ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  jle    L1
  nopl   0x0(%rax)
L15:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jg     L15
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int r;
  while (n > 0) {
    r = m % n;
    m = n;
    n = r;
  }
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  jle    L10
  nopl   0x0(%rax)
L5:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jg     L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int r;
  while (n > 0) {
    r = m % n;
    m = n;
    n = r;
  }
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fdevent_socket_nb_cloexec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fdevent_socket_nb_cloexec(int domain, int type, int protocol) {
  int fd;
  if (-1 != (fd = socket(domain, type, protocol))) {
  }
  return fd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fdevent_socket_nb_cloexec>:
  endbr64
  sub    $0x8,%rsp
  call   <socket@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fdevent_socket_nb_cloexec(int domain, int type, int protocol) {
  int fd;
  if (-1 != (fd = socket(domain, type, protocol))) {
  }
  return fd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fdevent_socket_nb_cloexec>:
  endbr64
  jmp    1050 <socket@plt>
```

assistant: ```c
int fdevent_socket_nb_cloexec(int domain, int type, int protocol) {
  int fd;
  if (-1 != (fd = socket(domain, type, protocol))) {
  }
  return fd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fdevent_socket_nb_cloexec>:
  endbr64
  jmp    1050 <socket@plt>
```

assistant: ```c
int fdevent_socket_nb_cloexec(int domain, int type, int protocol) {
  int fd;
  if (-1 != (fd = socket(domain, type, protocol))) {
  }
  return fd;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L20
L54:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L12
  lea    D4(%rip),%rdx
  jmp    L44
L12:
  lea    D1(%rip),%rdx
L44:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L6
  lea    D4(%rip),%rax
  jmp    L11
L6:
  lea    D18(%rip),%rax
L11:
  mov    -0x4(%rbp),%esi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x32,-0x4(%rbp)
  jle    L54
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string

tool: 

tool: D1: Puff

tool: D18: Huff

tool: D7: %d %s %s


assistant: ```c
int main(void) {
  for (int i = 1; i < 51; ++i) {
    printf("%d %s %s\n", i, i % 2 ? "" : "Huff", i % 5 ? "" : "Puff");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D35(%rip),%rcx
  mov    %rcx,%rbp
  lea    D38(%rip),%r13
  lea    D15(%rip),%r12
  lea    D29(%rip),%r14
L2:
  test   $0x1,%bl
  mov    %r13,%rdx
  cmovne %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x33,%ebx
  je     L19
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  mov    %r14,%rcx
  cmovne %rbp,%rcx
  jmp    L2
L19:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string

tool: 

tool: D38: Huff

tool: D15: %d %s %s


tool: D29: Puff

assistant: ```c
int main(void) {
  for (int i = 1; i < 51; ++i) {
    printf("%d %s %s\n", i, i % 2 ? "" : "Huff", i % 5 ? "" : "Puff");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  lea    D5(%rip),%rcx
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L13:
  imul   $0xcccccccd,%ebx,%eax
  mov    %r14,%rcx
  cmp    $0x33333333,%eax
  cmova  %rbp,%rcx
L4:
  test   $0x1,%bl
  mov    %r12,%rdx
  mov    %ebx,%esi
  cmovne %rbp,%rdx
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x33,%ebx
  jne    L13
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D1
data_type: string
name: read_data
arguments: data_label: D6
data_type: string
name: read_data
arguments: data_label: D21
data_type: string

tool: 

tool: D1: Puff

tool: D6: %d %s %s


tool: D21: Huff

assistant: ```c
int main(void) {
  for (int i = 1; i < 51; ++i) {
    printf("%d %s %s\n", i, i % 2 ? "" : "Huff", i % 5 ? "" : "Puff");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  lea    D28(%rip),%rcx
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L9:
  imul   $0xcccccccd,%ebx,%eax
  mov    %r14,%rcx
  cmp    $0x33333333,%eax
  cmova  %rbp,%rcx
L16:
  test   $0x1,%bl
  mov    %r12,%rdx
  mov    %ebx,%esi
  cmovne %rbp,%rdx
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x33,%ebx
  jne    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D25
data_type: string
name: disassemble_data
arguments: data_tag: D15
data_type: string

tool: 

