ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  lea    -0x10(%rbp),%rsi
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <iloraz_reszta@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D47
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D35
type_guessed: string
name: read_data
arguments: data_label: D56
type_guessed: string

tool: D27: Podaj liczbe calkowita 'n' : 

tool: D47: %i

tool: D15: Podaj liczbe calkowita 'k', k=/=0 : 

tool: D35: Iloraz calkowity : %i


tool: D56: Reszta z dzielenia : %i


assistant: ```c
int main() {
  int n, k, r, q;
  printf("Podaj liczbe calkowita 'n' : ");
  scanf("%i", &n);
  printf("Podaj liczbe calkowita 'k', k=/=0 : ");
  scanf("%i", &k);
  iloraz_reszta(&q, &r, n, k);
  printf("Iloraz calkowity : %i\n", q);
  printf("Reszta z dzielenia : %i\n", r);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  call   <iloraz_reszta@plt>
  mov    0x14(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D34
data_type: string
name: read_data
arguments: tag: D20
data_type: string
name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D1
data_type: string

tool: D34: Podaj liczbe calkowita 'n' : 

tool: D20: %i

tool: D28: Podaj liczbe calkowita 'k', k=/=0 : 

tool: D10: Iloraz calkowity : %i


tool: D1: Reszta z dzielenia : %i


assistant: ```c
int main() {
  int n, k, r, q;
  printf("Podaj liczbe calkowita 'n' : ");
  scanf("%i", &n);
  printf("Podaj liczbe calkowita 'k', k=/=0 : ");
  scanf("%i", &k);
  iloraz_reszta(&q, &r, n, k);
  printf("Iloraz calkowity : %i\n", q);
  printf("Reszta z dzielenia : %i\n", r);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D32(%rip),%rdi
  lea    D7(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  call   <iloraz_reszta@plt>
  mov    0x14(%rsp),%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D32
datatype: string
name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D49
datatype: string
name: unpack_data
arguments: label: D11
datatype: string

tool: D32: Podaj liczbe calkowita 'n' : 

tool: D7: %i

tool: D13: Podaj liczbe calkowita 'k', k=/=0 : 

tool: D49: Iloraz calkowity : %i


tool: D11: Reszta z dzielenia : %i


assistant: ```c
int main() {
  int n, k, r, q;
  printf("Podaj liczbe calkowita 'n' : ");
  scanf("%i", &n);
  printf("Podaj liczbe calkowita 'k', k=/=0 : ");
  scanf("%i", &k);
  iloraz_reszta(&q, &r, n, k);
  printf("Iloraz calkowity : %i\n", q);
  printf("Reszta z dzielenia : %i\n", r);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  lea    D37(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  call   <iloraz_reszta@plt>
  mov    0x14(%rsp),%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string
name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D47
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D8: Podaj liczbe calkowita 'n' : 

tool: D37: %i

tool: D15: Podaj liczbe calkowita 'k', k=/=0 : 

