ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nabs_df>:
  endbr64
  movsd  (%rdi),%xmm0
  orpd   D8(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double nabs_df(double *p) {
  double d = *p;
  __asm__("# reg %x0" : "+v"(d));
  return -__builtin_fabs(d);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nabs_df>:
  endbr64
  movsd  (%rdi),%xmm0
  orpd   D7(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double nabs_df(double *p) {
  double d = *p;
  __asm__("# reg %x0" : "+v"(d));
  return -__builtin_fabs(d);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nabs_df>:
  endbr64
  movsd  (%rdi),%xmm0
  orpd   D1(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double nabs_df(double *p) {
  double d = *p;
  __asm__("# reg %x0" : "+v"(d));
  return -__builtin_fabs(d);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x8(%rbp)
  movl   $0x2a,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int j;
  j = (i = 42, 99, i);
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int j;
  j = (i = 42, 99, i);
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int j;
  j = (i = 42, 99, i);
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int j;
  j = (i = 42, 99, i);
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_rules>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <ya_malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L49:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x58,%eax
  je     L61
  cmp    $0x59,%eax
  je     L50
  jmp    L29
L61:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  jmp    L87
L50:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0xfffffffe,(%rax)
  jmp    L87
L29:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L13
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  sub    $0x61,%edx
  mov    %edx,(%rax)
  jmp    L5
L13:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  sub    $0x30,%edx
  mov    %edx,(%rax)
L5:
  nop
L87:
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L49
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *parse_rules(const char *crules) {
  int rules_len = strlen(crules);
  int *rules = (int *)ya_malloc(sizeof(int) * rules_len);
  for (int i = 0; i < rules_len; i++) {
    switch (crules[i]) {
    case 'X': {
      rules[i] = -1;
      break;
    }
    case 'Y': {
      rules[i] = -2;
      break;
    }
    default:
      if (crules[i] >= 'a')
        rules[i] = crules[i] - 'a';
      else
        rules[i] = crules[i] - '0';
      break;
    }
  }
  return rules;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_rules>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x0(,%rax,4),%edi
  call   <ya_malloc@plt>
  test   %ebp,%ebp
  jle    L37
  mov    %rbx,%rdi
  mov    %rax,%rdx
  lea    -0x1(%rbp),%ecx
  lea    0x4(%rax,%rcx,4),%r8
  jmp    L11
L16:
  movl   $0xffffffff,(%rdx)
L50:
  add    $0x1,%rdi
  add    $0x4,%rdx
  cmp    %r8,%rdx
  je     L37
L11:
  movzbl (%rdi),%ecx
  cmp    $0x58,%cl
  je     L16
  cmp    $0x59,%cl
  je     L74
  movsbl %cl,%esi
  cmp    $0x60,%cl
  jle    L51
  sub    $0x61,%esi
  mov    %esi,(%rdx)
  jmp    L50
L74:
  movl   $0xfffffffe,(%rdx)
  jmp    L50
L51:
  sub    $0x30,%esi
  mov    %esi,(%rdx)
  jmp    L50
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *parse_rules(const char *crules) {
  int rules_len = strlen(crules);
  int *rules = (int *)ya_malloc(sizeof(int) * rules_len);
  for (int i = 0; i < rules_len; i++) {
    switch (crules[i]) {
    case 'X': {
      rules[i] = -1;
      break;
    }
    case 'Y': {
      rules[i] = -2;
      break;
    }
    default:
      if (crules[i] >= 'a')
        rules[i] = crules[i] - 'a';
      else
        rules[i] = crules[i] - '0';
      break;
    }
  }
  return rules;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_rules>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x0(,%rax,4),%edi
  call   <ya_malloc@plt>
  test   %ebp,%ebp
  jle    L1
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rdi
  mov    %rax,%rcx
  lea    0x4(%rax,%rdx,4),%r8
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%rdi),%esi
  mov    $0xffffffff,%edx
  cmp    $0x58,%sil
  je     L7
  mov    $0xfffffffe,%edx
  cmp    $0x59,%sil
  je     L7
  movsbl %sil,%edx
  lea    -0x61(%rdx),%r9d
  sub    $0x30,%edx
  cmp    $0x61,%sil
