ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<linenoiseHistoryLoad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D7(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L58
  mov    %rax,%rbp
  mov    %rsp,%rbx
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L27:
  movb   $0x0,(%rax)
L25:
  mov    %rbx,%rdi
  call   <linenoiseHistoryAdd@plt>
L53:
  mov    %rbp,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L78
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L27
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L25
  jmp    L27
  xchg   %ax,%ax
L78:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L10:
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  mov    $0xffffffff,%eax
  jmp    L10
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: r

assistant: ```c
int linenoiseHistoryLoad(const char *filename) {
  FILE *fp = fopen(filename, "r");
  char buf[4096];
  if (fp == NULL)
    return -1;
  while (fgets(buf, 4096, fp) != NULL) {
    char *p;
    p = strchr(buf, '\r');
    if (!p)
      p = strchr(buf, '\n');
    if (p)
      *p = '\0';
    linenoiseHistoryAdd(buf);
  }
  fclose(fp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<linenoiseHistoryLoad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D9(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L25
  mov    %rax,%rbp
  mov    %rsp,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L30:
  movb   $0x0,(%rax)
L5:
  mov    %rbx,%rdi
  call   <linenoiseHistoryAdd@plt>
L1:
  mov    %rbp,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L21
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L30
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  jmp    L30
  xchg   %ax,%ax
L21:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L52:
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0xffffffff,%eax
  jmp    L52
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: r

assistant: ```c
int linenoiseHistoryLoad(const char *filename) {
  FILE *fp = fopen(filename, "r");
  char buf[4096];
  if (fp == NULL)
    return -1;
  while (fgets(buf, 4096, fp) != NULL) {
    char *p;
    p = strchr(buf, '\r');
    if (!p)
      p = strchr(buf, '\n');
    if (p)
      *p = '\0';
    linenoiseHistoryAdd(buf);
  }
  fclose(fp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0xc(%rbp)
  jmp    L20
L21:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L14
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L20:
  cmpl   $0x3d0900,-0xc(%rbp)
  jle    L21
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int n_2 = 1;
  int n_1 = 2;
  int cur;
  int sum = 2;
  for (cur = 3; cur <= 4000000; cur = n_2 + n_1) {
    if (cur % 2 == 0)
      sum += cur;
    n_2 = n_1;
    n_1 = cur;
  }
  printf("%d\n", sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%ecx
  mov    $0x2,%esi
L12:
  lea    (%rcx,%rdx,1),%eax
  cmp    $0x3d0900,%eax
  jg     L15
  lea    (%rsi,%rax,1),%ecx
  test   $0x1,%al
  cmove  %ecx,%esi
  mov    %edx,%ecx
  mov    %eax,%edx
  jmp    L12
L15:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int n_2 = 1;
  int n_1 = 2;
  int cur;
  int sum = 2;
  for (cur = 3; cur <= 4000000; cur = n_2 + n_1) {
    if (cur % 2 == 0)
      sum += cur;
    n_2 = n_1;
    n_1 = cur;
  }
  printf("%d\n", sum);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%ecx
  mov    $0x2,%esi
  jmp    L13
  nopl   0x0(%rax)
L15:
  lea    (%rsi,%rax,1),%ecx
  test   $0x1,%al
  cmove  %ecx,%esi
  mov    %edx,%ecx
  mov    %eax,%edx
L13:
  lea    (%rdx,%rcx,1),%eax
  cmp    $0x3d0900,%eax
  jle    L15
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main() {
  int n_2 = 1;
  int n_1 = 2;
  int cur;
  int sum = 2;
  for (cur = 3; cur <= 4000000; cur = n_2 + n_1) {
    if (cur % 2 == 0)
      sum += cur;
    n_2 = n_1;
    n_1 = cur;
  }
  printf("%d\n", sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x5,%eax
  mov    $0x2,%esi
  jmp    L4
  nopl   0x0(%rax)
L17:
  mov    %edx,%eax
L4:
  lea    (%rsi,%rax,1),%edx
  test   $0x1,%al
  cmove  %edx,%esi
  lea    (%rcx,%rax,1),%edx
  mov    %eax,%ecx
  cmp    $0x3d0900,%edx
  jle    L17
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  int n_2 = 1;
  int n_1 = 2;
  int cur;
  int sum = 2;
  for (cur = 3; cur <= 4000000; cur = n_2 + n_1) {
    if (cur % 2 == 0)
      sum += cur;
    n_2 = n_1;
    n_1 = cur;
  }
  printf("%d\n", sum);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dh_compute_public_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *dh_compute_public_key(unsigned char *pub, size_t pub_size, const unsigned char *priv, size_t priv_size) {
  errno = ENOSYS;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dh_compute_public_key>:
  endbr64
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char *dh_compute_public_key(unsigned char *pub, size_t pub_size, const unsigned char *priv, size_t priv_size) {
  errno = ENOSYS;
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dh_compute_public_key>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *dh_compute_public_key(unsigned char *pub, size_t pub_size, const unsigned char *priv, size_t priv_size) {
  errno = ENOSYS;
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dh_compute_public_key>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *dh_compute_public_key(unsigned char *pub, size_t pub_size, const unsigned char *priv, size_t priv_size) {
  errno = ENOSYS;
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L17:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L17
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double mul(unsigned int numArgs, double *args) {
  double product = args[0];
  unsigned int i;
  for (i = 1; i < numArgs; i++)
    product *= args[i];
  return product;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mul>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jbe    L19
  lea    0x8(%rsi),%rax
  lea    -0x2(%rdi),%edx
  lea    0x10(%rsi,%rdx,8),%rdx
L17:
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L17
L19:
  ret
```

assistant: ```c
double mul(unsigned int numArgs, double *args) {
  double product = args[0];
  unsigned int i;
  for (i = 1; i < numArgs; i++)
    product *= args[i];
  return product;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mul>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jbe    L12
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax)
L9:
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L9
L12:
  ret
```

