ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x80(%rbp)
  jmp    L12
L47:
  mov    -0x80(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L56
  movl   $0x0,-0x78(%rbp)
L56:
  mov    -0x80(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x53,%al
  jne    L55
  addl   $0x1,-0x78(%rbp)
L55:
  mov    -0x80(%rbp),%eax
  add    $0x2,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x54,%al
  jne    L125
  addl   $0x1,-0x78(%rbp)
L125:
  mov    -0x80(%rbp),%eax
  add    $0x3,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  jne    L36
  addl   $0x1,-0x78(%rbp)
L36:
  mov    -0x80(%rbp),%eax
  add    $0x4,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x50,%al
  jne    L46
  addl   $0x1,-0x78(%rbp)
L46:
  mov    -0x80(%rbp),%eax
  add    $0x5,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L5
  addl   $0x1,-0x78(%rbp)
L5:
  cmpl   $0x5,-0x78(%rbp)
  jne    L81
  mov    -0x80(%rbp),%eax
  mov    %eax,-0x7c(%rbp)
  jmp    L44
L81:
  addl   $0x1,-0x80(%rbp)
L12:
  mov    -0x80(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L47
L44:
  movl   $0x0,-0x80(%rbp)
  jmp    L15
L68:
  mov    -0x80(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x80(%rbp)
L15:
  mov    -0x80(%rbp),%eax
  cmp    -0x7c(%rbp),%eax
  jl     L68
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: %[^
]s

assistant: ```c
int main() {
  int n, l, b, a;
  char s[100];
  scanf("%[^\n]s", s);
  l = strlen(s);
  for (n = 0; n < l; n++) {
    if (s[n] == ' ')
      a = 0;
    if (s[n + 1] == 'S')
      a++;
    if (s[n + 2] == 'T')
      a++;
    if (s[n + 3] == 'O')
      a++;
    if (s[n + 4] == 'P')
      a++;
    if (s[n + 5] == ' ')
      a++;
    if (a == 5) {
      b = n;
      break;
    }
  }
  for (n = 0; n < b; n++)
    printf("%c", s[n]);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rbp
  mov    %r12,%rdx
  mov    $0x0,%ecx
  mov    $0x0,%r8d
L40:
  cmp    %eax,%ecx
  jge    L22
  cmpb   $0x20,(%rdx)
  cmove  %r8d,%ebx
  lea    0x1(%rcx),%edi
  cmpb   $0x53,0x1(%rdx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ebx
  cmpb   $0x54,0x2(%rdx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ebx
  cmpb   $0x4f,0x3(%rdx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ebx
  cmpb   $0x50,0x4(%rdx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ebx
  cmpb   $0x20,0x5(%rdx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ebx
  add    $0x1,%rdx
  cmp    $0x5,%ebx
  je     L21
  mov    %edi,%ecx
  jmp    L40
L22:
  mov    $0x0,%ecx
L21:
  test   %ecx,%ecx
  jle    L39
  lea    -0x1(%rcx),%eax
  lea    0x1(%r12,%rax,1),%rbx
L27:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L27
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: %[^
]s

assistant: ```c
int main() {
  int n, l, b, a;
  char s[100];
  scanf("%[^\n]s", s);
  l = strlen(s);
  for (n = 0; n < l; n++) {
    if (s[n] == ' ')
      a = 0;
    if (s[n + 1] == 'S')
      a++;
    if (s[n + 2] == 'T')
      a++;
    if (s[n + 3] == 'O')
      a++;
    if (s[n + 4] == 'P')
      a++;
    if (s[n + 5] == ' ')
      a++;
    if (a == 5) {
      b = n;
      break;
    }
  }
  for (n = 0; n < b; n++)
    printf("%c", s[n]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  jmp    L29
  nopl   (%rax)
L54:
  cmpb   $0x20,(%rdx)
  lea    0x1(%rcx),%edi
  cmove  %r8d,%ebx
  xor    %esi,%esi
  cmpb   $0x53,0x1(%rdx)
  sete   %sil
  add    %esi,%ebx
  xor    %esi,%esi
  cmpb   $0x54,0x2(%rdx)
  sete   %sil
  add    %esi,%ebx
  xor    %esi,%esi
  cmpb   $0x4f,0x3(%rdx)
  sete   %sil
  add    %esi,%ebx
  xor    %esi,%esi
  cmpb   $0x50,0x4(%rdx)
  sete   %sil
  add    %esi,%ebx
  xor    %esi,%esi
  cmpb   $0x20,0x5(%rdx)
  sete   %sil
  add    $0x1,%rdx
  add    %esi,%ebx
  cmp    $0x5,%ebx
  je     L2
  mov    %edi,%ecx
L29:
  cmp    %eax,%ecx
  jl     L54
L13:
  test   %r12d,%r12d
  jle    L64
  lea    -0x1(%r12),%eax
  lea    0x1(%r13,%rax,1),%rbx
  nopl   0x0(%rax)
L61:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L61
L64:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %ecx,%r12d
  jmp    L13
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: %[^
]s

