ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<query_attribute_get_display_where_clause>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <strcpy@plt>
  mov    %r14,%rdx
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <search_replace_string@plt>
  lea    D39(%rip),%rdx
  lea    D29(%rip),%rsi
  mov    %rbp,%rdi
  call   <search_replace_string@plt>
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r12,%rdi
  lea    D52(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <search_replace_string@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D24(%rip),%rsi
  call   <sprintf@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <search_replace_string@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D44
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D29
datatype: string
name: retrieve_data
arguments: tag: D52
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string

tool: 

tool: D44: 1 = 1 and 

tool: D39: entire folder

tool: D29: 1 = 1

tool: D52: %s_%s.

tool: D24: %s.

assistant: ```c
void query_attribute_get_display_where_clause(char *display_where_clause, char *where_clause, char *application_name, char *folder_name) {
  char remove_folder_name_string[1024];
  strcpy(display_where_clause, where_clause);
  search_replace_string(display_where_clause, "1 = 1 and ", "");
  search_replace_string(display_where_clause, "1 = 1", "entire folder");
  sprintf(remove_folder_name_string, "%s_%s.", application_name, folder_name);
  search_replace_string(display_where_clause, remove_folder_name_string, "");
  sprintf(remove_folder_name_string, "%s.", folder_name);
  search_replace_string(display_where_clause, remove_folder_name_string, "");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x5,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L18
  addl   $0x1,-0xc(%rbp)
L18:
  mov    $0x2c,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L61
L17:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x2,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L61:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L17
  movl   $0x1,-0x10(%rbp)
  movl   $0xa,-0x14(%rbp)
  jmp    L15
L28:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x2,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L28
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L24
L59:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L24:
  cmpl   $0xa,-0x14(%rbp)
  jle    L59
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type: string
name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string

tool: D20: This is a series of od different ways to travel along a linera array

tool: D3: First off: bounce from one end to the other until reaching the middle.

tool: D24: %i 

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int midp = 11 / 2;
  if (midp % 2 == 1)
    midp++;
  int *ia = malloc(11 * sizeof(int));
  j = 0;
  for (i = 0; i < midp; i++) {
    ia[j] = i;
    j += 2;
  }
  j = 1;
  for (i = 11 - 1; i >= midp; i--) {
    ia[j] = i;
    j += 2;
  }
  printf("This is a series of od different ways to travel along a linera array\n");
  printf("First off: bounce from one end to the other until reaching the middle.\n");
  for (i = 0; i < 11; ++i)
    printf("%i ", ia[i]);
  printf("\n");
  free(ia);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2c,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movl   $0x0,(%rax)
  movl   $0x1,0x8(%rax)
  movl   $0x2,0x10(%rax)
  movl   $0x3,0x18(%rax)
  movl   $0x4,0x20(%rax)
  movl   $0x5,0x28(%rax)
  movl   $0xa,0x4(%rax)
  movl   $0x9,0xc(%rax)
  movl   $0x8,0x14(%rax)
  movl   $0x7,0x1c(%rax)
  movl   $0x6,0x24(%rax)
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rbx
  lea    0x2c(%rbp),%r13
  lea    D18(%rip),%r12
L8:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string

tool: D1: This is a series of od different ways to travel along a linera array

tool: D7: First off: bounce from one end to the other until reaching the middle.

tool: D18: %i 

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int midp = 11 / 2;
  if (midp % 2 == 1)
    midp++;
  int *ia = malloc(11 * sizeof(int));
  j = 0;
  for (i = 0; i < midp; i++) {
    ia[j] = i;
    j += 2;
  }
  j = 1;
  for (i = 11 - 1; i >= midp; i--) {
    ia[j] = i;
    j += 2;
  }
  printf("This is a series of od different ways to travel along a linera array\n");
  printf("First off: bounce from one end to the other until reaching the middle.\n");
  for (i = 0; i < 11; ++i)
    printf("%i ", ia[i]);
  printf("\n");
  free(ia);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2c,%edi
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%r13
  movabs $0xa00000000,%rax
  mov    %rax,0x0(%r13)
  mov    %r13,%rbx
  lea    0x2c(%r13),%r12
  movabs $0x900000001,%rax
  mov    %rax,0x8(%r13)
  movabs $0x800000002,%rax
  mov    %rax,0x10(%r13)
  movabs $0x700000003,%rax
  mov    %rax,0x18(%r13)
  movabs $0x600000004,%rax
  mov    %rax,0x20(%r13)
  movl   $0x5,0x28(%r13)
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  nop
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D12
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D10: %i 

tool: D12: This is a series of od different ways to travel along a linera array

tool: D9: First off: bounce from one end to the other until reaching the middle.

