ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L89
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L11
L89:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L2
L104:
  mov    %rsp,%rbx
  test   %ecx,%ecx
  jle    L94
  mov    %rbx,%r13
  xor    %r12d,%r12d
L155:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %r12d,-0x30(%rbp)
  jg     L155
L94:
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %edx,-0x30(%rbp)
  jl     L75
  mov    %rbx,%r14
  xor    %r13d,%r13d
  lea    D15(%rip),%r12
  xchg   %ax,%ax
L105:
  xor    %esi,%esi
  test   %edx,%edx
  jle    L124
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L9
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%r14,%rax,1),%rcx
  mov    %r14,%rax
  xchg   %ax,%ax
L69:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L69
  movdqa %xmm0,%xmm1
  mov    %edx,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%dl
  je     L124
L139:
  lea    (%rax,%r13,1),%ecx
  movslq %ecx,%rcx
  add    (%rbx,%rcx,4),%esi
  lea    0x1(%rax),%ecx
  cmp    %edx,%ecx
  jge    L124
  add    %r13d,%ecx
  add    $0x2,%eax
  movslq %ecx,%rcx
  add    (%rbx,%rcx,4),%esi
  cmp    %eax,%edx
  jle    L124
  add    %r13d,%eax
  cltq
  add    (%rbx,%rax,4),%esi
L124:
  mov    %r12,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  sub    %edx,%eax
  cmp    %r13d,%eax
  jge    L105
L75:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L9:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L139
L2:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L104
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D8: %d

tool: D15: %d


assistant: ```c
int main() {
  int n, k, i, j, m, x;
  scanf("%d", &n);
  int arr[n];
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (n - k); j++) {
    x = 0;
    for (m = 0; m <= k - 1; m++) {
      x = x + arr[j + m];
    }
    printf("%d\n", x);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_vcf_snps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rsi
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <output_vcf_row@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void output_vcf_snps(FILE *vcf_file_pointer, char **bases_for_snps, int *snp_locations, int number_of_snps, int number_of_samples, char pseudo_reference_sequence[]) {
  int i;
  for (i = 0; i < number_of_snps; i++) {
    output_vcf_row(vcf_file_pointer, bases_for_snps[i], snp_locations[i], number_of_samples, pseudo_reference_sequence);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<output_vcf_snps>:
  endbr64
  test   %ecx,%ecx
  jle    L12
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %r8d,%r13d
  mov    %r9,%r14
  mov    %rdx,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r15
L6:
  mov    %r14,%r8
  mov    %r13d,%ecx
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  call   <output_vcf_row@plt>
  add    $0x4,%rbx
  add    $0x8,%rbp
  cmp    %r15,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  ret
```

assistant: ```c
void output_vcf_snps(FILE *vcf_file_pointer, char **bases_for_snps, int *snp_locations, int number_of_snps, int number_of_samples, char pseudo_reference_sequence[]) {
  int i;
  for (i = 0; i < number_of_snps; i++) {
    output_vcf_row(vcf_file_pointer, bases_for_snps[i], snp_locations[i], number_of_samples, pseudo_reference_sequence);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<output_vcf_snps>:
  endbr64
  test   %ecx,%ecx
  jle    L6
  push   %r15
  lea    -0x1(%rcx),%eax
  push   %r14
  lea    0x4(%rdx,%rax,4),%r15
  mov    %r9,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L13:
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r14,%r8
  mov    %r13d,%ecx
  mov    %r12,%rdi
  add    $0x4,%rbx
  add    $0x8,%rbp
  call   <output_vcf_row@plt>
  cmp    %r15,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  ret
```

assistant: ```c
void output_vcf_snps(FILE *vcf_file_pointer, char **bases_for_snps, int *snp_locations, int number_of_snps, int number_of_samples, char pseudo_reference_sequence[]) {
  int i;
  for (i = 0; i < number_of_snps; i++) {
