ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<quoted_string>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  lea    D7(%rip),%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <match@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  je     L116
  test   %r13,%r13
  je     L53
  xor    %eax,%eax
  call   <data_segment_gdata@plt>
  xor    %eax,%eax
  call   <getlabel@plt>
  mov    %eax,0x0(%r13)
  mov    %eax,%edi
  call   <generate_label@plt>
L53:
  xor    %ebp,%ebp
  jmp    L26
  nopl   0x0(%rax)
L91:
  xor    %eax,%eax
  mov    $0x1,%ebp
  call   <gen_def_byte@plt>
  movsbl %bl,%edi
  call   <output_number@plt>
L94:
  add    $0x1,%r12d
L26:
  xor    %eax,%eax
  call   <ch@plt>
  cmp    $0x22,%al
  je     L118
  xor    %eax,%eax
  call   <ch@plt>
  test   %al,%al
  je     L118
  xor    %eax,%eax
  call   <gch@plt>
  mov    %eax,%ebx
  cmp    $0x5c,%al
  je     L64
L55:
  test   %ebp,%ebp
  je     L91
  mov    $0x2c,%edi
  call   <output_byte@plt>
  movsbl %bl,%edi
  call   <output_number@plt>
  cmp    $0x7,%ebp
  je     L80
  add    $0x1,%ebp
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  call   <spechar@plt>
  mov    %eax,%ebx
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L80:
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <newline@plt>
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L118:
  xor    %eax,%eax
  call   <gch@plt>
  test   %ebp,%ebp
  jne    L115
L145:
  xor    %eax,%eax
  call   <gen_def_byte@plt>
  xor    %edi,%edi
  call   <output_number@plt>
  xor    %eax,%eax
  call   <newline@plt>
  test   %r14,%r14
  je     L11
  add    $0x1,%r12d
  mov    %r12d,(%r14)
L11:
  mov    $0x1,%r15d
  test   %r13,%r13
  je     L116
  xor    %eax,%eax
  call   <code_segment_gtext@plt>
L116:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L115:
  xor    %eax,%eax
  call   <newline@plt>
  jmp    L145
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: "

assistant: ```c
int quoted_string(int *len, int *position) {
  char c;
  int x;
  int l;
  if (!match("\""))
    return (0);
  if (position) {
    data_segment_gdata();
    *position = getlabel();
    generate_label(*position);
  }
  x = 0;
  while (ch() != '"') {
    if (ch() == 0) {
      break;
    }
    c = gch();
    c = (c == '\\') ? spechar() : c;
    if (x == 0)
      gen_def_byte();
    else
      output_byte(',');
    output_number(c);
    if (x++ == 7) {
      x = 0;
      newline();
    }
    l++;
  }
  gch();
  if (x != 0)
    newline();
  gen_def_byte();
  output_number(0);
  newline();
  if (len)
    *len = l + 1;
  if (position)
    code_segment_gtext();
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetFileEndPos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell_err@plt>
  mov    %rax,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell_err@plt>
  mov    %rax,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fseek_err@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long GetFileEndPos(FILE *fp) {
  unsigned long originalpos, endpos;
  (assert(fp != NULL));
  originalpos = ftell_err(fp);
  (void)fseek(fp, 0, SEEK_END);
  endpos = ftell_err(fp);
  fseek_err(fp, originalpos, SEEK_SET);
  return endpos;
}
```
user: What is the c source code of the assembly code below?

