ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putc>:
  endbr64
  mov    $0xe2900010,%ecx
L4:
  mov    (%rcx),%rdx
  test   $0x4,%dl
  je     L4
  movsbq %dil,%rax
  movabs %rax,0xe2900020
  ret
```

assistant: ```c
void putc(char c) {
  while (!((*((volatile unsigned long *)0xE2900010)) & (1 << 2)))
    ;
  (*((volatile unsigned long *)0xE2900020)) = c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<putc>:
  endbr64
  mov    $0xe2900010,%ecx
  nopl   0x0(%rax)
L0:
  mov    (%rcx),%rdx
  and    $0x4,%edx
  je     L0
  movsbq %dil,%rax
  movabs %rax,0xe2900020
  ret
```

assistant: ```c
void putc(char c) {
  while (!((*((volatile unsigned long *)0xE2900010)) & (1 << 2)))
    ;
  (*((volatile unsigned long *)0xE2900020)) = c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<putc>:
  endbr64
  mov    $0xe2900010,%ecx
  nopl   0x0(%rax)
L2:
  mov    (%rcx),%rdx
  and    $0x4,%edx
  je     L2
  movsbq %dil,%rax
  movabs %rax,0xe2900020
  ret
```

assistant: ```c
void putc(char c) {
  while (!((*((volatile unsigned long *)0xE2900010)) & (1 << 2)))
    ;
  (*((volatile unsigned long *)0xE2900020)) = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rescalesigma_chi2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L36:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L6
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L6
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L6:
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L36
  nop
  nop
  leave
  ret
```

assistant: ```c
void rescalesigma_chi2(int N, double *sig, double chi2val) {
  int i;
  double factor;
  factor = sqrt(chi2val);
  for (i = 0; i < N; i++) {
    if (sig[i] > 0. && !isnan(sig[i]))
      sig[i] = sig[i] * factor;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rescalesigma_chi2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L28
  sqrtsd %xmm0,%xmm0
L58:
  test   %ebx,%ebx
  jle    L68
  mov    %rbp,%rax
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,8),%rcx
  pxor   %xmm2,%xmm2
  jmp    L75
L28:
  call   <sqrt@plt>
  jmp    L58
L16:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L68
L75:
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L16
  comisd %xmm2,%xmm1
  jbe    L16
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
  jmp    L16
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rescalesigma_chi2(int N, double *sig, double chi2val) {
  int i;
  double factor;
  factor = sqrt(chi2val);
  for (i = 0; i < N; i++) {
    if (sig[i] > 0. && !isnan(sig[i]))
      sig[i] = sig[i] * factor;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rescalesigma_chi2>:
  endbr64
  pxor   %xmm2,%xmm2
  ucomisd %xmm0,%xmm2
  ja     L51
  sqrtsd %xmm0,%xmm0
  test   %edi,%edi
  jle    L68
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rax
  xchg   %ax,%ax
L85:
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L56
  comisd %xmm2,%xmm1
  jbe    L56
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
L56:
  add    $0x8,%rsi
  cmp    %rax,%rsi
  jne    L85
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  ret
L51:
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edi,0x4(%rsp)
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    0x8(%rsp),%rsi
  pxor   %xmm2,%xmm2
  test   %edi,%edi
  jle    L55
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rax
L7:
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L65
  comisd %xmm2,%xmm1
  jbe    L65
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
L65:
  add    $0x8,%rsi
  cmp    %rax,%rsi
  jne    L7
L55:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void rescalesigma_chi2(int N, double *sig, double chi2val) {
  int i;
  double factor;
  factor = sqrt(chi2val);
  for (i = 0; i < N; i++) {
    if (sig[i] > 0. && !isnan(sig[i]))
      sig[i] = sig[i] * factor;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rescalesigma_chi2>:
  endbr64
  pxor   %xmm2,%xmm2
  ucomisd %xmm0,%xmm2
  ja     L33
  sqrtsd %xmm0,%xmm0
  test   %edi,%edi
  jle    L32
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rax
  xchg   %ax,%ax
L42:
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L31
  comisd %xmm2,%xmm1
  jbe    L31
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
L31:
  add    $0x8,%rsi
  cmp    %rsi,%rax
  jne    L42
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  ret
L33:
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edi,0x4(%rsp)
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    0x8(%rsp),%rsi
  pxor   %xmm2,%xmm2
  test   %edi,%edi
  jle    L52
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rax
L5:
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L45
  comisd %xmm2,%xmm1
  jbe    L45
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
L45:
  add    $0x8,%rsi
  cmp    %rsi,%rax
  jne    L5
L52:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void rescalesigma_chi2(int N, double *sig, double chi2val) {
  int i;
  double factor;
  factor = sqrt(chi2val);
  for (i = 0; i < N; i++) {
    if (sig[i] > 0. && !isnan(sig[i]))
      sig[i] = sig[i] * factor;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<intlog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x3f,-0x8(%rbp)
  mov    $0x1,%edi
  call   <UINT64_C@plt>
  mov    $0x3f,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L18:
  sarl   -0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L15:
  cmpl   $0x0,-0x4(%rbp)
  je     L25
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L18
L25:
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L29
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint8_t intlog2(uint64_t n) {
  uint8_t m = 63;
  uint64_t mask = UINT64_C(1) << 63;
  while (mask && !(n & mask)) {
    mask >>= 1;
    m--;
  }
  if (mask && (n & (mask - 1)))
    m++;
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intlog2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <UINT64_C@plt>
  mov    $0x3f,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t intlog2(uint64_t n) {
  uint8_t m = 63;
  uint64_t mask = UINT64_C(1) << 63;
  while (mask && !(n & mask)) {
    mask >>= 1;
    m--;
  }
  if (mask && (n & (mask - 1)))
    m++;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intlog2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <UINT64_C@plt>
  mov    $0x3f,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t intlog2(uint64_t n) {
  uint8_t m = 63;
  uint64_t mask = UINT64_C(1) << 63;
  while (mask && !(n & mask)) {
    mask >>= 1;
    m--;
  }
  if (mask && (n & (mask - 1)))
    m++;
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<intlog2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <UINT64_C@plt>
  mov    $0x3f,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t intlog2(uint64_t n) {
  uint8_t m = 63;
  uint64_t mask = UINT64_C(1) << 63;
  while (mask && !(n & mask)) {
    mask >>= 1;
    m--;
  }
  if (mask && (n & (mask - 1)))
    m++;
  return m;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HO_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  D22(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D40(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D38(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  D35(%rip),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_infered: byte[8]
name: retrieve_data
arguments: tag: D40
type_infered: byte[8]
name: retrieve_data
arguments: tag: D38
type_infered: byte[8]
name: retrieve_data
arguments: tag: D35
type_infered: f64
name: retrieve_data
arguments: tag: D9
type_infered: byte[8]

