ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<st103_set_rx_addr>:
  endbr64
  lea    0x4(,%rdi,8),%eax
  add    %eax,%eax
  cltq
  mov    %esi,0x40006000(%rax)
  ret
```

assistant: ```c
void st103_set_rx_addr(uint8_t ep_num, uint16_t addr) {
  uint16_t *reg_p = (uint16_t *)((0x40006000UL) + (ep_num * 8 + 4) * 2);
  *reg_p = addr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st103_set_rx_addr>:
  endbr64
  lea    0x4(,%rdi,8),%eax
  add    %eax,%eax
  cltq
  mov    %esi,0x40006000(%rax)
  ret
```

assistant: ```c
void st103_set_rx_addr(uint8_t ep_num, uint16_t addr) {
  uint16_t *reg_p = (uint16_t *)((0x40006000UL) + (ep_num * 8 + 4) * 2);
  *reg_p = addr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findNextPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  jg     L8
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L97
  cmp    $0x2,%eax
  je     L75
  jmp    L8
L97:
  mov    $0x2,%eax
  jmp    L5
L75:
  mov    $0x3,%eax
  jmp    L5
L8:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L68
L77:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L57
  mov    -0x4(%rbp),%eax
  jmp    L5
L57:
  addl   $0x2,-0x4(%rbp)
L68:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L77
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t findNextPrime(uint32_t *curPrime, uint32_t *searchLimit, uint8_t *isComposite) {
  if (*curPrime < 3) {
    switch (*curPrime) {
    case 1:
      return 2;
    case 2:
      return 3;
    }
  }
  for (uint32_t i = *curPrime + 2; i < *searchLimit; i += 2)
    if (!isComposite[i])
      return i;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findNextPrime>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x2,%eax
  jg     L60
  mov    $0x2,%ecx
  cmp    $0x1,%eax
  je     L46
  mov    $0x3,%ecx
  cmp    $0x2,%eax
  je     L46
L60:
  add    $0x2,%eax
  mov    (%rsi),%esi
  cmp    %esi,%eax
  jge    L62
  cltq
L49:
  mov    %eax,%ecx
  cmpl   $0x0,(%rdx,%rax,4)
  je     L46
  add    $0x2,%rax
  cmp    %eax,%esi
  jg     L49
  mov    $0x0,%ecx
L46:
  mov    %ecx,%eax
  ret
L62:
  mov    $0x0,%ecx
  jmp    L46
```

assistant: ```c
uint32_t findNextPrime(uint32_t *curPrime, uint32_t *searchLimit, uint8_t *isComposite) {
  if (*curPrime < 3) {
    switch (*curPrime) {
    case 1:
      return 2;
    case 2:
      return 3;
    }
  }
  for (uint32_t i = *curPrime + 2; i < *searchLimit; i += 2)
    if (!isComposite[i])
      return i;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<findNextPrime>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x2,%eax
  jg     L13
  mov    $0x2,%r8d
  cmp    $0x1,%eax
  je     L39
  mov    $0x3,%r8d
  cmp    $0x2,%eax
  je     L39
L13:
  mov    (%rsi),%ecx
  add    $0x2,%eax
  cmp    %ecx,%eax
  jge    L36
  cltq
  jmp    L49
  xchg   %ax,%ax
L46:
  add    $0x2,%rax
  cmp    %eax,%ecx
  jle    L36
L49:
  mov    (%rdx,%rax,4),%esi
  mov    %eax,%r8d
  test   %esi,%esi
  jne    L46
L39:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t findNextPrime(uint32_t *curPrime, uint32_t *searchLimit, uint8_t *isComposite) {
  if (*curPrime < 3) {
    switch (*curPrime) {
    case 1:
      return 2;
    case 2:
      return 3;
    }
  }
  for (uint32_t i = *curPrime + 2; i < *searchLimit; i += 2)
    if (!isComposite[i])
      return i;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<findNextPrime>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x2,%eax
  jg     L32
  mov    $0x2,%r8d
  cmp    $0x1,%eax
  je     L63
  mov    $0x3,%r8d
  cmp    $0x2,%eax
  je     L63
L32:
  mov    (%rsi),%ecx
  add    $0x2,%eax
  cmp    %ecx,%eax
  jge    L58
  cltq
  jmp    L16
  xchg   %ax,%ax
L66:
  add    $0x2,%rax
  cmp    %eax,%ecx
  jle    L58
L16:
  mov    (%rdx,%rax,4),%esi
  mov    %eax,%r8d
  test   %esi,%esi
  jne    L66
L63:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t findNextPrime(uint32_t *curPrime, uint32_t *searchLimit, uint8_t *isComposite) {
  if (*curPrime < 3) {
    switch (*curPrime) {
    case 1:
      return 2;
    case 2:
      return 3;
    }
  }
  for (uint32_t i = *curPrime + 2; i < *searchLimit; i += 2)
    if (!isComposite[i])
      return i;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<pause>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pause(void) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pause>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pause(void) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pause>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pause(void) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pause>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pause(void) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L8:
  nop
  leave
  ret
```

assistant: ```c
void chomp(char *s) {
  int end = strlen(s) - 1;
