ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ReplaceSymbolRF>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  movq   %xmm0,%r15
  lea    0x1000(%rsp),%r12
  call   <inlinestrpos@plt>
  movb   $0x0,0x1000(%rsp)
  movslq %eax,%rbx
  test   %ebx,%ebx
  jne    L6
L20:
  mov    $0x1,%edx
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rsp,%r13
  call   <strpos2@plt>
  mov    %rbp,%rdi
  lea    0x2000(%rsp),%r14
  movslq %eax,%rbx
  call   <strlen@plt>
  lea    0x3(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%ecx
  sub    %edx,%ecx
  lea    0x4(%rbx),%edx
  call   <strsub@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  movq   %r15,%xmm0
  mov    %r14,%rdi
  lea    D11(%rip),%rsi
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x3008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x3018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%ecx
  call   <strsub@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string

tool: D18: _RF_

tool: D11: %E

assistant: ```c
void ReplaceSymbolRF(char *ret, double y_value) {
  int k, ii;
  char laux[4096], inlinecomment[4096], lxp[4096];
  k = inlinestrpos(ret);
  inlinecomment[0] = '\0';
  if (k) {
    strsub(inlinecomment, ret, k, (int)strlen(ret));
    ret[k - 1] = '\0';
  }
  ii = strpos2(ret, "_RF_", 1) + 3;
  strsub(laux, ret, ii + 1, (int)strlen(ret) - ii);
  ret[ii - 2 - 2] = '\0';
  sprintf(lxp, "%E", y_value);
  strcat(ret, lxp);
  strcat(ret, laux);
  strcat(ret, inlinecomment);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ReplaceSymbolRF>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  movq   %xmm0,%r15
  lea    0x1000(%rsp),%r12
  call   <inlinestrpos@plt>
  movb   $0x0,0x1000(%rsp)
  movslq %eax,%rbx
  test   %ebx,%ebx
  jne    L16
L12:
  mov    $0x1,%edx
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rsp,%r13
  call   <strpos2@plt>
  mov    %rbp,%rdi
  lea    0x2000(%rsp),%r14
  movslq %eax,%rbx
  call   <strlen@plt>
  lea    0x3(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%ecx
  sub    %edx,%ecx
  lea    0x4(%rbx),%edx
  call   <strsub@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  movq   %r15,%xmm0
  mov    %r14,%rdi
  lea    D12(%rip),%rsi
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x3008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x3018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%ecx
  call   <strsub@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  jmp    L12
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string

tool: D10: _RF_

tool: D12: %E

assistant: ```c
void ReplaceSymbolRF(char *ret, double y_value) {
  int k, ii;
  char laux[4096], inlinecomment[4096], lxp[4096];
  k = inlinestrpos(ret);
  inlinecomment[0] = '\0';
  if (k) {
    strsub(inlinecomment, ret, k, (int)strlen(ret));
    ret[k - 1] = '\0';
  }
  ii = strpos2(ret, "_RF_", 1) + 3;
  strsub(laux, ret, ii + 1, (int)strlen(ret) - ii);
  ret[ii - 2 - 2] = '\0';
  sprintf(lxp, "%E", y_value);
  strcat(ret, lxp);
  strcat(ret, laux);
  strcat(ret, inlinecomment);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<interpolate_tri2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D0(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm1
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm2
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x58(%rbp),%rax
  add    $0x8,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x58(%rbp),%rax
  add    $0x10,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x58(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x58(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x58(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: f64

