ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<util_strreplace>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  cmpb   $0x0,(%rdx)
  je     L133
  mov    $0x1,%eax
  nopl   0x0(%rax)
L72:
  mov    %eax,%r13d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbp,%rax,1)
  jne    L72
L148:
  movzbl (%rdi),%ecx
  mov    %r15d,%r8d
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  sub    $0x1,%r13d
  test   %cl,%cl
  je     L62
L108:
  movzbl (%rbx),%eax
  test   %al,%al
  setne  %sil
  cmp    $0x2e,%al
  setne  %dl
  test   %dl,%sil
  je     L107
  cmp    %al,%cl
  jne    L144
L107:
  movslq %r14d,%r10
  xor    %edx,%edx
  add    %rdi,%r10
  nopl   0x0(%rax)
L19:
  cmp    $0x2e,%al
  je     L104
  test   %al,%al
  je     L90
L165:
  test   %cl,%cl
  je     L62
  movzbl 0x1(%rbx,%rdx,1),%eax
  movzbl 0x1(%r10,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  setne  %r9b
  cmp    %al,%cl
  setne  %sil
  test   %sil,%r9b
  je     L19
  cmp    $0x2e,%al
  je     L19
L144:
  add    $0x1,%r14d
  movslq %r14d,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L108
L62:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L104:
  mov    %ecx,%r12d
  jmp    L165
  nopl   (%rax)
L90:
  sub    $0x1,%r8d
  test   %r15d,%r15d
  je     L77
  test   %r8d,%r8d
  jne    L144
  mov    %edx,%ecx
  mov    %rbp,%rsi
  mov    %r14d,%edx
  call   <replace@plt>
  jmp    L62
  nopl   (%rax)
L77:
  mov    %edx,%ecx
  mov    %rbp,%rsi
  mov    %r14d,%edx
  add    %r13d,%r14d
  mov    %r8d,0xc(%rsp)
  add    $0x1,%r14d
  mov    %rdi,(%rsp)
  call   <replace@plt>
  mov    (%rsp),%rdi
  movslq %r14d,%rax
  mov    0xc(%rsp),%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L108
  jmp    L62
L133:
  xor    %r13d,%r13d
  jmp    L148
```

assistant: ```c
char util_strreplace(char a[], char x[], char y[], int n) {
  int replaceAll = !n;
  int i, j, lengthY;
  char dot = '\0';
  for (lengthY = 0; y[lengthY] != '\0'; lengthY++)
    ;
  for (i = 0; a[i] != '\0'; i++) {
    for (j = 0;; j++) {
      if (a[i + j] != x[j] && x[j] != '\0' && x[j] != '.')
        break;
      if (x[j] == '.')
        dot = a[i + j];
      if (x[j] == '\0') {
        n--;
        if (replaceAll) {
          replace(a, y, i, j);
          i += lengthY - 1;
        } else if (n == 0) {
          replace(a, y, i, j);
          return dot;
        }
        break;
      }
      if (a[i + j] == '\0')
        return dot;
    }
  }
  return dot;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<util_strreplace>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  cmpb   $0x0,(%rdx)
  je     L165
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %eax,%r13d
  add    $0x1,%rax
  cmpb   $0x0,0x0(%rbp,%rax,1)
  jne    L4
L24:
  movzbl (%rdi),%ecx
  mov    %r15d,%r8d
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  test   %cl,%cl
  je     L143
L89:
  movzbl (%rbx),%eax
  test   %al,%al
  setne  %sil
  cmp    $0x2e,%al
  setne  %dl
  test   %dl,%sil
  je     L115
  cmp    %cl,%al
  jne    L20
L115:
  movslq %r14d,%r10
  xor    %edx,%edx
  add    %rdi,%r10
  nopl   (%rax)
L173:
  cmp    $0x2e,%al
  je     L134
  test   %al,%al
  je     L22
L47:
  test   %cl,%cl
  je     L143
  movzbl 0x1(%rbx,%rdx,1),%eax
  movzbl 0x1(%r10,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  setne  %r9b
  cmp    %al,%cl
  setne  %sil
  test   %sil,%r9b
  je     L173
  cmp    $0x2e,%al
  je     L173
L20:
  add    $0x1,%r14d
  movslq %r14d,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L89
L143:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L134:
  mov    %ecx,%r12d
  jmp    L47
  nopl   (%rax)
L22:
  sub    $0x1,%r8d
  test   %r15d,%r15d
  je     L130
  test   %r8d,%r8d
  jne    L20
  mov    %edx,%ecx
  mov    %rbp,%rsi
  mov    %r14d,%edx
  call   <replace@plt>
  jmp    L143
  nopl   (%rax)
L130:
  mov    %edx,%ecx
  mov    %rbp,%rsi
  mov    %r14d,%edx
  add    %r13d,%r14d
  mov    %r8d,0xc(%rsp)
  add    $0x1,%r14d
  mov    %rdi,(%rsp)
  call   <replace@plt>
  mov    (%rsp),%rdi
  movslq %r14d,%rax
  mov    0xc(%rsp),%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L89
  jmp    L143
L165:
  mov    $0xffffffff,%r13d
  jmp    L24
```

assistant: ```c
char util_strreplace(char a[], char x[], char y[], int n) {
  int replaceAll = !n;
  int i, j, lengthY;
  char dot = '\0';
  for (lengthY = 0; y[lengthY] != '\0'; lengthY++)
    ;
  for (i = 0; a[i] != '\0'; i++) {
    for (j = 0;; j++) {
      if (a[i + j] != x[j] && x[j] != '\0' && x[j] != '.')
