ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L82:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L60
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L60:
  cmpl   $0x4,-0x8(%rbp)
  jle    L48
  mov    $0x0,%eax
  jmp    L58
L48:
  cmpl   $0x2,-0x8(%rbp)
  jne    L22
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L19
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L19
  mov    $0x0,%eax
  jmp    L58
L19:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  sub    $0x30,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0x10,-0x10(%rbp)
  jle    L82
  mov    $0x1,%eax
L58:
  pop    %rbp
  ret
```

assistant: ```c
int parse(char *isbn, int *parsed, char *publisher) {
  int i, j, dash = 0, counter = 0;
  for (i = 0, j = 0; i < 17; i++, j++) {
    if (isbn[i] == '-') {
      i++;
      dash++;
    }
    if (dash > 4)
      return 0;
    if (dash == 2) {
      publisher[counter] = isbn[i];
      counter++;
    }
    if (isbn[i] == '-' && isbn[i + 1] == '-')
      return 0;
    parsed[j] = isbn[i] - 48;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse>:
  endbr64
  mov    $0x0,%r10d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  jmp    L79
L63:
  add    $0x1,%ecx
  add    $0x1,%r8d
  jmp    L52
L17:
  movslq %ecx,%r9
  movzbl (%rdi,%r9,1),%eax
  cmp    $0x2d,%al
  je     L64
L71:
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,(%rsi)
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    $0x10,%ecx
  jg     L2
L79:
  movslq %ecx,%rax
  cmpb   $0x2d,(%rdi,%rax,1)
  je     L63
L52:
  cmp    $0x4,%r8d
  jg     L55
  cmp    $0x2,%r8d
  jne    L17
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%r9d
  movslq %r10d,%rax
  mov    %r9b,(%rdx,%rax,1)
  add    $0x1,%r10d
  jmp    L17
L64:
  cmpb   $0x2d,0x1(%rdi,%r9,1)
  jne    L71
  mov    $0x0,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
L55:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int parse(char *isbn, int *parsed, char *publisher) {
  int i, j, dash = 0, counter = 0;
  for (i = 0, j = 0; i < 17; i++, j++) {
    if (isbn[i] == '-') {
      i++;
      dash++;
    }
    if (dash > 4)
      return 0;
    if (dash == 2) {
      publisher[counter] = isbn[i];
      counter++;
    }
    if (isbn[i] == '-' && isbn[i + 1] == '-')
      return 0;
    parsed[j] = isbn[i] - 48;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse>:
  endbr64
  xor    %ecx,%ecx
  mov    %rdi,%r8
  xor    %r10d,%r10d
  xor    %edi,%edi
  movslq %ecx,%rax
  cmpb   $0x2d,(%r8,%rax,1)
  je     L78
L69:
  cmp    $0x5,%edi
  je     L14
  push   %rbx
  jmp    L47
L63:
  sub    $0x30,%eax
  add    $0x1,%ecx
  add    $0x4,%rsi
  mov    %eax,-0x4(%rsi)
  cmp    $0x10,%ecx
  jg     L33
  movslq %ecx,%rax
  cmpb   $0x2d,(%r8,%rax,1)
  jne    L23
  add    $0x1,%ecx
  add    $0x1,%edi
L23:
  cmp    $0x5,%edi
  je     L11
L47:
  movslq %ecx,%r9
  lea    (%r8,%r9,1),%rax
  cmp    $0x2,%edi
  jne    L43
  movzbl (%rax),%ebx
  movslq %r10d,%r11
  add    $0x1,%r10d
  mov    %bl,(%rdx,%r11,1)
L43:
  movsbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L63
  cmpb   $0x2d,0x1(%r8,%r9,1)
  jne    L63
L11:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L33:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nop
L78:
  add    $0x1,%ecx
  add    $0x1,%edi
  jmp    L69
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int parse(char *isbn, int *parsed, char *publisher) {
  int i, j, dash = 0, counter = 0;
  for (i = 0, j = 0; i < 17; i++, j++) {
    if (isbn[i] == '-') {
      i++;
      dash++;
    }
    if (dash > 4)
      return 0;
    if (dash == 2) {
      publisher[counter] = isbn[i];
      counter++;
    }
    if (isbn[i] == '-' && isbn[i + 1] == '-')
      return 0;
    parsed[j] = isbn[i] - 48;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse>:
  endbr64
  xor    %ecx,%ecx
  mov    %rdi,%r8
  xor    %r10d,%r10d
  xor    %edi,%edi
  movslq %ecx,%rax
  cmpb   $0x2d,(%r8,%rax,1)
  je     L65
L43:
  cmp    $0x5,%edi
  je     L96
  push   %rbx
  jmp    L73
L2:
  sub    $0x30,%eax
  add    $0x1,%ecx
  add    $0x4,%rsi
  mov    %eax,-0x4(%rsi)
  cmp    $0x10,%ecx
  jg     L8
  movslq %ecx,%rax
  cmpb   $0x2d,(%r8,%rax,1)
  jne    L53
  add    $0x1,%ecx
  add    $0x1,%edi
L53:
  cmp    $0x5,%edi
  je     L0
L73:
  movslq %ecx,%r9
  lea    (%r8,%r9,1),%rax
  cmp    $0x2,%edi
  jne    L90
  movzbl (%rax),%ebx
  movslq %r10d,%r11
  add    $0x1,%r10d
  mov    %bl,(%rdx,%r11,1)
L90:
  movsbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L2
  cmpb   $0x2d,0x1(%r8,%r9,1)
  jne    L2
L0:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nop
L65:
  add    $0x1,%ecx
  add    $0x1,%edi
  jmp    L43
L96:
  xor    %eax,%eax
  ret
```

