ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_argument>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  movzbl 0x0(%r13),%edi
  mov    %r13,%rbx
  test   %dil,%dil
  je     L87
L143:
  movsbl %dil,%edi
  call   <isblank@plt>
  test   %rax,%rax
  je     L63
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L143
L87:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rbx
  jmp    L55
L63:
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L87
  cmp    $0x22,%dl
  je     L66
  mov    $0x20,%edx
L4:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L61
  cmp    %al,%dl
  je     L61
  test   %r12,%r12
  je     L107
  add    %rbx,%r12
L182:
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L61
  cmp    %dl,%al
  je     L61
  cmp    %r12,%rbx
  jne    L182
L154:
  movb   $0x0,0x0(%rbp)
  movzbl (%r12),%eax
  test   %al,%al
  je     L156
  cmp    %al,%dl
  je     L156
L152:
  add    $0x1,%r12
  movzbl (%r12),%eax
  test   %al,%al
  je     L164
  cmp    %dl,%al
  jne    L152
L164:
  mov    %r12,%rbx
  jmp    L55
L66:
  add    $0x1,%rbx
  jmp    L4
L107:
  mov    %rbx,%r12
  jmp    L154
L61:
  movb   $0x0,0x0(%rbp)
L55:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L156:
  mov    %r12,%rbx
  jmp    L55
```

assistant: ```c
char *extract_argument(char *source, char *destination, size_t size) {
  assert(source);
  assert(destination);
  char *current = source;
  char *write = destination;
  while (*current != '\0' && isblank(*current)) {
    current++;
  }
  if (*current == '\0') {
    *write = '\0';
    return source;
  }
  char terminator = ' ';
  if (*current == '"') {
    terminator = '"';
    current++;
  }
  size_t count = 0;
  while (*current != terminator && *current != '\0') {
    if (count++ == size) {
      *write = '\0';
      while (*current != terminator && *current != '\0') {
        current++;
      }
      return current;
    }
    *write++ = *current++;
  }
  *write = '\0';
  return current;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extract_argument>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r13,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L64
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L40:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L60
L64:
  call   <isblank@plt>
  test   %rax,%rax
  jne    L40
  movzbl (%r12),%eax
  test   %al,%al
  je     L60
  mov    $0x20,%edx
  cmp    $0x22,%al
  je     L172
L73:
  test   %al,%al
  je     L74
  cmp    %al,%dl
  je     L74
  test   %rbp,%rbp
  je     L41
  add    %r12,%rbp
  jmp    L107
  nopl   (%rax)
L85:
  cmp    %dl,%al
  je     L74
  cmp    %r12,%rbp
  je     L97
L107:
  add    $0x1,%r12
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%r12),%eax
  test   %al,%al
  jne    L85
L74:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L172:
  movzbl 0x1(%r12),%eax
  mov    $0x22,%edx
  add    $0x1,%r12
  jmp    L73
  nopl   0x0(%rax)
L60:
  mov    %r13,%r12
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  mov    %r12,%rbp
  nop
L97:
  movb   $0x0,(%rbx)
  movzbl 0x0(%rbp),%eax
  cmp    %al,%dl
  je     L35
  test   %al,%al
  jne    L148
L35:
  add    $0x8,%rsp
  mov    %rbp,%r12
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  cmp    %dl,%al
  je     L35
L148:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  jne    L0
  jmp    L35
```

assistant: ```c
char *extract_argument(char *source, char *destination, size_t size) {
  assert(source);
  assert(destination);
  char *current = source;
  char *write = destination;
  while (*current != '\0' && isblank(*current)) {
    current++;
  }
  if (*current == '\0') {
    *write = '\0';
    return source;
  }
  char terminator = ' ';
  if (*current == '"') {
    terminator = '"';
    current++;
  }
  size_t count = 0;
  while (*current != terminator && *current != '\0') {
    if (count++ == size) {
      *write = '\0';
      while (*current != terminator && *current != '\0') {
        current++;
      }
      return current;
    }
    *write++ = *current++;
  }
  *write = '\0';
  return current;
}
```
user: What is the c source code of the assembly code below:

