ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D6(%rip),%rdi
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L14
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jle    L18
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    %ebx,%eax
  cmp    %r15d,%eax
  jge    L42
L18:
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,%ebp
  jne    L34
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x2,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L11
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D9
type: string

tool: D6: Kolko redove iskash : 

tool: D17: 


tool: D15: * 

tool: D13:   

tool: D9: %d

assistant: ```c
int main() {
  int i, q, n, z = 0;
  printf("Kolko redove iskash : ");
  scanf("%d", &n);
  for (i = 1; i <= n; ++i) {
    for (q = 1; q <= n - i; ++q) {
      printf("  ");
    }
    while (z != 2 * i - 1) {
      printf("* ");
      z++;
    }
    z = 0;
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D18(%rip),%rdi
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L40
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    $0x1,%r15d
  cmp    %ebx,%eax
  jle    L9
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    %ebx,%eax
  cmp    %r15d,%eax
  jge    L28
L9:
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jne    L51
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x2,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L32
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D40
type_infered: string

tool: D18: Kolko redove iskash : 

tool: D4: 


tool: D16: * 

tool: D20:   

tool: D40: %d

assistant: ```c
int main() {
  int i, q, n, z = 0;
  printf("Kolko redove iskash : ");
  scanf("%d", &n);
  for (i = 1; i <= n; ++i) {
    for (q = 1; q <= n - i; ++q) {
      printf("  ");
    }
    while (z != 2 * i - 1) {
      printf("* ");
      z++;
    }
    z = 0;
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x61,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L28
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime_number@plt>
  test   %rax,%rax
  je     L0
  lea    D2(%rip),%rax
  jmp    L6
L0:
  lea    D13(%rip),%rax
L6:
  mov    -0x4(%rbp),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string

tool: D2: prime number

tool: D13: non prime numebr

tool: D16: %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int num = 97;
  if (argc > 1) {
    num = atoi(argv[1]);
  }
  printf("%d is %s\n", num, is_prime_number(num) ? "prime number" : "non prime numebr");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  cmp    $0x1,%edi
  jg     L7
L16:
  mov    %ebx,%edi
  call   <is_prime_number@plt>
  test   %rax,%rax
  lea    D7(%rip),%rdx
  lea    D1(%rip),%rax
  cmove  %rax,%rdx
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L7:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  jmp    L16
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D16
datatype: string

tool: D7: prime number

tool: D1: non prime numebr

tool: D16: %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int num = 97;
  if (argc > 1) {
    num = atoi(argv[1]);
  }
  printf("%d is %s\n", num, is_prime_number(num) ? "prime number" : "non prime numebr");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x61,%ebp
  cmp    $0x1,%edi
  jle    L7
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L7:
  mov    %ebp,%edi
  call   <is_prime_number@plt>
  lea    D9(%rip),%rdx
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  test   %rax,%rax
  lea    D19(%rip),%rax
  cmove  %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D9: prime number

tool: D17: %d is %s


tool: D19: non prime numebr

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int num = 97;
  if (argc > 1) {
    num = atoi(argv[1]);
  }
  printf("%d is %s\n", num, is_prime_number(num) ? "prime number" : "non prime numebr");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x61,%ebp
  cmp    $0x1,%edi
  jle    L1
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L1:
  mov    %ebp,%edi
  call   <is_prime_number@plt>
  lea    D25(%rip),%rdx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  test   %rax,%rax
  lea    D8(%rip),%rax
  cmove  %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D25: prime number

tool: D9: %d is %s


tool: D8: non prime numebr

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int num = 97;
  if (argc > 1) {
    num = atoi(argv[1]);
  }
  printf("%d is %s\n", num, is_prime_number(num) ? "prime number" : "non prime numebr");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <BETestString@plt>
  mov    $0x0,%eax
  call   <BETestInteger@plt>
  mov    $0x0,%eax
  call   <BETestList@plt>
  mov    $0x0,%eax
  call   <BETestDictionary@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  BETestString();
  BETestInteger();
  BETestList();
  BETestDictionary();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <BETestString@plt>
  mov    $0x0,%eax
  call   <BETestInteger@plt>
  mov    $0x0,%eax
  call   <BETestList@plt>
  mov    $0x0,%eax
  call   <BETestDictionary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  BETestString();
  BETestInteger();
  BETestList();
  BETestDictionary();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <BETestString@plt>
  xor    %eax,%eax
  call   <BETestInteger@plt>
  xor    %eax,%eax
  call   <BETestList@plt>
  xor    %eax,%eax
  call   <BETestDictionary@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  BETestString();
  BETestInteger();
  BETestList();
  BETestDictionary();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <BETestString@plt>
  xor    %eax,%eax
  call   <BETestInteger@plt>
  xor    %eax,%eax
  call   <BETestList@plt>
  xor    %eax,%eax
  call   <BETestDictionary@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  BETestString();
  BETestInteger();
  BETestList();
  BETestDictionary();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WyswietlEkranPrzegranej>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <PiszW@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <NapiszTekst@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: Luuuzer

