ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_strv>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L23
  lea    0x8(%rbp),%rbx
  xchg   %ax,%ax
L5:
  call   <free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L5
L23:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
  nop
L28:
  ret
```

assistant: ```c
void free_strv(char *strv[]) {
  if (!strv)
    return;
  for (int i = 0; strv[i]; i++) {
    free(strv[i]);
  }
  free(strv);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_strv>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L12
  lea    0x8(%rbp),%rbx
  xchg   %ax,%ax
L4:
  call   <free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L4
L12:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
  nop
L11:
  ret
```

assistant: ```c
void free_strv(char *strv[]) {
  if (!strv)
    return;
  for (int i = 0; strv[i]; i++) {
    free(strv[i]);
  }
  free(strv);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<group>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <group_part@plt>
  jmp    L11
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <group_part@plt>
L11:
  mov    $0x0,%eax
  call   <is_group_part@plt>
  test   %rax,%rax
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void group(int skip) {
  group_part(skip);
  while (is_group_part())
    group_part(skip);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<group>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <group_part@plt>
  jmp    L9
L12:
  mov    %ebx,%edi
  call   <group_part@plt>
L9:
  mov    $0x0,%eax
  call   <is_group_part@plt>
  test   %rax,%rax
  jne    L12
  pop    %rbx
  ret
```

assistant: ```c
void group(int skip) {
  group_part(skip);
  while (is_group_part())
    group_part(skip);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<group>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <group_part@plt>
  jmp    L12
  xchg   %ax,%ax
L14:
  mov    %ebx,%edi
  call   <group_part@plt>
L12:
  xor    %eax,%eax
  call   <is_group_part@plt>
  test   %rax,%rax
  jne    L14
  pop    %rbx
  ret
```

assistant: ```c
void group(int skip) {
  group_part(skip);
  while (is_group_part())
    group_part(skip);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<group>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <group_part@plt>
  jmp    L16
  xchg   %ax,%ax
L10:
  mov    %ebx,%edi
  call   <group_part@plt>
L16:
  xor    %eax,%eax
  call   <is_group_part@plt>
  test   %rax,%rax
  jne    L10
  pop    %rbx
  ret
```

assistant: ```c
void group(int skip) {
  group_part(skip);
  while (is_group_part())
    group_part(skip);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_scanned_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L36
L32:
  addq   $0x1,-0x20(%rbp)
L36:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L18
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L32
L18:
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jne    L12
  mov    -0x38(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L33
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L67
L70:
  addq   $0x1,-0x20(%rbp)
L67:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L31
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L70
L31:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L33:
  leave
  ret
```

assistant: ```c
char *copy_scanned_argument(char **pointer, char *end_of_cmd) {
  char *scanner = *pointer;
  while (*scanner == ' ' && scanner < end_of_cmd)
    scanner++;
  if (scanner == end_of_cmd) {
    *pointer = scanner;
    return NULL;
  } else {
    char *arg_start = scanner;
    while (*scanner != ' ' && scanner < end_of_cmd)
      scanner++;
    char *arg_end = scanner;
    *pointer = scanner;
    int argsize = arg_end - arg_start;
    char *narg = (char *)malloc(argsize + 1);
    strncpy(narg, arg_start, argsize);
    narg[argsize] = '\0';
    return narg;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_scanned_argument>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  cmpb   $0x20,(%rbx)
  jne    L43
  cmp    %rsi,%rbx
  jae    L43
L70:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  jne    L43
  cmp    %rbx,%rsi
  ja     L70
L43:
  cmp    %rbx,%rsi
  je     L77
