ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xf86pathIsSafe>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <xf86pathIsAbsolute@plt>
  test   %rax,%rax
  jne    L29
  cmpb   $0x2e,0x0(%rbp)
  je     L41
L36:
  mov    $0x3,%edx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L79
L29:
  xor    %eax,%eax
L61:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L41:
  cmpb   $0x2e,0x1(%rbp)
  jne    L36
  cmpb   $0x0,0x2(%rbp)
  jne    L36
  xor    %eax,%eax
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L35
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D12(%rip),%rsi
  cltq
  lea    -0x3(%rbp,%rax,1),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L29
L35:
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D15
data_type: string

tool: D11: ../

tool: D12: /..

tool: D15: /../

assistant: ```c
int xf86pathIsSafe(const char *path) {
  if (xf86pathIsAbsolute(path))
    return 0;
  if (!strcmp(path, ".."))
    return 0;
  if (!strncmp(path, "../", 3))
    return 0;
  if ((strlen(path) > 3) && !strcmp(path + strlen(path) - 3, "/.."))
    return 0;
  if (strstr(path, "/../"))
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xf86pathIsSafe>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <xf86pathIsAbsolute@plt>
  test   %rax,%rax
  jne    L55
  cmpb   $0x2e,0x0(%rbp)
  je     L0
L42:
  mov    $0x3,%edx
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L32
L55:
  xor    %eax,%eax
L59:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  cmpb   $0x2e,0x1(%rbp)
  jne    L42
  cmpb   $0x0,0x2(%rbp)
  jne    L42
  xor    %eax,%eax
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D12(%rip),%rsi
  cltq
  lea    -0x3(%rbp,%rax,1),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L55
L8:
  mov    %rbp,%rdi
  lea    D27(%rip),%rsi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D24
type: string
name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D27
type: string

tool: D24: ../

tool: D12: /..

tool: D27: /../

assistant: ```c
int xf86pathIsSafe(const char *path) {
  if (xf86pathIsAbsolute(path))
    return 0;
  if (!strcmp(path, ".."))
    return 0;
  if (!strncmp(path, "../", 3))
    return 0;
  if ((strlen(path) > 3) && !strcmp(path + strlen(path) - 3, "/.."))
    return 0;
  if (strstr(path, "/../"))
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x5,-0x38(%rbp)
  movq   $0x3,-0x30(%rbp)
  movq   $0x5,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L92
L97:
  movq   $0x0,-0x18(%rbp)
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x48(%rbp),%rax
  cmp    $0x1,%rax
  jne    L14
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L92
L14:
  mov    -0x48(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L53
  movq   $0x5,-0x38(%rbp)
  movq   $0x3,-0x30(%rbp)
  movq   $0x5,-0x28(%rbp)
L53:
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L45:
  mov    -0x30(%rbp),%rax
  xor    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  xor    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  xor    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    %rax,-0x30(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L65
L10:
  mov    -0x20(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L65:
  cmpq   $0x0,-0x20(%rbp)
  jne    L10
L20:
  mov    -0x48(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L45
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L92:
  mov    -0x40(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  test   %rax,%rax
  jne    L97
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D3: %Lu

