ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x4,%edi
  je     L3
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L3:
  mov    0x18(%rbx),%rdx
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <update_user_info@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: Error! Wrong params!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 4) {
    printf("Error! Wrong params!\n");
    exit(1);
  }
  char *filename = argv[1];
  char *username = argv[2];
  char *password = argv[3];
  update_user_info(filename, username, password);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x4,%edi
  je     L2
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    0x18(%rbx),%rdx
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <update_user_info@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: Error! Wrong params!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 4) {
    printf("Error! Wrong params!\n");
    exit(1);
  }
  char *filename = argv[1];
  char *username = argv[2];
  char *password = argv[3];
  update_user_info(filename, username, password);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blockio_write_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L26:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L15
L31:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  jg     L60
  cmpl   $0x0,-0x10(%rbp)
  jns    L4
L60:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L41
L4:
  mov    -0x18(%rbp),%edx
  mov    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    %esi,%eax
  imul   %ecx,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%eax
  cmp    $0x7,%eax
  jbe    L31
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,-0x14(%rbp)
L8:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L26
  mov    $0x0,%eax
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: 

 ERROR! BINARY has only 1 and 0!


assistant: ```c
int blockio_write_bin(FILE *f, char *bin, int l) {
  int i, n, b, k, m;
  int len;
  unsigned char *buffer;
  buffer = (unsigned char *)malloc(sizeof(char) + 1);
  for (k = 0; k < strlen(bin); k += sizeof(char) * 8) {
    *buffer = 0;
    for (i = 0; i < sizeof(char) * 8; i++) {
      n = (bin[k + i] - '0');
      if ((n > 1) || (n < 0)) {
        puts("\n\n ERROR! BINARY has only 1 and 0!\n");
        return (-1);
      }
      b = pow(2, sizeof(char) * 8 - 1 - i);
      *buffer = *buffer + n * b;
    }
    fwrite(buffer, sizeof(char), 1, f);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blockio_write_bin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%r14d
  jmp    L34
L23:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    0x8(%rsp),%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  add    $0x8,%r14d
L34:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L36
  movb   $0x0,0x0(%r13)
  movslq %r14d,%r12
  add    %r15,%r12
  mov    $0x7,%ebp
L40:
  movsbl (%r12),%ebx
  sub    $0x30,%ebx
  cmp    $0x1,%ebx
  ja     L23
  mov    %ebp,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  imul   %edx,%eax
  add    %al,0x0(%r13)
  sub    $0x1,%ebp
  add    $0x1,%r12
  cmp    $0xffffffff,%ebp
  jne    L40
  jmp    L20
L36:
  mov    $0x0,%eax
  jmp    L55
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: 

 ERROR! BINARY has only 1 and 0!


assistant: ```c
int blockio_write_bin(FILE *f, char *bin, int l) {
  int i, n, b, k, m;
  int len;
  unsigned char *buffer;
  buffer = (unsigned char *)malloc(sizeof(char) + 1);
  for (k = 0; k < strlen(bin); k += sizeof(char) * 8) {
    *buffer = 0;
    for (i = 0; i < sizeof(char) * 8; i++) {
      n = (bin[k + i] - '0');
      if ((n > 1) || (n < 0)) {
        puts("\n\n ERROR! BINARY has only 1 and 0!\n");
        return (-1);
      }
      b = pow(2, sizeof(char) * 8 - 1 - i);
      *buffer = *buffer + n * b;
    }
    fwrite(buffer, sizeof(char), 1, f);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<blockio_write_bin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L37
L12:
  movb   $0x0,0x0(%rbp)
  movslq %r12d,%rdx
  mov    $0x7,%r15d
  lea    0x0(%r13,%rdx,1),%r14
  nopl   0x0(%rax)
L17:
  movsbl (%r14),%ebx
  sub    $0x30,%ebx
  cmp    $0x1,%ebx
  ja     L2
  mov    %r15d,%esi
  mov    $0x2,%edi
  sub    $0x1,%r15d
  add    $0x1,%r14
  call   <pow@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  imul   %r8d,%eax
  add    %al,0x0(%rbp)
  cmp    $0xffffffff,%r15d
  jne    L17
  mov    0x8(%rsp),%rcx
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  add    $0x8,%r12d
  call   <fwrite@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L12
L37:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: 

 ERROR! BINARY has only 1 and 0!


