ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<createReponse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *createReponse(char *resp_template, char *arg) {
  char *resp;
  size_t len = strlen(resp_template) + strlen(arg);
  resp = (char *)malloc(len);
  snprintf(resp, len, resp_template, arg);
  return resp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<createReponse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *createReponse(char *resp_template, char *arg) {
  char *resp;
  size_t len = strlen(resp_template) + strlen(arg);
  resp = (char *)malloc(len);
  snprintf(resp, len, resp_template, arg);
  return resp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<createReponse>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  add    %rax,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *createReponse(char *resp_template, char *arg) {
  char *resp;
  size_t len = strlen(resp_template) + strlen(arg);
  resp = (char *)malloc(len);
  snprintf(resp, len, resp_template, arg);
  return resp;
}
```
user: What is the c source code of the assembly code below?

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setvbuf@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setvbuf@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((constructor)) void init() {
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  push   %rbx
  mov    D1(%rip),%rbx
  mov    $0x0,%ecx
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    D26(%rip),%rax
  mov    (%rax),%edi
  call   <setvbuf@plt>
  mov    $0x0,%ecx
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <setvbuf@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((constructor)) void init() {
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  push   %rbx
  mov    D28(%rip),%rax
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    D14(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%edx
  call   <setvbuf@plt>
  mov    D23(%rip),%rax
  mov    (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <setvbuf@plt>
```

assistant: ```c
__attribute__((constructor)) void init() {
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rax
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    D26(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%edx
  call   <setvbuf@plt>
  mov    D22(%rip),%rax
  mov    (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <setvbuf@plt>
```

assistant: ```c
__attribute__((constructor)) void init() {
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_f_rintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  flds   -0x18(%rbp)
  frndint
  fstps  -0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float _f_rintf(float x) {
  float _result;
  asm("frndint" : "=t"(_result) : "0"(x));
  return _result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_f_rintf>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  flds   -0x4(%rsp)
  frndint
  fstps  -0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ret
```

assistant: ```c
float _f_rintf(float x) {
  float _result;
  asm("frndint" : "=t"(_result) : "0"(x));
  return _result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_f_rintf>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  flds   -0x4(%rsp)
  frndint
  fstps  -0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ret
```

assistant: ```c
float _f_rintf(float x) {
  float _result;
  asm("frndint" : "=t"(_result) : "0"(x));
  return _result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_f_rintf>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  flds   -0x4(%rsp)
  frndint
  fstps  -0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ret
```

assistant: ```c
float _f_rintf(float x) {
  float _result;
  asm("frndint" : "=t"(_result) : "0"(x));
  return _result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OpsLogStart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %edi,-0x1024(%rbp)
  mov    %rsi,-0x1030(%rbp)
  mov    %edx,-0x1028(%rbp)
  mov    %rcx,-0x1038(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1010(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movl   $0x0,-0x1014(%rbp)
  jmp    L4
L37:
  cmpl   $0x0,-0x1014(%rbp)
  je     L39
  lea    -0x1010(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L39:
  mov    -0x1014(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x1038(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x1014(%rbp)
L4:
  mov    -0x1014(%rbp),%eax
  cmp    -0x1028(%rbp),%eax
  jl     L37
  lea    -0x1010(%rbp),%rdx
  mov    -0x1030(%rbp),%rcx
  mov    -0x1024(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ErrLog@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string

tool: D9: PROGRAM START->

tool: D18:  

assistant: ```c
void OpsLogStart(int sock, char *name, int argc, char *argv[]) {
  char buffer[4096];
  int i;
  sprintf(buffer, "PROGRAM START->");
  for (i = 0; i < argc; i++) {
    if (i != 0)
      strcat(buffer, " ");
    strcat(buffer, argv[i]);
  }
  ErrLog(sock, name, buffer);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<OpsLogStart>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r15
  mov    %edx,%ebp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  test   %ebp,%ebp
  jle    L49
  mov    %ebp,%ebp
  mov    $0x1,%ebx
  lea    D18(%rip),%r13
  jmp    L40
L18:
  add    $0x1,%rbx
L40:
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  cmp    %rbp,%rbx
  je     L49
  test   %ebx,%ebx
  je     L18
  mov    %rsp,%rdi
  mov    %r13,%rsi
  call   <strcat@plt>
  jmp    L18
L49:
  mov    %rsp,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <ErrLog@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string
name: retrieve_data
arguments: data_tag: D18
type: string

