ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<getbnfrombuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L1
L10:
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  cmpq   $0x0,-0x20(%rbp)
  jne    L10
L38:
  cmpq   $0x0,-0x20(%rbp)
  je     L11
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BN_bin2bn@plt>
  jmp    L36
L11:
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_zero@plt>
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
BIGNUM *getbnfrombuf(const unsigned char *buf, size_t len) {
  while (*buf == 0 && len > 0) {
    buf++;
    len--;
  }
  if (len) {
    return BN_bin2bn(buf, len, NULL);
  } else {
    BIGNUM *b = BN_new();
    BN_zero(b);
    return b;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getbnfrombuf>:
  endbr64
  push   %rbx
  cmpb   $0x0,(%rdi)
  jne    L16
  test   %rsi,%rsi
  je     L16
L11:
  add    $0x1,%rdi
  sub    $0x1,%rsi
  cmpb   $0x0,(%rdi)
  jne    L16
  test   %rsi,%rsi
  jne    L11
L16:
  test   %rsi,%rsi
  je     L12
  mov    $0x0,%edx
  call   <BN_bin2bn@plt>
  mov    %rax,%rbx
L42:
  mov    %rbx,%rax
  pop    %rbx
  ret
L12:
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <BN_zero@plt>
  jmp    L42
```

assistant: ```c
BIGNUM *getbnfrombuf(const unsigned char *buf, size_t len) {
  while (*buf == 0 && len > 0) {
    buf++;
    len--;
  }
  if (len) {
    return BN_bin2bn(buf, len, NULL);
  } else {
    BIGNUM *b = BN_new();
    BN_zero(b);
    return b;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getbnfrombuf>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rdi
  sub    $0x1,%rsi
  cmpb   $0x0,(%rdi)
  jne    L1
L9:
  test   %rsi,%rsi
  jne    L27
L44:
  push   %r12
  xor    %eax,%eax
  call   <BN_new@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <BN_zero@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  test   %rsi,%rsi
  je     L44
  xor    %edx,%edx
  jmp    1070 <BN_bin2bn@plt>
```

assistant: ```c
BIGNUM *getbnfrombuf(const unsigned char *buf, size_t len) {
  while (*buf == 0 && len > 0) {
    buf++;
    len--;
  }
  if (len) {
    return BN_bin2bn(buf, len, NULL);
  } else {
    BIGNUM *b = BN_new();
    BN_zero(b);
    return b;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getbnfrombuf>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rdi
  sub    $0x1,%rsi
  cmpb   $0x0,(%rdi)
  jne    L3
L10:
  test   %rsi,%rsi
  jne    L42
L25:
  push   %r12
  xor    %eax,%eax
  call   <BN_new@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <BN_zero@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  test   %rsi,%rsi
  je     L25
  xor    %edx,%edx
  jmp    1070 <BN_bin2bn@plt>
```

assistant: ```c
BIGNUM *getbnfrombuf(const unsigned char *buf, size_t len) {
  while (*buf == 0 && len > 0) {
    buf++;
    len--;
  }
  if (len) {
    return BN_bin2bn(buf, len, NULL);
  } else {
    BIGNUM *b = BN_new();
    BN_zero(b);
    return b;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BOX_START_FROM_WHICH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  add    %edx,%edx
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x0(,%rax,8),%edx
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int BOX_START_FROM_WHICH(int which) {
  int x;
  x = (which % 3) * 3;
  x += ((which / 3) * 3) * 9;
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<BOX_START_FROM_WHICH>:
  endbr64
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edi
  lea    (%rdi,%rdi,2),%edx
  lea    (%rax,%rax,8),%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int BOX_START_FROM_WHICH(int which) {
  int x;
  x = (which % 3) * 3;
  x += ((which / 3) * 3) * 9;
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<BOX_START_FROM_WHICH>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edi
  lea    (%rax,%rax,8),%eax
  lea    (%rdi,%rdi,2),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int BOX_START_FROM_WHICH(int which) {
  int x;
  x = (which % 3) * 3;
  x += ((which / 3) * 3) * 9;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BOX_START_FROM_WHICH>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edi
  lea    (%rax,%rax,8),%eax
  lea    (%rdi,%rdi,2),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int BOX_START_FROM_WHICH(int which) {
  int x;
  x = (which % 3) * 3;
  x += ((which / 3) * 3) * 9;
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<spread_success>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    %r9d,%r12d
