ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696874,%rax
  movabs $0x6d20676e6f6c2061,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x7420656761737365,%rax
  movabs $0x6c6c697720746168,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x6572697571657220,%rax
  movabs $0x6620676e69656220,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x65746e656d676172,%rax
  movabs $0x6d206f746e692064,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x20656c7069746c75,%rax
  movabs $0x207374656b636170,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x656874207265766f,%rax
  movabs $0x6f72702050544e20,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x59202e6c6f636f74,%rax
  movabs $0x75732049202e7961,%rdx
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movabs $0x2065706f68206572,%rax
  movabs $0x736b726f77207469,%rdx
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  movw   $0x2e,0x80(%rsp)
L10:
  mov    $0x2,%edi
  call   <accept@plt>
  cmp    $0xffffffff,%eax
  je     L10
  mov    %rsp,%rsi
  mov    $0x82,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L11
L25:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x98,%rsp
  ret
L11:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L25
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: Error : Expected to write all bytes, but wrote -1

assistant: ```c
int main(int argc, char *argv[]) {
  int connection, bytes;
  char msg[] = "this is a long message that will require being fragmented into multiple packets over the NTP protocol. Yay. I sure hope it works.";
  do {
    connection = accept(2);
  } while (connection == -1);
  bytes = write(connection, msg, sizeof(msg));
  if (bytes == -1) {
    printf("Error : Expected to write all bytes, but wrote -1");
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x2e,%eax
  movaps %xmm0,(%rsp)
  movdqa D29(%rip),%xmm0
  mov    %ax,0x80(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D48(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D75(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D22(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D25(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x2,%edi
  call   <accept@plt>
  cmp    $0xffffffff,%eax
  je     L25
  mov    %rsp,%rsi
  mov    $0x82,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L8
L22:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x98,%rsp
  ret
L8:
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L22
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: byte[16]
name: unpack_data
arguments: label: D29
type_guessed: byte[16]
name: unpack_data
arguments: label: D48
type_guessed: byte[16]
name: unpack_data
arguments: label: D75
type_guessed: byte[16]
name: unpack_data
arguments: label: D22
type_guessed: byte[16]
name: unpack_data
arguments: label: D25
type_guessed: byte[16]
name: unpack_data
arguments: label: D7
type_guessed: byte[16]
name: unpack_data
arguments: label: D2
type_guessed: byte[16]
name: unpack_data
arguments: label: D66
type_guessed: string

tool: {"D5": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x6c,0x6f,0x6e,0x67,0x20,0x6d]}

tool: {"D29": [0x65,0x73,0x73,0x61,0x67,0x65,0x20,0x74,0x68,0x61,0x74,0x20,0x77,0x69,0x6c,0x6c]}

tool: {"D48": [0x20,0x72,0x65,0x71,0x75,0x69,0x72,0x65,0x20,0x62,0x65,0x69,0x6e,0x67,0x20,0x66]}

tool: {"D75": [0x72,0x61,0x67,0x6d,0x65,0x6e,0x74,0x65,0x64,0x20,0x69,0x6e,0x74,0x6f,0x20,0x6d]}

tool: {"D22": [0x75,0x6c,0x74,0x69,0x70,0x6c,0x65,0x20,0x70,0x61,0x63,0x6b,0x65,0x74,0x73,0x20]}

tool: {"D25": [0x6f,0x76,0x65,0x72,0x20,0x74,0x68,0x65,0x20,0x4e,0x54,0x50,0x20,0x70,0x72,0x6f]}

tool: {"D7": [0x74,0x6f,0x63,0x6f,0x6c,0x2e,0x20,0x59,0x61,0x79,0x2e,0x20,0x49,0x20,0x73,0x75]}

tool: {"D2": [0x72,0x65,0x20,0x68,0x6f,0x70,0x65,0x20,0x69,0x74,0x20,0x77,0x6f,0x72,0x6b,0x73]}