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int midp = 11 / 2;
  if (midp % 2 == 1)
    midp++;
  int *ia = malloc(11 * sizeof(int));
  j = 0;
  for (i = 0; i < midp; i++) {
    ia[j] = i;
    j += 2;
  }
  j = 1;
  for (i = 11 - 1; i >= midp; i--) {
    ia[j] = i;
    j += 2;
  }
  printf("This is a series of od different ways to travel along a linera array\n");
  printf("First off: bounce from one end to the other until reaching the middle.\n");
  for (i = 0; i < 11; ++i)
    printf("%i ", ia[i]);
  printf("\n");
  free(ia);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2c,%edi
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D22(%rip),%rdi
  mov    %rax,%r13
  movabs $0xa00000000,%rax
  mov    %rax,0x0(%r13)
  mov    %r13,%rbx
  lea    0x2c(%r13),%r12
  movabs $0x900000001,%rax
  mov    %rax,0x8(%r13)
  movabs $0x800000002,%rax
  mov    %rax,0x10(%r13)
  movabs $0x700000003,%rax
  mov    %rax,0x18(%r13)
  movabs $0x600000004,%rax
  mov    %rax,0x20(%r13)
  movl   $0x5,0x28(%r13)
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  nop
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D22
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string

tool: D1: %i 

tool: D22: This is a series of od different ways to travel along a linera array

tool: D5: First off: bounce from one end to the other until reaching the middle.

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int midp = 11 / 2;
  if (midp % 2 == 1)
    midp++;
  int *ia = malloc(11 * sizeof(int));
  j = 0;
  for (i = 0; i < midp; i++) {
    ia[j] = i;
    j += 2;
  }
  j = 1;
  for (i = 11 - 1; i >= midp; i--) {
    ia[j] = i;
    j += 2;
  }
  printf("This is a series of od different ways to travel along a linera array\n");
  printf("First off: bounce from one end to the other until reaching the middle.\n");
  for (i = 0; i < 11; ++i)
    printf("%i ", ia[i]);
  printf("\n");
  free(ia);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chSysUnconditionalUnlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <port_get_irq_status@plt>
  mov    %eax,%edi
  call   <port_irq_enabled@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  call   <chSysUnlock@plt>
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chSysUnconditionalUnlock(void) {
  if (!port_irq_enabled(port_get_irq_status()))
    chSysUnlock();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chSysUnconditionalUnlock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <port_get_irq_status@plt>
  mov    %eax,%edi
  call   <port_irq_enabled@plt>
  test   %eax,%eax
  je     L13
L5:
  add    $0x8,%rsp
  ret
L13:
  call   <chSysUnlock@plt>
  jmp    L5
```

assistant: ```c
void chSysUnconditionalUnlock(void) {
  if (!port_irq_enabled(port_get_irq_status()))
    chSysUnlock();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chSysUnconditionalUnlock>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <port_get_irq_status@plt>
  mov    %eax,%edi
  call   <port_irq_enabled@plt>
  test   %eax,%eax
  je     L2
  add    $0x8,%rsp
  ret
  nop
L2:
  add    $0x8,%rsp
  jmp    1070 <chSysUnlock@plt>
```

