ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x1(%rax),%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L42:
  mov    $0x1,%eax
  sub    %r12,%rax
  lea    (%rbx,%rax,8),%r15
  imul   %rbp,%r14
  lea    0x4(,%r14,4),%rdi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %rax,%rax
  je     L40
L12:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  shl    $0x2,%rax
  add    %rax,0x8(%rbx)
  cmp    %r12,%r13
  jle    L51
  shl    $0x2,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L45:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L45
L51:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  lea    D8(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L42
L40:
  lea    D0(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L12
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D0
datatype: string

tool: D8: Allocation error 1 in fmatrix()

tool: D0: Allocation error 2 in fmatrix()

assistant: ```c
float **fmatrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    zig_legacy_alloc_error("Allocation error 1 in fmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    zig_legacy_alloc_error("Allocation error 2 in fmatrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fmatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%rdi
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L45
L27:
  imul   %rbp,%r15
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%rbx)
  je     L49
L56:
  mov    $0x1,%edx
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r12
  jle    L35
  lea    0x0(,%rbp,4),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r12,8),%rsi
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L30
L35:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L45:
  lea    D13(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L27
  nopl   0x0(%rax)
L49:
  lea    D19(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  mov    0x8(%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L56
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D19
type: string

tool: D13: Allocation error 1 in fmatrix()

tool: D19: Allocation error 2 in fmatrix()

assistant: ```c
float **fmatrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    zig_legacy_alloc_error("Allocation error 1 in fmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    zig_legacy_alloc_error("Allocation error 2 in fmatrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fmatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rax,8),%rdi
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L37
L11:
  imul   %rbx,%r15
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    0x0(%r13,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%r13)
  je     L21
L0:
  mov    $0x1,%edx
  add    $0x1,%rbp
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rdx,0x8(%r13)
  cmp    %rbp,%r12
  jl     L20
  lea    0x0(,%rbx,4),%rcx
  lea    (%r8,%rbp,8),%rax
  lea    0x8(%r8,%r12,8),%rsi
L28:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L28
L20:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  lea    D0(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L11
  nopl   0x0(%rax)
L21:
  lea    D9(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  mov    0x8(%r13),%rax
  mov    0x8(%rsp),%r8
  jmp    L0
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string

tool: D0: Allocation error 1 in fmatrix()

tool: D9: Allocation error 2 in fmatrix()

assistant: ```c
float **fmatrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    zig_legacy_alloc_error("Allocation error 1 in fmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    zig_legacy_alloc_error("Allocation error 2 in fmatrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L17
L26:
  lea    -0x3f0(%rbp),%rdx
  mov    -0x3f4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: %d: %s

assistant: ```c
main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0)
    printf("%d: %s", len, line);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rbx
  jmp    L16
L21:
  mov    %rsp,%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
L16:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jg     L21
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d: %s

assistant: ```c
main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0)
    printf("%d: %s", len, line);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L11
  nopl   0x0(%rax)
L29:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
L11:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jg     L29
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: %d: %s

assistant: ```c
main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0)
    printf("%d: %s", len, line);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L0
  nopl   0x0(%rax)
L19:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
L0:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jg     L19
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: %d: %s

