ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<nextline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  movzbl (%rdx),%eax
  test   %al,%al
  je     L90
  mov    %rdi,%r13
  mov    %rdx,%rbp
  cmp    $0xa,%al
  je     L167
  cmp    $0xd,%al
  je     L167
  mov    %rdx,%rbx
  mov    $0x2401,%edx
L119:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0xd,%al
  ja     L119
  bt     %rax,%rdx
  jae    L119
  mov    %rbx,%r12
  sub    %rbp,%r12
  add    $0x1,%r12d
  test   %al,%al
  jne    L96
L15:
  test   %r12d,%r12d
  je     L66
  mov    0x0(%r13),%r14
  test   %r14,%r14
  je     L78
  movslq %r12d,%r15
  mov    0x8(%rsp),%rax
  cmp    %r15,(%rax)
  jb     L175
L151:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  mov    0x0(%r13),%rax
  movb   $0x0,-0x1(%rax,%r12,1)
L66:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L167:
  mov    %rbp,%rbx
  mov    $0x1,%r12d
L96:
  cmp    $0xa,%al
  je     L36
  cmp    $0xd,%al
  jne    L15
  cmpb   $0xa,0x1(%rbx)
  jne    L15
  add    $0x2,%rbx
  jmp    L15
L36:
  add    $0x1,%rbx
  jmp    L15
L78:
  mov    %r12d,%edi
  call   <malloc@plt>
  movslq %r12d,%r15
  jmp    L137
L175:
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <realloc@plt>
L137:
  mov    %rax,0x0(%r13)
  mov    0x8(%rsp),%rax
  mov    %r15,(%rax)
  mov    0x0(%r13),%r14
  test   %r14,%r14
  jne    L151
  lea    D9(%rip),%rdi
  call   <debug@plt>
  mov    %r14,%rbx
  jmp    L66
L90:
  mov    $0x0,%ebx
  jmp    L66
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: [nextline] Insufficient memory!


assistant: ```c
const char *nextline(char **lineptr, size_t *n, const char *text) {
  int len;
  const char *to = text;
  if (!*to)
    return NULL;
  while (*to && *to != '\n' && *to != '\r')
    to++;
  len = to - text + 1;
  if (*to) {
    if (*to == '\n')
      to++;
    else if (*to == '\r' && *(to + 1) == '\n')
      to += 2;
  }
  if (!len)
    return to;
  if (!*lineptr) {
    *lineptr = malloc(len);
    *n = len;
  } else if (*n < len) {
    *lineptr = realloc(*lineptr, len);
    *n = len;
  }
  if (!*lineptr) {
    debug("[nextline] Insufficient memory!\n");
    return 0;
  }
  memcpy(*lineptr, text, len);
  (*lineptr)[len - 1] = 0;
  return to;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdx),%eax
  test   %al,%al
  je     L142
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %rdx,%rcx
  lea    0x1(%rdx),%r12
  mov    $0x1,%r13d
  cmp    $0xa,%al
  jne    L81
  jmp    L199
  nopl   0x0(%rax)
L169:
  lea    0x1(%rcx),%r12
  test   %al,%al
  je     L22
  cmp    $0xa,%al
  je     L22
  mov    %r12,%rcx
L81:
  mov    %eax,%edx
  movzbl 0x1(%rcx),%eax
  cmp    $0xd,%dl
  jne    L169
  mov    %rcx,%r13
  sub    %rbp,%r13
  add    $0x1,%r13d
L104:
  cmpb   $0xa,0x1(%rcx)
  mov    %rcx,%r12
  je     L184
L49:
  test   %r13d,%r13d
  je     L33
L199:
  mov    (%rbx),%rdi
  movslq %r13d,%r15
  test   %rdi,%rdi
  je     L75
  cmp    %r15,(%r14)
  jb     L12
L1:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    (%rbx),%rax
  movb   $0x0,-0x1(%rax,%r15,1)
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    %r12,%r13
  sub    %rbp,%r13
  add    $0x1,%r13d
  test   %al,%al
  je     L49
  cmp    $0xa,%al
  jne    L138
  lea    0x2(%rcx),%r12
  test   %r13d,%r13d
  jne    L199
  jmp    L33
  nopl   (%rax)
L75:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
L166:
  mov    %rdi,(%rbx)
  mov    %r15,(%r14)
  test   %rdi,%rdi
  jne    L1
  lea    D5(%rip),%rdi
  xor    %r12d,%r12d
  call   <debug@plt>
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L184:
  add    $0x2,%r12
  jmp    L49
  nopl   0x0(%rax)
L142:
  xor    %r12d,%r12d
  jmp    L33
  nopl   (%rax)
L12:
  mov    %r13d,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  jmp    L166
L138:
  mov    %r12,%rcx
  jmp    L104
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: [nextline] Insufficient memory!