        break;
      if (x[j] == '.')
        dot = a[i + j];
      if (x[j] == '\0') {
        n--;
        if (replaceAll) {
          replace(a, y, i, j);
          i += lengthY - 1;
        } else if (n == 0) {
          replace(a, y, i, j);
          return dot;
        }
        break;
      }
      if (a[i + j] == '\0')
        return dot;
    }
  }
  return dot;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L1:
  addl   $0x1,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <l0_insert@plt>
  cmpl   $0x2,-0x4(%rbp)
  jg     L15
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L1
L15:
  mov    D4(%rip),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <l0_destroy@plt>
  mov    D4(%rip),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int main() {
  static struct L0 *list;
  int c = 0;
  do {
    c++;
    l0_insert(&list);
  } while (c < 3 && __VERIFIER_nondet_int());
  l0_destroy(list, 5);
  l0_destroy(list, 4);
  l0_destroy(list, 3);
  l0_destroy(list, 2);
  l0_destroy(list, 2);
  l0_destroy(list, 1);
  l0_destroy(list, 0);
  return !!list;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D67(%rip),%rdi
  call   <l0_insert@plt>
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L7
  lea    D67(%rip),%rdi
  call   <l0_insert@plt>
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L7
  lea    D67(%rip),%rdi
  call   <l0_insert@plt>
L7:
  mov    $0x5,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  mov    $0x4,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  mov    $0x3,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  mov    $0x2,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  mov    $0x2,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  mov    $0x1,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  mov    $0x0,%esi
  mov    D67(%rip),%rdi
  call   <l0_destroy@plt>
  cmpq   $0x0,D67(%rip)
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  static struct L0 *list;
  int c = 0;
  do {
    c++;
    l0_insert(&list);
  } while (c < 3 && __VERIFIER_nondet_int());
  l0_destroy(list, 5);
  l0_destroy(list, 4);
  l0_destroy(list, 3);
  l0_destroy(list, 2);
  l0_destroy(list, 2);
  l0_destroy(list, 1);
  l0_destroy(list, 0);
  return !!list;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rbp
  mov    %rbp,%rdi
  call   <l0_insert@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdi
  call   <l0_insert@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdi
  call   <l0_insert@plt>
L9:
  mov    D27(%rip),%rdi
  mov    $0x5,%esi
  call   <l0_destroy@plt>
  mov    D27(%rip),%rdi
  mov    $0x4,%esi
  call   <l0_destroy@plt>
  mov    D27(%rip),%rdi
  mov    $0x3,%esi
  call   <l0_destroy@plt>
  mov    D27(%rip),%rdi
  mov    $0x2,%esi
  call   <l0_destroy@plt>
  mov    D27(%rip),%rdi
  mov    $0x2,%esi
  call   <l0_destroy@plt>
  mov    D27(%rip),%rdi
  mov    $0x1,%esi
  call   <l0_destroy@plt>
  mov    D27(%rip),%rdi
  xor    %esi,%esi
  call   <l0_destroy@plt>
  xor    %eax,%eax
  cmpq   $0x0,D27(%rip)
  pop    %rbp
  setne  %al
  ret
```

assistant: ```c
int main() {
  static struct L0 *list;
  int c = 0;
  do {
    c++;
    l0_insert(&list);
  } while (c < 3 && __VERIFIER_nondet_int());
  l0_destroy(list, 5);
  l0_destroy(list, 4);
  l0_destroy(list, 3);
  l0_destroy(list, 2);
  l0_destroy(list, 2);
  l0_destroy(list, 1);
  l0_destroy(list, 0);
  return !!list;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D73(%rip),%rbp
  mov    %rbp,%rdi
  call   <l0_insert@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L10
  mov    %rbp,%rdi
  call   <l0_insert@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L10
  mov    %rbp,%rdi
  call   <l0_insert@plt>
L10:
  mov    D73(%rip),%rdi
  mov    $0x5,%esi
  call   <l0_destroy@plt>
