ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D41(%rip),%rdi
  lea    D6(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  call   <puts@plt>
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D63(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x5,%eax
  movsd  0x20(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  lea    D39(%rip),%rdi
  movapd %xmm1,%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm2,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm4
  subsd  %xmm5,%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm3,%xmm5
  addsd  %xmm5,%xmm4
  subsd  D23(%rip),%xmm4
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D41
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D78
type_infered: string
name: extract_symbolic_data
arguments: label: D26
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D63
type_infered: string
name: extract_symbolic_data
arguments: label: D39
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: f32[2]

tool: D41: Introduzca los coeficientes y el valor de x para obtener el resultado de:
	ax^5 - bx^3 + cx - 7


tool: D6: %lf

tool: D78: a = 

tool: D26: b = 

tool: D4: c = 

tool: D63: x = 

tool: D39: 
Para x = %g,  %gx^5 - %gx^3 + %gx - 7 = %g


tool: {"D23": [0.0,2.4375]}

assistant: ```c
main() {
  double a = 0, b = 0, c = 0, x = 0, p = 0;
  printf("Introduzca los coeficientes y el valor de x para obtener el resultado de:\n"
         "\tax^5 - bx^3 + cx - 7\n\n");
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("c = ");
  scanf("%lf", &c);
  printf("x = ");
  scanf("%lf", &x);
  p = a * x * x * x * x * x - b * x * x * x + c * x - 7;
  printf("\nPara x = %g,  %gx^5 - %gx^3 + %gx - 7 = %g\n", x, a, b, c, p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D78(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  call   <puts@plt>
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x5,%eax
  movsd  0x20(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  lea    D68(%rip),%rdi
  movapd %xmm1,%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm2,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm4
  subsd  %xmm5,%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm3,%xmm5
  addsd  %xmm5,%xmm4
  subsd  D31(%rip),%xmm4
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D78
datatype: string
name: disassemble_data
arguments: tag: D65
datatype: string
name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D46
datatype: string
name: disassemble_data
arguments: tag: D30
datatype: string
name: disassemble_data
arguments: tag: D68
datatype: string
name: disassemble_data
arguments: tag: D31
datatype: f32[2]

tool: D15: Introduzca los coeficientes y el valor de x para obtener el resultado de:
	ax^5 - bx^3 + cx - 7


