ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shove4444>:
  endbr64
  push   %r12
  pxor   %xmm3,%xmm3
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsd  (%rdi),%xmm0
  xor    %edi,%edi
  mov    %rdx,%rbx
  comisd %xmm3,%xmm0
  jb     L31
  movsd  D24(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L31:
  call   <assert@plt>
  movsd  0x8(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  xor    %edi,%edi
  comisd %xmm4,%xmm0
  jb     L6
  movsd  D24(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L6:
  call   <assert@plt>
  movsd  0x10(%rbp),%xmm0
  pxor   %xmm5,%xmm5
  xor    %edi,%edi
  comisd %xmm5,%xmm0
  jb     L9
  movsd  D24(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L9:
  call   <assert@plt>
  movsd  0x18(%rbp),%xmm0
  pxor   %xmm6,%xmm6
  xor    %edi,%edi
  comisd %xmm6,%xmm0
  jb     L39
  movsd  D24(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L39:
  call   <assert@plt>
  movsd  D0(%rip),%xmm0
  movsd  0x0(%rbp),%xmm2
  movslq %r12d,%rdx
  movsd  D9(%rip),%xmm1
  mulsd  %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%eax
  movsd  0x8(%rbp),%xmm2
  mulsd  %xmm0,%xmm2
  shl    $0xc,%eax
  movzwl %ax,%eax
  addsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%ecx
  movsd  0x18(%rbp),%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  0x10(%rbp),%xmm0
  shl    $0x8,%ecx
  and    $0xf00,%ecx
  or     %ecx,%eax
  addsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm2,%ecx
  and    $0xf,%ecx
  or     %ecx,%eax
  cvttsd2si %xmm0,%ecx
  shl    $0x4,%ecx
  movzbl %cl,%ecx
  or     %ecx,%eax
  mov    %eax,(%rbx,%rdx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
datatype: f64
name: extract_symbolic_data
arguments: data_label: D0
datatype: f32[2]
name: extract_symbolic_data
arguments: data_label: D9
datatype: f64

tool: D24: 1

tool: {"D0": [0.0,2.71875]}

tool: D9: 0.5

assistant: ```c
void shove4444(const GLfloat shoveComponents[], int index, void *packedPixel) {
  assert(0.0 <= shoveComponents[0] && shoveComponents[0] <= 1.0);
  assert(0.0 <= shoveComponents[1] && shoveComponents[1] <= 1.0);
  assert(0.0 <= shoveComponents[2] && shoveComponents[2] <= 1.0);
  assert(0.0 <= shoveComponents[3] && shoveComponents[3] <= 1.0);
  ((GLushort *)packedPixel)[index] = ((GLushort)((shoveComponents[0] * 15) + 0.5) << 12) & 0xf000;
  ((GLushort *)packedPixel)[index] |= ((GLushort)((shoveComponents[1] * 15) + 0.5) << 8) & 0x0f00;
  ((GLushort *)packedPixel)[index] |= ((GLushort)((shoveComponents[2] * 15) + 0.5) << 4) & 0x00f0;
  ((GLushort *)packedPixel)[index] |= ((GLushort)((shoveComponents[3] * 15) + 0.5)) & 0x000f;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shove4444>:
  endbr64
  push   %r12
  pxor   %xmm3,%xmm3
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsd  (%rdi),%xmm0
  xor    %edi,%edi
  mov    %rdx,%rbx
  comisd %xmm3,%xmm0
  jb     L28
  movsd  D41(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L28:
  call   <assert@plt>
  movsd  0x8(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  xor    %edi,%edi
  comisd %xmm4,%xmm0
  jb     L2
  movsd  D41(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L2:
  call   <assert@plt>
  movsd  0x10(%rbp),%xmm0
  pxor   %xmm5,%xmm5
  xor    %edi,%edi
  comisd %xmm5,%xmm0
  jb     L38
  movsd  D41(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L38:
  call   <assert@plt>
  movsd  0x18(%rbp),%xmm0
  pxor   %xmm6,%xmm6
  xor    %edi,%edi
  comisd %xmm6,%xmm0
  jb     L16
  movsd  D41(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L16:
  call   <assert@plt>
  movsd  D34(%rip),%xmm0
  movsd  0x0(%rbp),%xmm2
  movslq %r12d,%rdx
  movsd  D2(%rip),%xmm1
  mulsd  %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%eax
  movsd  0x8(%rbp),%xmm2
  mulsd  %xmm0,%xmm2
  shl    $0xc,%eax
  movzwl %ax,%eax
  addsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%ecx
  movsd  0x18(%rbp),%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  0x10(%rbp),%xmm0
  shl    $0x8,%ecx
  and    $0xf00,%ecx
  or     %ecx,%eax
  addsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm2,%ecx
  and    $0xf,%ecx
  or     %ecx,%eax
  cvttsd2si %xmm0,%ecx
  shl    $0x4,%ecx
  movzbl %cl,%ecx
  or     %ecx,%eax
  mov    %eax,(%rbx,%rdx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D41
datatype: f64
name: extract_symbolic_data
arguments: tag: D34
datatype: f32[2]
name: extract_symbolic_data
arguments: tag: D2
datatype: f64

