ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<utf8_strwidth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L10
  mov    %rdi,%r14
  mov    %esi,%ebp
  lea    0x4(%rsp),%r13
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L31:
  mov    %r14,%rdi
  mov    %r13,%rsi
  call   <utf8_tounicode@plt>
  mov    0x4(%rsp),%edi
  movslq %eax,%rbx
  call   <utf8_width@plt>
  add    %rbx,%r14
  add    %eax,%r12d
  sub    $0x1,%ebp
  jne    L31
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r12d,%r12d
  jmp    L36
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utf8_strwidth(const char *str, int charlen) {
  int width = 0;
  while (charlen) {
    int c;
    int l = utf8_tounicode(str, &c);
    width += utf8_width(c);
    str += l;
    charlen--;
  }
  return width;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa,%edi
  call   <factorial_recursion@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <factorial_iteration@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <Big_factorial_iteration@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7:  %d 


assistant: ```c
int main() {
  printf(" %d \n", factorial_recursion(10));
  printf(" %d \n", factorial_iteration(10));
  Big_factorial_iteration(20);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <factorial_recursion@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <factorial_iteration@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <Big_factorial_iteration@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2:  %d 


assistant: ```c
int main() {
  printf(" %d \n", factorial_recursion(10));
  printf(" %d \n", factorial_iteration(10));
  Big_factorial_iteration(20);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  lea    D4(%rip),%rbp
  call   <factorial_recursion@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <factorial_iteration@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <Big_factorial_iteration@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4:  %d 


assistant: ```c
int main() {
  printf(" %d \n", factorial_recursion(10));
  printf(" %d \n", factorial_iteration(10));
  Big_factorial_iteration(20);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  lea    D8(%rip),%rbp
  call   <factorial_recursion@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <factorial_iteration@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <Big_factorial_iteration@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8:  %d 


assistant: ```c
int main() {
  printf(" %d \n", factorial_recursion(10));
  printf(" %d \n", factorial_iteration(10));
  Big_factorial_iteration(20);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L12:
  mov    $0x0,%eax
  call   <displayMenu@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L52
  mov    $0x0,%eax
  call   <printWhile@plt>
  jmp    L63
L52:
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  je     L63
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  je     L63
  mov    -0xc(%rbp),%eax
  cmp    $0x4,%eax
  je     L63
  mov    $0x0,%eax
  jmp    L67
L63:
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  jne    L12
  mov    $0x0,%eax
L67:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: %d

assistant: ```c
int main() {
  int choice;
  do {
    displayMenu();
    scanf("%d", &choice);
    if (choice == 1) {
      printWhile();
    } else if (choice == 2) {
    } else if (choice == 3) {
    } else if (choice == 4) {
    } else
      return 0;
  } while (choice != 10);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rbx
  jmp    L43
L41:
  mov    $0x0,%eax
  call   <printWhile@plt>
L46:
  cmpl   $0xa,0x4(%rsp)
  je     L4
L43:
  mov    $0x0,%eax
  call   <displayMenu@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L41
  sub    $0x2,%eax
  cmp    $0x2,%eax
  jbe    L46
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main() {
  int choice;
  do {
    displayMenu();
    scanf("%d", &choice);
    if (choice == 1) {
      printWhile();
    } else if (choice == 2) {
    } else if (choice == 3) {
    } else if (choice == 4) {
    } else
      return 0;
  } while (choice != 10);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L8:
  lea    -0x2(%rax),%edx
  cmp    $0x2,%edx
  ja     L51
  cmp    $0xa,%eax
  je     L51
L28:
  xor    %eax,%eax
  call   <displayMenu@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L8
  xor    %eax,%eax
  call   <printWhile@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xa,%eax
  jne    L28
  nopl   0x0(%rax,%rax,1)
L51:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int choice;
  do {
    displayMenu();
    scanf("%d", &choice);
    if (choice == 1) {
      printWhile();
    } else if (choice == 2) {
    } else if (choice == 3) {
    } else if (choice == 4) {
    } else
      return 0;
  } while (choice != 10);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L18:
  lea    -0x2(%rax),%edx
  cmp    $0x2,%edx
  ja     L41
  cmp    $0xa,%eax
  je     L41
L11:
  xor    %eax,%eax
  call   <displayMenu@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L18
  xor    %eax,%eax
  call   <printWhile@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xa,%eax
  jne    L11
  nopl   0x0(%rax,%rax,1)
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: %d

