ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<sqUTF16ToUTF32Iterate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L44
  mov    -0x18(%rbp),%rax
  jmp    L41
L96:
  addq   $0x2,-0x18(%rbp)
  cmpl   $0xd7ff,-0x8(%rbp)
  jbe    L15
  cmpl   $0xdfff,-0x8(%rbp)
  jbe    L1
L15:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L80
L1:
  cmpl   $0xdbff,-0x8(%rbp)
  ja     L44
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L105
  addq   $0x2,-0x18(%rbp)
  cmpl   $0xdbff,-0x4(%rbp)
  jbe    L44
  cmpl   $0xdfff,-0x4(%rbp)
  ja     L44
  mov    -0x8(%rbp),%eax
  sub    $0xd800,%eax
  shl    $0xa,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    $0xdc00,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L44:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L96
  jmp    L80
L105:
  nop
L80:
  mov    -0x18(%rbp),%rax
L41:
  pop    %rbp
  ret
```

assistant: ```c
extern const unsigned short *sqUTF16ToUTF32Iterate(const unsigned short *string, int *dest) {
  unsigned int high;
  unsigned int low;
  *dest = 0;
  if (!*string)
    return string;
  while ((high = *string) != 0) {
    ++string;
    if (high < 0xD800 || 0xE000 <= high) {
      *dest = high;
      break;
    } else if (high < 0xDC00) {
      low = *string;
      if (!low)
        break;
      ++string;
      if (0xDC00 <= low && low < 0xE000) {
        *dest = (high - 0xD800) << 10 | (low - 0xDC00);
      }
    } else {
    }
  }
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqUTF16ToUTF32Iterate>:
  endbr64
  movl   $0x0,(%rsi)
  mov    %rdi,%rdx
  cmpw   $0x0,(%rdi)
  je     L8
L74:
  movzwl (%rdi),%ecx
  movzwl %cx,%eax
  test   %eax,%eax
  je     L69
  lea    0x2(%rdi),%rdx
  lea    -0xd800(%rax),%r8d
  cmp    $0x7ff,%r8d
  ja     L6
  cmp    $0xdbff,%eax
  jbe    L26
  mov    %rdx,%rdi
  jmp    L74
L6:
  movzwl %cx,%ecx
  mov    %ecx,(%rsi)
  jmp    L8
L26:
  movzwl (%rdx),%eax
  test   %eax,%eax
  je     L8
  add    $0x4,%rdi
  sub    $0xdc00,%eax
  cmp    $0x3ff,%eax
  ja     L74
  shl    $0xa,%r8d
  or     %eax,%r8d
  mov    %r8d,(%rsi)
  jmp    L74
L69:
  mov    %rdi,%rdx
L8:
  mov    %rdx,%rax
  ret
```

assistant: ```c
extern const unsigned short *sqUTF16ToUTF32Iterate(const unsigned short *string, int *dest) {
  unsigned int high;
  unsigned int low;
  *dest = 0;
  if (!*string)
    return string;
  while ((high = *string) != 0) {
    ++string;
    if (high < 0xD800 || 0xE000 <= high) {
      *dest = high;
      break;
    } else if (high < 0xDC00) {
      low = *string;
      if (!low)
        break;
      ++string;
      if (0xDC00 <= low && low < 0xE000) {
        *dest = (high - 0xD800) << 10 | (low - 0xDC00);
      }
    } else {
    }
  }
  return string;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sqUTF16ToUTF32Iterate>:
  endbr64
  movzwl (%rdi),%eax
  movl   $0x0,(%rsi)
  mov    %rdi,%r8
  test   %ax,%ax
  jne    L12
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L32:
  lea    -0xd800(%rax),%edx
  lea    0x2(%rdi),%r8
  cmp    $0x7ff,%edx
  ja     L43
  cmp    $0xdbff,%eax
  movzwl (%r8),%eax
  jbe    L46
  mov    %r8,%rdi
L12:
  test   %eax,%eax
  jne    L32
  mov    %rdi,%r8
L13:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %eax,(%rsi)
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  test   %eax,%eax
  je     L13
  sub    $0xdc00,%eax
  lea    0x4(%rdi),%rcx
  cmp    $0x3ff,%eax
  ja     L19
  shl    $0xa,%edx
  or     %eax,%edx
  mov    %edx,(%rsi)
L19:
  movzwl 0x4(%rdi),%eax
  mov    %rcx,%rdi
  jmp    L12
```

assistant: ```c
extern const unsigned short *sqUTF16ToUTF32Iterate(const unsigned short *string, int *dest) {
  unsigned int high;
  unsigned int low;
  *dest = 0;
  if (!*string)
    return string;
  while ((high = *string) != 0) {
    ++string;
    if (high < 0xD800 || 0xE000 <= high) {
      *dest = high;
      break;
    } else if (high < 0xDC00) {
      low = *string;
      if (!low)
        break;
      ++string;
      if (0xDC00 <= low && low < 0xE000) {
        *dest = (high - 0xD800) << 10 | (low - 0xDC00);
      }
    } else {
    }
  }
  return string;
}
```
user: What is the c source code of the assembly code below:

```asm
<sqUTF16ToUTF32Iterate>:
  endbr64
  cmpw   $0x0,(%rdi)
  movl   $0x0,(%rsi)
  mov    %rdi,%r8
  jne    L7
  jmp    L15
  nopl   (%rax)
L66:
  lea    -0xd800(%rax),%edx
  lea    0x2(%rdi),%r8
  cmp    $0x7ff,%edx
  ja     L44
  cmp    $0xdbff,%eax
  jbe    L39
  mov    %r8,%rdi
L7:
  movzwl (%rdi),%eax
  test   %eax,%eax
  jne    L66
  mov    %rdi,%r8
L15:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %eax,(%rsi)
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L39:
  movzwl (%r8),%eax
  test   %eax,%eax
  je     L15
  sub    $0xdc00,%eax
  add    $0x4,%rdi
  cmp    $0x3ff,%eax
  ja     L7
  shl    $0xa,%edx
  or     %eax,%edx
  mov    %edx,(%rsi)
  jmp    L7
```

