ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<execat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L8
L49:
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
L8:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L16
  movzbl (%rax),%edx
  cmp    $0x3a,%dl
  jne    L49
L16:
  cmp    %rbx,-0x10(%rbp)
  je     L63
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movb   $0x2f,(%rdx)
  jmp    L63
L77:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
L63:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L77
  movb   $0x0,(%rbx)
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L23
  add    $0x1,%rax
  jmp    L79
L23:
  mov    $0x0,%eax
L79:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = '\0';
  return (*s1 ? ++s1 : 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<execat>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L51
  cmp    $0x3a,%cl
  je     L51
  mov    %rdx,%rax
L76:
  add    $0x1,%rdi
  mov    %rax,%r8
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L47
  cmp    $0x3a,%cl
  jne    L76
L47:
  cmp    %rax,%rdx
  je     L28
  lea    0x2(%r8),%rdx
  movb   $0x2f,(%rax)
L51:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L72
L7:
  add    $0x1,%rsi
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L7
L72:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  cmpb   $0x0,(%rdi)
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
L28:
  mov    %rax,%rdx
  jmp    L51
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = '\0';
  return (*s1 ? ++s1 : 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<execat>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x3a,%al
  je     L55
  test   %al,%al
  je     L55
  mov    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rcx,%r8
  add    $0x1,%rdi
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L63
  cmp    $0x3a,%al
  jne    L4
L63:
  cmp    %rcx,%rdx
  je     L55
  movb   $0x2f,(%rcx)
  movzbl (%rsi),%eax
  lea    0x2(%r8),%rdx
  test   %al,%al
  je     L22
  nopl   0x0(%rax)
L36:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rsi
L55:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L36
L22:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  xor    %edx,%edx
  cmpb   $0x0,(%rdi)
  cmove  %rdx,%rax
  ret
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = '\0';
  return (*s1 ? ++s1 : 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<execat>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x3a,%al
  je     L43
  test   %al,%al
  je     L43
  mov    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rcx,%r8
  add    $0x1,%rdi
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L68
  cmp    $0x3a,%al
  jne    L4
L68:
  cmp    %rcx,%rdx
  je     L43
  movb   $0x2f,(%rcx)
  movzbl (%rsi),%eax
  lea    0x2(%r8),%rdx
  test   %al,%al
  je     L24
  nopl   0x0(%rax)
L52:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rsi
L43:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L52
L24:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  xor    %edx,%edx
  cmpb   $0x0,(%rdi)
  cmove  %rdx,%rax
  ret
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = '\0';
  return (*s1 ? ++s1 : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<eat_token2_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  jmp    L16
L12:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L12
L19:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *eat_token2_end(char *p, char *pend, char delim) {
  for (; (p < pend) && (*p != (delim)) && (*p != '\n') && (*p != '\r'); p++)
    ;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<eat_token2_end>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jae    L29
L12:
  movzbl (%rax),%ecx
  cmp    $0xa,%cl
  setne  %r8b
  cmp    %dl,%cl
  setne  %dil
  test   %dil,%r8b
  je     L32
  cmp    $0xd,%cl
  je     L1
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L12
  mov    %rsi,%rax
L32:
  ret
L29:
  ret
L1:
  ret
```

assistant: ```c
char *eat_token2_end(char *p, char *pend, char delim) {
  for (; (p < pend) && (*p != (delim)) && (*p != '\n') && (*p != '\r'); p++)
