ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tot64_relsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L26
L4:
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <has64_rel_mcount@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_mcounted_section_name@plt>
  test   %rax,%rax
  je     L23
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <w8@plt>
  add    %eax,-0x14(%rbp)
L23:
  subl   $0x1,-0x2c(%rbp)
  addq   $0x4,-0x10(%rbp)
L26:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L4
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned tot64_relsize(Elf64_Shdr const *const shdr0, unsigned nhdr, const char *const shstrtab, const char *const fname) {
  unsigned totrelsz = 0;
  Elf64_Shdr const *shdrp = shdr0;
  char const *txtname;
  for (; nhdr; --nhdr, ++shdrp) {
    txtname = has64_rel_mcount(shdrp, shdr0, shstrtab, fname);
    if (txtname && is_mcounted_section_name(txtname)) {
      totrelsz += w8(shdrp->sh_size);
    }
  }
  return totrelsz;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tot64_relsize>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L52
  mov    %rdi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%r15
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  jmp    L20
L38:
  add    $0x4,%rbx
  cmp    %r15,%rbx
  je     L34
L20:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <has64_rel_mcount@plt>
  test   %rax,%rax
  je     L38
  mov    %rax,%rdi
  call   <is_mcounted_section_name@plt>
  test   %rax,%rax
  je     L38
  mov    (%rbx),%edi
  call   <w8@plt>
  add    %eax,%r12d
  jmp    L38
L52:
  mov    %esi,%r12d
L34:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned tot64_relsize(Elf64_Shdr const *const shdr0, unsigned nhdr, const char *const shstrtab, const char *const fname) {
  unsigned totrelsz = 0;
  Elf64_Shdr const *shdrp = shdr0;
  char const *txtname;
  for (; nhdr; --nhdr, ++shdrp) {
    txtname = has64_rel_mcount(shdrp, shdr0, shstrtab, fname);
    if (txtname && is_mcounted_section_name(txtname)) {
      totrelsz += w8(shdrp->sh_size);
    }
  }
  return totrelsz;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tot64_relsize>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L27
  mov    %esi,%esi
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  lea    (%rdi,%rsi,4),%r13
  mov    %rdi,%r15
  xor    %r14d,%r14d
  jmp    L17
  nopl   (%rax)
L25:
  add    $0x4,%r15
  cmp    %r15,%r13
  je     L5
L17:
  mov    %r15,%rdi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <has64_rel_mcount@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L25
  call   <is_mcounted_section_name@plt>
  test   %rax,%rax
  je     L25
  mov    (%r15),%edi
  add    $0x4,%r15
  call   <w8@plt>
  add    %eax,%r14d
  cmp    %r15,%r13
  jne    L17
L5:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %r14d,%r14d
  jmp    L5
```

assistant: ```c
unsigned tot64_relsize(Elf64_Shdr const *const shdr0, unsigned nhdr, const char *const shstrtab, const char *const fname) {
  unsigned totrelsz = 0;
  Elf64_Shdr const *shdrp = shdr0;
  char const *txtname;
  for (; nhdr; --nhdr, ++shdrp) {
    txtname = has64_rel_mcount(shdrp, shdr0, shstrtab, fname);
    if (txtname && is_mcounted_section_name(txtname)) {
      totrelsz += w8(shdrp->sh_size);
    }
  }
  return totrelsz;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tot64_relsize>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L11
  mov    %esi,%esi
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  lea    (%rdi,%rsi,4),%r13
  mov    %rdi,%r15
  xor    %r14d,%r14d
  jmp    L6
  nopl   (%rax)
L7:
  add    $0x4,%r15
  cmp    %r15,%r13
  je     L8
L6:
  mov    %r15,%rdi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <has64_rel_mcount@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L7
  call   <is_mcounted_section_name@plt>
  test   %rax,%rax
  je     L7
  mov    (%r15),%edi
  add    $0x4,%r15
  call   <w8@plt>
  add    %eax,%r14d
  cmp    %r15,%r13
  jne    L6
L8:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r14d,%r14d
  jmp    L8
```

assistant: ```c
unsigned tot64_relsize(Elf64_Shdr const *const shdr0, unsigned nhdr, const char *const shstrtab, const char *const fname) {
  unsigned totrelsz = 0;
  Elf64_Shdr const *shdrp = shdr0;
  char const *txtname;
  for (; nhdr; --nhdr, ++shdrp) {
    txtname = has64_rel_mcount(shdrp, shdr0, shstrtab, fname);
    if (txtname && is_mcounted_section_name(txtname)) {
      totrelsz += w8(shdrp->sh_size);
    }
  }
  return totrelsz;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0xa,%eax
  ja     L6
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L54
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L54
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L54
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L54
L6:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L54:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D50
type_guessed: string
name: unpack_data
arguments: data_label: D75
type_guessed: string
name: unpack_data
arguments: data_label: D20
type_guessed: string
name: unpack_data
arguments: data_label: D36
type_guessed: string
name: unpack_data
arguments: data_label: D73
type_guessed: string
name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string

