ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hputnr8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movq   %xmm0,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  js     L9
  lea    0x8(%rsp),%r13
  lea    D12(%rip),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x10(%rsp),%rdi
  movq   %r12,%xmm0
  mov    %r13,%rsi
  mov    $0x1,%eax
  call   <sprintf@plt>
L58:
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fixnegzero@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <hputc@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  neg    %edx
  lea    0x8(%rsp),%r14
  lea    D3(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  lea    0x10(%rsp),%r13
  movq   %r12,%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L58
  mov    %r13,%rdx
  lea    -0x1(%rax),%eax
  lea    0x11(%rsp,%rax,1),%rax
  jmp    L16
L1:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L58
L16:
  cmpb   $0x65,(%rdx)
  jne    L1
  movb   $0x45,(%rdx)
  jmp    L1
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D3
type: string

tool: D12: %%.%df

tool: D3: %%.%dg

assistant: ```c
int hputnr8(hstring, keyword, ndec, dval)
char *hstring;
const char *keyword;
const int ndec;
const double dval;
{
  char value[30];
  char format[8];
  int i, lval;
  if (ndec < 0) {
    sprintf(format, "%%.%dg", -ndec);
    sprintf(value, format, dval);
    lval = (int)strlen(value);
    for (i = 0; i < lval; i++)
      if (value[i] == 'e')
        value[i] = 'E';
  } else {
    sprintf(format, "%%.%df", ndec);
    sprintf(value, format, dval);
  }
  fixnegzero(value);
  return (hputc(hstring, keyword, value));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hputnr8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  js     L58
  lea    0x18(%rsp),%r14
  lea    D12(%rip),%rsi
  xor    %eax,%eax
  mov    %r14,%rdi
  lea    0x20(%rsp),%r13
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  call   <sprintf@plt>
L10:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fixnegzero@plt>
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <hputc@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  lea    0x18(%rsp),%r14
  neg    %edx
  lea    0x20(%rsp),%r13
  lea    D7(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  mov    %r14,%rsi
  mov    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L10
  sub    $0x1,%eax
  mov    %r13,%rdx
  lea    0x21(%rsp,%rax,1),%rax
  nopl   0x0(%rax)
L51:
  cmpb   $0x65,(%rdx)
  jne    L45
  movb   $0x45,(%rdx)
L45:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L51
  jmp    L10
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D12: %%.%df

tool: D7: %%.%dg

assistant: ```c
int hputnr8(hstring, keyword, ndec, dval)
char *hstring;
const char *keyword;
const int ndec;
const double dval;
{
  char value[30];
  char format[8];
  int i, lval;
  if (ndec < 0) {
    sprintf(format, "%%.%dg", -ndec);
    sprintf(value, format, dval);
    lval = (int)strlen(value);
    for (i = 0; i < lval; i++)
      if (value[i] == 'e')
        value[i] = 'E';
  } else {
    sprintf(format, "%%.%df", ndec);
    sprintf(value, format, dval);
  }
  fixnegzero(value);
  return (hputc(hstring, keyword, value));
}
```
user: What is the c source code of the assembly code below:

```asm
<hputnr8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  js     L13
  lea    0x18(%rsp),%r14
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  mov    %r14,%rdi
  lea    0x20(%rsp),%r13
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  call   <sprintf@plt>
L54:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fixnegzero@plt>
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <hputc@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  lea    0x18(%rsp),%r14
  neg    %edx
  lea    0x20(%rsp),%r13
  lea    D15(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  mov    %r14,%rsi
  mov    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L54
  sub    $0x1,%eax
  mov    %r13,%rdx
  lea    0x21(%rsp,%rax,1),%rax
  nopl   0x0(%rax)
L25:
  cmpb   $0x65,(%rdx)
  jne    L28
  movb   $0x45,(%rdx)
L28:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L25
  jmp    L54
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string

