ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D48(%rip),%rsi
  lea    D59(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L13
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    0x0(%rbp),%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L10:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  lea    D58(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D48
type_guessed: string
name: parse_data
arguments: data_label: D59
type_guessed: string
name: parse_data
arguments: data_label: D31
type_guessed: string
name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string
name: parse_data
arguments: data_label: D58
type_guessed: string

tool: D48: r

tool: D59: test.txt

tool: D31: Success!

tool: D38: Opening "test.txt" in "r" mode!

tool: D5: File descriptor of fp: %d


tool: D58: Error

assistant: ```c
int main(void) {
  FILE *fp;
  if ((fp = fopen("test.txt", "r")) != NULL) {
    printf("Success!\n");
    printf("Opening \"test.txt\" in \"r\" mode!\n");
    printf("File descriptor of fp: %d\n", fp->_fileno);
  } else {
    perror("Error");
    exit(-1);
  }
  fclose(fp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i = 1;
  int j = 1;
  j = i++;
  print_int(j);
  print_int(i);
  j = ++i;
  print_int(j);
  print_int(i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <print_int@plt>
  mov    $0x2,%edi
  call   <print_int@plt>
  mov    $0x3,%edi
  call   <print_int@plt>
  mov    $0x3,%edi
  call   <print_int@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i = 1;
  int j = 1;
  j = i++;
  print_int(j);
  print_int(i);
  j = ++i;
  print_int(j);
  print_int(i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <print_int@plt>
  mov    $0x2,%edi
  call   <print_int@plt>
  mov    $0x3,%edi
  call   <print_int@plt>
  mov    $0x3,%edi
  call   <print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i = 1;
  int j = 1;
  j = i++;
  print_int(j);
  print_int(i);
  j = ++i;
  print_int(j);
  print_int(i);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <print_int@plt>
  mov    $0x2,%edi
  call   <print_int@plt>
  mov    $0x3,%edi
  call   <print_int@plt>
  mov    $0x3,%edi
  call   <print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i = 1;
  int j = 1;
  j = i++;
  print_int(j);
  print_int(i);
  j = ++i;
  print_int(j);
  print_int(i);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L76
  mov    -0x40(%rbp),%rax
  movl   $0x0,(%rax)
L76:
  mov    -0x34(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jne    L30
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L56
  mov    -0x40(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L32
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    -0x40(%rbp),%rdx
  mov    (%rdx),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x40(%rbp),%rdx
  mov    %ecx,(%rdx)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L32
L30:
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L6
L41:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <permute>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x14(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jle    L41
  jmp    L32
L56:
  nop
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void permute(char **result, char *a, int l, int r, int *len) {
  int i;
  if (l == 0)
    *len = 0;
  if (l == r) {
    if (a[0] == '0')
      return;
    if (!contains(result, *len, a)) {
      result[*len] = malloc(strlen(a) + 1);
      strcpy(result[(*len)++], a);
    }
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(result, a, l + 1, r, len);
      swap((a + l), (a + i));
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %r8,%r15
  test   %edx,%edx
  jne    L20
  movl   $0x0,(%r8)
L20:
  cmp    %ebp,%r13d
  je     L12
  jg     L67
  movslq %r13d,%r12
  add    %r14,%r12
  mov    %r12,%rbx
  lea    0x1(%r13),%eax
  mov    %eax,0xc(%rsp)
L24:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %r15,%r8
  mov    %ebp,%ecx
  mov    0xc(%rsp),%edx
  mov    %r14,%rsi
  mov    (%rsp),%rdi
  call   <permute>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  mov    %r13d,%eax
  sub    %r12d,%eax
  add    %ebx,%eax
  cmp    %eax,%ebp
  jge    L24
L67:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  cmpb   $0x30,(%r14)
  je     L67
  mov    %r14,%rdx
  mov    (%r15),%esi
  mov    (%rsp),%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L67
  mov    %r14,%rdi
  call   <strlen@plt>
  movslq (%r15),%rdx
  mov    (%rsp),%rbp
  lea    0x0(%rbp,%rdx,8),%rbx
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    (%r15),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%r15)
  cltq
  mov    0x0(%rbp,%rax,8),%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  jmp    L67
```

assistant: ```c
void permute(char **result, char *a, int l, int r, int *len) {
  int i;
  if (l == 0)
    *len = 0;
  if (l == r) {
    if (a[0] == '0')
      return;
    if (!contains(result, *len, a)) {
      result[*len] = malloc(strlen(a) + 1);
      strcpy(result[(*len)++], a);
    }
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(result, a, l + 1, r, len);
      swap((a + l), (a + i));
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  test   %edx,%edx
  jne    L20
  movl   $0x0,(%r8)
L20:
  cmp    %ebx,%edx
  je     L56
  jg     L59
  movslq %edx,%rbp
  lea    0x1(%rdx),%eax
  add    %r12,%rbp
  mov    %eax,0x8(%rsp)
  sub    %ebp,%edx
  mov    %rbp,%r15
  mov    %edx,0xc(%rsp)
L29:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x8(%rsp),%edx
  mov    %r13,%r8
  mov    %ebx,%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <permute>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r15
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  add    %r15d,%eax
  cmp    %eax,%ebx
  jge    L29
L59:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L56:
  cmpb   $0x30,(%r12)
  je     L59
  mov    0x0(%r13),%esi
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L59
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq 0x0(%r13),%rdx
  lea    0x1(%rax),%rdi
  lea    (%r14,%rdx,8),%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,(%rbx)
  movslq 0x0(%r13),%rax
  lea    0x1(%rax),%edx
  mov    (%r14,%rax,8),%rdi
  mov    %edx,0x0(%r13)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <strcpy@plt>
```

