ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_group>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdx),%r15
  mov    (%rdi),%rsi
  cmp    (%r12),%rsi
  je     L10
L57:
  mov    %r14d,(%r15,%rsi,4)
  add    $0x1,%rsi
  mov    %rsi,0x0(%rbp)
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rdx,%r13
  test   %rcx,%rcx
  jle    L33
  cmp    %rcx,%rsi
  je     L22
  add    %esi,%esi
  mov    %rcx,%rdi
  call   <MIN@plt>
  mov    %rax,%rbx
L28:
  mov    %r15,%rdi
  lea    0x0(,%rbx,4),%rsi
  call   <realloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L22
  mov    %rax,0x0(%r13)
  mov    %rbx,(%r12)
  mov    0x0(%rbp),%rsi
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L33:
  lea    (%rsi,%rsi,1),%rbx
  jmp    L28
```

assistant: ```c
void add_group(long int *start, long int *size, gid_t **groupsp, long int limit, gid_t gid) {
  gid_t *groups = *groupsp;
  if (*start == *size) {
    gid_t *newgroups;
    long int newsize;
    if (limit > 0 && *size == limit)
      return;
    if (limit <= 0)
      newsize = 2 * *size;
    else
      newsize = MIN(limit, 2 * *size);
    newgroups = realloc(groups, newsize * sizeof(*groups));
    if (newgroups == NULL)
      return;
    *groupsp = groups = newgroups;
    *size = newsize;
  }
  groups[*start] = gid;
  *start += 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getttynam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x5,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L16
  addq   $0x5,-0x18(%rbp)
L16:
  mov    $0x0,%eax
  call   <setttyent@plt>
  jmp    L22
L5:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L18
L22:
  mov    $0x0,%eax
  call   <getttyent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  jmp    L7
L18:
  nop
L7:
  mov    $0x0,%eax
  call   <endttyent@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: /dev/

assistant: ```c
struct ttyent *getttynam(const char *tty) {
  struct ttyent *t;
  if (strncmp(tty, "/dev/", 5) == 0)
    tty += 5;
  setttyent();
  while ((t = getttyent()))
    if (!strcmp(tty, t->ty_name))
      break;
  endttyent();
  return (t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getttynam>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x5,%edx
  lea    D2(%rip),%rsi
  call   <strncmp@plt>
  mov    %rax,%rdx
  lea    0x5(%rbp),%rax
  test   %rdx,%rdx
  cmove  %rax,%rbp
  mov    $0x0,%eax
  call   <setttyent@plt>
L14:
  mov    $0x0,%eax
  call   <getttyent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L14
L12:
  mov    $0x0,%eax
  call   <endttyent@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: /dev/

assistant: ```c
struct ttyent *getttynam(const char *tty) {
  struct ttyent *t;
  if (strncmp(tty, "/dev/", 5) == 0)
    tty += 5;
  setttyent();
  while ((t = getttyent()))
    if (!strcmp(tty, t->ty_name))
      break;
  endttyent();
  return (t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getttynam>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  lea    D2(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strncmp@plt>
  mov    %rax,%r8
  lea    0x5(%rbx),%rax
  test   %r8,%r8
  cmove  %rax,%rbx
  xor    %eax,%eax
  call   <setttyent@plt>
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
L2:
  xor    %eax,%eax
  call   <getttyent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L4
L14:
  xor    %eax,%eax
  call   <endttyent@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D2: /dev/

assistant: ```c
struct ttyent *getttynam(const char *tty) {
  struct ttyent *t;
  if (strncmp(tty, "/dev/", 5) == 0)
    tty += 5;
  setttyent();
  while ((t = getttyent()))
    if (!strcmp(tty, t->ty_name))
