ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<mbstowcs>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%r14
  test   %eax,%eax
  je     L18
  cltq
  add    $0x1,%r12
  add    %rax,%r15
L13:
  mov    %rbx,%rdx
  lea    0x0(%rbp,%r15,1),%rsi
  mov    %r14,%rdi
  mov    %r14,%r13
  sub    %r15,%rdx
  call   <mbtowc@plt>
  test   %eax,%eax
  jns    L7
  mov    $0xffffffffffffffff,%r12
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L18:
  movq   $0x0,0x0(%r13)
  jmp    L8
```

assistant: ```c
size_t mbstowcs(wchar_t *dest, const char *src, size_t max) {
  size_t total = 0;
  size_t read = 0;
  while (1) {
    int bytes = mbtowc(&dest[total], &src[read], max - read);
    if (bytes < 0)
      return (size_t)-1;
    if (bytes == 0) {
      dest[total] = 0;
      break;
    }
    ++total;
    read += bytes;
  };
  return total;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get__PIO_PCx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L19:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  shl    $0x4,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <readl@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x2,-0xc(%rbp)
  jle    L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long get__PIO_PCx(void *base, int pin) {
  unsigned long result = 0;
  int i;
  for (i = 0; i <= 2; i++)
    result |= ((readl(base + (0x20 + (i)*0x10)) >> pin) & 0x1) << i;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get__PIO_PCx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  lea    0x20(%rdi),%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
L9:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <readl@plt>
  mov    %r13d,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  cltq
  or     %rax,%r12
  add    $0x1,%ebx
  add    $0x10,%rbp
  cmp    $0x3,%ebx
  jne    L9
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long get__PIO_PCx(void *base, int pin) {
  unsigned long result = 0;
  int i;
  for (i = 0; i <= 2; i++)
    result |= ((readl(base + (0x20 + (i)*0x10)) >> pin) & 0x1) << i;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<get__PIO_PCx>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    0x20(%rdi),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
L8:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x10,%r12
  call   <readl@plt>
  mov    %ebx,%ecx
  sar    %cl,%eax
  mov    %ebp,%ecx
  add    $0x1,%ebp
  and    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r13
  cmp    $0x3,%ebp
  jne    L8
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long get__PIO_PCx(void *base, int pin) {
  unsigned long result = 0;
  int i;
  for (i = 0; i <= 2; i++)
    result |= ((readl(base + (0x20 + (i)*0x10)) >> pin) & 0x1) << i;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get__PIO_PCx>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    0x20(%rdi),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
L4:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x10,%r12
  call   <readl@plt>
  mov    %ebx,%ecx
  sar    %cl,%eax
  mov    %ebp,%ecx
  add    $0x1,%ebp
  and    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r13
  cmp    $0x3,%ebp
  jne    L4
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long get__PIO_PCx(void *base, int pin) {
  unsigned long result = 0;
  int i;
  for (i = 0; i <= 2; i++)
    result |= ((readl(base + (0x20 + (i)*0x10)) >> pin) & 0x1) << i;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  putc('\n', stderr);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<debug>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D4(%rip),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    (%r12),%edi
  call   <vfprintf@plt>
  mov    (%r12),%esi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  putc('\n', stderr);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<debug>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D6(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  putc('\n', stderr);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<debug>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D8(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  putc('\n', stderr);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sortNumbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
L19:
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L39
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L27
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L32
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0x0,-0xc(%rbp)
  je     L40
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <printNumbers@plt>
L40:
  cmpl   $0x0,-0xc(%rbp)
  jne    L19
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: !!!! FERTIG nach %d Durchlaeufen !!!!!

assistant: ```c
int sortNumbers(int n1, int n2, int n3, int n4) {
  int getauscht, count = 0;
  do {
    int tmp;
    getauscht = 0;
    if (n1 > n2) {
      tmp = n1;
      n1 = n2;
      n2 = tmp;
      getauscht = 1;
    }
    if (n2 > n3) {
      tmp = n2;
      n2 = n3;
      n3 = tmp;
      getauscht = 1;
    }
    if (n3 > n4) {
      tmp = n3;
      n3 = n4;
      n4 = tmp;
      getauscht = 1;
    }
    if (getauscht)
      printNumbers(n1, n2, n3, n4, ++count);
  } while (getauscht);
  printf("!!!! FERTIG nach %d Durchlaeufen !!!!!", count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortNumbers>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  jmp    L16
L17:
  mov    %r13d,%eax
  mov    %ebp,%r13d
  mov    %eax,%ebp
L29:
  add    $0x1,%r14d
  mov    %r14d,%r8d
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <printNumbers@plt>
  mov    %ebp,%eax
  mov    %r13d,%ebp
  mov    %eax,%r13d
L16:
  mov    %r15d,%eax
  cmp    %ebx,%r12d
  jle    L1
  mov    %r12d,%eax
  mov    %ebx,%r12d
  mov    %eax,%ebx
  mov    $0x1,%eax
L1:
  cmp    %ebp,%ebx
  jle    L32
  mov    %ebx,%eax
  mov    %ebp,%ebx
  mov    %eax,%ebp
  mov    $0x1,%eax
L32:
  cmp    %r13d,%ebp
  jg     L29
  test   %eax,%eax
  jne    L17
  mov    %r14d,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: !!!! FERTIG nach %d Durchlaeufen !!!!!

assistant: ```c
int sortNumbers(int n1, int n2, int n3, int n4) {
  int getauscht, count = 0;
  do {
    int tmp;
    getauscht = 0;
    if (n1 > n2) {
      tmp = n1;
      n1 = n2;
      n2 = tmp;
      getauscht = 1;
    }
    if (n2 > n3) {
      tmp = n2;
      n2 = n3;
      n3 = tmp;
      getauscht = 1;
    }
    if (n3 > n4) {
      tmp = n3;
      n3 = n4;
      n4 = tmp;
      getauscht = 1;
    }
    if (getauscht)
      printNumbers(n1, n2, n3, n4, ++count);
  } while (getauscht);
  printf("!!!! FERTIG nach %d Durchlaeufen !!!!!", count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortNumbers>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
L76:
  cmp    %ebx,%r12d
  jg     L88
  cmp    %ebp,%ebx
  jg     L13
  cmp    %r13d,%ebp
  jg     L69
  pop    %rbx
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L88:
  cmp    %ebp,%r12d
  jg     L37
  cmp    %r13d,%ebp
  mov    %ebp,%eax
  mov    %r12d,%ebp
  mov    %ebx,%r12d
  jg     L74
  mov    %r13d,%ebx
  mov    %eax,%r13d
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%r14d
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r14d,%r8d
  mov    %r12d,%edi
  call   <printNumbers@plt>
  mov    %ebx,%eax
  mov    %ebp,%ebx
  mov    %r13d,%ebp
  mov    %eax,%r13d
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r12d,%eax
  mov    %ebx,%r12d
  mov    %eax,%ebx
L13:
  cmp    %ebx,%r13d
  jl     L6
  mov    %r13d,%eax
  mov    %ebx,%r13d
L74:
  mov    %eax,%ebx
  jmp    L6
  nop
L69:
  mov    %ebp,%eax
  mov    %ebx,%ebp
  mov    %eax,%ebx
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string

tool: D1: !!!! FERTIG nach %d Durchlaeufen !!!!!

assistant: ```c
int sortNumbers(int n1, int n2, int n3, int n4) {
  int getauscht, count = 0;
  do {
    int tmp;
    getauscht = 0;
    if (n1 > n2) {
      tmp = n1;
      n1 = n2;
      n2 = tmp;
      getauscht = 1;
    }
    if (n2 > n3) {
      tmp = n2;
      n2 = n3;
      n3 = tmp;
      getauscht = 1;
    }
    if (n3 > n4) {
      tmp = n3;
      n3 = n4;
      n4 = tmp;
      getauscht = 1;
    }
    if (getauscht)
      printNumbers(n1, n2, n3, n4, ++count);
  } while (getauscht);
  printf("!!!! FERTIG nach %d Durchlaeufen !!!!!", count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sortNumbers>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
L10:
  cmp    %ebx,%r12d
  jg     L22
  cmp    %ebp,%ebx
  jg     L45
  cmp    %r13d,%ebp
  jg     L47
  pop    %rbx
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L22:
  cmp    %ebp,%r12d
  jg     L80
  cmp    %r13d,%ebp
  mov    %ebp,%eax
  mov    %r12d,%ebp
  mov    %ebx,%r12d
  jg     L15
  mov    %r13d,%ebx
  mov    %eax,%r13d
  nopl   0x0(%rax,%rax,1)
L74:
  add    $0x1,%r14d
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r14d,%r8d
  mov    %r12d,%edi
  call   <printNumbers@plt>
  mov    %ebx,%eax
  mov    %ebp,%ebx
  mov    %r13d,%ebp
  mov    %eax,%r13d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L80:
  mov    %r12d,%eax
  mov    %ebx,%r12d
  mov    %eax,%ebx
L45:
  cmp    %ebx,%r13d
  jl     L74
  mov    %r13d,%eax
  mov    %ebx,%r13d
L15:
  mov    %eax,%ebx
  jmp    L74
  nop
L47:
  mov    %ebp,%eax
  mov    %ebx,%ebp
  mov    %eax,%ebx
  jmp    L74
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: !!!! FERTIG nach %d Durchlaeufen !!!!!

assistant: ```c
int sortNumbers(int n1, int n2, int n3, int n4) {
  int getauscht, count = 0;
  do {
    int tmp;
    getauscht = 0;
    if (n1 > n2) {
      tmp = n1;
      n1 = n2;
      n2 = tmp;
      getauscht = 1;
    }
    if (n2 > n3) {
      tmp = n2;
      n2 = n3;
      n3 = tmp;
      getauscht = 1;
    }
    if (n3 > n4) {
      tmp = n3;
      n3 = n4;
      n4 = tmp;
      getauscht = 1;
    }
    if (getauscht)
      printNumbers(n1, n2, n3, n4, ++count);
  } while (getauscht);
  printf("!!!! FERTIG nach %d Durchlaeufen !!!!!", count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_ts_lcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L12
L34:
  movl   $0x1,-0x4(%rbp)
  jmp    L29
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L25
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x2e,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x1,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xc0,%eax
  test   %eax,%eax
  je     L59
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <_ts_ljump@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_ts_lcopy>
  jmp    L12
L59:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_ts_lcopy>
L12:
  leave
  ret
```

