ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__ccaprice_syscall_args_4>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r9
  mov    %rcx,%rdx
  mov    %rdi,%rax
  mov    %r9,%rcx
  mov    %r8,%rsi
  int    $0x80
  pop    %rbx
  ret
```

assistant: ```c
long __ccaprice_syscall_args_4(long A0, long A1, long A2, long A3, long A4) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3), "S"(A4) : "memory");
  return R;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__ccaprice_syscall_args_4>:
  endbr64
  mov    %rdx,%r10
  push   %rbx
  mov    %rcx,%rdx
  mov    %rsi,%rbx
  mov    %rdi,%rax
  mov    %r10,%rcx
  mov    %r8,%rsi
  int    $0x80
  pop    %rbx
  ret
```

assistant: ```c
long __ccaprice_syscall_args_4(long A0, long A1, long A2, long A3, long A4) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3), "S"(A4) : "memory");
  return R;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__ccaprice_syscall_args_4>:
  endbr64
  mov    %rdx,%r10
  push   %rbx
  mov    %rcx,%rdx
  mov    %rsi,%rbx
  mov    %rdi,%rax
  mov    %r10,%rcx
  mov    %r8,%rsi
  int    $0x80
  pop    %rbx
  ret
```

assistant: ```c
long __ccaprice_syscall_args_4(long A0, long A1, long A2, long A3, long A4) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3), "S"(A4) : "memory");
  return R;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_blank_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
L7:
  mov    $0x1,%eax
  jmp    L48
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_chr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L48
L18:
  mov    $0x0,%eax
L48:
  leave
  ret
```

assistant: ```c
short is_blank_(const char *s) {
  char *p;
  if (!s || !*s) {
    return 1;
  }
  p = str_chr(s);
  if (p == NULL) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_blank_>:
  endbr64
  test   %rdi,%rdi
  je     L1
  mov    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L19
  ret
L19:
  sub    $0x8,%rsp
  call   <str_chr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
short is_blank_(const char *s) {
  char *p;
  if (!s || !*s) {
    return 1;
  }
  p = str_chr(s);
  if (p == NULL) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_blank_>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L13
  cmpb   $0x0,(%rdi)
  jne    L18
  ret
  nopl   0x0(%rax)
L18:
  sub    $0x8,%rsp
  call   <str_chr@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nop
L13:
  ret
```

assistant: ```c
short is_blank_(const char *s) {
  char *p;
  if (!s || !*s) {
    return 1;
  }
  p = str_chr(s);
  if (p == NULL) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_blank_>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L13
  cmpb   $0x0,(%rdi)
  jne    L4
  ret
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  call   <str_chr@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nop
L13:
  ret
```

assistant: ```c
short is_blank_(const char *s) {
  char *p;
  if (!s || !*s) {
    return 1;
  }
  p = str_chr(s);
  if (p == NULL) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    -0x20(%rbp),%r12
  jmp    L9
L15:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L9:
  cmpq   $0x0,-0x28(%rbp)
  jne    L15
  mov    -0x18(%rbp),%rax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *s1, const void *s2, size_t n) {
  register unsigned char *r1 = s1;
  register const unsigned char *r2 = s2;
  while (n) {
    *r1++ = *r2++;
    --n;
  }
  return s1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L6
  mov    $0x0,%ecx
L5:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L5
L6:
  ret
```

assistant: ```c
void *memcpy(void *s1, const void *s2, size_t n) {
  register unsigned char *r1 = s1;
  register const unsigned char *r2 = s2;
  while (n) {
    *r1++ = *r2++;
    --n;
  }
  return s1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L13
  xor    %ecx,%ecx
  xchg   %ax,%ax
L19:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L19
L13:
  ret
```

assistant: ```c
void *memcpy(void *s1, const void *s2, size_t n) {
  register unsigned char *r1 = s1;
  register const unsigned char *r2 = s2;
  while (n) {
    *r1++ = *r2++;
    --n;
  }
