ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    0x20(%rsp),%rcx
  lea    0x24(%rsp),%r8
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%esi
  pxor   %xmm2,%xmm2
  movss  0x24(%rsp),%xmm3
  movss  0x20(%rsp),%xmm1
  mov    0x1c(%rsp),%edx
  pxor   %xmm0,%xmm0
  lea    D15(%rip),%rdi
  cvtsi2ss %esi,%xmm2
  lea    (%rsi,%rdx,1),%eax
  cvtsi2ss %eax,%xmm0
  mov    $0x3,%eax
  subss  %xmm3,%xmm2
  addss  %xmm1,%xmm0
  divss  %xmm1,%xmm2
  cvtss2sd %xmm1,%xmm1
  addss  %xmm3,%xmm0
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  mulss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  cvtss2sd %xmm2,%xmm2
  call   <printf@plt>
  lea    D11(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D0(%rip),%rdi
  mulss  D57(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
datatype: string
name: extract_symbolic_data
arguments: data_tag: D51
datatype: string
name: extract_symbolic_data
arguments: data_tag: D30
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string
name: extract_symbolic_data
arguments: data_tag: D57
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string

tool: D37: [n00862133@osprey COP2220]$ ./project2

COP2220 Project 2 - Gary Frazier


tool: D51: Enter four numbers in the format nnn nnn nnn.nn nnn.nn<enter>:

tool: D30: %d %d %f %f

tool: D15: 
The result of the calculation ((%d - %.2f) / %.2f) * %d is %.2f



tool: D11: The sum of the input numbers is:     %.2f


tool: D0: The average of the input numbers is: %.2f



tool: {"D57": [0x00,0x00,0x80,0x3e]}

tool: D35: Have a nice day!

assistant: ```c
int main(void) {
  printf("[n00862133@osprey COP2220]$ ./project2\n\nCOP2220 Project 2 - Gary Frazier\n\n");
  int number1;
  int number2;
  float number3;
  float number4;
  printf("Enter four numbers in the format nnn nnn nnn.nn nnn.nn<enter>:\n");
  scanf("%d %d %f %f", &number1, &number2, &number3, &number4);
  float result = ((number1 - number4) / number3) * number2;
  float sum = number1 + number2 + number3 + number4;
  float avg = sum / 4;
  printf("\nThe result of the calculation ((%d - %.2f) / %.2f) * %d is %.2f\n\n", number1, number4, number3, number2, result);
  printf("The sum of the input numbers is:     %.2f\n", sum);
  printf("The average of the input numbers is: %.2f\n\n", avg);
  printf("Have a nice day!\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D40(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    0x20(%rsp),%rcx
  lea    0x24(%rsp),%r8
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%esi
  pxor   %xmm2,%xmm2
  movss  0x24(%rsp),%xmm3
  movss  0x20(%rsp),%xmm1
  mov    0x1c(%rsp),%edx
  pxor   %xmm0,%xmm0
  lea    D10(%rip),%rdi
  cvtsi2ss %esi,%xmm2
  lea    (%rsi,%rdx,1),%eax
  cvtsi2ss %eax,%xmm0
  mov    $0x3,%eax
  subss  %xmm3,%xmm2
  addss  %xmm1,%xmm0
  divss  %xmm1,%xmm2
  cvtss2sd %xmm1,%xmm1
  addss  %xmm3,%xmm0
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  mulss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  cvtss2sd %xmm2,%xmm2
  call   <printf@plt>
  lea    D29(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D35(%rip),%rdi
  mulss  D13(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D40
datatype: string
name: extract_symbolic_data
arguments: data_tag: D46
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string
name: extract_symbolic_data
arguments: data_tag: D13
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D40: [n00862133@osprey COP2220]$ ./project2

COP2220 Project 2 - Gary Frazier


tool: D46: Enter four numbers in the format nnn nnn nnn.nn nnn.nn<enter>:

tool: D36: %d %d %f %f

tool: D10: 
The result of the calculation ((%d - %.2f) / %.2f) * %d is %.2f



tool: D29: The sum of the input numbers is:     %.2f


tool: D35: The average of the input numbers is: %.2f



tool: {"D13": [0x00,0x00,0x80,0x3e]}

tool: D8: Have a nice day!

