ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L10
  mov    %edx,%edx
  mov    $0x0,%eax
L5:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L7
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
  mov    $0x1,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int compare(int array1[], int array2[], int col) {
  int result = 1;
  int c;
  for (c = 0; c < col; c++) {
    if (array1[c] != array2[c]) {
      result = 0;
      return result;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L29
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L5
  nop
L36:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L29
L5:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L36
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int compare(int array1[], int array2[], int col) {
  int result = 1;
  int c;
  for (c = 0; c < col; c++) {
    if (array1[c] != array2[c]) {
      result = 0;
      return result;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L28
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L0
  nop
L11:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L28
L0:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L11
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int compare(int array1[], int array2[], int col) {
  int result = 1;
  int c;
  for (c = 0; c < col; c++) {
    if (array1[c] != array2[c]) {
      result = 0;
      return result;
    }
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MT_READ_ONLY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0xffffffcd,%edx
  mul    %dl
  shr    $0x8,%ax
  shr    $0x3,%al
  add    $0x30,%eax
  mov    %al,D11(%rip)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0xffffffcd,%edx
  mov    %edx,%eax
  mul    %cl
  shr    $0x8,%ax
  mov    %eax,%edx
  shr    $0x3,%dl
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %al,D8(%rip)
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <message@plt>
  nop
  leave
  ret
```

assistant: ```c
void MT_READ_ONLY(unsigned int rt) {
  static char write_to_read_only[] = "Invalid MTC0 from SR[00].";
  write_to_read_only[21] = '0' + (unsigned char)rt / 10;
  write_to_read_only[22] = '0' + (unsigned char)rt % 10;
  message(write_to_read_only);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MT_READ_ONLY>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffcd,%edx
  mov    %edx,%eax
  mul    %dil
  shr    $0xb,%ax
  lea    0x30(%rax),%edx
  mov    %dl,D17(%rip)
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,D2(%rip)
  lea    D6(%rip),%rdi
  call   <message@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MT_READ_ONLY(unsigned int rt) {
  static char write_to_read_only[] = "Invalid MTC0 from SR[00].";
  write_to_read_only[21] = '0' + (unsigned char)rt / 10;
  write_to_read_only[22] = '0' + (unsigned char)rt % 10;
  message(write_to_read_only);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<MT_READ_ONLY>:
  endbr64
  mov    $0xffffffcd,%eax
  mul    %dil
  shr    $0xb,%ax
  lea    0x30(%rax),%edx
  lea    (%rax,%rax,4),%eax
  mov    %dl,D13(%rip)
  lea    (%rax,%rax,1),%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,D1(%rip)
  lea    D17(%rip),%rdi
  jmp    1050 <message@plt>
```

assistant: ```c
void MT_READ_ONLY(unsigned int rt) {
  static char write_to_read_only[] = "Invalid MTC0 from SR[00].";
  write_to_read_only[21] = '0' + (unsigned char)rt / 10;
  write_to_read_only[22] = '0' + (unsigned char)rt % 10;
  message(write_to_read_only);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MT_READ_ONLY>:
  endbr64
  mov    $0xffffffcd,%eax
  mul    %dil
  shr    $0xb,%ax
  lea    0x30(%rax),%edx
  lea    (%rax,%rax,4),%eax
  mov    %dl,D17(%rip)
  lea    (%rax,%rax,1),%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,D3(%rip)
  lea    D27(%rip),%rdi
  jmp    1050 <message@plt>
```

assistant: ```c
void MT_READ_ONLY(unsigned int rt) {
  static char write_to_read_only[] = "Invalid MTC0 from SR[00].";
  write_to_read_only[21] = '0' + (unsigned char)rt / 10;
  write_to_read_only[22] = '0' + (unsigned char)rt % 10;
  message(write_to_read_only);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CopyFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L11
  mov    -0x30(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L16
L6:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x11(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L16
  movsbl -0x11(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
L16:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L11:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D14: rb

tool: D1: wb

assistant: ```c
void CopyFile(char sInputFile[], char sOutputFile[]) {
  FILE *fpInputFile, *fpOutputFile;
  char ch;
  if ((fpInputFile = fopen(sInputFile, "rb")) != NULL) {
    fpOutputFile = fopen(sOutputFile, "wb");
