ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<make_sha256_salt_para>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L5
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L12
L5:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L10:
  pop    %rbx
  ret
L12:
  mov    %rbx,%rcx
  lea    D25(%rip),%rdx
  mov    $0x15,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D25
type_guessed: string

tool: D13: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D25: $5$%s$

assistant: ```c
char *make_sha256_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$5$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_sha256_salt_para>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L14
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L1
L14:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rcx
  lea    D13(%rip),%r12
  lea    D20(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string

tool: D16: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D20: $5$%s$

assistant: ```c
char *make_sha256_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$5$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<make_sha256_salt_para>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L0
L7:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rcx
  lea    D18(%rip),%r12
  lea    D9(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D28
data_type: string
name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D28: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D9: $5$%s$

assistant: ```c
char *make_sha256_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$5$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<comp_name_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <comp_name@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <comp_value@plt>
  jmp    L9
L0:
  mov    -0x4(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int comp_name_value(const void *a, const void *b) {
  int res;
  res = comp_name(a, b);
  return res ? res : comp_value(a, b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<comp_name_value>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <comp_name@plt>
  test   %eax,%eax
  je     L7
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <comp_value@plt>
  jmp    L11
```

assistant: ```c
int comp_name_value(const void *a, const void *b) {
  int res;
  res = comp_name(a, b);
  return res ? res : comp_value(a, b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<comp_name_value>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <comp_name@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <comp_value@plt>
```

