ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jle    L20
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L31
L36:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sum@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L31:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L36
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <sum@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L29
L20:
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D21
data_type: string
name: extract_symbolic_data
arguments: data_label: D31
data_type: string

tool: D10: %d

tool: D7: %d! + 

tool: D21: %d! = %d


tool: D31: Invalid value

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n > 0) {
    int i;
    int result = 0;
    int s;
    for (i = 1; i < n; ++i) {
      s = sum(i);
      result += factorial(s);
      printf("%d! + ", s);
    }
    s = sum(n);
    result += factorial(s);
    printf("%d! = %d\n", s, result);
  } else {
    printf("Invalid value\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L35
  cmp    $0x1,%edi
  jle    L13
  mov    $0x0,%r12d
  mov    $0x1,%ebp
  lea    D25(%rip),%r13
L9:
  mov    %ebp,%edi
  call   <sum@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <factorial@plt>
  add    %eax,%r12d
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%edi
  cmp    %ebp,%edi
  jg     L9
L12:
  call   <sum@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <factorial@plt>
  lea    (%r12,%rax,1),%edx
  mov    %ebx,%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x0,%r12d
  jmp    L12
L35:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L45
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D33
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D37
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string

tool: D33: %d

tool: D25: %d! + 

tool: D37: %d! = %d


tool: D3: Invalid value

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n > 0) {
    int i;
    int result = 0;
    int s;
    for (i = 1; i < n; ++i) {
      s = sum(i);
      result += factorial(s);
      printf("%d! + ", s);
    }
    s = sum(n);
    result += factorial(s);
    printf("%d! = %d\n", s, result);
  } else {
    printf("Invalid value\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L3
  xor    %r12d,%r12d
  cmp    $0x1,%edi
  je     L48
  mov    $0x1,%ebx
  lea    D34(%rip),%r13
  nop
L44:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <sum@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %r13,%rdi
  mov    %ebp,%esi
  add    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebx,%edi
  jg     L44
L48:
  call   <sum@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %ebp,%esi
  lea    D27(%rip),%rdi
  lea    (%r12,%rax,1),%edx
  xor    %eax,%eax
  call   <printf@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string

tool: D13: %d

tool: D34: %d! + 

tool: D27: %d! = %d


tool: D20: Invalid value

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n > 0) {
    int i;
    int result = 0;
    int s;
    for (i = 1; i < n; ++i) {
      s = sum(i);
      result += factorial(s);
      printf("%d! + ", s);
    }
    s = sum(n);
    result += factorial(s);
    printf("%d! = %d\n", s, result);
  } else {
    printf("Invalid value\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L3
  xor    %r12d,%r12d
  cmp    $0x1,%edi
  je     L19
  mov    $0x1,%ebx
  lea    D35(%rip),%r13
  nop
L23:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <sum@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %r13,%rdi
  mov    %ebp,%esi
  add    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebx,%edi
  jg     L23
L19:
  call   <sum@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %ebp,%esi
  lea    D37(%rip),%rdi
  lea    (%r12,%rax,1),%edx
  xor    %eax,%eax
  call   <printf@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L10
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D2
type: string

