ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<mergeRanges>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %ecx,%r12d
  sub    %esi,%r12d
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  cmp    %r14d,%ebp
  jge    L95
  cmp    %r14d,%r13d
  jle    L95
  mov    %r14d,%edx
  mov    %ebp,%ecx
  mov    $0x0,%esi
  jmp    L27
L49:
  mov    %r8d,(%rax)
  add    $0x1,%edx
L26:
  add    $0x1,%esi
  add    $0x4,%rax
  cmp    %r14d,%ecx
  jge    L29
  cmp    %r13d,%edx
  jge    L29
L27:
  movslq %ecx,%r8
  mov    (%rbx,%r8,4),%r9d
  movslq %edx,%r8
  mov    (%rbx,%r8,4),%r8d
  cmp    %r8d,%r9d
  jge    L49
  mov    %r9d,(%rax)
  add    $0x1,%ecx
  jmp    L26
L95:
  mov    %r14d,%edx
  mov    %ebp,%ecx
  mov    $0x0,%esi
L29:
  cmp    %ecx,%r14d
  jle    L127
  movslq %esi,%r10
  lea    (%rdi,%r10,4),%rax
  mov    %ecx,%r8d
  lea    -0x1(%r14),%r9d
  sub    %ecx,%r9d
  add    %r10,%r9
  lea    0x4(%rdi,%r9,4),%r9
  movslq %ecx,%rcx
  sub    %r10,%rcx
  lea    (%rbx,%rcx,4),%r10
  sub    %rdi,%r10
L93:
  mov    (%r10,%rax,1),%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L93
  add    %esi,%r14d
  mov    %r14d,%esi
  sub    %r8d,%esi
L127:
  cmp    %edx,%r13d
  jle    L28
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  sub    $0x1,%r13d
  sub    %edx,%r13d
  add    %rsi,%r13
  lea    0x4(%rdi,%r13,4),%r8
  movslq %edx,%rdx
  shl    $0x2,%rdx
  sub    %rdi,%rdx
  neg    %rsi
  lea    (%rdx,%rsi,4),%rcx
  add    %rbx,%rcx
L46:
  mov    (%rcx,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L46
L28:
  test   %r12d,%r12d
  jle    L107
  mov    %rdi,%rax
  mov    %r12d,%r12d
  lea    (%rdi,%r12,4),%rsi
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,4),%rcx
  sub    %rdi,%rcx
L41:
  mov    (%rax),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L41
L107:
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mergeRanges(int values[], int startIndex, int midPoint, int endIndex) {
  int rangeSize = endIndex - startIndex;
  int *destination = (int *)calloc(rangeSize, sizeof(int));
  int firstIndex = startIndex;
  int secondIndex = midPoint;
  int copyIndex = 0;
  int i = 0;
  while (firstIndex < midPoint && secondIndex < endIndex) {
    if (values[firstIndex] < values[secondIndex]) {
      destination[copyIndex] = values[firstIndex];
      ++firstIndex;
    } else {
      destination[copyIndex] = values[secondIndex];
      ++secondIndex;
    }
    ++copyIndex;
  }
  while (firstIndex < midPoint) {
    destination[copyIndex] = values[firstIndex];
    ++copyIndex;
    ++firstIndex;
  }
  while (secondIndex < endIndex) {
    destination[copyIndex] = values[secondIndex];
    ++copyIndex;
    ++secondIndex;
  }
  for (i = 0; i < rangeSize; ++i) {
    values[i + startIndex] = destination[i];
  }
  free(destination);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buf_get_uint32_be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long buf_get_uint32_be(const void *buf, unsigned long addr) {
  const unsigned char *tmp = (const unsigned char *)buf + addr;
  unsigned long ret;
  ret = tmp[0];
  ret = (ret << 8) | tmp[1];
  ret = (ret << 8) | tmp[2];
  ret = (ret << 8) | tmp[3];
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<buf_get_uint32_be>:
  endbr64
  add    %rsi,%rdi
  movzbl (%rdi),%edx
  shl    $0x8,%rdx
  movzbl 0x1(%rdi),%eax
  or     %rdx,%rax
  shl    $0x8,%rax
  movzbl 0x2(%rdi),%edx
  or     %rax,%rdx
  shl    $0x8,%rdx
  movzbl 0x3(%rdi),%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long buf_get_uint32_be(const void *buf, unsigned long addr) {
  const unsigned char *tmp = (const unsigned char *)buf + addr;
