ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmd_watch_rssi>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1001,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edi
  call   <watchoids@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmd_watch_rssi(int argc, char **argv) {
  int oid = 0x1001;
  return watchoids(1, &oid);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmd_watch_rssi>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x1001,0x4(%rsp)
  call   <watchoids@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmd_watch_rssi(int argc, char **argv) {
  int oid = 0x1001;
  return watchoids(1, &oid);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_watch_rssi>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x1001,0x4(%rsp)
  call   <watchoids@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmd_watch_rssi(int argc, char **argv) {
  int oid = 0x1001;
  return watchoids(1, &oid);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  mov    %r8,(%rsp)
  test   %rdi,%rdi
  je     L75
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rcx,%r13
  mov    %r8,%r15
  test   %rsi,%rsi
  je     L75
  test   %edx,%edx
  setle  %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L67
  test   %r8,%r8
  je     L67
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L15
L7:
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  jmp    L109
L15:
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x0,%r14d
  jmp    L98
L100:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    %eax,%r15d
  lea    0x1(%rbx,%r15,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%r15
  sub    %r12,%r15
  mov    %r15d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r15,1)
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  add    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0xc(%rsp),%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r14,%r12
L109:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L100
L98:
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    $0x0,%r14d
  jmp    L98
L67:
  mov    $0x0,%r14d
  jmp    L98
```

assistant: ```c
char *str_replace(const char *src, char *buf, int len, const char *oldstr, const char *newstr) {
  char *needle;
  char *tmp;
  const char *replaced;
  if (src == NULL || buf == NULL || len <= 0 || oldstr == NULL || newstr == NULL) {
    return NULL;
  }
  if (strlen(oldstr) == strlen(newstr) && strcmp(oldstr, newstr) == 0) {
    return NULL;
  }
  strncpy(buf, src, len);
  replaced = src;
  while ((needle = strstr(replaced, oldstr))) {
    tmp = (char *)malloc(strlen(replaced) + (strlen(newstr) - strlen(oldstr)) + 1);
    strncpy(tmp, replaced, needle - replaced);
    tmp[needle - replaced] = '\0';
    strcat(tmp, newstr);
    strcat(tmp, needle + strlen(oldstr));
    strncpy(buf, tmp, len);
    replaced = buf;
    free(tmp);
  }
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L8
  mov    0xc(%rsp),%eax
  mov    %rcx,%r12
  test   %eax,%eax
  setle  %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L8
  mov    %r8,%r14
  test   %r8,%r8
  je     L8
  mov    %rdi,%r15
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L64
L81:
  mov    0xc(%rsp),%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    (%rsp),%edx
  sub    %eax,%ebp
  lea    0x1(%rdx,%rbp,1),%edi
  call   <malloc@plt>
  mov    %rbx,%rcx
  mov    %r15,%rsi
  sub    %r15,%rcx
  mov    %rax,%rdi
  mov    %rax,%rbp
  mov    %r13,%r15
  mov    %ecx,%edx
  mov    %rcx,(%rsp)
  call   <strncpy@plt>
  mov    (%rsp),%rcx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x0(%rbp,%rcx,1)
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rsi
  add    %rbx,%rsi
  call   <strcat@plt>
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L10:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L36
