ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_254_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_254_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rop3_254_1_0>:
  endbr64
  mov    %esi,%eax
  or     (%rdi),%al
  or     %edx,%eax
  mov    %esi,%edx
  not    %edx
  and    %edx,%eax
  mov    %esi,%edx
  and    (%rdi),%dl
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_254_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_254_1_0>:
  endbr64
  movzbl (%rdi),%eax
  or     %esi,%eax
  or     %edx,%eax
  mov    %esi,%edx
  not    %edx
  and    %edx,%eax
  movzbl (%rdi),%edx
  and    %esi,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_254_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_254_1_0>:
  endbr64
  movzbl (%rdi),%eax
  or     %esi,%eax
  or     %edx,%eax
  mov    %esi,%edx
  not    %edx
  and    %edx,%eax
  movzbl (%rdi),%edx
  and    %esi,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_254_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x7,-0xc(%rbp)
  movl   $0x8,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <test_and@plt>
  leave
  ret
```

assistant: ```c
int main() {
  int a = 7;
  int b = 8;
  int c = 1;
  return test_and(a, b, c);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    $0x7,%edi
  call   <test_and@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 7;
  int b = 8;
  int c = 1;
  return test_and(a, b, c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    $0x7,%edi
  jmp    1050 <test_and@plt>
```

assistant: ```c
int main() {
  int a = 7;
  int b = 8;
  int c = 1;
  return test_and(a, b, c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fmin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L29
  movsd  -0x10(%rbp),%xmm0
  jmp    L26
L29:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L12
  movsd  -0x8(%rbp),%xmm0
  jmp    L26
L12:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L6
  movsd  -0x8(%rbp),%xmm0
  jmp    L26
L6:
  movsd  -0x10(%rbp),%xmm0
L26:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double fmin(double x, double y) {
  if (isnan(x))
    return y;
  if (isnan(y))
    return x;
  return x < y ? x : y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fmin>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  movq   %xmm1,%rbx
  call   <isnan@plt>
  test   %rax,%rax
  je     L30
L7:
  movq   %rbx,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  movq   %rbx,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L19
  movq   %rbp,%xmm2
  movq   %rbx,%xmm3
  minsd  %xmm3,%xmm2
  movq   %xmm2,%rbx
  jmp    L7
L19:
  mov    %rbp,%rbx
  jmp    L7
```

assistant: ```c
double fmin(double x, double y) {
  if (isnan(x))
    return y;
  if (isnan(y))
    return x;
  return x < y ? x : y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fmin>:
  endbr64
  push   %rbx
  movq   %xmm1,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <isnan@plt>
  test   %rax,%rax
  je     L15
L2:
  movq   %rbx,%xmm0
L8:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L15:
  movq   %rbx,%xmm0
  call   <isnan@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  test   %rax,%rax
  jne    L8
  movq   %rbx,%xmm3
  comisd %xmm2,%xmm3
  jbe    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double fmin(double x, double y) {
  if (isnan(x))
    return y;
  if (isnan(y))
    return x;
  return x < y ? x : y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fmin>:
  endbr64
  push   %rbx
  movq   %xmm1,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <isnan@plt>
  test   %rax,%rax
  je     L3
L5:
  movq   %rbx,%xmm0
L0:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  movq   %rbx,%xmm0
  call   <isnan@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  test   %rax,%rax
  jne    L0
  movq   %rbx,%xmm3
  comisd %xmm2,%xmm3
  jbe    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double fmin(double x, double y) {
  if (isnan(x))
    return y;
  if (isnan(y))
    return x;
  return x < y ? x : y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<queue_int_tostring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L10
  lea    D5(%rip),%rax
  jmp    L14
L10:
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L13:
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L3:
  cmpl   $0x0,-0x10(%rbp)
  jne    L13
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L21
L54:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
L21:
  cmpl   $0x0,-0x24(%rbp)
  jne    L54
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: 0

assistant: ```c
char *queue_int_tostring(int number) {
  int length, temp = number;
  if (!number) {
    return "0";
  }
