ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse>:
  endbr64
  movslq %esi,%rcx
  movslq %edx,%rax
  cmp    %esi,%edx
  jle    L0
  xchg   %ax,%ax
L5:
  movzbl (%rdi,%rax,1),%edx
  sub    $0x1,%rax
  mov    %dl,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    %eax,%ecx
  jl     L5
L0:
  ret
```

assistant: ```c
void reverse(char str[], int start, int end) {
  if (start >= end)
    return;
  char temp = str[start];
  str[start] = str[end];
  str[end] = str[start];
  reverse(str, start + 1, end - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<itob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L16:
  mov    -0x20(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  and    $0x1,%edx
  mov    %edx,(%rax)
  sarl   -0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L16
  nop
  pop    %rbp
  ret
```

assistant: ```c
void itob(int binvec_p[], int symbol, int length) {
  int counter;
  for (counter = 0; counter < length; counter++) {
    binvec_p[length - counter - 1] = (symbol & 1);
    symbol = symbol >> 1;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itob>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%rax
  lea    -0x4(%rdi,%rcx,1),%rcx
  lea    -0x1(%rdx),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rcx
L8:
  mov    %esi,%edx
  and    $0x1,%edx
  mov    %edx,-0x4(%rax)
  sar    %esi
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
L11:
  ret
```

assistant: ```c
void itob(int binvec_p[], int symbol, int length) {
  int counter;
  for (counter = 0; counter < length; counter++) {
    binvec_p[length - counter - 1] = (symbol & 1);
    symbol = symbol >> 1;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itob>:
  endbr64
  test   %edx,%edx
  jle    L10
  movslq %edx,%rcx
  sub    $0x1,%edx
  shl    $0x2,%rcx
  shl    $0x2,%rdx
  lea    (%rdi,%rcx,1),%rax
  lea    -0x4(%rdi,%rcx,1),%rcx
  sub    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %esi,%edx
  sub    $0x4,%rax
  sar    %esi
  and    $0x1,%edx
  mov    %edx,(%rax)
  cmp    %rcx,%rax
  jne    L7
L10:
  ret
```

assistant: ```c
void itob(int binvec_p[], int symbol, int length) {
  int counter;
  for (counter = 0; counter < length; counter++) {
    binvec_p[length - counter - 1] = (symbol & 1);
    symbol = symbol >> 1;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<itob>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rcx
  sub    $0x1,%edx
  shl    $0x2,%rcx
  shl    $0x2,%rdx
  lea    (%rdi,%rcx,1),%rax
  lea    -0x4(%rdi,%rcx,1),%rcx
  sub    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %esi,%edx
  sub    $0x4,%rax
  sar    %esi
  and    $0x1,%edx
  mov    %edx,(%rax)
  cmp    %rcx,%rax
  jne    L2
L14:
  ret
```

assistant: ```c
void itob(int binvec_p[], int symbol, int length) {
  int counter;
  for (counter = 0; counter < length; counter++) {
    binvec_p[length - counter - 1] = (symbol & 1);
    symbol = symbol >> 1;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys$gettim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0xe,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$gettim(unsigned long long *timadr) {
  return ({
    unsigned long resultvar;
    register long int _a1 asm("rdi") = (long)(timadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(14), "r"(_a1)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sys$gettim>:
  endbr64
  mov    $0xe,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$gettim(unsigned long long *timadr) {
  return ({
    unsigned long resultvar;
    register long int _a1 asm("rdi") = (long)(timadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(14), "r"(_a1)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sys$gettim>:
  endbr64
  mov    $0xe,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$gettim(unsigned long long *timadr) {
  return ({
    unsigned long resultvar;
    register long int _a1 asm("rdi") = (long)(timadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(14), "r"(_a1)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tc_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tc_reset_vms@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tc_init@plt>
  nop
  leave
  ret
```

assistant: ```c
void tc_reset(struct Context *ctx) {
  tc_reset_vms(ctx);
  tc_init(ctx);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tc_reset>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <tc_reset_vms@plt>
  mov    %rbx,%rdi
  call   <tc_init@plt>
  pop    %rbx
  ret
```

assistant: ```c
void tc_reset(struct Context *ctx) {
  tc_reset_vms(ctx);
  tc_init(ctx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tc_reset>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <tc_reset_vms@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <tc_init@plt>
```

