user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc4(%rbp)
  movl   $0x0,-0xc0(%rbp)
  movl   $0x0,-0xbc(%rbp)
  movl   $0x0,-0xb8(%rbp)
  movl   $0x0,-0xb4(%rbp)
  movl   $0x0,-0xb0(%rbp)
  jmp    L108
L51:
  movl   $0x0,-0xac(%rbp)
  jmp    L19
L102:
  lea    -0xa0(%rbp),%rcx
  mov    -0xac(%rbp),%eax
  movslq %eax,%rsi
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xac(%rbp)
L19:
  cmpl   $0x5,-0xac(%rbp)
  jle    L102
  addl   $0x1,-0xb0(%rbp)
L108:
  cmpl   $0x5,-0xb0(%rbp)
  jle    L51
  jmp    L32
L98:
  mov    -0xb8(%rbp),%eax
  mov    %eax,-0xa8(%rbp)
  jmp    L88
L117:
  mov    -0xb4(%rbp),%eax
  mov    %eax,-0xa4(%rbp)
  jmp    L8
L86:
  mov    -0xb8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0xa8(%rbp)
  jne    L15
  mov    -0xb8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xb4(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0xa0(%rbp,%rax,4),%eax
  add    %eax,-0xc0(%rbp)
  jmp    L99
L15:
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xa8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0xa0(%rbp,%rax,4),%eax
  add    %eax,-0xc0(%rbp)
  addl   $0x1,-0xa4(%rbp)
L8:
  mov    -0xb4(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0xa4(%rbp)
  jle    L86
L99:
  addl   $0x1,-0xa8(%rbp)
L88:
  mov    -0xb8(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0xa8(%rbp)
  jle    L117
  cmpl   $0x2,-0xb4(%rbp)
  jg     L104
  addl   $0x1,-0xb4(%rbp)
  jmp    L158
L104:
  movl   $0x0,-0xb4(%rbp)
  addl   $0x1,-0xb8(%rbp)
L158:
  mov    -0xc0(%rbp),%eax
  cmp    -0xc4(%rbp),%eax
  jg     L116
  cmpl   $0x0,-0xbc(%rbp)
  jne    L140
L116:
  mov    -0xc0(%rbp),%eax
  mov    %eax,-0xc4(%rbp)
  movl   $0x0,-0xc0(%rbp)
  jmp    L155
L140:
  movl   $0x0,-0xc0(%rbp)
L155:
  addl   $0x1,-0xbc(%rbp)
L32:
  cmpl   $0xf,-0xbc(%rbp)
  jle    L98
  mov    -0xc4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string

tool: D5: %d

tool: D4: %i


assistant: ```c
int main() {
  int arr[6][6];
  int max = 0;
  int sum = 0;
  int n = 0;
  int i = 0;
  int j = 0;
  for (int row = 0; row < 6; row++) {
    for (int column = 0; column < 6; column++) {
      scanf("%d", &arr[row][column]);
    }
  }
  while (n < 16) {
    for (int row = i; row < i + 3; row++) {
      for (int column = j; column < j + 3; column++) {
        if (row == i + 1) {
          sum += arr[i + 1][j + 1];
          break;
        }
        sum += arr[row][column];
      }
    }
    if (j + 3 < 6) {
      j++;
    } else {
      j = 0;
      i++;
    }
    if (sum > max || n == 0) {
      max = sum;
      sum = 0;
    } else {
      sum = 0;
    }
    n++;
  }
  printf("%i\n", max);
  return max;
}
```