tool: D41: 1

tool: {"D34": [0.0,2.71875]}

tool: D2: 0.5

assistant: ```c
void shove4444(const GLfloat shoveComponents[], int index, void *packedPixel) {
  assert(0.0 <= shoveComponents[0] && shoveComponents[0] <= 1.0);
  assert(0.0 <= shoveComponents[1] && shoveComponents[1] <= 1.0);
  assert(0.0 <= shoveComponents[2] && shoveComponents[2] <= 1.0);
  assert(0.0 <= shoveComponents[3] && shoveComponents[3] <= 1.0);
  ((GLushort *)packedPixel)[index] = ((GLushort)((shoveComponents[0] * 15) + 0.5) << 12) & 0xf000;
  ((GLushort *)packedPixel)[index] |= ((GLushort)((shoveComponents[1] * 15) + 0.5) << 8) & 0x0f00;
  ((GLushort *)packedPixel)[index] |= ((GLushort)((shoveComponents[2] * 15) + 0.5) << 4) & 0x00f0;
  ((GLushort *)packedPixel)[index] |= ((GLushort)((shoveComponents[3] * 15) + 0.5)) & 0x000f;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aa_pro_ctr_a15>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rcx
  lea    D25(%rip),%rax
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x6,%edi
  mov    $0x0,%eax
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D6
datatype: string

tool: D17: !!!!!!!!

tool: D25: aa_pro_ctr_a15

tool: D6: hu_aap

assistant: ```c
int aa_pro_ctr_a15(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aa_pro_ctr_a15>:
  endbr64
  sub    $0x8,%rsp
  lea    D25(%rip),%rcx
  lea    D20(%rip),%rdx
  lea    D12(%rip),%rsi
  mov    $0x6,%edi
  mov    $0x0,%eax
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D12
type: string

tool: D25: !!!!!!!!

tool: D20: aa_pro_ctr_a15

tool: D12: hu_aap

assistant: ```c
int aa_pro_ctr_a15(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aa_pro_ctr_a15>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rcx
  xor    %eax,%eax
  mov    $0x6,%edi
  lea    D26(%rip),%rdx
  lea    D25(%rip),%rsi
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D25
datatype: string

tool: D20: !!!!!!!!

tool: D26: aa_pro_ctr_a15

tool: D25: hu_aap

assistant: ```c
int aa_pro_ctr_a15(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aa_pro_ctr_a15>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rcx
  xor    %eax,%eax
  mov    $0x6,%edi
  lea    D1(%rip),%rdx
  lea    D27(%rip),%rsi
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
type_infered: string
name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string

tool: D26: !!!!!!!!

