ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D20(%rip),%rsi
  lea    D38(%rip),%rdi
  push   %r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x198,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%rbx
  lea    0xa8(%rsp),%rbp
  call   <fopen@plt>
  movq   $0x0,0x8(%rsp)
  mov    %rax,%r12
  lea    0x40(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,%r15
  lea    0x20(%rsp),%rax
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L49:
  lea    -0x18(%rbp),%r14
  nopl   0x0(%rax)
L6:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x4,%r14
  call   <fscanf@plt>
  cmp    %rbp,%r14
  jne    L6
  movdqu -0x14(%r14),%xmm1
  mov    0x18(%rsp),%rdi
  add    $0x4,%r15
  lea    0x18(%r14),%rbp
  mov    $0x5,%esi
  movaps %xmm1,0x20(%rsp)
  mov    -0x4(%r14),%eax
  mov    %eax,0x30(%rsp)
  call   <heikin@plt>
  addq   $0x6,0x8(%rsp)
  mov    0x8(%rsp),%rax
  movss  %xmm0,-0x4(%r15)
  cmp    $0x3c,%rax
  jne    L49
  mov    0x10(%rsp),%rdi
  lea    0x60(%rsp),%r14
  mov    $0xa,%edx
  xor    %r13d,%r13d
  mov    %r14,%rsi
  lea    D41(%rip),%rbp
  call   <jyuni@plt>
  nopl   0x0(%rax)
L31:
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx,%r15,4),%esi
  mov    %rbp,%rdi
  add    $0x1,%r15
  call   <printf@plt>
  cmp    $0x6,%r15
  jne    L0
  mov    0x10(%rsp),%rax
  lea    D27(%rip),%rdi
  add    $0x18,%rbx
  cvttss2si (%rax,%r13,4),%esi
  call   <printf@plt>
  mov    (%r14,%r13,4),%esi
  mov    %rbp,%rdi
  add    $0x1,%r13
  call   <printf@plt>
  cmp    $0xa,%r13
  jne    L31
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x198,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D38
datatype: string
name: read_data
arguments: data_tag: D26
datatype: string
name: read_data
arguments: data_tag: D41
datatype: string
name: read_data
arguments: data_tag: D27
datatype: string

tool: D20: r

tool: D38: tensuu

tool: D26: %d

tool: D41: %3d

tool: D27: %5.1f

assistant: ```c
main() {
  int n = 10;
  int m = 6;
  int i, j, k, data[n][m];
  int T[5], B[n];
  float A[5];
  FILE *fp;
  fp = fopen("tensuu", "r");
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      fscanf(fp, "%d", &data[i][j]);
    }
    k = 0;
    for (j = 1; j < m; j++) {
      T[k] = data[i][j];
      k++;
    }
    A[i] = heikin(T, 5);
  }
  jyuni(A, B, n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      printf("%3d", data[i][j]);
    }
    printf("%5.1f", A[i]);
    printf("%3d", B[i]);
  }
  fclose(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,-0x20(%rbp)
  movabs $0x6161616161616161,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x6161,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rdx
  lea    -0x13(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rdx
  lea    -0x13(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L18
  mov    $0x1,%eax
  jmp    L20
L18:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string
name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D20
type: string

tool: D1: string

tool: D14: 	strcpy

tool: D20: 	passed.


assistant: ```c
int test_strcpy(void) {
  const char *str = "string";
  char buffer[11] = "aaaaaaaaaa";
  printf("\tstrcpy");
  strcpy(buffer, str);
  if (strcmp(buffer, str))
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_strcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6161616161616161,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x6161,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    0xd(%rsp),%rbx
  lea    D20(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L29
L28:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L28
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D20
type_infered: string
name: unpack_data
arguments: data_tag: D13
type_infered: string

tool: D10: 	strcpy

tool: D20: string

tool: D13: 	passed.


assistant: ```c
int test_strcpy(void) {
  const char *str = "string";
  char buffer[11] = "aaaaaaaaaa";
  printf("\tstrcpy");
  strcpy(buffer, str);
  if (strcmp(buffer, str))
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_strcpy>:
  endbr64
  push   %r12
  lea    D4(%rip),%rdi
  lea    D23(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6161616161616161,%rax
  lea    0xd(%rsp),%rbp
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x6161,%eax
  mov    %ax,0x15(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L8
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string

tool: D4: 	strcpy

tool: D23: string

tool: D16: 	passed.


