ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<curious_fraction>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  xor    %r9d,%r9d
  cmp    %esi,%edi
  jge    L109
  test   %edi,%edi
  jle    L109
  movslq %edi,%rcx
  mov    %edi,%esi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%esi
  sar    $0x22,%rcx
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%edi
  mov    %ecx,%esi
  mov    %eax,%ecx
  add    %edi,%edi
  sub    %edi,%ecx
  xor    %edi,%edi
  cmp    $0x9,%eax
  jle    L136
  mov    $0xcccccccd,%r8d
  mov    %esi,%edi
  imul   %r8,%rdi
  shr    $0x23,%rdi
  lea    (%rdi,%rdi,4),%r8d
  mov    %esi,%edi
  add    %r8d,%r8d
  sub    %r8d,%edi
L136:
  test   %edx,%edx
  jle    L28
  movslq %edx,%rsi
  mov    %edx,%r8d
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%r8d
  sar    $0x22,%rsi
  sub    %r8d,%esi
  lea    (%rsi,%rsi,4),%r8d
  mov    %esi,%r10d
  mov    %edx,%esi
  add    %r8d,%r8d
  sub    %r8d,%esi
  mov    %esi,%r9d
  cmp    $0x9,%edx
  jle    L28
  mov    %r10d,%r8d
  mov    $0xcccccccd,%r11d
  imul   %r11,%r8
  shr    $0x23,%r8
  lea    (%r8,%r8,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%r10d
  mov    %r10d,%r8d
  mov    %r8,%r10
  shl    $0x20,%r10
  or     %r10,%r9
  test   %ecx,%ecx
  je     L142
  cmp    %ecx,%r8d
  jne    L101
  test   %edi,%edi
  je     L65
  cmp    %edi,%esi
  jne    L65
  mov    %ecx,%edi
  mov    %ecx,%esi
L65:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2ss %edx,%xmm0
  mov    $0x0,%edx
  cvtsi2ss %eax,%xmm1
  xor    %eax,%eax
  cvtsi2ss %esi,%xmm2
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  divss  %xmm2,%xmm0
  ucomiss %xmm0,%xmm1
  setnp  %al
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  test   %ecx,%ecx
  jne    L101
L142:
  test   %edi,%edi
  jne    L22
L109:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L101:
  test   %edi,%edi
  je     L109
  cmp    %r9d,%edi
  jne    L109
  shr    $0x20,%r9
  mov    %ecx,%edi
  mov    %r9,%rsi
  jmp    L65
  nopl   0x0(%rax)
L22:
  cmp    %r9d,%edi
  jne    L109
  shr    $0x20,%r9
  xor    %edi,%edi
  mov    %r9,%rsi
  jmp    L65
```

assistant: ```c
int curious_fraction(int num, int den) {
  int i, j, p, curious_num = -1, curious_den = -1;
  int digits_of_num[2] = {0, 0};
  int digits_of_den[2] = {0, 0};
  float fraction, check;
  if (num == den || num >= den)
    return 0;
  i = num;
  p = 0;
  while (i > 0) {
    digits_of_num[p++] = i % 10;
    i = i / 10;
  }
  i = den;
  p = 0;
  while (i > 0) {
    digits_of_den[p++] = i % 10;
    i = i / 10;
  }
  for (i = 0; i < 2; i++) {
    for (j = 0; j < 2; j++) {
      if (digits_of_num[i] != 0 && i != j && digits_of_num[i] == digits_of_den[j]) {
        curious_num = (i == 0) ? 1 : 0;
        curious_den = (j == 0) ? 1 : 0;
      }
    }
  }
  if (curious_num == -1)
    return 0;
  fraction = (float)num / den;
  check = (float)digits_of_num[curious_num] / digits_of_den[curious_den];
  return (fraction == check);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<curious_fraction>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%ecx
  xor    %eax,%eax
  cmp    %esi,%edi
  jge    L113
  test   %edi,%edi
  jle    L113
  movslq %edi,%rsi
  sar    $0x1f,%edi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edi,%esi
  lea    (%rsi,%rsi,4),%r8d
  mov    %esi,%edi
  mov    %edx,%esi
  add    %r8d,%r8d
  sub    %r8d,%esi
  cmp    $0x9,%edx
  jle    L103
  mov    $0xcccccccd,%r8d
  mov    %edi,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r8d
  mov    %edi,%eax
  add    %r8d,%r8d
  sub    %r8d,%eax
L103:
  test   %ecx,%ecx
  jle    L104
  movslq %ecx,%rdi
  mov    %ecx,%r8d
  imul   $0x66666667,%rdi,%rdi
