ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findOne>:
  endbr64
  mov    %ecx,%eax
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %esi,%ecx
  mov    %eax,%esi
  mov    %ecx,%eax
  mov    %rdi,%rcx
  mov    %rdx,%rdi
  mov    %rcx,%rdx
L60:
  cmp    %eax,%esi
  jl     L29
  test   %eax,%eax
  je     L86
  cmp    $0x1,%r8d
  je     L53
  push   %rbx
  cs nopw 0x0(%rax,%rax,1)
L101:
  mov    %r8d,%ecx
  shr    $0x1f,%ecx
  add    %r8d,%ecx
  sar    %ecx
  cmp    %eax,%ecx
  cmovg  %eax,%ecx
  sub    %ecx,%r8d
  movslq %ecx,%r10
  movslq %r8d,%r9
  lea    0x0(,%r10,4),%rbx
  shl    $0x2,%r9
  mov    -0x4(%rdi,%r9,1),%r11d
  cmp    -0x4(%rdx,%r10,4),%r11d
  je     L69
  jle    L93
  sub    %ecx,%eax
  add    %rbx,%rdx
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L72:
  mov    %esi,%ecx
  mov    %eax,%esi
  mov    %ecx,%eax
  mov    %rdi,%rcx
  mov    %rdx,%rdi
  mov    %rcx,%rdx
L41:
  cmp    %eax,%esi
  jl     L72
  test   %eax,%eax
  je     L30
  cmp    $0x1,%r8d
  jne    L101
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  pop    %rbx
  jmp    1050 <min@plt>
  nopw   0x0(%rax,%rax,1)
L93:
  sub    %r8d,%esi
  add    %r9,%rdi
  mov    %ecx,%r8d
  jmp    L41
L30:
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sdl -0x4(%rdi,%r8,4),%xmm0
  ret
L69:
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %r11d,%xmm0
  ret
L86:
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rdi,%r8,4),%xmm0
  ret
L53:
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  jmp    1050 <min@plt>
```

assistant: ```c
double findOne(int *A, int m, int *B, int n, int k) {
  int mo, no;
  if (m < n)
    return findOne(B, n, A, m, k);
  if (n == 0)
    return A[k - 1];
  if (k == 1)
    return min(A[0], B[0]);
  no = (k / 2 < n) ? (k / 2) : n;
  mo = k - no;
  if (A[mo - 1] == B[no - 1])
    return A[mo - 1];
  else if (A[mo - 1] > B[no - 1])
    return findOne(A, m, B + no, n - no, k - no);
  else
    return findOne(A + mo, m - mo, B, n, k - mo);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findOne>:
  endbr64
  mov    %ecx,%eax
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %esi,%ecx
  mov    %eax,%esi
  mov    %ecx,%eax
  mov    %rdi,%rcx
  mov    %rdx,%rdi
  mov    %rcx,%rdx
L94:
  cmp    %eax,%esi
  jl     L22
  test   %eax,%eax
  je     L47
  cmp    $0x1,%r8d
  je     L69
  push   %rbx
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %r8d,%ecx
  shr    $0x1f,%ecx
  add    %r8d,%ecx
  sar    %ecx
  cmp    %eax,%ecx
  cmovg  %eax,%ecx
  sub    %ecx,%r8d
  movslq %ecx,%r10
  movslq %r8d,%r9
  lea    0x0(,%r10,4),%rbx
  shl    $0x2,%r9
  mov    -0x4(%rdi,%r9,1),%r11d
  cmp    -0x4(%rdx,%r10,4),%r11d
  je     L76
  jle    L15
  sub    %ecx,%eax
  add    %rbx,%rdx
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %esi,%ecx
  mov    %eax,%esi
  mov    %ecx,%eax
  mov    %rdi,%rcx
  mov    %rdx,%rdi
  mov    %rcx,%rdx
L59:
  cmp    %eax,%esi
  jl     L52
  test   %eax,%eax
  je     L84
  cmp    $0x1,%r8d
  jne    L17
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  pop    %rbx
  jmp    1050 <min@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  sub    %r8d,%esi
  add    %r9,%rdi
  mov    %ecx,%r8d
  jmp    L59
L84:
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sdl -0x4(%rdi,%r8,4),%xmm0
  ret
L76:
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %r11d,%xmm0
  ret
L47:
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rdi,%r8,4),%xmm0
  ret
L69:
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  jmp    1050 <min@plt>
```

