ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mct_decode>:
  endbr64
  movslq %ecx,%r8
  test   %r8d,%r8d
  jle    L96
  lea    0xf(%rsi),%rcx
  lea    0xf(%rdi),%rax
  sub    %rdx,%rcx
  cmp    $0x1e,%rcx
  seta   %cl
  cmp    $0x1,%r8d
  setne  %r9b
  and    %r9d,%ecx
  mov    %rax,%r9
  sub    %rsi,%r9
  cmp    $0x1e,%r9
  seta   %r9b
  test   %r9b,%cl
  je     L57
  sub    %rdx,%rax
  cmp    $0x1e,%rax
  jbe    L57
  lea    -0x1(%r8),%eax
  mov    %r8d,%r9d
  cmp    $0x2,%eax
  jbe    L30
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   (%rax)
L65:
  movdqu (%rsi,%rax,1),%xmm1
  movdqu (%rdx,%rax,1),%xmm2
  movdqu (%rdi,%rax,1),%xmm0
  paddd  %xmm1,%xmm2
  psrad  $0x2,%xmm2
  psubd  %xmm2,%xmm0
  movdqu (%rdx,%rax,1),%xmm2
  paddd  %xmm0,%xmm1
  paddd  %xmm0,%xmm2
  movups %xmm2,(%rdi,%rax,1)
  movups %xmm0,(%rsi,%rax,1)
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L65
  mov    %r8d,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%r8d
  je     L96
  sub    %ecx,%r8d
  mov    %r8d,%r9d
  cmp    $0x1,%r8d
  je     L43
L89:
  shl    $0x2,%rcx
  lea    (%rsi,%rcx,1),%r8
  lea    (%rdi,%rcx,1),%r10
  add    %rdx,%rcx
  movq   (%r8),%xmm1
  movq   (%rcx),%xmm2
  movq   (%r10),%xmm0
  movdqa %xmm1,%xmm3
  paddd  %xmm2,%xmm3
  psrad  $0x2,%xmm3
  psubd  %xmm3,%xmm0
  paddd  %xmm0,%xmm2
  paddd  %xmm0,%xmm1
  movq   %xmm2,(%r10)
  movq   %xmm0,(%r8)
  movq   %xmm1,(%rcx)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L96
L43:
  cltq
  shl    $0x2,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  add    %rdx,%rax
  mov    (%rsi),%ecx
  mov    (%rax),%r8d
  mov    (%rdi),%edx
  lea    (%rcx,%r8,1),%r9d
  sar    $0x2,%r9d
  sub    %r9d,%edx
  add    %edx,%r8d
  add    %edx,%ecx
  mov    %r8d,(%rdi)
  mov    %edx,(%rsi)
  mov    %ecx,(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L64:
  mov    (%rsi,%rax,4),%r9d
  mov    (%rdx,%rax,4),%r10d
  mov    (%rdi,%rax,4),%ecx
  lea    (%r9,%r10,1),%r11d
  sar    $0x2,%r11d
  sub    %r11d,%ecx
  add    %ecx,%r10d
  add    %ecx,%r9d
  mov    %r10d,(%rdi,%rax,4)
  mov    %ecx,(%rsi,%rax,4)
  mov    %r9d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L64
L96:
  ret
L30:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L89
```

assistant: ```c
void mct_decode(int *c0, int *c1, int *c2, int n) {
  int i;
  for (i = 0; i < n; i++) {
    int y, u, v, r, g, b;
    y = c0[i];
    u = c1[i];
    v = c2[i];
    g = y - ((u + v) >> 2);
    r = v + g;
    b = u + g;
    c0[i] = r;
    c1[i] = g;
    c2[i] = b;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nbsdecrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L53
L63:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L38
L59:
  addq   $0x1,-0x28(%rbp)
L38:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L59
L4:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x29(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <nbs8decrypt@plt>
  cltq
  mov    %rax,%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  cmpb   $0x0,-0x29(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x38(%rbp)
L53:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
  jmp    L79
L2:
  nop
L79:
  mov    -0x48(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
char *nbsdecrypt(cpt, key, result)
char *result;
char *cpt, *key;
{
  char *s;
  char c, oldbuf[20];
  result[0] = 0;
  strcpy(oldbuf, key);
  while (*cpt) {
    for (s = cpt; *s && *s != '$'; s++)
      ;
    c = *s;
    *s = 0;
    strcpy(oldbuf, nbs8decrypt(cpt, oldbuf));
    strcat(result, oldbuf);
    if (c == 0)
      break;
    cpt = s + 1;
  }
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nbsdecrypt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rdx)
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rsp,%r13
  cmpb   $0x0,(%r12)
  jne    L69
L59:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    %r14,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  mov    %r12,%rbx
L3:
  movb   $0x0,(%rbx)
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <nbs8decrypt@plt>
  movslq %eax,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  test   %bpl,%bpl
  je     L59
  lea    0x1(%rbx),%r12
  cmpb   $0x0,0x1(%rbx)
  je     L59
L69:
