ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<arr_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L31:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L29
  mov    $0x1,%eax
  jmp    L4
L29:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L31
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int arr_equal(int *a, int *b, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    if (a[i] != b[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arr_equal>:
  endbr64
  test   %edx,%edx
  jle    L13
  mov    %edx,%edx
  mov    $0x0,%eax
L17:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L25
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
  mov    $0x0,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int arr_equal(int *a, int *b, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    if (a[i] != b[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<arr_equal>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L17
  nop
L30:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L11
L17:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L30
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int arr_equal(int *a, int *b, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    if (a[i] != b[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arr_equal>:
  endbr64
  test   %edx,%edx
  jle    L22
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L11
  nop
L13:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L22
L11:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L13
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int arr_equal(int *a, int *b, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    if (a[i] != b[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sigintHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <termReset@plt>
  mov    $0x0,%eax
  call   <getNoKill@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <shutDown@plt>
  nop
  leave
  ret
```

assistant: ```c
void sigintHandler(int signum) {
  termReset();
  shutDown(getNoKill(), 1, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sigintHandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <termReset@plt>
  mov    $0x0,%eax
  call   <getNoKill@plt>
  mov    %eax,%edi
  mov    $0x0,%edx
  mov    $0x1,%esi
  call   <shutDown@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sigintHandler(int signum) {
  termReset();
  shutDown(getNoKill(), 1, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sigintHandler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <termReset@plt>
  xor    %eax,%eax
  call   <getNoKill@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <shutDown@plt>
```

assistant: ```c
void sigintHandler(int signum) {
  termReset();
  shutDown(getNoKill(), 1, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sigintHandler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <termReset@plt>
  xor    %eax,%eax
  call   <getNoKill@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <shutDown@plt>
```

assistant: ```c
void sigintHandler(int signum) {
  termReset();
  shutDown(getNoKill(), 1, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtrim_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%eax
  mov    %eax,%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L11
L43:
  movzbl (%rbx),%eax
  cmp    %al,%r13b
  jne    L32
  add    $0x1,%rbx
L11:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L12
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  test   %eax,%eax
  jne    L43
  jmp    L12
L32:
  nop
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *strtrim_left(register char *p, register char c) {
  register int len;
  len = strlen(p);
  while (*p && len--) {
    if (c == *p)
      p++;
    else
      break;
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtrim_left>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%ebp
  call   <strlen@plt>
  mov    %eax,%edi
  movzbl (%rbx),%eax
  test   %al,%al
  je     L53
  cmp    %r12b,%al
  jne    L6
  test   %edi,%edi
  je     L6
  mov    %rbx,%rax
L25:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L79
  mov    %ebx,%ecx
  sub    %eax,%ecx
  add    %edi,%ecx
  je     L79
  cmp    %bpl,%dl
  je     L25
L79:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  mov    %rbx,%rax
  jmp    L79
L6:
  mov    %rbx,%rax
  jmp    L79
```

assistant: ```c
char *strtrim_left(register char *p, register char c) {
  register int len;
  len = strlen(p);
  while (*p && len--) {
    if (c == *p)
      p++;
    else
      break;
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtrim_left>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  movzbl (%rbx),%eax
  test   %al,%al
  je     L17
  cmp    %r12b,%al
  mov    %rbx,%rax
  jne    L33
  test   %edi,%edi
  jne    L79
  jmp    L33
  nopl   0x0(%rax)
L4:
  mov    %ebx,%ecx
  sub    %eax,%ecx
  add    %edi,%ecx
  je     L33
  cmp    %bpl,%dl
  jne    L33
L79:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rbx,%rax
  jmp    L33
```

assistant: ```c
char *strtrim_left(register char *p, register char c) {
  register int len;
  len = strlen(p);
  while (*p && len--) {
    if (c == *p)
      p++;
    else
      break;
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtrim_left>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  movzbl (%rbx),%eax
  test   %al,%al
  je     L25
  cmp    %r12b,%al
  mov    %rbx,%rax
  jne    L73
  test   %edi,%edi
  jne    L75
  jmp    L73
  nopl   0x0(%rax)
L14:
  mov    %ebx,%ecx
  sub    %eax,%ecx
  add    %edi,%ecx
  je     L73
  cmp    %bpl,%dl
  jne    L73
L75:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L14
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    %rbx,%rax
  jmp    L73
```