assistant: ```c
int comp_name_value(const void *a, const void *b) {
  int res;
  res = comp_name(a, b);
  return res ? res : comp_value(a, b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comp_name_value>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <comp_name@plt>
  test   %eax,%eax
  je     L7
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <comp_value@plt>
```

assistant: ```c
int comp_name_value(const void *a, const void *b) {
  int res;
  res = comp_name(a, b);
  return res ? res : comp_value(a, b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ntransform>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mulmn@plt>
  addq   $0xc,-0x18(%rbp)
  subl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  jg     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void ntransform(float *src, int num, const float *to) {
  int i;
  for (i = num; i > 0; i--) {
    mulmn(src, to, src);
    src += 3;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ntransform>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %esi,%esi
  lea    (%rsi,%rsi,2),%rax
  lea    (%rdi,%rax,4),%r12
L13:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mulmn@plt>
  add    $0xc,%rbx
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void ntransform(float *src, int num, const float *to) {
  int i;
  for (i = num; i > 0; i--) {
    mulmn(src, to, src);
    src += 3;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ntransform>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  push   %r12
  lea    (%rsi,%rsi,2),%rax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    (%rdi,%rax,4),%r12
  mov    %rdi,%rbx
  nopl   (%rax)
L15:
  mov    %rbx,%rdx
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  add    $0xc,%rbx
  call   <mulmn@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
void ntransform(float *src, int num, const float *to) {
  int i;
  for (i = num; i > 0; i--) {
    mulmn(src, to, src);
    src += 3;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ntransform>:
  endbr64
  test   %esi,%esi
  jle    L3
  movslq %esi,%rsi
  push   %r12
  lea    (%rsi,%rsi,2),%rax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    (%rdi,%rax,4),%r12
  mov    %rdi,%rbx
  nopl   (%rax)
L5:
  mov    %rbx,%rdx
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  add    $0xc,%rbx
  call   <mulmn@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void ntransform(float *src, int num, const float *to) {
  int i;
  for (i = num; i > 0; i--) {
    mulmn(src, to, src);
    src += 3;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<url_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x25,%eax
  je     L77
  cmp    $0x2b,%eax
  je     L60
  jmp    L19
L77:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L12
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L12
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <TwoHex2Int@plt>
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x2,-0x18(%rbp)
  jmp    L12
L60:
  cmpl   $0x0,-0x1c(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x20,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L12
L19:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void url_decode(char *p, int queryString) {
  char *pD = p;
  while (*p) {
    switch (*p) {
    case '%':
      p++;
      if (isxdigit(p[0]) && isxdigit(p[1])) {
        *pD++ = (char)TwoHex2Int(p);
        p += 2;
      }
      break;
    case '+':
      if (queryString) {
        *pD++ = ' ';
        p++;
        break;
      }
    default:
      *pD++ = *p++;
    }
  }
  *pD = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<url_decode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L64
  mov    %esi,%r12d
  mov    %rdi,%rbp
  jmp    L23
L48:
  lea    0x1(%rbx),%r13
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L24
  mov    %r13,%rbx
  jmp    L78
L24:
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L72
  mov    %r13,%rbx
  jmp    L78
L72:
  mov    %r13,%rdi
  call   <TwoHex2Int@plt>
  mov    %al,0x0(%rbp)
  add    $0x3,%rbx
  lea    0x1(%rbp),%rbp
  jmp    L78
L29:
  add    $0x1,%rbx
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
L78:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L35
L23:
  cmp    $0x25,%al
  je     L48
  cmp    $0x2b,%al
  jne    L29
  test   %r12d,%r12d
  je     L29
  movb   $0x20,0x0(%rbp)
  add    $0x1,%rbx
  lea    0x1(%rbp),%rbp
  jmp    L78
L64:
  mov    %rdi,%rbp
L35:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void url_decode(char *p, int queryString) {
  char *pD = p;
  while (*p) {
    switch (*p) {
    case '%':
      p++;
      if (isxdigit(p[0]) && isxdigit(p[1])) {
        *pD++ = (char)TwoHex2Int(p);
        p += 2;
      }
      break;
    case '+':
      if (queryString) {
        *pD++ = ' ';
        p++;
        break;
      }
    default:
      *pD++ = *p++;
    }
  }
  *pD = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<url_decode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  mov    %esi,%r13d
  mov    %rdi,%rbp
  jmp    L24
  nopl   0x0(%rax)
L72:
  test   %r13d,%r13d
  je     L31
  movb   $0x20,0x0(%rbp)
  mov    %r12,%rbx
  add    $0x1,%rbp
L69:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L38
L24:
  lea    0x1(%rbx),%r12
  cmp    $0x25,%al
  je     L37
  cmp    $0x2b,%al
  je     L72
L31:
  mov    %r12,%rbx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L24
L38:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L36
L86:
  mov    %r12,%rbx
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L36:
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L86
  mov    %r12,%rdi
  add    $0x3,%rbx
  add    $0x1,%rbp
  call   <TwoHex2Int@plt>
  mov    %al,-0x1(%rbp)
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rbp
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void url_decode(char *p, int queryString) {
  char *pD = p;
  while (*p) {
    switch (*p) {
    case '%':
      p++;
      if (isxdigit(p[0]) && isxdigit(p[1])) {
        *pD++ = (char)TwoHex2Int(p);
        p += 2;
      }
      break;
    case '+':
      if (queryString) {
        *pD++ = ' ';
        p++;
        break;
      }
    default:
      *pD++ = *p++;
    }
  }
  *pD = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<url_decode>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L13
  test   %esi,%esi
  jne    L77
  lea    0x1(%rbx),%r12
  cmp    $0x25,%al
  je     L156
  nopl   0x0(%rax)
L89:
  mov    %al,0x0(%rbp)
  mov    %r12,%rbx
  add    $0x1,%rbp
L11:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L13
L22:
  lea    0x1(%rbx),%r12
  cmp    $0x25,%al
  jne    L89
L156:
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L26
L115:
  mov    %r12,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L22
L13:
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L86:
  movb   $0x20,0x0(%rbp)
  mov    %r12,%rbx
  add    $0x1,%rbp
  nopl   0x0(%rax,%rax,1)
L159:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L13
L77:
  lea    0x1(%rbx),%r12
  cmp    $0x25,%al
  je     L162
  cmp    $0x2b,%al
  je     L86
  mov    %al,0x0(%rbp)
  mov    %r12,%rbx
  add    $0x1,%rbp
  jmp    L159
  nopw   0x0(%rax,%rax,1)
L162:
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L58
L48:
  mov    %r12,%rbx
  jmp    L159
  nopw   0x0(%rax,%rax,1)
L26:
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L115
  mov    %r12,%rdi
  add    $0x3,%rbx
  add    $0x1,%rbp
  call   <TwoHex2Int@plt>
  mov    %al,-0x1(%rbp)
  jmp    L11
  nopl   (%rax)
L58:
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L48
  mov    %r12,%rdi
  add    $0x3,%rbx
  add    $0x1,%rbp
  call   <TwoHex2Int@plt>
  mov    %al,-0x1(%rbp)
  jmp    L159
```

