ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<read_argv>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  movslq %ebp,%rsi
  movzbl 0x1(%rbx,%rsi,1),%ecx
  cmp    $0xd,%cl
  je     L38
  cmp    $0xa,%cl
  je     L38
  mov    $0x1,%edx
  add    %rbx,%rsi
L31:
  mov    %cl,-0x1(%rax,%rdx,1)
  movzbl 0x1(%rsi,%rdx,1),%ecx
  mov    %rdx,%rdi
  add    $0x1,%rdx
  cmp    $0xd,%cl
  je     L26
  cmp    $0xa,%cl
  jne    L31
L26:
  movb   $0x0,(%rax,%rdi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    $0x0,%edi
  jmp    L26
```

assistant: ```c
char *read_argv(char *info, int request_len) {
  char *argv = (char *)malloc(sizeof(char) * strlen(info));
  int i;
  info += request_len + 1;
  for (i = 0; info[i] != '\r' && info[i] != '\n'; i++)
    argv[i] = info[i];
  argv[i] = '\0';
  return argv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_argv>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  movslq %ebx,%rsi
  movzbl 0x1(%rbp,%rsi,1),%ecx
  cmp    $0xd,%cl
  je     L16
  cmp    $0xa,%cl
  je     L16
  mov    $0x1,%edx
  lea    0x0(%rbp,%rsi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %cl,-0x1(%rax,%rdx,1)
  movzbl 0x1(%rdi,%rdx,1),%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmp    $0xd,%cl
  je     L1
  cmp    $0xa,%cl
  jne    L34
L1:
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *read_argv(char *info, int request_len) {
  char *argv = (char *)malloc(sizeof(char) * strlen(info));
  int i;
  info += request_len + 1;
  for (i = 0; info[i] != '\r' && info[i] != '\n'; i++)
    argv[i] = info[i];
  argv[i] = '\0';
  return argv;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_argv>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  movslq %ebx,%rsi
  movzbl 0x1(%rbp,%rsi,1),%ecx
  cmp    $0xd,%cl
  je     L25
  cmp    $0xa,%cl
  je     L25
  mov    $0x1,%edx
  lea    0x0(%rbp,%rsi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %cl,-0x1(%rax,%rdx,1)
  movzbl 0x1(%rdi,%rdx,1),%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmp    $0xd,%cl
  je     L13
  cmp    $0xa,%cl
  jne    L10
L13:
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *read_argv(char *info, int request_len) {
  char *argv = (char *)malloc(sizeof(char) * strlen(info));
  int i;
  info += request_len + 1;
  for (i = 0; info[i] != '\r' && info[i] != '\n'; i++)
    argv[i] = info[i];
  argv[i] = '\0';
  return argv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FNIEMOP_DEF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <AssertFailed@plt>
  mov    $0x0,%eax
  call   <IEMOP_RAISE_INVALID_OPCODE@plt>
  leave
  ret
```

assistant: ```c
FNIEMOP_DEF(iemOp_Grp7_vmlaunch) {
  AssertFailed();
  return IEMOP_RAISE_INVALID_OPCODE();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FNIEMOP_DEF>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <AssertFailed@plt>
  mov    $0x0,%eax
  call   <IEMOP_RAISE_INVALID_OPCODE@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
FNIEMOP_DEF(iemOp_Grp7_vmlaunch) {
  AssertFailed();
  return IEMOP_RAISE_INVALID_OPCODE();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FNIEMOP_DEF>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <AssertFailed@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <IEMOP_RAISE_INVALID_OPCODE@plt>
```

assistant: ```c
FNIEMOP_DEF(iemOp_Grp7_vmlaunch) {
  AssertFailed();
  return IEMOP_RAISE_INVALID_OPCODE();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FNIEMOP_DEF>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <AssertFailed@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <IEMOP_RAISE_INVALID_OPCODE@plt>
```

assistant: ```c
FNIEMOP_DEF(iemOp_Grp7_vmlaunch) {
  AssertFailed();
  return IEMOP_RAISE_INVALID_OPCODE();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<macro_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x10,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x12,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <do_cmd_macro_aux@plt>
  lea    -0x410(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <macro_add@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x13,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    $0x0,%eax
  call   <inkey_ex@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D36
type: string

tool: D27: Command: Remove a macro

tool: D16: Trigger: 

tool: 

tool: D36: Removed a macro.  Press any key to continue.

