ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverser@plt>
  nop
  leave
  ret
```

assistant: ```c
void reverse(char *s) {
  void reverser(char *s, int i, int len);
  reverser(s, 0, strlen(s));
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <reverser@plt>
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  void reverser(char *s, int i, int len);
  reverser(s, 0, strlen(s));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  mov    %eax,%edx
  jmp    1070 <reverser@plt>
```

assistant: ```c
void reverse(char *s) {
  void reverser(char *s, int i, int len);
  reverser(s, 0, strlen(s));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  mov    %eax,%edx
  jmp    1070 <reverser@plt>
```

assistant: ```c
void reverse(char *s) {
  void reverser(char *s, int i, int len);
  reverser(s, 0, strlen(s));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stdin_flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L19
L0:
  nop
L19:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L10
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L0
L10:
  nop
  leave
  ret
```

assistant: ```c
void stdin_flush(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    continue;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stdin_flush>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L1
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L8
L1:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stdin_flush(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    continue;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stdin_flush>:
  endbr64
  sub    $0x8,%rsp
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L10
  mov    D2(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L2
L10:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stdin_flush(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    continue;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<stdin_flush>:
  endbr64
  sub    $0x8,%rsp
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L14
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L18
L14:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stdin_flush(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    continue;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <GetMemory@plt>
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string

tool: D2: hello world

tool: D8: %s


assistant: ```c
void Test(void) {
  char *str = NULL;
  GetMemory(str);
  strcpy(str, "hello world");
  printf("%s\n", str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <GetMemory@plt>
  lea    D0(%rip),%rsi
  mov    $0x0,%edi
  call   <strcpy@plt>
  mov    $0x0,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D0: hello world

tool: D15: %s


assistant: ```c
void Test(void) {
  char *str = NULL;
  GetMemory(str);
  strcpy(str, "hello world");
  printf("%s\n", str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Test>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <GetMemory@plt>
  lea    D17(%rip),%rsi
  xor    %edi,%edi
  call   <strcpy@plt>
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D17
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string

tool: D17: hello world

tool: D11: %s


assistant: ```c
void Test(void) {
  char *str = NULL;
  GetMemory(str);
  strcpy(str, "hello world");
  printf("%s\n", str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Test>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <GetMemory@plt>
  lea    D4(%rip),%rsi
  xor    %edi,%edi
  call   <strcpy@plt>
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D5
data_type: string

tool: D4: hello world

tool: D5: %s


assistant: ```c
void Test(void) {
  char *str = NULL;
  GetMemory(str);
  strcpy(str, "hello world");
  printf("%s\n", str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TakeADoubleNaN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L10
  mov    $0x4,%eax
  jmp    L18
L10:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
extern int TakeADoubleNaN(double x) {
  if (isnan(x))
    return 4;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TakeADoubleNaN>:
  endbr64
  sub    $0x8,%rsp
  call   <isnan@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  shl    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern int TakeADoubleNaN(double x) {
  if (isnan(x))
    return 4;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<TakeADoubleNaN>:
  endbr64
  sub    $0x8,%rsp
  call   <isnan@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
extern int TakeADoubleNaN(double x) {
  if (isnan(x))
    return 4;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TakeADoubleNaN>:
  endbr64
  sub    $0x8,%rsp
  call   <isnan@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
extern int TakeADoubleNaN(double x) {
  if (isnan(x))
    return 4;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<avaliarExpressao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L61
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L67
L61:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L36
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <avaliarExpressao>
  jmp    L67
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L6
  cmpl   $0x0,-0xc(%rbp)
  jle    L40
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <avaliarExpressao>
  jmp    L67
L40:
  mov    $0x0,%eax
  jmp    L67
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <avaliarExpressao>
L67:
  leave
  ret
```

assistant: ```c
int avaliarExpressao(char *str, int expressoesAbertas) {
  if (*str == '\n') {
    return expressoesAbertas == 0;
  } else if (*str == '(') {
    return avaliarExpressao(str + 1, expressoesAbertas + 1);
  } else if (*str == ')') {
    if (expressoesAbertas > 0) {
      return avaliarExpressao(str + 1, expressoesAbertas - 1);
    } else {
      return 0;
    }
  } else {
    return avaliarExpressao(str + 1, expressoesAbertas);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<avaliarExpressao>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xa,%al
  je     L43
  sub    $0x8,%rsp
  cmp    $0x28,%al
  je     L37
  cmp    $0x29,%al
  jne    L50
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L63
L62:
  add    $0x8,%rsp
  ret
L43:
  test   %esi,%esi
  sete   %al
  movzbl %al,%eax
  ret
L37:
  add    $0x1,%esi
  add    $0x1,%rdi
  call   <avaliarExpressao>
  jmp    L62
L63:
  sub    $0x1,%esi
  add    $0x1,%rdi
  call   <avaliarExpressao>
  jmp    L62
L50:
  add    $0x1,%rdi
  call   <avaliarExpressao>
  jmp    L62
```