    output_vcf_row(vcf_file_pointer, bases_for_snps[i], snp_locations[i], number_of_samples, pseudo_reference_sequence);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<output_vcf_snps>:
  endbr64
  test   %ecx,%ecx
  jle    L16
  push   %r15
  lea    -0x1(%rcx),%eax
  push   %r14
  lea    0x4(%rdx,%rax,4),%r15
  mov    %r9,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L9:
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r14,%r8
  mov    %r13d,%ecx
  mov    %r12,%rdi
  add    $0x4,%rbx
  add    $0x8,%rbp
  call   <output_vcf_row@plt>
  cmp    %r15,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  ret
```

assistant: ```c
void output_vcf_snps(FILE *vcf_file_pointer, char **bases_for_snps, int *snp_locations, int number_of_snps, int number_of_samples, char pseudo_reference_sequence[]) {
  int i;
  for (i = 0; i < number_of_snps; i++) {
    output_vcf_row(vcf_file_pointer, bases_for_snps[i], snp_locations[i], number_of_samples, pseudo_reference_sequence);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftn2c_string_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L52
L121:
  addl   $0x1,-0x4(%rbp)
L52:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L121
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L79
L66:
  subl   $0x1,-0x24(%rbp)
L79:
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L66
  cmpq   $0x0,-0x20(%rbp)
  jne    L132
  mov    -0x24(%rbp),%eax
  jmp    L176
L132:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L151
  mov    $0xffffffff,%eax
  jmp    L176
L151:
  cmpb   $0x0,-0x2c(%rbp)
  jne    L149
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L149
  mov    $0xffffffff,%eax
  jmp    L176
L149:
  movl   $0x0,-0x4(%rbp)
  jmp    L85
L140:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L85:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L140
  cmpb   $0x0,-0x2c(%rbp)
  je     L29
  jmp    L126
L93:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x2c(%rbp),%eax
  mov    %al,(%rdx)
L126:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L93
  jmp    L157
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x2c(%rbp),%eax
  mov    %al,(%rdx)
L157:
  mov    -0x24(%rbp),%eax
L176:
  pop    %rbp
  ret
```

assistant: ```c
int ftn2c_string_copy(unsigned char *src, unsigned char *dest, int lsrc, int ldest, unsigned char pad) {
  int i;
  for (i = 0; src[i] != 0 && i < lsrc; i++)
    ;
  lsrc = i;
  while (src[lsrc - 1] == ' ')
    lsrc--;
  if (dest == NULL)
    return (lsrc);
  if (lsrc > ldest)
    return (-1);
  if (pad == 0 && lsrc == ldest)
    return (-1);
  for (i = 0; i < lsrc; i++)
    dest[i] = src[i];
  if (pad)
    while (i < ldest)
      dest[i++] = pad;
  else
    dest[i] = pad;
  return (lsrc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ftn2c_string_copy>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  mov    %ecx,%r11d
  mov    %r8d,%ebx
  cmpb   $0x0,(%rdi)
  je     L76
  test   %edx,%edx
  jle    L76
  mov    $0x1,%eax
L137:
  mov    %eax,%ecx
  cmpb   $0x0,(%rdi,%rax,1)
  setne  %r9b
  cmp    %eax,%edx
  setg   %sil
  add    $0x1,%rax
  test   %sil,%r9b
  jne    L137
L173:
  movslq %ecx,%rax
  cmpb   $0x20,-0x1(%rdi,%rax,1)
  jne    L17
  lea    -0x1(%rcx),%eax
  cltq
L152:
  mov    %eax,%ecx
  sub    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L152
L17:
  test   %r10,%r10
  je     L35
  cmp    %ecx,%r11d
  jl     L182
  test   %r8b,%r8b
  jne    L53
  cmp    %ecx,%r11d
  je     L30
L53:
  test   %ecx,%ecx
  jle    L91
  lea    -0x1(%rcx),%esi
  mov    $0x0,%eax
L132:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r10,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L132
  mov    %ecx,%esi
L136:
  test   %r8b,%r8b
  je     L66
  cmp    %esi,%r11d
  jle    L35
  movslq %esi,%rdx
  lea    (%r10,%rdx,1),%rax
  lea    0x1(%r10,%rdx,1),%rdx
  sub    $0x1,%r11d
  sub    %esi,%r11d
  add    %r11,%rdx
L139:
  mov    %bl,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L139
  jmp    L35
L76:
  mov    $0x0,%ecx
  jmp    L173
L91:
  mov    $0x0,%esi
  jmp    L136
L66:
  movslq %esi,%rsi
  movb   $0x0,(%r10,%rsi,1)
L35:
  mov    %ecx,%eax
  pop    %rbx
  ret
L182:
  mov    $0xffffffff,%ecx
  jmp    L35
L30:
  mov    $0xffffffff,%ecx
  jmp    L35
```

assistant: ```c
int ftn2c_string_copy(unsigned char *src, unsigned char *dest, int lsrc, int ldest, unsigned char pad) {
  int i;
  for (i = 0; src[i] != 0 && i < lsrc; i++)
    ;
  lsrc = i;
  while (src[lsrc - 1] == ' ')
    lsrc--;
  if (dest == NULL)
    return (lsrc);
  if (lsrc > ldest)
    return (-1);
  if (pad == 0 && lsrc == ldest)
    return (-1);
  for (i = 0; i < lsrc; i++)
    dest[i] = src[i];
  if (pad)
    while (i < ldest)
      dest[i++] = pad;
  else
    dest[i] = pad;
  return (lsrc);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ftn2c_string_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r11
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  movzbl (%rdi),%r10d
  test   %edx,%edx
  jle    L5
  test   %r10b,%r10b
  je     L5
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L59:
  cmpb   $0x0,(%rdi,%rax,1)
  mov    %eax,%r12d
  mov    %rax,%rsi
  setne  %r9b
  cmp    %eax,%edx
  setg   %cl
  add    $0x1,%rax
  test   %cl,%r9b
  jne    L59
  sub    $0x1,%rsi
L48:
  cmpb   $0x20,(%rdi,%rsi,1)
  jne    L4
  lea    -0x1(%r12),%eax
  cltq
  nopl   (%rax)
L44:
  mov    %eax,%r12d
  sub    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L44
L4:
  test   %r11,%r11
  je     L18
  cmp    %r12d,%ebx
  jl     L72
  test   %r8b,%r8b
  jne    L61
  cmp    %r12d,%ebx
  je     L72
L61:
  test   %r12d,%r12d
  jle    L93
  movslq %r12d,%rdx
  xor    %eax,%eax
  jmp    L60
  nopl   0x0(%rax)
L82:
  movzbl (%rdi,%rax,1),%r10d
L60:
  mov    %r10b,(%r11,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L82
  movslq %r12d,%rax
L119:
  test   %r8b,%r8b
  je     L133
  cmp    %eax,%ebx
  jle    L18
  lea    -0x1(%rbx),%edx
  movzbl %r8b,%esi
  lea    (%r11,%rax,1),%rdi
  mov    %edx,%ebx
  sub    %eax,%ebx
  lea    0x1(%rbx),%rdx
  call   <memset@plt>
L18:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L133:
  movb   $0x0,(%r11,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L5:
  mov    $0xffffffffffffffff,%rsi
  xor    %r12d,%r12d
  jmp    L48
L93:
  xor    %eax,%eax
  jmp    L119
L72:
  mov    $0xffffffff,%r12d
  jmp    L18
```

assistant: ```c
int ftn2c_string_copy(unsigned char *src, unsigned char *dest, int lsrc, int ldest, unsigned char pad) {
  int i;
  for (i = 0; src[i] != 0 && i < lsrc; i++)
    ;
  lsrc = i;
  while (src[lsrc - 1] == ' ')
    lsrc--;
  if (dest == NULL)
    return (lsrc);
  if (lsrc > ldest)
    return (-1);
  if (pad == 0 && lsrc == ldest)
    return (-1);
  for (i = 0; i < lsrc; i++)
    dest[i] = src[i];
  if (pad)
    while (i < ldest)
      dest[i++] = pad;
  else
    dest[i] = pad;
  return (lsrc);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned int o = 1;
  unsigned int z = 0;
  return (int)(o / z);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  div    %ecx
  ret
```

assistant: ```c
int main(void) {
  unsigned int o = 1;
  unsigned int z = 0;
  return (int)(o / z);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  ud2
```

assistant: ```c
int main(void) {
  unsigned int o = 1;
  unsigned int z = 0;
  return (int)(o / z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ud2
```

assistant: ```c
int main(void) {
  unsigned int o = 1;
  unsigned int z = 0;
  return (int)(o / z);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    $0x0,%eax
  call   <cbl_init@plt>
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <cbl_freebloc@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x1,-0x3c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cbl_freebloc@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdi
  mov    -0x20(%rbp),%rsi
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x10(%rbp)
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type: string
name: unpack_data
arguments: data_label: D4
type: string

tool: D17: %p
%p
%p
%p
%p
%p


tool: D4: %p


assistant: ```c
int main(void) {
  int status;
