ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ast_type_needs_children>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D1(%rip),%rbx
  lea    0x38(%rbx),%r12
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ast_type_needs_children(const char *type) {
  static const char *const partypes[] = {"block", "program", "call", "vardecl", "constdecl", "array", "hashmap"};
  size_t i;
  for (i = 0; i < (sizeof(partypes) / sizeof(partypes[0])); i++) {
    if (strcmp(type, partypes[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_createGenericNetlinkSocket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    (%rax),%ecx
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x24(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int _createGenericNetlinkSocket(void) {
  int socketFd;
  socketFd = socket(AF_NETLINK, SOCK_RAW, NETLINK_GENERIC);
  struct sockaddr_nl srcAddr;
  memset(&srcAddr, 0, sizeof(srcAddr));
  srcAddr.nl_family = AF_NETLINK;
  srcAddr.nl_pid = getpid();
  srcAddr.nl_groups = 0;
  bind(socketFd, (struct sockaddr *)&srcAddr, sizeof(srcAddr));
  return socketFd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_createGenericNetlinkSocket>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D24(%rip),%r12
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D29(%rip),%rax
  mov    (%rax),%esi
  mov    (%r12),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  mov    %rsp,%rbp
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r12),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _createGenericNetlinkSocket(void) {
  int socketFd;
  socketFd = socket(AF_NETLINK, SOCK_RAW, NETLINK_GENERIC);
  struct sockaddr_nl srcAddr;
  memset(&srcAddr, 0, sizeof(srcAddr));
  srcAddr.nl_family = AF_NETLINK;
  srcAddr.nl_pid = getpid();
  srcAddr.nl_groups = 0;
  bind(socketFd, (struct sockaddr *)&srcAddr, sizeof(srcAddr));
  return socketFd;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_createGenericNetlinkSocket>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D16(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %rsp,%rbp
  mov    (%rbx),%edi
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  xor    %esi,%esi
  mov    $0x10,%edx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  call   <getpid@plt>
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,0x8(%rsp)
  movq   $0x0,(%rsp)
  call   <bind@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _createGenericNetlinkSocket(void) {
  int socketFd;
  socketFd = socket(AF_NETLINK, SOCK_RAW, NETLINK_GENERIC);
  struct sockaddr_nl srcAddr;
  memset(&srcAddr, 0, sizeof(srcAddr));
  srcAddr.nl_family = AF_NETLINK;
  srcAddr.nl_pid = getpid();
  srcAddr.nl_groups = 0;
  bind(socketFd, (struct sockaddr *)&srcAddr, sizeof(srcAddr));
  return socketFd;
}
```
user: What is the c source code of the assembly code below?

```asm
<_createGenericNetlinkSocket>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D13(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  mov    %rsp,%rbp
  mov    (%rbx),%edi
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  xor    %esi,%esi
  mov    $0x10,%edx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  call   <getpid@plt>
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,0x8(%rsp)
  movq   $0x0,(%rsp)
  call   <bind@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _createGenericNetlinkSocket(void) {
  int socketFd;
  socketFd = socket(AF_NETLINK, SOCK_RAW, NETLINK_GENERIC);
  struct sockaddr_nl srcAddr;
  memset(&srcAddr, 0, sizeof(srcAddr));
  srcAddr.nl_family = AF_NETLINK;
  srcAddr.nl_pid = getpid();
  srcAddr.nl_groups = 0;
  bind(socketFd, (struct sockaddr *)&srcAddr, sizeof(srcAddr));
  return socketFd;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cstring_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int cstring_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cstring_cmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cstring_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cstring_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cstring_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cstring_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cstring_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <put_str@plt>
  mov    $0x0,%eax
  call   <idt_init@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: init_all


assistant: ```c
void init_all() {
  put_str("init_all\n");
  idt_init();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_all>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <put_str@plt>
  mov    $0x0,%eax
  call   <idt_init@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: init_all


assistant: ```c
void init_all() {
  put_str("init_all\n");
  idt_init();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<init_all>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <put_str@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <idt_init@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: init_all


assistant: ```c
void init_all() {
  put_str("init_all\n");
  idt_init();
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_all>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <put_str@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <idt_init@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D5: init_all