tool: D13: 1

tool: D11: %Lu


assistant: ```c
int main() {
  unsigned long long N, T;
  unsigned long long s1 = 5, s2 = 3, i = 5;
  unsigned long long tmp, step = 0, n;
  scanf("%Lu", &T);
  while (T--) {
    step = 0;
    scanf("%Lu", &N);
    if (N == 1)
      printf("1\n");
    else {
      if (n > N) {
        s1 = 5;
        s2 = 3;
        i = 5;
      }
      n = N;
      while (step < N) {
        s1 ^= s2;
        s2 ^= s1;
        s1 ^= s2;
        s2 += s1;
        i++;
        tmp = s2;
        step = 0;
        while (tmp > 0) {
          tmp /= 10;
          step++;
        }
      }
      printf("%Lu\n", i);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  test   %rax,%rax
  je     L52
  mov    $0x5,%r14d
  mov    $0x3,%ebp
  mov    $0x5,%r12d
  movabs $0xcccccccccccccccd,%rbx
  jmp    L42
L85:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L99
L92:
  mov    %rbp,%r12
  mov    %r13,%rbp
L80:
  add    $0x1,%r14
  add    %rbp,%r12
  mov    %r12,%r13
  je     L92
  mov    %r12,%rdx
  mov    $0x0,%ecx
L13:
  mov    %rdx,%rsi
  mov    %rdx,%rax
  mul    %rbx
  shr    $0x3,%rdx
  add    $0x1,%rcx
  cmp    $0x9,%rsi
  ja     L13
  cmp    %rcx,%r15
  ja     L92
L19:
  mov    %r14,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r15,0x8(%rsp)
  mov    %rbp,%r12
  mov    %r13,%rbp
L99:
  mov    0x20(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  test   %rax,%rax
  je     L52
L42:
  lea    0x18(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%r15
  cmp    $0x1,%r15
  je     L85
  mov    0x8(%rsp),%rdi
  cmp    %rdi,%r15
  mov    $0x5,%eax
  cmovb  %rax,%r14
  mov    $0x3,%eax
  cmovb  %rax,%rbp
  mov    $0x5,%eax
  cmovb  %rax,%r12
  test   %r15,%r15
  jne    L80
  mov    %rbp,%r13
  mov    %r12,%rbp
  jmp    L19
L52:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
data_type: string
name: retrieve_data
arguments: data_label: D38
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D19: %Lu

tool: D38: 1

tool: D5: %Lu


assistant: ```c
int main() {
  unsigned long long N, T;
  unsigned long long s1 = 5, s2 = 3, i = 5;
  unsigned long long tmp, step = 0, n;
  scanf("%Lu", &T);
  while (T--) {
    step = 0;
    scanf("%Lu", &N);
    if (N == 1)
      printf("1\n");
    else {
      if (n > N) {
        s1 = 5;
        s2 = 3;
        i = 5;
      }
      n = N;
      while (step < N) {
        s1 ^= s2;
        s2 ^= s1;
        s1 ^= s2;
        s2 += s1;
        i++;
        tmp = s2;
        step = 0;
        while (tmp > 0) {
          tmp /= 10;
          step++;
        }
      }
      printf("%Lu\n", i);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  mov    0x20(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  test   %rax,%rax
  je     L34
  mov    $0x5,%ebp
  mov    $0x3,%r14d
  mov    $0x5,%ebx
  movabs $0xcccccccccccccccd,%r15
  lea    0x18(%rsp),%r13
  nopl   0x0(%rax)
L35:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%r11
  cmp    $0x1,%r11
  je     L7
  cmp    (%rsp),%r11
  mov    $0x5,%ecx
  mov    $0x3,%eax
  cmovb  %rcx,%rbp
  cmovb  %rax,%r14
  cmovb  %rcx,%rbx
  test   %r11,%r11
  je     L92
  nopl   0x0(%rax)
L72:
  add    $0x1,%rbp
  add    %r14,%rbx
  mov    %rbx,%r9
  je     L10
  mov    %rbx,%rdx
  xor    %edi,%edi
  nopl   0x0(%rax)
L3:
  mov    %rdx,%rax
  mov    %rdx,%rsi
  add    $0x1,%rdi
  mul    %r15
  shr    $0x3,%rdx
  cmp    $0x9,%rsi
  ja     L3
  cmp    %rdi,%r11
  jbe    L61
L10:
  mov    %r14,%rbx
  mov    %r9,%r14
  jmp    L72
L92:
  mov    %r14,%r9
  mov    %rbx,%r14
  nopw   0x0(%rax,%rax,1)
L61:
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  mov    %r11,(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %r14,%rbx
  call   <printf@plt>
  mov    0x8(%rsp),%r14
L29:
  mov    0x20(%rsp),%rax
  lea    -0x1(%rax),%rsi
  mov    %rsi,0x20(%rsp)
  test   %rax,%rax
  jne    L35
L34:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L29
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D23
type_infered: string

