ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<LogL10toY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    D39(%rip),%rax
  jmp    L9
L13:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D34(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D25(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
L9:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D39
data_type: f64
name: retrieve_data
arguments: data_label: D34
data_type: byte[8]
name: retrieve_data
arguments: data_label: D38
data_type: byte[8]
name: retrieve_data
arguments: data_label: D25
data_type: byte[8]

tool: D39: 0

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D38": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0x86,0x3f]}

tool: {"D25": [0x73,0xab,0x3b,0x3f,0xb2,0xa2,0x20,0x40]}

assistant: ```c
double LogL10toY(int p10) {
  if (p10 == 0)
    return (0.);
  return (exp(0.69314718055994530942 / 64. * (p10 + .5) - 0.69314718055994530942 * 12.));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LogL10toY>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %edi,%edi
  jne    L7
  ret
L7:
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D27(%rip),%xmm0
  mulsd  D28(%rip),%xmm0
  subsd  D17(%rip),%xmm0
  call   <exp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
data_type: f32[2]
name: disassemble_data
arguments: tag: D28
data_type: byte[8]
name: disassemble_data
arguments: tag: D17
data_type: byte[8]

tool: {"D27": [0.0,1.75]}

tool: {"D28": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0x86,0x3f]}

tool: {"D17": [0x73,0xab,0x3b,0x3f,0xb2,0xa2,0x20,0x40]}

assistant: ```c
double LogL10toY(int p10) {
  if (p10 == 0)
    return (0.);
  return (exp(0.69314718055994530942 / 64. * (p10 + .5) - 0.69314718055994530942 * 12.));
}
```
user: Translate the below assembly code into C programming language:

```asm
<LogL10toY>:
  endbr64
  test   %edi,%edi
  jne    L9
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L9:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D26(%rip),%xmm0
  mulsd  D17(%rip),%xmm0
  subsd  D22(%rip),%xmm0
  jmp    1050 <exp@plt>
```

tool_calls: name: parse_data
arguments: label: D26
type_guessed: f32[2]
name: parse_data
arguments: label: D17
type_guessed: byte[8]
name: parse_data
arguments: label: D22
type_guessed: byte[8]

tool: {"D26": [0.0,1.75]}

tool: {"D17": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0x86,0x3f]}

tool: {"D22": [0x73,0xab,0x3b,0x3f,0xb2,0xa2,0x20,0x40]}

assistant: ```c
double LogL10toY(int p10) {
  if (p10 == 0)
    return (0.);
  return (exp(0.69314718055994530942 / 64. * (p10 + .5) - 0.69314718055994530942 * 12.));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LogL10toY>:
  endbr64
  test   %edi,%edi
  jne    L0
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L0:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D9(%rip),%xmm0
  mulsd  D4(%rip),%xmm0
  subsd  D0(%rip),%xmm0
  jmp    1050 <exp@plt>
```

tool_calls: name: read_data
arguments: label: D9
data_type: f32[2]
name: read_data
arguments: label: D4
data_type: byte[8]
name: read_data
arguments: label: D0
data_type: byte[8]

