ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <switch1@plt>
  xor    %eax,%eax
  call   <switch2@plt>
  xor    %eax,%eax
  call   <switch3@plt>
  xor    %eax,%eax
  call   <switch4@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: 

assistant: ```c
int main() {
  switch1();
  switch2();
  switch3();
  switch4();
  puts("");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <switch1@plt>
  xor    %eax,%eax
  call   <switch2@plt>
  xor    %eax,%eax
  call   <switch3@plt>
  xor    %eax,%eax
  call   <switch4@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: 

assistant: ```c
int main() {
  switch1();
  switch2();
  switch3();
  switch4();
  puts("");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_walnutname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <parse_help@plt>
  test   %rax,%rax
  jns    L40
  mov    $0xffffffff,%eax
  jmp    L41
L40:
  cmpl   $0x3,-0x4(%rbp)
  je     L28
  mov    $0xffffffff,%eax
  jmp    L41
L28:
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_walnutname@plt>
  test   %rax,%rax
  je     L11
  mov    $0xffffffff,%eax
  jmp    L41
L11:
  mov    $0x0,%eax
L41:
  leave
  ret
```

assistant: ```c
int parse_walnutname(int argc, char **argv, struct walnut_cmd_arg *cmd) {
  int ret;
  if (parse_help(argc, argv, cmd) < 0)
    return -1;
  if (argc != 3)
    return -1;
  if (get_walnutname(argv[2], cmd))
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_walnutname>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <parse_help@plt>
  cmp    $0x3,%ebx
  jne    L23
  test   %rax,%rax
  js     L23
  mov    0x10(%r12),%rdi
  mov    %rbp,%rsi
  call   <get_walnutname@plt>
  neg    %rax
  sbb    %eax,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int parse_walnutname(int argc, char **argv, struct walnut_cmd_arg *cmd) {
  int ret;
  if (parse_help(argc, argv, cmd) < 0)
    return -1;
  if (argc != 3)
    return -1;
  if (get_walnutname(argv[2], cmd))
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_walnutname>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <parse_help@plt>
  cmp    $0x3,%ebx
  jne    L23
  test   %rax,%rax
  js     L23
  mov    0x10(%r12),%rdi
  mov    %rbp,%rsi
  call   <get_walnutname@plt>
  neg    %rax
  sbb    %eax,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int parse_walnutname(int argc, char **argv, struct walnut_cmd_arg *cmd) {
  int ret;
  if (parse_help(argc, argv, cmd) < 0)
    return -1;
  if (argc != 3)
    return -1;
  if (get_walnutname(argv[2], cmd))
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_walnutname>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <parse_help@plt>
  cmp    $0x3,%ebx
  jne    L24
  test   %rax,%rax
  js     L24
  mov    0x10(%r12),%rdi
  mov    %rbp,%rsi
  call   <get_walnutname@plt>
  neg    %rax
  sbb    %eax,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int parse_walnutname(int argc, char **argv, struct walnut_cmd_arg *cmd) {
  int ret;
  if (parse_help(argc, argv, cmd) < 0)
    return -1;
  if (argc != 3)
    return -1;
  if (get_walnutname(argv[2], cmd))
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <anIntPlease@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <anIntPlease@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmpl   $0x0,-0x20(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmpl   $0x0,-0x20(%rbp)
  je     L55
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L70
L55:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L70:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L78
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L28
L78:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L28:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L71
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L67
L71:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L67:
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L16
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L47
L16:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L47:
  lea    -0x24(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L69
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L4
L69:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L4:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int unknown;
  int x, y;
  int *p, *q;
  p = anIntPlease();
  q = anIntPlease();
  assert(unknown);
  assert(unknown == 0);
  assert(x);
  assert(y);
  assert(x == y);
  assert(p);
  assert(q);
  assert(p == q);
  if (unknown)
    assert(1);
  else
    assert(1);
  if (x == y)
    assert(1);
  else
    assert(1);
  if (p == q)
    assert(1);
  else
    assert(1);
  p = &x;
  if (p == q)
    assert(1);
  else
    assert(1);
  assert(p == &x);
  if (q == p)
    assert(1);
  else
    assert(1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <anIntPlease@plt>
  movslq %eax,%rbp
  mov    $0x0,%eax
  call   <anIntPlease@plt>
  movslq %eax,%rbx
  mov    $0x0,%r12d
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%r13d
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%r14d
  mov    %r14d,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %r13d,%r14d
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %rbx,%rbp
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  test   %r12d,%r12d
  je     L39
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L20:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %rbx,%rbp
  je     L25
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
L17:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L20
L25:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L17
```

