ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_fun>:
  endbr64
  test   %edi,%edi
  jle    L9
  mov    $0x1,%eax
  test   %esi,%esi
  jg     L35
L9:
  lea    (%rdi,%rsi,1),%edx
  jmp    L39
L49:
  mov    %esi,%edi
L27:
  add    $0x1,%eax
L35:
  cmp    %edi,%esi
  jl     L49
  mov    %eax,%edx
  sub    $0x1,%edi
  jne    L27
L39:
  mov    %edx,%eax
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  if (x <= 0 || y <= 0) {
    return x + y;
  }
  while (!(x == 0)) {
    if (x > y) {
      x = y;
    } else {
      x = x - 1;
    }
    c = c + 1;
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_fun>:
  endbr64
  test   %edi,%edi
  jle    L1
  xor    %eax,%eax
  test   %esi,%esi
  jle    L1
  xchg   %ax,%ax
L45:
  add    $0x1,%eax
  cmp    %edi,%esi
  jl     L18
  sub    $0x1,%edi
  jne    L45
  ret
  nopl   (%rax)
L18:
  mov    %esi,%edi
  jmp    L45
  nopl   0x0(%rax)
L1:
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  if (x <= 0 || y <= 0) {
    return x + y;
  }
  while (!(x == 0)) {
    if (x > y) {
      x = y;
    } else {
      x = x - 1;
    }
    c = c + 1;
  }
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_fun>:
  endbr64
  test   %edi,%edi
  jle    L26
  xor    %eax,%eax
  test   %esi,%esi
  jle    L26
  xchg   %ax,%ax
L10:
  add    $0x1,%eax
  cmp    %edi,%esi
  jl     L30
  sub    $0x1,%edi
  jne    L10
  ret
  nopl   (%rax)
L30:
  mov    %esi,%edi
  jmp    L10
  nopl   0x0(%rax)
L26:
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  if (x <= 0 || y <= 0) {
    return x + y;
  }
  while (!(x == 0)) {
    if (x > y) {
      x = y;
    } else {
      x = x - 1;
    }
    c = c + 1;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x41,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L30:
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L43:
  addl   $0x1,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%edi
  call   <putchar@plt>
L33:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L43
  subl   $0x1,-0x10(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L16:
  cmpl   $0x0,-0x10(%rbp)
  jg     L30
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main() {
  int x, y, n, m = 'A';
  scanf("%d", &n);
  for (y = n; y > 0; y--, printf("\n"))
    for (x = 0; x < y; x++, printf("%c", m++))
      ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  mov    $0x41,%ebx
  test   %r12d,%r12d
  jg     L16
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L18
L35:
  sub    $0x1,%r12d
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %r12d,%r12d
  je     L41
L16:
  lea    (%rbx,%r12,1),%ebp
  test   %r12d,%r12d
  jg     L18
  jmp    L35
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: %d

assistant: ```c
int main() {
  int x, y, n, m = 'A';
  scanf("%d", &n);
  for (y = n; y > 0; y--, printf("\n"))
    for (x = 0; x < y; x++, printf("%c", m++))
      ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jle    L12
  mov    $0x41,%r12d
  xor    %r13d,%r13d
L15:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  lea    (%rbx,%r12,1),%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jl     L18
  test   %ebp,%ebp
  lea    -0x1(%rbp),%eax
  mov    $0xa,%edi
  cmovle %r13d,%eax
  sub    $0x1,%ebp
  lea    0x1(%r12,%rax,1),%r12d
  call   <putchar@plt>
  test   %ebp,%ebp
  jne    L15
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  int x, y, n, m = 'A';
  scanf("%d", &n);
  for (y = n; y > 0; y--, printf("\n"))
    for (x = 0; x < y; x++, printf("%c", m++))
      ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jle    L38
  mov    $0x41,%r12d
  xor    %r13d,%r13d
L6:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L39:
  lea    (%rbx,%r12,1),%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jl     L39
  test   %ebp,%ebp
  lea    -0x1(%rbp),%eax
  mov    $0xa,%edi
  cmovle %r13d,%eax
  sub    $0x1,%ebp
  lea    0x1(%r12,%rax,1),%r12d
  call   <putchar@plt>
  test   %ebp,%ebp
  jne    L6
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d

