ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D15(%rip),%r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L54
L25:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L25
L54:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L20:
  mov    %rsp,%r14
  test   %esi,%esi
  jle    L61
  mov    %r14,%r12
  xor    %ebx,%ebx
  nop
L68:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %ebx,%esi
  jg     L68
L61:
  mov    %r14,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L63
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <check@plt>
  test   %eax,%eax
  je     L30
L91:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L63:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L30:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L20
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D28
type: string

tool: D15: %d

tool: D20: YES

tool: D28: NO

assistant: ```c
int main() {
  int n, i, j;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  if (check(a, n) == 1)
    printf("YES");
  else if (check(a, n) == 0)
    printf("NO");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L44
L87:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L87
L44:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L10:
  mov    %rsp,%r14
  test   %esi,%esi
  jle    L33
  mov    %r14,%r12
  xor    %ebx,%ebx
  nop
L80:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %ebx,%esi
  jg     L80
L33:
  mov    %r14,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L43
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <check@plt>
  test   %eax,%eax
  je     L108
L59:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L43:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L108:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L10
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D22
type: string
name: parse_data
arguments: tag: D29
type: string

tool: D1: %d

tool: D22: YES

tool: D29: NO

assistant: ```c
int main() {
  int n, i, j;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  if (check(a, n) == 1)
    printf("YES");
  else if (check(a, n) == 0)
    printf("NO");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L27
  mov    $0x1,%eax
  jmp    L21
L28:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L28
  mov    -0x4(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int power(int n, int idx) {
  int ret = 1;
  if (idx == 0) {
    return 1;
  }
  while (idx--) {
    ret *= n;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L1
  sub    $0x1,%esi
L10:
  imul   %edi,%eax
  sub    $0x1,%esi
  cmp    $0xffffffff,%esi
  jne    L10
L1:
  ret
```

assistant: ```c
int power(int n, int idx) {
  int ret = 1;
  if (idx == 0) {
    return 1;
  }
  while (idx--) {
    ret *= n;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L0
  sub    $0x1,%esi
L8:
  imul   %edi,%eax
  sub    $0x1,%esi
  jae    L8
L0:
  ret
```

