ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jge    L31
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jg     L70
  cmp    %edx,%esi
  jl     L60
L101:
  cmp    %edx,%eax
  jge    L155
  cmp    %edx,%esi
  jle    L155
L104:
  mov    %edx,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L155
L70:
  mov    %eax,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L155
L60:
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L155:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L157:
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jle    L101
  cmp    %edx,%esi
  jl     L104
  jmp    L101
L31:
  jle    L157
  mov    0x14(%rsp),%edx
  cmp    %edx,%esi
  jg     L60
  jge    L155
  cmp    %edx,%eax
  jg     L104
  jmp    L155
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D46
datatype: string
name: retrieve_data
arguments: tag: D44
datatype: string

tool: D2: Please enter 3 numbers separated by spaces > 

tool: D46: %d %d %d

tool: D44: %d is the median


assistant: ```c
int main(void) {
  int int1, int2, int3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d %d %d", &int1, &int2, &int3);
  if (((int1 < int2) && (int1 > int3)) || ((int1 < int2) && (int1 > int3)))
    printf("%d is the median\n", int1);
  else if ((((int2 < int1)) && (int2 > int3)) || ((int2 < int3) && (int2 > int1)))
    printf("%d is the median\n", int2);
  else if (((int3 < int1) && (int3 > int2)) || ((int3 < int2) && (int3 > int1)))
    printf("%d is the median\n", int3);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r9d
  jge    L17
  cmp    %r8d,%r9d
  jg     L37
  cmp    %r8d,%esi
  jl     L78
L28:
  cmp    %r8d,%esi
  jle    L29
  cmp    %r8d,%r9d
  jge    L29
L114:
  mov    %r8d,%esi
L78:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L17:
  jle    L11
  cmp    %r8d,%esi
  jg     L78
  jge    L29
L93:
  cmp    %r8d,%r9d
  jg     L114
  jmp    L29
L37:
  mov    %r9d,%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L29
L11:
  cmp    %r8d,%esi
  jl     L93
  jmp    L28
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D30
type_infered: string
name: read_data
arguments: tag: D0
type_infered: string
name: read_data
arguments: tag: D38
type_infered: string

tool: D30: Please enter 3 numbers separated by spaces > 

tool: D0: %d %d %d

tool: D38: %d is the median


assistant: ```c
int main(void) {
  int int1, int2, int3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d %d %d", &int1, &int2, &int3);
  if (((int1 < int2) && (int1 > int3)) || ((int1 < int2) && (int1 > int3)))
    printf("%d is the median\n", int1);
  else if ((((int2 < int1)) && (int2 > int3)) || ((int2 < int3) && (int2 > int1)))
    printf("%d is the median\n", int2);
  else if (((int3 < int1) && (int3 > int2)) || ((int3 < int2) && (int3 > int1)))
    printf("%d is the median\n", int3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r9d
  jge    L113
  cmp    %r8d,%r9d
  jg     L62
  cmp    %r8d,%esi
  jl     L88
L107:
  cmp    %r8d,%esi
  jle    L7
  cmp    %r8d,%r9d
  jge    L7
L28:
  mov    %r8d,%esi
L88:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L113:
  jle    L90
  cmp    %r8d,%esi
  jg     L88
  jge    L7
L138:
  cmp    %r8d,%r9d
  jg     L28
  jmp    L7
L62:
  mov    %r9d,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L7
L90:
  cmp    %r8d,%esi
  jl     L138
  jmp    L107
L124:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D22: Please enter 3 numbers separated by spaces > 

