ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  xor    %esi,%esi
  mov    $0xffffffff,%r8d
  push   %r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D44(%rip),%r15
  mov    D40(%rip),%r14
  mov    D22(%rip),%r13
  mov    D16(%rip),%r12
  mov    (%r15),%ecx
  or     (%r14),%ecx
  mov    0x0(%r13),%edx
  or     (%r12),%edx
  call   <mmap@plt>
  mov    D27(%rip),%rbp
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  xor    %edi,%edi
  mov    (%r15),%ecx
  mov    0x0(%r13),%edx
  mov    $0x1000,%esi
  or     (%r14),%ecx
  or     (%r12),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  setne  %dil
  mov    %rax,%rbx
  call   <assert@plt>
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  xor    %edi,%edi
  mov    (%r15),%ecx
  mov    0x0(%r13),%edx
  mov    $0xa000,%esi
  or     (%r14),%ecx
  or     (%r12),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x9000(%rbx),%rdi
  mov    $0x1000,%esi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x2000(%rbx),%r10
  mov    $0x1000,%esi
  mov    %r10,%rdi
  mov    %r10,0x8(%rsp)
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rdi
  xor    %r9d,%r9d
  mov    (%r15),%ecx
  mov    $0xffffffff,%r8d
  or     (%r14),%ecx
  mov    0x0(%r13),%edx
  mov    $0x1000,%esi
  or     (%r12),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  setne  %dil
  call   <assert@plt>
  lea    0x1000(%rbx),%rdi
  mov    $0x8000,%esi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int main() {
  int ret;
  void *alloc = mmap(NULL, 0, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc == MAP_FAILED);
  alloc = mmap(NULL, 4096, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc != MAP_FAILED);
  ret = munmap(alloc, 4096);
  assert(ret == 0);
  alloc = mmap(NULL, 4096 * 10, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc != MAP_FAILED);
  ret = munmap(alloc, 4096);
  assert(ret == 0);
  alloc += 4096;
  ret = munmap(alloc + 4096 * 8, 4096);
  assert(ret == 0);
  ret = munmap(alloc + 4096, 4096);
  assert(ret == 0);
  void *alloc2 = mmap(alloc + 4096, 4096, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc2 != MAP_FAILED);
  ret = munmap(alloc, 4096 * 8);
  assert(ret == 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  xor    %esi,%esi
  mov    $0xffffffff,%r8d
  push   %r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D31(%rip),%r15
  mov    D22(%rip),%r14
  mov    D12(%rip),%r13
  mov    D39(%rip),%r12
  mov    (%r15),%ecx
  or     (%r14),%ecx
  mov    0x0(%r13),%edx
  or     (%r12),%edx
  call   <mmap@plt>
  mov    D47(%rip),%rbp
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  xor    %edi,%edi
  mov    (%r15),%ecx
  mov    0x0(%r13),%edx
  mov    $0x1000,%esi
  or     (%r14),%ecx
  or     (%r12),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  setne  %dil
  mov    %rax,%rbx
  call   <assert@plt>
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  xor    %edi,%edi
  mov    (%r15),%ecx
  mov    0x0(%r13),%edx
  mov    $0xa000,%esi
  or     (%r14),%ecx
  or     (%r12),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x9000(%rbx),%rdi
  mov    $0x1000,%esi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x2000(%rbx),%r10
  mov    $0x1000,%esi
  mov    %r10,%rdi
  mov    %r10,0x8(%rsp)
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rdi
  xor    %r9d,%r9d
  mov    (%r15),%ecx
  mov    $0xffffffff,%r8d
  or     (%r14),%ecx
  mov    0x0(%r13),%edx
  mov    $0x1000,%esi
  or     (%r12),%edx
  call   <mmap@plt>
  xor    %edi,%edi
  cmp    %rax,0x0(%rbp)
  setne  %dil
  call   <assert@plt>
  lea    0x1000(%rbx),%rdi
  mov    $0x8000,%esi
  call   <munmap@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int main() {
  int ret;
  void *alloc = mmap(NULL, 0, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc == MAP_FAILED);
  alloc = mmap(NULL, 4096, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc != MAP_FAILED);
  ret = munmap(alloc, 4096);
  assert(ret == 0);
  alloc = mmap(NULL, 4096 * 10, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc != MAP_FAILED);
  ret = munmap(alloc, 4096);
  assert(ret == 0);
  alloc += 4096;
  ret = munmap(alloc + 4096 * 8, 4096);
  assert(ret == 0);
  ret = munmap(alloc + 4096, 4096);
  assert(ret == 0);
  void *alloc2 = mmap(alloc + 4096, 4096, PROT_EXEC | PROT_READ, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
  assert(alloc2 != MAP_FAILED);
  ret = munmap(alloc, 4096 * 8);
  assert(ret == 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x10,-0xc(%rbp)
  jle    L29
  movl   $0x10,-0xc(%rbp)
  jmp    L29
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6:  %02x

