ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_varlist>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    D8(%rip),%rsi
  call   <strtok_r@plt>
  cmpb   $0x0,(%rax)
  jne    L62
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L62:
  lea    0xc(%rsp),%rsi
  mov    %rax,%rdi
  call   <find_variable@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L45
  sub    $0x1,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x1,%ebx
  lea    D8(%rip),%r12
L10:
  lea    0x10(%rsp),%rdx
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L11
  lea    0xc(%rsp),%rsi
  call   <find_variable@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L45
  sub    $0x1,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  jmp    L10
L11:
  mov    %ebx,(%r14)
  jmp    L45
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8:  ,

assistant: ```c
void parse_varlist(char *varlist, int *ivars, int *n) {
  char *item;
  char *toksave;
  int v, i = 0;
  item = strtok_r(varlist, " ,", &toksave);
  if (item[0] == 0)
    return;
  find_variable(item, &v);
  if (v <= 0)
    return;
  ivars[i] = v - 1;
  i++;
  while ((item = strtok_r(NULL, " ,", &toksave)) != NULL) {
    find_variable(item, &v);
    if (v <= 0)
      return;
    ivars[i] = v - 1;
    i++;
  }
  *n = i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_varlist>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdx
  call   <strtok_r@plt>
  cmpb   $0x0,(%rax)
  jne    L44
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  lea    0xc(%rsp),%r14
  mov    %rax,%rdi
  mov    %r14,%rsi
  call   <find_variable@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L33
  sub    $0x1,%eax
  mov    $0x1,%ebx
  mov    %eax,0x0(%rbp)
  jmp    L45
  nopl   (%rax)
L41:
  mov    %r14,%rsi
  call   <find_variable@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L33
  sub    $0x1,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
L45:
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L41
  mov    %ebx,(%r15)
  jmp    L33
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3:  ,

assistant: ```c
void parse_varlist(char *varlist, int *ivars, int *n) {
  char *item;
  char *toksave;
  int v, i = 0;
  item = strtok_r(varlist, " ,", &toksave);
  if (item[0] == 0)
    return;
  find_variable(item, &v);
  if (v <= 0)
    return;
  ivars[i] = v - 1;
  i++;
  while ((item = strtok_r(NULL, " ,", &toksave)) != NULL) {
    find_variable(item, &v);
    if (v <= 0)
      return;
    ivars[i] = v - 1;
    i++;
  }
  *n = i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_varlist>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdx
  call   <strtok_r@plt>
  cmpb   $0x0,(%rax)
  jne    L1
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0xc(%rsp),%r14
  mov    %rax,%rdi
  mov    %r14,%rsi
  call   <find_variable@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L63
  sub    $0x1,%eax
  mov    $0x1,%ebx
  mov    %eax,0x0(%rbp)
  jmp    L30
  nopl   (%rax)
L29:
  mov    %r14,%rsi
  call   <find_variable@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L63
  sub    $0x1,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
L30:
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L29
  mov    %ebx,(%r15)
  jmp    L63
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6:  ,

assistant: ```c
void parse_varlist(char *varlist, int *ivars, int *n) {
  char *item;
  char *toksave;
  int v, i = 0;
  item = strtok_r(varlist, " ,", &toksave);
  if (item[0] == 0)
    return;
  find_variable(item, &v);
  if (v <= 0)
    return;
  ivars[i] = v - 1;
  i++;
  while ((item = strtok_r(NULL, " ,", &toksave)) != NULL) {
    find_variable(item, &v);
    if (v <= 0)
      return;
    ivars[i] = v - 1;
    i++;
  }
  *n = i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lee_linea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L28
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
  jmp    L12
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L12:
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
L28:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string

tool: D10:  

assistant: ```c
int lee_linea(char *linea, char **argumentos) {
  char *token;
  int narg = 0;
  if ((token = strtok(linea, " ")) != NULL) {
    argumentos[narg] = (char *)strdup(token);
    narg++;
    while ((token = strtok(NULL, " ")) != NULL) {
      argumentos[narg] = (char *)strdup(token);
      narg++;
    }
  }
  argumentos[narg] = NULL;
  return narg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lee_linea>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D2(%rip),%rsi
  call   <strtok@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L10
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  mov    $0x1,%ebx
  lea    D2(%rip),%r12
  jmp    L9
L22:
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
L9:
  mov    %ebx,%r13d
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L22
L10:
  movslq %r13d,%rax
  movq   $0x0,0x0(%rbp,%rax,8)
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2:  

