ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_sudoku_generate>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <sudoku_generate@plt>
  mov    $0x51,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <assertNoEmpty@plt>
  test   %ebx,%ebx
  je     L0
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L0
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L0:
  add    $0x8,%rsp
  lea    D1(%rip),%r8
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: e: test_sudoku_generate()

assistant: ```c
char *test_sudoku_generate() {
  static int actual[81];
  int result = sudoku_generate(actual);
  int noEmpty = assertNoEmpty(actual, 81);
  do {
    if (!(result && noEmpty))
      return "e: test_sudoku_generate()";
  } while (0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lin_fmN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %ecx,-0x7c(%rbp)
  mov    %r8,-0x88(%rbp)
  mov    %r9,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L15
L62:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x88(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x88(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x88(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x88(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  mov    -0x90(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x90(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rax),%xmm1
  mov    -0x90(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x90(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L50
L13:
  movl   $0x0,-0x4c(%rbp)
  jmp    L54
L69:
  mov    -0x4c(%rbp),%eax
  cltq
  movsd  -0x40(%rbp,%rax,8),%xmm1
  mov    -0x50(%rbp),%eax
  cltq
  movsd  -0x20(%rbp,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x70(%rbp),%rax
  movsd  %xmm0,(%rax)
  addq   $0x8,-0x70(%rbp)
  addl   $0x1,-0x4c(%rbp)
L54:
  cmpl   $0x2,-0x4c(%rbp)
  jle    L69
  addl   $0x1,-0x50(%rbp)
L50:
  cmpl   $0x2,-0x50(%rbp)
  jle    L13
  addl   $0x1,-0x54(%rbp)
L15:
  mov    -0x54(%rbp),%eax
  cmp    -0x7c(%rbp),%eax
  jl     L62
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
datatype: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void lin_fmN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, k, l;
  a[2] = 1;
  b[2] = 1;
  s = u;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (k = 0; k < 3; k++)
      for (l = 0; l < 3; l++) {
        *p = a[l] * b[k];
        p++;
      }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lin_fmN>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mov    D9(%rip),%rdx
  mov    %rdx,0x10(%rsp)
  test   %ecx,%ecx
  jle    L5
  add    $0x48,%rsi
  mov    %rax,%r10
  lea    -0x1(%rcx),%edx
  lea    0x4(%rax,%rdx,4),%rcx
  jmp    L39
L2:
  add    $0x48,%rsi
  add    $0x4,%r10
  cmp    %rcx,%r10
  je     L5
L39:
  lea    -0x48(%rsi),%rax
  mov    (%r10),%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rdx
  movsd  (%r8),%xmm1
  movapd %xmm1,%xmm3
  mulsd  (%rdx),%xmm3
  addsd  0x8(%r8),%xmm3
  mulsd  0x8(%rdx),%xmm1
  addsd  0x10(%r8),%xmm1
  movsd  (%r9),%xmm0
  movapd %xmm0,%xmm2
  mulsd  0x18(%rdx),%xmm2
  addsd  0x8(%r9),%xmm2
  movsd  %xmm2,(%rsp)
  mulsd  0x20(%rdx),%xmm0
  addsd  0x10(%r9),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rsp,%rdx
L34:
  movsd  (%rdx),%xmm0
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,(%rax)
  movapd %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rax)
  movsd  %xmm0,0x10(%rax)
  add    $0x18,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rax
  jne    L34
  jmp    L2
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void lin_fmN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, k, l;
  a[2] = 1;
  b[2] = 1;
  s = u;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (k = 0; k < 3; k++)
      for (l = 0; l < 3; l++) {
        *p = a[l] * b[k];
        p++;
      }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lin_fmN>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rax,0x10(%rsp)
  test   %ecx,%ecx
  jle    L39
  lea    -0x1(%rcx),%eax
  add    $0x48,%rsi
  mov    %rdx,%r10
  mov    %rsp,%rcx
  lea    0x4(%rdx,%rax,4),%r11
  xchg   %ax,%ax
L44:
  mov    (%r10),%edx
