ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<pp_buf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  test   %rdx,%rdx
  je     L96
  mov    %rsi,%r15
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%rbp
  mov    $0x0,%ebx
  jmp    L66
L13:
  mov    %r14,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %r12
  test   %rdx,%rdx
  jne    L66
  jmp    L63
L84:
  cmp    %r13,%rbx
  jae    L96
L66:
  movzbl (%r15,%rbx,1),%edx
  lea    D2(%rip),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  setb   %cl
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L12
  test   %cl,%cl
  jne    L13
L12:
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %r12
  test   %rdx,%rdx
  jne    L84
  test   %cl,%cl
  je     L84
L63:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L66
L96:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: %02x

assistant: ```c
void pp_buf(FILE *fp, char *buf, size_t bufsize, size_t width, size_t group) {
  int i = 0;
  for (i = 0; i < bufsize; ++i) {
    fprintf(fp, "%02x", (unsigned char)*(buf + i));
    if ((i + 1) % group == 0 && i + 1 < bufsize)
      fprintf(fp, " ");
    if ((i + 1) % width == 0 && i + 1 < bufsize)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pp_buf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  test   %rdx,%rdx
  je     L14
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %r8,%rbp
  xor    %ebx,%ebx
  lea    D9(%rip),%r15
  nopl   0x0(%rax)
L4:
  movzbl (%r14,%rbx,1),%edx
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  cmp    %rbx,%r13
  mov    %rbx,%rax
  seta   %cl
  xor    %edx,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L42
  test   %cl,%cl
  jne    L12
L42:
  mov    %rbx,%rax
  xor    %edx,%edx
  divq   0x8(%rsp)
  test   %rdx,%rdx
  jne    L3
  test   %cl,%cl
  jne    L66
L3:
  cmp    %rbx,%r13
  ja     L4
L14:
  add    $0x18,%rsp
  mov    %r12,%rsi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <fputc@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  mov    %rbx,%rax
  xor    %edx,%edx
  divq   0x8(%rsp)
  test   %rdx,%rdx
  jne    L4
L66:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9: %02x

assistant: ```c
void pp_buf(FILE *fp, char *buf, size_t bufsize, size_t width, size_t group) {
  int i = 0;
  for (i = 0; i < bufsize; ++i) {
    fprintf(fp, "%02x", (unsigned char)*(buf + i));
    if ((i + 1) % group == 0 && i + 1 < bufsize)
      fprintf(fp, " ");
    if ((i + 1) % width == 0 && i + 1 < bufsize)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pp_buf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  test   %rdx,%rdx
  je     L13
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %r8,%rbp
  xor    %ebx,%ebx
  lea    D2(%rip),%r15
  nopl   0x0(%rax)
L58:
  movzbl (%r14,%rbx,1),%edx
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  cmp    %rbx,%r13
  mov    %rbx,%rax
  seta   %cl
  xor    %edx,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L23
  test   %cl,%cl
  jne    L36
L23:
  mov    %rbx,%rax
  xor    %edx,%edx
  divq   0x8(%rsp)
  test   %rdx,%rdx
  jne    L21
  test   %cl,%cl
  jne    L71
L21:
  cmp    %rbx,%r13
  ja     L58
L13:
  add    $0x18,%rsp
  mov    %r12,%rsi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <fputc@plt>
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r12,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  mov    %rbx,%rax
  xor    %edx,%edx
  divq   0x8(%rsp)
  test   %rdx,%rdx
  jne    L58
L71:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L58
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string

tool: D2: %02x

assistant: ```c
void pp_buf(FILE *fp, char *buf, size_t bufsize, size_t width, size_t group) {
  int i = 0;
  for (i = 0; i < bufsize; ++i) {
    fprintf(fp, "%02x", (unsigned char)*(buf + i));
    if ((i + 1) % group == 0 && i + 1 < bufsize)
      fprintf(fp, " ");
    if ((i + 1) % width == 0 && i + 1 < bufsize)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_frowkey@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_frowkey();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_frowkey@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_frowkey();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_frowkey@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_frowkey();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_frowkey@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_frowkey();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str7tont>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L33
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  addq   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L29
L20:
  nop
L29:
  pop    %rbp
  ret
```

assistant: ```c
str7tont(s) char *s;
{
  while (!(*s & 0x80)) {
    if (!*s)
      return;
    s++;
  }
  *s = *s & 0x7F;
  *++s = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str7tont>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  js     L16
L26:
  test   %al,%al
  je     L5
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jns    L26
L16:
  and    $0x7f,%eax
  mov    %al,(%rdi)
  movb   $0x0,0x1(%rdi)
L5:
  ret
```

