ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x78(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <index@plt>
  mov    %rax,-0x68(%rbp)
  cmpq   $0x0,-0x68(%rbp)
  je     L42
  mov    -0x68(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x68(%rbp)
  movb   $0x0,(%rax)
  mov    -0x78(%rbp),%rax
  mov    (%rax),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x78(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x68(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L41
L45:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    -0x60(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L65
  mov    $0x0,%eax
  jmp    L68
L65:
  addl   $0x1,-0x6c(%rbp)
L41:
  mov    -0x6c(%rbp),%eax
  cltq
  lea    -0x60(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  jmp    L68
L42:
  mov    $0x1,%eax
L68:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int get_number(char **name) {
  int i;
  char *ppos;
  char number[80] = "";
  if (ppos = index(*name, '.')) {
    *ppos++ = '\0';
    strcpy(number, *name);
    strcpy(*name, ppos);
    for (i = 0; *(number + i); i++)
      if (!isdigit(*(number + i)))
        return (0);
    return (atoi(number));
  }
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  mov    $0x2e,%esi
  mov    (%rdi),%rdi
  call   <index@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L40
  movb   $0x0,(%rbx)
  mov    %rsp,%rdi
  mov    0x0(%rbp),%rsi
  call   <strcpy@plt>
  lea    0x1(%rbx),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcpy@plt>
  movzbl (%rsp),%edi
  test   %dil,%dil
  je     L19
  lea    0x1(%rsp),%rbx
L31:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L40
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L31
L19:
  mov    %rsp,%rdi
  call   <atoi@plt>
L40:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_number(char **name) {
  int i;
  char *ppos;
  char number[80] = "";
  if (ppos = index(*name, '.')) {
    *ppos++ = '\0';
    strcpy(number, *name);
    strcpy(*name, ppos);
    for (i = 0; *(number + i); i++)
      if (!isdigit(*(number + i)))
        return (0);
    return (atoi(number));
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_number>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  pxor   %xmm0,%xmm0
  mov    $0x2e,%esi
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <index@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L8
  movb   $0x0,(%rbx)
  mov    %rsp,%rbp
  mov    (%r12),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    (%r12),%rdi
  lea    0x1(%rbx),%rsi
  call   <strcpy@plt>
  movsbl (%rsp),%edi
  test   %dil,%dil
  je     L1
  lea    0x1(%rsp),%rbx
  jmp    L13
  nopl   0x0(%rax)
L34:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L1
L13:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L34
L8:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <atoi@plt>
  jmp    L8
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_number(char **name) {
  int i;
  char *ppos;
  char number[80] = "";
  if (ppos = index(*name, '.')) {
    *ppos++ = '\0';
    strcpy(number, *name);
    strcpy(*name, ppos);
    for (i = 0; *(number + i); i++)
      if (!isdigit(*(number + i)))
        return (0);
    return (atoi(number));
  }
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_number>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  pxor   %xmm0,%xmm0
  mov    $0x2e,%esi
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <index@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L0
  movb   $0x0,(%rbx)
  mov    %rsp,%rbp
  mov    (%r12),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    (%r12),%rdi
  lea    0x1(%rbx),%rsi
  call   <strcpy@plt>
  movsbl (%rsp),%edi
  test   %dil,%dil
  je     L51
  lea    0x1(%rsp),%rbx
  jmp    L15
  nopl   0x0(%rax)
L33:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L51
L15:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L33
L0:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L51:
  mov    %rbp,%rdi
  call   <atoi@plt>
  jmp    L0
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_number(char **name) {
  int i;
  char *ppos;
  char number[80] = "";
  if (ppos = index(*name, '.')) {
    *ppos++ = '\0';
    strcpy(number, *name);
    strcpy(*name, ppos);
    for (i = 0; *(number + i); i++)
      if (!isdigit(*(number + i)))
        return (0);
    return (atoi(number));
  }
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<enginePageCalc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dl,-0x14(%rbp)
  mov    %ecx,%edx
  mov    %dx,-0x18(%rbp)
  mov    %ax,-0x1c(%rbp)
  movsbl -0x14(%rbp),%eax
  cmp    $0x3,%eax
  je     L66
  cmp    $0x3,%eax
  jg     L0
  cmp    $0x2,%eax
  je     L49
  cmp    $0x2,%eax
  jg     L0
  test   %eax,%eax
  je     L7
  cmp    $0x1,%eax
  je     L90
  jmp    L0
L7:
  movzwl -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x2(%rbp)
  jmp    L0
L90:
  movzwl -0x1c(%rbp),%eax
  mov    %ax,-0x2(%rbp)
  jmp    L0
L49:
  movswl -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  movzwl -0x18(%rbp),%eax
  imul   %edx,%eax
  mov    %ax,-0x2(%rbp)
  jmp    L0
L66:
  movswl -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  movzwl -0x18(%rbp),%eax
  imul   %edx,%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
  nop
L0:
  movswl -0x2(%rbp),%eax
  mov    %eax,%edi
  call   <itoa@plt>
  leave
  ret
```

assistant: ```c
char *enginePageCalc(char pagecalc, short rpp, short page) {
  short n;
  switch (pagecalc) {
  case 0:
    n = (page - 1);
    break;
  case 1:
    n = (page - 1) + 1;
    break;
  case 2:
    n = rpp * (page - 1);
    break;
  case 3:
    n = (rpp * (page - 1)) + 1;
    break;
  }
  return itoa(n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<enginePageCalc>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%dil
  je     L30
  mov    %edx,%eax
  jg     L8
  sub    $0x1,%edx
  test   %dil,%dil
  cmove  %edx,%eax
L27:
  movswl %ax,%edi
  call   <itoa@plt>
  add    $0x8,%rsp
  ret
L8:
  cmp    $0x3,%dil
  jne    L27
  sub    $0x1,%edx
  imul   %esi,%edx
  lea    0x1(%rdx),%eax
  jmp    L27
L30:
  lea    -0x1(%rdx),%eax
  imul   %esi,%eax
  jmp    L27
```

