ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L81:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L81
  cmp    $0x20,%al
  je     L81
  movb   $0x0,0x1(%rbp)
  movsbl %al,%r12d
  mov    %r12d,%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L94
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L132
  lea    -0x2d(%rbx),%eax
  cmp    $0x1,%eax
  ja     L69
L132:
  mov    $0x0,%r13d
  cmp    $0x2d,%ebx
  je     L186
L148:
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L178
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L124:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L124
L178:
  cmp    $0x2e,%ebx
  je     L32
L64:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D1(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L5
  mov    $0x30,%ebx
L69:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L94:
  add    $0x1,%rbp
L119:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  mov    %rbp,%rbx
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <islower@plt>
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L119
  movb   $0x0,(%rbx)
  mov    $0x31,%ebx
  mov    D1(%rip),%rax
  cmp    %r12d,(%rax)
  je     L69
  mov    %r12d,%edi
  call   <ungetch@plt>
  jmp    L69
L186:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  mov    %al,0x1(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L174
  mov    %r12d,%ebx
  mov    $0x1,%r13d
  jmp    L148
L174:
  mov    %r12d,%edi
  call   <ungetch@plt>
  jmp    L69
L32:
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L153:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L153
  jmp    L64
L5:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L69
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  i = 0;
  if (islower(c)) {
    while (islower(s[++i] = c = getch()))
      ;
    s[i] = '\0';
    if (c != EOF)
      ungetch(c);
    return '1';
  }
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  if (c == '-')
    if (!isdigit(s[++i] = c = getch())) {
      ungetch(c);
      return '-';
    }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<examples>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rdi
  mov    -0x8(%rbp),%rsi
  mov    -0x8(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x8(%rbp)
  push   -0x8(%rbp)
  push   -0x8(%rbp)
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D9: 
Request activation for Office 2013 using V4 protocol from 192.168.1.5:1688
	%s -l "Office 2013 Professional" -4 192.168.1.5
	%s -l "Office 2013 Professional" -4 192.168.1.5:1688

Request activation for Windows Server 2012 using V4 protocol from localhost:1688
	%s -4 -l "Windows Server 2012" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac
	%s -4 -l "Windows Server 2012"
	%s -4 -l "Windows Server 2012" [::1]:1688
	%s -4 -l "Windows Server 2012" 127.0.0.2:1688

Send 100,000 requests to localhost:1688
	%s -n 100000

Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer
	%s -l "Windows 8 Professional" -w steveb1.redmond.microsoft.com 10.0.0.1:4711



assistant: ```c
__attribute__((noreturn)) void examples(const char *const programName) {
  printf("\nRequest activation for Office 2013 using V4 protocol from 192.168.1.5:1688\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5:1688\n\n"
         "Request activation for Windows Server 2012 using V4 protocol from localhost:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac\n"
         "\t%s -4 -l \"Windows Server 2012\"\n"
         "\t%s -4 -l \"Windows Server 2012\" [::1]:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" 127.0.0.2:1688\n\n"
         "Send 100,000 requests to localhost:1688\n"
         "\t%s -n 100000\n\n"
         "Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer\n"
         "\t%s -l \"Windows 8 Professional\" -w steveb1.redmond.microsoft.com 10.0.0.1:4711\n\n",
         programName, programName, programName, programName, programName, programName, programName, programName);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<examples>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x10,%rsp
  mov    %rdi,%rsi
  push   %rdi
  push   %rdi
  push   %rdi
  mov    %rdi,%r9
  mov    %rdi,%r8
  mov    %rdi,%rcx
  mov    %rdi,%rdx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string

tool: D8: 
Request activation for Office 2013 using V4 protocol from 192.168.1.5:1688
	%s -l "Office 2013 Professional" -4 192.168.1.5
	%s -l "Office 2013 Professional" -4 192.168.1.5:1688

Request activation for Windows Server 2012 using V4 protocol from localhost:1688
	%s -4 -l "Windows Server 2012" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac
	%s -4 -l "Windows Server 2012"
	%s -4 -l "Windows Server 2012" [::1]:1688
	%s -4 -l "Windows Server 2012" 127.0.0.2:1688