assistant: ```c
int test_strcpy(void) {
  const char *str = "string";
  char buffer[11] = "aaaaaaaaaa";
  printf("\tstrcpy");
  strcpy(buffer, str);
  if (strcmp(buffer, str))
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_strcpy>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  lea    D22(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6161616161616161,%rax
  lea    0xd(%rsp),%rbp
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x6161,%eax
  mov    %ax,0x15(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L1
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D22
datatype: string
name: parse_data
arguments: label: D26
datatype: string

tool: D24: 	strcpy

tool: D22: string

tool: D26: 	passed.


assistant: ```c
int test_strcpy(void) {
  const char *str = "string";
  char buffer[11] = "aaaaaaaaaa";
  printf("\tstrcpy");
  strcpy(buffer, str);
  if (strcmp(buffer, str))
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sendDNSquery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x24(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    $0x4,%r9d
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x200,%edx
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L3
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: ERROR writing to socket


assistant: ```c
void sendDNSquery(int *socksd, char *buffer, struct sockaddr_in serveradd) {
  int n;
  n = sendto(*socksd, buffer, (size_t)512, 0, (struct sockaddr *)&serveradd, sizeof serveradd);
  if (n < 0)
    error("ERROR writing to socket\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sendDNSquery>:
  endbr64
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  mov    $0x4,%r9d
  lea    0xc(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x200,%edx
  mov    (%rdi),%edi
  call   <sendto@plt>
  test   %eax,%eax
  js     L16
L14:
  add    $0x18,%rsp
  ret
L16:
  lea    D0(%rip),%rdi
  call   <error@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: ERROR writing to socket


assistant: ```c
void sendDNSquery(int *socksd, char *buffer, struct sockaddr_in serveradd) {
  int n;
  n = sendto(*socksd, buffer, (size_t)512, 0, (struct sockaddr *)&serveradd, sizeof serveradd);
  if (n < 0)
    error("ERROR writing to socket\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendDNSquery>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%edi
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %edx,0xc(%rsp)
  lea    0xc(%rsp),%r8
  mov    $0x200,%edx
  call   <sendto@plt>
  test   %eax,%eax
  js     L4
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L4:
  lea    D8(%rip),%rdi
  call   <error@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: ERROR writing to socket


assistant: ```c
void sendDNSquery(int *socksd, char *buffer, struct sockaddr_in serveradd) {
  int n;
  n = sendto(*socksd, buffer, (size_t)512, 0, (struct sockaddr *)&serveradd, sizeof serveradd);
  if (n < 0)
    error("ERROR writing to socket\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<sendDNSquery>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%edi
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %edx,0xc(%rsp)
  lea    0xc(%rsp),%r8
  mov    $0x200,%edx
  call   <sendto@plt>
  test   %eax,%eax
  js     L2
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L2:
  lea    D9(%rip),%rdi
  call   <error@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: ERROR writing to socket


assistant: ```c
void sendDNSquery(int *socksd, char *buffer, struct sockaddr_in serveradd) {
  int n;
  n = sendto(*socksd, buffer, (size_t)512, 0, (struct sockaddr *)&serveradd, sizeof serveradd);
  if (n < 0)
    error("ERROR writing to socket\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1000,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x8000,-0xc(%rbp)
  jmp    L6
L19:
  shll   -0x10(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L20
  orl    $0x1,-0x10(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L13
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  or     %eax,-0x14(%rbp)
L13:
  sarl   -0xc(%rbp)
L6:
  cmpl   $0x0,-0xc(%rbp)
  jg     L19
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: Q=%d, R=%d


assistant: ```c
int main(void) {
  int n = 4096;
  int d = 10;
  int q = 0;
  int r = 0;
  int i = 32768;
  while (0 < i) {
    r <<= 1;
    if (n & i) {
      r |= 1;
    }
    if (d <= r) {
      r -= d;
      q |= i;
    }
    i >>= 1;
  }
  printf("Q=%d, R=%d\n", q, r);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8000,%eax
  mov    $0x10,%ecx
  mov    $0x0,%edx
  mov    $0x0,%edi
L0:
  sar    %eax
  sub    $0x1,%ecx
  je     L4
  add    %edx,%edx
  mov    %edx,%esi
  or     $0x1,%esi
  test   $0x10,%ah
  cmovne %esi,%edx
  cmp    $0x9,%edx
  jle    L0
  sub    $0xa,%edx
  or     %eax,%edi
  jmp    L0
L4:
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: Q=%d, R=%d


