ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gotcha_strnlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L10
  test   %rsi,%rsi
  jne    L34
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    %rax,%rsi
  jbe    L23
L34:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L21
L10:
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  ret
```

assistant: ```c
size_t gotcha_strnlen(const char *s, size_t max_length) {
  size_t i;
  for (i = 0; s[i] && i < max_length; i++)
    ;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gotcha_strnlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L49
  test   %rsi,%rsi
  jne    L32
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L41:
  cmp    %rax,%rsi
  jbe    L33
L32:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L41
L49:
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  ret
```

assistant: ```c
size_t gotcha_strnlen(const char *s, size_t max_length) {
  size_t i;
  for (i = 0; s[i] && i < max_length; i++)
    ;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CPtrArithAccess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L10
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%edi
  cqto
  idiv   %rdi
  cmp    %rax,%rcx
  jle    L35
  mov    0x28(%rbp),%rcx
  mov    0x20(%rbp),%edx
  mov    0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    0x10(%rbp),%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <deputy_fail_mayreturn@plt>
  jmp    L35
L10:
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%esi
  cqto
  idiv   %rsi
  cmp    %rax,%rcx
  jle    L35
  mov    0x28(%rbp),%rsi
  mov    0x20(%rbp),%ecx
  mov    0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <deputy_fail_mayreturn@plt>
L35:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D9: upper bound check

tool: D13: lower bound check

assistant: ```c
void CPtrArithAccess(const volatile void *lo, const volatile void *hi, const volatile void *p, int e, unsigned int sz, const char *textlo, const char *texthi, const char *file, int line, const char *func) {
  if (e >= 0) {
    if (!((unsigned)e + 1 <= (hi - p) / sz) || 0) {
      deputy_fail_mayreturn("upper bound check", texthi, file, line, func);
    };
  } else {
    if (!((unsigned)-e <= (p - lo) / sz) || 0) {
      deputy_fail_mayreturn("lower bound check", textlo, file, line, func);
    };
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CPtrArithAccess>:
  endbr64
  sub    $0x8,%rsp
  test   %ecx,%ecx
  js     L18
  lea    0x1(%rcx),%ecx
  mov    %rsi,%rax
  sub    %rdx,%rax
  mov    %r8d,%r8d
  cqto
  idiv   %r8
  cmp    %rax,%rcx
  jg     L26
L29:
  add    $0x8,%rsp
  ret
L26:
  mov    0x28(%rsp),%r8
  mov    0x20(%rsp),%ecx
  mov    0x18(%rsp),%rdx
  mov    0x10(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <deputy_fail_mayreturn@plt>
  jmp    L29
L18:
  neg    %ecx
  mov    %rdx,%rax
  sub    %rdi,%rax
  mov    %r8d,%r8d
  cqto
  idiv   %r8
  cmp    %rax,%rcx
  jle    L29
  mov    0x28(%rsp),%r8
  mov    0x20(%rsp),%ecx
  mov    0x18(%rsp),%rdx
  mov    %r9,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <deputy_fail_mayreturn@plt>
  jmp    L29
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D13: upper bound check

tool: D4: lower bound check

assistant: ```c
void CPtrArithAccess(const volatile void *lo, const volatile void *hi, const volatile void *p, int e, unsigned int sz, const char *textlo, const char *texthi, const char *file, int line, const char *func) {
  if (e >= 0) {
    if (!((unsigned)e + 1 <= (hi - p) / sz) || 0) {
      deputy_fail_mayreturn("upper bound check", texthi, file, line, func);
    };
  } else {
    if (!((unsigned)-e <= (p - lo) / sz) || 0) {
      deputy_fail_mayreturn("lower bound check", textlo, file, line, func);
    };
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CPtrArithAccess>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %r8d,%esi
  push   %rbx
  mov    0x18(%rsp),%rbp
  mov    0x20(%rsp),%r10
  mov    0x28(%rsp),%r11d
  mov    0x30(%rsp),%rbx
  test   %ecx,%ecx
  js     L19
  sub    %rdx,%rax
  add    $0x1,%ecx
  cqto
  idiv   %rsi
  cmp    %rax,%rcx
  jg     L22
L14:
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdx,%rax
  neg    %ecx
  sub    %rdi,%rax
  movslq %ecx,%rcx
  cqto
  idiv   %rsi
  cmp    %rax,%rcx
  jle    L14
  mov    %rbx,%r8
  mov    %r11d,%ecx
  pop    %rbx
  mov    %r10,%rdx
  mov    %r9,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <deputy_fail_mayreturn@plt>
  nopl   0x0(%rax)
L22:
  mov    %rbx,%r8
  mov    %rbp,%rsi
  pop    %rbx
  mov    %r11d,%ecx
  mov    %r10,%rdx
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <deputy_fail_mayreturn@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D10
data_type: string