    while (!feof(fpInputFile)) {
      ch = fgetc(fpInputFile);
      if (!feof(fpInputFile))
        fputc(ch, fpOutputFile);
    }
    fclose(fpInputFile);
    fclose(fpOutputFile);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CopyFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  lea    D17(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L28
  mov    %rax,%rbx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
L12:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L3
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L12
  movsbl %bpl,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  jmp    L12
L3:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D17: rb

tool: D11: wb

assistant: ```c
void CopyFile(char sInputFile[], char sOutputFile[]) {
  FILE *fpInputFile, *fpOutputFile;
  char ch;
  if ((fpInputFile = fopen(sInputFile, "rb")) != NULL) {
    fpOutputFile = fopen(sOutputFile, "wb");
    while (!feof(fpInputFile)) {
      ch = fgetc(fpInputFile);
      if (!feof(fpInputFile))
        fputc(ch, fpOutputFile);
    }
    fclose(fpInputFile);
    fclose(fpOutputFile);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<CopyFile>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D16(%rip),%rsi
  push   %rbp
  push   %rbx
  call   <fopen@plt>
  test   %rax,%rax
  je     L21
  mov    %r12,%rdi
  lea    D17(%rip),%rsi
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L19:
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <feof@plt>
  test   %eax,%eax
  je     L31
L14:
  mov    %rbp,%rdi
  call   <feof@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  je     L19
  call   <fclose@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <fclose@plt>
  nopl   0x0(%rax,%rax,1)
L31:
  movsbl %bl,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  jmp    L14
  nopl   (%rax)
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D17
data_type: string

tool: D16: rb

tool: D17: wb

assistant: ```c
void CopyFile(char sInputFile[], char sOutputFile[]) {
  FILE *fpInputFile, *fpOutputFile;
  char ch;
  if ((fpInputFile = fopen(sInputFile, "rb")) != NULL) {
    fpOutputFile = fopen(sOutputFile, "wb");
    while (!feof(fpInputFile)) {
      ch = fgetc(fpInputFile);
      if (!feof(fpInputFile))
        fputc(ch, fpOutputFile);
    }
    fclose(fpInputFile);
    fclose(fpOutputFile);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CopyFile>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D11(%rip),%rsi
  push   %rbp
  push   %rbx
  call   <fopen@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rdi
  lea    D4(%rip),%rsi
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L38:
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <feof@plt>
  test   %eax,%eax
  je     L8
L28:
  mov    %rbp,%rdi
  call   <feof@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  je     L38
  call   <fclose@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <fclose@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  movsbl %bl,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  jmp    L28
  nopl   (%rax)
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D11: rb

tool: D4: wb

assistant: ```c
void CopyFile(char sInputFile[], char sOutputFile[]) {
  FILE *fpInputFile, *fpOutputFile;
  char ch;
  if ((fpInputFile = fopen(sInputFile, "rb")) != NULL) {
    fpOutputFile = fopen(sOutputFile, "wb");
    while (!feof(fpInputFile)) {
      ch = fgetc(fpInputFile);
      if (!feof(fpInputFile))
        fputc(ch, fpOutputFile);
    }
    fclose(fpInputFile);
    fclose(fpOutputFile);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  x = -1;
  return x > 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = -1;
  return x > 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = -1;
  return x > 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = -1;
  return x > 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trouver_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L27
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L20
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L20:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int trouver_max(int *tab, int nb_element) {
  int max;
  int index;
  max = tab[0];
  index = 1;
  while (index < nb_element) {
    if (max >= tab[index])
      max = tab[index];
    index++;
  }
  return (max);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<trouver_max>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%esi
  jle    L15
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rsi
L10:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L10
L15:
  mov    %edx,%eax
  ret
```

assistant: ```c
int trouver_max(int *tab, int nb_element) {
  int max;
  int index;
  max = tab[0];
  index = 1;
  while (index < nb_element) {
    if (max >= tab[index])
