ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L14
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L0:
  pop    %rbx
  ret
L14:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <myformat@plt>
  mov    $0x0,%eax
  jmp    L0
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D3: Invalid number of arguments 

tool: D7: usage: %s diskSizeInBlockSize


tool: D16: Formatting the disk with size %lu 


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("Invalid number of arguments \n");
    printf("usage: %s diskSizeInBlockSize\n", argv[0]);
    return 1;
  }
  unsigned long size = atoi(argv[1]);
  printf("Formatting the disk with size %lu \n", size);
  myformat(size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L11
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <myformat@plt>
  xor    %eax,%eax
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_infered: string
name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D26: Invalid number of arguments 

tool: D22: usage: %s diskSizeInBlockSize


tool: D7: Formatting the disk with size %lu 


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("Invalid number of arguments \n");
    printf("usage: %s diskSizeInBlockSize\n", argv[0]);
    return 1;
  }
  unsigned long size = atoi(argv[1]);
  printf("Formatting the disk with size %lu \n", size);
  myformat(size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L12
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D25(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <myformat@plt>
  xor    %eax,%eax
  jmp    L5
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D25
type_infered: string

tool: D19: Invalid number of arguments 

tool: D15: usage: %s diskSizeInBlockSize


tool: D25: Formatting the disk with size %lu 


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("Invalid number of arguments \n");
    printf("usage: %s diskSizeInBlockSize\n", argv[0]);
    return 1;
  }
  unsigned long size = atoi(argv[1]);
  printf("Formatting the disk with size %lu \n", size);
  myformat(size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<biLerp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  movss  %xmm4,-0x24(%rbp)
  movss  %xmm5,-0x28(%rbp)
  movss  %xmm6,-0x2c(%rbp)
  movss  %xmm7,-0x30(%rbp)
  movss  -0x24(%rbp),%xmm3
  movss  -0x1c(%rbp),%xmm2
  movss  -0x30(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <lerp@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0x28(%rbp),%xmm3
  movss  -0x20(%rbp),%xmm2
  movss  -0x30(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <lerp@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm2
  movss  -0x8(%rbp),%xmm1
  movss  0x18(%rbp),%xmm0
  mov    -0x18(%rbp),%eax
  movaps %xmm2,%xmm4
  movaps %xmm1,%xmm3
  movaps %xmm0,%xmm2
  movss  0x10(%rbp),%xmm1
  movd   %eax,%xmm0
  call   <lerp@plt>
  leave
  ret
```

assistant: ```c
float biLerp(float x, float y, float q11, float q12, float q21, float q22, float x1, float x2, float y1, float y2) {
  float r1 = lerp(x, x1, x2, q11, q21);
  float r2 = lerp(x, x1, x2, q12, q22);
  return lerp(y, y1, y2, r1, r2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<biLerp>:
  endbr64
  sub    $0x28,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  %xmm3,0x10(%rsp)
  movss  %xmm5,0x14(%rsp)
  movaps %xmm2,%xmm3
  movss  %xmm7,0x1c(%rsp)
  movaps %xmm7,%xmm2
  movss  %xmm6,0x18(%rsp)
  movaps %xmm6,%xmm1
  movss  %xmm0,0x8(%rsp)
  call   <lerp@plt>
  movss  %xmm0,0x4(%rsp)
  movss  0x14(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm2
  movss  0x18(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  call   <lerp@plt>
  movaps %xmm0,%xmm4
  movss  0x4(%rsp),%xmm3
  movss  0x38(%rsp),%xmm2
  movss  0x30(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <lerp@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
float biLerp(float x, float y, float q11, float q12, float q21, float q22, float x1, float x2, float y1, float y2) {
  float r1 = lerp(x, x1, x2, q11, q21);
  float r2 = lerp(x, x1, x2, q12, q22);
  return lerp(y, y1, y2, r1, r2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<biLerp>:
  endbr64
  sub    $0x38,%rsp
  movaps %xmm0,%xmm8
  movaps %xmm2,%xmm0
  movss  0x48(%rsp),%xmm11
  movaps %xmm7,%xmm2
  movss  0x40(%rsp),%xmm7
  movss  %xmm1,0x2c(%rsp)
  movss  %xmm3,0x28(%rsp)
  movaps %xmm6,%xmm1
  movaps %xmm0,%xmm3
  movaps %xmm8,%xmm0
  movss  %xmm7,0x20(%rsp)
  movss  %xmm11,0x1c(%rsp)
  movss  %xmm6,0x14(%rsp)
  movss  %xmm5,0x24(%rsp)
  movss  %xmm2,0x18(%rsp)
  movss  %xmm8,0x10(%rsp)
  call   <lerp@plt>
  movss  0x24(%rsp),%xmm5
  movss  0x28(%rsp),%xmm10
  movss  0x10(%rsp),%xmm8
  movss  0x18(%rsp),%xmm2
  movss  %xmm0,0xc(%rsp)
  movss  0x14(%rsp),%xmm1
  movaps %xmm5,%xmm4
  movaps %xmm10,%xmm3
  movaps %xmm8,%xmm0
  call   <lerp@plt>
  movss  0xc(%rsp),%xmm6
  movss  0x1c(%rsp),%xmm11
  movss  0x20(%rsp),%xmm7
  movss  0x2c(%rsp),%xmm9
  movaps %xmm0,%xmm4
  add    $0x38,%rsp
  movaps %xmm6,%xmm3
  movaps %xmm11,%xmm2
  movaps %xmm7,%xmm1
  movaps %xmm9,%xmm0
  jmp    1050 <lerp@plt>
```