assistant: ```c
const char *nextline(char **lineptr, size_t *n, const char *text) {
  int len;
  const char *to = text;
  if (!*to)
    return NULL;
  while (*to && *to != '\n' && *to != '\r')
    to++;
  len = to - text + 1;
  if (*to) {
    if (*to == '\n')
      to++;
    else if (*to == '\r' && *(to + 1) == '\n')
      to += 2;
  }
  if (!len)
    return to;
  if (!*lineptr) {
    *lineptr = malloc(len);
    *n = len;
  } else if (*n < len) {
    *lineptr = realloc(*lineptr, len);
    *n = len;
  }
  if (!*lineptr) {
    debug("[nextline] Insufficient memory!\n");
    return 0;
  }
  memcpy(*lineptr, text, len);
  (*lineptr)[len - 1] = 0;
  return to;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nextline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdx),%eax
  test   %al,%al
  je     L73
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %rdx,%rcx
  lea    0x1(%rdx),%r12
  mov    $0x1,%r13d
  cmp    $0xa,%al
  jne    L26
  jmp    L35
  nopl   0x0(%rax)
L135:
  lea    0x1(%rcx),%r12
  test   %al,%al
  je     L183
  cmp    $0xa,%al
  je     L183
  mov    %r12,%rcx
L26:
  mov    %eax,%edx
  movzbl 0x1(%rcx),%eax
  cmp    $0xd,%dl
  jne    L135
  mov    %rcx,%r13
  sub    %rbp,%r13
  add    $0x1,%r13d
L178:
  cmpb   $0xa,0x1(%rcx)
  mov    %rcx,%r12
  je     L198
L88:
  test   %r13d,%r13d
  je     L59
L35:
  mov    (%rbx),%rdi
  movslq %r13d,%r15
  test   %rdi,%rdi
  je     L90
  cmp    %r15,(%r14)
  jb     L174
L197:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    (%rbx),%rax
  movb   $0x0,-0x1(%rax,%r15,1)
L59:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L183:
  mov    %r12,%r13
  sub    %rbp,%r13
  add    $0x1,%r13d
  test   %al,%al
  je     L88
  cmp    $0xa,%al
  jne    L16
  lea    0x2(%rcx),%r12
  test   %r13d,%r13d
  jne    L35
  jmp    L59
  nopl   (%rax)
L90:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
L31:
  mov    %rdi,(%rbx)
  mov    %r15,(%r14)
  test   %rdi,%rdi
  jne    L197
  lea    D5(%rip),%rdi
  xor    %r12d,%r12d
  call   <debug@plt>
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L198:
  add    $0x2,%r12
  jmp    L88
  nopl   0x0(%rax)
L73:
  xor    %r12d,%r12d
  jmp    L59
  nopl   (%rax)
L174:
  mov    %r13d,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  jmp    L31
L16:
  mov    %r12,%rcx
  jmp    L178
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: [nextline] Insufficient memory!


