ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x19,%ebp
  mov    $0x14,%r12d
  mov    $0x1d,%r13d
L14:
  mov    %r12d,%edi
  call   <print_int@plt>
  add    $0x1,%r12d
  mov    %ebp,%ebx
L5:
  mov    %ebx,%edi
  call   <print_int@plt>
  add    $0x1,%ebx
  cmp    $0x1d,%ebx
  jle    L5
  mov    %r13d,%eax
  sub    %ebp,%eax
  cmp    $0x1d,%ebp
  mov    $0x0,%edx
  cmovg  %edx,%eax
  lea    0x1(%rbp,%rax,1),%ebp
  cmp    $0x19,%r12d
  jne    L14
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int l = 20;
  int m = 25;
  do {
    print_int(l);
    l++;
    do {
      print_int(m);
      m++;
    } while (m < 30);
  } while (l < 25);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1d,%r13d
  push   %r12
  mov    $0x14,%r12d
  push   %rbp
  mov    $0x19,%ebp
  push   %rbx
  sub    $0x8,%rsp
L4:
  mov    %r12d,%edi
  mov    %ebp,%ebx
  add    $0x1,%r12d
  call   <print_int@plt>
  nopl   (%rax)
L3:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <print_int@plt>
  cmp    $0x1d,%ebx
  jle    L3
  mov    %r13d,%eax
  xor    %edx,%edx
  sub    %ebp,%eax
  cmp    $0x1d,%ebp
  cmovg  %edx,%eax
  lea    0x1(%rbp,%rax,1),%ebp
  cmp    $0x19,%r12d
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int l = 20;
  int m = 25;
  do {
    print_int(l);
    l++;
    do {
      print_int(m);
      m++;
    } while (m < 30);
  } while (l < 25);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1d,%r13d
  push   %r12
  mov    $0x14,%r12d
  push   %rbp
  mov    $0x19,%ebp
  push   %rbx
  sub    $0x8,%rsp
L12:
  mov    %r12d,%edi
  mov    %ebp,%ebx
  add    $0x1,%r12d
  call   <print_int@plt>
  nopl   (%rax)
L17:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <print_int@plt>
  cmp    $0x1d,%ebx
  jle    L17
  mov    %r13d,%eax
  xor    %edx,%edx
  sub    %ebp,%eax
  cmp    $0x1d,%ebp
  cmovg  %edx,%eax
  lea    0x1(%rbp,%rax,1),%ebp
  cmp    $0x19,%r12d
  jne    L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int l = 20;
  int m = 25;
  do {
    print_int(l);
    l++;
    do {
      print_int(m);
      m++;
    } while (m < 30);
  } while (l < 25);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nanotest_putstrnl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <nanotest_putstr@plt>
  mov    $0x0,%eax
  call   <nanotest_putnl@plt>
  nop
  leave
  ret
```

assistant: ```c
void nanotest_putstrnl(char const *str) {
  nanotest_putstr(str);
  nanotest_putnl();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nanotest_putstrnl>:
  endbr64
  sub    $0x8,%rsp
  call   <nanotest_putstr@plt>
  mov    $0x0,%eax
  call   <nanotest_putnl@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nanotest_putstrnl(char const *str) {
  nanotest_putstr(str);
  nanotest_putnl();
}
```
user: What is the c source code of the assembly code below:

```asm
<nanotest_putstrnl>:
  endbr64
  sub    $0x8,%rsp
  call   <nanotest_putstr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <nanotest_putnl@plt>
```

assistant: ```c
void nanotest_putstrnl(char const *str) {
  nanotest_putstr(str);
  nanotest_putnl();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nanotest_putstrnl>:
  endbr64
  sub    $0x8,%rsp
  call   <nanotest_putstr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <nanotest_putnl@plt>
```

assistant: ```c
void nanotest_putstrnl(char const *str) {
  nanotest_putstr(str);
  nanotest_putnl();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D70(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%edi
  call   <__set_errno@plt>
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <getpriority@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L58
  mov    D70(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L23
  mov    $0xffffffff,%eax
  jmp    L28
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
L58:
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setpriority@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L50
  mov    D70(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L17
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D70(%rip),%rax
  mov    %edx,(%rax)
L17:
  mov    $0xffffffff,%eax
  jmp    L28
L50:
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <getpriority@plt>
L28:
  leave
  ret
```

assistant: ```c
int nice(int incr) {
  int save;
  int prio;
  int result;
  save = errno;
  __set_errno(0);
  prio = getpriority(PRIO_PROCESS, 0);
  if (prio == -1) {
    if (errno != 0)
      return -1;
    else
      __set_errno(save);
  }
  result = setpriority(PRIO_PROCESS, 0, prio + incr);
  if (result == -1) {
    if (errno == EACCES)
      errno = EPERM;
    return -1;
  }
