ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<SPI_Out>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x7,%ebx
  sub    $0x8,%rsp
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L18:
  call   <ClearMOSI@plt>
L15:
  mov    $0x2,%edi
  call   <waitmicrosec@plt>
  xor    %eax,%eax
  call   <SetSCK@plt>
  mov    $0x3,%edi
  call   <waitmicrosec@plt>
  xor    %eax,%eax
  call   <ClearSCK@plt>
  mov    $0x2,%edi
  call   <waitmicrosec@plt>
  sub    $0x1,%ebx
  jb     L33
L36:
  xor    %eax,%eax
  bt     %ebx,%ebp
  jb     L18
  call   <SetMOSI@plt>
  jmp    L15
  nopl   0x0(%rax)
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SPI_Out(int b) {
  int i;
  for (i = 7; i >= 0; i--) {
    if (b & (1 << i))
      ClearMOSI();
    else
      SetMOSI();
    waitmicrosec(2);
    SetSCK();
    waitmicrosec(3);
    ClearSCK();
    waitmicrosec(2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SPI_Out>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x7,%ebx
  sub    $0x8,%rsp
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L33:
  call   <ClearMOSI@plt>
L11:
  mov    $0x2,%edi
  call   <waitmicrosec@plt>
  xor    %eax,%eax
  call   <SetSCK@plt>
  mov    $0x3,%edi
  call   <waitmicrosec@plt>
  xor    %eax,%eax
  call   <ClearSCK@plt>
  mov    $0x2,%edi
  call   <waitmicrosec@plt>
  sub    $0x1,%ebx
  jb     L32
L1:
  xor    %eax,%eax
  bt     %ebx,%ebp
  jb     L33
  call   <SetMOSI@plt>
  jmp    L11
  nopl   0x0(%rax)
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SPI_Out(int b) {
  int i;
  for (i = 7; i >= 0; i--) {
    if (b & (1 << i))
      ClearMOSI();
    else
      SetMOSI();
    waitmicrosec(2);
    SetSCK();
    waitmicrosec(3);
    ClearSCK();
    waitmicrosec(2);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edx
  mov    $0x2a30,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1c20,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x1c20,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x1c20,%esi
  lea    D135(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0xffff9d90,%esi
  lea    D135(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0xffffb9b0,%esi
  lea    D135(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1c21,%esi
  lea    D135(%rip),%rax
  mov    %rax,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D52
type: string
name: extract_symbolic_data
arguments: data_label: D78
type: string
name: extract_symbolic_data
arguments: data_label: D135
type: string

tool: D52: cest

tool: D78: %s


tool: D135: foobar

assistant: ```c
int main(void) {
  char *id;
  id = timelib_timezone_id_from_abbr("cest", 10800, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -7 * 3600, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -5 * 3600, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7201, 1);
  printf("%s\n", id);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x2a30,%esi
  lea    D11(%rip),%rbp
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1c20,%esi
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x1c20,%esi
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x1c20,%esi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0xffff9d90,%esi
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0xffffb9b0,%esi
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1c21,%esi
  mov    %rbp,%rdi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D11: cest

tool: D23: %s


tool: D9: foobar

assistant: ```c
int main(void) {
  char *id;
  id = timelib_timezone_id_from_abbr("cest", 10800, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -7 * 3600, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -5 * 3600, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7201, 1);
  printf("%s\n", id);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%r12
  mov    $0x1,%edx
  mov    $0x2a30,%esi
  push   %rbp
  mov    %r12,%rdi
  lea    D4(%rip),%rbp
  sub    $0x8,%rsp
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0x1c20,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0x1c20,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  lea    D12(%rip),%r12
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0x1c20,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0xffff9d90,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0xffffb9b0,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  mov    $0x1c21,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D28: cest

tool: D4: %s


tool: D12: foobar

assistant: ```c
int main(void) {
  char *id;
  id = timelib_timezone_id_from_abbr("cest", 10800, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -7 * 3600, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -5 * 3600, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7201, 1);
  printf("%s\n", id);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%r12
  mov    $0x1,%edx
  mov    $0x2a30,%esi
  push   %rbp
  mov    %r12,%rdi
  lea    D22(%rip),%rbp
  sub    $0x8,%rsp
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0x1c20,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0x1c20,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  lea    D14(%rip),%r12
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0x1c20,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0xffff9d90,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0xffffb9b0,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  mov    $0x1c21,%esi
  call   <timelib_timezone_id_from_abbr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D22
type: string
name: read_data
arguments: label: D14
type: string