tool: D8: lower bound check

tool: D10: upper bound check

assistant: ```c
void CPtrArithAccess(const volatile void *lo, const volatile void *hi, const volatile void *p, int e, unsigned int sz, const char *textlo, const char *texthi, const char *file, int line, const char *func) {
  if (e >= 0) {
    if (!((unsigned)e + 1 <= (hi - p) / sz) || 0) {
      deputy_fail_mayreturn("upper bound check", texthi, file, line, func);
    };
  } else {
    if (!((unsigned)-e <= (p - lo) / sz) || 0) {
      deputy_fail_mayreturn("lower bound check", textlo, file, line, func);
    };
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CPtrArithAccess>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %r8d,%esi
  push   %rbx
  mov    0x18(%rsp),%rbp
  mov    0x20(%rsp),%r10
  mov    0x28(%rsp),%r11d
  mov    0x30(%rsp),%rbx
  test   %ecx,%ecx
  js     L2
  sub    %rdx,%rax
  add    $0x1,%ecx
  cqto
  idiv   %rsi
  cmp    %rax,%rcx
  jg     L24
L14:
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdx,%rax
  neg    %ecx
  sub    %rdi,%rax
  movslq %ecx,%rcx
  cqto
  idiv   %rsi
  cmp    %rax,%rcx
  jle    L14
  mov    %rbx,%r8
  mov    %r11d,%ecx
  pop    %rbx
  mov    %r10,%rdx
  mov    %r9,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <deputy_fail_mayreturn@plt>
  nopl   0x0(%rax)
L24:
  mov    %rbx,%r8
  mov    %rbp,%rsi
  pop    %rbx
  mov    %r11d,%ecx
  mov    %r10,%rdx
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <deputy_fail_mayreturn@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D17: lower bound check

