ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<seq_ctrl_set_mute_select>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <seq_ctrl_set_record_mode@plt>
  test   %ebx,%ebx
  setne  %r12b
  cmp    $0xffffffff,%ebp
  je     L17
  cmp    $0x5,%ebp
  ja     L21
  xor    %eax,%eax
  call   <seq_engine_get_current_scene@plt>
  pop    %rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  jmp    10a0 <song_set_mute@plt>
  nopl   (%rax)
L21:
  pop    %rbx
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <log_error@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <seq_engine_get_current_scene@plt>
  mov    %ebx,%esi
  mov    %r12d,%edx
  add    $0x1,%ebx
  mov    %eax,%edi
  call   <song_set_mute@plt>
  cmp    $0x6,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: scsms - track invalid: %d

assistant: ```c
void seq_ctrl_set_mute_select(int track, int mute) {
  int i, val;
  seq_ctrl_set_record_mode(0);
  if (mute) {
    val = 1;
  } else {
    val = 0;
  }
  if (track == -1) {
    for (i = 0; i < 6; i++) {
      song_set_mute(seq_engine_get_current_scene(), i, val);
    }
  } else {
    if (track < 0 || track >= 6) {
      log_error("scsms - track invalid: %d", track);
      return;
    }
    song_set_mute(seq_engine_get_current_scene(), track, val);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<converts_h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  addq   $0x2,-0x18(%rbp)
  jmp    L42
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L0
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L48
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  sub    $0x37,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L48:
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  sub    $0x57,%rax
  mov    %rax,-0x8(%rbp)
L32:
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long int converts_h(char *s) {
  unsigned long long int n;
  s += 2;
  while (*s) {
    if (*s <= '9')
      n = n * 16 + *s - '0';
    else if (*s <= 'F')
      n = n * 16 + *s - 'A' + 10;
    else
      n = n * 16 + *s - 'a' + 10;
    s++;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<converts_h>:
  endbr64
  lea    0x2(%rdi),%rcx
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  jne    L32
L30:
  ret
L29:
  cmp    $0x46,%dl
  jg     L55
  shl    $0x4,%rax
  movsbq %dl,%rdx
  lea    -0x37(%rax,%rdx,1),%rax
L41:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L30
L32:
  cmp    $0x39,%dl
  jg     L29
  shl    $0x4,%rax
  movsbq %dl,%rdx
  lea    -0x30(%rax,%rdx,1),%rax
  jmp    L41
L55:
  shl    $0x4,%rax
  movsbq %dl,%rdx
  lea    -0x57(%rax,%rdx,1),%rax
  jmp    L41
```

assistant: ```c
unsigned long long int converts_h(char *s) {
  unsigned long long int n;
  s += 2;
  while (*s) {
    if (*s <= '9')
      n = n * 16 + *s - '0';
    else if (*s <= 'F')
      n = n * 16 + *s - 'A' + 10;
    else
      n = n * 16 + *s - 'a' + 10;
    s++;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<converts_h>:
  endbr64
  movzbl 0x2(%rdi),%edx
  lea    0x2(%rdi),%rcx
  test   %dl,%dl
  jne    L11
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  sub    $0x30,%rax
  test   %dl,%dl
  je     L6
L11:
  shl    $0x4,%rax
  movsbq %dl,%rsi
  add    %rsi,%rax
  cmp    $0x39,%dl
  jle    L17
  lea    -0x37(%rax),%rsi
  sub    $0x57,%rax
  cmp    $0x46,%dl
  cmovle %rsi,%rax
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L11
L6:
  ret
```

assistant: ```c
unsigned long long int converts_h(char *s) {
  unsigned long long int n;
  s += 2;
  while (*s) {
    if (*s <= '9')
      n = n * 16 + *s - '0';
    else if (*s <= 'F')
      n = n * 16 + *s - 'A' + 10;
    else
      n = n * 16 + *s - 'a' + 10;
    s++;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<converts_h>:
  endbr64
  movzbl 0x2(%rdi),%edx
  lea    0x2(%rdi),%rcx
  test   %dl,%dl
  jne    L19
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  sub    $0x30,%rax
  test   %dl,%dl
  je     L7
L19:
  shl    $0x4,%rax
  movsbq %dl,%rsi
  add    %rsi,%rax
  cmp    $0x39,%dl
  jle    L44
  lea    -0x37(%rax),%rsi
  sub    $0x57,%rax
  cmp    $0x46,%dl
  cmovle %rsi,%rax
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L19
L7:
  ret
```

assistant: ```c
unsigned long long int converts_h(char *s) {
  unsigned long long int n;
  s += 2;
  while (*s) {
    if (*s <= '9')
      n = n * 16 + *s - '0';
    else if (*s <= 'F')
      n = n * 16 + *s - 'A' + 10;
    else
      n = n * 16 + *s - 'a' + 10;
