ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kernel>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  lea    0x2100(%rdi),%rbp
  lea    0x2100(%rsi),%r11
  push   %rbx
  mov    $0x800,%ebx
L25:
  mov    %ebx,%r9d
  mov    %r11,%rdi
  mov    %rbp,%rcx
  mov    $0x40,%esi
  lea    0xe00(%rbp),%r10
  nopl   0x0(%rax)
L11:
  mov    $0x2,%edx
  nopl   (%rax)
L3:
  lea    0x22(%rdx),%eax
  movss  (%rcx,%rdx,4),%xmm0
  addss  -0x4(%rcx,%rdx,4),%xmm0
  and    $0x1f,%eax
  add    %esi,%eax
  add    %r9d,%eax
  cltq
  addss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x1e,%rdx
  jne    L3
  sub    $0xffffffffffffff80,%rcx
  add    $0x20,%esi
  sub    $0xffffffffffffff80,%rdi
  cmp    %rcx,%r10
  jne    L11
  add    $0x400,%rbx
  add    $0x1000,%rbp
  add    $0x1000,%r11
  cmp    $0x7800,%rbx
  jne    L25
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kernel(float *g1, float *g2) {
  int x, y, z;
  int halo_width = 2;
  for (z = halo_width; z < 32 - halo_width; ++z) {
    for (y = halo_width; y < 32 - halo_width; ++y) {
      for (x = halo_width; x < 32 - halo_width; ++x) {
        float v = g1[((x) + (y)*32 + (z)*32 * 32)] + g1[((x - 1) + (y)*32 + (z)*32 * 32)] + g1[((((x + 2) + 32) % 32) + (y)*32 + (z)*32 * 32)];
        g2[((x) + (y)*32 + (z)*32 * 32)] = v;
      }
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kernel>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  lea    0x2100(%rdi),%rbp
  lea    0x2100(%rsi),%r11
  push   %rbx
  mov    $0x800,%ebx
L2:
  mov    %ebx,%r9d
  mov    %r11,%rdi
  mov    %rbp,%rcx
  mov    $0x40,%esi
  lea    0xe00(%rbp),%r10
  nopl   0x0(%rax)
L18:
  mov    $0x2,%edx
  nopl   (%rax)
L11:
  lea    0x22(%rdx),%eax
  movss  (%rcx,%rdx,4),%xmm0
  addss  -0x4(%rcx,%rdx,4),%xmm0
  and    $0x1f,%eax
  add    %esi,%eax
  add    %r9d,%eax
  cltq
  addss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x1e,%rdx
  jne    L11
  sub    $0xffffffffffffff80,%rcx
  add    $0x20,%esi
  sub    $0xffffffffffffff80,%rdi
  cmp    %rcx,%r10
  jne    L18
  add    $0x400,%rbx
  add    $0x1000,%rbp
  add    $0x1000,%r11
  cmp    $0x7800,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kernel(float *g1, float *g2) {
  int x, y, z;
  int halo_width = 2;
  for (z = halo_width; z < 32 - halo_width; ++z) {
    for (y = halo_width; y < 32 - halo_width; ++y) {
      for (x = halo_width; x < 32 - halo_width; ++x) {
        float v = g1[((x) + (y)*32 + (z)*32 * 32)] + g1[((x - 1) + (y)*32 + (z)*32 * 32)] + g1[((((x + 2) + 32) % 32) + (y)*32 + (z)*32 * 32)];
        g2[((x) + (y)*32 + (z)*32 * 32)] = v;
      }
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L16
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L16
  movsd  D3(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L13
L16:
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L13:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: f32[2]

tool: {"D3": [0.0,-1.875]}

assistant: ```c
double s_r(double redchan, double nirchan) {
  double result;
  if ((redchan) == 0.0) {
    result = -1.0;
  } else {
    result = (nirchan / redchan);
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s_r>:
  endbr64
  ucomisd D5(%rip),%xmm0
  jp     L11
  movsd  D4(%rip),%xmm2
  jne    L11
L24:
  movapd %xmm2,%xmm0
  ret
L11:
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  jmp    L24
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: f64
name: read_data
