ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<wcsicmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    (%rdi),%r14d
  test   %r14d,%r14d
  jne    L53
  jmp    L1
  nopl   0x0(%rax)
L61:
  mov    %r15d,%edi
  call   <towlower@plt>
  cmp    %ebp,%eax
  jne    L56
  add    $0x4,%rbx
  mov    0x0(%r13,%rbx,1),%r14d
  test   %r14d,%r14d
  je     L69
L53:
  lea    (%r12,%rbx,1),%rax
  mov    %r14d,%edi
  mov    (%r12,%rbx,1),%r15d
  mov    %rax,0x8(%rsp)
  call   <towlower@plt>
  mov    %eax,%ebp
  test   %r15d,%r15d
  jne    L61
L22:
  mov    %r14d,%edi
  call   <towlower@plt>
  mov    %eax,%ebp
  mov    0x8(%rsp),%rax
  mov    (%rax),%edi
  call   <towlower@plt>
L56:
  mov    %ebp,%r8d
  add    $0x18,%rsp
  sub    %eax,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L69:
  lea    (%r12,%rbx,1),%rax
  mov    %rax,0x8(%rsp)
  jmp    L22
L1:
  mov    %rsi,0x8(%rsp)
  jmp    L22
```

assistant: ```c
int wcsicmp(const wchar_t *s1, const wchar_t *s2) {
  int i;
  for (i = 0; s1[i] != L'\0' && s2[i] != L'\0'; i++) {
    wint_t x = towlower(s1[i]);
    wint_t y = towlower(s2[i]);
    if (x != y)
      return x - y;
  }
  return towlower(s1[i]) - towlower(s2[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alarm_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D17
data_type: string

tool: D2: Got SIGALRM after 1 second


tool: D17: Test PASSED


assistant: ```c
void alarm_handler(int signo __attribute__((unused))) {
  printf("Got SIGALRM after 1 second\n");
  printf("Test PASSED\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alarm_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string

tool: D1: Got SIGALRM after 1 second


tool: D15: Test PASSED


assistant: ```c
void alarm_handler(int signo __attribute__((unused))) {
  printf("Got SIGALRM after 1 second\n");
  printf("Test PASSED\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<alarm_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D10: Got SIGALRM after 1 second


tool: D14: Test PASSED


assistant: ```c
void alarm_handler(int signo __attribute__((unused))) {
  printf("Got SIGALRM after 1 second\n");
  printf("Test PASSED\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<alarm_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D10: Got SIGALRM after 1 second


tool: D5: Test PASSED


assistant: ```c
void alarm_handler(int signo __attribute__((unused))) {
  printf("Got SIGALRM after 1 second\n");
  printf("Test PASSED\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rotatey_v3fo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movss  %xmm0,-0x54(%rbp)
  mov    %rdi,-0x60(%rbp)
  mov    %rsi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rdi
  movd   %eax,%xmm0
  call   <m3f_fill_roty_m3fo@plt>
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <m3f_mul_m3fo@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void rotatey_v3fo(float ry, const float *v, float *result) {
  float rm[16];
  m3f_fill_roty_m3fo(ry, rm);
  m3f_mul_m3fo(rm, v, result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotatey_v3fo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <m3f_fill_roty_m3fo@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <m3f_mul_m3fo@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotatey_v3fo(float ry, const float *v, float *result) {
  float rm[16];
  m3f_fill_roty_m3fo(ry, rm);
  m3f_mul_m3fo(rm, v, result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rotatey_v3fo>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <m3f_fill_roty_m3fo@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <m3f_mul_m3fo@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotatey_v3fo(float ry, const float *v, float *result) {
  float rm[16];
  m3f_fill_roty_m3fo(ry, rm);
  m3f_mul_m3fo(rm, v, result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotatey_v3fo>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <m3f_fill_roty_m3fo@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <m3f_mul_m3fo@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotatey_v3fo(float ry, const float *v, float *result) {
  float rm[16];
  m3f_fill_roty_m3fo(ry, rm);
  m3f_mul_m3fo(rm, v, result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xf4240,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  movb   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x1,(%rax)
  xchg   %bx,%bx
  movl   $0x2,-0xc(%rbp)
  jmp    L6
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mark@plt>
L23:
  addl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0xf423f,-0xc(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rax
