ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L39
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L2
L39:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L6
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L37
  movl   $0x3,-0x8(%rbp)
  jmp    L6
L37:
  movl   $0x4,-0x8(%rbp)
L6:
  movl   $0x2,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 3;
  int d = 4;
  if (a > b || c < d) {
    a = b + c;
  } else if (b > d) {
    c = 3;
  } else {
    c = 4;
  }
  a = 2;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 3;
  int d = 4;
  if (a > b || c < d) {
    a = b + c;
  } else if (b > d) {
    c = 3;
  } else {
    c = 4;
  }
  a = 2;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 3;
  int d = 4;
  if (a > b || c < d) {
    a = b + c;
  } else if (b > d) {
    c = 3;
  } else {
    c = 4;
  }
  a = 2;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 3;
  int d = 4;
  if (a > b || c < d) {
    a = b + c;
  } else if (b > d) {
    c = 3;
  } else {
    c = 4;
  }
  a = 2;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<imprime_vetor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5:  %d

assistant: ```c
void imprime_vetor(int *itinerario, int tamanho_do_vetor) {
  int i;
  for (i = 0; i < tamanho_do_vetor; i++) {
    printf(" %d", itinerario[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<imprime_vetor>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D6(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6:  %d

assistant: ```c
void imprime_vetor(int *itinerario, int tamanho_do_vetor) {
  int i;
  for (i = 0; i < tamanho_do_vetor; i++) {
    printf(" %d", itinerario[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<imprime_vetor>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1:  %d

assistant: ```c
void imprime_vetor(int *itinerario, int tamanho_do_vetor) {
  int i;
  for (i = 0; i < tamanho_do_vetor; i++) {
    printf(" %d", itinerario[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<imprime_vetor>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8:  %d

assistant: ```c
void imprime_vetor(int *itinerario, int tamanho_do_vetor) {
  int i;
  for (i = 0; i < tamanho_do_vetor; i++) {
    printf(" %d", itinerario[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1a0(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1a0(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x1b0(%rbp)
  cmpq   $0x0,-0x1b0(%rbp)
  je     L2
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L4:
  mov    -0x1a8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L24:
  mov    -0x1b0(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x1a8(%rbp)
  cmpq   $0x0,-0x1a8(%rbp)
  jne    L4
  mov    -0x1b0(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  jmp    L11
L2:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L11:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D46
type: string
name: disassemble_data
arguments: data_label: D10
type: string
name: disassemble_data
arguments: data_label: D27
type: string
name: disassemble_data
arguments: data_label: D37
type: string
name: disassemble_data
arguments: data_label: D36
type: string

tool: D46: clear

tool: D10: Enter full path name of directory you want to view:

tool: D27: %s

tool: D37: The Directory Contents are .
/******************************/ 

tool: D36: Directory doesnt exist

assistant: ```c
int main(void) {
  system("clear");
  DIR *d;
  struct dirent *dir;
  char path[400];
  puts("Enter full path name of directory you want to view:");
  scanf("%s", &path);
  d = opendir(path);
  if (d) {
    printf("The Directory Contents are .\n/******************************/ \n");
    while ((dir = readdir(d)) != NULL) {
      printf("%s\n", dir->d_name);
    }
    closedir(d);
  } else
    printf("Directory doesnt exist");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <system@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L43
  mov    %rax,%rbx
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L14:
  mov    (%rax),%rdi
  call   <puts@plt>
L27:
  mov    %rbx,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbx,%rdi
  call   <closedir@plt>
L20:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  ret
L43:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D38
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D11: clear

tool: D23: Enter full path name of directory you want to view:

tool: D17: %s

tool: D38: The Directory Contents are .
/******************************/ 

tool: D5: Directory doesnt exist

assistant: ```c
int main(void) {
  system("clear");
  DIR *d;
  struct dirent *dir;
  char path[400];
  puts("Enter full path name of directory you want to view:");
  scanf("%s", &path);
  d = opendir(path);
  if (d) {
    printf("The Directory Contents are .\n/******************************/ \n");
    while ((dir = readdir(d)) != NULL) {
      printf("%s\n", dir->d_name);
    }
    closedir(d);
  } else
    printf("Directory doesnt exist");
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <system@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L1
  lea    D18(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rax),%rdi
  call   <puts@plt>
L16:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L12
  mov    %rbp,%rdi
  call   <closedir@plt>
L5:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L5
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D33
data_type: string
name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D43
data_type: string
name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D44
data_type: string