tool: D4: PROGRAM START->

tool: D18:  

assistant: ```c
void OpsLogStart(int sock, char *name, int argc, char *argv[]) {
  char buffer[4096];
  int i;
  sprintf(buffer, "PROGRAM START->");
  for (i = 0; i < argc; i++) {
    if (i != 0)
      strcat(buffer, " ");
    strcat(buffer, argv[i]);
  }
  ErrLog(sock, name, buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<OpsLogStart>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %rsp,%r12
  mov    %edi,%r14d
  mov    %rsi,%r15
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  mov    %rcx,%rbx
  call   <sprintf@plt>
  test   %ebp,%ebp
  jle    L37
  lea    -0x1(%rbp),%eax
  lea    D12(%rip),%r13
  lea    0x8(%rbx,%rax,8),%rbp
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L10:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strcat@plt>
  cmp    %rbp,%rbx
  jne    L32
L37:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <ErrLog@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string

tool: D19: PROGRAM START->

tool: D12:  

assistant: ```c
void OpsLogStart(int sock, char *name, int argc, char *argv[]) {
  char buffer[4096];
  int i;
  sprintf(buffer, "PROGRAM START->");
  for (i = 0; i < argc; i++) {
    if (i != 0)
      strcat(buffer, " ");
    strcat(buffer, argv[i]);
  }
  ErrLog(sock, name, buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OpsLogStart>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %rsp,%r12
  mov    %edi,%r14d
  mov    %rsi,%r15
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  mov    %rcx,%rbx
  call   <sprintf@plt>
  test   %ebp,%ebp
  jle    L2
  lea    -0x1(%rbp),%eax
  lea    D14(%rip),%r13
  lea    0x8(%rbx,%rax,8),%rbp
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L18:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strcat@plt>
  cmp    %rbp,%rbx
  jne    L37
L2:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <ErrLog@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D16: PROGRAM START->

tool: D14:  

assistant: ```c
void OpsLogStart(int sock, char *name, int argc, char *argv[]) {
  char buffer[4096];
  int i;
  sprintf(buffer, "PROGRAM START->");
  for (i = 0; i < argc; i++) {
    if (i != 0)
      strcat(buffer, " ");
    strcat(buffer, argv[i]);
  }
  ErrLog(sock, name, buffer);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nearest_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L69
L71:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L52
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <error_handler@plt>
L52:
  addl   $0x1,-0x8(%rbp)
L69:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L71
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L107
  movl   $0x0,-0xc(%rbp)
  jmp    L74
L107:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L3
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L74
L3:
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L50
L9:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x18(%rbp),%xmm0
  jae    L66
  jmp    L50
L66:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movsd  -0x18(%rbp),%xmm1
  subsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jbe    L106
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L106:
  movl   $0x0,-0x4(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L74
  cmpl   $0x0,-0x4(%rbp)
  jne    L9
L74:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: nearest_index: array must be monotonically increasing

