ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<consecfactors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L40
L28:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  add    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L31
L48:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <count_factors@plt>
  cmp    %rax,-0x18(%rbp)
  jne    L40
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L48
L40:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L28
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint32_t consecfactors(uint32_t n) {
  uint32_t i = 1;
  for (uint32_t c = 0; c != n;) {
    i += c + 1;
    for (c = 0; count_factors(i + c) == n && c < n; c++)
      ;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<consecfactors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L49
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x1,%r12d
  jmp    L45
L58:
  cmp    %rbp,%rbx
  je     L42
L45:
  lea    0x1(%rbx,%r12,1),%r12
  mov    $0x0,%ebx
L25:
  lea    (%r12,%rbx,1),%rdi
  call   <count_factors@plt>
  cmp    %rbp,%rbx
  jge    L58
  cmp    %rbp,%rax
  jne    L58
  add    $0x1,%rbx
  jmp    L25
L49:
  mov    $0x1,%r12d
L42:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t consecfactors(uint32_t n) {
  uint32_t i = 1;
  for (uint32_t c = 0; c != n;) {
    i += c + 1;
    for (c = 0; count_factors(i + c) == n && c < n; c++)
      ;
  }
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<consecfactors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L35
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L26:
  lea    0x1(%rbx,%r12,1),%r12
  xor    %ebx,%ebx
  jmp    L49
  nopl   0x0(%rax)
L1:
  cmp    %rbp,%rbx
  jge    L46
  add    $0x1,%rbx
L49:
  lea    (%r12,%rbx,1),%rdi
  call   <count_factors@plt>
  cmp    %rbp,%rax
  je     L1
L46:
  cmp    %rbp,%rbx
  jne    L26
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x1,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
uint32_t consecfactors(uint32_t n) {
  uint32_t i = 1;
  for (uint32_t c = 0; c != n;) {
    i += c + 1;
    for (c = 0; count_factors(i + c) == n && c < n; c++)
      ;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<consecfactors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L29
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L31:
  lea    0x1(%rbx,%r12,1),%r12
  xor    %ebx,%ebx
  jmp    L2
  nopl   0x0(%rax)
L14:
  cmp    %rbp,%rbx
  jge    L30
  add    $0x1,%rbx
L2:
  lea    (%r12,%rbx,1),%rdi
  call   <count_factors@plt>
  cmp    %rbp,%rax
  je     L14
L30:
  cmp    %rbp,%rbx
  jne    L31
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x1,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
uint32_t consecfactors(uint32_t n) {
  uint32_t i = 1;
  for (uint32_t c = 0; c != n;) {
    i += c + 1;
    for (c = 0; count_factors(i + c) == n && c < n; c++)
      ;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    D4(%rip),%eax
  mov    %eax,%edi
  call   <do_cube@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int num = 6;
  char *ptr;
  ptr = malloc(1024);
  do_cube(num);
  free(ptr);
  exit(EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x6,%edi
  call   <do_cube@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int num = 6;
  char *ptr;
  ptr = malloc(1024);
  do_cube(num);
  free(ptr);
  exit(EXIT_SUCCESS);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x6,%edi
  mov    %rax,%rbp
  call   <do_cube@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int num = 6;
  char *ptr;
  ptr = malloc(1024);
  do_cube(num);
  free(ptr);
  exit(EXIT_SUCCESS);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x6,%edi
  mov    %rax,%rbp
  call   <do_cube@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  static int num = 6;
  char *ptr;
  ptr = malloc(1024);
  do_cube(num);
  free(ptr);
  exit(EXIT_SUCCESS);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<line_abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movapd %xmm1,%xmm4
  movapd %xmm3,%xmm1
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm4,%xmm0
  movss  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm2,%xmm0
  movss  %xmm0,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm2,%xmm2
  cvtss2sd -0x50(%rbp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd -0x40(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x48(%rbp),%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd -0x38(%rbp),%xmm5
  movq   %xmm5,%rax
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rsi
  lea    -0x28(%rbp),%rdi
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x4,%eax
  call   <clip@plt>
  test   %eax,%eax
  je     L13
  movss  -0x24(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x28(%rbp),%xmm1
  pxor   %xmm6,%xmm6
  cvtss2sd %xmm1,%xmm6
  movq   %xmm6,%rax
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <scale_to_screen@plt>
  movss  -0x1c(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x20(%rbp),%xmm1
  pxor   %xmm7,%xmm7
  cvtss2sd %xmm1,%xmm7
  movq   %xmm7,%rax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <scale_to_screen@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <line@plt>
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void line_abs(x1, y1, x2, y2) float x1, x2, y1, y2;
{
  float x1_out, y1_out, x2_out, y2_out;
  int xp1, yp1, xp2, yp2;
  if (clip(x1, x2, y1, y2, &x1_out, &y1_out, &x2_out, &y2_out)) {
    scale_to_screen(x1_out, y1_out, &xp1, &yp1);
    scale_to_screen(x2_out, y2_out, &xp2, &yp2);