assistant: ```c
int lee_linea(char *linea, char **argumentos) {
  char *token;
  int narg = 0;
  if ((token = strtok(linea, " ")) != NULL) {
    argumentos[narg] = (char *)strdup(token);
    narg++;
    while ((token = strtok(NULL, " ")) != NULL) {
      argumentos[narg] = (char *)strdup(token);
      narg++;
    }
  }
  argumentos[narg] = NULL;
  return narg;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lee_linea>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  lea    0x8(%rbp),%rbx
  mov    $0x1,%r12d
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  jmp    L20
L18:
  call   <strdup@plt>
  add    $0x1,%r12d
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
L20:
  xor    %edi,%edi
  mov    %r13,%rsi
  mov    %rbx,%rbp
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L18
L15:
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0:  

assistant: ```c
int lee_linea(char *linea, char **argumentos) {
  char *token;
  int narg = 0;
  if ((token = strtok(linea, " ")) != NULL) {
    argumentos[narg] = (char *)strdup(token);
    narg++;
    while ((token = strtok(NULL, " ")) != NULL) {
      argumentos[narg] = (char *)strdup(token);
      narg++;
    }
  }
  argumentos[narg] = NULL;
  return narg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lee_linea>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%rdi
  lea    0x8(%rbp),%rbx
  mov    $0x1,%r12d
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  jmp    L12
L9:
  call   <strdup@plt>
  add    $0x1,%r12d
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
L12:
  xor    %edi,%edi
  mov    %r13,%rsi
  mov    %rbx,%rbp
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L9
L20:
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8:  

