ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getmsgq>:
  endbr64
  sub    $0x8,%rsp
  call   <getkey@plt>
  mov    $0x1b0,%esi
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <msgget@plt>
```

assistant: ```c
int getmsgq(int id) {
  key_t clave;
  clave = getkey(id);
  return (msgget(clave, 0660));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L5:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D9: Rowne


tool: D10: Nierowne


assistant: ```c
int main() {
  int n = 0;
  if (n = 0)
    printf("Rowne\n");
  else
    printf("Nierowne\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: Nierowne


assistant: ```c
int main() {
  int n = 0;
  if (n = 0)
    printf("Rowne\n");
  else
    printf("Nierowne\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Nierowne


assistant: ```c
int main() {
  int n = 0;
  if (n = 0)
    printf("Rowne\n");
  else
    printf("Nierowne\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: Nierowne


assistant: ```c
int main() {
  int n = 0;
  if (n = 0)
    printf("Rowne\n");
  else
    printf("Nierowne\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x14,-0x28(%rbp)
  movl   $0xa,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x8,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0xe,-0x14(%rbp)
  movl   $0x15,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x1,-0x38(%rbp)
  movl   $0x2,-0x40(%rbp)
  jmp    L40
L13:
  mov    -0x40(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  jmp    L23
L37:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  subl   $0x1,-0x3c(%rbp)
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <imprimir_arreglo@plt>
L23:
  cmpl   $0x0,-0x3c(%rbp)
  jle    L48
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jg     L37
L48:
  addl   $0x1,-0x40(%rbp)
L40:
  cmpl   $0x9,-0x40(%rbp)
  jle    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: Iteracion #%03d 

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int temporal;
  int iteracion = 1;
  for (i = 2; i < 10; i++) {
    j = i - 1;
    while ((j >= 1) && (arreglo[j] > arreglo[j + 1])) {
      temporal = arreglo[j + 1];
      arreglo[j + 1] = arreglo[j];
      arreglo[j] = temporal;
      j--;
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x14,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x8,0x14(%rsp)
  movl   $0x9,0x18(%rsp)
  movl   $0xe,0x1c(%rsp)
  movl   $0x15,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  lea    0x8(%rsp),%r15
  mov    $0x1,%r14d
  mov    $0x1,%esi
  lea    D0(%rip),%r13
  jmp    L51
L62:
  mov    %r12d,%esi
L52:
  add    $0x1,%r14d
  add    $0x4,%r15
  cmp    $0x9,%r14d
  je     L9
L51:
  test   %r14d,%r14d
  jle    L52
  lea    (%rsi,%r14,1),%r12d
  mov    %r15,%rbx
L30:
  mov    -0x4(%rbx),%edx
  mov    (%rbx),%eax
  cmp    %eax,%edx
  jle    L52
  mov    %edx,(%rbx)
  mov    %eax,-0x4(%rbx)
  lea    0x1(%rsi),%ebp
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <imprimir_arreglo@plt>
  sub    $0x4,%rbx
  cmp    %r12d,%ebp
  je     L62
  mov    %ebp,%esi
  jmp    L30
L9:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Iteracion #%03d 

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int temporal;
  int iteracion = 1;
  for (i = 2; i < 10; i++) {
    j = i - 1;
    while ((j >= 1) && (arreglo[j] > arreglo[j + 1])) {
      temporal = arreglo[j + 1];
      arreglo[j + 1] = arreglo[j];
      arreglo[j] = temporal;
      j--;
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x14,%edx
  mov    $0x1,%esi
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000001,%rax
  lea    0x8(%rsp),%r13
  mov    %rax,(%rsp)
  movabs $0xa00000014,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x800000003,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xe00000009,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x600000015,%rax
  mov    %rax,0x20(%rsp)
  mov    $0x4,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  lea    -0x1(%r14,%rsi,1),%ebp
  mov    %r13,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L54:
  mov    -0x4(%rbx),%eax
  mov    (%rbx),%edx
  mov    %r15d,%esi
L1:
  cmp    %edx,%eax
  jle    L43
  mov    %edx,-0x4(%rbx)
  mov    %r12,%rdi
  lea    0x1(%rsi),%r15d
  sub    $0x4,%rbx
  mov    %eax,0x4(%rbx)
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <imprimir_arreglo@plt>
  cmp    %ebp,%r15d
  jne    L54
  add    $0x1,%r14d
  add    $0x4,%r13