assistant: ```c
extern const unsigned short *sqUTF16ToUTF32Iterate(const unsigned short *string, int *dest) {
  unsigned int high;
  unsigned int low;
  *dest = 0;
  if (!*string)
    return string;
  while ((high = *string) != 0) {
    ++string;
    if (high < 0xD800 || 0xE000 <= high) {
      *dest = high;
      break;
    } else if (high < 0xDC00) {
      low = *string;
      if (!low)
        break;
      ++string;
      if (0xDC00 <= low && low < 0xE000) {
        *dest = (high - 0xD800) << 10 | (low - 0xDC00);
      }
    } else {
    }
  }
  return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_164_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  notb   -0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_164_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_164_0_1>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%eax
  or     %esi,%eax
  not    %eax
  or     (%rdi),%al
  mov    %eax,%esi
  xor    %edx,%esi
  mov    %r8d,%ecx
  not    %ecx
  mov    %edx,%r9d
  and    (%rdi),%r9b
  and    %r9d,%ecx
  or     %edx,%eax
  not    %eax
  or     %ecx,%eax
  not    %esi
  mov    %esi,%edx
  and    %r8d,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_164_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_164_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%r8d
  movzbl (%rdi),%r9d
  or     %esi,%eax
  mov    %r8d,%ecx
  not    %eax
  or     (%rdi),%al
  and    %edx,%r9d
  not    %ecx
  mov    %eax,%esi
  or     %edx,%eax
  and    %r9d,%ecx
  xor    %edx,%esi
  not    %eax
  not    %esi
  or     %ecx,%eax
  mov    %esi,%edx
  and    %r8d,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_164_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_164_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%r8d
  movzbl (%rdi),%r9d
  or     %esi,%eax
  mov    %r8d,%ecx
  not    %eax
  or     (%rdi),%al
  and    %edx,%r9d
  not    %ecx
  mov    %eax,%esi
  or     %edx,%eax
  and    %r9d,%ecx
  xor    %edx,%esi
  not    %eax
  not    %esi
  or     %ecx,%eax
  mov    %esi,%edx
  and    %r8d,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_164_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__be_u24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t __be_u24(const void *p) {
  const unsigned char *c = (const unsigned char *)p;
  return (((uint32_t)c[0]) << 16U) | (((uint32_t)c[1]) << 8U) | (((uint32_t)c[2]) << 0U);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__be_u24>:
  endbr64
  movzbl (%rdi),%eax
  shl    $0x10,%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rdi),%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t __be_u24(const void *p) {
  const unsigned char *c = (const unsigned char *)p;
  return (((uint32_t)c[0]) << 16U) | (((uint32_t)c[1]) << 8U) | (((uint32_t)c[2]) << 0U);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__be_u24>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x10,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rdi),%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t __be_u24(const void *p) {
  const unsigned char *c = (const unsigned char *)p;
  return (((uint32_t)c[0]) << 16U) | (((uint32_t)c[1]) << 8U) | (((uint32_t)c[2]) << 0U);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__be_u24>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x10,%eax
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rdi),%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t __be_u24(const void *p) {
  const unsigned char *c = (const unsigned char *)p;
  return (((uint32_t)c[0]) << 16U) | (((uint32_t)c[1]) << 8U) | (((uint32_t)c[2]) << 0U);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getCommand>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L33
  cmp    $0x1,%edi
  jle    L133
  lea    -0x2(%rdi),%eax
  mov    %rcx,%r13
  mov    $0x1,%ebx
  shr    %eax
  lea    0x3(%rax,%rax,1),%r15
  jmp    L136
  nopl   0x0(%rax)
L64:
  add    $0x2,%rbx
  cmp    %r15,%rbx
  je     L119
L136:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
L67:
  lea    0x8(%rbp,%rbx,8),%rbx
  mov    (%rbx),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L23
L82:
  mov    (%rbx),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L23:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    0x0(%r13),%rdi
  jmp    L82
L119:
  cmp    $0x2,%r14d
  je     L133
  sub    $0x3,%r14d
  mov    $0x2,%ebx
  shr    %r14d
  add    $0x2,%r14d
  add    %r14,%r14
  jmp    L118
  nopl   0x0(%rax,%rax,1)
L75:
  add    $0x2,%rbx
  cmp    %rbx,%r14
  je     L133
L118:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L75
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    $0x1,%edi
  jle    L133
  mov    $0x2,%ebx
  nopw   0x0(%rax,%rax,1)
L134:
  mov    -0x8(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  cmp    %ebx,%r14d
  setg   %cl
  test   %rax,%rax
  setne  %dl
  add    $0x1,%rbx
  test   %dl,%cl
  jne    L134
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L133:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: Allocation error.

