ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_solution>:
  endbr64
  push   %r15
  lea    0x10(%rdi),%rax
  lea    D23(%rip),%r15
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rax,0x18(%rsp)
  movl   $0x19,0x10(%rsp)
  movl   $0x14,0xc(%rsp)
  movl   $0x41,0x14(%rsp)
L37:
  mov    0x14(%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rbx
  lea    -0x14(%rax),%r12d
L9:
  mov    %r15,%rdi
  xor    %eax,%eax
  lea    -0x10(%rbx),%r13
  call   <printf@plt>
L5:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%r13
  cvtss2sd -0x4(%r13),%xmm0
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L5
  pxor   %xmm0,%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  cvtss2sd (%rbx),%xmm0
  call   <printf@plt>
  cmp    0xc(%rsp),%r12d
  je     L13
  mov    $0x2c,%edi
  add    $0x14,%rbx
  add    $0x5,%r12d
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    0x10(%rsp),%r12d
  jne    L9
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
L38:
  mov    0x14(%rsp),%ebx
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  mov    %ebx,%edx
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%eax
  addl   $0x19,0xc(%rsp)
  add    $0x1,%eax
  addq   $0x64,0x18(%rsp)
  mov    %eax,0x14(%rsp)
  mov    0xc(%rsp),%eax
  addl   $0x19,0x10(%rsp)
  cmp    $0x46,%eax
  jne    L37
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string
name: unpack_data
arguments: data_tag: D31
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D23: [ 

tool: D19: %10.9e ]

tool: D22: %10.9e, 

tool: D31: %c: matrix(


tool: D3: );
%c: factor(%c);



assistant: ```c
void print_solution(const float *const res) {
  for (int m = 0; m < 2; m++) {
    char matrix = 'A' + m;
    printf("%c: matrix(\n", matrix);
    for (int h = 0; h < 5; h++) {
      int pos = m * 5 * 5 + h * 5;
      printf("[ ");
      for (int w = 0; w < 5 - 1; w++) {
        printf("%10.9e, ", res[pos + w]);
      }
      printf("%10.9e ]", res[pos + 5 - 1]);
      if (h < (5 - 1))
        printf(",");
      printf("\n");
    }
    printf(");\n%c: factor(%c);\n\n", matrix, matrix);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_solution>:
  endbr64
  push   %r15
  lea    0x10(%rdi),%rax
  lea    D11(%rip),%r15
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D40(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rax,0x18(%rsp)
  movl   $0x19,0x10(%rsp)
  movl   $0x14,0xc(%rsp)
  movl   $0x41,0x14(%rsp)
L22:
  mov    0x14(%rsp),%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rbx
  lea    -0x14(%rax),%r12d
L9:
  mov    %r15,%rdi
  xor    %eax,%eax
  lea    -0x10(%rbx),%r13
  call   <printf@plt>
L28:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%r13
  cvtss2sd -0x4(%r13),%xmm0
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L28
  pxor   %xmm0,%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  cvtss2sd (%rbx),%xmm0
  call   <printf@plt>
  cmp    0xc(%rsp),%r12d
  je     L31
  mov    $0x2c,%edi
  add    $0x14,%rbx
  add    $0x5,%r12d
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    0x10(%rsp),%r12d
  jne    L9
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
L40:
  mov    0x14(%rsp),%ebx
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  mov    %ebx,%edx
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%eax
  addl   $0x19,0xc(%rsp)
  add    $0x1,%eax
  addq   $0x64,0x18(%rsp)
  mov    %eax,0x14(%rsp)
  mov    0xc(%rsp),%eax
  addl   $0x19,0x10(%rsp)
  cmp    $0x46,%eax
  jne    L22
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D11
type: string
name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D40
type: string
name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D15
type: string

tool: D11: [ 

tool: D28: %10.9e ]

tool: D40: %10.9e, 

tool: D21: %c: matrix(


tool: D15: );
%c: factor(%c);



