ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mfm_subs_write>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,0x8(%rsp)
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  mov    %r14,%r13
  lea    D1(%rip),%r15
  jmp    L36
L39:
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  movslq 0x4(%rsp),%rax
  add    %rax,%rbp
  jmp    L4
L27:
  lea    -0x1(%rbx),%r12
  sub    %r13,%r12
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  add    %rbp,%r12
  movb   $0x25,(%r12)
  lea    0x2(%r12),%rbp
  movb   $0x66,0x1(%r12)
L4:
  lea    0x2(%rbx),%r13
L36:
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  cmp    %rbx,%r14
  je     L39
  cmpb   $0x25,-0x1(%rbx)
  je     L27
  mov    %rbx,%r12
  sub    %r13,%r12
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  add    %rbp,%r12
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  movslq 0x4(%rsp),%rbp
  add    %r12,%rbp
  jmp    L4
L2:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: %f

assistant: ```c
void mfm_subs_write(char *dest, char *orig, char *files) {
  int files_len = strlen(files);
  char *prev = orig;
  char *next;
  while (next = strstr(prev, "%f")) {
    if (next == orig) {
      strcpy(dest, files);
      dest += files_len;
    } else if (next[-1] == '%') {
      int delta = next - 1 - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      *dest++ = '%';
      *dest++ = 'f';
    } else {
      int delta = next - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      strcpy(dest, files);
      dest += files_len;
    }
    prev = next + 2;
  }
  strcpy(dest, prev);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mfm_subs_write>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  call   <strlen@plt>
  cltq
  mov    %rax,0x8(%rsp)
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rbx,%r12
  mov    %rbp,%rdi
  mov    %r15,%rsi
  sub    %r15,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  movslq %r12d,%rcx
  add    %rcx,%rbp
L49:
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  add    0x8(%rsp),%rbp
L1:
  lea    0x2(%rbx),%r15
L45:
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  cmp    %rbx,(%rsp)
  je     L49
  cmpb   $0x25,-0x1(%rbx)
  jne    L35
  lea    -0x1(%rbx),%rcx
  mov    %rbp,%rdi
  mov    %r15,%rsi
  sub    %r15,%rcx
  mov    %rcx,%r12
  mov    %ecx,%edx
  call   <memcpy@plt>
  movslq %r12d,%rcx
  mov    $0x6625,%eax
  add    %rbp,%rcx
  mov    %ax,(%rcx)
  lea    0x2(%rcx),%rbp
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x18,%rsp
  mov    %r15,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <strcpy@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: %f

assistant: ```c
void mfm_subs_write(char *dest, char *orig, char *files) {
  int files_len = strlen(files);
  char *prev = orig;
  char *next;
  while (next = strstr(prev, "%f")) {
    if (next == orig) {
      strcpy(dest, files);
      dest += files_len;
    } else if (next[-1] == '%') {
      int delta = next - 1 - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      *dest++ = '%';
      *dest++ = 'f';
    } else {
      int delta = next - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      strcpy(dest, files);
      dest += files_len;
    }
    prev = next + 2;
  }
  strcpy(dest, prev);
}
```
user: What is the c source code of the assembly code below:

```asm
<mfm_subs_write>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  call   <strlen@plt>
  cltq
  mov    %rax,0x8(%rsp)
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rbx,%r12
  mov    %rbp,%rdi
  mov    %r15,%rsi
  sub    %r15,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  movslq %r12d,%rcx
  add    %rcx,%rbp
L48:
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  add    0x8(%rsp),%rbp
L14:
  lea    0x2(%rbx),%r15
L4:
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L36
  cmp    %rbx,(%rsp)
  je     L48
  cmpb   $0x25,-0x1(%rbx)
  jne    L39
  lea    -0x1(%rbx),%rcx
  mov    %rbp,%rdi
  mov    %r15,%rsi
  sub    %r15,%rcx
  mov    %rcx,%r12
  mov    %ecx,%edx
  call   <memcpy@plt>
  movslq %r12d,%rcx
  mov    $0x6625,%eax
  add    %rbp,%rcx
  mov    %ax,(%rcx)
  lea    0x2(%rcx),%rbp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x18,%rsp
  mov    %r15,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <strcpy@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: %f

assistant: ```c
void mfm_subs_write(char *dest, char *orig, char *files) {
  int files_len = strlen(files);
  char *prev = orig;
  char *next;
  while (next = strstr(prev, "%f")) {
    if (next == orig) {
      strcpy(dest, files);
      dest += files_len;
    } else if (next[-1] == '%') {
      int delta = next - 1 - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      *dest++ = '%';
      *dest++ = 'f';
    } else {
      int delta = next - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      strcpy(dest, files);
      dest += files_len;
    }
    prev = next + 2;
  }
  strcpy(dest, prev);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <producer@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thread(void *arg) {
  (void)arg;
  producer();
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <producer@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *arg) {
  (void)arg;
  producer();
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <producer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *arg) {
  (void)arg;
  producer();
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <producer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *arg) {
  (void)arg;
  producer();
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<disp_perct_bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L29:
  mov    $0x23,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
L1:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L29
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L37
L3:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L37:
  cmpl   $0x63,-0x8(%rbp)
  jle    L3
  mov    $0x5d,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void disp_perct_bar(double perct) {
  int i, j;
  int barinc = 5;
  (void)putchar('[');
  for (i = 0; i < perct; i += barinc)
    (void)putchar('#');
  for (j = i; j < 100; j += barinc)
    (void)putchar(' ');
  (void)putchar(']');
}
```
user: Translate the below assembly code into C programming language:

```asm
<rd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L1
  movsd  -0x8(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L6
L1:
  movsd  -0x8(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
L6:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: f64

tool: D6: 0.5

assistant: ```c
int rd(dbl)
double dbl;
{
  if (dbl < 0.0) {
    return ((int)(dbl - 0.5));
  } else {
    return ((int)(dbl + 0.5));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rd>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L9
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
L9:
  subsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: f64

tool: D6: 0.5

assistant: ```c
int rd(dbl)
double dbl;
{
  if (dbl < 0.0) {
    return ((int)(dbl - 0.5));
  } else {
    return ((int)(dbl + 0.5));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rd>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L2
  addsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  subsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: f64

tool: D8: 0.5

assistant: ```c
int rd(dbl)
double dbl;
{
  if (dbl < 0.0) {
    return ((int)(dbl - 0.5));
  } else {
    return ((int)(dbl + 0.5));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rd>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L0
  addsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  subsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: f64

tool: D19: 0.5

assistant: ```c
int rd(dbl)
double dbl;
{
  if (dbl < 0.0) {
    return ((int)(dbl - 0.5));
  } else {
    return ((int)(dbl + 0.5));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<reshape>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %esi,%ecx
  mov    %edi,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <glViewport@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glLoadIdentity@plt>
  mov    %ebp,%esi
  pxor   %xmm1,%xmm1
  mov    %ebx,%edi
  movapd %xmm1,%xmm0
  call   <gluOrtho2D@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void reshape(int w, int h) {
  glViewport(0, 0, (GLsizei)w, (GLsizei)h);
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  gluOrtho2D(0.0, (GLdouble)w, 0.0, (GLdouble)h);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reshape>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %edi,%edx
  mov    %esi,%r12d
  push   %rbp
  xor    %esi,%esi
  mov    %edi,%ebp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <glViewport@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glLoadIdentity@plt>
  add    $0x8,%rsp
  pxor   %xmm1,%xmm1
  mov    %r12d,%esi
  mov    %ebp,%edi
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  jmp    10a0 <gluOrtho2D@plt>
```

assistant: ```c
void reshape(int w, int h) {
  glViewport(0, 0, (GLsizei)w, (GLsizei)h);
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  gluOrtho2D(0.0, (GLdouble)w, 0.0, (GLdouble)h);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reshape>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %edi,%edx
  mov    %esi,%r12d
  push   %rbp
  xor    %esi,%esi
  mov    %edi,%ebp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <glViewport@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glLoadIdentity@plt>
  add    $0x8,%rsp
  pxor   %xmm1,%xmm1
  mov    %r12d,%esi
  mov    %ebp,%edi
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  jmp    10a0 <gluOrtho2D@plt>
```

assistant: ```c
void reshape(int w, int h) {
  glViewport(0, 0, (GLsizei)w, (GLsizei)h);
  glMatrixMode(GL_PROJECTION);
  glLoadIdentity();
  gluOrtho2D(0.0, (GLdouble)w, 0.0, (GLdouble)h);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetSizeFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L27
  mov    $0xffffffff,%eax
  jmp    L23
L27:
  mov    -0x20(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L20
  mov    $0xffffffff,%eax
  jmp    L23
L20:
  mov    -0x18(%rbp),%rax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int GetSizeFile(char *filename) {
  struct stat buf;
  if (stat(filename, &buf) == -1) {
    return (-1);
  }
  if ((buf.st_mode & S_IFMT) == S_IFDIR)
    return -1;
  return (int)buf.st_size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GetSizeFile>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L37
  mov    D4(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  mov    D2(%rip),%rdx
  cmp    (%rdx),%eax
  je     L6
  mov    0x8(%rsp),%eax
L37:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x28,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L37
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetSizeFile(char *filename) {
  struct stat buf;
  if (stat(filename, &buf) == -1) {
    return (-1);
  }
  if ((buf.st_mode & S_IFMT) == S_IFDIR)
    return -1;
  return (int)buf.st_size;
}
```
user: What is the c source code of the assembly code below?

