ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load_noinstall_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rax
  add    $0x5,%ebx
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rax,1)
  movslq %ebx,%rbx
  lea    D4(%rip),%rsi
  call   <strcat@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: .libs

assistant: ```c
char *load_noinstall_path(const char *arg, int pathlen) {
  char *newarg, *expanded_path;
  int newpathlen;
  newarg = (char *)malloc(strlen(arg) + 10);
  strcpy(newarg, arg);
  newarg[pathlen] = 0;
  newpathlen = pathlen;
  strcat(newarg, ".libs");
  newpathlen += sizeof(".libs") - 1;
  newarg[newpathlen] = 0;
  expanded_path = newarg;
  return expanded_path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<load_noinstall_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rax
  add    $0x5,%ebx
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rax,1)
  movslq %ebx,%rbx
  lea    D6(%rip),%rsi
  call   <strcat@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: .libs

assistant: ```c
char *load_noinstall_path(const char *arg, int pathlen) {
  char *newarg, *expanded_path;
  int newpathlen;
  newarg = (char *)malloc(strlen(arg) + 10);
  strcpy(newarg, arg);
  newarg[pathlen] = 0;
  newpathlen = pathlen;
  strcat(newarg, ".libs");
  newpathlen += sizeof(".libs") - 1;
  newarg[newpathlen] = 0;
  expanded_path = newarg;
  return expanded_path;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L4:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i;
  for (i = 0; str[i] != 0; i++)
    ;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  mov    $0x0,%eax
L0:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L0
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i;
  for (i = 0; str[i] != 0; i++)
    ;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L3
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L1
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i;
  for (i = 0; str[i] != 0; i++)
    ;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L17
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i;
  for (i = 0; str[i] != 0; i++)
    ;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<moonphasebylunation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movsd  D8(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <moonphase@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: f64

tool: D8: 4

assistant: ```c
extern double moonphasebylunation(int lun, int phi) {
  double k;
  k = lun + phi / 4.0;
  return moonphase(k, phi);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<moonphasebylunation>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %esi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  mulsd  D2(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  call   <moonphase@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
extern double moonphasebylunation(int lun, int phi) {
  double k;
  k = lun + phi / 4.0;
  return moonphase(k, phi);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<moonphasebylunation>:
  endbr64
  pxor   %xmm0,%xmm0
  mov    %edi,%r8d
  pxor   %xmm1,%xmm1
  mov    %esi,%edi
  cvtsi2sd %esi,%xmm0
  mulsd  D8(%rip),%xmm0
  cvtsi2sd %r8d,%xmm1
  addsd  %xmm1,%xmm0
  jmp    1050 <moonphase@plt>
```

tool_calls: name: read_data
arguments: label: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
extern double moonphasebylunation(int lun, int phi) {
  double k;
  k = lun + phi / 4.0;
  return moonphase(k, phi);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<moonphasebylunation>:
  endbr64
  pxor   %xmm0,%xmm0
  mov    %edi,%r8d
  pxor   %xmm1,%xmm1
  mov    %esi,%edi
  cvtsi2sd %esi,%xmm0
  mulsd  D1(%rip),%xmm0
  cvtsi2sd %r8d,%xmm1
  addsd  %xmm1,%xmm0
  jmp    1050 <moonphase@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
extern double moonphasebylunation(int lun, int phi) {
  double k;
  k = lun + phi / 4.0;
  return moonphase(k, phi);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  imul   $0x20bbe199,%rax,%rax
