ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<op_subtract_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D23(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L10
  lea    0x1(%rax),%r8d
  lea    D8(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D16(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L19:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D2(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L10:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D9(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: data_tag: D23
data_type: string
name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string

tool: 

tool: D8:  

tool: D16: %s%s:%*s

tool: D2: subtract an incoming set of interval values from the current set


tool: D9: %s%s: 

assistant: ```c
void op_subtract_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "subtract an incoming set of interval values from the current set\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_subtract_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D15(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L19
  lea    0x1(%rax),%r8d
  lea    D14(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D19(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L17:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D49(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L19:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D48(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: tag: D15
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D19
type_infered: string
name: read_data
arguments: tag: D49
type_infered: string
name: read_data
arguments: tag: D48
type_infered: string

tool: 

tool: D14:  

tool: D19: %s%s:%*s

tool: D49: subtract an incoming set of interval values from the current set


tool: D48: %s%s: 

assistant: ```c
void op_subtract_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "subtract an incoming set of interval values from the current set\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TimerCapture1Get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long TimerCapture1Get(unsigned long ulBase) {

  ;
  return (*((volatile unsigned long *)(ulBase + 0x00000034)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TimerCapture1Get>:
  endbr64
  mov    0x34(%rdi),%rax
  ret
```

assistant: ```c
unsigned long TimerCapture1Get(unsigned long ulBase) {

  ;
  return (*((volatile unsigned long *)(ulBase + 0x00000034)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TimerCapture1Get>:
  endbr64
  mov    0x34(%rdi),%rax
  ret
```