  cmp    $0xa,%r14d
  je     L24
L39:
  mov    -0x4(%r13),%eax
  mov    0x0(%r13),%edx
  mov    %ebp,%esi
  jmp    L5
  nopl   0x0(%rax)
L43:
  add    $0x1,%r14d
  mov    %esi,%ebp
  add    $0x4,%r13
  cmp    $0xa,%r14d
  jne    L39
L24:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: Iteracion #%03d 

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int temporal;
  int iteracion = 1;
  for (i = 2; i < 10; i++) {
    j = i - 1;
    while ((j >= 1) && (arreglo[j] > arreglo[j + 1])) {
      temporal = arreglo[j + 1];
      arreglo[j + 1] = arreglo[j];
      arreglo[j] = temporal;
      j--;
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movdqa D33(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  lea    0x8(%rsp),%r14
  movaps %xmm0,(%rsp)
  movdqa D2(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  xchg   %ax,%ax
L13:
  lea    -0x1(%rsi,%r13,1),%ebp
  mov    %r14,%rbx
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r15d,%esi
L37:
  movq   -0x4(%rbx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%edx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%edx
  jle    L34
  movq   %xmm1,-0x4(%rbx)
  mov    %r12,%rdi
  lea    0x1(%rsi),%r15d
  sub    $0x4,%rbx
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <imprimir_arreglo@plt>
  cmp    %ebp,%r15d
  jne    L35
  mov    %ebp,%esi
L34:
  add    $0x1,%r13d
  add    $0x4,%r14
  cmp    $0xa,%r13d
  jne    L13
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
data_type: string
name: extract_symbolic_data
arguments: data_label: D33
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D28
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D2
data_type: byte[16]

tool: D27: Iteracion #%03d 

tool: {"D33": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D28": [0x15,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D2": [0x03,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0e,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int temporal;
  int iteracion = 1;
  for (i = 2; i < 10; i++) {
    j = i - 1;
    while ((j >= 1) && (arreglo[j] > arreglo[j + 1])) {
      temporal = arreglo[j + 1];
      arreglo[j + 1] = arreglo[j];
      arreglo[j] = temporal;
      j--;
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
L28:
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cmp    $0xffffffff,%eax
  je     L26
  mov    -0x20(%rbp),%eax
  imul   $0x15a8,%eax,%edx
  mov    -0x1c(%rbp),%eax
  imul   $0x3855,%eax,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   $0x508,%eax,%eax
  add    %edx,%eax
  add    $0x5304,%eax
  mov    -0x14(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x5304,-0x10(%rbp)
  jle    L37
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x31571165,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5304,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
L37:
  cmpl   $0x0,-0x10(%rbp)
  jg     L1
  addl   $0x5304,-0x10(%rbp)
L1:
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L26:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D2
data_type: string

tool: D13: %d %d %d %d

tool: D2: Case %d: the next triple peak occurs in %d days.


assistant: ```c
int main() {
  int phyDay, emoDay, intDay, startDay, peakDay;
  int nCase = 0;
  while (1) {
    scanf("%d %d %d %d", &phyDay, &emoDay, &intDay, &startDay);
    if (phyDay == -1)
      break;
    peakDay = phyDay * 5544 + emoDay * 14421 + intDay * 1288 + 21252 - startDay;
    if (peakDay > 21252)
      peakDay %= 21252;
    if (peakDay <= 0)
      peakDay += 21252;
    nCase++;
    printf("Case %d: the next triple peak occurs in %d days.\n", nCase, peakDay);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D11(%rip),%rbp
  lea    D18(%rip),%r14
  jmp    L39
L37:
  lea    0x5304(%rdx),%eax
  test   %edx,%edx
  cmovle %eax,%edx
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L39:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L36
  imul   $0x3855,0xc(%rsp),%edx
  imul   $0x15a8,%eax,%eax
  add    %edx,%eax
  imul   $0x508,0x10(%rsp),%edx
  lea    0x5304(%rax,%rdx,1),%edx
  sub    0x14(%rsp),%edx
  cmp    $0x5304,%edx
  jle    L37
  movslq %edx,%rax
  imul   $0x31571165,%rax,%rax
  sar    $0x2c,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x5304,%eax,%eax
  sub    %eax,%edx
  jmp    L37
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D11: %d %d %d %d

tool: D18: Case %d: the next triple peak occurs in %d days.


