ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<maxx>:
  endbr64
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovge %esi,%eax
  ret
```

assistant: ```c
int maxx(int a, int b) {
  if (b > a)
    return b;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fucked_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  lea    -0x18(%rbp),%rsi
  lea    -0x14(%rbp),%rdx
  mov    %rsi,%r8
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string

tool: D14: swap received %d (%p) %d (%p)


tool: D19: i have swapped %d %d


assistant: ```c
void fucked_swap(int a, int b) {
  printf("swap received %d (%p) %d (%p)\n", a, &a, b, &b);
  int temp = b;
  b = a;
  a = temp;
  printf("i have swapped %d %d\n", a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fucked_swap>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%ecx
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%r8
  mov    %edi,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  mov    %edx,0x8(%rsp)
  mov    %esi,0xc(%rsp)
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D11: swap received %d (%p) %d (%p)


tool: D6: i have swapped %d %d


assistant: ```c
void fucked_swap(int a, int b) {
  printf("swap received %d (%p) %d (%p)\n", a, &a, b, &b);
  int temp = b;
  b = a;
  a = temp;
  printf("i have swapped %d %d\n", a, b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fucked_swap>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%ecx
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%r8
  mov    %esi,0x8(%rsp)
  mov    %edi,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  mov    %edx,0x8(%rsp)
  mov    %esi,0xc(%rsp)
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D13: swap received %d (%p) %d (%p)


tool: D16: i have swapped %d %d


assistant: ```c
void fucked_swap(int a, int b) {
  printf("swap received %d (%p) %d (%p)\n", a, &a, b, &b);
  int temp = b;
  b = a;
  a = temp;
  printf("i have swapped %d %d\n", a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fucked_swap>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%ecx
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%r8
  mov    %esi,0x8(%rsp)
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  mov    %edx,0x8(%rsp)
  mov    %esi,0xc(%rsp)
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D2: swap received %d (%p) %d (%p)


tool: D17: i have swapped %d %d


assistant: ```c
void fucked_swap(int a, int b) {
  printf("swap received %d (%p) %d (%p)\n", a, &a, b, &b);
  int temp = b;
  b = a;
  a = temp;
  printf("i have swapped %d %d\n", a, b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L10
L16:
  shlw   -0x14(%rbp)
  andw   $0x7fff,-0x14(%rbp)
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L10:
  cmpb   $0x7,-0x1(%rbp)
  jbe    L16
  movzwl -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short foo(unsigned short x) {
  unsigned char i = 0;
  for (i = 0; i < 8; i++) {
    x <<= 1;
    x &= 0x7fff;
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  mov    %edi,%eax
  mov    $0x8,%edx
L2:
  add    %eax,%eax
  and    $0x7fff,%ax
  sub    $0x1,%dl
  jne    L2
  ret
```

assistant: ```c
unsigned short foo(unsigned short x) {
  unsigned char i = 0;
  for (i = 0; i < 8; i++) {
    x <<= 1;
    x &= 0x7fff;
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  mov    %edi,%eax
  mov    $0x8,%edx
  nopl   0x0(%rax,%rax,1)
L5:
  add    %eax,%eax
  and    $0x7fff,%ax
  sub    $0x1,%dl
  jne    L5
  ret
```

assistant: ```c
unsigned short foo(unsigned short x) {
  unsigned char i = 0;
  for (i = 0; i < 8; i++) {
    x <<= 1;
    x &= 0x7fff;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%eax
  and    $0x7f80,%ax
  ret
```

assistant: ```c
unsigned short foo(unsigned short x) {
  unsigned char i = 0;
  for (i = 0; i < 8; i++) {
    x <<= 1;
    x &= 0x7fff;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<errdie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <usagex@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: ERROR: %s


assistant: ```c
void errdie(char *s) {
  printf("ERROR: %s\n", s);
  usagex();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<errdie>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <usagex@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: ERROR: %s


assistant: ```c
void errdie(char *s) {
  printf("ERROR: %s\n", s);
  usagex();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<errdie>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <usagex@plt>
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: ERROR: %s


assistant: ```c
void errdie(char *s) {
  printf("ERROR: %s\n", s);
  usagex();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<errdie>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <usagex@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: ERROR: %s


