ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<arithmetic_shift_right>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L6
  mov    $0x40,%ecx
  cltd
  sub    %esi,%ecx
  shl    %cl,%edx
  mov    %esi,%ecx
  sar    %cl,%eax
  or     %edx,%eax
L6:
  ret
```

assistant: ```c
int64_t arithmetic_shift_right(int64_t value, uint8_t shift) {
  int64_t sign_ext;
  if (shift == 0) {
    return value;
  }
  sign_ext = (value >> 63) & 1;
  sign_ext = -sign_ext;
  return (value >> shift) | (sign_ext << (64 - shift));
}
```
user: Translate the below assembly code into C programming language:

```asm
<randomfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mkstemp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fdopen@plt>
  jmp    L34
L13:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L15
  mov    $0x0,%eax
L34:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D18
data_type: string

tool: D2: /tmp/kadimus-XXXXXX

tool: D18: w

assistant: ```c
FILE *randomfile(char *filename, int retry) {
  int i, fd;
  strcpy(filename, "/tmp/kadimus-XXXXXX");
  for (i = 0; i <= retry; i++) {
    if ((fd = mkstemp(filename)) != -1) {
      return fdopen(fd, "w");
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<randomfile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    D1(%rip),%rsi
  call   <strcpy@plt>
  test   %r12d,%r12d
  js     L35
  mov    $0x0,%ebx
L44:
  mov    %rbp,%rdi
  call   <mkstemp@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L44
  mov    $0x0,%eax
  jmp    L48
L9:
  lea    D4(%rip),%rsi
  mov    %eax,%edi
  call   <fdopen@plt>
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x0,%eax
  jmp    L48
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D1: /tmp/kadimus-XXXXXX

tool: D4: w

assistant: ```c
FILE *randomfile(char *filename, int retry) {
  int i, fd;
  strcpy(filename, "/tmp/kadimus-XXXXXX");
  for (i = 0; i <= retry; i++) {
    if ((fd = mkstemp(filename)) != -1) {
      return fdopen(fd, "w");
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<randomfile>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  lea    D3(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strcpy@plt>
  test   %r12d,%r12d
  js     L39
  xor    %ebx,%ebx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jl     L39
L34:
  mov    %rbp,%rdi
  call   <mkstemp@plt>
  cmp    $0xffffffff,%eax
  je     L8
  pop    %rbx
  lea    D5(%rip),%rsi
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    1090 <fdopen@plt>
  nop
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D5
datatype: string

tool: D3: /tmp/kadimus-XXXXXX

tool: D5: w

assistant: ```c
FILE *randomfile(char *filename, int retry) {
  int i, fd;
  strcpy(filename, "/tmp/kadimus-XXXXXX");
  for (i = 0; i <= retry; i++) {
    if ((fd = mkstemp(filename)) != -1) {
      return fdopen(fd, "w");
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<randomfile>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  lea    D5(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strcpy@plt>
  test   %r12d,%r12d
  js     L31
  xor    %ebx,%ebx
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jl     L31
L27:
  mov    %rbp,%rdi
  call   <mkstemp@plt>
  cmp    $0xffffffff,%eax
  je     L35
  pop    %rbx
  lea    D13(%rip),%rsi
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    1090 <fdopen@plt>
  nop
L31:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D13
type: string

tool: D5: /tmp/kadimus-XXXXXX

tool: D13: w

assistant: ```c
FILE *randomfile(char *filename, int retry) {
  int i, fd;
  strcpy(filename, "/tmp/kadimus-XXXXXX");
  for (i = 0; i <= retry; i++) {
    if ((fd = mkstemp(filename)) != -1) {
      return fdopen(fd, "w");
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
L14:
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x74(%rbp)
  cmpl   $0x0,-0x74(%rbp)
  jg     L14
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <htoi@plt>
  mov    %eax,%edx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: %s: %d


assistant: ```c
int main(void) {
  int len;
  char line[100];
  while ((len = getline(line, 100)) > 0)
    ;
  printf("%s: %d\n", line, htoi(line));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
L0:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %eax,%eax
  jg     L0
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <htoi@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: %s: %d


assistant: ```c
int main(void) {
  int len;
  char line[100];
  while ((len = getline(line, 100)) > 0)
    ;
  printf("%s: %d\n", line, htoi(line));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L9:
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <getline@plt>
  test   %eax,%eax
  jg     L9
  mov    %rbp,%rdi
  call   <htoi@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8: %s: %d


assistant: ```c
int main(void) {
  int len;
  char line[100];
  while ((len = getline(line, 100)) > 0)
    ;
  printf("%s: %d\n", line, htoi(line));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L15:
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <getline@plt>
  test   %eax,%eax
  jg     L15
  mov    %rbp,%rdi
  call   <htoi@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: %s: %d


assistant: ```c
int main(void) {
  int len;
  char line[100];
  while ((len = getline(line, 100)) > 0)
    ;
  printf("%s: %d\n", line, htoi(line));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <test_hll_sample@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_hll_sample(argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test_hll_sample@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_hll_sample(argc, argv);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test_hll_sample@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_hll_sample(argc, argv);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test_hll_sample@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_hll_sample(argc, argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GetDIP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%edi
  call   <ReadMax@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  not    %eax
  leave
  ret
```

