ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  mov    %eax,-0x418(%rbp)
L5:
  lea    -0x410(%rbp),%rcx
  mov    -0x418(%rbp),%eax
  mov    $0x3ff,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0x0,-0x414(%rbp)
  jle    L25
  mov    -0x414(%rbp),%eax
  cltq
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L50
  lea    -0x410(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L50
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  movl   $0x0,-0x41c(%rbp)
  jmp    L65
L28:
  mov    -0x41c(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x41c(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x410(%rbp,%rdx,1)
  addl   $0x1,-0x41c(%rbp)
L65:
  mov    -0x41c(%rbp),%eax
  cmp    -0x414(%rbp),%eax
  jl     L28
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x418(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L5
L25:
  nop
L50:
  mov    -0x418(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D15: bye


tool: D19: bye


assistant: ```c
void *fun(void *p) {
  int c = (int)p;
  char buf[1024];
  for (;;) {
    int n = read(c, buf, sizeof(buf) - 1);
    if (n <= 0)
      break;
    buf[n] = '\0';
    if (!strcmp(buf, "bye\n") || !strcmp(buf, "bye\r\n"))
      break;
    int i;
    write(1, buf, n);
    for (i = 0; i < n; i++)
      buf[i] = toupper(buf[i]);
    write(c, buf, n);
  }
  close(c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    %edi,%r14d
  lea    0x10(%rsp),%r13
  lea    D2(%rip),%r15
  lea    0x11(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L43
L29:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <write@plt>
L43:
  mov    $0x3ff,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L57
  cltq
  movb   $0x0,0x10(%rsp,%rax,1)
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L57
  lea    D11(%rip),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L57
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %r13,%rbx
  lea    -0x1(%r12),%ebp
  add    0x8(%rsp),%rbp
L24:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L24
  jmp    L29
L57:
  mov    %r14d,%edi
  call   <close@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string

tool: D2: bye


tool: D11: bye


assistant: ```c
void *fun(void *p) {
  int c = (int)p;
  char buf[1024];
  for (;;) {
    int n = read(c, buf, sizeof(buf) - 1);
    if (n <= 0)
      break;
    buf[n] = '\0';
    if (!strcmp(buf, "bye\n") || !strcmp(buf, "bye\r\n"))
      break;
    int i;
    write(1, buf, n);
    for (i = 0; i < n; i++)
      buf[i] = toupper(buf[i]);
    write(c, buf, n);
  }
  close(c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fun>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x1(%rsp),%r15
  nopl   0x0(%rax,%rax,1)
L65:
  mov    $0x3ff,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L26
  cltq
  movb   $0x0,(%rsp,%rax,1)
  cmpl   $0xa657962,0x0(%r13)
  je     L18
L89:
  cmpl   $0xd657962,0x0(%r13)
  je     L81
L16:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  mov    %r13,%rbx
  call   <write@plt>
  lea    -0x1(%r12),%ebp
  add    %r15,%rbp
  nopl   0x0(%rax,%rax,1)
L85:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L85
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <write@plt>
  jmp    L65
  nopl   0x0(%rax)
L18:
  cmpb   $0x0,0x4(%r13)
  jne    L89
L26:
  mov    %r14d,%edi
  call   <close@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L81:
  cmpw   $0xa,0x4(%r13)
  jne    L16
  jmp    L26
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *fun(void *p) {
  int c = (int)p;
  char buf[1024];
  for (;;) {
    int n = read(c, buf, sizeof(buf) - 1);
    if (n <= 0)
      break;
    buf[n] = '\0';
    if (!strcmp(buf, "bye\n") || !strcmp(buf, "bye\r\n"))
      break;