tool: D20: Puff

tool: D25: %d %s %s


tool: D15: Huff

assistant: ```c
int main(void) {
  for (int i = 1; i < 51; ++i) {
    printf("%d %s %s\n", i, i % 2 ? "" : "Huff", i % 5 ? "" : "Puff");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcmpi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
L5:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L10
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
L10:
  mov    -0x14(%rbp),%eax
  jmp    L37
L39:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
  jmp    L5
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcmpi(const char *a, const char *b) {
  for (;; a++, b++) {
    const int d = tolower(*a) - tolower(*b);
    if (d || !*a) {
      return d;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmpi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  jmp    L23
L13:
  add    $0x1,%rbp
  add    $0x1,%r12
L23:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <tolower@plt>
  sub    %eax,%ebx
  jne    L14
  cmpb   $0x0,0x0(%rbp)
  jne    L13
L14:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcmpi(const char *a, const char *b) {
  for (;; a++, b++) {
    const int d = tolower(*a) - tolower(*b);
    if (d || !*a) {
      return d;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcmpi>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L29
L13:
  cmpb   $0x0,0x0(%rbp)
  je     L0
  add    $0x1,%rbp
  add    $0x1,%r12
L29:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  sub    %eax,%ebx
  je     L13
L0:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcmpi(const char *a, const char *b) {
  for (;; a++, b++) {
    const int d = tolower(*a) - tolower(*b);
    if (d || !*a) {
      return d;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmpi>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L19
L20:
  cmpb   $0x0,0x0(%rbp)
  je     L6
  add    $0x1,%rbp
  add    $0x1,%r12
L19:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  sub    %eax,%ebx
  je     L20
L6:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcmpi(const char *a, const char *b) {
  for (;; a++, b++) {
    const int d = tolower(*a) - tolower(*b);
    if (d || !*a) {
      return d;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
L5:
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L5
  movsd  -0x8(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  je     L6
  jmp    L5
L6:
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double overflow(x)
double x;
{
  double y;
  do {
    y = x;
    x *= x;
  } while (y != x);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<overflow>:
  endbr64
L0:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm0
  ucomisd %xmm0,%xmm1
  jp     L0
  jne    L0
  ret
```

assistant: ```c
double overflow(x)
double x;
{
  double y;
  do {
    y = x;
    x *= x;
  } while (y != x);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<overflow>:
  endbr64
  nopl   0x0(%rax)
L7:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm0
  ucomisd %xmm0,%xmm1
  jp     L7
  jne    L7
  ret
```

assistant: ```c
double overflow(x)
double x;
{
  double y;
  do {
    y = x;
    x *= x;
  } while (y != x);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<overflow>:
  endbr64
  nopl   0x0(%rax)
L7:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm0
  ucomisd %xmm0,%xmm1
  jp     L7
  jne    L7
  ret
```

assistant: ```c
double overflow(x)
double x;
{
  double y;
  do {
    y = x;
    x *= x;
  } while (y != x);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    $0xbb8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L75
  mov    $0x0,%eax
  jmp    L8
L75:
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L50:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L61
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L59:
  mov    -0xc(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jb     L59
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  add    %eax,-0x10(%rbp)
  jmp    L70
L61:
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L70:
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jb     L50
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
char *replace(const char *str, const char *what, const char *to) {
  char *result = (char *)malloc(3000);
  unsigned int res_len = 0;
  if (!result)
    return NULL;
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (!strncmp(str + i, what, strlen(what))) {
      for (unsigned int j = 0; j < strlen(to); j++) {
        result[res_len + j] = to[j];
      }
      res_len += strlen(to);
      i += strlen(what) - 1;
    } else {
      result[res_len] = str[i];
      res_len++;
    }
  }
  result[res_len] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    %rdx,%r12
  mov    $0xbb8,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%r14
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L43
L66:
  mov    %ebx,%eax
  movzbl (%r12,%rax,1),%edx
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %dl,(%r14,%rax,1)
  add    $0x1,%ebx
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L66
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %eax,%ebp
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    -0x1(%r13,%rax,1),%r13d
L59:
  add    $0x1,%r13d
L43:
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jbe    L35
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r13d,%ebx
  add    0x8(%rsp),%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L39
  movzbl (%rbx),%edx
  mov    %ebp,%eax
  mov    %dl,(%r14,%rax,1)
  add    $0x1,%ebp
  jmp    L59
L39:
  mov    $0x0,%ebx
  jmp    L1
L35:
  mov    %ebp,%ebp
  movb   $0x0,(%r14,%rbp,1)
L72:
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    $0x0,%r14d
  jmp    L72
```

