ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<OPM_WriteHex>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%edx
  sar    $0x4,%edx
  lea    0x30(%rdx),%ecx
  lea    0x57(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %ecx,%eax
  mov    %al,0x5(%rsp)
  and    $0xf,%edi
  lea    0x30(%rdi),%edx
  lea    0x57(%rdi),%eax
  cmp    $0x9,%edi
  cmovle %edx,%eax
  mov    %al,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x5(%rsp),%rdi
  mov    $0x3,%esi
  call   <OPM_WriteString@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void OPM_WriteHex(long long i) {
  unsigned char s[3];
  int digit;
  digit = ((long long)((int)i) >> (4));
  if (digit < 10) {
    s[0] = (unsigned char)(48 + digit);
  } else {
    s[0] = (unsigned char)(87 + digit);
  }
  digit = (((int)i) & ~(-16));
  if (digit < 10) {
    s[1] = (unsigned char)(48 + digit);
  } else {
    s[1] = (unsigned char)(87 + digit);
  }
  s[2] = 0x00;
  OPM_WriteString(s, ((long long)(3)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<OPM_WriteHex>:
  endbr64
  mov    %edi,%edx
  sub    $0x18,%rsp
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sar    $0x4,%edx
  movb   $0x0,0x7(%rsp)
  cmp    $0x9,%edx
  lea    0x30(%rdx),%ecx
  lea    0x57(%rdx),%eax
  cmovle %ecx,%eax
  and    $0xf,%edi
  cmp    $0x9,%edi
  lea    0x30(%rdi),%edx
  mov    %al,0x5(%rsp)
  lea    0x57(%rdi),%eax
  lea    0x5(%rsp),%rdi
  cmovle %edx,%eax
  mov    %al,0x6(%rsp)
  call   <OPM_WriteString@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void OPM_WriteHex(long long i) {
  unsigned char s[3];
  int digit;
  digit = ((long long)((int)i) >> (4));
  if (digit < 10) {
    s[0] = (unsigned char)(48 + digit);
  } else {
    s[0] = (unsigned char)(87 + digit);
  }
  digit = (((int)i) & ~(-16));
  if (digit < 10) {
    s[1] = (unsigned char)(48 + digit);
  } else {
    s[1] = (unsigned char)(87 + digit);
  }
  s[2] = 0x00;
  OPM_WriteString(s, ((long long)(3)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OPM_WriteHex>:
  endbr64
  mov    %edi,%edx
  sub    $0x18,%rsp
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sar    $0x4,%edx
  movb   $0x0,0x7(%rsp)
  cmp    $0x9,%edx
  lea    0x30(%rdx),%ecx
  lea    0x57(%rdx),%eax
  cmovle %ecx,%eax
  and    $0xf,%edi
  cmp    $0x9,%edi
  lea    0x30(%rdi),%edx
  mov    %al,0x5(%rsp)
  lea    0x57(%rdi),%eax
  lea    0x5(%rsp),%rdi
  cmovle %edx,%eax
  mov    %al,0x6(%rsp)
  call   <OPM_WriteString@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void OPM_WriteHex(long long i) {
  unsigned char s[3];
  int digit;
  digit = ((long long)((int)i) >> (4));
  if (digit < 10) {
    s[0] = (unsigned char)(48 + digit);
  } else {
    s[0] = (unsigned char)(87 + digit);
  }
  digit = (((int)i) & ~(-16));
  if (digit < 10) {
    s[1] = (unsigned char)(48 + digit);
  } else {
    s[1] = (unsigned char)(87 + digit);
  }
  s[2] = 0x00;
  OPM_WriteString(s, ((long long)(3)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<norm_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dot_float@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double norm_float(float *vec, int beg, int end) {
  double temp;
  double dot_float(float *vec1, int beg, int end, float *vec2);
  temp = sqrt(dot_float(vec, beg, end, vec));
  return (temp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<norm_float>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  call   <dot_float@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
L5:
  add    $0x8,%rsp
  ret
L3:
  call   <sqrt@plt>
  jmp    L5
```

assistant: ```c
double norm_float(float *vec, int beg, int end) {
  double temp;
  double dot_float(float *vec1, int beg, int end, float *vec2);
  temp = sqrt(dot_float(vec, beg, end, vec));
  return (temp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<norm_float>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  call   <dot_float@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L6
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rsp
  ret
L6:
  pop    %rax
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double norm_float(float *vec, int beg, int end) {
  double temp;
  double dot_float(float *vec1, int beg, int end, float *vec2);
  temp = sqrt(dot_float(vec, beg, end, vec));
  return (temp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<norm_float>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  call   <dot_float@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L2
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rsp
  ret
L2:
  pop    %rax
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double norm_float(float *vec, int beg, int end) {
  double temp;
  double dot_float(float *vec1, int beg, int end, float *vec2);
  temp = sqrt(dot_float(vec, beg, end, vec));
  return (temp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_relocation_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L0
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L0:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  test   %rax,%rax
  jns    L45
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L45:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L24
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L24:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int read_relocation_table(int d, Elf64_Shdr const *section, Elf64_Rela **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Rela *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_relocation_table>:
  endbr64
  test   %rsi,%rsi
  je     L28
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    (%rsi),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    0x4(%rbx),%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%edi
  call   <lseek@plt>
  test   %rax,%rax
  js     L47
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jle    L2
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  ret
L47:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  jmp    L0
L2:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    D47(%rip),%rdx
  mov    %eax,(%rdx)
  jmp    L0
```

