ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<alg_get>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    0x8(%rdi),%rax
  mov    %rsp,%rsi
  xor    %edi,%edi
  mov    (%rax),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rsp)
  mov    0x8(%rax),%edx
  call   <d2i_PBEPARAM@plt>
  mov    (%rbx),%edi
  mov    %rax,%rbp
  call   <OBJ_obj2nid@plt>
  mov    %eax,(%r14)
  mov    0x8(%rbp),%edi
  call   <ASN1_INTEGER_get@plt>
  mov    %rbp,%rdi
  mov    %eax,0x0(%r13)
  mov    0x0(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%r12)
  call   <PBEPARAM_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int alg_get(X509_ALGOR *alg, int *pnid, int *piter, int *psaltlen) {
  PBEPARAM *pbe;
  const unsigned char *p;
  p = alg->parameter->value.sequence->data;
  pbe = d2i_PBEPARAM(NULL, &p, alg->parameter->value.sequence->length);
  *pnid = OBJ_obj2nid(alg->algorithm);
  *piter = ASN1_INTEGER_get(pbe->iter);
  *psaltlen = pbe->salt->length;
  PBEPARAM_free(pbe);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<alg_get>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    0x8(%rdi),%rax
  mov    %rsp,%rsi
  xor    %edi,%edi
  mov    (%rax),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rsp)
  mov    0x8(%rax),%edx
  call   <d2i_PBEPARAM@plt>
  mov    (%rbx),%edi
  mov    %rax,%rbp
  call   <OBJ_obj2nid@plt>
  mov    %eax,(%r14)
  mov    0x8(%rbp),%edi
  call   <ASN1_INTEGER_get@plt>
  mov    %rbp,%rdi
  mov    %eax,0x0(%r13)
  mov    0x0(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%r12)
  call   <PBEPARAM_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int alg_get(X509_ALGOR *alg, int *pnid, int *piter, int *psaltlen) {
  PBEPARAM *pbe;
  const unsigned char *p;
  p = alg->parameter->value.sequence->data;
  pbe = d2i_PBEPARAM(NULL, &p, alg->parameter->value.sequence->length);
  *pnid = OBJ_obj2nid(alg->algorithm);
  *piter = ASN1_INTEGER_get(pbe->iter);
  *psaltlen = pbe->salt->length;
  PBEPARAM_free(pbe);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mhs_diff_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L15
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  movabs $0x100000000,%rdx
  add    %rdx,%rax
  jmp    L2
L15:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
L2:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long mhs_diff_time(unsigned long now, unsigned long stamp) {
  if (stamp > now)
    return ((0xFFFFFFFF - stamp) + now + 1);
  else
    return (now - stamp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mhs_diff_time>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    %rdi,%rsi
  jbe    L9
  movabs $0x100000000,%rax
  add    %rdi,%rax
  sub    %rsi,%rax
L9:
  ret
```

assistant: ```c
unsigned long mhs_diff_time(unsigned long now, unsigned long stamp) {
  if (stamp > now)
    return ((0xFFFFFFFF - stamp) + now + 1);
  else
    return (now - stamp);
}
```
user: What is the c source code of the assembly code below?

```asm
<mhs_diff_time>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    %rdi,%rsi
  jbe    L5
  movabs $0x100000000,%rax
  add    %rdi,%rax
  sub    %rsi,%rax
L5:
  ret
```

assistant: ```c
unsigned long mhs_diff_time(unsigned long now, unsigned long stamp) {
  if (stamp > now)
    return ((0xFFFFFFFF - stamp) + now + 1);
  else
    return (now - stamp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mhs_diff_time>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    %rdi,%rsi
  jbe    L2
  movabs $0x100000000,%rax
  add    %rdi,%rax
  sub    %rsi,%rax
L2:
  ret
```

assistant: ```c
unsigned long mhs_diff_time(unsigned long now, unsigned long stamp) {
  if (stamp > now)
    return ((0xFFFFFFFF - stamp) + now + 1);