assistant: ```c
main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0)
    printf("%d: %s", len, line);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PyMPI_MSMPI_MPI_Add_error_class>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <MPI_Add_error_class@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L8
  mov    -0x10(%rbp),%eax
  jmp    L23
L8:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x9(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <MPI_Add_error_string@plt>
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int PyMPI_MSMPI_MPI_Add_error_class(int *errorclass) {
  int ierr;
  char errstr[1] = {0};
  ierr = MPI_Add_error_class(errorclass);
  if (ierr)
    return ierr;
  return MPI_Add_error_string(*errorclass, errstr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<PyMPI_MSMPI_MPI_Add_error_class>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <MPI_Add_error_class@plt>
  test   %eax,%eax
  je     L0
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  lea    0x7(%rsp),%rsi
  mov    (%rbx),%edi
  call   <MPI_Add_error_string@plt>
  jmp    L18
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int PyMPI_MSMPI_MPI_Add_error_class(int *errorclass) {
  int ierr;
  char errstr[1] = {0};
  ierr = MPI_Add_error_class(errorclass);
  if (ierr)
    return ierr;
  return MPI_Add_error_string(*errorclass, errstr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PyMPI_MSMPI_MPI_Add_error_class>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <MPI_Add_error_class@plt>
  test   %eax,%eax
  jne    L9
  mov    (%rbx),%edi
  lea    0x7(%rsp),%rsi
  call   <MPI_Add_error_string@plt>
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int PyMPI_MSMPI_MPI_Add_error_class(int *errorclass) {
  int ierr;
  char errstr[1] = {0};
  ierr = MPI_Add_error_class(errorclass);
  if (ierr)
    return ierr;
  return MPI_Add_error_string(*errorclass, errstr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PyMPI_MSMPI_MPI_Add_error_class>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <MPI_Add_error_class@plt>
  test   %eax,%eax
  jne    L8
  mov    (%rbx),%edi
  lea    0x7(%rsp),%rsi
  call   <MPI_Add_error_string@plt>
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int PyMPI_MSMPI_MPI_Add_error_class(int *errorclass) {
  int ierr;
  char errstr[1] = {0};
  ierr = MPI_Add_error_class(errorclass);
  if (ierr)
    return ierr;
  return MPI_Add_error_string(*errorclass, errstr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<score_game>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L34
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L2
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <score_roll@plt>
  lea    0xa(%rax),%rbx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <score_roll@plt>
  add    %rbx,%rax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L38
L2:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <score_roll@plt>
  add    $0xa,%rax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  addq   $0x2,-0x18(%rbp)
  jmp    L38
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <score_roll@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <score_roll@plt>
  add    %rbx,%rax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  addq   $0x2,-0x18(%rbp)
L38:
  addl   $0x1,-0x20(%rbp)
L34:
  cmpl   $0x9,-0x20(%rbp)
  jle    L53
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int score_game(char *game) {
  char *c = game;
  int frame = 0, score = 0;
  while (frame < 10) {
    if (*c == 'X') {
      score += 10 + score_roll(c + 1) + score_roll(c + 2);
      c++;
    } else if (*(c + 1) == '/') {
      score += 10 + score_roll(c + 2);
      c += 2;
    } else {
      score += score_roll(c) + score_roll(c + 1);
      c += 2;
    }
    frame++;
  }
  return score;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<score_game>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%r12d
  mov    $0x0,%r13d
  jmp    L4
L21:
  lea    0x1(%rbx),%r14
  mov    %r14,%rdi
  call   <score_roll@plt>
  mov    %rax,%rbp
  lea    0x2(%rbx),%rdi
  call   <score_roll@plt>
  lea    0xa(%rbp,%rax,1),%rax
  add    %eax,%r13d
  mov    %r14,%rbx
  jmp    L55
L10:
  add    $0x2,%rbx
  mov    %rbx,%rdi
  call   <score_roll@plt>
  lea    0xa(%r13,%rax,1),%r13d
L55:
  sub    $0x1,%r12d
  je     L54
L4:
  cmpb   $0x58,(%rbx)
  je     L21
  cmpb   $0x2f,0x1(%rbx)
  je     L10
  mov    %rbx,%rdi
  call   <score_roll@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx),%rdi
  call   <score_roll@plt>
  add    %rax,%rbp
  add    %ebp,%r13d
  add    $0x2,%rbx
  jmp    L55
L54:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int score_game(char *game) {
  char *c = game;
  int frame = 0, score = 0;
  while (frame < 10) {
    if (*c == 'X') {
      score += 10 + score_roll(c + 1) + score_roll(c + 2);
      c++;
    } else if (*(c + 1) == '/') {
      score += 10 + score_roll(c + 2);
      c += 2;
    } else {
      score += score_roll(c) + score_roll(c + 1);
      c += 2;
    }
    frame++;
  }
  return score;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<score_game>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    $0xa,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %rbx,%rdi
  call   <score_roll@plt>
  lea    0x1(%rbx),%rdi
  mov    %r13,%rbx
  mov    %rax,%rbp
  call   <score_roll@plt>
  add    %rax,%rbp
  add    %ebp,%r14d
L50:
  sub    $0x1,%r12d
  je     L35
L6:
  cmpb   $0x58,(%rbx)
  lea    0x2(%rbx),%r13
  je     L51
  cmpb   $0x2f,0x1(%rbx)
  jne    L37
  mov    %r13,%rdi
  mov    %r13,%rbx
  call   <score_roll@plt>
  lea    0xa(%r14,%rax,1),%r14d
  sub    $0x1,%r12d
  jne    L6
L35:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L51:
  add    $0x1,%rbx
  mov    %rbx,%rdi
  call   <score_roll@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <score_roll@plt>
  lea    0xa(%rbp,%rax,1),%rax
  add    %eax,%r14d
  jmp    L50
```

assistant: ```c
int score_game(char *game) {
  char *c = game;
  int frame = 0, score = 0;
  while (frame < 10) {
    if (*c == 'X') {
      score += 10 + score_roll(c + 1) + score_roll(c + 2);
      c++;
    } else if (*(c + 1) == '/') {
      score += 10 + score_roll(c + 2);
      c += 2;
    } else {
      score += score_roll(c) + score_roll(c + 1);
      c += 2;
    }
    frame++;
  }
  return score;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<score_game>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    $0xa,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %rbx,%rdi
  call   <score_roll@plt>
  lea    0x1(%rbx),%rdi
  mov    %r13,%rbx
  mov    %rax,%rbp
  call   <score_roll@plt>
  add    %rax,%rbp
  add    %ebp,%r14d
L10:
  sub    $0x1,%r12d
  je     L9
L55:
  cmpb   $0x58,(%rbx)
  lea    0x2(%rbx),%r13
  je     L26
  cmpb   $0x2f,0x1(%rbx)
  jne    L47
  mov    %r13,%rdi
  mov    %r13,%rbx
  call   <score_roll@plt>
  lea    0xa(%r14,%rax,1),%r14d
  sub    $0x1,%r12d
  jne    L55
L9:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L26:
  add    $0x1,%rbx
  mov    %rbx,%rdi
  call   <score_roll@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <score_roll@plt>
  lea    0xa(%rbp,%rax,1),%rax
  add    %eax,%r14d
  jmp    L10
```

