ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L24
  test   %eax,%eax
  je     L1
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L13:
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  lea    D27(%rip),%rdi
  call   <getenv@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  mov    %rax,0x8(%rbp)
  call   <execvp@plt>
  test   %rax,%rax
  jns    L13
  lea    D14(%rip),%rdi
  call   <puts@plt>
L24:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D35
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D3: child pid = %d


tool: D27: USER

tool: D35: ./hello02

tool: D14: fail :(

assistant: ```c
int main(int argc, char *argv[]) {
  pid_t pid;
  pid = fork();
  if (pid == -1) {
    exit(-1);
  } else if (pid == 0) {
    argv[1] = getenv("USER");
    if (execvp("./hello02", argv) < 0) {
      printf("fail :(\n");
      exit(-1);
    }
  } else {
    printf("child pid = %d\n", pid);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L7
  test   %eax,%eax
  je     L34
  mov    %eax,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L20:
  xor    %eax,%eax
  pop    %rbp
  ret
L34:
  lea    D16(%rip),%rdi
  call   <getenv@plt>
  mov    %rbp,%rsi
  lea    D22(%rip),%rdi
  mov    %rax,0x8(%rbp)
  call   <execvp@plt>
  test   %rax,%rax
  jns    L20
  lea    D17(%rip),%rdi
  call   <puts@plt>
L7:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: D20: child pid = %d


tool: D16: USER

tool: D22: ./hello02

tool: D17: fail :(

assistant: ```c
int main(int argc, char *argv[]) {
  pid_t pid;
  pid = fork();
  if (pid == -1) {
    exit(-1);
  } else if (pid == 0) {
    argv[1] = getenv("USER");
    if (execvp("./hello02", argv) < 0) {
      printf("fail :(\n");
      exit(-1);
    }
  } else {
    printf("child pid = %d\n", pid);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L85
L48:
  movl   $0x2,-0x8(%rbp)
  jmp    L15
L73:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L54
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L73
L54:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L50
  movl   $0x2,-0x8(%rbp)
  jmp    L13
L89:
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L83
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L89
L83:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L50
  mov    -0xc(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  addl   $0x1,-0xc(%rbp)
L85:
  cmpl   $0x6b,-0xc(%rbp)
  jle    L48
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: %d,%d


assistant: ```c
int main() {
  int i, a, b, z = 0;
  for (i = 1; i <= 107; i++) {
    a = 2;
    while (a < i && i % a != 0) {
      a++;
    }
    if (a == i) {
      a = 2;
      while (a < i + 2 && (i + 2) % a != 0) {
        a++;
      }
      if (a == i + 2) {
        printf("%d,%d\n", i, i + 2);
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x3,%ebp
  mov    $0x1,%ebx
  lea    D4(%rip),%r12
  jmp    L89
L30:
  je     L12
  add    $0x1,%ebx
  add    $0x1,%ebp
  jmp    L89
L12:
  mov    $0x3,%edi
  jmp    L138
L1:
  mov    $0x2,%ecx
  jmp    L85
L130:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L68
L51:
  add    $0x1,%edi
L138:
  mov    %ebp,%esi
  test   $0x1,%bpl
  je     L1
  mov    $0x2,%ecx
L19:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L85
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L19
L85:
  cmp    %ecx,%ebp
  je     L130
L68:
  add    $0x1,%ebx
  add    $0x1,%ebp
  cmp    $0x6c,%ebx
  je     L125
L89:
  cmp    $0x2,%ebx
  jle    L30
  mov    %ebx,%edi
  mov    $0x2,%ecx
  test   $0x1,%bl
  je     L68
L101:
  add    $0x1,%ecx
  cmp    %ebx,%ecx
  je     L51
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L101
  jmp    L68
L125:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string