  movzbl (%r12),%ebp
  test   %bpl,%bpl
  je     L49
  mov    %r12,%rbx
  cmp    $0x24,%bpl
  je     L49
L32:
  add    $0x1,%rbx
  movzbl (%rbx),%ebp
  test   %bpl,%bpl
  je     L3
  cmp    $0x24,%bpl
  jne    L32
  jmp    L3
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *nbsdecrypt(cpt, key, result)
char *result;
char *cpt, *key;
{
  char *s;
  char c, oldbuf[20];
  result[0] = 0;
  strcpy(oldbuf, key);
  while (*cpt) {
    for (s = cpt; *s && *s != '$'; s++)
      ;
    c = *s;
    *s = 0;
    strcpy(oldbuf, nbs8decrypt(cpt, oldbuf));
    strcat(result, oldbuf);
    if (c == 0)
      break;
    cpt = s + 1;
  }
  return (result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nbsdecrypt>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rdx)
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  movzbl (%r14),%eax
  test   %al,%al
  je     L18
  nopl   0x0(%rax)
L47:
  mov    %r14,%rbx
  cmp    $0x24,%al
  je     L24
  nopw   0x0(%rax,%rax,1)
L31:
  movzbl 0x1(%rbx),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L57
  cmp    $0x24,%bpl
  jne    L31
L57:
  movb   $0x0,(%rbx)
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <nbs8decrypt@plt>
  mov    %r12,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  test   %bpl,%bpl
  je     L18
L0:
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%r14
  test   %al,%al
  jne    L47
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  movb   $0x0,(%r14)
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <nbs8decrypt@plt>
  mov    %r12,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  jmp    L0
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *nbsdecrypt(cpt, key, result)
char *result;
char *cpt, *key;
{
  char *s;
  char c, oldbuf[20];
  result[0] = 0;
  strcpy(oldbuf, key);
  while (*cpt) {
    for (s = cpt; *s && *s != '$'; s++)
      ;
    c = *s;
    *s = 0;
    strcpy(oldbuf, nbs8decrypt(cpt, oldbuf));
    strcat(result, oldbuf);
    if (c == 0)
      break;
    cpt = s + 1;
  }
  return (result);
}
```
user: What is the c source code of the assembly code below?

```asm
<nbsdecrypt>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rdx)
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  movzbl (%r14),%eax
  test   %al,%al
  je     L24
  nopl   0x0(%rax)
L11:
  mov    %r14,%rbx
  cmp    $0x24,%al
  je     L1
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rbx),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L41
  cmp    $0x24,%bpl
  jne    L44
L41:
  movb   $0x0,(%rbx)
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <nbs8decrypt@plt>
  mov    %r12,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  test   %bpl,%bpl
  je     L24
L35:
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%r14
  test   %al,%al
  jne    L11
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%r14)
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <nbs8decrypt@plt>
  mov    %r12,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  jmp    L35
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *nbsdecrypt(cpt, key, result)
char *result;
char *cpt, *key;
{
  char *s;
  char c, oldbuf[20];
  result[0] = 0;
  strcpy(oldbuf, key);
  while (*cpt) {
    for (s = cpt; *s && *s != '$'; s++)
      ;
    c = *s;
    *s = 0;
    strcpy(oldbuf, nbs8decrypt(cpt, oldbuf));
    strcat(result, oldbuf);
    if (c == 0)
      break;
    cpt = s + 1;
  }
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gmx_strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L53
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L11
  movsbl -0x2(%rbp),%eax
  movsbl -0x1(%rbp),%edx
  sub    %edx,%eax
  jmp    L53
L11:
  subl   $0x1,-0x24(%rbp)
  cmpb   $0x0,-0x2(%rbp)
  je     L6
  cmpl   $0x0,-0x24(%rbp)
  jne    L9
L6:
  mov    $0x0,%eax
L53:
  leave
  ret
```

assistant: ```c
int gmx_strncasecmp(const char *str1, const char *str2, int n) {
  char ch1, ch2;
  if (n == 0)
    return 0;
  do {
    ch1 = toupper(*(str1++));
    ch2 = toupper(*(str2++));
    if (ch1 != ch2)
      return (ch1 - ch2);
    n--;
  } while (ch1 && n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gmx_strncasecmp>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  je     L12