  lea    0x1fd7f33e(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[local1] & 31UL) << 4UL;
      state[local1] |= (state[0UL] & 15UL) << 2UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[0UL] & 7UL) << 2UL;
      state[0UL] |= (state[local1] & 7UL) << 2UL;
      local1++;
    }
    output[0UL] = state[0UL] * 549183897UL + 534246206UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  imul   $0x20bbe199,%rax,%rax
  add    $0x1fd7f33e,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[local1] & 31UL) << 4UL;
      state[local1] |= (state[0UL] & 15UL) << 2UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[0UL] & 7UL) << 2UL;
      state[0UL] |= (state[local1] & 7UL) << 2UL;
      local1++;
    }
    output[0UL] = state[0UL] * 549183897UL + 534246206UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  imul   $0x20bbe199,%rax,%rax
  add    $0x1fd7f33e,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[local1] & 31UL) << 4UL;
      state[local1] |= (state[0UL] & 15UL) << 2UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[0UL] & 7UL) << 2UL;
      state[0UL] |= (state[local1] & 7UL) << 2UL;
      local1++;
    }
    output[0UL] = state[0UL] * 549183897UL + 534246206UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  imul   $0x20bbe199,%rax,%rax
  add    $0x1fd7f33e,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[local1] & 31UL) << 4UL;
      state[local1] |= (state[0UL] & 15UL) << 2UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] |= (state[0UL] & 7UL) << 2UL;
      state[0UL] |= (state[local1] & 7UL) << 2UL;
      local1++;
    }
    output[0UL] = state[0UL] * 549183897UL + 534246206UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<getStringLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L7:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long unsigned int getStringLength(const char *___st___, char ___tm___) {
  long unsigned int ___cn___ = 0;
  while (*(___st___ + ___cn___) != ___tm___) {
    ___cn___++;
  }
  return ___cn___;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getStringLength>:
  endbr64
  mov    %esi,%edx
  cmp    (%rdi),%sil
  je     L16
  mov    $0x0,%eax
L18:
  add    $0x1,%rax
  cmp    %dl,(%rdi,%rax,1)
  jne    L18
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
long unsigned int getStringLength(const char *___st___, char ___tm___) {
  long unsigned int ___cn___ = 0;
  while (*(___st___ + ___cn___) != ___tm___) {
    ___cn___++;
  }
  return ___cn___;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getStringLength>:
  endbr64
  mov    %esi,%edx
  xor    %eax,%eax
  cmp    (%rdi),%sil
  je     L9
  nopl   (%rax)
L13:
  add    $0x1,%rax
  cmp    %dl,(%rdi,%rax,1)
  jne    L13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
long unsigned int getStringLength(const char *___st___, char ___tm___) {
  long unsigned int ___cn___ = 0;
  while (*(___st___ + ___cn___) != ___tm___) {
    ___cn___++;
  }
  return ___cn___;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getStringLength>:
  endbr64
  mov    %esi,%edx
  xor    %eax,%eax
  cmp    (%rdi),%sil
  je     L3
  nopl   (%rax)
L12:
  add    $0x1,%rax
  cmp    %dl,(%rdi,%rax,1)
  jne    L12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
long unsigned int getStringLength(const char *___st___, char ___tm___) {
  long unsigned int ___cn___ = 0;
  while (*(___st___ + ___cn___) != ___tm___) {
    ___cn___++;
  }
  return ___cn___;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quicksortlib>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,0xc(%rsp)
  mov    %edx,%r12d
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r15
  sub    %esi,%edx
  sub    $0x1,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r14
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r13
  mov    (%r15),%edx
  mov    (%r14),%esi
  mov    0x0(%r13),%edi
  call   <median@plt>
  mov    %eax,%ebp
  mov    (%r15),%r8d
  mov    (%r14),%ecx
  mov    0x0(%r13),%edx
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x0(%r13),%eax
