user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D24(%rip),%rdi
  lea    D10(%rip),%r15
  push   %r14
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  push   %rbp
  lea    D32(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jg     L10
  jmp    L77
  nopl   0x0(%rax)
L66:
  lea    D59(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jle    L77
L10:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x10(%rsp)
  je     L66
  mov    $0x9,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    0x10(%rsp),%r14
  cmp    %r14,%rax
  jle    L107
L58:
  mov    $0x9,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    $0x6,%esi
  mov    $0xa,%edi
  mov    %rax,%r8
  mov    %r14,%rax
  cqto
  idiv   %r8
  mov    %rdx,0x10(%rsp)
  call   <pow@plt>
  mov    0x10(%rsp),%r14
  cmp    %r14,%rax
  jle    L17
L6:
  mov    $0x6,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    $0x3,%esi
  mov    $0xa,%edi
  mov    %rax,%r8
  mov    %r14,%rax
  cqto
  idiv   %r8
  mov    %rdx,0x10(%rsp)
  call   <pow@plt>
  mov    0x10(%rsp),%r14
  cmp    %r14,%rax
  jle    L96
L64:
  mov    $0x3,%esi
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r14,%rax
  cqto
  idiv   %r8
  mov    %rdx,%rdi
  mov    %rdx,0x10(%rsp)
  call   <num@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L10
L77:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L107:
  mov    $0x9,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r14,%rax
  cqto
  idiv   %r8
  mov    %rax,%rdi
  call   <num@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%r14
  jmp    L58
L96:
  mov    $0x3,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r14,%rax
  cqto
  idiv   %r8
  mov    %rax,%rdi
  call   <num@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%r14
  jmp    L64
  nopl   0x0(%rax)
L17:
  mov    $0x6,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r14,%rax
  cqto
  idiv   %r8
  mov    %rax,%rdi
  call   <num@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%r14
  jmp    L6
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D39
type: string
name: extract_symbolic_data
arguments: data_tag: D32
type: string
name: extract_symbolic_data
arguments: data_tag: D59
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D37
type: string

tool: D24: %d

tool: D10: Thousand 

tool: D39: 


tool: D32: %Ld

tool: D59: Zero


tool: D16: Billion 

tool: D37: Million 

assistant: ```c
int main() {
  int t, i, j;
  long long n;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%Ld", &n);
    if (n == 0)
      printf("Zero\n");
    else {
      if (n >= pow(10, 9)) {
        num(n / (long long)pow(10, 9));
        printf("Billion ");
      }
      n = n % (long long)pow(10, 9);
      if (n >= pow(10, 6)) {
        num(n / (long long)pow(10, 6));
        printf("Million ");
      }
      n = n % (long long)pow(10, 6);
      if (n >= pow(10, 3)) {
        num(n / (long long)pow(10, 3));
        printf("Thousand ");
      }
      n = n % (long long)pow(10, 3);
      num(n);
      printf("\n");
    }
  }
  return 0;
}
```