ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_space>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2c,%edi
  call   <ft_putchar@plt>
  mov    $0x20,%edi
  add    $0x8,%rsp
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_space(void) {
  ft_putchar(',');
  ft_putchar(' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <lock@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc_internal@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <unlock@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *malloc(size_t size) {
  lock();
  void *result = malloc_internal(size);
  unlock();
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<malloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <lock@plt>
  mov    %rbx,%rdi
  call   <malloc_internal@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <unlock@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *malloc(size_t size) {
  lock();
  void *result = malloc_internal(size);
  unlock();
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <lock@plt>
  mov    %r12,%rdi
  call   <malloc_internal@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <unlock@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *malloc(size_t size) {
  lock();
  void *result = malloc_internal(size);
  unlock();
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<malloc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <lock@plt>
  mov    %r12,%rdi
  call   <malloc_internal@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <unlock@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *malloc(size_t size) {
  lock();
  void *result = malloc_internal(size);
  unlock();
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arm_mv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %rdx,-0x238(%rbp)
  mov    %rcx,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rdi
  call   <init_send_buffer@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    -0x228(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stuff4byteuint@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    -0x230(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stuff4byteuint@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    -0x238(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stuff4byteuint@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    -0x240(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stuff4byteuint@plt>
  movzwl -0x21c(%rbp),%eax
  cwtl
  lea    -0x210(%rbp),%rdx
  mov    %rdx,%rcx
  mov    $0x2a,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <stuff_send_buffer_header@plt>
  lea    -0x110(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <special_request@plt>
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rdi
  call   <init_receive_buffer@plt>
  lea    -0x110(%rbp),%rcx
  lea    -0x21d(%rbp),%rdx
  lea    -0x21e(%rbp),%rsi
  lea    -0x21a(%rbp),%rax
  mov    %rax,%rdi
  call   <extract_receive_buffer_header@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,-0x218(%rbp)
  mov    -0x218(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
long arm_mv(long l_mode, long l_v, long g_mode, long g_v) {
  long result;
  short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff4byteuint(l_mode, user_send_buffer, &b_index);
  stuff4byteuint(l_v, user_send_buffer, &b_index);
  stuff4byteuint(g_mode, user_send_buffer, &b_index);
  stuff4byteuint(g_v, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 42, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<arm_mv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <init_send_buffer@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <stuff4byteuint@plt>
  movswl 0xc(%rsp),%edi
  mov    %rbp,%rcx
  mov    $0x2a,%edx
  mov    $0x0,%esi
  call   <stuff_send_buffer_header@plt>
  lea    0x110(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <special_request@plt>
  mov    %rbx,%rdi
  call   <init_receive_buffer@plt>
  lea    0xb(%rsp),%rdx
  lea    0xa(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  mov    %r12,%rcx
  call   <extract_receive_buffer_header@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <extract4byteuint@plt>
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long arm_mv(long l_mode, long l_v, long g_mode, long g_v) {
