ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bitmap_shift_right>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%r12d
  jg     L18
  test   %rax,%rax
  je     L18
  mov    0x0(%r13),%rax
  mov    %r14d,%ecx
  shr    %cl,%rax
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <__bitmap_shift_right@plt>
```

assistant: ```c
__attribute__((always_)) void bitmap_shift_right(unsigned long *dst, const unsigned long *src, int n, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    *dst = *src >> n;
  else
    __bitmap_shift_right(dst, src, n, nbits);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bitmap_shift_right>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%r12d
  jg     L13
  test   %rax,%rax
  je     L13
  mov    0x0(%r13),%rax
  mov    %r14d,%ecx
  shr    %cl,%rax
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <__bitmap_shift_right@plt>
```

assistant: ```c
__attribute__((always_)) void bitmap_shift_right(unsigned long *dst, const unsigned long *src, int n, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    *dst = *src >> n;
  else
    __bitmap_shift_right(dst, src, n, nbits);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  jns    L8
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L8:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int get_mac(int sock, struct ifreq *ifr) {
  if (ioctl(sock, SIOCGIFHWADDR, ifr) < 0) {
    close(sock);
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_mac>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L1
  mov    $0x0,%eax
L13:
  pop    %rbx
  ret
L1:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L13
```

assistant: ```c
int get_mac(int sock, struct ifreq *ifr) {
  if (ioctl(sock, SIOCGIFHWADDR, ifr) < 0) {
    close(sock);
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_mac>:
  endbr64
  mov    D0(%rip),%rax
  push   %rbp
  mov    %rsi,%rdx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L7
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_mac(int sock, struct ifreq *ifr) {
  if (ioctl(sock, SIOCGIFHWADDR, ifr) < 0) {
    close(sock);
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_mac>:
  endbr64
  mov    D9(%rip),%rax
  push   %rbp
  mov    %rsi,%rdx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L5
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_mac(int sock, struct ifreq *ifr) {
  if (ioctl(sock, SIOCGIFHWADDR, ifr) < 0) {
    close(sock);
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  movsd  D11(%rip),%xmm0
  mov    -0x24(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  lea    (%rax,%rax,1),%ebx
  movsd  D11(%rip),%xmm0
  mov    -0x28(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%ebx
  movsd  D8(%rip),%xmm0
  mov    -0x24(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  lea    (%rax,%rdx,1),%r12d
  movsd  D8(%rip),%xmm0
  mov    -0x28(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  add    %eax,%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    %edx,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: f64
name: retrieve_data
arguments: label: D8
type_guessed: f64

tool: D11: 3

tool: D8: 2

assistant: ```c
int calc(float a, float b) {
  float z;
  z = (2 * pow(a, 3.0) + 3 * pow(b, 3.0)) / (3 * pow(a, 2.0) - 2 * pow(b, 2.0));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  mov    D33(%rip),%rax
  movq   %rax,%xmm1
  movss  %xmm0,0xc(%rsp)
  call   <pow@plt>
  mov    D33(%rip),%rax
  movq   %rax,%xmm1
  movss  0x8(%rsp),%xmm0
  call   <pow@plt>
  mov    D25(%rip),%rax
  movq   %rax,%xmm1
  movss  0xc(%rsp),%xmm0
  call   <pow@plt>
  mov    D25(%rip),%rax
  movq   %rax,%xmm1
  movss  0x8(%rsp),%xmm0
  call   <pow@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D33
data_type: f64
name: retrieve_data
arguments: data_label: D25
data_type: f64

tool: D33: 3

tool: D25: 2

assistant: ```c
int calc(float a, float b) {
  float z;
  z = (2 * pow(a, 3.0) + 3 * pow(b, 3.0)) / (3 * pow(a, 2.0) - 2 * pow(b, 2.0));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movsd  D19(%rip),%xmm1
  movss  %xmm0,0xc(%rsp)
  call   <pow@plt>
  movss  0x8(%rsp),%xmm2
  mov    D19(%rip),%rax
  movaps %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <pow@plt>
  movss  0xc(%rsp),%xmm3
  movsd  D21(%rip),%xmm1
  movaps %xmm3,%xmm0
  call   <pow@plt>
  movss  0x8(%rsp),%xmm2
  mov    D21(%rip),%rax
  movaps %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <pow@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_infered: f64
name: read_data
arguments: label: D21
type_infered: f64

tool: D19: 3

