ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<QSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rsi,0x30(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %rsi,%rsi
  je     L79
  lea    -0x1(%rdx),%eax
  mov    %rsi,0x10(%rsp)
  mov    %rdx,%r14
  lea    0x8(%rdi,%rax,8),%rax
  mov    %rax,0x28(%rsp)
  lea    -0xb(%rsi),%rax
  mov    %rax,0x38(%rsp)
  nopl   0x0(%rax,%rax,1)
L65:
  mov    0x10(%rsp),%rax
  lea    (%rax,%rax,4),%rcx
  movabs $0x4ec4ec4ec4ec4ec5,%rax
  add    %rcx,%rcx
  mul    %rcx
  shr    $0x2,%rdx
  lea    -0x9(%rdx),%rax
  mov    %rdx,0x10(%rsp)
  cmp    $0x1,%rax
  jbe    L45
  cmp    $0xc,%rcx
  jbe    L61
  mov    0x30(%rsp),%rax
  cmp    $0x19,%rcx
  seta   0x1f(%rsp)
  sub    %rdx,%rax
  mov    %rax,(%rsp)
  je     L94
L31:
  mov    0x10(%rsp),%rsi
  mov    0x20(%rsp),%r13
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  mov    0x28(%rsp),%rbp
  mov    %r15d,0x18(%rsp)
  mov    %r12,%r15
  mov    %r14,%r12
  imul   %r14,%rsi
  mov    %r13,%r14
  add    %r13,%rsi
  mov    %rbp,%r13
  mov    %rsi,%rbp
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L93:
  add    $0x1,%r15
  add    %r12,%r14
  add    %r12,%rbp
  add    %r12,%r13
  cmp    (%rsp),%r15
  jae    L32
L46:
  mov    0x8(%rsp),%rax
  mov    %r14,%rbx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   *%rax
  test   %eax,%eax
  jle    L93
  mov    %rbp,%r10
  sub    %r14,%r10
  nopl   (%rax)
L117:
  lea    (%rbx,%r10,1),%rax
  mov    (%rbx),%rdx
  mov    %rbx,%rcx
  add    $0x8,%rbx
  mov    (%rax),%rsi
  mov    %rsi,(%rcx)
  mov    %rdx,(%rax)
  cmp    %r13,%rbx
  jne    L117
  movl   $0x1,0x18(%rsp)
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    0x18(%rsp),%r15d
  or     %r15b,0x1f(%rsp)
  mov    %r12,%r14
L94:
  cmpb   $0x0,0x1f(%rsp)
  jne    L65
L79:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    0x38(%rsp),%rax
  movb   $0x1,0x1f(%rsp)
  movq   $0xb,0x10(%rsp)
  mov    %rax,(%rsp)
  test   %rax,%rax
  jne    L31
  jmp    L65
  nopl   (%rax)
L61:
  mov    0x30(%rsp),%rax
  sub    $0x1,%rax
  mov    %rax,(%rsp)
  je     L79
  movb   $0x0,0x1f(%rsp)
  movq   $0x1,0x10(%rsp)
  jmp    L31
```

assistant: ```c
void QSort(void *base, size_t members, size_t size, int (*compar)(const void *, const void *)) {
  size_t i, j;
  size_t gap = members;
  uintptr_t p1, p2;
  bool worked;
  if (!members) {
    return;
  }
  do {
    gap = (gap * 10) / 13;
    if (gap == 9 || gap == 10) {
      gap = 11;
    } else if (gap < 1) {
      gap = 1;
    }
    worked = false;
    for (i = 0, p1 = (uintptr_t)base; i < members - gap; i++, p1 += size) {
      j = i + gap;
      p2 = (uintptr_t)base + j * size;
      if (compar((void *)p1, (void *)p2) > 0) {
        int k = size;
        uint8_t tmp;
        uint8_t *tp1;
        uint8_t *tp2;
        tp1 = (uint8_t *)p1;
        tp2 = (uint8_t *)p2;
        do {
          tmp = *tp1;
          *tp1++ = *tp2;
          *tp2++ = tmp;
        } while (--k);
        worked = true;
      }
    }
  } while (gap > 1 || worked);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_file_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  nop
L55:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L55
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  nop
L92:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L98
  cmpl   $0x0,-0x18(%rbp)
  jg     L92
L98:
  cmpl   $0x0,-0x18(%rbp)
  jne    L21
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L21:
  addl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L94
L81:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L94:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L81
  mov    -0x30(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L24
  mov    $0x1,%eax
  jmp    L87
L24:
  mov    -0x30(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L9
  mov    $0x2,%eax
  jmp    L87
L9:
  mov    $0x0,%eax
L87:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D10: .csv

tool: D14: .fmm

assistant: ```c
int get_file_ext(char *filename, char *ext) {
  int i = 0, full_len = 0, len = 0;
  while (filename[len++] != '\0')
    ;
  full_len = len;
  while (filename[len--] != '.' && len > 0)
    ;
  if (len == 0)
    len = full_len;
  ++len;
  for (i = 0; len < full_len; i++, len++)
    ext[i] = tolower(filename[len]);
  if (!strcmp(ext, ".csv"))
    return (1);
  if (!strcmp(ext, ".fmm"))
    return (2);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_file_ext>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdi,%rax
  mov    $0x0,%edx
L25:
  mov    %edx,%r8d
  add    $0x1,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L25
  movslq %r8d,%rax
L26:
  mov    %eax,%r9d
  cmpb   $0x2e,0x1(%rdi,%rax,1)
  setne  %sil
  test   %eax,%eax
  setg   %cl
  sub    $0x1,%rax
  test   %cl,%sil
  jne    L26
  test   %r9d,%r9d
  cmove  %edx,%r9d
  lea    0x1(%r9),%eax
  cmp    %r9d,%r8d
  jle    L14
  cltq
  lea    (%rdi,%rax,1),%rbx
  mov    %r12,%rbp
  sub    $0x1,%r8d
  sub    %r9d,%r8d
  lea    0x1(%r12,%r8,1),%r13
L48:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L48
L14:
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L30
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string
name: extract_symbolic_data
arguments: label: D18
type: string

tool: D2: .csv

tool: D18: .fmm

assistant: ```c
int get_file_ext(char *filename, char *ext) {
  int i = 0, full_len = 0, len = 0;
  while (filename[len++] != '\0')
    ;
  full_len = len;
  while (filename[len--] != '.' && len > 0)
    ;
  if (len == 0)
    len = full_len;
  ++len;
  for (i = 0; len < full_len; i++, len++)
    ext[i] = tolower(filename[len]);
  if (!strcmp(ext, ".csv"))
    return (1);
  if (!strcmp(ext, ".fmm"))
    return (2);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_file_ext>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  xor    %edx,%edx
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  mov    %edx,%r13d
  add    $0x1,%edx
  cmpb   $0x0,-0x1(%rax)
  jne    L19
  movslq %edx,%rcx
  mov    %edx,%eax
  add    %rbp,%rcx
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L42:
  sub    $0x1,%rcx
  test   %eax,%eax
  je     L79
L41:
  mov    %eax,%ebx
  sub    $0x1,%eax
  cmpb   $0x2e,(%rcx)
  jne    L42
  test   %eax,%eax
  je     L79
L6:
  movslq %ebx,%rbx
  mov    %r12,%r14
  sub    %rbx,%r14
  cmp    %eax,%r13d
  jle    L49
  nopl   0x0(%rax)
L86:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  lea    -0x1(%rbx),%eax
  cmp    %eax,%r13d
  jg     L86
L49:
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L71
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L71:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L79:
  lea    0x2(%r13),%ebx
  mov    %edx,%eax
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D4: .csv

tool: D2: .fmm

assistant: ```c
int get_file_ext(char *filename, char *ext) {
  int i = 0, full_len = 0, len = 0;
  while (filename[len++] != '\0')
    ;
  full_len = len;
  while (filename[len--] != '.' && len > 0)
    ;
  if (len == 0)
    len = full_len;
  ++len;
  for (i = 0; len < full_len; i++, len++)
    ext[i] = tolower(filename[len]);
  if (!strcmp(ext, ".csv"))
    return (1);
  if (!strcmp(ext, ".fmm"))
    return (2);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_file_ext>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  xor    %edx,%edx
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x1,%rax
  mov    %edx,%r13d
  add    $0x1,%edx
  cmpb   $0x0,-0x1(%rax)
  jne    L36
  movslq %edx,%rcx
  mov    %edx,%eax
  add    %rbp,%rcx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%rcx
