ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qEmpty>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: Queue is empty


assistant: ```c
void qEmpty() {
  printf("Queue is empty\n");
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qEmpty>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: Queue is empty


assistant: ```c
void qEmpty() {
  printf("Queue is empty\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  test   %rax,%rax
  jns    L2
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L2:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string

tool: D17: time

tool: D15: %ld


assistant: ```c
int main(void) {
  time_t current_time;
  if (time(&current_time) < 0) {
    perror("time");
  }
  printf("%ld\n", current_time);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  test   %rax,%rax
  js     L11
L9:
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L11:
  lea    D12(%rip),%rdi
  call   <perror@plt>
  jmp    L9
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D12
type: string

tool: D8: %ld


tool: D12: time

assistant: ```c
int main(void) {
  time_t current_time;
  if (time(&current_time) < 0) {
    perror("time");
  }
  printf("%ld\n", current_time);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  test   %rax,%rax
  js     L2
L22:
  mov    0x4(%rsp),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  jmp    L22
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D14: %ld


tool: D4: time

assistant: ```c
int main(void) {
  time_t current_time;
  if (time(&current_time) < 0) {
    perror("time");
  }
  printf("%ld\n", current_time);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  test   %rax,%rax
  js     L28
L23:
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L28:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L23
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D4: %ld


tool: D6: time

assistant: ```c
int main(void) {
  time_t current_time;
  if (time(&current_time) < 0) {
    perror("time");
  }
  printf("%ld\n", current_time);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <fatorialQuadruplo@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: O fatorial quaduplo de 5: %d

assistant: ```c
int main() {
  printf("O fatorial quaduplo de 5: %d", fatorialQuadruplo(5));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorialQuadruplo@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: O fatorial quaduplo de 5: %d

assistant: ```c
int main() {
  printf("O fatorial quaduplo de 5: %d", fatorialQuadruplo(5));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorialQuadruplo@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: O fatorial quaduplo de 5: %d

assistant: ```c
int main() {
  printf("O fatorial quaduplo de 5: %d", fatorialQuadruplo(5));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorialQuadruplo@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: O fatorial quaduplo de 5: %d

