ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fnMH_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x48,%rsp
  mov    0x10(%rbp),%rax
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x50(%rbp)
  movslq (%rdx),%rdx
  mov    %rsp,%rdi
  mov    %r8,-0x68(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    %rdx,%rsi
  mov    %rax,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdx,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L88
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L4
L88:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L77
L114:
  mov    %rsp,%r14
  xor    %eax,%eax
  test   %esi,%esi
  jle    L14
  nopl   0x0(%rax,%rax,1)
L8:
  movsd  (%r15,%rax,8),%xmm0
  mov    -0x48(%rbp),%rcx
  movsd  %xmm0,(%r14,%rax,8)
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
L14:
  mov    -0x60(%rbp),%rax
  cmpl   $0x1,(%rax)
  jle    L35
  movl   $0x0,-0x54(%rbp)
  mov    $0x1,%r13d
  jmp    L106
  nopw   0x0(%rax,%rax,1)
L60:
  test   %edx,%edx
  jle    L57
  mov    -0x48(%rbp),%rax
  movslq %r8d,%r8
  shl    $0x3,%rdx
  mov    %r14,%rsi
  lea    (%rax,%r8,8),%rdi
  call   <memcpy@plt>
L57:
  mov    -0x60(%rbp),%rax
  add    $0x1,%r13
  cmp    %r13d,(%rax)
  jle    L35
L106:
  movslq -0x54(%rbp),%rax
  movsd  (%rbx,%r13,8),%xmm0
  mov    %r13d,%r12d
  subsd  (%rbx,%rax,8),%xmm0
  call   <exp@plt>
  mov    -0x50(%rbp),%rax
  movapd %xmm0,%xmm1
  movsd  D4(%rip),%xmm0
  movslq (%rax),%rdx
  mov    -0x68(%rbp),%rax
  minsd  %xmm1,%xmm0
  mov    %edx,%r8d
  imul   %r13d,%r8d
  comisd (%rax,%r13,8),%xmm0
  jb     L60
  test   %edx,%edx
  jle    L45
  movslq %r8d,%rax
  shl    $0x3,%rdx
  mov    %r14,%rdi
  mov    %r8d,-0x54(%rbp)
  lea    (%r15,%rax,8),%rsi
  call   <memcpy@plt>
  mov    -0x54(%rbp),%r8d
L45:
  mov    -0x70(%rbp),%rax
  mov    %r12d,-0x54(%rbp)
  addl   $0x1,(%rax)
  mov    -0x50(%rbp),%rax
  movslq (%rax),%rdx
  jmp    L60
  nop
L35:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L77:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L114
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void fnMH_C(double *theta, int *N, int *k, double *lnw, double *u, double *draws, int *ns) {
  int m, s;
  double e;
  double tmp[*k];
  for (int j = 0; j < *k; j++) {
    tmp[j] = theta[j];
    draws[j] = theta[j];
  }
  s = 0;
  for (int i = 1; i < *N; i++) {
    e = exp(lnw[i] - lnw[s]);
    if (e > 1) {
      e = 1;
    }
    m = i * (*k);
    if (u[i] <= e) {
      for (int j = 0; j < *k; j++) {
        tmp[j] = theta[m + j];
      }
      s = i;
      *ns = *ns + 1;
    }
    for (int j = 0; j < *k; j++)
      draws[m + j] = tmp[j];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<emit_sltiu32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L0
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <emit_zeroreg@plt>
L0:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_cmpimm@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L15
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <emit_movimm@plt>
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <emit_adcimm@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_sltiu32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_adcimm(0, rt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_sltiu32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  cmp    %edx,%edi
  jne    L12
  call   <emit_cmpimm@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <emit_movimm@plt>
  jmp    L13
L12:
  mov    %edx,%edi
  call   <emit_zeroreg@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <emit_cmpimm@plt>
L13:
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <emit_adcimm@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void emit_sltiu32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_adcimm(0, rt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<emit_sltiu32>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  cmp    %edx,%edi
  jne    L5
  mov    %edx,%edi
  call   <emit_cmpimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  call   <emit_movimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <emit_adcimm@plt>
L5:
  mov    %edi,%r12d
  mov    %edx,%edi
  call   <emit_zeroreg@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmpimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <emit_adcimm@plt>
```

assistant: ```c
void emit_sltiu32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_adcimm(0, rt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<emit_sltiu32>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  cmp    %edx,%edi
  jne    L2
  mov    %edx,%edi
  call   <emit_cmpimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  call   <emit_movimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <emit_adcimm@plt>
L2:
  mov    %edi,%r12d
  mov    %edx,%edi
  call   <emit_zeroreg@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmpimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <emit_adcimm@plt>
```

