ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  movl   $0x7,0x2c(%rsp)
  movl   $0xfffffffb,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x4d,0x10(%rsp)
  mov    %rsp,%rdx
  lea    0x20(%rsp),%rbx
  mov    $0x5,%ecx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <merge@plt>
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <pr_array@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x1c0,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int a[100] = {1, 3, 5, 7};
  int b[] = {-5, 2, 4, 6, 77};
  merge(a, 4, b, 5);
  pr_array(a, 9);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%ecx
  mov    $0x4,%esi
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  mov    %rsp,%rdx
  movl   $0x4d,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  mov    $0x5,%ecx
  movabs $0x300000001,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2fffffffb,%rax
  mov    %rax,(%rsp)
  movabs $0x600000004,%rax
  mov    %rax,0x8(%rsp)
  call   <merge@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <pr_array@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1c0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int a[100] = {1, 3, 5, 7};
  int b[] = {-5, 2, 4, 6, 77};
  merge(a, 4, b, 5);
  pr_array(a, 9);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%ecx
  mov    $0x4,%esi
  sub    $0x1c0,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  mov    %rsp,%rdx
  movl   $0x4d,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  movaps %xmm0,0x20(%rsp)
  mov    %rbp,%rdi
  mov    $0x5,%ecx
  movdqa D19(%rip),%xmm0
  movaps %xmm0,(%rsp)
  call   <merge@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <pr_array@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1c0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: byte[16]
name: retrieve_data
arguments: tag: D19
datatype: byte[16]

tool: {"D3": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D19": [0xfb,0xff,0xff,0xff,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
main() {
  int a[100] = {1, 3, 5, 7};
  int b[] = {-5, 2, 4, 6, 77};
  merge(a, 4, b, 5);
  pr_array(a, 9);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<resolve_pct_format>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
datatype: byte[8]
name: unpack_data
arguments: data_label: D8
datatype: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D8: %7.3f%%

assistant: ```c
void resolve_pct_format(double *value, const char **format) {
  *value *= 100;
  *format = "%7.3f%%";
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<resolve_pct_format>:
  endbr64
  movsd  D16(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdi)
  lea    D3(%rip),%rax
  mov    %rax,(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D3: %7.3f%%

assistant: ```c
void resolve_pct_format(double *value, const char **format) {
  *value *= 100;
  *format = "%7.3f%%";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<resolve_pct_format>:
  endbr64
  movsd  D17(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  lea    D8(%rip),%rax
  movsd  %xmm0,(%rdi)
  mov    %rax,(%rsi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D8: %7.3f%%

assistant: ```c
void resolve_pct_format(double *value, const char **format) {
  *value *= 100;
  *format = "%7.3f%%";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<resolve_pct_format>:
  endbr64
  movsd  D0(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  lea    D7(%rip),%rax
  movsd  %xmm0,(%rdi)
  mov    %rax,(%rsi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: byte[8]
name: disassemble_data
arguments: tag: D7
type: string

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D7: %7.3f%%

assistant: ```c
void resolve_pct_format(double *value, const char **format) {
  *value *= 100;
  *format = "%7.3f%%";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TOOLS_RemovePadding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rbx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  sub    $0x1,%rax
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L59
L4:
  subq   $0x1,-0x18(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L4
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L7
L50:
  addq   $0x1,-0x20(%rbp)
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L50
  mov    -0x28(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L57
L2:
  nop
L57:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void TOOLS_RemovePadding(char **ppInputStr) {
  char *pStartPtr;
  char *pEndPtr;
  if (ppInputStr == NULL) {
    return;
  }
  for (pEndPtr = (*ppInputStr + strlen(*ppInputStr) - 1); *pEndPtr == ' '; pEndPtr--) {
  }
  *(pEndPtr + 1) = '\0';
  for (pStartPtr = *ppInputStr; *pStartPtr == ' '; pStartPtr++) {
  }
  *ppInputStr = pStartPtr;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TOOLS_RemovePadding>:
  endbr64
  test   %rdi,%rdi
  je     L20
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jne    L8
L32:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L32
L8:
  movb   $0x0,0x1(%rax)
  mov    (%rbx),%rax
  cmpb   $0x20,(%rax)
  jne    L44
L33:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L33
L44:
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  ret
```

assistant: ```c
void TOOLS_RemovePadding(char **ppInputStr) {
  char *pStartPtr;
  char *pEndPtr;
  if (ppInputStr == NULL) {
    return;
  }
  for (pEndPtr = (*ppInputStr + strlen(*ppInputStr) - 1); *pEndPtr == ' '; pEndPtr--) {
  }
  *(pEndPtr + 1) = '\0';
  for (pStartPtr = *ppInputStr; *pStartPtr == ' '; pStartPtr++) {
  }
  *ppInputStr = pStartPtr;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<TOOLS_RemovePadding>:
  endbr64
  test   %rdi,%rdi
  je     L34
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jne    L38
  nopl   0x0(%rax)
L18:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L18
L38:
  movb   $0x0,0x1(%rax)
  mov    (%rbx),%rax
  cmpb   $0x20,(%rax)
  jne    L4
  nopl   (%rax)
L17:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L17
L4:
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  ret
```

