user: Translate the below assembly code into C programming language:

```asm
<knight_tour>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x48,%rsp
  mov    %edx,-0x50(%rbp)
  mov    %ecx,-0x54(%rbp)
  mov    %rsp,%rcx
  mov    %edi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %edi,%eax
  imul   %esi,%eax
  cltq
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L88
L81:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L81
L88:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L26
L34:
  lea    0x3(%rsp),%rax
  movslq %r12d,%rdi
  mov    %rax,%rcx
  shl    $0x3,%rdi
  and    $0xfffffffffffffffc,%rax
  shr    $0x2,%rcx
  mov    %rax,-0x60(%rbp)
  mov    %rcx,-0x68(%rbp)
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L8
  test   %r12d,%r12d
  jle    L39
  mov    %r12d,%eax
  movslq -0x4c(%rbp),%rbx
  mov    %r15,%r14
  lea    (%r15,%rax,8),%rax
  mov    %rax,-0x48(%rbp)
  lea    0x1(%rbx),%r13d
  movslq %r13d,%r13
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %r13,%rdi
  add    $0x8,%r14
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    $0x30,%esi
  mov    %rax,-0x8(%r14)
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%r14),%rax
  movb   $0x0,(%rax,%rbx,1)
  cmp    -0x48(%rbp),%r14
  jne    L57
L39:
  mov    -0x68(%rbp),%rax
  movslq -0x54(%rbp),%rdx
  xor    %r8d,%r8d
  mov    %r15,%rdi
  mov    -0x50(%rbp),%ecx
  mov    -0x60(%rbp),%rsi
  mov    %edx,0x4(,%rax,4)
  mov    (%r15,%rdx,8),%rdx
  mov    %ecx,0x0(,%rax,4)
  movslq %ecx,%rax
  mov    %r12d,%ecx
  movb   $0x4b,(%rdx,%rax,1)
  mov    -0x4c(%rbp),%edx
  xor    %eax,%eax
  call   <kt_solve@plt>
  test   %eax,%eax
  je     L27
  mov    -0x4c(%rbp),%edx
  mov    -0x60(%rbp),%rsi
  mov    %r12d,%ecx
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <print_solution@plt>
L9:
  test   %r12d,%r12d
  jle    L56
  mov    %r12d,%r12d
  mov    %r15,%rbx
  lea    (%r15,%r12,8),%r12
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%r12
  jne    L0
L56:
  mov    %r15,%rdi
  call   <free@plt>
L8:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  lea    -0x28(%rbp),%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L27:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L9
  xchg   %ax,%ax
L26:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L34
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: The knight tour is not possible.


assistant: ```c
int knight_tour(int x, int y, int start_x, int start_y) {
  int i = 0;
  int sol[y * x][2];
  char **map = malloc(sizeof(char *) * y);
  if (!map)
    return (1);
  while (i < y) {
    map[i] = malloc(sizeof(char) * (x + 1));
    memset(map[i], '0', x);
    map[i++][x] = '\0';
  }
  sol[0][0] = start_x, sol[0][1] = start_y;
  map[sol[0][1]][sol[0][0]] = 'K';
  if (kt_solve(map, sol, x, y, 0))
    print_solution(map, sol, x, y);
  else
    printf("%s\n", "The knight tour is not possible.\n");
  i = 0;
  while (i < y)
    free(map[i++]);
  free(map);
  return (1);
}
```