user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    $0x4,%eax
  je     L250
  mov    $0x1,%eax
  jmp    L1
L250:
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cmp    $0x4,%eax
  je     L139
  mov    $0x2,%eax
  jmp    L1
L139:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    $0x2,%eax
  je     L208
  mov    $0x3,%eax
  jmp    L1
L208:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    $0x3,%eax
  je     L197
  mov    $0x4,%eax
  jmp    L1
L197:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cmp    $0x3,%eax
  je     L268
  mov    $0x5,%eax
  jmp    L1
L268:
  movl   $0x5,-0x34(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x34(%rbp),%eax
  cmp    $0x6,%eax
  je     L136
  mov    $0x6,%eax
  jmp    L1
L136:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x30(%rbp),%rdx
  mov    %ecx,(%rdx)
  cmp    $0x6,%eax
  je     L88
  mov    $0x7,%eax
  jmp    L1
L88:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x6,%eax
  je     L137
  mov    $0x8,%eax
  jmp    L1
L137:
  movl   $0xa,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    $0xb,%eax
  je     L229
  mov    $0x9,%eax
  jmp    L1
L229:
  mov    -0x20(%rbp),%eax
  cmp    $0xb,%eax
  je     L33
  mov    $0xa,%eax
  jmp    L1
L33:
  lea    -0x34(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  lea    -0x34(%rbp),%rdx
  cmp    %rdx,%rax
  je     L260
  mov    $0xb,%eax
  jmp    L1
L260:
  addq   $0x4,-0x28(%rbp)
  lea    -0x34(%rbp),%rax
  add    $0x8,%rax
  cmp    %rax,-0x28(%rbp)
  je     L111
  mov    $0xc,%eax
  jmp    L1
L111:
  mov    -0x28(%rbp),%rdx
  lea    -0x4(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x34(%rbp),%rax
  add    $0x8,%rax
  cmp    %rax,%rdx
  je     L93
  mov    $0xd,%eax
  jmp    L1
L93:
  subq   $0x4,-0x28(%rbp)
  lea    -0x34(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  je     L204
  mov    $0xe,%eax
  jmp    L1
L204:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

assistant: ```c
int main() {
  int a = 5;
  a--;
  if (a != 4)
    return 1;
  if (a-- != 4)
    return 2;
  if (--a != 2)
    return 3;
  if (++a != 3)
    return 4;
  if (a++ != 3)
    return 5;
  a = 5;
  int *b = &a;
  (*b)++;
  if (a != 6)
    return 6;
  if ((*b)++ != 6)
    return 7;
  if (--*b != 6)
    return 8;
  int arr[5];
  arr[0] = 10;
  if (++arr[0] != 11)
    return 9;
  if (arr[0] != 11)
    return 10;
  int *p = &a;
  if (p++ != &a)
    return 11;
  if (++p != &a + 2)
    return 12;
  if (p-- != &a + 2)
    return 13;
  if (--p - &a != 0)
    return 14;
}
```