user: 这段汇编代码用C语言表示是什么样的:

```asm
<calc_median_limits>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jne    L78
  movl   $0x0,(%rdx)
  mov    %r12,%rdi
  movl   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <ckfree@plt>
  nopw   0x0(%rax,%rax,1)
L78:
  mov    %rdi,%rbp
  lea    0x4(,%rsi,4),%edi
  mov    %esi,%ebx
  call   <ckalloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L64
  lea    0x4(%rbp),%rdx
  lea    -0x1(%rbx),%r8d
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L33
  cmp    $0x2,%r8d
  jbe    L33
  mov    %ebx,%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  xchg   %ax,%ax
L152:
  movups 0x0(%rbp,%rax,1),%xmm5
  movups %xmm5,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L152
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L161
  mov    %eax,%ecx
  movss  0x0(%rbp,%rcx,4),%xmm0
  lea    0x0(,%rcx,4),%rdx
  movss  %xmm0,(%r12,%rcx,4)
  lea    0x1(%rax),%ecx
  cmp    %ebx,%ecx
  jge    L161
  movss  0x4(%rbp,%rdx,1),%xmm0
  add    $0x2,%eax
  movss  %xmm0,0x4(%r12,%rdx,1)
  cmp    %eax,%ebx
  jle    L161
  movss  0x8(%rbp,%rdx,1),%xmm0
  movss  %xmm0,0x8(%r12,%rdx,1)
L161:
  xor    %esi,%esi
  mov    %r8d,%edx
  mov    %r12,%rdi
  call   <sort_scores@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movsd  D11(%rip),%xmm3
  cvtsi2sd %ebx,%xmm0
  mulsd  D23(%rip),%xmm0
  addsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvttss2si %xmm0,%eax
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  ucomiss D48(%rip),%xmm0
  jp     L89
  jne    L89
  movslq %eax,%rdx
  movss  D48(%rip),%xmm2
  movss  0x4(%r12,%rdx,4),%xmm1
  addss  (%r12,%rdx,4),%xmm1
  mov    %ebx,%edx
  sub    %eax,%edx
  movslq %edx,%rax
  movss  -0x4(%r12,%rax,4),%xmm0
  addss  (%r12,%rax,4),%xmm0
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm0
L85:
  cmp    $0x3,%ebx
  jg     L107
  movss  (%r12),%xmm0
  movslq %ebx,%rbx
  mov    %r12,%rdi
  movss  %xmm0,(%r14)
  movss  -0x4(%r12,%rbx,4),%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  movss  %xmm0,0x0(%r13)
  pop    %r13
  pop    %r14
  jmp    1080 <ckfree@plt>
  nopw   0x0(%rax,%rax,1)
L89:
  mov    %ebx,%edx
  movslq %eax,%rcx
  sub    %eax,%edx
  comiss D48(%rip),%xmm0
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  jbe    L80
  movss  0x4(%r12,%rcx,4),%xmm1
  movss  -0x4(%r12,%rdx,1),%xmm0
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L107:
  movaps %xmm1,%xmm4
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  pop    %rbx
  subss  %xmm0,%xmm4
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  cvtss2sd %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  subss  %xmm4,%xmm0
  addsd  %xmm1,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,(%r14)
  movss  %xmm0,0x0(%r13)
  pop    %r13
  pop    %r14
  jmp    1080 <ckfree@plt>
  xchg   %ax,%ax
L80:
  movss  (%r12,%rcx,4),%xmm1
  movss  (%r12,%rax,4),%xmm0
  jmp    L85
  nopl   0x0(%rax)
L33:
  mov    %ebx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L129:
  movss  0x0(%rbp,%rax,4),%xmm0
  movss  %xmm0,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L129
  jmp    L161
  nopw   0x0(%rax,%rax,1)
L64:
  lea    -0x1(%rbx),%r8d
  jmp    L161
```

tool_calls: name: parse_data
arguments: label: D11
data_type: f64
name: parse_data
arguments: label: D23
data_type: byte[8]
name: parse_data
arguments: label: D48
data_type: byte[4]

tool: D11: 0.5

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D48": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void calc_median_limits(float *scores, int n, float *ll, float *ul) {
  int i;
  float t, q1, q3;
  float *sortedscores;
  if (n == 0) {
    (*ul) = (*ll) = 0;
  } else {
    sortedscores = ckalloc((n + 1) * sizeof(float));
    for (i = 0; i < n; i++)
      sortedscores[i] = scores[i];
    sort_scores(sortedscores, 0, n - 1);
    t = n / 4.0 + 0.5;
    if (t - (int)t == 0.5) {
      q3 = (sortedscores[(int)t] + sortedscores[(int)t + 1]) / 2.0;
      q1 = (sortedscores[n - (int)t] + sortedscores[n - (int)t - 1]) / 2.0;
    } else if (t - (int)t > 0.5) {
      q3 = sortedscores[(int)t + 1];
      q1 = sortedscores[n - (int)t - 1];
    } else {
      q3 = sortedscores[(int)t];
      q1 = sortedscores[n - (int)t];
    }
    if (n < 4) {
      (*ul) = sortedscores[0];
      (*ll) = sortedscores[n - 1];
    } else {
      (*ul) = q3 + (q3 - q1) / 2.0;
      (*ll) = q1 - (q3 - q1);
    }
  }
  ckfree(sortedscores);
}
```