ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<utf8_wide_char>:
  endbr64
  test   %rdi,%rdi
  je     L31
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L18
  mov    D21(%rip),%rax
  mov    (%rax),%eax
L98:
  pop    %rbx
  ret
L18:
  call   <utf8_char_size@plt>
  cmp    $0x3,%eax
  je     L103
  jg     L70
  cmp    $0x1,%eax
  je     L63
  cmp    $0x2,%eax
  jne    L82
  movzbl (%rbx),%eax
  shl    $0x8,%eax
  movzbl 0x1(%rbx),%edx
  or     %edx,%eax
  jmp    L98
L70:
  cmp    $0x4,%eax
  jne    L82
  movzbl (%rbx),%eax
  shl    $0x18,%eax
  movzbl 0x1(%rbx),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl 0x3(%rbx),%edx
  or     %edx,%eax
  movzbl 0x2(%rbx),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  jmp    L98
L63:
  movsbl (%rbx),%eax
  jmp    L98
L103:
  movzbl (%rbx),%eax
  shl    $0x10,%eax
  movzbl 0x1(%rbx),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rbx),%edx
  or     %edx,%eax
  jmp    L98
L82:
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L98
L31:
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
wint_t utf8_wide_char(const char *string) {
  int char_size;
  wint_t result;
  if (!string || !string[0])
    return WEOF;
  char_size = utf8_char_size(string);
  switch (char_size) {
  case 1:
    result = (wint_t)string[0];
    break;
  case 2:
    result = ((wint_t)((unsigned char)string[0])) << 8 | ((wint_t)((unsigned char)string[1]));
    break;
  case 3:
    result = ((wint_t)((unsigned char)string[0])) << 16 | ((wint_t)((unsigned char)string[1])) << 8 | ((wint_t)((unsigned char)string[2]));
    break;
  case 4:
    result = ((wint_t)((unsigned char)string[0])) << 24 | ((wint_t)((unsigned char)string[1])) << 16 | ((wint_t)((unsigned char)string[2])) << 8 | ((wint_t)((unsigned char)string[3]));
    break;
  default:
    result = WEOF;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<utf8_wide_char>:
  endbr64
  test   %rdi,%rdi
  je     L24
  cmpb   $0x0,(%rdi)
  push   %rbx
  mov    %rdi,%rbx
  jne    L66
L53:
  mov    D9(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
  nopl   (%rax)
L66:
  call   <utf8_char_size@plt>
  cmp    $0x3,%eax
  je     L58
  jg     L7
  cmp    $0x1,%eax
  je     L39
  cmp    $0x2,%eax
  jne    L53
  movzwl (%rbx),%eax
  pop    %rbx
  rol    $0x8,%ax
  movzwl %ax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  cmp    $0x4,%eax
  jne    L53
  mov    (%rbx),%eax
  pop    %rbx
  bswap  %eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  movsbl (%rbx),%eax
  pop    %rbx
  ret
  nopl   (%rax)
L58:
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  shl    $0x10,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rbx),%edx
  pop    %rbx
  or     %edx,%eax
  ret
```

assistant: ```c
wint_t utf8_wide_char(const char *string) {
  int char_size;
  wint_t result;
  if (!string || !string[0])
    return WEOF;
  char_size = utf8_char_size(string);
  switch (char_size) {
  case 1:
    result = (wint_t)string[0];
    break;
  case 2:
    result = ((wint_t)((unsigned char)string[0])) << 8 | ((wint_t)((unsigned char)string[1]));
    break;
  case 3:
    result = ((wint_t)((unsigned char)string[0])) << 16 | ((wint_t)((unsigned char)string[1])) << 8 | ((wint_t)((unsigned char)string[2]));
    break;
  case 4:
    result = ((wint_t)((unsigned char)string[0])) << 24 | ((wint_t)((unsigned char)string[1])) << 16 | ((wint_t)((unsigned char)string[2])) << 8 | ((wint_t)((unsigned char)string[3]));
    break;
  default:
    result = WEOF;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utf8_wide_char>:
  endbr64
  test   %rdi,%rdi
  je     L51
  cmpb   $0x0,(%rdi)
  push   %rbx
  mov    %rdi,%rbx
  jne    L62
L13:
  mov    D14(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
  nopl   (%rax)
L62:
  call   <utf8_char_size@plt>
  cmp    $0x3,%eax
  je     L2
  jg     L7
  cmp    $0x1,%eax
  je     L22