assistant: ```c
int main(void) {
  int n = 4096;
  int d = 10;
  int q = 0;
  int r = 0;
  int i = 32768;
  while (0 < i) {
    r <<= 1;
    if (n & i) {
      r |= 1;
    }
    if (d <= r) {
      r -= d;
      q |= i;
    }
    i >>= 1;
  }
  printf("Q=%d, R=%d\n", q, r);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%ecx
  mov    $0x8000,%eax
  xor    %edx,%edx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L12:
  sar    %eax
  sub    $0x1,%ecx
  je     L0
L3:
  add    %edx,%edx
  mov    %edx,%esi
  or     $0x1,%esi
  test   $0x10,%ah
  cmovne %esi,%edx
  cmp    $0x9,%edx
  jle    L12
  or     %eax,%r8d
  sub    $0xa,%edx
  sar    %eax
  sub    $0x1,%ecx
  jne    L3
L0:
  mov    %r8d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: Q=%d, R=%d


assistant: ```c
int main(void) {
  int n = 4096;
  int d = 10;
  int q = 0;
  int r = 0;
  int i = 32768;
  while (0 < i) {
    r <<= 1;
    if (n & i) {
      r |= 1;
    }
    if (d <= r) {
      r -= d;
      q |= i;
    }
    i >>= 1;
  }
  printf("Q=%d, R=%d\n", q, r);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  mov    $0x199,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: Q=%d, R=%d


assistant: ```c
int main(void) {
  int n = 4096;
  int d = 10;
  int q = 0;
  int r = 0;
  int i = 32768;
  while (0 < i) {
    r <<= 1;
    if (n & i) {
      r |= 1;
    }
    if (d <= r) {
      r -= d;
      q |= i;
    }
    i >>= 1;
  }
  printf("Q=%d, R=%d\n", q, r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<data_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L20
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L20:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L24
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double data_max(int n, double *x) {
  double m = x[0];
  int i;
  for (i = 1; i < n; i++)
    if (m < x[i])
      m = x[i];
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<data_max>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jle    L7
  lea    0x8(%rsi),%rax
  lea    -0x2(%rdi),%edx
  lea    0x10(%rsi,%rdx,8),%rdx
L10:
  movsd  (%rax),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L10
L7:
  ret
```

assistant: ```c
double data_max(int n, double *x) {
  double m = x[0];
  int i;
  for (i = 1; i < n; i++)
    if (m < x[i])
      m = x[i];
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<data_max>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jle    L12
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax)
L1:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L1
L12:
  ret
```

assistant: ```c
double data_max(int n, double *x) {
  double m = x[0];
  int i;
  for (i = 1; i < n; i++)
    if (m < x[i])
      m = x[i];
  return m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<data_max>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jle    L7
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax)
L4:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L4
L7:
  ret
```

assistant: ```c
double data_max(int n, double *x) {
  double m = x[0];
  int i;
  for (i = 1; i < n; i++)
    if (m < x[i])
      m = x[i];
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prince_enc_dec_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    $0xc97c50dd,%edi
  call   <UINT64_C@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L28
  mov    -0x20(%rbp),%eax
  jmp    L58
L28:
  mov    $0x0,%eax
L58:
  xor    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <prince_k0_to_k0_prime@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L51
  mov    -0x18(%rbp),%eax
  jmp    L22
L51:
  mov    -0x28(%rbp),%eax
L22:
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L5
  mov    -0x28(%rbp),%eax
  jmp    L57
L5:
  mov    -0x18(%rbp),%eax
L57:
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <prince_core@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t prince_enc_dec_uint64(const uint64_t input, const uint64_t enc_k0, const uint64_t enc_k1, int decrypt) {
  const uint64_t prince_alpha = UINT64_C(0xc0ac29b7c97c50dd);
  const uint64_t k1 = enc_k1 ^ (decrypt ? prince_alpha : 0);
  const uint64_t enc_k0_prime = prince_k0_to_k0_prime(enc_k0);
  const uint64_t k0 = decrypt ? enc_k0_prime : enc_k0;
  const uint64_t k0_prime = decrypt ? enc_k0 : enc_k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  const uint64_t core_input = input ^ k0;
  const uint64_t core_output = prince_core(core_input, k1);
  const uint64_t output = core_output ^ k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prince_enc_dec_uint64>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    $0xc97c50dd,%edi
  call   <UINT64_C@plt>
  test   %r13d,%r13d
  je     L11
  xor    %eax,%ebp
  mov    %ebx,%edi
  call   <prince_k0_to_k0_prime@plt>
  mov    %eax,%edi
L5:
  xor    %r12d,%edi
  mov    %ebp,%esi
  call   <prince_core@plt>
  xor    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %ebx,%edi
  call   <prince_k0_to_k0_prime@plt>
  mov    %ebx,%edi
  mov    %eax,%ebx
  jmp    L5
```