tool: D78: %lf

tool: D65: a = 

tool: D27: b = 

tool: D46: c = 

tool: D30: x = 

tool: D68: 
Para x = %g,  %gx^5 - %gx^3 + %gx - 7 = %g


tool: {"D31": [0.0,2.4375]}

assistant: ```c
main() {
  double a = 0, b = 0, c = 0, x = 0, p = 0;
  printf("Introduzca los coeficientes y el valor de x para obtener el resultado de:\n"
         "\tax^5 - bx^3 + cx - 7\n\n");
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("c = ");
  scanf("%lf", &c);
  printf("x = ");
  scanf("%lf", &x);
  p = a * x * x * x * x * x - b * x * x * x + c * x - 7;
  printf("\nPara x = %g,  %gx^5 - %gx^3 + %gx - 7 = %g\n", x, a, b, c, p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a2i_IPADDRESS_NC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L91
  mov    $0x0,%eax
  jmp    L110
L91:
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x40(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L110
L1:
  mov    -0x38(%rbp),%rax
  sub    -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <a2i_ipadd@plt>
  mov    %eax,-0x50(%rbp)
  cmpl   $0x0,-0x50(%rbp)
  je     L58
  mov    -0x50(%rbp),%eax
  cltq
  lea    -0x30(%rbp),%rdx
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <a2i_ipadd@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x40(%rbp)
  cmpl   $0x0,-0x4c(%rbp)
  je     L128
  mov    -0x50(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jne    L128
  mov    $0x0,%eax
  call   <ASN1_OCTET_STRING_new@plt>
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  je     L46
  mov    -0x50(%rbp),%edx
  mov    -0x4c(%rbp),%eax
  add    %eax,%edx
  lea    -0x30(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ASN1_OCTET_STRING_set@plt>
  test   %eax,%eax
  je     L69
  mov    -0x48(%rbp),%rax
  jmp    L110
L58:
  nop
  jmp    L78
L128:
  nop
  jmp    L78
L46:
  nop
  jmp    L78
L69:
  nop
L78:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpq   $0x0,-0x48(%rbp)
  je     L148
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <ASN1_OCTET_STRING_free@plt>
L148:
  mov    $0x0,%eax
L110:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
ASN1_OCTET_STRING *a2i_IPADDRESS_NC(const char *ipasc) {
  ASN1_OCTET_STRING *ret = NULL;
  unsigned char ipout[32];
  char *iptmp = NULL, *p;
  int iplen1, iplen2;
  p = strchr(ipasc, '/');
  if (!p)
    return NULL;
  iptmp = strdup(ipasc);
  if (!iptmp)
    return NULL;
  p = iptmp + (p - ipasc);
  *p++ = 0;
  iplen1 = a2i_ipadd(ipout, iptmp);
  if (!iplen1)
    goto err;
  iplen2 = a2i_ipadd(ipout + iplen1, p);
  free(iptmp);
  iptmp = NULL;
  if (!iplen2 || (iplen1 != iplen2))
    goto err;
  ret = ASN1_OCTET_STRING_new();
  if (!ret)
    goto err;
  if (!ASN1_OCTET_STRING_set(ret, ipout, iplen1 + iplen2))
    goto err;
  return ret;
err:
  free(iptmp);
  if (ret)
    ASN1_OCTET_STRING_free(ret);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a2i_IPADDRESS_NC>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L59
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L109
  sub    %rbp,%rbx
  add    %rax,%rbx
  movb   $0x0,(%rbx)
  mov    %rsp,%rdi
  mov    %rax,%rsi
  call   <a2i_ipadd@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L115
L38:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L59
L115:
  lea    0x1(%rbx),%rsi
  cltq
  lea    (%rsp,%rax,1),%rdi
  call   <a2i_ipadd@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <free@plt>
  test   %r13d,%r13d
  je     L83
  cmp    %r13d,%ebp
  jne    L83
  mov    $0x0,%eax
  call   <ASN1_OCTET_STRING_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  lea    0x0(%rbp,%r13,1),%edx
  mov    %rsp,%rsi
  mov    %rax,%rdi
  call   <ASN1_OCTET_STRING_set@plt>
  test   %eax,%eax
  jne    L59
  mov    $0x0,%edi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <ASN1_OCTET_STRING_free@plt>
  mov    $0x0,%ebx
L59:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  mov    %rbx,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L109:
  mov    %rax,%rbx
  jmp    L59
L83:
  mov    $0x0,%r12d
  jmp    L38
L3:
  mov    %rax,%r12
  jmp    L38
L92:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OCTET_STRING *a2i_IPADDRESS_NC(const char *ipasc) {
  ASN1_OCTET_STRING *ret = NULL;
  unsigned char ipout[32];
  char *iptmp = NULL, *p;
  int iplen1, iplen2;
  p = strchr(ipasc, '/');
  if (!p)
    return NULL;
  iptmp = strdup(ipasc);
  if (!iptmp)
    return NULL;
  p = iptmp + (p - ipasc);
  *p++ = 0;
  iplen1 = a2i_ipadd(ipout, iptmp);
  if (!iplen1)
    goto err;
  iplen2 = a2i_ipadd(ipout + iplen1, p);
  free(iptmp);
