ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test2>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void test2() {
  if ("hi") {
  }
  while ("hello") {
  }
  for (; "howdy";) {
  }
  do {
  } while ("hey");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test2>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void test2() {
  if ("hi") {
  }
  while ("hello") {
  }
  for (; "howdy";) {
  }
  do {
  } while ("hey");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<assemble_21>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x14,%eax
  and    $0x100000,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  and    $0xffe00,%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  shr    $0x7,%eax
  and    $0x180,%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  shr    $0xe,%eax
  and    $0x7c,%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  shr    $0xc,%eax
  and    $0x3,%eax
  or     %edx,%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1fffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long assemble_21(x)
unsigned int x;
{
  unsigned long temp;
  temp = ((x & 1) << 20) | ((x & 0xffe) << 8) | ((x & 0xc000) >> 7) | ((x & 0x1f0000) >> 14) | ((x & 0x003000) >> 12);
  return temp & 0x1fffff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<assemble_21>:
  endbr64
  mov    %edi,%eax
  shl    $0x14,%eax
  and    $0x100000,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  and    $0xffe00,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x7,%edx
  and    $0x180,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0xe,%edx
  and    $0x7c,%edx
  or     %edx,%eax
  shr    $0xc,%edi
  and    $0x3,%edi
  or     %edi,%eax
  mov    %eax,%eax
  ret
```

assistant: ```c
unsigned long assemble_21(x)
unsigned int x;
{
  unsigned long temp;
  temp = ((x & 1) << 20) | ((x & 0xffe) << 8) | ((x & 0xc000) >> 7) | ((x & 0x1f0000) >> 14) | ((x & 0x003000) >> 12);
  return temp & 0x1fffff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<assemble_21>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shl    $0x14,%eax
  shl    $0x8,%edx
  and    $0xffe00,%edx
  and    $0x100000,%eax
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x7,%edx
  and    $0x180,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0xc,%edi
  shr    $0xe,%edx
  and    $0x3,%edi
  and    $0x7c,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned long assemble_21(x)
unsigned int x;
{
  unsigned long temp;
  temp = ((x & 1) << 20) | ((x & 0xffe) << 8) | ((x & 0xc000) >> 7) | ((x & 0x1f0000) >> 14) | ((x & 0x003000) >> 12);
  return temp & 0x1fffff;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<assemble_21>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shl    $0x14,%eax
  shl    $0x8,%edx
  and    $0xffe00,%edx
  and    $0x100000,%eax
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x7,%edx
  and    $0x180,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0xc,%edi
  shr    $0xe,%edx
  and    $0x3,%edi
  and    $0x7c,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned long assemble_21(x)
unsigned int x;
{
  unsigned long temp;
  temp = ((x & 1) << 20) | ((x & 0xffe) << 8) | ((x & 0xc000) >> 7) | ((x & 0x1f0000) >> 14) | ((x & 0x003000) >> 12);
  return temp & 0x1fffff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L17
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D15
type_infered: string

tool: D8: %s: 

tool: D15: %02X 

assistant: ```c
void print_hex(char *title, char *data, size_t size) {
  int i;
  printf("%s: ", title);
  for (i = 0; i < size; i++) {
    printf("%02X ", (unsigned char)data[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_hex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12,%r12
  je     L16
  mov    %rbp,%rbx
  add    %r12,%rbp
  lea    D15(%rip),%r12
L5:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L5
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D3: %s: 

tool: D15: %02X 

assistant: ```c
void print_hex(char *title, char *data, size_t size) {
  int i;
  printf("%s: ", title);
  for (i = 0; i < size; i++) {
    printf("%02X ", (unsigned char)data[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_hex>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L10
  add    %rbx,%rbp
  lea    D18(%rip),%r12
  xchg   %ax,%ax
L16:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L16
L10:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D18
type_guessed: string

tool: D4: %s: 

tool: D18: %02X 

assistant: ```c
void print_hex(char *title, char *data, size_t size) {
  int i;
  printf("%s: ", title);
  for (i = 0; i < size; i++) {
    printf("%02X ", (unsigned char)data[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_hex>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L19
  add    %rbx,%rbp
  lea    D14(%rip),%r12
  xchg   %ax,%ax
L13:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L13
L19:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D14
datatype: string

tool: D16: %s: 

tool: D14: %02X 

assistant: ```c
void print_hex(char *title, char *data, size_t size) {
  int i;
  printf("%s: ", title);
  for (i = 0; i < size; i++) {
    printf("%02X ", (unsigned char)data[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_signed_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <lrand48@plt>
  mov    -0x14(%rbp),%edx
  add    %edx,%edx
  lea    -0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  leave
  ret
```

