ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmd_innwstr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L8
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <report_error@plt>
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: UNSUPPORTED

assistant: ```c
void cmd_innwstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_innwstr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L6
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <report_error@plt>
  nopl   0x0(%rax)
L6:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: UNSUPPORTED

assistant: ```c
void cmd_innwstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <kexit@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: Exit code? 

assistant: ```c
void do_exit() {
  char exitStr[4];
  int exitCode;
  printf("Exit code? ");
  gets(exitStr);
  exitCode = atoi(exitStr);
  kexit(exitCode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_exit>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <kexit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: Exit code? 

assistant: ```c
void do_exit() {
  char exitStr[4];
  int exitCode;
  printf("Exit code? ");
  gets(exitStr);
  exitCode = atoi(exitStr);
  kexit(exitCode);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_exit>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <kexit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: Exit code? 

assistant: ```c
void do_exit() {
  char exitStr[4];
  int exitCode;
  printf("Exit code? ");
  gets(exitStr);
  exitCode = atoi(exitStr);
  kexit(exitCode);
}
```
user: What is the c source code of the assembly code below?

```asm
<do_exit>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <kexit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: Exit code? 

assistant: ```c
void do_exit() {
  char exitStr[4];
  int exitCode;
  printf("Exit code? ");
  gets(exitStr);
  exitCode = atoi(exitStr);
  kexit(exitCode);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dow>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  lea    0x190(%rax),%edx
  cmovs  %edx,%eax
  test   $0x3,%al
  jne    L54
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  imul   $0x64,%edx,%edx
  mov    $0x1,%edi
  cmp    %edx,%eax
  jne    L83
L54:
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  imul   $0x190,%edx,%edx
  cmp    %edx,%eax
  sete   %dil
  movzbl %dil,%edi
L83:
  lea    -0x1(%rcx),%edx
  cmp    $0xb,%edx
  ja     L79
  test   %esi,%esi
  jle    L79
  mov    %edi,%r8d
  cmp    $0x2,%ecx
  jne    L108
  test   %dil,%dil
  je     L108
  cmp    $0x1d,%esi
  jg     L8
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x2,%edx
  add    %eax,%edx
  movslq %eax,%rdi
  imul   $0x51eb851f,%rdi,%rdi
  sar    $0x25,%rdi
  sar    $0x1f,%eax
  sub    %edi,%eax
  add    %edx,%eax
L34:
  sub    $0x1,%eax
L13:
  sub    $0x1,%ecx
  movslq %ecx,%rcx
  lea    D13(%rip),%rdx
  add    (%rdx,%rcx,4),%eax
  lea    0x6(%rax,%rsi,1),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L108:
  lea    -0x1(%rcx),%edx
  movslq %edx,%rdx
  lea    D4(%rip),%rdi
  cmp    %esi,(%rdi,%rdx,4)
  jl     L56
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x2,%edx
  add    %eax,%edx
  movslq %eax,%rdi
  imul   $0x51eb851f,%rdi,%rdi
  sar    $0x25,%rdi
  sar    $0x1f,%eax
  sub    %edi,%eax
  add    %edx,%eax
  cmp    $0x2,%ecx
  jg     L13
  test   %r8b,%r8b
  je     L13
  jmp    L34
L79:
  mov    $0xffffffff,%eax
  ret
L8:
  mov    $0xffffffff,%eax
  ret
L56:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: 

tool: D4: 