tool: D66: Error : Expected to write all bytes, but wrote -1

assistant: ```c
int main(int argc, char *argv[]) {
  int connection, bytes;
  char msg[] = "this is a long message that will require being fragmented into multiple packets over the NTP protocol. Yay. I sure hope it works.";
  do {
    connection = accept(2);
  } while (connection == -1);
  bytes = write(connection, msg, sizeof(msg));
  if (bytes == -1) {
    printf("Error : Expected to write all bytes, but wrote -1");
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x2e,%eax
  movaps %xmm0,(%rsp)
  movdqa D65(%rip),%xmm0
  mov    %ax,0x80(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D57(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D30(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D3(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D5(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D74(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D87(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x2,%edi
  call   <accept@plt>
  cmp    $0xffffffff,%eax
  je     L20
  mov    %rsp,%rsi
  mov    $0x82,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L23
L18:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x98,%rsp
  ret
L23:
  lea    D86(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L18
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D65
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D57
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D30
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D3
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D5
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D74
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D87
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D86
type_guessed: string

tool: {"D25": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x6c,0x6f,0x6e,0x67,0x20,0x6d]}

tool: {"D65": [0x65,0x73,0x73,0x61,0x67,0x65,0x20,0x74,0x68,0x61,0x74,0x20,0x77,0x69,0x6c,0x6c]}

tool: {"D57": [0x20,0x72,0x65,0x71,0x75,0x69,0x72,0x65,0x20,0x62,0x65,0x69,0x6e,0x67,0x20,0x66]}

tool: {"D30": [0x72,0x61,0x67,0x6d,0x65,0x6e,0x74,0x65,0x64,0x20,0x69,0x6e,0x74,0x6f,0x20,0x6d]}

tool: {"D3": [0x75,0x6c,0x74,0x69,0x70,0x6c,0x65,0x20,0x70,0x61,0x63,0x6b,0x65,0x74,0x73,0x20]}

tool: {"D5": [0x6f,0x76,0x65,0x72,0x20,0x74,0x68,0x65,0x20,0x4e,0x54,0x50,0x20,0x70,0x72,0x6f]}

tool: {"D74": [0x74,0x6f,0x63,0x6f,0x6c,0x2e,0x20,0x59,0x61,0x79,0x2e,0x20,0x49,0x20,0x73,0x75]}

tool: {"D87": [0x72,0x65,0x20,0x68,0x6f,0x70,0x65,0x20,0x69,0x74,0x20,0x77,0x6f,0x72,0x6b,0x73]}

tool: D86: Error : Expected to write all bytes, but wrote -1

assistant: ```c
int main(int argc, char *argv[]) {
  int connection, bytes;
  char msg[] = "this is a long message that will require being fragmented into multiple packets over the NTP protocol. Yay. I sure hope it works.";
  do {
    connection = accept(2);
  } while (connection == -1);
  bytes = write(connection, msg, sizeof(msg));
  if (bytes == -1) {
    printf("Error : Expected to write all bytes, but wrote -1");
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<volatile_fetch_and_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t volatile_fetch_and_u16(volatile uint16_t *dest, uint16_t val) {
  uint16_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<volatile_fetch_and_u16>:
  endbr64
  mov    %esi,-0x14(%rsp)
  mov    (%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    -0x14(%rsp),%edx
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint16_t volatile_fetch_and_u16(volatile uint16_t *dest, uint16_t val) {
  uint16_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<volatile_fetch_and_u16>:
  endbr64
  mov    %esi,-0x14(%rsp)
  mov    (%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    -0x14(%rsp),%edx
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint16_t volatile_fetch_and_u16(volatile uint16_t *dest, uint16_t val) {
  uint16_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<volatile_fetch_and_u16>:
  endbr64
  mov    %esi,-0x14(%rsp)
  mov    (%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    -0x14(%rsp),%edx
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint16_t volatile_fetch_and_u16(volatile uint16_t *dest, uint16_t val) {
  uint16_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nnz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <absd@plt>
  test   %eax,%eax
  jg     L17
  movsd  D8(%rip),%xmm0
  jmp    L13
L17:
  movsd  -0x8(%rbp),%xmm0
L13:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: byte[8]

