ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D72(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D64(%rip),%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm0
  mov    0x8(%rsp),%rsi
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  addss  0x20(%rsp),%xmm0
  divss  D41(%rip),%xmm0
  comiss D9(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  jbe    L6
  lea    D56(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L6:
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L28
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D52
type: string
name: unpack_data
arguments: tag: D72
type: string
name: unpack_data
arguments: tag: D64
type: string
name: unpack_data
arguments: tag: D41
type: byte[4]
name: unpack_data
arguments: tag: D9
type: byte[4]
name: unpack_data
arguments: tag: D56
type: string
name: unpack_data
arguments: tag: D38
type: string

tool: D7: Ingresa tu matricula

tool: D52: %ld

tool: D72: Ingresa la calificacion de 5 materias, separadas por un espacio

tool: D64: %f %f %f %f %f

tool: {"D41": [0x00,0x00,0xa0,0x40]}

tool: {"D9": [0x00,0x00,0xc0,0x40]}

tool: D56: Aprobado : %ld ::: %.1f 


tool: D38: %ld ::: %.1f 


assistant: ```c
void main() {
  long int matricula;
  float calf[5], promedio;
  printf("Ingresa tu matricula\n");
  scanf("%ld", &matricula);
  printf("Ingresa la calificacion de 5 materias, separadas por un espacio\n");
  scanf("%f %f %f %f %f", &calf[0], &calf[1], &calf[2], &calf[3], &calf[4]);
  promedio = (calf[0] + calf[1] + calf[2] + calf[3] + calf[4]) / 5;
  if (promedio > 6) {
    printf("Aprobado : %ld ::: %.1f \n", matricula, promedio);
  } else {
    printf("%ld ::: %.1f \n", matricula, promedio);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DoShortTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %esi,-0x12c(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movw   $0xffff,-0x112(%rbp)
  lea    -0x112(%rbp),%rdx
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <testvsp@plt>
  movzwl -0x112(%rbp),%eax
  cwtl
  cmp    %eax,-0x12c(%rbp)
  je     L6
  movzwl -0x112(%rbp),%eax
  movswl %ax,%edx
  mov    -0x12c(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
L6:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x138(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L15
  lea    -0x110(%rbp),%rdx
  mov    -0x138(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
L15:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string

tool: D7: ERROR: Expected count parameter to resolve to %d, got %X


tool: D11: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoShortTest(const char *formatstr, int param, const char *checkstr) {
  char buf[256] = {0};
  short int n = -1;
  testvsp(buf, formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(buf) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<DoShortTest>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  movq   $0x0,0x100(%rsp)
  movq   $0x0,0x108(%rsp)
  movw   $0xffff,0xe(%rsp)
  lea    0xe(%rsp),%rdx
  lea    0x10(%rsp),%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <testvsp@plt>
  movswl 0xe(%rsp),%edx
  cmp    %ebx,%edx
  jne    L10
L27:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L9
L40:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
  jmp    L27
L9:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
  jmp    L40
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D2
data_type: string

tool: D16: ERROR: Expected count parameter to resolve to %d, got %X


tool: D2: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoShortTest(const char *formatstr, int param, const char *checkstr) {
  char buf[256] = {0};
  short int n = -1;
  testvsp(buf, formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(buf) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DoShortTest>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    $0xffffffff,%eax
  lea    0xe(%rsp),%rdx
  mov    %r13,%rdi
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  call   <testvsp@plt>
  movswl 0xe(%rsp),%edx
  cmp    %ebp,%edx
  je     L3
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <Fail@plt>
L3:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  lea    0x1(%rax),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L9
L25:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r13,%rdx
  mov    %r12,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <Fail@plt>
  jmp    L25
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D13
datatype: string

tool: D16: ERROR: Expected count parameter to resolve to %d, got %X


tool: D13: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoShortTest(const char *formatstr, int param, const char *checkstr) {
  char buf[256] = {0};
  short int n = -1;
  testvsp(buf, formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(buf) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DoShortTest>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    $0xffffffff,%eax
  lea    0xe(%rsp),%rdx
  mov    %r13,%rdi
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  call   <testvsp@plt>
  movswl 0xe(%rsp),%edx
  cmp    %ebp,%edx
  je     L22
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <Fail@plt>
L22:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  lea    0x1(%rax),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L25
L23:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r13,%rdx
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <Fail@plt>
  jmp    L23
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D8: ERROR: Expected count parameter to resolve to %d, got %X


