ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L7
L26:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string

tool: D10: %d

tool: D15: %lf

tool: D7: %.0f dias


assistant: ```c
int main(void) {
  int casos;
  double comidaDisponivel;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%lf", &comidaDisponivel);
    printf("%.0f dias\n", ceil(log2(comidaDisponivel)));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L8
  lea    0x10(%rsp),%r12
  lea    D10(%rip),%rbp
  lea    D28(%rip),%rbx
L19:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L19
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string

tool: D20: %d

tool: D10: %lf

tool: D28: %.0f dias


assistant: ```c
int main(void) {
  int casos;
  double comidaDisponivel;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%lf", &comidaDisponivel);
    printf("%.0f dias\n", ceil(log2(comidaDisponivel)));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L28
  lea    0x10(%rsp),%r12
  lea    D6(%rip),%rbp
  lea    D16(%rip),%rbx
  nop
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L5
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
datatype: string
name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D21: %d

tool: D6: %lf

tool: D16: %.0f dias


assistant: ```c
int main(void) {
  int casos;
  double comidaDisponivel;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%lf", &comidaDisponivel);
    printf("%.0f dias\n", ceil(log2(comidaDisponivel)));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L2
  lea    0x10(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D4(%rip),%rbx
  nop
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L18
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D18
type: string
name: read_data
arguments: label: D4
type: string

tool: D6: %d

tool: D18: %lf

tool: D4: %.0f dias


assistant: ```c
int main(void) {
  int casos;
  double comidaDisponivel;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%lf", &comidaDisponivel);
    printf("%.0f dias\n", ceil(log2(comidaDisponivel)));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yahoo_f01_42>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    $0x583d4bcf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <yahoo_M1Common@plt>
  leave
  ret
```

assistant: ```c
int yahoo_f01_42(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x583D4BCF;
  return yahoo_M1Common(b, Parameter);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yahoo_f01_42>:
  endbr64
  sub    $0x8,%rsp
  xor    $0x583d4bcf,%edi
  call   <yahoo_M1Common@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yahoo_f01_42(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x583D4BCF;
  return yahoo_M1Common(b, Parameter);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yahoo_f01_42>:
  endbr64
  xor    $0x583d4bcf,%edi
  jmp    1050 <yahoo_M1Common@plt>
```