assistant: ```c
int dow(int yr, int mo, int da) {
  static int totdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  static int numdays[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int addon = 0;
  int leap;
  yr %= 400;
  if (yr < 0)
    yr += 400;
  if (((((yr % 4) == 0) && ((yr % 100) != 0)) || ((yr % 400) == 0)))
    leap = 1;
  else
    leap = 0;
  if ((mo < 1) || (mo > 12))
    return (-1);
  if (da < 1)
    return (-1);
  if (leap && (mo == 2)) {
    if (da > (numdays[mo - 1] + 1))
      return (-1);
  } else if (da > numdays[mo - 1])
    return (-1);
  addon += yr;
  addon += yr / 4;
  addon -= yr / 100;
  if (leap && (mo <= 2))
    addon--;
  addon += totdays[mo - 1];
  addon += da;
  addon += 6;
  return (addon % 7);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dow>:
  endbr64
  movslq %edi,%rax
  mov    %edx,%ecx
  lea    -0x1(%rsi),%r8d
  mov    %edi,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x27,%rax
  sub    %edx,%eax
  imul   $0x190,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  lea    0x190(%rax),%edx
  cmovs  %edx,%eax
  cmp    $0xb,%r8d
  seta   %dl
  test   %ecx,%ecx
  setle  %dil
  or     %edi,%edx
  test   $0x3,%al
  jne    L42
  imul   $0xc28f5c29,%eax,%edi
  ror    $0x2,%edi
  cmp    $0x28f5c28,%edi
  seta   %r9b
  test   %eax,%eax
  sete   %dil
  or     %edi,%r9d
  test   %dl,%dl
  jne    L29
  cmp    $0x2,%esi
  jne    L30
  test   %r9b,%r9b
  je     L30
  cmp    $0x1d,%ecx
  jg     L29
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x2,%esi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x25,%rdx
  sub    %edx,%eax
  add    %esi,%eax
L44:
  sub    $0x1,%eax
  movslq %r8d,%rdi
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L42:
  test   %dl,%dl
  jne    L29
  movslq %r8d,%rdi
  lea    D20(%rip),%rdx
  cmp    %ecx,(%rdx,%rdi,4)
  jl     L29
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x2,%esi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x25,%rdx
  sub    %edx,%eax
  add    %esi,%eax
L26:
  lea    D4(%rip),%rdx
  add    (%rdx,%rdi,4),%eax
  lea    0x6(%rax,%rcx,1),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L29:
  mov    $0xffffffff,%eax
  ret
L30:
  movslq %r8d,%rdi
  lea    D20(%rip),%rdx
  cmp    %ecx,(%rdx,%rdi,4)
  jl     L29
  mov    %eax,%r10d
  mov    $0xffffff9c,%r11d
  cltd
  sar    $0x2,%r10d
  add    %eax,%r10d
  idiv   %r11d
  add    %r10d,%eax
  cmp    $0x2,%esi
  jg     L26
  test   %r9b,%r9b
  je     L26
  jmp    L44
```

tool_calls: name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D4
type: string

tool: D20: 

tool: 

assistant: ```c
int dow(int yr, int mo, int da) {
  static int totdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  static int numdays[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int addon = 0;
  int leap;
  yr %= 400;
  if (yr < 0)
    yr += 400;
  if (((((yr % 4) == 0) && ((yr % 100) != 0)) || ((yr % 400) == 0)))
    leap = 1;
  else
    leap = 0;
  if ((mo < 1) || (mo > 12))
    return (-1);
  if (da < 1)
    return (-1);
  if (leap && (mo == 2)) {
    if (da > (numdays[mo - 1] + 1))
      return (-1);
  } else if (da > numdays[mo - 1])
    return (-1);
  addon += yr;
  addon += yr / 4;
  addon -= yr / 100;
  if (leap && (mo <= 2))
    addon--;
  addon += totdays[mo - 1];
  addon += da;
  addon += 6;
  return (addon % 7);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dow>:
  endbr64
  movslq %edi,%rax
  mov    %edx,%ecx
  lea    -0x1(%rsi),%r8d
  mov    %edi,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x27,%rax
  sub    %edx,%eax
  imul   $0x190,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  lea    0x190(%rax),%edx
  cmovs  %edx,%eax
  cmp    $0xb,%r8d
  seta   %dl
  test   %ecx,%ecx
  setle  %dil
  or     %edi,%edx
  test   $0x3,%al
  jne    L47
  imul   $0xc28f5c29,%eax,%edi
  ror    $0x2,%edi
  cmp    $0x28f5c28,%edi
  seta   %r9b
  test   %eax,%eax
  sete   %dil
  or     %edi,%r9d
  test   %dl,%dl
  jne    L55
  cmp    $0x2,%esi
  jne    L45
  test   %r9b,%r9b
  je     L45
  cmp    $0x1d,%ecx
  jg     L55
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x2,%esi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x25,%rdx
  sub    %edx,%eax
  add    %esi,%eax
L26:
  sub    $0x1,%eax
  movslq %r8d,%rdi
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L47:
  test   %dl,%dl
  jne    L55
  movslq %r8d,%rdi
  lea    D4(%rip),%rdx
  cmp    (%rdx,%rdi,4),%ecx
  jg     L55
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x2,%esi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x25,%rdx
  sub    %edx,%eax
  add    %esi,%eax
L66:
  lea    D7(%rip),%rdx
  add    (%rdx,%rdi,4),%eax
  lea    0x6(%rax,%rcx,1),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L55:
  mov    $0xffffffff,%eax
  ret
L45:
  movslq %r8d,%rdi
  lea    D4(%rip),%rdx
  cmp    %ecx,(%rdx,%rdi,4)
  jl     L55
  mov    %eax,%r10d
  mov    $0xffffff9c,%r11d
  cltd
  sar    $0x2,%r10d
  add    %eax,%r10d
  idiv   %r11d
  add    %r10d,%eax
  cmp    $0x2,%esi
  jg     L66
  test   %r9b,%r9b
  je     L66
  jmp    L26
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D4: 

tool: 

assistant: ```c
int dow(int yr, int mo, int da) {
  static int totdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  static int numdays[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int addon = 0;
  int leap;
  yr %= 400;
  if (yr < 0)
    yr += 400;
  if (((((yr % 4) == 0) && ((yr % 100) != 0)) || ((yr % 400) == 0)))
    leap = 1;
  else
    leap = 0;
  if ((mo < 1) || (mo > 12))
    return (-1);
  if (da < 1)
    return (-1);
  if (leap && (mo == 2)) {
    if (da > (numdays[mo - 1] + 1))
      return (-1);
  } else if (da > numdays[mo - 1])
    return (-1);
  addon += yr;
  addon += yr / 4;
  addon -= yr / 100;
  if (leap && (mo <= 2))
    addon--;
  addon += totdays[mo - 1];
  addon += da;
  addon += 6;
  return (addon % 7);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_islower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L18
  cmpl   $0x7a,-0x4(%rbp)
  jg     L18
  mov    $0x1,%eax
  jmp    L21
L18:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int ft_islower(int c) {
  if (c >= 97 && c <= 122)
    return (1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_islower>:
  endbr64
  sub    $0x61,%edi
  cmp    $0x19,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_islower(int c) {
  if (c >= 97 && c <= 122)
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_islower>:
  endbr64
  sub    $0x61,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_islower(int c) {
  if (c >= 97 && c <= 122)
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_islower>:
  endbr64
  sub    $0x61,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_islower(int c) {
  if (c >= 97 && c <= 122)
    return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<choosePivot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L23
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swapval@plt>
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L18
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swapval@plt>
L18:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L21
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swapval@plt>
L21:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int choosePivot(int *arr, int low, int upp) {
  int mid = (low + upp) / 2;
  if (arr[low] > arr[upp]) {
    swapval(low, upp);
  }
  if (arr[mid] < arr[low]) {
    swapval(mid, low);
  }
  if (arr[upp] < arr[mid]) {
    swapval(mid, upp);
  }
  return mid;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<choosePivot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r15
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r14
  mov    (%r14),%eax
  cmp    %eax,(%r15)
  jg     L46
L10:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rbp
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp)
  jl     L2
L27:
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jl     L52
L8:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  mov    %edx,%esi
  mov    %r13d,%edi
  call   <swapval@plt>
  jmp    L10
L2:
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <swapval@plt>
  jmp    L27
L52:
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <swapval@plt>
  jmp    L8
```

