ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    D75(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <litend@plt>
  test   %rax,%rax
  lea    D60(%rip),%rsi
  lea    D47(%rip),%rax
  cmove  %rax,%rsi
  lea    D70(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D22
type: string
name: parse_data
arguments: label: D45
type: string
name: parse_data
arguments: label: D75
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D60
type: string
name: parse_data
arguments: label: D47
type: string
name: parse_data
arguments: label: D70
type: string
name: parse_data
arguments: label: D57
type: string

tool: D22: #ifndef ENDIAN_H

tool: D45: #define ENDIAN_H

tool: D75: #define __LITTLE_ENDIAN 1234

tool: D1: #define __BIG_ENDIAN    4321

tool: D60: LITTLE

tool: D47: BIG

tool: D70: #define __BYTE_ORDER __%s_ENDIAN


tool: D57: #endif

assistant: ```c
int main(int argc, char **argv) {
  printf("#ifndef ENDIAN_H\n");
  printf("#define ENDIAN_H\n");
  printf("#define __LITTLE_ENDIAN 1234\n");
  printf("#define __BIG_ENDIAN    4321\n");
  printf("#define __BYTE_ORDER __%s_ENDIAN\n", litend() ? "LITTLE" : "BIG");
  printf("#endif\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <litend@plt>
  lea    D5(%rip),%rsi
  lea    D26(%rip),%rdi
  test   %rax,%rax
  lea    D8(%rip),%rax
  cmove  %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D45
data_type: string
name: unpack_data
arguments: label: D54
data_type: string
name: unpack_data
arguments: label: D47
data_type: string
name: unpack_data
arguments: label: D52
data_type: string
name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D8
data_type: string
name: unpack_data
arguments: label: D10
data_type: string

tool: D45: #ifndef ENDIAN_H

tool: D54: #define ENDIAN_H

tool: D47: #define __LITTLE_ENDIAN 1234

tool: D52: #define __BIG_ENDIAN    4321

tool: D5: LITTLE

tool: D26: #define __BYTE_ORDER __%s_ENDIAN


tool: D8: BIG

tool: D10: #endif

assistant: ```c
int main(int argc, char **argv) {
  printf("#ifndef ENDIAN_H\n");
  printf("#define ENDIAN_H\n");
  printf("#define __LITTLE_ENDIAN 1234\n");
  printf("#define __BIG_ENDIAN    4321\n");
  printf("#define __BYTE_ORDER __%s_ENDIAN\n", litend() ? "LITTLE" : "BIG");
  printf("#endif\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <litend@plt>
  lea    D40(%rip),%rsi
  lea    D13(%rip),%rdi
  test   %rax,%rax
  lea    D64(%rip),%rax
  cmove  %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D31
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D40
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D64
datatype: string
name: extract_symbolic_data
arguments: data_label: D33
datatype: string

tool: D31: #ifndef ENDIAN_H

tool: D16: #define ENDIAN_H

tool: D12: #define __LITTLE_ENDIAN 1234

tool: D23: #define __BIG_ENDIAN    4321

tool: D40: LITTLE

tool: D13: #define __BYTE_ORDER __%s_ENDIAN


tool: D64: BIG

tool: D33: #endif

assistant: ```c
int main(int argc, char **argv) {
  printf("#ifndef ENDIAN_H\n");
  printf("#define ENDIAN_H\n");
  printf("#define __LITTLE_ENDIAN 1234\n");
  printf("#define __BIG_ENDIAN    4321\n");
  printf("#define __BYTE_ORDER __%s_ENDIAN\n", litend() ? "LITTLE" : "BIG");
  printf("#endif\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fmt_2digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int fmt_2digits(char *dest, int i) {
  dest[0] = (i / 10) + '0';
  dest[1] = (i % 10) + '0';
  return 2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fmt_2digits>:
  endbr64
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x30(%rax),%edx
  mov    %dl,(%rdi)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  add    $0x30,%esi
  mov    %sil,0x1(%rdi)
  mov    $0x2,%eax
  ret
```

assistant: ```c
unsigned int fmt_2digits(char *dest, int i) {
  dest[0] = (i / 10) + '0';
  dest[1] = (i % 10) + '0';
  return 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fmt_2digits>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    0x30(%rax),%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %dl,(%rdi)
  sub    %eax,%esi
  mov    $0x2,%eax
  add    $0x30,%esi
  mov    %sil,0x1(%rdi)
  ret
```

