user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x642f64255f726964,%rax
  movabs $0x64252f64255f7269,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x742e6425,-0x10(%rbp)
  movw   $0x7478,-0xc(%rbp)
  movb   $0x0,-0xa(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L77
L8:
  mov    -0x38(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%ecx
  lea    D49(%rip),%rdx
  mov    $0x17,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x1ed,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L58
L61:
  mov    -0x34(%rbp),%ecx
  mov    -0x38(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  lea    D19(%rip),%rdx
  mov    $0x17,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x1ed,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  movl   $0x0,-0x30(%rbp)
  jmp    L31
L66:
  movl   $0x0,-0x2c(%rbp)
  jmp    L47
L0:
  mov    -0x30(%rbp),%edi
  mov    -0x34(%rbp),%esi
  mov    -0x38(%rbp),%edx
  lea    -0x20(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x2c(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %edx,%ecx
  lea    D29(%rip),%rdx
  mov    $0x17,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    $0x10,%rsp
  lea    -0x20(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L7
  mov    -0x28(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L7:
  addl   $0x1,-0x2c(%rbp)
L47:
  cmpl   $0x9,-0x2c(%rbp)
  jle    L0
  addl   $0x1,-0x30(%rbp)
L31:
  cmpl   $0x9,-0x30(%rbp)
  jle    L66
  addl   $0x1,-0x34(%rbp)
L58:
  cmpl   $0x27,-0x34(%rbp)
  jle    L61
  addl   $0x1,-0x38(%rbp)
L77:
  cmpl   $0x9,-0x38(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D49
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string
name: disassemble_data
arguments: data_tag: D3
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D49: dir_%d

tool: D19: dir_%d/dir_%d

tool: D29: dir_%d/dir_%d/%d%d.txt

tool: D3: w

tool: D18: dummy file.


assistant: ```c
int main(void) {
  int i, j, k, l;
  char name[] = "dir_%d/dir_%d/%d%d.txt";
  for (i = 0; i < 10; ++i) {
    snprintf(name, sizeof(name), "dir_%d", i);
    mkdir(name, 0755);
    for (j = 0; j < 40; ++j) {
      snprintf(name, sizeof(name), "dir_%d/dir_%d", i, j);
      mkdir(name, 0755);
      for (k = 0; k < 10; ++k) {
        for (l = 0; l < 10; ++l) {
          FILE *fp;
          snprintf(name, sizeof(name), "dir_%d/dir_%d/%d%d.txt", i, j, k, l);
          fp = fopen(name, "w");
          if (fp) {
            fprintf(fp, "dummy file.\n");
            fclose(fp);
          }
        }
      }
    }
  }
  return 0;
}
```