ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<mygethostbyname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L22
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L22:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L13
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L13:
  movl   $0xffffffff,-0x4(%rbp)
L27:
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <doQuery@plt>
  leave
  ret
```

assistant: ```c
int mygethostbyname(char *name, void *addr, int family) {
  int type;
  if (family == AF_INET)
    type = T_A;
  else if (family == AF_INET6)
    type = T_AAAA;
  else
    type = -1;
  return doQuery(name, type, NULL, addr, family);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mygethostbyname>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  mov    %edx,%r8d
  mov    D9(%rip),%rax
  cmp    %edx,(%rax)
  je     L4
  mov    $0xffffffff,%esi
  mov    D14(%rip),%rax
  cmp    %edx,(%rax)
  je     L15
L36:
  mov    $0x0,%edx
  call   <doQuery@plt>
  add    $0x8,%rsp
  ret
L4:
  mov    D20(%rip),%rax
  mov    (%rax),%esi
  jmp    L36
L15:
  mov    D27(%rip),%rax
  mov    (%rax),%esi
  jmp    L36
```

assistant: ```c
int mygethostbyname(char *name, void *addr, int family) {
  int type;
  if (family == AF_INET)
    type = T_A;
  else if (family == AF_INET6)
    type = T_AAAA;
  else
    type = -1;
  return doQuery(name, type, NULL, addr, family);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mygethostbyname>:
  endbr64
  mov    D6(%rip),%rax
  mov    %rsi,%rcx
  mov    %edx,%r8d
  cmp    %edx,(%rax)
  je     L3
  mov    D26(%rip),%rax
  mov    $0xffffffff,%esi
  cmp    %edx,(%rax)
  je     L19
  xor    %edx,%edx
  jmp    1050 <doQuery@plt>
  nopl   0x0(%rax)
L19:
  mov    D4(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  jmp    1050 <doQuery@plt>
L3:
  mov    D25(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  jmp    1050 <doQuery@plt>
```

assistant: ```c
int mygethostbyname(char *name, void *addr, int family) {
  int type;
  if (family == AF_INET)
    type = T_A;
  else if (family == AF_INET6)
    type = T_AAAA;
  else
    type = -1;
  return doQuery(name, type, NULL, addr, family);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mygethostbyname>:
  endbr64
  mov    D8(%rip),%rax
  mov    %rsi,%rcx
  mov    %edx,%r8d
  cmp    %edx,(%rax)
  je     L13
  mov    D21(%rip),%rax
  mov    $0xffffffff,%esi
  cmp    %edx,(%rax)
  je     L10
  xor    %edx,%edx
  jmp    1050 <doQuery@plt>
  nopl   0x0(%rax)
L10:
  mov    D22(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  jmp    1050 <doQuery@plt>
L13:
  mov    D35(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  jmp    1050 <doQuery@plt>
```

assistant: ```c
int mygethostbyname(char *name, void *addr, int family) {
  int type;
  if (family == AF_INET)
    type = T_A;
  else if (family == AF_INET6)
    type = T_AAAA;
  else
    type = -1;
  return doQuery(name, type, NULL, addr, family);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_puiss10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L27
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <ft_puiss10>
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
L27:
  cmpl   $0x1,-0x14(%rbp)
  jne    L6
  mov    $0xa,%eax
  jmp    L11
L6:
  mov    -0x4(%rbp),%eax
L11:
  leave
  ret
```

assistant: ```c
int ft_puiss10(int y) {
  int res;
  if (y > 1)
    res = 10 * (ft_puiss10(y - 1));
  if (y == 1)
    return (10);
  return (res);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_puiss10>:
  endbr64
  cmp    $0x1,%edi
  jg     L3
  mov    $0x0,%eax
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
L3:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <ft_puiss10>
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ft_puiss10(int y) {
  int res;
  if (y > 1)
    res = 10 * (ft_puiss10(y - 1));
  if (y == 1)
    return (10);