tool: D0: 1

assistant: ```c
void interpolate_tri2d(const double a[2], const double ab[2], const double ac[2], const double p[2], double c[3]) {
  const double ap[2] = {p[0] - a[0], p[1] - a[1]};
  const double nrm = 1. / (ab[0] * ac[1] - ab[1] * ac[0]);
  c[1] = nrm * (ap[0] * ac[1] - ap[1] * ac[0]);
  c[2] = nrm * (ab[0] * ap[1] - ab[1] * ap[0]);
  c[0] = 1. - (c[1] + c[2]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interpolate_tri2d>:
  endbr64
  movsd  (%rcx),%xmm2
  subsd  (%rdi),%xmm2
  movsd  0x8(%rcx),%xmm1
  subsd  0x8(%rdi),%xmm1
  movsd  0x8(%rdx),%xmm0
  movsd  (%rdx),%xmm4
  movapd %xmm0,%xmm5
  mulsd  (%rsi),%xmm5
  movapd %xmm4,%xmm3
  mulsd  0x8(%rsi),%xmm3
  subsd  %xmm3,%xmm5
  movsd  D5(%rip),%xmm3
  movapd %xmm3,%xmm6
  divsd  %xmm5,%xmm6
  mulsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm0
  movsd  %xmm0,0x8(%r8)
  mulsd  (%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm6,%xmm1
  movsd  %xmm1,0x10(%r8)
  addsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  movsd  %xmm3,(%r8)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: f64

tool: D5: 1

assistant: ```c
void interpolate_tri2d(const double a[2], const double ab[2], const double ac[2], const double p[2], double c[3]) {
  const double ap[2] = {p[0] - a[0], p[1] - a[1]};
  const double nrm = 1. / (ab[0] * ac[1] - ab[1] * ac[0]);
  c[1] = nrm * (ap[0] * ac[1] - ap[1] * ac[0]);
  c[2] = nrm * (ab[0] * ap[1] - ab[1] * ap[0]);
  c[0] = 1. - (c[1] + c[2]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolate_tri2d>:
  endbr64
  movsd  0x8(%rdx),%xmm0
  movsd  (%rdx),%xmm4
  movsd  (%rsi),%xmm5
  movsd  0x8(%rsi),%xmm3
  movsd  (%rcx),%xmm2
  movsd  0x8(%rcx),%xmm1
  mulsd  %xmm4,%xmm3
  subsd  (%rdi),%xmm2
  subsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm5
  mulsd  %xmm1,%xmm4
  mulsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm5
  movsd  D5(%rip),%xmm3
  movapd %xmm3,%xmm6
  divsd  %xmm5,%xmm6
  subsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm0
  movsd  %xmm0,0x8(%r8)
  mulsd  (%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm1,0x10(%r8)
  subsd  %xmm0,%xmm3
  movsd  %xmm3,(%r8)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: f64

tool: D5: 1

assistant: ```c
void interpolate_tri2d(const double a[2], const double ab[2], const double ac[2], const double p[2], double c[3]) {
  const double ap[2] = {p[0] - a[0], p[1] - a[1]};
  const double nrm = 1. / (ab[0] * ac[1] - ab[1] * ac[0]);
  c[1] = nrm * (ap[0] * ac[1] - ap[1] * ac[0]);
  c[2] = nrm * (ab[0] * ap[1] - ab[1] * ap[0]);
  c[0] = 1. - (c[1] + c[2]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<interpolate_tri2d>:
  endbr64
  movsd  0x8(%rdx),%xmm0
  movsd  (%rdx),%xmm4
  movsd  (%rsi),%xmm5
  movsd  0x8(%rsi),%xmm3
  movsd  (%rcx),%xmm2
  movsd  0x8(%rcx),%xmm1
  mulsd  %xmm4,%xmm3
  subsd  (%rdi),%xmm2
  subsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm5
  mulsd  %xmm1,%xmm4
  mulsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm5
  movsd  D6(%rip),%xmm3
  movapd %xmm3,%xmm6
  divsd  %xmm5,%xmm6
  subsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm0
  movsd  %xmm0,0x8(%r8)
  mulsd  (%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm1,0x10(%r8)
  subsd  %xmm0,%xmm3
  movsd  %xmm3,(%r8)
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: f64

tool: D6: 1

assistant: ```c
void interpolate_tri2d(const double a[2], const double ab[2], const double ac[2], const double p[2], double c[3]) {
  const double ap[2] = {p[0] - a[0], p[1] - a[1]};
  const double nrm = 1. / (ab[0] * ac[1] - ab[1] * ac[0]);
  c[1] = nrm * (ap[0] * ac[1] - ap[1] * ac[0]);
  c[2] = nrm * (ab[0] * ap[1] - ab[1] * ap[0]);
  c[0] = 1. - (c[1] + c[2]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_envp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L82
L48:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L4
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L13
  jmp    L54
L4:
  nop
L54:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L41
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L51
L41:
  addl   $0x1,-0x8(%rbp)
L82:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L48
  mov    $0x0,%eax
L51:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: %s 