  cmp    %r8d,%r9d
  jge    L132
  mov    %r9d,0x0(%rbp)
  mov    %rcx,%rsi
  mov    %r15,%rdi
  call   *%r14
  cmp    %r13,%rbp
  je     L99
  lea    -0x1(%r12),%ebx
L78:
  test   %ebx,%ebx
  jle    L81
  lea    0x4(%rbp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L6
L132:
  mov    %r8d,%ebx
  mov    %r8d,0x0(%rbp)
  je     L94
L40:
  cmp    %r13,%rbp
  je     L112
  cmp    %ebx,%r12d
  jg     L74
L66:
  sub    $0x1,%ebx
  jmp    L78
L94:
  mov    %rcx,%rsi
  mov    %r15,%rdi
  call   *%r14
  jmp    L40
L74:
  lea    0x4(%rbp),%rdx
  mov    %r12d,%r9d
  sub    %ebx,%r9d
  mov    %ebx,%r8d
  mov    %r13,%rcx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <spread_success>
  test   %eax,%eax
  jne    L66
  jmp    L13
L1:
  sub    $0x1,%ebx
  je     L81
L6:
  mov    %ebx,0x0(%rbp)
  mov    %r12d,%r9d
  sub    %ebx,%r9d
  mov    %ebx,%r8d
  mov    %r13,%rcx
  mov    0x8(%rsp),%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <spread_success>
  test   %eax,%eax
  jne    L1
  mov    $0x1,%eax
  jmp    L13
L81:
  mov    $0x1,%eax
L13:
  movl   $0x0,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  mov    $0x1,%eax
  jmp    L13
L112:
  mov    $0x1,%eax
  jmp    L13
```

assistant: ```c
int spread_success(void (*report_pattern)(int *base, int *lim), int *base, int *next, int *lim, int max, int n) {
  int i;
  if (n < max) {
    *next = n;
    report_pattern(base, lim);
    if (next == lim) {
      *next = 0;
      return 1;
    }
    i = n - 1;
  } else {
    *next = max;
    if (n == max)
      report_pattern(base, lim);
    if (next == lim) {
      *next = 0;
      return 1;
    }
    if (n > max && !spread_success(report_pattern, base, next + 1, lim, max, n - max)) {
      *next = 0;
      return 0;
    }
    i = max - 1;
  }
  for (; i > 0; i--) {
    *next = i;
    if (!spread_success(report_pattern, base, next + 1, lim, i, n - i)) {
      *next = 0;
      return 1;
    }
  }
  *next = 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spread_success>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r8d,%r9d
  jge    L100
  mov    %r9d,0x0(%rbp)
  mov    %rcx,%rsi
  mov    %r15,%rdi
  lea    -0x1(%r12),%ebx
  call   *%r14
  cmp    %r13,%rbp
  je     L5
L95:
  lea    0x4(%rbp),%rdx
  test   %ebx,%ebx
  jle    L5
L62:
  mov    %ebx,0x0(%rbp)
  mov    %r12d,%r9d
  mov    %ebx,%r8d
  mov    %r13,%rcx
  sub    %ebx,%r9d
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %rdx,0x8(%rsp)
  call   <spread_success>
  test   %eax,%eax
  je     L5
  sub    $0x1,%ebx
  mov    0x8(%rsp),%rdx
  jne    L62
L5:
  mov    $0x1,%eax
L19:
  movl   $0x0,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L100:
  mov    %r8d,0x0(%rbp)
  mov    %r8d,%ebx
  jne    L32
  mov    %rcx,%rsi
  mov    %r15,%rdi
  call   *%r14
L32:
  cmp    %r13,%rbp
  je     L5
  cmp    %ebx,%r12d
  jg     L78
L76:
  sub    $0x1,%ebx
  jmp    L95
  nopl   0x0(%rax)
L78:
  mov    %r12d,%r9d
  lea    0x4(%rbp),%rdx
  mov    %ebx,%r8d
  mov    %r13,%rcx
  sub    %ebx,%r9d
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <spread_success>
  test   %eax,%eax
  jne    L76
  jmp    L19
```

assistant: ```c
int spread_success(void (*report_pattern)(int *base, int *lim), int *base, int *next, int *lim, int max, int n) {
  int i;
  if (n < max) {
    *next = n;
    report_pattern(base, lim);
    if (next == lim) {
      *next = 0;
      return 1;
    }
    i = n - 1;
  } else {
    *next = max;
    if (n == max)
      report_pattern(base, lim);
    if (next == lim) {
      *next = 0;
      return 1;
    }
    if (n > max && !spread_success(report_pattern, base, next + 1, lim, max, n - max)) {
      *next = 0;
      return 0;
    }
    i = max - 1;
  }
  for (; i > 0; i--) {
    *next = i;
    if (!spread_success(report_pattern, base, next + 1, lim, i, n - i)) {
      *next = 0;
      return 1;
    }
  }
  *next = 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ln_factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  pxor   %xmm0,%xmm0
  jmp    L56
L14:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L25
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L9
L25:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L9:
  movsd  D18(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%edi
  call   <log@plt>
  shr    %eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <log@plt>
  imul   -0x14(%rbp),%eax