assistant: ```c
int main() {
  int choice;
  do {
    displayMenu();
    scanf("%d", &choice);
    if (choice == 1) {
      printWhile();
    } else if (choice == 2) {
    } else if (choice == 3) {
    } else if (choice == 4) {
    } else
      return 0;
  } while (choice != 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: Hello, Sailor!


assistant: ```c
int main() {
  printf("Hello, Sailor!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: Hello, Sailor!


assistant: ```c
int main() {
  printf("Hello, Sailor!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: Hello, Sailor!


assistant: ```c
int main() {
  printf("Hello, Sailor!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D2: Hello, Sailor!


assistant: ```c
int main() {
  printf("Hello, Sailor!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uart_send_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L7
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_send_byte@plt>
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_send_word(char *string) {
  while (*string != '\0') {
    uart_send_byte(*string);
    string++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uart_send_word>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L18:
  movsbl %dil,%edi
  call   <uart_send_byte@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L19:
  pop    %rbx
  ret
```

assistant: ```c
void uart_send_word(char *string) {
  while (*string != '\0') {
    uart_send_byte(*string);
    string++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uart_send_word>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L16:
  call   <uart_send_byte@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L16
L5:
  pop    %rbx
  ret
```

assistant: ```c
void uart_send_word(char *string) {
  while (*string != '\0') {
    uart_send_byte(*string);
    string++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uart_send_word>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L7:
  call   <uart_send_byte@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L5:
  pop    %rbx
  ret
```

assistant: ```c
void uart_send_word(char *string) {
  while (*string != '\0') {
    uart_send_byte(*string);
    string++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<afrqfreq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  mov    %esi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x40(%rbp),%rbx
  mov    -0x48(%rbp),%r12
  mov    -0x50(%rbp),%r14
  mov    $0x0,%r13d
  jmp    L12
L7:
  movsd  (%rbx),%xmm0
  movsd  D1(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12)
  mov    %r14,%rax
  lea    0x4(%rax),%r14
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rbx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%r12
  add    $0x1,%r13d
L12:
  cmp    -0x2c(%rbp),%r13d
  jl     L7
  mov    $0x0,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: byte[8]

tool: {"D1": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
int afrqfreq(dummy, nafrq, safrq, sfreq, afrq, freq, stat)
double dummy;
int nafrq, safrq, sfreq;
const double afrq[];
double freq[];
int stat[];
{
  register int iafrq, *statp;
  register const double *afrqp;
  register double *freqp;
  (void)dummy;
  afrqp = afrq;
  freqp = freq;
  statp = stat;
  for (iafrq = 0; iafrq < nafrq; iafrq++) {
    *freqp = (*afrqp) / (2.0 * 3.141592653589793238462643);
    *(statp++) = 0;
    afrqp += safrq;
    freqp += sfreq;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<afrqfreq>:
  endbr64
  mov    %rcx,%rax
  test   %edi,%edi
  jle    L9
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%rcx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  mov    %edi,%edi
  lea    (%r9,%rdi,4),%rsi
  movsd  D3(%rip),%xmm1
L11:
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8)
  add    $0x4,%r9
  movl   $0x0,-0x4(%r9)
  add    %rcx,%rax
  add    %rdx,%r8
  cmp    %rsi,%r9
  jne    L11
L9:
  mov    $0x0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: byte[8]

tool: {"D3": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