  if (end >= 0 && s[end] == '\n')
    s[end] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L13
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L24
L13:
  pop    %rbx
  ret
L24:
  movb   $0x0,(%rbx)
  jmp    L13
```

assistant: ```c
void chomp(char *s) {
  int end = strlen(s) - 1;
  if (end >= 0 && s[end] == '\n')
    s[end] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L16
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L15
L16:
  pop    %rbx
  ret
  xchg   %ax,%ax
L15:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void chomp(char *s) {
  int end = strlen(s) - 1;
  if (end >= 0 && s[end] == '\n')
    s[end] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L11
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L17
L11:
  pop    %rbx
  ret
  xchg   %ax,%ax
L17:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void chomp(char *s) {
  int end = strlen(s) - 1;
  if (end >= 0 && s[end] == '\n')
    s[end] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
L27:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  cltq
  mov    %dl,-0xb(%rbp,%rax,1)
  addl   $0x1,-0x18(%rbp)
L16:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jne    L27
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x0,-0xb(%rbp,%rax,1)
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string

tool: D17: Minutes: 

tool: D0: Bottles: %i

assistant: ```c
int main(void) {
  int c;
  int i = 0;
  char input[3];
  printf("Minutes: ");
  while ((c = getchar()) != '\n') {
    input[i] = c;
    i++;
  }
  input[i] = '\0';
  printf("%s\n", input);
  int bottles = atoi(input) * 12;
  printf("Bottles: %i", bottles);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L10
L6:
  mov    %al,0x5(%rsp,%rbx,1)
  add    $0x1,%rbx
L10:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L6
  movslq %ebx,%rbp
  movb   $0x0,0x5(%rsp,%rbp,1)
  lea    0x5(%rsp),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  lea    (%rax,%rax,2),%esi
  shl    $0x2,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D17: Minutes: 

tool: D9: Bottles: %i

assistant: ```c
int main(void) {
  int c;
  int i = 0;
  char input[3];
  printf("Minutes: ");
  while ((c = getchar()) != '\n') {
    input[i] = c;
    i++;
  }
  input[i] = '\0';
  printf("%s\n", input);
  int bottles = atoi(input) * 12;
  printf("Bottles: %i", bottles);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  movslq %ebx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%r12
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L6
L5:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L5
L6:
  mov    %r12,%rdi
  movb   $0x0,0x5(%rsp,%rbp,1)
  call   <puts@plt>
  mov    %r12,%rdi
  call   <atoi@plt>
  lea    D2(%rip),%rdi
  lea    (%rax,%rax,2),%esi
  xor    %eax,%eax
  shl    $0x2,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string

tool: D11: Minutes: 

tool: D2: Bottles: %i

assistant: ```c
int main(void) {
  int c;
  int i = 0;
  char input[3];
  printf("Minutes: ");
  while ((c = getchar()) != '\n') {
    input[i] = c;
    i++;
  }
  input[i] = '\0';
  printf("%s\n", input);
  int bottles = atoi(input) * 12;
  printf("Bottles: %i", bottles);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  movslq %ebx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%r12
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L21
L10:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L10
L21:
  mov    %r12,%rdi
  movb   $0x0,0x5(%rsp,%rbp,1)
  call   <puts@plt>
  mov    %r12,%rdi
  call   <atoi@plt>
  lea    D14(%rip),%rdi
  lea    (%rax,%rax,2),%esi
  xor    %eax,%eax
  shl    $0x2,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string

tool: D5: Minutes: 

tool: D14: Bottles: %i

assistant: ```c
int main(void) {
  int c;
  int i = 0;
  char input[3];
  printf("Minutes: ");
  while ((c = getchar()) != '\n') {
    input[i] = c;
    i++;
  }
  input[i] = '\0';
  printf("%s\n", input);
  int bottles = atoi(input) * 12;
  printf("Bottles: %i", bottles);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_45_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_45_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_45_0_0>:
  endbr64
  movzbl %sil,%esi
  or     $0xffffff00,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_45_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return stk1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_45_0_0>:
  endbr64
  movzbl %sil,%esi
  or     $0xffffff00,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_45_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return stk1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fun_call_align_6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  movswl -0x8(%rbp),%edx
  movswl -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movswl -0x4(%rbp),%edx
