ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s2surpa_>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  mov    0x60(%rsp),%r9
  mov    0x68(%rsp),%rcx
  mov    0x70(%rsp),%r8
  mov    0x78(%rsp),%r10
  mov    %r9,0x18(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %r10,(%rsp)
  call   <_s2_f2c2darr@plt>
  mov    (%rsp),%r10
  mov    (%rbx),%esi
  mov    %rax,%rbp
  mov    (%r12),%edx
  push   %r10
  mov    0x20(%rsp),%r9
  mov    %rbp,%rdi
  mov    (%r9),%eax
  mov    (%r15),%r9d
  push   %rax
  mov    0x18(%rsp),%r8
  mov    0x20(%rsp),%rcx
  movss  (%r8),%xmm1
  mov    (%r14),%r8d
  movss  (%rcx),%xmm0
  mov    0x0(%r13),%ecx
  call   <s2surpa@plt>
  mov    (%rbx),%esi
  add    $0x38,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <_s2_free2darr@plt>
```

assistant: ```c
void s2surpa_(float *data, int *nx, int *ny, int *i1, int *i2, int *j1, int *j2, float *datamin, float *datamax, float *tr) {
  float **cdata = _s2_f2c2darr(data, *nx, *ny);
  s2surpa(cdata, *nx, *ny, *i1, *i2, *j1, *j2, *datamin, *datamax, tr);
  _s2_free2darr(cdata, *nx);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<s2surpa_>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  mov    0x60(%rsp),%r9
  mov    0x68(%rsp),%rcx
  mov    0x70(%rsp),%r8
  mov    0x78(%rsp),%r10
  mov    %r9,0x18(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %r10,(%rsp)
  call   <_s2_f2c2darr@plt>
  mov    (%rsp),%r10
  mov    (%rbx),%esi
  mov    %rax,%rbp
  mov    (%r12),%edx
  push   %r10
  mov    0x20(%rsp),%r9
  mov    %rbp,%rdi
  mov    (%r9),%eax
  mov    (%r15),%r9d
  push   %rax
  mov    0x18(%rsp),%r8
  mov    0x20(%rsp),%rcx
  movss  (%r8),%xmm1
  mov    (%r14),%r8d
  movss  (%rcx),%xmm0
  mov    0x0(%r13),%ecx
  call   <s2surpa@plt>
  mov    (%rbx),%esi
  add    $0x38,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <_s2_free2darr@plt>
```

assistant: ```c
void s2surpa_(float *data, int *nx, int *ny, int *i1, int *i2, int *j1, int *j2, float *datamin, float *datamax, float *tr) {
  float **cdata = _s2_f2c2darr(data, *nx, *ny);
  s2surpa(cdata, *nx, *ny, *i1, *i2, *j1, *j2, *datamin, *datamax, tr);
  _s2_free2darr(cdata, *nx);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<transfer_RGBA8888_to_RGB161616>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  imul   -0x4(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rdx
  movslq %eax,%rcx
  imul   $0xffffffff80808081,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x7,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  imul   -0x4(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x4,%rdx
  movslq %eax,%rcx
  imul   $0xffffffff80808081,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x7,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  imul   -0x4(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x8,%rdx
  movslq %eax,%rcx
  imul   $0xffffffff80808081,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x7,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0xc(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGB161616(uint16_t *(*output), unsigned char *input) {
  int y, u, v, opacity, r, g, b;
  opacity = input[3];
  (*output)[0] = (((int)input[0] << 8) | input[0]) * opacity / 0xff;
  (*output)[1] = (((int)input[1] << 8) | input[1]) * opacity / 0xff;
  (*output)[2] = (((int)input[2] << 8) | input[2]) * opacity / 0xff;
  (*output) += 3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transfer_RGBA8888_to_RGB161616>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  movzbl 0x3(%rsi),%esi
  movzbl (%rcx),%edi
  mov    (%rdx),%r8
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  imul   %esi,%eax
  movslq %eax,%rdi
  imul   $0xffffffff80808081,%rdi,%rdi
  shr    $0x20,%rdi
  add    %edi,%eax
  sar    $0x7,%eax
  mov    %eax,(%r8)
  movzbl 0x1(%rcx),%edi
  mov    (%rdx),%r8
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  imul   %esi,%eax
  movslq %eax,%rdi
  imul   $0xffffffff80808081,%rdi,%rdi
  shr    $0x20,%rdi
  add    %edi,%eax
  sar    $0x7,%eax
  mov    %eax,0x4(%r8)
  movzbl 0x2(%rcx),%ecx
  mov    (%rdx),%rdi
  mov    %ecx,%eax
  shl    $0x8,%eax
  or     %ecx,%eax
  imul   %esi,%eax
  movslq %eax,%rcx
  imul   $0xffffffff80808081,%rcx,%rcx
  shr    $0x20,%rcx
  add    %ecx,%eax
  sar    $0x7,%eax
  mov    %eax,0x8(%rdi)
  addq   $0xc,(%rdx)
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGB161616(uint16_t *(*output), unsigned char *input) {
  int y, u, v, opacity, r, g, b;
  opacity = input[3];
  (*output)[0] = (((int)input[0] << 8) | input[0]) * opacity / 0xff;
  (*output)[1] = (((int)input[1] << 8) | input[1]) * opacity / 0xff;
  (*output)[2] = (((int)input[2] << 8) | input[2]) * opacity / 0xff;
  (*output) += 3;
}
```
user: What is the c source code of the assembly code below?

