ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  cmp    $0x1,%ebx
  je     L34
  mov    $0x1,%eax
  cmp    $0x2,%ebx
  je     L34
  mov    $0x0,%eax
  test   $0x1,%bl
  jne    L5
L34:
  pop    %rbx
  ret
L5:
  mov    %ebx,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L41
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L34
  mov    $0x3,%ecx
L85:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jl     L62
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L85
  jmp    L34
L62:
  mov    $0x1,%eax
  jmp    L34
L41:
  mov    $0x1,%eax
  jmp    L34
```

assistant: ```c
int is_prime(int i) {
  assert(i >= 0);
  if (i == 1)
    return 0;
  else if (i == 2)
    return 1;
  else if (i % 2 == 0)
    return 0;
  else {
    int k, limit;
    limit = (int)(ceil(sqrt(i)));
    for (k = 3; k <= limit; k += 2)
      if (i % k == 0)
        return 0;
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    $0x1,%r12d
  je     L65
  cmp    $0x2,%r12d
  je     L48
  test   $0x1,%r12b
  jne    L51
L65:
  xor    %eax,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L48
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L65
  mov    $0x3,%ecx
  jmp    L13
L42:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L65
L13:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L42
L48:
  mov    $0x1,%eax
  pop    %r12
  ret
```

assistant: ```c
int is_prime(int i) {
  assert(i >= 0);
  if (i == 1)
    return 0;
  else if (i == 2)
    return 1;
  else if (i % 2 == 0)
    return 0;
  else {
    int k, limit;
    limit = (int)(ceil(sqrt(i)));
    for (k = 3; k <= limit; k += 2)
      if (i % k == 0)
        return 0;
    return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    $0x1,%r12d
  je     L79
  cmp    $0x2,%r12d
  je     L8
  test   $0x1,%r12b
  jne    L59
L79:
  xor    %eax,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L8
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L79
  mov    $0x3,%ecx
  jmp    L69
L39:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L79
L69:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L39
L8:
  mov    $0x1,%eax
  pop    %r12
  ret
```

assistant: ```c
int is_prime(int i) {
  assert(i >= 0);
  if (i == 1)
    return 0;
  else if (i == 2)
    return 1;
  else if (i % 2 == 0)
    return 0;
  else {
    int k, limit;
    limit = (int)(ceil(sqrt(i)));
    for (k = 3; k <= limit; k += 2)
      if (i % k == 0)
        return 0;
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<X3D_getCurrentSpeed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4d,%edi
  call   <_X3D_makeShortCommand@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L2:
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D19: %f

tool: D9: client, error - problem reading float from %s


assistant: ```c
float X3D_getCurrentSpeed() {
  char *ptr;
  float curspeed;
  ptr = _X3D_makeShortCommand('M');
  if (sscanf(ptr, "%f", &curspeed) == 0) {
    printf("client, error - problem reading float from %s\n", ptr);
    exit(0);
  }
  return curspeed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<X3D_getCurrentSpeed>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4d,%edi
  call   <_X3D_makeShortCommand@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L19
L24:
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L24
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D19: %f

tool: D18: client, error - problem reading float from %s


assistant: ```c
float X3D_getCurrentSpeed() {
  char *ptr;
  float curspeed;
  ptr = _X3D_makeShortCommand('M');
  if (sscanf(ptr, "%f", &curspeed) == 0) {
    printf("client, error - problem reading float from %s\n", ptr);
    exit(0);
  }
  return curspeed;
}
```
user: What is the c source code of the assembly code below:

```asm
<X3D_getCurrentSpeed>:
  endbr64
  push   %rbp
  mov    $0x4d,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_X3D_makeShortCommand@plt>
  lea    0x4(%rsp),%rdx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sscanf@plt>
  test   %rax,%rax
  je     L20
L0:
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L0
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D1: %f

tool: D16: client, error - problem reading float from %s


assistant: ```c
float X3D_getCurrentSpeed() {
  char *ptr;
  float curspeed;
  ptr = _X3D_makeShortCommand('M');
  if (sscanf(ptr, "%f", &curspeed) == 0) {
    printf("client, error - problem reading float from %s\n", ptr);
    exit(0);
  }
  return curspeed;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<X3D_getCurrentSpeed>:
  endbr64
  push   %rbp
  mov    $0x4d,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_X3D_makeShortCommand@plt>
  lea    0x4(%rsp),%rdx
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sscanf@plt>
  test   %rax,%rax
  je     L27
L10:
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L10
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D4
type: string

tool: D11: %f

tool: D4: client, error - problem reading float from %s


assistant: ```c
float X3D_getCurrentSpeed() {
  char *ptr;
  float curspeed;
  ptr = _X3D_makeShortCommand('M');
  if (sscanf(ptr, "%f", &curspeed) == 0) {
    printf("client, error - problem reading float from %s\n", ptr);
    exit(0);
  }
  return curspeed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fltcompare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jbe    L13
  mov    $0x1,%eax
  jmp    L15
L13:
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L23
  mov    $0xffffffff,%eax
  jmp    L15
L23:
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int fltcompare(const void *_i, const void *_j) {
  const float *i = (const float *)_i;
  const float *j = (const float *)_j;
  if (*i > *j)
    return (1);
  if (*i < *j)
    return (-1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fltcompare>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L0
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  neg    %eax
L0:
  ret
```