  mov    $0xf4240,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sum@plt>
  mov    %eax,%edx
  mov    $0xf4240,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0xf4240,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D20
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string

tool: D20: Allocating space

tool: D30: Counting

tool: D6: Primes less than %d: %d


tool: D25: Done

assistant: ```c
int main(int argc, char **argv) {
  int i;
  char *nonprime;
  printf("Allocating space\n");
  nonprime = (char *)calloc(1, 1000000);
  printf("Counting\n");
  nonprime[0] = 1;
  nonprime[1] = 1;
  do {
    __asm__ __volatile__("xchg %bx,%bx");
  } while (0);
  for (i = 2; i < 1000000; i++)
    if (!nonprime[i])
      mark(nonprime, 2 * i, i);
  printf("Primes less than %d: %d\n", 1000000, 1000000 - sum(nonprime, 1000000));
  printf("Done\n");
  free(nonprime);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0xf4240,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  lea    D18(%rip),%rdi
  call   <puts@plt>
  movb   $0x1,0x0(%rbp)
  movb   $0x1,0x1(%rbp)
  xchg   %bx,%bx
  mov    $0x2,%ebx
  jmp    L38
L26:
  add    $0x1,%rbx
  cmp    $0xf4240,%rbx
  je     L11
L38:
  mov    %ebx,%edx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L26
  lea    (%rbx,%rbx,1),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <mark@plt>
  jmp    L26
L11:
  mov    $0xf4240,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sum@plt>
  mov    $0xf4240,%edx
  sub    %eax,%edx
  mov    $0xf4240,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D30
datatype: string
name: extract_symbolic_data
arguments: data_tag: D37
datatype: string

tool: D14: Allocating space

tool: D18: Counting

tool: D30: Primes less than %d: %d


tool: D37: Done

assistant: ```c
int main(int argc, char **argv) {
  int i;
  char *nonprime;
  printf("Allocating space\n");
  nonprime = (char *)calloc(1, 1000000);
  printf("Counting\n");
  nonprime[0] = 1;
  nonprime[1] = 1;
  do {
    __asm__ __volatile__("xchg %bx,%bx");
  } while (0);
  for (i = 2; i < 1000000; i++)
    if (!nonprime[i])
      mark(nonprime, 2 * i, i);
  printf("Primes less than %d: %d\n", 1000000, 1000000 - sum(nonprime, 1000000));
  printf("Done\n");
  free(nonprime);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0xf4240,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  lea    D13(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    $0x101,%eax
  mov    %ax,0x0(%rbp)
  xchg   %bx,%bx
  mov    $0x2,%ebx
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
  cmp    $0xf4240,%rbx
  je     L27
L36:
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  mov    %ebx,%edx
  jne    L4
  lea    (%rbx,%rbx,1),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <mark@plt>
  cmp    $0xf4240,%rbx
  jne    L36
L27:
  mov    %rbp,%rdi
  mov    $0xf4240,%esi
  xor    %eax,%eax
  call   <sum@plt>
  mov    $0xf4240,%edx
  mov    $0xf4240,%esi
  lea    D38(%rip),%rdi
  sub    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D8: Allocating space

tool: D13: Counting

tool: D38: Primes less than %d: %d


tool: D27: Done

assistant: ```c
int main(int argc, char **argv) {
  int i;
  char *nonprime;
  printf("Allocating space\n");
  nonprime = (char *)calloc(1, 1000000);
  printf("Counting\n");
  nonprime[0] = 1;
  nonprime[1] = 1;
  do {
    __asm__ __volatile__("xchg %bx,%bx");
  } while (0);
  for (i = 2; i < 1000000; i++)
    if (!nonprime[i])
      mark(nonprime, 2 * i, i);
  printf("Primes less than %d: %d\n", 1000000, 1000000 - sum(nonprime, 1000000));
  printf("Done\n");
  free(nonprime);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0xf4240,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    $0x101,%eax
  mov    %ax,0x0(%rbp)
  xchg   %bx,%bx
  mov    $0x2,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rbx
  cmp    $0xf4240,%rbx
  je     L17
L16:
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  mov    %ebx,%edx
  jne    L18
  lea    (%rbx,%rbx,1),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <mark@plt>
  cmp    $0xf4240,%rbx
  jne    L16
L17:
  mov    %rbp,%rdi
  mov    $0xf4240,%esi
  xor    %eax,%eax
  call   <sum@plt>
  mov    $0xf4240,%edx
  mov    $0xf4240,%esi
  lea    D26(%rip),%rdi
  sub    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D33
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string

tool: D33: Allocating space

tool: D12: Counting

tool: D26: Primes less than %d: %d


tool: D16: Done

assistant: ```c