tool: D47: Iloraz calkowity : %i


tool: D13: Reszta z dzielenia : %i


assistant: ```c
int main() {
  int n, k, r, q;
  printf("Podaj liczbe calkowita 'n' : ");
  scanf("%i", &n);
  printf("Podaj liczbe calkowita 'k', k=/=0 : ");
  scanf("%i", &k);
  iloraz_reszta(&q, &r, n, k);
  printf("Iloraz calkowity : %i\n", q);
  printf("Reszta z dzielenia : %i\n", r);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_dns_format_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L55:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L54
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L54
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  jmp    L45
L54:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
L45:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L55
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x23,(%rax)
  cmpl   $0x0,-0x24(%rbp)
  jns    L15
  negl   -0x24(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2d,(%rax)
L15:
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L39:
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L39
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L53:
  mov    -0x10(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L53
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *_dns_format_code(char *buf, const char *prefix, int code) {
  char *bp = buf;
  unsigned c, n;
  do
    *bp++ = ((*prefix) >= 'a' && (*prefix) <= 'z' ? (*prefix) - 'a' + 'A' : (*prefix));
  while (*++prefix);
  *bp++ = '#';
  if (code < 0)
    code = -code, *bp++ = '-';
  n = 0;
  c = code;
  do
    ++n;
  while ((c /= 10));
  c = code;
  bp[n--] = '\0';
  do
    bp[n--] = c % 10 + '0';
  while ((c /= 10));
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<_dns_format_code>:
  endbr64
  mov    %rdi,%r9
  jmp    L18
L0:
  mov    %rcx,%r9
L18:
  movzbl (%rsi),%eax
  lea    -0x61(%rax),%r8d
  lea    -0x20(%rax),%ecx
  cmp    $0x1a,%r8b
  cmovb  %ecx,%eax
  lea    0x1(%r9),%rcx
  mov    %al,-0x1(%rcx)
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  jne    L0
  movb   $0x23,(%rcx)
  add    $0x2,%r9
  test   %edx,%edx
  js     L57
L39:
  mov    %edx,%ecx
  mov    $0x0,%eax
  mov    $0xcccccccd,%r10d
L25:
  mov    %eax,%esi
  add    $0x1,%eax
  mov    %edx,%r8d
  mov    %edx,%edx
  imul   %r10,%rdx
  shr    $0x23,%rdx
  cmp    $0x9,%r8d
  ja     L25
  mov    %eax,%eax
  movb   $0x0,(%r9,%rax,1)
  mov    $0xcccccccd,%r11d
L51:
  mov    %esi,%edx
  sub    $0x1,%esi
  mov    %edx,%edx
  mov    %ecx,%eax
  imul   %r11,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r10d
  add    %r10d,%r10d
  mov    %ecx,%r8d
  sub    %r10d,%r8d
  add    $0x30,%r8d
  mov    %r8b,(%r9,%rdx,1)
  mov    %ecx,%edx
  mov    %eax,%ecx
  cmp    $0x9,%edx
  ja     L51
  mov    %rdi,%rax
  ret
L57:
  neg    %edx
  lea    0x2(%rcx),%r9
  movb   $0x2d,0x1(%rcx)
  jmp    L39
```

assistant: ```c
const char *_dns_format_code(char *buf, const char *prefix, int code) {
  char *bp = buf;
  unsigned c, n;
  do
    *bp++ = ((*prefix) >= 'a' && (*prefix) <= 'z' ? (*prefix) - 'a' + 'A' : (*prefix));
  while (*++prefix);
  *bp++ = '#';
  if (code < 0)
    code = -code, *bp++ = '-';
  n = 0;
  c = code;
  do
    ++n;
  while ((c /= 10));
  c = code;
  bp[n--] = '\0';
  do
    bp[n--] = c % 10 + '0';
  while ((c /= 10));
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_dns_format_code>:
  endbr64
  movzbl (%rsi),%eax
  mov    %rdi,%r8
  mov    %rdi,%r10
  jmp    L37
  nop
L20:
  mov    %rcx,%r10
L37:
  lea    -0x61(%rax),%edi
  lea    -0x20(%rax),%ecx
  cmp    $0x1a,%dil
  cmovb  %ecx,%eax
  add    $0x1,%rsi
  lea    0x1(%r10),%rcx
  mov    %al,-0x1(%rcx)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L20
  movb   $0x23,(%rcx)
  test   %edx,%edx
  js     L57
  add    $0x2,%r10
L15:
  mov    %edx,%eax
  xor    %edi,%edi
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %eax,%eax
  mov    %edi,%ecx
  lea    0x1(%rdi),%edi
  mov    %rax,%rsi
  imul   %r9,%rax
  shr    $0x23,%rax
  cmp    $0x9,%esi
  ja     L19
  movb   $0x0,(%r10,%rdi,1)
  mov    $0xcccccccd,%r11d
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %edx,%eax
  mov    %edx,%edi
  mov    %ecx,%esi
  sub    $0x1,%ecx
  imul   %r11,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%edi
  add    $0x30,%edi
  mov    %dil,(%r10,%rsi,1)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  ja     L21
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  movb   $0x2d,0x1(%rcx)
  neg    %edx
  add    $0x3,%r10
  jmp    L15
```

