ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_score>:
  endbr64
  mov    (%rdi),%r8d
  mov    0x10(%rdi),%ecx
  cmp    $0x1,%r8d
  je     L68
  cmp    $0x2,%r8d
  jle    L8
  sub    $0x2,%r8d
  imul   $0x64,%r8d,%r8d
L6:
  mov    $0x2,%edx
L3:
  mov    -0x4(%rdi,%rdx,4),%eax
  cmp    $0x2,%eax
  jle    L107
  sub    $0x2,%eax
  imul   %edx,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%r8,%rax,2),%r8d
L107:
  add    $0x1,%rdx
  cmp    $0x7,%rdx
  jne    L3
  cmp    $0x2,%ecx
  jg     L36
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%r8d
L36:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  cmpl   $0x1,0x4(%rdi)
  je     L30
L8:
  lea    (%r8,%r8,4),%r8d
  add    %r8d,%r8d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L30:
  cmpl   $0x1,0x8(%rdi)
  jne    L8
  cmpl   $0x1,0xc(%rdi)
  jne    L8
  cmp    $0x1,%ecx
  jne    L8
  cmpl   $0x1,0x14(%rdi)
  jne    L8
  mov    $0x78,%r8d
  jmp    L36
```

assistant: ```c
int get_score(int *occ) {
  int score, i;
  if (occ[0] == 1 && occ[1] == 1 && occ[2] == 1 && occ[3] == 1 && occ[4] == 1 && occ[5] == 1) {
    return 120;
  }
  score = 0;
  if (occ[0] >= 3) {
    score += 100 * (occ[0] - 2);
  } else {
    score += 10 * occ[0];
  }
  for (i = 1; i < 6; i++) {
    if (occ[i] >= 3) {
      score += (i + 1) * 10 * (occ[i] - 2);
    }
  }
  if (occ[4] < 3) {
    score += 5 * occ[4];
  }
  return score;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_score>:
  endbr64
  mov    (%rdi),%edx
  mov    0x10(%rdi),%ecx
  cmp    $0x1,%edx
  je     L75
  cmp    $0x2,%edx
  jle    L81
  sub    $0x2,%edx
  imul   $0x64,%edx,%edx
L99:
  movdqu 0x4(%rdi),%xmm0
  movdqa D1(%rip),%xmm1
  movdqa D9(%rip),%xmm3
  paddd  %xmm0,%xmm1
  pcmpgtd D17(%rip),%xmm0
  movdqa %xmm1,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm3,%xmm2
  psrlq  $0x20,%xmm3
  pmuludq %xmm3,%xmm1
  pshufd $0x8,%xmm2,%xmm2
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm2
  movdqa %xmm2,%xmm1
  pslld  $0x2,%xmm1
  paddd  %xmm2,%xmm1
  pslld  $0x1,%xmm1
  pand   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %edx,%eax
  mov    0x14(%rdi),%edx
  cmp    $0x2,%edx
  jle    L22
  sub    $0x2,%edx
  imul   $0x3c,%edx,%edx
  add    %edx,%eax
L22:
  cmp    $0x2,%ecx
  jg     L41
  lea    (%rcx,%rcx,4),%edx
  add    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  cmpl   $0x1,0x4(%rdi)
  je     L80
L81:
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  jmp    L99
L41:
  ret
  nopl   0x0(%rax)
L80:
  cmpl   $0x1,0x8(%rdi)
  jne    L81
  cmpl   $0x1,0xc(%rdi)
  jne    L81
  cmp    $0x1,%ecx
  jne    L81
  cmpl   $0x1,0x14(%rdi)
  jne    L81
  mov    $0x78,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: byte[16]
name: retrieve_data
arguments: tag: D9
datatype: byte[16]
name: retrieve_data
arguments: tag: D17
datatype: byte[16]

tool: {"D1": [0xfe,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfe,0xff,0xff,0xff]}

tool: {"D9": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D17": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int get_score(int *occ) {
  int score, i;
  if (occ[0] == 1 && occ[1] == 1 && occ[2] == 1 && occ[3] == 1 && occ[4] == 1 && occ[5] == 1) {
    return 120;
  }
  score = 0;
  if (occ[0] >= 3) {
    score += 100 * (occ[0] - 2);
  } else {
    score += 10 * occ[0];
  }
  for (i = 1; i < 6; i++) {
    if (occ[i] >= 3) {
      score += (i + 1) * 10 * (occ[i] - 2);
    }
  }
  if (occ[4] < 3) {
    score += 5 * occ[4];
  }
  return score;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_tabstradd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L31
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_tabstrlen@plt>
  jmp    L17
L31:
  mov    $0x0,%eax
L17:
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ft_memcpy@plt>
  jmp    L0
L10:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **ft_tabstradd(char **tab, char *str) {
  char **newtab;
  size_t size_tab;
  size_tab = (tab) ? ft_tabstrlen(tab) : 0;
  if (tab) {
    newtab = (char **)malloc(sizeof(char *) * (size_tab + 2));
    ft_memcpy(newtab, tab, sizeof(char *) * size_tab);
  } else
    newtab = (char **)malloc(sizeof(char *) * 2);
  newtab[size_tab] = str;
  newtab[size_tab + 1] = 0;
  free(tab);
  return (newtab);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_tabstradd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rdi,%rdi
  je     L19
  call   <ft_tabstrlen@plt>
  mov    %rax,%r12
  lea    0x10(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x0(,%r12,8),%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_memcpy@plt>
L6:
  mov    %r13,(%rbx,%r12,8)
  movq   $0x0,0x8(%rbx,%r12,8)
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%r12d
  jmp    L6
```

