ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ltrim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L5
L10:
  add    $0x1,%rbx
L5:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  cmp    %rbp,%rbx
  je     L17
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L17:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p;
  for (p = s; isspace((u_char)*p); p++)
    ;
  if (p != s)
    strcpy(s, p);
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rbp
L22:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  cmp    %r12,%rbp
  je     L28
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p;
  for (p = s; isspace((u_char)*p); p++)
    ;
  if (p != s)
    strcpy(s, p);
  return (s);
}
```
user: What is the c source code of the assembly code below?

```asm
<ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rbp
L2:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  cmp    %r12,%rbp
  je     L13
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p;
  for (p = s; isspace((u_char)*p); p++)
    ;
  if (p != s)
    strcpy(s, p);
  return (s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func_sigint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: INFO: Catching SIGINT


assistant: ```c
void func_sigint(int signo) {
  printf("INFO: Catching SIGINT\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func_sigint>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: INFO: Catching SIGINT


assistant: ```c
void func_sigint(int signo) {
  printf("INFO: Catching SIGINT\n");
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func_sigint>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: INFO: Catching SIGINT


assistant: ```c
void func_sigint(int signo) {
  printf("INFO: Catching SIGINT\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<func_sigint>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D4: INFO: Catching SIGINT


assistant: ```c
void func_sigint(int signo) {
  printf("INFO: Catching SIGINT\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x5,%edi
  call   <alarm@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <alarm@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: the time left %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  ret = alarm(5);
  printf("the time left %d\n", ret);
  sleep(2);
  ret = alarm(1);
  printf("the time left %d\n", ret);
  while (1)
    ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5,%edi
  call   <alarm@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <alarm@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L7:
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: the time left %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  ret = alarm(5);
  printf("the time left %d\n", ret);
  sleep(2);
  ret = alarm(1);
  printf("the time left %d\n", ret);
  while (1)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%edi
  lea    D4(%rip),%rbp
  call   <alarm@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <alarm@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L3:
  jmp    L3
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: the time left %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  ret = alarm(5);
  printf("the time left %d\n", ret);
  sleep(2);
  ret = alarm(1);
  printf("the time left %d\n", ret);
  while (1)
    ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%edi
  lea    D0(%rip),%rbp
  call   <alarm@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <alarm@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L6:
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: the time left %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  ret = alarm(5);
  printf("the time left %d\n", ret);
  sleep(2);
  ret = alarm(1);
  printf("the time left %d\n", ret);
  while (1)
    ;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_substring_from_rhs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L90
L27:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L102
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L72:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L61
  movl   $0x1,-0x8(%rbp)
  jmp    L102
L61:
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
L102:
  cmpl   $0x0,-0x8(%rbp)
  jne    L7
  movl   $0x1,-0x4(%rbp)
  jmp    L107
L7:
  subl   $0x1,-0x14(%rbp)
L90:
  cmpl   $0x0,-0x14(%rbp)
  jns    L27
L107:
  cmpl   $0x1,-0x4(%rbp)
  jne    L8
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L23
L8:
  mov    $0xffffffff,%eax
L23:
  leave
  ret
```

assistant: ```c
int find_substring_from_rhs(char *str, char *sub) {
  int i, j, I, notfound = 1, found = 0;
  for (i = strlen(str) - 1; i >= 0; i--) {
    if (sub[0] == str[i]) {
      notfound = 0;
      I = i;
      for (j = 0; sub[j] != '\0'; j++, I--) {
        if (str[I] != sub[j]) {
          notfound = 1;
          break;
        }
      }
    }
    if (notfound == 0) {
      found = 1;
      break;
    }
  }
  if (found == 1)
    return (I + 1);
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_substring_from_rhs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L64
  movzbl 0x0(%rbp),%r8d
  movslq %eax,%rcx
  jmp    L26
L77:
  sub    $0x1,%rcx
  test   %ecx,%ecx
  js     L42
L26:
  mov    %ecx,%edx
  mov    %ecx,%eax
  cmp    (%rbx,%rcx,1),%r8b
  jne    L77
  test   %r8b,%r8b
  je     L89
  sub    $0x1,%edx
  movslq %edx,%rdx
  lea    0x1(%rbp),%rsi
L93:
  mov    %edx,%eax
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L89
  movzbl (%rbx,%rdx,1),%eax
  sub    $0x1,%rdx
  add    $0x1,%rsi
  cmp    %dil,%al
  je     L93
  jmp    L77
L42:
  mov    $0xffffffff,%eax
  jmp    L84
L64:
  mov    $0xffffffff,%eax
  jmp    L84
L89:
  add    $0x1,%eax
L84:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int find_substring_from_rhs(char *str, char *sub) {
  int i, j, I, notfound = 1, found = 0;
  for (i = strlen(str) - 1; i >= 0; i--) {
    if (sub[0] == str[i]) {
      notfound = 0;
      I = i;
      for (j = 0; sub[j] != '\0'; j++, I--) {
        if (str[I] != sub[j]) {
          notfound = 1;
          break;
        }
      }
    }
    if (notfound == 0) {
      found = 1;
      break;
    }
  }
  if (found == 1)
    return (I + 1);
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_substring_from_rhs>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L20
  movzbl 0x0(%rbp),%r10d
  cltq
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L46:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L20
L7:
  mov    %eax,%r9d
  cmp    (%rbx,%rax,1),%r10b
  jne    L46
  test   %r10b,%r10b
  je     L19
  lea    0x1(%rbp),%rcx
  mov    %rax,%rdx
  jmp    L80
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl -0x1(%rbx,%rdx,1),%edi
  add    $0x1,%rcx
  sub    $0x1,%rdx
  cmp    %r8b,%dil
  jne    L46
L80:
  movzbl (%rcx),%r8d
  mov    %edx,%r9d
  test   %r8b,%r8b
  jne    L38
L26:
  add    $0x8,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x8,%rsp
  mov    $0xffffffff,%r9d
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  add    $0x1,%r9d
  jmp    L26
```