      break;
  endttyent();
  return (t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getttynam>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  lea    D9(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strncmp@plt>
  mov    %rax,%r8
  lea    0x5(%rbx),%rax
  test   %r8,%r8
  cmove  %rax,%rbx
  xor    %eax,%eax
  call   <setttyent@plt>
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L12
L21:
  xor    %eax,%eax
  call   <getttyent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L14
L12:
  xor    %eax,%eax
  call   <endttyent@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: /dev/

assistant: ```c
struct ttyent *getttynam(const char *tty) {
  struct ttyent *t;
  if (strncmp(tty, "/dev/", 5) == 0)
    tty += 5;
  setttyent();
  while ((t = getttyent()))
    if (!strcmp(tty, t->ty_name))
      break;
  endttyent();
  return (t);
}
```
user: What is the c source code of the assembly code below:

```asm
<Q_stricmpn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
L107:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L89
  mov    $0x0,%eax
  jmp    L79
L89:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L106
  cmpl   $0x60,-0x8(%rbp)
  jle    L72
  cmpl   $0x7a,-0x8(%rbp)
  jg     L72
  subl   $0x20,-0x8(%rbp)
L72:
  cmpl   $0x60,-0x4(%rbp)
  jle    L54
  cmpl   $0x7a,-0x4(%rbp)
  jg     L54
  subl   $0x20,-0x4(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L106
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L108
  mov    $0xffffffff,%eax
  jmp    L79
L108:
  mov    $0x1,%eax
  jmp    L79
L106:
  cmpl   $0x0,-0x8(%rbp)
  jne    L107
  mov    $0x0,%eax
L79:
  pop    %rbp
  ret
```

assistant: ```c
int Q_stricmpn(const char *s1, const char *s2, int n) {
  int c1;
  do {
    int c2;
    c1 = *s1++;
    c2 = *s2++;
    if (!n--) {
      return 0;
    }
    if (c1 != c2) {
      if (c1 >= 'a' && c1 <= 'z') {
        c1 -= ('a' - 'A');
      }
      if (c2 >= 'a' && c2 <= 'z') {
        c2 -= ('a' - 'A');
      }
      if (c1 != c2) {
        return c1 < c2 ? -1 : 1;
      }
    }
  } while (c1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Q_stricmpn>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %edx,%edx
  mov    $0x0,%esi
  jmp    L45
L19:
  mov    %edi,%r8d
  mov    %eax,%edi
L43:
  cmp    %edi,%r8d
  setge  %dil
  movzbl %dil,%edi
  lea    -0x1(%rdi,%rdi,1),%edi
  jmp    L0
L32:
  mov    $0x0,%edi
L0:
  mov    %edi,%eax
  ret
L15:
  movsbl %cl,%ecx
  sub    $0x61,%ecx
  cmp    $0x19,%ecx
  ja     L43
L41:
  lea    -0x20(%rdi),%eax
  mov    %r8d,%edi
L21:
  cmp    %edi,%eax
  jne    L19
L8:
  add    $0x1,%rsi
  test   %edi,%edi
  je     L0
L45:
  movzbl (%r9,%rsi,1),%eax
  movsbl %al,%r8d
  movzbl (%r10,%rsi,1),%ecx
  movsbl %cl,%edi
  cmp    %rdx,%rsi
  je     L32
  cmp    %edi,%r8d
  je     L8
  mov    %r8d,%eax
  sub    $0x61,%eax
  cmp    $0x19,%eax
  ja     L15
  sub    $0x20,%r8d
  mov    %edi,%ecx
  sub    $0x61,%ecx
  cmp    $0x19,%ecx
  jbe    L41
  mov    %edi,%eax
  mov    %r8d,%edi
  jmp    L21
```

assistant: ```c
int Q_stricmpn(const char *s1, const char *s2, int n) {
  int c1;
  do {
    int c2;
    c1 = *s1++;
    c2 = *s2++;
    if (!n--) {
      return 0;
    }
    if (c1 != c2) {
      if (c1 >= 'a' && c1 <= 'z') {
        c1 -= ('a' - 'A');
      }
      if (c2 >= 'a' && c2 <= 'z') {
        c2 -= ('a' - 'A');
      }
      if (c1 != c2) {
        return c1 < c2 ? -1 : 1;
      }
    }
  } while (c1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Q_stricmpn>:
  endbr64
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L47:
  sub    $0x20,%r8d
  cmp    $0x19,%r10d
  jbe    L75
