user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_parse_depth>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x18,%rsp
  lea    D43(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xc008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4000(%rsp),%r13
  lea    0x8000(%rsp),%rbp
  call   <printf@plt>
  lea    D30(%rip),%rdx
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdx
  lea    D76(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  movb   $0x0,0x8000(%rsp)
  call   <parse_depth@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    %eax,%ebx
  sete   %dil
  xor    %ebx,%ebx
  call   <assert@plt>
  jmp    L11
  nopl   (%rax)
L36:
  movzbl (%r12,%rbx,1),%eax
  xor    %edi,%edi
  cmp    %al,0x0(%rbp,%rbx,1)
  sete   %dil
  add    $0x1,%rbx
  call   <assert@plt>
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L36
  mov    %r12,%rdx
  lea    D17(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <parse_depth@plt>
  xor    %edi,%edi
  cmp    $0x4,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rdx
  lea    D19(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <parse_depth@plt>
  xor    %edi,%edi
  cmp    $0x4,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rdx
  lea    D60(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <parse_depth@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    0xc008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xc018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D43
datatype: string
name: extract_symbolic_data
arguments: label: D30
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D76
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D60
datatype: string
name: extract_symbolic_data
arguments: label: D69
datatype: string

tool: D43: test_parse_depth...

tool: D30: title

tool: D21: %s

tool: D76: *** %s

tool: D17: **** %s

tool: D19: ****	%s

tool: D60: *%s*

tool: D69: Ok


assistant: ```c
void test_parse_depth() {
  char title[(4096 * 4)];
  char line1[(4096 * 4)];
  char header[(4096 * 4)];
  int i;
  printf("test_parse_depth...");
  sprintf(title, "%s", "title");
  sprintf(line1, "*** %s", title);
  header[0] = 0;
  assert(parse_depth(line1, header) == 3);
  assert(strlen(header) == strlen(title));
  for (i = 0; i < strlen(header); i++) {
    assert(header[i] == title[i]);
  }
  sprintf(line1, "**** %s", title);
  assert(parse_depth(line1, header) == 4);
  sprintf(line1, "****\t%s", title);
  assert(parse_depth(line1, header) == 4);
  sprintf(line1, "*%s*", title);
  assert(parse_depth(line1, header) == -1);
  printf("Ok\n");
}
```