ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<merge_increase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    %rsi,%rdi
  jb     L53
L91:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %rsi,%r14
  mov    %rsi,%rbp
  mov    %rdi,%r12
  sub    %rdi,%r14
  sar    $0x2,%r14
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r13
  mov    %r13,%rsi
  lea    0x4(%r13),%rbx
  call   <merge_increase>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <merge_increase>
  test   %r14d,%r14d
  js     L91
  mov    %rsp,%r8
  mov    %r14d,%r14d
  mov    %r12,%rdx
  mov    %r8,%rax
  lea    0x4(%rsp,%r14,4),%rdi
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %esi,%ecx
  add    $0x4,%rax
  add    $0x4,%rbx
  mov    %ecx,-0x4(%rax)
  cmp    %rax,%rdi
  je     L1
L66:
  mov    (%rdx),%ecx
  mov    (%rbx),%esi
  cmp    %rdx,%r13
  jb     L16
  cmp    %esi,%ecx
  jl     L33
L16:
  cmp    %rbx,%rbp
  jae    L6
L33:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rax,%rdi
  jne    L66
L1:
  lea    0x4(,%r14,4),%rdx
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  jmp    L91
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge_increase(int *front, int *end) {
  if (front >= end)
    return;
  int size = end - front;
  int *mid = front + size / 2;
  merge_increase(front, mid);
  merge_increase(mid + 1, end);
  int *left = front;
  int *right = mid + 1;
  int tmp_sort[1000];
  int i;
  for (i = 0; i <= size; ++i) {
    if (*left < *right && left <= mid || right > end) {
      tmp_sort[i] = *left;
      left++;
    } else {
      tmp_sort[i] = *right;
      right++;
    }
  }
  for (i = 0; i <= size; ++i)
    *(front + i) = tmp_sort[i];
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<merge_increase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    %rsi,%rdi
  jb     L65
L39:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %rsi,%r13
  mov    %rsi,%rbp
  mov    %rdi,%r12
  sub    %rdi,%r13
  sar    $0x2,%r13
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %r13d,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r14
  mov    %r14,%rsi
  lea    0x4(%r14),%rbx
  call   <merge_increase>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <merge_increase>
  test   %r13d,%r13d
  js     L39
  mov    %rsp,%r8
  mov    %r13d,%r13d
  mov    %r12,%rcx
  mov    %r8,%rax
  lea    0x4(%rsp,%r13,4),%rdi
  jmp    L96
  nopl   0x0(%rax,%rax,1)
L80:
  mov    %esi,%edx
  add    $0x4,%rax
  add    $0x4,%rbx
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rdi
  je     L54
L96:
  mov    (%rcx),%edx
  mov    (%rbx),%esi
  cmp    %edx,%esi
  jle    L19
  cmp    %rcx,%r14
  jae    L13
L19:
  cmp    %rbx,%rbp
  jae    L80
L13:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x4,%rcx
  cmp    %rax,%rdi
  jne    L96
L54:
  lea    0x4(,%r13,4),%rdx
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  jmp    L39
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge_increase(int *front, int *end) {
  if (front >= end)
    return;
  int size = end - front;
  int *mid = front + size / 2;
  merge_increase(front, mid);
  merge_increase(mid + 1, end);
  int *left = front;
  int *right = mid + 1;
  int tmp_sort[1000];
  int i;
  for (i = 0; i <= size; ++i) {
    if (*left < *right && left <= mid || right > end) {
      tmp_sort[i] = *left;
      left++;
    } else {
      tmp_sort[i] = *right;
      right++;
    }
  }
  for (i = 0; i <= size; ++i)
    *(front + i) = tmp_sort[i];
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printksize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  mov    -0x4(%rbp),%eax
  add    $0x3ff,%eax
  cmp    $0x7fe,%eax
  ja     L22
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L22:
  mov    -0x4(%rbp),%eax
  lea    0x3ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xa,%eax
  cltq
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L25:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D15:    1K 