assistant: ```c
void init_all() {
  put_str("init_all\n");
  idt_init();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
L1:
  lea    -0x13(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L118
  mov    $0xffffffff,%eax
  jmp    L89
L118:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  cmp    $0x3a,%al
  je     L62
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  jne    L34
L62:
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x0,-0x13(%rbp,%rax,1)
  nop
  mov    D26(%rip),%rax
  movq   $0x0,(%rax)
  lea    -0x13(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L23
  jmp    L82
L34:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L113
  mov    $0xfffffffe,%eax
  jmp    L89
L113:
  addl   $0x1,-0x18(%rbp)
  cmpl   $0xa,-0x18(%rbp)
  jle    L1
  mov    $0xfffffffd,%eax
  jmp    L89
L82:
  mov    $0xfffffffc,%eax
  jmp    L89
L23:
  mov    $0x0,%eax
L89:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L100
  call   <__stack_chk_fail@plt>
L100:
  leave
  ret
```

assistant: ```c
int parse_int(int fd, int *val) {
  char number[11];
  int character = 0;
  while (1) {
    if (read(fd, &number[character], 1) < 1)
      return -1;
    if (number[character] == ':' || number[character] == '\n') {
      number[character] = '\0';
      break;
    }
    if (!isdigit(number[character]))
      return -2;
    character++;
    if (character > 10)
      return -3;
  };
  errno = 0;
  *val = strtol(number, NULL, 10);
  if (errno == ERANGE)
    return -4;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0xd(%rsp),%rbp
L73:
  mov    %ebx,%r14d
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L66
  movzbl (%rbx,%rbp,1),%edi
  cmp    $0x3a,%dil
  je     L16
  cmp    $0xa,%dil
  je     L16
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L46
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L73
  mov    $0xfffffffd,%eax
L72:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  movslq %r14d,%r14
  movb   $0x0,0xd(%rsp,%r14,1)
  mov    D16(%rip),%rbx
  movq   $0x0,(%rbx)
  lea    0xd(%rsp),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %al
  movzbl %al,%eax
  lea    -0x4(,%rax,4),%eax
  jmp    L72
L66:
  mov    $0xffffffff,%eax
  jmp    L72
L46:
  mov    $0xfffffffe,%eax
  jmp    L72
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_int(int fd, int *val) {
  char number[11];
  int character = 0;
  while (1) {
    if (read(fd, &number[character], 1) < 1)
      return -1;
    if (number[character] == ':' || number[character] == '\n') {
      number[character] = '\0';
      break;
    }
    if (!isdigit(number[character]))
      return -2;
    character++;
    if (character > 10)
      return -3;
  };
  errno = 0;
  *val = strtol(number, NULL, 10);
  if (errno == ERANGE)
    return -4;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_int>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbp
  nopl   (%rax)
L63:
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  movslq %ebx,%r14
  call   <read@plt>
  test   %eax,%eax
  jle    L60
  movsbl 0x0(%rbp,%rbx,1),%edi
  cmp    $0x3a,%dil
  je     L56
  cmp    $0xa,%dil
  je     L56
  call   <isdigit@plt>
  test   %eax,%eax
  je     L73
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L63
  mov    $0xfffffffd,%eax
L83:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  mov    $0xffffffff,%eax
  jmp    L83
  nop
L56:
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  movb   $0x0,0xd(%rsp,%r14,1)
  mov    D6(%rip),%rbx
  movq   $0x0,(%rbx)
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %al
  movzbl %al,%eax
  lea    -0x4(,%rax,4),%eax
  jmp    L83
  nopl   0x0(%rax,%rax,1)
L73:
  mov    $0xfffffffe,%eax
  jmp    L83
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_int(int fd, int *val) {
  char number[11];
  int character = 0;
  while (1) {
    if (read(fd, &number[character], 1) < 1)
      return -1;
    if (number[character] == ':' || number[character] == '\n') {
      number[character] = '\0';
      break;
    }
    if (!isdigit(number[character]))
      return -2;
    character++;
    if (character > 10)
      return -3;
  };
  errno = 0;
  *val = strtol(number, NULL, 10);
  if (errno == ERANGE)
    return -4;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_int>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbp
  nopl   (%rax)
L59:
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  movslq %ebx,%r14
  call   <read@plt>
  test   %eax,%eax
  jle    L31
  movsbl 0x0(%rbp,%rbx,1),%edi
  cmp    $0x3a,%dil
  je     L25
  cmp    $0xa,%dil
  je     L25
  call   <isdigit@plt>
  test   %eax,%eax
  je     L28
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L59
  mov    $0xfffffffd,%eax
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    $0xffffffff,%eax
  jmp    L11
  nop
L25:
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  movb   $0x0,0xd(%rsp,%r14,1)
  mov    D10(%rip),%rbx
  movq   $0x0,(%rbx)
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %al
  movzbl %al,%eax
  lea    -0x4(,%rax,4),%eax
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0xfffffffe,%eax
  jmp    L11
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_int(int fd, int *val) {
  char number[11];
  int character = 0;
  while (1) {
    if (read(fd, &number[character], 1) < 1)
      return -1;
    if (number[character] == ':' || number[character] == '\n') {
      number[character] = '\0';
      break;
    }
    if (!isdigit(number[character]))
      return -2;
    character++;
    if (character > 10)
      return -3;
  };
  errno = 0;
  *val = strtol(number, NULL, 10);
  if (errno == ERANGE)
    return -4;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<newgap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L20
  mov    $0x1,%eax
  jmp    L35
L20:
  cmpl   $0x9,-0x4(%rbp)
  je     L5
  cmpl   $0xa,-0x4(%rbp)
  je     L5
  mov    -0x4(%rbp),%eax
  jmp    L35
L5:
  mov    $0xb,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap < 1)
    return 1;
  return (gap == 9 || gap == 10) ? 11 : gap;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<newgap>:
  endbr64
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
  mov    $0x1,%edx
  cmp    $0xc,%eax
  jle    L0
  movslq %eax,%rcx
  imul   $0x4ec4ec4f,%rcx,%rcx
  sar    $0x22,%rcx
  sar    $0x1f,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  sub    $0x9,%edx
  sub    %eax,%ecx
  cmp    $0x1,%edx
  mov    $0xb,%edx
  cmova  %ecx,%edx
L0:
  mov    %edx,%eax
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap < 1)
    return 1;
  return (gap == 9 || gap == 10) ? 11 : gap;
}
```
user: What is the c source code of the assembly code below:

```asm
<newgap>:
  endbr64
  lea    (%rdi,%rdi,4),%edx
  mov    $0x1,%eax
  add    %edx,%edx
  cmp    $0xc,%edx
  jle    L4
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%edx
  mov    $0xb,%edx
  cmovbe %edx,%eax
L4:
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap < 1)
    return 1;
  return (gap == 9 || gap == 10) ? 11 : gap;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<newgap>:
  endbr64
  lea    (%rdi,%rdi,4),%edx
  mov    $0x1,%eax
  add    %edx,%edx
  cmp    $0xc,%edx
  jle    L5
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%edx
  mov    $0xb,%edx
  cmovbe %edx,%eax
L5:
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap < 1)
    return 1;
  return (gap == 9 || gap == 10) ? 11 : gap;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hex2dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L17:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <c2i@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L17
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hex2dec(char *hex) {
  int len;
  int num = 0;
  int temp;
  int bits;
  int i;
  len = strlen(hex);
  for (i = 0, temp = 0; i < len; i++, temp = 0) {
    temp = c2i(*(hex + i));
    bits = (len - i - 1) * 4;
    temp = temp << bits;
    num = num | temp;
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2dec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L7
  mov    %r12,%rbx
  sub    $0x1,%eax
  lea    0x0(,%rax,4),%ebp
  mov    %eax,%eax
  lea    0x1(%r12,%rax,1),%r13
  mov    $0x0,%r12d
L23:
  movsbl (%rbx),%edi
  call   <c2i@plt>
  mov    %ebp,%ecx
  shl    %cl,%eax
  or     %eax,%r12d
  add    $0x1,%rbx
  sub    $0x4,%ebp
  cmp    %r13,%rbx
  jne    L23
L5:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    $0x0,%r12d
  jmp    L5
```