assistant: ```c
void tc_reset(struct Context *ctx) {
  tc_reset_vms(ctx);
  tc_init(ctx);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tc_reset>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <tc_reset_vms@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <tc_init@plt>
```

assistant: ```c
void tc_reset(struct Context *ctx) {
  tc_reset_vms(ctx);
  tc_init(ctx);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pre_li>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x52,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int pre_li(const struct mdoc_meta *meta, const struct mdoc_node *n) {
  font_push('R');
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<pre_li>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x52,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pre_li(const struct mdoc_meta *meta, const struct mdoc_node *n) {
  font_push('R');
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pre_li>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x52,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pre_li(const struct mdoc_meta *meta, const struct mdoc_node *n) {
  font_push('R');
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<pre_li>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x52,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pre_li(const struct mdoc_meta *meta, const struct mdoc_node *n) {
  font_push('R');
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<Xfail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L5
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <error@plt>
  jmp    L23
L5:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L23:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: Fail instruction

assistant: ```c
int Xfail(int modf, char *label, char *mnemo, char *oper) {
  if (oper && *oper)
    error(oper);
  else
    error("Fail instruction");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Xfail>:
  endbr64
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L8
  cmpb   $0x0,(%rcx)
  jne    L25
L8:
  lea    D7(%rip),%rdi
  call   <error@plt>
L12:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L25:
  mov    %rcx,%rdi
  call   <error@plt>
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: Fail instruction

assistant: ```c
int Xfail(int modf, char *label, char *mnemo, char *oper) {
  if (oper && *oper)
    error(oper);
  else
    error("Fail instruction");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Xfail>:
  endbr64
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L11
  cmpb   $0x0,(%rcx)
  jne    L19
L11:
  lea    D8(%rip),%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L19:
  mov    %rcx,%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: Fail instruction

assistant: ```c
int Xfail(int modf, char *label, char *mnemo, char *oper) {
  if (oper && *oper)
    error(oper);
  else
    error("Fail instruction");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Xfail>:
  endbr64
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L14
  cmpb   $0x0,(%rcx)
  jne    L2
L14:
  lea    D5(%rip),%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L2:
  mov    %rcx,%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: Fail instruction

assistant: ```c
int Xfail(int modf, char *label, char *mnemo, char *oper) {
  if (oper && *oper)
    error(oper);
  else
    error("Fail instruction");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<drawString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L59
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L46:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jle    L54
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  add    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <drawCharacter@plt>
L54:
  addl   $0x8,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L47
  movl   $0x0,-0x8(%rbp)
  subl   $0x8,-0x4(%rbp)
L47:
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  jmp    L17
L59:
  nop
L17:
  leave
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<drawString>:
  endbr64
  test   %rdi,%rdi
  je     L66
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%r14d
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L31
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L73
L76:
  lea    (%r14,%r12,1),%edx
  lea    0x0(%r13,%rbp,1),%esi
  movsbl %dil,%edi
  call   <drawCharacter@plt>
  jmp    L50
L70:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L31
L73:
  cmp    $0x1f,%dil
  jg     L76
L50:
  add    $0x8,%ebp
  cmpb   $0xa,(%rbx)
  jne    L70
  sub    $0x8,%r12d
  mov    $0x0,%ebp
  jmp    L70
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawString>:
  endbr64
  test   %rdi,%rdi
  je     L46
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  mov    %esi,%r12d
  mov    %edx,%r13d
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L5
  nopl   0x0(%rax)
L12:
  add    $0x8,%ebp
  cmpb   $0xa,(%rbx)
  jne    L67
  sub    $0x8,%r14d
  xor    %ebp,%ebp
L67:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L10
L5:
  cmp    $0x1f,%dil
  jle    L12
  lea    0x0(%r13,%r14,1),%edx
  lea    (%r12,%rbp,1),%esi
  call   <drawCharacter@plt>
  jmp    L12
  nopl   0x0(%rax)
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L46:
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<drawString>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L68
  mov    %esi,%r12d
  mov    %edx,%r13d
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L42
  nopl   0x0(%rax)
L56:
  add    $0x8,%ebp
  cmp    $0xa,%dil
  jne    L12
  sub    $0x8,%r14d
  xor    %ebp,%ebp
L12:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L68
L42:
  cmp    $0x1f,%dil
  jle    L56
  lea    0x0(%r13,%r14,1),%edx
  lea    (%r12,%rbp,1),%esi
  call   <drawCharacter@plt>
  movzbl (%rbx),%edi
  jmp    L56
  nopl   (%rax)
L68:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L44:
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gettime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x18(%rbp),%rax
  imul   $0x64,%eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x6b5fca6b,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x16,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
uint64_t gettime() {
  uint64_t t;
  struct timespec ti;
  clock_gettime(CLOCK_MONOTONIC, &ti);
  t = (uint64_t)ti.tv_sec * 100;
  t += ti.tv_nsec / 10000000;
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gettime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x64,0x8(%rsp),%ecx
  mov    (%rsp),%edx
  movslq %edx,%rax
  imul   $0x6b5fca6b,%rax,%rax
  sar    $0x36,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  add    %ecx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t gettime() {
  uint64_t t;
  struct timespec ti;
  clock_gettime(CLOCK_MONOTONIC, &ti);
  t = (uint64_t)ti.tv_sec * 100;
  t += ti.tv_nsec / 10000000;
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gettime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq (%rsp),%rax
  imul   $0x64,0x8(%rsp),%ecx
  mov    %rax,%rdx
  imul   $0x6b5fca6b,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x36,%rax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t gettime() {
  uint64_t t;
  struct timespec ti;
  clock_gettime(CLOCK_MONOTONIC, &ti);
  t = (uint64_t)ti.tv_sec * 100;
  t += ti.tv_nsec / 10000000;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gettime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq (%rsp),%rax
  imul   $0x64,0x8(%rsp),%ecx
  mov    %rax,%rdx
  imul   $0x6b5fca6b,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x36,%rax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t gettime() {
  uint64_t t;
  struct timespec ti;
  clock_gettime(CLOCK_MONOTONIC, &ti);
  t = (uint64_t)ti.tv_sec * 100;
  t += ti.tv_nsec / 10000000;
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<baz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <bar@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <foo@plt>
  nop
  leave
  ret
```