tool: D33: clear

tool: D1: Enter full path name of directory you want to view:

tool: D43: %s

tool: D18: The Directory Contents are .
/******************************/ 

tool: D44: Directory doesnt exist

assistant: ```c
int main(void) {
  system("clear");
  DIR *d;
  struct dirent *dir;
  char path[400];
  puts("Enter full path name of directory you want to view:");
  scanf("%s", &path);
  d = opendir(path);
  if (d) {
    printf("The Directory Contents are .\n/******************************/ \n");
    while ((dir = readdir(d)) != NULL) {
      printf("%s\n", dir->d_name);
    }
    closedir(d);
  } else
    printf("Directory doesnt exist");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D42(%rip),%rdi
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <system@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L8
  lea    D49(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L25:
  mov    (%rax),%rdi
  call   <puts@plt>
L23:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L25
  mov    %rbp,%rdi
  call   <closedir@plt>
L10:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L10
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D42
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string
name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D49
type_guessed: string
name: disassemble_data
arguments: label: D41
type_guessed: string

tool: D42: clear

tool: D2: Enter full path name of directory you want to view:

tool: D12: %s

tool: D49: The Directory Contents are .
/******************************/ 

tool: D41: Directory doesnt exist

assistant: ```c
int main(void) {
  system("clear");
  DIR *d;
  struct dirent *dir;
  char path[400];
  puts("Enter full path name of directory you want to view:");
  scanf("%s", &path);
  d = opendir(path);
  if (d) {
    printf("The Directory Contents are .\n/******************************/ \n");
    while ((dir = readdir(d)) != NULL) {
      printf("%s\n", dir->d_name);
    }
    closedir(d);
  } else
    printf("Directory doesnt exist");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L9
L11:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L9:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(void *dst, const void *src, unsigned int length) {
  while (length--)
    *(char *)dst++ = *(char *)src++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  lea    -0x1(%rdx),%ecx
  test   %edx,%edx
  je     L11
  mov    %ecx,%ecx
  mov    $0x0,%eax
L3:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L3
L11:
  ret
```

assistant: ```c
void memcpy(void *dst, const void *src, unsigned int length) {
  while (length--)
    *(char *)dst++ = *(char *)src++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L11
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L5:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L11:
  ret
```

assistant: ```c
void memcpy(void *dst, const void *src, unsigned int length) {
  while (length--)
    *(char *)dst++ = *(char *)src++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%r10d
  test   %edx,%edx
  je     L89
  lea    0x1(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0xe,%rax
  jbe    L27
  cmp    $0x6,%r10d
  jbe    L27
  cmp    $0xe,%r10d
  jbe    L159
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L48:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L48
  mov    %edx,%r9d
  and    $0xfffffff0,%r9d
  mov    %r9d,%r8d
  sub    %r9d,%r10d
  lea    (%rcx,%r8,1),%rax
  lea    (%rsi,%r8,1),%rdi
  cmp    %r9d,%edx
  je     L89
  sub    %r9d,%edx
  lea    -0x1(%rdx),%r9d
  cmp    $0x6,%r9d
  jbe    L21
L30:
  mov    (%rsi,%r8,1),%rsi
  mov    %rsi,(%rcx,%r8,1)
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%esi
  sub    %ecx,%r10d
  add    %rsi,%rax
  add    %rsi,%rdi
  cmp    %ecx,%edx
  je     L89
L21:
  movzbl (%rdi),%edx
  mov    %dl,(%rax)
  test   %r10d,%r10d
  je     L89
  movzbl 0x1(%rdi),%edx
  mov    %dl,0x1(%rax)
  cmp    $0x1,%r10d
  je     L89
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x2(%rax)
  cmp    $0x2,%r10d
  je     L89
  movzbl 0x3(%rdi),%edx
  mov    %dl,0x3(%rax)
  cmp    $0x3,%r10d
  je     L89
  movzbl 0x4(%rdi),%edx
  mov    %dl,0x4(%rax)
  cmp    $0x4,%r10d
  je     L89
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x5(%rax)
  cmp    $0x5,%r10d
  je     L89
  movzbl 0x6(%rdi),%edx
  mov    %dl,0x6(%rax)
  ret
  nopl   0x0(%rax)
L27:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L155:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L155
L89:
  ret
L159:
  mov    %rsi,%rdi
  mov    %rcx,%rax
  xor    %r8d,%r8d
  jmp    L30
```

assistant: ```c
void memcpy(void *dst, const void *src, unsigned int length) {
  while (length--)
    *(char *)dst++ = *(char *)src++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<qs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%r12
  lea    (%rsi,%rdx,1),%rdx
  mov    %rdx,%rax
  shr    $0x3f,%rax
  add    %rdx,%rax
  sar    %rax
  shl    $0x4,%rax
  mov    0x8(%rbp,%rax,1),%r8
  mov    %rsi,%r10
  mov    %rsi,%r9
  shl    $0x4,%r9
  add    %rbp,%r9
  lea    0x1(%rsi),%r11
  mov    %r12,%rdx
  jmp    L76
L66:
  cmp    %rdx,%rbx
  jg     L40
  mov    0x0(%r13),%rax
  mov    %rcx,0x8(%r13)
  mov    (%rsi),%rcx
  mov    %rcx,0x0(%r13)
  mov    %r14,0x8(%rsi)
  mov    %rax,(%rsi)
  mov    %r11,%rbx
  sub    $0x1,%rdx
  cmp    %rdx,%r11
  jg     L40
L32:
  add    $0x10,%r9
  add    $0x1,%r10
  add    $0x1,%r11
L76:
  mov    %r10,%rbx
  mov    %r9,%r13
  mov    0x8(%r9),%r14
  cmp    %r12,%r10
  jge    L73
  cmp    %r8,%r14
  jl     L32
L73:
  mov    %rdx,%rax
  shl    $0x4,%rax
  lea    0x0(%rbp,%rax,1),%rsi
  mov    0x8(%rsi),%rcx
  cmp    %rdi,%rdx
  jle    L66
  cmp    %rcx,%r8
  jge    L66
  lea    -0x10(%rbp,%rax,1),%rax
L34:
  sub    $0x1,%rdx
  mov    %rax,%rsi
  mov    0x8(%rax),%rcx
  sub    $0x10,%rax
  cmp    %rdx,%rdi
  jge    L66
  cmp    %r8,%rcx
  jg     L34
  jmp    L66
L40:
  cmp    %rdx,%rdi
  jl     L111
L61:
  cmp    %rbx,%r12
  jg     L27
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L111:
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <qs>
  jmp    L61
L27:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <qs>
  jmp    L15
```

