ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_negative>:
  endbr64
  push   %r12
  mov    $0x4,%ecx
  mov    $0x4,%esi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xfffffffefffffffd,%rax
  lea    0x10(%rsp),%rbp
  mov    %rsp,%r12
  mov    %rbp,%rdx
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  mov    $0xffffffff,%eax
  mov    %rax,0x8(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x18(%rsp)
  call   <median@plt>
  ucomisd D19(%rip),%xmm0
  jp     L77
  je     L44
L77:
  xor    %eax,%eax
L52:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    $0x4,%ecx
  mov    %r12,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <median@plt>
  ucomisd D19(%rip),%xmm0
  jp     L77
  jne    L77
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <median_opt@plt>
  ucomisd D19(%rip),%xmm0
  jp     L77
  jne    L77
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <median_opt@plt>
  xor    %eax,%eax
  ucomisd D19(%rip),%xmm0
  mov    $0x0,%edx
  setnp  %al
  cmovne %edx,%eax
  jmp    L52
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type_guessed: f64

tool: D19: 0.5

assistant: ```c
int test_negative() {
  int a[] = {-3, -2, -1, 0};
  int b[] = {1, 2, 3, 4};
  return 0.5 == median(a, 4, b, 4) && 0.5 == median(b, 4, a, 4) && 0.5 == median_opt(a, b, 4) && 0.5 == median_opt(b, a, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_negative>:
  endbr64
  push   %r12
  mov    $0x4,%ecx
  mov    $0x4,%esi
  push   %rbp
  sub    $0x38,%rsp
  movdqa D38(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D47(%rip),%xmm0
  mov    %rbp,%rdx
  mov    %r12,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <median@plt>
  ucomisd D45(%rip),%xmm0
  jp     L10
  je     L16
L10:
  xor    %eax,%eax
L5:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x4,%ecx
  mov    %r12,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <median@plt>
  ucomisd D45(%rip),%xmm0
  jp     L10
  jne    L10
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <median_opt@plt>
  ucomisd D45(%rip),%xmm0
  jp     L10
  jne    L10
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <median_opt@plt>
  xor    %eax,%eax
  ucomisd D45(%rip),%xmm0
  mov    $0x0,%edx
  setnp  %al
  cmovne %edx,%eax
  jmp    L5
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_tag: D47
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_tag: D45
type_guessed: f64

tool: {"D38": [0xfd,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00]}

tool: {"D47": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D45: 0.5

assistant: ```c
int test_negative() {
  int a[] = {-3, -2, -1, 0};
  int b[] = {1, 2, 3, 4};
  return 0.5 == median(a, 4, b, 4) && 0.5 == median(b, 4, a, 4) && 0.5 == median_opt(a, b, 4) && 0.5 == median_opt(b, a, 4);
}
```
user: What is the c source code of the assembly code below?

```asm
<du>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  jmp    L3
L16:
  addq   $0x1,-0x10(%rbp)
L3:
  lea    -0x11(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L16
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
long long du(int fd) {
  char c;
  long long ll = 0;
  while (read(fd, &c, 1) == 1) {
    ll++;
  }
  return (ll);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<du>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x7(%rsp),%r12
  jmp    L11
L1:
  add    $0x1,%rbx
L11:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long du(int fd) {
  char c;
  long long ll = 0;
  while (read(fd, &c, 1) == 1) {
    ll++;
  }
  return (ll);
}
```
user: Translate the below assembly code into C programming language:

```asm
<du>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12
L21:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long du(int fd) {
  char c;
  long long ll = 0;
  while (read(fd, &c, 1) == 1) {
    ll++;
  }
  return (ll);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<du>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12
L23:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long du(int fd) {
  char c;
  long long ll = 0;
  while (read(fd, &c, 1) == 1) {
    ll++;
  }
  return (ll);
}
```
user: What is the c source code of the assembly code below?

