ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<test_strcpy_not_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6765202c6d617073,%rax
  movabs $0x20646e61202c7367,%rdx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  movl   $0x6d6168,-0x80(%rbp)
  lea    -0x70(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x90(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <pl_cpy@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0x98(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rcx
  lea    D25(%rip),%rdx
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <assert_equal_str@plt>
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string

tool: D12: foobar

tool: D3: The strings are not equal

tool: D25: test_strcpy_not_empty

tool: D19: spam, eggs, and ham

assistant: ```c
void test_strcpy_not_empty() {
  char the_string[] = "spam, eggs, and ham";
  char *ret_val, tmp[100];
  strcpy(tmp, "foobar");
  ret_val = pl_cpy(the_string, NULL);
  assert_equal_str("spam, eggs, and ham", ret_val, "test_strcpy_not_empty", "The strings are not equal");
  free(ret_val);
}
```
user: What is the c source code of the assembly code below:

```asm
<test_strcpy_not_empty>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x6765202c6d617073,%rax
  movabs $0x20646e61202c7367,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x6d6168,0x10(%rsp)
  lea    0x20(%rsp),%rdi
  lea    D2(%rip),%rsi
  call   <strcpy@plt>
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <pl_cpy@plt>
  mov    %rax,%rbx
  lea    D10(%rip),%rcx
  lea    D1(%rip),%rdx
  mov    %rax,%rsi
  lea    D36(%rip),%rdi
  call   <assert_equal_str@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x90,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D36
type: string

tool: D2: foobar

tool: D10: The strings are not equal

tool: D1: test_strcpy_not_empty

tool: D36: spam, eggs, and ham

assistant: ```c
void test_strcpy_not_empty() {
  char the_string[] = "spam, eggs, and ham";
  char *ret_val, tmp[100];
  strcpy(tmp, "foobar");
  ret_val = pl_cpy(the_string, NULL);
  assert_equal_str("spam, eggs, and ham", ret_val, "test_strcpy_not_empty", "The strings are not equal");
  free(ret_val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_strcpy_not_empty>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rsi
  sub    $0x90,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  movl   $0x6d6168,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <strcpy@plt>
  xor    %esi,%esi
  mov    %rsp,%rdi
  call   <pl_cpy@plt>
  lea    D14(%rip),%rdi
  lea    D48(%rip),%rcx
  mov    %rax,%rbp
  lea    D22(%rip),%rdx
  mov    %rax,%rsi
  call   <assert_equal_str@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x90,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: byte[16]
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D48
type_infered: string
name: extract_symbolic_data
arguments: label: D22
type_infered: string

tool: D7: foobar

tool: {"D18": [0x73,0x70,0x61,0x6d,0x2c,0x20,0x65,0x67,0x67,0x73,0x2c,0x20,0x61,0x6e,0x64,0x20]}

tool: D14: spam, eggs, and ham

tool: D48: The strings are not equal

tool: D22: test_strcpy_not_empty

assistant: ```c
void test_strcpy_not_empty() {
  char the_string[] = "spam, eggs, and ham";
  char *ret_val, tmp[100];
  strcpy(tmp, "foobar");
  ret_val = pl_cpy(the_string, NULL);
  assert_equal_str("spam, eggs, and ham", ret_val, "test_strcpy_not_empty", "The strings are not equal");
  free(ret_val);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_strcpy_not_empty>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rsi
  sub    $0x90,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  movl   $0x6d6168,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <strcpy@plt>
  xor    %esi,%esi
  mov    %rsp,%rdi
  call   <pl_cpy@plt>
  lea    D35(%rip),%rdi
  lea    D19(%rip),%rcx
  mov    %rax,%rbp
  lea    D44(%rip),%rdx
  mov    %rax,%rsi
  call   <assert_equal_str@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x90,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
type_guessed: string
name: read_data
arguments: data_label: D6
type_guessed: byte[16]
name: read_data
arguments: data_label: D35
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D44
type_guessed: string

tool: D23: foobar

tool: {"D6": [0x73,0x70,0x61,0x6d,0x2c,0x20,0x65,0x67,0x67,0x73,0x2c,0x20,0x61,0x6e,0x64,0x20]}

