ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cm_nalloc_4d>:
  endbr64
  push   %r15
  mov    %r8,%r15
  mov    %rsi,%rdi
  imul   %rcx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  imul   %r9,%rdi
  push   %r12
  mov    %rsi,%r12
  imul   %r15,%r13
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9,%rbx
  imul   %r13,%rdi
  sub    $0x48,%rsp
  mov    %rdx,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,0x38(%rsp)
  test   %r12,%r12
  je     L35
  mov    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rax,0x10(%rsp)
  lea    (%rax,%r12,8),%rax
  imul   %rbx,%rsi
  mov    %rax,0x28(%rsp)
  imul   %rbx,%r15
  lea    0x0(,%rdx,8),%rax
  mov    %rax,0x30(%rsp)
  lea    0x0(,%r14,8),%rax
  mov    %rsi,0x20(%rsp)
  imul   %rbx,%rbp
  mov    %rax,0x8(%rsp)
L10:
  mov    0x20(%rsp),%rdi
  call   <malloc@plt>
  cmpq   $0x0,0x18(%rsp)
  mov    %rax,%r12
  mov    0x10(%rsp),%rax
  mov    %r12,(%rax)
  je     L1
  mov    0x30(%rsp),%rax
  add    %r12,%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L46:
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    %rax,%rdx
  test   %r14,%r14
  je     L16
  mov    %rax,%r13
  mov    0x8(%rsp),%rax
  lea    (%rdx,%rax,1),%rbx
L0:
  mov    %rbp,%rdi
  add    $0x8,%r13
  call   <malloc@plt>
  mov    %rax,-0x8(%r13)
  cmp    %r13,%rbx
  jne    L0
L16:
  add    $0x8,%r12
  cmp    (%rsp),%r12
  jne    L46
L1:
  addq   $0x8,0x10(%rsp)
  mov    0x10(%rsp),%rax
  cmp    0x28(%rsp),%rax
  jne    L10
L35:
  mov    0x38(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ****cm_nalloc_4d(void ****vector, size_t x_size, size_t y_size, size_t z_size, size_t t_size, size_t element_size) {
  int i, j, k;
  vector = malloc(t_size * z_size * y_size * x_size * element_size);
  for (i = 0; i < x_size; i++) {
    vector[i] = malloc(t_size * z_size * y_size * element_size);
    for (j = 0; j < y_size; j++) {
      vector[i][j] = malloc(t_size * z_size * element_size);
      for (k = 0; k < z_size; k++) {
        vector[i][j][k] = malloc(t_size * element_size);
      }
    }
  }
  return vector;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cm_nalloc_4d>:
  endbr64
  push   %r15
  mov    %r8,%r15
  mov    %rsi,%rdi
  imul   %rcx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  imul   %r9,%rdi
  push   %r12
  mov    %rsi,%r12
  imul   %r15,%r13
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9,%rbx
  imul   %r13,%rdi
  sub    $0x48,%rsp
  mov    %rdx,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,0x38(%rsp)
  test   %r12,%r12
  je     L13
  mov    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rax,0x10(%rsp)
  lea    (%rax,%r12,8),%rax
  imul   %rbx,%rsi
  mov    %rax,0x28(%rsp)
  imul   %rbx,%r15
  lea    0x0(,%rdx,8),%rax
  mov    %rax,0x30(%rsp)
  lea    0x0(,%r14,8),%rax
  mov    %rsi,0x20(%rsp)
  imul   %rbx,%rbp
  mov    %rax,0x8(%rsp)
L54:
  mov    0x20(%rsp),%rdi
  call   <malloc@plt>
  cmpq   $0x0,0x18(%rsp)
  mov    %rax,%r12
  mov    0x10(%rsp),%rax
  mov    %r12,(%rax)
  je     L52
  mov    0x30(%rsp),%rax
  add    %r12,%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L14:
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    %rax,%rdx
  test   %r14,%r14
  je     L8
  mov    %rax,%r13
  mov    0x8(%rsp),%rax
  lea    (%rdx,%rax,1),%rbx
L30:
  mov    %rbp,%rdi
  add    $0x8,%r13
  call   <malloc@plt>
  mov    %rax,-0x8(%r13)
  cmp    %r13,%rbx
  jne    L30
L8:
  add    $0x8,%r12
  cmp    (%rsp),%r12