assistant: ```c
void errdie(char *s) {
  printf("ERROR: %s\n", s);
  usagex();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L27:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  addl   $0x1,-0x4(%rbp)
L14:
  shrl   -0x14(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jne    L27
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitCount(unsigned X) {
  int b;
  for (b = 0; X != 0; X >>= 1) {
    if (X & 1) {
      b++;
    }
  }
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitCount>:
  endbr64
  test   %edi,%edi
  je     L10
  mov    $0x0,%eax
L4:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L4
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int bitCount(unsigned X) {
  int b;
  for (b = 0; X != 0; X >>= 1) {
    if (X & 1) {
      b++;
    }
  }
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitCount>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L9
  ret
L6:
  ret
```

assistant: ```c
int bitCount(unsigned X) {
  int b;
  for (b = 0; X != 0; X >>= 1) {
    if (X & 1) {
      b++;
    }
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitCount>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L17
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L5
  ret
L17:
  ret
```

assistant: ```c
int bitCount(unsigned X) {
  int b;
  for (b = 0; X != 0; X >>= 1) {
    if (X & 1) {
      b++;
    }
  }
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mi_phy_addr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%ebp
  shr    $0x4,%bpl
  and    $0x1,%ebp
  mov    %ebp,%eax
  or     $0x8,%eax
  movzbl %al,%eax
  mov    %ax,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  or     $0xc,%ebp
  movzbl %bpl,%ebp
  mov    %bp,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    %ebx,%ebp
  shr    $0x3,%bpl
  and    $0x1,%ebp
  mov    %ebp,%eax
  or     $0x8,%eax
  movzbl %al,%eax
  mov    %ax,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  or     $0xc,%ebp
  movzbl %bpl,%ebp
  mov    %bp,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    %ebx,%ebp
  shr    $0x2,%bpl
  and    $0x1,%ebp
  mov    %ebp,%eax
  or     $0x8,%eax
  movzbl %al,%eax
  mov    %ax,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  or     $0xc,%ebp
  movzbl %bpl,%ebp
  mov    %bp,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    %ebx,%ebp
  shr    %bpl
  and    $0x1,%ebp
  mov    %ebp,%eax
  or     $0x8,%eax
  movzbl %al,%eax
  mov    %ax,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  or     $0xc,%ebp
  movzbl %bpl,%ebp
  mov    %bp,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  and    $0x1,%ebx
  mov    %ebx,%eax
  or     $0x8,%eax
  movzbl %al,%eax
  mov    %ax,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  or     $0xc,%ebx
  movzbl %bl,%ebx
  mov    %bx,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mi_phy_addr(unsigned char addr) {
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 4) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 4) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 3) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 3) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 2) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 2) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 1) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 1) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = ((addr & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = ((addr & 0x1) | 0x0008 | 0x0004);
  udelay(100);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mi_phy_addr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  shr    $0x4,%bpl
  push   %rbx
  mov    %edi,%ebx
  mov    $0x64,%edi
  and    $0x1,%ebp
  mov    %ebp,%eax
  or     $0xc,%ebp
  or     $0x8,%eax
  sub    $0x8,%rsp
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    %ebx,%ebp
  mov    $0x64,%edi
  shr    $0x3,%bpl
  and    $0x1,%ebp
  call   <udelay@plt>
  mov    %ebp,%eax
  or     $0xc,%ebp
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    %ebx,%ebp
  mov    $0x64,%edi
  shr    $0x2,%bpl
  and    $0x1,%ebp
  call   <udelay@plt>
  mov    %ebp,%eax
  or     $0xc,%ebp
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    %ebx,%ebp
  mov    $0x64,%edi
  shr    %bpl
  and    $0x1,%ebx
  and    $0x1,%ebp
  call   <udelay@plt>
  mov    %ebp,%eax
  or     $0xc,%ebp
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    %ebx,%eax
  or     $0xc,%ebx
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bl,%ebx
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bx,0xc000c20
  add    $0x8,%rsp
  mov    $0x64,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <udelay@plt>
```

assistant: ```c
void mi_phy_addr(unsigned char addr) {
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 4) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 4) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 3) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 3) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 2) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 2) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 1) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 1) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = ((addr & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = ((addr & 0x1) | 0x0008 | 0x0004);
  udelay(100);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mi_phy_addr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  shr    $0x4,%bpl
  push   %rbx
  mov    %edi,%ebx
  mov    $0x64,%edi
  and    $0x1,%ebp
  mov    %ebp,%eax
  or     $0xc,%ebp
  or     $0x8,%eax
  sub    $0x8,%rsp
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    %ebx,%ebp
  mov    $0x64,%edi
  shr    $0x3,%bpl
  and    $0x1,%ebp
  call   <udelay@plt>
  mov    %ebp,%eax
  or     $0xc,%ebp
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    %ebx,%ebp
  mov    $0x64,%edi
  shr    $0x2,%bpl
  and    $0x1,%ebp
  call   <udelay@plt>
  mov    %ebp,%eax
  or     $0xc,%ebp
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    %ebx,%ebp
  mov    $0x64,%edi
  shr    %bpl
  and    $0x1,%ebx
  and    $0x1,%ebp
  call   <udelay@plt>
  mov    %ebp,%eax
  or     $0xc,%ebp
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bpl,%ebp
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bp,0xc000c20
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    %ebx,%eax
  or     $0xc,%ebx
  mov    $0x64,%edi
  or     $0x8,%eax
  movzbl %bl,%ebx
  movzbl %al,%eax
  mov    %ax,0xc000c20
  call   <udelay@plt>
  mov    %bx,0xc000c20
  add    $0x8,%rsp
  mov    $0x64,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <udelay@plt>
```

