ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LCDRasterPaletteSet>:
  endbr64
  mov    %esi,%edi
  mov    %rdx,%r10
  mov    %rcx,%r11
  test   %esi,%esi
  js     L49
  test   %r9d,%r9d
  je     L25
  movslq %r8d,%r8
  lea    -0x1(%r9),%edx
  lea    0x1(%r8,%rdx,1),%rcx
  lea    0x0(,%r8,4),%rax
  shl    $0x2,%rcx
  nopl   (%rax)
L46:
  mov    (%r11,%rax,1),%edx
  mov    %edx,(%r10,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L46
L25:
  mov    (%r10),%eax
  and    $0x7fffffff,%edi
  and    $0x8f,%ah
  or     %eax,%edi
  mov    %edi,(%r10)
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  test   %r9d,%r9d
  je     L25
  movslq %r8d,%r8
  mov    %r9d,%r9d
  xor    %ecx,%ecx
  lea    (%rdx,%r8,4),%r8
  nopl   0x0(%rax)
L51:
  mov    (%r11,%rcx,4),%edx
  mov    %edx,%eax
  mov    %edx,%esi
  sar    $0xc,%edx
  sar    $0x4,%eax
  sar    $0x8,%esi
  and    $0xf00,%edx
  and    $0xf,%eax
  and    $0xf0,%esi
  or     %esi,%eax
  or     %edx,%eax
  mov    %eax,(%r8,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L51
  jmp    L25
```

assistant: ```c
void LCDRasterPaletteSet(uint32_t ui32Base, uint32_t ui32Type, uint32_t *pui32Addr, const uint32_t *pui32SrcColors, uint32_t ui32Start, uint32_t ui32Count) {
  uint16_t *pui16Pal;
  uint16_t *pui16Src;
  uint32_t ui32Loop;
  ;
  ;
  ;
  ;
  ;

  ;
  pui16Pal = (uint16_t *)pui32Addr;
  if (ui32Type & 0x80000000) {
    ui32Loop = 0;
    while (ui32Count) {
      pui16Pal[ui32Start + ui32Loop] = (((pui32SrcColors[ui32Loop] & 0xF0) >> 4) | ((pui32SrcColors[ui32Loop] & 0xF000) >> 8) | ((pui32SrcColors[ui32Loop] & 0xF00000) >> 12));
      ui32Loop++;
      ui32Count--;
    }
  } else {
    pui16Src = (uint16_t *)pui32SrcColors;
    while (ui32Count) {
      pui16Pal[ui32Start] = pui16Src[ui32Start];
      ui32Start++;
      ui32Count--;
    }
  }
  pui16Pal[0] &= ~(0x00003000 | 0x00004000);
  pui16Pal[0] |= (ui32Type & ~0x80000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scan_ip4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <scan_ulong@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L13
L26:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  add    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L60
  mov    $0x0,%eax
  jmp    L13
L60:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <scan_ulong@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L89
  mov    $0x0,%eax
  jmp    L13
L89:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  add    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L78
  mov    $0x0,%eax
  jmp    L13
L78:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <scan_ulong@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L13
L8:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  add    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L47
  mov    $0x0,%eax
  jmp    L13
L47:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <scan_ulong@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L110
  mov    $0x0,%eax
  jmp    L13
L110:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  add    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

assistant: ```c
unsigned scan_ip4(const char *s, char ip[4]) {
  unsigned i;
  unsigned len;
  unsigned long u;
  len = 0;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[0] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[1] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[2] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[3] = u;
  s += i;
  len += i;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scan_ip4>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scan_ulong@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L134
  mov    (%rsp),%rax
  mov    %al,(%r12)
  mov    %ebp,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  je     L82
  mov    $0x0,%ebp
L134:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L82:
  add    $0x1,%rbx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L136
  mov    (%rsp),%rax
  mov    %al,0x1(%r12)
  mov    %r13d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  je     L54
  mov    $0x0,%ebp
  jmp    L134
L54:
  add    $0x1,%rbx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L128
  mov    (%rsp),%rax
  mov    %al,0x2(%r12)
  mov    %r14d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  je     L102
  mov    $0x0,%ebp
  jmp    L134
L102:
  mov    %rsp,%rsi
  lea    0x1(%rbx),%rdi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L83
  mov    (%rsp),%rdx
  mov    %dl,0x3(%r12)
  lea    0x3(%r13,%rbp,1),%ebp
  add    %r14d,%ebp
  add    %eax,%ebp
  jmp    L134
L136:
  mov    %eax,%ebp
  jmp    L134
L128:
  mov    %eax,%ebp
  jmp    L134
L83:
  mov    %eax,%ebp
  jmp    L134
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned scan_ip4(const char *s, char ip[4]) {
  unsigned i;
  unsigned len;
  unsigned long u;
  len = 0;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[0] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[1] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[2] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[3] = u;
  s += i;
  len += i;
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scan_ip4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L11
  mov    %eax,%r12d
  mov    (%rsp),%rax
  mov    %al,0x0(%rbp)
  mov    %r12d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  je     L8
L11:
  xor    %eax,%eax
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  add    $0x1,%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L11
  mov    (%rsp),%rax
  mov    %al,0x1(%rbp)
  mov    %r14d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  jne    L11
  add    $0x1,%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  je     L11
  mov    (%rsp),%rax
  mov    %al,0x2(%rbp)
  mov    %r15d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  jne    L11
  lea    0x1(%rbx),%rdi
  mov    %r13,%rsi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L11
  mov    (%rsp),%rdx
  mov    %dl,0x3(%rbp)
  lea    0x3(%r12,%r14,1),%edx
  add    %r15d,%edx
  add    %edx,%eax
  jmp    L46
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned scan_ip4(const char *s, char ip[4]) {
  unsigned i;
  unsigned len;
  unsigned long u;
  len = 0;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[0] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[1] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[2] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[3] = u;
  s += i;
  len += i;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<scan_ip4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L65
  mov    %eax,%r12d
  mov    (%rsp),%rax
  mov    %al,0x0(%rbp)
  mov    %r12d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  je     L71
L65:
  xor    %eax,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L71:
  add    $0x1,%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L65
  mov    (%rsp),%rax
  mov    %al,0x1(%rbp)
  mov    %r14d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  jne    L65
  add    $0x1,%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  je     L65
  mov    (%rsp),%rax
  mov    %al,0x2(%rbp)
  mov    %r15d,%eax
  add    %rax,%rbx
  cmpb   $0x2e,(%rbx)
  jne    L65
  lea    0x1(%rbx),%rdi
  mov    %r13,%rsi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L65
  mov    (%rsp),%rdx
  mov    %dl,0x3(%rbp)
  lea    0x3(%r12,%r14,1),%edx
  add    %r15d,%edx
  add    %edx,%eax
  jmp    L34
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned scan_ip4(const char *s, char ip[4]) {
  unsigned i;
  unsigned len;
  unsigned long u;
  len = 0;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[0] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[1] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[2] = u;
  s += i;
  len += i;
  if (*s != '.')
