ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<MergeSort>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdx,4),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L58
L17:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L17
L58:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L19
L21:
  mov    %rsp,%rdi
  test   %ebx,%ebx
  jle    L34
  shl    $0x2,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rax,%rdi
L34:
  xor    %esi,%esi
  lea    -0x1(%rbx),%edx
  mov    %ebx,%r8d
  mov    %r12,%rcx
  call   <MergeSort_Split@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L21
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MergeSort(int *p, int size, int round) {
  int i, arr[size];
  for (i = 0; i < size; i++)
    arr[i] = p[i];
  MergeSort_Split(arr, 0, size - 1, p, size);
}
```
user: What is the c source code of the assembly code below:

```asm
<MergeSort>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdx,4),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L42
L50:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L50
L42:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L34
L40:
  mov    %rsp,%rdi
  test   %ebx,%ebx
  jle    L23
  shl    $0x2,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rax,%rdi
L23:
  xor    %esi,%esi
  lea    -0x1(%rbx),%edx
  mov    %ebx,%r8d
  mov    %r12,%rcx
  call   <MergeSort_Split@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L40
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MergeSort(int *p, int size, int round) {
  int i, arr[size];
  for (i = 0; i < size; i++)
    arr[i] = p[i];
  MergeSort_Split(arr, 0, size - 1, p, size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<int_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L37
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L0:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cmp    $0x1,%eax
  jg     L0
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L36
  negl   -0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int int_n(unsigned const char *p, int n) {
  int i, sign;
  if (n == 0)
    return 0;
  sign = *p;
  i = *p++ & 127;
  while (n-- > 1) {
    i = i * 256 + (int)*p++;
  }
  if (sign & 0x80)
    i = -i;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<int_n>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L12
  movzbl (%rdi),%r8d
  lea    0x1(%rdi),%rdx
  mov    %r8d,%eax
  and    $0x7f,%eax
  cmp    $0x1,%esi
  jle    L23
  mov    %esi,%esi
  add    %rsi,%rdi
L17:
  shl    $0x8,%eax
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L17
L23:
  mov    %eax,%edx
  neg    %edx
  test   %r8b,%r8b
  cmovs  %edx,%eax
L12:
  ret
```

assistant: ```c
int int_n(unsigned const char *p, int n) {
  int i, sign;
  if (n == 0)
    return 0;
  sign = *p;
  i = *p++ & 127;
  while (n-- > 1) {
    i = i * 256 + (int)*p++;
  }
  if (sign & 0x80)
    i = -i;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<int_n>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L29
  movzbl (%rdi),%r8d
  lea    0x1(%rdi),%rdx
  mov    %r8d,%eax
  and    $0x7f,%eax
  cmp    $0x1,%esi
  jle    L26
  movslq %esi,%rsi
  add    %rsi,%rdi
  nopl   0x0(%rax,%rax,1)
L22:
  movzbl (%rdx),%ecx
  shl    $0x8,%eax
  add    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rdx,%rdi
  jne    L22
L26:
  mov    %eax,%edx
  neg    %edx
  test   %r8b,%r8b
  cmovs  %edx,%eax
L29:
  ret
```