assistant: ```c
int fltcompare(const void *_i, const void *_j) {
  const float *i = (const float *)_i;
  const float *j = (const float *)_j;
  if (*i > *j)
    return (1);
  if (*i < *j)
    return (-1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fltcompare>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L5
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  neg    %eax
L5:
  ret
```

assistant: ```c
int fltcompare(const void *_i, const void *_j) {
  const float *i = (const float *)_i;
  const float *j = (const float *)_j;
  if (*i > *j)
    return (1);
  if (*i < *j)
    return (-1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fltcompare>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L2
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  neg    %eax
L2:
  ret
```

assistant: ```c
int fltcompare(const void *_i, const void *_j) {
  const float *i = (const float *)_i;
  const float *j = (const float *)_j;
  if (*i > *j)
    return (1);
  if (*i < *j)
    return (-1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<number_of_permissible_single_bp_moves>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L20
L25:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    $0x1,%eax
  jne    L2
  mov    -0x18(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    $0x1,%eax
  jne    L2
  addl   $0x1,-0xc(%rbp)
L2:
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L25
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int number_of_permissible_single_bp_moves(int x, int y, int *k, int *l, int length) {
  int j, a, b, num_moves = 0;
  for (j = 0; j < length; ++j) {
    a = k[j];
    b = l[j];
    if ((int)abs(x - a) == 1 && (int)abs(y - b) == 1) {
      num_moves++;
    }
  }
  return num_moves;
}
```
user: What is the c source code of the assembly code below:

```asm
<number_of_permissible_single_bp_moves>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %r8d,%r8d
  jle    L0
  mov    %edi,%r12d
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  lea    -0x1(%r8),%eax
  lea    0x4(%rdx,%rax,4),%r14
  mov    $0x0,%r15d
  jmp    L9
L42:
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %r14,%rbx
  je     L36
L9:
  mov    0x0(%rbp),%r13d
  mov    %r12d,%edi
  sub    (%rbx),%edi
  call   <abs@plt>
  cmp    $0x1,%eax
  jne    L42
  mov    0xc(%rsp),%edi
  sub    %r13d,%edi
  call   <abs@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%r15d
  jmp    L42
L0:
  mov    $0x0,%r15d
L36:
  mov    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int number_of_permissible_single_bp_moves(int x, int y, int *k, int *l, int length) {
  int j, a, b, num_moves = 0;
  for (j = 0; j < length; ++j) {
    a = k[j];
    b = l[j];
    if ((int)abs(x - a) == 1 && (int)abs(y - b) == 1) {
      num_moves++;
    }
  }
  return num_moves;
}
```
user: Translate the below assembly code into C programming language:

```asm
<number_of_permissible_single_bp_moves>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %r8d,%r8d
  jle    L15
  lea    -0x1(%r8),%eax
  mov    %edi,%ebp
  mov    %rdx,%rbx
  mov    %rcx,%r15
  lea    0x4(%rdx,%rax,4),%r13
  xor    %r14d,%r14d
  jmp    L19
  nopl   0x0(%rax)
L54:
  add    $0x4,%rbx
  add    $0x4,%r15
  cmp    %r13,%rbx
  je     L26
L19:
  mov    %ebp,%edi
  sub    (%rbx),%edi
  mov    (%r15),%r12d
  call   <abs@plt>
  cmp    $0x1,%eax
  jne    L54
  mov    0xc(%rsp),%edi
  sub    %r12d,%edi
  call   <abs@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x4,%rbx
  add    $0x4,%r15
  movzbl %al,%eax
  add    %eax,%r14d
  cmp    %r13,%rbx
  jne    L19
L26:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L15:
  xor    %r14d,%r14d
  jmp    L26
```

assistant: ```c
int number_of_permissible_single_bp_moves(int x, int y, int *k, int *l, int length) {
  int j, a, b, num_moves = 0;
  for (j = 0; j < length; ++j) {
    a = k[j];
    b = l[j];
    if ((int)abs(x - a) == 1 && (int)abs(y - b) == 1) {
      num_moves++;
    }
  }
  return num_moves;
}
```
user: Translate the below assembly code into C programming language:

```asm
<number_of_permissible_single_bp_moves>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %r8d,%r8d
  jle    L6
  lea    -0x1(%r8),%eax
  mov    %edi,%ebp
  mov    %rdx,%rbx
  mov    %rcx,%r15
  lea    0x4(%rdx,%rax,4),%r13
  xor    %r14d,%r14d
  jmp    L7
  nopl   0x0(%rax)
L52:
  add    $0x4,%rbx
  add    $0x4,%r15
  cmp    %r13,%rbx
  je     L23
L7:
  mov    %ebp,%edi
  sub    (%rbx),%edi
  mov    (%r15),%r12d
  call   <abs@plt>
  cmp    $0x1,%eax
  jne    L52
  mov    0xc(%rsp),%edi
  sub    %r12d,%edi
  call   <abs@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x4,%rbx
  add    $0x4,%r15
  movzbl %al,%eax
  add    %eax,%r14d
  cmp    %r13,%rbx
  jne    L7
L23:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L6:
  xor    %r14d,%r14d
  jmp    L23
```

assistant: ```c
int number_of_permissible_single_bp_moves(int x, int y, int *k, int *l, int length) {
  int j, a, b, num_moves = 0;
  for (j = 0; j < length; ++j) {
    a = k[j];
    b = l[j];
    if ((int)abs(x - a) == 1 && (int)abs(y - b) == 1) {
      num_moves++;
    }
  }
  return num_moves;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<disp_name_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L16:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L16
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1:  %s


assistant: ```c
void disp_name_array(char **name_array) {
  while (*name_array)
    printf(" %s\n", *name_array++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<disp_name_array>:
  endbr64
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D0(%rip),%rbp
L13:
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0:  %s


assistant: ```c
void disp_name_array(char **name_array) {
  while (*name_array)
    printf(" %s\n", *name_array++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<disp_name_array>:
  endbr64
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L16
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2:  %s


assistant: ```c
void disp_name_array(char **name_array) {
  while (*name_array)
    printf(" %s\n", *name_array++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<disp_name_array>:
  endbr64
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L18
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8:  %s