tool: D1: %%.%df

tool: D15: %%.%dg

assistant: ```c
int hputnr8(hstring, keyword, ndec, dval)
char *hstring;
const char *keyword;
const int ndec;
const double dval;
{
  char value[30];
  char format[8];
  int i, lval;
  if (ndec < 0) {
    sprintf(format, "%%.%dg", -ndec);
    sprintf(value, format, dval);
    lval = (int)strlen(value);
    for (i = 0; i < lval; i++)
      if (value[i] == 'e')
        value[i] = 'E';
  } else {
    sprintf(format, "%%.%df", ndec);
    sprintf(value, format, dval);
  }
  fixnegzero(value);
  return (hputc(hstring, keyword, value));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iupStrReturnStrStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L88
  cmpq   $0x0,-0x20(%rbp)
  je     L79
L88:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L46
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
L46:
  cmpq   $0x0,-0x20(%rbp)
  je     L48
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
L48:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <iupStrGetMemory@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L39
  cmpl   $0x0,-0x10(%rbp)
  je     L39
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L39:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x24(%rbp),%eax
  mov    %al,(%rdx)
  cmpq   $0x0,-0x20(%rbp)
  je     L6
  cmpl   $0x0,-0xc(%rbp)
  je     L6
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
L6:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L80
L79:
  mov    $0x0,%eax
L80:
  leave
  ret
```

assistant: ```c
char *iupStrReturnStrStr(const char *str1, const char *str2, char sep) {
  if (str1 || str2) {
    char *ret_str;
    int size1 = 0, size2 = 0;
    if (str1)
      size1 = (int)strlen(str1);
    if (str2)
      size2 = (int)strlen(str2);
    ret_str = iupStrGetMemory(size1 + size2 + 2);
    if (str1 && size1)
      memcpy(ret_str, str1, size1);
    ret_str[size1] = sep;
    if (str2 && size2)
      memcpy(ret_str + size1 + 1, str2, size2);
    ret_str[size1 + 1 + size2] = 0;
    return ret_str;
  } else
    return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<iupStrReturnStrStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  mov    %rdi,%r12
  or     %rsi,%r12
  je     L3
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  0xf(%rsp)
  je     L63
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %eax,%r14d
  test   %rbx,%rbx
  je     L2
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x2(%r13,%rax,1),%edi
  call   <iupStrGetMemory@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  je     L74
  cmpb   $0x0,0xf(%rsp)
  je     L74
L98:
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
L74:
  movslq %r14d,%rax
  movzbl 0x8(%rsp),%ecx
  mov    %cl,(%r12,%rax,1)
  test   %rbx,%rbx
  je     L8
  test   %r15d,%r15d
  je     L8
  lea    0x1(%r12,%rax,1),%rdi
  mov    %r15d,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L8:
  lea    0x1(%r15,%r14,1),%eax
  cltq
  movb   $0x0,(%r12,%rax,1)
L3:
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L95:
  mov    $0x0,%r15d
  jmp    L98
L2:
  lea    0x2(%rax),%edi
  call   <iupStrGetMemory@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jne    L95
  movzbl 0x8(%rsp),%eax
  mov    %al,(%r12)
  mov    %r13d,%r15d
  jmp    L8
L63:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x2(%rax),%edi
  call   <iupStrGetMemory@plt>
  mov    %rax,%r12
  mov    $0x0,%r14d
  jmp    L74
```