  cmp    $0x2,%eax
  jne    L13
  movzwl (%rbx),%eax
  pop    %rbx
  rol    $0x8,%ax
  movzwl %ax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  cmp    $0x4,%eax
  jne    L13
  mov    (%rbx),%eax
  pop    %rbx
  bswap  %eax
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  movsbl (%rbx),%eax
  pop    %rbx
  ret
  nopl   (%rax)
L2:
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  shl    $0x10,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rbx),%edx
  pop    %rbx
  or     %edx,%eax
  ret
```

assistant: ```c
wint_t utf8_wide_char(const char *string) {
  int char_size;
  wint_t result;
  if (!string || !string[0])
    return WEOF;
  char_size = utf8_char_size(string);
  switch (char_size) {
  case 1:
    result = (wint_t)string[0];
    break;
  case 2:
    result = ((wint_t)((unsigned char)string[0])) << 8 | ((wint_t)((unsigned char)string[1]));
    break;
  case 3:
    result = ((wint_t)((unsigned char)string[0])) << 16 | ((wint_t)((unsigned char)string[1])) << 8 | ((wint_t)((unsigned char)string[2]));
    break;
  case 4:
    result = ((wint_t)((unsigned char)string[0])) << 24 | ((wint_t)((unsigned char)string[1])) << 16 | ((wint_t)((unsigned char)string[2])) << 8 | ((wint_t)((unsigned char)string[3]));
    break;
  default:
    result = WEOF;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ax25_create_ui_packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x11a,-0x2c(%rbp)
  jg     L9
  cmpq   $0x0,-0x38(%rbp)
  jne    L17
L9:
  mov    $0x0,%eax
  jmp    L15
L17:
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x7,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x7,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1c(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x7,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x7,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x38,%rax
  movl   $0x3,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x3c,%rax
  movl   $0xf0,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x40(%rax),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ax25_compute_crc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  addl   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
uint32_t ax25_create_ui_packet(uint8_t *src_in, uint8_t *dst_in, uint8_t *payload_in, uint16_t payload_length, uint8_t *packet_out) {
  uint16_t crc = 0;
  uint16_t len = 0;
  uint16_t ax25_len = 0;
  if (payload_length > ((256) + (18 + 8)) || packet_out == NULL)
    return 0;
  memcpy(packet_out + 0, dst_in, 7);
  len += 7;
  memcpy(packet_out + (0 + 7), src_in, 7);
  len += 7;
  packet_out[((0 + 7) + 7)] = 0x03;
  len += 1;
  packet_out[(((0 + 7) + 7) + 1)] = 0xF0;
  len += 1;
  memcpy(packet_out + ((((0 + 7) + 7) + 1) + 1), payload_in, payload_length);
  len += payload_length;
  crc = ax25_compute_crc(packet_out, len);
  packet_out[len] = crc >> 8 & 0xFF;
  packet_out[len + 1] = crc & 0xFF;
  len += 2;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ax25_create_ui_packet>:
  endbr64
  cmp    $0x11a,%ecx
  jg     L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %r8,%rbx
  mov    $0x0,%eax
  test   %r8,%r8
  je     L11
  mov    $0x7,%edx
  mov    %r8,%rdi
  call   <memcpy@plt>
  lea    0x1c(%rbx),%rdi
  mov    $0x7,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  movl   $0x3,0x38(%rbx)
  movl   $0xf0,0x3c(%rbx)
  lea    0x40(%rbx),%rdi
  mov    %ebp,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  lea    0x10(%rbp),%r12d
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <ax25_compute_crc@plt>
  movslq %r12d,%r12
  movzbl %ah,%edx
  mov    %edx,(%rbx,%r12,4)
  and    $0xff,%eax
  mov    %eax,0x4(%rbx,%r12,4)
  lea    0x12(%rbp),%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint32_t ax25_create_ui_packet(uint8_t *src_in, uint8_t *dst_in, uint8_t *payload_in, uint16_t payload_length, uint8_t *packet_out) {
