ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<HashString>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  mov    $0x0,%edx
L10:
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,8),%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
L0:
  mov    %edx,%eax
  ret
L7:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
unsigned int HashString(const char *s) {
  unsigned int ret = 0;
  while (*s != '\0') {
    ret += ((ret << 3) + (unsigned int)*s++);
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HashString>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  xchg   %ax,%ax
L7:
  lea    (%rax,%r8,8),%eax
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L7
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int HashString(const char *s) {
  unsigned int ret = 0;
  while (*s != '\0') {
    ret += ((ret << 3) + (unsigned int)*s++);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<HashString>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L5
  xchg   %ax,%ax
L14:
  lea    (%rax,%r8,8),%eax
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L14
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int HashString(const char *s) {
  unsigned int ret = 0;
  while (*s != '\0') {
    ret += ((ret << 3) + (unsigned int)*s++);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0xfffffd70,-0x28(%rbp)
  movl   $0x22,-0x24(%rbp)
  movl   $0x21,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <create_stack@plt>
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L13
L41:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <push@plt>
  addl   $0x1,-0x3c(%rbp)
L13:
  cmpl   $0x6,-0x3c(%rbp)
  jle    L41
  subl   $0x1,-0x3c(%rbp)
  jmp    L33
L17:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <first@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x30(%rbp,%rdx,4),%edx
  cmp    %edx,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  subl   $0x1,-0x3c(%rbp)
L33:
  cmpl   $0x0,-0x3c(%rbp)
  jns    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main() {
  int test_data[7] = {6, 4, -656, 34, 33, 1, 0};
  struct stack *stack = create_stack();
  int i = 0;
  for (; i < 7; ++i) {
    push(stack, test_data[i]);
  }
  for (--i; i > -1; --i) {
    printf("%d\n", first(stack));
    assert(pop(stack) == test_data[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0xfffffd70,0x8(%rsp)
  movl   $0x22,0xc(%rsp)
  movl   $0x21,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  call   <create_stack@plt>
  mov    %rax,%rbp
  mov    %rsp,%r12
  lea    0x1c(%rsp),%r13
  mov    %r12,%rbx
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <push@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L14
  lea    0x18(%rsp),%rbx
  lea    D8(%rip),%r13
L15:
  mov    %rbp,%rdi
  call   <first@plt>
  mov    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  cmp    %eax,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %r12,%rax
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: %d


assistant: ```c
int main() {
  int test_data[7] = {6, 4, -656, 34, 33, 1, 0};
  struct stack *stack = create_stack();
  int i = 0;
  for (; i < 7; ++i) {
    push(stack, test_data[i]);
  }
  for (--i; i > -1; --i) {
    printf("%d\n", first(stack));
    assert(pop(stack) == test_data[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000006,%rax
  mov    %rsp,%r12
  lea    0x4(%rsp),%rbx
  lea    0x1c(%rsp),%r13
  movl   $0x0,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x22fffffd70,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000021,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <create_stack@plt>
  mov    $0x6,%esi
  mov    %rax,%rbp
  jmp    L38
  xchg   %ax,%ax
L36:
  mov    (%rbx),%esi
  add    $0x4,%rbx
L38:
  mov    %rbp,%rdi
  call   <push@plt>
  cmp    %r13,%rbx
  jne    L36
  lea    0x18(%rsp),%rbx
  lea    D6(%rip),%r13
  nop
L16:
  mov    %rbp,%rdi
  call   <first@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  xor    %edi,%edi
  cmp    %eax,(%rbx)
  sete   %dil
  call   <assert@plt>
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %r12,%rax
  jne    L16
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main() {
  int test_data[7] = {6, 4, -656, 34, 33, 1, 0};
  struct stack *stack = create_stack();
  int i = 0;
  for (; i < 7; ++i) {
    push(stack, test_data[i]);
  }
  for (--i; i > -1; --i) {
    printf("%d\n", first(stack));
    assert(pop(stack) == test_data[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movdqa D23(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rsp,%r12
  lea    0x1c(%rsp),%r13
  movl   $0x0,0x18(%rsp)
  mov    %r12,%rbx
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <create_stack@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <push@plt>
  cmp    %r13,%rbx
  jne    L2
  lea    0x18(%rsp),%rbx
  lea    D7(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  call   <first@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  xor    %edi,%edi
  cmp    %eax,(%rbx)
  sete   %dil
  call   <assert@plt>
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %r12,%rax
  jne    L4
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
data_type: byte[16]
name: unpack_data
arguments: tag: D3
data_type: byte[8]
name: unpack_data
arguments: tag: D7
data_type: string

tool: {"D23": [0x06,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x70,0xfd,0xff,0xff,0x22,0x00,0x00,0x00]}