tool: D8: %Lu

tool: D27: %Lu


tool: D23: 1

assistant: ```c
int main() {
  unsigned long long N, T;
  unsigned long long s1 = 5, s2 = 3, i = 5;
  unsigned long long tmp, step = 0, n;
  scanf("%Lu", &T);
  while (T--) {
    step = 0;
    scanf("%Lu", &N);
    if (N == 1)
      printf("1\n");
    else {
      if (n > N) {
        s1 = 5;
        s2 = 3;
        i = 5;
      }
      n = N;
      while (step < N) {
        s1 ^= s2;
        s2 ^= s1;
        s1 ^= s2;
        s2 += s1;
        i++;
        tmp = s2;
        step = 0;
        while (tmp > 0) {
          tmp /= 10;
          step++;
        }
      }
      printf("%Lu\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  mov    0x20(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  test   %rax,%rax
  je     L54
  mov    $0x5,%ebp
  mov    $0x3,%r14d
  mov    $0x5,%ebx
  movabs $0xcccccccccccccccd,%r15
  lea    0x18(%rsp),%r13
  nopl   0x0(%rax)
L65:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%r11
  cmp    $0x1,%r11
  je     L93
  cmp    (%rsp),%r11
  mov    $0x5,%ecx
  mov    $0x3,%eax
  cmovb  %rcx,%rbp
  cmovb  %rax,%r14
  cmovb  %rcx,%rbx
  test   %r11,%r11
  je     L9
  nopl   0x0(%rax)
L5:
  add    $0x1,%rbp
  add    %r14,%rbx
  mov    %rbx,%r9
  je     L53
  mov    %rbx,%rdx
  xor    %edi,%edi
  nopl   0x0(%rax)
L21:
  mov    %rdx,%rax
  mov    %rdx,%rsi
  add    $0x1,%rdi
  mul    %r15
  shr    $0x3,%rdx
  cmp    $0x9,%rsi
  ja     L21
  cmp    %rdi,%r11
  jbe    L15
L53:
  mov    %r14,%rbx
  mov    %r9,%r14
  jmp    L5
L9:
  mov    %r14,%r9
  mov    %rbx,%r14
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  mov    %r11,(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %r14,%rbx
  call   <printf@plt>
  mov    0x8(%rsp),%r14
L42:
  mov    0x20(%rsp),%rax
  lea    -0x1(%rax),%rsi
  mov    %rsi,0x20(%rsp)
  test   %rax,%rax
  jne    L65
L54:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L42
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string

tool: D24: %Lu

tool: D5: %Lu


tool: D7: 1

assistant: ```c
int main() {
  unsigned long long N, T;
  unsigned long long s1 = 5, s2 = 3, i = 5;
  unsigned long long tmp, step = 0, n;
  scanf("%Lu", &T);
  while (T--) {
    step = 0;
    scanf("%Lu", &N);
    if (N == 1)
      printf("1\n");
    else {
      if (n > N) {
        s1 = 5;
        s2 = 3;
        i = 5;
      }
      n = N;
      while (step < N) {
        s1 ^= s2;
        s2 ^= s1;
        s1 ^= s2;
        s2 += s1;
        i++;
        tmp = s2;
        step = 0;
        while (tmp > 0) {
          tmp /= 10;
          step++;
        }
      }
      printf("%Lu\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<DestroyEDistList2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DestroyEDistList2(Schema, A) struct univStruct *Schema;
struct Student **A;
{
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<DestroyEDistList2>:
  endbr64
  ret
```

assistant: ```c
void DestroyEDistList2(Schema, A) struct univStruct *Schema;
struct Student **A;
{
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DestroyEDistList2>:
  endbr64
  ret
```

