ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ezRect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x18(%rbp)
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  jmp    L25
L4:
  movzbl -0x18(%rbp),%eax
  mov    %al,-0x2(%rbp)
  jmp    L19
L24:
  movzbl -0x2(%rbp),%edx
  movzbl -0x1(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ezPlot@plt>
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L19:
  movzbl -0x2(%rbp),%eax
  movzbl -0x18(%rbp),%ecx
  movzbl -0x20(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jl     L24
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L25:
  movzbl -0x1(%rbp),%eax
  movzbl -0x14(%rbp),%ecx
  movzbl -0x1c(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void ezRect(unsigned char x, unsigned char y, unsigned char w, unsigned char h) {
  unsigned char i, j;
  for (j = x; j < x + w; j++) {
    for (i = y; i < y + h; i++) {
      ezPlot(j, i);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ezRect>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %sil,0xf(%rsp)
  movzbl %dil,%ebp
  movzbl %dl,%edx
  lea    (%rdx,%rbp,1),%r15d
  movzbl %sil,%r14d
  movzbl %cl,%ecx
  lea    (%rcx,%r14,1),%r12d
  cmp    %r15d,%ebp
  jl     L40
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    %ebp,%edi
  call   <ezPlot@plt>
  add    $0x1,%ebx
  movzbl %bl,%esi
  cmp    %r12d,%esi
  jl     L17
L9:
  add    $0x1,%r13d
  movzbl %r13b,%ebp
  cmp    %r15d,%ebp
  jge    L18
L40:
  mov    %r14d,%esi
  movzbl 0xf(%rsp),%ebx
  cmp    %r12d,%r14d
  jl     L17
  jmp    L9
```

assistant: ```c
void ezRect(unsigned char x, unsigned char y, unsigned char w, unsigned char h) {
  unsigned char i, j;
  for (j = x; j < x + w; j++) {
    for (i = y; i < y + h; i++) {
      ezPlot(j, i);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ezRect>:
  endbr64
  push   %r15
  movzbl %dl,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl %dil,%ebx
  lea    (%rdx,%rbx,1),%eax
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  cmp    %eax,%ebx
  jge    L3
  movzbl %sil,%r13d
  movzbl %cl,%ecx
  mov    %edi,%r12d
  mov    %esi,%r15d
  lea    (%rcx,%r13,1),%ebp
  nopl   (%rax)
L27:
  mov    %r15d,%r14d
  mov    %r13d,%esi
  cmp    %ebp,%r13d
  jge    L31
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%edi
  add    $0x1,%r14d
  call   <ezPlot@plt>
  movzbl %r14b,%esi
  cmp    %ebp,%esi
  jl     L28
L31:
  add    $0x1,%r12d
  movzbl %r12b,%ebx
  cmp    0xc(%rsp),%ebx
  jl     L27
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ezRect(unsigned char x, unsigned char y, unsigned char w, unsigned char h) {
  unsigned char i, j;
  for (j = x; j < x + w; j++) {
    for (i = y; i < y + h; i++) {
      ezPlot(j, i);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ezRect>:
  endbr64
  push   %r15
  movzbl %dl,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl %dil,%ebx
  lea    (%rdx,%rbx,1),%eax
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  cmp    %eax,%ebx
  jge    L36
  movzbl %sil,%r13d
  movzbl %cl,%ecx
  mov    %edi,%r12d
  mov    %esi,%r15d
  lea    (%rcx,%r13,1),%ebp
  cmp    %ebp,%r13d
  jge    L36
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r15d,%r14d
  mov    %r13d,%esi
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %ebx,%edi
  add    $0x1,%r14d
  call   <ezPlot@plt>
  movzbl %r14b,%esi
  cmp    %ebp,%esi
  jl     L16
  add    $0x1,%r12d
  movzbl %r12b,%ebx
  cmp    0xc(%rsp),%ebx
  jl     L29
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ezRect(unsigned char x, unsigned char y, unsigned char w, unsigned char h) {
  unsigned char i, j;
  for (j = x; j < x + w; j++) {
    for (i = y; i < y + h; i++) {
      ezPlot(j, i);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gera>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L24:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <tem_repeticao@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void gera(int *v, int n) {
  int i = 0;
  int numero;
  while (i < n) {
    numero = rand();
    if (!tem_repeticao(v, n, numero)) {
      v[i] = numero;
      ++i;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gera>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%r13d
L8:
  cmp    %r13d,%ebp
  jle    L20
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <tem_repeticao@plt>
  test   %eax,%eax
  jne    L8
  mov    %ebx,(%r12,%r13,4)
  add    $0x1,%r13
  jmp    L8
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gera(int *v, int n) {
  int i = 0;
  int numero;
  while (i < n) {
    numero = rand();
    if (!tem_repeticao(v, n, numero)) {
      v[i] = numero;
      ++i;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gera>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  mov    %eax,%ebx
  call   <tem_repeticao@plt>
  test   %eax,%eax
  je     L3
L12:
  cmp    %r13d,%ebp
  jg     L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %ebx,(%r12,%r13,4)
  add    $0x1,%r13
  jmp    L12
```