  long result;
  short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff4byteuint(l_mode, user_send_buffer, &b_index);
  stuff4byteuint(l_v, user_send_buffer, &b_index);
  stuff4byteuint(g_mode, user_send_buffer, &b_index);
  stuff4byteuint(g_v, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 42, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arm_mv>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdi
  call   <init_send_buffer@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <stuff4byteuint@plt>
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <stuff4byteuint@plt>
  movswl 0xc(%rsp),%edi
  mov    %r12,%rcx
  xor    %esi,%esi
  mov    $0x2a,%edx
  lea    0x110(%rsp),%r13
  call   <stuff_send_buffer_header@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <special_request@plt>
  mov    %rbp,%rdi
  call   <init_receive_buffer@plt>
  lea    0xb(%rsp),%rdx
  lea    0xa(%rsp),%rsi
  mov    %r13,%rcx
  lea    0xe(%rsp),%rdi
  call   <extract_receive_buffer_header@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <extract4byteuint@plt>
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long arm_mv(long l_mode, long l_v, long g_mode, long g_v) {
  long result;
  short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff4byteuint(l_mode, user_send_buffer, &b_index);
  stuff4byteuint(l_v, user_send_buffer, &b_index);
  stuff4byteuint(g_mode, user_send_buffer, &b_index);
  stuff4byteuint(g_v, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 42, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arm_mv>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdi
  call   <init_send_buffer@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <stuff4byteuint@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <stuff4byteuint@plt>
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <stuff4byteuint@plt>
  movswl 0xc(%rsp),%edi
  mov    %r12,%rcx
  xor    %esi,%esi
  mov    $0x2a,%edx
  lea    0x110(%rsp),%r13
  call   <stuff_send_buffer_header@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <special_request@plt>
  mov    %rbp,%rdi
  call   <init_receive_buffer@plt>
  lea    0xb(%rsp),%rdx
  lea    0xa(%rsp),%rsi
  mov    %r13,%rcx
  lea    0xe(%rsp),%rdi
  call   <extract_receive_buffer_header@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <extract4byteuint@plt>
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long arm_mv(long l_mode, long l_v, long g_mode, long g_v) {
  long result;
  short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff4byteuint(l_mode, user_send_buffer, &b_index);
  stuff4byteuint(l_v, user_send_buffer, &b_index);
  stuff4byteuint(g_mode, user_send_buffer, &b_index);
  stuff4byteuint(g_v, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 42, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<movsx_reg32_reg8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0xbe,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  or     -0x8(%rbp),%eax
  or     $0xc0,%al
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void movsx_reg32_reg8(int reg32, int reg8) {
  put8(0x0F);
  put8(0xBE);
  put8((reg32 << 3) | reg8 | 0xC0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<movsx_reg32_reg8>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0xbe,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %ebp,%edi
  or     $0xc0,%dil
  call   <put8@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void movsx_reg32_reg8(int reg32, int reg8) {
  put8(0x0F);
  put8(0xBE);
  put8((reg32 << 3) | reg8 | 0xC0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<movsx_reg32_reg8>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf,%edi
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0xbe,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <put8@plt>
```

assistant: ```c
void movsx_reg32_reg8(int reg32, int reg8) {
  put8(0x0F);
  put8(0xBE);
  put8((reg32 << 3) | reg8 | 0xC0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<movsx_reg32_reg8>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf,%edi
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0xbe,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <put8@plt>
```

