ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<exclude_snp_sites_in_block>:
  endbr64
  push   %rbp
  mov    %rdx,%r9
  mov    %edi,%r8d
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L100
L18:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L18
L100:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L12
L29:
  mov    %rsp,%r10
  test   %ebx,%ebx
  jle    L0
  lea    -0x1(%rbx),%edx
  mov    %r9,%rax
  xor    %r12d,%r12d
  mov    %rdx,%r13
  lea    0x4(%r9,%rdx,4),%rdi
L84:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jg     L104
  cmp    %r8d,%edx
  jge    L37
L104:
  movslq %r12d,%rcx
  add    $0x1,%r12d
  mov    %edx,(%r10,%rcx,4)
L37:
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L84
  xor    %r14d,%r14d
  test   %r12d,%r12d
  je     L19
  movslq %r12d,%r14
  mov    %r9,%rdi
  mov    %r10,%rsi
  lea    0x0(,%r14,4),%rdx
  call   <memcpy@plt>
  mov    %rax,%r9
  cmp    %ebx,%r12d
  jge    L98
L19:
  sub    %r12d,%r13d
  lea    (%r9,%r14,4),%rdi
  xor    %esi,%esi
  lea    0x4(,%r13,4),%rdx
  call   <memset@plt>
L98:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  lea    -0x20(%rbp),%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L29
L0:
  xor    %r12d,%r12d
  jmp    L98
L106:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exclude_snp_sites_in_block(int window_start_coordinate, int window_end_coordinate, int *snp_site_coords, int number_of_branch_snps) {
  int i;
  int updated_snp_site_coords[number_of_branch_snps];
  int number_of_branch_snps_excluding_block = 0;
  for (i = 0; i < number_of_branch_snps; i++) {
    if (snp_site_coords[i] >= window_start_coordinate && snp_site_coords[i] <= window_end_coordinate) {
    } else {
      updated_snp_site_coords[number_of_branch_snps_excluding_block] = snp_site_coords[i];
      number_of_branch_snps_excluding_block++;
    }
  }
  for (i = 0; i < number_of_branch_snps_excluding_block; i++) {
    snp_site_coords[i] = updated_snp_site_coords[i];
  }
  for (i = number_of_branch_snps_excluding_block; i < number_of_branch_snps; i++) {
    snp_site_coords[i] = 0;
  }
  return number_of_branch_snps_excluding_block;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x1c,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x5,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct header {
    int one;
    int *two;
    int three;
  } * h;
  char *p;
  char *v = (char *)malloc(sizeof(struct header) + 4);
  h = (struct header *)v;
  h->one = 5;
  p = (char *)(h + 1);
  p++;
  p--;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  struct header {
    int one;
    int *two;
    int three;
  } * h;
  char *p;
  char *v = (char *)malloc(sizeof(struct header) + 4);
  h = (struct header *)v;
  h->one = 5;
  p = (char *)(h + 1);
  p++;
  p--;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct header {
    int one;
    int *two;
    int three;
  } * h;
  char *p;
  char *v = (char *)malloc(sizeof(struct header) + 4);
  h = (struct header *)v;
  h->one = 5;
  p = (char *)(h + 1);
  p++;
  p--;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct header {
    int one;
    int *two;
    int three;
  } * h;
  char *p;
  char *v = (char *)malloc(sizeof(struct header) + 4);
  h = (struct header *)v;
  h->one = 5;
  p = (char *)(h + 1);
  p++;
  p--;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L14
  mov    -0x8(%rbp),%eax
  cmp    $0x2,%eax
  jne    L14
  mov    -0x4(%rbp),%eax
  cmp    $0x3,%eax
  je     L25
L14:
  mov    $0x0,%eax
  call   <abort@plt>
L25:
  nop
  leave
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } x = {1, 2, 3};
  if (x.i != 1 || x.a.j != 2 || x.a.k != 3)
    abort();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } x = {1, 2, 3};
  if (x.i != 1 || x.a.j != 2 || x.a.k != 3)
    abort();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } x = {1, 2, 3};
  if (x.i != 1 || x.a.j != 2 || x.a.k != 3)
    abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } x = {1, 2, 3};
  if (x.i != 1 || x.a.j != 2 || x.a.k != 3)
    abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L2
L10:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  for (; str[length] != '\0'; length++)
    ;
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x0,%eax
L15:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L15
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  for (; str[length] != '\0'; length++)
    ;
  return length;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L5
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L15
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  for (; str[length] != '\0'; length++)
    ;
  return length;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L15
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  for (; str[length] != '\0'; length++)
    ;
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<realloce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <oom@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *realloce(void *ptr, size_t newsize) {
  void *ret;
  ret = realloc(ptr, newsize);
  if (!ret)
    oom();
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<realloce>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
