ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  nop
L34:
  xor    %ebp,%ebp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  adc    $0x0,%ebp
  cmp    $0x3,%ebp
  je     L45
  cmp    $0x2,%ebp
  jne    L26
  cmp    %ebx,%r12d
  jne    L26
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L26:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L2
L45:
  add    $0x1,%r12d
  add    $0x1,%r13d
  cmp    $0x65,%r12d
  jne    L34
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: %d	

assistant: ```c
int main() {
  int number = 0;
  int temp = 0;
  int counter = 0;
  for (number = 1; number <= 100; number++) {
    for (temp = 1; temp <= number; temp++) {
      if (number % temp == 0) {
        counter++;
      }
      if (counter > 2) {
        break;
      } else if (counter == 2 && temp == number) {
        printf("%d\t", number);
      }
    }
    counter = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x40(%rbp)
  jle    L77
  mov    $0x0,%r15d
  lea    D24(%rip),%r14
  jmp    L111
L10:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L52
  orq    $0x0,-0x8(%rsp,%rax,1)
L52:
  lea    0x7(%rsp),%rax
  mov    %rax,%rdi
  shr    $0x3,%rdi
  mov    %rdi,-0x50(%rbp)
  and    $0xfffffffffffffff8,%rax
  mov    %rax,%r12
  mov    %rax,-0x58(%rbp)
  test   %edx,%edx
  jle    L65
  mov    $0x0,%ebx
  mov    $0x0,%r13d
L113:
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    (%r12),%rbx
  add    $0x1,%r13d
  mov    -0x3c(%rbp),%ecx
  add    $0x8,%r12
  cmp    %r13d,%ecx
  jg     L113
  test   %ecx,%ecx
  jle    L65
  mov    -0x50(%rbp),%rax
  mov    0x0(,%rax,8),%rdx
  sub    %rdx,%rbx
  je     L81
  mov    -0x58(%rbp),%rdi
  lea    0x8(%rdi),%rax
  mov    %ecx,%ecx
  lea    (%rdi,%rcx,8),%rsi
  mov    $0x0,%ecx
L94:
  add    %rdx,%rcx
  cmp    %rsi,%rax
  je     L65
  mov    (%rax),%rdx
  sub    %rdx,%rbx
  add    $0x8,%rax
  cmp    %rcx,%rbx
  jne    L94
L81:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L65:
  lea    D40(%rip),%rdi
  call   <printf@plt>
L33:
  mov    -0x48(%rbp),%rsp
  add    $0x1,%r15d
  cmp    %r15d,-0x40(%rbp)
  jle    L77
L111:
  mov    %rsp,-0x48(%rbp)
  lea    -0x3c(%rbp),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L86:
  cmp    %rcx,%rsp
  je     L10
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L86
L77:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D24
data_type: string
name: read_data
arguments: label: D30
data_type: string
name: read_data
arguments: label: D40
data_type: string

