ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  mov    0x18(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  mov    0x20(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jae    L43
  mov    -0x28(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jae    L43
  mov    $0xffffffff,%eax
  jmp    L13
L43:
  mov    -0x50(%rbp),%r9
  mov    -0x48(%rbp),%r8
  mov    -0x60(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x78(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x20(%rbp),%rdi
  push   %rdi
  push   -0x40(%rbp)
  push   -0x38(%rbp)
  mov    %rax,%rdi
  call   <AEAD_ENC@plt>
  add    $0x20,%rsp
  movl   $0x0,-0x2c(%rbp)
  jmp    L57
L38:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x2c(%rbp)
L57:
  cmpl   $0xf,-0x2c(%rbp)
  jle    L38
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  lea    0x10(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  unsigned long long cr;
  unsigned char tag[16];
  cr = mlen + adlen;
  if ((cr < mlen) && (cr < adlen))
    return -1;
  AEAD_ENC(k, npub, ad, adlen, m, mlen, c, clen, tag);
  do {
    int u;
    for (u = 0; u < 16; u++)
      (c + *clen)[u] = (tag)[u];
  } while (0);
  *clen += 16;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%r10
  mov    %rcx,%rax
  mov    0x48(%rsp),%r12
  mov    0x50(%rsp),%r11
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  lea    (%rcx,%r9,1),%rsi
  cmp    %r9,%rcx
  mov    %r9,%rdx
  cmovbe %rcx,%rdx
  cmp    %rdx,%rsi
  jb     L13
  mov    %rdi,%rbp
  mov    %r8,%rdi
  mov    %r9,%rcx
  sub    $0x8,%rsp
  lea    0x8(%rsp),%rdx
  push   %rdx
  push   %rbx
  push   %rbp
  mov    %rax,%r9
  mov    %r10,%r8
  mov    %rdi,%rdx
  mov    %r12,%rsi
  mov    %r11,%rdi
  call   <AEAD_ENC@plt>
  add    $0x20,%rsp
  mov    $0x0,%eax
L25:
  lea    0x0(%rbp,%rax,1),%rdx
  add    (%rbx),%rdx
  movzbl (%rsp,%rax,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L25
  addq   $0x10,(%rbx)
  mov    $0x0,%eax
L3:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L3
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  unsigned long long cr;
  unsigned char tag[16];
  cr = mlen + adlen;
  if ((cr < mlen) && (cr < adlen))
    return -1;
  AEAD_ENC(k, npub, ad, adlen, m, mlen, c, clen, tag);
  do {
    int u;
    for (u = 0; u < 16; u++)
      (c + *clen)[u] = (tag)[u];
  } while (0);
  *clen += 16;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %r13
  mov    %rcx,%rax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  lea    (%rcx,%r9,1),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  cmp    %r9,%rcx
  mov    %r9,%rdx
  mov    0x58(%rsp),%r13
  cmovbe %rcx,%rdx
  mov    0x60(%rsp),%r11
  cmp    %rdx,%rsi
  jb     L11
  sub    $0x8,%rsp
  mov    %r8,%r10
  mov    %r9,%rcx
  mov    %rdi,%r8
  lea    0x8(%rsp),%r12
  mov    %rax,%r9
  mov    %r10,%rdx
  mov    %r13,%rsi
  push   %r12
  mov    %r11,%rdi
  push   %rbx
  push   %rbp
  call   <AEAD_ENC@plt>
  mov    %r12,%rsp
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  movzbl (%r12,%rax,1),%ecx
  lea    0x0(%rbp,%rax,1),%rdx
  add    $0x1,%rax
  add    (%rbx),%rdx
  mov    %cl,(%rdx)
  cmp    $0x10,%rax
  jne    L23
  addq   $0x10,(%rbx)
  xor    %eax,%eax
L36:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L36
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  unsigned long long cr;
  unsigned char tag[16];
  cr = mlen + adlen;
  if ((cr < mlen) && (cr < adlen))
    return -1;
  AEAD_ENC(k, npub, ad, adlen, m, mlen, c, clen, tag);
  do {
    int u;
    for (u = 0; u < 16; u++)
      (c + *clen)[u] = (tag)[u];
  } while (0);
  *clen += 16;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %r12
  mov    %rcx,%rax
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  lea    (%rcx,%r9,1),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  cmp    %r9,%rcx
  mov    %r9,%rdx
  mov    0x48(%rsp),%r12
  cmovbe %rcx,%rdx
  mov    0x50(%rsp),%r11
  cmp    %rdx,%rsi
  jb     L11
  sub    $0x8,%rsp
  mov    %r8,%r10
  mov    %r9,%rcx
  mov    %rdi,%r8
  lea    0x8(%rsp),%rdx
  mov    %rax,%r9
  mov    %r12,%rsi
  mov    %r11,%rdi
  push   %rdx
  mov    %r10,%rdx
  push   %rbx
  push   %rbp
  call   <AEAD_ENC@plt>
  mov    (%rbx),%rax
  movzbl 0x20(%rsp),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  movzbl 0x21(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x1(%rbp,%rax,1)
  movzbl 0x22(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x2(%rbp,%rax,1)
  movzbl 0x23(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x3(%rbp,%rax,1)
  movzbl 0x24(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x4(%rbp,%rax,1)
  movzbl 0x25(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x5(%rbp,%rax,1)
  movzbl 0x26(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x6(%rbp,%rax,1)
  movzbl 0x27(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x7(%rbp,%rax,1)
  movzbl 0x28(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x8(%rbp,%rax,1)
  movzbl 0x29(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0x9(%rbp,%rax,1)
  movzbl 0x2a(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0xa(%rbp,%rax,1)
  mov    (%rbx),%rax
  movzbl 0x2b(%rsp),%edx
  mov    %dl,0xb(%rbp,%rax,1)
  movzbl 0x2c(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0xc(%rbp,%rax,1)
  movzbl 0x2d(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0xd(%rbp,%rax,1)
  movzbl 0x2e(%rsp),%edx
  mov    (%rbx),%rax
  mov    %dl,0xe(%rbp,%rax,1)
  movzbl 0x2f(%rsp),%edx
  add    $0x20,%rsp
  mov    (%rbx),%rax
  mov    %dl,0xf(%rbp,%rax,1)
  xor    %eax,%eax
  addq   $0x10,(%rbx)
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L17
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  unsigned long long cr;
  unsigned char tag[16];
  cr = mlen + adlen;
  if ((cr < mlen) && (cr < adlen))
    return -1;
  AEAD_ENC(k, npub, ad, adlen, m, mlen, c, clen, tag);
  do {
    int u;
    for (u = 0; u < 16; u++)
      (c + *clen)[u] = (tag)[u];
  } while (0);
  *clen += 16;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Listen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <listen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: Error listening

