ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  lea    D6(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L34
L40:
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L11
L48:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <pages@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L34:
  lea    D49(%rip),%rdi
  call   <die@plt>
  jmp    L40
L11:
  lea    D49(%rip),%rdi
  call   <die@plt>
  jmp    L48
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D28
datatype: string
name: parse_data
arguments: label: D30
datatype: string
name: parse_data
arguments: label: D49
datatype: string

tool: D7: Input the number of lines that can be printed on one page: 

tool: D6: %u

tool: D28: Input the number of lines we want to print: 

tool: D30: The number of pages required for %u number of lines with %u lines per page is %u.


tool: D49: Input failure.


assistant: ```c
int main() {
  unsigned input1, input2;
  printf("Input the number of lines that can be printed on one page: ");
  if (!scanf("%u", &input1))
    die("Input failure.\n");
  printf("Input the number of lines we want to print: ");
  if (!scanf("%u", &input2))
    die("Input failure.\n");
  printf("The number of pages required for %u number of lines with %u lines per page is %u.\n", input2, input1, pages(input1, input2));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getCurrentTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
uint64_t getCurrentTime() {
  struct timeval now;
  gettimeofday(&now, NULL);
  uint64_t now64 = now.tv_sec;
  now64 *= 1000000;
  now64 += (now.tv_usec);
  return now64;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getCurrentTime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  add    0x8(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t getCurrentTime() {
  struct timeval now;
  gettimeofday(&now, NULL);
  uint64_t now64 = now.tv_sec;
  now64 *= 1000000;
  now64 += (now.tv_usec);
  return now64;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCurrentTime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  add    0x8(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t getCurrentTime() {
  struct timeval now;
  gettimeofday(&now, NULL);
  uint64_t now64 = now.tv_sec;
  now64 *= 1000000;
  now64 += (now.tv_usec);
  return now64;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getCurrentTime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  add    0x8(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t getCurrentTime() {
  struct timeval now;
  gettimeofday(&now, NULL);
  uint64_t now64 = now.tv_sec;
  now64 *= 1000000;
  now64 += (now.tv_usec);
  return now64;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *shift_args(int *argc, char ***argv) {
  char *shifted_arg = **argv;
  (*argc)--;
  (*argv)++;
  return shifted_arg;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shift_args>:
  endbr64
  mov    (%rsi),%rax
  mov    (%rax),%rax
  subl   $0x1,(%rdi)
  addq   $0x8,(%rsi)
  ret
```

assistant: ```c
char *shift_args(int *argc, char ***argv) {
  char *shifted_arg = **argv;
  (*argc)--;
  (*argv)++;
  return shifted_arg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shift_args>:
  endbr64
  mov    (%rsi),%rax
  mov    (%rax),%r8
  add    $0x8,%rax
  subl   $0x1,(%rdi)
  mov    %rax,(%rsi)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *shift_args(int *argc, char ***argv) {
  char *shifted_arg = **argv;
  (*argc)--;
  (*argv)++;
  return shifted_arg;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shift_args>:
  endbr64
  mov    (%rsi),%rax
  mov    (%rax),%r8
  add    $0x8,%rax
  subl   $0x1,(%rdi)
  mov    %rax,(%rsi)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *shift_args(int *argc, char ***argv) {
  char *shifted_arg = **argv;
  (*argc)--;
  (*argv)++;
  return shifted_arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x54(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L69
L60:
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L2:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L12:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L45
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L45:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x52,%al
  jne    L72
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L72:
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x47,%al
  jne    L76
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L76:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  addl   $0x1,-0x4c(%rbp)
L69:
  mov    -0x54(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L60
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D32
datatype: string
name: unpack_data
arguments: data_label: D53
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D49
datatype: string

tool: D32: %d

tool: D53: %s

tool: D27: Rounak

tool: D0: Sanchit

tool: D49: 


assistant: ```c
main() {
  int i, t, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    char s[n];
    scanf("%s", s);
    if (s[0] == 'R')
      printf("Rounak");
    if (s[0] == 'G')
      printf("Sanchit");