assistant: ```c
uint64_t prince_enc_dec_uint64(const uint64_t input, const uint64_t enc_k0, const uint64_t enc_k1, int decrypt) {
  const uint64_t prince_alpha = UINT64_C(0xc0ac29b7c97c50dd);
  const uint64_t k1 = enc_k1 ^ (decrypt ? prince_alpha : 0);
  const uint64_t enc_k0_prime = prince_k0_to_k0_prime(enc_k0);
  const uint64_t k0 = decrypt ? enc_k0_prime : enc_k0;
  const uint64_t k0_prime = decrypt ? enc_k0 : enc_k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  const uint64_t core_input = input ^ k0;
  const uint64_t core_output = prince_core(core_input, k1);
  const uint64_t output = core_output ^ k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  return output;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<prince_enc_dec_uint64>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0xc97c50dd,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  call   <UINT64_C@plt>
  test   %ebx,%ebx
  je     L5
  mov    %ebp,%edi
  xor    %eax,%r12d
  mov    %ebp,%ebx
  call   <prince_k0_to_k0_prime@plt>
  mov    %eax,%edi
L1:
  xor    %r13d,%edi
  mov    %r12d,%esi
  call   <prince_core@plt>
  add    $0x8,%rsp
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %ebp,%edi
  call   <prince_k0_to_k0_prime@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  jmp    L1
```

assistant: ```c
uint64_t prince_enc_dec_uint64(const uint64_t input, const uint64_t enc_k0, const uint64_t enc_k1, int decrypt) {
  const uint64_t prince_alpha = UINT64_C(0xc0ac29b7c97c50dd);
  const uint64_t k1 = enc_k1 ^ (decrypt ? prince_alpha : 0);
  const uint64_t enc_k0_prime = prince_k0_to_k0_prime(enc_k0);
  const uint64_t k0 = decrypt ? enc_k0_prime : enc_k0;
  const uint64_t k0_prime = decrypt ? enc_k0 : enc_k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  const uint64_t core_input = input ^ k0;
  const uint64_t core_output = prince_core(core_input, k1);
  const uint64_t output = core_output ^ k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  return output;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prince_enc_dec_uint64>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0xc97c50dd,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  call   <UINT64_C@plt>
  test   %ebx,%ebx
  je     L1
  mov    %ebp,%edi
  xor    %eax,%r12d
  mov    %ebp,%ebx
  call   <prince_k0_to_k0_prime@plt>
  mov    %eax,%edi
L5:
  xor    %r13d,%edi
  mov    %r12d,%esi
  call   <prince_core@plt>
  add    $0x8,%rsp
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  mov    %ebp,%edi
  call   <prince_k0_to_k0_prime@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  jmp    L5
```

assistant: ```c
uint64_t prince_enc_dec_uint64(const uint64_t input, const uint64_t enc_k0, const uint64_t enc_k1, int decrypt) {
  const uint64_t prince_alpha = UINT64_C(0xc0ac29b7c97c50dd);
  const uint64_t k1 = enc_k1 ^ (decrypt ? prince_alpha : 0);
  const uint64_t enc_k0_prime = prince_k0_to_k0_prime(enc_k0);
  const uint64_t k0 = decrypt ? enc_k0_prime : enc_k0;
  const uint64_t k0_prime = decrypt ? enc_k0 : enc_k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  const uint64_t core_input = input ^ k0;
  const uint64_t core_output = prince_core(core_input, k1);
  const uint64_t output = core_output ^ k0_prime;
  do {
  } while (0);
  do {
  } while (0);
  return output;
}
```