ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quatgetreciprocal>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x18,%rsp
  call   <quatinvsqmagnitude@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <quatgetconjugate@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <quatscale@plt>
```

assistant: ```c
void quatgetreciprocal(float *qout, const float *qin) {
  float m = quatinvsqmagnitude(qin);
  quatgetconjugate(qout, qin);
  quatscale(qout, qout, m);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L157
L124:
  movl   $0x0,-0x8(%rbp)
  jmp    L36
L59:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L80
  cmpl   $0x0,-0x8(%rbp)
  je     L119
L80:
  cmpl   $0x0,-0x4(%rbp)
  jne    L88
  cmpl   $0x0,-0x8(%rbp)
  jne    L88
L119:
  mov    $0x41,%edi
  call   <ft_putchar@plt>
  jmp    L60
L88:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L174
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  je     L114
L174:
  cmpl   $0x0,-0x4(%rbp)
  jne    L121
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L121
L114:
  mov    $0x43,%edi
  call   <ft_putchar@plt>
  jmp    L60
L121:
  cmpl   $0x0,-0x4(%rbp)
  je     L107
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  je     L107
  cmpl   $0x0,-0x8(%rbp)
  je     L107
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L172
L107:
  mov    $0x42,%edi
  call   <ft_putchar@plt>
  jmp    L60
L172:
  mov    $0x20,%edi
  call   <ft_putchar@plt>
L60:
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L59
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  addl   $0x1,-0x4(%rbp)
L157:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L124
  nop
  nop
  leave
  ret
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == 0))
        ft_putchar('A');
      else if ((it_y == y - 1 && it_x == x - 1) || (it_y == 0 && it_x == x - 1))
        ft_putchar('C');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('B');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rush>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%r14d
  mov    $0x0,%ebp
  lea    -0x1(%rsi),%r13d
  test   %esi,%esi
  jg     L162
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  mov    %ebx,%edx
  or     %ebp,%edx
  jne    L166
L107:
  mov    $0x41,%edi
  call   <ft_putchar@plt>
L48:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L8
L91:
  cmp    %ebp,%r13d
  sete   %al
  test   %ebx,%ebx
  jne    L37
  test   %al,%al
  je     L37
  jmp    L107
L166:
  test   %ebp,%ebp
  je     L135
  test   %al,%al
  jne    L135
  test   %ebx,%ebx
  je     L108
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  je     L108
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  jmp    L48
L135:
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  je     L26
L108:
  mov    $0x42,%edi
  call   <ft_putchar@plt>
  jmp    L48
L26:
  mov    $0x43,%edi
  call   <ft_putchar@plt>
  jmp    L48
L8:
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  je     L9
L162:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L91
  jmp    L8
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == 0))
        ft_putchar('A');
      else if ((it_y == y - 1 && it_x == x - 1) || (it_y == 0 && it_x == x - 1))
        ft_putchar('C');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('B');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rush>:
  endbr64
  test   %esi,%esi
  jle    L53
  push   %r15
  mov    %esi,%r15d
  push   %r14
  lea    -0x1(%rdi),%r14d
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jg     L31
  jmp    L64
  nopl   0x0(%rax)
L65:
  mov    $0x41,%edi
  call   <ft_putchar@plt>
L146:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L64
L31:
  cmp    %r13d,%ebp
  je     L145
  mov    %ebp,%eax
  or     %ebx,%eax
  je     L65
  test   %ebp,%ebp
  je     L133
  test   %ebx,%ebx
  je     L36
  cmp    %ebx,%r14d
  je     L36
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%r12d
  jne    L31
  nopl   0x0(%rax)
L64:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <ft_putchar@plt>
  cmp    %ebp,%r15d
  jne    L45
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L145:
  test   %ebx,%ebx
  je     L65
L133:
  cmp    %ebx,%r14d
  je     L67
L36:
  mov    $0x42,%edi
  call   <ft_putchar@plt>
  jmp    L146
  nopl   (%rax)
L67:
  mov    $0x43,%edi
  call   <ft_putchar@plt>
  jmp    L146
L53:
  ret
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == 0))
        ft_putchar('A');
      else if ((it_y == y - 1 && it_x == x - 1) || (it_y == 0 && it_x == x - 1))