tool: D28: cest

tool: D22: %s


tool: D14: foobar

assistant: ```c
int main(void) {
  char *id;
  id = timelib_timezone_id_from_abbr("cest", 10800, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("cest", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7200, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -7 * 3600, 0);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", -5 * 3600, 1);
  printf("%s\n", id);
  id = timelib_timezone_id_from_abbr("foobar", 7201, 1);
  printf("%s\n", id);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<i2xyz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L11:
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x1c(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,(%rcx)
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  sub    %eax,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  nop
  leave
  ret
```

assistant: ```c
void i2xyz(const int d, const int L, int index, int *coord) {
  int i;
  for (i = 0; i < d; ++i) {
    coord[i] = index / (int)pow(L, d - i - 1);
    index = index - (int)pow(L, d - i - 1) * coord[i];
    index = index % ((int)pow(L, d - i - 1));
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i2xyz>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    -0x1(%rdi),%ebx
  mov    %rcx,%rbp
L3:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  imul   0x0(%rbp),%eax
  sub    %eax,%r12d
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %edx,%r12d
  sub    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0xffffffff,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  ret
```

assistant: ```c
void i2xyz(const int d, const int L, int index, int *coord) {
  int i;
  for (i = 0; i < d; ++i) {
    coord[i] = index / (int)pow(L, d - i - 1);
    index = index - (int)pow(L, d - i - 1) * coord[i];
    index = index % ((int)pow(L, d - i - 1));
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i2xyz>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L14:
  mov    %ebx,%esi
  mov    %r13d,%edi
  add    $0x4,%rbp
  call   <pow@plt>
  mov    %ebx,%esi
  mov    %r13d,%edi
  mov    %rax,%r8
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,-0x4(%rbp)
  call   <pow@plt>
  imul   -0x4(%rbp),%eax
  mov    %ebx,%esi
  mov    %r13d,%edi
  sub    $0x1,%ebx
  sub    %eax,%r12d
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r12d
  cmp    $0xffffffff,%ebx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void i2xyz(const int d, const int L, int index, int *coord) {
  int i;
  for (i = 0; i < d; ++i) {
    coord[i] = index / (int)pow(L, d - i - 1);
    index = index - (int)pow(L, d - i - 1) * coord[i];
    index = index % ((int)pow(L, d - i - 1));
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i2xyz>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L11:
  mov    %ebx,%esi
  mov    %r13d,%edi
  add    $0x4,%rbp
  call   <pow@plt>
  mov    %ebx,%esi
  mov    %r13d,%edi
  mov    %rax,%r8
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,-0x4(%rbp)
  call   <pow@plt>
  imul   -0x4(%rbp),%eax
  mov    %ebx,%esi
  mov    %r13d,%edi
  sub    $0x1,%ebx
  sub    %eax,%r12d
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r12d
  cmp    $0xffffffff,%ebx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void i2xyz(const int d, const int L, int index, int *coord) {
  int i;
  for (i = 0; i < d; ++i) {
    coord[i] = index / (int)pow(L, d - i - 1);
    index = index - (int)pow(L, d - i - 1) * coord[i];
    index = index % ((int)pow(L, d - i - 1));
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcaseequal>:
  endbr64
  mov    %rsi,%r8
  mov    %rdx,%rsi
  test   %rdx,%rdx
  je     L54
  mov    $0x0,%ecx
  jmp    L29
L93:
  jle    L116
  lea    -0x41(%rdx),%r9d
  cmp    $0x19,%r9b
  ja     L75
  lea    -0x61(%rax),%r9d
  cmp    $0x19,%r9b
  ja     L82
  movsbl %al,%eax
  sub    $0x20,%eax
  movsbl %dl,%edx
  cmp    %edx,%eax
  jne    L34
L116:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  je     L45
L29:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%r8,%rcx,1),%edx
  cmp    %dl,%al
  je     L116
  jge    L93
  lea    -0x41(%rax),%r9d
  cmp    $0x19,%r9b
  ja     L15
  lea    -0x61(%rdx),%r9d
  cmp    $0x19,%r9b
  ja     L42
  movsbl %al,%eax
  add    $0x20,%eax
  movsbl %dl,%edx
  cmp    %edx,%eax
  je     L116
  mov    $0x0,%eax
  ret
L45:
  mov    $0x1,%eax
  ret
L54:
  mov    $0x1,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
L42:
  mov    $0x0,%eax
  ret
L75:
  mov    $0x0,%eax
  ret
L82:
  mov    $0x0,%eax
  ret
L34:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcaseequal(const char *str1, const char *str2, size_t length) {
  size_t i;
  for (i = 0; i < length; i++) {
    if (str1[i] == str2[i]) {
      continue;
    }
    if (str1[i] < str2[i]) {
      if (str1[i] < 'A' || str1[i] > 'Z') {
        return 0;
      }
      if (str2[i] < 'a' || str2[i] > 'z') {