assistant: ```c
const char *_dns_format_code(char *buf, const char *prefix, int code) {
  char *bp = buf;
  unsigned c, n;
  do
    *bp++ = ((*prefix) >= 'a' && (*prefix) <= 'z' ? (*prefix) - 'a' + 'A' : (*prefix));
  while (*++prefix);
  *bp++ = '#';
  if (code < 0)
    code = -code, *bp++ = '-';
  n = 0;
  c = code;
  do
    ++n;
  while ((c /= 10));
  c = code;
  bp[n--] = '\0';
  do
    bp[n--] = c % 10 + '0';
  while ((c /= 10));
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_dns_format_code>:
  endbr64
  mov    %rdi,%r8
  mov    %rdi,%r10
  jmp    L21
  nopl   0x0(%rax)
L28:
  sub    $0x20,%eax
  add    $0x1,%rsi
  mov    %al,-0x1(%rcx)
  cmpb   $0x0,(%rsi)
  je     L12
L48:
  mov    %rcx,%r10
L21:
  movzbl (%rsi),%eax
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  lea    0x1(%r10),%rcx
  jbe    L28
  add    $0x1,%rsi
  mov    %al,-0x1(%rcx)
  cmpb   $0x0,(%rsi)
  jne    L48
L12:
  movb   $0x23,(%rcx)
  add    $0x2,%r10
  test   %edx,%edx
  jns    L13
  movb   $0x2d,0x1(%rcx)
  neg    %edx
  lea    0x2(%rcx),%r10
L13:
  mov    %edx,%eax
  xor    %edi,%edi
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L15:
  mov    %eax,%eax
  mov    %edi,%ecx
  lea    0x1(%rdi),%edi
  mov    %rax,%rsi
  imul   %r9,%rax
  shr    $0x23,%rax
  cmp    $0x9,%esi
  ja     L15
  movb   $0x0,(%r10,%rdi,1)
  mov    $0xcccccccd,%r11d
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %edx,%eax
  mov    %edx,%edi
  mov    %ecx,%esi
  sub    $0x1,%ecx
  imul   %r11,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%edi
  add    $0x30,%edi
  mov    %dil,(%r10,%rsi,1)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  ja     L39
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *_dns_format_code(char *buf, const char *prefix, int code) {
  char *bp = buf;
  unsigned c, n;
  do
    *bp++ = ((*prefix) >= 'a' && (*prefix) <= 'z' ? (*prefix) - 'a' + 'A' : (*prefix));
  while (*++prefix);
  *bp++ = '#';
  if (code < 0)
    code = -code, *bp++ = '-';
  n = 0;
  c = code;
  do
    ++n;
  while ((c /= 10));
  c = code;
  bp[n--] = '\0';
  do
    bp[n--] = c % 10 + '0';
  while ((c /= 10));
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x30(%rbp),%r8d
  mov    -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <mmap@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xmmap(void *addr, size_t length, int prot, int flags, int fd, off_t offset) {
  void *ret = mmap(addr, length, prot, flags, fd, offset);
  if (ret == MAP_FAILED) {
    ;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xmmap>:
  endbr64
  sub    $0x8,%rsp
  call   <mmap@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *xmmap(void *addr, size_t length, int prot, int flags, int fd, off_t offset) {
  void *ret = mmap(addr, length, prot, flags, fd, offset);
  if (ret == MAP_FAILED) {
    ;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmmap>:
  endbr64
  jmp    1050 <mmap@plt>
```

assistant: ```c
void *xmmap(void *addr, size_t length, int prot, int flags, int fd, off_t offset) {
  void *ret = mmap(addr, length, prot, flags, fd, offset);
  if (ret == MAP_FAILED) {
    ;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmmap>:
  endbr64
  jmp    1050 <mmap@plt>
```

