user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c0(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1b0(%rbp)
  jmp    L85
L14:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1b0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1b0(%rbp)
L85:
  mov    -0x1c0(%rbp),%eax
  cmp    %eax,-0x1b0(%rbp)
  jl     L14
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1bc(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1b8(%rbp)
  mov    -0x1c0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1b4(%rbp)
  jmp    L108
L23:
  mov    -0x1b8(%rbp),%edx
  mov    -0x1b4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1bc(%rbp),%eax
  cmp    %eax,%edx
  jne    L16
  movl   $0x1,-0x1a8(%rbp)
  mov    -0x1a4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1ac(%rbp)
  jmp    L71
L16:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1bc(%rbp),%eax
  cmp    %eax,%edx
  jge    L0
  mov    -0x1a4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1b8(%rbp)
  jmp    L108
L0:
  mov    -0x1a4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1b4(%rbp)
L108:
  mov    -0x1b8(%rbp),%eax
  cmp    -0x1b4(%rbp),%eax
  jl     L23
L71:
  cmpl   $0x1,-0x1a8(%rbp)
  jne    L31
  mov    -0x1ac(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L31:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L93
  call   <__stack_chk_fail@plt>
L93:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D73
type_guessed: string
name: unpack_data
arguments: label: D51
type_guessed: string
name: unpack_data
arguments: label: D47
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: string

tool: D73: Enter the number of elements in the array 

tool: D51: %d

tool: D47: Enter %d elements in the array 

tool: D18: Enter the element to be searched 

tool: D27: Element found at position %d


tool: D4: Element not found

assistant: ```c
int main() {
  int x[100], n, m, lower, upper, mid, i, p, f;
  printf("Enter the number of elements in the array ");
  scanf("%d", &n);
  printf("Enter %d elements in the array ", n);
  for (i = 0; i < n; i++)
    scanf("%d", &x[i]);
  printf("Enter the element to be searched ");
  scanf("%d", &m);
  lower = 0;
  upper = n - 1;
  while (lower < upper) {
    mid = (lower + upper) / 2;
    if (x[mid] == m) {
      f = 1;
      p = mid + 1;
      break;
    } else if (x[mid] < m)
      lower = mid + 1;
    else
      upper = mid - 1;
  }
  if (f == 1)
    printf("Element found at position %d\n", p);
  else
    printf("Element not found\n");
  return 0;
}
```