ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xor_bytes>:
  endbr64
  mov    %rsi,%r8
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  test   %rcx,%rcx
  je     L56
  lea    0x4(%rsi),%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  seta   %cl
  cmp    $0x1,%rdx
  setne  %al
  test   %al,%cl
  je     L14
  lea    0x4(%r8),%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L14
  lea    -0x1(%rdx),%rax
  cmp    $0x2,%rax
  jbe    L5
  mov    %rdx,%rcx
  xor    %eax,%eax
  shr    $0x2,%rcx
  shl    $0x4,%rcx
  nopl   (%rax)
L43:
  movdqu (%r8,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L43
  mov    %rdx,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%dl
  je     L56
  sub    %rax,%rdx
  cmp    $0x1,%rdx
  je     L0
L69:
  movq   (%r8,%rax,4),%xmm0
  movq   (%rsi,%rax,4),%xmm1
  mov    %rdx,%rcx
  and    $0xfffffffffffffffe,%rcx
  pxor   %xmm1,%xmm0
  movq   %xmm0,(%rdi,%rax,4)
  add    %rcx,%rax
  cmp    %rcx,%rdx
  je     L56
L0:
  mov    (%r8,%rax,4),%edx
  xor    (%rsi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L49:
  mov    (%r8,%rax,4),%ecx
  xor    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L49
L56:
  ret
L5:
  xor    %eax,%eax
  jmp    L69
```

assistant: ```c
void xor_bytes(uint8_t *out, const uint8_t *a, const uint8_t *b, const size_t len) {
  for (size_t i = 0; i < len; ++i) {
    out[i] = a[i] ^ b[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<localArrayTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void localArrayTest() {
  char *p = (char *)malloc(12);
  char *ArrayL[12];
  ArrayL[0] = p;
}
```
user: What is the c source code of the assembly code below?

```asm
<localArrayTest>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void localArrayTest() {
  char *p = (char *)malloc(12);
  char *ArrayL[12];
  ArrayL[0] = p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<localArrayTest>:
  endbr64
  mov    $0xc,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
void localArrayTest() {
  char *p = (char *)malloc(12);
  char *ArrayL[12];
  ArrayL[0] = p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %esi,-0xe8(%rbp)
  mov    %rdx,-0xf0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xe8(%rbp),%eax
  mov    %eax,-0xd8(%rbp)
  movl   $0x0,-0xd4(%rbp)
  jmp    L48
L11:
  mov    -0xd4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xd4(%rbp)
  cltq
  mov    -0xd8(%rbp),%edx
  mov    %edx,-0xd0(%rbp,%rax,4)
  mov    -0xd8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xf0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xd8(%rbp)
L48:
  mov    -0xd8(%rbp),%eax
  cmp    -0xe4(%rbp),%eax
  jne    L11
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd8(%rbp),%edx
  mov    %edx,-0xd0(%rbp,%rax,4)
  jmp    L19
L46:
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0xd4(%rbp)
L19:
  cmpl   $0x0,-0xd4(%rbp)
  jg     L46
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D16: %d -> 

tool: D4: %d


assistant: ```c
void print_path(int start, int stop, int precede[]) {
  int current = stop;
  int i = 0;
  int number_buffer[50];
  while (current != start) {
    number_buffer[i++] = current;
    current = precede[current];
  }
  number_buffer[i] = current;
  for (; i > 0; i--) {
    printf("%d -> ", number_buffer[i]);
  }
  printf("%d\n", number_buffer[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  cmp    %edi,%esi
  je     L17
  mov    $0x1,%eax
L59:
  mov    %eax,%ecx
  mov    %esi,-0x4(%rsp,%rax,4)
  movslq %esi,%rsi
  mov    (%rdx,%rsi,4),%esi
  mov    %rax,%r8
  add    $0x1,%rax
  cmp    %esi,%edi
  jne    L59
  movslq %ecx,%rax
  mov    %esi,(%rsp,%rax,4)
  test   %ecx,%ecx
  jle    L8
  mov    %rax,%rcx
  shl    $0x2,%rcx
  lea    (%rsp,%rcx,1),%rbx
  lea    -0x4(%rsp,%rcx,1),%rbp
  lea    -0x1(%r8),%eax
  shl    $0x2,%rax
  sub    %rax,%rbp
  lea    D12(%rip),%r12
L54:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L54
  mov    $0x0,%ecx
L8:
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %edi,(%rsp)
  mov    $0x0,%ecx
  jmp    L8
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: string

tool: D12: %d -> 

tool: D1: %d


assistant: ```c
void print_path(int start, int stop, int precede[]) {
  int current = stop;
  int i = 0;
  int number_buffer[50];
  while (current != start) {
    number_buffer[i++] = current;
    current = precede[current];
  }
  number_buffer[i] = current;
  for (; i > 0; i--) {
    printf("%d -> ", number_buffer[i]);
  }
  printf("%d\n", number_buffer[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_path>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  cmp    %edi,%esi
  je     L30
  mov    $0x1,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L29:
  mov    %esi,-0x4(%rbp,%rax,4)
  movslq %esi,%rsi
  mov    %eax,%ebx
  add    $0x1,%rax
  mov    (%rdx,%rsi,4),%esi