assistant: ```c
int avaliarExpressao(char *str, int expressoesAbertas) {
  if (*str == '\n') {
    return expressoesAbertas == 0;
  } else if (*str == '(') {
    return avaliarExpressao(str + 1, expressoesAbertas + 1);
  } else if (*str == ')') {
    if (expressoesAbertas > 0) {
      return avaliarExpressao(str + 1, expressoesAbertas - 1);
    } else {
      return 0;
    }
  } else {
    return avaliarExpressao(str + 1, expressoesAbertas);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<avaliarExpressao>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  cmp    $0xa,%al
  jne    L16
  jmp    L44
  nopl   0x0(%rax)
L23:
  cmp    $0x29,%al
  je     L72
L19:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  cmp    $0xa,%al
  je     L44
L16:
  cmp    $0x28,%al
  jne    L23
  movzbl (%rdx),%eax
  add    $0x1,%esi
  add    $0x1,%rdx
  cmp    $0xa,%al
  jne    L16
L44:
  xor    %eax,%eax
  test   %esi,%esi
  sete   %al
  ret
  nopl   0x0(%rax)
L72:
  test   %esi,%esi
  jle    L70
  sub    $0x1,%esi
  jmp    L19
  nopl   0x0(%rax)
L70:
  xor    %eax,%eax
  ret
```

assistant: ```c
int avaliarExpressao(char *str, int expressoesAbertas) {
  if (*str == '\n') {
    return expressoesAbertas == 0;
  } else if (*str == '(') {
    return avaliarExpressao(str + 1, expressoesAbertas + 1);
  } else if (*str == ')') {
    if (expressoesAbertas > 0) {
      return avaliarExpressao(str + 1, expressoesAbertas - 1);
    } else {
      return 0;
    }
  } else {
    return avaliarExpressao(str + 1, expressoesAbertas);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<avaliarExpressao>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  cmp    $0xa,%al
  jne    L48
  jmp    L22
  nopl   0x0(%rax)
L58:
  cmp    $0x29,%al
  je     L53
L34:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  cmp    $0xa,%al
  je     L22
L48:
  cmp    $0x28,%al
  jne    L58
  movzbl (%rdx),%eax
  add    $0x1,%esi
  add    $0x1,%rdx
  cmp    $0xa,%al
  jne    L48
L22:
  xor    %eax,%eax
  test   %esi,%esi
  sete   %al
  ret
  nopl   0x0(%rax)
L53:
  test   %esi,%esi
  jle    L8
  sub    $0x1,%esi
  jmp    L34
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int avaliarExpressao(char *str, int expressoesAbertas) {
  if (*str == '\n') {
    return expressoesAbertas == 0;
  } else if (*str == '(') {
    return avaliarExpressao(str + 1, expressoesAbertas + 1);
  } else if (*str == ')') {
    if (expressoesAbertas > 0) {
      return avaliarExpressao(str + 1, expressoesAbertas - 1);
    } else {
      return 0;
    }
  } else {
    return avaliarExpressao(str + 1, expressoesAbertas);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <cBreak@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sH() {
  dot();
  dot();
  dot();
  dot();
  cBreak();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sH>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <cBreak@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sH() {
  dot();
  dot();
  dot();
  dot();
  cBreak();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sH>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cBreak@plt>
```