    return 0;
  ++s;
  ++len;
  i = scan_ulong(s, &u);
  if (!i)
    return 0;
  ip[3] = u;
  s += i;
  len += i;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L59
L29:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L41
  addl   $0x1,-0x4(%rbp)
  jmp    L58
L41:
  addl   $0x1,-0x8(%rbp)
L59:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jle    L29
L58:
  cmpl   $0x0,-0x4(%rbp)
  jne    L22
  cmpl   $0x1,-0x14(%rbp)
  je     L22
  mov    $0x1,%eax
  jmp    L18
L22:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int m) {
  int i, count = 0;
  for (i = 2; i <= m / 2; i++) {
    if (m % i == 0) {
      count++;
      break;
    }
  }
  if (count == 0 && m != 1)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L50
  test   $0x1,%dil
  je     L40
  mov    $0x2,%ecx
L34:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L7
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L34
  mov    $0x1,%eax
  jmp    L25
L7:
  mov    $0x0,%eax
L25:
  test   %eax,%eax
  sete   %dl
  cmp    $0x1,%edi
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
L50:
  mov    $0x0,%eax
  jmp    L25
L40:
  mov    $0x1,%eax
  jmp    L25
```

assistant: ```c
int is_prime(int m) {
  int i, count = 0;
  for (i = 2; i <= m / 2; i++) {
    if (m % i == 0) {
      count++;
      break;
    }
  }
  if (count == 0 && m != 1)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L36
  test   $0x1,%dil
  je     L18
  mov    $0x2,%ecx
  jmp    L34
  nop
L15:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L27
L34:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jle    L15
L36:
  xor    %edx,%edx
  cmp    $0x1,%edi
  setne  %dl
L27:
  mov    %edx,%eax
  ret
L18:
  xor    %edx,%edx
  jmp    L27
```

assistant: ```c
int is_prime(int m) {
  int i, count = 0;
  for (i = 2; i <= m / 2; i++) {
    if (m % i == 0) {
      count++;
      break;
    }
  }
  if (count == 0 && m != 1)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L5
  test   $0x1,%dil
  je     L22
  mov    $0x2,%ecx
  jmp    L51
  nop
L57:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L46
L51:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jle    L57
L5:
  xor    %edx,%edx
  cmp    $0x1,%edi
  setne  %dl
L46:
  mov    %edx,%eax
  ret
L22:
  xor    %edx,%edx
  jmp    L46
```

assistant: ```c
int is_prime(int m) {
  int i, count = 0;
  for (i = 2; i <= m / 2; i++) {
    if (m % i == 0) {
      count++;
      break;
    }
  }
  if (count == 0 && m != 1)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__syscall6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x38(%rbp),%r10
  mov    -0x40(%rbp),%r8
  mov    0x10(%rbp),%r9
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdi
  mov    -0x28(%rbp),%rsi
  mov    -0x30(%rbp),%rdx
  syscall
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long __syscall6(long n, long a1, long a2, long a3, long a4, long a5, long a6) {
  unsigned long ret;
  register long r10 __asm__("r10") = a4;
  register long r8 __asm__("r8") = a5;
  register long r9 __asm__("r9") = a6;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3), "r"(r10), "r"(r8), "r"(r9) : "rcx", "r11", "memory");
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__syscall6>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %r8,%r10
  mov    %r9,%r8
  mov    0x8(%rsp),%r9
  syscall
  ret
```

assistant: ```c
long __syscall6(long n, long a1, long a2, long a3, long a4, long a5, long a6) {
  unsigned long ret;
  register long r10 __asm__("r10") = a4;
  register long r8 __asm__("r8") = a5;
  register long r9 __asm__("r9") = a6;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3), "r"(r10), "r"(r8), "r"(r9) : "rcx", "r11", "memory");
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<__syscall6>:
  endbr64
  mov    %rdi,%rax
  mov    %r8,%r10
  mov    %rsi,%rdi
  mov    %r9,%r8
  mov    %rdx,%rsi
  mov    0x8(%rsp),%r9
  mov    %rcx,%rdx