Send 100,000 requests to localhost:1688
	%s -n 100000

Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer
	%s -l "Windows 8 Professional" -w steveb1.redmond.microsoft.com 10.0.0.1:4711



assistant: ```c
__attribute__((noreturn)) void examples(const char *const programName) {
  printf("\nRequest activation for Office 2013 using V4 protocol from 192.168.1.5:1688\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5:1688\n\n"
         "Request activation for Windows Server 2012 using V4 protocol from localhost:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac\n"
         "\t%s -4 -l \"Windows Server 2012\"\n"
         "\t%s -4 -l \"Windows Server 2012\" [::1]:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" 127.0.0.2:1688\n\n"
         "Send 100,000 requests to localhost:1688\n"
         "\t%s -n 100000\n\n"
         "Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer\n"
         "\t%s -l \"Windows 8 Professional\" -w steveb1.redmond.microsoft.com 10.0.0.1:4711\n\n",
         programName, programName, programName, programName, programName, programName, programName, programName);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<examples>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x10,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%r9
  mov    %rdi,%r8
  push   %rdi
  mov    %rdi,%rcx
  mov    %rdi,%rdx
  push   %rdi
  push   %rdi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  xor    %edi,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7: 
Request activation for Office 2013 using V4 protocol from 192.168.1.5:1688
	%s -l "Office 2013 Professional" -4 192.168.1.5
	%s -l "Office 2013 Professional" -4 192.168.1.5:1688

Request activation for Windows Server 2012 using V4 protocol from localhost:1688
	%s -4 -l "Windows Server 2012" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac
	%s -4 -l "Windows Server 2012"
	%s -4 -l "Windows Server 2012" [::1]:1688
	%s -4 -l "Windows Server 2012" 127.0.0.2:1688

Send 100,000 requests to localhost:1688
	%s -n 100000

Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer
	%s -l "Windows 8 Professional" -w steveb1.redmond.microsoft.com 10.0.0.1:4711



assistant: ```c
__attribute__((noreturn)) void examples(const char *const programName) {
  printf("\nRequest activation for Office 2013 using V4 protocol from 192.168.1.5:1688\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5:1688\n\n"
         "Request activation for Windows Server 2012 using V4 protocol from localhost:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac\n"
         "\t%s -4 -l \"Windows Server 2012\"\n"
         "\t%s -4 -l \"Windows Server 2012\" [::1]:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" 127.0.0.2:1688\n\n"
         "Send 100,000 requests to localhost:1688\n"
         "\t%s -n 100000\n\n"
         "Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer\n"
         "\t%s -l \"Windows 8 Professional\" -w steveb1.redmond.microsoft.com 10.0.0.1:4711\n\n",
         programName, programName, programName, programName, programName, programName, programName, programName);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<examples>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x10,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%r9
  mov    %rdi,%r8
  push   %rdi
  mov    %rdi,%rcx
  mov    %rdi,%rdx
  push   %rdi
  push   %rdi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  xor    %edi,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: 
Request activation for Office 2013 using V4 protocol from 192.168.1.5:1688
	%s -l "Office 2013 Professional" -4 192.168.1.5
	%s -l "Office 2013 Professional" -4 192.168.1.5:1688

Request activation for Windows Server 2012 using V4 protocol from localhost:1688
	%s -4 -l "Windows Server 2012" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac
	%s -4 -l "Windows Server 2012"
	%s -4 -l "Windows Server 2012" [::1]:1688
	%s -4 -l "Windows Server 2012" 127.0.0.2:1688

Send 100,000 requests to localhost:1688
	%s -n 100000

Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer
	%s -l "Windows 8 Professional" -w steveb1.redmond.microsoft.com 10.0.0.1:4711