assistant: ```c
char *strtrim_left(register char *p, register char c) {
  register int len;
  len = strlen(p);
  while (*p && len--) {
    if (c == *p)
      p++;
    else
      break;
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cJSON_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L14
L10:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
char *cJSON_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cJSON_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cJSON_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cJSON_strdup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
L6:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *cJSON_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cJSON_strdup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
L6:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *cJSON_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<negotiate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1ffbff,-0x20(%rbp)
  movw   $0x0,-0x18(%rbp)
  movabs $0xff180050001ffaff,%rax
  mov    %rax,-0x16(%rbp)
  movw   $0xf0,-0xe(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xfd,%al
  jne    L5
  mov    -0x40(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jne    L5
  lea    -0x20(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x3,%edx
  mov    %eax,%edi
  call   <Send@plt>
  lea    -0x20(%rbp),%rax
  lea    0xa(%rax),%rsi
  mov    -0x34(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x9,%edx
  mov    %eax,%edi
  call   <Send@plt>
  jmp    L35
L5:
  movl   $0x0,-0x24(%rbp)
  jmp    L10
L39:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xfd,%al
  jne    L4
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0xfc,(%rax)
  jmp    L6
L4:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xfb,%al
  jne    L6
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0xfd,(%rax)
L6:
  addl   $0x1,-0x24(%rbp)
L10:
  mov    -0x24(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L39
  mov    -0x38(%rbp),%edx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <Send@plt>
L35:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void negotiate(int sock, unsigned char *buf, int len) {
  unsigned char str_term[2][10] = {{255, 251, 31}, {255, 250, 31, 0, 80, 0, 24, 255, 240}};
  int i;
  if (buf[1] == 0xfd && buf[2] == 31) {
    Send(sock, str_term[0], 3, 0);
    Send(sock, str_term[1], 9, 0);
    return;
  }
  for (i = 0; i < len; i++) {
    if (buf[i] == 0xfd)
      buf[i] = 0xfc;
    else if (buf[i] == 0xfb)
      buf[i] = 0xfd;
  }
  Send(sock, buf, len, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<negotiate>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x1ffbff,(%rsp)
  movw   $0x0,0x8(%rsp)
  movabs $0xff180050001ffaff,%rax
  mov    %rax,0xa(%rsp)
  movw   $0xf0,0x12(%rsp)
  cmpb   $0xfd,0x1(%rsi)
  je     L19
L32:
  test   %edx,%edx
  jle    L14
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edi
  add    %rsi,%rdi
  jmp    L33
L19:
  cmpb   $0x1f,0x2(%rsi)
  jne    L32
  mov    %rsp,%rsi
  mov    $0x0,%ecx
  mov    $0x3,%edx
  call   <Send@plt>
  lea    0xa(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x9,%edx
  mov    %ebx,%edi
  call   <Send@plt>
  jmp    L62
L98:
  movb   $0xfc,(%rax)
L75:
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  je     L14
  mov    %rcx,%rax
L33:
  movzbl (%rax),%ecx
  cmp    $0xfd,%cl
  je     L98
  cmp    $0xfb,%cl
  jne    L75
  movb   $0xfd,(%rax)
  jmp    L75
L14:
  mov    $0x0,%ecx
  mov    %ebx,%edi
  call   <Send@plt>
L62:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x20,%rsp
  pop    %rbx
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void negotiate(int sock, unsigned char *buf, int len) {
  unsigned char str_term[2][10] = {{255, 251, 31}, {255, 250, 31, 0, 80, 0, 24, 255, 240}};
  int i;
  if (buf[1] == 0xfd && buf[2] == 31) {
    Send(sock, str_term[0], 3, 0);
    Send(sock, str_term[1], 9, 0);
    return;
  }
  for (i = 0; i < len; i++) {
    if (buf[i] == 0xfd)
      buf[i] = 0xfc;
    else if (buf[i] == 0xfb)
      buf[i] = 0xfd;
  }
  Send(sock, buf, len, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<negotiate>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0xfd,0x1(%rsi)
  movl   $0xf0ff18,0x10(%rsp)
  movaps %xmm0,(%rsp)
  je     L83
L1:
  test   %edx,%edx
  jle    L27
  lea    -0x1(%rdx),%edi
  mov    %rsi,%rax
  add    %rsi,%rdi
  jmp    L49
  nopl   0x0(%rax)
L19:
  cmp    $0xfb,%cl
  jne    L26
  movb   $0xfd,(%rax)
L26:
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  je     L27
L92:
  mov    %rcx,%rax
L49:
  movzbl (%rax),%ecx
  cmp    $0xfd,%cl
  jne    L19
  movb   $0xfc,(%rax)
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  jne    L92
L27:
  xor    %ecx,%ecx
  mov    %ebp,%edi
  call   <Send@plt>
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L83:
  cmpb   $0x1f,0x2(%rsi)
  jne    L1
  mov    %rsp,%rsi
  xor    %ecx,%ecx
  mov    $0x3,%edx
  call   <Send@plt>
  lea    0xa(%rsp),%rsi
  xor    %ecx,%ecx
  mov    %ebp,%edi
  mov    $0x9,%edx
  call   <Send@plt>
  jmp    L6
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: byte[16]

tool: {"D0": [0xff,0xfb,0x1f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xff,0xfa,0x1f,0x00,0x50,0x00]}

