ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x404(%rbp)
  jle    L23
  mov    $0x0,%edi
  call   <close@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x410(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  jmp    L23
L35:
  mov    -0x3f4(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L23:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jne    L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    close(0);
    open(argv[1], O_RDONLY);
  }
  char buf[1000];
  int len;
  while ((len = read(0, buf, 1000)))
    write(1, buf, len);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jg     L0
L28:
  mov    %rsp,%rbx
  jmp    L24
L0:
  mov    %rsi,%rbx
  mov    $0x0,%edi
  call   <close@plt>
  mov    0x8(%rbx),%rdi
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  jmp    L28
L40:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L24:
  mov    $0x3e8,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L40
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    close(0);
    open(argv[1], O_RDONLY);
  }
  char buf[1000];
  int len;
  while ((len = read(0, buf, 1000)))
    write(1, buf, len);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L22
  xor    %edi,%edi
  mov    %rsi,%rbx
  call   <close@plt>
  mov    D3(%rip),%rax
  mov    0x8(%rbx),%rdi
  mov    (%rax),%esi
  call   <open@plt>
L22:
  mov    %rsp,%rbx
  jmp    L28
  nopl   (%rax)
L9:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L28:
  mov    $0x3e8,%edx
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L9
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    close(0);
    open(argv[1], O_RDONLY);
  }
  char buf[1000];
  int len;
  while ((len = read(0, buf, 1000)))
    write(1, buf, len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L18
  xor    %edi,%edi
  mov    %rsi,%rbx
  call   <close@plt>
  mov    D9(%rip),%rax
  mov    0x8(%rbx),%rdi
  mov    (%rax),%esi
  call   <open@plt>
L18:
  mov    %rsp,%rbx
  jmp    L10
  nopl   (%rax)
L6:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L10:
  mov    $0x3e8,%edx
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L6
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    close(0);
    open(argv[1], O_RDONLY);
  }
  char buf[1000];
  int len;
  while ((len = read(0, buf, 1000)))
    write(1, buf, len);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lonlat_to_xyz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdi,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    -0x38(%rbp),%rdx
  add    $0x8,%rdx
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x38(%rbp),%rax
  lea    0x10(%rax),%rbx
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void lonlat_to_xyz(double lon, double lat, double *xyz) {
  double coslat = cos(lat);
  xyz[0] = coslat * cos(lon);
  xyz[1] = coslat * sin(lon);
  xyz[2] = sin(lat);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lonlat_to_xyz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm1,%r13
  mov    %rdi,%rbx
  lea    0x8(%rsp),%r14
  mov    %rsp,%r15
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <sincos@plt>
  mov    (%rsp),%r12
  mov    0x8(%rsp),%rbp
  mov    %r15,%rsi
  mov    %r14,%rdi
  movq   %r13,%xmm0
  call   <sincos@plt>
  movsd  (%rsp),%xmm0
  movq   %r12,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movq   %rbp,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rbx)
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void lonlat_to_xyz(double lon, double lat, double *xyz) {
  double coslat = cos(lat);
  xyz[0] = coslat * cos(lon);
  xyz[1] = coslat * sin(lon);
  xyz[2] = sin(lat);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lonlat_to_xyz>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movsd  %xmm1,0x18(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x20(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm3
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm2,(%rbx)
  movsd  %xmm0,0x8(%rbx)
  movsd  0x28(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lonlat_to_xyz(double lon, double lat, double *xyz) {
  double coslat = cos(lat);
  xyz[0] = coslat * cos(lon);
  xyz[1] = coslat * sin(lon);
  xyz[2] = sin(lat);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lonlat_to_xyz>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movsd  %xmm1,0x18(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x20(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm3
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm1
  movapd %xmm2,%xmm0
  unpcklpd %xmm3,%xmm0
  unpcklpd %xmm1,%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rbx)
  movsd  0x28(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lonlat_to_xyz(double lon, double lat, double *xyz) {
  double coslat = cos(lat);
  xyz[0] = coslat * cos(lon);
  xyz[1] = coslat * sin(lon);
  xyz[2] = sin(lat);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L51
  comiss %xmm0,%xmm1
  jbe    L82
  comiss 0xc(%rsp),%xmm0
  jae    L119
L82:
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  jbe    L87
  comiss 0x10(%rsp),%xmm0
  jae    L103
L87:
  movss  0x10(%rsp),%xmm1
  comiss %xmm0,%xmm1
  jbe    L3
  comiss 0x14(%rsp),%xmm0
  jae    L77
L3:
  lea    D23(%rip),%rdi
  call   <printf@plt>
L69:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L51:
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L119:
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L103:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L77:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D28
type_guessed: string
name: read_data
arguments: data_label: D53
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: string
name: read_data
arguments: data_label: D80
type_guessed: string
name: read_data
arguments: data_label: D75
type_guessed: string
name: read_data
arguments: data_label: D45
type_guessed: string
name: read_data
arguments: data_label: D48
type_guessed: string