  movswl -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: a = %d, b = %d


assistant: ```c
int fun_call_align_6(short a, short b) {
  printf("a = %d, b = %d\n", a, b);
  return a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fun_call_align_6>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movswl %si,%ebx
  movswl %di,%ebp
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string

tool: D0: a = %d, b = %d


assistant: ```c
int fun_call_align_6(short a, short b) {
  printf("a = %d, b = %d\n", a, b);
  return a + b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fun_call_align_6>:
  endbr64
  push   %rbp
  movswl %di,%ebp
  lea    D8(%rip),%rdi
  push   %rbx
  movswl %si,%ebx
  mov    %ebp,%esi
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: a = %d, b = %d


assistant: ```c
int fun_call_align_6(short a, short b) {
  printf("a = %d, b = %d\n", a, b);
  return a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fun_call_align_6>:
  endbr64
  push   %rbp
  movswl %di,%ebp
  lea    D3(%rip),%rdi
  push   %rbx
  movswl %si,%ebx
  mov    %ebp,%esi
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: a = %d, b = %d


assistant: ```c
int fun_call_align_6(short a, short b) {
  printf("a = %d, b = %d\n", a, b);
  return a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<EDirectAlphaRowARGB32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  jmp    L16
L2:
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rbx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  mov    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0xc(%rax),%rbx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  addq   $0x10,-0x18(%rbp)
  addq   $0x10,-0x20(%rbp)
L16:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  test   %eax,%eax
  jne    L2
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void EDirectAlphaRowARGB32(u_int8_t *src, u_int8_t *dst, u_int8_t a, int width) {
  while (width--) {
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EDirectAlphaRowARGB32>:
  endbr64
  test   %ecx,%ecx
  je     L1
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %ecx,%ecx
  shl    $0x4,%rcx
  lea    (%rdi,%rcx,1),%r13
L16:
  mov    0x4(%rbx),%edx
  mov    0x4(%rbp),%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,0x4(%rbx)
  mov    0x8(%rbx),%edx
  mov    0x8(%rbp),%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,0x8(%rbx)
  mov    0xc(%rbx),%edx
  mov    0xc(%rbp),%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,0xc(%rbx)
  add    $0x10,%rbp
  add    $0x10,%rbx
  cmp    %r13,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  ret
```

assistant: ```c
void EDirectAlphaRowARGB32(u_int8_t *src, u_int8_t *dst, u_int8_t a, int width) {
  while (width--) {
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<EDirectAlphaRowARGB32>:
  endbr64
  test   %ecx,%ecx
  je     L11
  push   %r13
  mov    %ecx,%ecx
  push   %r12
  shl    $0x4,%rcx
  mov    %edx,%r12d
  push   %rbp
  lea    (%rdi,%rcx,1),%r13
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L19:
  mov    0x4(%rbx),%edx
  mov    0x4(%rbp),%esi
  mov    %r12d,%edi
  add    $0x10,%rbp
  add    $0x10,%rbx
  call   <eblend@plt>
  mov    -0x8(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0xc(%rbx)
  mov    -0x8(%rbp),%esi
  call   <eblend@plt>
  mov    -0x4(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0x8(%rbx)
  mov    -0x4(%rbp),%esi
  call   <eblend@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbp
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void EDirectAlphaRowARGB32(u_int8_t *src, u_int8_t *dst, u_int8_t a, int width) {
  while (width--) {
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EDirectAlphaRowARGB32>:
  endbr64
  test   %ecx,%ecx
  je     L1
  push   %r13
  mov    %ecx,%ecx
  push   %r12
  shl    $0x4,%rcx
  mov    %edx,%r12d
  push   %rbp
  lea    (%rdi,%rcx,1),%r13
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L15:
  mov    0x4(%rbx),%edx
  mov    0x4(%rbp),%esi
  mov    %r12d,%edi
  add    $0x10,%rbp
  add    $0x10,%rbx
  call   <eblend@plt>
  mov    -0x8(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0xc(%rbx)
  mov    -0x8(%rbp),%esi
  call   <eblend@plt>
  mov    -0x4(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0x8(%rbx)
  mov    -0x4(%rbp),%esi
  call   <eblend@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbp
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void EDirectAlphaRowARGB32(u_int8_t *src, u_int8_t *dst, u_int8_t a, int width) {
  while (width--) {
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SwapIntegerElements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SwapIntegerElements(int array[], int p1, int p2) {
  int tmp;
  tmp = array[p1];
  array[p1] = array[p2];
  array[p2] = tmp;
}
```