ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<max_right>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  lea    0x1(%rdx),%esi
  cmp    %edi,%esi
  jge    L68
  mov    %edi,%eax
  sub    %edx,%eax
  lea    -0x1(%rax),%r9d
  sub    $0x2,%eax
  cmp    $0x2,%eax
  jbe    L61
  mov    %r9d,%eax
  movslq %edx,%rdx
  pxor   %xmm2,%xmm2
  shr    $0x2,%eax
  lea    0x4(%r8,%rdx,4),%rdx
  lea    -0x1(%rax),%ecx
  lea    0x10(%rdx),%rax
  shl    $0x4,%rcx
  add    %rax,%rcx
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x10,%rax
L47:
  movdqu (%rdx),%xmm0
  mov    %rax,%rdx
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L13
  movdqa %xmm2,%xmm0
  mov    %r9d,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  movdqa %xmm0,%xmm1
  add    %edx,%esi
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%r9d
  je     L55
L76:
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    (%r8,%rdx,4),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  lea    0x1(%rsi),%edx
  cmp    %edx,%edi
  jle    L4
  mov    0x4(%r8,%rcx,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x2,%esi
  cmp    %esi,%edi
  jle    L4
  mov    0x8(%r8,%rcx,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  ret
L61:
  xor    %eax,%eax
  jmp    L76
```

assistant: ```c
int max_right(int array[], int size, int pos) {
  int max = 0;
  for (int i = pos + 1; i < size; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L49
  mov    $0x1,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L49:
  movl   $0x0,-0x28(%rbp)
  jmp    L36
L12:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L36:
  cmpl   $0x0,-0x28(%rbp)
  jle    L12
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  movabs $0xffffffd17765e3ff,%rdx
  cmp    %rdx,%rax
  jne    L1
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L1:
  movl   $0x0,-0x24(%rbp)
  jmp    L29
L17:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L29:
  cmpl   $0x0,-0x24(%rbp)
  jle    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
type: string
name: parse_data
arguments: tag: D10
type: string
name: parse_data
arguments: tag: D12
type: string

tool: D24: Call this program with %i arguments


tool: D10: You win!

tool: D12: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446743873849254911UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L34
L26:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  movabs $0xffffffd17765e3ff,%rax
  cmp    %rax,0x10(%rsp)
  je     L5
L41:
  mov    0x10(%rsp),%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L26
L5:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L41
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D10
type: string

tool: D25: %lu


tool: D6: Call this program with %i arguments


tool: D10: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446743873849254911UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L31
  lea    D18(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L31:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0xffffffd17765e3ff,%rax
  cmp    %rax,%rsi
  je     L15
L33:
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L33
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D18: Call this program with %i arguments


tool: D13: %lu


tool: D2: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446743873849254911UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L39
  lea    D18(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L39:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0xffffffd17765e3ff,%rax
  cmp    %rax,%rsi
  je     L24
L19:
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L19
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D21
type_guessed: string
name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D18: Call this program with %i arguments


tool: D21: %lu


tool: D4: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446743873849254911UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L18
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L18:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L26
L38:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x0,-0x8(%rbp)
  jns    L38
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D13: Usage %s <string2reverse>