assistant: ```c
void printd(data, cnt) const unsigned char *data;
int cnt;
{
  if (cnt > 16)
    cnt = 16;
  while (cnt-- > 0) {
    printf(" %02x", *data);
    ++data;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%ebp
  cmp    %ebp,%esi
  cmovle %esi,%ebp
  test   %esi,%esi
  jle    L17
  mov    %rdi,%r12
  mov    %rdi,%rbx
  lea    D5(%rip),%r13
L7:
  movzbl (%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  lea    0x0(%rbp,%r12,1),%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L7
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D5:  %02x

assistant: ```c
void printd(data, cnt) const unsigned char *data;
int cnt;
{
  if (cnt > 16)
    cnt = 16;
  while (cnt-- > 0) {
    printf(" %02x", *data);
    ++data;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printd>:
  endbr64
  mov    $0x10,%eax
  cmp    %eax,%esi
  cmovle %esi,%eax
  test   %esi,%esi
  jle    L10
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    (%rax,%rdi,1),%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    %ebp,%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3:  %02x

assistant: ```c
void printd(data, cnt) const unsigned char *data;
int cnt;
{
  if (cnt > 16)
    cnt = 16;
  while (cnt-- > 0) {
    printf(" %02x", *data);
    ++data;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printd>:
  endbr64
  mov    $0x10,%eax
  cmp    %eax,%esi
  cmovle %esi,%eax
  test   %esi,%esi
  jle    L6
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    (%rax,%rdi,1),%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    %ebp,%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4:  %02x

assistant: ```c
void printd(data, cnt) const unsigned char *data;
int cnt;
{
  if (cnt > 16)
    cnt = 16;
  while (cnt-- > 0) {
    printf(" %02x", *data);
    ++data;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<make_assignment_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x1,-0x18(%rbp)
  cmpq   $0x9,-0x28(%rbp)
  jbe    L17
  movq   $0x2,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L21
L26:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: arg%llu

assistant: ```c
char *make_assignment_name(size_t idx) {
  const unsigned long long int idx_llu = idx;
  char *arg = NULL;
  size_t numbers = 1;
  if (9 < idx) {
    numbers = 2;
  }
  arg = malloc(numbers + strlen("arg") + 1);
  if (NULL == arg) {
    return NULL;
  }
  sprintf(arg, "arg%llu", idx_llu);
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<make_assignment_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmp    $0x9,%rdi
  seta   %dil
  movzbl %dil,%edi
  add    $0x5,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: arg%llu

assistant: ```c
char *make_assignment_name(size_t idx) {
  const unsigned long long int idx_llu = idx;
  char *arg = NULL;
  size_t numbers = 1;
  if (9 < idx) {
    numbers = 2;
  }
  arg = malloc(numbers + strlen("arg") + 1);
  if (NULL == arg) {
    return NULL;
  }
  sprintf(arg, "arg%llu", idx_llu);
  return arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<make_assignment_name>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  cmp    $0x9,%rdi
  seta   %dil
  movzbl %dil,%edi
  add    $0x5,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: arg%llu

assistant: ```c
char *make_assignment_name(size_t idx) {
  const unsigned long long int idx_llu = idx;
  char *arg = NULL;
  size_t numbers = 1;
  if (9 < idx) {
    numbers = 2;
  }
  arg = malloc(numbers + strlen("arg") + 1);
  if (NULL == arg) {
    return NULL;
  }
  sprintf(arg, "arg%llu", idx_llu);
  return arg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_assignment_name>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  cmp    $0x9,%rdi
  seta   %dil
  movzbl %dil,%edi
  add    $0x5,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: arg%llu

