user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x5,-0x34(%rbp)
  je     L36
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L36:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x40(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    D36(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L16
L39:
  mov    -0x18(%rbp),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movzwl -0x22(%rbp),%eax
  movswl %ax,%edx
  mov    -0x10(%rbp),%rax
  lea    D38(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  addl   $0x1,-0x20(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L39
  mov    -0x18(%rbp),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movzwl -0x22(%rbp),%eax
  movswl %ax,%edx
  mov    -0x10(%rbp),%rax
  lea    D44(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D36
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D44
datatype: string

tool: D16: usage: %s inputRawFile outputHeaderFile arrayName samples


tool: D6: rb

tool: D10: wt

tool: D36: short %s[] = {


tool: D38: %d,


tool: D44: %d
};


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fraw, *fheader;
  int i, samples;
  short sam;
  if (argc != 5) {
    printf("usage: %s inputRawFile outputHeaderFile arrayName samples\n", argv[0]);
    exit(1);
  }
  fraw = fopen(argv[1], "rb");
  assert(fraw != NULL);
  fheader = fopen(argv[2], "wt");
  assert(fheader != NULL);
  samples = atoi(argv[4]);
  fprintf(fheader, "short %s[] = {\n", argv[3]);
  for (i = 0; i < samples - 1; i++) {
    fread(&sam, sizeof(short), 1, fraw);
    fprintf(fheader, "%d,\n", sam);
  }
  fread(&sam, sizeof(short), 1, fraw);
  fprintf(fheader, "%d\n};\n", sam);
  fclose(fraw);
  fclose(fheader);
  return 0;
}
```