ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bin2hex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %edx,%edx
  je     L6
  mov    %edx,%edx
  mov    %rsi,%rbp
  lea    (%rdi,%rdx,2),%r12
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  add    $0x2,%rbx
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <bits2ASCII@plt>
  mov    %al,-0x2(%rbx)
  movzbl -0x1(%rbp),%edi
  and    $0xf,%edi
  call   <bits2ASCII@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r12
  jne    L11
L6:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bin2hex(char *dst, char *src, int len) {
  while (len--) {
    *dst++ = bits2ASCII((*src >> 4) & 0xf);
    *dst++ = bits2ASCII(*src++ & 0xf);
  }
  *dst = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_ulong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  seta   %al
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  setb   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_ulong(const void *l1, const void *l2) {
  unsigned long a, b;
  a = (unsigned long)l1;
  b = (unsigned long)l2;
  return (a > b) - (a < b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_ulong>:
  endbr64
  cmp    %rsi,%rdi
  seta   %al
  movzbl %al,%eax
  sbb    $0x0,%eax
  ret
```

assistant: ```c
int compare_ulong(const void *l1, const void *l2) {
  unsigned long a, b;
  a = (unsigned long)l1;
  b = (unsigned long)l2;
  return (a > b) - (a < b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_ulong>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  seta   %al
  sbb    $0x0,%eax
  ret
```

assistant: ```c
int compare_ulong(const void *l1, const void *l2) {
  unsigned long a, b;
  a = (unsigned long)l1;
  b = (unsigned long)l2;
  return (a > b) - (a < b);
}
```
user: What is the c source code of the assembly code below?

```asm
<compare_ulong>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  seta   %al
  sbb    $0x0,%eax
  ret
```

assistant: ```c
int compare_ulong(const void *l1, const void *l2) {
  unsigned long a, b;
  a = (unsigned long)l1;
  b = (unsigned long)l2;
  return (a > b) - (a < b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<preinc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L4:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void preinc(long *q, long n) {
  long i;
  for (i = 0; i < n; i++)
    q[i] = i;
}
```
user: What is the c source code of the assembly code below?

```asm
<preinc>:
  endbr64
  test   %rsi,%rsi
  jle    L17
  mov    $0x0,%eax
L7:
  mov    %rax,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L7
L17:
  ret
```

assistant: ```c
void preinc(long *q, long n) {
  long i;
  for (i = 0; i < n; i++)
    q[i] = i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<preinc>:
  endbr64
  test   %rsi,%rsi
  jle    L17
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rax,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L7
L17:
  ret
```

assistant: ```c
void preinc(long *q, long n) {
  long i;
  for (i = 0; i < n; i++)
    q[i] = i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<preinc>:
  endbr64
  test   %rsi,%rsi
  jle    L13
  cmp    $0x1,%rsi
  je     L7
  mov    %rsi,%rdx
  movdqa D14(%rip),%xmm0
  movdqa D15(%rip),%xmm2
  mov    %rdi,%rax
  shr    %rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nop
L17:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddq  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L17
  mov    %rsi,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%esi
  je     L35
L0:
  mov    %rax,(%rdi,%rax,8)
L13:
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  ret
L7:
  xor    %eax,%eax
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D15
type_infered: byte[16]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D15": [0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void preinc(long *q, long n) {
  long i;
  for (i = 0; i < n; i++)
    q[i] = i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x6000(%rsp),%r11
L64:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L64