  cmpb   $0x20,(%rbx)
  je     L61
  mov    %rbx,%rax
  cmp    %rbx,%rsi
  jbe    L61
L97:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L9
  cmp    %rax,%rsi
  ja     L97
L9:
  mov    %rax,(%rdi)
  sub    %rbx,%rax
  mov    %rax,%rbp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
L109:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  mov    %rbx,%rax
  jmp    L9
L77:
  mov    %rbx,(%rdi)
  mov    $0x0,%r12d
  jmp    L109
```

assistant: ```c
char *copy_scanned_argument(char **pointer, char *end_of_cmd) {
  char *scanner = *pointer;
  while (*scanner == ' ' && scanner < end_of_cmd)
    scanner++;
  if (scanner == end_of_cmd) {
    *pointer = scanner;
    return NULL;
  } else {
    char *arg_start = scanner;
    while (*scanner != ' ' && scanner < end_of_cmd)
      scanner++;
    char *arg_end = scanner;
    *pointer = scanner;
    int argsize = arg_end - arg_start;
    char *narg = (char *)malloc(argsize + 1);
    strncpy(narg, arg_start, argsize);
    narg[argsize] = '\0';
    return narg;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copy_scanned_argument>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  cmpb   $0x20,0x0(%rbp)
  jne    L95
  cmp    %rsi,%rbp
  jb     L71
  jmp    L95
  xchg   %ax,%ax
L50:
  cmp    %rbp,%rsi
  jbe    L95
L71:
  add    $0x1,%rbp
  cmpb   $0x20,0x0(%rbp)
  je     L50
L95:
  cmp    %rbp,%rsi
  je     L10
  cmpb   $0x20,0x0(%rbp)
  je     L81
  mov    %rbp,%rax
  cmp    %rbp,%rsi
  ja     L45
  jmp    L81
  nopl   0x0(%rax)
L77:
  cmp    %rax,%rsi
  jbe    L3
L45:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  jne    L77
L3:
  mov    %rax,%rdx
  sub    %rbp,%rdx
  mov    %edx,%r13d
  lea    0x1(%rdx),%r8d
  movslq %edx,%rbx
L107:
  mov    %rax,(%rdi)
  mov    %r8d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L10:
  mov    %rsi,(%rdi)
  xor    %r12d,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L81:
  mov    %rbp,%rax
  xor    %ebx,%ebx
  mov    $0x1,%r8d
  xor    %r13d,%r13d
  jmp    L107
```

assistant: ```c
char *copy_scanned_argument(char **pointer, char *end_of_cmd) {
  char *scanner = *pointer;
  while (*scanner == ' ' && scanner < end_of_cmd)
    scanner++;
  if (scanner == end_of_cmd) {
    *pointer = scanner;
    return NULL;
  } else {
    char *arg_start = scanner;
    while (*scanner != ' ' && scanner < end_of_cmd)
      scanner++;
    char *arg_end = scanner;
    *pointer = scanner;
    int argsize = arg_end - arg_start;
    char *narg = (char *)malloc(argsize + 1);
    strncpy(narg, arg_start, argsize);
    narg[argsize] = '\0';
    return narg;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_scanned_argument>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  movzbl 0x0(%rbp),%eax
  cmp    %rsi,%rbp
  setb   %dl
  cmp    $0x20,%al
  je     L93
  jmp    L89
  nopl   0x0(%rax)
L12:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  cmp    %rbp,%rsi
  seta   %dl
  cmp    $0x20,%al
  jne    L89
L93:
  test   %dl,%dl
  jne    L12
L89:
  cmp    %rbp,%rsi
  je     L64
  cmp    $0x20,%al
  je     L32
  mov    %rbp,%rax
  test   %dl,%dl
  jne    L42
  jmp    L32
L18:
  cmp    %rax,%rsi
  jbe    L109
L42:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  jne    L18
L109:
  mov    %rax,%rdx
  sub    %rbp,%rdx
  mov    %edx,%r13d
  lea    0x1(%rdx),%r8d
  movslq %edx,%rbx
L88:
  mov    %rax,(%rdi)
  mov    %r8d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L64:
  mov    %rsi,(%rdi)
  xor    %r12d,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %rbp,%rax
  xor    %ebx,%ebx
  mov    $0x1,%r8d
  xor    %r13d,%r13d
  jmp    L88
```

assistant: ```c
char *copy_scanned_argument(char **pointer, char *end_of_cmd) {
  char *scanner = *pointer;
  while (*scanner == ' ' && scanner < end_of_cmd)
    scanner++;
  if (scanner == end_of_cmd) {
    *pointer = scanner;
    return NULL;
  } else {
    char *arg_start = scanner;
    while (*scanner != ' ' && scanner < end_of_cmd)
      scanner++;
    char *arg_end = scanner;
    *pointer = scanner;
    int argsize = arg_end - arg_start;
    char *narg = (char *)malloc(argsize + 1);
    strncpy(narg, arg_start, argsize);
    narg[argsize] = '\0';