  unsigned long ret;
  ret = tmp[0];
  ret = (ret << 8) | tmp[1];
  ret = (ret << 8) | tmp[2];
  ret = (ret << 8) | tmp[3];
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buf_get_uint32_be>:
  endbr64
  mov    (%rdi,%rsi,1),%eax
  bswap  %eax
  mov    %eax,%eax
  ret
```

assistant: ```c
unsigned long buf_get_uint32_be(const void *buf, unsigned long addr) {
  const unsigned char *tmp = (const unsigned char *)buf + addr;
  unsigned long ret;
  ret = tmp[0];
  ret = (ret << 8) | tmp[1];
  ret = (ret << 8) | tmp[2];
  ret = (ret << 8) | tmp[3];
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<buf_get_uint32_be>:
  endbr64
  mov    (%rdi,%rsi,1),%eax
  bswap  %eax
  mov    %eax,%eax
  ret
```

assistant: ```c
unsigned long buf_get_uint32_be(const void *buf, unsigned long addr) {
  const unsigned char *tmp = (const unsigned char *)buf + addr;
  unsigned long ret;
  ret = tmp[0];
  ret = (ret << 8) | tmp[1];
  ret = (ret << 8) | tmp[2];
  ret = (ret << 8) | tmp[3];
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dcopy_codegen_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x10,-0x8(%rbp)
  movl   $0x10,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L37:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L12
L17:
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L17
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dcopy_codegen_3(double *A, double *C) {
  const int n = 4 + 0 * 40 + 3 * 4;
  const int lda = 4 + 0 * 40 + 3 * 4;
  int ii, jj;
  for (jj = 0; jj < n; jj++) {
    for (ii = jj; ii < n; ii++) {
      C[ii + lda * jj] = A[ii + lda * jj];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dcopy_codegen_3>:
  endbr64
  mov    $0x0,%edx
  jmp    L27
L17:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0xf,%eax
  jle    L17
L24:
  add    $0x1,%rdx
  sub    $0xffffffffffffff80,%rdi
  sub    $0xffffffffffffff80,%rsi
  cmp    $0x10,%rdx
  je     L42
L27:
  mov    %rdx,%rax
  cmp    $0xf,%edx
  jle    L17
  jmp    L24
L42:
  ret
```

assistant: ```c
void dcopy_codegen_3(double *A, double *C) {
  const int n = 4 + 0 * 40 + 3 * 4;
  const int lda = 4 + 0 * 40 + 3 * 4;
  int ii, jj;
  for (jj = 0; jj < n; jj++) {
    for (ii = jj; ii < n; ii++) {
      C[ii + lda * jj] = A[ii + lda * jj];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dcopy_codegen_3>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %rdx,%rax
  nopl   0x0(%rax,%rax,1)
L18:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x10,%eax
  jne    L18
  add    $0x1,%rdx
  sub    $0xffffffffffffff80,%rdi
  sub    $0xffffffffffffff80,%rsi
  cmp    $0x10,%rdx
  jne    L16
  ret
```

assistant: ```c
void dcopy_codegen_3(double *A, double *C) {
  const int n = 4 + 0 * 40 + 3 * 4;
  const int lda = 4 + 0 * 40 + 3 * 4;
  int ii, jj;
  for (jj = 0; jj < n; jj++) {
    for (ii = jj; ii < n; ii++) {
      C[ii + lda * jj] = A[ii + lda * jj];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dcopy_codegen_3>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  lea    0x8(%rdi),%rcx
  mov    %rsi,%rdx
  mov    $0x10,%r8d
  xor    %edi,%edi
  mov    $0xf,%ebx
  jmp    L182
  nopl   0x0(%rax)
L158:
  cmp    %rdx,%rcx
  je     L204
  movupd -0x8(%rcx),%xmm1
  mov    %r8d,%r9d
  shr    %r9d
  movups %xmm1,(%rdx)
  cmp    $0x1,%r9d
  je     L123
  movupd 0x8(%rcx),%xmm2
  movups %xmm2,0x10(%rdx)
  cmp    $0x2,%r9d
  je     L123
  movupd 0x18(%rcx),%xmm3
  movups %xmm3,0x20(%rdx)
  cmp    $0x3,%r9d
  je     L123
  movupd 0x28(%rcx),%xmm4
  movups %xmm4,0x30(%rdx)
  cmp    $0x4,%r9d
  je     L123
  movupd 0x38(%rcx),%xmm5
  movups %xmm5,0x40(%rdx)
  cmp    $0x5,%r9d