tool: {"D8": [0xbc,0x89,0xd8,0x97,0xb2,0xd2,0x9c,0x3c]}

assistant: ```c
double nnz(double x) {
  if (absd(x) < 1e-16) {
    return 1e-16;
  } else {
    return x;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nnz>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <absd@plt>
  movq   %rbx,%xmm0
  test   %eax,%eax
  jle    L4
L1:
  pop    %rbx
  ret
L4:
  movsd  D4(%rip),%xmm0
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: byte[8]

tool: {"D4": [0xbc,0x89,0xd8,0x97,0xb2,0xd2,0x9c,0x3c]}

assistant: ```c
double nnz(double x) {
  if (absd(x) < 1e-16) {
    return 1e-16;
  } else {
    return x;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nnz>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <absd@plt>
  movsd  D1(%rip),%xmm0
  test   %eax,%eax
  jle    L5
  movsd  0x8(%rsp),%xmm0
L5:
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: byte[8]

tool: {"D1": [0xbc,0x89,0xd8,0x97,0xb2,0xd2,0x9c,0x3c]}

assistant: ```c
double nnz(double x) {
  if (absd(x) < 1e-16) {
    return 1e-16;
  } else {
    return x;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<nnz>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <absd@plt>
  movsd  D0(%rip),%xmm0
  test   %eax,%eax
  jle    L4
  movsd  0x8(%rsp),%xmm0
L4:
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: byte[8]

tool: {"D0": [0xbc,0x89,0xd8,0x97,0xb2,0xd2,0x9c,0x3c]}

assistant: ```c
double nnz(double x) {
  if (absd(x) < 1e-16) {
    return 1e-16;
  } else {
    return x;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmpq   $0xa,-0x38(%rbp)
  ja     L42
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L0:
  cmp    %rdx,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L32:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L31
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L31:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <f0@plt>
  mov    %rbx,%rsp
L42:
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void f1(long unsigned int a) {
  if (a <= 10) {
    uint32_t x[a];
    f0(x);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmp    $0xa,%rdi
  jbe    L42
L33:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    -0x8(%rbp),%rbx
  leave
  ret
L42:
  mov    %rsp,%rbx
  lea    0xf(,%rdi,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L40:
  cmp    %rdx,%rsp
  je     L4
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L40
L4:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L50
  orq    $0x0,-0x8(%rsp,%rax,1)
L50:
  mov    %rsp,%rdi
  call   <f0@plt>
  mov    %rbx,%rsp
  jmp    L33
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f1(long unsigned int a) {
  if (a <= 10) {
    uint32_t x[a];
    f0(x);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmp    $0xa,%rdi
  jbe    L44
L66:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  lea    0xf(,%rdi,4),%rax
  mov    %rsp,%rcx
  mov    %rsp,%rbx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L55
L2:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L2
L55:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L67
L40:
  mov    %rsp,%rdi
  call   <f0@plt>
  mov    %rbx,%rsp
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L67:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f1(long unsigned int a) {
  if (a <= 10) {
    uint32_t x[a];
    f0(x);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmp    $0xa,%rdi
  jbe    L26
L21:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  lea    0xf(,%rdi,4),%rax
  mov    %rsp,%rcx
  mov    %rsp,%rbx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L10
L65:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L65
L10:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L23
L68:
  mov    %rsp,%rdi
  call   <f0@plt>
  mov    %rbx,%rsp
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L23:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L68
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f1(long unsigned int a) {
  if (a <= 10) {
    uint32_t x[a];
    f0(x);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x7,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string