tool: D21: 2

assistant: ```c
int calc(float a, float b) {
  float z;
  z = (2 * pow(a, 3.0) + 3 * pow(b, 3.0)) / (3 * pow(a, 2.0) - 2 * pow(b, 2.0));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movsd  D15(%rip),%xmm1
  movss  %xmm0,0xc(%rsp)
  call   <pow@plt>
  movss  0x8(%rsp),%xmm2
  mov    D15(%rip),%rax
  movaps %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <pow@plt>
  movss  0xc(%rsp),%xmm3
  movsd  D12(%rip),%xmm1
  movaps %xmm3,%xmm0
  call   <pow@plt>
  movss  0x8(%rsp),%xmm2
  mov    D12(%rip),%rax
  movaps %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <pow@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_guessed: f64
name: retrieve_data
arguments: tag: D12
type_guessed: f64

tool: D15: 3

tool: D12: 2

assistant: ```c
int calc(float a, float b) {
  float z;
  z = (2 * pow(a, 3.0) + 3 * pow(b, 3.0)) / (3 * pow(a, 2.0) - 2 * pow(b, 2.0));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test8_struct>:
  endbr64
  cmpb   $0x1c,0x88(%rsp)
  setne  %al
  cmpb   $0x1d,0x90(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x1b,0x80(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x1a,0x78(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x19,0x70(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x18,0x68(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x17,0x60(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x16,0x58(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x12,0x50(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x11,0x48(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x10,0x40(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xf,0x38(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xe,0x30(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xd,0x28(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xc,0x20(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xb,0x18(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x8,0x10(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x7,0x8(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmp    $0x6,%r9b
  setne  %r9b
  or     %r9d,%eax
  cmp    $0x5,%r8b
  setne  %r8b
  or     %r8d,%eax
  cmp    $0x4,%cl
  setne  %cl
  or     %ecx,%eax
  cmp    $0x3,%dl
  setne  %dl
  or     %edx,%eax
  cmp    $0x2,%sil
  setne  %dl
  or     %edx,%eax
  cmp    $0x1,%dil
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int test8_struct(char a0, char a1, char a2, char a3, char a4, char a5, char a6, char a7, char a8, char a9, char a10, char a11, char a12, char a13, char a14, char a15, char a16, char a17, char a18, char a19, char a20, char a21, char a22, char a23) {
  if (a0 != 1)
    return 1;
  if (a1 != 2)
    return 1;
  if (a2 != 3)
    return 1;
  if (a3 != 4)
    return 1;
  if (a4 != 5)
    return 1;
  if (a5 != 6)
    return 1;
  if (a6 != 7)
    return 1;
  if (a7 != 8)
    return 1;
  if (a8 != 11)
    return 1;
  if (a9 != 12)
    return 1;
  if (a10 != 13)
    return 1;
  if (a11 != 14)
    return 1;
  if (a12 != 15)
    return 1;
  if (a13 != 16)
    return 1;
  if (a14 != 17)
    return 1;
  if (a15 != 18)
    return 1;
  if (a16 != 22)
    return 1;
  if (a17 != 23)
    return 1;
  if (a18 != 24)
    return 1;
  if (a19 != 25)
    return 1;
  if (a20 != 26)
    return 1;
  if (a21 != 27)
    return 1;
  if (a22 != 28)
    return 1;
  if (a23 != 29)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test8_struct>:
  endbr64
  cmpb   $0x1c,0x88(%rsp)
  setne  %al
  cmpb   $0x1d,0x90(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x1b,0x80(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x1a,0x78(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x19,0x70(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x18,0x68(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x17,0x60(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x16,0x58(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x12,0x50(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x11,0x48(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x10,0x40(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xf,0x38(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xe,0x30(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xd,0x28(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xc,0x20(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xb,0x18(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x8,0x10(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x7,0x8(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmp    $0x6,%r9b
  setne  %r9b
  or     %r9d,%eax
