ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  lea    -0x1(%rbx),%eax
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  je     L79
  mov    $0x0,%ebx
  lea    D23(%rip),%rbp
  jmp    L48
L54:
  add    $0x1,%ebx
L46:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L79
L48:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x4(%rsp),%eax
  cmp    $0x2b,%al
  je     L54
  movzbl 0x6(%rsp),%edx
  cmp    $0x2b,%dl
  je     L54
  cmp    $0x2d,%dl
  je     L18
  cmp    $0x2d,%al
  jne    L46
L18:
  sub    $0x1,%ebx
  jmp    L46
L79:
  mov    %ebx,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D23
data_type: string
name: parse_data
arguments: data_label: D27
data_type: string

tool: D9: %d

tool: D23: %s

tool: D27: %d


assistant: ```c
int main() {
  char a[4];
  int x = 0;
  int n;
  scanf("%d", &n);
  while (n--) {
    scanf("%s", a);
    if ((a[0] == '+') || (a[2] == '+'))
      x++;
    else if ((a[0] == '-') || (a[2] == '-'))
      x--;
  }
  printf("%d\n", x);
  x = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  test   %ebp,%ebp
  je     L73
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r12
  lea    D9(%rip),%rbx
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L30:
  movzbl 0x6(%rsp),%edx
  cmp    $0x2b,%dl
  je     L85
  cmp    $0x2d,%al
  je     L12
  cmp    $0x2d,%dl
  je     L12
L61:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L73
L76:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x4(%rsp),%eax
  cmp    $0x2b,%al
  jne    L30
L85:
  mov    (%rsp),%eax
  add    $0x1,%ebp
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L76
L73:
  mov    %ebp,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L12:
  sub    $0x1,%ebp
  jmp    L61
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: string

tool: D7: %d

tool: D9: %s

tool: D26: %d


assistant: ```c
int main() {
  char a[4];
  int x = 0;
  int n;
  scanf("%d", &n);
  while (n--) {
    scanf("%s", a);
    if ((a[0] == '+') || (a[2] == '+'))
      x++;
    else if ((a[0] == '-') || (a[2] == '-'))
      x--;
  }
  printf("%d\n", x);
  x = 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  test   %ebp,%ebp
  je     L74
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r12
  lea    D21(%rip),%rbx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L82:
  movzbl 0x6(%rsp),%edx
  cmp    $0x2b,%dl
  je     L6
  cmp    $0x2d,%al
  je     L97
  cmp    $0x2d,%dl
  je     L97
L9:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L74
L16:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x4(%rsp),%eax
  cmp    $0x2b,%al
  jne    L82
L6:
  mov    (%rsp),%eax
  add    $0x1,%ebp
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L16
L74:
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L97:
  sub    $0x1,%ebp
  jmp    L9
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D24
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D24: %d

tool: D21: %s

tool: D15: %d


assistant: ```c
int main() {
  char a[4];
  int x = 0;
  int n;
  scanf("%d", &n);
  while (n--) {
    scanf("%s", a);
    if ((a[0] == '+') || (a[2] == '+'))
      x++;
    else if ((a[0] == '-') || (a[2] == '-'))
      x--;
  }
  printf("%d\n", x);
  x = 0;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ldr_getlux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x18(%rbp),%xmm0
  movsd  D18(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D10(%rip),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D7(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type: f64
name: parse_data
arguments: label: D10
type: byte[8]
name: parse_data
arguments: label: D7
type: byte[8]

tool: D18: 165

tool: {"D10": [0x66,0x66,0x66,0x66,0x66,0x66,0xfa,0xbf]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x94,0xc1,0x40]}

assistant: ```c
unsigned long ldr_getlux(long adcresistance) {
  double a = adcresistance / (double)165;
  return (long)((double)9000 * (pow((double)a, (double)-1.65)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ldr_getlux>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  divsd  D16(%rip),%xmm0
  movsd  D20(%rip),%xmm1
  call   <pow@plt>
  mulsd  D28(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
data_type: f64
name: disassemble_data
arguments: tag: D20
data_type: byte[8]
name: disassemble_data
arguments: tag: D28
data_type: byte[8]

