ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <test_next_smallest@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L5
L12:
  mov    $0x0,%eax
  call   <test_next_largest@plt>
  test   %eax,%eax
  je     L24
L34:
  mov    %ebx,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
L5:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  jmp    L12
L24:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%ebx
  jmp    L34
```

tool_calls: name: parse_data
arguments: data_label: D21
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string

tool: D21: %d tests failed.


tool: D14: Next smallest positive test failed!

tool: D13: Next largest positive test failed!

assistant: ```c
void main() {
  int counter = 0;
  if (!test_next_smallest()) {
    printf("Next smallest positive test failed!\n");
    counter++;
  }
  if (!test_next_largest()) {
    printf("Next largest positive test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <test_next_smallest@plt>
  test   %eax,%eax
  je     L3
L8:
  xor    %eax,%eax
  call   <test_next_largest@plt>
  test   %eax,%eax
  je     L14
L25:
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    10a0 <printf@plt>
L3:
  lea    D10(%rip),%rdi
  mov    $0x1,%ebp
  call   <puts@plt>
  jmp    L8
L14:
  lea    D20(%rip),%rdi
  add    $0x1,%ebp
  call   <puts@plt>
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_label: D22
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string

tool: D22: %d tests failed.


tool: D10: Next smallest positive test failed!

tool: D20: Next largest positive test failed!

assistant: ```c
void main() {
  int counter = 0;
  if (!test_next_smallest()) {
    printf("Next smallest positive test failed!\n");
    counter++;
  }
  if (!test_next_largest()) {
    printf("Next largest positive test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <test_next_smallest@plt>
  test   %eax,%eax
  je     L33
L37:
  xor    %eax,%eax
  call   <test_next_largest@plt>
  test   %eax,%eax
  je     L23
L21:
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    10a0 <printf@plt>
L33:
  lea    D9(%rip),%rdi
  mov    $0x1,%ebp
  call   <puts@plt>
  jmp    L37
L23:
  lea    D15(%rip),%rdi
  add    $0x1,%ebp
  call   <puts@plt>
  jmp    L21
```

tool_calls: name: parse_data
arguments: tag: D13
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D15
type_infered: string

tool: D13: %d tests failed.


tool: D9: Next smallest positive test failed!

tool: D15: Next largest positive test failed!

