ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    %rsi,%r8
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%r8),%rdi
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L17
  mov    $0x1,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L17:
  mov    %rax,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L27
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: %ld

assistant: ```c
int main(int argc, const char *argv[]) {
  long d;
  char *endptr;
  d = strtol(argv[1], &endptr, 8);
  if (*endptr != '\0')
    return (1);
  printf("%ld", d);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    %rsi,%r8
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%r8),%rdi
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L16
  mov    $0x1,%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
L16:
  mov    %rax,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L26
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: %ld

assistant: ```c
int main(int argc, const char *argv[]) {
  long d;
  char *endptr;
  d = strtol(argv[1], &endptr, 8);
  if (*endptr != '\0')
    return (1);
  printf("%ld", d);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<concatenate_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L24
L17:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  movl   $0x0,-0x18(%rbp)
  jmp    L38
L32:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L38:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: The size of the string is %d


assistant: ```c
char *concatenate_string(char *original, char *add) {
  int originalSize = strlen(original);
  int addSize = strlen(add);
  int totalSize = originalSize + addSize;
  printf("The size of the string is %d\n", totalSize + 1);
  char *combinedWord = (char *)malloc(totalSize * sizeof(char));
  int i;
  for (i = 0; i < originalSize; i++) {
    combinedWord[i] = original[i];
  }
  for (i = 0; i < addSize; i++) {
    combinedWord[originalSize + i] = add[i];
  }
  return combinedWord;
}
```
user: What is the c source code of the assembly code below:

```asm
<concatenate_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x0(%rbp,%rax,1),%r14d
  lea    0x1(%r14),%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %ebp,%ebp
  jle    L24
  lea    -0x1(%rbp),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    %rdi,%rax
  mov    %r13,%rcx
  sub    %rdi,%rcx
L13:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L13
L24:
  test   %r12d,%r12d
  jle    L17
  movslq %ebp,%rbp
  add    %rdi,%rbp
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%rsi
  mov    %rbp,%rax
  sub    %rbp,%rbx
  mov    %rbx,%rcx
L11:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L11
L17:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: The size of the string is %d


assistant: ```c
char *concatenate_string(char *original, char *add) {
  int originalSize = strlen(original);
  int addSize = strlen(add);
  int totalSize = originalSize + addSize;
  printf("The size of the string is %d\n", totalSize + 1);
  char *combinedWord = (char *)malloc(totalSize * sizeof(char));
  int i;
  for (i = 0; i < originalSize; i++) {
    combinedWord[i] = original[i];
  }
  for (i = 0; i < addSize; i++) {
    combinedWord[originalSize + i] = add[i];
  }
  return combinedWord;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<concatenate_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    D3(%rip),%rdi
  lea    (%rbx,%rax,1),%r14d
  mov    %eax,%r13d
  lea    0x1(%r14),%esi
  call   <printf@plt>
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L34
  lea    -0x1(%rbx),%eax
  mov    %r12,%rcx
  lea    0x1(%r8,%rax,1),%rsi
  sub    %r8,%rcx
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L29
L34:
  test   %r13d,%r13d
  jle    L11
  movslq %ebx,%rax
  lea    -0x1(%r13),%edx
  add    %r8,%rax
  lea    0x1(%rax,%rdx,1),%rcx
  sub    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  movzbl 0x0(%rbp,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L6
L11:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: The size of the string is %d