  else
    return (now - stamp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<syntFilter>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%r9d
  mov    %rcx,%r8
  lea    0x4(%rsi),%r10
  lea    0x24(%rcx),%rbp
  mov    %rdi,%rcx
  mov    %r10,%rax
  mov    $0x28,%esi
  mov    $0x0,%r11d
  add    $0x30,%rbx
  jmp    L6
L17:
  mov    %rcx,%r12
  test   %r11d,%r11d
  jle    L46
  lea    -0x2c(%rcx,%rsi,1),%r13
  mov    %r10,%rdx
  mov    %rcx,%rax
L62:
  add    $0x4,%rdx
  sub    $0x4,%rax
  movss  -0x4(%rdx),%xmm1
  mulss  0x4(%rax),%xmm1
  movss  0x4(%r12),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%r12)
  cmp    %r13,%rax
  jne    L62
  mov    %rbx,%rax
  sub    %rsi,%rax
L48:
  add    $0x4,%rcx
  sub    $0x4,%rsi
L6:
  add    $0x1,%r11d
  cmp    $0xa,%r11d
  jg     L17
  lea    (%rax,%rsi,1),%r12
  mov    %rbp,%rdx
L81:
  add    $0x4,%rax
  sub    $0x4,%rdx
  movss  -0x4(%rax),%xmm1
  mulss  0x4(%rdx),%xmm1
  movss  (%rcx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
  cmp    %r12,%rax
  jne    L81
  cmp    $0xa,%r11d
  jne    L17
  cmp    $0xa,%r9d
  jle    L13
  lea    -0x4(%rdi),%rdx
  lea    -0xb(%r9),%eax
  lea    (%rdi,%rax,4),%rsi
L28:
  lea    0x28(%rdx),%rax
  mov    %r10,%rcx
L89:
  add    $0x4,%rcx
  sub    $0x4,%rax
  movss  -0x4(%rcx),%xmm1
  mulss  0x4(%rax),%xmm1
  movss  0x2c(%rdx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x2c(%rdx)
  cmp    %rax,%rdx
  jne    L89
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  jne    L28
L13:
  movslq %r9d,%r9
  lea    -0x28(%rdi,%r9,4),%rsi
  mov    $0x28,%edx
  mov    %r8,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  mov    %r10,%rax
  jmp    L48
```

assistant: ```c
void syntFilter(float *Out, float *a, int len, float *mem) {
  int i;
  int j;
  float *po;
  float *pi;
  float *pa;
  float *pm;
  po = Out;
  for (i = 0; i < 10; i++) {
    pi = &Out[i - 1];
    pa = &a[1];
    pm = &mem[10 - 1];
    for (j = 1; j <= i; j++)
      *po -= (*pa++) * (*pi--);
    for (j = i + 1; j < 10 + 1; j++)
      *po -= (*pa++) * (*pm--);
    po++;
  }
  for (i = 10; i < len; i++) {
    pi = &Out[i - 1];
    pa = &a[1];
    for (j = 1; j < 10 + 1; j++)
      *po -= (*pa++) * (*pi--);
    po++;
  }
  memcpy(mem, &Out[len - 10], 10 * sizeof(float));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<syntFilter>:
  endbr64
  lea    0x4(%rsi),%r10
  push   %r12
  lea    0x8(%rsi),%r11
  movslq %edx,%r9
  push   %rbp
  mov    %rcx,%r8
  lea    0x24(%rcx),%r12
  mov    %rdi,%rsi
  push   %rbx
  mov    %r10,%rax
  xor    %ebx,%ebx
  lea    0x28(%rdi),%rbp
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %rbp,%rcx
  movss  (%rsi),%xmm1
  add    $0x1,%ebx
  mov    %r12,%rdx
  sub    %rsi,%rcx
  add    %rax,%rcx
  nopl   0x0(%rax,%rax,1)
L52:
  sub    $0x4,%rdx
  movss  (%rax),%xmm0
  add    $0x4,%rax
  mulss  0x4(%rdx),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rsi)
  cmp    %rcx,%rax
  jne    L52
  cmp    $0xa,%ebx
  je     L31
  movss  0x4(%rsi),%xmm1
  mov    %r10,%rdx
  mov    %rsi,%rcx
  cs nopw 0x0(%rax,%rax,1)
L47:
  sub    $0x4,%rcx
  movss  (%rdx),%xmm0
  add    $0x4,%rdx
  mov    %r11,%rax
  mulss  0x4(%rcx),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rsi)
  cmp    %r11,%rdx
  jne    L47
  add    $0x4,%rsi
  add    $0x4,%r11
  jmp    L59
  nopl   0x0(%rax)
L31:
  cmp    $0xa,%r9d
  jle    L37
  lea    -0xb(%r9),%eax
  lea    -0x4(%rdi),%rcx
  lea    (%rdi,%rax,4),%rsi
  nopw   0x0(%rax,%rax,1)
L0:
  movss  0x2c(%rcx),%xmm1
  lea    0x28(%rcx),%rax
  mov    %r10,%rdx
  nopl   0x0(%rax)
L51:
  sub    $0x4,%rax
  movss  (%rdx),%xmm0
  add    $0x4,%rdx
  mulss  0x4(%rax),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0x2c(%rcx)