assistant: ```c
int hex2dec(char *hex) {
  int len;
  int num = 0;
  int temp;
  int bits;
  int i;
  len = strlen(hex);
  for (i = 0, temp = 0; i < len; i++, temp = 0) {
    temp = c2i(*(hex + i));
    bits = (len - i - 1) * 4;
    temp = temp << bits;
    num = num | temp;
  }
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hex2dec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L8
  sub    $0x1,%eax
  xor    %r12d,%r12d
  lea    0x0(,%rax,4),%ebp
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax)
L17:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <c2i@plt>
  mov    %ebp,%ecx
  sub    $0x4,%ebp
  shl    %cl,%eax
  or     %eax,%r12d
  cmp    %r13,%rbx
  jne    L17
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hex2dec(char *hex) {
  int len;
  int num = 0;
  int temp;
  int bits;
  int i;
  len = strlen(hex);
  for (i = 0, temp = 0; i < len; i++, temp = 0) {
    temp = c2i(*(hex + i));
    bits = (len - i - 1) * 4;
    temp = temp << bits;
    num = num | temp;
  }
  return num;
}
```
user: What is the c source code of the assembly code below?

```asm
<hex2dec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L6
  sub    $0x1,%eax
  xor    %r12d,%r12d
  lea    0x0(,%rax,4),%ebp
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax)
L16:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <c2i@plt>
  mov    %ebp,%ecx
  sub    $0x4,%ebp
  shl    %cl,%eax
  or     %eax,%r12d
  cmp    %r13,%rbx
  jne    L16
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L6:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hex2dec(char *hex) {
  int len;
  int num = 0;
  int temp;
  int bits;
  int i;
  len = strlen(hex);
  for (i = 0, temp = 0; i < len; i++, temp = 0) {
    temp = c2i(*(hex + i));
    bits = (len - i - 1) * 4;
    temp = temp << bits;
    num = num | temp;
  }
  return num;
}
```