  sar    $0x1f,%r8d
  sar    $0x22,%rdi
  sub    %r8d,%edi
  lea    (%rdi,%rdi,4),%r8d
  mov    %edi,%r9d
  mov    %ecx,%edi
  add    %r8d,%r8d
  sub    %r8d,%edi
  cmp    $0x9,%ecx
  jle    L82
  mov    %r9d,%r8d
  mov    $0xcccccccd,%r10d
  imul   %r10,%r8
  shr    $0x23,%r8
  lea    (%r8,%r8,4),%r10d
  add    %r10d,%r10d
  sub    %r10d,%r9d
  mov    %r9d,%r8d
  test   %esi,%esi
  je     L21
  cmp    %esi,%r9d
  jne    L5
  test   %eax,%eax
  je     L11
  cmp    %eax,%edi
  jne    L11
  mov    %esi,%eax
  mov    %esi,%edi
L11:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2ss %ecx,%xmm0
  cvtsi2ss %edx,%xmm1
  mov    $0x0,%edx
  cvtsi2ss %edi,%xmm2
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  xor    %eax,%eax
  divss  %xmm2,%xmm0
  ucomiss %xmm0,%xmm1
  setnp  %al
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L113:
  ret
  nopl   0x0(%rax)
L104:
  xor    %edi,%edi
L82:
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L16
L5:
  test   %eax,%eax
  jne    L6
  ret
L21:
  mov    %r9d,%esi
L16:
  test   %eax,%eax
  je     L30
  cmp    %edi,%eax
  je     L84
L26:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L30:
  ret
  nopl   0x0(%rax)
L6:
  cmp    %edi,%eax
  jne    L26
  mov    %r8d,%edi
  mov    %esi,%eax
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L84:
  mov    %esi,%edi
  xor    %eax,%eax
  jmp    L11
```

assistant: ```c
int curious_fraction(int num, int den) {
  int i, j, p, curious_num = -1, curious_den = -1;
  int digits_of_num[2] = {0, 0};
  int digits_of_den[2] = {0, 0};
  float fraction, check;
  if (num == den || num >= den)
    return 0;
  i = num;
  p = 0;
  while (i > 0) {
    digits_of_num[p++] = i % 10;
    i = i / 10;
  }
  i = den;
  p = 0;
  while (i > 0) {
    digits_of_den[p++] = i % 10;
    i = i / 10;
  }
  for (i = 0; i < 2; i++) {
    for (j = 0; j < 2; j++) {
      if (digits_of_num[i] != 0 && i != j && digits_of_num[i] == digits_of_den[j]) {
        curious_num = (i == 0) ? 1 : 0;
        curious_den = (j == 0) ? 1 : 0;
      }
    }
  }
  if (curious_num == -1)
    return 0;
  fraction = (float)num / den;
  check = (float)digits_of_num[curious_num] / digits_of_den[curious_den];
  return (fraction == check);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sstrappendch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x2c(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xa(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sstrappend@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int sstrappendch(char str[], size_t *len, size_t size, char c) {
  const char suffix[] = {c, '\0'};
  return sstrappend(str, len, size, suffix);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sstrappendch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %cl,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%rcx
  call   <sstrappend@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sstrappendch(char str[], size_t *len, size_t size, char c) {
  const char suffix[] = {c, '\0'};
  return sstrappend(str, len, size, suffix);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sstrappendch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %cl,0x6(%rsp)
  lea    0x6(%rsp),%rcx
  movb   $0x0,0x7(%rsp)
  call   <sstrappend@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sstrappendch(char str[], size_t *len, size_t size, char c) {
  const char suffix[] = {c, '\0'};
  return sstrappend(str, len, size, suffix);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sstrappendch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %cl,0x6(%rsp)
  lea    0x6(%rsp),%rcx
  movb   $0x0,0x7(%rsp)