L58:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L81
  nopl   0x0(%rax)
L8:
  xor    %r13d,%r13d
  jmp    L58
```

assistant: ```c
char *str_replace(const char *src, char *buf, int len, const char *oldstr, const char *newstr) {
  char *needle;
  char *tmp;
  const char *replaced;
  if (src == NULL || buf == NULL || len <= 0 || oldstr == NULL || newstr == NULL) {
    return NULL;
  }
  if (strlen(oldstr) == strlen(newstr) && strcmp(oldstr, newstr) == 0) {
    return NULL;
  }
  strncpy(buf, src, len);
  replaced = src;
  while ((needle = strstr(replaced, oldstr))) {
    tmp = (char *)malloc(strlen(replaced) + (strlen(newstr) - strlen(oldstr)) + 1);
    strncpy(tmp, replaced, needle - replaced);
    tmp[needle - replaced] = '\0';
    strcat(tmp, newstr);
    strcat(tmp, needle + strlen(oldstr));
    strncpy(buf, tmp, len);
    replaced = buf;
    free(tmp);
  }
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  test   %rdi,%rdi
  je     L39
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L39
  mov    0xc(%rsp),%eax
  mov    %rcx,%r12
  test   %eax,%eax
  setle  %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L39
  mov    %r8,%r14
  test   %r8,%r8
  je     L39
  mov    %rdi,%r15
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L36
L41:
  mov    0xc(%rsp),%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    (%rsp),%edx
  sub    %eax,%ebp
  lea    0x1(%rdx,%rbp,1),%edi
  call   <malloc@plt>
  mov    %rbx,%rcx
  mov    %r15,%rsi
  sub    %r15,%rcx
  mov    %rax,%rdi
  mov    %rax,%rbp
  mov    %r13,%r15
  mov    %ecx,%edx
  mov    %rcx,(%rsp)
  call   <strncpy@plt>
  mov    (%rsp),%rcx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x0(%rbp,%rcx,1)
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rsi
  add    %rbx,%rsi
  call   <strcat@plt>
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L70:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L0
L84:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L41
  nopl   0x0(%rax)
L39:
  xor    %r13d,%r13d
  jmp    L84
```

assistant: ```c
char *str_replace(const char *src, char *buf, int len, const char *oldstr, const char *newstr) {
  char *needle;
  char *tmp;
  const char *replaced;
  if (src == NULL || buf == NULL || len <= 0 || oldstr == NULL || newstr == NULL) {
    return NULL;
  }
  if (strlen(oldstr) == strlen(newstr) && strcmp(oldstr, newstr) == 0) {
    return NULL;
  }
  strncpy(buf, src, len);
  replaced = src;
  while ((needle = strstr(replaced, oldstr))) {
    tmp = (char *)malloc(strlen(replaced) + (strlen(newstr) - strlen(oldstr)) + 1);
    strncpy(tmp, replaced, needle - replaced);
    tmp[needle - replaced] = '\0';
    strcat(tmp, newstr);
    strcat(tmp, needle + strlen(oldstr));
    strncpy(buf, tmp, len);
    replaced = buf;
    free(tmp);
  }
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nstrread_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x0,%ecx
  mov    $0x4,%edx
  call   <jelio_read@plt>
  mov    $0xffffffffffffffff,%r12
  cmp    $0x4,%rax
  jne    L146
  cmpb   $0x3a,0x3(%rsp)
  jne    L14
  movb   $0x0,0x3(%rsp)
L6:
  movzbl (%rsp),%eax
  test   %al,%al
  je     L37
  mov    $0x0,%r12d
  mov    %rsp,%rdx
L21:
  lea    (%r12,%r12,4),%rcx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rcx,2),%r12
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L21
L82:
  lea    0x2(%r12),%rdi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L47
  lea    0x1(%r12),%r13
  mov    $0x0,%ecx
  mov    %r13,%rdx
  mov    %ebx,%edi
  call   <jelio_read@plt>
  cmp    %rax,%r13
  jne    L8
  mov    0x0(%rbp),%rdi
  lea    (%rdi,%r12,1),%rax
  cmpb   $0x2c,(%rax)
  jne    L148
  movb   $0x0,(%rax)
L146:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L100