assistant: ```c
void permute(char **result, char *a, int l, int r, int *len) {
  int i;
  if (l == 0)
    *len = 0;
  if (l == r) {
    if (a[0] == '0')
      return;
    if (!contains(result, *len, a)) {
      result[*len] = malloc(strlen(a) + 1);
      strcpy(result[(*len)++], a);
    }
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(result, a, l + 1, r, len);
      swap((a + l), (a + i));
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  test   %edx,%edx
  jne    L27
  movl   $0x0,(%r8)
L27:
  cmp    %ebx,%edx
  je     L18
  jg     L43
  movslq %edx,%rbp
  lea    0x1(%rdx),%eax
  add    %r12,%rbp
  mov    %eax,0x8(%rsp)
  sub    %ebp,%edx
  mov    %rbp,%r15
  mov    %edx,0xc(%rsp)
L7:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x8(%rsp),%edx
  mov    %r13,%r8
  mov    %ebx,%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <permute>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r15
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  add    %r15d,%eax
  cmp    %ebx,%eax
  jle    L7
L43:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L18:
  cmpb   $0x30,(%r12)
  je     L43
  mov    0x0(%r13),%esi
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L43
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq 0x0(%r13),%rdx
  lea    0x1(%rax),%rdi
  lea    (%r14,%rdx,8),%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,(%rbx)
  movslq 0x0(%r13),%rax
  lea    0x1(%rax),%edx
  mov    (%r14,%rax,8),%rdi
  mov    %edx,0x0(%r13)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <strcpy@plt>
```

assistant: ```c
void permute(char **result, char *a, int l, int r, int *len) {
  int i;
  if (l == 0)
    *len = 0;
  if (l == r) {
    if (a[0] == '0')
      return;
    if (!contains(result, *len, a)) {
      result[*len] = malloc(strlen(a) + 1);
      strcpy(result[(*len)++], a);
    }
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(result, a, l + 1, r, len);
      swap((a + l), (a + i));
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: Hello World

assistant: ```c
int main() {
  printf("Hello World");
  ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: Hello World

assistant: ```c
int main() {
  printf("Hello World");
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: Hello World

assistant: ```c
int main() {
  printf("Hello World");
  ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: Hello World

assistant: ```c
int main() {
  printf("Hello World");
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x9(%rbp,%rdx,1)
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L5
  addl   $0x1,-0x10(%rbp)
L5:
  cmpl   $0x0,-0x10(%rbp)
  jle    L3
  mov    $0x0,%eax
  call   <clear_input_buff@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int get_int(void) {
  char input[1];
  int i = 0;
  do {
    input[i] = getchar();
    if (isdigit(input[i])) {
      ++i;
    }
  } while (i < 1);
  clear_input_buff();
  return (input[0] - 48);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  test   %ebp,%ebp
  jle    L2
  mov    $0x0,%eax
  call   <clear_input_buff@plt>
  lea    -0x30(%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_int(void) {
  char input[1];
  int i = 0;
  do {
    input[i] = getchar();
    if (isdigit(input[i])) {
      ++i;
    }
  } while (i < 1);
  clear_input_buff();
  return (input[0] - 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_int>:
  endbr64
  push   %rbx
  nopl   (%rax)
L3:
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L3
  xor    %eax,%eax
  call   <clear_input_buff@plt>
  lea    -0x30(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int get_int(void) {
  char input[1];
  int i = 0;
  do {
    input[i] = getchar();
    if (isdigit(input[i])) {
      ++i;
    }
  } while (i < 1);
  clear_input_buff();
  return (input[0] - 48);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_int>:
  endbr64
  push   %rbx
  nopl   (%rax)
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L9
  xor    %eax,%eax
  call   <clear_input_buff@plt>
  lea    -0x30(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int get_int(void) {
  char input[1];
  int i = 0;
  do {
    input[i] = getchar();
    if (isdigit(input[i])) {
      ++i;
    }
  } while (i < 1);
  clear_input_buff();
  return (input[0] - 48);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nmultiplier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L23
  mov    $0x0,%eax
  jmp    L3
L23:
  cmpl   $0x9,-0x4(%rbp)
  jg     L30
  mov    $0x1,%eax
  jmp    L3
L30:
  cmpl   $0x63,-0x4(%rbp)
  jg     L6
  mov    $0x2,%eax
  jmp    L3
L6:
  cmpl   $0x3e7,-0x4(%rbp)
  jg     L25
  mov    $0x3,%eax
  jmp    L3
L25:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int nmultiplier(int num) {
  if (num < 0)
    return 0;
  if (num < 10)
    return 1;
  if (num < 100)
    return 2;
  if (num < 1000)
    return 3;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nmultiplier>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L2
  mov    $0x1,%eax
  cmp    $0x9,%edi
  jle    L2
  mov    $0x2,%eax
  cmp    $0x63,%edi
  jle    L2
  cmp    $0x3e7,%edi
  setle  %al
  movzbl %al,%eax
  lea    (%rax,%rax,2),%eax
L2:
  ret
```