int afrqfreq(dummy, nafrq, safrq, sfreq, afrq, freq, stat)
double dummy;
int nafrq, safrq, sfreq;
const double afrq[];
double freq[];
int stat[];
{
  register int iafrq, *statp;
  register const double *afrqp;
  register double *freqp;
  (void)dummy;
  afrqp = afrq;
  freqp = freq;
  statp = stat;
  for (iafrq = 0; iafrq < nafrq; iafrq++) {
    *freqp = (*afrqp) / (2.0 * 3.141592653589793238462643);
    *(statp++) = 0;
    afrqp += safrq;
    freqp += sfreq;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<afrqfreq>:
  endbr64
  mov    %rcx,%rax
  test   %edi,%edi
  jle    L3
  movslq %esi,%rsi
  movslq %edx,%rdx
  movslq %edi,%rdi
  movsd  D4(%rip),%xmm1
  lea    0x0(,%rsi,8),%rcx
  shl    $0x3,%rdx
  lea    (%r9,%rdi,4),%rsi
  nopl   0x0(%rax)
L16:
  movsd  (%rax),%xmm0
  add    $0x4,%r9
  add    %rcx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8)
  add    %rdx,%r8
  movl   $0x0,-0x4(%r9)
  cmp    %rsi,%r9
  jne    L16
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: byte[8]

tool: {"D4": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
int afrqfreq(dummy, nafrq, safrq, sfreq, afrq, freq, stat)
double dummy;
int nafrq, safrq, sfreq;
const double afrq[];
double freq[];
int stat[];
{
  register int iafrq, *statp;
  register const double *afrqp;
  register double *freqp;
  (void)dummy;
  afrqp = afrq;
  freqp = freq;
  statp = stat;
  for (iafrq = 0; iafrq < nafrq; iafrq++) {
    *freqp = (*afrqp) / (2.0 * 3.141592653589793238462643);
    *(statp++) = 0;
    afrqp += safrq;
    freqp += sfreq;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<useit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,D2(%rip)
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sum_upto@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int useit(val) {
  static int usedval;
  usedval = val;
  return val + sum_upto(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<useit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sum_upto@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int useit(val) {
  static int usedval;
  usedval = val;
  return val + sum_upto(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<useit>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <sum_upto@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int useit(val) {
  static int usedval;
  usedval = val;
  return val + sum_upto(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<useit>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <sum_upto@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int useit(val) {
  static int usedval;
  usedval = val;
  return val + sum_upto(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa,%edi
  call   <squareOf@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: square of 10: %d


assistant: ```c
int main(void) {
  printf("square of 10: %d\n", squareOf(10));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <squareOf@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D2: square of 10: %d


assistant: ```c
int main(void) {
  printf("square of 10: %d\n", squareOf(10));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <squareOf@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: square of 10: %d


assistant: ```c
int main(void) {
  printf("square of 10: %d\n", squareOf(10));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <squareOf@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: square of 10: %d


assistant: ```c
int main(void) {
  printf("square of 10: %d\n", squareOf(10));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<const_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <mult_sum@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <mult_sum@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xf,%edi
  call   <mult_sum@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long const_time(unsigned long long max) {
  unsigned long long three_sum;
  unsigned long long five_sum;
  unsigned long long common_sum;
  max -= 1;
  three_sum = mult_sum(3, max);
