ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  mov    $0x64,%ebx
  sub    $0x20,%rsp
  movl   $0x0,0x1c(%rsp)
  nopw   0x0(%rax,%rax,1)
L9:
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <sqrtfcn@plt>
  pxor   %xmm0,%xmm0
  movss  0x1c(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  D10(%rip),%xmm1
  addss  %xmm2,%xmm0
  movss  %xmm0,0x1c(%rsp)
  sub    $0x1,%ebx
  jne    L9
  movss  0x1c(%rsp),%xmm0
  mulss  D9(%rip),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: f32
name: unpack_data
arguments: data_label: D9
data_type: byte[4]

tool: D10: 100

tool: {"D9": [0x00,0x50,0xc3,0x47]}

assistant: ```c
int benchmark() {
  float i = 0.0;
  volatile float accum = 0.0;
  for (i = 0.0; i < 10000.; i += 100.)
    accum += sqrtfcn(i);
  return (int)(accum * 100000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_aes_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L22
L14:
  mov    -0x34(%rbp),%eax
  mov    -0x60(%rbp),%rdx
  shr    $0x4,%rdx
  cmp    %rdx,%rax
  jne    L59
  mov    -0x60(%rbp),%rax
  and    $0xf,%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L36
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L32
L59:
  movl   $0x10,-0x2c(%rbp)
L32:
  mov    -0x34(%rbp),%eax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <decrypt@plt>
  cmpl   $0x0,-0x34(%rbp)
  jne    L53
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L27
L53:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
L27:
  movl   $0x0,-0x30(%rbp)
  jmp    L54
L102:
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x30(%rbp),%eax
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  shl    $0x4,%rax
  mov    %rax,%rsi
  mov    -0x30(%rbp),%eax
  add    %rax,%rsi
  mov    -0x58(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x30(%rbp)
L54:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L102
  addl   $0x1,-0x34(%rbp)
L22:
  mov    -0x34(%rbp),%eax
  mov    -0x60(%rbp),%rdx
  shr    $0x4,%rdx
  cmp    %rdx,%rax
  jbe    L14
  jmp    L13
L36:
  nop
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void my_aes_decrypt(unsigned char *iv, unsigned char *inbuf, unsigned char *outbuf, unsigned long long len) {
  unsigned char block[16];
  unsigned int blockno = 0, i;
  for (blockno = 0; blockno <= (len / sizeof(block)); blockno++) {
    unsigned int fraction;
    if (blockno == (len / sizeof(block))) {
      fraction = len % sizeof(block);
      if (fraction == 0)
        break;
      memset(block, 0, sizeof(block));
    } else
      fraction = 16;
    memcpy(block, inbuf + blockno * sizeof(block), fraction);
    decrypt((char *)block);
    unsigned char *ctext_ptr;
    if (blockno == 0)
      ctext_ptr = iv;
    else
      ctext_ptr = inbuf + (blockno - 1) * sizeof(block);
    for (i = 0; i < fraction; i++)
      outbuf[blockno * sizeof(block) + i] = ctext_ptr[i] ^ block[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_aes_decrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rcx,%r14
  shr    $0x4,%r14
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  mov    $0x10,%r15d
  jmp    L64
L97:
  mov    0x18(%rsp),%rcx
L10:
  mov    $0x0,%eax
  add    0x8(%rsp),%rbx
  lea    0x20(%rsp),%rsi
L40:
  movzbl (%rcx,%rax,1),%edx
  xor    (%rax,%rsi,1),%dl
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebp
  ja     L40
L48:
  add    $0x1,%r12d
  mov    %r12d,%ebx
  cmp    %r14,%rbx
  ja     L55
L64:
  cmp    %rbx,%r14
  jne    L35
  mov    0x10(%rsp),%ebp
  and    $0xf,%ebp
  je     L55
  lea    0x20(%rsp),%rdi
  mov    %r15d,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  jmp    L53
L35:
  mov    %r15d,%ebp
L53:
  shl    $0x4,%rbx
  mov    (%rsp),%rax
  lea    (%rax,%rbx,1),%rsi
  lea    0x20(%rsp),%r13
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <decrypt@plt>
  test   %r12d,%r12d
  je     L97
  lea    -0x1(%r12),%ecx
  shl    $0x4,%rcx
  add    (%rsp),%rcx
  test   %ebp,%ebp
  jne    L10
  jmp    L48
