ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SDL_imageFilterMultByByte>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  movzbl %r13b,%r13d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <SDL_imageFilterMMXdetect@plt>
  test   %rax,%rax
  je     L31
  cmp    $0x7,%ebx
  jg     L34
L31:
  xor    %eax,%eax
L46:
  cmp    %ebx,%eax
  jae    L55
  lea    -0x1(%rbx),%edx
  xor    %ecx,%ecx
  sub    %eax,%edx
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%rbp,%rcx,1),%eax
  mov    $0xff,%esi
  imul   %r13d,%eax
  cmp    %esi,%eax
  cmovg  %esi,%eax
  mov    %al,(%r12,%rcx,1)
  mov    %rcx,%rax
  add    $0x1,%rcx
  cmp    %rax,%rdx
  jne    L8
L55:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SDL_imageFilterMultByByteMMX@plt>
  test   $0x7,%bl
  je     L55
  mov    %ebx,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%edx
  add    %rdx,%rbp
  add    %rdx,%r12
  jmp    L46
```

assistant: ```c
int SDL_imageFilterMultByByte(unsigned char *Src1, unsigned char *Dest, int length, unsigned char C) {
  unsigned int i, istart;
  int iC;
  unsigned char *cursrc1;
  unsigned char *curdest;
  int result;
  if ((SDL_imageFilterMMXdetect()) && (length > 7)) {
    SDL_imageFilterMultByByteMMX(Src1, Dest, length, C);
    if ((length & 7) > 0) {
      istart = length & 0xfffffff8;
      cursrc1 = &Src1[istart];
      curdest = &Dest[istart];
    } else {
      return (0);
    }
  } else {
    istart = 0;
    cursrc1 = Src1;
    curdest = Dest;
  }
  iC = (int)C;
  for (i = istart; i < length; i++) {
    result = (int)*cursrc1 * iC;
    if (result > 255)
      result = 255;
    *curdest = (unsigned char)result;
    cursrc1++;
    curdest++;
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jedico>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1869f,-0x4(%rbp)
  jg     L36
  lea    D22(%rip),%rax
  jmp    L40
L36:
  cmpl   $0x1869f,-0x4(%rbp)
  jle    L18
  cmpl   $0xf423f,-0x4(%rbp)
  jg     L18
  lea    D26(%rip),%rax
  jmp    L40
L18:
  lea    D4(%rip),%rax
L40:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
type_infered: string
name: read_data
arguments: data_tag: D26
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string

tool: D22: Padawan

tool: D26: Cavaleiro Jedi

tool: D4: Mestre Jedi

assistant: ```c
char *jedico(n) {
  if (n < 100000) {
    return ("Padawan");
  } else if (n >= 100000 && n < 1000000) {
    return ("Cavaleiro Jedi");
  } else {
    return ("Mestre Jedi");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jedico>:
  endbr64
  lea    D24(%rip),%rax
  cmp    $0x1869f,%edi
  jle    L4
  sub    $0x186a0,%edi
  cmp    $0xdbba0,%edi
  lea    D8(%rip),%rax
  lea    D22(%rip),%rdx
  cmovae %rdx,%rax
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string

tool: D24: Padawan

tool: D8: Cavaleiro Jedi

tool: D22: Mestre Jedi

assistant: ```c
char *jedico(n) {
  if (n < 100000) {
    return ("Padawan");
  } else if (n >= 100000 && n < 1000000) {
    return ("Cavaleiro Jedi");
  } else {
    return ("Mestre Jedi");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<jedico>:
  endbr64
  lea    D26(%rip),%rax
  cmp    $0x1869f,%edi
  jle    L7
  sub    $0x186a0,%edi
  lea    D0(%rip),%rax
  lea    D5(%rip),%rdx
  cmp    $0xdbba0,%edi
  cmovae %rdx,%rax
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D26
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string

tool: D26: Padawan

tool: D0: Cavaleiro Jedi

tool: D5: Mestre Jedi

assistant: ```c
char *jedico(n) {
  if (n < 100000) {
    return ("Padawan");
  } else if (n >= 100000 && n < 1000000) {
    return ("Cavaleiro Jedi");
  } else {
    return ("Mestre Jedi");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<jedico>:
  endbr64
  lea    D17(%rip),%rax
  cmp    $0x1869f,%edi
  jle    L5
  sub    $0x186a0,%edi
  lea    D10(%rip),%rax
  lea    D21(%rip),%rdx
  cmp    $0xdbba0,%edi
  cmovae %rdx,%rax
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D10
type: string
name: retrieve_data
arguments: label: D21
type: string

tool: D17: Padawan

tool: D10: Cavaleiro Jedi

tool: D21: Mestre Jedi

assistant: ```c
char *jedico(n) {
  if (n < 100000) {
    return ("Padawan");
  } else if (n >= 100000 && n < 1000000) {
    return ("Cavaleiro Jedi");
  } else {
    return ("Mestre Jedi");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<return_chars_until_chr_cd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L19:
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L36
  mov    -0xc(%rbp),%eax
  jmp    L4
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0xc(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int return_chars_until_chr_cd(const unsigned char *src, const unsigned char breakpoint) {
  const unsigned char *rpos = src;
  int charslen = 0;
  while (*rpos != '\0') {
    charslen++;
    if (*(rpos++) == breakpoint)
      return (charslen);
  }
  return (charslen);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<return_chars_until_chr_cd>:
  endbr64
  mov    $0x0,%edx
L14:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  add    $0x1,%edx
  add    $0x1,%rdi
  cmp    %sil,%al
  jne    L14
L0:
  mov    %edx,%eax
  ret
```