assistant: ```c
void main() {
  int counter = 0;
  if (!test_next_smallest()) {
    printf("Next smallest positive test failed!\n");
    counter++;
  }
  if (!test_next_largest()) {
    printf("Next largest positive test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L15:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L12:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *restrict dest, const char *restrict src, size_t n) {
  char *ret = dest;
  while (n--) {
    *dest++ = *src++;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L8
  mov    $0x0,%ecx
L18:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L18
L8:
  ret
```

assistant: ```c
char *strncpy(char *restrict dest, const char *restrict src, size_t n) {
  char *ret = dest;
  while (n--) {
    *dest++ = *src++;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncpy>:
  endbr64
  test   %rdx,%rdx
  je     L5
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strncpy(char *restrict dest, const char *restrict src, size_t n) {
  char *ret = dest;
  while (n--) {
    *dest++ = *src++;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncpy>:
  endbr64
  test   %rdx,%rdx
  je     L6
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strncpy(char *restrict dest, const char *restrict src, size_t n) {
  char *ret = dest;
  while (n--) {
    *dest++ = *src++;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<output_binary_exponential_buffer_to_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_exponential_buffer_data@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_exponential_buffer_size@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L7
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  jmp    L17
L7:
  movl   $0x0,-0x18(%rbp)
  jmp    L22
L15:
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addl   $0x1,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L15
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D15: w

tool: D8: Failed to open file %s for write.


assistant: ```c
int output_binary_exponential_buffer_to_file(struct binary_exponential_buffer *buffer, unsigned char *out_file) {
  FILE *f = NULL;
  unsigned char *data = (unsigned char *)binary_exponential_buffer_data(buffer);
  unsigned int size = binary_exponential_buffer_size(buffer);
  unsigned int i;
  if (!(f = fopen((char *)out_file, "w"))) {
    printf("Failed to open file %s for write.\n", out_file);
    assert(0);
    return 1;
  }
  for (i = 0; i < size; i++) {
    fputc(data[i], f);
  }
  fclose(f);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_binary_exponential_buffer_to_file>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  call   <binary_exponential_buffer_data@plt>
  mov    %rax,%r13
  mov    %rbx,%rdi
  call   <binary_exponential_buffer_size@plt>
  mov    %eax,%r12d
  lea    D0(%rip),%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rbp
  test   %r12d,%r12d
  je     L11
  mov    %r13,%rbx
  lea    -0x1(%r12),%eax
  lea    0x1(%r13,%rax,1),%r12
L3:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L3
L11:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    %r14,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  jmp    L28
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D3
datatype: string

tool: D0: w

tool: D3: Failed to open file %s for write.


assistant: ```c
int output_binary_exponential_buffer_to_file(struct binary_exponential_buffer *buffer, unsigned char *out_file) {
  FILE *f = NULL;
  unsigned char *data = (unsigned char *)binary_exponential_buffer_data(buffer);
  unsigned int size = binary_exponential_buffer_size(buffer);
  unsigned int i;
  if (!(f = fopen((char *)out_file, "w"))) {
    printf("Failed to open file %s for write.\n", out_file);
    assert(0);
    return 1;
  }
  for (i = 0; i < size; i++) {
    fputc(data[i], f);
  }
  fclose(f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_binary_exponential_buffer_to_file>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <binary_exponential_buffer_data@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <binary_exponential_buffer_size@plt>
  lea    D11(%rip),%rsi
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <fopen@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbp
  test   %r12d,%r12d
  je     L34
  lea    -0x1(%r12),%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopl   (%rax)
L8:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r12,%rbx
  jne    L8
L34:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  mov    %r13,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  jmp    L19
```

tool_calls: name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D11: w

tool: D15: Failed to open file %s for write.


assistant: ```c
int output_binary_exponential_buffer_to_file(struct binary_exponential_buffer *buffer, unsigned char *out_file) {
  FILE *f = NULL;
  unsigned char *data = (unsigned char *)binary_exponential_buffer_data(buffer);
  unsigned int size = binary_exponential_buffer_size(buffer);
  unsigned int i;
  if (!(f = fopen((char *)out_file, "w"))) {
    printf("Failed to open file %s for write.\n", out_file);
    assert(0);
    return 1;
  }
  for (i = 0; i < size; i++) {
    fputc(data[i], f);
  }
  fclose(f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<output_binary_exponential_buffer_to_file>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <binary_exponential_buffer_data@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <binary_exponential_buffer_size@plt>
  lea    D6(%rip),%rsi
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <fopen@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%rbp
  test   %r12d,%r12d
  je     L4
  lea    -0x1(%r12),%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopl   (%rax)
L34:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r12,%rbx
  jne    L34
L4:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  mov    %r13,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  jmp    L2
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D6: w

tool: D15: Failed to open file %s for write.


