ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x15,%edx
  mov    $0xa,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x17,%edx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D5
data_type: string

tool: D0: this is test1 %d %d


tool: D5: this is test2 %d


assistant: ```c
int main(void) {
  int a;
  a = 10;
  { printf("this is test1 %d %d\r\n", a++, 21); };
  do {
    printf("this is test2 %d\r\n", a++);
  } while (0);
  { printf("this is test1 %d %d\r\n", a++, 23); };
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    $0x15,%edx
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x17,%edx
  xor    %eax,%eax
  mov    $0xc,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string

tool: D2: this is test1 %d %d


tool: D17: this is test2 %d


assistant: ```c
int main(void) {
  int a;
  a = 10;
  { printf("this is test1 %d %d\r\n", a++, 21); };
  do {
    printf("this is test2 %d\r\n", a++);
  } while (0);
  { printf("this is test1 %d %d\r\n", a++, 23); };
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x15,%edx
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x17,%edx
  xor    %eax,%eax
  mov    $0xc,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string

tool: D0: this is test1 %d %d


tool: D18: this is test2 %d


assistant: ```c
int main(void) {
  int a;
  a = 10;
  { printf("this is test1 %d %d\r\n", a++, 21); };
  do {
    printf("this is test2 %d\r\n", a++);
  } while (0);
  { printf("this is test1 %d %d\r\n", a++, 23); };
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<return_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: test string

assistant: ```c
char *return_string() {
  char *strval = (char *)calloc(12, sizeof(char));
  strcpy(strval, "test string");
  return strval;
}
```
user: What is the c source code of the assembly code below:

```asm
<return_string>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string

tool: D5: test string

assistant: ```c
char *return_string() {
  char *strval = (char *)calloc(12, sizeof(char));
  strcpy(strval, "test string");
  return strval;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<return_string>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <calloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: test string

assistant: ```c
char *return_string() {
  char *strval = (char *)calloc(12, sizeof(char));
  strcpy(strval, "test string");
  return strval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<return_string>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <calloc@plt>
  lea    D3(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: test string

assistant: ```c
char *return_string() {
  char *strval = (char *)calloc(12, sizeof(char));
  strcpy(strval, "test string");
  return strval;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<frobcmp_ci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    $0x2a,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x12(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  xor    $0x2a,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x11(%rbp)
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  jne    L24
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L21
L24:
  movsbl -0x12(%rbp),%eax
  movsbl -0x11(%rbp),%edx
  sub    %edx,%eax
  jmp    L74
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L40
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L0
L40:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L88
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L88
  mov    $0x0,%eax
  jmp    L74
L88:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L42
  mov    $0xffffffff,%eax
  jmp    L74
L42:
  mov    $0x1,%eax
L74:
  leave
  ret
```

assistant: ```c
int frobcmp_ci(uint8_t const *const *aa, uint8_t const *const *ba) {
  uint8_t const *a = *aa, *b = *ba;
  while (*a != ' ' && *b != ' ') {
    uint8_t ca = toupper(*a ^ 0x2a);
    uint8_t cb = toupper(*b ^ 0x2a);
    if (ca == cb) {
      ++a;
      ++b;
    } else
      return (int)ca - (int)cb;
  }
  if (*a == ' ' && *b == ' ')
    return 0;
  else if (*a == ' ')
    return -1;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<frobcmp_ci>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rbp
  mov    (%rsi),%rbx
  movzbl 0x0(%rbp),%edi
  cmp    $0x20,%dil
  je     L54
L12:
  cmpb   $0x20,(%rbx)
  je     L46
  xor    $0x2a,%edi
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %eax,%r12d
  movzbl (%rbx),%edi
  xor    $0x2a,%edi
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    %al,%r12b
  jne    L44
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%edi
  cmp    $0x20,%dil
  jne    L12
L54:
  cmpb   $0x20,(%rbx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L26
L44:
  movsbl %r12b,%r12d
  movsbl %al,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  jmp    L26
L46:
  cmp    $0x20,%dil
  setne  %al
  movzbl %al,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int frobcmp_ci(uint8_t const *const *aa, uint8_t const *const *ba) {
  uint8_t const *a = *aa, *b = *ba;
  while (*a != ' ' && *b != ' ') {
    uint8_t ca = toupper(*a ^ 0x2a);
    uint8_t cb = toupper(*b ^ 0x2a);
    if (ca == cb) {
      ++a;
      ++b;
    } else
      return (int)ca - (int)cb;
  }
  if (*a == ' ' && *b == ' ')
    return 0;
  else if (*a == ' ')
    return -1;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<frobcmp_ci>:
  endbr64
  push   %r12
  push   %rbp
  mov    (%rsi),%rbp
  push   %rbx
  mov    (%rdi),%r12
  movzbl (%r12),%edi
  cmp    $0x20,%dil
  jne    L11
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L9:
  xor    $0x2a,%edi
  movsbl %dil,%edi
  call   <toupper@plt>
  movzbl 0x0(%rbp),%edi
  movsbl %al,%ebx
  xor    $0x2a,%edi
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    %al,%bl
  jne    L5
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  cmp    $0x20,%dil
  je     L16
L11:
  cmpb   $0x20,0x0(%rbp)
  jne    L9
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl %al,%edx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  cmpb   $0x20,0x0(%rbp)
  pop    %rbx
  setne  %al
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int frobcmp_ci(uint8_t const *const *aa, uint8_t const *const *ba) {
  uint8_t const *a = *aa, *b = *ba;
  while (*a != ' ' && *b != ' ') {
    uint8_t ca = toupper(*a ^ 0x2a);
    uint8_t cb = toupper(*b ^ 0x2a);
    if (ca == cb) {
      ++a;
      ++b;
    } else
      return (int)ca - (int)cb;
  }
  if (*a == ' ' && *b == ' ')
    return 0;
  else if (*a == ' ')
    return -1;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<frobcmp_ci>:
  endbr64
  push   %r12
  push   %rbp
  mov    (%rsi),%rbp
  push   %rbx
  mov    (%rdi),%r12
  movzbl (%r12),%edi
  cmp    $0x20,%dil
  jne    L13
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L39:
  xor    $0x2a,%edi
  movsbl %dil,%edi
  call   <toupper@plt>
  movzbl 0x0(%rbp),%edi
  movsbl %al,%ebx
  xor    $0x2a,%edi
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    %al,%bl
  jne    L46
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  cmp    $0x20,%dil
  je     L21
L13:
  cmpb   $0x20,0x0(%rbp)
  jne    L39
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  movsbl %al,%edx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  cmpb   $0x20,0x0(%rbp)
  pop    %rbx
  setne  %al
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int frobcmp_ci(uint8_t const *const *aa, uint8_t const *const *ba) {
  uint8_t const *a = *aa, *b = *ba;
  while (*a != ' ' && *b != ' ') {
    uint8_t ca = toupper(*a ^ 0x2a);
    uint8_t cb = toupper(*b ^ 0x2a);
    if (ca == cb) {
      ++a;
      ++b;
    } else
      return (int)ca - (int)cb;
  }
  if (*a == ' ' && *b == ' ')
    return 0;
  else if (*a == ' ')
    return -1;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<morpheus_tanh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L13:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <tanh@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void morpheus_tanh(int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = tanh(x[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<morpheus_tanh>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %edi,%ebp
  mov    $0x0,%ebx
L19:
  movsd  (%r12,%rbx,8),%xmm0
  call   <tanh@plt>
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  ret
```