  movsd  (%r9),%xmm2
  lea    -0x48(%rsi),%rax
  movsd  (%r8),%xmm1
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rdx
  movsd  0x18(%rdx),%xmm0
  movsd  (%rdx),%xmm3
  mulsd  %xmm2,%xmm0
  mulsd  0x20(%rdx),%xmm2
  addsd  0x8(%r9),%xmm0
  mulsd  %xmm1,%xmm3
  addsd  0x10(%r9),%xmm2
  mulsd  0x8(%rdx),%xmm1
  addsd  0x8(%r8),%xmm3
  mov    %rcx,%rdx
  addsd  0x10(%r8),%xmm1
  movsd  %xmm2,0x8(%rsp)
L37:
  movapd %xmm3,%xmm2
  movsd  %xmm0,0x10(%rax)
  add    $0x18,%rax
  add    $0x8,%rdx
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,-0x18(%rax)
  movapd %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,-0x10(%rax)
  cmp    %rsi,%rax
  je     L12
  movsd  (%rdx),%xmm0
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x4,%r10
  add    $0x48,%rsi
  cmp    %r11,%r10
  jne    L44
L39:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void lin_fmN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, k, l;
  a[2] = 1;
  b[2] = 1;
  s = u;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (k = 0; k < 3; k++)
      for (l = 0; l < 3; l++) {
        *p = a[l] * b[k];
        p++;
      }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lin_fmN>:
  endbr64
  mov    %rsi,%rax
  test   %ecx,%ecx
  jle    L8
  mov    %rdx,%rsi
  movsd  D5(%rip),%xmm3
  lea    -0x1(%rcx),%edx
  lea    0x4(%rsi,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%rsi),%edx
  movsd  (%r8),%xmm1
  add    $0x4,%rsi
  add    $0x48,%rax
  movupd (%r8),%xmm0
  movupd 0x8(%r8),%xmm7
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  unpcklpd %xmm0,%xmm0
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rdx
  movsd  (%rdx),%xmm4
  movupd (%rdx),%xmm6
  movsd  0x18(%rdx),%xmm2
  mulsd  %xmm1,%xmm4
  mulsd  0x8(%rdx),%xmm1
  addsd  0x8(%r8),%xmm4
  addsd  0x10(%r8),%xmm1
  mulpd  %xmm6,%xmm0
  unpcklpd %xmm1,%xmm4
  movsd  (%r9),%xmm1
  mulsd  %xmm1,%xmm2
  addpd  %xmm7,%xmm0
  addsd  0x8(%r9),%xmm2
  mulsd  0x20(%rdx),%xmm1
  addsd  0x10(%r9),%xmm1
  movups %xmm4,-0x18(%rax)
  movsd  %xmm3,-0x8(%rax)
  movapd %xmm2,%xmm5
  unpcklpd %xmm5,%xmm5
  mulpd  %xmm0,%xmm5
  movups %xmm5,-0x48(%rax)
  movapd %xmm0,%xmm5
  unpckhpd %xmm0,%xmm0
  mulsd  %xmm1,%xmm5
  mulsd  %xmm1,%xmm0
  unpcklpd %xmm5,%xmm2
  unpcklpd %xmm1,%xmm0
  movups %xmm2,-0x38(%rax)
  movups %xmm0,-0x28(%rax)
  cmp    %rsi,%rcx
  jne    L3
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void lin_fmN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, k, l;
  a[2] = 1;
  b[2] = 1;
  s = u;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (k = 0; k < 3; k++)
      for (l = 0; l < 3; l++) {
        *p = a[l] * b[k];
        p++;
      }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test1n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jge    L15
  mov    $0x1,%eax
  jmp    L9
L15:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int test1n(long long n) {
  if (n < -1LL)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test1n>:
  endbr64
  cmp    $0xffffffffffffffff,%rdi
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test1n(long long n) {
  if (n < -1LL)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test1n>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffffffffffffffff,%rdi
  setl   %al
  ret
```

assistant: ```c
int test1n(long long n) {
  if (n < -1LL)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test1n>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffffffffffffffff,%rdi
  setl   %al
  ret
```

assistant: ```c
int test1n(long long n) {
  if (n < -1LL)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x20(%rbp),%rbx
  movb   $0x0,(%rbx)
  cmpq   $0x0,-0x30(%rbp)
  je     L45
  mov    -0x28(%rbp),%r13
  mov    $0x1,%r12d
  jmp    L12
L55:
  mov    %r13,%rdx
  lea    0x1(%rdx),%r13
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  jmp    L58
L40:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  add    $0x1,%r12
L58:
  cmp    -0x30(%rbp),%r12
  jb     L40
  mov    -0x20(%rbp),%rax
  jmp    L13
L48:
  add    $0x1,%r12
L12:
  cmp    -0x30(%rbp),%r12
  jb     L55
  movb   $0x0,(%rbx)
L45:
  mov    -0x20(%rbp),%rax