    line(xp1, yp1, xp2, yp2);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<line_abs>:
  endbr64
  sub    $0x38,%rsp
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  cvtsd2ss %xmm1,%xmm4
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm2,%xmm1
  cvtsd2ss %xmm3,%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm4,%xmm2
  cvtss2sd %xmm1,%xmm1
  mov    $0x4,%eax
  call   <clip@plt>
  test   %eax,%eax
  jne    L5
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  ret
L5:
  lea    0x1c(%rsp),%rsi
  lea    0x18(%rsp),%rdi
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mov    $0x2,%eax
  call   <scale_to_screen@plt>
  lea    0x24(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  mov    $0x2,%eax
  call   <scale_to_screen@plt>
  mov    0x24(%rsp),%ecx
  mov    0x20(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x18(%rsp),%edi
  mov    $0x0,%eax
  call   <line@plt>
  jmp    L14
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void line_abs(x1, y1, x2, y2) float x1, x2, y1, y2;
{
  float x1_out, y1_out, x2_out, y2_out;
  int xp1, yp1, xp2, yp2;
  if (clip(x1, x2, y1, y2, &x1_out, &y1_out, &x2_out, &y2_out)) {
    scale_to_screen(x1_out, y1_out, &xp1, &yp1);
    scale_to_screen(x2_out, y2_out, &xp2, &yp2);
    line(xp1, yp1, xp2, yp2);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<line_abs>:
  endbr64
  pxor   %xmm4,%xmm4
  sub    $0x38,%rsp
  cvtsd2ss %xmm0,%xmm0
  cvtsd2ss %xmm3,%xmm3
  cvtsd2ss %xmm1,%xmm4
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  lea    0x14(%rsp),%rcx
  cvtsd2ss %xmm2,%xmm1
  lea    0x10(%rsp),%rdx
  pxor   %xmm2,%xmm2
  lea    0xc(%rsp),%rsi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm4,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    0x8(%rsp),%rdi
  mov    $0x4,%eax
  call   <clip@plt>
  test   %eax,%eax
  jne    L8
L7:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    0x1c(%rsp),%rsi
  lea    0x18(%rsp),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x2,%eax
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsp),%xmm0
  cvtss2sd 0xc(%rsp),%xmm1
  call   <scale_to_screen@plt>
  lea    0x24(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm1
  call   <scale_to_screen@plt>
  mov    0x24(%rsp),%ecx
  mov    0x20(%rsp),%edx
  mov    0x1c(%rsp),%esi
  xor    %eax,%eax
  mov    0x18(%rsp),%edi
  call   <line@plt>
  jmp    L7
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void line_abs(x1, y1, x2, y2) float x1, x2, y1, y2;
{
  float x1_out, y1_out, x2_out, y2_out;
  int xp1, yp1, xp2, yp2;
  if (clip(x1, x2, y1, y2, &x1_out, &y1_out, &x2_out, &y2_out)) {
    scale_to_screen(x1_out, y1_out, &xp1, &yp1);
    scale_to_screen(x2_out, y2_out, &xp2, &yp2);
    line(xp1, yp1, xp2, yp2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<line_abs>:
  endbr64
  pxor   %xmm4,%xmm4
  sub    $0x38,%rsp
  cvtsd2ss %xmm0,%xmm0
  cvtsd2ss %xmm3,%xmm3
  cvtsd2ss %xmm1,%xmm4
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  lea    0x14(%rsp),%rcx
  cvtsd2ss %xmm2,%xmm1
  lea    0x10(%rsp),%rdx
  pxor   %xmm2,%xmm2
  lea    0xc(%rsp),%rsi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm4,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    0x8(%rsp),%rdi
  mov    $0x4,%eax
  call   <clip@plt>
  test   %eax,%eax
  jne    L8
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    0x1c(%rsp),%rsi
  lea    0x18(%rsp),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x2,%eax
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsp),%xmm0
  cvtss2sd 0xc(%rsp),%xmm1
  call   <scale_to_screen@plt>
  lea    0x24(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm1
  call   <scale_to_screen@plt>
  mov    0x24(%rsp),%ecx
  mov    0x20(%rsp),%edx
  mov    0x1c(%rsp),%esi
  xor    %eax,%eax
  mov    0x18(%rsp),%edi
  call   <line@plt>
  jmp    L0
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void line_abs(x1, y1, x2, y2) float x1, x2, y1, y2;
{
  float x1_out, y1_out, x2_out, y2_out;
  int xp1, yp1, xp2, yp2;
  if (clip(x1, x2, y1, y2, &x1_out, &y1_out, &x2_out, &y2_out)) {
    scale_to_screen(x1_out, y1_out, &xp1, &yp1);
    scale_to_screen(x2_out, y2_out, &xp2, &yp2);
    line(xp1, yp1, xp2, yp2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<u2mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L10
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L31
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L32
L31:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L32:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L10:
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void u2mac(char *dst, char *name, int len) {
  while (len) {
    if (*name == '/') {
      *dst = 0;
    } else {
      *dst = *name;
    }
    dst++;
    name++;
    len--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<u2mac>:
  endbr64
  test   %edx,%edx
  je     L8
  mov    %edx,%edx
  mov    $0x0,%eax
  mov    $0x0,%r8d
L18:
  movzbl (%rsi,%rax,1),%ecx
  cmp    $0x2f,%cl
  cmove  %r8d,%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L8:
  ret
```

assistant: ```c
void u2mac(char *dst, char *name, int len) {
  while (len) {
    if (*name == '/') {
      *dst = 0;
    } else {
      *dst = *name;
    }
    dst++;
    name++;
    len--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<u2mac>:
  endbr64
  test   %edx,%edx
  je     L9
  mov    %edx,%edx
  xor    %eax,%eax
  xor    %r8d,%r8d
  nop
L17:
  movzbl (%rsi,%rax,1),%ecx
  cmp    $0x2f,%cl
  cmove  %r8d,%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L9:
  ret
```

