ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_strupr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  mov    %r12,%rbx
  nopl   0x0(%rax)
L6:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L6
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *_strupr(char *n) {
  const char *m = n;
  while (*n != '\0') {
    *n = toupper(*n);
    n++;
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_strupr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L17
  mov    %r12,%rbx
  nopl   0x0(%rax)
L13:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L13
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *_strupr(char *n) {
  const char *m = n;
  while (*n != '\0') {
    *n = toupper(*n);
    n++;
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arch_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0x73,-0x4(%rbp)
  je     L7
  mov    $0x0,%eax
  call   <s5pv210_wdt_reset@plt>
L7:
  mov    $0x0,%edi
  call   <cpu_reset@plt>
  nop
  leave
  ret
```

assistant: ```c
void arch_reset(char mode, const char *cmd) {
  if (mode != 's')
    s5pv210_wdt_reset();
  cpu_reset(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<arch_reset>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x73,%dil
  jne    L17
L18:
  mov    $0x0,%edi
  call   <cpu_reset@plt>
  add    $0x8,%rsp
  ret
L17:
  mov    $0x0,%eax
  call   <s5pv210_wdt_reset@plt>
  jmp    L18
```

assistant: ```c
void arch_reset(char mode, const char *cmd) {
  if (mode != 's')
    s5pv210_wdt_reset();
  cpu_reset(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arch_reset>:
  endbr64
  cmp    $0x73,%dil
  jne    L0
  xor    %edi,%edi
  jmp    1070 <cpu_reset@plt>
  nopl   0x0(%rax)
L0:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <s5pv210_wdt_reset@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <cpu_reset@plt>
```

assistant: ```c
void arch_reset(char mode, const char *cmd) {
  if (mode != 's')
    s5pv210_wdt_reset();
  cpu_reset(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<arch_reset>:
  endbr64
  cmp    $0x73,%dil
  jne    L2
  xor    %edi,%edi
  jmp    1070 <cpu_reset@plt>
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <s5pv210_wdt_reset@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <cpu_reset@plt>
```

assistant: ```c
void arch_reset(char mode, const char *cmd) {
  if (mode != 's')
    s5pv210_wdt_reset();
  cpu_reset(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1c,%ecx
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    $0x15,%edi
  call   <setbits@plt>
  cmp    $0x11,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  assert(setbits(21, 4, 3, 28) == 17);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c,%ecx
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    $0x15,%edi
  call   <setbits@plt>
  cmp    $0x11,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(setbits(21, 4, 3, 28) == 17);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c,%ecx
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    $0x15,%edi
  call   <setbits@plt>
  xor    %edi,%edi
  cmp    $0x11,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(setbits(21, 4, 3, 28) == 17);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c,%ecx
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    $0x15,%edi
  call   <setbits@plt>
  xor    %edi,%edi