assistant: ```c
int Listen(int des, int backlog) {
  int temp;
  temp = listen(des, backlog);
  if (temp < 0) {
    perror("Error listening");
    exit(1);
  }
  return temp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Listen>:
  endbr64
  push   %rbx
  call   <listen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L3
L9:
  mov    %ebx,%eax
  pop    %rbx
  ret
L3:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: Error listening

assistant: ```c
int Listen(int des, int backlog) {
  int temp;
  temp = listen(des, backlog);
  if (temp < 0) {
    perror("Error listening");
    exit(1);
  }
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Listen>:
  endbr64
  push   %r12
  call   <listen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: Error listening

assistant: ```c
int Listen(int des, int backlog) {
  int temp;
  temp = listen(des, backlog);
  if (temp < 0) {
    perror("Error listening");
    exit(1);
  }
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Listen>:
  endbr64
  push   %r12
  call   <listen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L6
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: Error listening

assistant: ```c
int Listen(int des, int backlog) {
  int temp;
  temp = listen(des, backlog);
  if (temp < 0) {
    perror("Error listening");
    exit(1);
  }
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_prefix_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0xffffffff,(%rax)
  jmp    L44
L45:
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L37
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
L37:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L44
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L44:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L45
  nop
  nop
  leave
  ret
```

assistant: ```c
void compute_prefix_function(const char *pattern, int *next) {
  int i = 0;
  int j = -1;
  next[0] = -1;
  while (i < strlen(pattern) - 1) {
    if (-1 == j || pattern[i] == pattern[j]) {
      ++i;
      ++j;
      next[i] = j;
    } else {
      j = next[j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<compute_prefix_function>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  movl   $0xffffffff,(%rsi)
  mov    $0xffffffff,%ebx
  mov    $0x0,%ebp
  jmp    L20
L15:
  add    $0x1,%ebp
  add    $0x1,%ebx
  movslq %ebp,%rax
  mov    %ebx,0x0(%r13,%rax,4)
L20:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jle    L25
  cmp    $0xffffffff,%ebx
  je     L15
  movslq %ebx,%rax
  movslq %ebp,%rdx
  movzbl (%r12,%rax,1),%ecx
  cmp    %cl,(%r12,%rdx,1)
  je     L15
  mov    0x0(%r13,%rax,4),%ebx
  jmp    L20
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void compute_prefix_function(const char *pattern, int *next) {
  int i = 0;
  int j = -1;
  next[0] = -1;
  while (i < strlen(pattern) - 1) {
    if (-1 == j || pattern[i] == pattern[j]) {
      ++i;
      ++j;
      next[i] = j;
    } else {
      j = next[j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compute_prefix_function>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x8,%rsp
  movl   $0xffffffff,(%rsi)
  nopl   0x0(%rax)
L31:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jle    L27
L35:
  cmp    $0xffffffff,%ebx
  je     L1
  movslq %ebx,%rax
  movslq %ebp,%rdx
  movzbl (%r12,%rax,1),%ecx
  cmp    %cl,(%r12,%rdx,1)
  je     L1
  mov    %r12,%rdi
  mov    0x0(%r13,%rax,4),%ebx
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jg     L35
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  add    $0x1,%ebp
  add    $0x1,%ebx
  movslq %ebp,%rax
  mov    %ebx,0x0(%r13,%rax,4)
  jmp    L31
```

