ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<axt_to_uint32>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  movzbl %dh,%ecx
  shl    $0x18,%eax
  shl    $0x10,%ecx
  shr    $0x8,%edx
  add    %ecx,%eax
  mov    %edi,%ecx
  and    $0xff00,%edx
  shr    $0x18,%ecx
  add    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int axt_to_uint32(unsigned int axt_uint32) {
  unsigned char *buf = (unsigned char *)&axt_uint32;
  return (((unsigned int)buf[0]) << 24) + (((unsigned int)buf[1]) << 16) + (((unsigned int)buf[2]) << 8) + (((unsigned int)buf[3]));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<delete_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L6
  addq   $0x1,-0x8(%rbp)
L6:
  addq   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void delete_spaces(char *buff) {
  char *ptr;
  ptr = buff;
  while (*buff) {
    *ptr = *buff;
    if (!isspace(*ptr))
      ptr++;
    buff++;
  }
  *ptr = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delete_spaces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L5
  mov    %rbx,%rbp
L20:
  mov    %dil,0x0(%rbp)
  movsbl %dil,%edi
  call   <isspace@plt>
  cmp    $0x1,%eax
  adc    $0x0,%rbp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L20
L14:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbx,%rbp
  jmp    L14
```

assistant: ```c
void delete_spaces(char *buff) {
  char *ptr;
  ptr = buff;
  while (*buff) {
    *ptr = *buff;
    if (!isspace(*ptr))
      ptr++;
    buff++;
  }
  *ptr = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<delete_spaces>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
  mov    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %dil,(%rbx)
  call   <isspace@plt>
  cmp    $0x1,%eax
  adc    $0x0,%rbx
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L11
L5:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void delete_spaces(char *buff) {
  char *ptr;
  ptr = buff;
  while (*buff) {
    *ptr = *buff;
    if (!isspace(*ptr))
      ptr++;
    buff++;
  }
  *ptr = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<delete_spaces>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  mov    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %dil,(%rbx)
  call   <isspace@plt>
  cmp    $0x1,%eax
  adc    $0x0,%rbx
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L7
L6:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void delete_spaces(char *buff) {
  char *ptr;
  ptr = buff;
  while (*buff) {
    *ptr = *buff;
    if (!isspace(*ptr))
      ptr++;
    buff++;
  }
  *ptr = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x50,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  mov    $0x50,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x120(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0xc0(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D14: Introduce un texto (max %d cars.): 

tool: D27: Introduce otro texto (max %d cars.): 

tool: D9: Concatenacion de ambos: %s

assistant: ```c
int main(void) {
  char a[80 + 1], b[80 + 1], c[80 + 1];
  printf("Introduce un texto (max %d cars.): ", 80);
  gets(a);
  printf("Introduce otro texto (max %d cars.): ", 80);
  gets(b);
  strcpy(c, a);
  strcpy(c, b);
  printf("Concatenacion de ambos: %s", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    $0x50,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <gets@plt>
  mov    $0x50,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x60(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0xc0(%rsp),%rbx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_guessed: string
name: retrieve_data
arguments: data_label: D26
type_guessed: string
name: retrieve_data
arguments: data_label: D20
type_guessed: string

tool: D21: Introduce un texto (max %d cars.): 

tool: D26: Introduce otro texto (max %d cars.): 

tool: D20: Concatenacion de ambos: %s

assistant: ```c
int main(void) {
  char a[80 + 1], b[80 + 1], c[80 + 1];
  printf("Introduce un texto (max %d cars.): ", 80);
  gets(a);