assistant: ```c
__attribute__((noreturn)) void examples(const char *const programName) {
  printf("\nRequest activation for Office 2013 using V4 protocol from 192.168.1.5:1688\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5\n"
         "\t%s -l \"Office 2013 Professional\" -4 192.168.1.5:1688\n\n"
         "Request activation for Windows Server 2012 using V4 protocol from localhost:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" -k 8665cb71-468c-4aa3-a337-cb9bc9d5eaac\n"
         "\t%s -4 -l \"Windows Server 2012\"\n"
         "\t%s -4 -l \"Windows Server 2012\" [::1]:1688\n"
         "\t%s -4 -l \"Windows Server 2012\" 127.0.0.2:1688\n\n"
         "Send 100,000 requests to localhost:1688\n"
         "\t%s -n 100000\n\n"
         "Request Activation for Windows 8 from 10.0.0.1:4711 and pretend to be Steve Ballmer\n"
         "\t%s -l \"Windows 8 Professional\" -w steveb1.redmond.microsoft.com 10.0.0.1:4711\n\n",
         programName, programName, programName, programName, programName, programName, programName, programName);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fnMatchAny>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L16:
  movl   $0x0,-0x4(%rbp)
  jmp    L52
L24:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L20
  mov    -0x8(%rbp),%eax
  jmp    L7
L20:
  addl   $0x1,-0x4(%rbp)
L52:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L24
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L16
  mov    $0xffffffff,%eax
L7:
  leave
  ret
```

assistant: ```c
int fnMatchAny(char s1[], char s2[]) {
  int i, j;
  for (i = 0; i < strlen(s1); i++) {
    for (j = 0; j < strlen(s2); j++) {
      if (s1[i] == s2[j])
        return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fnMatchAny>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    $0x0,%r12d
L24:
  mov    %r12d,%r14d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L10
  mov    $0x0,%ebx
L43:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L49
  add    $0x1,%rbx
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    %al,0x0(%r13,%r12,1)
  jne    L43
L42:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  add    $0x1,%r12
  jmp    L24
L10:
  mov    $0xffffffff,%r14d
  jmp    L42
```

assistant: ```c
int fnMatchAny(char s1[], char s2[]) {
  int i, j;
  for (i = 0; i < strlen(s1); i++) {
    for (j = 0; j < strlen(s2); j++) {
      if (s1[i] == s2[j])
        return i;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fnMatchAny>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r13,%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%r14d
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L27
L38:
  xor    %ebx,%ebx
  jmp    L30
  nopl   0x0(%rax)
L29:
  add    $0x1,%rbx
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    %al,0x0(%r13,%r12,1)
  je     L32
L30:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L29
  add    $0x1,%r12
  mov    %r13,%rdi
  mov    %r12d,%r14d
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L38
L27:
  mov    $0xffffffff,%r14d
L32:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fnMatchAny(char s1[], char s2[]) {
  int i, j;
  for (i = 0; i < strlen(s1); i++) {
    for (j = 0; j < strlen(s2); j++) {
      if (s1[i] == s2[j])
        return i;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fnMatchAny>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r13,%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%r14d
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L13
L10:
  xor    %ebx,%ebx
  jmp    L41
  nopl   0x0(%rax)
L34:
  add    $0x1,%rbx
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    %al,0x0(%r13,%r12,1)
  je     L3
L41:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L34
  add    $0x1,%r12
  mov    %r13,%rdi
  mov    %r12d,%r14d
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L10
L13:
  mov    $0xffffffff,%r14d
L3:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fnMatchAny(char s1[], char s2[]) {
  int i, j;
  for (i = 0; i < strlen(s1); i++) {
    for (j = 0; j < strlen(s2); j++) {
      if (s1[i] == s2[j])
        return i;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r12
  lea    0x4(%rsp),%rbp
  lea    D14(%rip),%rbx
  lea    D17(%rip),%r13
  jmp    L114
L12:
  add    $0x1,%r9d
  cmp    %cx,%r9w
  ja     L101
L107:
  movzwl %r9w,%eax
  imul   $0xcccd,%eax,%eax
  shr    $0x13,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %r9d,%r10d
  sub    %edi,%r10d
  movzwl %ax,%edi
  imul   $0xcccd,%edi,%edi
  shr    $0x13,%edi
  lea    (%rdi,%rdi,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  mov    %r9d,%edi
  shr    $0x2,%di
  movzwl %di,%edi
  imul   $0x147b,%edi,%edi
  shr    $0x11,%edi
  movzwl %di,%r8d
  imul   $0xcccd,%r8d,%r8d
  shr    $0x13,%r8d
  lea    (%r8,%r8,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  cmp    %al,%r10b
  je     L12
  cmp    %dil,%r10b
  je     L12
  mov    %r9d,%r8d
  shr    $0x3,%r8w
  movzwl %r8w,%r8d
  imul   $0x20c5,%r8d,%r8d
  shr    $0x14,%r8d
  cmp    %r8b,%r10b
  je     L12
  cmp    %dil,%al
  je     L12
  cmp    %r8b,%al
  je     L12
  cmp    %r8b,%dil
  setne  %al
  cmp    $0x1,%al
  sbb    $0xffff,%si
  jmp    L12
L41:
  mov    $0x0,%esi
L101:
  movzwl %cx,%ecx
  movzwl %dx,%edx
  movzwl %si,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L114:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L3
  movzwl 0x4(%rsp),%edx
  movzwl 0x6(%rsp),%ecx
  cmp    %cx,%dx
  ja     L41
  mov    %edx,%r9d
  mov    $0x0,%esi
  jmp    L107
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: D14: %hu %hu

tool: D17: There are %hu non-repeating years between %hu and %hu.


