ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<luart_putc>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    $0x1,%ebp
  setbe  %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <luart_chktxi_@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <luart_settxi_@plt>
  nop
L4:
  mov    %ebp,%edi
  call   <luart_chktxc_@plt>
  test   %rax,%rax
  je     L4
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <luart_puttxd_@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <luart_settxi_@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int luart_putc(unsigned num, int c) {
  assert(num < 2);
  int s = luart_chktxi_(num);
  luart_settxi_(num, 0);
  while (luart_chktxc_(num) == 0)
    ;
  c = luart_puttxd_(num, c);
  luart_settxi_(num, s);
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<msg_add_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dynar_cat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void msg_add_len(struct dynar *msg) {
  uint32_t len;
  len = 0;
  dynar_cat(msg, &len, sizeof(len));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<msg_add_len>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <dynar_cat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_add_len(struct dynar *msg) {
  uint32_t len;
  len = 0;
  dynar_cat(msg, &len, sizeof(len));
}
```
user: What is the c source code of the assembly code below?

```asm
<msg_add_len>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <dynar_cat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_add_len(struct dynar *msg) {
  uint32_t len;
  len = 0;
  dynar_cat(msg, &len, sizeof(len));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msg_add_len>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <dynar_cat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_add_len(struct dynar *msg) {
  uint32_t len;
  len = 0;
  dynar_cat(msg, &len, sizeof(len));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <arreglo@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  arreglo();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <arreglo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  arreglo();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <arreglo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  arreglo();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <arreglo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  arreglo();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix_rotation_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  movq   D15(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,0x8(%rax)
  mov    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x10(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x10(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,0x10(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_infered: byte[8]
name: disassemble_data
arguments: label: D16
type_infered: byte[8]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void matrix_rotation_z(double cos_a, double sin_a, double R[][3]) {
  R[0][0] = cos_a;
  R[0][1] = -sin_a;
  R[0][2] = 0;
  R[1][0] = sin_a;
  R[1][1] = cos_a;
  R[1][2] = 0;
  R[2][0] = 0;
  R[2][1] = 0;
  R[2][2] = 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_rotation_z>:
  endbr64
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm2
  xorpd  D16(%rip),%xmm2
  movsd  %xmm2,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movsd  %xmm1,0x18(%rdi)
  movsd  %xmm0,0x20(%rdi)
  movq   $0x0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  mov    D15(%rip),%rax
  mov    %rax,0x40(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type: byte[16]
name: unpack_data
arguments: label: D15
type: byte[8]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void matrix_rotation_z(double cos_a, double sin_a, double R[][3]) {
  R[0][0] = cos_a;
  R[0][1] = -sin_a;
  R[0][2] = 0;
  R[1][0] = sin_a;
  R[1][1] = cos_a;
  R[1][2] = 0;
  R[2][0] = 0;
  R[2][1] = 0;
  R[2][2] = 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix_rotation_z>:
  endbr64
  mov    D6(%rip),%rax
  movapd %xmm1,%xmm2
  xorpd  D3(%rip),%xmm2
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  mov    %rax,0x40(%rdi)
  movsd  %xmm0,(%rdi)
  movsd  %xmm2,0x8(%rdi)
  movsd  %xmm1,0x18(%rdi)
  movsd  %xmm0,0x20(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: byte[8]
name: unpack_data
arguments: data_tag: D3
datatype: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void matrix_rotation_z(double cos_a, double sin_a, double R[][3]) {
  R[0][0] = cos_a;
  R[0][1] = -sin_a;
  R[0][2] = 0;
  R[1][0] = sin_a;
  R[1][1] = cos_a;
  R[1][2] = 0;
  R[2][0] = 0;
  R[2][1] = 0;
  R[2][2] = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_rotation_z>:
  endbr64
  movapd %xmm1,%xmm3
  xorpd  D1(%rip),%xmm3
  mov    D11(%rip),%rax
  movapd %xmm0,%xmm2
  movq   $0x0,0x10(%rdi)
  unpcklpd %xmm3,%xmm2
  movq   $0x0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  mov    %rax,0x40(%rdi)
  movups %xmm2,(%rdi)
  movsd  %xmm1,0x18(%rdi)
  movsd  %xmm0,0x20(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: byte[16]
name: disassemble_data
arguments: tag: D11
data_type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void matrix_rotation_z(double cos_a, double sin_a, double R[][3]) {
  R[0][0] = cos_a;
  R[0][1] = -sin_a;
  R[0][2] = 0;
  R[1][0] = sin_a;
  R[1][1] = cos_a;
  R[1][2] = 0;
  R[2][0] = 0;
  R[2][1] = 0;
  R[2][2] = 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <scanf_s@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L75
L86:
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L106:
  cmpl   $0x0,-0x10(%rbp)
  jle    L101
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L101
  cmpl   $0x0,-0xc(%rbp)
  jle    L101
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jge    L101
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L101
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L101:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L106
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L75:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L86
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L91
  call   <__stack_chk_fail@plt>
L91:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D52
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D57
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D53
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string

