ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<char_to_int>:
  endbr64
  lea    -0x41(%rdi),%eax
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x13,%al
  ja     L6
  lea    D6(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L6:
  lea    -0x32(%rbx),%edx
  xor    %eax,%eax
  cmp    $0x7,%dl
  jbe    L10
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x2,%edi
  call   <malloc@plt>
  movb   $0x0,0x1(%rax)
  mov    %rax,%rdi
  mov    %bl,(%rax)
  pop    %rbx
  jmp    1070 <atoi@plt>
  nopl   0x0(%rax)
  mov    $0xe,%eax
  pop    %rbx
  ret
  nop
  mov    $0xd,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0xc,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0xa,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0xb,%eax
  pop    %rbx
  ret
```

assistant: ```c
int char_to_int(char cardValue) {
  int integerValue = 0;
  switch (cardValue) {
  case 'T':
    integerValue = 10;
    break;
  case 'J':
    integerValue = 11;
    break;
  case 'Q':
    integerValue = 12;
    break;
  case 'K':
    integerValue = 13;
    break;
  case 'A':
    integerValue = 14;
    break;
  default:
    if (cardValue >= 0x32 && cardValue <= 0x39) {
      char *str = malloc(sizeof(char) * 2);
      str[1] = '\0';
      str[0] = cardValue;
      integerValue = atoi(str);
    }
    break;
  }
  return integerValue;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f2_enum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x5,(%rax)
  movl   $0x5,-0x14(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void f2_enum() {
  enum E1;
  enum E1 *e1;
  enum E1 { A = 4, B };
  enum E1 e2;
  enum E1 e3;
  e1 = &e3;
  *e1 = B;
  e2 = B;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f2_enum>:
  endbr64
  ret
```

assistant: ```c
void f2_enum() {
  enum E1;
  enum E1 *e1;
  enum E1 { A = 4, B };
  enum E1 e2;
  enum E1 e3;
  e1 = &e3;
  *e1 = B;
  e2 = B;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f2_enum>:
  endbr64
  ret
```

assistant: ```c
void f2_enum() {
  enum E1;
  enum E1 *e1;
  enum E1 { A = 4, B };
  enum E1 e2;
  enum E1 e3;
  e1 = &e3;
  *e1 = B;
  e2 = B;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f2_enum>:
  endbr64
  ret
```

assistant: ```c
void f2_enum() {
  enum E1;
  enum E1 *e1;
  enum E1 { A = 4, B };
  enum E1 e2;
  enum E1 e3;
  e1 = &e3;
  *e1 = B;
  e2 = B;
}
```
user: What is the c source code of the assembly code below?

```asm
<add_usecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x10(%rbp),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  lea    (%rsi,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rsi
  mov    -0x10(%rbp),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4240,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  lea    (%rsi,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    $0xf423f,%rax
  jle    L4
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  lea    (%rsi,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4240,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x8(%rdx)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_usecs(struct timeval *t, int64_t usecs) {
  t->tv_sec += usecs / 1000000L;
  t->tv_usec += usecs % 1000000L;
  if (t->tv_usec >= 1000000L) {
    t->tv_sec += t->tv_usec / 1000000L;
    t->tv_usec %= 1000000L;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add_usecs>:
  endbr64
  mov    %rdi,%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rdi
  add    (%rcx),%rdi
  mov    %rdi,(%rcx)
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  add    0x8(%rcx),%rsi
  mov    %rsi,0x8(%rcx)
  cmp    $0xf423f,%rsi
  jle    L6
  movabs $0x431bde82d7b634db,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  add    %rdx,%rdi
  mov    %rdi,(%rcx)
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x8(%rcx)
L6:
  ret
```

assistant: ```c
void add_usecs(struct timeval *t, int64_t usecs) {
  t->tv_sec += usecs / 1000000L;
  t->tv_usec += usecs % 1000000L;
  if (t->tv_usec >= 1000000L) {
    t->tv_sec += t->tv_usec / 1000000L;
    t->tv_usec %= 1000000L;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_usecs>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rax
  movabs $0x431bde82d7b634db,%rdi
  imul   %rdi
  mov    %rsi,%rax
  mov    (%rcx),%r8
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  add    %rdx,%r8
  imul   $0xf4240,%rdx,%rdx
  mov    %r8,(%rcx)
  sub    %rdx,%rsi
  add    0x8(%rcx),%rsi
  mov    %rsi,0x8(%rcx)
  cmp    $0xf423f,%rsi
  jle    L9
  mov    %rsi,%rax
  imul   %rdi
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  add    %rdx,%r8
  imul   $0xf4240,%rdx,%rdx
  mov    %r8,(%rcx)
  sub    %rdx,%rsi
  mov    %rsi,0x8(%rcx)
L9:
  ret
```