tool: D9: %4lldK 

assistant: ```c
void printksize(off_t size) {
  if (size != 0 && size / 1024 == 0)
    printf("   1K ");
  else
    printf("%4lldK ", (long long)size / 1024);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printksize>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L3
  lea    0x3ff(%rdi),%eax
  cmp    $0x7fe,%eax
  jbe    L27
L3:
  lea    0x3ff(%rdi),%esi
  test   %edi,%edi
  cmovns %edi,%esi
  sar    $0xa,%esi
  movslq %esi,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  add    $0x8,%rsp
  ret
L27:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string

tool: D4: %4lldK 

tool: D15:    1K 

assistant: ```c
void printksize(off_t size) {
  if (size != 0 && size / 1024 == 0)
    printf("   1K ");
  else
    printf("%4lldK ", (long long)size / 1024);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printksize>:
  endbr64
  mov    $0x3ff,%esi
  test   %edi,%edi
  je     L12
  lea    0x3ff(%rdi),%esi
  cmp    $0x7fe,%esi
  jbe    L13
L12:
  test   %edi,%edi
  cmovns %edi,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  sar    $0xa,%esi
  movslq %esi,%rsi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L13:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string

tool: D18: %4lldK 

tool: D1:    1K 

assistant: ```c
void printksize(off_t size) {
  if (size != 0 && size / 1024 == 0)
    printf("   1K ");
  else
    printf("%4lldK ", (long long)size / 1024);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printksize>:
  endbr64
  mov    $0x3ff,%esi
  test   %edi,%edi
  je     L7
  lea    0x3ff(%rdi),%esi
  cmp    $0x7fe,%esi
  jbe    L8
L7:
  test   %edi,%edi
  cmovns %edi,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  sar    $0xa,%esi
  movslq %esi,%rsi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L8:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D1: %4lldK 

tool: D5:    1K 

assistant: ```c
void printksize(off_t size) {
  if (size != 0 && size / 1024 == 0)
    printf("   1K ");
  else
    printf("%4lldK ", (long long)size / 1024);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gdb_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <rsp_client_close@plt>
  mov    $0x30,%edi
  call   <client_close@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gdb_close() {
  rsp_client_close();
  client_close('0');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gdb_close>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rsp_client_close@plt>
  mov    $0x30,%edi
  call   <client_close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gdb_close() {
  rsp_client_close();
  client_close('0');
}
```
user: Translate the below assembly code into C programming language:

```asm
<gdb_close>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rsp_client_close@plt>
  mov    $0x30,%edi
  add    $0x8,%rsp
  jmp    1060 <client_close@plt>
```

assistant: ```c
void gdb_close() {
  rsp_client_close();
  client_close('0');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gdb_close>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rsp_client_close@plt>
  mov    $0x30,%edi
  add    $0x8,%rsp
  jmp    1060 <client_close@plt>
```

assistant: ```c
void gdb_close() {
  rsp_client_close();
  client_close('0');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1a8(%rbp)
  movl   $0x0,-0x1a4(%rbp)
  jmp    L23
L26:
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1ac(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L23
  mov    -0x1ac(%rbp),%edx
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
  addl   $0x1,-0x1a4(%rbp)
L23:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L26
  movl   $0x0,-0x1a8(%rbp)
  jmp    L8
L6:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b0(%rbp),%eax
  sub    -0x1a8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1a8(%rbp)
L8:
  mov    -0x1b0(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L6
  mov    -0x1a4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string

tool: D29: %d

tool: D16: %d


assistant: ```c
int main() {
  int i, n, b, t;
  int mas[100];
  scanf("%d", &n);
  for (i = 0, b = 0; i < n;) {
    scanf("%d", &t);
    if (t % 2 != 0) {
      mas[i] = t;
      i++;
      b++;
    }
  }
  for (i = 0; i < n / 2; i++)
    printf("%d\n", mas[i] - mas[n - i - 1]);
  printf("%d\n", mas[b / 2]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D19(%rip),%rbp
L29:
  mov    %ebx,%r12d
L7:
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jle    L13
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  je     L7
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  jmp    L29
L13:
  cmp    $0x1,%eax
  jle    L51
  mov    $0x0,%ebx
  lea    D32(%rip),%rbp
L20:
  sub    %ebx,%eax
  sub    $0x1,%eax
  cltq
  mov    0x10(%rsp,%rbx,4),%esi
  sub    0x10(%rsp,%rax,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  add    $0x1,%rbx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebx,%edx
  jg     L20
L51:
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D32
type_infered: string