    ;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eat_token2_end>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L35
  jmp    L22
  xchg   %ax,%ax
L24:
  cmp    $0xd,%cl
  je     L20
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L20
L35:
  movzbl (%rax),%ecx
  cmp    $0xa,%cl
  setne  %r8b
  cmp    %dl,%cl
  setne  %dil
  test   %dil,%r8b
  jne    L24
L20:
  ret
L22:
  ret
```

assistant: ```c
char *eat_token2_end(char *p, char *pend, char delim) {
  for (; (p < pend) && (*p != (delim)) && (*p != '\n') && (*p != '\r'); p++)
    ;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eat_token2_end>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L40
  jmp    L37
  xchg   %ax,%ax
L41:
  cmp    $0xd,%cl
  je     L16
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L16
L40:
  movzbl (%rax),%ecx
  cmp    $0xa,%cl
  setne  %r8b
  cmp    %dl,%cl
  setne  %dil
  test   %dil,%r8b
  jne    L41
L16:
  ret
L37:
  ret
```

assistant: ```c
char *eat_token2_end(char *p, char *pend, char delim) {
  for (; (p < pend) && (*p != (delim)) && (*p != '\n') && (*p != '\r'); p++)
    ;
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L5:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  jne    L4
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x3,%eax
  jne    L4
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L4:
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L5
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D10
type: string

tool: D3: %d%d

tool: D10: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, a, b, sum = 0;
  scanf("%d%d", &a, &b);
  for (i = a; i <= b; i++) {
    if (i % 3 == 1 && i % 5 == 3)
      sum += i;
  }
  printf("%d", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  cmp    %esi,%edx
  jg     L25
  add    $0x1,%esi
  mov    $0x0,%edi
  jmp    L22
L28:
  add    $0x1,%edx
  cmp    %esi,%edx
  je     L34
L22:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  jne    L28
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rdx,1),%eax
  cmp    $0x3,%ecx
  cmove  %eax,%edi
  jmp    L28
L25:
  mov    $0x0,%edi
L34:
  mov    %edi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D5
datatype: string

tool: D3: %d%d

tool: D5: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, a, b, sum = 0;
  scanf("%d%d", &a, &b);
  for (i = a; i <= b; i++) {
    if (i % 3 == 1 && i % 5 == 3)
      sum += i;
  }
  printf("%d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%r8d
  cmp    %r8d,%edx
  jg     L42
  add    $0x1,%r8d
  xor    %r9d,%r9d
L43:
  movslq %edx,%rcx
  mov    %edx,%esi
  imul   $0x55555556,%rcx,%rax
  sar    $0x1f,%esi
  shr    $0x20,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,2),%edi
  mov    %edx,%eax
  sub    %edi,%eax
  cmp    $0x1,%eax
  jne    L24
  imul   $0x66666667,%rcx,%rcx
  sar    $0x21,%rcx
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%r9,%rdx,1),%eax
  cmp    $0x3,%ecx
  cmove  %eax,%r9d
L24:
  add    $0x1,%edx
  cmp    %edx,%r8d
  jne    L43
L19:
  mov    %r9d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L42:
  xor    %r9d,%r9d
  jmp    L19
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D19: %d%d

tool: D6: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, a, b, sum = 0;
  scanf("%d%d", &a, &b);
  for (i = a; i <= b; i++) {
    if (i % 3 == 1 && i % 5 == 3)
      sum += i;
  }
  printf("%d", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ic_stmt_assign_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L1
L26:
  cmpl   $0x0,-0xc(%rbp)
  je     L21
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L21:
  mov    $0x1,%eax
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: ic_stmt_assign_destroy: assign was null

assistant: ```c
unsigned int ic_stmt_assign_destroy(struct ic_stmt_assign *assign, unsigned int free_assign) {
  if (!assign) {
    puts("ic_stmt_assign_destroy: assign was null");
    return 0;
  }
  if (free_assign) {
    free(assign);
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ic_stmt_assign_destroy>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L34
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L36
