ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L8
  xchg   %ax,%ax
L7:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L7
  ret
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  while (n > 1) {
    result *= n--;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  jmp    L9
L7:
  movsbl -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L9:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jg     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void fill(int numFillers, char filler) {
  while (numFillers-- > 0) {
    putchar(filler);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fill>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%ebx
  movsbl %sil,%ebp
L6:
  mov    %ebp,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

assistant: ```c
void fill(int numFillers, char filler) {
  while (numFillers-- > 0) {
    putchar(filler);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fill>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %rbp
  movsbl %sil,%ebp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L2:
  mov    %ebp,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void fill(int numFillers, char filler) {
  while (numFillers-- > 0) {
    putchar(filler);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fill>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %rbp
  movsbl %sil,%ebp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L7:
  mov    %ebp,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void fill(int numFillers, char filler) {
  while (numFillers-- > 0) {
    putchar(filler);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f_vector_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L16
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <flag_table_3_3@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L16
  mov    -0x4(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L11
  lea    D1(%rip),%rax
  jmp    L12
L11:
  lea    D10(%rip),%rax
L12:
  mov    -0x30(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <sprintf@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x30(%rbp)
L16:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string

tool: D1: winds(grid)

tool: D10: winds(N/S)

assistant: ```c
int f_vector_dir(int mode, unsigned char **sec, float *data, unsigned int ndata, char *inv_out, void **local) {
  int res;
  if (mode >= 0) {
    res = flag_table_3_3(sec);
    if (res >= 0) {
      sprintf(inv_out, res & 8 ? "winds(grid)" : "winds(N/S)");
      inv_out += strlen(inv_out);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f_vector_dir>:
  endbr64
  test   %edi,%edi
  jns    L16
  mov    $0x0,%eax
  ret
L16:
  push   %rbx
  mov    %r8,%rbx
  mov    %rsi,%rdi
  call   <flag_table_3_3@plt>
  test   %eax,%eax
  js     L18
  test   $0x8,%al
  lea    D11(%rip),%rsi
  lea    D4(%rip),%rax
  cmove  %rax,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
L18:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D11: winds(grid)

tool: D4: winds(N/S)

assistant: ```c
int f_vector_dir(int mode, unsigned char **sec, float *data, unsigned int ndata, char *inv_out, void **local) {
  int res;
  if (mode >= 0) {
    res = flag_table_3_3(sec);
    if (res >= 0) {
      sprintf(inv_out, res & 8 ? "winds(grid)" : "winds(N/S)");
      inv_out += strlen(inv_out);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f_vector_dir>:
  endbr64
  test   %edi,%edi
  jns    L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  push   %rbp
  mov    %rsi,%rdi
  mov    %r8,%rbp
  call   <flag_table_3_3@plt>
  test   %eax,%eax
  js     L13
  test   $0x8,%al
  lea    D8(%rip),%rsi
  lea    D15(%rip),%rax
  mov    %rbp,%rdi
  cmove  %rax,%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
L13:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D15
type_infered: string

tool: D8: winds(grid)

tool: D15: winds(N/S)

assistant: ```c
int f_vector_dir(int mode, unsigned char **sec, float *data, unsigned int ndata, char *inv_out, void **local) {
  int res;
  if (mode >= 0) {
    res = flag_table_3_3(sec);
    if (res >= 0) {
      sprintf(inv_out, res & 8 ? "winds(grid)" : "winds(N/S)");
      inv_out += strlen(inv_out);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f_vector_dir>:
  endbr64
  test   %edi,%edi
  jns    L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  push   %rbp
  mov    %rsi,%rdi
  mov    %r8,%rbp
  call   <flag_table_3_3@plt>
  test   %eax,%eax
  js     L10
  test   $0x8,%al
  lea    D11(%rip),%rsi
  lea    D1(%rip),%rax
  mov    %rbp,%rdi
  cmove  %rax,%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
L10:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string

tool: D11: winds(grid)

tool: D1: winds(N/S)