L55:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_aes_decrypt(unsigned char *iv, unsigned char *inbuf, unsigned char *outbuf, unsigned long long len) {
  unsigned char block[16];
  unsigned int blockno = 0, i;
  for (blockno = 0; blockno <= (len / sizeof(block)); blockno++) {
    unsigned int fraction;
    if (blockno == (len / sizeof(block))) {
      fraction = len % sizeof(block);
      if (fraction == 0)
        break;
      memset(block, 0, sizeof(block));
    } else
      fraction = 16;
    memcpy(block, inbuf + blockno * sizeof(block), fraction);
    decrypt((char *)block);
    unsigned char *ctext_ptr;
    if (blockno == 0)
      ctext_ptr = iv;
    else
      ctext_ptr = inbuf + (blockno - 1) * sizeof(block);
    for (i = 0; i < fraction; i++)
      outbuf[blockno * sizeof(block) + i] = ctext_ptr[i] ^ block[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_aes_decrypt>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  shr    $0x4,%rbx
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  cmp    %rbx,%r12
  jne    L66
  mov    0x18(%rsp),%r15d
  and    $0xf,%r15d
  je     L21
  lea    0x20(%rsp),%r13
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
L51:
  shl    $0x4,%r12
  mov    %r15d,%edx
  mov    %r13,%rdi
  lea    0x0(%rbp,%r12,1),%rsi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <decrypt@plt>
  mov    0x8(%rsp),%rsi
  test   %r14d,%r14d
  je     L47
  lea    -0x1(%r14),%esi
  shl    $0x4,%rsi
  add    %rbp,%rsi
L47:
  mov    0x10(%rsp),%rdi
  mov    %r15d,%ecx
  xor    %eax,%eax
  lea    (%rdi,%r12,1),%r9
  nop
L61:
  movzbl (%rsi,%rax,1),%edx
  xor    0x0(%r13,%rax,1),%dl
  mov    %dl,(%r9,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L61
  lea    0x1(%r14),%r12d
  mov    %r12,%r14
  cmp    %rbx,%r12
  jbe    L3
L21:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L66:
  mov    $0x10,%r15d
  lea    0x20(%rsp),%r13
  jmp    L51
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_aes_decrypt(unsigned char *iv, unsigned char *inbuf, unsigned char *outbuf, unsigned long long len) {
  unsigned char block[16];
  unsigned int blockno = 0, i;
  for (blockno = 0; blockno <= (len / sizeof(block)); blockno++) {
    unsigned int fraction;
    if (blockno == (len / sizeof(block))) {
      fraction = len % sizeof(block);
      if (fraction == 0)
        break;
      memset(block, 0, sizeof(block));
    } else
      fraction = 16;
    memcpy(block, inbuf + blockno * sizeof(block), fraction);
    decrypt((char *)block);
    unsigned char *ctext_ptr;
    if (blockno == 0)
      ctext_ptr = iv;
    else
      ctext_ptr = inbuf + (blockno - 1) * sizeof(block);
    for (i = 0; i < fraction; i++)
      outbuf[blockno * sizeof(block) + i] = ctext_ptr[i] ^ block[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<place_and_route>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <read_place@plt>
  mov    $0x0,%eax
  call   <alloc_and_load_placement_structs@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void place_and_route() {
  read_place();
  alloc_and_load_placement_structs();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<place_and_route>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <read_place@plt>
  mov    $0x0,%eax
  call   <alloc_and_load_placement_structs@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void place_and_route() {
  read_place();
  alloc_and_load_placement_structs();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<place_and_route>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read_place@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <alloc_and_load_placement_structs@plt>
```

assistant: ```c
void place_and_route() {
  read_place();
  alloc_and_load_placement_structs();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<place_and_route>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read_place@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <alloc_and_load_placement_structs@plt>
```