  cmp    %ebp,%eax
  je     L48
  cmp    %ebp,(%r14)
  je     L15
  cmp    %ebp,(%r15)
  je     L47
L48:
  mov    %r12d,%edx
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    %eax,(%r14)
  mov    %ebp,0x0(%r13)
  jmp    L48
L47:
  mov    %eax,(%r15)
  mov    %ebp,0x0(%r13)
  jmp    L48
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: Median = %d, low = %d, middle = %d, high = %d

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low - 1) / 2;
  median1 = median(a[low], a[middle], a[high]);
  printf("Median = %d, low = %d, middle = %d, high = %d", median1, a[low], a[middle], a[high]);
  if (median1 == a[low]) {
    ;
  } else if (median1 == a[middle]) {
    a[middle] = a[low];
    a[low] = median1;
  } else if (median1 == a[high]) {
    a[high] = a[low];
    a[low] = median1;
  }
  quicksort(a, low, high);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quicksortlib>:
  endbr64
  movslq %edx,%rax
  push   %r15
  mov    %eax,%edx
  push   %r14
  lea    (%rdi,%rax,4),%rcx
  mov    %rax,%r14
  sub    %esi,%edx
  push   %r13
  mov    %esi,%r13d
  sub    $0x1,%edx
  push   %r12
  mov    %edx,%eax
  push   %rbp
  mov    %rdi,%rbp
  shr    $0x1f,%eax
  push   %rbx
  add    %edx,%eax
  sar    %eax
  cltq
  sub    $0x18,%rsp
  mov    (%rcx),%edx
  lea    (%rdi,%rax,4),%r15
  movslq %esi,%rax
  mov    %rcx,0x8(%rsp)
  lea    (%rdi,%rax,4),%rbx
  mov    (%r15),%esi
  mov    (%rbx),%edi
  call   <median@plt>
  mov    0x8(%rsp),%rcx
  mov    (%rbx),%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  mov    (%rcx),%r8d
  mov    (%r15),%ecx
  call   <printf@plt>
  mov    (%rbx),%eax
  cmp    %r12d,%eax
  je     L11
  cmp    %r12d,(%r15)
  je     L19
  mov    0x8(%rsp),%rsi
  cmp    %r12d,(%rsi)
  je     L8
L11:
  add    $0x18,%rsp
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <quicksort@plt>
L19:
  mov    %eax,(%r15)
  mov    %r12d,(%rbx)
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %eax,(%rsi)
  mov    %r12d,(%rbx)
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: Median = %d, low = %d, middle = %d, high = %d

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low - 1) / 2;
  median1 = median(a[low], a[middle], a[high]);
  printf("Median = %d, low = %d, middle = %d, high = %d", median1, a[low], a[middle], a[high]);
  if (median1 == a[low]) {
    ;
  } else if (median1 == a[middle]) {
    a[middle] = a[low];
    a[low] = median1;
  } else if (median1 == a[high]) {
    a[high] = a[low];
    a[low] = median1;
  }
  quicksort(a, low, high);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quicksortlib>:
  endbr64
  movslq %edx,%rax
  push   %r15
  mov    %eax,%edx
  push   %r14
  lea    (%rdi,%rax,4),%rcx
  mov    %rax,%r14
  sub    %esi,%edx
  push   %r13
  mov    %esi,%r13d
  sub    $0x1,%edx
  push   %r12
  mov    %edx,%eax
  push   %rbp
  mov    %rdi,%rbp
  shr    $0x1f,%eax
  push   %rbx
  add    %edx,%eax
  sar    %eax
  cltq
  sub    $0x18,%rsp
  mov    (%rcx),%edx
  lea    (%rdi,%rax,4),%r15
  movslq %esi,%rax
  mov    %rcx,0x8(%rsp)
  lea    (%rdi,%rax,4),%rbx
  mov    (%r15),%esi
  mov    (%rbx),%edi
  call   <median@plt>
  mov    0x8(%rsp),%rcx
  mov    (%rbx),%edx
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  mov    (%rcx),%r8d
  mov    (%r15),%ecx
  call   <printf@plt>
  mov    (%rbx),%eax
  cmp    %r12d,%eax
  je     L21
  cmp    %r12d,(%r15)
  je     L2
  mov    0x8(%rsp),%rsi
  cmp    %r12d,(%rsi)
  je     L40
L21:
  add    $0x18,%rsp
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <quicksort@plt>
L2:
  mov    %eax,(%r15)
  mov    %r12d,(%rbx)
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %eax,(%rsi)
  mov    %r12d,(%rbx)
  jmp    L21
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string

tool: D7: Median = %d, low = %d, middle = %d, high = %d

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low - 1) / 2;
  median1 = median(a[low], a[middle], a[high]);
  printf("Median = %d, low = %d, middle = %d, high = %d", median1, a[low], a[middle], a[high]);
