ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<soundex>:
  endbr64
  movabs $0x400000002,%rsi
  push   %r12
  movabs $0x200000000,%rdx
  movabs $0x300000002,%rcx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  movabs $0x100000000,%rax
  mov    %rsi,0x28(%rsp)
  lea    0x73(%rsp),%rdi
  movabs $0x500000005,%rsi
  mov    %rsi,0x30(%rsp)
  movabs $0x600000002,%rsi
  mov    %rsi,0x40(%rsp)
  lea    D8(%rip),%rsi
  mov    %rcx,0x8(%rsp)
  movq   $0x2,0x18(%rsp)
  mov    %rdx,0x20(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %rcx,0x48(%rsp)
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  mov    %rdx,0x60(%rsp)
  call   <strcpy@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L100
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L76:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L13
L100:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L76
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L13
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    $0x1,%r12d
  mov    %al,0x73(%rsp)
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  mov    (%rsp,%rax,4),%ebp
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L62:
  add    $0x1,%rbx
  cmp    $0x4,%r12d
  je     L13
L47:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L13
  call   <isalpha@plt>
  test   %rax,%rax
  je     L62
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  cmp    %ebp,%eax
  je     L62
  xor    %ebp,%ebp
  test   %eax,%eax
  je     L62
  movslq %r12d,%rdx
  lea    0x30(%rax),%ecx
  add    $0x1,%r12d
  mov    %eax,%ebp
  mov    %cl,0x73(%rsp,%rdx,1)
  add    $0x1,%rbx
  cmp    $0x4,%r12d
  jne    L47
  nopl   0x0(%rax,%rax,1)
L13:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: Z000

assistant: ```c
char *soundex(char *in) {
  int code[] = {0, 1, 2, 3, 0, 1, 2, 0, 0, 2, 2, 4, 5, 5, 0, 1, 2, 6, 2, 3, 0, 1, 0, 2, 0, 2};
  char key[5], ch;
  int last, count;
  strcpy(key, "Z000");
  while (*in != '\0' && !isalpha(*in))
    ++in;
  if (*in == '\0')
    return key;
  key[0] = toupper(*in);
  last = code[key[0] - 'A'];
  ++in;
  for (count = 1; count < 4 && *in != '\0'; ++in) {
    if (isalpha(*in)) {
      ch = tolower(*in);
      if (last != code[ch - 'a']) {
        last = code[ch - 'a'];
        if (last != 0)
          key[count++] = '0' + last;
      }
    }
  }
  return key;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x2,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L8
L11:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L8:
  cmpl   $0x5d,-0x1c(%rbp)
  jle    L11
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string

tool: D16: %llu, 

tool: D5: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,

assistant: ```c
int main() {
  long long unsigned int a = 2, b = 1, c;
  int i;
  for (i = 1; i <= 93; i++) {
    c = a + b;
    printf("%llu, ", a);
    a = b;
    b = c;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5d,%ebp
  mov    $0x1,%ebx
  mov    $0x2,%esi
  lea    D1(%rip),%r13
L5:
  mov    %rbx,%r12
  add    %rsi,%rbx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  sub    $0x1,%ebp
  jne    L5
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D1: %llu, 

tool: D3: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,

assistant: ```c
int main() {
  long long unsigned int a = 2, b = 1, c;
  int i;
  for (i = 1; i <= 93; i++) {
    c = a + b;
    printf("%llu, ", a);
    a = b;
    b = c;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2,%esi
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  mov    $0x5d,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    %rbx,%r12
  mov    %r13,%rdi
  xor    %eax,%eax
  add    %rsi,%rbx
  call   <printf@plt>
  mov    %r12,%rsi
  sub    $0x1,%ebp
  jne    L7
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D5: %llu, 

tool: D0: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,

assistant: ```c
int main() {
  long long unsigned int a = 2, b = 1, c;
  int i;
  for (i = 1; i <= 93; i++) {
    c = a + b;
    printf("%llu, ", a);
    a = b;
    b = c;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2,%esi
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  mov    $0x5d,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    %rbx,%r12
  mov    %r13,%rdi
  xor    %eax,%eax
  add    %rsi,%rbx
  call   <printf@plt>
  mov    %r12,%rsi
  sub    $0x1,%ebp
  jne    L6
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D9: %llu, 

