ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tokenize>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L61
  test   %r8d,%r8d
  jle    L71
  movslq %esi,%rsi
  mov    %rax,%r10
  xor    %r9d,%r9d
  lea    (%rdi,%rsi,1),%rdi
  jmp    L23
  nop
L4:
  cmp    %r8d,%r9d
  jge    L35
L23:
  movzbl (%rax),%esi
  add    $0x1,%rax
  cmp    %dl,%sil
  jne    L72
  movslq %r9d,%rsi
  movb   $0x0,-0x1(%rax)
  add    $0x1,%r9d
  mov    %r10,(%rcx,%rsi,8)
  mov    %rax,%r10
L72:
  cmp    %rax,%rdi
  jne    L4
L2:
  cmp    %r9d,%r8d
  jle    L35
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %r10,(%rcx,%rax,8)
L35:
  mov    %r9d,%eax
  ret
L61:
  mov    %rdi,%r10
  xor    %r9d,%r9d
  jmp    L2
L71:
  xor    %r9d,%r9d
  jmp    L35
```

assistant: ```c
int tokenize(char *src, int length, char delimiter, char *tokens[], int max_tokens) {
  int tokens_found = 0;
  char *last_token_pos = src;
  while ((length-- > 0) && (tokens_found < max_tokens)) {
    if (*src == delimiter) {
      *src = '\0';
      tokens[tokens_found++] = last_token_pos;
      last_token_pos = src;
      last_token_pos++;
    }
    src++;
  }
  if (tokens_found < max_tokens) {
    tokens[tokens_found++] = last_token_pos;
  }
  return tokens_found;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tokenize>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L54
  test   %r8d,%r8d
  jle    L12
  movslq %esi,%rsi
  mov    %rax,%r10
  xor    %r9d,%r9d
  lea    (%rdi,%rsi,1),%rdi
  jmp    L33
  nop
L19:
  cmp    %r8d,%r9d
  jge    L70
L33:
  movzbl (%rax),%esi
  add    $0x1,%rax
  cmp    %dl,%sil
  jne    L17
  movslq %r9d,%rsi
  movb   $0x0,-0x1(%rax)
  add    $0x1,%r9d
  mov    %r10,(%rcx,%rsi,8)
  mov    %rax,%r10
L17:
  cmp    %rax,%rdi
  jne    L19
L38:
  cmp    %r9d,%r8d
  jle    L70
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %r10,(%rcx,%rax,8)
L70:
  mov    %r9d,%eax
  ret
L54:
  mov    %rdi,%r10
  xor    %r9d,%r9d
  jmp    L38
L12:
  xor    %r9d,%r9d
  jmp    L70
```

assistant: ```c
int tokenize(char *src, int length, char delimiter, char *tokens[], int max_tokens) {
  int tokens_found = 0;
  char *last_token_pos = src;
  while ((length-- > 0) && (tokens_found < max_tokens)) {
    if (*src == delimiter) {
      *src = '\0';
      tokens[tokens_found++] = last_token_pos;
      last_token_pos = src;
      last_token_pos++;
    }
    src++;
  }
  if (tokens_found < max_tokens) {
    tokens[tokens_found++] = last_token_pos;
  }
  return tokens_found;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x98(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <answerHello@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <answerSomething@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x9c(%rbp),%ecx
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x80,%edi
  call   <getTime@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D22
type: string
name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D24
type: string

tool: D25: HelloWorld !!!

tool: D22: Merdeuh!

tool: D31: PAF1

tool: D24: PAF2

assistant: ```c
int main() {
  char format[128] = {0};
  time_t timeInit = NULL;
  struct tm date;
  printf("HelloWorld !!!\n");
  answerHello();
  answerSomething("Merdeuh!");
  printf("PAF1\n");
  getTime(128, format, timeInit, date);
  printf("PAF2\n");
  printf("%s\n", format);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <answerHello@plt>
  lea    D16(%rip),%rdi
  call   <answerSomething@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    $0x80,%edi
  call   <getTime@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D30
type: string
name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D26
type: string

tool: D30: HelloWorld !!!

tool: D16: Merdeuh!

tool: D9: PAF1

tool: D26: PAF2

assistant: ```c
int main() {
  char format[128] = {0};
  time_t timeInit = NULL;
  struct tm date;
  printf("HelloWorld !!!\n");
  answerHello();
  answerSomething("Merdeuh!");
  printf("PAF1\n");
  getTime(128, format, timeInit, date);
  printf("PAF2\n");
  printf("%s\n", format);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  lea    D23(%rip),%rdi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %rsp,%rbp
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <puts@plt>
  xor    %eax,%eax
  call   <answerHello@plt>
  lea    D39(%rip),%rdi
  call   <answerSomething@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    $0x80,%edi
  call   <getTime@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D39
data_type: string
name: disassemble_data
arguments: data_label: D27
data_type: string
name: disassemble_data
arguments: data_label: D24
data_type: string

tool: D23: HelloWorld !!!

