ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<tokenize_host_port>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L34
L5:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <isnumeric@plt>
  test   %eax,%eax
  jne    L26
  mov    $0xffffffff,%eax
  jmp    L34
L26:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int tokenize_host_port(char *token, char *host, uint16_t *port) {
  char *p = strstr(token, ":");
  int len;
  if (p == NULL)
    return -1;
  if (!isnumeric(p + 1))
    return -1;
  len = p - token;
  strncpy(host, token, len);
  host[len] = 0;
  *port = (uint16_t)strtol(p + 1, NULL, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tokenize_host_port>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    $0x3a,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbx
  lea    0x1(%rax),%r14
  mov    %r14,%rdi
  call   <isnumeric@plt>
  test   %eax,%eax
  je     L2
  sub    %rbp,%rbx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <strtol@plt>
  mov    %rax,0x0(%r13)
  mov    $0x0,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L36
L2:
  mov    $0xffffffff,%eax
  jmp    L36
```

assistant: ```c
int tokenize_host_port(char *token, char *host, uint16_t *port) {
  char *p = strstr(token, ":");
  int len;
  if (p == NULL)
    return -1;
  if (!isnumeric(p + 1))
    return -1;
  len = p - token;
  strncpy(host, token, len);
  host[len] = 0;
  *port = (uint16_t)strtol(p + 1, NULL, 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tokenize_host_port>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x3a,%esi
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
  lea    0x1(%rax),%r14
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <isnumeric@plt>
  test   %eax,%eax
  je     L16
  sub    %r13,%rbx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <strtol@plt>
  mov    %rax,(%r12)
  xor    %eax,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int tokenize_host_port(char *token, char *host, uint16_t *port) {
  char *p = strstr(token, ":");
  int len;
  if (p == NULL)
    return -1;
  if (!isnumeric(p + 1))
    return -1;
  len = p - token;
  strncpy(host, token, len);
  host[len] = 0;
  *port = (uint16_t)strtol(p + 1, NULL, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tokenize_host_port>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x3a,%esi
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  lea    0x1(%rax),%r14
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <isnumeric@plt>
  test   %eax,%eax
  je     L6
  sub    %r13,%rbx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <strtol@plt>
  mov    %rax,(%r12)
  xor    %eax,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int tokenize_host_port(char *token, char *host, uint16_t *port) {
  char *p = strstr(token, ":");
  int len;
  if (p == NULL)
    return -1;
  if (!isnumeric(p + 1))
    return -1;
  len = p - token;
  strncpy(host, token, len);
  host[len] = 0;
  *port = (uint16_t)strtol(p + 1, NULL, 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *test(void *arg) {
  sleep(10);
  return arg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *test(void *arg) {
  sleep(10);
  return arg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *test(void *arg) {
  sleep(10);
  return arg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *test(void *arg) {
  sleep(10);
  return arg;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ROL64_53>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  rol    $0x35,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ROL64_53(uint64_t x) {
  __asm__("rolq $53, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ROL64_53>:
  endbr64
  mov    %rdi,%rax
  rol    $0x35,%rax
  ret
```

assistant: ```c
uint64_t ROL64_53(uint64_t x) {
  __asm__("rolq $53, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ROL64_53>:
  endbr64
  mov    %rdi,%rax
  rol    $0x35,%rax
  ret
```

assistant: ```c
uint64_t ROL64_53(uint64_t x) {
  __asm__("rolq $53, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ROL64_53>:
  endbr64
  mov    %rdi,%rax
  rol    $0x35,%rax
  ret
```

assistant: ```c
uint64_t ROL64_53(uint64_t x) {
  __asm__("rolq $53, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L15
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0xa,-0x4(%rbp)
  jbe    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: %u


assistant: ```c
int main(void) {
  unsigned int counter = 1;
  for (counter; counter <= 10; counter++) {
    printf("%u\n", counter);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: %u


assistant: ```c
int main(void) {
  unsigned int counter = 1;
  for (counter; counter <= 10; counter++) {
    printf("%u\n", counter);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string

tool: D5: %u


assistant: ```c
int main(void) {
  unsigned int counter = 1;
  for (counter; counter <= 10; counter++) {
    printf("%u\n", counter);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: %u


assistant: ```c
int main(void) {
  unsigned int counter = 1;
  for (counter; counter <= 10; counter++) {
    printf("%u\n", counter);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<QEIIntDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  not    %rax
  mov    %rax,%rsi
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    (%rdx),%rcx
  add    $0x20,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  and    %rcx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void QEIIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000020))) &= ~(ui32IntFlags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QEIIntDisable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdx
  mov    0x20(%rdx),%rcx
  not    %rax
  and    %rcx,%rax
  mov    %rax,0x20(%rdx)
  ret
```

assistant: ```c
void QEIIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000020))) &= ~(ui32IntFlags);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<QEIIntDisable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdx
  not    %rax
  mov    0x20(%rdx),%rcx
  and    %rcx,%rax
  mov    %rax,0x20(%rdx)
  ret
```

assistant: ```c
void QEIIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000020))) &= ~(ui32IntFlags);
}
```
user: Translate the below assembly code into C programming language:

```asm
<QEIIntDisable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdx
  not    %rax
  mov    0x20(%rdx),%rcx
  and    %rcx,%rax
  mov    %rax,0x20(%rdx)
  ret
```

assistant: ```c
void QEIIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000020))) &= ~(ui32IntFlags);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D34(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D52
type_infered: string
name: parse_data
arguments: data_label: D53
type_infered: string
name: parse_data
arguments: data_label: D34
type_infered: f32[2]
name: parse_data
arguments: data_label: D17
type_infered: string

tool: D19: Please enter the sides of the triangle:
 Side A = 

tool: D6: %lf

tool: D52: 
 Side B = 

tool: D53: 
 Side C = 

tool: {"D34": [0.0,2.0]}

tool: D17: Area = %lf

assistant: ```c
int main() {
  double triangleA = 0, triangleB = 0, triangleC = 0;
  double area = 0, halfPerimeter = 0;
  printf("Please enter the sides of the triangle:\n Side A = ");
  scanf("%lf", &triangleA);
  printf("\n Side B = ");
  scanf("%lf", &triangleB);
  printf("\n Side C = ");
  scanf("%lf", &triangleC);
  halfPerimeter = (triangleA + triangleB + triangleC) / 2;
  area = sqrt(halfPerimeter * (halfPerimeter - triangleA) * (halfPerimeter - triangleB) * (halfPerimeter - triangleC));
  printf("Area = %lf", area);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  D35(%rip),%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm4
  mulsd  %xmm4,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L20
  sqrtsd %xmm0,%xmm0
L6:
  lea    D59(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L20:
  call   <sqrt@plt>
  jmp    L6
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D55
data_type: string
name: retrieve_data
arguments: label: D53
data_type: string
name: retrieve_data
arguments: label: D35
data_type: f32[2]
name: retrieve_data
arguments: label: D59
data_type: string

tool: D6: Please enter the sides of the triangle:
 Side A = 

tool: D19: %lf

tool: D55: 
 Side B = 

tool: D53: 
 Side C = 

tool: {"D35": [0.0,1.75]}

tool: D59: Area = %lf

assistant: ```c
int main() {
  double triangleA = 0, triangleB = 0, triangleC = 0;
  double area = 0, halfPerimeter = 0;
  printf("Please enter the sides of the triangle:\n Side A = ");
  scanf("%lf", &triangleA);
  printf("\n Side B = ");
  scanf("%lf", &triangleB);
  printf("\n Side C = ");
  scanf("%lf", &triangleC);
  halfPerimeter = (triangleA + triangleB + triangleC) / 2;
  area = sqrt(halfPerimeter * (halfPerimeter - triangleA) * (halfPerimeter - triangleB) * (halfPerimeter - triangleC));
  printf("Area = %lf", area);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D55(%rip),%rdi
  lea    D49(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  D4(%rip),%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm4
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L15
  sqrtsd %xmm0,%xmm0
L11:
  lea    D48(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  call   <sqrt@plt>
  jmp    L11
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D55
data_type: string
name: retrieve_data
arguments: data_tag: D49
data_type: string
name: retrieve_data
arguments: data_tag: D33
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D4
data_type: f32[2]
name: retrieve_data
arguments: data_tag: D48
data_type: string

tool: D55: Please enter the sides of the triangle:
 Side A = 

tool: D49: %lf

tool: D33: 
 Side B = 

tool: D34: 
 Side C = 

tool: {"D4": [0.0,1.75]}

tool: D48: Area = %lf

assistant: ```c
int main() {
  double triangleA = 0, triangleB = 0, triangleC = 0;
  double area = 0, halfPerimeter = 0;
  printf("Please enter the sides of the triangle:\n Side A = ");
  scanf("%lf", &triangleA);
  printf("\n Side B = ");
  scanf("%lf", &triangleB);
  printf("\n Side C = ");
  scanf("%lf", &triangleC);
  halfPerimeter = (triangleA + triangleB + triangleC) / 2;
  area = sqrt(halfPerimeter * (halfPerimeter - triangleA) * (halfPerimeter - triangleB) * (halfPerimeter - triangleC));
  printf("Area = %lf", area);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  lea    D50(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  D40(%rip),%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm4
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L29
  sqrtsd %xmm0,%xmm0
L16:
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L29:
  call   <sqrt@plt>
  jmp    L16
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D50
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D56
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D40
type_guessed: f32[2]
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D38: Please enter the sides of the triangle:
 Side A = 

tool: D50: %lf

tool: D19: 
 Side B = 

tool: D56: 
 Side C = 

tool: {"D40": [0.0,1.75]}

tool: D1: Area = %lf

assistant: ```c
int main() {
  double triangleA = 0, triangleB = 0, triangleC = 0;
  double area = 0, halfPerimeter = 0;
  printf("Please enter the sides of the triangle:\n Side A = ");
  scanf("%lf", &triangleA);
  printf("\n Side B = ");
  scanf("%lf", &triangleB);
  printf("\n Side C = ");
  scanf("%lf", &triangleC);
  halfPerimeter = (triangleA + triangleB + triangleC) / 2;
  area = sqrt(halfPerimeter * (halfPerimeter - triangleA) * (halfPerimeter - triangleB) * (halfPerimeter - triangleC));
  printf("Area = %lf", area);
  return 0;
}
```