  return s1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L130
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rax
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L36
  cmp    $0x6,%rax
  jbe    L36
  cmp    $0xe,%rax
  jbe    L143
  mov    %rdx,%rsi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rsi
  nopl   0x0(%rax,%rax,1)
L31:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L31
  mov    %rdx,%r9
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%r9
  and    $0xf,%eax
  lea    (%r8,%r9,1),%rsi
  lea    (%rcx,%r9,1),%rdi
  cmp    %r9,%rdx
  je     L130
  lea    -0x1(%rax),%r10
  mov    %rax,%rdx
  cmp    $0x6,%r10
  jbe    L159
L104:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%r8,%r9,1)
  mov    %rdx,%rcx
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rax
  add    %rcx,%rsi
  add    %rcx,%rdi
  cmp    %rcx,%rdx
  je     L130
  lea    -0x1(%rax),%r10
L159:
  movzbl (%rdi),%edx
  mov    %dl,(%rsi)
  test   %r10,%r10
  je     L130
  movzbl 0x1(%rdi),%edx
  mov    %dl,0x1(%rsi)
  cmp    $0x2,%rax
  je     L130
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x2(%rsi)
  cmp    $0x3,%rax
  je     L130
  movzbl 0x3(%rdi),%edx
  mov    %dl,0x3(%rsi)
  cmp    $0x4,%rax
  je     L130
  movzbl 0x4(%rdi),%edx
  mov    %dl,0x4(%rsi)
  cmp    $0x5,%rax
  je     L130
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x5(%rsi)
  cmp    $0x6,%rax
  je     L130
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%rsi)
L130:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L36:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L115:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L115
  mov    %r8,%rax
  ret
L143:
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    %rdx,%rax
  xor    %r9d,%r9d
  jmp    L104
```

assistant: ```c
void *memcpy(void *s1, const void *s2, size_t n) {
  register unsigned char *r1 = s1;
  register const unsigned char *r2 = s2;
  while (n) {
    *r1++ = *r2++;
    --n;
  }
  return s1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L10:
  mov    $0x0,%eax
  call   <Random@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x13,-0x4(%rbp)
  jle    L10
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: %6f


assistant: ```c
main() {
  int i;
  for (i = 0; i < 20; i++)
    printf("%6f\n", Random());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x14,%ebx
  lea    D0(%rip),%rbp
L6:
  mov    $0x0,%eax
  call   <Random@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: %6f


assistant: ```c
main() {
  int i;
  for (i = 0; i < 20; i++)
    printf("%6f\n", Random());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <Random@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: %6f


assistant: ```c
main() {
  int i;
  for (i = 0; i < 20; i++)
    printf("%6f\n", Random());
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <Random@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: %6f


assistant: ```c
main() {
  int i;
  for (i = 0; i < 20; i++)
    printf("%6f\n", Random());
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  imul   %eax,%esi
  lea    -0x4(,%rax,4),%eax
  sub    %eax,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L48
  mov    $0x0,%ebp
  jmp    L124
L127:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L168
L88:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L168
L32:
  mov    $0x2a,%edi
  call   <putchar@plt>
L168:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  lea    (%rax,%rdx,1),%ecx
  cmp    %ebx,%ecx
  jle    L166
L45:
  test   %ebp,%ebp
  jne    L19
  lea    -0x2(%rax,%rax,1),%eax
  sar    %eax
  cmp    %ebx,%eax
  je     L127
L19:
  cmp    %ebp,%edx
  je     L88
  cmp    %ebx,%r13d
  je     L32
  cmp    %ebx,%r12d
  je     L32
  cmp    %ebx,%r13d
  jge    L14
  cmp    %ebx,%r12d
  jg     L2
L14:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L168
L2:
  mov    $0x23,%edi
  call   <putchar@plt>
  jmp    L168
L166:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jle    L48
L124:
  lea    -0x1(%rax,%rax,1),%ecx
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  lea    (%rax,%rdx,1),%esi
  test   %esi,%esi
