user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    0x50(%rsi),%rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  sub    $0x118,%rsp
  mov    (%rsi),%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  jne    L219
  nopl   0x0(%rax)
L191:
  mov    -0x8(%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2d,%edx
  jne    L186
  cmpb   $0x63,0x1(%rax)
  je     L228
L184:
  cmp    $0x2d,%edx
  jne    L186
  cmpb   $0x6d,0x1(%rax)
  je     L58
L100:
  cmp    $0x2d,%edx
  jne    L186
  cmpb   $0x73,0x1(%rax)
  je     L143
L29:
  cmp    $0x2d,%edx
  je     L35
  nopl   (%rax)
L186:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L191
L185:
  lea    0x9(%rsp),%rbx
  mov    %rsp,%rbp
  mov    %r13,%rsi
  movb   $0x20,0x8(%rsp)
  movabs $0x692d20636e652f2e,%rax
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x2070,%ecx
  movdqa D33(%rip),%xmm0
  mov    %r15,%rsi
  lea    0x0(%rbp,%rax,1),%rdx
  lea    0x12(%rbp,%rax,1),%rdi
  mov    %cx,0x10(%rdx)
  movups %xmm0,(%rdx)
  call   <strcpy@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <system@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movb   $0x20,0x8(%rsp)
  movabs $0x632d20626d652f2e,%rax
  mov    %rax,(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x2073,%esi
  movdqa D3(%rip),%xmm0
  lea    0x0(%rbp,%rax,1),%rdx
  lea    0x12(%rbp,%rax,1),%rdi
  mov    %si,0x10(%rdx)
  mov    %r14,%rsi
  movups %xmm0,(%rdx)
  call   <strcpy@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <system@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <system@plt>
L188:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L227
  add    $0x118,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L228:
  cmpb   $0x0,0x2(%rax)
  jne    L184
  mov    $0x9,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    -0x8(%rbx),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  cmp    %rbp,%rbx
  jne    L191
  jmp    L185
  nopl   (%rax)
L58:
  cmpb   $0x0,0x2(%rax)
  jne    L100
  mov    $0x9,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    -0x8(%rbx),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  cmp    %rbp,%rbx
  jne    L191
  jmp    L185
L35:
  cmpb   $0x70,0x1(%rax)
  jne    L186
  cmpb   $0x0,0x2(%rax)
  jne    L186
  mov    $0x9,%edi
  call   <malloc@plt>
  mov    (%rbx),%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strcpy@plt>
  jmp    L186
  xchg   %ax,%ax
L143:
  cmpb   $0x0,0x2(%rax)
  jne    L29
  mov    $0x9,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    -0x8(%rbx),%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <strcpy@plt>
  cmp    %rbp,%rbx
  jne    L191
  jmp    L185
L219:
  mov    %r8,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L188
L227:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type_infered: byte[16]
name: extract_symbolic_data
arguments: label: D3
type_infered: byte[16]
name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: string

tool: {"D33": [0x20,0x2d,0x6f,0x20,0x63,0x72,0x79,0x70,0x74,0x6f,0x2e,0x74,0x78,0x74,0x20,0x2d]}

tool: {"D3": [0x20,0x2d,0x6d,0x20,0x63,0x72,0x79,0x70,0x74,0x6f,0x2e,0x74,0x78,0x74,0x20,0x2d]}

tool: D17: rm crypto.txt

tool: D23: usage: %s -c <coverfile (.ppm)> -m <message filename> -s <stegofile> -p <password>


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 9) {
    printf("usage: %s -c <coverfile (.ppm)> -m <message filename> -s <stegofile> -p <password>\n", argv[0]);
    return 0;
  }
  unsigned char *cover;
  unsigned char *message;
  unsigned char *stego;
  unsigned char *password;
  for (int i = 0; i < argc; i++) {
    if (!strcmp(argv[i], "-c")) {
      cover = malloc(sizeof(argv[i + 1]) + 1);
      strcpy(cover, argv[i + 1]);
    } else if (!strcmp(argv[i], "-m")) {
      message = malloc(sizeof(argv[i + 1]) + 1);
      strcpy(message, argv[i + 1]);
    } else if (!strcmp(argv[i], "-s")) {
      stego = malloc(sizeof(argv[i + 1]) + 1);
      strcpy(stego, argv[i + 1]);
    } else if (!strcmp(argv[i], "-p")) {
      password = malloc(sizeof(argv[i + 1]) + 1);
      strcpy(password, argv[i + 1]);
    }
  }
  char cmd[256];
  strcpy(cmd, "./enc -i ");
  strcat(cmd, message);
  strcat(cmd, " -o crypto.txt -p ");
  strcat(cmd, password);
  system(cmd);
  strcpy(cmd, "./emb -c ");
  strcat(cmd, cover);
  strcat(cmd, " -m crypto.txt -s ");
  strcat(cmd, stego);
  system(cmd);
  system("rm crypto.txt");
  return 0;
}
```