assistant: ```c
int blockio_write_bin(FILE *f, char *bin, int l) {
  int i, n, b, k, m;
  int len;
  unsigned char *buffer;
  buffer = (unsigned char *)malloc(sizeof(char) + 1);
  for (k = 0; k < strlen(bin); k += sizeof(char) * 8) {
    *buffer = 0;
    for (i = 0; i < sizeof(char) * 8; i++) {
      n = (bin[k + i] - '0');
      if ((n > 1) || (n < 0)) {
        puts("\n\n ERROR! BINARY has only 1 and 0!\n");
        return (-1);
      }
      b = pow(2, sizeof(char) * 8 - 1 - i);
      *buffer = *buffer + n * b;
    }
    fwrite(buffer, sizeof(char), 1, f);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blockio_write_bin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L27
L32:
  movb   $0x0,0x0(%rbp)
  movslq %r12d,%rdx
  mov    $0x7,%r15d
  lea    0x0(%r13,%rdx,1),%r14
  nopl   0x0(%rax)
L17:
  movsbl (%r14),%ebx
  sub    $0x30,%ebx
  cmp    $0x1,%ebx
  ja     L13
  mov    %r15d,%esi
  mov    $0x2,%edi
  sub    $0x1,%r15d
  add    $0x1,%r14
  call   <pow@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  imul   %r8d,%eax
  add    %al,0x0(%rbp)
  cmp    $0xffffffff,%r15d
  jne    L17
  mov    0x8(%rsp),%rcx
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  add    $0x8,%r12d
  call   <fwrite@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L32
L27:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L13:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: 

 ERROR! BINARY has only 1 and 0!


