ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L38
  nopw   0x0(%rax,%rax,1)
L14:
  shl    $0x4,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L23
  mov    %rdx,%rsi
  not    %rdx
  shr    $0x18,%rsi
  xor    %rsi,%rax
  and    %rdx,%rax
L23:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L14
  ret
  xchg   %ax,%ax
L38:
  ret
  nopl   0x0(%rax)
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long elf_hash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name != 0) {
    h = (h << 4) + *name++;
    if ((g = h & 0xf0000000) != 0) {
      h ^= g >> 24;
      h &= ~g;
    }
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<assert_true>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) bool assert_true(bool flag) {
  assert(flag);
  return flag;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assert_true>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <assert@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) bool assert_true(bool flag) {
  assert(flag);
  return flag;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<assert_true>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <assert@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) bool assert_true(bool flag) {
  assert(flag);
  return flag;
}
```
user: Translate the below assembly code into C programming language:

```asm
<assert_true>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <assert@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) bool assert_true(bool flag) {
  assert(flag);
  return flag;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double norm(const double *x, const int n_dimensions) {
  double ans = 0;
  int i;
  for (i = 0; i < n_dimensions; i++) {
    ans += x[i] * x[i];
  }
  return sqrt(ans);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<norm>:
  endbr64
  test   %esi,%esi
  jle    L12
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L32:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L32
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L9
L29:
  sqrtsd %xmm0,%xmm0
  ret
L12:
  pxor   %xmm0,%xmm0
  jmp    L29
L9:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double norm(const double *x, const int n_dimensions) {
  double ans = 0;
  int i;
  for (i = 0; i < n_dimensions; i++) {
    ans += x[i] * x[i];
  }
  return sqrt(ans);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<norm>:
  endbr64
  test   %esi,%esi
  jle    L25
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L21:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L21
  ucomisd %xmm0,%xmm2
  ja     L0
  sqrtsd %xmm0,%xmm0
  ret
L25:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L0:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm(const double *x, const int n_dimensions) {
  double ans = 0;
  int i;
  for (i = 0; i < n_dimensions; i++) {
    ans += x[i] * x[i];
  }
  return sqrt(ans);
}
```
user: Translate the below assembly code into C programming language:

```asm
<norm>:
  endbr64
  test   %esi,%esi
  jle    L23
  cmp    $0x1,%esi
  je     L18
  mov    %esi,%edx
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L49:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L49
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L24
L22:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L24:
  ucomisd %xmm0,%xmm3
  ja     L56
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L23:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L18:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L22
L56:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm(const double *x, const int n_dimensions) {
  double ans = 0;
  int i;
  for (i = 0; i < n_dimensions; i++) {
    ans += x[i] * x[i];
  }
  return sqrt(ans);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fileRead16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  shl    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fileRead16(FILE *fp) {
  unsigned int r = fgetc(fp);
  r |= fgetc(fp) << 8;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fileRead16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <fgetc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <fgetc@plt>
  shl    $0x8,%eax
  or     %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fileRead16(FILE *fp) {
  unsigned int r = fgetc(fp);
  r |= fgetc(fp) << 8;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fileRead16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fileRead16(FILE *fp) {
  unsigned int r = fgetc(fp);
  r |= fgetc(fp) << 8;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fileRead16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fileRead16(FILE *fp) {
  unsigned int r = fgetc(fp);
  r |= fgetc(fp) << 8;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<binsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L61
L21:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L1
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L61
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L2
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L61
L2:
  mov    -0x4(%rbp),%eax
  jmp    L13
L61:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L21
  mov    $0xffffffff,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int binsearch(int x, int v[], int n) {
  int low, mid, high;
  low = 0;
  high = n - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < v[mid])
      high = mid - 1;
    else if (x > v[mid])
      low = mid + 1;
    else
      return mid;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binsearch>:
  endbr64
  sub    $0x1,%edx
  js     L32
  mov    $0x0,%r8d
  jmp    L28
L39:
  jge    L3
  lea    0x1(%rax),%r8d
L12:
  cmp    %edx,%r8d
  jg     L0
L28:
  lea    (%r8,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rsi,%rcx,4),%ecx
  cmp    %edi,%ecx
  jle    L39
  lea    -0x1(%rax),%edx
  jmp    L12
L0:
  mov    $0xffffffff,%r9d
L3:
  mov    %r9d,%eax
  ret
L32:
  mov    $0xffffffff,%r9d
  jmp    L3
```

assistant: ```c
int binsearch(int x, int v[], int n) {
  int low, mid, high;
  low = 0;
  high = n - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < v[mid])
      high = mid - 1;
    else if (x > v[mid])
      low = mid + 1;
    else
      return mid;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binsearch>:
  endbr64
  sub    $0x1,%edx
  js     L3
  xor    %ecx,%ecx
  jmp    L15
  nopl   (%rax)
L14:
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jl     L3
L15:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edi,(%rsi,%r8,4)
  jg     L14
  jge    L49
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jge    L15
L3:
  mov    $0xffffffff,%eax
L49:
  ret
```