  cmp    $0x11,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(setbits(21, 4, 3, 28) == 17);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rgb482uyvy>:
  endbr64
  lea    (%rdx,%rdx,2),%eax
  lea    -0x1(%rax,%rax,1),%eax
  test   %eax,%eax
  jle    L2
  movslq %eax,%rcx
  push   %r12
  lea    -0x1(%rdx,%rdx,1),%edx
  add    %rdi,%rcx
  push   %rbp
  movslq %edx,%rdx
  push   %rbx
  sub    %ecx,%eax
  lea    (%rsi,%rdx,1),%r8
  mov    %eax,%edi
  nopl   0x0(%rax)
L3:
  movzbl -0x3(%rcx),%ebx
  movzbl -0x5(%rcx),%edx
  movzbl -0x1(%rcx),%r11d
  movzbl -0x7(%rcx),%r9d
  imul   $0x259,%ebx,%ebp
  movzbl -0x9(%rcx),%r10d
  movzbl -0xb(%rcx),%eax
  imul   $0x132,%edx,%esi
  imul   $0xfffffe53,%r10d,%r12d
  add    %ebp,%esi
  imul   $0x75,%r11d,%ebp
  add    %ebp,%esi
  mov    %edx,%ebp
  sar    $0xa,%esi
  shl    $0x9,%ebp
  imul   $0xffffff54,%edx,%edx
  mov    %sil,(%r8)
  imul   $0xfffffe53,%ebx,%esi
  imul   $0xfffffeac,%ebx,%ebx
  add    %esi,%ebp
  imul   $0xffffffad,%r11d,%esi
  shl    $0x9,%r11d
  add    %ebx,%edx
  add    %r11d,%edx
  add    %esi,%ebp
  mov    %eax,%esi
  sar    $0xa,%edx
  shl    $0x9,%esi
  sar    $0xa,%ebp
  add    %r12d,%esi
  imul   $0xffffffad,%r9d,%r12d
  add    %r12d,%esi
  sar    $0xa,%esi
  lea    0x100(%rbp,%rsi,1),%esi
  sar    %esi
  imul   $0x259,%r10d,%ebp
  mov    %sil,-0x1(%r8)
  imul   $0x132,%eax,%esi
  imul   $0xffffff54,%eax,%eax
  add    %ebp,%esi
  imul   $0x75,%r9d,%ebp
  add    %ebp,%esi
  sar    $0xa,%esi
  imul   $0xfffffeac,%r10d,%r10d
  shl    $0x9,%r9d
  sub    $0xc,%rcx
  mov    %sil,-0x2(%r8)
  sub    $0x4,%r8
  add    %r10d,%eax
  add    %r9d,%eax
  sar    $0xa,%eax
  lea    0x100(%rdx,%rax,1),%eax
  sar    %eax
  mov    %al,0x1(%r8)
  lea    (%rdi,%rcx,1),%eax
  test   %eax,%eax
  jg     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void rgb482uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels) {
  register int i = ((NumPixels + (NumPixels << 1)) << 1) - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1, u0, u1, v0, v1;
  register int r, g, b;
  while (i > 0) {
    i--;
    b = (unsigned char)src[i--];
    i--;
    g = (unsigned char)src[i--];
    i--;
    r = (unsigned char)src[i--];
    i--;
    y0 = (306 * r + 601 * g + 117 * b) >> 10;
    u0 = ((-172 * r - 340 * g + 512 * b) >> 10) + 128;
    v0 = ((512 * r - 429 * g - 83 * b) >> 10) + 128;
    y0 = y0 < 0 ? 0 : y0;
    u0 = u0 < 0 ? 0 : u0;
    v0 = v0 < 0 ? 0 : v0;
    y0 = y0 > 255 ? 255 : y0;
    u0 = u0 > 255 ? 255 : u0;
    v0 = v0 > 255 ? 255 : v0;
    b = (unsigned char)src[i--];
    i--;
    g = (unsigned char)src[i--];
    i--;
    r = (unsigned char)src[i--];
    y1 = (306 * r + 601 * g + 117 * b) >> 10;
    u1 = ((-172 * r - 340 * g + 512 * b) >> 10) + 128;
    v1 = ((512 * r - 429 * g - 83 * b) >> 10) + 128;
    y1 = y1 < 0 ? 0 : y1;
    u1 = u1 < 0 ? 0 : u1;
    v1 = v1 < 0 ? 0 : v1;
    y1 = y1 > 255 ? 255 : y1;
    u1 = u1 > 255 ? 255 : u1;
    v1 = v1 > 255 ? 255 : v1;
    dest[j--] = y0;
    dest[j--] = (v0 + v1) >> 1;
    dest[j--] = y1;
    dest[j--] = (u0 + u1) >> 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rgb482uyvy>:
  endbr64
  lea    (%rdx,%rdx,2),%eax
  lea    -0x1(%rax,%rax,1),%eax
  test   %eax,%eax
  jle    L8
  movslq %eax,%rcx
  push   %r12
  lea    -0x1(%rdx,%rdx,1),%edx
  add    %rdi,%rcx
  push   %rbp
  movslq %edx,%rdx