L26:
  add    $0x8,%rsp
  ret
L34:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L26
L36:
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L26
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: ic_stmt_assign_destroy: assign was null

assistant: ```c
unsigned int ic_stmt_assign_destroy(struct ic_stmt_assign *assign, unsigned int free_assign) {
  if (!assign) {
    puts("ic_stmt_assign_destroy: assign was null");
    return 0;
  }
  if (free_assign) {
    free(assign);
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ic_stmt_assign_destroy>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L0
  mov    $0x1,%r12d
  test   %esi,%esi
  jne    L19
L1:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  call   <free@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  lea    D2(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: ic_stmt_assign_destroy: assign was null

assistant: ```c
unsigned int ic_stmt_assign_destroy(struct ic_stmt_assign *assign, unsigned int free_assign) {
  if (!assign) {
    puts("ic_stmt_assign_destroy: assign was null");
    return 0;
  }
  if (free_assign) {
    free(assign);
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ic_stmt_assign_destroy>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L28
  mov    $0x1,%r12d
  test   %esi,%esi
  jne    L12
L10:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  call   <free@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D9(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: ic_stmt_assign_destroy: assign was null

assistant: ```c
unsigned int ic_stmt_assign_destroy(struct ic_stmt_assign *assign, unsigned int free_assign) {
  if (!assign) {
    puts("ic_stmt_assign_destroy: assign was null");
    return 0;
  }
  if (free_assign) {
    free(assign);
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<babel_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %edx,-0x68(%rbp)
  mov    %rcx,-0x78(%rbp)
  mov    %r8d,-0x7c(%rbp)
  mov    %r9,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x5c(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x68(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x7c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x18,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x88(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    0x10(%rbp),%eax
  mov    %eax,-0x50(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  movl   $0x2,-0x4c(%rbp)
L28:
  lea    -0x50(%rbp),%rcx
  mov    -0x64(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sendmsg@plt>
  mov    %eax,-0x58(%rbp)
  cmpl   $0x0,-0x58(%rbp)
  jns    L15
  mov    D59(%rip),%rax
  mov    (%rax),%rdx
  mov    D27(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L73
  addl   $0x1,-0x5c(%rbp)
  cmpl   $0x63,-0x5c(%rbp)
  jg     L15
  jmp    L28
L73:
  mov    D59(%rip),%rax
  mov    (%rax),%rdx
  mov    D29(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L15
  mov    -0x64(%rbp),%eax
  mov    $0x5,%edx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <wait_for_fd@plt>
  mov    %eax,-0x54(%rbp)
  cmpl   $0x0,-0x54(%rbp)
  jle    L21
  addl   $0x1,-0x5c(%rbp)
  cmpl   $0x63,-0x5c(%rbp)
  jg     L21
  jmp    L28
L21:
  mov    D29(%rip),%rax
  mov    (%rax),%rdx
  mov    D59(%rip),%rax
  mov    %rdx,(%rax)
L15:
  mov    -0x58(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int babel_send(int s, const void *buf1, int buflen1, const void *buf2, int buflen2, const struct sockaddr *sin, int slen) {
  struct iovec iovec[2];
  struct msghdr msg;
  int rc, count = 0;
  iovec[0].iov_base = (void *)buf1;
  iovec[0].iov_len = buflen1;
  iovec[1].iov_base = (void *)buf2;
  iovec[1].iov_len = buflen2;
  memset(&msg, 0, sizeof(msg));
  msg.msg_name = (struct sockaddr *)sin;
  msg.msg_namelen = slen;
  msg.msg_iov = iovec;
  msg.msg_iovlen = 2;
again:
  rc = sendmsg(s, &msg, 0);
  if (rc < 0) {
    if (errno == EINTR) {
      count++;
      if (count < 100)
        goto again;
    } else if (errno == EAGAIN) {
      int rc2;
      rc2 = wait_for_fd(1, s, 5);
      if (rc2 > 0) {
        count++;
        if (count < 100)