assistant: ```c
double findOne(int *A, int m, int *B, int n, int k) {
  int mo, no;
  if (m < n)
    return findOne(B, n, A, m, k);
  if (n == 0)
    return A[k - 1];
  if (k == 1)
    return min(A[0], B[0]);
  no = (k / 2 < n) ? (k / 2) : n;
  mo = k - no;
  if (A[mo - 1] == B[no - 1])
    return A[mo - 1];
  else if (A[mo - 1] > B[no - 1])
    return findOne(A, m, B + no, n - no, k - no);
  else
    return findOne(A + mo, m - mo, B, n, k - mo);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int ptr, ptr2;
  ptr = *a;
  *a = *c;
  ptr2 = *b;
  *b = ptr;
  *c = ptr2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotr>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rdx),%eax
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int ptr, ptr2;
  ptr = *a;
  *a = *c;
  ptr2 = *b;
  *b = ptr;
  *c = ptr2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotr>:
  endbr64
  mov    (%rdx),%eax
  mov    (%rdi),%ecx
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int ptr, ptr2;
  ptr = *a;
  *a = *c;
  ptr2 = *b;
  *b = ptr;
  *c = ptr2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rotr>:
  endbr64
  mov    (%rdx),%eax
  mov    (%rdi),%ecx
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int ptr, ptr2;
  ptr = *a;
  *a = *c;
  ptr2 = *b;
  *b = ptr;
  *c = ptr2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L31
  mov    $0x1,%eax
  jmp    L83
L31:
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L15
  mov    $0x1,%eax
  jmp    L83
L15:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <make_tu@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L47
  mov    $0x1,%eax
  jmp    L83
L47:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <make_tu@plt>
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L95
  mov    $0x1,%eax
  jmp    L83
L95:
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <make_tu@plt>
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L50
  mov    $0x1,%eax
  jmp    L83
L50:
  mov    $0x0,%eax
L83:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (test__umodti3(0, 1, 0))
    return 1;
  if (test__umodti3(2, 1, 0))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 1, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 2, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0xFFFFFFFFFFFFFFFFuLL, 0xFFFFFFFFFFFFFFFFuLL), 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <test__umodti3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L44
L31:
  add    $0x8,%rsp
  ret
L44:
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umodti3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L31
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <make_tu@plt>
  mov    %eax,%edi
  mov    $0x0,%edx
  mov    $0x1,%esi
  call   <test__umodti3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L31
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <make_tu@plt>
  mov    %eax,%edi
  mov    $0x0,%edx
  mov    $0x2,%esi
  call   <test__umodti3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L31
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <make_tu@plt>
  mov    %eax,%edi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <test__umodti3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L31
```

assistant: ```c
int main() {
  if (test__umodti3(0, 1, 0))
    return 1;
  if (test__umodti3(2, 1, 0))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 1, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 2, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0xFFFFFFFFFFFFFFFFuLL, 0xFFFFFFFFFFFFFFFFuLL), 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L13
L40:
  mov    $0x1,%eax
L48:
  add    $0x8,%rsp
  ret
L13:
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  jne    L40
  xor    %esi,%esi
  xor    %edi,%edi
  call   <make_tu@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  jne    L40
  xor    %esi,%esi
  xor    %edi,%edi
  call   <make_tu@plt>
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  jne    L40
  or     $0xffffffff,%esi
  or     $0xffffffff,%edi
  call   <make_tu@plt>
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L48
```