assistant: ```c
char *enginePageCalc(char pagecalc, short rpp, short page) {
  short n;
  switch (pagecalc) {
  case 0:
    n = (page - 1);
    break;
  case 1:
    n = (page - 1) + 1;
    break;
  case 2:
    n = rpp * (page - 1);
    break;
  case 3:
    n = (rpp * (page - 1)) + 1;
    break;
  }
  return itoa(n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<enginePageCalc>:
  endbr64
  mov    %edx,%eax
  cmp    $0x2,%dil
  je     L2
  jg     L13
  sub    $0x1,%edx
  test   %dil,%dil
  cmove  %edx,%eax
L1:
  movswl %ax,%edi
  jmp    1050 <itoa@plt>
  nop
L13:
  cmp    $0x3,%dil
  jne    L1
  sub    $0x1,%edx
  imul   %esi,%edx
  lea    0x1(%rdx),%eax
  movswl %ax,%edi
  jmp    1050 <itoa@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  lea    -0x1(%rdx),%eax
  imul   %esi,%eax
  movswl %ax,%edi
  jmp    1050 <itoa@plt>
```

assistant: ```c
char *enginePageCalc(char pagecalc, short rpp, short page) {
  short n;
  switch (pagecalc) {
  case 0:
    n = (page - 1);
    break;
  case 1:
    n = (page - 1) + 1;
    break;
  case 2:
    n = rpp * (page - 1);
    break;
  case 3:
    n = (rpp * (page - 1)) + 1;
    break;
  }
  return itoa(n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<enginePageCalc>:
  endbr64
  mov    %edx,%eax
  cmp    $0x2,%dil
  je     L29
  jg     L17
  sub    $0x1,%edx
  test   %dil,%dil
  cmove  %edx,%eax
L27:
  movswl %ax,%edi
  jmp    1050 <itoa@plt>
  nop
L17:
  cmp    $0x3,%dil
  jne    L27
  sub    $0x1,%edx
  imul   %esi,%edx
  lea    0x1(%rdx),%eax
  movswl %ax,%edi
  jmp    1050 <itoa@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  lea    -0x1(%rdx),%eax
  imul   %esi,%eax
  movswl %ax,%edi
  jmp    1050 <itoa@plt>
```

assistant: ```c
char *enginePageCalc(char pagecalc, short rpp, short page) {
  short n;
  switch (pagecalc) {
  case 0:
    n = (page - 1);
    break;
  case 1:
    n = (page - 1) + 1;
    break;
  case 2:
    n = rpp * (page - 1);
    break;
  case 3:
    n = (rpp * (page - 1)) + 1;
    break;
  }
  return itoa(n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L9
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L10
L9:
  nop
L10:
  leave
  ret
```

assistant: ```c
void shift(char *seq, int step) {
  int len;
  len = strlen(seq);
  if ((step %= len) == 0)
    return;
  reverse(seq, 0, step - 1);
  reverse(seq, step, len - 1);
  reverse(seq, 0, len - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shift>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L18
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %edx,%ebp
  lea    -0x1(%rdx),%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <reverse@plt>
  sub    $0x1,%ebx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <reverse@plt>
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <reverse@plt>
  jmp    L3
```