  cmp    %rcx,%rax
  jne    L51
  add    $0x4,%rcx
  cmp    %rcx,%rsi
  jne    L0
L37:
  pop    %rbx
  lea    -0x28(%rdi,%r9,4),%rsi
  pop    %rbp
  mov    $0x28,%edx
  mov    %r8,%rdi
  pop    %r12
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void syntFilter(float *Out, float *a, int len, float *mem) {
  int i;
  int j;
  float *po;
  float *pi;
  float *pa;
  float *pm;
  po = Out;
  for (i = 0; i < 10; i++) {
    pi = &Out[i - 1];
    pa = &a[1];
    pm = &mem[10 - 1];
    for (j = 1; j <= i; j++)
      *po -= (*pa++) * (*pi--);
    for (j = i + 1; j < 10 + 1; j++)
      *po -= (*pa++) * (*pm--);
    po++;
  }
  for (i = 10; i < len; i++) {
    pi = &Out[i - 1];
    pa = &a[1];
    for (j = 1; j < 10 + 1; j++)
      *po -= (*pa++) * (*pi--);
    po++;
  }
  memcpy(mem, &Out[len - 10], 10 * sizeof(float));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rnc_larger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  cmpb   $0x0,-0x8(%rbp)
  jne    L111
  mov    $0x1,%eax
  jmp    L50
L111:
  cmpb   $0x0,-0x4(%rbp)
  jne    L79
  mov    $0x0,%eax
  jmp    L50
L79:
  cmpb   $0x4d,-0x8(%rbp)
  jne    L47
  mov    $0x0,%eax
  jmp    L50
L47:
  cmpb   $0x4d,-0x4(%rbp)
  jne    L155
  mov    $0x1,%eax
  jmp    L50
L155:
  cmpb   $0x44,-0x8(%rbp)
  jne    L149
  mov    $0x0,%eax
  jmp    L50
L149:
  cmpb   $0x44,-0x4(%rbp)
  jne    L40
  mov    $0x1,%eax
  jmp    L50
L40:
  cmpb   $0x43,-0x8(%rbp)
  jne    L237
  mov    $0x0,%eax
  jmp    L50
L237:
  cmpb   $0x43,-0x4(%rbp)
  jne    L154
  mov    $0x1,%eax
  jmp    L50
L154:
  cmpb   $0x4c,-0x8(%rbp)
  jne    L60
  mov    $0x0,%eax
  jmp    L50
L60:
  cmpb   $0x4c,-0x4(%rbp)
  jne    L211
  mov    $0x1,%eax
  jmp    L50
L211:
  cmpb   $0x58,-0x8(%rbp)
  jne    L215
  mov    $0x0,%eax
  jmp    L50
L215:
  cmpb   $0x58,-0x4(%rbp)
  jne    L72
  mov    $0x1,%eax
  jmp    L50
L72:
  cmpb   $0x56,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
L50:
  pop    %rbp
  ret
```

assistant: ```c
bool rnc_larger(char l, char r) {
  if (!r)
    return true;
  else if (!l)
    return false;
  else if (r == 'M')
    return false;
  else if (l == 'M')
    return true;
  else if (r == 'D')
    return false;
  else if (l == 'D')
    return true;
  else if (r == 'C')
    return false;
  else if (l == 'C')
    return true;
  else if (r == 'L')
    return false;
  else if (l == 'L')
    return true;
  else if (r == 'X')
    return false;
  else if (l == 'X')
    return true;
  else
    return r != 'V';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rnc_larger>:
  endbr64
  mov    $0x1,%eax
  test   %sil,%sil
  je     L98
  cmp    $0x4d,%sil
  je     L103
  test   %dil,%dil
  je     L103
  cmp    $0x4d,%dil
  je     L98
  mov    $0x0,%eax
  cmp    $0x44,%sil
  je     L98
  mov    $0x1,%eax
  cmp    $0x44,%dil
  je     L98
  mov    $0x0,%eax
  cmp    $0x43,%sil
  je     L98
  mov    $0x1,%eax
  cmp    $0x43,%dil
  je     L98
  mov    $0x0,%eax
  cmp    $0x4c,%sil
  je     L98
  mov    $0x1,%eax
  cmp    $0x4c,%dil
  je     L98
  mov    $0x0,%eax
  cmp    $0x58,%sil
  je     L98
  mov    $0x1,%eax
  cmp    $0x58,%dil
  je     L98
  cmp    $0x56,%sil
  setne  %al
  movzbl %al,%eax
  ret
L103:
  mov    $0x0,%eax
L98:
  ret
```

assistant: ```c
bool rnc_larger(char l, char r) {
  if (!r)
    return true;
  else if (!l)
    return false;
  else if (r == 'M')
    return false;
  else if (l == 'M')
    return true;
  else if (r == 'D')
    return false;
  else if (l == 'D')
    return true;
  else if (r == 'C')
    return false;
  else if (l == 'C')
    return true;
  else if (r == 'L')
    return false;
  else if (l == 'L')
    return true;
  else if (r == 'X')