assistant: ```c
void mi_phy_addr(unsigned char addr) {
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 4) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 4) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 3) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 3) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 2) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 2) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 1) & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = (((addr >> 1) & 0x1) | 0x0008 | 0x0004);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = ((addr & 0x1) | 0x0008);
  udelay(100);
  (*((volatile unsigned short *)(0x0C000000 + ((0x300 + (0x8)) << 2)))) = ((addr & 0x1) | 0x0008 | 0x0004);
  udelay(100);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prompt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: *************************************************************
The Read Line Program
*************************************************************
The (command)?> display takes only one argument. All subsequent
arguments follow suit. You may use a letter, or a word, to be
given as a command. All other options are void. For Example:
*************************************************************
h[enter] or help[enter] for the Help Display.
*************************************************************


assistant: ```c
void prompt(void) {
  printf("*************************************************************\n"
         "The Read Line Program\n"
         "*************************************************************\n"
         "The (command)?> display takes only one argument. All subsequent\n"
         "arguments follow suit. You may use a letter, or a word, to be\n"
         "given as a command. All other options are void. For Example:\n"
         "*************************************************************\n"
         "h[enter] or help[enter] for the Help Display.\n"
         "*************************************************************\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<prompt>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: *************************************************************
The Read Line Program
*************************************************************
The (command)?> display takes only one argument. All subsequent
arguments follow suit. You may use a letter, or a word, to be
given as a command. All other options are void. For Example:
*************************************************************
h[enter] or help[enter] for the Help Display.
*************************************************************


assistant: ```c
void prompt(void) {
  printf("*************************************************************\n"
         "The Read Line Program\n"
         "*************************************************************\n"
         "The (command)?> display takes only one argument. All subsequent\n"
         "arguments follow suit. You may use a letter, or a word, to be\n"
         "given as a command. All other options are void. For Example:\n"
         "*************************************************************\n"
         "h[enter] or help[enter] for the Help Display.\n"
         "*************************************************************\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<prompt>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: *************************************************************
The Read Line Program
*************************************************************
The (command)?> display takes only one argument. All subsequent
arguments follow suit. You may use a letter, or a word, to be
given as a command. All other options are void. For Example:
*************************************************************
h[enter] or help[enter] for the Help Display.
*************************************************************


assistant: ```c
void prompt(void) {
  printf("*************************************************************\n"
         "The Read Line Program\n"
         "*************************************************************\n"
         "The (command)?> display takes only one argument. All subsequent\n"
         "arguments follow suit. You may use a letter, or a word, to be\n"
         "given as a command. All other options are void. For Example:\n"
         "*************************************************************\n"
         "h[enter] or help[enter] for the Help Display.\n"
         "*************************************************************\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prompt>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: *************************************************************
The Read Line Program
*************************************************************
The (command)?> display takes only one argument. All subsequent
arguments follow suit. You may use a letter, or a word, to be
given as a command. All other options are void. For Example:
*************************************************************
h[enter] or help[enter] for the Help Display.
*************************************************************


assistant: ```c
void prompt(void) {
  printf("*************************************************************\n"
         "The Read Line Program\n"
         "*************************************************************\n"
         "The (command)?> display takes only one argument. All subsequent\n"
         "arguments follow suit. You may use a letter, or a word, to be\n"
         "given as a command. All other options are void. For Example:\n"
         "*************************************************************\n"
         "h[enter] or help[enter] for the Help Display.\n"
         "*************************************************************\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_one_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L0:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x5f5e0ff,-0x4(%rbp)
  jle    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_one_loop(int i, int *n) {
  int j;
  for (j = 0; j < 100000000; j++)
    (*n) = (*n) + i * j;
}
```