    return narg;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<iround>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L8
  movsd  -0x8(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L13
L8:
  movsd  -0x8(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
L13:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: f64

tool: D9: 0.5

assistant: ```c
int iround(double x) {
  if (x < 0.0) {
    return (int)(x - 0.5);
  } else {
    return (int)(x + 0.5);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<iround>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
  addsd  D18(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
L6:
  subsd  D18(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: f64

tool: D18: 0.5

assistant: ```c
int iround(double x) {
  if (x < 0.0) {
    return (int)(x - 0.5);
  } else {
    return (int)(x + 0.5);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iround>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L9
  addsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  subsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type: f64

tool: D5: 0.5

assistant: ```c
int iround(double x) {
  if (x < 0.0) {
    return (int)(x - 0.5);
  } else {
    return (int)(x + 0.5);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<iround>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L0
  addsd  D16(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  subsd  D16(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
datatype: f64

tool: D16: 0.5

assistant: ```c
int iround(double x) {
  if (x < 0.0) {
    return (int)(x - 0.5);
  } else {
    return (int)(x + 0.5);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<q_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D10(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x24(%rbp),%xmm1
  movss  D4(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sar    %rax
  mov    %rax,%rdx
  mov    $0x5f3759df,%eax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x14(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x14(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_infered: byte[4]
name: read_data
arguments: label: D4
type_infered: byte[4]

tool: {"D10": [0x00,0x00,0xc0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float q_sqrt(float number) {
  long i;
  float x2, y;
  const float threehalfs = 1.5F;
  x2 = number * 0.5F;
  y = number;
  i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (threehalfs - (x2 * y * y));
  y = y * (threehalfs - (x2 * y * y));
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<q_sqrt>:
  endbr64
  movaps %xmm0,%xmm1
  mulss  D0(%rip),%xmm1
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%rdx
  sar    %rdx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  movd   %eax,%xmm3
  movd   %eax,%xmm4
  mulss  %xmm1,%xmm4
  mulss  %xmm3,%xmm4
  movss  D14(%rip),%xmm0
  movaps %xmm0,%xmm2
  subss  %xmm4,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x3f]}

tool: {"D14": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float q_sqrt(float number) {
  long i;
  float x2, y;
  const float threehalfs = 1.5F;
  x2 = number * 0.5F;
  y = number;
  i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (threehalfs - (x2 * y * y));
  y = y * (threehalfs - (x2 * y * y));
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<q_sqrt>:
  endbr64
  movss  D16(%rip),%xmm1
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%rdx
  mov    $0x5f3759df,%eax
  mulss  %xmm0,%xmm1
  sar    %rdx
  movss  D0(%rip),%xmm0
  sub    %edx,%eax
  movd   %eax,%xmm4
  movd   %eax,%xmm3
  movaps %xmm0,%xmm2
  mulss  %xmm1,%xmm4
  mulss  %xmm3,%xmm4
  subss  %xmm4,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
data_type: byte[4]
name: disassemble_data
arguments: data_tag: D0
data_type: byte[4]

tool: {"D16": [0x00,0x00,0x00,0x3f]}

tool: {"D0": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float q_sqrt(float number) {
  long i;
  float x2, y;
  const float threehalfs = 1.5F;
  x2 = number * 0.5F;
  y = number;
  i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (threehalfs - (x2 * y * y));
  y = y * (threehalfs - (x2 * y * y));
  return y;
}
```
user: What is the c source code of the assembly code below?

