ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<getCurrentTime>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x3e8,(%rsp),%ecx
  pxor   %xmm0,%xmm0
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %ecx,%eax
  cvtsi2sd %eax,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double getCurrentTime(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  double curr = (tv.tv_sec) * 1000 + (tv.tv_usec) / 1000;
  return curr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getCurrentTime>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x3e8,(%rsp),%ecx
  pxor   %xmm0,%xmm0
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %ecx,%eax
  cvtsi2sd %eax,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double getCurrentTime(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  double curr = (tv.tv_sec) * 1000 + (tv.tv_usec) / 1000;
  return curr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<G38_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D11: G38_f(const char *s) is not yet implemented!


tool: D14: %s


assistant: ```c
int G38_f(char *s) {
  debug("G38_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<G38_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string

tool: D9: G38_f(const char *s) is not yet implemented!


tool: D16: %s


assistant: ```c
int G38_f(char *s) {
  debug("G38_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<G38_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D13
data_type: string

tool: D3: G38_f(const char *s) is not yet implemented!


tool: D13: %s


assistant: ```c
int G38_f(char *s) {
  debug("G38_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<G38_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string

tool: D3: G38_f(const char *s) is not yet implemented!


tool: D6: %s


assistant: ```c
int G38_f(char *s) {
  debug("G38_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L3
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jg     L14
L3:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L20
L14:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L45
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
  movl   $0x0,-0x1c(%rbp)
  jmp    L30
L40:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L26
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L20
L26:
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L40
L45:
  mov    -0x10(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string

tool: D32: %d

tool: D15: first value invalid


tool: D24: int value invalid


assistant: ```c
int *rdin() {
  int l, r;
  int *ay = NULL;
  int *ayp = NULL;
  r = scanf("%d", &l);
  if (r != 1 || l <= 0) {
    printf("first value invalid\n");
    return NULL;
  }
  ay = (int *)malloc((l + 1) * sizeof(int));
  if (ay != NULL) {
    ayp = ay;
    *ayp++ = l;
    for (r = 0; r < l; r++) {
      if (scanf("%d", ayp++) != 1) {
        printf("int value invalid\n");
        return NULL;
      }
    }
  }
  return ay;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rdin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L62
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L62
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L75
  lea    0x4(%rax),%rbx
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  cmpl   $0x0,0x4(%rsp)
  jle    L75
  mov    $0x0,%ebp
  lea    D37(%rip),%r13
L31:
  mov    %rbx,%rsi
  add    $0x4,%rbx
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L87
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jg     L31
  jmp    L75
L62:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r12d
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L87:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r12d
  jmp    L75
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D37
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D37: %d

tool: D39: first value invalid


tool: D5: int value invalid


assistant: ```c
int *rdin() {
  int l, r;
  int *ay = NULL;
  int *ayp = NULL;
  r = scanf("%d", &l);
  if (r != 1 || l <= 0) {
    printf("first value invalid\n");
    return NULL;
  }
  ay = (int *)malloc((l + 1) * sizeof(int));
  if (ay != NULL) {
    ayp = ay;
    *ayp++ = l;
    for (r = 0; r < l; r++) {
      if (scanf("%d", ayp++) != 1) {
        printf("int value invalid\n");
        return NULL;
      }
    }
  }
  return ay;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdin>:
  endbr64
  push   %r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L59
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L59
  lea    0x4(,%rax,4),%edi
  xor    %r13d,%r13d
  call   <malloc@plt>
  test   %rax,%rax
  je     L88
  mov    %rax,%r13
  lea    0x4(%rax),%rbx
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%r13)
  test   %eax,%eax
  jle    L88
  xor    %ebp,%ebp
  jmp    L87
  xchg   %ax,%ax
L52:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L88
L87:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L52
  lea    D8(%rip),%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
  nopl   0x0(%rax)
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L59:
  lea    D12(%rip),%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
  jmp    L88
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D12
type: string

tool: D20: %d

tool: D8: int value invalid


tool: D12: first value invalid


assistant: ```c
int *rdin() {
  int l, r;
  int *ay = NULL;
  int *ayp = NULL;
  r = scanf("%d", &l);
  if (r != 1 || l <= 0) {
    printf("first value invalid\n");
    return NULL;
  }
  ay = (int *)malloc((l + 1) * sizeof(int));
  if (ay != NULL) {
    ayp = ay;
    *ayp++ = l;
    for (r = 0; r < l; r++) {
      if (scanf("%d", ayp++) != 1) {
        printf("int value invalid\n");
        return NULL;
      }
    }
  }
  return ay;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rdin>:
  endbr64
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L32
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L32
  lea    0x4(,%rax,4),%edi
  xor    %r13d,%r13d
  call   <malloc@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%r13
  lea    0x4(%rax),%rbx
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%r13)
  test   %eax,%eax
  jle    L29
  xor    %ebp,%ebp
  jmp    L73
  xchg   %ax,%ax
L13:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L29
L73:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L13
  lea    D26(%rip),%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
  nopl   0x0(%rax)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L32:
  lea    D6(%rip),%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
  jmp    L29
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D26
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D2: %d

