ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__NONDET__@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a[32];
  int x = __NONDET__();
  a[x % 32] = 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__NONDET__@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a[32];
  int x = __NONDET__();
  a[x % 32] = 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L36
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L21
L36:
  mov    $0x1,%eax
  jmp    L31
L21:
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
int match(char *line, char *name) {
  int len;
  len = strlen(name);
  return (strncmp(line, name, len) == 0 && (line[len] == ' ' || line[len] == '\t'));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<match>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L8
  movslq %ebx,%rbx
  movzbl (%r12,%rbx,1),%edx
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int match(char *line, char *name) {
  int len;
  len = strlen(name);
  return (strncmp(line, name, len) == 0 && (line[len] == ' ' || line[len] == '\t'));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<match>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <strncmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L3
  movzbl (%r12,%rbx,1),%edx
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int match(char *line, char *name) {
  int len;
  len = strlen(name);
  return (strncmp(line, name, len) == 0 && (line[len] == ' ' || line[len] == '\t'));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<match>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <strncmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L1
  movzbl (%r12,%rbx,1),%edx
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int match(char *line, char *name) {
  int len;
  len = strlen(name);
  return (strncmp(line, name, len) == 0 && (line[len] == ' ' || line[len] == '\t'));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_isspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  je     L27
  cmpb   $0xa,-0x4(%rbp)
  je     L27
  cmpb   $0x9,-0x4(%rbp)
  jne    L22
L27:
  mov    $0x1,%eax
  jmp    L1
L22:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\n' || c == '\t')
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_isspace>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x20,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\n' || c == '\t')
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_isspace>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x20,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\n' || c == '\t')
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_isspace>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x20,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\n' || c == '\t')
    return (1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Info_RemoveKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
L111:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L85
  addq   $0x1,-0x28(%rbp)
L85:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L10:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  mov    $0x0,%eax
  jmp    L42
L53:
  addq   $0x1,-0x28(%rbp)
L6:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L10
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L56
L119:
  addq   $0x1,-0x28(%rbp)
L56:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L50
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L119
L50:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L114
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Q_strkey@plt>
  test   %rax,%rax
  je     L114
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  jmp    L42
L114:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  jmp    L111
L22:
  nop
  mov    $0x0,%eax
L42:
  leave
  ret
```

assistant: ```c
int Info_RemoveKey(char *s, const char *key) {
  char *start;
  char *pkey;
  int key_len, len;
  key_len = (int)strlen(key);
  while (1) {
    start = s;
    if (*s == '\\')
      s++;
    pkey = s;
    while (*s != '\\') {
      if (*s == '\0')
        return 0;
      ++s;
    }
    len = (int)(s - pkey);
    ++s;
    while (*s != '\\' && *s != '\0')
      ++s;
    if (len == key_len && Q_strkey(pkey, key, key_len)) {
      memmove(start, s, strlen(s) + 1);
      return (int)(s - start);
    }
    if (*s == '\0')
      break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Info_RemoveKey>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
L58:
  movzbl 0x0(%rbp),%eax
  mov    %rbp,%rdi