assistant: ```c
int choosePivot(int *arr, int low, int upp) {
  int mid = (low + upp) / 2;
  if (arr[low] > arr[upp]) {
    swapval(low, upp);
  }
  if (arr[mid] < arr[low]) {
    swapval(mid, low);
  }
  if (arr[upp] < arr[mid]) {
    swapval(mid, upp);
  }
  return mid;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<choosePivot>:
  endbr64
  lea    (%rsi,%rdx,1),%eax
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  add    %eax,%r12d
  movslq %esi,%rax
  mov    %rdi,%rbx
  lea    (%rdi,%rax,4),%r15
  movslq %ebp,%rax
  sar    %r12d
  lea    (%rdi,%rax,4),%r14
  sub    $0x8,%rsp
  mov    (%r15),%edx
  cmp    (%r14),%edx
  jg     L34
  movslq %r12d,%rax
  lea    (%rbx,%rax,4),%rbx
  mov    (%rbx),%eax
  cmp    %edx,%eax
  jl     L6
L3:
  cmp    %eax,(%r14)
  jl     L37
L56:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L34:
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <swapval@plt>
  movslq %r12d,%rax
  mov    (%r15),%edx
  lea    (%rbx,%rax,4),%rbx
  mov    (%rbx),%eax
  cmp    %edx,%eax
  jge    L3
L6:
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <swapval@plt>
  mov    (%rbx),%eax
  cmp    %eax,(%r14)
  jge    L56
L37:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <swapval@plt>
  jmp    L56
```

assistant: ```c
int choosePivot(int *arr, int low, int upp) {
  int mid = (low + upp) / 2;
  if (arr[low] > arr[upp]) {
    swapval(low, upp);
  }
  if (arr[mid] < arr[low]) {
    swapval(mid, low);
  }
  if (arr[upp] < arr[mid]) {
    swapval(mid, upp);
  }
  return mid;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<choosePivot>:
  endbr64
  lea    (%rsi,%rdx,1),%eax
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  add    %eax,%r12d
  movslq %esi,%rax
  mov    %rdi,%rbx
  lea    (%rdi,%rax,4),%r15
  movslq %ebp,%rax
  sar    %r12d
  lea    (%rdi,%rax,4),%r14
  sub    $0x8,%rsp
  mov    (%r15),%edx
  cmp    (%r14),%edx
  jg     L9
  movslq %r12d,%rax
  lea    (%rbx,%rax,4),%rbx
  mov    (%rbx),%eax
  cmp    %edx,%eax
  jl     L52
L41:
  cmp    %eax,(%r14)
  jl     L34
L51:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <swapval@plt>
  movslq %r12d,%rax
  mov    (%r15),%edx
  lea    (%rbx,%rax,4),%rbx
  mov    (%rbx),%eax
  cmp    %edx,%eax
  jge    L41
L52:
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <swapval@plt>
  mov    (%rbx),%eax
  cmp    %eax,(%r14)
  jge    L51
L34:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <swapval@plt>
  jmp    L51
```