  jne    L14
L52:
  addq   $0x8,0x10(%rsp)
  mov    0x10(%rsp),%rax
  cmp    0x28(%rsp),%rax
  jne    L54
L13:
  mov    0x38(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ****cm_nalloc_4d(void ****vector, size_t x_size, size_t y_size, size_t z_size, size_t t_size, size_t element_size) {
  int i, j, k;
  vector = malloc(t_size * z_size * y_size * x_size * element_size);
  for (i = 0; i < x_size; i++) {
    vector[i] = malloc(t_size * z_size * y_size * element_size);
    for (j = 0; j < y_size; j++) {
      vector[i][j] = malloc(t_size * z_size * element_size);
      for (k = 0; k < z_size; k++) {
        vector[i][j][k] = malloc(t_size * element_size);
      }
    }
  }
  return vector;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumVectorInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumVectorInt(int *ma, int dim) {
  int i, res;
  for (i = 0; i < dim; i++) {
    res += ma[i];
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumVectorInt>:
  endbr64
  test   %esi,%esi
  jle    L25
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L20:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L20
L2:
  mov    %edx,%eax
  ret
L25:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
int sumVectorInt(int *ma, int dim) {
  int i, res;
  for (i = 0; i < dim; i++) {
    res += ma[i];
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sumVectorInt>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L19
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumVectorInt(int *ma, int dim) {
  int i, res;
  for (i = 0; i < dim; i++) {
    res += ma[i];
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sumVectorInt>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L61
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L38
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L66:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L66
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L49
L50:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L13
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L13
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L61:
  xor    %eax,%eax
L13:
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  ret
L38:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L50
```

assistant: ```c
int sumVectorInt(int *ma, int dim) {
  int i, res;
  for (i = 0; i < dim; i++) {
    res += ma[i];
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D0: Usage: %s val1 val2 ...


tool: D15: Values may be given as hex patterns or as floating point numbers

assistant: ```c
void usage(char *fname) {
  printf("Usage: %s val1 val2 ...\n", fname);
  printf("Values may be given as hex patterns or as floating point numbers\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D2
type: string

tool: D5: Usage: %s val1 val2 ...


tool: D2: Values may be given as hex patterns or as floating point numbers

assistant: ```c
void usage(char *fname) {
  printf("Usage: %s val1 val2 ...\n", fname);
  printf("Values may be given as hex patterns or as floating point numbers\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D9: Usage: %s val1 val2 ...


tool: D7: Values may be given as hex patterns or as floating point numbers

assistant: ```c
void usage(char *fname) {
  printf("Usage: %s val1 val2 ...\n", fname);
  printf("Values may be given as hex patterns or as floating point numbers\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D12: Usage: %s val1 val2 ...