  cmp    $0x5c,%al
  je     L149
L24:
  mov    %rdi,%rdx
L88:
  test   %al,%al
  je     L145
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  cmp    $0x5c,%al
  jne    L88
L128:
  mov    %rdx,%rcx
  sub    %rdi,%rcx
  lea    0x1(%rdx),%rbx
  movzbl 0x1(%rdx),%eax
  cmp    $0x5c,%al
  je     L14
  test   %al,%al
  je     L14
L97:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  je     L14
  test   %al,%al
  jne    L97
L14:
  cmp    %ecx,%r12d
  je     L93
L100:
  cmpb   $0x0,(%rbx)
  je     L92
  mov    %rbx,%rbp
  jmp    L58
L149:
  lea    0x1(%rbp),%rdi
  movzbl 0x1(%rbp),%eax
  cmp    $0x5c,%al
  jne    L24
  mov    %rdi,%rdx
  jmp    L128
L93:
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <Q_strkey@plt>
  test   %rax,%rax
  je     L100
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  mov    %ebx,%eax
  sub    %ebp,%eax
  jmp    L123
L92:
  mov    $0x0,%eax
  jmp    L123
L145:
  mov    $0x0,%eax
L123:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int Info_RemoveKey(char *s, const char *key) {
  char *start;
  char *pkey;
  int key_len, len;
  key_len = (int)strlen(key);
  while (1) {
    start = s;
    if (*s == '\\')
      s++;
    pkey = s;
    while (*s != '\\') {
      if (*s == '\0')
        return 0;
      ++s;
    }
    len = (int)(s - pkey);
    ++s;
    while (*s != '\\' && *s != '\0')
      ++s;
    if (len == key_len && Q_strkey(pkey, key, key_len)) {
      memmove(start, s, strlen(s) + 1);
      return (int)(s - start);
    }
    if (*s == '\0')
      break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Info_RemoveKey>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  movzbl 0x0(%rbp),%eax
  cmp    $0x5c,%al
  je     L48
L68:
  mov    %rdi,%rdx
  jmp    L64
  nop
L1:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    $0x5c,%al
  je     L106
L64:
  test   %al,%al
  jne    L1
L119:
  xor    %eax,%eax
L149:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L106:
  mov    %edx,%ecx
  sub    %edi,%ecx
L109:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%rbx
  cmp    $0x5c,%al
  jne    L75
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L100:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x5c,%al
  je     L83
L75:
  test   %al,%al
  jne    L100
L83:
  cmp    %ecx,%r12d
  je     L113
L12:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L119
  mov    %rbx,%rbp
  mov    %rbp,%rdi
  cmp    $0x5c,%al
  jne    L68
L48:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rdi
  cmp    $0x5c,%al
  jne    L68
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  jmp    L109
  nopl   0x0(%rax)
L113:
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <Q_strkey@plt>
  test   %rax,%rax
  je     L12
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %ebx,%eax
  sub    %ebp,%eax
  jmp    L149
```

assistant: ```c
int Info_RemoveKey(char *s, const char *key) {
  char *start;
  char *pkey;
  int key_len, len;
  key_len = (int)strlen(key);
  while (1) {
    start = s;
    if (*s == '\\')
      s++;
    pkey = s;
    while (*s != '\\') {
      if (*s == '\0')
        return 0;
      ++s;
    }
    len = (int)(s - pkey);
    ++s;
    while (*s != '\\' && *s != '\0')
      ++s;
    if (len == key_len && Q_strkey(pkey, key, key_len)) {
      memmove(start, s, strlen(s) + 1);
      return (int)(s - start);
    }
    if (*s == '\0')
      break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Info_RemoveKey>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  movzbl 0x0(%rbp),%eax
  cmp    $0x5c,%al
  je     L106
L24:
  mov    %rdi,%rdx
  jmp    L8
  nop
L89:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    $0x5c,%al
  je     L77
L8:
  test   %al,%al
  jne    L89
L62:
  xor    %eax,%eax
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L77:
  mov    %edx,%ecx
  sub    %edi,%ecx
L33:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%rbx
  cmp    $0x5c,%al
  jne    L28
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x5c,%al
  je     L125
L28:
  test   %al,%al
  jne    L18
L125:
  cmp    %ecx,%r12d
  je     L116
L159:
  test   %al,%al
  je     L62
  mov    %rbx,%rbp
  mov    %rbp,%rdi
  cmp    $0x5c,%al
  jne    L24
L106:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rdi
  cmp    $0x5c,%al
  jne    L24
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  jmp    L33
  xchg   %ax,%ax
L116:
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <Q_strkey@plt>
  test   %rax,%rax
  jne    L81
  movzbl (%rbx),%eax
  jmp    L159