  mov    D73(%rip),%rdi
  mov    $0x4,%esi
  call   <l0_destroy@plt>
  mov    D73(%rip),%rdi
  mov    $0x3,%esi
  call   <l0_destroy@plt>
  mov    D73(%rip),%rdi
  mov    $0x2,%esi
  call   <l0_destroy@plt>
  mov    D73(%rip),%rdi
  mov    $0x2,%esi
  call   <l0_destroy@plt>
  mov    D73(%rip),%rdi
  mov    $0x1,%esi
  call   <l0_destroy@plt>
  mov    D73(%rip),%rdi
  xor    %esi,%esi
  call   <l0_destroy@plt>
  xor    %eax,%eax
  cmpq   $0x0,D73(%rip)
  pop    %rbp
  setne  %al
  ret
```

assistant: ```c
int main() {
  static struct L0 *list;
  int c = 0;
  do {
    c++;
    l0_insert(&list);
  } while (c < 3 && __VERIFIER_nondet_int());
  l0_destroy(list, 5);
  l0_destroy(list, 4);
  l0_destroy(list, 3);
  l0_destroy(list, 2);
  l0_destroy(list, 2);
  l0_destroy(list, 1);
  l0_destroy(list, 0);
  return !!list;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utarray_str_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L16
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L16:
  nop
  leave
  ret
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src == NULL) {
    *_dst = NULL;
  } else {
    size_t len = strlen(*_src) + 1;
    *_dst = malloc(len);
    memcpy(*_dst, *_src, len);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utarray_str_cpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L4
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %r12,%rdx
  mov    (%rbx),%rsi
  call   <memcpy@plt>
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  movq   $0x0,0x0(%rbp)
  jmp    L12
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src == NULL) {
    *_dst = NULL;
  } else {
    size_t len = strlen(*_src) + 1;
    *_dst = malloc(len);
    memcpy(*_dst, *_src, len);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utarray_str_cpy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L0
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rsi
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
L0:
  pop    %rbx
  movq   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src == NULL) {
    *_dst = NULL;
  } else {
    size_t len = strlen(*_src) + 1;
    *_dst = malloc(len);
    memcpy(*_dst, *_src, len);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utarray_str_cpy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L1
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rsi
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
L1:
  pop    %rbx
  movq   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void utarray_str_cpy(void *dst, const void *src) {
  char **_src = (char **)src, **_dst = (char **)dst;
  if (*_src == NULL) {
    *_dst = NULL;
  } else {
    size_t len = strlen(*_src) + 1;
    *_dst = malloc(len);
    memcpy(*_dst, *_src, len);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mapreduce_init@plt>
  mov    $0x0,%eax
  call   <view_tests@plt>
  mov    $0x0,%eax
  call   <purge_tests@plt>
  mov    $0x0,%eax
  call   <mapreduce_deinit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  mapreduce_init();
  view_tests();
  purge_tests();
  mapreduce_deinit();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mapreduce_init@plt>
  mov    $0x0,%eax
  call   <view_tests@plt>
  mov    $0x0,%eax
  call   <purge_tests@plt>
  mov    $0x0,%eax
  call   <mapreduce_deinit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mapreduce_init();
  view_tests();
  purge_tests();
  mapreduce_deinit();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mapreduce_init@plt>
  xor    %eax,%eax
  call   <view_tests@plt>
  xor    %eax,%eax
  call   <purge_tests@plt>
  xor    %eax,%eax
  call   <mapreduce_deinit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mapreduce_init();
  view_tests();
  purge_tests();
  mapreduce_deinit();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mapreduce_init@plt>