  syscall
  ret
```

assistant: ```c
long __syscall6(long n, long a1, long a2, long a3, long a4, long a5, long a6) {
  unsigned long ret;
  register long r10 __asm__("r10") = a4;
  register long r8 __asm__("r8") = a5;
  register long r9 __asm__("r9") = a6;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3), "r"(r10), "r"(r8), "r"(r9) : "rcx", "r11", "memory");
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__syscall6>:
  endbr64
  mov    %rdi,%rax
  mov    %r8,%r10
  mov    %rsi,%rdi
  mov    %r9,%r8
  mov    %rdx,%rsi
  mov    0x8(%rsp),%r9
  mov    %rcx,%rdx
  syscall
  ret
```

assistant: ```c
long __syscall6(long n, long a1, long a2, long a3, long a4, long a5, long a6) {
  unsigned long ret;
  register long r10 __asm__("r10") = a4;
  register long r8 __asm__("r8") = a5;
  register long r9 __asm__("r9") = a6;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3), "r"(r10), "r"(r8), "r"(r9) : "rcx", "r11", "memory");
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x34(%rbp)
  jmp    L2
L27:
  mov    -0x34(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <pow@plt>
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x34(%rbp)
L2:
  cmpl   $0x64,-0x34(%rbp)
  jle    L27
  mov    -0x20(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <pow@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D0
type: string

tool: D13: %lu - %lu = %lu

tool: D0: 
took %lu usec


assistant: ```c
int main(void) {
  struct timeval stop, start;
  gettimeofday(&start, NULL);
  int i;
  long sum = 0, squared = 0, squaredsum = 0;
  for (i = 1; i <= 100; i++) {
    sum += i;
    squared += pow(i, 2);
  }
  squaredsum = pow(sum, 2);
  printf("%lu - %lu = %lu", squaredsum, squared, squaredsum - squared);
  gettimeofday(&stop, NULL);
  printf("\ntook %lu usec\n", stop.tv_usec - start.tv_usec);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L10:
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <pow@plt>
  add    %rax,%rbp
  add    $0x1,%rbx
  cmp    $0x65,%rbx
  jne    L10
  mov    $0x2,%esi
  mov    $0x13ba,%edi
  call   <pow@plt>
  mov    %rax,%rsi
  mov    %rax,%rcx
  sub    %rbp,%rcx
  mov    %rbp,%rdx
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rsi
  sub    0x10(%rsp),%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D5
type: string

tool: D7: %lu - %lu = %lu

tool: D5: 
took %lu usec


assistant: ```c
int main(void) {
  struct timeval stop, start;
  gettimeofday(&start, NULL);
  int i;
  long sum = 0, squared = 0, squaredsum = 0;
  for (i = 1; i <= 100; i++) {
    sum += i;
    squared += pow(i, 2);
  }
  squaredsum = pow(sum, 2);
  printf("%lu - %lu = %lu", squaredsum, squared, squaredsum - squared);
  gettimeofday(&stop, NULL);
  printf("\ntook %lu usec\n", stop.tv_usec - start.tv_usec);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  xor    %r12d,%r12d
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  nop
L7:
  mov    %rbx,%rdi
  mov    $0x2,%esi
  add    $0x1,%rbx
  call   <pow@plt>
  add    %rax,%r12
  cmp    $0x65,%rbx
  jne    L7
  mov    $0x2,%esi
  mov    $0x13ba,%edi
  call   <pow@plt>
  mov    %r12,%rdx
  lea    D7(%rip),%rdi
  mov    %rax,%rcx
  mov    %rax,%rsi
  xor    %eax,%eax
  sub    %r12,%rcx
  call   <printf@plt>
  xor    %esi,%esi
  lea    0x8(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  sub    0x10(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string

tool: D7: %lu - %lu = %lu

tool: D18: 
took %lu usec


assistant: ```c
int main(void) {
  struct timeval stop, start;
  gettimeofday(&start, NULL);
  int i;
  long sum = 0, squared = 0, squaredsum = 0;
  for (i = 1; i <= 100; i++) {
    sum += i;
    squared += pow(i, 2);
  }
  squaredsum = pow(sum, 2);
  printf("%lu - %lu = %lu", squaredsum, squared, squaredsum - squared);
  gettimeofday(&stop, NULL);
  printf("\ntook %lu usec\n", stop.tv_usec - start.tv_usec);
  return 0;
}
```