```asm
<GetFileEndPos>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <ftell_err@plt>
  mov    %rax,%r12
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbx,%rdi
  call   <ftell_err@plt>
  mov    %rax,%rbp
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fseek_err@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long GetFileEndPos(FILE *fp) {
  unsigned long originalpos, endpos;
  (assert(fp != NULL));
  originalpos = ftell_err(fp);
  (void)fseek(fp, 0, SEEK_END);
  endpos = ftell_err(fp);
  fseek_err(fp, originalpos, SEEK_SET);
  return endpos;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetFileEndPos>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <ftell_err@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell_err@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  call   <fseek_err@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long GetFileEndPos(FILE *fp) {
  unsigned long originalpos, endpos;
  (assert(fp != NULL));
  originalpos = ftell_err(fp);
  (void)fseek(fp, 0, SEEK_END);
  endpos = ftell_err(fp);
  fseek_err(fp, originalpos, SEEK_SET);
  return endpos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetFileEndPos>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <ftell_err@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell_err@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  call   <fseek_err@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long GetFileEndPos(FILE *fp) {
  unsigned long originalpos, endpos;
  (assert(fp != NULL));
  originalpos = ftell_err(fp);
  (void)fseek(fp, 0, SEEK_END);
  endpos = ftell_err(fp);
  fseek_err(fp, originalpos, SEEK_SET);
  return endpos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L7:
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L52:
  movl   $0x1,-0x8(%rbp)
  jmp    L19
L45:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <invert@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x7,-0x8(%rbp)
  jle    L45
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x7,-0xc(%rbp)
  jle    L52
  addl   $0x31,-0x10(%rbp)
L18:
  cmpl   $0x2bb,-0x10(%rbp)
  jbe    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: invert(%u,%d,%d)=%u


assistant: ```c
int main() {
  unsigned x, k;
  int p, n;
  for (x = 0; x < 700; x += 49) {
    for (p = 1; p < 8; p++) {
      for (n = 1; n < 8; n++) {
        k = invert(x, p, n);
        printf("invert(%u,%d,%d)=%u\n", x, p, n, k);
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  lea    D2(%rip),%r13
  jmp    L32
L44:
  add    $0x31,%r12d
  cmp    $0x2df,%r12d
  je     L46
L32:
  mov    $0x1,%ebp
L38:
  mov    $0x1,%ebx
L19:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <invert@plt>
  mov    %eax,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L19
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L38
  jmp    L44
L46:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: invert(%u,%d,%d)=%u


assistant: ```c
int main() {
  unsigned x, k;
  int p, n;
  for (x = 0; x < 700; x += 49) {
    for (p = 1; p < 8; p++) {
      for (n = 1; n < 8; n++) {
        k = invert(x, p, n);
        printf("invert(%u,%d,%d)=%u\n", x, p, n, k);
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%ebp
  nopl   (%rax)
L22:
  mov    $0x1,%ebx
  nopl   (%rax)
L19:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <invert@plt>
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %eax,%r8d
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x8,%ebx
  jne    L19
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L22
  add    $0x31,%r12d
  cmp    $0x2df,%r12d
  jne    L20
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: invert(%u,%d,%d)=%u


assistant: ```c
int main() {
  unsigned x, k;
  int p, n;
  for (x = 0; x < 700; x += 49) {
    for (p = 1; p < 8; p++) {
      for (n = 1; n < 8; n++) {
        k = invert(x, p, n);
        printf("invert(%u,%d,%d)=%u\n", x, p, n, k);
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%ebp
  nopl   (%rax)
L19:
  mov    $0x1,%ebx
  nopl   (%rax)
L8:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <invert@plt>
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %eax,%r8d
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x8,%ebx
  jne    L8
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L19
  add    $0x31,%r12d
  cmp    $0x2df,%r12d
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: invert(%u,%d,%d)=%u


assistant: ```c
int main() {
  unsigned x, k;
  int p, n;
  for (x = 0; x < 700; x += 49) {
    for (p = 1; p < 8; p++) {
      for (n = 1; n < 8; n++) {
        k = invert(x, p, n);
        printf("invert(%u,%d,%d)=%u\n", x, p, n, k);
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L45
L6:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L22
  mov    -0x4(%rbp),%eax
  jmp    L36
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L15
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L45
L15:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L6
  mov    $0xffffffff,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search(int *arr, int num, int key) {
  int mid, high = num - 1, low = 0;
  while (low <= high) {
    mid = (high + low) / 2;
    if (arr[mid] == key)
      return mid;
    else if (arr[mid] > key)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%esi
  js     L66
  mov    $0x0,%r8d
  jmp    L44
L68:
  lea    0x1(%rax),%r8d
L54:
  cmp    %r8d,%esi
  jl     L21
L44:
  lea    (%rsi,%r8,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L40
  jle    L68
  lea    -0x1(%rax),%esi
  jmp    L54
L21:
  mov    $0xffffffff,%r9d
L40:
  mov    %r9d,%eax
  ret
L66:
  mov    $0xffffffff,%r9d
  jmp    L40
```

assistant: ```c
int binary_search(int *arr, int num, int key) {
  int mid, high = num - 1, low = 0;
  while (low <= high) {
    mid = (high + low) / 2;
    if (arr[mid] == key)
      return mid;
    else if (arr[mid] > key)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%esi
  js     L46
  xor    %ecx,%ecx
  jmp    L12
  nopl   (%rax)
L33:
  lea    -0x1(%rax),%esi
  cmp    %esi,%ecx
  jg     L46
L12:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L5
  jg     L33
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L12
L46:
  mov    $0xffffffff,%eax
L5:
  ret
```

