ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<posix_spawnattr_setsigdefault>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int posix_spawnattr_setsigdefault(posix_spawnattr_t *attr, const sigset_t *sigdefault) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <scan_data@plt>
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sum_data@plt>
  movzbl -0x11(%rbp),%eax
  cmp    $0xa,%al
  je     L23
  jmp    L1
L23:
  nop
  mov    -0x10(%rbp),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <conversion@plt>
  mov    -0xc(%rbp),%eax
  add    $0x16,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D14: Enter an abitrarily long string, ending with carriage return > 

tool: D1: Check sum is %c


assistant: ```c
int main() {
  int accumulator = 0;
  int remainder;
  char input;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (1) {
    scan_data(&input);
    sum_data(input, &accumulator);
    if (input == '\n')
      break;
  }
  conversion(accumulator, &remainder);
  remainder = remainder + 22;
  input = (char)remainder;
  printf("Check sum is %c\n", input);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0xf(%rsp),%rbx
L2:
  mov    %rbx,%rdi
  call   <scan_data@plt>
  lea    0x10(%rsp),%rsi
  movsbl 0xf(%rsp),%edi
  call   <sum_data@plt>
  cmpb   $0xa,0xf(%rsp)
  jne    L2
  lea    0x14(%rsp),%rsi
  mov    0x10(%rsp),%edi
  call   <conversion@plt>
  mov    0x14(%rsp),%eax
  lea    0x16(%rax),%esi
  mov    %esi,0x14(%rsp)
  mov    %sil,0xf(%rsp)
  movsbl %sil,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D18
type: string

tool: D3: Enter an abitrarily long string, ending with carriage return > 

tool: D18: Check sum is %c


assistant: ```c
int main() {
  int accumulator = 0;
  int remainder;
  char input;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (1) {
    scan_data(&input);
    sum_data(input, &accumulator);
    if (input == '\n')
      break;
  }
  conversion(accumulator, &remainder);
  remainder = remainder + 22;
  input = (char)remainder;
  printf("Check sum is %c\n", input);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  movl   $0x0,0x10(%rsp)
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  call   <scan_data@plt>
  movsbl 0xf(%rsp),%edi
  mov    %rbx,%rsi
  call   <sum_data@plt>
  cmpb   $0xa,0xf(%rsp)
  jne    L6
  mov    0x10(%rsp),%edi
  lea    0x14(%rsp),%rsi
  call   <conversion@plt>
  mov    0x14(%rsp),%eax
  lea    D10(%rip),%rdi
  lea    0x16(%rax),%esi
  xor    %eax,%eax
  mov    %esi,0x14(%rsp)
  mov    %sil,0xf(%rsp)
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D12: Enter an abitrarily long string, ending with carriage return > 

tool: D10: Check sum is %c


assistant: ```c
int main() {
  int accumulator = 0;
  int remainder;
  char input;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (1) {
    scan_data(&input);
    sum_data(input, &accumulator);
    if (input == '\n')
      break;
  }
  conversion(accumulator, &remainder);
  remainder = remainder + 22;
  input = (char)remainder;
  printf("Check sum is %c\n", input);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  movl   $0x0,0x10(%rsp)
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <scan_data@plt>
  movsbl 0xf(%rsp),%edi
  mov    %rbx,%rsi
  call   <sum_data@plt>
  cmpb   $0xa,0xf(%rsp)
  jne    L9
  mov    0x10(%rsp),%edi
  lea    0x14(%rsp),%rsi
  call   <conversion@plt>
  mov    0x14(%rsp),%eax
  lea    D8(%rip),%rdi
  lea    0x16(%rax),%esi
  xor    %eax,%eax
  mov    %esi,0x14(%rsp)
  mov    %sil,0xf(%rsp)
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string

tool: D18: Enter an abitrarily long string, ending with carriage return > 

tool: D8: Check sum is %c


assistant: ```c
int main() {
  int accumulator = 0;
  int remainder;
  char input;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (1) {
    scan_data(&input);
    sum_data(input, &accumulator);
    if (input == '\n')
      break;
  }
  conversion(accumulator, &remainder);
  remainder = remainder + 22;
  input = (char)remainder;
  printf("Check sum is %c\n", input);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L16
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L15
L16:
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <print_dir@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1) {
    usage();
    return 1;
  }
  for (int i = 1; i < argc; ++i)
    print_dir(argv[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  cmp    $0x1,%edi
  je     L6
  mov    $0x0,%eax
  jle    L27
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L1:
  mov    (%rbx),%rdi
  call   <print_dir@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L1
  mov    $0x0,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    %ebp,%eax
  jmp    L27
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1) {
    usage();
    return 1;
  }
  for (int i = 1; i < argc; ++i)
    print_dir(argv[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L10
  jle    L4
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   (%rax)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <print_dir@plt>
  cmp    %rbp,%rbx
  jne    L18
L4:
  xor    %eax,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  xor    %eax,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L13
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1) {
    usage();
    return 1;
  }
  for (int i = 1; i < argc; ++i)
    print_dir(argv[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L8
  jle    L36
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   (%rax)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <print_dir@plt>
  cmp    %rbp,%rbx
  jne    L18
L36:
  xor    %eax,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  xor    %eax,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L14
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1) {
    usage();
    return 1;
  }
  for (int i = 1; i < argc; ++i)
    print_dir(argv[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_head_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <list_front@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <compare@plt>
  test   %eax,%eax
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <failure@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: head should have been '%s'