assistant: ```c
const char *nextline(char **lineptr, size_t *n, const char *text) {
  int len;
  const char *to = text;
  if (!*to)
    return NULL;
  while (*to && *to != '\n' && *to != '\r')
    to++;
  len = to - text + 1;
  if (*to) {
    if (*to == '\n')
      to++;
    else if (*to == '\r' && *(to + 1) == '\n')
      to += 2;
  }
  if (!len)
    return to;
  if (!*lineptr) {
    *lineptr = malloc(len);
    *n = len;
  } else if (*n < len) {
    *lineptr = realloc(*lineptr, len);
    *n = len;
  }
  if (!*lineptr) {
    debug("[nextline] Insufficient memory!\n");
    return 0;
  }
  memcpy(*lineptr, text, len);
  (*lineptr)[len - 1] = 0;
  return to;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L4
L8:
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rbx
  mov    %rbx,%rax
  shl    $0x2,%rax
  add    %rbx,%rax
  add    %rax,%rax
  mov    %rcx,%rbx
  sub    %rax,%rbx
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %rbx,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  subl   $0x1,-0x2c(%rbp)
L4:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L8
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long reverse(long n, int d) {
  long reverse_n = 0;
  while (d > 0) {
    reverse_n += (n % 10) * pow(10, d - 1);
    n /= 10;
    d--;
  }
  return reverse_n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%r12d
  movabs $0x6666666666666667,%r13
L25:
  sub    $0x1,%ebp
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %rbx,%rax
  imul   %r13
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  imul   %rcx,%rbx
  add    %rbx,%r12
  mov    %rdx,%rbx
  test   %ebp,%ebp
  jne    L25
L26:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%r12d
  jmp    L26
```

assistant: ```c
long reverse(long n, int d) {
  long reverse_n = 0;
  while (d > 0) {
    reverse_n += (n % 10) * pow(10, d - 1);
    n /= 10;
    d--;
  }
  return reverse_n;
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rbx
  mov    %esi,%r13d
  xor    %r12d,%r12d
  movabs $0x6666666666666667,%rbp
  nopl   (%rax)
L18:
  sub    $0x1,%r13d
  mov    $0xa,%edi
  mov    %r13d,%esi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  imul   %rbp
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  imul   %r8,%rbx
  add    %rbx,%r12
  mov    %rdx,%rbx
  test   %r13d,%r13d
  jne    L18
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long reverse(long n, int d) {
  long reverse_n = 0;
  while (d > 0) {
    reverse_n += (n % 10) * pow(10, d - 1);
    n /= 10;
    d--;
  }
  return reverse_n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rbx
  mov    %esi,%r13d
  xor    %r12d,%r12d
  movabs $0x6666666666666667,%rbp
  nopl   (%rax)
L10:
  sub    $0x1,%r13d
  mov    $0xa,%edi
  mov    %r13d,%esi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  imul   %rbp
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  imul   %r8,%rbx
  add    %rbx,%r12
  mov    %rdx,%rbx
  test   %r13d,%r13d
  jne    L10
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long reverse(long n, int d) {
  long reverse_n = 0;
  while (d > 0) {
    reverse_n += (n % 10) * pow(10, d - 1);
    n /= 10;
    d--;
  }
  return reverse_n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recur_piapprox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L82
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D38(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%eax
  test   %rax,%rax
  js     L68
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L55
L68:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L55:
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D38(%rip),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%eax
  test   %rax,%rax
  js     L41
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L38
L41:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L38:
  divsd  %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L29
L82:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D38(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%eax
  test   %rax,%rax
  js     L95
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L81
L95:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L81:
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D38(%rip),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%eax
  test   %rax,%rax
  js     L54
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L97
L54:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L97:
  divsd  %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <recur_piapprox>
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L29:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D38
data_type: f64
name: disassemble_data
arguments: data_label: D13
data_type: f64

tool: D38: 0.5

tool: D13: 1

assistant: ```c
double recur_piapprox(int index, unsigned int n) {
  double result;
  double approx;
  if (index == 1)
    result = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
  else {
    approx = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
    result = approx + recur_piapprox(index - 1, n);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recur_piapprox>:
  endbr64
  cmp    $0x1,%edi
  jne    L3
  mov    %esi,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  movsd  D4(%rip),%xmm2
  movapd %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  D26(%rip),%xmm0
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
L3:
  sub    $0x18,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  subsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  mov    %esi,%eax
  pxor   %xmm4,%xmm4
  cvtsi2sd %rax,%xmm4
  movsd  %xmm4,0x8(%rsp)