```asm
<extract_argument>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r13,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L174
  jmp    L57
  cs nopw 0x0(%rax,%rax,1)
L73:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L57
L174:
  call   <isblank@plt>
  test   %rax,%rax
  jne    L73
  movzbl (%r12),%eax
  test   %al,%al
  je     L57
  mov    $0x20,%edx
  cmp    $0x22,%al
  je     L27
L144:
  test   %al,%al
  je     L127
  cmp    %al,%dl
  je     L127
  test   %rbp,%rbp
  je     L173
  add    %r12,%rbp
  jmp    L18
  nopl   (%rax)
L142:
  cmp    %dl,%al
  je     L127
  cmp    %rbp,%r12
  je     L133
L18:
  add    $0x1,%r12
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%r12),%eax
  test   %al,%al
  jne    L142
L127:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L27:
  movzbl 0x1(%r12),%eax
  mov    $0x22,%edx
  add    $0x1,%r12
  jmp    L144
  nopl   0x0(%rax)
L57:
  mov    %r13,%r12
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L173:
  mov    %r12,%rbp
  nop
L133:
  movb   $0x0,(%rbx)
  movzbl 0x0(%rbp),%eax
  cmp    %al,%dl
  je     L108
  test   %al,%al
  jne    L67
L108:
  add    $0x8,%rsp
  mov    %rbp,%r12
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L97:
  cmp    %dl,%al
  je     L108
L67:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  jne    L97
  jmp    L108
```

assistant: ```c
char *extract_argument(char *source, char *destination, size_t size) {
  assert(source);
  assert(destination);
  char *current = source;
  char *write = destination;
  while (*current != '\0' && isblank(*current)) {
    current++;
  }
  if (*current == '\0') {
    *write = '\0';
    return source;
  }
  char terminator = ' ';
  if (*current == '"') {
    terminator = '"';
    current++;
  }
  size_t count = 0;
  while (*current != terminator && *current != '\0') {
    if (count++ == size) {
      *write = '\0';
      while (*current != terminator && *current != '\0') {
        current++;
      }
      return current;
    }
    *write++ = *current++;
  }
  *write = '\0';
  return current;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <start_routine@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  start_routine(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <start_routine@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  start_routine(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <start_routine@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  start_routine(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <start_routine@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  start_routine(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<create_group>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x18(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L68
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L30
L68:
  lea    D27(%rip),%rax
  mov    %rax,-0x10(%rbp)
L30:
  cmpl   $0x2,-0x24(%rbp)
  jle    L51
  mov    -0x30(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L51:
  lea    D47(%rip),%rax
  mov    %rax,-0x8(%rbp)
L49:
  cmpl   $0x3,-0x24(%rbp)
  jle    L71
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  jmp    L19
L71:
  movl   $0x1,-0x18(%rbp)
L19:
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <client_create_group@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L23
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L60
L23:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <run_netplay@plt>
  mov    $0x0,%eax
L60:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type: string
name: extract_symbolic_data
arguments: label: D47
type: string
name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D23
type: string
name: extract_symbolic_data
arguments: label: D15
type: string

tool: D27: testroom

tool: 

tool: D13: create room, %d, name:%s, passwd:%s


tool: D23: create room fail.

tool: D15: wait other player.

assistant: ```c
int create_group(int argc, char **argv) {
  int ret;
  int open = 1;
  char *name;
  char *passwd;
  if (argc > 1)
    name = argv[1];
  else
    name = "testroom";
  if (argc > 2)
    passwd = argv[2];
  else
    passwd = "";
  if (argc > 3)
    open = atoi(argv[3]);
  else
    open = 1;
  printf("create room, %d, name:%s, passwd:%s\n", open, name, passwd);
  ret = client_create_group(open, name, passwd);
  if (ret) {
    printf("create room fail.\n");
    return -1;
  }
  printf("wait other player.\n");
  run_netplay();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_group>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbp
  cmp    $0x1,%edi
  jle    L30
  mov    0x8(%rsi),%rbp
L30:
  lea    D15(%rip),%r12
  cmp    $0x2,%edi
  jle    L10
  mov    0x10(%rsi),%r12
L10:
  mov    $0x1,%ebx
  cmp    $0x3,%edi
  jg     L26
L1:
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <client_create_group@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L25
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <run_netplay@plt>
L56:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    0x18(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  jmp    L1
L25:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%ebx
  jmp    L56
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string

tool: D12: testroom

tool: 

tool: D17: create room, %d, name:%s, passwd:%s


tool: D22: wait other player.

tool: D29: create room fail.

assistant: ```c
int create_group(int argc, char **argv) {
  int ret;
  int open = 1;
  char *name;
  char *passwd;
  if (argc > 1)
    name = argv[1];
  else
    name = "testroom";
  if (argc > 2)
    passwd = argv[2];
  else
    passwd = "";
  if (argc > 3)
    open = atoi(argv[3]);
  else
    open = 1;
  printf("create room, %d, name:%s, passwd:%s\n", open, name, passwd);
  ret = client_create_group(open, name, passwd);
  if (ret) {
    printf("create room fail.\n");
    return -1;
  }
  printf("wait other player.\n");
  run_netplay();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<create_group>:
  endbr64
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D15(%rip),%rbp
  cmp    $0x1,%edi
  jle    L40
  mov    0x8(%rsi),%rbp
  cmp    $0x2,%edi
  je     L40
  mov    0x10(%rsi),%r13
  cmp    $0x3,%edi
  je     L40
  mov    0x18(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
L40:
  mov    %r12d,%esi
  mov    %r13,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <client_create_group@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L28
  lea    D27(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <run_netplay@plt>
L35:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D30(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  jmp    L35
```