  for (length = 0; temp; temp /= 10) {
    length++;
  }
  char *result = (char *)malloc((length + 1) * sizeof(char));
  int i;
  for (i = length; number; number /= 10) {
    result[--i] = (char)('0' + number % 10);
  }
  result[length] = 0;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<queue_int_tostring>:
  endbr64
  lea    D3(%rip),%rax
  test   %edi,%edi
  je     L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%edx
  mov    $0x0,%ebp
L23:
  mov    %ebp,%edi
  add    $0x1,%ebp
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  jne    L23
  add    $0x2,%edi
  call   <malloc@plt>
  movslq %ebp,%rbp
  lea    -0x1(%rax,%rbp,1),%rsi
L7:
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rsi)
  mov    %edx,%ebx
  sub    $0x1,%rsi
  test   %edx,%edx
  jne    L7
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: 0

assistant: ```c
char *queue_int_tostring(int number) {
  int length, temp = number;
  if (!number) {
    return "0";
  }
  for (length = 0; temp; temp /= 10) {
    length++;
  }
  char *result = (char *)malloc((length + 1) * sizeof(char));
  int i;
  for (i = length; number; number /= 10) {
    result[--i] = (char)('0' + number % 10);
  }
  result[length] = 0;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<queue_int_tostring>:
  endbr64
  test   %edi,%edi
  je     L3
  push   %rbp
  mov    %edi,%edx
  xor    %ebp,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L19:
  movslq %edx,%rax
  mov    %edx,%ecx
  mov    %ebp,%edi
  add    $0x1,%ebp
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L19
  add    $0x2,%edi
  movslq %ebp,%rbp
  call   <malloc@plt>
  lea    -0x1(%rax,%rbp,1),%rsi
  xchg   %ax,%ax
L13:
  movslq %ebx,%rdx
  mov    %ebx,%ecx
  sub    $0x1,%rsi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rsi)
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L13
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: 0

assistant: ```c
char *queue_int_tostring(int number) {
  int length, temp = number;
  if (!number) {
    return "0";
  }
  for (length = 0; temp; temp /= 10) {
    length++;
  }
  char *result = (char *)malloc((length + 1) * sizeof(char));
  int i;
  for (i = length; number; number /= 10) {
    result[--i] = (char)('0' + number % 10);
  }
  result[length] = 0;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<queue_int_tostring>:
  endbr64
  test   %edi,%edi
  je     L25
  push   %rbp
  mov    %edi,%edx
  xor    %ebp,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L12:
  movslq %edx,%rax
  mov    %edx,%ecx
  mov    %ebp,%edi
  add    $0x1,%ebp
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L12
  add    $0x2,%edi
  movslq %ebp,%rbp
  call   <malloc@plt>
  lea    -0x1(%rax,%rbp,1),%rsi
  xchg   %ax,%ax
L0:
  movslq %ebx,%rdx
  mov    %ebx,%ecx
  sub    $0x1,%rsi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rsi)
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L0
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: 0

assistant: ```c
char *queue_int_tostring(int number) {
  int length, temp = number;
  if (!number) {
    return "0";
  }
  for (length = 0; temp; temp /= 10) {
    length++;
  }
  char *result = (char *)malloc((length + 1) * sizeof(char));
  int i;
  for (i = length; number; number /= 10) {
    result[--i] = (char)('0' + number % 10);
  }
  result[length] = 0;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<programHeader2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: Student Assignment Number %d
Student: Don Retzlaff donr@unt.edu



assistant: ```c
void programHeader2(int assignmentNumber) {
  printf("Student Assignment Number %d\n"
         "Student: Don Retzlaff donr@unt.edu\n\n",
         assignmentNumber);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<programHeader2>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: Student Assignment Number %d
Student: Don Retzlaff donr@unt.edu



assistant: ```c
void programHeader2(int assignmentNumber) {
  printf("Student Assignment Number %d\n"
         "Student: Don Retzlaff donr@unt.edu\n\n",
         assignmentNumber);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<programHeader2>:
  endbr64
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: Student Assignment Number %d
Student: Don Retzlaff donr@unt.edu



assistant: ```c
void programHeader2(int assignmentNumber) {
  printf("Student Assignment Number %d\n"
         "Student: Don Retzlaff donr@unt.edu\n\n",
         assignmentNumber);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<programHeader2>:
  endbr64
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: Student Assignment Number %d
Student: Don Retzlaff donr@unt.edu



assistant: ```c
