ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<u16stou8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ishsurrogate@plt>
  test   %rax,%rax
  je     L27
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <islsurrogate@plt>
  test   %rax,%rax
  je     L27
  subl   $0xd7c0,-0xc(%rbp)
  subl   $0xdc00,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  and    $0x3,%eax
  or     $0xf0,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x2,%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  sar    $0x6,%eax
  and    $0xf,%eax
  or     %edx,%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    $0x4,%eax
  jmp    L17
L27:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
size_t u16stou8(uint8_t *buf, uint16_t hsg, uint16_t lsg) {
  if (ishsurrogate(hsg) && islsurrogate(lsg)) {
    hsg = hsg - 0xd800 + 0x40;
    lsg -= 0xdc00;
    buf[0] = 0xf0 | ((hsg >> 8) & 0x3);
    buf[1] = 0x80 | ((hsg >> 2) & 0x3f);
    buf[2] = 0x80 | (((hsg << 4) | ((lsg >> 6) & 0xf)) & 0x3f);
    buf[3] = 0x80 | (lsg & 0x3f);
    return 4;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<u16stou8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %esi,%edi
  call   <ishsurrogate@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L14
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %r12d,%edi
  call   <islsurrogate@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L25
  sub    $0xd7c0,%ebx
  lea    -0xdc00(%r12),%eax
  mov    %ebx,%edx
  sar    $0x8,%edx
  and    $0x3,%edx
  or     $0xf0,%dl
  mov    %edx,0x0(%rbp)
  mov    %ebx,%edx
  sar    $0x2,%edx
  and    $0x3f,%edx
  or     $0x80,%dl
  mov    %edx,0x4(%rbp)
  mov    %eax,%edx
  sar    $0x6,%edx
  and    $0xf,%edx
  shl    $0x4,%ebx
  or     %ebx,%edx
  and    $0x3f,%edx
  or     $0x80,%dl
  mov    %edx,0x8(%rbp)
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,0xc(%rbp)
  mov    $0x4,%eax
  jmp    L25
```

assistant: ```c
size_t u16stou8(uint8_t *buf, uint16_t hsg, uint16_t lsg) {
  if (ishsurrogate(hsg) && islsurrogate(lsg)) {
    hsg = hsg - 0xd800 + 0x40;
    lsg -= 0xdc00;
    buf[0] = 0xf0 | ((hsg >> 8) & 0x3);
    buf[1] = 0x80 | ((hsg >> 2) & 0x3f);
    buf[2] = 0x80 | (((hsg << 4) | ((lsg >> 6) & 0xf)) & 0x3f);
    buf[3] = 0x80 | (lsg & 0x3f);
    return 4;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u16stou8>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <ishsurrogate@plt>
  test   %rax,%rax
  jne    L18
L6:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r12d,%edi
  call   <islsurrogate@plt>
  test   %rax,%rax
  je     L6
  sub    $0xd7c0,%ebx
  lea    -0xdc00(%r12),%edx
  mov    %ebx,%eax
  sar    $0x8,%eax
  and    $0x3,%eax
  or     $0xf0,%al
  mov    %eax,0x0(%rbp)
  mov    %ebx,%eax
  shl    $0x4,%ebx
  sar    $0x2,%eax
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,0x4(%rbp)
  mov    %edx,%eax
  and    $0x3f,%edx
  sar    $0x6,%eax
  or     $0x80,%dl
  and    $0xf,%eax
  mov    %edx,0xc(%rbp)
  or     %ebx,%eax
  pop    %rbx
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,0x8(%rbp)
  mov    $0x4,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t u16stou8(uint8_t *buf, uint16_t hsg, uint16_t lsg) {
  if (ishsurrogate(hsg) && islsurrogate(lsg)) {
    hsg = hsg - 0xd800 + 0x40;
    lsg -= 0xdc00;
    buf[0] = 0xf0 | ((hsg >> 8) & 0x3);
    buf[1] = 0x80 | ((hsg >> 2) & 0x3f);
    buf[2] = 0x80 | (((hsg << 4) | ((lsg >> 6) & 0xf)) & 0x3f);
    buf[3] = 0x80 | (lsg & 0x3f);
    return 4;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<u16stou8>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <ishsurrogate@plt>
  test   %rax,%rax
  jne    L4
L10:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12d,%edi
  call   <islsurrogate@plt>
  test   %rax,%rax
  je     L10
  sub    $0xd7c0,%ebx
  lea    -0xdc00(%r12),%edx
  mov    %ebx,%eax
  mov    %ebx,%ecx
  shl    $0x4,%ebx
  movd   %edx,%xmm2
  sar    $0x8,%eax
  sar    $0x2,%ecx
  movd   %eax,%xmm0
  mov    %edx,%eax
  movd   %ecx,%xmm3
  sar    $0x6,%eax
  punpckldq %xmm3,%xmm0
  and    $0xf,%eax
  or     %ebx,%eax
  pop    %rbx
  movd   %eax,%xmm1
  mov    $0x4,%eax
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  pand   D4(%rip),%xmm0
  por    D16(%rip),%xmm0