  sub    $0x1,%edi
  call   <recur_piapprox>
  movapd %xmm0,%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm3,%xmm1
  movsd  0x8(%rsp),%xmm4
  divsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm1
  divsd  %xmm4,%xmm1
  movsd  D26(%rip),%xmm0
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: f64
name: read_data
arguments: data_tag: D26
data_type: f64

tool: D4: 0.5

tool: D26: 1

assistant: ```c
double recur_piapprox(int index, unsigned int n) {
  double result;
  double approx;
  if (index == 1)
    result = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
  else {
    approx = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
    result = approx + recur_piapprox(index - 1, n);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recur_piapprox>:
  endbr64
  mov    %esi,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  cmp    $0x1,%edi
  jne    L0
  movsd  D29(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  divsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L0:
  pxor   %xmm3,%xmm3
  sub    $0x18,%rsp
  cvtsi2sd %edi,%xmm3
  subsd  D29(%rip),%xmm3
  sub    $0x1,%edi
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <recur_piapprox>
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm4
  movsd  D0(%rip),%xmm0
  add    $0x18,%rsp
  movapd %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D29
datatype: f64
name: read_data
arguments: label: D0
datatype: f64

tool: D29: 0.5

tool: D0: 1

assistant: ```c
double recur_piapprox(int index, unsigned int n) {
  double result;
  double approx;
  if (index == 1)
    result = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
  else {
    approx = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
    result = approx + recur_piapprox(index - 1, n);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<recur_piapprox>:
  endbr64
  mov    %esi,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  cmp    $0x1,%edi
  jne    L0
  movsd  D27(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D39(%rip),%xmm0
  divsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L0:
  pxor   %xmm1,%xmm1
  movsd  D27(%rip),%xmm4
  lea    -0x1(%rdi),%eax
  cvtsi2sd %edi,%xmm1
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D39(%rip),%xmm1
  movapd %xmm1,%xmm3
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm3
  cmp    $0x2,%edi
  jne    L46
  movapd %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L46:
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm5
  lea    -0x2(%rdi),%eax
  subsd  %xmm4,%xmm5
  movapd %xmm5,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm5,%xmm0
  movapd %xmm1,%xmm5
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm5
  cmp    $0x3,%edi
  jne    L27
  movapd %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
L13:
  addsd  %xmm5,%xmm1
  addsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
  nopl   (%rax)
L27:
  pxor   %xmm6,%xmm6
  cvtsi2sd %eax,%xmm6
  lea    -0x3(%rdi),%eax
  subsd  %xmm4,%xmm6
  movapd %xmm6,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm0
  movapd %xmm1,%xmm6
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm6
  cmp    $0x4,%edi
  jne    L7
  movapd %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  addsd  %xmm6,%xmm1
  jmp    L13
  xchg   %ax,%ax
L7:
  pxor   %xmm7,%xmm7
  sub    $0x38,%rsp
  sub    $0x4,%edi
  cvtsi2sd %eax,%xmm7
  movsd  %xmm6,0x28(%rsp)
  movsd  %xmm5,0x20(%rsp)
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  subsd  %xmm4,%xmm7
  movsd  %xmm7,0x8(%rsp)
  call   <recur_piapprox>
  movsd  0x8(%rsp),%xmm7
  movsd  0x18(%rsp),%xmm2
  movapd %xmm0,%xmm4
  mov    D39(%rip),%rax
  movsd  0x28(%rsp),%xmm6
  movapd %xmm7,%xmm0
  movsd  0x20(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm2,%xmm0
  movq   %rax,%xmm1
  mulsd  %xmm7,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  addsd  %xmm6,%xmm1
  addsd  %xmm5,%xmm1
  addsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type: f64
name: disassemble_data
arguments: data_label: D39
type: f64

tool: D27: 0.5

tool: D39: 1

assistant: ```c
double recur_piapprox(int index, unsigned int n) {
  double result;
  double approx;
  if (index == 1)
    result = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
  else {
    approx = 1.0 / (1.0 + (((double)index) - 0.5) / ((double)n) * (((double)index) - 0.5) / ((double)n));
    result = approx + recur_piapprox(index - 1, n);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<chess_square_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <chess_square@plt>
  leave
  ret
```

assistant: ```c
int chess_square_index(const char *square) {
  int rank, file;
  file = square[0] - 97;
  rank = atoi(++square) - 1;
  return chess_square(rank, file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chess_square_index>:
  endbr64
  push   %rbx
  movsbl (%rdi),%ebx
  sub    $0x61,%ebx
  add    $0x1,%rdi
  call   <atoi@plt>
  lea    -0x1(%rax),%edi
  mov    %ebx,%esi
  call   <chess_square@plt>
  pop    %rbx
  ret
```

assistant: ```c
int chess_square_index(const char *square) {
  int rank, file;
  file = square[0] - 97;
  rank = atoi(++square) - 1;
  return chess_square(rank, file);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<chess_square_index>:
  endbr64
  push   %rbp
  movsbl (%rdi),%ebp
  add    $0x1,%rdi
  sub    $0x61,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  pop    %rbp
  lea    -0x1(%rax),%edi
  jmp    1060 <chess_square@plt>
```

assistant: ```c
int chess_square_index(const char *square) {
  int rank, file;
  file = square[0] - 97;
  rank = atoi(++square) - 1;
  return chess_square(rank, file);
}
```