assistant: ```c
int main() {
  int unknown;
  int x, y;
  int *p, *q;
  p = anIntPlease();
  q = anIntPlease();
  assert(unknown);
  assert(unknown == 0);
  assert(x);
  assert(y);
  assert(x == y);
  assert(p);
  assert(q);
  assert(p == q);
  if (unknown)
    assert(1);
  else
    assert(1);
  if (x == y)
    assert(1);
  else
    assert(1);
  if (p == q)
    assert(1);
  else
    assert(1);
  p = &x;
  if (p == q)
    assert(1);
  else
    assert(1);
  assert(p == &x);
  if (q == p)
    assert(1);
  else
    assert(1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <anIntPlease@plt>
  movslq %eax,%rbp
  xor    %eax,%eax
  call   <anIntPlease@plt>
  xor    %edi,%edi
  movslq %eax,%rbx
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12d,%r13d
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %rbx,%rbp
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int unknown;
  int x, y;
  int *p, *q;
  p = anIntPlease();
  q = anIntPlease();
  assert(unknown);
  assert(unknown == 0);
  assert(x);
  assert(y);
  assert(x == y);
  assert(p);
  assert(q);
  assert(p == q);
  if (unknown)
    assert(1);
  else
    assert(1);
  if (x == y)
    assert(1);
  else
    assert(1);
  if (p == q)
    assert(1);
  else
    assert(1);
  p = &x;
  if (p == q)
    assert(1);
  else
    assert(1);
  assert(p == &x);
  if (q == p)
    assert(1);
  else
    assert(1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <anIntPlease@plt>
  movslq %eax,%rbp
  xor    %eax,%eax
  call   <anIntPlease@plt>
  xor    %edi,%edi
  movslq %eax,%rbx
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12d,%r13d
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %rbx,%rbp
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int unknown;
  int x, y;
  int *p, *q;
  p = anIntPlease();
  q = anIntPlease();
  assert(unknown);
  assert(unknown == 0);
  assert(x);
  assert(y);
  assert(x == y);
  assert(p);
  assert(q);
  assert(p == q);
  if (unknown)
    assert(1);
  else
    assert(1);
  if (x == y)
    assert(1);
  else
    assert(1);
  if (p == q)
    assert(1);
  else
    assert(1);
  p = &x;
  if (p == q)
    assert(1);
  else
    assert(1);
  assert(p == &x);
  if (q == p)
    assert(1);
  else
    assert(1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fts_lfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L18
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void fts_lfree(FTSENT *head) {
  FTSENT *p;
  while ((p = head)) {
    head = head->fts_link;
    free(p);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fts_lfree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L10
L7:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L7
L10:
  pop    %rbx
  ret
```

assistant: ```c
void fts_lfree(FTSENT *head) {
  FTSENT *p;
  while ((p = head)) {
    head = head->fts_link;
    free(p);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fts_lfree>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L13:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L13
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void fts_lfree(FTSENT *head) {
  FTSENT *p;
  while ((p = head)) {
    head = head->fts_link;
    free(p);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fts_lfree>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L13:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L13
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void fts_lfree(FTSENT *head) {
  FTSENT *p;
  while ((p = head)) {
    head = head->fts_link;
    free(p);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_php_image_output_ctxfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <efree@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void _php_image_output_ctxfree(struct gdIOCtx *ctx) {
  if (ctx) {
    efree(ctx);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_php_image_output_ctxfree>:
  endbr64
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  call   <efree@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void _php_image_output_ctxfree(struct gdIOCtx *ctx) {
  if (ctx) {
    efree(ctx);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_php_image_output_ctxfree>:
  endbr64
  test   %rdi,%rdi
  je     L2
  jmp    1050 <efree@plt>
  xchg   %ax,%ax
L2:
  ret
```

