ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<assertFuzzyEquals>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm2
  sub    $0x10,%rsp
  ucomisd D1(%rip),%xmm1
  jp     L28
  jne    L28
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <fabsl@plt>
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
L29:
  fldl   0xea2(%rip)        # 2040 <_fini+0xe30>
  xor    %ebp,%ebp
  fcomip %st(1),%st
  fstp   %st(0)
  setae  %bpl
  jb     L38
  add    $0x10,%rsp
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <assert@plt>
  cs nopw 0x0(%rax,%rax,1)
L28:
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x8(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  divsd  %xmm2,%xmm0
  call   <fabsl@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm2
  jmp    L29
  nopl   0x0(%rax)
L38:
  lea    D16(%rip),%rdi
  movapd %xmm3,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: f64
name: extract_symbolic_data
arguments: label: D16
type_infered: string

tool: D1: 0

tool: D16: Expected should be near: %1.16e , but got: %1.16e


assistant: ```c
void assertFuzzyEquals(double act, double exp) {
  bool inrange;
  double merr = 1e-12;
  long double e;
  if (exp == 0.0) {
    e = fabsl(act);
  } else {
    e = fabsl((act - exp) / exp);
  }
  inrange = (e <= merr);
  if (inrange == false) {
    printf("Expected should be near: %1.16e , but got: %1.16e\n", exp, act);
  }
  assert(inrange == 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<assertFuzzyEquals>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm2
  sub    $0x10,%rsp
  ucomisd D17(%rip),%xmm1
  jp     L27
  jne    L27
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <fabsl@plt>
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
L37:
  fldl   0xea2(%rip)        # 2040 <_fini+0xe30>
  xor    %ebp,%ebp
  fcomip %st(1),%st
  fstp   %st(0)
  setae  %bpl
  jb     L14
  add    $0x10,%rsp
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <assert@plt>
  cs nopw 0x0(%rax,%rax,1)
L27:
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x8(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  divsd  %xmm2,%xmm0
  call   <fabsl@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm2
  jmp    L37
  nopl   0x0(%rax)
L14:
  lea    D11(%rip),%rdi
  movapd %xmm3,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <assert@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: f64
name: parse_data
arguments: label: D11
datatype: string

tool: D17: 0

tool: D11: Expected should be near: %1.16e , but got: %1.16e


assistant: ```c
void assertFuzzyEquals(double act, double exp) {
  bool inrange;
  double merr = 1e-12;
  long double e;
  if (exp == 0.0) {
    e = fabsl(act);
  } else {
    e = fabsl((act - exp) / exp);
  }
  inrange = (e <= merr);
  if (inrange == false) {
    printf("Expected should be near: %1.16e , but got: %1.16e\n", exp, act);
  }
  assert(inrange == 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<setSignalBehavior>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    D83(%rip),%rax
  mov    (%rax),%edx
  mov    D117(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D83(%rip),%rax
  mov    (%rax),%edx
  mov    D143(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D83(%rip),%rax
  mov    (%rax),%edx
  mov    D119(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D83(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  jmp    L8
L6:
  mov    D70(%rip),%rax
  mov    (%rax),%edx
  mov    D117(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D70(%rip),%rax
  mov    (%rax),%edx
  mov    D143(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D70(%rip),%rax
  mov    (%rax),%edx
  mov    D119(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D70(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void setSignalBehavior(int restoreFlag) {
  if (restoreFlag) {
    signal(SIGINT, SIG_DFL);
    signal(SIGTERM, SIG_DFL);
    signal(SIGQUIT, SIG_DFL);
    signal(SIGTSTP, SIG_DFL);
  } else {
    signal(SIGINT, SIG_IGN);
    signal(SIGTERM, SIG_IGN);
    signal(SIGQUIT, SIG_IGN);
    signal(SIGTSTP, SIG_IGN);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setSignalBehavior>:
  endbr64
  push   %rbx
  test   %edi,%edi
  je     L9
  mov    D69(%rip),%rbx
  mov    (%rbx),%esi
  mov    D77(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D72(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D76(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
L17:
  pop    %rbx
  ret
L9:
  mov    D1(%rip),%rbx
  mov    (%rbx),%esi
  mov    D77(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D72(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D76(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  jmp    L17
```

assistant: ```c
void setSignalBehavior(int restoreFlag) {
  if (restoreFlag) {
    signal(SIGINT, SIG_DFL);
    signal(SIGTERM, SIG_DFL);
    signal(SIGQUIT, SIG_DFL);
    signal(SIGTSTP, SIG_DFL);
  } else {
    signal(SIGINT, SIG_IGN);
    signal(SIGTERM, SIG_IGN);
    signal(SIGQUIT, SIG_IGN);
    signal(SIGTSTP, SIG_IGN);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<setSignalBehavior>:
  endbr64
  mov    D43(%rip),%rax
  mov    %edi,%r8d
  push   %rbx
  mov    (%rax),%edi
  test   %r8d,%r8d
  je     L16
  mov    D10(%rip),%rbx
L19:
  mov    (%rbx),%esi
  call   <signal@plt>
  mov    D45(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D9(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D59(%rip),%rax
  mov    (%rbx),%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <signal@plt>
  nopl   (%rax)
L16:
  mov    D3(%rip),%rbx
  jmp    L19
```