assistant: ```c
int main() {
  int x, y, n, m = 'A';
  scanf("%d", &n);
  for (y = n; y > 0; y--, printf("\n"))
    for (x = 0; x < y; x++, printf("%c", m++))
      ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<god_mode_finish>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void god_mode_finish() {
  endwin();
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<god_mode_finish>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void god_mode_finish() {
  endwin();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<god_mode_finish>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void god_mode_finish() {
  endwin();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<god_mode_finish>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void god_mode_finish() {
  endwin();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printHeaderWithFactorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D17: Number	Factorial	Approximation1		Approximation2


tool: D6: ---------------------------------------------------------------


assistant: ```c
void printHeaderWithFactorial() {
  printf("Number\tFactorial\tApproximation1\t\tApproximation2\n");
  printf("-------------------------------------------------------"
         "--------\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printHeaderWithFactorial>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D19: Number	Factorial	Approximation1		Approximation2


tool: D2: ---------------------------------------------------------------


assistant: ```c
void printHeaderWithFactorial() {
  printf("Number\tFactorial\tApproximation1\t\tApproximation2\n");
  printf("-------------------------------------------------------"
         "--------\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printHeaderWithFactorial>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D2: Number	Factorial	Approximation1		Approximation2


tool: D18: ---------------------------------------------------------------


assistant: ```c
void printHeaderWithFactorial() {
  printf("Number\tFactorial\tApproximation1\t\tApproximation2\n");
  printf("-------------------------------------------------------"
         "--------\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printHeaderWithFactorial>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type: string
name: disassemble_data
arguments: data_tag: D4
type: string

tool: D17: Number	Factorial	Approximation1		Approximation2


tool: D4: ---------------------------------------------------------------


assistant: ```c
void printHeaderWithFactorial() {
  printf("Number\tFactorial\tApproximation1\t\tApproximation2\n");
  printf("-------------------------------------------------------"
         "--------\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type: string
name: disassemble_data
arguments: data_tag: D7
type: string
name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D32
type: string

tool: D18: Enter a character: 

tool: D7: %s

tool: D13: %c

tool: D32: ASCII value of %c = %d

assistant: ```c
int main() {
  char c;
  printf("%s", "Enter a character: ");
  scanf("%c", &c);
  printf("ASCII value of %c = %d", c, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  mov    %esi,%edx
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
datatype: string
name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D25
datatype: string

tool: D18: Enter a character: 

tool: D3: %s

tool: D2: %c

tool: D25: ASCII value of %c = %d

assistant: ```c
int main() {
  char c;
  printf("%s", "Enter a character: ");
  scanf("%c", &c);
  printf("ASCII value of %c = %d", c, c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rsi
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  mov    %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D20
type_infered: string

tool: D15: Enter a character: 

tool: D3: %s

tool: D16: %c

tool: D20: ASCII value of %c = %d

assistant: ```c
int main() {
  char c;
  printf("%s", "Enter a character: ");
  scanf("%c", &c);
  printf("ASCII value of %c = %d", c, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rsi
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  mov    %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D39
data_type: string
name: disassemble_data
arguments: data_tag: D36
data_type: string

tool: D5: Enter a character: 

tool: D23: %s

tool: D39: %c

tool: D36: ASCII value of %c = %d

assistant: ```c
int main() {
  char c;
  printf("%s", "Enter a character: ");
  scanf("%c", &c);
  printf("ASCII value of %c = %d", c, c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<value_map_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x2,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L30
  movsd  D34(%rip),%xmm0
  jmp    L67
L30:
  cmpl   $0x1,-0x4(%rbp)
  jne    L46
  movsd  D41(%rip),%xmm0
  jmp    L67
L46:
  cmpl   $0x2,-0x4(%rbp)
  jne    L11
  movsd  D39(%rip),%xmm0
  jmp    L67
L11:
  cmpl   $0x3,-0x4(%rbp)
  jne    L71
  movsd  D4(%rip),%xmm0
  jmp    L67
L71:
  movsd  D40(%rip),%xmm0
L67:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D34
type_infered: f64
name: extract_symbolic_data
arguments: label: D41
type_infered: f64
name: extract_symbolic_data
arguments: label: D39
type_infered: f64
name: extract_symbolic_data
arguments: label: D4
type_infered: f64
name: extract_symbolic_data
arguments: label: D40
type_infered: f64

