ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<base64encode>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%r9
  movabs $0x504f4e4d4c4b4a49,%r10
  mov    %r9,(%rsp)
  mov    %r10,0x8(%rsp)
  movabs $0x5857565554535251,%r9
  movabs $0x6665646362615a59,%r10
  mov    %r9,0x10(%rsp)
  mov    %r10,0x18(%rsp)
  movabs $0x6e6d6c6b6a696867,%r9
  movabs $0x767574737271706f,%r10
  mov    %r9,0x20(%rsp)
  mov    %r10,0x28(%rsp)
  movabs $0x333231307a797877,%r9
  movabs $0x2f2b393837363534,%r10
  mov    %r9,0x30(%rsp)
  mov    %r10,0x38(%rsp)
  movb   $0x0,0x40(%rsp)
  test   %edx,%edx
  jle    L22
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r8
  mov    $0x0,%edx
  mov    $0x0,%ecx
L71:
  shl    $0x8,%edx
  add    $0x8,%ecx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  or     %eax,%edx
  cmp    $0x5,%ecx
  jle    L36
L74:
  sub    $0x6,%ecx
  add    $0x1,%rsi
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x3f,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x5,%ecx
  jg     L74
L36:
  cmp    %rdi,%r8
  jne    L71
  cmp    $0x4,%ecx
  je     L37
  cmp    $0x2,%ecx
  jne    L22
  shl    $0x4,%edx
  and    $0x30,%edx
  movzbl (%rsp,%rdx,1),%eax
  mov    %al,(%rsi)
  movb   $0x3d,0x1(%rsi)
  movb   $0x3d,0x2(%rsi)
  lea    0x3(%rsi),%rsi
  jmp    L22
L37:
  shl    $0x2,%edx
  and    $0x3c,%edx
  movzbl (%rsp,%rdx,1),%eax
  mov    %al,(%rsi)
  movb   $0x3d,0x1(%rsi)
  lea    0x2(%rsi),%rsi
L22:
  movb   $0x0,(%rsi)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x58,%rsp
  ret
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void base64encode(const unsigned char *in, char *out, int len) {
  char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int shift = 0;
  int accum = 0;
  while (len > 0) {
    len--;
    accum <<= 8;
    shift += 8;
    accum |= *in++;
    while (shift >= 6) {
      shift -= 6;
      *out++ = alphabet[(accum >> shift) & 0x3F];
    }
  }
  if (shift == 4) {
    *out++ = alphabet[(accum & 0xF) << 2];
    *out++ = '=';
  } else if (shift == 2) {
    *out++ = alphabet[(accum & 0x3) << 4];
    *out++ = '=';
    *out++ = '=';
  }
  *out++ = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<base64encode>:
  endbr64
  sub    $0x58,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x40(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  test   %edx,%edx
  jle    L38
  movslq %edx,%rdx
  xor    %ecx,%ecx
  lea    (%rdi,%rdx,1),%r8
  xor    %edx,%edx
  nop
L70:
  movzbl (%rdi),%eax
  shl    $0x8,%edx
  add    $0x1,%rdi
  add    $0x8,%ecx
  or     %eax,%edx
  nop
L69:
  sub    $0x6,%ecx
  mov    %edx,%eax
  add    $0x1,%rsi
  sar    %cl,%eax
  and    $0x3f,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x5,%ecx
  jg     L69
  cmp    %rdi,%r8
  jne    L70
  cmp    $0x4,%ecx
  je     L49
  cmp    $0x2,%ecx
  je     L23
L38:
  movb   $0x0,(%rsi)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x58,%rsp
  ret
L23:
  shl    $0x4,%edx
  add    $0x3,%rsi
  and    $0x30,%edx
  movzbl (%rsp,%rdx,1),%eax
  mov    %al,-0x3(%rsi)
  mov    $0x3d3d,%eax
  mov    %ax,-0x2(%rsi)
  jmp    L38
L49:
  shl    $0x2,%edx
  movb   $0x3d,0x1(%rsi)
  add    $0x2,%rsi
  and    $0x3c,%edx
  movzbl (%rsp,%rdx,1),%eax
  mov    %al,-0x2(%rsi)
  jmp    L38
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D20
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D8
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D7
type_guessed: byte[16]

tool: {"D12": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D20": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D8": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D7": [0x77,0x78,0x79,0x7a,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x2b,0x2f]}