assistant: ```c
float biLerp(float x, float y, float q11, float q12, float q21, float q22, float x1, float x2, float y1, float y2) {
  float r1 = lerp(x, x1, x2, q11, q21);
  float r2 = lerp(x, x1, x2, q12, q22);
  return lerp(y, y1, y2, r1, r2);
}
```
user: What is the c source code of the assembly code below?

```asm
<biLerp>:
  endbr64
  sub    $0x38,%rsp
  movaps %xmm0,%xmm8
  movaps %xmm2,%xmm0
  movss  0x48(%rsp),%xmm11
  movaps %xmm7,%xmm2
  movss  0x40(%rsp),%xmm7
  movss  %xmm1,0x2c(%rsp)
  movss  %xmm3,0x28(%rsp)
  movaps %xmm6,%xmm1
  movaps %xmm0,%xmm3
  movaps %xmm8,%xmm0
  movss  %xmm7,0x20(%rsp)
  movss  %xmm11,0x1c(%rsp)
  movss  %xmm6,0x14(%rsp)
  movss  %xmm5,0x24(%rsp)
  movss  %xmm2,0x18(%rsp)
  movss  %xmm8,0x10(%rsp)
  call   <lerp@plt>
  movss  0x24(%rsp),%xmm5
  movss  0x28(%rsp),%xmm10
  movss  0x10(%rsp),%xmm8
  movss  0x18(%rsp),%xmm2
  movss  %xmm0,0xc(%rsp)
  movss  0x14(%rsp),%xmm1
  movaps %xmm5,%xmm4
  movaps %xmm10,%xmm3
  movaps %xmm8,%xmm0
  call   <lerp@plt>
  movss  0xc(%rsp),%xmm6
  movss  0x1c(%rsp),%xmm11
  movss  0x20(%rsp),%xmm7
  movss  0x2c(%rsp),%xmm9
  movaps %xmm0,%xmm4
  add    $0x38,%rsp
  movaps %xmm6,%xmm3
  movaps %xmm11,%xmm2
  movaps %xmm7,%xmm1
  movaps %xmm9,%xmm0
  jmp    1050 <lerp@plt>
```

assistant: ```c
float biLerp(float x, float y, float q11, float q12, float q21, float q22, float x1, float x2, float y1, float y2) {
  float r1 = lerp(x, x1, x2, q11, q21);
  float r2 = lerp(x, x1, x2, q12, q22);
  return lerp(y, y1, y2, r1, r2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<from_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0xc0,-0x4(%rbp)
  jmp    L0
L1:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  not    %eax
  and    -0x8(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0x8(%rbp)
  shll   $0x5,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  not    %eax
  and    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int from_utf8(char *s) {
  int i = 1;
  int r = (unsigned char)s[0];
  int m;
  for (m = 0xc0; (r & m) == m; m <<= 5)
    r = ((r & ~(m << 1)) << 6) | ((unsigned char)s[i++] & 0x3f);
  return r & ~(m << 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<from_utf8>:
  endbr64
  movzbl (%rdi),%eax
  movzbl %al,%edx
  and    $0xffffffc0,%eax
  cmp    $0xc0,%al
  jne    L21
  add    $0x1,%rdi
  mov    $0xc0,%ecx
L19:
  lea    (%rcx,%rcx,1),%eax
  not    %eax
  and    %edx,%eax
  shl    $0x6,%eax
  movzbl (%rdi),%edx
  and    $0x3f,%edx
  or     %eax,%edx
  shl    $0x5,%ecx
  add    $0x1,%rdi
  mov    %edx,%eax
  and    %ecx,%eax
  cmp    %ecx,%eax
  je     L19
L3:
  lea    (%rcx,%rcx,1),%eax
  not    %eax
  and    %edx,%eax
  ret
L21:
  mov    $0xc0,%ecx
  jmp    L3
```

