ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<trigamma>:
  endbr64
  addsd  D32(%rip),%xmm0
  movsd  D55(%rip),%xmm4
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm2
  movsd  D18(%rip),%xmm0
  movapd %xmm0,%xmm3
  divsd  %xmm2,%xmm3
  movsd  D21(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  D38(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  D54(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  D59(%rip),%xmm3
  addsd  %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  divsd  %xmm4,%xmm3
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  divsd  %xmm4,%xmm3
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  divsd  %xmm4,%xmm3
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D32
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D55
type_guessed: f64
name: disassemble_data
arguments: data_label: D18
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D21
type_guessed: f64
name: disassemble_data
arguments: data_label: D38
type_guessed: f64
name: disassemble_data
arguments: data_label: D54
type_guessed: f64
name: disassemble_data
arguments: data_label: D59
type_guessed: f64

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D55: 0.033333333333333

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D21: 0.075757575757576

tool: D38: 0.0238095238095238

tool: D54: 0.166666666666667

tool: D59: 0.5

assistant: ```c
double trigamma(double x) {
  double p;
  int i;
  x = x + 6;
  p = 1 / (x * x);
  p = (((((0.075757575757576 * p - 0.033333333333333) * p + 0.0238095238095238) * p - 0.033333333333333) * p + 0.166666666666667) * p + 1) / x + 0.5 * p;
  for (i = 0; i < 6; i++) {
    x = x - 1;
    p = 1 / (x * x) + p;
  }
  return (p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x14,-0x40(%rbp)
  movl   $0x1a,-0x3c(%rbp)
  movl   $0x4,-0x38(%rbp)
  movl   $0x17,-0x34(%rbp)
  movl   $0x5a,-0x30(%rbp)
  movl   $0x33,-0x2c(%rbp)
  movl   $0x4f,-0x28(%rbp)
  movl   $0x3c,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x3e,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  movl   $0xe,-0x44(%rbp)
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L17
L15:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L17:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: %d 

assistant: ```c
int main() {
  int a[] = {20, 26, 4, 23, 90, 51, 79, 60, 10, 7, 62, 31, 6, 20};
  int len = (int)sizeof(a) / sizeof(*a);
  insertion_sort(a, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", a[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x14,(%rsp)
  movl   $0x1a,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x17,0xc(%rsp)
  movl   $0x5a,0x10(%rsp)
  movl   $0x33,0x14(%rsp)
  movl   $0x4f,0x18(%rsp)
  movl   $0x3c,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  movl   $0x3e,0x28(%rsp)
  movl   $0x1f,0x2c(%rsp)
  movl   $0x6,0x30(%rsp)
  movl   $0x14,0x34(%rsp)
  mov    %rsp,%rbx
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <insertion_sort@plt>
  lea    0x38(%rsp),%r12
  lea    D8(%rip),%rbp
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L11
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string

tool: D8: %d 

assistant: ```c
int main() {
  int a[] = {20, 26, 4, 23, 90, 51, 79, 60, 10, 7, 62, 31, 6, 20};
  int len = (int)sizeof(a) / sizeof(*a);
  insertion_sort(a, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", a[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xe,%esi
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x1a00000014,%rax
  mov    %rsp,%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x1700000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x330000005a,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x3c0000004f,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x70000000a,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x1f0000003e,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x1400000006,%rax
  mov    %rax,0x30(%rsp)
  call   <insertion_sort@plt>
  xchg   %ax,%ax
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: %d 

assistant: ```c
int main() {
  int a[] = {20, 26, 4, 23, 90, 51, 79, 60, 10, 7, 62, 31, 6, 20};
  int len = (int)sizeof(a) / sizeof(*a);
  insertion_sort(a, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", a[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xe,%esi
  push   %rbp
  lea    D38(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D37(%rip),%rax
  lea    0x38(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D46(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D28(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <insertion_sort@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L17
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D38
datatype: string
name: read_data
arguments: data_tag: D7
datatype: byte[16]
name: read_data
arguments: data_tag: D37
datatype: byte[8]
name: read_data
arguments: data_tag: D46
datatype: byte[16]
name: read_data
arguments: data_tag: D28
datatype: byte[16]