    s++;
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x834(%rbp)
  movl   $0x0,-0x830(%rbp)
  jmp    L15
L34:
  movl   $0x7,-0x82c(%rbp)
  subl   $0x1,-0x834(%rbp)
L15:
  cmpl   $0x1,-0x834(%rbp)
  jg     L34
  movl   $0x5,-0x834(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L37
L45:
  movl   $0x7,-0x18(%rbp)
  subl   $0x1,-0x834(%rbp)
L37:
  cmpl   $0x1,-0x834(%rbp)
  jg     L45
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int main(void) {
  int arr[260];
  int n;
  n = 5;
  arr[0] = 0;
  while (n > 1) {
    arr[1] = 7;
    n--;
  }
  int arr2[260];
  n = 5;
  arr2[259] = 0;
  while (n > 1) {
    arr2[258] = 7;
    n--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int arr[260];
  int n;
  n = 5;
  arr[0] = 0;
  while (n > 1) {
    arr[1] = 7;
    n--;
  }
  int arr2[260];
  n = 5;
  arr2[259] = 0;
  while (n > 1) {
    arr2[258] = 7;
    n--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int arr[260];
  int n;
  n = 5;
  arr[0] = 0;
  while (n > 1) {
    arr[1] = 7;
    n--;
  }
  int arr2[260];
  n = 5;
  arr2[259] = 0;
  while (n > 1) {
    arr2[258] = 7;
    n--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int arr[260];
  int n;
  n = 5;
  arr[0] = 0;
  while (n > 1) {
    arr[1] = 7;
    n--;
  }
  int arr2[260];
  n = 5;
  arr2[259] = 0;
  while (n > 1) {
    arr2[258] = 7;
    n--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f9(int x, unsigned y) {
  int a = x - y;
  return x - a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f9>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int f9(int x, unsigned y) {
  int a = x - y;
  return x - a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f9>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int f9(int x, unsigned y) {
  int a = x - y;
  return x - a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f9>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int f9(int x, unsigned y) {
  int a = x - y;
  return x - a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Pascal2CamelbackX@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L22
L4:
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D19
type: string

tool: D0: AaaBbCccDdd

tool: D13: aaaBbCccDdd

tool: D6: Input is %s


tool: D19: result is %s 


assistant: ```c
int test24() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = (char *)malloc(strlen(camelback_test) * 2);
  memset(result, 0, strlen(camelback_test) * 2);
  Pascal2CamelbackX(camelback_test, &result);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test24>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rbx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edx
  mov    $0x0,%esi
  mov    (%rsp),%rdi
  call   <memset@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <Pascal2CamelbackX@plt>
  mov    (%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L23
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L26
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D39
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string

tool: D8: AaaBbCccDdd

tool: D14: Input is %s


tool: D39: result is %s 


tool: D21: aaaBbCccDdd

assistant: ```c
int test24() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = (char *)malloc(strlen(camelback_test) * 2);
  memset(result, 0, strlen(camelback_test) * 2);
  Pascal2CamelbackX(camelback_test, &result);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test24>:
  endbr64
  push   %rbp
  lea    D32(%rip),%rbp
  lea    D29(%rip),%rdi
  mov    %rbp,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  xor    %esi,%esi
  lea    (%rax,%rax,1),%edx
  call   <memset@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <Pascal2CamelbackX@plt>
  mov    (%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L13
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L29
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D32: AaaBbCccDdd

tool: D29: Input is %s


tool: D11: result is %s 


tool: D9: aaaBbCccDdd

assistant: ```c
int test24() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = (char *)malloc(strlen(camelback_test) * 2);
  memset(result, 0, strlen(camelback_test) * 2);
  Pascal2CamelbackX(camelback_test, &result);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test24>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  lea    D38(%rip),%rdi
  mov    %rbp,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  xor    %esi,%esi
  lea    (%rax,%rax,1),%edx
