user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matriz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D64(%rip),%r13
  push   %r12
  lea    D55(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %edi,0xc(%rsp)
  lea    D7(%rip),%rdi
  lea    0x10(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L146
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <scanf@plt>
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jg     L22
L146:
  mov    $0xa,%edi
  xor    %r13d,%r13d
  lea    0x10(%rsp),%rbx
  call   <putchar@plt>
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%r14d
  movq   $0x0,(%rsp)
  lea    D55(%rip),%rbp
  lea    -0x1(%r8),%r12d
  test   %r12d,%r12d
  jle    L59
  nopl   (%rax)
L88:
  movslq %r12d,%rax
  lea    (%rbx,%rax,4),%rcx
L71:
  cmp    %r13d,%r12d
  setg   %sil
  xor    %eax,%eax
L24:
  test   %eax,%eax
  jne    L48
  test   %sil,%sil
  je     L93
  mov    $0x1,%eax
  cmp    %r14d,(%rcx)
  jle    L24
  sub    $0x1,%r12d
  sub    $0x4,%rcx
  jmp    L71
  nopl   (%rax)
L93:
  test   %eax,%eax
  jne    L48
L124:
  xor    %r15d,%r15d
  test   %r8d,%r8d
  jle    L60
  nopl   0x0(%rax)
L9:
  mov    (%rbx,%r15,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15d,0xc(%rsp)
  jg     L9
L60:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%r13d
  jge    L111
  mov    0xc(%rsp),%r8d
  jmp    L88
  nop
L48:
  movslq %r12d,%r9
  mov    (%rsp),%rdx
  add    $0x1,%r13d
  mov    0x10(%rsp,%r9,4),%ecx
  lea    (%rbx,%rdx,4),%rsi
  mov    %ecx,0x10(%rsp,%rdx,4)
L123:
  cmp    %r12d,%r13d
  setl   %dil
  xor    %ecx,%ecx
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L203:
  mov    %eax,%ecx
L42:
  test   $0x1,%cl
  jne    L16
  test   %dil,%dil
  je     L16
  cmp    %r14d,0x4(%rsi)
  jg     L203
  add    $0x1,%r13d
  add    $0x4,%rsi
  jmp    L123
  nopl   0x0(%rax)
L16:
  movslq %r13d,%rax
  mov    %rax,(%rsp)
  test   %ecx,%ecx
  je     L124
  mov    0x10(%rsp,%rax,4),%eax
  sub    $0x1,%r12d
  mov    %eax,0x10(%rsp,%r9,4)
  jmp    L124
L111:
  mov    0xc(%rsp),%r8d
L59:
  mov    (%rsp),%rax
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  lea    D55(%rip),%r12
  mov    %r14d,0x10(%rsp,%rax,4)
  test   %r8d,%r8d
  jle    L100
  nopw   0x0(%rax,%rax,1)
L185:
  mov    (%rbx,%rbp,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jg     L185
L100:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L144
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L144:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D64
data_type: string
name: extract_symbolic_data
arguments: data_tag: D55
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D40
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D64: %d

tool: D55: %d 

tool: D7: Digite n: 

tool: D40: n = %d


tool: D5: Digite uma sequencia de %d numeros.


assistant: ```c
int matriz(int n) {
  int inic, fim, i, aux, para, a[100];
  printf("Digite n: ");
  scanf("%d", &n);
  printf("n = %d\n", n);
  printf("Digite uma sequencia de %d numeros.\n", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    printf("%d ", a[i]);
  }
  printf("\n");
  inic = 0;
  fim = n - 1;
  aux = a[inic];
  while (inic < fim) {
    para = 0;
    while ((inic < fim) && !para) {
      if (a[fim] <= aux)
        para = 1;
      else
        fim = fim - 1;
    }
    if (para) {
      a[inic] = a[fim];
      inic = inic + 1;
      para = 0;
      while ((inic < fim) && !para) {
        if (a[inic] <= aux)
          inic = inic + 1;
        else
          para = 1;
      }
      if (para) {
        a[fim] = a[inic];
        fim = fim - 1;
      }
    }
    for (i = 0; i < n; i++)
      printf("%d ", a[i]);
    printf("\n");
  }
  a[inic] = aux;
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```