ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<longestPalindromeSubseq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L87
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L115
L87:
  mov    $0x0,%eax
  jmp    L58
L115:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L75
L37:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x20(%rbp)
L75:
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L37
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L99
L22:
  movl   $0x0,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L43
L82:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L55
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  add    $0x2,%edx
  mov    %edx,(%rax)
L55:
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L43:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L82
  subl   $0x1,-0x20(%rbp)
L99:
  cmpl   $0x0,-0x20(%rbp)
  jns    L22
  movl   $0x0,-0x20(%rbp)
  jmp    L24
L64:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x20(%rbp)
L24:
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L64
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
L58:
  leave
  ret
```

assistant: ```c
int longestPalindromeSubseq(char *s) {
  int len, *dp, i, j, n, t, ret = 0;
  if (!(s && *s))
    return 0;
  len = strlen(s);
  dp = (int *)malloc(len * sizeof(int));
  for (i = 0; i < len; ++i)
    dp[i] = 1;
  for (i = len - 1; i >= 0; --i) {
    n = 0;
    for (j = i + 1; j < len; ++j) {
      t = dp[j];
      if (s[i] == s[j])
        dp[j] = n + 2;
      n = ((n) > (t) ? (n) : (t));
    }
  }
  for (i = 0; i < len; ++i)
    ret = ((ret) > (dp[i]) ? (ret) : (dp[i]));
  free(dp);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<longestPalindromeSubseq>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L29
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  cmpb   $0x0,(%rdi)
  jne    L109
L20:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L109:
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r10
  test   %ebx,%ebx
  jle    L11
  lea    -0x1(%rbx),%edx
  lea    0x4(%rax,%rdx,4),%rdx
L130:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L130
  mov    %ebx,%r8d
  lea    -0x1(%rbx),%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  jmp    L136
L87:
  cmp    %esi,%edx
  cmovl  %esi,%edx
  add    $0x1,%rax
  add    $0x4,%rcx
  cmp    %eax,%ebx
  jle    L124
L7:
  mov    (%rcx),%esi
  movzbl 0x0(%rbp,%rax,1),%r11d
  cmp    %r11b,(%rdi)
  jne    L87
  lea    0x2(%rdx),%r9d
  mov    %r9d,(%rcx)
  jmp    L87
L124:
  lea    -0x1(%r8),%eax
  sub    $0x1,%rdi
  sub    $0x2,%r8d
  js     L114
  mov    %eax,%r8d
L136:
  cmp    %r8d,%ebx
  jle    L124
  movslq %r8d,%rax
  lea    (%r10,%rax,4),%rcx
  mov    $0x0,%edx
  jmp    L7
L114:
  test   %ebx,%ebx
  jle    L36
  mov    %r10,%rax
  lea    -0x1(%rbx),%edx
  lea    0x4(%r10,%rdx,4),%rcx
  mov    $0x0,%ebx
L43:
  mov    (%rax),%edx
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L43
L166:
  mov    %r10,%rdi
  call   <free@plt>
  jmp    L20
L11:
  mov    $0x0,%ebx
  jmp    L166
L36:
  mov    $0x0,%ebx
  jmp    L166
L29:
  mov    $0x0,%ebx
  jmp    L20
```

assistant: ```c
int longestPalindromeSubseq(char *s) {
  int len, *dp, i, j, n, t, ret = 0;
  if (!(s && *s))
    return 0;
  len = strlen(s);
  dp = (int *)malloc(len * sizeof(int));
  for (i = 0; i < len; ++i)
    dp[i] = 1;
  for (i = len - 1; i >= 0; --i) {
    n = 0;
    for (j = i + 1; j < len; ++j) {
      t = dp[j];
      if (s[i] == s[j])
        dp[j] = n + 2;
      n = ((n) > (t) ? (n) : (t));
    }
  }
  for (i = 0; i < len; ++i)
    ret = ((ret) > (dp[i]) ? (ret) : (dp[i]));
  free(dp);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<longestPalindromeSubseq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L77
  xor    %r13d,%r13d
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  jne    L98
L0:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L98:
  call   <strlen@plt>
  lea    0x0(,%rax,4),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L86
  lea    0x4(%rax),%rdi
  lea    -0x1(%rbp),%edx
  mov    %rdi,0x8(%rsp)
  mov    %rdx,%r15
  lea    (%rdi,%rdx,4),%rdx
  nopl   0x0(%rax)
L108:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L108
  movslq %r15d,%r10
  lea    -0x2(%rbp),%r14d
  lea    0x8(%r12),%r13
  mov    %ebp,%r11d
  lea    (%rbx,%r10,1),%rdi
  nopw   0x0(%rax,%rax,1)
L81:
  cmp    %r11d,%ebp
  jle    L33
  mov    %r14d,%edx
  movslq %r11d,%rcx
  sub    %r10d,%edx
  lea    (%r12,%rcx,4),%rax
  add    %rbx,%rcx
  add    %r10,%rdx
  lea    0x0(%r13,%rdx,4),%r8