    int i;
    write(1, buf, n);
    for (i = 0; i < n; i++)
      buf[i] = toupper(buf[i]);
    write(c, buf, n);
  }
  close(c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fun>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x1(%rsp),%r15
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x3ff,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L29
  cltq
  movb   $0x0,(%rsp,%rax,1)
  cmpl   $0xa657962,0x0(%r13)
  je     L35
L59:
  cmpl   $0xd657962,0x0(%r13)
  je     L72
L14:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  mov    %r13,%rbx
  call   <write@plt>
  lea    -0x1(%r12),%ebp
  add    %r15,%rbp
  nopl   0x0(%rax,%rax,1)
L41:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L41
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <write@plt>
  jmp    L8
  nopl   0x0(%rax)
L35:
  cmpb   $0x0,0x4(%r13)
  jne    L59
L29:
  mov    %r14d,%edi
  call   <close@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L72:
  cmpw   $0xa,0x4(%r13)
  jne    L14
  jmp    L29
L87:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *fun(void *p) {
  int c = (int)p;
  char buf[1024];
  for (;;) {
    int n = read(c, buf, sizeof(buf) - 1);
    if (n <= 0)
      break;
    buf[n] = '\0';
    if (!strcmp(buf, "bye\n") || !strcmp(buf, "bye\r\n"))
      break;
    int i;
    write(1, buf, n);
    for (i = 0; i < n; i++)
      buf[i] = toupper(buf[i]);
    write(c, buf, n);
  }
  close(c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Temporisation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
L9:
  mov    $0x0,%eax
  call   <clock@plt>
  cmp    %rax,-0x8(%rbp)
  jg     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void Temporisation(int n) {
  clock_t start, stop;
  n = n * CLOCKS_PER_SEC / 1000;
  start = clock();
  stop = start + n;
  while (clock() < stop) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Temporisation>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  imul   (%rax),%edi
  mov    %edi,%ebp
  mov    $0x0,%eax
  call   <clock@plt>
  movslq %ebp,%rbx
  imul   $0x10624dd3,%rbx,%rbx
  sar    $0x26,%rbx
  sar    $0x1f,%ebp
  sub    %ebp,%ebx
  movslq %ebx,%rbx
  add    %rax,%rbx
L5:
  mov    $0x0,%eax
  call   <clock@plt>
  cmp    %rbx,%rax
  jl     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Temporisation(int n) {
  clock_t start, stop;
  n = n * CLOCKS_PER_SEC / 1000;
  start = clock();
  stop = start + n;
  while (clock() < stop) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Temporisation>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  imul   (%rax),%edi
  xor    %eax,%eax
  movslq %edi,%rbx
  call   <clock@plt>
  mov    %rbx,%rbp
  imul   $0x10624dd3,%rbx,%rbx
  sar    $0x1f,%ebp
  sar    $0x26,%rbx
  sub    %ebp,%ebx
  movslq %ebx,%rbx
  add    %rax,%rbx
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <clock@plt>
  cmp    %rbx,%rax
  jl     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Temporisation(int n) {
  clock_t start, stop;
  n = n * CLOCKS_PER_SEC / 1000;
  start = clock();
  stop = start + n;
  while (clock() < stop) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Temporisation>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  imul   (%rax),%edi
  xor    %eax,%eax
  movslq %edi,%rbx
  call   <clock@plt>
  mov    %rbx,%rbp
  imul   $0x10624dd3,%rbx,%rbx
  sar    $0x1f,%ebp
  sar    $0x26,%rbx
  sub    %ebp,%ebx
  movslq %ebx,%rbx
  add    %rax,%rbx
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <clock@plt>
  cmp    %rbx,%rax
  jl     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Temporisation(int n) {
  clock_t start, stop;
  n = n * CLOCKS_PER_SEC / 1000;
  start = clock();
  stop = start + n;
