ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hfdprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <hvsprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L9
  nopl   0x0(%rax)
L11:
  sub    %eax,%ebx
  test   %ebx,%ebx
  jle    L15
L9:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xwrite@plt>
  test   %eax,%eax
  jns    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdi
  call   <xfree@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hfdprintf(int fd, const char *format, ...) {
  char *str, *p;
  va_list ap;
  int n, rc;
  va_start(ap, format);
  str = hvsprintf(format, ap);
  va_end(ap);
  p = str;
  n = strlen(p);
  rc = 0;
  do {
    rc = xwrite(fd, str, n);
    if (rc < 0)
      return rc;
    n -= rc;
    p += rc;
  } while (n > 0);
  xfree(str);
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <EulerTotient_ProductForm@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D6
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string

tool: D28: Enter the number: 

tool: D6: %lld

tool: D13: Euler totient function value is: %lld

assistant: ```c
int main() {
  long long num;
  printf("Enter the number: \n");
  scanf("%lld", &num);
  printf("Euler totient function value is: %lld", EulerTotient_ProductForm(num));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <EulerTotient_ProductForm@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D5: Enter the number: 

tool: D8: %lld

tool: D16: Euler totient function value is: %lld

assistant: ```c
int main() {
  long long num;
  printf("Enter the number: \n");
  scanf("%lld", &num);
  printf("Euler totient function value is: %lld", EulerTotient_ProductForm(num));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <EulerTotient_ProductForm@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D1: Enter the number: 

tool: D3: %lld

tool: D2: Euler totient function value is: %lld

assistant: ```c
int main() {
  long long num;
  printf("Enter the number: \n");
  scanf("%lld", &num);
  printf("Euler totient function value is: %lld", EulerTotient_ProductForm(num));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <EulerTotient_ProductForm@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D26
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string

tool: D26: Enter the number: 

tool: D6: %lld

tool: D24: Euler totient function value is: %lld

assistant: ```c
int main() {
  long long num;
  printf("Enter the number: \n");
  scanf("%lld", &num);
  printf("Euler totient function value is: %lld", EulerTotient_ProductForm(num));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_ucpname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  lea    D8(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: ??

assistant: ```c
const char *get_ucpname(int ptype, int pvalue) {
  ptype = ptype * pvalue;
  return (ptype == pvalue) ? "??" : "??";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ucpname>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: ??

assistant: ```c
const char *get_ucpname(int ptype, int pvalue) {
  ptype = ptype * pvalue;
  return (ptype == pvalue) ? "??" : "??";
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_ucpname>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: ??

assistant: ```c
const char *get_ucpname(int ptype, int pvalue) {
  ptype = ptype * pvalue;
  return (ptype == pvalue) ? "??" : "??";
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_ucpname>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: ??

assistant: ```c
const char *get_ucpname(int ptype, int pvalue) {
  ptype = ptype * pvalue;
  return (ptype == pvalue) ? "??" : "??";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getCachePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getCacheApp@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <createPathIfNotExists@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void getCachePath(char **path, char *app_name) {
  getCacheApp(path, app_name);
  if (*path) {
    createPathIfNotExists(path);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getCachePath>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <getCacheApp@plt>
  cmpq   $0x0,(%rbx)
  je     L3
  mov    %rbx,%rdi
  call   <createPathIfNotExists@plt>
L3:
  pop    %rbx
  ret
```

assistant: ```c
void getCachePath(char **path, char *app_name) {
  getCacheApp(path, app_name);
  if (*path) {
    createPathIfNotExists(path);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCachePath>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <getCacheApp@plt>
  cmpq   $0x0,0x0(%rbp)
  je     L7
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <createPathIfNotExists@plt>
  nopl   (%rax)
L7:
  pop    %rbp
  ret
```