assistant: ```c
char *make_assignment_name(size_t idx) {
  const unsigned long long int idx_llu = idx;
  char *arg = NULL;
  size_t numbers = 1;
  if (9 < idx) {
    numbers = 2;
  }
  arg = malloc(numbers + strlen("arg") + 1);
  if (NULL == arg) {
    return NULL;
  }
  sprintf(arg, "arg%llu", idx_llu);
  return arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getFibonacciNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L0
  mov    $0x1,%eax
  jmp    L15
L8:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L8
  mov    -0x8(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int getFibonacciNumber(int n) {
  int first = 1, second = 1, result = 0, i = 0;
  if (n <= 2) {
    return 1;
  }
  for (; i < n - 2; ++i) {
    result = first + second;
    first = second;
    second = result;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getFibonacciNumber>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jle    L9
  sub    $0x2,%edi
  mov    $0x0,%edx
  mov    $0x1,%ecx
L13:
  mov    %eax,%esi
  add    %ecx,%eax
  add    $0x1,%edx
  mov    %esi,%ecx
  cmp    %edx,%edi
  jne    L13
L9:
  ret
```

assistant: ```c
int getFibonacciNumber(int n) {
  int first = 1, second = 1, result = 0, i = 0;
  if (n <= 2) {
    return 1;
  }
  for (; i < n - 2; ++i) {
    result = first + second;
    first = second;
    second = result;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getFibonacciNumber>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jle    L1
  sub    $0x2,%edi
  xor    %edx,%edx
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %eax,%esi
  add    $0x1,%edx
  add    %ecx,%eax
  mov    %esi,%ecx
  cmp    %edi,%edx
  jne    L11
L1:
  ret
```

assistant: ```c
int getFibonacciNumber(int n) {
  int first = 1, second = 1, result = 0, i = 0;
  if (n <= 2) {
    return 1;
  }
  for (; i < n - 2; ++i) {
    result = first + second;
    first = second;
    second = result;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getFibonacciNumber>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jle    L15
  sub    $0x2,%edi
  xor    %edx,%edx
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %eax,%esi
  add    $0x1,%edx
  add    %ecx,%eax
  mov    %esi,%ecx
  cmp    %edi,%edx
  jne    L18
L15:
  ret
```

assistant: ```c
int getFibonacciNumber(int n) {
  int first = 1, second = 1, result = 0, i = 0;
  if (n <= 2) {
    return 1;
  }
  for (; i < n - 2; ++i) {
    result = first + second;
    first = second;
    second = result;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpb   $0x0,-0x1c(%rbp)
  jne    L33
  mov    -0xc(%rbp),%eax
  jmp    L58
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L48
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  addq   $0x1,-0x8(%rbp)
  jmp    L44
L42:
  nop
  addl   $0x1,-0xc(%rbp)
  subq   $0x1,-0x18(%rbp)
L48:
  addq   $0x1,-0x18(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0xc(%rbp),%eax
L58:
  pop    %rbp
  ret
```

assistant: ```c
int Delete(char *String, char From) {
  int Deleted = 0;
  char *c;
  if (From == '\0')
    return (Deleted);
  for (; *String != '\0'; String++)
    if (*String == From) {
      c = String;
      for (;; c++) {
        *c = *(c + 1);
        if (*c == '\0')
          break;
      }
      Deleted++;
      String--;
    }
  return (Deleted);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Delete>:
  endbr64
  mov    %esi,%ecx
  mov    $0x0,%r8d
  test   %sil,%sil
  je     L51
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%r8d
L51:
  mov    %r8d,%eax
  ret
L19:
  add    $0x1,%r8d
  lea    -0x1(%rdi),%rdx
L1:
  lea    0x1(%rdx),%rdi
  movzbl 0x1(%rdx),%eax
  test   %al,%al
  je     L51
L33:
  mov    %rdi,%rdx
  cmp    %al,%cl
  jne    L1
  movzbl 0x1(%rdi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L19
  mov    %rdi,%rax
L9:
  add    $0x1,%rax
  movzbl 0x1(%rax),%edx
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L9
  jmp    L19
```

assistant: ```c
int Delete(char *String, char From) {
  int Deleted = 0;
  char *c;
  if (From == '\0')
    return (Deleted);
  for (; *String != '\0'; String++)
    if (*String == From) {
      c = String;
      for (;; c++) {
        *c = *(c + 1);
        if (*c == '\0')
          break;
      }
      Deleted++;
      String--;
    }
  return (Deleted);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Delete>:
  endbr64
  mov    %esi,%ecx
  xor    %r8d,%r8d
  test   %sil,%sil
  je     L56
  movzbl (%rdi),%eax
L70:
  test   %al,%al
  je     L56
L61:
  movzbl 0x1(%rdi),%edx
  cmp    %al,%cl
  je     L58
  mov    %edx,%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L61
L56:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %dl,(%rdi)
  test   %dl,%dl
  je     L63
  mov    %rdi,%rax
  nopl   0x0(%rax)
L73:
  movzbl 0x2(%rax),%edx
  add    $0x1,%rax
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L73
  movzbl (%rdi),%eax
  add    $0x1,%r8d
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L63:
  add    $0x1,%r8d
  jmp    L56
```