assistant: ```c
int gen_signed_number(int range) {
  int temp;
  temp = lrand48() % (2 * range - 1);
  return temp - (range - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_signed_number>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <lrand48@plt>
  lea    -0x1(%rbx,%rbx,1),%ecx
  cltd
  idiv   %ecx
  sub    $0x1,%ebx
  mov    %edx,%eax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int gen_signed_number(int range) {
  int temp;
  temp = lrand48() % (2 * range - 1);
  return temp - (range - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_signed_number>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <lrand48@plt>
  lea    -0x1(%rbx,%rbx,1),%ecx
  sub    $0x1,%ebx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int gen_signed_number(int range) {
  int temp;
  temp = lrand48() % (2 * range - 1);
  return temp - (range - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_signed_number>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <lrand48@plt>
  lea    -0x1(%rbx,%rbx,1),%ecx
  sub    $0x1,%ebx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int gen_signed_number(int range) {
  int temp;
  temp = lrand48() % (2 * range - 1);
  return temp - (range - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <CreateBase64StringFromHexString@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string

tool: D17: 49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d

tool: D19: SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t

assistant: ```c
int main(int argc, const char *argv[]) {
  char *hexString = "49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d";
  char *base64String = "SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t";
  char *convertedString = CreateBase64StringFromHexString(hexString, strlen(hexString));
  assert(strcmp(convertedString, base64String) == 0);
  free(convertedString);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <CreateBase64StringFromHexString@plt>
  mov    %rax,%rbx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string

tool: D6: 49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d

tool: D14: SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t

assistant: ```c
int main(int argc, const char *argv[]) {
  char *hexString = "49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d";
  char *base64String = "SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t";
  char *convertedString = CreateBase64StringFromHexString(hexString, strlen(hexString));
  assert(strcmp(convertedString, base64String) == 0);
  free(convertedString);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <CreateBase64StringFromHexString@plt>
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D8: 49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d

tool: D7: SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t

assistant: ```c
int main(int argc, const char *argv[]) {
  char *hexString = "49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d";
  char *base64String = "SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t";
  char *convertedString = CreateBase64StringFromHexString(hexString, strlen(hexString));
  assert(strcmp(convertedString, base64String) == 0);
  free(convertedString);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <CreateBase64StringFromHexString@plt>
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D5: 49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d

tool: D19: SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t

assistant: ```c
int main(int argc, const char *argv[]) {
  char *hexString = "49276d206b696c6c696e6720796f757220627261696e206c696b65206120706f69736f6e6f7573206d757368726f6f6d";
  char *base64String = "SSdtIGtpbGxpbmcgeW91ciBicmFpbiBsaWtlIGEgcG9pc29ub3VzIG11c2hyb29t";
  char *convertedString = CreateBase64StringFromHexString(hexString, strlen(hexString));
  assert(strcmp(convertedString, base64String) == 0);
  free(convertedString);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x32,%eax
  cmp    $0x22,%eax
  ja     L123
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D12(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xd,%eax
  jmp    L78
  mov    $0xc,%eax
  jmp    L78
  mov    $0xb,%eax
  jmp    L78
  mov    $0xa,%eax
  jmp    L78
  mov    $0x9,%eax
  jmp    L78
  mov    $0x8,%eax
  jmp    L78
  mov    $0x7,%eax
  jmp    L78
  mov    $0x6,%eax
  jmp    L78
  mov    $0x5,%eax
  jmp    L78
  mov    $0x4,%eax
  jmp    L78
  mov    $0x3,%eax
  jmp    L78
  mov    $0x2,%eax
  jmp    L78
  mov    $0x1,%eax
  jmp    L78
L123:
  mov    $0x1,%eax
L78:
  pop    %rbp
  ret
```

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<number>:
  endbr64
  sub    $0x32,%edi
  cmp    $0x22,%dil
  ja     L7
  movzbl %dil,%edi
  lea    D6(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xc,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x1,%eax
  ret
L7:
  mov    $0x1,%eax
  ret
  mov    $0xd,%eax
  ret
```

