ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bitmap_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L0:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  jmp    L14
L3:
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L0
  mov    -0x2c(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L46
  mov    $0x40,%eax
  sub    -0xc(%rbp),%eax
  mov    $0xffffffffffffffff,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  and    %rdx,%rax
  test   %rax,%rax
  je     L46
  mov    $0x0,%eax
  jmp    L14
L46:
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int bitmap_empty(unsigned long *addr, int size) {
  long mask;
  int tail;
  int len;
  int i;
  len = size / 64;
  for (i = 0; i < len; i++)
    if (addr[i] != 0)
      return (0);
  tail = size & (64 - 1);
  if (tail) {
    mask = (~0UL >> (64 - (tail)));
    if ((addr[i] & mask) != 0)
      return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitmap_empty>:
  endbr64
  lea    0x3f(%rsi),%ecx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x6,%ecx
  cmp    $0x3f,%esi
  jle    L16
  mov    %rdi,%rdx
  mov    $0x0,%eax
L54:
  cmpq   $0x0,(%rdx)
  jne    L20
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%ecx
  jg     L54
L7:
  mov    $0x1,%edx
  and    $0x3f,%esi
  je     L25
  cltq
  mov    $0x40,%ecx
  sub    %esi,%ecx
  mov    $0xffffffffffffffff,%rdx
  shr    %cl,%rdx
  and    (%rdi,%rax,8),%rdx
  sete   %dl
  movzbl %dl,%edx
  jmp    L25
L16:
  mov    $0x0,%eax
  jmp    L7
L20:
  mov    $0x0,%edx
L25:
  mov    %edx,%eax
  ret
```

assistant: ```c
int bitmap_empty(unsigned long *addr, int size) {
  long mask;
  int tail;
  int len;
  int i;
  len = size / 64;
  for (i = 0; i < len; i++)
    if (addr[i] != 0)
      return (0);
  tail = size & (64 - 1);
  if (tail) {
    mask = (~0UL >> (64 - (tail)));
    if ((addr[i] & mask) != 0)
      return (0);
  }
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitmap_empty>:
  endbr64
  test   %esi,%esi
  lea    0x3f(%rsi),%ecx
  cmovns %esi,%ecx
  sar    $0x6,%ecx
  cmp    $0x3f,%esi
  jle    L21
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%ecx
  jle    L28
L26:
  cmpq   $0x0,(%rdx)
  je     L30
  xor    %r8d,%r8d
L9:
  mov    %r8d,%eax
  ret
L21:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%r8d
  and    $0x3f,%esi
  je     L9
  mov    $0x40,%ecx
  cltq
  mov    $0xffffffffffffffff,%rdx
  xor    %r8d,%r8d
  sub    %esi,%ecx
  shr    %cl,%rdx
  and    (%rdi,%rax,8),%rdx
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitmap_empty(unsigned long *addr, int size) {
  long mask;
  int tail;
  int len;
  int i;
  len = size / 64;
  for (i = 0; i < len; i++)
    if (addr[i] != 0)
      return (0);
  tail = size & (64 - 1);
  if (tail) {
    mask = (~0UL >> (64 - (tail)));
    if ((addr[i] & mask) != 0)
      return (0);
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitmap_empty>:
  endbr64
  test   %esi,%esi
  lea    0x3f(%rsi),%ecx
  cmovns %esi,%ecx
  sar    $0x6,%ecx
  cmp    $0x3f,%esi
  jle    L22
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%ecx
  jle    L17
L36:
  cmpq   $0x0,(%rdx)
  je     L41
  xor    %r8d,%r8d
L9:
  mov    %r8d,%eax
  ret
L22:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%r8d
  and    $0x3f,%esi
  je     L9
  mov    $0x40,%ecx
  cltq
  mov    $0xffffffffffffffff,%rdx
  xor    %r8d,%r8d
  sub    %esi,%ecx
  shr    %cl,%rdx
  and    (%rdi,%rax,8),%rdx
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitmap_empty(unsigned long *addr, int size) {
  long mask;
  int tail;
  int len;
  int i;
  len = size / 64;
  for (i = 0; i < len; i++)
    if (addr[i] != 0)
      return (0);
  tail = size & (64 - 1);
  if (tail) {
    mask = (~0UL >> (64 - (tail)));
    if ((addr[i] & mask) != 0)
      return (0);
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<capi20_release>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <loadlib@plt>
  test   %rax,%rax
  jns    L6
  mov    $0x1009,%eax
  jmp    L8
L6:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fptr_capi20_release@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned capi20_release(unsigned ApplID) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_release(ApplID);
}
```
user: What is the c source code of the assembly code below?

```asm
<capi20_release>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <loadlib@plt>
  mov    %rax,%rdx
  mov    $0x1009,%eax
  test   %rdx,%rdx
  js     L7
  mov    %ebx,%edi
  call   <fptr_capi20_release@plt>
L7:
  pop    %rbx
  ret
```

assistant: ```c
unsigned capi20_release(unsigned ApplID) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_release(ApplID);
}
```
user: Translate the below assembly code into C programming language:

```asm
<capi20_release>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <loadlib@plt>
  test   %rax,%rax
  js     L3
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <fptr_capi20_release@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1009,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned capi20_release(unsigned ApplID) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_release(ApplID);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<capi20_release>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <loadlib@plt>
  test   %rax,%rax
  js     L3
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <fptr_capi20_release@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1009,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned capi20_release(unsigned ApplID) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_release(ApplID);
}
```
user: What is the c source code of the assembly code below:

```asm
<ws_random_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <random@plt>
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ws_random_mask>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ws_random_mask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ws_random_mask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x1a8(%rbp)
  movl   $0x2,-0x1a4(%rbp)
  movl   $0x2,-0x1ac(%rbp)
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x1ac(%rbp),%edx
  lea    -0x1a0(%rbp),%rcx
  lea    -0x1a8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <decbin@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string

tool: D5: 


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {2, 2};
  int size = sizeof(a) / sizeof(a[0]);
  int res[100] = {0};
  decbin(a, res, size);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x2,%edx
  call   <decbin@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: 


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {2, 2};
  int size = sizeof(a) / sizeof(a[0]);
  int res[100] = {0};
  decbin(a, res, size);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  mov    $0x32,%ecx
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  movabs $0x200000002,%rax
  lea    0x10(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x8(%rsp),%rdi
  call   <decbin@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x1b8,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: 


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {2, 2};
  int size = sizeof(a) / sizeof(a[0]);
  int res[100] = {0};
  decbin(a, res, size);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  mov    $0x32,%ecx
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  lea    0x10(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x8(%rsp),%rdi
  call   <decbin@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x1b8,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: byte[8]
name: read_data
arguments: data_label: D11
type_guessed: string

tool: {"D17": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D11: 


assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {2, 2};
  int size = sizeof(a) / sizeof(a[0]);
  int res[100] = {0};
  decbin(a, res, size);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trimr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L11:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trimr(char *s) {
  size_t len = strlen(s);
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trimr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L8
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L6
L8:
  mov    %rbx,%rax
  pop    %rbx
  ret
L6:
  movb   $0x0,(%rax)
  jmp    L8
```

assistant: ```c
char *trimr(char *s) {
  size_t len = strlen(s);
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trimr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L9
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L3
L9:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trimr(char *s) {
  size_t len = strlen(s);
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trimr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L5
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L3
L5:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trimr(char *s) {
  size_t len = strlen(s);
  if (len && s[len - 1] == '\n') {
    s[len - 1] = '\0';
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L14
L32:
  cmpl   $0x1,-0x14(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L14
L7:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibo>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibo>
  add    %ebx,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibo(int n) {
  if (n == 0)
    return 0;
  else if (n == 1)
    return 1;
  else
    return fibo(n - 1) + fibo(n - 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L29
  cmp    $0x1,%edi
  jne    L28
L29:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  lea    -0x1(%rdi),%edi
  call   <fibo>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fibo>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L29
```

assistant: ```c
int fibo(int n) {
  if (n == 0)
    return 0;
  else if (n == 1)
    return 1;
  else
    return fibo(n - 1) + fibo(n - 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sqlite3AffinityType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L98
  mov    $0x6f,%eax
  jmp    L60
L98:
  movl   $0x0,-0x1c(%rbp)
  jmp    L40
L75:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D24(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D34(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x2c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D24(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L11
L68:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L13
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L79
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D34(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sqlite3StrNICmp@plt>
  test   %rax,%rax
  jne    L79
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D15(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  jmp    L60
L79:
  addl   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L68
  addl   $0x1,-0x1c(%rbp)
L40:
  mov    -0x1c(%rbp),%eax
  cmp    $0x4,%eax
  jbe    L75
  mov    $0x6e,%eax
L60:
  leave
  ret
```

assistant: ```c
char sqlite3AffinityType(const char *zType, int nType) {
  int n, i;
  static const struct {
    const char *zSub;
    char nSub;
    char affinity;
  } substrings[] = {
      {"INT", 3, 'i'}, {"CHAR", 4, 't'}, {"CLOB", 4, 't'}, {"TEXT", 4, 't'}, {"BLOB", 4, 'o'},
  };
  if (nType == 0) {
    return 'o';
  }
  for (i = 0; i < sizeof(substrings) / sizeof(substrings[0]); i++) {
    int c1 = substrings[i].zSub[0];
    int c2 = tolower(c1);
    int limit = nType - substrings[i].nSub;
    const char *z = substrings[i].zSub;
    for (n = 0; n <= limit; n++) {
      int c = zType[n];
      if ((c == c1 || c == c2) && 0 == sqlite3StrNICmp(&zType[n], z, substrings[i].nSub)) {
        return substrings[i].affinity;
      }
    }
  }
  return 'n';
}
```
user: Translate the below assembly code into C programming language:

```asm
<sqlite3AffinityType>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x14(%rsp)
  mov    $0x6f,%eax
  test   %esi,%esi
  je     L11
  lea    D19(%rip),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  jmp    L3
L5:
  mov    0x4(%rsp),%edx
  mov    %r15,%rsi
  call   <sqlite3StrNICmp@plt>
  test   %rax,%rax
  je     L24
L27:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r14d
  jl     L103
L86:
  mov    %rbx,%rdi
  movsbl (%rbx),%eax
  cmp    %eax,%r12d
  je     L5
  cmp    %eax,%r13d
  jne    L27
  jmp    L5
L24:
  movslq 0x10(%rsp),%rax
  shl    $0x4,%rax
  lea    D19(%rip),%rdx
  movzbl 0x9(%rdx,%rax,1),%eax
L11:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L103:
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%eax
  addq   $0x10,0x8(%rsp)
  cmp    $0x5,%eax
  je     L94
L3:
  mov    0x8(%rsp),%rbx
  mov    (%rbx),%r15
  movsbl (%r15),%r12d
  mov    %r12d,%edi
  call   <tolower@plt>
  mov    %eax,%r13d
  movsbl 0x8(%rbx),%eax
  mov    %eax,0x4(%rsp)
  mov    0x14(%rsp),%r14d
  sub    %eax,%r14d
  js     L103
  mov    0x18(%rsp),%rbx
  mov    $0x0,%ebp
  jmp    L86
L94:
  mov    $0x6e,%eax
  jmp    L11
```