assistant: ```c
int main(void) {
  printf("[n00862133@osprey COP2220]$ ./project2\n\nCOP2220 Project 2 - Gary Frazier\n\n");
  int number1;
  int number2;
  float number3;
  float number4;
  printf("Enter four numbers in the format nnn nnn nnn.nn nnn.nn<enter>:\n");
  scanf("%d %d %f %f", &number1, &number2, &number3, &number4);
  float result = ((number1 - number4) / number3) * number2;
  float sum = number1 + number2 + number3 + number4;
  float avg = sum / 4;
  printf("\nThe result of the calculation ((%d - %.2f) / %.2f) * %d is %.2f\n\n", number1, number4, number3, number2, result);
  printf("The sum of the input numbers is:     %.2f\n", sum);
  printf("The average of the input numbers is: %.2f\n\n", avg);
  printf("Have a nice day!\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safecpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,%rcx
  mov    %edx,%eax
  mov    -0x10(%rbp),%rbx
  test   %rcx,%rcx
  je     L17
  sub    $0x1,%eax
  jmp    L0
L27:
  sub    $0x1,%eax
L0:
  test   %eax,%eax
  je     L17
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L27
L17:
  movb   $0x0,(%rbx)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *safecpy(to, from, len)
char *to;
register char *from;
register int len;
{
  register char *dest = to;
  if (from != ((char *)0))
    for (len--; len && (*dest++ = *from++); len--)
      ;
  *dest = '\0';
  return to;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<safecpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L21
  cmp    $0x1,%edx
  je     L21
  lea    -0x1(%rdx),%r8d
  add    %rsi,%r8
L18:
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rsi),%edx
  mov    %dl,-0x1(%rcx)
  test   %dl,%dl
  je     L21
  cmp    %r8,%rsi
  jne    L18
L21:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *safecpy(to, from, len)
char *to;
register char *from;
register int len;
{
  register char *dest = to;
  if (from != ((char *)0))
    for (len--; len && (*dest++ = *from++); len--)
      ;
  *dest = '\0';
  return to;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<safecpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L20
  cmp    $0x1,%edx
  je     L20
  lea    -0x1(%rdx),%r8d
  add    %rsi,%r8
  jmp    L31
  nopl   (%rax)
L14:
  cmp    %r8,%rsi
  je     L20
L31:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  test   %dl,%dl
  jne    L14
L20:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *safecpy(to, from, len)
char *to;
register char *from;
register int len;
{
  register char *dest = to;
  if (from != ((char *)0))
    for (len--; len && (*dest++ = *from++); len--)
      ;
  *dest = '\0';
  return to;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<safecpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L23
  cmp    $0x1,%edx
  je     L23
  lea    -0x1(%rdx),%r8d
  add    %rsi,%r8
  jmp    L14
  nopl   (%rax)
L3:
  cmp    %r8,%rsi
  je     L23
L14:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  test   %dl,%dl
  jne    L3
L23:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *safecpy(to, from, len)
char *to;
register char *from;
register int len;
{
  register char *dest = to;
  if (from != ((char *)0))
    for (len--; len && (*dest++ = *from++); len--)
      ;
  *dest = '\0';
  return to;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ide_wait_ready>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L22:
  mov    $0xa05f7018,%eax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%eax
  test   %al,%al
  js     L34
  mov    $0x0,%eax
  jmp    L11
L34:
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x98967f,-0x4(%rbp)
  jle    L22
  movzbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <ide_dump_registers@plt>
  mov    $0x1,%eax
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: Timeout waiting for IDE to become ready (status = 0x%02X)


assistant: ```c
int ide_wait_ready() {
  unsigned char status;
  int i;
  for (i = 0; i < 10000000; i++) {
    status = (unsigned int)(*((volatile unsigned char *)(0xA05F7000 + 0x018)));
    if ((status & 0x80) == 0)
      return 0;
  }
  printf("Timeout waiting for IDE to become ready (status = 0x%02X)\n", status);
  ide_dump_registers();
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ide_wait_ready>:
  endbr64
  mov    $0x989680,%eax
  mov    $0xa05f7018,%ecx
L10:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jns    L15
  sub    $0x1,%eax
  jne    L10
  sub    $0x8,%rsp
  movzbl %dl,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <ide_dump_registers@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L15:
  mov    $0x0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: Timeout waiting for IDE to become ready (status = 0x%02X)