assistant: ```c
void u2mac(char *dst, char *name, int len) {
  while (len) {
    if (*name == '/') {
      *dst = 0;
    } else {
      *dst = *name;
    }
    dst++;
    name++;
    len--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L10
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *skip_decimal(const char *str) {
  if (str) {
    if (*str == '.')
      str++;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<skip_decimal>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L9
  cmpb   $0x2e,(%rdi)
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
L9:
  ret
```

assistant: ```c
const char *skip_decimal(const char *str) {
  if (str) {
    if (*str == '.')
      str++;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<skip_decimal>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L5
  xor    %edx,%edx
  cmpb   $0x2e,(%rdi)
  sete   %dl
  add    %rdx,%rax
L5:
  ret
```

assistant: ```c
const char *skip_decimal(const char *str) {
  if (str) {
    if (*str == '.')
      str++;
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skip_decimal>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L8
  xor    %edx,%edx
  cmpb   $0x2e,(%rdi)
  sete   %dl
  add    %rdx,%rax
L8:
  ret
```

assistant: ```c
const char *skip_decimal(const char *str) {
  if (str) {
    if (*str == '.')
      str++;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    $0x3e7,%eax
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay() {
  volatile int i;
  for (i = 0; i < 1000; i++)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x3e7,%eax
  jg     L11
L16:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x3e7,%eax
  jle    L16
L11:
  ret
```

assistant: ```c
void delay() {
  volatile int i;
  for (i = 0; i < 1000; i++)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<delay>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x3e7,%eax
  jg     L2
  nopw   0x0(%rax,%rax,1)
L0:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x3e7,%eax
  jle    L0
L2:
  ret
```

assistant: ```c
void delay() {
  volatile int i;
  for (i = 0; i < 1000; i++)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<delay>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x3e7,%eax
  jg     L16
  nopw   0x0(%rax,%rax,1)
L19:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x3e7,%eax
  jle    L19
L16:
  ret
```