assistant: ```c
unsigned char GetDIP() {
  unsigned char val = ReadMax(2);
  return ~val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<GetDIP>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <ReadMax@plt>
  not    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char GetDIP() {
  unsigned char val = ReadMax(2);
  return ~val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GetDIP>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <ReadMax@plt>
  add    $0x8,%rsp
  not    %eax
  ret
```

assistant: ```c
unsigned char GetDIP() {
  unsigned char val = ReadMax(2);
  return ~val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetDIP>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <ReadMax@plt>
  add    $0x8,%rsp
  not    %eax
  ret
```

assistant: ```c
unsigned char GetDIP() {
  unsigned char val = ReadMax(2);
  return ~val;
}
```
user: What is the c source code of the assembly code below:

```asm
<div_lo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <mpfr_set_default_rounding_mode@plt>
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double div_lo(double x, double y) {
  double z;
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  z = x / y;
  return (z);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<div_lo>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <mpfr_set_default_rounding_mode@plt>
  movq   %rbx,%xmm0
  movq   %r14,%xmm2
  divsd  %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double div_lo(double x, double y) {
  double z;
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  z = x / y;
  return (z);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<div_lo>:
  endbr64
  sub    $0x18,%rsp
  mov    D1(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  mov    (%rax),%edi
  movsd  %xmm1,(%rsp)
  call   <mpfr_set_default_rounding_mode@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double div_lo(double x, double y) {
  double z;
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  z = x / y;
  return (z);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<div_lo>:
  endbr64
  sub    $0x18,%rsp
  mov    D5(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  mov    (%rax),%edi
  movsd  %xmm1,(%rsp)
  call   <mpfr_set_default_rounding_mode@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double div_lo(double x, double y) {
  double z;
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  z = x / y;
  return (z);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0xe8(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  jmp    L22
L33:
  lea    -0xd0(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %eax,%edi
  call   <atol@plt>
  mov    %rax,-0xd8(%rbp)
  mov    -0xd8(%rbp),%rax
  cmp    -0xe8(%rbp),%rax
  je     L31
  mov    -0xd8(%rbp),%rax
  mov    %rax,-0xe8(%rbp)
  jmp    L22
L31:
  addq   $0x1,-0xe0(%rbp)
L22:
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L33
  mov    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string

tool: D2: :

tool: D12: %ld


assistant: ```c
main() {
  long pid, cid, count;
  char t[200];
  pid = -1;
  cid = 0;
  count = 0;
  while (gets(t)) {
    cid = atol(strtok(t, ":"));
    if (cid != pid) {
      pid = cid;
      continue;
    }
    count++;
  }
  printf("%ld\n", count);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    $0xffffffffffffffff,%rbp
  lea    D11(%rip),%r12
  jmp    L12
L2:
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <strtok@plt>
  mov    %eax,%edi
  call   <atol@plt>
  cmp    %rax,%rbp
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rbx
  mov    %rax,%rbp
L12:
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbx,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type: string
name: unpack_data
arguments: tag: D19
type: string

tool: D11: :