assistant: ```c
int ide_wait_ready() {
  unsigned char status;
  int i;
  for (i = 0; i < 10000000; i++) {
    status = (unsigned int)(*((volatile unsigned char *)(0xA05F7000 + 0x018)));
    if ((status & 0x80) == 0)
      return 0;
  }
  printf("Timeout waiting for IDE to become ready (status = 0x%02X)\n", status);
  ide_dump_registers();
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ide_wait_ready>:
  endbr64
  mov    $0x989680,%eax
  mov    $0xa05f7018,%ecx
  jmp    L10
L24:
  sub    $0x1,%eax
  je     L23
L10:
  movzbl (%rcx),%edx
  test   %dl,%dl
  js     L24
  xor    %eax,%eax
  ret
  nop
L23:
  sub    $0x8,%rsp
  movzbl %dl,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <ide_dump_registers@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: Timeout waiting for IDE to become ready (status = 0x%02X)


assistant: ```c
int ide_wait_ready() {
  unsigned char status;
  int i;
  for (i = 0; i < 10000000; i++) {
    status = (unsigned int)(*((volatile unsigned char *)(0xA05F7000 + 0x018)));
    if ((status & 0x80) == 0)
      return 0;
  }
  printf("Timeout waiting for IDE to become ready (status = 0x%02X)\n", status);
  ide_dump_registers();
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ide_wait_ready>:
  endbr64
  mov    $0x989680,%eax
  mov    $0xa05f7018,%ecx
  jmp    L21
L11:
  sub    $0x1,%eax
  je     L18
L21:
  movzbl (%rcx),%edx
  test   %dl,%dl
  js     L11
  xor    %eax,%eax
  ret
  nop
L18:
  sub    $0x8,%rsp
  movzbl %dl,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <ide_dump_registers@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: Timeout waiting for IDE to become ready (status = 0x%02X)