assistant: ```c
void compute_prefix_function(const char *pattern, int *next) {
  int i = 0;
  int j = -1;
  next[0] = -1;
  while (i < strlen(pattern) - 1) {
    if (-1 == j || pattern[i] == pattern[j]) {
      ++i;
      ++j;
      next[i] = j;
    } else {
      j = next[j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compute_prefix_function>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x8,%rsp
  movl   $0xffffffff,(%rsi)
  nopl   0x0(%rax)
L48:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jle    L13
L4:
  cmp    $0xffffffff,%ebx
  je     L2
  movslq %ebx,%rax
  movslq %ebp,%rdx
  movzbl (%r12,%rax,1),%ecx
  cmp    %cl,(%r12,%rdx,1)
  je     L2
  mov    %r12,%rdi
  mov    0x0(%r13,%rax,4),%ebx
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jg     L4
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  add    $0x1,%ebp
  add    $0x1,%ebx
  movslq %ebp,%rax
  mov    %ebx,0x0(%r13,%rax,4)
  jmp    L48
```

assistant: ```c
void compute_prefix_function(const char *pattern, int *next) {
  int i = 0;
  int j = -1;
  next[0] = -1;
  while (i < strlen(pattern) - 1) {
    if (-1 == j || pattern[i] == pattern[j]) {
      ++i;
      ++j;
      next[i] = j;
    } else {
      j = next[j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<align_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,%rax
  sub    %rax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const void *align_to(size_t tz, const void *p) {
  uintptr_t x = (uintptr_t)p;
  if (x % tz) {
    x -= x % tz;
  }
  return (const void *)x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<align_to>:
  endbr64
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rdi
  mov    %rsi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
const void *align_to(size_t tz, const void *p) {
  uintptr_t x = (uintptr_t)p;
  if (x % tz) {
    x -= x % tz;
  }
  return (const void *)x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<align_to>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rdi
  mov    %rsi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
const void *align_to(size_t tz, const void *p) {
  uintptr_t x = (uintptr_t)p;
  if (x % tz) {
    x -= x % tz;
  }
  return (const void *)x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<align_to>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rdi
  mov    %rsi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
const void *align_to(size_t tz, const void *p) {
  uintptr_t x = (uintptr_t)p;
  if (x % tz) {
    x -= x % tz;
  }
  return (const void *)x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<work1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L13:
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <work2@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L13
  nop
  leave
  ret
```

assistant: ```c
work1(i, n) int i, n;
{
  int j;
#pragma omp for
  for (j = 0; j < n; j++) {
    work2(i, j);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<work1>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x0,%ebx
L7:
  mov    %ebx,%esi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <work2@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  ret
```

assistant: ```c
work1(i, n) int i, n;
{
  int j;
#pragma omp for
  for (j = 0; j < n; j++) {
    work2(i, j);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<work1>:
  endbr64
  test   %esi,%esi
  jle    L6
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%esi
  mov    %r12d,%edi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <work2@plt>
  cmp    %ebx,%ebp
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  ret
```

assistant: ```c
work1(i, n) int i, n;
{
  int j;
#pragma omp for
  for (j = 0; j < n; j++) {
    work2(i, j);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<work1>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%esi
  mov    %r12d,%edi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <work2@plt>
  cmp    %ebx,%ebp
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  ret
```

assistant: ```c
work1(i, n) int i, n;
{
  int j;
#pragma omp for
  for (j = 0; j < n; j++) {
    work2(i, j);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L0
L24:
  movq   $0x0,-0x8(%rbp)
  jmp    L30
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,-0x8(%rbp)
L30:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L3
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *r;
  if (c == 0)
    return strchr(s, 0);
  r = 0;
  while (s = strchr(s, c))
    r = (char *)s++;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strrchr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%r12d
  test   %esi,%esi
  jne    L10
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r12
  jmp    L21
L9:
  lea    0x1(%rax),%rbx
  mov    %rax,%r12
L10:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L9
L21:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *r;
  if (c == 0)
    return strchr(s, 0);
  r = 0;
  while (s = strchr(s, c))
    r = (char *)s++;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strrchr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  test   %esi,%esi
  jne    L1
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
L1:
  mov    %ebx,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L12
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L16:
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  lea    (%rdi,%rax,1),%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *r;
  if (c == 0)
    return strchr(s, 0);
  r = 0;
  while (s = strchr(s, c))
    r = (char *)s++;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strrchr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  test   %esi,%esi
  jne    L29
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
L29:
  mov    %ebx,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L17
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L14:
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  lea    (%rdi,%rax,1),%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *r;
  if (c == 0)
    return strchr(s, 0);
  r = 0;
  while (s = strchr(s, c))
    r = (char *)s++;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xce4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```