assistant: ```c
int read_relocation_table(int d, Elf64_Shdr const *section, Elf64_Rela **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Rela *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_relocation_table>:
  endbr64
  test   %rsi,%rsi
  je     L37
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rsi),%edi
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    0x4(%rbx),%esi
  mov    %r12d,%edi
  mov    %rax,0x0(%rbp)
  mov    D36(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  test   %rax,%rax
  js     L1
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jle    L35
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D20(%rip),%rax
  mov    D34(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L10
  nopl   (%rax)
L1:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D34(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int read_relocation_table(int d, Elf64_Shdr const *section, Elf64_Rela **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Rela *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_relocation_table>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rsi),%edi
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    0x4(%rbx),%esi
  mov    %r12d,%edi
  mov    %rax,0x0(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  test   %rax,%rax
  js     L15
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jle    L13
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D4(%rip),%rax
  mov    D40(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L8
  nopl   (%rax)
L15:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D40(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int read_relocation_table(int d, Elf64_Shdr const *section, Elf64_Rela **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Rela *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtc_get_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
L26:
  mov    $0x0,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L26
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  nop
L3:
  mov    $0x0,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L3
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L6
  mov    $0xb,%edi
  call   <get_RTC_register@plt>
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  jne    L0
  mov    -0x8(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rtc_get_year() {
  int year;
  int last_year;
  while (rtc_update_in_progress())
    ;
  year = get_RTC_register(0x09);
  do {
    last_year = year;
    while (rtc_update_in_progress())
      ;
    year = get_RTC_register(0x09);
  } while (last_year != year);
  unsigned char registerB = get_RTC_register(0x0B);
  if (!(registerB & 0x04)) {
    year = (year & 0x0F) + ((year / 16) * 10);
  }
  return year;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtc_get_year>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L6:
  mov    $0x0,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,%ebx
  jmp    L3
L44:
  mov    %eax,%ebx
L3:
  mov    $0x0,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L3
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,%ebp
  cmp    %eax,%ebx
  jne    L44
  mov    $0xb,%edi
  call   <get_RTC_register@plt>
  test   $0x4,%al
  jne    L32
  mov    %ebp,%edx
  and    $0xf,%edx
  lea    0xf(%rbp),%eax
  test   %ebp,%ebp
  cmovns %ebp,%eax
  sar    $0x4,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%ebp
L32:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rtc_get_year() {
  int year;
  int last_year;
  while (rtc_update_in_progress())
    ;
  year = get_RTC_register(0x09);
  do {
    last_year = year;
    while (rtc_update_in_progress())
      ;
    year = get_RTC_register(0x09);
  } while (last_year != year);
  unsigned char registerB = get_RTC_register(0x0B);
  if (!(registerB & 0x04)) {
    year = (year & 0x0F) + ((year / 16) * 10);
  }
  return year;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rtc_get_year>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L1
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,%ebx
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L9
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  je     L23
  mov    %eax,%ebx
  jmp    L9
  nopl   0x0(%rax)
L23:
  mov    $0xb,%edi
  call   <get_RTC_register@plt>
  test   $0x4,%al
  jne    L45
  mov    %r12d,%edx
  lea    0xf(%r12),%eax
  and    $0xf,%edx
  test   %r12d,%r12d
  cmovns %r12d,%eax
  sar    $0x4,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%r12d
L45:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int rtc_get_year() {
  int year;
  int last_year;
  while (rtc_update_in_progress())
    ;
  year = get_RTC_register(0x09);
  do {
    last_year = year;
    while (rtc_update_in_progress())
      ;
    year = get_RTC_register(0x09);
  } while (last_year != year);
  unsigned char registerB = get_RTC_register(0x0B);
  if (!(registerB & 0x04)) {
    year = (year & 0x0F) + ((year / 16) * 10);
  }
  return year;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rtc_get_year>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L5
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,%ebx
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <rtc_update_in_progress@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x9,%edi
  call   <get_RTC_register@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  je     L36
  mov    %eax,%ebx
  jmp    L6
  nopl   0x0(%rax)
L36:
  mov    $0xb,%edi
  call   <get_RTC_register@plt>
  test   $0x4,%al
  jne    L4
  mov    %r12d,%edx
  lea    0xf(%r12),%eax
  and    $0xf,%edx
  test   %r12d,%r12d
  cmovns %r12d,%eax
  sar    $0x4,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%r12d
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int rtc_get_year() {
  int year;
  int last_year;
  while (rtc_update_in_progress())
    ;
  year = get_RTC_register(0x09);
  do {
    last_year = year;
    while (rtc_update_in_progress())
      ;
    year = get_RTC_register(0x09);
  } while (last_year != year);
  unsigned char registerB = get_RTC_register(0x0B);
  if (!(registerB & 0x04)) {
    year = (year & 0x0F) + ((year / 16) * 10);
  }
  return year;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uninitvar_fgetc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_fgetc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <fgetc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uninitvar_fgetc>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <fgetc@plt>
```

assistant: ```c
void uninitvar_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uninitvar_fgetc>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <fgetc@plt>
```

