ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <isEmpty@plt>
  test   %eax,%eax
  lea    D59(%rip),%rsi
  lea    D13(%rip),%rax
  cmove  %rax,%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <add@plt>
  mov    $0x0,%eax
  call   <peek@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <add@plt>
  mov    $0x0,%eax
  call   <peek@plt>
  mov    %eax,%esi
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <add@plt>
  mov    $0x0,%eax
  call   <peek@plt>
  mov    %eax,%esi
  lea    D99(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <take@plt>
  mov    %eax,%esi
  lea    D80(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <take@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <take@plt>
  mov    %eax,%esi
  lea    D108(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <isEmpty@plt>
  test   %eax,%eax
  lea    D59(%rip),%rsi
  lea    D13(%rip),%rax
  cmove  %rax,%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D59
type: string
name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D36
type: string
name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D69
type: string
name: disassemble_data
arguments: data_label: D99
type: string
name: disassemble_data
arguments: data_label: D80
type: string
name: disassemble_data
arguments: data_label: D12
type: string
name: disassemble_data
arguments: data_label: D108
type: string
name: disassemble_data
arguments: data_label: D39
type: string

tool: D59: empty

tool: D13: full

tool: D36: At the beginning the queue is: %s


tool: D33: Add 1 to the queue. Peek() returns: %i


tool: D69: Add 2 to the queue. Peek() returns: %i


tool: D99: Add 3 to the queue. Peek() returns: %i


tool: D80: take() test. Expect 1, returns: %i


tool: D12: take() test. Expect 2, returns: %i


tool: D108: take() test. Expect 3, returns: %i


tool: D39: At the end the queue is: %s


assistant: ```c
int main(void) {
  printf("At the beginning the queue is: %s\n", isEmpty() ? "empty" : "full");
  add(1);
  printf("Add 1 to the queue. Peek() returns: %i\n", peek());
  add(2);
  printf("Add 2 to the queue. Peek() returns: %i\n", peek());
  add(3);
  printf("Add 3 to the queue. Peek() returns: %i\n", peek());
  printf("take() test. Expect 1, returns: %i\n", take());
  printf("take() test. Expect 2, returns: %i\n", take());
  printf("take() test. Expect 3, returns: %i\n", take());
  printf("At the end the queue is: %s\n", isEmpty() ? "empty" : "full");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D76(%rip),%rbp
  push   %rbx
  lea    D66(%rip),%rbx
  sub    $0x8,%rsp
  call   <isEmpty@plt>
  mov    %rbp,%rsi
  lea    D94(%rip),%rdi
  test   %eax,%eax
  cmovne %rbx,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <add@plt>
  xor    %eax,%eax
  call   <peek@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  xor    %eax,%eax
  call   <add@plt>
  xor    %eax,%eax
  call   <peek@plt>
  lea    D52(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  xor    %eax,%eax
  call   <add@plt>
  xor    %eax,%eax
  call   <peek@plt>
  lea    D80(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <take@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <take@plt>
  lea    D60(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <take@plt>
  lea    D67(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <isEmpty@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  test   %eax,%eax
  cmovne %rbx,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D76
datatype: string
name: unpack_data
arguments: data_tag: D66
datatype: string
name: unpack_data
arguments: data_tag: D94
datatype: string
name: unpack_data
arguments: data_tag: D20
datatype: string
name: unpack_data
arguments: data_tag: D52
datatype: string
name: unpack_data
arguments: data_tag: D80
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D60
datatype: string
name: unpack_data
arguments: data_tag: D67
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D76: full

tool: D66: empty

tool: D94: At the beginning the queue is: %s


tool: D20: Add 1 to the queue. Peek() returns: %i


tool: D52: Add 2 to the queue. Peek() returns: %i


tool: D80: Add 3 to the queue. Peek() returns: %i


tool: D3: take() test. Expect 1, returns: %i


tool: D60: take() test. Expect 2, returns: %i


tool: D67: take() test. Expect 3, returns: %i


tool: D2: At the end the queue is: %s


assistant: ```c
int main(void) {
  printf("At the beginning the queue is: %s\n", isEmpty() ? "empty" : "full");
  add(1);
  printf("Add 1 to the queue. Peek() returns: %i\n", peek());
  add(2);
  printf("Add 2 to the queue. Peek() returns: %i\n", peek());
  add(3);
  printf("Add 3 to the queue. Peek() returns: %i\n", peek());
  printf("take() test. Expect 1, returns: %i\n", take());
  printf("take() test. Expect 2, returns: %i\n", take());
  printf("take() test. Expect 3, returns: %i\n", take());
  printf("At the end the queue is: %s\n", isEmpty() ? "empty" : "full");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D91(%rip),%rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x8,%rsp
  call   <isEmpty@plt>
  mov    %rbp,%rsi
  lea    D70(%rip),%rdi
  test   %eax,%eax
  cmovne %rbx,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <add@plt>
  xor    %eax,%eax
  call   <peek@plt>
  lea    D31(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  xor    %eax,%eax
  call   <add@plt>
  xor    %eax,%eax
  call   <peek@plt>
  lea    D54(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  xor    %eax,%eax
  call   <add@plt>
  xor    %eax,%eax
  call   <peek@plt>
  lea    D30(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <take@plt>
  lea    D68(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <take@plt>
  lea    D98(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <take@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <isEmpty@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  test   %eax,%eax
  cmovne %rbx,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D91
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D70
type: string
name: read_data
arguments: tag: D31
type: string
name: read_data
arguments: tag: D54
type: string
name: read_data
arguments: tag: D30
type: string
name: read_data
arguments: tag: D68
type: string
name: read_data
arguments: tag: D98
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D13
type: string