  while (clock() < stop) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmpz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  neg    %eax
  jmp    L5
L18:
  mov    -0x4(%rbp),%eax
L5:
  leave
  ret
```

assistant: ```c
int strncmpz(char *l, char *r, size_t llen) {
  int i = strncmp(l, r, llen);
  if (i == 0)
    return -r[llen];
  else
    return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmpz>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L5
  movsbl 0x0(%rbp,%rbx,1),%eax
  neg    %eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strncmpz(char *l, char *r, size_t llen) {
  int i = strncmp(l, r, llen);
  if (i == 0)
    return -r[llen];
  else
    return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncmpz>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L1
  movsbl 0x0(%rbp,%rbx,1),%eax
  neg    %eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strncmpz(char *l, char *r, size_t llen) {
  int i = strncmp(l, r, llen);
  if (i == 0)
    return -r[llen];
  else
    return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmpz>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L7
  movsbl 0x0(%rbp,%rbx,1),%eax
  neg    %eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strncmpz(char *l, char *r, size_t llen) {
  int i = strncmp(l, r, llen);
  if (i == 0)
    return -r[llen];
  else
    return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sock_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sock_read@plt>
  test   %rax,%rax
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void sock_in(void *arg) {
  struct sock *f = arg;
  while (sock_read(f))
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sock_in>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L8:
  mov    %rbx,%rdi
  call   <sock_read@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void sock_in(void *arg) {
  struct sock *f = arg;
  while (sock_read(f))
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sock_in>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <sock_read@plt>
  test   %rax,%rax
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void sock_in(void *arg) {
  struct sock *f = arg;
  while (sock_read(f))
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_in>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <sock_read@plt>
  test   %rax,%rax
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void sock_in(void *arg) {
  struct sock *f = arg;
  while (sock_read(f))
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wby_base64_encode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %rcx,%rdi
  call   <wby_base64_bufsize@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  cmp    %r13,%rdx
  ja     L8
  test   %rbp,%rbp
  je     L41
  mov    $0x2,%esi
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  mov    $0x0,%r10d
  mov    $0x40,%r8d
  lea    D7(%rip),%rdi
  jmp    L31
L14:
  or     %eax,%edx
  add    $0x3,%rcx
  mov    %eax,%r13d
  shr    $0x12,%r13d
  shr    $0xc,%eax
  and    $0x3f,%eax
  mov    %edx,%r14d
  shr    $0x6,%r14d
  and    $0x3f,%r14d
  cmp    %rsi,%rbp
  cmovb  %r8d,%r14d
  and    $0x3f,%edx
  cmp    %rcx,%rbp
  cmovb  %r8d,%edx
  mov    %r13d,%r13d
  movzbl (%rdi,%r13,1),%r11d
  mov    %r11b,(%rbx)
  mov    %eax,%r11d
  movzbl (%rdi,%r11,1),%eax
  mov    %al,0x1(%rbx)
  mov    %r14d,%eax
  movzbl (%rdi,%rax,1),%eax
  mov    %al,0x2(%rbx)
  lea    0x4(%rbx),%r11
  mov    %edx,%edx
  movzbl (%rdi,%rdx,1),%eax
  mov    %al,0x3(%rbx)
  add    $0x1,%r9d
  cmp    $0x13,%r9d
  je     L34
  mov    %r11,%rbx
L73:
  add    $0x3,%rsi
  cmp    %rcx,%rbp
  jbe    L41
L31:
  movzbl (%r12,%rcx,1),%edx
  shl    $0x10,%edx
  lea    0x1(%rcx),%r11
  mov    %r10d,%eax