  push   %rbx
  sub    %ecx,%eax
  lea    (%rsi,%rdx,1),%r8
  mov    %eax,%edi
  nopl   0x0(%rax)
L15:
  movzbl -0x3(%rcx),%ebx
  movzbl -0x5(%rcx),%edx
  movzbl -0x1(%rcx),%r11d
  movzbl -0x7(%rcx),%r9d
  imul   $0x259,%ebx,%ebp
  movzbl -0x9(%rcx),%r10d
  movzbl -0xb(%rcx),%eax
  imul   $0x132,%edx,%esi
  imul   $0xfffffe53,%r10d,%r12d
  add    %ebp,%esi
  imul   $0x75,%r11d,%ebp
  add    %ebp,%esi
  mov    %edx,%ebp
  sar    $0xa,%esi
  shl    $0x9,%ebp
  imul   $0xffffff54,%edx,%edx
  mov    %sil,(%r8)
  imul   $0xfffffe53,%ebx,%esi
  imul   $0xfffffeac,%ebx,%ebx
  add    %esi,%ebp
  imul   $0xffffffad,%r11d,%esi
  shl    $0x9,%r11d
  add    %ebx,%edx
  add    %r11d,%edx
  add    %esi,%ebp
  mov    %eax,%esi
  sar    $0xa,%edx
  shl    $0x9,%esi
  sar    $0xa,%ebp
  add    %r12d,%esi
  imul   $0xffffffad,%r9d,%r12d
  add    %r12d,%esi
  sar    $0xa,%esi
  lea    0x100(%rbp,%rsi,1),%esi
  sar    %esi
  imul   $0x259,%r10d,%ebp
  mov    %sil,-0x1(%r8)
  imul   $0x132,%eax,%esi
  imul   $0xffffff54,%eax,%eax
  add    %ebp,%esi
  imul   $0x75,%r9d,%ebp
  add    %ebp,%esi
  sar    $0xa,%esi
  imul   $0xfffffeac,%r10d,%r10d
  shl    $0x9,%r9d
  sub    $0xc,%rcx
  mov    %sil,-0x2(%r8)
  sub    $0x4,%r8
  add    %r10d,%eax
  add    %r9d,%eax
  sar    $0xa,%eax
  lea    0x100(%rdx,%rax,1),%eax
  sar    %eax
  mov    %al,0x1(%r8)
  lea    (%rdi,%rcx,1),%eax
  test   %eax,%eax
  jg     L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void rgb482uyvy(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels) {
  register int i = ((NumPixels + (NumPixels << 1)) << 1) - 1;
  register int j = (NumPixels << 1) - 1;
  register int y0, y1, u0, u1, v0, v1;
  register int r, g, b;
  while (i > 0) {
    i--;
    b = (unsigned char)src[i--];
    i--;
    g = (unsigned char)src[i--];
    i--;
    r = (unsigned char)src[i--];
    i--;
    y0 = (306 * r + 601 * g + 117 * b) >> 10;
    u0 = ((-172 * r - 340 * g + 512 * b) >> 10) + 128;
    v0 = ((512 * r - 429 * g - 83 * b) >> 10) + 128;
    y0 = y0 < 0 ? 0 : y0;
    u0 = u0 < 0 ? 0 : u0;
    v0 = v0 < 0 ? 0 : v0;
    y0 = y0 > 255 ? 255 : y0;
    u0 = u0 > 255 ? 255 : u0;
    v0 = v0 > 255 ? 255 : v0;
    b = (unsigned char)src[i--];
    i--;
    g = (unsigned char)src[i--];
    i--;
    r = (unsigned char)src[i--];
    y1 = (306 * r + 601 * g + 117 * b) >> 10;
    u1 = ((-172 * r - 340 * g + 512 * b) >> 10) + 128;
    v1 = ((512 * r - 429 * g - 83 * b) >> 10) + 128;
    y1 = y1 < 0 ? 0 : y1;
    u1 = u1 < 0 ? 0 : u1;
    v1 = v1 < 0 ? 0 : v1;
    y1 = y1 > 255 ? 255 : y1;
    u1 = u1 > 255 ? 255 : u1;
    v1 = v1 > 255 ? 255 : v1;
    dest[j--] = y0;
    dest[j--] = (v0 + v1) >> 1;
    dest[j--] = y1;
    dest[j--] = (u0 + u1) >> 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stbi_png_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L15
L17:
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <stbi_png_info_from_file@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: rb

assistant: ```c
int stbi_png_info(char const *filename, int *x, int *y, int *comp) {
  int res;
  FILE *f = fopen(filename, "rb");
  if (!f)
    return 0;
  res = stbi_png_info_from_file(f, x, y, comp);
  fclose(f);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi_png_info>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%r14