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<number>:
  endbr64
  sub    $0x32,%edi
  mov    $0x1,%eax
  cmp    $0x22,%dil
  ja     L8
  movzbl %dil,%edi
  lea    D4(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L8:
  ret
```

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<number>:
  endbr64
  sub    $0x32,%edi
  mov    $0x1,%eax
  cmp    $0x22,%dil
  ja     L9
  movzbl %dil,%edi
  lea    D1(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L9:
  ret
```

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nextprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L8
L13:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L13
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int nextprime(int v) {
  while (!isprime(v))
    v++;
  return v;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nextprime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L17
L10:
  add    $0x1,%ebx
L17:
  mov    %ebx,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L10
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int nextprime(int v) {
  while (!isprime(v))
    v++;
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nextprime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%r12d
L12:
  mov    %r12d,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L7
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int nextprime(int v) {
  while (!isprime(v))
    v++;
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nextprime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%r12d
L12:
  mov    %r12d,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L8
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int nextprime(int v) {
  while (!isprime(v))
    v++;
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pr_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  jmp    L9
L2:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  mov    $0xfffffff6,%edx
  imul   %edx,%eax
  add    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L2
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pr_dec(int d, char *p, int n) {
  while ((n--) > 0) {
    int dDiv10 = ((d) / 10);
    *p-- = '0' + d - dDiv10 * 10;
    d = dDiv10;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pr_dec>:
  endbr64
  mov    %edi,%ecx
  test   %edx,%edx
  jle    L5
  lea    -0x1(%rdx),%r8d
  not    %r8
  add    %rsi,%r8
  mov    $0xfffffff6,%r9d
L13:
  mov    %ecx,%edi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  sub    $0x1,%rsi
  mov    %edx,%eax
  imul   %r9d,%eax
  lea    0x30(%rax,%rdi,1),%eax
  mov    %al,0x1(%rsi)
  cmp    %r8,%rsi
  jne    L13
L5:
  ret
```

assistant: ```c
void pr_dec(int d, char *p, int n) {
  while ((n--) > 0) {
    int dDiv10 = ((d) / 10);
    *p-- = '0' + d - dDiv10 * 10;
    d = dDiv10;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pr_dec>:
  endbr64
  mov    %edi,%ecx
  test   %edx,%edx
  jle    L16
  lea    -0x1(%rdx),%edi
  mov    $0xfffffff6,%r8d
  not    %rdi
  add    %rsi,%rdi
  nopl   0x0(%rax)
L17:
  movslq %ecx,%rcx
  sub    $0x1,%rsi
  mov    %rcx,%rdx
  imul   $0x66666667,%rcx,%rcx
  mov    %edx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  mov    %r8d,%eax
  imul   %ecx,%eax
  lea    0x30(%rax,%rdx,1),%eax
  mov    %al,0x1(%rsi)
  cmp    %rdi,%rsi
  jne    L17
L16:
  ret
```

assistant: ```c
void pr_dec(int d, char *p, int n) {
  while ((n--) > 0) {
    int dDiv10 = ((d) / 10);
    *p-- = '0' + d - dDiv10 * 10;
    d = dDiv10;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pr_dec>:
  endbr64
  mov    %edi,%ecx
  test   %edx,%edx
  jle    L17
  lea    -0x1(%rdx),%edi
  mov    $0xfffffff6,%r8d
  not    %rdi
  add    %rsi,%rdi
  nopl   0x0(%rax)
L2:
  movslq %ecx,%rcx
  sub    $0x1,%rsi
  mov    %rcx,%rdx
  imul   $0x66666667,%rcx,%rcx
  mov    %edx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  mov    %r8d,%eax
  imul   %ecx,%eax
  lea    0x30(%rax,%rdx,1),%eax
  mov    %al,0x1(%rsi)
  cmp    %rdi,%rsi
  jne    L2
L17:
  ret
```

assistant: ```c
void pr_dec(int d, char *p, int n) {
  while ((n--) > 0) {
    int dDiv10 = ((d) / 10);
    *p-- = '0' + d - dDiv10 * 10;
    d = dDiv10;
  }
  return;
}
```