assistant: ```c
void _php_image_output_ctxfree(struct gdIOCtx *ctx) {
  if (ctx) {
    efree(ctx);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_php_image_output_ctxfree>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <efree@plt>
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void _php_image_output_ctxfree(struct gdIOCtx *ctx) {
  if (ctx) {
    efree(ctx);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_header_val@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <add_header@plt>
  jmp    L12
L7:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L26
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L26:
  mov    -0x8(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
L12:
  nop
  leave
  ret
```

assistant: ```c
void set_header(struct http_pkg *pkg, char *key, char *val) {
  char **old_val = get_header_val(pkg, key);
  if (old_val == NULL) {
    add_header(pkg, key, *old_val);
  } else {
    do {
      if (*old_val != NULL) {
        free(*old_val);
        *old_val = NULL;
      }
    } while (0);
    *old_val = val;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_header>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  call   <get_header_val@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rbx
  mov    (%rax),%rdi
  test   %rdi,%rdi
  je     L10
  call   <free@plt>
L10:
  mov    %r13,(%rbx)
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    0x0,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_header@plt>
  jmp    L21
```

assistant: ```c
void set_header(struct http_pkg *pkg, char *key, char *val) {
  char **old_val = get_header_val(pkg, key);
  if (old_val == NULL) {
    add_header(pkg, key, *old_val);
  } else {
    do {
      if (*old_val != NULL) {
        free(*old_val);
        *old_val = NULL;
      }
    } while (0);
    *old_val = val;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_header>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <get_header_val@plt>
  test   %rax,%rax
  je     L9
  mov    (%rax),%rdi
  mov    %rax,%rbx
  test   %rdi,%rdi
  je     L6
  call   <free@plt>
L6:
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  mov    0x0,%rax
  ud2
```

assistant: ```c
void set_header(struct http_pkg *pkg, char *key, char *val) {
  char **old_val = get_header_val(pkg, key);
  if (old_val == NULL) {
    add_header(pkg, key, *old_val);
  } else {
    do {
      if (*old_val != NULL) {
        free(*old_val);
        *old_val = NULL;
      }
    } while (0);
    *old_val = val;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_header>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <get_header_val@plt>
  test   %rax,%rax
  je     L16
  mov    (%rax),%rdi
  mov    %rax,%rbx
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
L3:
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  mov    0x0,%rax
  ud2
```

assistant: ```c
void set_header(struct http_pkg *pkg, char *key, char *val) {
  char **old_val = get_header_val(pkg, key);
  if (old_val == NULL) {
    add_header(pkg, key, *old_val);
  } else {
    do {
      if (*old_val != NULL) {
        free(*old_val);
        *old_val = NULL;
      }
    } while (0);
    *old_val = val;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L21
L49:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L21
  mov    -0x4(%rbp),%eax
  jmp    L24
L21:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    int c = *s1++ - *s2++;
    if (c) {
      return c;
    }
  }
  return *s1 - *s2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
L26:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L4
  add    $0x1,%rdi
  add    $0x1,%rsi
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  je     L26
  jmp    L39
L4:
  movsbl %al,%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
L39:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    int c = *s1++ - *s2++;
    if (c) {
      return c;
    }
  }
  return *s1 - *s2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %eax,%r9d
  sub    %r8d,%r9d
  test   %r8b,%r8b
  je     L37
  add    $0x1,%rdx
  test   %r9d,%r9d
  jne    L4
L19:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%r8d
  test   %al,%al
  jne    L6
  xor    %eax,%eax
L34:
  sub    %r8d,%eax
  mov    %eax,%r9d
L4:
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L37:
  xor    %r8d,%r8d
  jmp    L34
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    int c = *s1++ - *s2++;
    if (c) {
      return c;
    }
  }
  return *s1 - *s2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %eax,%r9d
  sub    %r8d,%r9d
  test   %r8b,%r8b
  je     L45
  add    $0x1,%rdx
  test   %r9d,%r9d
  jne    L32
L13:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%r8d
  test   %al,%al
  jne    L46
  xor    %eax,%eax
L20:
  sub    %r8d,%eax
  mov    %eax,%r9d
L32:
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L45:
  xor    %r8d,%r8d
  jmp    L20
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    int c = *s1++ - *s2++;
    if (c) {
      return c;
    }
  }
  return *s1 - *s2;
}
```