assistant: ```c
char *concatenate_string(char *original, char *add) {
  int originalSize = strlen(original);
  int addSize = strlen(add);
  int totalSize = originalSize + addSize;
  printf("The size of the string is %d\n", totalSize + 1);
  char *combinedWord = (char *)malloc(totalSize * sizeof(char));
  int i;
  for (i = 0; i < originalSize; i++) {
    combinedWord[i] = original[i];
  }
  for (i = 0; i < addSize; i++) {
    combinedWord[originalSize + i] = add[i];
  }
  return combinedWord;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readLongLong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <readInt@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x4(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <readInt@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %rax,-0x8(%rbp)
  shlq   $0x20,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long readLongLong(int pos, unsigned char *cmddata) {
  unsigned int a, b;
  unsigned long long c;
  a = readInt(pos, cmddata);
  b = readInt(pos + 4, cmddata);
  c = a;
  c <<= 32;
  c |= b;
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<readLongLong>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  call   <readInt@plt>
  mov    %eax,%ebp
  lea    0x4(%rbx),%edi
  mov    %r12,%rsi
  call   <readInt@plt>
  shl    $0x20,%rbp
  mov    %eax,%eax
  or     %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long readLongLong(int pos, unsigned char *cmddata) {
  unsigned int a, b;
  unsigned long long c;
  a = readInt(pos, cmddata);
  b = readInt(pos + 4, cmddata);
  c = a;
  c <<= 32;
  c |= b;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readLongLong>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  call   <readInt@plt>
  lea    0x4(%rbx),%edi
  mov    %r12,%rsi
  mov    %eax,%ebp
  call   <readInt@plt>
  shl    $0x20,%rbp
  pop    %rbx
  mov    %eax,%eax
  or     %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long readLongLong(int pos, unsigned char *cmddata) {
  unsigned int a, b;
  unsigned long long c;
  a = readInt(pos, cmddata);
  b = readInt(pos + 4, cmddata);
  c = a;
  c <<= 32;
  c |= b;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readLongLong>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  call   <readInt@plt>
  lea    0x4(%rbx),%edi
  mov    %r12,%rsi
  mov    %eax,%ebp
  call   <readInt@plt>
  shl    $0x20,%rbp
  pop    %rbx
  mov    %eax,%eax
  or     %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long readLongLong(int pos, unsigned char *cmddata) {
  unsigned int a, b;
  unsigned long long c;
  a = readInt(pos, cmddata);
  b = readInt(pos + 4, cmddata);
  c = a;
  c <<= 32;
  c |= b;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pfail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void pfail(const char *s) {
  perror(s);
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pfail>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pfail(const char *s) {
  perror(s);
  exit(EXIT_FAILURE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pfail>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void pfail(const char *s) {
  perror(s);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pfail>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void pfail(const char *s) {
  perror(s);
  exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<log_combination_k_r_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  movss  %xmm0,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L12
  pxor   %xmm0,%xmm0
  jmp    L30
L12:
  mov    -0x24(%rbp),%eax
  test   %rax,%rax
  js     L16
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L8
L16:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L8:
  addss  -0x28(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <lgammaf@plt>
  movd   %xmm0,%ebx
  mov    -0x28(%rbp),%eax
  movd   %eax,%xmm0
  call   <lgammaf@plt>
  movd   %ebx,%xmm2
  subss  %xmm0,%xmm2
  movss  %xmm2,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <log_factorial_f@plt>
  movaps %xmm0,%xmm1
  movss  -0x2c(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
L30:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
float log_combination_k_r_f(unsigned int k, float r) {
  if (!k)
    return 0;
  float val = lgammaf(k + r) - lgammaf(r) - log_factorial_f(k);
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_combination_k_r_f>:
  endbr64
  test   %edi,%edi
  jne    L7
  pxor   %xmm0,%xmm0
  ret
L7:
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  movaps %xmm0,%xmm2
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm2,0xc(%rsp)
  addss  %xmm2,%xmm0
  call   <lgammaf@plt>
  movss  %xmm0,0x8(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <lgammaf@plt>
  movss  0x8(%rsp),%xmm3
  subss  %xmm0,%xmm3
  movss  %xmm3,0x8(%rsp)
  mov    %ebx,%edi
  call   <log_factorial_f@plt>
  movaps %xmm0,%xmm1
  movss  0x8(%rsp),%xmm0
  subss  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
float log_combination_k_r_f(unsigned int k, float r) {
  if (!k)
    return 0;
  float val = lgammaf(k + r) - lgammaf(r) - log_factorial_f(k);
  return val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log_combination_k_r_f>:
  endbr64
  test   %edi,%edi
  jne    L6
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L6:
  movaps %xmm0,%xmm2
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  cvtsi2ss %rax,%xmm0
  mov    %edi,%ebp
  sub    $0x10,%rsp
  movss  %xmm2,0xc(%rsp)
  addss  %xmm2,%xmm0
  call   <lgammaf@plt>
  movss  0xc(%rsp),%xmm2