assistant: ```c
void TOOLS_RemovePadding(char **ppInputStr) {
  char *pStartPtr;
  char *pEndPtr;
  if (ppInputStr == NULL) {
    return;
  }
  for (pEndPtr = (*ppInputStr + strlen(*ppInputStr) - 1); *pEndPtr == ' '; pEndPtr--) {
  }
  *(pEndPtr + 1) = '\0';
  for (pStartPtr = *ppInputStr; *pStartPtr == ' '; pStartPtr++) {
  }
  *ppInputStr = pStartPtr;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TOOLS_RemovePadding>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jne    L15
  nopl   0x0(%rax)
L1:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L1
L15:
  movb   $0x0,0x1(%rax)
  mov    (%rbx),%rax
  cmpb   $0x20,(%rax)
  jne    L6
  nopl   (%rax)
L39:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L39
L6:
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
void TOOLS_RemovePadding(char **ppInputStr) {
  char *pStartPtr;
  char *pEndPtr;
  if (ppInputStr == NULL) {
    return;
  }
  for (pEndPtr = (*ppInputStr + strlen(*ppInputStr) - 1); *pEndPtr == ' '; pEndPtr--) {
  }
  *(pEndPtr + 1) = '\0';
  for (pStartPtr = *ppInputStr; *pStartPtr == ' '; pStartPtr++) {
  }
  *ppInputStr = pStartPtr;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L5
L19:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <discardnewline@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: %s


assistant: ```c
int main(void) {
  char line[1024];
  while (getline(line, sizeof line) > 0) {
    discardnewline(line);
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rbp
  jmp    L17
L13:
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <discardnewline@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L17:
  mov    %rsp,%rdi
  mov    $0x400,%esi
  call   <getline@plt>
  test   %rax,%rax
  jg     L13
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %s


assistant: ```c
int main(void) {
  char line[1024];
  while (getline(line, sizeof line) > 0) {
    discardnewline(line);
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L16
  nopl   0x0(%rax)
L27:
  mov    %rbx,%rdi
  call   <discardnewline@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L16:
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L27
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: %s


assistant: ```c
int main(void) {
  char line[1024];
  while (getline(line, sizeof line) > 0) {
    discardnewline(line);
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L23
  nopl   0x0(%rax)
L18:
  mov    %rbx,%rdi
  call   <discardnewline@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L23:
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L18
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: %s


assistant: ```c
int main(void) {
  char line[1024];
  while (getline(line, sizeof line) > 0) {
    discardnewline(line);
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<days_since_beginning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x10,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: Days since January 1, 1970 = %d


assistant: ```c
void days_since_beginning() {
  time_t seconds;
  seconds = time(NULL);
  printf("Days since January 1, 1970 = %d\n", seconds / 3600 / 24);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<days_since_beginning>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  movslq %eax,%rsi
  imul   $0xffffffffc22e4507,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x10,%esi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: Days since January 1, 1970 = %d


assistant: ```c
void days_since_beginning() {
  time_t seconds;
  seconds = time(NULL);
  printf("Days since January 1, 1970 = %d\n", seconds / 3600 / 24);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<days_since_beginning>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  movslq %eax,%rsi
  imul   $0xffffffffc22e4507,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x10,%esi
  sub    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: Days since January 1, 1970 = %d


assistant: ```c
void days_since_beginning() {
  time_t seconds;
  seconds = time(NULL);
  printf("Days since January 1, 1970 = %d\n", seconds / 3600 / 24);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<days_since_beginning>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  movslq %eax,%rsi
  imul   $0xffffffffc22e4507,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x10,%esi
  sub    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: Days since January 1, 1970 = %d