assistant: ```c
void macro_remove(void *unused, const char *title) {
  char pat[1024];
  prt("Command: Remove a macro", 16, 0);
  prt("Trigger: ", 18, 0);
  do_cmd_macro_aux(pat);
  macro_add(pat, pat);
  prt("", 0, 0);
  prt("Removed a macro.  Press any key to continue.", 19, 0);
  (void)inkey_ex();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<macro_remove>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x10,%esi
  lea    D0(%rip),%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x12,%esi
  lea    D12(%rip),%rdi
  call   <prt@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <do_cmd_macro_aux@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <macro_add@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D19(%rip),%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x13,%esi
  lea    D24(%rip),%rdi
  call   <prt@plt>
  mov    $0x0,%eax
  call   <inkey_ex@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x410,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D24
type_infered: string

tool: D0: Command: Remove a macro

tool: D12: Trigger: 

tool: 

tool: D24: Removed a macro.  Press any key to continue.

assistant: ```c
void macro_remove(void *unused, const char *title) {
  char pat[1024];
  prt("Command: Remove a macro", 16, 0);
  prt("Trigger: ", 18, 0);
  do_cmd_macro_aux(pat);
  macro_add(pat, pat);
  prt("", 0, 0);
  prt("Removed a macro.  Press any key to continue.", 19, 0);
  (void)inkey_ex();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<macro_remove>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x10,%esi
  lea    D3(%rip),%rdi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x12,%esi
  lea    D30(%rip),%rdi
  call   <prt@plt>
  mov    %rbp,%rdi
  call   <do_cmd_macro_aux@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <macro_add@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D18(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x13,%esi
  lea    D29(%rip),%rdi
  call   <prt@plt>
  xor    %eax,%eax
  call   <inkey_ex@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x410,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D30
datatype: string
name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D29
datatype: string

tool: D3: Command: Remove a macro

tool: D30: Trigger: 

tool: 

tool: D29: Removed a macro.  Press any key to continue.

assistant: ```c
void macro_remove(void *unused, const char *title) {
  char pat[1024];
  prt("Command: Remove a macro", 16, 0);
  prt("Trigger: ", 18, 0);
  do_cmd_macro_aux(pat);
  macro_add(pat, pat);
  prt("", 0, 0);
  prt("Removed a macro.  Press any key to continue.", 19, 0);
  (void)inkey_ex();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<macro_remove>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x10,%esi
  lea    D17(%rip),%rdi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x12,%esi
  lea    D38(%rip),%rdi
  call   <prt@plt>
  mov    %rbp,%rdi
  call   <do_cmd_macro_aux@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <macro_add@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x13,%esi
  lea    D9(%rip),%rdi
  call   <prt@plt>
  xor    %eax,%eax
  call   <inkey_ex@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type_infered: string
name: disassemble_data
arguments: data_label: D38
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D17: Command: Remove a macro

tool: D38: Trigger: 

tool: 

tool: D9: Removed a macro.  Press any key to continue.