assistant: ```c
int power(int n, int idx) {
  int ret = 1;
  if (idx == 0) {
    return 1;
  }
  while (idx--) {
    ret *= n;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L14
  sub    $0x1,%esi
L2:
  imul   %edi,%eax
  sub    $0x1,%esi
  jae    L2
L14:
  ret
```

assistant: ```c
int power(int n, int idx) {
  int ret = 1;
  if (idx == 0) {
    return 1;
  }
  while (idx--) {
    ret *= n;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<maxProduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L25
L28:
  movl   $0x0,-0x1c(%rbp)
  jmp    L1
L39:
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  lea    -0x18(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <maxDirectionalProduct@plt>
  addl   $0x1,-0x1c(%rbp)
L1:
  cmpl   $0x13,-0x1c(%rbp)
  jle    L39
  addl   $0x1,-0x20(%rbp)
L25:
  cmpl   $0x13,-0x20(%rbp)
  jle    L28
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
long maxProduct(long ***gridptr) {
  long **grid = *(gridptr);
  long max = 0;
  for (int y = 0; y < 20; y++) {
    for (int x = 0; x < 20; x++) {
      maxDirectionalProduct(gridptr, &max, x, y);
    }
  }
  return max;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maxProduct>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%ebp
  mov    %rsp,%r13
L20:
  mov    $0x0,%ebx
L6:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <maxDirectionalProduct@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L6
  add    $0x1,%ebp
  cmp    $0x14,%ebp
  jne    L20
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long maxProduct(long ***gridptr) {
  long **grid = *(gridptr);
  long max = 0;
  for (int y = 0; y < 20; y++) {
    for (int x = 0; x < 20; x++) {
      maxDirectionalProduct(gridptr, &max, x, y);
    }
  }
  return max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<maxProduct>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%r13
  xchg   %ax,%ax
L13:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%edx
  mov    %ebp,%ecx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <maxDirectionalProduct@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L12
  add    $0x1,%ebp
  cmp    $0x14,%ebp
  jne    L13
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long maxProduct(long ***gridptr) {
  long **grid = *(gridptr);
  long max = 0;
  for (int y = 0; y < 20; y++) {
    for (int x = 0; x < 20; x++) {
      maxDirectionalProduct(gridptr, &max, x, y);
    }
  }
  return max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<maxProduct>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%r13
  xchg   %ax,%ax
L3:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%edx
  mov    %ebp,%ecx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <maxDirectionalProduct@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L26
  add    $0x1,%ebp
  cmp    $0x14,%ebp
  jne    L3
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long maxProduct(long ***gridptr) {
  long **grid = *(gridptr);
  long max = 0;
  for (int y = 0; y < 20; y++) {
    for (int x = 0; x < 20; x++) {
      maxDirectionalProduct(gridptr, &max, x, y);
    }
  }
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IGRFMagCmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rcx
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rdi
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <IGRFCall@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    -0x50(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: f64
name: unpack_data
arguments: data_label: D3
type_guessed: byte[8]

tool: D9: 6372

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int IGRFMagCmp(double date, double frho, double flat, double flon, double *bx, double *by, double *bz, double *b) {
  int s;
  frho = frho - 6372.;
  s = IGRFCall(date, flat, flon, frho, bx, by, bz);
  *b = sqrt(*bx * *bx + *by * *by + *bz * *bz);
  *bx = -*bx;
  *bz = -*bz;
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<IGRFMagCmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movapd %xmm1,%xmm4
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %rcx,%r13
  movapd %xmm4,%xmm3
  subsd  D19(%rip),%xmm3
  call   <IGRFCall@plt>
  mov    %eax,%r12d
  movsd  0x0(%rbp),%xmm0
  movsd  (%r14),%xmm2
  movsd  (%rbx),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L7
  sqrtsd %xmm0,%xmm0
L12:
  movsd  %xmm0,0x0(%r13)
  movsd  0x0(%rbp),%xmm0
  movq   D11(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  (%rbx),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <sqrt@plt>
  jmp    L12
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: f64
name: parse_data
arguments: data_tag: D11
type_guessed: byte[8]

tool: D19: 6372

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int IGRFMagCmp(double date, double frho, double flat, double flon, double *bx, double *by, double *bz, double *b) {
  int s;
  frho = frho - 6372.;
  s = IGRFCall(date, flat, flon, frho, bx, by, bz);
  *b = sqrt(*bx * *bx + *by * *by + *bz * *bz);
  *bx = -*bx;
  *bz = -*bz;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IGRFMagCmp>:
  endbr64
  push   %r13
  movapd %xmm1,%xmm4
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  push   %r12
  movapd %xmm4,%xmm3
  mov    %rsi,%r12
  mov    %rcx,%r13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  subsd  D8(%rip),%xmm3
  call   <IGRFCall@plt>
  movsd  0x0(%rbp),%xmm0
  movsd  (%r12),%xmm2
  movsd  (%rbx),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L7
  sqrtsd %xmm0,%xmm0
L11:
  movsd  %xmm0,0x0(%r13)
  movq   D2(%rip),%xmm1
  movsd  0x0(%rbp),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  (%rbx),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %eax,0xc(%rsp)
  call   <sqrt@plt>
  mov    0xc(%rsp),%eax
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: f64
name: extract_symbolic_data
arguments: label: D2
data_type: byte[8]

tool: D8: 6372

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int IGRFMagCmp(double date, double frho, double flat, double flon, double *bx, double *by, double *bz, double *b) {
  int s;
  frho = frho - 6372.;
  s = IGRFCall(date, flat, flon, frho, bx, by, bz);
  *b = sqrt(*bx * *bx + *by * *by + *bz * *bz);
  *bx = -*bx;
  *bz = -*bz;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IGRFMagCmp>:
  endbr64
  push   %r13
  movapd %xmm1,%xmm4
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  push   %r12
  movapd %xmm4,%xmm3
  mov    %rsi,%r12
  mov    %rcx,%r13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  subsd  D18(%rip),%xmm3
  call   <IGRFCall@plt>
  movsd  0x0(%rbp),%xmm0
  movsd  (%r12),%xmm2
  movsd  (%rbx),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L6
  sqrtsd %xmm0,%xmm0
L2:
  movsd  %xmm0,0x0(%r13)
  movq   D4(%rip),%xmm1
  movsd  0x0(%rbp),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  (%rbx),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    %eax,0xc(%rsp)
  call   <sqrt@plt>
  mov    0xc(%rsp),%eax
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: f64
name: disassemble_data
arguments: tag: D4
data_type: byte[8]

tool: D18: 6372

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int IGRFMagCmp(double date, double frho, double flat, double flon, double *bx, double *by, double *bz, double *b) {
  int s;
  frho = frho - 6372.;
  s = IGRFCall(date, flat, flon, frho, bx, by, bz);
  *b = sqrt(*bx * *bx + *by * *by + *bz * *bz);
  *bx = -*bx;
  *bz = -*bz;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_tag_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L10:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0xa,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x4(%rbp),%eax
  jmp    L34
L19:
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0xe,-0x4(%rbp)
  jle    L10
  mov    $0xffffffff,%eax
L34:
  leave
  ret
```

