ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x40091eb8,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  lea    0x10(%rsp),%rbp
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L8
  nop
L15:
  add    $0x1,%ebx
  cmp    $0x401860f8,%ebx
  je     L1
L8:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <stdlib_base_float64_set_high_word@plt>
  movsd  0x10(%rsp),%xmm0
  ucomisd %xmm0,%xmm0
  jnp    L15
  lea    D16(%rip),%rdi
  call   <printf@plt>
L1:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  0x10(%rsp),%xmm1
  subsd  0x8(%rsp),%xmm0
  ucomisd %xmm1,%xmm1
  jp     L34
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L34:
  lea    D16(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L25
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type: f64
name: unpack_data
arguments: label: D16
type: string

tool: D17: 3.14

tool: D16: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  x = 3.14;
  h = 1074339512;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    stdlib_base_float64_set_high_word(h + i, &x);
    if (x != x) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x != x) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<debugLog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: *DEBUG LOG* %s


assistant: ```c
void debugLog(char *logLine) {
  int x;
  printf("*DEBUG LOG* %s\n", logLine);
  x = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<debugLog>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: *DEBUG LOG* %s


assistant: ```c
void debugLog(char *logLine) {
  int x;
  printf("*DEBUG LOG* %s\n", logLine);
  x = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<debugLog>:
  endbr64
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: *DEBUG LOG* %s


assistant: ```c
void debugLog(char *logLine) {
  int x;
  printf("*DEBUG LOG* %s\n", logLine);
  x = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<debugLog>:
  endbr64
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: *DEBUG LOG* %s


assistant: ```c
void debugLog(char *logLine) {
  int x;
  printf("*DEBUG LOG* %s\n", logLine);
  x = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat_identity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L1:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L8
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D9(%rip),%xmm0
  movss  %xmm0,(%rax)
  jmp    L39
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L39:
  addl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0xf,-0x4(%rbp)
  jle    L1
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat_identity(float mat[16]) {
  int i;
  for (i = 0; i < 16; i++) {
    if ((i % 5) == 0) {
      mat[i] = 1.0f;
    } else {
      mat[i] = 0.0f;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mat_identity>:
  endbr64
  mov    $0x0,%edx
  movss  D5(%rip),%xmm0
  jmp    L2
L39:
  movl   $0x0,(%rdi,%rdx,4)
L19:
  add    $0x1,%rdx
  cmp    $0x10,%rdx
  je     L21
L2:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %edx,%eax
  jne    L39
  movss  %xmm0,(%rdi,%rdx,4)
  jmp    L19
L21:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat_identity(float mat[16]) {
  int i;
  for (i = 0; i < 16; i++) {
    if ((i % 5) == 0) {
      mat[i] = 1.0f;
    } else {
      mat[i] = 0.0f;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mat_identity>:
  endbr64
  movss  D9(%rip),%xmm2
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L0:
  imul   $0xcccccccd,%eax,%edx
  movaps %xmm1,%xmm0
  cmp    $0x33333333,%edx
  ja     L10
  movaps %xmm2,%xmm0
L10:
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat_identity(float mat[16]) {
  int i;
  for (i = 0; i < 16; i++) {
    if ((i % 5) == 0) {
      mat[i] = 1.0f;
    } else {
      mat[i] = 0.0f;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mat_identity>:
  endbr64
  movss  D34(%rip),%xmm0
  movups %xmm0,(%rdi)
  movaps D30(%rip),%xmm0
  movups %xmm0,0x10(%rdi)
  movaps D16(%rip),%xmm0
  movups %xmm0,0x20(%rdi)
  movaps D24(%rip),%xmm0
  movups %xmm0,0x30(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D34
datatype: byte[4]
name: unpack_data
arguments: tag: D30
datatype: byte[16]
name: unpack_data
arguments: tag: D16
datatype: byte[16]
name: unpack_data
arguments: tag: D24
datatype: byte[16]