tool: D6: %d %d %d

tool: D3: %d is the median


assistant: ```c
int main(void) {
  int int1, int2, int3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d %d %d", &int1, &int2, &int3);
  if (((int1 < int2) && (int1 > int3)) || ((int1 < int2) && (int1 > int3)))
    printf("%d is the median\n", int1);
  else if ((((int2 < int1)) && (int2 > int3)) || ((int2 < int3) && (int2 > int1)))
    printf("%d is the median\n", int2);
  else if (((int3 < int1) && (int3 > int2)) || ((int3 < int2) && (int3 > int1)))
    printf("%d is the median\n", int3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cal_g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %rcx,-0x80(%rbp)
  mov    %r8d,-0x84(%rbp)
  mov    %r9d,-0x88(%rbp)
  movsd  %xmm0,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x84(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x80(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x60(%rbp)
  mov    -0x88(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x84(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crstrns@plt>
  mov    -0x90(%rbp),%rcx
  lea    -0x50(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L22
L7:
  lea    -0x60(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mv_mul@plt>
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int cal_g(double *g, double *vx, double *b, double *ep, const int i, const int n, const double eps) {
  double t[2], s[4], u[4];
  t[0] = b[i] - ep[0];
  t[1] = b[n - 1 - i] - ep[1];
  crstrns(s, vx);
  if (inverse(u, s, eps) == -1)
    return (-1);
  mv_mul(g, u, t);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cal_g>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%rbx
  mov    %rcx,%rax
  movq   %xmm0,%rbp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x58(%rsp)
  xor    %ecx,%ecx
  movslq %r8d,%rcx
  movsd  (%rdx,%rcx,8),%xmm0
  subsd  (%rax),%xmm0
  movsd  %xmm0,(%rsp)
  sub    $0x1,%r9d
  sub    %r8d,%r9d
  movslq %r9d,%r9
  movsd  (%rdx,%r9,8),%xmm0
  subsd  0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <crstrns@plt>
  lea    0x30(%rsp),%rdi
  movq   %rbp,%xmm0
  mov    %r12,%rsi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L6
  mov    %rsp,%rdx
  lea    0x30(%rsp),%rsi
  mov    %rbx,%rdi
  call   <mv_mul@plt>
  mov    $0x0,%eax
L6:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cal_g(double *g, double *vx, double *b, double *ep, const int i, const int n, const double eps) {
  double t[2], s[4], u[4];
  t[0] = b[i] - ep[0];
  t[1] = b[n - 1 - i] - ep[1];
  crstrns(s, vx);
  if (inverse(u, s, eps) == -1)
    return (-1);
  mv_mul(g, u, t);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cal_g>:
  endbr64
  push   %r13
  mov    %rcx,%rax
  sub    $0x1,%r9d
  push   %r12
  sub    %r8d,%r9d
  push   %rbp
  movslq %r9d,%r9
  mov    %rdi,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x20(%rsp),%r12
  lea    0x40(%rsp),%r13
  mov    %fs:0x28,%rcx
  mov    %rcx,0x68(%rsp)
  xor    %ecx,%ecx
  movslq %r8d,%rcx
  mov    %r12,%rdi
  movsd  (%rdx,%rcx,8),%xmm1
  subsd  (%rax),%xmm1
  movsd  %xmm1,0x10(%rsp)
  movsd  (%rdx,%r9,8),%xmm1
  subsd  0x8(%rax),%xmm1
  movsd  %xmm1,0x18(%rsp)
  call   <crstrns@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L17
  lea    0x10(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <mv_mul@plt>
  xor    %eax,%eax
L17:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x70,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cal_g(double *g, double *vx, double *b, double *ep, const int i, const int n, const double eps) {
  double t[2], s[4], u[4];
  t[0] = b[i] - ep[0];
  t[1] = b[n - 1 - i] - ep[1];
  crstrns(s, vx);
  if (inverse(u, s, eps) == -1)
    return (-1);
  mv_mul(g, u, t);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cal_g>:
  endbr64
  push   %r13
  sub    $0x1,%r9d
  push   %r12
  sub    %r8d,%r9d
  push   %rbp
  movslq %r9d,%r9
  mov    %rdi,%rbp
  sub    $0x70,%rsp
  movupd (%rcx),%xmm2
  movsd  %xmm0,0x8(%rsp)
  lea    0x20(%rsp),%r12
  lea    0x40(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movslq %r8d,%rax
  mov    %r12,%rdi
  movsd  (%rdx,%rax,8),%xmm1
  movhpd (%rdx,%r9,8),%xmm1
  subpd  %xmm2,%xmm1
  movaps %xmm1,0x10(%rsp)
  call   <crstrns@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L12
  lea    0x10(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <mv_mul@plt>
  xor    %eax,%eax
L12:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x70,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cal_g(double *g, double *vx, double *b, double *ep, const int i, const int n, const double eps) {
  double t[2], s[4], u[4];
  t[0] = b[i] - ep[0];
  t[1] = b[n - 1 - i] - ep[1];
  crstrns(s, vx);
  if (inverse(u, s, eps) == -1)