  call   <memset@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <Pascal2CamelbackX@plt>
  mov    (%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L1
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L29
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D38
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D35
type_guessed: string

tool: D8: AaaBbCccDdd

tool: D38: Input is %s


tool: D0: result is %s 


tool: D35: aaaBbCccDdd

assistant: ```c
int test24() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = (char *)malloc(strlen(camelback_test) * 2);
  memset(result, 0, strlen(camelback_test) * 2);
  Pascal2CamelbackX(camelback_test, &result);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<COM_GetExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L21:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L26
  cmpl   $0x0,-0x8(%rbp)
  jne    L6
L26:
  lea    D2(%rip),%rax
  jmp    L17
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L21
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  int length, i;
  length = strlen(name) - 1;
  i = length;
  while (name[i] != '.') {
    i--;
    if (name[i] == '/' || i == 0)
      return "";
  }
  return &name[i + 1];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<COM_GetExtension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
L13:
  cmpb   $0x2e,(%rbx,%rax,1)
  je     L27
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  sete   %dl
  cmp    $0x1,%eax
  sete   %cl
  sub    $0x1,%rax
  or     %cl,%dl
  je     L13
  lea    D9(%rip),%rax
L8:
  pop    %rbx
  ret
L27:
  lea    0x1(%rbx,%rax,1),%rax
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  int length, i;
  length = strlen(name) - 1;
  i = length;
  while (name[i] != '.') {
    i--;
    if (name[i] == '/' || i == 0)
      return "";
  }
  return &name[i + 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<COM_GetExtension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %rbx,%rdx
  movzbl (%rdx),%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  sub    $0x1,%eax
  je     L8
  cmp    $0x2f,%cl
  je     L8
L23:
  cmp    $0x2e,%cl
  jne    L7
  cltq
  lea    0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
L8:
  lea    D1(%rip),%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  int length, i;
  length = strlen(name) - 1;
  i = length;
  while (name[i] != '.') {
    i--;
    if (name[i] == '/' || i == 0)
      return "";
  }
  return &name[i + 1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<COM_GetExtension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L6:
  cmpb   $0x2e,(%rbx,%rax,1)
  je     L15
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  sete   %dl
  cmp    $0x1,%eax
  sete   %cl
  sub    $0x1,%rax
  or     %cl,%dl
  je     L6
  lea    D5(%rip),%rax
  pop    %rbx
  ret
  nopl   (%rax)
L15:
  lea    0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  int length, i;
  length = strlen(name) - 1;
  i = length;
  while (name[i] != '.') {
    i--;
    if (name[i] == '/' || i == 0)
      return "";
  }
  return &name[i + 1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L27
L43:
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L0:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L43
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D31
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D7: %d

tool: D31: %lld%d

tool: D15: Airborne wins.


tool: D0: Pagfloyd wins.


assistant: ```c
int main() {
  int t;
  long long int n;
  int x;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld%d", &n, &x);
    if (x == 0)
      printf("Airborne wins.\n");
    else
      printf("Pagfloyd wins.\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L31
  lea    0xc(%rsp),%rbp
  lea    D14(%rip),%rbx
  lea    D22(%rip),%r13
  lea    D15(%rip),%r12
  jmp    L48
L35:
  mov    %r13,%rdi
  call   <printf@plt>
L49:
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L31
L48:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jne    L35
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L49
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D1: %d

tool: D14: %lld%d

tool: D22: Pagfloyd wins.


tool: D15: Airborne wins.


assistant: ```c
int main() {
  int t;
  long long int n;
  int x;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld%d", &n, &x);
    if (x == 0)
      printf("Airborne wins.\n");
    else
      printf("Pagfloyd wins.\n");
  }
  return 0;
}
```