assistant: ```c
int binary_search(int *arr, int num, int key) {
  int mid, high = num - 1, low = 0;
  while (low <= high) {
    mid = (high + low) / 2;
    if (arr[mid] == key)
      return mid;
    else if (arr[mid] > key)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%esi
  js     L48
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L57:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L2
  jle    L49
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L57
L48:
  mov    $0xffffffff,%eax
L2:
  ret
  nopl   (%rax)
L49:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L57
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int binary_search(int *arr, int num, int key) {
  int mid, high = num - 1, low = 0;
  while (low <= high) {
    mid = (high + low) / 2;
    if (arr[mid] == key)
      return mid;
    else if (arr[mid] > key)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cocktail_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movb   $0x1,-0xd(%rbp)
  jmp    L23
L75:
  movb   $0x0,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L38
L57:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L66
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movb   $0x1,-0xd(%rbp)
L66:
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L57
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L58
L74:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L14
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movb   $0x1,-0xd(%rbp)
L14:
  subl   $0x1,-0xc(%rbp)
L58:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L74
  addl   $0x1,-0x8(%rbp)
L23:
  cmpb   $0x0,-0xd(%rbp)
  jne    L75
  nop
  nop
  leave
  ret
```

assistant: ```c
void cocktail_sort(int arr[], int n) {
  int i, front = 0, rear = n - 1;
  char swapped = 1;
  while (swapped) {
    swapped = 0;
    for (i = front; i < rear; ++i) {
      if (arr[i] > arr[i + 1]) {
        swap(arr + i, arr + i + 1);
        swapped = 1;
      }
    }
    --rear;
    for (i = rear; i > front; --i) {
      if (arr[i - 1] > arr[i]) {
        swap(arr + i - 1, arr + i);
        swapped = 1;
      }
    }
    ++front;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cocktail_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  lea    -0x2(%rsi),%r13d
  mov    %r13d,0x4(%rsp)
  mov    $0x0,%r12d
  lea    0x4(%rdi),%rax
  mov    %rax,0x8(%rsp)
  jmp    L124
L18:
  cmp    %rbx,%r15
  je     L113
L1:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  mov    0x4(%rdi),%ecx
  cmp    %ecx,(%rdi)
  jle    L18
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    $0x1,%eax
  jmp    L18
L113:
  mov    %r13d,%r15d
  cmp    %ebp,%r13d
  jle    L91
L134:
  movslq %r15d,%rdx
  lea    (%r14,%rdx,4),%rbx
  jmp    L61
L128:
  sub    $0x1,%r15d
  sub    $0x4,%rbx
  cmp    %ebp,%r15d
  jle    L91
L61:
  lea    -0x4(%rbx),%rdi
  mov    (%rbx),%edx
  cmp    %edx,-0x4(%rbx)
  jle    L128
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    $0x1,%eax
  jmp    L128
L91:
  add    $0x1,%r12
  sub    $0x1,%r13d
  subl   $0x2,0x4(%rsp)
  test   %al,%al
  je     L94
L124:
  mov    %r12d,%ebp
  lea    0x1(%r13),%eax
  cmp    %eax,%r12d
  jge    L100
  lea    (%r14,%r12,4),%rbx
  mov    0x4(%rsp),%eax
  add    %r12,%rax
  mov    0x8(%rsp),%rsi
  lea    (%rsi,%rax,4),%r15
  mov    $0x0,%eax
  jmp    L1
L100:
  mov    %r13d,%r15d
  cmp    %r12d,%r13d
  jle    L94
  mov    $0x0,%eax
  jmp    L134
L94:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cocktail_sort(int arr[], int n) {
  int i, front = 0, rear = n - 1;
  char swapped = 1;
  while (swapped) {
    swapped = 0;
    for (i = front; i < rear; ++i) {
      if (arr[i] > arr[i + 1]) {
        swap(arr + i, arr + i + 1);
        swapped = 1;
      }
    }