  call   <sstrappend@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sstrappendch(char str[], size_t *len, size_t size, char c) {
  const char suffix[] = {c, '\0'};
  return sstrappend(str, len, size, suffix);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get8@plt>
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get8@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint16_t get16(uint8_t **ppv) {
  uint16_t w;
  w = (((uint16_t)get8(ppv)) << 8) | (uint16_t)get8(ppv);
  return w;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <get8@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <get8@plt>
  shl    $0x8,%ebx
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint16_t get16(uint8_t **ppv) {
  uint16_t w;
  w = (((uint16_t)get8(ppv)) << 8) | (uint16_t)get8(ppv);
  return w;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <get8@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <get8@plt>
  shl    $0x8,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint16_t get16(uint8_t **ppv) {
  uint16_t w;
  w = (((uint16_t)get8(ppv)) << 8) | (uint16_t)get8(ppv);
  return w;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <get8@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <get8@plt>
  shl    $0x8,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint16_t get16(uint8_t **ppv) {
  uint16_t w;
  w = (((uint16_t)get8(ppv)) << 8) | (uint16_t)get8(ppv);
  return w;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L65
  mov    -0x4(%rbp),%eax
  jmp    L55
L65:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jge    L24
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L15
  mov    $0xffffffff,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search(int *array, int start, int end, int key) {
  int mid;
  mid = start + (end - start) / 2;
  while (start <= end) {
    if (array[mid] == key) {
      return mid;
    } else if (array[mid] > key) {
      end = mid - 1;
      mid = start + (end - start) / 2;
    } else if (array[mid] < key) {
      start = mid + 1;
      mid = start + (end - start) / 2;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<binary_search>:
  endbr64
  mov    %edx,%r8d
  sub    %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %esi,%eax
  cmp    %esi,%r8d
  jge    L12
  mov    $0xffffffff,%eax
L14:
  ret
L51:
  jge    L58
  lea    0x1(%rax),%esi
  mov    %r8d,%edx
  sub    %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %esi,%eax
L58:
  cmp    %r8d,%esi
  jg     L37
L12:
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %ecx,%edx
  je     L14
  jle    L51
  lea    -0x1(%rax),%r8d
  mov    %r8d,%edx
  sub    %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %esi,%eax
  jmp    L58
L37:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int binary_search(int *array, int start, int end, int key) {
  int mid;
  mid = start + (end - start) / 2;
  while (start <= end) {
    if (array[mid] == key) {
      return mid;
    } else if (array[mid] > key) {
      end = mid - 1;
      mid = start + (end - start) / 2;
    } else if (array[mid] < key) {
      start = mid + 1;
      mid = start + (end - start) / 2;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binary_search>:
  endbr64
  mov    %ecx,%r8d
L31:
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
L10:
  cmp    %esi,%edx
  jl     L11
L46:
  movslq %eax,%rcx
  cmp    %r8d,(%rdi,%rcx,4)
  je     L20
  jle    L2
  lea    -0x1(%rax),%edx
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
  cmp    %esi,%edx
  jge    L46
L11:
  mov    $0xffffffff,%eax
L20:
  ret
  nopl   0x0(%rax)
L2:
  jge    L10
  lea    0x1(%rax),%esi
  jmp    L31
```

assistant: ```c
int binary_search(int *array, int start, int end, int key) {
  int mid;
  mid = start + (end - start) / 2;