L9:
  mov    $0x0,%eax
  call   <oom@plt>
  jmp    L5
```

assistant: ```c
void *realloce(void *ptr, size_t newsize) {
  void *ret;
  ret = realloc(ptr, newsize);
  if (!ret)
    oom();
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<realloce>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
L0:
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  xor    %eax,%eax
  call   <oom@plt>
  jmp    L0
```

assistant: ```c
void *realloce(void *ptr, size_t newsize) {
  void *ret;
  ret = realloc(ptr, newsize);
  if (!ret)
    oom();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<realloce>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L5:
  mov    %r12,%rax
  pop    %r12
  ret
L18:
  xor    %eax,%eax
  call   <oom@plt>
  jmp    L5
```

assistant: ```c
void *realloce(void *ptr, size_t newsize) {
  void *ret;
  ret = realloc(ptr, newsize);
  if (!ret)
    oom();
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<compareChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int compareChar(void *p1, void *p2) {
  char *c1 = (char *)p1;
  char *c2 = (char *)p2;
  return strcmp(c1, c2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compareChar>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compareChar(void *p1, void *p2) {
  char *c1 = (char *)p1;
  char *c2 = (char *)p2;
  return strcmp(c1, c2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compareChar>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int compareChar(void *p1, void *p2) {
  char *c1 = (char *)p1;
  char *c2 = (char *)p2;
  return strcmp(c1, c2);
}
```
user: What is the c source code of the assembly code below:

```asm
<compareChar>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int compareChar(void *p1, void *p2) {
  char *c1 = (char *)p1;
  char *c2 = (char *)p2;
  return strcmp(c1, c2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L26
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  jmp    L4
L26:
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] || s2[i]) {
    if (s1[i] != s2[i])
      return ((unsigned char)s1[i] - (unsigned char)s2[i]);
    i++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strcmp>:
  endbr64
  mov    $0x0,%eax
  jmp    L19
L30:
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  jne    L11
L19:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L30
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L7
L11:
  movzbl %dl,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] || s2[i]) {
    if (s1[i] != s2[i])
      return ((unsigned char)s1[i] - (unsigned char)s2[i]);
    i++;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strcmp>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L32:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L10
  test   %cl,%cl
  je     L26
L24:
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L32
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] || s2[i]) {
    if (s1[i] != s2[i])
      return ((unsigned char)s1[i] - (unsigned char)s2[i]);
    i++;
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strcmp>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L20:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L35
  test   %cl,%cl
  je     L17
L14:
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L20
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] || s2[i]) {
    if (s1[i] != s2[i])
      return ((unsigned char)s1[i] - (unsigned char)s2[i]);
    i++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  lea    -0x14(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ft_pn@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    $0xfffffffd,%eax
  jne    L40
  mov    $0x0,%eax
  jmp    L7
L40:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L3
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L5
L3:
  addl   $0x1,-0xc(%rbp)
  jmp    L5
L34:
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L87
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jg     L34
L87:
  mov    -0x14(%rbp),%eax
  cmp    $0xfffffffe,%eax
  jne    L98
  mov    -0x10(%rbp),%eax
  neg    %eax
  jmp    L7
L98:
  mov    -0x10(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int result;
  int p_n;
  int i;
  i = 0;
  p_n = 0;
  result = 0;
  i = ft_pn(str, &p_n, i);
  if (p_n == -3)
    return (0);
  if (str[i] == '-' || str[i] == '+')
    i++;
  while (str[i] <= 57 && str[i] >= 48) {
    result = result * 10 + str[i] - '0';
    i++;
  }
  if (p_n == -2)
    return (-result);
  else
    return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_atoi>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  call   <ft_pn@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%edi
  mov    $0x0,%eax
  cmp    $0xfffffffd,%edi
  je     L36
  movslq %edx,%rax
  movzbl (%rbx,%rax,1),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%edx
  movslq %edx,%rax
  movzbl (%rbx,%rax,1),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L21
  lea    0x1(%rbx,%rax,1),%rcx
  mov    $0x0,%eax
L26:
  lea    (%rax,%rax,4),%eax
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rax,2),%eax