assistant: ```c
void test_head_data(struct list *list, char *data) {
  if (!compare(list_front(list), data))
    failure("head should have been '%s'", data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_head_data>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <list_front@plt>
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <compare@plt>
  test   %eax,%eax
  je     L9
L7:
  pop    %rbx
  ret
L9:
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <failure@plt>
  jmp    L7
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: head should have been '%s'

assistant: ```c
void test_head_data(struct list *list, char *data) {
  if (!compare(list_front(list), data))
    failure("head should have been '%s'", data);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_head_data>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <list_front@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <compare@plt>
  test   %eax,%eax
  je     L8
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  jmp    1080 <failure@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: head should have been '%s'

assistant: ```c
void test_head_data(struct list *list, char *data) {
  if (!compare(list_front(list), data))
    failure("head should have been '%s'", data);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_head_data>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <list_front@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <compare@plt>
  test   %eax,%eax
  je     L7
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  pop    %rbp
  jmp    1080 <failure@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D7: head should have been '%s'

assistant: ```c
void test_head_data(struct list *list, char *data) {
  if (!compare(list_front(list), data))
    failure("head should have been '%s'", data);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sfile_argv_bsl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jg     L119
  mov    $0x0,%eax
  jmp    L111
L119:
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L101
  mov    $0xffffffff,%eax
  jmp    L111
L101:
  movl   $0x0,-0x28(%rbp)
  jmp    L22
L124:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L77
  movl   $0xffffffff,-0x24(%rbp)
  jmp    L109
L77:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x2c(%rbp),%rdx
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <Sfile_bsl_interpreter@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L110
  addl   $0x1,-0x28(%rbp)
L22:
  mov    -0x28(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L124
  movl   $0x1,-0x24(%rbp)
  jmp    L109
L110:
  nop
L109:
  cmpl   $0x0,-0x24(%rbp)
  jg     L116
  cmpq   $0x0,-0x20(%rbp)
  je     L21
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L21
L116:
  mov    -0x40(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
L21:
  mov    -0x24(%rbp),%eax
L111:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Sfile_argv_bsl(int argc, char ***argv, int flag) {
  int i, ret, eaten;
  char **new_argv = NULL;
  if (argc <= 0)
    return (0);
  new_argv = (char **)malloc(argc * sizeof(char *));
  if (new_argv == NULL)
    return (-1);
  for (i = 0; i < argc; i++) {
    new_argv[i] = strdup((*argv)[i]);
    if (new_argv[i] == NULL) {
      ret = -1;
      goto ex;
    }
    ret = Sfile_bsl_interpreter(new_argv[i], strlen(new_argv[i]), &eaten, 0);
    if (ret <= 0)
      goto ex;
  }
  ret = 1;
ex:;
  if (ret <= 0) {
    if (new_argv != NULL)
      free((char *)new_argv);
  } else
    *argv = new_argv;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Sfile_argv_bsl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  test   %edi,%edi
  jle    L9
  mov    %edi,%r12d
  mov    %rsi,%r13
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L40
  mov    %r12d,%r12d
  shl    $0x3,%r12
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r15
L46:
  lea    (%r14,%rbx,1),%rbp
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L27
  call   <strlen@plt>
  mov    %eax,%esi
  mov    $0x0,%ecx
  mov    %r15,%rdx
  mov    0x0(%rbp),%rdi
  call   <Sfile_bsl_interpreter@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L0
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L46
  mov    %r14,0x0(%r13)
  mov    $0x1,%ebp
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    $0xffffffff,%ebp
L0:
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L9
L40:
  mov    $0xffffffff,%ebp
  jmp    L9
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Sfile_argv_bsl(int argc, char ***argv, int flag) {
  int i, ret, eaten;
  char **new_argv = NULL;
  if (argc <= 0)
    return (0);
  new_argv = (char **)malloc(argc * sizeof(char *));
  if (new_argv == NULL)
    return (-1);
  for (i = 0; i < argc; i++) {
    new_argv[i] = strdup((*argv)[i]);
    if (new_argv[i] == NULL) {
      ret = -1;
      goto ex;
    }