assistant: ```c
int binsearch(int x, int v[], int n) {
  int low, mid, high;
  low = 0;
  high = n - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < v[mid])
      high = mid - 1;
    else if (x > v[mid])
      low = mid + 1;
    else
      return mid;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binsearch>:
  endbr64
  sub    $0x1,%edx
  js     L39
  xor    %ecx,%ecx
  jmp    L7
  nopl   (%rax)
L36:
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jl     L39
L7:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edi,(%rsi,%r8,4)
  jg     L36
  jge    L25
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jge    L7
L39:
  mov    $0xffffffff,%eax
L25:
  ret
```

assistant: ```c
int binsearch(int x, int v[], int n) {
  int low, mid, high;
  low = 0;
  high = n - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < v[mid])
      high = mid - 1;
    else if (x > v[mid])
      low = mid + 1;
    else
      return mid;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<int_ascending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L15
  mov    $0xffffffff,%eax
  jmp    L8
L15:
  mov    $0x1,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int int_ascending(const void *a, const void *b) {
  if (*(int *)a < *(int *)b)
    return -1;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int_ascending>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int int_ascending(const void *a, const void *b) {
  if (*(int *)a < *(int *)b)
    return -1;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int_ascending>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int int_ascending(const void *a, const void *b) {
  if (*(int *)a < *(int *)b)
    return -1;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_ascending>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int int_ascending(const void *a, const void *b) {
  if (*(int *)a < *(int *)b)
    return -1;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L13
L21:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x9,-0x14(%rbp)
  jg     L21
  mov    -0x4(%rbp),%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int64_t get(int64_t n) {
  int m;
  m = 0;
  if (n == 0)
    return (0);
  while (n >= 10) {
    n /= 10;
    m++;
  }
  return (m);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get>:
  endbr64
  cmp    $0x9,%edi
  jle    L10
  mov    $0x0,%edx
L5:
  mov    %edi,%ecx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edi
  add    $0x1,%edx
  cmp    $0x63,%ecx
  jg     L5
L1:
  mov    %edx,%eax
  ret
L10:
  mov    $0x0,%edx
  jmp    L1
```

assistant: ```c
int64_t get(int64_t n) {
  int m;
  m = 0;
  if (n == 0)
    return (0);
  while (n >= 10) {
    n /= 10;
    m++;
  }
  return (m);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x9,%edi
  jle    L11
  mov    $0xcccccccd,%edx
  nopl   0x0(%rax)
L0:
  mov    %edi,%edi
  add    $0x1,%r8d
  mov    %rdi,%rax
  imul   %rdx,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%eax
  jg     L0
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int64_t get(int64_t n) {
  int m;
  m = 0;
  if (n == 0)
    return (0);
  while (n >= 10) {
    n /= 10;
    m++;
  }
  return (m);
}
```
user: What is the c source code of the assembly code below:

```asm
<get>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x9,%edi
  jle    L3
  mov    $0xcccccccd,%edx
  nopl   0x0(%rax)
L11:
  mov    %edi,%edi
  add    $0x1,%r8d
  mov    %rdi,%rax
  imul   %rdx,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%eax
  jg     L11
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int64_t get(int64_t n) {
  int m;
  m = 0;
  if (n == 0)
    return (0);
  while (n >= 10) {
    n /= 10;
    m++;
  }
  return (m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: 0123456789abcdef

assistant: ```c
int main() {
  char str[5];
  strcpy(str, "0123456789abcdef");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  lea    D6(%rip),%rsi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: 0123456789abcdef

assistant: ```c
int main() {
  char str[5];
  strcpy(str, "0123456789abcdef");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8: 0123456789abcdef

assistant: ```c
int main() {
  char str[5];
  strcpy(str, "0123456789abcdef");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 0123456789abcdef