tool: D4: %d,%d


assistant: ```c
int main() {
  int i, a, b, z = 0;
  for (i = 1; i <= 107; i++) {
    a = 2;
    while (a < i && i % a != 0) {
      a++;
    }
    if (a == i) {
      a = 2;
      while (a < i + 2 && (i + 2) % a != 0) {
        a++;
      }
      if (a == i + 2) {
        printf("%d,%d\n", i, i + 2);
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbx
  lea    D6(%rip),%rbx
  nopl   0x0(%rax)
L106:
  cmp    $0x2,%r12d
  jbe    L100
  mov    $0x2,%ecx
  test   $0x1,%r12b
  jne    L143
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L45
L143:
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L13
L38:
  mov    $0x3,%ecx
  test   $0x1,%r13b
  jne    L101
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %eax,%ecx
L101:
  mov    %r13d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L26
  lea    0x1(%rcx),%eax
  cmp    %r12d,%ecx
  jle    L10
  cmp    %eax,%r13d
  je     L110
  nopl   0x0(%rax)
L45:
  add    $0x1,%r12d
  add    $0x1,%r13d
  cmp    $0x6c,%r12d
  jne    L106
  pop    %rbx
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
L100:
  jne    L45
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %ecx,%eax
  cmp    %eax,%r13d
  jne    L45
L110:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L45
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: %d,%d


assistant: ```c
int main() {
  int i, a, b, z = 0;
  for (i = 1; i <= 107; i++) {
    a = 2;
    while (a < i && i % a != 0) {
      a++;
    }
    if (a == i) {
      a = 2;
      while (a < i + 2 && (i + 2) % a != 0) {
        a++;
      }
      if (a == i + 2) {
        printf("%d,%d\n", i, i + 2);
      }
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbx
  lea    D3(%rip),%rbx
  nopl   0x0(%rax)
L43:
  cmp    $0x2,%r12d
  jbe    L70
  mov    $0x2,%ecx
  test   $0x1,%r12b
  jne    L126
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L133:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L50
L126:
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L133
L140:
  mov    $0x3,%ecx
  test   $0x1,%r13b
  jne    L117
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L108:
  mov    %eax,%ecx
L117:
  mov    %r13d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
  lea    0x1(%rcx),%eax
  cmp    %r12d,%ecx
  jle    L108
  cmp    %eax,%r13d
  je     L67
  nopl   0x0(%rax)
L50:
  add    $0x1,%r12d
  add    $0x1,%r13d
  cmp    $0x6c,%r12d
  jne    L43
  pop    %rbx
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
L70:
  jne    L50
  jmp    L140
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %ecx,%eax
  cmp    %eax,%r13d
  jne    L50
L67:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L50
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: %d,%d