assistant: ```c
double mul(unsigned int numArgs, double *args) {
  double product = args[0];
  unsigned int i;
  for (i = 1; i < numArgs; i++)
    product *= args[i];
  return product;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mul>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jbe    L14
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax)
L8:
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L8
L14:
  ret
```

assistant: ```c
double mul(unsigned int numArgs, double *args) {
  double product = args[0];
  unsigned int i;
  for (i = 1; i < numArgs; i++)
    product *= args[i];
  return product;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stq_le_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stl_le_p@plt>
  mov    $0x20,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stl_le_p@plt>
  nop
  leave
  ret
```

assistant: ```c
void stq_le_p(void *ptr, uint64_t v) {
  uint8_t *p = ptr;
  stl_le_p(p, (uint32_t)v);
  stl_le_p(p + 4, v >> 32);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stq_le_p>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <stl_le_p@plt>
  mov    %ebp,%esi
  mov    $0x20,%ecx
  sar    %cl,%esi
  lea    0x10(%rbx),%rdi
  call   <stl_le_p@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stq_le_p(void *ptr, uint64_t v) {
  uint8_t *p = ptr;
  stl_le_p(p, (uint32_t)v);
  stl_le_p(p + 4, v >> 32);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stq_le_p>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <stl_le_p@plt>
  mov    %ebp,%esi
  add    $0x8,%rsp
  mov    $0x20,%ecx
  lea    0x10(%rbx),%rdi
  sar    %cl,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <stl_le_p@plt>
```

assistant: ```c
void stq_le_p(void *ptr, uint64_t v) {
  uint8_t *p = ptr;
  stl_le_p(p, (uint32_t)v);
  stl_le_p(p + 4, v >> 32);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stq_le_p>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <stl_le_p@plt>
  mov    %ebp,%esi
  add    $0x8,%rsp
  mov    $0x20,%ecx
  lea    0x10(%rbx),%rdi
  sar    %cl,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <stl_le_p@plt>
```

assistant: ```c
void stq_le_p(void *ptr, uint64_t v) {
  uint8_t *p = ptr;
  stl_le_p(p, (uint32_t)v);
  stl_le_p(p + 4, v >> 32);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L34:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L34
  jmp    L13
L48:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L8
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L13:
  cmpl   $0xa,-0x8(%rbp)
  je     L3
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L48
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n)
      str[i++] = ch;
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r12d
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x0,%ebp
  cmp    $0xa,%ebx
  je     L14
  mov    D2(%rip),%r14
  jmp    L46
L14:
  mov    $0x0,%ebp
L0:
  movslq %ebp,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L0
L46:
  cmp    %ebx,(%r14)
  je     L0
  cmp    %ebp,%r12d
  jle    L1
  movslq %ebp,%rax
  mov    %bl,0x0(%r13,%rax,1)
  lea    0x1(%rbp),%ebp
  jmp    L1
```

assistant: ```c
int read_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n)
      str[i++] = ch;
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L24
  mov    %r12,%rax
  xor    %r15d,%r15d
  cmp    $0xa,%ebx
  je     L35
  mov    D8(%rip),%r14
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  jmp    L46
  xchg   %ax,%ax
L11:
  cmp    %r15d,%r13d
  jle    L1
  mov    %bl,(%rax)
  add    $0x1,%r15d
  movslq %r15d,%rbp
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L60
L46:
  lea    (%r12,%rbp,1),%rax
  cmp    %ebx,(%r14)
  jne    L11
L35:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  lea    (%r12,%rbp,1),%rax
  jmp    L35
```