assistant: ```c
int main() {
  printf("O fatorial quaduplo de 5: %d", fatorialQuadruplo(5));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GetLcm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Sub1@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int GetLcm(int sz[], int len) {
  int i = 0;
  int re = 1;
  for (i = 0; i < len; ++i) {
    re = Sub1(sz[i], re);
  }
  return re;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetLcm>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
  mov    $0x1,%esi
L0:
  mov    (%rbx),%edi
  call   <Sub1@plt>
  mov    %eax,%esi
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x1,%esi
  mov    %esi,%eax
  ret
```

assistant: ```c
int GetLcm(int sz[], int len) {
  int i = 0;
  int re = 1;
  for (i = 0; i < len; ++i) {
    re = Sub1(sz[i], re);
  }
  return re;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetLcm>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %rbp
  lea    -0x1(%rsi),%eax
  mov    $0x1,%esi
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L3:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <Sub1@plt>
  mov    %eax,%esi
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int GetLcm(int sz[], int len) {
  int i = 0;
  int re = 1;
  for (i = 0; i < len; ++i) {
    re = Sub1(sz[i], re);
  }
  return re;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GetLcm>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %rbp
  lea    -0x1(%rsi),%eax
  mov    $0x1,%esi
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L0:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <Sub1@plt>
  mov    %eax,%esi
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int GetLcm(int sz[], int len) {
  int i = 0;
  int re = 1;
  for (i = 0; i < len; ++i) {
    re = Sub1(sz[i], re);
  }
  return re;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<at_tok_nextint_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L100
  mov    $0xffffffff,%eax
  jmp    L63
L100:
  cmpq   $0x0,-0x30(%rbp)
  jne    L42
  mov    $0xffffffff,%eax
  jmp    L63
L42:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <nextTok@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L63
L14:
  cmpl   $0x0,-0x38(%rbp)
  je     L55
  mov    -0x34(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L86
L55:
  mov    -0x34(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x18(%rbp)
L86:
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L93
  mov    $0xffffffff,%eax
  jmp    L63
L93:
  mov    $0x0,%eax
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

assistant: ```c
int at_tok_nextint_base(char **p_cur, int *p_out, int base, int uns) {
  char *ret;
  if (*p_cur == NULL)
    return -1;
  if (p_out == NULL)
    return -1;
  ret = nextTok(p_cur);
  if (ret == NULL)
    return -1;
  else {
    long l;
    char *end;
    if (uns)
      l = strtoul(ret, &end, base);
    else
      l = strtol(ret, &end, base);
    *p_out = (int)l;
    if (end == ret)
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<at_tok_nextint_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L10
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %ecx,%r12d
  test   %rsi,%rsi
  je     L10
  call   <nextTok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L66
  test   %r12d,%r12d
  je     L22
  mov    %rsp,%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  call   <strtoul@plt>
L67:
  mov    %eax,0x0(%rbp)
  cmp    %rbx,(%rsp)
  setne  %al
  movzbl %al,%eax
  sub    $0x1,%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    %rsp,%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  call   <strtol@plt>
  jmp    L67
L10:
  mov    $0xffffffff,%eax
  jmp    L26
L66:
  mov    $0xffffffff,%eax
  jmp    L26
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int at_tok_nextint_base(char **p_cur, int *p_out, int base, int uns) {