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

tool: {"D40": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D35: 2

tool: {"D9": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

assistant: ```c
double HO_1(const double a, const double x) {
  double retval = sqrt(0.2e1) * pow(a, 0.3e1 / 0.4e1) * x * exp(-a * x * x / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1);
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HO_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movsd  %xmm1,0x8(%rsp)
  movsd  D45(%rip),%xmm1
  call   <pow@plt>
  movq   %xmm0,%rbp
  movq   %rbx,%xmm0
  xorpd  D13(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  D30(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  mulsd  D34(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  D36(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D45
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D13
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D30
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D34
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D36
data_type: byte[8]

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D34": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

tool: {"D36": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

assistant: ```c
double HO_1(const double a, const double x) {
  double retval = sqrt(0.2e1) * pow(a, 0.3e1 / 0.4e1) * x * exp(-a * x * x / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1);
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HO_1>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  D11(%rip),%xmm1
  movsd  %xmm0,0x18(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  xorpd  D4(%rip),%xmm2
  movsd  0x8(%rsp),%xmm3
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  D37(%rip),%xmm0
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm1
  mulsd  D17(%rip),%xmm1
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  D47(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D11
data_type: byte[8]
name: read_data
arguments: label: D4
data_type: byte[16]
name: read_data
arguments: label: D37
data_type: byte[8]
name: read_data
arguments: label: D17
data_type: byte[8]
name: read_data
arguments: label: D47
data_type: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D17": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

tool: {"D47": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

assistant: ```c
double HO_1(const double a, const double x) {
  double retval = sqrt(0.2e1) * pow(a, 0.3e1 / 0.4e1) * x * exp(-a * x * x / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1);
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HO_1>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  D31(%rip),%xmm1
  movsd  %xmm0,0x18(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  xorpd  D48(%rip),%xmm2
  movsd  0x8(%rsp),%xmm3
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  D20(%rip),%xmm0
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm1
  mulsd  D5(%rip),%xmm1
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  D44(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D31
type_guessed: byte[8]
name: retrieve_data
arguments: label: D48
type_guessed: byte[16]
name: retrieve_data
arguments: label: D20
type_guessed: byte[8]
name: retrieve_data
arguments: label: D5
type_guessed: byte[8]
name: retrieve_data
arguments: label: D44
type_guessed: byte[8]