          goto again;
      }
      errno = EAGAIN;
    }
  }
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<babel_send>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%r12d
  mov    %r9,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x28(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %rcx,0x38(%rsp)
  mov    %r8d,0x30(%rsp)
  mov    %rsp,%rdi
  mov    $0x18,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbx,0x10(%rsp)
  mov    0x80(%rsp),%eax
  mov    %eax,(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x2,0x4(%rsp)
  mov    $0x1,%ebp
  mov    %rsp,%r13
  jmp    L54
L53:
  cmp    $0x63,%ebp
  jg     L1
L43:
  add    $0x1,%ebp
L54:
  mov    $0x0,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <sendmsg@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L1
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  mov    D27(%rip),%rdx
  cmp    (%rdx),%rax
  je     L53
  mov    D15(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L1
  mov    $0x5,%edx
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <wait_for_fd@plt>
  test   %eax,%eax
  jle    L71
  cmp    $0x63,%ebp
  jle    L43
L71:
  mov    D15(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    %rdx,(%rax)
L1:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    %ebx,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int babel_send(int s, const void *buf1, int buflen1, const void *buf2, int buflen2, const struct sockaddr *sin, int slen) {
  struct iovec iovec[2];
  struct msghdr msg;
  int rc, count = 0;
  iovec[0].iov_base = (void *)buf1;
  iovec[0].iov_len = buflen1;
  iovec[1].iov_base = (void *)buf2;
  iovec[1].iov_len = buflen2;
  memset(&msg, 0, sizeof(msg));
  msg.msg_name = (struct sockaddr *)sin;
  msg.msg_namelen = slen;
  msg.msg_iov = iovec;
  msg.msg_iovlen = 2;
again:
  rc = sendmsg(s, &msg, 0);
  if (rc < 0) {
    if (errno == EINTR) {
      count++;
      if (count < 100)
        goto again;
    } else if (errno == EAGAIN) {
      int rc2;
      rc2 = wait_for_fd(1, s, 5);
      if (rc2 > 0) {
        count++;
        if (count < 100)
          goto again;
      }
      errno = EAGAIN;
    }
  }
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<babel_send>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %rsi,0x28(%rsp)
  xor    %esi,%esi
  mov    %edx,0x20(%rsp)
  mov    %r14,%rdi
  mov    $0x18,%edx
  mov    %rcx,0x38(%rsp)
  mov    %r8d,0x30(%rsp)
  call   <memset@plt>
  mov    0x90(%rsp),%eax
  mov    %rbx,0x10(%rsp)
  mov    $0x1,%ebx
  movl   $0x2,0x4(%rsp)
  mov    %eax,(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L21
  nopl   (%rax)
L79:
  mov    D25(%rip),%r15
  cmp    (%r15),%rax
  jne    L0
  mov    $0x5,%edx
  mov    %r13d,%esi
  mov    $0x1,%edi
  call   <wait_for_fd@plt>
  test   %eax,%eax
  jle    L23
  cmp    $0x64,%ebx
  je     L23
L86:
  add    $0x1,%ebx
L21:
  xor    %edx,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <sendmsg@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L0
  mov    D7(%rip),%rbp
  mov    D0(%rip),%rdx
  mov    0x0(%rbp),%rax
  cmp    (%rdx),%rax
  jne    L79
  cmp    $0x64,%ebx
  jne    L86
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%r15),%rax
  mov    %rax,0x0(%rbp)
  jmp    L0
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int babel_send(int s, const void *buf1, int buflen1, const void *buf2, int buflen2, const struct sockaddr *sin, int slen) {
  struct iovec iovec[2];
  struct msghdr msg;
  int rc, count = 0;
  iovec[0].iov_base = (void *)buf1;
  iovec[0].iov_len = buflen1;
  iovec[1].iov_base = (void *)buf2;
  iovec[1].iov_len = buflen2;
  memset(&msg, 0, sizeof(msg));
  msg.msg_name = (struct sockaddr *)sin;
  msg.msg_namelen = slen;
  msg.msg_iov = iovec;
  msg.msg_iovlen = 2;
again:
  rc = sendmsg(s, &msg, 0);
  if (rc < 0) {
    if (errno == EINTR) {
      count++;
      if (count < 100)
        goto again;
    } else if (errno == EAGAIN) {
      int rc2;
      rc2 = wait_for_fd(1, s, 5);
      if (rc2 > 0) {
        count++;
        if (count < 100)
          goto again;
      }
      errno = EAGAIN;
    }
  }
  return rc;
}
```