assistant: ```c
void negotiate(int sock, unsigned char *buf, int len) {
  unsigned char str_term[2][10] = {{255, 251, 31}, {255, 250, 31, 0, 80, 0, 24, 255, 240}};
  int i;
  if (buf[1] == 0xfd && buf[2] == 31) {
    Send(sock, str_term[0], 3, 0);
    Send(sock, str_term[1], 9, 0);
    return;
  }
  for (i = 0; i < len; i++) {
    if (buf[i] == 0xfd)
      buf[i] = 0xfc;
    else if (buf[i] == 0xfb)
      buf[i] = 0xfd;
  }
  Send(sock, buf, len, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<negotiate>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0xfd,0x1(%rsi)
  movl   $0xf0ff18,0x10(%rsp)
  movaps %xmm0,(%rsp)
  je     L85
L55:
  test   %edx,%edx
  jle    L8
  lea    -0x1(%rdx),%edi
  mov    %rsi,%rax
  add    %rsi,%rdi
  jmp    L75
  nopl   0x0(%rax)
L92:
  cmp    $0xfb,%cl
  jne    L87
  movb   $0xfd,(%rax)
L87:
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  je     L8
L99:
  mov    %rcx,%rax
L75:
  movzbl (%rax),%ecx
  cmp    $0xfd,%cl
  jne    L92
  movb   $0xfc,(%rax)
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  jne    L99
L8:
  xor    %ecx,%ecx
  mov    %ebp,%edi
  call   <Send@plt>
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L85:
  cmpb   $0x1f,0x2(%rsi)
  jne    L55
  mov    %rsp,%rsi
  xor    %ecx,%ecx
  mov    $0x3,%edx
  call   <Send@plt>
  lea    0xa(%rsp),%rsi
  xor    %ecx,%ecx
  mov    %ebp,%edi
  mov    $0x9,%edx
  call   <Send@plt>
  jmp    L22
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: byte[16]

tool: {"D5": [0xff,0xfb,0x1f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xff,0xfa,0x1f,0x00,0x50,0x00]}

assistant: ```c
void negotiate(int sock, unsigned char *buf, int len) {
  unsigned char str_term[2][10] = {{255, 251, 31}, {255, 250, 31, 0, 80, 0, 24, 255, 240}};
  int i;
  if (buf[1] == 0xfd && buf[2] == 31) {
    Send(sock, str_term[0], 3, 0);
    Send(sock, str_term[1], 9, 0);
    return;
  }
  for (i = 0; i < len; i++) {
    if (buf[i] == 0xfd)
      buf[i] = 0xfc;
    else if (buf[i] == 0xfb)
      buf[i] = 0xfd;
  }
  Send(sock, buf, len, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xt_core_hash_sdbm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L19:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x6,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long xt_core_hash_sdbm(char *string) {
  assert(string);
  unsigned long hash;
  int c;
  hash = 0;
  while ((c = *string++)) {
    hash = c + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xt_core_hash_sdbm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L19
  lea    0x1(%rbx),%rcx
  mov    $0x0,%eax
L12:
  imul   $0x1003f,%rax,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L12
L7:
  pop    %rbx
  ret
L19:
  mov    $0x0,%eax
  jmp    L7
```

assistant: ```c
unsigned long xt_core_hash_sdbm(char *string) {
  assert(string);
  unsigned long hash;
  int c;
  hash = 0;
  while ((c = *string++)) {
    hash = c + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xt_core_hash_sdbm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movsbq (%rbx),%rdx
  test   %dl,%dl
  je     L8
  lea    0x1(%rbx),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L2:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L2
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long xt_core_hash_sdbm(char *string) {
  assert(string);
  unsigned long hash;
  int c;
  hash = 0;
  while ((c = *string++)) {
    hash = c + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xt_core_hash_sdbm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movsbq (%rbx),%rdx
  test   %dl,%dl
  je     L17
  lea    0x1(%rbx),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L13
  pop    %rbx
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long xt_core_hash_sdbm(char *string) {
  assert(string);
  unsigned long hash;
  int c;
  hash = 0;
  while ((c = *string++)) {
    hash = c + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<number_divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <number_get_reciprocal@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L16
L8:
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <number_multiply@plt>
L16:
  leave
  ret
```

assistant: ```c
struct Number *number_divide(struct Stack *restrict output_stack, struct Stack *restrict local_stack, struct Number *dividend, struct Number *divisor) {
  struct Number *reciprocal = number_get_reciprocal(local_stack, output_stack, divisor);
  if (!reciprocal) {
    return 0;
  }
  return number_multiply(output_stack, local_stack, dividend, reciprocal);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<number_divide>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%rdx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <number_get_reciprocal@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <number_multiply@plt>
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct Number *number_divide(struct Stack *restrict output_stack, struct Stack *restrict local_stack, struct Number *dividend, struct Number *divisor) {
  struct Number *reciprocal = number_get_reciprocal(local_stack, output_stack, divisor);
  if (!reciprocal) {
    return 0;
  }
  return number_multiply(output_stack, local_stack, dividend, reciprocal);
}
```
user: Translate the below assembly code into C programming language:

```asm
<number_divide>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    %rcx,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <number_get_reciprocal@plt>
  test   %rax,%rax
  je     L8
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <number_multiply@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct Number *number_divide(struct Stack *restrict output_stack, struct Stack *restrict local_stack, struct Number *dividend, struct Number *divisor) {
  struct Number *reciprocal = number_get_reciprocal(local_stack, output_stack, divisor);
  if (!reciprocal) {
    return 0;
  }
  return number_multiply(output_stack, local_stack, dividend, reciprocal);
}
```