ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IsAPowerOfTwo>:
  endbr64
  cmp    $0x2,%edi
  je     L14
  test   $0x1,%dil
  jne    L56
  mov    $0x1,%ecx
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L34:
  test   $0x1,%al
  jne    L56
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  je     L14
L58:
  mov    %edi,%eax
  shr    %cl,%eax
  cmp    $0x2,%eax
  jne    L34
L14:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
  ret
```

assistant: ```c
int IsAPowerOfTwo(unsigned int a) {
  int i;
  for (i = 0; i < 8 * sizeof(unsigned int); i++) {
    if ((a >> i) == 2) {
      return 1;
    } else if ((a >> i) % 2 != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IsAPowerOfTwo>:
  endbr64
  cmp    $0x2,%edi
  je     L16
  test   $0x1,%dil
  jne    L55
  mov    $0x1,%ecx
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L57:
  test   $0x1,%al
  jne    L55
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  je     L16
L19:
  mov    %edi,%eax
  shr    %cl,%eax
  cmp    $0x2,%eax
  jne    L57
L16:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  xor    %eax,%eax
  ret
```

assistant: ```c
int IsAPowerOfTwo(unsigned int a) {
  int i;
  for (i = 0; i < 8 * sizeof(unsigned int); i++) {
    if ((a >> i) == 2) {
      return 1;
    } else if ((a >> i) % 2 != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L8
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L20
  jmp    L23
L31:
  nop
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1++ == *str2++) {
    if (*str1 == '\0') {
      break;
    }
  }
  return *str1 - *str2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcmp>:
  endbr64
L3:
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  cmp    %al,-0x1(%rdi)
  jne    L19
  cmpb   $0x0,(%rdi)
  jne    L3
L19:
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1++ == *str2++) {
    if (*str1 == '\0') {
      break;
    }
  }
  return *str1 - *str2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  jmp    L11
  nopl   0x0(%rax)
L18:
  test   %al,%al
  je     L9
L11:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %eax,%edx
  movsbl (%rdi),%eax
  cmp    %dl,-0x1(%rsi)
  je     L18
L9:
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1++ == *str2++) {
    if (*str1 == '\0') {
      break;
    }
  }
  return *str1 - *str2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  jmp    L19
  nopl   0x0(%rax)
L0:
  test   %al,%al
  je     L6
L19:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %eax,%edx
  movsbl (%rdi),%eax
  cmp    %dl,-0x1(%rsi)
  je     L0
L6:
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1++ == *str2++) {
    if (*str1 == '\0') {
      break;
    }
  }
  return *str1 - *str2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TestC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: C

assistant: ```c
void TestC() {
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TestC>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
L2:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L2
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: C

assistant: ```c
void TestC() {
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TestC>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  nopl   0x0(%rax)
L7:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: C

assistant: ```c
void TestC() {
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<TestC>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  nopl   0x0(%rax)
L1:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: C