  sub    $0x440,%rsp
  mov    %rdi,-0x6428(%rbp)
  mov    %esi,-0x642c(%rbp)
  mov    %edx,-0x6430(%rbp)
  mov    %rcx,-0x6438(%rbp)
  mov    %r8d,-0x643c(%rbp)
  mov    %r9d,-0x6440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x642c(%rbp),%eax
  cmp    -0x643c(%rbp),%eax
  jne    L61
  mov    -0x6430(%rbp),%eax
  cmp    -0x6440(%rbp),%eax
  je     L39
L61:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L80
L39:
  movl   $0x0,-0x6418(%rbp)
  jmp    L44
L34:
  movl   $0x0,-0x6414(%rbp)
  jmp    L70
L47:
  mov    -0x6418(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x6428(%rbp),%rax
  add    %rax,%rdx
  mov    -0x6414(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x6418(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x6438(%rbp),%rax
  add    %rax,%rdx
  mov    -0x6414(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  add    %eax,%ecx
  mov    -0x6414(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x6418(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  add    %rsi,%rax
  mov    %ecx,-0x6410(%rbp,%rax,4)
  addl   $0x1,-0x6414(%rbp)
L70:
  mov    -0x6414(%rbp),%eax
  cmp    -0x6430(%rbp),%eax
  jl     L47
  addl   $0x1,-0x6418(%rbp)
L44:
  mov    -0x6418(%rbp),%eax
  cmp    -0x642c(%rbp),%eax
  jl     L34
  mov    -0x6430(%rbp),%edx
  mov    -0x642c(%rbp),%ecx
  lea    -0x6410(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mat_write@plt>
L80:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: Not Possible

assistant: ```c
void mat_add(int m1[][80], int r1, int c1, int m2[][80], int r2, int c2) {
  int i, j;
  int m[80][80];
  if (r1 != r2 || c1 != c2)
    puts("Not Possible");
  else {
    for (i = 0; i < r1; ++i)
      for (j = 0; j < c1; ++j)
        m[i][j] = m1[i][j] + m2[i][j];
    mat_write(m, r1, c1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat_add>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x6000(%rsp),%r11
L55:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L55
  sub    $0x418,%rsp
  mov    %edx,%ebx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x6408(%rsp)
  xor    %edx,%edx
  cmp    %r8d,%esi
  jne    L67
  mov    %esi,%r11d
  cmp    %r9d,%ebx
  jne    L67
  test   %esi,%esi
  jle    L59
  mov    %rdi,%r9
  mov    %rcx,%r10
  mov    %rsp,%rcx
  lea    -0x1(%rsi),%edx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x6,%rdx
  lea    0x140(%rdi,%rdx,1),%rbp
  lea    -0x1(%rbx),%r8d
  jmp    L25
L67:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L32
L0:
  mov    (%rsi,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%r8
  jne    L0
L50:
  add    $0x140,%r9
  add    $0x140,%r10
  add    $0x140,%rcx
  cmp    %rbp,%r9
  je     L59
L25:
  mov    %r9,%rdi
  mov    %r10,%rsi
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L0
  jmp    L50
L59:
  mov    %rsp,%rdi
  mov    %ebx,%edx
  mov    %r11d,%esi
  call   <mat_write@plt>
L32:
  mov    0x6408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x6418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: Not Possible

assistant: ```c
void mat_add(int m1[][80], int r1, int c1, int m2[][80], int r2, int c2) {
  int i, j;
  int m[80][80];
  if (r1 != r2 || c1 != c2)
    puts("Not Possible");
  else {
    for (i = 0; i < r1; ++i)
      for (j = 0; j < c1; ++j)
        m[i][j] = m1[i][j] + m2[i][j];
    mat_write(m, r1, c1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat_add>:
  endbr64
  push   %rbp
  lea    -0x6000(%rsp),%r11
L25:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L25
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x6408(%rsp)
  xor    %eax,%eax
  cmp    %r8d,%esi
  jne    L6
  mov    %edx,%r10d
  cmp    %r9d,%edx
  jne    L6
  mov    %esi,%r11d
  mov    %rsp,%rbp
  test   %esi,%esi
  jle    L60
  lea    -0x1(%r11),%eax
  mov    %rdi,%rsi
  mov    %rsp,%rbp
  movslq %edx,%r8
  lea    (%rax,%rax,4),%rax
  mov    %rbp,%rdi
  shl    $0x6,%rax
  lea    0x140(%rsi,%rax,1),%r9
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %eax,%eax