```asm
<bench_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  movl   $0x15180,-0x2c(%rbp)
  movl   $0xe10,-0x28(%rbp)
  movl   $0x3c,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x10(%rbp),%rax
  cqto
  idiv   %rsi
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdi
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rdi
  mov    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L25
  lea    D41(%rip),%rcx
  jmp    L74
L25:
  lea    D80(%rip),%rcx
L74:
  cmpl   $0x1,-0x18(%rbp)
  jle    L64
  lea    D41(%rip),%rdx
  jmp    L65
L64:
  lea    D80(%rip),%rdx
L65:
  cmpl   $0x1,-0x1c(%rbp)
  jle    L50
  lea    D41(%rip),%rsi
  jmp    L77
L50:
  lea    D80(%rip),%rsi
L77:
  cmpl   $0x1,-0x20(%rbp)
  jle    L27
  lea    D41(%rip),%rax
  jmp    L7
L27:
  lea    D80(%rip),%rax
L7:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%r10d
  mov    -0x20(%rbp),%edi
  sub    $0x8,%rsp
  push   %rcx
  mov    -0x14(%rbp),%ecx
  push   %rcx
  push   %rdx
  mov    %r8d,%r9d
  mov    %rsi,%r8
  mov    %r10d,%ecx
  mov    %rax,%rdx
  mov    %edi,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D41
type_infered: string
name: extract_symbolic_data
arguments: data_label: D80
type_infered: string
name: extract_symbolic_data
arguments: data_label: D32
type_infered: string

tool: D41: s

tool: 

tool: D32: Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s



assistant: ```c
void bench_time(time_t t) {
  const int one_day = 86400;
  const int one_hour = 3600;
  const int one_min = 60;
  int days;
  int hours;
  int minutes;
  int seconds;
  long int upmind;
  long int upminh;
  days = t / one_day;
  upmind = t - (days * one_day);
  hours = upmind / one_hour;
  upminh = upmind - hours * one_hour;
  minutes = upminh / one_min;
  seconds = upminh - minutes * one_min;
  printf("Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s\n\n", days, (days > 1) ? "s" : "", hours, (hours > 1) ? "s" : "", minutes, (minutes > 1) ? "s" : "", seconds, (seconds > 1) ? "s" : "");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bench_time>:
  endbr64
  sub    $0x10,%rsp
  mov    %edi,%esi
  movslq %edi,%rax
  imul   $0xffffffffc22e4507,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x10,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  imul   $0xfffeae80,%eax,%ecx
  add    %esi,%ecx
  movslq %ecx,%rcx
  movabs $0x48d159e26af37c05,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0xa,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%r8
  mov    %edx,%r10d
  imul   $0xe10,%edx,%eax
  cltq
  sub    %rax,%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  imul   %rdx
  add    %rcx,%rdx
  sar    $0x5,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  cmp    $0x1,%ecx
  lea    D19(%rip),%r11
  lea    D65(%rip),%rax
  cmovle %rax,%r11
  cmp    $0x1,%edx
  lea    D19(%rip),%r9
  cmovle %rax,%r9
  cmp    $0x1,%r8d
  lea    D19(%rip),%r8
  cmovle %rax,%r8
  cmp    $0x2a2ff,%esi
  lea    D19(%rip),%rax
  lea    D65(%rip),%rsi
  cmovle %rsi,%rax
  push   %r11
  push   %rcx
  push   %r9
  mov    %edx,%r9d
  mov    %r10d,%ecx
  mov    %rax,%rdx
  mov    %edi,%esi
  lea    D61(%rip),%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D65
data_type: string
name: disassemble_data
arguments: tag: D61
data_type: string

tool: D19: s

tool: 

tool: D61: Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s



assistant: ```c
void bench_time(time_t t) {
  const int one_day = 86400;
  const int one_hour = 3600;
  const int one_min = 60;
  int days;
  int hours;
  int minutes;
  int seconds;
  long int upmind;
  long int upminh;
  days = t / one_day;
  upmind = t - (days * one_day);
  hours = upmind / one_hour;
  upminh = upmind - hours * one_hour;
  minutes = upminh / one_min;
  seconds = upminh - minutes * one_min;
  printf("Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s\n\n", days, (days > 1) ? "s" : "", hours, (hours > 1) ? "s" : "", minutes, (minutes > 1) ? "s" : "", seconds, (seconds > 1) ? "s" : "");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bench_time>:
  endbr64
  movabs $0x48d159e26af37c05,%rdx
  movslq %edi,%rsi
  mov    %edi,%eax
  push   %rbp
  imul   $0xffffffffc22e4507,%rsi,%rsi
  sar    $0x1f,%eax
  push   %rbx
  shr    $0x20,%rsi
  sub    $0x10,%rsp
  add    %edi,%esi
  sar    $0x10,%esi
  sub    %eax,%esi
  imul   $0xfffeae80,%esi,%ecx
  add    %edi,%ecx
  movslq %ecx,%rcx
  mov    %rcx,%rax
  mov    %rcx,%r8
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0xa,%rdx
  sub    %rax,%rdx
  mov    %edx,%r10d
  imul   $0xe10,%edx,%edx
  movslq %edx,%rdx
  sub    %rdx,%r8
  movabs $0x8888888888888889,%rdx
  mov    %r8,%rax
  mov    %r8d,%r11d
  imul   %rdx
  mov    %r8,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%r8,1),%r9
  lea    D11(%rip),%rdx
  sar    $0x5,%r9
  mov    %rdx,%rbx
  sub    %rax,%r9
  imul   $0x3c,%r9d,%eax
  sub    %eax,%r11d
  lea    D24(%rip),%rax
  cmp    $0x1,%r11d
  mov    %rax,%rbp
  cmovg  %rdx,%rbp
  cmp    $0x78,%r8
  mov    %rdx,%r8
  cmovl  %rax,%rbx
  cmp    $0x1c20,%rcx
  mov    %r10d,%ecx
  push   %rbp
  cmovl  %rax,%r8
  cmp    $0x2a2ff,%edi
  push   %r11
  cmovle %rax,%rdx
  lea    D17(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D24
type: string
name: retrieve_data
arguments: tag: D17
type: string