assistant: ```c
int output_binary_exponential_buffer_to_file(struct binary_exponential_buffer *buffer, unsigned char *out_file) {
  FILE *f = NULL;
  unsigned char *data = (unsigned char *)binary_exponential_buffer_data(buffer);
  unsigned int size = binary_exponential_buffer_size(buffer);
  unsigned int i;
  if (!(f = fopen((char *)out_file, "w"))) {
    printf("Failed to open file %s for write.\n", out_file);
    assert(0);
    return 1;
  }
  for (i = 0; i < size; i++) {
    fputc(data[i], f);
  }
  fclose(f);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convolve_real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    0x18(%rbp),%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%r8d
  mov    0x10(%rbp),%ecx
  mov    %eax,%edi
  call   <bounds_check@plt>
  test   %rax,%rax
  jns    L15
  mov    $0xffffffff,%eax
  jmp    L16
L15:
  mov    0x18(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  mov    $0x1,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    0x18(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%r8
  mov    %rax,%rsi
  call   *%r8
  jmp    L18
L25:
  mov    -0x34(%rbp),%r9d
  mov    -0x30(%rbp),%r8
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    0x18(%rbp),%edi
  push   %rdi
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  call   <_base_convolve_real@plt>
  add    $0x10,%rsp
L18:
  mov    0x18(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int convolve_real(float *x, int x_len, float *h, int h_len, float *y, int y_len, int start, int len) {
  void (*conv_func)(float *, float *, float *, int) = NULL;
  if (bounds_check(x_len, h_len, y_len, start, len) < 0)
    return -1;
  memset(y, 0, len * 2 * sizeof(float));
  if (conv_func) {
    conv_func(&x[2 * (-(h_len - 1) + start)], h, y, len);
  } else {
    _base_convolve_real(x, x_len, h, h_len, y, y_len, start, len);
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convolve_real>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%ebp
  mov    %rdx,%r15
  mov    %ecx,%r12d
  mov    %r8,%r14
  mov    %r9d,%r13d
  mov    0x58(%rsp),%ebx
  mov    %ebx,%r8d
  mov    0x50(%rsp),%ecx
  mov    %r9d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bounds_check@plt>
  test   %rax,%rax
  js     L7
  lea    0x0(,%rbx,8),%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  push   %rbx
  mov    0x58(%rsp),%eax
  push   %rax
  mov    %r13d,%r9d
  mov    %r14,%r8
  mov    %r12d,%ecx
  mov    %r15,%rdx
  mov    %ebp,%esi
  mov    0x18(%rsp),%rdi
  call   <_base_convolve_real@plt>
  add    $0x10,%rsp
  mov    %ebx,%eax
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int convolve_real(float *x, int x_len, float *h, int h_len, float *y, int y_len, int start, int len) {
  void (*conv_func)(float *, float *, float *, int) = NULL;
  if (bounds_check(x_len, h_len, y_len, start, len) < 0)
    return -1;
  memset(y, 0, len * 2 * sizeof(float));
  if (conv_func) {
    conv_func(&x[2 * (-(h_len - 1) + start)], h, y, len);
  } else {
    _base_convolve_real(x, x_len, h, h_len, y, y_len, start, len);
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<convolve_real>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rdx,%r14
  mov    %r9d,%edx
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %r12d,%esi
  push   %rbx
  sub    $0x18,%rsp
  mov    0x58(%rsp),%ebx
  mov    0x50(%rsp),%ecx
  mov    %rdi,0x8(%rsp)
  mov    %ebp,%edi
  mov    %ebx,%r8d
  call   <bounds_check@plt>
  test   %rax,%rax
  js     L4
  lea    0x0(,%rbx,8),%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  push   %rbx
  mov    0x58(%rsp),%eax
  mov    %r14,%rdx
  mov    %r13d,%r9d
  mov    %r15,%r8
  mov    %r12d,%ecx
  mov    %ebp,%esi
  push   %rax
  mov    0x18(%rsp),%rdi
  call   <_base_convolve_real@plt>
  pop    %rax
  mov    %ebx,%eax
  pop    %rdx
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int convolve_real(float *x, int x_len, float *h, int h_len, float *y, int y_len, int start, int len) {
  void (*conv_func)(float *, float *, float *, int) = NULL;
  if (bounds_check(x_len, h_len, y_len, start, len) < 0)
    return -1;
  memset(y, 0, len * 2 * sizeof(float));
  if (conv_func) {