        return 0;
      }
      if (str1[i] + 'a' - 'A' != str2[i]) {
        return 0;
      }
    }
    if (str1[i] > str2[i]) {
      if (str2[i] < 'A' || str2[i] > 'Z') {
        return 0;
      }
      if (str1[i] < 'a' || str1[i] > 'z') {
        return 0;
      }
      if (str1[i] + 'A' - 'a' != str2[i]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memcaseequal>:
  endbr64
  mov    %rdi,%r8
  test   %rdx,%rdx
  je     L14
  xor    %ecx,%ecx
  jmp    L81
L82:
  lea    -0x41(%rax),%r9d
  cmp    $0x19,%r9b
  ja     L9
  lea    -0x61(%rdi),%r9d
  cmp    $0x19,%r9b
  ja     L9
  add    $0x20,%eax
  cmp    %al,%dil
  jne    L9
L25:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L14
L81:
  movzbl (%r8,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edi
  cmp    %dil,%al
  je     L25
  jl     L82
  jle    L25
  lea    -0x41(%rdi),%r9d
  cmp    $0x19,%r9b
  ja     L9
  lea    -0x61(%rax),%r9d
  cmp    $0x19,%r9b
  ja     L9
  sub    $0x20,%eax
  cmp    %al,%dil
  je     L25
L9:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcaseequal(const char *str1, const char *str2, size_t length) {
  size_t i;
  for (i = 0; i < length; i++) {
    if (str1[i] == str2[i]) {
      continue;
    }
    if (str1[i] < str2[i]) {
      if (str1[i] < 'A' || str1[i] > 'Z') {
        return 0;
      }
      if (str2[i] < 'a' || str2[i] > 'z') {
        return 0;
      }
      if (str1[i] + 'a' - 'A' != str2[i]) {
        return 0;
      }
    }
    if (str1[i] > str2[i]) {
      if (str2[i] < 'A' || str2[i] > 'Z') {
        return 0;
      }
      if (str1[i] < 'a' || str1[i] > 'z') {
        return 0;
      }
      if (str1[i] + 'A' - 'a' != str2[i]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcaseequal>:
  endbr64
  mov    %rdi,%r8
  test   %rdx,%rdx
  je     L30
  xor    %ecx,%ecx
  jmp    L61
L69:
  lea    -0x41(%rax),%r9d
  cmp    $0x19,%r9b
  ja     L43
  lea    -0x61(%rdi),%r9d
  cmp    $0x19,%r9b
  ja     L43
  add    $0x20,%eax
  cmp    %al,%dil
  jne    L43
L68:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L30
L61:
  movzbl (%r8,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edi
  cmp    %dil,%al
  je     L68
  jl     L69
  jle    L68
  lea    -0x41(%rdi),%r9d
  cmp    $0x19,%r9b
  ja     L43
  lea    -0x61(%rax),%r9d
  cmp    $0x19,%r9b
  ja     L43
  sub    $0x20,%eax
  cmp    %al,%dil
  je     L68
L43:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcaseequal(const char *str1, const char *str2, size_t length) {
  size_t i;
  for (i = 0; i < length; i++) {
    if (str1[i] == str2[i]) {
      continue;
    }
    if (str1[i] < str2[i]) {
      if (str1[i] < 'A' || str1[i] > 'Z') {
        return 0;
      }
      if (str2[i] < 'a' || str2[i] > 'z') {
        return 0;
      }
      if (str1[i] + 'a' - 'A' != str2[i]) {
        return 0;
      }
    }
    if (str1[i] > str2[i]) {
      if (str2[i] < 'A' || str2[i] > 'Z') {
        return 0;
      }
      if (str1[i] < 'a' || str1[i] > 'z') {
        return 0;
      }
      if (str1[i] + 'A' - 'a' != str2[i]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_config_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L87
L38:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <next_char@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L100
  cmpl   $0x23,-0x4(%rbp)
  je     L27
  cmpl   $0x3b,-0x4(%rbp)
  jne    L100
L27:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_line@plt>
  jmp    L87
L100:
  cmpl   $0x0,-0x8(%rbp)
  jne    L29
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L29
  jmp    L87
L29:
  cmpl   $0x3d,-0x4(%rbp)
  jne    L60
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L60
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L61
L60:
  cmpl   $0xa,-0x4(%rbp)
  jne    L78
  cmpl   $0x0,-0x8(%rbp)
  jne    L78
  movl   $0x0,-0xc(%rbp)
  jmp    L87
L78:
  cmpl   $0xa,-0x4(%rbp)
  je     L164
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L141
L164:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L111
L141:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L61:
  movl   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L87:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L38
L111:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_config_line(FILE *f, char *line, const char **value, int bufsize) {
  int i = 0, isname = 0;
  *value = NULL;
  while (i < bufsize - 1) {
    int c = next_char(f);
    if (!isname && (c == '#' || c == ';')) {
      skip_line(f);
      continue;
    }
    if (!isname && isspace(c))
      continue;
    if (c == '=' && !*value) {
      line[i] = 0;
      *value = &line[i + 1];
    } else if (c == '\n' && !isname) {
      i = 0;
      continue;
    } else if (c == '\n' || c == EOF) {
      line[i] = 0;
      break;
    } else {
      line[i] = c;
    }
    isname = 1;
    i++;
  }
  line[i + 1] = 0;
  return i;
}
```