ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<useXCBPoorly>:
  endbr64
  push   %r13
  push   %r12
  lea    0xfa0(%rdi),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rbx),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rcx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <xcb_intern_atom@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    %eax,%esi
  call   <xcb_intern_atom_reply@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L11
  call   <free@plt>
L11:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void useXCBPoorly(char **names, xcb_connection_t *connection) {
  xcb_atom_t atoms[500];
  for (int i = 0; i < 500; i++) {
    xcb_intern_atom_cookie_t cookie = xcb_intern_atom(connection, 0, strlen(names[i]), names[i]);
    xcb_intern_atom_reply_t *reply = xcb_intern_atom_reply(connection, cookie, NULL);
    if (reply) {
      atoms[i] = reply->atom;
      free(reply);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x202c73696854202d,%rax
  movabs $0x706d617320202061,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x202020202020656c,%rax
  movabs $0x2e676e6972747320,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x2e202e2e,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x38(%rbp)
  jmp    L18
L27:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x38(%rbp)
L18:
  cmpq   $0x0,-0x38(%rbp)
  jne    L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D38
data_type: string

tool: D8: Splitting string "%s" into tokens:


tool: D15:  ,.-

tool: D38: %s

assistant: ```c
main() {
  char str[] = "- This, a   sample       string... .";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok(str, " ,.-");
  while (pch != NULL) {
    printf("%s", pch);
    pch = strtok(NULL, " ,.-");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x202c73696854202d,%rax
  movabs $0x706d617320202061,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x202020202020656c,%rax
  movabs $0x2e676e6972747320,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0x2e202e2e,0x20(%rsp)
  movb   $0x0,0x24(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rsi
  lea    D24(%rip),%rbp
  lea    D18(%rip),%rbx
L1:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L1
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
datatype: string
name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string

tool: D20: Splitting string "%s" into tokens:


tool: D18:  ,.-

tool: D24: %s

assistant: ```c
main() {
  char str[] = "- This, a   sample       string... .";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok(str, " ,.-");
  while (pch != NULL) {
    printf("%s", pch);
    pch = strtok(NULL, " ,.-");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x38,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x2e202e2e,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D28(%rip),%xmm0
  mov    %rbp,%rsi
  movb   $0x0,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rsi
  lea    D43(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L22
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D37
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D4
type: byte[16]
name: unpack_data
arguments: data_label: D28
type: byte[16]
name: unpack_data
arguments: data_label: D43
type: string

tool: D37: Splitting string "%s" into tokens:


tool: D19:  ,.-

tool: {"D4": [0x2d,0x20,0x54,0x68,0x69,0x73,0x2c,0x20,0x61,0x20,0x20,0x20,0x73,0x61,0x6d,0x70]}

tool: {"D28": [0x6c,0x65,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x2e]}

tool: D43: %s

assistant: ```c
main() {
  char str[] = "- This, a   sample       string... .";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok(str, " ,.-");
  while (pch != NULL) {
    printf("%s", pch);
    pch = strtok(NULL, " ,.-");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rdi
  push   %rbx
  lea    D45(%rip),%rbx
  sub    $0x38,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x2e202e2e,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %rbp,%rsi
  movb   $0x0,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rsi
  lea    D41(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L20
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D44
type_infered: string
name: parse_data
arguments: tag: D45
type_infered: string
name: parse_data
arguments: tag: D14
type_infered: byte[16]
name: parse_data
arguments: tag: D5
type_infered: byte[16]
name: parse_data
arguments: tag: D41
type_infered: string

tool: D44: Splitting string "%s" into tokens:


tool: D45:  ,.-

tool: {"D14": [0x2d,0x20,0x54,0x68,0x69,0x73,0x2c,0x20,0x61,0x20,0x20,0x20,0x73,0x61,0x6d,0x70]}

tool: {"D5": [0x6c,0x65,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x2e]}

tool: D41: %s

assistant: ```c
main() {
  char str[] = "- This, a   sample       string... .";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok(str, " ,.-");
  while (pch != NULL) {
    printf("%s", pch);
    pch = strtok(NULL, " ,.-");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    $0x43,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: %-8c

assistant: ```c
void crit(int exitcode, char *s, ...) {
  printf("%-8c", 'C');
  va_list args;
  va_start(args, s);
  vprintf(s, args);
  va_end(args);
  printf("\n");
  exit(exitcode);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x43,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %-8c

assistant: ```c
void crit(int exitcode, char *s, ...) {
  printf("%-8c", 'C');
  va_list args;
  va_start(args, s);
  vprintf(s, args);
  va_end(args);
  printf("\n");
  exit(exitcode);
}
```
user: What is the c source code of the assembly code below?