  if (median1 == a[low]) {
    ;
  } else if (median1 == a[middle]) {
    a[middle] = a[low];
    a[low] = median1;
  } else if (median1 == a[high]) {
    a[high] = a[low];
    a[low] = median1;
  }
  quicksort(a, low, high);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<multiply_numbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string

tool: D4: %d * %d = %d


assistant: ```c
void multiply_numbers(const int a, const int b) {
  ((void)0);
  if ((a * b) == 777) {
    ((void)0);
  }
  printf("%d * %d = %d\n", a, b, a * b);
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply_numbers>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %edi,%ecx
  imul   %esi,%ecx
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: %d * %d = %d


assistant: ```c
void multiply_numbers(const int a, const int b) {
  ((void)0);
  if ((a * b) == 777) {
    ((void)0);
  }
  printf("%d * %d = %d\n", a, b, a * b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<multiply_numbers>:
  endbr64
  mov    %edi,%ecx
  mov    %esi,%edx
  imul   %esi,%ecx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string

tool: D4: %d * %d = %d


assistant: ```c
void multiply_numbers(const int a, const int b) {
  ((void)0);
  if ((a * b) == 777) {
    ((void)0);
  }
  printf("%d * %d = %d\n", a, b, a * b);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply_numbers>:
  endbr64
  mov    %edi,%ecx
  mov    %esi,%edx
  imul   %esi,%ecx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %d * %d = %d


assistant: ```c
void multiply_numbers(const int a, const int b) {
  ((void)0);
  if ((a * b) == 777) {
    ((void)0);
  }
  printf("%d * %d = %d\n", a, b, a * b);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf0,%rsp
  mov    %rdi,-0x10d8(%rbp)
  mov    %esi,-0x10dc(%rbp)
  mov    %edx,-0x10e0(%rbp)
  mov    %ecx,-0x10e4(%rbp)
  mov    %r8,-0x10f0(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L11
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L11:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x10dc(%rbp),%edx
  mov    -0x10d8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wattron@plt>
  mov    -0x10f0(%rbp),%rdx
  mov    -0x10c8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x10c8(%rbp),%edx
  mov    -0x10f0(%rbp),%rcx
  lea    -0x10c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  lea    -0x10c0(%rbp),%rcx
  mov    -0x10e4(%rbp),%edx
  mov    -0x10e0(%rbp),%esi
  mov    -0x10d8(%rbp),%rax
  mov    %rax,%rdi
  call   <mvwprintw@plt>
  mov    %eax,-0x10c4(%rbp)
  mov    -0x10c8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x10dc(%rbp),%edx
  mov    -0x10d8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wattroff@plt>
  mov    -0x10c4(%rbp),%eax
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int wprintf(WINDOW *win, int attr, int y, int x, const char *format, ...) {
  char dest[4096];
  wattron(win, attr);
  va_list argptr;
  va_start(argptr, format);
  vsprintf(dest, format, argptr);
  int ret = mvwprintw(win, y, x, dest);
  va_end(argptr);
  wattroff(win, attr);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,0xc(%rsp)
  mov    %ecx,%r14d
  mov    %r8,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  call   <wattron@plt>
  mov    %r12,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  lea    0x10(%rsp),%r15
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <vsprintf@plt>
  mov    %r15,%rcx
  mov    %r14d,%edx
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <mvwprintw@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <wattroff@plt>
  mov    0x1018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12d,%eax
  add    $0x1028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wprintf(WINDOW *win, int attr, int y, int x, const char *format, ...) {
  char dest[4096];
  wattron(win, attr);
  va_list argptr;
  va_start(argptr, format);
  vsprintf(dest, format, argptr);
  int ret = mvwprintw(win, y, x, dest);
  va_end(argptr);
  wattroff(win, attr);
  return ret;
}
```