arguments: label: D4
type_guessed: byte[8]

tool: D5: 0

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double s_r(double redchan, double nirchan) {
  double result;
  if ((redchan) == 0.0) {
    result = -1.0;
  } else {
    result = (nirchan / redchan);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<s_r>:
  endbr64
  ucomisd D10(%rip),%xmm0
  jp     L5
  movsd  D19(%rip),%xmm2
  jne    L5
  movapd %xmm2,%xmm0
  ret
  nopl   (%rax)
L5:
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
datatype: f64
name: disassemble_data
arguments: tag: D19
datatype: byte[8]

tool: D10: 0

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double s_r(double redchan, double nirchan) {
  double result;
  if ((redchan) == 0.0) {
    result = -1.0;
  } else {
    result = (nirchan / redchan);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<s_r>:
  endbr64
  ucomisd D6(%rip),%xmm0
  jp     L18
  movsd  D7(%rip),%xmm2
  jne    L18
  movapd %xmm2,%xmm0
  ret
  nopl   (%rax)
L18:
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: f64
name: read_data
arguments: label: D7
type_guessed: byte[8]

tool: D6: 0

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double s_r(double redchan, double nirchan) {
  double result;
  if ((redchan) == 0.0) {
    result = -1.0;
  } else {
    result = (nirchan / redchan);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qtdDigitosW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L1:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpq   $0x9,-0x18(%rbp)
  jg     L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int qtdDigitosW(long int num) {
  int qtd = 1;
  while (num >= 10) {
    num = num / 10;
    qtd++;
  }
  return qtd;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<qtdDigitosW>:
  endbr64
  cmp    $0x9,%rdi
  jle    L14
  mov    $0x1,%ecx
  movabs $0x6666666666666667,%r8
L27:
  mov    %rdi,%rsi
  mov    %rdi,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rdi
  add    $0x1,%ecx
  cmp    $0x63,%rsi
  jg     L27
L19:
  mov    %ecx,%eax
  ret
L14:
  mov    $0x1,%ecx
  jmp    L19
```

assistant: ```c
int qtdDigitosW(long int num) {
  int qtd = 1;
  while (num >= 10) {
    num = num / 10;
    qtd++;
  }
  return qtd;
}
```
user: What is the c source code of the assembly code below:

```asm
<qtdDigitosW>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%r8d
  cmp    $0x9,%rdi
  jle    L2
  movabs $0xcccccccccccccccd,%rsi
  nopl   (%rax)
L18:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L18
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int qtdDigitosW(long int num) {
  int qtd = 1;
  while (num >= 10) {
    num = num / 10;
    qtd++;
  }
  return qtd;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<qtdDigitosW>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%r8d
  cmp    $0x9,%rdi
  jle    L0
  movabs $0xcccccccccccccccd,%rsi
  nopl   (%rax)
L9:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L9
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int qtdDigitosW(long int num) {
  int qtd = 1;
  while (num >= 10) {
    num = num / 10;
    qtd++;
  }
  return qtd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movabs $0x1000000000000000,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <f0@plt>
  movabs $0x800000000000000,%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <f1@plt>
  movabs $0x400000000000000,%rax
  mov    %rax,%rdx
  mov    $0x1e,%esi
  mov    $0x14,%edi
