ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq -0x2c(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L79:
  cmp    %rdx,%rsp
  je     L52
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L52:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L30
  orq    $0x0,-0x8(%rsp,%rax,1)
L30:
  mov    %rsp,%r13
  lea    -0x2c(%rbp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x2c(%rbp)
  jle    L31
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D23(%rip),%r14
L102:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x2c(%rbp)
  jg     L102
L31:
  mov    $0x0,%r12d
  lea    D23(%rip),%r14
  cmpl   $0x0,-0x2c(%rbp)
  jns    L22
L59:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L10:
  mov    %ebx,%eax
  not    %eax
  add    -0x2c(%rbp),%eax
  cltq
  mov    0x0(%r13,%rax,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jle    L10
L94:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    %r12d,-0x2c(%rbp)
  jl     L59
L22:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jns    L10
  jmp    L94
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D23
datatype: string

tool: D5: %d

tool: D23: %d 

assistant: ```c
int main() {
  int i, j, n;
  int a[n];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d ", &a[i]);
  }
  for (i = 0; i <= n; i++) {
    for (j = 0; j < i + 1; j++) {
      printf("%d ", a[n - 1 - j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L33
L67:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L67
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L41
L42:
  lea    -0x2c(%rbp),%rsi
  lea    D16(%rip),%rdi
  mov    %rsp,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L28
  mov    %r13,%r14
  xor    %ebx,%ebx
  lea    D15(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L105:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L105
L28:
  xor    %ebx,%ebx
  lea    D15(%rip),%r12
  test   %eax,%eax
  js     L48
  xchg   %ax,%ax
L88:
  xor    %r14d,%r14d
  jmp    L29
  nopl   (%rax)
L75:
  mov    -0x2c(%rbp),%eax
L29:
  sub    $0x1,%eax
  mov    %r12,%rdi
  sub    %r14d,%eax
  add    $0x1,%r14d
  cltq
  mov    0x0(%r13,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L75
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jge    L88
L48:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L41:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L42
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D16: %d

tool: D15: %d 

assistant: ```c
int main() {
  int i, j, n;
  int a[n];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d ", &a[i]);
  }
  for (i = 0; i <= n; i++) {
    for (j = 0; j < i + 1; j++) {
      printf("%d ", a[n - 1 - j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L69
L8:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L8
L69:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L72:
  lea    -0x2c(%rbp),%rsi
  lea    D19(%rip),%rdi
  mov    %rsp,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L32
  mov    %r13,%r14
  xor    %ebx,%ebx
  lea    D10(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L71
L32:
  xor    %ebx,%ebx
  lea    D10(%rip),%r12
  test   %eax,%eax
  js     L16
  xchg   %ax,%ax
L39:
  xor    %r14d,%r14d
  jmp    L50
  nopl   (%rax)
L94:
  mov    -0x2c(%rbp),%eax
L50:
  sub    $0x1,%eax
  mov    %r12,%rdi
  sub    %r14d,%eax
  add    $0x1,%r14d
  cltq
  mov    0x0(%r13,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L94
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jge    L39
L16:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L72
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string

tool: D19: %d

tool: D10: %d 

assistant: ```c
int main() {
  int i, j, n;
  int a[n];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d ", &a[i]);
  }
  for (i = 0; i <= n; i++) {
    for (j = 0; j < i + 1; j++) {
      printf("%d ", a[n - 1 - j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<standard_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D25(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <syscon_read_standard_system@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <syscon_write_standard_system@plt>
  mov    %eax,-0x14(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,%rsi
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <solve_with_standard_doubles@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    %eax,-0x14(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type: byte[8]
name: unpack_data
arguments: label: D33
type: string
name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D8
type: string

tool: {"D25": [0x11,0xea,0x2d,0x81,0x99,0x97,0x71,0x3d]}

tool: D33: 
Give the maximum number of iterations : 