assistant: ```c
int main() {
  int n, l, b, a;
  char s[100];
  scanf("%[^\n]s", s);
  l = strlen(s);
  for (n = 0; n < l; n++) {
    if (s[n] == ' ')
      a = 0;
    if (s[n + 1] == 'S')
      a++;
    if (s[n + 2] == 'T')
      a++;
    if (s[n + 3] == 'O')
      a++;
    if (s[n + 4] == 'P')
      a++;
    if (s[n + 5] == ' ')
      a++;
    if (a == 5) {
      b = n;
      break;
    }
  }
  for (n = 0; n < b; n++)
    printf("%c", s[n]);
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movzbl 0x2(%rsp),%r8d
  movzbl 0x3(%rsp),%ecx
  lea    0x5(%rsp),%r11
  mov    %eax,%r9d
  movzbl 0x4(%rsp),%esi
  movzbl (%rsp),%edx
  xor    %eax,%eax
  jmp    L16
L41:
  cmp    $0x20,%dl
  movzbl (%r12,%rax,1),%edx
  cmove  %r13d,%ebx
  xor    %edi,%edi
  cmp    $0x53,%dl
  sete   %dil
  add    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x54,%r8b
  sete   %dil
  add    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x4f,%cl
  sete   %dil
  add    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x50,%sil
  sete   %dil
  xor    %r8d,%r8d
  add    %edi,%ebx
  movzbl (%r11,%rax,1),%edi
  cmp    $0x20,%dil
  sete   %r8b
  add    $0x1,%rax
  add    %r8d,%ebx
  mov    %ecx,%r8d
  mov    %esi,%ecx
  cmp    $0x5,%ebx
  je     L43
  mov    %edi,%esi
L16:
  mov    %eax,%r10d
  cmp    %eax,%r9d
  jg     L41
  xor    %r10d,%r10d
L43:
  test   %r10d,%r10d
  je     L50
  lea    -0x1(%r10),%eax
  mov    %rbp,%rbx
  lea    0x1(%rsp,%rax,1),%rbp
  nopl   0x0(%rax)
L20:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L20
L50:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: %[^
]s

