ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<count_bitarray_low20_AND_SSE2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x10,%esi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r14
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <__builtin_assume_aligned@plt>
  lea    0x800000(%r14),%r13
  mov    %r14,%rbx
  mov    $0x0,%ebp
  sub    %r14,%rax
  mov    %rax,%r12
  jmp    L9
L17:
  mov    (%rbx),%rdi
  call   <bitcount_SSE2@plt>
  add    %eax,%ebp
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L13
L9:
  cmpq   $0x0,(%r12,%rbx,1)
  jne    L17
  movq   $0x0,(%rbx)
  jmp    L17
L13:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t count_bitarray_low20_AND_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  uint16_t *a = (uint16_t *)__builtin_assume_aligned(A, 16);
  uint16_t *b = (uint16_t *)__builtin_assume_aligned(B, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 20); i++) {
    if (!b[i]) {
      a[i] = 0;
    }
    count += bitcount_SSE2(a[i]);
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_bitarray_low20_AND_SSE2>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x10,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <__builtin_assume_aligned@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  mov    %rax,%r13
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbx
  lea    0x800000(%rax),%rbp
  sub    %rax,%r13
  jmp    L19
  nopl   (%rax)
L31:
  mov    (%rax),%rdi
L3:
  call   <bitcount_SSE2@plt>
  add    $0x8,%rbx
  add    %eax,%r12d
  cmp    %rbp,%rbx
  je     L21
L19:
  mov    (%rbx),%rdi
  lea    0x0(%r13,%rbx,1),%rax
  test   %rdi,%rdi
  jne    L31
  movq   $0x0,(%rax)
  jmp    L3
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t count_bitarray_low20_AND_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  uint16_t *a = (uint16_t *)__builtin_assume_aligned(A, 16);
  uint16_t *b = (uint16_t *)__builtin_assume_aligned(B, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 20); i++) {
    if (!b[i]) {
      a[i] = 0;
    }
    count += bitcount_SSE2(a[i]);
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_bitarray_low20_AND_SSE2>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x10,%esi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <__builtin_assume_aligned@plt>
  mov    %r12,%rdi
  mov    $0x10,%esi
  xor    %r12d,%r12d
  mov    %rax,%rbp
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbx
  lea    0x800000(%rax),%r13
  sub    %rax,%rbp
  jmp    L11
  nopl   (%rax)
L28:
  mov    (%rax),%rdi
L22:
  call   <bitcount_SSE2@plt>
  add    $0x8,%rbx
  add    %eax,%r12d
  cmp    %rbx,%r13
  je     L1
L11:
  cmpq   $0x0,(%rbx)
  lea    0x0(%rbp,%rbx,1),%rax
  jne    L28
  movq   $0x0,(%rax)
  xor    %edi,%edi
  jmp    L22
L1:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t count_bitarray_low20_AND_SSE2(uint32_t *restrict A, uint32_t *restrict B) {
  uint16_t *a = (uint16_t *)__builtin_assume_aligned(A, 16);
  uint16_t *b = (uint16_t *)__builtin_assume_aligned(B, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 20); i++) {
    if (!b[i]) {
      a[i] = 0;
    }
    count += bitcount_SSE2(a[i]);
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dc_crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L3
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L3:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <dc_crypt_stream@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D26: 
Beginning decryption...


tool: D18: 
Beginning encryption...


tool: D12: 


assistant: ```c
void dc_crypt(int src_fd, int dest_fd, int decrypt) {
  if (decrypt)
    printf("\nBeginning decryption...\n");
  else
    printf("\nBeginning encryption...\n");
  dc_crypt_stream(src_fd, dest_fd, decrypt);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dc_crypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  test   %edx,%edx
  je     L3
  lea    D14(%rip),%rdi
  call   <printf@plt>
L1:
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <dc_crypt_stream@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string

tool: D14: 
Beginning decryption...


tool: D2: 


tool: D23: 
Beginning encryption...


assistant: ```c
void dc_crypt(int src_fd, int dest_fd, int decrypt) {
  if (decrypt)
    printf("\nBeginning decryption...\n");
  else
    printf("\nBeginning encryption...\n");
  dc_crypt_stream(src_fd, dest_fd, decrypt);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dc_crypt>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  test   %edx,%edx
  je     L10
  lea    D7(%rip),%rdi
  call   <printf@plt>
L15:
  mov    %ebp,%edi
  mov    %r12d,%edx
  mov    %r13d,%esi
  call   <dc_crypt_stream@plt>
  pop    %rbp
  lea    D13(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
  nop
L10:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D19
type: string

tool: D7: 
Beginning decryption...