tool: D5: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,

assistant: ```c
int main() {
  long long unsigned int a = 2, b = 1, c;
  int i;
  for (i = 1; i <= 93; i++) {
    c = a + b;
    printf("%llu, ", a);
    a = b;
    b = c;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127,");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Data_Start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  jmp    L11
L4:
  nop
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D30
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D27
type_guessed: string

tool: D3: .ctors,"aw",@progbits

tool: D18: .section

tool: D4: 8

tool: D30: .align

tool: D25: %s

tool: D27: .quad

assistant: ```c
void Data_Start(char *initializer_fct) {
  if (initializer_fct == NULL)
    return;
  Inst_Printf(".section", ".ctors,\"aw\",@progbits");
  Inst_Printf(".align", "8");
  Inst_Printf(".quad", "%s", initializer_fct);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Data_Start>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    D10(%rip),%rsi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  mov    %rbx,%rdx
  lea    D57(%rip),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  pop    %rbx
  ret
L7:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D56
type_guessed: string
name: unpack_data
arguments: data_label: D57
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string

tool: D2: .ctors,"aw",@progbits

tool: D16: .section

tool: D10: 8

tool: D56: .align

tool: D57: %s

tool: D17: .quad

assistant: ```c
void Data_Start(char *initializer_fct) {
  if (initializer_fct == NULL)
    return;
  Inst_Printf(".section", ".ctors,\"aw\",@progbits");
  Inst_Printf(".align", "8");
  Inst_Printf(".quad", "%s", initializer_fct);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Data_Start>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %r12
  lea    D17(%rip),%rsi
  mov    %rdi,%r12
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D27(%rip),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <Inst_Printf@plt>
  mov    %r12,%rdx
  lea    D58(%rip),%rsi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  pop    %r12
  jmp    1050 <Inst_Printf@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: read_data
arguments: label: D17
type_guessed: string
name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D27
type_guessed: string
name: read_data
arguments: label: D31
type_guessed: string
name: read_data
arguments: label: D58
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string

tool: D17: .ctors,"aw",@progbits

tool: D25: .section

tool: D27: 8

tool: D31: .align

tool: D58: %s

tool: D0: .quad

assistant: ```c
void Data_Start(char *initializer_fct) {
  if (initializer_fct == NULL)
    return;
  Inst_Printf(".section", ".ctors,\"aw\",@progbits");
  Inst_Printf(".align", "8");
  Inst_Printf(".quad", "%s", initializer_fct);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Data_Start>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %r12
  lea    D16(%rip),%rsi
  mov    %rdi,%r12
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D49(%rip),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <Inst_Printf@plt>
  mov    %r12,%rdx
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  pop    %r12
  jmp    1050 <Inst_Printf@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D40
datatype: string
name: read_data
arguments: label: D49
datatype: string
name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D42
datatype: string

