ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<baz_5>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  test   %edi,%edi
  je     L41
  test   %esi,%esi
  jne    L39
L22:
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <blah@plt>
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  call   <foo@plt>
  test   %ebx,%ebx
  je     L22
  xor    %eax,%eax
  pop    %rbx
  jmp    1090 <bar@plt>
  nopl   0x0(%rax,%rax,1)
L41:
  test   %esi,%esi
  je     L22
  test   %edx,%edx
  je     L22
  pop    %rbx
  ret
```

assistant: ```c
void baz_5(int a, int b, int c) {
  if (a && b) {
    foo();
    if (c)
      bar();
  }
  if (!b || !c)
    blah();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factrl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L27
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L27:
  cmpl   $0x20,-0x14(%rbp)
  jle    L38
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  call   <gammln@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <exp@plt>
  movd   %xmm0,%eax
  jmp    L19
L33:
  mov    D39(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D33(%rip)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  movss  (%rdx,%rax,1),%xmm1
  mov    D33(%rip),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    D33(%rip),%eax
  mulss  %xmm1,%xmm0
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  movss  %xmm0,(%rdx,%rax,1)
L38:
  mov    D33(%rip),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L33
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D33(%rip),%rax
  mov    (%rdx,%rax,1),%eax
L19:
  movd   %eax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D64
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: f64

tool: D64: Negative factorial in routine factrl

tool: D15: 1

assistant: ```c
float factrl(int n) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  static int ntop = 4;
  static float a[33] = {1.0, 1.0, 2.0, 6.0, 24.0};
  int j;
  if (n < 0)
    nrerror("Negative factorial in routine factrl");
  if (n > 32)
    return exp(gammln(n + 1.0));
  while (ntop < n) {
    j = ntop++;
    a[ntop] = a[j] * ntop;
  }
  return a[n];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factrl>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L47
  cmp    $0x20,%edi
  jg     L17
L27:
  mov    D45(%rip),%edx
  cmp    %edx,%ebx
  jle    L43
  lea    0x1(%rdx),%eax
  cltq
  mov    %ebx,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%ecx
  movslq %edx,%rdx
  lea    0x2(%rcx,%rdx,1),%rsi
  lea    D39(%rip),%rcx
  lea    0x4(%rcx),%rdx
L57:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L57
  mov    %ebx,D14(%rip)
  movslq %ebx,%rax
  lea    D14(%rip),%rdx
  movss  %xmm0,(%rdx,%rax,4)
L43:
  movslq %ebx,%rbx
  lea    D14(%rip),%rax
  movss  (%rax,%rbx,4),%xmm0
L5:
  pop    %rbx
  ret
L47:
  lea    D42(%rip),%rdi
  call   <nrerror@plt>
  jmp    L27
L17:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D18(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <gammln@plt>
  call   <exp@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D42
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: f64

tool: D42: Negative factorial in routine factrl

tool: D18: 1

assistant: ```c
float factrl(int n) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  static int ntop = 4;
  static float a[33] = {1.0, 1.0, 2.0, 6.0, 24.0};
  int j;
  if (n < 0)
    nrerror("Negative factorial in routine factrl");
  if (n > 32)
    return exp(gammln(n + 1.0));
  while (ntop < n) {
    j = ntop++;
    a[ntop] = a[j] * ntop;
  }
  return a[n];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<factrl>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  test   %ebx,%ebx
  js     L39
  cmp    $0x20,%ebx
  jg     L12
L16:
  mov    D21(%rip),%ecx
  lea    D38(%rip),%rdx
  cmp    %ecx,%ebx
  jle    L19
  mov    %ebx,%edi
  movslq %ecx,%rsi
  lea    0x1(%rcx),%eax
  sub    %ecx,%edi
  movss  (%rdx,%rsi,4),%xmm0
  cltq
  lea    -0x1(%rdi),%ecx
  lea    0x2(%rsi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L33:
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L33
  mov    %ebx,D11(%rip)
L19:
  movss  (%rdx,%rbx,4),%xmm0
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  lea    D11(%rip),%rdi
  call   <nrerror@plt>
  jmp    L16
  xchg   %ax,%ax
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  D39(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <gammln@plt>
  pop    %rbx
  jmp    1090 <exp@plt>
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D39
data_type: f64

tool: D11: Negative factorial in routine factrl

tool: D39: 1

assistant: ```c
float factrl(int n) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  static int ntop = 4;
  static float a[33] = {1.0, 1.0, 2.0, 6.0, 24.0};
  int j;
  if (n < 0)
    nrerror("Negative factorial in routine factrl");
  if (n > 32)
    return exp(gammln(n + 1.0));
  while (ntop < n) {
    j = ntop++;
    a[ntop] = a[j] * ntop;
  }
  return a[n];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<factrl>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  test   %ebx,%ebx
  js     L44
  cmp    $0x20,%ebx