tool: D91: full

tool: D6: empty

tool: D70: At the beginning the queue is: %s


tool: D31: Add 1 to the queue. Peek() returns: %i


tool: D54: Add 2 to the queue. Peek() returns: %i


tool: D30: Add 3 to the queue. Peek() returns: %i


tool: D68: take() test. Expect 1, returns: %i


tool: D98: take() test. Expect 2, returns: %i


tool: D15: take() test. Expect 3, returns: %i


tool: D13: At the end the queue is: %s


assistant: ```c
int main(void) {
  printf("At the beginning the queue is: %s\n", isEmpty() ? "empty" : "full");
  add(1);
  printf("Add 1 to the queue. Peek() returns: %i\n", peek());
  add(2);
  printf("Add 2 to the queue. Peek() returns: %i\n", peek());
  add(3);
  printf("Add 3 to the queue. Peek() returns: %i\n", peek());
  printf("take() test. Expect 1, returns: %i\n", take());
  printf("take() test. Expect 2, returns: %i\n", take());
  printf("take() test. Expect 3, returns: %i\n", take());
  printf("At the end the queue is: %s\n", isEmpty() ? "empty" : "full");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L0
L26:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  shl    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type_infered: string
name: extract_symbolic_data
arguments: data_label: D18
type_infered: string

tool: D28: %lld

tool: D18: %lld


assistant: ```c
int main() {
  long long n, s, t;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &s);
    n = (-1 + sqrt(1 + 8 * s)) / 2;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L26
  lea    0x8(%rsp),%r12
  lea    D3(%rip),%rbp
  lea    D10(%rip),%rbx
L24:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x1(,%rax,8),%edi
  call   <sqrt@plt>
  sub    $0x1,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  movslq %esi,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L24
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string

tool: D3: %lld

tool: D10: %lld


assistant: ```c
int main() {
  long long n, s, t;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &s);
    n = (-1 + sqrt(1 + 8 * s)) / 2;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L22
  lea    0x8(%rsp),%r12
  lea    D14(%rip),%rbp
  nop
L14:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x1(,%rax,8),%edi
  call   <sqrt@plt>
  mov    %rbp,%rdi
  sub    $0x1,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  movslq %esi,%rsi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L14
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D18: %lld

tool: D14: %lld


assistant: ```c
int main() {
  long long n, s, t;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &s);
    n = (-1 + sqrt(1 + 8 * s)) / 2;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L12
  lea    0x8(%rsp),%r12
  lea    D12(%rip),%rbp
  nop
L5:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x1(,%rax,8),%edi
  call   <sqrt@plt>
  mov    %rbp,%rdi
  sub    $0x1,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  movslq %esi,%rsi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L5
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D3: %lld

tool: D12: %lld


assistant: ```c
int main() {
  long long n, s, t;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &s);
    n = (-1 + sqrt(1 + 8 * s)) / 2;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<createCompressedFileName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L15
L49:
  subl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x0,-0x14(%rbp)
  js     L45
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L49
L45:
  addl   $0x1,-0x14(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L17
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: .huff

assistant: ```c
char *createCompressedFileName(char pathFile[]) {
  int endOfName = strlen(pathFile);
  int i, j;
  for (i = endOfName; i >= 0 && pathFile[i] != '\\';)
    i--;
  i++;
  char *newFileName = (char *)malloc(100 * sizeof(char));
  for (j = 0; i < endOfName; j++, i++)
    newFileName[j] = pathFile[i];
  newFileName[j] = '\0';
  strcat(newFileName, ".huff");
  return (newFileName);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<createCompressedFileName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L51
  cltq
  add    %rbp,%rax
  mov    %r12d,%ebx
L18:
  cmpb   $0x5c,(%rax)
  je     L56
  sub    $0x1,%ebx
  sub    $0x1,%rax
  cmp    $0xffffffff,%ebx
  jne    L18
L56:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    0x1(%rbx),%eax
  cmp    %eax,%r12d
  jle    L55
  mov    %ebx,%esi
  lea    -0x2(%r12),%eax
  sub    %ebx,%eax
  lea    0x1(%r13,%rax,1),%rcx
  mov    %r13,%rax
  movslq %ebx,%rbx
  sub    %r13,%rbx
  add    %rbx,%rbp
L9:
  movzbl 0x1(%rbp,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L9
  sub    $0x1,%r12d
  sub    %esi,%r12d
L60:
  movslq %r12d,%r12
  movb   $0x0,0x0(%r13,%r12,1)
  lea    D2(%rip),%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  mov    %eax,%ebx
  jmp    L56
L55:
  mov    $0x0,%r12d
  jmp    L60
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: .huff

