ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  movsd  D46(%rip),%xmm1
  mov    $0x64,%eax
  pxor   %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L15:
  addsd  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L15
  movsd  D45(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L13
  jne    L13
  lea    D3(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
L28:
  mov    %r12d,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L13:
  mov    $0x1,%esi
  lea    D47(%rip),%rdi
  mov    $0x2,%eax
  mov    $0x1,%r12d
  call   <printf@plt>
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: data_label: D46
type_guessed: f32[2]
name: disassemble_data
arguments: data_label: D45
type_guessed: f64
name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D47
type_guessed: string

tool: {"D46": [0.0,1.875]}

tool: D45: 100

tool: D3: successful

tool: D29: done with %d errors


tool: D47: update (implicit) a %f != %f (error %d)


assistant: ```c
int main() {
  int fail = 0;
  int error = 0;
  double a = 0;
  int ii = 0;
#pragma omp target map(tofrom : a)
  {
#pragma omp parallel for
    for (ii = 0; ii < 100; ++ii)
#pragma omp atomic
      a++;
  }
  double result = a;
  double expect = 100;
  if (result != expect) {
    printf("update (implicit) a %f != %f (error %d)\n", result, expect, ++error);
    fail = 1;
  }
  if (!fail)
    printf("successful\n");
  else
    fail = 0;
  printf("done with %d errors\n", error);
  return error;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L43
L32:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L24:
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L32
L6:
  cmpl   $0x0,-0x8(%rbp)
  jne    L57
  mov    $0x1,%eax
  jmp    L41
L57:
  mov    $0x0,%eax
L41:
  leave
  ret
```

assistant: ```c
int is_prime(int num) {
  int i = 2;
  int flag = 0;
  int m = sqrt(num);
  while (i <= m) {
    if (m % i == 0) {
      flag = 1;
      break;
    }
    i++;
  }
  if (flag == 0)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  sub    $0x8,%rsp
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L11
  mov    %eax,%esi
  test   $0x1,%al
  je     L10
  mov    $0x2,%ecx
L66:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L41
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L66
  mov    $0x1,%eax
  jmp    L63
L41:
  mov    $0x0,%eax
L63:
  xor    $0x1,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    $0x0,%eax
  jmp    L63
L10:
  mov    $0x1,%eax
  jmp    L63
```

assistant: ```c
int is_prime(int num) {
  int i = 2;
  int flag = 0;
  int m = sqrt(num);
  while (i <= m) {
    if (m % i == 0) {
      flag = 1;
      break;
    }
    i++;
  }
  if (flag == 0)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_prime>:
  endbr64
  sub    $0x8,%rsp
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L2
  mov    %eax,%esi
  test   $0x1,%al
  je     L36
  mov    $0x2,%ecx
  jmp    L57
  nop
L18:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L11
L57:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L18
L2:
  mov    $0x1,%edx
L11:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L36:
  xor    %edx,%edx
  jmp    L11
```

assistant: ```c
int is_prime(int num) {
  int i = 2;
  int flag = 0;
  int m = sqrt(num);
  while (i <= m) {
    if (m % i == 0) {
      flag = 1;
      break;
    }
    i++;
  }
  if (flag == 0)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_prime>:
  endbr64
  sub    $0x8,%rsp
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L12
  mov    %eax,%esi
  test   $0x1,%al
  je     L14
  mov    $0x2,%ecx
  jmp    L40
  nop
L19:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L1
L40:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L19
L12:
  mov    $0x1,%edx
L1:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L14:
  xor    %edx,%edx
  jmp    L1
```

assistant: ```c
int is_prime(int num) {
  int i = 2;
  int flag = 0;
  int m = sqrt(num);
  while (i <= m) {
    if (m % i == 0) {
      flag = 1;
      break;
    }
    i++;
  }
  if (flag == 0)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L37
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L4
L37:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L21
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int counter = 0;
  while (counter < strlen(haystack)) {
    if (needle == haystack[counter]) {
      return (haystack + counter);
    }
    counter++;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L28:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L25
  lea    0x0(%rbp,%rbx,1),%rax
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  jne    L28
  jmp    L5
L25:
  mov    $0x0,%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int counter = 0;
  while (counter < strlen(haystack)) {
    if (needle == haystack[counter]) {
      return (haystack + counter);
    }
    counter++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L12:
  lea    0x0(%rbp,%rbx,1),%rax
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L26
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
  xor    %eax,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int counter = 0;
  while (counter < strlen(haystack)) {
    if (needle == haystack[counter]) {
      return (haystack + counter);
    }
    counter++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L29:
  lea    0x0(%rbp,%rbx,1),%rax
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L8
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L29
  xor    %eax,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int counter = 0;
  while (counter < strlen(haystack)) {
    if (needle == haystack[counter]) {
      return (haystack + counter);
    }
    counter++;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L4
L9:
  mov    $0x0,%eax
L4:
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L10:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *gets(char *s) {
  char *ret = fgets(s, INT_MAX, stdin);
  size_t len = ret ? strlen(s) : 0;
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gets>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L20
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L20
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L1
L20:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  movb   $0x0,(%rax)
  jmp    L20
```

assistant: ```c
char *gets(char *s) {
  char *ret = fgets(s, INT_MAX, stdin);
  size_t len = ret ? strlen(s) : 0;
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gets>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L17
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L0
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L0:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *gets(char *s) {
  char *ret = fgets(s, INT_MAX, stdin);
  size_t len = ret ? strlen(s) : 0;
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gets>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L12
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L21
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L21:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *gets(char *s) {
  char *ret = fgets(s, INT_MAX, stdin);
  size_t len = ret ? strlen(s) : 0;
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_HT_GetKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1b20f,-0xc(%rbp)
  jmp    L7
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xa,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x6,%eax
  xor    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0xb,%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xf,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int _HT_GetKey(const char *key) {
  const char *current = key;
  unsigned int hash = 111119;
  while (*current) {
    hash += (unsigned char)*current;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    current++;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_HT_GetKey>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    $0x1b20f,%edx
L7:
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0xa,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L0:
  lea    (%rdx,%rdx,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
L5:
  mov    $0x1b20f,%edx
  jmp    L0
```

