ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x4,%edx
  mov    $0xa,%esi
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D20(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D13(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <findPair@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
datatype: byte[16]
name: unpack_data
arguments: data_tag: D20
datatype: byte[8]
name: unpack_data
arguments: data_tag: D13
datatype: byte[16]

tool: {"D25": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D20": [0x09,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D13": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 2};
  findPair(a, 10, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: %d %d


assistant: ```c
main() {
  int x = 1;
  int y = 2;
  swap(&x, &y);
  printf("%d %d\n", x, y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: %d %d


assistant: ```c
main() {
  int x = 1;
  int y = 2;
  swap(&x, &y);
  printf("%d %d\n", x, y);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: %d %d


assistant: ```c
main() {
  int x = 1;
  int y = 2;
  swap(&x, &y);
  printf("%d %d\n", x, y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string

tool: D8: %d %d


assistant: ```c
main() {
  int x = 1;
  int y = 2;
  swap(&x, &y);
  printf("%d %d\n", x, y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x65,-0x1a4(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  jmp    L56
L49:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x1a8(%rbp),%xmm0
  mov    -0x1a8(%rbp),%eax
  cltq
  movss  %xmm0,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L56:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L49
  movl   $0x0,-0x1a8(%rbp)
  jmp    L53
L45:
  mov    -0x1a8(%rbp),%eax
  cltq
  movss  -0x1a0(%rbp,%rax,4),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x1a4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L65
  mov    -0x1a8(%rbp),%eax
  cltq
  movss  -0x1a0(%rbp,%rax,4),%xmm0
  cvttss2si %xmm0,%eax
  jmp    L0
L65:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x1a4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
L0:
  mov    %eax,-0x1a4(%rbp)
  addl   $0x1,-0x1a8(%rbp)
L53:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L45
  cmpl   $0x0,-0x1a4(%rbp)
  je     L41
  mov    $0x0,%eax
  call   <abort@plt>
L41:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
#pragma omp declare reduction(min:float : _out = _out > _in ? _in : _out) identity(2147483647)
  int i, x = 100 + 1;
  float a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(min : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
L4:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L4
  mov    %rsp,%rax
  lea    0x190(%rsp),%rcx
  mov    $0x65,%edx
  jmp    L48
L47:
  cvttss2si %xmm0,%edx
L25:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L50
L48:
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  comiss %xmm1,%xmm0
  jbe    L47
  cvttss2si %xmm1,%edx
  jmp    L25
L50:
  test   %edx,%edx
  jne    L35
L30:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  ret
L35:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L30
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
#pragma omp declare reduction(min:float : _out = _out > _in ? _in : _out) identity(2147483647)
  int i, x = 100 + 1;
  float a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(min : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  nopl   0x0(%rax,%rax,1)
L7:
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  movss  %xmm0,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x64,%rdx
  jne    L7
  lea    0x190(%rsp),%rcx
  mov    $0x65,%edx
  jmp    L61
  xchg   %ax,%ax
L3:
  add    $0x4,%rax
  cvttss2si %xmm1,%edx
  cmp    %rcx,%rax
  je     L8
L61:
  pxor   %xmm0,%xmm0
  movss  (%rax),%xmm1
  cvtsi2ss %edx,%xmm0
  comiss %xmm1,%xmm0
  ja     L3
  add    $0x4,%rax
  cvttss2si %xmm0,%edx
  cmp    %rcx,%rax
  jne    L61
L8:
  test   %edx,%edx
  jne    L12
L42:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L12:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L42
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
#pragma omp declare reduction(min:float : _out = _out > _in ? _in : _out) identity(2147483647)
  int i, x = 100 + 1;
  float a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(min : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  movdqa D2(%rip),%xmm1
  movdqa D12(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  mov    %rsp,%rax
  lea    0x190(%rsp),%rcx
  mov    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L78:
  movdqa %xmm1,%xmm0
  add    $0x10,%rdx
  paddd  %xmm2,%xmm1
  cvtdq2ps %xmm0,%xmm0
  movaps %xmm0,-0x10(%rdx)