  return getpriority(PRIO_PROCESS, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nice>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    D72(%rip),%rax
  mov    (%rax),%r12d
  mov    $0x0,%edi
  call   <__set_errno@plt>
  mov    $0x0,%esi
  mov    D54(%rip),%rax
  mov    (%rax),%edi
  call   <getpriority@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L16
  mov    D72(%rip),%rax
  cmpl   $0x0,(%rax)
  jne    L29
  mov    %r12d,%edi
  call   <__set_errno@plt>
L16:
  lea    (%rbx,%rbp,1),%edx
  mov    $0x0,%esi
  mov    D54(%rip),%rax
  mov    (%rax),%edi
  call   <setpriority@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L43
  mov    $0x0,%esi
  mov    D54(%rip),%rax
  mov    (%rax),%edi
  call   <getpriority@plt>
  mov    %eax,%ebx
L29:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    D72(%rip),%rdx
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  jne    L29
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D72(%rip),%rax
  mov    %edx,(%rax)
  jmp    L29
```

assistant: ```c
int nice(int incr) {
  int save;
  int prio;
  int result;
  save = errno;
  __set_errno(0);
  prio = getpriority(PRIO_PROCESS, 0);
  if (prio == -1) {
    if (errno != 0)
      return -1;
    else
      __set_errno(save);
  }
  result = setpriority(PRIO_PROCESS, 0, prio + incr);
  if (result == -1) {
    if (errno == EACCES)
      errno = EPERM;
    return -1;
  }
  return getpriority(PRIO_PROCESS, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nice>:
  endbr64
  push   %r14
  push   %r13
  mov    D8(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    0x0(%r13),%r14d
  call   <__set_errno@plt>
  mov    D17(%rip),%r12
  xor    %esi,%esi
  mov    (%r12),%edi
  call   <getpriority@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L11
  mov    0x0(%r13),%eax
  test   %eax,%eax
  jne    L38
  mov    %r14d,%edi
  call   <__set_errno@plt>
L11:
  mov    (%r12),%edi
  xor    %esi,%esi
  lea    (%rbx,%rbp,1),%edx
  call   <setpriority@plt>
  cmp    $0xffffffff,%eax
  je     L13
  mov    (%r12),%edi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <getpriority@plt>
  nop
L13:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,0x0(%r13)
  jne    L38
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x0(%r13)
L38:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int nice(int incr) {
  int save;
  int prio;
  int result;
  save = errno;
  __set_errno(0);
  prio = getpriority(PRIO_PROCESS, 0);
  if (prio == -1) {
    if (errno != 0)
      return -1;
    else
      __set_errno(save);
  }
  result = setpriority(PRIO_PROCESS, 0, prio + incr);
  if (result == -1) {
    if (errno == EACCES)
      errno = EPERM;
    return -1;
  }
  return getpriority(PRIO_PROCESS, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nice>:
  endbr64
  push   %r14
  push   %r13
  mov    D17(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    0x0(%r13),%r14d
  call   <__set_errno@plt>
  mov    D4(%rip),%r12
  xor    %esi,%esi
  mov    (%r12),%edi
  call   <getpriority@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L21
  mov    0x0(%r13),%eax
  test   %eax,%eax
  jne    L10
  mov    %r14d,%edi
  call   <__set_errno@plt>
L21:
  mov    (%r12),%edi
  xor    %esi,%esi
  lea    (%rbx,%rbp,1),%edx
  call   <setpriority@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    (%r12),%edi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <getpriority@plt>
  nop
L1:
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,0x0(%r13)
  jne    L10
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x0(%r13)
L10:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int nice(int incr) {
  int save;
  int prio;
  int result;
  save = errno;
  __set_errno(0);
  prio = getpriority(PRIO_PROCESS, 0);
  if (prio == -1) {
    if (errno != 0)
      return -1;
    else
      __set_errno(save);
  }
  result = setpriority(PRIO_PROCESS, 0, prio + incr);
  if (result == -1) {
    if (errno == EACCES)
      errno = EPERM;
    return -1;
  }
  return getpriority(PRIO_PROCESS, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_memccpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L32
L38:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L17
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L27
L17:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L38
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memccpy(void *dst, const void *src, unsigned char c, size_t n) {
  size_t i;
  i = 0;
  while (i < n) {
    ((unsigned char *)dst)[i] = ((unsigned char *)src)[i];
    if (((unsigned char *)src)[i] == c)
      return (dst + i + 1);
    i++;
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_memccpy>:
  endbr64
  test   %rcx,%rcx
  je     L22
