ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D28(%rip),%rdi
  mov    %esi,%eax
  neg    %esi
  not    %eax
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string

tool: D18: Nr=

tool: D17: %d

tool: D28: New value: %d

assistant: ```c
int main() {
  int n;
  printf("Nr=");
  scanf("%d", &n);
  n = ~n;
  printf("New value: %d", n + 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    %esi,%eax
  neg    %esi
  not    %eax
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D0: Nr=

tool: D1: %d

tool: D19: New value: %d

assistant: ```c
int main() {
  int n;
  printf("Nr=");
  scanf("%d", &n);
  n = ~n;
  printf("New value: %d", n + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gdt_compare_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L35
  mov    $0xffffffff,%eax
  jmp    L1
L35:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jle    L27
  mov    $0x1,%eax
  jmp    L1
L27:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int gdt_compare_char(const void *p1, const void *p2) {
  char c1 = *((char *)p1);
  char c2 = *((char *)p2);
  if (c1 < c2) {
    return -1;
  } else if (c1 > c2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gdt_compare_char>:
  endbr64
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,%cl
  jl     L1
  setg   %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
int gdt_compare_char(const void *p1, const void *p2) {
  char c1 = *((char *)p1);
  char c2 = *((char *)p2);
  if (c1 < c2) {
    return -1;
  } else if (c1 > c2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<gdt_compare_char>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int gdt_compare_char(const void *p1, const void *p2) {
  char c1 = *((char *)p1);
  char c2 = *((char *)p2);
  if (c1 < c2) {
    return -1;
  } else if (c1 > c2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gdt_compare_char>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int gdt_compare_char(const void *p1, const void *p2) {
  char c1 = *((char *)p1);
  char c2 = *((char *)p2);
  if (c1 < c2) {
    return -1;
  } else if (c1 > c2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<base32tobyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jg     L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x18,%eax
  jmp    L22
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
L22:
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x5,%eax
  and    $0x7,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  ja     L46
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%edx
  mov    %edx,%edi
  movzbl -0xd(%rbp),%esi
  mov    -0xc(%rbp),%edx
  mov    %edx,%ecx
  sar    %cl,%esi
  mov    %esi,%edx
  or     %edi,%edx
  mov    %dl,(%rax)
L46:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  movzbl -0xd(%rbp),%edx
  mov    $0x8,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void base32tobyte(const char *str, unsigned char *bin, int len) {
  const char *e = str + len;
  unsigned shift = 0;
  unsigned char b;
  for (; str < e; str++) {
    b = ((*str) < 'A' ? (*str) - '2' + 26 : ((*str) & ~0x20) - 'A');
    shift = (shift + 5) % 8;
    if (shift < 5) {
      *bin++ |= (b >> shift);
    }
    *bin |= b << (8 - shift);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base32tobyte>:
  endbr64
  movslq %edx,%r9
  add    %rdi,%r9
  cmp    %r9,%rdi
  jae    L27
  mov    $0x0,%edx
  mov    $0x8,%r10d
  jmp    L18
L40:
  movzbl %al,%eax
  mov    %r10d,%ecx
  sub    %edx,%ecx
  shl    %cl,%eax
  or     %al,(%rsi)
  add    $0x1,%rdi
  cmp    %rdi,%r9
  je     L27
L18:
  movzbl (%rdi),%ecx
  lea    -0x18(%rcx),%r8d
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x40,%cl
  cmovle %r8d,%eax
  add    $0x5,%edx
  and    $0x7,%edx
  cmp    $0x4,%edx
  ja     L40
  movzbl %al,%r8d
  mov    %edx,%ecx
  sar    %cl,%r8d
  or     %r8b,(%rsi)
  lea    0x1(%rsi),%rsi
  jmp    L40
L27:
  ret
```

assistant: ```c
void base32tobyte(const char *str, unsigned char *bin, int len) {
  const char *e = str + len;
  unsigned shift = 0;
  unsigned char b;
  for (; str < e; str++) {
    b = ((*str) < 'A' ? (*str) - '2' + 26 : ((*str) & ~0x20) - 'A');
    shift = (shift + 5) % 8;
    if (shift < 5) {
      *bin++ |= (b >> shift);
    }
    *bin |= b << (8 - shift);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base32tobyte>:
  endbr64
  movslq %edx,%r9
  mov    %rsi,%r8
  add    %rdi,%r9
  cmp    %r9,%rdi
  jae    L1
  movzbl (%rsi),%esi
  xor    %edx,%edx
  mov    $0x8,%r10d
  nopl   (%rax)
L19:
  movzbl (%rdi),%ecx
  mov    %ecx,%eax
  lea    -0x18(%rcx),%r11d
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x40,%cl
  cmovle %r11d,%eax
  add    $0x5,%edx
  and    $0x7,%edx
  movzbl %al,%eax
  cmp    $0x4,%edx
  ja     L8
  mov    %edx,%ecx
  mov    %eax,%r11d
  add    $0x1,%r8
  sar    %cl,%r11d
  mov    %r11d,%ecx
  or     %esi,%ecx
  movzbl (%r8),%esi
  mov    %cl,-0x1(%r8)
L8:
  mov    %r10d,%ecx
  add    $0x1,%rdi
  sub    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  mov    %sil,(%r8)
  cmp    %rdi,%r9
  jne    L19
L1:
  ret
```