  mov    $0x0,%eax
  call   <f2@plt>
  movabs $0x200000000000000,%rax
  mov    %rax,%rcx
  mov    $0x3c,%edx
  mov    $0x32,%esi
  mov    $0x28,%edi
  mov    $0x0,%eax
  call   <f3@plt>
  movabs $0x100000000000000,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <f4@plt>
  movabs $0x20000000000000,%rax
  mov    %rax,%rcx
  movabs $0x40000000000000,%rax
  mov    %rax,%rdx
  movabs $0x80000000000000,%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <f5@plt>
  movabs $0x10000000000000,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <f7@plt>
  mov    %eax,%edx
  movabs $0x800000000000000,%rax
  mov    %rax,%rcx
  mov    $0x50,%esi
  mov    $0x46,%edi
  mov    $0x0,%eax
  call   <f6@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
data_type: string

tool: D10: %ld


assistant: ```c
int main(void) {
  printf("%ld\n", __alignof__(char));
  printf("%ld\n", __alignof__(short));
  printf("%ld\n", __alignof__(int));
  printf("%ld\n", __alignof__(long));
  f0(1152921504606846976LL);
  f1(10, 576460752303423488LL);
  f2(20, 30, 288230376151711744LL);
  f3(40, 50, 60, 144115188075855872LL);
  f4(72057594037927936LL);
  f5(3, 36028797018963968LL, 18014398509481984LL, 9007199254740992LL);
  f6(70, 80, f7(4503599627370496LL), 576460752303423488LL);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movabs $0x1000000000000000,%rdi
  mov    $0x0,%eax
  call   <f0@plt>
  movabs $0x800000000000000,%rbx
  mov    %rbx,%rsi
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <f1@plt>
  movabs $0x400000000000000,%rdx
  mov    $0x1e,%esi
  mov    $0x14,%edi
  mov    $0x0,%eax
  call   <f2@plt>
  movabs $0x200000000000000,%rcx
  mov    $0x3c,%edx
  mov    $0x32,%esi
  mov    $0x28,%edi
  mov    $0x0,%eax
  call   <f3@plt>
  movabs $0x100000000000000,%rdi
  mov    $0x0,%eax
  call   <f4@plt>
  movabs $0x20000000000000,%rcx
  movabs $0x40000000000000,%rdx
  movabs $0x80000000000000,%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <f5@plt>
  movabs $0x10000000000000,%rdi
  mov    $0x0,%eax
  call   <f7@plt>
  mov    %eax,%edx
  mov    %rbx,%rcx
  mov    $0x50,%esi
  mov    $0x46,%edi
  mov    $0x0,%eax
  call   <f6@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: %ld


assistant: ```c
int main(void) {
  printf("%ld\n", __alignof__(char));
  printf("%ld\n", __alignof__(short));
  printf("%ld\n", __alignof__(int));
  printf("%ld\n", __alignof__(long));
  f0(1152921504606846976LL);
  f1(10, 576460752303423488LL);
  f2(20, 30, 288230376151711744LL);
  f3(40, 50, 60, 144115188075855872LL);
  f4(72057594037927936LL);
  f5(3, 36028797018963968LL, 18014398509481984LL, 9007199254740992LL);
  f6(70, 80, f7(4503599627370496LL), 576460752303423488LL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  xor    %eax,%eax
  movabs $0x800000000000000,%r12
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  movabs $0x1000000000000000,%rdi
  call   <f0@plt>
  mov    %r12,%rsi
  mov    $0xa,%edi
  xor    %eax,%eax
  call   <f1@plt>
  mov    $0x1e,%esi
  mov    $0x14,%edi
  xor    %eax,%eax
  movabs $0x400000000000000,%rdx
  call   <f2@plt>
  mov    $0x3c,%edx
  mov    $0x32,%esi
  xor    %eax,%eax
  movabs $0x200000000000000,%rcx
  mov    $0x28,%edi
  call   <f3@plt>
  xor    %eax,%eax
  movabs $0x100000000000000,%rdi
  call   <f4@plt>
  mov    $0x3,%edi
  xor    %eax,%eax
  movabs $0x20000000000000,%rcx
  movabs $0x40000000000000,%rdx
  movabs $0x80000000000000,%rsi