assistant: ```c
void place_and_route() {
  read_place();
  alloc_and_load_placement_structs();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clk_prepare_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <clk_prepare@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  mov    -0x4(%rbp),%eax
  jmp    L28
L22:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <clk_enable@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <clk_unprepare@plt>
L16:
  mov    -0x4(%rbp),%eax
L28:
  leave
  ret
```

assistant: ```c
int clk_prepare_enable(struct clk *clk) {
  int ret;
  ret = clk_prepare(clk);
  if (ret)
    return ret;
  ret = clk_enable(clk);
  if (ret)
    clk_unprepare(clk);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clk_prepare_enable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <clk_prepare@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L0
L20:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rdi
  call   <clk_enable@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L20
  mov    %rbp,%rdi
  call   <clk_unprepare@plt>
  jmp    L20
```

assistant: ```c
int clk_prepare_enable(struct clk *clk) {
  int ret;
  ret = clk_prepare(clk);
  if (ret)
    return ret;
  ret = clk_enable(clk);
  if (ret)
    clk_unprepare(clk);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clk_prepare_enable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <clk_prepare@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L1
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    %rbp,%rdi
  call   <clk_enable@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L5
  mov    %rbp,%rdi
  call   <clk_unprepare@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int clk_prepare_enable(struct clk *clk) {
  int ret;
  ret = clk_prepare(clk);
  if (ret)
    return ret;
  ret = clk_enable(clk);
  if (ret)
    clk_unprepare(clk);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clk_prepare_enable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <clk_prepare@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L9
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L9:
  mov    %rbp,%rdi
  call   <clk_enable@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L6
  mov    %rbp,%rdi
  call   <clk_unprepare@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int clk_prepare_enable(struct clk *clk) {
  int ret;
  ret = clk_prepare(clk);
  if (ret)
    return ret;
  ret = clk_enable(clk);
  if (ret)
    clk_unprepare(clk);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<adts_set_cp_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  and    $0xfffffff3,%edx
  mov    %edx,(%rax)
  cmpl   $0x0,-0xc(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  or     $0x8,%edx
  mov    %edx,(%rax)
L7:
  cmpl   $0x0,-0x10(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  or     $0x4,%edx
  mov    %edx,(%rax)
L10:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void adts_set_cp_id(uint8_t *p_adts, bool b_bit, bool b_start) {
  p_adts[3] &= ~0x0c;
  if (b_bit)
    p_adts[3] |= 0x08;
  if (b_start)
    p_adts[3] |= 0x04;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<adts_set_cp_id>:
  endbr64
  mov    0xc(%rdi),%eax
  and    $0xfffffff3,%eax
  mov    %eax,%ecx
  or     $0x8,%ecx
  test   %esi,%esi
  cmovne %ecx,%eax
  mov    %eax,0xc(%rdi)
  test   %edx,%edx
  je     L6
  orl    $0x4,0xc(%rdi)
L6:
  ret
```

assistant: ```c
void adts_set_cp_id(uint8_t *p_adts, bool b_bit, bool b_start) {
  p_adts[3] &= ~0x0c;
  if (b_bit)
    p_adts[3] |= 0x08;
  if (b_start)
    p_adts[3] |= 0x04;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adts_set_cp_id>:
  endbr64
  mov    0xc(%rdi),%eax
  and    $0xfffffff3,%eax
  mov    %eax,%ecx
  or     $0x8,%ecx
  test   %esi,%esi
  cmovne %ecx,%eax
  mov    %eax,0xc(%rdi)
  test   %edx,%edx
  je     L1
  orl    $0x4,0xc(%rdi)
L1:
  ret
```

assistant: ```c
void adts_set_cp_id(uint8_t *p_adts, bool b_bit, bool b_start) {
  p_adts[3] &= ~0x0c;
  if (b_bit)
    p_adts[3] |= 0x08;
  if (b_start)
    p_adts[3] |= 0x04;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<adts_set_cp_id>:
  endbr64
  mov    0xc(%rdi),%eax
  and    $0xfffffff3,%eax
  test   %esi,%esi
  je     L18
  or     $0x8,%eax
L18:
  mov    %eax,0xc(%rdi)
  test   %edx,%edx
  je     L10
  or     $0x4,%eax
  mov    %eax,0xc(%rdi)
L10:
  ret
```

assistant: ```c
void adts_set_cp_id(uint8_t *p_adts, bool b_bit, bool b_start) {
  p_adts[3] &= ~0x0c;
  if (b_bit)
    p_adts[3] |= 0x08;
  if (b_start)
    p_adts[3] |= 0x04;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unsign8b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0xffffff80,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unsign8b(unsigned char *data, int size) {
  int i;
  for (i = 0; i < size; i++)
    data[i] += 0x80;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unsign8b>:
  endbr64
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L18:
  addb   $0x80,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L1:
  ret
```

