ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<xdr_double>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L74
  cmp    $0x82,%eax
  je     L44
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L88:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L74:
  mov    D24(%rip),%rdx
  mov    D8(%rip),%rcx
  movslq (%rsi),%rax
  mov    (%rdx),%edx
  cmp    %edx,(%rcx)
  je     L36
  movslq 0x4(%rsi),%rax
L32:
  mov    %rax,(%rsp)
  movslq (%rbx),%rax
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  call   <XDR_PUTLONG@plt>
  test   %eax,%eax
  je     L88
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <XDR_PUTLONG@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L88
  nopl   0x0(%rax)
L44:
  mov    D8(%rip),%r14
  mov    D24(%rip),%r13
  mov    %rsp,%r12
  mov    0x0(%r13),%eax
  cmp    %eax,(%r14)
  setne  %al
  movzbl %al,%eax
  lea    (%r12,%rax,8),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  je     L84
  mov    0x0(%r13),%eax
  cmp    %eax,(%r14)
  mov    %rbp,%rdi
  sete   %al
  movzbl %al,%eax
  lea    (%r12,%rax,8),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  jne    L51
L84:
  xor    %eax,%eax
  jmp    L88
  nop
L36:
  add    $0x4,%rbx
  jmp    L32
  nopl   0x0(%rax)
L51:
  mov    (%rsp),%rax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  mov    %eax,0x4(%rbx)
  mov    $0x1,%eax
  jmp    L88
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_double(XDR *xdrs, double *dp) {
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    if (2 * sizeof(long) == sizeof(double)) {
      long *lp = (long *)dp;
      return (XDR_PUTLONG(xdrs, lp + !(__FLOAT_WORD_ORDER == __BIG_ENDIAN)) && XDR_PUTLONG(xdrs, lp + (__FLOAT_WORD_ORDER == __BIG_ENDIAN)));
    } else if (2 * sizeof(int) == sizeof(double)) {
      int *ip = (int *)dp;
      long tmp[2];
      tmp[0] = ip[!(__FLOAT_WORD_ORDER == __BIG_ENDIAN)];
      tmp[1] = ip[(__FLOAT_WORD_ORDER == __BIG_ENDIAN)];
      return (XDR_PUTLONG(xdrs, tmp) && XDR_PUTLONG(xdrs, tmp + 1));
    }
    break;
  case XDR_DECODE:
    if (2 * sizeof(long) == sizeof(double)) {
      long *lp = (long *)dp;
      return (XDR_GETLONG(xdrs, lp + !(__FLOAT_WORD_ORDER == __BIG_ENDIAN)) && XDR_GETLONG(xdrs, lp + (__FLOAT_WORD_ORDER == __BIG_ENDIAN)));
    } else if (2 * sizeof(int) == sizeof(double)) {
      int *ip = (int *)dp;
      long tmp[2];
      if (XDR_GETLONG(xdrs, tmp + !(__FLOAT_WORD_ORDER == __BIG_ENDIAN)) && XDR_GETLONG(xdrs, tmp + (__FLOAT_WORD_ORDER == __BIG_ENDIAN))) {
        ip[0] = tmp[0];
        ip[1] = tmp[1];
        return ((1));
      }
    }
    break;
  case XDR_FREE:
    return ((1));
  }
  return ((0));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xdr_double>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L14
  cmp    $0x82,%eax
  je     L97
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L71:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L14:
  mov    D8(%rip),%rdx
  mov    D37(%rip),%rcx
  movslq (%rsi),%rax
  mov    (%rdx),%edx
  cmp    %edx,(%rcx)
  je     L38
  movslq 0x4(%rsi),%rax
  movq   %rax,%xmm0
L5:
  movslq (%rbx),%rax
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <XDR_PUTLONG@plt>
  test   %eax,%eax
  je     L71
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <XDR_PUTLONG@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L97:
  mov    D37(%rip),%r14