assistant: ```c
int main(void) {
  unsigned short begin, end;
  while (scanf("%hu %hu", &begin, &end) == 2) {
    unsigned short counter = 0;
    for (unsigned short i = begin; i <= end; i++) {
      char a = i % 10;
      char b = (i / 10) % 10;
      char c = (i / 100) % 10;
      char d = i / 1000;
      if (!(a == b || a == c || a == d || b == c || b == d || c == d))
        counter++;
    }
    printf("There are %hu non-repeating years between %hu and %hu.\n", counter, begin, end);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r12
  lea    0x4(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L84:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L109
  movzwl 0x4(%rsp),%edx
  movzwl 0x6(%rsp),%ecx
  cmp    %cx,%dx
  ja     L50
  mov    %edx,%r9d
  xor    %esi,%esi
  nop
L36:
  movzwl %r9w,%eax
  mov    %r9d,%r10d
  imul   $0xcccd,%eax,%eax
  shr    $0x13,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%r10d
  movzwl %ax,%edi
  imul   $0xcccd,%edi,%edi
  shr    $0x13,%edi
  lea    (%rdi,%rdi,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  mov    %r9d,%edi
  shr    $0x2,%di
  movzwl %di,%edi
  imul   $0x147b,%edi,%edi
  shr    $0x11,%edi
  movzwl %di,%r8d
  imul   $0xcccd,%r8d,%r8d
  shr    $0x13,%r8d
  lea    (%r8,%r8,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  cmp    %al,%r10b
  je     L77
  cmp    %dil,%r10b
  je     L77
  mov    %r9d,%r8d
  shr    $0x3,%r8w
  movzwl %r8w,%r8d
  imul   $0x20c5,%r8d,%r8d
  shr    $0x14,%r8d
  cmp    %r8b,%r10b
  je     L77
  cmp    %dil,%al
  je     L77
  cmp    %r8b,%al
  je     L77
  cmp    %r8b,%dil
  setne  %al
  cmp    $0x1,%al
  sbb    $0xffff,%si
  nopl   0x0(%rax,%rax,1)
L77:
  add    $0x1,%r9d
  cmp    %cx,%r9w
  jbe    L36
  movzwl %si,%esi
L67:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L84
  cs nopw 0x0(%rax,%rax,1)
L109:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L50:
  xor    %esi,%esi
  jmp    L67
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D0: There are %hu non-repeating years between %hu and %hu.


tool: D11: %hu %hu

assistant: ```c
int main(void) {
  unsigned short begin, end;
  while (scanf("%hu %hu", &begin, &end) == 2) {
    unsigned short counter = 0;
    for (unsigned short i = begin; i <= end; i++) {
      char a = i % 10;
      char b = (i / 10) % 10;
      char c = (i / 100) % 10;
      char d = i / 1000;
      if (!(a == b || a == c || a == d || b == c || b == d || c == d))
        counter++;
    }
    printf("There are %hu non-repeating years between %hu and %hu.\n", counter, begin, end);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %d  

assistant: ```c
void print_primes(int prime[], int length) {
  int i;
  for (i = 0; i < length; i++)
    if (prime[i] == 1)
      printf("%d  ", i);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L36
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
  jmp    L2
L5:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L36
L2:
  mov    %ebx,%esi
  cmpl   $0x1,(%r12,%rbx,4)
  jne    L5
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: %d  

assistant: ```c
void print_primes(int prime[], int length) {
  int i;
  for (i = 0; i < length; i++)
    if (prime[i] == 1)
      printf("%d  ", i);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_primes>:
  endbr64
  test   %esi,%esi
  jle    L38
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L5
L7:
  cmpl   $0x1,(%r12,%rbx,4)
  mov    %ebx,%esi
  jne    L20
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L7
L5:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L38:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %d  

assistant: ```c
void print_primes(int prime[], int length) {
  int i;
  for (i = 0; i < length; i++)
    if (prime[i] == 1)
      printf("%d  ", i);
  printf("\n");
}
```