```asm
<crit>:
  endbr64
  push   %r13
  xor    %eax,%eax
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    D1(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x43,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: %-8c

assistant: ```c
void crit(int exitcode, char *s, ...) {
  printf("%-8c", 'C');
  va_list args;
  va_start(args, s);
  vprintf(s, args);
  va_end(args);
  printf("\n");
  exit(exitcode);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crit>:
  endbr64
  push   %r13
  xor    %eax,%eax
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    D4(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x43,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %-8c

assistant: ```c
void crit(int exitcode, char *s, ...) {
  printf("%-8c", 'C');
  va_list args;
  va_start(args, s);
  vprintf(s, args);
  va_end(args);
  printf("\n");
  exit(exitcode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fermat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3e8,-0x4(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
L42:
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  imul   -0x8(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  jne    L58
  mov    $0x1,%eax
  jmp    L25
L58:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L17
  movl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L23
  movl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L14
  jmp    L42
L14:
  nop
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int fermat(void) {
  const int MAX = 1000;
  int a = 1, b = 1, c = 1;
  while (1) {
    if (((a * a * a) == ((b * b * b) + (c * c * c)))) {
      return 1;
    }
    a++;
    if (a > MAX) {
      a = 1;
      b++;
    }
    if (b > MAX) {
      b = 1;
      c++;
    }
    if (c > MAX) {
      break;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fermat>:
  endbr64
  mov    $0x1,%esi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  jmp    L56
L0:
  cmp    $0x3e8,%esi
  jg     L19
  mov    %eax,%edi
  imul   %eax,%edi
  imul   %eax,%edi
  mov    %ecx,%edx
  imul   %ecx,%edx
  imul   %ecx,%edx
  mov    %esi,%r8d
  imul   %esi,%r8d
  imul   %esi,%r8d
  add    %r8d,%edx
  cmp    %edx,%edi
  je     L31
L56:
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jle    L17
  add    $0x1,%ecx
  mov    $0x1,%eax
L17:
  cmp    $0x3e8,%ecx
  jle    L0
  add    $0x1,%esi
  mov    $0x1,%ecx
  jmp    L0
L19:
  mov    $0x0,%eax
  ret
L31:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fermat(void) {
  const int MAX = 1000;
  int a = 1, b = 1, c = 1;
  while (1) {
    if (((a * a * a) == ((b * b * b) + (c * c * c)))) {
      return 1;
    }
    a++;
    if (a > MAX) {
      a = 1;
      b++;
    }
    if (b > MAX) {
      b = 1;
      c++;
    }
    if (c > MAX) {
      break;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fermat>:
  endbr64
  mov    $0x1,%esi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%eax
  cmp    $0x3e9,%eax
  jne    L24
  add    $0x1,%ecx
  mov    $0x1,%eax
L24:
  cmp    $0x3e9,%ecx
  jne    L9
  add    $0x1,%esi
  mov    $0x1,%ecx
L9:
  cmp    $0x3e9,%esi
  je     L12
  mov    %ecx,%edx
  mov    %esi,%r8d
  mov    %eax,%edi
  imul   %ecx,%edx
  imul   %esi,%r8d
  imul   %eax,%edi
  imul   %ecx,%edx
  imul   %esi,%r8d
  imul   %eax,%edi
  add    %r8d,%edx
  cmp    %edx,%edi
  jne    L23
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int fermat(void) {
  const int MAX = 1000;
  int a = 1, b = 1, c = 1;
  while (1) {
    if (((a * a * a) == ((b * b * b) + (c * c * c)))) {
      return 1;
    }
    a++;
    if (a > MAX) {
      a = 1;
      b++;
    }
    if (b > MAX) {
      b = 1;
      c++;
    }
    if (c > MAX) {
      break;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fermat>:
  endbr64
  mov    $0x1,%esi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%eax
  cmp    $0x3e9,%eax
  jne    L37
  add    $0x1,%ecx
  mov    $0x1,%eax
L37:
  cmp    $0x3e9,%ecx
  jne    L26
  add    $0x1,%esi
  mov    $0x1,%ecx
L26:
  cmp    $0x3e9,%esi
  je     L22
  mov    %ecx,%edx
  mov    %esi,%r8d
  mov    %eax,%edi
  imul   %ecx,%edx
  imul   %esi,%r8d
  imul   %eax,%edi
  imul   %ecx,%edx
  imul   %esi,%r8d
  imul   %eax,%edi
  add    %r8d,%edx
  cmp    %edx,%edi
  jne    L38
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int fermat(void) {
  const int MAX = 1000;
  int a = 1, b = 1, c = 1;
  while (1) {
    if (((a * a * a) == ((b * b * b) + (c * c * c)))) {
      return 1;
    }
    a++;
    if (a > MAX) {
      a = 1;
      b++;
    }
    if (b > MAX) {
      b = 1;
      c++;
    }
    if (c > MAX) {
      break;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<update_qte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  mov    $0x0,%eax
  call   <readLine@plt>
  mov    %rax,-0x10(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  mov    $0x0,%eax
  call   <readLine@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <update_ingredients@plt>
  mov    $0x0,%eax
  call   <show_ingredients@plt>
  mov    $0x0,%eax
  call   <read_user@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D29
type: string
name: read_data
arguments: data_label: D22
type: string