    ret = Sfile_bsl_interpreter(new_argv[i], strlen(new_argv[i]), &eaten, 0);
    if (ret <= 0)
      goto ex;
  }
  ret = 1;
ex:;
  if (ret <= 0) {
    if (new_argv != NULL)
      free((char *)new_argv);
  } else
    *argv = new_argv;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Sfile_argv_bsl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L43
  lea    0x0(,%rbp,8),%edi
  mov    %rsi,%r12
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L72
  shl    $0x3,%rbp
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L54:
  mov    (%r12),%rax
  lea    0x0(%r13,%r15,1),%rbx
  mov    (%rax,%r15,1),%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L23
  call   <strlen@plt>
  mov    (%rbx),%rdi
  xor    %ecx,%ecx
  mov    %r14,%rdx
  mov    %eax,%esi
  call   <Sfile_bsl_interpreter@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L44
  add    $0x8,%r15
  cmp    %r15,%rbp
  jne    L54
  mov    %r13,(%r12)
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    $0xffffffff,%ebx
  xchg   %ax,%ax
L44:
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L43
L72:
  mov    $0xffffffff,%ebx
  jmp    L43
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Sfile_argv_bsl(int argc, char ***argv, int flag) {
  int i, ret, eaten;
  char **new_argv = NULL;
  if (argc <= 0)
    return (0);
  new_argv = (char **)malloc(argc * sizeof(char *));
  if (new_argv == NULL)
    return (-1);
  for (i = 0; i < argc; i++) {
    new_argv[i] = strdup((*argv)[i]);
    if (new_argv[i] == NULL) {
      ret = -1;
      goto ex;
    }
    ret = Sfile_bsl_interpreter(new_argv[i], strlen(new_argv[i]), &eaten, 0);
    if (ret <= 0)
      goto ex;
  }
  ret = 1;
ex:;
  if (ret <= 0) {
    if (new_argv != NULL)
      free((char *)new_argv);
  } else
    *argv = new_argv;
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sfile_argv_bsl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L17
  lea    0x0(,%rbp,8),%edi
  mov    %rsi,%r12
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L40
  shl    $0x3,%rbp
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%r12),%rax
  lea    0x0(%r13,%r15,1),%rbx
  mov    (%rax,%r15,1),%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L3
  call   <strlen@plt>
  mov    (%rbx),%rdi
  xor    %ecx,%ecx
  mov    %r14,%rdx
  mov    %eax,%esi
  call   <Sfile_bsl_interpreter@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L75
  add    $0x8,%r15
  cmp    %r15,%rbp
  jne    L35
  mov    %r13,(%r12)
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x18,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  mov    $0xffffffff,%ebx
  xchg   %ax,%ax
L75:
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L17
L40:
  mov    $0xffffffff,%ebx
  jmp    L17
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Sfile_argv_bsl(int argc, char ***argv, int flag) {
  int i, ret, eaten;
  char **new_argv = NULL;
  if (argc <= 0)
    return (0);
  new_argv = (char **)malloc(argc * sizeof(char *));
  if (new_argv == NULL)
    return (-1);
  for (i = 0; i < argc; i++) {
    new_argv[i] = strdup((*argv)[i]);
    if (new_argv[i] == NULL) {
      ret = -1;
      goto ex;
    }
    ret = Sfile_bsl_interpreter(new_argv[i], strlen(new_argv[i]), &eaten, 0);
    if (ret <= 0)
      goto ex;
  }
  ret = 1;
ex:;
  if (ret <= 0) {
    if (new_argv != NULL)
      free((char *)new_argv);
  } else
    *argv = new_argv;
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isendword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  jmp    L26
L13:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L10
L26:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L13
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
int isendword(char *w, char *ENDCHARS, int len) {
  char c = w[strlen(w) - 1];
  while (len-- > 0) {
    if (c == ENDCHARS[len])
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isendword>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <strlen@plt>
  cltq
  movzbl -0x1(%r12,%rax,1),%eax
  movslq %ebx,%rdx
L12:
  test   %edx,%edx
  jle    L20
  sub    $0x1,%rdx
  cmp    %al,0x0(%rbp,%rdx,1)
  jne    L12
  mov    $0x1,%eax
  jmp    L10
L20:
  mov    $0x0,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int isendword(char *w, char *ENDCHARS, int len) {
  char c = w[strlen(w) - 1];
  while (len-- > 0) {
    if (c == ENDCHARS[len])
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isendword>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <strlen@plt>
  movslq %ebx,%rdx
  cltq
  movzbl -0x1(%r12,%rax,1),%eax
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L22:
  sub    $0x1,%rdx
  cmp    %al,0x0(%rbp,%rdx,1)
  je     L1
L13:
  test   %edx,%edx
  jg     L22
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int isendword(char *w, char *ENDCHARS, int len) {
  char c = w[strlen(w) - 1];
  while (len-- > 0) {
    if (c == ENDCHARS[len])
      return 1;
  }
  return 0;
}
```