assistant: ```c
void print_solution(const float *const res) {
  for (int m = 0; m < 2; m++) {
    char matrix = 'A' + m;
    printf("%c: matrix(\n", matrix);
    for (int h = 0; h < 5; h++) {
      int pos = m * 5 * 5 + h * 5;
      printf("[ ");
      for (int w = 0; w < 5 - 1; w++) {
        printf("%10.9e, ", res[pos + w]);
      }
      printf("%10.9e ]", res[pos + 5 - 1]);
      if (h < (5 - 1))
        printf(",");
      printf("\n");
    }
    printf(");\n%c: factor(%c);\n\n", matrix, matrix);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nextUp_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x14(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L13
  mov    -0x8(%rbp),%rax
  jmp    L12
L13:
  movsd  -0x8(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <nextafterf_custom@plt>
  movq   %xmm0,%rax
L12:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double nextUp_d(float d) {
  double result = d;
  if (result > d)
    return result;
  return nextafterf_custom(result, result + 1000000);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nextUp_d>:
  endbr64
  sub    $0x8,%rsp
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  addsd  D7(%rip),%xmm1
  call   <nextafterf_custom@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double nextUp_d(float d) {
  double result = d;
  if (result > d)
    return result;
  return nextafterf_custom(result, result + 1000000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nextUp_d>:
  endbr64
  movsd  D0(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  jmp    1050 <nextafterf_custom@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double nextUp_d(float d) {
  double result = d;
  if (result > d)
    return result;
  return nextafterf_custom(result, result + 1000000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextUp_d>:
  endbr64
  movsd  D8(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  jmp    1050 <nextafterf_custom@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double nextUp_d(float d) {
  double result = d;
  if (result > d)
    return result;
  return nextafterf_custom(result, result + 1000000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<autohelperowl_attackpat50>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x3,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend_n@plt>
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat50(struct pattern *patt, int transformation, int move, int color, int action) {
  int a;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 1, move, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<autohelperowl_attackpat50>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r8d
  mov    $0x3,%edi
  sub    %ebp,%edi
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int autohelperowl_attackpat50(struct pattern *patt, int transformation, int move, int color, int action) {
  int a;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 1, move, a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<autohelperowl_attackpat50>:
  endbr64
  push   %r12
  xor    %edi,%edi
  mov    %edx,%r12d
  push   %rbx
  mov    %ecx,%ebx
  mov    %esi,%ecx
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <offset@plt>
  add    $0x8,%rsp
  mov    $0x3,%edi
  mov    %r12d,%ecx
  sub    %ebx,%edi
  mov    %eax,%r8d
  pop    %rbx
  mov    $0x1,%edx
  mov    $0x1,%esi
  pop    %r12
  jmp    1060 <play_attack_defend_n@plt>
```

assistant: ```c
int autohelperowl_attackpat50(struct pattern *patt, int transformation, int move, int color, int action) {
  int a;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 1, move, a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<autohelperowl_attackpat50>:
  endbr64
  push   %r12
  xor    %edi,%edi
  mov    %edx,%r12d
  push   %rbx
  mov    %ecx,%ebx
  mov    %esi,%ecx
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <offset@plt>
  add    $0x8,%rsp
  mov    $0x3,%edi
  mov    %r12d,%ecx
  sub    %ebx,%edi
  mov    %eax,%r8d
  pop    %rbx
  mov    $0x1,%edx
  mov    $0x1,%esi
  pop    %r12
  jmp    1060 <play_attack_defend_n@plt>
```