  cmp    $0x5,%r8b
  setne  %r8b
  or     %r8d,%eax
  cmp    $0x4,%cl
  setne  %cl
  or     %ecx,%eax
  cmp    $0x3,%dl
  setne  %dl
  or     %edx,%eax
  cmp    $0x2,%sil
  setne  %dl
  or     %edx,%eax
  cmp    $0x1,%dil
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int test8_struct(char a0, char a1, char a2, char a3, char a4, char a5, char a6, char a7, char a8, char a9, char a10, char a11, char a12, char a13, char a14, char a15, char a16, char a17, char a18, char a19, char a20, char a21, char a22, char a23) {
  if (a0 != 1)
    return 1;
  if (a1 != 2)
    return 1;
  if (a2 != 3)
    return 1;
  if (a3 != 4)
    return 1;
  if (a4 != 5)
    return 1;
  if (a5 != 6)
    return 1;
  if (a6 != 7)
    return 1;
  if (a7 != 8)
    return 1;
  if (a8 != 11)
    return 1;
  if (a9 != 12)
    return 1;
  if (a10 != 13)
    return 1;
  if (a11 != 14)
    return 1;
  if (a12 != 15)
    return 1;
  if (a13 != 16)
    return 1;
  if (a14 != 17)
    return 1;
  if (a15 != 18)
    return 1;
  if (a16 != 22)
    return 1;
  if (a17 != 23)
    return 1;
  if (a18 != 24)
    return 1;
  if (a19 != 25)
    return 1;
  if (a20 != 26)
    return 1;
  if (a21 != 27)
    return 1;
  if (a22 != 28)
    return 1;
  if (a23 != 29)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test8_struct>:
  endbr64
  cmpb   $0x1c,0x88(%rsp)
  setne  %al
  cmpb   $0x1d,0x90(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x1b,0x80(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x1a,0x78(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x19,0x70(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x18,0x68(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x17,0x60(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x16,0x58(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x12,0x50(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x11,0x48(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x10,0x40(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xf,0x38(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xe,0x30(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xd,0x28(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xc,0x20(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0xb,0x18(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x8,0x10(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmpb   $0x7,0x8(%rsp)
  setne  %r10b
  or     %r10d,%eax
  cmp    $0x6,%r9b
  setne  %r9b
  or     %r9d,%eax
  cmp    $0x5,%r8b
  setne  %r8b
  or     %r8d,%eax
  cmp    $0x4,%cl
  setne  %cl
  or     %ecx,%eax
  cmp    $0x3,%dl
  setne  %dl
  or     %edx,%eax
  cmp    $0x2,%sil
  setne  %dl
  or     %edx,%eax
  cmp    $0x1,%dil
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int test8_struct(char a0, char a1, char a2, char a3, char a4, char a5, char a6, char a7, char a8, char a9, char a10, char a11, char a12, char a13, char a14, char a15, char a16, char a17, char a18, char a19, char a20, char a21, char a22, char a23) {
  if (a0 != 1)
    return 1;
  if (a1 != 2)
    return 1;
  if (a2 != 3)
    return 1;
  if (a3 != 4)
    return 1;
  if (a4 != 5)
    return 1;
  if (a5 != 6)
    return 1;
  if (a6 != 7)
    return 1;
  if (a7 != 8)
    return 1;
  if (a8 != 11)
    return 1;
  if (a9 != 12)
    return 1;
  if (a10 != 13)
    return 1;
  if (a11 != 14)
    return 1;
  if (a12 != 15)
    return 1;
  if (a13 != 16)
    return 1;
  if (a14 != 17)
    return 1;
  if (a15 != 18)
    return 1;
  if (a16 != 22)
    return 1;
  if (a17 != 23)
    return 1;
  if (a18 != 24)
    return 1;
  if (a19 != 25)
    return 1;
  if (a20 != 26)
    return 1;
  if (a21 != 27)
    return 1;
  if (a22 != 28)
    return 1;
  if (a23 != 29)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<va_buffer_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  movl   $0x0,-0xb8(%rbp)
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,%edx
  mov    -0xb8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xb8(%rbp)
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int va_buffer_size(const char *format, ...) {
  int bufsize = 0;
  va_list args;
  va_start(args, format);
  bufsize += vsnprintf(NULL, 0, format, args);
  va_end(args);
  return bufsize;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<va_buffer_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int va_buffer_size(const char *format, ...) {
  int bufsize = 0;
  va_list args;
  va_start(args, format);
  bufsize += vsnprintf(NULL, 0, format, args);
  va_end(args);