    return false;
  else if (l == 'X')
    return true;
  else
    return r != 'V';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rnc_larger>:
  endbr64
  mov    $0x1,%eax
  test   %sil,%sil
  je     L7
  cmp    $0x4d,%sil
  je     L13
  test   %dil,%dil
  je     L13
  cmp    $0x4d,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x44,%sil
  je     L7
  mov    $0x1,%eax
  cmp    $0x44,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x43,%sil
  je     L7
  mov    $0x1,%eax
  cmp    $0x43,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x4c,%sil
  je     L7
  mov    $0x1,%eax
  cmp    $0x4c,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x58,%sil
  je     L7
  mov    $0x1,%eax
  cmp    $0x58,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x56,%sil
  setne  %al
  ret
  nopl   (%rax)
L13:
  xor    %eax,%eax
L7:
  ret
```

assistant: ```c
bool rnc_larger(char l, char r) {
  if (!r)
    return true;
  else if (!l)
    return false;
  else if (r == 'M')
    return false;
  else if (l == 'M')
    return true;
  else if (r == 'D')
    return false;
  else if (l == 'D')
    return true;
  else if (r == 'C')
    return false;
  else if (l == 'C')
    return true;
  else if (r == 'L')
    return false;
  else if (l == 'L')
    return true;
  else if (r == 'X')
    return false;
  else if (l == 'X')
    return true;
  else
    return r != 'V';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rnc_larger>:
  endbr64
  mov    $0x1,%eax
  test   %sil,%sil
  je     L110
  cmp    $0x4d,%sil
  je     L78
  test   %dil,%dil
  je     L78
  cmp    $0x4d,%dil
  je     L110
  xor    %eax,%eax
  cmp    $0x44,%sil
  je     L110
  mov    $0x1,%eax
  cmp    $0x44,%dil
  je     L110
  xor    %eax,%eax
  cmp    $0x43,%sil
  je     L110
  mov    $0x1,%eax
  cmp    $0x43,%dil
  je     L110
  xor    %eax,%eax
  cmp    $0x4c,%sil
  je     L110
  mov    $0x1,%eax
  cmp    $0x4c,%dil
  je     L110
  xor    %eax,%eax
  cmp    $0x58,%sil
  je     L110
  mov    $0x1,%eax
  cmp    $0x58,%dil
  je     L110
  xor    %eax,%eax
  cmp    $0x56,%sil
  setne  %al
  ret
  nopl   (%rax)
L78:
  xor    %eax,%eax
L110:
  ret
```

assistant: ```c
bool rnc_larger(char l, char r) {
  if (!r)
    return true;
  else if (!l)
    return false;
  else if (r == 'M')
    return false;
  else if (l == 'M')
    return true;
  else if (r == 'D')
    return false;
  else if (l == 'D')
    return true;
  else if (r == 'C')
    return false;
  else if (l == 'C')
    return true;
  else if (r == 'L')
    return false;
  else if (l == 'L')
    return true;
  else if (r == 'X')
    return false;
  else if (l == 'X')
    return true;
  else
    return r != 'V';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L16
L9:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x0,-0x14(%rbp)
  jne    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(unsigned char *str1, unsigned char *str2, unsigned int len) {
  while (len > 0) {
    *str1++ = *str2++;
    len--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L5
  mov    %edx,%edx
  mov    $0x0,%eax
L7:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L7
L5:
  ret
```

assistant: ```c
void memcpy(unsigned char *str1, unsigned char *str2, unsigned int len) {
  while (len > 0) {
    *str1++ = *str2++;
    len--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L12
L15:
  ret
```

assistant: ```c
void memcpy(unsigned char *str1, unsigned char *str2, unsigned int len) {
  while (len > 0) {
    *str1++ = *str2++;
    len--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  je     L126
  lea    0x1(%rsi),%r8
  lea    -0x1(%rdx),%eax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L57
  cmp    $0x6,%eax
