x[klo];
  result = yc1[klo] + dx * (yc2[klo] + dx * (yc3[klo] + dx * yc4[klo]));
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hermint>:
  endbr64
  push   %rbx
  mov    %rdx,%r11
  mov    %rcx,%rbx
  mov    %rsi,%r10
  lea    -0x1(%rdi),%ecx
  xor    %edx,%edx
  jmp    L7
  nopl   (%rax)
L6:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%rsi
  movsd  (%r10,%rsi,8),%xmm1
  comisd %xmm0,%xmm1
  cmovbe %eax,%edx
  cmova  %eax,%ecx
L7:
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jg     L6
  movslq %edx,%rdx
  subsd  (%r10,%rdx,8),%xmm0
  movsd  (%r9,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r8,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rbx,%rdx,8),%xmm1
  pop    %rbx
  mulsd  %xmm1,%xmm0
  addsd  (%r11,%rdx,8),%xmm0
  ret
```

assistant: ```c
double hermint(double xbar, int n, double *x, double *yc1, double *yc2, double *yc3, double *yc4) {
  int klo, khi, k;
  double dx;
  double result;
  klo = 0;
  khi = n - 1;
  while (khi - klo > 1) {
    k = (khi + klo) >> 1;
    if (x[k] > xbar)
      khi = k;
    else
      klo = k;
  }
  dx = xbar - x[klo];
  result = yc1[klo] + dx * (yc2[klo] + dx * (yc3[klo] + dx * yc4[klo]));
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_AND>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <mksym_i32@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <mksym_i32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <func@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <gen_func@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_AND() {
  int res = 0, y = 0, z = 0;
  y = mksym_i32();
  z = mksym_i32();
  res = func(y, z);
  gen_func(y, z, res);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_AND>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mksym_i32@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <mksym_i32@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <func@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <gen_func@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test_AND() {
  int res = 0, y = 0, z = 0;
  y = mksym_i32();
  z = mksym_i32();
  res = func(y, z);
  gen_func(y, z, res);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_AND>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <mksym_i32@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <mksym_i32@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <func@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <gen_func@plt>
```

assistant: ```c
void test_AND() {
  int res = 0, y = 0, z = 0;
  y = mksym_i32();
  z = mksym_i32();
  res = func(y, z);
  gen_func(y, z, res);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int vs[], int i, int j) {
  int t;
  t = vs[i];
  vs[i] = vs[j];
  vs[j] = t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int vs[], int i, int j) {
  int t;
  t = vs[i];
  vs[i] = vs[j];
  vs[j] = t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int vs[], int i, int j) {
  int t;
  t = vs[i];
  vs[i] = vs[j];
  vs[j] = t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int vs[], int i, int j) {
  int t;
  t = vs[i];
  vs[i] = vs[j];
  vs[j] = t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swap_mem_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_mem_int(int *a, int *b) {
  int tmp = *a;
  *a = *b;
  *b = tmp;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap_mem_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap_mem_int(int *a, int *b) {
  int tmp = *a;
  *a = *b;
  *b = tmp;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_mem_int>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap_mem_int(int *a, int *b) {
  int tmp = *a;
  *a = *b;
  *b = tmp;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wait_for_data_from>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3e8,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  cmpq   $0x0,-0x30(%rbp)
  je     L45
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  jmp    L46
L45:
  mov    -0x28(%rbp),%eax
L46:
  mov    %eax,-0x28(%rbp)
L53:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <process_cancel_request@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x10(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L53
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L34
  mov    D11(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L53
L34:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void wait_for_data_from(pid_t pid, FILE *f, int fd) {
  const struct timeval ts_init = {.tv_sec = 0, .tv_usec = 1000};
  struct timeval ts;
  int select_result;
  fd_set read_ready;
  FD_ZERO(&read_ready);
  fd = (f != NULL) ? fileno(f) : fd;
  do {
    process_cancel_request(pid);
    ts = ts_init;
    FD_SET(fd, &read_ready);
    select_result = select(fd + 1, &read_ready, NULL, NULL, &ts);
  } while (select_result == 0 || (select_result == -1 && errno == EINTR));
}
```
user: Translate the below assembly code into C programming language:

```asm
<wait_for_data_from>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <FD_ZERO@plt>
  test   %rbp,%rbp
  je     L46
  mov    %rbp,%rdi
  call   <fileno@plt>
  mov    %eax,%ebx
L46:
  lea    0xc(%rsp),%rbp
L8:
  mov    %r12d,%edi
  call   <process_cancel_request@plt>
  movl   $0x3e8,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  call   <select@plt>
  test   %eax,%eax
  je     L8
  cmp    $0xffffffff,%eax
  jne    L33
  mov    D15(%rip),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L8
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wait_for_data_from(pid_t pid, FILE *f, int fd) {
  const struct timeval ts_init = {.tv_sec = 0, .tv_usec = 1000};
  struct timeval ts;
  int select_result;
  fd_set read_ready;
  FD_ZERO(&read_ready);
  fd = (f != NULL) ? fileno(f) : fd;
  do {
    process_cancel_request(pid);
    ts = ts_init;
    FD_SET(fd, &read_ready);
    select_result = select(fd + 1, &read_ready, NULL, NULL, &ts);
  } while (select_result == 0 || (select_result == -1 && errno == EINTR));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wait_for_data_from>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  test   %r13,%r13
  je     L32
  mov    %r13,%rdi
  call   <fileno@plt>
  mov    %eax,%ebp
L32:
  lea    0x1(%rbp),%r14d
  lea    0x10(%rsp),%r13
  nopl   (%rax)
L39:
  mov    %r12d,%edi
  call   <process_cancel_request@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  movq   $0x3e8,0x10(%rsp)
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r13,%r8
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <select@plt>
  test   %eax,%eax
  je     L39
  cmp    $0xffffffff,%eax
  jne    L29
  mov    D19(%rip),%rax
  mov    D17(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L39
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wait_for_data_from(pid_t pid, FILE *f, int fd) {
  const struct timeval ts_init = {.tv_sec = 0, .tv_usec = 1000};
  struct timeval ts;
  int select_result;
  fd_set read_ready;
  FD_ZERO(&read_ready);
  fd = (f != NULL) ? fileno(f) : fd;
  do {
    process_cancel_request(pid);
    ts = ts_init;
    FD_SET(fd, &read_ready);
    select_result = select(fd + 1, &read_ready, NULL, NULL, &ts);
  } while (select_result == 0 || (select_result == -1 && errno == EINTR));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mpy_ex32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imull  -0x20(%rbp)
  mov    %rax,-0x18(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
extern long mpy_ex32(long a, long b) {
  long edx;
  __asm__("imull %2" : "=a"(a), "=d"(edx) : "rm"(b), "0"(a));
  return edx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D17
type: string

tool: D10: Die Spielfelder tragen von links nach rechts die Nummern 1-9


tool: D17: Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'


assistant: ```c
void info(void) {
  printf("Die Spielfelder tragen von links nach rechts die Nummern 1-9\n");
  printf("Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<info>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D17: Die Spielfelder tragen von links nach rechts die Nummern 1-9


tool: D14: Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'


assistant: ```c
void info(void) {
  printf("Die Spielfelder tragen von links nach rechts die Nummern 1-9\n");
  printf("Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<info>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string

tool: D3: Die Spielfelder tragen von links nach rechts die Nummern 1-9


tool: D18: Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'


assistant: ```c
void info(void) {
  printf("Die Spielfelder tragen von links nach rechts die Nummern 1-9\n");
  printf("Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<info>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D3: Die Spielfelder tragen von links nach rechts die Nummern 1-9


tool: D13: Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'


assistant: ```c
void info(void) {
  printf("Die Spielfelder tragen von links nach rechts die Nummern 1-9\n");
  printf("Der Spieler hat das Zeichen 'X' der Computer das Zeichen 'Y'\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo() {
  int x, y;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int foo() {
  int x, y;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int foo() {
  int x, y;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int foo() {
  int x, y;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x6f0,%rsp
  mov    %rdi,-0x36e8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x36e8(%rbp),%rax
  mov    %rax,-0x36d0(%rbp)
  lea    -0x36c0(%rbp),%rax
  mov    %rax,-0x36c8(%rbp)
  lea    -0x36c0(%rbp),%rax
  mov    $0x36b0,%edx
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x36d4(%rbp)
  jmp    L4
L29:
  movl   $0x4,-0x36d8(%rbp)
  jmp    L26
L71:
  mov    -0x36d0(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xf0,%al
  jbe    L49
  mov    -0x36d0(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xef,%al
  ja     L49
  mov    -0x36c8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x36c8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L69
L49:
  mov    -0x36d0(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xef,%al
  ja     L69
  mov    -0x36d0(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xf0,%al
  jbe    L69
  mov    -0x36c8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x36c8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
L69:
  addq   $0x1,-0x36d0(%rbp)
  addq   $0x1,-0x36c8(%rbp)
  addl   $0x1,-0x36d8(%rbp)
L26:
  cmpl   $0xc3,-0x36d8(%rbp)
  jle    L71
  addl   $0x1,-0x36d4(%rbp)
L4:
  cmpl   $0x45,-0x36d4(%rbp)
  jle    L29
  lea    -0x36c0(%rbp),%rcx
  mov    -0x36e8(%rbp),%rax
  mov    $0x36b0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

