user: 下面的汇编指令对应的C源代码是什么:

```asm
<lcs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rax,0x20(%rsp)
  lea    0x1(%rax),%r12
  mov    $0x8,%esi
  mov    %r12,%rdi
  call   <calloc@plt>
  mov    %rax,%r14
  mov    %rax,0x30(%rsp)
  mov    $0x8,%esi
  mov    %r12,%rdi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %ebx,%eax
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  js     L80
  cltq
  add    %rbp,%rax
  mov    %r13d,%esi
  sub    $0x1,%esi
  mov    %esi,0xc(%rsp)
  mov    %r14,0x28(%rsp)
  mov    %rax,%r14
L37:
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  js     L16
  mov    0x8(%rsp),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  lea    (%rsi,%rax,1),%r13d
  and    $0x1,%r13d
  sub    %eax,%r13d
  movslq %r13d,%r13
  lea    0x1(%rsi),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x1,%ebp
  sub    %edx,%ebp
  movslq %ebp,%rbp
  movslq %edi,%rbx
L49:
  mov    0x30(%rsp,%rbp,8),%rdx
  lea    0x0(,%rbx,8),%rax
  mov    0x30(%rsp,%r13,8),%rcx
  lea    (%rcx,%rax,1),%r12
  mov    (%rdx,%rbx,8),%r8
  mov    0x8(%rcx,%rax,1),%rsi
  movzbl (%r15,%rbx,1),%ecx
  cmp    %cl,(%r14)
  sete   %dil
  movzbl %dil,%edi
  add    0x8(%rdx,%rax,1),%edi
  mov    %r8,%rdx
  call   <max3@plt>
  mov    %rax,(%r12)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L49
L16:
  sub    $0x1,%r14
  subl   $0x1,0x8(%rsp)
  jns    L37
  mov    0x28(%rsp),%r14
L80:
  mov    (%r14),%r12
  mov    0x20(%rsp),%r13
  test   %r13,%r13
  je     L93
  mov    $0x0,%ebx
  lea    D0(%rip),%rbp
L4:
  mov    (%r14,%rbx,8),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L4
L93:
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %r12,%r12
  je     L66
  mov    0x10(%rsp),%rcx
  mov    %r12,%rdx
  mov    $0x0,%eax
  jmp    L74
L98:
  add    $0x1,%rax
  cmp    %rdx,(%r14,%rax,8)
  je     L98
L108:
  movzbl -0x1(%r15,%rax,1),%esi
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  sub    $0x1,%rdx
  je     L94
L74:
  cmp    %rdx,(%r14,%rax,8)
  je     L98
  jmp    L108
L66:
  mov    %r12,%rax
  jmp    L82
L94:
  mov    %r12,%rax
L82:
  mov    0x10(%rsp),%rsi
  movb   $0x0,(%rsi,%rax,1)
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  mov    %r12,%rax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: %zd

assistant: ```c
size_t lcs(char *c, const char *a, const char *b) {
  size_t *m[2];
  size_t la = strlen(a);
  size_t lb = strlen(b);
  m[0] = calloc(lb + 1, sizeof(*m[0]));
  m[1] = calloc(lb + 1, sizeof(*m[1]));
  for (int yy = la - 1; yy >= 0; yy--) {
    for (int x = lb - 1; x >= 0; x--) {
      size_t y = yy % 2;
      size_t y1 = (yy + 1) % 2;
      m[y][x] = max3((a[yy] == b[x]) + m[y1][x + 1], m[y][x + 1], m[y1][x]);
    }
  }
  size_t ret = m[0][0];
  size_t v = ret;
  size_t i = 0;
  size_t j = 0;
  for (int d = 0; d < lb; d++) {
    printf("%zd", m[0][d]);
  }
  printf("\n");
  while (v > 0) {
    while (m[0][i] == v)
      i++;
    c[j++] = b[i - 1];
    v--;
  }
  c[j] = 0;
  free(m[0]);
  free(m[1]);
  return ret;
}
```