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L26
L31:
  mov    %eax,%edx
  neg    %edx
  cmp    $0xfffffffe,%edi
  cmove  %edx,%eax
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L21:
  mov    $0x0,%eax
  jmp    L31
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(const char *str) {
  int result;
  int p_n;
  int i;
  i = 0;
  p_n = 0;
  result = 0;
  i = ft_pn(str, &p_n, i);
  if (p_n == -3)
    return (0);
  if (str[i] == '-' || str[i] == '+')
    i++;
  while (str[i] <= 57 && str[i] >= 48) {
    result = result * 10 + str[i] - '0';
    i++;
  }
  if (p_n == -2)
    return (-result);
  else
    return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_atoi>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <ft_pn@plt>
  mov    0x4(%rsp),%edi
  cmp    $0xfffffffd,%edi
  je     L21
  mov    %eax,%ecx
  cltq
  movsbl (%rbx,%rax,1),%edx
  lea    -0x2b(%rdx),%esi
  and    $0xfd,%esi
  je     L4
L12:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L60
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L63:
  lea    (%rax,%rax,4),%eax
  add    $0x1,%rcx
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L63
L10:
  mov    %eax,%edx
  neg    %edx
  cmp    $0xfffffffe,%edi
  cmove  %edx,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsbl (%rbx,%rax,1),%edx
  jmp    L12
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  jmp    L24
  nopl   0x0(%rax)
L60:
  xor    %eax,%eax
  jmp    L10
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(const char *str) {
  int result;
  int p_n;
  int i;
  i = 0;
  p_n = 0;
  result = 0;
  i = ft_pn(str, &p_n, i);
  if (p_n == -3)
    return (0);
  if (str[i] == '-' || str[i] == '+')
    i++;
  while (str[i] <= 57 && str[i] >= 48) {
    result = result * 10 + str[i] - '0';
    i++;
  }
  if (p_n == -2)
    return (-result);
  else
    return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_atoi>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <ft_pn@plt>
  mov    0x4(%rsp),%edi
  cmp    $0xfffffffd,%edi
  je     L1
  mov    %eax,%ecx
  cltq
  movsbl (%rbx,%rax,1),%edx
  lea    -0x2b(%rdx),%esi
  and    $0xfd,%esi
  je     L78
L19:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L30
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L20:
  lea    (%rax,%rax,4),%eax
  add    $0x1,%rcx
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L20
L32:
  mov    %eax,%edx
  neg    %edx
  cmp    $0xfffffffe,%edi
  cmove  %edx,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  add    $0x1,%ecx
  movslq %ecx,%rax
  movsbl (%rbx,%rax,1),%edx
  jmp    L19
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax)
L30:
  xor    %eax,%eax
  jmp    L32
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(const char *str) {
  int result;
  int p_n;
  int i;
  i = 0;
  p_n = 0;
  result = 0;
  i = ft_pn(str, &p_n, i);
  if (p_n == -3)
    return (0);
  if (str[i] == '-' || str[i] == '+')
    i++;
  while (str[i] <= 57 && str[i] >= 48) {
    result = result * 10 + str[i] - '0';
    i++;
  }
  if (p_n == -2)
    return (-result);
  else
    return (result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<debug_display_usertable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x79c0,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L26
L4:
  mov    -0x30(%rbp),%ecx
  lea    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <debug_display_fields@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x34(%rbp)
  addl   $0x1,-0x38(%rbp)
L26:
  cmpl   $0xf,-0x38(%rbp)
  jle    L4
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D27
type: string
name: read_data
arguments: tag: D15
type: string

tool: D22: User name

tool: D27: Encrypted Password

tool: D15: 


assistant: ```c
int debug_display_usertable() {
  const char *fields[] = {"User name", "Encrypted Password"};
  const int fields_len[] = {1, 1};
  int i, ptr;
  const int n_fields = 2;
  const int entry_size = 2;
  ptr = 31168;
  for (i = 0; i < 16; i++) {
    debug_display_fields(ptr, fields, fields_len, n_fields);
    printf("\n");
    ptr = ptr + entry_size;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<debug_display_usertable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D28(%rip),%rax
  mov    %rax,0x18(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  mov    $0x79c0,%ebx
  lea    D27(%rip),%rbp
L2:
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    $0x2,%ecx
  mov    %ebx,%edi
  call   <debug_display_fields@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    $0x79e0,%ebx
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x1,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string
name: extract_symbolic_data
arguments: data_tag: D27
type: string

tool: D19: User name

tool: D28: Encrypted Password

tool: D27: 


assistant: ```c
int debug_display_usertable() {
  const char *fields[] = {"User name", "Encrypted Password"};
  const int fields_len[] = {1, 1};
  int i, ptr;
  const int n_fields = 2;
  const int entry_size = 2;
  ptr = 31168;
  for (i = 0; i < 16; i++) {
    debug_display_fields(ptr, fields, fields_len, n_fields);
    printf("\n");
    ptr = ptr + entry_size;
  }
  return 1;
}
```