tool: D13: 


tool: D19: 
Beginning encryption...


assistant: ```c
void dc_crypt(int src_fd, int dest_fd, int decrypt) {
  if (decrypt)
    printf("\nBeginning decryption...\n");
  else
    printf("\nBeginning encryption...\n");
  dc_crypt_stream(src_fd, dest_fd, decrypt);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dc_crypt>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  test   %edx,%edx
  je     L15
  lea    D12(%rip),%rdi
  call   <printf@plt>
L9:
  mov    %ebp,%edi
  mov    %r12d,%edx
  mov    %r13d,%esi
  call   <dc_crypt_stream@plt>
  pop    %rbp
  lea    D13(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
  nop
L15:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D26
type: string

tool: D12: 
Beginning decryption...


tool: D13: 


tool: D26: 
Beginning encryption...


assistant: ```c
void dc_crypt(int src_fd, int dest_fd, int decrypt) {
  if (decrypt)
    printf("\nBeginning decryption...\n");
  else
    printf("\nBeginning encryption...\n");
  dc_crypt_stream(src_fd, dest_fd, decrypt);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L16
  mov    $0x1,%eax
  jmp    L2
L16:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: 
Factorial of %d is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int num, f;
  num = (int)argv[1][0];
  f = fact(num);
  printf("\nFactorial of %d is: %d\n", num, f);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L4
  push   %rbx
  mov    0x8(%rsi),%rax
  movsbl (%rax),%ebx
  mov    %ebx,%edi
  call   <fact@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L4:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: 
Factorial of %d is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int num, f;
  num = (int)argv[1][0];
  f = fact(num);
  printf("\nFactorial of %d is: %d\n", num, f);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  push   %rbp
  mov    0x8(%rsi),%rax
  movsbl (%rax),%ebp
  mov    %ebp,%edi
  call   <fact@plt>
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  mov    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: 
Factorial of %d is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int num, f;
  num = (int)argv[1][0];
  f = fact(num);
  printf("\nFactorial of %d is: %d\n", num, f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L5
  push   %rbp
  mov    0x8(%rsi),%rax
  movsbl (%rax),%ebp
  mov    %ebp,%edi
  call   <fact@plt>
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  mov    $0x1,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: 
Factorial of %d is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int num, f;
  num = (int)argv[1][0];
  f = fact(num);
  printf("\nFactorial of %d is: %d\n", num, f);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpu_model>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0xc,%eax
  and    $0xf0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int cpu_model(unsigned int eax) {
  unsigned model = (eax & 0xf0) >> 4;
  unsigned ext_model = (eax & 0xf0000) >> 12;
  return ext_model + model;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpu_model>:
  endbr64
  mov    %edi,%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  shr    $0xc,%edi
  and    $0xf0,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned int cpu_model(unsigned int eax) {
  unsigned model = (eax & 0xf0) >> 4;
  unsigned ext_model = (eax & 0xf0000) >> 12;
  return ext_model + model;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpu_model>:
  endbr64
  mov    %edi,%eax
  shr    $0xc,%edi
  shr    $0x4,%eax
  and    $0xf0,%edi
  and    $0xf,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned int cpu_model(unsigned int eax) {
  unsigned model = (eax & 0xf0) >> 4;
  unsigned ext_model = (eax & 0xf0000) >> 12;
  return ext_model + model;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpu_model>:
  endbr64
  mov    %edi,%eax
  shr    $0xc,%edi
  shr    $0x4,%eax
  and    $0xf0,%edi
  and    $0xf,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned int cpu_model(unsigned int eax) {
  unsigned model = (eax & 0xf0) >> 4;
  unsigned ext_model = (eax & 0xf0000) >> 12;
  return ext_model + model;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<el_hdlcEncode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L27
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
L27:
  mov    $0xffffffff,%eax
  jmp    L4
L7:
  movq   $0x0,-0x8(%rbp)
  jmp    L26
L38:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L38
L4:
  pop    %rbp
  ret
```

assistant: ```c
int el_hdlcEncode(uint8_t *in, size_t inLength, uint8_t *out, size_t outLength) {
  size_t i;
  if (in == NULL || out == NULL)
    return -1;