tool: D38: %d 

tool: {"D7": [0x14,0x00,0x00,0x00,0x1a,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

tool: {"D37": [0x06,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: {"D46": [0x5a,0x00,0x00,0x00,0x33,0x00,0x00,0x00,0x4f,0x00,0x00,0x00,0x3c,0x00,0x00,0x00]}

tool: {"D28": [0x0a,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x3e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[] = {20, 26, 4, 23, 90, 51, 79, 60, 10, 7, 62, 31, 6, 20};
  int len = (int)sizeof(a) / sizeof(*a);
  insertion_sort(a, len);
  int i;
  for (i = 0; i < len; i++)
    printf("%d ", a[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sal_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L25
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L31
L42:
  addq   $0x8,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1010101(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  not    %rax
  and    %rdx,%rax
  and    $0x80808080,%eax
  test   %rax,%rax
  je     L42
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L25
L3:
  addq   $0x1,-0x18(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sal_strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sal_strcat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   $0x7,%dil
  je     L34
L35:
  cmpb   $0x0,(%rdi)
  je     L18
L60:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L60
L18:
  call   <sal_strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  jmp    L35
L34:
  mov    (%rdi),%rax
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  jne    L7
L51:
  add    $0x8,%rdi
  mov    (%rdi),%rax
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  je     L51
  jmp    L35
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sal_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   $0x7,%dil
  jne    L35
  mov    (%rdi),%rax
  jmp    L10
  nopl   0x0(%rax)
L28:
  mov    0x8(%rdi),%rax
  add    $0x8,%rdi
L10:
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  je     L28
  cmpb   $0x0,(%rdi)
  je     L34
  nopl   0x0(%rax)
L44:
  add    $0x1,%rdi
L35:
  cmpb   $0x0,(%rdi)
  jne    L44
L34:
  call   <sal_strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sal_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   $0x7,%dil
  jne    L28
  mov    (%rdi),%rax
  jmp    L16
  nopl   0x0(%rax)
L1:
  mov    0x8(%rdi),%rax
  add    $0x8,%rdi
L16:
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  je     L1
  cmpb   $0x0,(%rdi)
  je     L15
  nopl   0x0(%rax)
L32:
  add    $0x1,%rdi
L28:
  cmpb   $0x0,(%rdi)
  jne    L32
L15:
  call   <sal_strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_191_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_191_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rop3_191_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%esi
  not    %esi
  or     (%rdi),%sil
  mov    %eax,%edx
  not    %edx
  and    %edx,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_191_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_191_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %esi
  not    %edx
  or     (%rdi),%sil
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_191_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_191_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %esi
  not    %edx
  or     (%rdi),%sil
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_191_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x3,-0x3c(%rbp)
  movl   $0x5,-0x38(%rbp)
  movl   $0x6,-0x34(%rbp)
  movl   $0x7,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0xb,-0x28(%rbp)
  movl   $0x14,-0x24(%rbp)
  movl   $0x21,-0x20(%rbp)
  movl   $0x3a,-0x1c(%rbp)
  movl   $0x59,-0x18(%rbp)
  movl   $0xb,-0x48(%rbp)
  mov    -0x48(%rbp),%ecx
  lea    -0x40(%rbp),%rax
  mov    $0xb,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <binary_search@plt>
  mov    %eax,-0x44(%rbp)
  cmpl   $0xffffffff,-0x44(%rbp)
  jne    L22
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L15
L22:
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D7: not found!