tool: D19: %d

tool: D32: %d


assistant: ```c
int main() {
  int i, n, b, t;
  int mas[100];
  scanf("%d", &n);
  for (i = 0, b = 0; i < n;) {
    scanf("%d", &t);
    if (t % 2 != 0) {
      mas[i] = t;
      i++;
      b++;
    }
  }
  for (i = 0; i < n / 2; i++)
    printf("%d\n", mas[i] - mas[n - i - 1]);
  printf("%d\n", mas[b / 2]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
L14:
  mov    %ebp,%ebx
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  jne    L57
L42:
  mov    0x8(%rsp),%eax
  cmp    %ebp,%eax
  jg     L4
  lea    D3(%rip),%r13
  cmp    $0x1,%eax
  jle    L51
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L12:
  sub    %ebp,%eax
  mov    (%r12,%rbp,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbp
  sub    $0x1,%eax
  cltq
  sub    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebp,%edx
  jg     L12
L51:
  sar    %ebx
  mov    %r13,%rdi
  movslq %ebx,%rbx
  mov    0x10(%rsp,%rbx,4),%esi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L57:
  mov    %eax,0x10(%rsp,%rbp,4)
  add    $0x1,%rbp
  jmp    L14
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string
name: read_data
arguments: data_label: D3
datatype: string

tool: D6: %d

tool: D3: %d


assistant: ```c
int main() {
  int i, n, b, t;
  int mas[100];
  scanf("%d", &n);
  for (i = 0, b = 0; i < n;) {
    scanf("%d", &t);
    if (t % 2 != 0) {
      mas[i] = t;
      i++;
      b++;
    }
  }
  for (i = 0; i < n / 2; i++)
    printf("%d\n", mas[i] - mas[n - i - 1]);
  printf("%d\n", mas[b / 2]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
L34:
  mov    %ebp,%ebx
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  jne    L40
L33:
  mov    0x8(%rsp),%eax
  cmp    %ebp,%eax
  jg     L65
  lea    D2(%rip),%r13
  cmp    $0x1,%eax
  jle    L14
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L23:
  sub    %ebp,%eax
  mov    (%r12,%rbp,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbp
  sub    $0x1,%eax
  cltq
  sub    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebp,%edx
  jg     L23
L14:
  sar    %ebx
  mov    %r13,%rdi
  movslq %ebx,%rbx
  mov    0x10(%rsp,%rbx,4),%esi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  mov    %eax,0x10(%rsp,%rbp,4)
  add    $0x1,%rbp
  jmp    L34
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D10: %d

tool: D2: %d


assistant: ```c
int main() {
  int i, n, b, t;
  int mas[100];
  scanf("%d", &n);
  for (i = 0, b = 0; i < n;) {
    scanf("%d", &t);
    if (t % 2 != 0) {
      mas[i] = t;
      i++;
      b++;
    }
  }
  for (i = 0; i < n / 2; i++)
    printf("%d\n", mas[i] - mas[n - i - 1]);
  printf("%d\n", mas[b / 2]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NRMethod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    %rsi,-0x48(%rbp)
  movsd  %xmm1,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  movl   $0x0,-0x24(%rbp)
L32:
  mov    -0x38(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rbx
  mov    -0x38(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x38(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L2
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  jmp    L48
L2:
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
L48:
  movsd  %xmm0,-0x18(%rbp)
  cmpl   $0x0,-0x54(%rbp)
  je     L17
  movsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rdx
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L17:
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  addl   $0x1,-0x24(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x50(%rbp),%xmm0
  ja     L32
  cmpl   $0x0,-0x54(%rbp)
  je     L23
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string

