ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D79(%rip),%rdi
  lea    D82(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  divss  D3(%rip),%xmm1
  addss  D29(%rip),%xmm1
  mulss  0x1c(%rsp),%xmm1
  mov    $0x1,%eax
  cvtsi2ssl 0x24(%rsp),%xmm2
  lea    D62(%rip),%rdi
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D79
type_guessed: string
name: parse_data
arguments: data_label: D82
type_guessed: string
name: parse_data
arguments: data_label: D52
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D67
type_guessed: string
name: parse_data
arguments: data_label: D3
type_guessed: f32
name: parse_data
arguments: data_label: D29
type_guessed: f32
name: parse_data
arguments: data_label: D62
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string

tool: D79: Enter the product price: 

tool: D82: %f

tool: D52: Enter number of installments: 

tool: D4: %d

tool: D67: Enter interest rate: 

tool: D3: 100

tool: D29: 1

tool: D62: Installment amount: %.3f


tool: D19: Total payed amount: %.3f


assistant: ```c
int main() {
  float price, interest, amount;
  int installments;
  printf("Enter the product price: ");
  scanf("%f", &price);
  printf("Enter number of installments: ");
  scanf("%d", &installments);
  printf("Enter interest rate: ");
  scanf("%f", &interest);
  float total = price * (1 + interest / 100);
  printf("Installment amount: %.3f\n", total / installments);
  printf("Total payed amount: %.3f\n", total);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x11,%edi
  call   <tester@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: %d ---


assistant: ```c
void main() {
  int a = tester(17);
  printf("%d ---\n", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <tester@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: %d ---


assistant: ```c
void main() {
  int a = tester(17);
  printf("%d ---\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <tester@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: %d ---


assistant: ```c
void main() {
  int a = tester(17);
  printf("%d ---\n", a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <tester@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: %d ---


assistant: ```c
void main() {
  int a = tester(17);
  printf("%d ---\n", a);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<legal_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L96:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jle    L43
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L43
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L28
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L43
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L49
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L49
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L43
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L82
L43:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L72
L82:
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L96
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L119
  mov    $0x0,%eax
  jmp    L72
L119:
  mov    $0x1,%eax
L72:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D8: %c

tool: D9: ..

assistant: ```c
int legal_string(char *test_string) {
  int i;
  for (i = 0; i < strlen(test_string); i++) {
    if ((test_string[i] < 43) || (test_string[i] == 44) || ((test_string[i] > 57) && (test_string[i] < 65)) || ((test_string[i] != 95) && (test_string[i] > 90) && (test_string[i] < 97)) || (test_string[i] > 122)) {
      printf("%c", test_string[i]);
      return 0;
    }
  }
  if (strstr(test_string, "..")) {
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<legal_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L64
  movzbl 0x0(%rbp,%rbx,1),%esi
  lea    -0x2b(%rsi),%eax
  cmp    $0x4f,%al
  ja     L10
  cmp    $0x2c,%sil
  je     L10
  lea    -0x3a(%rsi),%eax
  cmp    $0x6,%al
  jbe    L10
  add    $0x1,%rbx
  lea    -0x5b(%rsi),%eax
  cmp    $0x5,%al
  ja     L12
  cmp    $0x5f,%sil
  je     L12
L10:
  movsbl %sil,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L64:
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D11: %c

tool: D7: ..

assistant: ```c
int legal_string(char *test_string) {
  int i;
  for (i = 0; i < strlen(test_string); i++) {
    if ((test_string[i] < 43) || (test_string[i] == 44) || ((test_string[i] > 57) && (test_string[i] < 65)) || ((test_string[i] != 95) && (test_string[i] > 90) && (test_string[i] < 97)) || (test_string[i] > 122)) {
      printf("%c", test_string[i]);
      return 0;
    }
  }
  if (strstr(test_string, "..")) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<legal_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L41:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L21
  movsbl 0x0(%rbp,%rbx,1),%esi
  lea    -0x2b(%rsi),%eax
  cmp    $0x4f,%al
  ja     L34
  cmp    $0x2c,%sil
  je     L34
  lea    -0x3a(%rsi),%eax
  cmp    $0x6,%al
  jbe    L34
  lea    -0x5b(%rsi),%eax
  add    $0x1,%rbx
  cmp    $0x5,%al
  ja     L41
  cmp    $0x5f,%sil
  je     L41
L34:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D12: %c

tool: D15: ..