  xor    %eax,%eax
  call   <view_tests@plt>
  xor    %eax,%eax
  call   <purge_tests@plt>
  xor    %eax,%eax
  call   <mapreduce_deinit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mapreduce_init();
  view_tests();
  purge_tests();
  mapreduce_deinit();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<basepairing>:
  endbr64
  movl   $0x0,(%rcx)
  test   %esi,%esi
  jle    L85
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdi
  lea    D4(%rip),%r9
  jmp    L136
L66:
  cmpb   $0x6e,(%rax)
  je     L137
  addl   $0x1,(%rcx)
L137:
  sub    $0x1,%r8
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L32
L136:
  movzbl (%r8),%esi
  cmp    $0x6e,%sil
  je     L66
  movzbl (%rax),%edx
  sub    $0x61,%edx
  cmp    $0x18,%dl
  ja     L137
  movzbl %dl,%edx
  movslq (%r9,%rdx,4),%rdx
  add    %r9,%rdx
  notrack jmp *%rdx
  cmp    $0x74,%sil
  jne    L137
  addl   $0x1,(%rcx)
  jmp    L137
  cmp    $0x67,%sil
  jne    L137
  addl   $0x1,(%rcx)
  jmp    L137
  cmp    $0x63,%sil
  je     L122
  cmp    $0x74,%sil
  jne    L137
L122:
  addl   $0x1,(%rcx)
  jmp    L137
  cmp    $0x61,%sil
  je     L131
  cmp    $0x67,%sil
  jne    L137
L131:
  addl   $0x1,(%rcx)
  jmp    L137
  addl   $0x1,(%rcx)
  jmp    L137
L32:
  ret
L85:
  ret
```

assistant: ```c
void basepairing(char *ptr, int npair, int lpair, int *ncomp) {
  int n;
  *ncomp = 0;
  for (n = 0; n < npair; n++) {
    if ((*(ptr + lpair - n) == 'n') && (*(ptr + n) != 'n')) {
      (*ncomp)++;
    } else {
      switch (*(ptr + n)) {
      case 'a':
        if (*(ptr + lpair - n) == 't')
          (*ncomp)++;
        break;
      case 'c':
        if (*(ptr + lpair - n) == 'g')
          (*ncomp)++;
        break;
      case 'g':
      case 'r':
        if ((*(ptr + lpair - n) == 'c') || (*(ptr + lpair - n) == 't'))
          (*ncomp)++;
        break;
      case 't':
      case 'y':
        if ((*(ptr + lpair - n) == 'a') || (*(ptr + lpair - n) == 'g'))
          (*ncomp)++;
        break;
      case 'n':
        if (*(ptr + lpair - n) != 'n')
          (*ncomp)++;
        break;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<basepairing>:
  endbr64
  movl   $0x0,(%rcx)
  mov    %esi,%eax
  mov    %rcx,%r8
  test   %esi,%esi
  jle    L65
  movslq %edx,%rdx
  sub    $0x1,%eax
  lea    D6(%rip),%r9
  lea    -0x1(%rdi,%rdx,1),%rsi
  lea    (%rdi,%rdx,1),%rcx
  sub    %rax,%rsi
L41:
  movzbl (%rcx),%edx
  movzbl (%rdi),%eax
  cmp    $0x6e,%dl
  je     L49
  sub    $0x61,%eax
  cmp    $0x18,%al
  ja     L39
  movzbl %al,%eax
  movslq (%r9,%rax,4),%rax
  add    %r9,%rax
  notrack jmp *%rax
  nop
L49:
  cmp    $0x6e,%al
  je     L39
L55:
  addl   $0x1,(%r8)
L39:
  sub    $0x1,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  jne    L41
L45:
  ret
  cs nopw 0x0(%rax,%rax,1)
  cmp    $0x61,%dl
  je     L55
  cmp    $0x67,%dl
  je     L55
  sub    $0x1,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  jne    L41
  jmp    L45
  nopl   0x0(%rax)
  cmp    $0x63,%dl
  je     L55
  cmp    $0x74,%dl
  je     L55
  sub    $0x1,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  jne    L41
  jmp    L45
  nopl   0x0(%rax)
L65:
  ret
```

assistant: ```c
void basepairing(char *ptr, int npair, int lpair, int *ncomp) {
  int n;
  *ncomp = 0;
  for (n = 0; n < npair; n++) {
    if ((*(ptr + lpair - n) == 'n') && (*(ptr + n) != 'n')) {
      (*ncomp)++;
    } else {
      switch (*(ptr + n)) {
      case 'a':
        if (*(ptr + lpair - n) == 't')
          (*ncomp)++;
        break;
      case 'c':
        if (*(ptr + lpair - n) == 'g')
          (*ncomp)++;
        break;
      case 'g':
      case 'r':
        if ((*(ptr + lpair - n) == 'c') || (*(ptr + lpair - n) == 't'))
          (*ncomp)++;
        break;
      case 't':