  printf("Introduce otro texto (max %d cars.): ", 80);
  gets(b);
  strcpy(c, a);
  strcpy(c, b);
  printf("Concatenacion de ambos: %s", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x50,%esi
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x60(%rsp),%r12
  lea    0xc0(%rsp),%rbp
  call   <printf@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  mov    $0x50,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D23
data_type: string

tool: D7: Introduce un texto (max %d cars.): 

tool: D9: Introduce otro texto (max %d cars.): 

tool: D23: Concatenacion de ambos: %s

assistant: ```c
int main(void) {
  char a[80 + 1], b[80 + 1], c[80 + 1];
  printf("Introduce un texto (max %d cars.): ", 80);
  gets(a);
  printf("Introduce otro texto (max %d cars.): ", 80);
  gets(b);
  strcpy(c, a);
  strcpy(c, b);
  printf("Concatenacion de ambos: %s", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x50,%esi
  lea    D8(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x60(%rsp),%r12
  lea    0xc0(%rsp),%rbp
  call   <printf@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  mov    $0x50,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D23
type: string
name: retrieve_data
arguments: data_tag: D18
type: string

tool: D8: Introduce un texto (max %d cars.): 

tool: D23: Introduce otro texto (max %d cars.): 

tool: D18: Concatenacion de ambos: %s

assistant: ```c
int main(void) {
  char a[80 + 1], b[80 + 1], c[80 + 1];
  printf("Introduce un texto (max %d cars.): ", 80);
  gets(a);
  printf("Introduce otro texto (max %d cars.): ", 80);
  gets(b);
  strcpy(c, a);
  strcpy(c, b);
  printf("Concatenacion de ambos: %s", c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tag_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L36
  mov    $0xffffffff,%eax
  jmp    L30
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L35
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L35
  mov    -0x4(%rbp),%eax
  jmp    L30
L35:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L0
  mov    $0xffffffff,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int tag_exists(const char *tag, const char **tags) {
  int itag = 0;
  if (!tags)
    return -1;
  while (tags[itag]) {
    if (tags[itag][0] == tag[0] && tags[itag][1] == tag[1])
      return itag;
    itag++;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tag_exists>:
  endbr64
  test   %rsi,%rsi
  je     L7
  mov    (%rsi),%rdx
  test   %rdx,%rdx
  je     L39
  movzbl (%rdi),%r8d
  mov    $0x0,%eax
  jmp    L85
L25:
  add    $0x1,%rax
  mov    (%rsi,%rax,8),%rdx
  test   %rdx,%rdx
  je     L80
L85:
  mov    %eax,%ecx
  cmp    %r8b,(%rdx)
  jne    L25
  movzbl 0x1(%rdi),%r9d
  cmp    %r9b,0x1(%rdx)
  jne    L25
  jmp    L67
L80:
  mov    $0xffffffff,%ecx
L67:
  mov    %ecx,%eax
  ret
L7:
  mov    $0xffffffff,%ecx
  jmp    L67
L39:
  mov    $0xffffffff,%ecx
  jmp    L67
```

assistant: ```c
int tag_exists(const char *tag, const char **tags) {
  int itag = 0;
  if (!tags)
    return -1;
  while (tags[itag]) {
    if (tags[itag][0] == tag[0] && tags[itag][1] == tag[1])
      return itag;
    itag++;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tag_exists>:
  endbr64
  test   %rsi,%rsi
  je     L44
  mov    (%rsi),%rdx
  test   %rdx,%rdx
  je     L44
  movzbl (%rdi),%ecx
  xor    %eax,%eax
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rax
  mov    (%rsi,%rax,8),%rdx
  test   %rdx,%rdx
  je     L44
L3:
  mov    %eax,%r8d
  cmp    %cl,(%rdx)
  jne    L28
  movzbl 0x1(%rdi),%r9d
  cmp    %r9b,0x1(%rdx)
  jne    L28
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tag_exists(const char *tag, const char **tags) {
  int itag = 0;
  if (!tags)
    return -1;
  while (tags[itag]) {
    if (tags[itag][0] == tag[0] && tags[itag][1] == tag[1])
      return itag;
    itag++;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tag_exists>:
  endbr64
  test   %rsi,%rsi
  je     L8
  mov    (%rsi),%rdx
  test   %rdx,%rdx
  je     L8
  movzbl (%rdi),%ecx
  xor    %eax,%eax
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rax