      max = tab[index];
    index++;
  }
  return (max);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trouver_max>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  jle    L13
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovg  %edx,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L10
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int trouver_max(int *tab, int nb_element) {
  int max;
  int index;
  max = tab[0];
  index = 1;
  while (index < nb_element) {
    if (max >= tab[index])
      max = tab[index];
    index++;
  }
  return (max);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trouver_max>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L22
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%esi
  cmp    $0x2,%esi
  jbe    L50
  mov    %edi,%esi
  movd   %eax,%xmm4
  lea    0x4(%rdx),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm4,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L26:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L26
  movdqa %xmm0,%xmm2
  mov    %edi,%r8d
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%r8d
  movdqa %xmm2,%xmm1
  lea    0x1(%r8),%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %r8d,%edi
  je     L15
L27:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  mov    (%rdx,%rdi,4),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%ecx
  jle    L22
  mov    0x4(%rdx,%r8,1),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L22
  mov    0x8(%rdx,%r8,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L22:
  ret
  nopl   (%rax)
L15:
  ret
L50:
  mov    $0x1,%esi
  jmp    L27
```

assistant: ```c
int trouver_max(int *tab, int nb_element) {
  int max;
  int index;
  max = tab[0];
  index = 1;
  while (index < nb_element) {
    if (max >= tab[index])
      max = tab[index];
    index++;
  }
  return (max);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<col_convert3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L14:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0x14(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L23
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <col_convert_block@plt>
  addl   $0x8,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0x4(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
  addl   $0x8,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0x8(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void col_convert3(int dim, int *G) {
  int i, j, di, dj;
  for (i = 0, di = 0; i < dim; i += 8, di += 8 * dim)
    for (j = i, dj = i * 8 * dim; j < dim; j += 8, dj += 8 * dim)
      col_convert_block(dim, G + dj + i, G + di + j);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<col_convert3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rsi,0x28(%rsp)
  test   %edi,%edi
  jle    L4
  mov    %edi,%r12d
  mov    %edi,%eax
  shl    $0x6,%eax
  cltq
  lea    0x20(,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  lea    0x0(,%rdi,8),%edx
  movslq %edx,%rdx
  lea    0x8(%rdx),%rax
  mov    %rax,0x18(%rsp)
  lea    -0x1(%rdi),%eax
  mov    %eax,0x34(%rsp)
  shr    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x3,%rax
  mov    %rax,0x20(%rsp)
  lea    0x0(,%rdx,4),%rax
  mov    %rax,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    0x20(%rsi),%rax
  mov    %rax,0x38(%rsp)
L36:
  cmp    %r14d,%r12d
  jle    L20
  mov    0x28(%rsp),%rax
  lea    (%rax,%r15,4),%rbx
  mov    0x34(%rsp),%eax
  sub    %r14d,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  lea    (%r15,%rax,8),%rax
  mov    0x38(%rsp),%rcx
  lea    (%rcx,%rax,4),%r13
  mov    0x8(%rsp),%rbp
L6:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <col_convert_block@plt>
  add    (%rsp),%rbp
  add    $0x20,%rbx
  cmp    %r13,%rbx
  jne    L6
L20:
  mov    0x10(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  add    $0x8,%r14
  add    0x18(%rsp),%r15
  cmp    0x20(%rsp),%r14
  jne    L36
L4:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void col_convert3(int dim, int *G) {
  int i, j, di, dj;
  for (i = 0, di = 0; i < dim; i += 8, di += 8 * dim)
    for (j = i, dj = i * 8 * dim; j < dim; j += 8, dj += 8 * dim)
      col_convert_block(dim, G + dj + i, G + di + j);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<col_convert3>:
  endbr64
  test   %edi,%edi
  jle    L25
  push   %r15
  mov    %edi,%eax
  push   %r14
  shl    $0x6,%eax
  mov    %edi,%r14d
  push   %r13
  cltq
  push   %r12
  lea    0x20(,%rax,4),%rax
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    0x0(,%rdi,8),%ebx
  movslq %ebx,%rbx
  sub    $0x38,%rsp
  mov    %rax,0x18(%rsp)
  lea    0x20(,%rbx,4),%rax
  shl    $0x2,%rbx
  mov    %rax,0x20(%rsp)
  lea    -0x1(%rdi),%eax
  shr    $0x3,%eax
  mov    %rsi,0x8(%rsp)
  add    $0x1,%eax