  for (i = 0; i < inLength; i++) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<el_hdlcEncode>:
  endbr64
  test   %rdi,%rdi
  je     L3
  test   %rdx,%rdx
  je     L3
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L7
L15:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L15
  ret
L7:
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int el_hdlcEncode(uint8_t *in, size_t inLength, uint8_t *out, size_t outLength) {
  size_t i;
  if (in == NULL || out == NULL)
    return -1;
  for (i = 0; i < inLength; i++) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<el_hdlcEncode>:
  endbr64
  test   %rdi,%rdi
  je     L14
  test   %rdx,%rdx
  je     L14
  ret
  nop
L14:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int el_hdlcEncode(uint8_t *in, size_t inLength, uint8_t *out, size_t outLength) {
  size_t i;
  if (in == NULL || out == NULL)
    return -1;
  for (i = 0; i < inLength; i++) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<el_hdlcEncode>:
  endbr64
  test   %rdi,%rdi
  je     L5
  test   %rdx,%rdx
  je     L5
  ret
  nop
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int el_hdlcEncode(uint8_t *in, size_t inLength, uint8_t *out, size_t outLength) {
  size_t i;
  if (in == NULL || out == NULL)
    return -1;
  for (i = 0; i < inLength; i++) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<msleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  imul   $0x3e8,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  imul   $0xf4240,%rax,%rax
  mov    %rax,-0x18(%rbp)
  nop
L0:
  lea    -0x20(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L0
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void msleep(unsigned long milisec) {
  struct timespec ts;
  ts.tv_sec = milisec / 1000ULL;
  ts.tv_nsec = (milisec % 1000ULL) * 1000000ULL;
  while (nanosleep(&ts, &ts) == -1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msleep>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  shr    $0x3,%rdx
  movabs $0x20c49ba5e353f7cf,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x4,%rdx
  mov    %rdx,(%rsp)
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rdi
  imul   $0xf4240,%rdi,%rdi
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rbx
L9:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(unsigned long milisec) {
  struct timespec ts;
  ts.tv_sec = milisec / 1000ULL;
  ts.tv_nsec = (milisec % 1000ULL) * 1000000ULL;
  while (nanosleep(&ts, &ts) == -1)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<msleep>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rcx
  push   %rbx
  mov    %rdi,%rdx
  shr    $0x3,%rdx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rax
  mov    %rsp,%rbx
  mul    %rcx
  shr    $0x4,%rdx
  mov    %rdx,(%rsp)
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rdi
  imul   $0xf4240,%rdi,%rdi
  mov    %rdi,0x8(%rsp)
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(unsigned long milisec) {
  struct timespec ts;
  ts.tv_sec = milisec / 1000ULL;
  ts.tv_nsec = (milisec % 1000ULL) * 1000000ULL;
  while (nanosleep(&ts, &ts) == -1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<msleep>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rcx
  push   %rbx
  mov    %rdi,%rdx
  shr    $0x3,%rdx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rax
  mov    %rsp,%rbx
  mul    %rcx
  shr    $0x4,%rdx
  imul   $0x3e8,%rdx,%rax
  movq   %rdx,%xmm0
  sub    %rax,%rdi
  imul   $0xf4240,%rdi,%rdi
  movq   %rdi,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L6
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(unsigned long milisec) {
  struct timespec ts;
  ts.tv_sec = milisec / 1000ULL;
  ts.tv_nsec = (milisec % 1000ULL) * 1000000ULL;
  while (nanosleep(&ts, &ts) == -1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_llmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L0
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long _llmax(long long a, long long b) {
  long long max_val;
  max_val = b;
  if (a > b) {
    max_val = a;
  }
  return max_val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_llmax>:
  endbr64
  cmp    %rdi,%rsi
  mov    %rdi,%rax
  cmovge %rsi,%rax
  ret
```

assistant: ```c
long long _llmax(long long a, long long b) {
  long long max_val;
  max_val = b;
  if (a > b) {
    max_val = a;
  }
  return max_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_llmax>:
  endbr64
  cmp    %rdi,%rsi
  mov    %rdi,%rax
  cmovge %rsi,%rax
  ret
```

assistant: ```c
long long _llmax(long long a, long long b) {
  long long max_val;
  max_val = b;
  if (a > b) {
    max_val = a;
  }
  return max_val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_llmax>:
  endbr64
  cmp    %rdi,%rsi
  mov    %rdi,%rax
  cmovge %rsi,%rax
  ret
```