tool: D11: index = %d


assistant: ```c
int main() {
  int array[] = {1, 3, 5, 6, 7, 9, 11, 20, 33, 58, 89};
  int size = sizeof(array) / sizeof(array[0]);
  int idx_ret = binary_search(array, size, 11);
  if (idx_ret == -1) {
    printf("not found!\n");
  } else {
    printf("index = %d\n", idx_ret);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x7,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0xb,0x18(%rsp)
  movl   $0x14,0x1c(%rsp)
  movl   $0x21,0x20(%rsp)
  movl   $0x3a,0x24(%rsp)
  movl   $0x59,0x28(%rsp)
  mov    %rsp,%rdi
  mov    $0xb,%edx
  mov    $0xb,%esi
  call   <binary_search@plt>
  cmp    $0xffffffff,%eax
  je     L21
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L21:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: D7: index = %d


tool: D10: not found!

assistant: ```c
int main() {
  int array[] = {1, 3, 5, 6, 7, 9, 11, 20, 33, 58, 89};
  int size = sizeof(array) / sizeof(array[0]);
  int idx_ret = binary_search(array, size, 11);
  if (idx_ret == -1) {
    printf("not found!\n");
  } else {
    printf("index = %d\n", idx_ret);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0xb,%edx
  mov    $0xb,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%rdi
  movl   $0x59,0x28(%rsp)
  mov    %rax,(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x900000007,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x140000000b,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3a00000021,%rax
  mov    %rax,0x20(%rsp)
  call   <binary_search@plt>
  cmp    $0xffffffff,%eax
  je     L24
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L1:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L24:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L1
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D12
type_infered: string

tool: D19: index = %d


tool: D12: not found!

assistant: ```c
int main() {
  int array[] = {1, 3, 5, 6, 7, 9, 11, 20, 33, 58, 89};
  int size = sizeof(array) / sizeof(array[0]);
  int idx_ret = binary_search(array, size, 11);
  if (idx_ret == -1) {
    printf("not found!\n");
  } else {
    printf("index = %d\n", idx_ret);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0xb,%edx
  mov    $0xb,%esi
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rdi
  movl   $0x59,0x28(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D33(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <binary_search@plt>
  cmp    $0xffffffff,%eax
  je     L19
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L19:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L13
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: byte[16]
name: unpack_data
arguments: data_tag: D0
data_type: byte[8]
name: unpack_data
arguments: data_tag: D33
data_type: byte[16]
name: unpack_data
arguments: data_tag: D11
data_type: string
name: unpack_data
arguments: data_tag: D32
data_type: string

tool: {"D13": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D0": [0x21,0x00,0x00,0x00,0x3a,0x00,0x00,0x00]}

tool: {"D33": [0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: D11: index = %d


tool: D32: not found!

assistant: ```c
int main() {
  int array[] = {1, 3, 5, 6, 7, 9, 11, 20, 33, 58, 89};
  int size = sizeof(array) / sizeof(array[0]);
  int idx_ret = binary_search(array, size, 11);
  if (idx_ret == -1) {
    printf("not found!\n");
  } else {
    printf("index = %d\n", idx_ret);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<td_bcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L14
L35:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L14
  mov    $0x1,%eax
  jmp    L21
L14:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L35
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int td_bcmp(s1, s2, count) const void *s1;
const void *s2;
int count;
{
  while (count-- > 0)
    if (*(unsigned char *)s1++ != *(unsigned char *)s2++)
      return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<td_bcmp>:
  endbr64
  mov    $0x0,%eax
L7:
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L13
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  je     L7
  mov    $0x1,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int td_bcmp(s1, s2, count) const void *s1;
const void *s2;
int count;
{
  while (count-- > 0)
    if (*(unsigned char *)s1++ != *(unsigned char *)s2++)
      return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<td_bcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L23
L8:
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jg     L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int td_bcmp(s1, s2, count) const void *s1;
const void *s2;
int count;
{
  while (count-- > 0)
    if (*(unsigned char *)s1++ != *(unsigned char *)s2++)
      return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<td_bcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L21
L29:
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jg     L13
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int td_bcmp(s1, s2, count) const void *s1;
const void *s2;
int count;
{
  while (count-- > 0)
    if (*(unsigned char *)s1++ != *(unsigned char *)s2++)
      return (1);
  return (0);
}
```