assistant: ```c
int main() {
  if (test__umodti3(0, 1, 0))
    return 1;
  if (test__umodti3(2, 1, 0))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 1, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 2, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0xFFFFFFFFFFFFFFFFuLL, 0xFFFFFFFFFFFFFFFFuLL), 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <test__umodti3@plt>
  test   %rax,%rax
  je     L27
L17:
  mov    $0x1,%eax
L41:
  add    $0x8,%rsp
  ret
L27:
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  jne    L17
  xor    %esi,%esi
  xor    %edi,%edi
  call   <make_tu@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  jne    L17
  xor    %esi,%esi
  xor    %edi,%edi
  call   <make_tu@plt>
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  jne    L17
  or     $0xffffffff,%esi
  or     $0xffffffff,%edi
  call   <make_tu@plt>
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <test__umodti3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L41
```

assistant: ```c
int main() {
  if (test__umodti3(0, 1, 0))
    return 1;
  if (test__umodti3(2, 1, 0))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 1, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0x8000000000000000uLL, 0), 2, 0x0uLL))
    return 1;
  if (test__umodti3(make_tu(0xFFFFFFFFFFFFFFFFuLL, 0xFFFFFFFFFFFFFFFFuLL), 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fibo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L33
L15:
  cmpl   $0x2,-0x14(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L33
L26:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibo>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibo>
  add    %ebx,%eax
L33:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibo(int n) {
  if (n == 1)
    return 0;
  else if (n == 2)
    return 1;
  else
    return fibo(n - 1) + fibo(n - 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fibo>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L21
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L24
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  lea    -0x1(%rdi),%edi
  call   <fibo>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fibo>
  add    %ebp,%eax
  jmp    L18
L21:
  ret
```

assistant: ```c
int fibo(int n) {
  if (n == 1)
    return 0;
  else if (n == 2)
    return 1;
  else
    return fibo(n - 1) + fibo(n - 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<debase64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L11
  cmpb   $0x7a,-0x4(%rbp)
  jg     L11
  movsbl -0x4(%rbp),%eax
  sub    $0x47,%eax
  jmp    L107
L11:
  cmpb   $0x40,-0x4(%rbp)
  jle    L110
  cmpb   $0x5a,-0x4(%rbp)
  jg     L110
  movsbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L107
L110:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L61
  cmpb   $0x39,-0x4(%rbp)
  jg     L61
  movsbl -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L107
L61:
  cmpb   $0x2f,-0x4(%rbp)
  jne    L46
  mov    $0x3f,%eax
  jmp    L107
L46:
  cmpb   $0x2b,-0x4(%rbp)
  jne    L75
  mov    $0x3e,%eax
  jmp    L107
L75:
  mov    $0xffffffff,%eax
L107:
  pop    %rbp
  ret
```

assistant: ```c
int debase64(char c) {
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  else if (c >= 'A' && c <= 'Z')
    return c - 'A';
  else if (c >= '0' && c <= '9')
    return c - '0' + 52;
  else if (c == '/')
    return 63;
  else if (c == '+')
    return 62;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<debase64>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L30
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L2
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L33
  cmp    $0x2f,%dil
  je     L18
  cmp    $0x2b,%dil
  mov    $0x3e,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
L30:
  movsbl %dil,%edi
  lea    -0x47(%rdi),%eax
  ret
L2:
  movsbl %dil,%edi
  lea    -0x41(%rdi),%eax
  ret
L33:
  movsbl %dil,%edi
  lea    0x4(%rdi),%eax
  ret
L18:
  mov    $0x3f,%eax
  ret
```

assistant: ```c
int debase64(char c) {
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  else if (c >= 'A' && c <= 'Z')
    return c - 'A';
  else if (c >= '0' && c <= '9')
    return c - '0' + 52;
  else if (c == '/')
    return 63;
  else if (c == '+')
    return 62;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<debase64>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L21
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L12
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L22
  cmp    $0x2f,%dil
  je     L29
  cmp    $0x2b,%dil
  mov    $0xffffffff,%edx
  mov    $0x3e,%eax
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L12:
  movsbl %al,%eax
  ret
  nopl   0x0(%rax)
L21:
  sub    $0x47,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x4,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x3f,%eax
  ret
```

assistant: ```c
int debase64(char c) {
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  else if (c >= 'A' && c <= 'Z')
    return c - 'A';
  else if (c >= '0' && c <= '9')
    return c - '0' + 52;
  else if (c == '/')
    return 63;
  else if (c == '+')
    return 62;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<debase64>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L23
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L17
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L2
  cmp    $0x2f,%dil
  je     L14
  cmp    $0x2b,%dil
  mov    $0xffffffff,%edx
  mov    $0x3e,%eax
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L17:
  movsbl %al,%eax
  ret
  nopl   0x0(%rax)
L23:
  sub    $0x47,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x4,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x3f,%eax
  ret
```