assistant: ```c
void macro_remove(void *unused, const char *title) {
  char pat[1024];
  prt("Command: Remove a macro", 16, 0);
  prt("Trigger: ", 18, 0);
  do_cmd_macro_aux(pat);
  macro_add(pat, pat);
  prt("", 0, 0);
  prt("Removed a macro.  Press any key to continue.", 19, 0);
  (void)inkey_ex();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_cursor_scan_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L3
  movzbl -0x4(%rbp),%eax
  and    $0xf,%eax
  or     $0x10,%eax
  mov    %al,-0x4(%rbp)
L3:
  movzbl -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <crtc_reg_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no)) set_cursor_scan_start(unsigned char scan_start) {
  if (scan_start & 0x20)
    scan_start = 0x10 | (scan_start & 0xf);
  crtc_reg_write(0xa, scan_start);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_cursor_scan_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  and    $0xf,%eax
  or     $0x10,%eax
  test   $0x20,%dil
  cmovne %eax,%edi
  movzbl %dil,%esi
  mov    $0xa,%edi
  call   <crtc_reg_write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no)) set_cursor_scan_start(unsigned char scan_start) {
  if (scan_start & 0x20)
    scan_start = 0x10 | (scan_start & 0xf);
  crtc_reg_write(0xa, scan_start);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_cursor_scan_start>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  or     $0x10,%eax
  test   $0x20,%dil
  cmovne %eax,%edi
  movzbl %dil,%esi
  mov    $0xa,%edi
  jmp    1050 <crtc_reg_write@plt>
```

assistant: ```c
void __attribute__((no)) set_cursor_scan_start(unsigned char scan_start) {
  if (scan_start & 0x20)
    scan_start = 0x10 | (scan_start & 0xf);
  crtc_reg_write(0xa, scan_start);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_cursor_scan_start>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  or     $0x10,%eax
  test   $0x20,%dil
  cmovne %eax,%edi
  movzbl %dil,%esi
  mov    $0xa,%edi
  jmp    1050 <crtc_reg_write@plt>
```

