ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<place_commas_in_unsigned_int>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  lea    D8(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <place_commas_in_number_string@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %u

assistant: ```c
char *place_commas_in_unsigned_int(unsigned int n) {
  char s[20];
  sprintf(s, "%u", n);
  return place_commas_in_number_string(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<place_commas_in_unsigned_int>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  lea    D9(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <place_commas_in_number_string@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: %u

assistant: ```c
char *place_commas_in_unsigned_int(unsigned int n) {
  char s[20];
  sprintf(s, "%u", n);
  return place_commas_in_number_string(s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x3d0000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x920,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x3d0914(%rbp)
  jmp    L40
L2:
  lea    -0x3d0910(%rbp),%rdx
  mov    -0x3d0914(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x3d0914(%rbp)
L40:
  cmpl   $0xf423f,-0x3d0914(%rbp)
  jle    L2
  lea    -0x3d0910(%rbp),%rax
  mov    $0xf423f,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x3d0914(%rbp)
  jmp    L27
L36:
  mov    -0x3d0914(%rbp),%eax
  cltq
  mov    -0x3d0910(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3d0914(%rbp)
L27:
  cmpl   $0xf423f,-0x3d0914(%rbp)
  jle    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D22
type: string
name: read_data
arguments: data_label: D26
type: string
name: read_data
arguments: data_label: D1
type: string

tool: D22: %d

tool: D26: 
Final array  :

tool: D1: %d


assistant: ```c
int main() {
  int A[999999 + 1];
  int i;
  for (i = 1; i <= 999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x918,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3d0908(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x3d0900(%rsp),%r12
  mov    %rbx,%rbp
  lea    D10(%rip),%r13
L1:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L1
  mov    %rsp,%rdi
  mov    $0xf423f,%edx
  mov    $0x1,%esi
  call   <quick_sort@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rbp
L33:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x3d0908(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x3d0918,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D28
datatype: string
name: extract_symbolic_data
arguments: tag: D22
datatype: string

tool: D10: %d

tool: D28: 
Final array  :

tool: D22: %d


assistant: ```c
int main() {
  int A[999999 + 1];
  int i;
  for (i = 1; i <= 999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0x918,%rsp
  lea    D7(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3d0908(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x3d0900(%rsp),%r12
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L16
  mov    %rsp,%rdi
  mov    $0xf423f,%edx
  mov    $0x1,%esi
  call   <quick_sort@plt>
  lea    D14(%rip),%rdi
  lea    D27(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L20:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x3d0908(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x3d0918,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string
name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D27
type: string

tool: D7: %d

tool: D14: 
Final array  :

tool: D27: %d


assistant: ```c
int main() {
  int A[999999 + 1];
  int i;
  for (i = 1; i <= 999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x918,%rsp
  lea    D8(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3d0908(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x3d0900(%rsp),%r12
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L3
  mov    %rsp,%rdi
  mov    $0xf423f,%edx
  mov    $0x1,%esi
  call   <quick_sort@plt>
  lea    D15(%rip),%rdi
  lea    D9(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L32:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x3d0908(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x3d0918,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string
name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D9
data_type: string

tool: D8: %d

tool: D15: 
Final array  :

tool: D9: %d


assistant: ```c
int main() {
  int A[999999 + 1];
  int i;
  for (i = 1; i <= 999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<unparse_sha1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movslq %ecx,%rdx
  lea    D8(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movslq %ecx,%rdx
  lea    D8(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  cmpl   $0x13,-0x14(%rbp)
  jle    L0
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D21(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: 0123456789abcdef