assistant: ```c
void days_since_beginning() {
  time_t seconds;
  seconds = time(NULL);
  printf("Days since January 1, 1970 = %d\n", seconds / 3600 / 24);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,-0xd(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L53:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L18
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L18:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L15
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L17
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
L17:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L53
  nop
  nop
  leave
  ret
```

assistant: ```c
void Sort(char *vals) {
  int smallest = 0;
  char tmp = 0;
  for (int i = 0; i < strlen(vals) - 1; ++i) {
    smallest = i;
    for (int j = i + 1; j < strlen(vals); ++j)
      if (vals[j] < vals[smallest])
        smallest = j;
    if (smallest != i) {
      tmp = vals[i];
      vals[i] = vals[smallest];
      vals[smallest] = tmp;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    $0x0,%r14d
  jmp    L2
L44:
  movslq %ebp,%rax
  movzbl (%r12,%rax,1),%eax
  cmp    %al,(%r12,%rbx,1)
  cmovl  %r13d,%ebp
  add    $0x1,%rbx
L42:
  mov    %ebx,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L44
  cmp    0xc(%rsp),%ebp
  je     L24
  movzbl (%r12,%r14,1),%eax
  movslq %ebp,%rbp
  add    %r12,%rbp
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%r12,%r14,1)
  mov    %al,0x0(%rbp)
L24:
  mov    %r15,%r14
L2:
  mov    %r14d,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r14d,0xc(%rsp)
  sub    $0x1,%eax
  cmp    %r14d,%eax
  jle    L10
  lea    0x1(%r14),%r15
  mov    %r15,%rbx
  jmp    L42
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Sort(char *vals) {
  int smallest = 0;
  char tmp = 0;
  for (int i = 0; i < strlen(vals) - 1; ++i) {
    smallest = i;
    for (int j = i + 1; j < strlen(vals); ++j)
      if (vals[j] < vals[smallest])
        smallest = j;
    if (smallest != i) {
      tmp = vals[i];
      vals[i] = vals[smallest];
      vals[smallest] = tmp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rdi
  mov    %r12d,%ebp
  mov    %r12d,%r15d
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jle    L22
  lea    0x1(%r12),%r13
  mov    %r13,%rbx
  jmp    L18
L9:
  movslq %ebp,%rax
  movzbl (%r14,%rax,1),%eax
  cmp    %al,(%r14,%rbx,1)
  cmovl  %ebx,%ebp
  add    $0x1,%rbx
L18:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  cmp    %r15d,%ebp
  je     L43
  movslq %ebp,%rbp
  movzbl (%r14,%r12,1),%eax
  add    %r14,%rbp
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%r14,%r12,1)
  mov    %al,0x0(%rbp)
L43:
  mov    %r13,%r12
  jmp    L25
  nop
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Sort(char *vals) {
  int smallest = 0;
  char tmp = 0;
  for (int i = 0; i < strlen(vals) - 1; ++i) {
    smallest = i;
    for (int j = i + 1; j < strlen(vals); ++j)
      if (vals[j] < vals[smallest])
        smallest = j;
    if (smallest != i) {
      tmp = vals[i];
      vals[i] = vals[smallest];
      vals[smallest] = tmp;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r14,%rdi
  mov    %r12d,%ebp
  mov    %r12d,%r15d
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jle    L28
  lea    0x1(%r12),%r13
  mov    %r13,%rbx
  jmp    L2
L17:
  movslq %ebp,%rax
  movzbl (%r14,%rax,1),%eax
  cmp    %al,(%r14,%rbx,1)
  cmovl  %ebx,%ebp
  add    $0x1,%rbx
L2:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L17
  cmp    %r15d,%ebp
  je     L25
  movslq %ebp,%rbp
  movzbl (%r14,%r12,1),%eax
  add    %r14,%rbp
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%r14,%r12,1)
  mov    %al,0x0(%rbp)
L25:
  mov    %r13,%r12
  jmp    L47
  nop
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Sort(char *vals) {
  int smallest = 0;
  char tmp = 0;
  for (int i = 0; i < strlen(vals) - 1; ++i) {
    smallest = i;
    for (int j = i + 1; j < strlen(vals); ++j)
      if (vals[j] < vals[smallest])
        smallest = j;
    if (smallest != i) {
      tmp = vals[i];
      vals[i] = vals[smallest];
      vals[smallest] = tmp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L11
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L8
L11:
  nop
L8:
  leave
  ret
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  if (a == b)
    return;
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```