user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sampleStats>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %eax,%ebp
  add    $0x1,%rax
  mov    -0x4(%rdi,%rax,4),%edx
  test   %edx,%edx
  je     L64
  sub    $0x1,%esi
  movslq %esi,%rax
  nopl   0x0(%rax)
L19:
  mov    %eax,%ebx
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%ecx
  test   %ecx,%ecx
  je     L19
  cmp    %ebx,%ebp
  jg     L48
  movslq %ebp,%rax
  mov    %edx,%esi
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  mov    %rax,%r10
  mov    %rax,%rcx
  xor    %r13d,%r13d
  xor    %r9d,%r9d
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L167:
  mov    (%rdi,%rcx,4),%esi
L28:
  test   %esi,%esi
  je     L9
  mov    %esi,%r8d
  add    %esi,%r13d
  imul   %ecx,%r8d
  movslq %r8d,%r8
  add    %r8,%r14
  cmp    %r9d,%esi
  jle    L9
  mov    %ecx,%r15d
  mov    %esi,%r9d
L9:
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jge    L167
  test   $0x1,%r13b
  je     L122
  lea    -0x1(%r13),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  xor    %ecx,%ecx
  sar    %eax
L128:
  test   %edx,%edx
  je     L184
  add    %edx,%ecx
  cmp    %ecx,%eax
  jg     L184
  pxor   %xmm0,%xmm0
  cvtsi2sd %r10d,%xmm0
L165:
  mov    $0x28,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <malloc@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %ebp,%xmm1
  cvtsi2sd %r13d,%xmm2
  movsd  %xmm0,0x18(%rax)
  pxor   %xmm0,%xmm0
  cvtsi2sd %r15d,%xmm0
  movsd  %xmm1,(%rax)
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  movsd  %xmm0,0x20(%rax)
  movsd  %xmm1,0x8(%rax)
  pxor   %xmm1,%xmm1
  cvtsi2sd %r14,%xmm1
  divsd  %xmm2,%xmm1
  movsd  %xmm1,0x10(%rax)
  movl   $0x5,(%r12)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L184:
  add    $0x1,%r10
  cmp    %r10d,%ebx
  jl     L165
  mov    (%rdi,%r10,4),%edx
  jmp    L128
  cs nopw 0x0(%rax,%rax,1)
L122:
  mov    %r13d,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  shr    $0x1f,%r9d
  add    %r13d,%r9d
  sar    %r9d
  lea    -0x1(%r9),%r10d
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L20:
  mov    (%rdi,%rax,4),%edx
L18:
  test   %edx,%edx
  je     L138
  test   %r8b,%r8b
  jne    L202
  add    %edx,%ecx
  cmp    %r10d,%ecx
  jl     L138
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  cmp    %r9d,%ecx
  jg     L165
  mov    $0x1,%r8d
L138:
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L20
  jmp    L165
  nopw   0x0(%rax,%rax,1)
L202:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D9(%rip),%xmm0
  jmp    L165
  nopl   0x0(%rax)
L48:
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  jmp    L165
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double *sampleStats(int *count, int countSize, int *returnSize) {
  int min, max, max_cnt = 0, cnt = 0, most = 0;
  long sum = 0;
  double *ret;
  double middle;
  int i = 0;
  while (count[i++] == 0)
    ;
  min = i - 1;
  i = countSize - 1;
  while (count[i--] == 0)
    ;
  max = i + 1;
  for (i = min; i <= max; i++) {
    if (count[i] != 0) {
      cnt += count[i];
      sum += i * count[i];
      if (max_cnt < count[i]) {
        max_cnt = count[i];
        most = i;
      }
    }
  }
  if (cnt % 2 == 0) {
    int mid1 = cnt / 2 - 1, mid2 = cnt / 2, tmp_cnt = 0;
    unsigned char found = 0;
    for (i = min; i <= max; i++) {
      if (count[i] != 0) {
        if (found) {
          middle += (double)i;
          middle /= 2.0;
          break;
        }
        tmp_cnt += count[i];
        if (tmp_cnt < mid1) {
          continue;
        } else if (tmp_cnt > mid2) {
          middle = (double)i;
          break;
        } else {
          found = 1;
          middle = (double)i;
        }
      }
    }
  } else {
    int mid = (cnt - 1) / 2, tmp_cnt = 0;
    for (i = min; i <= max; i++) {
      if (count[i] != 0) {
        tmp_cnt += count[i];
        if (tmp_cnt < mid) {
          continue;
        } else {
          middle = (double)i;
          break;
        }
      }
    }
  }
  ret = (double *)malloc(sizeof(double) * 5);
  ret[0] = (double)min;
  ret[1] = (double)max;
  ret[2] = (double)sum / (double)cnt;
  ret[3] = (double)middle;
  ret[4] = (double)most;
  *returnSize = 5;
  return ret;
}
```