  mov    (%rsi,%rax,8),%rdx
  test   %rdx,%rdx
  je     L8
L47:
  mov    %eax,%r8d
  cmp    %cl,(%rdx)
  jne    L42
  movzbl 0x1(%rdi),%r9d
  cmp    %r9b,0x1(%rdx)
  jne    L42
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tag_exists(const char *tag, const char **tags) {
  int itag = 0;
  if (!tags)
    return -1;
  while (tags[itag]) {
    if (tags[itag][0] == tag[0] && tags[itag][1] == tag[1])
      return itag;
    itag++;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_rid_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L39
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L19
L39:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L19:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_rid_of(char *string) {
  while ('\0' != *string) {
    if ('\r' == *string || '\n' == *string) {
      *string = '\0';
    }
    string++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_rid_of>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
L5:
  ret
L36:
  movb   $0x0,(%rdi)
L19:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
L11:
  cmp    $0xd,%al
  je     L36
  cmp    $0xa,%al
  jne    L19
  jmp    L36
```

assistant: ```c
void get_rid_of(char *string) {
  while ('\0' != *string) {
    if ('\r' == *string || '\n' == *string) {
      *string = '\0';
    }
    string++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_rid_of>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L23:
  add    $0x1,%rdi
L10:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  cmp    $0xd,%al
  je     L28
  cmp    $0xa,%al
  jne    L23
L28:
  movb   $0x0,(%rdi)
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void get_rid_of(char *string) {
  while ('\0' != *string) {
    if ('\r' == *string || '\n' == *string) {
      *string = '\0';
    }
    string++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_rid_of>:
  endbr64
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L30:
  add    $0x1,%rdi
L5:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L43
L10:
  cmp    $0xd,%al
  je     L22
  cmp    $0xa,%al
  jne    L30
L22:
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  ret
```

assistant: ```c
void get_rid_of(char *string) {
  while ('\0' != *string) {
    if ('\r' == *string || '\n' == *string) {
      *string = '\0';
    }
    string++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bits_to_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %ecx,%eax
  mov    %r8d,%r10d
  mov    0x10(%rbp),%r8d
  mov    0x18(%rbp),%ecx
  mov    %dil,-0x14(%rbp)
  mov    %sil,-0x18(%rbp)
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    %r10d,%eax
  mov    %al,-0x24(%rbp)
  mov    %r9d,%eax
  mov    %al,-0x28(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x2c(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x30(%rbp)
  movzbl -0x30(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x2c(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x28(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x24(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x20(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x1c(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x18(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char bits_to_byte(char bt0, char bt1, char bt2, char bt3, char bt4, char bt5, char bt6, char bt7) {
  unsigned char rbyte;
  rbyte = (unsigned char)(bt0 + (2 * bt1) + (4 * bt2) + (8 * bt3) + (16 * bt4) + (32 * bt5) + (64 * bt6) + (128 * bt7));
  return (rbyte);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bits_to_byte>:
  endbr64
  movzbl 0x10(%rsp),%eax
  add    %eax,%eax
  add    0x8(%rsp),%al
  lea    (%r9,%rax,2),%eax
  lea    (%r8,%rax,2),%eax
  lea    (%rcx,%rax,2),%eax
  lea    (%rdx,%rax,2),%eax
  lea    (%rsi,%rax,2),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bits_to_byte(char bt0, char bt1, char bt2, char bt3, char bt4, char bt5, char bt6, char bt7) {
  unsigned char rbyte;
  rbyte = (unsigned char)(bt0 + (2 * bt1) + (4 * bt2) + (8 * bt3) + (16 * bt4) + (32 * bt5) + (64 * bt6) + (128 * bt7));
