ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getopt_long>:
  endbr64
  mov    $0x1,%r9d
  xor    %eax,%eax
  jmp    1050 <getopt_internal@plt>
```

assistant: ```c
int getopt_long(nargc, nargv, options, long_options, idx)
int nargc;
char *const *nargv;
const char *options;
const struct option *long_options;
int *idx;
{ return (getopt_internal(nargc, nargv, options, long_options, idx, 0x01)); }
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getopt_long>:
  endbr64
  mov    $0x1,%r9d
  xor    %eax,%eax
  jmp    1050 <getopt_internal@plt>
```

assistant: ```c
int getopt_long(nargc, nargv, options, long_options, idx)
int nargc;
char *const *nargv;
const char *options;
const struct option *long_options;
int *idx;
{ return (getopt_internal(nargc, nargv, options, long_options, idx, 0x01)); }
```
user: Translate the below assembly code into C programming language:

```asm
<write_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x24(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0xffffffff,-0x38(%rbp)
  je     L25
  lea    -0x20(%rbp),%rdx
  jmp    L1
L25:
  mov    $0x0,%edx
L1:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x24(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <select@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int write_wait(int fd, int msec) {
  struct timeval tv;
  fd_set wfds;
  FD_ZERO(&wfds);
  FD_SET(fd, &wfds);
  tv.tv_sec = 0;
  tv.tv_usec = msec;
  return select(fd + 1, NULL, &wfds, NULL, (msec != -1) ? &tv : NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_wait>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  movq   $0x0,0x18(%rsp)
  mov    %ebp,0x10(%rsp)
  lea    0x10(%rsp),%r8
  cmp    $0xffffffff,%ebp
  mov    $0x0,%eax
  cmove  %rax,%r8
  mov    %r12,%rdx
  lea    0x1(%rbx),%edi
  mov    $0x0,%ecx
  mov    $0x0,%esi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_wait(int fd, int msec) {
  struct timeval tv;
  fd_set wfds;
  FD_ZERO(&wfds);
  FD_SET(fd, &wfds);
  tv.tv_sec = 0;
  tv.tv_usec = msec;
  return select(fd + 1, NULL, &wfds, NULL, (msec != -1) ? &tv : NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_wait>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%r8
  cmp    $0xffffffff,%ebp
  cmove  %rax,%r8
  mov    %r12,%rdx
  xor    %ecx,%ecx
  xor    %esi,%esi
  lea    0x1(%rbx),%edi
  mov    %ebp,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_wait(int fd, int msec) {
  struct timeval tv;
  fd_set wfds;
  FD_ZERO(&wfds);
  FD_SET(fd, &wfds);
  tv.tv_sec = 0;
  tv.tv_usec = msec;
  return select(fd + 1, NULL, &wfds, NULL, (msec != -1) ? &tv : NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_wait>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%r8
  cmp    $0xffffffff,%ebp
  cmove  %rax,%r8
  mov    %r12,%rdx
  xor    %ecx,%ecx
  xor    %esi,%esi
  lea    0x1(%rbx),%edi
  mov    %ebp,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_wait(int fd, int msec) {
  struct timeval tv;
  fd_set wfds;
  FD_ZERO(&wfds);
  FD_SET(fd, &wfds);
  tv.tv_sec = 0;
  tv.tv_usec = msec;
  return select(fd + 1, NULL, &wfds, NULL, (msec != -1) ? &tv : NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L5
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <ft_putbase@plt>
  jmp    L13
L5:
  mov    -0x4(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <ft_putbase@plt>
L13:
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbr(int n) {
  if (n < 0) {
    ft_putchar('-');
    ft_putbase(-n, 10);
  } else
    ft_putbase(n, 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putnbr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L4
  mov    $0xa,%esi
  call   <ft_putbase@plt>
L14:
  pop    %rbx
  ret
L4:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  neg    %ebx
  mov    %ebx,%edi
  mov    $0xa,%esi
  call   <ft_putbase@plt>
  jmp    L14
```

assistant: ```c
void ft_putnbr(int n) {
  if (n < 0) {
    ft_putchar('-');
    ft_putbase(-n, 10);
  } else
    ft_putbase(n, 10);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  test   %edi,%edi
  js     L3
  mov    $0xa,%esi
  pop    %rbp
  jmp    1060 <ft_putbase@plt>
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  pop    %rbp
  neg    %edi
  jmp    1060 <ft_putbase@plt>
```