  char *ret;
  if (*p_cur == NULL)
    return -1;
  if (p_out == NULL)
    return -1;
  ret = nextTok(p_cur);
  if (ret == NULL)
    return -1;
  else {
    long l;
    char *end;
    if (uns)
      l = strtoul(ret, &end, base);
    else
      l = strtol(ret, &end, base);
    *p_out = (int)l;
    if (end == ret)
      return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<at_tok_nextint_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L66
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L66
  mov    %edx,%r12d
  mov    %ecx,%r13d
  call   <nextTok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L66
  mov    %rsp,%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  test   %r13d,%r13d
  jne    L28
  call   <strtol@plt>
L23:
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  cmp    %rbx,(%rsp)
  setne  %al
  sub    $0x1,%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  call   <strtoul@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L66:
  mov    $0xffffffff,%eax
  jmp    L22
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int at_tok_nextint_base(char **p_cur, int *p_out, int base, int uns) {
  char *ret;
  if (*p_cur == NULL)
    return -1;
  if (p_out == NULL)
    return -1;
  ret = nextTok(p_cur);
  if (ret == NULL)
    return -1;
  else {
    long l;
    char *end;
    if (uns)
      l = strtoul(ret, &end, base);
    else
      l = strtol(ret, &end, base);
    *p_out = (int)l;
    if (end == ret)
      return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<at_tok_nextint_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L39
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L39
  mov    %edx,%r12d
  mov    %ecx,%r13d
  call   <nextTok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  mov    %rsp,%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  test   %r13d,%r13d
  jne    L27
  call   <strtol@plt>
L43:
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  cmp    %rbx,(%rsp)
  setne  %al
  sub    $0x1,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  call   <strtoul@plt>
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%eax
  jmp    L34
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int at_tok_nextint_base(char **p_cur, int *p_out, int base, int uns) {
  char *ret;
  if (*p_cur == NULL)
    return -1;
  if (p_out == NULL)
    return -1;
  ret = nextTok(p_cur);
  if (ret == NULL)
    return -1;
  else {
    long l;
    char *end;
    if (uns)
      l = strtoul(ret, &end, base);
    else
      l = strtol(ret, &end, base);
    *p_out = (int)l;
    if (end == ret)
      return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<upsample_cpu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,-0x24(%rsp)
  mov    %r8d,-0x4(%rsp)
  mov    0x38(%rsp),%r11d
  mov    0x40(%rsp),%r13
  test   %r8d,%r8d
  jle    L109
  mov    %rdi,%r10
  mov    %esi,%r14d
  mov    %edx,%eax
  mov    %r9d,%esi
  movaps %xmm0,%xmm1
  mov    %edx,%r15d
  imul   %r9d,%r15d
  mov    %r9d,%r12d
  imul   %r14d,%r12d
  mov    %r9d,%edx
  imul   %r9d,%edx
  imul   %r14d,%edx
  mov    %edx,%ebx
  imul   %eax,%ebx
  mov    %ebx,-0x20(%rsp)
  imul   %ecx,%ebx
  mov    %ebx,-0xc(%rsp)
  imul   %r14d,%eax
  mov    %eax,-0x1c(%rsp)
  imul   %eax,%ecx
  mov    %ecx,-0x8(%rsp)
  movl   $0x0,-0x10(%rsp)
  movl   $0x0,-0x14(%rsp)
  movl   $0x0,-0x18(%rsp)
  mov    %r12d,%r9d
  jmp    L136
L125:
  cltq
  lea    (%r10,%rax,4),%rax
  movaps %xmm1,%xmm0
  mulss  (%r8,%rcx,4),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
L107:
  add    $0x1,%rcx
  cmp    %rcx,%r9
  je     L56
L94:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  add    %edi,%eax
  test   %r11d,%r11d
  je     L125
  cltq
  movaps %xmm1,%xmm0