  jle    L166
  mov    %ecx,%r12d
  shr    $0x1f,%r12d
  add    %ecx,%r12d
  sar    %r12d
  lea    0x1(%rbp,%rbp,1),%esi
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  neg    %ecx
  lea    (%rcx,%r12,1),%r13d
  sub    %ecx,%r12d
  mov    $0x0,%ebx
  jmp    L45
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string
name: read_data
arguments: tag: D6
datatype: string

tool: D5: %d

tool: D6: 
%d


assistant: ```c
int main() {
  int j;
  int i;
  int height;
  int number = 0;
  scanf("%d", &height);
  number = (height * height) - (height + (height - 1) + (height - 2) * 2 + 1);
  printf("\n%d\n", number);
  for (i = 0; i < height; i++) {
    int all_symbols = height + (height - 1);
    for (j = 0; j < height + (height - 1); j++) {
      int symbols = (i * 2) + 1;
      if (i == 0 && j == (height + (height - 2)) / 2) {
        printf("*");
      } else if (i == height - 1) {
        printf("*");
      } else if (j == all_symbols / 2 - symbols / 2 || j == all_symbols / 2 + symbols / 2) {
        printf("*");
      } else if (j > all_symbols / 2 - symbols / 2 && j < all_symbols / 2 + symbols / 2) {
        printf("#");
      } else {
        printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  lea    -0x4(,%rax,4),%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L23
  nopl   (%rax)
L121:
  lea    0x1(%rbp,%rbp,1),%esi
  lea    -0x1(%rax),%edx
  xor    %ebx,%ebx
  mov    %esi,%ecx
  lea    (%rdx,%rax,1),%r12d
  shr    $0x1f,%ecx
  sar    %r12d
  add    %esi,%ecx
  sar    %ecx
  neg    %ecx
  lea    (%rcx,%r12,1),%r13d
  sub    %ecx,%r12d
  jmp    L2
  nopl   0x0(%rax)
L124:
  jle    L61
  cmp    %ebx,%r13d
  jl     L48
L61:
  mov    $0x20,%edi
  call   <putchar@plt>
L88:
  mov    0x4(%rsp),%eax
  add    $0x1,%ebx
  lea    -0x1(%rax),%edx
  lea    (%rax,%rdx,1),%ecx
  cmp    %ebx,%ecx
  jle    L81
L2:
  test   %ebp,%ebp
  jne    L103
  lea    -0x2(%rax,%rax,1),%eax
  sar    %eax
  cmp    %ebx,%eax
  je     L65
L103:
  cmp    %edx,%ebp
  je     L65
  cmp    %ebx,%r13d
  je     L65
  cmp    %ebx,%r12d
  jne    L124
L65:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jg     L121
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    $0x23,%edi
  call   <putchar@plt>
  jmp    L88
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D13
type: string

tool: D0: %d

tool: D13: 
%d


assistant: ```c
int main() {
  int j;
  int i;
  int height;
  int number = 0;
  scanf("%d", &height);
  number = (height * height) - (height + (height - 1) + (height - 2) * 2 + 1);
  printf("\n%d\n", number);
  for (i = 0; i < height; i++) {
    int all_symbols = height + (height - 1);
    for (j = 0; j < height + (height - 1); j++) {
      int symbols = (i * 2) + 1;
      if (i == 0 && j == (height + (height - 2)) / 2) {
        printf("*");
      } else if (i == height - 1) {
        printf("*");
      } else if (j == all_symbols / 2 - symbols / 2 || j == all_symbols / 2 + symbols / 2) {
        printf("*");
      } else if (j > all_symbols / 2 - symbols / 2 && j < all_symbols / 2 + symbols / 2) {
        printf("#");
      } else {
        printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x4a49,-0xa(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0x15,-0x28(%rbp)
  movl   $0x1f,-0x24(%rbp)
  movl   $0x29,-0x20(%rbp)
  movw   $0x3,-0x3e(%rbp)
  movw   $0x5,-0x3c(%rbp)
  movw   $0x7,-0x3a(%rbp)
  movw   $0x9,-0x38(%rbp)
  movw   $0xd,-0x36(%rbp)
  movw   $0xf,-0x34(%rbp)
  movw   $0x11,-0x32(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  movw   $0x3,(%rax)
  mov    -0x58(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x2,-0x58(%rbp)
  lea    D40(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rdx
  lea    -0x3e(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x7,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  movb   $0x0,-0x12(%rbp)
  movl   $0x0,-0x30(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x50(%rbp)
  movl   $0x0,-0x64(%rbp)
  jmp    L11
L6:
  mov    -0x64(%rbp),%eax
  cltq
  movzwl -0x3e(%rbp,%rax,2),%eax
  movzwl %ax,%edx
  mov    -0x64(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L11:
  mov    -0x64(%rbp),%eax
  cmp    $0x6,%eax
  jbe    L6
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D54
type_guessed: string
name: parse_data
arguments: tag: D40
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D29
type_guessed: string

tool: D54: pzz = %d


tool: D40: wb

tool: D2: test.bin

tool: D6: rb

tool: D29: z[%d] = %d


assistant: ```c
int main(void) {
  FILE *file;
  size_t ret;
  int i;
  char x[10] = "ABCDEFGHIJ";
  unsigned y[5] = {1, 11, 21, 31, 41};
  unsigned short z[7] = {3, 5, 7, 9, 13, 15, 17};
  unsigned short *zz, *pzz;
  zz = malloc(sizeof(unsigned short) * 2);
  pzz = zz;
  *pzz = 3;
  printf("pzz = %d\n", *pzz);
  pzz++;
  file = fopen("test.bin", "wb");
  ret = fwrite(z, sizeof(z[0]), sizeof(z) / sizeof(z[0]), file);
  fclose(file);
  *x = 0;
  *y = 0;
  file = fopen("test.bin", "rb");
  for (i = 0; i < sizeof(z) / sizeof(z[0]); i++)
    printf("z[%d] = %d\n", i, z[i]);
  fclose(file);
  free(zz);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x3,0xa(%rsp)
  movw   $0x5,0xc(%rsp)
  movw   $0x7,0xe(%rsp)
  movw   $0x9,0x10(%rsp)
  movw   $0xd,0x12(%rsp)
  movw   $0xf,0x14(%rsp)
  movw   $0x11,0x16(%rsp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movw   $0x3,(%rax)
  mov    $0x3,%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D45(%rip),%rsi
  lea    D22(%rip),%rbp
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    0xa(%rsp),%rdi
  mov    %rax,%rcx
  mov    $0x7,%edx
  mov    $0x2,%esi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
  lea    D44(%rip),%rbp
L14:
  movzwl 0xa(%rsp,%rbx,2),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x7,%rbx
  jne    L14
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D32
type_infered: string
name: parse_data
arguments: label: D45
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D44
type_infered: string

tool: D32: pzz = %d


tool: D45: wb

tool: D22: test.bin

tool: D13: rb

tool: D44: z[%d] = %d


assistant: ```c
int main(void) {
  FILE *file;
  size_t ret;
  int i;
  char x[10] = "ABCDEFGHIJ";
  unsigned y[5] = {1, 11, 21, 31, 41};
  unsigned short z[7] = {3, 5, 7, 9, 13, 15, 17};
  unsigned short *zz, *pzz;
  zz = malloc(sizeof(unsigned short) * 2);
  pzz = zz;
  *pzz = 3;
  printf("pzz = %d\n", *pzz);
  pzz++;
  file = fopen("test.bin", "wb");
  ret = fwrite(z, sizeof(z[0]), sizeof(z) / sizeof(z[0]), file);
  fclose(file);
  *x = 0;
  *y = 0;
  file = fopen("test.bin", "rb");
  for (i = 0; i < sizeof(z) / sizeof(z[0]); i++)
    printf("z[%d] = %d\n", i, z[i]);
  fclose(file);
  free(zz);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x4,%edi
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x9000700050003,%rax
  movl   $0xf000d,0x12(%rsp)
  lea    0xa(%rsp),%rbp
  mov    %rax,0xa(%rsp)
  mov    $0x11,%eax
  mov    %ax,0x16(%rsp)
  call   <malloc@plt>
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D5(%rip),%rdi
  mov    %dx,(%rax)
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    $0x7,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %r12,%rdi
  lea    D47(%rip),%r12
  call   <fclose@plt>
  mov    %r14,%rdi
  lea    D49(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r14
  nopl   (%rax)
L4:
  movzwl 0x0(%rbp,%rbx,2),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L4
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D47
data_type: string
name: extract_symbolic_data
arguments: tag: D49
data_type: string

tool: D21: test.bin

tool: D5: pzz = %d


tool: D0: wb

tool: D47: z[%d] = %d


tool: D49: rb

assistant: ```c
int main(void) {
  FILE *file;
  size_t ret;
  int i;
  char x[10] = "ABCDEFGHIJ";
  unsigned y[5] = {1, 11, 21, 31, 41};
  unsigned short z[7] = {3, 5, 7, 9, 13, 15, 17};
  unsigned short *zz, *pzz;
  zz = malloc(sizeof(unsigned short) * 2);
  pzz = zz;
  *pzz = 3;
  printf("pzz = %d\n", *pzz);
  pzz++;
  file = fopen("test.bin", "wb");
  ret = fwrite(z, sizeof(z[0]), sizeof(z) / sizeof(z[0]), file);
  fclose(file);
  *x = 0;
  *y = 0;
  file = fopen("test.bin", "rb");
  for (i = 0; i < sizeof(z) / sizeof(z[0]); i++)
    printf("z[%d] = %d\n", i, z[i]);
  fclose(file);
  free(zz);
  return 0;
}
```