assistant: ```c
void ft_putnbr(int n) {
  if (n < 0) {
    ft_putchar('-');
    ft_putbase(-n, 10);
  } else
    ft_putbase(n, 10);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  test   %edi,%edi
  js     L9
  mov    $0xa,%esi
  pop    %rbp
  jmp    1060 <ft_putbase@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  pop    %rbp
  neg    %edi
  jmp    1060 <ft_putbase@plt>
```

assistant: ```c
void ft_putnbr(int n) {
  if (n < 0) {
    ft_putchar('-');
    ft_putbase(-n, 10);
  } else
    ft_putbase(n, 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ROL64_57>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  rol    $0x39,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ROL64_57(uint64_t x) {
  __asm__("rolq $57, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ROL64_57>:
  endbr64
  mov    %rdi,%rax
  rol    $0x39,%rax
  ret
```

assistant: ```c
uint64_t ROL64_57(uint64_t x) {
  __asm__("rolq $57, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ROL64_57>:
  endbr64
  mov    %rdi,%rax
  rol    $0x39,%rax
  ret
```

assistant: ```c
uint64_t ROL64_57(uint64_t x) {
  __asm__("rolq $57, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ROL64_57>:
  endbr64
  mov    %rdi,%rax
  rol    $0x39,%rax
  ret
```

assistant: ```c
uint64_t ROL64_57(uint64_t x) {
  __asm__("rolq $57, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<Xorriso__to_upper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L41
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L25
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  jmp    L22
L25:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L22:
  addl   $0x1,-0x14(%rbp)
L41:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L49
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L49:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Xorriso__to_upper(char *in, char *out, int out_size, int flag) {
  int i;
  for (i = 0; i < out_size - 1 && in[i] != 0; i++)
    if (isalpha(in[i]))
      out[i] = toupper(in[i]);
    else
      out[i] = in[i];
  out[i] = 0;
  return (in[i] == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Xorriso__to_upper>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  cmp    $0x1,%edx
  jle    L59
  lea    -0x2(%rdx),%r14d
  mov    $0x0,%ebx
  jmp    L22
L32:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%r13,%rbx,1)
L23:
  lea    0x1(%r12),%eax
  lea    0x1(%rbx),%rdx
  cmp    %r14,%rbx
  je     L51
  mov    %rdx,%rbx
L22:
  mov    %ebx,%r12d
  mov    %ebx,%eax
  movzbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L51
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L32
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,0x0(%r13,%rbx,1)
  jmp    L23
L59:
  mov    $0x0,%eax
L51:
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  cmpb   $0x0,0x0(%rbp,%rax,1)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int Xorriso__to_upper(char *in, char *out, int out_size, int flag) {
  int i;
  for (i = 0; i < out_size - 1 && in[i] != 0; i++)
    if (isalpha(in[i]))
      out[i] = toupper(in[i]);
    else
      out[i] = in[i];
  out[i] = 0;
  return (in[i] == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Xorriso__to_upper>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edx
  jle    L69
  lea    -0x2(%rdx),%eax
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x1,%r13d
  lea    0x1(%rsi,%rax,1),%r14
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L58:
  movzbl 0x0(%rbp),%eax
L36:
  mov    %al,(%rbx)
  mov    %r13d,%eax
  add    $0x1,%rbp
  sub    %r12d,%eax
  add    %ebx,%eax
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L49
L33:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%rax
  mov    %rbx,%rdx
  test   %dil,%dil
  je     L68
  call   <isalpha@plt>
  test   %rax,%rax
  je     L58
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  jmp    L36
  nop
L49:
  cltq
  lea    (%r12,%rax,1),%rdx
  add    %r15,%rax
L68:
  movb   $0x0,(%rdx)
  cmpb   $0x0,(%rax)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  mov    %rdi,%rax
  mov    %rsi,%rdx
  jmp    L68
```

assistant: ```c
int Xorriso__to_upper(char *in, char *out, int out_size, int flag) {
  int i;
  for (i = 0; i < out_size - 1 && in[i] != 0; i++)
    if (isalpha(in[i]))
      out[i] = toupper(in[i]);
    else
      out[i] = in[i];
  out[i] = 0;
  return (in[i] == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Xorriso__to_upper>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edx
  jle    L53
  lea    -0x2(%rdx),%eax
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x1,%r13d
  lea    0x1(%rsi,%rax,1),%r14
  nopl   (%rax)
L20:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%rax
  mov    %rbx,%rdx
  test   %dil,%dil
  je     L31
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L59
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbp
  mov    %al,(%rbx)
  mov    %r13d,%eax
  sub    %r12d,%eax
  add    %ebx,%eax
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L20
  cltq
  lea    (%r12,%rax,1),%rdx
  add    %r15,%rax
L31:
  movb   $0x0,(%rdx)
  cmpb   $0x0,(%rax)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  call   <toupper@plt>
  mov    %al,(%rbx)
  mov    %r13d,%eax
  sub    %r12d,%eax
  add    %ebx,%eax
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L20
  cltq
  lea    (%r12,%rax,1),%rdx
  add    %r15,%rax
  jmp    L31
L53:
  mov    %rdi,%rax
  mov    %rsi,%rdx
  jmp    L31
```