assistant: ```c
void base64encode(const unsigned char *in, char *out, int len) {
  char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int shift = 0;
  int accum = 0;
  while (len > 0) {
    len--;
    accum <<= 8;
    shift += 8;
    accum |= *in++;
    while (shift >= 6) {
      shift -= 6;
      *out++ = alphabet[(accum >> shift) & 0x3F];
    }
  }
  if (shift == 4) {
    *out++ = alphabet[(accum & 0xF) << 2];
    *out++ = '=';
  } else if (shift == 2) {
    *out++ = alphabet[(accum & 0x3) << 4];
    *out++ = '=';
    *out++ = '=';
  }
  *out++ = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<base64encode>:
  endbr64
  sub    $0x58,%rsp
  movdqa D39(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x40(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D14(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D28(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  test   %edx,%edx
  jle    L17
  movslq %edx,%rdx
  xor    %r8d,%r8d
  lea    (%rdi,%rdx,1),%r9
  jmp    L27
L72:
  mov    %eax,%edx
  sub    $0x4,%r8d
  add    $0x2,%rsi
  and    $0x3f,%edx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  cmp    %rdi,%r9
  je     L34
L27:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  lea    0x2(%r8),%ecx
  add    $0x1,%rdi
  lea    0x1(%rsi),%r10
  or     %edx,%eax
  mov    %eax,%edx
  sar    %cl,%edx
  and    $0x3f,%edx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,(%rsi)
  cmp    $0x5,%ecx
  jg     L72
  mov    %r10,%rsi
  mov    %ecx,%r8d
  cmp    %rdi,%r9
  jne    L27
  nopw   0x0(%rax,%rax,1)
L34:
  cmp    $0x4,%r8d
  je     L84
  cmp    $0x2,%r8d
  je     L6
L17:
  movb   $0x0,(%rsi)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  ret
L6:
  shl    $0x4,%eax
  add    $0x3,%rsi
  and    $0x30,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x3(%rsi)
  mov    $0x3d3d,%eax
  mov    %ax,-0x2(%rsi)
  jmp    L17
L84:
  shl    $0x2,%eax
  movb   $0x3d,0x1(%rsi)
  add    $0x2,%rsi
  and    $0x3c,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x2(%rsi)
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D39
type_infered: byte[16]
name: retrieve_data
arguments: tag: D1
type_infered: byte[16]
name: retrieve_data
arguments: tag: D14
type_infered: byte[16]
name: retrieve_data
arguments: tag: D28
type_infered: byte[16]

tool: {"D39": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D1": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D14": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D28": [0x77,0x78,0x79,0x7a,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x2b,0x2f]}

assistant: ```c
void base64encode(const unsigned char *in, char *out, int len) {
  char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int shift = 0;
  int accum = 0;
  while (len > 0) {
    len--;
    accum <<= 8;
    shift += 8;
    accum |= *in++;
    while (shift >= 6) {
      shift -= 6;
      *out++ = alphabet[(accum >> shift) & 0x3F];
    }
  }
  if (shift == 4) {
    *out++ = alphabet[(accum & 0xF) << 2];
    *out++ = '=';
  } else if (shift == 2) {
    *out++ = alphabet[(accum & 0x3) << 4];
    *out++ = '=';
    *out++ = '=';
  }
  *out++ = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x676e697274732061,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0x7961727261202c,%rax
  mov    %rax,-0x10(%rbp)
  lea    D54(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp1@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jns    L15
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L41
L15:
  cmpl   $0x0,-0x2c(%rbp)
  jle    L21
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L41
L21:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L41:
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp2@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D54
data_type: string
name: parse_data
arguments: label: D22
data_type: string
name: parse_data
arguments: label: D53
data_type: string
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D35
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D54: This is a string, pointer

tool: D22: %d (str1 < str2)


tool: D53: %d (str1 > str2)


tool: D30: %d (str1 == str2)


tool: D35: result=%d


tool: D8: 
Press any key to end...