  jg     L47
L32:
  mov    D36(%rip),%ecx
  lea    D29(%rip),%rdx
  cmp    %ecx,%ebx
  jle    L17
  mov    %ebx,%edi
  lea    D29(%rip),%rdx
  lea    0x1(%rcx),%eax
  movslq %ecx,%rsi
  sub    %ecx,%edi
  movss  (%rdx,%rsi,4),%xmm0
  cltq
  lea    -0x1(%rdi),%ecx
  lea    0x2(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L43:
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L43
  mov    %ebx,D40(%rip)
L17:
  movss  (%rdx,%rbx,4),%xmm0
  pop    %rbx
  ret
  nop
L44:
  lea    D40(%rip),%rdi
  call   <nrerror@plt>
  jmp    L32
  xchg   %ax,%ax
L47:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  D27(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <gammln@plt>
  pop    %rbx
  jmp    1090 <exp@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D40
datatype: string
name: extract_symbolic_data
arguments: tag: D27
datatype: f64

tool: D40: Negative factorial in routine factrl

tool: D27: 1

assistant: ```c
float factrl(int n) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  static int ntop = 4;
  static float a[33] = {1.0, 1.0, 2.0, 6.0, 24.0};
  int j;
  if (n < 0)
    nrerror("Negative factorial in routine factrl");
  if (n > 32)
    return exp(gammln(n + 1.0));
  while (ntop < n) {
    j = ntop++;
    a[ntop] = a[j] * ntop;
  }
  return a[n];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ctime_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L9
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <asctime_r@plt>
  jmp    L16
L9:
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
char *ctime_r(const time_t *t, char *buf) {
  struct tm tm, *tm_p = localtime_r(t, &tm);
  return tm_p ? asctime_r(tm_p, buf) : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ctime_r>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <localtime_r@plt>
  test   %rax,%rax
  je     L12
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <asctime_r@plt>
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ctime_r(const time_t *t, char *buf) {
  struct tm tm, *tm_p = localtime_r(t, &tm);
  return tm_p ? asctime_r(tm_p, buf) : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ctime_r>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <localtime_r@plt>
  test   %rax,%rax
  je     L15
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <asctime_r@plt>
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ctime_r(const time_t *t, char *buf) {
  struct tm tm, *tm_p = localtime_r(t, &tm);
  return tm_p ? asctime_r(tm_p, buf) : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ctime_r>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <localtime_r@plt>
  test   %rax,%rax
  je     L6
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <asctime_r@plt>
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ctime_r(const time_t *t, char *buf) {
  struct tm tm, *tm_p = localtime_r(t, &tm);
  return tm_p ? asctime_r(tm_p, buf) : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum_lt5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  jg     L3
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L5
L3:
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int sum_lt5(void *_a, void *_b) {
  int *a = _a, *b = _b;
  int sum = *a + *b;
  if (sum < 5) {
    *a = sum;
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_lt5>:
  endbr64
  mov    (%rsi),%eax
  add    (%rdi),%eax
  mov    $0x1,%edx
  cmp    $0x4,%eax
  jle    L8
L0:
  mov    %edx,%eax
  ret
L8:
  mov    %eax,(%rdi)
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
int sum_lt5(void *_a, void *_b) {
  int *a = _a, *b = _b;
  int sum = *a + *b;
  if (sum < 5) {
    *a = sum;
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_lt5>:
  endbr64
  mov    (%rsi),%eax
  add    (%rdi),%eax
  mov    $0x1,%r8d
  cmp    $0x4,%eax
  jg     L8
  mov    %eax,(%rdi)
  xor    %r8d,%r8d
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_lt5(void *_a, void *_b) {
  int *a = _a, *b = _b;
  int sum = *a + *b;
  if (sum < 5) {
    *a = sum;
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<sum_lt5>:
  endbr64
  mov    (%rsi),%eax
  add    (%rdi),%eax
  mov    $0x1,%r8d
  cmp    $0x4,%eax
  jg     L4
  mov    %eax,(%rdi)
  xor    %r8d,%r8d
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_lt5(void *_a, void *_b) {
  int *a = _a, *b = _b;
  int sum = *a + *b;
  if (sum < 5) {
    *a = sum;
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mp_fprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
L6:
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mp_fprint_internal@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mp_fprint(FILE *file, const char *data) {
  if (!file)
    file = stdout;
  int res = mp_fprint_internal(file, &data);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mp_fprint>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rdi,%rdi
  je     L6
L3:
  lea    0x8(%rsp),%rsi
  call   <mp_fprint_internal@plt>
  add    $0x18,%rsp
  ret
L6:
  mov    D3(%rip),%rax
  mov    (%rax),%rdi
  jmp    L3
```

assistant: ```c
int mp_fprint(FILE *file, const char *data) {
  if (!file)
    file = stdout;