```asm
<q_sqrt>:
  endbr64
  movss  D9(%rip),%xmm1
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%rdx
  mov    $0x5f3759df,%eax
  mulss  %xmm0,%xmm1
  sar    %rdx
  movss  D11(%rip),%xmm0
  sub    %edx,%eax
  movd   %eax,%xmm4
  movd   %eax,%xmm3
  movaps %xmm0,%xmm2
  mulss  %xmm1,%xmm4
  mulss  %xmm3,%xmm4
  subss  %xmm4,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x3f]}

tool: {"D11": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float q_sqrt(float number) {
  long i;
  float x2, y;
  const float threehalfs = 1.5F;
  x2 = number * 0.5F;
  y = number;
  i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (threehalfs - (x2 * y * y));
  y = y * (threehalfs - (x2 * y * y));
  return y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rfact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  jg     L0
  movq   $0x1,-0x8(%rbp)
  jmp    L18
L0:
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <rfact>
  mov    -0x18(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long rfact(long n) {
  long result;
  if (n <= 1) {
    result = 1;
  } else {
    result = n * rfact(n - 1);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rfact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%rdi
  jg     L5
  ret
L5:
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rdi
  call   <rfact>
  imul   %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long rfact(long n) {
  long result;
  if (n <= 1) {
    result = 1;
  } else {
    result = n * rfact(n - 1);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rfact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%rdi
  jle    L2
  nop
L11:
  mov    %rdi,%rdx
  sub    $0x1,%rdi
  imul   %rdx,%rax
  cmp    $0x1,%rdi
  jne    L11
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
long rfact(long n) {
  long result;
  if (n <= 1) {
    result = 1;
  } else {
    result = n * rfact(n - 1);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rfact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%rdi
  jle    L8
  nop
L6:
  mov    %rdi,%rdx
  sub    $0x1,%rdi
  imul   %rdx,%rax
  cmp    $0x1,%rdi
  jne    L6
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
long rfact(long n) {
  long result;
  if (n <= 1) {
    result = 1;
  } else {
    result = n * rfact(n - 1);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L2
L21:
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L2:
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L21
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D28: Enter n1 and n2 

tool: D27: %d%d

tool: D0: GCD and LCM of %d and %d are %d and %d respectively


assistant: ```c
main() {
  int gcd, lcm, n1, n2, num1, num2, r;
  printf("Enter n1 and n2 \n");
  scanf("%d%d", &n1, &n2);
  num1 = n1;
  num2 = n2;
  while (n1 % n2 != 0) {
    r = n1 % n2;
    n1 = n2;
    n2 = r;
  }
  gcd = n2;
  lcm = (num1 * num2) / gcd;
  printf("GCD and LCM of %d and %d are %d and %d respectively\n", num1, num2, gcd, lcm);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r10d
  mov    %esi,%eax
  cltd
  idiv   %r10d
  test   %edx,%edx
  je     L10
  mov    %edx,%ecx
  mov    %r10d,%edi
  jmp    L15
L44:
  mov    %r9d,%edi
L15:
  mov    %ecx,%r9d
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L44
  mov    %edi,(%rsp)
  mov    %r9d,0x4(%rsp)
L3:
  mov    %esi,%eax
  imul   %r10d,%eax
  cltd
  idiv   %r9d
  mov    %eax,%r8d
  mov    %r9d,%ecx
  mov    %r10d,%edx
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L10:
  mov    %r10d,%r9d
  jmp    L3
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D22
type_infered: string

tool: D10: Enter n1 and n2 

tool: D3: %d%d

tool: D22: GCD and LCM of %d and %d are %d and %d respectively


assistant: ```c
main() {
  int gcd, lcm, n1, n2, num1, num2, r;
  printf("Enter n1 and n2 \n");
  scanf("%d%d", &n1, &n2);
  num1 = n1;
  num2 = n2;
  while (n1 % n2 != 0) {
    r = n1 % n2;
    n1 = n2;
    n2 = r;
  }
  gcd = n2;
  lcm = (num1 * num2) / gcd;
  printf("GCD and LCM of %d and %d are %d and %d respectively\n", num1, num2, gcd, lcm);
}
```