ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<hd44780DisplayMode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  shl    $0x2,%edx
  or     %r8d,%edx
  add    %ecx,%ecx
  or     %ecx,%edx
  or     $0x8,%edx
  mov    $0x0,%ecx
  call   <hd44780WriteByte@plt>
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <hd44780WriteByte@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int8_t hd44780DisplayMode(struct mcp23017 *mcp23017, struct hd44780 *hd44780, bool display, bool cursor, bool blink) {
  hd44780WriteByte(mcp23017, hd44780, 0x08 | (display * 0x04) | (cursor * 0x02) | (blink * 0x01), 0);
  hd44780WriteByte(mcp23017, hd44780, 0x01, 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hd44780DisplayMode>:
  endbr64
  push   %r12
  shl    $0x2,%edx
  add    %ecx,%ecx
  mov    %rsi,%r12
  push   %rbp
  or     %r8d,%edx
  mov    %rdi,%rbp
  or     %ecx,%edx
  xor    %ecx,%ecx
  or     $0x8,%edx
  sub    $0x8,%rsp
  call   <hd44780WriteByte@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  mov    $0x1,%edx
  call   <hd44780WriteByte@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int8_t hd44780DisplayMode(struct mcp23017 *mcp23017, struct hd44780 *hd44780, bool display, bool cursor, bool blink) {
  hd44780WriteByte(mcp23017, hd44780, 0x08 | (display * 0x04) | (cursor * 0x02) | (blink * 0x01), 0);
  hd44780WriteByte(mcp23017, hd44780, 0x01, 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hd44780DisplayMode>:
  endbr64
  push   %r12
  shl    $0x2,%edx
  add    %ecx,%ecx
  mov    %rsi,%r12
  push   %rbp
  or     %r8d,%edx
  mov    %rdi,%rbp
  or     %ecx,%edx
  xor    %ecx,%ecx
  or     $0x8,%edx
  sub    $0x8,%rsp
  call   <hd44780WriteByte@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  mov    $0x1,%edx
  call   <hd44780WriteByte@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int8_t hd44780DisplayMode(struct mcp23017 *mcp23017, struct hd44780 *hd44780, bool display, bool cursor, bool blink) {
  hd44780WriteByte(mcp23017, hd44780, 0x08 | (display * 0x04) | (cursor * 0x02) | (blink * 0x01), 0);
  hd44780WriteByte(mcp23017, hd44780, 0x01, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<e_sbc_zpx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_sbc@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e_sbc_zpx() {
  e_zpx();
  e_sbc();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<e_sbc_zpx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_sbc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void e_sbc_zpx() {
  e_zpx();
  e_sbc();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<e_sbc_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <e_sbc@plt>
```

assistant: ```c
void e_sbc_zpx() {
  e_zpx();
  e_sbc();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<e_sbc_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <e_sbc@plt>
```

