user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L44:
  movss  D73(%rip),%xmm0
  addss  0x1c(%rsp),%xmm0
  movss  %xmm0,0x1c(%rsp)
  call   <f@plt>
  pxor   %xmm7,%xmm7
  comisd %xmm0,%xmm7
  ja     L44
  movss  0x1c(%rsp),%xmm5
  movss  %xmm5,0xc(%rsp)
  addss  D73(%rip),%xmm5
  movss  %xmm5,0x8(%rsp)
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    0x24(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x24(%rsp)
  jle    L4
  mov    $0x0,%ebx
  lea    D67(%rip),%rbp
  jmp    L17
L9:
  movss  (%rsp),%xmm5
  movss  %xmm5,0xc(%rsp)
L36:
  movss  (%rsp),%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd (%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  subss  0x8(%rsp),%xmm0
  call   <fabs@plt>
  movss  D19(%rip),%xmm6
  comiss %xmm0,%xmm6
  jae    L4
  add    $0x1,%ebx
  cmp    %ebx,0x24(%rsp)
  jle    L4
L17:
  movss  0xc(%rsp),%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  movss  0x8(%rsp),%xmm3
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  %xmm2,(%rsp)
  movaps %xmm3,%xmm0
  call   <f@plt>
  movapd %xmm0,%xmm1
  movss  0xc(%rsp),%xmm4
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  (%rsp),%xmm2
  subsd  %xmm0,%xmm2
  movsd  %xmm2,(%rsp)
  movaps %xmm4,%xmm0
  call   <f@plt>
  movq   %xmm0,%r12
  movss  0x8(%rsp),%xmm0
  call   <f@plt>
  movq   %r12,%xmm6
  subsd  %xmm0,%xmm6
  movsd  (%rsp),%xmm1
  divsd  %xmm6,%xmm1
  pxor   %xmm5,%xmm5
  cvtsd2ss %xmm1,%xmm5
  movss  %xmm5,(%rsp)
  movss  0x8(%rsp),%xmm0
  call   <f@plt>
  movq   %xmm0,%r12
  movss  (%rsp),%xmm0
  call   <f@plt>
  movq   %r12,%xmm7
  mulsd  %xmm7,%xmm0
  pxor   %xmm3,%xmm3
  comisd %xmm0,%xmm3
  ja     L9
  movss  (%rsp),%xmm5
  movss  %xmm5,0x8(%rsp)
  jmp    L36
L4:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D73
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D22
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D67
type_infered: string
name: extract_symbolic_data
arguments: data_label: D19
type_infered: f32

tool: D9: Enter approximation ranges

tool: D1: %f%f

tool: {"D73": [0x00,0x00,0x80,0x3f]}

tool: D22: Enter n

tool: D13: %d

tool: D67: %f ------ %f


tool: D19: 0.0001

assistant: ```c
int main() {
  float e = 0.0001, r1, r2, x;
  int i, n;
  printf("Enter approximation ranges");
  scanf("%f%f", &r1, &r2);
  while (f(++r1) < 0)
    ;
  float a, b;
  a = r1;
  b = r1 + 1;
  printf("Enter n\n");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    x = (b * f(a) - a * f(b)) / (f(a) - f(b));
    if (f(b) * f(x) < 0)
      a = x;
    else
      b = x;
    printf("%f ------ %f\n", x, f(x));
    if (fabs(a - b) <= e)
      break;
  }
}
```