ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<pgm_open_and_initialize>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %esi,%ecx
  lea    D6(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  lea    D49(%rip),%rsi
  call   <fopen@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D40(%rip),%rdi
  mov    %rax,%r12
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    $0x70,%ecx
  mov    $0x80,%edx
  mov    %r12,%rdi
  lea    D34(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D43(%rip),%rdi
  call   <fwrite@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D49
datatype: string
name: unpack_data
arguments: data_label: D40
datatype: string
name: unpack_data
arguments: data_label: D34
datatype: string
name: unpack_data
arguments: data_label: D43
datatype: string

tool: D6: %s-%d.pgm

tool: D49: w+

tool: D40: P5


tool: D34: %d %d


tool: D43: 255


assistant: ```c
FILE *pgm_open_and_initialize(char filename[], uint8_t postfix) {
  char full_name[262];
  sprintf(full_name, "%s-%d.pgm", filename, postfix);
  FILE *image = fopen(full_name, "w+");
  fputs("P5\n", image);
  fprintf(image, "%d %d\n", 16 * 8, 14 * 8);
  fputs("255\n", image);
  return image;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L22
  cmpq   $0x0,-0x20(%rbp)
  jne    L47
L22:
  mov    $0x0,%eax
  jmp    L21
L47:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cgc_strlen@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L14:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <cgc_strlen@plt>
  cmp    %rax,-0x8(%rbp)
  jb     L14
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L21:
  leave
  ret
```

assistant: ```c
char *strcat(char *restrict s1, const char *restrict s2) {
  uint32_t i, j;
  if (!s1 || !s2) {
    return (NULL);
  }
  for (i = cgc_strlen(s1), j = 0; j < cgc_strlen(s2); i++, j++) {
    s1[i] = s2[j];
  }
  s1[i] = '\0';
  return (s1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  call   <cgc_strlen@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  lea    (%r15,%rax,1),%r14
  jmp    L16
L3:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L16:
  lea    (%rbx,%r12,1),%r13
  mov    %rbp,%rdi
  call   <cgc_strlen@plt>
  cmp    %rbx,%rax
  ja     L3
  movb   $0x0,(%r15,%r13,1)
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *strcat(char *restrict s1, const char *restrict s2) {
  uint32_t i, j;
  if (!s1 || !s2) {
    return (NULL);
  }
  for (i = cgc_strlen(s1), j = 0; j < cgc_strlen(s2); i++, j++) {
    s1[i] = s2[j];
  }
  s1[i] = '\0';
  return (s1);
}
```
user: What is the c source code of the assembly code below:

```asm
<strcat>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <cgc_strlen@plt>
  lea    0x0(%r13,%rax,1),%rbp
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%r12,%rbx,1),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
L1:
  mov    %r12,%rdi
  call   <cgc_strlen@plt>
  cmp    %rbx,%rax
  ja     L19
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strcat(char *restrict s1, const char *restrict s2) {
  uint32_t i, j;
  if (!s1 || !s2) {
    return (NULL);
  }
  for (i = cgc_strlen(s1), j = 0; j < cgc_strlen(s2); i++, j++) {
    s1[i] = s2[j];
  }
  s1[i] = '\0';
  return (s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcat>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <cgc_strlen@plt>
  lea    0x0(%r13,%rax,1),%rbp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl (%r12,%rbx,1),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
L17:
  mov    %r12,%rdi
  call   <cgc_strlen@plt>
  cmp    %rbx,%rax
  ja     L8
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strcat(char *restrict s1, const char *restrict s2) {
  uint32_t i, j;
  if (!s1 || !s2) {
    return (NULL);
  }
  for (i = cgc_strlen(s1), j = 0; j < cgc_strlen(s2); i++, j++) {