assistant: ```c
void _ts_lcopy(unsigned char *a, unsigned char *label, char *host) {
  int len;
  if (*label == 0) {
    *host = 0;
    return;
  }
  for (len = 1; len <= *label; len++)
    *host++ = label[len];
  *host++ = '.';
  label += *label + 1;
  if (*label & 0xc0)
    return _ts_lcopy(a, a + _ts_ljump(label), host);
  _ts_lcopy(a, label, host);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_ts_lcopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x1,%eax
  cmpb   $0x0,(%rsi)
  je     L22
L15:
  mov    %rdx,%rdi
  add    $0x1,%rdx
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,-0x1(%rdx)
  add    $0x1,%rax
  movzbl (%rsi),%ecx
  cmp    %eax,%ecx
  jge    L15
  lea    0x2(%rdi),%rbp
  movb   $0x2e,(%rdx)
  movzbl (%rsi),%eax
  lea    0x1(%rsi,%rax,1),%rsi
  testb  $0xc0,(%rsi)
  jne    L14
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <_ts_lcopy>
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  movb   $0x0,(%rdx)
  jmp    L26
L14:
  mov    %rsi,%rdi
  call   <_ts_ljump@plt>
  movslq %eax,%rsi
  add    %rbx,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <_ts_lcopy>
  jmp    L26
```

assistant: ```c
void _ts_lcopy(unsigned char *a, unsigned char *label, char *host) {
  int len;
  if (*label == 0) {
    *host = 0;
    return;
  }
  for (len = 1; len <= *label; len++)
    *host++ = label[len];
  *host++ = '.';
  label += *label + 1;
  if (*label & 0xc0)
    return _ts_lcopy(a, a + _ts_ljump(label), host);
  _ts_lcopy(a, label, host);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_ts_lcopy>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L21
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %rbp,%rax
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rdi,%rcx,1),%esi
  mov    %rax,%rdx
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %sil,-0x1(%rax)
  movzbl (%rdi),%esi
  cmp    %ecx,%esi
  jge    L6
  movb   $0x2e,(%rax)
  movzbl (%rdi),%eax
  lea    0x2(%rdx),%rbp
  lea    0x1(%rdi,%rax,1),%rdi
  movzbl (%rdi),%eax
  test   $0xc0,%al
  jne    L27
L0:
  test   %al,%al
  jne    L41
L21:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L27:
  call   <_ts_ljump@plt>
  movslq %eax,%rdi
  add    %rbx,%rdi
  movzbl (%rdi),%eax
  jmp    L0
```

