user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x38(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L78:
  mov    -0x3c(%rbp),%ebx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L44
  addl   $0x1,-0x38(%rbp)
  jmp    L78
L44:
  nop
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L29
L68:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  add    %eax,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L64
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x30(%rbp)
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L14
L64:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L14
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x30(%rbp)
  lea    D108(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L14:
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L29:
  mov    -0x34(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L68
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D94
data_type: string
name: disassemble_data
arguments: data_tag: D77
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string
name: disassemble_data
arguments: data_tag: D48
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string
name: disassemble_data
arguments: data_tag: D95
data_type: string
name: disassemble_data
arguments: data_tag: D108
data_type: string
name: disassemble_data
arguments: data_tag: D39
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D5: Enter a number: 

tool: D94: %d

tool: D77: the digit is: %d



tool: D7: The base is: %d


tool: D48: The fra is: %d


tool: D2: The mod is: %d


tool: D29: The quan is: %d


tool: D95: A

tool: D108: B

tool: D39: The n1 is: %d



tool: D4: The number of ones is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int num;
  int frac = 1;
  int digit = 1;
  printf("Enter a number: ");
  scanf("%d", &num);
  while (1) {
    frac = num / power(10, digit);
    if (frac == 0)
      break;
    digit += 1;
  }
  printf("the digit is: %d\n\n", digit);
  int j;
  int n1;
  for (j = 0, n1 = 0; j < digit; j++) {
    int base = power(10, j + 1);
    printf("The base is: %d\n", base);
    int fra = num / base;
    printf("The fra is: %d\n", fra);
    int mod = num - base * fra;
    printf("The mod is: %d\n", mod);
    int quan = power(10, j);
    printf("The quan is: %d\n", quan);
    n1 += fra * quan;
    if (mod > 2 * quan - 1) {
      n1 += quan;
      printf("A\n");
    } else if (mod > quan - 1) {
      n1 += mod - quan + 1;
      printf("B\n");
    }
    printf("The n1 is: %d\n\n", n1);
  }
  printf("The number of ones is: %d\n", n1);
  getchar();
  getchar();
  return 0;
}
```