  call   <f5@plt>
  xor    %eax,%eax
  movabs $0x10000000000000,%rdi
  call   <f7@plt>
  mov    %r12,%rcx
  mov    $0x50,%esi
  mov    $0x46,%edi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <f6@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: %ld


assistant: ```c
int main(void) {
  printf("%ld\n", __alignof__(char));
  printf("%ld\n", __alignof__(short));
  printf("%ld\n", __alignof__(int));
  printf("%ld\n", __alignof__(long));
  f0(1152921504606846976LL);
  f1(10, 576460752303423488LL);
  f2(20, 30, 288230376151711744LL);
  f3(40, 50, 60, 144115188075855872LL);
  f4(72057594037927936LL);
  f5(3, 36028797018963968LL, 18014398509481984LL, 9007199254740992LL);
  f6(70, 80, f7(4503599627370496LL), 576460752303423488LL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  xor    %eax,%eax
  movabs $0x800000000000000,%r12
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  movabs $0x1000000000000000,%rdi
  call   <f0@plt>
  mov    %r12,%rsi
  mov    $0xa,%edi
  xor    %eax,%eax
  call   <f1@plt>
  mov    $0x1e,%esi
  mov    $0x14,%edi
  xor    %eax,%eax
  movabs $0x400000000000000,%rdx
  call   <f2@plt>
  mov    $0x3c,%edx
  mov    $0x32,%esi
  xor    %eax,%eax
  movabs $0x200000000000000,%rcx
  mov    $0x28,%edi
  call   <f3@plt>
  xor    %eax,%eax
  movabs $0x100000000000000,%rdi
  call   <f4@plt>
  mov    $0x3,%edi
  xor    %eax,%eax
  movabs $0x20000000000000,%rcx
  movabs $0x40000000000000,%rdx
  movabs $0x80000000000000,%rsi
  call   <f5@plt>
  xor    %eax,%eax
  movabs $0x10000000000000,%rdi
  call   <f7@plt>
  mov    %r12,%rcx
  mov    $0x50,%esi
  mov    $0x46,%edi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <f6@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: %ld


assistant: ```c
int main(void) {
  printf("%ld\n", __alignof__(char));
  printf("%ld\n", __alignof__(short));
  printf("%ld\n", __alignof__(int));
  printf("%ld\n", __alignof__(long));
  f0(1152921504606846976LL);
  f1(10, 576460752303423488LL);
  f2(20, 30, 288230376151711744LL);
  f3(40, 50, 60, 144115188075855872LL);
  f4(72057594037927936LL);
  f5(3, 36028797018963968LL, 18014398509481984LL, 9007199254740992LL);
  f6(70, 80, f7(4503599627370496LL), 576460752303423488LL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D103(%rip),%rax
  movq   %rax,%xmm3
  lea    D191(%rip),%r8
  mov    D136(%rip),%rax
  movq   %rax,%xmm2
  lea    D75(%rip),%rcx
  mov    D35(%rip),%rax
  movq   %rax,%xmm1
  lea    D130(%rip),%rdx
  mov    D210(%rip),%rax
  movq   %rax,%xmm0
  lea    D68(%rip),%rsi
  lea    D177(%rip),%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  mov    D103(%rip),%rax
  movq   %rax,%xmm3
  mov    D136(%rip),%rax
  movq   %rax,%xmm2
  mov    D35(%rip),%rax
  movq   %rax,%xmm1
  mov    D210(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x4,%edi
  mov    $0x4,%eax
  call   <average@plt>
  mov    %eax,%ebp
  mov    D136(%rip),%rax
  movq   %rax,%xmm2
  mov    D35(%rip),%rax
  movq   %rax,%xmm1
  mov    D210(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x3,%edi
  mov    $0x3,%eax
  call   <average@plt>
  mov    %eax,%ebx
  mov    D35(%rip),%rax
  movq   %rax,%xmm1
  mov    D210(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x2,%edi
  mov    $0x2,%eax
  call   <average@plt>
  mov    %eax,%edx
  sub    $0x8,%rsp
  push   %rbp
  lea    D67(%rip),%r9
  mov    %ebx,%r8d
  lea    D54(%rip),%rcx
  lea    D86(%rip),%rsi