assistant: ```c
int parse(char *isbn, int *parsed, char *publisher) {
  int i, j, dash = 0, counter = 0;
  for (i = 0, j = 0; i < 17; i++, j++) {
    if (isbn[i] == '-') {
      i++;
      dash++;
    }
    if (dash > 4)
      return 0;
    if (dash == 2) {
      publisher[counter] = isbn[i];
      counter++;
    }
    if (isbn[i] == '-' && isbn[i + 1] == '-')
      return 0;
    parsed[j] = isbn[i] - 48;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L54
  lea    0x10(%rsp),%r13
  lea    0x14(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D15(%rip),%rbx
  lea    D31(%rip),%r15
  lea    D61(%rip),%r14
  jmp    L20
  nopl   0x0(%rax)
L2:
  cmpl   $0x15e0,0x10(%rsp)
  jg     L119
  cmp    $0x32,%eax
  jle    L80
  lea    D87(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L133:
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L54
L20:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    0xc(%rsp),%eax
  movsd  D65(%rip),%xmm1
  cvtss2sd 0x14(%rsp),%xmm0
  comisd %xmm0,%xmm1
  ja     L2
  cmpl   $0x15e0,0x10(%rsp)
  jle    L58
  cmp    $0x32,%eax
  jle    L80
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L20
L54:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L142
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L80:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L133
  nopl   (%rax)
L119:
  cmp    $0x32,%eax
  jle    L87
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L133
  xchg   %ax,%ax
L58:
  cmp    $0x32,%eax
  jg     L80
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L133
L87:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L133
L142:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
type: string
name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D31
type: string
name: retrieve_data
arguments: label: D61
type: string
name: retrieve_data
arguments: label: D87
type: string
name: retrieve_data
arguments: label: D65
type: f64
name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D38
type: string
name: retrieve_data
arguments: label: D23
type: string