assistant: ```c
int yahoo_f01_42(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x583D4BCF;
  return yahoo_M1Common(b, Parameter);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<yahoo_f01_42>:
  endbr64
  xor    $0x583d4bcf,%edi
  jmp    1050 <yahoo_M1Common@plt>
```

assistant: ```c
int yahoo_f01_42(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x583D4BCF;
  return yahoo_M1Common(b, Parameter);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Stream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x5,%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L18
L28:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <MemSet@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movl   $0xa,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L34:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%ecx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D2(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D2(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L34
  mov    -0x8(%rbp),%rax
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string

tool: D15: %.10d

assistant: ```c
char *Stream(char *data, int size) {
  int i, j, slen;
  char *r;
  static char hexa[17] = "abcdefghijklmnop";
  slen = 10 + size * 2 + 1;
  r = (char *)malloc(slen);
  if (!r)
    return 0;
  MemSet(r, 0, slen);
  sprintf(r, "%.10d", size);
  j = 10;
  for (i = 0; i < size; i++) {
    r[j++] = hexa[((unsigned char)data[i]) / 16];
    r[j++] = hexa[((unsigned char)data[i]) % 16];
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Stream>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  lea    0xb(%rsi,%rsi,1),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L29
  mov    %rax,%r12
  mov    %rax,%rbp
  mov    %r14d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <MemSet@plt>
  mov    %r13d,%edx
  lea    D13(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  test   %r13d,%r13d
  jle    L29
  mov    %rbx,%rcx
  lea    0xa(%r12),%rdx
  lea    -0x1(%r13),%eax
  lea    0xc(%r12,%rax,2),%rdi
  lea    D17(%rip),%rsi
L28:
  movzbl (%rcx),%eax
  shr    $0x4,%al
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,(%rdx)
  movzbl (%rcx),%eax
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,0x1(%rdx)
  add    $0x1,%rcx
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  jne    L28
L29:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string

tool: D13: %.10d

tool: D17: abcdefghijklmnop

assistant: ```c
char *Stream(char *data, int size) {
  int i, j, slen;
  char *r;
  static char hexa[17] = "abcdefghijklmnop";
  slen = 10 + size * 2 + 1;
  r = (char *)malloc(slen);
  if (!r)
    return 0;
  MemSet(r, 0, slen);
  sprintf(r, "%.10d", size);
  j = 10;
  for (i = 0; i < size; i++) {
    r[j++] = hexa[((unsigned char)data[i]) / 16];
    r[j++] = hexa[((unsigned char)data[i]) % 16];
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Stream>:
  endbr64
  push   %r13
  lea    0xb(%rsi,%rsi,1),%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %r13d,%edx
  mov    %rax,%rdi
  call   <MemSet@plt>
  mov    %ebp,%edx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  test   %ebp,%ebp
  jle    L8
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rcx
  lea    0xa(%r12),%rdx
  lea    0xc(%r12,%rax,2),%rdi
  lea    D17(%rip),%rsi
  nopl   0x0(%rax)
L0:
  movzbl (%rcx),%eax
  add    $0x2,%rdx
  add    $0x1,%rcx
  shr    $0x4,%al
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,-0x2(%rdx)
  movzbl -0x1(%rcx),%eax
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L0
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D2: %.10d

tool: D17: abcdefghijklmnop

assistant: ```c
char *Stream(char *data, int size) {
  int i, j, slen;
  char *r;
  static char hexa[17] = "abcdefghijklmnop";
  slen = 10 + size * 2 + 1;
  r = (char *)malloc(slen);
  if (!r)
    return 0;
  MemSet(r, 0, slen);
  sprintf(r, "%.10d", size);
  j = 10;
  for (i = 0; i < size; i++) {
    r[j++] = hexa[((unsigned char)data[i]) / 16];
    r[j++] = hexa[((unsigned char)data[i]) % 16];
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Stream>:
  endbr64
  push   %r13
  lea    0xb(%rsi,%rsi,1),%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L26
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %r13d,%edx
  mov    %rax,%rdi
  call   <MemSet@plt>
  mov    %ebp,%edx
  lea    D11(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  test   %ebp,%ebp
  jle    L26
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rcx
  lea    0xa(%r12),%rdx
  lea    0xc(%r12,%rax,2),%rdi
  lea    D19(%rip),%rsi
  nopl   0x0(%rax)
L20:
  movzbl (%rcx),%eax
  add    $0x2,%rdx
  add    $0x1,%rcx
  shr    $0x4,%al
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,-0x2(%rdx)
  movzbl -0x1(%rcx),%eax
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L20
L26:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D11: %.10d

tool: D19: abcdefghijklmnop

assistant: ```c
char *Stream(char *data, int size) {
  int i, j, slen;
  char *r;
  static char hexa[17] = "abcdefghijklmnop";
  slen = 10 + size * 2 + 1;
  r = (char *)malloc(slen);
  if (!r)
    return 0;
  MemSet(r, 0, slen);
  sprintf(r, "%.10d", size);
  j = 10;
  for (i = 0; i < size; i++) {
    r[j++] = hexa[((unsigned char)data[i]) / 16];
    r[j++] = hexa[((unsigned char)data[i]) % 16];
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dummy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <socket@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <connect@plt>
  call   <fork@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <dup2@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <execv@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string

tool: 

assistant: ```c
void dummy() {
  char *arg[] = {NULL};
  socket(0, 0, 0);
  connect(0, NULL, 0);
  fork();
  dup2(0, 0);
  execv("", arg);
  perror("");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dummy>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <socket@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <connect@plt>
  call   <fork@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <dup2@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <execv@plt>
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: 

assistant: ```c
void dummy() {
  char *arg[] = {NULL};
  socket(0, 0, 0);
  connect(0, NULL, 0);
  fork();
  dup2(0, 0);
  execv("", arg);
  perror("");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dummy>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  lea    D8(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <socket@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <connect@plt>
  call   <fork@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <dup2@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <execv@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: 

assistant: ```c
void dummy() {
  char *arg[] = {NULL};
  socket(0, 0, 0);
  connect(0, NULL, 0);
  fork();
  dup2(0, 0);
  execv("", arg);
  perror("");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dummy>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  lea    D6(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <socket@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <connect@plt>
  call   <fork@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <dup2@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <execv@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: 

assistant: ```c
void dummy() {
  char *arg[] = {NULL};
  socket(0, 0, 0);
  connect(0, NULL, 0);
  fork();
  dup2(0, 0);
  execv("", arg);
  perror("");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x13,-0xc(%rbp)
  ja     L19
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  jmp    L18
L19:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
L18:
  nop
  leave
  ret
```