  add    %ebx,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L43
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L56
L43:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L56:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D18
datatype: byte[8]
name: read_data
arguments: label: D2
datatype: f64

tool: {"D18": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D2: 3.1415926

assistant: ```c
double ln_factorial(unsigned int n) {
  if (n == 0)
    return 0;
  return log((2 * n + 1 / 3.0) * 3.1415926) / 2 + n * log(n) - n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ln_factorial>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %edi,%edi
  jne    L9
  ret
L9:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    (%rdi,%rdi,1),%eax
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D9(%rip),%xmm0
  mulsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <log@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <log@plt>
  shr    %ebp
  imul   %ebx,%eax
  add    %eax,%ebp
  sub    %ebx,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D13
type_guessed: f64

tool: {"D9": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D13: 3.1415926

assistant: ```c
double ln_factorial(unsigned int n) {
  if (n == 0)
    return 0;
  return log((2 * n + 1 / 3.0) * 3.1415926) / 2 + n * log(n) - n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ln_factorial>:
  endbr64
  test   %edi,%edi
  jne    L6
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L6:
  push   %rbp
  lea    (%rdi,%rdi,1),%eax
  pxor   %xmm0,%xmm0
  push   %rbx
  cvtsi2sd %rax,%xmm0
  mov    %edi,%ebx
  sub    $0x8,%rsp
  addsd  D7(%rip),%xmm0
  mulsd  D9(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <log@plt>
  mov    %ebx,%edi
  mov    %eax,%ebp
  call   <log@plt>
  shr    %ebp
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  imul   %ebx,%eax
  add    %eax,%ebp
  sub    %ebx,%ebp
  pop    %rbx
  cvtsi2sd %rbp,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: byte[8]
name: disassemble_data
arguments: label: D9
datatype: f64

tool: {"D7": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D9: 3.1415926

assistant: ```c
double ln_factorial(unsigned int n) {
  if (n == 0)
    return 0;
  return log((2 * n + 1 / 3.0) * 3.1415926) / 2 + n * log(n) - n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ln_factorial>:
  endbr64
  test   %edi,%edi
  jne    L0
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L0:
  push   %rbp
  lea    (%rdi,%rdi,1),%eax
  pxor   %xmm0,%xmm0
  push   %rbx
  cvtsi2sd %rax,%xmm0
  mov    %edi,%ebx
  sub    $0x8,%rsp
  addsd  D18(%rip),%xmm0
  mulsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <log@plt>
  mov    %ebx,%edi
  mov    %eax,%ebp
  call   <log@plt>
  shr    %ebp
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  imul   %ebx,%eax
  add    %eax,%ebp
  sub    %ebx,%ebp
  pop    %rbx
  cvtsi2sd %rbp,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
datatype: byte[8]
name: unpack_data
arguments: data_tag: D3
datatype: f64

tool: {"D18": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D3: 3.1415926

assistant: ```c
double ln_factorial(unsigned int n) {
  if (n == 0)
    return 0;
  return log((2 * n + 1 / 3.0) * 3.1415926) / 2 + n * log(n) - n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rev32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    %eax
  and    $0x55555555,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x2,%eax
  and    $0xcccccccc,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x4,%eax
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x10,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rev32(uint32_t *x) {
  *x = ((*x) & 0x55555555) << 1 | ((*x) & 0xAAAAAAAA) >> 1;
  *x = ((*x) & 0x33333333) << 2 | ((*x) & 0xCCCCCCCC) >> 2;
  *x = ((*x) & 0x0F0F0F0F) << 4 | ((*x) & 0xF0F0F0F0) >> 4;
  *x = ((*x) & 0x00FF00FF) << 8 | ((*x) & 0xFF00FF00) >> 8;
  *x = ((*x) & 0x0000FFFF) << 16 | ((*x) & 0xFFFF0000) >> 16;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rev32>:
  endbr64
  mov    (%rdi),%edx
  lea    (%rdx,%rdx,1),%eax
  and    $0xaaaaaaaa,%eax
  shr    %edx
  and    $0x55555555,%edx
  or     %edx,%eax
  lea    0x0(,%rax,4),%edx
  and    $0xcccccccc,%edx
  shr    $0x2,%eax
  and    $0x33333333,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  shr    $0x4,%edx
  and    $0xf0f0f0f,%edx
  or     %edx,%eax