tool: D0: %d

tool: D8: 
Number of iterations : %d


assistant: ```c
void standard_test(void) {
  int fail, max, nit;
  const double eps = 1.0e-12;
  fail = syscon_read_standard_system();
  fail = syscon_write_standard_system();
  printf("\nGive the maximum number of iterations : ");
  scanf("%d", &max);
  fail = solve_with_standard_doubles(max, eps, &nit);
  printf("\nNumber of iterations : %d\n", nit);
  fail = solcon_write_standard_solutions();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<standard_test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <syscon_read_standard_system@plt>
  mov    $0x0,%eax
  call   <syscon_write_standard_system@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  movsd  D29(%rip),%xmm0
  mov    (%rsp),%edi
  call   <solve_with_standard_doubles@plt>
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D29
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D34: 
Give the maximum number of iterations : 

tool: D27: %d

tool: {"D29": [0x11,0xea,0x2d,0x81,0x99,0x97,0x71,0x3d]}

tool: D11: 
Number of iterations : %d


assistant: ```c
void standard_test(void) {
  int fail, max, nit;
  const double eps = 1.0e-12;
  fail = syscon_read_standard_system();
  fail = syscon_write_standard_system();
  printf("\nGive the maximum number of iterations : ");
  scanf("%d", &max);
  fail = solve_with_standard_doubles(max, eps, &nit);
  printf("\nNumber of iterations : %d\n", nit);
  fail = solcon_write_standard_solutions();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<standard_test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <syscon_read_standard_system@plt>
  xor    %eax,%eax
  call   <syscon_write_standard_system@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  movsd  D24(%rip),%xmm0
  mov    (%rsp),%edi
  lea    0x4(%rsp),%rsi
  call   <solve_with_standard_doubles@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D24
type: byte[8]
name: unpack_data
arguments: data_tag: D1
type: string

tool: D5: 
Give the maximum number of iterations : 

tool: D3: %d

tool: {"D24": [0x11,0xea,0x2d,0x81,0x99,0x97,0x71,0x3d]}

tool: D1: 
Number of iterations : %d


assistant: ```c
void standard_test(void) {
  int fail, max, nit;
  const double eps = 1.0e-12;
  fail = syscon_read_standard_system();
  fail = syscon_write_standard_system();
  printf("\nGive the maximum number of iterations : ");
  scanf("%d", &max);
  fail = solve_with_standard_doubles(max, eps, &nit);
  printf("\nNumber of iterations : %d\n", nit);
  fail = solcon_write_standard_solutions();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<standard_test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <syscon_read_standard_system@plt>
  xor    %eax,%eax
  call   <syscon_write_standard_system@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  D20(%rip),%xmm0
  mov    (%rsp),%edi
  lea    0x4(%rsp),%rsi
  call   <solve_with_standard_doubles@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D16
data_type: string

tool: D32: 
Give the maximum number of iterations : 