tool: {"D9": [0.0,1.75]}

tool: {"D4": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0x86,0x3f]}

tool: {"D0": [0x73,0xab,0x3b,0x3f,0xb2,0xa2,0x20,0x40]}

assistant: ```c
double LogL10toY(int p10) {
  if (p10 == 0)
    return (0.);
  return (exp(0.69314718055994530942 / 64. * (p10 + .5) - 0.69314718055994530942 * 12.));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotate_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x20,%eax
  sub    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  or     -0x8(%rbp),%eax
  and    %ecx,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned right = x >> n;
  unsigned left = x << ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rotate_right>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  sete   %dl
  movzbl %dl,%edx
  lea    -0x1(%rdx),%eax
  mov    %edi,%esi
  ror    %cl,%esi
  and    %esi,%eax
  neg    %edx
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned right = x >> n;
  unsigned left = x << ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotate_right>:
  endbr64
  xor    %edx,%edx
  test   %esi,%esi
  mov    %esi,%ecx
  mov    %edi,%esi
  sete   %dl
  ror    %cl,%esi
  lea    -0x1(%rdx),%eax
  neg    %edx
  and    %esi,%eax
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned right = x >> n;
  unsigned left = x << ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rotate_right>:
  endbr64
  xor    %edx,%edx
  test   %esi,%esi
  mov    %esi,%ecx
  mov    %edi,%esi
  sete   %dl
  ror    %cl,%esi
  lea    -0x1(%rdx),%eax
  neg    %edx
  and    %esi,%eax
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_right(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned right = x >> n;
  unsigned left = x << ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mov    -0x18(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <get_biggest_of_three@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: string

tool: D37: %f

tool: D32: %.1f


assistant: ```c
int main() {
  float a = 0, b = 0, c = 0;
  scanf("%f", &a);
  scanf("%f", &b);
  scanf("%f", &c);
  float result = get_biggest_of_three(a, b, c);
  printf("%.1f\n", result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <get_biggest_of_three@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D19: %f

tool: D17: %.1f


assistant: ```c
int main() {
  float a = 0, b = 0, c = 0;
  scanf("%f", &a);
  scanf("%f", &b);
  scanf("%f", &c);
  float result = get_biggest_of_three(a, b, c);
  printf("%.1f\n", result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <get_biggest_of_three@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string

tool: D7: %f

tool: D2: %.1f


assistant: ```c
int main() {
  float a = 0, b = 0, c = 0;
  scanf("%f", &a);
  scanf("%f", &b);
  scanf("%f", &c);
  float result = get_biggest_of_three(a, b, c);
  printf("%.1f\n", result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <get_biggest_of_three@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type: string
name: extract_symbolic_data
arguments: data_label: D13
type: string