tool: D37: %d

tool: D15: %d %f %d

tool: D31: 5


tool: D61: 6


tool: D87: 9


tool: D65: 0.7

tool: D12: 7


tool: D38: 10


tool: D23: 8


assistant: ```c
int main() {
  int T, a, c, ca, cb, cc;
  float b;
  scanf("%d", &T);
  while (T--) {
    ca = cb = cc = 0;
    scanf("%d %f %d", &a, &b, &c);
    if (a > 50)
      ca = 1;
    if (b < 0.7)
      cb = 1;
    if (c > 5600)
      cc = 1;
    if (ca && cb && cc)
      printf("10\n");
    else if (ca && cb && !cc)
      printf("9\n");
    else if (!ca && cb && cc)
      printf("8\n");
    else if (ca && !cb && cc)
      printf("7\n");
    else if ((ca && !cb && !cc) || (!ca && cb && !cc) || (!ca && !cb && cc))
      printf("6\n");
    else
      printf("5\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <somavet@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: Soma dos elementos e: %d

assistant: ```c
main() {
  int vet[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("Soma dos elementos e: %d", somavet(vet));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  mov    %rsp,%rdi
  call   <somavet@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: Soma dos elementos e: %d

assistant: ```c
main() {
  int vet[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("Soma dos elementos e: %d", somavet(vet));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  call   <somavet@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: Soma dos elementos e: %d

assistant: ```c
main() {
  int vet[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("Soma dos elementos e: %d", somavet(vet));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D13(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <somavet@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D28
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D13
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: {"D17": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D28": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D13": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D8: Soma dos elementos e: %d

assistant: ```c
main() {
  int vet[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("Soma dos elementos e: %d", somavet(vet));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decode_modifiers_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  ja     L32
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L67
  mov    $0x400000,%eax
  jmp    L67
  mov    $0x800000,%eax
  jmp    L67
  mov    $0xc00000,%eax
  jmp    L67
  mov    $0x1000000,%eax
  jmp    L67
  mov    $0x1400000,%eax
  jmp    L67
  mov    $0x1800000,%eax
  jmp    L67
  mov    $0x1c00000,%eax
  jmp    L67
L32:
  mov    $0xffffffff,%eax
L67:
  pop    %rbp
  ret
```

assistant: ```c
int32_t decode_modifiers_code(int c) {
  switch (c) {
  case 0:
    return 0;
  case 2:
    return 0x00400000;
  case 3:
    return 0x00800000;
  case 4:
    return 0x00400000 | 0x00800000;
  case 5:
    return 0x01000000;
  case 6:
    return 0x00400000 | 0x01000000;
  case 7:
    return 0x00800000 | 0x01000000;
  case 8:
    return 0x00400000 | 0x00800000 | 0x01000000;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode_modifiers_code>:
  endbr64
  cmp    $0x8,%edi
  ja     L4
  mov    %edi,%eax
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x400000,%eax
  ret
  mov    $0x800000,%eax
  ret
  mov    $0xc00000,%eax
  ret
  mov    $0x1000000,%eax
  ret
  mov    $0x1400000,%eax
  ret
  mov    $0x1800000,%eax
  ret
  mov    $0x1c00000,%eax
  ret
L4:
  mov    $0xffffffff,%eax
  ret
  mov    %edi,%eax
  ret
```

assistant: ```c
int32_t decode_modifiers_code(int c) {
  switch (c) {
  case 0:
    return 0;
  case 2:
    return 0x00400000;
  case 3:
    return 0x00800000;
  case 4:
    return 0x00400000 | 0x00800000;
  case 5:
    return 0x01000000;
  case 6:
    return 0x00400000 | 0x01000000;
  case 7:
    return 0x00800000 | 0x01000000;
  case 8:
    return 0x00400000 | 0x00800000 | 0x01000000;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decode_modifiers_code>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x8,%edi
  ja     L1
  mov    %edi,%edi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L1:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: 

assistant: ```c
int32_t decode_modifiers_code(int c) {
  switch (c) {
  case 0:
    return 0;
  case 2:
    return 0x00400000;
  case 3:
    return 0x00800000;
  case 4:
    return 0x00400000 | 0x00800000;
  case 5:
    return 0x01000000;
  case 6:
    return 0x00400000 | 0x01000000;
  case 7:
    return 0x00800000 | 0x01000000;
  case 8:
    return 0x00400000 | 0x00800000 | 0x01000000;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode_modifiers_code>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x8,%edi
  ja     L4
  mov    %edi,%edi
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L4:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: 