assistant: ```c
void shift(char *seq, int step) {
  int len;
  len = strlen(seq);
  if ((step %= len) == 0)
    return;
  reverse(seq, 0, step - 1);
  reverse(seq, step, len - 1);
  reverse(seq, 0, len - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shift>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  lea    -0x1(%rbx),%r12d
  mov    %edx,%r13d
  mov    %rbp,%rdi
  xor    %esi,%esi
  lea    -0x1(%rdx),%edx
  call   <reverse@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <reverse@plt>
```

assistant: ```c
void shift(char *seq, int step) {
  int len;
  len = strlen(seq);
  if ((step %= len) == 0)
    return;
  reverse(seq, 0, step - 1);
  reverse(seq, step, len - 1);
  reverse(seq, 0, len - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  lea    -0x1(%rbx),%r12d
  mov    %edx,%r13d
  mov    %rbp,%rdi
  xor    %esi,%esi
  lea    -0x1(%rdx),%edx
  call   <reverse@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <reverse@plt>
```

assistant: ```c
void shift(char *seq, int step) {
  int len;
  len = strlen(seq);
  if ((step %= len) == 0)
    return;
  reverse(seq, 0, step - 1);
  reverse(seq, step, len - 1);
  reverse(seq, 0, len - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ephMSTG>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <ephCalcT@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D46(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D49(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  -0x8(%rbp),%xmm0
  movsd  D40(%rip),%xmm4
  movapd %xmm0,%xmm3
  divsd  %xmm4,%xmm3
  movsd  D17(%rip),%xmm0
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <ephAngleRed@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D46
type_guessed: f64
name: read_data
arguments: label: D49
type_guessed: f64
name: read_data
arguments: label: D15
type_guessed: f64
name: read_data
arguments: label: D40
type_guessed: f64
name: read_data
arguments: label: D17
type_guessed: f64

tool: D46: 2451545

tool: D49: 360.98564736629

tool: D15: 280.46061837

tool: D40: 38710000

tool: D17: 0.000387933

assistant: ```c
double ephMSTG(double jd) {
  double t;
  t = ephCalcT(jd);
  return ephAngleRed(280.46061837 + 360.98564736629 * (jd - 2451545.0) + t * t * (0.000387933 - t / 38710000.0));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ephMSTG>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <ephCalcT@plt>
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  divsd  D48(%rip),%xmm2
  movsd  D6(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  movq   %rbx,%xmm1
  subsd  D12(%rip),%xmm1
  mulsd  D9(%rip),%xmm1
  addsd  D30(%rip),%xmm1
  addsd  %xmm1,%xmm0
  call   <ephAngleRed@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D48
type: f64
name: parse_data
arguments: tag: D6
type: f64
name: parse_data
arguments: tag: D12
type: f64
name: parse_data
arguments: tag: D9
type: f64
name: parse_data
arguments: tag: D30
type: f64

tool: D48: 38710000

tool: D6: 0.000387933

tool: D12: 2451545

tool: D9: 360.98564736629

tool: D30: 280.46061837

assistant: ```c
double ephMSTG(double jd) {
  double t;
  t = ephCalcT(jd);
  return ephAngleRed(280.46061837 + 360.98564736629 * (jd - 2451545.0) + t * t * (0.000387933 - t / 38710000.0));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ephMSTG>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ephCalcT@plt>
  movsd  0x8(%rsp),%xmm1
  subsd  D32(%rip),%xmm1
  mulsd  D7(%rip),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  movsd  D30(%rip),%xmm0
  mulsd  %xmm2,%xmm2
  divsd  D3(%rip),%xmm3
  addsd  D13(%rip),%xmm1
  add    $0x18,%rsp
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  jmp    1060 <ephAngleRed@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
type: f64
name: extract_symbolic_data
arguments: data_tag: D7
type: f64
name: extract_symbolic_data
arguments: data_tag: D30
type: f64
name: extract_symbolic_data
arguments: data_tag: D3
type: f64
name: extract_symbolic_data
arguments: data_tag: D13
type: f64