assistant: ```c
int ide_wait_ready() {
  unsigned char status;
  int i;
  for (i = 0; i < 10000000; i++) {
    status = (unsigned int)(*((volatile unsigned char *)(0xA05F7000 + 0x018)));
    if ((status & 0x80) == 0)
      return 0;
  }
  printf("Timeout waiting for IDE to become ready (status = 0x%02X)\n", status);
  ide_dump_registers();
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mangle_delete_at>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  mov    -0x1c(%rbp),%eax
  jmp    L13
L25:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L6
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int mangle_delete_at(char arr[64], int arr_len, int upos) {
  if (upos >= arr_len)
    return (arr_len);
  int arr_pos;
  for (arr_pos = upos; arr_pos < arr_len - 1; arr_pos++) {
    arr[arr_pos] = arr[arr_pos + 1];
  }
  return (arr_len - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mangle_delete_at>:
  endbr64
  mov    %esi,%r8d
  cmp    %esi,%edx
  jge    L26
  lea    -0x1(%rsi),%r8d
  cmp    %r8d,%edx
  jge    L26
  movslq %edx,%rcx
  lea    (%rdi,%rcx,1),%rax
  lea    0x1(%rdi,%rcx,1),%rcx
  sub    $0x2,%esi
  sub    %edx,%esi
  add    %rsi,%rcx
L20:
  movzbl 0x1(%rax),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L20
L26:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mangle_delete_at(char arr[64], int arr_len, int upos) {
  if (upos >= arr_len)
    return (arr_len);
  int arr_pos;
  for (arr_pos = upos; arr_pos < arr_len - 1; arr_pos++) {
    arr[arr_pos] = arr[arr_pos + 1];
  }
  return (arr_len - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mangle_delete_at>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  cmp    %esi,%edx
  jge    L4
  sub    $0x1,%r12d
  cmp    %r12d,%edx
  jge    L4
  sub    $0x2,%esi
  movslq %edx,%rax
  sub    %edx,%esi
  lea    0x1(%rsi),%rdx
  lea    0x1(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  call   <memmove@plt>
L4:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int mangle_delete_at(char arr[64], int arr_len, int upos) {
  if (upos >= arr_len)
    return (arr_len);
  int arr_pos;
  for (arr_pos = upos; arr_pos < arr_len - 1; arr_pos++) {
    arr[arr_pos] = arr[arr_pos + 1];
  }
  return (arr_len - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mangle_delete_at>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  cmp    %esi,%edx
  jge    L7
  sub    $0x1,%r12d
  cmp    %r12d,%edx
  jge    L7
  sub    $0x2,%esi
  movslq %edx,%rax
  sub    %edx,%esi
  lea    0x1(%rsi),%rdx
  lea    0x1(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  call   <memmove@plt>
L7:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int mangle_delete_at(char arr[64], int arr_len, int upos) {
  if (upos >= arr_len)
    return (arr_len);
  int arr_pos;
  for (arr_pos = upos; arr_pos < arr_len - 1; arr_pos++) {
    arr[arr_pos] = arr[arr_pos + 1];
  }
  return (arr_len - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__imlib_BlendSpanToRGB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  jmp    L11
L14:
  lea    -0x14(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x20(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    -0x14(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  sub    $0xffffff80,%eax
  shr    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  add    %ecx,%edx
  mov    %dl,(%rax)
  lea    -0x14(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x20(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    -0x14(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  sub    $0xffffff80,%eax
  shr    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  add    %ecx,%edx
  mov    %dl,(%rax)
  lea    -0x14(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    %eax,%edx
  lea    -0x14(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  sub    $0xffffff80,%eax
  shr    $0x8,%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x4,-0x20(%rbp)
L11:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __imlib_BlendSpanToRGB(unsigned int color, unsigned int *dst, int len) {
  while (len--) {
    unsigned int tmp;
    tmp = ((((unsigned char *)(&color))[2]) - (((unsigned char *)(dst))[2])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[2] = (((unsigned char *)(dst))[2]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    tmp = ((((unsigned char *)(&color))[1]) - (((unsigned char *)(dst))[1])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[1] = (((unsigned char *)(dst))[1]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    tmp = ((((unsigned char *)(&color))[0]) - (((unsigned char *)(dst))[0])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[0] = (((unsigned char *)(dst))[0]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    ;
    dst++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__imlib_BlendSpanToRGB>:
  endbr64
  test   %edx,%edx
  je     L19
  push   %rbx
  mov    %rsi,%rax
  mov    %edx,%edx
  lea    (%rsi,%rdx,4),%r9
  mov    %edi,%esi
  shr    $0x18,%esi
  mov    %edi,%r8d
  shr    $0x10,%r8d
  movzbl %r8b,%r8d
  mov    %edi,%ebx
  movzbl %bh,%ebx
  movzbl %dil,%edi
L12:
  movzbl 0x2(%rax),%edx
  movzbl %dl,%r10d
  mov    %r8d,%ecx
  sub    %r10d,%ecx
  imul   %esi,%ecx
  mov    %ecx,%r10d
  shr    $0x8,%r10d
  lea    0x80(%rcx,%r10,1),%ecx
  shr    $0x8,%ecx
  add    %ecx,%edx
  mov    %dl,0x2(%rax)
  movzbl 0x1(%rax),%edx
  movzbl %dl,%r10d
  mov    %ebx,%ecx
  sub    %r10d,%ecx
  imul   %esi,%ecx
  mov    %ecx,%r10d
  shr    $0x8,%r10d
  lea    0x80(%rcx,%r10,1),%ecx
  shr    $0x8,%ecx
  add    %ecx,%edx
  mov    %dl,0x1(%rax)
  movzbl (%rax),%edx
  movzbl %dl,%r10d
  mov    %edi,%ecx
  sub    %r10d,%ecx
  imul   %esi,%ecx
  mov    %ecx,%r10d
  shr    $0x8,%r10d
  lea    0x80(%rcx,%r10,1),%ecx
  shr    $0x8,%ecx
  add    %ecx,%edx
  mov    %dl,(%rax)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L12
  pop    %rbx
  ret
L19:
  ret
```

assistant: ```c
void __imlib_BlendSpanToRGB(unsigned int color, unsigned int *dst, int len) {
  while (len--) {
    unsigned int tmp;
    tmp = ((((unsigned char *)(&color))[2]) - (((unsigned char *)(dst))[2])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[2] = (((unsigned char *)(dst))[2]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    tmp = ((((unsigned char *)(&color))[1]) - (((unsigned char *)(dst))[1])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[1] = (((unsigned char *)(dst))[1]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    tmp = ((((unsigned char *)(&color))[0]) - (((unsigned char *)(dst))[0])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[0] = (((unsigned char *)(dst))[0]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    ;
    dst++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__imlib_BlendSpanToRGB>:
  endbr64
  mov    %rsi,%rax
  test   %edx,%edx
  je     L6
  mov    %edi,%r8d
  mov    %edi,%ecx
  mov    %edi,%esi
  mov    %edx,%edx
  shr    $0x10,%r8d
  movzbl %ch,%ecx
  shr    $0x18,%esi
  movzbl %dil,%edi
  movzbl %r8b,%r8d
  mov    %ecx,%r10d
  lea    (%rax,%rdx,4),%r9
  nopl   0x0(%rax)
L4:
  movzbl 0x2(%rax),%r11d
  mov    %r8d,%ecx
  add    $0x4,%rax
  sub    %r11d,%ecx
  mov    %r11d,%edx
  imul   %esi,%ecx
  mov    %ecx,%r11d
  shr    $0x8,%r11d
  lea    0x80(%rcx,%r11,1),%ecx
  movzbl -0x3(%rax),%r11d
  shr    $0x8,%ecx
  add    %ecx,%edx
  mov    %r10d,%ecx
  sub    %r11d,%ecx
  mov    %dl,-0x2(%rax)
  mov    %r11d,%edx
  imul   %esi,%ecx
  mov    %ecx,%r11d
  shr    $0x8,%r11d
  lea    0x80(%rcx,%r11,1),%ecx
  movzbl -0x4(%rax),%r11d
  shr    $0x8,%ecx
  add    %ecx,%edx
  mov    %edi,%ecx
  sub    %r11d,%ecx
  mov    %dl,-0x3(%rax)
  mov    %r11d,%edx
  imul   %esi,%ecx
  mov    %ecx,%r11d
  shr    $0x8,%r11d
  lea    0x80(%rcx,%r11,1),%ecx
  shr    $0x8,%ecx
  add    %ecx,%edx
  mov    %dl,-0x4(%rax)
  cmp    %r9,%rax
  jne    L4
L6:
  ret
```