  mov    %rsi,0x10(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x28(%rsp)
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x10(%rsp),%r13
  mov    0x8(%rsp),%r15
  mov    %ebp,%r12d
  nopl   (%rax)
L3:
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  add    $0x8,%r12d
  call   <col_convert_block@plt>
  add    %rbx,%r15
  add    $0x20,%r13
  cmp    %r12d,%r14d
  jg     L3
  mov    0x18(%rsp),%rcx
  add    $0x8,%rbp
  add    %rcx,0x8(%rsp)
  mov    0x20(%rsp),%rcx
  add    %rcx,0x10(%rsp)
  cmp    0x28(%rsp),%rbp
  jne    L21
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  ret
```

assistant: ```c
void col_convert3(int dim, int *G) {
  int i, j, di, dj;
  for (i = 0, di = 0; i < dim; i += 8, di += 8 * dim)
    for (j = i, dj = i * 8 * dim; j < dim; j += 8, dj += 8 * dim)
      col_convert_block(dim, G + dj + i, G + di + j);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<col_convert3>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r15
  mov    %edi,%eax
  push   %r14
  shl    $0x6,%eax
  mov    %edi,%r14d
  push   %r13
  cltq
  push   %r12
  lea    0x20(,%rax,4),%rax
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    0x0(,%rdi,8),%ebx
  movslq %ebx,%rbx
  sub    $0x38,%rsp
  mov    %rax,0x18(%rsp)
  lea    0x20(,%rbx,4),%rax
  shl    $0x2,%rbx
  mov    %rax,0x20(%rsp)
  lea    -0x1(%rdi),%eax
  shr    $0x3,%eax
  mov    %rsi,0x10(%rsp)
  add    $0x1,%eax
  mov    %rsi,0x8(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x28(%rsp)
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rsp),%r13
  mov    0x10(%rsp),%r15
  mov    %ebp,%r12d
  nopl   (%rax)
L16:
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  add    $0x8,%r12d
  call   <col_convert_block@plt>
  add    %rbx,%r15
  add    $0x20,%r13
  cmp    %r12d,%r14d
  jg     L16
  mov    0x18(%rsp),%rcx
  add    $0x8,%rbp
  add    %rcx,0x10(%rsp)
  mov    0x20(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  cmp    0x28(%rsp),%rbp
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  ret
```

assistant: ```c
void col_convert3(int dim, int *G) {
  int i, j, di, dj;
  for (i = 0, di = 0; i < dim; i += 8, di += 8 * dim)
    for (j = i, dj = i * 8 * dim; j < dim; j += 8, dj += 8 * dim)
      col_convert_block(dim, G + dj + i, G + di + j);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<project_v>:
  endbr64
  mov    %edx,%r10d
  lea    (%rsi,%rdi,2),%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rdi,1),%edx
  lea    (%rsi,%rdx,2),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  movsd  (%r8,%rdx,8),%xmm7
  movsd  0x8(%r8,%rdx,8),%xmm6
  lea    (%rcx,%r10,2),%edx
  lea    (%rdx,%rdx,2),%r10d
  add    %r10d,%edi
  lea    (%rsi,%rdi,2),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  movsd  (%r8,%rdx,8),%xmm5
  movsd  0x8(%r8,%rdx,8),%xmm4
  lea    (%r10,%r10,1),%r8d
  mov    %r8d,%edi
  movslq %r8d,%rdx
  shl    $0x4,%rdx
  lea    0x20(%rdx,%r9,1),%rcx
  add    $0x6,%r8d
  movslq %r10d,%rdx
  movslq %eax,%rsi
  sub    %rdx,%rsi
  shl    $0x5,%rsi
  sub    $0x20,%rsi
  jmp    L7
L14:
  add    $0x2,%edi
  add    $0x20,%rcx
  cmp    %r8d,%edi
  je     L31
L7:
  lea    (%rsi,%rcx,1),%rdx
  lea    -0x20(%rcx),%rax
L32:
  movsd  (%rdx),%xmm2
  movsd  0x8(%rdx),%xmm3
  movsd  (%rax),%xmm8
  movsd  0x8(%rax),%xmm0
  movapd %xmm7,%xmm1
  mulsd  %xmm8,%xmm1
  movapd %xmm6,%xmm9
  mulsd  %xmm0,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm5,%xmm9
  mulsd  %xmm2,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm4,%xmm9
  mulsd  %xmm3,%xmm9
  addsd  %xmm9,%xmm1
  movsd  %xmm1,(%rax)
  mulsd  %xmm7,%xmm0
  mulsd  %xmm6,%xmm8
  addsd  %xmm8,%xmm0
  mulsd  %xmm5,%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rax)
  add    $0x10,%rdx
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L32
  jmp    L14
L31:
  ret
```

assistant: ```c
void project_v(int a, int i, int b, int j, double r[], double v[]) {
  int c, k;
  double xi, yi, xj, yj;
  xi = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((i) + 2 * (a))))]))[0];
  yi = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((i) + 2 * (a))))]))[1];
  xj = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((j) + 2 * (b))))]))[0];
  yj = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((j) + 2 * (b))))]))[1];
  for (c = 0; c < 3; c++)
    for (k = 0; k < 2; k++) {
      double zi = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[0];
      double ti = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[1];
      double zj = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[0];
      double tj = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[1];
      (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[0] = xi * zj - yi * tj - xj * zi + yj * ti;
      (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[1] = xi * tj + yi * zj - xj * ti - yj * zi;
    }
}
```