assistant: ```c
unsigned int fmt_2digits(char *dest, int i) {
  dest[0] = (i / 10) + '0';
  dest[1] = (i % 10) + '0';
  return 2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fmt_2digits>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    0x30(%rax),%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %dl,(%rdi)
  sub    %eax,%esi
  mov    $0x2,%eax
  add    $0x30,%esi
  mov    %sil,0x1(%rdi)
  ret
```

assistant: ```c
unsigned int fmt_2digits(char *dest, int i) {
  dest[0] = (i / 10) + '0';
  dest[1] = (i % 10) + '0';
  return 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mygetchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L1:
  mov    $0x0,%eax
  call   <read_console@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mygetchar() {
  int ret;
  do
    ret = read_console();
  while (ret == 0);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mygetchar>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0x0,%eax
  call   <read_console@plt>
  test   %eax,%eax
  je     L9
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mygetchar() {
  int ret;
  do
    ret = read_console();
  while (ret == 0);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mygetchar>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <read_console@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mygetchar() {
  int ret;
  do
    ret = read_console();
  while (ret == 0);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mygetchar>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <read_console@plt>
  test   %eax,%eax
  je     L5
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mygetchar() {
  int ret;
  do
    ret = read_console();
  while (ret == 0);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D11: 123

tool: D5: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *s = "123";
  int n = atoi(s);
  printf("%d\n", n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string

tool: D0: 123

tool: D11: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *s = "123";
  int n = atoi(s);
  printf("%d\n", n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <atoi@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string

tool: D0: 123

tool: D10: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *s = "123";
  int n = atoi(s);
  printf("%d\n", n);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <atoi@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D17: 123

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *s = "123";
  int n = atoi(s);
  printf("%d\n", n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L4
  jmp    L24
L13:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L13
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L8
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L43
L8:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L43
L4:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L43:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string

tool: D16: 1

tool: D17: 0

tool: D15: -1

assistant: ```c
int is_prime(int num) {
  int sim = 2;
  if (num >= 2) {
    while (num % sim != 0) {
      sim++;
    }
    if (sim == num)
      printf("1");
    else
      printf("0");
  } else
    printf("-1");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L52
  test   $0x1,%dil
  je     L3
  mov    $0x2,%ecx
L37:
  add    $0x1,%ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L37
L46:
  cmp    %ecx,%edi
  je     L43
  lea    D3(%rip),%rdi
  call   <printf@plt>
L68:
  add    $0x8,%rsp
  ret
L3:
  mov    $0x2,%ecx
  jmp    L46
L43:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L68
L52:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L68
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D10
type: string

tool: D3: 0

tool: D11: 1

tool: D10: -1

assistant: ```c
int is_prime(int num) {
  int sim = 2;
  if (num >= 2) {
    while (num % sim != 0) {
      sim++;
    }
    if (sim == num)
      printf("1");
    else
      printf("0");
  } else
    printf("-1");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L28
  mov    $0x2,%ecx
  test   $0x1,%dil
  je     L7
  nopl   0x0(%rax)
L31:
  mov    %edi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L31
L7:
  cmp    %ecx,%edi
  je     L23
  lea    D22(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L23:
  lea    D14(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L28:
  lea    D10(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string

tool: D22: 0

tool: D14: 1

tool: D10: -1

assistant: ```c
int is_prime(int num) {
  int sim = 2;
  if (num >= 2) {
    while (num % sim != 0) {
      sim++;
    }
    if (sim == num)
      printf("1");
    else
      printf("0");
  } else
    printf("-1");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  mov    $0x2,%ecx
  test   $0x1,%dil
  je     L22
  nopl   0x0(%rax)
L16:
  mov    %edi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L16
L22:
  cmp    %ecx,%edi
  je     L34
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L34:
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L12:
  lea    D24(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D24
datatype: string

tool: D4: 0

tool: D13: 1

tool: D24: -1

assistant: ```c
int is_prime(int num) {
  int sim = 2;
  if (num >= 2) {
    while (num % sim != 0) {
      sim++;
    }
    if (sim == num)
      printf("1");
    else
      printf("0");
  } else
    printf("-1");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fgetl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L7
  mov    $0xffffffff,%eax
  jmp    L22
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L22
L33:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <super_chop@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
int fgetl(FILE *stream, size_t sz, char *buf) {
  if (feof(stream))
    return -1;
  char *s = fgets(buf, sz, stream);
  if (s == NULL)
    return -1;
  size_t len = strlen(s);
  len = super_chop(s, len);
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgetl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L34
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L21
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <super_chop@plt>
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L0
L21:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int fgetl(FILE *stream, size_t sz, char *buf) {
  if (feof(stream))
    return -1;
  char *s = fgets(buf, sz, stream);
  if (s == NULL)
    return -1;
  size_t len = strlen(s);
  len = super_chop(s, len);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgetl>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L21
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <super_chop@plt>
L19:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int fgetl(FILE *stream, size_t sz, char *buf) {
  if (feof(stream))
    return -1;
  char *s = fgets(buf, sz, stream);
  if (s == NULL)
    return -1;
  size_t len = strlen(s);
  len = super_chop(s, len);
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fgetl>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L16
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <super_chop@plt>
L6:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int fgetl(FILE *stream, size_t sz, char *buf) {
  if (feof(stream))
    return -1;
  char *s = fgets(buf, sz, stream);
  if (s == NULL)
    return -1;
  size_t len = strlen(s);
  len = super_chop(s, len);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wordlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L37:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L37
L25:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int wordlen(const char *str, int len) {
  int i = 0;
  while (i < len && str[i] != '\0' && str[i] != ' ' && str[i] != '\r' && str[i] != '\n')
    i++;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wordlen>:
  endbr64
  test   %esi,%esi
  jle    L76
  mov    $0x0,%edx
  movabs $0x100002400,%rcx
  jmp    L49
L60:
  add    $0x1,%edx
  add    $0x1,%rdi
  cmp    %edx,%esi
  je     L9
L49:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L44
  cmp    $0x20,%al
  ja     L60
  bt     %rax,%rcx
  jae    L60
L44:
  mov    %edx,%eax
  ret
L76:
  mov    $0x0,%edx
  jmp    L44
L9:
  mov    %esi,%edx
  jmp    L44
```