tool: D0: upper bound check

assistant: ```c
void CPtrArithAccess(const volatile void *lo, const volatile void *hi, const volatile void *p, int e, unsigned int sz, const char *textlo, const char *texthi, const char *file, int line, const char *func) {
  if (e >= 0) {
    if (!((unsigned)e + 1 <= (hi - p) / sz) || 0) {
      deputy_fail_mayreturn("upper bound check", texthi, file, line, func);
    };
  } else {
    if (!((unsigned)-e <= (p - lo) / sz) || 0) {
      deputy_fail_mayreturn("lower bound check", textlo, file, line, func);
    };
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <info_fun1@plt>
  mov    $0x61,%edi
  call   <info_fun2@plt>
  mov    $0x62,%edi
  call   <info_fun2bis@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x63,%edi
  call   <info_fun2xxx@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x64,%edi
  call   <info_fun2yyy@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv, char **envp) {
  info_fun1();
  (void)info_fun2('a');
  (void)info_fun2bis('b');
  (void)info_fun2xxx('c', 1, 2);
  (void)info_fun2yyy('d', 3, 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <info_fun1@plt>
  mov    $0x61,%edi
  call   <info_fun2@plt>
  mov    $0x62,%edi
  call   <info_fun2bis@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x63,%edi
  call   <info_fun2xxx@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x64,%edi
  call   <info_fun2yyy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv, char **envp) {
  info_fun1();
  (void)info_fun2('a');
  (void)info_fun2bis('b');
  (void)info_fun2xxx('c', 1, 2);
  (void)info_fun2yyy('d', 3, 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <info_fun1@plt>
  mov    $0x61,%edi
  call   <info_fun2@plt>
  mov    $0x62,%edi
  call   <info_fun2bis@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x63,%edi
  call   <info_fun2xxx@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x64,%edi
  call   <info_fun2yyy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv, char **envp) {
  info_fun1();
  (void)info_fun2('a');
  (void)info_fun2bis('b');
  (void)info_fun2xxx('c', 1, 2);
  (void)info_fun2yyy('d', 3, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <info_fun1@plt>
  mov    $0x61,%edi
  call   <info_fun2@plt>
  mov    $0x62,%edi
  call   <info_fun2bis@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x63,%edi
  call   <info_fun2xxx@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x64,%edi
  call   <info_fun2yyy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv, char **envp) {
  info_fun1();
  (void)info_fun2('a');
  (void)info_fun2bis('b');
  (void)info_fun2xxx('c', 1, 2);
  (void)info_fun2yyy('d', 3, 4);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_dotted_ipv4_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x5(%rbp)
  jmp    L5
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jbe    L27
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  ja     L27
  movzbl -0x5(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  movzbl -0x5(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %al,-0x5(%rbp)
  jmp    L12
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L12
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x5(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  movb   $0x0,-0x5(%rbp)
L12:
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x5(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int read_dotted_ipv4_address(unsigned char *str) {
  unsigned int result = 0;
  unsigned char temp = 0;
  while (*str != '\0') {
    if (*str >= '0' && *str <= '9') {
      temp *= 10;
      temp += *str - '0';
    } else if (*str == '.') {
      result = (result << 8) | temp;
      temp = 0;
    }
    str++;
  }
  result = (result << 8) | temp;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_dotted_ipv4_address>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L54
  mov    $0x0,%eax
  mov    $0x0,%esi
  mov    $0x0,%r8d
  jmp    L3
L47:
  cmp    $0x2e,%dl
  je     L62
L49:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
L3:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L47
  lea    (%rax,%rax,4),%eax
  lea    (%rcx,%rax,2),%eax
  jmp    L49
L62:
  shl    $0x8,%esi
  movzbl %al,%eax
  or     %eax,%esi
  mov    %r8d,%eax
  jmp    L49
L54:
  mov    %edx,%eax
  mov    $0x0,%esi
L18:
  shl    $0x8,%esi
  movzbl %al,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned int read_dotted_ipv4_address(unsigned char *str) {
  unsigned int result = 0;
  unsigned char temp = 0;
  while (*str != '\0') {
    if (*str >= '0' && *str <= '9') {
      temp *= 10;
      temp += *str - '0';
    } else if (*str == '.') {
      result = (result << 8) | temp;
      temp = 0;
    }
    str++;
  }
  result = (result << 8) | temp;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_dotted_ipv4_address>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L27
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L15
  nopl   0x0(%rax)
L18:
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rsi,%rcx,2),%ecx
L5:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L47
L15:
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L18
  cmp    $0x2e,%dl
  jne    L5
  movzbl 0x1(%rdi),%edx
  movzbl %cl,%ecx
  shl    $0x8,%eax
  add    $0x1,%rdi
  or     %ecx,%eax
  xor    %ecx,%ecx
  test   %dl,%dl
  jne    L15
L47:
  shl    $0x8,%eax
  movzbl %cl,%ecx
  or     %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int read_dotted_ipv4_address(unsigned char *str) {
  unsigned int result = 0;
  unsigned char temp = 0;
  while (*str != '\0') {
    if (*str >= '0' && *str <= '9') {
      temp *= 10;
      temp += *str - '0';
    } else if (*str == '.') {
      result = (result << 8) | temp;
      temp = 0;
    }
    str++;
  }
  result = (result << 8) | temp;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_dotted_ipv4_address>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L32
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L43
  nopl   0x0(%rax)
L3:
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rsi,%rcx,2),%ecx
L37:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L54
L43:
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L3
  cmp    $0x2e,%dl
  jne    L37
  movzbl 0x1(%rdi),%edx
  movzbl %cl,%ecx
  shl    $0x8,%eax
  add    $0x1,%rdi
  or     %ecx,%eax
  xor    %ecx,%ecx
  test   %dl,%dl
  jne    L43
L54:
  shl    $0x8,%eax
  movzbl %cl,%ecx
  or     %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int read_dotted_ipv4_address(unsigned char *str) {
  unsigned int result = 0;
  unsigned char temp = 0;
  while (*str != '\0') {
    if (*str >= '0' && *str <= '9') {
      temp *= 10;
      temp += *str - '0';
    } else if (*str == '.') {
      result = (result << 8) | temp;
      temp = 0;
    }
    str++;
  }
  result = (result << 8) | temp;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<flip_sign_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movq   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movq   $0x1,0x8(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movq   $0x0,0x10(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movq   $0x0,0x8(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movq   $0x1,0x10(%rax)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movq   $0xffffffffffffffff,(%rdx,%rax,8)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flip_sign_row(long L[3][3], const int i) {
  L[0][0] = 1;
  L[0][1] = 0;
  L[0][2] = 0;
  L[1][0] = 0;
  L[1][1] = 1;
  L[1][2] = 0;
  L[2][0] = 0;
  L[2][1] = 0;
  L[2][2] = 1;
  L[i][i] = -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<flip_sign_row>:
  endbr64
  movq   $0x1,(%rdi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x1,0x20(%rdi)
  movq   $0x0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x1,0x40(%rdi)
  movslq %esi,%rsi
  shl    $0x5,%rsi
  movq   $0xffffffffffffffff,(%rsi,%rdi,1)
  ret
```

assistant: ```c
void flip_sign_row(long L[3][3], const int i) {
  L[0][0] = 1;
  L[0][1] = 0;
  L[0][2] = 0;
  L[1][0] = 0;
  L[1][1] = 1;
  L[1][2] = 0;
  L[2][0] = 0;
  L[2][1] = 0;
  L[2][2] = 1;
  L[i][i] = -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flip_sign_row>:
  endbr64
  movslq %esi,%rsi
  movq   $0x1,(%rdi)
  shl    $0x5,%rsi
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x1,0x20(%rdi)
  movq   $0x0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x1,0x40(%rdi)
  movq   $0xffffffffffffffff,(%rsi,%rdi,1)
  ret
```