assistant: ```c
int find_substring_from_rhs(char *str, char *sub) {
  int i, j, I, notfound = 1, found = 0;
  for (i = strlen(str) - 1; i >= 0; i--) {
    if (sub[0] == str[i]) {
      notfound = 0;
      I = i;
      for (j = 0; sub[j] != '\0'; j++, I--) {
        if (str[I] != sub[j]) {
          notfound = 1;
          break;
        }
      }
    }
    if (notfound == 0) {
      found = 1;
      break;
    }
  }
  if (found == 1)
    return (I + 1);
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_substring_from_rhs>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L11
  movzbl 0x0(%rbp),%r10d
  cltq
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L33:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L11
L31:
  mov    %eax,%r9d
  cmp    (%rbx,%rax,1),%r10b
  jne    L33
  test   %r10b,%r10b
  je     L68
  lea    0x1(%rbp),%rcx
  mov    %rax,%rdx
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L22:
  movzbl -0x1(%rbx,%rdx,1),%edi
  add    $0x1,%rcx
  sub    $0x1,%rdx
  cmp    %r8b,%dil
  jne    L33
L71:
  movzbl (%rcx),%r8d
  mov    %edx,%r9d
  test   %r8b,%r8b
  jne    L22
L4:
  add    $0x8,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  mov    $0xffffffff,%r9d
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  ret
L68:
  add    $0x1,%r9d
  jmp    L4
```

assistant: ```c
int find_substring_from_rhs(char *str, char *sub) {
  int i, j, I, notfound = 1, found = 0;
  for (i = strlen(str) - 1; i >= 0; i--) {
    if (sub[0] == str[i]) {
      notfound = 0;
      I = i;
      for (j = 0; sub[j] != '\0'; j++, I--) {
        if (str[I] != sub[j]) {
          notfound = 1;
          break;
        }
      }
    }
    if (notfound == 0) {
      found = 1;
      break;
    }
  }
  if (found == 1)
    return (I + 1);
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Com_SkipCharset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <Com_CharIsOneOfCharset@plt>
  test   %rax,%rax
  je     L28
  addq   $0x1,-0x8(%rbp)
L18:
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  jmp    L35
L28:
  nop
L35:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *Com_SkipCharset(char *s, char *sep) {
  char *p = s;
  while (p) {
    if (Com_CharIsOneOfCharset(*p, sep)) {
      p++;
    } else {
      break;
    }
  }
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<Com_SkipCharset>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  jne    L18
  mov    %rdi,%rax
  jmp    L9
L11:
  add    $0x1,%rbx
L18:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <Com_CharIsOneOfCharset@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbx,%rax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *Com_SkipCharset(char *s, char *sep) {
  char *p = s;
  while (p) {
    if (Com_CharIsOneOfCharset(*p, sep)) {
      p++;
    } else {
      break;
    }
  }
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Com_SkipCharset>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
L13:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <Com_CharIsOneOfCharset@plt>
  test   %rax,%rax
  jne    L12
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *Com_SkipCharset(char *s, char *sep) {
  char *p = s;
  while (p) {
    if (Com_CharIsOneOfCharset(*p, sep)) {
      p++;
    } else {
      break;
    }
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Com_SkipCharset>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
L1:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <Com_CharIsOneOfCharset@plt>
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *Com_SkipCharset(char *s, char *sep) {
  char *p = s;
  while (p) {
    if (Com_CharIsOneOfCharset(*p, sep)) {
      p++;
    } else {
      break;
    }
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<multiply217>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L34
L28:
  movl   $0x0,-0x3c(%rbp)
  jmp    L10
L35:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L10:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L35
  addl   $0x1,-0x40(%rbp)
L34:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L28
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply217(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply217>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L4:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L9:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L9
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

assistant: ```c
void multiply217(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply217>:
  endbr64
  test   %edi,%edi
  jle    L19
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L7
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L27
  pop    %rbx
  ret
L19:
  ret
```

