user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matLUbksb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %rdx,-0xc8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa0(%rbp)
  movl   $0x0,-0xa8(%rbp)
  jmp    L148
L169:
  movl   $0x0,-0xa4(%rbp)
  jmp    L122
L120:
  mov    -0xa8(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0xa4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movsd  %xmm0,-0x90(%rbp,%rax,8)
  addl   $0x1,-0xa4(%rbp)
L122:
  cmpl   $0x3,-0xa4(%rbp)
  jle    L120
  addl   $0x1,-0xa8(%rbp)
L148:
  cmpl   $0x3,-0xa8(%rbp)
  jle    L169
  movl   $0x0,-0xa8(%rbp)
  jmp    L75
L95:
  mov    -0xa8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xc0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x9c(%rbp)
  mov    -0x9c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x98(%rbp)
  mov    -0xa8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x9c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0xc8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  cmpl   $0x0,-0xa0(%rbp)
  je     L153
  mov    -0xa0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xa4(%rbp)
  jmp    L11
L54:
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movsd  -0x90(%rbp,%rax,8),%xmm1
  mov    -0xa4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x98(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x98(%rbp)
  addl   $0x1,-0xa4(%rbp)
L11:
  mov    -0xa8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xa4(%rbp)
  jl     L54
  jmp    L103
L153:
  pxor   %xmm0,%xmm0
  ucomisd -0x98(%rbp),%xmm0
  jp     L42
  pxor   %xmm0,%xmm0
  ucomisd -0x98(%rbp),%xmm0
  je     L103
L42:
  mov    -0xa8(%rbp),%eax
  mov    %eax,-0xa0(%rbp)
L103:
  mov    -0xa8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x98(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xa8(%rbp)
L75:
  cmpl   $0x3,-0xa8(%rbp)
  jle    L95
  movl   $0x3,-0xa8(%rbp)
  jmp    L19
L59:
  mov    -0xa8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x98(%rbp)
  mov    -0xa8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xa4(%rbp)
  jmp    L127
L85:
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movsd  -0x90(%rbp,%rax,8),%xmm1
  mov    -0xa4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x98(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x98(%rbp)
  addl   $0x1,-0xa4(%rbp)
L127:
  cmpl   $0x3,-0xa4(%rbp)
  jle    L85
  mov    -0xa8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rbp,%rax
  sub    $0x90,%rax
  movsd  (%rax),%xmm1
  mov    -0xa8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x98(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0xa8(%rbp)
L19:
  cmpl   $0x0,-0xa8(%rbp)
  jns    L59
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L78
  call   <__stack_chk_fail@plt>
L78:
  leave
  ret
```

assistant: ```c
int matLUbksb(double *aa, int *indx, double *b) {
  double a[4][4];
  int i, j;
  int ii = 0;
  int ll;
  double sum;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      a[i][j] = aa[i * 4 + j];
  for (i = 0; i < 4; i++) {
    ll = indx[i];
    sum = b[ll];
    b[ll] = b[i];
    if (ii != 0) {
      for (j = ii - 1; j < i - 1; j++)
        sum -= a[i][j] * b[j];
    } else if (sum != 0.0) {
      ii = i;
    }
    b[i] = sum;
  }
  for (i = 3; i >= 0; i--) {
    sum = b[i];
    for (j = i + 1; j < 4; j++)
      sum -= a[i][j] * b[j];
    b[i] = sum / a[i][i];
  }
  return 0;
}
```