assistant: ```c
char *createCompressedFileName(char pathFile[]) {
  int endOfName = strlen(pathFile);
  int i, j;
  for (i = endOfName; i >= 0 && pathFile[i] != '\\';)
    i--;
  i++;
  char *newFileName = (char *)malloc(100 * sizeof(char));
  for (j = 0; i < endOfName; j++, i++)
    newFileName[j] = pathFile[i];
  newFileName[j] = '\0';
  strcat(newFileName, ".huff");
  return (newFileName);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<createCompressedFileName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L26
  cltq
  jmp    L4
  nopl   (%rax)
L49:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L6
L4:
  cmpb   $0x5c,(%rbx,%rax,1)
  mov    %eax,%ebp
  jne    L49
  add    $0x1,%ebp
L6:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    %ebp,%r12d
  jle    L0
  lea    -0x1(%r12),%eax
  movslq %ebp,%rdx
  sub    %ebp,%eax
  sub    %r13,%rdx
  lea    0x1(%r13,%rax,1),%rcx
  add    %rdx,%rbx
  mov    %r13,%rax
  nopl   (%rax)
L10:
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L10
  sub    %ebp,%r12d
  movslq %r12d,%r12
  add    %r13,%r12
L37:
  movb   $0x0,(%r12)
  mov    %r13,%rdi
  lea    D7(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rax,%r12
  jmp    L37
L26:
  lea    0x1(%rax),%ebp
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: .huff

assistant: ```c
char *createCompressedFileName(char pathFile[]) {
  int endOfName = strlen(pathFile);
  int i, j;
  for (i = endOfName; i >= 0 && pathFile[i] != '\\';)
    i--;
  i++;
  char *newFileName = (char *)malloc(100 * sizeof(char));
  for (j = 0; i < endOfName; j++, i++)
    newFileName[j] = pathFile[i];
  newFileName[j] = '\0';
  strcat(newFileName, ".huff");
  return (newFileName);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Readline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x1,-0x20(%rbp)
  jmp    L83
L10:
  lea    -0x21(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <my_read@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x1,-0x10(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x21(%rbp),%edx
  mov    %dl,(%rax)
  movzbl -0x21(%rbp),%eax
  cmp    $0xa,%al
  jne    L15
  jmp    L22
L4:
  cmpq   $0x0,-0x10(%rbp)
  jne    L64
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  jmp    L62
L64:
  mov    $0xffffffffffffffff,%rax
  jmp    L62
L15:
  addq   $0x1,-0x20(%rbp)
L83:
  mov    -0x20(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L10
L22:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L62:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

assistant: ```c
ssize_t Readline(int fd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *ptr;
  ptr = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = my_read(fd, &c)) == 1) {
      *ptr++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      *ptr = 0;
      return n - 1;
    } else
      return -1;
  }
  *ptr = 0;
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdx
  jbe    L9
  mov    %edi,%r12d
  lea    -0x1(%rsi,%rdx,1),%r14
  mov    $0x1,%ebp
  lea    0x7(%rsp),%r13
L10:
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <my_read@plt>
  cmp    $0x1,%rax
  jne    L7
  add    $0x1,%rbx
  movzbl 0x7(%rsp),%eax
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%al
  je     L64
  add    $0x1,%rbp
  cmp    %r14,%rbx
  jne    L10
  mov    %r14,%rbx
L64:
  movb   $0x0,(%rbx)
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  test   %rax,%rax
  jne    L26
  movb   $0x0,(%rbx)
  sub    $0x1,%rbp
  jmp    L31
L9:
  mov    $0x1,%ebp
  jmp    L64
L26:
  mov    $0xffffffffffffffff,%rbp
  jmp    L31
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t Readline(int fd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *ptr;
  ptr = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = my_read(fd, &c)) == 1) {
      *ptr++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      *ptr = 0;
      return n - 1;
    } else
      return -1;
  }
  *ptr = 0;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdx
  jbe    L42
  mov    %edi,%ebp
  lea    -0x1(%rsi,%rdx,1),%r14
  mov    $0x1,%r12d
  lea    0x7(%rsp),%r13
  jmp    L36
  nopl   (%rax)
L14:
  movzbl 0x7(%rsp),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%al
  je     L57
  add    $0x1,%r12
  cmp    %r14,%rbx
  je     L57
L36:
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <my_read@plt>
  cmp    $0x1,%rax
  je     L14
  test   %rax,%rax
  jne    L54
  movb   $0x0,(%rbx)
  sub    $0x1,%r12
  jmp    L40
L42:
  mov    $0x1,%r12d
  nopl   (%rax)
L57:
  movb   $0x0,(%rbx)
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  mov    $0xffffffffffffffff,%r12
  jmp    L40
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t Readline(int fd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *ptr;
  ptr = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = my_read(fd, &c)) == 1) {
      *ptr++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      *ptr = 0;
      return n - 1;
    } else
      return -1;
  }
  *ptr = 0;
  return n;
}
```