tool: D12:     Quel ingredient voulez vous changer/ajouter ?
    > 

tool: D29:     Combien y a t'il de 

tool: D22:  dans votre frigo ?
    > 

assistant: ```c
void update_qte() {
  char *name, *s_qte;
  my_putstr("    Quel ingredient voulez vous changer/ajouter ?\n    > ");
  name = readLine();
  my_putstr("    Combien y a t'il de ");
  my_putstr(name);
  my_putstr(" dans votre frigo ?\n    > ");
  s_qte = readLine();
  update_ingredients(name, s_qte);
  show_ingredients();
  read_user();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<update_qte>:
  endbr64
  push   %rbx
  lea    D14(%rip),%rdi
  call   <my_putstr@plt>
  mov    $0x0,%eax
  call   <readLine@plt>
  mov    %rax,%rbx
  lea    D2(%rip),%rdi
  call   <my_putstr@plt>
  mov    %rbx,%rdi
  call   <my_putstr@plt>
  lea    D19(%rip),%rdi
  call   <my_putstr@plt>
  mov    $0x0,%eax
  call   <readLine@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <update_ingredients@plt>
  mov    $0x0,%eax
  call   <show_ingredients@plt>
  mov    $0x0,%eax
  call   <read_user@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D14:     Quel ingredient voulez vous changer/ajouter ?
    > 

tool: D2:     Combien y a t'il de 

tool: D19:  dans votre frigo ?
    > 

assistant: ```c
void update_qte() {
  char *name, *s_qte;
  my_putstr("    Quel ingredient voulez vous changer/ajouter ?\n    > ");
  name = readLine();
  my_putstr("    Combien y a t'il de ");
  my_putstr(name);
  my_putstr(" dans votre frigo ?\n    > ");
  s_qte = readLine();
  update_ingredients(name, s_qte);
  show_ingredients();
  read_user();
}
```
user: Translate the below assembly code into C programming language:

```asm
<update_qte>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  call   <my_putstr@plt>
  xor    %eax,%eax
  call   <readLine@plt>
  lea    D29(%rip),%rdi
  mov    %rax,%rbp
  call   <my_putstr@plt>
  mov    %rbp,%rdi
  call   <my_putstr@plt>
  lea    D1(%rip),%rdi
  call   <my_putstr@plt>
  xor    %eax,%eax
  call   <readLine@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <update_ingredients@plt>
  xor    %eax,%eax
  call   <show_ingredients@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10b0 <read_user@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D29
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: D13:     Quel ingredient voulez vous changer/ajouter ?
    > 

tool: D29:     Combien y a t'il de 

tool: D1:  dans votre frigo ?
    > 

assistant: ```c
void update_qte() {
  char *name, *s_qte;
  my_putstr("    Quel ingredient voulez vous changer/ajouter ?\n    > ");
  name = readLine();
  my_putstr("    Combien y a t'il de ");
  my_putstr(name);
  my_putstr(" dans votre frigo ?\n    > ");
  s_qte = readLine();
  update_ingredients(name, s_qte);
  show_ingredients();
  read_user();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<update_qte>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  call   <my_putstr@plt>
  xor    %eax,%eax
  call   <readLine@plt>
  lea    D26(%rip),%rdi
  mov    %rax,%rbp
  call   <my_putstr@plt>
  mov    %rbp,%rdi
  call   <my_putstr@plt>
  lea    D6(%rip),%rdi
  call   <my_putstr@plt>
  xor    %eax,%eax
  call   <readLine@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <update_ingredients@plt>
  xor    %eax,%eax
  call   <show_ingredients@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10b0 <read_user@plt>
```

tool_calls: name: read_data
arguments: tag: D15
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D6
data_type: string

tool: D15:     Quel ingredient voulez vous changer/ajouter ?
    > 

tool: D26:     Combien y a t'il de 

tool: D6:  dans votre frigo ?
    > 

assistant: ```c
void update_qte() {
  char *name, *s_qte;
  my_putstr("    Quel ingredient voulez vous changer/ajouter ?\n    > ");
  name = readLine();
  my_putstr("    Combien y a t'il de ");
  my_putstr(name);
  my_putstr(" dans votre frigo ?\n    > ");
  s_qte = readLine();
  update_ingredients(name, s_qte);
  show_ingredients();
  read_user();
}
```