user: 这段汇编代码用C语言表示是什么样的？

```asm
<_sample_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %r9d,-0x48(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L45
L11:
  mov    -0x48(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x20(%rbp)
L45:
  mov    -0x20(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L11
  mov    -0x44(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_normalize@plt>
  mov    -0x48(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x44(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_random_choice@plt>
  mov    %eax,(%rbx)
  mov    -0x48(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L52
L41:
  movl   $0x0,-0x20(%rbp)
  jmp    L37
L5:
  mov    -0x1c(%rbp),%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x20(%rbp)
L37:
  mov    -0x20(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L5
  mov    -0x44(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_normalize@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x44(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_random_choice@plt>
  mov    %eax,(%rbx)
  subl   $0x1,-0x1c(%rbp)
L52:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L41
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void _sample_path(int *path, const double *alpha, const double *A, const double *pobs, const int N, const int T) {
  int i, t;
  double *psel = (double *)malloc(N * sizeof(double));
  srand(time(NULL));
  for (i = 0; i < N; i++) {
    psel[i] = alpha[(T - 1) * N + i];
  }
  _normalize(psel, N);
  path[T - 1] = _random_choice(psel, N);
  for (t = T - 2; t >= 0; t--) {
    for (i = 0; i < N; i++) {
      psel[i] = alpha[t * N + i] * A[i * N + path[t + 1]];
    }
    _normalize(psel, N);
    path[t] = _random_choice(psel, N);
  }
}
```