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rdi,%rbp
L3:
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  add    $0x1,%r12
  movsbl -0x1(%r12),%edi
  call   <toupper@plt>
  cmp    %al,%bl
  jne    L33
  mov    %r14d,%eax
  sub    %ebp,%eax
  add    %r13d,%eax
  je     L20
  test   %bl,%bl
  jne    L3
L20:
  mov    $0x0,%eax
  jmp    L29
L33:
  movsbl %bl,%ebx
  movsbl %al,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  ret
```

assistant: ```c
int gmx_strncasecmp(const char *str1, const char *str2, int n) {
  char ch1, ch2;
  if (n == 0)
    return 0;
  do {
    ch1 = toupper(*(str1++));
    ch2 = toupper(*(str2++));
    if (ch1 != ch2)
      return (ch1 - ch2);
    n--;
  } while (ch1 && n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gmx_strncasecmp>:
  endbr64
  test   %edx,%edx
  je     L35
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L34
  xchg   %ax,%ax
L38:
  mov    %r13d,%eax
  sub    %r14d,%eax
  add    %r12d,%eax
  je     L15
  test   %bl,%bl
  je     L15
L34:
  movsbl (%r14),%edi
  add    $0x1,%rbp
  add    $0x1,%r14
  call   <toupper@plt>
  movsbl -0x1(%rbp),%edi
  movsbl %al,%ebx
  call   <toupper@plt>
  cmp    %al,%bl
  je     L38
  movsbl %al,%edx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int gmx_strncasecmp(const char *str1, const char *str2, int n) {
  char ch1, ch2;
  if (n == 0)
    return 0;
  do {
    ch1 = toupper(*(str1++));
    ch2 = toupper(*(str2++));
    if (ch1 != ch2)
      return (ch1 - ch2);
    n--;
  } while (ch1 && n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gmx_strncasecmp>:
  endbr64
  test   %edx,%edx
  je     L42
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L22
  xchg   %ax,%ax
L20:
  mov    %r13d,%eax
  sub    %r14d,%eax
  add    %r12d,%eax
  je     L32
  test   %bl,%bl
  je     L32
L22:
  movsbl (%r14),%edi
  add    $0x1,%rbp
  add    $0x1,%r14
  call   <toupper@plt>
  movsbl -0x1(%rbp),%edi
  movsbl %al,%ebx
  call   <toupper@plt>
  cmp    %al,%bl
  je     L20
  movsbl %al,%edx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
int gmx_strncasecmp(const char *str1, const char *str2, int n) {
  char ch1, ch2;
  if (n == 0)
    return 0;
  do {
    ch1 = toupper(*(str1++));
    ch2 = toupper(*(str2++));
    if (ch1 != ch2)
      return (ch1 - ch2);
    n--;
  } while (ch1 && n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MAIN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <is_prime@plt>
  test   %eax,%eax
  je     L12
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <write@plt>
L12:
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L23
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D5
type: string

tool: D13: enter a range, for example, 5<ENTER> 23<ENTER>:

tool: D5: 


assistant: ```c
int MAIN() {
  int i, num1, num2;
  write("enter a range, for example, 5<ENTER> 23<ENTER>:");
  num1 = read();
  num2 = read();
  for (i = num1; i < num2; i = i + 1) {
    if (is_prime(i)) {
      write(i);
      write("\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MAIN>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <read@plt>
  cmp    %eax,%ebx
  jge    L45
  mov    %eax,%ebp
  lea    D12(%rip),%r12
  jmp    L47
L1:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L45
L47:
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <is_prime@plt>
  test   %eax,%eax
  je     L1
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <write@plt>
  jmp    L1
L45:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D12
type: string

tool: D6: enter a range, for example, 5<ENTER> 23<ENTER>:

tool: D12: 


assistant: ```c
int MAIN() {
  int i, num1, num2;
  write("enter a range, for example, 5<ENTER> 23<ENTER>:");
  num1 = read();
  num2 = read();
  for (i = num1; i < num2; i = i + 1) {
    if (is_prime(i)) {
      write(i);
      write("\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<MAIN>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <write@plt>
  xor    %eax,%eax
  call   <read@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <read@plt>
  cmp    %eax,%ebx
  jge    L43
  mov    %eax,%ebp
  lea    D6(%rip),%r12
  jmp    L8
  nopl   (%rax)
L25:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L43
L8:
  xor    %eax,%eax