  lea    D137(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D103
type_guessed: f64
name: disassemble_data
arguments: data_label: D191
type_guessed: string
name: disassemble_data
arguments: data_label: D136
type_guessed: f64
name: disassemble_data
arguments: data_label: D75
type_guessed: string
name: disassemble_data
arguments: data_label: D35
type_guessed: f64
name: disassemble_data
arguments: data_label: D130
type_guessed: string
name: disassemble_data
arguments: data_label: D210
type_guessed: f64
name: disassemble_data
arguments: data_label: D68
type_guessed: string
name: disassemble_data
arguments: data_label: D177
type_guessed: string
name: disassemble_data
arguments: data_label: D67
type_guessed: string
name: disassemble_data
arguments: data_label: D54
type_guessed: string
name: disassemble_data
arguments: data_label: D86
type_guessed: string
name: disassemble_data
arguments: data_label: D137
type_guessed: string

tool: D103: 10.2

tool: D191: z = 

tool: D136: 1.7

tool: D75: y = 

tool: D35: 22.5

tool: D130: x = 

tool: D210: 37.5

tool: D68: w = 

tool: D177: %s%.1f
%s%.1f
%s%.1f
%s%.1f



tool: D67: The average of w, x, y, and z is 

tool: D54: The average of w, x, and y is 

tool: D86: The average of w and x is 

tool: D137: %s%.3f
%s%.3f
%s%.3f


assistant: ```c
int main(void) {
  double w = 37.5;
  double x = 22.5;
  double y = 1.7;
  double z = 10.2;
  printf("%s%.1f\n%s%.1f\n%s%.1f\n%s%.1f\n\n", "w = ", w, "x = ", x, "y = ", y, "z = ", z);
  printf("%s%.3f\n%s%.3f\n%s%.3f\n", "The average of w and x is ", average(2, w, x), "The average of w, x, and y is ", average(3, w, x, y), "The average of w, x, y, and z is ", average(4, w, x, y, z));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D65(%rip),%r8
  lea    D57(%rip),%rcx
  mov    $0x4,%eax
  push   %rbx
  lea    D21(%rip),%rdx
  lea    D14(%rip),%rsi
  lea    D104(%rip),%rdi
  sub    $0x8,%rsp
  movsd  D75(%rip),%xmm3
  movsd  D106(%rip),%xmm2
  movsd  D68(%rip),%xmm1
  movsd  D165(%rip),%xmm0
  call   <printf@plt>
  mov    D75(%rip),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm3
  mov    D106(%rip),%rax
  movq   %rax,%xmm2
  mov    D68(%rip),%rax
  movq   %rax,%xmm1
  mov    D165(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x4,%eax
  call   <average@plt>
  mov    $0x3,%edi
  mov    %eax,%ebp
  mov    D106(%rip),%rax
  movq   %rax,%xmm2
  mov    D68(%rip),%rax
  movq   %rax,%xmm1
  mov    D165(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <average@plt>
  mov    $0x2,%edi
  mov    %eax,%ebx
  mov    D68(%rip),%rax
  movq   %rax,%xmm1
  mov    D165(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <average@plt>
  sub    $0x8,%rsp
  mov    %ebx,%r8d
  lea    D117(%rip),%r9
  push   %rbp
  mov    %eax,%edx
  xor    %eax,%eax
  lea    D187(%rip),%rcx
  lea    D195(%rip),%rsi
  lea    D188(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D65
type_guessed: string
name: disassemble_data
arguments: tag: D57
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D104
type_guessed: string
name: disassemble_data
arguments: tag: D75
type_guessed: f64
name: disassemble_data
arguments: tag: D106
type_guessed: f64
name: disassemble_data
arguments: tag: D68
type_guessed: f64
name: disassemble_data
arguments: tag: D165
type_guessed: f64
name: disassemble_data
arguments: tag: D117
type_guessed: string
name: disassemble_data
arguments: tag: D187
type_guessed: string
name: disassemble_data
arguments: tag: D195