    s1[i] = s2[j];
  }
  s1[i] = '\0';
  return (s1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_node_characters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    $0x0,%r12d
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L230
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L230
  mov    $0x0,%eax
  jmp    L245
L230:
  cmpq   $0x0,-0x28(%rbp)
  je     L78
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L78
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
  add    $0x1,%r12d
  jmp    L78
L39:
  cmpl   $0x0,-0x14(%rbp)
  je     L178
  cmp    $0x28,%ebx
  jne    L180
  addl   $0x1,-0x14(%rbp)
  jmp    L165
L180:
  cmp    $0x29,%ebx
  jne    L165
  subl   $0x1,-0x14(%rbp)
  jmp    L165
L178:
  cmp    $0x9,%ebx
  je     L30
  cmp    $0x2c,%ebx
  je     L30
  cmp    $0x7f,%ebx
  je     L30
  cmpl   $0x0,-0x2c(%rbp)
  jne    L9
  cmp    $0xa,%ebx
  je     L30
L9:
  cmpl   $0x0,-0x18(%rbp)
  je     L99
  movslq %r12d,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L99
  cmp    $0x20,%ebx
  je     L30
  cmp    $0x2e,%ebx
  je     L30
L99:
  cmp    $0x2e,%ebx
  jne    L128
  movslq %r12d,%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L30
  movslq %r12d,%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L30
  movslq %r12d,%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L30
  movslq %r12d,%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  je     L30
  jmp    L128
L165:
  nop
L128:
  add    $0x1,%r12d
L78:
  cmpq   $0x0,-0x28(%rbp)
  je     L30
  movslq %r12d,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ebx
  test   %ebx,%ebx
  jne    L39
L30:
  mov    %r12d,%eax
L245:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int skip_node_characters(char *string, int newlines_okay) {
  register int c, i = 0;
  int paren_seen = 0;
  int paren = 0;
  if (string && *string == '.')
    return 0;
  if (string && *string == '(') {
    paren++;
    paren_seen++;
    i++;
  }
  for (; string && (c = string[i]); i++) {
    if (paren) {
      if (c == '(')
        paren++;
      else if (c == ')')
        paren--;
      continue;
    }
    if (c == '\t' || c == ',' || c == '\177' || ((!newlines_okay) && (c == '\n')) || ((paren_seen && string[i - 1] == ')') && (c == ' ' || c == '.')) || (c == '.' && (((((string[i + 1] == ' ') || (string[i + 1] == '\t')) || (string[i + 1] == '\n'))) || (string[i + 1] == ')'))))
      break;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_node_characters>:
  endbr64
  mov    $0x0,%r10d
  test   %rdi,%rdi
  je     L161
  movzbl (%rdi),%r11d
  cmp    $0x2e,%r11b
  je     L161
  push   %rbx
  cmp    $0x28,%r11b
  sete   %r8b
  movzbl %r8b,%r8d
  sete   %dl
  movzbl %dl,%edx
  movabs $0x20100000600,%rbx
  jmp    L25
L97:
  cmp    $0x28,%eax
  je     L187
  cmp    $0x29,%eax
  sete   %al
  movzbl %al,%eax
  sub    %eax,%r8d
  jmp    L194
L187:
  add    $0x1,%r8d
  jmp    L194
L188:
  cmp    $0x2e,%eax
  je     L37
L194:
  add    $0x1,%rdx
L25:
  mov    %edx,%r10d
  movsbl (%rdi,%rdx,1),%eax
  test   %eax,%eax
  je     L123
  test   %r8d,%r8d
  jne    L97
  cmp    $0x9,%eax
  sete   %cl
  cmp    $0x2c,%eax
  sete   %r9b
  or     %r9b,%cl
  jne    L123
  cmp    $0x7f,%eax
  je     L123
  test   %esi,%esi
  jne    L111
  cmp    $0xa,%eax
  je     L123
L111:
  cmp    $0x28,%r11b
  jne    L188
  cmpb   $0x29,-0x1(%rdi,%rdx,1)
  jne    L188
  cmp    $0x20,%eax
  je     L123
  cmp    $0x2e,%eax
  jne    L194
  jmp    L123
L37:
  movzbl 0x1(%rdi,%rdx,1),%eax
  cmp    $0x29,%al
  ja     L194
  bt     %rax,%rbx
  jae    L194
L123:
  mov    %r10d,%eax
  pop    %rbx
  ret
L161:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int skip_node_characters(char *string, int newlines_okay) {
  register int c, i = 0;
  int paren_seen = 0;
  int paren = 0;
  if (string && *string == '.')
