ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<path_append>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x2(%r12,%rax,1),%rdi
  call   <calloc@plt>
  mov    %r13,%rsi
  movb   $0x2f,0x7(%rsp)
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    0x7(%rsp),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *path_append(const char *basedir, const char *append) {
  char *r = calloc(strlen(basedir) + strlen(append) + 1 + 1, sizeof(char));
  char sep[] = {'/'};
  strcat(r, basedir);
  strcat(r, sep);
  strcat(r, append);
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toBinary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x400(%rbp)
  movl   $0x0,-0x3fc(%rbp)
  movl   $0x0,-0x3f8(%rbp)
  cmpl   $0x0,-0x404(%rbp)
  jns    L15
  negl   -0x404(%rbp)
  movl   $0x1,-0x3f8(%rbp)
  jmp    L15
L3:
  mov    -0x404(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x3f4(%rbp)
  mov    -0x404(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x404(%rbp)
  mov    -0x3f4(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x400(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x400(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x3f0(%rbp,%rax,1)
L15:
  cmpl   $0x0,-0x404(%rbp)
  jg     L3
  cmpl   $0x0,-0x3f8(%rbp)
  je     L32
  mov    -0x400(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x400(%rbp)
  cltq
  movb   $0x31,-0x3f0(%rbp,%rax,1)
  jmp    L74
L32:
  mov    -0x400(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x400(%rbp)
  cltq
  movb   $0x30,-0x3f0(%rbp,%rax,1)
  jmp    L74
L51:
  subl   $0x1,-0x400(%rbp)
  mov    -0x3fc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3fc(%rbp)
  mov    -0x400(%rbp),%edx
  movslq %edx,%rdx
  movzbl -0x3f0(%rbp,%rdx,1),%edx
  cltq
  lea    D3(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
L74:
  cmpl   $0x0,-0x400(%rbp)
  jns    L51
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    D3(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D3(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
char *toBinary(int decimal) {
  static char binary[1000];
  int k = 0, n = 0;
  int negative = 0;
  int remain;
  char temp[1000];
  if (decimal < 0) {
    decimal = -decimal;
    negative = 1;
  }
  while (decimal > 0) {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  }
  if (negative)
    temp[k++] = '1';
  else
    temp[k++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
  return binary;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toBinary>:
  endbr64
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L59
  mov    $0x0,%r9d
  mov    $0x0,%edx
  jle    L35
L82:
  mov    %rsp,%rcx
  mov    $0x0,%edx
L46:
  mov    %edi,%esi
  shr    $0x1f,%esi
  lea    (%rdi,%rsi,1),%eax
  and    $0x1,%eax
  sub    %esi,%eax
  mov    %edi,%r8d
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %esi,%edi
  sar    %edi
  mov    %edx,%esi
  add    $0x1,%edx
  add    $0x30,%eax
  mov    %al,(%rcx)
  add    $0x1,%rcx
  cmp    $0x1,%r8d
  jg     L46
  test   %r9d,%r9d
  je     L35
  add    $0x2,%esi
  mov    $0x31,%eax
L54:
  movslq %edx,%rdx
  mov    %al,(%rsp,%rdx,1)
  test   %esi,%esi
  js     L4
  movslq %esi,%rax
  lea    (%rsp,%rax,1),%rdx
  lea    D18(%rip),%rax
  mov    %esi,%ecx
  lea    0x1(%rax),%rdi
  add    %rcx,%rdi
L22:
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L22
  add    $0x1,%esi
L11:
  lea    D18(%rip),%rax
  sub    $0x1,%esi
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x3f8,%rsp
  ret
L59:
  neg    %edi
  mov    $0x1,%r9d
  jmp    L82
L4:
  mov    $0x0,%esi
  jmp    L11
L35:
  lea    0x1(%rdx),%esi
  mov    $0x30,%eax
  jmp    L54
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *toBinary(int decimal) {
  static char binary[1000];
  int k = 0, n = 0;
  int negative = 0;
  int remain;
  char temp[1000];
  if (decimal < 0) {
    decimal = -decimal;
    negative = 1;
  }
  while (decimal > 0) {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  }
  if (negative)
    temp[k++] = '1';
  else
    temp[k++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
  return binary;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<toBinary>:
  endbr64
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L63
  mov    $0x0,%r9d
  je     L55
L15:
  mov    %rsp,%rcx
  xor    %edx,%edx
  mov    %rcx,%rsi
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %edi,%eax
  mov    %edx,%r8d
  add    $0x1,%rsi
  add    $0x1,%edx
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rsi)
  sar    %edi
  jne    L21
  add    $0x2,%r8d
  test   %r9d,%r9d
  je     L79
  mov    $0x31,%eax
L30:
  lea    D0(%rip),%r9
  movslq %edx,%rdx
  movslq %r8d,%r8
  lea    0x1(%r9),%rsi
  mov    %al,(%rsp,%rdx,1)
  lea    (%rcx,%r8,1),%rdx
  mov    %r9,%rax
  add    %r8,%rsi
  nopl   (%rax)
L1:
  movzbl -0x1(%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L1
  movb   $0x0,(%r9,%r8,1)
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    %r9,%rax
  add    $0x3f8,%rsp
  ret
L55:
  xor    %edx,%edx
  mov    $0x1,%r8d
  mov    %rsp,%rcx
  nopw   0x0(%rax,%rax,1)
L79:
  mov    $0x30,%eax
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L63:
  neg    %edi
  mov    $0x1,%r9d
  jmp    L15
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *toBinary(int decimal) {
  static char binary[1000];
  int k = 0, n = 0;
  int negative = 0;
  int remain;
  char temp[1000];
  if (decimal < 0) {
    decimal = -decimal;
    negative = 1;
  }
  while (decimal > 0) {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  }
  if (negative)
    temp[k++] = '1';
  else
    temp[k++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
  return binary;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<toBinary>:
  endbr64
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L6
  mov    $0x0,%r9d
  je     L52
L76:
  mov    %rsp,%rcx
  xor    %edx,%edx
  mov    %rcx,%rsi
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %edi,%eax
  mov    %edx,%r8d
  add    $0x1,%rsi
  add    $0x1,%edx
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rsi)
  sar    %edi
  jne    L74
  add    $0x2,%r8d
  test   %r9d,%r9d
  je     L47
  mov    $0x31,%eax
L1:
  lea    D6(%rip),%r9
  movslq %edx,%rdx
  movslq %r8d,%r8
  lea    0x1(%r9),%rsi
  mov    %al,(%rsp,%rdx,1)
  lea    (%rcx,%r8,1),%rdx
  mov    %r9,%rax
  add    %r8,%rsi
  nopl   (%rax)
L62:
  movzbl -0x1(%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rax,%rsi
  jne    L62
  movb   $0x0,(%r9,%r8,1)
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %r9,%rax
  add    $0x3f8,%rsp
  ret
L52:
  xor    %edx,%edx
  mov    $0x1,%r8d
  mov    %rsp,%rcx
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x30,%eax
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L6:
  neg    %edi
  mov    $0x1,%r9d
  jmp    L76
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *toBinary(int decimal) {
  static char binary[1000];
  int k = 0, n = 0;
  int negative = 0;
  int remain;
  char temp[1000];
  if (decimal < 0) {
    decimal = -decimal;
    negative = 1;
  }
  while (decimal > 0) {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  }
  if (negative)
    temp[k++] = '1';
  else
    temp[k++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
  return binary;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L22
L24:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L24
L4:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_string(char *s) {
  while (*s && *s != '"')
    s++;
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_string>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L24
  cmp    $0x22,%dl
  je     L24
L1:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L24
  cmp    $0x22,%dl
  jne    L1
L24:
  ret
```

assistant: ```c
char *skip_string(char *s) {
  while (*s && *s != '"')
    s++;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skip_string>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L38
  jmp    L1
L11:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L1
L38:
  cmp    $0x22,%dl
  jne    L11
L1:
  ret
```

assistant: ```c
char *skip_string(char *s) {
  while (*s && *s != '"')
    s++;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_string>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L27
  jmp    L15
L23:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L15
L27:
  cmp    $0x22,%dl
  jne    L23
L15:
  ret
```

assistant: ```c
char *skip_string(char *s) {
  while (*s && *s != '"')
    s++;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipsp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L7
L24:
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L24
L15:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skipsp(char *str) {
  while (*(str) && isspace((unsigned char)*(str)))
    (str)++;
  ;
  return (str);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skipsp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    %rbx,%rax
  test   %dil,%dil
  je     L22
L36:
  movzbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L9
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L36
  mov    %rbx,%rax
  jmp    L22
L9:
  mov    %rbx,%rax
L22:
  pop    %rbx
  ret
```

assistant: ```c
char *skipsp(char *str) {
  while (*(str) && isspace((unsigned char)*(str)))
    (str)++;
  ;
  return (str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skipsp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L6
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L20
L6:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
L20:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipsp(char *str) {
  while (*(str) && isspace((unsigned char)*(str)))
    (str)++;
  ;
  return (str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skipsp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L19
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L30:
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L0
L19:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L30
L0:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipsp(char *str) {
  while (*(str) && isspace((unsigned char)*(str)))
    (str)++;
  ;
  return (str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<time_usec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned long long time_usec() {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return (unsigned long long)tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<time_usec>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x18(%rsp),%rax
  add    0x10(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long time_usec() {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return (unsigned long long)tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: What is the c source code of the assembly code below:

```asm
<time_usec>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x18(%rsp),%rax
  add    0x10(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long time_usec() {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return (unsigned long long)tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<time_usec>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x18(%rsp),%rax
  add    0x10(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long time_usec() {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return (unsigned long long)tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bench>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <benchmark@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <benchmark@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: benchmark(size=%d bytes, times=%d):