tool: D16: .ctors,"aw",@progbits

tool: D40: .section

tool: D49: 8

tool: D0: .align

tool: D8: %s

tool: D42: .quad

assistant: ```c
void Data_Start(char *initializer_fct) {
  if (initializer_fct == NULL)
    return;
  Inst_Printf(".section", ".ctors,\"aw\",@progbits");
  Inst_Printf(".align", "8");
  Inst_Printf(".quad", "%s", initializer_fct);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x24(%rbp)
  je     L60
  mov    $0x0,%eax
  call   <_usage@plt>
  jmp    L24
L60:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  cmpq   $0x0,-0x10(%rbp)
  jns    L18
L0:
  mov    $0x0,%eax
  call   <_usage@plt>
  jmp    L24
L18:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_sleep@plt>
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long time;
  char *p;
  if (argc != 2)
    return _usage();
  time = strtol(argv[1], &p, 10);
  if (argv[1][0] == '\0' || *p != '\0' || time < 0)
    return _usage();
  return _sleep(time);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L10
  call   <_usage@plt>
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x10,%rsp
  pop    %rbx
  ret
L10:
  mov    %rsi,%rbx
  mov    %rsp,%rsi
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    0x8(%rbx),%rdx
  cmpb   $0x0,(%rdx)
  je     L50
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L50
  test   %rax,%rax
  js     L50
  mov    %rax,%rdi
  call   <_sleep@plt>
  jmp    L18
L50:
  mov    $0x0,%eax
  call   <_usage@plt>
  jmp    L18
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  long time;
  char *p;
  if (argc != 2)
    return _usage();
  time = strtol(argv[1], &p, 10);
  if (argv[1][0] == '\0' || *p != '\0' || time < 0)
    return _usage();
  return _sleep(time);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L45
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  jmp    10a0 <_usage@plt>
L45:
  mov    %rsi,%rbx
  mov    $0xa,%edx
  mov    %rsp,%rsi
  mov    0x8(%rbx),%rdi
  call   <strtol@plt>
  mov    0x8(%rbx),%rdx
  cmpb   $0x0,(%rdx)
  je     L66
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L66
  test   %rax,%rax
  js     L66
  mov    %rax,%rdi
  call   <_sleep@plt>
  jmp    L3
L66:
  xor    %eax,%eax
  call   <_usage@plt>
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  long time;
  char *p;
  if (argc != 2)
    return _usage();
  time = strtol(argv[1], &p, 10);
  if (argv[1][0] == '\0' || *p != '\0' || time < 0)
    return _usage();
  return _sleep(time);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L28
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  jmp    10a0 <_usage@plt>
L28:
  mov    %rsi,%rbx
  mov    $0xa,%edx
  mov    %rsp,%rsi
  mov    0x8(%rbx),%rdi
  call   <strtol@plt>
  mov    0x8(%rbx),%rdx
  cmpb   $0x0,(%rdx)
  je     L44
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L44
  test   %rax,%rax
  js     L44
  mov    %rax,%rdi
  call   <_sleep@plt>
  jmp    L56
L44:
  xor    %eax,%eax
  call   <_usage@plt>
L56:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x10,%rsp
  pop    %rbx
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  long time;
  char *p;
  if (argc != 2)
    return _usage();
  time = strtol(argv[1], &p, 10);
  if (argv[1][0] == '\0' || *p != '\0' || time < 0)
    return _usage();
  return _sleep(time);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <run_xor@plt>
  mov    $0x22,%esi
  mov    $0x64,%edi
  call   <run_xor@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_xor() {
  run_xor(0, 1);
  run_xor(100, 34);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_xor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <run_xor@plt>
  mov    $0x22,%esi
  mov    $0x64,%edi
  call   <run_xor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_xor() {
  run_xor(0, 1);
  run_xor(100, 34);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_xor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <run_xor@plt>
  mov    $0x22,%esi
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1050 <run_xor@plt>
```

assistant: ```c
void test_xor() {
  run_xor(0, 1);
  run_xor(100, 34);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_xor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <run_xor@plt>
  mov    $0x22,%esi
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1050 <run_xor@plt>
```

assistant: ```c
void test_xor() {
  run_xor(0, 1);
  run_xor(100, 34);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fd_set_cloexec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  or     %eax,-0x4(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  nop
  leave
  ret
```

assistant: ```c
void fd_set_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fd_set_cloexec>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    D10(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fd_set_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fd_set_cloexec>:
  endbr64
  mov    D21(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  mov    D4(%rip),%rdx
  mov    %ebp,%edi
  pop    %rbp
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D29(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1050 <fcntl@plt>
```

assistant: ```c
void fd_set_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: What is the c source code of the assembly code below?

```asm
<fd_set_cloexec>:
  endbr64
  mov    D24(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  mov    D20(%rip),%rdx
  mov    %ebp,%edi
  pop    %rbp
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1050 <fcntl@plt>
```

assistant: ```c
void fd_set_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L18:
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x2,-0xc(%rbp)
  jle    L18
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: D5: cos

tool: D6: # c::cephes::%s


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "cos");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D21(%rip),%r13
  lea    D13(%rip),%r12
  lea    D7(%rip),%rbp
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D21: cos

tool: D13: # c::cephes::%s


tool: D7: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "cos");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```