assistant: ```c
void e_sbc_zpx() {
  e_zpx();
  e_sbc();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<resolve_host>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inet_aton@plt>
  test   %eax,%eax
  jne    L44
  lea    -0x20(%rbp),%rax
  mov    $0x18,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x30(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getaddrinfo@plt>
  test   %rax,%rax
  je     L82
  mov    $0xffffffff,%eax
  jmp    L61
L82:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L75
L11:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L55
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
  mov    $0x0,%eax
  jmp    L61
L55:
  mov    -0x28(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x28(%rbp)
L75:
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
  mov    $0xffffffff,%eax
  jmp    L61
L44:
  mov    $0x0,%eax
L61:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int resolve_host(struct in_addr *sin_addr, const char *hostname) {
  if (!inet_aton(hostname, sin_addr)) {
    struct addrinfo *ai, *cur;
    struct addrinfo hints;
    memset(&hints, 0, sizeof(hints));
    hints.ai_family = AF_INET;
    if (getaddrinfo(hostname, NULL, &hints, &ai))
      return -1;
    for (cur = ai; cur; cur = cur->ai_next) {
      if (cur->ai_family == AF_INET) {
        *sin_addr = ((struct sockaddr_in *)cur->ai_addr)->sin_addr;
        freeaddrinfo(ai);
        return 0;
      }
    }
    freeaddrinfo(ai);
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<resolve_host>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <inet_aton@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L71
L65:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %ebx,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    %eax,%ebx
  lea    0x10(%rsp),%r13
  mov    $0x18,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x10(%rsp)
  lea    0x8(%rsp),%rcx
  mov    %r13,%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <getaddrinfo@plt>
  test   %rax,%rax
  jne    L72
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  je     L51
  mov    D17(%rip),%rax
  mov    (%rax),%rdx
  mov    %rdi,%rax
L79:
  cmp    %rdx,(%rax)
  je     L1
  mov    0x10(%rax),%rax
  test   %rax,%rax
  jne    L79
L51:
  call   <freeaddrinfo@plt>
  mov    $0xffffffff,%ebx
  jmp    L65
L1:
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  mov    %eax,(%r12)
  call   <freeaddrinfo@plt>
  jmp    L65
L72:
  mov    $0xffffffff,%ebx
  jmp    L65
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int resolve_host(struct in_addr *sin_addr, const char *hostname) {
  if (!inet_aton(hostname, sin_addr)) {
    struct addrinfo *ai, *cur;
    struct addrinfo hints;
    memset(&hints, 0, sizeof(hints));
    hints.ai_family = AF_INET;
    if (getaddrinfo(hostname, NULL, &hints, &ai))
      return -1;
    for (cur = ai; cur; cur = cur->ai_next) {
      if (cur->ai_family == AF_INET) {
        *sin_addr = ((struct sockaddr_in *)cur->ai_addr)->sin_addr;
        freeaddrinfo(ai);
        return 0;
      }
    }
    freeaddrinfo(ai);
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<resolve_host>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <inet_aton@plt>
  test   %eax,%eax
  je     L77
L38:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L77:
  lea    0x10(%rsp),%r13
  xor    %esi,%esi
  mov    $0x18,%edx
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  lea    0x8(%rsp),%rcx
  mov    %r13,%rdx
  mov    D0(%rip),%r14
  mov    %rbp,%rdi
  mov    (%r14),%rax
  mov    %rax,0x10(%rsp)
  call   <getaddrinfo@plt>
  test   %rax,%rax
  jne    L89
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  je     L0
  mov    (%r14),%rdx
  mov    %rdi,%rax
  jmp    L24
  nop
L16:
  mov    0x10(%rax),%rax
  test   %rax,%rax
  je     L0
L24:
  cmp    %rdx,(%rax)
  jne    L16
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  call   <freeaddrinfo@plt>
  jmp    L38
L89:
  mov    $0xffffffff,%r12d
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L0:
  call   <freeaddrinfo@plt>
  mov    $0xffffffff,%r12d
  jmp    L38
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int resolve_host(struct in_addr *sin_addr, const char *hostname) {
  if (!inet_aton(hostname, sin_addr)) {
    struct addrinfo *ai, *cur;
    struct addrinfo hints;
    memset(&hints, 0, sizeof(hints));
    hints.ai_family = AF_INET;
    if (getaddrinfo(hostname, NULL, &hints, &ai))
      return -1;
    for (cur = ai; cur; cur = cur->ai_next) {
      if (cur->ai_family == AF_INET) {
        *sin_addr = ((struct sockaddr_in *)cur->ai_addr)->sin_addr;
        freeaddrinfo(ai);
        return 0;
      }
    }
    freeaddrinfo(ai);
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<resolve_host>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <inet_aton@plt>
  test   %eax,%eax
  je     L18
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L18:
  lea    0x10(%rsp),%r13
  xor    %esi,%esi
  mov    $0x18,%edx
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  lea    0x8(%rsp),%rcx
  mov    %r13,%rdx
  mov    D7(%rip),%r14
  mov    %rbp,%rdi
  mov    (%r14),%rax
  mov    %rax,0x10(%rsp)
  call   <getaddrinfo@plt>
  test   %rax,%rax
  jne    L66
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  je     L36
  mov    (%r14),%rdx
  mov    %rdi,%rax
  jmp    L11
  nop
L33:
  mov    0x10(%rax),%rax
  test   %rax,%rax
  je     L36
L11:
  cmp    %rdx,(%rax)
  jne    L33
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  call   <freeaddrinfo@plt>
  jmp    L1
L66:
  mov    $0xffffffff,%r12d
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L36:
  call   <freeaddrinfo@plt>
  mov    $0xffffffff,%r12d
  jmp    L1
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int resolve_host(struct in_addr *sin_addr, const char *hostname) {
  if (!inet_aton(hostname, sin_addr)) {
    struct addrinfo *ai, *cur;
    struct addrinfo hints;
    memset(&hints, 0, sizeof(hints));
    hints.ai_family = AF_INET;
    if (getaddrinfo(hostname, NULL, &hints, &ai))
      return -1;
    for (cur = ai; cur; cur = cur->ai_next) {
      if (cur->ai_family == AF_INET) {
        *sin_addr = ((struct sockaddr_in *)cur->ai_addr)->sin_addr;
        freeaddrinfo(ai);
        return 0;
      }
    }
    freeaddrinfo(ai);
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L30:
  movzbl -0x11(%rbp),%eax
  cmp    -0x12(%rbp),%al
  jne    L18
  jmp    L31
L18:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L30
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  sub    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t _strspn(const char *s1, const char *s2) {
  const char *p = s1, *spanp;
  char c, sc;
cont:
  c = *p++;
  for (spanp = s2; (sc = *spanp++) != 0;)
    if (sc == c)
      goto cont;
  return (p - 1 - s1);
}
```
user: What is the c source code of the assembly code below?