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D5": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

tool: {"D44": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

assistant: ```c
double HO_1(const double a, const double x) {
  double retval = sqrt(0.2e1) * pow(a, 0.3e1 / 0.4e1) * x * exp(-a * x * x / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1);
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ehPrimo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L60
  mov    $0x0,%eax
  jmp    L18
L60:
  cmpl   $0x2,-0x14(%rbp)
  jne    L70
  mov    $0x1,%eax
  jmp    L18
L70:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
  jmp    L18
L13:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L29
L17:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L18
L28:
  addl   $0x2,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int ehPrimo(int n) {
  int i, ate;
  if (n < 2) {
    return 0;
  } else if (n == 2) {
    return 1;
  } else if (n % 2 == 0) {
    return 0;
  } else {
    ate = sqrt(n) + 1;
    for (i = 3; i < ate; i += 2) {
      if (n % i == 0) {
        return 0;
      }
    }
    return 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ehPrimo>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L44
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L36
  mov    $0x0,%eax
  test   $0x1,%dil
  jne    L48
L36:
  pop    %rbx
  ret
L48:
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L47
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L36
  mov    $0x3,%ecx
L34:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jl     L46
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L34
  jmp    L36
L46:
  mov    $0x1,%eax
  jmp    L36
L47:
  mov    $0x1,%eax
  jmp    L36
L44:
  ret
```

assistant: ```c
int ehPrimo(int n) {
  int i, ate;
  if (n < 2) {
    return 0;
  } else if (n == 2) {
    return 1;
  } else if (n % 2 == 0) {
    return 0;
  } else {
    ate = sqrt(n) + 1;
    for (i = 3; i < ate; i += 2) {
      if (n % i == 0) {
        return 0;
      }
    }
    return 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ehPrimo>:
  endbr64
  cmp    $0x1,%edi
  jle    L77
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  je     L44
  test   $0x1,%dil
  jne    L71
L34:
  xor    %eax,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L71:
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L44
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L34
  mov    $0x3,%ecx
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L34
L5:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L55
L44:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L77:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ehPrimo(int n) {
  int i, ate;
  if (n < 2) {
    return 0;
  } else if (n == 2) {
    return 1;
  } else if (n % 2 == 0) {
    return 0;
  } else {
    ate = sqrt(n) + 1;
    for (i = 3; i < ate; i += 2) {
      if (n % i == 0) {
        return 0;
      }
    }
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ehPrimo>:
  endbr64
  cmp    $0x1,%edi
  jle    L58
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  je     L2
  test   $0x1,%dil
  jne    L20
L9:
  xor    %eax,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L20:
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L2
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L9
  mov    $0x3,%ecx
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L9
L72:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L69
L2:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L58:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ehPrimo(int n) {
  int i, ate;
  if (n < 2) {
    return 0;
  } else if (n == 2) {
    return 1;
  } else if (n % 2 == 0) {
    return 0;
  } else {
    ate = sqrt(n) + 1;
    for (i = 3; i < ate; i += 2) {
      if (n % i == 0) {
        return 0;
      }
    }
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <is_Prime@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D28
data_type: string
name: unpack_data
arguments: label: D12
data_type: string

tool: D14: Enter a number:

tool: D28: %s

tool: D12: %d

assistant: ```c
int main() {
  char s[10];
  scanf("%s", ({
          printf("Enter a number:");
          s;
        }));
  printf("%d", is_Prime(s));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rbx
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <is_Prime@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D20
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string

tool: D4: Enter a number:

tool: D20: %s

tool: D22: %d

assistant: ```c
int main() {
  char s[10];
  scanf("%s", ({
          printf("Enter a number:");
          s;
        }));
  printf("%d", is_Prime(s));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <is_Prime@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string

tool: D13: Enter a number:

tool: D1: %s

tool: D11: %d

assistant: ```c
int main() {
  char s[10];
  scanf("%s", ({
          printf("Enter a number:");
          s;
        }));
  printf("%d", is_Prime(s));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <is_Prime@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string
name: read_data
arguments: label: D17
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string

tool: D1: Enter a number:

tool: D17: %s

tool: D10: %d

assistant: ```c
int main() {
  char s[10];
  scanf("%s", ({
          printf("Enter a number:");
          s;
        }));
  printf("%d", is_Prime(s));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L9
  cmpl   $0xa,-0x4(%rbp)
  jg     L9
  mov    $0x1,%eax
  jmp    L5
L9:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int check_year(int year) {
  if (year >= 1 && year <= 10)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_year>:
  endbr64
  sub    $0x1,%edi
  cmp    $0x9,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int check_year(int year) {
  if (year >= 1 && year <= 10)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_year>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int check_year(int year) {
  if (year >= 1 && year <= 10)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_year>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int check_year(int year) {
  if (year >= 1 && year <= 10)
    return 1;
  return 0;
}
```