  mulss  (%r10,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rcx,4)
  jmp    L107
L56:
  add    $0x1,%ebx
  add    %r12d,%ebp
  cmp    %r15d,%ebx
  je     L104
L60:
  test   %r12d,%r12d
  jle    L56
  mov    %ebx,%eax
  cltd
  idiv   %esi
  imul   %r14d,%eax
  mov    -0x34(%rsp),%edx
  lea    (%rax,%rdx,1),%edi
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%r8
  mov    $0x0,%ecx
  jmp    L94
L104:
  addl   $0x1,-0x30(%rsp)
  mov    -0x30(%rsp),%eax
  mov    -0x20(%rsp),%edi
  add    %edi,-0x2c(%rsp)
  mov    -0x1c(%rsp),%edx
  add    %edx,-0x28(%rsp)
  cmp    %eax,-0x24(%rsp)
  je     L127
L96:
  test   %r15d,%r15d
  jle    L104
  mov    -0x28(%rsp),%eax
  mov    %eax,-0x34(%rsp)
  mov    -0x2c(%rsp),%ebp
  mov    $0x0,%ebx
  jmp    L60
L127:
  addl   $0x1,-0x18(%rsp)
  mov    -0x18(%rsp),%eax
  mov    -0xc(%rsp),%edi
  add    %edi,-0x14(%rsp)
  mov    -0x8(%rsp),%edi
  add    %edi,-0x10(%rsp)
  cmp    %eax,-0x4(%rsp)
  je     L109
L136:
  mov    -0x10(%rsp),%eax
  mov    %eax,-0x28(%rsp)
  mov    -0x14(%rsp),%eax
  mov    %eax,-0x2c(%rsp)
  movl   $0x0,-0x30(%rsp)
  cmpl   $0x0,-0x24(%rsp)
  jg     L96
  jmp    L127
L109:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void upsample_cpu(float *in, int w, int h, int c, int batch, int stride, int forward, float scale, float *out) {
  int i, j, k, b;
  for (b = 0; b < batch; ++b) {
    for (k = 0; k < c; ++k) {
      for (j = 0; j < h * stride; ++j) {
        for (i = 0; i < w * stride; ++i) {
          int in_index = b * w * h * c + k * w * h + (j / stride) * w + i / stride;
          int out_index = b * w * h * c * stride * stride + k * w * h * stride * stride + j * w * stride + i;
          if (forward)
            out[out_index] = scale * in[in_index];
          else
            in[in_index] += scale * out[out_index];
        }
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<upsample_cpu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11d
  mov    0x40(%rsp),%r15
  mov    %esi,-0x30(%rsp)
  mov    %ecx,-0x24(%rsp)
  mov    %r8d,-0x4(%rsp)
  test   %r8d,%r8d
  jle    L90
  mov    %edx,%eax
  mov    %edx,%r14d
  mov    %r9d,%edx
  mov    %esi,%ebx
  imul   %r9d,%edx
  mov    %ebx,%r12d
  mov    %r9d,%esi
  mov    %rdi,%r10
  imul   %r9d,%r12d
  movl   $0x0,-0x10(%rsp)
  movaps %xmm0,%xmm2
  movl   $0x0,-0x14(%rsp)
  imul   %r9d,%r14d
  imul   %ebx,%edx
  movl   $0x0,-0x18(%rsp)
  mov    %r12d,%r9d
  imul   %eax,%edx
  imul   %ebx,%eax
  mov    %edx,-0x20(%rsp)
  imul   %ecx,%edx
  mov    %eax,-0x1c(%rsp)
  imul   %ecx,%eax
  mov    %edx,-0x8(%rsp)
  mov    %eax,-0xc(%rsp)
L105:
  mov    -0x14(%rsp),%eax
  movl   $0x0,-0x2c(%rsp)
  mov    -0x10(%rsp),%r13d
  mov    %eax,-0x28(%rsp)
  mov    -0x24(%rsp),%eax
  test   %eax,%eax
  jle    L92
  nopl   0x0(%rax,%rax,1)
L38:
  test   %r14d,%r14d
  jle    L74
  mov    -0x28(%rsp),%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L28:
  test   %r12d,%r12d
  jle    L1
  mov    %ebx,%eax
  xor    %ecx,%ecx
  cltd
  idiv   %esi
  imul   -0x30(%rsp),%eax
  lea    (%rax,%r13,1),%edi
  movslq %ebp,%rax
  lea    (%r15,%rax,4),%r8
  jmp    L63
  xchg   %ax,%ax
L37:
  mulss  %xmm2,%xmm0
  movss  %xmm0,(%r8,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  je     L1
L63:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  add    %edi,%eax
  cltq
  lea    (%r10,%rax,4),%rax
  movss  (%rax),%xmm0
  test   %r11d,%r11d
  jne    L37
  movss  (%r8,%rcx,4),%xmm1
  add    $0x1,%rcx
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  cmp    %rcx,%r9
  jne    L63
L1:
  add    $0x1,%ebx
  add    %r12d,%ebp
  cmp    %r14d,%ebx
  jne    L28
L74:
  addl   $0x1,-0x2c(%rsp)
  mov    -0x20(%rsp),%edi
  mov    -0x2c(%rsp),%eax
  add    %edi,-0x28(%rsp)
  add    -0x1c(%rsp),%r13d
  cmp    %eax,-0x24(%rsp)
  jne    L38
L92:
  mov    -0x8(%rsp),%edx
