ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<simplex_contract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L34
L35:
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D25(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  addss  -0x8(%rbp),%xmm1
  movss  D25(%rip),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L17:
  mov    -0x14(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  mov    -0x34(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm0
  mulss  -0x8(%rbp),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x14(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mulss  -0x4(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movslq %edx,%rdx
  movss  %xmm0,(%rax,%rdx,4)
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L17
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0x34(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L35
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
data_type: f32
name: disassemble_data
arguments: data_label: D25
data_type: f32

tool: D19: 2

tool: D25: 1

assistant: ```c
simplex_contract(pt, rf, n, best, worst, howmuch) int n, best, worst;
float howmuch;
float (*pt)[], (*rf)[];
{
  int i, j;
  float r1, r2, r3, randf();
  for (i = 0; i < n + 1; i++) {
    r1 = 2.;
    r2 = 1.;
    r3 = 1. / (r1 + r2);
    for (j = 0; j < n; j++)
      (*pt)[i * n + j] = r3 * (r1 * (*pt)[i * n + j] + r2 * (*pt)[n * best + j]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simplex_contract>:
  endbr64
  test   %edx,%edx
  js     L31
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %edx,%r9d
  imul   %edx,%ecx
  lea    0x1(%rdx),%ebx
  mov    $0x0,%r8d
  mov    $0x0,%edi
  lea    -0x1(%rdx),%r12d
  lea    0x4(%r11),%rbp
  movslq %ecx,%r10
  movss  D9(%rip),%xmm1
  jmp    L34
L15:
  movslq %r8d,%rsi
  lea    (%r11,%rsi,4),%rax
  lea    (%r12,%rsi,1),%rdx
  lea    0x0(%rbp,%rdx,4),%rcx
  mov    %r10,%rdx
  sub    %rsi,%rdx
L8:
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm0
  addss  (%rax,%rdx,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
L33:
  add    $0x1,%edi
  add    %r9d,%r8d
  cmp    %ebx,%edi
  je     L1
L34:
  test   %r9d,%r9d
  jg     L15
  jmp    L33
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: byte[4]

tool: {"D9": [0xab,0xaa,0xaa,0x3e]}

assistant: ```c
simplex_contract(pt, rf, n, best, worst, howmuch) int n, best, worst;
float howmuch;
float (*pt)[], (*rf)[];
{
  int i, j;
  float r1, r2, r3, randf();
  for (i = 0; i < n + 1; i++) {
    r1 = 2.;
    r2 = 1.;
    r3 = 1. / (r1 + r2);
    for (j = 0; j < n; j++)
      (*pt)[i * n + j] = r3 * (r1 * (*pt)[i * n + j] + r2 * (*pt)[n * best + j]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<simplex_contract>:
  endbr64
  test   %edx,%edx
  js     L21
  imul   %edx,%ecx
  mov    %rdi,%r11
  movss  D0(%rip),%xmm1
  push   %r12
  mov    %edx,%r9d
  push   %rbp
  xor    %r8d,%r8d
  xor    %edi,%edi
  push   %rbx
  lea    -0x1(%rdx),%r12d
  lea    0x1(%rdx),%ebx
  lea    0x4(%r11),%rbp
  movslq %ecx,%r10
L8:
  test   %r9d,%r9d
  je     L2
  movslq %r8d,%rsi
  lea    (%r12,%rsi,1),%rdx
  lea    (%r11,%rsi,4),%rax
  lea    0x0(%rbp,%rdx,4),%rcx
  mov    %r10,%rdx
  sub    %rsi,%rdx
  nopl   0x0(%rax,%rax,1)
L24:
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm0
  addss  (%rax,%rdx,4),%xmm0
  add    $0x4,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L24
L2:
  add    $0x1,%edi
  add    %r9d,%r8d
  cmp    %ebx,%edi
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: byte[4]

tool: {"D0": [0xab,0xaa,0xaa,0x3e]}

assistant: ```c
simplex_contract(pt, rf, n, best, worst, howmuch) int n, best, worst;
float howmuch;
float (*pt)[], (*rf)[];
{
  int i, j;
  float r1, r2, r3, randf();
  for (i = 0; i < n + 1; i++) {
    r1 = 2.;
    r2 = 1.;
    r3 = 1. / (r1 + r2);
    for (j = 0; j < n; j++)
      (*pt)[i * n + j] = r3 * (r1 * (*pt)[i * n + j] + r2 * (*pt)[n * best + j]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L22:
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L38
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type: string
name: disassemble_data
arguments: data_label: D6
type: string