assistant: ```c
int autohelperowl_attackpat50(struct pattern *patt, int transformation, int move, int color, int action) {
  int a;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 1, move, a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fill_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L25:
  mov    D29(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D37(%rip),%rax
  mov    (%rax),%ecx
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x100000,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,-0x8(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L25
  mov    -0x8(%rbp),%rax
  mov    $0x100000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fill_mem(int mb_count) {
  int i, j;
  char *ptr = NULL;
  for (j = 0; j < mb_count; j++) {
    do {
      ptr = mmap(NULL, (1024 * 1024) * sizeof(char), PROT_READ | PROT_WRITE, MAP_ANONYMOUS | MAP_PRIVATE, -1, 0);
    } while (ptr == MAP_FAILED);
    memset(ptr, 1, (1024 * 1024) * sizeof(char));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_mem>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x0,%ebp
  mov    D28(%rip),%rbx
L12:
  mov    (%rbx),%ecx
  mov    D1(%rip),%rax
  or     (%rax),%ecx
  mov    D43(%rip),%rax
  mov    (%rax),%edx
  mov    D20(%rip),%rax
  or     (%rax),%edx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x100000,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    D8(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L12
  mov    $0x100000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jne    L12
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int fill_mem(int mb_count) {
  int i, j;
  char *ptr = NULL;
  for (j = 0; j < mb_count; j++) {
    do {
      ptr = mmap(NULL, (1024 * 1024) * sizeof(char), PROT_READ | PROT_WRITE, MAP_ANONYMOUS | MAP_PRIVATE, -1, 0);
    } while (ptr == MAP_FAILED);
    memset(ptr, 1, (1024 * 1024) * sizeof(char));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fill_mem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %edi,%edi
  jle    L28
  mov    D36(%rip),%r14
  mov    D31(%rip),%r13
  xor    %r15d,%r15d
  mov    D8(%rip),%r12
  mov    D46(%rip),%rbp
  mov    D7(%rip),%rbx
L16:
  mov    (%r14),%ecx
  mov    (%r12),%edx
  xor    %r9d,%r9d
  xor    %edi,%edi
  or     0x0(%r13),%ecx
  or     0x0(%rbp),%edx
  mov    $0xffffffff,%r8d
  mov    $0x100000,%esi
  call   <mmap@plt>
  cmp    %rax,(%rbx)
  je     L16
  mov    $0x100000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  add    $0x1,%r15d
  call   <memset@plt>
  cmp    %r15d,0xc(%rsp)
  jne    L16
L28:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int fill_mem(int mb_count) {
  int i, j;
  char *ptr = NULL;
  for (j = 0; j < mb_count; j++) {
    do {
      ptr = mmap(NULL, (1024 * 1024) * sizeof(char), PROT_READ | PROT_WRITE, MAP_ANONYMOUS | MAP_PRIVATE, -1, 0);
    } while (ptr == MAP_FAILED);
    memset(ptr, 1, (1024 * 1024) * sizeof(char));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fill_mem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %edi,%edi
  jle    L25
  mov    D8(%rip),%r14
  mov    D1(%rip),%r13
  xor    %r15d,%r15d
  mov    D7(%rip),%r12
  mov    D43(%rip),%rbp
  mov    D18(%rip),%rbx
L17:
  mov    (%r14),%ecx
  mov    (%r12),%edx
  xor    %r9d,%r9d
  xor    %edi,%edi
  or     0x0(%r13),%ecx
  or     0x0(%rbp),%edx
  mov    $0xffffffff,%r8d
  mov    $0x100000,%esi
  call   <mmap@plt>
  cmp    %rax,(%rbx)
  je     L17
  mov    $0x100000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  add    $0x1,%r15d
  call   <memset@plt>
  cmp    %r15d,0xc(%rsp)
  jne    L17
L25:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int fill_mem(int mb_count) {
  int i, j;
  char *ptr = NULL;
  for (j = 0; j < mb_count; j++) {
    do {
      ptr = mmap(NULL, (1024 * 1024) * sizeof(char), PROT_READ | PROT_WRITE, MAP_ANONYMOUS | MAP_PRIVATE, -1, 0);
    } while (ptr == MAP_FAILED);
    memset(ptr, 1, (1024 * 1024) * sizeof(char));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<script_action_installnext_timer_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <script_action_run_install@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int script_action_installnext_timer_cb(const void *pointer, void *data, int remaining_calls) {
  (void)data;
  (void)remaining_calls;
  script_action_run_install((pointer) ? 1 : 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<script_action_installnext_timer_cb>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <script_action_run_install@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int script_action_installnext_timer_cb(const void *pointer, void *data, int remaining_calls) {
  (void)data;
  (void)remaining_calls;
  script_action_run_install((pointer) ? 1 : 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<script_action_installnext_timer_cb>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <script_action_run_install@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int script_action_installnext_timer_cb(const void *pointer, void *data, int remaining_calls) {
  (void)data;
  (void)remaining_calls;
  script_action_run_install((pointer) ? 1 : 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<script_action_installnext_timer_cb>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <script_action_run_install@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int script_action_installnext_timer_cb(const void *pointer, void *data, int remaining_calls) {
  (void)data;
  (void)remaining_calls;
  script_action_run_install((pointer) ? 1 : 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L16
  mov    -0x8(%rbp),%rax
  jmp    L0
L16:
  mov    -0x10(%rbp),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
size_t max(size_t a, size_t b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<max>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovae %rdi,%rax
  ret
```

assistant: ```c
size_t max(size_t a, size_t b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovae %rdi,%rax
  ret
```

