ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 1;
  a = a + b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L5
  mov    -0x4(%rbp),%eax
  jmp    L20
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L27
  mov    -0x8(%rbp),%eax
  jmp    L20
L27:
  mov    -0x4(%rbp),%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int min(int x, int y) {
  if (x < y)
    return x;
  else if (x > y)
    return y;
  else
    return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int x, int y) {
  if (x < y)
    return x;
  else if (x > y)
    return y;
  else
    return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int x, int y) {
  if (x < y)
    return x;
  else if (x > y)
    return y;
  else
    return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x434241,-0x10(%rbp)
  movl   $0x5a5958,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <print_list@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  char arr_a[4] = "ABC";
  char arr_b[4] = "XYZ";
  print_list(arr_a, arr_b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x434241,(%rsp)
  movl   $0x5a5958,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <print_list@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char arr_a[4] = "ABC";
  char arr_b[4] = "XYZ";
  print_list(arr_a, arr_b);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x434241,(%rsp)
  movl   $0x5a5958,0x4(%rsp)
  call   <print_list@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char arr_a[4] = "ABC";
  char arr_b[4] = "XYZ";
  print_list(arr_a, arr_b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x434241,(%rsp)
  movl   $0x5a5958,0x4(%rsp)
  call   <print_list@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char arr_a[4] = "ABC";
  char arr_b[4] = "XYZ";
  print_list(arr_a, arr_b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<switch_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L0
  nop
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void switch_test(int i) {
  switch (i) {
  case 1 ... 3:
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<switch_test>:
  endbr64
  ret
```

assistant: ```c
void switch_test(int i) {
  switch (i) {
  case 1 ... 3:
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<switch_test>:
  endbr64
  ret
```

assistant: ```c
void switch_test(int i) {
  switch (i) {
  case 1 ... 3:
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<switch_test>:
  endbr64
  ret
```

assistant: ```c
void switch_test(int i) {
  switch (i) {
  case 1 ... 3:
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<opcode_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int opcode_length(unsigned char op) {
  static int length_lookup[] = {1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 0, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 3, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 0, 2, 0, 0, 2, 2, 2, 0, 1, 1, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 0, 3, 0, 0, 2, 2, 2, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0};
  return length_lookup[op];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<opcode_length>:
  endbr64
  movzbl %dil,%edi
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string

tool: D7: 

assistant: ```c
int opcode_length(unsigned char op) {
  static int length_lookup[] = {1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 0, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 3, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 0, 2, 0, 0, 2, 2, 2, 0, 1, 1, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 0, 3, 0, 0, 2, 2, 2, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0};
  return length_lookup[op];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<opcode_length>:
  endbr64
  movzbl %dil,%edi
  lea    D8(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: 

assistant: ```c
int opcode_length(unsigned char op) {
  static int length_lookup[] = {1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 0, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 3, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 0, 2, 0, 0, 2, 2, 2, 0, 1, 1, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 0, 3, 0, 0, 2, 2, 2, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0};
  return length_lookup[op];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<opcode_length>:
  endbr64
  movzbl %dil,%edi
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: 

assistant: ```c
int opcode_length(unsigned char op) {
  static int length_lookup[] = {1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 0, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 3, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 1, 2, 0, 0, 0, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 0, 2, 0, 0, 2, 2, 2, 0, 1, 1, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 0, 3, 0, 0, 2, 2, 2, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 3, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0, 2, 2, 0, 0, 2, 2, 2, 0, 1, 2, 1, 0, 3, 3, 3, 0, 2, 2, 0, 0, 0, 2, 2, 0, 1, 3, 0, 0, 0, 3, 3, 0};
  return length_lookup[op];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x8c(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x88(%rbp)
  cmpq   $0x0,-0x88(%rbp)
  jne    L33
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L33
L10:
  mov    -0x8c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8c(%rbp)
  lea    -0x7a(%rbp),%rdi
  mov    %eax,%ecx
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  mov    $0xa,%esi
  call   <snprintf@plt>
  lea    -0x7a(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <add_to_cache@plt>
L33:
  mov    -0x88(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type: string
name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D34
type: string
name: read_data
arguments: data_label: D3
type: string

tool: D21: r

tool: D11: test65.dat

tool: D34: can't open: 

tool: D3: %u

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  file = fopen("test65.dat", "r");
  if (file == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L37
L7:
  mov    $0x0,%ebx
  lea    D37(%rip),%r13
  jmp    L4
L37:
  lea    D24(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L7
L25:
  lea    0x1(%rbx),%r14d
  lea    0x6(%rsp),%rbp
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <add_to_cache@plt>
  mov    %r14d,%ebx
L4:
  lea    0x10(%rsp),%rdi
  mov    %r12,%rdx
  mov    $0x64,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L25
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D37
data_type: string
name: retrieve_data
arguments: data_label: D24
data_type: string

tool: D9: r

tool: D23: test65.dat

tool: D37: %u

tool: D24: can't open: 