  mov    D8(%rip),%r13
  mov    %rsp,%r12
  mov    0x0(%r13),%eax
  cmp    %eax,(%r14)
  setne  %al
  movzbl %al,%eax
  lea    (%r12,%rax,8),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  je     L55
  mov    0x0(%r13),%eax
  cmp    %eax,(%r14)
  mov    %rbp,%rdi
  sete   %al
  movzbl %al,%eax
  lea    (%r12,%rax,8),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  jne    L77
L55:
  xor    %eax,%eax
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L38:
  movq   %rax,%xmm0
  add    $0x4,%rbx
  jmp    L5
  xchg   %ax,%ax
L77:
  movd   (%rsp),%xmm0
  movd   0x8(%rsp),%xmm2
  mov    $0x1,%eax
  punpckldq %xmm2,%xmm0
  movq   %xmm0,(%rbx)
  jmp    L71
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_double(XDR *xdrs, double *dp) {
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    if (2 * sizeof(long) == sizeof(double)) {
      long *lp = (long *)dp;
      return (XDR_PUTLONG(xdrs, lp + !(__FLOAT_WORD_ORDER == __BIG_ENDIAN)) && XDR_PUTLONG(xdrs, lp + (__FLOAT_WORD_ORDER == __BIG_ENDIAN)));
    } else if (2 * sizeof(int) == sizeof(double)) {
      int *ip = (int *)dp;
      long tmp[2];
      tmp[0] = ip[!(__FLOAT_WORD_ORDER == __BIG_ENDIAN)];
      tmp[1] = ip[(__FLOAT_WORD_ORDER == __BIG_ENDIAN)];
      return (XDR_PUTLONG(xdrs, tmp) && XDR_PUTLONG(xdrs, tmp + 1));
    }
    break;
  case XDR_DECODE:
    if (2 * sizeof(long) == sizeof(double)) {
      long *lp = (long *)dp;
      return (XDR_GETLONG(xdrs, lp + !(__FLOAT_WORD_ORDER == __BIG_ENDIAN)) && XDR_GETLONG(xdrs, lp + (__FLOAT_WORD_ORDER == __BIG_ENDIAN)));
    } else if (2 * sizeof(int) == sizeof(double)) {
      int *ip = (int *)dp;
      long tmp[2];
      if (XDR_GETLONG(xdrs, tmp + !(__FLOAT_WORD_ORDER == __BIG_ENDIAN)) && XDR_GETLONG(xdrs, tmp + (__FLOAT_WORD_ORDER == __BIG_ENDIAN))) {
        ip[0] = tmp[0];
        ip[1] = tmp[1];
        return ((1));
      }
    }
    break;
  case XDR_FREE:
    return ((1));
  }
  return ((0));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double mean(const double *samples, int n) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += samples[i];
  return sum / n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mean>:
  endbr64
  test   %esi,%esi
  jle    L21
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L29:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L29
L5:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L21:
  pxor   %xmm0,%xmm0
  jmp    L5
```

assistant: ```c
double mean(const double *samples, int n) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += samples[i];
  return sum / n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mean>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L6:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L6
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double mean(const double *samples, int n) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += samples[i];
  return sum / n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mean>:
  endbr64
  test   %esi,%esi
  jle    L5
  cmp    $0x1,%esi
  je     L8
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L16:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L16
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L3
L32:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
L3:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L32
```

