ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<encode_half>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    $0x3f,%ecx
  mov    %eax,%esi
  mov    %eax,%edx
  shl    $0xc,%eax
  sar    %cl,%esi
  mov    $0x34,%ecx
  sar    $0xc,%eax
  sar    %cl,%edx
  mov    $0x2a,%ecx
  shl    $0xf,%esi
  and    $0x7ff,%edx
  sar    %cl,%eax
  cmp    $0x7ff,%edx
  je     L32
  lea    -0x3ff(%rdx),%edi
  cmp    $0xf,%edi
  jle    L22
  mov    $0x3ff,%eax
  mov    $0x7800,%r8d
L54:
  or     %eax,%r8d
  or     %esi,%r8d
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    %r8d,%eax
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    $0xfffffff2,%edi
  jge    L66
  xor    %r8d,%r8d
  cmp    $0xffffffe8,%edi
  jl     L15
  mov    $0xfffffff2,%ecx
  or     $0x4,%ah
  sub    %edi,%ecx
  sar    %cl,%eax
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L32:
  sar    %eax
  mov    $0x7c00,%r8d
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L66:
  lea    -0x3f0(%rdx),%r8d
  shl    $0xa,%r8d
  jmp    L54
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short encode_half(double val) {
  uint64_t v;
  memcpy(&v, &val, sizeof(v));
  int sign = v >> 63 << 15;
  int exp = (v >> 52) & 0x7ff;
  int mant = v << 12 >> 12 >> (53 - 11);
  exp -= 1023;
  if (exp == 1024) {
    exp = 16;
    mant >>= 1;
  } else if (exp >= 16) {
    exp = 15;
    mant = 1023;
  } else if (exp >= -14) {
  } else if (exp >= -24) {
    mant |= 1024;
    mant >>= -(exp + 14);
    exp = -15;
  } else {
    return 0;
  }
  return sign | ((exp + 15) << 10) | mant;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L19:
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  divsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D27(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <tan@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  movsd  D27(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D29(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  ja     L15
  mov    D21(%rip),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  shl    $0x3,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  jmp    L19
L15:
  nop
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D27
type_infered: f64
name: parse_data
arguments: label: D29
type_infered: byte[8]
name: parse_data
arguments: label: D21
type_infered: f64

tool: D27: 2

tool: {"D29": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D21: 1

assistant: ```c
double solve(double B, double H) {
  double h;
  double sum = 0;
  double theta;
  double r;
  while (1) {
    theta = atan(2.0 * H / B);
    r = tan(theta / 2.0) * B / 2.0;
    if (r < 1e-6)
      break;
    sum += 2 * (4 * atan(1.0)) * r;
    h = H - 2 * r;
    B = B * h / H;
    H = h;
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<solve>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x10(%rsp)
  jmp    L12
L15:
  movsd  D34(%rip),%xmm0
  call   <atan@plt>
  shl    $0x3,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  0x18(%rsp),%xmm3
  mulsd  %xmm3,%xmm0
  movapd %xmm0,%xmm5
  addsd  0x10(%rsp),%xmm5
  movsd  %xmm5,0x10(%rsp)
  addsd  %xmm3,%xmm3
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  movsd  (%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
L12:
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm2,%xmm0
  divsd  (%rsp),%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D36(%rip),%xmm0
  call   <tan@plt>
  mulsd  (%rsp),%xmm0
  mulsd  D36(%rip),%xmm0
  movsd  D24(%rip),%xmm6
  movsd  %xmm0,0x18(%rsp)
  comisd %xmm0,%xmm6
  jbe    L15
  movsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D34
type_infered: f64
name: parse_data
arguments: data_label: D36
type_infered: f32[2]
name: parse_data
arguments: data_label: D24
type_infered: byte[8]

tool: D34: 1

tool: {"D36": [0.0,1.75]}

tool: {"D24": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double solve(double B, double H) {
  double h;
  double sum = 0;
  double theta;
  double r;
  while (1) {
    theta = atan(2.0 * H / B);
    r = tan(theta / 2.0) * B / 2.0;
    if (r < 1e-6)
      break;
    sum += 2 * (4 * atan(1.0)) * r;
    h = H - 2 * r;
    B = B * h / H;
    H = h;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<solve>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm6,%xmm6
  movsd  %xmm0,(%rsp)
  movsd  %xmm6,0x8(%rsp)
  jmp    L8
  nopl   0x0(%rax)
L1:
  mov    D26(%rip),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  shl    $0x3,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movsd  %xmm2,(%rsp)
L8:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  addsd  %xmm1,%xmm0
  divsd  (%rsp),%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D25(%rip),%xmm0
  call   <tan@plt>
  mulsd  (%rsp),%xmm0
  movsd  D25(%rip),%xmm2
  movsd  D13(%rip),%xmm4
  mulsd  %xmm0,%xmm2
  comisd %xmm2,%xmm4
  movsd  %xmm2,0x10(%rsp)
  jbe    L1
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_infered: f64
name: parse_data
arguments: data_tag: D25
type_infered: f32[2]
name: parse_data
arguments: data_tag: D13
type_infered: byte[8]