  uint16_t crc = 0;
  uint16_t len = 0;
  uint16_t ax25_len = 0;
  if (payload_length > ((256) + (18 + 8)) || packet_out == NULL)
    return 0;
  memcpy(packet_out + 0, dst_in, 7);
  len += 7;
  memcpy(packet_out + (0 + 7), src_in, 7);
  len += 7;
  packet_out[((0 + 7) + 7)] = 0x03;
  len += 1;
  packet_out[(((0 + 7) + 7) + 1)] = 0xF0;
  len += 1;
  memcpy(packet_out + ((((0 + 7) + 7) + 1) + 1), payload_in, payload_length);
  len += payload_length;
  crc = ax25_compute_crc(packet_out, len);
  packet_out[len] = crc >> 8 & 0xFF;
  packet_out[len + 1] = crc & 0xFF;
  len += 2;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<ax25_create_ui_packet>:
  endbr64
  cmp    $0x11a,%ecx
  jg     L6
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r8,%r8
  je     L17
  mov    %rdx,%r12
  mov    %rdi,%r13
  mov    $0x7,%edx
  mov    %r8,%rdi
  mov    %ecx,%ebx
  call   <memcpy@plt>
  lea    0x1c(%rbp),%rdi
  mov    $0x7,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  lea    0x40(%rbp),%rdi
  movabs $0xf000000003,%rax
  lea    0x10(%rbx),%r12d
  mov    %rax,0x38(%rbp)
  call   <memcpy@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movslq %r12d,%r12
  call   <ax25_compute_crc@plt>
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x0(%rbp,%r12,4)
  mov    %eax,0x4(%rbp,%r12,4)
  lea    0x12(%rbx),%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t ax25_create_ui_packet(uint8_t *src_in, uint8_t *dst_in, uint8_t *payload_in, uint16_t payload_length, uint8_t *packet_out) {
  uint16_t crc = 0;
  uint16_t len = 0;
  uint16_t ax25_len = 0;
  if (payload_length > ((256) + (18 + 8)) || packet_out == NULL)
    return 0;
  memcpy(packet_out + 0, dst_in, 7);
  len += 7;
  memcpy(packet_out + (0 + 7), src_in, 7);
  len += 7;
  packet_out[((0 + 7) + 7)] = 0x03;
  len += 1;
  packet_out[(((0 + 7) + 7) + 1)] = 0xF0;
  len += 1;
  memcpy(packet_out + ((((0 + 7) + 7) + 1) + 1), payload_in, payload_length);
  len += payload_length;
  crc = ax25_compute_crc(packet_out, len);
  packet_out[len] = crc >> 8 & 0xFF;
  packet_out[len + 1] = crc & 0xFF;
  len += 2;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ax25_create_ui_packet>:
  endbr64
  cmp    $0x11a,%ecx
  jg     L17
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r8,%r8
  je     L18
  mov    %rdx,%r12
  mov    %rdi,%r13
  mov    $0x7,%edx
  mov    %r8,%rdi
  mov    %ecx,%ebx
  call   <memcpy@plt>
  lea    0x1c(%rbp),%rdi
  mov    $0x7,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  lea    0x40(%rbp),%rdi
  mov    D4(%rip),%rax
  lea    0x10(%rbx),%r12d
  mov    %rax,0x38(%rbp)
  call   <memcpy@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movslq %r12d,%r12
  call   <ax25_compute_crc@plt>
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x0(%rbp,%r12,4)
  mov    %eax,0x4(%rbp,%r12,4)
  lea    0x12(%rbx),%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: byte[8]

tool: {"D4": [0x03,0x00,0x00,0x00,0xf0,0x00,0x00,0x00]}

assistant: ```c
uint32_t ax25_create_ui_packet(uint8_t *src_in, uint8_t *dst_in, uint8_t *payload_in, uint16_t payload_length, uint8_t *packet_out) {
  uint16_t crc = 0;
  uint16_t len = 0;
  uint16_t ax25_len = 0;
  if (payload_length > ((256) + (18 + 8)) || packet_out == NULL)
    return 0;
  memcpy(packet_out + 0, dst_in, 7);
  len += 7;
  memcpy(packet_out + (0 + 7), src_in, 7);
  len += 7;
  packet_out[((0 + 7) + 7)] = 0x03;
  len += 1;
  packet_out[(((0 + 7) + 7) + 1)] = 0xF0;
  len += 1;
  memcpy(packet_out + ((((0 + 7) + 7) + 1) + 1), payload_in, payload_length);
  len += payload_length;
  crc = ax25_compute_crc(packet_out, len);
  packet_out[len] = crc >> 8 & 0xFF;
  packet_out[len + 1] = crc & 0xFF;
  len += 2;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uppercaseString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L40
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movb   $0x0,-0x21(%rbp)