assistant: ```c
void TestC() {
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AL_heap_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <build_max_heapify@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L12:
  mov    -0x20(%rbp),%rax
  imul   -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  subq   $0x1,-0x10(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <max_heapify@plt>
  subq   $0x1,-0x8(%rbp)
L19:
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void AL_heap_sort(void *arr, size_t size, size_t count, int (*comp)(void *key1, void *key2)) {
  size_t heapsize = build_max_heapify(arr, size, count, comp);
  for (size_t i = count - 1; i >= 1; i--) {
    swap(arr, arr + size * i, size);
    heapsize--;
    max_heapify(arr, size, heapsize, 0, comp);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<AL_heap_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r15
  mov    %rcx,0x8(%rsp)
  call   <build_max_heapify@plt>
  mov    %rax,(%rsp)
  mov    %r15,%r12
  sub    $0x1,%r12
  je     L10
  imul   %rbp,%r12
  add    %r13,%r12
  mov    %rax,%rbx
L17:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    %rbx,%r14
  sub    $0x1,%rbx
  mov    0x8(%rsp),%r8
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <max_heapify@plt>
  sub    %rbp,%r12
  lea    -0x2(%r14,%r15,1),%rax
  cmp    %rax,(%rsp)
  jne    L17
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AL_heap_sort(void *arr, size_t size, size_t count, int (*comp)(void *key1, void *key2)) {
  size_t heapsize = build_max_heapify(arr, size, count, comp);
  for (size_t i = count - 1; i >= 1; i--) {
    swap(arr, arr + size * i, size);
    heapsize--;
    max_heapify(arr, size, heapsize, 0, comp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<AL_heap_sort>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <build_max_heapify@plt>
  mov    %r15,%r9
  mov    %rax,(%rsp)
  sub    $0x1,%r9
  je     L9
  imul   %rbp,%r9
  mov    %rax,%rbx
  lea    (%r12,%r9,1),%r15
L0:
  mov    %r15,%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  mov    %rbx,%r13
  call   <swap@plt>
  sub    $0x1,%rbx
  mov    %r14,%r8
  xor    %ecx,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %rbp,%r15
  call   <max_heapify@plt>
  mov    0x8(%rsp),%rax
  lea    -0x2(%r13,%rax,1),%rax
  cmp    %rax,(%rsp)
  jne    L0
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AL_heap_sort(void *arr, size_t size, size_t count, int (*comp)(void *key1, void *key2)) {
  size_t heapsize = build_max_heapify(arr, size, count, comp);
  for (size_t i = count - 1; i >= 1; i--) {
    swap(arr, arr + size * i, size);
    heapsize--;
    max_heapify(arr, size, heapsize, 0, comp);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AL_heap_sort>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <build_max_heapify@plt>
  mov    %r15,%r9
  mov    %rax,(%rsp)
  sub    $0x1,%r9
  je     L10
  imul   %rbp,%r9
  mov    %rax,%rbx
  lea    (%r12,%r9,1),%r15
L0:
  mov    %r15,%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  mov    %rbx,%r13
  call   <swap@plt>
  sub    $0x1,%rbx
  mov    %r14,%r8
  xor    %ecx,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %rbp,%r15
  call   <max_heapify@plt>
  mov    0x8(%rsp),%rax
  lea    -0x2(%r13,%rax,1),%rax
  cmp    %rax,(%rsp)
  jne    L0
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AL_heap_sort(void *arr, size_t size, size_t count, int (*comp)(void *key1, void *key2)) {
  size_t heapsize = build_max_heapify(arr, size, count, comp);
  for (size_t i = count - 1; i >= 1; i--) {
    swap(arr, arr + size * i, size);
    heapsize--;
    max_heapify(arr, size, heapsize, 0, comp);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x12b,-0x4c8(%rbp)
  jmp    L0
L27:
  lea    -0x4c0(%rbp),%rdx
  mov    -0x4c8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x4c8(%rbp),%eax
  cltq
  mov    -0x4c0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jns    L3
  mov    -0x4c8(%rbp),%eax
  mov    %eax,-0x4c4(%rbp)
  jmp    L50
L3:
  subl   $0x1,-0x4c8(%rbp)
L0:
  cmpl   $0x0,-0x4c8(%rbp)
  jns    L27
L50:
  movl   $0x0,-0x4c8(%rbp)
  jmp    L20
L69:
  mov    -0x4c8(%rbp),%eax
  cltq
  mov    -0x4c0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4c8(%rbp)
L20:
  mov    -0x4c8(%rbp),%eax
  cmp    -0x4c4(%rbp),%eax
  jl     L69
  mov    -0x4c4(%rbp),%eax
  cltq
  mov    -0x4c0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type: string
name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D29
type: string

tool: D23: %d

tool: D2: %d 

tool: D29: %d


assistant: ```c
int main() {
  int inteiros[299], i, stop;
  for (i = 299; i >= 0; i--) {
    scanf("%d", &inteiros[i]);
    if (inteiros[i] < 0) {
      stop = i;
      break;
    }
  }
  for (i = 0; i < stop; i++)
    printf("%d ", inteiros[i]);
  printf("%d\n", inteiros[stop]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  lea    0x4ac(%rsp),%rbx
  mov    $0x12b,%ebp
  lea    D6(%rip),%r12
L16:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rbx)
  js     L9
  sub    $0x1,%ebp
  sub    $0x4,%rbx
  cmp    $0xffffffff,%ebp
  jne    L16
  mov    $0x0,%ebp
L9:
  test   %ebp,%ebp
  jle    L39
  mov    %rsp,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%rsp,%rax,4),%r13
  lea    D12(%rip),%r12
L20:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L20
L39:
  movslq %ebp,%rbp
  mov    (%rsp,%rbp,4),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x4c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string