assistant: ```c
void setSignalBehavior(int restoreFlag) {
  if (restoreFlag) {
    signal(SIGINT, SIG_DFL);
    signal(SIGTERM, SIG_DFL);
    signal(SIGQUIT, SIG_DFL);
    signal(SIGTSTP, SIG_DFL);
  } else {
    signal(SIGINT, SIG_IGN);
    signal(SIGTERM, SIG_IGN);
    signal(SIGQUIT, SIG_IGN);
    signal(SIGTSTP, SIG_IGN);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setSignalBehavior>:
  endbr64
  mov    D39(%rip),%rax
  mov    %edi,%r8d
  push   %rbx
  mov    (%rax),%edi
  test   %r8d,%r8d
  je     L9
  mov    D16(%rip),%rbx
L12:
  mov    (%rbx),%esi
  call   <signal@plt>
  mov    D3(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D12(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D2(%rip),%rax
  mov    (%rbx),%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <signal@plt>
  nopl   (%rax)
L9:
  mov    D46(%rip),%rbx
  jmp    L12
```

assistant: ```c
void setSignalBehavior(int restoreFlag) {
  if (restoreFlag) {
    signal(SIGINT, SIG_DFL);
    signal(SIGTERM, SIG_DFL);
    signal(SIGQUIT, SIG_DFL);
    signal(SIGTSTP, SIG_DFL);
  } else {
    signal(SIGINT, SIG_IGN);
    signal(SIGTERM, SIG_IGN);
    signal(SIGQUIT, SIG_IGN);
    signal(SIGTSTP, SIG_IGN);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<points_within_and_visible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L35
  mov    $0x0,%eax
  jmp    L13
L35:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L70
  mov    $0x0,%eax
  jmp    L13
L70:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L42
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  mov    $0x0,%eax
  jmp    L13
L42:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L18
  mov    $0x0,%eax
  jmp    L13
L18:
  mov    $0x1,%eax
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: /.

assistant: ```c
int points_within_and_visible(const char *target, const char *root) {
  int tlen = strlen(target);
  int rlen = strlen(root);
  if (rlen > tlen)
    return 0;
  if (strncmp(target, root, rlen))
    return 0;
  if (target[rlen] != '/' && target[rlen] != '\0')
    return 0;
  if (strstr(target + rlen, "/."))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<points_within_and_visible>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  cmp    %ebp,%r13d
  jge    L30
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L12
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rdi
  movzbl (%rdi),%edx
  cmp    $0x2f,%dl
  je     L21
  test   %dl,%dl
  jne    L12
L21:
  lea    D7(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: /.

assistant: ```c
int points_within_and_visible(const char *target, const char *root) {
  int tlen = strlen(target);
  int rlen = strlen(root);
  if (rlen > tlen)
    return 0;
  if (strncmp(target, root, rlen))
    return 0;
  if (target[rlen] != '/' && target[rlen] != '\0')
    return 0;
  if (strstr(target + rlen, "/."))
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<points_within_and_visible>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  movslq %eax,%rbp
  cmp    %ebp,%r13d
  jge    L7
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L36
  lea    (%rbx,%rbp,1),%rdi
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  je     L11
  test   %al,%al
  jne    L36
L11:
  lea    D9(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: /.

assistant: ```c
int points_within_and_visible(const char *target, const char *root) {
  int tlen = strlen(target);
  int rlen = strlen(root);
  if (rlen > tlen)
    return 0;
  if (strncmp(target, root, rlen))
    return 0;
  if (target[rlen] != '/' && target[rlen] != '\0')
    return 0;
  if (strstr(target + rlen, "/."))
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<points_within_and_visible>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  movslq %eax,%rbp
  cmp    %ebp,%r13d
  jge    L32
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L32:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L6
  lea    (%rbx,%rbp,1),%rdi
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  je     L7
  test   %al,%al
  jne    L6
L7:
  lea    D2(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: /.

assistant: ```c
int points_within_and_visible(const char *target, const char *root) {
  int tlen = strlen(target);
  int rlen = strlen(root);
  if (rlen > tlen)
    return 0;
  if (strncmp(target, root, rlen))
    return 0;
  if (target[rlen] != '/' && target[rlen] != '\0')
    return 0;
  if (strstr(target + rlen, "/."))
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x6,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0xa,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <findMissing@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: Number missing array : %d 


assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 6, 7, 5, 8, 10};
  int n = findMissing(a, sizeof(a) / sizeof(int));
  printf("Number missing array : %d \n", n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x6,0x10(%rsp)
  movl   $0x7,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  mov    %rsp,%rdi
  mov    $0x9,%esi
  call   <findMissing@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: Number missing array : %d 


assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 6, 7, 5, 8, 10};
  int n = findMissing(a, sizeof(a) / sizeof(int));
  printf("Number missing array : %d \n", n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x9,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  movl   $0xa,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000005,%rax
  mov    %rax,0x18(%rsp)
  call   <findMissing@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: Number missing array : %d 


assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 6, 7, 5, 8, 10};
  int n = findMissing(a, sizeof(a) / sizeof(int));
  printf("Number missing array : %d \n", n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D18(%rip),%xmm0
  mov    $0x9,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0xa,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <findMissing@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
datatype: byte[16]
name: read_data
arguments: label: D8
datatype: byte[16]
name: read_data
arguments: label: D0
datatype: string

tool: {"D18": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D8": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D0: Number missing array : %d 


assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 6, 7, 5, 8, 10};
  int n = findMissing(a, sizeof(a) / sizeof(int));
  printf("Number missing array : %d \n", n);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L15
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pad(char *string, int length) {
  int l;
  l = strlen(string);
  while (l < length) {
    string[l] = ' ';
    l++;
  }
  string[l] = '\0';
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L17
  movslq %eax,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rcx
  lea    -0x1(%rbx),%esi
  sub    %eax,%esi
  lea    (%rcx,%rsi,1),%rax
L16:
  movb   $0x20,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L16
L2:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %eax,%ebx
  jmp    L2
```

