ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_bold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1b,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5b,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6d,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *insert_bold(char *data, int *pc) {
  data[(*pc)++] = '\033';
  data[(*pc)++] = '[';
  data[(*pc)++] = '1';
  data[(*pc)++] = 'm';
  return data;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insert_bold>:
  endbr64
  mov    %rdi,%rax
  mov    (%rsi),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movslq %edx,%rdx
  movb   $0x1b,(%rdi,%rdx,1)
  mov    (%rsi),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movslq %edx,%rdx
  movb   $0x5b,(%rdi,%rdx,1)
  mov    (%rsi),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movslq %edx,%rdx
  movb   $0x31,(%rdi,%rdx,1)
  mov    (%rsi),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movslq %edx,%rdx
  movb   $0x6d,(%rdi,%rdx,1)
  ret
```

assistant: ```c
char *insert_bold(char *data, int *pc) {
  data[(*pc)++] = '\033';
  data[(*pc)++] = '[';
  data[(*pc)++] = '1';
  data[(*pc)++] = 'm';
  return data;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_bold>:
  endbr64
  movslq (%rsi),%rdx
  mov    %rdi,%rax
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movb   $0x1b,(%rdi,%rdx,1)
  movslq (%rsi),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movb   $0x5b,(%rdi,%rdx,1)
  movslq (%rsi),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movb   $0x31,(%rdi,%rdx,1)
  movslq (%rsi),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  movb   $0x6d,(%rdi,%rdx,1)
  ret
```

assistant: ```c
char *insert_bold(char *data, int *pc) {
  data[(*pc)++] = '\033';
  data[(*pc)++] = '[';
  data[(*pc)++] = '1';
  data[(*pc)++] = 'm';
  return data;
}
```
user: What is the c source code of the assembly code below:

```asm
<getPermutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L0
L2:
  mov    -0x24(%rbp),%eax
  add    $0x31,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  addl   $0x1,-0x24(%rbp)
L0:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%esi
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <fun@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
char *getPermutation(int n, int k) {
  char buf[10] = {0};
  char *ret = (char *)calloc(sizeof(char), 10);
  int i;
  for (i = 0; i < n; i++)
    buf[i] = '1' + i;
  fun(buf, n, k, ret);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getPermutation>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L29
  lea    0xe(%rsp),%rdx
  lea    -0x1(%rbx),%eax
  lea    0xf(%rsp,%rax,1),%rsi
  mov    %rdx,%rax
  mov    $0x31,%ecx
  sub    %edx,%ecx
L18:
  lea    (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L18
L29:
  lea    0xe(%rsp),%rdi
  mov    %rbp,%rcx
  mov    %r12d,%edx
  mov    %ebx,%esi
  call   <fun@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbp,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getPermutation(int n, int k) {
  char buf[10] = {0};
  char *ret = (char *)calloc(sizeof(char), 10);
  int i;
  for (i = 0; i < n; i++)
    buf[i] = '1' + i;
  fun(buf, n, k, ret);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getPermutation>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0xa,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  mov    %ax,0x16(%rsp)
  call   <calloc@plt>
  lea    0xe(%rsp),%r8
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L29
  lea    -0x1(%rbp),%eax
  mov    $0x31,%esi
  mov    %r8,%rdx
  lea    0xf(%rsp,%rax,1),%rdi
  sub    %r8d,%esi
L0:
  lea    (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L0
L29:
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r8,%rdi
  call   <fun@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getPermutation(int n, int k) {
  char buf[10] = {0};
  char *ret = (char *)calloc(sizeof(char), 10);
  int i;
  for (i = 0; i < n; i++)
    buf[i] = '1' + i;
  fun(buf, n, k, ret);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getPermutation>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0xa,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  mov    %ax,0x16(%rsp)
  call   <calloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L66
  movb   $0x31,0xe(%rsp)
  cmp    $0x1,%ebp
  je     L66
  movb   $0x32,0xf(%rsp)
  cmp    $0x2,%ebp
  je     L66
  movb   $0x33,0x10(%rsp)
  cmp    $0x3,%ebp
  je     L66
  movb   $0x34,0x11(%rsp)
  cmp    $0x4,%ebp
  je     L66
  movb   $0x35,0x12(%rsp)
  cmp    $0x5,%ebp
  je     L66
  movb   $0x36,0x13(%rsp)
  cmp    $0x6,%ebp
  je     L66
  movb   $0x37,0x14(%rsp)
  cmp    $0x7,%ebp
  je     L66
  movb   $0x38,0x15(%rsp)
  cmp    $0x8,%ebp
  je     L66
  movb   $0x39,0x16(%rsp)
  cmp    $0x9,%ebp
  je     L66
  movb   $0x3a,0x17(%rsp)
L66:
  lea    0xe(%rsp),%rdi
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %ebp,%esi
  call   <fun@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getPermutation(int n, int k) {
  char buf[10] = {0};
  char *ret = (char *)calloc(sizeof(char), 10);
  int i;
  for (i = 0; i < n; i++)
    buf[i] = '1' + i;
  fun(buf, n, k, ret);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L38
  mov    $0x1,%eax
  jmp    L19
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L1
  mov    $0xffffffff,%eax
  jmp    L19
L1:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int cmp(const void *p, const void *q) {
  int l = *(const int *)p;
  int r = *(const int *)q;
  if (l > r)
    return 1;
  else if (l < r)
    return -1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L9
  setl   %al
  movzbl %al,%eax
  neg    %eax
L9:
  ret
```

assistant: ```c
int cmp(const void *p, const void *q) {
  int l = *(const int *)p;
  int r = *(const int *)q;
  if (l > r)
    return 1;
  else if (l < r)
    return -1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L9
  setl   %al
  movzbl %al,%eax
  neg    %eax
L9:
  ret
```

assistant: ```c
int cmp(const void *p, const void *q) {
  int l = *(const int *)p;
  int r = *(const int *)q;
  if (l > r)
    return 1;
  else if (l < r)
    return -1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L1
  setl   %al
  movzbl %al,%eax
  neg    %eax
L1:
  ret
```

assistant: ```c
int cmp(const void *p, const void *q) {
  int l = *(const int *)p;
  int r = *(const int *)q;
  if (l > r)
    return 1;
  else if (l < r)
    return -1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ResetISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe000ed88,%eax
  mov    (%rax),%edx
  mov    $0xe000ed88,%eax
  or     $0xf00000,%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: What is the c source code of the assembly code below?