  cbl_init();
  void *s1 = cbl_newbloc();
  void *s2 = cbl_newbloc();
  void *s3 = cbl_newbloc();
  status = cbl_freebloc(s3);
  assert(status == 1);
  void *s4 = cbl_newbloc();
  void *s5 = cbl_newbloc();
  void *s6 = cbl_newbloc();
  void *s7 = cbl_newbloc();
  status = cbl_freebloc(s7);
  assert(status == 0);
  printf("%p\n%p\n%p\n%p\n%p\n%p\n", s1, s2, s3, s4, s5, s6);
  printf("%p\n", s7);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <cbl_init@plt>
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,0x8(%rsp)
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r12
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <cbl_freebloc@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r13
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r14
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <cbl_freebloc@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x8,%rsp
  push   %r15
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    0x18(%rsp),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D12: %p
%p
%p
%p
%p
%p


tool: D3: %p


assistant: ```c
int main(void) {
  int status;
  cbl_init();
  void *s1 = cbl_newbloc();
  void *s2 = cbl_newbloc();
  void *s3 = cbl_newbloc();
  status = cbl_freebloc(s3);
  assert(status == 1);
  void *s4 = cbl_newbloc();
  void *s5 = cbl_newbloc();
  void *s6 = cbl_newbloc();
  void *s7 = cbl_newbloc();
  status = cbl_freebloc(s7);
  assert(status == 0);
  printf("%p\n%p\n%p\n%p\n%p\n%p\n", s1, s2, s3, s4, s5, s6);
  printf("%p\n", s7);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <cbl_init@plt>
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r13
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r14
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <cbl_freebloc@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r15
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <cbl_freebloc@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  sub    $0x8,%rsp
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    0x10(%rsp),%rdx
  mov    %r12,%rcx
  mov    %r13,%rsi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  push   %rdx
  mov    %r14,%rdx
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string
name: disassemble_data
arguments: data_label: D11
datatype: string

tool: D8: %p
%p
%p
%p
%p
%p


tool: D11: %p


assistant: ```c
int main(void) {
  int status;
  cbl_init();
  void *s1 = cbl_newbloc();
  void *s2 = cbl_newbloc();
  void *s3 = cbl_newbloc();
  status = cbl_freebloc(s3);
  assert(status == 1);
  void *s4 = cbl_newbloc();
  void *s5 = cbl_newbloc();
  void *s6 = cbl_newbloc();
  void *s7 = cbl_newbloc();
  status = cbl_freebloc(s7);
  assert(status == 0);
  printf("%p\n%p\n%p\n%p\n%p\n%p\n", s1, s2, s3, s4, s5, s6);
  printf("%p\n", s7);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <cbl_init@plt>
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r13
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r14
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <cbl_freebloc@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%r15
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <cbl_newbloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <cbl_freebloc@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  sub    $0x8,%rsp
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    0x10(%rsp),%rdx
  mov    %r12,%rcx
  mov    %r13,%rsi
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  push   %rdx
  mov    %r14,%rdx
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D19
data_type: string

tool: D15: %p
%p
%p
%p
%p
%p


tool: D19: %p


assistant: ```c
int main(void) {
  int status;
  cbl_init();
  void *s1 = cbl_newbloc();
  void *s2 = cbl_newbloc();
  void *s3 = cbl_newbloc();
  status = cbl_freebloc(s3);
  assert(status == 1);
  void *s4 = cbl_newbloc();
  void *s5 = cbl_newbloc();
  void *s6 = cbl_newbloc();
  void *s7 = cbl_newbloc();
  status = cbl_freebloc(s7);
  assert(status == 0);
  printf("%p\n%p\n%p\n%p\n%p\n%p\n", s1, s2, s3, s4, s5, s6);
  printf("%p\n", s7);
}
```