assistant: ```c
int int_n(unsigned const char *p, int n) {
  int i, sign;
  if (n == 0)
    return 0;
  sign = *p;
  i = *p++ & 127;
  while (n-- > 1) {
    i = i * 256 + (int)*p++;
  }
  if (sign & 0x80)
    i = -i;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int_n>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L11
  movzbl (%rdi),%r8d
  lea    0x1(%rdi),%rdx
  mov    %r8d,%eax
  and    $0x7f,%eax
  cmp    $0x1,%esi
  jle    L17
  movslq %esi,%rsi
  add    %rsi,%rdi
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl (%rdx),%ecx
  shl    $0x8,%eax
  add    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rdx,%rdi
  jne    L24
L17:
  mov    %eax,%edx
  neg    %edx
  test   %r8b,%r8b
  cmovs  %edx,%eax
L11:
  ret
```

assistant: ```c
int int_n(unsigned const char *p, int n) {
  int i, sign;
  if (n == 0)
    return 0;
  sign = *p;
  i = *p++ & 127;
  while (n-- > 1) {
    i = i * 256 + (int)*p++;
  }
  if (sign & 0x80)
    i = -i;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<printSBAStructureData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x18,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    $0x0,%ebx
  jmp    L12
L21:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  lea    0x1(%rbx),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
L10:
  add    $0x1,%ebx
L12:
  mov    -0x28(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cmp    %eax,%ebx
  jl     L21
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D14: 

Structure parameters:


tool: D5: %.10e 

assistant: ```c
void printSBAStructureData(FILE *fp, double *motstruct, int ncams, int n3Dpts, int cnp, int pnp) {
  register int i;
  motstruct += ncams * cnp;
  fputs("\n\nStructure parameters:\n", fp);
  for (i = 0; i < n3Dpts * pnp; ++i) {
    fprintf(fp, "%.10e ", motstruct[i]);
    if ((i + 1) % pnp == 0)
      fputc('\n', fp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printSBAStructureData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %ecx,%r14d
  mov    %r9d,%ebp
  imul   %r8d,%edx
  movslq %edx,%rbx
  mov    %rdi,%rcx
  mov    $0x18,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  call   <fwrite@plt>
  mov    %r14d,%eax
  imul   %ebp,%eax
  test   %eax,%eax
  jle    L28
  lea    0x1(%rax),%r15d
  lea    0x0(%r13,%rbx,8),%r14
  mov    $0x1,%ebx
  lea    D7(%rip),%r13
  jmp    L35
L3:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L28
L35:
  movsd  -0x8(%r14,%rbx,8),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L3
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L3
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D7
data_type: string

tool: D2: 

Structure parameters:


tool: D7: %.10e 

assistant: ```c
void printSBAStructureData(FILE *fp, double *motstruct, int ncams, int n3Dpts, int cnp, int pnp) {
  register int i;
  motstruct += ncams * cnp;
  fputs("\n\nStructure parameters:\n", fp);
  for (i = 0; i < n3Dpts * pnp; ++i) {
    fprintf(fp, "%.10e ", motstruct[i]);
    if ((i + 1) % pnp == 0)
      fputc('\n', fp);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printSBAStructureData>:
  endbr64
  push   %r15
  imul   %r8d,%edx
  push   %r14
  mov    %ecx,%r14d
  mov    %rdi,%rcx
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r12
  lea    D12(%rip),%rdi
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  movslq %edx,%rbx
  mov    $0x18,%edx
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %r14d,%eax
  imul   %ebp,%eax
  test   %eax,%eax
  jle    L45
  lea    0x0(%r13,%rbx,8),%r14
  lea    0x1(%rax),%r15d
  mov    $0x1,%ebx
  lea    D8(%rip),%r13
  jmp    L38
  nop
L8:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L45
L38:
  movsd  -0x8(%r14,%rbx,8),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L8
  mov    %r12,%rsi
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r15,%rbx
  jne    L38
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D8
data_type: string

tool: D12: 

Structure parameters:


tool: D8: %.10e 

assistant: ```c
void printSBAStructureData(FILE *fp, double *motstruct, int ncams, int n3Dpts, int cnp, int pnp) {
  register int i;
  motstruct += ncams * cnp;
  fputs("\n\nStructure parameters:\n", fp);
  for (i = 0; i < n3Dpts * pnp; ++i) {
    fprintf(fp, "%.10e ", motstruct[i]);
    if ((i + 1) % pnp == 0)
      fputc('\n', fp);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printSBAStructureData>:
  endbr64
  push   %r15
  imul   %r8d,%edx
  push   %r14
  mov    %ecx,%r14d
  mov    %rdi,%rcx
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r12
  lea    D9(%rip),%rdi
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  movslq %edx,%rbx
  mov    $0x18,%edx
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %r14d,%eax
  imul   %ebp,%eax
  test   %eax,%eax
  jle    L47
  lea    0x0(%r13,%rbx,8),%r14
  lea    0x1(%rax),%r15d
  mov    $0x1,%ebx
  lea    D2(%rip),%r13
  jmp    L10
  nop
L30:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L47
L10:
  movsd  -0x8(%r14,%rbx,8),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L30
  mov    %r12,%rsi
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r15,%rbx
  jne    L10
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string

tool: D9: 

Structure parameters:


tool: D2: %.10e 

assistant: ```c
void printSBAStructureData(FILE *fp, double *motstruct, int ncams, int n3Dpts, int cnp, int pnp) {
  register int i;
  motstruct += ncams * cnp;
  fputs("\n\nStructure parameters:\n", fp);
  for (i = 0; i < n3Dpts * pnp; ++i) {
    fprintf(fp, "%.10e ", motstruct[i]);
    if ((i + 1) % pnp == 0)
      fputc('\n', fp);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L2
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L2:
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int t(int i) {
  int j;
  if (i >= 0)
    j = i;
  else
    j = -i;
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<t>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int t(int i) {
  int j;
  if (i >= 0)
    j = i;
  else
    j = -i;
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<t>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int t(int i) {
  int j;
  if (i >= 0)
    j = i;
  else
    j = -i;
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<t>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int t(int i) {
  int j;
  if (i >= 0)
    j = i;
  else
    j = -i;
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
L3:
  mov    $0x0,%eax
  call   <mcal_cpu_nop@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
```

