ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  ja     L64
  lea    0x10(%rsp),%rdi
  mov    $0x30,%edx
  mov    $0xffffffff,%esi
  call   <memset@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L10
  mov    $0x0,%ebx
  lea    D38(%rip),%rbp
L81:
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  js     L32
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    0x8(%rsp),%rdi
  cmp    %rdi,%rax
  jl     L32
  call   <find_digits@plt>
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jg     L81
L10:
  lea    0x10(%rsp),%rbx
  lea    0x40(%rsp),%r12
  lea    D10(%rip),%rbp
L44:
  mov    (%rbx),%esi
  cmp    $0xffffffff,%esi
  je     L28
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L44
  jmp    L28
L64:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L32:
  mov    0x8(%rsp),%esi
  lea    D47(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
data_type: string
name: parse_data
arguments: tag: D38
data_type: string
name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D29
data_type: string
name: parse_data
arguments: tag: D47
data_type: string

tool: D25: %d

tool: D38: %lld

tool: D10: %d


tool: D29: error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d


tool: D47: error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).


assistant: ```c
int main() {
  signed long long value = 0;
  int t = 0;
  int i;
  int count_arr[12];
  scanf("%d", &t);
  if ((t < 1) || (t > 15)) {
    printf("error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d\n", t);
    return 0;
  }
  memset(count_arr, -1, sizeof(count_arr));
  for (i = 0; i < t; i++) {
    scanf("%lld", &value);
    if ((value < 0) || (value > pow(10, 10))) {
      printf("error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).\n", value);
      return 0;
    }
    count_arr[i] = find_digits(value);
  }
  for (i = 0; i < (sizeof(count_arr) / sizeof(int)); i++) {
    if (count_arr[i] == -1) {
      return 0;
    }
    printf("%d\n", count_arr[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  ja     L18
  lea    0x10(%rsp),%rbp
  or     $0xffffffff,%esi
  mov    $0x30,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L64
  xor    %ebx,%ebx
  lea    0x8(%rsp),%r13
  lea    D48(%rip),%r12
  jmp    L23
L61:
  mov    $0xa,%edi
  mov    $0xa,%esi
  call   <pow@plt>
  mov    0x8(%rsp),%rdi
  cmp    %rdi,%rax
  jl     L35
  call   <find_digits@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jle    L64
L23:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  jns    L61
  mov    0x8(%rsp),%rdi
L35:
  mov    %edi,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L64:
  lea    0x40(%rsp),%r12
  lea    D8(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L98:
  mov    0x0(%rbp),%esi
  cmp    $0xffffffff,%esi
  je     L0
  mov    %rbx,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L98
  jmp    L0
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string
name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D37
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D4: %d

tool: D48: %lld

tool: D37: error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).


tool: D27: error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d


tool: D8: %d


assistant: ```c
int main() {
  signed long long value = 0;
  int t = 0;
  int i;
  int count_arr[12];
  scanf("%d", &t);
  if ((t < 1) || (t > 15)) {
    printf("error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d\n", t);
    return 0;
  }
  memset(count_arr, -1, sizeof(count_arr));
  for (i = 0; i < t; i++) {
    scanf("%lld", &value);
    if ((value < 0) || (value > pow(10, 10))) {
      printf("error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).\n", value);
      return 0;
    }
    count_arr[i] = find_digits(value);
  }
  for (i = 0; i < (sizeof(count_arr) / sizeof(int)); i++) {
    if (count_arr[i] == -1) {
      return 0;
    }
    printf("%d\n", count_arr[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  ja     L86
  lea    0x10(%rsp),%rbp
  or     $0xffffffff,%esi
  mov    $0x30,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L48
  xor    %ebx,%ebx
  lea    0x8(%rsp),%r13
  lea    D34(%rip),%r12
  jmp    L21
L40:
  mov    $0xa,%edi
  mov    $0xa,%esi
  call   <pow@plt>
  mov    0x8(%rsp),%rdi
  cmp    %rdi,%rax
  jl     L56
  call   <find_digits@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jle    L48
L21:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  jns    L40
  mov    0x8(%rsp),%rdi
L56:
  mov    %edi,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
L59:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L86:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L48:
  lea    0x40(%rsp),%r12
  lea    D26(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L24:
  mov    0x0(%rbp),%esi
  cmp    $0xffffffff,%esi
  je     L59
  mov    %rbx,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L24
  jmp    L59
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string

tool: D7: %d

tool: D34: %lld

tool: D38: error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).


tool: D8: error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d


tool: D26: %d


assistant: ```c
int main() {
  signed long long value = 0;
  int t = 0;
  int i;
  int count_arr[12];
  scanf("%d", &t);
  if ((t < 1) || (t > 15)) {
    printf("error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d\n", t);
    return 0;
  }
  memset(count_arr, -1, sizeof(count_arr));
  for (i = 0; i < t; i++) {
    scanf("%lld", &value);
    if ((value < 0) || (value > pow(10, 10))) {
      printf("error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).\n", value);
      return 0;
    }
    count_arr[i] = find_digits(value);
  }
  for (i = 0; i < (sizeof(count_arr) / sizeof(int)); i++) {
    if (count_arr[i] == -1) {
      return 0;
    }
    printf("%d\n", count_arr[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xrop3_144_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_144_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xrop3_144_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  and    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_144_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_144_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  xor    $0xffffff00,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_144_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return stk1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_144_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  xor    $0xffffff00,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_144_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mycalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mycalloc(size_t nmemb, size_t size) {
  void *Result = NULL;
  Result = malloc(nmemb * size);
  if (NULL != Result) {
    memset(Result, 0x00, nmemb * size);
  }
  return Result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mycalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *mycalloc(size_t nmemb, size_t size) {
  void *Result = NULL;
  Result = malloc(nmemb * size);
  if (NULL != Result) {
    memset(Result, 0x00, nmemb * size);
  }
  return Result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mycalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *mycalloc(size_t nmemb, size_t size) {
  void *Result = NULL;
  Result = malloc(nmemb * size);
  if (NULL != Result) {
    memset(Result, 0x00, nmemb * size);
  }
  return Result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mycalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *mycalloc(size_t nmemb, size_t size) {
  void *Result = NULL;
  Result = malloc(nmemb * size);
  if (NULL != Result) {
    memset(Result, 0x00, nmemb * size);
  }
  return Result;
}
```
user: What is the c source code of the assembly code below?