assistant: ```c
void WyswietlEkranPrzegranej() {
  PiszW(4, 4);
  NapiszTekst("Luuuzer");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WyswietlEkranPrzegranej>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <PiszW@plt>
  lea    D5(%rip),%rdi
  call   <NapiszTekst@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: Luuuzer

assistant: ```c
void WyswietlEkranPrzegranej() {
  PiszW(4, 4);
  NapiszTekst("Luuuzer");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<WyswietlEkranPrzegranej>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x4,%esi
  call   <PiszW@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <NapiszTekst@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: Luuuzer

assistant: ```c
void WyswietlEkranPrzegranej() {
  PiszW(4, 4);
  NapiszTekst("Luuuzer");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WyswietlEkranPrzegranej>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x4,%esi
  call   <PiszW@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <NapiszTekst@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: Luuuzer

assistant: ```c
void WyswietlEkranPrzegranej() {
  PiszW(4, 4);
  NapiszTekst("Luuuzer");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<word_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L4:
  addl   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  addl   $0x1,-0x4(%rbp)
  jmp    L17
L3:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L32
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
L32:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int word_count(char const *str) {
  int index;
  int count;
  index = 0;
  count = 0;
  while (str[index]) {
    while (is_sep(str[index]))
      index++;
    if (!is_sep(str[index]) && str[index] != '\0')
      count++;
    while (!is_sep(str[index]) && str[index] != '\0')
      index++;
  }
  return (count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<word_count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  cmpb   $0x0,(%rdi)
  jne    L63
  jmp    L22
L3:
  cmpb   $0x0,(%rbx)
  je     L22
L63:
  movslq %ebp,%rax
  add    %r13,%rax
  mov    %rax,%rbx
  sub    %eax,%ebp
L31:
  lea    0x0(%rbp,%rbx,1),%r12d
  mov    %rbx,%r15
  movsbl (%rbx),%edi
  call   <is_sep@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L31
  movsbl (%r15),%edi
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L68
  cmpb   $0x1,(%r15)
  sbb    $0xffffffff,%r14d
L68:
  movslq %r12d,%rax
  add    %r13,%rax
  mov    %rax,%rbx
  sub    %eax,%r12d
L51:
  lea    (%r12,%rbx,1),%ebp
  movsbl (%rbx),%edi
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L3
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  jne    L51
L22:
  mov    %r14d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int word_count(char const *str) {
  int index;
  int count;
  index = 0;
  count = 0;
  while (str[index]) {
    while (is_sep(str[index]))
      index++;
    if (!is_sep(str[index]) && str[index] != '\0')
      count++;
    while (!is_sep(str[index]) && str[index] != '\0')
      index++;
  }
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<word_count>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L26
  nopl   0x0(%rax)
L21:
  movslq %ebp,%rbp
  jmp    L52
  nopl   (%rax)
L37:
  movsbl (%r12,%rbp,1),%edi
L52:
  call   <is_sep@plt>
  mov    %ebp,%r14d
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L37
  movslq %r14d,%rbx
  add    %r12,%rbx
  movsbl (%rbx),%edi
  call   <is_sep@plt>
  movsbl (%rbx),%edi
  test   %rax,%rax
  jne    L60
  cmp    $0x1,%dil
  sbb    $0xffffffff,%r13d
L60:
  sub    %ebx,%r14d
  jmp    L67
  nopl   0x0(%rax)
L65:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L26
  movsbl (%rbx),%edi
L67:
  lea    (%r14,%rbx,1),%ebp
  call   <is_sep@plt>
  test   %rax,%rax
  je     L65
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L21
L26:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int word_count(char const *str) {
  int index;
  int count;
  index = 0;
  count = 0;
  while (str[index]) {
    while (is_sep(str[index]))
      index++;
    if (!is_sep(str[index]) && str[index] != '\0')
      count++;
    while (!is_sep(str[index]) && str[index] != '\0')
      index++;
  }
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<word_count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L31
L0:
  movslq %r13d,%rbx
  add    %rbp,%rbx
  sub    %ebx,%r13d
  nopl   0x0(%rax)
L45:
  movsbl (%rbx),%edi
  lea    0x0(%r13,%rbx,1),%r14d
  mov    %rbx,%r15
  add    $0x1,%rbx
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L45
  movsbl (%r15),%edi
  call   <is_sep@plt>
  test   %rax,%rax
  jne    L68
  cmpb   $0x1,(%r15)
  sbb    $0xffffffff,%r12d
L68:
  movslq %r14d,%rbx
  add    %rbp,%rbx
  sub    %ebx,%r14d
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L31
L9:
  movsbl (%rbx),%edi
  lea    (%r14,%rbx,1),%r13d
  call   <is_sep@plt>
  test   %rax,%rax
  je     L44
  cmpb   $0x0,(%rbx)
  jne    L0
L31:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int word_count(char const *str) {
  int index;
  int count;
  index = 0;
  count = 0;
  while (str[index]) {
    while (is_sep(str[index]))
      index++;
    if (!is_sep(str[index]) && str[index] != '\0')
      count++;
    while (!is_sep(str[index]) && str[index] != '\0')
      index++;
  }
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  float *pf;
  float f1();
  float *f2();
  float (*f3)();
  void (*fp)();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  float *pf;
  float f1();
  float *f2();
  float (*f3)();
  void (*fp)();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  float *pf;
  float f1();
  float *f2();
  float (*f3)();
  void (*fp)();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  float *pf;
  float f1();
  float *f2();
  float (*f3)();
  void (*fp)();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xc,-0x20(%rbp)
  movl   $0xd,-0x1c(%rbp)
  movl   $0xe,-0x18(%rbp)
  movl   $0xf,-0x14(%rbp)
  movl   $0x14,-0x40(%rbp)
  movl   $0x1e,-0x3c(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  subq   $0x4,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movl   $0x14,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D40
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D49
type_infered: string