  je     L123
  movupd 0x48(%rcx),%xmm6
  movups %xmm6,0x50(%rdx)
  cmp    $0x6,%r9d
  je     L123
  movupd 0x58(%rcx),%xmm7
  movups %xmm7,0x60(%rdx)
  cmp    $0x8,%r9d
  jne    L123
  movupd 0x68(%rcx),%xmm7
  movups %xmm7,0x70(%rdx)
L123:
  mov    %r8d,%r11d
  and    $0xfffffffe,%r11d
  lea    (%r11,%rdi,1),%r9d
  cmp    %r11d,%r8d
  je     L37
  add    %r9d,%eax
  cltq
  movsd  (%r10,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
L37:
  add    $0x1,%edi
  add    $0x88,%rcx
  add    $0x88,%rdx
  sub    $0x1,%r8d
  je     L191
L182:
  mov    %ebx,%r9d
  mov    %edi,%eax
  sub    %edi,%r9d
  shl    $0x4,%eax
  cmp    $0x2,%r9d
  ja     L158
L204:
  movsd  -0x8(%rcx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    $0xf,%edi
  je     L37
  movsd  (%rcx),%xmm0
  movsd  %xmm0,0x8(%rdx)
  cmp    $0xe,%edi
  je     L37
  movsd  0x8(%rcx),%xmm0
  movsd  %xmm0,0x10(%rdx)
  cmp    $0xd,%edi
  je     L37
  movsd  0x10(%rcx),%xmm0
  movsd  %xmm0,0x18(%rdx)
  cmp    $0xc,%edi
  je     L37
  movsd  0x18(%rcx),%xmm0
  movsd  %xmm0,0x20(%rdx)
  cmp    $0xb,%edi
  je     L37
  movsd  0x20(%rcx),%xmm0
  movsd  %xmm0,0x28(%rdx)
  cmp    $0xa,%edi
  je     L37
  movsd  0x28(%rcx),%xmm0
  movsd  %xmm0,0x30(%rdx)
  cmp    $0x9,%edi
  je     L37
  movsd  0x30(%rcx),%xmm0
  movsd  %xmm0,0x38(%rdx)
  cmp    $0x8,%edi
  je     L37
  movsd  0x38(%rcx),%xmm0
  movsd  %xmm0,0x40(%rdx)
  cmp    $0x7,%edi
  je     L37
  movsd  0x40(%rcx),%xmm0
  movsd  %xmm0,0x48(%rdx)
  cmp    $0x6,%edi
  je     L37
  movsd  0x48(%rcx),%xmm0
  movsd  %xmm0,0x50(%rdx)
  cmp    $0x5,%edi
  je     L37
  movsd  0x50(%rcx),%xmm0
  movsd  %xmm0,0x58(%rdx)
  cmp    $0x4,%edi
  je     L37
  movsd  0x58(%rcx),%xmm0
  movsd  %xmm0,0x60(%rdx)
  cmp    $0x3,%edi
  je     L37
  movsd  0x60(%rcx),%xmm0
  movsd  %xmm0,0x68(%rdx)
  cmp    $0x2,%edi
  je     L37
  movsd  0x68(%rcx),%xmm0
  movsd  %xmm0,0x70(%rdx)
  cmp    $0x1,%edi
  je     L37
  movsd  0x70(%rcx),%xmm0
  movsd  %xmm0,0x78(%rdx)
  jmp    L37
L191:
  pop    %rbx
  ret
```

assistant: ```c
void dcopy_codegen_3(double *A, double *C) {
  const int n = 4 + 0 * 40 + 3 * 4;
  const int lda = 4 + 0 * 40 + 3 * 4;
  int ii, jj;
  for (jj = 0; jj < n; jj++) {
    for (ii = jj; ii < n; ii++) {
      C[ii + lda * jj] = A[ii + lda * jj];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <test@plt>
  cmp    %eax,-0x4(%rbp)
  je     L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = INT_MAX;
  if (test(x) != x)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D0(%rip),%rax
  mov    (%rax),%ebx
  mov    %ebx,%edi
  call   <test@plt>
  cmp    %ebx,%eax
  jne    L16
L15:
  mov    $0x0,%eax
  pop    %rbx
  ret
L16:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L15
```

assistant: ```c
int main() {
  int x = INT_MAX;
  if (test(x) != x)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    D0(%rip),%rax
  push   %rbx
  mov    (%rax),%ebx
  mov    %ebx,%edi
  call   <test@plt>
  cmp    %ebx,%eax
  je     L3
  xor    %eax,%eax
  call   <abort@plt>
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x = INT_MAX;
  if (test(x) != x)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    D1(%rip),%rax
  push   %rbx
  mov    (%rax),%ebx
  mov    %ebx,%edi
  call   <test@plt>
  cmp    %ebx,%eax
  je     L3
  xor    %eax,%eax
  call   <abort@plt>
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x = INT_MAX;
  if (test(x) != x)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ntuple_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <size_to_vi@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L23