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L0
  mov    %rax,%rbx
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <stbi_png_info_from_file@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <fclose@plt>
L0:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: rb

assistant: ```c
int stbi_png_info(char const *filename, int *x, int *y, int *comp) {
  int res;
  FILE *f = fopen(filename, "rb");
  if (!f)
    return 0;
  res = stbi_png_info_from_file(f, x, y, comp);
  fclose(f);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<stbi_png_info>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  lea    D8(%rip),%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <stbi_png_info_from_file@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fclose@plt>
L7:
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: rb

assistant: ```c
int stbi_png_info(char const *filename, int *x, int *y, int *comp) {
  int res;
  FILE *f = fopen(filename, "rb");
  if (!f)
    return 0;
  res = stbi_png_info_from_file(f, x, y, comp);
  fclose(f);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi_png_info>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  lea    D2(%rip),%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <stbi_png_info_from_file@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fclose@plt>
L0:
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: rb

assistant: ```c
int stbi_png_info(char const *filename, int *x, int *y, int *comp) {
  int res;
  FILE *f = fopen(filename, "rb");
  if (!f)
    return 0;
  res = stbi_png_info_from_file(f, x, y, comp);
  fclose(f);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<asm_normalise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L137
L50:
  addl   $0x1,-0x8(%rbp)
L130:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L50
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L50
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L50
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L50
  jmp    L28
L40:
  addl   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L116
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  je     L40
L116:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x40,-0x9(%rbp)
  jle    L36
  cmpb   $0x5a,-0x9(%rbp)
  jg     L36
  movzbl -0x9(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0x9(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D17(%rip),%rcx
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax,%rcx,1)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L137:
  cmpl   $0x7cf,-0x4(%rbp)
  jg     L37
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L37
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L130
L37:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D17(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D17(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *asm_normalise(const char *asm_str) {
  static char norm_str[2000 + 1];
  int source, dest;
  char chr;
  source = 0;
  dest = 0;
  while (dest < 2000 && asm_str[source] != '\0' && asm_str[source] != ';' && asm_str[source] != '#') {
    while (asm_str[source] == ' ' || asm_str[source] == '\t' || asm_str[source] == '\n' || asm_str[source] == '\r')
      source++;
    while (asm_str[source] == '\\' && asm_str[source + 1] == '|')
      source++;
    chr = asm_str[source];
    if (chr >= 'A' && chr <= 'Z')