assistant: ```c
int nearest_index(double value, const double *array, int ia) {
  int index, i;
  int keep_going;
  for (i = 1; i < ia; i++) {
    if (array[i] < array[i - 1])
      error_handler("nearest_index: array must be monotonically increasing");
  }
  if (value < array[0])
    index = 0;
  else if (value > array[ia - 1])
    index = ia - 1;
  else {
    i = 0;
    keep_going = 1;
    while (i < ia && keep_going) {
      i = i + 1;
      if (value <= array[i]) {
        index = i;
        if (array[i] - value > value - array[i - 1])
          index = i - 1;
        keep_going = 0;
      }
    }
  }
  return index;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nearest_index>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %rdi,%rbp
  mov    %esi,%r13d
  cmp    $0x1,%esi
  jle    L77
  mov    %rdi,%rbx
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D3(%rip),%r14
  jmp    L46
L6:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L77
L46:
  movsd  (%rbx),%xmm0
  comisd 0x8(%rbx),%xmm0
  jbe    L6
  mov    %r14,%rdi
  call   <error_handler@plt>
  jmp    L6
L77:
  movsd  0x0(%rbp),%xmm0
  mov    $0x0,%eax
  movsd  0x8(%rsp),%xmm3
  comisd %xmm3,%xmm0
  ja     L91
  movslq %r13d,%rdx
  comisd -0x8(%rbp,%rdx,8),%xmm3
  ja     L85
  test   %r13d,%r13d
  jle    L91
  mov    $0x8,%edx
  mov    $0x0,%eax
  jmp    L95
L85:
  lea    -0x1(%r13),%eax
  jmp    L91
L24:
  add    $0x8,%rdx
  cmp    %eax,%r13d
  je     L91
L95:
  mov    %eax,%ecx
  add    $0x1,%eax
  movsd  0x0(%rbp,%rdx,1),%xmm1
  movsd  0x8(%rsp),%xmm2
  comisd %xmm2,%xmm1
  jb     L24
  subsd  %xmm2,%xmm1
  subsd  -0x8(%rbp,%rdx,1),%xmm2
  ucomisd %xmm2,%xmm1
  cmova  %ecx,%eax
L91:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: nearest_index: array must be monotonically increasing

assistant: ```c
int nearest_index(double value, const double *array, int ia) {
  int index, i;
  int keep_going;
  for (i = 1; i < ia; i++) {
    if (array[i] < array[i - 1])
      error_handler("nearest_index: array must be monotonically increasing");
  }
  if (value < array[0])
    index = 0;
  else if (value > array[ia - 1])
    index = ia - 1;
  else {
    i = 0;
    keep_going = 1;
    while (i < ia && keep_going) {
      i = i + 1;
      if (value <= array[i]) {
        index = i;
        if (array[i] - value > value - array[i - 1])
          index = i - 1;
        keep_going = 0;
      }
    }
  }
  return index;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nearest_index>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jle    L103
  lea    -0x2(%rsi),%eax
  mov    %rdi,%rbx
  lea    D6(%rip),%r14
  lea    0x8(%rdi,%rax,8),%r12
  jmp    L65
  nop
L92:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L103
L65:
  movsd  (%rbx),%xmm1
  comisd 0x8(%rbx),%xmm1
  jbe    L92
  mov    %r14,%rdi
  add    $0x8,%rbx
  movsd  %xmm0,0x8(%rsp)
  call   <error_handler@plt>
  movsd  0x8(%rsp),%xmm0
  cmp    %r12,%rbx
  jne    L65
L103:
  movsd  0x0(%rbp),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L12
  movslq %r13d,%rdx
  comisd -0x8(%rbp,%rdx,8),%xmm0
  ja     L57
  mov    $0x8,%edx
  test   %r13d,%r13d
  jle    L12
  nopl   0x0(%rax,%rax,1)
L5:
  movsd  0x0(%rbp,%rdx,1),%xmm1
  mov    %eax,%ecx
  add    $0x1,%eax
  comisd %xmm0,%xmm1
  jb     L30
  subsd  %xmm0,%xmm1
  subsd  -0x8(%rbp,%rdx,1),%xmm0
  ucomisd %xmm0,%xmm1
  cmova  %ecx,%eax
L12:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  add    $0x10,%rsp
  lea    -0x1(%r13),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  add    $0x8,%rdx
  cmp    %eax,%r13d
  jne    L5
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: nearest_index: array must be monotonically increasing

