user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  lea    0x10(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%r15
  nopl   0x0(%rax)
L197:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  test   %ecx,%ecx
  je     L112
  mov    0x8(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %r15,%r8
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D24(%rip),%rdi
  movq   $0x0,0x30(%rsp)
  mov    %r12,%r14
  movq   $0x0,0x38(%rsp)
  lea    0x24(%rsp),%rbx
  movq   $0x0,0x40(%rsp)
  call   <scanf@plt>
  mov    %r12,%rcx
L120:
  mov    (%rcx),%eax
  add    $0x4,%rcx
  sub    $0x1,%eax
  cltq
  addl   $0x1,0x30(%rsp,%rax,8)
  cmp    %rbx,%rcx
  jne    L120
  mov    0x30(%rsp),%eax
  mov    0x38(%rsp),%ecx
  test   %eax,%eax
  jle    L193
  test   %ecx,%ecx
  jle    L127
  mov    0x40(%rsp),%edx
  test   %edx,%edx
  jle    L127
L35:
  movl   $0x3,0x34(%rsp)
  movl   $0x3,0x3c(%rsp)
  movl   $0x3,0x44(%rsp)
  nopl   0x0(%rax)
L33:
  mov    (%r14),%eax
  mov    %rbp,%rdi
  add    $0x4,%r14
  sub    $0x1,%eax
  cltq
  mov    0x34(%rsp,%rax,8),%esi
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L33
  jmp    L197
  nopw   0x0(%rax,%rax,1)
L127:
  cmp    $0x5,%eax
  je     L35
L193:
  cmp    $0x5,%ecx
  je     L35
  mov    0x40(%rsp),%esi
  cmp    $0x5,%esi
  je     L35
  test   %ecx,%ecx
  setg   %cl
  test   %eax,%eax
  setg   %al
  jle    L126
  test   %cl,%cl
  je     L126
  movl   $0x1,0x34(%rsp)
  movl   $0x2,0x3c(%rsp)
  jmp    L33
  nopl   (%rax)
L126:
  test   %esi,%esi
  setg   %sil
  jle    L92
  test   %cl,%cl
  je     L92
  movl   $0x1,0x3c(%rsp)
  movl   $0x2,0x44(%rsp)
  jmp    L33
  xchg   %ax,%ax
L92:
  test   %al,%al
  je     L33
  test   %sil,%sil
  je     L33
  movl   $0x1,0x44(%rsp)
  movl   $0x2,0x34(%rsp)
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L112:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L170
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L170:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D24
datatype: string

tool: D0: %d

tool: D19: %d


tool: D24: %d %d %d %d

assistant: ```c
int main(void) {
  int hand[5], kind[3][2], i, num;
  while (1) {
    scanf("%d", &hand[0]);
    if (hand[0] == 0)
      break;
    for (i = 0; i < 3; i++)
      kind[i][0] = 0, kind[i][1] = 0;
    scanf("%d %d %d %d", &hand[1], &hand[2], &hand[3], &hand[4]);
    for (i = 0; i < 5; i++)
      kind[hand[i] - 1][0]++;
    if ((kind[0][0] > 0 && kind[1][0] > 0 && kind[2][0] > 0) || kind[0][0] == 5 || kind[1][0] == 5 || kind[2][0] == 5) {
      kind[0][1] = 3, kind[1][1] = 3, kind[2][1] = 3;
    } else if (kind[0][0] > 0 && kind[1][0] > 0) {
      kind[0][1] = 1, kind[1][1] = 2;
    } else if (kind[1][0] > 0 && kind[2][0] > 0) {
      kind[1][1] = 1, kind[2][1] = 2;
    } else if (kind[2][0] > 0 && kind[0][0] > 0) {
      kind[2][1] = 1, kind[0][1] = 2;
    }
    for (i = 0; i < 5; i++) {
      printf("%d\n", kind[hand[i] - 1][1]);
    }
  }
  return 0;
}
```