  cmovge %r9d,%edx
L7:
  mov    %edx,(%rcx)
  add    $0x4,%rcx
  add    $0x1,%rdi
  cmp    %r8,%rcx
  jne    L9
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *parse_rules(const char *crules) {
  int rules_len = strlen(crules);
  int *rules = (int *)ya_malloc(sizeof(int) * rules_len);
  for (int i = 0; i < rules_len; i++) {
    switch (crules[i]) {
    case 'X': {
      rules[i] = -1;
      break;
    }
    case 'Y': {
      rules[i] = -2;
      break;
    }
    default:
      if (crules[i] >= 'a')
        rules[i] = crules[i] - 'a';
      else
        rules[i] = crules[i] - '0';
      break;
    }
  }
  return rules;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parse_rules>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x0(,%rax,4),%edi
  call   <ya_malloc@plt>
  test   %ebp,%ebp
  jle    L21
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rdi
  mov    %rax,%rcx
  lea    0x4(%rax,%rdx,4),%r8
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl (%rdi),%esi
  mov    $0xffffffff,%edx
  cmp    $0x58,%sil
  je     L31
  mov    $0xfffffffe,%edx
  cmp    $0x59,%sil
  je     L31
  movsbl %sil,%edx
  lea    -0x61(%rdx),%r9d
  sub    $0x30,%edx
  cmp    $0x61,%sil
  cmovge %r9d,%edx
L31:
  mov    %edx,(%rcx)
  add    $0x4,%rcx
  add    $0x1,%rdi
  cmp    %rcx,%r8
  jne    L39
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *parse_rules(const char *crules) {
  int rules_len = strlen(crules);
  int *rules = (int *)ya_malloc(sizeof(int) * rules_len);
  for (int i = 0; i < rules_len; i++) {
    switch (crules[i]) {
    case 'X': {
      rules[i] = -1;
      break;
    }
    case 'Y': {
      rules[i] = -2;
      break;
    }
    default:
      if (crules[i] >= 'a')
        rules[i] = crules[i] - 'a';
      else
        rules[i] = crules[i] - '0';
      break;
    }
  }
  return rules;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_rfind_not_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mem_begin@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L27
L19:
  cmpq   $0x0,-0x20(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L27
L34:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L17
L57:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x10(%rbp),%rax
  jmp    L27
L39:
  subq   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L57
  mov    $0x0,%eax
L27:
  leave
  ret
```

assistant: ```c
char *str_rfind_not_char(char *haystack, char *needles) {
  char *haystack_begin = mem_begin(haystack);
  char *str = NULL;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  for (str = haystack; str >= haystack_begin; str--) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<str_rfind_not_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <mem_begin@plt>
  test   %rbp,%rbp
  je     L60
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L60
  cmp    %rax,%rbx
  jb     L54
L22:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  jbe    L22
  mov    $0x0,%eax
  jmp    L64
L60:
  mov    $0x0,%eax
  jmp    L64
L54:
  mov    $0x0,%eax
  jmp    L64
L1:
  mov    %rbx,%rax
L64:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rfind_not_char(char *haystack, char *needles) {
  char *haystack_begin = mem_begin(haystack);
  char *str = NULL;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  for (str = haystack; str >= haystack_begin; str--) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_rfind_not_char>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <mem_begin@plt>
  test   %rbp,%rbp
  je     L47
  test   %rbx,%rbx
  je     L47
  mov    %rax,%r12
  cmp    %rax,%rbx
  jae    L8
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L38:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L47
L8:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L38
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L47:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rfind_not_char(char *haystack, char *needles) {
  char *haystack_begin = mem_begin(haystack);
  char *str = NULL;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  for (str = haystack; str >= haystack_begin; str--) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_rfind_not_char>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <mem_begin@plt>
  test   %rbp,%rbp
  je     L55
  test   %rbx,%rbx
  je     L55
  mov    %rax,%r12
