user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xb88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2b78(%rsp)
  xor    %eax,%eax
  lea    0x460(%rsp),%r12
  mov    %r12,%rbx
  lea    D16(%rip),%r13
  jmp    L40
L192:
  add    $0x1,%rbx
L40:
  mov    %rbx,%rbp
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L128
  cmpb   $0x44,(%rbx)
  jne    L192
  cmpb   $0x2d,-0x1(%rbp)
  jne    L192
  cmpb   $0x4e,-0x2(%rbp)
  jne    L192
  cmpb   $0x2d,-0x3(%rbp)
  jne    L192
  cmpb   $0x45,-0x4(%rbp)
  jne    L192
L128:
  lea    0x460(%rsp),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L132
  mov    %eax,%eax
  mov    %rax,(%rsp)
  mov    $0x0,%ebx
  mov    $0x0,%edi
  mov    $0x0,%ecx
  lea    0x1(%r12),%rax
  mov    %rax,0x8(%rsp)
  jmp    L16
L117:
  cmp    %ebx,%ecx
  jge    L105
  movslq %ecx,%rax
  lea    0x460(%rsp,%rax,1),%rbp
  lea    -0x1(%r15),%r14d
  add    0x8(%rsp),%rax
  add    %rax,%r14
  mov    $0x0,%r12d
  jmp    L125
L77:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  movslq %r12d,%rax
  mov    %dl,0x10(%rsp,%rax,1)
  add    $0x1,%r12d
L97:
  add    $0x1,%rbp
  cmp    %r14,%rbp
  je     L185
L125:
  movzbl 0x0(%rbp),%edi
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  jbe    L77
  cmp    $0x2d,%dil
  jne    L97
  jmp    L77
L105:
  mov    $0x0,%r12d
L185:
  movslq %r12d,%r12
  movb   $0x0,0x10(%rsp,%r12,1)
  mov    %r15d,%edi
  mov    %r13d,%ecx
L92:
  add    $0x1,%rbx
  cmp    (%rsp),%rbx
  je     L132
L16:
  mov    %ebx,%r13d
  movzbl 0x460(%rsp,%rbx,1),%edx
  mov    %edx,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  jbe    L92
  cmp    $0x2d,%dl
  je     L92
  mov    %ebx,%r15d
  sub    %ecx,%r15d
  cmp    %edi,%r15d
  jg     L117
  mov    %ebx,%ecx
  jmp    L92
L132:
  lea    0x10(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x2b78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  mov    $0x0,%eax
  add    $0x2b88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D6
type: string

tool: D16: %c

tool: D6: %s


assistant: ```c
int main() {
  int i = 0, j, c = 0, m[110], l, k, len, num = 0;
  char a[10000], b[1100];
  while (scanf("%c", &a[i]) == 1) {
    if (a[i] == 'D' && a[i - 1] == '-' && a[i - 2] == 'N' && a[i - 3] == '-' && a[i - 4] == 'E') {
      i++;
      break;
    } else {
      i++;
      continue;
    }
  }
  len = strlen(a);
  k = 0;
  for (i = 0; i < len; i++) {
    if (a[i] >= 'A' && a[i] <= 'Z' || a[i] >= 'a' && a[i] <= 'z' || a[i] == '-') {
      continue;
    } else {
      m[k] = i - c;
      if (m[k] > num) {
        num = m[k];
        l = 0;
        for (j = c; j < i; j++) {
          if (a[j] >= 'A' && a[j] <= 'Z' || a[j] >= 'a' && a[j] <= 'z' || a[j] == '-') {
            b[l] = tolower(a[j]);
            l++;
          }
        }
        b[l] = '\0';
      }
      c = i;
      k++;
    }
  }
  printf("%s\n", b);
  return 0;
}
```