  test   %r10d,%r10d
  jle    L56
  nopw   0x0(%rax,%rax,1)
L57:
  mov    (%rcx,%rax,4),%edx
  add    (%rsi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L57
L56:
  add    $0x140,%rsi
  add    $0x140,%rcx
  add    $0x140,%rdi
  cmp    %r9,%rsi
  jne    L58
L60:
  mov    %r10d,%edx
  mov    %r11d,%esi
  mov    %rbp,%rdi
  call   <mat_write@plt>
  mov    0x6408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x6410,%rsp
  pop    %rbp
  ret
L6:
  mov    0x6408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x6410,%rsp
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: Not Possible

assistant: ```c
void mat_add(int m1[][80], int r1, int c1, int m2[][80], int r2, int c2) {
  int i, j;
  int m[80][80];
  if (r1 != r2 || c1 != c2)
    puts("Not Possible");
  else {
    for (i = 0; i < r1; ++i)
      for (j = 0; j < c1; ++j)
        m[i][j] = m1[i][j] + m2[i][j];
    mat_write(m, r1, c1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat_add>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x6000(%rsp),%r11
L121:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L121
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x6418(%rsp)
  xor    %eax,%eax
  cmp    %r8d,%esi
  jne    L129
  mov    %edx,%r11d
  cmp    %r9d,%edx
  jne    L129
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L143
  test   %edx,%edx
  jle    L143
  lea    -0x1(%rdx),%eax
  mov    %edx,%r15d
  mov    %rdi,%rbx
  mov    %rcx,%r12
  mov    %eax,0xc(%rsp)
  mov    %edx,%eax
  and    $0xfffffffc,%r15d
  xor    %r9d,%r9d
  shr    $0x2,%eax
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r13
  xor    %edi,%edi
  lea    -0x1(%rax),%r8d
  add    $0x1,%r8
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L70:
  xor    %eax,%eax
  cmpl   $0x2,0xc(%rsp)
  lea    (%rbx,%r9,1),%rdx
  lea    (%r12,%r9,1),%rcx
  lea    0x0(%r13,%r9,1),%rsi
  jbe    L89
  nopw   0x0(%rax,%rax,1)
L74:
  movdqu (%rdx,%rax,1),%xmm0
  movdqu (%rcx,%rax,1),%xmm2
  paddd  %xmm2,%xmm0
  movaps %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L74
  cmp    %r15d,%r11d
  je     L35
  mov    %r15d,%esi
  mov    %r15d,%eax
L148:
  mov    %r11d,%r10d
  sub    %esi,%r10d
  cmp    $0x1,%r10d
  je     L77
  add    %r14,%rsi
  movq   (%rbx,%rsi,4),%xmm0
  movq   (%r12,%rsi,4),%xmm1
  paddd  %xmm1,%xmm0
  movq   %xmm0,0x10(%rsp,%rsi,4)
  mov    %r10d,%esi
  and    $0xfffffffe,%esi
  add    %esi,%eax
  cmp    %esi,%r10d
  je     L35
L77:
  movslq %eax,%r10
  movslq %edi,%rax
  lea    (%rax,%rax,4),%rsi
  mov    (%rcx,%r10,4),%eax
  add    (%rdx,%r10,4),%eax
  shl    $0x4,%rsi
  add    %r10,%rsi
  mov    %eax,0x10(%rsp,%rsi,4)
L35:
  add    $0x1,%edi
  add    $0x50,%r14
  add    $0x140,%r9
  cmp    %edi,%ebp
  jne    L70
L3:
  mov    %r11d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <mat_write@plt>
  mov    0x6418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L118
  add    $0x6428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L148
L129:
  mov    0x6418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L118
  add    $0x6428,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <puts@plt>
L143:
  lea    0x10(%rsp),%r13
  jmp    L3
L118:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Not Possible

assistant: ```c
void mat_add(int m1[][80], int r1, int c1, int m2[][80], int r2, int c2) {
  int i, j;
  int m[80][80];
  if (r1 != r2 || c1 != c2)
    puts("Not Possible");
  else {
    for (i = 0; i < r1; ++i)
      for (j = 0; j < c1; ++j)
        m[i][j] = m1[i][j] + m2[i][j];
    mat_write(m, r1, c1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_best_tree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L7:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L35:
  cmpl   $0x31,-0x8(%rbp)
  jbe    L7
  mov    -0xc(%rbp),%eax
  and    $0x3ff,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L39
L9:
  sarl   $0xa,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x3ff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jae    L1