assistant: ```c
int lee_linea(char *linea, char **argumentos) {
  char *token;
  int narg = 0;
  if ((token = strtok(linea, " ")) != NULL) {
    argumentos[narg] = (char *)strdup(token);
    narg++;
    while ((token = strtok(NULL, " ")) != NULL) {
      argumentos[narg] = (char *)strdup(token);
      narg++;
    }
  }
  argumentos[narg] = NULL;
  return narg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<startHandleMessages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x13000(%rsp),%r11
L48:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L48
  sub    $0x8e0,%rsp
  mov    %rdi,-0x138a8(%rbp)
  mov    %rsi,-0x138b0(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x138c0(%rbp)
  mov    %r8,-0x138c8(%rbp)
  mov    %r9,-0x138d0(%rbp)
  mov    %al,-0x138b4(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x138d8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1389c(%rbp)
  movzbl -0x138b4(%rbp),%esi
  mov    -0x138c0(%rbp),%r8
  lea    -0x1389c(%rbp),%rdi
  lea    -0x13890(%rbp),%rcx
  mov    -0x138b0(%rbp),%rdx
  mov    -0x138a8(%rbp),%rax
  push   -0x138d0(%rbp)
  push   -0x138c8(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <handleMessages@plt>
  add    $0x10,%rsp
  mov    %eax,-0x13898(%rbp)
  cmpl   $0x0,-0x13898(%rbp)
  je     L15
  cmpl   $0xc9,-0x13898(%rbp)
  je     L15
  mov    -0x1389c(%rbp),%edx
  lea    -0x13890(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <freeCommands@plt>
  mov    -0x13898(%rbp),%eax
  jmp    L44
L15:
  mov    -0x1389c(%rbp),%edx
  mov    -0x138d0(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x138d8(%rbp),%rcx
  lea    -0x13890(%rbp),%rsi
  mov    %rax,%rdi
  call   <startNonBlockingBatch@plt>
  mov    %eax,-0x13894(%rbp)
  cmpl   $0x0,-0x13894(%rbp)
  je     L62
  mov    -0x13894(%rbp),%eax
  jmp    L44
L62:
  mov    -0x13898(%rbp),%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
unsigned int startHandleMessages(void *handle, char *messages, unsigned char actionType, unsigned int *resultsLength, unsigned int **results, void **rulesBinding, unsigned int *replyCount) {
  char *commands[10000];
  unsigned int commandCount = 0;
  unsigned int result = handleMessages(handle, actionType, messages, commands, &commandCount, resultsLength, results, rulesBinding);
  if (result != 0 && result != 201) {
    freeCommands(commands, commandCount);
    return result;
  }
  unsigned int batchResult = startNonBlockingBatch(*rulesBinding, commands, commandCount, replyCount);
  if (batchResult != 0) {
    return batchResult;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<startHandleMessages>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x8a0,%rsp
  mov    %rsi,%rax
  mov    %rcx,%r10
  mov    %r9,%rbp
  mov    0x138c0(%rsp),%r12
  mov    %fs:0x28,%rcx
  mov    %rcx,0x13898(%rsp)
  xor    %ecx,%ecx
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  movzbl %dl,%esi
  push   %r9
  push   %r8
  mov    %r10,%r9
  lea    0x1c(%rsp),%r8
  mov    %rax,%rdx
  call   <handleMessages@plt>
  mov    %eax,%ebx
  add    $0x10,%rsp
  test   %eax,%eax
  je     L15
  cmp    $0xc9,%eax
  je     L15
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%esi
  call   <freeCommands@plt>
  jmp    L19
L15:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rcx
  mov    0xc(%rsp),%edx
  mov    0x0(%rbp),%rdi
  call   <startNonBlockingBatch@plt>
  test   %eax,%eax
  cmovne %eax,%ebx
L19:
  mov    0x13898(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %ebx,%eax
  add    $0x138a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int startHandleMessages(void *handle, char *messages, unsigned char actionType, unsigned int *resultsLength, unsigned int **results, void **rulesBinding, unsigned int *replyCount) {
  char *commands[10000];
  unsigned int commandCount = 0;
  unsigned int result = handleMessages(handle, actionType, messages, commands, &commandCount, resultsLength, results, rulesBinding);
  if (result != 0 && result != 201) {
    freeCommands(commands, commandCount);
    return result;
  }
  unsigned int batchResult = startNonBlockingBatch(*rulesBinding, commands, commandCount, replyCount);
  if (batchResult != 0) {
    return batchResult;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<startHandleMessages>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L44:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L44
  sub    $0x8a8,%rsp
  mov    0x138d0(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x13898(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rsi,%r10
  mov    %r9,%rbx
  movl   $0x0,0xc(%rsp)
  movzbl %dl,%esi
  mov    %r10,%rdx
  push   %r9
  mov    %rcx,%r9
  mov    %rbp,%rcx
  push   %r8
  lea    0x1c(%rsp),%r8
  call   <handleMessages@plt>
  pop    %rdx
  pop    %rcx
  mov    %eax,%r12d
  test   %eax,%eax
  je     L19
  cmp    $0xc9,%eax
  je     L19
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <freeCommands@plt>
  jmp    L49
L19:
  mov    0xc(%rsp),%edx
  mov    (%rbx),%rdi
  mov    %r13,%rcx
  mov    %rbp,%rsi
  call   <startNonBlockingBatch@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
L49:
  mov    0x13898(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x138a8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int startHandleMessages(void *handle, char *messages, unsigned char actionType, unsigned int *resultsLength, unsigned int **results, void **rulesBinding, unsigned int *replyCount) {
  char *commands[10000];
  unsigned int commandCount = 0;
  unsigned int result = handleMessages(handle, actionType, messages, commands, &commandCount, resultsLength, results, rulesBinding);
  if (result != 0 && result != 201) {
    freeCommands(commands, commandCount);
    return result;
  }
  unsigned int batchResult = startNonBlockingBatch(*rulesBinding, commands, commandCount, replyCount);
  if (batchResult != 0) {
    return batchResult;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<startHandleMessages>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x8a8,%rsp
  mov    0x138d0(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x13898(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rsi,%r10
  mov    %r9,%rbx
  movl   $0x0,0xc(%rsp)
  movzbl %dl,%esi
  mov    %r10,%rdx
  push   %r9
  mov    %rcx,%r9
  mov    %rbp,%rcx
  push   %r8
  lea    0x1c(%rsp),%r8
  call   <handleMessages@plt>
  pop    %rdx
  pop    %rcx
  mov    %eax,%r12d
  test   %eax,%eax
  je     L8
  cmp    $0xc9,%eax
  je     L8
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <freeCommands@plt>
  jmp    L16
L8:
  mov    0xc(%rsp),%edx
  mov    (%rbx),%rdi
  mov    %r13,%rcx
  mov    %rbp,%rsi
  call   <startNonBlockingBatch@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
L16:
  mov    0x13898(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x138a8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int startHandleMessages(void *handle, char *messages, unsigned char actionType, unsigned int *resultsLength, unsigned int **results, void **rulesBinding, unsigned int *replyCount) {
  char *commands[10000];
  unsigned int commandCount = 0;
  unsigned int result = handleMessages(handle, actionType, messages, commands, &commandCount, resultsLength, results, rulesBinding);
  if (result != 0 && result != 201) {
    freeCommands(commands, commandCount);
    return result;
  }
  unsigned int batchResult = startNonBlockingBatch(*rulesBinding, commands, commandCount, replyCount);
  if (batchResult != 0) {
    return batchResult;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x11,%edx
  mov    $0x400,%esi
  mov    $0x0,%edi
  call   <f2@plt>
  cmp    $0x180c,%eax
  jne    L16
  mov    $0x20,%ecx
  mov    $0x0,%edx
  mov    $0x20,%esi
  mov    $0x0,%edi
  call   <f3@plt>
  cmp    $0x40,%eax
  je     L8
L16:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L8:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (f2(0, 1024, 17) != 1024 + (17 + 5 * 1023) || f3(0, 32, 0, 32) != 64)
    __builtin_abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edx
  mov    $0x400,%esi
  mov    $0x0,%edi
  call   <f2@plt>
  cmp    $0x180c,%eax
  je     L27
L15:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L26:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L27:
  mov    $0x20,%ecx
  mov    $0x0,%edx
  mov    $0x20,%esi
  mov    $0x0,%edi
  call   <f3@plt>
  cmp    $0x40,%eax
  jne    L15
  jmp    L26
```

assistant: ```c
int main() {
  if (f2(0, 1024, 17) != 1024 + (17 + 5 * 1023) || f3(0, 32, 0, 32) != 64)
    __builtin_abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0x11,%edx
  mov    $0x400,%esi
  call   <f2@plt>
  cmp    $0x180c,%eax
  je     L25
L12:
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L25:
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x20,%ecx
  mov    $0x20,%esi
  call   <f3@plt>
  cmp    $0x40,%eax
  jne    L12
  jmp    L3
```