  cmp    %rdx,%rcx
  jne    L78
  mov    $0x65,%edx
  jmp    L45
  nop
L66:
  add    $0x4,%rax
  cvttss2si %xmm1,%edx
  cmp    %rax,%rcx
  je     L35
L45:
  pxor   %xmm0,%xmm0
  movss  (%rax),%xmm1
  cvtsi2ss %edx,%xmm0
  comiss %xmm1,%xmm0
  ja     L66
  add    $0x4,%rax
  cvttss2si %xmm0,%edx
  cmp    %rax,%rcx
  jne    L45
L35:
  test   %edx,%edx
  jne    L44
L10:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L44:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L10
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D12
data_type: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
#pragma omp declare reduction(min:float : _out = _out > _in ? _in : _out) identity(2147483647)
  int i, x = 100 + 1;
  float a[100];
  for (i = 0; i < 100; i++)
    a[i] = i;
#pragma omp parallel for reduction(min : x)
  for (i = 0; i < 100; i++) {
    x = a[i] < x ? a[i] : x;
  }
  if (x != 0)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  movss  %xmm1,-0x10(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  movss  -0xc(%rbp),%xmm1
  movss  %xmm0,-0x10(%rbp)
  movss  %xmm1,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm0,-0x14(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
_Complex float test1(_Complex float f) {
  __asm__("" : "+r"(__real f));
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test1>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  mov    -0x8(%rsp),%eax
  mov    %eax,-0x10(%rsp)
  movss  -0x4(%rsp),%xmm0
  movss  %xmm0,-0xc(%rsp)
  movq   -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
_Complex float test1(_Complex float f) {
  __asm__("" : "+r"(__real f));
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test1>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  movss  -0x4(%rsp),%xmm0
  mov    -0x8(%rsp),%eax
  movss  %xmm0,-0xc(%rsp)
  mov    %eax,-0x10(%rsp)
  movq   -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
_Complex float test1(_Complex float f) {
  __asm__("" : "+r"(__real f));
  return f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test1>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  movss  -0x4(%rsp),%xmm0
  mov    -0x8(%rsp),%eax
  movss  %xmm0,-0xc(%rsp)
  mov    %eax,-0x10(%rsp)
  movq   -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
_Complex float test1(_Complex float f) {
  __asm__("" : "+r"(__real f));
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<caseless_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L1
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x0,%eax
  jmp    L29
L6:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L33
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int caseless_cmp(char *line1, char *line2) {
  while (tolower(*line1) == tolower(*line2)) {
    if (*line1 == '\0') {
      return 0;
    }
    line1++;
    line2++;
  }
  return (tolower(*line1) - tolower(*line2));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<caseless_cmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  jmp    L12
L14:
  add    $0x1,%rbx
  add    $0x1,%r12
L12:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  movsbl (%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L15
  cmpb   $0x0,(%rbx)
  jne    L14
  mov    $0x0,%eax
  jmp    L28
L15:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int caseless_cmp(char *line1, char *line2) {
  while (tolower(*line1) == tolower(*line2)) {
    if (*line1 == '\0') {
      return 0;
    }
    line1++;
    line2++;
  }
  return (tolower(*line1) - tolower(*line2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<caseless_cmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L25
L28:
  cmpb   $0x0,(%rbx)
  je     L24
  add    $0x1,%rbx
  add    $0x1,%r12
L25:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L28
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int caseless_cmp(char *line1, char *line2) {
  while (tolower(*line1) == tolower(*line2)) {
    if (*line1 == '\0') {
      return 0;
    }
    line1++;
    line2++;
  }
  return (tolower(*line1) - tolower(*line2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<caseless_cmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L21
L24:
  cmpb   $0x0,(%rbx)
  je     L5
  add    $0x1,%rbx
  add    $0x1,%r12
L21:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L24
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int caseless_cmp(char *line1, char *line2) {
  while (tolower(*line1) == tolower(*line2)) {
    if (*line1 == '\0') {
      return 0;
    }
    line1++;
    line2++;
  }
  return (tolower(*line1) - tolower(*line2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
L6:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: y