assistant: ```c
void qs(long daten[][2], long links, long rechts) {
  long i, j;
  long x, y, z;
  i = links;
  j = rechts;
  x = daten[(links + rechts) / 2][1];
  do {
    while (daten[i][1] < x && i < rechts)
      i++;
    while (x < daten[j][1] && j > links)
      j--;
    if (i <= j) {
      y = daten[i][1];
      z = daten[i][0];
      daten[i][1] = daten[j][1];
      daten[i][0] = daten[j][0];
      daten[j][1] = y;
      daten[j][0] = z;
      i++;
      j--;
    }
  } while (i <= j);
  if (links < j)
    qs(daten, links, j);
  if (i < rechts)
    qs(daten, i, rechts);
}
```
user: Translate the below assembly code into C programming language:

```asm
<qs>:
  endbr64
  push   %r15
  mov    %rsi,%r8
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
L124:
  lea    (%r8,%rbp,1),%rdx
  mov    %r8,%r9
  lea    0x1(%r8),%r11
  mov    %r8,%r10
  mov    %rdx,%rax
  shl    $0x4,%r9
  shr    $0x3f,%rax
  add    %r12,%r9
  add    %rdx,%rax
  mov    %rbp,%rdx
  sar    %rax
  shl    $0x4,%rax
  mov    0x8(%r12,%rax,1),%rdi
  nopl   0x0(%rax)
L89:
  mov    %rdx,%r14
  mov    0x8(%r9),%r13
  mov    %r10,%rbx
  shl    $0x4,%r14
  cmp    %r8,%rdx
  lea    (%r12,%r14,1),%rsi
  setg   %al
  mov    0x8(%rsi),%rcx
  cmp    %rcx,%rdi
  setl   %r15b
  and    %r15d,%eax
  cmp    %rbp,%r10
  jge    L75
  cmp    %rdi,%r13
  jl     L47
L75:
  test   %al,%al
  je     L64
  lea    -0x10(%r12,%r14,1),%rax
  jmp    L104
  nopl   0x0(%rax,%rax,1)
L48:
  cmp    %rdi,%rcx
  jle    L64
L104:
  sub    $0x1,%rdx
  mov    0x8(%rax),%rcx
  mov    %rax,%rsi
  sub    $0x10,%rax
  cmp    %rdx,%r8
  jl     L48
L64:
  cmp    %rdx,%r10
  jle    L55
L87:
  cmp    %rdx,%r8
  jl     L39
L3:
  cmp    %rbx,%rbp
  jle    L103
  mov    %rbx,%r8
  jmp    L124
L55:
  mov    %rcx,0x8(%r9)
  mov    (%r9),%rax
  sub    $0x1,%rdx
  mov    %r11,%rbx
  mov    (%rsi),%rcx
  mov    %rcx,(%r9)
  mov    %r13,0x8(%rsi)
  mov    %rax,(%rsi)
  cmp    %rdx,%r11
  jg     L87
L47:
  add    $0x10,%r9
  add    $0x1,%r10
  add    $0x1,%r11
  jmp    L89
L103:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <qs>
  jmp    L3
```

assistant: ```c
void qs(long daten[][2], long links, long rechts) {
  long i, j;
  long x, y, z;
  i = links;
  j = rechts;
  x = daten[(links + rechts) / 2][1];
  do {
    while (daten[i][1] < x && i < rechts)
      i++;
    while (x < daten[j][1] && j > links)
      j--;
    if (i <= j) {