assistant: ```c
unsigned long TimerCapture1Get(unsigned long ulBase) {

  ;
  return (*((volatile unsigned long *)(ulBase + 0x00000034)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TimerCapture1Get>:
  endbr64
  mov    0x34(%rdi),%rax
  ret
```

assistant: ```c
unsigned long TimerCapture1Get(unsigned long ulBase) {

  ;
  return (*((volatile unsigned long *)(ulBase + 0x00000034)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_pins>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rcx
  lea    -0x12(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rcx
  lea    -0xd(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L86
L80:
  mov    -0x20(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%edx
  mov    -0x20(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L71
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x78,(%rax)
  mov    -0x20(%rbp),%eax
  cltq
  movb   $0x3f,-0x12(%rbp,%rax,1)
  mov    -0x20(%rbp),%eax
  cltq
  movb   $0x24,-0xd(%rbp,%rax,1)
L71:
  addl   $0x1,-0x20(%rbp)
L86:
  cmpl   $0x3,-0x20(%rbp)
  jle    L80
  movl   $0x0,-0x20(%rbp)
  jmp    L64
L77:
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L78:
  mov    -0x20(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L59
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6f,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  movb   $0x3f,-0x12(%rbp,%rax,1)
  mov    -0x20(%rbp),%eax
  cltq
  movb   $0x24,-0xd(%rbp,%rax,1)
  jmp    L47
L59:
  addl   $0x1,-0x1c(%rbp)
L18:
  cmpl   $0x3,-0x1c(%rbp)
  jle    L78
L47:
  addl   $0x1,-0x20(%rbp)
L64:
  cmpl   $0x3,-0x20(%rbp)
  jle    L77
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string

tool: D9: ----

assistant: ```c
void get_pins(const char *choice, const char *code, char *pins) {
  int i, j, k = 0;
  char code_c[5], choice_c[5];
  strcpy(pins, "----");
  memcpy(code_c, code, 5);
  memcpy(choice_c, choice, 5);
  for (i = 0; i < 4; i++)
    if (choice_c[i] == code_c[i]) {
      pins[k++] = ('x');
      code_c[i] = '?';
      choice_c[i] = '$';
    }
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (choice_c[i] == code_c[j]) {
        pins[k++] = ('o');
        code_c[j] = '?';
        choice_c[i] = '$';
        break;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_pins>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  lea    0xe(%rsp),%r12
  mov    $0x5,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  lea    0x13(%rsp),%rbx
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rcx
  lea    0x17(%rsp),%r8
  mov    %rbx,%rax
  mov    $0x0,%r9d
  jmp    L25
L2:
  add    $0x1,%rax
  add    $0x1,%rcx
  cmp    %r8,%rax
  je     L36
L25:
  movzbl (%rcx),%ebx
  cmp    %bl,(%rax)
  jne    L2
  movslq %r9d,%rsi
  movb   $0x78,0x0(%rbp,%rsi,1)
  movb   $0x3f,(%rcx)
  movb   $0x24,(%rax)
  lea    0x1(%r9),%r9d
  jmp    L2
L36:
  lea    0xe(%rsp),%rdi
  jmp    L98
L37:
  movslq %r9d,%rax
  movb   $0x6f,0x0(%rbp,%rax,1)
  movslq %esi,%rsi
  movb   $0x3f,0xe(%rsp,%rsi,1)
  movb   $0x24,(%r10)
  lea    0x1(%r9),%r9d
L85:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L18
L98:
  mov    %rdx,%r10
  movzbl (%rdx),%ecx
  mov    $0x0,%eax
L74:
  mov    %eax,%esi
  cmp    (%rax,%rdi,1),%cl
  je     L37
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L74
  jmp    L85
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: ----

assistant: ```c
void get_pins(const char *choice, const char *code, char *pins) {
  int i, j, k = 0;
  char code_c[5], choice_c[5];
  strcpy(pins, "----");
  memcpy(code_c, code, 5);
  memcpy(choice_c, choice, 5);
  for (i = 0; i < 4; i++)
    if (choice_c[i] == code_c[i]) {
      pins[k++] = ('x');
      code_c[i] = '?';
      choice_c[i] = '$';
    }
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (choice_c[i] == code_c[j]) {
        pins[k++] = ('o');
        code_c[j] = '?';
        choice_c[i] = '$';
        break;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_pins>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  lea    D2(%rip),%rsi
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  lea    0x13(%rsp),%rbx
  call   <strcpy@plt>
  mov    $0x5,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x5,%edx
  mov    %rbx,%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rcx
  lea    0x17(%rsp),%rdi
  mov    %rbx,%rax
  xor    %r8d,%r8d
L70:
  movzbl (%rcx),%ebx
  cmp    %bl,(%rax)
  jne    L19
  movslq %r8d,%rsi
  movb   $0x3f,(%rcx)
  add    $0x1,%r8d
  movb   $0x78,(%r12,%rsi,1)
  movb   $0x24,(%rax)
L19:
  add    $0x1,%rax
  add    $0x1,%rcx
  cmp    %rdi,%rax
  jne    L70
L43:
  movzbl (%rdx),%ecx
  xor    %eax,%eax
L13:
  movslq %eax,%rsi
  cmp    0x0(%rbp,%rax,1),%cl
  je     L59
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L13
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L43
L71:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  movslq %r8d,%rax
  movb   $0x24,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%r8d
  movb   $0x6f,(%r12,%rax,1)
  movb   $0x3f,0xe(%rsp,%rsi,1)
  cmp    %rdi,%rdx
  jne    L43
  jmp    L71
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D2: ----

assistant: ```c
void get_pins(const char *choice, const char *code, char *pins) {
  int i, j, k = 0;
  char code_c[5], choice_c[5];
  strcpy(pins, "----");
  memcpy(code_c, code, 5);
  memcpy(choice_c, choice, 5);
  for (i = 0; i < 4; i++)
    if (choice_c[i] == code_c[i]) {
      pins[k++] = ('x');
      code_c[i] = '?';
      choice_c[i] = '$';
    }
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (choice_c[i] == code_c[j]) {
        pins[k++] = ('o');
        code_c[j] = '?';
        choice_c[i] = '$';
        break;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no)) foo(int i, const char *x) {
  if (i >= 4)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  cmp    $0x3,%edi
  jg     L6
  ret
L6:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no)) foo(int i, const char *x) {
  if (i >= 4)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  cmp    $0x3,%edi
  jg     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) foo(int i, const char *x) {
  if (i >= 4)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  cmp    $0x3,%edi
  jg     L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) foo(int i, const char *x) {
  if (i >= 4)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_client_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <get_existent_client@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <remove_client@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void remove_client_fd(int s) {
  struct client *c = get_existent_client(s);
  if (c != 0)
    remove_client(c);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<remove_client_fd>:
  endbr64
  sub    $0x8,%rsp
  call   <get_existent_client@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <remove_client@plt>
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void remove_client_fd(int s) {
  struct client *c = get_existent_client(s);
  if (c != 0)
    remove_client(c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<remove_client_fd>:
  endbr64
  sub    $0x8,%rsp
  call   <get_existent_client@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <remove_client@plt>
  xchg   %ax,%ax
L4:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void remove_client_fd(int s) {
  struct client *c = get_existent_client(s);
  if (c != 0)
    remove_client(c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_client_fd>:
  endbr64
  sub    $0x8,%rsp
  call   <get_existent_client@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <remove_client@plt>
  xchg   %ax,%ax
L4:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void remove_client_fd(int s) {
  struct client *c = get_existent_client(s);
  if (c != 0)
    remove_client(c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L12:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L4:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    $0x3,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L4
  mov    $0x4,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void test(int M, int N) {
  int i, j;
  for (i = 0; i <= M; i++) {
    {
      hash(1);
      hash(i);
    };
    for (j = 0; j <= N; j++) {
      {
        hash(2);
        hash(i);
        hash(j);
      };
      {
        hash(3);
        hash(i);
        hash(j);
      };
    }
    {
      hash(4);
      hash(i);
    };
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  test   %edi,%edi
  js     L36
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    $0x0,%ebp
L4:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  test   %r12d,%r12d
  js     L12
  mov    $0x0,%ebx
L24:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L24
L12:
  mov    $0x4,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jge    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  ret
```