assistant: ```c
int read_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n)
      str[i++] = ch;
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbp,%rax
  xor    %r14d,%r14d
  cmp    $0xa,%ebx
  je     L62
  mov    D4(%rip),%r13
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  nopl   (%rax)
L49:
  lea    0x0(%rbp,%r15,1),%rax
  cmp    %ebx,0x0(%r13)
  je     L62
  cmp    %r14d,%r12d
  jle    L0
  mov    %bl,(%rax)
  xor    %eax,%eax
  add    $0x1,%r14d
  movslq %r14d,%r15
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  jne    L49
  lea    0x0(%rbp,%r15,1),%rax
L62:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  jne    L49
  lea    0x0(%rbp,%r15,1),%rax
  jmp    L62
```

assistant: ```c
int read_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n)
      str[i++] = ch;
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<extract_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    $0x0,%r9d
  mov    $0x1b3,%r8d
  lea    D2(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <reallocate@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fix_escaping@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c

assistant: ```c
char *extract_token(const char *s, size_t l) {
  char *token;
  token = reallocate(NULL, (l + 1), (sizeof(char)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c", 435, false);
  strncpy(token, s, l);
  token[l] = '\0';
  fix_escaping(token, l);
  return token;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extract_token>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rsi
  mov    $0x0,%r9d
  mov    $0x1b3,%r8d
  lea    D9(%rip),%rcx
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <reallocate@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fix_escaping@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c

assistant: ```c
char *extract_token(const char *s, size_t l) {
  char *token;
  token = reallocate(NULL, (l + 1), (sizeof(char)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c", 435, false);
  strncpy(token, s, l);
  token[l] = '\0';
  fix_escaping(token, l);
  return token;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<extract_token>:
  endbr64
  push   %r13
  xor    %r9d,%r9d
  mov    %rdi,%r13
  mov    $0x1b3,%r8d
  push   %r12
  lea    D8(%rip),%rcx
  mov    $0x1,%edx
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rsi
  call   <reallocate@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fix_escaping@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c

assistant: ```c
char *extract_token(const char *s, size_t l) {
  char *token;
  token = reallocate(NULL, (l + 1), (sizeof(char)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c", 435, false);
  strncpy(token, s, l);
  token[l] = '\0';
  fix_escaping(token, l);
  return token;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extract_token>:
  endbr64
  push   %r13
  xor    %r9d,%r9d
  mov    %rdi,%r13
  mov    $0x1b3,%r8d
  push   %r12
  lea    D8(%rip),%rcx
  mov    $0x1,%edx
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rsi
  call   <reallocate@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fix_escaping@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c

assistant: ```c
char *extract_token(const char *s, size_t l) {
  char *token;
  token = reallocate(NULL, (l + 1), (sizeof(char)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/RecipeML/Recipe/refs/heads/master/src/grammar.c", 435, false);
  strncpy(token, s, l);
  token[l] = '\0';
  fix_escaping(token, l);
  return token;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  mov    $0x0,%ebx
  jmp    L23
L32:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  add    $0x1,%rbx
L23:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,%rbx
  jb     L32
  jmp    L37
L20:
  nop
L37:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t my_strnlen(char const *string, int size) {
  register size_t length;
  for (length = 0; length < size; length += 1)
    if (*string++ == '\0')
      break;
  return length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strnlen>:
  endbr64
  movslq %esi,%rsi
  test   %rsi,%rsi
  je     L11
  mov    $0x0,%eax
L20:
  cmpb   $0x0,(%rdi,%rax,1)
  je     L24
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L20
  jmp    L11
L24:
  mov    %rax,%rsi
L11:
  mov    %rsi,%rax
  ret
```

assistant: ```c
size_t my_strnlen(char const *string, int size) {
  register size_t length;
  for (length = 0; length < size; length += 1)
    if (*string++ == '\0')
      break;
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_strnlen>:
  endbr64
  movslq %esi,%r8
  test   %r8,%r8
  je     L12
  xor    %eax,%eax
  jmp    L20
L6:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L12
L20:
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L6
  mov    %rax,%r8
L12:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t my_strnlen(char const *string, int size) {
  register size_t length;
  for (length = 0; length < size; length += 1)
    if (*string++ == '\0')
      break;
  return length;
}
```