  mov    %eax,%r9d
  mov    %r8d,%eax
L23:
  cmp    %r8d,%r9d
  jne    L13
L87:
  add    $0x1,%rcx
  test   %eax,%eax
  je     L29
L34:
  movsbl (%rdi,%rcx,1),%r8d
  movsbl (%rsi,%rcx,1),%eax
  cmp    %rcx,%rdx
  je     L74
  cmp    %eax,%r8d
  je     L87
  lea    -0x61(%r8),%r9d
  lea    -0x61(%rax),%r10d
  cmp    $0x19,%r9d
  jbe    L47
  cmp    $0x19,%r10d
  ja     L40
L75:
  lea    -0x20(%rax),%r9d
  mov    %r8d,%eax
  jmp    L23
  nopl   (%rax)
L74:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  ret
L13:
  mov    %r9d,%eax
L40:
  cmp    %eax,%r8d
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int Q_stricmpn(const char *s1, const char *s2, int n) {
  int c1;
  do {
    int c2;
    c1 = *s1++;
    c2 = *s2++;
    if (!n--) {
      return 0;
    }
    if (c1 != c2) {
      if (c1 >= 'a' && c1 <= 'z') {
        c1 -= ('a' - 'A');
      }
      if (c2 >= 'a' && c2 <= 'z') {
        c2 -= ('a' - 'A');
      }
      if (c1 != c2) {
        return c1 < c2 ? -1 : 1;
      }
    }
  } while (c1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Q_stricmpn>:
  endbr64
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L89:
  sub    $0x20,%r8d
  cmp    $0x19,%r10d
  jbe    L41
  mov    %eax,%r9d
  mov    %r8d,%eax
L4:
  cmp    %r8d,%r9d
  jne    L62
L19:
  add    $0x1,%rcx
  test   %eax,%eax
  je     L45
L30:
  movsbl (%rdi,%rcx,1),%r8d
  movsbl (%rsi,%rcx,1),%eax
  cmp    %rcx,%rdx
  je     L80
  cmp    %eax,%r8d
  je     L19
  lea    -0x61(%r8),%r9d
  lea    -0x61(%rax),%r10d
  cmp    $0x19,%r9d
  jbe    L89
  cmp    $0x19,%r10d
  ja     L54
L41:
  lea    -0x20(%rax),%r9d
  mov    %r8d,%eax
  jmp    L4
  nopl   (%rax)
L80:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  ret
L62:
  mov    %r9d,%eax
L54:
  cmp    %eax,%r8d
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int Q_stricmpn(const char *s1, const char *s2, int n) {
  int c1;
  do {
    int c2;
    c1 = *s1++;
    c2 = *s2++;
    if (!n--) {
      return 0;
    }
    if (c1 != c2) {
      if (c1 >= 'a' && c1 <= 'z') {
        c1 -= ('a' - 'A');
      }
      if (c2 >= 'a' && c2 <= 'z') {
        c2 -= ('a' - 'A');
      }
      if (c1 != c2) {
        return c1 < c2 ? -1 : 1;
      }
    }
  } while (c1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rotsArePrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <findMul@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L6
L36:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x0,%eax
  jmp    L25
L20:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L36
  mov    $0x1,%eax
L25:
  leave
  ret
```

assistant: ```c
int rotsArePrime(int n) {
  int num = n;
  int mul = findMul(n);
  int tmp = n;
  while (tmp) {
    if (!isPrime(n))
      return 0;
    int main = n / 10;
    int top = n % 10;
    n = main + top * mul;
    tmp /= 10;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rotsArePrime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  call   <findMul@plt>
  test   %ebx,%ebx
  je     L20
  mov    %eax,%r12d
  mov    %ebx,%ebp
L22:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %eax,%eax
  je     L17
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %r12d,%ebx
  add    %eax,%ebx
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ebp
  sub    %ebp,%eax
  mov    %eax,%ebp
  jne    L22
  mov    $0x1,%eax
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x1,%eax
  jmp    L17
```

assistant: ```c
int rotsArePrime(int n) {
  int num = n;
  int mul = findMul(n);
  int tmp = n;
  while (tmp) {
    if (!isPrime(n))
      return 0;
    int main = n / 10;
    int top = n % 10;
    n = main + top * mul;