  iptmp = NULL;
  if (!iplen2 || (iplen1 != iplen2))
    goto err;
  ret = ASN1_OCTET_STRING_new();
  if (!ret)
    goto err;
  if (!ASN1_OCTET_STRING_set(ret, ipout, iplen1 + iplen2))
    goto err;
  return ret;
err:
  free(iptmp);
  if (ret)
    ASN1_OCTET_STRING_free(ret);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<a2i_IPADDRESS_NC>:
  endbr64
  push   %r14
  mov    $0x2f,%esi
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
  sub    %r12,%rbx
  mov    %rsp,%r13
  mov    %rax,%rsi
  add    %rax,%rbx
  mov    %r13,%rdi
  movb   $0x0,(%rbx)
  call   <a2i_ipadd@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L22
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <free@plt>
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L22:
  movslq %eax,%rdi
  lea    0x1(%rbx),%rsi
  add    %r13,%rdi
  call   <a2i_ipadd@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  test   %ebx,%ebx
  je     L94
  cmp    %ebx,%r12d
  jne    L94
  xor    %eax,%eax
  call   <ASN1_OCTET_STRING_new@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L94
  lea    (%r12,%rbx,1),%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <ASN1_OCTET_STRING_set@plt>
  test   %eax,%eax
  jne    L51
  xor    %edi,%edi
  call   <free@plt>
  mov    %r14,%rdi
  call   <ASN1_OCTET_STRING_free@plt>
L19:
  xor    %r14d,%r14d
L51:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L94:
  xor    %edi,%edi
  xor    %r14d,%r14d
  call   <free@plt>
  jmp    L51
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OCTET_STRING *a2i_IPADDRESS_NC(const char *ipasc) {
  ASN1_OCTET_STRING *ret = NULL;
  unsigned char ipout[32];
  char *iptmp = NULL, *p;
  int iplen1, iplen2;
  p = strchr(ipasc, '/');
  if (!p)
    return NULL;
  iptmp = strdup(ipasc);
  if (!iptmp)
    return NULL;
  p = iptmp + (p - ipasc);
  *p++ = 0;
  iplen1 = a2i_ipadd(ipout, iptmp);
  if (!iplen1)
    goto err;
  iplen2 = a2i_ipadd(ipout + iplen1, p);
  free(iptmp);
  iptmp = NULL;
  if (!iplen2 || (iplen1 != iplen2))
    goto err;
  ret = ASN1_OCTET_STRING_new();
  if (!ret)
    goto err;
  if (!ASN1_OCTET_STRING_set(ret, ipout, iplen1 + iplen2))
    goto err;
  return ret;
err:
  free(iptmp);
  if (ret)
    ASN1_OCTET_STRING_free(ret);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a2i_IPADDRESS_NC>:
  endbr64
  push   %r14
  mov    $0x2f,%esi
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L12
  sub    %r12,%rbx
  mov    %rsp,%r13
  mov    %rax,%rsi
  add    %rax,%rbx
  mov    %r13,%rdi
  movb   $0x0,(%rbx)
  call   <a2i_ipadd@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L7
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <free@plt>
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L7:
  movslq %eax,%rdi
  lea    0x1(%rbx),%rsi
  add    %r13,%rdi
  call   <a2i_ipadd@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  test   %ebx,%ebx
  je     L25
  cmp    %ebx,%r12d
  jne    L25
  xor    %eax,%eax
  call   <ASN1_OCTET_STRING_new@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L25
  lea    (%r12,%rbx,1),%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <ASN1_OCTET_STRING_set@plt>
  test   %eax,%eax
  jne    L55
  xor    %edi,%edi
  call   <free@plt>
  mov    %r14,%rdi
  call   <ASN1_OCTET_STRING_free@plt>
L12:
  xor    %r14d,%r14d
L55:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x30,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  xor    %edi,%edi
  xor    %r14d,%r14d
  call   <free@plt>
  jmp    L55
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OCTET_STRING *a2i_IPADDRESS_NC(const char *ipasc) {
  ASN1_OCTET_STRING *ret = NULL;
  unsigned char ipout[32];
  char *iptmp = NULL, *p;
  int iplen1, iplen2;
  p = strchr(ipasc, '/');
  if (!p)
    return NULL;
  iptmp = strdup(ipasc);
  if (!iptmp)
    return NULL;
  p = iptmp + (p - ipasc);
  *p++ = 0;
  iplen1 = a2i_ipadd(ipout, iptmp);
  if (!iplen1)
    goto err;
  iplen2 = a2i_ipadd(ipout + iplen1, p);
  free(iptmp);
  iptmp = NULL;
  if (!iplen2 || (iplen1 != iplen2))
    goto err;
  ret = ASN1_OCTET_STRING_new();
  if (!ret)
    goto err;
  if (!ASN1_OCTET_STRING_set(ret, ipout, iplen1 + iplen2))
    goto err;
  return ret;
err:
  free(iptmp);
  if (ret)
    ASN1_OCTET_STRING_free(ret);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_inet6_print_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L2
L8:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x2,-0x10(%rbp)
L2:
  cmpq   $0xf,-0x10(%rbp)
  jbe    L8
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string