  mov    $0x0,%eax
L4:
  movzbl (%rsi,%rax,1),%r8d
  mov    %r8b,(%rdi,%rax,1)
  cmp    %dl,%r8b
  je     L20
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L4
  mov    $0x0,%eax
  ret
L20:
  lea    0x1(%rdi,%rax,1),%rax
  ret
L22:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *ft_memccpy(void *dst, const void *src, unsigned char c, size_t n) {
  size_t i;
  i = 0;
  while (i < n) {
    ((unsigned char *)dst)[i] = ((unsigned char *)src)[i];
    if (((unsigned char *)src)[i] == c)
      return (dst + i + 1);
    i++;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_memccpy>:
  endbr64
  xor    %r8d,%r8d
  test   %rcx,%rcx
  jne    L31
  jmp    L6
  xchg   %ax,%ax
L24:
  cmp    %r8,%rcx
  je     L6
L31:
  movzbl (%rsi,%r8,1),%r9d
  mov    %r9b,(%rdi,%r8,1)
  add    $0x1,%r8
  cmp    %dl,%r9b
  jne    L24
  lea    (%rdi,%r8,1),%rax
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *ft_memccpy(void *dst, const void *src, unsigned char c, size_t n) {
  size_t i;
  i = 0;
  while (i < n) {
    ((unsigned char *)dst)[i] = ((unsigned char *)src)[i];
    if (((unsigned char *)src)[i] == c)
      return (dst + i + 1);
    i++;
  }
  return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_memccpy>:
  endbr64
  xor    %r8d,%r8d
  test   %rcx,%rcx
  jne    L1
  jmp    L21
  xchg   %ax,%ax
L22:
  cmp    %r8,%rcx
  je     L21
L1:
  movzbl (%rsi,%r8,1),%r9d
  mov    %r9b,(%rdi,%r8,1)
  add    $0x1,%r8
  cmp    %dl,%r9b
  jne    L22
  lea    (%rdi,%r8,1),%rax
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *ft_memccpy(void *dst, const void *src, unsigned char c, size_t n) {
  size_t i;
  i = 0;
  while (i < n) {
    ((unsigned char *)dst)[i] = ((unsigned char *)src)[i];
    if (((unsigned char *)src)[i] == c)
      return (dst + i + 1);
    i++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  mov    %rax,%rdi
  call   <output_char@plt>
  addq   $0x1,-0x8(%rbp)
  jmp    L2
L13:
  nop
  leave
  ret
```

assistant: ```c
void output_str(char *s) {
  long n;
  n = 0;
output_str_j1:
  if (s[n] != 0) {
    output_char((long)s[n]);
    n = n + 1;
    goto output_str_j1;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  push   %rbx
  lea    0x1(%rdi),%rbx
L18:
  movsbq %al,%rdi
  call   <output_char@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L18
  pop    %rbx
  ret
L10:
  ret
```

assistant: ```c
void output_str(char *s) {
  long n;
  n = 0;
output_str_j1:
  if (s[n] != 0) {
    output_char((long)s[n]);
    n = n + 1;
    goto output_str_j1;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<output_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  push   %rbx
  lea    0x1(%rdi),%rbx
L6:
  movsbq %al,%rdi
  add    $0x1,%rbx
  call   <output_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L6
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void output_str(char *s) {
  long n;
  n = 0;
output_str_j1:
  if (s[n] != 0) {
    output_char((long)s[n]);
    n = n + 1;
    goto output_str_j1;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  push   %rbx
  lea    0x1(%rdi),%rbx
L9:
  movsbq %al,%rdi
  add    $0x1,%rbx
  call   <output_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L9
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void output_str(char *s) {
  long n;
  n = 0;
output_str_j1:
  if (s[n] != 0) {
    output_char((long)s[n]);
    n = n + 1;
    goto output_str_j1;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L59
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L61
  mov    $0x0,%eax
  jmp    L37
L61:
  addq   $0x1,-0x18(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L14
  movq   $0x0,-0x8(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2f,-0xc(%rbp)
  jle    L33
  cmpl   $0x39,-0xc(%rbp)
  jg     L33
  subl   $0x30,-0xc(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L33:
  mov    -0x8(%rbp),%rax
L37:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long atoul(const char *string) {
  unsigned long value;
  int c;
  while (*string <= ' ') {
    if (!*string) {
      return 0;
    }
    string++;
  }
  value = 0;
  do {
    c = *string++;
    if (c < '0' || c > '9') {
      break;
    }
    c -= '0';
    value = value * 10 + c;
  } while (1);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atoul>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jg     L49
L62:
  test   %al,%al
  je     L33
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jle    L62
L49:
  lea    0x1(%rdi),%rcx
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L64
  mov    $0x0,%edx
L13:
  lea    (%rdx,%rdx,4),%rdx
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%esi
  jbe    L13
  jmp    L28
L33:
  mov    $0x0,%edx
L28:
  mov    %rdx,%rax
  ret
L64:
  mov    $0x0,%edx
  jmp    L28
```

assistant: ```c
unsigned long atoul(const char *string) {
  unsigned long value;
  int c;
  while (*string <= ' ') {
    if (!*string) {
      return 0;
    }
    string++;
  }
  value = 0;
  do {
    c = *string++;
    if (c < '0' || c > '9') {
      break;
    }
    c -= '0';
    value = value * 10 + c;
  } while (1);
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atoul>:
  endbr64
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L24:
  test   %al,%al
  je     L15
  add    $0x1,%rdi
L39:
  movsbl (%rdi),%eax
  cmp    $0x20,%al
  jle    L24
  sub    $0x30,%eax
  add    $0x1,%rdi
  xor    %r8d,%r8d
  cmp    $0x9,%eax
  ja     L12
  xchg   %ax,%ax
L21:
  cltq
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8
  movsbl -0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L21
L12:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L15:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long atoul(const char *string) {
  unsigned long value;
  int c;
  while (*string <= ' ') {
    if (!*string) {
      return 0;
    }
    string++;
  }
  value = 0;
  do {
    c = *string++;
    if (c < '0' || c > '9') {
      break;
    }
    c -= '0';
    value = value * 10 + c;
  } while (1);
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atoul>:
  endbr64
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L19:
  test   %al,%al
  je     L0
  add    $0x1,%rdi
L1:
  movsbl (%rdi),%eax
  cmp    $0x20,%al
  jle    L19
  sub    $0x30,%eax
  add    $0x1,%rdi
  xor    %r8d,%r8d
  cmp    $0x9,%eax
  ja     L49
  xchg   %ax,%ax
L23:
  cltq
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8
  movsbl -0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L23
L49:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L0:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long atoul(const char *string) {
  unsigned long value;
  int c;
  while (*string <= ' ') {
    if (!*string) {
      return 0;
    }
    string++;
  }
  value = 0;
  do {
    c = *string++;
    if (c < '0' || c > '9') {
      break;
    }
    c -= '0';
    value = value * 10 + c;
  } while (1);
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<sumOfDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L18:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L14:
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumOfDigits(int data) {
  int k, sum = 0;
  while (data != 0) {
    k = data % 10;
    sum = sum + k;
    data /= 10;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sumOfDigits>:
  endbr64
  test   %edi,%edi
  je     L19
  mov    $0x0,%ecx
L27:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%ecx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L27
L20:
  mov    %ecx,%eax
  ret
L19:
  mov    %edi,%ecx
  jmp    L20
```

assistant: ```c
int sumOfDigits(int data) {
  int k, sum = 0;
  while (data != 0) {
    k = data % 10;
    sum = sum + k;
    data /= 10;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sumOfDigits>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L6
  nopl   0x0(%rax,%rax,1)
L18:
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L18
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sumOfDigits(int data) {
  int k, sum = 0;
  while (data != 0) {
    k = data % 10;
    sum = sum + k;
    data /= 10;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<sumOfDigits>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L4
  nopl   0x0(%rax,%rax,1)
L9:
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L9
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sumOfDigits(int data) {
  int k, sum = 0;
  while (data != 0) {
    k = data % 10;
    sum = sum + k;
    data /= 10;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<generate_guard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L35
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  jmp    L42
L35:
  mov    -0x28(%rbp),%rax
L42:
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L4
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L47
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
L47:
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extendfile@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string

tool: D8: _H_RPCGEN

assistant: ```c
char *generate_guard(char *pathname) {
  char *filename, *guard, *tmp;
  filename = strrchr(pathname, '/');
  filename = ((filename == 0) ? pathname : filename + 1);
  guard = strdup(filename);
  tmp = guard;
  while (*tmp) {
    if (islower(*tmp))
      *tmp = toupper(*tmp);
    tmp++;
  }
  guard = extendfile(guard, "_H_RPCGEN");
  return (guard);
}
```