  cmp    %rax,%rbx
  jae    L57
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L15:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L55
L57:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rfind_not_char(char *haystack, char *needles) {
  char *haystack_begin = mem_begin(haystack);
  char *str = NULL;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  for (str = haystack; str >= haystack_begin; str--) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ShiftRight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x5(%rbp)
  movb   $0x0,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L22:
  movzbl -0x6(%rbp),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L12
  movb   $0x80,-0x6(%rbp)
  jmp    L13
L12:
  movb   $0x0,-0x6(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  shr    %dl
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x5(%rbp),%edx
  add    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0xf,-0x4(%rbp)
  jle    L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ShiftRight(unsigned char *SHFT) {
  unsigned char prevcarry = 0x00;
  unsigned char currcarry = 0x00;
  for (int i = 0; i < 16; i++) {
    prevcarry = currcarry;
    if (SHFT[i] & 0x01)
      currcarry = 0x80;
    else
      currcarry = 0x00;
    SHFT[i] >>= 0x01;
    SHFT[i] += prevcarry;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ShiftRight>:
  endbr64
  lea    0x10(%rdi),%rsi
  mov    $0x0,%edx
L5:
  movzbl (%rdi),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  shl    $0x7,%edx
  shr    %al
  add    %ecx,%eax
  mov    %al,(%rdi)
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L5
  ret
```

assistant: ```c
void ShiftRight(unsigned char *SHFT) {
  unsigned char prevcarry = 0x00;
  unsigned char currcarry = 0x00;
  for (int i = 0; i < 16; i++) {
    prevcarry = currcarry;
    if (SHFT[i] & 0x01)
      currcarry = 0x80;
    else
      currcarry = 0x00;
    SHFT[i] >>= 0x01;
    SHFT[i] += prevcarry;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ShiftRight>:
  endbr64
  lea    0x10(%rdi),%rsi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl (%rdi),%eax
  mov    %edx,%ecx
  add    $0x1,%rdi
  mov    %eax,%edx
  shr    %al
  add    %ecx,%eax
  shl    $0x7,%edx
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L8
  ret
```

assistant: ```c
void ShiftRight(unsigned char *SHFT) {
  unsigned char prevcarry = 0x00;
  unsigned char currcarry = 0x00;
  for (int i = 0; i < 16; i++) {
    prevcarry = currcarry;
    if (SHFT[i] & 0x01)
      currcarry = 0x80;
    else
      currcarry = 0x00;
    SHFT[i] >>= 0x01;
    SHFT[i] += prevcarry;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ShiftRight>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %ecx,%edx
  shl    $0x7,%ecx
  shr    %dl
  mov    %dl,(%rdi)
  movzbl 0x1(%rdi),%edx
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    %sil
  add    %esi,%ecx
  mov    %cl,0x1(%rdi)
  movzbl 0x2(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0x2(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    %sil
  add    %esi,%ecx
  mov    %cl,0x3(%rdi)
  movzbl 0x4(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0x4(%rdi)
  movzbl 0x5(%rdi),%edx
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    %sil
  add    %esi,%ecx
  mov    %cl,0x5(%rdi)
  movzbl 0x6(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0x6(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    %sil
  add    %esi,%ecx
  mov    %cl,0x7(%rdi)
  movzbl 0x8(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0x8(%rdi)
  movzbl 0x9(%rdi),%edx
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    %sil
  add    %esi,%ecx
  mov    %cl,0x9(%rdi)
  movzbl 0xa(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0xa(%rdi)
  movzbl 0xb(%rdi),%edx
  mov    %edx,%esi
  shr    %sil
  shl    $0x7,%edx
  add    %esi,%ecx
  mov    %cl,0xb(%rdi)
  movzbl 0xc(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0xc(%rdi)
  movzbl 0xd(%rdi),%edx
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    %sil
  add    %esi,%ecx
  mov    %cl,0xd(%rdi)
  movzbl 0xe(%rdi),%ecx
  mov    %ecx,%esi
  shl    $0x7,%ecx
  shr    %sil
  add    %esi,%edx
  mov    %dl,0xe(%rdi)
  movzbl 0xf(%rdi),%edx
  shr    %dl
  add    %ecx,%edx
  mov    %dl,0xf(%rdi)
  ret
```

assistant: ```c