void programHeader2(int assignmentNumber) {
  printf("Student Assignment Number %d\n"
         "Student: Don Retzlaff donr@unt.edu\n\n",
         assignmentNumber);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<InvCipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0xa,%edi
  call   <AddRoundKey@plt>
  movl   $0x9,-0x4(%rbp)
  jmp    L12
L10:
  mov    $0x0,%eax
  call   <InvShiftRows@plt>
  mov    $0x0,%eax
  call   <InvSubBytes@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <AddRoundKey@plt>
  mov    $0x0,%eax
  call   <InvMixColumns@plt>
  subl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  jg     L10
  mov    $0x0,%eax
  call   <InvShiftRows@plt>
  mov    $0x0,%eax
  call   <InvSubBytes@plt>
  mov    $0x0,%edi
  call   <AddRoundKey@plt>
  nop
  leave
  ret
```

assistant: ```c
void InvCipher(void) {
  uint8_t round = 0;
  AddRoundKey(10);
  for (round = 10 - 1; round > 0; round--) {
    InvShiftRows();
    InvSubBytes();
    AddRoundKey(round);
    InvMixColumns();
  }
  InvShiftRows();
  InvSubBytes();
  AddRoundKey(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InvCipher>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <AddRoundKey@plt>
  mov    $0x9,%ebx
L6:
  mov    $0x0,%eax
  call   <InvShiftRows@plt>
  mov    $0x0,%eax
  call   <InvSubBytes@plt>
  mov    %ebx,%edi
  call   <AddRoundKey@plt>
  mov    $0x0,%eax
  call   <InvMixColumns@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  call   <InvShiftRows@plt>
  mov    $0x0,%eax
  call   <InvSubBytes@plt>
  mov    $0x0,%edi
  call   <AddRoundKey@plt>
  pop    %rbx
  ret
```

assistant: ```c
void InvCipher(void) {
  uint8_t round = 0;
  AddRoundKey(10);
  for (round = 10 - 1; round > 0; round--) {
    InvShiftRows();
    InvSubBytes();
    AddRoundKey(round);
    InvMixColumns();
  }
  InvShiftRows();
  InvSubBytes();
  AddRoundKey(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InvCipher>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  mov    $0x9,%ebx
  call   <AddRoundKey@plt>
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <InvShiftRows@plt>
  xor    %eax,%eax
  call   <InvSubBytes@plt>
  mov    %ebx,%edi
  call   <AddRoundKey@plt>
  xor    %eax,%eax
  call   <InvMixColumns@plt>
  sub    $0x1,%ebx
  jne    L7
  xor    %eax,%eax
  call   <InvShiftRows@plt>
  xor    %eax,%eax
  call   <InvSubBytes@plt>
  xor    %edi,%edi
  pop    %rbx
  jmp    10b0 <AddRoundKey@plt>
```

assistant: ```c
void InvCipher(void) {
  uint8_t round = 0;
  AddRoundKey(10);
  for (round = 10 - 1; round > 0; round--) {
    InvShiftRows();
    InvSubBytes();
    AddRoundKey(round);
    InvMixColumns();
  }
  InvShiftRows();
  InvSubBytes();
  AddRoundKey(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InvCipher>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  mov    $0x9,%ebx
  call   <AddRoundKey@plt>
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <InvShiftRows@plt>
  xor    %eax,%eax
  call   <InvSubBytes@plt>
  mov    %ebx,%edi
  call   <AddRoundKey@plt>
  xor    %eax,%eax
  call   <InvMixColumns@plt>
  sub    $0x1,%ebx
  jne    L0
  xor    %eax,%eax
  call   <InvShiftRows@plt>
  xor    %eax,%eax
  call   <InvSubBytes@plt>
  xor    %edi,%edi
  pop    %rbx
  jmp    10b0 <AddRoundKey@plt>
```

assistant: ```c
void InvCipher(void) {
  uint8_t round = 0;
  AddRoundKey(10);
  for (round = 10 - 1; round > 0; round--) {
    InvShiftRows();
    InvSubBytes();
    AddRoundKey(round);
    InvMixColumns();
  }
  InvShiftRows();
  InvSubBytes();
  AddRoundKey(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_collapse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%r13d
  jmp    L6
L40:
  sub    $0x1,%r13d
  je     L11
L6:
  mov    $0x10,%r12d
L12:
  mov    $0x10,%ebp
L29:
  mov    $0x10,%ebx
L24:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L24
  sub    $0x1,%ebp
  jne    L29
  sub    $0x1,%r12d
  jne    L12
  jmp    L40
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel
#pragma omp for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel
#pragma omp for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(2)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L27:
  mov    $0x10,%r12d
L18:
  mov    $0x10,%ebp
  nop
L36:
  mov    $0x10,%ebx
  nopl   (%rax)
L34:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L34
  sub    $0x1,%ebp
  jne    L36
  sub    $0x1,%r12d
  jne    L18
  sub    $0x1,%r13d
  jne    L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel
#pragma omp for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel
#pragma omp for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(2)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```