assistant: ```c
int main(void) {
  volatile uint32_t counter = 0;
  while (1) {
    mcal_cpu_nop();
    counter++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movq   $0x0,0x8(%rsp)
L2:
  mov    $0x0,%eax
  call   <mcal_cpu_nop@plt>
  mov    0x8(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  jmp    L2
```

assistant: ```c
int main(void) {
  volatile uint32_t counter = 0;
  while (1) {
    mcal_cpu_nop();
    counter++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movq   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <mcal_cpu_nop@plt>
  mov    0x8(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  jmp    L8
```

assistant: ```c
int main(void) {
  volatile uint32_t counter = 0;
  while (1) {
    mcal_cpu_nop();
    counter++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movq   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  call   <mcal_cpu_nop@plt>
  mov    0x8(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  jmp    L6
```

assistant: ```c
int main(void) {
  volatile uint32_t counter = 0;
  while (1) {
    mcal_cpu_nop();
    counter++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BPartition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L15
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L15:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L18
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int BPartition(int *A, int p, int r) {
  int x = A[r];
  int i = p - 1;
  int j = p;
  int tmp = 0;
  for (; j < r; j++) {
    if (A[j] < x) {
      i = i + 1;
      tmp = A[i];
      A[i] = A[j];
      A[j] = tmp;
    }
  }
  A[r] = A[i + 1];
  A[i + 1] = x;
  return i + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BPartition>:
  endbr64
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r11
  mov    (%r11),%r8d
  lea    -0x1(%rsi),%eax
  cmp    %esi,%edx
  jle    L25
  movslq %esi,%r9
  lea    (%rdi,%r9,4),%rcx
  sub    %esi,%edx
  lea    -0x1(%rdx),%edx
  add    %r9,%rdx
  lea    0x4(%rdi,%rdx,4),%r9
  jmp    L17
L0:
  add    $0x4,%rcx
  cmp    %r9,%rcx
  je     L25
L17:
  mov    (%rcx),%edx
  cmp    %r8d,%edx
  jge    L0
  add    $0x1,%eax
  movslq %eax,%rsi
  lea    (%rdi,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %edx,(%rsi)
  mov    %r10d,(%rcx)
  jmp    L0
L25:
  movslq %eax,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r8d,(%rdx)
  add    $0x1,%eax
  ret
```

