ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_memfuncs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <__builtin_bzero@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <__builtin_memcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_memcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <__builtin_memmove@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_memmove@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <__builtin_mempcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_mempcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <__builtin_memset@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_memfuncs(void *s, unsigned n) {
  __builtin_bzero(null(), n);
  sink(0, __builtin_memcpy(null(), s, n));
  sink(0, __builtin_memcpy(s, null(), n));
  sink(0, __builtin_memmove(null(), s, n));
  sink(0, __builtin_memmove(s, null(), n));
  sink(0, __builtin_mempcpy(null(), s, n));
  sink(0, __builtin_mempcpy(s, null(), n));
  sink(0, __builtin_memset(null(), 0, n));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_memfuncs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <__builtin_bzero@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <__builtin_memcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <__builtin_memcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <__builtin_memmove@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <__builtin_memmove@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <__builtin_mempcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <__builtin_mempcpy@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%edx
  mov    $0x0,%esi
  call   <__builtin_memset@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test_memfuncs(void *s, unsigned n) {
  __builtin_bzero(null(), n);
  sink(0, __builtin_memcpy(null(), s, n));
  sink(0, __builtin_memcpy(s, null(), n));
  sink(0, __builtin_memmove(null(), s, n));
  sink(0, __builtin_memmove(s, null(), n));
  sink(0, __builtin_mempcpy(null(), s, n));
  sink(0, __builtin_mempcpy(s, null(), n));
  sink(0, __builtin_memset(null(), 0, n));
}
```
user: What is the c source code of the assembly code below?

```asm
<test_memfuncs>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <null@plt>
  mov    %r12d,%esi
  mov    %rax,%rdi
  call   <__builtin_bzero@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin_memcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin_memcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin_memmove@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin_memmove@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin_mempcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin_mempcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <__builtin_memset@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1100 <sink@plt>
```

assistant: ```c
void test_memfuncs(void *s, unsigned n) {
  __builtin_bzero(null(), n);
  sink(0, __builtin_memcpy(null(), s, n));
  sink(0, __builtin_memcpy(s, null(), n));
  sink(0, __builtin_memmove(null(), s, n));
  sink(0, __builtin_memmove(s, null(), n));
  sink(0, __builtin_mempcpy(null(), s, n));
  sink(0, __builtin_mempcpy(s, null(), n));
  sink(0, __builtin_memset(null(), 0, n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_memfuncs>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <null@plt>
  mov    %r12d,%esi
  mov    %rax,%rdi
  call   <__builtin_bzero@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin_memcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin_memcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin_memmove@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin_memmove@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin_mempcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin_mempcpy@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <__builtin_memset@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1100 <sink@plt>
```

assistant: ```c
void test_memfuncs(void *s, unsigned n) {
  __builtin_bzero(null(), n);
  sink(0, __builtin_memcpy(null(), s, n));
  sink(0, __builtin_memcpy(s, null(), n));
  sink(0, __builtin_memmove(null(), s, n));
  sink(0, __builtin_memmove(s, null(), n));
  sink(0, __builtin_mempcpy(null(), s, n));
  sink(0, __builtin_mempcpy(s, null(), n));
  sink(0, __builtin_memset(null(), 0, n));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotateL_fun_llong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  jmp    L15
L1:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    $0x3f,%eax
  sub    -0xc(%rbp),%eax
  movabs $0x7fffffffffffffff,%rdx
  mov    %rdx,%rdi
  mov    %eax,%ecx
  sar    %cl,%rdi
  mov    $0x40,%eax
  sub    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  and    %rdi,%rax
  or     %rsi,%rax
L15:
  pop    %rbp
  ret
```

assistant: ```c
long long rotateL_fun_llong(long long x, int i) {
  if ((i %= 64) == 0)
    return x;
  return (x << i) | ((0x7fffffffffffffffll >> (63 - i)) & (x >> (64 - i)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotateL_fun_llong>:
  endbr64
  mov    %rdi,%rdx
  mov    %rdi,%rax
  test   $0x3f,%sil
  je     L3
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rsi,%rax,1),%edi
  and    $0x3f,%edi
  sub    %eax,%edi
  mov    $0x3f,%ecx
  sub    %edi,%ecx
  movabs $0x7fffffffffffffff,%rax
  sar    %cl,%rax
  mov    $0x40,%ecx
  sub    %edi,%ecx
  mov    %rdx,%rdi
  sar    %cl,%rdi
  and    %rdi,%rax
  mov    %esi,%ecx
  shl    %cl,%rdx
  or     %rdx,%rax
L3:
  ret
```