assistant: ```c
str7tont(s) char *s;
{
  while (!(*s & 0x80)) {
    if (!*s)
      return;
    s++;
  }
  *s = *s & 0x7F;
  *++s = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str7tont>:
  endbr64
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L10:
  test   %al,%al
  je     L0
  add    $0x1,%rdi
L18:
  movzbl (%rdi),%eax
  test   %al,%al
  jns    L10
  and    $0x7f,%eax
  movb   $0x0,0x1(%rdi)
  mov    %al,(%rdi)
L0:
  ret
```

assistant: ```c
str7tont(s) char *s;
{
  while (!(*s & 0x80)) {
    if (!*s)
      return;
    s++;
  }
  *s = *s & 0x7F;
  *++s = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<str7tont>:
  endbr64
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L18:
  test   %al,%al
  je     L1
  add    $0x1,%rdi
L28:
  movzbl (%rdi),%eax
  test   %al,%al
  jns    L18
  and    $0x7f,%eax
  movb   $0x0,0x1(%rdi)
  mov    %al,(%rdi)
L1:
  ret
```

assistant: ```c
str7tont(s) char *s;
{
  while (!(*s & 0x80)) {
    if (!*s)
      return;
    s++;
  }
  *s = *s & 0x7F;
  *++s = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <printLine@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L32:
  mov    $0x19,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x4,-0x4(%rbp)
  jle    L32
  movl   $0x0,-0x4(%rbp)
  jmp    L54
L41:
  mov    $0x14,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L54:
  cmpl   $0x4,-0x4(%rbp)
  jle    L41
  movl   $0x1,-0x4(%rbp)
  jmp    L51
L20:
  mov    -0x4(%rbp),%eax
  add    $0x14,%eax
  mov    %eax,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L51:
  cmpl   $0x4,-0x4(%rbp)
  jle    L20
  mov    $0x0,%eax
  call   <printLine@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  printLine();
  for (i = 1; i < 5; ++i) {
    printBlank(20 + (5 - i));
    putchar('C');
    putchar('\n');
  }
  for (i = 0; i < 5; ++i) {
    printBlank(20);
    putchar('C');
    putchar('\n');
  }
  for (i = 1; i < 5; ++i) {
    printBlank(20 + i);
    putchar('C');
    putchar('\n');
  }
  printLine();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <printLine@plt>
  mov    $0x18,%ebx
L21:
  mov    %ebx,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L21
  mov    $0x5,%ebx
L17:
  mov    $0x14,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L17
  mov    $0x15,%ebx
L24:
  mov    %ebx,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    $0x19,%ebx
  jne    L24
  mov    $0x0,%eax
  call   <printLine@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  printLine();
  for (i = 1; i < 5; ++i) {
    printBlank(20 + (5 - i));
    putchar('C');
    putchar('\n');
  }
  for (i = 0; i < 5; ++i) {
    printBlank(20);
    putchar('C');
    putchar('\n');
  }
  for (i = 1; i < 5; ++i) {
    printBlank(20 + i);
    putchar('C');
    putchar('\n');
  }
  printLine();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0x18,%ebx
  call   <printLine@plt>
L12:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x14,%ebx
  jne    L12
  mov    $0x5,%ebx
L7:
  mov    $0x14,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    $0x15,%ebx
L16:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x19,%ebx
  jne    L16
  xor    %eax,%eax
  call   <printLine@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  printLine();
  for (i = 1; i < 5; ++i) {
    printBlank(20 + (5 - i));
    putchar('C');
    putchar('\n');
  }
  for (i = 0; i < 5; ++i) {
    printBlank(20);
    putchar('C');
    putchar('\n');
  }
  for (i = 1; i < 5; ++i) {
    printBlank(20 + i);
    putchar('C');
    putchar('\n');
  }
  printLine();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0x18,%ebx
  call   <printLine@plt>
L24:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x14,%ebx
  jne    L24
  mov    $0x5,%ebx
L14:
  mov    $0x14,%edi
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L14
  mov    $0x15,%ebx
L3:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <printBlank@plt>
  mov    $0x43,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x19,%ebx
  jne    L3
  xor    %eax,%eax
  call   <printLine@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  printLine();
  for (i = 1; i < 5; ++i) {
    printBlank(20 + (5 - i));
    putchar('C');
    putchar('\n');
  }
  for (i = 0; i < 5; ++i) {
    printBlank(20);
    putchar('C');
    putchar('\n');
  }
  for (i = 1; i < 5; ++i) {
    printBlank(20 + i);
    putchar('C');
    putchar('\n');
  }
  printLine();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__InitRandom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L8
  mov    $0x74cbb1,%edi
  call   <mysrand@plt>
  jmp    L13
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mysrand@plt>
L13:
  nop
  leave
  ret
```

assistant: ```c
void __InitRandom(int seed) {
  if (seed == -1)
    mysrand(7654321L);
  else
    mysrand(seed);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__InitRandom>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  je     L18
  call   <mysrand@plt>
L3:
  add    $0x8,%rsp
  ret
L18:
  mov    $0x74cbb1,%edi
  call   <mysrand@plt>
  jmp    L3
```

assistant: ```c
void __InitRandom(int seed) {
  if (seed == -1)
    mysrand(7654321L);
  else
    mysrand(seed);
}
```
user: What is the c source code of the assembly code below:

```asm
<__InitRandom>:
  endbr64
  cmp    $0xffffffff,%edi
  je     L0
  jmp    1050 <mysrand@plt>
  xchg   %ax,%ax
L0:
  mov    $0x74cbb1,%edi
  jmp    1050 <mysrand@plt>
```

assistant: ```c
void __InitRandom(int seed) {
  if (seed == -1)
    mysrand(7654321L);
  else
    mysrand(seed);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__InitRandom>:
  endbr64
  cmp    $0xffffffff,%edi
  je     L0
  jmp    1050 <mysrand@plt>
  xchg   %ax,%ax
L0:
  mov    $0x74cbb1,%edi
  jmp    1050 <mysrand@plt>
```

assistant: ```c
void __InitRandom(int seed) {
  if (seed == -1)
    mysrand(7654321L);
  else
    mysrand(seed);
}
```
user: What is the c source code of the assembly code below?

```asm
<i915_get_instruction_src2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xac(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x98(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x10,%eax
  and    $0x1f,%eax
  mov    %eax,-0x94(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0xc,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x90(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x8,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x88(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x80(%rbp)
  mov    -0x98(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x15,%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    -0xb8(%rbp),%rdx
  mov    -0x94(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <i915_get_instruction_src_name@plt>
  mov    -0x78(%rbp),%rdi
  mov    -0x80(%rbp),%rsi
  mov    -0x88(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L15
  lea    -0x70(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L15:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D14
data_type: string

tool: D11: .%s%s%s%s

tool: D14: .xyzw

assistant: ```c
void i915_get_instruction_src2(const uint32_t *data, int i, char *srcname) {
  uint32_t a2 = data[i + 2];
  int src_nr = (a2 >> 16) & 0x1f;
  char *swizzle_x = i915_get_channel_swizzle((a2 >> 12) & 0xf);
  char *swizzle_y = i915_get_channel_swizzle((a2 >> 8) & 0xf);
  char *swizzle_z = i915_get_channel_swizzle((a2 >> 4) & 0xf);
  char *swizzle_w = i915_get_channel_swizzle((a2 >> 0) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a2 >> 21) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i915_get_instruction_src2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movslq %esi,%rsi
  mov    0x8(%rdi,%rsi,4),%ebx
  mov    %ebx,%edi
  sar    $0xc,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r12
  mov    %ebx,%edi
  sar    $0x8,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r13
  mov    %ebx,%edi
  sar    $0x4,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r14
  mov    %ebx,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r15
  mov    %ebx,%esi
  sar    $0x10,%esi
  and    $0x1f,%esi
  sar    $0x15,%ebx
  mov    %ebx,%edi
  and    $0x7,%edi
  mov    %rbp,%rdx
  call   <i915_get_instruction_src_name@plt>
  mov    %rsp,%rbx
  mov    %r15,%r9
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
L6:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L6
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string

tool: D16: .%s%s%s%s

tool: D13: .xyzw

assistant: ```c
void i915_get_instruction_src2(const uint32_t *data, int i, char *srcname) {
  uint32_t a2 = data[i + 2];
  int src_nr = (a2 >> 16) & 0x1f;
  char *swizzle_x = i915_get_channel_swizzle((a2 >> 12) & 0xf);
  char *swizzle_y = i915_get_channel_swizzle((a2 >> 8) & 0xf);
  char *swizzle_z = i915_get_channel_swizzle((a2 >> 4) & 0xf);
  char *swizzle_w = i915_get_channel_swizzle((a2 >> 0) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a2 >> 21) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<i915_get_instruction_src2>:
  endbr64
  push   %r15
  movslq %esi,%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    0x8(%rdi,%rsi,4),%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %ebx,%edi
  sar    $0xc,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  sar    $0x8,%edi
  mov    %rax,%r12
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  sar    $0x4,%edi
  mov    %rax,%r13
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  and    $0xf,%edi
  mov    %rax,%r14
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%esi
  sar    $0x15,%ebx
  mov    %rbp,%rdx
  sar    $0x10,%esi
  mov    %ebx,%edi
  mov    %rax,%r15
  mov    %rsp,%rbx
  and    $0x1f,%esi
  and    $0x7,%edi
  call   <i915_get_instruction_src_name@plt>
  mov    %rbx,%rdi
  mov    %r15,%r9
  mov    %r14,%r8
  lea    D11(%rip),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  call   <sprintf@plt>
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
L16:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L16
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type: string
name: disassemble_data
arguments: label: D7
type: string

tool: D11: .%s%s%s%s

tool: D7: .xyzw

assistant: ```c
void i915_get_instruction_src2(const uint32_t *data, int i, char *srcname) {
  uint32_t a2 = data[i + 2];
  int src_nr = (a2 >> 16) & 0x1f;
  char *swizzle_x = i915_get_channel_swizzle((a2 >> 12) & 0xf);
  char *swizzle_y = i915_get_channel_swizzle((a2 >> 8) & 0xf);
  char *swizzle_z = i915_get_channel_swizzle((a2 >> 4) & 0xf);
  char *swizzle_w = i915_get_channel_swizzle((a2 >> 0) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a2 >> 21) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```