assistant: ```c
int main() {
  int i, a, b, z = 0;
  for (i = 1; i <= 107; i++) {
    a = 2;
    while (a < i && i % a != 0) {
      a++;
    }
    if (a == i) {
      a = 2;
      while (a < i + 2 && (i + 2) % a != 0) {
        a++;
      }
      if (a == i + 2) {
        printf("%d,%d\n", i, i + 2);
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gettok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L76
  mov    -0x18(%rbp),%rax
  mov    %rax,D84(%rip)
  mov    D84(%rip),%rax
  mov    %rax,D78(%rip)
  mov    -0x28(%rbp),%rax
  movb   $0x20,(%rax)
  jmp    L38
L76:
  mov    D84(%rip),%rax
  mov    -0x28(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    D84(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D135(%rip)
L38:
  mov    D84(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    D135(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
L18:
  mov    $0x0,%eax
  jmp    L59
L47:
  mov    D135(%rip),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  mov    D135(%rip),%rdx
  cltq
  add    %rdx,%rax
  mov    %rax,D135(%rip)
  mov    D135(%rip),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L21
  mov    D135(%rip),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L63
L21:
  mov    D135(%rip),%rax
  mov    %rax,%rdi
  call   <quotespan@plt>
  mov    %rax,D135(%rip)
  jmp    L58
L63:
  mov    D135(%rip),%rbx
  mov    D135(%rip),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  mov    %rax,D135(%rip)
L58:
  mov    D135(%rip),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    D135(%rip),%rax
  movb   $0x0,(%rax)
  mov    D135(%rip),%rax
L59:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *gettok(char *string, const char *skip, char *nextc) {
  static char *p, *q;
  if (string != NULL) {
    p = q = string;
    *nextc = ' ';
  } else {
    *q = *nextc;
    p = q + 1;
  }
  if (*q == '\0' || *p == '\0') {
    return NULL;
  }
  p += strspn(p, skip);
  if (*p == '"' || *p == '\'') {
    q = quotespan(p);
  } else {
    q = p + strcspn(p, skip);
  }
  *nextc = *q;
  *q = '\0';
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gettok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L69
  mov    %rdi,D94(%rip)
  mov    %rdi,D55(%rip)
  movb   $0x20,(%rdx)
L54:
  mov    D94(%rip),%rax
  cmpb   $0x0,(%rax)
  je     L38
  mov    D55(%rip),%rdi
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L49
  mov    %r12,%rsi
  call   <strspn@plt>
  movslq %eax,%rbx
  add    D55(%rip),%rbx
  mov    %rbx,D87(%rip)
  movzbl (%rbx),%eax
  cmp    $0x22,%al
  je     L44
  cmp    $0x27,%al
  je     L44
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  jmp    L43
L69:
  mov    D94(%rip),%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  mov    %rax,D87(%rip)
  jmp    L54
L44:
  mov    %rbx,%rdi
  call   <quotespan@plt>
L43:
  mov    %rax,D87(%rip)
  movzbl (%rax),%edx
  mov    %dl,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    D87(%rip),%rax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  mov    $0x0,%eax
  jmp    L49
```

assistant: ```c
char *gettok(char *string, const char *skip, char *nextc) {
  static char *p, *q;
  if (string != NULL) {
    p = q = string;
    *nextc = ' ';
  } else {
    *q = *nextc;
    p = q + 1;
  }
  if (*q == '\0' || *p == '\0') {
    return NULL;
  }
  p += strspn(p, skip);
  if (*p == '"' || *p == '\'') {
    q = quotespan(p);
  } else {
    q = p + strcspn(p, skip);
  }
  *nextc = *q;
  *q = '\0';
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gettok>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L32
  movb   $0x20,(%rdx)
  movzbl (%rdi),%eax
  mov    %rdi,D69(%rip)
  mov    %rdi,D22(%rip)
  test   %al,%al
  je     L51
L22:
  mov    D22(%rip),%rdi
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L60
  mov    %r12,%rsi
  call   <strspn@plt>
  movslq %eax,%rbp
  add    D22(%rip),%rbp
  movzbl 0x0(%rbp),%eax
  mov    %rbp,D78(%rip)
  cmp    $0x22,%al
  je     L21
  cmp    $0x27,%al
  je     L21
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcspn@plt>
  cltq
  add    %rbp,%rax
L43:
  movzbl (%rax),%edx
  mov    %rax,D78(%rip)
  mov    %dl,(%rbx)
  movb   $0x0,(%rax)
  mov    D78(%rip),%rax
L60:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  mov    %rbp,%rdi
  call   <quotespan@plt>
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L32:
  mov    D78(%rip),%rdx
  movzbl (%rbx),%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  mov    %rdx,D78(%rip)
  test   %al,%al
  jne    L22
L51:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *gettok(char *string, const char *skip, char *nextc) {
  static char *p, *q;
  if (string != NULL) {
    p = q = string;
    *nextc = ' ';
  } else {
    *q = *nextc;
    p = q + 1;
  }
  if (*q == '\0' || *p == '\0') {
    return NULL;
  }
  p += strspn(p, skip);
  if (*p == '"' || *p == '\'') {
    q = quotespan(p);
  } else {
    q = p + strcspn(p, skip);
  }
  *nextc = *q;
  *q = '\0';
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gettok>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L31
  mov    %rdi,D41(%rip)
  movb   $0x20,(%rdx)
  movzbl (%rdi),%eax
L3:
  test   %al,%al
  mov    %rdi,D63(%rip)
  mov    $0x0,%eax
  je     L55
  cmpb   $0x0,(%rdi)
  je     L55
  mov    %r12,%rsi
  call   <strspn@plt>
  movslq %eax,%rbp
  add    D63(%rip),%rbp
  movzbl 0x0(%rbp),%eax
  mov    %rbp,D24(%rip)
  cmp    $0x22,%al
  je     L5
  cmp    $0x27,%al
  je     L5
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcspn@plt>
  cltq
  add    %rbp,%rax
L11:
  movzbl (%rax),%edx
  mov    %rax,D24(%rip)
  mov    %dl,(%rbx)
  movb   $0x0,(%rax)
  mov    D24(%rip),%rax
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  call   <quotespan@plt>
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L31:
  mov    D24(%rip),%rdi
  movzbl (%rdx),%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  jmp    L3
```

