ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<stricmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L141
L101:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L141:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L118
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L118
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L45
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L45
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x20(%rax),%edx
  jmp    L25
L45:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L82
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L82
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x20,%eax
  jmp    L51
L82:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L51:
  cmp    %eax,%edx
  je     L101
L118:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L139
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L139
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x20,%eax
  jmp    L113
L139:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L113:
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    $0x60,%dl
  jle    L92
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    $0x7a,%dl
  jg     L92
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    $0x20,%edx
  jmp    L69
L92:
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
L69:
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && ((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) == ((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2)) {
    s1++;
    s2++;
  }
  return (int)((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) - (int)((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stricmp>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L11
L43:
  movzbl (%r9),%eax
  test   %al,%al
  je     L48
  lea    -0x61(%rcx),%edi
  movsbl %cl,%esi
  sub    $0x20,%esi
  movsbl %cl,%edx
  cmp    $0x19,%dil
  cmovbe %esi,%edx
  lea    -0x61(%rax),%edi
  movsbl %al,%esi
  sub    $0x20,%esi
  movsbl %al,%eax
  cmp    $0x19,%dil
  cmovbe %esi,%eax
  cmp    %eax,%edx
  jne    L48
  add    $0x1,%r8
  add    $0x1,%r9
  movzbl (%r8),%ecx
  test   %cl,%cl
  jne    L43
L11:
  mov    $0x0,%ecx
L37:
  movsbl %cl,%eax
  jmp    L14
L48:
  lea    -0x61(%rcx),%eax
  cmp    $0x19,%al
  ja     L37
  movsbl %cl,%eax
  sub    $0x20,%eax
L14:
  movzbl (%r9),%edx
  lea    -0x61(%rdx),%esi
  movsbl %dl,%ecx
  sub    $0x20,%ecx
  movsbl %dl,%edx
  cmp    $0x19,%sil
  cmovbe %ecx,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && ((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) == ((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2)) {
    s1++;
    s2++;
  }
  return (int)((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) - (int)((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stricmp>:
  endbr64
  push   %rbx
  mov    %rdi,%r9
  movzbl (%rdi),%edi
  mov    %rsi,%r11
  test   %dil,%dil
  jne    L43
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L13:
  lea    -0x20(%rdi),%eax
  cmp    $0x19,%r10b
  movsbl %dil,%ecx
  movsbl %sil,%edx
  movsbl %al,%eax
  lea    -0x61(%rsi),%ebx
  lea    -0x20(%rsi),%r8d
  cmovbe %eax,%ecx
  movsbl %r8b,%r8d
  cmp    $0x19,%bl
  cmovbe %r8d,%edx
  cmp    %edx,%ecx
  jne    L10
  movzbl 0x1(%r9),%edi
  add    $0x1,%r9
  lea    0x1(%r11),%rax
  test   %dil,%dil
  je     L68
  mov    %rax,%r11
L43:
  movsbl (%r11),%esi
  lea    -0x61(%rdi),%r10d
  test   %sil,%sil
  jne    L13
  cmp    $0x19,%r10b
  ja     L35
  lea    -0x20(%rdi),%eax
  movsbl %al,%eax
L98:
  sub    %esi,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L10:
  cmp    $0x19,%r10b
  ja     L40
L19:
  cmp    $0x19,%bl
  ja     L98
  sub    $0x20,%esi
  pop    %rbx
  movsbl %sil,%esi
  sub    %esi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L68:
  movsbl 0x1(%r11),%esi
  xor    %eax,%eax
  lea    -0x61(%rsi),%ebx
  jmp    L19
L35:
  mov    $0xffffff9f,%ebx
L40:
  movsbl %dil,%eax
  jmp    L19
L62:
  movsbl (%rsi),%esi
  xor    %eax,%eax
  lea    -0x61(%rsi),%ebx
  jmp    L19
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && ((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) == ((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2)) {
    s1++;
    s2++;
  }
  return (int)((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) - (int)((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stricmp>:
  endbr64
  push   %rbx
  mov    %rdi,%r9
  movzbl (%rdi),%edi
  mov    %rsi,%r11
  test   %dil,%dil
  jne    L73
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L94:
  lea    -0x20(%rdi),%eax
  cmp    $0x19,%r10b
  movsbl %dil,%ecx
  movsbl %sil,%edx
  movsbl %al,%eax
  lea    -0x61(%rsi),%ebx
  lea    -0x20(%rsi),%r8d
  cmovbe %eax,%ecx
  movsbl %r8b,%r8d
  cmp    $0x19,%bl
  cmovbe %r8d,%edx
  cmp    %edx,%ecx
  jne    L98
  movzbl 0x1(%r9),%edi
  add    $0x1,%r9