  while (start <= end) {
    if (array[mid] == key) {
      return mid;
    } else if (array[mid] > key) {
      end = mid - 1;
      mid = start + (end - start) / 2;
    } else if (array[mid] < key) {
      start = mid + 1;
      mid = start + (end - start) / 2;
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binary_search>:
  endbr64
  mov    %ecx,%r8d
L34:
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
L56:
  cmp    %esi,%edx
  jl     L53
L3:
  movslq %eax,%rcx
  cmp    %r8d,(%rdi,%rcx,4)
  je     L31
  jle    L59
  lea    -0x1(%rax),%edx
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
  cmp    %esi,%edx
  jge    L3
L53:
  mov    $0xffffffff,%eax
L31:
  ret
  nopl   0x0(%rax)
L59:
  jge    L56
  lea    0x1(%rax),%esi
  jmp    L34
```

assistant: ```c
int binary_search(int *array, int start, int end, int key) {
  int mid;
  mid = start + (end - start) / 2;
  while (start <= end) {
    if (array[mid] == key) {
      return mid;
    } else if (array[mid] > key) {
      end = mid - 1;
      mid = start + (end - start) / 2;
    } else if (array[mid] < key) {
      start = mid + 1;
      mid = start + (end - start) / 2;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<brot_calc_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  mov    %edi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L28:
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm2
  mulss  %xmm0,%xmm2
  subss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x10(%rbp),%xmm0
  addss  %xmm0,%xmm0
  mulss  -0xc(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L24:
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  D3(%rip),%xmm0
  comiss %xmm1,%xmm0
  jbe    L5
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L28
L5:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x40]}

assistant: ```c
int brot_calc_escape(float xPos, float yPos, float limit, int depth) {
  float x = 0;
  float y = 0;
  float temp = 0;
  int iteration = 0;
  while (((x * x + y * y) < 4) && (iteration < depth)) {
    temp = x * x - y * y + xPos;
    y = 2 * x * y + yPos;
    x = temp;
    iteration++;
  }
  return iteration;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<brot_calc_escape>:
  endbr64
  test   %edi,%edi
  jle    L18
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm5
  movaps %xmm2,%xmm6
  movaps %xmm2,%xmm3
  movss  D4(%rip),%xmm7
L16:
  movaps %xmm5,%xmm4
  subss  %xmm6,%xmm3
  movaps %xmm3,%xmm5
  addss  %xmm0,%xmm5
  addss  %xmm4,%xmm4
  mulss  %xmm4,%xmm2
  addss  %xmm1,%xmm2
  add    $0x1,%eax
  movaps %xmm5,%xmm3
  mulss  %xmm5,%xmm3
  movaps %xmm2,%xmm6
  mulss  %xmm2,%xmm6
  movaps %xmm3,%xmm4
  addss  %xmm6,%xmm4
  comiss %xmm4,%xmm7
  jbe    L2
  cmp    %eax,%edi
  jg     L16
  ret
L18:
  mov    $0x0,%eax
L2:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x40]}

assistant: ```c
int brot_calc_escape(float xPos, float yPos, float limit, int depth) {
  float x = 0;
  float y = 0;
  float temp = 0;
  int iteration = 0;
  while (((x * x + y * y) < 4) && (iteration < depth)) {
    temp = x * x - y * y + xPos;
    y = 2 * x * y + yPos;
    x = temp;
    iteration++;
  }
  return iteration;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<brot_calc_escape>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L8
  pxor   %xmm2,%xmm2
  movss  D6(%rip),%xmm7
  movaps %xmm2,%xmm5
  movaps %xmm2,%xmm6
  movaps %xmm2,%xmm3
  jmp    L28
  nopl   0x0(%rax)
L23:
  cmp    %eax,%edi
  jle    L30
L28:
  movaps %xmm5,%xmm4
  subss  %xmm6,%xmm3
  add    $0x1,%eax
  addss  %xmm4,%xmm4
  movaps %xmm3,%xmm5
  mulss  %xmm4,%xmm2
  addss  %xmm0,%xmm5
  movaps %xmm5,%xmm3
  mulss  %xmm5,%xmm3
