ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L22
L27:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L22:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L27
  mov    -0x28(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <producer_consumer_parallel@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D14:  %d %d %d

tool: D16:  %d

assistant: ```c
int main() {
  int nThreads, nIter, n;
  int i;
  scanf(" %d %d %d", &nThreads, &nIter, &n);
  int *buffer = (int *)calloc(n, sizeof(int));
  int *vec = (int *)calloc(nIter, sizeof(int));
  for (i = 0; i < nIter; i++) {
    scanf(" %d", &vec[i]);
  }
  producer_consumer_parallel(buffer, n, vec, nIter, nThreads);
  free(buffer);
  free(vec);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    $0x4,%esi
  mov    0x14(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%r14
  mov    $0x4,%esi
  mov    0x10(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    0x10(%rsp),%ecx
  test   %ecx,%ecx
  jle    L24
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D1(%rip),%r12
L16:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L16
L24:
  mov    0xc(%rsp),%r8d
  mov    %r13,%rdx
  mov    0x14(%rsp),%esi
  mov    %r14,%rdi
  call   <producer_consumer_parallel@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D15:  %d %d %d

tool: D1:  %d

assistant: ```c
int main() {
  int nThreads, nIter, n;
  int i;
  scanf(" %d %d %d", &nThreads, &nIter, &n);
  int *buffer = (int *)calloc(n, sizeof(int));
  int *vec = (int *)calloc(nIter, sizeof(int));
  for (i = 0; i < nIter; i++) {
    scanf(" %d", &vec[i]);
  }
  producer_consumer_parallel(buffer, n, vec, nIter, nThreads);
  free(buffer);
  free(vec);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    0x10(%rsp),%edi
  mov    $0x4,%esi
  mov    %rax,%r14
  call   <calloc@plt>
  mov    0x10(%rsp),%ecx
  mov    %rax,%r13
  test   %ecx,%ecx
  jle    L19
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D14(%rip),%r12
  nopl   0x0(%rax)
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L28
L19:
  mov    0xc(%rsp),%r8d
  mov    0x14(%rsp),%esi
  mov    %r13,%rdx
  mov    %r14,%rdi
  call   <producer_consumer_parallel@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D13:  %d %d %d

tool: D14:  %d

assistant: ```c
int main() {
  int nThreads, nIter, n;
  int i;
  scanf(" %d %d %d", &nThreads, &nIter, &n);
  int *buffer = (int *)calloc(n, sizeof(int));
  int *vec = (int *)calloc(nIter, sizeof(int));
  for (i = 0; i < nIter; i++) {
    scanf(" %d", &vec[i]);
  }
  producer_consumer_parallel(buffer, n, vec, nIter, nThreads);
  free(buffer);
  free(vec);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    0x10(%rsp),%edi
  mov    $0x4,%esi
  mov    %rax,%r14
  call   <calloc@plt>
  mov    0x10(%rsp),%ecx
  mov    %rax,%r13
  test   %ecx,%ecx
  jle    L6
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D5(%rip),%r12
  nopl   0x0(%rax)
L21:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L21
L6:
  mov    0xc(%rsp),%r8d
  mov    0x14(%rsp),%esi
  mov    %r13,%rdx
  mov    %r14,%rdi
  call   <producer_consumer_parallel@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D18:  %d %d %d

tool: D5:  %d

assistant: ```c
int main() {
  int nThreads, nIter, n;
  int i;
  scanf(" %d %d %d", &nThreads, &nIter, &n);
  int *buffer = (int *)calloc(n, sizeof(int));
  int *vec = (int *)calloc(nIter, sizeof(int));
  for (i = 0; i < nIter; i++) {
    scanf(" %d", &vec[i]);
  }
  producer_consumer_parallel(buffer, n, vec, nIter, nThreads);
  free(buffer);
  free(vec);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ht_hash_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L14
  addq   $0x1,-0x8(%rbp)
  jmp    L29
L26:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
L14:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ht_hash_function(const char *skey) {
  const signed char *p = (const signed char *)skey;
  unsigned int h = *p;
  if (h) {
    for (p += 1; *p != '\0'; ++p)
      h = (h << 5) - h + *p;
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ht_hash_function>:
  endbr64
  movsbl (%rdi),%ecx
  test   %ecx,%ecx
  je     L4
  lea    0x1(%rdi),%rsi
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L4
L7:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L7
L4:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int ht_hash_function(const char *skey) {
  const signed char *p = (const signed char *)skey;
  unsigned int h = *p;
  if (h) {
    for (p += 1; *p != '\0'; ++p)
      h = (h << 5) - h + *p;
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ht_hash_function>:
  endbr64
  movsbl (%rdi),%r8d
  test   %r8d,%r8d
  je     L10
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L10
  nopl   0x0(%rax)
L11:
  mov    %r8d,%edx
  add    $0x1,%rcx
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl (%rcx),%eax
  test   %al,%al
  jne    L11
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ht_hash_function(const char *skey) {
  const signed char *p = (const signed char *)skey;
  unsigned int h = *p;
  if (h) {
    for (p += 1; *p != '\0'; ++p)
      h = (h << 5) - h + *p;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ht_hash_function>:
  endbr64
  movsbl (%rdi),%r8d
  test   %r8d,%r8d
  je     L3
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L3
  nopl   0x0(%rax)
L15:
  mov    %r8d,%edx
  add    $0x1,%rcx
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl (%rcx),%eax
  test   %al,%al
  jne    L15
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ht_hash_function(const char *skey) {
  const signed char *p = (const signed char *)skey;
  unsigned int h = *p;
  if (h) {
    for (p += 1; *p != '\0'; ++p)
      h = (h << 5) - h + *p;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<encodeReserved>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L9
  cmpq   $0x0,-0x38(%rbp)
  je     L9
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L77
  mov    -0x8(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  jmp    L73
L139:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L91
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L91
  cmpl   $0x1,-0x14(%rbp)
  jle    L101
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  lea    D9(%rip),%rdx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  subl   $0x2,-0x14(%rbp)
  jmp    L91
L101:
  mov    $0x0,%eax
  jmp    L0
L91:
  addq   $0x1,-0x10(%rbp)
L73:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  cmpl   $0x0,-0x14(%rbp)
  jne    L139
  jmp    L14
L77:
  mov    $0x0,%eax
  jmp    L0
L14:
  mov    -0x30(%rbp),%rax
  jmp    L0
L9:
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D4: -._~