assistant: ```c
void morpheus_tanh(int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = tanh(x[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<morpheus_tanh>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L16:
  movsd  (%r12,%rbx,8),%xmm0
  call   <tanh@plt>
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void morpheus_tanh(int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = tanh(x[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<morpheus_tanh>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L10:
  movsd  (%r12,%rbx,8),%xmm0
  call   <tanh@plt>
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void morpheus_tanh(int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = tanh(x[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_dup(char *s) {
  char *s1;
  int i;
  i = strlen(s) + 1;
  s1 = malloc(i);
  strncpy(s1, s, i);
  return s1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_dup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_dup(char *s) {
  char *s1;
  int i;
  i = strlen(s) + 1;
  s1 = malloc(i);
  strncpy(s1, s, i);
  return s1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *str_dup(char *s) {
  char *s1;
  int i;
  i = strlen(s) + 1;
  s1 = malloc(i);
  strncpy(s1, s, i);
  return s1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *str_dup(char *s) {
  char *s1;
  int i;
  i = strlen(s) + 1;
  s1 = malloc(i);
  strncpy(s1, s, i);
  return s1;
}
```
user: What is the c source code of the assembly code below:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L8:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *str, int c, unsigned int bytes) {
  unsigned int i;
  unsigned char ch = (unsigned char)c;
  char *s = (char *)str;
  for (i = 0; i < bytes; i++) {
    s[i] = ch;
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L1
  mov    %rdi,%rcx
  mov    %edx,%edx
  add    %rdi,%rdx
L16:
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L16
L1:
  ret
```