assistant: ```c
int f_vector_dir(int mode, unsigned char **sec, float *data, unsigned int ndata, char *inv_out, void **local) {
  int res;
  if (mode >= 0) {
    res = flag_table_3_3(sec);
    if (res >= 0) {
      sprintf(inv_out, res & 8 ? "winds(grid)" : "winds(N/S)");
      inv_out += strlen(inv_out);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__arch_copy_to_user>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__arch_copy_to_user>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__arch_copy_to_user>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__arch_copy_to_user>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<feed_text_init_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <feed_text_init@plt>
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  leave
  ret
```

assistant: ```c
char feed_text_init_cb(void *const p_object, struct feed_client *const p_client, void const *const p_descriptor) {
  char b_result;
  struct feed_text *const p_text = (struct feed_text *)(p_object);
  (void)(p_descriptor);
  b_result = feed_text_init(p_text, p_client);
  return b_result;
}
```
user: What is the c source code of the assembly code below?

```asm
<feed_text_init_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <feed_text_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char feed_text_init_cb(void *const p_object, struct feed_client *const p_client, void const *const p_descriptor) {
  char b_result;
  struct feed_text *const p_text = (struct feed_text *)(p_object);
  (void)(p_descriptor);
  b_result = feed_text_init(p_text, p_client);
  return b_result;
}
```
user: What is the c source code of the assembly code below?

```asm
<feed_text_init_cb>:
  endbr64
  jmp    1050 <feed_text_init@plt>
```

assistant: ```c
char feed_text_init_cb(void *const p_object, struct feed_client *const p_client, void const *const p_descriptor) {
  char b_result;
  struct feed_text *const p_text = (struct feed_text *)(p_object);
  (void)(p_descriptor);
  b_result = feed_text_init(p_text, p_client);
  return b_result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<feed_text_init_cb>:
  endbr64
  jmp    1050 <feed_text_init@plt>
```

assistant: ```c
char feed_text_init_cb(void *const p_object, struct feed_client *const p_client, void const *const p_descriptor) {
  char b_result;
  struct feed_text *const p_text = (struct feed_text *)(p_object);
  (void)(p_descriptor);
  b_result = feed_text_init(p_text, p_client);
  return b_result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<namco_setParamsC0XX_GuessN175>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <namcoGuessN175@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <namco_setParamsC0XX_N175@plt>
  nop
  leave
  ret
```

assistant: ```c
void namco_setParamsC0XX_GuessN175(uint16_t addr, uint8_t val) {
  namcoGuessN175(addr);
  namco_setParamsC0XX_N175(addr, val);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<namco_setParamsC0XX_GuessN175>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <namcoGuessN175@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <namco_setParamsC0XX_N175@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void namco_setParamsC0XX_GuessN175(uint16_t addr, uint8_t val) {
  namcoGuessN175(addr);
  namco_setParamsC0XX_N175(addr, val);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<namco_setParamsC0XX_GuessN175>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <namcoGuessN175@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <namco_setParamsC0XX_N175@plt>
```

assistant: ```c
void namco_setParamsC0XX_GuessN175(uint16_t addr, uint8_t val) {
  namcoGuessN175(addr);
  namco_setParamsC0XX_N175(addr, val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<namco_setParamsC0XX_GuessN175>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <namcoGuessN175@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <namco_setParamsC0XX_N175@plt>
```

assistant: ```c
void namco_setParamsC0XX_GuessN175(uint16_t addr, uint8_t val) {
  namcoGuessN175(addr);
  namco_setParamsC0XX_N175(addr, val);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x4,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func2(int x) {
  static char buffer[100];
  return 4;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<func2>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int func2(int x) {
  static char buffer[100];
  return 4;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func2>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int func2(int x) {
  static char buffer[100];
  return 4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func2>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int func2(int x) {
  static char buffer[100];
  return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L7:
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L15:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    D28(%rip),%eax
  add    %edx,%eax
  mov    %eax,D25(%rip)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x3,-0x4(%rbp)
  jle    L15
  addl   $0x1,-0x8(%rbp)
L22:
  cmpl   $0x2,-0x8(%rbp)
  jle    L7
  mov    D25(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_all(int (*arr)[4]) {
  static int tot = 0;
  for (int r = 0; r < 3; r++)
    for (int c = 0; c < 4; c++)
      tot += arr[r][c];
  return tot;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum_all>:
  endbr64
  mov    D12(%rip),%eax
  mov    %rdi,%rdx
  add    $0x30,%rdi
L5:
  add    (%rdx),%eax
  add    0x4(%rdx),%eax
  add    0x8(%rdx),%eax
  add    0xc(%rdx),%eax
  add    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L5
  mov    %eax,D7(%rip)
  ret
```

assistant: ```c
int sum_all(int (*arr)[4]) {
  static int tot = 0;
  for (int r = 0; r < 3; r++)
    for (int c = 0; c < 4; c++)
      tot += arr[r][c];
  return tot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum_all>:
  endbr64
  mov    D19(%rip),%eax
  lea    0x30(%rdi),%rdx
L5:
  add    (%rdi),%eax
  add    $0x10,%rdi
  add    -0xc(%rdi),%eax
  add    -0x8(%rdi),%eax
  add    -0x4(%rdi),%eax
  cmp    %rdi,%rdx
  jne    L5
  mov    %eax,D3(%rip)
  ret
```