assistant: ```c
int main() {
  int phyDay, emoDay, intDay, startDay, peakDay;
  int nCase = 0;
  while (1) {
    scanf("%d %d %d %d", &phyDay, &emoDay, &intDay, &startDay);
    if (phyDay == -1)
      break;
    peakDay = phyDay * 5544 + emoDay * 14421 + intDay * 1288 + 21252 - startDay;
    if (peakDay > 21252)
      peakDay %= 21252;
    if (peakDay <= 0)
      peakDay += 21252;
    nCase++;
    printf("Case %d: the next triple peak occurs in %d days.\n", nCase, peakDay);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r15
  lea    0x10(%rsp),%r14
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  jmp    L15
  nopl   0x0(%rax)
L26:
  imul   $0x3855,0xc(%rsp),%edx
  imul   $0x15a8,%eax,%eax
  add    %edx,%eax
  imul   $0x508,0x10(%rsp),%edx
  lea    0x5304(%rax,%rdx,1),%edx
  sub    0x14(%rsp),%edx
  cmp    $0x5304,%edx
  jle    L37
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x31571165,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x2c,%rax
  sub    %ecx,%eax
  imul   $0x5304,%eax,%eax
  sub    %eax,%edx
L37:
  test   %edx,%edx
  lea    0x5304(%rdx),%eax
  lea    D9(%rip),%rdi
  cmovle %eax,%edx
  add    $0x1,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
L15:
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    $0xffffffff,%eax
  jne    L26
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D11: %d %d %d %d

tool: D9: Case %d: the next triple peak occurs in %d days.


assistant: ```c
int main() {
  int phyDay, emoDay, intDay, startDay, peakDay;
  int nCase = 0;
  while (1) {
    scanf("%d %d %d %d", &phyDay, &emoDay, &intDay, &startDay);
    if (phyDay == -1)
      break;
    peakDay = phyDay * 5544 + emoDay * 14421 + intDay * 1288 + 21252 - startDay;
    if (peakDay > 21252)
      peakDay %= 21252;
    if (peakDay <= 0)
      peakDay += 21252;
    nCase++;
    printf("Case %d: the next triple peak occurs in %d days.\n", nCase, peakDay);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r15
  lea    0x10(%rsp),%r14
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  jmp    L24
  nopl   0x0(%rax)
L37:
  imul   $0x3855,0xc(%rsp),%edx
  imul   $0x15a8,%eax,%eax
  add    %edx,%eax
  imul   $0x508,0x10(%rsp),%edx
  lea    0x5304(%rax,%rdx,1),%edx
  sub    0x14(%rsp),%edx
  cmp    $0x5304,%edx
  jle    L27
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x31571165,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x2c,%rax
  sub    %ecx,%eax
  imul   $0x5304,%eax,%eax
  sub    %eax,%edx
L27:
  test   %edx,%edx
  lea    0x5304(%rdx),%eax
  lea    D5(%rip),%rdi
  cmovle %eax,%edx
  add    $0x1,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
L24:
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    $0xffffffff,%eax
  jne    L37
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D17: %d %d %d %d

tool: D5: Case %d: the next triple peak occurs in %d days.


assistant: ```c
int main() {
  int phyDay, emoDay, intDay, startDay, peakDay;
  int nCase = 0;
  while (1) {
    scanf("%d %d %d %d", &phyDay, &emoDay, &intDay, &startDay);
    if (phyDay == -1)
      break;
    peakDay = phyDay * 5544 + emoDay * 14421 + intDay * 1288 + 21252 - startDay;
    if (peakDay > 21252)
      peakDay %= 21252;
    if (peakDay <= 0)
      peakDay += 21252;
    nCase++;
    printf("Case %d: the next triple peak occurs in %d days.\n", nCase, peakDay);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%edx
  lea    -0xd(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x1c(%rbp),%edx
  lea    -0xd(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: %%0%dX

assistant: ```c
void int2hex(char *dst, unsigned int input, int dim) {
  char pattern[5];
  sprintf(pattern, "%%0%dX", dim);
  sprintf(dst, pattern, input);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int2hex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: %%0%dX

assistant: ```c
void int2hex(char *dst, unsigned int input, int dim) {
  char pattern[5];
  sprintf(pattern, "%%0%dX", dim);
  sprintf(dst, pattern, input);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int2hex>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D7(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7: %%0%dX

assistant: ```c
void int2hex(char *dst, unsigned int input, int dim) {
  char pattern[5];
  sprintf(pattern, "%%0%dX", dim);
  sprintf(dst, pattern, input);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int2hex>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %%0%dX

assistant: ```c
void int2hex(char *dst, unsigned int input, int dim) {
  char pattern[5];
  sprintf(pattern, "%%0%dX", dim);
  sprintf(dst, pattern, input);
}
```