assistant: ```c
void add_usecs(struct timeval *t, int64_t usecs) {
  t->tv_sec += usecs / 1000000L;
  t->tv_usec += usecs % 1000000L;
  if (t->tv_usec >= 1000000L) {
    t->tv_sec += t->tv_usec / 1000000L;
    t->tv_usec %= 1000000L;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add_usecs>:
  endbr64
  mov    %rsi,%rax
  movdqu (%rdi),%xmm2
  movabs $0x431bde82d7b634db,%rcx
  imul   %rcx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  imul   $0xf4240,%rdx,%rax
  movq   %rdx,%xmm0
  sub    %rax,%rsi
  movq   %rsi,%xmm1
  punpcklqdq %xmm1,%xmm0
  paddq  %xmm2,%xmm0
  movhlps %xmm0,%xmm3
  movq   %xmm0,%r8
  movups %xmm0,(%rdi)
  movq   %xmm3,%rsi
  cmp    $0xf423f,%rsi
  jle    L3
  movq   %xmm3,%rax
  imul   %rcx
  movq   %xmm3,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%r8,1),%rax
  imul   $0xf4240,%rdx,%rdx
  movq   %rax,%xmm0
  sub    %rdx,%rsi
  movq   %rsi,%xmm4
  punpcklqdq %xmm4,%xmm0
  movups %xmm0,(%rdi)
L3:
  ret
```

assistant: ```c
void add_usecs(struct timeval *t, int64_t usecs) {
  t->tv_sec += usecs / 1000000L;
  t->tv_usec += usecs % 1000000L;
  if (t->tv_usec >= 1000000L) {
    t->tv_sec += t->tv_usec / 1000000L;
    t->tv_usec %= 1000000L;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<resize_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L26
  mov    $0x0,%eax
  jmp    L4
L26:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L4
L21:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
char *resize_buffer(char *buffer, size_t oldsize, size_t newsize) {
  char *new = NULL;
  if (newsize < oldsize) {
    return NULL;
  }
  new = (char *)malloc(newsize);
  if (!new) {
    return NULL;
  }
  memcpy(new, buffer, oldsize);
  free(buffer);
  return new;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resize_buffer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  cmp    %rsi,%rdx
  jb     L15
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L15
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L15:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *resize_buffer(char *buffer, size_t oldsize, size_t newsize) {
  char *new = NULL;
  if (newsize < oldsize) {
    return NULL;
  }
  new = (char *)malloc(newsize);
  if (!new) {
    return NULL;
  }
  memcpy(new, buffer, oldsize);
  free(buffer);
  return new;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<resize_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  cmp    %rsi,%rdx
  jb     L3
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  mov    %rsi,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *resize_buffer(char *buffer, size_t oldsize, size_t newsize) {
  char *new = NULL;
  if (newsize < oldsize) {
    return NULL;
  }
  new = (char *)malloc(newsize);
  if (!new) {
    return NULL;
  }
  memcpy(new, buffer, oldsize);
  free(buffer);
  return new;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<resize_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  cmp    %rsi,%rdx
  jb     L8
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  mov    %rsi,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *resize_buffer(char *buffer, size_t oldsize, size_t newsize) {
  char *new = NULL;
  if (newsize < oldsize) {
    return NULL;
  }
  new = (char *)malloc(newsize);
  if (!new) {
    return NULL;
  }
  memcpy(new, buffer, oldsize);
  free(buffer);
  return new;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bioImageSubmitId>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %esi,-0x21c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x21c(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    %edx,%ecx
  lea    D0(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <sqlSafef@plt>
  lea    -0x110(%rbp),%rdx
  lea    -0x210(%rbp),%rsi
  mov    -0x218(%rbp),%rax
  mov    $0x100,%ecx
  mov    %rax,%rdi
  call   <sqlQuickQuery@plt>
  mov    %eax,%edi
  call   <cloneString@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: select submitId from image where image.id=%d

assistant: ```c
char *bioImageSubmitId(struct sqlConnection *conn, int id) {
  char query[256], buf[256];
  sqlSafef(query, sizeof(query),
           "select submitId from image"
           " where image.id=%d",
           id);
  return cloneString(sqlQuickQuery(conn, query, buf, sizeof(buf)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<bioImageSubmitId>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D9(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <sqlSafef@plt>
  lea    0x100(%rsp),%rdx
  mov    $0x100,%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sqlQuickQuery@plt>
  mov    %eax,%edi
  call   <cloneString@plt>
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: select submitId from image where image.id=%d

assistant: ```c
char *bioImageSubmitId(struct sqlConnection *conn, int id) {
  char query[256], buf[256];
  sqlSafef(query, sizeof(query),
           "select submitId from image"
           " where image.id=%d",
           id);
  return cloneString(sqlQuickQuery(conn, query, buf, sizeof(buf)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bioImageSubmitId>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  lea    D6(%rip),%rdx
  mov    $0x100,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sqlSafef@plt>
  mov    %rbp,%rdi
  mov    $0x100,%ecx
  mov    %r12,%rsi
  lea    0x100(%rsp),%rdx
  call   <sqlQuickQuery@plt>
  mov    %eax,%edi
  call   <cloneString@plt>
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: select submitId from image where image.id=%d

assistant: ```c
char *bioImageSubmitId(struct sqlConnection *conn, int id) {
  char query[256], buf[256];
  sqlSafef(query, sizeof(query),
           "select submitId from image"
           " where image.id=%d",
           id);
  return cloneString(sqlQuickQuery(conn, query, buf, sizeof(buf)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bioImageSubmitId>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sqlSafef@plt>
  mov    %rbp,%rdi
  mov    $0x100,%ecx
  mov    %r12,%rsi
  lea    0x100(%rsp),%rdx
  call   <sqlQuickQuery@plt>
  mov    %eax,%edi
  call   <cloneString@plt>
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: select submitId from image where image.id=%d

assistant: ```c
char *bioImageSubmitId(struct sqlConnection *conn, int id) {
  char query[256], buf[256];
  sqlSafef(query, sizeof(query),
           "select submitId from image"
           " where image.id=%d",
           id);
  return cloneString(sqlQuickQuery(conn, query, buf, sizeof(buf)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<devide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    -0x44(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L18
L9:
  movl   $0xa,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %eax,-0x30(%rbp)
  movsd  D19(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D13(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x38(%rbp)
L18:
  cmpl   $0x1391,-0x38(%rbp)
  jle    L9
  mov    -0x34(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type: f64
name: parse_data
arguments: data_tag: D13
type: f64

tool: D19: 20.23

tool: D13: 10.12

assistant: ```c
int devide(int num, int divider) {
  int result = num / divider;
  int a, b, c, d, i;
  double e, f, g, h;
  for (i = 0; i < 5010; ++i) {
    a = 10;
    b = 5;
    c = a / b;
    d = 5;
    a = d / a;
    e = 20.23;
    f = 10.12;
    g = e / f;
    h = e;
    f = f / h;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<devide>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    $0x1392,%edx
L0:
  sub    $0x1,%edx
  jne    L0
  ret
```