  cmp    %esi,%r8d
  jne    L29
  movslq %ebx,%rax
  sub    $0x1,%ebx
  lea    D8(%rip),%r12
  mov    %esi,(%rsp,%rax,4)
  movslq %ebx,%rbx
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp,%rbx,4),%esi
  sub    $0x1,%rbx
L46:
  mov    %r12,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L0
  mov    (%rsp),%r8d
L30:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xd0,%rsp
  mov    %r8d,%esi
  lea    D13(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D8: %d -> 

tool: D13: %d


assistant: ```c
void print_path(int start, int stop, int precede[]) {
  int current = stop;
  int i = 0;
  int number_buffer[50];
  while (current != start) {
    number_buffer[i++] = current;
    current = precede[current];
  }
  number_buffer[i] = current;
  for (; i > 0; i--) {
    printf("%d -> ", number_buffer[i]);
  }
  printf("%d\n", number_buffer[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_path>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  cmp    %edi,%esi
  je     L5
  mov    $0x1,%eax
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L11:
  mov    %esi,-0x4(%rbx,%rax,4)
  movslq %esi,%rsi
  mov    %eax,%ecx
  add    $0x1,%rax
  mov    (%rdx,%rsi,4),%esi
  cmp    %esi,%r8d
  jne    L11
  movslq %ecx,%rax
  lea    D0(%rip),%r12
  mov    %r8d,(%rsp,%rax,4)
  shl    $0x2,%rax
  lea    -0x4(%rsp,%rax,1),%rbp
  add    %rax,%rbx
  lea    -0x1(%rcx),%eax
  shl    $0x2,%rax
  sub    %rax,%rbp
  nopl   0x0(%rax)
L34:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L34
  mov    (%rsp),%r8d
L5:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0xd0,%rsp
  mov    %r8d,%esi
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D0: %d -> 

tool: D2: %d


assistant: ```c
void print_path(int start, int stop, int precede[]) {
  int current = stop;
  int i = 0;
  int number_buffer[50];
  while (current != start) {
    number_buffer[i++] = current;
    current = precede[current];
  }
  number_buffer[i] = current;
  for (; i > 0; i--) {
    printf("%d -> ", number_buffer[i]);
  }
  printf("%d\n", number_buffer[i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sse2_blkxor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  shr    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L19
L0:
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x30(%rbp),%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    -0x28(%rbp),%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,(%rbx)
  addq   $0x1,-0x30(%rbp)
L19:
  mov    -0x30(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L0
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void sse2_blkxor(void *dest, const void *src, size_t len) {
  __m128i *D = dest;
  const __m128i *S = src;
  size_t L = len / 16;
  size_t i;
  for (i = 0; i < L; i++)
    D[i] = _mm_xor_si128(D[i], S[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sse2_blkxor>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  shr    $0x4,%r13
  cmp    $0xf,%rdx
  jbe    L7
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
L13:
  mov    (%r12,%rbx,4),%esi
  mov    0x0(%rbp,%rbx,4),%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L13
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sse2_blkxor(void *dest, const void *src, size_t len) {
  __m128i *D = dest;
  const __m128i *S = src;
  size_t L = len / 16;
  size_t i;
  for (i = 0; i < L; i++)
    D[i] = _mm_xor_si128(D[i], S[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<sse2_blkxor>:
  endbr64
  shr    $0x4,%rdx
  je     L2
  push   %r12
  lea    (%rsi,%rdx,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%esi
  mov    0x0(%rbp),%edi
  add    $0x4,%rbx
  add    $0x4,%rbp
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L2:
  ret
```

assistant: ```c
void sse2_blkxor(void *dest, const void *src, size_t len) {
  __m128i *D = dest;
  const __m128i *S = src;
  size_t L = len / 16;
  size_t i;
  for (i = 0; i < L; i++)
    D[i] = _mm_xor_si128(D[i], S[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sse2_blkxor>:
  endbr64
  shr    $0x4,%rdx
  je     L17
  push   %r12
  lea    (%rsi,%rdx,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%esi
  mov    0x0(%rbp),%edi
  add    $0x4,%rbx
  add    $0x4,%rbp
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L17:
  ret
```

assistant: ```c
void sse2_blkxor(void *dest, const void *src, size_t len) {
  __m128i *D = dest;
  const __m128i *S = src;
  size_t L = len / 16;
  size_t i;
  for (i = 0; i < L; i++)
    D[i] = _mm_xor_si128(D[i], S[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FileString_GetExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
L10:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int FileString_GetExtension(char *str) {
  int dotPos = -1;
  char *strSrc = str;
  while (*strSrc) {
    if (*strSrc == '.')