assistant: ```c
int from_utf8(char *s) {
  int i = 1;
  int r = (unsigned char)s[0];
  int m;
  for (m = 0xc0; (r & m) == m; m <<= 5)
    r = ((r & ~(m << 1)) << 6) | ((unsigned char)s[i++] & 0x3f);
  return r & ~(m << 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<from_utf8>:
  endbr64
  movzbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xffffffc0,%edx
  cmp    $0xc0,%dl
  jne    L17
  add    $0x1,%rdi
  mov    $0xc0,%ecx
  nopw   0x0(%rax,%rax,1)
L10:
  lea    (%rcx,%rcx,1),%edx
  mov    %ecx,%esi
  shl    $0x5,%ecx
  add    $0x1,%rdi
  not    %edx
  and    %eax,%edx
  movzbl -0x1(%rdi),%eax
  shl    $0x6,%edx
  and    $0x3f,%eax
  or     %edx,%eax
  mov    %eax,%edx
  and    %ecx,%edx
  cmp    %ecx,%edx
  je     L10
  shl    $0x6,%esi
  not    %esi
  and    %esi,%eax
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xfffffe7f,%esi
  and    %esi,%eax
  ret
```

assistant: ```c
int from_utf8(char *s) {
  int i = 1;
  int r = (unsigned char)s[0];
  int m;
  for (m = 0xc0; (r & m) == m; m <<= 5)
    r = ((r & ~(m << 1)) << 6) | ((unsigned char)s[i++] & 0x3f);
  return r & ~(m << 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<from_utf8>:
  endbr64
  movzbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xffffffc0,%edx
  cmp    $0xc0,%dl
  jne    L19
  add    $0x1,%rdi
  mov    $0xc0,%ecx
  nopw   0x0(%rax,%rax,1)
L7:
  lea    (%rcx,%rcx,1),%edx
  mov    %ecx,%esi
  shl    $0x5,%ecx
  add    $0x1,%rdi
  not    %edx
  and    %eax,%edx
  movzbl -0x1(%rdi),%eax
  shl    $0x6,%edx
  and    $0x3f,%eax
  or     %edx,%eax
  mov    %eax,%edx
  and    %ecx,%edx
  cmp    %ecx,%edx
  je     L7
  shl    $0x6,%esi
  not    %esi
  and    %esi,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    $0xfffffe7f,%esi
  and    %esi,%eax
  ret
```

