user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L61:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L61
  sub    $0x28,%rsp
  lea    D16(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x30018(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x210(%rsp),%r14
  lea    0x10210(%rsp),%rbx
L99:
  lea    -0x200(%r14),%rbp
L101:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r14,%rbp
  jne    L101
  lea    0x200(%rbp),%r14
  cmp    %rbx,%r14
  jne    L99
  lea    0x20210(%rsp),%rax
  lea    0x10010(%rsp),%rbp
  mov    %rbx,%r14
  mov    %rax,0x8(%rsp)
L107:
  lea    -0x200(%r14),%r15
L103:
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    %r14,%r15
  jne    L103
  lea    0x200(%r15),%r14
  cmp    0x8(%rsp),%r14
  jne    L107
  lea    0x20010(%rsp),%r9
  xor    %r10d,%r10d
  lea    0x10000(%rbp),%r11
  xor    %eax,%eax
  mov    %r9,%r8
L23:
  lea    0x8(%r8),%rdi
  mov    %r8,%rcx
  mov    %r10,%r14
  mov    %r11,%rsi
  and    $0xfffffffffffffff8,%rdi
  shl    $0x9,%r14
  movq   $0x0,(%r8)
  mov    %r8,%r13
  sub    %rdi,%rcx
  add    %r12,%r14
  movq   $0x0,0x1f8(%r8)
  add    $0x200,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
L98:
  mov    %rdi,%rdx
  mov    %r14,%rcx
  pxor   %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L72:
  movss  (%rcx),%xmm0
  add    $0x200,%rdx
  add    $0x4,%rcx
  shufps $0x0,%xmm0,%xmm0
  mulps  -0x200(%rdx),%xmm0
  addps  %xmm0,%xmm1
  cmp    %rsi,%rdx
  jne    L72
  add    $0x10,%rdi
  movaps %xmm1,0x0(%r13)
  lea    0x10(%rdx),%rsi
  add    $0x10,%r13
  cmp    %rbx,%rdi
  jne    L98
  add    $0x1,%r10
  add    $0x200,%r8
  cmp    $0x80,%r10
  jne    L23
  lea    0x200(%r9),%rbp
  lea    0x10200(%r9),%r13
  lea    D12(%rip),%r12
L87:
  lea    -0x200(%rbp),%rbx
L22:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L22
  mov    $0xa,%edi
  add    $0x200,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L87
  mov    0x30018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x30028,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D12
type_guessed: string

tool: D16:  %f

tool: D12: %6.2f 

assistant: ```c
int main() {
  int i, j, k;
  float a[128][128], b[128][128], c[128][128];
  for (i = 0; i < 128; i++)
    for (j = 0; j < 128; j++)
      scanf(" %f", &a[i][j]);
  for (i = 0; i < 128; i++)
    for (j = 0; j < 128; j++)
      scanf(" %f", &b[i][j]);
#pragma scop
  for (i = 0; i < 128; i++)
    for (j = 0; j < 128; j++) {
      c[i][j] = 0.0;
      for (k = 0; k < 128; k++)
        c[i][j] = c[i][j] + a[i][k] * b[k][j];
    }
#pragma endscop
  for (i = 0; i < 128; i++) {
    for (j = 0; j < 128; j++)
      printf("%6.2f ", c[i][j]);
    printf("\n");
  }
  return 0;
}
```