  xor    %edx,%edx
  nop
L1:
  mov    (%rax),%esi
  movzbl (%rcx),%r9d
  cmp    %r9b,(%rdi)
  jne    L36
  lea    0x2(%rdx),%r9d
  mov    %r9d,(%rax)
L36:
  cmp    %esi,%edx
  cmovl  %esi,%edx
  add    $0x4,%rax
  add    $0x1,%rcx
  cmp    %r8,%rax
  jne    L1
L33:
  sub    $0x1,%r10
  sub    $0x1,%r11d
  sub    $0x1,%rdi
  test   %r10d,%r10d
  jns    L81
  mov    0x8(%rsp),%rbx
  mov    %r12,%rax
  xor    %r13d,%r13d
  lea    (%rbx,%r15,4),%rcx
  nopl   0x0(%rax)
L25:
  mov    (%rax),%edx
  cmp    %edx,%r13d
  cmovl  %edx,%r13d
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L25
L86:
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L0
L77:
  xor    %r13d,%r13d
  jmp    L0
```

assistant: ```c
int longestPalindromeSubseq(char *s) {
  int len, *dp, i, j, n, t, ret = 0;
  if (!(s && *s))
    return 0;
  len = strlen(s);
  dp = (int *)malloc(len * sizeof(int));
  for (i = 0; i < len; ++i)
    dp[i] = 1;
  for (i = len - 1; i >= 0; --i) {
    n = 0;
    for (j = i + 1; j < len; ++j) {
      t = dp[j];
      if (s[i] == s[j])
        dp[j] = n + 2;
      n = ((n) > (t) ? (n) : (t));
    }
  }
  for (i = 0; i < len; ++i)
    ret = ((ret) > (dp[i]) ? (ret) : (dp[i]));
  free(dp);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<quick_sort_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x30(%rbp)
  movl   $0x8,-0x2c(%rbp)
  movl   $0x9,-0x28(%rbp)
  movl   $0x17,-0x24(%rbp)
  movl   $0x43,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0x1f,-0x10(%rbp)
  movl   $0x38,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <dump@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void quick_sort_test() {
  int test[10] = {5, 8, 9, 23, 67, 1, 3, 7, 31, 56};
  quick_sort(test, 10);
  dump(test, 10);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quick_sort_test>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0x9,0x8(%rsp)
  movl   $0x17,0xc(%rsp)
  movl   $0x43,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x1f,0x20(%rsp)
  movl   $0x38,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <quick_sort@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <dump@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quick_sort_test() {
  int test[10] = {5, 8, 9, 23, 67, 1, 3, 7, 31, 56};
  quick_sort(test, 10);
  dump(test, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quick_sort_test>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000005,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x1700000009,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000043,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x380000001f,%rax
  mov    %rax,0x20(%rsp)
  call   <quick_sort@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <dump@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quick_sort_test() {
  int test[10] = {5, 8, 9, 23, 67, 1, 3, 7, 31, 56};
  quick_sort(test, 10);
  dump(test, 10);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quick_sort_test>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  movdqa D16(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D28(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <quick_sort@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <dump@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: byte[16]
name: parse_data
arguments: data_label: D0
type_infered: byte[8]
name: parse_data
arguments: data_label: D28
type_infered: byte[16]

tool: {"D16": [0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

tool: {"D0": [0x1f,0x00,0x00,0x00,0x38,0x00,0x00,0x00]}

tool: {"D28": [0x43,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
void quick_sort_test() {
  int test[10] = {5, 8, 9, 23, 67, 1, 3, 7, 31, 56};
  quick_sort(test, 10);
  dump(test, 10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L18
L15:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputwc@plt>
L18:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void out(FILE *f, const wchar_t *s, size_t l) {
  while (l--)
    fputwc(*s++, f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<out>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%rbp
  test   %rdx,%rdx
  je     L18
L11:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%edi
  mov    %r12,%rsi
  call   <fputwc@plt>
  sub    $0x1,%rbp
  cmp    $0xffffffffffffffff,%rbp
  jne    L11
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void out(FILE *f, const wchar_t *s, size_t l) {
  while (l--)
    fputwc(*s++, f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<out>:
  endbr64
  test   %rdx,%rdx
  je     L2