tool: D39: Merdeuh!

tool: D27: PAF1

tool: D24: PAF2

assistant: ```c
int main() {
  char format[128] = {0};
  time_t timeInit = NULL;
  struct tm date;
  printf("HelloWorld !!!\n");
  answerHello();
  answerSomething("Merdeuh!");
  printf("PAF1\n");
  getTime(128, format, timeInit, date);
  printf("PAF2\n");
  printf("%s\n", format);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  lea    D38(%rip),%rdi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %rsp,%rbp
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <puts@plt>
  xor    %eax,%eax
  call   <answerHello@plt>
  lea    D11(%rip),%rdi
  call   <answerSomething@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    $0x80,%edi
  call   <getTime@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D38
type_guessed: string
name: retrieve_data
arguments: data_tag: D11
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D38: HelloWorld !!!

tool: D11: Merdeuh!

tool: D22: PAF1

tool: D9: PAF2

assistant: ```c
int main() {
  char format[128] = {0};
  time_t timeInit = NULL;
  struct tm date;
  printf("HelloWorld !!!\n");
  answerHello();
  answerSomething("Merdeuh!");
  printf("PAF1\n");
  getTime(128, format, timeInit, date);
  printf("PAF2\n");
  printf("%s\n", format);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GetStringLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  nop
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
const size_t GetStringLength(const char *str) {
  size_t idx = 0;
  while (str[idx++] != 0)
    ;
  return idx - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetStringLength>:
  endbr64
  mov    $0x0,%eax
L3:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L3
  mov    %rdx,%rax
  ret
```

assistant: ```c
const size_t GetStringLength(const char *str) {
  size_t idx = 0;
  while (str[idx++] != 0)
    ;
  return idx - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetStringLength>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8,%rax
  ret
```