    return 0;
  if (string && *string == '(') {
    paren++;
    paren_seen++;
    i++;
  }
  for (; string && (c = string[i]); i++) {
    if (paren) {
      if (c == '(')
        paren++;
      else if (c == ')')
        paren--;
      continue;
    }
    if (c == '\t' || c == ',' || c == '\177' || ((!newlines_okay) && (c == '\n')) || ((paren_seen && string[i - 1] == ')') && (c == ' ' || c == '.')) || (c == '.' && (((((string[i + 1] == ' ') || (string[i + 1] == '\t')) || (string[i + 1] == '\n'))) || (string[i + 1] == ')'))))
      break;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_node_characters>:
  endbr64
  xor    %r9d,%r9d
  test   %rdi,%rdi
  je     L34
  movzbl (%rdi),%r10d
  cmp    $0x2e,%r10b
  je     L34
  xor    %ecx,%ecx
  cmp    $0x28,%r10b
  sete   %dl
  sete   %cl
  movzbl %dl,%edx
  jmp    L72
  nop
L111:
  cmp    $0x29,%eax
  sete   %al
  movzbl %al,%eax
  sub    %eax,%ecx
L143:
  add    $0x1,%rdx
L72:
  movsbl (%rdi,%rdx,1),%eax
  mov    %edx,%r9d
  test   %eax,%eax
  je     L34
  test   %ecx,%ecx
  je     L54
  cmp    $0x28,%eax
  jne    L111
  add    $0x1,%ecx
  jmp    L143
  nopl   0x0(%rax,%rax,1)
L54:
  movabs $0xfffffdfefffff9ff,%r11
  jmp    L139
  nopl   0x0(%rax)
L118:
  add    $0x1,%rdx
  movsbl (%rdi,%rdx,1),%eax
  mov    %edx,%r9d
  test   %eax,%eax
  je     L34
L139:
  cmp    $0x9,%eax
  sete   %cl
  cmp    $0x2c,%eax
  sete   %r8b
  or     %r8b,%cl
  jne    L34
  cmp    $0x7f,%eax
  je     L34
  test   %esi,%esi
  jne    L195
  cmp    $0xa,%eax
  je     L34
L195:
  cmp    $0x28,%r10b
  jne    L115
  cmpb   $0x29,-0x1(%rdi,%rdx,1)
  je     L148
L115:
  cmp    $0x2e,%eax
  jne    L118
  movzbl 0x1(%rdi,%rdx,1),%eax
  cmp    $0x29,%al
  ja     L118
  bt     %rax,%r11
  jb     L118
L34:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L148:
  cmp    $0x20,%eax
  je     L34
  cmp    $0x2e,%eax
  jne    L118
  jmp    L34
```

assistant: ```c
int skip_node_characters(char *string, int newlines_okay) {
  register int c, i = 0;
  int paren_seen = 0;
  int paren = 0;
  if (string && *string == '.')