assistant: ```c
int nmultiplier(int num) {
  if (num < 0)
    return 0;
  if (num < 10)
    return 1;
  if (num < 100)
    return 2;
  if (num < 1000)
    return 3;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nmultiplier>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L17
  mov    $0x1,%eax
  cmp    $0x9,%edi
  jle    L17
  mov    $0x2,%eax
  cmp    $0x63,%edi
  jle    L17
  xor    %eax,%eax
  cmp    $0x3e7,%edi
  setle  %al
  lea    (%rax,%rax,2),%eax
L17:
  ret
```

assistant: ```c
int nmultiplier(int num) {
  if (num < 0)
    return 0;
  if (num < 10)
    return 1;
  if (num < 100)
    return 2;
  if (num < 1000)
    return 3;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nmultiplier>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L20
  mov    $0x1,%eax
  cmp    $0x9,%edi
  jle    L20
  mov    $0x2,%eax
  cmp    $0x63,%edi
  jle    L20
  xor    %eax,%eax
  cmp    $0x3e7,%edi
  setle  %al
  lea    (%rax,%rax,2),%eax
L20:
  ret
```

assistant: ```c
int nmultiplier(int num) {
  if (num < 0)
    return 0;
  if (num < 10)
    return 1;
  if (num < 100)
    return 2;
  if (num < 1000)
    return 3;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<evenODD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type: string
name: read_data
arguments: data_tag: D8
type: string

tool: D13: %d is even.


tool: D8: %d is odd.


assistant: ```c
void evenODD(int i) {
  if (i % 2 == 0) {
    printf("%d is even.\n", i);
  } else {
    printf("%d is odd.\n", i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<evenODD>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  test   $0x1,%dil
  jne    L1
  lea    D8(%rip),%rdi
  call   <printf@plt>
L10:
  add    $0x8,%rsp
  ret
L1:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D8: %d is even.


tool: D1: %d is odd.


assistant: ```c
void evenODD(int i) {
  if (i % 2 == 0) {
    printf("%d is even.\n", i);
  } else {
    printf("%d is odd.\n", i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<evenODD>:
  endbr64
  mov    %edi,%esi
  test   $0x1,%dil
  jne    L0
  lea    D14(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  lea    D15(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string

tool: D14: %d is even.


tool: D15: %d is odd.


assistant: ```c
void evenODD(int i) {
  if (i % 2 == 0) {
    printf("%d is even.\n", i);
  } else {
    printf("%d is odd.\n", i);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<evenODD>:
  endbr64
  mov    %edi,%esi
  test   $0x1,%dil
  jne    L6
  lea    D14(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D14: %d is even.


tool: D1: %d is odd.


assistant: ```c
void evenODD(int i) {
  if (i % 2 == 0) {
    printf("%d is even.\n", i);
  } else {
    printf("%d is odd.\n", i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L14
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <errx@plt>
L14:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <errx@plt>
L7:
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subq   $0x1,-0x8(%rbp)
  jmp    L7
L13:
  nop
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D23: usage: num string

tool: D10: num must be numeric

tool: D4: %s


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long num;
  if (argc < 3)
    errx(2, "usage: num string");
  num = strtol(argv[1], 0, 10);
  if (!num)
    errx(2, "num must be numeric");
  for (;;) {
    if (!num)
      break;
    printf("%s\n", argv[2]);
    --num;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  cmp    $0x2,%edi
  jle    L16
L44:
  mov    0x8(%rbp),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbx
  lea    D24(%rip),%r12
  test   %rax,%rax
  je     L17
L35:
  mov    0x10(%rbp),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  jne    L35
L45:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D28(%rip),%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  jmp    L44
L17:
  lea    D17(%rip),%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  jmp    L45
```

tool_calls: name: unpack_data
arguments: data_tag: D24
type: string
name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D17
type: string

tool: D24: %s


tool: D28: usage: num string

tool: D17: num must be numeric

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long num;
  if (argc < 3)
    errx(2, "usage: num string");
  num = strtol(argv[1], 0, 10);
  if (!num)
    errx(2, "num must be numeric");
  for (;;) {
    if (!num)
      break;
    printf("%s\n", argv[2]);
    --num;
  }
  return 0;
}
```