ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bernstein>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x18,%rsp
  cmp    %ebx,%esi
  setbe  %dil
  movsd  %xmm0,(%rsp)
  call   <assert@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  sub    %ebp,%ebx
  call   <binomial@plt>
  cvttsd2si (%rsp),%edi
  mov    %ebp,%esi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%esi
  mulsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  subsd  (%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: f64

tool: D2: 1

assistant: ```c
double bernstein(unsigned int n, unsigned int v, double x) {
  assert(v <= n);
  return binomial(n, v) * pow(x, v) * pow(1. - x, n - v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bernstein>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x18,%rsp
  cmp    %ebx,%esi
  setbe  %dil
  movsd  %xmm0,(%rsp)
  call   <assert@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  sub    %ebp,%ebx
  call   <binomial@plt>
  cvttsd2si (%rsp),%edi
  mov    %ebp,%esi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%esi
  mulsd  %xmm0,%xmm1
  movsd  D8(%rip),%xmm0
  subsd  (%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: f64

tool: D8: 1

assistant: ```c
double bernstein(unsigned int n, unsigned int v, double x) {
  assert(v <= n);
  return binomial(n, v) * pow(x, v) * pow(1. - x, n - v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Sum_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x30d4,%eax,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   $0x30d4,%eax,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Sum_array(int tid, int a[]) {
  int i;
  int sum = 0;
  for (i = tid * 100000 / 8; i < (tid + 1) * 100000 / 8; i++)
    sum += a[i];
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Sum_array>:
  endbr64
  imul   $0x30d4,%edi,%edi
  lea    0x30d4(%rdi),%edx
  movslq %edi,%rdi
  mov    $0x0,%eax
L7:
  add    (%rsi,%rdi,4),%eax
  add    $0x1,%rdi
  cmp    %edi,%edx
  jg     L7
  ret
```

assistant: ```c
int Sum_array(int tid, int a[]) {
  int i;
  int sum = 0;
  for (i = tid * 100000 / 8; i < (tid + 1) * 100000 / 8; i++)
    sum += a[i];
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Sum_array>:
  endbr64
  imul   $0x30d4,%edi,%edi
  xor    %eax,%eax
  lea    0x30d4(%rdi),%edx
  movslq %edi,%rdi
  nopl   (%rax)
L8:
  add    (%rsi,%rdi,4),%eax
  add    $0x1,%rdi
  cmp    %edi,%edx
  jg     L8
  ret
```

assistant: ```c
int Sum_array(int tid, int a[]) {
  int i;
  int sum = 0;
  for (i = tid * 100000 / 8; i < (tid + 1) * 100000 / 8; i++)
    sum += a[i];
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sum_array>:
  endbr64
  movslq %edi,%rdi
  pxor   %xmm0,%xmm0
  imul   $0xc350,%rdi,%rdi
  add    %rdi,%rsi
  lea    0xc350(%rsi),%rax
  nopl   0x0(%rax)
L0:
  movdqu (%rsi),%xmm2
  add    $0x10,%rsi
  paddd  %xmm2,%xmm0
  cmp    %rax,%rsi
  jne    L0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  ret
```

assistant: ```c
int Sum_array(int tid, int a[]) {
  int i;
  int sum = 0;
  for (i = tid * 100000 / 8; i < (tid + 1) * 100000 / 8; i++)
    sum += a[i];
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L9
L40:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D18(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <stdlib_base_rsqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L29
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L29:
  addl   $0x1,-0x24(%rbp)
L9:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L40
L47:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L28
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
data_type: f64
name: parse_data
arguments: label: D17
data_type: string

tool: D18: 100000

tool: D17: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = stdlib_base_rsqrt(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L11:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D10(%rip),%xmm0
  call   <stdlib_base_rsqrt@plt>
  ucomisd %xmm0,%xmm0
  jp     L16
  sub    $0x1,%ebx
  jne    L11
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L15
L16:
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L15:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_guessed: f64
name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D10: 100000

tool: D7: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = stdlib_base_rsqrt(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L9
  xchg   %ax,%ax
L8:
  sub    $0x1,%ebx
  je     L18
L9:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D19(%rip),%xmm0
  call   <stdlib_base_rsqrt@plt>
  ucomisd %xmm0,%xmm0
  jnp    L8
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: f64
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D19: 100000

tool: D15: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = stdlib_base_rsqrt(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L7
  xchg   %ax,%ax
L25:
  sub    $0x1,%ebx
  je     L5
L7:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D0(%rip),%xmm0
  call   <stdlib_base_rsqrt@plt>
  ucomisd %xmm0,%xmm0
  jnp    L25
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: f64
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D0: 100000

tool: D6: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = stdlib_base_rsqrt(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What is the c source code of the assembly code below?