    return 0;
  if (string && *string == '(') {
    paren++;
    paren_seen++;
    i++;
  }
  for (; string && (c = string[i]); i++) {
    if (paren) {
      if (c == '(')
        paren++;
      else if (c == ')')
        paren--;
      continue;
    }
    if (c == '\t' || c == ',' || c == '\177' || ((!newlines_okay) && (c == '\n')) || ((paren_seen && string[i - 1] == ')') && (c == ' ' || c == '.')) || (c == '.' && (((((string[i + 1] == ' ') || (string[i + 1] == '\t')) || (string[i + 1] == '\n'))) || (string[i + 1] == ')'))))
      break;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skip_node_characters>:
  endbr64
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  mov    %esi,%edi
  test   %rcx,%rcx
  je     L39
  movsbl (%rcx),%eax
  cmp    $0x2e,%al
  je     L39
  cmp    $0x28,%al
  je     L263
  test   %eax,%eax
  je     L39
  movabs $0xfffffdfefffff9ff,%r10
  xor    %edx,%edx
L14:
  cmp    $0x2c,%eax
  sete   %sil
  cmp    $0x9,%eax
  sete   %r9b
  or     %r9b,%sil
  jne    L39
  cmp    $0x7f,%eax
  je     L39
  cmp    $0xa,%eax
  jne    L139
  test   %edi,%edi
  je     L39
L139:
  cmp    $0x2e,%eax
  je     L18
L138:
  add    $0x1,%rdx
  movsbl (%rcx,%rdx,1),%eax
  mov    %edx,%r8d
  test   %eax,%eax
  jne    L14
L39:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L18:
  movzbl 0x1(%rcx,%rdx,1),%eax
  cmp    $0x29,%al
  ja     L138
  bt     %rax,%r10
  jb     L138
  jmp    L39
  nopl   0x0(%rax)
L263:
  mov    $0x1,%edx
  mov    $0x1,%esi
  jmp    L128
  nopl   0x0(%rax)
L85:
  cmp    $0x29,%eax
  sete   %al
  movzbl %al,%eax
  sub    %eax,%esi
L315:
  add    $0x1,%rdx
L128:
  movsbl (%rcx,%rdx,1),%eax
  mov    %edx,%r8d
  test   %eax,%eax
  je     L39
  test   %esi,%esi
  je     L105
  cmp    $0x28,%eax
  jne    L85
  add    $0x1,%esi
  jmp    L315
L105:
  movabs $0xfffffdfefffff9ff,%r10
  jmp    L148
  nopl   0x0(%rax)
L134:
  add    $0x1,%rdx
  movsbl (%rcx,%rdx,1),%eax
  mov    %edx,%r8d
  test   %eax,%eax
  je     L39
L148:
  cmp    $0x9,%eax
  sete   %sil
  cmp    $0x2c,%eax
  sete   %r9b
  or     %r9b,%sil
  jne    L39
  cmp    $0x7f,%eax
  je     L39
  test   %edi,%edi
  jne    L10
  cmp    $0xa,%eax
  je     L39
L10:
  cmpb   $0x29,-0x1(%rcx,%rdx,1)
  je     L86
  cmp    $0x2e,%eax
  jne    L134
  movzbl 0x1(%rcx,%rdx,1),%eax
  cmp    $0x29,%al
  ja     L134
  bt     %rax,%r10
  jb     L134
  jmp    L39
  nopl   0x0(%rax)
L86:
  cmp    $0x20,%eax
  je     L39
  cmp    $0x2e,%eax
  jne    L134
  jmp    L39
```

assistant: ```c
int skip_node_characters(char *string, int newlines_okay) {
  register int c, i = 0;
  int paren_seen = 0;
  int paren = 0;
  if (string && *string == '.')