        ft_putchar('C');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('B');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rush>:
  endbr64
  test   %esi,%esi
  jle    L96
  push   %r15
  mov    %esi,%r15d
  push   %r14
  lea    -0x1(%rdi),%r14d
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  test   %ebp,%ebp
  jle    L56
  cmp    %r12d,%r13d
  sete   %al
  test   %r12d,%r12d
  sete   %dl
  xor    %ebx,%ebx
  or     %edx,%eax
  cmp    %r12d,%r13d
  je     L32
  test   %al,%al
  je     L85
  jmp    L127
  nopw   0x0(%rax,%rax,1)
L98:
  cmp    %r14d,%ebx
  je     L58
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  je     L56
  xchg   %ax,%ax
L85:
  test   %ebx,%ebx
  jne    L98
L58:
  mov    $0x42,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  jne    L85
L56:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <ft_putchar@plt>
  cmp    %r12d,%r15d
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L148:
  cmp    %ebx,%r14d
  je     L162
  mov    $0x42,%edi
  call   <ft_putchar@plt>
L18:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L56
L32:
  test   %ebx,%ebx
  jne    L148
  mov    $0x41,%edi
  call   <ft_putchar@plt>
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L62:
  mov    $0x41,%edi
  call   <ft_putchar@plt>
L79:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  je     L56
L127:
  mov    %r12d,%eax
  or     %ebx,%eax
  je     L62
  cmp    %r14d,%ebx
  je     L113
  mov    $0x42,%edi
  call   <ft_putchar@plt>
  jmp    L79
L162:
  mov    $0x43,%edi
  call   <ft_putchar@plt>
  jmp    L18
L113:
  mov    $0x43,%edi
  call   <ft_putchar@plt>
  jmp    L79
L96:
  ret
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == 0))
        ft_putchar('A');
      else if ((it_y == y - 1 && it_x == x - 1) || (it_y == 0 && it_x == x - 1))
        ft_putchar('C');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('B');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<median_int_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L17
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L22
L17:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L0
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L22
L0:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L22:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: f64

tool: D3: 2

assistant: ```c
double median_int_array(const int array[], int laenge) {
  double median = 0.0;
  if (laenge < 1)
    median = 0.0;
  else {
    if (laenge % 2) {
      median = array[(laenge - 1) / 2];
    } else {
      median = (array[(laenge / 2) - 1] + array[(laenge / 2)]) / 2.0;
    }
  }
  return median;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<median_int_array>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jle    L12
  test   $0x1,%sil
  je     L10
  sub    $0x1,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  ret
L10:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edx
  add    -0x4(%rdi,%rax,4),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D9(%rip),%xmm0
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: f32[2]

tool: {"D9": [0.0,1.75]}

assistant: ```c
double median_int_array(const int array[], int laenge) {
  double median = 0.0;
  if (laenge < 1)
    median = 0.0;
  else {
    if (laenge % 2) {
      median = array[(laenge - 1) / 2];
    } else {
      median = (array[(laenge / 2) - 1] + array[(laenge / 2)]) / 2.0;
    }
  }
  return median;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<median_int_array>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jle    L6
  test   $0x1,%sil
  je     L5
  sub    $0x1,%esi
  pxor   %xmm0,%xmm0
  sar    %esi
  movslq %esi,%rsi
  cvtsi2sdl (%rdi,%rsi,4),%xmm0
  ret
  nopl   0x0(%rax)
L5:
  sar    %esi
  pxor   %xmm0,%xmm0
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  add    -0x4(%rdi,%rsi,4),%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D9(%rip),%xmm0
L6:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: f32[2]

tool: {"D9": [0.0,1.75]}

assistant: ```c
double median_int_array(const int array[], int laenge) {
  double median = 0.0;
  if (laenge < 1)
    median = 0.0;
  else {
    if (laenge % 2) {
      median = array[(laenge - 1) / 2];
    } else {
      median = (array[(laenge / 2) - 1] + array[(laenge / 2)]) / 2.0;
    }
  }
  return median;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<median_int_array>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jle    L14