  return bufsize;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<va_buffer_size>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int va_buffer_size(const char *format, ...) {
  int bufsize = 0;
  va_list args;
  va_start(args, format);
  bufsize += vsnprintf(NULL, 0, format, args);
  va_end(args);
  return bufsize;
}
```
user: Translate the below assembly code into C programming language:

```asm
<va_buffer_size>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int va_buffer_size(const char *format, ...) {
  int bufsize = 0;
  va_list args;
  va_start(args, format);
  bufsize += vsnprintf(NULL, 0, format, args);
  va_end(args);
  return bufsize;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getSize(void *mem) {
  int *p = mem;
  return p[(0)];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getSize>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int getSize(void *mem) {
  int *p = mem;
  return p[(0)];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getSize>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int getSize(void *mem) {
  int *p = mem;
  return p[(0)];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getSize>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int getSize(void *mem) {
  int *p = mem;
  return p[(0)];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L42
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  jg     L42
  addl   $0x1,-0x8(%rbp)
  jmp    L62
L20:
  movzbl -0x9(%rbp),%edx
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x4(%rbp)
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L62:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  jl     L20
  jmp    L1
L42:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
L1:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L31
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void expand(char s1[], char s2[]) {
  char c;
  int i, j;
  i = j = 0;
  while ((c = s1[i++]) != '\0')
    if (s1[i] == '-' && s1[i + 1] >= c) {
      i++;
      while (c < s1[i])
        s2[j++] = c++;
    } else
      s2[j++] = c;
  s2[j] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<expand>:
  endbr64
  mov    %rdi,%r8
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  mov    $0x1,%edi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L47
L69:
  movslq %edx,%rcx
  mov    %al,(%rsi,%rcx,1)
  lea    0x1(%rdx),%edx
  mov    %edi,%ecx
L10:
  lea    0x1(%rcx),%edi
  movslq %ecx,%rax
  movzbl (%r8,%rax,1),%eax
  test   %al,%al
  je     L70
L47:
  movslq %edi,%r9
  cmpb   $0x2d,(%r8,%r9,1)
  jne    L69
  cmp    %al,0x1(%r8,%r9,1)
  jl     L69
  add    $0x2,%ecx
  movslq %ecx,%r10
  add    %r8,%r10
  cmp    %al,(%r10)
  jle    L10
  add    $0x1,%edx
  movslq %edx,%rdi
L45:
  mov    %eax,%r9d
  add    $0x1,%eax
  mov    %edi,%edx
  mov    %r9b,-0x1(%rsi,%rdi,1)
  add    $0x1,%rdi
  cmp    %al,(%r10)
  jg     L45
  jmp    L10
L6:
  mov    $0x0,%edx
L70:
  movslq %edx,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  ret
```

assistant: ```c
void expand(char s1[], char s2[]) {
  char c;
  int i, j;
  i = j = 0;
  while ((c = s1[i++]) != '\0')
    if (s1[i] == '-' && s1[i + 1] >= c) {
      i++;
      while (c < s1[i])
        s2[j++] = c++;
    } else
      s2[j++] = c;
  s2[j] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<expand>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%rdi
  movzbl (%r10),%eax
  test   %al,%al
  je     L56
  mov    $0x1,%ecx
  xor    %edx,%edx
  xor    %r9d,%r9d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L53:
  movslq %edx,%r8
  mov    %ecx,%r9d
  add    $0x1,%edx
  mov    %al,(%rdi,%r8,1)
  movzbl (%rsi),%eax
L46:
  lea    0x1(%r9),%ecx
  test   %al,%al
  je     L33
L6:
  movslq %ecx,%r8
  lea    (%r10,%r8,1),%rsi
  cmpb   $0x2d,(%rsi)
  jne    L53
  cmp    %al,0x1(%r10,%r8,1)
  jl     L53
  add    $0x2,%r9d
  movslq %r9d,%r8
  add    %r10,%r8
  movzbl (%r8),%ecx
  cmp    %al,%cl
  jle    L32
  add    $0x1,%edx
  mov    %eax,%ecx
  movslq %edx,%rsi
  nopl   (%rax)
L13:
  mov    %ecx,%eax
  add    $0x1,%ecx
  mov    %esi,%edx
  mov    %al,-0x1(%rdi,%rsi,1)
  movzbl (%r8),%eax
  add    $0x1,%rsi
  cmp    %cl,%al
  jg     L13
  lea    0x1(%r9),%ecx
  test   %al,%al
  jne    L6
  nop
L33:
  movslq %edx,%rdx
  add    %rdx,%rdi
L56:
  movb   $0x0,(%rdi)
  ret
L32:
  mov    %ecx,%eax
  jmp    L46
```

assistant: ```c
void expand(char s1[], char s2[]) {
  char c;
  int i, j;
  i = j = 0;
  while ((c = s1[i++]) != '\0')
    if (s1[i] == '-' && s1[i + 1] >= c) {
      i++;
      while (c < s1[i])
        s2[j++] = c++;
    } else
      s2[j++] = c;
  s2[j] = '\0';
}
```