L13:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *Strncpy(char *const dst, const char *const src, const size_t n) {
  register char *d;
  register const char *s;
  register size_t i;
  d = dst;
  *d = 0;
  if (n != 0) {
    s = src;
    for (i = 1; i < n; i++) {
      if ((*d++ = *s++) == 0) {
        for (; i < n; i++)
          *d++ = 0;
        return dst;
      }
    }
    *d = 0;
  }
  return (dst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Strncpy>:
  endbr64
  mov    %rdi,%rax
  movb   $0x0,(%rdi)
  test   %rdx,%rdx
  je     L50
  cmp    $0x1,%rdx
  jbe    L60
  mov    %rdi,%rcx
  mov    $0x1,%r8d
L16:
  add    $0x1,%rcx
  movzbl -0x1(%rsi,%r8,1),%r9d
  mov    %r9b,-0x1(%rcx)
  test   %r9b,%r9b
  je     L10
  add    $0x1,%r8
  cmp    %r8,%rdx
  jne    L16
L18:
  movb   $0x0,(%rcx)
L50:
  ret
L10:
  cmp    %r8,%rdx
  jbe    L50
  sub    %r8,%rdx
  add    %rcx,%rdx
L57:
  add    $0x1,%rcx
  movb   $0x0,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L57
  ret
L60:
  mov    %rdi,%rcx
  jmp    L18
```

assistant: ```c
char *Strncpy(char *const dst, const char *const src, const size_t n) {
  register char *d;
  register const char *s;
  register size_t i;
  d = dst;
  *d = 0;
  if (n != 0) {
    s = src;
    for (i = 1; i < n; i++) {
      if ((*d++ = *s++) == 0) {
        for (; i < n; i++)
          *d++ = 0;
        return dst;
      }
    }
    *d = 0;
  }
  return (dst);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Strncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movb   $0x0,(%rdi)
  test   %rdx,%rdx
  je     L27
  cmp    $0x1,%rdx
  je     L22
  mov    $0x1,%eax
  jmp    L59
  xchg   %ax,%ax
L19:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L22
L59:
  movzbl -0x1(%rsi,%rax,1),%ecx
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  jne    L19
  cmp    %rax,%rdx
  jbe    L27
  sub    %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L27:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L22:
  mov    %r12,%rax
  movb   $0x0,(%rdi)
  pop    %r12
  ret
```

assistant: ```c
char *Strncpy(char *const dst, const char *const src, const size_t n) {
  register char *d;
  register const char *s;
  register size_t i;
  d = dst;
  *d = 0;
  if (n != 0) {
    s = src;
    for (i = 1; i < n; i++) {
      if ((*d++ = *s++) == 0) {
        for (; i < n; i++)
          *d++ = 0;
        return dst;
      }
    }
    *d = 0;
  }
  return (dst);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Strncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movb   $0x0,(%rdi)
  test   %rdx,%rdx
  je     L25
  cmp    $0x1,%rdx
  je     L14
  mov    $0x1,%eax
  jmp    L34
  xchg   %ax,%ax
L39:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L14
L34:
  movzbl -0x1(%rsi,%rax,1),%ecx
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  jne    L39
  cmp    %rax,%rdx
  jbe    L25
  sub    %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L25:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L14:
  mov    %r12,%rax
  movb   $0x0,(%rdi)
  pop    %r12
  ret
```

assistant: ```c
char *Strncpy(char *const dst, const char *const src, const size_t n) {
  register char *d;
  register const char *s;
  register size_t i;
  d = dst;
  *d = 0;
  if (n != 0) {
    s = src;
    for (i = 1; i < n; i++) {
      if ((*d++ = *s++) == 0) {
        for (; i < n; i++)
          *d++ = 0;
        return dst;
      }
    }
    *d = 0;
  }
  return (dst);
}
```
user: Translate the below assembly code into C programming language:

```asm
<evtag_marshal_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <evbuffer_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <run_marshal@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <evtag_marshal_buffer@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void evtag_marshal_run(struct evbuffer *evbuf, ev_uint32_t tag, const struct run *msg) {
  struct evbuffer *buf_ = evbuffer_new();
  assert(buf_ != NULL);
  run_marshal(buf_, msg);
  evtag_marshal_buffer(evbuf, tag, buf_);
  evbuffer_free(buf_);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<evtag_marshal_run>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    $0x0,%eax