assistant: ```c
int sum_all(int (*arr)[4]) {
  static int tot = 0;
  for (int r = 0; r < 3; r++)
    for (int c = 0; c < 4; c++)
      tot += arr[r][c];
  return tot;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum_all>:
  endbr64
  movdqu (%rdi),%xmm2
  movd   D13(%rip),%xmm0
  movdqu 0x10(%rdi),%xmm1
  paddd  %xmm2,%xmm0
  paddd  %xmm0,%xmm1
  movdqu 0x20(%rdi),%xmm0
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %xmm0,D16(%rip)
  ret
```

assistant: ```c
int sum_all(int (*arr)[4]) {
  static int tot = 0;
  for (int r = 0; r < 3; r++)
    for (int c = 0; c < 4; c++)
      tot += arr[r][c];
  return tot;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ken_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mutex_init@plt>
  mov    $0x0,%eax
  call   <irq_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ken_init() {
  mutex_init();
  irq_init();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ken_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mutex_init@plt>
  mov    $0x0,%eax
  call   <irq_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ken_init() {
  mutex_init();
  irq_init();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ken_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mutex_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <irq_init@plt>
```

assistant: ```c
void ken_init() {
  mutex_init();
  irq_init();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<initmac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <defmac@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <defmac@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D7: mc6809	1

tool: D11: smallc	1

assistant: ```c
void initmac(void) {
  defmac("mc6809\t1");
  defmac("smallc\t1");
}
```
user: What is the c source code of the assembly code below:

```asm
<initmac>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <defmac@plt>
  lea    D18(%rip),%rdi
  call   <defmac@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string

tool: D2: mc6809	1

tool: D18: smallc	1

assistant: ```c
void initmac(void) {
  defmac("mc6809\t1");
  defmac("smallc\t1");
}
```
user: Translate the below assembly code into C programming language:

```asm
<initmac>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <defmac@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <defmac@plt>
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string

tool: D15: mc6809	1

tool: D17: smallc	1

assistant: ```c
void initmac(void) {
  defmac("mc6809\t1");
  defmac("smallc\t1");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initmac>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <defmac@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <defmac@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D0: mc6809	1

tool: D18: smallc	1

assistant: ```c
void initmac(void) {
  defmac("mc6809\t1");
  defmac("smallc\t1");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sendStart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x80,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <myWrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void sendStart(int fd) {
  uint8_t data[1] = {128};
  myWrite(fd, data, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sendStart>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x80,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <myWrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sendStart(int fd) {
  uint8_t data[1] = {128};
  myWrite(fd, data, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sendStart>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x80,0x4(%rsp)
  call   <myWrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sendStart(int fd) {
  uint8_t data[1] = {128};
  myWrite(fd, data, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sendStart>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x80,0x4(%rsp)
  call   <myWrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sendStart(int fd) {
  uint8_t data[1] = {128};
  myWrite(fd, data, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_sys_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  mov    -0x18(%rbp),%rax
  lea    -0x10(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L7
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x10(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L7
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x10(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x20(%rbp)
L7:
  cmpq   $0x0,-0x38(%rbp)
  je     L55
  mov    -0x38(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L55:
  cmpq   $0x0,-0x40(%rbp)
  je     L39
  mov    -0x40(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
L39:
  cmpq   $0x0,-0x48(%rbp)
  je     L5
  mov    -0x48(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
L5:
  mov    -0x1c(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x20(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned int get_sys_version(int *major, int *minor, int *minor2) {
  struct utsname un;
  int m1;
  int m2;
  int m3;
  char *p;
  memset(&un, 0, sizeof(un));
  m1 = m2 = m3 = 0;
  uname(&un);
  m1 = strtol(un.release, &p, 10);
  if (*p == '.') {
    p++;
    m2 = strtol(p, &p, 10);
    if (*p == '.') {
      p++;
      m3 = strtol(p, &p, 10);
    }
  }
  if (major)
    *major = m1;
  if (minor)
    *minor = m2;
  if (minor2)
    *minor2 = m3;
  return ((m1 << 16) | (m2 << 8) | (m3));
}
```