ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L5:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  subq   $0x1,-0x18(%rbp)
  jmp    L26
L18:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L26:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *r = dst;
  while (*dst++)
    ;
  dst--;
  while (*src)
    *dst++ = *src++;
  *dst = '\0';
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
L5:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L5
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L4
L27:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L27
L4:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *r = dst;
  while (*dst++)
    ;
  dst--;
  while (*src)
    *dst++ = *src++;
  *dst = '\0';
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  cmpb   $0x0,(%rdx)
  jne    L8
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L29
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rsi
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L13
L29:
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *r = dst;
  while (*dst++)
    ;
  dst--;
  while (*src)
    *dst++ = *src++;
  *dst = '\0';
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  cmpb   $0x0,(%rdx)
  jne    L12
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L3
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rsi
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L11
L3:
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *r = dst;
  while (*dst++)
    ;
  dst--;
  while (*src)
    *dst++ = *src++;
  *dst = '\0';
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<runDiskTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testBitmap@plt>
  mov    $0x0,%eax
  call   <testSizes@plt>
  mov    $0x0,%eax
  call   <testDiskFormat@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void runDiskTest() {
  testBitmap();
  testSizes();
  testDiskFormat();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<runDiskTest>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testBitmap@plt>
  mov    $0x0,%eax
  call   <testSizes@plt>
  mov    $0x0,%eax
  call   <testDiskFormat@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void runDiskTest() {
  testBitmap();
  testSizes();
  testDiskFormat();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<runDiskTest>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testBitmap@plt>
  xor    %eax,%eax
  call   <testSizes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <testDiskFormat@plt>
```

assistant: ```c
void runDiskTest() {
  testBitmap();
  testSizes();
  testDiskFormat();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<runDiskTest>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testBitmap@plt>
  xor    %eax,%eax
  call   <testSizes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <testDiskFormat@plt>
```

assistant: ```c
void runDiskTest() {
  testBitmap();
  testSizes();
  testDiskFormat();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nr_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L20:
  addq   $0x8,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L13:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  add    $0x4,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L11
L4:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string

tool: D16: allocation failure 1 in matrix()

tool: D19: allocation failure 2 in matrix()

assistant: ```c
float **nr_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nr_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x1(%rax),%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L31
L6:
  mov    $0x1,%eax
  sub    %r12,%rax
  lea    (%rbx,%rax,8),%r15
  imul   %rbp,%r14
  lea    0x4(,%r14,4),%rdi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %rax,%rax
  je     L13
L41:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  shl    $0x2,%rax
  add    %rax,0x8(%rbx)
  cmp    %r12,%r13
  jle    L59
  shl    $0x2,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L29:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L29
L59:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  lea    D6(%rip),%rdi
  call   <nrerror@plt>
  jmp    L6
L13:
  lea    D4(%rip),%rdi
  call   <nrerror@plt>
  jmp    L41
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D6: allocation failure 1 in matrix()

tool: D4: allocation failure 2 in matrix()

assistant: ```c
float **nr_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nr_matrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%rdi
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L57:
  imul   %rbp,%r15
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%rbx)
  je     L11
L59:
  mov    $0x1,%edx
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r12
  jle    L56
  lea    0x0(,%rbp,4),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r12,8),%rsi
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L20
L56:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L5:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L57
  nopl   0x0(%rax)
L11:
  lea    D1(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L59
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D1
type: string

tool: D0: allocation failure 1 in matrix()

tool: D1: allocation failure 2 in matrix()

assistant: ```c
float **nr_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nr_matrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rax,8),%rdi
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L34
L4:
  imul   %rbx,%r15
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    0x0(%r13,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%r13)
  je     L43
L49:
  mov    $0x1,%edx
  add    $0x1,%rbp
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rdx,0x8(%r13)
  cmp    %rbp,%r12
  jl     L45
  lea    0x0(,%rbx,4),%rcx
  lea    (%r8,%rbp,8),%rax
  lea    0x8(%r8,%r12,8),%rsi
L3:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L3
L45:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  lea    D11(%rip),%rdi
  call   <nrerror@plt>
  jmp    L4
  nopl   0x0(%rax)
L43:
  lea    D14(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%r13),%rax
  mov    0x8(%rsp),%r8
  jmp    L49
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D11: allocation failure 1 in matrix()

tool: D14: allocation failure 2 in matrix()