  lea    0x1(%r11),%rax
  test   %dil,%dil
  je     L24
  mov    %rax,%r11
L73:
  movsbl (%r11),%esi
  lea    -0x61(%rdi),%r10d
  test   %sil,%sil
  jne    L94
  cmp    $0x19,%r10b
  ja     L86
  lea    -0x20(%rdi),%eax
  movsbl %al,%eax
L93:
  sub    %esi,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L98:
  cmp    $0x19,%r10b
  ja     L30
L68:
  cmp    $0x19,%bl
  ja     L93
  sub    $0x20,%esi
  pop    %rbx
  movsbl %sil,%esi
  sub    %esi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  movsbl 0x1(%r11),%esi
  xor    %eax,%eax
  lea    -0x61(%rsi),%ebx
  jmp    L68
L86:
  mov    $0xffffff9f,%ebx
L30:
  movsbl %dil,%eax
  jmp    L68
L16:
  movsbl (%rsi),%esi
  xor    %eax,%eax
  lea    -0x61(%rsi),%ebx
  jmp    L68
```

assistant: ```c
int stricmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && ((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) == ((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2)) {
    s1++;
    s2++;
  }
  return (int)((*s1 >= 'a' && *s1 <= 'z') ? (*s1 + ('A' - 'a')) : *s1) - (int)((*s2 >= 'a' && *s2 <= 'z') ? (*s2 + ('A' - 'a')) : *s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_value_ptr@plt>
  cmp    $0x1,%eax
  jne    L11
  mov    $0x1,%eax
  jmp    L5
L11:
  lea    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_var_nbytes@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L30
  mov    -0x14(%rbp),%eax
  jmp    L5
L30:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
int get_value(void *self, const char *name, void *dest) {
  void *src = NULL;
  if (get_value_ptr(self, name, &src) == (1)) {
    return (1);
  } else {
    int nbytes;
    {
      const int status = (get_var_nbytes(self, name, &nbytes));
      if (status != (0))
        return status;
    };
    memcpy(dest, src, nbytes);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_value>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  call   <get_value_ptr@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  je     L35
  lea    0xc(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <get_var_nbytes@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L28
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  jmp    L35
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_value(void *self, const char *name, void *dest) {
  void *src = NULL;
  if (get_value_ptr(self, name, &src) == (1)) {
    return (1);
  } else {
    int nbytes;
    {
      const int status = (get_var_nbytes(self, name, &nbytes));
      if (status != (0))
        return status;
    };
    memcpy(dest, src, nbytes);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_value>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  movq   $0x0,0x10(%rsp)
  call   <get_value_ptr@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  je     L0
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <get_var_nbytes@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L7
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L0
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_value(void *self, const char *name, void *dest) {
  void *src = NULL;
  if (get_value_ptr(self, name, &src) == (1)) {
    return (1);
  } else {
    int nbytes;
    {
      const int status = (get_var_nbytes(self, name, &nbytes));
      if (status != (0))
        return status;
    };
    memcpy(dest, src, nbytes);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_value>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  movq   $0x0,0x10(%rsp)
  call   <get_value_ptr@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  je     L30
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <get_var_nbytes@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L34
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L34:
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L30
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_value(void *self, const char *name, void *dest) {
  void *src = NULL;
  if (get_value_ptr(self, name, &src) == (1)) {
    return (1);
  } else {
    int nbytes;
    {
      const int status = (get_var_nbytes(self, name, &nbytes));
      if (status != (0))
        return status;
    };
    memcpy(dest, src, nbytes);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pt_time_sec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
long pt_time_sec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (long)tv.tv_sec;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pt_time_sec>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long pt_time_sec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (long)tv.tv_sec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pt_time_sec>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long pt_time_sec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (long)tv.tv_sec;
}
```
user: What is the c source code of the assembly code below?