tool: D11: s

tool: 

tool: D17: Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s



assistant: ```c
void bench_time(time_t t) {
  const int one_day = 86400;
  const int one_hour = 3600;
  const int one_min = 60;
  int days;
  int hours;
  int minutes;
  int seconds;
  long int upmind;
  long int upminh;
  days = t / one_day;
  upmind = t - (days * one_day);
  hours = upmind / one_hour;
  upminh = upmind - hours * one_hour;
  minutes = upminh / one_min;
  seconds = upminh - minutes * one_min;
  printf("Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s\n\n", days, (days > 1) ? "s" : "", hours, (hours > 1) ? "s" : "", minutes, (minutes > 1) ? "s" : "", seconds, (seconds > 1) ? "s" : "");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bench_time>:
  endbr64
  movabs $0x48d159e26af37c05,%rdx
  movslq %edi,%rsi
  mov    %edi,%eax
  push   %rbp
  imul   $0xffffffffc22e4507,%rsi,%rsi
  sar    $0x1f,%eax
  push   %rbx
  shr    $0x20,%rsi
  sub    $0x10,%rsp
  add    %edi,%esi
  sar    $0x10,%esi
  sub    %eax,%esi
  imul   $0xfffeae80,%esi,%ecx
  add    %edi,%ecx
  movslq %ecx,%rcx
  mov    %rcx,%rax
  mov    %rcx,%r8
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0xa,%rdx
  sub    %rax,%rdx
  mov    %edx,%r10d
  imul   $0xe10,%edx,%edx
  movslq %edx,%rdx
  sub    %rdx,%r8
  movabs $0x8888888888888889,%rdx
  mov    %r8,%rax
  mov    %r8d,%r11d
  imul   %rdx
  mov    %r8,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%r8,1),%r9
  lea    D1(%rip),%rdx
  sar    $0x5,%r9
  mov    %rdx,%rbx
  sub    %rax,%r9
  imul   $0x3c,%r9d,%eax
  sub    %eax,%r11d
  lea    D17(%rip),%rax
  cmp    $0x1,%r11d
  mov    %rax,%rbp
  cmovg  %rdx,%rbp
  cmp    $0x78,%r8
  mov    %rdx,%r8
  cmovl  %rax,%rbx
  cmp    $0x1c20,%rcx
  mov    %r10d,%ecx
  push   %rbp
  cmovl  %rax,%r8
  cmp    $0x2a2ff,%edi
  push   %r11
  cmovle %rax,%rdx
  lea    D18(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string

tool: D1: s

tool: 

tool: D18: Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s



assistant: ```c
void bench_time(time_t t) {
  const int one_day = 86400;
  const int one_hour = 3600;
  const int one_min = 60;
  int days;
  int hours;
  int minutes;
  int seconds;
  long int upmind;
  long int upminh;
  days = t / one_day;
  upmind = t - (days * one_day);
  hours = upmind / one_hour;
  upminh = upmind - hours * one_hour;
  minutes = upminh / one_min;
  seconds = upminh - minutes * one_min;
  printf("Elapsed time: %i day%s, %i hour%s, %i minute%s and %i second%s\n\n", days, (days > 1) ? "s" : "", hours, (hours > 1) ? "s" : "", minutes, (minutes > 1) ? "s" : "", seconds, (seconds > 1) ? "s" : "");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wildsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L58
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L42
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L33
L12:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  jmp    L5
L42:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L5:
  addq   $0x1,-0x18(%rbp)
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D2(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *wildsub(char *pat, char *stem) {
  static char temp[100];
  char *s, *t;
  s = temp;
  for (; *pat; ++pat)
    if (*pat == '%')
      for (t = stem; *t;)
        *s++ = *t++;
    else
      *s++ = *pat;
  *s = '\0';
  return temp;
}
```
user: What is the c source code of the assembly code below?