tool: D9: gc%d.%d

assistant: ```c
int main() {
  if (0xff == 0xff) {
    printf("gc%d.%d", 7, 0);
  } else {
    printf("gc%d.%dalpha%d", 7, 0, 0xff);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x7,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: gc%d.%d

assistant: ```c
int main() {
  if (0xff == 0xff) {
    printf("gc%d.%d", 7, 0);
  } else {
    printf("gc%d.%dalpha%d", 7, 0, 0xff);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x7,%esi
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: gc%d.%d

assistant: ```c
int main() {
  if (0xff == 0xff) {
    printf("gc%d.%d", 7, 0);
  } else {
    printf("gc%d.%dalpha%d", 7, 0, 0xff);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x7,%esi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: gc%d.%d

assistant: ```c
int main() {
  if (0xff == 0xff) {
    printf("gc%d.%d", 7, 0);
  } else {
    printf("gc%d.%dalpha%d", 7, 0, 0xff);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  jne    L59
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm2
  movsd  D26(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x8(%rbp),%xmm2
  movsd  D26(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  D26(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L33
L59:
  cmpl   $0xc,-0xc(%rbp)
  jne    L24
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  D40(%rip),%xmm1
  subsd  %xmm1,%xmm0
  jmp    L33
L24:
  cmpl   $0xe,-0xc(%rbp)
  jne    L6
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  D26(%rip),%xmm1
  subsd  %xmm1,%xmm0
  jmp    L33
L6:
  jmp    L14
L33:
  movq   %xmm0,%rax
L14:
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D40
type_guessed: byte[8]

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f(double x, int q) {
  if (q == 4)
    return x * x * x * x - 2 * x * x * x - 4 * x * x + 4 * x + 4;
  else if (q == 12)
    return x * x - 3;
  else if (q == 14)
    return x * x * x + x - 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  cmp    $0x4,%edi
  je     L24
  cmp    $0xc,%edi
  je     L2
  cmp    $0xe,%edi
  je     L11
  ret
L24:
  movsd  D9(%rip),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm3,%xmm4
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
L2:
  mulsd  %xmm0,%xmm0
  subsd  D6(%rip),%xmm0
  ret
L11:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D9(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: byte[8]
name: parse_data
arguments: data_label: D6
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f(double x, int q) {
  if (q == 4)
    return x * x * x * x - 2 * x * x * x - 4 * x * x + 4 * x + 4;
  else if (q == 12)
    return x * x - 3;
  else if (q == 14)
    return x * x * x + x - 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  cmp    $0x4,%edi
  je     L5
  cmp    $0xc,%edi
  je     L22
  cmp    $0xe,%edi
  je     L26
  ret
  nopl   0x0(%rax)
L5:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movsd  D11(%rip),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  mulsd  %xmm4,%xmm0
  subsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L26:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D11(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L22:
  mulsd  %xmm0,%xmm0
  subsd  D22(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D22
type_guessed: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f(double x, int q) {
  if (q == 4)
    return x * x * x * x - 2 * x * x * x - 4 * x * x + 4 * x + 4;
  else if (q == 12)
    return x * x - 3;
  else if (q == 14)
    return x * x * x + x - 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  cmp    $0x4,%edi
  je     L5
  cmp    $0xc,%edi
  je     L6
  cmp    $0xe,%edi
  je     L25
  ret
  nopl   0x0(%rax)
L5:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movsd  D28(%rip),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  mulsd  %xmm4,%xmm0
  subsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L25:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D28(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L6:
  mulsd  %xmm0,%xmm0
  subsd  D15(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D28
datatype: byte[8]
name: parse_data
arguments: label: D15
datatype: byte[8]

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f(double x, int q) {
  if (q == 4)
    return x * x * x * x - 2 * x * x * x - 4 * x * x + 4 * x + 4;
  else if (q == 12)
    return x * x - 3;
  else if (q == 14)
    return x * x * x + x - 4;
}
```