  test   $0x1,%sil
  je     L10
  sub    $0x1,%esi
  pxor   %xmm0,%xmm0
  sar    %esi
  movslq %esi,%rsi
  cvtsi2sdl (%rdi,%rsi,4),%xmm0
  ret
  nopl   0x0(%rax)
L10:
  sar    %esi
  pxor   %xmm0,%xmm0
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  add    -0x4(%rdi,%rsi,4),%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D1(%rip),%xmm0
L14:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: f32[2]

tool: {"D1": [0.0,1.75]}

assistant: ```c
double median_int_array(const int array[], int laenge) {
  double median = 0.0;
  if (laenge < 1)
    median = 0.0;
  else {
    if (laenge % 2) {
      median = array[(laenge - 1) / 2];
    } else {
      median = (array[(laenge / 2) - 1] + array[(laenge / 2)]) / 2.0;
    }
  }
  return median;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x7d0,-0xc(%rbp)
  mov    $0x8,%esi
  mov    $0x3d0900,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <init_array@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <kernel_lu@plt>
  cmpl   $0x2a,-0x14(%rbp)
  jle    L0
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L0
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <print_array@plt>
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2000;
  double(*A)[2000 + 0][2000 + 0];
  A = (double(*)[2000 + 0][2000 + 0]) polybench_alloc_data((2000 + 0) * (2000 + 0), sizeof(double));
  ;
  init_array(n, *A);
  ;
  kernel_lu(n, *A);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(n, *A);
  free((void *)A);
  ;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0x8,%esi
  mov    $0x3d0900,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    $0x7d0,%edi
  call   <init_array@plt>
  mov    %rbx,%rsi
  mov    $0x7d0,%edi
  call   <kernel_lu@plt>
  cmp    $0x2a,%ebp
  jle    L5
  mov    (%r12),%rax
  cmpb   $0x0,(%rax)
  je     L12
L5:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %rbx,%rsi
  mov    $0x7d0,%edi
  call   <print_array@plt>
  jmp    L5
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2000;
  double(*A)[2000 + 0][2000 + 0];
  A = (double(*)[2000 + 0][2000 + 0]) polybench_alloc_data((2000 + 0) * (2000 + 0), sizeof(double));
  ;
  init_array(n, *A);
  ;
  kernel_lu(n, *A);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(n, *A);
  free((void *)A);
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3d0900,%edi
  call   <polybench_alloc_data@plt>
  mov    $0x7d0,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <init_array@plt>
  mov    %rbp,%rsi
  mov    $0x7d0,%edi
  call   <kernel_lu@plt>
  cmp    $0x2a,%ebx
  jle    L9
  mov    (%r12),%rax
  cmpb   $0x0,(%rax)
  je     L8
L9:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    %rbp,%rsi
  mov    $0x7d0,%edi
  call   <print_array@plt>
  jmp    L9
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2000;
  double(*A)[2000 + 0][2000 + 0];
  A = (double(*)[2000 + 0][2000 + 0]) polybench_alloc_data((2000 + 0) * (2000 + 0), sizeof(double));
  ;
  init_array(n, *A);
  ;
  kernel_lu(n, *A);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(n, *A);
  free((void *)A);
  ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3d0900,%edi
  call   <polybench_alloc_data@plt>
  mov    $0x7d0,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <init_array@plt>
  mov    %rbp,%rsi
  mov    $0x7d0,%edi
  call   <kernel_lu@plt>
  cmp    $0x2a,%ebx
  jle    L3
  mov    (%r12),%rax
  cmpb   $0x0,(%rax)
  je     L10
L3:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbp,%rsi
  mov    $0x7d0,%edi
  call   <print_array@plt>
  jmp    L3
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2000;
  double(*A)[2000 + 0][2000 + 0];
  A = (double(*)[2000 + 0][2000 + 0]) polybench_alloc_data((2000 + 0) * (2000 + 0), sizeof(double));
  ;
  init_array(n, *A);
  ;
  kernel_lu(n, *A);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(n, *A);
  free((void *)A);
  ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_weight_value>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  lea    0x190(%rsi),%rdx
  lea    0x9dd0(%rsi),%rcx
L57:
  lea    -0x190(%rdx),%rax
L19:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
  add    $0x190,%rdx
  cmp    %rcx,%rdx
  jne    L57
  mov    $0x0,%ebp
  mov    $0x1,%r12d
  mov    $0x1,%r10d
  jmp    L29
L37:
  add    $0x1,%r10d
  cmp    $0x63,%r10d
  jg     L8
L29:
  movslq %ebp,%rax
  lea    0x0(,%rax,4),%r9
  add    %r9,%rax
  lea    (%rax,%rax,4),%rcx
  shl    $0x4,%rcx
  add    %rbx,%rcx
  movslq %r10d,%rax
