user: 这段汇编代码用C语言表示是什么样的:

```asm
<Rabin_Karp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  jle    L164
  lea    -0x1(%rax),%esi
  mov    $0x0,%edx
  mov    $0x1,%r12d
L13:
  mov    %r12d,%eax
  shl    $0x8,%eax
  movslq %eax,%r12
  imul   $0xdbeb61f,%r12,%r12
  sar    $0x23,%r12
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%r12d
  imul   $0x95,%r12d,%ecx
  sub    %ecx,%eax
  mov    %eax,%r12d
  add    $0x1,%edx
  cmp    %esi,%edx
  jne    L13
L35:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L55
  mov    %eax,%ecx
  mov    $0x0,%edx
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L134:
  mov    %ebx,%eax
  shl    $0x8,%eax
  movsbl (%r15,%rdx,1),%esi
  add    %esi,%eax
  movslq %eax,%rbx
  imul   $0xdbeb61f,%rbx,%rbx
  sar    $0x23,%rbx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%ebx
  imul   $0x95,%ebx,%esi
  sub    %esi,%eax
  mov    %eax,%ebx
  mov    %ebp,%eax
  shl    $0x8,%eax
  movsbl (%r14,%rdx,1),%esi
  add    %esi,%eax
  movslq %eax,%rbp
  imul   $0xdbeb61f,%rbp,%rbp
  sar    $0x23,%rbp
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%ebp
  imul   $0x95,%ebp,%esi
  sub    %esi,%eax
  mov    %eax,%ebp
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L134
L21:
  sub    0xc(%rsp),%r13d
  mov    %r13d,0x4(%rsp)
  js     L133
  mov    $0x0,%r13d
  jmp    L100
L164:
  mov    $0x1,%r12d
  jmp    L35
L55:
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L21
L48:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    %eax,%esi
  mov    $0x0,%eax
  lea    (%r15,%r13,1),%rcx
L105:
  mov    %eax,%edx
  movzbl (%r14,%rax,1),%edi
  cmp    %dil,(%rcx,%rax,1)
  jne    L165
  lea    0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L105
L165:
  cmp    %edx,0xc(%rsp)
  jne    L83
  mov    0x8(%rsp),%eax
  lea    0x1(%rax),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L83
L2:
  mov    $0x0,%edx
  jmp    L165
L88:
  add    $0x1,%r13
  cmp    %r13d,0x4(%rsp)
  jl     L133
L100:
  mov    %r13d,0x8(%rsp)
  cmp    %ebp,%ebx
  je     L48
L83:
  cmp    %r13d,0x4(%rsp)
  jle    L88
  movsbl (%r15,%r13,1),%edx
  imul   %r12d,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  shl    $0x8,%eax
  mov    0x8(%rsp),%edx
  add    0xc(%rsp),%edx
  movslq %edx,%rdx
  movsbl (%r15,%rdx,1),%edx
  add    %edx,%eax
  movslq %eax,%rbx
  imul   $0xdbeb61f,%rbx,%rbx
  sar    $0x23,%rbx
  cltd
  sub    %edx,%ebx
  imul   $0x95,%ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  lea    0x95(%rax),%eax
  cmovs  %eax,%ebx
  jmp    L88
L133:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: 

Pattern searched is found at position %d



assistant: ```c
void Rabin_Karp(char *text, char *pattern) {
  int text_len = strlen(text);
  int pattern_len = strlen(pattern);
  int hash = 1;
  int asciichars = 256;
  int prime = 149;
  for (int i = 0; i < pattern_len - 1; i++) {
    hash = (hash * asciichars) % prime;
  }
  int hash_txt = 0, hash_pat = 0;
  for (int i = 0; i < pattern_len; i++) {
    hash_txt = (hash_txt * asciichars + text[i]) % prime;
    hash_pat = (hash_pat * asciichars + pattern[i]) % prime;
  }
  for (int i = 0; i <= text_len - pattern_len; i++) {
    int j;
    if (hash_txt == hash_pat) {
      for (j = 0; j < pattern_len; j++) {
        if (text[i + j] != pattern[j])
          break;
      }
      if (j == pattern_len) {
        printf("\n\nPattern searched is found at position %d\n\n", i + 1);
      }
    }
    if (i < text_len - pattern_len) {
      hash_txt = ((hash_txt - text[i] * hash) * asciichars + text[i + pattern_len]) % prime;
      if (hash_txt < 0) {
        hash_txt = hash_txt + prime;
      }
    }
  }
}
```