assistant: ```c
int get_tag_index(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return i;
    }
    i++;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_tag_index>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L6:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%ebp
  add    $0x400,%rbx
  cmp    $0xf,%ebp
  jne    L6
  mov    $0xffffffff,%ebp
L17:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_tag_index(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return i;
    }
    i++;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_tag_index>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L8
  add    $0x1,%r12d
  add    $0x400,%rbx
  cmp    $0xf,%r12d
  jne    L6
  mov    $0xffffffff,%r12d
L8:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_tag_index(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return i;
    }
    i++;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_tag_index>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%r12d
  add    $0x400,%rbx
  cmp    $0xf,%r12d
  jne    L10
  mov    $0xffffffff,%r12d
L16:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_tag_index(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return i;
    }
    i++;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<_SysCtlFrequencyGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    $0x400fe160,%eax
  mov    (%rax),%eax
  sar    $0xa,%eax
  and    $0x3ff,%eax
  mov    %eax,-0x1c(%rbp)
  mov    $0x400fe160,%eax
  mov    (%rax),%eax
  and    $0x3ff,%eax
  mov    %eax,-0x18(%rbp)
  mov    $0x400fe164,%eax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x400fe164,%eax
  mov    (%rax),%eax
  and    $0x1f,%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0xc(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x8(%rbp),%eax
  lea    0x3ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xa,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t _SysCtlFrequencyGet(uint32_t ui32Xtal) {
  uint32_t ui32Result;
  uint_fast16_t ui16F1, ui16F2;
  uint_fast16_t ui16PInt, ui16PFract;
  uint_fast8_t ui8Q, ui8N;
  ui16PFract = (((*((volatile uint32_t *)(0x400FE160))) & 0x000FFC00) >> 10);
  ui16PInt = (*((volatile uint32_t *)(0x400FE160))) & 0x000003FF;
  ui8Q = ((((*((volatile uint32_t *)(0x400FE164))) & 0x00001F00) >> 8) + 1);
  ui8N = ((((*((volatile uint32_t *)(0x400FE164))) & 0x0000001F) >> 0) + 1);
  ui32Xtal /= (uint32_t)ui8N;
  ui16F1 = ui16PFract / 32;
  ui16F2 = ui16PFract - (ui16F1 * 32);
  ui32Result = ui32Xtal * (uint32_t)ui16PInt;
  ui32Result += (ui32Xtal * (uint32_t)ui16F1) / 32;
  ui32Result += (ui32Xtal * (uint32_t)ui16F2) / 1024;
  ui32Result = ui32Result / (uint32_t)ui8Q;
  return (ui32Result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_SysCtlFrequencyGet>:
  endbr64
  mov    %edi,%eax
  mov    0x400fe160,%esi
  sar    $0xa,%esi
  mov    0x400fe160,%r9d
  mov    0x400fe164,%ecx
  mov    0x400fe164,%r8d
  and    $0x1f,%r8d
  add    $0x1,%r8d
  cltd
  idiv   %r8d
  and    $0x3ff,%r9d
  imul   %eax,%r9d
  mov    %esi,%r8d
  and    $0x3ff,%r8d
  sar    $0x5,%r8d
  imul   %eax,%r8d
  lea    0x1f(%r8),%edx
  test   %r8d,%r8d
  cmovns %r8d,%edx
  sar    $0x5,%edx
  add    %r9d,%edx
  and    $0x1f,%esi
  mov    %esi,%edi
  imul   %eax,%edi
  lea    0x3ff(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0xa,%eax
  add    %edx,%eax
  sar    $0x8,%ecx
  and    $0x1f,%ecx
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  ret
```

assistant: ```c
uint32_t _SysCtlFrequencyGet(uint32_t ui32Xtal) {
  uint32_t ui32Result;
  uint_fast16_t ui16F1, ui16F2;
  uint_fast16_t ui16PInt, ui16PFract;
  uint_fast8_t ui8Q, ui8N;
  ui16PFract = (((*((volatile uint32_t *)(0x400FE160))) & 0x000FFC00) >> 10);
  ui16PInt = (*((volatile uint32_t *)(0x400FE160))) & 0x000003FF;
  ui8Q = ((((*((volatile uint32_t *)(0x400FE164))) & 0x00001F00) >> 8) + 1);
  ui8N = ((((*((volatile uint32_t *)(0x400FE164))) & 0x0000001F) >> 0) + 1);
  ui32Xtal /= (uint32_t)ui8N;
  ui16F1 = ui16PFract / 32;
  ui16F2 = ui16PFract - (ui16F1 * 32);
  ui32Result = ui32Xtal * (uint32_t)ui16PInt;
  ui32Result += (ui32Xtal * (uint32_t)ui16F1) / 32;
  ui32Result += (ui32Xtal * (uint32_t)ui16F2) / 1024;
  ui32Result = ui32Result / (uint32_t)ui8Q;
  return (ui32Result);
}
```