ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D7(%rip),%rbp
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %ld


assistant: ```c
void print_array(long array[], int length) {
  for (int i = 0; i < length; i++) {
    printf("%ld\n", array[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L14:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: %ld


assistant: ```c
void print_array(long array[], int length) {
  for (int i = 0; i < length; i++) {
    printf("%ld\n", array[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L4:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: %ld


assistant: ```c
void print_array(long array[], int length) {
  for (int i = 0; i < length; i++) {
    printf("%ld\n", array[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<squeeze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L27
L42:
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L57:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L57
L48:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  addl   $0x1,-0x4(%rbp)
  jmp    L69
L23:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L69:
  cmpl   $0x0,-0x4(%rbp)
  jle    L17
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L17:
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void squeeze(char s[], char f[]) {
  int i, j, x;
  x = 0;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 0; f[j] != '\0' && f[j] != s[i]; j++)
      ;
    if (f[j] != '\0')
      x += 1;
    else
      s[i - x] = s[i];
    if (x > 0)
      s[i] = ' ';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<squeeze>:
  endbr64
  movzbl (%rdi),%ecx
  mov    $0x0,%r8d
  mov    $0x0,%r10d
  test   %cl,%cl
  jne    L64
  ret
L50:
  test   %al,%al
  je     L81
  add    $0x1,%r10d
L34:
  test   %r10d,%r10d
  jle    L65
  movb   $0x20,(%rdi,%r8,1)
L65:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  je     L98
L64:
  mov    %r8d,%r9d
  movzbl (%rsi),%eax
  cmp    %cl,%al
  je     L50
  test   %al,%al
  setne  %r11b
  lea    0x1(%rsi),%rdx
  test   %r11b,%r11b
  je     L50
L1:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  cmp    %cl,%al
  je     L50
  test   %al,%al
  jne    L1
  jmp    L50
L81:
  sub    %r10d,%r9d
  movslq %r9d,%r9
  mov    %cl,(%rdi,%r9,1)
  jmp    L34
L98:
  ret
```

assistant: ```c
void squeeze(char s[], char f[]) {
  int i, j, x;
  x = 0;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 0; f[j] != '\0' && f[j] != s[i]; j++)
      ;
    if (f[j] != '\0')
      x += 1;
    else
      s[i - x] = s[i];
    if (x > 0)
      s[i] = ' ';
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<squeeze>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  test   %cl,%cl
  je     L32
  nopl   0x0(%rax)
L47:
  movzbl (%rsi),%eax
  mov    %r8d,%r9d
  test   %al,%al
  je     L7
  lea    0x1(%rsi),%rdx
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L7
L53:
  cmp    %al,%cl
  jne    L8
  add    $0x1,%r10d
L15:
  movb   $0x20,(%rdi,%r8,1)
L33:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L47
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  sub    %r10d,%r9d
  movslq %r9d,%r9
  mov    %cl,(%rdi,%r9,1)
  test   %r10d,%r10d
  je     L33
  jmp    L15
L32:
  ret
```

assistant: ```c
void squeeze(char s[], char f[]) {
  int i, j, x;
  x = 0;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 0; f[j] != '\0' && f[j] != s[i]; j++)
      ;
    if (f[j] != '\0')
      x += 1;
    else
      s[i - x] = s[i];
    if (x > 0)
      s[i] = ' ';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<squeeze>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  test   %cl,%cl
  je     L31
  nopl   0x0(%rax)
L59:
  movzbl (%rsi),%eax
  mov    %r8d,%r9d
  test   %al,%al
  je     L32
  lea    0x1(%rsi),%rdx
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L32
L79:
  cmp    %al,%cl
  jne    L38
  add    $0x1,%r10d
L57:
  movb   $0x20,(%rdi,%r8,1)
L35:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L59
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  sub    %r10d,%r9d
  movslq %r9d,%r9
  mov    %cl,(%rdi,%r9,1)
  test   %r10d,%r10d
  je     L35
  jmp    L57
L31:
  ret
```

assistant: ```c
void squeeze(char s[], char f[]) {
  int i, j, x;
  x = 0;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 0; f[j] != '\0' && f[j] != s[i]; j++)
      ;
    if (f[j] != '\0')
      x += 1;
    else
      s[i - x] = s[i];
    if (x > 0)
      s[i] = ' ';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<wrenUtf8EncodeNumBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L49
  mov    $0x1,%eax
  jmp    L40
L49:
  cmpl   $0x7ff,-0x4(%rbp)
  jg     L60
  mov    $0x2,%eax
  jmp    L40
L60:
  cmpl   $0xffff,-0x4(%rbp)
  jg     L16
  mov    $0x3,%eax
  jmp    L40
L16:
  cmpl   $0x10ffff,-0x4(%rbp)
  jg     L68
  mov    $0x4,%eax
  jmp    L40
L68:
  mov    $0x0,%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int wrenUtf8EncodeNumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrenUtf8EncodeNumBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L3
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L3
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L3
  cmp    $0x10ffff,%edi
  setle  %al
  movzbl %al,%eax
  shl    $0x2,%eax
L3:
  ret
```