tool: {"D3": [0x21,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D7: %d


assistant: ```c
int main() {
  int test_data[7] = {6, 4, -656, 34, 33, 1, 0};
  struct stack *stack = create_stack();
  int i = 0;
  for (; i < 7; ++i) {
    push(stack, test_data[i]);
  }
  for (--i; i > -1; --i) {
    printf("%d\n", first(stack));
    assert(pop(stack) == test_data[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L23
L40:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L42
L27:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L42:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L27
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
data_type: string
name: read_data
arguments: label: D38
data_type: string
name: read_data
arguments: label: D17
data_type: string

tool: D7: %d

tool: D38: %d%d

tool: D17: %d %d


assistant: ```c
int main(void) {
  int N;
  scanf("%d", &N);
  while (N-- > 0) {
    int L, M;
    scanf("%d%d", &L, &M);
    int x = 0, y = 0, i;
    for (i = 0; i < M; i++) {
      int a;
      scanf("%d", &a);
      x = max(x, min(a, L - a));
      y = max(y, max(a, L - a));
    }
    printf("%d %d\n", x, y);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jle    L18
  lea    0x10(%rsp),%r15
  lea    D38(%rip),%r14
  lea    D9(%rip),%r13
L25:
  lea    0xc(%rsp),%rsi
  mov    %r15,%rdx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x10(%rsp)
  jle    L1
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L32:
  lea    0x14(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  mov    0xc(%rsp),%esi
  sub    %edi,%esi
  call   <min@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <max@plt>
  mov    %eax,%ebx
  mov    0x14(%rsp),%edi
  mov    0xc(%rsp),%esi
  sub    %edi,%esi
  call   <max@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <max@plt>
  mov    %eax,%ebp
  add    $0x1,%r12d
  cmp    %r12d,0x10(%rsp)
  jg     L32
L29:
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jg     L25
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L29
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D9: %d

tool: D38: %d%d

tool: D7: %d %d


assistant: ```c
int main(void) {
  int N;
  scanf("%d", &N);
  while (N-- > 0) {
    int L, M;
    scanf("%d%d", &L, &M);
    int x = 0, y = 0, i;
    for (i = 0; i < M; i++) {
      int a;
      scanf("%d", &a);
      x = max(x, min(a, L - a));
      y = max(y, max(a, L - a));
    }
    printf("%d %d\n", x, y);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jle    L54
  lea    0x1c(%rsp),%rax
  lea    0x20(%rsp),%r15
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L41:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jle    L53
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    0x24(%rsp),%rbx
  xor    %ebp,%ebp
  nop
L59:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0x24(%rsp),%edi
  mov    0x1c(%rsp),%esi
  sub    %edi,%esi
  call   <min@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <max@plt>
  mov    0x24(%rsp),%edi
  mov    0x1c(%rsp),%esi
  mov    %eax,%ebp
  sub    %edi,%esi
  call   <max@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <max@plt>
  mov    %eax,%r13d
  cmp    %r14d,0x20(%rsp)
  jg     L59
L15:
  mov    %r13d,%edx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jg     L41
L54:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  jmp    L15
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D6: %d

tool: D13: %d%d

tool: D8: %d %d


assistant: ```c
int main(void) {
  int N;
  scanf("%d", &N);
  while (N-- > 0) {
    int L, M;
    scanf("%d%d", &L, &M);
    int x = 0, y = 0, i;
    for (i = 0; i < M; i++) {
      int a;
      scanf("%d", &a);
      x = max(x, min(a, L - a));
      y = max(y, max(a, L - a));
    }
    printf("%d %d\n", x, y);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jle    L32
  lea    0x1c(%rsp),%rax
  lea    0x20(%rsp),%r15
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L23:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    0x24(%rsp),%rbx
  xor    %ebp,%ebp
  nop
L26:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0x24(%rsp),%edi
  mov    0x1c(%rsp),%esi
  sub    %edi,%esi
  call   <min@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <max@plt>
  mov    0x24(%rsp),%edi
  mov    0x1c(%rsp),%esi
  mov    %eax,%ebp
  sub    %edi,%esi
  call   <max@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <max@plt>
  mov    %eax,%r13d
  cmp    %r14d,0x20(%rsp)
  jg     L26
L19:
  mov    %r13d,%edx
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jg     L23
L32:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  jmp    L19
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
data_type: string
name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D23
data_type: string