  movss  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <lgammaf@plt>
  movss  0x8(%rsp),%xmm1
  mov    %ebp,%edi
  subss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <log_factorial_f@plt>
  movss  0x8(%rsp),%xmm1
  add    $0x10,%rsp
  pop    %rbp
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float log_combination_k_r_f(unsigned int k, float r) {
  if (!k)
    return 0;
  float val = lgammaf(k + r) - lgammaf(r) - log_factorial_f(k);
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log_combination_k_r_f>:
  endbr64
  test   %edi,%edi
  jne    L7
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L7:
  movaps %xmm0,%xmm2
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  cvtsi2ss %rax,%xmm0
  mov    %edi,%ebp
  sub    $0x10,%rsp
  movss  %xmm2,0xc(%rsp)
  addss  %xmm2,%xmm0
  call   <lgammaf@plt>
  movss  0xc(%rsp),%xmm2
  movss  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <lgammaf@plt>
  movss  0x8(%rsp),%xmm1
  mov    %ebp,%edi
  subss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <log_factorial_f@plt>
  movss  0x8(%rsp),%xmm1
  add    $0x10,%rsp
  pop    %rbp
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float log_combination_k_r_f(unsigned int k, float r) {
  if (!k)
    return 0;
  float val = lgammaf(k + r) - lgammaf(r) - log_factorial_f(k);
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L19
  cmpq   $0x6,-0x8(%rbp)
  jle    L4
L19:
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
__attribute__((no)) void foo(void *p) {
  long l = (long)p;
  if (l < 0 || l > 6)
    abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  cmp    $0x6,%rdi
  ja     L5
  ret
L5:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((no)) void foo(void *p) {
  long l = (long)p;
  if (l < 0 || l > 6)
    abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  cmp    $0x6,%rdi
  ja     L6
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
__attribute__((no)) void foo(void *p) {
  long l = (long)p;
  if (l < 0 || l > 6)
    abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  cmp    $0x6,%rdi
  ja     L3
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
__attribute__((no)) void foo(void *p) {
  long l = (long)p;
  if (l < 0 || l > 6)
    abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x200,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jns    L17
  mov    $0x0,%eax
  jmp    L49
L17:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L27
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  movq   $0x1,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
L27:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <u8_toucs@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpq   $0x0,-0x38(%rbp)
  je     L1
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L1:
  mov    -0x10(%rbp),%rax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  u_int32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((ssize_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (u_int32_t *)alloca((cnt + 1) * sizeof(u_int32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x200,%edi
  call   <alloca@plt>
  mov    %rax,%r13
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  js     L27
  mov    %rax,%rbx
  cmp    $0x1ff,%rax
  ja     L4
  lea    0x1(%rax),%r12
  lea    0x0(,%r12,8),%rdi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <u8_toucs@plt>
  mov    %rax,%r12
  movq   $0x0,(%r14,%rax,8)
  mov    %r14,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
L27:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    %r12,%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L4:
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  lea    0x0(,%r12,8),%rdi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <u8_toucs@plt>
  mov    %rax,%r12
  movq   $0x0,(%r14,%rax,8)
  mov    %r14,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L27
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  u_int32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((ssize_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (u_int32_t *)alloca((cnt + 1) * sizeof(u_int32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rdi,%r14
  mov    $0x200,%edi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <vsnprintf@plt>
  test   %rax,%rax
  js     L27
  lea    0x1(%rax),%r13
  mov    %rax,%r12
  lea    0x0(,%r13,8),%r8
  cmp    $0x1ff,%rax
  ja     L37
  mov    %r8,%rdi
  call   <alloca@plt>
  mov    %r13,%rsi
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <u8_toucs@plt>
  mov    %r14,%rsi
  lea    D15(%rip),%rdi
  movq   $0x0,(%r14,%rax,8)
  mov    %rax,%r13
  call   <printf@plt>
L27:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  lea    -0x28(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L37:
  mov    %r13,%rdi
  mov    %r8,-0x48(%rbp)
  call   <malloc@plt>
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <vsnprintf@plt>
  mov    -0x48(%rbp),%rdi
  call   <alloca@plt>
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <u8_toucs@plt>
  mov    %r14,%rsi
  lea    D15(%rip),%rdi
  movq   $0x0,(%r14,%rax,8)
  mov    %rax,%r13
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L27
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type: string

tool: D15: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  u_int32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((ssize_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (u_int32_t *)alloca((cnt + 1) * sizeof(u_int32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```