assistant: ```c
void gera(int *v, int n) {
  int i = 0;
  int numero;
  while (i < n) {
    numero = rand();
    if (!tem_repeticao(v, n, numero)) {
      v[i] = numero;
      ++i;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gera>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %r14
  lea    -0x1(%rsi),%eax
  push   %r13
  lea    0x4(%rdi,%rax,4),%r14
  mov    %rdi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
L10:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  mov    %eax,%ebx
  call   <tem_repeticao@plt>
  test   %eax,%eax
  jne    L10
  mov    %ebx,0x0(%r13)
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  ret
```

assistant: ```c
void gera(int *v, int n) {
  int i = 0;
  int numero;
  while (i < n) {
    numero = rand();
    if (!tem_repeticao(v, n, numero)) {
      v[i] = numero;
      ++i;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DatetoJD>:
  endbr64
  mov    (%rdi),%edx
  mov    0x4(%rdi),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x20(%rdi),%xmm1
  movsd  0x8(%rdi),%xmm0
  divsd  D2(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  divsd  D67(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm0
  divsd  D26(%rip),%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0x1,%eax
  jbe    L13
  add    $0x76c,%edx
  lea    0x1(%rax),%ecx
L30:
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x25,%rsi
  sar    $0x27,%rax
  sub    %esi,%eax
  lea    0x2(%rax),%esi
  cmp    $0x62e,%edx
  jg     L53
  cmp    $0x62d,%edx
  jle    L63
  cmp    $0x9,%ecx
  jle    L63
  cmp    $0xa,%ecx
  jne    L53
  movsd  D3(%rip),%xmm0
  ucomisd %xmm1,%xmm0
  mov    $0x0,%eax
  cmovae %eax,%esi
  jmp    L53
L13:
  add    $0x76b,%edx
  lea    0xd(%rax),%ecx
  jmp    L30
L63:
  mov    $0x0,%esi
L53:
  add    $0x126c,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D18(%rip),%xmm0
  cvttsd2si %xmm0,%rdx
  lea    0x1(%rcx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D30(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D31(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: f64
name: parse_data
arguments: data_tag: D67
type: f64
name: parse_data
arguments: data_tag: D26
type: f64
name: parse_data
arguments: data_tag: D3
type: byte[8]
name: parse_data
arguments: data_tag: D18
type: f64
name: parse_data
arguments: data_tag: D30
type: f64
name: parse_data
arguments: data_tag: D31
type: f64

tool: D2: 24

tool: D67: 1440

tool: D26: 86400

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x2e,0x40]}

tool: D18: 365.25

tool: D30: 30.6001

tool: D31: 1524.5

assistant: ```c
extern double DatetoJD(struct tm *event_date) {
  int y, m;
  double d;
  int a, b;
  double jd;
  y = event_date->tm_year + 1900;
  m = event_date->tm_mon + 1;
  d = (double)(event_date->tm_mday) + (event_date->tm_hour / 24.0) + (event_date->tm_min / 1440.0) + (event_date->tm_sec / 86400.0);
  if (m == 1 || m == 2) {
    y--;
    m += 12;
  }
  a = (int)(y / 100);
  b = 2 - a + (int)(a / 4);
  if (y < 1583)
    if ((y < 1582) || (m < 10) || ((m == 10) && (d <= 15)))
      b = 0;
  jd = (long)(365.25 * (y + 4716)) + (long)(30.6001 * (m + 1)) + d + b - 1524.5;
  return jd;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DatetoJD>:
  endbr64
  pxor   %xmm1,%xmm1
  movsd  0x8(%rdi),%xmm0
  divsd  D20(%rip),%xmm0
  mov    0x4(%rdi),%eax
  cvtsi2sdq 0x20(%rdi),%xmm1
  mov    (%rdi),%edx
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  divsd  D12(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm0
  divsd  D23(%rip),%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0x1,%eax
  jbe    L83
  add    $0x76c,%edx
  lea    0x1(%rax),%ecx
L89:
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %esi,%eax
  add    $0x2,%eax
  cmp    $0x62e,%edx
  jg     L63
  cmp    $0x62d,%edx
  jle    L5
  cmp    $0x9,%ecx
  jle    L5
  cmp    $0xa,%ecx
  je     L70
L63:
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
L27:
  add    $0x126c,%edx
  pxor   %xmm0,%xmm0
  lea    0x1(%rcx),%eax
  cvtsi2sd %edx,%xmm0
  mulsd  D28(%rip),%xmm0
  pxor   %xmm2,%xmm2
  cvttsd2si %xmm0,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D65(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    %rdx,%rax
  cvtsi2sd %rax,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  subsd  D14(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm3,%xmm3
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L83:
  add    $0x76b,%edx
  lea    0xd(%rax),%ecx
  jmp    L89
  xchg   %ax,%ax
L70:
  movsd  D51(%rip),%xmm0
  pxor   %xmm3,%xmm3
  comisd %xmm1,%xmm0
  jae    L27
  jmp    L63
```