tool: D40: x is %d, y is %d, z is %d


tool: D9: u is %d, v is %d


tool: D49: b[0] is %d, b[1] is %d, b[2] is %d, b[3] is %d


assistant: ```c
main() {
  int b[4] = {12, 13, 14, 15};
  int u = 20, v = 30, *x = &u, *y, *z;
  y = &u;
  z = &b[2];
  printf("x is %d, y is %d, z is %d\n", *x, *y, *z);
  printf("u is %d, v is %d\n", u, v);
  printf("b[0] is %d, b[1] is %d, b[2] is %d, b[3] is %d\n", b[0], b[1], b[2], b[3]);
  ++*x;
  y = &v;
  --z;
  z[1] = 20;
  printf("x is %d, y is %d, z is %d\n", *x, *y, *z);
  printf("u is %d, v is %d\n", u, v);
  printf("b[0] is %d, b[1] is %d, b[2] is %d, b[3] is %d\n", b[0], b[1], b[2], b[3]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xe,%ecx
  mov    $0x14,%edx
  mov    $0x14,%esi
  lea    D27(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1e,%edx
  mov    $0x14,%esi
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xf,%r8d
  mov    $0xe,%ecx
  mov    $0xd,%edx
  mov    $0xc,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xd,%ecx
  mov    $0x1e,%edx
  mov    $0x15,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1e,%edx
  mov    $0x15,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xf,%r8d
  mov    $0x14,%ecx
  mov    $0xd,%edx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D27
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D27: x is %d, y is %d, z is %d


tool: D17: u is %d, v is %d


tool: D4: b[0] is %d, b[1] is %d, b[2] is %d, b[3] is %d


assistant: ```c
main() {
  int b[4] = {12, 13, 14, 15};
  int u = 20, v = 30, *x = &u, *y, *z;
  y = &u;
  z = &b[2];
  printf("x is %d, y is %d, z is %d\n", *x, *y, *z);
  printf("u is %d, v is %d\n", u, v);
  printf("b[0] is %d, b[1] is %d, b[2] is %d, b[3] is %d\n", b[0], b[1], b[2], b[3]);
  ++*x;
  y = &v;
  --z;
  z[1] = 20;
  printf("x is %d, y is %d, z is %d\n", *x, *y, *z);
  printf("u is %d, v is %d\n", u, v);
  printf("b[0] is %d, b[1] is %d, b[2] is %d, b[3] is %d\n", b[0], b[1], b[2], b[3]);
}
```