tool: D9: %%%02X

assistant: ```c
char *encodeReserved(const char *pcSrc, char *pcDst, size_t iDstLen) {
  char *s = pcDst;
  size_t iSrcLen;
  int iDiff;
  if (pcDst && iDstLen > 0) {
    if (pcSrc) {
      iSrcLen = strlen(pcSrc);
      iDiff = iDstLen - iSrcLen;
      if (iDiff >= 0) {
        memmove(pcDst, pcSrc, iSrcLen + 1);
        while (*s && iDiff) {
          if (!isalnum((unsigned char)*s) && !strchr("-._~", *s)) {
            if (iDiff >= 2) {
              memmove(s + 3, s + 1, strlen(s + 1) + 1);
              snprintf(s, 3, "%%%02X", (int)*s);
              iDiff -= 2;
            } else {
              return NULL;
            }
          }
          s++;
        }
      } else {
        return NULL;
      }
    }
    return pcDst;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encodeReserved>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L86
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L86
  test   %rdi,%rdi
  je     L103
  call   <strlen@plt>
  sub    %eax,%ebp
  js     L75
  lea    0x1(%rax),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movzbl (%r12),%edi
  test   %ebp,%ebp
  je     L103
  test   %dil,%dil
  je     L103
  mov    %r12,%rbx
  lea    D8(%rip),%r13
  lea    D14(%rip),%r14
  jmp    L20
L74:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %ebp,%ebp
  je     L103
  test   %dil,%dil
  je     L103
L20:
  movzbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L74
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L74
  cmp    $0x1,%ebp
  jle    L93
  lea    0x1(%rbx),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  lea    0x3(%rbx),%rdi
  mov    %r15,%rsi
  call   <memmove@plt>
  movsbl (%rbx),%ecx
  mov    %r14,%rdx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  sub    $0x2,%ebp
  jmp    L74
L86:
  mov    $0x0,%r12d
L103:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    $0x0,%r12d
  jmp    L103
L93:
  mov    $0x0,%r12d
  jmp    L103
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D8: -._~

tool: D14: %%%02X

assistant: ```c
char *encodeReserved(const char *pcSrc, char *pcDst, size_t iDstLen) {
  char *s = pcDst;
  size_t iSrcLen;
  int iDiff;
  if (pcDst && iDstLen > 0) {
    if (pcSrc) {
      iSrcLen = strlen(pcSrc);
      iDiff = iDstLen - iSrcLen;
      if (iDiff >= 0) {
        memmove(pcDst, pcSrc, iSrcLen + 1);
        while (*s && iDiff) {
          if (!isalnum((unsigned char)*s) && !strchr("-._~", *s)) {
            if (iDiff >= 2) {
              memmove(s + 3, s + 1, strlen(s + 1) + 1);
              snprintf(s, 3, "%%%02X", (int)*s);
              iDiff -= 2;
            } else {
              return NULL;
            }
          }
          s++;
        }
      } else {
        return NULL;
      }
    }
    return pcDst;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<encodeReserved>:
  endbr64
  test   %rsi,%rsi
  je     L108
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L127
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L77
  call   <strlen@plt>
  sub    %eax,%ebx
  js     L127
  mov    %rbp,%rdi
  lea    0x1(%rax),%edx
  mov    %r12,%rsi
  call   <memmove@plt>
  movzbl 0x0(%rbp),%edi
  test   %ebx,%ebx
  je     L77
  test   %dil,%dil
  je     L77
  lea    0x1(%rbp),%r15
  lea    D6(%rip),%r13
  lea    D3(%rip),%r14
  jmp    L102
  nopw   0x0(%rax,%rax,1)
L104:
  movzbl (%r15),%edi
  add    $0x1,%r15
  test   %ebx,%ebx
  je     L77
L34:
  test   %dil,%dil
  je     L77
L102:
  lea    -0x1(%r15),%r12
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L104
  movsbl -0x1(%r15),%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L104
  cmp    $0x1,%ebx
  je     L127
  mov    %r15,%rdi
  sub    $0x2,%ebx
  call   <strlen@plt>
  lea    0x2(%r15),%rdi
  mov    %r15,%rsi
  add    $0x1,%r15
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  movsbl -0x2(%r15),%ecx
  mov    %r12,%rdi
  mov    %r14,%rdx
  mov    $0x3,%esi
  call   <snprintf@plt>
  movzbl -0x1(%r15),%edi
  test   %ebx,%ebx
  jne    L34
L77:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L127:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L108:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D6: -._~

