user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ecx
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rsi
  sub    %rdx,%rsi
L99:
  cmp    %rsi,%rsp
  je     L35
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L99
L35:
  mov    %rdi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L205
  orq    $0x0,-0x8(%rsp,%rdx,1)
L205:
  mov    %rsp,%rbx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L203:
  cmp    %rsi,%rsp
  je     L179
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L203
L179:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L124
  orq    $0x0,-0x8(%rsp,%rax,1)
L124:
  lea    0x3(%rsp),%r12
  mov    %r12,%rax
  shr    $0x2,%rax
  mov    %rax,-0x48(%rbp)
  and    $0xfffffffffffffffc,%r12
  test   %ecx,%ecx
  jle    L14
  mov    %rbx,%r14
  mov    $0x0,%r13d
  lea    D24(%rip),%r15
L1:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  add    $0x1,%r13d
  mov    -0x3c(%rbp),%r9d
  add    $0x4,%r14
  cmp    %r13d,%r9d
  jg     L1
  test   %r9d,%r9d
  jle    L201
  mov    -0x48(%rbp),%rax
  movl   $0x1,0x0(,%rax,4)
  lea    0x4(%r12),%r10
  mov    $0x4,%ecx
  mov    $0x0,%r8d
  jmp    L53
L123:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L23
L151:
  cmp    (%rbx,%rax,1),%esi
  jle    L123
  mov    (%r12,%rax,1),%edx
  cmp    (%rdi),%edx
  jl     L123
  add    $0x1,%edx
  mov    %edx,(%rdi)
  jmp    L123
L23:
  add    $0x4,%r10
  add    $0x4,%rcx
L53:
  add    $0x1,%r8d
  cmp    %r8d,%r9d
  je     L207
  mov    %r10,%rdi
  movl   $0x1,(%r10)
  test   %r8d,%r8d
  jle    L23
  mov    (%rbx,%rcx,1),%esi
  mov    $0x0,%eax
  jmp    L151
L207:
  mov    -0x48(%rbp),%rax
  mov    0x0(,%rax,4),%esi
  mov    %r12,%rax
  mov    %r9d,%r9d
  lea    (%r12,%r9,4),%rcx
L187:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L187
L3:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L201:
  mov    -0x48(%rbp),%rax
  movl   $0x1,0x0(,%rax,4)
  jmp    L95
L14:
  mov    -0x48(%rbp),%rax
  movl   $0x1,0x0(,%rax,4)
L95:
  mov    -0x48(%rbp),%rax
  mov    0x0(,%rax,4),%esi
  jmp    L3
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D24
type_guessed: string

tool: D24: %d

assistant: ```c
int main() {
  int n, i, p, j, k, m;
  scanf("%d", &n);
  int a[n];
  int MaxTill[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  MaxTill[0] = 1;
  for (j = 0; j < n; j++) {
    MaxTill[j] = 1;
    for (m = 0; m < j; m++) {
      if (a[j] > a[m]) {
        if (1 + MaxTill[m] > MaxTill[j]) {
          MaxTill[j] = MaxTill[m] + 1;
        }
      }
    }
  }
  m = MaxTill[0];
  for (p = 0; p < n; p++) {
    if (MaxTill[p] > m)
      m = MaxTill[p];
  }
  printf("%d", m);
}
```