assistant: ```c
void flip_sign_row(long L[3][3], const int i) {
  L[0][0] = 1;
  L[0][1] = 0;
  L[0][2] = 0;
  L[1][0] = 0;
  L[1][1] = 1;
  L[1][2] = 0;
  L[2][0] = 0;
  L[2][1] = 0;
  L[2][2] = 1;
  L[i][i] = -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flip_sign_row>:
  endbr64
  movdqa D4(%rip),%xmm1
  movslq %esi,%rsi
  pxor   %xmm0,%xmm0
  movq   $0x1,0x40(%rdi)
  shl    $0x5,%rsi
  movups %xmm0,0x10(%rdi)
  movups %xmm1,(%rdi)
  movups %xmm1,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movq   $0xffffffffffffffff,(%rsi,%rdi,1)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: byte[16]

tool: {"D4": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void flip_sign_row(long L[3][3], const int i) {
  L[0][0] = 1;
  L[0][1] = 0;
  L[0][2] = 0;
  L[1][0] = 0;
  L[1][1] = 1;
  L[1][2] = 0;
  L[2][0] = 0;
  L[2][1] = 0;
  L[2][2] = 1;
  L[i][i] = -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<key_mouse2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *key_mouse2str(double x) {
  static const char *a[] = {"off", "on"};
  return a[x < 0];
}
```
user: What is the c source code of the assembly code below:

```asm
<key_mouse2str>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  lea    D6(%rip),%rax
  mov    (%rax,%rdx,8),%rax
  ret
```

assistant: ```c
const char *key_mouse2str(double x) {
  static const char *a[] = {"off", "on"};
  return a[x < 0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<key_mouse2str>:
  endbr64
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  lea    D7(%rip),%rax
  comisd %xmm0,%xmm1
  seta   %dl
  mov    (%rax,%rdx,8),%rax
  ret
```

assistant: ```c
const char *key_mouse2str(double x) {
  static const char *a[] = {"off", "on"};
  return a[x < 0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<key_mouse2str>:
  endbr64
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  lea    D6(%rip),%rax
  comisd %xmm0,%xmm1
  seta   %dl
  mov    (%rax,%rdx,8),%rax
  ret
```

assistant: ```c
const char *key_mouse2str(double x) {
  static const char *a[] = {"off", "on"};
  return a[x < 0];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ngaValidatePackedOpcodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L26:
  mov    -0x10(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L10
  cmpl   $0x1a,-0x4(%rbp)
  jle    L23
L10:
  movl   $0x0,-0xc(%rbp)
L23:
  sarl   $0x8,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L24:
  cmpl   $0x3,-0x8(%rbp)
  jle    L26
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ngaValidatePackedOpcodes(int32_t opcode) {
  int32_t raw = opcode;
  int32_t current;
  int valid = -1;
  int i;
  for (i = 0; i < 4; i++) {
    current = raw & 0xFF;
    if (!(current >= 0 && current <= 26))
      valid = 0;
    raw = raw >> 8;
  }
  return valid;
}
```
user: What is the c source code of the assembly code below:

```asm
<ngaValidatePackedOpcodes>:
  endbr64
  mov    $0x4,%eax
  mov    $0xffffffff,%edx
  mov    $0x0,%ecx
L8:
  cmp    $0x1a,%dil
  cmova  %ecx,%edx
  sar    $0x8,%edi
  sub    $0x1,%eax
  jne    L8
  mov    %edx,%eax
  ret
```

assistant: ```c
int ngaValidatePackedOpcodes(int32_t opcode) {
  int32_t raw = opcode;
  int32_t current;
  int valid = -1;
  int i;
  for (i = 0; i < 4; i++) {
    current = raw & 0xFF;
    if (!(current >= 0 && current <= 26))
      valid = 0;
    raw = raw >> 8;
  }
  return valid;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ngaValidatePackedOpcodes>:
  endbr64
  mov    $0x4,%eax
  mov    $0xffffffff,%r8d
  xor    %ecx,%ecx
L2:
  movzbl %dil,%edx
  cmp    $0x1b,%edx
  cmovge %ecx,%r8d
  sar    $0x8,%edi
  sub    $0x1,%eax
  jne    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ngaValidatePackedOpcodes(int32_t opcode) {
  int32_t raw = opcode;
  int32_t current;
  int valid = -1;
  int i;
  for (i = 0; i < 4; i++) {
    current = raw & 0xFF;
    if (!(current >= 0 && current <= 26))
      valid = 0;
    raw = raw >> 8;
  }
  return valid;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ngaValidatePackedOpcodes>:
  endbr64
  movzbl %dil,%eax
  mov    %edi,%edx
  cmp    $0x1a,%eax
  movzbl %dh,%esi
  setle  %al
  xor    %ecx,%ecx
  movzbl %al,%eax
  neg    %eax
  cmp    $0x1b,%esi
  mov    %edi,%esi
  cmovge %ecx,%eax
  sar    $0x10,%esi
  movzbl %sil,%esi
  cmp    $0x1b,%esi
  cmovge %ecx,%eax
  cmp    $0x1affffff,%edi
  cmova  %ecx,%eax
  ret
```

assistant: ```c
int ngaValidatePackedOpcodes(int32_t opcode) {
  int32_t raw = opcode;
  int32_t current;
  int valid = -1;
  int i;
  for (i = 0; i < 4; i++) {
    current = raw & 0xFF;
    if (!(current >= 0 && current <= 26))
      valid = 0;
    raw = raw >> 8;
  }
  return valid;
}
```