assistant: ```c
long long rotateL_fun_llong(long long x, int i) {
  if ((i %= 64) == 0)
    return x;
  return (x << i) | ((0x7fffffffffffffffll >> (63 - i)) & (x >> (64 - i)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rotateL_fun_llong>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%edi
  and    $0x3f,%edi
  je     L1
  mov    %esi,%edx
  mov    $0x3f,%ecx
  sar    $0x1f,%edx
  shr    $0x1a,%edx
  add    %edx,%esi
  and    $0x3f,%esi
  sub    %edx,%esi
  movabs $0x7fffffffffffffff,%rdx
  sub    %esi,%ecx
  sar    %cl,%rdx
  mov    $0x40,%ecx
  sub    %esi,%ecx
  mov    %rax,%rsi
  sar    %cl,%rsi
  mov    %edi,%ecx
  and    %rsi,%rdx
  shl    %cl,%rax
  or     %rdx,%rax
L1:
  ret
```

assistant: ```c
long long rotateL_fun_llong(long long x, int i) {
  if ((i %= 64) == 0)
    return x;
  return (x << i) | ((0x7fffffffffffffffll >> (63 - i)) & (x >> (64 - i)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotateL_fun_llong>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%edi
  and    $0x3f,%edi
  je     L9
  mov    %esi,%edx
  mov    $0x3f,%ecx
  sar    $0x1f,%edx
  shr    $0x1a,%edx
  add    %edx,%esi
  and    $0x3f,%esi
  sub    %edx,%esi
  movabs $0x7fffffffffffffff,%rdx
  sub    %esi,%ecx
  sar    %cl,%rdx
  mov    $0x40,%ecx
  sub    %esi,%ecx
  mov    %rax,%rsi
  sar    %cl,%rsi
  mov    %edi,%ecx
  and    %rsi,%rdx
  shl    %cl,%rax
  or     %rdx,%rax
L9:
  ret
```

assistant: ```c
long long rotateL_fun_llong(long long x, int i) {
  if ((i %= 64) == 0)
    return x;
  return (x << i) | ((0x7fffffffffffffffll >> (63 - i)) & (x >> (64 - i)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<postProcess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <checkFcnSanity@plt>
  mov    $0x0,%eax
  call   <fixupFcnCalls@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void postProcess(void) {
  checkFcnSanity();
  fixupFcnCalls();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<postProcess>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <checkFcnSanity@plt>
  mov    $0x0,%eax
  call   <fixupFcnCalls@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void postProcess(void) {
  checkFcnSanity();
  fixupFcnCalls();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<postProcess>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <checkFcnSanity@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <fixupFcnCalls@plt>
```

assistant: ```c
void postProcess(void) {
  checkFcnSanity();
  fixupFcnCalls();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<postProcess>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <checkFcnSanity@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <fixupFcnCalls@plt>
```

assistant: ```c
void postProcess(void) {
  checkFcnSanity();
  fixupFcnCalls();
}
```
user: What is the c source code of the assembly code below:

```asm
<add2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L8
  mov    $0x1,%eax
  jmp    L12
L8:
  mov    -0x18(%rbp),%eax
  lea    0x2(%rax),%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <add1@plt>
  add    %ebx,%eax
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int add2(int n, int m) {
  if (n < 1)
    return 1;
  return 2 + m + add1(n - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add2>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L2
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%edi
  call   <add1@plt>
  lea    0x2(%rbx,%rax,1),%eax
  pop    %rbx
  ret
L2:
  ret
```

assistant: ```c
int add2(int n, int m) {
  if (n < 1)
    return 1;
  return 2 + m + add1(n - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<add2>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %rbx
  sub    $0x1,%edi
  mov    %esi,%ebx
  call   <add1@plt>
  lea    0x2(%rbx,%rax,1),%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add2(int n, int m) {
  if (n < 1)
    return 1;
  return 2 + m + add1(n - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add2>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %rbx
  sub    $0x1,%edi
  mov    %esi,%ebx
  call   <add1@plt>
  lea    0x2(%rbx,%rax,1),%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add2(int n, int m) {
  if (n < 1)
    return 1;
  return 2 + m + add1(n - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_kips>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_kips(int *argc, char ***argv) {
  (void)argc;
  (void)argv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_kips>:
  endbr64
  ret
```

assistant: ```c
void init_kips(int *argc, char ***argv) {
  (void)argc;
  (void)argv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_kips>:
  endbr64
  ret
```

assistant: ```c
void init_kips(int *argc, char ***argv) {
  (void)argc;
  (void)argv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_kips>:
  endbr64
  ret
```

assistant: ```c
void init_kips(int *argc, char ***argv) {
  (void)argc;
  (void)argv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string

tool: D11: %d

tool: D19: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int number;
  scanf("%d", &number);
  printf("%d\n", number);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string

tool: D12: %d

tool: D8: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int number;
  scanf("%d", &number);
  printf("%d\n", number);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string

tool: D1: %d

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int number;
  scanf("%d", &number);
  printf("%d\n", number);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D14: %d