  cmp    %rbp,%r11
  jae    L38
  movzbl 0x1(%r12,%rcx,1),%eax
  shl    $0x8,%eax
L38:
  or     %edx,%eax
  mov    %r10d,%edx
  cmp    %rsi,%rbp
  jbe    L14
  movzbl 0x2(%r12,%rcx,1),%edx
  jmp    L14
L34:
  movb   $0xd,0x4(%rbx)
  movb   $0xa,0x5(%rbx)
  lea    0x6(%rbx),%rbx
  jmp    L73
L41:
  movb   $0x0,(%rbx)
  mov    $0x0,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=

assistant: ```c
int wby_base64_encode(char *output, unsigned long output_size, const unsigned char *input, unsigned long input_size) {
  unsigned long i = 0;
  int line_out = 0;
  static const char enc[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                            "abcdefghijklmnopqrstuvwxyz"
                            "0123456789+/=";
  if (output_size < wby_base64_bufsize(input_size))
    return 1;
  while (i < input_size) {
    unsigned int idx_0, idx_1, idx_2, idx_3;
    unsigned int i0;
    i0 = (unsigned int)(input[i]) << 16;
    i++;
    i0 |= (unsigned int)(i < input_size ? input[i] : 0) << 8;
    i++;
    i0 |= (i < input_size ? input[i] : 0);
    i++;
    idx_0 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_1 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_2 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_3 = (i0 & 0xfc0000) >> 18;
    if (i - 1 > input_size)
      idx_2 = 64;
    if (i > input_size)
      idx_3 = 64;
    *output++ = enc[idx_0];
    *output++ = enc[idx_1];
    *output++ = enc[idx_2];
    *output++ = enc[idx_3];
    if (++line_out == 19) {
      *output++ = '\r';
      *output++ = '\n';
    }
  }
  *output = '\0';
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wby_base64_encode>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rcx,%rdi
  sub    $0x8,%rsp
  call   <wby_base64_bufsize@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  cmp    %r13,%r8
  ja     L6
  test   %rbp,%rbp
  je     L32
  mov    $0x2,%esi
  xor    %r9d,%r9d
  xor    %edx,%edx
  lea    D4(%rip),%r8
  jmp    L93
  nop
L51:
  add    $0x4,%rbx
  add    $0x3,%rsi
  cmp    %rdx,%rbp
  jbe    L32
L93:
  movzbl (%r12,%rdx,1),%eax
  lea    0x1(%rdx),%rcx
  shl    $0x10,%eax
  cmp    %rbp,%rcx
  jae    L76
  movzbl 0x1(%r12,%rdx,1),%ecx
  shl    $0x8,%ecx
  or     %ecx,%eax
L76:
  cmp    %rbp,%rsi
  jae    L20
  movzbl 0x2(%r12,%rdx,1),%ecx
  or     %ecx,%eax
L20:
  mov    %eax,%ecx
  mov    %eax,%edi
  add    $0x3,%rdx
  mov    $0x3d,%r11d
  shr    $0xc,%ecx
  shr    $0x12,%edi
  and    $0x3f,%ecx
  cmp    %rbp,%rsi
  ja     L17
  mov    %eax,%r10d
  shr    $0x6,%r10d
  and    $0x3f,%r10d
  movzbl (%r8,%r10,1),%r11d
L17:
  mov    $0x3d,%r10d
  cmp    %rdx,%rbp
  jb     L63
  and    $0x3f,%eax
  movzbl (%r8,%rax,1),%r10d
L63:
  mov    %edi,%eax
  add    $0x1,%r9d
  mov    %r11b,0x2(%rbx)
  movzbl (%r8,%rax,1),%eax
  mov    %r10b,0x3(%rbx)
  mov    %al,(%rbx)
  mov    %ecx,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,0x1(%rbx)
  cmp    $0x13,%r9d
  jne    L51
  mov    $0xa0d,%eax
  add    $0x6,%rbx
  add    $0x3,%rsi
  mov    %ax,-0x2(%rbx)
  cmp    %rdx,%rbp
  ja     L93
L32:
  movb   $0x0,(%rbx)
  xor    %eax,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=

assistant: ```c
int wby_base64_encode(char *output, unsigned long output_size, const unsigned char *input, unsigned long input_size) {
  unsigned long i = 0;
  int line_out = 0;
  static const char enc[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                            "abcdefghijklmnopqrstuvwxyz"
                            "0123456789+/=";
  if (output_size < wby_base64_bufsize(input_size))
    return 1;
  while (i < input_size) {
    unsigned int idx_0, idx_1, idx_2, idx_3;
    unsigned int i0;
    i0 = (unsigned int)(input[i]) << 16;
