user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L108:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L108
  sub    $0xdf0,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x9de8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%r8d
  test   %r8d,%r8d
  jle    L130
  mov    0xc(%rsp),%eax
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D7(%rip),%r12
  test   %eax,%eax
  jle    L118
  nopl   0x0(%rax,%rax,1)
L127:
  lea    0x1a0(%rsp,%r14,4),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L44
  mov    0x8(%rsp),%r8d
  add    $0x1,%r13d
  cmp    %r8d,%r13d
  jge    L176
  add    $0x64,%r14
  test   %eax,%eax
  jg     L127
L118:
  add    $0x1,%r13d
  cmp    %r8d,%r13d
  jge    L176
  lea    0x10(%rsp),%rbp
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
L4:
  mov    0xc(%rsp),%r10d
  mov    %rbp,%rsi
  lea    0x1a0(%rsp),%r9
  xor    %edi,%edi
  mov    %r10d,%eax
  mov    %r10d,%r11d
  lea    -0x1(%r10),%r12d
  shr    $0x2,%eax
  and    $0xfffffffc,%r11d
  lea    -0x1(%rax),%ebx
  add    $0x1,%rbx
  shl    $0x4,%rbx
  nopl   0x0(%rax,%rax,1)
L53:
  test   %r10d,%r10d
  jle    L153
  mov    (%rsi),%edx
  cmp    $0x2,%r12d
  jbe    L231
  lea    (%rbx,%r9,1),%rcx
  mov    %r9,%rax
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax,%rax,1)
L163:
  paddd  (%rax),%xmm0
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L163
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%edx
  mov    %r11d,%eax
  cmp    %r10d,%r11d
  je     L173
L239:
  movslq %edi,%rcx
  movslq %eax,%r13
  lea    (%rcx,%rcx,4),%rcx
  lea    (%rcx,%rcx,4),%rcx
  shl    $0x2,%rcx
  add    %rcx,%r13
  add    0x1a0(%rsp,%r13,4),%edx
  lea    0x1(%rax),%r13d
  cmp    %r10d,%r13d
  jge    L173
  movslq %r13d,%r13
  add    $0x2,%eax
  add    %rcx,%r13
  add    0x1a0(%rsp,%r13,4),%edx
  cmp    %eax,%r10d
  jle    L173
  cltq
  add    %rax,%rcx
  add    0x1a0(%rsp,%rcx,4),%edx
L173:
  mov    %edx,(%rsi)
L153:
  add    $0x1,%edi
  add    $0x4,%rsi
  add    $0x190,%r9
  cmp    %r8d,%edi
  jne    L53
L213:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  lea    D6(%rip),%r13
  xor    %ebx,%ebx
  call   <maxs@plt>
  mov    %eax,%r12d
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L238
  nopl   (%rax)
L34:
  mov    %ebx,%esi
  cmp    %r12d,0x0(%rbp,%rbx,4)
  je     L191
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L34
L238:
  mov    0x9de8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x9df0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L191:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L34
  jmp    L238
L231:
  xor    %eax,%eax
  jmp    L239
L130:
  lea    0x10(%rsp),%rbp
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L213
L176:
  lea    0x10(%rsp),%rbp
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r8d,%r8d
  jg     L4
  jmp    L213
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D6
datatype: string

tool: D13: %d %d

tool: D7: %d

tool: D6: %d 

assistant: ```c
int main() {
  int n, m, i, j;
  scanf("%d %d", &n, &m);
  int a[100][100];
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++)
      scanf("%d", &a[i][j]);
  }
  int sum[100];
  for (j = 0; j < 100; j++)
    sum[j] = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++)
      sum[i] = sum[i] + a[i][j];
  }
  int max = maxs(sum, n);
  for (j = 0; j < n; j++) {
    if (sum[j] == max)
      printf("%d ", j);
  }
  return 0;
}
```