assistant: ```c
int devide(int num, int divider) {
  int result = num / divider;
  int a, b, c, d, i;
  double e, f, g, h;
  for (i = 0; i < 5010; ++i) {
    a = 10;
    b = 5;
    c = a / b;
    d = 5;
    a = d / a;
    e = 20.23;
    f = 10.12;
    g = e / f;
    h = e;
    f = f / h;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<devide>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int devide(int num, int divider) {
  int result = num / divider;
  int a, b, c, d, i;
  double e, f, g, h;
  for (i = 0; i < 5010; ++i) {
    a = 10;
    b = 5;
    c = a / b;
    d = 5;
    a = d / a;
    e = 20.23;
    f = 10.12;
    g = e / f;
    h = e;
    f = f / h;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<devide>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int devide(int num, int divider) {
  int result = num / divider;
  int a, b, c, d, i;
  double e, f, g, h;
  for (i = 0; i < 5010; ++i) {
    a = 10;
    b = 5;
    c = a / b;
    d = 5;
    a = d / a;
    e = 20.23;
    f = 10.12;
    g = e / f;
    h = e;
    f = f / h;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<maxHeapFilterDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L25:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L35
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L35
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L21
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L25
  jmp    L34
L21:
  nop
L34:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void maxHeapFilterDown(int array[], int index, int size) {
  int dad, son, temp;
  dad = index;
  temp = array[dad];
  son = dad * 2 + 1;
  while (son < size) {
    if (son + 1 < size && array[son + 1] > array[son]) {
      son++;
    }
    if (array[son] <= temp) {
      break;
    }
    array[dad] = array[son];
    dad = son;
    son = dad * 2 + 1;
  }
  array[dad] = temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<maxHeapFilterDown>:
  endbr64
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r9d
  lea    0x1(%rsi,%rsi,1),%ecx
  cmp    %edx,%ecx
  jl     L25
  jmp    L50
L13:
  mov    %ecx,%eax
L14:
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %r9d,%ecx
  jle    L50
  movslq %esi,%rsi
  mov    %ecx,(%rdi,%rsi,4)
  lea    0x1(%rax,%rax,1),%ecx
  cmp    %ecx,%edx
  jle    L17
  mov    %eax,%esi
L25:
  lea    0x1(%rcx),%eax
  cmp    %edx,%eax
  jge    L13
  movslq %ecx,%r8
  mov    (%rdi,%r8,4),%r10d
  cmp    %r10d,0x4(%rdi,%r8,4)
  cmovle %ecx,%eax
  jmp    L14
L17:
  mov    %eax,%esi
L50:
  movslq %esi,%rsi
  mov    %r9d,(%rdi,%rsi,4)
  ret
```

assistant: ```c
void maxHeapFilterDown(int array[], int index, int size) {
  int dad, son, temp;
  dad = index;
  temp = array[dad];
  son = dad * 2 + 1;
  while (son < size) {
    if (son + 1 < size && array[son + 1] > array[son]) {
      son++;
    }
    if (array[son] <= temp) {
      break;
    }
    array[dad] = array[son];
    dad = son;
    son = dad * 2 + 1;
  }
  array[dad] = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<maxHeapFilterDown>:
  endbr64
  movslq %esi,%r11
  lea    0x1(%rsi,%rsi,1),%eax
  push   %rbx
  mov    %rdi,%r8
  lea    (%rdi,%r11,4),%r9
  mov    (%r9),%ebx
  cmp    %edx,%eax
  jl     L41
  jmp    L20
  nopl   0x0(%rax)
L42:
  lea    0x4(%r8,%rsi,1),%rsi
  mov    (%rsi),%r9d
  cmp    %edi,%r9d
  jle    L5
  mov    %r9d,%edi
  mov    %rsi,%r10
  lea    (%r8,%r11,4),%r9
  cmp    %edi,%ebx
  jge    L20
L48:
  lea    0x1(%rcx,%rcx,1),%eax
  mov    %edi,(%r9)
  cmp    %eax,%edx
  jle    L26
  movslq %ecx,%r11
L41:
  movslq %eax,%rsi
  lea    0x1(%rax),%ecx
  shl    $0x2,%rsi
  lea    (%r8,%rsi,1),%r10
  mov    (%r10),%edi
  cmp    %edx,%ecx
  jl     L42
L5:
  mov    %eax,%ecx
  lea    (%r8,%r11,4),%r9
  cmp    %edi,%ebx
  jl     L48
L20:
  mov    %ebx,(%r9)
  pop    %rbx
  ret
  nopl   (%rax)
L26:
  mov    %r10,%r9
  mov    %ebx,(%r9)
  pop    %rbx
  ret
```