assistant: ```c
int legal_string(char *test_string) {
  int i;
  for (i = 0; i < strlen(test_string); i++) {
    if ((test_string[i] < 43) || (test_string[i] == 44) || ((test_string[i] > 57) && (test_string[i] < 65)) || ((test_string[i] != 95) && (test_string[i] > 90) && (test_string[i] < 97)) || (test_string[i] > 122)) {
      printf("%c", test_string[i]);
      return 0;
    }
  }
  if (strstr(test_string, "..")) {
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<legal_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L58:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L28
  movsbl 0x0(%rbp,%rbx,1),%esi
  lea    -0x2b(%rsi),%eax
  cmp    $0x4f,%al
  ja     L49
  cmp    $0x2c,%sil
  je     L49
  lea    -0x3a(%rsi),%eax
  cmp    $0x6,%al
  jbe    L49
  lea    -0x5b(%rsi),%eax
  add    $0x1,%rbx
  cmp    $0x5,%al
  ja     L58
  cmp    $0x5f,%sil
  je     L58
L49:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string

tool: D2: %c

tool: D11: ..

assistant: ```c
int legal_string(char *test_string) {
  int i;
  for (i = 0; i < strlen(test_string); i++) {
    if ((test_string[i] < 43) || (test_string[i] == 44) || ((test_string[i] > 57) && (test_string[i] < 65)) || ((test_string[i] != 95) && (test_string[i] > 90) && (test_string[i] < 97)) || (test_string[i] > 122)) {
      printf("%c", test_string[i]);
      return 0;
    }
  }
  if (strstr(test_string, "..")) {
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cvector_scale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cvector_scale(double *vdest, double c, const double *vorg, int n) {
  for (int i = 0; i < n; i++) {
    vdest[i] = c * vorg[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cvector_scale>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
L14:
  movapd %xmm0,%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
L0:
  ret
```

assistant: ```c
void cvector_scale(double *vdest, double c, const double *vorg, int n) {
  for (int i = 0; i < n; i++) {
    vdest[i] = c * vorg[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cvector_scale>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L8
L1:
  ret
```

assistant: ```c
void cvector_scale(double *vdest, double c, const double *vorg, int n) {
  for (int i = 0; i < n; i++) {
    vdest[i] = c * vorg[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cvector_scale>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L47
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L45
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L45
  mov    %edx,%edi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdi
  xchg   %ax,%ax
L24:
  movupd (%rsi,%rax,1),%xmm1
  mulpd  %xmm2,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L24
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L47
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L46:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L46
L47:
  ret
```

assistant: ```c
void cvector_scale(double *vdest, double c, const double *vorg, int n) {
  for (int i = 0; i < n; i++) {
    vdest[i] = c * vorg[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inode_dec_link_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <drop_nlink@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mark_inode_dirty@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void inode_dec_link_count(struct inode *inode) {
  drop_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inode_dec_link_count>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <drop_nlink@plt>
  mov    %rbx,%rdi
  call   <mark_inode_dirty@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) void inode_dec_link_count(struct inode *inode) {
  drop_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inode_dec_link_count>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <drop_nlink@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <mark_inode_dirty@plt>
```