tool: D3: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D28: %f%f%f%f

tool: D53: Thank you. Now enter student score (percent) >

tool: D22: %f

tool: D23: Student has an F grade


tool: D80: Student has an A grade


tool: D75: Student has an B grade


tool: D45: Student has and C grade


tool: D48: Student has an D grade


assistant: ```c
int main() {
  float score, A, B, C, D;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &A, &B, &C, &D);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &score);
  if (score >= A) {
    printf("Student has an A grade\n");
  } else if (score < A && score >= B) {
    printf("Student has an B grade\n");
  } else if (score < B && score >= C) {
    printf("Student has and C grade\n");
  } else if (score < C && score >= D) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D84(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L29
  comiss %xmm0,%xmm1
  movss  0xc(%rsp),%xmm2
  jbe    L92
  comiss %xmm2,%xmm0
  jae    L7
L92:
  comiss %xmm0,%xmm2
  movss  0x10(%rsp),%xmm1
  ja     L43
L75:
  comiss %xmm0,%xmm1
  jbe    L26
  comiss 0x14(%rsp),%xmm0
  jae    L113
L26:
  lea    D59(%rip),%rdi
  call   <printf@plt>
L116:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L43:
  comiss %xmm1,%xmm0
  jb     L75
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L29:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L7:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L113:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D84
datatype: string
name: unpack_data
arguments: data_label: D18
datatype: string
name: unpack_data
arguments: data_label: D39
datatype: string
name: unpack_data
arguments: data_label: D50
datatype: string
name: unpack_data
arguments: data_label: D59
datatype: string
name: unpack_data
arguments: data_label: D34
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D64
datatype: string

tool: D84: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D18: %f%f%f%f

tool: D39: Thank you. Now enter student score (percent) >

tool: D50: %f

tool: D59: Student has an F grade


tool: D34: Student has and C grade


tool: D9: Student has an A grade


tool: D14: Student has an B grade


tool: D64: Student has an D grade


assistant: ```c
int main() {
  float score, A, B, C, D;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &A, &B, &C, &D);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &score);
  if (score >= A) {
    printf("Student has an A grade\n");
  } else if (score < A && score >= B) {
    printf("Student has an B grade\n");
  } else if (score < B && score >= C) {
    printf("Student has and C grade\n");
  } else if (score < C && score >= D) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L113
  comiss %xmm0,%xmm1
  movss  0xc(%rsp),%xmm2
  jbe    L95
  comiss %xmm2,%xmm0
  jae    L44
L95:
  comiss %xmm0,%xmm2
  movss  0x10(%rsp),%xmm1
  ja     L31
L15:
  comiss %xmm0,%xmm1
  jbe    L118
  comiss 0x14(%rsp),%xmm0
  jae    L39
L118:
  lea    D80(%rip),%rdi
  call   <printf@plt>
L98:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L31:
  comiss %xmm1,%xmm0
  jb     L15
  lea    D88(%rip),%rdi
  call   <printf@plt>
  jmp    L98
L113:
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L98
L44:
  lea    D70(%rip),%rdi
  call   <printf@plt>
  jmp    L98
L39:
  lea    D85(%rip),%rdi
  call   <printf@plt>
  jmp    L98
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string
name: read_data
arguments: data_label: D6
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D80
type_infered: string
name: read_data
arguments: data_label: D88
type_infered: string
name: read_data
arguments: data_label: D51
type_infered: string
name: read_data
arguments: data_label: D70
type_infered: string
name: read_data
arguments: data_label: D85
type_infered: string

