ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<getFileExt>:
  endbr64
  push   %rbp
  mov    $0x2e,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L33
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  cmp    %rax,%rbx
  jae    L21
L33:
  add    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <scalloc@plt>
  cs nopw 0x0(%rax,%rax,1)
L21:
  lea    0x1(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <smalloc@plt>
  movslq %ebp,%rdx
  sub    $0x1,%ebp
  movb   $0x0,(%rax,%rdx,1)
  movslq %ebp,%rcx
  js     L35
  nopw   0x0(%rax,%rax,1)
L28:
  movzbl 0x1(%rbx,%rcx,1),%edx
  lea    -0x41(%rdx),%edi
  lea    -0x1a(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jns    L28
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getFileExt(char *path) {
  char *ext, *point = strrchr(path, '.');
  int extLen;
  if (!point || point < strrchr(path, '/'))
    return scalloc(1, 1);
  point++;
  ext = smalloc((extLen = strlen(point)) + 1);
  ext[extLen] = 0;
  for (point += --extLen; extLen >= 0; point--)
    ext[extLen--] = ('A' <= *point && *point <= 'Z') ? ((*point) - 26) : *point;
  return ext;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getFileExt>:
  endbr64
  push   %rbp
  mov    $0x2e,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L37
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  cmp    %rax,%rbx
  jae    L34
L37:
  add    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <scalloc@plt>
  cs nopw 0x0(%rax,%rax,1)
L34:
  lea    0x1(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <smalloc@plt>
  movslq %ebp,%rdx
  sub    $0x1,%ebp
  movb   $0x0,(%rax,%rdx,1)
  movslq %ebp,%rdx
  js     L5
  nopw   0x0(%rax,%rax,1)
L49:
  movzbl 0x1(%rbx,%rdx,1),%ecx
  lea    -0x41(%rcx),%esi
  cmp    $0x19,%sil
  ja     L3
  sub    $0x1a,%ecx
  mov    %cl,(%rax,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L49
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %cl,(%rax,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L49
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getFileExt(char *path) {
  char *ext, *point = strrchr(path, '.');
  int extLen;
  if (!point || point < strrchr(path, '/'))
    return scalloc(1, 1);
  point++;
  ext = smalloc((extLen = strlen(point)) + 1);
  ext[extLen] = 0;
  for (point += --extLen; extLen >= 0; point--)
    ext[extLen--] = ('A' <= *point && *point <= 'Z') ? ((*point) - 26) : *point;
  return ext;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    $0x8,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char getByte(unsigned char *inp, unsigned int bitpos) {
  unsigned char *addr;
  addr = inp + (bitpos >> 3);
  return (addr[0] << (bitpos & 7)) | (addr[1] >> (8 - (bitpos & 7)));
}
```
user: What is the c source code of the assembly code below?

```asm
<getByte>:
  endbr64
  mov    %esi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  add    %rax,%rdi
  and    $0x7,%esi
  movzbl 0x1(%rdi),%eax
  mov    $0x8,%ecx
  sub    %esi,%ecx
  sar    %cl,%eax
  movzbl (%rdi),%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char getByte(unsigned char *inp, unsigned int bitpos) {
  unsigned char *addr;
  addr = inp + (bitpos >> 3);
  return (addr[0] << (bitpos & 7)) | (addr[1] >> (8 - (bitpos & 7)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getByte>:
  endbr64
  mov    %esi,%eax
  mov    $0x8,%ecx
  and    $0x7,%esi
  shr    $0x3,%eax
  sub    %esi,%ecx
  add    %rax,%rdi
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  sar    %cl,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char getByte(unsigned char *inp, unsigned int bitpos) {
  unsigned char *addr;
  addr = inp + (bitpos >> 3);
  return (addr[0] << (bitpos & 7)) | (addr[1] >> (8 - (bitpos & 7)));
}
```
user: What is the c source code of the assembly code below?