assistant: ```c
int from_utf8(char *s) {
  int i = 1;
  int r = (unsigned char)s[0];
  int m;
  for (m = 0xc0; (r & m) == m; m <<= 5)
    r = ((r & ~(m << 1)) << 6) | ((unsigned char)s[i++] & 0x3f);
  return r & ~(m << 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d2i_DSA_PUBKEY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <d2i_PUBKEY@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L35
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_get1_DSA@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_free@plt>
  cmpq   $0x0,-0x10(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L35
L50:
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <DSA_free@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L2:
  mov    -0x10(%rbp),%rax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

assistant: ```c
DSA *d2i_DSA_PUBKEY(DSA **a, const unsigned char **pp, long length) {
  EVP_PKEY *pkey;
  DSA *key;
  const unsigned char *q;
  q = *pp;
  pkey = d2i_PUBKEY(NULL, &q, length);
  if (!pkey)
    return NULL;
  key = EVP_PKEY_get1_DSA(pkey);
  EVP_PKEY_free(pkey);
  if (!key)
    return NULL;
  *pp = q;
  if (a) {
    DSA_free(*a);
    *a = key;
  }
  return key;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d2i_DSA_PUBKEY>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edi
  call   <d2i_PUBKEY@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
  mov    %rax,%rdi
  call   <EVP_PKEY_get1_DSA@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <EVP_PKEY_free@plt>
  test   %rbp,%rbp
  je     L12
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  test   %r13,%r13
  je     L12
  mov    0x0(%r13),%rdi
  call   <DSA_free@plt>
  mov    %rbp,0x0(%r13)
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %rax,%rbp
  jmp    L12
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
DSA *d2i_DSA_PUBKEY(DSA **a, const unsigned char **pp, long length) {
  EVP_PKEY *pkey;
  DSA *key;
  const unsigned char *q;
  q = *pp;
  pkey = d2i_PUBKEY(NULL, &q, length);
  if (!pkey)
    return NULL;
  key = EVP_PKEY_get1_DSA(pkey);
  EVP_PKEY_free(pkey);
  if (!key)
    return NULL;
  *pp = q;
  if (a) {
    DSA_free(*a);
    *a = key;
  }
  return key;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<d2i_DSA_PUBKEY>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <d2i_PUBKEY@plt>
  test   %rax,%rax
  je     L31
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <EVP_PKEY_get1_DSA@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_PKEY_free@plt>
  test   %r12,%r12
  je     L31
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  test   %r13,%r13
  je     L44
  mov    0x0(%r13),%rdi
  call   <DSA_free@plt>
  mov    %r12,0x0(%r13)
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %r12d,%r12d
  jmp    L44
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
DSA *d2i_DSA_PUBKEY(DSA **a, const unsigned char **pp, long length) {
  EVP_PKEY *pkey;
  DSA *key;
  const unsigned char *q;
  q = *pp;
  pkey = d2i_PUBKEY(NULL, &q, length);
  if (!pkey)
    return NULL;
  key = EVP_PKEY_get1_DSA(pkey);
  EVP_PKEY_free(pkey);
  if (!key)
    return NULL;
  *pp = q;
  if (a) {
    DSA_free(*a);
    *a = key;
  }
  return key;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d2i_DSA_PUBKEY>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <d2i_PUBKEY@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <EVP_PKEY_get1_DSA@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_PKEY_free@plt>
  test   %r12,%r12
  je     L9
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  test   %r13,%r13
  je     L2
  mov    0x0(%r13),%rdi
  call   <DSA_free@plt>
  mov    %r12,0x0(%r13)
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r12d,%r12d
  jmp    L2
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
DSA *d2i_DSA_PUBKEY(DSA **a, const unsigned char **pp, long length) {
  EVP_PKEY *pkey;
  DSA *key;
  const unsigned char *q;
  q = *pp;
  pkey = d2i_PUBKEY(NULL, &q, length);
  if (!pkey)
    return NULL;
  key = EVP_PKEY_get1_DSA(pkey);
  EVP_PKEY_free(pkey);
  if (!key)
