user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D76(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x24(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x1c(%rsp)
  call   <printf@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  movss  0x1c(%rsp),%xmm0
  pxor   %xmm4,%xmm4
  ucomiss %xmm4,%xmm0
  jp     L78
  je     L56
L78:
  movss  0x20(%rsp),%xmm1
  movss  D21(%rip),%xmm2
  pxor   %xmm5,%xmm5
  mulss  %xmm0,%xmm2
  movaps %xmm1,%xmm3
  mulss  %xmm1,%xmm3
  mulss  0x24(%rsp),%xmm2
  subss  %xmm2,%xmm3
  comiss %xmm5,%xmm3
  ja     L77
  pxor   %xmm6,%xmm6
  ucomiss %xmm6,%xmm3
  jp     L67
  jne    L67
  addss  %xmm0,%xmm0
  xorps  D20(%rip),%xmm1
  mov    $0x1,%eax
  lea    D45(%rip),%rdi
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
L33:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L77:
  movaps %xmm3,%xmm0
  movss  %xmm1,0x8(%rsp)
  movss  %xmm3,0xc(%rsp)
  call   <sqrt@plt>
  movss  0x8(%rsp),%xmm1
  xorps  D20(%rip),%xmm1
  movss  0xc(%rsp),%xmm3
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  movss  0x1c(%rsp),%xmm0
  addss  %xmm0,%xmm0
  divss  %xmm0,%xmm2
  movaps %xmm3,%xmm0
  movss  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movss  0x8(%rsp),%xmm2
  mov    $0x2,%eax
  lea    D60(%rip),%rdi
  movaps %xmm0,%xmm1
  movss  0x1c(%rsp),%xmm0
  subss  0x20(%rsp),%xmm1
  addss  %xmm0,%xmm0
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  jmp    L33
L67:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L33
L56:
  lea    D80(%rip),%rdi
  call   <puts@plt>
  jmp    L33
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D76
type_infered: string
name: unpack_data
arguments: data_tag: D28
type_infered: string
name: unpack_data
arguments: data_tag: D21
type_infered: f32
name: unpack_data
arguments: data_tag: D20
type_infered: byte[16]
name: unpack_data
arguments: data_tag: D45
type_infered: string
name: unpack_data
arguments: data_tag: D60
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string
name: unpack_data
arguments: data_tag: D80
type_infered: string

tool: D76: Enter coefficients of quadratic equation: 

tool: D28: %f %f %f

tool: D21: 4

tool: {"D20": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D45: Solution: x = %.2f.


tool: D60: Solutions: x1 = %.2f, x2 = %.2f.


tool: D29: There is no solution.

tool: D80: This is a linear equation!

assistant: ```c
int main() {
  float a, b, c;
  a = b = c = 0;
  printf("Enter coefficients of quadratic equation: ");
  scanf("%f %f %f", &a, &b, &c);
  if (a == 0) {
    printf("This is a linear equation!\n");
    return 0;
  }
  float delta = b * b - 4 * a * c;
  if (delta > 0) {
    float x1 = (-b - sqrt(delta)) / (2 * a);
    float x2 = (-b + sqrt(delta)) / (2 * a);
    printf("Solutions: x1 = %.2f, x2 = %.2f.\n", x1, x2);
  } else if (delta == 0) {
    float x = (-b) / (2 * a);
    printf("Solution: x = %.2f.\n", x);
  } else
    printf("There is no solution.\n");
  return 0;
}
```