tool: D50: %d

tool: D75: youxiu


tool: D20: lianghao


tool: D36: zhongdneg


tool: D73: jige


tool: D15: bujige


tool: D13: error


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  switch (num / 10) {
  case 10:
  case 9:
    printf("youxiu\n");
    break;
  case 8:
    printf("lianghao\n");
    break;
  case 7:
    printf("zhongdneg\n");
    break;
  case 6:
    printf("jige\n");
  case 5:
  case 4:
  case 3:
  case 2:
  case 1:
  case 0:
    printf("bujige\n");
    break;
  default:
    printf("error\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  cmp    $0xa,%eax
  ja     L34
  mov    %eax,%eax
  lea    D54(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L9
  lea    D40(%rip),%rdi
  call   <printf@plt>
  jmp    L9
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L9
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L34:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D62
type_infered: string
name: parse_data
arguments: data_tag: D40
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D44
type_infered: string
name: parse_data
arguments: data_tag: D56
type_infered: string
name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D27: %d

tool: D62: youxiu


tool: D40: lianghao


tool: D17: zhongdneg


tool: D44: jige


tool: D56: bujige


tool: D0: error


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  switch (num / 10) {
  case 10:
  case 9:
    printf("youxiu\n");
    break;
  case 8:
    printf("lianghao\n");
    break;
  case 7:
    printf("zhongdneg\n");
    break;
  case 6:
    printf("jige\n");
  case 5:
  case 4:
  case 3:
  case 2:
  case 1:
  case 0:
    printf("bujige\n");
    break;
  default:
    printf("error\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D49(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  cmp    $0xa,%eax
  ja     L7
  lea    D26(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D72(%rip),%rdi
  call   <printf@plt>
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L7:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D49
data_type: string
name: extract_symbolic_data
arguments: data_tag: D68
data_type: string
name: extract_symbolic_data
arguments: data_tag: D72
data_type: string
name: extract_symbolic_data
arguments: data_tag: D58
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string
name: extract_symbolic_data
arguments: data_tag: D38
data_type: string

tool: D49: %d

tool: D68: jige


tool: D72: bujige


tool: D58: youxiu


tool: D2: zhongdneg


tool: D18: lianghao


tool: D38: error


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  switch (num / 10) {
  case 10:
  case 9:
    printf("youxiu\n");
    break;
  case 8:
    printf("lianghao\n");
    break;
  case 7:
    printf("zhongdneg\n");
    break;
  case 6:
    printf("jige\n");
  case 5:
  case 4:
  case 3:
  case 2:
  case 1:
  case 0:
    printf("bujige\n");
    break;
  default:
    printf("error\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  cmp    $0xa,%eax
  ja     L32
  lea    D13(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
L57:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L57
  lea    D66(%rip),%rdi
  call   <printf@plt>
  jmp    L57
  lea    D70(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L32:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D37
datatype: string
name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D66
datatype: string
name: disassemble_data
arguments: tag: D70
datatype: string
name: disassemble_data
arguments: tag: D36
datatype: string

tool: D21: %d

tool: D37: jige


tool: D28: bujige


tool: D2: youxiu


tool: D66: zhongdneg


tool: D70: lianghao


tool: D36: error


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  switch (num / 10) {
  case 10:
  case 9:
    printf("youxiu\n");
    break;
  case 8:
    printf("lianghao\n");
    break;
  case 7:
    printf("zhongdneg\n");
    break;
  case 6:
    printf("jige\n");
  case 5:
  case 4:
  case 3:
  case 2:
  case 1:
  case 0:
    printf("bujige\n");
    break;
  default:
    printf("error\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int a = 2;
  foo(a);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 2;
  foo(a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 2;
  foo(a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 2;
  foo(a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<frag_three>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x17,-0x20(%rbp)
  movl   $0x2a,-0x1c(%rbp)
  movl   $0xc,-0x18(%rbp)
  movl   $0x2c,-0x14(%rbp)
  movl   $0x37,-0x10(%rbp)
  movl   $0x4c,-0xc(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L9
L19:
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
L9:
  cmpl   $0x5,-0x24(%rbp)
  jle    L19
  movl   $0x0,-0x24(%rbp)
  jmp    L41
L40:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L41:
  cmpl   $0x5,-0x24(%rbp)
  jle    L40
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string