L57:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <size_to_vi@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L29
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  jmp    L38
L29:
  movq   $0x0,-0x18(%rbp)
  jmp    L53
L38:
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L57
L53:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t ntuple_size(size_t rank, const size_t *info) {
  size_t size, n, i;
  size = 0;
  n = size_to_vi(rank, NULL, -1);
  if (n) {
    size = n;
    for (i = 0; i < rank; i++) {
      n = size_to_vi(info[i], NULL, -1);
      if (n) {
        size += n;
      } else {
        size = 0;
        break;
      }
    }
  }
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<ntuple_size>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  call   <size_to_vi@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L42
  test   %r12,%r12
  je     L42
  mov    $0x0,%ebx
L29:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  call   <size_to_vi@plt>
  test   %rax,%rax
  je     L20
  add    %rax,%rbp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L29
  jmp    L42
L20:
  mov    %rax,%rbp
L42:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t ntuple_size(size_t rank, const size_t *info) {
  size_t size, n, i;
  size = 0;
  n = size_to_vi(rank, NULL, -1);
  if (n) {
    size = n;
    for (i = 0; i < rank; i++) {
      n = size_to_vi(info[i], NULL, -1);
      if (n) {
        size += n;
      } else {
        size = 0;
        break;
      }
    }
  }
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<ntuple_size>:
  endbr64
  push   %r13
  mov    $0xffffffff,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <size_to_vi@plt>
  test   %rax,%rax
  je     L43
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L4
  xor    %ebx,%ebx
  jmp    L26
  nopl   0x0(%rax)
L28:
  add    $0x1,%rbx
  add    %rax,%r12
  cmp    %rbx,%rbp
  je     L4
L26:
  mov    0x0(%r13,%rbx,8),%rdi
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  call   <size_to_vi@plt>
  test   %rax,%rax
  jne    L28
L43:
  xor    %r12d,%r12d
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t ntuple_size(size_t rank, const size_t *info) {
  size_t size, n, i;
  size = 0;
  n = size_to_vi(rank, NULL, -1);
  if (n) {
    size = n;
    for (i = 0; i < rank; i++) {
      n = size_to_vi(info[i], NULL, -1);
      if (n) {
        size += n;
      } else {
        size = 0;
        break;
      }
    }
  }
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ntuple_size>:
  endbr64
  push   %r13
  mov    $0xffffffff,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <size_to_vi@plt>
  test   %rax,%rax
  je     L40
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L5
  xor    %ebx,%ebx
  jmp    L2
  nopl   0x0(%rax)
L20:
  add    $0x1,%rbx
  add    %rax,%r12
  cmp    %rbx,%rbp
  je     L5
L2:
  mov    0x0(%r13,%rbx,8),%rdi
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  call   <size_to_vi@plt>
  test   %rax,%rax
  jne    L20
L40:
  xor    %r12d,%r12d
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t ntuple_size(size_t rank, const size_t *info) {
  size_t size, n, i;
  size = 0;
  n = size_to_vi(rank, NULL, -1);
  if (n) {
    size = n;
    for (i = 0; i < rank; i++) {
      n = size_to_vi(info[i], NULL, -1);
      if (n) {
        size += n;
      } else {
        size = 0;
        break;
      }
    }
  }
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sigignore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigaction@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int sigignore(int sig) {
  struct sigaction sa;
  sigemptyset(&sa.sa_mask);