assistant: ```c
char *replace(const char *str, const char *what, const char *to) {
  char *result = (char *)malloc(3000);
  unsigned int res_len = 0;
  if (!result)
    return NULL;
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (!strncmp(str + i, what, strlen(what))) {
      for (unsigned int j = 0; j < strlen(to); j++) {
        result[res_len + j] = to[j];
      }
      res_len += strlen(to);
      i += strlen(what) - 1;
    } else {
      result[res_len] = str[i];
      res_len++;
    }
  }
  result[res_len] = '\0';
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    $0xbb8,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L36
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L11
  nopl   0x0(%rax)
L65:
  movzbl (%rcx),%edx
  mov    %ebx,%eax
  add    $0x1,%ebx
  mov    %dl,0x0(%r13,%rax,1)
L44:
  add    $0x1,%r12d
L11:
  mov    (%rsp),%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jbe    L5
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r12d,%ecx
  add    (%rsp),%rcx
  mov    %r14,%rsi
  mov    %rcx,%rdi
  mov    %eax,%edx
  mov    %rcx,0x8(%rsp)
  call   <strncmp@plt>
  mov    0x8(%rsp),%rcx
  test   %eax,%eax
  jne    L65
  xor    %r15d,%r15d
  jmp    L46
  xchg   %ax,%ax
L69:
  mov    %r15d,%eax
  movzbl 0x0(%rbp,%rax,1),%ecx
  lea    (%rbx,%r15,1),%eax
  add    $0x1,%r15d
  mov    %cl,0x0(%r13,%rax,1)
L46:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  ja     L69
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    -0x1(%r12,%rax,1),%r12d
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L5:
  movb   $0x0,0x0(%r13,%rbx,1)
L36:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *replace(const char *str, const char *what, const char *to) {
  char *result = (char *)malloc(3000);
  unsigned int res_len = 0;
  if (!result)
    return NULL;
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (!strncmp(str + i, what, strlen(what))) {
      for (unsigned int j = 0; j < strlen(to); j++) {
        result[res_len + j] = to[j];
      }
      res_len += strlen(to);
      i += strlen(what) - 1;
    } else {
      result[res_len] = str[i];
      res_len++;
    }
  }
  result[res_len] = '\0';
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    $0xbb8,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L55
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L48
  nopl   0x0(%rax)
L54:
  movzbl (%rcx),%edx
  mov    %ebx,%eax
  add    $0x1,%ebx
  mov    %dl,0x0(%r13,%rax,1)
L33:
  add    $0x1,%r12d
L48:
  mov    (%rsp),%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jbe    L61
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r12d,%ecx
  add    (%rsp),%rcx
  mov    %r14,%rsi
  mov    %rcx,%rdi
  mov    %eax,%edx
  mov    %rcx,0x8(%rsp)
  call   <strncmp@plt>
  mov    0x8(%rsp),%rcx
  test   %eax,%eax
  jne    L54
  xor    %r15d,%r15d
  jmp    L24
  xchg   %ax,%ax
L17:
  mov    %r15d,%eax
  movzbl 0x0(%rbp,%rax,1),%ecx
  lea    (%rbx,%r15,1),%eax
  add    $0x1,%r15d
  mov    %cl,0x0(%r13,%rax,1)
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  ja     L17
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    -0x1(%r12,%rax,1),%r12d
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L61:
  movb   $0x0,0x0(%r13,%rbx,1)
L55:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *replace(const char *str, const char *what, const char *to) {
  char *result = (char *)malloc(3000);
  unsigned int res_len = 0;
  if (!result)
    return NULL;
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (!strncmp(str + i, what, strlen(what))) {
      for (unsigned int j = 0; j < strlen(to); j++) {
        result[res_len + j] = to[j];
      }
      res_len += strlen(to);
      i += strlen(what) - 1;
    } else {
      result[res_len] = str[i];
      res_len++;
    }
  }
  result[res_len] = '\0';
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kill_and_wait_proc_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <kill_proc_fn@plt>
  test   %rax,%rax
  je     L30
  mov    $0xffffffff,%eax
  jmp    L19
L30:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <wait_proc_fn@plt>
  test   %rax,%rax
  je     L14
  mov    $0xfffffffe,%eax
  jmp    L19
L14:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int kill_and_wait_proc_fn(int id, int sgnl, const char *id_str) {
  if (kill_proc_fn(id, sgnl, id_str) != 0) {
    return -1;
  }
  if (wait_proc_fn(id, id_str) != 0) {
    return -2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kill_and_wait_proc_fn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rdx,%rbp
  call   <kill_proc_fn@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <wait_proc_fn@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0xfffffffe,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int kill_and_wait_proc_fn(int id, int sgnl, const char *id_str) {
  if (kill_proc_fn(id, sgnl, id_str) != 0) {
    return -1;
  }
  if (wait_proc_fn(id, id_str) != 0) {
    return -2;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kill_and_wait_proc_fn>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <kill_proc_fn@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <wait_proc_fn@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0xfffffffe,%eax
L19:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int kill_and_wait_proc_fn(int id, int sgnl, const char *id_str) {
  if (kill_proc_fn(id, sgnl, id_str) != 0) {
    return -1;
  }
  if (wait_proc_fn(id, id_str) != 0) {
    return -2;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kill_and_wait_proc_fn>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <kill_proc_fn@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <wait_proc_fn@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0xfffffffe,%eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int kill_and_wait_proc_fn(int id, int sgnl, const char *id_str) {
  if (kill_proc_fn(id, sgnl, id_str) != 0) {
    return -1;
  }
  if (wait_proc_fn(id, id_str) != 0) {
    return -2;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vetor_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vetor_copy(int v[], int vetor_aux[], int n) {
  int x;
  int z = 0;
  for (x = 0; x < n; x++) {
    vetor_aux[z] = *(v + x);
    z++;
  }
}
```