assistant: ```c
char *gettok(char *string, const char *skip, char *nextc) {
  static char *p, *q;
  if (string != NULL) {
    p = q = string;
    *nextc = ' ';
  } else {
    *q = *nextc;
    p = q + 1;
  }
  if (*q == '\0' || *p == '\0') {
    return NULL;
  }
  p += strspn(p, skip);
  if (*p == '"' || *p == '\'') {
    q = quotespan(p);
  } else {
    q = p + strcspn(p, skip);
  }
  *nextc = *q;
  *q = '\0';
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QRinput_estimateBitsModeNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  je     L17
  cmp    $0x2,%eax
  je     L39
  jmp    L36
L17:
  addl   $0x4,-0x8(%rbp)
  jmp    L36
L39:
  addl   $0x7,-0x8(%rbp)
  nop
L36:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int QRinput_estimateBitsModeNum(int size) {
  int w;
  int bits;
  w = size / 3;
  bits = w * 10;
  switch (size - w * 3) {
  case 1:
    bits += 4;
    break;
  case 2:
    bits += 7;
    break;
  default:
    break;
  }
  return bits;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<QRinput_estimateBitsModeNum>:
  endbr64
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,4),%esi
  lea    (%rsi,%rax,1),%edx
  add    %edx,%edx
  mov    %edx,%ecx
  sub    %esi,%eax
  add    %edi,%eax
  cmp    $0x1,%eax
  je     L16
  add    $0x7,%edx
  cmp    $0x2,%eax
  cmove  %edx,%ecx
L18:
  mov    %ecx,%eax
  ret
L16:
  lea    0x4(%rdx),%ecx
  jmp    L18
```

assistant: ```c
int QRinput_estimateBitsModeNum(int size) {
  int w;
  int bits;
  w = size / 3;
  bits = w * 10;
  switch (size - w * 3) {
  case 1:
    bits += 4;
    break;
  case 2:
    bits += 7;
    break;
  default:
    break;
  }
  return bits;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<QRinput_estimateBitsModeNum>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    0x0(,%rax,4),%ecx
  lea    (%rcx,%rax,1),%edx
  sub    %ecx,%eax
  add    %edx,%edx
  add    %edi,%eax
  lea    0x4(%rdx),%r8d
  cmp    $0x1,%eax
  je     L0
  lea    0x7(%rdx),%r8d
  cmp    $0x2,%eax
  cmovne %edx,%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int QRinput_estimateBitsModeNum(int size) {
  int w;
  int bits;
  w = size / 3;
  bits = w * 10;
  switch (size - w * 3) {
  case 1:
    bits += 4;
    break;
  case 2:
    bits += 7;
    break;
  default:
    break;
  }
  return bits;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<QRinput_estimateBitsModeNum>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    0x0(,%rax,4),%ecx
  lea    (%rcx,%rax,1),%edx
  sub    %ecx,%eax
  add    %edx,%edx
  add    %edi,%eax
  lea    0x4(%rdx),%r8d
  cmp    $0x1,%eax
  je     L6
  lea    0x7(%rdx),%r8d
  cmp    $0x2,%eax
  cmovne %edx,%r8d
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int QRinput_estimateBitsModeNum(int size) {
  int w;
  int bits;
  w = size / 3;
  bits = w * 10;
  switch (size - w * 3) {
  case 1:
    bits += 4;
    break;
  case 2:
    bits += 7;
    break;
  default:
    break;
  }
  return bits;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <add_test@plt>