assistant: ```c
int wordlen(const char *str, int len) {
  int i = 0;
  while (i < len && str[i] != '\0' && str[i] != ' ' && str[i] != '\r' && str[i] != '\n')
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wordlen>:
  endbr64
  movabs $0x100002400,%rdx
  xor    %r8d,%r8d
  test   %esi,%esi
  jg     L53
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmp    %r8d,%esi
  je     L55
L53:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L55
  cmp    $0x20,%al
  ja     L5
  bt     %rax,%rdx
  jae    L5
L55:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int wordlen(const char *str, int len) {
  int i = 0;
  while (i < len && str[i] != '\0' && str[i] != ' ' && str[i] != '\r' && str[i] != '\n')
    i++;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wordlen>:
  endbr64
  movabs $0x100002400,%rdx
  xor    %r8d,%r8d
  test   %esi,%esi
  jg     L49
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmp    %r8d,%esi
  je     L47
L49:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L47
  cmp    $0x20,%al
  ja     L9
  bt     %rax,%rdx
  jae    L9
L47:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int wordlen(const char *str, int len) {
  int i = 0;
  while (i < len && str[i] != '\0' && str[i] != ' ' && str[i] != '\r' && str[i] != '\n')
    i++;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_folder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x218(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  test   %rax,%rax
  je     L26
  mov    $0xffffffff,%eax
  jmp    L5
L26:
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: rm -rf %s

assistant: ```c
int remove_folder(char *folder) {
  char cmd[512];
  sprintf(cmd, "rm -rf %s", folder);
  if (system(cmd))
    return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_folder>:
  endbr64
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  neg    %rax
  sbb    %eax,%eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x210,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: rm -rf %s

assistant: ```c
int remove_folder(char *folder) {
  char cmd[512];
  sprintf(cmd, "rm -rf %s", folder);
  if (system(cmd))
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_folder>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  lea    D7(%rip),%rsi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  neg    %rax
  sbb    %eax,%eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x210,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: rm -rf %s

assistant: ```c
int remove_folder(char *folder) {
  char cmd[512];
  sprintf(cmd, "rm -rf %s", folder);
  if (system(cmd))
    return -1;
  return 0;
}
```