user: 请从给定的汇编指令推导出C源代码:

```asm
<dpu_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x10,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L18
L1:
  cmpl   $0x4000,-0x3c(%rbp)
  je     L128
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L145
L71:
  cmpl   $0x4000,-0x3c(%rbp)
  jne    L8
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L68
L8:
  mov    -0x24(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jne    L148
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L68
L148:
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x3c(%rbp)
  addl   $0x1,-0x24(%rbp)
L145:
  cmpl   $0xf,-0x2c(%rbp)
  jbe    L71
L68:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L22
L80:
  mov    -0x2c(%rbp),%eax
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L16
  mov    -0x2c(%rbp),%eax
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L44
L16:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  addl   $0x1,-0x2c(%rbp)
L22:
  mov    -0x2c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jb     L80
  mov    $0xa,%edi
  call   <putchar@plt>
L18:
  mov    -0x24(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jb     L1
  jmp    L131
L128:
  nop
L131:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L108
  call   <__stack_chk_fail@plt>
L108:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D21
datatype: string
name: retrieve_data
arguments: label: D22
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string

tool: D28: %04X	

tool: D21: %02X 

tool: D22: 
	

tool: D4:  %c 

tool: D24:  . 

assistant: ```c
int dpu_dump(void *memptr, unsigned int offset, unsigned int length) {
  unsigned int i;
  unsigned char line[0x10];
  unsigned int lineLength = 0x10;
  unsigned int count = 0;
  while (count < length) {
    if (offset == 0x4000) {
      break;
    }
    printf("%04X\t", offset);
    for (i = 0; i < 0x10; i++, offset++, count++) {
      if (offset == 0x4000) {
        lineLength = i;
        break;
      }
      if (count == length) {
        lineLength = i;
        break;
      }
      line[i] = *((char *)memptr + offset);
      printf("%02X ", line[i]);
    }
    printf("\n\t");
    for (i = 0; i < lineLength; i++) {
      if (isprint(line[i])) {
        printf(" %c ", line[i]);
      } else {
        printf(" . ");
      }
    }
    printf("\n");
  }
  return 0;
}
```