    return (-1);
  mv_mul(g, u, t);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utilReadInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <utilIsLittleEndian@plt>
  test   %rax,%rax
  je     L8
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  lea    -0xc(%rbp),%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  jmp    L5
L8:
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int32_t utilReadInt32(const unsigned char *buf) {
  int32_t i;
  if (utilIsLittleEndian()) {
    ((unsigned char *)&i)[0] = buf[3];
    ((unsigned char *)&i)[1] = buf[2];
    ((unsigned char *)&i)[2] = buf[1];
    ((unsigned char *)&i)[3] = buf[0];
    return i;
  } else {
    memcpy((unsigned char *)&i, buf, 4);
    return i;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utilReadInt32>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <utilIsLittleEndian@plt>
  test   %rax,%rax
  je     L16
  movzbl 0x3(%rbx),%eax
  mov    %al,0x4(%rsp)
  movzbl 0x2(%rbx),%eax
  mov    %al,0x5(%rsp)
  movzbl 0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  movzbl (%rbx),%eax
  mov    %al,0x7(%rsp)
  mov    0x4(%rsp),%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  jmp    L29
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t utilReadInt32(const unsigned char *buf) {
  int32_t i;
  if (utilIsLittleEndian()) {
    ((unsigned char *)&i)[0] = buf[3];
    ((unsigned char *)&i)[1] = buf[2];
    ((unsigned char *)&i)[2] = buf[1];
    ((unsigned char *)&i)[3] = buf[0];
    return i;
  } else {
    memcpy((unsigned char *)&i, buf, 4);
    return i;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<utilReadInt32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <utilIsLittleEndian@plt>
  test   %rax,%rax
  je     L10
  mov    0x0(%rbp),%eax
  bswap  %eax
  mov    %eax,0x4(%rsp)
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  jmp    L14
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t utilReadInt32(const unsigned char *buf) {
  int32_t i;
  if (utilIsLittleEndian()) {
    ((unsigned char *)&i)[0] = buf[3];
    ((unsigned char *)&i)[1] = buf[2];
    ((unsigned char *)&i)[2] = buf[1];
    ((unsigned char *)&i)[3] = buf[0];
    return i;
  } else {
    memcpy((unsigned char *)&i, buf, 4);
    return i;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utilReadInt32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <utilIsLittleEndian@plt>
  test   %rax,%rax
  je     L2
  mov    0x0(%rbp),%eax
  bswap  %eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  jmp    L11
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t utilReadInt32(const unsigned char *buf) {
  int32_t i;
  if (utilIsLittleEndian()) {
    ((unsigned char *)&i)[0] = buf[3];
    ((unsigned char *)&i)[1] = buf[2];
    ((unsigned char *)&i)[2] = buf[1];
    ((unsigned char *)&i)[3] = buf[0];
    return i;
  } else {
    memcpy((unsigned char *)&i, buf, 4);
    return i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ax25_callsign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L58
L52:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L13
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,(%rax)
  jmp    L66
L13:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movl   $0x40,(%rax)
L66:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L58:
  cmpb   $0x5,-0x1(%rbp)
  jle    L52
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L35
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %al,-0x2(%rbp)
  jmp    L7
L35:
  movb   $0x0,-0x2(%rbp)
L7:
  movsbl -0x2(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint8_t *_ax25_callsign(uint8_t *s, char *callsign) {
  char ssid;
  char i;
  for (i = 0; i < 6; i++) {
    if (*callsign && *callsign != '-')
      *(s++) = *(callsign++) << 1;
    else
      *(s++) = ' ' << 1;
  }
  if (*callsign == '-')
    ssid = atoi(callsign + 1);
  else
    ssid = 0;
  *(s++) = ('0' + ssid) << 1;
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_ax25_callsign>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    0x4(%rdi),%rdx
  lea    0x1c(%rdi),%rcx
  mov    $0x40,%edi
  jmp    L43
L45:
  add    $0x1,%rsi
  movsbl %al,%eax
  add    %eax,%eax
L25:
  mov    %eax,-0x4(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  je     L12
L43:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L33
  cmp    $0x2d,%al
  jne    L45
L33:
  mov    %edi,%eax
  jmp    L25
L12:
  mov    $0x0,%eax
  cmpb   $0x2d,(%rsi)
  je     L32
L58:
  movsbl %al,%eax
  lea    0x60(%rax,%rax,1),%eax
  mov    %eax,0x18(%rbx)
  lea    0x1c(%rbx),%rax
  pop    %rbx
  ret
L32:
  lea    0x1(%rsi),%rdi
  call   <atoi@plt>
  jmp    L58
```

assistant: ```c
uint8_t *_ax25_callsign(uint8_t *s, char *callsign) {