    tmp /= 10;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotsArePrime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  call   <findMul@plt>
  test   %ebx,%ebx
  je     L23
  mov    %eax,%ebp
  mov    %ebx,%r12d
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  mov    %r12d,%edx
  imul   %ebp,%ebx
  sar    $0x1f,%edx
  add    %eax,%ebx
  movslq %r12d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%r12d
  je     L23
L31:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %eax,%eax
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int rotsArePrime(int n) {
  int num = n;
  int mul = findMul(n);
  int tmp = n;
  while (tmp) {
    if (!isPrime(n))
      return 0;
    int main = n / 10;
    int top = n % 10;
    n = main + top * mul;
    tmp /= 10;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rotsArePrime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  call   <findMul@plt>
  test   %ebx,%ebx
  je     L18
  mov    %eax,%ebp
  mov    %ebx,%r12d
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L15:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  mov    %r12d,%edx
  imul   %ebp,%ebx
  sar    $0x1f,%edx
  add    %eax,%ebx
  movslq %r12d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%r12d
  je     L18
L27:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %eax,%eax
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int rotsArePrime(int n) {
  int num = n;
  int mul = findMul(n);
  int tmp = n;
  while (tmp) {
    if (!isPrime(n))
      return 0;
    int main = n / 10;
    int top = n % 10;
    n = main + top * mul;
    tmp /= 10;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trapezoid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D20(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L46
L59:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L46:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L59
  jmp    L20
L50:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L50
  jmp    L4
L56:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  D20(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L56
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D20
type: f64
name: parse_data
arguments: label: D22
type: f64

tool: D20: 4

tool: D22: 1

assistant: ```c
double *trapezoid(double *w, const int leng) {
  int k, m1, m2;
  double *p, slope;
  m1 = leng / 4;
  m2 = (leng * 3) / 4;
  slope = 4.0 / (double)(leng - 1);
  for (k = 0, p = w; k < m1; k++)
    *p++ = slope * k;
  for (; k < m2; k++)
    *p++ = 1.0;
  for (; k < leng; k++)
    *p++ = 4.0 - slope * k;
  return (w);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trapezoid>:
  endbr64
  mov    %rdi,%r8
  lea    0x3(%rsi),%ecx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x2,%ecx
  lea    (%rsi,%rsi,2),%eax
  lea    0x3(%rax),%r9d
  test   %eax,%eax
  cmovns %eax,%r9d
  sar    $0x2,%r9d
  mov    %r9d,%edx
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D13(%rip),%xmm1
  divsd  %xmm0,%xmm1
  cmp    $0x3,%esi
  jle    L71
  mov    $0x0,%eax
L52:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L52
  lea    -0x1(%rcx),%eax
  lea    0x8(,%rax,8),%rax
  cmp    $0x3,%esi
  mov    $0x8,%edi
  cmovle %rdi,%rax
  add    %r8,%rax
  test   %ecx,%ecx
  mov    $0x1,%edi
  cmovg  %ecx,%edi
L55:
  cmp    %edi,%r9d
  jle    L46
  sub    $0x1,%r9d
  sub    %edi,%r9d
  lea    0x8(%rax,%r9,8),%rcx
  movsd  D4(%rip),%xmm0
L49:
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L49
L64:
  cmp    %edx,%esi
  jle    L35
  movsd  D13(%rip),%xmm3
L0:
  add    $0x8,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm3,%xmm2
  subsd  %xmm0,%xmm2
