user: 这段汇编代码用C语言表示是什么样的：

```asm
<printclosest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edx,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L183
L214:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L214
L183:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L173
L128:
  mov    %r14d,%edx
  mov    %r15d,%esi
  lea    0x3(%rsp),%r13
  mov    %r12,%rdi
  call   <BinarySearch@plt>
  mov    %r13,%rbx
  and    $0xfffffffffffffffc,%r13
  movslq %eax,%rdx
  shr    $0x2,%rbx
  lea    0x1(%rax),%esi
  mov    (%r12,%rdx,4),%ecx
  lea    0x0(,%rdx,4),%r8
  cmp    %r14d,%ecx
  je     L225
  mov    %eax,%r9d
  not    %r9d
  mov    %r9d,%r8d
  shr    $0x1f,%r8d
  cmp    %esi,%r15d
  mov    %r8d,%r10d
  setg   %dil
  jle    L13
  xor    %edx,%edx
  test   %r8b,%r8b
  je     L13
L175:
  add    $0x1,%edx
  movslq %edx,%rdx
  jmp    L261
L174:
  sub    $0x1,%eax
  mov    %eax,%r9d
  not    %r9d
L235:
  mov    %ecx,-0x4(%r13,%rdx,4)
  mov    %r9d,%ecx
  shr    $0x1f,%ecx
  cmp    %esi,%r15d
  setg   %r8b
  mov    %ecx,%r10d
  mov    %r8d,%edi
  test   %cl,%cl
  je     L47
  test   %r8b,%r8b
  je     L47
  mov    %edx,%ebx
  cmp    $0x5,%edx
  je     L204
  movslq %eax,%rcx
  add    $0x1,%rdx
  mov    (%r12,%rcx,4),%ecx
L261:
  movslq %esi,%rdi
  mov    %r14d,%r10d
  mov    %edx,%ebx
  mov    (%r12,%rdi,4),%edi
  sub    %ecx,%r10d
  mov    %edi,%r8d
  sub    %r14d,%r8d
  cmp    %r8d,%r10d
  jl     L174
  add    $0x1,%esi
  mov    %edi,%ecx
  jmp    L235
  nopl   0x0(%rax)
L225:
  sub    $0x1,%eax
  mov    %r14d,0x0(,%rbx,4)
  mov    %eax,%r9d
  not    %r9d
  mov    %r9d,%edx
  shr    $0x1f,%edx
  cmp    %esi,%r15d
  mov    %edx,%r10d
  setg   %dil
  jle    L262
  test   %dl,%dl
  je     L262
  mov    -0x4(%r12,%r8,1),%ecx
  mov    $0x1,%edx
  jmp    L175
  xchg   %ax,%ax
L47:
  cmp    $0x4,%ebx
  setle  %dl
  and    %edx,%r10d
L220:
  test   %r10b,%r10b
  je     L112
  lea    0x1(%rbx),%edx
  sub    $0x1,%eax
  movslq %edx,%rdx
  cltq
  nopl   (%rax)
L223:
  mov    0x4(%r12,%rax,4),%ecx
  cmp    $0x4,%edx
  mov    %edx,%ebx
  setle  %r8b
  mov    %ecx,-0x4(%r13,%rdx,4)
  mov    %eax,%ecx
  add    $0x1,%rdx
  sub    $0x1,%rax
  not    %ecx
  shr    $0x1f,%ecx
  test   %cl,%r8b
  jne    L223
  test   %r8b,%r8b
  je     L204
  test   %dil,%dil
  je     L204
L207:
  lea    0x1(%rsi),%eax
  movslq %ebx,%rdx
  movslq %esi,%rsi
  sub    %rsi,%rdx
  cltq
  lea    0x0(%r13,%rdx,4),%rsi
  nopl   0x0(%rax)
L287:
  mov    %ebx,%r14d
  add    $0x1,%ebx
  mov    -0x4(%r12,%rax,4),%edx
  cmp    $0x4,%ebx
  setle  %cl
  cmp    %eax,%r15d
  mov    %edx,-0x4(%rsi,%rax,4)
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L287
L213:
  xor    %r12d,%r12d
  lea    D3(%rip),%r15
  nopl   (%rax)
L240:
  mov    0x0(%r13,%r12,4),%esi
  xor    %eax,%eax
  mov    %r15,%rdi
  call   <printf@plt>
  cmp    %r12d,%r14d
  je     L197
  mov    $0x20,%edi
  call   <putchar@plt>
L197:
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jg     L240
L291:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L112:
  test   %dil,%dil
  je     L25
  test   %dl,%dl
  jne    L207
L25:
  test   %ebx,%ebx
  je     L291
L204:
  lea    -0x1(%rbx),%r14d
  jmp    L213
  xchg   %ax,%ax
L173:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L128
L13:
  mov    $0x1,%edx
  xor    %ebx,%ebx
  jmp    L220
L262:
  mov    $0x1,%edx
  mov    $0x1,%ebx
  jmp    L220
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: %d

assistant: ```c
int printclosest(int *arr, int k, int n) {
  int pivot, i, j = 0, right, count = 0;
  int temp[n];
  pivot = BinarySearch(arr, n, k);
  right = pivot + 1;
  if (arr[pivot] == k) {
    temp[j++] = arr[pivot];
    pivot--;
    count++;
  }
  while (pivot >= 0 && right < n && count < 5) {
    if (k - arr[pivot] < arr[right] - k) {
      temp[j++] = arr[pivot];
      pivot--;
    } else {
      temp[j++] = arr[right];
      right++;
    }
    count++;
  }
  while (count < 5 && pivot >= 0) {
    temp[j++] = arr[pivot];
    pivot--;
    count++;
  }
  while (count < 5 && right < n) {
    temp[j++] = arr[right];
    right++;
    count++;
  }
  for (i = 0; i < j; i++) {
    printf("%d", temp[i]);
    if (i != j - 1)
      printf(" ");
  }
  return 0;
}
```