```asm
<soChars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L6
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L15
L6:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0x1,%eax
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: 
Nome invalido!
Digite apenas letras!


assistant: ```c
int soChars(char *nome, int tamanho) {
  for (int i = 0; i < tamanho; i++) {
    if (isdigit(nome[i]) != 0) {
      printf("\nNome invalido!\nDigite apenas letras!\n");
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<soChars>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L12:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
  mov    $0x1,%eax
  jmp    L31
L13:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x1,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: 
Nome invalido!
Digite apenas letras!


assistant: ```c
int soChars(char *nome, int tamanho) {
  for (int i = 0; i < tamanho; i++) {
    if (isdigit(nome[i]) != 0) {
      printf("\nNome invalido!\nDigite apenas letras!\n");
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<soChars>:
  endbr64
  test   %esi,%esi
  jle    L33
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L6
L36:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L27
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L33:
  mov    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: 
Nome invalido!
Digite apenas letras!


assistant: ```c
int soChars(char *nome, int tamanho) {
  for (int i = 0; i < tamanho; i++) {
    if (isdigit(nome[i]) != 0) {
      printf("\nNome invalido!\nDigite apenas letras!\n");
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<soChars>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L24
L30:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L23
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: 
Nome invalido!
Digite apenas letras!


assistant: ```c
int soChars(char *nome, int tamanho) {
  for (int i = 0; i < tamanho; i++) {
    if (isdigit(nome[i]) != 0) {
      printf("\nNome invalido!\nDigite apenas letras!\n");
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbq -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  shrq   $0x3f,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char negative(signed char b) {
  unsigned long long x = b;
  x >>= 63;
  return (unsigned char)x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<negative>:
  endbr64
  movsbq %dil,%rax
  shr    $0x3f,%rax
  ret
```

assistant: ```c
unsigned char negative(signed char b) {
  unsigned long long x = b;
  x >>= 63;
  return (unsigned char)x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<negative>:
  endbr64
  movsbq %dil,%rax
  shr    $0x3f,%rax
  ret
```

assistant: ```c
unsigned char negative(signed char b) {
  unsigned long long x = b;
  x >>= 63;
  return (unsigned char)x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<negative>:
  endbr64
  movsbq %dil,%rax
  shr    $0x3f,%rax
  ret
```

assistant: ```c
unsigned char negative(signed char b) {
  unsigned long long x = b;
  x >>= 63;
  return (unsigned char)x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__cvmx_nand_get_address_cycles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__cvmx_nand_get_column_bits@plt>
  add    $0x7,%eax
  and    $0xfffffff8,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__cvmx_nand_get_row_bits@plt>
  add    $0x7,%eax
  and    $0xfffffff8,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x7,%eax
  sar    $0x3,%eax
  leave
  ret
```

assistant: ```c
int __cvmx_nand_get_address_cycles(int chip) {
  int address_bits = ((__cvmx_nand_get_column_bits(chip) + 7) >> 3) << 3;
  address_bits += ((__cvmx_nand_get_row_bits(chip) + 7) >> 3) << 3;
  return (address_bits + 7) >> 3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__cvmx_nand_get_address_cycles>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <__cvmx_nand_get_column_bits@plt>
  lea    0x7(%rax),%ebx
  and    $0xfffffff8,%ebx
  mov    %ebp,%edi
  call   <__cvmx_nand_get_row_bits@plt>
  add    $0x7,%eax
  and    $0xfffffff8,%eax
  lea    0x7(%rbx,%rax,1),%eax
  sar    $0x3,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __cvmx_nand_get_address_cycles(int chip) {
  int address_bits = ((__cvmx_nand_get_column_bits(chip) + 7) >> 3) << 3;
  address_bits += ((__cvmx_nand_get_row_bits(chip) + 7) >> 3) << 3;
  return (address_bits + 7) >> 3;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__cvmx_nand_get_address_cycles>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <__cvmx_nand_get_column_bits@plt>
  mov    %ebp,%edi
  lea    0x7(%rax),%ebx
  call   <__cvmx_nand_get_row_bits@plt>
  and    $0xfffffff8,%ebx
  add    $0x8,%rsp
  add    $0x7,%eax
  and    $0xfffffff8,%eax
  lea    0x7(%rbx,%rax,1),%eax
  pop    %rbx
  pop    %rbp
  sar    $0x3,%eax
  ret
```

assistant: ```c
int __cvmx_nand_get_address_cycles(int chip) {
  int address_bits = ((__cvmx_nand_get_column_bits(chip) + 7) >> 3) << 3;
  address_bits += ((__cvmx_nand_get_row_bits(chip) + 7) >> 3) << 3;
  return (address_bits + 7) >> 3;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__cvmx_nand_get_address_cycles>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <__cvmx_nand_get_column_bits@plt>
  mov    %ebp,%edi
  lea    0x7(%rax),%ebx
  call   <__cvmx_nand_get_row_bits@plt>
  and    $0xfffffff8,%ebx
  add    $0x8,%rsp
  add    $0x7,%eax
  and    $0xfffffff8,%eax
  lea    0x7(%rbx,%rax,1),%eax
  pop    %rbx
  pop    %rbp
  sar    $0x3,%eax
  ret
```