tool: D26: int value invalid


tool: D6: first value invalid


assistant: ```c
int *rdin() {
  int l, r;
  int *ay = NULL;
  int *ayp = NULL;
  r = scanf("%d", &l);
  if (r != 1 || l <= 0) {
    printf("first value invalid\n");
    return NULL;
  }
  ay = (int *)malloc((l + 1) * sizeof(int));
  if (ay != NULL) {
    ayp = ay;
    *ayp++ = l;
    for (r = 0; r < l; r++) {
      if (scanf("%d", ayp++) != 1) {
        printf("int value invalid\n");
        return NULL;
      }
    }
  }
  return ay;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<init_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x1a,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  mov    $0xffffffff,%edi
  call   <errPointer@plt>
L24:
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L8:
  mov    -0x4(%rbp),%eax
  lea    0x41(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x19,-0x4(%rbp)
  jle    L8
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *init_up(char *v) {
  int i = 0;
  v = malloc(26 * sizeof(char));
  if (v == NULL)
    errPointer(-1);
  for (i = 0; i < 26; i++)
    v[i] = 'A' + i;
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_up>:
  endbr64
  push   %rbx
  mov    $0x1a,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
L5:
  lea    0x1a(%rbx),%rsi
  mov    %rbx,%rax
  mov    $0x41,%ecx
  sub    %ebx,%ecx
L16:
  lea    (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L16
  mov    %rbx,%rax
  pop    %rbx
  ret
L27:
  mov    $0xffffffff,%edi
  call   <errPointer@plt>
  jmp    L5
```

assistant: ```c
char *init_up(char *v) {
  int i = 0;
  v = malloc(26 * sizeof(char));
  if (v == NULL)
    errPointer(-1);
  for (i = 0; i < 26; i++)
    v[i] = 'A' + i;
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_up>:
  endbr64
  push   %r12
  mov    $0x1a,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L22
L3:
  mov    $0x41,%ecx
  lea    0x1a(%r12),%rsi
  mov    %r12,%rax
  sub    %r12d,%ecx
  nopl   0x0(%rax,%rax,1)
L5:
  lea    (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L5
  mov    %r12,%rax
  pop    %r12
  ret
L22:
  mov    $0xffffffff,%edi
  call   <errPointer@plt>
  jmp    L3
```

assistant: ```c
char *init_up(char *v) {
  int i = 0;
  v = malloc(26 * sizeof(char));
  if (v == NULL)
    errPointer(-1);
  for (i = 0; i < 26; i++)
    v[i] = 'A' + i;
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<init_up>:
  endbr64
  push   %r12
  mov    $0x1a,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L12:
  mov    D18(%rip),%rax
  movdqa D12(%rip),%xmm0
  mov    %rax,0x10(%r12)
  mov    $0x5a59,%eax
  mov    %ax,0x18(%r12)
  mov    %r12,%rax
  movups %xmm0,(%r12)
  pop    %r12
  ret
L14:
  mov    $0xffffffff,%edi
  call   <errPointer@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: data_label: D18
type_infered: byte[8]
name: read_data
arguments: data_label: D12
type_infered: byte[16]

tool: {"D18": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58]}

tool: {"D12": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

assistant: ```c
char *init_up(char *v) {
  int i = 0;
  v = malloc(26 * sizeof(char));
  if (v == NULL)
    errPointer(-1);
  for (i = 0; i < 26; i++)
    v[i] = 'A' + i;
  return v;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<break_caesar_cipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: 

assistant: ```c
char *break_caesar_cipher(char *ciphertext, char *known_word) {
  char *plaintext = "";
  return plaintext;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<break_caesar_cipher>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: 

assistant: ```c
char *break_caesar_cipher(char *ciphertext, char *known_word) {
  char *plaintext = "";
  return plaintext;
}
```
user: What is the c source code of the assembly code below?

```asm
<break_caesar_cipher>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: 

assistant: ```c
char *break_caesar_cipher(char *ciphertext, char *known_word) {
  char *plaintext = "";
  return plaintext;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<break_caesar_cipher>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: 