tool: D12: %f

tool: D13: %.1f


assistant: ```c
int main() {
  float a = 0, b = 0, c = 0;
  scanf("%f", &a);
  scanf("%f", &b);
  scanf("%f", &c);
  float result = get_biggest_of_three(a, b, c);
  printf("%.1f\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L24
  mov    $0xd,%edi
  call   <outbyte@plt>
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <outbyte@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L15
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  int i;
  (void)fd;
  for (i = 0; i < nbytes; i++) {
    if (*(buf + i) == '\n') {
      outbyte('\r');
    }
    outbyte(*(buf + i));
  }
  return (nbytes);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L36
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%r12
  jmp    L27
L10:
  movsbl 0x0(%rbp),%edi
  call   <outbyte@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L36
L27:
  mov    %rbx,%rbp
  cmpb   $0xa,(%rbx)
  jne    L10
  mov    $0xd,%edi
  call   <outbyte@plt>
  jmp    L10
L36:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  int i;
  (void)fd;
  for (i = 0; i < nbytes; i++) {
    if (*(buf + i) == '\n') {
      outbyte('\r');
    }
    outbyte(*(buf + i));
  }
  return (nbytes);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_write>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L25
  lea    -0x1(%rdx),%eax
  mov    %rsi,%rbx
  lea    0x1(%rsi,%rax,1),%rbp
  jmp    L33
  nopl   0x0(%rax)
L24:
  call   <outbyte@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L25
L33:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  jne    L24
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <outbyte@plt>
  movsbl -0x1(%rbx),%edi
  call   <outbyte@plt>
  cmp    %rbp,%rbx
  jne    L33
L25:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  int i;
  (void)fd;
  for (i = 0; i < nbytes; i++) {
    if (*(buf + i) == '\n') {
      outbyte('\r');
    }
    outbyte(*(buf + i));
  }
  return (nbytes);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_write>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L3
  lea    -0x1(%rdx),%eax
  mov    %rsi,%rbx
  lea    0x1(%rsi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  je     L17
  call   <outbyte@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
L3:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L17:
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <outbyte@plt>
  movsbl -0x1(%rbx),%edi
  call   <outbyte@plt>
  cmp    %rbx,%rbp
  jne    L13
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  int i;
  (void)fd;
  for (i = 0; i < nbytes; i++) {
    if (*(buf + i) == '\n') {
      outbyte('\r');
    }
    outbyte(*(buf + i));
  }
  return (nbytes);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mybsearch_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L57
L42:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L25
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L57
L25:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L46
L15:
  mov    -0x4(%rbp),%eax
  jmp    L13
L46:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L57:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L42
  mov    $0xffffffff,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int mybsearch_4(int a[], int size, int value) {
  int mid = 0;
  int left = 0;
  int right = size - 1;
  while (left <= right) {
    mid = left + ((right - left) >> 1);
    if (a[mid] > value) {
      right = mid - 1;
    } else {
      if ((mid == (size - 1)) || (a[mid + 1] > value)) {
        return mid;
      } else {
        left = mid + 1;
      }
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mybsearch_4>:
  endbr64
  sub    $0x1,%esi
  js     L33
  mov    %esi,%r9d
  mov    $0x0,%ecx
  jmp    L22
L2:
  cmp    %eax,%esi
  je     L39
  cmp    %edx,0x4(%rdi,%r10,1)
  jg     L39
  lea    0x1(%rax),%ecx
L12:
  cmp    %r9d,%ecx
  jg     L44
L22:
  mov    %r9d,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%r8
  lea    0x0(,%r8,4),%r10
  cmp    %edx,(%rdi,%r8,4)
  jle    L2
  lea    -0x1(%rax),%r9d
  jmp    L12
L44:
  mov    $0xffffffff,%eax
  ret
L33:
  mov    $0xffffffff,%eax
L39:
  ret
```

assistant: ```c
int mybsearch_4(int a[], int size, int value) {
  int mid = 0;
  int left = 0;
  int right = size - 1;
  while (left <= right) {
    mid = left + ((right - left) >> 1);
    if (a[mid] > value) {
      right = mid - 1;
    } else {
      if ((mid == (size - 1)) || (a[mid + 1] > value)) {
        return mid;
      } else {
        left = mid + 1;
      }
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mybsearch_4>:
  endbr64
  sub    $0x1,%esi
  js     L28
  mov    %esi,%r9d
  xor    %ecx,%ecx
  jmp    L50
L6:
  lea    -0x1(%rax),%r9d
  cmp    %ecx,%r9d
  jl     L28
L50:
  mov    %r9d,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%r8
  lea    0x0(,%r8,4),%r10
  cmp    %edx,(%rdi,%r8,4)
  jg     L6
  cmp    %eax,%esi
  je     L55
  cmp    %edx,0x4(%rdi,%r10,1)
  jg     L55
  lea    0x1(%rax),%ecx
  cmp    %ecx,%r9d
  jge    L50
L28:
  mov    $0xffffffff,%eax
L55:
  ret
```

assistant: ```c
int mybsearch_4(int a[], int size, int value) {
  int mid = 0;
  int left = 0;
  int right = size - 1;
  while (left <= right) {
    mid = left + ((right - left) >> 1);
    if (a[mid] > value) {
      right = mid - 1;
    } else {
      if ((mid == (size - 1)) || (a[mid + 1] > value)) {
        return mid;
      } else {
        left = mid + 1;
      }
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mybsearch_4>:
  endbr64
  sub    $0x1,%esi
  js     L40
  mov    %esi,%r9d
  xor    %ecx,%ecx
  jmp    L27
L60:
  lea    -0x1(%rax),%r9d
  cmp    %ecx,%r9d
  jl     L40
L27:
  mov    %r9d,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%r8
  lea    0x0(,%r8,4),%r10
  cmp    %edx,(%rdi,%r8,4)
  jg     L60
  cmp    %eax,%esi
  je     L52
  cmp    %edx,0x4(%rdi,%r10,1)
  jg     L52
  lea    0x1(%rax),%ecx
  cmp    %ecx,%r9d
  jge    L27
L40:
  mov    $0xffffffff,%eax
L52:
  ret
```

assistant: ```c
int mybsearch_4(int a[], int size, int value) {
  int mid = 0;
  int left = 0;
  int right = size - 1;
  while (left <= right) {
    mid = left + ((right - left) >> 1);
    if (a[mid] > value) {
      right = mid - 1;
    } else {
      if ((mid == (size - 1)) || (a[mid + 1] > value)) {
        return mid;
      } else {
        left = mid + 1;
      }
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<merge_bars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_merge_bars@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <calc_barprice_aves@plt>
  nop
  leave
  ret
```