assistant: ```c
void chSysUnconditionalUnlock(void) {
  if (!port_irq_enabled(port_get_irq_status()))
    chSysUnlock();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chSysUnconditionalUnlock>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <port_get_irq_status@plt>
  mov    %eax,%edi
  call   <port_irq_enabled@plt>
  test   %eax,%eax
  je     L0
  add    $0x8,%rsp
  ret
  nop
L0:
  add    $0x8,%rsp
  jmp    1070 <chSysUnlock@plt>
```

assistant: ```c
void chSysUnconditionalUnlock(void) {
  if (!port_irq_enabled(port_get_irq_status()))
    chSysUnlock();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<APDUGetTag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  jle    L11
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L32:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  or     %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x2,-0x8(%rbp)
  jle    L32
  mov    -0x4(%rbp),%eax
  jmp    L39
L11:
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int APDUGetTag(const uint8_t *p_apdu, int i_size) {
  if (i_size >= 3) {
    int i, t = 0;
    for (i = 0; i < 3; i++)
      t = (t << 8) | *p_apdu++;
    return t;
  }
  return 0x000000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<APDUGetTag>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x2,%esi
  jg     L1
L5:
  ret
L1:
  mov    (%rdi),%eax
  shl    $0x8,%eax
  or     0x4(%rdi),%eax
  shl    $0x8,%eax
  or     0x8(%rdi),%eax
  jmp    L5
```

assistant: ```c
int APDUGetTag(const uint8_t *p_apdu, int i_size) {
  if (i_size >= 3) {
    int i, t = 0;
    for (i = 0; i < 3; i++)
      t = (t << 8) | *p_apdu++;
    return t;
  }
  return 0x000000;
}
```
user: What is the c source code of the assembly code below:

```asm
<APDUGetTag>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%esi
  jg     L6
  ret
  nopl   0x0(%rax)
L6:
  mov    (%rdi),%eax
  shl    $0x8,%eax
  or     0x4(%rdi),%eax
  shl    $0x8,%eax
  or     0x8(%rdi),%eax
  ret
```

assistant: ```c
int APDUGetTag(const uint8_t *p_apdu, int i_size) {
  if (i_size >= 3) {
    int i, t = 0;
    for (i = 0; i < 3; i++)
      t = (t << 8) | *p_apdu++;
    return t;
  }
  return 0x000000;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<APDUGetTag>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%esi
  jg     L1
  ret
  nopl   0x0(%rax)
L1:
  mov    (%rdi),%eax
  shl    $0x8,%eax
  or     0x4(%rdi),%eax
  shl    $0x8,%eax
  or     0x8(%rdi),%eax
  ret
```

assistant: ```c
int APDUGetTag(const uint8_t *p_apdu, int i_size) {
  if (i_size >= 3) {
    int i, t = 0;
    for (i = 0; i < 3; i++)
      t = (t << 8) | *p_apdu++;
    return t;
  }
  return 0x000000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<long_to_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %rcx,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x8,%eax
  je     L13
  mov    -0x90(%rbp),%rax
  movl   $0xffffffff,(%rax)
  mov    -0x90(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x88(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x88(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x80(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L22
L13:
  lea    -0x70(%rbp),%rax
  add    $0x4,%rax
  lea    -0x50(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  lea    -0x50(%rbp),%rax
  add    $0x2,%rax
  lea    -0x30(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  movb   $0x0,-0x6c(%rbp)
  movb   $0x0,-0x4e(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x80(%rbp),%rdx
  mov    %eax,(%rdx)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x88(%rbp),%rdx
  mov    %eax,(%rdx)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x90(%rbp),%rdx
  mov    %eax,(%rdx)
L22:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: %ld

assistant: ```c
void long_to_date(long l, int *y, int *m, int *d) {
  char year[32], month[32], day[32];
  sprintf(year, "%ld", l);
  if (strlen(year) != 8) {
    *y = *m = *d = -1;
    return;
  }
  strcpy(month, year + 4);
  strcpy(day, month + 2);
  year[4] = '\0';
  month[2] = '\0';
  *y = atoi(year);
  *m = atoi(month);
  *d = atoi(day);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<long_to_date>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,%rdx
  lea    D6(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x8,%eax
  je     L17
  movl   $0xffffffff,(%rbx)
  movl   $0xffffffff,0x0(%rbp)
  movl   $0xffffffff,(%r12)
L21:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    %rsp,%r15
  lea    0x4(%rsp),%rsi
  lea    0x20(%rsp),%r14
  mov    %r14,%rdi
  call   <strcpy@plt>
  lea    0x22(%rsp),%rsi
  lea    0x40(%rsp),%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  movb   $0x0,0x4(%rsp)
  movb   $0x0,0x22(%rsp)
  mov    %r15,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  mov    %r14,%rdi
  call   <atoi@plt>
  mov    %eax,0x0(%rbp)
  mov    %r13,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  jmp    L21
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D6: %ld