      dotPos = (int)(strSrc - str);
    strSrc++;
  }
  return dotPos;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FileString_GetExtension>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L13
  mov    %rdi,%rax
  mov    $0xffffffff,%ecx
L18:
  mov    %rax,%rsi
  sub    %rdi,%rsi
  cmp    $0x2e,%dl
  cmove  %esi,%ecx
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L18
L17:
  mov    %ecx,%eax
  ret
L13:
  mov    $0xffffffff,%ecx
  jmp    L17
```

assistant: ```c
int FileString_GetExtension(char *str) {
  int dotPos = -1;
  char *strSrc = str;
  while (*strSrc) {
    if (*strSrc == '.')
      dotPos = (int)(strSrc - str);
    strSrc++;
  }
  return dotPos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FileString_GetExtension>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
  mov    %rdi,%rax
  mov    $0xffffffff,%r8d
  nopl   0x0(%rax)
L6:
  mov    %rax,%rcx
  sub    %rdi,%rcx
  cmp    $0x2e,%dl
  cmove  %ecx,%r8d
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L12:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int FileString_GetExtension(char *str) {
  int dotPos = -1;
  char *strSrc = str;
  while (*strSrc) {
    if (*strSrc == '.')
      dotPos = (int)(strSrc - str);
    strSrc++;
  }
  return dotPos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FileString_GetExtension>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  mov    %rdi,%rax
  mov    $0xffffffff,%r8d
  nopl   0x0(%rax)
L6:
  mov    %rax,%rcx
  sub    %rdi,%rcx
  cmp    $0x2e,%dl
  cmove  %ecx,%r8d
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L18:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int FileString_GetExtension(char *str) {
  int dotPos = -1;
  char *strSrc = str;
  while (*strSrc) {
    if (*strSrc == '.')
      dotPos = (int)(strSrc - str);
    strSrc++;
  }
  return dotPos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Interp2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  andl   $0xfcfcfc,-0xc(%rbp)
  andl   $0xfcfcfc,-0x10(%rbp)
  andl   $0xfcfcfc,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Interp2(unsigned char *pc, int c1, int c2, int c3) {
  c1 &= 0xfcfcfc;
  c2 &= 0xfcfcfc;
  c3 &= 0xfcfcfc;
  *((int *)pc) = (c1 * 2 + c2 + c3) >> 2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Interp2>:
  endbr64
  and    $0xfcfcfc,%esi
  and    $0xfcfcfc,%edx
  lea    (%rdx,%rsi,2),%eax
  and    $0xfcfcfc,%ecx
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Interp2(unsigned char *pc, int c1, int c2, int c3) {
  c1 &= 0xfcfcfc;
  c2 &= 0xfcfcfc;
  c3 &= 0xfcfcfc;
  *((int *)pc) = (c1 * 2 + c2 + c3) >> 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<Interp2>:
  endbr64
  and    $0xfcfcfc,%esi
  and    $0xfcfcfc,%edx
  and    $0xfcfcfc,%ecx
  lea    (%rdx,%rsi,2),%eax
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Interp2(unsigned char *pc, int c1, int c2, int c3) {
  c1 &= 0xfcfcfc;
  c2 &= 0xfcfcfc;
  c3 &= 0xfcfcfc;
  *((int *)pc) = (c1 * 2 + c2 + c3) >> 2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Interp2>:
  endbr64
  and    $0xfcfcfc,%esi
  and    $0xfcfcfc,%edx
  and    $0xfcfcfc,%ecx
  lea    (%rdx,%rsi,2),%eax
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Interp2(unsigned char *pc, int c1, int c2, int c3) {
  c1 &= 0xfcfcfc;
  c2 &= 0xfcfcfc;
  c3 &= 0xfcfcfc;
  *((int *)pc) = (c1 * 2 + c2 + c3) >> 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gpsatol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L2:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <gpsisdigit@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long gpsatol(const char *str) {
  long ret = 0;
  while (gpsisdigit(*str))
    ret = 10 * ret + *str++ - '0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gpsatol>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L11
L19:
  add    $0x1,%rbx
  lea    0x0(%rbp,%rbp,4),%rdx
  movsbq -0x1(%rbx),%rax
  lea    -0x30(%rax,%rdx,2),%rbp
L11:
  movsbl (%rbx),%edi