tool: D19: %d

tool: D24: %ld

tool: D30: YES


tool: D40: NO


assistant: ```c
int main() {
  int t, n, i, j, k, l, flag = 0;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    long int a[n], s1 = 0, s2 = 0;
    long long int b = 0;
    for (j = 0; j < n; j++) {
      scanf("%ld", &a[j]);
      b += a[j];
    }
    for (j = 0; j < n; j++) {
      s2 = b - a[j];
      b = s2;
      if (s1 == s2) {
        printf("YES\n");
        flag = 1;
        break;
      }
      s1 += a[j];
    }
    if (flag == 0)
      printf("NO\n");
    flag = 0;
    s1 = 0;
    s2 = 0;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<max_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jg     L0
  mov    $0x0,%eax
  jmp    L34
L0:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L32:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L32
  mov    -0x18(%rbp),%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int max_product(int *nums, int nums_size) {
  if (nums_size <= 0) {
    return 0;
  }
  int max, min_at, max_at, min_at_prev, max_at_prev;
  int i;
  max = min_at = max_at = nums[0];
  for (i = 1; i < nums_size; ++i) {
    min_at_prev = min_at;
    max_at_prev = max_at;
    min_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? min_at_prev * nums[i] : max_at_prev * nums[i];
    min_at = min_at < nums[i] ? min_at : nums[i];
    max_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? max_at_prev * nums[i] : min_at_prev * nums[i];
    max_at = max_at < nums[i] ? nums[i] : max_at;
    max = max < max_at ? max_at : max;
  }
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_product>:
  endbr64
  mov    $0x0,%r9d
  test   %esi,%esi
  jle    L27
  mov    (%rdi),%r9d
  cmp    $0x1,%esi
  jle    L27
  lea    0x4(%rdi),%r8
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%rdi
  mov    %r9d,%eax
  mov    %r9d,%ecx
L16:
  mov    (%r8),%edx
  imul   %edx,%eax
  imul   %edx,%ecx
  mov    %ecx,%esi
  cmp    %ecx,%eax
  cmovle %eax,%ecx
  cmp    %ecx,%edx
  cmovle %edx,%ecx
  cmp    %esi,%eax
  cmovl  %esi,%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  cmp    %eax,%r9d
  cmovl  %eax,%r9d
  add    $0x4,%r8
  cmp    %rdi,%r8
  jne    L16
L27:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int max_product(int *nums, int nums_size) {
  if (nums_size <= 0) {
    return 0;
  }
  int max, min_at, max_at, min_at_prev, max_at_prev;
  int i;
  max = min_at = max_at = nums[0];
  for (i = 1; i < nums_size; ++i) {
    min_at_prev = min_at;
    max_at_prev = max_at;
    min_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? min_at_prev * nums[i] : max_at_prev * nums[i];
    min_at = min_at < nums[i] ? min_at : nums[i];
    max_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? max_at_prev * nums[i] : min_at_prev * nums[i];
    max_at = max_at < nums[i] ? nums[i] : max_at;
    max = max < max_at ? max_at : max;
  }
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max_product>:
  endbr64
  xor    %r9d,%r9d
  test   %esi,%esi
  jle    L19
  mov    (%rdi),%ecx
  cmp    $0x1,%esi
  je     L17
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%r8
  mov    %ecx,%r9d
  lea    0x8(%rdi,%rax,4),%rdi
  mov    %ecx,%eax
  nopl   0x0(%rax,%rax,1)
L22:
  mov    (%r8),%edx
  imul   %edx,%eax
  imul   %edx,%ecx
  cmp    %ecx,%eax
  mov    %ecx,%esi
  cmovle %eax,%ecx
  cmp    %ecx,%edx
  cmovle %edx,%ecx
  cmp    %esi,%eax
  cmovl  %esi,%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  cmp    %eax,%r9d
  cmovl  %eax,%r9d
  add    $0x4,%r8
  cmp    %r8,%rdi
  jne    L22
L19:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %ecx,%r9d
  jmp    L19
```

assistant: ```c
int max_product(int *nums, int nums_size) {
  if (nums_size <= 0) {
    return 0;
  }
  int max, min_at, max_at, min_at_prev, max_at_prev;
  int i;
  max = min_at = max_at = nums[0];
  for (i = 1; i < nums_size; ++i) {
    min_at_prev = min_at;
    max_at_prev = max_at;
    min_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? min_at_prev * nums[i] : max_at_prev * nums[i];
    min_at = min_at < nums[i] ? min_at : nums[i];
    max_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? max_at_prev * nums[i] : min_at_prev * nums[i];
    max_at = max_at < nums[i] ? nums[i] : max_at;
    max = max < max_at ? max_at : max;
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<max_product>:
  endbr64
  xor    %r9d,%r9d
  test   %esi,%esi
  jle    L26
  mov    (%rdi),%ecx
  cmp    $0x1,%esi
  je     L3
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%r8
  mov    %ecx,%r9d
  lea    0x8(%rdi,%rax,4),%rdi
  mov    %ecx,%eax
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%r8),%edx
  imul   %edx,%eax
  imul   %edx,%ecx
  cmp    %ecx,%eax
  mov    %ecx,%esi
  cmovle %eax,%ecx
  cmp    %ecx,%edx
  cmovle %edx,%ecx
  cmp    %esi,%eax
  cmovl  %esi,%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  cmp    %eax,%r9d
  cmovl  %eax,%r9d
  add    $0x4,%r8
  cmp    %r8,%rdi
  jne    L27
L26:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ecx,%r9d
  jmp    L26
```