assistant: ```c
int is_envp(char *env, char *envp[]) {
  int i = 0, j = 0;
  for (; envp[i] != NULL; i++) {
    j = 0;
    while (envp[i][j] != '=') {
      if (envp[i][j] != env[j]) {
        break;
      }
      j++;
    }
    if (envp[i][j] == '=' && env[j] == '\0') {
      printf("%s ", (char *)envp[i] + j + 1);
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_envp>:
  endbr64
  mov    (%rsi),%rcx
  test   %rcx,%rcx
  je     L43
  add    $0x8,%rsi
  jmp    L24
L21:
  cmp    $0x3d,%dl
  je     L32
L46:
  add    $0x8,%rsi
  mov    -0x8(%rsi),%rcx
  test   %rcx,%rcx
  je     L13
L24:
  movzbl (%rcx),%edx
  mov    $0x0,%eax
  cmp    $0x3d,%dl
  je     L32
L79:
  cmp    %dl,(%rdi,%rax,1)
  jne    L21
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x3d,%dl
  jne    L79
L32:
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L46
  sub    $0x8,%rsp
  lea    0x1(%rcx,%rax,1),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L43:
  mov    $0x0,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: %s 

assistant: ```c
int is_envp(char *env, char *envp[]) {
  int i = 0, j = 0;
  for (; envp[i] != NULL; i++) {
    j = 0;
    while (envp[i][j] != '=') {
      if (envp[i][j] != env[j]) {
        break;
      }
      j++;
    }
    if (envp[i][j] == '=' && env[j] == '\0') {
      printf("%s ", (char *)envp[i] + j + 1);
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_envp>:
  endbr64
  mov    (%rsi),%rcx
  test   %rcx,%rcx
  je     L5
  add    $0x8,%rsi
L3:
  movzbl (%rcx),%edx
  xor    %eax,%eax
  cmp    $0x3d,%dl
  jne    L20
  jmp    L66
  nopl   0x0(%rax)
L40:
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x3d,%dl
  je     L14
L20:
  cmp    %dl,(%rdi,%rax,1)
  je     L40
L45:
  mov    (%rsi),%rcx
  add    $0x8,%rsi
  test   %rcx,%rcx
  jne    L3
L5:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L14:
  lea    (%rdi,%rax,1),%rdx
L73:
  cmpb   $0x0,(%rdx)
  jne    L45
  sub    $0x8,%rsp
  lea    0x1(%rcx,%rax,1),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L66:
  mov    %rdi,%rdx
  jmp    L73
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: %s 

assistant: ```c
int is_envp(char *env, char *envp[]) {
  int i = 0, j = 0;
  for (; envp[i] != NULL; i++) {
    j = 0;
    while (envp[i][j] != '=') {
      if (envp[i][j] != env[j]) {
        break;
      }
      j++;
    }
    if (envp[i][j] == '=' && env[j] == '\0') {
      printf("%s ", (char *)envp[i] + j + 1);
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_envp>:
  endbr64
  mov    (%rsi),%rcx
  test   %rcx,%rcx
  je     L50
  add    $0x8,%rsi
L79:
  movzbl (%rcx),%edx
  xor    %eax,%eax
  cmp    $0x3d,%dl
  jne    L56
  jmp    L67
  nopl   0x0(%rax)
L38:
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x3d,%dl
  je     L30
L56:
  cmp    %dl,(%rdi,%rax,1)
  je     L38
L10:
  mov    (%rsi),%rcx
  add    $0x8,%rsi
  test   %rcx,%rcx
  jne    L79
L50:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L30:
  lea    (%rdi,%rax,1),%rdx
L48:
  cmpb   $0x0,(%rdx)
  jne    L10
  sub    $0x8,%rsp
  lea    0x1(%rcx,%rax,1),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L67:
  mov    %rdi,%rdx
  jmp    L48
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: %s 