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  file = fopen("test65.dat", "r");
  if (file == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D18(%rip),%rsi
  lea    D30(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L16
L34:
  xor    %r12d,%r12d
  lea    0x10(%rsp),%rbx
  lea    D13(%rip),%r14
  jmp    L15
  nopl   (%rax)
L36:
  lea    0x6(%rsp),%rbp
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  lea    0x1(%r12),%r15d
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r15d,%r12d
  call   <add_to_cache@plt>
L15:
  mov    %r13,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L36
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  lea    D23(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L34
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D30
datatype: string
name: read_data
arguments: label: D13
datatype: string
name: read_data
arguments: label: D23
datatype: string

tool: D18: r

tool: D30: test65.dat

tool: D13: %u

tool: D23: can't open: 

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  file = fopen("test65.dat", "r");
  if (file == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%rsi
  lea    D7(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L5
L41:
  xor    %r12d,%r12d
  lea    0x10(%rsp),%rbx
  lea    D9(%rip),%r14
  jmp    L36
  nopl   (%rax)
L17:
  lea    0x6(%rsp),%rbp
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  lea    0x1(%r12),%r15d
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r15d,%r12d
  call   <add_to_cache@plt>
L36:
  mov    %r13,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L17
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  lea    D23(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L41
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D23
type_guessed: string

tool: D37: r

tool: D7: test65.dat

tool: D9: %u

tool: D23: can't open: 

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  file = fopen("test65.dat", "r");
  if (file == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_cwde>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cwtl
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movswl %ax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  je     L4
  mov    $0x1,%eax
  (bad)
L4:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void test_cwde(int x) {
  volatile int a, newa;
  a = x;
  __asm__ __volatile__("mov %1, %%eax\n\t"
                       "cwtl\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(newa)
                       : "m"(a)
                       : "eax");
  do {
    if (!(newa == (int)(short)a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_cwde>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    (%rsp),%eax
  cwtl
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cwtl
  cmp    %edx,%eax
  je     L4
  mov    $0x1,%eax
  (bad)
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_cwde(int x) {
  volatile int a, newa;
  a = x;
  __asm__ __volatile__("mov %1, %%eax\n\t"
                       "cwtl\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(newa)
                       : "m"(a)
                       : "eax");
  do {
    if (!(newa == (int)(short)a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_cwde>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    (%rsp),%eax
  cwtl
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cwtl
  cmp    %edx,%eax
  je     L10
  mov    $0x1,%eax
  (bad)
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_cwde(int x) {
  volatile int a, newa;
  a = x;
  __asm__ __volatile__("mov %1, %%eax\n\t"
                       "cwtl\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(newa)
                       : "m"(a)
                       : "eax");
  do {
    if (!(newa == (int)(short)a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_cwde>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    (%rsp),%eax
  cwtl
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cwtl
  cmp    %edx,%eax
  je     L17
  mov    $0x1,%eax
  (bad)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_cwde(int x) {
  volatile int a, newa;
  a = x;
  __asm__ __volatile__("mov %1, %%eax\n\t"
                       "cwtl\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(newa)
                       : "m"(a)
                       : "eax");
  do {
    if (!(newa == (int)(short)a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x28(%rbp)
  lea    -0x13(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  mov    %al,-0x2d(%rbp)
  jmp    L18
L35:
  movzbl -0x2d(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  mov    %al,-0x2d(%rbp)
L18:
  cmpb   $0x2f,-0x2d(%rbp)
  jbe    L34
  cmpb   $0x39,-0x2d(%rbp)
  jbe    L35
L34:
  mov    -0x2c(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
int main(void) {
  char in[11];
  char *s;
  unsigned char c;
  int i, j;
  int idx_in;
  in[10] = 0;
  idx_in = 0;
  s = in;
  i = 0;
  c = in[idx_in];
  while (('0' <= c) && (c <= '9')) {
    j = c - '0';
    i = i * 10U + j;
    idx_in++;
    c = in[idx_in];
  }
  __VERIFIER_assert(i >= 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x17(%rsp)
  movzbl 0xd(%rsp),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L22
  lea    0xe(%rsp),%rdx
  mov    $0x0,%edi
L0:
  lea    (%rdi,%rdi,4),%ecx
  movzbl %al,%eax
  lea    -0x30(%rax,%rcx,2),%edi
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L0
L39:
  not    %edi
  shr    $0x1f,%edi
  call   <__VERIFIER_assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L22:
  mov    $0x0,%edi
  jmp    L39
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char in[11];
  char *s;
  unsigned char c;
  int i, j;
  int idx_in;
  in[10] = 0;
  idx_in = 0;
  s = in;
  i = 0;
  c = in[idx_in];
  while (('0' <= c) && (c <= '9')) {
    j = c - '0';
    i = i * 10U + j;
    idx_in++;
    c = in[idx_in];
  }
  __VERIFIER_assert(i >= 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl 0xd(%rsp),%eax
  movb   $0x0,0x17(%rsp)
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L38
  lea    0xe(%rsp),%rdx
  xor    %edi,%edi
  nopl   0x0(%rax)
L15:
  lea    (%rdi,%rdi,4),%ecx
  add    $0x1,%rdx
  lea    -0x30(%rax,%rcx,2),%edi
  movzbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L15
L18:
  not    %edi
  shr    $0x1f,%edi
  call   <__VERIFIER_assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L38:
  xor    %edi,%edi
  jmp    L18
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char in[11];
  char *s;
  unsigned char c;
  int i, j;
  int idx_in;
  in[10] = 0;
  idx_in = 0;
  s = in;
  i = 0;
  c = in[idx_in];
  while (('0' <= c) && (c <= '9')) {
    j = c - '0';
    i = i * 10U + j;
    idx_in++;
    c = in[idx_in];
  }
  __VERIFIER_assert(i >= 0);
  return 0;
}
```