assistant: ```c
long long _llmax(long long a, long long b) {
  long long max_val;
  max_val = b;
  if (a > b) {
    max_val = a;
  }
  return max_val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stbi__zlib_flushf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L1
L26:
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  sub    $0x4,%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L5
L8:
  lea    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <stbi__sbgrowf@plt>
  nop
L5:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rdi
  mov    -0x8(%rbp),%rax
  sub    $0x4,%rax
  mov    (%rax),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rax)
  movslq %edx,%rax
  add    %rdi,%rax
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x7,%eax
  jg     L26
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *stbi__zlib_flushf(unsigned char *data, unsigned int *bitbuffer, int *bitcount) {
  while (*bitcount >= 8) {
    ((((data) == 0 || ((int *)(data)-2)[1] + (1) >= ((int *)(data)-2)[0]) ? stbi__sbgrowf((void **)&(data), (1), sizeof(*(data))) : 0), (data)[((int *)(data)-2)[1]++] = ((unsigned char)*bitbuffer));
    *bitbuffer >>= 8;
    *bitcount -= 8;
  }
  return data;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stbi__zlib_flushf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  cmpl   $0x7,(%rdx)
  jle    L37
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    0x8(%rsp),%r12
  jmp    L44
L1:
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <stbi__sbgrowf@plt>
L57:
  mov    (%rbx),%ecx
  mov    0x8(%rsp),%rdx
  mov    -0x4(%rdx),%eax
  lea    0x1(%rax),%esi
  mov    %esi,-0x4(%rdx)
  cltq
  mov    %cl,(%rdx,%rax,1)
  shrl   $0x8,(%rbx)
  mov    0x0(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,0x0(%rbp)
  cmp    $0x7,%eax
  jle    L37
L44:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L1
  mov    -0x4(%rax),%edi
  lea    0x1(%rdi),%edx
  cmp    -0x8(%rax),%edx
  jl     L57
  jmp    L1
L37:
  mov    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char *stbi__zlib_flushf(unsigned char *data, unsigned int *bitbuffer, int *bitcount) {
  while (*bitcount >= 8) {
    ((((data) == 0 || ((int *)(data)-2)[1] + (1) >= ((int *)(data)-2)[0]) ? stbi__sbgrowf((void **)&(data), (1), sizeof(*(data))) : 0), (data)[((int *)(data)-2)[1]++] = ((unsigned char)*bitbuffer));
    *bitbuffer >>= 8;
    *bitcount -= 8;
  }
  return data;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi__zlib_flushf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmpl   $0x7,(%rdx)
  mov    %rdi,0x8(%rsp)
  jle    L38
  mov    %rsi,%rbx
  mov    %rdx,%r12
  lea    0x8(%rsp),%rbp
  nopl   0x0(%rax)
L2:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L17
  movslq -0x4(%rax),%rdx
  lea    0x1(%rdx),%ecx
  cmp    -0x8(%rax),%ecx
  jl     L27
L17:
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <stbi__sbgrowf@plt>
  mov    0x8(%rsp),%rax
  movslq -0x4(%rax),%rdx
  lea    0x1(%rdx),%ecx
L27:
  mov    (%rbx),%esi
  mov    %ecx,-0x4(%rax)
  mov    %sil,(%rax,%rdx,1)
  shrl   $0x8,(%rbx)
  mov    (%r12),%eax
  sub    $0x8,%eax
  mov    %eax,(%r12)
  cmp    $0x7,%eax
  jg     L2
L38:
  mov    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char *stbi__zlib_flushf(unsigned char *data, unsigned int *bitbuffer, int *bitcount) {
  while (*bitcount >= 8) {
    ((((data) == 0 || ((int *)(data)-2)[1] + (1) >= ((int *)(data)-2)[0]) ? stbi__sbgrowf((void **)&(data), (1), sizeof(*(data))) : 0), (data)[((int *)(data)-2)[1]++] = ((unsigned char)*bitbuffer));
    *bitbuffer >>= 8;
    *bitcount -= 8;
  }
  return data;
}
```