ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  mov    $0xe10,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  movl   $0x3c,0x14(%rsp)
  movq   $0x1,0x18(%rsp)
  call   <scanf@plt>
  test   %rbp,%rbp
  jne    L36
L38:
  mov    0xc(%rsp),%eax
  mov    %r12,%rdi
  cltd
  idiv   %ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  mov    0x4(%r13),%ebx
  mov    %edx,0xc(%rsp)
L21:
  add    $0x1,%rbp
  test   %rbp,%rbp
  je     L38
L36:
  mov    $0x3a,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  mov    %r12,%rdi
  cltd
  idiv   %ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  mov    0x4(%r13,%rbp,4),%ebx
  mov    %edx,0xc(%rsp)
  test   %ebx,%ebx
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: %d

assistant: ```c
int main(void) {
  int segundos;
  int medidas[] = {3600, 60, 1, 0};
  int i = 0;
  scanf("%d", &segundos);
  while (medidas[i] != 0) {
    if (i != 0)
      printf(":");
    printf("%d", segundos / medidas[i]);
    segundos = segundos % medidas[i];
    i++;
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  mov    $0xe10,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0x1c(%rsp)
  lea    0x10(%rsp),%r13
  mov    %rax,0x14(%rsp)
  call   <scanf@plt>
  test   %rbp,%rbp
  jne    L34
L14:
  mov    0xc(%rsp),%eax
  mov    %r12,%rdi
  cltd
  idiv   %ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  mov    0x4(%r13),%ebx
  mov    %edx,0xc(%rsp)
L22:
  add    $0x1,%rbp
  test   %rbp,%rbp
  je     L14
L34:
  mov    $0x3a,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  mov    %r12,%rdi
  cltd
  idiv   %ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  mov    0x4(%r13,%rbp,4),%ebx
  mov    %edx,0xc(%rsp)
  test   %ebx,%ebx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: byte[8]

tool: D9: %d

tool: {"D1": [0x3c,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int segundos;
  int medidas[] = {3600, 60, 1, 0};
  int i = 0;
  scanf("%d", &segundos);
  while (medidas[i] != 0) {
    if (i != 0)
      printf(":");
    printf("%d", segundos / medidas[i]);
    segundos = segundos % medidas[i];
    i++;
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<av_resample>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzwl (%rax),%eax
  cwtl
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int av_resample(int filter_length, short *src, short *filter) {
  int i;
  int val = 0;
  for (i = 0; i < filter_length; i++)
    val += src[i] * filter[i];
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<av_resample>:
  endbr64
  test   %edi,%edi
  jle    L24
  mov    %edi,%edi
  mov    $0x0,%eax
  mov    $0x0,%r8d
L27:
  movswl (%rsi,%rax,2),%ecx
  movswl (%rdx,%rax,2),%r9d
  imul   %r9d,%ecx
  add    %ecx,%r8d
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L27
L6:
  mov    %r8d,%eax
  ret
L24:
  mov    $0x0,%r8d
  jmp    L6
```

assistant: ```c
int av_resample(int filter_length, short *src, short *filter) {
  int i;
  int val = 0;
  for (i = 0; i < filter_length; i++)
    val += src[i] * filter[i];
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<av_resample>:
  endbr64
  test   %edi,%edi
  jle    L19
  movslq %edi,%rdi
  xor    %eax,%eax
  xor    %r8d,%r8d
L17:
  movswl (%rsi,%rax,2),%ecx
  movswl (%rdx,%rax,2),%r9d
  add    $0x1,%rax
  imul   %r9d,%ecx
  add    %ecx,%r8d
  cmp    %rax,%rdi
  jne    L17
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int av_resample(int filter_length, short *src, short *filter) {
  int i;
  int val = 0;
  for (i = 0; i < filter_length; i++)
    val += src[i] * filter[i];
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<av_resample>:
  endbr64
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L42
  lea    -0x1(%rdi),%eax
  cmp    $0x6,%eax
  jbe    L50
  mov    %edi,%esi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  shr    $0x3,%esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L47:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rdx,%rax,1),%xmm2
  add    $0x10,%rax
  pmaddwd %xmm2,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L47