tool_calls: name: parse_data
arguments: data_label: D20
datatype: f64
name: parse_data
arguments: data_label: D12
datatype: f64
name: parse_data
arguments: data_label: D23
datatype: f64
name: parse_data
arguments: data_label: D28
datatype: f64
name: parse_data
arguments: data_label: D65
datatype: f64
name: parse_data
arguments: data_label: D14
datatype: f64
name: parse_data
arguments: data_label: D51
datatype: byte[8]

tool: D20: 24

tool: D12: 1440

tool: D23: 86400

tool: D28: 365.25

tool: D65: 30.6001

tool: D14: 1524.5

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x2e,0x40]}

assistant: ```c
extern double DatetoJD(struct tm *event_date) {
  int y, m;
  double d;
  int a, b;
  double jd;
  y = event_date->tm_year + 1900;
  m = event_date->tm_mon + 1;
  d = (double)(event_date->tm_mday) + (event_date->tm_hour / 24.0) + (event_date->tm_min / 1440.0) + (event_date->tm_sec / 86400.0);
  if (m == 1 || m == 2) {
    y--;
    m += 12;
  }
  a = (int)(y / 100);
  b = 2 - a + (int)(a / 4);
  if (y < 1583)
    if ((y < 1582) || (m < 10) || ((m == 10) && (d <= 15)))
      b = 0;
  jd = (long)(365.25 * (y + 4716)) + (long)(30.6001 * (m + 1)) + d + b - 1524.5;
  return jd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<DatetoJD>:
  endbr64
  pxor   %xmm1,%xmm1
  movsd  0x8(%rdi),%xmm0
  divsd  D22(%rip),%xmm0
  mov    0x4(%rdi),%eax
  cvtsi2sdq 0x20(%rdi),%xmm1
  mov    (%rdi),%edx
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  divsd  D23(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm0
  divsd  D50(%rip),%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0x1,%eax
  jbe    L25
  add    $0x76c,%edx
  lea    0x1(%rax),%ecx
L21:
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %esi,%eax
  add    $0x2,%eax
  cmp    $0x62e,%edx
  jg     L86
  cmp    $0x62d,%edx
  jle    L36
  cmp    $0x9,%ecx
  jle    L36
  cmp    $0xa,%ecx
  je     L0
L86:
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
L68:
  add    $0x126c,%edx
  pxor   %xmm0,%xmm0
  lea    0x1(%rcx),%eax
  cvtsi2sd %edx,%xmm0
  mulsd  D1(%rip),%xmm0
  pxor   %xmm2,%xmm2
  cvttsd2si %xmm0,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D39(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    %rdx,%rax
  cvtsi2sd %rax,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  subsd  D66(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L36:
  pxor   %xmm3,%xmm3
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L25:
  add    $0x76b,%edx
  lea    0xd(%rax),%ecx
  jmp    L21
  xchg   %ax,%ax
L0:
  movsd  D9(%rip),%xmm0
  pxor   %xmm3,%xmm3
  comisd %xmm1,%xmm0
  jae    L68
  jmp    L86
```

tool_calls: name: unpack_data
arguments: data_label: D22
type_infered: f64
name: unpack_data
arguments: data_label: D23
type_infered: f64
name: unpack_data
arguments: data_label: D50
type_infered: f64
name: unpack_data
arguments: data_label: D1
type_infered: f64
name: unpack_data
arguments: data_label: D39
type_infered: f64
name: unpack_data
arguments: data_label: D66
type_infered: f64
name: unpack_data
arguments: data_label: D9
type_infered: byte[8]

tool: D22: 24

tool: D23: 1440

tool: D50: 86400

tool: D1: 365.25

tool: D39: 30.6001

tool: D66: 1524.5

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x2e,0x40]}

assistant: ```c
extern double DatetoJD(struct tm *event_date) {
  int y, m;
  double d;
  int a, b;
  double jd;
  y = event_date->tm_year + 1900;
  m = event_date->tm_mon + 1;
  d = (double)(event_date->tm_mday) + (event_date->tm_hour / 24.0) + (event_date->tm_min / 1440.0) + (event_date->tm_sec / 86400.0);
  if (m == 1 || m == 2) {
    y--;
    m += 12;
  }
  a = (int)(y / 100);
  b = 2 - a + (int)(a / 4);
  if (y < 1583)
    if ((y < 1582) || (m < 10) || ((m == 10) && (d <= 15)))
      b = 0;
  jd = (long)(365.25 * (y + 4716)) + (long)(30.6001 * (m + 1)) + d + b - 1524.5;
  return jd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<XOR_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    -0x8(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L0
  mov    $0x45,%edi
  call   <addbyte@plt>
  mov    $0x31,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  or     $0xc0,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  and    $0x38,%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  jmp    L15
L0:
  mov    -0x4(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L28
  mov    $0x41,%edi
  call   <addbyte@plt>
  mov    $0x31,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  or     $0xc0,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  and    $0x38,%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  jmp    L15