assistant: ```c
char *iupStrReturnStrStr(const char *str1, const char *str2, char sep) {
  if (str1 || str2) {
    char *ret_str;
    int size1 = 0, size2 = 0;
    if (str1)
      size1 = (int)strlen(str1);
    if (str2)
      size2 = (int)strlen(str2);
    ret_str = iupStrGetMemory(size1 + size2 + 2);
    if (str1 && size1)
      memcpy(ret_str, str1, size1);
    ret_str[size1] = sep;
    if (str2 && size2)
      memcpy(ret_str + size1 + 1, str2, size2);
    ret_str[size1 + 1 + size2] = 0;
    return ret_str;
  } else
    return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iupStrReturnStrStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  or     %rsi,%r13
  je     L36
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  test   %rdi,%rdi
  je     L43
  call   <strlen@plt>
  mov    %rax,%r15
  lea    0x1(%rax),%ebx
  test   %r12,%r12
  je     L16
  movslq %eax,%rcx
  mov    %r12,%rdi
  mov    %eax,0x1c(%rsp)
  mov    %rcx,0x10(%rsp)
  call   <strlen@plt>
  lea    0x2(%rax,%r15,1),%edi
  mov    %eax,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  call   <iupStrGetMemory@plt>
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rcx
  mov    0x1c(%rsp),%edx
  mov    %rax,%r13
  test   %esi,%esi
  setne  %r9b
  add    %esi,%ebx
  test   %r15d,%r15d
  je     L70
L81:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %r9b,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
  movzbl 0x10(%rsp),%r9d
  jmp    L20
  nop
L43:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x2(%rax),%edi
  mov    %eax,0x18(%rsp)
  call   <iupStrGetMemory@plt>
  test   %ebx,%ebx
  setne  %r9b
  mov    %rax,%r13
  add    $0x1,%ebx
  xor    %ecx,%ecx
L20:
  mov    %r14b,0x0(%r13,%rcx,1)
  test   %r9b,%r9b
  je     L29
  mov    0x18(%rsp),%edx
  lea    0x1(%r13,%rcx,1),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
L29:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%r13,%rbx,1)
L36:
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  lea    0x2(%rax),%edi
  mov    %eax,0x18(%rsp)
  call   <iupStrGetMemory@plt>
  test   %r15d,%r15d
  mov    0x18(%rsp),%edx
  mov    %rax,%r13
  jne    L57
  mov    %r14b,0x0(%r13)
  mov    $0x1,%ebx
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L70:
  xor    %ecx,%ecx
  jmp    L20
  nopl   0x0(%rax)
L57:
  movl   $0x0,0x18(%rsp)
  movslq %r15d,%rcx
  xor    %r9d,%r9d
  jmp    L81
```

assistant: ```c
char *iupStrReturnStrStr(const char *str1, const char *str2, char sep) {
  if (str1 || str2) {
    char *ret_str;
    int size1 = 0, size2 = 0;
    if (str1)
      size1 = (int)strlen(str1);
    if (str2)
      size2 = (int)strlen(str2);
    ret_str = iupStrGetMemory(size1 + size2 + 2);
    if (str1 && size1)
      memcpy(ret_str, str1, size1);
    ret_str[size1] = sep;
    if (str2 && size2)
      memcpy(ret_str + size1 + 1, str2, size2);
    ret_str[size1 + 1 + size2] = 0;
    return ret_str;
  } else
    return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<iupStrReturnStrStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  or     %rsi,%r13
  je     L10
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  test   %rdi,%rdi
  je     L60
  call   <strlen@plt>
  mov    %rax,%r15
  lea    0x1(%rax),%ebx
  test   %r12,%r12
  je     L73
  movslq %eax,%rcx
  mov    %r12,%rdi
  mov    %eax,0x1c(%rsp)
  mov    %rcx,0x10(%rsp)
  call   <strlen@plt>
  lea    0x2(%rax,%r15,1),%edi
  mov    %eax,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  call   <iupStrGetMemory@plt>
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rcx
  mov    0x1c(%rsp),%edx
  mov    %rax,%r13
  test   %esi,%esi
  setne  %r9b
  add    %esi,%ebx
  test   %r15d,%r15d
  je     L31
L48:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %r9b,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
  movzbl 0x10(%rsp),%r9d
  jmp    L68
  nop
L60:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x2(%rax),%edi
  mov    %eax,0x18(%rsp)
  call   <iupStrGetMemory@plt>
  test   %ebx,%ebx
  setne  %r9b
  mov    %rax,%r13
  add    $0x1,%ebx
  xor    %ecx,%ecx
L68:
  mov    %r14b,0x0(%r13,%rcx,1)
  test   %r9b,%r9b
  je     L36
  mov    0x18(%rsp),%edx
  lea    0x1(%r13,%rcx,1),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
L36:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%r13,%rbx,1)
L10:
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  lea    0x2(%rax),%edi
  mov    %eax,0x18(%rsp)
  call   <iupStrGetMemory@plt>
  test   %r15d,%r15d
  mov    0x18(%rsp),%edx
  mov    %rax,%r13
  jne    L88
  mov    %r14b,0x0(%r13)
  mov    $0x1,%ebx
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %ecx,%ecx
  jmp    L68
  nopl   0x0(%rax)
L88:
  movl   $0x0,0x18(%rsp)
  movslq %r15d,%rcx
  xor    %r9d,%r9d
  jmp    L48
```

assistant: ```c
char *iupStrReturnStrStr(const char *str1, const char *str2, char sep) {
  if (str1 || str2) {
    char *ret_str;
    int size1 = 0, size2 = 0;
    if (str1)
      size1 = (int)strlen(str1);
    if (str2)
      size2 = (int)strlen(str2);
    ret_str = iupStrGetMemory(size1 + size2 + 2);
    if (str1 && size1)
      memcpy(ret_str, str1, size1);
    ret_str[size1] = sep;
    if (str2 && size2)
      memcpy(ret_str + size1 + 1, str2, size2);
    ret_str[size1 + 1 + size2] = 0;
    return ret_str;
  } else
    return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kernel_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  mov    %rax,-0x8(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <intern@plt>
  mov    %eax,%esi
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <toi_funcall@plt>
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D8: stdout