  call   <gpsisdigit@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long gpsatol(const char *str) {
  long ret = 0;
  while (gpsisdigit(*str))
    ret = 10 * ret + *str++ - '0';
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gpsatol>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L5:
  movsbq (%rbx),%rax
  lea    (%r12,%r12,4),%rdx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12
L0:
  movsbl (%rbx),%edi
  call   <gpsisdigit@plt>
  test   %rax,%rax
  jne    L5
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
long gpsatol(const char *str) {
  long ret = 0;
  while (gpsisdigit(*str))
    ret = 10 * ret + *str++ - '0';
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gpsatol>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L8:
  movsbq (%rbx),%rax
  lea    (%r12,%r12,4),%rdx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12
L9:
  movsbl (%rbx),%edi
  call   <gpsisdigit@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
long gpsatol(const char *str) {
  long ret = 0;
  while (gpsisdigit(*str))
    ret = 10 * ret + *str++ - '0';
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L10
  mov    -0x4(%rbp),%eax
  jmp    L16
L10:
  mov    -0x8(%rbp),%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b) {
    return a;
  } else {
    return b;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b) {
    return a;
  } else {
    return b;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b) {
    return a;
  } else {
    return b;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b) {
    return a;
  } else {
    return b;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timespec_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rsi,%rax
  mov    %edi,%r8d
  mov    %r8,%rsi
  mov    %r9,%rdi
  mov    %rax,%rdi
  mov    %rsi,-0x30(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %edx,%eax
  mov    %rcx,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x40(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    $0x3b9ac9ff,%eax
  jle    L5
  mov    -0x20(%rbp),%eax
  sub    $0x3b9aca00,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rcx
  mov    %rdx,%rbx
  mov    %ecx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec a, struct timespec b) {
  struct timespec ret;
  ret.tv_sec = a.tv_sec + b.tv_sec;
  ret.tv_nsec = a.tv_nsec + b.tv_nsec;
  if (ret.tv_nsec > 999999999) {
    ret.tv_nsec -= 999999999 + 1;
    ret.tv_sec += 1;
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<timespec_add>:
  endbr64
  mov    %edx,%eax
  lea    (%rsi,%rcx,1),%rdx
  add    %edi,%eax
  cmp    $0x3b9ac9ff,%eax
  jle    L5
  sub    $0x3b9aca00,%eax
  add    $0x1,%rdx
L5:
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec a, struct timespec b) {
  struct timespec ret;
  ret.tv_sec = a.tv_sec + b.tv_sec;
  ret.tv_nsec = a.tv_nsec + b.tv_nsec;
  if (ret.tv_nsec > 999999999) {
    ret.tv_nsec -= 999999999 + 1;
    ret.tv_sec += 1;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timespec_add>:
  endbr64
  mov    %edx,%r8d
  lea    (%rsi,%rcx,1),%rdx
  lea    (%rdi,%r8,1),%eax
  cmp    $0x3b9ac9ff,%eax
  jle    L8
  sub    $0x3b9aca00,%eax
  add    $0x1,%rdx
L8:
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec a, struct timespec b) {
  struct timespec ret;
  ret.tv_sec = a.tv_sec + b.tv_sec;
  ret.tv_nsec = a.tv_nsec + b.tv_nsec;
  if (ret.tv_nsec > 999999999) {
    ret.tv_nsec -= 999999999 + 1;
    ret.tv_sec += 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<timespec_add>:
  endbr64
  mov    %edx,%r8d
  lea    (%rsi,%rcx,1),%rdx
  lea    (%rdi,%r8,1),%eax
  cmp    $0x3b9ac9ff,%eax
  jle    L6
  sub    $0x3b9aca00,%eax
  add    $0x1,%rdx
L6:
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec a, struct timespec b) {
  struct timespec ret;
  ret.tv_sec = a.tv_sec + b.tv_sec;
  ret.tv_nsec = a.tv_nsec + b.tv_nsec;
  if (ret.tv_nsec > 999999999) {
    ret.tv_nsec -= 999999999 + 1;
    ret.tv_sec += 1;
  }
  return ret;
}
```