    return 0;
  if (string && *string == '(') {
    paren++;
    paren_seen++;
    i++;
  }
  for (; string && (c = string[i]); i++) {
    if (paren) {
      if (c == '(')
        paren++;
      else if (c == ')')
        paren--;
      continue;
    }
    if (c == '\t' || c == ',' || c == '\177' || ((!newlines_okay) && (c == '\n')) || ((paren_seen && string[i - 1] == ')') && (c == ' ' || c == '.')) || (c == '.' && (((((string[i + 1] == ' ') || (string[i + 1] == '\t')) || (string[i + 1] == '\n'))) || (string[i + 1] == ')'))))
      break;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<null_distort_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  movsd  D0(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L1
  mov    $0xffffffff,%eax
  jmp    L14
L1:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: byte[8]

tool: {"D0": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int null_distort_func(const void *data, const double ray[3], double *x, double *y) {
  if (ray[2] < 1e-10)
    return -1;
  *x = ray[0] / ray[2];
  *y = ray[1] / ray[2];
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<null_distort_func>:
  endbr64
  movsd  0x10(%rsi),%xmm1
  movsd  D0(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L7
  movsd  (%rsi),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rsi),%xmm0
  divsd  0x10(%rsi),%xmm0
  movsd  %xmm0,(%rcx)
  mov    $0x0,%eax
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: byte[8]

tool: {"D0": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int null_distort_func(const void *data, const double ray[3], double *x, double *y) {
  if (ray[2] < 1e-10)
    return -1;
  *x = ray[0] / ray[2];
  *y = ray[1] / ray[2];
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<null_distort_func>:
  endbr64
  movsd  0x10(%rsi),%xmm1
  movsd  D7(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L4
  movsd  (%rsi),%xmm0
  xor    %eax,%eax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rsi),%xmm0
  divsd  0x10(%rsi),%xmm0
  movsd  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: byte[8]

tool: {"D7": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int null_distort_func(const void *data, const double ray[3], double *x, double *y) {
  if (ray[2] < 1e-10)
    return -1;
  *x = ray[0] / ray[2];
  *y = ray[1] / ray[2];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<null_distort_func>:
  endbr64
  movsd  0x10(%rsi),%xmm1
  movsd  D6(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L8
  movsd  (%rsi),%xmm0
  xor    %eax,%eax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rsi),%xmm0
  divsd  0x10(%rsi),%xmm0
  movsd  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax)
L8:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: byte[8]

tool: {"D6": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int null_distort_func(const void *data, const double ray[3], double *x, double *y) {
  if (ray[2] < 1e-10)
    return -1;
  *x = ray[0] / ray[2];
  *y = ray[1] / ray[2];
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <mstring_get_length@plt>
  add    $0xf,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L39:
  cmp    %rdx,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L39
L32:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L20
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L20:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <mstring_get_length@plt>
  lea    0xf(%rax),%esi
  mov    -0x58(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rcx
  lea    D11(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <read_file@plt>
  mov    %rax,-0x40(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    -0x40(%rbp),%rax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D20
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string

tool: D11: %s > cmd.temp

tool: D20: cmd.temp

tool: D14: rm -rf cmd.temp

assistant: ```c
char *get_output(char *cmd_in) {
  char cmd[mstring_get_length(cmd_in) + 15];
  snprintf(cmd, mstring_get_length(cmd_in) + 15, "%s > cmd.temp", cmd_in);
  system(cmd);
  char *buff = read_file("cmd.temp");
  system("rm -rf cmd.temp");
  return buff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <mstring_get_length@plt>
  add    $0xf,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L38:
  cmp    %rdx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L38
L9:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L28
  orq    $0x0,-0x8(%rsp,%rax,1)
L28:
  mov    %rbx,%rdi
  call   <mstring_get_length@plt>
  lea    0xf(%rax),%esi
  mov    %rbx,%rcx
  lea    D15(%rip),%rdx
  mov    %rsp,%rdi
  call   <snprintf@plt>
  mov    %rsp,%rdi
  call   <system@plt>
  lea    D4(%rip),%rdi
  call   <read_file@plt>
  mov    %rax,%rbx
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D3
type: string

tool: D15: %s > cmd.temp

tool: D4: cmd.temp

tool: D3: rm -rf cmd.temp

assistant: ```c
char *get_output(char *cmd_in) {
  char cmd[mstring_get_length(cmd_in) + 15];
  snprintf(cmd, mstring_get_length(cmd_in) + 15, "%s > cmd.temp", cmd_in);
  system(cmd);
  char *buff = read_file("cmd.temp");
  system("rm -rf cmd.temp");
  return buff;
}
```