assistant: ```c
void DestroyEDistList2(Schema, A) struct univStruct *Schema;
struct Student **A;
{
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<DestroyEDistList2>:
  endbr64
  ret
```

assistant: ```c
void DestroyEDistList2(Schema, A) struct univStruct *Schema;
struct Student **A;
{
}
```
user: What is the c source code of the assembly code below:

```asm
<EndFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D5
data_type: string

tool: D19: return Cycles;


tool: D5: }


assistant: ```c
void EndFunction(FILE *fh) {
  fprintf(fh, "return Cycles;\r\n");
  fprintf(fh, "}\r\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<EndFunction>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D7(%rip),%rsi
  call   <fprintf@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string

tool: D7: return Cycles;


tool: D3: }


assistant: ```c
void EndFunction(FILE *fh) {
  fprintf(fh, "return Cycles;\r\n");
  fprintf(fh, "}\r\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<EndFunction>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rsi
  mov    %rdi,%rbp
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  pop    %rbp
  jmp    1050 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D6: return Cycles;


tool: D9: }


assistant: ```c
void EndFunction(FILE *fh) {
  fprintf(fh, "return Cycles;\r\n");
  fprintf(fh, "}\r\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EndFunction>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rsi
  mov    %rdi,%rbp
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  pop    %rbp
  jmp    1050 <fprintf@plt>
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D0
type: string

tool: D15: return Cycles;


tool: D0: }


assistant: ```c
void EndFunction(FILE *fh) {
  fprintf(fh, "return Cycles;\r\n");
  fprintf(fh, "}\r\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<which>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L107
  mov    %r12,%rdi
  call   <is_there@plt>
  test   %rax,%rax
  jne    L31
L107:
  lea    D35(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L22
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L71
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%r14d
  movslq %r14d,%rax
  mov    %rax,(%rsp)
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L117
  lea    D36(%rip),%r15
L64:
  lea    0x10(%rsp),%r13
L59:
  lea    D19(%rip),%rsi
  mov    %r13,%rdi
  call   <strsep@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L129
  cmpb   $0x0,(%rbx)
  cmove  %r15,%rbx
  mov    %r12,%r8
  mov    %rbx,%rcx
  lea    D13(%rip),%rdx
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cmp    %eax,%r14d
  jle    L59
  mov    %rbp,%rdi
  call   <is_there@plt>
  test   %rax,%rax
  je     L64
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rbx
  jmp    L22
L31:
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  jmp    L22
L117:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rbx
  jmp    L22
L129:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L125
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  mov    0x8(%rsp),%rbx
  jmp    L22
L125:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D36
type: string
name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D13
type: string

tool: D35: PATH

tool: D36: .

tool: D19: :

tool: D13: %s/%s

assistant: ```c
char *which(char *filename) {
  size_t max_candidate;
  char *candidate, *path, *spath;
  const char *d, *p;
  if (strchr(filename, '/') != NULL && is_there(filename))
    return (strdup(filename));
  if ((p = getenv("PATH")) == NULL)
    return (NULL);
  spath = path = strdup(p);
  if (path == NULL)
    return (NULL);
  max_candidate = strlen(path) + strlen(filename) + 2;
  if ((candidate = malloc(max_candidate)) == NULL) {
    free(spath);
    return NULL;
  }
  while ((d = strsep(&path, ":")) != NULL) {
    if (*d == '\0')
      d = ".";
    if (snprintf(candidate, max_candidate, "%s/%s", d, filename) >= (int)max_candidate)
      continue;
    if (is_there(candidate)) {
      free(spath);
      return (candidate);
    }
  }
  free(path);
  free(candidate);
  return (NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L11:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  cmpl   $0x9,-0x8(%rbp)
  jle    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x9,-0x4(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string

tool: D11: %-2d 

assistant: ```c
int main(int argc, char *argv[]) {
  int ii = 10;
  for (ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
  for (int ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
L18:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: %-2d 

assistant: ```c
int main(int argc, char *argv[]) {
  int ii = 10;
  for (ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
  for (int ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L7
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %-2d 

assistant: ```c
int main(int argc, char *argv[]) {
  int ii = 10;
  for (ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
  for (int ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L1
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %-2d 

assistant: ```c
int main(int argc, char *argv[]) {
  int ii = 10;
  for (ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
  for (int ii = 0; ii < 10; ii++)
    printf("%-2d ", ii);
  printf("\n");
}
```