  return (res);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_puiss10>:
  endbr64
  cmp    $0x1,%edi
  jg     L49
  je     L45
L20:
  ret
  nopl   0x0(%rax)
L49:
  mov    $0x64,%eax
  cmp    $0x2,%edi
  je     L20
  cmp    $0x3,%edi
  jne    L30
  mov    $0x3e8,%eax
  ret
  nopl   (%rax)
L30:
  mov    $0x1,%eax
L47:
  lea    -0x3(%rdi),%edx
  imul   $0x3e8,%eax,%edi
  cmp    $0x1,%edx
  jne    L67
L45:
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L67:
  cmp    $0x2,%edx
  jne    L22
  imul   $0x186a0,%eax,%eax
  ret
  nopl   0x0(%rax)
L22:
  cmp    $0x3,%edx
  jne    L31
  imul   $0xf4240,%eax,%eax
  ret
L31:
  mov    %edi,%eax
  mov    %edx,%edi
  jmp    L47
```

assistant: ```c
int ft_puiss10(int y) {
  int res;
  if (y > 1)
    res = 10 * (ft_puiss10(y - 1));
  if (y == 1)
    return (10);
  return (res);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_puiss10>:
  endbr64
  cmp    $0x1,%edi
  jg     L0
  je     L34
L26:
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x64,%eax
  cmp    $0x2,%edi
  je     L26
  cmp    $0x3,%edi
  jne    L21
  mov    $0x3e8,%eax
  ret
  nopl   (%rax)
L21:
  mov    $0x1,%eax
L49:
  lea    -0x3(%rdi),%edx
  imul   $0x3e8,%eax,%edi
  cmp    $0x1,%edx
  jne    L18
L34:
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L18:
  cmp    $0x2,%edx
  jne    L58
  imul   $0x186a0,%eax,%eax
  ret
  nopl   0x0(%rax)
L58:
  cmp    $0x3,%edx
  jne    L22
  imul   $0xf4240,%eax,%eax
  ret
L22:
  mov    %edi,%eax
  mov    %edx,%edi
  jmp    L49
```

assistant: ```c
int ft_puiss10(int y) {
  int res;
  if (y > 1)
    res = 10 * (ft_puiss10(y - 1));
  if (y == 1)
    return (10);
  return (res);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get64_H>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x3f,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L13
L8:
  mov    $0x1,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int get64_H(uint64_t x) {
  if (((x >> 63) & 0x01) != 0x01)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get64_H>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int get64_H(uint64_t x) {
  if (((x >> 63) & 0x01) != 0x01)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get64_H>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int get64_H(uint64_t x) {
  if (((x >> 63) & 0x01) != 0x01)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get64_H>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int get64_H(uint64_t x) {
  if (((x >> 63) & 0x01) != 0x01)
    return 0;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rdx,%r15
  mov    %rdx,0x18(%rsp)
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L8
  mov    %rdi,%rbx
  mov    %rsi,%r14
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,0x8(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rax,0x10(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  mov    $0x0,%ebp
  jmp    L78
L41:
  add    $0x1,%rbp
  mov    0x8(%rsp),%rax
  lea    (%rbx,%rax,1),%rdi
L78:
  mov    %r14,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L41
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rax
  mov    0x10(%rsp),%rdx
  sub    %rdx,%rax
  imul   %rbp,%rax
  cmp    %rdx,%rcx
  jb     L73
  cmp    %r12,%rax
  ja     L39
  test   %rax,%rax
  js     L39
L126:
  lea    0x1(%r12),%rcx
  mov    %rcx,0x28(%rsp)
  mov    %rcx,%rdi
  sub    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  mov    %rax,%r15
  mov    0x20(%rsp),%r13
  jmp    L79
L73:
  test   %rax,%rax
  jle    L126
  jmp    L39
L1:
  mov    %rax,%r12
  sub    %r13,%r12
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  add    %r12,%r15
  mov    0x10(%rsp),%r13
  mov    %r13,%rdx
  mov    0x18(%rsp),%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  add    %r13,%r15
  mov    0x8(%rsp),%rax
  lea    0x0(%rbp,%rax,1),%r13
L79:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L1
