ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<grow_expansion_zeroelim>:
  endbr64
  test   %edi,%edi
  jle    L44
  lea    -0x1(%rdi),%eax
  pxor   %xmm5,%xmm5
  lea    0x8(%rsi,%rax,8),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L53:
  movsd  (%rsi),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  ucomisd %xmm5,%xmm1
  jp     L45
  je     L33
L45:
  movslq %eax,%rdi
  add    $0x1,%eax
  movsd  %xmm1,(%rdx,%rdi,8)
L33:
  add    $0x8,%rsi
  cmp    %rsi,%rcx
  jne    L53
  ucomisd %xmm5,%xmm0
  mov    $0x1,%esi
  setp   %cl
  cmovne %esi,%ecx
  test   %cl,%cl
  jne    L25
  test   %eax,%eax
  je     L25
  ret
  nopl   0x0(%rax)
L25:
  movslq %eax,%rcx
  add    $0x1,%eax
  lea    (%rdx,%rcx,8),%rdx
L13:
  movsd  %xmm0,(%rdx)
  ret
  nop
L44:
  mov    $0x1,%eax
  jmp    L13
```

assistant: ```c
int grow_expansion_zeroelim(int elen, double *e, double b, double *h) {
  double Q, hh;
  double Qnew;
  int eindex, hindex;
  double enow;
  double bvirt;
  double avirt, bround, around;
  hindex = 0;
  Q = b;
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    hh = around + bround;
    Q = Qnew;
    if (hh != 0.0) {
      h[hindex++] = hh;
    }
  }
  if ((Q != 0.0) || (hindex == 0)) {
    h[hindex++] = Q;
  }
  return hindex;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int index = 0;
  for (index = 0; index < size; index++) {
    printf("%d ", arr[index]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D6(%rip),%rbp
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int index = 0;
  for (index = 0; index < size; index++) {
    printf("%d ", arr[index]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int index = 0;
  for (index = 0; index < size; index++) {
    printf("%d ", arr[index]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string

tool: D2: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int index = 0;
  for (index = 0; index < size; index++) {
    printf("%d ", arr[index]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mlt_audio_calculate_samples_to_position>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0x14(%rbp),%xmm0
  jp     L18
  pxor   %xmm0,%xmm0
  ucomiss -0x14(%rbp),%xmm0
  je     L7
L18:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x20(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x14(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  cmpq   $0x0,-0x20(%rbp)
  jns    L35
  movsd  D4(%rip),%xmm0
  jmp    L17
L35:
  movsd  D9(%rip),%xmm0
L17:
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: byte[8]
name: disassemble_data
arguments: tag: D9
type_infered: f64

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D9: 0.5

assistant: ```c
int64_t mlt_audio_calculate_samples_to_position(float fps, int frequency, int64_t position) {
  int64_t samples = 0;
  if (fps) {
    samples = (int64_t)((double)position * (double)frequency / (double)fps + (position < 0 ? -0.5 : 0.5));
  }
  return samples;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mlt_audio_calculate_samples_to_position>:
  endbr64
  ucomiss D20(%rip),%xmm0
  jp     L28
  mov    $0x0,%eax
  jne    L28
L27:
  ret
L28:
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  mulsd  %xmm2,%xmm1
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D20(%rip),%xmm0
  test   %rsi,%rsi
  js     L34
  movsd  D29(%rip),%xmm0
L34:
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  jmp    L27
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: f64

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D29: 0.5

assistant: ```c
int64_t mlt_audio_calculate_samples_to_position(float fps, int frequency, int64_t position) {
  int64_t samples = 0;
  if (fps) {
    samples = (int64_t)((double)position * (double)frequency / (double)fps + (position < 0 ? -0.5 : 0.5));
  }
  return samples;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mlt_audio_calculate_samples_to_position>:
  endbr64
  ucomiss D19(%rip),%xmm0
  jp     L28
  mov    $0x0,%eax
  jne    L28
  ret
  nopl   (%rax)
L28:
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm1
  cvtsi2sd %edi,%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  test   %rsi,%rsi
  js     L27
  movsd  D28(%rip),%xmm0
L27:
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type: byte[8]
name: unpack_data
arguments: data_tag: D28
type: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D28: 0.5

assistant: ```c
int64_t mlt_audio_calculate_samples_to_position(float fps, int frequency, int64_t position) {
  int64_t samples = 0;
  if (fps) {
    samples = (int64_t)((double)position * (double)frequency / (double)fps + (position < 0 ? -0.5 : 0.5));
  }
  return samples;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mlt_audio_calculate_samples_to_position>:
  endbr64
  ucomiss D2(%rip),%xmm0
  jp     L9
  mov    $0x0,%eax
  jne    L9
  ret
  nopl   (%rax)
L9:
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm1
  cvtsi2sd %edi,%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  test   %rsi,%rsi
  js     L22
  movsd  D24(%rip),%xmm0
L22:
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: byte[8]
name: unpack_data
arguments: label: D24
datatype: f64

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D24: 0.5

assistant: ```c
int64_t mlt_audio_calculate_samples_to_position(float fps, int frequency, int64_t position) {
  int64_t samples = 0;
  if (fps) {
    samples = (int64_t)((double)position * (double)frequency / (double)fps + (position < 0 ? -0.5 : 0.5));
  }
  return samples;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rmdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L59
  mov    $0x0,%eax
  jmp    L22
L59:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movb   $0x0,-0x29(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L9
L58:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x29(%rbp)
  jge    L46
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
L46:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x29(%rbp)
  addq   $0x1,-0x20(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L58
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L35
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L35:
  mov    -0x8(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
char *str_rmdup(const char *s) {
  size_t s_len;
  char *s_nodup;
  char *p;
  char prev;
  char *ret;
  s_len = strlen(s);
  if (!(s_nodup = malloc(sizeof(char) * (s_len + 1))))
    return NULL;
  p = s_nodup;
  prev = '\0';
  for (size_t i = 0; i < s_len; ++i) {
    if (s[i] > prev)
      *p++ = s[i];
    prev = s[i];
  }
  *p = '\0';
  if (!(ret = realloc(s_nodup, sizeof(char) * (p - s_nodup + 1))))
    free(s_nodup);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_rmdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L47
  test   %r12,%r12
  je     L45
  mov    %rbp,%rax
  lea    0x0(%rbp,%r12,1),%r8
  mov    %rbx,%rsi
  mov    $0x0,%ecx
  jmp    L55
L85:
  movzbl (%rdi),%ecx
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L61
L55:
  mov    %rax,%rdi
  movzbl (%rax),%edx
  cmp    %cl,%dl
  jle    L85
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%rsi
  jmp    L85
L45:
  mov    %rax,%rsi
L61:
  movb   $0x0,(%rsi)
  sub    %rbx,%rsi
  add    $0x1,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L62
L74:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L74
L47:
  mov    %rax,%rbp
  jmp    L74
```