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm6
  mulss  %xmm2,%xmm6
  movaps %xmm3,%xmm4
  addss  %xmm6,%xmm4
  comiss %xmm4,%xmm7
  ja     L23
L8:
  ret
  nopl   0x0(%rax)
L30:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x40]}

assistant: ```c
int brot_calc_escape(float xPos, float yPos, float limit, int depth) {
  float x = 0;
  float y = 0;
  float temp = 0;
  int iteration = 0;
  while (((x * x + y * y) < 4) && (iteration < depth)) {
    temp = x * x - y * y + xPos;
    y = 2 * x * y + yPos;
    x = temp;
    iteration++;
  }
  return iteration;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<brot_calc_escape>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L0
  pxor   %xmm2,%xmm2
  movss  D7(%rip),%xmm7
  movaps %xmm2,%xmm5
  movaps %xmm2,%xmm6
  movaps %xmm2,%xmm3
  jmp    L32
  nopl   0x0(%rax)
L9:
  cmp    %eax,%edi
  jle    L7
L32:
  movaps %xmm5,%xmm4
  subss  %xmm6,%xmm3
  add    $0x1,%eax
  addss  %xmm4,%xmm4
  movaps %xmm3,%xmm5
  mulss  %xmm4,%xmm2
  addss  %xmm0,%xmm5
  movaps %xmm5,%xmm3
  mulss  %xmm5,%xmm3
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm6
  mulss  %xmm2,%xmm6
  movaps %xmm3,%xmm4
  addss  %xmm6,%xmm4
  comiss %xmm4,%xmm7
  ja     L9
L0:
  ret
  nopl   0x0(%rax)
L7:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x40]}

assistant: ```c
int brot_calc_escape(float xPos, float yPos, float limit, int depth) {
  float x = 0;
  float y = 0;
  float temp = 0;
  int iteration = 0;
  while (((x * x + y * y) < 4) && (iteration < depth)) {
    temp = x * x - y * y + xPos;
    y = 2 * x * y + yPos;
    x = temp;
    iteration++;
  }
  return iteration;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_chld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
L17:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L17
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void sig_chld(int signo) {
  pid_t pid;
  int status;
  while ((pid = waitpid(-1, &status, WNOHANG)) > 0)
    ;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sig_chld>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rbx
L13:
  lea    0x4(%rsp),%rsi
  mov    (%rbx),%edx
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %eax,%eax
  jg     L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sig_chld(int signo) {
  pid_t pid;
  int status;
  while ((pid = waitpid(-1, &status, WNOHANG)) > 0)
    ;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sig_chld>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D5(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp),%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %eax,%eax
  jg     L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sig_chld(int signo) {
  pid_t pid;
  int status;
  while ((pid = waitpid(-1, &status, WNOHANG)) > 0)
    ;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<sig_chld>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D0(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp),%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %eax,%eax
  jg     L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sig_chld(int signo) {
  pid_t pid;
  int status;
  while ((pid = waitpid(-1, &status, WNOHANG)) > 0)
    ;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cutItemToFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x220(%rbp)
  mov    %al,-0x21c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsbl -0x21c(%rbp),%edx
  mov    -0x220(%rbp),%ecx
  lea    -0x210(%rbp),%rsi
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <cutItem@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
float cutItemToFloat(char *in, char sep, int num) {
  char tmp[512];
  cutItem(in, tmp, sep, num);
  return atof(tmp);
}
```