assistant: ```c
int score_game(char *game) {
  char *c = game;
  int frame = 0, score = 0;
  while (frame < 10) {
    if (*c == 'X') {
      score += 10 + score_roll(c + 1) + score_roll(c + 2);
      c++;
    } else if (*(c + 1) == '/') {
      score += 10 + score_roll(c + 2);
      c += 2;
    } else {
      score += score_roll(c) + score_roll(c + 1);
      c += 2;
    }
    frame++;
  }
  return score;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L38
  mov    %esi,%r12d
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    $0x2,%eax
  jle    L157
  cmp    $0x1,%r12d
  je     L157
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  lea    -0x1(%r12),%r15d
  lea    (%r15,%r15,1),%edi
  mov    %edi,0xc(%rsp)
  cmp    %r12d,%ebx
  cmovle %ebx,%r12d
  test   %r12d,%r12d
  jle    L101
  mov    %r12d,%r12d
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  movslq %edi,%rdi
  mov    %rdi,(%rsp)
  mov    $0x1,%r11d
  mov    $0x0,%r14d
  jmp    L152
L157:
  mov    %rbp,%rdi
  call   <strdup@plt>
  jmp    L164
L22:
  cmp    %edx,%ebx
  jle    L118
  lea    0x1(%rcx),%edx
  movslq %edx,%rdx
  mov    %r9,%rsi
L147:
  mov    %edx,%ecx
  movzbl 0x0(%rbp,%rsi,1),%edi
  mov    %dil,-0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  add    (%rsp),%rsi
  cmp    %esi,%ebx
  jg     L147
L118:
  add    $0x1,%r9
  add    $0x2,%r10d
  cmp    %r12,%r9
  je     L119
L152:
  mov    %r9d,%esi
  mov    %r9d,%edx
  test   %r9d,%r9d
  je     L22
  cmp    %r9d,%r15d
  je     L22
  mov    %r10d,0x8(%rsp)
  mov    0xc(%rsp),%r13d
  sub    %r10d,%r13d
  cmp    %r9d,%ebx
  jle    L118
  lea    0x1(%rcx),%edx
  movslq %edx,%rdx
  mov    %r11d,%edi
  jmp    L114
L78:
  add    0x8(%rsp),%esi
  mov    %r11d,%edi
L128:
  add    $0x1,%rdx
  cmp    %esi,%ebx
  jle    L118
L114:
  mov    %edx,%ecx
  movslq %esi,%r8
  movzbl 0x0(%rbp,%r8,1),%r8d
  mov    %r8b,-0x1(%rax,%rdx,1)
  test   %edi,%edi
  je     L78
  add    %r13d,%esi
  mov    %r14d,%edi
  jmp    L128
L101:
  mov    $0x0,%ecx
L119:
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
L164:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  mov    %rdi,%rax
  jmp    L164
```

assistant: ```c
char *convert(char *s, int numRows) {
  if (!s)
    return (0);
  char *res;
  int i, j, l, step1, step2, flag, p, k;
  l = strlen(s);
  if (l <= 2 || numRows == 1)
    return (strdup(s));
  res = malloc(l + 1);
  k = 2 * numRows - 2;
  p = 0;
  for (i = 0; i < numRows && i < l; i++) {
    if (i == 0 || i == (numRows - 1)) {
      for (j = i; j < l; j += k)
        res[p++] = s[j];
      continue;
    }
    step1 = k - i * 2;
    step2 = k - step1;
    flag = 1;
    for (j = i; j < l;) {
      res[p++] = s[j];
      if (flag) {
        flag = 0;
        j += step1;
      } else {
        flag = 1;
        j += step2;
      }
    }
  }
  res[p] = 0;
  return (res);
}
```