assistant: ```c
char **ft_tabstradd(char **tab, char *str) {
  char **newtab;
  size_t size_tab;
  size_tab = (tab) ? ft_tabstrlen(tab) : 0;
  if (tab) {
    newtab = (char **)malloc(sizeof(char *) * (size_tab + 2));
    ft_memcpy(newtab, tab, sizeof(char *) * size_tab);
  } else
    newtab = (char **)malloc(sizeof(char *) * 2);
  newtab[size_tab] = str;
  newtab[size_tab + 1] = 0;
  free(tab);
  return (newtab);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_tabstradd>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L10
  call   <ft_tabstrlen@plt>
  lea    0x10(,%rax,8),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edx
  mov    %rbp,%rsi
  shl    $0x3,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <ft_memcpy@plt>
  lea    (%r12,%rbx,1),%rax
  add    $0x8,%rbx
L11:
  mov    %r13,(%rax)
  mov    %rbp,%rdi
  movq   $0x0,(%r12,%rbx,1)
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L10:
  mov    $0x10,%edi
  mov    $0x8,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L11
```

assistant: ```c
char **ft_tabstradd(char **tab, char *str) {
  char **newtab;
  size_t size_tab;
  size_tab = (tab) ? ft_tabstrlen(tab) : 0;
  if (tab) {
    newtab = (char **)malloc(sizeof(char *) * (size_tab + 2));
    ft_memcpy(newtab, tab, sizeof(char *) * size_tab);
  } else
    newtab = (char **)malloc(sizeof(char *) * 2);
  newtab[size_tab] = str;
  newtab[size_tab + 1] = 0;
  free(tab);
  return (newtab);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_tabstradd>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  call   <ft_tabstrlen@plt>
  lea    0x10(,%rax,8),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edx
  mov    %rbp,%rsi
  shl    $0x3,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <ft_memcpy@plt>
  lea    (%r12,%rbx,1),%rax
  add    $0x8,%rbx
L16:
  mov    %r13,(%rax)
  mov    %rbp,%rdi
  movq   $0x0,(%r12,%rbx,1)
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L12:
  mov    $0x10,%edi
  mov    $0x8,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L16
```

assistant: ```c
char **ft_tabstradd(char **tab, char *str) {
  char **newtab;
  size_t size_tab;
  size_tab = (tab) ? ft_tabstrlen(tab) : 0;
  if (tab) {
    newtab = (char **)malloc(sizeof(char *) * (size_tab + 2));
    ft_memcpy(newtab, tab, sizeof(char *) * size_tab);
  } else
    newtab = (char **)malloc(sizeof(char *) * 2);
  newtab[size_tab] = str;
  newtab[size_tab + 1] = 0;
  free(tab);
  return (newtab);
}
```
user: What is the c source code of the assembly code below:

```asm
<run_process_sandbox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execve@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D10
type: string

tool: D1: /virt/sandbox.sh

tool: D4: TERM=linux

tool: D10: HOME=/virt/home

assistant: ```c
int run_process_sandbox(char *filename) {
  char *new_argv[] = {filename, "/virt/sandbox.sh", NULL};
  char *new_env[] = {"TERM=linux", "HOME=/virt/home", NULL};
  return execve(filename, new_argv, new_env);
}
```
user: Translate the below assembly code into C programming language:

```asm
<run_process_sandbox>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  lea    D1(%rip),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    D13(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D2(%rip),%rax
  mov    %rax,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0x20(%rsp),%rdx
  mov    %rsp,%rsi
  call   <execve@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string

tool: D1: /virt/sandbox.sh

tool: D13: TERM=linux

tool: D2: HOME=/virt/home

assistant: ```c
int run_process_sandbox(char *filename) {
  char *new_argv[] = {filename, "/virt/sandbox.sh", NULL};
  char *new_env[] = {"TERM=linux", "HOME=/virt/home", NULL};
  return execve(filename, new_argv, new_env);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<run_process_sandbox>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rsp,%rsi
  mov    %rdi,(%rsp)
  mov    %rax,0x8(%rsp)
  lea    D1(%rip),%rax
  lea    0x20(%rsp),%rdx
  mov    %rax,0x20(%rsp)
  lea    D22(%rip),%rax
  movq   $0x0,0x10(%rsp)
  mov    %rax,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  call   <execve@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string
name: disassemble_data
arguments: data_label: D22
data_type: string

tool: D17: /virt/sandbox.sh

tool: D1: TERM=linux

tool: D22: HOME=/virt/home

assistant: ```c
int run_process_sandbox(char *filename) {
  char *new_argv[] = {filename, "/virt/sandbox.sh", NULL};
  char *new_env[] = {"TERM=linux", "HOME=/virt/home", NULL};
  return execve(filename, new_argv, new_env);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<run_process_sandbox>:
  endbr64
  sub    $0x48,%rsp
  lea    D21(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rsp,%rsi
  mov    %rdi,(%rsp)
  mov    %rax,0x8(%rsp)
  lea    D27(%rip),%rax
  movq   %rcx,%xmm0
  lea    0x20(%rsp),%rdx
  movq   $0x0,0x10(%rsp)
  movq   %rax,%xmm1
  movq   $0x0,0x30(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <execve@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x48,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D27
type_infered: string

tool: D21: TERM=linux

tool: D8: /virt/sandbox.sh

tool: D27: HOME=/virt/home

assistant: ```c
int run_process_sandbox(char *filename) {
  char *new_argv[] = {filename, "/virt/sandbox.sh", NULL};
  char *new_env[] = {"TERM=linux", "HOME=/virt/home", NULL};
  return execve(filename, new_argv, new_env);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<soru_7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L9
  mov    $0xffffffff,%eax
  jmp    L13
L9:
  mov    -0x4(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
int soru_7(const char s[], const char aranan[]) {
  int x = strstr(s, aranan);
  if (x == 0)
    return -1;
  else
    return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<soru_7>:
  endbr64
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %eax,%eax
  je     L14
L6:
  add    $0x8,%rsp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int soru_7(const char s[], const char aranan[]) {
  int x = strstr(s, aranan);
  if (x == 0)
    return -1;
  else
    return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<soru_7>:
  endbr64
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %eax,%eax
  je     L2
L18:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int soru_7(const char s[], const char aranan[]) {
  int x = strstr(s, aranan);
  if (x == 0)
    return -1;
  else
    return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<soru_7>:
  endbr64
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %eax,%eax
  je     L3
L16:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int soru_7(const char s[], const char aranan[]) {
  int x = strstr(s, aranan);
  if (x == 0)
    return -1;
  else
    return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L47
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L47
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L35
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L35:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
L47:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L48
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L30
L48:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L30:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int copy_int(const char *a, char *buffer, int bufLen) {
  int len = 0;
  while (*a != 0) {
    if (*a < '0' || *a > '9')
      break;
    if (len < bufLen - 1)
      buffer[len] = *a;
    ++len;
    ++a;
  }
  if (len >= bufLen)
    buffer[bufLen - 1] = 0;
  else
    buffer[len] = 0;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_int>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L34
  mov    $0x0,%eax
  lea    -0x1(%rdx),%r11d
  jmp    L62
L59:
  lea    0x1(%r10),%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L60
L62:
  mov    %eax,%r10d
  mov    %eax,%r8d
  lea    -0x30(%rcx),%r9d
  cmp    $0x9,%r9b
  ja     L60
  cmp    %eax,%r11d
  jle    L59
  mov    %cl,(%rsi,%rax,1)
  jmp    L59
L34:
  mov    $0x0,%r8d
L60:
  cmp    %r8d,%edx
  jg     L41
  movslq %edx,%rdx
  movb   $0x0,-0x1(%rsi,%rdx,1)
L64:
  mov    %r8d,%eax
  ret
L41:
  movslq %r8d,%rax
  movb   $0x0,(%rsi,%rax,1)
  jmp    L64
```

assistant: ```c
int copy_int(const char *a, char *buffer, int bufLen) {
  int len = 0;
  while (*a != 0) {
    if (*a < '0' || *a > '9')
      break;
    if (len < bufLen - 1)
      buffer[len] = *a;
    ++len;
    ++a;
  }
  if (len >= bufLen)
    buffer[bufLen - 1] = 0;
  else
    buffer[len] = 0;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_int>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L58
  xor    %eax,%eax
  lea    -0x1(%rdx),%r11d
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L60:
  cmp    %eax,%r11d
  jle    L45
  mov    %cl,(%rsi,%rax,1)
L45:
  add    $0x1,%rax
  lea    0x1(%r10),%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L40
L25:
  lea    -0x30(%rcx),%r9d
  mov    %eax,%r10d
  mov    %eax,%r8d
  cmp    $0x9,%r9b
  jbe    L60
L40:
  cmp    %r8d,%edx
  jg     L20
  movslq %edx,%rdx
  mov    %r8d,%eax
  movb   $0x0,-0x1(%rsi,%rdx,1)
  ret
  nopl   0x0(%rax)
L20:
  movslq %r8d,%rax
  movb   $0x0,(%rsi,%rax,1)
  mov    %r8d,%eax
  ret
L58:
  xor    %r8d,%r8d
  jmp    L40
```