```asm
<_strspn>:
  endbr64
  mov    %rdi,%rax
L21:
  lea    0x1(%rax),%r9
  movzbl -0x1(%r9),%r8d
  mov    %rsi,%rdx
L7:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  test   %cl,%cl
  je     L10
  cmp    %cl,%r8b
  jne    L7
  mov    %r9,%rax
  jmp    L21
L10:
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t _strspn(const char *s1, const char *s2) {
  const char *p = s1, *spanp;
  char c, sc;
cont:
  c = *p++;
  for (spanp = s2; (sc = *spanp++) != 0;)
    if (sc == c)
      goto cont;
  return (p - 1 - s1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_strspn>:
  endbr64
  mov    %rdi,%rax
L6:
  lea    0x1(%rax),%r9
  mov    %rsi,%rdx
  movzbl -0x1(%r9),%r8d
  jmp    L7
  nopl   (%rax)
L18:
  cmp    %cl,%r8b
  je     L24
L7:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L18
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax)
L24:
  mov    %r9,%rax
  jmp    L6
```

assistant: ```c
size_t _strspn(const char *s1, const char *s2) {
  const char *p = s1, *spanp;
  char c, sc;
cont:
  c = *p++;
  for (spanp = s2; (sc = *spanp++) != 0;)
    if (sc == c)
      goto cont;
  return (p - 1 - s1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_strspn>:
  endbr64
  mov    %rdi,%rax
L15:
  lea    0x1(%rax),%r9
  mov    %rsi,%rdx
  movzbl -0x1(%r9),%r8d
  jmp    L2
  nopl   (%rax)
L5:
  cmp    %cl,%r8b
  je     L12
L2:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L5
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax)
L12:
  mov    %r9,%rax
  jmp    L15
```

assistant: ```c
size_t _strspn(const char *s1, const char *s2) {
  const char *p = s1, *spanp;
  char c, sc;
cont:
  c = *p++;
  for (spanp = s2; (sc = *spanp++) != 0;)
    if (sc == c)
      goto cont;
  return (p - 1 - s1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L28
L25:
  lea    -0xb(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <array_pos@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,-0x4c(%rbp)
  jge    L6
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,-0x4c(%rbp)
L6:
  addl   $0x1,-0x48(%rbp)
L28:
  cmpl   $0x4,-0x48(%rbp)
  jle    L25
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D3: %s