      case 'y':
        if ((*(ptr + lpair - n) == 'a') || (*(ptr + lpair - n) == 'g'))
          (*ncomp)++;
        break;
      case 'n':
        if (*(ptr + lpair - n) != 'n')
          (*ncomp)++;
        break;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<basepairing>:
  endbr64
  movl   $0x0,(%rcx)
  mov    %esi,%eax
  mov    %rcx,%r8
  test   %esi,%esi
  jle    L112
  movslq %edx,%rdx
  sub    $0x1,%eax
  lea    D8(%rip),%r9
  lea    -0x1(%rdi,%rdx,1),%rsi
  lea    (%rdi,%rdx,1),%rcx
  sub    %rax,%rsi
L101:
  movzbl (%rcx),%edx
  movzbl (%rdi),%eax
  cmp    $0x6e,%dl
  je     L96
  sub    $0x61,%eax
  cmp    $0x18,%al
  ja     L85
  movzbl %al,%eax
  movslq (%r9,%rax,4),%rax
  add    %r9,%rax
  notrack jmp *%rax
  nop
L96:
  cmp    $0x6e,%al
  je     L85
L30:
  addl   $0x1,(%r8)
L85:
  sub    $0x1,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  jne    L101
L98:
  ret
  cs nopw 0x0(%rax,%rax,1)
  cmp    $0x61,%dl
  je     L30
  cmp    $0x67,%dl
  je     L30
  sub    $0x1,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  jne    L101
  jmp    L98
  nopl   0x0(%rax)
  cmp    $0x63,%dl
  je     L30
  cmp    $0x74,%dl
  je     L30
  sub    $0x1,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  jne    L101
  jmp    L98
  nopl   0x0(%rax)
L112:
  ret
```

assistant: ```c
void basepairing(char *ptr, int npair, int lpair, int *ncomp) {
  int n;
  *ncomp = 0;
  for (n = 0; n < npair; n++) {
    if ((*(ptr + lpair - n) == 'n') && (*(ptr + n) != 'n')) {
      (*ncomp)++;
    } else {
      switch (*(ptr + n)) {
      case 'a':
        if (*(ptr + lpair - n) == 't')
          (*ncomp)++;
        break;
      case 'c':
        if (*(ptr + lpair - n) == 'g')
          (*ncomp)++;
        break;
      case 'g':
      case 'r':
        if ((*(ptr + lpair - n) == 'c') || (*(ptr + lpair - n) == 't'))
          (*ncomp)++;
        break;
      case 't':
      case 'y':
        if ((*(ptr + lpair - n) == 'a') || (*(ptr + lpair - n) == 'g'))
          (*ncomp)++;
        break;
      case 'n':
        if (*(ptr + lpair - n) != 'n')
          (*ncomp)++;
        break;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lfds700_misc_prng_internal_hash_murmurhash3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x21,%rax
  xor    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xff51afd7ed558ccd,%rdx
  imul   %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x21,%rax
  xor    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xc4ceb9fe1a85ec53,%rdx
  imul   %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x21,%rax
  xor    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void lfds700_misc_prng_internal_hash_murmurhash3(int long long unsigned *murmurhash3_state) {
  assert(murmurhash3_state != ((void *)0));
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xff51afd7ed558ccdULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xc4ceb9fe1a85ec53ULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lfds700_misc_prng_internal_hash_murmurhash3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    (%rbx),%rax
  mov    %rax,%rdx
  shr    $0x21,%rdx
  xor    %rax,%rdx
  movabs $0xff51afd7ed558ccd,%rax
  imul   %rax,%rdx
  mov    %rdx,%rax
  shr    $0x21,%rax
  xor    %rdx,%rax
  movabs $0xc4ceb9fe1a85ec53,%rdx
  imul   %rdx,%rax
  mov    %rax,%rdx
  shr    $0x21,%rdx
  xor    %rdx,%rax
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void lfds700_misc_prng_internal_hash_murmurhash3(int long long unsigned *murmurhash3_state) {
  assert(murmurhash3_state != ((void *)0));
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xff51afd7ed558ccdULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xc4ceb9fe1a85ec53ULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  return;
}
```