assistant: ```c
int Xorriso__to_upper(char *in, char *out, int out_size, int flag) {
  int i;
  for (i = 0; i < out_size - 1 && in[i] != 0; i++)
    if (isalpha(in[i]))
      out[i] = toupper(in[i]);
    else
      out[i] = in[i];
  out[i] = 0;
  return (in[i] == 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<wordcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L9
  mov    $0xffffffff,%eax
  jmp    L32
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L34
  mov    $0x1,%eax
  jmp    L32
L34:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
L32:
  leave
  ret
```

assistant: ```c
int wordcmp(const char *s1, const char *s2, const char *delim) {
  int n1 = strcspn(s1, delim);
  int n2 = strcspn(s2, delim);
  if (n1 < n2)
    return -1;
  else if (n1 > n2)
    return 1;
  return strncmp(s1, s2, n1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wordcmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <strcspn@plt>
  mov    %eax,%ebx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcspn@plt>
  cmp    %eax,%ebx
  jl     L26
  mov    $0x1,%edx
  jle    L23
L31:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %eax,%edx
  jmp    L31
L26:
  mov    $0xffffffff,%edx
  jmp    L31
```

assistant: ```c
int wordcmp(const char *s1, const char *s2, const char *delim) {
  int n1 = strcspn(s1, delim);
  int n2 = strcspn(s2, delim);
  if (n1 < n2)
    return -1;
  else if (n1 > n2)
    return 1;
  return strncmp(s1, s2, n1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wordcmp>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <strcspn@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <strcspn@plt>
  cmp    %eax,%r14d
  jl     L0
  mov    $0x1,%eax
  jle    L20
L27:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  add    $0x8,%rsp
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <strncmp@plt>
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  jmp    L27
```

assistant: ```c
int wordcmp(const char *s1, const char *s2, const char *delim) {
  int n1 = strcspn(s1, delim);
  int n2 = strcspn(s2, delim);
  if (n1 < n2)
    return -1;
  else if (n1 > n2)
    return 1;
  return strncmp(s1, s2, n1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wordcmp>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <strcspn@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <strcspn@plt>
  cmp    %eax,%r14d
  jl     L15
  mov    $0x1,%eax
  jle    L17
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <strncmp@plt>
  nopl   0x0(%rax)
L15:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int wordcmp(const char *s1, const char *s2, const char *delim) {
  int n1 = strcspn(s1, delim);
  int n2 = strcspn(s2, delim);
  if (n1 < n2)
    return -1;
  else if (n1 > n2)
    return 1;
  return strncmp(s1, s2, n1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mdbm_log_at>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %edx,-0xd0(%rbp)
  mov    %rcx,-0xd8(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edi
  mov    -0xd8(%rbp),%rcx
  mov    -0xd0(%rbp),%edx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <mdbm_log_vlog_at@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mdbm_log_at(const char *file, int line, int level, const char *format, ...) {
  int ret;
  va_list args;
  va_start(args, format);