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eint0_3_irq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L8:
  mov    $0x7f008924,%eax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  cltq
  and    %rdx,%rax
  test   %rax,%rax
  je     L38
  mov    $0x7f008834,%eax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  cltq
  and    %rdx,%rax
  test   %rax,%rax
  je     L21
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L21:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L38:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x3,-0x4(%rbp)
  jle    L8
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D7
type: string

tool: D11: eint0_3_irq


tool: D12: K%d released


tool: D7: K%d pressed


assistant: ```c
void eint0_3_irq(void) {
  int i;
  printf("eint0_3_irq\n\r");
  for (i = 0; i < 4; i++) {
    if ((*((volatile unsigned long *)0x7F008924)) & (1 << i)) {
      if ((*((volatile unsigned long *)0x7F008834)) & (1 << i)) {
        printf("K%d released\n\r", i + 1);
      } else {
        printf("K%d pressed\n\r", i + 1);
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eint0_3_irq>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    D27(%rip),%r13
  lea    D28(%rip),%r12
  jmp    L15
L2:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L37:
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  je     L30
L15:
  mov    0x7f008924,%rdx
  lea    -0x1(%rbx),%ecx
  mov    %ebp,%eax
  shl    %cl,%eax
  cltq
  test   %rax,%rdx
  je     L37
  mov    0x7f008834,%rdx
  test   %rdx,%rax
  je     L2
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D11
type: string
name: unpack_data
arguments: tag: D27
type: string
name: unpack_data
arguments: tag: D28
type: string

tool: D11: eint0_3_irq


tool: D27: K%d pressed


tool: D28: K%d released


assistant: ```c
void eint0_3_irq(void) {
  int i;
  printf("eint0_3_irq\n\r");
  for (i = 0; i < 4; i++) {
    if ((*((volatile unsigned long *)0x7F008924)) & (1 << i)) {
      if ((*((volatile unsigned long *)0x7F008834)) & (1 << i)) {
        printf("K%d released\n\r", i + 1);
      } else {
        printf("K%d pressed\n\r", i + 1);
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<eint0_3_irq>:
  endbr64
  push   %r13
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
L33:
  mov    %r12d,%ecx
  mov    %r13d,%eax
  mov    0x7f008924,%rdx
  add    $0x1,%r12d
  shl    %cl,%eax
  cltq
  test   %rax,%rdx
  je     L9
  mov    0x7f008834,%rdx
  mov    %r12d,%esi
  test   %rdx,%rax
  je     L10
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L9:
  cmp    $0x4,%r12d
  jne    L33
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L10:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D22
type: string
name: unpack_data
arguments: data_label: D27
type: string

tool: D14: eint0_3_irq


tool: D22: K%d pressed


tool: D27: K%d released


assistant: ```c
void eint0_3_irq(void) {
  int i;
  printf("eint0_3_irq\n\r");
  for (i = 0; i < 4; i++) {
    if ((*((volatile unsigned long *)0x7F008924)) & (1 << i)) {
      if ((*((volatile unsigned long *)0x7F008834)) & (1 << i)) {
        printf("K%d released\n\r", i + 1);
      } else {
        printf("K%d pressed\n\r", i + 1);
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eint0_3_irq>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
L34:
  mov    %r12d,%ecx
  mov    %r13d,%eax
  mov    0x7f008924,%rdx
  add    $0x1,%r12d
  shl    %cl,%eax
  cltq
  test   %rax,%rdx
  je     L38
  mov    0x7f008834,%rdx
  mov    %r12d,%esi
  test   %rdx,%rax
  je     L3
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L38:
  cmp    $0x4,%r12d
  jne    L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L38
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D12
datatype: string

tool: D4: eint0_3_irq


tool: D11: K%d pressed


tool: D12: K%d released


assistant: ```c
void eint0_3_irq(void) {
  int i;
  printf("eint0_3_irq\n\r");
  for (i = 0; i < 4; i++) {
    if ((*((volatile unsigned long *)0x7F008924)) & (1 << i)) {
      if ((*((volatile unsigned long *)0x7F008834)) & (1 << i)) {
        printf("K%d released\n\r", i + 1);
      } else {
        printf("K%d pressed\n\r", i + 1);
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<warn_mempcpy_chain_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <unsigned_range@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <unsigned_range@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <unsigned_range@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void warn_mempcpy_chain_3(const void *s) {
