user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x17,%ecx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0xc(%rsp),%rsi
  rep stos %rax,%es:(%rdi)
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movapd D3(%rip),%xmm0
  mov    0xc(%rsp),%ebp
  movaps %xmm0,0x10(%rsp)
  cmp    $0x1,%ebp
  jle    L19
  movsd  D3(%rip),%xmm0
  lea    0x1(%rbp),%ecx
  mov    $0x3,%edx
  mov    $0x2,%eax
  lea    0x10(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L138:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  add    $0x2,%edx
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L138
L19:
  movsd  D26(%rip),%xmm4
  lea    -0x2(%rbp),%edi
  movsd  %xmm4,0x10(%rsp)
  test   %edi,%edi
  jle    L54
  mov    $0x5,%r10d
  mov    $0x2,%r9d
  lea    0x18(%rsp),%rbx
  mov    $0x1,%r11d
  nopl   0x0(%rax)
L24:
  mov    %r11d,%r8d
  movsd  0x10(%rsp),%xmm2
  mov    %rbx,%rdx
  mov    %r10d,%ecx
  mov    %r9d,%eax
  sub    %r9d,%r8d
  nopl   (%rax)
L37:
  pxor   %xmm1,%xmm1
  mov    %eax,%esi
  pxor   %xmm0,%xmm0
  add    $0x1,%eax
  cvtsi2sd %ecx,%xmm1
  neg    %esi
  pxor   %xmm3,%xmm3
  add    $0x8,%rdx
  cvtsi2sd %esi,%xmm0
  mulsd  -0x8(%rdx),%xmm0
  lea    (%r8,%rax,1),%esi
  add    $0x2,%ecx
  cvtsi2sd %eax,%xmm3
  mulsd  %xmm2,%xmm1
  divsd  %xmm3,%xmm0
  divsd  %xmm3,%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,-0x8(%rdx)
  cmp    %esi,%edi
  jge    L37
  add    $0x2,%r9d
  mov    %r11d,%eax
  pxor   %xmm0,%xmm0
  sub    $0x2,%edi
  sub    %r9d,%eax
  add    $0x4,%r10d
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  divsd  %xmm0,%xmm4
  movsd  %xmm4,0x10(%rsp)
  test   %edi,%edi
  jg     L24
L54:
  mov    %ebp,%edx
  shr    $0x1f,%edx
  lea    0x0(%rbp,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L16
L76:
  test   $0x1,%bpl
  jne    L127
  test   %ebp,%ebp
  je     L73
  js     L127
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  lea    D35(%rip),%r12
  lea    D63(%rip),%r13
  jmp    L129
  xchg   %ax,%ax
L119:
  mov    %r13,%rdi
  add    $0x2,%rbp
  call   <puts@plt>
  cmp    %ebp,0xc(%rsp)
  jl     L127
L129:
  movsd  (%rbx,%rbp,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jne    L119
  nopw   0x0(%rax,%rax,1)
L127:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  test   %ebp,%ebp
  jle    L76
  mov    $0x1,%ebp
  lea    0x10(%rsp),%rbx
  lea    D79(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L87:
  movsd  (%rbx,%rbp,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x2,%rbp
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jge    L87
  mov    0xc(%rsp),%ebp
  jmp    L76
L73:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  jmp    L127
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D3
type_infered: f64[2]
name: retrieve_data
arguments: data_tag: D26
type_infered: f32[2]
name: retrieve_data
arguments: data_tag: D35
type_infered: string
name: retrieve_data
arguments: data_tag: D63
type_infered: string
name: retrieve_data
arguments: data_tag: D79
type_infered: string
name: retrieve_data
arguments: data_tag: D43
type_infered: string

tool: D15: %d

tool: {"D3": [1.0,1.0]}

tool: {"D26": [0.0,-1.75]}

tool: D35: %.2lf


tool: D63: 0.00

tool: D79: 0.00
%.2lf


tool: D43: 1.00

assistant: ```c
int main() {
  int order, i, ordern, j;
  double x[25] = {0.0};
  scanf("%d", &order);
  x[0] = 1.0;
  x[1] = 1.0;
  for (i = 2; i <= order; i++) {
    x[i] = (2 * i - 1) * x[i - 1] / i;
  }
  for (ordern = 2; 1 == 1; ordern += 2) {
    x[0] = x[0] * (-(ordern - 1)) / (ordern);
    if ((order - ordern) <= 0)
      break;
    for (i = 1, j = ordern; i <= (order - ordern); i++, j++) {
      x[i] = x[i] * (-(j)) / (j + 1) + (2 * (j) + 1) * x[i - 1] / (j + 1);
    }
  }
  if (order % 2 == 1) {
    for (i = 1; i <= order; i += 2) {
      printf("0.00\n%.2lf\n", x[i]);
    }
  }
  if (order % 2 == 0) {
    if (order == 0) {
      printf("1.00\n");
    } else {
      for (i = 0; i <= order; i += 2) {
        printf("%.2lf\n", x[i]);
        if (i == order)
          break;
        printf("0.00\n");
      }
    }
  }
}
```