  return (rbyte);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bits_to_byte>:
  endbr64
  movzbl 0x10(%rsp),%eax
  add    %eax,%eax
  add    0x8(%rsp),%al
  lea    (%r9,%rax,2),%eax
  lea    (%r8,%rax,2),%eax
  lea    (%rcx,%rax,2),%eax
  lea    (%rdx,%rax,2),%eax
  lea    (%rsi,%rax,2),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bits_to_byte(char bt0, char bt1, char bt2, char bt3, char bt4, char bt5, char bt6, char bt7) {
  unsigned char rbyte;
  rbyte = (unsigned char)(bt0 + (2 * bt1) + (4 * bt2) + (8 * bt3) + (16 * bt4) + (32 * bt5) + (64 * bt6) + (128 * bt7));
  return (rbyte);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bits_to_byte>:
  endbr64
  movzbl 0x10(%rsp),%eax
  add    %eax,%eax
  add    0x8(%rsp),%al
  lea    (%r9,%rax,2),%eax
  lea    (%r8,%rax,2),%eax
  lea    (%rcx,%rax,2),%eax
  lea    (%rdx,%rax,2),%eax
  lea    (%rsi,%rax,2),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bits_to_byte(char bt0, char bt1, char bt2, char bt3, char bt4, char bt5, char bt6, char bt7) {
  unsigned char rbyte;
  rbyte = (unsigned char)(bt0 + (2 * bt1) + (4 * bt2) + (8 * bt3) + (16 * bt4) + (32 * bt5) + (64 * bt6) + (128 * bt7));
  return (rbyte);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ketopt_permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L4:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L4
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ketopt_permute(char *argv[], int j, int n) {
  int k;
  char *p = argv[j];
  for (k = 0; k < n; ++k)
    argv[j - k] = argv[j - k - 1];
  argv[j - k] = p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ketopt_permute>:
  endbr64
  mov    %rdi,%r8
  movslq %esi,%rcx
  shl    $0x3,%rcx
  lea    (%rdi,%rcx,1),%rax
  mov    (%rax),%r9
  test   %edx,%edx
  jle    L9
  lea    -0x8(%rdi,%rcx,1),%rdi
  lea    -0x1(%rdx),%ecx
  shl    $0x3,%rcx
  sub    %rcx,%rdi
L27:
  mov    -0x8(%rax),%rcx
  mov    %rcx,(%rax)
  sub    $0x8,%rax
  cmp    %rdi,%rax
  jne    L27
L6:
  sub    %edx,%esi
  movslq %esi,%rsi
  mov    %r9,(%r8,%rsi,8)
  ret
L9:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
void ketopt_permute(char *argv[], int j, int n) {
  int k;
  char *p = argv[j];
  for (k = 0; k < n; ++k)
    argv[j - k] = argv[j - k - 1];
  argv[j - k] = p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ketopt_permute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  movslq %esi,%rdi
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%rdi
  lea    0x0(%rbp,%rdi,1),%rax
  sub    $0x8,%rsp
  mov    (%rax),%r13
  test   %edx,%edx
  jle    L5
  lea    -0x1(%rdx),%eax
  mov    %edx,%r12d
  mov    %edx,%edx
  neg    %rax
  sub    %r12d,%ebx
  shl    $0x3,%rdx
  shl    $0x3,%rax
  movslq %ebx,%rbx
  lea    -0x8(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  add    %rbp,%rsi
  add    %rbp,%rdi
  call   <memmove@plt>
  lea    0x0(%rbp,%rbx,8),%rax
L5:
  mov    %r13,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ketopt_permute(char *argv[], int j, int n) {
  int k;
  char *p = argv[j];
  for (k = 0; k < n; ++k)
    argv[j - k] = argv[j - k - 1];
  argv[j - k] = p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ketopt_permute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  movslq %esi,%rdi
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%rdi
  lea    0x0(%rbp,%rdi,1),%rax
  sub    $0x8,%rsp
  mov    (%rax),%r13
  test   %edx,%edx
  jle    L9
  lea    -0x1(%rdx),%eax
  mov    %edx,%r12d
  mov    %edx,%edx
  neg    %rax
  sub    %r12d,%ebx
  shl    $0x3,%rdx
  shl    $0x3,%rax
  movslq %ebx,%rbx
  lea    -0x8(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  add    %rbp,%rsi
  add    %rbp,%rdi
  call   <memmove@plt>
  lea    0x0(%rbp,%rbx,8),%rax
L9:
  mov    %r13,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ketopt_permute(char *argv[], int j, int n) {
  int k;
  char *p = argv[j];
  for (k = 0; k < n; ++k)
    argv[j - k] = argv[j - k - 1];
  argv[j - k] = p;
}
```