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L25
  mov    %ebx,%edi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <write@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <write@plt>
  cmp    %ebx,%ebp
  jne    L8
L43:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string
name: read_data
arguments: label: D6
data_type: string

tool: D9: enter a range, for example, 5<ENTER> 23<ENTER>:

tool: D6: 


assistant: ```c
int MAIN() {
  int i, num1, num2;
  write("enter a range, for example, 5<ENTER> 23<ENTER>:");
  num1 = read();
  num2 = read();
  for (i = num1; i < num2; i = i + 1) {
    if (is_prime(i)) {
      write(i);
      write("\n");
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MAIN>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <write@plt>
  xor    %eax,%eax
  call   <read@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <read@plt>
  cmp    %eax,%ebx
  jge    L35
  mov    %eax,%ebp
  lea    D18(%rip),%r12
  jmp    L41
  nopl   (%rax)
L18:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L35
L41:
  xor    %eax,%eax
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L18
  mov    %ebx,%edi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <write@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <write@plt>
  cmp    %ebx,%ebp
  jne    L41
L35:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D18
datatype: string

tool: D7: enter a range, for example, 5<ENTER> 23<ENTER>:

tool: D18: 


assistant: ```c
int MAIN() {
  int i, num1, num2;
  write("enter a range, for example, 5<ENTER> 23<ENTER>:");
  num1 = read();
  num2 = read();
  for (i = num1; i < num2; i = i + 1) {
    if (is_prime(i)) {
      write(i);
      write("\n");
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xe4(%rbp)
  movl   $0x0,-0xe8(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L6:
  lea    -0xe0(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <detab@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xe8(%rbp)
  jmp    L14
L2:
  mov    -0xe8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%ecx
  mov    -0xe8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0xe8(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xe8(%rbp)
L14:
  mov    -0xe8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L2
L24:
  lea    -0xe0(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <getline_my@plt>
  mov    %eax,-0xe4(%rbp)
  cmpl   $0x0,-0xe4(%rbp)
  jg     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D12
datatype: string

tool: D29: Input, please, lines to detab:

tool: D22: %s;


tool: D12: newline [ %d ] = '%c' and %d;


assistant: ```c
int main() {
  int len = 0;
  char line[100];
  char newline[100];
  int i = 0;
  printf("Input, please, lines to detab:\n");
  while ((len = getline_my(line, 100)) > 0) {
    detab(newline, line);
    printf("%s;\n", newline);
    i = 0;
    while (newline[i] != '\0') {
      printf("newline [ %d ] = '%c' and %d;\n", i, newline[i], newline[i]);
      i++;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%r13
  lea    0x70(%rsp),%rbp
  lea    D10(%rip),%r14
  lea    D1(%rip),%r12
L48:
  mov    $0x64,%esi
  mov    %r13,%rdi
  call   <getline_my@plt>
  test   %eax,%eax
  jle    L46
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <detab@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl 0x70(%rsp),%edx
  test   %dl,%dl
  je     L48
  mov    $0x0,%ebx
L21:
  movsbl %dl,%edx
  mov    %edx,%ecx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  movzbl (%rbx,%rbp,1),%edx
  test   %dl,%dl
  jne    L21
  jmp    L48
L46:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
data_type: string
name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D1
data_type: string

tool: D16: Input, please, lines to detab:

tool: D10: %s;


tool: D1: newline [ %d ] = '%c' and %d;


assistant: ```c
int main() {
  int len = 0;
  char line[100];
  char newline[100];
  int i = 0;
  printf("Input, please, lines to detab:\n");
  while ((len = getline_my(line, 100)) > 0) {
    detab(newline, line);
    printf("%s;\n", newline);
    i = 0;
    while (newline[i] != '\0') {
      printf("newline [ %d ] = '%c' and %d;\n", i, newline[i], newline[i]);
      i++;
    }
  }
  return 0;
}
```