assistant: ```c
void uninitvar_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<to_int_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L5
L8:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <to_int@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x20(%rbp)
L5:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *to_int_values(char *s) {
  int length = strlen(s);
  int i;
  int *int_values = (int *)malloc(length * sizeof(int));
  for (i = 0; i < length; ++i) {
    int_values[i] = to_int(s[i]);
  }
  return int_values;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to_int_values>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L16
  mov    %r14,%rbx
  mov    %rax,%rbp
  lea    -0x1(%r12),%eax
  lea    0x1(%r14,%rax,1),%r12
L0:
  movsbl (%rbx),%edi
  call   <to_int@plt>
  mov    %eax,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %r12,%rbx
  jne    L0
L16:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *to_int_values(char *s) {
  int length = strlen(s);
  int i;
  int *int_values = (int *)malloc(length * sizeof(int));
  for (i = 0; i < length; ++i) {
    int_values[i] = to_int(s[i]);
  }
  return int_values;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<to_int_values>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x0(,%rax,4),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L4
  mov    %rax,%rbp
  lea    -0x1(%r13),%eax
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax)
L9:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x4,%rbp
  call   <to_int@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r13,%rbx
  jne    L9
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *to_int_values(char *s) {
  int length = strlen(s);
  int i;
  int *int_values = (int *)malloc(length * sizeof(int));
  for (i = 0; i < length; ++i) {
    int_values[i] = to_int(s[i]);
  }
  return int_values;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<to_int_values>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x0(,%rax,4),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L15
  mov    %rax,%rbp
  lea    -0x1(%r13),%eax
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax)
L16:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x4,%rbp
  call   <to_int@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r13,%rbx
  jne    L16
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *to_int_values(char *s) {
  int length = strlen(s);
  int i;
  int *int_values = (int *)malloc(length * sizeof(int));
  for (i = 0; i < length; ++i) {
    int_values[i] = to_int(s[i]);
  }
  return int_values;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addr_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <l2@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x4be00,%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D25(%rip),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
type: string

tool: D28: %2d, %2d

assistant: ```c
const char *addr_map(unsigned int addr, unsigned int mask) {
  static char buf[100];
  sprintf(buf, "%2d, %2d", addr - 0xFFFB4200, l2(mask));
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<addr_map>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  call   <l2@plt>
  mov    %eax,%ecx
  lea    0x4be00(%rbx),%edx
  lea    D14(%rip),%rsi
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string

tool: D14: %2d, %2d

assistant: ```c
const char *addr_map(unsigned int addr, unsigned int mask) {
  static char buf[100];
  sprintf(buf, "%2d, %2d", addr - 0xFFFB4200, l2(mask));
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<addr_map>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  sub    $0x8,%rsp
  call   <l2@plt>
  lea    0x4be00(%rbx),%edx
  mov    %r12,%rdi
  lea    D11(%rip),%rsi
  mov    %eax,%ecx
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D11
datatype: string

tool: D11: %2d, %2d

assistant: ```c
const char *addr_map(unsigned int addr, unsigned int mask) {
  static char buf[100];
  sprintf(buf, "%2d, %2d", addr - 0xFFFB4200, l2(mask));
  return buf;
}
```