assistant: ```c
void multiply217(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<multiply217>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L59
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L12:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L89
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L89
  nopl   0x0(%rax)
L71:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L71
  cmp    -0x24(%rsp),%r11d
  je     L38
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L38
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L38
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L38:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L12
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L89:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L88:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L88
  mov    -0x18(%rsp),%r8
  jmp    L38
```

assistant: ```c
void multiply217(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_UInt8Number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0xff,-0x4(%rbp)
  jbe    L6
  mov    $0x1,%eax
  jmp    L14
L6:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int write_UInt8Number(unsigned int d, char *p) {
  if (d > 255)
    return 1;
  ((unsigned char *)p)[0] = (unsigned char)d;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_UInt8Number>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xff,%edi
  ja     L8
  mov    %dil,(%rsi)
  mov    $0x0,%eax
L8:
  ret
```

assistant: ```c
int write_UInt8Number(unsigned int d, char *p) {
  if (d > 255)
    return 1;
  ((unsigned char *)p)[0] = (unsigned char)d;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_UInt8Number>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xff,%edi
  ja     L1
  mov    %dil,(%rsi)
  xor    %eax,%eax
L1:
  ret
```

assistant: ```c
int write_UInt8Number(unsigned int d, char *p) {
  if (d > 255)
    return 1;
  ((unsigned char *)p)[0] = (unsigned char)d;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_UInt8Number>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xff,%edi
  ja     L3
  mov    %dil,(%rsi)
  xor    %eax,%eax
L3:
  ret
```

assistant: ```c
int write_UInt8Number(unsigned int d, char *p) {
  if (d > 255)
    return 1;
  ((unsigned char *)p)[0] = (unsigned char)d;
  return 0;
}
```