assistant: ```c
void test(int M, int N) {
  int i, j;
  for (i = 0; i <= M; i++) {
    {
      hash(1);
      hash(i);
    };
    for (j = 0; j <= N; j++) {
      {
        hash(2);
        hash(i);
        hash(j);
      };
      {
        hash(3);
        hash(i);
        hash(j);
      };
    }
    {
      hash(4);
      hash(i);
    };
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  test   %edi,%edi
  js     L6
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L0:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  test   %r12d,%r12d
  js     L21
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L32
L21:
  mov    $0x4,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <hash@plt>
  cmp    %ebp,%r13d
  jge    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

assistant: ```c
void test(int M, int N) {
  int i, j;
  for (i = 0; i <= M; i++) {
    {
      hash(1);
      hash(i);
    };
    for (j = 0; j <= N; j++) {
      {
        hash(2);
        hash(i);
        hash(j);
      };
      {
        hash(3);
        hash(i);
        hash(j);
      };
    }
    {
      hash(4);
      hash(i);
    };
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  test   %edi,%edi
  js     L30
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L10:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  test   %r12d,%r12d
  js     L23
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L39
L23:
  mov    $0x4,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <hash@plt>
  cmp    %ebp,%r13d
  jge    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  ret
```

assistant: ```c
void test(int M, int N) {
  int i, j;
  for (i = 0; i <= M; i++) {
    {
      hash(1);
      hash(i);
    };
    for (j = 0; j <= N; j++) {
      {
        hash(2);
        hash(i);
        hash(j);
      };
      {
        hash(3);
        hash(i);
        hash(j);
      };
    }
    {
      hash(4);
      hash(i);
    };
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  cmp    $0x2,%eax
  je     L32
  mov    $0x1,%eax
  jmp    L100
L32:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  cmp    $0x3,%eax
  je     L17
  mov    $0x2,%eax
  jmp    L100
L17:
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  cmp    $0x3,%eax
  je     L73
  mov    $0x1,%eax
  jmp    L100
L73:
  mov    -0x18(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  cmp    $0x2,%eax
  je     L39
  mov    $0x2,%eax
  jmp    L100
L39:
  lea    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  addq   $0x4,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  je     L48
  mov    $0x1,%eax
  jmp    L100
L48:
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  subq   $0x4,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  je     L60
  mov    $0x1,%eax
  jmp    L100
L60:
  mov    $0x0,%eax
L100:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[2];
  int *p;
  arr[0] = 2;
  arr[1] = 3;
  p = &arr[0];
  if (*(p++) != 2)
    return 1;
  if (*(p++) != 3)
    return 2;
  p = &arr[1];
  if (*(p--) != 3)
    return 1;
  if (*(p--) != 2)
    return 2;
  p = &arr[0];
  if (*(++p) != 3)
    return 1;
  p = &arr[1];
  if (*(--p) != 2)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int arr[2];
  int *p;
  arr[0] = 2;
  arr[1] = 3;
  p = &arr[0];
  if (*(p++) != 2)
    return 1;
  if (*(p++) != 3)
    return 2;
  p = &arr[1];
  if (*(p--) != 3)
    return 1;
  if (*(p--) != 2)
    return 2;
  p = &arr[0];
  if (*(++p) != 3)
    return 1;
  p = &arr[1];
  if (*(--p) != 2)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int arr[2];
  int *p;
  arr[0] = 2;
  arr[1] = 3;
  p = &arr[0];
  if (*(p++) != 2)
    return 1;
  if (*(p++) != 3)
    return 2;
  p = &arr[1];
  if (*(p--) != 3)
    return 1;
  if (*(p--) != 2)
    return 2;
  p = &arr[0];
  if (*(++p) != 3)
    return 1;
  p = &arr[1];
  if (*(--p) != 2)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int arr[2];
  int *p;
  arr[0] = 2;
  arr[1] = 3;
  p = &arr[0];
  if (*(p++) != 2)
    return 1;
  if (*(p++) != 3)
    return 2;
  p = &arr[1];
  if (*(p--) != 3)
    return 1;
  if (*(p--) != 2)
    return 2;
  p = &arr[0];
  if (*(++p) != 3)
    return 1;
  p = &arr[1];
  if (*(--p) != 2)
    return 1;
  return 0;
}
```