assistant: ```c
int nearest_index(double value, const double *array, int ia) {
  int index, i;
  int keep_going;
  for (i = 1; i < ia; i++) {
    if (array[i] < array[i - 1])
      error_handler("nearest_index: array must be monotonically increasing");
  }
  if (value < array[0])
    index = 0;
  else if (value > array[ia - 1])
    index = ia - 1;
  else {
    i = 0;
    keep_going = 1;
    while (i < ia && keep_going) {
      i = i + 1;
      if (value <= array[i]) {
        index = i;
        if (array[i] - value > value - array[i - 1])
          index = i - 1;
        keep_going = 0;
      }
    }
  }
  return index;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nearest_index>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jle    L69
  lea    -0x2(%rsi),%eax
  mov    %rdi,%rbx
  lea    D2(%rip),%r14
  lea    0x8(%rdi,%rax,8),%r12
  jmp    L104
  nop
L40:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L69
L104:
  movsd  (%rbx),%xmm1
  comisd 0x8(%rbx),%xmm1
  jbe    L40
  mov    %r14,%rdi
  add    $0x8,%rbx
  movsd  %xmm0,0x8(%rsp)
  call   <error_handler@plt>
  movsd  0x8(%rsp),%xmm0
  cmp    %rbx,%r12
  jne    L104
L69:
  movsd  0x0(%rbp),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L107
  movslq %r13d,%rdx
  comisd -0x8(%rbp,%rdx,8),%xmm0
  ja     L3
  mov    $0x8,%edx
  test   %r13d,%r13d
  jle    L107
  nopl   0x0(%rax,%rax,1)
L22:
  movsd  0x0(%rbp,%rdx,1),%xmm1
  mov    %eax,%ecx
  add    $0x1,%eax
  comisd %xmm0,%xmm1
  jb     L84
  subsd  %xmm0,%xmm1
  subsd  -0x8(%rbp,%rdx,1),%xmm0
  ucomisd %xmm0,%xmm1
  cmova  %ecx,%eax
L107:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x10,%rsp
  lea    -0x1(%r13),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L84:
  add    $0x8,%rdx
  cmp    %eax,%r13d
  jne    L22
  jmp    L107
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string

tool: D2: nearest_index: array must be monotonically increasing

assistant: ```c
int nearest_index(double value, const double *array, int ia) {
  int index, i;
  int keep_going;
  for (i = 1; i < ia; i++) {
    if (array[i] < array[i - 1])
      error_handler("nearest_index: array must be monotonically increasing");
  }
  if (value < array[0])
    index = 0;
  else if (value > array[ia - 1])
    index = ia - 1;
  else {
    i = 0;
    keep_going = 1;
    while (i < ia && keep_going) {
      i = i + 1;
      if (value <= array[i]) {
        index = i;
        if (array[i] - value > value - array[i - 1])
          index = i - 1;
        keep_going = 0;
      }
    }
  }
  return index;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L25
L30:
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L40
L33:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L40:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L21
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L33
L21:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

assistant: ```c
char *my_strndup(const char *str, const unsigned int n) {
  char *dup;
  unsigned int i;
  if (!(dup = malloc(n + 1)))
    return (NULL);
  i = -1;
  while (str[++i] && i < n)
    dup[i] = str[i];
  dup[i] = '\0';
  return (dup);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_strndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L51
  movzbl 0x0(%rbp),%esi
  test   %ebx,%ebx
  je     L8
  test   %sil,%sil
  je     L8
  mov    $0x0,%edx
  mov    $0x0,%ecx
L41:
  mov    %sil,(%rax,%rcx,1)
  add    $0x1,%edx
  mov    %edx,%ecx
  movzbl 0x0(%rbp,%rcx,1),%esi
  cmp    %edx,%ebx
  jbe    L19
  test   %sil,%sil
  jne    L41
L19:
  movb   $0x0,(%rax,%rcx,1)
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x0,%ecx
  jmp    L19
```

assistant: ```c
char *my_strndup(const char *str, const unsigned int n) {
  char *dup;
  unsigned int i;
  if (!(dup = malloc(n + 1)))
    return (NULL);
  i = -1;
  while (str[++i] && i < n)
    dup[i] = str[i];
  dup[i] = '\0';
  return (dup);
}
```