tool: D16: write

assistant: ```c
unsigned long int kernel_write(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("write"), 1, arg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<kernel_write>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D10(%rip),%rdi
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  mov    %rax,%rbx
  lea    D18(%rip),%rdi
  call   <intern@plt>
  mov    %eax,%esi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <toi_funcall@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: string

tool: D10: stdout

tool: D18: write

assistant: ```c
unsigned long int kernel_write(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("write"), 1, arg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kernel_write>:
  endbr64
  push   %r12
  lea    D4(%rip),%rdi
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rbp
  call   <intern@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1090 <toi_funcall@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D9
datatype: string

tool: D4: stdout

tool: D9: write

assistant: ```c
unsigned long int kernel_write(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("write"), 1, arg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kernel_write>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  lea    D18(%rip),%rdi
  mov    %rax,%rbp
  call   <intern@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1090 <toi_funcall@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string

tool: D3: stdout

tool: D18: write

assistant: ```c
unsigned long int kernel_write(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("write"), 1, arg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<change_basis_tricli>:
  endbr64
  push   %r14
  mulsd  %xmm0,%xmm0
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x148,%rsp
  movdqu (%rsi),%xmm2
  movdqu 0x10(%rsi),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  movdqu 0x20(%rsi),%xmm4
  movdqu 0x30(%rsi),%xmm5
  mov    %rsp,%rdi
  mov    0x40(%rsi),%rax
  movaps %xmm2,(%rsp)
  movaps %xmm3,0x10(%rsp)
  mov    %rax,0x40(%rsp)
  movaps %xmm4,0x20(%rsp)
  movaps %xmm5,0x30(%rsp)
  call   <niggli_reduce@plt>
  test   %eax,%eax
  je     L27
  movdqa (%rsp),%xmm6
  movdqa 0x10(%rsp),%xmm7
  lea    0x50(%rsp),%r13
  mov    0x40(%rsp),%rax
  mov    %r13,%rdi
  movaps %xmm6,0x50(%rsp)
  movdqa 0x20(%rsp),%xmm6
  movaps %xmm7,0x60(%rsp)
  movdqa 0x30(%rsp),%xmm7
  mov    %rax,0x90(%rsp)
  movaps %xmm6,0x70(%rsp)
  movaps %xmm7,0x80(%rsp)
  call   <mat_get_determinant_d3@plt>
  test   %rax,%rax
  js     L3
L18:
  lea    0xa0(%rsp),%r14
  mov    %r12,%rsi
  xor    %edx,%edx
  mov    %r14,%rdi
  lea    0xf0(%rsp),%r12
  call   <mat_inverse_matrix_d3@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mat_cast_matrix_3d_to_3i@plt>
  mov    $0x1,%eax
L27:
  mov    0x138(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x148,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movq   D7(%rip),%xmm1
  mov    %r13,%rax
  lea    0x98(%rsp),%rdx
L20:
  movsd  (%rax),%xmm0
  add    $0x18,%rax
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rax)
  movsd  -0x10(%rax),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rax)
  movsd  -0x8(%rax),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L20
  jmp    L18
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int change_basis_tricli(int int_transform_mat[3][3], double conv_lattice[3][3], double primitive_lattice[3][3], const double symprec) {
  int i, j;
  double niggli_cell[9];
  double smallest_lattice[3][3], inv_lattice[3][3], transform_mat[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      niggli_cell[i * 3 + j] = conv_lattice[i][j];
    }
  }
  if (!niggli_reduce(niggli_cell, symprec * symprec)) {
    return 0;
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      smallest_lattice[i][j] = niggli_cell[i * 3 + j];
    }
  }
  if (mat_get_determinant_d3(smallest_lattice) < 0) {
    for (i = 0; i < 3; i++) {
      for (j = 0; j < 3; j++) {
        smallest_lattice[i][j] = -smallest_lattice[i][j];
      }
    }
  }
  mat_inverse_matrix_d3(inv_lattice, primitive_lattice, 0);
  mat_multiply_matrix_d3(transform_mat, inv_lattice, smallest_lattice);
  mat_cast_matrix_3d_to_3i(int_transform_mat, transform_mat);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <og_startup@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  og_startup();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <og_startup@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  og_startup();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <og_startup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  og_startup();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <og_startup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  og_startup();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_and_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  not    %rax
  and    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  and    -0x10(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, unsigned long *addr) {
  unsigned long mask = (1 << (nr));
  unsigned long old = *addr;
  *addr = old & ~mask;
  return (old & mask) != 0;
}
```