  movups %xmm0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: byte[16]
name: retrieve_data
arguments: tag: D16
type_infered: byte[16]

tool: {"D4": [0x03,0x00,0x00,0x00,0x3f,0x00,0x00,0x00,0x3f,0x00,0x00,0x00,0x3f,0x00,0x00,0x00]}

tool: {"D16": [0xf0,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00]}

assistant: ```c
size_t u16stou8(uint8_t *buf, uint16_t hsg, uint16_t lsg) {
  if (ishsurrogate(hsg) && islsurrogate(lsg)) {
    hsg = hsg - 0xd800 + 0x40;
    lsg -= 0xdc00;
    buf[0] = 0xf0 | ((hsg >> 8) & 0x3);
    buf[1] = 0x80 | ((hsg >> 2) & 0x3f);
    buf[2] = 0x80 | (((hsg << 4) | ((lsg >> 6) & 0xf)) & 0x3f);
    buf[3] = 0x80 | (lsg & 0x3f);
    return 4;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GPS_Math_XYZ_To_Airy1830LatLonH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm3
  movsd  -0x10(%rbp),%xmm2
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <GPS_Math_XYZ_To_LatLonH@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
type: f64
name: retrieve_data
arguments: tag: D12
type: f64

tool: D16: 6377563.396

tool: D12: 6356256.91

assistant: ```c
void GPS_Math_XYZ_To_Airy1830LatLonH(double *phi, double *lambda, double *H, double x, double y, double z) {
  double a = 6377563.396;
  double b = 6356256.910;
  GPS_Math_XYZ_To_LatLonH(phi, lambda, H, x, y, z, a, b);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GPS_Math_XYZ_To_Airy1830LatLonH>:
  endbr64
  sub    $0x8,%rsp
  movsd  D12(%rip),%xmm4
  movsd  D4(%rip),%xmm3
  call   <GPS_Math_XYZ_To_LatLonH@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: f64
name: unpack_data
arguments: data_label: D4
type_infered: f64

tool: D12: 6356256.91

tool: D4: 6377563.396

assistant: ```c
void GPS_Math_XYZ_To_Airy1830LatLonH(double *phi, double *lambda, double *H, double x, double y, double z) {
  double a = 6377563.396;
  double b = 6356256.910;
  GPS_Math_XYZ_To_LatLonH(phi, lambda, H, x, y, z, a, b);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPS_Math_XYZ_To_Airy1830LatLonH>:
  endbr64
  movsd  D18(%rip),%xmm4
  movsd  D12(%rip),%xmm3
  jmp    1050 <GPS_Math_XYZ_To_LatLonH@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
datatype: f64
name: disassemble_data
arguments: tag: D12
datatype: f64

tool: D18: 6356256.91

tool: D12: 6377563.396

assistant: ```c
void GPS_Math_XYZ_To_Airy1830LatLonH(double *phi, double *lambda, double *H, double x, double y, double z) {
  double a = 6377563.396;
  double b = 6356256.910;
  GPS_Math_XYZ_To_LatLonH(phi, lambda, H, x, y, z, a, b);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GPS_Math_XYZ_To_Airy1830LatLonH>:
  endbr64
  movsd  D12(%rip),%xmm4
  movsd  D18(%rip),%xmm3
  jmp    1050 <GPS_Math_XYZ_To_LatLonH@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
type_guessed: f64
name: parse_data
arguments: data_label: D18
type_guessed: f64

tool: D12: 6356256.91

tool: D18: 6377563.396

assistant: ```c
void GPS_Math_XYZ_To_Airy1830LatLonH(double *phi, double *lambda, double *H, double x, double y, double z) {
  double a = 6377563.396;
  double b = 6356256.910;
  GPS_Math_XYZ_To_LatLonH(phi, lambda, H, x, y, z, a, b);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strjoin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L0
  cmpq   $0x0,-0x30(%rbp)
  je     L0
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L12
L61:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L12:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L61
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L28:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L28
  mov    -0x8(%rbp),%rax
  jmp    L71
L0:
  mov    $0x0,%eax
L71:
  leave
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, const char *s2) {
  int s1_len;
  int s2_len;
  int i;
  char *ret;
  if (s1 && s2) {
    s1_len = ft_strlen(s1);
    s2_len = ft_strlen(s2);
    if ((ret = ft_strnew(s1_len + s2_len))) {
      i = -1;
      while (++i < s1_len)
        ret[i] = s1[i];
      i = 0;
      while (i < s2_len) {
        ret[s1_len + i] = s2[i];
        i++;
      }
      return (ret);
    }
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strjoin>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L34
  call   <ft_strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%r13d