```asm
<getByte>:
  endbr64
  mov    %esi,%eax
  mov    $0x8,%ecx
  and    $0x7,%esi
  shr    $0x3,%eax
  sub    %esi,%ecx
  add    %rax,%rdi
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  sar    %cl,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char getByte(unsigned char *inp, unsigned int bitpos) {
  unsigned char *addr;
  addr = inp + (bitpos >> 3);
  return (addr[0] << (bitpos & 7)) | (addr[1] >> (8 - (bitpos & 7)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  D10(%rip),%xmm0
  mov    D22(%rip),%rax
  mov    $0x1,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <aster@plt>
  movsd  D17(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <moi@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: f64
name: retrieve_data
arguments: tag: D22
type_guessed: f64
name: retrieve_data
arguments: tag: D17
type_guessed: f64

tool: D10: 0.2

tool: D22: 0.5

tool: D17: 3.14159265

assistant: ```c
int main() {
  float color = aster(0.5, 0.2, 1) * 3.14159265;
  return moi(1, 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  movsd  D18(%rip),%xmm1
  movsd  D0(%rip),%xmm0
  call   <aster@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <moi@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: f64
name: parse_data
arguments: tag: D0
type_infered: f64

tool: D18: 0.2

tool: D0: 0.5

assistant: ```c
int main() {
  float color = aster(0.5, 0.2, 1) * 3.14159265;
  return moi(1, 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D5(%rip),%xmm1
  mov    $0x1,%edi
  movsd  D2(%rip),%xmm0
  call   <aster@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <moi@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: f64
name: disassemble_data
arguments: label: D2
type_infered: f64

tool: D5: 0.2

tool: D2: 0.5

assistant: ```c
int main() {
  float color = aster(0.5, 0.2, 1) * 3.14159265;
  return moi(1, 2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D17(%rip),%xmm1
  mov    $0x1,%edi
  movsd  D10(%rip),%xmm0
  call   <aster@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <moi@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D10
data_type: f64

tool: D17: 0.2

tool: D10: 0.5

assistant: ```c
int main() {
  float color = aster(0.5, 0.2, 1) * 3.14159265;
  return moi(1, 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L8
L12:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L8:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  jne    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero(uint8_t *b, uint16_t len) {
  while (len--)
    b[len] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zero>:
  endbr64
  lea    -0x1(%rsi),%rax
  test   %rsi,%rsi
  je     L8
L11:
  movq   $0x0,(%rdi,%rax,8)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L11
L8:
  ret
```

assistant: ```c
void zero(uint8_t *b, uint16_t len) {
  while (len--)
    b[len] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zero>:
  endbr64
  test   %rsi,%rsi
  je     L2
  lea    0x0(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void zero(uint8_t *b, uint16_t len) {
  while (len--)
    b[len] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<zero>:
  endbr64
  test   %rsi,%rsi
  je     L3
  lea    0x0(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void zero(uint8_t *b, uint16_t len) {
  while (len--)
    b[len] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  je     L9
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  mov    $0x0,%eax
  call   <check@plt>
  mov    $0x0,%eax
  call   <exec@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: You need to be uid 0


assistant: ```c
int main() {
  if (geteuid()) {
    printf("You need to be uid 0\n");
    exit(1);
  }
  check();
  exec();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  jne    L19
L12:
  mov    $0x0,%eax
  call   <check@plt>
  mov    $0x0,%eax
  call   <exec@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L19:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: You need to be uid 0


assistant: ```c
int main() {
  if (geteuid()) {
    printf("You need to be uid 0\n");
    exit(1);
  }
  check();
  exec();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  jne    L16
L13:
  xor    %eax,%eax
  call   <check@plt>
  xor    %eax,%eax
  call   <exec@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L16:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: You need to be uid 0


assistant: ```c
int main() {
  if (geteuid()) {
    printf("You need to be uid 0\n");
    exit(1);
  }
  check();
  exec();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  jne    L5
L4:
  xor    %eax,%eax
  call   <check@plt>
  xor    %eax,%eax
  call   <exec@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L5:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: You need to be uid 0


assistant: ```c
int main() {
  if (geteuid()) {
    printf("You need to be uid 0\n");
    exit(1);
  }
  check();
  exec();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D49
type_guessed: string
name: retrieve_data
arguments: label: D56
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string

tool: D22: 
Digite um numero para o valor 1: 

tool: D20: %d

tool: D49: Digite um numero para o valor 2: 

tool: D56: 
valor 1: %d

tool: D14: 
valor 2: %d


assistant: ```c
void main() {
  int valor_1, valor_2;
  printf("\nDigite um numero para o valor 1: ");
  scanf("%d", &valor_1);
  printf("Digite um numero para o valor 2: ");
  scanf("%d", &valor_2);
  printf("\nvalor 1: %d", valor_1);
  printf("\nvalor 2: %d\n", valor_2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D25(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D25
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D24
type_guessed: string
name: disassemble_data
arguments: data_tag: D36
type_guessed: string

tool: D26: 
Digite um numero para o valor 1: 

tool: D25: %d

tool: D7: Digite um numero para o valor 2: 

tool: D24: 
valor 1: %d

tool: D36: 
valor 2: %d


assistant: ```c
void main() {
  int valor_1, valor_2;
  printf("\nDigite um numero para o valor 1: ");
  scanf("%d", &valor_1);
  printf("Digite um numero para o valor 2: ");
  scanf("%d", &valor_2);
  printf("\nvalor 1: %d", valor_1);
  printf("\nvalor 2: %d\n", valor_2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  lea    D23(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D30
type_guessed: string
name: retrieve_data
arguments: data_tag: D28
type_guessed: string
name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D26: 
Digite um numero para o valor 1: 

tool: D23: %d

tool: D30: Digite um numero para o valor 2: 

tool: D28: 
valor 1: %d

tool: D7: 
valor 2: %d


assistant: ```c
void main() {
  int valor_1, valor_2;
  printf("\nDigite um numero para o valor 1: ");
  scanf("%d", &valor_1);
  printf("Digite um numero para o valor 2: ");
  scanf("%d", &valor_2);
  printf("\nvalor 1: %d", valor_1);
  printf("\nvalor 2: %d\n", valor_2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D22(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string
name: parse_data
arguments: tag: D32
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D12: 
Digite um numero para o valor 1: 

tool: D22: %d

tool: D38: Digite um numero para o valor 2: 

tool: D32: 
valor 1: %d

tool: D14: 
valor 2: %d


assistant: ```c
void main() {
  int valor_1, valor_2;
  printf("\nDigite um numero para o valor 1: ");
  scanf("%d", &valor_1);
  printf("Digite um numero para o valor 2: ");
  scanf("%d", &valor_2);
  printf("\nvalor 1: %d", valor_1);
  printf("\nvalor 2: %d\n", valor_2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<display_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <deasplay_hal_init@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <display_set_cursor@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void display_init(void) {
  deasplay_hal_init();
  display_set_cursor(0, 0);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <deasplay_hal_init@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <display_set_cursor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void display_init(void) {
  deasplay_hal_init();
  display_set_cursor(0, 0);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <deasplay_hal_init@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <display_set_cursor@plt>
```