L81:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %ebx,%eax
  sub    %ebp,%eax
  jmp    L38
```

assistant: ```c
int Info_RemoveKey(char *s, const char *key) {
  char *start;
  char *pkey;
  int key_len, len;
  key_len = (int)strlen(key);
  while (1) {
    start = s;
    if (*s == '\\')
      s++;
    pkey = s;
    while (*s != '\\') {
      if (*s == '\0')
        return 0;
      ++s;
    }
    len = (int)(s - pkey);
    ++s;
    while (*s != '\\' && *s != '\0')
      ++s;
    if (len == key_len && Q_strkey(pkey, key, key_len)) {
      memmove(start, s, strlen(s) + 1);
      return (int)(s - start);
    }
    if (*s == '\0')
      break;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L148
L66:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  cmp    $0x1,%eax
  jle    L60
  mov    %eax,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x8(%rax),%rax
  lea    -0x2(%rbp),%edx
  lea    0xc(%rbx,%rdx,4),%rdx
L0:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L0
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L87
L29:
  mov    $0x4,%ecx
  mov    $0x2,%eax
  jmp    L104
L148:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L66
L60:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    %ebp,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jg     L29
  mov    $0x0,%esi
  jmp    L134
L62:
  add    $0x1,%rax
  add    $0x2,%ecx
  cmp    %eax,%esi
  jl     L73
L104:
  cmpl   $0x1,(%rbx,%rax,4)
  jne    L62
  cmp    %ecx,%ebp
  jl     L62
  movslq %ecx,%rdx
L98:
  movl   $0x0,(%rbx,%rdx,4)
  add    %rax,%rdx
  cmp    %edx,%ebp
  jge    L98
  jmp    L62
L73:
  cmp    $0x1,%ebp
  jle    L149
L87:
  mov    $0x2,%eax
  mov    $0x0,%esi
  jmp    L115
L21:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jl     L134
L115:
  cmpl   $0x1,(%rbx,%rax,4)
  jne    L21
  add    $0x1,%esi
  jmp    L21
L149:
  mov    $0x0,%esi
L134:
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D43
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D11
data_type: string

tool: D43: Finding primes in range 1..%d


tool: D1: Usage: ./prime <N>

tool: D8: N must be greater than 1

tool: D11: Total %d primes found


assistant: ```c
int main(int argc, char **argv) {
  int N;
  if (argc < 2) {
    printf("Usage: ./prime <N>\n");
    exit(0);
  }
  if ((N = atoi(argv[1])) < 2) {
    printf("N must be greater than 1\n");
    exit(0);
  }
  printf("Finding primes in range 1..%d\n", N);
  int *array = (int *)malloc(sizeof(int) * (N + 1));
  for (int i = 2; i <= N; i++)
    array[i] = 1;
  int limit = (int)sqrt((double)N);
  for (int i = 2; i <= limit; i++) {
    if (array[i] == 1) {
      for (int j = i + i; j <= N; j += i)
        array[j] = 0;
    }
  }
  int cnt = 0;
  for (int i = 2; i <= N; i++) {
    if (array[i] == 1)
      cnt++;
  }
  printf("Total %d primes found\n", cnt);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L15
L61:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  cmp    $0x1,%eax
  jle    L41
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(,%rbp,4),%edi
  call   <malloc@plt>
  lea    -0x2(%rbp),%edx
  mov    %rax,%rbx
  lea    0x8(%rax),%rax
  lea    0xc(%rbx,%rdx,4),%rdx
  nopl   (%rax)
L21:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L21
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L3
L97:
  mov    $0x4,%ecx
  mov    $0x2,%eax
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  add    $0x2,%ecx
  cmp    %eax,%esi
  jl     L113
L83:
  cmpl   $0x1,(%rbx,%rax,4)
  jne    L8
  cmp    %ecx,%ebp
  jl     L8
  movslq %ecx,%rdx
  nopl   0x0(%rax,%rax,1)
L60:
  movl   $0x0,(%rbx,%rdx,4)
  add    %rax,%rdx
  cmp    %edx,%ebp
  jge    L60
  add    $0x1,%rax
  add    $0x2,%ecx
  cmp    %eax,%esi
  jge    L83
  nopl   0x0(%rax)
L113:
  cmp    $0x1,%ebp
  jle    L145
L3:
  mov    $0x2,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L153:
  cmpl   $0x1,(%rbx,%rax,4)
  jne    L76
  add    $0x1,%esi
L76:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L153
L47:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L41:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(,%rbp,4),%edi
  call   <malloc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mov    %rax,%rbx
  call   <sqrt@plt>
  mov    %eax,%esi
  sub    $0x1,%eax
  jg     L97
L145:
  xor    %esi,%esi
  jmp    L47
L15:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L61
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D20
type: string
name: extract_symbolic_data
arguments: data_tag: D36
