ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rdi
  lea    D16(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L21
  je     L68
  nopl   0x0(%rax,%rax,1)
L61:
  movslq %eax,%rdx
  mov    %eax,%ecx
  mov    %rbx,%rdi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  jne    L61
L36:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  movslq %eax,%rsi
  cltd
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  mov    %eax,%esi
  add    %edx,%edx
  sub    %edx,%esi
  cmp    $0xfffffff7,%eax
  jge    L43
  neg    %esi
L43:
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  jne    L21
  jmp    L36
L68:
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L36
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string
name: disassemble_data
arguments: label: D46
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D44
datatype: string

tool: D5: 
Enter an integer > 

tool: D16: 
%d

tool: D46: %d

tool: D7: 
That's all, have a nice day!

tool: D44: 
0

assistant: ```c
int main() {
  int num, digit;
  printf("\nEnter an integer > ");
  scanf("%d", &num);
  if (num < 0) {
    while (num != 0) {
      digit = num % 10;
      if (num > (-10))
        printf("\n%d", digit);
      else
        printf("\n%d", -digit);
      num = num / 10;
    }
  } else if (num == 0) {
    printf("\n0");
  } else
    while (num != 0) {
      digit = num % 10;
      printf("\n%d", digit);
      num = num / 10;
    }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  lea    D21(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L33
  je     L37
  nopl   0x0(%rax,%rax,1)
L16:
  movslq %eax,%rdx
  mov    %eax,%ecx
  mov    %rbx,%rdi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  jne    L16
L46:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  movslq %eax,%rsi
  cltd
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  mov    %eax,%esi
  add    %edx,%edx
  sub    %edx,%esi
  cmp    $0xfffffff7,%eax
  jge    L23
  neg    %esi
L23:
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  jne    L33
  jmp    L46
L37:
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L46
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D48
data_type: string

tool: D12: 
Enter an integer > 

tool: D21: 
%d

tool: D11: %d

tool: D2: 
That's all, have a nice day!

tool: D48: 
0

assistant: ```c
int main() {
  int num, digit;
  printf("\nEnter an integer > ");
  scanf("%d", &num);
  if (num < 0) {
    while (num != 0) {
      digit = num % 10;
      if (num > (-10))
        printf("\n%d", digit);
      else
        printf("\n%d", -digit);
      num = num / 10;
    }
  } else if (num == 0) {
    printf("\n0");
  } else
    while (num != 0) {
      digit = num % 10;
      printf("\n%d", digit);
      num = num / 10;
    }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcpy1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L11:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strcpy1(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy1>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L7
  mov    $0x1,%eax
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
L7:
  ret
```

assistant: ```c
void strcpy1(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcpy1>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L3
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L0
L3:
  ret
```

assistant: ```c
void strcpy1(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy1>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L4
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L13
L4:
  ret
```

assistant: ```c
void strcpy1(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_pid_and_port_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D13: w

tool: D8: %d


assistant: ```c
void write_pid_and_port_literal(int portno, char *filename) {
  FILE *pfile;
  pfile = fopen(filename, "w");
  fprintf(pfile, "%d\n", portno);
  fclose(pfile);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_pid_and_port_literal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  lea    D16(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D11: w

tool: D16: %d


assistant: ```c
void write_pid_and_port_literal(int portno, char *filename) {
  FILE *pfile;
  pfile = fopen(filename, "w");
  fprintf(pfile, "%d\n", portno);
  fclose(pfile);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_pid_and_port_literal>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  lea    D3(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12d,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D3: w

tool: D4: %d


assistant: ```c
void write_pid_and_port_literal(int portno, char *filename) {
  FILE *pfile;
  pfile = fopen(filename, "w");
  fprintf(pfile, "%d\n", portno);
  fclose(pfile);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_pid_and_port_literal>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  lea    D15(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12d,%edx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D15: w

tool: D3: %d


assistant: ```c
void write_pid_and_port_literal(int portno, char *filename) {
  FILE *pfile;
  pfile = fopen(filename, "w");
  fprintf(pfile, "%d\n", portno);
  fclose(pfile);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nth_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L32
  mov    $0x2,%eax
  jmp    L11
L32:
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L49:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L9
  subl   $0x1,-0x14(%rbp)
L9:
  cmpl   $0x0,-0x14(%rbp)
  jg     L49
  mov    -0x4(%rbp),%eax
L11:
  leave
  ret
```

