ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<host_get_file_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  movslq %esi,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  (bad)
  add    %dl,(%rax)
  add    (%rax),%eax
  add    %al,(%rax)
  add    %al,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int host_get_file_name(char *buffer, int max_buffer_size) {
  int ret;
  memset(buffer, 0, max_buffer_size);
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x03"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       : "=a"(ret)
                       : "a"(buffer), "b"(max_buffer_size));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<host_get_file_name>:
  endbr64
  push   %rbx
  movslq %esi,%rdx
  xor    %esi,%esi
  mov    %rdx,%rbx
  call   <memset@plt>
  (bad)
  add    %dl,(%rax)
  add    (%rax),%eax
  add    %al,(%rax)
  add    %al,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int host_get_file_name(char *buffer, int max_buffer_size) {
  int ret;
  memset(buffer, 0, max_buffer_size);
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x03"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       : "=a"(ret)
                       : "a"(buffer), "b"(max_buffer_size));
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<host_get_file_name>:
  endbr64
  push   %rbx
  movslq %esi,%rdx
  xor    %esi,%esi
  mov    %rdx,%rbx
  call   <memset@plt>
  (bad)
  add    %dl,(%rax)
  add    (%rax),%eax
  add    %al,(%rax)
  add    %al,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int host_get_file_name(char *buffer, int max_buffer_size) {
  int ret;
  memset(buffer, 0, max_buffer_size);
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x03"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       : "=a"(ret)
                       : "a"(buffer), "b"(max_buffer_size));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_utf8pre_to_utf8dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  cmp    $0xc3,%eax
  jne    L16
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  cmp    $0xa4,%eax
  jne    L16
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x61,(%rax)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xcc,(%rax)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x88,(%rax)
  addl   $0x1,-0x8(%rbp)
  jmp    L32
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L32:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int convert_utf8pre_to_utf8dec(const char *src, int src_len, char *dest, int dest_len) {
  int i, j = 0;
  for (i = 0; i < src_len; i++) {
    if (((src[i] & 0xff) == 0xc3) && ((src[i + 1] & 0xff) == 0xa4)) {
      dest[j] = 0x61;
      j++;
      dest[j] = 0xcc;
      j++;
      dest[j] = 0x88;
      i++;
    } else
      dest[j] = src[i];
    j++;
  }
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_utf8pre_to_utf8dec>:
  endbr64
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L39
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L36
L10:
  movslq %ecx,%r8
  mov    %dil,(%rdx,%r8,1)
L15:
  add    $0x1,%ecx
  add    $0x1,%eax
  cmp    %eax,%esi
  jle    L56
L36:
  movslq %eax,%r8
  movzbl (%r9,%r8,1),%edi
  cmp    $0xc3,%dil
  jne    L10
  cmpb   $0xa4,0x1(%r9,%r8,1)
  jne    L10
  movslq %ecx,%rdi
  movb   $0x61,(%rdx,%rdi,1)
  lea    0x1(%rcx),%edi
  movslq %edi,%rdi
  movb   $0xcc,(%rdx,%rdi,1)
  add    $0x2,%ecx
  movslq %ecx,%rdi
  movb   $0x88,(%rdx,%rdi,1)
  add    $0x1,%eax
  jmp    L15
L39:
  mov    $0x0,%ecx
L56:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int convert_utf8pre_to_utf8dec(const char *src, int src_len, char *dest, int dest_len) {
  int i, j = 0;
  for (i = 0; i < src_len; i++) {
    if (((src[i] & 0xff) == 0xc3) && ((src[i + 1] & 0xff) == 0xa4)) {
      dest[j] = 0x61;
      j++;
      dest[j] = 0xcc;
      j++;
      dest[j] = 0x88;
      i++;
    } else
      dest[j] = src[i];
    j++;
  }
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<convert_utf8pre_to_utf8dec>:
  endbr64
  mov    %rdi,%r10
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L49
  xor    %eax,%eax
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L57:
  add    $0x1,%eax
  mov    %dil,(%rcx)
  add    $0x1,%r8d
  cmp    %eax,%esi
  jle    L49
L40:
  movslq %eax,%r9
  movslq %r8d,%rcx
  movzbl (%r10,%r9,1),%edi
  add    %rdx,%rcx
  cmp    $0xc3,%dil
  jne    L57
  cmpb   $0xa4,0x1(%r10,%r9,1)
  jne    L57
  movb   $0x61,(%rcx)
  lea    0x1(%r8),%ecx
  add    $0x1,%eax
  add    $0x2,%r8d
  movslq %ecx,%rcx
  add    $0x1,%eax
  movb   $0xcc,(%rdx,%rcx,1)
  movslq %r8d,%rcx
  add    $0x1,%r8d