  jbe    L57
  cmp    $0xe,%eax
  jbe    L91
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
L105:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L105
  mov    %edx,%r10d
  mov    %edx,%eax
  and    $0xfffffff0,%r10d
  mov    %r10d,%r9d
  sub    %r10d,%eax
  lea    (%rcx,%r9,1),%rdi
  lea    (%rsi,%r9,1),%r8
  cmp    %r10d,%edx
  je     L126
  lea    -0x1(%rax),%r10d
  mov    %eax,%edx
  cmp    $0x6,%r10d
  jbe    L1
L18:
  mov    (%rsi,%r9,1),%rsi
  mov    %rsi,(%rcx,%r9,1)
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%esi
  sub    %ecx,%eax
  add    %rsi,%rdi
  add    %rsi,%r8
  cmp    %ecx,%edx
  je     L126
  lea    -0x1(%rax),%r10d
L1:
  movzbl (%r8),%edx
  mov    %dl,(%rdi)
  test   %r10d,%r10d
  je     L126
  movzbl 0x1(%r8),%edx
  mov    %dl,0x1(%rdi)
  cmp    $0x2,%eax
  je     L126
  movzbl 0x2(%r8),%edx
  mov    %dl,0x2(%rdi)
  cmp    $0x3,%eax
  je     L126
  movzbl 0x3(%r8),%edx
  mov    %dl,0x3(%rdi)
  cmp    $0x4,%eax
  je     L126
  movzbl 0x4(%r8),%edx
  mov    %dl,0x4(%rdi)
  cmp    $0x5,%eax
  je     L126
  movzbl 0x5(%r8),%edx
  mov    %dl,0x5(%rdi)
  cmp    $0x6,%eax
  je     L126
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L146:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L146
L126:
  ret
L91:
  mov    %edx,%eax
  mov    %rsi,%r8
  mov    %rcx,%rdi
  xor    %r9d,%r9d
  jmp    L18
```

assistant: ```c
void memcpy(unsigned char *str1, unsigned char *str2, unsigned int len) {
  while (len > 0) {
    *str1++ = *str2++;
    len--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0x48,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string

tool: D15: I am %d years old.


tool: D12: I am %d inches tall.


assistant: ```c
int main(int argc, char **argv) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string

tool: D11: I am %d years old.


tool: D1: I am %d inches tall.


assistant: ```c
int main(int argc, char **argv) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string

tool: D19: I am %d years old.


tool: D11: I am %d inches tall.


assistant: ```c
int main(int argc, char **argv) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string

tool: D11: I am %d years old.


tool: D16: I am %d inches tall.


assistant: ```c
int main(int argc, char **argv) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x7,-0x10(%rbp)
  cmpl   $0x3,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x3,-0x18(%rbp)
  jbe    L15
  mov    -0x14(%rbp),%eax
  jmp    L9
L15:
  mov    -0x10(%rbp),%eax
L9:
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D4: x = %d


tool: D6: y = %d


tool: D1: z = %d


assistant: ```c
int main(char argc, char **argv) {
  unsigned int a = 3, b = 5, c = 7;
  unsigned int x, y, z;
  x = a == 3;
  y = (a << 1) & b;
  z = (a > 3) ? b : c;
  printf("x = %d\n", x);
  printf("y = %d\n", y);
  printf("z = %d\n", z);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type: string
name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D25
type: string

tool: D12: x = %d


tool: D13: y = %d


tool: D25: z = %d


assistant: ```c
int main(char argc, char **argv) {
  unsigned int a = 3, b = 5, c = 7;
  unsigned int x, y, z;
  x = a == 3;
  y = (a << 1) & b;
  z = (a > 3) ? b : c;
  printf("x = %d\n", x);
  printf("y = %d\n", y);
  printf("z = %d\n", z);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D28
type_guessed: string

tool: D12: x = %d


tool: D2: y = %d


tool: D28: z = %d


assistant: ```c
int main(char argc, char **argv) {
  unsigned int a = 3, b = 5, c = 7;
  unsigned int x, y, z;
  x = a == 3;
  y = (a << 1) & b;
  z = (a > 3) ? b : c;
  printf("x = %d\n", x);
  printf("y = %d\n", y);
  printf("z = %d\n", z);
  return 0;
}
```