assistant: ```c
int nth_prime(int n) {
  if (n <= 1)
    return 2;
  int p = 1;
  while (n > 0) {
    p++;
    if (is_prime(p))
      n--;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nth_prime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L18
  mov    %edi,%ebx
  mov    $0x1,%ebp
L16:
  add    $0x1,%ebp
  mov    %ebp,%edi
  call   <is_prime@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%ebx
  test   %ebx,%ebx
  jg     L16
L23:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0x2,%ebp
  jmp    L23
```

assistant: ```c
int nth_prime(int n) {
  if (n <= 1)
    return 2;
  int p = 1;
  while (n > 0) {
    p++;
    if (is_prime(p))
      n--;
  }
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<nth_prime>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L7
  mov    %edi,%ebx
  mov    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%r12d
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L27
  sub    $0x1,%ebx
  jne    L27
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x2,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int nth_prime(int n) {
  if (n <= 1)
    return 2;
  int p = 1;
  while (n > 0) {
    p++;
    if (is_prime(p))
      n--;
  }
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nth_prime>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L13
  mov    %edi,%ebx
  mov    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12d
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L11
  sub    $0x1,%ebx
  jne    L11
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x2,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int nth_prime(int n) {
  if (n <= 1)
    return 2;
  int p = 1;
  while (n > 0) {
    p++;
    if (is_prime(p))
      n--;
  }
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<wd_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rcx
  lea    D4(%rip),%rdx
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: pidof %s

assistant: ```c
bool wd_check(const char *progname) {
  char command[1024];
  snprintf(command, 1024, "pidof %s", progname);
  return system(command) == 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wd_check>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D3(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: pidof %s

assistant: ```c
bool wd_check(const char *progname) {
  char command[1024];
  snprintf(command, 1024, "pidof %s", progname);
  return system(command) == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wd_check>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  lea    D8(%rip),%rdx
  mov    $0x400,%esi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x410,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: pidof %s

assistant: ```c
bool wd_check(const char *progname) {
  char command[1024];
  snprintf(command, 1024, "pidof %s", progname);
  return system(command) == 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wd_check>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  lea    D9(%rip),%rdx
  mov    $0x400,%esi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x410,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: pidof %s

assistant: ```c
bool wd_check(const char *progname) {
  char command[1024];
  snprintf(command, 1024, "pidof %s", progname);
  return system(command) == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<minKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L0
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L0:
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x1,-0x8(%rbp)
  jle    L7
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int minKey(int key[]) {
  int min_index, v, min;
  for (v = 0; v < 2; v++)
    if (key[v] < min)
      min = min_index = v;
  return min_index;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minKey>:
  endbr64
  cmpl   $0x0,0x4(%rdi)
  sets   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int minKey(int key[]) {
  int min_index, v, min;
  for (v = 0; v < 2; v++)
    if (key[v] < min)
      min = min_index = v;
  return min_index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minKey>:
  endbr64
  mov    0x4(%rdi),%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int minKey(int key[]) {
  int min_index, v, min;
  for (v = 0; v < 2; v++)
    if (key[v] < min)
      min = min_index = v;
  return min_index;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <put_s@plt>