tool: D19: %ld


assistant: ```c
main() {
  long pid, cid, count;
  char t[200];
  pid = -1;
  cid = 0;
  count = 0;
  while (gets(t)) {
    cid = atol(strtok(t, ":"));
    if (cid != pid) {
      pid = cid;
      continue;
    }
    count++;
  }
  printf("%ld\n", count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L19
  nopl   0x0(%rax)
L6:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %eax,%edi
  call   <atol@plt>
  xor    %edx,%edx
  cmp    %rax,%r12
  mov    %rax,%r12
  sete   %dl
  add    %rdx,%rbp
L19:
  mov    %rbx,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L6
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D10
data_type: string

tool: D16: :

tool: D10: %ld


assistant: ```c
main() {
  long pid, cid, count;
  char t[200];
  pid = -1;
  cid = 0;
  count = 0;
  while (gets(t)) {
    cid = atol(strtok(t, ":"));
    if (cid != pid) {
      pid = cid;
      continue;
    }
    count++;
  }
  printf("%ld\n", count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L25
  nopl   0x0(%rax)
L24:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %eax,%edi
  call   <atol@plt>
  xor    %edx,%edx
  cmp    %rax,%r12
  mov    %rax,%r12
  sete   %dl
  add    %rdx,%rbp
L25:
  mov    %rbx,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L24
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: D3: :

tool: D1: %ld


assistant: ```c
main() {
  long pid, cid, count;
  char t[200];
  pid = -1;
  cid = 0;
  count = 0;
  while (gets(t)) {
    cid = atol(strtok(t, ":"));
    if (cid != pid) {
      pid = cid;
      continue;
    }
    count++;
  }
  printf("%ld\n", count);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<autohelperowl_attackpat265>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  je     L4
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x1,%eax
  jmp    L5
L4:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat265(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(0, 3, move, transformation);
  return play_attack_defend_n(color, 1, 1, a, a) != 0 && !play_attack_defend_n(color, 1, 1, a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<autohelperowl_attackpat265>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%ebx
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    %ebx,%r8d
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <play_attack_defend_n@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L8
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L7
```

assistant: ```c
int autohelperowl_attackpat265(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(0, 3, move, transformation);
  return play_attack_defend_n(color, 1, 1, a, a) != 0 && !play_attack_defend_n(color, 1, 1, a, b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<autohelperowl_attackpat265>:
  endbr64
  push   %r14
  xor    %edi,%edi
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%edx
  mov    %r14d,%ecx
  mov    $0x3,%esi
  mov    %eax,%r12d
  xor    %edi,%edi
  call   <offset@plt>
  mov    %r12d,%r8d
  mov    %r12d,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <play_attack_defend_n@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int autohelperowl_attackpat265(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(0, 3, move, transformation);
  return play_attack_defend_n(color, 1, 1, a, a) != 0 && !play_attack_defend_n(color, 1, 1, a, b);
}
```
user: What is the c source code of the assembly code below:

```asm
<autohelperowl_attackpat265>:
  endbr64
  push   %r14
  xor    %edi,%edi
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%edx
  mov    %r14d,%ecx
  mov    $0x3,%esi
  mov    %eax,%r12d
  xor    %edi,%edi
  call   <offset@plt>
  mov    %r12d,%r8d
  mov    %r12d,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <play_attack_defend_n@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int autohelperowl_attackpat265(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(0, 3, move, transformation);
  return play_attack_defend_n(color, 1, 1, a, a) != 0 && !play_attack_defend_n(color, 1, 1, a, b);
}
```
user: What is the c source code of the assembly code below:

```asm
<enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  andl   $0x3f,-0x4(%rbp)
  cmpl   $0x19,-0x4(%rbp)
  jg     L67
  mov    -0x4(%rbp),%eax
  add    $0x41,%eax
  jmp    L17
L67:
  cmpl   $0x33,-0x4(%rbp)
  jg     L19
  mov    -0x4(%rbp),%eax
  add    $0x47,%eax
  jmp    L17
L19:
  cmpl   $0x3d,-0x4(%rbp)
  jg     L8
  mov    -0x4(%rbp),%eax
  sub    $0x4,%eax
  jmp    L17
L8:
  cmpl   $0x3e,-0x4(%rbp)
  jne    L39
  mov    $0x2b,%eax
  jmp    L17
L39:
  mov    $0x2f,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int enc(int val) {
  val &= 0x3f;
  if (val <= 25)
    return ('A' + val);
  if (val <= 51)
    return ('a' + val - 26);
  if (val <= 61)
    return ('0' + val - 52);
  if (val == 62)
    return '+';
  return '/';
}
```