ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<atou>:
  endbr64
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L20
  mov    $0x0,%ecx
L21:
  lea    (%rcx,%rcx,4),%rdx
  movsbq %al,%rax
  lea    -0x30(%rax,%rdx,2),%rcx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L21
L13:
  test   %al,%al
  mov    $0xffffffffffffffff,%rax
  cmovne %rax,%rcx
  mov    %rcx,%rax
  ret
L20:
  mov    $0x0,%ecx
  jmp    L13
```

assistant: ```c
long atou(str)
char *str;
{
  long value;
  for (value = 0; (isdigit((*str))); ++str)
    value = value * 10 + *str - '0';
  return *str ? -1L : value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atou>:
  endbr64
  movsbq (%rdi),%rdx
  xor    %r8d,%r8d
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L13
  cs nopw 0x0(%rax,%rax,1)
L19:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8
  movsbq (%rdi),%rax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L19
L13:
  test   %al,%al
  mov    $0xffffffffffffffff,%rax
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long atou(str)
char *str;
{
  long value;
  for (value = 0; (isdigit((*str))); ++str)
    value = value * 10 + *str - '0';
  return *str ? -1L : value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atou>:
  endbr64
  movsbq (%rdi),%rdx
  xor    %r8d,%r8d
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L1
  cs nopw 0x0(%rax,%rax,1)
L14:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8
  movsbq (%rdi),%rax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L14
L1:
  test   %al,%al
  mov    $0xffffffffffffffff,%rax
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long atou(str)
char *str;
{
  long value;
  for (value = 0; (isdigit((*str))); ++str)
    value = value * 10 + *str - '0';
  return *str ? -1L : value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L4:
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void printRow(int a, char lineChar) {
  printf("\n");
  int i = 0;
  for (; i < a; i++) {
    printf("%c", lineChar);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printRow>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %r12d,%r12d
  jle    L1
  mov    $0x0,%ebx
  movsbl %bpl,%ebp
L4:
  mov    %ebp,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L4
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printRow(int a, char lineChar) {
  printf("\n");
  int i = 0;
  for (; i < a; i++) {
    printf("%c", lineChar);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printRow>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0xa,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movsbl %bpl,%ebp
  xor    %ebx,%ebx
  call   <putchar@plt>
  test   %r12d,%r12d
  jle    L13
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L3
L13:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
```