tool: D3: %%%02X

assistant: ```c
char *encodeReserved(const char *pcSrc, char *pcDst, size_t iDstLen) {
  char *s = pcDst;
  size_t iSrcLen;
  int iDiff;
  if (pcDst && iDstLen > 0) {
    if (pcSrc) {
      iSrcLen = strlen(pcSrc);
      iDiff = iDstLen - iSrcLen;
      if (iDiff >= 0) {
        memmove(pcDst, pcSrc, iSrcLen + 1);
        while (*s && iDiff) {
          if (!isalnum((unsigned char)*s) && !strchr("-._~", *s)) {
            if (iDiff >= 2) {
              memmove(s + 3, s + 1, strlen(s + 1) + 1);
              snprintf(s, 3, "%%%02X", (int)*s);
              iDiff -= 2;
            } else {
              return NULL;
            }
          }
          s++;
        }
      } else {
        return NULL;
      }
    }
    return pcDst;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<encodeReserved>:
  endbr64
  test   %rsi,%rsi
  je     L49
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L123
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L56
  call   <strlen@plt>
  sub    %eax,%ebx
  js     L123
  mov    %rbp,%rdi
  lea    0x1(%rax),%edx
  mov    %r12,%rsi
  call   <memmove@plt>
  movzbl 0x0(%rbp),%edi
  test   %ebx,%ebx
  je     L56
  test   %dil,%dil
  je     L56
  lea    0x1(%rbp),%r15
  lea    D0(%rip),%r13
  lea    D13(%rip),%r14
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L70:
  movzbl (%r15),%edi
  add    $0x1,%r15
  test   %ebx,%ebx
  je     L56
L86:
  test   %dil,%dil
  je     L56
L13:
  lea    -0x1(%r15),%r12
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L70
  movsbl -0x1(%r15),%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L70
  cmp    $0x1,%ebx
  je     L123
  mov    %r15,%rdi
  sub    $0x2,%ebx
  call   <strlen@plt>
  lea    0x2(%r15),%rdi
  mov    %r15,%rsi
  add    $0x1,%r15
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  movsbl -0x2(%r15),%ecx
  mov    %r12,%rdi
  mov    %r14,%rdx
  mov    $0x3,%esi
  call   <snprintf@plt>
  movzbl -0x1(%r15),%edi
  test   %ebx,%ebx
  jne    L86
L56:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L123:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D0: -._~

tool: D13: %%%02X

assistant: ```c
char *encodeReserved(const char *pcSrc, char *pcDst, size_t iDstLen) {
  char *s = pcDst;
  size_t iSrcLen;
  int iDiff;
  if (pcDst && iDstLen > 0) {
    if (pcSrc) {
      iSrcLen = strlen(pcSrc);
      iDiff = iDstLen - iSrcLen;
      if (iDiff >= 0) {
        memmove(pcDst, pcSrc, iSrcLen + 1);
        while (*s && iDiff) {
          if (!isalnum((unsigned char)*s) && !strchr("-._~", *s)) {
            if (iDiff >= 2) {
              memmove(s + 3, s + 1, strlen(s + 1) + 1);
              snprintf(s, 3, "%%%02X", (int)*s);
              iDiff -= 2;
            } else {
              return NULL;
            }
          }
          s++;
        }
      } else {
        return NULL;
      }
    }
    return pcDst;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x61,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x41,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x65,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x45,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x69,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x49,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x6f,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x4f,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x75,%al
  je     L109
  movzbl -0x9(%rbp),%eax
  cmp    $0x55,%al
  jne    L75
L109:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L117
L75:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L117:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string

tool: D1: Enter any English Alphabet: 

tool: D35: %c

tool: D16: 
The letter is a Vowel.


tool: D8: 
The letter is a Consonant.


assistant: ```c
int main() {
  char ch;
  printf("Enter any English Alphabet: ");
  scanf("%c", &ch);
  if (ch == 'a' || ch == 'A' || ch == 'e' || ch == 'E' || ch == 'i' || ch == 'I' || ch == 'o' || ch == 'O' || ch == 'u' || ch == 'U') {
    printf("\nThe letter is a Vowel.\n");
  } else {
    printf("\nThe letter is a Consonant.\n");
  }
  return 0;
}
```