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int number;
  scanf("%d", &number);
  printf("%d\n", number);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mult_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L39:
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L15:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L14:
  mov    -0x14(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L14
  mov    -0x14(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mult_matrix(int n, int m, int o, double *a, double *b, double *r) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < o; j++) {
      double sum = 0;
      for (k = 0; k < m; k++)
        sum += (a[i * m + k] * b[k * o + j]);
      r[i * o + j] = sum;
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mult_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x24(%rsp)
  mov    %r8,-0x20(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %edi,%edi
  jle    L88
  mov    %esi,%r10d
  mov    %edx,%r12d
  mov    %rcx,%r13
  movslq %edx,%rsi
  shl    $0x3,%rsi
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  mov    %edx,%r11d
  lea    -0x1(%r10),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x8(%rcx),%rax
  mov    %rax,-0x8(%rsp)
  jmp    L26
L54:
  mov    %r8,%rdx
  mov    %rbx,%rax
  pxor   %xmm1,%xmm1
L10:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L10
L83:
  movsd  %xmm1,(%r9,%rdi,8)
  add    $0x1,%rdi
  add    $0x8,%r8
  cmp    %r11,%rdi
  je     L60
L9:
  pxor   %xmm1,%xmm1
  test   %r10d,%r10d
  jg     L54
  jmp    L83
L60:
  add    $0x1,%ebp
  add    %r12d,%r14d
  add    %r10d,%r15d
  cmp    %ebp,-0x24(%rsp)
  je     L88
L26:
  test   %r12d,%r12d
  jle    L60
  mov    -0x20(%rsp),%r8
  movslq %r15d,%rax
  lea    0x0(%r13,%rax,8),%rbx
  add    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdi
  lea    (%rdi,%rax,8),%rcx
  movslq %r14d,%rax
  mov    -0x18(%rsp),%rdi
  lea    (%rdi,%rax,8),%r9
  mov    $0x0,%edi
  jmp    L9
L88:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mult_matrix(int n, int m, int o, double *a, double *b, double *r) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < o; j++) {
      double sum = 0;
      for (k = 0; k < m; k++)
        sum += (a[i * m + k] * b[k * o + j]);
      r[i * o + j] = sum;
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mult_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x24(%rsp)
  mov    %r8,-0x20(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %edi,%edi
  jle    L65
  mov    %esi,%r10d
  movslq %edx,%rsi
  mov    %edx,%r12d
  mov    %rcx,%r13
  lea    -0x1(%r10),%eax
  shl    $0x3,%rsi
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  mov    %rax,-0x10(%rsp)
  lea    0x8(%rcx),%rax
  xor    %ebp,%ebp
  lea    -0x1(%rdx),%ebx
  mov    %rax,-0x8(%rsp)
  pxor   %xmm2,%xmm2
  nopl   (%rax)
L27:
  test   %r12d,%r12d
  jle    L38
  mov    -0x8(%rsp),%rdi
  movslq %r15d,%rax
  mov    -0x20(%rsp),%r8
  lea    0x0(%r13,%rax,8),%r11
  add    -0x10(%rsp),%rax
  lea    (%rdi,%rax,8),%rcx
  mov    -0x18(%rsp),%rdi
  movslq %r14d,%rax
  lea    (%rdi,%rax,8),%r9
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %r8,%rdx
  mov    %r11,%rax
  movapd %xmm2,%xmm1
  test   %r10d,%r10d
  jle    L42
  nop
L6:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L6
L42:
  movsd  %xmm1,(%r9,%rdi,8)
  lea    0x1(%rdi),%rax
  add    $0x8,%r8
  cmp    %rbx,%rdi
  je     L38
  mov    %rax,%rdi
  jmp    L53
L38:
  add    $0x1,%ebp
  add    %r12d,%r14d
  add    %r10d,%r15d
  cmp    %ebp,-0x24(%rsp)
  jne    L27
L65:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mult_matrix(int n, int m, int o, double *a, double *b, double *r) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < o; j++) {
      double sum = 0;
      for (k = 0; k < m; k++)
        sum += (a[i * m + k] * b[k * o + j]);
      r[i * o + j] = sum;
    }
}
```