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L1:
  addl   $0x1,-0x14(%rbp)
L39:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L9
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_best_tree(const uint16_t *gs, unsigned nt, const uint64_t *len_pack) {
  unsigned c, bc;
  unsigned t, bt;
  uint64_t cp;
  unsigned i;
  cp = 0;
  for (i = 0; i < 50; i++)
    cp += len_pack[gs[i]];
  bc = cp & 0x3ff;
  bt = 0;
  for (t = 1; t < nt; t++) {
    cp >>= 10;
    c = cp & 0x3ff;
    if (c < bc)
      bc = c, bt = t;
  }
  return bt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_best_tree>:
  endbr64
  mov    %rdi,%rax
  lea    0x190(%rdi),%r8
  mov    $0x0,%ecx
L18:
  mov    (%rax),%rdi
  add    (%rdx,%rdi,4),%ecx
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L18
  mov    %ecx,%edi
  and    $0x3ff,%edi
  cmp    $0x1,%esi
  jbe    L36
  mov    $0x0,%r8d
  mov    $0x1,%eax
  jmp    L0
L45:
  add    $0x1,%eax
  cmp    %eax,%esi
  je     L44
L0:
  sar    $0xa,%ecx
  mov    %ecx,%edx
  and    $0x3ff,%edx
  cmp    %edi,%edx
  jae    L45
  mov    %eax,%r8d
  mov    %edx,%edi
  jmp    L45
L36:
  mov    $0x0,%r8d
L44:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_best_tree(const uint16_t *gs, unsigned nt, const uint64_t *len_pack) {
  unsigned c, bc;
  unsigned t, bt;
  uint64_t cp;
  unsigned i;
  cp = 0;
  for (i = 0; i < 50; i++)
    cp += len_pack[gs[i]];
  bc = cp & 0x3ff;
  bt = 0;
  for (t = 1; t < nt; t++) {
    cp >>= 10;
    c = cp & 0x3ff;
    if (c < bc)
      bc = c, bt = t;
  }
  return bt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_best_tree>:
  endbr64
  lea    0x190(%rdi),%r8
  xor    %ecx,%ecx
  nopl   (%rax)
L21:
  mov    (%rdi),%rax
  add    $0x8,%rdi
  add    (%rdx,%rax,4),%ecx
  cmp    %rdi,%r8
  jne    L21
  mov    %ecx,%r8d
  xor    %eax,%eax
  and    $0x3ff,%r8d
  cmp    $0x1,%esi
  jbe    L29
  mov    $0x1,%edx
  nopl   (%rax)
L0:
  sar    $0xa,%ecx
  mov    %ecx,%edi
  and    $0x3ff,%edi
  cmp    %r8d,%edi
  jae    L23
  mov    %edx,%eax
  mov    %edi,%r8d
L23:
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L0
  ret
L29:
  ret
```

assistant: ```c
int find_best_tree(const uint16_t *gs, unsigned nt, const uint64_t *len_pack) {
  unsigned c, bc;
  unsigned t, bt;
  uint64_t cp;
  unsigned i;
  cp = 0;
  for (i = 0; i < 50; i++)
    cp += len_pack[gs[i]];
  bc = cp & 0x3ff;
  bt = 0;
  for (t = 1; t < nt; t++) {
    cp >>= 10;
    c = cp & 0x3ff;
    if (c < bc)
      bc = c, bt = t;
  }
  return bt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_best_tree>:
  endbr64
  lea    0x190(%rdi),%r8
  xor    %ecx,%ecx
  nopl   (%rax)
L20:
  mov    (%rdi),%rax
  add    $0x8,%rdi
  add    (%rdx,%rax,4),%ecx
  cmp    %rdi,%r8
  jne    L20
  mov    %ecx,%r8d
  xor    %eax,%eax
  and    $0x3ff,%r8d
  cmp    $0x1,%esi
  jbe    L23
  mov    $0x1,%edx
  nopl   (%rax)
L14:
  sar    $0xa,%ecx
  mov    %ecx,%edi
  and    $0x3ff,%edi
  cmp    %r8d,%edi
  jae    L16
  mov    %edx,%eax
  mov    %edi,%r8d
L16:
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L14
  ret
L23:
  ret
```

assistant: ```c
int find_best_tree(const uint16_t *gs, unsigned nt, const uint64_t *len_pack) {
  unsigned c, bc;
  unsigned t, bt;
  uint64_t cp;
  unsigned i;
  cp = 0;
  for (i = 0; i < 50; i++)
    cp += len_pack[gs[i]];
  bc = cp & 0x3ff;
  bt = 0;
  for (t = 1; t < nt; t++) {
    cp >>= 10;
    c = cp & 0x3ff;
    if (c < bc)
      bc = c, bt = t;
  }
  return bt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<saa7114_get_decoder_output_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xcc,%edi
  call   <saa7114_read_reg@plt>
  movzbl -0x11(%rbp),%eax
  movzbl %al,%eax
  mov    %rax,-0x10(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xcd,%edi
  call   <saa7114_read_reg@plt>
  movzbl -0x11(%rbp),%eax
  movzbl %al,%eax
  shl    $0x8,%rax
  or     %rax,-0x10(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xce,%edi
  call   <saa7114_read_reg@plt>
