ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x80(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x40(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x40(%rbp),%rcx
  lea    -0x80(%rbp),%rax
  mov    $0x7,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string

tool: D19: Tweedledee 

tool: D14: Tweedledum

assistant: ```c
int main() {
  char s1[50], s2[50];
  strcpy(s1, "Tweedledee ");
  strcpy(s2, "Tweedledum");
  strncat(s1, s2, 7);
  puts(s1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    0x40(%rsp),%rbp
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x7,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D13
data_type: string

tool: D5: Tweedledee 

tool: D13: Tweedledum

assistant: ```c
int main() {
  char s1[50], s2[50];
  strcpy(s1, "Tweedledee ");
  strcpy(s2, "Tweedledum");
  strncat(s1, s2, 7);
  puts(s1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rsi
  push   %rbp
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    $0x7,%edx
  mov    %r12,%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string

tool: D14: Tweedledee 

tool: D19: Tweedledum

assistant: ```c
int main() {
  char s1[50], s2[50];
  strcpy(s1, "Tweedledee ");
  strcpy(s2, "Tweedledum");
  strncat(s1, s2, 7);
  puts(s1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rsi
  push   %rbp
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    $0x7,%edx
  mov    %r12,%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D16: Tweedledee 

tool: D14: Tweedledum

assistant: ```c
int main() {
  char s1[50], s2[50];
  strcpy(s1, "Tweedledee ");
  strcpy(s2, "Tweedledum");
  strncat(s1, s2, 7);
  puts(s1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_find_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L32
  mov    -0x4(%rbp),%eax
  jmp    L9
L32:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    $0xffffffff,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int ft_find_base(char c, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (c == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_find_base>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L29
  mov    $0x0,%eax
L39:
  mov    %eax,%ecx
  cmp    %dl,%dil
  je     L20
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L39
  mov    $0xffffffff,%ecx
L20:
  mov    %ecx,%eax
  ret
L29:
  mov    $0xffffffff,%ecx
  jmp    L20
```

assistant: ```c
int ft_find_base(char c, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (c == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_find_base>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L20
  xor    %eax,%eax
  jmp    L3
  nop
L0:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L20
L3:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L0
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_find_base(char c, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (c == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_find_base>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L7
  xor    %eax,%eax
  jmp    L20
  nop
L6:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L7
L20:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_find_base(char c, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (c == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    D0(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D19(%rip)
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  negl   -0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <itoa>
L10:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    D19(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D19(%rip)
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    D19(%rip),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void itoa(int n, char s[]) {
  static int position = 0;
  if (n < 0) {
    s[position++] = '-';
    n = -n;
  }
  if (n / 10) {
    itoa(n / 10, s);
  }
  n = n % 10;
  s[position++] = n + '0';
  s[position] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %edi,%edi
  js     L10
L30:
  lea    0x9(%rbx),%eax
  cmp    $0x12,%eax
  ja     L0
L22:
  mov    D34(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D33(%rip)
  movslq %eax,%rcx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x0(%rbp,%rcx,1)
  movslq %edx,%rdx
  movb   $0x0,0x0(%rbp,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    D33(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D33(%rip)
  cltq
  movb   $0x2d,(%rsi,%rax,1)
  neg    %ebx
  jmp    L30
L0:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  mov    %rbp,%rsi
  call   <itoa>
  jmp    L22
```