tool: D2: Values may be given as hex patterns or as floating point numbers

assistant: ```c
void usage(char *fname) {
  printf("Usage: %s val1 val2 ...\n", fname);
  printf("Values may be given as hex patterns or as floating point numbers\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0xffffffffffffffff,-0x10(%rbp)
  movabs $0x8be589eac7,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x2,-0x20(%rbp)
  jmp    L13
L10:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L30
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L4
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L4:
  movq   $0x2,-0x20(%rbp)
L30:
  addq   $0x1,-0x20(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %rax,-0x20(%rbp)
  jl     L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: %ld


assistant: ```c
int main() {
  long input, i, compound;
  long prime = -1;
  input = 600851475143;
  compound = input;
  for (i = 2; i < sqrt(input); i++) {
    if (compound % i == 0) {
      compound = compound / i;
      if (i > prime) {
        prime = i;
      }
      i = 2;
    }
  }
  printf("%ld\n", prime);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xffffffffffffffff,%r12
  movabs $0x8be589eac7,%rbp
  mov    $0x2,%ebx
  mov    %rbp,%r13
  jmp    L18
L39:
  add    $0x1,%rbx
L18:
  mov    %r13,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L8
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L39
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  mov    %rax,%rbp
  cmp    %rbx,%r12
  cmovl  %rbx,%r12
  mov    $0x2,%ebx
  jmp    L39
L8:
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D5: %ld


assistant: ```c
int main() {
  long input, i, compound;
  long prime = -1;
  input = 600851475143;
  compound = input;
  for (i = 2; i < sqrt(input); i++) {
    if (compound % i == 0) {
      compound = compound / i;
      if (i > prime) {
        prime = i;
      }
      i = 2;
    }
  }
  printf("%ld\n", prime);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  movabs $0x8be589eac7,%rbp
  push   %rbx
  mov    %rbp,%r13
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r13,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L15
L33:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L18
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jg     L33
L15:
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  cmp    %rbx,%r12
  mov    %rax,%rbp
  cmovl  %rbx,%r12
  mov    $0x3,%ebx
  jmp    L9
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: %ld


assistant: ```c
int main() {
  long input, i, compound;
  long prime = -1;
  input = 600851475143;
  compound = input;
  for (i = 2; i < sqrt(input); i++) {
    if (compound % i == 0) {
      compound = compound / i;
      if (i > prime) {
        prime = i;
      }
      i = 2;
    }
  }
  printf("%ld\n", prime);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  movabs $0x8be589eac7,%rbp
  push   %rbx
  mov    %rbp,%r13
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r13,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L3
L12:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L20
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jg     L12
L3:
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  cmp    %rbx,%r12
  mov    %rax,%rbp
  cmovl  %rbx,%r12
  mov    $0x3,%ebx
  jmp    L37
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: %ld


assistant: ```c
int main() {
  long input, i, compound;
  long prime = -1;
  input = 600851475143;
  compound = input;
  for (i = 2; i < sqrt(input); i++) {
    if (compound % i == 0) {
      compound = compound / i;
      if (i > prime) {
        prime = i;
      }
      i = 2;
    }
  }
  printf("%ld\n", prime);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kill_lwp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    D5(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <kill@plt>
  leave
  ret
```

assistant: ```c
int kill_lwp(unsigned long lwpid, int signo) {
  static int tkill_failed;
  errno = 0;
  return kill(lwpid, signo);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kill_lwp>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  movq   $0x0,(%rax)
  call   <kill@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int kill_lwp(unsigned long lwpid, int signo) {
  static int tkill_failed;
  errno = 0;
  return kill(lwpid, signo);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<kill_lwp>:
  endbr64
  mov    D7(%rip),%rax
  movq   $0x0,(%rax)
  jmp    1050 <kill@plt>
```

assistant: ```c
int kill_lwp(unsigned long lwpid, int signo) {
  static int tkill_failed;
  errno = 0;
  return kill(lwpid, signo);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kill_lwp>:
  endbr64
  mov    D2(%rip),%rax
  movq   $0x0,(%rax)
  jmp    1050 <kill@plt>
```

assistant: ```c
int kill_lwp(unsigned long lwpid, int signo) {
  static int tkill_failed;
  errno = 0;
  return kill(lwpid, signo);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Exception_Trap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L2:
  jmp    L2
```

assistant: ```c
void Exception_Trap(void) {
  for (;;)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Exception_Trap>:
  endbr64
L2:
  jmp    L2
```

assistant: ```c
void Exception_Trap(void) {
