user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dij>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x3c(%rbp)
  jmp    L47
L101:
  mov    -0x3c(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x3c(%rbp)
L47:
  mov    -0x3c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jle    L101
  movl   $0x2,-0x38(%rbp)
  jmp    L29
L96:
  movl   $0x3e7,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  jmp    L48
L42:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x40(%rbp)
  jle    L115
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L115
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x40(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x34(%rbp)
L115:
  addl   $0x1,-0x3c(%rbp)
L48:
  mov    -0x3c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jle    L42
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x38(%rbp)
  movl   $0x1,-0x3c(%rbp)
  jmp    L108
L51:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L16
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L16
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x58(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L16:
  addl   $0x1,-0x3c(%rbp)
L108:
  mov    -0x3c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jle    L51
L29:
  mov    -0x38(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jle    L96
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void dij(int scr, int cost[][10], int *dist, int n) {
  int visited[10], min, i, count, u;
  for (i = 1; i <= n; i++)
    visited[i] = 0, dist[i] = cost[scr][i];
  count = 2;
  while (count <= n) {
    min = 999;
    for (i = 1; i <= n; i++)
      if (dist[i] < min && !visited[i])
        min = dist[i], u = i;
    visited[u] = 1;
    count++;
    for (i = 1; i <= n; i++)
      if ((dist[u] + cost[u][i] < dist[i]) && !visited[i])
        dist[i] = dist[u] + cost[u][i];
  }
}
```