  test   %eax,%eax
  je     L47
L26:
  mov    %eax,%ebx
  sub    $0x1,%eax
  cmpb   $0x2e,(%rcx)
  jne    L5
  test   %eax,%eax
  je     L47
L4:
  movslq %ebx,%rbx
  mov    %r12,%r14
  sub    %rbx,%r14
  cmp    %eax,%r13d
  jle    L71
  nopl   0x0(%rax)
L59:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  lea    -0x1(%rbx),%eax
  cmp    %eax,%r13d
  jg     L59
L71:
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L37
  lea    D12(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  lea    0x2(%r13),%ebx
  mov    %edx,%eax
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D12
data_type: string

tool: D8: .csv

tool: D12: .fmm

assistant: ```c
int get_file_ext(char *filename, char *ext) {
  int i = 0, full_len = 0, len = 0;
  while (filename[len++] != '\0')
    ;
  full_len = len;
  while (filename[len--] != '.' && len > 0)
    ;
  if (len == 0)
    len = full_len;
  ++len;
  for (i = 0; len < full_len; i++, len++)
    ext[i] = tolower(filename[len]);
  if (!strcmp(ext, ".csv"))
    return (1);
  if (!strcmp(ext, ".fmm"))
    return (2);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L35:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L1
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L1:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string

tool: D0: 
%f	

tool: D7: %f	

assistant: ```c
void print(float *tal, int size) {
  int i;
  for (i = 0; i < size; i++)
    if ((i) % 10 == 0)
      printf("\n%f\t", tal[i]);
    else
      printf("%f\t", tal[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D1(%rip),%r14
  lea    D7(%rip),%r13
  jmp    L22
L4:
  pxor   %xmm0,%xmm0
  cvtss2sd (%r12,%rbx,4),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L15:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L19
L22:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jne    L4
  pxor   %xmm0,%xmm0
  cvtss2sd (%r12,%rbx,4),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L15
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D1: %f	

tool: D7: 
%f	

assistant: ```c
void print(float *tal, int size) {
  int i;
  for (i = 0; i < size; i++)
    if ((i) % 10 == 0)
      printf("\n%f\t", tal[i]);
    else
      printf("%f\t", tal[i]);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L27
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L15
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  je     L13
L15:
  imul   $0xcccccccd,%ebx,%eax
  movss  0x0(%rbp,%rbx,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  ror    %eax
  cmp    $0x19999999,%eax
  jbe    L3
  mov    %r14,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L15
L13:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D5: %f	

tool: D8: 
%f	

assistant: ```c
void print(float *tal, int size) {
  int i;
  for (i = 0; i < size; i++)
    if ((i) % 10 == 0)
      printf("\n%f\t", tal[i]);
    else
      printf("%f\t", tal[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L27
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopl   0x0(%rax)
L1:
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  je     L14
L16:
  imul   $0xcccccccd,%ebx,%eax
  movss  0x0(%rbp,%rbx,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  ror    %eax
  cmp    $0x19999999,%eax
  jbe    L1
  mov    %r14,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L16
L14:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string

tool: D2: %f	

tool: D13: 
%f	

assistant: ```c
void print(float *tal, int size) {
  int i;
  for (i = 0; i < size; i++)
    if ((i) % 10 == 0)
      printf("\n%f\t", tal[i]);
    else
      printf("%f\t", tal[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<djb2_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L3
L18:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movsbq -0x9(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long djb2_hash(const char *str) {