  movdqa %xmm1,%xmm0
  mov    %edi,%r8d
  psrldq $0x8,%xmm0
  and    $0xfffffff8,%r8d
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x7,%dil
  je     L23
L62:
  movslq %r8d,%r10
  movswl (%rcx,%r10,2),%r9d
  lea    (%r10,%r10,1),%rsi
  movswl (%rdx,%r10,2),%r10d
  imul   %r10d,%r9d
  add    %r9d,%eax
  lea    0x1(%r8),%r9d
  cmp    %r9d,%edi
  jle    L78
  movswl 0x2(%rcx,%rsi,1),%r9d
  movswl 0x2(%rdx,%rsi,1),%r10d
  imul   %r10d,%r9d
  add    %r9d,%eax
  lea    0x2(%r8),%r9d
  cmp    %r9d,%edi
  jle    L78
  movswl 0x4(%rcx,%rsi,1),%r9d
  movswl 0x4(%rdx,%rsi,1),%r10d
  imul   %r10d,%r9d
  add    %r9d,%eax
  lea    0x3(%r8),%r9d
  cmp    %r9d,%edi
  jle    L78
  movswl 0x6(%rcx,%rsi,1),%r9d
  movswl 0x6(%rdx,%rsi,1),%r10d
  imul   %r10d,%r9d
  add    %r9d,%eax
  lea    0x4(%r8),%r9d
  cmp    %r9d,%edi
  jle    L78
  movswl 0x8(%rcx,%rsi,1),%r9d
  movswl 0x8(%rdx,%rsi,1),%r10d
  imul   %r10d,%r9d
  add    %r9d,%eax
  lea    0x5(%r8),%r9d
  cmp    %r9d,%edi
  jle    L78
  movswl 0xa(%rcx,%rsi,1),%r9d
  movswl 0xa(%rdx,%rsi,1),%r10d
  add    $0x6,%r8d
  imul   %r10d,%r9d
  add    %r9d,%eax
  cmp    %r8d,%edi
  jle    L78
  movswl 0xc(%rdx,%rsi,1),%edx
  movswl 0xc(%rcx,%rsi,1),%ecx
  imul   %ecx,%edx
  add    %edx,%eax
  ret
  nop
L42:
  xor    %eax,%eax
L78:
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  ret
L50:
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L62
```

assistant: ```c
int av_resample(int filter_length, short *src, short *filter) {
  int i;
  int val = 0;
  for (i = 0; i < filter_length; i++)
    val += src[i] * filter[i];
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_hash_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  add    %rax,-0x10(%rbp)
L0:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long str_hash_2(const void *key) {
  do {
    unsigned long _result_ = 0;
    do {
      unsigned char const *_key_ = (unsigned char const *)(((const char *)key)) - 1;
      while (*++_key_)
        (_result_) += (*_key_ << (_key_[1] & 0x7));
    } while (0);
    return _result_;
  } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_hash_2>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  mov    $0x0,%edx
L2:
  movzbl %al,%eax
  movzbl 0x1(%rdi),%ecx
  and    $0x7,%ecx
  shl    %cl,%eax
  cltq
  add    %rax,%rdx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
L21:
  mov    %rdx,%rax
  ret
L6:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
unsigned long str_hash_2(const void *key) {
  do {
    unsigned long _result_ = 0;
    do {
      unsigned char const *_key_ = (unsigned char const *)(((const char *)key)) - 1;
      while (*++_key_)
        (_result_) += (*_key_ << (_key_[1] & 0x7));
    } while (0);
    return _result_;
  } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_hash_2>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  test   %dl,%dl
  je     L2
  xchg   %ax,%ax
L17:
  movzbl %dl,%eax
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%ecx
  and    $0x7,%ecx
  shl    %cl,%eax
  cltq
  add    %rax,%r8
  test   %dl,%dl
  jne    L17
L2:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long str_hash_2(const void *key) {
  do {
    unsigned long _result_ = 0;
    do {
      unsigned char const *_key_ = (unsigned char const *)(((const char *)key)) - 1;
      while (*++_key_)
        (_result_) += (*_key_ << (_key_[1] & 0x7));
    } while (0);
    return _result_;
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_hash_2>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  test   %dl,%dl
  je     L18
  xchg   %ax,%ax
L15:
  movzbl %dl,%eax
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%ecx
  and    $0x7,%ecx
  shl    %cl,%eax
  cltq
  add    %rax,%r8
  test   %dl,%dl
  jne    L15
L18:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long str_hash_2(const void *key) {
  do {
    unsigned long _result_ = 0;
    do {
      unsigned char const *_key_ = (unsigned char const *)(((const char *)key)) - 1;
      while (*++_key_)