tool: D15: %d 

tool: D6: %d


assistant: ```c
void printMatrix(int **A, int n, int m) {
  int i = 0;
  while (i < n) {
    for (int j = 0; j < m - 1; j++) {
      printf("%d ", A[i][j]);
    }
    printf("%d\n", A[i][m - 1]);
    ++i;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printMatrix>:
  endbr64
  test   %esi,%esi
  jle    L52
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,%r14d
  movslq %edx,%rax
  lea    -0x4(,%rax,4),%r15
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x2(%rdx),%eax
  lea    0x4(,%rax,4),%r13
  lea    D14(%rip),%r12
  jmp    L44
L11:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r13
  jne    L11
L58:
  mov    0x0(%rbp),%rax
  mov    (%rax,%r15,1),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rbp
  cmp    0x8(%rsp),%rbp
  je     L12
L44:
  mov    $0x0,%ebx
  cmp    $0x1,%r14d
  jg     L11
  jmp    L58
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  ret
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D4
datatype: string

tool: D14: %d 

tool: D4: %d


assistant: ```c
void printMatrix(int **A, int n, int m) {
  int i = 0;
  while (i < n) {
    for (int j = 0; j < m - 1; j++) {
      printf("%d ", A[i][j]);
    }
    printf("%d\n", A[i][m - 1]);
    ++i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printMatrix>:
  endbr64
  test   %esi,%esi
  jle    L20
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    -0x4(,%rax,4),%rax
  mov    %rdi,%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  mov    %rax,(%rsp)
  lea    -0x2(%rdx),%eax
  lea    0x4(,%rax,4),%rbp
  nopl   (%rax)
L14:
  xor    %r15d,%r15d
  cmp    $0x1,%r12d
  jle    L26
  nopl   0x0(%rax)
L10:
  mov    (%r14),%rax
  mov    %rbx,%rdi
  mov    (%rax,%r15,1),%esi
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L10
L26:
  mov    (%r14),%rax
  mov    0x8(%rsp),%rcx
  mov    %r13,%rdi
  add    $0x8,%r14
  mov    (%rax,%rcx,1),%esi
  call   <printf@plt>
  cmp    %r14,(%rsp)
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D12: %d


tool: D0: %d 

assistant: ```c
void printMatrix(int **A, int n, int m) {
  int i = 0;
  while (i < n) {
    for (int j = 0; j < m - 1; j++) {
      printf("%d ", A[i][j]);
    }
    printf("%d\n", A[i][m - 1]);
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printMatrix>:
  endbr64
  test   %esi,%esi
  jle    L24
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    -0x4(,%rax,4),%rax
  mov    %rdi,%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x18,%rsp
  mov    %rax,(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x2(%rdx),%eax
  lea    0x4(,%rax,4),%rbp
  nopl   (%rax)
L33:
  xor    %r15d,%r15d
  cmp    $0x1,%r12d
  jle    L35
  nopl   0x0(%rax)
L30:
  mov    (%r14),%rax
  mov    %rbx,%rdi
  mov    (%rax,%r15,1),%esi
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbp,%r15
  jne    L30
L35:
  mov    (%r14),%rax
  mov    (%rsp),%rcx
  mov    %r13,%rdi
  add    $0x8,%r14
  mov    (%rax,%rcx,1),%esi
  call   <printf@plt>
  cmp    0x8(%rsp),%r14
  jne    L33
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string
name: read_data
arguments: data_label: D0
type: string