  movb   $0x88,(%rdx,%rcx,1)
  cmp    %eax,%esi
  jg     L40
L49:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int convert_utf8pre_to_utf8dec(const char *src, int src_len, char *dest, int dest_len) {
  int i, j = 0;
  for (i = 0; i < src_len; i++) {
    if (((src[i] & 0xff) == 0xc3) && ((src[i + 1] & 0xff) == 0xa4)) {
      dest[j] = 0x61;
      j++;
      dest[j] = 0xcc;
      j++;
      dest[j] = 0x88;
      i++;
    } else
      dest[j] = src[i];
    j++;
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_utf8pre_to_utf8dec>:
  endbr64
  mov    %rdi,%r10
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L8
  xor    %eax,%eax
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%eax
  mov    %dil,(%rcx)
  add    $0x1,%r8d
  cmp    %eax,%esi
  jle    L8
L13:
  movslq %eax,%r9
  movslq %r8d,%rcx
  movzbl (%r10,%r9,1),%edi
  add    %rdx,%rcx
  cmp    $0xc3,%dil
  jne    L30
  cmpb   $0xa4,0x1(%r10,%r9,1)
  jne    L30
  movb   $0x61,(%rcx)
  lea    0x1(%r8),%ecx
  add    $0x1,%eax
  add    $0x2,%r8d
  movslq %ecx,%rcx
  add    $0x1,%eax
  movb   $0xcc,(%rdx,%rcx,1)
  movslq %r8d,%rcx
  add    $0x1,%r8d
  movb   $0x88,(%rdx,%rcx,1)
  cmp    %eax,%esi
  jg     L13
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int convert_utf8pre_to_utf8dec(const char *src, int src_len, char *dest, int dest_len) {
  int i, j = 0;
  for (i = 0; i < src_len; i++) {
    if (((src[i] & 0xff) == 0xc3) && ((src[i + 1] & 0xff) == 0xa4)) {
      dest[j] = 0x61;
      j++;
      dest[j] = 0xcc;
      j++;
      dest[j] = 0x88;
      i++;
    } else
      dest[j] = src[i];
    j++;
  }
  return j;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test3@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test3();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test3@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test3();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test3@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test3();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test3@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test3();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<formatLong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    D16(%rip),%eax
  test   %eax,%eax
  jne    L39
  mov    $0x0,%eax
  call   <localeconv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L39
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,D27(%rip)
  jmp    L39
L0:
  movl   $0x2c,D27(%rip)
L39:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L72:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L5
  cmpl   $0x0,-0x14(%rbp)
  je     L5
  mov    D27(%rip),%eax
  subq   $0x1,-0x10(%rbp)
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L5:
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x10(%rbp)
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  addl   $0x1,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L72
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *formatLong(long num) {
  static int comma = '\0';
  static char retbuf[30];
  char *p = &retbuf[sizeof(retbuf) - 1];
  int i = 0;
  if (comma == '\0') {
    struct lconv *lcp = localeconv();
    if (lcp != NULL) {
      if (lcp->thousands_sep != NULL && *lcp->thousands_sep != '\0')
        comma = *lcp->thousands_sep;
      else
        comma = ',';
    }
  }
  *p = '\0';
  do {
    if (i % 3 == 0 && i != 0)
      *--p = comma;
    *--p = '0' + num % 10;
    num /= 10;
    i++;
  } while (num != 0);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<formatLong>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpl   $0x0,D56(%rip)
  je     L65
L25:
  movb   $0x0,D44(%rip)
  movzbl D56(%rip),%r9d
  mov    $0x0,%ecx
  lea    D44(%rip),%rsi
  movabs $0x6666666666666667,%r8
  jmp    L109
L65:
  mov    $0x0,%eax
  call   <localeconv@plt>
  test   %rax,%rax
  je     L25
  mov    (%rax),%rax
  test   %rax,%rax
  je     L47
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  movsbl %al,%eax
  mov    %eax,D25(%rip)
  jmp    L25
L47:
  movl   $0x2c,D25(%rip)
  jmp    L25
L71:
  mov    %rdi,%rsi
L109:
  lea    -0x1(%rsi),%rdi
  mov    %rbx,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  add    $0x30,%ebx
  mov    %bl,-0x1(%rsi)
  mov    %rdx,%rbx
  add    $0x1,%ecx
  test   %rdx,%rdx
  je     L92
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ecx
  jne    L71
  test   %ecx,%ecx
  je     L71
  lea    -0x2(%rsi),%rdi
  mov    %r9b,-0x2(%rsi)
  jmp    L71
L92:
  mov    %rdi,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *formatLong(long num) {