L28:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L15:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: !(dst_reg & src_reg & 8)


assistant: ```c
void XOR_HOST_REG_L(int dst_reg, int src_reg) {
  if (dst_reg & src_reg & 8) {
    addbyte(0x45);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else if (dst_reg & 8) {
    addbyte(0x41);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else
    fatal("!(dst_reg & src_reg & 8)\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<XOR_HOST_REG_L>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edi,%eax
  and    %esi,%eax
  test   $0x8,%al
  jne    L35
  test   $0x8,%dil
  je     L14
  mov    $0x41,%edi
  call   <addbyte@plt>
  mov    $0x31,%edi
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  and    $0x38,%edi
  and    $0x7,%ebp
  or     %ebp,%edi
  or     $0xc0,%dil
  call   <addbyte@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0x45,%edi
  call   <addbyte@plt>
  mov    $0x31,%edi
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  and    $0x38,%edi
  and    $0x7,%ebp
  or     %ebp,%edi
  or     $0xc0,%dil
  call   <addbyte@plt>
  jmp    L11
L14:
  lea    D0(%rip),%rdi
  call   <fatal@plt>
  jmp    L11
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: !(dst_reg & src_reg & 8)


assistant: ```c
void XOR_HOST_REG_L(int dst_reg, int src_reg) {
  if (dst_reg & src_reg & 8) {
    addbyte(0x45);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else if (dst_reg & 8) {
    addbyte(0x41);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else
    fatal("!(dst_reg & src_reg & 8)\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XOR_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %edi,%ebp
  mov    $0x45,%edi
  push   %rbx
  and    %esi,%eax
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   $0x8,%al
  jne    L13
  test   $0x8,%bpl
  je     L5
  mov    $0x41,%edi
L13:
  call   <addbyte@plt>
  mov    $0x31,%edi
  and    $0x7,%ebp
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  and    $0x38,%edi
  pop    %rbx
  or     %ebp,%edi
  pop    %rbp
  or     $0xc0,%dil
  jmp    1060 <addbyte@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <fatal@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: !(dst_reg & src_reg & 8)


assistant: ```c
void XOR_HOST_REG_L(int dst_reg, int src_reg) {
  if (dst_reg & src_reg & 8) {
    addbyte(0x45);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else if (dst_reg & 8) {
    addbyte(0x41);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else
    fatal("!(dst_reg & src_reg & 8)\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<XOR_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %edi,%ebp
  mov    $0x45,%edi
  push   %rbx
  and    %esi,%eax
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   $0x8,%al
  jne    L14
  test   $0x8,%bpl
  je     L18
  mov    $0x41,%edi
L14:
  call   <addbyte@plt>
  mov    $0x31,%edi
  and    $0x7,%ebp
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  and    $0x38,%edi
  pop    %rbx
  or     %ebp,%edi
  pop    %rbp
  or     $0xc0,%dil
  jmp    1060 <addbyte@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <fatal@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: !(dst_reg & src_reg & 8)


assistant: ```c
void XOR_HOST_REG_L(int dst_reg, int src_reg) {
  if (dst_reg & src_reg & 8) {
    addbyte(0x45);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else if (dst_reg & 8) {
    addbyte(0x41);
    addbyte(0x31);
    addbyte(0xc0 | (dst_reg & 7) | ((src_reg & 7) << 3));
  } else
    fatal("!(dst_reg & src_reg & 8)\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  shl    $0x7,%eax
  and    $0xb500,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L38
L31:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jae    L26
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl -0xc(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
L26:
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L38:
  cmpw   $0x0,-0xc(%rbp)
  je     L31
  movzwl -0xa(%rbp),%eax
  shl    $0x3,%eax
  and    $0x4248,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 690137161UL) << (unsigned short)3;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  and    $0xb500,%ax
  mov    %eax,%edx
  je     L8
  movsbl %ah,%eax
  mov    %dl,%dh
  mov    %al,%dl
L8:
  shl    $0x3,%edx
  and    $0x4248,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 690137161UL) << (unsigned short)3;
  }
}
```