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x40(%rbp)
  jle    L26
  mov    $0x0,%ebx
  lea    D27(%rip),%r14
  lea    D44(%rip),%r15
  jmp    L81
L54:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L19
  orq    $0x0,-0x8(%rsp,%rax,1)
L19:
  mov    %rsp,%r13
  mov    %rsp,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpb   $0x52,(%rsp)
  je     L105
L71:
  cmpb   $0x47,0x0(%r13)
  je     L34
L12:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsp
  add    $0x1,%ebx
  cmp    %ebx,-0x40(%rbp)
  jle    L26
L81:
  mov    %rsp,%r12
  lea    -0x3c(%rbp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L29:
  cmp    %rdx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L29
L105:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L34:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L26:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D44
type_guessed: string
name: disassemble_data
arguments: label: D26
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string

tool: D27: %d

tool: D44: %s

tool: D26: 


tool: D3: Rounak

tool: D13: Sanchit

assistant: ```c
main() {
  int i, t, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    char s[n];
    scanf("%s", s);
    if (s[0] == 'R')
      printf("Rounak");
    if (s[0] == 'G')
      printf("Sanchit");
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  lea    -0x3c(%rbp),%r15
  push   %r13
  lea    D43(%rip),%r13
  lea    D34(%rip),%r14
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  jle    L4
  nop
L55:
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L6
L56:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L56
L6:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L71
  orq    $0x0,-0x8(%rsp,%rdx,1)
L71:
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl (%rsp),%eax
  cmp    $0x52,%al
  jne    L64
  lea    D45(%rip),%rdi
  call   <printf@plt>
  movzbl (%rsp),%eax
L64:
  cmp    $0x47,%al
  je     L62
L29:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r12,%rsp
  cmp    %ebx,-0x40(%rbp)
  jg     L55
L4:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L62:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D43
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D45
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D43: %d

tool: D34: 


tool: D15: %s

tool: D45: Rounak

tool: D9: Sanchit

assistant: ```c
main() {
  int i, t, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    char s[n];
    scanf("%s", s);
    if (s[0] == 'R')
      printf("Rounak");
    if (s[0] == 'G')
      printf("Sanchit");
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D40(%rip),%r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  lea    -0x3c(%rbp),%r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  jle    L57
  nop
L76:
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L82
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L7
L82:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L39
  orq    $0x0,-0x8(%rsp,%rdx,1)
L39:
  mov    %rsp,%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl (%rsp),%eax
  cmp    $0x52,%al
  jne    L79
  lea    D20(%rip),%rdi
  call   <printf@plt>
  movzbl (%rsp),%eax
L79:
  cmp    $0x47,%al
  je     L56
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r12,%rsp
  cmp    %ebx,-0x40(%rbp)
  jg     L76
L57:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L56:
  lea    D36(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12,%rsp
  cmp    -0x40(%rbp),%ebx
  jl     L76
  jmp    L57
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D40
data_type: string
name: read_data
arguments: data_tag: D26
data_type: string
name: read_data
arguments: data_tag: D24
data_type: string
name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string

tool: D40: 


tool: D26: %d

tool: D24: %s

tool: D20: Rounak

tool: D36: Sanchit

assistant: ```c
main() {
  int i, t, n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    char s[n];
    scanf("%s", s);
    if (s[0] == 'R')
      printf("Rounak");
    if (s[0] == 'G')
      printf("Sanchit");
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<asn1DecodeFlags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L9
L21:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     %rax,%rsi
  mov    %rsi,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jle    L11
  cmpq   $0x0,-0x20(%rbp)
  jne    L21
L11:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void asn1DecodeFlags(unsigned char *data, size_t length, unsigned long *flags) {
  int c = 4;
  *flags = 0;
  while ((c-- > 0) && (length > 0)) {
    *flags |= *data << (c << 3);
    data++;
    length--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<asn1DecodeFlags>:
  endbr64
  movq   $0x0,(%rdx)
  test   %rsi,%rsi
  je     L19
  mov    %rdi,%r9
  mov    $0x3,%r8d
  add    %rsi,%rdi
L10:
  movzbl (%r9),%eax
  lea    0x0(,%r8,8),%ecx
  shl    %cl,%eax
  cltq
  or     %rax,(%rdx)
  add    $0x1,%r9
  cmp    %rdi,%r9
  setne  %cl
  test   %r8d,%r8d
  setg   %al
  sub    $0x1,%r8d
  test   %al,%cl
  jne    L10
L19:
  ret
```