assistant: ```c
void printRow(int a, char lineChar) {
  printf("\n");
  int i = 0;
  for (; i < a; i++) {
    printf("%c", lineChar);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printRow>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0xa,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movsbl %bpl,%ebp
  xor    %ebx,%ebx
  call   <putchar@plt>
  test   %r12d,%r12d
  jle    L18
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L5
L18:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
```

assistant: ```c
void printRow(int a, char lineChar) {
  printf("\n");
  int i = 0;
  for (; i < a; i++) {
    printf("%c", lineChar);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<on_dict_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <display_name@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <append@plt>
  mov    $0x0,%eax
  call   <indent@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", display_name(code, name));
  indent();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<on_dict_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <display_name@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <append@plt>
  mov    $0x0,%eax
  call   <indent@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", display_name(code, name));
  indent();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<on_dict_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <display_name@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <append@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <indent@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", display_name(code, name));
  indent();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<on_dict_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <display_name@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <append@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <indent@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", display_name(code, name));
  indent();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L9
L7:
  movl   $0x0,-0x1c(%rbp)
  jmp    L17
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  addl   $0x1,-0x20(%rbp)
L9:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L7
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <display2d@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D4
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string

tool: D5: success

tool: D4: matrix %p


tool: D1: &matrix %p


tool: D29: matrix* %p

assistant: ```c
int main() {
  int rows = 2;
  int columns = 5;
  int *matrix = (int *)malloc(rows * columns * sizeof(int));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++) {
      *(matrix + (i * columns) + j) = i * j;
    }
  }
  printf("success\n");
  display2d(matrix, 2, 5);
  printf("matrix %p\n", matrix);
  printf("&matrix %p\n", &matrix);
  printf("matrix* %p", *matrix);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    $0x0,%eax
L26:
  mov    (%rsp),%rdx
  movl   $0x0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L26
  mov    $0x0,%edx
L14:
  mov    (%rsp),%rcx
  mov    %edx,(%rcx,%rax,1)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    $0x5,%edx
  jne    L14
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x5,%edx
  mov    $0x2,%esi
  mov    (%rsp),%rdi
  call   <display2d@plt>
  mov    (%rsp),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  mov    (%rax),%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string

tool: D4: success

tool: D17: matrix %p


tool: D14: &matrix %p


tool: D23: matrix* %p

assistant: ```c
int main() {
  int rows = 2;
  int columns = 5;
  int *matrix = (int *)malloc(rows * columns * sizeof(int));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++) {
      *(matrix + (i * columns) + j) = i * j;
    }
  }
  printf("success\n");
  display2d(matrix, 2, 5);
  printf("matrix %p\n", matrix);
  printf("&matrix %p\n", &matrix);
  printf("matrix* %p", *matrix);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x28,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    D9(%rip),%rdi
  movabs $0x200000001,%rcx
  movabs $0x400000003,%rdx
  mov    %rcx,0x18(%rax)
  mov    %rax,(%rsp)
  mov    %rdx,0x20(%rax)
  movq   $0x0,(%rax)
  movq   $0x0,0x8(%rax)
  movq   $0x0,0x10(%rax)
  call   <puts@plt>
  mov    (%rsp),%rdi
  mov    $0x5,%edx
  mov    $0x2,%esi
  call   <display2d@plt>
  mov    (%rsp),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    D6(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D38
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string

tool: D9: success

tool: D17: matrix %p


tool: D38: &matrix %p


tool: D6: matrix* %p

assistant: ```c
int main() {
  int rows = 2;
  int columns = 5;
  int *matrix = (int *)malloc(rows * columns * sizeof(int));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++) {
      *(matrix + (i * columns) + j) = i * j;
    }
  }
  printf("success\n");
  display2d(matrix, 2, 5);
  printf("matrix %p\n", matrix);
  printf("&matrix %p\n", &matrix);
  printf("matrix* %p", *matrix);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x28,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    D4(%rip),%rdx
  pxor   %xmm0,%xmm0
  lea    D30(%rip),%rdi
  mov    %rax,(%rsp)
  mov    %rdx,0x20(%rax)
  movups %xmm0,(%rax)
  movdqa D1(%rip),%xmm0
  movups %xmm0,0x10(%rax)
  call   <puts@plt>
  mov    (%rsp),%rdi
  mov    $0x5,%edx
  mov    $0x2,%esi
  call   <display2d@plt>
  mov    (%rsp),%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    D21(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D30
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D21
type_guessed: string

tool: {"D4": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D30: success

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D25: matrix %p


tool: D0: &matrix %p


tool: D21: matrix* %p

assistant: ```c
int main() {
  int rows = 2;
  int columns = 5;
  int *matrix = (int *)malloc(rows * columns * sizeof(int));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++) {
      *(matrix + (i * columns) + j) = i * j;
    }
  }
  printf("success\n");
  display2d(matrix, 2, 5);
  printf("matrix %p\n", matrix);
  printf("&matrix %p\n", &matrix);
  printf("matrix* %p", *matrix);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iselem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L15
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L37
  mov    $0x1,%eax
  jmp    L39
L37:
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int iselem(int c, char const *l) {
  for (; *l != '\0'; l++) {
    if (*l == c)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<iselem>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L22
L0:
  movsbl %al,%eax
  cmp    %edi,%eax
  je     L27
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
  ret
L22:
  mov    $0x0,%eax
  ret
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iselem(int c, char const *l) {
  for (; *l != '\0'; l++) {
    if (*l == c)
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iselem>:
  endbr64
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L8:
  cmp    %edi,%eax
  je     L13
  add    $0x1,%rsi
L1:
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L8
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iselem(int c, char const *l) {
  for (; *l != '\0'; l++) {
    if (*l == c)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<iselem>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L20:
  cmp    %edi,%eax
  je     L19
  add    $0x1,%rsi
L16:
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L20
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iselem(int c, char const *l) {
  for (; *l != '\0'; l++) {
    if (*l == c)
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <spawn@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: /usr/games/fortune

assistant: ```c
int main(int argc, char *argv[]) {
  char *args[] = {"/usr/games/fortune", NULL};
  return (spawn((sizeof(args) / sizeof((args)[0])) - 1, args));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edi
  call   <spawn@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: /usr/games/fortune

assistant: ```c
int main(int argc, char *argv[]) {
  char *args[] = {"/usr/games/fortune", NULL};
  return (spawn((sizeof(args) / sizeof((args)[0])) - 1, args));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D6(%rip),%rax
  mov    %rsp,%rsi
  movq   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <spawn@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: /usr/games/fortune

assistant: ```c
int main(int argc, char *argv[]) {
  char *args[] = {"/usr/games/fortune", NULL};
  return (spawn((sizeof(args) / sizeof((args)[0])) - 1, args));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D7(%rip),%rax
  mov    %rsp,%rsi
  movq   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <spawn@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: /usr/games/fortune

assistant: ```c
int main(int argc, char *argv[]) {
  char *args[] = {"/usr/games/fortune", NULL};
  return (spawn((sizeof(args) / sizeof((args)[0])) - 1, args));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func(char c, char *d) {
  *d = c + 1;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  add    $0x1,%edi
  mov    %dil,(%rsi)
  ret
```