  movsd  %xmm2,-0x8(%rcx)
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L0
L35:
  mov    %r8,%rax
  ret
L71:
  mov    %rdi,%rax
  mov    $0x0,%edi
  jmp    L55
L46:
  mov    %rax,%rcx
  mov    %edi,%edx
  jmp    L64
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: f64
name: unpack_data
arguments: data_tag: D4
data_type: f64

tool: D13: 4

tool: D4: 1

assistant: ```c
double *trapezoid(double *w, const int leng) {
  int k, m1, m2;
  double *p, slope;
  m1 = leng / 4;
  m2 = (leng * 3) / 4;
  slope = 4.0 / (double)(leng - 1);
  for (k = 0, p = w; k < m1; k++)
    *p++ = slope * k;
  for (; k < m2; k++)
    *p++ = 1.0;
  for (; k < leng; k++)
    *p++ = 4.0 - slope * k;
  return (w);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trapezoid>:
  endbr64
  test   %esi,%esi
  lea    0x3(%rsi),%ecx
  lea    (%rsi,%rsi,2),%eax
  mov    %rdi,%r8
  cmovns %esi,%ecx
  lea    0x3(%rax),%edi
  pxor   %xmm0,%xmm0
  movsd  D18(%rip),%xmm3
  sar    $0x2,%ecx
  test   %eax,%eax
  movapd %xmm3,%xmm1
  cmovns %eax,%edi
  lea    -0x1(%rsi),%eax
  cvtsi2sd %eax,%xmm0
  sar    $0x2,%edi
  mov    %edi,%edx
  divsd  %xmm0,%xmm1
  cmp    $0x3,%esi
  jle    L71
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L78:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L78
  test   %ecx,%ecx
  lea    -0x1(%rcx),%eax
  mov    $0x1,%r9d
  cmovg  %ecx,%r9d
  lea    0x8(,%rax,8),%rax
  cmp    $0x3,%esi
  mov    $0x8,%ecx
  cmovle %rcx,%rax
  add    %r8,%rax
  cmp    %r9d,%edi
  jle    L61
L35:
  sub    $0x1,%edi
  movsd  D12(%rip),%xmm0
  sub    %r9d,%edi
  lea    0x8(%rax,%rdi,8),%rcx
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L15
L70:
  cmp    %edx,%esi
  jle    L7
  nopw   0x0(%rax,%rax,1)
L21:
  pxor   %xmm0,%xmm0
  movapd %xmm3,%xmm2
  add    $0x8,%rcx
  cvtsi2sd %edx,%xmm0
  add    $0x1,%edx
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm2
  movsd  %xmm2,-0x8(%rcx)
  cmp    %edx,%esi
  jne    L21
L7:
  mov    %r8,%rax
  ret
L71:
  xor    %r9d,%r9d
  mov    %r8,%rax
  cmp    %r9d,%edi
  jg     L35
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %rax,%rcx
  mov    %r9d,%edx
  jmp    L70
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: f64
name: parse_data
arguments: data_tag: D12
data_type: f64

tool: D18: 4

tool: D12: 1

assistant: ```c
double *trapezoid(double *w, const int leng) {
  int k, m1, m2;
  double *p, slope;
  m1 = leng / 4;
  m2 = (leng * 3) / 4;
  slope = 4.0 / (double)(leng - 1);
  for (k = 0, p = w; k < m1; k++)
    *p++ = slope * k;
  for (; k < m2; k++)
    *p++ = 1.0;
  for (; k < leng; k++)
    *p++ = 4.0 - slope * k;
  return (w);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L40
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L5
L40:
  cmpq   $0x0,-0x20(%rbp)
  jne    L39
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L5
L39:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <findRealPtr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L10
  mov    -0x20(%rbp),%rax
  sub    $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <real_realloc@plt>
  jmp    L5
L10:
  mov    -0x20(%rbp),%rax
  add    $0x100,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <real_realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
L5:
  leave
  ret
```

assistant: ```c
void *realloc(void *ptr, size_t size) {
  if (NULL == ptr)
    return malloc(size);
  if (size == 0) {
    free(ptr);
    return NULL;
  };
  void *realptr = findRealPtr((char *)ptr);
  if (realptr == ptr) {
    ;
    return real_realloc(ptr, size + 128);
  }
  void *newptr = real_realloc(realptr, 128 + size + 128);
  ;
  return newptr + 128;
}
```