assistant: ```c
int main() {
  int n, l, b, a;
  char s[100];
  scanf("%[^\n]s", s);
  l = strlen(s);
  for (n = 0; n < l; n++) {
    if (s[n] == ' ')
      a = 0;
    if (s[n + 1] == 'S')
      a++;
    if (s[n + 2] == 'T')
      a++;
    if (s[n + 3] == 'O')
      a++;
    if (s[n + 4] == 'P')
      a++;
    if (s[n + 5] == ' ')
      a++;
    if (a == 5) {
      b = n;
      break;
    }
  }
  for (n = 0; n < b; n++)
    printf("%c", s[n]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<charSepToSlNames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,%eax
  mov    %al,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L1
L42:
  movsbl -0x3c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <newSlName@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <slAddHead@plt>
  jmp    L29
L19:
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <slNameNewN@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <slAddHead@plt>
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L1:
  cmpq   $0x0,-0x20(%rbp)
  je     L29
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
L29:
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <slReverse@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
struct slName *charSepToSlNames(char *string, char c) {
  struct slName *list = NULL, *el;
  char *s, *e;
  s = string;
  while (s != NULL && s[0] != 0) {
    e = strchr(s, c);
    if (e == NULL) {
      el = newSlName(s);
      slAddHead(&list, el);
      break;
    } else {
      el = slNameNewN(s, e - s);
      slAddHead(&list, el);
      s = e + 1;
    }
  }
  slReverse(&list);
  return list;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<charSepToSlNames>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movsbl %sil,%r12d
  test   %rdi,%rdi
  jne    L6
  jmp    L49
L11:
  mov    %eax,%esi
  sub    %ebp,%esi
  mov    %rbp,%rdi
  call   <slNameNewN@plt>
  mov    %rax,%rsi
  mov    %rsp,%rdi
  call   <slAddHead@plt>
  lea    0x1(%rbx),%rbp
L6:
  cmpb   $0x0,0x0(%rbp)
  je     L49
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L11
  mov    %rbp,%rdi
  call   <newSlName@plt>
  mov    %rax,%rsi
  mov    %rsp,%rdi
  call   <slAddHead@plt>
L49:
  mov    %rsp,%rdi
  call   <slReverse@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct slName *charSepToSlNames(char *string, char c) {
  struct slName *list = NULL, *el;
  char *s, *e;
  s = string;
  while (s != NULL && s[0] != 0) {
    e = strchr(s, c);
    if (e == NULL) {
      el = newSlName(s);
      slAddHead(&list, el);
      break;
    } else {
      el = slNameNewN(s, e - s);
      slAddHead(&list, el);
      s = e + 1;
    }
  }
  slReverse(&list);
  return list;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<charSepToSlNames>:
  endbr64
  push   %r13
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  jne    L52
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L58
  mov    %eax,%esi
  mov    %rbp,%rdi
  sub    %ebp,%esi
  lea    0x1(%rbx),%rbp
  call   <slNameNewN@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <slAddHead@plt>
L52:
  cmpb   $0x0,0x0(%rbp)
  jne    L25
L37:
  mov    %r13,%rdi
  call   <slReverse@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rbp,%rdi
  call   <newSlName@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <slAddHead@plt>
  jmp    L37
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct slName *charSepToSlNames(char *string, char c) {
  struct slName *list = NULL, *el;
  char *s, *e;
  s = string;
  while (s != NULL && s[0] != 0) {
    e = strchr(s, c);
    if (e == NULL) {
      el = newSlName(s);
      slAddHead(&list, el);
      break;
    } else {
      el = slNameNewN(s, e - s);
      slAddHead(&list, el);
      s = e + 1;
    }
  }
  slReverse(&list);
  return list;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<charSepToSlNames>:
  endbr64
  push   %r13
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  jne    L55
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L56
  mov    %eax,%esi
  mov    %rbp,%rdi
  sub    %ebp,%esi
  lea    0x1(%rbx),%rbp
  call   <slNameNewN@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <slAddHead@plt>
L55:
  cmpb   $0x0,0x0(%rbp)
  jne    L19
L40:
  mov    %r13,%rdi
  call   <slReverse@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %rbp,%rdi
  call   <newSlName@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <slAddHead@plt>
  jmp    L40
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct slName *charSepToSlNames(char *string, char c) {
  struct slName *list = NULL, *el;
  char *s, *e;
  s = string;
  while (s != NULL && s[0] != 0) {
    e = strchr(s, c);
    if (e == NULL) {
      el = newSlName(s);
      slAddHead(&list, el);
      break;
    } else {
      el = slNameNewN(s, e - s);
      slAddHead(&list, el);
      s = e + 1;
    }
  }
  slReverse(&list);
  return list;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D50(%rip),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    -0xc(%rbp),%esi
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2,-0xc(%rbp)
  jle    L0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    D34(%rip),%rdx
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L0:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D50
type: string
name: retrieve_data
arguments: label: D44
type: string
name: retrieve_data
arguments: label: D27
type: string

tool: D19: Extracting from '%s'


tool: D50: %d /%d /%d%n

tool: D44: %02d/%02d/%04d nf = %d, n = %d


tool: D27: Remainder = '%s'


assistant: ```c
int main(int argc, char *argv[]) {
  int nf;
  int n;
  int month, day, year;
  static char date[] = "   12/  2 / 2008 ";
  printf("Extracting from '%s'\n", date);
  nf = sscanf(date, "%d /%d /%d%n", &month, &day, &year, &n);
  printf("%02d/%02d/%04d nf = %d, n = %d\n", month, day, year, nf, n);
  if (nf >= 3) {
    printf("Remainder = '%s'\n", &date[n]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rbx
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%r9
  lea    0x14(%rsp),%r8
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    %eax,%ebx
  mov    0x8(%rsp),%r9d
  mov    %eax,%r8d
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  jg     L9
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  movslq 0x8(%rsp),%rsi
  lea    D9(%rip),%rax
  add    %rax,%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D27
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D30
data_type: string
name: retrieve_data
arguments: label: D22
data_type: string

