ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mostraMenu@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  mostraMenu();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mostraMenu@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  mostraMenu();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mostraMenu@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  mostraMenu();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mostraMenu@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  mostraMenu();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mystrndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mystrncpy@plt>
  mov    -0x8(%rbp),%rax
  jmp    L4
L2:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
char *mystrndup(char *src, int n) {
  if (src) {
    char *ptr = (char *)malloc(n + 1);
    mystrncpy(ptr, src, n);
    return ptr;
  } else
    return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mystrndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%rbx
  mov    %esi,%r12d
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <mystrncpy@plt>
L9:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrndup(char *src, int n) {
  if (src) {
    char *ptr = (char *)malloc(n + 1);
    mystrncpy(ptr, src, n);
    return ptr;
  } else
    return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mystrndup>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  mov    %esi,%r13d
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <mystrncpy@plt>
L6:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mystrndup(char *src, int n) {
  if (src) {
    char *ptr = (char *)malloc(n + 1);
    mystrncpy(ptr, src, n);
    return ptr;
  } else
    return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mystrndup>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  mov    %esi,%r13d
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <mystrncpy@plt>
L7:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mystrndup(char *src, int n) {
  if (src) {
    char *ptr = (char *)malloc(n + 1);
    mystrncpy(ptr, src, n);
    return ptr;
  } else
    return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<even>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L17
  mov    $0x1,%eax
  jmp    L16
L17:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int even(int n) {
  if (n % 2 == 0) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<even>:
  endbr64
  mov    %edi,%eax
  xor    $0x1,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int even(int n) {
  if (n % 2 == 0) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<even>:
  endbr64
  mov    %edi,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int even(int n) {
  if (n % 2 == 0) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<even>:
  endbr64
  mov    %edi,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int even(int n) {
  if (n % 2 == 0) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cbw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x98,%edi
  call   <put8@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cbw() {
  put8(0x66);
  put8(0x98);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cbw>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x98,%edi
  call   <put8@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cbw() {
  put8(0x66);
  put8(0x98);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cbw>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x98,%edi
  add    $0x8,%rsp
  jmp    1050 <put8@plt>
```

assistant: ```c
void cbw() {
  put8(0x66);
  put8(0x98);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    $0x0,%ebx
  jmp    L14
L32:
  mov    %ebx,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L52
L10:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L52:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L10
L18:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    %ebx,%eax
  jmp    L53
L29:
  add    $0x1,%ebx
L14:
  movslq %ebx,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    $0xffffffff,%eax
L53:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stindex(char *str1, char *str2) {
  register int base;
  int str1ind;
  int str2ind;
  for (base = 0; *(str1 + base) != '\0'; base++) {
    for (str1ind = base, str2ind = 0; *(str2 + str2ind) != '\0' && *(str2 + str2ind) == *(str1 + str1ind); str1ind++, str2ind++)
      ;
    if (*(str2 + str2ind) == '\0')
      return (base);
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L37
  movzbl (%rsi),%r8d
  mov    $0x0,%ecx
  jmp    L45
L53:
  test   %dl,%dl
  je     L10
  movzbl 0x1(%rdi,%rcx,1),%eax
  add    $0x1,%rcx
  sub    $0x1,%rsi
  test   %al,%al
  je     L26
L45:
  mov    %ecx,%r9d
  test   %r8b,%r8b
  je     L10
  mov    %rcx,%rax
  mov    %r8d,%edx
L55:
  cmp    %dl,(%rdi,%rax,1)
  jne    L53
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L55
L10:
  mov    %r9d,%eax
  ret
L37:
  mov    $0xffffffff,%r9d
  jmp    L10
L26:
  mov    $0xffffffff,%r9d
  jmp    L10
```