tool: D24: %d

tool: D3: %d%d

tool: D23: %d %d


assistant: ```c
int main(void) {
  int N;
  scanf("%d", &N);
  while (N-- > 0) {
    int L, M;
    scanf("%d%d", &L, &M);
    int x = 0, y = 0, i;
    for (i = 0; i < M; i++) {
      int a;
      scanf("%d", &a);
      x = max(x, min(a, L - a));
      y = max(y, max(a, L - a));
    }
    printf("%d %d\n", x, y);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__SubStrings__Copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%ebx
  jmp    L3
L13:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
  add    $0x1,%ebx
L3:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L6
  mov    -0xc(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%ebx
  jb     L13
L6:
  movb   $0x0,(%rax)
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned __SubStrings__Copy(register char *Dest, register const char *Source, unsigned Max) {
  register unsigned Inc = 0;
  for (; *Source != '\0' && Inc < Max - 1; ++Inc)
    *Dest++ = *Source++;
  *Dest = '\0';
  return Inc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__SubStrings__Copy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L13
  cmp    $0x1,%edx
  je     L39
  lea    -0x2(%rdx),%edx
  add    $0x2,%rdx
  mov    $0x1,%eax
L37:
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  mov    %eax,%r8d
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L51
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L37
L51:
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
L13:
  mov    $0x0,%r8d
  jmp    L51
L39:
  mov    $0x0,%r8d
  jmp    L51
```

assistant: ```c
unsigned __SubStrings__Copy(register char *Dest, register const char *Source, unsigned Max) {
  register unsigned Inc = 0;
  for (; *Source != '\0' && Inc < Max - 1; ++Inc)
    *Dest++ = *Source++;
  *Dest = '\0';
  return Inc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__SubStrings__Copy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L5
  cmp    $0x1,%edx
  je     L5
  sub    $0x2,%edx
  mov    $0x1,%eax
  add    $0x2,%rdx
  jmp    L43
  xchg   %ax,%ax
L15:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L21
L43:
  mov    %cl,(%rdi)
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rdi
  mov    %eax,%r8d
  test   %cl,%cl
  jne    L15
L21:
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %r8d,%r8d
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned __SubStrings__Copy(register char *Dest, register const char *Source, unsigned Max) {
  register unsigned Inc = 0;
  for (; *Source != '\0' && Inc < Max - 1; ++Inc)
    *Dest++ = *Source++;
  *Dest = '\0';
  return Inc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__SubStrings__Copy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L48
  cmp    $0x1,%edx
  je     L48
  sub    $0x2,%edx
  mov    $0x1,%eax
  add    $0x2,%rdx
  jmp    L25
  xchg   %ax,%ax
L23:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L7
L25:
  mov    %cl,(%rdi)
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rdi
  mov    %eax,%r8d
  test   %cl,%cl
  jne    L23
L7:
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L48:
  xor    %r8d,%r8d
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned __SubStrings__Copy(register char *Dest, register const char *Source, unsigned Max) {
  register unsigned Inc = 0;
  for (; *Source != '\0' && Inc < Max - 1; ++Inc)
    *Dest++ = *Source++;
  *Dest = '\0';
  return Inc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smash_tilde>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L19
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jne    L38
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  movb   $0x60,(%rax)
L1:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  nop
  pop    %rbp
  ret
```

assistant: ```c
void smash_tilde(char *str) {
  for (; *str != '\0'; str++) {
    if (*str == '~')
      *str = '-';
    if (*str == '\'')
      *str = '`';
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<smash_tilde>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L38
L15:
  ret
L22:
  movb   $0x2d,(%rdi)
L47:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
L38:
  cmp    $0x7e,%al
  je     L22
  cmpb   $0x27,(%rdi)
  jne    L47
  movb   $0x60,(%rdi)
  jmp    L47
```

assistant: ```c
void smash_tilde(char *str) {
  for (; *str != '\0'; str++) {
    if (*str == '~')
      *str = '-';
    if (*str == '\'')
      *str = '`';
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smash_tilde>:
  endbr64
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L12:
  cmpb   $0x27,(%rdi)
  jne    L17
  movb   $0x60,(%rdi)
L17:
  add    $0x1,%rdi
L22:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L40
  cmp    $0x7e,%al
  jne    L12
  movb   $0x2d,(%rdi)
  jmp    L17
  nopl   0x0(%rax)
L40:
  ret
```

assistant: ```c
void smash_tilde(char *str) {
  for (; *str != '\0'; str++) {
    if (*str == '~')
      *str = '-';
    if (*str == '\'')
      *str = '`';
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smash_tilde>:
  endbr64
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L29:
  cmpb   $0x27,(%rdi)
  jne    L45
  movb   $0x60,(%rdi)
L45:
  add    $0x1,%rdi
L25:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L40
  cmp    $0x7e,%al
  jne    L29
  movb   $0x2d,(%rdi)
  jmp    L45
  nopl   0x0(%rax)
L40:
  ret
```

assistant: ```c
void smash_tilde(char *str) {
  for (; *str != '\0'; str++) {
    if (*str == '~')
      *str = '-';
    if (*str == '\'')
      *str = '`';
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_2_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x20,-0x20(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <scan_for_intN@plt>
  mov    %eax,-0x1c(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L6:
  cmpq   $0x0,-0x38(%rbp)
  je     L26
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L26:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int str_2_int(const char *_str, int *ret_, const char **end_) {
  long long ret;
  const char *end;
  int N = sizeof(unsigned int) * 8;
  int b_err = scan_for_intN(_str, N, &ret, &end);
  if (ret_) {
    *ret_ = (int)ret;
  }
  if (end_) {
    *end_ = end;
  }
  return b_err;
}
```