assistant: ```c
int choosePivot(int *arr, int low, int upp) {
  int mid = (low + upp) / 2;
  if (arr[low] > arr[upp]) {
    swapval(low, upp);
  }
  if (arr[mid] < arr[low]) {
    swapval(mid, low);
  }
  if (arr[upp] < arr[mid]) {
    swapval(mid, upp);
  }
  return mid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ILLutil_linked_radixsort>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %ecx,%eax
  mov    %fs:0x28,%rcx
  mov    %rcx,0x1018(%rsp)
  xor    %ecx,%ecx
  sub    %rdi,%rsi
  sub    %rdi,%rdx
  mov    %eax,%edi
  sub    $0x1,%edi
  js     L3
  mov    %rsi,%r8
  movslq %edi,%rdi
  add    %rdx,%rdi
  movslq %eax,%rcx
  lea    -0x2(%rdx,%rcx,1),%r9
  lea    -0x1(%rax),%eax
  sub    %rax,%r9
  lea    0x810(%rsp),%rcx
  lea    0x8(%rsp),%r10
  jmp    L82
L103:
  mov    %rdx,(%rsi)
  mov    (%rax,%rcx,1),%rsi
L23:
  add    $0x8,%rax
  cmp    $0x800,%rax
  je     L97
L69:
  mov    0x10(%rsp,%rax,1),%rdx
  test   %rdx,%rdx
  jne    L103
  jmp    L23
L97:
  movq   $0x0,(%rsi)
  sub    $0x1,%rdi
  cmp    %r9,%rdi
  je     L3
L82:
  lea    0x10(%rsp),%rax
  lea    0x810(%rsp),%rdx
L18:
  movq   $0x0,(%rax)
  mov    %rax,(%rdx)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L18
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L84
L14:
  movzbl (%rax,%rdi,1),%edx
  mov    0x810(%rsp,%rdx,8),%rsi
  mov    %rax,(%rsi)
  add    %r8,%rax
  mov    %rax,0x810(%rsp,%rdx,8)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L14
L84:
  mov    $0x0,%eax
  mov    %r10,%rsi
  jmp    L69
L3:
  mov    0x8(%rsp),%rax
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L87
  add    $0x1028,%rsp
  ret
L87:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ILLutil_linked_radixsort(char *data, char *datanext, char *dataval, int valsize) {
  size_t nextoff = datanext - data;
  size_t valoff = dataval - data;
  int i;
  char *head[(1 << (8))];
  char **tail[(1 << (8))];
  char *p;
  char **last;
  int j;
  int v;
  for (j = valsize - 1; j >= 0; j--) {
    for (i = 0; i < (1 << (8)); i++) {
      head[i] = (char *)NULL;
      tail[i] = &head[i];
    }
    for (p = data; p; p = *(char **)(p + nextoff)) {
      v = (unsigned char)p[valoff + j];
      *tail[v] = p;
      tail[v] = (char **)(p + nextoff);
    }
    last = &data;
    for (i = 0; i < (1 << (8)); i++) {
      if (head[i]) {
        *last = head[i];
        last = tail[i];
      }
    }
    *last = (char *)NULL;
  }
  return data;
}
```