assistant: ```c
int getCommand(int argc, char *argv[], char *command, char **value) {
  int i;
  int ok = 0;
  if (value == NULL) {
    for (i = 1; (ok == 0) && (i < argc); i += 1) {
      if (strcmp(command, argv[i]) == 0) {
        ok = 1;
      }
    }
  } else {
    for (i = 1; (ok == 0) && (i < argc); i += 2) {
      if (strcmp(command, argv[i]) == 0) {
        *value = (char *)malloc(strlen(argv[i + 1]) + 1);
        if (*value == 0) {
          puts("Allocation error.");
          exit(1);
        }
        strcpy(*value, argv[i + 1]);
        ok = 1;
      }
    }
    if (ok == 0) {
      for (i = 2; (ok == 0) && (i < argc); i += 2) {
        if (strcmp(command, argv[i]) == 0) {
          *value = (char *)malloc(strlen(argv[i + 1]) + 1);
          if (*value == 0) {
            puts("Allocation error.");
            exit(1);
          }
          strcpy(*value, argv[i + 1]);
          ok = 1;
        }
      }
    }
  }
  return (ok);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getCommand>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L130
  cmp    $0x1,%edi
  jle    L10
  lea    -0x2(%rdi),%eax
  mov    %rcx,%r13
  mov    $0x1,%ebx
  shr    %eax
  lea    0x3(%rax,%rax,1),%r15
  jmp    L111
  nopl   0x0(%rax)
L126:
  add    $0x2,%rbx
  cmp    %rbx,%r15
  je     L124
L111:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L126
L128:
  lea    0x8(%rbp,%rbx,8),%rbx
  mov    (%rbx),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L102
L135:
  mov    (%rbx),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L102:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    0x0(%r13),%rdi
  jmp    L135
L124:
  cmp    $0x2,%r14d
  je     L10
  sub    $0x3,%r14d
  mov    $0x2,%ebx
  shr    %r14d
  add    $0x2,%r14d
  add    %r14,%r14
  jmp    L82
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x2,%rbx
  cmp    %rbx,%r14
  je     L10
L82:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L56
  jmp    L128
  nopl   0x0(%rax,%rax,1)
L130:
  cmp    $0x1,%edi
  jle    L10
  mov    $0x2,%ebx
  nopw   0x0(%rax,%rax,1)
L76:
  mov    -0x8(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  cmp    %ebx,%r14d
  setg   %cl
  test   %rax,%rax
  setne  %dl
  add    $0x1,%rbx
  test   %dl,%cl
  jne    L76
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: Allocation error.