assistant: ```c
__attribute__((always_)) void inode_dec_link_count(struct inode *inode) {
  drop_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inode_dec_link_count>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <drop_nlink@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <mark_inode_dirty@plt>
```

assistant: ```c
__attribute__((always_)) void inode_dec_link_count(struct inode *inode) {
  drop_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rot13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L48:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L20
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L19
  mov    $0x61,%eax
  jmp    L1
L19:
  mov    $0x41,%eax
L1:
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movsbl -0x15(%rbp),%edx
  sub    %edx,%eax
  add    $0xd,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movzbl -0x15(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L13
L20:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L13:
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  ja     L48
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rot13(char *plain_or_cipher) {
  size_t length = strlen(plain_or_cipher);
  char *output = malloc(length);
  for (int i = 0; i < length; i++) {
    if (isalpha(plain_or_cipher[i])) {
      char char_base = islower(plain_or_cipher[i]) ? 'a' : 'A';
      output[i] = (plain_or_cipher[i] - char_base + 13) % 26 + char_base;
    } else {
      output[i] = plain_or_cipher[i];
    }
  }
  return output;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rot13>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r14,%r14
  je     L44
  mov    %r12,%rbx
  mov    %rax,%rbp
  add    %r14,%r12
  jmp    L10
L6:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
L25:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L44
L10:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L6
  movsbl (%rbx),%edi
  call   <islower@plt>
  cmp    $0x1,%rax
  sbb    %ecx,%ecx
  and    $0xffffffe0,%ecx
  add    $0x61,%ecx
  movsbl (%rbx),%eax
  movsbl %cl,%edx
  sub    %edx,%eax
  add    $0xd,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    %eax,%ecx
  mov    %cl,0x0(%rbp)
  jmp    L25
L44:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *rot13(char *plain_or_cipher) {
  size_t length = strlen(plain_or_cipher);
  char *output = malloc(length);
  for (int i = 0; i < length; i++) {
    if (isalpha(plain_or_cipher[i])) {
      char char_base = islower(plain_or_cipher[i]) ? 'a' : 'A';
      output[i] = (plain_or_cipher[i] - char_base + 13) % 26 + char_base;
    } else {
      output[i] = plain_or_cipher[i];
    }
  }
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rot13>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <malloc@plt>
  lea    (%rbx,%r14,1),%rbp
  mov    %rax,%r12
  test   %r14,%r14
  je     L9
  mov    %rax,%r13
  jmp    L47
L48:
  movzbl (%rbx),%eax
L38:
  add    $0x1,%rbx
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  cmp    %rbp,%rbx
  je     L9
L47:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L48
  movsbl (%rbx),%edi
  call   <islower@plt>
  cmp    $0x1,%rax
  sbb    %edx,%edx
  and    $0xffffffe0,%edx
  cmp    $0x1,%rax
  movsbl (%rbx),%eax
  sbb    %ecx,%ecx
  and    $0xffffffe0,%ecx
  sub    %ecx,%eax
  lea    -0x54(%rax),%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x23,%rax
  sub    %esi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ecx
  lea    0x61(%rdx,%rcx,1),%eax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *rot13(char *plain_or_cipher) {
  size_t length = strlen(plain_or_cipher);
  char *output = malloc(length);
  for (int i = 0; i < length; i++) {
    if (isalpha(plain_or_cipher[i])) {
      char char_base = islower(plain_or_cipher[i]) ? 'a' : 'A';
      output[i] = (plain_or_cipher[i] - char_base + 13) % 26 + char_base;
    } else {
      output[i] = plain_or_cipher[i];
    }
  }
  return output;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rot13>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <malloc@plt>
  lea    (%rbx,%r14,1),%rbp
  mov    %rax,%r12
  test   %r14,%r14
  je     L44
  mov    %rax,%r13
  jmp    L3
L35:
  movzbl (%rbx),%eax
L48:
  add    $0x1,%rbx
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  cmp    %rbp,%rbx
  je     L44
L3:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L35
  movsbl (%rbx),%edi
  call   <islower@plt>
  cmp    $0x1,%rax
  sbb    %edx,%edx
  and    $0xffffffe0,%edx
  cmp    $0x1,%rax
  movsbl (%rbx),%eax
  sbb    %ecx,%ecx
  and    $0xffffffe0,%ecx
  sub    %ecx,%eax
  lea    -0x54(%rax),%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x23,%rax
  sub    %esi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ecx
  lea    0x61(%rdx,%rcx,1),%eax
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L44:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *rot13(char *plain_or_cipher) {
  size_t length = strlen(plain_or_cipher);
  char *output = malloc(length);
  for (int i = 0; i < length; i++) {
    if (isalpha(plain_or_cipher[i])) {
      char char_base = islower(plain_or_cipher[i]) ? 'a' : 'A';
      output[i] = (plain_or_cipher[i] - char_base + 13) % 26 + char_base;
    } else {
      output[i] = plain_or_cipher[i];
    }
  }
  return output;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L3:
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x8,-0x4(%rbp)
  jle    L0
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int minDistance(int distance[], int shortest[]) {
  int minV = INT_MAX;
  int min_index;
  int i;
  for (i = 0; i < 9; i++)
    if (shortest[i] == 0 && distance[i] <= minV) {
      minV = distance[i];
      min_index = i;
    }
  return min_index;
}
```