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  lea    0x4(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %ebx,%edi
  call   <jelio_read@plt>
  cmp    $0x4,%rax
  jne    L146
  cmpb   $0x3a,0x7(%rsp)
  jne    L146
  movb   $0x0,0x7(%rsp)
  jmp    L6
L37:
  mov    $0x0,%r12d
  jmp    L82
L8:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  mov    $0xffffffffffffffff,%r12
  jmp    L146
L148:
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  mov    $0xffffffffffffffff,%r12
  jmp    L146
L47:
  mov    $0xffffffffffffffff,%r12
  jmp    L146
L100:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t nstrread_dup(int fd, char **s) {
  char buf[8], *p;
  size_t len = 0;
  if (jelio_read(fd, buf, 4, NULL) != 4)
    return -1;
  if (buf[3] != ':') {
    if (jelio_read(fd, buf + 4, 4, NULL) != 4)
      return -1;
    if (buf[7] != ':')
      return -1;
    buf[7] = 0;
  } else
    buf[3] = 0;
  for (p = buf; *p; p++) {
    len *= 10;
    len += *p - '0';
  }
  *s = malloc(len + 2);
  if (!*s)
    return -1;
  if (jelio_read(fd, *s, len + 1, NULL) != len + 1) {
    free(*s);
    *s = NULL;
    return -1;
  }
  if (*(*s + len) != ',') {
    free(*s);
    *s = NULL;
    return -1;
  }
  *(*s + len) = 0;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nstrread_dup>:
  endbr64
  push   %r13
  xor    %ecx,%ecx
  mov    $0x4,%edx
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <jelio_read@plt>
  cmp    $0x4,%rax
  jne    L122
  cmpb   $0x3a,0x3(%rsp)
  jne    L8
  movb   $0x0,0x3(%rsp)
L72:
  movsbl (%rsp),%eax
  test   %al,%al
  je     L74
  xor    %r12d,%r12d
  mov    %rbp,%rdx
  nopw   0x0(%rax,%rax,1)
L42:
  sub    $0x30,%eax
  lea    (%r12,%r12,4),%rcx
  add    $0x1,%rdx
  cltq
  lea    (%rax,%rcx,2),%r12
  movsbl (%rdx),%eax
  test   %al,%al
  jne    L42
  lea    0x2(%r12),%rdi
L84:
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rsi
  test   %rax,%rax
  je     L122
  lea    0x1(%r12),%rbp
  mov    %r13d,%edi
  xor    %ecx,%ecx
  mov    %rbp,%rdx
  call   <jelio_read@plt>
  mov    (%rbx),%rdi
  cmp    %rax,%rbp
  jne    L124
  lea    (%rdi,%r12,1),%rax
  cmpb   $0x2c,(%rax)
  jne    L124
  movb   $0x0,(%rax)
  jmp    L36
  nopl   (%rax)
L124:
  call   <free@plt>
  movq   $0x0,(%rbx)
L122:
  mov    $0xffffffffffffffff,%r12
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  xor    %ecx,%ecx
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %r13d,%edi
  call   <jelio_read@plt>
  cmp    $0x4,%rax
  jne    L122
  cmpb   $0x3a,0x7(%rsp)
  jne    L122
  movb   $0x0,0x7(%rsp)
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L74:
  mov    $0x2,%edi
  xor    %r12d,%r12d
  jmp    L84
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t nstrread_dup(int fd, char **s) {
  char buf[8], *p;
  size_t len = 0;
  if (jelio_read(fd, buf, 4, NULL) != 4)
    return -1;
  if (buf[3] != ':') {
    if (jelio_read(fd, buf + 4, 4, NULL) != 4)
      return -1;
    if (buf[7] != ':')
      return -1;
    buf[7] = 0;
  } else
    buf[3] = 0;
  for (p = buf; *p; p++) {
    len *= 10;
    len += *p - '0';
  }
  *s = malloc(len + 2);
  if (!*s)
    return -1;
  if (jelio_read(fd, *s, len + 1, NULL) != len + 1) {
    free(*s);
    *s = NULL;
    return -1;
  }
  if (*(*s + len) != ',') {
    free(*s);
    *s = NULL;
    return -1;
  }
  *(*s + len) = 0;
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nstrread_dup>:
  endbr64
  push   %r13
  xor    %ecx,%ecx
  mov    $0x4,%edx
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <jelio_read@plt>
  cmp    $0x4,%rax
  jne    L52
  cmpb   $0x3a,0x3(%rsp)
  jne    L30
  movb   $0x0,0x3(%rsp)
L22:
  movsbl (%rsp),%eax
  test   %al,%al
  je     L41
  xor    %r12d,%r12d
  mov    %rbp,%rdx
  nopw   0x0(%rax,%rax,1)
L33:
  sub    $0x30,%eax
  lea    (%r12,%r12,4),%rcx