type: string

tool: D8: Finding primes in range 1..%d


tool: D4: Total %d primes found


tool: D20: N must be greater than 1

tool: D36: Usage: ./prime <N>

assistant: ```c
int main(int argc, char **argv) {
  int N;
  if (argc < 2) {
    printf("Usage: ./prime <N>\n");
    exit(0);
  }
  if ((N = atoi(argv[1])) < 2) {
    printf("N must be greater than 1\n");
    exit(0);
  }
  printf("Finding primes in range 1..%d\n", N);
  int *array = (int *)malloc(sizeof(int) * (N + 1));
  for (int i = 2; i <= N; i++)
    array[i] = 1;
  int limit = (int)sqrt((double)N);
  for (int i = 2; i <= limit; i++) {
    if (array[i] == 1) {
      for (int j = i + i; j <= N; j += i)
        array[j] = 0;
    }
  }
  int cnt = 0;
  for (int i = 2; i <= N; i++) {
    if (array[i] == 1)
      cnt++;
  }
  printf("Total %d primes found\n", cnt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<more_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x41,-0xaa(%rbp)
  movb   $0x15,-0xa9(%rbp)
  movw   $0xfff2,-0xa8(%rbp)
  movw   $0x7,-0xa6(%rbp)
  movl   $0x66,-0xa4(%rbp)
  movl   $0x3ea,-0xa0(%rbp)
  movq   $0xffffffffffffff16,-0x70(%rbp)
  movq   $0xea,-0x68(%rbp)
  movss  D10(%rip),%xmm0
  movss  %xmm0,-0x9c(%rbp)
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  lea    -0xaa(%rbp),%rax
  mov    %rax,-0x98(%rbp)
  lea    -0x98(%rbp),%rax
  mov    %rax,-0x90(%rbp)
  lea    -0x90(%rbp),%rax
  mov    %rax,-0x88(%rbp)
  lea    -0x88(%rbp),%rax
  mov    %rax,-0x80(%rbp)
  lea    -0x80(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  lea    -0x78(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  lea    -0xa9(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  lea    -0xa8(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  lea    -0xa6(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    -0xa4(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  lea    -0xa0(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x68(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x9c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <marker1@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: f32
name: extract_symbolic_data
arguments: label: D14
type: byte[8]

tool: D10: 12500000000

tool: {"D14": [0x72,0x2e,0x2d,0x93,0x84,0x44,0x45,0xb8]}

assistant: ```c
int more_code() {
  char C, *pC, **ppC, ***pppC, ****ppppC, *****pppppC, ******ppppppC;
  unsigned char UC, *pUC;
  short S, *pS;
  unsigned short US, *pUS;
  int I, *pI;
  unsigned int UI, *pUI;
  long L, *pL;
  unsigned long UL, *pUL;
  float F, *pF;
  double D, *pD;
  C = 'A';
  UC = 21;
  S = -14;
  US = 7;
  I = 102;
  UI = 1002;
  L = -234;
  UL = 234;
  F = 1.25E10;
  D = -1.25E-37;
  pC = &C;
  ppC = &pC;
  pppC = &ppC;
  ppppC = &pppC;
  pppppC = &ppppC;
  ppppppC = &pppppC;
  pUC = &UC;
  pS = &S;
  pUS = &US;
  pI = &I;
  pUI = &UI;
  pL = &L;
  pUL = &UL;
  pF = &F;
  pD = &D;
  marker1();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<more_code>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <marker1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int more_code() {
  char C, *pC, **ppC, ***pppC, ****ppppC, *****pppppC, ******ppppppC;
  unsigned char UC, *pUC;
  short S, *pS;
  unsigned short US, *pUS;
  int I, *pI;
  unsigned int UI, *pUI;
  long L, *pL;
  unsigned long UL, *pUL;
  float F, *pF;
  double D, *pD;
  C = 'A';
  UC = 21;
  S = -14;
  US = 7;
  I = 102;
  UI = 1002;
  L = -234;
  UL = 234;
  F = 1.25E10;
  D = -1.25E-37;
  pC = &C;
  ppC = &pC;
  pppC = &ppC;
  ppppC = &pppC;
  pppppC = &ppppC;
  ppppppC = &pppppC;
  pUC = &UC;
  pS = &S;
  pUS = &US;
  pI = &I;
  pUI = &UI;
  pL = &L;
  pUL = &UL;
  pF = &F;
  pD = &D;
  marker1();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<more_code>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <marker1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int more_code() {
  char C, *pC, **ppC, ***pppC, ****ppppC, *****pppppC, ******ppppppC;
  unsigned char UC, *pUC;
  short S, *pS;
  unsigned short US, *pUS;
  int I, *pI;
  unsigned int UI, *pUI;
  long L, *pL;
  unsigned long UL, *pUL;
  float F, *pF;
  double D, *pD;
  C = 'A';
  UC = 21;
  S = -14;
  US = 7;
  I = 102;
  UI = 1002;
  L = -234;
  UL = 234;
  F = 1.25E10;
  D = -1.25E-37;
  pC = &C;
  ppC = &pC;
  pppC = &ppC;
  ppppC = &pppC;
  pppppC = &ppppC;
  ppppppC = &pppppC;
  pUC = &UC;
  pS = &S;
  pUS = &US;
  pI = &I;
  pUI = &UI;
  pL = &L;
  pUL = &UL;
  pF = &F;
  pD = &D;
  marker1();
  return 0;
}
```