assistant: ```c
int return_chars_until_chr_cd(const unsigned char *src, const unsigned char breakpoint) {
  const unsigned char *rpos = src;
  int charslen = 0;
  while (*rpos != '\0') {
    charslen++;
    if (*(rpos++) == breakpoint)
      return (charslen);
  }
  return (charslen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<return_chars_until_chr_cd>:
  endbr64
  xor    %r8d,%r8d
  jmp    L12
  nopl   0x0(%rax)
L6:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmp    %sil,%al
  je     L26
L12:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L26:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int return_chars_until_chr_cd(const unsigned char *src, const unsigned char breakpoint) {
  const unsigned char *rpos = src;
  int charslen = 0;
  while (*rpos != '\0') {
    charslen++;
    if (*(rpos++) == breakpoint)
      return (charslen);
  }
  return (charslen);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<return_chars_until_chr_cd>:
  endbr64
  xor    %r8d,%r8d
  jmp    L14
  nopl   0x0(%rax)
L29:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmp    %sil,%al
  je     L23
L14:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L29
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int return_chars_until_chr_cd(const unsigned char *src, const unsigned char breakpoint) {
  const unsigned char *rpos = src;
  int charslen = 0;
  while (*rpos != '\0') {
    charslen++;
    if (*(rpos++) == breakpoint)
      return (charslen);
  }
  return (charslen);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_fabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L17
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L17:
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_fabs(int n) {
  int f;
  if (n >= 0)
    f = n;
  else
    f = -n;
  return f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_fabs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int my_fabs(int n) {
  int f;
  if (n >= 0)
    f = n;
  else
    f = -n;
  return f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_fabs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int my_fabs(int n) {
  int f;
  if (n >= 0)
    f = n;
  else
    f = -n;
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_fabs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int my_fabs(int n) {
  int f;
  if (n >= 0)
    f = n;
  else
    f = -n;
  return f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<weechat_backtrace_addr2line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void weechat_backtrace_addr2line(int number, void *address, const char *symbol) {
  (void)number;
  (void)address;
  (void)symbol;
}
```
user: What is the c source code of the assembly code below?

```asm
<weechat_backtrace_addr2line>:
  endbr64
  ret
```

assistant: ```c
void weechat_backtrace_addr2line(int number, void *address, const char *symbol) {
  (void)number;
  (void)address;
  (void)symbol;
}
```
user: Translate the below assembly code into C programming language:

```asm
<weechat_backtrace_addr2line>:
  endbr64
  ret
```

assistant: ```c
void weechat_backtrace_addr2line(int number, void *address, const char *symbol) {
  (void)number;
  (void)address;
  (void)symbol;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<weechat_backtrace_addr2line>:
  endbr64
  ret
```

assistant: ```c
void weechat_backtrace_addr2line(int number, void *address, const char *symbol) {
  (void)number;
  (void)address;
  (void)symbol;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<faultISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  jmp    L3
```