assistant: ```c
int __cvmx_nand_get_address_cycles(int chip) {
  int address_bits = ((__cvmx_nand_get_column_bits(chip) + 7) >> 3) << 3;
  address_bits += ((__cvmx_nand_get_row_bits(chip) + 7) >> 3) << 3;
  return (address_bits + 7) >> 3;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<blinkY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <blinkdash@plt>
  mov    $0x0,%eax
  call   <blinkdot@plt>
  mov    $0x0,%eax
  call   <blinkdash@plt>
  mov    $0x0,%eax
  call   <blinkdash@plt>
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  call   <sleep@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: f64

tool: D6: 1.5

assistant: ```c
int blinkY() {
  blinkdash();
  blinkdot();
  blinkdash();
  blinkdash();
  sleep(1.5);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<blinkY>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <blinkdash@plt>
  mov    $0x0,%eax
  call   <blinkdot@plt>
  mov    $0x0,%eax
  call   <blinkdash@plt>
  mov    $0x0,%eax
  call   <blinkdash@plt>
  movsd  D2(%rip),%xmm0
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: f64

tool: D2: 1.5

assistant: ```c
int blinkY() {
  blinkdash();
  blinkdot();
  blinkdash();
  blinkdash();
  sleep(1.5);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<blinkY>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <blinkdash@plt>
  xor    %eax,%eax
  call   <blinkdot@plt>
  xor    %eax,%eax
  call   <blinkdash@plt>
  xor    %eax,%eax
  call   <blinkdash@plt>
  movsd  D4(%rip),%xmm0
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: f64

tool: D4: 1.5

assistant: ```c
int blinkY() {
  blinkdash();
  blinkdot();
  blinkdash();
  blinkdash();
  sleep(1.5);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<blinkY>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <blinkdash@plt>
  xor    %eax,%eax
  call   <blinkdot@plt>
  xor    %eax,%eax
  call   <blinkdash@plt>
  xor    %eax,%eax
  call   <blinkdash@plt>
  movsd  D5(%rip),%xmm0
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: f64

tool: D5: 1.5

assistant: ```c
int blinkY() {
  blinkdash();
  blinkdot();
  blinkdash();
  blinkdash();
  sleep(1.5);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ax25_setsockopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8d,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x4c(%rbp),%eax
  cmp    $0x3,%eax
  ja     L2
  mov    $0xffffffea,%eax
  jmp    L34
L2:
  cmpl   $0x19,-0x40(%rbp)
  jne    L64
  cmpl   $0x10,-0x4c(%rbp)
  jle    L69
  movl   $0x10,-0x4c(%rbp)
L69:
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy_from_user@plt>
  test   %eax,%eax
  je     L64
  movl   $0xfffffff2,-0x24(%rbp)
  jmp    L26
L64:
  movl   $0xffffffa4,-0x24(%rbp)
L26:
  mov    -0x24(%rbp),%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
int ax25_setsockopt(struct socket *sock, int level, int optname, char *optval, int optlen) {
  char devname[16];
  int res = 0;
  if (optlen < sizeof(int))
    return -22;
  switch (optname) {
  case 25:
    if (optlen > 16)
      optlen = 16;
    if (copy_from_user(devname, optval, optlen)) {
      res = -14;
      break;
    }
  default:
    res = -92;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ax25_setsockopt>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xffffffea,%eax
  cmp    $0x3,%r8d
  jbe    L28
  mov    $0xffffffa4,%eax
  cmp    $0x19,%edx
  je     L24
L28:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x28,%rsp
  ret
L24:
  mov    $0x10,%eax
  cmp    %eax,%r8d
  cmovle %r8d,%eax
  mov    %eax,%edx
  mov    %rsp,%rdi
  mov    %rcx,%rsi
  call   <copy_from_user@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0xffffffb2,%eax
  sub    $0xe,%eax
  jmp    L28
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ax25_setsockopt(struct socket *sock, int level, int optname, char *optval, int optlen) {
  char devname[16];
  int res = 0;
  if (optlen < sizeof(int))
    return -22;
  switch (optname) {
  case 25:
    if (optlen > 16)
      optlen = 16;
    if (copy_from_user(devname, optval, optlen)) {
      res = -14;
      break;
    }
  default:
    res = -92;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ax25_setsockopt>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0xffffffea,%eax
  cmp    $0x3,%r8d
  jbe    L45
  cmp    $0x19,%edx
  je     L22
L43:
  mov    $0xffffffa4,%eax
L45:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x28,%rsp
  ret
L22:
  mov    $0x10,%eax
  mov    %rsp,%rdi
  mov    %rcx,%rsi
  cmp    %eax,%r8d
  cmovle %r8d,%eax
  mov    %eax,%edx
  call   <copy_from_user@plt>
  mov    %eax,%r8d
  mov    $0xfffffff2,%eax
  test   %r8d,%r8d
  jne    L45
  jmp    L43
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ax25_setsockopt(struct socket *sock, int level, int optname, char *optval, int optlen) {
  char devname[16];
  int res = 0;
  if (optlen < sizeof(int))
    return -22;
  switch (optname) {
  case 25:
    if (optlen > 16)
      optlen = 16;
    if (copy_from_user(devname, optval, optlen)) {
      res = -14;
      break;
    }
  default:
    res = -92;
  }
  return res;
}
```