    return NULL;
  *pp = q;
  if (a) {
    DSA_free(*a);
    *a = key;
  }
  return key;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  jne    L36
  movl   $0x400,-0x24(%rbp)
L36:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rdi
  mov    -0x24(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <getpwuid_r@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L4
L16:
  mov    $0x0,%eax
  jmp    L8
L4:
  mov    -0x20(%rbp),%rax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
char *get_name(uid_t u_id) {
  int bufsize;
  if ((bufsize = sysconf(_SC_GETPW_R_SIZE_MAX)) == -1) {
    bufsize = 1024;
  }
  char *buffer = malloc(bufsize);
  struct passwd pwd, *result = NULL;
  if (getpwuid_r(u_id, &pwd, buffer, bufsize, &result) != 0 || !result) {
    return NULL;
  }
  return pwd.pw_name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  mov    $0x400,%eax
  cmove  %eax,%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  movq   $0x0,0x10(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%r8
  mov    %ebx,%ecx
  mov    %ebp,%edi
  call   <getpwuid_r@plt>
  test   %rax,%rax
  jne    L10
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  cmovne 0x8(%rsp),%rax
L19:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x0,%eax
  jmp    L19
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_name(uid_t u_id) {
  int bufsize;
  if ((bufsize = sysconf(_SC_GETPW_R_SIZE_MAX)) == -1) {
    bufsize = 1024;
  }
  char *buffer = malloc(bufsize);
  struct passwd pwd, *result = NULL;
  if (getpwuid_r(u_id, &pwd, buffer, bufsize, &result) != 0 || !result) {
    return NULL;
  }
  return pwd.pw_name;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_name>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  cmp    $0xffffffff,%eax
  mov    %eax,%r12d
  mov    $0x400,%eax
  cmove  %eax,%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12d,%ecx
  mov    %ebp,%edi
  mov    %rax,%rdx
  lea    0x10(%rsp),%r8
  movq   $0x0,0x10(%rsp)
  call   <getpwuid_r@plt>
  test   %rax,%rax
  jne    L25
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  cmovne 0x8(%rsp),%rax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  jmp    L14
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_name(uid_t u_id) {
  int bufsize;
  if ((bufsize = sysconf(_SC_GETPW_R_SIZE_MAX)) == -1) {
    bufsize = 1024;
  }
  char *buffer = malloc(bufsize);
  struct passwd pwd, *result = NULL;
  if (getpwuid_r(u_id, &pwd, buffer, bufsize, &result) != 0 || !result) {
    return NULL;
  }
  return pwd.pw_name;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_name>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  cmp    $0xffffffff,%eax
  mov    %eax,%r12d
  mov    $0x400,%eax
  cmove  %eax,%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12d,%ecx
  mov    %ebp,%edi
  mov    %rax,%rdx
  lea    0x10(%rsp),%r8
  movq   $0x0,0x10(%rsp)
  call   <getpwuid_r@plt>
  test   %rax,%rax
  jne    L18
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  cmovne 0x8(%rsp),%rax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  jmp    L16
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_name(uid_t u_id) {
  int bufsize;
  if ((bufsize = sysconf(_SC_GETPW_R_SIZE_MAX)) == -1) {
    bufsize = 1024;
  }
  char *buffer = malloc(bufsize);
  struct passwd pwd, *result = NULL;
  if (getpwuid_r(u_id, &pwd, buffer, bufsize, &result) != 0 || !result) {
    return NULL;
  }
  return pwd.pw_name;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<simple_array_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int simple_array_sum(int *data, int n) {
  int sum, i;
  for (sum = 0, i = 0; i < n; i++)
    sum += data[i];
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<simple_array_sum>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L5:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
L2:
  mov    %edx,%eax
  ret
L29:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
int simple_array_sum(int *data, int n) {
  int sum, i;
  for (sum = 0, i = 0; i < n; i++)
    sum += data[i];
  return sum;
}
```