assistant: ```c
int32_t decode_modifiers_code(int c) {
  switch (c) {
  case 0:
    return 0;
  case 2:
    return 0x00400000;
  case 3:
    return 0x00800000;
  case 4:
    return 0x00400000 | 0x00800000;
  case 5:
    return 0x01000000;
  case 6:
    return 0x00400000 | 0x01000000;
  case 7:
    return 0x00800000 | 0x01000000;
  case 8:
    return 0x00400000 | 0x00800000 | 0x01000000;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %esi,-0x8c(%rbp)
  mov    %edx,-0x90(%rbp)
  mov    %ecx,-0x94(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x90(%rbp),%eax
  sub    -0x8c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x68(%rbp)
  mov    -0x94(%rbp),%eax
  sub    -0x90(%rbp),%eax
  mov    %eax,-0x64(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L6
L35:
  mov    -0x8c(%rbp),%edx
  mov    -0x74(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x74(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x74(%rbp)
L6:
  mov    -0x74(%rbp),%eax
  cmp    -0x68(%rbp),%eax
  jl     L35
  movl   $0x0,-0x70(%rbp)
  jmp    L76
L60:
  mov    -0x90(%rbp),%edx
  mov    -0x70(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x70(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x70(%rbp)
L76:
  mov    -0x70(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L60
  mov    -0x74(%rbp),%eax
  cltq
  movl   $0x270f,-0x60(%rbp,%rax,4)
  mov    -0x70(%rbp),%eax
  cltq
  movl   $0x270f,-0x30(%rbp,%rax,4)
  movl   $0x0,-0x74(%rbp)
  movl   $0x0,-0x70(%rbp)
  mov    -0x8c(%rbp),%eax
  mov    %eax,-0x6c(%rbp)
  jmp    L51
L19:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jg     L36
  mov    -0x74(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x74(%rbp)
  mov    -0x6c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x88(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  jmp    L70
L36:
  mov    -0x70(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x70(%rbp)
  mov    -0x6c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x88(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
L70:
  addl   $0x1,-0x6c(%rbp)
L51:
  mov    -0x6c(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jle    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int merge(int arr[], int l, int m, int h) {
  int arr1[10], arr2[10];
  int n1, n2, i, j, k;
  n1 = m - l + 1;
  n2 = h - m;
  for (i = 0; i < n1; i++)
    arr1[i] = arr[l + i];
  for (j = 0; j < n2; j++)
    arr2[j] = arr[m + j + 1];
  arr1[i] = 9999;
  arr2[j] = 9999;
  i = 0;
  j = 0;
  for (k = l; k <= h; k++) {
    if (arr1[i] <= arr2[j])
      arr[k] = arr1[i++];
    else
      arr[k] = arr2[j++];
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<merge>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %edx,%r10d
  mov    %ecx,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %ecx,%ebx
  sub    %edx,%ebx
  mov    %edx,%r11d
  sub    %r9d,%r11d
  js     L36
  lea    0x1(%r11),%ecx
  shl    $0x2,%rcx
  movslq %r9d,%rax
  lea    (%rdi,%rax,4),%rdi
  mov    $0x0,%eax
L3:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L3
  add    $0x1,%r11d
L18:
  test   %ebx,%ebx
  jle    L108
  lea    0x1(%rbx),%edi
  movslq %r10d,%r10