assistant: ```c
void base32tobyte(const char *str, unsigned char *bin, int len) {
  const char *e = str + len;
  unsigned shift = 0;
  unsigned char b;
  for (; str < e; str++) {
    b = ((*str) < 'A' ? (*str) - '2' + 26 : ((*str) & ~0x20) - 'A');
    shift = (shift + 5) % 8;
    if (shift < 5) {
      *bin++ |= (b >> shift);
    }
    *bin |= b << (8 - shift);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<base32tobyte>:
  endbr64
  movslq %edx,%r10
  add    %rdi,%r10
  cmp    %r10,%rdi
  jae    L45
  push   %rbx
  mov    %rsi,%r8
  movzbl (%rsi),%r9d
  mov    $0x8,%r11d
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rdi),%edx
  mov    %edx,%eax
  lea    -0x18(%rdx),%ecx
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x40,%dl
  cmovle %ecx,%eax
  add    $0x5,%esi
  and    $0x7,%esi
  cmp    $0x4,%esi
  ja     L5
  movzbl %al,%eax
  mov    %esi,%ecx
  lea    0x1(%r8),%rbx
  add    $0x1,%rdi
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r11d,%ecx
  or     %r9d,%edx
  sub    %esi,%ecx
  movzbl 0x1(%r8),%r9d
  shl    %cl,%eax
  mov    %dl,(%r8)
  or     %eax,%r9d
  mov    %r9b,0x1(%r8)
  cmp    %rdi,%r10
  je     L13
  mov    %rbx,%r8
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r11d,%ecx
  movzbl %al,%edx
  add    $0x1,%rdi
  sub    %esi,%ecx
  shl    %cl,%edx
  or     %edx,%r9d
  mov    %r9b,(%r8)
  cmp    %rdi,%r10
  jne    L4
L13:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  ret
```

assistant: ```c
void base32tobyte(const char *str, unsigned char *bin, int len) {
  const char *e = str + len;
  unsigned shift = 0;
  unsigned char b;
  for (; str < e; str++) {
    b = ((*str) < 'A' ? (*str) - '2' + 26 : ((*str) & ~0x20) - 'A');
    shift = (shift + 5) % 8;
    if (shift < 5) {
      *bin++ |= (b >> shift);
    }
    *bin |= b << (8 - shift);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((__visibility__("default"))) int test(int intValue, const char *textValue, char *outTextValue) {
  strcpy(outTextValue, textValue);
  return intValue;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__visibility__("default"))) int test(int intValue, const char *textValue, char *outTextValue) {
  strcpy(outTextValue, textValue);
  return intValue;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__visibility__("default"))) int test(int intValue, const char *textValue, char *outTextValue) {
  strcpy(outTextValue, textValue);
  return intValue;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__visibility__("default"))) int test(int intValue, const char *textValue, char *outTextValue) {
  strcpy(outTextValue, textValue);
  return intValue;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fileExists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jle    L6
  movl   $0x1,-0x14(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int fileExists(const char *filename) {
  int status = 0;
  struct stat buf;
  if (stat(filename, &buf) == 0) {
    if (buf.st_size > 0)
      status = 1;
  }
  return (status);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fileExists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L0
  cmpq   $0x0,(%rsp)
  setg   %al
  movzbl %al,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileExists(const char *filename) {
  int status = 0;
  struct stat buf;
  if (stat(filename, &buf) == 0) {
    if (buf.st_size > 0)
      status = 1;
  }
  return (status);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fileExists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L10
  xor    %eax,%eax
  cmpq   $0x0,(%rsp)
  setg   %al
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileExists(const char *filename) {
  int status = 0;
  struct stat buf;
  if (stat(filename, &buf) == 0) {
    if (buf.st_size > 0)
      status = 1;
  }
  return (status);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fileExists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
  xor    %eax,%eax
  cmpq   $0x0,(%rsp)
  setg   %al
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileExists(const char *filename) {
  int status = 0;
  struct stat buf;
  if (stat(filename, &buf) == 0) {
    if (buf.st_size > 0)
      status = 1;
  }
  return (status);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gui_send_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x818(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <string_to_hex@plt>
  lea    -0x410(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: hex%s