tool: D13: %d

tool: {"D20": [0x11,0xea,0x2d,0x81,0x99,0x97,0x71,0x3d]}

tool: D16: 
Number of iterations : %d


assistant: ```c
void standard_test(void) {
  int fail, max, nit;
  const double eps = 1.0e-12;
  fail = syscon_read_standard_system();
  fail = syscon_write_standard_system();
  printf("\nGive the maximum number of iterations : ");
  scanf("%d", &max);
  fail = solve_with_standard_doubles(max, eps, &nit);
  printf("\nNumber of iterations : %d\n", nit);
  fail = solcon_write_standard_solutions();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getCofactor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L39:
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L28:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  je     L23
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  je     L23
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L23
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L23:
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L28
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getCofactor(float **A, float **temp, int p, int q, int n) {
  int i = 0, j = 0, row, col;
  for (row = 0; row < n; row++)
    for (col = 0; col < n; col++) {
      if (row != p && col != q) {
        temp[i][j] = A[row][col];
        j++;
        if (j == n - 1) {
          j = 0;
          i++;
        }
      }
    }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getCofactor>:
  endbr64
  test   %r8d,%r8d
  jle    L56
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %edx,%r9d
  mov    %ecx,%ebp
  mov    %r8d,%edi
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ebx
  lea    -0x1(%r8),%r12d
  jmp    L12
L22:
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L73
L32:
  cmp    %esi,%r9d
  je     L22
  cmp    %eax,%ebp
  je     L22
  mov    (%r10,%rsi,8),%rcx
  movss  (%rcx,%rax,4),%xmm0
  movslq %ebx,%rcx
  movslq %edx,%r8
  mov    (%r11,%rcx,8),%rcx
  movss  %xmm0,(%rcx,%r8,4)
  add    $0x1,%edx
  cmp    %edx,%r12d
  jne    L22
  add    $0x1,%ebx
  mov    $0x0,%edx
  jmp    L22
L73:
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  je     L60
L12:
  mov    $0x0,%eax
  jmp    L32
L60:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  ret
```

assistant: ```c
void getCofactor(float **A, float **temp, int p, int q, int n) {
  int i = 0, j = 0, row, col;
  for (row = 0; row < n; row++)
    for (col = 0; col < n; col++) {
      if (row != p && col != q) {
        temp[i][j] = A[row][col];
        j++;
        if (j == n - 1) {
          j = 0;
          i++;
        }
      }
    }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getCofactor>:
  endbr64
  test   %r8d,%r8d
  jle    L8
  push   %r13
  mov    %rdi,%r11
  xor    %r9d,%r9d
  mov    %ecx,%edi
  push   %r12
  lea    -0x1(%r8),%r13d
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  xor    %edx,%edx
  push   %rbx
  mov    %rsi,%rbx
  movslq %r8d,%rsi
  nopl   0x0(%rax)
L3:
  cmp    %r9d,%ebp
  setne  %r10b
  xor    %eax,%eax
  nopl   0x0(%rax)
L44:
  cmp    %eax,%edi
  je     L48
  test   %r10b,%r10b
  je     L48
  mov    (%r11,%r9,8),%rcx
  movslq %edx,%r8
  add    $0x1,%edx
  movss  (%rcx,%rax,4),%xmm0
  movslq %r12d,%rcx
  mov    (%rbx,%rcx,8),%rcx
  movss  %xmm0,(%rcx,%r8,4)
  cmp    %edx,%r13d
  jne    L48
  add    $0x1,%r12d
  xor    %edx,%edx
L48:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L44
  add    $0x1,%r9
  cmp    %rsi,%r9
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  ret
```

assistant: ```c
void getCofactor(float **A, float **temp, int p, int q, int n) {
  int i = 0, j = 0, row, col;
  for (row = 0; row < n; row++)
    for (col = 0; col < n; col++) {
      if (row != p && col != q) {
        temp[i][j] = A[row][col];
        j++;
        if (j == n - 1) {
          j = 0;
          i++;
        }
      }
    }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getCofactor>:
  endbr64
  test   %r8d,%r8d
  jle    L6
  push   %r13
  mov    %rdi,%r11
  xor    %r9d,%r9d
  mov    %ecx,%edi
  push   %r12
  lea    -0x1(%r8),%r13d
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  xor    %edx,%edx
  push   %rbx
  mov    %rsi,%rbx
  movslq %r8d,%rsi
  nopl   0x0(%rax)
L32:
  cmp    %r9d,%ebp
  setne  %r10b
  xor    %eax,%eax
  nopl   0x0(%rax)
L52:
  cmp    %eax,%edi
  je     L16
  test   %r10b,%r10b
  je     L16
  mov    (%r11,%r9,8),%rcx
  movslq %edx,%r8
  add    $0x1,%edx
  movss  (%rcx,%rax,4),%xmm0
  movslq %r12d,%rcx
  mov    (%rbx,%rcx,8),%rcx
  movss  %xmm0,(%rcx,%r8,4)
  cmp    %edx,%r13d
  jne    L16
  add    $0x1,%r12d
  xor    %edx,%edx
L16:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L52
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