    conv_func(&x[2 * (-(h_len - 1) + start)], h, y, len);
  } else {
    _base_convolve_real(x, x_len, h, h_len, y, y_len, start, len);
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convolve_real>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rdx,%r14
  mov    %r9d,%edx
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %r12d,%esi
  push   %rbx
  sub    $0x18,%rsp
  mov    0x58(%rsp),%ebx
  mov    0x50(%rsp),%ecx
  mov    %rdi,0x8(%rsp)
  mov    %ebp,%edi
  mov    %ebx,%r8d
  call   <bounds_check@plt>
  test   %rax,%rax
  js     L16
  lea    0x0(,%rbx,8),%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  push   %rbx
  mov    0x58(%rsp),%eax
  mov    %r14,%rdx
  mov    %r13d,%r9d
  mov    %r15,%r8
  mov    %r12d,%ecx
  mov    %ebp,%esi
  push   %rax
  mov    0x18(%rsp),%rdi
  call   <_base_convolve_real@plt>
  pop    %rax
  mov    %ebx,%eax
  pop    %rdx
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L16:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int convolve_real(float *x, int x_len, float *h, int h_len, float *y, int y_len, int start, int len) {
  void (*conv_func)(float *, float *, float *, int) = NULL;
  if (bounds_check(x_len, h_len, y_len, start, len) < 0)
    return -1;
  memset(y, 0, len * 2 * sizeof(float));
  if (conv_func) {
    conv_func(&x[2 * (-(h_len - 1) + start)], h, y, len);
  } else {
    _base_convolve_real(x, x_len, h, h_len, y, y_len, start, len);
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cvtbase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L51
L47:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L6:
  mov    -0x8(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rsi
  mov    %rax,%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,-0x8(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L6
  subl   $0x1,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  mov    %dl,(%rax)
L51:
  cmpl   $0x0,-0xc(%rbp)
  jle    L9
  cmpl   $0x0,-0x34(%rbp)
  jg     L47
L9:
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L28:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cvtbase(oldbase, newbase, input, inlen, result, reslen) long oldbase;
int newbase;
int input[];
int inlen;
unsigned char result[];
int reslen;
{
  int d, e;
  long sum;
  e = 1;
  while (e > 0 && reslen > 0) {
    d = 0;
    e = 0;
    sum = 0;
    while (d < inlen) {
      sum = sum * oldbase + (long)input[d];
      e += (sum > 0);
      input[d++] = sum / newbase;
      sum %= newbase;
    }
    result[--reslen] = sum;
  }
  for (d = 0; d < reslen; d++)
    result[d] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cvtbase>:
  endbr64
  test   %r9d,%r9d
  jle    L17
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  mov    %r8,%r12
  movslq %r9d,%rax
  lea    -0x1(%r8,%rax,1),%r8
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r11
  mov    $0x0,%r13d
  movslq %esi,%rdi
  jmp    L39
L15:
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    $0x0,%esi
L54:
  imul   %r10,%rdx
  movslq (%rcx),%rax
  add    %rdx,%rax
  test   %rax,%rax
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%esi
  cqto
  idiv   %rdi
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  cmp    %r11,%rcx
  jne    L54
  sub    $0x1,%r9d
  mov    %dl,(%r8)
  sub    $0x1,%r8
  test   %esi,%esi
  jle    L31
  test   %r9d,%r9d
  jle    L31
L39:
  test   %ebp,%ebp
  jg     L15
  sub    $0x1,%r9d
  movslq %r9d,%rax
  movb   $0x0,(%r12,%rax,1)
L31:
  test   %r9d,%r9d
  jle    L60
  mov    %r12,%rax
  lea    -0x1(%r9),%edx
  lea    0x1(%r12,%rdx,1),%rdx
L70:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L70
L60:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  ret
```

assistant: ```c
void cvtbase(oldbase, newbase, input, inlen, result, reslen) long oldbase;
int newbase;
int input[];
int inlen;
unsigned char result[];
int reslen;
{
  int d, e;
  long sum;
  e = 1;
  while (e > 0 && reslen > 0) {
    d = 0;
    e = 0;
    sum = 0;
    while (d < inlen) {
      sum = sum * oldbase + (long)input[d];
      e += (sum > 0);
      input[d++] = sum / newbase;
      sum %= newbase;
    }
    result[--reslen] = sum;
  }
  for (d = 0; d < reslen; d++)
    result[d] = 0;
}
```