assistant: ```c
char sqlite3AffinityType(const char *zType, int nType) {
  int n, i;
  static const struct {
    const char *zSub;
    char nSub;
    char affinity;
  } substrings[] = {
      {"INT", 3, 'i'}, {"CHAR", 4, 't'}, {"CLOB", 4, 't'}, {"TEXT", 4, 't'}, {"BLOB", 4, 'o'},
  };
  if (nType == 0) {
    return 'o';
  }
  for (i = 0; i < sizeof(substrings) / sizeof(substrings[0]); i++) {
    int c1 = substrings[i].zSub[0];
    int c2 = tolower(c1);
    int limit = nType - substrings[i].nSub;
    const char *z = substrings[i].zSub;
    for (n = 0; n <= limit; n++) {
      int c = zType[n];
      if ((c == c1 || c == c2) && 0 == sqlite3StrNICmp(&zType[n], z, substrings[i].nSub)) {
        return substrings[i].affinity;
      }
    }
  }
  return 'n';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sqlite3AffinityType>:
  endbr64
  push   %r15
  mov    $0x6f,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,0x1c(%rsp)
  test   %esi,%esi
  je     L29
  lea    D10(%rip),%rax
  movl   $0x0,0x18(%rsp)
  mov    $0x49,%r9d
  mov    %rax,0x8(%rsp)
  lea    D14(%rip),%rax
  mov    %rax,(%rsp)
L59:
  movsbl %r9b,%ebx
  xor    %ebp,%ebp
  mov    %ebx,%edi
  call   <tolower@plt>
  mov    0x1c(%rsp),%r14d
  mov    0x10(%rsp),%r12
  mov    %eax,%r13d
  mov    0x8(%rsp),%rax
  movsbl 0x8(%rax),%r15d
  sub    %r15d,%r14d
  jns    L5
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L51:
  add    $0x1,%ebp
  add    $0x1,%r12
  cmp    %ebp,%r14d
  jl     L67
L5:
  movsbl (%r12),%eax
  cmp    %eax,%ebx
  je     L8
  cmp    %eax,%r13d
  jne    L51
L8:
  mov    (%rsp),%rsi
  mov    %r15d,%edx
  mov    %r12,%rdi
  call   <sqlite3StrNICmp@plt>
  test   %rax,%rax
  jne    L51
  movslq 0x18(%rsp),%r12
  lea    D10(%rip),%rax
  shl    $0x4,%r12
  movzbl 0x9(%rax,%r12,1),%eax
L29:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  addl   $0x1,0x18(%rsp)
  mov    0x18(%rsp),%eax
  addq   $0x10,0x8(%rsp)
  cmp    $0x5,%eax
  je     L82
  mov    0x8(%rsp),%rax
  mov    (%rax),%rax
  mov    %rax,(%rsp)
  movzbl (%rax),%r9d
  jmp    L59
L82:
  add    $0x28,%rsp
  mov    $0x6e,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string

tool: D14: INT

assistant: ```c
char sqlite3AffinityType(const char *zType, int nType) {
  int n, i;
  static const struct {
    const char *zSub;
    char nSub;
    char affinity;
  } substrings[] = {
      {"INT", 3, 'i'}, {"CHAR", 4, 't'}, {"CLOB", 4, 't'}, {"TEXT", 4, 't'}, {"BLOB", 4, 'o'},
  };
  if (nType == 0) {
    return 'o';
  }
  for (i = 0; i < sizeof(substrings) / sizeof(substrings[0]); i++) {
    int c1 = substrings[i].zSub[0];
    int c2 = tolower(c1);
    int limit = nType - substrings[i].nSub;
    const char *z = substrings[i].zSub;
    for (n = 0; n <= limit; n++) {
      int c = zType[n];
      if ((c == c1 || c == c2) && 0 == sqlite3StrNICmp(&zType[n], z, substrings[i].nSub)) {
        return substrings[i].affinity;
      }
    }
  }
  return 'n';
}
```