tool: D26: 1

tool: {"D25": [0.0,1.75]}

tool: {"D13": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double solve(double B, double H) {
  double h;
  double sum = 0;
  double theta;
  double r;
  while (1) {
    theta = atan(2.0 * H / B);
    r = tan(theta / 2.0) * B / 2.0;
    if (r < 1e-6)
      break;
    sum += 2 * (4 * atan(1.0)) * r;
    h = H - 2 * r;
    B = B * h / H;
    H = h;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<solve>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm6,%xmm6
  movsd  %xmm0,(%rsp)
  movsd  %xmm6,0x8(%rsp)
  jmp    L13
  nopl   0x0(%rax)
L1:
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  shl    $0x3,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movsd  %xmm2,(%rsp)
L13:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  addsd  %xmm1,%xmm0
  divsd  (%rsp),%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D27(%rip),%xmm0
  call   <tan@plt>
  mulsd  (%rsp),%xmm0
  movsd  D27(%rip),%xmm2
  movsd  D18(%rip),%xmm4
  mulsd  %xmm0,%xmm2
  comisd %xmm2,%xmm4
  movsd  %xmm2,0x10(%rsp)
  jbe    L1
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: f64
name: read_data
arguments: data_label: D27
type_infered: f32[2]
name: read_data
arguments: data_label: D18
type_infered: byte[8]

tool: D19: 1

tool: {"D27": [0.0,1.75]}

tool: {"D18": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double solve(double B, double H) {
  double h;
  double sum = 0;
  double theta;
  double r;
  while (1) {
    theta = atan(2.0 * H / B);
    r = tan(theta / 2.0) * B / 2.0;
    if (r < 1e-6)
      break;
    sum += 2 * (4 * atan(1.0)) * r;
    h = H - 2 * r;
    B = B * h / H;
    H = h;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L9
L45:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x28(%rbp)
L9:
  cmpq   $0x0,-0x28(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L45
L12:
  cmpq   $0x0,-0x28(%rbp)
  je     L53
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  jmp    L43
L53:
  mov    $0x0,%eax
L43:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n && *s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2, --n;
  return n ? (int)tolower(*s1) - (int)tolower(*s2) : 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L32
L0:
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L72
  cmpb   $0x0,(%rbx)
  je     L72
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%rbp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L72
  add    $0x1,%r13
  add    $0x1,%rbx
  sub    $0x1,%r12
  jne    L0
L32:
  mov    $0x0,%eax
  jmp    L48
L72:
  mov    $0x0,%eax
  test   %r12,%r12
  jne    L77
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L77:
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  mov    %rax,%rbp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %rax,%rdx
  mov    %ebp,%eax
  sub    %edx,%eax
  jmp    L48
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n && *s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2, --n;
  return n ? (int)tolower(*s1) - (int)tolower(*s2) : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncasecmp>:
  endbr64
  test   %rdx,%rdx
  je     L22
  push   %r13
  lea    (%rsi,%rdx,1),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L69:
  cmpb   $0x0,(%rbx)
  je     L17
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L49
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %rbx,%r13
  je     L2
L47:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L69
L17:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %rax,%r8
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L49:
  movsbl (%r12),%edi
  jmp    L17
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n && *s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2, --n;
  return n ? (int)tolower(*s1) - (int)tolower(*s2) : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncasecmp>:
  endbr64
  test   %rdx,%rdx
  je     L59
  push   %r13
  lea    (%rsi,%rdx,1),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L36:
  cmpb   $0x0,(%rbx)
  je     L3
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L18
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %rbx,%r13
  je     L41
L4:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L36
L3:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %rax,%r8
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L41:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  movsbl (%r12),%edi
  jmp    L3
L59:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n && *s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2, --n;
  return n ? (int)tolower(*s1) - (int)tolower(*s2) : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int a, int b, int *l) {
  int tmp = l[a];
  l[a] = l[b];
  l[b] = tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap>:
  endbr64
  movslq %edi,%rdi
  lea    (%rdx,%rdi,4),%rcx
  mov    (%rcx),%edi
  movslq %esi,%rsi
  lea    (%rdx,%rsi,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void swap(int a, int b, int *l) {
  int tmp = l[a];
  l[a] = l[b];
  l[b] = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  lea    (%rdx,%rdi,4),%rcx
  lea    (%rdx,%rsi,4),%rax
  mov    (%rcx),%edi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void swap(int a, int b, int *l) {
  int tmp = l[a];
  l[a] = l[b];
  l[b] = tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swap>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  lea    (%rdx,%rdi,4),%rcx
  lea    (%rdx,%rsi,4),%rax
  mov    (%rcx),%edi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void swap(int a, int b, int *l) {
  int tmp = l[a];
  l[a] = l[b];
  l[b] = tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L70
  je     L111
  mov    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x3,%eax
  jmp    L64
L70:
  lea    D9(%rip),%rdi
  call   <puts@plt>
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L111:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L55
L113:
  mov    %ecx,%esi
L64:
  lea    (%r8,%rsi,1),%ecx
  mov    %eax,%edx
  add    $0x1,%eax
  mov    %esi,%r8d
  cmp    %ecx,%edi
  jge    L113
  mov    %ecx,%eax
  sub    %edi,%eax
  sub    %esi,%edi
  cmp    %edi,%eax
  jl     L2
  jg     L60
  jne    L55
  sub    $0x1,%edx
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L55
L2:
  mov    %ecx,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L55
L60:
  sub    $0x1,%edx
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L55
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D39
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D39: Please enter a Fibonacci number: 