tool: D34: 0.01

tool: D41: 0.03

tool: D39: 0.05

tool: D4: 0.07

tool: D40: 0.1

assistant: ```c
double value_map_size(char *seq, long gen_number) {
  int x = gen_number % 5;
  if (x == 0)
    return 0.01;
  else if (x == 1)
    return 0.03;
  else if (x == 2)
    return 0.05;
  else if (x == 3)
    return 0.07;
  else
    return 0.1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<value_map_size>:
  endbr64
  movabs $0x6666666666666667,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rsi,%rdx
  sub    %rax,%rdx
  movsd  D0(%rip),%xmm0
  cmp    %eax,%esi
  je     L6
  cmp    $0x1,%edx
  je     L23
  cmp    $0x2,%edx
  je     L36
  movsd  D35(%rip),%xmm0
  cmp    $0x3,%edx
  je     L6
  movsd  D14(%rip),%xmm0
  ret
L23:
  movsd  D16(%rip),%xmm0
  ret
L36:
  movsd  D38(%rip),%xmm0
L6:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: f64
name: retrieve_data
arguments: data_label: D35
type_guessed: f64
name: retrieve_data
arguments: data_label: D14
type_guessed: f64
name: retrieve_data
arguments: data_label: D16
type_guessed: f64
name: retrieve_data
arguments: data_label: D38
type_guessed: f64

tool: D0: 0.01

tool: D35: 0.07

tool: D14: 0.1

tool: D16: 0.03

tool: D38: 0.05

assistant: ```c
double value_map_size(char *seq, long gen_number) {
  int x = gen_number % 5;
  if (x == 0)
    return 0.01;
  else if (x == 1)
    return 0.03;
  else if (x == 2)
    return 0.05;
  else if (x == 3)
    return 0.07;
  else
    return 0.1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<value_map_size>:
  endbr64
  mov    %rsi,%rax
  movsd  D8(%rip),%xmm0
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  sub    %rax,%rsi
  je     L38
  cmp    $0x1,%rsi
  je     L17
  cmp    $0x2,%esi
  je     L26
  movsd  D49(%rip),%xmm0
  cmp    $0x3,%esi
  je     L38
  movsd  D11(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movsd  D7(%rip),%xmm0
L38:
  ret
  nopl   0x0(%rax)
L17:
  movsd  D15(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: f64
name: retrieve_data
arguments: data_label: D49
type_guessed: f64
name: retrieve_data
arguments: data_label: D11
type_guessed: f64
name: retrieve_data
arguments: data_label: D7
type_guessed: f64
name: retrieve_data
arguments: data_label: D15
type_guessed: f64

tool: D8: 0.01

tool: D49: 0.07

tool: D11: 0.1

tool: D7: 0.05

tool: D15: 0.03

assistant: ```c
double value_map_size(char *seq, long gen_number) {
  int x = gen_number % 5;
  if (x == 0)
    return 0.01;
  else if (x == 1)
    return 0.03;
  else if (x == 2)
    return 0.05;
  else if (x == 3)
    return 0.07;
  else
    return 0.1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<value_map_size>:
  endbr64
  mov    %rsi,%rax
  movsd  D47(%rip),%xmm0
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  sub    %rax,%rsi
  je     L31
  cmp    $0x1,%rsi
  je     L28
  cmp    $0x2,%esi
  je     L23
  movsd  D30(%rip),%xmm0
  cmp    $0x3,%esi
  je     L31
  movsd  D42(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  movsd  D2(%rip),%xmm0
L31:
  ret
  nopl   0x0(%rax)
L28:
  movsd  D16(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D47
type: f64
name: extract_symbolic_data
arguments: data_tag: D30
type: f64
name: extract_symbolic_data
arguments: data_tag: D42
type: f64
name: extract_symbolic_data
arguments: data_tag: D2
type: f64
name: extract_symbolic_data
arguments: data_tag: D16
type: f64