assistant: ```c
void emit_sltiu32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_adcimm(0, rt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  fldz
  fstpt  -0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L36
L20:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L3
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L3
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  fldl   -0x40(%rbp)
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L3:
  addl   $0x1,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L20
  pxor   %xmm3,%xmm3
  cvtsi2sdl -0x14(%rbp),%xmm3
  movsd  %xmm3,-0x40(%rbp)
  fldl   -0x40(%rbp)
  fldt   -0x10(%rbp)
  fdivp  %st,%st(1)
  fstpt  -0x10(%rbp)
  fldt   -0x10(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
long double mean(int n, double *data, double *ysig) {
  int i;
  int num = 0;
  long double meanval = 0;
  for (i = 0; i < n; i++) {
    if (!isnan(data[i]) && !isnan(ysig[i])) {
      meanval += (long double)(data[i] / (ysig[i] * ysig[i]));
      num++;
    }
  }
  meanval /= (double)num;
  return meanval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mean>:
  endbr64
  test   %edi,%edi
  jle    L11
  mov    %edi,%edi
  mov    $0x0,%eax
  fldz
  mov    $0x0,%ecx
  jmp    L4
L37:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L24
L4:
  movsd  (%rsi,%rax,8),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L37
  movsd  (%rdx,%rax,8),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L37
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rsp)
  faddl  -0x10(%rsp)
  add    $0x1,%ecx
  jmp    L37
L11:
  fldz
  mov    $0x0,%ecx
L24:
  mov    %ecx,-0x10(%rsp)
  fildl  -0x10(%rsp)
  fdivrp %st,%st(1)
  ret
```

assistant: ```c
long double mean(int n, double *data, double *ysig) {
  int i;
  int num = 0;
  long double meanval = 0;
  for (i = 0; i < n; i++) {
    if (!isnan(data[i]) && !isnan(ysig[i])) {
      meanval += (long double)(data[i] / (ysig[i] * ysig[i]));
      num++;
    }
  }
  meanval /= (double)num;
  return meanval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mean>:
  endbr64
  test   %edi,%edi
  jle    L14
  movslq %edi,%rdi
  fldz
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L20:
  movsd  (%rsi,%rax,8),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L36
  movsd  (%rdx,%rax,8),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L36
  mulsd  %xmm0,%xmm0
  add    $0x1,%ecx
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rsp)
  faddl  -0x10(%rsp)
L36:
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L20
  mov    %ecx,-0x10(%rsp)
  fildl  -0x10(%rsp)
  fdivrp %st,%st(1)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  fldz
  fld    %st(0)
  fdivrp %st,%st(1)
  ret
```