assistant: ```c
int main() {
  char str1[] = "This is a string, array";
  char *str2 = "This is a string, pointer";
  int result;
  result = strcmp1(str1, str2);
  if (result < 0)
    printf("%d (str1 < str2)\n", result);
  else if (result > 0)
    printf("%d (str1 > str2)\n", result);
  else
    printf("%d (str1 == str2)\n", result);
  result = strcmp2(str1, str2);
  printf("result=%d\n", result);
  printf("\nPress any key to end...");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x676e697274732061,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x7961727261202c,%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rdi
  lea    D50(%rip),%rsi
  call   <strcmp1@plt>
  mov    %eax,%esi
  test   %eax,%eax
  js     L30
  jle    L16
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  mov    %rsp,%rdi
  lea    D50(%rip),%rsi
  call   <strcmp2@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L30:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L16:
  mov    $0x0,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D50
type: string
name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D33
type: string
name: retrieve_data
arguments: data_tag: D49
type: string
name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D30
type: string

tool: D50: This is a string, pointer

tool: D11: %d (str1 > str2)


tool: D33: result=%d


tool: D49: 
Press any key to end...

tool: D15: %d (str1 < str2)


tool: D30: %d (str1 == str2)


assistant: ```c
int main() {
  char str1[] = "This is a string, array";
  char *str2 = "This is a string, pointer";
  int result;
  result = strcmp1(str1, str2);
  if (result < 0)
    printf("%d (str1 < str2)\n", result);
  else if (result > 0)
    printf("%d (str1 > str2)\n", result);
  else
    printf("%d (str1 == str2)\n", result);
  result = strcmp2(str1, str2);
  printf("result=%d\n", result);
  printf("\nPress any key to end...");
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  sub    $0x28,%rsp
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movabs $0x7961727261202c,%rax
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <strcmp1@plt>
  mov    %eax,%esi
  test   %eax,%eax
  js     L45
  jne    L20
  xor    %esi,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp2@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
L45:
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: byte[16]
name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D28
type_guessed: string
name: retrieve_data
arguments: data_tag: D40
type_guessed: string

tool: D20: This is a string, pointer

tool: {"D25": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x73,0x74,0x72,0x69,0x6e,0x67]}

tool: D21: %d (str1 == str2)


tool: D24: result=%d


tool: D29: 
Press any key to end...

tool: D28: %d (str1 > str2)


tool: D40: %d (str1 < str2)


assistant: ```c
int main() {
  char str1[] = "This is a string, array";
  char *str2 = "This is a string, pointer";
  int result;
  result = strcmp1(str1, str2);
  if (result < 0)
    printf("%d (str1 < str2)\n", result);
  else if (result > 0)
    printf("%d (str1 > str2)\n", result);
  else
    printf("%d (str1 == str2)\n", result);
  result = strcmp2(str1, str2);
  printf("result=%d\n", result);
  printf("\nPress any key to end...");
  getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  sub    $0x28,%rsp
  movdqa D66(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movabs $0x7961727261202c,%rax
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <strcmp1@plt>
  mov    %eax,%esi
  test   %eax,%eax
  js     L47
  jne    L8
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp2@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    D59(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L47:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D66
type_guessed: byte[16]
name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D24
type_guessed: string
name: read_data
arguments: tag: D59
type_guessed: string
name: read_data
arguments: tag: D56
type_guessed: string
name: read_data
arguments: tag: D38
type_guessed: string

tool: D23: This is a string, pointer

tool: {"D66": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x73,0x74,0x72,0x69,0x6e,0x67]}

tool: D11: %d (str1 == str2)


tool: D24: result=%d


tool: D59: 
Press any key to end...

tool: D56: %d (str1 > str2)


tool: D38: %d (str1 < str2)