tool: {"D34": [0x00,0x00,0x80,0x3f]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x00]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat_identity(float mat[16]) {
  int i;
  for (i = 0; i < 16; i++) {
    if ((i % 5) == 0) {
      mat[i] = 1.0f;
    } else {
      mat[i] = 0.0f;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getperms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L4:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L13
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  je     L53
  cmp    $0x2,%eax
  jg     L48
  test   %eax,%eax
  je     L68
  cmp    $0x1,%eax
  je     L9
  jmp    L48
L68:
  mov    $0x8,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x78,(%rax)
  jmp    L91
L9:
  mov    $0x8,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x77,(%rax)
  jmp    L91
L53:
  mov    $0x8,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x72,(%rax)
  jmp    L91
L48:
  mov    $0x8,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L91
L13:
  mov    $0x8,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L91:
  addl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0x8,-0x4(%rbp)
  jle    L4
  mov    -0x20(%rbp),%rax
  add    $0x9,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *getperms(mode_t mode, char *buf) {
  int i;
  for (i = 0; i < 9; i++) {
    if ((mode >> i) & 1) {
      switch (i % 3) {
      case 0:
        buf[8 - i] = 'x';
        break;
      case 1:
        buf[8 - i] = 'w';
        break;
      case 2:
        buf[8 - i] = 'r';
        break;
      default:
        buf[8 - i] = '-';
        break;
      }
    } else {
      buf[8 - i] = '-';
    }
  }
  buf[9] = 0;
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getperms>:
  endbr64
  mov    %rsi,%rax
  lea    -0x9(%rsi),%rsi
  mov    %rax,%rcx
  jmp    L35
L34:
  movb   $0x78,0x8(%rcx)
  jmp    L64
L17:
  movb   $0x77,0x8(%rcx)
  jmp    L64
L93:
  movb   $0x72,0x8(%rcx)
  jmp    L64
L75:
  movb   $0x2d,0x8(%rcx)
L64:
  sub    $0x1,%rcx
  cmp    %rsi,%rcx
  je     L4
L35:
  mov    %eax,%r8d
  sub    %ecx,%r8d
  bt     %r8d,%edi
  jae    L75
  movslq %r8d,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %r8d,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%edx
  lea    (%rdx,%rdx,2),%r9d
  mov    %r8d,%edx
  sub    %r9d,%edx
  cmp    $0x1,%edx
  je     L17
  cmp    $0x2,%edx
  je     L93
  test   %edx,%edx
  je     L34
  movb   $0x2d,0x8(%rcx)
  jmp    L64
L4:
  movb   $0x0,0x9(%rax)
  ret
```

assistant: ```c
char *getperms(mode_t mode, char *buf) {
  int i;
  for (i = 0; i < 9; i++) {
    if ((mode >> i) & 1) {
      switch (i % 3) {
      case 0:
        buf[8 - i] = 'x';
        break;
      case 1:
        buf[8 - i] = 'w';
        break;
      case 2:
        buf[8 - i] = 'r';
        break;
      default:
        buf[8 - i] = '-';
        break;
      }
    } else {
      buf[8 - i] = '-';
    }
  }
  buf[9] = 0;
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getperms>:
  endbr64
  mov    %rsi,%rax
  push   %rbx
  lea    -0x9(%rsi),%rsi
  mov    $0xaaaaaaab,%ebx
  mov    %rax,%rdx
  mov    $0x78,%r11d
  mov    $0x72,%r10d
L21:
  mov    %eax,%r9d
  mov    $0x2d,%r8d
  sub    %edx,%r9d
  bt     %r9d,%edi
  jae    L16
  mov    %r9d,%ecx
  imul   %rbx,%rcx
  shr    $0x21,%rcx
  lea    (%rcx,%rcx,2),%r8d
  mov    %r9d,%ecx
  sub    %r8d,%ecx
  mov    $0x77,%r8d
  cmp    $0x1,%ecx
  je     L16
  cmp    $0x2,%ecx
  mov    %r10d,%r8d
  cmovne %r11d,%r8d
L16:
  mov    %r8b,0x8(%rdx)
  sub    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L21
  movb   $0x0,0x9(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *getperms(mode_t mode, char *buf) {
  int i;
  for (i = 0; i < 9; i++) {
    if ((mode >> i) & 1) {
      switch (i % 3) {
      case 0:
        buf[8 - i] = 'x';
        break;
      case 1:
        buf[8 - i] = 'w';
        break;
      case 2:
        buf[8 - i] = 'r';
        break;
      default:
        buf[8 - i] = '-';
        break;
      }
    } else {
      buf[8 - i] = '-';
    }
  }
  buf[9] = 0;
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getperms>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  movb   $0x0,0x9(%rsi)