assistant: ```c
void delay() {
  volatile int i;
  for (i = 0; i < 1000; i++)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpuStep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <setjmp@plt>
  endbr64
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pushEnvironment@plt>
  mov    $0x0,%eax
  call   <timerTick@plt>
  mov    $0x0,%eax
  call   <execNextInstruction@plt>
  mov    $0x0,%eax
  call   <handleInterrupts@plt>
  jmp    L18
L13:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <cpuSetInterrupt@plt>
  mov    $0x0,%eax
  call   <handleInterrupts@plt>
L18:
  mov    $0x0,%eax
  call   <popEnvironment@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void cpuStep(void) {
  jmp_buf myEnvironment;
  int exception;
  exception = setjmp(myEnvironment);
  if (exception == 0) {
    pushEnvironment(&myEnvironment);
    timerTick();
    execNextInstruction();
    handleInterrupts();
  } else {
    cpuSetInterrupt(exception);
    handleInterrupts();
  }
  popEnvironment();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpuStep>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%edi
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L4
  lea    0x4(%rsp),%rdi
  call   <pushEnvironment@plt>
  mov    $0x0,%eax
  call   <timerTick@plt>
  mov    $0x0,%eax
  call   <execNextInstruction@plt>
  mov    $0x0,%eax
  call   <handleInterrupts@plt>
L10:
  mov    $0x0,%eax
  call   <popEnvironment@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  ret
L4:
  mov    %eax,%edi
  call   <cpuSetInterrupt@plt>
  mov    $0x0,%eax
  call   <handleInterrupts@plt>
  jmp    L10
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cpuStep(void) {
  jmp_buf myEnvironment;
  int exception;
  exception = setjmp(myEnvironment);
  if (exception == 0) {
    pushEnvironment(&myEnvironment);
    timerTick();
    execNextInstruction();
    handleInterrupts();
  } else {
    cpuSetInterrupt(exception);
    handleInterrupts();
  }
  popEnvironment();
}
```
user: Translate the below assembly code into C programming language:

```asm
<cpuStep>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%edi
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L7
  lea    0x4(%rsp),%rdi
  call   <pushEnvironment@plt>
  xor    %eax,%eax
  call   <timerTick@plt>
  xor    %eax,%eax
  call   <execNextInstruction@plt>
  xor    %eax,%eax
  call   <handleInterrupts@plt>
L8:
  xor    %eax,%eax
  call   <popEnvironment@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L7:
  mov    %eax,%edi
  call   <cpuSetInterrupt@plt>
  xor    %eax,%eax
  call   <handleInterrupts@plt>
  jmp    L8
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cpuStep(void) {
  jmp_buf myEnvironment;
  int exception;
  exception = setjmp(myEnvironment);
  if (exception == 0) {
    pushEnvironment(&myEnvironment);
    timerTick();
    execNextInstruction();
    handleInterrupts();
  } else {
    cpuSetInterrupt(exception);
    handleInterrupts();
  }
  popEnvironment();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpuStep>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%edi
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L29
  lea    0x4(%rsp),%rdi
  call   <pushEnvironment@plt>
  xor    %eax,%eax
  call   <timerTick@plt>
  xor    %eax,%eax
  call   <execNextInstruction@plt>
  xor    %eax,%eax
  call   <handleInterrupts@plt>
L12:
  xor    %eax,%eax
  call   <popEnvironment@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L29:
  mov    %eax,%edi
  call   <cpuSetInterrupt@plt>
  xor    %eax,%eax
  call   <handleInterrupts@plt>
  jmp    L12
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cpuStep(void) {
  jmp_buf myEnvironment;
  int exception;
  exception = setjmp(myEnvironment);
  if (exception == 0) {
    pushEnvironment(&myEnvironment);
    timerTick();
    execNextInstruction();
    handleInterrupts();
  } else {
    cpuSetInterrupt(exception);
    handleInterrupts();
  }
  popEnvironment();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cli
  hlt
L6:
  jmp    L6
```

assistant: ```c
__attribute__((noreturn)) void abort(void) {
  __asm__ __volatile__("cli; hlt");
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abort>:
  endbr64
  cli
  hlt
L3:
  jmp    L3
```

assistant: ```c
__attribute__((noreturn)) void abort(void) {
  __asm__ __volatile__("cli; hlt");
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abort>:
  endbr64
  cli
  hlt
L9:
  jmp    L9
```

assistant: ```c
__attribute__((noreturn)) void abort(void) {
  __asm__ __volatile__("cli; hlt");
  while (1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<abort>:
  endbr64
  cli
  hlt
L2:
  jmp    L2
```

assistant: ```c
__attribute__((noreturn)) void abort(void) {
  __asm__ __volatile__("cli; hlt");
  while (1)
    ;
}
```