assistant: ```c
int main() {
  char str1[] = "This is a string, array";
  char *str2 = "This is a string, pointer";
  int result;
  result = strcmp1(str1, str2);
  if (result < 0)
    printf("%d (str1 < str2)\n", result);
  else if (result > 0)
    printf("%d (str1 > str2)\n", result);
  else
    printf("%d (str1 == str2)\n", result);
  result = strcmp2(str1, str2);
  printf("result=%d\n", result);
  printf("\nPress any key to end...");
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<month_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L29
  cmpl   $0xc,-0x4(%rbp)
  jle    L14
L29:
  mov    D12(%rip),%rax
  jmp    L6
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%rax
L6:
  pop    %rbp
  ret
```

assistant: ```c
char *month_name(int n) {
  static char *names[] = {"Illegal Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? names[0] : names[n];
}
```
user: Translate the below assembly code into C programming language:

```asm
<month_name>:
  endbr64
  lea    -0x1(%rdi),%edx
  lea    D2(%rip),%rax
  cmp    $0xb,%edx
  ja     L8
  movslq %edi,%rdi
  lea    D12(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L8:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: Illegal Month

assistant: ```c
char *month_name(int n) {
  static char *names[] = {"Illegal Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? names[0] : names[n];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<month_name>:
  endbr64
  lea    -0x1(%rdi),%edx
  lea    D15(%rip),%rax
  cmp    $0xb,%edx
  ja     L9
  movslq %edi,%rdi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L9:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string

tool: D15: Illegal Month

assistant: ```c
char *month_name(int n) {
  static char *names[] = {"Illegal Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? names[0] : names[n];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<month_name>:
  endbr64
  lea    -0x1(%rdi),%edx
  lea    D15(%rip),%rax
  cmp    $0xb,%edx
  ja     L7
  movslq %edi,%rdi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L7:
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
type_infered: string

tool: D15: Illegal Month

assistant: ```c
char *month_name(int n) {
  static char *names[] = {"Illegal Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? names[0] : names[n];
}
```
user: What is the c source code of the assembly code below:

```asm
<pass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: PASS

assistant: ```c
int pass(char *msg) {
  printf("%s\n", msg);
  printf("PASS\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pass>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: PASS

assistant: ```c
int pass(char *msg) {
  printf("%s\n", msg);
  printf("PASS\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pass>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: PASS

assistant: ```c
int pass(char *msg) {
  printf("%s\n", msg);
  printf("PASS\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pass>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: PASS

assistant: ```c
int pass(char *msg) {
  printf("%s\n", msg);
  printf("PASS\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dec_to_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L13:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x4(%rbp)
  sarl   -0x1c(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *dec_to_bin(char *bin, int dec, int nbr_bits) {
  int i;
  bin[nbr_bits] = '\0';
  for (i = nbr_bits - 1; i >= 0; --i, dec >>= 1) {
    bin[i] = (dec & 1) + '0';
  }
  return bin;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dec_to_bin>:
  endbr64
  movslq %edx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  mov    %edx,%eax
  sub    $0x1,%eax
  js     L12
  cltq
  add    %rdi,%rax
  lea    -0x2(%rdi,%rcx,1),%rcx
  lea    -0x1(%rdx),%edx
  sub    %rdx,%rcx
L2:
  mov    %esi,%edx
  and    $0x1,%edx
  add    $0x30,%edx
  mov    %dl,(%rax)
  sar    %esi
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L2
L12:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *dec_to_bin(char *bin, int dec, int nbr_bits) {
  int i;
  bin[nbr_bits] = '\0';
  for (i = nbr_bits - 1; i >= 0; --i, dec >>= 1) {
    bin[i] = (dec & 1) + '0';
  }
  return bin;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dec_to_bin>:
  endbr64
  movslq %edx,%rcx
  mov    %rdi,%r8
  movb   $0x0,(%rdi,%rcx,1)
  sub    $0x1,%edx
  js     L17
  movslq %edx,%rax
  lea    -0x2(%rdi,%rcx,1),%rcx
  mov    %edx,%edx
  add    %rdi,%rax
  sub    %rdx,%rcx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %esi,%edx
  sub    $0x1,%rax
  sar    %esi
  and    $0x1,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  cmp    %rcx,%rax
  jne    L1
L17:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *dec_to_bin(char *bin, int dec, int nbr_bits) {
  int i;
  bin[nbr_bits] = '\0';
  for (i = nbr_bits - 1; i >= 0; --i, dec >>= 1) {
    bin[i] = (dec & 1) + '0';
  }
  return bin;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dec_to_bin>:
  endbr64
  movslq %edx,%rcx
  mov    %rdi,%r8
  movb   $0x0,(%rdi,%rcx,1)
  sub    $0x1,%edx
  js     L10
  movslq %edx,%rax
  lea    -0x2(%rdi,%rcx,1),%rcx
  mov    %edx,%edx
  add    %rdi,%rax
  sub    %rdx,%rcx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %esi,%edx
  sub    $0x1,%rax
  sar    %esi
  and    $0x1,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  cmp    %rax,%rcx
  jne    L0
L10:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *dec_to_bin(char *bin, int dec, int nbr_bits) {
  int i;
  bin[nbr_bits] = '\0';
  for (i = nbr_bits - 1; i >= 0; --i, dec >>= 1) {
    bin[i] = (dec & 1) + '0';
  }
  return bin;
}
```