assistant: ```c
int Delete(char *String, char From) {
  int Deleted = 0;
  char *c;
  if (From == '\0')
    return (Deleted);
  for (; *String != '\0'; String++)
    if (*String == From) {
      c = String;
      for (;; c++) {
        *c = *(c + 1);
        if (*c == '\0')
          break;
      }
      Deleted++;
      String--;
    }
  return (Deleted);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Delete>:
  endbr64
  mov    %esi,%ecx
  xor    %r8d,%r8d
  test   %sil,%sil
  je     L26
  movzbl (%rdi),%eax
L21:
  test   %al,%al
  je     L26
L5:
  movzbl 0x1(%rdi),%edx
  cmp    %al,%cl
  je     L16
  mov    %edx,%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L5
L26:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %dl,(%rdi)
  test   %dl,%dl
  je     L42
  mov    %rdi,%rax
  nopl   0x0(%rax)
L25:
  movzbl 0x2(%rax),%edx
  add    $0x1,%rax
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L25
  movzbl (%rdi),%eax
  add    $0x1,%r8d
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x1,%r8d
  jmp    L26
```

assistant: ```c
int Delete(char *String, char From) {
  int Deleted = 0;
  char *c;
  if (From == '\0')
    return (Deleted);
  for (; *String != '\0'; String++)
    if (*String == From) {
      c = String;
      for (;; c++) {
        *c = *(c + 1);
        if (*c == '\0')
          break;
      }
      Deleted++;
      String--;
    }
  return (Deleted);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x80(%rbp)
  movl   $0x0,-0x7c(%rbp)
  mov    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  jmp    L45
L33:
  mov    -0x80(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x74(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x74(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L46
  movl   $0x1,-0x7c(%rbp)
  jmp    L45
L46:
  addl   $0x1,-0x80(%rbp)
L45:
  cmpl   $0x0,-0x7c(%rbp)
  jne    L44
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x74(%rbp),%eax
  cmp    %eax,-0x80(%rbp)
  jle    L33
L44:
  cmpl   $0x0,-0x7c(%rbp)
  je     L48
  mov    -0x80(%rbp),%eax
  mov    %eax,-0x78(%rbp)
  jmp    L72
L48:
  movl   $0xffffffff,-0x78(%rbp)
L72:
  mov    -0x78(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int pos(const char *source, const char *to_find) {
  int i = 0, find_len, found = 0, position;
  char substring[100];
  find_len = strlen(to_find);
  while (!found && i <= strlen(source) - find_len) {
    strncpy(substring, &source[i], find_len);
    substring[find_len] = '\0';
    if (strcmp(substring, to_find) == 0)
      found = 1;
    else
      ++i;
  }
  if (found)
    position = i;
  else
    position = -1;
  return (position);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
  mov    %rsp,%r13
L29:
  mov    %ebx,%r15d
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jl     L18
  lea    (%r12,%rbx,1),%rsi
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rax
  movb   $0x0,(%rsp,%rax,1)
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L29
  jmp    L5
L18:
  mov    $0xffffffff,%r15d
L5:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r15d,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pos(const char *source, const char *to_find) {
  int i = 0, find_len, found = 0, position;
  char substring[100];
  find_len = strlen(to_find);
  while (!found && i <= strlen(source) - find_len) {
    strncpy(substring, &source[i], find_len);
    substring[find_len] = '\0';
    if (strcmp(substring, to_find) == 0)
      found = 1;
    else
      ++i;
  }
  if (found)
    position = i;
  else
    position = -1;
  return (position);
}
```