tool: D12: %d

tool: D35: %d! + 

tool: D37: %d! = %d


tool: D2: Invalid value

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n > 0) {
    int i;
    int result = 0;
    int s;
    for (i = 1; i < n; ++i) {
      s = sum(i);
      result += factorial(s);
      printf("%d! + ", s);
    }
    s = sum(n);
    result += factorial(s);
    printf("%d! = %d\n", s, result);
  } else {
    printf("Invalid value\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <move_register_test@plt>
  mov    $0x0,%eax
  call   <move_from_memory_test@plt>
  mov    $0x0,%eax
  call   <move_to_memory_test@plt>
  mov    $0x0,%eax
  call   <move_immediate_test@plt>
  mov    $0x0,%eax
  call   <move_to_memory_immediate_test@plt>
  mov    $0x0,%eax
  call   <load_register_pair_immediate_test@plt>
  mov    $0x0,%eax
  call   <load_accumulator_direct_test@plt>
  mov    $0x0,%eax
  call   <store_accumulator_direct_test@plt>
  mov    $0x0,%eax
  call   <load_HL_direct_test@plt>
  mov    $0x0,%eax
  call   <store_HL_direct_test@plt>
  mov    $0x0,%eax
  call   <load_accumulator_indirect_test@plt>
  mov    $0x0,%eax
  call   <store_accumulator_indirect_test@plt>
  mov    $0x0,%eax
  call   <exchange_HL_DE_test@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  move_register_test();
  move_from_memory_test();
  move_to_memory_test();
  move_immediate_test();
  move_to_memory_immediate_test();
  load_register_pair_immediate_test();
  load_accumulator_direct_test();
  store_accumulator_direct_test();
  load_HL_direct_test();
  store_HL_direct_test();
  load_accumulator_indirect_test();
  store_accumulator_indirect_test();
  exchange_HL_DE_test();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <move_register_test@plt>
  mov    $0x0,%eax
  call   <move_from_memory_test@plt>
  mov    $0x0,%eax
  call   <move_to_memory_test@plt>
  mov    $0x0,%eax
  call   <move_immediate_test@plt>
  mov    $0x0,%eax
  call   <move_to_memory_immediate_test@plt>
  mov    $0x0,%eax
  call   <load_register_pair_immediate_test@plt>
  mov    $0x0,%eax
  call   <load_accumulator_direct_test@plt>
  mov    $0x0,%eax
  call   <store_accumulator_direct_test@plt>
  mov    $0x0,%eax
  call   <load_HL_direct_test@plt>
  mov    $0x0,%eax
  call   <store_HL_direct_test@plt>
  mov    $0x0,%eax
  call   <load_accumulator_indirect_test@plt>
  mov    $0x0,%eax
  call   <store_accumulator_indirect_test@plt>
  mov    $0x0,%eax
  call   <exchange_HL_DE_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  move_register_test();
  move_from_memory_test();
  move_to_memory_test();
  move_immediate_test();
  move_to_memory_immediate_test();
  load_register_pair_immediate_test();
  load_accumulator_direct_test();
  store_accumulator_direct_test();
  load_HL_direct_test();
  store_HL_direct_test();
  load_accumulator_indirect_test();
  store_accumulator_indirect_test();
  exchange_HL_DE_test();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <move_register_test@plt>
  xor    %eax,%eax
  call   <move_from_memory_test@plt>
  xor    %eax,%eax
  call   <move_to_memory_test@plt>
  xor    %eax,%eax
  call   <move_immediate_test@plt>
  xor    %eax,%eax
  call   <move_to_memory_immediate_test@plt>
  xor    %eax,%eax
  call   <load_register_pair_immediate_test@plt>
  xor    %eax,%eax
  call   <load_accumulator_direct_test@plt>
  xor    %eax,%eax
  call   <store_accumulator_direct_test@plt>
  xor    %eax,%eax
  call   <load_HL_direct_test@plt>
  xor    %eax,%eax
  call   <store_HL_direct_test@plt>
  xor    %eax,%eax
  call   <load_accumulator_indirect_test@plt>
  xor    %eax,%eax
  call   <store_accumulator_indirect_test@plt>
  xor    %eax,%eax
  call   <exchange_HL_DE_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  move_register_test();
  move_from_memory_test();
  move_to_memory_test();
  move_immediate_test();
  move_to_memory_immediate_test();
  load_register_pair_immediate_test();
  load_accumulator_direct_test();
  store_accumulator_direct_test();
  load_HL_direct_test();
  store_HL_direct_test();
  load_accumulator_indirect_test();
  store_accumulator_indirect_test();
  exchange_HL_DE_test();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <move_register_test@plt>
  xor    %eax,%eax
  call   <move_from_memory_test@plt>
  xor    %eax,%eax
  call   <move_to_memory_test@plt>
  xor    %eax,%eax
  call   <move_immediate_test@plt>
  xor    %eax,%eax
  call   <move_to_memory_immediate_test@plt>
  xor    %eax,%eax
  call   <load_register_pair_immediate_test@plt>
  xor    %eax,%eax
  call   <load_accumulator_direct_test@plt>
  xor    %eax,%eax
  call   <store_accumulator_direct_test@plt>
  xor    %eax,%eax
  call   <load_HL_direct_test@plt>
  xor    %eax,%eax
  call   <store_HL_direct_test@plt>
  xor    %eax,%eax
  call   <load_accumulator_indirect_test@plt>
  xor    %eax,%eax
  call   <store_accumulator_indirect_test@plt>
  xor    %eax,%eax
  call   <exchange_HL_DE_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  move_register_test();
  move_from_memory_test();
  move_to_memory_test();
  move_immediate_test();
  move_to_memory_immediate_test();
  load_register_pair_immediate_test();
  load_accumulator_direct_test();
  store_accumulator_direct_test();
  load_HL_direct_test();
  store_HL_direct_test();
  load_accumulator_indirect_test();
  store_accumulator_indirect_test();
  exchange_HL_DE_test();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<func9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func9() {
#pragma critTer : 34 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 35 :../../ test / resources / functionNumber.c:
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func9>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func9() {
#pragma critTer : 34 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 35 :../../ test / resources / functionNumber.c:
}
```
user: Translate the below assembly code into C programming language:

```asm
<func9>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func9() {
#pragma critTer : 34 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 35 :../../ test / resources / functionNumber.c:
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func9>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func9() {
#pragma critTer : 34 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 35 :../../ test / resources / functionNumber.c:
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    $0x4,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: %ld %ld

assistant: ```c
int main() {
  float a;
  double b;
  printf("%ld %ld", sizeof(a), sizeof(b));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edx
  mov    $0x4,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %ld %ld

assistant: ```c
int main() {
  float a;
  double b;
  printf("%ld %ld", sizeof(a), sizeof(b));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edx
  mov    $0x4,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: %ld %ld

assistant: ```c
int main() {
  float a;
  double b;
  printf("%ld %ld", sizeof(a), sizeof(b));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edx
  mov    $0x4,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: %ld %ld

assistant: ```c
int main() {
  float a;
  double b;
  printf("%ld %ld", sizeof(a), sizeof(b));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L52
L51:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L30
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L1
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L1
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L30:
  addl   $0x1,-0x14(%rbp)
L52:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L51
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D30
type_infered: string
name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D33
type_infered: string
name: read_data
arguments: label: D4
type_infered: string

tool: D30: Kac sayi girilecek: 

tool: D6: %d

tool: D33: %d. sayi giriniz: 

tool: D4: ebob = %d

assistant: ```c
int main() {
  int i, n, sayi, buyuk, ebob;
  printf("Kac sayi girilecek: ");
  scanf("%d", &n);
  buyuk = 0;
  for (i = 1; i <= n; i++) {
    printf("%d. sayi giriniz: ", i);
    scanf("%d", &sayi);
    if (buyuk < sayi) {
      if (buyuk % i == 0 && sayi % i == 0) {
        ebob = i;
      }
      buyuk = sayi;
    }
  }
  printf("ebob = %d", ebob);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L60
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  lea    D40(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D1(%rip),%r12
  jmp    L47
L45:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L60
L47:
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebp,%ecx
  jle    L45
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %ecx,%ebp
  test   %edx,%edx
  jne    L45
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  cmove  %ebx,%r15d
  jmp    L45
L60:
  mov    %r15d,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D42
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D40
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string

tool: D42: Kac sayi girilecek: 

tool: D1: %d

tool: D40: %d. sayi giriniz: 

tool: D23: ebob = %d

assistant: ```c
int main() {
  int i, n, sayi, buyuk, ebob;
  printf("Kac sayi girilecek: ");
  scanf("%d", &n);
  buyuk = 0;
  for (i = 1; i <= n; i++) {
    printf("%d. sayi giriniz: ", i);
    scanf("%d", &sayi);
    if (buyuk < sayi) {
      if (buyuk % i == 0 && sayi % i == 0) {
        ebob = i;
      }
      buyuk = sayi;
    }
  }
  printf("ebob = %d", ebob);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D39(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L3
  xor    %ebp,%ebp
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r13
  lea    D29(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebp,%ecx
  jle    L39
  mov    %ebp,%eax
  mov    %ecx,%ebp
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L39
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  cmove  %ebx,%r15d
L39:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L44
L3:
  xor    %eax,%eax
  mov    %r15d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D39
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D3: Kac sayi girilecek: 

tool: D39: %d

tool: D29: %d. sayi giriniz: 

tool: D18: ebob = %d

assistant: ```c
int main() {
  int i, n, sayi, buyuk, ebob;
  printf("Kac sayi girilecek: ");
  scanf("%d", &n);
  buyuk = 0;
  for (i = 1; i <= n; i++) {
    printf("%d. sayi giriniz: ", i);
    scanf("%d", &sayi);
    if (buyuk < sayi) {
      if (buyuk % i == 0 && sayi % i == 0) {
        ebob = i;
      }
      buyuk = sayi;
    }
  }
  printf("ebob = %d", ebob);
  return 0;
}
```