ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<primeKeyGeneration>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <gmp_randinit_default@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <gmp_randseed_ui@plt>
L2:
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <mpz_set_ui@plt>
  mov    $0x400,%edx
  mov    $0x0,%ebp
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_urandomb@plt>
  mov    %ebx,%edi
  call   <millerRabin@plt>
  test   %eax,%eax
  je     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void primeKeyGeneration(mpz_t p) {
  gmp_randstate_t state;
  gmp_randinit_default(state);
  gmp_randseed_ui(state, time(NULL));
  int isPrime = 0;
  while (isPrime == 0) {
    mpz_set_ui(p, 0);
    mpz_urandomb(p, state, 1024);
    isPrime = millerRabin(p);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<primeKeyGeneration>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <gmp_randinit_default@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <gmp_randseed_ui@plt>
  nopl   (%rax)
L9:
  xor    %esi,%esi
  mov    %ebx,%edi
  call   <mpz_set_ui@plt>
  xor    %esi,%esi
  mov    %ebx,%edi
  mov    $0x400,%edx
  call   <mpz_urandomb@plt>
  mov    %ebx,%edi
  call   <millerRabin@plt>
  test   %eax,%eax
  je     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void primeKeyGeneration(mpz_t p) {
  gmp_randstate_t state;
  gmp_randinit_default(state);
  gmp_randseed_ui(state, time(NULL));
  int isPrime = 0;
  while (isPrime == 0) {
    mpz_set_ui(p, 0);
    mpz_urandomb(p, state, 1024);
    isPrime = millerRabin(p);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<primeKeyGeneration>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <gmp_randinit_default@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <gmp_randseed_ui@plt>
  nopl   (%rax)
L5:
  xor    %esi,%esi
  mov    %ebx,%edi
  call   <mpz_set_ui@plt>
  xor    %esi,%esi
  mov    %ebx,%edi
  mov    $0x400,%edx
  call   <mpz_urandomb@plt>
  mov    %ebx,%edi
  call   <millerRabin@plt>
  test   %eax,%eax
  je     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void primeKeyGeneration(mpz_t p) {
  gmp_randstate_t state;
  gmp_randinit_default(state);
  gmp_randseed_ui(state, time(NULL));
  int isPrime = 0;
  while (isPrime == 0) {
    mpz_set_ui(p, 0);
    mpz_urandomb(p, state, 1024);
    isPrime = millerRabin(p);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <function@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <function@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L27
  mov    -0x10(%rbp),%rax
  lea    D21(%rip),%rdx
  cmp    %rdx,%rax
  jne    L27
  mov    $0x1,%eax
  jmp    L12
L27:
  mov    $0x0,%eax
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_infered: string

tool: D21: asdf

assistant: ```c
int main() {
  long t1 = function("asdf");
  long t2 = function("asdf");
  return t1 == t2 && t1 == "asdf";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <function@plt>
  movslq %eax,%rbx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <function@plt>
  cltq
  mov    $0x0,%edx
  cmp    %rax,%rbx
  je     L16
L5:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  cmp    %rbp,%rbx
  sete   %dl
  movzbl %dl,%edx
  jmp    L5
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: asdf

assistant: ```c
int main() {
  long t1 = function("asdf");
  long t2 = function("asdf");
  return t1 == t2 && t1 == "asdf";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <function@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  xor    %eax,%eax
  call   <function@plt>
  xor    %r8d,%r8d
  cltq
  cmp    %rax,%rbx
  jne    L4
  xor    %r8d,%r8d
  cmp    %rbp,%rbx
  sete   %r8b
L4:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: asdf

assistant: ```c
int main() {
  long t1 = function("asdf");
  long t2 = function("asdf");
  return t1 == t2 && t1 == "asdf";
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <function@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  xor    %eax,%eax
  call   <function@plt>
  xor    %r8d,%r8d
  cltq
  cmp    %rax,%rbx
  jne    L0
  xor    %r8d,%r8d
  cmp    %rbp,%rbx
  sete   %r8b
L0:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: asdf

assistant: ```c
int main() {
  long t1 = function("asdf");
  long t2 = function("asdf");
  return t1 == t2 && t1 == "asdf";
}
```
user: What is the c source code of the assembly code below:

```asm
<StrCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L16
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L2
L16:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L2:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *StrCopy(char *Dest, size_t DestSize, const char *Source) {
  size_t Len = strlen(Source);
  if (Len >= DestSize) {
    memcpy(Dest, Source, DestSize - 1);
    Dest[DestSize - 1] = '\0';
  } else {
    memcpy(Dest, Source, Len + 1);
  }
  return Dest;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<StrCopy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <strlen@plt>
  cmp    %r12,%rax
  jb     L13
  lea    -0x1(%r12),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbx,%r12,1)
L15:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  jmp    L15
```

assistant: ```c
char *StrCopy(char *Dest, size_t DestSize, const char *Source) {
  size_t Len = strlen(Source);
  if (Len >= DestSize) {
    memcpy(Dest, Source, DestSize - 1);
    Dest[DestSize - 1] = '\0';
  } else {
    memcpy(Dest, Source, Len + 1);
  }
  return Dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrCopy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  jb     L2
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *StrCopy(char *Dest, size_t DestSize, const char *Source) {
  size_t Len = strlen(Source);
  if (Len >= DestSize) {
    memcpy(Dest, Source, DestSize - 1);
    Dest[DestSize - 1] = '\0';
  } else {
    memcpy(Dest, Source, Len + 1);
  }
  return Dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<StrCopy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  jb     L8
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *StrCopy(char *Dest, size_t DestSize, const char *Source) {
  size_t Len = strlen(Source);
  if (Len >= DestSize) {
    memcpy(Dest, Source, DestSize - 1);
    Dest[DestSize - 1] = '\0';
  } else {
    memcpy(Dest, Source, Len + 1);
  }
  return Dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L34
L12:
  cmpl   $0x1,-0x14(%rbp)
  jne    L39
  mov    $0x1,%eax
  jmp    L34
L39:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibonacci>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibonacci>
  add    %ebx,%eax
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibonacci(int n) {
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return (fibonacci(n - 2) + fibonacci(n - 1));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L10
  cmp    $0x1,%edi
  jne    L5
L10:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    -0x2(%rdi),%edi
  call   <fibonacci>
  mov    %eax,%ebp
  lea    -0x1(%rbx),%edi
  call   <fibonacci>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L10
```

assistant: ```c
int fibonacci(int n) {
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return (fibonacci(n - 2) + fibonacci(n - 1));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L11:
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x2,-0xc(%rbp)
  jle    L11
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D22: clamp

tool: D15: # c::native::%s


tool: D17: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "clamp");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D14(%rip),%r13
  lea    D13(%rip),%r12
  lea    D21(%rip),%rbp
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L6
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string

tool: D14: clamp

tool: D13: # c::native::%s


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "clamp");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D19(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string
name: disassemble_data
arguments: data_label: D24
type_infered: string

tool: D19: clamp

tool: D4: # c::native::%s


tool: D24: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "clamp");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D29(%rip),%r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D29
type: string
name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D23
type: string

tool: D29: clamp

tool: D11: # c::native::%s


tool: D23: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "clamp");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ASCIIINT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L9
  mov    -0x20(%rbp),%rax
  movw   $0x0,(%rax)
  movzwl -0xa(%rbp),%eax
  jmp    L34
L9:
  lea    -0xa(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L46
  mov    -0x20(%rbp),%rax
  movw   $0x2,(%rax)
  jmp    L6
L46:
  mov    -0x20(%rbp),%rax
  movw   $0x1,(%rax)
L6:
  movzwl -0xa(%rbp),%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: %hd

