user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D68(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D54(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq (%rsp),%rdi
  mov    %rdi,%r13
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r13d,%r13d
  jle    L26
  mov    0x4(%rsp),%eax
  mov    %r13d,%r13d
  mov    %rbp,%rbx
  lea    0x0(%rbp,%r13,8),%r13
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  shl    $0x2,%r12
  nop
L75:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbx,%r13
  jne    L75
L26:
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L63
  mov    0x4(%rsp),%eax
  mov    %rbp,%r14
  xor    %r13d,%r13d
  lea    D40(%rip),%r12
  test   %eax,%eax
  js     L35
  nopl   0x0(%rax)
L78:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L72:
  mov    (%r14),%rax
  mov    %r12,%rdi
  lea    (%rax,%rbx,4),%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L72
  add    $0x1,%r13d
  cmp    (%rsp),%r13d
  jge    L35
  add    $0x8,%r14
  test   %eax,%eax
  jns    L78
L35:
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%r14
  call   <puts@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L6
  mov    %r14,%r12
  xor    %ebx,%ebx
  lea    D40(%rip),%r13
  nopl   0x0(%rax)
L59:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  add    $0x4,%r12
  cmp    %ebx,%ecx
  jg     L59
L6:
  movslq %ecx,%rax
  mov    (%rsp),%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  movl   $0x0,(%r14,%rax,4)
  xor    %eax,%eax
  call   <revisedsimplex@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  mov    0x4(%rsp),%eax
  jmp    L35
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D68
datatype: string
name: read_data
arguments: data_label: D54
datatype: string
name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D65
datatype: string
name: read_data
arguments: data_label: D40
datatype: string
name: read_data
arguments: data_label: D6
datatype: string

tool: D68: Enter the number of equations(m) : 

tool: D54: %d

tool: D3: Enter the number of unknowns(n): 

tool: D65: Enter the augmented matrix A:

tool: D40: %f

tool: D6: Enter the coefficients of expression(Z): 

assistant: ```c
void main() {
  int i, j, m, n, in, *flag;
  float **A, *Z, **T0, **T1, p, *xB, **Y, **P, r;
  printf("Enter the number of equations(m) : ");
  scanf("%d", &m);
  printf("Enter the number of unknowns(n): ");
  scanf("%d", &n);
  A = (float **)malloc((m) * sizeof(float *));
  for (i = 0; i < m; i++)
    A[i] = (float *)malloc((n + 1) * sizeof(float));
  printf("Enter the augmented matrix A:\n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n + 1; j++) {
      scanf("%f", &A[i][j]);
    }
  }
  Z = (float *)malloc((n + 1) * sizeof(float));
  printf("Enter the coefficients of expression(Z): \n");
  for (i = 0; i < n; i++) {
    scanf("%f", &Z[i]);
  }
  Z[n] = 0;
  revisedsimplex(A, Z, m, n);
}
```