```asm
<transfer_RGBA8888_to_RGB161616>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%r8
  movzbl 0x3(%rsi),%edi
  movzbl (%rsi),%esi
  mov    (%rdx),%rcx
  mov    %esi,%eax
  shl    $0x8,%eax
  add    $0xc,%rcx
  or     %esi,%eax
  mov    $0x80808081,%esi
  imul   %edi,%eax
  imul   %rsi,%rax
  shr    $0x27,%rax
  mov    %eax,-0xc(%rcx)
  movzbl 0x1(%r8),%r9d
  mov    %r9d,%eax
  shl    $0x8,%eax
  or     %r9d,%eax
  imul   %edi,%eax
  imul   %rsi,%rax
  shr    $0x27,%rax
  mov    %eax,-0x8(%rcx)
  movzbl 0x2(%r8),%r8d
  mov    %r8d,%eax
  shl    $0x8,%eax
  or     %r8d,%eax
  imul   %edi,%eax
  imul   %rsi,%rax
  shr    $0x27,%rax
  mov    %eax,-0x4(%rcx)
  mov    %rcx,(%rdx)
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGB161616(uint16_t *(*output), unsigned char *input) {
  int y, u, v, opacity, r, g, b;
  opacity = input[3];
  (*output)[0] = (((int)input[0] << 8) | input[0]) * opacity / 0xff;
  (*output)[1] = (((int)input[1] << 8) | input[1]) * opacity / 0xff;
  (*output)[2] = (((int)input[2] << 8) | input[2]) * opacity / 0xff;
  (*output) += 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transfer_RGBA8888_to_RGB161616>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%r8
  movzbl 0x3(%rsi),%edi
  movzbl (%rsi),%esi
  mov    (%rdx),%rcx
  mov    %esi,%eax
  shl    $0x8,%eax
  add    $0xc,%rcx
  or     %esi,%eax
  mov    $0x80808081,%esi
  imul   %edi,%eax
  imul   %rsi,%rax
  shr    $0x27,%rax
  mov    %eax,-0xc(%rcx)
  movzbl 0x1(%r8),%r9d
  mov    %r9d,%eax
  shl    $0x8,%eax
  or     %r9d,%eax
  imul   %edi,%eax
  imul   %rsi,%rax
  shr    $0x27,%rax
  mov    %eax,-0x8(%rcx)
  movzbl 0x2(%r8),%r8d
  mov    %r8d,%eax
  shl    $0x8,%eax
  or     %r8d,%eax
  imul   %edi,%eax
  imul   %rsi,%rax
  shr    $0x27,%rax
  mov    %eax,-0x4(%rcx)
  mov    %rcx,(%rdx)
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGB161616(uint16_t *(*output), unsigned char *input) {
  int y, u, v, opacity, r, g, b;
  opacity = input[3];
  (*output)[0] = (((int)input[0] << 8) | input[0]) * opacity / 0xff;
  (*output)[1] = (((int)input[1] << 8) | input[1]) * opacity / 0xff;
  (*output)[2] = (((int)input[2] << 8) | input[2]) * opacity / 0xff;
  (*output) += 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<args_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D26
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D52
datatype: string
name: disassemble_data
arguments: data_label: D59
datatype: string
name: disassemble_data
arguments: data_label: D48
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string

tool: D22: Usage: %s [OPTIONS] 


tool: D26: %s - 


tool: 

tool: D13:   -i, --input	input file

tool: D52:   -o, --output	output file

tool: D59:   -f, --format	output format (markdown csv)

tool: D48:   -t, --type	data type (hex int original)

tool: D37:   -h, --help	Give this help list

assistant: ```c
void args_help(const char *argv0) {
  char *argv0_copy = strdup(argv0);
  char *argv0_base = basename(argv0_copy);
  printf("Usage: %s [OPTIONS] \n", argv0_base);
  printf("%s - \n", argv0_base);
  puts("");
  printf("  -i, --input\tinput file\n");
  printf("  -o, --output\toutput file\n");
  printf("  -f, --format\toutput format (markdown csv)\n");
  printf("  -t, --type\tdata type (hex int original)\n");
  printf("  -h, --help\tGive this help list\n");
  puts("");
  free(argv0_copy);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<args_help>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D46(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D46
type_infered: string
name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D39
type_infered: string
name: extract_symbolic_data
arguments: tag: D57
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string

tool: D12: Usage: %s [OPTIONS] 


tool: D15: %s - 


tool: 

tool: D22:   -i, --input	input file

tool: D1:   -o, --output	output file

tool: D39:   -f, --format	output format (markdown csv)

tool: D57:   -t, --type	data type (hex int original)