assistant: ```c
void sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  if (size < 20) {
    insertion_sort(collection, size, comp);
  } else {
    quick_sort(collection, 0, size - 1, comp);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  cmp    $0x13,%esi
  ja     L5
  call   <insertion_sort@plt>
L7:
  add    $0x8,%rsp
  ret
L5:
  lea    -0x1(%rsi),%edx
  mov    $0x0,%esi
  call   <quick_sort@plt>
  jmp    L7
```

assistant: ```c
void sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  if (size < 20) {
    insertion_sort(collection, size, comp);
  } else {
    quick_sort(collection, 0, size - 1, comp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  mov    %rdx,%rcx
  cmp    $0x13,%esi
  ja     L5
  jmp    1060 <insertion_sort@plt>
  nopl   0x0(%rax)
L5:
  lea    -0x1(%rsi),%edx
  xor    %esi,%esi
  jmp    1070 <quick_sort@plt>
```

assistant: ```c
void sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  if (size < 20) {
    insertion_sort(collection, size, comp);
  } else {
    quick_sort(collection, 0, size - 1, comp);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort>:
  endbr64
  mov    %rdx,%rcx
  cmp    $0x13,%esi
  ja     L7
  jmp    1060 <insertion_sort@plt>
  nopl   0x0(%rax)
L7:
  lea    -0x1(%rsi),%edx
  xor    %esi,%esi
  jmp    1070 <quick_sort@plt>
```

assistant: ```c
void sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  if (size < 20) {
    insertion_sort(collection, size, comp);
  } else {
    quick_sort(collection, 0, size - 1, comp);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <AddRoundKey@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <InvShiftRow@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <InvByteSub@plt>
  movl   $0x9,-0x4(%rbp)
  jmp    L19
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <AddRoundKey@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <InvMixColumn@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <InvShiftRow@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <InvByteSub@plt>
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jg     L4
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <AddRoundKey@plt>
  nop
  leave
  ret
```

assistant: ```c
void Decrypt(unsigned char State[4][4]) {
  int i, j;
  AddRoundKey(State, 10);
  InvShiftRow(State);
  InvByteSub(State);
  for (i = 9; i > 0; i--) {
    AddRoundKey(State, i);
    InvMixColumn(State);
    InvShiftRow(State);
    InvByteSub(State);
  }
  AddRoundKey(State, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Decrypt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <AddRoundKey@plt>
  mov    %rbx,%rdi
  call   <InvShiftRow@plt>
  mov    %rbx,%rdi
  call   <InvByteSub@plt>
  mov    $0x9,%ebp
L3:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <AddRoundKey@plt>
  mov    %rbx,%rdi
  call   <InvMixColumn@plt>
  mov    %rbx,%rdi
  call   <InvShiftRow@plt>
  mov    %rbx,%rdi
  call   <InvByteSub@plt>
  sub    $0x1,%ebp
  jne    L3
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <AddRoundKey@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Decrypt(unsigned char State[4][4]) {
  int i, j;
  AddRoundKey(State, 10);
  InvShiftRow(State);
  InvByteSub(State);
  for (i = 9; i > 0; i--) {
    AddRoundKey(State, i);
    InvMixColumn(State);
    InvShiftRow(State);
    InvByteSub(State);
  }
  AddRoundKey(State, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Decrypt>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x9,%ebx
  sub    $0x8,%rsp
  call   <AddRoundKey@plt>
  mov    %rbp,%rdi
  call   <InvShiftRow@plt>
  mov    %rbp,%rdi
  call   <InvByteSub@plt>
  nopl   0x0(%rax)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <AddRoundKey@plt>
  mov    %rbp,%rdi
  call   <InvMixColumn@plt>
  mov    %rbp,%rdi
  call   <InvShiftRow@plt>
  mov    %rbp,%rdi
  call   <InvByteSub@plt>
  sub    $0x1,%ebx
  jne    L7
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <AddRoundKey@plt>
```

assistant: ```c
void Decrypt(unsigned char State[4][4]) {
  int i, j;
  AddRoundKey(State, 10);
  InvShiftRow(State);
  InvByteSub(State);
  for (i = 9; i > 0; i--) {
    AddRoundKey(State, i);
    InvMixColumn(State);
    InvShiftRow(State);
    InvByteSub(State);
  }
  AddRoundKey(State, 0);
}
```