ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  fld1
  test   %edi,%edi
  je     L16
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edi,%eax
  mov    %rax,-0x10(%rsp)
  fildll -0x10(%rsp)
  fmulp  %st,%st(1)
  sub    $0x1,%edi
  jne    L9
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
long double factorial(unsigned n) {
  long double f = 1;
  while (n > 0) {
    f *= n--;
  }
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<factorial>:
  endbr64
  fld1
  test   %edi,%edi
  je     L15
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edi,%eax
  mov    %rax,-0x10(%rsp)
  fildll -0x10(%rsp)
  fmulp  %st,%st(1)
  sub    $0x1,%edi
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
long double factorial(unsigned n) {
  long double f = 1;
  while (n > 0) {
    f *= n--;
  }
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puth2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x6665646362613938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x4,-0x24(%rbp)
  jmp    L19
L20:
  mov    -0x24(%rbp),%eax
  mov    -0x34(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,%eax
  movzbl -0x20(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putch@plt>
  subl   $0x4,-0x24(%rbp)
L19:
  cmpl   $0xfffffffc,-0x24(%rbp)
  jne    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void puth2(unsigned int i) {
  int pos;
  char c[] = "0123456789abcdef";
  for (pos = 4; pos != -4; pos -= 4) {
    putch(c[(i >> pos) & 0xF]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puth2>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x6665646362613938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  mov    %edi,%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  movsbl (%rsp,%rax,1),%edi
  call   <putch@plt>
  and    $0xf,%ebx
  movsbl (%rsp,%rbx,1),%edi
  call   <putch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void puth2(unsigned int i) {
  int pos;
  char c[] = "0123456789abcdef";
  for (pos = 4; pos != -4; pos -= 4) {
    putch(c[(i >> pos) & 0xF]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<puth2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  movb   $0x0,0x10(%rsp)
  shr    $0x4,%eax
  movaps %xmm0,(%rsp)
  and    $0xf,%eax
  movsbl (%rsp,%rax,1),%edi
  call   <putch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  and    $0xf,%ebx
  movsbl (%rsp,%rbx,1),%edi
  add    $0x20,%rsp
  pop    %rbx
  jmp    1070 <putch@plt>
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: byte[16]

tool: {"D2": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
void puth2(unsigned int i) {
  int pos;
  char c[] = "0123456789abcdef";
  for (pos = 4; pos != -4; pos -= 4) {
    putch(c[(i >> pos) & 0xF]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<puth2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  movb   $0x0,0x10(%rsp)
  shr    $0x4,%eax
  movaps %xmm0,(%rsp)
  and    $0xf,%eax
  movsbl (%rsp,%rax,1),%edi
  call   <putch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  and    $0xf,%ebx
  movsbl (%rsp,%rbx,1),%edi
  add    $0x20,%rsp
  pop    %rbx
  jmp    1070 <putch@plt>
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: byte[16]

tool: {"D3": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
void puth2(unsigned int i) {
  int pos;
  char c[] = "0123456789abcdef";
  for (pos = 4; pos != -4; pos -= 4) {
    putch(c[(i >> pos) & 0xF]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_flower_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0x10(%rbp)
  jmp    L29
L18:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L47:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x8(%rbp)
  jne    L47
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L12
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  addl   $0x1,-0x10(%rbp)
L29:
  cmpl   $0x3e7,-0x10(%rbp)
  jle    L18
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %d


assistant: ```c
void print_flower_number() {
  int i, sum, temp, one_digit;
  for (i = 100; i < 1000; i++) {
    temp = i;
    sum = 0;
    while (temp) {
      one_digit = temp % 10;
      sum += one_digit * one_digit * one_digit;
      temp /= 10;
    }
    if (i == sum) {
      printf("%d\n", sum);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_flower_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebx
  lea    D8(%rip),%rbp
  jmp    L32
L45:
  mov    %rbp,%rdi
  call   <printf@plt>
L4:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L33
L32:
  mov    %ebx,%edx
  mov    $0x0,%edi
  mov    %ebx,%esi
  test   %ebx,%ebx
  je     L45
L44:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edx,%eax
  add    %eax,%edi
  mov    %esi,%edx
  test   %esi,%esi
  jne    L44
  cmp    %ebx,%edi
  jne    L4
  mov    %ebx,%esi
  jmp    L45
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: %d