```asm
<GetSizeFile>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L32
  mov    D16(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  mov    D10(%rip),%rdx
  cmp    (%rdx),%eax
  je     L14
  mov    0x8(%rsp),%eax
L32:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x28,%rsp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L32
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetSizeFile(char *filename) {
  struct stat buf;
  if (stat(filename, &buf) == -1) {
    return (-1);
  }
  if ((buf.st_mode & S_IFMT) == S_IFDIR)
    return -1;
  return (int)buf.st_size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetSizeFile>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L4
  mov    D8(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  mov    D16(%rip),%rdx
  cmp    (%rdx),%eax
  je     L31
  mov    0x8(%rsp),%eax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L31:
  mov    $0xffffffff,%eax
  jmp    L4
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetSizeFile(char *filename) {
  struct stat buf;
  if (stat(filename, &buf) == -1) {
    return (-1);
  }
  if ((buf.st_mode & S_IFMT) == S_IFDIR)
    return -1;
  return (int)buf.st_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Command_Say_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <COM_Argc@plt>
  cmp    $0x1,%eax
  jg     L7
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <CONS_Printf@plt>
  jmp    L19
L7:
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <DoSayCommand@plt>
L19:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: say <message>: send a message


assistant: ```c
void Command_Say_f(void) {
  if (COM_Argc() < 2) {
    CONS_Printf(("say <message>: send a message\n"));
    return;
  }
  DoSayCommand(0, 1, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Command_Say_f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <COM_Argc@plt>
  cmp    $0x1,%eax
  jle    L14
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <DoSayCommand@plt>
L7:
  add    $0x8,%rsp
  ret
L14:
  lea    D4(%rip),%rdi
  call   <CONS_Printf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: say <message>: send a message


assistant: ```c
void Command_Say_f(void) {
  if (COM_Argc() < 2) {
    CONS_Printf(("say <message>: send a message\n"));
    return;
  }
  DoSayCommand(0, 1, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Command_Say_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <COM_Argc@plt>
  cmp    $0x1,%eax
  jle    L6
  xor    %edx,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <DoSayCommand@plt>
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <CONS_Printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: say <message>: send a message


assistant: ```c
void Command_Say_f(void) {
  if (COM_Argc() < 2) {
    CONS_Printf(("say <message>: send a message\n"));
    return;
  }
  DoSayCommand(0, 1, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Command_Say_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <COM_Argc@plt>
  cmp    $0x1,%eax
  jle    L0
  xor    %edx,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <DoSayCommand@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <CONS_Printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: say <message>: send a message


assistant: ```c
void Command_Say_f(void) {
  if (COM_Argc() < 2) {
    CONS_Printf(("say <message>: send a message\n"));
    return;
  }
  DoSayCommand(0, 1, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L35
  cmpq   $0x0,-0x20(%rbp)
  jne    L38
L35:
  mov    $0x0,%eax
  jmp    L3
L38:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  cmp    %rax,-0x18(%rbp)
  je     L51
  mov    $0x0,%eax
  jmp    L3
L51:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L40
  mov    $0x0,%eax
  jmp    L3
L40:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  if (nmemb == 0 || size == 0) {
    return NULL;
  }
  size_t required_size = nmemb * size;
  if (nmemb != required_size / size) {
    return NULL;
  }
  void *result = malloc(required_size);
  if (result == NULL) {
    return NULL;
  }
  memset(result, 0, required_size);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L5
  test   %rsi,%rsi
  je     L5
  mov    %rdi,%rbp
  imul   %rsi,%rbp
  mov    %rbp,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    $0x0,%ebx
  cmp    %rdi,%rax
  jne    L11
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L11
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L11:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x0,%ebx
  jmp    L11
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  if (nmemb == 0 || size == 0) {
    return NULL;
  }
  size_t required_size = nmemb * size;
  if (nmemb != required_size / size) {
    return NULL;
  }
  void *result = malloc(required_size);
  if (result == NULL) {
    return NULL;
  }
  memset(result, 0, required_size);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calloc>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  test   %rsi,%rsi
  je     L2
  mov    %rdi,%rax
  mul    %rsi
  mov    %rax,%r12
  jo     L2
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L3
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r13d,%r13d
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  if (nmemb == 0 || size == 0) {
    return NULL;
  }
  size_t required_size = nmemb * size;
  if (nmemb != required_size / size) {
    return NULL;
  }
  void *result = malloc(required_size);
  if (result == NULL) {
    return NULL;
  }
  memset(result, 0, required_size);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calloc>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L21
  test   %rsi,%rsi
  je     L21
  mov    %rdi,%rax
  mul    %rsi
  mov    %rax,%r12
  jo     L21
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L10
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L10:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %r13d,%r13d
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  if (nmemb == 0 || size == 0) {
    return NULL;
  }
  size_t required_size = nmemb * size;
  if (nmemb != required_size / size) {
    return NULL;
  }
  void *result = malloc(required_size);
  if (result == NULL) {
    return NULL;
  }
  memset(result, 0, required_size);
  return result;
}
```