tool: D16: 165

tool: {"D20": [0x66,0x66,0x66,0x66,0x66,0x66,0xfa,0xbf]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x94,0xc1,0x40]}

assistant: ```c
unsigned long ldr_getlux(long adcresistance) {
  double a = adcresistance / (double)165;
  return (long)((double)9000 * (pow((double)a, (double)-1.65)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ldr_getlux>:
  endbr64
  sub    $0x8,%rsp
  movsd  D23(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  divsd  D20(%rip),%xmm0
  call   <pow@plt>
  mulsd  D27(%rip),%xmm0
  add    $0x8,%rsp
  cvttsd2si %xmm0,%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D23
type_infered: byte[8]
name: read_data
arguments: data_label: D20
type_infered: f64
name: read_data
arguments: data_label: D27
type_infered: byte[8]

tool: {"D23": [0x66,0x66,0x66,0x66,0x66,0x66,0xfa,0xbf]}

tool: D20: 165

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x94,0xc1,0x40]}

assistant: ```c
unsigned long ldr_getlux(long adcresistance) {
  double a = adcresistance / (double)165;
  return (long)((double)9000 * (pow((double)a, (double)-1.65)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ldr_getlux>:
  endbr64
  sub    $0x8,%rsp
  movsd  D4(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  divsd  D28(%rip),%xmm0
  call   <pow@plt>
  mulsd  D5(%rip),%xmm0
  add    $0x8,%rsp
  cvttsd2si %xmm0,%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D28
type_guessed: f64
name: retrieve_data
arguments: data_label: D5
type_guessed: byte[8]

tool: {"D4": [0x66,0x66,0x66,0x66,0x66,0x66,0xfa,0xbf]}

tool: D28: 165

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x94,0xc1,0x40]}

assistant: ```c
unsigned long ldr_getlux(long adcresistance) {
  double a = adcresistance / (double)165;
  return (long)((double)9000 * (pow((double)a, (double)-1.65)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <strupr@plt>
  lea    -0x1c0(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0xe0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <urutarray@plt>
  lea    -0x150(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <strupr@plt>
  lea    -0x1c0(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <urutarray@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  lea    -0x150(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L25:
  lea    -0x150(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
data_type: string
name: extract_symbolic_data
arguments: data_tag: D34
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D30: %100s

tool: D34: String "%s" dan "%s" adalah sebuah anagram


tool: D2: String "%s" dan "%s" bukan sebuah anagram


assistant: ```c
int main() {
  char input[100];
  char string[100];
  char temp[100], temp2[100];
  scanf("%100s", input);
  strupr(input);
  strcpy(temp, input);
  urutarray(temp, strlen(temp));
  scanf("%100s", string);
  strupr(string);
  strcpy(temp2, input);
  urutarray(temp2, strlen(temp2));
  if (strcmp(temp, temp2) == 0)
    printf("String \"%s\" dan \"%s\" adalah sebuah anagram\n", input, string);
  else
    printf("String \"%s\" dan \"%s\" bukan sebuah anagram\n", input, string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  lea    D24(%rip),%r13
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strupr@plt>
  lea    0xe0(%rsp),%rbx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <urutarray@plt>
  lea    0x70(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strupr@plt>
  lea    0x150(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <urutarray@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  lea    0x70(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
L19:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  lea    0x70(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D25
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string

tool: D24: %100s

tool: D25: String "%s" dan "%s" adalah sebuah anagram


tool: D12: String "%s" dan "%s" bukan sebuah anagram


assistant: ```c
int main() {
  char input[100];
  char string[100];
  char temp[100], temp2[100];
  scanf("%100s", input);
  strupr(input);
  strcpy(temp, input);
  urutarray(temp, strlen(temp));
  scanf("%100s", string);
  strupr(string);
  strcpy(temp2, input);
  urutarray(temp2, strlen(temp2));
  if (strcmp(temp, temp2) == 0)
    printf("String \"%s\" dan \"%s\" adalah sebuah anagram\n", input, string);
  else
    printf("String \"%s\" dan \"%s\" bukan sebuah anagram\n", input, string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x1c8,%rsp
  mov    %rsp,%rbp
  lea    0xe0(%rsp),%r12
  lea    0x70(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strupr@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <urutarray@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  lea    0x150(%rsp),%r13
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <strupr@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <urutarray@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  test   %rax,%rax
  jne    L6
  lea    D1(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string