assistant: ```c
void merge_bars(float bar[16], float newbar[16]) {
  _merge_bars(bar, newbar);
  calc_barprice_aves(bar);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<merge_bars>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <_merge_bars@plt>
  mov    %rbx,%rdi
  call   <calc_barprice_aves@plt>
  pop    %rbx
  ret
```

assistant: ```c
void merge_bars(float bar[16], float newbar[16]) {
  _merge_bars(bar, newbar);
  calc_barprice_aves(bar);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<merge_bars>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <_merge_bars@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <calc_barprice_aves@plt>
```

assistant: ```c
void merge_bars(float bar[16], float newbar[16]) {
  _merge_bars(bar, newbar);
  calc_barprice_aves(bar);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<merge_bars>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <_merge_bars@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <calc_barprice_aves@plt>
```

assistant: ```c
void merge_bars(float bar[16], float newbar[16]) {
  _merge_bars(bar, newbar);
  calc_barprice_aves(bar);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L45
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L40
L45:
  mov    $0x0,%eax
  jmp    L36
L40:
  cmpl   $0x0,-0x10(%rbp)
  js     L33
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L27
L33:
  mov    $0x0,%eax
  jmp    L36
L27:
  mov    $0x1,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int range(int width, int height, int i, int j) {
  if ((i < 0) || (i >= height))
    return 0;
  if ((j < 0) || (j >= width))
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<range>:
  endbr64
  test   %edx,%edx
  js     L19
  cmp    %esi,%edx
  jge    L19
  mov    %ecx,%edx
  shr    $0x1f,%edx
  cmp    %edi,%ecx
  setge  %al
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int range(int width, int height, int i, int j) {
  if ((i < 0) || (i >= height))
    return 0;
  if ((j < 0) || (j >= width))
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<range>:
  endbr64
  test   %edx,%edx
  js     L6
  cmp    %esi,%edx
  jge    L6
  mov    %ecx,%edx
  shr    $0x1f,%edx
  cmp    %edi,%ecx
  setge  %al
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nop
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int range(int width, int height, int i, int j) {
  if ((i < 0) || (i >= height))
    return 0;
  if ((j < 0) || (j >= width))
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<range>:
  endbr64
  test   %edx,%edx
  js     L12
  cmp    %esi,%edx
  jge    L12
  mov    %ecx,%edx
  shr    $0x1f,%edx
  cmp    %edi,%ecx
  setge  %al
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nop
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int range(int width, int height, int i, int j) {
  if ((i < 0) || (i >= height))
    return 0;
  if ((j < 0) || (j >= width))
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pthread_cond_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cond_init@plt>
  leave
  ret
```

assistant: ```c
int pthread_cond_init(pthread_cond_t *cond, const pthread_condattr_t *attr) {
  (void)attr;
  assert(cond);
  return cond_init(cond);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pthread_cond_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <cond_init@plt>
  pop    %rbx
  ret
```

assistant: ```c
int pthread_cond_init(pthread_cond_t *cond, const pthread_condattr_t *attr) {
  (void)attr;
  assert(cond);
  return cond_init(cond);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pthread_cond_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <cond_init@plt>
```

assistant: ```c
int pthread_cond_init(pthread_cond_t *cond, const pthread_condattr_t *attr) {
  (void)attr;
  assert(cond);
  return cond_init(cond);
}
```