assistant: ```c
void sH() {
  dot();
  dot();
  dot();
  dot();
  cBreak();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sH>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cBreak@plt>
```

assistant: ```c
void sH() {
  dot();
  dot();
  dot();
  dot();
  cBreak();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<periphery_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: v1.1.1

assistant: ```c
const char *periphery_version(void) {
  return "v"
         "1"
         "."
         "1"
         "."
         "1";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<periphery_version>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: v1.1.1

assistant: ```c
const char *periphery_version(void) {
  return "v"
         "1"
         "."
         "1"
         "."
         "1";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<periphery_version>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D1: v1.1.1

assistant: ```c
const char *periphery_version(void) {
  return "v"
         "1"
         "."
         "1"
         "."
         "1";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<periphery_version>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: v1.1.1

assistant: ```c
const char *periphery_version(void) {
  return "v"
         "1"
         "."
         "1"
         "."
         "1";
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
L31:
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jne    L31
  subl   $0x1,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L38
L17:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
L38:
  cmpl   $0x0,-0x2c(%rbp)
  jns    L17
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void to_string(char *buff, int number) {
  char inv_buff[16];
  int offset = 0;
  int m10;
  int i = 0;
  do {
    m10 = number % 10;
    m10 = (m10 < 0) ? -m10 : m10;
    inv_buff[offset++] = (char)('0' + m10);
    number = number / 10;
  } while (number);
  offset--;
  for (i = 0; offset >= 0; offset--, i++)
    buff[i] = inv_buff[offset];
  buff[i] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<to_string>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ecx
L24:
  mov    %ecx,%r9d
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%r8d
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    $0x30,%eax
  mov    %al,(%rsp,%rcx,1)
  mov    %r8d,%esi
  add    $0x1,%rcx
  test   %r8d,%r8d
  jne    L24
  test   %r9d,%r9d
  js     L18
  movslq %r9d,%rax
  lea    (%rsp,%rax,1),%rdx
  mov    %rdi,%rax
  mov    %r9d,%r10d
  lea    0x1(%rdi,%r10,1),%rsi
L3:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L3
  lea    0x1(%r9),%esi
L18:
  movslq %esi,%rsi
  movb   $0x0,(%rdi,%rsi,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void to_string(char *buff, int number) {
  char inv_buff[16];
  int offset = 0;
  int m10;
  int i = 0;
  do {
    m10 = number % 10;
    m10 = (m10 < 0) ? -m10 : m10;
    inv_buff[offset++] = (char)('0' + m10);
    number = number / 10;
  } while (number);
  offset--;
  for (i = 0; offset >= 0; offset--, i++)
    buff[i] = inv_buff[offset];
  buff[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<to_string>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %edx,%rax
  mov    %edx,%esi
  mov    %ecx,%r9d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  mov    %eax,%esi
  mov    %edx,%eax
  add    %edi,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %esi,%edx
  mov    %rcx,%rsi
  add    $0x30,%eax
  mov    %al,(%r10,%rcx,1)
  add    $0x1,%rcx
  test   %edx,%edx
  jne    L6
  movslq %r9d,%rdx
  mov    %r8,%rcx
  add    %r8,%rsi
  add    %r10,%rdx
  jmp    L12
  nopl   0x0(%rax)
L9:
  movzbl (%rdx),%eax
  add    $0x1,%rcx
L12:
  mov    %al,(%rcx)
  sub    $0x1,%rdx