assistant: ```c
double mean(const double *samples, int n) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += samples[i];
  return sum / n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: Hello world from t1 Main!


assistant: ```c
int main() {
  printf("Hello world from t1 Main!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D5: Hello world from t1 Main!


assistant: ```c
int main() {
  printf("Hello world from t1 Main!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: Hello world from t1 Main!


assistant: ```c
int main() {
  printf("Hello world from t1 Main!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: Hello world from t1 Main!


assistant: ```c
int main() {
  printf("Hello world from t1 Main!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ilog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  test   %eax,%eax
  je     L10
  mov    $0x10,%eax
  jmp    L28
L10:
  mov    $0x0,%eax
L28:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  test   %eax,%eax
  je     L1
  mov    $0x8,%eax
  jmp    L21
L1:
  mov    $0x0,%eax
L21:
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  test   %eax,%eax
  je     L34
  mov    $0x4,%eax
  jmp    L75
L34:
  mov    $0x0,%eax
L75:
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  test   %eax,%eax
  je     L61
  mov    $0x2,%eax
  jmp    L51
L61:
  mov    $0x0,%eax
L51:
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ilog2(int x) {
  int pos = 0;
  pos = (!!(x >> 16)) << 4;
  pos = pos + ((!!(x >> (pos + 8))) << 3);
  pos = pos + ((!!(x >> (pos + 4))) << 2);
  pos = pos + ((!!(x >> (pos + 2))) << 1);
  pos = pos + (!!(x >> (pos + 1)));
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ilog2>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shr    $0x10,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0x4,%eax
  lea    0x8(%rax),%ecx
  mov    %edi,%esi
  sar    %cl,%esi
  test   %esi,%esi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,8),%eax
  lea    0x4(%rax),%ecx
  mov    %edi,%esi
  sar    %cl,%esi
  test   %esi,%esi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,4),%eax
  lea    0x2(%rax),%ecx
  sar    %cl,%edi
  test   %edi,%edi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,2),%eax
  lea    0x1(%rax),%ecx
  sar    %cl,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int ilog2(int x) {
  int pos = 0;
  pos = (!!(x >> 16)) << 4;
  pos = pos + ((!!(x >> (pos + 8))) << 3);
  pos = pos + ((!!(x >> (pos + 4))) << 2);
  pos = pos + ((!!(x >> (pos + 2))) << 1);
  pos = pos + (!!(x >> (pos + 1)));
  return pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ilog2>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%esi
  mov    %edi,%edx
  shr    $0x10,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0x4,%eax
  lea    0x8(%rax),%ecx
  sar    %cl,%esi
  test   %esi,%esi
  mov    %edi,%esi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,8),%eax
  lea    0x4(%rax),%ecx
  sar    %cl,%esi
  test   %esi,%esi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,4),%eax
  lea    0x2(%rax),%ecx
  sar    %cl,%edi
  test   %edi,%edi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,2),%eax
  lea    0x1(%rax),%ecx
  sar    %cl,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int ilog2(int x) {
  int pos = 0;
  pos = (!!(x >> 16)) << 4;
  pos = pos + ((!!(x >> (pos + 8))) << 3);
  pos = pos + ((!!(x >> (pos + 4))) << 2);
  pos = pos + ((!!(x >> (pos + 2))) << 1);
  pos = pos + (!!(x >> (pos + 1)));
  return pos;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ilog2>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%esi
  mov    %edi,%edx
  shr    $0x10,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0x4,%eax
  lea    0x8(%rax),%ecx
  sar    %cl,%esi
  test   %esi,%esi
  mov    %edi,%esi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,8),%eax
  lea    0x4(%rax),%ecx
  sar    %cl,%esi
  test   %esi,%esi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,4),%eax
  lea    0x2(%rax),%ecx
  sar    %cl,%edi
  test   %edi,%edi
  setne  %cl
  movzbl %cl,%ecx
  lea    (%rax,%rcx,2),%eax
  lea    0x1(%rax),%ecx
  sar    %cl,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int ilog2(int x) {
  int pos = 0;
  pos = (!!(x >> 16)) << 4;
  pos = pos + ((!!(x >> (pos + 8))) << 3);
  pos = pos + ((!!(x >> (pos + 4))) << 2);
  pos = pos + ((!!(x >> (pos + 2))) << 1);
  pos = pos + (!!(x >> (pos + 1)));
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OUT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <out_@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void OUT(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  out_(fmt, args);
  va_end(args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OUT>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <out_@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void OUT(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  out_(fmt, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<OUT>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <out_@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void OUT(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  out_(fmt, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<OUT>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <out_@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void OUT(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  out_(fmt, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L27
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L13
L27:
  mov    -0xc(%rbp),%eax
  imul   $0x34,%eax,%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_infered: string
name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D36
type_infered: string

tool: D19: Enter the number of decks: 

tool: D24: %i

tool: D22: Not a valid number of decks

tool: D36: There are %i cards in the deck.


assistant: ```c
int main() {
  int decks;
  puts("Enter the number of decks: ");
  scanf("%i", &decks);
  if (decks < 1) {
    puts("Not a valid number of decks");
    return 1;
  }
  printf("There are %i cards in the deck.\n", (decks * 52));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L13
  imul   $0x34,%esi,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  ret
L13:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L8
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
datatype: string
name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D20
datatype: string
name: retrieve_data
arguments: data_tag: D29
datatype: string

tool: D24: Enter the number of decks: 

tool: D3: %i

tool: D20: There are %i cards in the deck.


tool: D29: Not a valid number of decks

assistant: ```c
int main() {
  int decks;
  puts("Enter the number of decks: ");
  scanf("%i", &decks);
  if (decks < 1) {
    puts("Not a valid number of decks");
    return 1;
  }
  printf("There are %i cards in the deck.\n", (decks * 52));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L27
  imul   $0x34,%esi,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L27:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L4
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string

tool: D6: Enter the number of decks: 

tool: D32: %i

tool: D35: There are %i cards in the deck.


tool: D20: Not a valid number of decks

assistant: ```c
int main() {
  int decks;
  puts("Enter the number of decks: ");
  scanf("%i", &decks);
  if (decks < 1) {
    puts("Not a valid number of decks");
    return 1;
  }
  printf("There are %i cards in the deck.\n", (decks * 52));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L22
  imul   $0x34,%esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L22:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L12
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D31
data_type: string
name: read_data
arguments: data_label: D7
data_type: string
name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D24
data_type: string

tool: D31: Enter the number of decks: 

tool: D7: %i

tool: D4: There are %i cards in the deck.


tool: D24: Not a valid number of decks

assistant: ```c
int main() {
  int decks;
  puts("Enter the number of decks: ");
  scanf("%i", &decks);
  if (decks < 1) {
    puts("Not a valid number of decks");
    return 1;
  }
  printf("There are %i cards in the deck.\n", (decks * 52));
  return 0;
}
```