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%edi
  mov    %r12,%rsi
  add    $0x4,%rbx
  call   <fputwc@plt>
  sub    $0x1,%rbp
  jae    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void out(FILE *f, const wchar_t *s, size_t l) {
  while (l--)
    fputwc(*s++, f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<out>:
  endbr64
  test   %rdx,%rdx
  je     L11
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%edi
  mov    %r12,%rsi
  add    $0x4,%rbx
  call   <fputwc@plt>
  sub    $0x1,%rbp
  jae    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
void out(FILE *f, const wchar_t *s, size_t l) {
  while (l--)
    fputwc(*s++, f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nontextchars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  jmp    L36
L47:
  subl   $0x1,-0x2c(%rbp)
L36:
  cmpl   $0x0,-0x2c(%rbp)
  jle    L122
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1a,%al
  je     L47
L122:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L151
  movss  D17(%rip),%xmm0
  jmp    L114
L151:
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L159
L145:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jbe    L68
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jbe    L15
L68:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jbe    L148
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x41,%al
  jbe    L15
L148:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L15
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L48
  addl   $0x1,-0x10(%rbp)
  jmp    L15
L48:
  addl   $0x1,-0x14(%rbp)
L15:
  addl   $0x1,-0x18(%rbp)
L159:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L145
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L18
  movss  D17(%rip),%xmm0
  jmp    L114
L18:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
L114:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: f32

tool: D17: 1

assistant: ```c
float nontextchars(char *s, int nbytes) {
  int i, n, badchars, spaces;
  unsigned char *us;
  while (nbytes > 0 && (s[nbytes - 1] == '\0' || s[nbytes - 1] == '\x1a'))
    nbytes--;
  if (nbytes == 0)
    return 1.0;
  n = nbytes;
  badchars = 0;
  spaces = 0;
  us = (unsigned char *)s;
  for (i = 0; i < n; i++) {
    if (!((us[i] >= 'a' && us[i] <= 'z') || (us[i] >= 'A' && us[i] <= 'A') || us[i] >= 128)) {
      if (isspace(us[i]))
        spaces++;
      else
        badchars++;
    }
  }
  if (n == spaces)
    return 1.0;
  return (float)badchars / (float)(n - spaces);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nontextchars>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L11
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rax
  jmp    L91
L68:
  sub    $0x1,%rax
  sub    $0x1,%ebx
  je     L175
L91:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L68
  cmp    $0x1a,%dl
  je     L68
  test   %ebx,%ebx
  je     L170
  jle    L145
  mov    %rdi,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L84
L155:
  add    $0x1,%r14d
L160:
  add    $0x1,%rbp
  cmp    %r12,%rbp
  je     L21
L84:
  movzbl 0x0(%rbp),%edi
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L160
  cmp    $0x41,%dil
  je     L160
  test   %dil,%dil
  js     L160
  movzbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L155
  add    $0x1,%r13d
  jmp    L160
L21:
  cmp    %ebx,%r13d
  je     L77
L42:
  pxor   %xmm0,%xmm0
  cvtsi2ss %r14d,%xmm0
  sub    %r13d,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
L178:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L145:
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L42
L175:
  movss  D3(%rip),%xmm0
  jmp    L178
L170:
  movss  D3(%rip),%xmm0
  jmp    L178
L77:
  movss  D3(%rip),%xmm0
  jmp    L178
L214:
  movss  D3(%rip),%xmm0
  jmp    L178
L11:
  je     L214
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L42
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: f32

tool: D3: 1

assistant: ```c
float nontextchars(char *s, int nbytes) {
  int i, n, badchars, spaces;
  unsigned char *us;
  while (nbytes > 0 && (s[nbytes - 1] == '\0' || s[nbytes - 1] == '\x1a'))
    nbytes--;
  if (nbytes == 0)
    return 1.0;
  n = nbytes;
  badchars = 0;
  spaces = 0;
  us = (unsigned char *)s;
  for (i = 0; i < n; i++) {
    if (!((us[i] >= 'a' && us[i] <= 'z') || (us[i] >= 'A' && us[i] <= 'A') || us[i] >= 128)) {
      if (isspace(us[i]))
        spaces++;
      else
        badchars++;
    }
  }
  if (n == spaces)
    return 1.0;
  return (float)badchars / (float)(n - spaces);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nontextchars>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L95