  char ssid;
  char i;
  for (i = 0; i < 6; i++) {
    if (*callsign && *callsign != '-')
      *(s++) = *(callsign++) << 1;
    else
      *(s++) = ' ' << 1;
  }
  if (*callsign == '-')
    ssid = atoi(callsign + 1);
  else
    ssid = 0;
  *(s++) = ('0' + ssid) << 1;
  return (s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ax25_callsign>:
  endbr64
  push   %rbx
  lea    0x18(%rdi),%rax
  mov    %rdi,%rbx
  mov    %rdi,%rcx
  jmp    L47
  nopl   0x0(%rax)
L58:
  add    %edx,%edx
  add    $0x1,%rsi
  mov    %edx,-0x4(%rcx)
  cmp    %rcx,%rax
  je     L11
L47:
  movsbl (%rsi),%edx
  add    $0x4,%rcx
  test   %dl,%dl
  je     L55
  cmp    $0x2d,%dl
  jne    L58
L55:
  mov    $0x40,%edx
  mov    %edx,-0x4(%rcx)
  cmp    %rcx,%rax
  jne    L47
L11:
  cmpb   $0x2d,(%rsi)
  mov    $0x60,%eax
  je     L27
  mov    %eax,0x18(%rbx)
  lea    0x1c(%rbx),%rax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  lea    0x1(%rsi),%rdi
  call   <atoi@plt>
  movsbl %al,%eax
  lea    0x60(%rax,%rax,1),%eax
  mov    %eax,0x18(%rbx)
  lea    0x1c(%rbx),%rax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t *_ax25_callsign(uint8_t *s, char *callsign) {
  char ssid;
  char i;
  for (i = 0; i < 6; i++) {
    if (*callsign && *callsign != '-')
      *(s++) = *(callsign++) << 1;
    else
      *(s++) = ' ' << 1;
  }
  if (*callsign == '-')
    ssid = atoi(callsign + 1);
  else
    ssid = 0;
  *(s++) = ('0' + ssid) << 1;
  return (s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_ax25_callsign>:
  endbr64
  movsbl (%rsi),%eax
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  cmp    $0x2d,%al
  je     L71
  test   %al,%al
  je     L71
  add    %eax,%eax
  add    $0x1,%rdi
  mov    %eax,(%rbx)
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L128
L73:
  test   %al,%al
  je     L128
  add    %eax,%eax
  add    $0x1,%rdi
  mov    %eax,0x4(%rbx)
  movsbl (%rdi),%eax
  test   %al,%al
  je     L100
L135:
  cmp    $0x2d,%al
  je     L100
  add    %eax,%eax
  add    $0x1,%rdi
  mov    %eax,0x8(%rbx)
  movsbl (%rdi),%eax
  test   %al,%al
  je     L51
L1:
  cmp    $0x2d,%al
  je     L51
  add    %eax,%eax
  add    $0x1,%rdi
  mov    %eax,0xc(%rbx)
  movsbl (%rdi),%eax
  test   %al,%al
  je     L62
L85:
  cmp    $0x2d,%al
  je     L62
  add    %eax,%eax
  add    $0x1,%rdi
  mov    %eax,0x10(%rbx)
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L32
L101:
  test   %al,%al
  je     L32
  add    %eax,%eax
  add    $0x1,%rdi
  mov    %eax,0x14(%rbx)
  cmpb   $0x2d,(%rdi)
  mov    $0x60,%eax
  je     L119
L46:
  mov    %eax,0x18(%rbx)
  lea    0x1c(%rbx),%rax
  pop    %rbx
  ret
  nopl   (%rax)
L71:
  mov    $0x40,%eax
  mov    %eax,(%rbx)
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  jne    L73
L128:
  mov    $0x40,%eax
  mov    %eax,0x4(%rbx)
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L135
L100:
  mov    $0x40,%eax
  mov    %eax,0x8(%rbx)
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L1
L51:
  mov    $0x40,%eax
  mov    %eax,0xc(%rbx)
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L85
L62:
  mov    $0x40,%eax
  mov    %eax,0x10(%rbx)
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  jne    L101
L32:
  mov    $0x40,%eax
  mov    %eax,0x14(%rbx)
  cmpb   $0x2d,(%rdi)
  mov    $0x60,%eax
  jne    L46
L119:
  add    $0x1,%rdi
  call   <atoi@plt>
  movsbl %al,%eax
  lea    0x60(%rax,%rax,1),%eax
  mov    %eax,0x18(%rbx)
  lea    0x1c(%rbx),%rax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t *_ax25_callsign(uint8_t *s, char *callsign) {
  char ssid;
  char i;
  for (i = 0; i < 6; i++) {
    if (*callsign && *callsign != '-')
      *(s++) = *(callsign++) << 1;
    else
      *(s++) = ' ' << 1;
  }
  if (*callsign == '-')
    ssid = atoi(callsign + 1);
  else
    ssid = 0;
  *(s++) = ('0' + ssid) << 1;
  return (s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bublesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L10
  movl   $0x0,-0xc(%rbp)
  jmp    L68
L5:
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L15:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L32
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L32:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L15
  addl   $0x1,-0xc(%rbp)
L68:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  jmp    L65
L10:
  nop
L65:
  pop    %rbp
  ret
```

assistant: ```c
void bublesort(int *parray, int arraysize) {
  int i, j;
  int temp;
  if (parray == NULL)
    return;
  for (i = 0; i < arraysize; i++) {
    for (j = 0; j < arraysize - i - 1; j++) {
      if (parray[j + 1] > parray[j]) {
        temp = parray[j + 1];
        parray[j + 1] = parray[j];
        parray[j] = temp;
      }
    }
  }
  return;
}
```