tool: D9: x0 = %lf x1 = %lf and |x1-x0| = %lf


tool: D16: No of Iterations: %d


assistant: ```c
double NRMethod(double x0, double (*f)(double), double (*g)(double), double accuracy, int verbose) {
  double x1, diff;
  int i = 0;
  do {
    x1 = x0 - f(x0) / g(x0);
    diff = x0 > x1 ? (x0 - x1) : x1 - x0;
    if (verbose)
      printf("x0 = %lf x1 = %lf and |x1-x0| = %lf\n", x0, x1, diff);
    x0 = x1;
    i++;
  } while (diff > accuracy);
  if (verbose)
    printf("No of Iterations: %d\n", i);
  return x1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NRMethod>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  mov    %rdi,%r14
  mov    %rsi,%r13
  movsd  %xmm1,0x8(%rsp)
  mov    %edx,%r12d
  mov    $0x0,%ebp
  lea    D3(%rip),%r15
  jmp    L70
L11:
  movapd %xmm1,%xmm6
  subsd  %xmm3,%xmm6
  movq   %xmm6,%rbx
L46:
  test   %r12d,%r12d
  jne    L9
L61:
  add    $0x1,%ebp
  movq   %rbx,%xmm4
  comisd 0x8(%rsp),%xmm4
  jbe    L27
L70:
  movsd  (%rsp),%xmm0
  call   *%r14
  movq   %xmm0,%rbx
  movsd  (%rsp),%xmm0
  call   *%r13
  movapd %xmm0,%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm3,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm3
  movsd  %xmm3,(%rsp)
  comisd %xmm3,%xmm1
  ja     L11
  movsd  (%rsp),%xmm7
  subsd  %xmm1,%xmm7
  movq   %xmm7,%rbx
  jmp    L46
L9:
  cvttsd2si %xmm1,%esi
  movq   %rbx,%xmm1
  movsd  (%rsp),%xmm0
  mov    %r15,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L61
L27:
  test   %r12d,%r12d
  jne    L64
L38:
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D3: x0 = %lf x1 = %lf and |x1-x0| = %lf


tool: D2: No of Iterations: %d


assistant: ```c
double NRMethod(double x0, double (*f)(double), double (*g)(double), double accuracy, int verbose) {
  double x1, diff;
  int i = 0;
  do {
    x1 = x0 - f(x0) / g(x0);
    diff = x0 > x1 ? (x0 - x1) : x1 - x0;
    if (verbose)
      printf("x0 = %lf x1 = %lf and |x1-x0| = %lf\n", x0, x1, diff);
    x0 = x1;
    i++;
  } while (diff > accuracy);
  if (verbose)
    printf("No of Iterations: %d\n", i);
  return x1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NRMethod>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm2
  lea    D2(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  movsd  %xmm1,0x18(%rsp)
  jmp    L56
  nopl   (%rax)
L42:
  movapd %xmm3,%xmm1
  subsd  %xmm2,%xmm1
  test   %ebx,%ebx
  jne    L75
L18:
  add    $0x1,%ebp
  comisd 0x18(%rsp),%xmm1
  jbe    L43
L56:
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%r13
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  call   *%r12
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm0,%xmm1
  movapd %xmm2,%xmm3
  subsd  %xmm1,%xmm2
  comisd %xmm2,%xmm3
  ja     L42
  movapd %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  test   %ebx,%ebx
  je     L18
L75:
  cvttsd2si %xmm3,%esi
  movapd %xmm2,%xmm0
  mov    %r14,%rdi
  mov    $0x2,%eax
  movsd  %xmm1,0x10(%rsp)
  add    $0x1,%ebp
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm1
  comisd 0x18(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  ja     L56
L43:
  test   %ebx,%ebx
  jne    L73
L64:
  add    $0x20,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L73:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  jmp    L64
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D2: x0 = %lf x1 = %lf and |x1-x0| = %lf


tool: D4: No of Iterations: %d


assistant: ```c
double NRMethod(double x0, double (*f)(double), double (*g)(double), double accuracy, int verbose) {
  double x1, diff;
  int i = 0;
  do {
    x1 = x0 - f(x0) / g(x0);
    diff = x0 > x1 ? (x0 - x1) : x1 - x0;
    if (verbose)
      printf("x0 = %lf x1 = %lf and |x1-x0| = %lf\n", x0, x1, diff);
    x0 = x1;
    i++;
  } while (diff > accuracy);
  if (verbose)
    printf("No of Iterations: %d\n", i);
  return x1;
}
```