user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heap_sort_min_with_time_shown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <print_heap@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <build_heap_min@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <print_heap@plt>
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  jmp    L15
L37:
  mov    -0x24(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x3c(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <adjust_heap_min@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <print_heap@plt>
  subl   $0x1,-0x24(%rbp)
L15:
  cmpl   $0x0,-0x24(%rbp)
  jg     L37
  movl   $0x0,-0x24(%rbp)
  jmp    L51
L21:
  movl   $0x0,-0x20(%rbp)
  jmp    L48
L32:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x20(%rbp),%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x24(%rbp),%xmm2
  movsd  D35(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x20(%rbp)
L48:
  cmpl   $0x270f,-0x20(%rbp)
  jle    L32
  addl   $0x1,-0x24(%rbp)
L51:
  cmpl   $0x270f,-0x24(%rbp)
  jle    L21
  mov    $0x0,%eax
  call   <clock@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  D67(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D42
type_guessed: string
name: disassemble_data
arguments: tag: D58
type_guessed: string
name: disassemble_data
arguments: tag: D64
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: f64
name: disassemble_data
arguments: tag: D35
type_guessed: f64
name: disassemble_data
arguments: tag: D67
type_guessed: f64
name: disassemble_data
arguments: tag: D18
type_guessed: string

tool: D42: Before sort:

tool: D58: Built  heap:

tool: D64: Sort   heap:

tool: D13: 0.123

tool: D35: 3.567

tool: D67: 18.2

tool: D18: It takes %lf 


assistant: ```c
void heap_sort_min_with_time_shown(int matrix[], int length) {
  double t1, t2;
  int i, j;
  double k;
  t1 = clock();
  int ilength = length;
  print_heap("Before sort:", matrix, length);
  build_heap_min(matrix, length);
  print_heap("Built  heap:", matrix, length);
  for (i = length - 1; i >= 1; i--) {
    swap(matrix, 0, i);
    length--;
    adjust_heap_min(matrix, 0, length);
    print_heap("Sort   heap:", matrix, ilength);
  }
  for (i = 0; i < 10000; i++)
    for (j = 0; j < 10000; j++)
      k = 0.123 * j + 3.567 * i;
  t2 = clock();
  printf("It takes %lf \n", (t2 - t1) / 18.2);
}
```