tool: D17: for (i = 0; i < N; a[++i] = i);

tool: D14: %d

assistant: ```c
void frag_three() {
  printf("for (i = 0; i < N; a[++i] = i);\n");
  int a[] = {23, 42, 12, 44, 55, 76};
  int i;
  for (i = 0; i < 6; a[++i] = i)
    ;
  for (i = 0; i < 6; ++i)
    printf("%d", a[i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<frag_three>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  movl   $0x17,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  lea    D15(%rip),%rbp
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D15
type: string

tool: D8: for (i = 0; i < N; a[++i] = i);

tool: D15: %d

assistant: ```c
void frag_three() {
  printf("for (i = 0; i < N; a[++i] = i);\n");
  int a[] = {23, 42, 12, 44, 55, 76};
  int i;
  for (i = 0; i < 6; a[++i] = i)
    ;
  for (i = 0; i < 6; ++i)
    printf("%d", a[i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<frag_three>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  call   <puts@plt>
  movl   $0x1,0x4(%rsp)
  mov    $0x17,%esi
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  jmp    L20
  nopl   0x0(%rax)
L28:
  mov    (%rbx),%esi
L20:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L28
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <putchar@plt>
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
datatype: string
name: parse_data
arguments: label: D9
datatype: string

tool: D14: for (i = 0; i < N; a[++i] = i);

tool: D9: %d

assistant: ```c
void frag_three() {
  printf("for (i = 0; i < N; a[++i] = i);\n");
  int a[] = {23, 42, 12, 44, 55, 76};
  int i;
  for (i = 0; i < 6; a[++i] = i)
    ;
  for (i = 0; i < 6; ++i)
    printf("%d", a[i]);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<frag_three>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  call   <puts@plt>
  mov    D0(%rip),%rax
  movdqa D19(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  nop
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <putchar@plt>
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D19
datatype: byte[16]

tool: D28: for (i = 0; i < N; a[++i] = i);

tool: D12: %d

tool: {"D0": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D19": [0x17,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
void frag_three() {
  printf("for (i = 0; i < N; a[++i] = i);\n");
  int a[] = {23, 42, 12, 44, 55, 76};
  int i;
  for (i = 0; i < 6; a[++i] = i)
    ;
  for (i = 0; i < 6; ++i)
    printf("%d", a[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<detect_unusual_el_valence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L95
  cmpl   $0x0,-0x24(%rbp)
  jne    L95
  mov    $0x0,%eax
  jmp    L148
L95:
  cmpl   $0xfffffffe,-0x18(%rbp)
  jl     L18
  cmpl   $0x2,-0x18(%rbp)
  jle    L124
L18:
  mov    -0x20(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L149
  mov    $0x0,%eax
  jmp    L148
L149:
  mov    -0x20(%rbp),%eax
  jmp    L148
L124:
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <get_el_valence@plt>
  test   %eax,%eax
  jne    L145
  mov    -0x20(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L145
  mov    $0x0,%eax
  jmp    L148
L145:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  jne    L93
  movl   $0x1,-0xc(%rbp)
  jmp    L37
L93:
  cmpl   $0x3,-0x1c(%rbp)
  je     L147
  cmpl   $0x1,-0x1c(%rbp)
  jne    L37
L147:
  movl   $0x2,-0xc(%rbp)
L37:
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L53:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <get_el_valence@plt>
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L88
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L88
  mov    $0x0,%eax
  jmp    L148
L88:
  addl   $0x1,-0x10(%rbp)
L48:
  cmpl   $0x4,-0x10(%rbp)
  jle    L53
  mov    -0x8(%rbp),%eax
L148:
  leave
  ret
```

assistant: ```c
int detect_unusual_el_valence(int nPeriodicNum, int charge, int radical, int bonds_valence, int num_H, int num_bonds) {
  int i, chem_valence, rad_adj, known_chem_valence;
  if (!num_bonds && !num_H)
    return 0;
  if (charge < (-2) || charge > 2) {
    if (bonds_valence == num_bonds)
      return 0;
    return bonds_valence;
  }
  if (!get_el_valence(nPeriodicNum, charge, 0) && bonds_valence == num_bonds)
    return 0;
  chem_valence = bonds_valence + num_H;
  rad_adj = 0;
  if (radical == 2)
    rad_adj = 1;
  else if (radical == 3 || radical == 1)
    rad_adj = 2;
  for (i = 0; i < 5; i++) {
    if (0 < (known_chem_valence = get_el_valence(nPeriodicNum, charge, i) - rad_adj)) {
      if (known_chem_valence == chem_valence) {
        return 0;
      }
    }
  }
  return chem_valence;
}
```