  int res = mp_fprint_internal(file, &data);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mp_fprint>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rdi,%rdi
  je     L7
  lea    0x8(%rsp),%rsi
  call   <mp_fprint_internal@plt>
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L7:
  mov    D8(%rip),%rax
  lea    0x8(%rsp),%rsi
  mov    (%rax),%rdi
  call   <mp_fprint_internal@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int mp_fprint(FILE *file, const char *data) {
  if (!file)
    file = stdout;
  int res = mp_fprint_internal(file, &data);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mp_fprint>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rdi,%rdi
  je     L0
  lea    0x8(%rsp),%rsi
  call   <mp_fprint_internal@plt>
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L0:
  mov    D9(%rip),%rax
  lea    0x8(%rsp),%rsi
  mov    (%rax),%rdi
  call   <mp_fprint_internal@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int mp_fprint(FILE *file, const char *data) {
  if (!file)
    file = stdout;
  int res = mp_fprint_internal(file, &data);
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rdar8511238>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x14,%eax
  pop    %rbp
  ret
```

assistant: ```c
int rdar8511238() {
  enum A { A_foo, A_bar };
  enum A a;
  if (a < 0)
    return 0;
  return 20;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rdar8511238>:
  endbr64
  mov    $0x14,%eax
  ret
```

assistant: ```c
int rdar8511238() {
  enum A { A_foo, A_bar };
  enum A a;
  if (a < 0)
    return 0;
  return 20;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdar8511238>:
  endbr64
  mov    $0x14,%eax
  ret
```

assistant: ```c
int rdar8511238() {
  enum A { A_foo, A_bar };
  enum A a;
  if (a < 0)
    return 0;
  return 20;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0xa,-0x14(%rbp)
  jmp    L17
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L17:
  cmpl   $0x63,-0x14(%rbp)
  jle    L16
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x2a,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int *p = (int *)malloc(sizeof(int));
  int i;
  for (i = 10; i < 100; i++)
    p[i] = 0;
  char *jp = (char *)p;
  jp[42] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    0x28(%rax),%rdx
  lea    0x190(%rax),%rcx
L8:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L8
  movb   $0x0,0x2a(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int *p = (int *)malloc(sizeof(int));
  int i;
  for (i = 10; i < 100; i++)
    p[i] = 0;
  char *jp = (char *)p;
  jp[42] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    0x30(%rax),%rdi
  movq   $0x0,0x28(%rax)
  movq   $0x0,0x188(%rax)
  and    $0xfffffffffffffff8,%rdi
  sub    %edi,%eax
  lea    0x190(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int *p = (int *)malloc(sizeof(int));
  int i;
  for (i = 10; i < 100; i++)
    p[i] = 0;
  char *jp = (char *)p;
  jp[42] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L23
  mov    $0x0,%eax
  jmp    L15
L23:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strnew@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L15
L9:
  mov    -0x1c(%rbp),%eax
  add    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ft_strncpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *sub;
  if (!s)
    return (NULL);
  if (!(sub = ft_strnew(len)))
    return (NULL);
  s += start;
  sub = ft_strncpy(sub, s, len);
  return (sub);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strsub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L6
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %rdx,%rdi
  call   <ft_strnew@plt>
  test   %rax,%rax
  je     L18
  mov    %ebx,%esi
  add    %rbp,%rsi
  mov    %r12,%rdx
  mov    %rax,%rdi
  call   <ft_strncpy@plt>
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rdi,%rax
  jmp    L18
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *sub;
  if (!s)
    return (NULL);
  if (!(sub = ft_strnew(len)))
    return (NULL);
  s += start;
  sub = ft_strncpy(sub, s, len);
  return (sub);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strsub>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <ft_strnew@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  mov    %ebp,%esi
  mov    %r12,%rdx
  add    %rbx,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <ft_strncpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *sub;
  if (!s)
    return (NULL);
  if (!(sub = ft_strnew(len)))
    return (NULL);
  s += start;
  sub = ft_strncpy(sub, s, len);
  return (sub);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strsub>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <ft_strnew@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L14
  mov    %ebp,%esi
  mov    %r12,%rdx
  add    %rbx,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <ft_strncpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L14:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *sub;
  if (!s)
    return (NULL);
  if (!(sub = ft_strnew(len)))
    return (NULL);
  s += start;
  sub = ft_strncpy(sub, s, len);
  return (sub);
}
```
user: What is the c source code of the assembly code below?