tool: D47: 0.01

tool: D30: 0.07

tool: D42: 0.1

tool: D2: 0.05

tool: D16: 0.03

assistant: ```c
double value_map_size(char *seq, long gen_number) {
  int x = gen_number % 5;
  if (x == 0)
    return 0.01;
  else if (x == 1)
    return 0.03;
  else if (x == 2)
    return 0.05;
  else if (x == 3)
    return 0.07;
  else
    return 0.1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xxtea_uint_decrypt>:
  endbr64
  mov    %esi,%ecx
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L31
  mov    %rdx,%r10
  mov    $0x34,%eax
  cltd
  idiv   %ecx
  add    $0x6,%eax
  imul   $0x9e3779b9,%eax,%r8d
  test   %r8d,%r8d
  je     L31
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%eax
  movslq %esi,%r11
  lea    (%rdi,%r11,4),%rbx
L36:
  mov    %r8d,%r9d
  sar    $0x2,%r9d
  mov    %r11,%rsi
L19:
  mov    -0x4(%rdi,%rsi,4),%ecx
  mov    %r9d,%edx
  xor    %esi,%edx
  and    $0x3,%edx
  mov    %ecx,%ebp
  xor    (%r10,%rdx,4),%ebp
  mov    %eax,%r12d
  xor    %r8d,%r12d
  lea    0x0(%rbp,%r12,1),%ebp
  mov    %ecx,%edx
  sar    $0x5,%edx
  lea    0x0(,%rax,4),%r12d
  xor    %r12d,%edx
  sar    $0x3,%eax
  shl    $0x4,%ecx
  xor    %ecx,%eax
  add    %edx,%eax
  mov    %ebp,%edx
  xor    %eax,%edx
  mov    (%rdi,%rsi,4),%eax
  sub    %edx,%eax
  mov    %eax,(%rdi,%rsi,4)
  sub    $0x1,%rsi
  test   %esi,%esi
  jg     L19
  mov    (%rbx),%ecx
  mov    %ecx,%edx
  sar    $0x5,%edx
  lea    0x0(,%rax,4),%esi
  xor    %esi,%edx
  mov    %eax,%esi
  sar    $0x3,%esi
  mov    %ecx,%ebp
  shl    $0x4,%ebp
  xor    %ebp,%esi
  add    %esi,%edx
  and    $0x3,%r9d
  xor    (%r10,%r9,4),%ecx
  xor    %r8d,%eax
  add    %eax,%ecx
  xor    %ecx,%edx
  mov    (%rdi),%eax
  sub    %edx,%eax
  mov    %eax,(%rdi)
  add    $0x61c88647,%r8d
  jne    L36
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint32_t *xxtea_uint_decrypt(uint32_t *data, size_t len, uint32_t *key) {
  uint32_t n = (uint32_t)len - 1;
  uint32_t z, y = data[0], p, q = 6 + 52 / (n + 1), sum = q * 0x9e3779b9, e;
  if (n < 1)
    return data;
  while (sum != 0) {
    e = sum >> 2 & 3;
    for (p = n; p > 0; p--) {
      z = data[p - 1];
      y = data[p] -= (((z >> 5) ^ (y << 2)) + ((y >> 3) ^ (z << 4))) ^ ((sum ^ y) + (key[(p & 3) ^ e] ^ z));
    }
    z = data[n];
    y = data[0] -= (((z >> 5) ^ (y << 2)) + ((y >> 3) ^ (z << 4))) ^ ((sum ^ y) + (key[(p & 3) ^ e] ^ z));
    sum -= 0x9e3779b9;
  }
  return data;
}
```