assistant: ```c
char *break_caesar_cipher(char *ciphertext, char *known_word) {
  char *plaintext = "";
  return plaintext;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bwstrdup_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L39
  cmpq   $0x0,-0x20(%rbp)
  je     L39
L19:
  mov    $0x0,%eax
  jmp    L6
L39:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bmemdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
wchar_t *bwstrdup_n(const wchar_t *str, size_t n) {
  wchar_t *dup;
  if (!str || (!*str && n > 0))
    return NULL;
  dup = (wchar_t *)bmemdup(str, (n + 1) * sizeof(wchar_t));
  dup[n] = 0;
  return dup;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bwstrdup_n>:
  endbr64
  test   %rdi,%rdi
  je     L20
  cmpq   $0x0,(%rdi)
  jne    L24
  mov    $0x0,%eax
  test   %rsi,%rsi
  jne    L3
L24:
  push   %rbx
  lea    0x8(,%rsi,8),%rbx
  mov    %rbx,%rsi
  call   <bmemdup@plt>
  movq   $0x0,-0x8(%rax,%rbx,1)
  pop    %rbx
  ret
L20:
  mov    %rdi,%rax
  ret
L3:
  ret
```

assistant: ```c
wchar_t *bwstrdup_n(const wchar_t *str, size_t n) {
  wchar_t *dup;
  if (!str || (!*str && n > 0))
    return NULL;
  dup = (wchar_t *)bmemdup(str, (n + 1) * sizeof(wchar_t));
  dup[n] = 0;
  return dup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bwstrdup_n>:
  endbr64
  test   %rdi,%rdi
  je     L16
  cmpq   $0x0,(%rdi)
  jne    L13
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L24
L13:
  push   %rbx
  lea    0x8(,%rsi,8),%rbx
  mov    %rbx,%rsi
  call   <bmemdup@plt>
  movq   $0x0,-0x8(%rax,%rbx,1)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t *bwstrdup_n(const wchar_t *str, size_t n) {
  wchar_t *dup;
  if (!str || (!*str && n > 0))
    return NULL;
  dup = (wchar_t *)bmemdup(str, (n + 1) * sizeof(wchar_t));
  dup[n] = 0;
  return dup;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bwstrdup_n>:
  endbr64
  test   %rdi,%rdi
  je     L19
  cmpq   $0x0,(%rdi)
  jne    L6
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L15
L6:
  push   %rbx
  lea    0x8(,%rsi,8),%rbx
  mov    %rbx,%rsi
  call   <bmemdup@plt>
  movq   $0x0,-0x8(%rax,%rbx,1)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t *bwstrdup_n(const wchar_t *str, size_t n) {
  wchar_t *dup;
  if (!str || (!*str && n > 0))
    return NULL;
  dup = (wchar_t *)bmemdup(str, (n + 1) * sizeof(wchar_t));
  dup[n] = 0;
  return dup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L18
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L51
L38:
  addl   $0x1,-0x10(%rbp)
L51:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L38
  jmp    L66
L1:
  subl   $0x1,-0xc(%rbp)
L66:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L16
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L51
L16:
  nop
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x1c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <quicksort>
  jmp    L57
L18:
  nop
L57:
  leave
  ret
```

assistant: ```c
void quicksort(int *a, int array_size) {
  int pivot = a[array_size / 2];
  int i, j, temp;
  if (array_size < 2)
    return;
  for (i = 0, j = array_size - 1;; i++, j++) {
    while (a[i] < pivot)
      i++;
    while (a[j] > pivot)
      j--;
    if (i >= j)
      break;
    temp = a[i];
    a[i] = a[j];
    a[j] = temp;
  }
  quicksort(a, i);
  quicksort(a + i, array_size - i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L31
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%r12d
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%esi
  lea    -0x1(%r12),%edx
  mov    %rdi,%r8
  mov    $0x0,%r9d
  jmp    L29
L45:
  add    $0x1,%r9
  add    $0x4,%r8
L29:
  mov    %r9d,%ebp
  mov    %r8,%rbx
  mov    (%r8),%r10d
  cmp    %esi,%r10d
  jl     L45
  movslq %edx,%rax
  lea    (%r11,%rax,4),%rdi
  mov    (%rdi),%ecx
  cmp    %ecx,%esi
  jge    L67
  lea    -0x4(%r11,%rax,4),%rax
L9:
  sub    $0x1,%edx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%ecx
  cmp    %esi,%ecx
  jg     L9
L67:
  cmp    %r9d,%edx
  jle    L66
  mov    %ecx,(%rbx)
  mov    %r10d,(%rdi)
  add    $0x1,%edx
  jmp    L45
L66:
  mov    %ebp,%esi
  mov    %r11,%rdi
  call   <quicksort>
  mov    %r12d,%esi
  sub    %ebp,%esi
  mov    %rbx,%rdi
  call   <quicksort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  ret
```

assistant: ```c
void quicksort(int *a, int array_size) {
  int pivot = a[array_size / 2];
  int i, j, temp;
  if (array_size < 2)
    return;
  for (i = 0, j = array_size - 1;; i++, j++) {
    while (a[i] < pivot)
      i++;
    while (a[j] > pivot)
      j--;
    if (i >= j)
      break;
    temp = a[i];
    a[i] = a[j];
    a[j] = temp;
  }
  quicksort(a, i);
  quicksort(a + i, array_size - i);
}
```