assistant: ```c
int stindex(char *str1, char *str2) {
  register int base;
  int str1ind;
  int str2ind;
  for (base = 0; *(str1 + base) != '\0'; base++) {
    for (str1ind = base, str2ind = 0; *(str2 + str2ind) != '\0' && *(str2 + str2ind) == *(str1 + str1ind); str1ind++, str2ind++)
      ;
    if (*(str2 + str2ind) == '\0')
      return (base);
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L59
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L38:
  mov    %ecx,%r9d
  test   %r8b,%r8b
  je     L15
  mov    %rcx,%rax
  mov    %r8d,%edx
  jmp    L9
L10:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L15
L9:
  cmp    %dl,(%rdi,%rax,1)
  je     L10
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L38
L59:
  mov    $0xffffffff,%r9d
L15:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int stindex(char *str1, char *str2) {
  register int base;
  int str1ind;
  int str2ind;
  for (base = 0; *(str1 + base) != '\0'; base++) {
    for (str1ind = base, str2ind = 0; *(str2 + str2ind) != '\0' && *(str2 + str2ind) == *(str1 + str1ind); str1ind++, str2ind++)
      ;
    if (*(str2 + str2ind) == '\0')
      return (base);
  }
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L29
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L59:
  mov    %ecx,%r9d
  test   %r8b,%r8b
  je     L48
  mov    %rcx,%rax
  mov    %r8d,%edx
  jmp    L26
L20:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L48
L26:
  cmp    %dl,(%rdi,%rax,1)
  je     L20
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L59
L29:
  mov    $0xffffffff,%r9d
L48:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int stindex(char *str1, char *str2) {
  register int base;
  int str1ind;
  int str2ind;
  for (base = 0; *(str1 + base) != '\0'; base++) {
    for (str1ind = base, str2ind = 0; *(str2 + str2ind) != '\0' && *(str2 + str2ind) == *(str1 + str1ind); str1ind++, str2ind++)
      ;
    if (*(str2 + str2ind) == '\0')
      return (base);
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<filterString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L59:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x40,-0xc(%rbp)
  jle    L42
  cmpl   $0x5a,-0xc(%rbp)
  jle    L47
L42:
  cmpl   $0x60,-0xc(%rbp)
  jle    L45
  cmpl   $0x7a,-0xc(%rbp)
  jle    L47
L45:
  addl   $0x1,-0x18(%rbp)
  jmp    L49
L47:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L49:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L59
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *filterString(const char *input) {
  int length = strlen(input);
  char *newStr = malloc(sizeof(char) * (length + 1));
  int i = 0;
  int j = 0;
  int ch = 0;
  for (i = 0, j = 0; i < length;) {
    ch = *input++;
    if (!((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z'))) {
      ++i;
    } else {
      newStr[j++] = (char)ch;
    }
  }
  newStr[j] = '\0';
  return newStr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<filterString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L23
  mov    $0x0,%edi
  mov    $0x0,%esi
  jmp    L25
L43:
  movslq %edi,%rdx
  mov    %cl,(%rax,%rdx,1)
  lea    0x1(%rdi),%edi
L24:
  cmp    %ebp,%esi
  jge    L17
L25:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%ecx
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L43
  add    $0x1,%esi
  jmp    L24
L23:
  mov    $0x0,%edi
L17:
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *filterString(const char *input) {
  int length = strlen(input);
  char *newStr = malloc(sizeof(char) * (length + 1));
  int i = 0;
  int j = 0;
  int ch = 0;
  for (i = 0, j = 0; i < length;) {
    ch = *input++;
    if (!((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z'))) {
      ++i;
    } else {
      newStr[j++] = (char)ch;
    }
  }
  newStr[j] = '\0';
  return newStr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<filterString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L2
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L21:
  add    $0x1,%edi
  cmp    %ebp,%edi
  jge    L6
L32:
  movzbl (%rbx),%ecx
  add    $0x1,%rbx
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L21
  movslq %esi,%rdx
  add    $0x1,%esi
  mov    %cl,(%rax,%rdx,1)
  cmp    %ebp,%edi
  jl     L32
L6:
  movslq %esi,%rsi
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *filterString(const char *input) {
  int length = strlen(input);
  char *newStr = malloc(sizeof(char) * (length + 1));
  int i = 0;
  int j = 0;
  int ch = 0;
  for (i = 0, j = 0; i < length;) {
    ch = *input++;
    if (!((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z'))) {
      ++i;
    } else {
      newStr[j++] = (char)ch;
    }
  }
  newStr[j] = '\0';
  return newStr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<filterString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L46
  xor    %ecx,%ecx
  xor    %edi,%edi
  nopl   0x0(%rax)
L18:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  mov    %esi,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L49
  add    $0x1,%edi
  cmp    %edi,%ebp
  jg     L18
  mov    %ecx,%edx
L32:
  movslq %edx,%rdx
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L49:
  mov    %sil,(%rax,%rcx,1)
  lea    0x1(%rcx),%edx
  cmp    %edi,%ebp
  jle    L32
  movslq %edx,%rcx
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *filterString(const char *input) {
  int length = strlen(input);
  char *newStr = malloc(sizeof(char) * (length + 1));
  int i = 0;
  int j = 0;
  int ch = 0;
  for (i = 0, j = 0; i < length;) {
    ch = *input++;
    if (!((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z'))) {
      ++i;
    } else {
      newStr[j++] = (char)ch;
    }
  }
  newStr[j] = '\0';
  return newStr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_device_devnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <makedev@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <minor@plt>
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <major@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <udev_device_new_from_devnum@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L0
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <print_device@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_device_unref@plt>
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: looking up device: %u:%u


assistant: ```c
int test_device_devnum(struct udev *udev) {
  dev_t devnum = makedev(1, 3);
  struct udev_device *device;
  printf("looking up device: %u:%u\n", major(devnum), minor(devnum));
  device = udev_device_new_from_devnum(udev, 'c', devnum);
  if (device == NULL)
    return -1;
  print_device(device);
  udev_device_unref(device);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_device_devnum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <makedev@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <minor@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <major@plt>
  mov    %eax,%esi
  mov    %r12d,%edx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edx
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <udev_device_new_from_devnum@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <print_device@plt>
  mov    %rbx,%rdi
  call   <udev_device_unref@plt>
  mov    $0x0,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: looking up device: %u:%u