tool: D32: 2451545

tool: D7: 360.98564736629

tool: D30: 0.000387933

tool: D3: 38710000

tool: D13: 280.46061837

assistant: ```c
double ephMSTG(double jd) {
  double t;
  t = ephCalcT(jd);
  return ephAngleRed(280.46061837 + 360.98564736629 * (jd - 2451545.0) + t * t * (0.000387933 - t / 38710000.0));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ephMSTG>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ephCalcT@plt>
  movsd  0x8(%rsp),%xmm1
  subsd  D17(%rip),%xmm1
  mulsd  D16(%rip),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  movsd  D22(%rip),%xmm0
  mulsd  %xmm2,%xmm2
  divsd  D14(%rip),%xmm3
  addsd  D9(%rip),%xmm1
  add    $0x18,%rsp
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  jmp    1060 <ephAngleRed@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: f64
name: extract_symbolic_data
arguments: data_label: D16
data_type: f64
name: extract_symbolic_data
arguments: data_label: D22
data_type: f64
name: extract_symbolic_data
arguments: data_label: D14
data_type: f64
name: extract_symbolic_data
arguments: data_label: D9
data_type: f64

tool: D17: 2451545

tool: D16: 360.98564736629

tool: D22: 0.000387933

tool: D14: 38710000

tool: D9: 280.46061837

assistant: ```c
double ephMSTG(double jd) {
  double t;
  t = ephCalcT(jd);
  return ephAngleRed(280.46061837 + 360.98564736629 * (jd - 2451545.0) + t * t * (0.000387933 - t / 38710000.0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L28
  cmpl   $0x1,-0x4(%rbp)
  jne    L9
L28:
  mov    $0x1,%eax
  jmp    L17
L9:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fact>
  imul   -0x4(%rbp),%eax
L17:
  leave
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0 || n == 1)
    return 1;
  return (n * fact(n - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L2
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fact>
  imul   %ebx,%eax
  pop    %rbx
  ret
L2:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0 || n == 1)
    return 1;
  return (n * fact(n - 1));
}
```
user: What is the c source code of the assembly code below?

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L13
  xchg   %ax,%ax
L17:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L17
L13:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0 || n == 1)
    return 1;
  return (n * fact(n - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L14
  xchg   %ax,%ax
L9:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L9
L14:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0 || n == 1)
    return 1;
  return (n * fact(n - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<pause_detect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  cmpl   $0xfffffffe,-0x14(%rbp)
  jne    L5
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L47
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <difftime@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  comisd -0x8(%rbp),%xmm1
  jbe    L22
  mov    $0xffffffff,%eax
  jmp    L17
L47:
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L22
L5:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L22
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
L22:
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: f64

tool: D6: 5

assistant: ```c
int pause_detect(int ntrans, time_t *p_pause) {
  time_t now = 0;
  const double MAX_PAUSE_SEC = 5.0;
  assert(p_pause);
  if (-2 == ntrans) {
    now = time(NULL);
    if (*p_pause) {
      if (difftime(now, *p_pause) > MAX_PAUSE_SEC) {
        ((void)0);
        return -1;
      }
    } else {
      *p_pause = now;
      ((void)0);
    }
  } else {
    if (*p_pause) {
      *p_pause = 0;
      ((void)0);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pause_detect>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <assert@plt>
  cmp    $0xfffffffe,%ebp
  je     L25
  mov    $0x0,%eax
  cmpq   $0x0,(%rbx)
  je     L48
  movq   $0x0,(%rbx)
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x0,%edi
  call   <time@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L39
  mov    %rax,(%rbx)
  mov    $0x0,%eax
  jmp    L48
L39:
  mov    %rax,%rdi
  call   <difftime@plt>
  comisd D0(%rip),%xmm0
  seta   %al
  movzbl %al,%eax
  neg    %eax
  jmp    L48
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: f64

tool: D0: 5

assistant: ```c
int pause_detect(int ntrans, time_t *p_pause) {
  time_t now = 0;
  const double MAX_PAUSE_SEC = 5.0;
  assert(p_pause);
  if (-2 == ntrans) {
    now = time(NULL);
    if (*p_pause) {
      if (difftime(now, *p_pause) > MAX_PAUSE_SEC) {
        ((void)0);
        return -1;
      }
    } else {
      *p_pause = now;
      ((void)0);
    }
  } else {
    if (*p_pause) {
      *p_pause = 0;
      ((void)0);
    }
  }
  return 0;
}
```