type_guessed: string
name: disassemble_data
arguments: tag: D188
type_guessed: string

tool: D65: z = 

tool: D57: y = 

tool: D21: x = 

tool: D14: w = 

tool: D104: %s%.1f
%s%.1f
%s%.1f
%s%.1f



tool: D75: 10.2

tool: D106: 1.7

tool: D68: 22.5

tool: D165: 37.5

tool: D117: The average of w, x, y, and z is 

tool: D187: The average of w, x, and y is 

tool: D195: The average of w and x is 

tool: D188: %s%.3f
%s%.3f
%s%.3f


assistant: ```c
int main(void) {
  double w = 37.5;
  double x = 22.5;
  double y = 1.7;
  double z = 10.2;
  printf("%s%.1f\n%s%.1f\n%s%.1f\n%s%.1f\n\n", "w = ", w, "x = ", x, "y = ", y, "z = ", z);
  printf("%s%.3f\n%s%.3f\n%s%.3f\n", "The average of w and x is ", average(2, w, x), "The average of w, x, and y is ", average(3, w, x, y), "The average of w, x, y, and z is ", average(4, w, x, y, z));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%r8
  lea    D63(%rip),%rcx
  mov    $0x4,%eax
  push   %rbx
  lea    D45(%rip),%rdx
  lea    D176(%rip),%rsi
  lea    D167(%rip),%rdi
  sub    $0x8,%rsp
  movsd  D111(%rip),%xmm3
  movsd  D72(%rip),%xmm2
  movsd  D135(%rip),%xmm1
  movsd  D36(%rip),%xmm0
  call   <printf@plt>
  mov    D111(%rip),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm3
  mov    D72(%rip),%rax
  movq   %rax,%xmm2
  mov    D135(%rip),%rax
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x4,%eax
  call   <average@plt>
  mov    $0x3,%edi
  mov    %eax,%ebp
  mov    D72(%rip),%rax
  movq   %rax,%xmm2
  mov    D135(%rip),%rax
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <average@plt>
  mov    $0x2,%edi
  mov    %eax,%ebx
  mov    D135(%rip),%rax
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <average@plt>
  sub    $0x8,%rsp
  mov    %ebx,%r8d
  lea    D101(%rip),%r9
  push   %rbp
  mov    %eax,%edx
  xor    %eax,%eax
  lea    D97(%rip),%rcx
  lea    D166(%rip),%rsi
  lea    D85(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string
name: unpack_data
arguments: label: D63
type_guessed: string
name: unpack_data
arguments: label: D45
type_guessed: string
name: unpack_data
arguments: label: D176
type_guessed: string
name: unpack_data
arguments: label: D167
type_guessed: string
name: unpack_data
arguments: label: D111
type_guessed: f64
name: unpack_data
arguments: label: D72
type_guessed: f64
name: unpack_data
arguments: label: D135
type_guessed: f64
name: unpack_data
arguments: label: D36
type_guessed: f64
name: unpack_data
arguments: label: D101
type_guessed: string
name: unpack_data
arguments: label: D97
type_guessed: string
name: unpack_data
arguments: label: D166
type_guessed: string
name: unpack_data
arguments: label: D85
type_guessed: string

tool: D3: z = 

tool: D63: y = 

tool: D45: x = 

tool: D176: w = 

tool: D167: %s%.1f
%s%.1f
%s%.1f
%s%.1f



tool: D111: 10.2

tool: D72: 1.7

tool: D135: 22.5

tool: D36: 37.5

tool: D101: The average of w, x, y, and z is 

tool: D97: The average of w, x, and y is 

tool: D166: The average of w and x is 

tool: D85: %s%.3f
%s%.3f
%s%.3f


assistant: ```c
int main(void) {
  double w = 37.5;
  double x = 22.5;
  double y = 1.7;
  double z = 10.2;
  printf("%s%.1f\n%s%.1f\n%s%.1f\n%s%.1f\n\n", "w = ", w, "x = ", x, "y = ", y, "z = ", z);
  printf("%s%.3f\n%s%.3f\n%s%.3f\n", "The average of w and x is ", average(2, w, x), "The average of w, x, and y is ", average(3, w, x, y), "The average of w, x, y, and z is ", average(4, w, x, y, z));
  return 0;
}
```