tool: D1: aa_pro_ctr_a15

tool: D27: hu_aap

assistant: ```c
int aa_pro_ctr_a15(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x1028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1028(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x1018(%rbp)
  cmpq   $0x0,-0x1018(%rbp)
  je     L19
  jmp    L21
L13:
  mov    -0x1018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  mov    -0x1018(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  jmp    L46
L19:
  mov    $0xffffffff,%eax
L46:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string

tool: D10: r

tool: D13: %s

assistant: ```c
int cat(char *filename) {
  FILE *fp;
  char buf[4096];
  if ((fp = fopen(filename, "r")) != NULL) {
    while (!feof(fp)) {
      fgets(buf, sizeof(buf), fp);
      printf("%s", buf);
    }
    printf("\n");
  } else {
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbp
  lea    D5(%rip),%r12
  jmp    L46
L11:
  mov    $0xffffffff,%eax
  jmp    L42
L21:
  mov    %rsp,%rbx
  mov    %rbp,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L46:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L42:
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D1: r

tool: D5: %s

assistant: ```c
int cat(char *filename) {
  FILE *fp;
  char buf[4096];
  if ((fp = fopen(filename, "r")) != NULL) {
    while (!feof(fp)) {
      fgets(buf, sizeof(buf), fp);
      printf("%s", buf);
    }
    printf("\n");
  } else {
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  lea    D17(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L23
  mov    %rax,%rbx
  lea    D3(%rip),%r12
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rsp,%rbp
  mov    $0x1000,%esi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L33:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
L39:
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L39
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
datatype: string
name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D17: r

tool: D3: %s

assistant: ```c
int cat(char *filename) {
  FILE *fp;
  char buf[4096];
  if ((fp = fopen(filename, "r")) != NULL) {
    while (!feof(fp)) {
      fgets(buf, sizeof(buf), fp);
      printf("%s", buf);
    }
    printf("\n");
  } else {
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  lea    D3(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L36
  mov    %rax,%rbx
  lea    D11(%rip),%r12
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rsp,%rbp
  mov    $0x1000,%esi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L40
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
L48:
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    $0xffffffff,%eax
  jmp    L48
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D3: r

tool: D11: %s

assistant: ```c
int cat(char *filename) {
  FILE *fp;
  char buf[4096];
  if ((fp = fopen(filename, "r")) != NULL) {
    while (!feof(fp)) {
      fgets(buf, sizeof(buf), fp);
      printf("%s", buf);
    }
    printf("\n");
  } else {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<numberOfBands>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  pxor   %xmm3,%xmm3
  cvtsi2sdl -0x14(%rbp),%xmm3
  movsd  %xmm3,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x1c(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mulsd  -0x28(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x20(%rbp),%xmm2
  movsd  D0(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D16(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D16
datatype: f64

tool: {"D0": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xf6,0x3f]}

tool: D16: 0.5

assistant: ```c
int numberOfBands(int b_p_o, int start, int stop, float warp_factor) {
  int result = 0;
  ;
  ;
  ;
  ;
  ;
  ;
  result = 2 * (int)(b_p_o * log((float)(stop) / start) / (2.0 * log(2.0) * warp_factor) + 0.5);
  ;
  return (result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numberOfBands>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mulsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  add    %eax,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: byte[8]
name: read_data
arguments: data_label: D3
type_infered: f64

tool: {"D0": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xf6,0x3f]}

tool: D3: 0.5

assistant: ```c
int numberOfBands(int b_p_o, int start, int stop, float warp_factor) {
  int result = 0;
  ;
  ;
  ;
  ;
  ;
  ;
  result = 2 * (int)(b_p_o * log((float)(stop) / start) / (2.0 * log(2.0) * warp_factor) + 0.5);
  ;
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<numberOfBands>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  mov    %edi,%ebx
  cvtsi2ss %esi,%xmm1
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <log@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm2
  cvtsi2sd %ebx,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D13(%rip),%xmm0
  divsd  %xmm0,%xmm1
  addsd  D18(%rip),%xmm1
  add    $0x10,%rsp
  pop    %rbx
  cvttsd2si %xmm1,%eax
  add    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: byte[8]
name: unpack_data
arguments: tag: D18
type_guessed: f64