    --rear;
    for (i = rear; i > front; --i) {
      if (arr[i - 1] > arr[i]) {
        swap(arr + i - 1, arr + i);
        swapped = 1;
      }
    }
    ++front;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cocktail_sort>:
  endbr64
  push   %r15
  xor    %edx,%edx
  lea    -0x1(%rsi),%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    -0x8(%rdi),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   (%rax)
L53:
  add    $0x1,%ebx
L7:
  cmp    %r15d,%ebx
  jge    L30
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdi
  lea    0x4(%r14,%rax,1),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jle    L53
  call   <swap@plt>
  mov    $0x1,%edx
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L30:
  lea    -0x1(%r15),%r13d
  cmp    %ebp,%r13d
  jle    L77
  movslq %r13d,%rax
  sub    $0x2,%r15d
  shl    $0x2,%rax
  sub    %ebp,%r15d
  lea    0x0(,%r15,4),%rcx
  lea    (%r14,%rax,1),%rbx
  lea    0x4(%r12,%rax,1),%rax
  sub    %rcx,%rax
  mov    %rax,%r15
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L107:
  cmp    %rbx,%r15
  je     L77
L5:
  mov    %rbx,%rsi
  sub    $0x4,%rbx
  mov    (%rsi),%eax
  cmp    %eax,-0x4(%rsi)
  jle    L107
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    $0x1,%edx
  cmp    %rbx,%r15
  jne    L5
L77:
  lea    0x1(%rbp),%ebx
  test   %dl,%dl
  je     L74
  mov    %r13d,%r15d
  mov    %ebx,%ebp
  xor    %edx,%edx
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L74:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cocktail_sort(int arr[], int n) {
  int i, front = 0, rear = n - 1;
  char swapped = 1;
  while (swapped) {
    swapped = 0;
    for (i = front; i < rear; ++i) {
      if (arr[i] > arr[i + 1]) {
        swap(arr + i, arr + i + 1);
        swapped = 1;
      }
    }
    --rear;
    for (i = rear; i > front; --i) {
      if (arr[i - 1] > arr[i]) {
        swap(arr + i - 1, arr + i);
        swapped = 1;
      }
    }
    ++front;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cocktail_sort>:
  endbr64
  push   %r15
  xor    %edx,%edx
  lea    -0x1(%rsi),%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    -0x8(%rdi),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L98
  nopl   (%rax)
L31:
  add    $0x1,%ebx
L98:
  cmp    %r15d,%ebx
  jge    L62
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdi
  lea    0x4(%r14,%rax,1),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jle    L31
  call   <swap@plt>
  mov    $0x1,%edx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L62:
  lea    -0x1(%r15),%r13d
  cmp    %r13d,%ebp
  jge    L5
  movslq %r13d,%rax
  sub    $0x2,%r15d
  shl    $0x2,%rax
  sub    %ebp,%r15d
  lea    0x0(,%r15,4),%rcx
  lea    (%r14,%rax,1),%rbx
  lea    0x4(%r12,%rax,1),%rax
  sub    %rcx,%rax
  mov    %rax,%r15
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %r15,%rbx
  je     L5
L73:
  mov    %rbx,%rsi
  sub    $0x4,%rbx
  mov    (%rsi),%eax
  cmp    %eax,-0x4(%rsi)
  jle    L0
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    $0x1,%edx
  cmp    %r15,%rbx
  jne    L73
L5:
  lea    0x1(%rbp),%ebx
  test   %dl,%dl
  je     L57
  mov    %r13d,%r15d
  mov    %ebx,%ebp
  xor    %edx,%edx
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L57:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cocktail_sort(int arr[], int n) {
  int i, front = 0, rear = n - 1;
  char swapped = 1;
  while (swapped) {
    swapped = 0;
    for (i = front; i < rear; ++i) {
      if (arr[i] > arr[i + 1]) {
        swap(arr + i, arr + i + 1);
        swapped = 1;
      }
    }
    --rear;
    for (i = rear; i > front; --i) {
      if (arr[i - 1] > arr[i]) {
        swap(arr + i - 1, arr + i);
        swapped = 1;
      }
    }
    ++front;
  }
}
```