```asm
<permutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L28
L9:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L20
L29:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L29
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned *permutation(int size, int seed) {
  unsigned *array = malloc(sizeof(unsigned) * size);
  for (int i = 0; i < size; i++)
    array[i] = i;
  srand(seed);
  for (int i = 0; i < size; i++) {
    int r1 = rand() % size;
    int r2 = rand() % size;
    int tmp = array[r1];
    array[r1] = array[r2];
    array[r2] = tmp;
  }
  return array;
}
```
user: What is the c source code of the assembly code below?

```asm
<permutation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L10
  mov    %ebx,%edx
  mov    $0x0,%eax
L8:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
  mov    %r12d,%edi
  call   <srand@plt>
  mov    $0x0,%r12d
L18:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%r13d
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %r13d,%r13
  lea    0x0(%rbp,%r13,4),%rcx
  mov    (%rcx),%esi
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jne    L18
L33:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %r12d,%edi
  call   <srand@plt>
  jmp    L33
```

assistant: ```c
unsigned *permutation(int size, int seed) {
  unsigned *array = malloc(sizeof(unsigned) * size);
  for (int i = 0; i < size; i++)
    array[i] = i;
  srand(seed);
  for (int i = 0; i < size; i++) {
    int r1 = rand() % size;
    int r2 = rand() % size;
    int tmp = array[r1];
    array[r1] = array[r2];
    array[r2] = tmp;
  }
  return array;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<permutation>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x0(,%rbp,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L22
  mov    %rbp,%rbx
  xor    %eax,%eax
  nopl   0x0(%rax)
L14:
  mov    %eax,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L14
  mov    %r13d,%edi
  xor    %r13d,%r13d
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%rbp
  call   <rand@plt>
  lea    (%r12,%rbp,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %r13d,%ebx
  jne    L25
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  mov    %r13d,%edi
  call   <srand@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned *permutation(int size, int seed) {
  unsigned *array = malloc(sizeof(unsigned) * size);
  for (int i = 0; i < size; i++)
    array[i] = i;
  srand(seed);
  for (int i = 0; i < size; i++) {
    int r1 = rand() % size;
    int r2 = rand() % size;
    int tmp = array[r1];
    array[r1] = array[r2];
    array[r2] = tmp;
  }
  return array;
}
```
user: Translate the below assembly code into C programming language:

```asm
<permutation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L51
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L66
  mov    %ebx,%edx
  movdqa D9(%rip),%xmm0
  movdqa D19(%rip),%xmm2
  mov    %r13,%rax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r13,%rdx
L28:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L28
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L31
L61:
  movslq %eax,%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jle    L31
  add    $0x2,%eax
  mov    %edx,0x4(%r13,%rcx,1)
  cmp    %eax,%ebx
  jle    L31
  mov    %eax,0x8(%r13,%rcx,1)
L31:
  mov    %ebp,%edi
  xor    %r12d,%r12d
  call   <srand@plt>
  nopl   0x0(%rax)
L48:
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%rbp
  call   <rand@plt>
  lea    0x0(%r13,%rbp,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %r12d,%ebx
  jne    L48
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %ebp,%edi
  call   <srand@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  xor    %eax,%eax
  jmp    L61
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D19
type_guessed: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D19": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
unsigned *permutation(int size, int seed) {
  unsigned *array = malloc(sizeof(unsigned) * size);
  for (int i = 0; i < size; i++)
    array[i] = i;
  srand(seed);
  for (int i = 0; i < size; i++) {
    int r1 = rand() % size;
    int r2 = rand() % size;
    int tmp = array[r1];
    array[r1] = array[r2];
    array[r2] = tmp;
  }
  return array;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_float_compare_descending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L41
  ucomiss %xmm1,%xmm0
  jne    L41
  mov    $0x0,%eax
  jmp    L46
L41:
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L33
  mov    $0x1,%eax
  jmp    L46
L33:
  mov    $0xffffffff,%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int my_float_compare_descending(const void *xv, const void *yv) {
  float *x, *y;
  x = (float *)xv;
  y = (float *)yv;
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return 1;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<my_float_compare_descending>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L17
  mov    $0x0,%eax
  je     L3
L17:
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L3:
  ret
```

assistant: ```c
int my_float_compare_descending(const void *xv, const void *yv) {
  float *x, *y;
  x = (float *)xv;
  y = (float *)yv;
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return 1;
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_float_compare_descending>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L7
  mov    $0x0,%eax
  je     L12
L7:
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
L12:
  ret
```

assistant: ```c
int my_float_compare_descending(const void *xv, const void *yv) {
  float *x, *y;
  x = (float *)xv;
  y = (float *)yv;
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return 1;
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_float_compare_descending>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L10
  mov    $0x0,%eax
  je     L6
L10:
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
L6:
  ret
```

assistant: ```c
int my_float_compare_descending(const void *xv, const void *yv) {
  float *x, *y;
  x = (float *)xv;
  y = (float *)yv;
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return 1;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  leave
  ret
```

assistant: ```c
char *strtok(char *s, const char *b) {
  static char *under_rock;
  return strtok_r(s, b, &under_rock);
}
```