  cmp    %rsi,%rcx
  jne    L9
  add    $0x1,%r9d
  movslq %r9d,%r9
  movb   $0x0,(%r8,%r9,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x28,%rsp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void to_string(char *buff, int number) {
  char inv_buff[16];
  int offset = 0;
  int m10;
  int i = 0;
  do {
    m10 = number % 10;
    m10 = (m10 < 0) ? -m10 : m10;
    inv_buff[offset++] = (char)('0' + m10);
    number = number / 10;
  } while (number);
  offset--;
  for (i = 0; offset >= 0; offset--, i++)
    buff[i] = inv_buff[offset];
  buff[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D53(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    D27(%rip),%rax
  mov    D180(%rip),%rdx
  mov    %rax,D225(%rip)
  mov    %rdx,D220(%rip)
  mov    D125(%rip),%rax
  mov    D128(%rip),%rdx
  mov    %rax,D86(%rip)
  mov    %rdx,D239(%rip)
  movq   $0x0,D239(%rip)
  movq   $0x0,D86(%rip)
  mov    D220(%rip),%edx
  mov    D160(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,D116(%rip)
  mov    D116(%rip),%edx
  mov    D116(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,D72(%rip)
  mov    D225(%rip),%rdx
  mov    D72(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    D225(%rip),%rdx
  mov    D214(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  lea    D225(%rip),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  lea    -0xd(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  lea    D27(%rip),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  add    %eax,-0xc(%rbp)
L7:
  cmpl   $0x1,-0xc(%rbp)
  jne    L6
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  jmp    L14
L6:
  mov    $0xffffffff,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int getch(void) {
  char ch;
  int error;
  static struct termios Otty, Ntty;
  fflush(stdout);
  tcgetattr(0, &Otty);
  Ntty = Otty;
  Ntty.c_iflag = 0;
  Ntty.c_oflag = 0;
  Ntty.c_lflag &= ~ICANON;
  Ntty.c_lflag &= ~ECHO;
  Ntty.c_cc[VMIN] = 1;
  Ntty.c_cc[VTIME] = 1;
  if (0 == (error = tcsetattr(0, TCSANOW, &Ntty))) {
    error = read(0, &ch, 1);
    error += tcsetattr(0, TCSANOW, &Otty);
  }
  return (error == 1 ? (int)ch : -1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getch>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D131(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  lea    D160(%rip),%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  movdqa D160(%rip),%xmm0
  movaps %xmm0,D78(%rip)
  movq   $0x0,D52(%rip)
  movq   $0x0,D148(%rip)
  mov    D61(%rip),%rax
  mov    (%rax),%eax
  mov    D60(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,D9(%rip)
  mov    D77(%rip),%rax
  mov    (%rax),%rdx
  mov    D78(%rip),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D78(%rip),%rax
  movl   $0x1,(%rax,%rdx,4)
  lea    D78(%rip),%rdx
  mov    D130(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  test   %eax,%eax
  je     L32
L23:
  cmp    $0x1,%eax
  jne    L49
  movsbl 0x7(%rsp),%eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L32:
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%ebx
  lea    D160(%rip),%rdx
  mov    D130(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  add    %ebx,%eax
  jmp    L23
L49:
  mov    $0xffffffff,%eax
  jmp    L48
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  char ch;
  int error;
  static struct termios Otty, Ntty;
  fflush(stdout);
  tcgetattr(0, &Otty);
  Ntty = Otty;
  Ntty.c_iflag = 0;
  Ntty.c_oflag = 0;
  Ntty.c_lflag &= ~ICANON;
  Ntty.c_lflag &= ~ECHO;
  Ntty.c_cc[VMIN] = 1;
  Ntty.c_cc[VTIME] = 1;
  if (0 == (error = tcsetattr(0, TCSANOW, &Ntty))) {
    error = read(0, &ch, 1);
    error += tcsetattr(0, TCSANOW, &Otty);
  }
  return (error == 1 ? (int)ch : -1);
}
```