```asm
<finn_mat4_rotate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movss  %xmm0,0x8(%rsp)
  call   <sin@plt>
  movss  %xmm0,0x4(%rsp)
  movss  0x8(%rsp),%xmm0
  call   <cos@plt>
  movss  D2(%rip),%xmm3
  movss  %xmm0,0x8(%rsp)
  subss  %xmm0,%xmm3
  movss  %xmm3,0xc(%rsp)
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <finn_vec3_normalize@plt>
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movss  (%rbx),%xmm0
  mulss  %xmm0,%xmm0
  movss  0xc(%rsp),%xmm3
  mulss  %xmm3,%xmm0
  movss  0x8(%rsp),%xmm4
  addss  %xmm4,%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x4(%rbx),%xmm0
  mulss  (%rbx),%xmm0
  mulss  %xmm3,%xmm0
  movss  0x4(%rsp),%xmm2
  movaps %xmm2,%xmm1
  mulss  0x8(%rbx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbp)
  movss  0x8(%rbx),%xmm0
  mulss  (%rbx),%xmm0
  mulss  %xmm3,%xmm0
  movaps %xmm2,%xmm1
  mulss  0x4(%rbx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rbp)
  movss  (%rbx),%xmm0
  mulss  0x4(%rbx),%xmm0
  mulss  %xmm3,%xmm0
  movaps %xmm2,%xmm1
  mulss  0x8(%rbx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x10(%rbp)
  movss  0x4(%rbx),%xmm0
  mulss  %xmm0,%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm4,%xmm0
  movss  %xmm0,0x14(%rbp)
  movss  0x8(%rbx),%xmm0
  mulss  0x4(%rbx),%xmm0
  mulss  %xmm3,%xmm0
  movaps %xmm2,%xmm1
  mulss  (%rbx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x18(%rbp)
  movss  (%rbx),%xmm0
  mulss  0x8(%rbx),%xmm0
  mulss  %xmm3,%xmm0
  movaps %xmm2,%xmm1
  mulss  0x4(%rbx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x20(%rbp)
  movss  0x4(%rbx),%xmm0
  movaps %xmm0,%xmm1
  mulss  0x8(%rbx),%xmm1
  mulss  %xmm3,%xmm1
  mulss  (%rbx),%xmm2
  subss  %xmm2,%xmm1
  movss  %xmm1,0x24(%rbp)
  movss  0x8(%rbx),%xmm0
  mulss  %xmm0,%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm4,%xmm0
  movss  %xmm0,0x28(%rbp)
  movl   $0x3f800000,0x3c(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f32

tool: D2: 1

assistant: ```c
void finn_mat4_rotate(float *mat, float *axis, float rad) {
  float s = sin(rad);
  float c = cos(rad);
  float t = 1 - c;
  finn_vec3_normalize(axis, axis);
  memset(mat, 0, sizeof(float) * 16);
  mat[0] = axis[0] * axis[0] * t + c;
  mat[1] = axis[1] * axis[0] * t + axis[2] * s;
  mat[2] = axis[2] * axis[0] * t - axis[1] * s;
  mat[4] = axis[0] * axis[1] * t - axis[2] * s;
  mat[5] = axis[1] * axis[1] * t + c;
  mat[6] = axis[2] * axis[1] * t + axis[0] * s;
  mat[8] = axis[0] * axis[2] * t + axis[1] * s;
  mat[9] = axis[1] * axis[2] * t - axis[0] * s;
  mat[10] = axis[2] * axis[2] * t + c;
  mat[15] = 1.0f;
}
```