assistant: ```c
void *memset(void *str, int c, unsigned int bytes) {
  unsigned int i;
  unsigned char ch = (unsigned char)c;
  char *s = (char *)str;
  for (i = 0; i < bytes; i++) {
    s[i] = ch;
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L9
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *str, int c, unsigned int bytes) {
  unsigned int i;
  unsigned char ch = (unsigned char)c;
  char *s = (char *)str;
  for (i = 0; i < bytes; i++) {
    s[i] = ch;
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L6
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *str, int c, unsigned int bytes) {
  unsigned int i;
  unsigned char ch = (unsigned char)c;
  char *s = (char *)str;
  for (i = 0; i < bytes; i++) {
    s[i] = ch;
  }
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<base64encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BIO_set_flags@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_flush@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BIO_set_close@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free_all@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BUF_MEM_grow@plt>
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char *base64encode(const void *b64_encode_this, int encode_this_many_bytes) {
  BIO *b64_bio, *mem_bio;
  BUF_MEM *mem_bio_mem_ptr;
  b64_bio = BIO_new(BIO_f_base64());
  mem_bio = BIO_new(BIO_s_mem());
  BIO_push(b64_bio, mem_bio);
  BIO_set_flags(b64_bio, BIO_FLAGS_BASE64_NO_NL);
  BIO_write(b64_bio, b64_encode_this, encode_this_many_bytes);
  BIO_flush(b64_bio);
  BIO_get_mem_ptr(mem_bio, &mem_bio_mem_ptr);
  BIO_set_close(mem_bio, BIO_NOCLOSE);
  BIO_free_all(b64_bio);
  BUF_MEM_grow(mem_bio_mem_ptr, (*mem_bio_mem_ptr).length + 1);
  (*mem_bio_mem_ptr).data[(*mem_bio_mem_ptr).length] = '\0';
  return (*mem_bio_mem_ptr).data;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<base64encode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <BIO_push@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <BIO_set_flags@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <BIO_write@plt>
  mov    %rbx,%rdi
  call   <BIO_flush@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  call   <BIO_set_close@plt>
  mov    %rbx,%rdi
  call   <BIO_free_all@plt>
  mov    (%rsp),%rdi
  mov    (%rdi),%eax
  lea    0x1(%rax),%esi
  call   <BUF_MEM_grow@plt>
  mov    (%rsp),%rax
  movslq (%rax),%rdx
  mov    0x8(%rax),%rax
  movb   $0x0,(%rax,%rdx,1)
  mov    (%rsp),%rax
  mov    0x8(%rax),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *base64encode(const void *b64_encode_this, int encode_this_many_bytes) {
  BIO *b64_bio, *mem_bio;
  BUF_MEM *mem_bio_mem_ptr;
  b64_bio = BIO_new(BIO_f_base64());
  mem_bio = BIO_new(BIO_s_mem());
  BIO_push(b64_bio, mem_bio);
  BIO_set_flags(b64_bio, BIO_FLAGS_BASE64_NO_NL);
  BIO_write(b64_bio, b64_encode_this, encode_this_many_bytes);
  BIO_flush(b64_bio);
  BIO_get_mem_ptr(mem_bio, &mem_bio_mem_ptr);
  BIO_set_close(mem_bio, BIO_NOCLOSE);
  BIO_free_all(b64_bio);
  BUF_MEM_grow(mem_bio_mem_ptr, (*mem_bio_mem_ptr).length + 1);
  (*mem_bio_mem_ptr).data[(*mem_bio_mem_ptr).length] = '\0';
  return (*mem_bio_mem_ptr).data;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<base64encode>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <BIO_push@plt>
  mov    D8(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <BIO_set_flags@plt>
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    D12(%rip),%rax
  mov    %r12,%rdi
  mov    (%rax),%esi
  call   <BIO_set_close@plt>
  mov    %rbp,%rdi
  call   <BIO_free_all@plt>
  mov    (%rsp),%rdi
  mov    (%rdi),%eax
  lea    0x1(%rax),%esi
  call   <BUF_MEM_grow@plt>
  mov    (%rsp),%rax
  movslq (%rax),%rdx
  mov    0x8(%rax),%rax
  movb   $0x0,(%rax,%rdx,1)
  mov    (%rsp),%rax
  mov    0x8(%rax),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *base64encode(const void *b64_encode_this, int encode_this_many_bytes) {
  BIO *b64_bio, *mem_bio;
  BUF_MEM *mem_bio_mem_ptr;
  b64_bio = BIO_new(BIO_f_base64());
  mem_bio = BIO_new(BIO_s_mem());
  BIO_push(b64_bio, mem_bio);
  BIO_set_flags(b64_bio, BIO_FLAGS_BASE64_NO_NL);
  BIO_write(b64_bio, b64_encode_this, encode_this_many_bytes);
  BIO_flush(b64_bio);
  BIO_get_mem_ptr(mem_bio, &mem_bio_mem_ptr);
  BIO_set_close(mem_bio, BIO_NOCLOSE);
  BIO_free_all(b64_bio);
  BUF_MEM_grow(mem_bio_mem_ptr, (*mem_bio_mem_ptr).length + 1);
  (*mem_bio_mem_ptr).data[(*mem_bio_mem_ptr).length] = '\0';
  return (*mem_bio_mem_ptr).data;
}
```