  unsigned long hash;
  char ch;
  hash = 5381;
  while ((ch = *str++)) {
    hash = ((hash << 5) + hash) + ch;
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<djb2_hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  mov    $0x1505,%eax
L18:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L18
  ret
L7:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned long djb2_hash(const char *str) {
  unsigned long hash;
  char ch;
  hash = 5381;
  while ((ch = *str++)) {
    hash = ((hash << 5) + hash) + ch;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<djb2_hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L13
  nopl   (%rax)
L12:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
unsigned long djb2_hash(const char *str) {
  unsigned long hash;
  char ch;
  hash = 5381;
  while ((ch = *str++)) {
    hash = ((hash << 5) + hash) + ch;
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<djb2_hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L10
  nopl   (%rax)
L18:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
unsigned long djb2_hash(const char *str) {
  unsigned long hash;
  char ch;
  hash = 5381;
  while ((ch = *str++)) {
    hash = ((hash << 5) + hash) + ch;
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xcc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc0(%rbp)
  movl   $0x1,-0xc8(%rbp)
  mov    -0xc0(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0xc4(%rbp)
  jmp    L6
L10:
  mov    -0xc4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%edx
  mov    -0xc8(%rbp),%eax
  add    %eax,%edx
  mov    -0xc4(%rbp),%eax
  cltq
  mov    %edx,-0xc0(%rbp,%rax,4)
  mov    -0xc4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  mov    %eax,-0xc8(%rbp)
  mov    -0xc4(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc4(%rbp)
L6:
  mov    -0xcc(%rbp),%eax
  cmp    %eax,-0xc4(%rbp)
  jl     L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string

tool: D8: %d

tool: D2:  %d

assistant: ```c
int main() {
  int N, F[46], j;
  scanf("%d", &N);
  F[0] = 0;
  j = 1;
  printf("%d", F[0]);
  for (int i = 1; i < (N); i++) {
    F[i] = F[i - 1] + j;
    j = F[i - 1];
    printf(" %d", F[i]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  movl   $0x0,0x10(%rsp)
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L23
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    D7(%rip),%r12
L28:
  mov    0xc(%rsp,%rbx,4),%eax
  lea    0x0(%rbp,%rax,1),%esi
  mov    %esi,0x10(%rsp,%rbx,4)
  mov    %eax,%ebp
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L28
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D12: %d

tool: D7:  %d

assistant: ```c
int main() {
  int N, F[46], j;
  scanf("%d", &N);
  F[0] = 0;
  j = 1;
  printf("%d", F[0]);
  for (int i = 1; i < (N); i++) {
    F[i] = F[i - 1] + j;
    j = F[i - 1];
    printf(" %d", F[i]);
  }
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  movl   $0x0,0x10(%rsp)
  call   <printf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L39
  lea    0x14(%rsp),%rbp
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  mov    $0x1,%r13d
  lea    D18(%rip),%r14
  jmp    L9
  nopl   0x0(%rax)
L31:
  add    $0x4,%rbp
L9:
  add    %r13d,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    -0x4(%rbp),%r13d
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0xc(%rsp)
  jg     L31
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string
name: parse_data
arguments: data_label: D18
type_guessed: string

tool: D1: %d

tool: D18:  %d

assistant: ```c
int main() {
  int N, F[46], j;
  scanf("%d", &N);
  F[0] = 0;
  j = 1;
  printf("%d", F[0]);
  for (int i = 1; i < (N); i++) {
    F[i] = F[i - 1] + j;
    j = F[i - 1];
    printf(" %d", F[i]);
  }
  printf("\n");
  return 0;
}
```