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Exception_Trap>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void Exception_Trap(void) {
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Exception_Trap>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
void Exception_Trap(void) {
  for (;;)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L13:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <decode@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <eval@plt>
L12:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void run(uint32_t pc) {
  int running = 1;
  while (running) {
    decode(&pc);
    eval(&running, &pc);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x14(%rsp)
  lea    0xc(%rsp),%rbx
L4:
  mov    %rbx,%rdi
  call   <decode@plt>
  lea    0x14(%rsp),%rdi
  mov    %rbx,%rsi
  call   <eval@plt>
  cmpl   $0x0,0x14(%rsp)
  jne    L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void run(uint32_t pc) {
  int running = 1;
  while (running) {
    decode(&pc);
    eval(&running, &pc);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<run>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  lea    0x14(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x14(%rsp)
L1:
  mov    %rbx,%rdi
  call   <decode@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <eval@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L1
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void run(uint32_t pc) {
  int running = 1;
  while (running) {
    decode(&pc);
    eval(&running, &pc);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  lea    0x14(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x14(%rsp)
L2:
  mov    %rbx,%rdi
  call   <decode@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <eval@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void run(uint32_t pc) {
  int running = 1;
  while (running) {
    decode(&pc);
    eval(&running, &pc);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L32
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L46
L32:
  movq   $0x0,-0x8(%rbp)
  jmp    L39
L29:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jae    L36
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L36:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
L46:
  leave
  ret
```

assistant: ```c
size_t strlcpy(char *dst, char const *src, size_t s) {
  size_t i = 0;
  if (!s) {
    return strlen(src);
  }
  for (i = 0; ((i < s - 1) && src[i]); i++) {
    dst[i] = src[i];
  }
  dst[i] = 0;
  return i + strlen(src + i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlcpy>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L8
  mov    %rdi,%r8
  mov    %rdx,%rbx
  mov    $0x0,%eax
  sub    $0x1,%rbx
  je     L47
L16:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L4
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L16
  jmp    L47
L8:
  mov    %rsi,%rdi
  call   <strlen@plt>
  jmp    L22
L4:
  mov    %rax,%rbx
L47:
  movb   $0x0,(%r8,%rbx,1)
  lea    (%rsi,%rbx,1),%rdi
  call   <strlen@plt>
  add    %rbx,%rax
L22:
  pop    %rbx
  ret
```

assistant: ```c
size_t strlcpy(char *dst, char const *src, size_t s) {
  size_t i = 0;
  if (!s) {
    return strlen(src);
  }
  for (i = 0; ((i < s - 1) && src[i]); i++) {
    dst[i] = src[i];
  }
  dst[i] = 0;
  return i + strlen(src + i);
}
```
user: What is the c source code of the assembly code below:

```asm
<strlcpy>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  test   %rdx,%rdx
  je     L5
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1,%rdx
  mov    %rsi,%r8
  mov    %rcx,%rsi
  jne    L19
  jmp    L14
L48:
  mov    %al,(%rcx,%rbx,1)
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  je     L17
L19:
  movzbl (%rdi,%rbx,1),%eax
  lea    (%rdi,%rbx,1),%r8
  lea    (%rcx,%rbx,1),%rsi
  test   %al,%al
  jne    L48
L14:
  movb   $0x0,(%rsi)
  mov    %r8,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  jmp    1050 <strlen@plt>
  nopl   (%rax)
L17:
  lea    (%rcx,%rbx,1),%rsi
  lea    (%rdi,%rbx,1),%r8
  movb   $0x0,(%rsi)
  mov    %r8,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t strlcpy(char *dst, char const *src, size_t s) {
  size_t i = 0;
  if (!s) {
    return strlen(src);
  }
  for (i = 0; ((i < s - 1) && src[i]); i++) {
    dst[i] = src[i];
  }
  dst[i] = 0;
  return i + strlen(src + i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlcpy>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  test   %rdx,%rdx
  je     L2
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1,%rdx
  mov    %rsi,%r8
  mov    %rcx,%rsi
  jne    L28
  jmp    L9
L37:
  mov    %al,(%rcx,%rbx,1)
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  je     L24
L28:
  movzbl (%rdi,%rbx,1),%eax
  lea    (%rdi,%rbx,1),%r8
  lea    (%rcx,%rbx,1),%rsi
  test   %al,%al
  jne    L37
L9:
  movb   $0x0,(%rsi)
  mov    %r8,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  jmp    1050 <strlen@plt>
  nopl   (%rax)
L24:
  lea    (%rcx,%rbx,1),%rsi
  lea    (%rdi,%rbx,1),%r8
  movb   $0x0,(%rsi)
  mov    %r8,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t strlcpy(char *dst, char const *src, size_t s) {
  size_t i = 0;
  if (!s) {
    return strlen(src);
  }
  for (i = 0; ((i < s - 1) && src[i]); i++) {
    dst[i] = src[i];
  }
  dst[i] = 0;
  return i + strlen(src + i);
}
```