assistant: ```c
int is_envp(char *env, char *envp[]) {
  int i = 0, j = 0;
  for (; envp[i] != NULL; i++) {
    j = 0;
    while (envp[i][j] != '=') {
      if (envp[i][j] != env[j]) {
        break;
      }
      j++;
    }
    if (envp[i][j] == '=' && env[j] == '\0') {
      printf("%s ", (char *)envp[i] + j + 1);
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <heapify@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sift_down_iterative@plt>
L15:
  cmpl   $0x0,-0x8(%rbp)
  jg     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void heap_sort(int *A, int size) {
  int j;
  heapify(A, size);
  j = size - 1;
  while (j > 0) {
    {
      int tmp;
      tmp = (A[0]);
      (A[0]) = (A[j]);
      (A[j]) = tmp;
    };
    j = j - 1;
    sift_down_iterative(A, 0, j);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heap_sort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <heapify@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L6
  movslq %ebx,%rbx
L18:
  mov    0x0(%rbp),%eax
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,0x0(%rbp,%rbx,4)
  lea    -0x1(%rbx),%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <sift_down_iterative@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L18
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heap_sort(int *A, int size) {
  int j;
  heapify(A, size);
  j = size - 1;
  while (j > 0) {
    {
      int tmp;
      tmp = (A[0]);
      (A[0]) = (A[j]);
      (A[j]) = tmp;
    };
    j = j - 1;
    sift_down_iterative(A, 0, j);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x8,%rsp
  call   <heapify@plt>
  test   %ebx,%ebx
  jle    L6
  movslq %ebx,%rbx
  xchg   %ax,%ax
L2:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%rbp),%eax
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp)
  lea    -0x1(%rbx),%edx
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <sift_down_iterative@plt>
  test   %ebx,%ebx
  jg     L2
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heap_sort(int *A, int size) {
  int j;
  heapify(A, size);
  j = size - 1;
  while (j > 0) {
    {
      int tmp;
      tmp = (A[0]);
      (A[0]) = (A[j]);
      (A[j]) = tmp;
    };
    j = j - 1;
    sift_down_iterative(A, 0, j);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x8,%rsp
  call   <heapify@plt>
  test   %ebx,%ebx
  jle    L13
  movslq %ebx,%rbx
  xchg   %ax,%ax
L14:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%rbp),%eax
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp)
  lea    -0x1(%rbx),%edx
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <sift_down_iterative@plt>
  test   %ebx,%ebx
  jg     L14
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heap_sort(int *A, int size) {
  int j;
  heapify(A, size);
  j = size - 1;
  while (j > 0) {
    {
      int tmp;
      tmp = (A[0]);
      (A[0]) = (A[j]);
      (A[j]) = tmp;
    };
    j = j - 1;
    sift_down_iterative(A, 0, j);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L12
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D2: Enter two numbeers

tool: D15: %d %d 

tool: D5: %d is multiple of %d

assistant: ```c
int main() {
  int m, n, p;
  printf("Enter two numbeers");
  scanf("%d %d ", &m, &n);
  p = n / m;
  if ((p * m) == n) {
    printf("%d is multiple of %d", m, n);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  imul   %esi,%eax
  cmp    %eax,%ecx
  je     L6
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  mov    %ecx,%edx
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L10
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D0
type: string

tool: D10: Enter two numbeers

tool: D9: %d %d 

tool: D0: %d is multiple of %d

assistant: ```c
int main() {
  int m, n, p;
  printf("Enter two numbeers");
  scanf("%d %d ", &m, &n);
  p = n / m;
  if ((p * m) == n) {
    printf("%d is multiple of %d", m, n);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  mov    (%rsp),%esi
  mov    %r8d,%eax
  cltd
  idiv   %esi
  imul   %esi,%eax
  cmp    %eax,%r8d
  je     L14
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  mov    %r8d,%edx
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L19
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D24
datatype: string

tool: D4: Enter two numbeers

tool: D7: %d %d 

tool: D24: %d is multiple of %d

assistant: ```c
int main() {
  int m, n, p;
  printf("Enter two numbeers");
  scanf("%d %d ", &m, &n);
  p = n / m;
  if ((p * m) == n) {
    printf("%d is multiple of %d", m, n);
  }
  return 0;
}
```