  lea    0x0(,%rax,4),%r8
  add    %r8,%rax
  lea    (%rax,%rax,4),%rsi
  shl    $0x4,%rsi
  add    %rbx,%rsi
  add    %r11,%r9
  add    %r11,%r8
  mov    $0x0,%edx
  movslq %r10d,%rdi
  movslq %ebp,%r13
L38:
  mov    (%r9,%rdx,1),%eax
  imul   (%r8,%rdx,1),%eax
  add    (%rcx,%rdi,4),%eax
  mov    %eax,(%rcx,%rdi,4)
  mov    %eax,(%rsi,%r13,4)
  add    $0x190,%rdx
  cmp    $0x4b0,%rdx
  jne    L38
  jmp    L37
L8:
  lea    0x1(%r12),%r10d
  cmp    $0x63,%r10d
  jg     L51
  mov    %r12d,%ebp
  mov    %r10d,%r12d
  jmp    L29
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void set_weight_value(int pattern[][100], int weight[][100]) {
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      weight[i][j] = 0;
    }
  }
  for (int i = 0; i < 100; i++) {
    for (int j = i + 1; j < 100; j++) {
      for (int k = 0; k < 3; k++) {
        weight[i][j] += pattern[k][i] * pattern[k][j];
        weight[j][i] = weight[i][j];
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<set_weight_value>:
  endbr64
  push   %r12
  mov    %rsi,%r10
  mov    $0x9c40,%edx
  xor    %esi,%esi
  push   %rbp
  mov    $0x1,%r12d
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r10,%rdi
  call   <memset@plt>
  xor    %r11d,%r11d
  mov    %rax,%r10
  xchg   %ax,%ax
L37:
  lea    0x0(,%r11,4),%r9
  movslq %ebp,%rsi
  xor    %edx,%edx
  lea    (%r9,%r11,1),%rax
  lea    0x0(,%rsi,4),%r8
  add    %rbx,%r9
  lea    (%rax,%rax,4),%rcx
  lea    (%r8,%rsi,1),%rax
  add    %rbx,%r8
  lea    (%rax,%rax,4),%rdi
  shl    $0x4,%rcx
  shl    $0x4,%rdi
  add    %r10,%rcx
  add    %r10,%rdi
L32:
  mov    (%r9,%rdx,1),%eax
  imul   (%r8,%rdx,1),%eax
  add    $0x190,%rdx
  add    (%rcx,%rsi,4),%eax
  mov    %eax,(%rcx,%rsi,4)
  mov    %eax,(%rdi,%r11,4)
  cmp    $0x4b0,%rdx
  jne    L32
  add    $0x1,%ebp
  cmp    $0x64,%ebp
  jne    L37
  lea    0x1(%r12),%ebp
  cmp    $0x63,%r12d
  je     L31
  movslq %r12d,%r11
  mov    %ebp,%r12d
  jmp    L37
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void set_weight_value(int pattern[][100], int weight[][100]) {
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      weight[i][j] = 0;
    }
  }
  for (int i = 0; i < 100; i++) {
    for (int j = i + 1; j < 100; j++) {
      for (int k = 0; k < 3; k++) {
        weight[i][j] += pattern[k][i] * pattern[k][j];
        weight[j][i] = weight[i][j];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<set_weight_value>:
  endbr64
  push   %r12
  mov    $0x9c40,%edx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%r10d
  mov    $0x1,%r8d
  xor    %r9d,%r9d
  mov    %rax,%rdi
  nopl   0x0(%rax)
L13:
  lea    0x0(,%r9,4),%rcx
  movslq %r8d,%r12
  add    $0x1,%r8d
  lea    (%rcx,%r9,1),%rax
  lea    0x0(,%r12,4),%rdx
  lea    (%rax,%rax,4),%rax
  lea    (%rbx,%rdx,1),%r11
  shl    $0x4,%rax
  lea    (%rbx,%rcx,1),%rbp
  add    %rdx,%rax
  add    %r12,%rdx
  mov    0x0(%rbp),%esi
  add    %rdi,%rax
  imul   (%r11),%esi
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  add    (%rax),%esi
  add    %rcx,%rdx
  mov    %esi,(%rax)
  add    %rdi,%rdx
  mov    %esi,(%rdx)
  mov    0x190(%rbp),%ecx
  imul   0x190(%r11),%ecx
  add    %esi,%ecx
  mov    %ecx,(%rax)
  mov    %ecx,(%rdx)
  mov    0x320(%rbp),%esi
  imul   0x320(%r11),%esi
  add    %esi,%ecx
  mov    %ecx,(%rax)
  mov    %ecx,(%rdx)
  cmp    $0x64,%r8d
  jne    L13
  lea    0x1(%r10),%r8d
  cmp    $0x63,%r10d
  je     L15
  movslq %r10d,%r9
  mov    %r8d,%r10d
  jmp    L13
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void set_weight_value(int pattern[][100], int weight[][100]) {
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      weight[i][j] = 0;
    }
  }
  for (int i = 0; i < 100; i++) {
    for (int j = i + 1; j < 100; j++) {
      for (int k = 0; k < 3; k++) {
        weight[i][j] += pattern[k][i] * pattern[k][j];
        weight[j][i] = weight[i][j];
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<yasm__fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <yasm_fatal@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void yasm__fatal(const char *message, ...) {
  va_list va;
  va_start(va, message);
  yasm_fatal(message, va);
  va_end(va);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yasm__fatal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <yasm_fatal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void yasm__fatal(const char *message, ...) {
  va_list va;
  va_start(va, message);
  yasm_fatal(message, va);
  va_end(va);
}
```