tool: D11:   -h, --help	Give this help list

assistant: ```c
void args_help(const char *argv0) {
  char *argv0_copy = strdup(argv0);
  char *argv0_base = basename(argv0_copy);
  printf("Usage: %s [OPTIONS] \n", argv0_base);
  printf("%s - \n", argv0_base);
  puts("");
  printf("  -i, --input\tinput file\n");
  printf("  -o, --output\toutput file\n");
  printf("  -f, --format\toutput format (markdown csv)\n");
  printf("  -t, --type\tdata type (hex int original)\n");
  printf("  -h, --help\tGive this help list\n");
  puts("");
  free(argv0_copy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<args_help>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <basename@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D40(%rip),%r12
  mov    %r12,%rdi
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D40
type_infered: string
name: parse_data
arguments: tag: D37
type_infered: string
name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D22
type_infered: string
name: parse_data
arguments: tag: D60
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string

tool: D0: Usage: %s [OPTIONS] 


tool: D11: %s - 


tool: 

tool: D37:   -i, --input	input file

tool: D14:   -o, --output	output file

tool: D22:   -f, --format	output format (markdown csv)

tool: D60:   -t, --type	data type (hex int original)

tool: D23:   -h, --help	Give this help list

assistant: ```c
void args_help(const char *argv0) {
  char *argv0_copy = strdup(argv0);
  char *argv0_base = basename(argv0_copy);
  printf("Usage: %s [OPTIONS] \n", argv0_base);
  printf("%s - \n", argv0_base);
  puts("");
  printf("  -i, --input\tinput file\n");
  printf("  -o, --output\toutput file\n");
  printf("  -f, --format\toutput format (markdown csv)\n");
  printf("  -t, --type\tdata type (hex int original)\n");
  printf("  -h, --help\tGive this help list\n");
  puts("");
  free(argv0_copy);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<args_help>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <basename@plt>
  lea    D63(%rip),%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D30(%rip),%r12
  mov    %r12,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D63
type: string
name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D30
type: string
name: retrieve_data
arguments: tag: D49
type: string
name: retrieve_data
arguments: tag: D56
type: string
name: retrieve_data
arguments: tag: D57
type: string
name: retrieve_data
arguments: tag: D38
type: string
name: retrieve_data
arguments: tag: D6
type: string

tool: D63: Usage: %s [OPTIONS] 


tool: D25: %s - 


tool: 

tool: D49:   -i, --input	input file

tool: D56:   -o, --output	output file

tool: D57:   -f, --format	output format (markdown csv)

tool: D38:   -t, --type	data type (hex int original)

tool: D6:   -h, --help	Give this help list

assistant: ```c
void args_help(const char *argv0) {
  char *argv0_copy = strdup(argv0);
  char *argv0_base = basename(argv0_copy);
  printf("Usage: %s [OPTIONS] \n", argv0_base);
  printf("%s - \n", argv0_base);
  puts("");
  printf("  -i, --input\tinput file\n");
  printf("  -o, --output\toutput file\n");
  printf("  -f, --format\toutput format (markdown csv)\n");
  printf("  -t, --type\tdata type (hex int original)\n");
  printf("  -h, --help\tGive this help list\n");
  puts("");
  free(argv0_copy);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <copy_it@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(int argc, char argv[]) {
  char buffer[200];
  read(0, buffer, 200);
  copy_it(buffer, 200);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xc8,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <copy_it@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char argv[]) {
  char buffer[200];
  read(0, buffer, 200);
  copy_it(buffer, 200);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  mov    $0xc8,%edx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <read@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <copy_it@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char argv[]) {
  char buffer[200];
  read(0, buffer, 200);
  copy_it(buffer, 200);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  mov    $0xc8,%edx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <read@plt>
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <copy_it@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char argv[]) {
  char buffer[200];
  read(0, buffer, 200);
  copy_it(buffer, 200);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpuid_width_fixed_counters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0xc(%rbp)
  lea    -0x10(%rbp),%rdi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <cpuid@plt>
  mov    -0x10(%rbp),%eax
  sar    $0x5,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int cpuid_width_fixed_counters(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rdx) & ((((uint64_t)1 << (((12)) - ((5)) + 1)) - 1) << ((5)))) >> (5));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpuid_width_fixed_counters>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0xa,%edi
  call   <cpuid@plt>
  mov    0x14(%rsp),%eax
  sar    $0x5,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_width_fixed_counters(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rdx) & ((((uint64_t)1 << (((12)) - ((5)) + 1)) - 1) << ((5)))) >> (5));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpuid_width_fixed_counters>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x14(%rsp),%eax
  sar    $0x5,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_width_fixed_counters(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rdx) & ((((uint64_t)1 << (((12)) - ((5)) + 1)) - 1) << ((5)))) >> (5));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cpuid_width_fixed_counters>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x14(%rsp),%eax
  sar    $0x5,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_width_fixed_counters(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rdx) & ((((uint64_t)1 << (((12)) - ((5)) + 1)) - 1) << ((5)))) >> (5));
}
```