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    %eax,-0x1a8(%rbp)
  movl   $0x0,-0x1ac(%rbp)
  jmp    L5
L65:
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    -0x1ac(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x1a0(%rbp,%rdx,4)
  addl   $0x1,-0x1ac(%rbp)
L5:
  mov    -0x1ac(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jl     L65
  movl   $0x0,-0x1ac(%rbp)
  jmp    L68
L19:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1a8(%rbp),%eax
  sub    -0x1ac(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a8(%rbp),%eax
  sub    -0x1ac(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a4(%rbp),%edx
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1ac(%rbp)
L68:
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L19
  movl   $0x0,-0x1ac(%rbp)
  jmp    L54
L13:
  mov    $0x23,%edi
  call   <put_c@plt>
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <put_i@plt>
  addl   $0x1,-0x1ac(%rbp)
L54:
  mov    -0x1ac(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jl     L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: n=

assistant: ```c
void main() {
  int i, n, t;
  int v[100];
  put_s("n=");
  n = get_i();
  for (i = 0; i < n; i = i + 1) {
    v[i] = get_i();
  }
  for (i = 0; i < n / 2; i = i + 1) {
    t = v[i];
    v[i] = v[n - i - 1];
    v[n - i - 1] = t;
  }
  for (i = 0; i < n; i = i + 1) {
    put_c('#');
    put_i(v[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <put_s@plt>
  mov    $0x0,%eax
  call   <get_i@plt>
  test   %eax,%eax
  jle    L47
  mov    %eax,%ebp
  mov    %rsp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x4(%rsp,%rax,4),%r12
L49:
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L49
  mov    %ebp,%r8d
  shr    $0x1f,%r8d
  add    %ebp,%r8d
  sar    %r8d
  cmp    $0x1,%ebp
  jle    L44
  mov    %rsp,%rax
  movslq %ebp,%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    $0x0,%ecx
L51:
  mov    (%rax),%esi
  mov    -0x4(%rdx),%edi
  mov    %edi,(%rax)
  mov    %esi,-0x4(%rdx)
  add    $0x1,%ecx
  add    $0x4,%rax
  sub    $0x4,%rdx
  cmp    %ecx,%r8d
  jg     L51
  test   %ebp,%ebp
  jle    L47
  mov    $0x0,%ebx
L9:
  mov    $0x23,%edi
  call   <put_c@plt>
  mov    (%rsp,%rbx,4),%edi
  call   <put_i@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L9
L47:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    $0x23,%edi
  call   <put_c@plt>
  mov    (%rsp),%edi
  call   <put_i@plt>
  jmp    L47
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: n=

assistant: ```c
void main() {
  int i, n, t;
  int v[100];
  put_s("n=");
  n = get_i();
  for (i = 0; i < n; i = i + 1) {
    v[i] = get_i();
  }
  for (i = 0; i < n / 2; i = i + 1) {
    t = v[i];
    v[i] = v[n - i - 1];
    v[n - i - 1] = t;
  }
  for (i = 0; i < n; i = i + 1) {
    put_c('#');
    put_i(v[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  call   <put_s@plt>
  xor    %eax,%eax
  call   <get_i@plt>
  test   %eax,%eax
  jle    L32
  mov    %eax,%ebp
  mov    %rsp,%r12
  lea    -0x1(%rax),%eax
  mov    %r12,%rbx
  lea    0x4(%rsp,%rax,4),%r13
  nop
L8:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <get_i@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbx
  jne    L8
  mov    %ebp,%r8d
  sar    %r8d
  cmp    $0x1,%ebp
  je     L38
  movslq %ebp,%rax
  mov    %r12,%rdx
  xor    %ecx,%ecx
  lea    (%r12,%rax,4),%rax
  nopw   0x0(%rax,%rax,1)
L36:
  mov    (%rdx),%esi
  mov    -0x4(%rax),%edi
  add    $0x1,%ecx
  add    $0x4,%rdx
  sub    $0x4,%rax
  mov    %edi,-0x4(%rdx)
  mov    %esi,(%rax)
  cmp    %ecx,%r8d
  jg     L36
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L0:
  mov    $0x23,%edi
  call   <put_c@plt>
  mov    (%r12,%rbx,4),%edi
  add    $0x1,%rbx
  call   <put_i@plt>
  cmp    %ebx,%ebp
  jg     L0
L32:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    $0x23,%edi
  call   <put_c@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    (%rsp),%edi
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <put_i@plt>
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: n=

assistant: ```c
void main() {
  int i, n, t;
  int v[100];
  put_s("n=");
  n = get_i();
  for (i = 0; i < n; i = i + 1) {
    v[i] = get_i();
  }
  for (i = 0; i < n / 2; i = i + 1) {
    t = v[i];
    v[i] = v[n - i - 1];
    v[n - i - 1] = t;
  }
  for (i = 0; i < n; i = i + 1) {
    put_c('#');
    put_i(v[i]);
  }
}
```