  jmp    L23
L35:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  cmpb   $0x60,-0x21(%rbp)
  jle    L41
  cmpb   $0x7a,-0x21(%rbp)
  jg     L41
  movzbl -0x21(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x21(%rbp)
L41:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x21(%rbp),%edx
  mov    %dl,(%rax)
L23:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L40:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *uppercaseString(const char *source) {
  size_t len = strlen(source);
  char *buffer = malloc(len + 1);
  if (buffer) {
    const char *sourceChar = source;
    char *destChar = buffer;
    char finalChar = 0;
    while (*sourceChar) {
      finalChar = *sourceChar++;
      if (finalChar >= 'a' && finalChar <= 'z') {
        finalChar -= 32;
      }
      *destChar++ = finalChar;
    }
    *destChar = 0;
  }
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uppercaseString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L20
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L24
  mov    %rax,%rcx
L22:
  add    $0x1,%rbx
  lea    -0x61(%rdx),%edi
  lea    -0x20(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L22
L34:
  movb   $0x0,(%rcx)
L20:
  pop    %rbx
  ret
L24:
  mov    %rax,%rcx
  jmp    L34
```

assistant: ```c
const char *uppercaseString(const char *source) {
  size_t len = strlen(source);
  char *buffer = malloc(len + 1);
  if (buffer) {
    const char *sourceChar = source;
    char *destChar = buffer;
    char finalChar = 0;
    while (*sourceChar) {
      finalChar = *sourceChar++;
      if (finalChar >= 'a' && finalChar <= 'z') {
        finalChar -= 32;
      }
      *destChar++ = finalChar;
    }
    *destChar = 0;
  }
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uppercaseString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  je     L11
  nopl   (%rax)
L6:
  lea    -0x61(%rdx),%edi
  add    $0x1,%rbx
  lea    -0x20(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L6
L11:
  movb   $0x0,(%rcx)
L1:
  pop    %rbx
  ret
```

assistant: ```c
const char *uppercaseString(const char *source) {
  size_t len = strlen(source);
  char *buffer = malloc(len + 1);
  if (buffer) {
    const char *sourceChar = source;
    char *destChar = buffer;
    char finalChar = 0;
    while (*sourceChar) {
      finalChar = *sourceChar++;
      if (finalChar >= 'a' && finalChar <= 'z') {
        finalChar -= 32;
      }
      *destChar++ = finalChar;
    }
    *destChar = 0;
  }
  return buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uppercaseString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L49
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  je     L9
  nopl   (%rax)
L28:
  lea    -0x61(%rdx),%esi
  add    $0x1,%rbx
  add    $0x1,%rcx
  cmp    $0x19,%sil
  ja     L29
  sub    $0x20,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L28
L9:
  movb   $0x0,(%rcx)
L49:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L28
  movb   $0x0,(%rcx)
  jmp    L49
```

assistant: ```c
const char *uppercaseString(const char *source) {
  size_t len = strlen(source);
  char *buffer = malloc(len + 1);
  if (buffer) {
    const char *sourceChar = source;
    char *destChar = buffer;
    char finalChar = 0;
    while (*sourceChar) {
      finalChar = *sourceChar++;
      if (finalChar >= 'a' && finalChar <= 'z') {
        finalChar -= 32;
      }
      *destChar++ = finalChar;
    }
    *destChar = 0;
  }
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpq   $0x1,-0x18(%rbp)
  jne    L11
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L11
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <kTeiler@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rax,-0x18(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  je     L11
  mov    $0x2a,%edi
  call   <putchar@plt>
L11:
  cmpq   $0x1,-0x18(%rbp)