assistant: ```c
float **nr_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x20(%rbp)
  je     L34
  cmpq   $0x6,-0x20(%rbp)
  ja     L34
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  lea    -0xf(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_memcpy@plt>
  lea    -0xf(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  jmp    L31
L34:
  nop
L31:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *p, unsigned long l) {
  if (l < 1 || l > 6)
    return;
  char buf[7];
  __builtin_memcpy(buf, p, l + 1);
  bar(buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsi),%rax
  cmp    $0x5,%rax
  jbe    L13
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L13:
  lea    0x1(%rsi),%rdx
  lea    0x1(%rsp),%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <__builtin_memcpy@plt>
  mov    %rbx,%rdi
  call   <bar@plt>
  jmp    L23
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *p, unsigned long l) {
  if (l < 1 || l > 6)
    return;
  char buf[7];
  __builtin_memcpy(buf, p, l + 1);
  bar(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsi),%rax
  cmp    $0x5,%rax
  ja     L13
  lea    0x1(%rsp),%rbp
  lea    0x1(%rsi),%rdx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <__builtin_memcpy@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *p, unsigned long l) {
  if (l < 1 || l > 6)
    return;
  char buf[7];
  __builtin_memcpy(buf, p, l + 1);
  bar(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsi),%rax
  cmp    $0x5,%rax
  ja     L16
  lea    0x1(%rsp),%rbp
  lea    0x1(%rsi),%rdx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <__builtin_memcpy@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *p, unsigned long l) {
  if (l < 1 || l > 6)
    return;
  char buf[7];
  __builtin_memcpy(buf, p, l + 1);
  bar(buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<append_query_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  je     L5
  movq   $0x1,-0x20(%rbp)
L5:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmpq   $0x0,-0x20(%rbp)
  je     L2
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3f,(%rax)
L2:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void append_query_string(char **req, const char *qstr) {
  char *r;
  size_t s1, s2, qm = 0;
  s1 = strlen(*req);
  s2 = strlen(qstr);
  if (*qstr != '?')
    qm = 1;
  r = xmalloc(s1 + s2 + qm + 1);
  memcpy(r, *req, s1);
  if (qm)
    r[s1] = '?';
  memcpy(r + s1 + qm, qstr, s2 + 1);
  free(*req);
  *req = r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<append_query_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    (%rdi),%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,0x8(%rsp)
  movzbl 0x0(%r13),%r15d
  cmp    $0x3f,%r15b
  setne  %r14b
  movzbl %r14b,%r14d
  lea    0x1(%r14,%rbx,1),%rdi
  add    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    0x0(%rbp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmp    $0x3f,%r15b
  je     L5
  movb   $0x3f,(%r12,%rbx,1)
L5:
  mov    0x8(%rsp),%rdx
  add    $0x1,%rdx
  lea    (%rbx,%r14,1),%rdi
  add    %r12,%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    %r12,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void append_query_string(char **req, const char *qstr) {
  char *r;
  size_t s1, s2, qm = 0;
  s1 = strlen(*req);
  s2 = strlen(qstr);
  if (*qstr != '?')
    qm = 1;
  r = xmalloc(s1 + s2 + qm + 1);
  memcpy(r, *req, s1);
  if (qm)
    r[s1] = '?';
  memcpy(r + s1 + qm, qstr, s2 + 1);
  free(*req);
  *req = r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<append_query_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmpb   $0x3f,0x0(%r13)
  mov    %rax,%rbp
  lea    (%rbx,%rax,1),%rdi
  je     L0
  add    $0x2,%rdi
  call   <xmalloc@plt>
  mov    (%r12),%rsi
  mov    %rbx,%rdx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x3f,(%r14,%rbx,1)
  add    $0x1,%rbx
L19:
  lea    (%r14,%rbx,1),%rdi
  lea    0x1(%rbp),%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    (%r12),%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  mov    %r14,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L0:
  add    $0x1,%rdi
  call   <xmalloc@plt>
  mov    (%r12),%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  jmp    L19
```

assistant: ```c
void append_query_string(char **req, const char *qstr) {
  char *r;
  size_t s1, s2, qm = 0;
  s1 = strlen(*req);
  s2 = strlen(qstr);
  if (*qstr != '?')
    qm = 1;
  r = xmalloc(s1 + s2 + qm + 1);
  memcpy(r, *req, s1);
  if (qm)
    r[s1] = '?';
  memcpy(r + s1 + qm, qstr, s2 + 1);
  free(*req);
  *req = r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<append_query_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmpb   $0x3f,0x0(%r13)
  mov    %rax,%rbp
  lea    (%rbx,%rax,1),%rdi
  je     L4
  add    $0x2,%rdi
  call   <xmalloc@plt>
  mov    (%r12),%rsi
  mov    %rbx,%rdx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x3f,(%r14,%rbx,1)
  add    $0x1,%rbx
L3:
  lea    (%r14,%rbx,1),%rdi
  lea    0x1(%rbp),%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    (%r12),%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  mov    %r14,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L4:
  add    $0x1,%rdi
  call   <xmalloc@plt>
  mov    (%r12),%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  jmp    L3
```

assistant: ```c
void append_query_string(char **req, const char *qstr) {
  char *r;
  size_t s1, s2, qm = 0;
  s1 = strlen(*req);
  s2 = strlen(qstr);
  if (*qstr != '?')
    qm = 1;
  r = xmalloc(s1 + s2 + qm + 1);
  memcpy(r, *req, s1);
  if (qm)
    r[s1] = '?';
  memcpy(r + s1 + qm, qstr, s2 + 1);
  free(*req);
  *req = r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L31
L32:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <EhBisexto@plt>
  cmp    $0x1,%eax
  jne    L38
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L38:
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L32
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D20
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string

tool: D20: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int iIndice, iAnoInicial, iAnoFinal, iNBi = 0;
  scanf("%d %d", &iAnoInicial, &iAnoFinal);
  for (iIndice = iAnoInicial; iIndice <= iAnoFinal; iIndice++) {
    if (EhBisexto(iIndice) == 1) {
      printf("%d\n", iIndice);
      iNBi++;
    }
  }
  printf("%d\n", iNBi);
  return 0;
}
```