assistant: ```c
int gui_send_data(char *tx_data_in) {
  char tx_data[1024];
  char temp[1024];
  string_to_hex(temp, tx_data_in);
  sprintf(tx_data, "hex%s", temp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gui_send_data>:
  endbr64
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    0x400(%rsp),%rbx
  mov    %rbx,%rdi
  call   <string_to_hex@plt>
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x810,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string

tool: D2: hex%s

assistant: ```c
int gui_send_data(char *tx_data_in) {
  char tx_data[1024];
  char temp[1024];
  string_to_hex(temp, tx_data_in);
  sprintf(tx_data, "hex%s", temp);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gui_send_data>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    0x400(%rsp),%r12
  mov    %r12,%rdi
  call   <string_to_hex@plt>
  mov    %rsp,%rdi
  mov    %r12,%rdx
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x810,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: hex%s

assistant: ```c
int gui_send_data(char *tx_data_in) {
  char tx_data[1024];
  char temp[1024];
  string_to_hex(temp, tx_data_in);
  sprintf(tx_data, "hex%s", temp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gui_send_data>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    0x400(%rsp),%r12
  mov    %r12,%rdi
  call   <string_to_hex@plt>
  mov    %rsp,%rdi
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  call   <sprintf@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x810,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: hex%s

assistant: ```c
int gui_send_data(char *tx_data_in) {
  char tx_data[1024];
  char temp[1024];
  string_to_hex(temp, tx_data_in);
  sprintf(tx_data, "hex%s", temp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basic_authentication_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shl    $0x2,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <concat_strings@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D19: %s:%s

tool: D6: Basic 

assistant: ```c
char *basic_authentication_encode(const char *user, const char *passwd) {
  char *t1, *t2;
  int len1 = strlen(user) + 1 + strlen(passwd);
  t1 = (char *)alloca(len1 + 1);
  sprintf(t1, "%s:%s", user, passwd);
  t2 = (char *)alloca((4 * (((len1) + 2) / 3)) + 1);
  base64_encode(t1, len1, t2);
  return concat_strings("Basic ", t2, (char *)0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<basic_authentication_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%r12d
  lea    0x1(%r12),%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    0x2(%r12),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x1(,%rax,4),%edi
  call   <alloca@plt>
  mov    %rax,%r13
  mov    %rax,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <base64_encode@plt>
  mov    $0x0,%edx
  mov    %r13,%rsi
  lea    D1(%rip),%rdi
  call   <concat_strings@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string

tool: D5: %s:%s

tool: D1: Basic 

assistant: ```c
char *basic_authentication_encode(const char *user, const char *passwd) {
  char *t1, *t2;
  int len1 = strlen(user) + 1 + strlen(passwd);
  t1 = (char *)alloca(len1 + 1);
  sprintf(t1, "%s:%s", user, passwd);
  t2 = (char *)alloca((4 * (((len1) + 2) / 3)) + 1);
  base64_encode(t1, len1, t2);
  return concat_strings("Basic ", t2, (char *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<basic_authentication_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    0x1(%r13,%rax,1),%r14d
  lea    0x1(%r14),%edi
  call   <alloca@plt>
  mov    %r15,%rcx
  mov    %r12,%rdx
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  lea    0x2(%r14),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    0x1(,%rax,4),%edi
  call   <alloca@plt>
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  call   <base64_encode@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  lea    D19(%rip),%rdi
  call   <concat_strings@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  lea    -0x20(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D15: %s:%s

tool: D19: Basic 

assistant: ```c
char *basic_authentication_encode(const char *user, const char *passwd) {
  char *t1, *t2;
  int len1 = strlen(user) + 1 + strlen(passwd);
  t1 = (char *)alloca(len1 + 1);
  sprintf(t1, "%s:%s", user, passwd);
  t2 = (char *)alloca((4 * (((len1) + 2) / 3)) + 1);
  base64_encode(t1, len1, t2);
  return concat_strings("Basic ", t2, (char *)0);
}
```