assistant: ```c
void url_decode(char *p, int queryString) {
  char *pD = p;
  while (*p) {
    switch (*p) {
    case '%':
      p++;
      if (isxdigit(p[0]) && isxdigit(p[1])) {
        *pD++ = (char)TwoHex2Int(p);
        p += 2;
      }
      break;
    case '+':
      if (queryString) {
        *pD++ = ' ';
        p++;
        break;
      }
    default:
      *pD++ = *p++;
    }
  }
  *pD = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bytes_to_h8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t bytes_to_h8(char *bytes) {
  uint8_t result = *(uint8_t *)bytes;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bytes_to_h8>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint8_t bytes_to_h8(char *bytes) {
  uint8_t result = *(uint8_t *)bytes;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bytes_to_h8>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint8_t bytes_to_h8(char *bytes) {
  uint8_t result = *(uint8_t *)bytes;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bytes_to_h8>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint8_t bytes_to_h8(char *bytes) {
  uint8_t result = *(uint8_t *)bytes;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L8
L20:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sizeLine@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L17
  mov    $0x0,%eax
  jmp    L8
L17:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L44
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
  addl   $0x1,-0x20(%rbp)
L44:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
char *getLine(const char *str) {
  if (str == NULL)
    return NULL;
  int sz = sizeLine(str);
  if (sz <= 0)
    return NULL;
  char *buffer = (char *)malloc(sz + 1);
  int i;
  char *it, *itr;
  it = str;
  itr = buffer;
  for (i = 0; i < sz; i++) {
    *itr = *it;
    it++;
    itr++;
  }
  *itr = '\0';
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getLine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L34
  call   <sizeLine@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  test   %ebp,%ebp
  jle    L21
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %ebp,%ebp
  lea    0x0(%rbp,%rax,1),%rsi
  mov    %rax,%rdx
  sub    %rax,%rbx
L12:
  movzbl (%rdx,%rbx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
  movb   $0x0,(%rax,%rbp,1)
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  mov    %rdi,%rax
  jmp    L21
```

assistant: ```c
char *getLine(const char *str) {
  if (str == NULL)
    return NULL;
  int sz = sizeLine(str);
  if (sz <= 0)
    return NULL;
  char *buffer = (char *)malloc(sz + 1);
  int i;
  char *it, *itr;
  it = str;
  itr = buffer;
  for (i = 0; i < sz; i++) {
    *itr = *it;
    it++;
    itr++;
  }
  *itr = '\0';
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getLine>:
  endbr64
  test   %rdi,%rdi
  je     L25
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <sizeLine@plt>
  movslq %eax,%rbp
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L5
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  sub    %rax,%rbx
  lea    (%rax,%rbp,1),%rsi
  mov    %rax,%rdx
  mov    %rbx,%rdi
  nopl   (%rax)
L24:
  movzbl (%rdx,%rdi,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L24