  mov    $0x0,%eax
  call   <and_test@plt>
  mov    $0x0,%eax
  call   <branch_test@plt>
  mov    $0x0,%eax
  call   <load_store_test@plt>
  mov    $0x0,%eax
  call   <or_test@plt>
  mov    $0x0,%eax
  call   <sll_test@plt>
  mov    $0x0,%eax
  call   <srl_sra_test@plt>
  mov    $0x0,%eax
  call   <xor_test@plt>
  mov    $0x0,%eax
  call   <sub_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  add_test();
  and_test();
  branch_test();
  load_store_test();
  or_test();
  sll_test();
  srl_sra_test();
  xor_test();
  sub_test();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <add_test@plt>
  mov    $0x0,%eax
  call   <and_test@plt>
  mov    $0x0,%eax
  call   <branch_test@plt>
  mov    $0x0,%eax
  call   <load_store_test@plt>
  mov    $0x0,%eax
  call   <or_test@plt>
  mov    $0x0,%eax
  call   <sll_test@plt>
  mov    $0x0,%eax
  call   <srl_sra_test@plt>
  mov    $0x0,%eax
  call   <xor_test@plt>
  mov    $0x0,%eax
  call   <sub_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  add_test();
  and_test();
  branch_test();
  load_store_test();
  or_test();
  sll_test();
  srl_sra_test();
  xor_test();
  sub_test();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <add_test@plt>
  xor    %eax,%eax
  call   <and_test@plt>
  xor    %eax,%eax
  call   <branch_test@plt>
  xor    %eax,%eax
  call   <load_store_test@plt>
  xor    %eax,%eax
  call   <or_test@plt>
  xor    %eax,%eax
  call   <sll_test@plt>
  xor    %eax,%eax
  call   <srl_sra_test@plt>
  xor    %eax,%eax
  call   <xor_test@plt>
  xor    %eax,%eax
  call   <sub_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  add_test();
  and_test();
  branch_test();
  load_store_test();
  or_test();
  sll_test();
  srl_sra_test();
  xor_test();
  sub_test();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <add_test@plt>
  xor    %eax,%eax
  call   <and_test@plt>
  xor    %eax,%eax
  call   <branch_test@plt>
  xor    %eax,%eax
  call   <load_store_test@plt>
  xor    %eax,%eax
  call   <or_test@plt>
  xor    %eax,%eax
  call   <sll_test@plt>
  xor    %eax,%eax
  call   <srl_sra_test@plt>
  xor    %eax,%eax
  call   <xor_test@plt>
  xor    %eax,%eax
  call   <sub_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  add_test();
  and_test();
  branch_test();
  load_store_test();
  or_test();
  sll_test();
  srl_sra_test();
  xor_test();
  sub_test();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<exponential>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L15:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L15
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  neg    %eax
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  lea    (%rax,%rax,1),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  call   <exp@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double exponential(double *x, double *y, int n, double sigma) {
  int i;
  double d = 0.0;
  for (i = 0; i < n; i++)
    d += pow(x[i] - y[i], 2);
  return exp(-sqrt(d) / (2 * pow(sigma, 2)));
}
```