assistant: ```c
unsigned char *unparse_sha1(const void *shabuf) {
  const unsigned char *s = (const unsigned char *)shabuf;
  int i;
  static unsigned char buf[64];
  unsigned char *p;
  static const unsigned char hexd[] = "0123456789abcdef";
  for (i = 0, p = buf; i < 20; i++, s++) {
    *p++ = hexd[(*s >> 4) & 0xf];
    *p++ = hexd[*s & 0xf];
  }
  *p = 0;
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7f4(%rbp)
  movl   $0x0,-0x7f0(%rbp)
  movl   $0x2,-0x7ec(%rbp)
  jmp    L18
L71:
  movl   $0x0,-0x7f4(%rbp)
  movl   $0x1,-0x7e8(%rbp)
  jmp    L26
L0:
  mov    -0x7ec(%rbp),%eax
  cltd
  idivl  -0x7e8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L17
  addl   $0x1,-0x7f4(%rbp)
L17:
  addl   $0x1,-0x7e8(%rbp)
L26:
  mov    -0x7e8(%rbp),%eax
  cmp    -0x7ec(%rbp),%eax
  jle    L0
  cmpl   $0x2,-0x7f4(%rbp)
  jne    L39
  mov    -0x7f0(%rbp),%eax
  cltq
  mov    -0x7ec(%rbp),%edx
  mov    %edx,-0x7e0(%rbp,%rax,4)
  addl   $0x1,-0x7f0(%rbp)
L39:
  addl   $0x1,-0x7ec(%rbp)
L18:
  cmpl   $0x1f4,-0x7ec(%rbp)
  jle    L71
  movl   $0x0,-0x7e4(%rbp)
  jmp    L65
L66:
  mov    -0x7e4(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x7e0(%rbp,%rax,4),%edx
  mov    -0x7e4(%rbp),%eax
  cltq
  mov    -0x7e0(%rbp,%rax,4),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <twin_prime@plt>
  addl   $0x1,-0x7e4(%rbp)
L65:
  mov    -0x7f0(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x7e4(%rbp)
  jl     L66
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int main() {
  int f = 0, a[500], n = 0;
  for (int i = 2; i <= 500; ++i) {
    f = 0;
    for (int j = 1; j <= i; ++j) {
      if (i % j == 0) {
        f++;
      }
    }
    if (f == 2) {
      a[n] = i;
      n++;
    }
  }
  for (int i = 0; i < n - 1; ++i) {
    twin_prime(a[i], a[i + 1]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x3,%r8d
  mov    $0x2,%esi
  mov    $0x0,%r9d
  jmp    L78
L84:
  add    $0x1,%esi
  add    $0x1,%r8d
  cmp    $0x1f5,%esi
  je     L75
L78:
  mov    $0x1,%ecx
  mov    $0x0,%edi
  test   %esi,%esi
  jle    L84
L2:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L2
  cmp    $0x2,%edi
  jne    L84
  movslq %r9d,%rax
  mov    %esi,(%rsp,%rax,4)
  add    $0x1,%r9d
  jmp    L84
L75:
  cmp    $0x1,%r9d
  jle    L86
  mov    %rsp,%rbx
  lea    -0x2(%r9),%eax
  lea    0x4(%rsp,%rax,4),%rbp
L25:
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  call   <twin_prime@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L25
L86:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int f = 0, a[500], n = 0;
  for (int i = 2; i <= 500; ++i) {
    f = 0;
    for (int j = 1; j <= i; ++j) {
      if (i % j == 0) {
        f++;
      }
    }
    if (f == 2) {
      a[n] = i;
      n++;
    }
  }
  for (int i = 0; i < n - 1; ++i) {
    twin_prime(a[i], a[i + 1]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%r8d
  xor    %r9d,%r9d
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L46:
  lea    -0x1(%r8),%edi
  mov    $0x1,%ecx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L55
  cmp    $0x2,%esi
  jne    L42
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %edi,(%rsp,%rax,4)
L42:
  add    $0x1,%r8d
  cmp    $0x1f6,%r8d
  jne    L46
  cmp    $0x1,%r9d
  jle    L43
  lea    -0x2(%r9),%eax
  mov    (%rsp),%ebp
  lea    0x4(%rsp),%rbx
  lea    0x8(%rsp,%rax,4),%r12
L32:
  mov    %ebp,%edi
  mov    (%rbx),%ebp
  add    $0x4,%rbx
  mov    %ebp,%esi
  call   <twin_prime@plt>
  cmp    %r12,%rbx
  jne    L32
L43:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x7e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int f = 0, a[500], n = 0;
  for (int i = 2; i <= 500; ++i) {
    f = 0;
    for (int j = 1; j <= i; ++j) {
      if (i % j == 0) {
        f++;
      }
    }
    if (f == 2) {
      a[n] = i;
      n++;
    }
  }
  for (int i = 0; i < n - 1; ++i) {
    twin_prime(a[i], a[i + 1]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%r8d
  xor    %r9d,%r9d
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L59:
  lea    -0x1(%r8),%edi
  mov    $0x1,%ecx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L6
  cmp    $0x2,%esi
  jne    L39
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %edi,(%rsp,%rax,4)
L39:
  add    $0x1,%r8d
  cmp    $0x1f6,%r8d
  jne    L59
  cmp    $0x1,%r9d
  jle    L56
  lea    -0x2(%r9),%eax
  mov    %rsp,%rbx
  lea    0x4(%rsp,%rax,4),%rbp
L37:
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <twin_prime@plt>
  cmp    %rbx,%rbp
  jne    L37
L56:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int f = 0, a[500], n = 0;
  for (int i = 2; i <= 500; ++i) {
    f = 0;
    for (int j = 1; j <= i; ++j) {
      if (i % j == 0) {
        f++;
      }
    }
    if (f == 2) {
      a[n] = i;
      n++;
    }
  }
  for (int i = 0; i < n - 1; ++i) {
    twin_prime(a[i], a[i + 1]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<asbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x3,%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L32
L23:
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <getbits@plt>
  test   %rax,%rax
  je     L19
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L22
L19:
  mov    $0x30,%edi
  call   <putchar@plt>
L22:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L0
  mov    $0x20,%edi
  call   <putchar@plt>
L0:
  subl   $0x1,-0x4(%rbp)
L32:
  cmpl   $0x0,-0x4(%rbp)
  jns    L23
  cmpl   $0x0,-0x18(%rbp)
  je     L11
  mov    $0xa,%edi
  call   <putchar@plt>
L11:
  nop
  leave
  ret
```

assistant: ```c
void asbits(unsigned x, size_t s, int nl) {
  int i;
  for (i = s * 8 - 1; i >= 0; i--) {
    getbits(x, i, 1) ? putchar('1') : putchar('0');
    if (!(i % 4))
      putchar(' ');
  }
  if (nl)
    putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<asbits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %edx,%r12d
  lea    -0x1(,%rsi,8),%ebx
  test   %ebx,%ebx
  jns    L34
L12:
  test   %r12d,%r12d
  jne    L45
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  mov    $0x30,%edi
  call   <putchar@plt>
L27:
  test   $0x3,%bl
  je     L29
L70:
  sub    $0x1,%ebx
  js     L12
L34:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <getbits@plt>
  test   %rax,%rax
  je     L52
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L27
L29:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L70
L45:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L11
```

