user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0xae8,%rsp
  movdqa D103(%rip),%xmm0
  mov    $0xa,%ecx
  xor    %esi,%esi
  mov    $0xc,%edx
  lea    D93(%rip),%rbp
  lea    D86(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3d0ad8(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D54(%rip),%xmm0
  mov    %rsp,%rdi
  movl   $0x63,0x30(%rsp)
  lea    0x1d0(%rsp),%r12
  lea    0x3d0ad0(%rsp),%rbx
  movaps %xmm0,0x10(%rsp)
  movdqa D108(%rip),%xmm0
  mov    %r12,%r15
  movaps %xmm0,0x20(%rsp)
  call   <findRank@plt>
  mov    $0xa,%esi
  lea    D56(%rip),%rdi
  mov    (%rsp,%rax,4),%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D57(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x4,%r15
  call   <fscanf@plt>
  cmp    %r15,%rbx
  jne    L41
  lea    D82(%rip),%rdi
  lea    0x40(%rsp),%rbx
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  mov    %rbx,%rbp
  call   <fopen@plt>
  mov    %rax,%r15
  nopl   (%rax)
L46:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x4,%rbp
  call   <fscanf@plt>
  cmp    %rbp,%r12
  jne    L46
  mov    %r15,%rdi
  lea    D118(%rip),%r13
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  lea    D98(%rip),%rsi
  lea    D106(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L33:
  mov    (%rbx),%ecx
  mov    $0xf423f,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <findRank@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    0x1d0(%rsp,%rax,4),%edx
  call   <fprintf@plt>
  cmp    %rbx,%r12
  jne    L33
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  mov    0x3d0ad8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x3d0ae8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D103
data_type: byte[16]
name: parse_data
arguments: data_label: D93
data_type: string
name: parse_data
arguments: data_label: D86
data_type: string
name: parse_data
arguments: data_label: D54
data_type: byte[16]
name: parse_data
arguments: data_label: D108
data_type: byte[16]
name: parse_data
arguments: data_label: D56
data_type: string
name: parse_data
arguments: data_label: D82
data_type: string
name: parse_data
arguments: data_label: D57
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D118
data_type: string
name: parse_data
arguments: data_label: D98
data_type: string
name: parse_data
arguments: data_label: D106
data_type: string

tool: {"D103": [0x0a,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x3c,0x00,0x00,0x00,0x64,0x00,0x00,0x00]}

tool: D93: r

tool: D86: %d

tool: {"D54": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D108": [0x50,0x00,0x00,0x00,0x28,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x16,0x00,0x00,0x00]}

tool: D56: 
 The element with rank %d is %d


tool: D82: 





tool: D57: data.in

tool: D5: data_rank.in

tool: D118: %d


tool: D98: w

tool: D106: data_out.in

assistant: ```c
int main(int argc, char *argv[]) {
  int A[1000000], B[100];
  FILE *fp_num, *fp_rank, *fp_out;
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  int rank = 10;
  printf("\n The element with rank %d is %d\n", rank, a[findRank(a, 0, size - 1, rank)]);
  printf("\n");
  printf("\n\n\n\n\n");
  fp_num = fopen("data.in", "r");
  for (int i = 0; i < 1000000; i++)
    fscanf(fp_num, "%d", &A[i]);
  printf("\n\n\n\n\n");
  fp_rank = fopen("data_rank.in", "r");
  for (int i = 0; i < 100; i++)
    fscanf(fp_rank, "%d", &B[i]);
  fclose(fp_rank);
  fclose(fp_num);
  fp_out = fopen("data_out.in", "w");
  for (int i = 0; i < 100; i++) {
    fprintf(fp_out, "%d\n", A[findRank(A, 0, 1000000 - 1, B[i])]);
  }
  fclose(fp_out);
  printf("\n\n\n\n\n");
  return 0;
}
```