tool: D9: %100s

tool: D1: String "%s" dan "%s" adalah sebuah anagram


tool: D18: String "%s" dan "%s" bukan sebuah anagram


assistant: ```c
int main() {
  char input[100];
  char string[100];
  char temp[100], temp2[100];
  scanf("%100s", input);
  strupr(input);
  strcpy(temp, input);
  urutarray(temp, strlen(temp));
  scanf("%100s", string);
  strupr(string);
  strcpy(temp2, input);
  urutarray(temp2, strlen(temp2));
  if (strcmp(temp, temp2) == 0)
    printf("String \"%s\" dan \"%s\" adalah sebuah anagram\n", input, string);
  else
    printf("String \"%s\" dan \"%s\" bukan sebuah anagram\n", input, string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x1c8,%rsp
  mov    %rsp,%rbp
  lea    0xe0(%rsp),%r12
  lea    0x70(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strupr@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <urutarray@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  lea    0x150(%rsp),%r13
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <strupr@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <urutarray@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  test   %rax,%rax
  jne    L27
  lea    D18(%rip),%rdi
  call   <printf@plt>
L15:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D8
type_guessed: string

tool: D3: %100s

tool: D18: String "%s" dan "%s" adalah sebuah anagram


tool: D8: String "%s" dan "%s" bukan sebuah anagram


assistant: ```c
int main() {
  char input[100];
  char string[100];
  char temp[100], temp2[100];
  scanf("%100s", input);
  strupr(input);
  strcpy(temp, input);
  urutarray(temp, strlen(temp));
  scanf("%100s", string);
  strupr(string);
  strcpy(temp2, input);
  urutarray(temp2, strlen(temp2));
  if (strcmp(temp, temp2) == 0)
    printf("String \"%s\" dan \"%s\" adalah sebuah anagram\n", input, string);
  else
    printf("String \"%s\" dan \"%s\" bukan sebuah anagram\n", input, string);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<create_sll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
L16:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L13:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L37:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L37
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<create_sll>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
L23:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L23
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  mov    %rsp,%rbx
L36:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L36
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  mov    %rsp,%rbx
L30:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L30
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: What is the c source code of the assembly code below?

```asm
<create_sll>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   (%rax)
L26:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L26
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  nopl   0x0(%rax)
L36:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L36
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  nopl   0x0(%rax)
L32:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L32
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<create_sll>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   (%rax)
L5:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L5
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  nopl   0x0(%rax)
L19:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L19
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rdi
  call   <chain_node@plt>
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L8
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct node *create_sll(const struct node **pp1, const struct node **pp2) {
  struct node *list = NULL;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp2 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  *pp1 = list;
  do
    chain_node(&list);
  while (___sl_get_nondet_int());
  return list;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_I_TBS_UL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0xa,-0x4(%rbp)
  ja     L44
  movzbl -0x4(%rbp),%eax
  jmp    L16
L44:
  cmpb   $0xa,-0x4(%rbp)
  jne    L21
  mov    $0xa,%eax
  jmp    L16
L21:
  cmpb   $0x14,-0x4(%rbp)
  ja     L4
  movzbl -0x4(%rbp),%eax
  sub    $0x1,%eax
  jmp    L16
L4:
  movzbl -0x4(%rbp),%eax
  sub    $0x2,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char get_I_TBS_UL(unsigned char I_MCS) {
  if (I_MCS <= 10)
    return (I_MCS);
  else if (I_MCS == 10)
    return (10);
  else if (I_MCS < 21)
    return (I_MCS - 1);
  else
    return (I_MCS - 2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_I_TBS_UL>:
  endbr64
  mov    %edi,%eax
  cmp    $0xa,%dil
  jbe    L6
  cmp    $0x15,%dil
  adc    $0xfe,%al
L6:
  ret
```

assistant: ```c
unsigned char get_I_TBS_UL(unsigned char I_MCS) {
  if (I_MCS <= 10)
    return (I_MCS);
  else if (I_MCS == 10)
    return (10);
  else if (I_MCS < 21)
    return (I_MCS - 1);
  else
    return (I_MCS - 2);
}
```