user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%rdi
  lea    D35(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  lea    D78(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    D87(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  cmp    $0x3,%ecx
  jle    L2
  lea    -0x4(%rcx),%edx
  mov    $0xaaaaaaab,%esi
  mov    %rdx,%rax
  imul   %rsi,%rdx
  shr    $0x21,%rdx
  add    $0x1,%edx
  cmp    $0x8,%eax
  jbe    L91
  movd   %ecx,%xmm4
  mov    %edx,%esi
  movdqa D56(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  movdqa D80(%rip),%xmm2
  paddd  D75(%rip),%xmm1
  shr    $0x2,%esi
  nopl   0x0(%rax)
L18:
  movdqa %xmm1,%xmm0
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%esi
  jne    L18
  mov    %edx,%esi
  pshufd $0xff,%xmm0,%xmm0
  and    $0xfffffffc,%esi
  movd   %xmm0,%eax
  lea    0x0(,%rsi,4),%r8d
  mov    %esi,%edi
  sub    %r8d,%edi
  add    %edi,%ecx
  cmp    %esi,%edx
  je     L45
L91:
  lea    -0x3(%rcx),%eax
  cmp    $0x3,%eax
  jle    L45
  lea    -0x6(%rcx),%eax
  cmp    $0x3,%eax
  jle    L45
  lea    -0x9(%rcx),%eax
L45:
  mov    %eax,0x14(%rsp)
L81:
  xor    %ebx,%ebx
  nopl   (%rax)
L27:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L27
L41:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  lea    D59(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  test   %ecx,%ecx
  jle    L41
  jmp    L81
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D35
datatype: string
name: read_data
arguments: tag: D78
datatype: string
name: read_data
arguments: tag: D58
datatype: string
name: read_data
arguments: tag: D87
datatype: string
name: read_data
arguments: tag: D56
datatype: byte[16]
name: read_data
arguments: tag: D80
datatype: byte[16]
name: read_data
arguments: tag: D75
datatype: byte[16]
name: read_data
arguments: tag: D59
datatype: string

tool: D29:  Enter the 1st Number: 

tool: D35: %d

tool: D78:  Enter the 2nd Number: 

tool: D58:  Enter the 3rd Number: 

tool: D87:  Times of Rotation: 

tool: {"D56": [0xf4,0xff,0xff,0xff,0xf4,0xff,0xff,0xff,0xf4,0xff,0xff,0xff,0xf4,0xff,0xff,0xff]}

tool: {"D80": [0xfd,0xff,0xff,0xff,0xfd,0xff,0xff,0xff,0xfd,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

tool: {"D75": [0x00,0x00,0x00,0x00,0xfd,0xff,0xff,0xff,0xfa,0xff,0xff,0xff,0xf7,0xff,0xff,0xff]}

tool: D59:  %d %d %d 

assistant: ```c
int main() {
  int a, b, c, n, count;
  printf(" Enter the 1st Number: \n");
  scanf("%d", &a);
  printf(" Enter the 2nd Number: \n");
  scanf("%d", &b);
  printf(" Enter the 3rd Number: \n");
  scanf("%d", &c);
  printf(" Times of Rotation: \n");
  scanf("%d", &n);
  while (n > 3)
    n = n - 3;
  for (count = 0; count < n; count++)
    rotr(&a, &b, &c);
  printf(" %d %d %d ", a, b, c);
  return 0;
}
```