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffb5,%edx
  add    $0x78,%edx
  mov    %dl,0x8(%rsi)
  mov    %edi,%edx
  sar    %edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffb6,%edx
  add    $0x77,%edx
  mov    %dl,0x7(%rsi)
  mov    %edi,%edx
  sar    $0x2,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffbb,%edx
  add    $0x72,%edx
  mov    %dl,0x6(%rsi)
  mov    %edi,%edx
  sar    $0x3,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffb5,%edx
  add    $0x78,%edx
  mov    %dl,0x5(%rsi)
  mov    %edi,%edx
  sar    $0x4,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffb6,%edx
  add    $0x77,%edx
  mov    %dl,0x4(%rsi)
  mov    %edi,%edx
  sar    $0x5,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffbb,%edx
  add    $0x72,%edx
  mov    %dl,0x3(%rsi)
  mov    %edi,%edx
  sar    $0x6,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0xffffffb5,%edx
  add    $0x78,%edx
  mov    %dl,0x2(%rsi)
  mov    %edi,%edx
  sar    $0x7,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  sar    $0x8,%eax
  and    $0xffffffb6,%edx
  and    $0x1,%eax
  add    $0x77,%edx
  cmp    $0x1,%eax
  sbb    %eax,%eax
  mov    %dl,0x1(%rsi)
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *getperms(mode_t mode, char *buf) {
  int i;
  for (i = 0; i < 9; i++) {
    if ((mode >> i) & 1) {
      switch (i % 3) {
      case 0:
        buf[8 - i] = 'x';
        break;
      case 1:
        buf[8 - i] = 'w';
        break;
      case 2:
        buf[8 - i] = 'r';
        break;
      default:
        buf[8 - i] = '-';
        break;
      }
    } else {
      buf[8 - i] = '-';
    }
  }
  buf[9] = 0;
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L20
L16:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  jmp    L21
L17:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    -0x14(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0)
      return (0);
  }
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L32
  test   $0x1,%dil
  je     L3
  mov    $0x2,%ecx
L16:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L32
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L16
  mov    %edx,%edi
L32:
  mov    %edi,%eax
  ret
L3:
  mov    $0x0,%edi
  jmp    L32
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0)
      return (0);
  }
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_prime>:
  endbr64
  mov    %edi,%r8d
  cmp    $0x2,%edi
  jle    L40
  test   $0x1,%dil
  je     L37
  mov    $0x2,%ecx
  jmp    L26
  nopl   0x0(%rax)
L44:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L37
L26:
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L44
L40:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0)
      return (0);
  }
  return num;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_prime>:
  endbr64
  mov    %edi,%r8d
  cmp    $0x2,%edi
  jle    L31
  test   $0x1,%dil
  je     L13
  mov    $0x2,%ecx
  jmp    L23
  nopl   0x0(%rax)
L30:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L13
L23:
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L30
L31:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0)
      return (0);
  }
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<findmax>:
  endbr64
  cmp    %esi,%edx
  je     L69
  lea    0x1(%rsi),%eax
  cmp    %edx,%eax
  je     L24
  sub    $0x8,%rsp
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
  je     L12
  movslq %eax,%rcx
  mov    -0x4(%rdi,%rcx,4),%r10d
  cmp    %r10d,(%rdi,%rcx,4)
  jle    L55
L12:
  cmp    %eax,%edx
  je     L90
  movslq %eax,%rcx
  lea    0x0(,%rcx,4),%r9
  mov    (%rdi,%rcx,4),%r8d
  cmp    0x4(%rdi,%rcx,4),%r8d
  jg     L90
  cmp    -0x4(%rdi,%r9,1),%r8d
  jle    L55
  cmp    0x4(%rdi,%r9,1),%r8d
  jl     L56
L55:
  lea    -0x1(%rax),%edx
  call   <findmax>
L87:
  add    $0x8,%rsp
  ret
L69:
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  ret
L24:
  movslq %edx,%rdx
  movslq %esi,%rsi
  mov    (%rdi,%rdx,4),%eax
  mov    (%rdi,%rsi,4),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
L90:
  cltq
  mov    (%rdi,%rax,4),%eax
  jmp    L87
L56:
  lea    0x1(%rax),%esi
  call   <findmax>
  jmp    L87
```