  static int comma = '\0';
  static char retbuf[30];
  char *p = &retbuf[sizeof(retbuf) - 1];
  int i = 0;
  if (comma == '\0') {
    struct lconv *lcp = localeconv();
    if (lcp != NULL) {
      if (lcp->thousands_sep != NULL && *lcp->thousands_sep != '\0')
        comma = *lcp->thousands_sep;
      else
        comma = ',';
    }
  }
  *p = '\0';
  do {
    if (i % 3 == 0 && i != 0)
      *--p = comma;
    *--p = '0' + num % 10;
    num /= 10;
    i++;
  } while (num != 0);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<formatLong>:
  endbr64
  mov    D19(%rip),%r9d
  push   %rbx
  mov    %rdi,%rbx
  test   %r9d,%r9d
  je     L74
L24:
  movb   $0x0,D45(%rip)
  xor    %esi,%esi
  lea    D45(%rip),%rcx
  movabs $0x6666666666666667,%rdi
  jmp    L48
L72:
  mov    %r8,%rcx
L48:
  mov    %rbx,%rax
  lea    -0x1(%rcx),%r8
  add    $0x1,%esi
  imul   %rdi
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  add    $0x30,%ebx
  mov    %bl,-0x1(%rcx)
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L38
  imul   $0xaaaaaaab,%esi,%eax
  cmp    $0x55555555,%eax
  ja     L72
  mov    %r9b,-0x2(%rcx)
  lea    -0x2(%rcx),%r8
  jmp    L72
  nopl   (%rax)
L38:
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L74:
  xor    %eax,%eax
  call   <localeconv@plt>
  movzbl D19(%rip),%r9d
  test   %rax,%rax
  je     L24
  mov    (%rax),%rax
  test   %rax,%rax
  je     L90
  movzbl (%rax),%r9d
  test   %r9b,%r9b
  je     L90
  movsbl %r9b,%eax
  mov    %eax,D51(%rip)
  jmp    L24
L90:
  movl   $0x2c,D51(%rip)
  mov    $0x2c,%r9d
  jmp    L24
```

assistant: ```c
char *formatLong(long num) {
  static int comma = '\0';
  static char retbuf[30];
  char *p = &retbuf[sizeof(retbuf) - 1];
  int i = 0;
  if (comma == '\0') {
    struct lconv *lcp = localeconv();
    if (lcp != NULL) {
      if (lcp->thousands_sep != NULL && *lcp->thousands_sep != '\0')
        comma = *lcp->thousands_sep;
      else
        comma = ',';
    }
  }
  *p = '\0';
  do {
    if (i % 3 == 0 && i != 0)
      *--p = comma;
    *--p = '0' + num % 10;
    num /= 10;
    i++;
  } while (num != 0);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<formatLong>:
  endbr64
  mov    D12(%rip),%r10d
  push   %rbx
  mov    %rdi,%rbx
  test   %r10d,%r10d
  je     L1
L107:
  mov    %rbx,%rax
  movb   $0x0,D22(%rip)
  movabs $0x6666666666666667,%r9
  lea    D26(%rip),%r8
  imul   %r9
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  add    $0x30,%ebx
  mov    %bl,D0(%rip)
  test   %rcx,%rcx
  je     L12
  mov    $0x1,%edi
  mov    %r8,%rsi
  lea    0x1(%r8),%r11
  jmp    L96
  nopl   0x0(%rax)
L56:
  mov    %rcx,%rax
  lea    -0x1(%rsi),%r8
  add    $0x1,%edi
  imul   %r9
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  add    $0x30,%ecx
  mov    %cl,-0x1(%rsi)
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L12
L41:
  mov    %rsi,%r11
  mov    %r8,%rsi
L96:
  imul   $0xaaaaaaab,%edi,%eax
  cmp    $0x55555555,%eax
  ja     L56
  mov    %rcx,%rax
  mov    %r10b,-0x2(%r11)
  lea    -0x2(%r11),%rsi
  lea    -0x3(%r11),%r8
  imul   %r9
  mov    %rcx,%rax
  add    $0x1,%edi
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  add    $0x30,%ecx
  mov    %cl,-0x3(%r11)
  mov    %rdx,%rcx
  test   %rdx,%rdx
  jne    L41
L12:
  mov    %r8,%rax
  pop    %rbx
  ret
  nop
L1:
  xor    %eax,%eax
  call   <localeconv@plt>
  movzbl D12(%rip),%r10d
  test   %rax,%rax
  je     L107
  mov    (%rax),%rax
  test   %rax,%rax
  je     L106
  movzbl (%rax),%r10d
  test   %r10b,%r10b
  je     L106
  movsbl %r10b,%eax
  mov    %eax,D0(%rip)
  jmp    L107
  nopl   0x0(%rax,%rax,1)
L106:
  movl   $0x2c,D0(%rip)
  mov    $0x2c,%r10d
  jmp    L107
```

assistant: ```c
char *formatLong(long num) {
  static int comma = '\0';
  static char retbuf[30];
  char *p = &retbuf[sizeof(retbuf) - 1];
  int i = 0;
  if (comma == '\0') {
    struct lconv *lcp = localeconv();
    if (lcp != NULL) {
      if (lcp->thousands_sep != NULL && *lcp->thousands_sep != '\0')
        comma = *lcp->thousands_sep;
      else
        comma = ',';
    }
  }
  *p = '\0';
  do {
    if (i % 3 == 0 && i != 0)
      *--p = comma;
    *--p = '0' + num % 10;
    num /= 10;
    i++;
  } while (num != 0);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<growing_fifo_append>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <growing_fifo_write@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fifo_buffer_append@plt>
  nop
  leave
  ret
```

assistant: ```c
void growing_fifo_append(struct fifo_buffer **buffer_p, const void *data, size_t length) {
  void *p = growing_fifo_write(buffer_p, length);