assistant: ```c
int wrenUtf8EncodeNumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrenUtf8EncodeNumBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L10
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L10
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L10
  xor    %eax,%eax
  cmp    $0x10ffff,%edi
  setle  %al
  shl    $0x2,%eax
L10:
  ret
```

assistant: ```c
int wrenUtf8EncodeNumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wrenUtf8EncodeNumBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L3
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L3
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L3
  xor    %eax,%eax
  cmp    $0x10ffff,%edi
  setle  %al
  shl    $0x2,%eax
L3:
  ret
```

assistant: ```c
int wrenUtf8EncodeNumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strCompare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L15
  mov    $0x1,%eax
  jmp    L11
L15:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sjhashStrNICmp@plt>
L11:
  leave
  ret
```

assistant: ```c
int strCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return sjhashStrNICmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: What is the c source code of the assembly code below?

```asm
<strCompare>:
  endbr64
  mov    %esi,%r8d
  mov    $0x1,%eax
  cmp    %ecx,%esi
  je     L6
  ret
L6:
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %r8d,%edx
  call   <sjhashStrNICmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int strCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return sjhashStrNICmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: What is the c source code of the assembly code below?

```asm
<strCompare>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rsi
  cmp    %ecx,%r8d
  je     L5
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L5:
  mov    %r8d,%edx
  jmp    1050 <sjhashStrNICmp@plt>
```

assistant: ```c
int strCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return sjhashStrNICmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strCompare>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rsi
  cmp    %ecx,%r8d
  je     L2
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L2:
  mov    %r8d,%edx
  jmp    1050 <sjhashStrNICmp@plt>
```

assistant: ```c
int strCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return sjhashStrNICmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<UPnPRenderingControl_SetVolume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %ax,-0x10(%rbp)
  movzwl -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UPnPResponse_RenderingControl_SetVolume@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);


assistant: ```c
void UPnPRenderingControl_SetVolume(void *upnptoken, unsigned int InstanceID, char *Channel, unsigned short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolume(upnptoken);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UPnPRenderingControl_SetVolume>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzwl %cx,%ecx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <UPnPResponse_RenderingControl_SetVolume@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);


assistant: ```c
void UPnPRenderingControl_SetVolume(void *upnptoken, unsigned int InstanceID, char *Channel, unsigned short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolume(upnptoken);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UPnPRenderingControl_SetVolume>:
  endbr64
  push   %rbp
  movzwl %cx,%ecx
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UPnPResponse_RenderingControl_SetVolume@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);


assistant: ```c
void UPnPRenderingControl_SetVolume(void *upnptoken, unsigned int InstanceID, char *Channel, unsigned short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolume(upnptoken);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UPnPRenderingControl_SetVolume>:
  endbr64
  push   %rbp
  movzwl %cx,%ecx
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UPnPResponse_RenderingControl_SetVolume@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);


assistant: ```c
void UPnPRenderingControl_SetVolume(void *upnptoken, unsigned int InstanceID, char *Channel, unsigned short DesiredVolume) {
  printf("Invoke: UPnPRenderingControl_SetVolume(%u,%s,%u);\r\n", InstanceID, Channel, DesiredVolume);
  UPnPResponse_RenderingControl_SetVolume(upnptoken);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Int2Char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  add    $0x37,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
char Int2Char(int x) {
  if (x < 10)
    return x + '0';
  else
    return (x - 10) + 'A';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Int2Char>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
  ret
```

assistant: ```c
char Int2Char(int x) {
  if (x < 10)
    return x + '0';
  else
    return (x - 10) + 'A';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Int2Char>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
  ret
```

assistant: ```c
char Int2Char(int x) {
  if (x < 10)
    return x + '0';
  else
    return (x - 10) + 'A';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Int2Char>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
  ret
```

assistant: ```c
char Int2Char(int x) {
  if (x < 10)
    return x + '0';
  else
    return (x - 10) + 'A';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pubnub_uname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: POSIX%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "POSIX"
         "%2F"
         "2.1-alpha";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pubnub_uname>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: POSIX%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "POSIX"
         "%2F"
         "2.1-alpha";
}
```
user: Translate the below assembly code into C programming language:

```asm
<pubnub_uname>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: POSIX%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "POSIX"
         "%2F"
         "2.1-alpha";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pubnub_uname>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: POSIX%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "POSIX"
         "%2F"
         "2.1-alpha";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x5000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0xdf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L29
L37:
  movl   $0x0,-0x5ddc(%rbp)
  jmp    L52
L42:
  lea    -0x5de0(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x5de0(%rbp),%edx
  mov    -0x5ddc(%rbp),%eax
  cltq
  mov    %edx,-0x5dd0(%rbp,%rax,4)
  mov    -0x5ddc(%rbp),%eax
  cltq
  movl   $0x0,-0x2ef0(%rbp,%rax,4)
  addl   $0x1,-0x5ddc(%rbp)
L52:
  mov    -0x5de4(%rbp),%eax
  cmp    %eax,-0x5ddc(%rbp)
  jl     L42
  movl   $0x0,-0x5dd8(%rbp)
  movl   $0x0,-0x5ddc(%rbp)
  jmp    L50
L91:
  mov    -0x5ddc(%rbp),%eax
  cltq
  mov    -0x5dd0(%rbp,%rax,4),%edx
  mov    -0x5ddc(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x5dd0(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x5dd4(%rbp)
  mov    -0x5dd4(%rbp),%eax
  cltq
  mov    -0x2ef0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L34
  mov    -0x5dd4(%rbp),%eax
  cltq
  movl   $0x1,-0x2ef0(%rbp,%rax,4)
  addl   $0x1,-0x5dd8(%rbp)
L34:
  addl   $0x1,-0x5ddc(%rbp)
L50:
  mov    -0x5de4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x5ddc(%rbp)
  jl     L91
  mov    -0x5de4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x5dd8(%rbp)
  jne    L68
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L68:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  lea    -0x5de4(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D37
type: string
name: unpack_data
arguments: tag: D28
type: string

tool: D14: %d

tool: D37: Jolly


tool: D28: Not jolly


assistant: ```c
int main() {
  int integers[3000];
  int check[3000];
  int n_int, n;
  int i, diff, count;
  while (scanf("%d", &n_int) == 1) {
    for (i = 0; i < n_int; i++) {
      scanf("%d", &n);
      integers[i] = n;
      check[i] = 0;
    }
    for (count = 0, i = 0; i < n_int - 1; i++) {
      diff = ((integers[i] - integers[i + 1]) > 0) ? (integers[i] - integers[i + 1]) : (-1 * (integers[i] - integers[i + 1]));
      if (!check[diff]) {
        check[diff] = 1;
        count++;
      }
    }
    if (count == n_int - 1)
      printf("Jolly\n");
    else
      printf("Not jolly\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L101:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L101
  sub    $0xde0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x5dd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    D3(%rip),%rbx
  lea    D10(%rip),%r12
  lea    D20(%rip),%r13
  jmp    L11
L7:
  add    $0x4,%rcx
  cmp    %rcx,%rdi
  je     L111
L79:
  mov    (%rcx),%eax
  sub    0x4(%rcx),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  movslq %eax,%rdx
  cmpl   $0x0,0x2ef0(%rsp,%rdx,4)
  jne    L7
  movl   $0x1,0x2ef0(%rsp,%rdx,4)
  add    $0x1,%esi
  jmp    L7
L30:
  mov    $0x0,%esi
L111:
  cmp    %esi,%r8d
  je     L78
  mov    %r12,%rdi
  call   <printf@plt>
L11:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L90
  mov    0x8(%rsp),%eax
  mov    $0x0,%r14d
  test   %eax,%eax
  jle    L4
L123:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,0x10(%rsp,%r14,4)
  movl   $0x0,0x2ef0(%rsp,%r14,4)
  mov    0x8(%rsp),%eax
  add    $0x1,%r14
  cmp    %r14d,%eax
  jg     L123
L4:
  lea    -0x1(%rax),%r8d
  test   %r8d,%r8d
  jle    L30
  lea    0x10(%rsp),%rcx
  lea    -0x2(%rax),%eax
  lea    0x14(%rsp,%rax,4),%rdi
  mov    $0x0,%esi
  jmp    L79
L78:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L11
L90:
  mov    0x5dd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x5de0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string

tool: D3: %d

tool: D10: Not jolly


tool: D20: Jolly


assistant: ```c
int main() {
  int integers[3000];
  int check[3000];
  int n_int, n;
  int i, diff, count;
  while (scanf("%d", &n_int) == 1) {
    for (i = 0; i < n_int; i++) {
      scanf("%d", &n);
      integers[i] = n;
      check[i] = 0;
    }
    for (count = 0, i = 0; i < n_int - 1; i++) {
      diff = ((integers[i] - integers[i + 1]) > 0) ? (integers[i] - integers[i + 1]) : (-1 * (integers[i] - integers[i + 1]));
      if (!check[diff]) {
        check[diff] = 1;
        count++;
      }
    }
    if (count == n_int - 1)
      printf("Jolly\n");
    else
      printf("Not jolly\n");
  }
  return 0;
}
```