user: 请从给定的汇编指令推导出C源代码:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x44(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L66:
  cmp    %rdx,%rsp
  je     L53
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L66
L53:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L8
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L8:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L54
L144:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L1
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    (%rcx),%ecx
  mov    -0x10(%rbp),%rdx
  cltq
  mov    %ecx,(%rdx,%rax,4)
  jmp    L54
L1:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    (%rcx),%ecx
  mov    -0x10(%rbp),%rdx
  cltq
  mov    %ecx,(%rdx,%rax,4)
L54:
  mov    -0x28(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jge    L6
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jle    L144
  jmp    L6
L57:
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    (%rcx),%ecx
  mov    -0x10(%rbp),%rdx
  cltq
  mov    %ecx,(%rdx,%rax,4)
L6:
  mov    -0x28(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L57
  jmp    L135
L96:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    (%rcx),%ecx
  mov    -0x10(%rbp),%rdx
  cltq
  mov    %ecx,(%rdx,%rax,4)
L135:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jle    L96
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L141
L33:
  mov    -0x28(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rax,%rcx
  mov    -0x10(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0x28(%rbp)
L141:
  mov    -0x28(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jle    L33
  mov    $0x0,%eax
  mov    %rsi,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int merge(int arr[], int low, int mid, int high) {
  int i, j, k, n;
  n = high - low + 1;
  int temp[n];
  i = low;
  j = mid;
  k = 0;
  while (i < mid && j <= high) {
    if (arr[i] < arr[j]) {
      temp[k++] = arr[i++];
    } else {
      temp[k++] = arr[j++];
    }
  }
  while (i < mid) {
    temp[k++] = arr[i++];
  }
  while (j <= high) {
    temp[k++] = arr[j++];
  }
  for (i = low; i <= high; ++i) {
    arr[i] = temp[i - low];
  }
  return 0;
}
```