tool: 

assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  int end = 0;
  if (argc != 2) {
    printf("Usage %s <string2reverse>\n", argv[0]);
    return -1;
  }
  end = strlen(argv[1]) - 1;
  for (i = end; i >= 0; i--) {
    printf("%c", argv[1][i]);
  }
  puts("");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  cmp    $0x2,%edi
  jne    L28
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L19
  movslq %ebx,%rbx
  movslq %eax,%rbp
  sub    $0x2,%rbp
  lea    -0x1(%rax),%eax
  sub    %rax,%rbp
L9:
  mov    0x8(%r12),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <putchar@plt>
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L19:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    (%rsi),%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string

tool: 

tool: D9: Usage %s <string2reverse>


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  int end = 0;
  if (argc != 2) {
    printf("Usage %s <string2reverse>\n", argv[0]);
    return -1;
  }
  end = strlen(argv[1]) - 1;
  for (i = end; i >= 0; i--) {
    printf("%c", argv[1][i]);
  }
  puts("");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jne    L5
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L28
  movslq %eax,%rbp
  movslq %edx,%rbx
  mov    %edx,%edx
  sub    $0x2,%rbp
  sub    %rdx,%rbp
  nop
L8:
  mov    0x8(%r12),%rax
  movsbl (%rax,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L8
L28:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: 

tool: D1: Usage %s <string2reverse>


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  int end = 0;
  if (argc != 2) {
    printf("Usage %s <string2reverse>\n", argv[0]);
    return -1;
  }
  end = strlen(argv[1]) - 1;
  for (i = end; i >= 0; i--) {
    printf("%c", argv[1][i]);
  }
  puts("");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jne    L31
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L34
  movslq %eax,%rbp
  movslq %edx,%rbx
  mov    %edx,%edx
  sub    $0x2,%rbp
  sub    %rdx,%rbp
  nop
L17:
  mov    0x8(%r12),%rax
  movsbl (%rax,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L17
L34:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    (%rsi),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L24
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D10
type: string

tool: 

tool: D10: Usage %s <string2reverse>


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  int end = 0;
  if (argc != 2) {
    printf("Usage %s <string2reverse>\n", argv[0]);
    return -1;
  }
  end = strlen(argv[1]) - 1;
  for (i = end; i >= 0; i--) {
    printf("%c", argv[1][i]);
  }
  puts("");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L48
L11:
  addq   $0x1,-0x28(%rbp)
L48:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  je     L32
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L32:
  mov    -0x28(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L57
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L38
L57:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x48(%rbp)
  ja     L36
  mov    -0x48(%rbp),%rax
  sub    -0x10(%rbp),%rax
  sub    $0x1,%rax
  jmp    L68
L36:
  mov    -0x18(%rbp),%rax
L68:
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bcopy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L38:
  leave
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t dstsize) {
  char *df = dst;
  size_t left = dstsize;
  size_t l1;
  size_t l2 = strlen(src);
  size_t copied;
  while (left-- != 0 && *df != '\0')
    df++;
  l1 = df - dst;
  if (dstsize == l1)
    return (l1 + l2);
  copied = l1 + l2 >= dstsize ? dstsize - l1 - 1 : l2;
  bcopy(src, dst + l1, copied);
  dst[l1 + copied] = '\0';
  return (l1 + l2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlcat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %r12,%r12
  je     L33
  mov    %rax,%r15
  lea    -0x1(%r12),%rcx
  lea    (%rbx,%r12,1),%rdx
  mov    %rbx,%rsi
L47:
  cmpb   $0x0,(%rsi)
  je     L37
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  jne    L47
  mov    %rdx,%rsi
L37:
  mov    %rsi,%r14
  sub    %rbx,%r14
  cmp    %r14,%r12
  je     L18
  lea    (%rax,%r14,1),%rbp
  sub    %r14,%rcx
  cmp    %r12,%rbp
  cmovae %rcx,%r15
  mov    %r15,%rdx
  mov    %r13,%rdi