assistant: ```c
void print_flower_number() {
  int i, sum, temp, one_digit;
  for (i = 100; i < 1000; i++) {
    temp = i;
    sum = 0;
    while (temp) {
      one_digit = temp % 10;
      sum += one_digit * one_digit * one_digit;
      temp /= 10;
    }
    if (i == sum) {
      printf("%d\n", sum);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_flower_number>:
  endbr64
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %ebp,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L13:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edx,%eax
  mov    %ecx,%edx
  add    %eax,%edi
  test   %ecx,%ecx
  jne    L13
  cmp    %ebp,%edi
  je     L19
L3:
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  jne    L24
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L19:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: %d


assistant: ```c
void print_flower_number() {
  int i, sum, temp, one_digit;
  for (i = 100; i < 1000; i++) {
    temp = i;
    sum = 0;
    while (temp) {
      one_digit = temp % 10;
      sum += one_digit * one_digit * one_digit;
      temp /= 10;
    }
    if (i == sum) {
      printf("%d\n", sum);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_flower_number>:
  endbr64
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %ebp,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L4:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edx,%eax
  mov    %ecx,%edx
  add    %eax,%edi
  test   %ecx,%ecx
  jne    L4
  cmp    %ebp,%edi
  je     L24
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L24:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    $0x3e8,%ebp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: %d


assistant: ```c
void print_flower_number() {
  int i, sum, temp, one_digit;
  for (i = 100; i < 1000; i++) {
    temp = i;
    sum = 0;
    while (temp) {
      one_digit = temp % 10;
      sum += one_digit * one_digit * one_digit;
      temp /= 10;
    }
    if (i == sum) {
      printf("%d\n", sum);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x249000(%rsp),%r11
L70:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L70
  sub    $0xf30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x249f28(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L52
L73:
  lea    -0x249f30(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x1,-0x249f20(%rbp)
  jmp    L28
L74:
  lea    -0x249f10(%rbp),%rdx
  mov    -0x249f20(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addq   $0x1,-0x249f20(%rbp)
L28:
  mov    -0x249f30(%rbp),%rax
  cmp    %rax,-0x249f20(%rbp)
  jle    L74
  mov    -0x249f30(%rbp),%rcx
  lea    -0x186a10(%rbp),%rdx
  lea    -0xc3510(%rbp),%rsi
  lea    -0x249f10(%rbp),%rax
  mov    %rax,%rdi
  call   <counting_sort@plt>
  movq   $0x1,-0x249f18(%rbp)
  jmp    L41
L48:
  mov    -0x249f18(%rbp),%rax
  mov    -0x186a10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x249f18(%rbp)
L41:
  mov    -0x249f30(%rbp),%rax
  cmp    %rax,-0x249f18(%rbp)
  jle    L48
  mov    $0xa,%edi
  call   <putchar@plt>
L52:
  mov    -0x249f28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x249f28(%rbp)
  test   %rax,%rax
  jne    L73
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D1: %lld

tool: D15: %lld 

assistant: ```c
int main() {
  long long int i, j, k;
  long long int n, t;
  long long int arr[100000], res[100000], dup[100000];
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    for (j = 1; j <= n; j++) {
      scanf("%lld", &arr[j]);
    }
    counting_sort(arr, dup, res, n);
    for (k = 1; k <= n; k++) {
      printf("%lld ", res[k]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x249000(%rsp),%r11
L54:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L54
  sub    $0xf28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x249f18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  je     L11
  mov    %rsp,%r14
  lea    D9(%rip),%r12
  lea    0xc3510(%rsp),%rbp
  lea    D29(%rip),%r13
L34:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  test   %rcx,%rcx
  jle    L26
  lea    0x18(%rsp),%r15
  mov    $0x1,%ebx
L50:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%rbx
  mov    (%rsp),%rcx
  add    $0x8,%r15
  cmp    %rbx,%rcx
  jge    L50
L26:
  lea    0x186a10(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rdx
  call   <counting_sort@plt>
  cmpq   $0x0,(%rsp)
  jle    L14
  mov    $0x1,%ebx
L35:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,(%rsp)
  jge    L35
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  jne    L34
L11:
  mov    0x249f18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0x249f28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string
name: disassemble_data
arguments: tag: D29
type_guessed: string