assistant: ```c
void _ts_lcopy(unsigned char *a, unsigned char *label, char *host) {
  int len;
  if (*label == 0) {
    *host = 0;
    return;
  }
  for (len = 1; len <= *label; len++)
    *host++ = label[len];
  *host++ = '.';
  label += *label + 1;
  if (*label & 0xc0)
    return _ts_lcopy(a, a + _ts_ljump(label), host);
  _ts_lcopy(a, label, host);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ts_lcopy>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L48
  nopl   (%rax)
L58:
  mov    $0x1,%eax
  nopl   (%rax)
L49:
  movzbl (%rdi,%rax,1),%ecx
  mov    %rdx,%rsi
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  movzbl (%rdi),%ecx
  cmp    %eax,%ecx
  jge    L49
  movb   $0x2e,(%rdx)
  movzbl (%rdi),%eax
  lea    0x2(%rsi),%rbp
  lea    0x1(%rdi,%rax,1),%rdi
  movzbl (%rdi),%eax
  test   $0xc0,%al
  jne    L9
  test   %al,%al
  je     L57
L38:
  mov    %rbp,%rdx
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L9:
  call   <_ts_ljump@plt>
  movslq %eax,%rdi
  add    %rbx,%rdi
  cmpb   $0x0,(%rdi)
  jne    L38
L57:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    %rdx,%rbp
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void _ts_lcopy(unsigned char *a, unsigned char *label, char *host) {
  int len;
  if (*label == 0) {
    *host = 0;
    return;
  }
  for (len = 1; len <= *label; len++)
    *host++ = label[len];
  *host++ = '.';
  label += *label + 1;
  if (*label & 0xc0)
    return _ts_lcopy(a, a + _ts_ljump(label), host);
  _ts_lcopy(a, label, host);
}
```
user: What is the c source code of the assembly code below?