  call   <bcopy@plt>
  add    %r15,%rbx
  movb   $0x0,(%rbx,%r14,1)
L28:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    %r12,%r14
L18:
  lea    (%rax,%r14,1),%rbp
  jmp    L28
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t dstsize) {
  char *df = dst;
  size_t left = dstsize;
  size_t l1;
  size_t l2 = strlen(src);
  size_t copied;
  while (left-- != 0 && *df != '\0')
    df++;
  l1 = df - dst;
  if (dstsize == l1)
    return (l1 + l2);
  copied = l1 + l2 >= dstsize ? dstsize - l1 - 1 : l2;
  bcopy(src, dst + l1, copied);
  dst[l1 + copied] = '\0';
  return (l1 + l2);
}
```
user: What is the c source code of the assembly code below:

```asm
<strlcat>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  test   %rbx,%rbx
  je     L46
  mov    %rax,%r8
  lea    -0x1(%rbx),%r14
  lea    0x0(%rbp,%rbx,1),%rcx
  mov    %rbp,%rsi
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L66:
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  je     L29
L41:
  cmpb   $0x0,(%rsi)
  jne    L66
L29:
  mov    %rsi,%rdx
  sub    %rbp,%rdx
  lea    (%rax,%rdx,1),%r12
  cmp    %rdx,%rbx
  je     L1
  cmp    %r12,%rbx
  jbe    L5
  mov    %r12,%r14
L45:
  mov    %r8,%rdx
  mov    %r13,%rdi
  call   <bcopy@plt>
  movb   $0x0,0x0(%rbp,%r14,1)
L1:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r14,%r8
  sub    %rdx,%r8
  jmp    L45
L46:
  mov    %rax,%r12
  jmp    L1
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t dstsize) {
  char *df = dst;
  size_t left = dstsize;
  size_t l1;
  size_t l2 = strlen(src);
  size_t copied;
  while (left-- != 0 && *df != '\0')
    df++;
  l1 = df - dst;
  if (dstsize == l1)
    return (l1 + l2);
  copied = l1 + l2 >= dstsize ? dstsize - l1 - 1 : l2;
  bcopy(src, dst + l1, copied);
  dst[l1 + copied] = '\0';
  return (l1 + l2);
}
```
user: What is the c source code of the assembly code below:

```asm
<strlcat>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  test   %rbx,%rbx
  je     L79
  mov    %rax,%r8
  lea    -0x1(%rbx),%r14
  lea    0x0(%rbp,%rbx,1),%rcx
  mov    %rbp,%rsi
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  je     L16
L58:
  cmpb   $0x0,(%rsi)
  jne    L40
L16:
  mov    %rsi,%rdx
  sub    %rbp,%rdx
  lea    (%rax,%rdx,1),%r12
  cmp    %rdx,%rbx
  je     L31
  cmp    %r12,%rbx
  jbe    L32
  mov    %r12,%r14
L38:
  mov    %r8,%rdx
  mov    %r13,%rdi
  call   <bcopy@plt>
  movb   $0x0,0x0(%rbp,%r14,1)
L31:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r14,%r8
  sub    %rdx,%r8
  jmp    L38
L79:
  mov    %rax,%r12
  jmp    L31
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t dstsize) {
  char *df = dst;
  size_t left = dstsize;
  size_t l1;
  size_t l2 = strlen(src);
  size_t copied;
  while (left-- != 0 && *df != '\0')
    df++;
  l1 = df - dst;
  if (dstsize == l1)
    return (l1 + l2);
  copied = l1 + l2 >= dstsize ? dstsize - l1 - 1 : l2;
  bcopy(src, dst + l1, copied);
  dst[l1 + copied] = '\0';
  return (l1 + l2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0xffffffff,%eax
  jmp    L108
L38:
  cmpq   $0x0,-0x10(%rbp)
  jne    L65
  mov    $0x1,%eax
  jmp    L108
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    $0x0,%eax
  jmp    L108
L13:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L65:
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  cmpq   $0x0,-0x10(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L5
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L108:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  if (s1 == NULL)
    return -1;
  if (s2 == NULL)
    return 1;
  while (s1 && s2 && *s1 && *s2 && *s1 == *s2) {
    if (*s1 == 0)
      return 0;
    s1++;
    s2++;
  }
  return *(unsigned const char *)s1 - *(unsigned const char *)(s2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcmp>:
  endbr64
L2:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L8
  cmp    %dl,%al
  jne    L8
  add    $0x1,%rdi
  add    $0x1,%rsi
  jmp    L2
L8:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  if (s1 == NULL)
    return -1;
  if (s2 == NULL)
    return 1;
  while (s1 && s2 && *s1 && *s2 && *s1 == *s2) {
    if (*s1 == 0)
      return 0;
    s1++;
    s2++;
  }
  return *(unsigned const char *)s1 - *(unsigned const char *)(s2);
}
```