  movb   $0x0,(%rax,%rbp,1)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getLine(const char *str) {
  if (str == NULL)
    return NULL;
  int sz = sizeLine(str);
  if (sz <= 0)
    return NULL;
  char *buffer = (char *)malloc(sz + 1);
  int i;
  char *it, *itr;
  it = str;
  itr = buffer;
  for (i = 0; i < sz; i++) {
    *itr = *it;
    it++;
    itr++;
  }
  *itr = '\0';
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getLine>:
  endbr64
  test   %rdi,%rdi
  je     L122
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <sizeLine@plt>
  xor    %r8d,%r8d
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L168
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  lea    0x1(%rbp),%rsi
  mov    %rax,%rdx
  mov    %rax,%r8
  lea    -0x1(%rbx),%eax
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L78
  cmp    $0x6,%eax
  jbe    L78
  cmp    $0xe,%eax
  jbe    L45
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  mov    %rdx,%rax
  shr    $0x4,%ecx
  sub    %rdx,%rsi
  shl    $0x4,%rcx
  add    %rdx,%rcx
  nopl   0x0(%rax)
L15:
  movdqu (%rax,%rsi,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L15
  mov    %ebx,%eax
  mov    %ebx,%r9d
  and    $0xfffffff0,%eax
  mov    %eax,%edi
  lea    0x0(%rbp,%rdi,1),%rsi
  lea    (%rdx,%rdi,1),%rcx
  cmp    %eax,%ebx
  je     L77
  mov    %ebx,%r10d
  sub    %eax,%r10d
  lea    -0x1(%r10),%r9d
  cmp    $0x6,%r9d
  jbe    L109
L52:
  mov    0x0(%rbp,%rdi,1),%r9
  mov    %r9,(%rdx,%rdi,1)
  mov    %r10d,%edi
  and    $0xfffffff8,%edi
  mov    %edi,%r9d
  add    %edi,%eax
  add    %r9,%rsi
  add    %r9,%rcx
  mov    %ebx,%r9d
  cmp    %r10d,%edi
  je     L77
L109:
  movzbl (%rsi),%edi
  mov    %ebx,%r9d
  mov    %dil,(%rcx)
  lea    0x1(%rax),%edi
  cmp    %edi,%ebx
  jle    L77
  movzbl 0x1(%rsi),%edi
  mov    %dil,0x1(%rcx)
  lea    0x2(%rax),%edi
  cmp    %edi,%ebx
  jle    L77
  movzbl 0x2(%rsi),%edi
  mov    %dil,0x2(%rcx)
  lea    0x3(%rax),%edi
  cmp    %edi,%ebx
  jle    L77
  movzbl 0x3(%rsi),%edi
  mov    %dil,0x3(%rcx)
  lea    0x4(%rax),%edi
  cmp    %edi,%ebx
  jle    L77
  movzbl 0x4(%rsi),%edi
  mov    %dil,0x4(%rcx)
  lea    0x5(%rax),%edi
  cmp    %edi,%ebx
  jle    L77
  movzbl 0x5(%rsi),%edi
  add    $0x6,%eax
  mov    %dil,0x5(%rcx)
  cmp    %eax,%ebx
  jle    L77
  movzbl 0x6(%rsi),%eax
  mov    %al,0x6(%rcx)
L77:
  movb   $0x0,(%rdx,%r9,1)
L168:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L45:
  mov    %ebx,%r10d
  mov    %rdx,%rcx
  mov    %rbp,%rsi
  xor    %eax,%eax
  xor    %edi,%edi
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L78:
  mov    %ebx,%r9d
  mov    %rdx,%rax
  sub    %rdx,%rbp
  lea    (%r9,%rdx,1),%rsi
  nopl   (%rax)
L126:
  movzbl (%rax,%rbp,1),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L126
  movb   $0x0,(%rdx,%r9,1)
  jmp    L168
  nopw   0x0(%rax,%rax,1)
L122:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getLine(const char *str) {
  if (str == NULL)
    return NULL;
  int sz = sizeLine(str);
  if (sz <= 0)
    return NULL;
  char *buffer = (char *)malloc(sz + 1);
  int i;
  char *it, *itr;
  it = str;
  itr = buffer;
  for (i = 0; i < sz; i++) {
    *itr = *it;
    it++;
    itr++;
  }
  *itr = '\0';
  return buffer;
}
```