  call   <evbuffer_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <run_marshal@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <evtag_marshal_buffer@plt>
  mov    %rbx,%rdi
  call   <evbuffer_free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void evtag_marshal_run(struct evbuffer *evbuf, ev_uint32_t tag, const struct run *msg) {
  struct evbuffer *buf_ = evbuffer_new();
  assert(buf_ != NULL);
  run_marshal(buf_, msg);
  evtag_marshal_buffer(evbuf, tag, buf_);
  evbuffer_free(buf_);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<evtag_marshal_run>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <evbuffer_new@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <run_marshal@plt>
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r13d,%esi
  call   <evtag_marshal_buffer@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <evbuffer_free@plt>
```

assistant: ```c
void evtag_marshal_run(struct evbuffer *evbuf, ev_uint32_t tag, const struct run *msg) {
  struct evbuffer *buf_ = evbuffer_new();
  assert(buf_ != NULL);
  run_marshal(buf_, msg);
  evtag_marshal_buffer(evbuf, tag, buf_);
  evbuffer_free(buf_);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<evtag_marshal_run>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <evbuffer_new@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <run_marshal@plt>
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r13d,%esi
  call   <evtag_marshal_buffer@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <evbuffer_free@plt>
```

assistant: ```c
void evtag_marshal_run(struct evbuffer *evbuf, ev_uint32_t tag, const struct run *msg) {
  struct evbuffer *buf_ = evbuffer_new();
  assert(buf_ != NULL);
  run_marshal(buf_, msg);
  evtag_marshal_buffer(evbuf, tag, buf_);
  evbuffer_free(buf_);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xa(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: %c

assistant: ```c
int main(void) {
  char c, C;
  scanf("%c", &c);
  C = c - 32;
  printf("%c", C);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x20(%rax),%esi
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: %c

assistant: ```c
int main(void) {
  char c, C;
  scanf("%c", &c);
  C = c - 32;
  printf("%c", C);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0x20(%rax),%esi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: %c

assistant: ```c
int main(void) {
  char c, C;
  scanf("%c", &c);
  C = c - 32;
  printf("%c", C);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0x20(%rax),%esi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: %c

assistant: ```c
int main(void) {
  char c, C;
  scanf("%c", &c);
  C = c - 32;
  printf("%c", C);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Get_Byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x3(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x3(%rbp)
  jmp    L23
L7:
  shlb   -0x2(%rbp)
  mov    $0x0,%eax
  call   <SO@plt>
  mov    %al,-0x1(%rbp)
  mov    $0x1,%edi
  call   <SCK@plt>
  cmpb   $0x1,-0x1(%rbp)
  jne    L18
  orb    $0x1,-0x2(%rbp)
L18:
  mov    $0x0,%edi
  call   <SCK@plt>
  movzbl -0x3(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x3(%rbp)
L23:
  cmpb   $0x7,-0x3(%rbp)
  jbe    L7
  movzbl -0x2(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char Get_Byte() {
  unsigned char i = 0, in = 0, temp = 0;
  for (i = 0; i < 8; i++) {
    in = (in << 1);
    temp = SO();
    SCK(1);
    if (temp == 1)
      in = in | 0x01;
    SCK(0);
  }
  return in;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Get_Byte>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x8,%r12d
  mov    $0x0,%ebx
L5:
  add    %ebx,%ebx
  mov    $0x0,%eax
  call   <SO@plt>
  mov    %eax,%ebp
  mov    $0x1,%edi
  call   <SCK@plt>
  mov    %ebx,%eax
  or     $0x1,%eax
  cmp    $0x1,%bpl
  cmove  %eax,%ebx
  mov    $0x0,%edi
  call   <SCK@plt>
  sub    $0x1,%r12b
  jne    L5
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char Get_Byte() {
  unsigned char i = 0, in = 0, temp = 0;
  for (i = 0; i < 8; i++) {
    in = (in << 1);
    temp = SO();
    SCK(1);
    if (temp == 1)
      in = in | 0x01;
    SCK(0);
  }
  return in;
}
```