tool: D12: %d


assistant: ```c
int main() {
  int counter[13] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int curr_max = 0;
  for (int i = 0; i < 5; i++) {
    char card[3];
    scanf("%s", card);
    int rank = array_pos(card[0]);
    counter[rank] += 1;
    if (counter[rank] > curr_max)
      curr_max = counter[rank];
  }
  printf("%d\n", curr_max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    $0x5,%ebp
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L3:
  lea    0x35(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsbl 0x35(%rsp),%edi
  call   <array_pos@plt>
  cltq
  mov    (%rsp,%rax,4),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%rsp,%rax,4)
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  sub    $0x1,%ebp
  jne    L3
  mov    %ebx,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D19
type_infered: string

tool: D8: %s

tool: D19: %d


assistant: ```c
int main() {
  int counter[13] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int curr_max = 0;
  for (int i = 0; i < 5; i++) {
    char card[3];
    scanf("%s", card);
    int rank = array_pos(card[0]);
    counter[rank] += 1;
    if (counter[rank] > curr_max)
      curr_max = counter[rank];
  }
  printf("%d\n", curr_max);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x30(%rsp)
  lea    0x35(%rsp),%r12
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
L7:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x35(%rsp),%edi
  call   <array_pos@plt>
  cltq
  mov    (%rsp,%rax,4),%ecx
  lea    0x1(%rcx),%edx
  cmp    %edx,%r13d
  mov    %edx,(%rsp,%rax,4)
  cmovl  %edx,%r13d
  sub    $0x1,%ebx
  jne    L7
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D4: %s

tool: D1: %d


assistant: ```c
int main() {
  int counter[13] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int curr_max = 0;
  for (int i = 0; i < 5; i++) {
    char card[3];
    scanf("%s", card);
    int rank = array_pos(card[0]);
    counter[rank] += 1;
    if (counter[rank] > curr_max)
      curr_max = counter[rank];
  }
  printf("%d\n", curr_max);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x30(%rsp)
  lea    0x35(%rsp),%r12
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
L17:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x35(%rsp),%edi
  call   <array_pos@plt>
  cltq
  mov    (%rsp,%rax,4),%ecx
  lea    0x1(%rcx),%edx
  cmp    %edx,%r13d
  mov    %edx,(%rsp,%rax,4)
  cmovl  %edx,%r13d
  sub    $0x1,%ebx
  jne    L17
  mov    %r13d,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string

tool: D3: %s

tool: D13: %d


assistant: ```c
int main() {
  int counter[13] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int curr_max = 0;
  for (int i = 0; i < 5; i++) {
    char card[3];
    scanf("%s", card);
    int rank = array_pos(card[0]);
    counter[rank] += 1;
    if (counter[rank] > curr_max)
      curr_max = counter[rank];
  }
  printf("%d\n", curr_max);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x17,-0xc(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0x3e8,-0x4(%rbp)
  jmp    L19
L35:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L9
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L41
L9:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L41
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
L41:
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L35
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: %d


assistant: ```c
int main() {
  int sum = 23;
  int n = 10;
  int n_max = 1000;
  while (n < n_max) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  printf("%d\n", sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edx
  mov    $0x17,%esi
  jmp    L28
L35:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  lea    (%rsi,%rdx,1),%eax
  cmp    %ecx,%edx
  cmove  %eax,%esi
L10:
  add    $0x1,%edx
  cmp    $0x3e8,%edx
  je     L32
L28:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%edx
  jne    L35
  add    %edx,%esi
  jmp    L10
L32:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main() {
  int sum = 23;
  int n = 10;
  int n_max = 1000;
  while (n < n_max) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  printf("%d\n", sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%eax
  mov    $0x17,%esi
  jmp    L27
  nopl   0x0(%rax)
L15:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  je     L10
L27:
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  jbe    L15
  imul   $0xaaaaaaab,%eax,%ecx
  lea    (%rsi,%rax,1),%edx
  cmp    $0x55555556,%ecx
  cmovb  %edx,%esi
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L27
L10:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main() {
  int sum = 23;
  int n = 10;
  int n_max = 1000;
  while (n < n_max) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  printf("%d\n", sum);
}
```