assistant: ```c
long double mean(int n, double *data, double *ysig) {
  int i;
  int num = 0;
  long double meanval = 0;
  for (i = 0; i < n; i++) {
    if (!isnan(data[i]) && !isnan(ysig[i])) {
      meanval += (long double)(data[i] / (ysig[i] * ysig[i]));
      num++;
    }
  }
  meanval /= (double)num;
  return meanval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mean>:
  endbr64
  test   %edi,%edi
  jle    L11
  movslq %edi,%rdi
  fldz
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L4:
  movsd  (%rsi,%rax,8),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L25
  movsd  (%rdx,%rax,8),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L25
  mulsd  %xmm0,%xmm0
  add    $0x1,%ecx
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rsp)
  faddl  -0x10(%rsp)
L25:
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L4
  mov    %ecx,-0x10(%rsp)
  fildl  -0x10(%rsp)
  fdivrp %st,%st(1)
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  fldz
  fld    %st(0)
  fdivrp %st,%st(1)
  ret
```

assistant: ```c
long double mean(int n, double *data, double *ysig) {
  int i;
  int num = 0;
  long double meanval = 0;
  for (i = 0; i < n; i++) {
    if (!isnan(data[i]) && !isnan(ysig[i])) {
      meanval += (long double)(data[i] / (ysig[i] * ysig[i]));
      num++;
    }
  }
  meanval /= (double)num;
  return meanval;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x9,-0x4(%rbp)
  jle    L6
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
#pragma acc parallel
  {
    int j = 0;
#pragma acc loop private(j)
    for (int i = 0; i < 10; i++)
      j++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
#pragma acc parallel
  {
    int j = 0;
#pragma acc loop private(j)
    for (int i = 0; i < 10; i++)
      j++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
#pragma acc parallel
  {
    int j = 0;
#pragma acc loop private(j)
    for (int i = 0; i < 10; i++)
      j++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
#pragma acc parallel
  {
    int j = 0;
#pragma acc loop private(j)
    for (int i = 0; i < 10; i++)
      j++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clickplc_int16_enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %ax,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  movzwl -0x14(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzwl -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int clickplc_int16_enc(unsigned short number, unsigned char *stream2bytes) {
  int retval = 2;
  stream2bytes[0] = (unsigned char)(number >> 8);
  stream2bytes[1] = (unsigned char)(number & 0x00ff);
  return (retval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clickplc_int16_enc>:
  endbr64
  mov    %edi,%eax
  movzbl %ah,%edx
  mov    %dl,(%rsi)
  mov    %dil,0x1(%rsi)
  mov    $0x2,%eax
  ret
```

assistant: ```c
int clickplc_int16_enc(unsigned short number, unsigned char *stream2bytes) {
  int retval = 2;
  stream2bytes[0] = (unsigned char)(number >> 8);
  stream2bytes[1] = (unsigned char)(number & 0x00ff);
  return (retval);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clickplc_int16_enc>:
  endbr64
  rol    $0x8,%di
  mov    $0x2,%eax
  mov    %di,(%rsi)
  ret
```

assistant: ```c
int clickplc_int16_enc(unsigned short number, unsigned char *stream2bytes) {
  int retval = 2;
  stream2bytes[0] = (unsigned char)(number >> 8);
  stream2bytes[1] = (unsigned char)(number & 0x00ff);
  return (retval);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clickplc_int16_enc>:
  endbr64
  rol    $0x8,%di
  mov    $0x2,%eax
  mov    %di,(%rsi)
  ret
```

assistant: ```c
int clickplc_int16_enc(unsigned short number, unsigned char *stream2bytes) {
  int retval = 2;
  stream2bytes[0] = (unsigned char)(number >> 8);
  stream2bytes[1] = (unsigned char)(number & 0x00ff);
  return (retval);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_getline_from_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x64,%edi
  call   <alarm@plt>
  lea    -0x110(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x210(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline_from_buffer@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L56
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
L56:
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L60
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
L60:
  lea    -0x110(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x210(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline_from_buffer@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L16
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
L16:
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L50
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
L50:
  mov    $0x0,%edi
  call   <alarm@plt>
  mov    $0x0,%eax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D25
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D0: 


tool: D23: FAILURE: scratchbuf not snarfed


tool: D25: FAILURE: linebuf not populated


tool: D19: 