assistant: ```c
int BPartition(int *A, int p, int r) {
  int x = A[r];
  int i = p - 1;
  int j = p;
  int tmp = 0;
  for (; j < r; j++) {
    if (A[j] < x) {
      i = i + 1;
      tmp = A[i];
      A[i] = A[j];
      A[j] = tmp;
    }
  }
  A[r] = A[i + 1];
  A[i + 1] = x;
  return i + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BPartition>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%r8
  lea    (%rdi,%rax,4),%r11
  lea    -0x1(%rsi),%edi
  mov    (%r11),%r9d
  cmp    %esi,%edx
  jle    L24
  sub    %esi,%edx
  movslq %esi,%r10
  lea    -0x1(%rdx),%eax
  lea    (%r8,%r10,4),%rcx
  add    %r10,%rax
  lea    0x4(%r8,%rax,4),%rsi
  nopl   0x0(%rax)
L37:
  mov    (%rcx),%eax
  cmp    %r9d,%eax
  jge    L10
  add    $0x1,%edi
  movslq %edi,%rdx
  lea    (%r8,%rdx,4),%rdx
  mov    (%rdx),%r10d
  mov    %eax,(%rdx)
  mov    %r10d,(%rcx)
L10:
  add    $0x4,%rcx
  cmp    %rcx,%rsi
  jne    L37
  lea    0x1(%rdi),%eax
L9:
  movslq %edi,%rdi
  lea    0x4(%r8,%rdi,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r9d,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %esi,%eax
  jmp    L9
```

assistant: ```c
int BPartition(int *A, int p, int r) {
  int x = A[r];
  int i = p - 1;
  int j = p;
  int tmp = 0;
  for (; j < r; j++) {
    if (A[j] < x) {
      i = i + 1;
      tmp = A[i];
      A[i] = A[j];
      A[j] = tmp;
    }
  }
  A[r] = A[i + 1];
  A[i + 1] = x;
  return i + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BPartition>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%r8
  lea    (%rdi,%rax,4),%r11
  lea    -0x1(%rsi),%edi
  mov    (%r11),%r9d
  cmp    %esi,%edx
  jle    L20
  sub    %esi,%edx
  movslq %esi,%r10
  lea    -0x1(%rdx),%eax
  lea    (%r8,%r10,4),%rcx
  add    %r10,%rax
  lea    0x4(%r8,%rax,4),%rsi
  nopl   0x0(%rax)
L9:
  mov    (%rcx),%eax
  cmp    %r9d,%eax
  jge    L11
  add    $0x1,%edi
  movslq %edi,%rdx
  lea    (%r8,%rdx,4),%rdx
  mov    (%rdx),%r10d
  mov    %eax,(%rdx)
  mov    %r10d,(%rcx)
L11:
  add    $0x4,%rcx
  cmp    %rcx,%rsi
  jne    L9
  lea    0x1(%rdi),%eax
L32:
  movslq %edi,%rdi
  lea    0x4(%r8,%rdi,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r9d,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    %esi,%eax
  jmp    L32
```

assistant: ```c
int BPartition(int *A, int p, int r) {
  int x = A[r];
  int i = p - 1;
  int j = p;
  int tmp = 0;
  for (; j < r; j++) {
    if (A[j] < x) {
      i = i + 1;
      tmp = A[i];
      A[i] = A[j];
      A[j] = tmp;
    }
  }
  A[r] = A[i + 1];
  A[i + 1] = x;
  return i + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x3,(%rax)
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x9,-0xc(%rbp)
  jle    L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *val() {
  int *ret = (int *)malloc(sizeof(int) * 10);
  for (int i = 0; i < 10; i++) {
    ret[i] = 3;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<val>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  lea    0x28(%rax),%rcx
L1:
  movl   $0x3,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *val() {
  int *ret = (int *)malloc(sizeof(int) * 10);
  for (int i = 0; i < 10; i++) {
    ret[i] = 3;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<val>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  lea    0x28(%rax),%rcx
  nopl   0x0(%rax)
L7:
  movl   $0x3,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L7
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *val() {
  int *ret = (int *)malloc(sizeof(int) * 10);
  for (int i = 0; i < 10; i++) {
    ret[i] = 3;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<val>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  movdqa D19(%rip),%xmm0
  mov    D19(%rip),%rdx
  mov    %rdx,0x20(%rax)
  movups %xmm0,(%rax)
  movups %xmm0,0x10(%rax)
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: byte[16]

tool: {"D19": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
void *val() {
  int *ret = (int *)malloc(sizeof(int) * 10);
  for (int i = 0; i < 10; i++) {
    ret[i] = 3;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<QRSFilter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L6
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <hpfilt@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <lpfilt@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <mvwint@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <deriv1@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <deriv2@plt>
L6:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lpfilt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <hpfilt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <deriv2@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mvwint@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int QRSFilter(int datum, int init) {
  if (init) {
    hpfilt(0, 1);
    lpfilt(0, 1);
    mvwint(0, 1);
    deriv1(0, 1);
    deriv2(0, 1);
  }
  datum = lpfilt(datum, 0);
  datum = hpfilt(datum, 0);
  datum = deriv2(datum, 0);
  datum = abs(datum);
  datum = mvwint(datum, 0);
  return datum;
}
```