assistant: ```c
void filter(unsigned char im[70 * 200]) {
  unsigned char om[70 * 200];
  unsigned char *i = im;
  unsigned char *o = om;
  memset(om, 0xff, sizeof(om));
  int x, y;
  for (y = 0; y < 70; y++) {
    for (x = 4; x < 200 - 4; x++) {
      if ((i[0] > 0xf0) && (i[1] < 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      } else if ((i[0] < 0xf0) && (i[1] > 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      }
      i++;
      o++;
    }
  }
  memmove(im, om, sizeof(om));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<filter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x6c8,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x36b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x36b0,%edx
  mov    $0xff,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0xc0(%rbp),%rsi
  mov    %rbx,%rdi
  lea    0x3480(%rsp),%r8
  jmp    L30
L10:
  cmp    $0xef,%cl
  ja     L64
  cmpb   $0xf0,0x1(%rax)
  jbe    L64
  movb   $0x0,(%rdx)
  movb   $0x0,0x1(%rdx)
L64:
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  je     L75
L85:
  movzbl (%rax),%ecx
  cmp    $0xf0,%cl
  jbe    L10
  cmpb   $0xef,0x1(%rax)
  ja     L64
  movb   $0x0,(%rdx)
  movb   $0x0,0x1(%rdx)
  jmp    L64
L75:
  add    $0xc0,%rdi
  add    $0xc0,%rsi
  cmp    %r8,%rdi
  je     L39
L30:
  lea    -0xc0(%rsi),%rax
  mov    %rdi,%rdx
  jmp    L85
L39:
  mov    %rsp,%rsi
  mov    $0x36b0,%edx
  mov    %rbp,%rdi
  call   <memmove@plt>
  mov    0x36b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x36c8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filter(unsigned char im[70 * 200]) {
  unsigned char om[70 * 200];
  unsigned char *i = im;
  unsigned char *o = om;
  memset(om, 0xff, sizeof(om));
  int x, y;
  for (y = 0; y < 70; y++) {
    for (x = 4; x < 200 - 4; x++) {
      if ((i[0] > 0xf0) && (i[1] < 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      } else if ((i[0] < 0xf0) && (i[1] > 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      }
      i++;
      o++;
    }
  }
  memmove(im, om, sizeof(om));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<filter>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x6c8,%rsp
  mov    $0xff,%esi
  mov    $0x36b0,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x36b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0xc0(%rbp),%rcx
  mov    %r12,%rsi
  lea    0x3480(%rsp),%rdi
L11:
  lea    -0xc0(%rcx),%rax
  mov    %rsi,%rdx
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L7:
  cmpb   $0xef,0x1(%rax)
  ja     L49
L24:
  movb   $0x0,(%rdx)
  movb   $0x0,0x1(%rdx)
L49:
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rcx,%rax
  je     L39
L52:
  cmpb   $0xf0,(%rax)
  ja     L7
  je     L49
  cmpb   $0xf0,0x1(%rax)
  ja     L24
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rcx,%rax
  jne    L52
L39:
  add    $0xc0,%rsi
  lea    0xc0(%rax),%rcx
  cmp    %rdi,%rsi
  jne    L11
  mov    $0x36b0,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  mov    0x36b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x36c8,%rsp
  pop    %rbp
  pop    %r12
  ret
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filter(unsigned char im[70 * 200]) {
  unsigned char om[70 * 200];
  unsigned char *i = im;
  unsigned char *o = om;
  memset(om, 0xff, sizeof(om));
  int x, y;
  for (y = 0; y < 70; y++) {
    for (x = 4; x < 200 - 4; x++) {
      if ((i[0] > 0xf0) && (i[1] < 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      } else if ((i[0] < 0xf0) && (i[1] > 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      }
      i++;
      o++;
    }
  }
  memmove(im, om, sizeof(om));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filter>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x6c8,%rsp
  mov    $0xff,%esi
  mov    $0x36b0,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x36b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0xc0(%rbp),%rcx
  mov    %r12,%rsi
  lea    0x3480(%rsp),%rdi
L36:
  lea    -0xc0(%rcx),%rax
  mov    %rsi,%rdx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L5:
  cmpb   $0xef,0x1(%rax)
  ja     L2
L58:
  movb   $0x0,(%rdx)
  movb   $0x0,0x1(%rdx)
L2:
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rcx,%rax
  je     L22
L19:
  cmpb   $0xf0,(%rax)
  ja     L5
  je     L2
  cmpb   $0xf0,0x1(%rax)
  ja     L58
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rcx,%rax
  jne    L19
L22:
  add    $0xc0,%rsi
  lea    0xc0(%rax),%rcx
  cmp    %rdi,%rsi
  jne    L36
  mov    $0x36b0,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  mov    0x36b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x36c8,%rsp
  pop    %rbp
  pop    %r12
  ret
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filter(unsigned char im[70 * 200]) {
  unsigned char om[70 * 200];
  unsigned char *i = im;
  unsigned char *o = om;
  memset(om, 0xff, sizeof(om));
  int x, y;
  for (y = 0; y < 70; y++) {
    for (x = 4; x < 200 - 4; x++) {
      if ((i[0] > 0xf0) && (i[1] < 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      } else if ((i[0] < 0xf0) && (i[1] > 0xf0)) {
        o[0] = 0;
        o[1] = 0;
      }
      i++;
      o++;
    }
  }
  memmove(im, om, sizeof(om));
}
```