assistant: ```c
int debase64(char c) {
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  else if (c >= 'A' && c <= 'Z')
    return c - 'A';
  else if (c >= '0' && c <= '9')
    return c - '0' + 52;
  else if (c == '/')
    return 63;
  else if (c == '+')
    return 62;
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SSIDataGetNonBlocking>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  cltq
  mov    (%rax),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L7
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L5
L7:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int32_t SSIDataGetNonBlocking(uint32_t ui32Base, uint32_t *pui32Data) {
  ;
  if ((*((volatile uint32_t *)(ui32Base + 0x0000000C))) & 0x00000004) {
    *pui32Data = (*((volatile uint32_t *)(ui32Base + 0x00000008)));
    return (1);
  } else {
    return (0);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SSIDataGetNonBlocking>:
  endbr64
  lea    0xc(%rdi),%eax
  cltq
  mov    (%rax),%eax
  and    $0x4,%eax
  je     L1
  add    $0x8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  mov    $0x1,%eax
L1:
  ret
```

assistant: ```c
int32_t SSIDataGetNonBlocking(uint32_t ui32Base, uint32_t *pui32Data) {
  ;
  if ((*((volatile uint32_t *)(ui32Base + 0x0000000C))) & 0x00000004) {
    *pui32Data = (*((volatile uint32_t *)(ui32Base + 0x00000008)));
    return (1);
  } else {
    return (0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<SSIDataGetNonBlocking>:
  endbr64
  lea    0xc(%rdi),%eax
  cltq
  mov    (%rax),%eax
  and    $0x4,%eax
  je     L6
  add    $0x8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  mov    $0x1,%eax
L6:
  ret
```

assistant: ```c
int32_t SSIDataGetNonBlocking(uint32_t ui32Base, uint32_t *pui32Data) {
  ;
  if ((*((volatile uint32_t *)(ui32Base + 0x0000000C))) & 0x00000004) {
    *pui32Data = (*((volatile uint32_t *)(ui32Base + 0x00000008)));
    return (1);
  } else {
    return (0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SSIDataGetNonBlocking>:
  endbr64
  lea    0xc(%rdi),%eax
  cltq
  mov    (%rax),%eax
  and    $0x4,%eax
  je     L8
  add    $0x8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  mov    $0x1,%eax
L8:
  ret
```

assistant: ```c
int32_t SSIDataGetNonBlocking(uint32_t ui32Base, uint32_t *pui32Data) {
  ;
  if ((*((volatile uint32_t *)(ui32Base + 0x0000000C))) & 0x00000004) {
    *pui32Data = (*((volatile uint32_t *)(ui32Base + 0x00000008)));
    return (1);
  } else {
    return (0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x12(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x60,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    $0x7b,%eax
  sub    %edx,%eax
  mov    %al,-0x11(%rbp)
  movsbl -0x11(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: %c

assistant: ```c
int main() {
  char a, b;
  int c, d;
  scanf("%c", &a);
  c = a;
  d = c - 96;
  b = 123 - d;
  printf("%c", b);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: %c

assistant: ```c
int main() {
  char a, b;
  int c, d;
  scanf("%c", &a);
  c = a;
  d = c - 96;
  b = 123 - d;
  printf("%c", b);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  mov    %rbp,%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: %c

assistant: ```c
int main() {
  char a, b;
  int c, d;
  scanf("%c", &a);
  c = a;
  d = c - 96;
  b = 123 - d;
  printf("%c", b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  mov    %rbp,%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0: %c

assistant: ```c
int main() {
  char a, b;
  int c, d;
  scanf("%c", &a);
  c = a;
  d = c - 96;
  b = 123 - d;
  printf("%c", b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nanosleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int nanosleep(const struct timespec *requested_time, struct timespec *remaining) {
  remaining->tv_sec = 0;
  remaining->tv_nsec = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nanosleep>:
  endbr64
  movq   $0x0,0x8(%rsi)
  movq   $0x0,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int nanosleep(const struct timespec *requested_time, struct timespec *remaining) {
  remaining->tv_sec = 0;
  remaining->tv_nsec = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nanosleep>:
  endbr64
  movq   $0x0,0x8(%rsi)
  xor    %eax,%eax
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
int nanosleep(const struct timespec *requested_time, struct timespec *remaining) {
  remaining->tv_sec = 0;
  remaining->tv_nsec = 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nanosleep>:
  endbr64
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movups %xmm0,(%rsi)
  ret
```

assistant: ```c
int nanosleep(const struct timespec *requested_time, struct timespec *remaining) {
  remaining->tv_sec = 0;
  remaining->tv_nsec = 0;
  return 0;
}
```