assistant: ```c
void display_init(void) {
  deasplay_hal_init();
  display_set_cursor(0, 0);
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<display_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <deasplay_hal_init@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <display_set_cursor@plt>
```

assistant: ```c
void display_init(void) {
  deasplay_hal_init();
  display_set_cursor(0, 0);
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<appendStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L9:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rsi
  mov    -0x8(%rbp),%rcx
  mov    %rsi,(%rcx)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void appendStr(char **pDstStr, char *srcStr) {
  while (*(*pDstStr)++ = *srcStr++)
    ;
  (*pDstStr)--;
  **pDstStr = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<appendStr>:
  endbr64
L4:
  add    $0x1,%rsi
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rdi)
  movzbl -0x1(%rsi),%eax
  mov    %al,(%rdx)
  test   %al,%al
  jne    L4
  mov    (%rdi),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0x0,-0x1(%rax)
  ret
```

assistant: ```c
void appendStr(char **pDstStr, char *srcStr) {
  while (*(*pDstStr)++ = *srcStr++)
    ;
  (*pDstStr)--;
  **pDstStr = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<appendStr>:
  endbr64
  nopl   0x0(%rax)
L3:
  mov    (%rdi),%rdx
  add    $0x1,%rsi
  lea    0x1(%rdx),%rax
  mov    %rax,(%rdi)
  movzbl -0x1(%rsi),%eax
  mov    %al,(%rdx)
  test   %al,%al
  jne    L3
  mov    (%rdi),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0x0,-0x1(%rax)
  ret
```

assistant: ```c
void appendStr(char **pDstStr, char *srcStr) {
  while (*(*pDstStr)++ = *srcStr++)
    ;
  (*pDstStr)--;
  **pDstStr = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<appendStr>:
  endbr64
  nopl   0x0(%rax)
L2:
  mov    (%rdi),%rdx
  add    $0x1,%rsi
  lea    0x1(%rdx),%rax
  mov    %rax,(%rdi)
  movzbl -0x1(%rsi),%eax
  mov    %al,(%rdx)
  test   %al,%al
  jne    L2
  mov    (%rdi),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0x0,-0x1(%rax)
  ret
```

assistant: ```c
void appendStr(char **pDstStr, char *srcStr) {
  while (*(*pDstStr)++ = *srcStr++)
    ;
  (*pDstStr)--;
  **pDstStr = 0;
}
```