  addl   $0x1,-0x18(%rsp)
  add    %edx,-0x14(%rsp)
  mov    -0x18(%rsp),%eax
  mov    -0xc(%rsp),%edx
  add    %edx,-0x10(%rsp)
  cmp    %eax,-0x4(%rsp)
  jne    L105
L90:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void upsample_cpu(float *in, int w, int h, int c, int batch, int stride, int forward, float scale, float *out) {
  int i, j, k, b;
  for (b = 0; b < batch; ++b) {
    for (k = 0; k < c; ++k) {
      for (j = 0; j < h * stride; ++j) {
        for (i = 0; i < w * stride; ++i) {
          int in_index = b * w * h * c + k * w * h + (j / stride) * w + i / stride;
          int out_index = b * w * h * c * stride * stride + k * w * h * stride * stride + j * w * stride + i;
          if (forward)
            out[out_index] = scale * in[in_index];
          else
            in[in_index] += scale * out[out_index];
        }
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<upsample_cpu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r13d
  mov    0x40(%rsp),%r12
  mov    %esi,-0x30(%rsp)
  mov    %ecx,-0x1c(%rsp)
  mov    %r8d,-0x4(%rsp)
  test   %r8d,%r8d
  jle    L106
  mov    %rdi,%r10
  mov    %esi,%edi
  mov    %edx,%r14d
  mov    %edx,%eax
  mov    %edi,%ebx
  imul   %r9d,%r14d
  mov    %r9d,%esi
  imul   %r9d,%ebx
  test   %ecx,%ecx
  jle    L106
  test   %r14d,%r14d
  jle    L106
  mov    %r9d,%edx
  movl   $0x0,-0x14(%rsp)
  mov    %ebx,%r8d
  imul   %r9d,%edx
  movl   $0x0,-0x10(%rsp)
  movl   $0x0,-0x18(%rsp)
  imul   %edi,%edx
  imul   %eax,%edx
  imul   %edi,%eax
  mov    %edx,-0x24(%rsp)
  imul   %ecx,%edx
  mov    %eax,-0x20(%rsp)
  imul   %ecx,%eax
  mov    %edx,-0x8(%rsp)
  mov    %eax,-0xc(%rsp)
L36:
  mov    -0x10(%rsp),%eax
  mov    -0x14(%rsp),%ebp
  movl   $0x0,-0x2c(%rsp)
  mov    %eax,-0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L88:
  mov    -0x28(%rsp),%r11d
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L9:
  test   %ebx,%ebx
  jle    L108
  mov    %r9d,%eax
  xor    %ecx,%ecx
  cltd
  idiv   %esi
  imul   -0x30(%rsp),%eax
  lea    (%rax,%rbp,1),%edi
  movslq %r11d,%rax
  lea    (%r12,%rax,4),%r15
  test   %r13d,%r13d
  jne    L78
  nopl   0x0(%rax)
L102:
  mov    %ecx,%eax
  movss  (%r15,%rcx,4),%xmm1
  add    $0x1,%rcx
  cltd
  idiv   %esi
  mulss  %xmm0,%xmm1
  add    %edi,%eax
  cltq
  lea    (%r10,%rax,4),%rax
  addss  (%rax),%xmm1
  movss  %xmm1,(%rax)
  cmp    %rcx,%r8
  jne    L102
L108:
  add    $0x1,%r9d
  add    %ebx,%r11d
  cmp    %r14d,%r9d
  jne    L9
  addl   $0x1,-0x2c(%rsp)
  mov    -0x24(%rsp),%edx
  mov    -0x2c(%rsp),%eax
  add    %edx,-0x28(%rsp)
  add    -0x20(%rsp),%ebp
  cmp    %eax,-0x1c(%rsp)
  jne    L88
  mov    -0x8(%rsp),%edx
  addl   $0x1,-0x18(%rsp)
  add    %edx,-0x10(%rsp)
  mov    -0x18(%rsp),%eax
  mov    -0xc(%rsp),%edx
  add    %edx,-0x14(%rsp)
  cmp    %eax,-0x4(%rsp)
  jne    L36
L106:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L78:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  add    %edi,%eax
  cltq
  movss  (%r10,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%r15,%rcx,4)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L78
  jmp    L108
```

assistant: ```c
void upsample_cpu(float *in, int w, int h, int c, int batch, int stride, int forward, float scale, float *out) {
  int i, j, k, b;
  for (b = 0; b < batch; ++b) {
    for (k = 0; k < c; ++k) {
      for (j = 0; j < h * stride; ++j) {
        for (i = 0; i < w * stride; ++i) {
          int in_index = b * w * h * c + k * w * h + (j / stride) * w + i / stride;
          int out_index = b * w * h * c * stride * stride + k * w * h * stride * stride + j * w * stride + i;
          if (forward)
            out[out_index] = scale * in[in_index];
          else
            in[in_index] += scale * out[out_index];
        }
      }
    }
  }
}
```