tool: D35: spam, eggs, and ham

tool: D19: The strings are not equal

tool: D44: test_strcpy_not_empty

assistant: ```c
void test_strcpy_not_empty() {
  char the_string[] = "spam, eggs, and ham";
  char *ret_val, tmp[100];
  strcpy(tmp, "foobar");
  ret_val = pl_cpy(the_string, NULL);
  assert_equal_str("spam, eggs, and ham", ret_val, "test_strcpy_not_empty", "The strings are not equal");
  free(ret_val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_ipv4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %ax,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x45,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  mov    %rax,-0x28(%rbp)
  movzwl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <append_bytes@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <append_bytes@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <in_cksum@plt>
  mov    %ax,-0x1a(%rbp)
  lea    -0x1a(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *write_ipv4(char *bufferptr, unsigned short identifier, unsigned char *local_ip, unsigned char *dest_ip) {
  char *start = bufferptr;
  bufferptr = append_byte(bufferptr, 0x45);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_short(bufferptr, (64 - (2 * 6 + 2)));
  ;
  bufferptr = append_short(bufferptr, identifier);
  ;
  bufferptr = append_byte(bufferptr, 0x40);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_byte(bufferptr, 64);
  ;
  bufferptr = append_byte(bufferptr, 1);
  ;
  char *checksumstart = bufferptr;
  bufferptr = append_short(bufferptr, 0);
  ;
  bufferptr = append_bytes(bufferptr, local_ip, 4);
  ;
  bufferptr = append_bytes(bufferptr, dest_ip, 4);
  ;
  unsigned short checksum = in_cksum((short unsigned int *)start, 20);
  memcpy(checksumstart, &checksum, 2);
  return bufferptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_ipv4>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x45,%esi
  call   <append_byte@plt>
  mov    %rax,%rdi
  mov    $0x0,%esi
  call   <append_byte@plt>
  mov    %rax,%rdi
  mov    $0x32,%esi
  call   <append_short@plt>
  mov    %rax,%rdi
  movzwl %bx,%esi
  call   <append_short@plt>
  mov    %rax,%rdi
  mov    $0x40,%esi
  call   <append_byte@plt>
  mov    %rax,%rdi
  mov    $0x0,%esi
  call   <append_byte@plt>
  mov    %rax,%rdi
  mov    $0x40,%esi
  call   <append_byte@plt>
  mov    %rax,%rdi
  mov    $0x1,%esi
  call   <append_byte@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  mov    %rax,%rdi
  mov    $0x4,%edx
  mov    %r13,%rsi
  call   <append_bytes@plt>
  mov    %rax,%rdi
  mov    $0x4,%edx
  mov    %r12,%rsi
  call   <append_bytes@plt>
  mov    %rax,%r12
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <in_cksum@plt>
  mov    %ax,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *write_ipv4(char *bufferptr, unsigned short identifier, unsigned char *local_ip, unsigned char *dest_ip) {
  char *start = bufferptr;
  bufferptr = append_byte(bufferptr, 0x45);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_short(bufferptr, (64 - (2 * 6 + 2)));
  ;
  bufferptr = append_short(bufferptr, identifier);
  ;
  bufferptr = append_byte(bufferptr, 0x40);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_byte(bufferptr, 64);
  ;
  bufferptr = append_byte(bufferptr, 1);
  ;
  char *checksumstart = bufferptr;
  bufferptr = append_short(bufferptr, 0);
  ;
  bufferptr = append_bytes(bufferptr, local_ip, 4);
  ;
  bufferptr = append_bytes(bufferptr, dest_ip, 4);
  ;
  unsigned short checksum = in_cksum((short unsigned int *)start, 20);
  memcpy(checksumstart, &checksum, 2);
  return bufferptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_ipv4>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x45,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <append_byte@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  movzwl %bx,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <append_short@plt>
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <append_bytes@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <append_bytes@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <in_cksum@plt>
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  mov    %ax,0x6(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *write_ipv4(char *bufferptr, unsigned short identifier, unsigned char *local_ip, unsigned char *dest_ip) {
  char *start = bufferptr;
  bufferptr = append_byte(bufferptr, 0x45);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_short(bufferptr, (64 - (2 * 6 + 2)));
  ;
  bufferptr = append_short(bufferptr, identifier);
  ;
  bufferptr = append_byte(bufferptr, 0x40);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_byte(bufferptr, 64);
  ;
  bufferptr = append_byte(bufferptr, 1);
  ;
  char *checksumstart = bufferptr;
  bufferptr = append_short(bufferptr, 0);
  ;
  bufferptr = append_bytes(bufferptr, local_ip, 4);
  ;
  bufferptr = append_bytes(bufferptr, dest_ip, 4);
  ;
  unsigned short checksum = in_cksum((short unsigned int *)start, 20);
  memcpy(checksumstart, &checksum, 2);
  return bufferptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_ipv4>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x45,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <append_byte@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  movzwl %bx,%esi
  mov    %rax,%rdi
  call   <append_short@plt>
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <append_byte@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <append_short@plt>
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <append_bytes@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <append_bytes@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <in_cksum@plt>
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  mov    %ax,0x6(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *write_ipv4(char *bufferptr, unsigned short identifier, unsigned char *local_ip, unsigned char *dest_ip) {
  char *start = bufferptr;
  bufferptr = append_byte(bufferptr, 0x45);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_short(bufferptr, (64 - (2 * 6 + 2)));
  ;
  bufferptr = append_short(bufferptr, identifier);
  ;
  bufferptr = append_byte(bufferptr, 0x40);
  ;
  bufferptr = append_byte(bufferptr, 0);
  ;
  bufferptr = append_byte(bufferptr, 64);
  ;
  bufferptr = append_byte(bufferptr, 1);
  ;
  char *checksumstart = bufferptr;
  bufferptr = append_short(bufferptr, 0);
  ;
  bufferptr = append_bytes(bufferptr, local_ip, 4);
  ;
  bufferptr = append_bytes(bufferptr, dest_ip, 4);
  ;
  unsigned short checksum = in_cksum((short unsigned int *)start, 20);
  memcpy(checksumstart, &checksum, 2);
  return bufferptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L55
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L55:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L10
L46:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  jne    L27
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0x10(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L46
  jmp    L39
L27:
  nop
L39:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_guessed: string