assistant: ```c
void __attribute__((no)) set_cursor_scan_start(unsigned char scan_start) {
  if (scan_start & 0x20)
    scan_start = 0x10 | (scan_start & 0xf);
  crtc_reg_write(0xa, scan_start);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mc_maximize_sndbuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mc_get_sndbuf@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  js     L56
  movl   $0x10000000,-0xc(%rbp)
  jmp    L24
L13:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mc_set_sndbuf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L38
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L24
L38:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L13
  jmp    L45
L56:
  nop
L45:
  leave
  ret
```

assistant: ```c
void mc_maximize_sndbuf(int sd) {
  int status, min, max, avg;
  min = mc_get_sndbuf(sd);
  if (min < 0) {
    return;
  }
  max = 256 * (1024 * (1024));
  while (min <= max) {
    avg = (min + max) / 2;
    status = mc_set_sndbuf(sd, avg);
    if (status != 0) {
      max = avg - 1;
    } else {
      min = avg + 1;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mc_maximize_sndbuf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  call   <mc_get_sndbuf@plt>
  cmp    $0x10000000,%eax
  ja     L10
  mov    %eax,%ebp
  mov    $0x10000000,%r12d
  jmp    L2
L38:
  lea    0x1(%rbx),%ebp
L40:
  cmp    %r12d,%ebp
  jg     L10
L2:
  lea    0x0(%rbp,%r12,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <mc_set_sndbuf@plt>
  test   %eax,%eax
  je     L38
  lea    -0x1(%rbx),%r12d
  jmp    L40
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mc_maximize_sndbuf(int sd) {
  int status, min, max, avg;
  min = mc_get_sndbuf(sd);
  if (min < 0) {
    return;
  }
  max = 256 * (1024 * (1024));
  while (min <= max) {
    avg = (min + max) / 2;
    status = mc_set_sndbuf(sd, avg);
    if (status != 0) {
      max = avg - 1;
    } else {
      min = avg + 1;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mc_maximize_sndbuf>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mc_get_sndbuf@plt>
  cmp    $0x10000000,%eax
  ja     L14
  mov    %eax,%ebp
  mov    $0x10000000,%r12d
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L16:
  lea    -0x1(%rbx),%r12d
  cmp    %ebp,%r12d
  jl     L14
L4:
  lea    0x0(%rbp,%r12,1),%ebx
  mov    %r13d,%edi
  sar    %ebx
  mov    %ebx,%esi
  call   <mc_set_sndbuf@plt>
  test   %eax,%eax
  jne    L16
  lea    0x1(%rbx),%ebp
  cmp    %ebp,%r12d
  jge    L4
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mc_maximize_sndbuf(int sd) {
  int status, min, max, avg;
  min = mc_get_sndbuf(sd);
  if (min < 0) {
    return;
  }
  max = 256 * (1024 * (1024));
  while (min <= max) {
    avg = (min + max) / 2;
    status = mc_set_sndbuf(sd, avg);
    if (status != 0) {
      max = avg - 1;
    } else {
      min = avg + 1;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mc_maximize_sndbuf>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mc_get_sndbuf@plt>
  cmp    $0x10000000,%eax
  ja     L35
  mov    %eax,%ebp
  mov    $0x10000000,%r12d
  nopl   (%rax)
L31:
  lea    0x0(%rbp,%r12,1),%ebx
  mov    %r13d,%edi
  sar    %ebx
  mov    %ebx,%esi
  call   <mc_set_sndbuf@plt>
  test   %eax,%eax
  je     L3
  lea    -0x1(%rbx),%r12d
  cmp    %ebp,%r12d
  jge    L31
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  lea    0x1(%rbx),%ebp
  cmp    %r12d,%ebp
  jle    L31
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mc_maximize_sndbuf(int sd) {
  int status, min, max, avg;
  min = mc_get_sndbuf(sd);
  if (min < 0) {
    return;
  }
  max = 256 * (1024 * (1024));
  while (min <= max) {
    avg = (min + max) / 2;
    status = mc_set_sndbuf(sd, avg);
    if (status != 0) {
      max = avg - 1;
    } else {
      min = avg + 1;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xxtea_to_ubyte_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  shl    $0x2,%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L30
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  subq   $0x4,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x3,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L39
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L53
L39:
  mov    $0x0,%eax
  jmp    L54
L53:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L14
L37:
  mov    -0x20(%rbp),%rax
  shr    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%eax
  and    $0x18,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
L14:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L37
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
L54:
  leave
  ret
```