assistant: ```c
int max_product(int *nums, int nums_size) {
  if (nums_size <= 0) {
    return 0;
  }
  int max, min_at, max_at, min_at_prev, max_at_prev;
  int i;
  max = min_at = max_at = nums[0];
  for (i = 1; i < nums_size; ++i) {
    min_at_prev = min_at;
    max_at_prev = max_at;
    min_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? min_at_prev * nums[i] : max_at_prev * nums[i];
    min_at = min_at < nums[i] ? min_at : nums[i];
    max_at = min_at_prev * nums[i] < max_at_prev * nums[i] ? max_at_prev * nums[i] : min_at_prev * nums[i];
    max_at = max_at < nums[i] ? nums[i] : max_at;
    max = max < max_at ? max_at : max;
  }
  return max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%r14d
  mov    %r14d,%ecx
  mov    $0x0,%r13d
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_inits@plt>
  mov    $0x2,%ebp
  movq   $0x0,0x8(%rsp)
  jmp    L54
L23:
  mov    %ebx,%esi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r14d,0x4(%rsp)
  mov    %r14d,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebx,%esi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <mpz_set@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r13d,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r14d,%edi
  call   <mpz_sub_ui@plt>
  mov    0x4(%rsp),%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_mul@plt>
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_mul@plt>
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_mul@plt>
  mov    %ebx,%edi
  call   <mpz_perfect_square_p@plt>
  test   %rax,%rax
  je     L25
  mov    (%rsp),%eax
  add    %r12d,%eax
  cltq
  add    %rax,0x8(%rsp)
  jmp    L25
L46:
  add    $0x1,%ebp
  cmp    $0x13de4355,%ebp
  je     L18
L54:
  lea    0x0(%rbp,%rbp,1),%eax
  mov    %eax,(%rsp)
  lea    -0x1(%rbp),%r12d
  lea    0x3(%rbp),%r15d
L19:
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_set_ui@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_add_ui@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_add_ui@plt>
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_add_ui@plt>
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_cdiv_q_ui@plt>
  test   %rax,%rax
  je     L23
L25:
  add    $0x2,%r12d
  cmp    %r15d,%r12d
  jne    L19
  jmp    L46
L18:
  mov    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: %llu


assistant: ```c
int main(int argc, char **argv) {
  mpz_t s, sa, sb, sc;
  mpz_inits(s, sa, sb, sc, 0);
  const long max = 1000000000;
  unsigned long long sum = 0;
  for (int a = 2; a < max / 3; ++a) {
    for (int j = -1; j <= 1; j += 2) {
      const int b = a;
      const int c = a + j;
      mpz_set_ui(s, 0);
      mpz_add_ui(s, s, a);
      mpz_add_ui(s, s, b);
      mpz_add_ui(s, s, c);
      if (mpz_cdiv_q_ui(s, s, 2) == 0) {
        mpz_set(sa, s);
        mpz_sub_ui(sa, sa, a);
        mpz_set(sb, s);
        mpz_sub_ui(sb, sb, b);
        mpz_set(sc, s);
        mpz_sub_ui(sc, sc, c);
        mpz_mul(s, s, sa);
        mpz_mul(s, s, sb);
        mpz_mul(s, s, sc);
        if (mpz_perfect_square_p(s)) {
          sum += a + b + c;
        }
      }
    }
  }
  printf("%llu\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %r14
  xor    %esi,%esi
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  call   <mpz_inits@plt>
  movq   $0x0,0x8(%rsp)
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x2,%r12d
  cmp    %r13d,%r12d
  jne    L40
  add    $0x1,%ebx
  cmp    $0x13de4355,%ebx
  je     L57
L13:
  lea    (%rbx,%rbx,1),%eax
  lea    -0x1(%rbx),%r12d
  mov    %eax,(%rsp)
  lea    0x3(%rbx),%r13d
L40:
  xor    %ebp,%ebp
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <mpz_set_ui@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add_ui@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add_ui@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add_ui@plt>
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_cdiv_q_ui@plt>
  test   %rax,%rax
  jne    L15
  xor    %r15d,%r15d
  mov    %ebp,%esi
  xor    %r14d,%r14d
  mov    %r15d,%edi
  call   <mpz_set@plt>
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r15d,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r14d,%edi
  call   <mpz_sub_ui@plt>
  xor    %r11d,%r11d
  mov    %ebp,%esi
  mov    %r11d,%edi
  mov    %r11d,0x4(%rsp)
  call   <mpz_set@plt>
  mov    0x4(%rsp),%r11d
  mov    %r12d,%edx
  mov    %r11d,%esi
  mov    %r11d,%edi
  call   <mpz_sub_ui@plt>
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    0x4(%rsp),%edx
  mov    %ebp,%edi
  mov    %ebp,%esi
  call   <mpz_mul@plt>
  mov    %ebp,%edi
  call   <mpz_perfect_square_p@plt>
  test   %rax,%rax
  je     L15
  mov    (%rsp),%eax
  add    %r12d,%eax
  cltq
  add    %rax,0x8(%rsp)
  jmp    L15
L57:
  mov    0x8(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: %llu