assistant: ```c
int test_device_devnum(struct udev *udev) {
  dev_t devnum = makedev(1, 3);
  struct udev_device *device;
  printf("looking up device: %u:%u\n", major(devnum), minor(devnum));
  device = udev_device_new_from_devnum(udev, 'c', devnum);
  if (device == NULL)
    return -1;
  print_device(device);
  udev_device_unref(device);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_device_devnum>:
  endbr64
  push   %r13
  mov    $0x3,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  call   <makedev@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <minor@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <major@plt>
  mov    %r13d,%edx
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <udev_device_new_from_devnum@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <print_device@plt>
  mov    %r12,%rdi
  call   <udev_device_unref@plt>
  xor    %eax,%eax
L16:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0xffffffff,%eax
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: looking up device: %u:%u


assistant: ```c
int test_device_devnum(struct udev *udev) {
  dev_t devnum = makedev(1, 3);
  struct udev_device *device;
  printf("looking up device: %u:%u\n", major(devnum), minor(devnum));
  device = udev_device_new_from_devnum(udev, 'c', devnum);
  if (device == NULL)
    return -1;
  print_device(device);
  udev_device_unref(device);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_device_devnum>:
  endbr64
  push   %r13
  mov    $0x3,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  call   <makedev@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <minor@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <major@plt>
  mov    %r13d,%edx
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <udev_device_new_from_devnum@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <print_device@plt>
  mov    %r12,%rdi
  call   <udev_device_unref@plt>
  xor    %eax,%eax
L17:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L17
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: looking up device: %u:%u


assistant: ```c
int test_device_devnum(struct udev *udev) {
  dev_t devnum = makedev(1, 3);
  struct udev_device *device;
  printf("looking up device: %u:%u\n", major(devnum), minor(devnum));
  device = udev_device_new_from_devnum(udev, 'c', devnum);
  if (device == NULL)
    return -1;
  print_device(device);
  udev_device_unref(device);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<extract_input_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r15d
  mov    %rcx,%r14
  mov    %esi,%r13d
  call   <strlen@plt>
  mov    %eax,%esi
  cmp    %bpl,(%rbx)
  je     L10
  test   %eax,%eax
  js     L10
  mov    $0x1,%eax
L36:
  mov    %eax,%ebp
  cmp    %r13b,(%rbx,%rax,1)
  setne  %cl
  cmp    %eax,%esi
  setge  %dl
  mov    %rax,%r12
  add    $0x1,%rax
  test   %dl,%cl
  jne    L36
L51:
  cmp    %ebp,%esi
  je     L49
  lea    0x1(%rbp),%edi
  movslq %edi,%rax
  movzbl (%rbx,%rax,1),%eax
  cmp    $0xa,%al
  setne  %dl
  cmp    $0x2c,%al
  setne  %al
  test   %al,%dl
  je     L5
  cmp    %edi,%esi
  jl     L5
  lea    0x2(%rbp),%eax
  cltq
L39:
  mov    %eax,%edi
  movzbl (%rbx,%rax,1),%ecx
  cmp    $0xa,%cl
  setne  %dl
  cmp    $0x2c,%cl
  setne  %cl
  and    %ecx,%edx
  cmp    %eax,%esi
  setge  %cl
  add    $0x1,%rax
  test   %cl,%dl
  jne    L39
L5:
  lea    0x1(%rdi),%eax
  mov    %eax,(%r14)
  sub    %ebp,%edi
  lea    -0x1(%rdi),%r13d
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L103
L29:
  lea    0x1(%rbx,%r12,1),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L51
L49:
  mov    %rbx,%rcx
  mov    %r15d,%edx
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  lea    0x1(%rbp),%edi
  jmp    L5
L103:
  mov    %rbx,%rcx
  mov    %r13d,%edx
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D6: unrecognized input string in read_platform_properties for index = %d, string = %s

tool: D9: extract_input_string failled to malloc return string of length %d for processing %s

assistant: ```c
char *extract_input_string(char *instr, char key, int index, int *next) {
  int i, j, k, len;
  char *ret_string;
  len = strlen(instr);
  i = 0;
  while ((instr[i] != key) && (i <= len))
    i++;
  if (i == len)
    err(1, "unrecognized input string in read_platform_properties for index = %d, string = %s", index, instr);
  j = i + 1;
  while ((instr[j] != '\n') && (instr[j] != ',') && (j <= len))
    j++;
  *next = j + 1;
  len = j - i - 1;
  ret_string = malloc(len + 1);
  if (ret_string == NULL)
    err(1, "extract_input_string failled to malloc return string of length %d for processing %s", len, instr);
  strncpy(ret_string, &instr[i + 1], len);
  ret_string[len] = '\0';
  return ret_string;
}
```