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    printf("y\n\r");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
L0:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: y


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    printf("y\n\r");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  nopl   0x0(%rax)
L7:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: y


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    printf("y\n\r");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: y


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    printf("y\n\r");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strUncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x10000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x30,%rsp
  mov    %rdi,-0x10018(%rbp)
  mov    %rsi,-0x10020(%rbp)
  mov    %edx,-0x10024(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x10018(%rbp),%rdx
  lea    -0x10010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10020(%rbp),%rdx
  lea    -0x8010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x10010(%rbp),%rax
  mov    %rax,%rdi
  call   <ucase@plt>
  lea    -0x8010(%rbp),%rax
  mov    %rax,%rdi
  call   <ucase@plt>
  mov    -0x10024(%rbp),%eax
  cltq
  movb   $0x0,-0x10010(%rbp,%rax,1)
  mov    -0x10024(%rbp),%eax
  cltq
  movb   $0x0,-0x8010(%rbp,%rax,1)
  lea    -0x8010(%rbp),%rdx
  lea    -0x10010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int strUncmp(char *s1, char *s2, int len) {
  char zwi1[32768];
  char zwi2[32768];
  strcpy(zwi1, s1);
  strcpy(zwi2, s2);
  ucase(zwi1);
  ucase(zwi2);
  zwi1[len] = 0;
  zwi2[len] = 0;
  return (strcmp(zwi1, zwi2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strUncmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L4:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L4
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    0x8000(%rsp),%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <ucase@plt>
  mov    %r12,%rdi
  call   <ucase@plt>
  movslq %ebx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  movb   $0x0,0x8000(%rsp,%rdx,1)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strUncmp(char *s1, char *s2, int len) {
  char zwi1[32768];
  char zwi2[32768];
  strcpy(zwi1, s1);
  strcpy(zwi2, s2);
  ucase(zwi1);
  ucase(zwi2);
  zwi1[len] = 0;
  zwi2[len] = 0;
  return (strcmp(zwi1, zwi2));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strUncmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0x18,%rsp
  mov    %rsp,%rbp
  lea    0x8000(%rsp),%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <ucase@plt>
  mov    %r12,%rdi
  call   <ucase@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  movb   $0x0,0x8000(%rsp,%rdx,1)
  call   <strcmp@plt>
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strUncmp(char *s1, char *s2, int len) {
  char zwi1[32768];
  char zwi2[32768];
  strcpy(zwi1, s1);
  strcpy(zwi2, s2);
  ucase(zwi1);
  ucase(zwi2);
  zwi1[len] = 0;
  zwi2[len] = 0;
  return (strcmp(zwi1, zwi2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strUncmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0x18,%rsp
  mov    %rsp,%rbp
  lea    0x8000(%rsp),%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <ucase@plt>
  mov    %r12,%rdi
  call   <ucase@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  movb   $0x0,0x8000(%rsp,%rdx,1)
  call   <strcmp@plt>
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strUncmp(char *s1, char *s2, int len) {
  char zwi1[32768];
  char zwi2[32768];
  strcpy(zwi1, s1);
  strcpy(zwi2, s2);
  ucase(zwi1);
  ucase(zwi2);
  zwi1[len] = 0;
  zwi2[len] = 0;
  return (strcmp(zwi1, zwi2));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_concat_params>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x14(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ft_argvlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L11
  jmp    L7
L31:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ft_strncat@plt>
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L7
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ft_strncat@plt>
L7:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L31
L11:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: 


assistant: ```c
char *ft_concat_params(int argc, char **argv) {
  int i;
  char *dest;
  char *bn;
  i = 1;
  bn = "\n";
  dest = (char *)malloc(sizeof(char) * ft_argvlen(argc, argv));
  if (argc > 1)
    while (++i < argc + 1) {
      ft_strncat(dest, argv[i - 1], ft_strlen(argv[i - 1]));
      if (i < argc)
        ft_strncat(dest, bn, 1);
    }
  return (dest);
}
```