assistant: ```c
void itoa(int n, char s[]) {
  static int position = 0;
  if (n < 0) {
    s[position++] = '-';
    n = -n;
  }
  if (n / 10) {
    itoa(n / 10, s);
  }
  n = n % 10;
  s[position++] = n + '0';
  s[position] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jns    L0
  movslq D9(%rip),%rax
  neg    %ebx
  lea    0x1(%rax),%edx
  movb   $0x2d,(%rsi,%rax,1)
  mov    %edx,D7(%rip)
L0:
  lea    0x9(%rbx),%eax
  mov    %ebx,%ebp
  cmp    $0x12,%eax
  ja     L16
L25:
  mov    $0xcccccccd,%eax
  movslq D7(%rip),%rcx
  imul   %rbp,%rax
  lea    0x1(%rcx),%edx
  mov    %edx,D7(%rip)
  movslq %edx,%rdx
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,(%r12,%rcx,1)
  pop    %rbx
  movb   $0x0,(%r12,%rdx,1)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  mov    $0xcccccccd,%edi
  mov    %r12,%rsi
  imul   %rbp,%rdi
  shr    $0x23,%rdi
  call   <itoa>
  jmp    L25
```

assistant: ```c
void itoa(int n, char s[]) {
  static int position = 0;
  if (n < 0) {
    s[position++] = '-';
    n = -n;
  }
  if (n / 10) {
    itoa(n / 10, s);
  }
  n = n % 10;
  s[position++] = n + '0';
  s[position] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  test   %edi,%edi
  jns    L0
  movslq D54(%rip),%rax
  neg    %ebx
  lea    0x1(%rax),%edx
  movb   $0x2d,(%rsi,%rax,1)
  mov    %edx,D48(%rip)
L0:
  lea    0x9(%rbx),%eax
  cmp    $0x12,%eax
  ja     L57
  movslq D48(%rip),%rcx
  mov    %ebx,%r13d
  mov    %rcx,%rax
  add    %rsi,%rcx
L44:
  mov    $0xcccccccd,%edx
  add    $0x1,%eax
  imul   %r13,%rdx
  mov    %eax,D48(%rip)
  cltq
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rcx)
  movb   $0x0,(%rsi,%rax,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L57:
  mov    %ebx,%r13d
  mov    $0xcccccccd,%edi
  mov    %r13,%r12
  imul   %rdi,%r12
  shr    $0x23,%r12
  lea    0x9(%r12),%eax
  cmp    $0x12,%eax
  ja     L43
  movslq D48(%rip),%rcx
  mov    %r12d,%r15d
  mov    %rcx,%rax
  add    %rsi,%rcx
L58:
  mov    $0xcccccccd,%edx
  add    $0x1,%eax
  imul   %r15,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%r12d
  add    $0x30,%r12d
  mov    %r12b,(%rcx)
  movslq %eax,%rcx
  add    %rsi,%rcx
  movb   $0x0,(%rcx)
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %r12d,%r15d
  mov    %r15,%r14
  imul   %rdi,%r14
  shr    $0x23,%r14
  lea    0x9(%r14),%eax
  mov    %r14d,%ebp
  cmp    $0x12,%eax
  ja     L66
L20:
  mov    $0xcccccccd,%edx
  movslq D48(%rip),%rcx
  imul   %rbp,%rdx
  lea    0x1(%rcx),%eax
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%r14d
  add    $0x30,%r14d
  mov    %r14b,(%rsi,%rcx,1)
  movslq %eax,%rcx
  add    %rsi,%rcx
  movb   $0x0,(%rcx)
  jmp    L58
  nopl   0x0(%rax)
L66:
  imul   %rbp,%rdi
  mov    %rsi,0x8(%rsp)
  shr    $0x23,%rdi
  call   <itoa>
  mov    0x8(%rsp),%rsi
  jmp    L20
```

assistant: ```c
void itoa(int n, char s[]) {
  static int position = 0;
  if (n < 0) {
    s[position++] = '-';
    n = -n;
  }
  if (n / 10) {
    itoa(n / 10, s);
  }
  n = n % 10;
  s[position++] = n + '0';
  s[position] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x3f4(%rbp)
  jmp    L53
L34:
  mov    -0x3f4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3f4(%rbp)
  cltq
  movzbl -0x3f5(%rbp),%edx
  mov    %dl,-0x3f0(%rbp,%rax,1)
L53:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x3f5(%rbp)
  cmpb   $0x0,-0x3f5(%rbp)
  jne    L34
  mov    -0x3f4(%rbp),%eax
  cltq
  movb   $0x0,-0x3f0(%rbp,%rax,1)
  movl   $0x0,-0x3f4(%rbp)
  jmp    L11
L27:
  mov    $0x0,%eax
  call   <rand@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L56
  mov    -0x3f4(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <upper@plt>
  jmp    L3
L56:
  mov    -0x3f4(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lower@plt>
L3:
  addl   $0x1,-0x3f4(%rbp)
L11:
  cmpl   $0x3e7,-0x3f4(%rbp)
  jle    L27
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: Output: %s 


assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  char input_string[1000];
  char c;
  int i = 0;
  while ((c = getchar()) != '\0') {
    input_string[i++] = c;
  }
  input_string[i] = '\0';
  for (i = 0; i < 1000; i++) {
    (rand() & 1) ? upper(input_string, i) : lower(input_string, i);
  }
  printf("Output: %s \n", input_string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%ebx
  jmp    L17
L67:
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
L17:
  mov    $0x0,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L67
  movslq %ebx,%rbp
  movb   $0x0,(%rsp,%rbp,1)
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L60
L62:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <lower@plt>
L49:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L59
L60:
  mov    $0x0,%eax
  call   <rand@plt>
  test   $0x1,%al
  je     L62
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <upper@plt>
  jmp    L49
L59:
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: Output: %s 


assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  char input_string[1000];
  char c;
  int i = 0;
  while ((c = getchar()) != '\0') {
    input_string[i++] = c;
  }
  input_string[i] = '\0';
  for (i = 0; i < 1000; i++) {
    (rand() & 1) ? upper(input_string, i) : lower(input_string, i);
  }
  printf("Output: %s \n", input_string);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L69:
  xor    %eax,%eax
  movslq %ebx,%r12
  call   <getchar@plt>
  test   %al,%al
  jne    L43
  movb   $0x0,(%rsp,%r12,1)
  xor    %ebx,%ebx
  jmp    L15
  nop
L2:
  call   <upper@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L68
L15:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  test   $0x1,%al
  jne    L2
  call   <lower@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L15
L68:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: Output: %s 


assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  char input_string[1000];
  char c;
  int i = 0;
  while ((c = getchar()) != '\0') {
    input_string[i++] = c;
  }
  input_string[i] = '\0';
  for (i = 0; i < 1000; i++) {
    (rand() & 1) ? upper(input_string, i) : lower(input_string, i);
  }
  printf("Output: %s \n", input_string);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L61:
  xor    %eax,%eax
  movslq %ebx,%r12
  call   <getchar@plt>
  test   %al,%al
  jne    L23
  movb   $0x0,(%rsp,%r12,1)
  xor    %ebx,%ebx
  jmp    L33
  nop
L31:
  call   <upper@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L27
L33:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  test   $0x1,%al
  jne    L31
  call   <lower@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L33
L27:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: Output: %s 


assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  char input_string[1000];
  char c;
  int i = 0;
  while ((c = getchar()) != '\0') {
    input_string[i++] = c;
  }
  input_string[i] = '\0';
  for (i = 0; i < 1000; i++) {
    (rand() & 1) ? upper(input_string, i) : lower(input_string, i);
  }
  printf("Output: %s \n", input_string);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_wfd_cfg_op_channel_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string
name: retrieve_data
arguments: data_label: D11
type_infered: string

tool: D2: Usage : wfd_cfg_op_channel [OperatingChannel]


tool: D11: If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.


assistant: ```c
void print_wfd_cfg_op_channel_usage(void) {
  printf("Usage : wfd_cfg_op_channel [OperatingChannel]\n");
  printf("If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_wfd_cfg_op_channel_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string

tool: D3: Usage : wfd_cfg_op_channel [OperatingChannel]


tool: D6: If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.


assistant: ```c
void print_wfd_cfg_op_channel_usage(void) {
  printf("Usage : wfd_cfg_op_channel [OperatingChannel]\n");
  printf("If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_wfd_cfg_op_channel_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string

tool: D2: Usage : wfd_cfg_op_channel [OperatingChannel]


tool: D12: If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.


assistant: ```c
void print_wfd_cfg_op_channel_usage(void) {
  printf("Usage : wfd_cfg_op_channel [OperatingChannel]\n");
  printf("If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_wfd_cfg_op_channel_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string

tool: D10: Usage : wfd_cfg_op_channel [OperatingChannel]


tool: D9: If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.


assistant: ```c
void print_wfd_cfg_op_channel_usage(void) {
  printf("Usage : wfd_cfg_op_channel [OperatingChannel]\n");
  printf("If OperatingChannel parameter is provided, 'set' is performed otherwise 'get' is performed.\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  jmp    L26
L6:
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  test   %eax,%eax
  je     L27
  mov    $0x5,%eax
  jmp    L39
L27:
  mov    $0x4,%eax
L39:
  mov    %eax,%edi
  call   <exit@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string

tool: D2: mdadm: memory allocation failure - aborting


assistant: ```c
char *xstrdup(const char *str) {
  char *rv = strdup(str);
  char *msg;
  if (rv)
    return rv;
  msg = "mdadm"
        ": memory allocation failure - aborting\n";
  exit(4 + !!write(2, msg, strlen(msg)));
}
```