tool: {"D13": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xf6,0x3f]}

tool: D18: 0.5

assistant: ```c
int numberOfBands(int b_p_o, int start, int stop, float warp_factor) {
  int result = 0;
  ;
  ;
  ;
  ;
  ;
  ;
  result = 2 * (int)(b_p_o * log((float)(stop) / start) / (2.0 * log(2.0) * warp_factor) + 0.5);
  ;
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numberOfBands>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  mov    %edi,%ebx
  cvtsi2ss %esi,%xmm1
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <log@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm2
  cvtsi2sd %ebx,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D9(%rip),%xmm0
  divsd  %xmm0,%xmm1
  addsd  D7(%rip),%xmm1
  add    $0x10,%rsp
  pop    %rbx
  cvttsd2si %xmm1,%eax
  add    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: byte[8]
name: retrieve_data
arguments: tag: D7
data_type: f64

tool: {"D9": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xf6,0x3f]}

tool: D7: 0.5

assistant: ```c
int numberOfBands(int b_p_o, int start, int stop, float warp_factor) {
  int result = 0;
  ;
  ;
  ;
  ;
  ;
  ;
  result = 2 * (int)(b_p_o * log((float)(stop) / start) / (2.0 * log(2.0) * warp_factor) + 0.5);
  ;
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L6:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0xc(%rbp),%edx
  lea    0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void shuffle(int a[], int size) {
  int r;
  int temp;
  for (int i = 0; i < size; i++) {
    srand(time(NULL));
    r = rand() % (i + 1);
    temp = a[i];
    a[i] = a[r];
    a[r] = temp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shuffle>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    0x1(%rsi),%r12d
  mov    $0x1,%ebx
L0:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp,%rbx,4),%ecx
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%rbp,%rbx,4)
  mov    %ecx,(%rax)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  ret
```

assistant: ```c
void shuffle(int a[], int size) {
  int r;
  int temp;
  for (int i = 0; i < size; i++) {
    srand(time(NULL));
    r = rand() % (i + 1);
    temp = a[i];
    a[i] = a[r];
    a[r] = temp;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<shuffle>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rsi),%ebp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    -0x4(%r12,%rbx,4),%ecx
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%r12,%rbx,4)
  add    $0x1,%rbx
  mov    %ecx,(%rax)
  cmp    %rbp,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void shuffle(int a[], int size) {
  int r;
  int temp;
  for (int i = 0; i < size; i++) {
    srand(time(NULL));
    r = rand() % (i + 1);
    temp = a[i];
    a[i] = a[r];
    a[r] = temp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shuffle>:
  endbr64
  test   %esi,%esi
  jle    L10
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rsi),%ebp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    -0x4(%r12,%rbx,4),%ecx
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%r12,%rbx,4)
  add    $0x1,%rbx
  mov    %ecx,(%rax)
  cmp    %rbp,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
void shuffle(int a[], int size) {
  int r;
  int temp;
  for (int i = 0; i < size; i++) {
    srand(time(NULL));
    r = rand() % (i + 1);
    temp = a[i];
    a[i] = a[r];
    a[r] = temp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<note_request>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void note_request(const char *key, size_t bytes) {
  (void)key;
  (void)bytes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<note_request>:
  endbr64
  ret
```

assistant: ```c
void note_request(const char *key, size_t bytes) {
  (void)key;
  (void)bytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<note_request>:
  endbr64
  ret
```

assistant: ```c
void note_request(const char *key, size_t bytes) {
  (void)key;
  (void)bytes;
}
```