assistant: ```c
int blockio_write_bin(FILE *f, char *bin, int l) {
  int i, n, b, k, m;
  int len;
  unsigned char *buffer;
  buffer = (unsigned char *)malloc(sizeof(char) + 1);
  for (k = 0; k < strlen(bin); k += sizeof(char) * 8) {
    *buffer = 0;
    for (i = 0; i < sizeof(char) * 8; i++) {
      n = (bin[k + i] - '0');
      if ((n > 1) || (n < 0)) {
        puts("\n\n ERROR! BINARY has only 1 and 0!\n");
        return (-1);
      }
      b = pow(2, sizeof(char) * 8 - 1 - i);
      *buffer = *buffer + n * b;
    }
    fwrite(buffer, sizeof(char), 1, f);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <createList@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <createList@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sortList@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sortList@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mergeTwoLists@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <printList@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <freeList@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <freeList@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <freeList@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(void) {
  int arr1[1] = {2};
  int arr2[1] = {1};
  struct ListNode *l1 = NULL;
  struct ListNode *l2 = NULL;
  struct ListNode *res = NULL;
  l1 = createList(arr1, 1);
  l2 = createList(arr2, 1);
  l1 = sortList(l1);
  l2 = sortList(l2);
  res = mergeTwoLists(l1, l2);
  printList(res);
  freeList(l1);
  freeList(l2);
  freeList(res);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%esi
  call   <createList@plt>
  mov    %rax,%rbp
  lea    0x4(%rsp),%rdi
  mov    $0x1,%esi
  call   <createList@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <sortList@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <sortList@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <mergeTwoLists@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <printList@plt>
  mov    %r12,%rdi
  call   <freeList@plt>
  mov    %rbp,%rdi
  call   <freeList@plt>
  mov    %rbx,%rdi
  call   <freeList@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int arr1[1] = {2};
  int arr2[1] = {1};
  struct ListNode *l1 = NULL;
  struct ListNode *l2 = NULL;
  struct ListNode *res = NULL;
  l1 = createList(arr1, 1);
  l2 = createList(arr2, 1);
  l1 = sortList(l1);
  l2 = sortList(l2);
  res = mergeTwoLists(l1, l2);
  printList(res);
  freeList(l1);
  freeList(l2);
  freeList(res);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <createList@plt>
  mov    $0x1,%esi
  lea    0x4(%rsp),%rdi
  mov    %rax,%r12
  call   <createList@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <sortList@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <sortList@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <mergeTwoLists@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <printList@plt>
  mov    %r13,%rdi
  call   <freeList@plt>
  mov    %r12,%rdi
  call   <freeList@plt>
  mov    %rbp,%rdi
  call   <freeList@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int arr1[1] = {2};
  int arr2[1] = {1};
  struct ListNode *l1 = NULL;
  struct ListNode *l2 = NULL;
  struct ListNode *res = NULL;
  l1 = createList(arr1, 1);
  l2 = createList(arr2, 1);
  l1 = sortList(l1);
  l2 = sortList(l2);
  res = mergeTwoLists(l1, l2);
  printList(res);
  freeList(l1);
  freeList(l2);
  freeList(res);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <createList@plt>
  mov    $0x1,%esi
  lea    0x4(%rsp),%rdi
  mov    %rax,%r12
  call   <createList@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <sortList@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <sortList@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <mergeTwoLists@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <printList@plt>
  mov    %r13,%rdi
  call   <freeList@plt>
  mov    %r12,%rdi
  call   <freeList@plt>
  mov    %rbp,%rdi
  call   <freeList@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int arr1[1] = {2};
  int arr2[1] = {1};
  struct ListNode *l1 = NULL;
  struct ListNode *l2 = NULL;
  struct ListNode *res = NULL;
  l1 = createList(arr1, 1);
  l2 = createList(arr2, 1);
  l1 = sortList(l1);
  l2 = sortList(l2);
  res = mergeTwoLists(l1, l2);
  printList(res);
  freeList(l1);
  freeList(l2);
  freeList(res);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_native_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    $0x0,%eax
  call   <exit_if_app_is_offline@plt>
  lea    -0xc(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *read_native_message() {
  char bInLen[4];
  read(0, bInLen, 4);
  exit_if_app_is_offline();
  unsigned int inLen = *(unsigned int *)bInLen;
  char *inMsg = (char *)malloc(inLen);
  read(0, inMsg, inLen);
  return inMsg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_native_message>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    $0x0,%edi
  call   <read@plt>
  mov    $0x0,%eax
  call   <exit_if_app_is_offline@plt>
  mov    0x4(%rsp),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_native_message() {
  char bInLen[4];
  read(0, bInLen, 4);
  exit_if_app_is_offline();
  unsigned int inLen = *(unsigned int *)bInLen;
  char *inMsg = (char *)malloc(inLen);
  read(0, inMsg, inLen);
  return inMsg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_native_message>:
  endbr64
  push   %r13
  mov    $0x4,%edx
  xor    %edi,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <read@plt>
  xor    %eax,%eax
  call   <exit_if_app_is_offline@plt>
  mov    0x4(%rsp),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %r13d,%edx
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_native_message() {
  char bInLen[4];
  read(0, bInLen, 4);
  exit_if_app_is_offline();
  unsigned int inLen = *(unsigned int *)bInLen;
  char *inMsg = (char *)malloc(inLen);
  read(0, inMsg, inLen);
  return inMsg;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_native_message>:
  endbr64
  push   %r13
  mov    $0x4,%edx
  xor    %edi,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <read@plt>
  xor    %eax,%eax
  call   <exit_if_app_is_offline@plt>
  mov    0x4(%rsp),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %r13d,%edx
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_native_message() {
  char bInLen[4];
  read(0, bInLen, 4);
  exit_if_app_is_offline();
  unsigned int inLen = *(unsigned int *)bInLen;
  char *inMsg = (char *)malloc(inLen);
  read(0, inMsg, inLen);
  return inMsg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    $0x0,%ebx
  mov    $0x20,%r14d
  cmpl   $0x0,-0x34(%rbp)
  jle    L75
  mov    $0x0,%r12d
  mov    -0x30(%rbp),%r13
  jmp    L56
L77:
  add    $0x1,%r12d
  add    $0x1,%r13
L56:
  movzbl 0x0(%r13),%eax
  test   %al,%al
  jne    L77
  cmp    -0x34(%rbp),%r12d
  jl     L12
  movl   $0x0,-0x34(%rbp)
  jmp    L93
L12:
  sub    %r12d,-0x34(%rbp)
L93:
  mov    -0x38(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L75
  mov    $0x30,%r14d
L75:
  mov    -0x38(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L68
  jmp    L40
L9:
  mov    %r14d,%eax
  movsbl %al,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printchar@plt>
  add    $0x1,%ebx
  subl   $0x1,-0x34(%rbp)
L40:
  cmpl   $0x0,-0x34(%rbp)
  jg     L9
  jmp    L68
L81:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printchar@plt>
  add    $0x1,%ebx
  addq   $0x1,-0x30(%rbp)
L68:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L81
  jmp    L80
L82:
  mov    %r14d,%eax
  movsbl %al,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printchar@plt>
  add    $0x1,%ebx
  subl   $0x1,-0x34(%rbp)
L80:
  cmpl   $0x0,-0x34(%rbp)
  jg     L82
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int prints(char **out, const char *string, int width, int pad, char *buflimit) {
  register int pc = 0, padchar = ' ';
  if (width > 0) {
    register int len = 0;
    register const char *ptr;
    for (ptr = string; *ptr; ++ptr)
      ++len;
    if (len >= width)
      width = 0;
    else
      width -= len;
    if (pad & 2)
      padchar = '0';
  }
  if (!(pad & 1)) {
    for (; width > 0; --width) {
      printchar(out, padchar, buflimit);
      ++pc;
    }
  }
  for (; *string; ++string) {
    printchar(out, *string, buflimit);
    ++pc;
  }
  for (; width > 0; --width) {
    printchar(out, padchar, buflimit);
    ++pc;
  }
  return pc;
}
```