  lea    (%r8,%r10,4),%rcx
  mov    $0x1,%eax
L44:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,0x2c(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L44
L22:
  movslq %r11d,%r11
  movl   $0x270f,(%rsp,%r11,4)
  movslq %ebx,%rbx
  movl   $0x270f,0x30(%rsp,%rbx,4)
  cmp    %esi,%r9d
  jg     L106
  movslq %r9d,%rdx
  lea    (%r8,%rdx,4),%rax
  sub    %r9d,%esi
  add    %rdx,%rsi
  lea    0x4(%r8,%rsi,4),%r8
  mov    $0x0,%edi
  mov    $0x0,%esi
  jmp    L17
L36:
  mov    $0x0,%r11d
  jmp    L18
L108:
  mov    $0x0,%ebx
  jmp    L22
L20:
  add    $0x1,%edi
  mov    %edx,(%rax)
L53:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L106
L17:
  movslq %esi,%rdx
  mov    (%rsp,%rdx,4),%ecx
  movslq %edi,%rdx
  mov    0x30(%rsp,%rdx,4),%edx
  cmp    %edx,%ecx
  jg     L20
  add    $0x1,%esi
  mov    %ecx,(%rax)
  jmp    L53
L106:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int merge(int arr[], int l, int m, int h) {
  int arr1[10], arr2[10];
  int n1, n2, i, j, k;
  n1 = m - l + 1;
  n2 = h - m;
  for (i = 0; i < n1; i++)
    arr1[i] = arr[l + i];
  for (j = 0; j < n2; j++)
    arr2[j] = arr[m + j + 1];
  arr1[i] = 9999;
  arr2[j] = 9999;
  i = 0;
  j = 0;
  for (k = l; k <= h; k++) {
    if (arr1[i] <= arr2[j])
      arr[k] = arr1[i++];
    else
      arr[k] = arr2[j++];
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<merge>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%r13d
  mov    %ecx,%ebx
  sub    %ebp,%r15d
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  sub    %esi,%r13d
  js     L67
  movslq %r13d,%rax
  mov    %rsp,%rdi
  add    $0x1,%r13d
  lea    0x4(,%rax,4),%rdx
  movslq %esi,%rax
  lea    (%r14,%rax,4),%rsi
  call   <memcpy@plt>
  test   %r15d,%r15d
  jle    L2
L97:
  movslq %r15d,%r15
  lea    0x30(%rsp),%rdi
  lea    0x4(%r14,%rbp,4),%rsi
  lea    0x0(,%r15,4),%rdx
  call   <memcpy@plt>
L69:
  movl   $0x270f,0x30(%rsp,%r15,4)
  movslq %r13d,%r13
  movl   $0x270f,(%rsp,%r13,4)
  cmp    %ebx,%r12d
  jg     L37
  movslq %r12d,%rdx
  sub    %r12d,%ebx
  xor    %edi,%edi
  xor    %esi,%esi
  add    %rdx,%rbx
  lea    (%r14,%rdx,4),%rax
  lea    0x4(%r14,%rbx,4),%r8
  jmp    L38
  nopl   0x0(%rax)
L49:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %rax,%r8
  je     L37
L38:
  movslq %esi,%rdx
  movslq %edi,%rcx
  mov    (%rsp,%rdx,4),%edx
  mov    0x30(%rsp,%rcx,4),%ecx
  cmp    %ecx,%edx
  jle    L49
  mov    %ecx,%edx
  add    $0x4,%rax
  add    $0x1,%edi
  mov    %edx,-0x4(%rax)
  cmp    %rax,%r8
  jne    L38
L37:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L67:
  xor    %r13d,%r13d
  test   %r15d,%r15d
  jg     L97
  nopl   0x0(%rax)
L2:
  xor    %r15d,%r15d
  jmp    L69
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int merge(int arr[], int l, int m, int h) {
  int arr1[10], arr2[10];
  int n1, n2, i, j, k;
  n1 = m - l + 1;
  n2 = h - m;
  for (i = 0; i < n1; i++)
    arr1[i] = arr[l + i];
  for (j = 0; j < n2; j++)
    arr2[j] = arr[m + j + 1];
  arr1[i] = 9999;
  arr2[j] = 9999;
  i = 0;
  j = 0;
  for (k = l; k <= h; k++) {
    if (arr1[i] <= arr2[j])
      arr[k] = arr1[i++];
    else
      arr[k] = arr2[j++];
  }
  return 0;
}
```