assistant: ```c
void unsign8b(unsigned char *data, int size) {
  int i;
  for (i = 0; i < size; i++)
    data[i] += 0x80;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unsign8b>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
L15:
  addb   $0x80,(%rdi)
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L15
L16:
  ret
```

assistant: ```c
void unsign8b(unsigned char *data, int size) {
  int i;
  for (i = 0; i < size; i++)
    data[i] += 0x80;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unsign8b>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L31
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  jbe    L64
  shr    $0x4,%esi
  movdqa D4(%rip),%xmm1
  mov    %rdi,%rax
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopw   0x0(%rax,%rax,1)
L121:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddb  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L121
  mov    %ecx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%esi
  cmp    %eax,%ecx
  je     L105
L91:
  mov    %ecx,%edi
  sub    %eax,%edi
  lea    -0x1(%rdi),%r8d
  cmp    $0x6,%r8d
  jbe    L98
  movq   D4(%rip),%xmm1
  add    %rdx,%rax
  movq   (%rax),%xmm0
  paddb  %xmm1,%xmm0
  movq   %xmm0,(%rax)
  mov    %edi,%eax
  and    $0xfffffff8,%eax
  add    %eax,%esi
  cmp    %eax,%edi
  je     L31
L98:
  movslq %esi,%rax
  addb   $0x80,(%rdx,%rax,1)
  lea    0x1(%rsi),%eax
  cmp    %eax,%ecx
  jle    L31
  cltq
  addb   $0x80,(%rdx,%rax,1)
  lea    0x2(%rsi),%eax
  cmp    %eax,%ecx
  jle    L31
  cltq
  addb   $0x80,(%rdx,%rax,1)
  lea    0x3(%rsi),%eax
  cmp    %eax,%ecx
  jle    L31
  cltq
  addb   $0x80,(%rdx,%rax,1)
  lea    0x4(%rsi),%eax
  cmp    %eax,%ecx
  jle    L31
  cltq
  addb   $0x80,(%rdx,%rax,1)
  lea    0x5(%rsi),%eax
  cmp    %eax,%ecx
  jle    L31
  cltq
  add    $0x6,%esi
  addb   $0x80,(%rdx,%rax,1)
  cmp    %esi,%ecx
  jle    L31
  movslq %esi,%rsi
  addb   $0x80,(%rdx,%rsi,1)
L31:
  ret
L64:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L91
L105:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: byte[16]

tool: {"D4": [0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80]}

assistant: ```c
void unsign8b(unsigned char *data, int size) {
  int i;
  for (i = 0; i < size; i++)
    data[i] += 0x80;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sum_tab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L2
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double sum_tab(tab, max)
int tab[];
int max;
{
  double res;
  int i;
  for (i = 0, res = 0.0; i < max; res = res + (double)(tab[i]), i++)
    ;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum_tab>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L14:
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rax),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L14
  ret
L4:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double sum_tab(tab, max)
int tab[];
int max;
{
  double res;
  int i;
  for (i = 0, res = 0.0; i < max; res = res + (double)(tab[i]), i++)
    ;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum_tab>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L0:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtsi2sdl -0x4(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L0
  ret
  nop
L7:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double sum_tab(tab, max)
int tab[];
int max;
{
  double res;
  int i;
  for (i = 0, res = 0.0; i < max; res = res + (double)(tab[i]), i++)
    ;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_tab>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L14:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtsi2sdl -0x4(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L14
  ret
  nop
L17:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double sum_tab(tab, max)
int tab[];
int max;
{
  double res;
  int i;
  for (i = 0, res = 0.0; i < max; res = res + (double)(tab[i]), i++)
    ;
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <create_counter@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <inc@plt>
  mov    $0x0,%eax
  call   <create_counter@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <inc@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <inc@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <counter_get@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <dispose@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <dispose@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct counter *c1 = create_counter();
  inc(c1);
  struct counter *c2 = create_counter();
  inc(c2);
  inc(c2);
  swap(c1, c2);
  int tmp = counter_get(c1);
  dispose(c1);
  dispose(c2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <create_counter@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <inc@plt>
  mov    $0x0,%eax
  call   <create_counter@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <inc@plt>
  mov    %rbx,%rdi
  call   <inc@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %rbp,%rdi
  call   <counter_get@plt>
  mov    %rbp,%rdi
  call   <dispose@plt>
  mov    %rbx,%rdi
  call   <dispose@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct counter *c1 = create_counter();
  inc(c1);
  struct counter *c2 = create_counter();
  inc(c2);
  inc(c2);
  swap(c1, c2);
  int tmp = counter_get(c1);
  dispose(c1);
  dispose(c2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <create_counter@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <inc@plt>
  xor    %eax,%eax
  call   <create_counter@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <inc@plt>
  mov    %rbp,%rdi
  call   <inc@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %r12,%rdi
  call   <counter_get@plt>
  mov    %r12,%rdi
  call   <dispose@plt>
  mov    %rbp,%rdi
  call   <dispose@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  struct counter *c1 = create_counter();
  inc(c1);
  struct counter *c2 = create_counter();
  inc(c2);
  inc(c2);
  swap(c1, c2);
  int tmp = counter_get(c1);
  dispose(c1);
  dispose(c2);
  return 0;
}
```