assistant: ```c
int getCommand(int argc, char *argv[], char *command, char **value) {
  int i;
  int ok = 0;
  if (value == NULL) {
    for (i = 1; (ok == 0) && (i < argc); i += 1) {
      if (strcmp(command, argv[i]) == 0) {
        ok = 1;
      }
    }
  } else {
    for (i = 1; (ok == 0) && (i < argc); i += 2) {
      if (strcmp(command, argv[i]) == 0) {
        *value = (char *)malloc(strlen(argv[i + 1]) + 1);
        if (*value == 0) {
          puts("Allocation error.");
          exit(1);
        }
        strcpy(*value, argv[i + 1]);
        ok = 1;
      }
    }
    if (ok == 0) {
      for (i = 2; (ok == 0) && (i < argc); i += 2) {
        if (strcmp(command, argv[i]) == 0) {
          *value = (char *)malloc(strlen(argv[i + 1]) + 1);
          if (*value == 0) {
            puts("Allocation error.");
            exit(1);
          }
          strcpy(*value, argv[i + 1]);
          ok = 1;
        }
      }
    }
  }
  return (ok);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  jmp    L3
L18:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  sub    $0x30,%eax
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
L3:
  mov    $0x0,%eax
  call   <peek@plt>
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L18
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int read_number(int val) {
  while (isdigit(peek()))
    val = val * 10 + (getchar() - '0');
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_number>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L5
L8:
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    -0x30(%rbx,%rax,1),%ebx
L5:
  mov    $0x0,%eax
  call   <peek@plt>
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L8
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int read_number(int val) {
  while (isdigit(peek()))
    val = val * 10 + (getchar() - '0');
  return val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_number>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  jmp    L13
L3:
  lea    (%r12,%r12,4),%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  add    %ebx,%ebx
  lea    -0x30(%rbx,%rax,1),%r12d
L13:
  xor    %eax,%eax
  call   <peek@plt>
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int read_number(int val) {
  while (isdigit(peek()))
    val = val * 10 + (getchar() - '0');
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_number>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  jmp    L5
L11:
  lea    (%r12,%r12,4),%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  add    %ebx,%ebx
  lea    -0x30(%rbx,%rax,1),%r12d
L5:
  xor    %eax,%eax
  call   <peek@plt>
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int read_number(int val) {
  while (isdigit(peek()))
    val = val * 10 + (getchar() - '0');
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L34
L78:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x2c,%eax
  je     L111
  cmp    $0x2c,%eax
  jg     L119
  cmp    $0x7,%eax
  je     L17
  cmp    $0x7,%eax
  jg     L119
  cmp    $0xfffffffc,%eax
  je     L40
  cmp    $0x3,%eax
  je     L85
  jmp    L119
L17:
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L103
L111:
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0xc(%rbp)
  jmp    L103
L40:
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L103
L85:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L103
L119:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L103:
  addl   $0x1,-0x10(%rbp)
L34:
  cmpl   $0x6,-0x10(%rbp)
  jle    L78
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L123
  call   <__stack_chk_fail@plt>
L123:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D40
datatype: string
name: retrieve_data
arguments: label: D72
datatype: string
name: retrieve_data
arguments: label: D62
datatype: string
name: retrieve_data
arguments: label: D67
datatype: string
name: retrieve_data
arguments: label: D74
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D78
datatype: string

tool: D40: Please enter an integer: 

tool: D72: %d

tool: D62: You entered an 8!	Just kidding...	Or am I???

tool: D67: Best number ever!

tool: D74: This is a negative four.

tool: D13: The number of counting shall be three, and three shall be the number to which thou shalt count.

tool: D7: Happy Tuesday!!

tool: D78: You entered 44 %d times.

assistant: ```c
void main() {
  int i, a, j = 0;
  for (a = 1; a <= 6; a += 1) {
    printf("Please enter an integer: ");
    scanf("%d", &i);
    switch (i) {
    case 7:
      printf("You entered an 8!\tJust kidding...\tOr am I???\n");
      break;
    case 44:
      printf("Best number ever!\n");
      j += 1;
      break;
    case -4:
      printf("This is a negative four.\n");
      break;
    case 3:
      printf("The number of counting shall be three, and three shall be the number to which thou shalt count.\n");
      break;
    default:
      printf("Happy Tuesday!!\n");
      break;
    }
  }
  printf("You entered 44 %d times.", j);
}
```