  ret = mdbm_log_vlog_at(file, line, level, format, args);
  va_end(args);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mdbm_log_at>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %rcx,%rbx
  mov    %rcx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <mdbm_log_vlog_at@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mdbm_log_at(const char *file, int line, int level, const char *format, ...) {
  int ret;
  va_list args;
  va_start(args, format);
  ret = mdbm_log_vlog_at(file, line, level, format, args);
  va_end(args);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mdbm_log_at>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  mov    %rcx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mdbm_log_vlog_at@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int mdbm_log_at(const char *file, int line, int level, const char *format, ...) {
  int ret;
  va_list args;
  va_start(args, format);
  ret = mdbm_log_vlog_at(file, line, level, format, args);
  va_end(args);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mdbm_log_at>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  mov    %rcx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mdbm_log_vlog_at@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int mdbm_log_at(const char *file, int line, int level, const char *format, ...) {
  int ret;
  va_list args;
  va_start(args, format);
  ret = mdbm_log_vlog_at(file, line, level, format, args);
  va_end(args);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filtersvr_qsort_cmp2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L0
  mov    $0x0,%eax
  jmp    L29
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L8
  mov    $0x1,%eax
  jmp    L29
L8:
  mov    $0xffffffff,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int filtersvr_qsort_cmp2(const void *p1, const void *p2) {
  int v1 = *(int *)p1;
  int v2 = *(int *)p2;
  if (v1 == v2) {
    return (0);
  }
  return ((v1 < v2) ? 1 : -1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filtersvr_qsort_cmp2>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x0,%eax
  cmp    %edx,%ecx
  je     L0
  setl   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L0:
  ret
```

assistant: ```c
int filtersvr_qsort_cmp2(const void *p1, const void *p2) {
  int v1 = *(int *)p1;
  int v2 = *(int *)p2;
  if (v1 == v2) {
    return (0);
  }
  return ((v1 < v2) ? 1 : -1);
}
```
user: What is the c source code of the assembly code below?

```asm
<filtersvr_qsort_cmp2>:
  endbr64
  mov    (%rsi),%edx
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  je     L1
  setl   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L1:
  ret
```

assistant: ```c
int filtersvr_qsort_cmp2(const void *p1, const void *p2) {
  int v1 = *(int *)p1;
  int v2 = *(int *)p2;
  if (v1 == v2) {
    return (0);
  }
  return ((v1 < v2) ? 1 : -1);
}
```
user: What is the c source code of the assembly code below?

```asm
<filtersvr_qsort_cmp2>:
  endbr64
  mov    (%rsi),%edx
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  je     L2
  setl   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L2:
  ret
```

assistant: ```c
int filtersvr_qsort_cmp2(const void *p1, const void *p2) {
  int v1 = *(int *)p1;
  int v2 = *(int *)p2;
  if (v1 == v2) {
    return (0);
  }
  return ((v1 < v2) ? 1 : -1);
}
```