assistant: ```c
size_t max(size_t a, size_t b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<max>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovae %rdi,%rax
  ret
```

assistant: ```c
size_t max(size_t a, size_t b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x3f,-0xc(%rbp)
  movl   $0x77,-0x8(%rbp)
  movl   $0xabc,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: x is %d, y is %d, z is %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 077;
  int y = 0x77;
  int z = 0xABC;
  printf("x is %d, y is %d, z is %d.\n", x, y, z);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xabc,%ecx
  mov    $0x77,%edx
  mov    $0x3f,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D2: x is %d, y is %d, z is %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 077;
  int y = 0x77;
  int z = 0xABC;
  printf("x is %d, y is %d, z is %d.\n", x, y, z);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xabc,%ecx
  mov    $0x77,%edx
  mov    $0x3f,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: x is %d, y is %d, z is %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 077;
  int y = 0x77;
  int z = 0xABC;
  printf("x is %d, y is %d, z is %d.\n", x, y, z);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xabc,%ecx
  mov    $0x77,%edx
  mov    $0x3f,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: x is %d, y is %d, z is %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 077;
  int y = 0x77;
  int z = 0xABC;
  printf("x is %d, y is %d, z is %d.\n", x, y, z);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_func_00>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  subq   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *test_func_00(char *p, int c) {
  *--p = (char)c;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_func_00>:
  endbr64
  mov    %sil,-0x1(%rdi)
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
char *test_func_00(char *p, int c) {
  *--p = (char)c;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_func_00>:
  endbr64
  mov    %sil,-0x1(%rdi)
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
char *test_func_00(char *p, int c) {
  *--p = (char)c;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_func_00>:
  endbr64
  mov    %sil,-0x1(%rdi)
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
char *test_func_00(char *p, int c) {
  *--p = (char)c;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x7,-0x4(%rbp)
  jne    L46
  cmpl   $0x0,-0x8(%rbp)
  je     L24
  mov    $0x7,%eax
  jmp    L50
L24:
  mov    $0x8,%eax
  jmp    L50
L46:
  cmpl   $0xd,-0x4(%rbp)
  jle    L25
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  jmp    L50
L25:
  mov    -0x4(%rbp),%eax
L50:
  pop    %rbp
  ret
```

assistant: ```c
int mod(int i, int j) {
  ++i;
  if (i == 7)
    return (j ? 7 : 8);
  if (i > 13)
    return (j ? 1 : 0);
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mod>:
  endbr64
  lea    0x1(%rdi),%eax
  cmp    $0x6,%edi
  je     L21
  cmp    $0xd,%eax
  jg     L5
L19:
  ret
L21:
  test   %esi,%esi
  mov    $0x8,%edx
  cmove  %edx,%eax
  ret
L5:
  test   %esi,%esi
  setne  %al
  movzbl %al,%eax
  jmp    L19
```

assistant: ```c
int mod(int i, int j) {
  ++i;
  if (i == 7)
    return (j ? 7 : 8);
  if (i > 13)
    return (j ? 1 : 0);
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mod>:
  endbr64
  lea    0x1(%rdi),%eax
  cmp    $0x6,%edi
  je     L13
  cmp    $0xd,%eax
  jg     L15
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  test   %esi,%esi
  setne  %al
  ret
L13:
  test   %esi,%esi
  mov    $0x8,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int mod(int i, int j) {
  ++i;
  if (i == 7)
    return (j ? 7 : 8);
  if (i > 13)
    return (j ? 1 : 0);
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mod>:
  endbr64
  lea    0x1(%rdi),%eax
  cmp    $0x6,%edi
  je     L2
  cmp    $0xd,%eax
  jg     L13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  test   %esi,%esi
  setne  %al
  ret
L2:
  test   %esi,%esi
  mov    $0x8,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int mod(int i, int j) {
  ++i;
  if (i == 7)
    return (j ? 7 : 8);
  if (i > 13)
    return (j ? 1 : 0);
  return (i);
}
```