tool: D5: %d


tool: D0: %d 

assistant: ```c
void printMatrix(int **A, int n, int m) {
  int i = 0;
  while (i < n) {
    for (int j = 0; j < m - 1; j++) {
      printf("%d ", A[i][j]);
    }
    printf("%d\n", A[i][m - 1]);
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <setup@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L4:
  mov    $0x0,%eax
  call   <loop@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x31,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setup();
  for (int i = 0; i < 50; i++) {
    loop();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <setup@plt>
  mov    $0x32,%ebx
L3:
  mov    $0x0,%eax
  call   <loop@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setup();
  for (int i = 0; i < 50; i++) {
    loop();
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0x32,%ebx
  call   <setup@plt>
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <loop@plt>
  sub    $0x1,%ebx
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setup();
  for (int i = 0; i < 50; i++) {
    loop();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0x32,%ebx
  call   <setup@plt>
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <loop@plt>
  sub    $0x1,%ebx
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setup();
  for (int i = 0; i < 50; i++) {
    loop();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parseLabels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L32
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L39
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x2c,(%rax)
  jmp    L35
L39:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L35:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void parseLabels(char *s, char **l1, char **l2) {
  char *p = s;
  *l1 = NULL;
  *l2 = NULL;
  while (*p) {
    if (*p == ',') {
      *l2 = strdup(p + 1);
      *p = '\0';
      *l1 = strdup(s);
      *p = ',';
      break;
    }
    p++;
  }
  assert(*l1);
  assert(*l2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseLabels>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
  mov    %rdi,%r13
  mov    %rdi,%rbx
L6:
  cmp    $0x2c,%al
  je     L2
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L6
  jmp    L36
L2:
  lea    0x1(%rbx),%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  movb   $0x0,(%rbx)
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  movb   $0x2c,(%rbx)
L36:
  mov    (%r12),%rdi
  call   <assert@plt>
  mov    0x0(%rbp),%rdi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void parseLabels(char *s, char **l1, char **l2) {
  char *p = s;
  *l1 = NULL;
  *l2 = NULL;
  while (*p) {
    if (*p == ',') {
      *l2 = strdup(p + 1);
      *p = '\0';
      *l1 = strdup(s);
      *p = ',';
      break;
    }
    p++;
  }
  assert(*l1);
  assert(*l2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseLabels>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  mov    %rdi,%r13
  jmp    L23
  xchg   %ax,%ax
L19:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
L23:
  mov    %rdi,%rbx
  add    $0x1,%rdi
  cmp    $0x2c,%al
  jne    L19
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    %rax,0x0(%rbp)
  movb   $0x0,(%rbx)
  call   <strdup@plt>
  mov    %rax,(%r12)
  movb   $0x2c,(%rbx)
L24:
  mov    (%r12),%rdi
  call   <assert@plt>
  mov    0x0(%rbp),%rdi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <assert@plt>
```

assistant: ```c
void parseLabels(char *s, char **l1, char **l2) {
  char *p = s;
  *l1 = NULL;
  *l2 = NULL;
  while (*p) {
    if (*p == ',') {
      *l2 = strdup(p + 1);
      *p = '\0';
      *l1 = strdup(s);
      *p = ',';
      break;
    }
    p++;
  }
  assert(*l1);
  assert(*l2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseLabels>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
  mov    %rdi,%r13
  jmp    L21
  xchg   %ax,%ax
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
L21:
  mov    %rdi,%rbx
  add    $0x1,%rdi
  cmp    $0x2c,%al
  jne    L13
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    %rax,0x0(%rbp)
  movb   $0x0,(%rbx)
  call   <strdup@plt>
  mov    %rax,(%r12)
  movb   $0x2c,(%rbx)
L31:
  mov    (%r12),%rdi
  call   <assert@plt>
  mov    0x0(%rbp),%rdi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <assert@plt>
```

assistant: ```c
void parseLabels(char *s, char **l1, char **l2) {
  char *p = s;
  *l1 = NULL;
  *l2 = NULL;
  while (*p) {
    if (*p == ',') {
      *l2 = strdup(p + 1);
      *p = '\0';
      *l1 = strdup(s);
      *p = ',';
      break;
    }
    p++;
  }
  assert(*l1);
  assert(*l2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sprint_xch_direct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: XCH   A, 0x%02X                   

assistant: ```c
void sprint_xch_direct(char *str, uint8_t direct) {
  sprintf(str,
          "XCH   A, "
          "0x%02X"
          "                   ",
          direct);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sprint_xch_direct>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  lea    D8(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: XCH   A, 0x%02X                   

assistant: ```c
void sprint_xch_direct(char *str, uint8_t direct) {
  sprintf(str,
          "XCH   A, "
          "0x%02X"
          "                   ",
          direct);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sprint_xch_direct>:
  endbr64
  mov    %esi,%edx
  lea    D5(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: XCH   A, 0x%02X                   