void ShiftRight(unsigned char *SHFT) {
  unsigned char prevcarry = 0x00;
  unsigned char currcarry = 0x00;
  for (int i = 0; i < 16; i++) {
    prevcarry = currcarry;
    if (SHFT[i] & 0x01)
      currcarry = 0x80;
    else
      currcarry = 0x00;
    SHFT[i] >>= 0x01;
    SHFT[i] += prevcarry;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<E_old_pw_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <smbhash@plt>
  mov    -0x8(%rbp),%rax
  lea    0x7(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rsi
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <smbhash@plt>
  nop
  leave
  ret
```

assistant: ```c
void E_old_pw_hash(unsigned char *p14, unsigned char *in, unsigned char *out) {
  smbhash(out, in, p14, 1);
  smbhash(out + 8, in + 8, p14 + 7, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<E_old_pw_hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x1,%ecx
  mov    %rdi,%rdx
  mov    %rbx,%rdi
  call   <smbhash@plt>
  lea    0x7(%r12),%rdx
  lea    0x8(%rbp),%rsi
  lea    0x8(%rbx),%rdi
  mov    $0x1,%ecx
  call   <smbhash@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void E_old_pw_hash(unsigned char *p14, unsigned char *in, unsigned char *out) {
  smbhash(out, in, p14, 1);
  smbhash(out + 8, in + 8, p14 + 7, 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<E_old_pw_hash>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  mov    %rbx,%rdi
  call   <smbhash@plt>
  lea    0x7(%r12),%rdx
  lea    0x8(%rbp),%rsi
  mov    $0x1,%ecx
  lea    0x8(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <smbhash@plt>
```

assistant: ```c
void E_old_pw_hash(unsigned char *p14, unsigned char *in, unsigned char *out) {
  smbhash(out, in, p14, 1);
  smbhash(out + 8, in + 8, p14 + 7, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<E_old_pw_hash>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  mov    %rbx,%rdi
  call   <smbhash@plt>
  lea    0x7(%r12),%rdx
  lea    0x8(%rbp),%rsi
  mov    $0x1,%ecx
  lea    0x8(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <smbhash@plt>
```

assistant: ```c
void E_old_pw_hash(unsigned char *p14, unsigned char *in, unsigned char *out) {
  smbhash(out, in, p14, 1);
  smbhash(out + 8, in + 8, p14 + 7, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzwl (%rax),%eax
  cwtl
  imul   %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L0
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float get_power(short buf[], unsigned length) {
  float rt;
  int j;
  rt = 0.0;
  for (j = 0; j < length; j++) {
    rt += buf[j] * buf[j];
  }
  return rt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_power>:
  endbr64
  test   %esi,%esi
  je     L6
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x2(%rdi,%rax,2),%rcx
  pxor   %xmm0,%xmm0
L2:
  movswl (%rdx),%eax
  imul   %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
  add    $0x2,%rdx
  cmp    %rcx,%rdx
  jne    L2
  ret
L6:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float get_power(short buf[], unsigned length) {
  float rt;
  int j;
  rt = 0.0;
  for (j = 0; j < length; j++) {
    rt += buf[j] * buf[j];
  }
  return rt;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_power>:
  endbr64
  test   %esi,%esi
  je     L1
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x2(%rdi,%rax,2),%rdx
  nopl   0x0(%rax)
L3:
  movswl (%rdi),%eax
  pxor   %xmm1,%xmm1
  add    $0x2,%rdi
  imul   %eax,%eax
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rdi,%rdx
  jne    L3
  ret
  nopl   0x0(%rax)
L1:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float get_power(short buf[], unsigned length) {
  float rt;
  int j;
  rt = 0.0;
  for (j = 0; j < length; j++) {
    rt += buf[j] * buf[j];
  }
  return rt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_power>:
  endbr64
  test   %esi,%esi
  je     L12
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x2(%rdi,%rax,2),%rdx
  nopl   0x0(%rax)
L11:
  movswl (%rdi),%eax
  pxor   %xmm1,%xmm1
  add    $0x2,%rdi
  imul   %eax,%eax
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rdi,%rdx
  jne    L11
  ret
  nopl   0x0(%rax)
L12:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float get_power(short buf[], unsigned length) {
  float rt;
  int j;
  rt = 0.0;
  for (j = 0; j < length; j++) {
    rt += buf[j] * buf[j];
  }
  return rt;
}
```