```asm
<wildsub>:
  endbr64
  movzbl (%rdi),%edx
  lea    D18(%rip),%rax
  test   %dl,%dl
  jne    L36
L44:
  movb   $0x0,(%rax)
  lea    D18(%rip),%rax
  ret
L25:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L5
  mov    %rsi,%rcx
L55:
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L55
L5:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L44
L36:
  cmp    $0x25,%dl
  je     L25
  mov    %dl,(%rax)
  lea    0x1(%rax),%rax
  jmp    L5
```

assistant: ```c
char *wildsub(char *pat, char *stem) {
  static char temp[100];
  char *s, *t;
  s = temp;
  for (; *pat; ++pat)
    if (*pat == '%')
      for (t = stem; *t;)
        *s++ = *t++;
    else
      *s++ = *pat;
  *s = '\0';
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wildsub>:
  endbr64
  movzbl (%rdi),%edx
  lea    D5(%rip),%r8
  mov    %r8,%rax
  test   %dl,%dl
  jne    L21
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %dl,(%rax)
  add    $0x1,%rax
L54:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L63
L21:
  cmp    $0x25,%dl
  jne    L40
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L54
  mov    %rsi,%rcx
  nopl   0x0(%rax)
L45:
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L45
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L21
L63:
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *wildsub(char *pat, char *stem) {
  static char temp[100];
  char *s, *t;
  s = temp;
  for (; *pat; ++pat)
    if (*pat == '%')
      for (t = stem; *t;)
        *s++ = *t++;
    else
      *s++ = *pat;
  *s = '\0';
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wildsub>:
  endbr64
  movzbl (%rdi),%edx
  lea    D6(%rip),%r8
  mov    %r8,%rax
  test   %dl,%dl
  jne    L31
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %dl,(%rax)
  add    $0x1,%rax
L16:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L61
L31:
  cmp    $0x25,%dl
  jne    L7
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L16
  mov    %rsi,%rcx
  nopl   0x0(%rax)
L45:
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L45
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L31
L61:
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *wildsub(char *pat, char *stem) {
  static char temp[100];
  char *s, *t;
  s = temp;
  for (; *pat; ++pat)
    if (*pat == '%')
      for (t = stem; *t;)
        *s++ = *t++;
    else
      *s++ = *pat;
  *s = '\0';
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy1r_smatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x40(%rbp),%rsi
  mov    %rdx,%rcx
  mov    0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   <dup_svector@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void copy1r_smatrix(short **X, long nr, short **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    dup_svector(X[nr], ncl, nch, Y[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<copy1r_smatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  mov    0x40(%rsp),%r14
  movslq %ecx,%rdx
  cmp    %rdx,%r8
  jl     L0
  mov    %r8,%rbp
  mov    %r9,%r13
  lea    (%rdi,%rsi,8),%r15
  mov    %rdx,%rbx
L10:
  mov    (%r12,%rbx,8),%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    (%r15),%rdi
  call   <dup_svector@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L10
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy1r_smatrix(short **X, long nr, short **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    dup_svector(X[nr], ncl, nch, Y[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy1r_smatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r13
  cmp    %rbx,%r8
  jl     L6
  mov    %rdx,%r15
  mov    %r8,%rbp
  lea    (%rdi,%rsi,8),%r14
  mov    %r9,%r12
  nopl   0x0(%rax)
L9:
  mov    (%r15,%rbx,8),%rcx
  mov    (%r14),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <dup_svector@plt>
  cmp    %rbx,%rbp
  jge    L9
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy1r_smatrix(short **X, long nr, short **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    dup_svector(X[nr], ncl, nch, Y[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy1r_smatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r13
  cmp    %rbx,%r8
  jl     L17
  mov    %rdx,%r15
  mov    %r8,%rbp
  lea    (%rdi,%rsi,8),%r14
  mov    %r9,%r12
  nopl   0x0(%rax)
L0:
  mov    (%r15,%rbx,8),%rcx
  mov    (%r14),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <dup_svector@plt>
  cmp    %rbx,%rbp
  jge    L0
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy1r_smatrix(short **X, long nr, short **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    dup_svector(X[nr], ncl, nch, Y[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L8
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    $0x0,%eax
  jmp    L36
L10:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L28
  mov    $0x1,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while ((*a) == (*b)) {
    if (*a == 0)
      return 0;
    a++;
    b++;
  };
  return 1;
}
```