assistant: ```c
void sprint_xch_direct(char *str, uint8_t direct) {
  sprintf(str,
          "XCH   A, "
          "0x%02X"
          "                   ",
          direct);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sprint_xch_direct>:
  endbr64
  mov    %esi,%edx
  lea    D3(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: XCH   A, 0x%02X                   

assistant: ```c
void sprint_xch_direct(char *str, uint8_t direct) {
  sprintf(str,
          "XCH   A, "
          "0x%02X"
          "                   ",
          direct);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CompareStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L77
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L23
L77:
  mov    $0x0,%eax
L23:
  mov    %eax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L100
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L65
L100:
  mov    $0x0,%eax
L65:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L35
  cmpl   $0x0,-0x4(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L68
L35:
  cmpl   $0x0,-0x8(%rbp)
  jne    L44
  mov    $0xffffffff,%eax
  jmp    L68
L44:
  cmpl   $0x0,-0x4(%rbp)
  jne    L28
  mov    $0x1,%eax
  jmp    L68
L28:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L68:
  leave
  ret
```

assistant: ```c
int CompareStr(const char *S1, const char *S2) {
  int len1, len2;
  len1 = (S1 ? strlen(S1) : 0);
  len2 = (S2 ? strlen(S2) : 0);
  if ((len1 == 0) && (len2 == 0))
    return (0);
  if (len1 == 0)
    return (-1);
  if (len2 == 0)
    return (1);
  return (strcmp(S1, S2));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CompareStr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L30
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  test   %rbp,%rbp
  je     L46
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
L46:
  mov    %eax,%edx
  or     %r12d,%edx
  je     L71
  test   %r12d,%r12d
  je     L27
  mov    $0x1,%edx
  test   %eax,%eax
  je     L71
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
L71:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    $0xffffffff,%edx
  jmp    L71
L30:
  mov    $0x0,%r12d
  test   %rsi,%rsi
  jne    L25
  mov    $0x0,%edx
  jmp    L71
```

assistant: ```c
int CompareStr(const char *S1, const char *S2) {
  int len1, len2;
  len1 = (S1 ? strlen(S1) : 0);
  len2 = (S2 ? strlen(S2) : 0);
  if ((len1 == 0) && (len2 == 0))
    return (0);
  if (len1 == 0)
    return (-1);
  if (len2 == 0)
    return (1);
  return (strcmp(S1, S2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<CompareStr>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L73
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %r12,%r12
  jne    L5
  xor    %eax,%eax
  test   %ebx,%ebx
  setne  %al
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  or     %eax,%edx
  je     L20
  test   %ebx,%ebx
  je     L43
  test   %eax,%eax
  je     L26
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcmp@plt>
  nopl   (%rax)
L20:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L73:
  test   %rsi,%rsi
  je     L20
  mov    %r12,%rdi
  call   <strlen@plt>
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  sbb    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    $0x1,%eax
  jmp    L9
L43:
  or     $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int CompareStr(const char *S1, const char *S2) {
  int len1, len2;
  len1 = (S1 ? strlen(S1) : 0);
  len2 = (S2 ? strlen(S2) : 0);
  if ((len1 == 0) && (len2 == 0))
    return (0);
  if (len1 == 0)
    return (-1);
  if (len2 == 0)
    return (1);
  return (strcmp(S1, S2));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CompareStr>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L15
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %r12,%r12
  jne    L52
  xor    %eax,%eax
  test   %ebx,%ebx
  setne  %al
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  or     %eax,%edx
  je     L38
  test   %ebx,%ebx
  je     L29
  test   %eax,%eax
  je     L25
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcmp@plt>
  nopl   (%rax)
L38:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L15:
  test   %rsi,%rsi
  je     L38
  mov    %r12,%rdi
  call   <strlen@plt>
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  sbb    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
  jmp    L78
L29:
  or     $0xffffffff,%eax
  jmp    L78
```

assistant: ```c
int CompareStr(const char *S1, const char *S2) {
  int len1, len2;
  len1 = (S1 ? strlen(S1) : 0);
  len2 = (S2 ? strlen(S2) : 0);
  if ((len1 == 0) && (len2 == 0))
    return (0);
  if (len1 == 0)
    return (-1);
  if (len2 == 0)
    return (1);
  return (strcmp(S1, S2));
}
```