```asm
<pt_time_sec>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long pt_time_sec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (long)tv.tv_sec;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<errExit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void errExit(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<errExit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void errExit(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<errExit>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D14(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void errExit(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<errExit>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void errExit(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvt_31x6p5_bin32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <div31@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <div31@plt>
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <div31@plt>
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <div31@plt>
  mov    -0x18(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <div31@plt>
  mov    -0x18(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <div31@plt>
  mov    -0x18(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
uint8_t cvt_31x6p5_bin32(uint8_t *gfv, uint32_t bv) {
  uint32_t r;
  div31(&bv, &r, bv);
  gfv[0] = r;
  div31(&bv, &r, bv);
  gfv[1] = r;
  div31(&bv, &r, bv);
  gfv[2] = r;
  div31(&bv, &r, bv);
  gfv[3] = r;
  div31(&bv, &r, bv);
  gfv[4] = r;
  div31(&bv, &r, bv);
  gfv[5] = r;
  return bv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cvt_31x6p5_bin32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edx
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
  lea    0xc(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x4(%rbx)
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x8(%rbx)
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0xc(%rbx)
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x10(%rbx)
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x14(%rbx)
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t cvt_31x6p5_bin32(uint8_t *gfv, uint32_t bv) {
  uint32_t r;
  div31(&bv, &r, bv);
  gfv[0] = r;
  div31(&bv, &r, bv);
  gfv[1] = r;
  div31(&bv, &r, bv);
  gfv[2] = r;
  div31(&bv, &r, bv);
  gfv[3] = r;
  div31(&bv, &r, bv);
  gfv[4] = r;
  div31(&bv, &r, bv);
  gfv[5] = r;
  return bv;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cvt_31x6p5_bin32>:
  endbr64
  push   %r12
  mov    %esi,%edx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %esi,0xc(%rsp)
  lea    0x14(%rsp),%r12
  lea    0xc(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x4(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x8(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0xc(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x10(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x14(%rbx)
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t cvt_31x6p5_bin32(uint8_t *gfv, uint32_t bv) {
  uint32_t r;
  div31(&bv, &r, bv);
  gfv[0] = r;
  div31(&bv, &r, bv);
  gfv[1] = r;
  div31(&bv, &r, bv);
  gfv[2] = r;
  div31(&bv, &r, bv);
  gfv[3] = r;
  div31(&bv, &r, bv);
  gfv[4] = r;
  div31(&bv, &r, bv);
  gfv[5] = r;
  return bv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cvt_31x6p5_bin32>:
  endbr64
  push   %r12
  mov    %esi,%edx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %esi,0xc(%rsp)
  lea    0x14(%rsp),%r12
  lea    0xc(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x4(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x8(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0xc(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x10(%rbx)
  call   <div31@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x14(%rbx)
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t cvt_31x6p5_bin32(uint8_t *gfv, uint32_t bv) {
  uint32_t r;
  div31(&bv, &r, bv);
  gfv[0] = r;
  div31(&bv, &r, bv);
  gfv[1] = r;
  div31(&bv, &r, bv);
  gfv[2] = r;
  div31(&bv, &r, bv);
  gfv[3] = r;
  div31(&bv, &r, bv);
  gfv[4] = r;
  div31(&bv, &r, bv);
  gfv[5] = r;
  return bv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getpathbuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <memerrexit@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getpathbuffer(void) {
  char *buf;
  if (!(buf = malloc(1023 + 1)))
    memerrexit();
  return buf;
}
```