assistant: ```c
char *str_rmdup(const char *s) {
  size_t s_len;
  char *s_nodup;
  char *p;
  char prev;
  char *ret;
  s_len = strlen(s);
  if (!(s_nodup = malloc(sizeof(char) * (s_len + 1))))
    return NULL;
  p = s_nodup;
  prev = '\0';
  for (size_t i = 0; i < s_len; ++i) {
    if (s[i] > prev)
      *p++ = s[i];
    prev = s[i];
  }
  *p = '\0';
  if (!(ret = realloc(s_nodup, sizeof(char) * (p - s_nodup + 1))))
    free(s_nodup);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_rmdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L51
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L2
  mov    %rbx,%rdi
  lea    (%rbx,%rbp,1),%rax
  mov    %r12,%r8
  xor    %edx,%edx
  xchg   %ax,%ax
L64:
  mov    %edx,%ecx
  movzbl (%rdi),%edx
  cmp    %cl,%dl
  jle    L29
  mov    %dl,(%r8)
  add    $0x1,%r8
L29:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  jne    L64
  mov    %r8,%rsi
  sub    %r12,%rsi
  add    $0x1,%esi
L17:
  movb   $0x0,(%r8)
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L6
L69:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L6:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L2:
  mov    %rax,%r8
  mov    $0x1,%esi
  jmp    L17
L51:
  xor    %r13d,%r13d
  jmp    L69
```

assistant: ```c
char *str_rmdup(const char *s) {
  size_t s_len;
  char *s_nodup;
  char *p;
  char prev;
  char *ret;
  s_len = strlen(s);
  if (!(s_nodup = malloc(sizeof(char) * (s_len + 1))))
    return NULL;
  p = s_nodup;
  prev = '\0';
  for (size_t i = 0; i < s_len; ++i) {
    if (s[i] > prev)
      *p++ = s[i];
    prev = s[i];
  }
  *p = '\0';
  if (!(ret = realloc(s_nodup, sizeof(char) * (p - s_nodup + 1))))
    free(s_nodup);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rmdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L45
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L13
  mov    %rbx,%rdi
  lea    (%rbx,%rbp,1),%rax
  mov    %r12,%r8
  xor    %edx,%edx
  xchg   %ax,%ax
L60:
  mov    %edx,%ecx
  movzbl (%rdi),%edx
  cmp    %cl,%dl
  jle    L29
  mov    %dl,(%r8)
  add    $0x1,%r8
L29:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  jne    L60
  mov    %r8,%rsi
  sub    %r12,%rsi
  add    $0x1,%esi
L44:
  movb   $0x0,(%r8)
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L7
L38:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L13:
  mov    %rax,%r8
  mov    $0x1,%esi
  jmp    L44
L45:
  xor    %r13d,%r13d
  jmp    L38
```