assistant: ```c
void func(char c, char *d) {
  *d = c + 1;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func>:
  endbr64
  add    $0x1,%edi
  mov    %dil,(%rsi)
  ret
```

assistant: ```c
void func(char c, char *d) {
  *d = c + 1;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func>:
  endbr64
  add    $0x1,%edi
  mov    %dil,(%rsi)
  ret
```

assistant: ```c
void func(char c, char *d) {
  *d = c + 1;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%eax
  call   <luaL_resetbuffer@plt>
  jmp    L27
L29:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <luaL_check_number@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  cvttsd2si -0x8(%rbp),%eax
  movzbl %al,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L2
  ucomisd -0x8(%rbp),%xmm0
  je     L4
L2:
  mov    -0xc(%rbp),%eax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <luaL_argerror@plt>
L4:
  cvttsd2si -0x8(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <luaL_addchar@plt>
L27:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <lua_lua2C@plt>
  test   %rax,%rax
  jne    L29
  mov    $0x0,%eax
  call   <closeandpush@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: invalid value

assistant: ```c
void str_char(void) {
  int i = 0;
  luaL_resetbuffer();
  while (lua_lua2C(++i) != 0) {
    double c = luaL_check_number(i);
    if (!((unsigned char)c == c))
      luaL_argerror(i, "invalid value");
    luaL_addchar((unsigned char)c);
  }
  closeandpush();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <luaL_resetbuffer@plt>
  mov    $0x0,%ebp
  lea    D3(%rip),%r12
  jmp    L12
L8:
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <luaL_argerror@plt>
L38:
  mov    %ebx,%edi
  call   <luaL_addchar@plt>
L12:
  add    $0x1,%ebp
  mov    %ebp,%edi
  call   <lua_lua2C@plt>
  test   %rax,%rax
  je     L19
  mov    %ebp,%edi
  call   <luaL_check_number@plt>
  cvttsd2si %xmm0,%ebx
  movzbl %bl,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L8
  je     L38
  jmp    L8
L19:
  call   <closeandpush@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: invalid value

assistant: ```c
void str_char(void) {
  int i = 0;
  luaL_resetbuffer();
  while (lua_lua2C(++i) != 0) {
    double c = luaL_check_number(i);
    if (!((unsigned char)c == c))
      luaL_argerror(i, "invalid value");
    luaL_addchar((unsigned char)c);
  }
  closeandpush();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_char>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <luaL_resetbuffer@plt>
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%edi
  call   <luaL_addchar@plt>
L40:
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <lua_lua2C@plt>
  test   %rax,%rax
  je     L19
  mov    %ebx,%edi
  call   <luaL_check_number@plt>
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%ebp
  movzbl %bpl,%ebp
  cvtsi2sd %ebp,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L30
  je     L4
L30:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <luaL_argerror@plt>
  jmp    L4
  nopl   0x0(%rax)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10b0 <closeandpush@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: invalid value

assistant: ```c
void str_char(void) {
  int i = 0;
  luaL_resetbuffer();
  while (lua_lua2C(++i) != 0) {
    double c = luaL_check_number(i);
    if (!((unsigned char)c == c))
      luaL_argerror(i, "invalid value");
    luaL_addchar((unsigned char)c);
  }
  closeandpush();
}
```