user: 请从给定的汇编指令推导出C源代码:

```asm
<problemA>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    D113(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D99(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D92(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D136(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D60(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  lea    (%rsi,%rdx,1),%ecx
  lea    D115(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  lea    D118(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  movapd %xmm1,%xmm0
  lea    D57(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %eax,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    %edi,%edx
  lea    D132(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edx
  lea    D109(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  cvttsd2si 0x10(%rsp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%esi
  movsd  0x10(%rsp),%xmm1
  lea    D79(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %eax,%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    (%rsp),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  and    $0x1,%esi
  sub    %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <main@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D113
type: string
name: disassemble_data
arguments: data_label: D99
type: string
name: disassemble_data
arguments: data_label: D92
type: string
name: disassemble_data
arguments: data_label: D136
type: string
name: disassemble_data
arguments: data_label: D60
type: string
name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D115
type: string
name: disassemble_data
arguments: data_label: D118
type: string
name: disassemble_data
arguments: data_label: D57
type: string
name: disassemble_data
arguments: data_label: D132
type: string
name: disassemble_data
arguments: data_label: D109
type: string
name: disassemble_data
arguments: data_label: D55
type: string
name: disassemble_data
arguments: data_label: D79
type: string
name: disassemble_data
arguments: data_label: D40
type: string

tool: D113: Input Integer #1: 

tool: D99: %d

tool: D92: Input Integer #2: 

tool: D136: Input Floating-point #1: 

tool: D60: %lf

tool: D19: Input Floating-point #2: 

tool: D115: A.1: Result = Integer #1 + Integer #2 = %d + %d = %d 


tool: D118: A.2: Result = Floating-point #1 - Floating-point #2 = %lf - %lf = %lf 


tool: D57: A.3: Result = Integer #1 * Floating-point #1 = %d * %lf = %d 


tool: D132: A.4: Result = Integer #1 / Integer #2 = %d / %d = %d (Integer version), %lf (Floating-point version)


tool: D109: A.5: Result = Integer #1 / Floating-point #2 = %d / %lf = %d (Integer version), %lf (Floating-point version)


tool: D55: A.6: Result = Integer #1 / Integer #2 = %d / %d = %lf 


tool: D79: A.7: Result = Floating-point #1 mod Floating-point #2 = %lf mod %lf = %d 


tool: D40: A.8: Result = 0 if integer is even, 1 if integer is odd.
    Integer #1: %d 
    Integer #2: %d 


assistant: ```c
int problemA(void) {
  int number1_int = 0, number2_int = 0;
  double number1_float = 0.0, number2_float = 0.0;
  int int_result = 0, int_result2 = 0;
  double float_result = 0;
  printf("Input Integer #1: ");
  scanf("%d", &number1_int);
  printf("Input Integer #2: ");
  scanf("%d", &number2_int);
  printf("Input Floating-point #1: ");
  scanf("%lf", &number1_float);
  printf("Input Floating-point #2: ");
  scanf("%lf", &number2_float);
  int_result = number1_int + number2_int;
  printf("A.1: Result = Integer #1 + Integer #2 = %d + %d = %d \n", number1_int, number2_int, int_result);
  float_result = number1_float - number2_float;
  printf("A.2: Result = Floating-point #1 - Floating-point #2 = %lf - %lf = %lf \n", number1_float, number2_float, float_result);
  int_result = number1_int * number1_float;
  printf("A.3: Result = Integer #1 * Floating-point #1 = %d * %lf = %d \n", number1_int, number1_float, int_result);
  int_result = number1_int / number2_int;
  float_result = number1_int / number2_int;
  printf("A.4: Result = Integer #1 / Integer #2 = %d / %d = %d (Integer version), %lf (Floating-point version)\n", number1_int, number2_int, int_result, float_result);
  int_result = number1_int / number2_float;
  float_result = number1_int / number2_float;
  printf("A.5: Result = Integer #1 / Floating-point #2 = %d / %lf = %d (Integer version), %lf (Floating-point version)\n", number1_int, number2_float, int_result, float_result);
  float_result = (double)number1_int / number2_int;
  printf("A.6: Result = Integer #1 / Integer #2 = %d / %d = %lf \n", number1_int, number2_int, float_result);
  int_result = (int)number1_float % (int)number2_float;
  printf("A.7: Result = Floating-point #1 mod Floating-point #2 = %lf mod %lf = %d \n", number1_float, number2_float, int_result);
  int_result = number1_int % 2;
  int_result2 = number2_int % 2;
  printf("A.8: Result = 0 if integer is even, 1 if integer is odd.\n    Integer #1: %d \n    Integer #2: %d \n", int_result, int_result2);
  return main();
}
```