tool: D15: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoShortTest(const char *formatstr, int param, const char *checkstr) {
  char buf[256] = {0};
  short int n = -1;
  testvsp(buf, formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(buf) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  nop
L10:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  cmp    %rax,%rdx
  jge    L8
  mov    $0x0,%eax
  jmp    L62
L64:
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
  mov    $0x0,%eax
  jmp    L62
L8:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  ja     L64
  jmp    L40
L43:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L40:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L43
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L62:
  pop    %rbp
  ret
```

assistant: ```c
int suffix(char *a, char *b, char *p) {
  char *a0, *b0;
  a0 = a;
  b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<suffix>:
  endbr64
  mov    %rdi,%rcx
L24:
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L24
  mov    %rsi,%rax
L76:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L76
  mov    %rcx,%r10
  sub    %rdi,%r10
  mov    %rax,%r9
  sub    %rsi,%r9
  mov    $0x0,%r8d
  cmp    %r9,%r10
  jl     L26
L30:
  cmp    %rsi,%rax
  jbe    L79
  sub    $0x1,%rcx
  sub    $0x1,%rax
  movzbl (%rax),%r11d
  cmp    %r11b,(%rcx)
  je     L30
  mov    $0x0,%r8d
  jmp    L26
L79:
  cmp    %rdi,%rcx
  jbe    L40
  sub    %rdi,%rcx
  mov    $0x0,%eax
L43:
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L43
  add    %rcx,%rdx
L40:
  movb   $0x0,(%rdx)
  mov    $0x1,%r8d
L26:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int suffix(char *a, char *b, char *p) {
  char *a0, *b0;
  a0 = a;
  b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<suffix>:
  endbr64
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L9
  mov    %rsi,%rax
  nopl   (%rax)
L22:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L22
  mov    %rcx,%r10
  mov    %rax,%r9
  xor    %r8d,%r8d
  sub    %rdi,%r10
  sub    %rsi,%r9
  cmp    %r9,%r10
  jge    L21
  jmp    L39
L46:
  sub    $0x1,%rcx
  sub    $0x1,%rax
  movzbl (%rax),%r11d
  cmp    %r11b,(%rcx)
  jne    L43
L21:
  cmp    %rsi,%rax
  ja     L46
  cmp    %rdi,%rcx
  jbe    L69
  sub    %rdi,%rcx
  xor    %eax,%eax
L24:
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L24
  add    %rax,%rdx
L69:
  movb   $0x0,(%rdx)
  mov    $0x1,%r8d
L39:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L43:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int suffix(char *a, char *b, char *p) {
  char *a0, *b0;
  a0 = a;
  b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<suffix>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  nopl   (%rax)
L122:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L122
  mov    %rsi,%rax
  nopl   (%rax)
L109:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L109
  mov    %rdx,%r10
  mov    %rax,%r9
  xor    %r8d,%r8d
  sub    %rcx,%r10
  sub    %rsi,%r9
  cmp    %r9,%r10
  jge    L0
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L71:
  sub    $0x1,%rdx
  sub    $0x1,%rax
  movzbl (%rax),%r11d
  cmp    %r11b,(%rdx)
  jne    L201
L0:
  cmp    %rsi,%rax
  ja     L71
  cmp    %rcx,%rdx
  jbe    L154
  mov    %rdx,%rsi
  lea    0x1(%rcx),%r9
  mov    %rdi,%r8
  sub    %rcx,%rsi
  sub    %r9,%r8
  lea    -0x1(%rsi),%rax
  cmp    $0xe,%r8
  jbe    L51
  cmp    $0x6,%rax
  jbe    L51
  cmp    $0xe,%rax
  jbe    L151
  mov    %rsi,%r8
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%r8
  cs nopw 0x0(%rax,%rax,1)
L61:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L61
  mov    %rsi,%r9
  and    $0xfffffffffffffff0,%r9
  lea    (%rdi,%r9,1),%r8
  lea    (%rcx,%r9,1),%rax
  cmp    %r9,%rsi
  je     L193
  mov    %rsi,%r10
  sub    %r9,%r10
  lea    -0x1(%r10),%r11
  cmp    $0x6,%r11
  jbe    L197
L184:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%rdi,%r9,1)
  mov    %r10,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%r8
  add    %rcx,%rax
  cmp    %rcx,%r10
  je     L193
L197:
  movzbl (%rax),%ecx
  mov    %cl,(%r8)
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L193
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x1(%r8)
  lea    0x2(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L193
  movzbl 0x2(%rax),%ecx
  mov    %cl,0x2(%r8)
  lea    0x3(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L193
  movzbl 0x3(%rax),%ecx
  mov    %cl,0x3(%r8)
  lea    0x4(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L193
  movzbl 0x4(%rax),%ecx
  mov    %cl,0x4(%r8)
  lea    0x5(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L193
  movzbl 0x5(%rax),%ecx
  mov    %cl,0x5(%r8)
  lea    0x6(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L193
  movzbl 0x6(%rax),%eax
  mov    %al,0x6(%r8)
L193:
  add    %rsi,%rdi
L154:
  movb   $0x0,(%rdi)
  mov    $0x1,%r8d
L23:
  mov    %r8d,%eax
  ret
L201:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
L51:
  xor    %eax,%eax
  nopl   0x0(%rax)
L82:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L82
  jmp    L193
L151:
  mov    %rsi,%r10
  mov    %rcx,%rax
  mov    %rdi,%r8
  xor    %r9d,%r9d
  jmp    L184
```

assistant: ```c
int suffix(char *a, char *b, char *p) {
  char *a0, *b0;
  a0 = a;
  b0 = b;
  while (*a++)
    ;
  while (*b++)
    ;
  if ((a - a0) < (b - b0))
    return 0;
  while (b > b0)
    if (*--a != *--b)
      return 0;
  while (a0 < a)
    *p++ = *a0++;
  *p = '\0';
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rpmlget16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rpmlget16(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rpmlget16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <getc@plt>
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rpmlget16(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rpmlget16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rdi
  shl    $0x8,%eax
  mov    %eax,%ebx
  call   <getc@plt>
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rpmlget16(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rpmlget16>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rdi
  shl    $0x8,%eax
  mov    %eax,%ebx
  call   <getc@plt>
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rpmlget16(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getche>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%ecx
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%ecx
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int getche(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getche>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    D9(%rip),%rbx
  mov    %r12,%rsi
  mov    (%rbx),%edi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D23(%rip),%r13
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  mov    %r12,%rdx
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getche(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getche>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D21(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    (%rbx),%edi
  lea    0x4(%rsp),%rdx
  mov    D0(%rip),%rbp
  mov    %eax,0x4(%rsp)
  mov    D18(%rip),%rax
  mov    0x0(%rbp),%esi
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getche(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```