assistant: ```c
int findmax(int a[], int low, int high) {
  if (high == low) {
    return a[low];
  }
  if (high == low + 1) {
    if (a[high] > a[low])
      return a[high];
    else
      return a[low];
  }
  int mid = low + (high - low) / 2;
  if ((mid == 0 || a[mid] > a[mid - 1]) && (mid == high || a[mid] > a[mid + 1]))
    return a[mid];
  if (a[mid] > a[mid - 1] && a[mid] < a[mid + 1])
    return findmax(a, mid + 1, high);
  else
    return findmax(a, low, mid - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findmax>:
  endbr64
  mov    %esi,%ecx
  cmp    %edx,%esi
  je     L33
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jne    L114
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L28:
  cmp    %edx,%eax
  je     L67
  mov    0x4(%rdi,%r9,1),%esi
  cmp    %r8d,%esi
  jl     L67
  cmp    %r8d,-0x4(%rdi,%r9,1)
  jge    L90
  cmp    %r8d,%esi
  jle    L90
  lea    0x1(%rax),%ecx
  cmp    %edx,%ecx
  je     L33
L6:
  lea    0x1(%rcx),%eax
  cmp    %edx,%eax
  je     L37
L114:
  mov    %edx,%esi
  sub    %ecx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rsi
  mov    (%rdi,%rsi,4),%r8d
  lea    0x0(,%rsi,4),%r9
  je     L28
  cmp    %r8d,-0x4(%rdi,%r9,1)
  jl     L28
L90:
  lea    -0x1(%rax),%edx
  cmp    %edx,%ecx
  jne    L6
L33:
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%r8d
L67:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L37:
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    (%rdi,%rcx,4),%eax
  mov    (%rdi,%rdx,4),%r8d
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int findmax(int a[], int low, int high) {
  if (high == low) {
    return a[low];
  }
  if (high == low + 1) {
    if (a[high] > a[low])
      return a[high];
    else
      return a[low];
  }
  int mid = low + (high - low) / 2;
  if ((mid == 0 || a[mid] > a[mid - 1]) && (mid == high || a[mid] > a[mid + 1]))
    return a[mid];
  if (a[mid] > a[mid - 1] && a[mid] < a[mid + 1])
    return findmax(a, mid + 1, high);
  else
    return findmax(a, low, mid - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findmax>:
  endbr64
  mov    %esi,%ecx
  cmp    %edx,%esi
  je     L84
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jne    L114
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L37:
  cmp    %edx,%eax
  je     L18
  mov    0x4(%rdi,%r9,1),%esi
  cmp    %r8d,%esi
  jl     L18
  cmp    %r8d,-0x4(%rdi,%r9,1)
  jge    L90
  cmp    %r8d,%esi
  jle    L90
  lea    0x1(%rax),%ecx
  cmp    %edx,%ecx
  je     L84
L118:
  lea    0x1(%rcx),%eax
  cmp    %edx,%eax
  je     L16
L114:
  mov    %edx,%esi
  sub    %ecx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rsi
  mov    (%rdi,%rsi,4),%r8d
  lea    0x0(,%rsi,4),%r9
  je     L37
  cmp    %r8d,-0x4(%rdi,%r9,1)
  jl     L37
L90:
  lea    -0x1(%rax),%edx
  cmp    %edx,%ecx
  jne    L118
L84:
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%r8d
L18:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L16:
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    (%rdi,%rcx,4),%eax
  mov    (%rdi,%rdx,4),%r8d
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int findmax(int a[], int low, int high) {
  if (high == low) {
    return a[low];
  }
  if (high == low + 1) {
    if (a[high] > a[low])
      return a[high];
    else
      return a[low];
  }
  int mid = low + (high - low) / 2;
  if ((mid == 0 || a[mid] > a[mid - 1]) && (mid == high || a[mid] > a[mid + 1]))
    return a[mid];
  if (a[mid] > a[mid - 1] && a[mid] < a[mid + 1])
    return findmax(a, mid + 1, high);
  else
    return findmax(a, low, mid - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hand_handle_child>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  nop
L0:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void hand_handle_child(int sig) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hand_handle_child>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
L6:
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L6
  pop    %rbx
  ret
```

assistant: ```c
void hand_handle_child(int sig) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hand_handle_child>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L8
  pop    %rbx
  ret
```

assistant: ```c
void hand_handle_child(int sig) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hand_handle_child>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L4
  pop    %rbx
  ret
```

assistant: ```c
void hand_handle_child(int sig) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<replaceExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L4:
  subl   $0x1,-0x8(%rbp)
L36:
  cmpl   $0x0,-0x8(%rbp)
  js     L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L4
L0:
  cmpl   $0x0,-0x8(%rbp)
  js     L9
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L9
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  leave
  ret
```

assistant: ```c
void replaceExt(char *str, char *ext) {
  int len, ind;
  len = strlen(str);
  ind = len - 1;
  while (ind >= 0 && str[ind] != '.' && str[ind] != '\\' && str[ind] != '/')
    ind--;
  if (ind >= 0 && str[ind] == '.') {
    str[ind] = 0;
  }
  strcat(str, ext);
}
```