  jg     L0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L23:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D22
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D13
datatype: string

tool: D22: %I64d = 

tool: D9:  %I64d 

tool: D13: 


assistant: ```c
void prim(long long n) {
  unsigned long long kleinster;
  if (n != 0) {
    printf("%I64d = ", n);
    if (n == 1) {
      printf("1");
    }
    while (n > 1) {
      kleinster = kTeiler(n);
      printf(" %I64d ", kleinster);
      n /= kleinster;
      if (n != 1) {
        printf("*");
      }
    }
    printf("\n\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prim>:
  endbr64
  test   %rdi,%rdi
  jne    L63
  ret
L63:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%rbp
  je     L67
  jle    L23
  lea    D12(%rip),%r12
  jmp    L65
L67:
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L23
L13:
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x1,%rbx
  jle    L23
L65:
  mov    %rbp,%rdi
  call   <kTeiler@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rax
  mov    $0x0,%edx
  div    %rbx
  mov    %rax,%rbx
  mov    %rax,%rbp
  cmp    $0x1,%rax
  jne    L13
L23:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string

tool: D16: %I64d = 

tool: D12:  %I64d 

tool: D17: 


assistant: ```c
void prim(long long n) {
  unsigned long long kleinster;
  if (n != 0) {
    printf("%I64d = ", n);
    if (n == 1) {
      printf("1");
    }
    while (n > 1) {
      kleinster = kTeiler(n);
      printf(" %I64d ", kleinster);
      n /= kleinster;
      if (n != 1) {
        printf("*");
      }
    }
    printf("\n\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prim>:
  endbr64
  test   %rdi,%rdi
  jne    L56
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  xor    %eax,%eax
  push   %rbp
  lea    D13(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    $0x1,%r12
  je     L59
  jle    L22
  lea    D0(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %r12,%rdi
  call   <kTeiler@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  mov    %rax,%r12
  cmp    $0x1,%rax
  je     L22
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x1,%r12
  ja     L40
L22:
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <puts@plt>
  nopl   0x0(%rax)
L59:
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string

tool: D13: %I64d = 

tool: D0:  %I64d 

tool: D10: 


assistant: ```c
void prim(long long n) {
  unsigned long long kleinster;
  if (n != 0) {
    printf("%I64d = ", n);
    if (n == 1) {
      printf("1");
    }
    while (n > 1) {
      kleinster = kTeiler(n);
      printf(" %I64d ", kleinster);
      n /= kleinster;
      if (n != 1) {
        printf("*");
      }
    }
    printf("\n\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<prim>:
  endbr64
  test   %rdi,%rdi
  jne    L16
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  xor    %eax,%eax
  push   %rbp
  lea    D17(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    $0x1,%r12
  je     L58
  jle    L11
  lea    D12(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdi
  call   <kTeiler@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  mov    %rax,%r12
  cmp    $0x1,%rax
  je     L11
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x1,%r12
  ja     L13
L11:
  pop    %rbx
  lea    D29(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <puts@plt>
  nopl   0x0(%rax)
L58:
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string

tool: D17: %I64d = 

tool: D12:  %I64d 

tool: D29: 


assistant: ```c
void prim(long long n) {
  unsigned long long kleinster;
  if (n != 0) {
    printf("%I64d = ", n);
    if (n == 1) {
      printf("1");
    }
    while (n > 1) {
      kleinster = kTeiler(n);
      printf(" %I64d ", kleinster);
      n /= kleinster;
      if (n != 1) {
        printf("*");
      }
    }
    printf("\n\n");
  }
}
```