  mov    %r13,%rax
  sub    0x20(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %rax,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
L39:
  mov    %rbx,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    $0x0,%ebx
  jmp    L39
```

assistant: ```c
char *str_replace(const char *src, const char *from, const char *to) {
  if (src == NULL || from == NULL || to == NULL)
    return NULL;
  const char *sp;
  const char *mp;
  char *dp;
  size_t from_len = strlen(from);
  size_t to_len = strlen(to);
  size_t src_len = strlen(src);
  size_t count = 0;
  sp = src;
  while (1) {
    mp = strstr(sp, from);
    if (mp == NULL)
      break;
    count++;
    sp = mp + from_len;
  }
  size_t len = src_len;
  long int sub = (from_len - to_len) * count;
  if (from_len >= to_len) {
    if (sub > len || sub < 0)
      return NULL;
  } else {
    if ((len - sub) < 0 || sub > 0)
      return NULL;
  }
  size_t actual_size = (len - sub) + 1;
  char *dest = malloc(actual_size);
  if (dest != NULL) {
    sp = src;
    dp = dest;
    while (1) {
      mp = strstr(sp, from);
      if (mp == NULL)
        break;
      memcpy(dp, sp, mp - sp);
      dp += mp - sp;
      memcpy(dp, to, to_len);
      dp += to_len;
      sp = mp + from_len;
    }
    size_t k = src_len - (sp - src) + 1;
    memcpy(dp, sp, k);
  }
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  mov    %rdi,0x18(%rsp)
  sete   %dl
  or     %dl,%al
  jne    L112
  test   %rdi,%rdi
  je     L112
  mov    %rsi,%rdi
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    0x18(%rsp),%rbp
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  xor    %ebp,%ebp
  mov    %rax,%r15
  jmp    L80
  nopw   0x0(%rax,%rax,1)
L85:
  add    $0x1,%rbp
  lea    (%rax,%r12,1),%rdi
L80:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L85
  mov    %r12,%rax
  sub    %r13,%rax
  imul   %rbp,%rax
  cmp    %r13,%r12
  jae    L108
  test   %rax,%rax
  jg     L112
L89:
  lea    0x1(%r15),%rsi
  mov    %rsi,%rdi
  mov    %rsi,0x28(%rsp)
  sub    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,0x20(%rsp)
  test   %rax,%rax
  je     L112
  mov    0x18(%rsp),%r15
  mov    %rax,%rbp
  jmp    L30
  nopl   (%rax)
L84:
  mov    %rax,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  sub    %r15,%rdx
  mov    %rdx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdx
  mov    %r14,%rsi
  add    %rdx,%rbp
  mov    %r13,%rdx
  mov    %rbp,%rdi
  add    %r13,%rbp
  call   <memcpy@plt>
  mov    0x10(%rsp),%rcx
  lea    (%rcx,%r12,1),%r15
L30:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L84
  mov    0x28(%rsp),%rdx
  mov    %r15,%rax
  sub    0x18(%rsp),%rax
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %rax,%rdx
  call   <memcpy@plt>
L47:
  mov    0x20(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L108:
  cmp    %r15,%rax
  ja     L112
  test   %rax,%rax
  jns    L89
  xchg   %ax,%ax
L112:
  movq   $0x0,0x20(%rsp)
  jmp    L47
```

assistant: ```c
char *str_replace(const char *src, const char *from, const char *to) {
  if (src == NULL || from == NULL || to == NULL)
    return NULL;
  const char *sp;
  const char *mp;
  char *dp;
  size_t from_len = strlen(from);
  size_t to_len = strlen(to);
  size_t src_len = strlen(src);
  size_t count = 0;
  sp = src;
  while (1) {
    mp = strstr(sp, from);
    if (mp == NULL)
      break;
    count++;
    sp = mp + from_len;
  }
  size_t len = src_len;
  long int sub = (from_len - to_len) * count;
  if (from_len >= to_len) {
    if (sub > len || sub < 0)
      return NULL;
  } else {
    if ((len - sub) < 0 || sub > 0)
      return NULL;
  }
  size_t actual_size = (len - sub) + 1;
  char *dest = malloc(actual_size);
  if (dest != NULL) {
    sp = src;
    dp = dest;
    while (1) {
      mp = strstr(sp, from);
      if (mp == NULL)
        break;
      memcpy(dp, sp, mp - sp);
      dp += mp - sp;