  movslq %esi,%rax
  mov    %rdi,%rbp
  lea    -0x1(%rdi,%rax,1),%rax
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L141:
  sub    $0x1,%rax
  sub    $0x1,%ebx
  je     L128
L35:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L141
  cmp    $0x1a,%dl
  je     L141
  lea    -0x1(%rbx),%eax
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  lea    0x1(%rbp,%rax,1),%r13
  jmp    L63
  nopl   0x0(%rax)
L155:
  add    $0x1,%rbp
  cmp    %rbp,%r13
  je     L93
L63:
  movzbl 0x0(%rbp),%edi
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L155
  cmp    $0x41,%dil
  je     L155
  test   %dil,%dil
  js     L155
  call   <isspace@plt>
  test   %rax,%rax
  je     L99
  add    $0x1,%rbp
  add    $0x1,%r14d
  cmp    %rbp,%r13
  jne    L63
  xchg   %ax,%ax
L93:
  cmp    %ebx,%r14d
  je     L128
L143:
  sub    %r14d,%ebx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12d,%xmm0
  cvtsi2ss %ebx,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  divss  %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L128:
  pop    %rbx
  movss  D5(%rip),%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L99:
  add    $0x1,%r12d
  jmp    L155
L95:
  je     L128
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  jmp    L143
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: f32

tool: D5: 1

assistant: ```c
float nontextchars(char *s, int nbytes) {
  int i, n, badchars, spaces;
  unsigned char *us;
  while (nbytes > 0 && (s[nbytes - 1] == '\0' || s[nbytes - 1] == '\x1a'))
    nbytes--;
  if (nbytes == 0)
    return 1.0;
  n = nbytes;
  badchars = 0;
  spaces = 0;
  us = (unsigned char *)s;
  for (i = 0; i < n; i++) {
    if (!((us[i] >= 'a' && us[i] <= 'z') || (us[i] >= 'A' && us[i] <= 'A') || us[i] >= 128)) {
      if (isspace(us[i]))
        spaces++;
      else
        badchars++;
    }
  }
  if (n == spaces)
    return 1.0;
  return (float)badchars / (float)(n - spaces);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nontextchars>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L90
  movslq %esi,%rax
  mov    %rdi,%rbp
  lea    -0x1(%rdi,%rax,1),%rax
  jmp    L139
  nopl   0x0(%rax,%rax,1)
L117:
  sub    $0x1,%rax
  sub    $0x1,%ebx
  je     L124
L139:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L117
  cmp    $0x1a,%dl
  je     L117
  lea    -0x1(%rbx),%eax
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  lea    0x1(%rbp,%rax,1),%r13
  jmp    L18
  nopl   0x0(%rax)
L25:
  add    $0x1,%rbp
  cmp    %rbp,%r13
  je     L38
L18:
  movzbl 0x0(%rbp),%edi
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L25
  cmp    $0x41,%dil
  je     L25
  test   %dil,%dil
  js     L25
  call   <isspace@plt>
  test   %rax,%rax
  je     L29
  add    $0x1,%rbp
  add    $0x1,%r14d
  cmp    %rbp,%r13
  jne    L18
  xchg   %ax,%ax
L38:
  cmp    %ebx,%r14d
  je     L124
L62:
  sub    %r14d,%ebx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12d,%xmm0
  cvtsi2ss %ebx,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  divss  %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L124:
  pop    %rbx
  movss  D7(%rip),%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L29:
  add    $0x1,%r12d
  jmp    L25
L90:
  je     L124
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  jmp    L62
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: f32

tool: D7: 1

assistant: ```c
float nontextchars(char *s, int nbytes) {
  int i, n, badchars, spaces;
  unsigned char *us;
  while (nbytes > 0 && (s[nbytes - 1] == '\0' || s[nbytes - 1] == '\x1a'))
    nbytes--;
  if (nbytes == 0)
    return 1.0;
  n = nbytes;
  badchars = 0;
  spaces = 0;
  us = (unsigned char *)s;
  for (i = 0; i < n; i++) {
    if (!((us[i] >= 'a' && us[i] <= 'z') || (us[i] >= 'A' && us[i] <= 'A') || us[i] >= 128)) {
      if (isspace(us[i]))
        spaces++;
      else
        badchars++;
    }
  }
  if (n == spaces)
    return 1.0;
  return (float)badchars / (float)(n - spaces);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: Hello, world!

assistant: ```c
int main(void) {
  puts("Hello, world!");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: Hello, world!

assistant: ```c
int main(void) {
  puts("Hello, world!");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: Hello, world!

assistant: ```c
int main(void) {
  puts("Hello, world!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: Hello, world!

assistant: ```c
int main(void) {
  puts("Hello, world!");
  return 0;
}
```