assistant: ```c
int test_getline_from_buffer(void) {
  char linebuf[256];
  char scratchbuf[256];
  alarm(100);
  strcpy(scratchbuf, "\r\n");
  getline_from_buffer(scratchbuf, linebuf, 256);
  if (strlen(scratchbuf) != 0) {
    printf("FAILURE: scratchbuf not snarfed\n");
    return (1);
  }
  if (strlen(linebuf) != 2) {
    printf("FAILURE: linebuf not populated\n");
    return (1);
  }
  strcpy(scratchbuf, "\n");
  getline_from_buffer(scratchbuf, linebuf, 256);
  if (strlen(scratchbuf) != 0) {
    printf("FAILURE: scratchbuf not snarfed\n");
    return (1);
  }
  if (strlen(linebuf) != 1) {
    printf("FAILURE: linebuf not populated\n");
    return (1);
  }
  alarm(0);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_getline_from_buffer>:
  endbr64
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x64,%edi
  call   <alarm@plt>
  lea    0x100(%rsp),%rbx
  lea    D54(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rsi
  mov    $0x100,%edx
  mov    %rbx,%rdi
  call   <getline_from_buffer@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L7
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L6
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L78
L7:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
L78:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    %ebx,%eax
  add    $0x210,%rsp
  pop    %rbx
  ret
L6:
  lea    0x100(%rsp),%rbx
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rsi
  mov    $0x100,%edx
  mov    %rbx,%rdi
  call   <getline_from_buffer@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L55
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L86
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L78
L55:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L78
L86:
  mov    $0x0,%edi
  call   <alarm@plt>
  jmp    L78
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D54
type_infered: string
name: retrieve_data
arguments: data_label: D25
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D47
type_infered: string

tool: D54: 


tool: D25: FAILURE: linebuf not populated


tool: D39: FAILURE: scratchbuf not snarfed


tool: D47: 


assistant: ```c
int test_getline_from_buffer(void) {
  char linebuf[256];
  char scratchbuf[256];
  alarm(100);
  strcpy(scratchbuf, "\r\n");
  getline_from_buffer(scratchbuf, linebuf, 256);
  if (strlen(scratchbuf) != 0) {
    printf("FAILURE: scratchbuf not snarfed\n");
    return (1);
  }
  if (strlen(linebuf) != 2) {
    printf("FAILURE: linebuf not populated\n");
    return (1);
  }
  strcpy(scratchbuf, "\n");
  getline_from_buffer(scratchbuf, linebuf, 256);
  if (strlen(scratchbuf) != 0) {
    printf("FAILURE: scratchbuf not snarfed\n");
    return (1);
  }
  if (strlen(linebuf) != 1) {
    printf("FAILURE: linebuf not populated\n");
    return (1);
  }
  alarm(0);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_getline_from_buffer>:
  endbr64
  push   %r13
  mov    $0x64,%edi
  push   %r12
  push   %rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    0x100(%rsp),%rbp
  mov    %rsp,%r13
  call   <alarm@plt>
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    $0x100,%edx
  mov    %r13,%rsi
  call   <getline_from_buffer@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L26
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L43
L34:
  lea    D0(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
L64:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x210,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L43:
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x100,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <getline_from_buffer@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L26
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L34
  xor    %edi,%edi
  call   <alarm@plt>
  jmp    L64
  nopl   0x0(%rax)
L26:
  lea    D2(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
  jmp    L64
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D37: 


tool: D0: FAILURE: linebuf not populated


tool: D22: 


tool: D2: FAILURE: scratchbuf not snarfed


assistant: ```c
int test_getline_from_buffer(void) {
  char linebuf[256];
  char scratchbuf[256];
  alarm(100);
  strcpy(scratchbuf, "\r\n");
  getline_from_buffer(scratchbuf, linebuf, 256);
  if (strlen(scratchbuf) != 0) {
    printf("FAILURE: scratchbuf not snarfed\n");
    return (1);
  }
  if (strlen(linebuf) != 2) {
    printf("FAILURE: linebuf not populated\n");
    return (1);
  }
  strcpy(scratchbuf, "\n");
  getline_from_buffer(scratchbuf, linebuf, 256);
  if (strlen(scratchbuf) != 0) {
    printf("FAILURE: scratchbuf not snarfed\n");
    return (1);
  }
  if (strlen(linebuf) != 1) {
    printf("FAILURE: linebuf not populated\n");
    return (1);
  }
  alarm(0);
  return (0);
}
```