  lea    0x0(%rbp,%rax,1),%edi
  call   <ft_strnew@plt>
  test   %rax,%rax
  je     L34
  test   %ebp,%ebp
  jle    L65
  mov    %ebp,%esi
  mov    $0x0,%edx
L17:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L17
L65:
  test   %r13d,%r13d
  jle    L34
  mov    %r13d,%r13d
  mov    $0x0,%edx
  movslq %ebp,%rbp
  add    %rax,%rbp
L11:
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %r13,%rdx
  jne    L11
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, const char *s2) {
  int s1_len;
  int s2_len;
  int i;
  char *ret;
  if (s1 && s2) {
    s1_len = ft_strlen(s1);
    s2_len = ft_strlen(s2);
    if ((ret = ft_strnew(s1_len + s2_len))) {
      i = -1;
      while (++i < s1_len)
        ret[i] = s1[i];
      i = 0;
      while (i < s2_len) {
        ret[s1_len + i] = s2[i];
        i++;
      }
      return (ret);
    }
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strjoin>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L53
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <ft_strlen@plt>
  lea    (%r12,%rax,1),%edi
  mov    %eax,%r13d
  call   <ft_strnew@plt>
  test   %rax,%rax
  je     L53
  test   %r12d,%r12d
  jle    L10
  movslq %r12d,%rcx
  xor    %edx,%edx
  nopl   (%rax)
L60:
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L60
L10:
  test   %r13d,%r13d
  jle    L1
  movslq %r12d,%rcx
  movslq %r13d,%rsi
  xor    %edx,%edx
  add    %rax,%rcx
  nopl   0x0(%rax)
L49:
  movzbl 0x0(%rbp,%rdx,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L49
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L53:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, const char *s2) {
  int s1_len;
  int s2_len;
  int i;
  char *ret;
  if (s1 && s2) {
    s1_len = ft_strlen(s1);
    s2_len = ft_strlen(s2);
    if ((ret = ft_strnew(s1_len + s2_len))) {
      i = -1;
      while (++i < s1_len)
        ret[i] = s1[i];
      i = 0;
      while (i < s2_len) {
        ret[s1_len + i] = s2[i];
        i++;
      }
      return (ret);
    }
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: Usage: %s [-h] <file> <prefix>

Options:
  -h         display help


assistant: ```c
void usage(const char *argv0, int exit_code) {
  printf("Usage: %s [-h] <file> <prefix>\n"
         "\n"
         "Options:\n"
         "  -h         display help\n",
         argv0);
  exit(exit_code);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: Usage: %s [-h] <file> <prefix>

Options:
  -h         display help


assistant: ```c
void usage(const char *argv0, int exit_code) {
  printf("Usage: %s [-h] <file> <prefix>\n"
         "\n"
         "Options:\n"
         "  -h         display help\n",
         argv0);
  exit(exit_code);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: Usage: %s [-h] <file> <prefix>

Options:
  -h         display help


assistant: ```c
void usage(const char *argv0, int exit_code) {
  printf("Usage: %s [-h] <file> <prefix>\n"
         "\n"
         "Options:\n"
         "  -h         display help\n",
         argv0);
  exit(exit_code);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: Usage: %s [-h] <file> <prefix>

Options:
  -h         display help


assistant: ```c
void usage(const char *argv0, int exit_code) {
  printf("Usage: %s [-h] <file> <prefix>\n"
         "\n"
         "Options:\n"
         "  -h         display help\n",
         argv0);
  exit(exit_code);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<I2SFrameConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%edi
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    $0x40021008,%edx
  movzbl -0x8(%rbp),%eax
  or     -0x10(%rbp),%al
  mov    %al,(%rdx)
  mov    $0x40021010,%edx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x40021014,%edx
  movzbl -0x14(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void I2SFrameConfigure(uint32_t ui32Base, uint8_t ui8StatusAD0, uint8_t ui8ChanAD0, uint8_t ui8StatusAD1, uint8_t ui8ChanAD1) {
  ;
  (*((volatile unsigned char *)(0x40021000 + 0x00000008))) = (ui8StatusAD0 | ui8StatusAD1);
  (*((volatile unsigned char *)(0x40021000 + 0x00000010))) = ui8ChanAD0;
  (*((volatile unsigned char *)(0x40021000 + 0x00000014))) = ui8ChanAD1;
}
```
user: What is the c source code of the assembly code below?

