user: 请将以下的汇编代码转换成C语言代码:

```asm
<clpf_block>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L48:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L48
  sub    $0x38,%rsp
  mov    %ecx,0x1c(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x4028(%rsp)
  xor    %eax,%eax
  cmp    %r8d,%ecx
  jge    L20
  mov    %rdi,%rbp
  mov    0x1c(%rsp),%edi
  mov    %edx,%ebx
  mov    %esi,%r12d
  mov    %r9d,%r13d
  xor    %r14d,%r14d
  lea    -0x1(%rdi),%eax
  sub    %edi,%r8d
  movslq %esi,%rdi
  mov    %rdi,%rdx
  mov    %rdi,(%rsp)
  imul   %r9d,%eax
  neg    %rdx
  mov    %r8d,0x18(%rsp)
  lea    0x0(,%rdx,4),%rdi
  mov    %rdi,0x8(%rsp)
  lea    0x20(%rsp),%rdi
  mov    %rdi,0x10(%rsp)
L15:
  lea    0x0(%r13,%rax,1),%r15d
  cmp    %ebx,%r12d
  jge    L74
  cltq
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rcx
  lea    0x0(%rbp,%rax,4),%r11
  movslq %r15d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  lea    (%r15,%r13,1),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%r10
  mov    %r14d,%eax
  shl    $0x6,%eax
  cltq
  lea    (%rsi,%rax,4),%r9
  add    0x10(%rsp),%r9
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%rdi,%rcx,4),%edx
  mov    -0x4(%rdi,%rcx,4),%r8d
  add    (%r11,%rcx,4),%r8d
  add    0x4(%rdi,%rcx,4),%r8d
  lea    0x0(,%rdx,4),%eax
  add    (%r10,%rcx,4),%r8d
  sub    %eax,%r8d
  mov    %r8d,%esi
  mov    %r8d,%eax
  sar    $0x1f,%esi
  or     $0x1,%esi
  neg    %eax
  cmovs  %r8d,%eax
  mov    $0x1,%r8d
  add    $0x2,%eax
  sar    $0x2,%eax
  test   %eax,%eax
  cmovg  %r8d,%eax
  imul   %esi,%eax
  add    %edx,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,(%r9,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jg     L31
L74:
  add    $0x1,%r14d
  mov    %r15d,%eax
  cmp    %r14d,0x18(%rsp)
  jne    L15
  mov    0x1c(%rsp),%r15d
  lea    -0x1(%rbx),%eax
  lea    0x20(%rsp),%rdi
  xor    %r14d,%r14d
  sub    %r12d,%eax
  mov    %rdi,0x10(%rsp)
  imul   %r13d,%r15d
  lea    0x4(,%rax,4),%rax
  mov    %ebx,0x8(%rsp)
  mov    %r14d,%ebx
  mov    %rbp,%r14
  mov    %rax,%rbp
  nopl   0x0(%rax)
L17:
  cmp    0x8(%rsp),%r12d
  jge    L33
  movslq %r15d,%rax
  add    (%rsp),%rax
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdx
  lea    (%r14,%rax,4),%rdi
  mov    %ebx,%eax
  shl    $0x6,%eax
  cltq
  lea    (%rsi,%rax,4),%rsi
  call   <memcpy@plt>
L33:
  add    $0x1,%ebx
  add    %r13d,%r15d
  cmp    0x18(%rsp),%ebx
  jne    L17
L20:
  mov    0x4028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x4038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void clpf_block(uint8_t *rec, int x0, int x1, int y0, int y1, int stride) {
  int y, x, A, B, C, D, X, Xprime, delta, sum, sign;
  uint8_t tmp_block[64 * 64];
  for (y = y0; y < y1; y++) {
    for (x = x0; x < x1; x++) {
      A = rec[(y - 1) * stride + x + 0];
      B = rec[(y + 0) * stride + x - 1];
      X = rec[(y + 0) * stride + x + 0];
      C = rec[(y + 0) * stride + x + 1];
      D = rec[(y + 1) * stride + x + 0];
      sum = A + B + C + D - 4 * X;
      sign = sum < 0 ? -1 : 1;
      delta = sign * ((1) < (((abs(sum) + 2) >> 2)) ? (1) : (((abs(sum) + 2) >> 2)));
      Xprime = ((255) < (((0) > ((X + delta)) ? (0) : ((X + delta)))) ? (255) : (((0) > ((X + delta)) ? (0) : ((X + delta)))));
      tmp_block[(y - y0) * 64 + x - x0] = Xprime;
    }
  }
  for (y = y0; y < y1; y++) {
    for (x = x0; x < x1; x++) {
      rec[y * stride + x] = tmp_block[(y - y0) * 64 + x - x0];
    }
  }
}
```