assistant: ```c
void disp_name_array(char **name_array) {
  while (*name_array)
    printf(" %s\n", *name_array++);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L13
L27:
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L23
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L27
L23:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L56
  mov    -0x8(%rbp),%rax
  jmp    L42
L35:
  addl   $0x1,-0x10(%rbp)
L56:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  je     L48
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L35
L48:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
L42:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: 

assistant: ```c
char *getValue(char *line) {
  int i = 0, j = 0, len = strlen(line);
  char *result = malloc(1024);
  strcpy(result, "");
  while (line[i] != '(' && line[i] != '\n')
    i++;
  j = ++i;
  if (i >= len)
    return result;
  while (line[j] != ')' && line[i] != '\n')
    j++;
  line[j] = '\0';
  strcat(result, line + i);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movzbl (%rbx),%eax
  cmp    $0x28,%al
  je     L99
  cmp    $0xa,%al
  je     L99
  mov    $0x1,%eax
L87:
  mov    %eax,%ecx
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x28,%dl
  je     L94
  cmp    $0xa,%dl
  jne    L87
L94:
  add    $0x1,%ecx
  cmp    %ecx,%r12d
  jle    L20
  movslq %ecx,%rcx
  lea    (%rbx,%rcx,1),%rsi
  movzbl (%rsi),%edx
  cmp    $0x29,%dl
  je     L24
  lea    0x1(%rbx,%rcx,1),%rax
  mov    %rsi,%rcx
L71:
  cmp    $0xa,%dl
  je     L11
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x29,-0x1(%rax)
  jne    L71
L11:
  movb   $0x0,(%rcx)
  mov    %rbp,%rdi
  call   <strcat@plt>
L20:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L99:
  mov    $0x0,%ecx
  jmp    L94
L24:
  mov    %rsi,%rcx
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string

tool: 

assistant: ```c
char *getValue(char *line) {
  int i = 0, j = 0, len = strlen(line);
  char *result = malloc(1024);
  strcpy(result, "");
  while (line[i] != '(' && line[i] != '\n')
    i++;
  j = ++i;
  if (i >= len)
    return result;
  while (line[j] != ')' && line[i] != '\n')
    j++;
  line[j] = '\0';
  strcat(result, line + i);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x400,%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movzbl (%rbx),%eax
  cmp    $0x28,%al
  je     L93
  cmp    $0xa,%al
  je     L93
  mov    $0x1,%eax
  xchg   %ax,%ax
L19:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%ecx
  add    $0x1,%rax
  cmp    $0x28,%dl
  je     L75
  cmp    $0xa,%dl
  jne    L19
L75:
  add    $0x1,%ecx
L70:
  cmp    %ecx,%ebp
  jle    L31
  movslq %ecx,%rcx
  lea    (%rbx,%rcx,1),%r8
  movzbl (%r8),%esi
  cmp    $0x29,%sil
  je     L47
  lea    0x1(%rbx,%rcx,1),%rax
  mov    %r8,%rdx
  mov    %rax,%rcx
  sub    %r8,%rcx
  jmp    L57
  nopl   0x0(%rax)
L84:
  add    $0x1,%rax
  add    %rcx,%rdx
  cmpb   $0x29,-0x1(%rax)
  je     L23
L57:
  cmp    $0xa,%sil
  jne    L84
L23:
  movb   $0x0,(%rdx)
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L31:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L93:
  mov    $0x1,%ecx
  jmp    L70
L47:
  mov    %r8,%rdx
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: 

assistant: ```c
char *getValue(char *line) {
  int i = 0, j = 0, len = strlen(line);
  char *result = malloc(1024);
  strcpy(result, "");
  while (line[i] != '(' && line[i] != '\n')
    i++;
  j = ++i;
  if (i >= len)
    return result;
  while (line[j] != ')' && line[i] != '\n')
    j++;
  line[j] = '\0';
  strcat(result, line + i);
  return result;
}
```