assistant: ```c
char *pad(char *string, int length) {
  int l;
  l = strlen(string);
  while (l < length) {
    string[l] = ' ';
    l++;
  }
  string[l] = '\0';
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pad>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L9
  lea    -0x1(%rbx),%edx
  mov    $0x20,%esi
  sub    %eax,%edx
  cltq
  lea    (%r12,%rax,1),%rdi
  add    $0x1,%rdx
  call   <memset@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movslq %eax,%rbx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *pad(char *string, int length) {
  int l;
  l = strlen(string);
  while (l < length) {
    string[l] = ' ';
    l++;
  }
  string[l] = '\0';
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pad>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L6
  lea    -0x1(%rbx),%edx
  mov    $0x20,%esi
  sub    %eax,%edx
  cltq
  lea    (%r12,%rax,1),%rdi
  add    $0x1,%rdx
  call   <memset@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movslq %eax,%rbx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *pad(char *string, int length) {
  int l;
  l = strlen(string);
  while (l < length) {
    string[l] = ' ';
    l++;
  }
  string[l] = '\0';
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <exgcd@plt>
  jmp    L6
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  js     L7
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
long long inverse(long long num, long long mod) {
  long long x, y;
  exgcd(num, mod, &x, &y);
  while (x < 0)
    x += mod, y -= num;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inverse>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <exgcd@plt>
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  jns    L13
L22:
  add    %rbx,%rax
  js     L22
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x20,%rsp
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long inverse(long long num, long long mod) {
  long long x, y;
  exgcd(num, mod, &x, &y);
  while (x < 0)
    x += mod, y -= num;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inverse>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <exgcd@plt>
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  jns    L17
  nopl   (%rax)
L11:
  add    %rbx,%rax
  js     L11
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x20,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long inverse(long long num, long long mod) {
  long long x, y;
  exgcd(num, mod, &x, &y);
  while (x < 0)
    x += mod, y -= num;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inverse>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <exgcd@plt>
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  jns    L8
  nopl   (%rax)
L15:
  add    %rbx,%rax
  js     L15
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long inverse(long long num, long long mod) {
  long long x, y;
  exgcd(num, mod, &x, &y);
  while (x < 0)
    x += mod, y -= num;
  return x;
}
```