tool: D13: %d

assistant: ```c
int main() {
  int N, i;
  scanf("%d", &N);
  if (N == 1) {
    printf("%d", N + 1);
  }
  for (i = N; i <= N * N; i++) {
    if (check_prime(i)) {
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L27
L3:
  mov    0x4(%rsp),%ebx
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ebx
  jg     L35
L54:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  jne    L35
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  cmp    %ebx,%eax
  jge    L54
L35:
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L27:
  mov    $0x2,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  int N, i;
  scanf("%d", &N);
  if (N == 1) {
    printf("%d", N + 1);
  }
  for (i = N; i <= N * N; i++) {
    if (check_prime(i)) {
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cmp    $0x1,%ebp
  je     L68
L38:
  mov    %ebp,%eax
  imul   %ebp,%eax
  cmp    %eax,%ebp
  jle    L21
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L51:
  mov    0x4(%rsp),%eax
  add    $0x1,%ebp
  imul   %eax,%eax
  cmp    %ebp,%eax
  jl     L22
L21:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L51
L22:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L68:
  mov    $0x2,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ebp
  jmp    L38
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: %d

assistant: ```c
int main() {
  int N, i;
  scanf("%d", &N);
  if (N == 1) {
    printf("%d", N + 1);
  }
  for (i = N; i <= N * N; i++) {
    if (check_prime(i)) {
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cmp    $0x1,%ebp
  je     L3
L50:
  mov    %ebp,%eax
  imul   %ebp,%eax
  cmp    %eax,%ebp
  jle    L8
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rsp),%eax
  add    $0x1,%ebp
  imul   %eax,%eax
  cmp    %ebp,%eax
  jl     L53
L8:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L18
L53:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0x2,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ebp
  jmp    L50
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: %d

assistant: ```c
int main() {
  int N, i;
  scanf("%d", &N);
  if (N == 1) {
    printf("%d", N + 1);
  }
  for (i = N; i <= N * N; i++) {
    if (check_prime(i)) {
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cuddComputeFloorLog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L17:
  addl   $0x1,-0x4(%rbp)
  shrl   -0x14(%rbp)
L16:
  cmpl   $0x1,-0x14(%rbp)
  ja     L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cuddComputeFloorLog2(unsigned int value) {
  int floorLog = 0;
  while (value > 1) {
    floorLog++;
    value >>= 1;
  }
  return (floorLog);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cuddComputeFloorLog2>:
  endbr64
  cmp    $0x1,%edi
  jbe    L7
  mov    $0x0,%eax
L0:
  add    $0x1,%eax
  shr    %edi
  cmp    $0x1,%edi
  ja     L0
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int cuddComputeFloorLog2(unsigned int value) {
  int floorLog = 0;
  while (value > 1) {
    floorLog++;
    value >>= 1;
  }
  return (floorLog);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cuddComputeFloorLog2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jbe    L2
  nopl   0x0(%rax,%rax,1)
L1:
  shr    %edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jne    L1
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
int cuddComputeFloorLog2(unsigned int value) {
  int floorLog = 0;
  while (value > 1) {
    floorLog++;
    value >>= 1;
  }
  return (floorLog);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cuddComputeFloorLog2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jbe    L0
  nopl   0x0(%rax,%rax,1)
L15:
  shr    %edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jne    L15
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
int cuddComputeFloorLog2(unsigned int value) {
  int floorLog = 0;
  while (value > 1) {
    floorLog++;
    value >>= 1;
  }
  return (floorLog);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<difference_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void difference_vector(double *vector, double *minus_vector, double *result_vector, int size) {
  int i;
  for (i = 0; i < size; ++i)
    result_vector[i] = vector[i] - minus_vector[i];
}
```