  add    $0x1,%rdx
  cltq
  lea    (%rax,%rcx,2),%r12
  movsbl (%rdx),%eax
  test   %al,%al
  jne    L33
  lea    0x2(%r12),%rdi
L13:
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rsi
  test   %rax,%rax
  je     L52
  lea    0x1(%r12),%rbp
  mov    %r13d,%edi
  xor    %ecx,%ecx
  mov    %rbp,%rdx
  call   <jelio_read@plt>
  mov    (%rbx),%rdi
  cmp    %rax,%rbp
  jne    L49
  lea    (%rdi,%r12,1),%rax
  cmpb   $0x2c,(%rax)
  jne    L49
  movb   $0x0,(%rax)
  jmp    L126
  nopl   (%rax)
L49:
  call   <free@plt>
  movq   $0x0,(%rbx)
L52:
  mov    $0xffffffffffffffff,%r12
L126:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  xor    %ecx,%ecx
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %r13d,%edi
  call   <jelio_read@plt>
  cmp    $0x4,%rax
  jne    L52
  cmpb   $0x3a,0x7(%rsp)
  jne    L52
  movb   $0x0,0x7(%rsp)
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L41:
  mov    $0x2,%edi
  xor    %r12d,%r12d
  jmp    L13
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t nstrread_dup(int fd, char **s) {
  char buf[8], *p;
  size_t len = 0;
  if (jelio_read(fd, buf, 4, NULL) != 4)
    return -1;
  if (buf[3] != ':') {
    if (jelio_read(fd, buf + 4, 4, NULL) != 4)
      return -1;
    if (buf[7] != ':')
      return -1;
    buf[7] = 0;
  } else
    buf[3] = 0;
  for (p = buf; *p; p++) {
    len *= 10;
    len += *p - '0';
  }
  *s = malloc(len + 2);
  if (!*s)
    return -1;
  if (jelio_read(fd, *s, len + 1, NULL) != len + 1) {
    free(*s);
    *s = NULL;
    return -1;
  }
  if (*(*s + len) != ',') {
    free(*s);
    *s = NULL;
    return -1;
  }
  *(*s + len) = 0;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msgarg_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  jg     L20
  mov    $0x0,%eax
  jmp    L67
L20:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x22,(%rax)
  addl   $0x1,-0xc(%rbp)
  jmp    L57
L55:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L26
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L10
L26:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x5c,(%rax)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L57:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L69
  mov    -0x1c(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L55
L69:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x22,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
L67:
  pop    %rbp
  ret
```

assistant: ```c
int msgarg_escape(char *buf, int bufsize, const char *in) {
  char *out = buf;
  int len = 0;
  if (bufsize < 3) {
    return 0;
  }
  *out++ = '"';
  len++;
  while (*in && len < bufsize - 3) {
    if (*in == '"' || *in == '\\') {
      *out++ = '\\';
      len++;
    }
    *out++ = *in++;
    len++;
  }
  *out++ = '"';
  *out = '\0';
  len++;
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<msgarg_escape>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x2,%esi
  jle    L43
  lea    0x1(%rdi),%r8
  movb   $0x22,(%rdi)
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L15
  sub    $0x3,%esi
  cmp    $0x1,%esi
  jle    L92
  mov    $0x1,%eax
  jmp    L29
L47:
  lea    0x1(%r8),%rdi
  movb   $0x5c,(%r8)
  add    $0x1,%eax
L13:
  add    $0x1,%rdx
  lea    0x1(%rdi),%r8
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rdi)
  add    $0x1,%eax
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L90
  cmp    %esi,%eax
  jge    L90
L29:
  cmp    $0x22,%cl
  je     L47
  mov    %r8,%rdi
  cmp    $0x5c,%cl
  jne    L13
  jmp    L47
L15:
  mov    $0x1,%eax
L90:
  movb   $0x22,(%r8)
  movb   $0x0,0x1(%r8)
  add    $0x1,%eax
L43:
  ret
L92:
  mov    $0x1,%eax
  jmp    L90
```

assistant: ```c
int msgarg_escape(char *buf, int bufsize, const char *in) {
  char *out = buf;
  int len = 0;
  if (bufsize < 3) {
    return 0;
  }
  *out++ = '"';