tool: D52: Enter length: 

tool: D57: %d

tool: D53:  

tool: D37: *

tool: D30: 


tool: D19: pause

assistant: ```c
main() {
  int i, j, length;
  printf("Enter length: ");
  scanf_s("%d", &length);
  for (i = 0; i < length; i++) {
    for (j = 0; j < length; j++) {
      if ((i > 0 && i < length - 1) && (j > 0 && j < length - 1) && (i != j)) {
        printf(" ");
      } else
        printf("*");
    }
    printf("\n");
  }
  system("pause");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf_s@plt>
  mov    $0x0,%ebp
  lea    D25(%rip),%r12
  lea    D4(%rip),%r14
  lea    D57(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L16
L42:
  lea    D21(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L94:
  mov    %r12,%rdi
  call   <printf@plt>
L85:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jle    L95
L9:
  test   %ebp,%ebp
  jle    L94
  sub    $0x1,%eax
  test   %ebx,%ebx
  setg   %dl
  cmp    %ebp,%eax
  setg   %cl
  and    %ecx,%edx
  cmp    %ebx,%eax
  setg   %al
  test   %al,%dl
  je     L94
  cmp    %ebx,%ebp
  je     L94
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L85
L95:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L42
L16:
  mov    0x4(%rsp),%eax
  mov    $0x0,%ebx
  test   %eax,%eax
  jg     L9
  jmp    L95
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D58
type_guessed: string
name: retrieve_data
arguments: data_label: D37
type_guessed: string
name: retrieve_data
arguments: data_label: D25
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D57
type_guessed: string
name: retrieve_data
arguments: data_label: D21
type_guessed: string

tool: D58: Enter length: 

tool: D37: %d

tool: D25: *

tool: D4:  

tool: D57: 


tool: D21: pause

assistant: ```c
main() {
  int i, j, length;
  printf("Enter length: ");
  scanf_s("%d", &length);
  for (i = 0; i < length; i++) {
    for (j = 0; j < length; j++) {
      if ((i > 0 && i < length - 1) && (j > 0 && j < length - 1) && (i != j)) {
        printf(" ");
      } else
        printf("*");
    }
    printf("\n");
  }
  system("pause");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  lea    D30(%rip),%rdi
  push   %r13
  lea    D55(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L39
  nopl   0x0(%rax)
L16:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L28:
  test   %ebx,%ebx
  je     L55
  sub    $0x1,%eax
  test   %r14d,%r14d
  setne  %dl
  cmp    %ebx,%eax
  setg   %cl
  and    %ecx,%edx
  cmp    %r14d,%eax
  setg   %al
  test   %al,%dl
  je     L55
  cmp    %r14d,%ebx
  jne    L20
L55:
  mov    %rbp,%rdi
  call   <printf@plt>
L30:
  mov    0x4(%rsp),%eax
  add    $0x1,%r14d
  cmp    %r14d,%eax
  jg     L28
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L16
L39:
  lea    D24(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L20:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L30
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D30
type_guessed: string
name: parse_data
arguments: label: D55
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string

tool: D30: Enter length: 

tool: D55:  

tool: D2: 


tool: D14: *

tool: D22: %d

tool: D24: pause

assistant: ```c
main() {
  int i, j, length;
  printf("Enter length: ");
  scanf_s("%d", &length);
  for (i = 0; i < length; i++) {
    for (j = 0; j < length; j++) {
      if ((i > 0 && i < length - 1) && (j > 0 && j < length - 1) && (i != j)) {
        printf(" ");
      } else
        printf("*");
    }
    printf("\n");
  }
  system("pause");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D37(%rip),%rdi
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D57(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L39
  nopl   0x0(%rax)
L29:
  xor    %r14d,%r14d
  test   %ebx,%ebx
  je     L76
  nopl   0x0(%rax,%rax,1)
L32:
  sub    $0x1,%eax
  test   %r14d,%r14d
  setne  %dl
  cmp    %r14d,%eax
  setg   %cl
  and    %ecx,%edx
  cmp    %ebx,%eax
  setg   %al
  test   %al,%dl
  je     L49
  mov    %r13,%rdi
  cmp    %r14d,%ebx
  jne    L86
L49:
  mov    %rbp,%rdi
L86:
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%r14d
  cmp    %r14d,%eax
  jg     L32
L21:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L29
L39:
  lea    D33(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L76:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    0x4(%rsp),%r14d
  jl     L76
  jmp    L21
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
data_type: string
name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D57
data_type: string
name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D33
data_type: string