assistant: ```c
void __imlib_BlendSpanToRGB(unsigned int color, unsigned int *dst, int len) {
  while (len--) {
    unsigned int tmp;
    tmp = ((((unsigned char *)(&color))[2]) - (((unsigned char *)(dst))[2])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[2] = (((unsigned char *)(dst))[2]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    tmp = ((((unsigned char *)(&color))[1]) - (((unsigned char *)(dst))[1])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[1] = (((unsigned char *)(dst))[1]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    tmp = ((((unsigned char *)(&color))[0]) - (((unsigned char *)(dst))[0])) * (((unsigned char *)(&color))[3]);
    ((unsigned char *)(dst))[0] = (((unsigned char *)(dst))[0]) + ((tmp + (tmp >> 8) + 0x80) >> 8);
    ;
    ;
    dst++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <erroFatalMemoria@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcalloc(size_t n, size_t t) {
  void *p = calloc(n, t);
  if (!p)
    erroFatalMemoria();
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xcalloc>:
  endbr64
  push   %rbx
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L19:
  mov    %rbx,%rax
  pop    %rbx
  ret
L2:
  mov    $0x0,%eax
  call   <erroFatalMemoria@plt>
  jmp    L19
```

assistant: ```c
void *xcalloc(size_t n, size_t t) {
  void *p = calloc(n, t);
  if (!p)
    erroFatalMemoria();
  return p;
}
```