assistant: ```c
char *str_rmdup(const char *s) {
  size_t s_len;
  char *s_nodup;
  char *p;
  char prev;
  char *ret;
  s_len = strlen(s);
  if (!(s_nodup = malloc(sizeof(char) * (s_len + 1))))
    return NULL;
  p = s_nodup;
  prev = '\0';
  for (size_t i = 0; i < s_len; ++i) {
    if (s[i] > prev)
      *p++ = s[i];
    prev = s[i];
  }
  *p = '\0';
  if (!(ret = realloc(s_nodup, sizeof(char) * (p - s_nodup + 1))))
    free(s_nodup);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_reverse(int **tab1, int **tab2) {
  int *tmp;
  tmp = *tab1;
  *tab1 = *tab2;
  *tab2 = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_reverse>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void ft_reverse(int **tab1, int **tab2) {
  int *tmp;
  tmp = *tab1;
  *tab1 = *tab2;
  *tab2 = tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_reverse>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void ft_reverse(int **tab1, int **tab2) {
  int *tmp;
  tmp = *tab1;
  *tab1 = *tab2;
  *tab2 = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_reverse>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void ft_reverse(int **tab1, int **tab2) {
  int *tmp;
  tmp = *tab1;
  *tab1 = *tab2;
  *tab2 = tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L45
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L45:
  cmpl   $0x0,-0x14(%rbp)
  jg     L15
  jmp    L39
L56:
  mov    -0x20(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  add    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x20(%rbp)
L39:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jg     L56
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L59
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L41
L59:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L41:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
data_type: string
name: retrieve_data
arguments: data_tag: D9
data_type: string
name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D25: Enter a number: 

tool: D9: %d

tool: D0: 
The number is armstrong


tool: D6: 
The number is not armstrong


assistant: ```c
int main(void) {
  int n, r, a = 0, t, c = 0, z;
  printf("Enter a number: ");
  scanf("%d", &n);
  t = n;
  z = n;
  while (z > 0) {
    z = z / 10;
    c++;
  }
  while (n > 0) {
    r = n % 10;
    a = a + pow(r, c);
    n = n / 10;
  }
  if (a == t)
    printf("\nThe number is armstrong\n");
  else
    printf("\nThe number is not armstrong\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  jle    L67
  mov    %r12d,%edx
  mov    $0x0,%ebx
L69:
  mov    %edx,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  add    $0x1,%ebx
  cmp    $0x9,%ecx
  jg     L69
  mov    %r12d,%edi
  mov    $0x0,%ebp
L57:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  mov    %ebx,%esi
  call   <pow@plt>
  add    %eax,%ebp
  mov    0x4(%rsp),%eax
  movslq %eax,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  cltd
  sub    %edx,%edi
  mov    %edi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L57
L37:
  cmp    %ebp,%r12d
  je     L12
  lea    D11(%rip),%rdi
  call   <printf@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  mov    $0x0,%ebp
  jmp    L37
L12:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D36
datatype: string

tool: D2: Enter a number: 

tool: D1: %d

tool: D11: 
The number is not armstrong


tool: D36: 
The number is armstrong


assistant: ```c
int main(void) {
  int n, r, a = 0, t, c = 0, z;
  printf("Enter a number: ");
  scanf("%d", &n);
  t = n;
  z = n;
  while (z > 0) {
    z = z / 10;
    c++;
  }
  while (n > 0) {
    r = n % 10;
    a = a + pow(r, c);
    n = n / 10;
  }
  if (a == t)
    printf("\nThe number is armstrong\n");
  else
    printf("\nThe number is not armstrong\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jle    L12
  mov    %ebp,%eax
  xor    %r12d,%r12d
  mov    $0xcccccccd,%ecx
  nop
L10:
  mov    %eax,%eax
  add    $0x1,%r12d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  jg     L10
  mov    %ebp,%edi
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %r12d,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <pow@plt>
  movslq 0x4(%rsp),%rdi
  add    %eax,%ebx
  mov    %rdi,%rax
  imul   $0x66666667,%rdi,%rdi
  cltd
  sar    $0x22,%rdi
  sub    %edx,%edi
  mov    %edi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L11
L25:
  cmp    %ebx,%ebp
  je     L54
  lea    D4(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L12:
  xor    %ebx,%ebx
  jmp    L25
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D22
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string
name: read_data
arguments: data_tag: D28
data_type: string

tool: D22: Enter a number: 

tool: D36: %d

tool: D4: 
The number is not armstrong


tool: D28: 
The number is armstrong


assistant: ```c
int main(void) {
  int n, r, a = 0, t, c = 0, z;
  printf("Enter a number: ");
  scanf("%d", &n);
  t = n;
  z = n;
  while (z > 0) {
    z = z / 10;
    c++;
  }
  while (n > 0) {
    r = n % 10;
    a = a + pow(r, c);
    n = n / 10;
  }
  if (a == t)
    printf("\nThe number is armstrong\n");
  else
    printf("\nThe number is not armstrong\n");
  return 0;
}
```