assistant: ```c
void bench(int copysize, int times) {
  printf("benchmark(size=%d bytes, times=%d):\n", copysize, times);
  benchmark(1, 1, copysize, times);
  benchmark(1, 0, copysize, times);
  benchmark(0, 1, copysize, times);
  benchmark(0, 0, copysize, times);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bench>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <benchmark@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <benchmark@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: benchmark(size=%d bytes, times=%d):


assistant: ```c
void bench(int copysize, int times) {
  printf("benchmark(size=%d bytes, times=%d):\n", copysize, times);
  benchmark(1, 1, copysize, times);
  benchmark(1, 0, copysize, times);
  benchmark(0, 1, copysize, times);
  benchmark(0, 0, copysize, times);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bench>:
  endbr64
  push   %r13
  mov    %esi,%edx
  mov    %esi,%r13d
  xor    %eax,%eax
  push   %r12
  mov    %edi,%esi
  mov    %edi,%r12d
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <benchmark@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %edi,%edi
  xor    %esi,%esi
  call   <benchmark@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %r12
  pop    %r13
  jmp    1070 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: benchmark(size=%d bytes, times=%d):


assistant: ```c
void bench(int copysize, int times) {
  printf("benchmark(size=%d bytes, times=%d):\n", copysize, times);
  benchmark(1, 1, copysize, times);
  benchmark(1, 0, copysize, times);
  benchmark(0, 1, copysize, times);
  benchmark(0, 0, copysize, times);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bench>:
  endbr64
  push   %r13
  mov    %esi,%edx
  mov    %esi,%r13d
  xor    %eax,%eax
  push   %r12
  mov    %edi,%esi
  mov    %edi,%r12d
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <benchmark@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <benchmark@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %edi,%edi
  xor    %esi,%esi
  call   <benchmark@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %r12
  pop    %r13
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: benchmark(size=%d bytes, times=%d):


assistant: ```c
void bench(int copysize, int times) {
  printf("benchmark(size=%d bytes, times=%d):\n", copysize, times);
  benchmark(1, 1, copysize, times);
  benchmark(1, 0, copysize, times);
  benchmark(0, 1, copysize, times);
  benchmark(0, 0, copysize, times);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L4:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  leave
  ret
```

assistant: ```c
char *trim(char *phrase) {
  char *old = phrase;
  char *new = phrase;
  while (*old == ' ') {
    *(new ++) = *(old++);
  }
  *new = 0;
  return (char *)realloc(phrase, strlen(phrase) + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x20,(%rdi)
  jne    L25
  mov    %rdi,%rax
L15:
  add    $0x1,%rax
  movb   $0x20,-0x1(%rax)
  cmpb   $0x20,(%rax)
  je     L15
L16:
  movb   $0x0,(%rax)
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    %rbx,%rdi
  call   <realloc@plt>
  pop    %rbx
  ret
L25:
  mov    %rdi,%rax
  jmp    L16
```

assistant: ```c
char *trim(char *phrase) {
  char *old = phrase;
  char *new = phrase;
  while (*old == ' ') {
    *(new ++) = *(old++);
  }
  *new = 0;
  return (char *)realloc(phrase, strlen(phrase) + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trim>:
  endbr64
  push   %rbp
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbp
  mov    %rdi,%rax
  jne    L10
L13:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L13
L10:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  lea    0x1(%rax),%rsi
  jmp    1070 <realloc@plt>
```

assistant: ```c
char *trim(char *phrase) {
  char *old = phrase;
  char *new = phrase;
  while (*old == ' ') {
    *(new ++) = *(old++);
  }
  *new = 0;
  return (char *)realloc(phrase, strlen(phrase) + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  push   %rbp
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbp
  mov    %rdi,%rax
  jne    L17
L16:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L16
L17:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  lea    0x1(%rax),%rsi
  jmp    1070 <realloc@plt>
```

assistant: ```c
char *trim(char *phrase) {
  char *old = phrase;
  char *new = phrase;
  while (*old == ' ') {
    *(new ++) = *(old++);
  }
  *new = 0;
  return (char *)realloc(phrase, strlen(phrase) + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swe_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: 2.09.03

assistant: ```c
char *swe_version(char *s) {
  strcpy(s, "2.09.03");
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swe_version>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rsi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: string

tool: D9: 2.09.03

assistant: ```c
char *swe_version(char *s) {
  strcpy(s, "2.09.03");
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swe_version>:
  endbr64
  push   %r12
  lea    D7(%rip),%rsi
  mov    %rdi,%r12
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: 2.09.03

assistant: ```c
char *swe_version(char *s) {
  strcpy(s, "2.09.03");
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swe_version>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  mov    %rdi,%r12
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: 2.09.03

assistant: ```c
char *swe_version(char *s) {
  strcpy(s, "2.09.03");
  return s;
}
```