assistant: ```c
int copy_int(const char *a, char *buffer, int bufLen) {
  int len = 0;
  while (*a != 0) {
    if (*a < '0' || *a > '9')
      break;
    if (len < bufLen - 1)
      buffer[len] = *a;
    ++len;
    ++a;
  }
  if (len >= bufLen)
    buffer[bufLen - 1] = 0;
  else
    buffer[len] = 0;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_int>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L3
  xor    %eax,%eax
  lea    -0x1(%rdx),%r10d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L47:
  cmp    %eax,%r10d
  jle    L66
  mov    %cl,(%rsi,%rax,1)
L66:
  add    $0x1,%rax
  add    $0x1,%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L11
L5:
  lea    -0x30(%rcx),%r9d
  mov    %eax,%r8d
  cmp    $0x9,%r9b
  jbe    L47
L11:
  cmp    %r8d,%edx
  jg     L60
  movslq %edx,%rdx
  mov    %r8d,%eax
  movb   $0x0,-0x1(%rsi,%rdx,1)
  ret
  xchg   %ax,%ax
L60:
  movslq %r8d,%rax
  movb   $0x0,(%rsi,%rax,1)
  mov    %r8d,%eax
  ret
L3:
  xor    %r8d,%r8d
  jmp    L11
```

assistant: ```c
int copy_int(const char *a, char *buffer, int bufLen) {
  int len = 0;
  while (*a != 0) {
    if (*a < '0' || *a > '9')
      break;
    if (len < bufLen - 1)
      buffer[len] = *a;
    ++len;
    ++a;
  }
  if (len >= bufLen)
    buffer[bufLen - 1] = 0;
  else
    buffer[len] = 0;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoull@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
L6:
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L4
L27:
  mov    -0x10(%rbp),%rax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
unsigned long long getnum(char *str, char **err) {
  char *e;
  unsigned long long rv = strtoull(str, &e, 10);
  if (e == str || *e) {
    *err = str;
    return 0;
  }
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtoull@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L19
  cmpb   $0x0,(%rdx)
  jne    L19
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %rbx,0x0(%rbp)
  mov    $0x0,%eax
  jmp    L4
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long getnum(char *str, char **err) {
  char *e;
  unsigned long long rv = strtoull(str, &e, 10);
  if (e == str || *e) {
    *err = str;
    return 0;
  }
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getnum>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoull@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L11
  cmpb   $0x0,(%rdx)
  jne    L11
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,0x0(%rbp)
  xor    %eax,%eax
  jmp    L34
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long getnum(char *str, char **err) {
  char *e;
  unsigned long long rv = strtoull(str, &e, 10);
  if (e == str || *e) {
    *err = str;
    return 0;
  }
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getnum>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoull@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L5
  cmpb   $0x0,(%rdx)
  jne    L5
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbx,0x0(%rbp)
  xor    %eax,%eax
  jmp    L29
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long getnum(char *str, char **err) {
  char *e;
  unsigned long long rv = strtoull(str, &e, 10);
  if (e == str || *e) {
    *err = str;
    return 0;
  }
  return rv;
}
```