  movzbl -0x11(%rbp),%eax
  movzbl %al,%eax
  shl    $0x11,%rax
  or     %rax,-0x10(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xcf,%edi
  call   <saa7114_read_reg@plt>
  movzbl -0x11(%rbp),%eax
  movzbl %al,%eax
  shl    $0x19,%rax
  or     %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned long saa7114_get_decoder_output_size(void) {
  unsigned long value = 0;
  unsigned char data;
  saa7114_read_reg(0xCC, &data);
  value = (unsigned long)data;
  saa7114_read_reg(0xCD, &data);
  value |= ((unsigned long)data) << 8;
  saa7114_read_reg(0xCE, &data);
  value |= ((unsigned long)data) << 17;
  saa7114_read_reg(0xCF, &data);
  value |= ((unsigned long)data) << 25;
  return (value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<saa7114_get_decoder_output_size>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  mov    %rbp,%rsi
  mov    $0xcc,%edi
  call   <saa7114_read_reg@plt>
  movzbl 0x7(%rsp),%r13d
  mov    %rbp,%rsi
  mov    $0xcd,%edi
  call   <saa7114_read_reg@plt>
  movzbl 0x7(%rsp),%r12d
  shl    $0x8,%r12
  mov    %rbp,%rsi
  mov    $0xce,%edi
  call   <saa7114_read_reg@plt>
  movzbl 0x7(%rsp),%ebx
  shl    $0x11,%rbx
  or     %r12,%rbx
  or     %r13,%rbx
  mov    %rbp,%rsi
  mov    $0xcf,%edi
  call   <saa7114_read_reg@plt>
  movzbl 0x7(%rsp),%eax
  shl    $0x19,%rax
  or     %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long saa7114_get_decoder_output_size(void) {
  unsigned long value = 0;
  unsigned char data;
  saa7114_read_reg(0xCC, &data);
  value = (unsigned long)data;
  saa7114_read_reg(0xCD, &data);
  value |= ((unsigned long)data) << 8;
  saa7114_read_reg(0xCE, &data);
  value |= ((unsigned long)data) << 17;
  saa7114_read_reg(0xCF, &data);
  value |= ((unsigned long)data) << 25;
  return (value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<saa7114_get_decoder_output_size>:
  endbr64
  push   %r13
  mov    $0xcc,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  mov    %rbp,%rsi
  call   <saa7114_read_reg@plt>
  mov    %rbp,%rsi
  mov    $0xcd,%edi
  movzbl 0x7(%rsp),%r13d
  call   <saa7114_read_reg@plt>
  mov    %rbp,%rsi
  mov    $0xce,%edi
  movzbl 0x7(%rsp),%r12d
  call   <saa7114_read_reg@plt>
  movzbl 0x7(%rsp),%ebx
  mov    %rbp,%rsi
  mov    $0xcf,%edi
  call   <saa7114_read_reg@plt>
  shl    $0x8,%r12
  movzbl 0x7(%rsp),%eax
  shl    $0x11,%rbx
  or     %r12,%rbx
  shl    $0x19,%rax
  or     %r13,%rbx
  or     %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long saa7114_get_decoder_output_size(void) {
  unsigned long value = 0;
  unsigned char data;
  saa7114_read_reg(0xCC, &data);
  value = (unsigned long)data;
  saa7114_read_reg(0xCD, &data);
  value |= ((unsigned long)data) << 8;
  saa7114_read_reg(0xCE, &data);
  value |= ((unsigned long)data) << 17;
  saa7114_read_reg(0xCF, &data);
  value |= ((unsigned long)data) << 25;
  return (value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<saa7114_get_decoder_output_size>:
  endbr64
  push   %r13
  mov    $0xcc,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  mov    %rbp,%rsi
  call   <saa7114_read_reg@plt>
  mov    %rbp,%rsi
  mov    $0xcd,%edi
  movzbl 0x7(%rsp),%r13d
  call   <saa7114_read_reg@plt>
  mov    %rbp,%rsi
  mov    $0xce,%edi
  movzbl 0x7(%rsp),%r12d
  call   <saa7114_read_reg@plt>
  movzbl 0x7(%rsp),%ebx
  mov    %rbp,%rsi
  mov    $0xcf,%edi
  call   <saa7114_read_reg@plt>
  shl    $0x8,%r12
  movzbl 0x7(%rsp),%eax
  shl    $0x11,%rbx
  or     %r12,%rbx
  shl    $0x19,%rax
  or     %r13,%rbx
  or     %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long saa7114_get_decoder_output_size(void) {
  unsigned long value = 0;
  unsigned char data;
  saa7114_read_reg(0xCC, &data);
  value = (unsigned long)data;
  saa7114_read_reg(0xCD, &data);
  value |= ((unsigned long)data) << 8;
  saa7114_read_reg(0xCE, &data);
  value |= ((unsigned long)data) << 17;
  saa7114_read_reg(0xCF, &data);
  value |= ((unsigned long)data) << 25;
  return (value);
}
```