      memcpy(dp, to, to_len);
      dp += to_len;
      sp = mp + from_len;
    }
    size_t k = src_len - (sp - src) + 1;
    memcpy(dp, sp, k);
  }
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  mov    %rdi,0x18(%rsp)
  sete   %dl
  or     %dl,%al
  jne    L9
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %rbp,%rdi
  xor    %ebp,%ebp
  mov    %rax,%r15
  jmp    L119
  nopl   (%rax)
L13:
  add    $0x1,%rbp
  lea    (%rax,%r12,1),%rdi
L119:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rax
  sub    %r13,%rax
  imul   %rbp,%rax
  cmp    %r13,%r12
  jae    L60
  test   %rax,%rax
  jg     L9
L67:
  lea    0x1(%r15),%rsi
  mov    %rsi,%rdi
  mov    %rsi,0x28(%rsp)
  sub    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,0x20(%rsp)
  test   %rax,%rax
  je     L9
  mov    0x18(%rsp),%r15
  mov    %rax,%rbp
  jmp    L46
  nopl   (%rax)
L22:
  mov    %rax,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  sub    %r15,%rdx
  mov    %rdx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdx
  mov    %r14,%rsi
  add    %rdx,%rbp
  mov    %r13,%rdx
  mov    %rbp,%rdi
  add    %r13,%rbp
  call   <memcpy@plt>
  mov    0x10(%rsp),%rcx
  lea    (%rcx,%r12,1),%r15
L46:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L22
  mov    0x28(%rsp),%rdx
  mov    %r15,%rax
  sub    0x18(%rsp),%rax
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %rax,%rdx
  call   <memcpy@plt>
L54:
  mov    0x20(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L60:
  cmp    %r15,%rax
  ja     L9
  test   %rax,%rax
  jns    L67
  cs nopw 0x0(%rax,%rax,1)
L9:
  movq   $0x0,0x20(%rsp)
  jmp    L54
```

assistant: ```c
char *str_replace(const char *src, const char *from, const char *to) {
  if (src == NULL || from == NULL || to == NULL)
    return NULL;
  const char *sp;
  const char *mp;
  char *dp;
  size_t from_len = strlen(from);
  size_t to_len = strlen(to);
  size_t src_len = strlen(src);
  size_t count = 0;
  sp = src;
  while (1) {
    mp = strstr(sp, from);
    if (mp == NULL)
      break;
    count++;
    sp = mp + from_len;
  }
  size_t len = src_len;
  long int sub = (from_len - to_len) * count;
  if (from_len >= to_len) {
    if (sub > len || sub < 0)
      return NULL;
  } else {
    if ((len - sub) < 0 || sub > 0)
      return NULL;
  }
  size_t actual_size = (len - sub) + 1;
  char *dest = malloc(actual_size);
  if (dest != NULL) {
    sp = src;
    dp = dest;
    while (1) {
      mp = strstr(sp, from);
      if (mp == NULL)
        break;
      memcpy(dp, sp, mp - sp);
      dp += mp - sp;
      memcpy(dp, to, to_len);
      dp += to_len;
      sp = mp + from_len;
    }
    size_t k = src_len - (sp - src) + 1;
    memcpy(dp, sp, k);
  }
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cf_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cf_init(int *table, int n) {
  int i;
  for (i = 0; i < n; i++)
    table[i] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cf_init>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L7:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L7
L13:
  ret
```

assistant: ```c
void cf_init(int *table, int n) {
  int i;
  for (i = 0; i < n; i++)
    table[i] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cf_init>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void cf_init(int *table, int n) {
  int i;
  for (i = 0; i < n; i++)
    table[i] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cf_init>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void cf_init(int *table, int n) {
  int i;
  for (i = 0; i < n; i++)
    table[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bitmap_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L25
  cmpl   $0x20,-0x1c(%rbp)
  ja     L25
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L20
L25:
  mov    -0x1c(%rbp),%eax
  add    $0x3f,%rax
  shr    $0x6,%rax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