        (_result_) += (*_key_ << (_key_[1] & 0x7));
    } while (0);
    return _result_;
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rsp,%rax
L12:
  cmp    %rax,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L12
L18:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  mov    %rsp,%r15
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0xffffffff,%edx
  mov    $0x64,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  mov    $0xffffffff,%edx
  mov    $0x64,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    %r14,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  movl   $0x11,(%rbx)
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free_anything@plt>
  mov    -0x48(%rbp),%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1_size = 100;
  int array1[array1_size];
  int array2_size = 100;
  int *array2 = malloc(array2_size * sizeof(int));
  read_element(array1, array1_size, -1);
  read_element(array1, array1_size, 100);
  read_element(array2, array2_size, -1);
  read_element(array2, array2_size, 100);
  free(array2);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L5
L17:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L17
L5:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  mov    $0x190,%edi
  mov    %rsp,%r8
  mov    %r8,-0x48(%rbp)
  call   <malloc@plt>
  mov    -0x48(%rbp),%rdi
  or     $0xffffffff,%edx
  mov    $0x64,%esi
  mov    %rax,%rbx
  call   <read_element@plt>
  mov    -0x48(%rbp),%rdi
  mov    $0x64,%edx
  mov    $0x64,%esi
  call   <read_element@plt>
  or     $0xffffffff,%edx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  movl   $0x11,0x0(%r13)
  mov    %r13,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1_size = 100;
  int array1[array1_size];
  int array2_size = 100;
  int *array2 = malloc(array2_size * sizeof(int));
  read_element(array1, array1_size, -1);
  read_element(array1, array1_size, 100);
  read_element(array2, array2_size, -1);
  read_element(array2, array2_size, 100);
  free(array2);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L21
L20:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L20
L21:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  mov    $0x190,%edi
  mov    %rsp,%r8
  mov    %r8,-0x48(%rbp)
  call   <malloc@plt>
  mov    -0x48(%rbp),%rdi
  or     $0xffffffff,%edx
  mov    $0x64,%esi
  mov    %rax,%rbx
  call   <read_element@plt>
  mov    -0x48(%rbp),%rdi
  mov    $0x64,%edx
  mov    $0x64,%esi
  call   <read_element@plt>
  or     $0xffffffff,%edx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  movl   $0x11,0x0(%r13)
  mov    %r13,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1_size = 100;
  int array1[array1_size];
  int array2_size = 100;
  int *array2 = malloc(array2_size * sizeof(int));
  read_element(array1, array1_size, -1);
  read_element(array1, array1_size, 100);
  read_element(array2, array2_size, -1);
  read_element(array2, array2_size, 100);
  free(array2);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy2ddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <nand_init@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L2:
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <nandll_read_page@plt>
  addl   $0x1,-0xc(%rbp)
  addq   $0x800,-0x8(%rbp)
L13:
  cmpl   $0x3,-0xc(%rbp)
  jle    L2
  movl   $0x4,-0xc(%rbp)
  jmp    L22
L30:
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <nandll_read_page@plt>
  addl   $0x1,-0xc(%rbp)
  addq   $0x2000,-0x8(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  add    $0x1000,%eax
  shr    $0xd,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  ja     L30
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int copy2ddr(unsigned int nand_start, unsigned int ddr_start, unsigned int len) {
  unsigned char *dest = (unsigned char *)ddr_start;
  int i;
  nand_init();
  for (i = 0; i < 4; i++, dest += 2048) {
    nandll_read_page(dest, i, 2);
  }
  for (i = 4; i < ((len + 4096) >> 13); i++, dest += 8192) {