assistant: ```c
void faultISR(void) {
  while (1) {
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<faultISR>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
void faultISR(void) {
  while (1) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<faultISR>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
void faultISR(void) {
  while (1) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<faultISR>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void faultISR(void) {
  while (1) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L14:
  cmpl   $0x3,-0x4(%rbp)
  je     L12
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x4,-0x4(%rbp)
  jle    L14
  jmp    L0
L12:
  nop
L0:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: %d 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    if (i == 3)
      break;
    printf("%d ", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x3,%ebx
  je     L7
  cmp    $0x4,%ebx
  jle    L13
L7:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: %d 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    if (i == 3)
      break;
    printf("%d ", i);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: %d 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    if (i == 3)
      break;
    printf("%d ", i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: %d 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    if (i == 3)
      break;
    printf("%d ", i);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<baz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jne    L6
  cmpl   $0x2,-0x8(%rbp)
  je     L11
L6:
  mov    $0x0,%eax
  call   <abort@plt>
L11:
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no, noclone)) baz(int f, int j) {
  if (f != 4 || j != 2)
    abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<baz>:
  endbr64
  cmp    $0x4,%edi
  jne    L12
  cmp    $0x2,%esi
  jne    L12
  ret
L12:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no, noclone)) baz(int f, int j) {
  if (f != 4 || j != 2)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<baz>:
  endbr64
  cmp    $0x4,%edi
  jne    L18
  cmp    $0x2,%esi
  jne    L18
  ret
  nop
L18:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no, noclone)) baz(int f, int j) {
  if (f != 4 || j != 2)
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<baz>:
  endbr64
  cmp    $0x4,%edi
  jne    L8
  cmp    $0x2,%esi
  jne    L8
  ret
  nop
L8:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no, noclone)) baz(int f, int j) {
  if (f != 4 || j != 2)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_lseek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
off_t _lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = ESPIPE;
  return ((off_t)-1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_lseek>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
off_t _lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = ESPIPE;
  return ((off_t)-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_lseek>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
off_t _lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = ESPIPE;
  return ((off_t)-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<_lseek>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
off_t _lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = ESPIPE;
  return ((off_t)-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x55ebcb63,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rcx
  neg    %rcx
  cmovns %rcx,%rax
  mov    %rax,(%rdx)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: empty

assistant: ```c
int main() {
  long *a = (long *)"empty";
  int_least32_t i = 1441516387;
  a[i] = labs(a[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    D7(%rip),%rax
  movabs $0x2af5e5b18,%rdx
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    %rcx,%rdx
  neg    %rdx
  cmovs  %rcx,%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string

tool: D7: empty

assistant: ```c
int main() {
  long *a = (long *)"empty";
  int_least32_t i = 1441516387;
  a[i] = labs(a[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  movabs $0x2af5e5b18,%rdx
  lea    D5(%rip),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    %rcx,%rdx
  neg    %rdx
  cmovs  %rcx,%rdx
  mov    %rdx,(%rax)
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: empty

assistant: ```c
int main() {
  long *a = (long *)"empty";
  int_least32_t i = 1441516387;
  a[i] = labs(a[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  movabs $0x2af5e5b18,%rdx
  lea    D6(%rip),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    %rcx,%rdx
  neg    %rdx
  cmovs  %rcx,%rdx
  mov    %rdx,(%rax)
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: empty

assistant: ```c
int main() {
  long *a = (long *)"empty";
  int_least32_t i = 1441516387;
  a[i] = labs(a[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0x2,%edi
  call   <test@plt>
  mov    $0x0,%edi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test(5);
  test(2);
  test(0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0x2,%edi
  call   <test@plt>
  mov    $0x0,%edi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(5);
  test(2);
  test(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0x2,%edi
  call   <test@plt>
  xor    %edi,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(5);
  test(2);
  test(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0x2,%edi
  call   <test@plt>
  xor    %edi,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(5);
  test(2);
  test(0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *mem = strdup(s);
  if (mem == NULL) {
    perror("strdup");
    exit(1);
  }
  return mem;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L1:
  mov    %rbx,%rax
  pop    %rbx
  ret
L0:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *mem = strdup(s);
  if (mem == NULL) {
    perror("strdup");
    exit(1);
  }
  return mem;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L0:
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D9: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *mem = strdup(s);
  if (mem == NULL) {
    perror("strdup");
    exit(1);
  }
  return mem;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
L7:
  mov    %r12,%rax
  pop    %r12
  ret
L19:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *mem = strdup(s);
  if (mem == NULL) {
    perror("strdup");
    exit(1);
  }
  return mem;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <func_haha@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x10,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D12: main

tool: D17: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ZhangIIIr/one/refs/heads/master/Practice/CLanguage/print_func_name.c

tool: D13: %d


assistant: ```c
int main(void) {
  func_haha();
  printf("%s\n", __func__);
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ZhangIIIr/one/refs/heads/master/Practice/CLanguage/print_func_name.c");
  printf("%d\n", 16);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <func_haha@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x10,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D3: main

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ZhangIIIr/one/refs/heads/master/Practice/CLanguage/print_func_name.c

tool: D13: %d


assistant: ```c
int main(void) {
  func_haha();
  printf("%s\n", __func__);
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ZhangIIIr/one/refs/heads/master/Practice/CLanguage/print_func_name.c");
  printf("%d\n", 16);
  return 0;
}
```