tool: 

tool: D5: %s%02x%02x

tool: D2: :

assistant: ```c
void _inet6_print_addr(struct in6_addr *addr) {
  size_t i;
  char const *sep = "";
  for (i = 0; i < 16; i += 2) {
    printf("%s%02x%02x", sep, addr->s6_addr[i], addr->s6_addr[i + 1]);
    sep = ":";
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_inet6_print_addr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x4,%ebx
  lea    D3(%rip),%rsi
  lea    D13(%rip),%r13
  lea    D6(%rip),%r12
L5:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%ecx
  mov    -0x4(%rax,%rbx,1),%edx
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  mov    %r12,%rsi
  cmp    $0x44,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string

tool: 

tool: D13: %s%02x%02x

tool: D6: :

assistant: ```c
void _inet6_print_addr(struct in6_addr *addr) {
  size_t i;
  char const *sep = "";
  for (i = 0; i < 16; i += 2) {
    printf("%s%02x%02x", sep, addr->s6_addr[i], addr->s6_addr[i + 1]);
    sep = ":";
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_inet6_print_addr>:
  endbr64
  push   %r13
  lea    D12(%rip),%rsi
  mov    %rdi,%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x0(%r13),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%ecx
  mov    -0x4(%rax,%rbx,1),%edx
  add    $0x8,%rbx
  call   <printf@plt>
  mov    %rbp,%rsi
  cmp    $0x44,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string

tool: 

tool: D28: %s%02x%02x

tool: D1: :

assistant: ```c
void _inet6_print_addr(struct in6_addr *addr) {
  size_t i;
  char const *sep = "";
  for (i = 0; i < 16; i += 2) {
    printf("%s%02x%02x", sep, addr->s6_addr[i], addr->s6_addr[i + 1]);
    sep = ":";
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_inet6_print_addr>:
  endbr64
  push   %r13
  lea    D6(%rip),%rsi
  mov    %rdi,%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x0(%r13),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%ecx
  mov    -0x4(%rax,%rbx,1),%edx
  add    $0x8,%rbx
  call   <printf@plt>
  mov    %rbp,%rsi
  cmp    $0x44,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: 

tool: D2: %s%02x%02x

tool: D5: :

assistant: ```c
void _inet6_print_addr(struct in6_addr *addr) {
  size_t i;
  char const *sep = "";
  for (i = 0; i < 16; i += 2) {
    printf("%s%02x%02x", sep, addr->s6_addr[i], addr->s6_addr[i + 1]);
    sep = ":";
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<arr_contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L12
  mov    $0x1,%eax
  jmp    L9
L12:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
bool arr_contains(int *arr, int size, int x) {
  for (int i = 0; i < size; ++i) {
    if (arr[i] == x) {
      return true;
    }
  }
  return false;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arr_contains>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
L4:
  cmp    %edx,(%rax)
  je     L12
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L4
  mov    $0x0,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool arr_contains(int *arr, int size, int x) {
  for (int i = 0; i < size; ++i) {
    if (arr[i] == x) {
      return true;
    }
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<arr_contains>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L33:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L6
L0:
  cmp    %edx,(%rdi)
  jne    L33
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool arr_contains(int *arr, int size, int x) {
  for (int i = 0; i < size; ++i) {
    if (arr[i] == x) {
      return true;
    }
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<arr_contains>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L16
L26:
  cmp    %edx,(%rdi)
  jne    L5
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool arr_contains(int *arr, int size, int x) {
  for (int i = 0; i < size; ++i) {
    if (arr[i] == x) {
      return true;
    }
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L27:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L22
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: The new string is %s.


assistant: ```c
void substring(const char source[81], int start, int count, char result[81]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; ++i)
    result[i] = source[i + start];
  result[i] = '\0';
  printf("The new string is %s.\n", result);
}
```