tool: D37: Enter length: 

tool: D23:  

tool: D3: 


tool: D57: *

tool: D1: %d

tool: D33: pause

assistant: ```c
main() {
  int i, j, length;
  printf("Enter length: ");
  scanf_s("%d", &length);
  for (i = 0; i < length; i++) {
    for (j = 0; j < length; j++) {
      if ((i > 0 && i < length - 1) && (j > 0 && j < length - 1) && (i != j)) {
        printf(" ");
      } else
        printf("*");
    }
    printf("\n");
  }
  system("pause");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<slog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0xc,-0x4(%rbp)
  jmp    L34
L12:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L39
  mov    -0x4(%rbp),%eax
  jmp    L37
L39:
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x10,-0x4(%rbp)
  jle    L12
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int slog(unsigned int block) {
  int i;
  for (i = 12; i <= 16; i++)
    if (block == (1 << i))
      return i;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<slog>:
  endbr64
  cmp    $0x1000,%edi
  je     L35
  cmp    $0x2000,%edi
  je     L38
  cmp    $0x4000,%edi
  je     L26
  cmp    $0x8000,%edi
  je     L34
  cmp    $0x10000,%edi
  je     L20
  mov    $0x0,%eax
  ret
L38:
  mov    $0xd,%eax
  ret
L26:
  mov    $0xe,%eax
  ret
L34:
  mov    $0xf,%eax
  ret
L20:
  mov    $0x10,%eax
  ret
L35:
  mov    $0xc,%eax
  ret
```

assistant: ```c
unsigned int slog(unsigned int block) {
  int i;
  for (i = 12; i <= 16; i++)
    if (block == (1 << i))
      return i;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<slog>:
  endbr64
  cmp    $0x1000,%edi
  je     L25
  cmp    $0x2000,%edi
  je     L32
  cmp    $0x4000,%edi
  je     L16
  cmp    $0x8000,%edi
  je     L9
  xor    %eax,%eax
  cmp    $0x10000,%edi
  sete   %al
  shl    $0x4,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xc,%eax
  ret
  xchg   %ax,%ax
L32:
  mov    $0xd,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0xf,%eax
  ret
```

assistant: ```c
unsigned int slog(unsigned int block) {
  int i;
  for (i = 12; i <= 16; i++)
    if (block == (1 << i))
      return i;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<slog>:
  endbr64
  cmp    $0x1000,%edi
  je     L32
  cmp    $0x2000,%edi
  je     L13
  cmp    $0x4000,%edi
  je     L37
  cmp    $0x8000,%edi
  je     L11
  xor    %eax,%eax
  cmp    $0x10000,%edi
  sete   %al
  shl    $0x4,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0xc,%eax
  ret
  xchg   %ax,%ax
L13:
  mov    $0xd,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0xf,%eax
  ret
```

assistant: ```c
unsigned int slog(unsigned int block) {
  int i;
  for (i = 12; i <= 16; i++)
    if (block == (1 << i))
      return i;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<open_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L8
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L43
L8:
  mov    $0x0,%eax
L43:
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L16
L5:
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x34(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L35
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,-0x14(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int open_file(char *prefix, char *path, int flags) {
  int prefix_len = (prefix == NULL) ? 0 : strlen(prefix);
  int path_len = strlen(path);
  char *fullpath;
  int rv;
  fullpath = malloc(prefix_len + path_len + 1);
  if (fullpath == NULL)
    return -ENOMEM;
  memcpy(fullpath, prefix, prefix_len);
  memcpy(fullpath + prefix_len, path, path_len + 1);
  rv = open(fullpath, flags);
  if (rv < 0)
    rv = -errno;
  free(fullpath);
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<open_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L36
  call   <strlen@plt>
  mov    %eax,%ebx
L36:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L11
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r14),%edx
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L17
L43:
  mov    %rbp,%rdi
  call   <free@plt>
L26:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    D19(%rip),%rax
  mov    (%rax),%ebx
  neg    %ebx
  jmp    L26
L17:
  mov    D12(%rip),%rax
  mov    (%rax),%ebx
  neg    %ebx
  jmp    L43
```

assistant: ```c
int open_file(char *prefix, char *path, int flags) {
  int prefix_len = (prefix == NULL) ? 0 : strlen(prefix);
  int path_len = strlen(path);
  char *fullpath;
  int rv;
  fullpath = malloc(prefix_len + path_len + 1);
  if (fullpath == NULL)
    return -ENOMEM;
  memcpy(fullpath, prefix, prefix_len);
  memcpy(fullpath + prefix_len, path, path_len + 1);
  rv = open(fullpath, flags);
  if (rv < 0)
    rv = -errno;
  free(fullpath);
  return rv;
}
```