assistant: ```c
void maxHeapFilterDown(int array[], int index, int size) {
  int dad, son, temp;
  dad = index;
  temp = array[dad];
  son = dad * 2 + 1;
  while (son < size) {
    if (son + 1 < size && array[son + 1] > array[son]) {
      son++;
    }
    if (array[son] <= temp) {
      break;
    }
    array[dad] = array[son];
    dad = son;
    son = dad * 2 + 1;
  }
  array[dad] = temp;
}
```
user: What is the c source code of the assembly code below:

```asm
<maxHeapFilterDown>:
  endbr64
  movslq %esi,%r11
  lea    0x1(%rsi,%rsi,1),%eax
  push   %rbx
  mov    %rdi,%r8
  lea    (%rdi,%r11,4),%r9
  mov    (%r9),%ebx
  cmp    %edx,%eax
  jl     L64
  jmp    L9
  nopl   0x0(%rax)
L16:
  lea    0x4(%r8,%rsi,1),%rsi
  mov    (%rsi),%r9d
  cmp    %edi,%r9d
  jle    L68
  mov    %r9d,%edi
  mov    %rsi,%r10
  lea    (%r8,%r11,4),%r9
  cmp    %edi,%ebx
  jge    L9
L60:
  lea    0x1(%rcx,%rcx,1),%eax
  mov    %edi,(%r9)
  cmp    %eax,%edx
  jle    L12
  movslq %ecx,%r11
L64:
  movslq %eax,%rsi
  lea    0x1(%rax),%ecx
  shl    $0x2,%rsi
  lea    (%r8,%rsi,1),%r10
  mov    (%r10),%edi
  cmp    %edx,%ecx
  jl     L16
L68:
  mov    %eax,%ecx
  lea    (%r8,%r11,4),%r9
  cmp    %edi,%ebx
  jl     L60
L9:
  mov    %ebx,(%r9)
  pop    %rbx
  ret
  nopl   (%rax)
L12:
  mov    %r10,%r9
  mov    %ebx,(%r9)
  pop    %rbx
  ret
```

assistant: ```c
void maxHeapFilterDown(int array[], int index, int size) {
  int dad, son, temp;
  dad = index;
  temp = array[dad];
  son = dad * 2 + 1;
  while (son < size) {
    if (son + 1 < size && array[son + 1] > array[son]) {
      son++;
    }
    if (array[son] <= temp) {
      break;
    }
    array[dad] = array[son];
    dad = son;
    son = dad * 2 + 1;
  }
  array[dad] = temp;
}
```