```asm
<I2SFrameConfigure>:
  endbr64
  or     %esi,%ecx
  mov    %cl,0x40021008
  mov    %dl,0x40021010
  mov    %r8b,0x40021014
  ret
```

assistant: ```c
void I2SFrameConfigure(uint32_t ui32Base, uint8_t ui8StatusAD0, uint8_t ui8ChanAD0, uint8_t ui8StatusAD1, uint8_t ui8ChanAD1) {
  ;
  (*((volatile unsigned char *)(0x40021000 + 0x00000008))) = (ui8StatusAD0 | ui8StatusAD1);
  (*((volatile unsigned char *)(0x40021000 + 0x00000010))) = ui8ChanAD0;
  (*((volatile unsigned char *)(0x40021000 + 0x00000014))) = ui8ChanAD1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<I2SFrameConfigure>:
  endbr64
  or     %esi,%ecx
  mov    %cl,0x40021008
  mov    %dl,0x40021010
  mov    %r8b,0x40021014
  ret
```

assistant: ```c
void I2SFrameConfigure(uint32_t ui32Base, uint8_t ui8StatusAD0, uint8_t ui8ChanAD0, uint8_t ui8StatusAD1, uint8_t ui8ChanAD1) {
  ;
  (*((volatile unsigned char *)(0x40021000 + 0x00000008))) = (ui8StatusAD0 | ui8StatusAD1);
  (*((volatile unsigned char *)(0x40021000 + 0x00000010))) = ui8ChanAD0;
  (*((volatile unsigned char *)(0x40021000 + 0x00000014))) = ui8ChanAD1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2SFrameConfigure>:
  endbr64
  or     %esi,%ecx
  mov    %cl,0x40021008
  mov    %dl,0x40021010
  mov    %r8b,0x40021014
  ret
```

assistant: ```c
void I2SFrameConfigure(uint32_t ui32Base, uint8_t ui8StatusAD0, uint8_t ui8ChanAD0, uint8_t ui8StatusAD1, uint8_t ui8ChanAD1) {
  ;
  (*((volatile unsigned char *)(0x40021000 + 0x00000008))) = (ui8StatusAD0 | ui8StatusAD1);
  (*((volatile unsigned char *)(0x40021000 + 0x00000010))) = ui8ChanAD0;
  (*((volatile unsigned char *)(0x40021000 + 0x00000014))) = ui8ChanAD1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xdr_u_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_u_int@plt>
  test   %eax,%eax
  jne    L27
  mov    $0x0,%eax
  jmp    L12
L27:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
bool_t xdr_u_char(XDR *xdr, u_char *cp) {
  u_int u = (*cp);
  if (!xdr_u_int(xdr, &u))
    return 0;
  *cp = (u_char)u;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xdr_u_char>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  call   <xdr_u_int@plt>
  test   %eax,%eax
  je     L0
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_char(XDR *xdr, u_char *cp) {
  u_int u = (*cp);
  if (!xdr_u_int(xdr, &u))
    return 0;
  *cp = (u_char)u;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xdr_u_char>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <xdr_u_int@plt>
  test   %eax,%eax
  je     L17
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_char(XDR *xdr, u_char *cp) {
  u_int u = (*cp);
  if (!xdr_u_int(xdr, &u))
    return 0;
  *cp = (u_char)u;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdr_u_char>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <xdr_u_int@plt>
  test   %eax,%eax
  je     L16
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_char(XDR *xdr, u_char *cp) {
  u_int u = (*cp);
  if (!xdr_u_int(xdr, &u))
    return 0;
  *cp = (u_char)u;
  return 1;
}
```