      chr = chr - 'A' + 'a';
    norm_str[dest] = chr;
    source++;
    dest++;
  }
  norm_str[dest] = '\0';
  return norm_str;
}
```
user: What is the c source code of the assembly code below:

```asm
<asm_normalise>:
  endbr64
  mov    %rdi,%rsi
  lea    D7(%rip),%r10
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  movabs $0x800000800000001,%r11
  movabs $0x100002600,%rdi
  jmp    L60
L35:
  add    $0x1,%rax
  bt     %rdx,%rdi
  jae    L72
L21:
  mov    %eax,%ecx
  movzbl (%rsi,%rax,1),%edx
  cmp    $0x20,%dl
  jbe    L35
L72:
  movslq %ecx,%rax
  movzbl (%rsi,%rax,1),%r8d
  cmp    $0x5c,%r8b
  jne    L133
  lea    0x1(%rsi,%rax,1),%rax
L100:
  cmpb   $0x7c,(%rax)
  jne    L34
  add    $0x1,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rax),%edx
  cmp    $0x5c,%dl
  je     L100
L5:
  lea    -0x41(%rdx),%eax
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%al
  cmovae %edx,%r8d
L34:
  mov    %r8b,(%r10)
  add    $0x1,%ecx
  add    $0x1,%r9d
  add    $0x1,%r10
  cmp    $0x7d0,%r9d
  je     L7
L60:
  movslq %ecx,%rax
  movzbl (%rsi,%rax,1),%eax
  cmp    $0x3b,%al
  ja     L96
  bt     %rax,%r11
  jb     L7
L96:
  cmp    $0x20,%al
  ja     L72
  bt     %rax,%rdi
  jae    L22
  lea    0x1(%rcx),%eax
  cltq
  jmp    L21
L133:
  mov    %r8d,%edx
  jmp    L5
L22:
  movslq %ecx,%rax
  movzbl (%rsi,%rax,1),%edx
  jmp    L5
L7:
  lea    D7(%rip),%rax
  movslq %r9d,%r9
  movb   $0x0,(%rax,%r9,1)
  ret
```

assistant: ```c
char *asm_normalise(const char *asm_str) {
  static char norm_str[2000 + 1];
  int source, dest;
  char chr;
  source = 0;
  dest = 0;
  while (dest < 2000 && asm_str[source] != '\0' && asm_str[source] != ';' && asm_str[source] != '#') {
    while (asm_str[source] == ' ' || asm_str[source] == '\t' || asm_str[source] == '\n' || asm_str[source] == '\r')
      source++;
    while (asm_str[source] == '\\' && asm_str[source + 1] == '|')
      source++;
    chr = asm_str[source];
    if (chr >= 'A' && chr <= 'Z')
      chr = chr - 'A' + 'a';
    norm_str[dest] = chr;
    source++;
    dest++;
  }
  norm_str[dest] = '\0';
  return norm_str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<asm_normalise>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  xor    %r11d,%r11d
  xor    %esi,%esi
  push   %rbx
  lea    D8(%rip),%r12
  movabs $0xf7fffff7fffffffe,%rbx
  movabs $0xfffffffeffffd9ff,%r10
  nopw   0x0(%rax,%rax,1)
L109:
  movslq %esi,%rax
  movslq %r11d,%rdi
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x3b,%dl
  ja     L95
  bt     %rdx,%rbx
  movzbl %dl,%r8d
  jae    L40
  cmp    $0x20,%dl
  ja     L95
  bt     %r8,%r10
  jb     L13
  add    $0x1,%esi
  movslq %esi,%rax
  xchg   %ax,%ax
L86:
  movzbl (%rcx,%rax,1),%edx
  mov    %eax,%esi
  cmp    $0x20,%dl
  jbe    L108
L95:
  cmp    $0x5c,%dl
  jne    L13
  add    $0x1,%esi
  movslq %esi,%rdi
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rcx,%rdi,1),%r9d
  lea    0x1(%rdi),%r8
  mov    %rdi,%rax
  cmp    $0x5c,%r9b
  jne    L117
  mov    %r8,%rdi
L113:
  cmpb   $0x7c,0x1(%rcx,%rax,1)
  lea    -0x1(%rdi),%r8d
  mov    %edi,%esi
  je     L6
L119:
  mov    %dl,(%r12,%r11,1)
  add    $0x1,%r11
  lea    0x1(%r8),%esi
  cmp    $0x7d0,%r11
  jne    L109
  mov    $0x7d0,%edi
L40:
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdi,1)
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L108:
  add    $0x1,%rax
  bt     %rdx,%r10
  jae    L86
L13:
  mov    %edx,%r9d
  nopl   (%rax)
L117:
  lea    -0x41(%r9),%eax
  cmp    $0x19,%al
  ja     L44
  lea    0x20(%r9),%edx
  mov    %esi,%r8d
  jmp    L119
L44:
  mov    %esi,%r8d
  mov    %r9d,%edx
  jmp    L119
```

assistant: ```c
char *asm_normalise(const char *asm_str) {
  static char norm_str[2000 + 1];
  int source, dest;
  char chr;
  source = 0;
  dest = 0;
  while (dest < 2000 && asm_str[source] != '\0' && asm_str[source] != ';' && asm_str[source] != '#') {
    while (asm_str[source] == ' ' || asm_str[source] == '\t' || asm_str[source] == '\n' || asm_str[source] == '\r')
      source++;
    while (asm_str[source] == '\\' && asm_str[source + 1] == '|')
      source++;
    chr = asm_str[source];
    if (chr >= 'A' && chr <= 'Z')
      chr = chr - 'A' + 'a';
    norm_str[dest] = chr;
    source++;
    dest++;
  }
  norm_str[dest] = '\0';
  return norm_str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<asm_normalise>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  xor    %r11d,%r11d
  xor    %esi,%esi
  push   %rbx
  lea    D4(%rip),%r12
  movabs $0xf7fffff7fffffffe,%rbx
  movabs $0xfffffffeffffd9ff,%r10
  nopw   0x0(%rax,%rax,1)
L47:
  movslq %esi,%rdx
  movslq %r11d,%rdi
  movzbl (%rcx,%rdx,1),%eax
  mov    %eax,%r8d
  cmp    $0x3b,%al
  ja     L52
  bt     %rax,%rbx
  movzbl %al,%r9d
  jae    L24
  cmp    $0x20,%al
  ja     L52
  bt     %r9,%r10
  jb     L18
  add    $0x1,%esi
  movslq %esi,%rdx
  nop
L89:
  movzbl (%rcx,%rdx,1),%eax
  mov    %edx,%esi
  mov    %eax,%r8d
  cmp    $0x20,%al
  jbe    L85
L52:
  cmp    $0x5c,%al
  jne    L18
  add    $0x1,%esi
  movslq %esi,%rdi
  jmp    L118
  nopl   0x0(%rax)
L44:
  lea    0x1(%rdi),%rsi
  mov    %rdi,%rdx
  movzbl -0x1(%rcx,%rsi,1),%r9d
  cmp    $0x5c,%r9b
  jne    L1
  mov    %rsi,%rdi
L118:
  cmpb   $0x7c,0x1(%rcx,%rdx,1)
  lea    -0x1(%rdi),%esi
  je     L44
L34:
  mov    %al,(%r12,%r11,1)
  add    $0x1,%r11
  add    $0x1,%esi
  cmp    $0x7d0,%r11
  jne    L47
  mov    $0x7d0,%edi
L24:
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdi,1)
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L85:
  add    $0x1,%rdx
  bt     %rax,%r10
  jae    L89
L18:
  mov    %eax,%r9d
  nopl   (%rax)
L62:
  lea    -0x41(%r8),%eax
  add    $0x20,%r8d
  cmp    $0x1a,%al
  mov    %r9d,%eax
  cmovb  %r8d,%eax
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r9d,%r8d
  mov    %edi,%esi
  jmp    L62
```

assistant: ```c
char *asm_normalise(const char *asm_str) {
  static char norm_str[2000 + 1];
  int source, dest;
  char chr;
  source = 0;
  dest = 0;
  while (dest < 2000 && asm_str[source] != '\0' && asm_str[source] != ';' && asm_str[source] != '#') {
    while (asm_str[source] == ' ' || asm_str[source] == '\t' || asm_str[source] == '\n' || asm_str[source] == '\r')
      source++;
    while (asm_str[source] == '\\' && asm_str[source + 1] == '|')
      source++;
    chr = asm_str[source];
    if (chr >= 'A' && chr <= 'Z')
      chr = chr - 'A' + 'a';
    norm_str[dest] = chr;
    source++;
    dest++;
  }
  norm_str[dest] = '\0';
  return norm_str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TERMhandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: Killed!


assistant: ```c
void TERMhandler(int sig) {
  printf("Killed!\n");
  exit(1);
}
```