assistant: ```c
void movsx_reg32_reg8(int reg32, int reg8) {
  put8(0x0F);
  put8(0xBE);
  put8((reg32 << 3) | reg8 | 0xC0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lib_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string

tool: D4: lib_entry

tool: D16: %s: Entry point of the service library


assistant: ```c
void lib_entry(void) {
  printf("%s: Entry point of the service library\n", __func__);
  _exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lib_entry>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D15
type: string

tool: D17: lib_entry

tool: D15: %s: Entry point of the service library


assistant: ```c
void lib_entry(void) {
  printf("%s: Entry point of the service library\n", __func__);
  _exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lib_entry>:
  endbr64
  lea    D11(%rip),%rdi
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <_exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D11: %s: Entry point of the service library


tool: D3: lib_entry

assistant: ```c
void lib_entry(void) {
  printf("%s: Entry point of the service library\n", __func__);
  _exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lib_entry>:
  endbr64
  lea    D16(%rip),%rdi
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <_exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D4
type: string

tool: D16: %s: Entry point of the service library


tool: D4: lib_entry

assistant: ```c
void lib_entry(void) {
  printf("%s: Entry point of the service library\n", __func__);
  _exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jePopolno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L29
L6:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L27
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  add    %eax,-0x8(%rbp)
L27:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L6
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int jePopolno(int a) {
  int s = 0;
  for (int i = 2; i < sqrt(a); ++i) {
    if (a % i == 0) {
      s += i;
      s += a / i;
    }
  }
  return (s + 1) == a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<jePopolno>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x2,%ebx
  mov    $0x0,%r12d
  jmp    L11
L31:
  add    $0x1,%ebx
L11:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L33
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L31
  add    %ebx,%r12d
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  add    %eax,%r12d
  jmp    L31
L33:
  add    $0x1,%r12d
  cmp    %ebp,%r12d
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int jePopolno(int a) {
  int s = 0;
  for (int i = 2; i < sqrt(a); ++i) {
    if (a % i == 0) {
      s += i;
      s += a / i;
    }
  }
  return (s + 1) == a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jePopolno>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  jmp    L9
  nopl   0x0(%rax)
L6:
  mov    %r12d,%eax
  lea    0x0(%rbp,%rbx,1),%ecx
  cltd
  idiv   %ebx
  add    %ecx,%eax
  test   %edx,%edx
  cmove  %eax,%ebp
  add    $0x1,%ebx
L9:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jg     L6
  add    $0x1,%ebp
  xor    %eax,%eax
  pop    %rbx
  cmp    %r12d,%ebp
  pop    %rbp
  pop    %r12
  sete   %al
  ret
```

assistant: ```c
int jePopolno(int a) {
  int s = 0;
  for (int i = 2; i < sqrt(a); ++i) {
    if (a % i == 0) {
      s += i;
      s += a / i;
    }
  }
  return (s + 1) == a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jePopolno>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  jmp    L5
  nopl   0x0(%rax)
L9:
  mov    %r12d,%eax
  lea    0x0(%rbp,%rbx,1),%ecx
  cltd
  idiv   %ebx
  add    %ecx,%eax
  test   %edx,%edx
  cmove  %eax,%ebp
  add    $0x1,%ebx
L5:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jg     L9
  add    $0x1,%ebp
  xor    %eax,%eax
  pop    %rbx
  cmp    %r12d,%ebp
  pop    %rbp
  pop    %r12
  sete   %al
  ret
```

assistant: ```c
int jePopolno(int a) {
  int s = 0;
  for (int i = 2; i < sqrt(a); ++i) {
    if (a % i == 0) {
      s += i;
      s += a / i;
    }
  }
  return (s + 1) == a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfffffffc,-0x50(%rbp)
  movl   $0xfffffffe,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0xfffffffb,-0x44(%rbp)
  movl   $0xfffffffc,-0x40(%rbp)
  movl   $0xfffffffc,-0x3c(%rbp)
  movl   $0x4,-0x38(%rbp)
  movl   $0xfffffffe,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0xfffffffe,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0xfffffffb,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x60(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <threeSum@plt>
  mov    %rax,-0x58(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L10
L6:
  mov    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  mov    (%rax),%ecx
  mov    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x58(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x5c(%rbp)
L10:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x5c(%rbp)
  jl     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int arr[] = {-4, -2, 1, -5, -4, -4, 4, -2, 0, 4, 0, -2, 3, 1, -5, 0};
  int **r, n, i;
  r = threeSum(arr, ((sizeof(arr)) / sizeof((arr)[0])), &n);
  for (i = 0; i < n; i++) {
    printf("%d %d %d\n", r[i][0], r[i][1], r[i][2]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffc,0x10(%rsp)
  movl   $0xfffffffe,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0xfffffffb,0x1c(%rsp)
  movl   $0xfffffffc,0x20(%rsp)
  movl   $0xfffffffc,0x24(%rsp)
  movl   $0x4,0x28(%rsp)
  movl   $0xfffffffe,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x4,0x34(%rsp)
  movl   $0x0,0x38(%rsp)
  movl   $0xfffffffe,0x3c(%rsp)
  movl   $0x3,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0xfffffffb,0x48(%rsp)
  movl   $0x0,0x4c(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    $0x10,%esi
  call   <threeSum@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L0
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L19:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L19
L0:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int arr[] = {-4, -2, 1, -5, -4, -4, 4, -2, 0, 4, 0, -2, 3, 1, -5, 0};
  int **r, n, i;
  r = threeSum(arr, ((sizeof(arr)) / sizeof((arr)[0])), &n);
  for (i = 0; i < n; i++) {
    printf("%d %d %d\n", r[i][0], r[i][1], r[i][2]);
  }
  return 0;
}
```