  sa.sa_handler = SIG_IGN;
  sa.sa_flags = 0;
  return sigaction(sig, &sa, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sigignore>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xc(%rsp),%rdi
  call   <sigemptyset@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <sigaction@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sigignore(int sig) {
  struct sigaction sa;
  sigemptyset(&sa.sa_mask);
  sa.sa_handler = SIG_IGN;
  sa.sa_flags = 0;
  return sigaction(sig, &sa, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sigignore>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    %rsp,%r12
  call   <sigemptyset@plt>
  mov    D3(%rip),%rax
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %r12,%rsi
  movq   $0x0,(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  call   <sigaction@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sigignore(int sig) {
  struct sigaction sa;
  sigemptyset(&sa.sa_mask);
  sa.sa_handler = SIG_IGN;
  sa.sa_flags = 0;
  return sigaction(sig, &sa, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sigignore>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    %rsp,%r12
  call   <sigemptyset@plt>
  mov    D1(%rip),%rax
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %r12,%rsi
  movq   $0x0,(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  call   <sigaction@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sigignore(int sig) {
  struct sigaction sa;
  sigemptyset(&sa.sa_mask);
  sa.sa_handler = SIG_IGN;
  sa.sa_flags = 0;
  return sigaction(sig, &sa, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gdp_files_quick_getfloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gdp_files_open@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gdp_files_getfloat@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <gdp_files_close@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double gdp_files_quick_getfloat(char *FileName, char *cParameter) {
  FILE *fAux = gdp_files_open(FileName);
  double ret = gdp_files_getfloat(fAux, cParameter);
  gdp_files_close(fAux);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gdp_files_quick_getfloat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <gdp_files_open@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <gdp_files_getfloat@plt>
  movq   %xmm0,%rbp
  mov    %rbx,%rdi
  call   <gdp_files_close@plt>
  movq   %rbp,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double gdp_files_quick_getfloat(char *FileName, char *cParameter) {
  FILE *fAux = gdp_files_open(FileName);
  double ret = gdp_files_getfloat(fAux, cParameter);
  gdp_files_close(fAux);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gdp_files_quick_getfloat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x18,%rsp
  call   <gdp_files_open@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <gdp_files_getfloat@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <gdp_files_close@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double gdp_files_quick_getfloat(char *FileName, char *cParameter) {
  FILE *fAux = gdp_files_open(FileName);
  double ret = gdp_files_getfloat(fAux, cParameter);
  gdp_files_close(fAux);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<byteReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  (void)buf;
  (void)longs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byteReverse>:
  endbr64
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  (void)buf;
  (void)longs;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<byteReverse>:
  endbr64
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  (void)buf;
  (void)longs;
}
```