assistant: ```c
int main(int argc, char **argv) {
  mpz_t s, sa, sb, sc;
  mpz_inits(s, sa, sb, sc, 0);
  const long max = 1000000000;
  unsigned long long sum = 0;
  for (int a = 2; a < max / 3; ++a) {
    for (int j = -1; j <= 1; j += 2) {
      const int b = a;
      const int c = a + j;
      mpz_set_ui(s, 0);
      mpz_add_ui(s, s, a);
      mpz_add_ui(s, s, b);
      mpz_add_ui(s, s, c);
      if (mpz_cdiv_q_ui(s, s, 2) == 0) {
        mpz_set(sa, s);
        mpz_sub_ui(sa, sa, a);
        mpz_set(sb, s);
        mpz_sub_ui(sb, sb, b);
        mpz_set(sc, s);
        mpz_sub_ui(sc, sc, c);
        mpz_mul(s, s, sa);
        mpz_mul(s, s, sb);
        mpz_mul(s, s, sc);
        if (mpz_perfect_square_p(s)) {
          sum += a + b + c;
        }
      }
    }
  }
  printf("%llu\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %r14
  xor    %esi,%esi
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  call   <mpz_inits@plt>
  movq   $0x0,0x8(%rsp)
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x2,%r12d
  cmp    %r13d,%r12d
  jne    L52
  add    $0x1,%ebx
  cmp    $0x13de4355,%ebx
  je     L21
L48:
  lea    (%rbx,%rbx,1),%eax
  lea    -0x1(%rbx),%r12d
  mov    %eax,(%rsp)
  lea    0x3(%rbx),%r13d
L52:
  xor    %ebp,%ebp
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <mpz_set_ui@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add_ui@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add_ui@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add_ui@plt>
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_cdiv_q_ui@plt>
  test   %rax,%rax
  jne    L14
  xor    %r15d,%r15d
  mov    %ebp,%esi
  xor    %r14d,%r14d
  mov    %r15d,%edi
  call   <mpz_set@plt>
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r15d,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r14d,%edi
  call   <mpz_sub_ui@plt>
  xor    %r11d,%r11d
  mov    %ebp,%esi
  mov    %r11d,%edi
  mov    %r11d,0x4(%rsp)
  call   <mpz_set@plt>
  mov    0x4(%rsp),%r11d
  mov    %r12d,%edx
  mov    %r11d,%esi
  mov    %r11d,%edi
  call   <mpz_sub_ui@plt>
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    0x4(%rsp),%edx
  mov    %ebp,%edi
  mov    %ebp,%esi
  call   <mpz_mul@plt>
  mov    %ebp,%edi
  call   <mpz_perfect_square_p@plt>
  test   %rax,%rax
  je     L14
  mov    (%rsp),%eax
  add    %r12d,%eax
  cltq
  add    %rax,0x8(%rsp)
  jmp    L14
L21:
  mov    0x8(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: %llu


assistant: ```c
int main(int argc, char **argv) {
  mpz_t s, sa, sb, sc;
  mpz_inits(s, sa, sb, sc, 0);
  const long max = 1000000000;
  unsigned long long sum = 0;
  for (int a = 2; a < max / 3; ++a) {
    for (int j = -1; j <= 1; j += 2) {
      const int b = a;
      const int c = a + j;
      mpz_set_ui(s, 0);
      mpz_add_ui(s, s, a);
      mpz_add_ui(s, s, b);
      mpz_add_ui(s, s, c);
      if (mpz_cdiv_q_ui(s, s, 2) == 0) {
        mpz_set(sa, s);
        mpz_sub_ui(sa, sa, a);
        mpz_set(sb, s);
        mpz_sub_ui(sb, sb, b);
        mpz_set(sc, s);
        mpz_sub_ui(sc, sc, c);
        mpz_mul(s, s, sa);
        mpz_mul(s, s, sb);
        mpz_mul(s, s, sc);
        if (mpz_perfect_square_p(s)) {
          sum += a + b + c;
        }
      }
    }
  }
  printf("%llu\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drawMaze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L49:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L41
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L41:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0xc,-0x4(%rbp)
  jle    L49
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L51:
  cmpl   $0xc,-0x8(%rbp)
  jle    L11
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string

tool: D28: # 

tool: D20:   

tool: D26: 


assistant: ```c
void drawMaze(int (*maze)[13]) {
  int i, j;
  for (i = 0; i < 13; i++) {
    for (j = 0; j < 13; j++) {
      if (maze[i][j] == 1)
        printf("# ");
      else
        printf("  ");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<drawMaze>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x34(%rdi),%rbp
  lea    0x2d8(%rdi),%r14
  lea    D1(%rip),%r12
  lea    D3(%rip),%r13
  lea    D17(%rip),%r15
  jmp    L24
L5:
  mov    %r13,%rdi
  call   <printf@plt>
L51:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L25
L3:
  cmpl   $0x1,(%rbx)
  je     L5
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L51
L25:
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x34,%rbp
  cmp    %r14,%rbp
  je     L28
L24:
  lea    -0x34(%rbp),%rbx
  jmp    L3
L28:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D1:   

tool: D3: # 

tool: D17: 


assistant: ```c
void drawMaze(int (*maze)[13]) {
  int i, j;
  for (i = 0; i < 13; i++) {
    for (j = 0; j < 13; j++) {
      if (maze[i][j] == 1)
        printf("# ");
      else
        printf("  ");
    }
    printf("\n");
  }
  printf("\n");
}
```