assistant: ```c
int main() {
  char str[5];
  strcpy(str, "0123456789abcdef");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L23:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L18
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L18:
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L23
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low];
  int leftwall = low;
  for (int i = low + 1; i < high; i++) {
    if (a[i] < pivot) {
      leftwall++;
      int temp = a[i];
      a[i] = a[leftwall];
      a[leftwall] = temp;
    }
  }
  int temp = a[low];
  a[low] = a[leftwall];
  a[leftwall] = temp;
  return (leftwall);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<partition>:
  endbr64
  mov    %esi,%eax
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%r11
  mov    (%r11),%r9d
  lea    0x1(%rsi),%ecx
  cmp    %edx,%ecx
  jge    L36
  movslq %ecx,%rcx
  jmp    L18
L35:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jle    L36
L18:
  mov    (%rdi,%rcx,4),%esi
  cmp    %r9d,%esi
  jge    L35
  add    $0x1,%eax
  movslq %eax,%r8
  lea    (%rdi,%r8,4),%r8
  mov    (%r8),%r10d
  mov    %r10d,(%rdi,%rcx,4)
  mov    %esi,(%r8)
  jmp    L35
L36:
  mov    (%r11),%ecx
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%esi
  mov    %esi,(%r11)
  mov    %ecx,(%rdx)
  ret
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low];
  int leftwall = low;
  for (int i = low + 1; i < high; i++) {
    if (a[i] < pivot) {
      leftwall++;
      int temp = a[i];
      a[i] = a[leftwall];
      a[leftwall] = temp;
    }
  }
  int temp = a[low];
  a[low] = a[leftwall];
  a[leftwall] = temp;
  return (leftwall);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partition>:
  endbr64
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%r11
  mov    %rcx,%rax
  lea    0x1(%rcx),%ecx
  mov    (%r11),%r9d
  cmp    %edx,%ecx
  jge    L4
  movslq %ecx,%rcx
  nopl   0x0(%rax,%rax,1)
L22:
  mov    (%rdi,%rcx,4),%esi
  cmp    %r9d,%esi
  jge    L28
  add    $0x1,%eax
  movslq %eax,%r8
  lea    (%rdi,%r8,4),%r8
  mov    (%r8),%r10d
  mov    %r10d,(%rdi,%rcx,4)
  mov    %esi,(%r8)
L28:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jg     L22
  movslq %eax,%rdx
  mov    (%r11),%ecx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%r9d
  mov    %r9d,(%r11)
  mov    %ecx,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r9d,%ecx
  mov    %r11,%rdx
  mov    %r9d,(%r11)
  mov    %ecx,(%rdx)
  ret
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low];
  int leftwall = low;
  for (int i = low + 1; i < high; i++) {
    if (a[i] < pivot) {
      leftwall++;
      int temp = a[i];
      a[i] = a[leftwall];
      a[leftwall] = temp;
    }
  }
  int temp = a[low];
  a[low] = a[leftwall];
  a[leftwall] = temp;
  return (leftwall);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<partition>:
  endbr64
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%r11
  mov    %rcx,%rax
  lea    0x1(%rcx),%ecx
  mov    (%r11),%r9d
  cmp    %edx,%ecx
  jge    L3
  movslq %ecx,%rcx
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rdi,%rcx,4),%esi
  cmp    %r9d,%esi
  jge    L5
  add    $0x1,%eax
  movslq %eax,%r8
  lea    (%rdi,%r8,4),%r8
  mov    (%r8),%r10d
  mov    %r10d,(%rdi,%rcx,4)
  mov    %esi,(%r8)
L5:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jg     L13
  movslq %eax,%rdx
  mov    (%r11),%ecx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%r9d
  mov    %r9d,(%r11)
  mov    %ecx,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r9d,%ecx
  mov    %r11,%rdx
  mov    %r9d,(%r11)
  mov    %ecx,(%rdx)
  ret
```

assistant: ```c
int partition(int a[], int low, int high) {
  int pivot = a[low];
  int leftwall = low;
  for (int i = low + 1; i < high; i++) {
    if (a[i] < pivot) {
      leftwall++;
      int temp = a[i];
      a[i] = a[leftwall];
      a[leftwall] = temp;
    }
  }
  int temp = a[low];
  a[low] = a[leftwall];
  a[leftwall] = temp;
  return (leftwall);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<t1_init_ctxno_mag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x2000,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L12:
  movl   $0x2,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  add    $0xa,%eax
  pop    %rbp
  ret
```

assistant: ```c
int t1_init_ctxno_mag(int f) {
  int n;
  if (!(f & 0x2000)) {
    n = (f & ((0x0010 | 0x0001 | 0x0020 | 0x0002 | 0x0040 | 0x0004 | 0x0080 | 0x0008))) ? 1 : 0;
  } else {
    n = 2;
  }
  return (((0 + 1) + 9) + n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<t1_init_ctxno_mag>:
  endbr64
  mov    $0x2,%eax
  test   $0x2000,%edi
  jne    L0
  test   %dil,%dil
  setne  %al
  movzbl %al,%eax
L0:
  add    $0xa,%eax
  ret
```

assistant: ```c
int t1_init_ctxno_mag(int f) {
  int n;
  if (!(f & 0x2000)) {
    n = (f & ((0x0010 | 0x0001 | 0x0020 | 0x0002 | 0x0040 | 0x0004 | 0x0080 | 0x0008))) ? 1 : 0;
  } else {
    n = 2;
  }
  return (((0 + 1) + 9) + n);
}
```