assistant: ```c
const size_t GetStringLength(const char *str) {
  size_t idx = 0;
  while (str[idx++] != 0)
    ;
  return idx - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetStringLength>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L0
  mov    %r8,%rax
  ret
```

assistant: ```c
const size_t GetStringLength(const char *str) {
  size_t idx = 0;
  while (str[idx++] != 0)
    ;
  return idx - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  time_t time_a = 0;
  struct tm *tm;
  tm = localtime(&time_a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  time_t time_a = 0;
  struct tm *tm;
  tm = localtime(&time_a);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <localtime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  time_t time_a = 0;
  struct tm *tm;
  tm = localtime(&time_a);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <localtime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  time_t time_a = 0;
  struct tm *tm;
  tm = localtime(&time_a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L38
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L43
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L13
  jmp    L43
L38:
  nop
L43:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L27
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  jmp    L45
L27:
  mov    $0xffffffff,%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  int s1;
  int s2;
  size_t i = 0;
  do {
    s1 = *str1++;
    s2 = *str2++;
    ++i;
    if (s1 == 0)
      break;
  } while (s1 == s2 && i < len);
  return (s1 < s2) ? -1 : (s1 > s2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strncmp>:
  endbr64
  mov    $0x0,%eax
L5:
  movsbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  add    $0x1,%rax
  test   %ecx,%ecx
  je     L10
  cmp    %r8d,%ecx
  jne    L10
  cmp    %rdx,%rax
  jb     L5
L10:
  mov    $0xffffffff,%eax
  cmp    %ecx,%r8d
  jg     L6
  setl   %al
  movzbl %al,%eax
L6:
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  int s1;
  int s2;
  size_t i = 0;
  do {
    s1 = *str1++;
    s2 = *str2++;
    ++i;
    if (s1 == 0)
      break;
  } while (s1 == s2 && i < len);
  return (s1 < s2) ? -1 : (s1 > s2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    %r8d,%ecx
  jne    L22
  cmp    %rdx,%rax
  jae    L22
L1:
  movsbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  add    $0x1,%rax
  test   %ecx,%ecx
  jne    L33
L22:
  xor    %eax,%eax
  cmp    %r8d,%ecx
  mov    $0xffffffff,%edx
  setg   %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  int s1;
  int s2;
  size_t i = 0;
  do {
    s1 = *str1++;
    s2 = *str2++;
    ++i;
    if (s1 == 0)
      break;
  } while (s1 == s2 && i < len);
  return (s1 < s2) ? -1 : (s1 > s2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    %r8d,%ecx
  jne    L30
  cmp    %rdx,%rax
  jae    L30
L20:
  movsbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  add    $0x1,%rax
  test   %ecx,%ecx
  jne    L23
L30:
  xor    %eax,%eax
  cmp    %r8d,%ecx
  mov    $0xffffffff,%edx
  setg   %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  int s1;
  int s2;
  size_t i = 0;
  do {
    s1 = *str1++;
    s2 = *str2++;
    ++i;
    if (s1 == 0)
      break;
  } while (s1 == s2 && i < len);
  return (s1 < s2) ? -1 : (s1 > s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  test   %eax,%eax
  jle    L3
  mov    -0x24(%rbp),%eax
  test   %eax,%eax
  jle    L3
  mov    $0x1,%eax
  jmp    L38
L3:
  mov    $0x0,%eax
L38:
  mov    %eax,%edi
  call   <assert@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getMatrix@plt>
  mov    %rax,-0x20(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getMatrix@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <addMatrices@plt>
  mov    %rax,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printMatrix@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <deallocateMatrix@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <deallocateMatrix@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <deallocateMatrix@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D37
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D42
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D37: Enter the number of rows and columns: 

tool: D8: %d %d

tool: D21: Enter matrix A:


tool: D42: Enter matrix B:


tool: D5: A + B = 


assistant: ```c
int main() {
  int n = 0, m = 0;
  printf("Enter the number of rows and columns: ");
  scanf("%d %d", &n, &m);
  assert(n > 0 && m > 0);
  printf("Enter matrix A:\n");
  int **A = getMatrix(n, m);
  printf("Enter matrix B:\n");
  int **B = getMatrix(n, m);
  int **C = addMatrices(A, B, n, m);
  printf("A + B = \n");
  printMatrix(C, n, m);
  deallocateMatrix(A, n);
  deallocateMatrix(B, n);
  deallocateMatrix(C, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  cmpl   $0x0,(%rsp)
  jle    L18
  cmpl   $0x0,0x4(%rsp)
  setg   %dil
  movzbl %dil,%edi
L18:
  call   <assert@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <getMatrix@plt>
  mov    %rax,%r12
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <getMatrix@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <addMatrices@plt>
  mov    %rax,%rbx
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <printMatrix@plt>
  mov    (%rsp),%esi
  mov    %r12,%rdi
  call   <deallocateMatrix@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <deallocateMatrix@plt>
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <deallocateMatrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D45
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D43
type_guessed: string
name: unpack_data
arguments: tag: D36
type_guessed: string

tool: D25: Enter the number of rows and columns: 

tool: D45: %d %d

tool: D20: Enter matrix A:


tool: D43: Enter matrix B:


tool: D36: A + B = 


assistant: ```c
int main() {
  int n = 0, m = 0;
  printf("Enter the number of rows and columns: ");
  scanf("%d %d", &n, &m);
  assert(n > 0 && m > 0);
  printf("Enter matrix A:\n");
  int **A = getMatrix(n, m);
  printf("Enter matrix B:\n");
  int **B = getMatrix(n, m);
  int **C = addMatrices(A, B, n, m);
  printf("A + B = \n");
  printMatrix(C, n, m);
  deallocateMatrix(A, n);
  deallocateMatrix(B, n);
  deallocateMatrix(C, n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    D41(%rip),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  jle    L0
  xor    %edi,%edi
  cmpl   $0x0,0x4(%rsp)
  setg   %dil
L0:
  call   <assert@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <getMatrix@plt>
  lea    D34(%rip),%rdi
  mov    %rax,%r13
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <getMatrix@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <addMatrices@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <printMatrix@plt>
  mov    (%rsp),%esi
  mov    %r13,%rdi
  call   <deallocateMatrix@plt>
  mov    (%rsp),%esi
  mov    %r12,%rdi
  call   <deallocateMatrix@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <deallocateMatrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D41
data_type: string
name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D34
data_type: string
name: unpack_data
arguments: label: D9
data_type: string

tool: D12: Enter the number of rows and columns: 

tool: D41: %d %d

tool: D6: Enter matrix A:


tool: D34: Enter matrix B:


tool: D9: A + B = 


assistant: ```c
int main() {
  int n = 0, m = 0;
  printf("Enter the number of rows and columns: ");
  scanf("%d %d", &n, &m);
  assert(n > 0 && m > 0);
  printf("Enter matrix A:\n");
  int **A = getMatrix(n, m);
  printf("Enter matrix B:\n");
  int **B = getMatrix(n, m);
  int **C = addMatrices(A, B, n, m);
  printf("A + B = \n");
  printMatrix(C, n, m);
  deallocateMatrix(A, n);
  deallocateMatrix(B, n);
  deallocateMatrix(C, n);
}
```