int main(int argc, char **argv) {
  int i;
  char *nonprime;
  printf("Allocating space\n");
  nonprime = (char *)calloc(1, 1000000);
  printf("Counting\n");
  nonprime[0] = 1;
  nonprime[1] = 1;
  do {
    __asm__ __volatile__("xchg %bx,%bx");
  } while (0);
  for (i = 2; i < 1000000; i++)
    if (!nonprime[i])
      mark(nonprime, 2 * i, i);
  printf("Primes less than %d: %d\n", 1000000, 1000000 - sum(nonprime, 1000000));
  printf("Done\n");
  free(nonprime);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mdelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void mdelay(unsigned msecs) {
  struct timespec req;
  req.tv_sec = msecs / 1000;
  req.tv_nsec = (msecs % 1000) * 1000000;
  nanosleep(&req, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mdelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mdelay(unsigned msecs) {
  struct timespec req;
  req.tv_sec = msecs / 1000;
  req.tv_nsec = (msecs % 1000) * 1000000;
  nanosleep(&req, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mdelay>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mdelay(unsigned msecs) {
  struct timespec req;
  req.tv_sec = msecs / 1000;
  req.tv_nsec = (msecs % 1000) * 1000000;
  nanosleep(&req, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mdelay>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  imul   $0xf4240,%edi,%edi
  movd   %edi,%xmm1
  mov    %rsp,%rdi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mdelay(unsigned msecs) {
  struct timespec req;
  req.tv_sec = msecs / 1000;
  req.tv_nsec = (msecs % 1000) * 1000000;
  nanosleep(&req, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L20
L21:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x16(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzwl -0x16(%rbp),%eax
  test   %ax,%ax
  je     L21
  movzwl -0x16(%rbp),%eax
  cwtl
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <func_posneg@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D44
data_type: string
name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D41
data_type: string

tool: D44: Cantidad de numeros: 

tool: D31: %d

tool: D0: Numero: 

tool: D19: %hd

tool: D41: %s



assistant: ```c
int main(void) {
  int n, i, resul = 0;
  short int num;
  printf("Cantidad de numeros: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    do {
      printf("Numero: ");
      scanf("%hd", &num);
    } while (num == 0);
    resul = func_posneg(num);
    printf("%s\n\n", resul);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L28
  mov    $0x1,%r13d
  lea    D27(%rip),%r12
  lea    0x2(%rsp),%rbp
  lea    D29(%rip),%rbx
  lea    D13(%rip),%r14
L1:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzwl 0x2(%rsp),%edi
  test   %di,%di
  je     L1
  movswl %di,%edi
  mov    $0x0,%eax
  call   <func_posneg@plt>
  mov    %eax,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    %r13d,0x4(%rsp)
  jge    L1
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D40
datatype: string
name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D29
datatype: string
name: read_data
arguments: label: D13
datatype: string

tool: D40: Cantidad de numeros: 

tool: D8: %d

tool: D27: Numero: 

tool: D29: %hd

tool: D13: %s



assistant: ```c
int main(void) {
  int n, i, resul = 0;
  short int num;
  printf("Cantidad de numeros: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    do {
      printf("Numero: ");
      scanf("%hd", &num);
    } while (num == 0);
    resul = func_posneg(num);
    printf("%s\n\n", resul);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L11
  mov    $0x1,%r13d
  lea    D7(%rip),%r12
  lea    0x2(%rsp),%rbp
  lea    D45(%rip),%rbx
  lea    D21(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  movswl 0x2(%rsp),%edi
  test   %di,%di
  je     L17
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <func_posneg@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r13d,0x4(%rsp)
  jge    L17
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D28
type: string
name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D45
type: string
name: parse_data
arguments: data_label: D21
type: string

tool: D28: Cantidad de numeros: 

tool: D22: %d

tool: D7: Numero: 

tool: D45: %hd

tool: D21: %s



assistant: ```c
int main(void) {
  int n, i, resul = 0;
  short int num;
  printf("Cantidad de numeros: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    do {
      printf("Numero: ");
      scanf("%hd", &num);
    } while (num == 0);
    resul = func_posneg(num);
    printf("%s\n\n", resul);
  }
  return 0;
}
```