assistant: ```c
void *xmmap(void *addr, size_t length, int prot, int flags, int fd, off_t offset) {
  void *ret = mmap(addr, length, prot, flags, fd, offset);
  if (ret == MAP_FAILED) {
    ;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L49
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L18
L49:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <validarCadena@plt>
  test   %rax,%rax
  je     L36
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <str_a_entero@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L36:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string

tool: D1: Error

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    printf("Error\n");
    return 2;
  }
  int i = 0;
  int total = 0;
  for (i = 1; i < argc; i++) {
    if (validarCadena(argv[i])) {
      total += str_a_entero(argv[i]);
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L24
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
  mov    $0x0,%r12d
  jmp    L34
L24:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L52
L9:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L19
L34:
  mov    (%rbx),%rdi
  call   <validarCadena@plt>
  test   %rax,%rax
  je     L9
  mov    (%rbx),%rdi
  call   <str_a_entero@plt>
  add    %eax,%r12d
  jmp    L9
L19:
  mov    %r12d,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D5: Error

tool: D15: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    printf("Error\n");
    return 2;
  }
  int i = 0;
  int total = 0;
  for (i = 1; i < argc; i++) {
    if (validarCadena(argv[i])) {
      total += str_a_entero(argv[i]);
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L25
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  xor    %r12d,%r12d
  lea    0x10(%rsi,%rax,8),%rbp
  jmp    L7
  xchg   %ax,%ax
L23:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L1
L7:
  mov    (%rbx),%rdi
  call   <validarCadena@plt>
  test   %rax,%rax
  je     L23
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <str_a_entero@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L7
L1:
  mov    %r12d,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L49
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D17
type: string

tool: D16: %d


tool: D17: Error

assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    printf("Error\n");
    return 2;
  }
  int i = 0;
  int total = 0;
  for (i = 1; i < argc; i++) {
    if (validarCadena(argv[i])) {
      total += str_a_entero(argv[i]);
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L20
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  xor    %r12d,%r12d
  lea    0x10(%rsi,%rax,8),%rbp
  jmp    L23
  xchg   %ax,%ax
L15:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L34
L23:
  mov    (%rbx),%rdi
  call   <validarCadena@plt>
  test   %rax,%rax
  je     L15
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <str_a_entero@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L23
L34:
  mov    %r12d,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%eax
  jmp    L22
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string

tool: D0: %d


tool: D13: Error

assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    printf("Error\n");
    return 2;
  }
  int i = 0;
  int total = 0;
  for (i = 1; i < argc; i++) {
    if (validarCadena(argv[i])) {
      total += str_a_entero(argv[i]);
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0xc7,-0x10(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assume@plt>
  jmp    L16
L1:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L8:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0xc7,-0x8(%rbp)
  jle    L8
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
L16:
  cmpl   $0x1f3,-0x10(%rbp)
  jle    L1
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  i = j;
  assume(i < 200);
  while (i < 500) {
    i = i + 1;
    j = j + 1;
    k = 0;
    l = 0;
    while (k < 200) {
      k = k + 1;
      l = l + 1;
    }
    i = i + k;
    j = j + l;
  }
  assert(i == j + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  mov    $0x1,%edi
  call   <assume@plt>
L13:
  mov    $0xc8,%eax
L15:
  sub    $0x1,%eax
  jne    L15
  add    $0xc9,%ebx
  cmp    $0x1f3,%ebx
  jle    L13
  mov    %ebx,%eax
  add    $0x1,%eax
  cmp    %ebx,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  i = j;
  assume(i < 200);
  while (i < 500) {
    i = i + 1;
    j = j + 1;
    k = 0;
    l = 0;
    while (k < 200) {
      k = k + 1;
      l = l + 1;
    }
    i = i + k;
    j = j + l;
  }
  assert(i == j + 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assume@plt>
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  i = j;
  assume(i < 200);
  while (i < 500) {
    i = i + 1;
    j = j + 1;
    k = 0;
    l = 0;
    while (k < 200) {
      k = k + 1;
      l = l + 1;
    }
    i = i + k;
    j = j + l;
  }
  assert(i == j + 1);
  return 0;
}
```