  mov    %eax,%edx
  shl    $0x8,%edx
  and    $0xff00ff00,%edx
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  or     %edx,%eax
  rol    $0x10,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void rev32(uint32_t *x) {
  *x = ((*x) & 0x55555555) << 1 | ((*x) & 0xAAAAAAAA) >> 1;
  *x = ((*x) & 0x33333333) << 2 | ((*x) & 0xCCCCCCCC) >> 2;
  *x = ((*x) & 0x0F0F0F0F) << 4 | ((*x) & 0xF0F0F0F0) >> 4;
  *x = ((*x) & 0x00FF00FF) << 8 | ((*x) & 0xFF00FF00) >> 8;
  *x = ((*x) & 0x0000FFFF) << 16 | ((*x) & 0xFFFF0000) >> 16;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rev32>:
  endbr64
  mov    (%rdi),%eax
  lea    (%rax,%rax,1),%edx
  shr    %eax
  and    $0x55555555,%eax
  and    $0xaaaaaaaa,%edx
  or     %eax,%edx
  lea    0x0(,%rdx,4),%eax
  shr    $0x2,%edx
  and    $0x33333333,%edx
  and    $0xcccccccc,%eax
  or     %edx,%eax
  mov    %eax,%edx
  shr    $0x4,%eax
  shl    $0x4,%edx
  and    $0xf0f0f0f,%eax
  and    $0xf0f0f0f0,%edx
  or     %edx,%eax
  bswap  %eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void rev32(uint32_t *x) {
  *x = ((*x) & 0x55555555) << 1 | ((*x) & 0xAAAAAAAA) >> 1;
  *x = ((*x) & 0x33333333) << 2 | ((*x) & 0xCCCCCCCC) >> 2;
  *x = ((*x) & 0x0F0F0F0F) << 4 | ((*x) & 0xF0F0F0F0) >> 4;
  *x = ((*x) & 0x00FF00FF) << 8 | ((*x) & 0xFF00FF00) >> 8;
  *x = ((*x) & 0x0000FFFF) << 16 | ((*x) & 0xFFFF0000) >> 16;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_exact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L11
  mov    -0x4(%rbp),%eax
  jmp    L6
L11:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L9
  mov    -0x18(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int write_exact(int fd, void *buf, int len) {
  int i, wrote = 0;
  do {
    if ((i = write(fd, buf + wrote, len - wrote)) <= 0)
      return i;
    wrote += i;
  } while (wrote < len);
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_exact>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%ebx
L7:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r12,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L4
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jg     L7
  mov    %ebp,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_exact(int fd, void *buf, int len) {
  int i, wrote = 0;
  do {
    if ((i = write(fd, buf + wrote, len - wrote)) <= 0)
      return i;
    wrote += i;
  } while (wrote < len);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_exact>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L20:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L11
L26:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %r12,%rsi
  call   <write@plt>
  test   %eax,%eax
  jg     L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_exact(int fd, void *buf, int len) {
  int i, wrote = 0;
  do {
    if ((i = write(fd, buf + wrote, len - wrote)) <= 0)
      return i;
    wrote += i;
  } while (wrote < len);
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_exact>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L21:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L12
L19:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %r12,%rsi
  call   <write@plt>
  test   %eax,%eax
  jg     L21
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_exact(int fd, void *buf, int len) {
  int i, wrote = 0;
  do {
    if ((i = write(fd, buf + wrote, len - wrote)) <= 0)
      return i;
    wrote += i;
  } while (wrote < len);
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x7ec(%rbp)
  subl   $0x1,-0x7ec(%rbp)
  jmp    L34
L48:
  mov    -0x7ec(%rbp),%eax
  cltq
  movzbl -0x7e0(%rbp,%rax,1),%edx
  mov    -0x7e8(%rbp),%eax
  cltq
  mov    %dl,-0x3f0(%rbp,%rax,1)
  addl   $0x1,-0x7e8(%rbp)
  subl   $0x1,-0x7ec(%rbp)
L34:
  cmpl   $0x0,-0x7ec(%rbp)
  jns    L48
  mov    -0x7e8(%rbp),%eax
  mov    %eax,-0x7e4(%rbp)
  movl   $0x0,-0x7e8(%rbp)
  jmp    L5
L21:
  mov    -0x7e8(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x7e8(%rbp)
L5:
  mov    -0x7e8(%rbp),%eax
  cmp    -0x7e4(%rbp),%eax
  jl     L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D0: Text:

tool: D7: %[^
]s

assistant: ```c
int main() {
  char text6[1000];
  char text9[1000];
  int l, a = 0, n;
  printf("Text:");
  scanf("%[^\n]s", text6);
  l = strlen(text6);
  for (l = l - 1; l >= 0; l--) {
    text9[a] = text6[l];
    a++;
  }
  n = a;
  for (a = 0; a < n; a++) {
    printf("%c", text9[a]);
  }
  return 0;
}
```