assistant: ```c
void baz(long a, long b, void *c) {
  long d;
  d = (long)c;
  foo(d, bar(a, 1), b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<baz>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x1,%esi
  call   <bar@plt>
  mov    %eax,%esi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <foo@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void baz(long a, long b, void *c) {
  long d;
  d = (long)c;
  foo(d, bar(a, 1), b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<baz>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <bar@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  pop    %r12
  jmp    1060 <foo@plt>
```

assistant: ```c
void baz(long a, long b, void *c) {
  long d;
  d = (long)c;
  foo(d, bar(a, 1), b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baz>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <bar@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  pop    %r12
  jmp    1060 <foo@plt>
```

assistant: ```c
void baz(long a, long b, void *c) {
  long d;
  d = (long)c;
  foo(d, bar(a, 1), b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<op_0xd9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <EXX@plt>
  mov    $0x4,%edi
  call   <T_WAIT_UNTIL@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op_0xd9(void) {
  EXX();
  T_WAIT_UNTIL(4);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_0xd9>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <EXX@plt>
  mov    $0x4,%edi
  call   <T_WAIT_UNTIL@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op_0xd9(void) {
  EXX();
  T_WAIT_UNTIL(4);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<op_0xd9>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <EXX@plt>
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_0xd9(void) {
  EXX();
  T_WAIT_UNTIL(4);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<op_0xd9>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <EXX@plt>
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_0xd9(void) {
  EXX();
  T_WAIT_UNTIL(4);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L15
L16:
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
L15:
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  test   %eax,%eax
  jne    L16
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jge    L11
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L35
L11:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  add    %eax,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  add    $0x3,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D27
type: string

tool: D3: %d

tool: D27: %d


assistant: ```c
int main() {
  int n, x, y = 0, s = 0;
  int a[5] = {0};
  scanf("%d", &n);
  while (n--) {
    scanf("%d", &x);
    a[x]++;
  }
  s = a[4];
  if (a[3] < a[1])
    y = a[3];
  else
    y = a[1];
  a[3] -= y;
  a[1] -= y;
  s += y;
  s += a[3];
  s += (2 * a[2] + a[1] + 3) / 4;
  printf("%d\n", s);
  return 0;
}
```