tool: D27: Extracting from '%s'


tool: D11: %d /%d /%d%n

tool: D30: %02d/%02d/%04d nf = %d, n = %d


tool: D22: Remainder = '%s'


assistant: ```c
int main(int argc, char *argv[]) {
  int nf;
  int n;
  int month, day, year;
  static char date[] = "   12/  2 / 2008 ";
  printf("Extracting from '%s'\n", date);
  nf = sscanf(date, "%d /%d /%d%n", &month, &day, &year, &n);
  printf("%02d/%02d/%04d nf = %d, n = %d\n", month, day, year, nf, n);
  if (nf >= 3) {
    printf("Remainder = '%s'\n", &date[n]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D42(%rip),%rbp
  lea    D4(%rip),%rdi
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0x8(%rsp),%r9
  lea    0x14(%rsp),%r8
  lea    D1(%rip),%rsi
  call   <sscanf@plt>
  mov    0x8(%rsp),%r9d
  mov    0x14(%rsp),%ecx
  lea    D46(%rip),%rdi
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %eax,%ebx
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  jg     L19
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  movslq 0x8(%rsp),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  add    %rbp,%rsi
  call   <printf@plt>
  jmp    L8
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string
name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D46
type: string
name: unpack_data
arguments: data_tag: D31
type: string

tool: D4: Extracting from '%s'


tool: D1: %d /%d /%d%n

tool: D46: %02d/%02d/%04d nf = %d, n = %d


tool: D31: Remainder = '%s'


assistant: ```c
int main(int argc, char *argv[]) {
  int nf;
  int n;
  int month, day, year;
  static char date[] = "   12/  2 / 2008 ";
  printf("Extracting from '%s'\n", date);
  nf = sscanf(date, "%d /%d /%d%n", &month, &day, &year, &n);
  printf("%02d/%02d/%04d nf = %d, n = %d\n", month, day, year, nf, n);
  if (nf >= 3) {
    printf("Remainder = '%s'\n", &date[n]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  lea    D13(%rip),%rdi
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0x8(%rsp),%r9
  lea    0x14(%rsp),%r8
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  mov    0x8(%rsp),%r9d
  mov    0x14(%rsp),%ecx
  lea    D12(%rip),%rdi
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %eax,%ebx
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  jg     L13
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  movslq 0x8(%rsp),%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  add    %rbp,%rsi
  call   <printf@plt>
  jmp    L17
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string

tool: D13: Extracting from '%s'


tool: D9: %d /%d /%d%n

tool: D12: %02d/%02d/%04d nf = %d, n = %d


tool: D43: Remainder = '%s'


assistant: ```c
int main(int argc, char *argv[]) {
  int nf;
  int n;
  int month, day, year;
  static char date[] = "   12/  2 / 2008 ";
  printf("Extracting from '%s'\n", date);
  nf = sscanf(date, "%d /%d /%d%n", &month, &day, &year, &n);
  printf("%02d/%02d/%04d nf = %d, n = %d\n", month, day, year, nf, n);
  if (nf >= 3) {
    printf("Remainder = '%s'\n", &date[n]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L14
  movsd  -0x8(%rbp),%xmm0
  movq   D14(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <_tan_reduce@plt>
  movq   %xmm0,%rax
  movq   D14(%rip),%xmm0
  movq   %rax,%xmm2
  xorpd  %xmm0,%xmm2
  movq   %xmm2,%rax
  jmp    L15
L14:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <_tan_reduce@plt>
  movq   %xmm0,%rax
L15:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
datatype: f32[2]

tool: {"D14": [0.0,-0.0]}

assistant: ```c
double tan(double x) {
  if (x < 0.0)
    return -_tan_reduce(-x);
  else
    return _tan_reduce(x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tan>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L19
  call   <_tan_reduce@plt>
L5:
  add    $0x8,%rsp
  ret
L19:
  xorpd  D19(%rip),%xmm0
  call   <_tan_reduce@plt>
  xorpd  D19(%rip),%xmm0
  jmp    L5
```

tool_calls: name: unpack_data
arguments: label: D19
type: f32[4]

tool: {"D19": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double tan(double x) {
  if (x < 0.0)
    return -_tan_reduce(-x);
  else
    return _tan_reduce(x);
}
```