L20:
  nop
  leave
  ret
```

assistant: ```c
void bitmap_zero(unsigned long *dst, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    *dst = 0UL;
  else {
    unsigned int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memset(dst, 0, len);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_zero>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L9
  test   %rax,%rax
  je     L9
  movq   $0x0,0x0(%rbp)
  jmp    L10
L9:
  mov    %ebx,%edx
  add    $0x3f,%rdx
  shr    $0x6,%rdx
  shl    $0x3,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bitmap_zero(unsigned long *dst, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    *dst = 0UL;
  else {
    unsigned int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memset(dst, 0, len);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_zero>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L5
  test   %rax,%rax
  je     L5
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L5:
  mov    %ebx,%edx
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  add    $0x3f,%rdx
  pop    %rbx
  pop    %rbp
  shr    $0x6,%rdx
  shl    $0x3,%edx
  jmp    1060 <memset@plt>
```

assistant: ```c
void bitmap_zero(unsigned long *dst, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    *dst = 0UL;
  else {
    unsigned int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memset(dst, 0, len);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bitmap_zero>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L17
  test   %rax,%rax
  je     L17
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L17:
  mov    %ebx,%edx
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  add    $0x3f,%rdx
  pop    %rbx
  pop    %rbp
  shr    $0x6,%rdx
  shl    $0x3,%edx
  jmp    1060 <memset@plt>
```

assistant: ```c
void bitmap_zero(unsigned long *dst, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    *dst = 0UL;
  else {
    unsigned int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memset(dst, 0, len);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L1
L13:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L13
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L13
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nextchar(char *string, int pos) {
  while (string[pos] == ' ' || string[pos] == '\t')
    pos++;
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nextchar>:
  endbr64
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x20,%al
  je     L3
  cmp    $0x9,%al
  jne    L16
L3:
  add    $0x1,%esi
  movslq %esi,%rax
L28:
  mov    %eax,%esi
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L28
  cmp    $0x9,%dl
  je     L28
L16:
  mov    %esi,%eax
  ret
```

assistant: ```c
int nextchar(char *string, int pos) {
  while (string[pos] == ' ' || string[pos] == '\t')
    pos++;
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nextchar>:
  endbr64
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x20,%al
  je     L35
  cmp    $0x9,%al
  jne    L4
L35:
  add    $0x1,%esi
  movslq %esi,%rax
  nopl   0x0(%rax)
L3:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L3
  cmp    $0x9,%dl
  je     L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L4:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nextchar(char *string, int pos) {
  while (string[pos] == ' ' || string[pos] == '\t')
    pos++;
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nextchar>:
  endbr64
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x20,%al
  je     L31
  cmp    $0x9,%al
  jne    L5
L31:
  add    $0x1,%esi
  movslq %esi,%rax
  nopl   0x0(%rax)
L12:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L12
  cmp    $0x9,%dl
  je     L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nextchar(char *string, int pos) {
  while (string[pos] == ' ' || string[pos] == '\t')
    pos++;
  return pos;
}
```