```asm
<inthandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <shutdown@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <reboot@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void inthandler(int sig) {
  shutdown();
  reboot(RB_POWER_OFF);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<inthandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <shutdown@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <reboot@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void inthandler(int sig) {
  shutdown();
  reboot(RB_POWER_OFF);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inthandler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <shutdown@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <reboot@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <exit@plt>
```

assistant: ```c
void inthandler(int sig) {
  shutdown();
  reboot(RB_POWER_OFF);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inthandler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <shutdown@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <reboot@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <exit@plt>
```

assistant: ```c
void inthandler(int sig) {
  shutdown();
  reboot(RB_POWER_OFF);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<psoct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%r12d
  mov    -0x14(%rbp),%ebx
  test   %ebx,%ebx
  jns    L6
  neg    %ebx
  mov    $0x2d,%r12d
L6:
  mov    %ebx,%edx
  mov    %r12d,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: %c%o

assistant: ```c
psoct(an) {
  register int n, sign;
  sign = 0;
  if ((n = an) < 0) {
    n = -n;
    sign = '-';
  }
  printf("%c%o", sign, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<psoct>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edx
  mov    $0x0,%esi
  test   %edi,%edi
  js     L4
L5:
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L4:
  neg    %edx
  mov    $0x2d,%esi
  jmp    L5
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: %c%o

assistant: ```c
psoct(an) {
  register int n, sign;
  sign = 0;
  if ((n = an) < 0) {
    n = -n;
    sign = '-';
  }
  printf("%c%o", sign, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<psoct>:
  endbr64
  mov    %edi,%edx
  xor    %esi,%esi
  test   %edi,%edi
  jns    L2
  neg    %edx
  mov    $0x2d,%esi
L2:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %c%o

assistant: ```c
psoct(an) {
  register int n, sign;
  sign = 0;
  if ((n = an) < 0) {
    n = -n;
    sign = '-';
  }
  printf("%c%o", sign, n);
}
```