tool: D7: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D20: %f%f%f%f

tool: D6: Thank you. Now enter student score (percent) >

tool: D37: %f

tool: D80: Student has an F grade


tool: D88: Student has and C grade


tool: D51: Student has an A grade


tool: D70: Student has an B grade


tool: D85: Student has an D grade


assistant: ```c
int main() {
  float score, A, B, C, D;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &A, &B, &C, &D);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &score);
  if (score >= A) {
    printf("Student has an A grade\n");
  } else if (score < A && score >= B) {
    printf("Student has an B grade\n");
  } else if (score < B && score >= C) {
    printf("Student has and C grade\n");
  } else if (score < C && score >= D) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <delta@plt>
  movsd  -0x28(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jb     L12
  mov    -0x18(%rbp),%eax
  jmp    L30
L12:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L42
L27:
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <delta@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  comisd -0x28(%rbp),%xmm2
  jbe    L31
  mov    -0x4(%rbp),%eax
  jmp    L30
L31:
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L27
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
unsigned int next_e(unsigned int i, double *points, unsigned int size, double e) {
  unsigned int k;
  if (delta(i, size - 1, points, size) <= e) {
    return size;
  }
  for (k = i + 1; k < size; k++) {
    if (delta(i, k, points, size) > e) {
      return k;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<next_e>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebp
  movsd  %xmm0,0x8(%rsp)
  lea    -0x1(%rdx),%esi
  mov    %edx,%ecx
  mov    %r13,%rdx
  call   <delta@plt>
  mov    %ebp,%ebx
  movsd  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm2
  jae    L2
  lea    0x1(%r12),%ebx
  cmp    %ebx,%ebp
  jbe    L20
L19:
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <delta@plt>
  comisd 0x8(%rsp),%xmm0
  ja     L2
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  ja     L19
  mov    $0x0,%ebx
L2:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    $0x0,%ebx
  jmp    L2
```

assistant: ```c
unsigned int next_e(unsigned int i, double *points, unsigned int size, double e) {
  unsigned int k;
  if (delta(i, size - 1, points, size) <= e) {
    return size;
  }
  for (k = i + 1; k < size; k++) {
    if (delta(i, k, points, size) > e) {
      return k;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<next_e>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%ecx
  lea    -0x1(%rdx),%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    %r13,%rdx
  mov    %ebx,%r12d
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <delta@plt>
  movsd  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm2
  jae    L36
  lea    0x1(%rbp),%r12d
  cmp    %r12d,%ebx
  ja     L21
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jbe    L33
L21:
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <delta@plt>
  comisd 0x8(%rsp),%xmm0
  jbe    L25
L36:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  add    $0x18,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int next_e(unsigned int i, double *points, unsigned int size, double e) {
  unsigned int k;
  if (delta(i, size - 1, points, size) <= e) {
    return size;
  }
  for (k = i + 1; k < size; k++) {
    if (delta(i, k, points, size) > e) {
      return k;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_e>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%ecx
  lea    -0x1(%rdx),%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    %r13,%rdx
  mov    %ebx,%r12d
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <delta@plt>
  movsd  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm2
  jae    L32
  lea    0x1(%rbp),%r12d
  cmp    %r12d,%ebx
  ja     L6
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jbe    L1
L6:
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <delta@plt>
  comisd 0x8(%rsp),%xmm0
  jbe    L39
L32:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x18,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int next_e(unsigned int i, double *points, unsigned int size, double e) {
  unsigned int k;
  if (delta(i, size - 1, points, size) <= e) {
    return size;
  }
  for (k = i + 1; k < size; k++) {
    if (delta(i, k, points, size) > e) {
      return k;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L7:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L32
  movl   $0x5b,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    $0x64,%eax
  jle    L19
  mov    -0x10(%rbp),%eax
  sub    $0xa,%eax
  mov    %eax,-0xc(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L32:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string

tool: D5: %d

tool: D10: f91(%d) = %d


assistant: ```c
int main(void) {
  int n, result;
  while (1) {
    scanf("%d", &n);
    if (n == 0)
      break;
    result = 91;
    if (n > 100)
      result = n - 10;
    printf("f91(%d) = %d\n", n, result);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    D19(%rip),%rbx
  mov    $0x5b,%r13d
  lea    D7(%rip),%r12
  jmp    L29
L17:
  lea    -0xa(%rsi),%edx
  cmp    $0x64,%esi
  cmovle %r13d,%edx
  mov    %r12,%rdi
  call   <printf@plt>
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jne    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D7
type: string

tool: D19: %d

tool: D7: f91(%d) = %d


assistant: ```c
int main(void) {
  int n, result;
  while (1) {
    scanf("%d", &n);
    if (n == 0)
      break;
    result = 91;
    if (n > 100)
      result = n - 10;
    printf("f91(%d) = %d\n", n, result);
  }
  return 0;
}
```