tool: D6: %d

tool: D12: %d 

tool: D9: %d


assistant: ```c
int main() {
  int inteiros[299], i, stop;
  for (i = 299; i >= 0; i--) {
    scanf("%d", &inteiros[i]);
    if (inteiros[i] < 0) {
      stop = i;
      break;
    }
  }
  for (i = 0; i < stop; i++)
    printf("%d ", inteiros[i]);
  printf("%d\n", inteiros[stop]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x12b,%ebx
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L27:
  sub    $0x1,%rbx
  jb     L66
L13:
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    %r14,%rdi
  movslq %ebx,%r13
  mov    %rbp,%r12
  call   <scanf@plt>
  mov    0x0(%rbp,%rbx,4),%eax
  test   %eax,%eax
  jns    L27
L66:
  test   %r13d,%r13d
  je     L62
  lea    -0x1(%r13),%eax
  add    $0x4,%rbp
  lea    D22(%rip),%rbx
  lea    0x0(%rbp,%rax,4),%r14
  jmp    L56
  nopl   0x0(%rax)
L37:
  add    $0x4,%rbp
L56:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  mov    %rbp,%r12
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L37
L62:
  mov    (%rsp,%r13,4),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x4c0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D22
datatype: string
name: parse_data
arguments: label: D20
datatype: string

tool: D10: %d

tool: D22: %d 

tool: D20: %d


assistant: ```c
int main() {
  int inteiros[299], i, stop;
  for (i = 299; i >= 0; i--) {
    scanf("%d", &inteiros[i]);
    if (inteiros[i] < 0) {
      stop = i;
      break;
    }
  }
  for (i = 0; i < stop; i++)
    printf("%d ", inteiros[i]);
  printf("%d\n", inteiros[stop]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x12b,%ebx
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L32:
  sub    $0x1,%rbx
  jb     L23
L38:
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    %r14,%rdi
  movslq %ebx,%r13
  mov    %rbp,%r12
  call   <scanf@plt>
  mov    0x0(%rbp,%rbx,4),%eax
  test   %eax,%eax
  jns    L32
L23:
  test   %r13d,%r13d
  je     L16
  lea    -0x1(%r13),%eax
  add    $0x4,%rbp
  lea    D24(%rip),%rbx
  lea    0x0(%rbp,%rax,4),%r14
  jmp    L41
  nopl   0x0(%rax)
L66:
  add    $0x4,%rbp
L41:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  mov    %rbp,%r12
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L66
L16:
  mov    (%rsp,%r13,4),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x4c0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string

tool: D10: %d

tool: D24: %d 

tool: D2: %d


assistant: ```c
int main() {
  int inteiros[299], i, stop;
  for (i = 299; i >= 0; i--) {
    scanf("%d", &inteiros[i]);
    if (inteiros[i] < 0) {
      stop = i;
      break;
    }
  }
  for (i = 0; i < stop; i++)
    printf("%d ", inteiros[i]);
  printf("%d\n", inteiros[stop]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ssc_allow_prevent_removal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t ssc_allow_prevent_removal(struct scsi_cmd *cmd) {
  ;
  return 0x00;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssc_allow_prevent_removal>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint8_t ssc_allow_prevent_removal(struct scsi_cmd *cmd) {
  ;
  return 0x00;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ssc_allow_prevent_removal>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t ssc_allow_prevent_removal(struct scsi_cmd *cmd) {
  ;
  return 0x00;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ssc_allow_prevent_removal>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t ssc_allow_prevent_removal(struct scsi_cmd *cmd) {
  ;
  return 0x00;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPermissible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L55
L130:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L124
  mov    $0x0,%eax
  jmp    L132
L124:
  addl   $0x1,-0x4(%rbp)
L55:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L130
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L72
L17:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L63
  mov    $0x0,%eax
  jmp    L132
L63:
  subl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L72:
  cmpl   $0x0,-0x8(%rbp)
  js     L68
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
L68:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L82:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L25
  mov    $0x0,%eax
  jmp    L132
L25:
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x7,-0x8(%rbp)
  jg     L58
  cmpl   $0x0,-0x4(%rbp)
  jns    L82
L58:
  mov    $0x1,%eax
L132:
  pop    %rbp
  ret
```

assistant: ```c
int isPermissible(int board[8][8], int row, int column) {
  int x, y;
  for (y = 0; y < column; y++) {
    if (board[row][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x >= 0 && y >= 0; x--, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x <= 8 - 1 && y >= 0; x++, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  return 1;
}
```