assistant: ```c
unsigned int _HT_GetKey(const char *key) {
  const char *current = key;
  unsigned int hash = 111119;
  while (*current) {
    hash += (unsigned char)*current;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    current++;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_HT_GetKey>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  mov    $0x1b20f,%edx
L18:
  add    %edx,%eax
  add    $0x1,%rdi
  mov    %eax,%edx
  shl    $0xa,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
  lea    (%rdx,%rdx,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nopl   (%rax)
L11:
  mov    $0xa1c6c36f,%eax
  ret
```

assistant: ```c
unsigned int _HT_GetKey(const char *key) {
  const char *current = key;
  unsigned int hash = 111119;
  while (*current) {
    hash += (unsigned char)*current;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    current++;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<_HT_GetKey>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  mov    $0x1b20f,%edx
L6:
  add    %edx,%eax
  add    $0x1,%rdi
  mov    %eax,%edx
  shl    $0xa,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
  lea    (%rdx,%rdx,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nopl   (%rax)
L9:
  mov    $0xa1c6c36f,%eax
  ret
```

assistant: ```c
unsigned int _HT_GetKey(const char *key) {
  const char *current = key;
  unsigned int hash = 111119;
  while (*current) {
    hash += (unsigned char)*current;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    current++;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L56
L49:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L57
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
L57:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L0
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    $0x2,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,%rdx
  movzwl -0x12(%rbp),%eax
  mov    %ax,(%rdx)
  jmp    L27
L0:
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x14(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    $0x2,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,%rdx
  movzwl -0x14(%rbp),%eax
  mov    %ax,(%rdx)
L27:
  addl   $0x2,-0x10(%rbp)
L56:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L49
  mov    -0xc(%rbp),%eax
  lea    -0x2bbfcfe6(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] == local1) {
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 733990886UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%esi
  test   %esi,%esi
  je     L11
  mov    $0x0,%eax
  lea    0x4(%rsp),%rdi
L14:
  mov    0x4(%rsp),%ecx
  cmp    %eax,%ecx
  ja     L0
  add    %ecx,%ecx
  mov    %eax,%r8d
  mov    %ecx,0x4(%rsp,%r8,4)
  cmp    %eax,%ecx
  jne    L0
  mov    %eax,%ecx
  lea    (%rdi,%rcx,4),%rcx
  movzwl 0x2(%rcx),%r8d
  movzwl (%rcx),%r9d
  mov    %r9w,0x2(%rcx)
  mov    %r8w,(%rcx)
  jmp    L5
L0:
  mov    %eax,%ecx
  lea    (%rdi,%rcx,4),%rcx
  movzwl 0x2(%rcx),%r8d
  movzwl (%rcx),%r9d
  mov    %r9w,0x2(%rcx)
  mov    %r8w,(%rcx)
L5:
  add    $0x2,%eax
  cmp    %esi,%eax
  jb     L14
L11:
  mov    0x4(%rsp),%eax
  sub    $0x2bbfcfe6,%eax
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x18,%rsp
  ret
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] == local1) {
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 733990886UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%ecx
  sub    $0x99f4bb,%eax
  test   %ecx,%ecx
  je     L17
  xor    %edx,%edx
L14:
  cmp    %eax,%edx
  lea    (%rax,%rax,1),%edi
  cmovae %edi,%eax
  add    $0x2,%edx
  cmp    %ecx,%edx
  jb     L14
L17:
  sub    $0x2bbfcfe6,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] == local1) {
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 733990886UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  sub    $0x99f4bb,%eax
  test   %edx,%edx
  je     L48
  test   %eax,%eax
  jne    L54
  cmp    $0x2,%edx
  jbe    L48
  cmp    $0x4,%edx
  jbe    L48
L77:
  mov    $0x4,%ecx
L42:
  cmp    %eax,%ecx
  lea    (%rax,%rax,1),%edi
  cmovae %edi,%eax
  add    $0x2,%ecx
  cmp    %edx,%ecx
  jb     L42
L48:
  sub    $0x2bbfcfe6,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L54:
  cmp    $0x2,%edx
  jbe    L48
  lea    (%rax,%rax,1),%ecx
  cmp    $0x3,%eax
  cmovb  %ecx,%eax
  cmp    $0x4,%edx
  jbe    L48
  jmp    L77
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] == local1) {
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 733990886UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<id_wsuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: 64

assistant: ```c
char *id_wsuf() {
  return ("64");
  return ("");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<id_wsuf>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: 64

assistant: ```c
char *id_wsuf() {
  return ("64");
  return ("");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<id_wsuf>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: 64

assistant: ```c
char *id_wsuf() {
  return ("64");
  return ("");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<id_wsuf>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: 64

assistant: ```c
char *id_wsuf() {
  return ("64");
  return ("");
}
```