tool_calls: name: parse_data
arguments: data_label: D24
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D30
type_infered: string

tool: 

tool: D15: testroom

tool: D29: create room, %d, name:%s, passwd:%s


tool: D27: wait other player.

tool: D30: create room fail.

assistant: ```c
int create_group(int argc, char **argv) {
  int ret;
  int open = 1;
  char *name;
  char *passwd;
  if (argc > 1)
    name = argv[1];
  else
    name = "testroom";
  if (argc > 2)
    passwd = argv[2];
  else
    passwd = "";
  if (argc > 3)
    open = atoi(argv[3]);
  else
    open = 1;
  printf("create room, %d, name:%s, passwd:%s\n", open, name, passwd);
  ret = client_create_group(open, name, passwd);
  if (ret) {
    printf("create room fail.\n");
    return -1;
  }
  printf("wait other player.\n");
  run_netplay();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_group>:
  endbr64
  push   %r13
  lea    D49(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D8(%rip),%rbp
  cmp    $0x1,%edi
  jle    L30
  mov    0x8(%rsi),%rbp
  cmp    $0x2,%edi
  je     L30
  mov    0x10(%rsi),%r13
  cmp    $0x3,%edi
  je     L30
  mov    0x18(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
L30:
  mov    %r12d,%esi
  mov    %r13,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <client_create_group@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L28
  lea    D33(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <run_netplay@plt>
L2:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D41(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_tag: D49
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D35
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string
name: read_data
arguments: data_tag: D41
data_type: string

tool: 

tool: D8: testroom

tool: D35: create room, %d, name:%s, passwd:%s


tool: D33: wait other player.

tool: D41: create room fail.

assistant: ```c
int create_group(int argc, char **argv) {
  int ret;
  int open = 1;
  char *name;
  char *passwd;
  if (argc > 1)
    name = argv[1];
  else
    name = "testroom";
  if (argc > 2)
    passwd = argv[2];
  else
    passwd = "";
  if (argc > 3)
    open = atoi(argv[3]);
  else
    open = 1;
  printf("create room, %d, name:%s, passwd:%s\n", open, name, passwd);
  ret = client_create_group(open, name, passwd);
  if (ret) {
    printf("create room fail.\n");
    return -1;
  }
  printf("wait other player.\n");
  run_netplay();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movabs $0x755372457453614d,%rax
  movabs $0x7245705968526550,%rdx
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  movl   $0x59654b,-0x70(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movabs $0x38577a2b72273f58,%rax
  mov    $0x73554650,%edx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x88(%rbp)
  jmp    L29
L26:
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    -0x88(%rbp),%eax
  movslq %eax,%rbx
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rcx
  mov    %rcx,%rax
  mov    %eax,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x84(%rbp)
  mov    -0x84(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  sub    $0x30,%eax
  mov    %eax,%edx
  mov    -0x88(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  add    $0x64,%eax
  xor    %edx,%eax
  sub    $0x31,%eax
  mov    %eax,%edx
  mov    -0x88(%rbp),%eax
  cltq
  mov    %dl,-0x60(%rbp,%rax,1)
  subl   $0x1,-0x88(%rbp)
L29:
  cmpl   $0x0,-0x88(%rbp)
  jns    L26
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: Password: %s