assistant: ```c
int main() {
  if (f2(0, 1024, 17) != 1024 + (17 + 5 * 1023) || f3(0, 32, 0, 32) != 64)
    __builtin_abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0x11,%edx
  mov    $0x400,%esi
  call   <f2@plt>
  cmp    $0x180c,%eax
  je     L16
L8:
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L29:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L16:
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x20,%ecx
  mov    $0x20,%esi
  call   <f3@plt>
  cmp    $0x40,%eax
  jne    L8
  jmp    L29
```

assistant: ```c
int main() {
  if (f2(0, 1024, 17) != 1024 + (17 + 5 * 1023) || f3(0, 32, 0, 32) != 64)
    __builtin_abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0xa,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    0xa(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <read_and_write@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <read_and_write@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <read_and_write@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D4
type: string

tool: D6: First error, go beyond memory boundaries {%d}


tool: D13: Second error, forget to free memory {%d}


tool: D4: Third error, free memory twice {%d}


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int buff_size = 10;
  int *buff = NULL;
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("First error, go beyond memory boundaries {%d}\n", read_and_write(buff, buff_size + 10, rand()));
  free(buff);
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Second error, forget to free memory {%d}\n", read_and_write(buff, buff_size, rand()));
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Third error, free memory twice {%d}\n", read_and_write(buff, buff_size, rand()));
  free(buff);
  free(buff);
  return 0;
}
```