tool: D9: %lld

tool: D29: %lld 

assistant: ```c
int main() {
  long long int i, j, k;
  long long int n, t;
  long long int arr[100000], res[100000], dup[100000];
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    for (j = 1; j <= n; j++) {
      scanf("%lld", &arr[j]);
    }
    counting_sort(arr, dup, res, n);
    for (k = 1; k <= n; k++) {
      printf("%lld ", res[k]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x249000(%rsp),%r11
L54:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L54
  sub    $0xf38,%rsp
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x249f28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x18(%rsp)
  test   %rax,%rax
  je     L71
  lea    0x186a20(%rsp),%rax
  lea    0x10(%rsp),%r15
  mov    %rax,(%rsp)
  lea    0x20(%rsp),%rax
  lea    0xc3520(%rsp),%rbp
  mov    %rax,0x8(%rsp)
  lea    D13(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L77:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r8
  test   %r8,%r8
  jle    L55
  lea    0x28(%rsp),%r14
  mov    $0x1,%r13d
L42:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13
  add    $0x8,%r14
  call   <scanf@plt>
  mov    0x10(%rsp),%r8
  cmp    %r13,%r8
  jge    L42
L55:
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  mov    %r8,%rcx
  mov    %rbp,%rdx
  call   <counting_sort@plt>
  cmpq   $0x0,0x10(%rsp)
  jle    L33
  mov    $0x1,%r13d
  nop
L7:
  mov    0x0(%rbp,%r13,8),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  cmp    %r13,0x10(%rsp)
  jge    L7
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x18(%rsp)
  test   %rax,%rax
  jne    L77
L71:
  mov    0x249f28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x249f38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string

tool: D6: %lld

tool: D13: %lld 

assistant: ```c
int main() {
  long long int i, j, k;
  long long int n, t;
  long long int arr[100000], res[100000], dup[100000];
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    for (j = 1; j <= n; j++) {
      scanf("%lld", &arr[j]);
    }
    counting_sort(arr, dup, res, n);
    for (k = 1; k <= n; k++) {
      printf("%lld ", res[k]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x249000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0xf38,%rsp
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x249f28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x18(%rsp)
  test   %rax,%rax
  je     L40
  lea    0x186a20(%rsp),%rax
  lea    0x10(%rsp),%r15
  mov    %rax,(%rsp)
  lea    0x20(%rsp),%rax
  lea    0xc3520(%rsp),%rbp
  mov    %rax,0x8(%rsp)
  lea    D11(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r8
  test   %r8,%r8
  jle    L59
  lea    0x28(%rsp),%r14
  mov    $0x1,%r13d
L2:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13
  add    $0x8,%r14
  call   <scanf@plt>
  mov    0x10(%rsp),%r8
  cmp    %r13,%r8
  jge    L2
L59:
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  mov    %r8,%rcx
  mov    %rbp,%rdx
  call   <counting_sort@plt>
  cmpq   $0x0,0x10(%rsp)
  jle    L61
  mov    $0x1,%r13d
  nop
L50:
  mov    0x0(%rbp,%r13,8),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  cmp    %r13,0x10(%rsp)
  jge    L50
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x18(%rsp)
  test   %rax,%rax
  jne    L23
L40:
  mov    0x249f28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x249f38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string

tool: D16: %lld

tool: D11: %lld 

assistant: ```c
int main() {
  long long int i, j, k;
  long long int n, t;
  long long int arr[100000], res[100000], dup[100000];
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    for (j = 1; j <= n; j++) {
      scanf("%lld", &arr[j]);
    }
    counting_sort(arr, dup, res, n);
    for (k = 1; k <= n; k++) {
      printf("%lld ", res[k]);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<combine_bumper_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dl,-0x14(%rbp)
  mov    %ecx,%edx
  mov    %dl,-0x18(%rbp)
  mov    %al,-0x1c(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x18(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,%edx
  movzbl -0x1c(%rbp),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long combine_bumper_vector(unsigned char b1, unsigned char b2, unsigned char b3) {
  long num;
  num = b1 + (b2 * 256) + (b3 * 65536);
  return (num);
}
```
user: What is the c source code of the assembly code below:

```asm
<combine_bumper_vector>:
  endbr64
  movzbl %sil,%esi
  shl    $0x8,%esi
  movzbl %dil,%edi
  add    %edi,%esi
  movzbl %dl,%edx
  shl    $0x10,%edx
  add    %edx,%esi
  movslq %esi,%rax
  ret
```

assistant: ```c
long combine_bumper_vector(unsigned char b1, unsigned char b2, unsigned char b3) {
  long num;
  num = b1 + (b2 * 256) + (b3 * 65536);
  return (num);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<combine_bumper_vector>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  movzbl %dl,%edx
  shl    $0x8,%esi
  shl    $0x10,%edx
  add    %edi,%esi
  add    %edx,%esi
  movslq %esi,%rax
  ret
```

assistant: ```c
long combine_bumper_vector(unsigned char b1, unsigned char b2, unsigned char b3) {
  long num;
  num = b1 + (b2 * 256) + (b3 * 65536);
  return (num);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<combine_bumper_vector>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  movzbl %dl,%edx
  shl    $0x8,%esi
  shl    $0x10,%edx
  add    %edi,%esi
  add    %edx,%esi
  movslq %esi,%rax
  ret
```

assistant: ```c
long combine_bumper_vector(unsigned char b1, unsigned char b2, unsigned char b3) {
  long num;
  num = b1 + (b2 * 256) + (b3 * 65536);
  return (num);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<evolveUniv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x68,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,%r15d
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x70(%rbp)
  movslq %edi,%rax
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L127:
  cmp    %rdx,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L127
L55:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L3
  orq    $0x0,-0x8(%rsp,%rax,1)
L3:
  mov    %rsp,%rax
  mov    -0x44(%rbp),%ecx
  test   %ecx,%ecx
  je     L97
  mov    -0x50(%rbp),%rdi
  mov    %rdi,-0x80(%rbp)
  mov    %ecx,%ecx
  mov    %rcx,-0x78(%rbp)
  mov    %rdi,-0x68(%rbp)
  mov    %rax,%r14
  movq   $0x0,-0x58(%rbp)
  mov    %rax,-0x88(%rbp)
  jmp    L155
L92:
  mov    %edx,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L25
L177:
  mov    -0x50(%rbp),%r8
  mov    %r15d,%ecx
  mov    -0x44(%rbp),%edx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <getNeighbours@plt>
  mov    $0x1,%edx
  cmp    $0x3,%eax
  je     L92
  mov    $0x0,%edx
  cmp    $0x2,%eax
  jne    L92
  mov    -0x60(%rbp),%rax
  cmpl   $0x0,(%rax,%rbx,4)
  setne  %dl
  movzbl %dl,%edx
  jmp    L92
L25:
  addq   $0x1,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  mov    -0x70(%rbp),%rcx
  add    %rcx,%r14
  add    %rcx,-0x68(%rbp)
  cmp    -0x78(%rbp),%rax
  je     L49
L155:
  mov    -0x58(%rbp),%r13d
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  mov    %r15d,%r12d
  mov    $0x0,%ebx
  test   %r15d,%r15d
  jne    L177
  jmp    L25
L100:
  mov    (%r12,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L100
L173:
  add    $0x1,%edi
  add    %r9,%r12
  add    %r9,%r8
  cmp    %edi,%r10d
  je     L97
L17:
  mov    %r8,%rcx
  mov    $0x0,%eax
  test   %r15d,%r15d
  jne    L100
  jmp    L173
L49:
  mov    -0x88(%rbp),%r12
  mov    $0x0,%edi
  mov    %r15d,%esi
  mov    -0x70(%rbp),%r9
  mov    -0x80(%rbp),%r8
  mov    -0x44(%rbp),%r10d
  jmp    L17
L97:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L129
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L129:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void evolveUniv(int rows, int cols, int univ[][cols]) {
  int new_univ[rows][cols];
  int i, j;
  int live_neighbours;
  for (i = 0; i != rows; i++) {
    for (j = 0; j != cols; j++) {
      live_neighbours = getNeighbours(i, j, rows, cols, univ);
      new_univ[i][j] = (live_neighbours == 3 || (live_neighbours == 2 && univ[i][j]));
    }
  }
  for (i = 0; i != rows; i++) {
    for (j = 0; j != cols; j++) {
      univ[i][j] = new_univ[i][j];
    }
  }
}
```