    i++;
    i0 |= (unsigned int)(i < input_size ? input[i] : 0) << 8;
    i++;
    i0 |= (i < input_size ? input[i] : 0);
    i++;
    idx_0 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_1 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_2 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_3 = (i0 & 0xfc0000) >> 18;
    if (i - 1 > input_size)
      idx_2 = 64;
    if (i > input_size)
      idx_3 = 64;
    *output++ = enc[idx_0];
    *output++ = enc[idx_1];
    *output++ = enc[idx_2];
    *output++ = enc[idx_3];
    if (++line_out == 19) {
      *output++ = '\r';
      *output++ = '\n';
    }
  }
  *output = '\0';
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wby_base64_encode>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rcx,%rdi
  sub    $0x8,%rsp
  call   <wby_base64_bufsize@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  cmp    %r13,%r8
  ja     L80
  test   %rbp,%rbp
  je     L44
  mov    $0x2,%esi
  xor    %r9d,%r9d
  xor    %edx,%edx
  lea    D5(%rip),%r8
  jmp    L17
  nop
L2:
  add    $0x4,%rbx
  add    $0x3,%rsi
  cmp    %rdx,%rbp
  jbe    L44
L17:
  movzbl (%r12,%rdx,1),%eax
  lea    0x1(%rdx),%rcx
  shl    $0x10,%eax
  cmp    %rcx,%rbp
  jbe    L23
  movzbl 0x1(%r12,%rdx,1),%ecx
  shl    $0x8,%ecx
  or     %ecx,%eax
L23:
  cmp    %rsi,%rbp
  jbe    L71
  movzbl 0x2(%r12,%rdx,1),%ecx
  or     %ecx,%eax
L71:
  mov    %eax,%ecx
  mov    %eax,%edi
  add    $0x3,%rdx
  mov    $0x3d,%r11d
  shr    $0xc,%ecx
  shr    $0x12,%edi
  and    $0x3f,%ecx
  cmp    %rsi,%rbp
  jb     L34
  mov    %eax,%r10d
  shr    $0x6,%r10d
  and    $0x3f,%r10d
  movzbl (%r8,%r10,1),%r11d
L34:
  mov    $0x3d,%r10d
  cmp    %rdx,%rbp
  jb     L69
  and    $0x3f,%eax
  movzbl (%r8,%rax,1),%r10d
L69:
  mov    %edi,%eax
  add    $0x1,%r9d
  mov    %r11b,0x2(%rbx)
  movzbl (%r8,%rax,1),%eax
  mov    %r10b,0x3(%rbx)
  mov    %al,(%rbx)
  mov    %ecx,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,0x1(%rbx)
  cmp    $0x13,%r9d
  jne    L2
  mov    $0xa0d,%eax
  add    $0x6,%rbx
  add    $0x3,%rsi
  mov    %ax,-0x2(%rbx)
  cmp    %rdx,%rbp
  ja     L17
L44:
  movb   $0x0,(%rbx)
  xor    %eax,%eax
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=

assistant: ```c
int wby_base64_encode(char *output, unsigned long output_size, const unsigned char *input, unsigned long input_size) {
  unsigned long i = 0;
  int line_out = 0;
  static const char enc[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                            "abcdefghijklmnopqrstuvwxyz"
                            "0123456789+/=";
  if (output_size < wby_base64_bufsize(input_size))
    return 1;
  while (i < input_size) {
    unsigned int idx_0, idx_1, idx_2, idx_3;
    unsigned int i0;
    i0 = (unsigned int)(input[i]) << 16;
    i++;
    i0 |= (unsigned int)(i < input_size ? input[i] : 0) << 8;
    i++;
    i0 |= (i < input_size ? input[i] : 0);
    i++;
    idx_0 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_1 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_2 = (i0 & 0xfc0000) >> 18;
    i0 <<= 6;
    idx_3 = (i0 & 0xfc0000) >> 18;
    if (i - 1 > input_size)
      idx_2 = 64;
    if (i > input_size)
      idx_3 = 64;
    *output++ = enc[idx_0];
    *output++ = enc[idx_1];
    *output++ = enc[idx_2];
    *output++ = enc[idx_3];
    if (++line_out == 19) {
      *output++ = '\r';
      *output++ = '\n';
    }
  }
  *output = '\0';
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0x8,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <multi_arr@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[3][3] = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}};
  int barr[2][2];
  multi_arr(arr);
  return 0;
}
```