tool: D23: %d

tool: D9: 1, 1

tool: D12: %d, %d

assistant: ```c
int main() {
  int number = 0, fibonacciInput = 0, fibonacciA = 1, fibonacciB = 1, fibonacciC = 0;
  printf("Please enter a Fibonacci number: ");
  scanf("%d", &fibonacciInput);
  if (fibonacciInput < 0) {
    printf("1, 1\n");
  } else if (fibonacciInput == 0) {
    printf("1, 1\n");
  } else {
    for (number = 3; fibonacciC <= fibonacciInput; number++) {
      fibonacciC = fibonacciA + fibonacciB;
      fibonacciA = fibonacciB;
      fibonacciB = fibonacciC;
    }
    if ((fibonacciC - fibonacciInput) < (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciC, number - 1);
    } else if ((fibonacciC - fibonacciInput) > (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciA, number - 2);
    } else if ((fibonacciC - fibonacciInput) == (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciA, number - 2);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    D47(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L34
  mov    $0x1,%esi
  mov    $0x1,%ecx
  mov    $0x3,%eax
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r8d,%esi
L48:
  lea    (%rcx,%rsi,1),%r8d
  mov    %eax,%edx
  mov    %esi,%ecx
  add    $0x1,%eax
  cmp    %r8d,%edi
  jge    L33
  mov    %r8d,%eax
  sub    %edi,%eax
  sub    %esi,%edi
  cmp    %edi,%eax
  jl     L13
  jg     L57
  jne    L21
L57:
  sub    $0x1,%edx
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L21
L34:
  lea    D0(%rip),%rdi
  call   <puts@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L13:
  mov    %r8d,%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L21
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D45
datatype: string
name: extract_symbolic_data
arguments: tag: D47
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string
name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D45: Please enter a Fibonacci number: 

tool: D47: %d

tool: D38: %d, %d

tool: D0: 1, 1

assistant: ```c
int main() {
  int number = 0, fibonacciInput = 0, fibonacciA = 1, fibonacciB = 1, fibonacciC = 0;
  printf("Please enter a Fibonacci number: ");
  scanf("%d", &fibonacciInput);
  if (fibonacciInput < 0) {
    printf("1, 1\n");
  } else if (fibonacciInput == 0) {
    printf("1, 1\n");
  } else {
    for (number = 3; fibonacciC <= fibonacciInput; number++) {
      fibonacciC = fibonacciA + fibonacciB;
      fibonacciA = fibonacciB;
      fibonacciB = fibonacciC;
    }
    if ((fibonacciC - fibonacciInput) < (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciC, number - 1);
    } else if ((fibonacciC - fibonacciInput) > (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciA, number - 2);
    } else if ((fibonacciC - fibonacciInput) == (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciA, number - 2);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L74
  mov    $0x1,%esi
  mov    $0x1,%ecx
  mov    $0x3,%eax
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L80:
  mov    %r8d,%esi
L60:
  lea    (%rcx,%rsi,1),%r8d
  mov    %eax,%edx
  mov    %esi,%ecx
  add    $0x1,%eax
  cmp    %r8d,%edi
  jge    L80
  mov    %r8d,%eax
  sub    %edi,%eax
  sub    %esi,%edi
  cmp    %edi,%eax
  jl     L70
  jg     L17
  jne    L54
L17:
  sub    $0x1,%edx
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L54
L74:
  lea    D44(%rip),%rdi
  call   <puts@plt>
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L70:
  mov    %r8d,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L54
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D44
type_guessed: string

tool: D8: Please enter a Fibonacci number: 

tool: D5: %d

tool: D10: %d, %d

tool: D44: 1, 1

assistant: ```c
int main() {
  int number = 0, fibonacciInput = 0, fibonacciA = 1, fibonacciB = 1, fibonacciC = 0;
  printf("Please enter a Fibonacci number: ");
  scanf("%d", &fibonacciInput);
  if (fibonacciInput < 0) {
    printf("1, 1\n");
  } else if (fibonacciInput == 0) {
    printf("1, 1\n");
  } else {
    for (number = 3; fibonacciC <= fibonacciInput; number++) {
      fibonacciC = fibonacciA + fibonacciB;
      fibonacciA = fibonacciB;
      fibonacciB = fibonacciC;
    }
    if ((fibonacciC - fibonacciInput) < (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciC, number - 1);
    } else if ((fibonacciC - fibonacciInput) > (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciA, number - 2);
    } else if ((fibonacciC - fibonacciInput) == (fibonacciInput - fibonacciA)) {
      printf("%d, %d", fibonacciA, number - 2);
    }
  }
  return 0;
}
```