user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x18(%rbp),%xmm2
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L25
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L25:
  movss  -0x14(%rbp),%xmm2
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L9
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L9:
  movss  -0x10(%rbp),%xmm2
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L32
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L32:
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x1c(%rbp),%xmm4
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm4,%xmm5
  movq   %xmm5,%rax
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x5,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D87
type: string
name: unpack_data
arguments: data_tag: D72
type: string
name: unpack_data
arguments: data_tag: D74
type: string
name: unpack_data
arguments: data_tag: D95
type: string
name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D28
type: string

tool: D3: 
		----------------		
		QUIN ES MES GRAN		
		-----------------


tool: D87: Entra els 4 valors a comparar:
1.>

tool: D72: %f

tool: D74: 2.>

tool: D95: 3.>

tool: D22: 4.>

tool: D28: Dels vlaors [%.2f,%.2f,%.2f,%.2f] el mes gran es: %.2f


assistant: ```c
int main() {
  float a, b, c, d, max;
  printf("\n\t\t----------------		\n\t\tQUIN ES MES GRAN		\n\t\t-----------------\n\n");
  printf("Entra els 4 valors a comparar:\n1.>");
  scanf("%f", &a);
  printf("2.>");
  scanf("%f", &b);
  printf("3.>");
  scanf("%f", &c);
  printf("4.>");
  scanf("%f", &d);
  max = a;
  if (max - b < 0) {
    max = b;
  }
  if (max - c < 0) {
    max = c;
  }
  if (max - d < 0) {
    max = d;
  }
  printf("Dels vlaors [%.2f,%.2f,%.2f,%.2f] el mes gran es: %.2f\n", a, b, c, d, max);
  return 0;
}
```