assistant: ```c
void asbits(unsigned x, size_t s, int nl) {
  int i;
  for (i = s * 8 - 1; i >= 0; i--) {
    getbits(x, i, 1) ? putchar('1') : putchar('0');
    if (!(i % 4))
      putchar(' ');
  }
  if (nl)
    putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<asbits>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  lea    -0x1(,%rsi,8),%ebx
  test   %ebx,%ebx
  js     L47
  mov    %edi,%ebp
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x31,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  je     L17
L61:
  sub    $0x1,%ebx
  jb     L47
L7:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <getbits@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x30,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  jne    L61
L17:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L7
L47:
  test   %r12d,%r12d
  jne    L33
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L33:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

assistant: ```c
void asbits(unsigned x, size_t s, int nl) {
  int i;
  for (i = s * 8 - 1; i >= 0; i--) {
    getbits(x, i, 1) ? putchar('1') : putchar('0');
    if (!(i % 4))
      putchar(' ');
  }
  if (nl)
    putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<asbits>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  lea    -0x1(,%rsi,8),%ebx
  test   %ebx,%ebx
  js     L37
  mov    %edi,%ebp
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L55:
  mov    $0x31,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  je     L12
L9:
  sub    $0x1,%ebx
  jb     L37
L75:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <getbits@plt>
  test   %rax,%rax
  jne    L55
  mov    $0x30,%edi
  call   <putchar@plt>
  test   $0x3,%bl
  jne    L9
L12:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L75
L37:
  test   %r12d,%r12d
  jne    L24
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L24:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

assistant: ```c
void asbits(unsigned x, size_t s, int nl) {
  int i;
  for (i = s * 8 - 1; i >= 0; i--) {
    getbits(x, i, 1) ? putchar('1') : putchar('0');
    if (!(i % 4))
      putchar(' ');
  }
  if (nl)
    putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<recursive_truc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L0
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L1
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L0:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L14
L39:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <recursive_truc>
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L39
L11:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string

tool: D3: %d

tool: 

assistant: ```c
void recursive_truc(int i, int n, int *T) {
  int j, temp;
  if (i == n) {
    for (j = 0; j < n; j++) {
      printf("%d", T[j]);
    }
    puts("");
  } else {
    for (j = i; j < n; j++) {
      temp = T[i];
      T[i] = T[j];
      T[j] = temp;
      recursive_truc(i + 1, n, T);
      temp = T[i];
      T[i] = T[j];
      T[j] = temp;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<recursive_truc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %rdx,%r13
  cmp    %esi,%edi
  je     L45
  jge    L1
  movslq %edi,%rdx
  lea    0x0(%r13,%rdx,4),%rbp
  mov    %rbp,%rbx
  lea    -0x1(%rsi),%eax
  sub    %edi,%eax
  add    %rdx,%rax
  lea    0x4(%r13,%rax,4),%r14
  lea    0x1(%rdi),%r15d
L30:
  mov    0x0(%rbp),%eax
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <recursive_truc>
  mov    0x0(%rbp),%eax
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L30
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  test   %esi,%esi
  jle    L52
  mov    %rdx,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdx,%rax,4),%r12
  lea    D5(%rip),%rbp
L37:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L37
L52:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string

tool: D5: %d

tool: 

assistant: ```c
void recursive_truc(int i, int n, int *T) {
  int j, temp;
  if (i == n) {
    for (j = 0; j < n; j++) {
      printf("%d", T[j]);
    }
    puts("");
  } else {
    for (j = i; j < n; j++) {
      temp = T[i];
      T[i] = T[j];
      T[j] = temp;
      recursive_truc(i + 1, n, T);
      temp = T[i];
      T[i] = T[j];
      T[j] = temp;
    }
  }
}
```