assistant: ```c
short ASCIIINT(char *S, short *Er) {
  short I;
  I = 0;
  if ((int)strlen(S) > 10) {
    *Er = 0;
    return I;
  }
  *Er = (sscanf(S, "%hd", &I) == 0);
  if (*Er == 0)
    *Er = 2;
  else
    *Er = 1;
  return I;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ASCIIINT>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x0,0x6(%rsp)
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L3
  movw   $0x0,0x0(%rbp)
  mov    $0x0,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  lea    0x6(%rsp),%rdx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  sbb    $0xffff,%ax
  mov    %ax,0x0(%rbp)
  movzwl 0x6(%rsp),%eax
  jmp    L27
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: %hd

assistant: ```c
short ASCIIINT(char *S, short *Er) {
  short I;
  I = 0;
  if ((int)strlen(S) > 10) {
    *Er = 0;
    return I;
  }
  *Er = (sscanf(S, "%hd", &I) == 0);
  if (*Er == 0)
    *Er = 2;
  else
    *Er = 1;
  return I;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ASCIIINT>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dx,0x6(%rsp)
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L28
  xor    %eax,%eax
  mov    %ax,(%rbx)
  xor    %eax,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L28:
  lea    0x6(%rsp),%rdx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  sbb    $0xffff,%ax
  mov    %ax,(%rbx)
  movzwl 0x6(%rsp),%eax
  jmp    L16
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: %hd

assistant: ```c
short ASCIIINT(char *S, short *Er) {
  short I;
  I = 0;
  if ((int)strlen(S) > 10) {
    *Er = 0;
    return I;
  }
  *Er = (sscanf(S, "%hd", &I) == 0);
  if (*Er == 0)
    *Er = 2;
  else
    *Er = 1;
  return I;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ASCIIINT>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dx,0x6(%rsp)
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L4
  xor    %eax,%eax
  mov    %ax,(%rbx)
  xor    %eax,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L4:
  lea    0x6(%rsp),%rdx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  sbb    $0xffff,%ax
  mov    %ax,(%rbx)
  movzwl 0x6(%rsp),%eax
  jmp    L0
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: %hd

assistant: ```c
short ASCIIINT(char *S, short *Er) {
  short I;
  I = 0;
  if ((int)strlen(S) > 10) {
    *Er = 0;
    return I;
  }
  *Er = (sscanf(S, "%hd", &I) == 0);
  if (*Er == 0)
    *Er = 2;
  else
    *Er = 1;
  return I;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mapcon_clear_maps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1b0,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mapcon_clear_maps(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(432, a, b, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mapcon_clear_maps>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1b0,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mapcon_clear_maps(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(432, a, b, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mapcon_clear_maps>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1b0,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int mapcon_clear_maps(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(432, a, b, c);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0xb8000,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L30:
  mov    D8(%rip),%eax
  cmp    $0x7d0,%eax
  jne    L34
  mov    $0x0,%eax
  call   <ShiftDisplayUpOneLine@plt>
  mov    D8(%rip),%eax
  sub    $0x50,%eax
  mov    %eax,D52(%rip)
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L45
  mov    D52(%rip),%esi
  mov    D52(%rip),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x6,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  add    $0x50,%eax
  mov    %eax,D52(%rip)
  jmp    L40
L45:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cbtw
  or     $0x2,%ah
  mov    %eax,%ecx
  mov    D52(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D52(%rip)
  mov    %eax,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dx,(%rax)
L40:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  nop
  nop
  leave
  ret
```

assistant: ```c
void Print(char text[]) {
  static unsigned int CurrentLocation = 0;
  unsigned short *DisplayMemoryPtr = (unsigned short *)0xB8000;
  int i;
  for (i = 0; text[i] != 0; i++) {
    if (CurrentLocation == 2000) {
      ShiftDisplayUpOneLine();
      CurrentLocation -= 80;
    }
    if (text[i] == '\n') {
      CurrentLocation += (80 - (CurrentLocation % 80));
    } else {
      DisplayMemoryPtr[CurrentLocation++] = (unsigned short)(0x0200 | text[i]);
    }
  }
}
```