  memcpy(p, data, length);
  fifo_buffer_append(*buffer_p, length);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<growing_fifo_append>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  call   <growing_fifo_write@plt>
  mov    %rax,%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  mov    0x0(%rbp),%rdi
  call   <fifo_buffer_append@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void growing_fifo_append(struct fifo_buffer **buffer_p, const void *data, size_t length) {
  void *p = growing_fifo_write(buffer_p, length);
  memcpy(p, data, length);
  fifo_buffer_append(*buffer_p, length);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<growing_fifo_append>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <growing_fifo_write@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <fifo_buffer_append@plt>
```

assistant: ```c
void growing_fifo_append(struct fifo_buffer **buffer_p, const void *data, size_t length) {
  void *p = growing_fifo_write(buffer_p, length);
  memcpy(p, data, length);
  fifo_buffer_append(*buffer_p, length);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<growing_fifo_append>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <growing_fifo_write@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <fifo_buffer_append@plt>
```

assistant: ```c
void growing_fifo_append(struct fifo_buffer **buffer_p, const void *data, size_t length) {
  void *p = growing_fifo_write(buffer_p, length);
  memcpy(p, data, length);
  fifo_buffer_append(*buffer_p, length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<semver_clean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <has_valid_length@plt>
  test   %rax,%rax
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L38
L11:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x41,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L39
L34:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <contains@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <strcut@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L51
  mov    $0xffffffff,%eax
  jmp    L38
L51:
  subq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L2:
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L34
  mov    $0x0,%eax
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: 0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ.-+

assistant: ```c
int semver_clean(char *s) {
  size_t i, len, mlen;
  int res;
  if (has_valid_length(s) == 0)
    return -1;
  len = strlen(s);
  mlen = strlen("0123456789"
                "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
                "."
                "-"
                "+");
  for (i = 0; i < len; i++) {
    if (contains(s[i],
                 "0123456789"
                 "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
                 "."
                 "-"
                 "+",
                 mlen) == 0) {
      res = strcut(s, (int)i, 1);
      if (res == -1)
        return -1;
      --len;
      --i;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<semver_clean>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <has_valid_length@plt>
  test   %rax,%rax
  je     L59
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L82
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
  jmp    L36
L11:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jbe    L23
L36:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    $0x41,%edx
  mov    %r13,%rsi
  call   <contains@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <strcut@plt>
  cmp    $0xffffffff,%eax
  je     L0
  sub    $0x1,%r12
  sub    $0x1,%rbx
  jmp    L11
L23:
  mov    $0x0,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  mov    $0xffffffff,%eax
  jmp    L0
L82:
  mov    $0x0,%eax
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9: 0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ.-+

assistant: ```c
int semver_clean(char *s) {
  size_t i, len, mlen;
  int res;
  if (has_valid_length(s) == 0)
    return -1;
  len = strlen(s);
  mlen = strlen("0123456789"
                "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
                "."
                "-"
                "+");
  for (i = 0; i < len; i++) {
    if (contains(s[i],
                 "0123456789"
                 "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
                 "."
                 "-"
                 "+",
                 mlen) == 0) {
      res = strcut(s, (int)i, 1);
      if (res == -1)
        return -1;
      --len;
      --i;
    }
  }
  return 0;
}
```