assistant: ```c
void asn1DecodeFlags(unsigned char *data, size_t length, unsigned long *flags) {
  int c = 4;
  *flags = 0;
  while ((c-- > 0) && (length > 0)) {
    *flags |= *data << (c << 3);
    data++;
    length--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<asn1DecodeFlags>:
  endbr64
  movq   $0x0,(%rdx)
  test   %rsi,%rsi
  je     L11
  mov    $0x3,%r8d
  xor    %r9d,%r9d
  add    %rdi,%rsi
L18:
  movzbl (%rdi),%eax
  lea    0x0(,%r8,8),%ecx
  add    $0x1,%rdi
  shl    %cl,%eax
  cltq
  or     %rax,%r9
  cmp    %rsi,%rdi
  setne  %cl
  test   %r8d,%r8d
  mov    %r9,(%rdx)
  setne  %al
  sub    $0x1,%r8d
  test   %al,%cl
  jne    L18
L11:
  ret
```

assistant: ```c
void asn1DecodeFlags(unsigned char *data, size_t length, unsigned long *flags) {
  int c = 4;
  *flags = 0;
  while ((c-- > 0) && (length > 0)) {
    *flags |= *data << (c << 3);
    data++;
    length--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<asn1DecodeFlags>:
  endbr64
  movq   $0x0,(%rdx)
  mov    %rdx,%rax
  test   %rsi,%rsi
  je     L32
  movzbl (%rdi),%ecx
  shl    $0x18,%ecx
  movslq %ecx,%rdx
  mov    %rdx,(%rax)
  cmp    $0x1,%rsi
  je     L32
  movzbl 0x1(%rdi),%edx
  shl    $0x10,%edx
  or     %ecx,%edx
  movslq %edx,%rcx
  mov    %rcx,(%rax)
  cmp    $0x2,%rsi
  je     L32
  movzbl 0x2(%rdi),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  movslq %edx,%rdx
  mov    %rdx,(%rax)
  cmp    $0x3,%rsi
  je     L32
  movzbl 0x3(%rdi),%ecx
  or     %rcx,%rdx
  mov    %rdx,(%rax)
L32:
  ret
```

assistant: ```c
void asn1DecodeFlags(unsigned char *data, size_t length, unsigned long *flags) {
  int c = 4;
  *flags = 0;
  while ((c-- > 0) && (length > 0)) {
    *flags |= *data << (c << 3);
    data++;
    length--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <start_watchdog@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sem_init@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sem_init@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_wait@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_post@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_destroy@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(void) {
  int r;
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <start_watchdog@plt>
  lea    0x4(%rsp),%rbx
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <sem_init@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <sem_init@plt>
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <sem_wait@plt>
  mov    %rbx,%rdi
  call   <sem_post@plt>
  mov    %rbx,%rdi
  call   <sem_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int r;
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <start_watchdog@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    %rbp,%rdi
  call   <sem_init@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <sem_init@plt>
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <sem_wait@plt>
  mov    %rbp,%rdi
  call   <sem_post@plt>
  mov    %rbp,%rdi
  call   <sem_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int r;
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <start_watchdog@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    %rbp,%rdi
  call   <sem_init@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <sem_init@plt>
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <sem_wait@plt>
  mov    %rbp,%rdi
  call   <sem_post@plt>
  mov    %rbp,%rdi
  call   <sem_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int r;
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```