assistant: ```c
void getCachePath(char **path, char *app_name) {
  getCacheApp(path, app_name);
  if (*path) {
    createPathIfNotExists(path);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getCachePath>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <getCacheApp@plt>
  cmpq   $0x0,0x0(%rbp)
  je     L7
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <createPathIfNotExists@plt>
  nopl   (%rax)
L7:
  pop    %rbp
  ret
```

assistant: ```c
void getCachePath(char **path, char *app_name) {
  getCacheApp(path, app_name);
  if (*path) {
    createPathIfNotExists(path);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_get_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L5:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L31
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L5
L31:
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _get_num(const char *s, const char **end) {
  int n;
  n = 0;
  while (*s != '\0' && (*s >= '0' && *s <= '9')) {
    n = n * 10 + (*s - '0');
    s++;
  }
  *end = s;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_get_num>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L13
  mov    $0x0,%edx
L25:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L25
L19:
  mov    %rdi,(%rsi)
  mov    %edx,%eax
  ret
L13:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int _get_num(const char *s, const char **end) {
  int n;
  n = 0;
  while (*s != '\0' && (*s >= '0' && *s <= '9')) {
    n = n * 10 + (*s - '0');
    s++;
  }
  *end = s;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_get_num>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L17
  nopw   0x0(%rax,%rax,1)
L0:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L0
L17:
  mov    %rdi,(%rsi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _get_num(const char *s, const char **end) {
  int n;
  n = 0;
  while (*s != '\0' && (*s >= '0' && *s <= '9')) {
    n = n * 10 + (*s - '0');
    s++;
  }
  *end = s;
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_get_num>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L10
  nopw   0x0(%rax,%rax,1)
L19:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L19
L10:
  mov    %rdi,(%rsi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _get_num(const char *s, const char **end) {
  int n;
  n = 0;
  while (*s != '\0' && (*s >= '0' && *s <= '9')) {
    n = n * 10 + (*s - '0');
    s++;
  }
  *end = s;
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x418(%rbp)
  jmp    L19
L21:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x41c(%rbp)
  mov    -0x41c(%rbp),%edx
  lea    -0x410(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sort_puple@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: %s


assistant: ```c
int main() {
  char in[1024];
  char *p = in;
  while (gets(in) != NULL) {
    int len = strlen(in);
    sort_puple(in, len);
    printf("%s\n", in);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rbp
  jmp    L9
L8:
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <sort_puple@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L9:
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L8
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: %s


assistant: ```c
int main() {
  char in[1024];
  char *p = in;
  while (gets(in) != NULL) {
    int len = strlen(in);
    sort_puple(in, len);
    printf("%s\n", in);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L22
  nopl   0x0(%rax)
L26:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <sort_puple@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L22:
  mov    %rbx,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L26
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: %s


assistant: ```c
int main() {
  char in[1024];
  char *p = in;
  while (gets(in) != NULL) {
    int len = strlen(in);
    sort_puple(in, len);
    printf("%s\n", in);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L1
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <sort_puple@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L1:
  mov    %rbx,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L28
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: %s


assistant: ```c
int main() {
  char in[1024];
  char *p = in;
  while (gets(in) != NULL) {
    int len = strlen(in);
    sort_puple(in, len);
    printf("%s\n", in);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <contas@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D30
type: string
name: unpack_data
arguments: data_tag: D34
type: string
name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D30: 
 Entre com o numero para os calculos: 

tool: D34: %d

tool: D16: 
 Valor da raiz         : %d

tool: D8: 
 Valor da exponenciacao: %d


assistant: ```c
int main() {
  int Raiz = 0, A = 0, Num = 0, *Exp = NULL;
  Exp = &A;
  printf("\n Entre com o numero para os calculos: ");
  scanf("%d", &Num);
  contas(&Raiz, Exp, Num);
  printf("\n Valor da raiz         : %d", Raiz);
  printf("\n Valor da exponenciacao: %d\n", *Exp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    0x14(%rsp),%edx
  call   <contas@plt>
  mov    0xc(%rsp),%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D24
type_infered: string
name: retrieve_data
arguments: tag: D25
type_infered: string

tool: D11: 
 Entre com o numero para os calculos: 

tool: D8: %d

tool: D24: 
 Valor da raiz         : %d

tool: D25: 
 Valor da exponenciacao: %d


assistant: ```c
int main() {
  int Raiz = 0, A = 0, Num = 0, *Exp = NULL;
  Exp = &A;
  printf("\n Entre com o numero para os calculos: ");
  scanf("%d", &Num);
  contas(&Raiz, Exp, Num);
  printf("\n Valor da raiz         : %d", Raiz);
  printf("\n Valor da exponenciacao: %d\n", *Exp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <contas@plt>
  mov    0xc(%rsp),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_infered: string
name: retrieve_data
arguments: tag: D34
type_infered: string
name: retrieve_data
arguments: tag: D32
type_infered: string
name: retrieve_data
arguments: tag: D39
type_infered: string

tool: D23: 
 Entre com o numero para os calculos: 

tool: D34: %d

tool: D32: 
 Valor da raiz         : %d

tool: D39: 
 Valor da exponenciacao: %d


assistant: ```c
int main() {
  int Raiz = 0, A = 0, Num = 0, *Exp = NULL;
  Exp = &A;
  printf("\n Entre com o numero para os calculos: ");
  scanf("%d", &Num);
  contas(&Raiz, Exp, Num);
  printf("\n Valor da raiz         : %d", Raiz);
  printf("\n Valor da exponenciacao: %d\n", *Exp);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <contas@plt>
  mov    0xc(%rsp),%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D28
datatype: string
name: extract_symbolic_data
arguments: data_tag: D34
datatype: string

tool: D25: 
 Entre com o numero para os calculos: 

tool: D6: %d

tool: D28: 
 Valor da raiz         : %d

tool: D34: 
 Valor da exponenciacao: %d


assistant: ```c
int main() {
  int Raiz = 0, A = 0, Num = 0, *Exp = NULL;
  Exp = &A;
  printf("\n Entre com o numero para os calculos: ");
  scanf("%d", &Num);
  contas(&Raiz, Exp, Num);
  printf("\n Valor da raiz         : %d", Raiz);
  printf("\n Valor da exponenciacao: %d\n", *Exp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__intlog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L12:
  addl   $0x1,-0x4(%rbp)
  sarl   -0x14(%rbp)
L10:
  cmpl   $0x1,-0x14(%rbp)
  jg     L12
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __intlog2(int a) {
  int i;
  for (i = 1; a > 1; i++, a = a >> 1)
    ;
  return i - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__intlog2>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  mov    $0x1,%eax
L20:
  add    $0x1,%eax
  sar    %edi
  cmp    $0x1,%edi
  jg     L20
L14:
  sub    $0x1,%eax
  ret
L4:
  mov    $0x1,%eax
  jmp    L14
```

assistant: ```c
int __intlog2(int a) {
  int i;
  for (i = 1; a > 1; i++, a = a >> 1)
    ;
  return i - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__intlog2>:
  endbr64
  cmp    $0x1,%edi
  jle    L2
  mov    $0x1,%eax
  xchg   %ax,%ax
L17:
  sar    %edi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmp    $0x1,%edi
  jne    L17
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int __intlog2(int a) {
  int i;
  for (i = 1; a > 1; i++, a = a >> 1)
    ;
  return i - 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__intlog2>:
  endbr64
  cmp    $0x1,%edi
  jle    L6
  mov    $0x1,%eax
  xchg   %ax,%ax
L7:
  sar    %edi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmp    $0x1,%edi
  jne    L7
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int __intlog2(int a) {
  int i;
  for (i = 1; a > 1; i++, a = a >> 1)
    ;
  return i - 1;
}
```