assistant: ```c
uint8_t *xxtea_to_ubyte_array(const uint32_t *data, size_t len, int inc_len, size_t *out_len) {
  uint8_t *out;
  size_t i;
  size_t m, n;
  n = len << 2;
  if (inc_len) {
    m = data[len - 1];
    n -= 4;
    if ((m < n - 3) || (m > n))
      return NULL;
    n = m;
  }
  out = (uint8_t *)malloc(n + 1);
  for (i = 0; i < n; ++i) {
    out[i] = (uint8_t)(data[i >> 2] >> ((i & 3) << 3));
  }
  out[n] = '\0';
  *out_len = n;
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xxtea_to_ubyte_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rcx,%r12
  lea    0x0(,%rsi,4),%rax
  test   %edx,%edx
  je     L7
  mov    -0x8(%rdi,%rsi,8),%rbx
  lea    -0x4(%rax),%rdx
  cmp    %rdx,%rbx
  ja     L21
  sub    $0x7,%rax
  cmp    %rbx,%rax
  ja     L21
L25:
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rbx,%rbx
  je     L30
  mov    $0x0,%edx
L5:
  mov    %rdx,%rsi
  shr    $0x2,%rsi
  lea    0x0(,%rdx,8),%ecx
  and    $0x18,%ecx
  mov    0x0(%rbp,%rsi,8),%rsi
  shr    %cl,%rsi
  mov    %sil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L5
L30:
  movb   $0x0,(%rax,%rbx,1)
  mov    %rbx,(%r12)
L42:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %rax,%rbx
  jmp    L25
L21:
  mov    $0x0,%edi
  jmp    L42
```

assistant: ```c
uint8_t *xxtea_to_ubyte_array(const uint32_t *data, size_t len, int inc_len, size_t *out_len) {
  uint8_t *out;
  size_t i;
  size_t m, n;
  n = len << 2;
  if (inc_len) {
    m = data[len - 1];
    n -= 4;
    if ((m < n - 3) || (m > n))
      return NULL;
    n = m;
  }
  out = (uint8_t *)malloc(n + 1);
  for (i = 0; i < n; ++i) {
    out[i] = (uint8_t)(data[i >> 2] >> ((i & 3) << 3));
  }
  out[n] = '\0';
  *out_len = n;
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xxtea_to_ubyte_array>:
  endbr64
  push   %r12
  lea    0x0(,%rsi,4),%rax
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %edx,%edx
  je     L20
  mov    -0x8(%rdi,%rsi,8),%rbx
  lea    -0x7(%rax),%rdx
  cmp    %rbx,%rdx
  ja     L19
  sub    $0x4,%rax
  cmp    %rax,%rbx
  ja     L19
L48:
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  je     L4
  xor    %edx,%edx
  nopl   0x0(%rax)
L49:
  mov    %rdx,%rsi
  lea    0x0(,%rdx,8),%ecx
  shr    $0x2,%rsi
  and    $0x18,%ecx
  mov    0x0(%rbp,%rsi,8),%rsi
  shr    %cl,%rsi
  mov    %sil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L49
L4:
  movb   $0x0,(%rax,%rbx,1)
  mov    %r8,%rax
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L19:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rax,%rbx
  jmp    L48
```

assistant: ```c
uint8_t *xxtea_to_ubyte_array(const uint32_t *data, size_t len, int inc_len, size_t *out_len) {
  uint8_t *out;
  size_t i;
  size_t m, n;
  n = len << 2;
  if (inc_len) {
    m = data[len - 1];
    n -= 4;
    if ((m < n - 3) || (m > n))
      return NULL;
    n = m;
  }
  out = (uint8_t *)malloc(n + 1);
  for (i = 0; i < n; ++i) {
    out[i] = (uint8_t)(data[i >> 2] >> ((i & 3) << 3));
  }
  out[n] = '\0';
  *out_len = n;
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xxtea_to_ubyte_array>:
  endbr64
  push   %r12
  lea    0x0(,%rsi,4),%rax
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %edx,%edx
  je     L8
  mov    -0x8(%rdi,%rsi,8),%rbx
  lea    -0x7(%rax),%rdx
  cmp    %rbx,%rdx
  ja     L12
  sub    $0x4,%rax
  cmp    %rax,%rbx
  ja     L12
L29:
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  je     L16
  xor    %edx,%edx
  nopl   0x0(%rax)
L20:
  mov    %rdx,%rsi
  lea    0x0(,%rdx,8),%ecx
  shr    $0x2,%rsi
  and    $0x18,%ecx
  mov    0x0(%rbp,%rsi,8),%rsi
  shr    %cl,%rsi
  mov    %sil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L20
L16:
  movb   $0x0,(%rax,%rbx,1)
  mov    %r8,%rax
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L12:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rax,%rbx
  jmp    L29
```

assistant: ```c
uint8_t *xxtea_to_ubyte_array(const uint32_t *data, size_t len, int inc_len, size_t *out_len) {
  uint8_t *out;
  size_t i;
  size_t m, n;
  n = len << 2;
  if (inc_len) {
    m = data[len - 1];
    n -= 4;
    if ((m < n - 3) || (m > n))
      return NULL;
    n = m;
  }
  out = (uint8_t *)malloc(n + 1);
  for (i = 0; i < n; ++i) {
    out[i] = (uint8_t)(data[i >> 2] >> ((i & 3) << 3));
  }
  out[n] = '\0';
  *out_len = n;
  return out;
}
```