assistant: ```c
int main(void) {
  char key[] = {"MaStErSuPeRhYpErKeY"};
  char pass[32] = {0};
  char hash[32] = {"X?'r+zW8PFUs"};
  int idx, ckey;
  for (idx = strlen(hash) - 1; idx >= 0; ckey = strlen(key) - (idx % strlen(key)) - 1, pass[idx] = ((key[ckey] - '0') ^ (hash[idx] + 100)) - '1', idx--)
    ;
  printf("Password: %s\n", pass);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x755372457453614d,%rax
  movabs $0x7245705968526550,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x59654b,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movabs $0x38577a2b72273f58,%rax
  mov    $0x73554650,%edx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  lea    0x40(%rsp),%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L7
  movslq %eax,%rbx
  mov    %rsp,%rbp
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  lea    -0x1(%rax),%ecx
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rsi
  sub    %edx,%ecx
  movslq %ecx,%rcx
  movzbl (%rsp,%rcx,1),%eax
  sub    $0x30,%eax
  movzbl 0x40(%rsp,%rbx,1),%edi
  lea    0x64(%rdi),%edx
  xor    %edx,%eax
  sub    $0x31,%eax
  mov    %al,0x20(%rsp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L9
L7:
  lea    0x20(%rsp),%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: Password: %s


assistant: ```c
int main(void) {
  char key[] = {"MaStErSuPeRhYpErKeY"};
  char pass[32] = {0};
  char hash[32] = {"X?'r+zW8PFUs"};
  int idx, ckey;
  for (idx = strlen(hash) - 1; idx >= 0; ckey = strlen(key) - (idx % strlen(key)) - 1, pass[idx] = ((key[ckey] - '0') ^ (hash[idx] + 100)) - '1', idx--)
    ;
  printf("Password: %s\n", pass);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    $0xb,%ecx
  mov    $0x12,%edi
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    0x40(%rsp),%r9
  movdqa D3(%rip),%xmm1
  movabs $0xd79435e50d79435f,%r8
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movl   $0x59654b,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm1,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rcx,%rax
  mul    %r8
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  mov    %edi,%eax
  sub    %edx,%eax
  movzbl (%r9,%rcx,1),%edx
  cltq
  movzbl (%rsp,%rax,1),%eax
  add    $0x64,%edx
  sub    $0x30,%eax
  xor    %edx,%eax
  sub    $0x31,%eax
  mov    %al,(%rsi,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffff,%ecx
  jne    L4
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
datatype: byte[16]
name: unpack_data
arguments: data_tag: D3
datatype: byte[16]
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: {"D26": [0x4d,0x61,0x53,0x74,0x45,0x72,0x53,0x75,0x50,0x65,0x52,0x68,0x59,0x70,0x45,0x72]}

tool: {"D3": [0x58,0x3f,0x27,0x72,0x2b,0x7a,0x57,0x38,0x50,0x46,0x55,0x73,0x00,0x00,0x00,0x00]}

tool: D16: Password: %s


assistant: ```c
int main(void) {
  char key[] = {"MaStErSuPeRhYpErKeY"};
  char pass[32] = {0};
  char hash[32] = {"X?'r+zW8PFUs"};
  int idx, ckey;
  for (idx = strlen(hash) - 1; idx >= 0; ckey = strlen(key) - (idx % strlen(key)) - 1, pass[idx] = ((key[ckey] - '0') ^ (hash[idx] + 100)) - '1', idx--)
    ;
  printf("Password: %s\n", pass);
  return 0;
}
```