  five_sum = mult_sum(5, max);
  common_sum = mult_sum(3 * 5, max);
  return three_sum + five_sum - common_sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<const_time>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%rbp
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <mult_sum@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    $0x5,%edi
  call   <mult_sum@plt>
  mov    %rax,%r12
  mov    %rbp,%rsi
  mov    $0xf,%edi
  call   <mult_sum@plt>
  mov    %rax,%rdx
  lea    (%rbx,%r12,1),%rax
  sub    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long const_time(unsigned long long max) {
  unsigned long long three_sum;
  unsigned long long five_sum;
  unsigned long long common_sum;
  max -= 1;
  three_sum = mult_sum(3, max);
  five_sum = mult_sum(5, max);
  common_sum = mult_sum(3 * 5, max);
  return three_sum + five_sum - common_sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<const_time>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x1(%rdi),%rbp
  mov    $0x3,%edi
  push   %rbx
  mov    %rbp,%rsi
  call   <mult_sum@plt>
  mov    %rbp,%rsi
  mov    $0x5,%edi
  mov    %rax,%rbx
  call   <mult_sum@plt>
  mov    %rbp,%rsi
  mov    $0xf,%edi
  mov    %rax,%r12
  call   <mult_sum@plt>
  mov    %rax,%r8
  lea    (%rbx,%r12,1),%rax
  pop    %rbx
  pop    %rbp
  sub    %r8,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned long long const_time(unsigned long long max) {
  unsigned long long three_sum;
  unsigned long long five_sum;
  unsigned long long common_sum;
  max -= 1;
  three_sum = mult_sum(3, max);
  five_sum = mult_sum(5, max);
  common_sum = mult_sum(3 * 5, max);
  return three_sum + five_sum - common_sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<const_time>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x1(%rdi),%rbp
  mov    $0x3,%edi
  push   %rbx
  mov    %rbp,%rsi
  call   <mult_sum@plt>
  mov    %rbp,%rsi
  mov    $0x5,%edi
  mov    %rax,%rbx
  call   <mult_sum@plt>
  mov    %rbp,%rsi
  mov    $0xf,%edi
  mov    %rax,%r12
  call   <mult_sum@plt>
  mov    %rax,%r8
  lea    (%rbx,%r12,1),%rax
  pop    %rbx
  pop    %rbp
  sub    %r8,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned long long const_time(unsigned long long max) {
  unsigned long long three_sum;
  unsigned long long five_sum;
  unsigned long long common_sum;
  max -= 1;
  three_sum = mult_sum(3, max);
  five_sum = mult_sum(5, max);
  common_sum = mult_sum(3 * 5, max);
  return three_sum + five_sum - common_sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<same_sgn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L22
  cmpq   $0x0,-0x10(%rbp)
  js     L22
  mov    $0x1,%eax
  jmp    L41
L22:
  cmpq   $0x0,-0x8(%rbp)
  jns    L24
  cmpq   $0x0,-0x10(%rbp)
  jns    L24
  mov    $0xffffffff,%eax
  jmp    L41
L24:
  mov    $0x0,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
int same_sgn(int64_t a, int64_t b) {
  if (a >= 0 && b >= 0)
    return 1;
  if (a < 0 && b < 0)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<same_sgn>:
  endbr64
  mov    $0x1,%eax
  mov    %rdi,%rdx
  or     %rsi,%rdx
  jns    L8
  and    %rsi,%rdi
  sar    $0x3f,%rdi
  mov    %rdi,%rax
L8:
  ret
```

assistant: ```c
int same_sgn(int64_t a, int64_t b) {
  if (a >= 0 && b >= 0)
    return 1;
  if (a < 0 && b < 0)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<same_sgn>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%eax
  or     %rsi,%rdx
  jns    L0
  and    %rsi,%rdi
  sar    $0x3f,%rdi
  mov    %rdi,%rax
L0:
  ret
```

assistant: ```c
int same_sgn(int64_t a, int64_t b) {
  if (a >= 0 && b >= 0)
    return 1;
  if (a < 0 && b < 0)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<same_sgn>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%eax
  or     %rsi,%rdx
  jns    L3
  and    %rsi,%rdi
  sar    $0x3f,%rdi
  mov    %rdi,%rax
L3:
  ret
```

assistant: ```c
int same_sgn(int64_t a, int64_t b) {
  if (a >= 0 && b >= 0)
    return 1;
  if (a < 0 && b < 0)
    return -1;
  return 0;
}
```