  char *p = malloc(5);
  p = mempcpy(p, s, unsigned_range((1), (2)));
  p = mempcpy(p, s, unsigned_range((2), (3)));
  p = mempcpy(p, s, unsigned_range((3), (4)));
  sink(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warn_mempcpy_chain_3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <unsigned_range@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    %rax,%rbp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <unsigned_range@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    %rax,%rbp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <unsigned_range@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    %rax,%rdi
  call   <sink@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void warn_mempcpy_chain_3(const void *s) {
  char *p = malloc(5);
  p = mempcpy(p, s, unsigned_range((1), (2)));
  p = mempcpy(p, s, unsigned_range((2), (3)));
  p = mempcpy(p, s, unsigned_range((3), (4)));
  sink(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warn_mempcpy_chain_3>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x5,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    %rax,%r12
  call   <unsigned_range@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <mempcpy@plt>
  mov    $0x3,%esi
  mov    $0x2,%edi
  mov    %rax,%r12
  call   <unsigned_range@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <mempcpy@plt>
  mov    $0x4,%esi
  mov    $0x3,%edi
  mov    %rax,%r12
  call   <unsigned_range@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <mempcpy@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %rax,%rdi
  pop    %r12
  jmp    1080 <sink@plt>
```

assistant: ```c
void warn_mempcpy_chain_3(const void *s) {
  char *p = malloc(5);
  p = mempcpy(p, s, unsigned_range((1), (2)));
  p = mempcpy(p, s, unsigned_range((2), (3)));
  p = mempcpy(p, s, unsigned_range((3), (4)));
  sink(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hostformat_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L13
L5:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L0
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
  add    $0x5,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int hostformat_parse(const char *str, char *hostname, char *port) {
  char *semicolon_pos;
  size_t cpy_cnt;
  semicolon_pos = strrchr(str, ':');
  if (semicolon_pos == NULL)
    return -1;
  cpy_cnt = semicolon_pos - str;
  if (cpy_cnt > HOST_NAME_MAX)
    cpy_cnt = HOST_NAME_MAX - 1;
  strncpy(hostname, str, cpy_cnt);
  hostname[cpy_cnt] = '\0';
  strncpy(port, (semicolon_pos + 1), 6);
  port[6 - 1] = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hostformat_parse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    $0x3a,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    %rax,%r14
  sub    %rbp,%r14
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  cmp    %r14,%rax
  cmovb  %rdx,%r14
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r14,1)
  lea    0x1(%rbx),%rsi
  mov    $0x6,%edx
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x5(%r12)
  mov    $0x0,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int hostformat_parse(const char *str, char *hostname, char *port) {
  char *semicolon_pos;
  size_t cpy_cnt;
  semicolon_pos = strrchr(str, ':');
  if (semicolon_pos == NULL)
    return -1;
  cpy_cnt = semicolon_pos - str;
  if (cpy_cnt > HOST_NAME_MAX)
    cpy_cnt = HOST_NAME_MAX - 1;
  strncpy(hostname, str, cpy_cnt);
  hostname[cpy_cnt] = '\0';
  strncpy(port, (semicolon_pos + 1), 6);
  port[6 - 1] = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hostformat_parse>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    $0x3a,%esi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbx
  mov    %rax,%r12
  mov    D2(%rip),%rax
  mov    %rbp,%rsi
  sub    %rbp,%r12
  mov    %r14,%rdi
  mov    (%rax),%rax
  cmp    %r12,%rax
  lea    -0x1(%rax),%rdx
  cmovb  %rdx,%r12
  mov    %r12d,%edx
  call   <strncpy@plt>
  movb   $0x0,(%r14,%r12,1)
  lea    0x1(%rbx),%rsi
  mov    %r13,%rdi
  mov    $0x6,%edx
  call   <strncpy@plt>
  movb   $0x0,0x5(%r13)
  xor    %eax,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int hostformat_parse(const char *str, char *hostname, char *port) {
  char *semicolon_pos;
  size_t cpy_cnt;
  semicolon_pos = strrchr(str, ':');
  if (semicolon_pos == NULL)
    return -1;
  cpy_cnt = semicolon_pos - str;
  if (cpy_cnt > HOST_NAME_MAX)
    cpy_cnt = HOST_NAME_MAX - 1;
  strncpy(hostname, str, cpy_cnt);
  hostname[cpy_cnt] = '\0';
  strncpy(port, (semicolon_pos + 1), 6);
  port[6 - 1] = '\0';
  return 0;
}
```