assistant: ```c
void getCofactor(float **A, float **temp, int p, int q, int n) {
  int i = 0, j = 0, row, col;
  for (row = 0; row < n; row++)
    for (col = 0; col < n; col++) {
      if (row != p && col != q) {
        temp[i][j] = A[row][col];
        j++;
        if (j == n - 1) {
          j = 0;
          i++;
        }
      }
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pdu_get_tpoa_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  addl   $0x1,-0x1c(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pdu_get_tpoa_number(char *body, int oa_len, char *oa_number) {
  char *pBegin, *pEnd;
  pBegin = body;
  if (oa_len % 2) {
    oa_len++;
  }
  pEnd = pBegin + oa_len;
  strncpy(oa_number, pBegin, oa_len);
  oa_number[oa_len] = '\0';
  return pEnd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pdu_get_tpoa_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%esi
  movslq %esi,%rbp
  lea    (%rdi,%rbp,1),%r12
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pdu_get_tpoa_number(char *body, int oa_len, char *oa_number) {
  char *pBegin, *pEnd;
  pBegin = body;
  if (oa_len % 2) {
    oa_len++;
  }
  pEnd = pBegin + oa_len;
  strncpy(oa_number, pBegin, oa_len);
  oa_number[oa_len] = '\0';
  return pEnd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pdu_get_tpoa_number>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%r8d
  push   %r12
  mov    %rdi,%rsi
  and    $0x1,%eax
  push   %rbp
  cmp    $0x1,%eax
  push   %rbx
  mov    %rdx,%rbx
  sbb    $0xffffffff,%r8d
  movslq %r8d,%rbp
  mov    %r8d,%edx
  lea    (%rdi,%rbp,1),%r12
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pdu_get_tpoa_number(char *body, int oa_len, char *oa_number) {
  char *pBegin, *pEnd;
  pBegin = body;
  if (oa_len % 2) {
    oa_len++;
  }
  pEnd = pBegin + oa_len;
  strncpy(oa_number, pBegin, oa_len);
  oa_number[oa_len] = '\0';
  return pEnd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pdu_get_tpoa_number>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%r8d
  push   %r12
  mov    %rdi,%rsi
  and    $0x1,%eax
  push   %rbp
  cmp    $0x1,%eax
  push   %rbx
  mov    %rdx,%rbx
  sbb    $0xffffffff,%r8d
  movslq %r8d,%rbp
  mov    %r8d,%edx
  lea    (%rdi,%rbp,1),%r12
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pdu_get_tpoa_number(char *body, int oa_len, char *oa_number) {
  char *pBegin, *pEnd;
  pBegin = body;
  if (oa_len % 2) {
    oa_len++;
  }
  pEnd = pBegin + oa_len;
  strncpy(oa_number, pBegin, oa_len);
  oa_number[oa_len] = '\0';
  return pEnd;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__basepriSetRetVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__set_BASEPRI_MAX_nb@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
uint8_t __basepriSetRetVal(uint8_t prio) {
  __set_BASEPRI_MAX_nb(prio);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__basepriSetRetVal>:
  endbr64
  sub    $0x8,%rsp
  call   <__set_BASEPRI_MAX_nb@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t __basepriSetRetVal(uint8_t prio) {
  __set_BASEPRI_MAX_nb(prio);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__basepriSetRetVal>:
  endbr64
  sub    $0x8,%rsp
  call   <__set_BASEPRI_MAX_nb@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t __basepriSetRetVal(uint8_t prio) {
  __set_BASEPRI_MAX_nb(prio);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__basepriSetRetVal>:
  endbr64
  sub    $0x8,%rsp
  call   <__set_BASEPRI_MAX_nb@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t __basepriSetRetVal(uint8_t prio) {
  __set_BASEPRI_MAX_nb(prio);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putnbyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  shrl   $0x8,-0x1c(%rbp)
  subl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putnbyte(unsigned char *pnt, unsigned int value, unsigned int nbytes) {
  int i;
  for (i = nbytes - 1; i >= 0; i--) {
    pnt[i] = value & 0xff;
    value = value >> 8;
  }
}
```