  len++;
  while (*in && len < bufsize - 3) {
    if (*in == '"' || *in == '\\') {
      *out++ = '\\';
      len++;
    }
    *out++ = *in++;
    len++;
  }
  *out++ = '"';
  *out = '\0';
  len++;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<msgarg_escape>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%esi
  jle    L66
  movb   $0x22,(%rdi)
  movzbl (%rdx),%ecx
  lea    0x1(%rdi),%r9
  test   %cl,%cl
  je     L3
  sub    $0x3,%esi
  cmp    $0x1,%esi
  jle    L3
  mov    $0x1,%edi
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L63:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  lea    0x1(%r8),%r9
  lea    0x1(%rax),%edi
  mov    %cl,(%r8)
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L15
  cmp    %esi,%edi
  jge    L15
L31:
  cmp    $0x22,%cl
  je     L49
  mov    %edi,%eax
  mov    %r9,%r8
  cmp    $0x5c,%cl
  jne    L63
L49:
  movb   $0x5c,(%r9)
  lea    0x1(%r9),%r8
  lea    0x1(%rdi),%eax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x2,%eax
L95:
  mov    $0x22,%edx
  mov    %dx,(%r9)
L66:
  ret
  nopl   (%rax)
L3:
  mov    $0x2,%eax
  jmp    L95
```

assistant: ```c
int msgarg_escape(char *buf, int bufsize, const char *in) {
  char *out = buf;
  int len = 0;
  if (bufsize < 3) {
    return 0;
  }
  *out++ = '"';
  len++;
  while (*in && len < bufsize - 3) {
    if (*in == '"' || *in == '\\') {
      *out++ = '\\';
      len++;
    }
    *out++ = *in++;
    len++;
  }
  *out++ = '"';
  *out = '\0';
  len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msgarg_escape>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%esi
  jle    L55
  movb   $0x22,(%rdi)
  movzbl (%rdx),%ecx
  lea    0x1(%rdi),%r9
  test   %cl,%cl
  je     L71
  sub    $0x3,%esi
  cmp    $0x1,%esi
  jle    L71
  mov    $0x1,%edi
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%rdx
  mov    %cl,(%r8)
  lea    0x1(%r8),%r9
  lea    0x1(%rax),%edi
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L39
  cmp    %esi,%edi
  jge    L39
L74:
  cmp    $0x22,%cl
  je     L42
  mov    %edi,%eax
  mov    %r9,%r8
  cmp    $0x5c,%cl
  jne    L54
L42:
  movb   $0x5c,(%r9)
  lea    0x1(%r9),%r8
  movzbl (%rdx),%ecx
  lea    0x1(%rdi),%eax
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x2,%eax
L9:
  mov    $0x22,%edx
  mov    %dx,(%r9)
L55:
  ret
  nopl   (%rax)
L71:
  mov    $0x2,%eax
  jmp    L9
```

assistant: ```c
int msgarg_escape(char *buf, int bufsize, const char *in) {
  char *out = buf;
  int len = 0;
  if (bufsize < 3) {
    return 0;
  }
  *out++ = '"';
  len++;
  while (*in && len < bufsize - 3) {
    if (*in == '"' || *in == '\\') {
      *out++ = '\\';
      len++;
    }
    *out++ = *in++;
    len++;
  }
  *out++ = '"';
  *out = '\0';
  len++;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x6,-0x8(%rbp)
  jmp    L31
L37:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x100000,%esi
  mov    %rax,%rdi
  call   <check@plt>
  test   %rax,%rax
  je     L16
  mov    $0xffffffff,%eax
  jmp    L39
L16:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  shlq   -0x8(%rbp)
L31:
  cmpq   $0x7ff,-0x8(%rbp)
  jbe    L37
  mov    $0x100000,%esi
  mov    $0x400,%edi
  call   <demo@plt>
  mov    $0x100000,%esi
  mov    $0x100000,%edi
  call   <demo@plt>
  mov    $0x100000,%esi
  mov    $0x2000000,%edi
  call   <demo@plt>
  mov    $0x0,%eax
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D18
type_guessed: string

tool: D17: checking input size = %zu 
 

tool: D18: Ok!
 

assistant: ```c
int main() {
  size_t x;
  for (x = 6; x < 2048; x *= 2) {
    printf("checking input size = %zu \n ", x);
    if (check(x, 1024 * 1024))
      return -1;
    printf("Ok!\n ");
  }
  demo(1024, 1024 * 1024);
  demo(1024 * 1024, 1024 * 1024);
  demo(32 * 1024 * 1024, 1024 * 1024);
  return 0;
}
```