      y = daten[i][1];
      z = daten[i][0];
      daten[i][1] = daten[j][1];
      daten[i][0] = daten[j][0];
      daten[j][1] = y;
      daten[j][0] = z;
      i++;
      j--;
    }
  } while (i <= j);
  if (links < j)
    qs(daten, links, j);
  if (i < rechts)
    qs(daten, i, rechts);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qs>:
  endbr64
  push   %r15
  mov    %rsi,%r8
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
L9:
  lea    (%r8,%rbp,1),%rdx
  mov    %r8,%r9
  lea    0x1(%r8),%r11
  mov    %r8,%r10
  mov    %rdx,%rax
  shl    $0x4,%r9
  shr    $0x3f,%rax
  add    %r12,%r9
  add    %rdx,%rax
  mov    %rbp,%rdx
  sar    %rax
  shl    $0x4,%rax
  mov    0x8(%r12,%rax,1),%rdi
  nopl   0x0(%rax)
L63:
  mov    %rdx,%r14
  mov    0x8(%r9),%r13
  mov    %r10,%rbx
  shl    $0x4,%r14
  cmp    %r8,%rdx
  lea    (%r12,%r14,1),%rsi
  setg   %al
  mov    0x8(%rsi),%rcx
  cmp    %rcx,%rdi
  setl   %r15b
  and    %r15d,%eax
  cmp    %rbp,%r10
  jge    L101
  cmp    %rdi,%r13
  jl     L129
L101:
  test   %al,%al
  je     L40
  lea    -0x10(%r12,%r14,1),%rax
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    %rdi,%rcx
  jle    L40
L46:
  sub    $0x1,%rdx
  mov    0x8(%rax),%rcx
  mov    %rax,%rsi
  sub    $0x10,%rax
  cmp    %rdx,%r8
  jl     L36
L40:
  cmp    %rdx,%r10
  jle    L88
L48:
  cmp    %rdx,%r8
  jl     L29
L45:
  cmp    %rbx,%rbp
  jle    L0
  mov    %rbx,%r8
  jmp    L9
L88:
  movq   (%r9),%xmm0
  mov    %rcx,0x8(%r9)
  sub    $0x1,%rdx
  mov    %r11,%rbx
  mov    (%rsi),%rax
  movq   %r13,%xmm1
  punpcklqdq %xmm1,%xmm0
  mov    %rax,(%r9)
  movups %xmm0,(%rsi)
  cmp    %rdx,%r11
  jg     L48
L129:
  add    $0x10,%r9
  add    $0x1,%r10
  add    $0x1,%r11
  jmp    L63
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <qs>
  jmp    L45
```

assistant: ```c
void qs(long daten[][2], long links, long rechts) {
  long i, j;
  long x, y, z;
  i = links;
  j = rechts;
  x = daten[(links + rechts) / 2][1];
  do {
    while (daten[i][1] < x && i < rechts)
      i++;
    while (x < daten[j][1] && j > links)
      j--;
    if (i <= j) {
      y = daten[i][1];
      z = daten[i][0];
      daten[i][1] = daten[j][1];
      daten[i][0] = daten[j][0];
      daten[j][1] = y;
      daten[j][0] = z;
      i++;
      j--;
    }
  } while (i <= j);
  if (links < j)
    qs(daten, links, j);
  if (i < rechts)
    qs(daten, i, rechts);
}
```