assistant: ```c
void long_to_date(long l, int *y, int *m, int *d) {
  char year[32], month[32], day[32];
  sprintf(year, "%ld", l);
  if (strlen(year) != 8) {
    *y = *m = *d = -1;
    return;
  }
  strcpy(month, year + 4);
  strcpy(day, month + 2);
  year[4] = '\0';
  month[2] = '\0';
  *y = atoi(year);
  *m = atoi(month);
  *d = atoi(day);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<long_to_date>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D1(%rip),%rsi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rdi,%rdx
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x8,%eax
  je     L24
  movl   $0xffffffff,(%rbx)
  movl   $0xffffffff,0x0(%rbp)
  movl   $0xffffffff,(%r12)
L5:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L24:
  lea    0x20(%rsp),%r15
  lea    0x4(%rsp),%rsi
  mov    %r15,%rdi
  lea    0x40(%rsp),%r14
  call   <strcpy@plt>
  lea    0x22(%rsp),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,0x4(%rsp)
  movb   $0x0,0x22(%rsp)
  call   <atoi@plt>
  mov    %r15,%rdi
  mov    %eax,(%r12)
  call   <atoi@plt>
  mov    %r14,%rdi
  mov    %eax,0x0(%rbp)
  call   <atoi@plt>
  mov    %eax,(%rbx)
  jmp    L5
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: %ld

assistant: ```c
void long_to_date(long l, int *y, int *m, int *d) {
  char year[32], month[32], day[32];
  sprintf(year, "%ld", l);
  if (strlen(year) != 8) {
    *y = *m = *d = -1;
    return;
  }
  strcpy(month, year + 4);
  strcpy(day, month + 2);
  year[4] = '\0';
  month[2] = '\0';
  *y = atoi(year);
  *m = atoi(month);
  *d = atoi(day);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<long_to_date>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rdi,%rdx
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x8,%eax
  je     L24
  movl   $0xffffffff,(%rbx)
  movl   $0xffffffff,0x0(%rbp)
  movl   $0xffffffff,(%r12)
L4:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L24:
  lea    0x20(%rsp),%r15
  lea    0x4(%rsp),%rsi
  mov    %r15,%rdi
  lea    0x40(%rsp),%r14
  call   <strcpy@plt>
  lea    0x22(%rsp),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,0x4(%rsp)
  movb   $0x0,0x22(%rsp)
  call   <atoi@plt>
  mov    %r15,%rdi
  mov    %eax,(%r12)
  call   <atoi@plt>
  mov    %r14,%rdi
  mov    %eax,0x0(%rbp)
  call   <atoi@plt>
  mov    %eax,(%rbx)
  jmp    L4
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: %ld

assistant: ```c
void long_to_date(long l, int *y, int *m, int *d) {
  char year[32], month[32], day[32];
  sprintf(year, "%ld", l);
  if (strlen(year) != 8) {
    *y = *m = *d = -1;
    return;
  }
  strcpy(month, year + 4);
  strcpy(day, month + 2);
  year[4] = '\0';
  month[2] = '\0';
  *y = atoi(year);
  *m = atoi(month);
  *d = atoi(day);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<packi32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void packi32(unsigned char *buf, int i) {
  *buf++ = i >> 24;
  *buf++ = i >> 16;
  *buf++ = i >> 8;
  *buf++ = i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<packi32>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  sar    $0x18,%edx
  mov    %dl,(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x1(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %sil,0x3(%rdi)
  ret
```

assistant: ```c
void packi32(unsigned char *buf, int i) {
  *buf++ = i >> 24;
  *buf++ = i >> 16;
  *buf++ = i >> 8;
  *buf++ = i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<packi32>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void packi32(unsigned char *buf, int i) {
  *buf++ = i >> 24;
  *buf++ = i >> 16;
  *buf++ = i >> 8;
  *buf++ = i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<packi32>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void packi32(unsigned char *buf, int i) {
  *buf++ = i >> 24;
  *buf++ = i >> 16;
  *buf++ = i >> 8;
  *buf++ = i;
}
```