    nandll_read_page(dest, i, 2);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy2ddr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <nand_init@plt>
  mov    %rbp,%r12
  mov    $0x0,%ebx
L1:
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <nandll_read_page@plt>
  add    $0x1,%ebx
  add    $0x800,%r12
  cmp    $0x4,%ebx
  jne    L1
  add    $0x2000,%rbp
  lea    0x1000(%r13),%edx
  mov    %edx,%r12d
  shr    $0xd,%r12d
  cmp    $0x9fff,%edx
  jbe    L25
L23:
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nandll_read_page@plt>
  add    $0x1,%ebx
  add    $0x2000,%rbp
  cmp    %r12d,%ebx
  jne    L23
L25:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copy2ddr(unsigned int nand_start, unsigned int ddr_start, unsigned int len) {
  unsigned char *dest = (unsigned char *)ddr_start;
  int i;
  nand_init();
  for (i = 0; i < 4; i++, dest += 2048) {
    nandll_read_page(dest, i, 2);
  }
  for (i = 4; i < ((len + 4096) >> 13); i++, dest += 8192) {
    nandll_read_page(dest, i, 2);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy2ddr>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rbp,%r12
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <nand_init@plt>
L3:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x2,%edx
  add    $0x1,%ebx
  call   <nandll_read_page@plt>
  add    $0x800,%r12
  cmp    $0x4,%ebx
  jne    L3
  lea    0x1000(%r13),%edx
  add    $0x2000,%rbp
  mov    %edx,%r12d
  shr    $0xd,%r12d
  cmp    $0x9fff,%edx
  jbe    L16
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x2,%edx
  add    $0x1,%ebx
  call   <nandll_read_page@plt>
  add    $0x2000,%rbp
  cmp    %ebx,%r12d
  jne    L5
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copy2ddr(unsigned int nand_start, unsigned int ddr_start, unsigned int len) {
  unsigned char *dest = (unsigned char *)ddr_start;
  int i;
  nand_init();
  for (i = 0; i < 4; i++, dest += 2048) {
    nandll_read_page(dest, i, 2);
  }
  for (i = 4; i < ((len + 4096) >> 13); i++, dest += 8192) {
    nandll_read_page(dest, i, 2);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy2ddr>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rbp,%r12
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <nand_init@plt>
L10:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x2,%edx
  add    $0x1,%ebx
  call   <nandll_read_page@plt>
  add    $0x800,%r12
  cmp    $0x4,%ebx
  jne    L10
  lea    0x1000(%r13),%edx
  add    $0x2000,%rbp
  mov    %edx,%r12d
  shr    $0xd,%r12d
  cmp    $0x9fff,%edx
  jbe    L28
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x2,%edx
  add    $0x1,%ebx
  call   <nandll_read_page@plt>
  add    $0x2000,%rbp
  cmp    %ebx,%r12d
  jne    L12
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copy2ddr(unsigned int nand_start, unsigned int ddr_start, unsigned int len) {
  unsigned char *dest = (unsigned char *)ddr_start;
  int i;
  nand_init();
  for (i = 0; i < 4; i++, dest += 2048) {
    nandll_read_page(dest, i, 2);
  }
  for (i = 4; i < ((len + 4096) >> 13); i++, dest += 8192) {
    nandll_read_page(dest, i, 2);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<o_crdy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L67
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L8:
  mov    -0x14(%rbp),%eax
  add    $0x10004,%eax
  shl    $0x4,%eax
  cltq
  mov    (%rax),%rax
  and    $0x1e0,%eax
  cmp    $0x1e0,%rax
  je     L49
  mov    $0x1,%eax
  jmp    L34
L49:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
  jmp    L34
L67:
  nop
L53:
  mov    -0x14(%rbp),%eax
  add    $0x10004,%eax
  shl    $0x4,%eax
  cltq
  mov    (%rax),%rax
  and    $0x1e0,%eax
  cmp    $0x1e0,%rax
  je     L53
  mov    $0x1,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int o_crdy(int channel, int tries) {
  int i;
  if (tries) {
    for (i = 0; i < tries; i++)
      if ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) != 0x1e0)
        return (1);
    return (0);
  } else {
    while ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) == 0x1e0)
      ;
    return (1);
  }
}
```