ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<goodSuffix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L167
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L167
  lea    0x8(%rsp),%rbp
  mov    %rdi,%r12
  mov    %rbp,%rdi
  call   <applyArr@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L167
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <upfrontGoodSuffix@plt>
  mov    0x8(%rsp),%rsi
  mov    %rax,%r12
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  test   %r12,%r12
  je     L163
  nopl   (%rax)
L34:
  mov    %ebx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L34
  lea    -0x1(%rbx),%edi
  xor    %edx,%edx
  lea    0x4(%rsi),%r11
  xor    %r9d,%r9d
  movslq %edi,%rax
  lea    (%r12,%rax,4),%rcx
  jmp    L79
L58:
  add    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %ebx,%edx
  je     L138
L79:
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    %eax,(%rcx)
  jne    L58
  cmp    %r9d,%edx
  jle    L58
  lea    -0x1(%rdx),%r8d
  movslq %r9d,%r10
  sub    %r9d,%r8d
  lea    (%rsi,%r10,4),%rax
  add    %r10,%r8
  lea    (%r11,%r8,4),%r8
  nopl   (%rax)
L136:
  cmp    %ebx,(%rax)
  jne    L8
  mov    %edx,(%rax)
L8:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L136
  mov    %edx,%r9d
  add    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %ebx,%edx
  jne    L79
  nopl   (%rax)
L138:
  test   %edi,%edi
  je     L11
  mov    %r12,%rcx
  mov    %edi,%eax
  nopl   0x0(%rax)
L37:
  mov    %edi,%edx
  sub    (%rcx),%edx
  add    $0x4,%rcx
  movslq %edx,%rdx
  mov    %eax,(%rsi,%rdx,4)
  sub    $0x1,%eax
  jne    L37
L11:
  lea    0x10(%rsp),%rdi
  call   <freeArr@plt>
  mov    0x8(%rsp),%r12
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L167:
  xor    %r12d,%r12d
  jmp    L2
L163:
  mov    %rbp,%rdi
  call   <freeArr@plt>
  jmp    L2
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *goodSuffix(char *pattern, int len) {
  if (!pattern || 0 >= len) {
    return NULL;
  }
  int *arr, *suffixArr;
  applyArr(&arr, len);
  if (!arr) {
    return NULL;
  }
  suffixArr = upfrontGoodSuffix(pattern, len);
  if (!suffixArr) {
    freeArr(&arr);
    return NULL;
  }
  int i = 0;
  while (i < len) {
    arr[i++] = len;
  }
  int j = 0;
  for (i = len - 1; i >= 0; i--) {
    if (i + 1 == suffixArr[i]) {
      while (j < len - 1 - i) {
        if (len == arr[j]) {
          arr[j] = len - 1 - i;
        }
        j++;
      }
    }
  }
  for (i = 0; i < len - 1; i++) {
    arr[len - 1 - suffixArr[i]] = len - 1 - i;
  }
  freeArr(&suffixArr);
  return arr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<infile_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L19
L0:
  mov    $0x0,%eax
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: Can't close input file

assistant: ```c
int infile_close(int fd) {
  if (close(fd) == -1) {
    perror("Can't close input file");
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<infile_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L8
L18:
  add    $0x8,%rsp
  ret
L8:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: Can't close input file

assistant: ```c
int infile_close(int fd) {
  if (close(fd) == -1) {
    perror("Can't close input file");
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<infile_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L6
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L6:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: Can't close input file

assistant: ```c
int infile_close(int fd) {
  if (close(fd) == -1) {
    perror("Can't close input file");
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<infile_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L8
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L8:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: Can't close input file

assistant: ```c
int infile_close(int fd) {
  if (close(fd) == -1) {
    perror("Can't close input file");
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x8,-0x4(%rbp)
  jmp    L17
L9:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L22
L8:
  mov    $0x30,%edi
  call   <putchar@plt>
L22:
  subl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: % i = 0b

assistant: ```c
void print_bits(int i) {
  int index;
  printf("% i = 0b", i);
  for (index = 8; index >= 0; index--) {
    if (i & (1 << index)) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_bits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%ebx
  jmp    L34
L9:
  mov    $0x30,%edi
  call   <putchar@plt>
L0:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L20
L34:
  bt     %ebx,%ebp
  jae    L9
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L0
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: % i = 0b

assistant: ```c
void print_bits(int i) {
  int index;
  printf("% i = 0b", i);
  for (index = 8; index >= 0; index--) {
    if (i & (1 << index)) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_bits>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  xor    %eax,%eax
  push   %rbx
  lea    D8(%rip),%rdi
  mov    $0x8,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x31,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jb     L37
L10:
  bt     %ebx,%ebp
  jb     L32
  mov    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L10
L37:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: % i = 0b

assistant: ```c
void print_bits(int i) {
  int index;
  printf("% i = 0b", i);
  for (index = 8; index >= 0; index--) {
    if (i & (1 << index)) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_bits>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  xor    %eax,%eax
  push   %rbx
  lea    D1(%rip),%rdi
  mov    $0x8,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x31,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jb     L11
L12:
  bt     %ebx,%ebp
  jb     L16
  mov    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L12
L11:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: % i = 0b

assistant: ```c
void print_bits(int i) {
  int index;
  printf("% i = 0b", i);
  for (index = 8; index >= 0; index--) {
    if (i & (1 << index)) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<text_keypress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <common_keypress_handler@plt>
  test   %rax,%rax
  leave
  ret
```

assistant: ```c
void text_keypress(int key) {
  if (common_keypress_handler(key))
    return;
  switch (key) {}
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<text_keypress>:
  endbr64
  sub    $0x8,%rsp
  call   <common_keypress_handler@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void text_keypress(int key) {
  if (common_keypress_handler(key))
    return;
  switch (key) {}
}
```
user: Translate the below assembly code into C programming language:

```asm
<text_keypress>:
  endbr64
  jmp    1050 <common_keypress_handler@plt>
```

assistant: ```c
void text_keypress(int key) {
  if (common_keypress_handler(key))
    return;
  switch (key) {}
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<text_keypress>:
  endbr64
  jmp    1050 <common_keypress_handler@plt>
```

assistant: ```c
void text_keypress(int key) {
  if (common_keypress_handler(key))
    return;
  switch (key) {}
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L35
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L35:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L11
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L11:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D32
data_type: string
name: unpack_data
arguments: tag: D37
data_type: string

tool: D2: Enter 1 no.: 

tool: D30: %d

tool: D18: It's an even no


tool: D32: It's an odd no


tool: D37: this is an invalid input . . .
Please Run again . . .

assistant: ```c
void main() {
  int input;
  printf("Enter 1 no.: ");
  scanf("%d", &input);
  if (input % 2 == 0) {
    printf("It's an even no\n");
  } else if (input % 2 != 0) {
    printf("It's an odd no\n");
  } else {
    printf("this is an invalid input . . .\nPlease Run again . . .");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L8
  lea    D30(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  ret
L8:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D30
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string

tool: D17: Enter 1 no.: 

tool: D4: %d

tool: D30: It's an even no


tool: D10: It's an odd no


assistant: ```c
void main() {
  int input;
  printf("Enter 1 no.: ");
  scanf("%d", &input);
  if (input % 2 == 0) {
    printf("It's an even no\n");
  } else if (input % 2 != 0) {
    printf("It's an odd no\n");
  } else {
    printf("this is an invalid input . . .\nPlease Run again . . .");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L25
  lea    D22(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  ret
L25:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D25
datatype: string
name: read_data
arguments: data_label: D12
datatype: string
name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D25: Enter 1 no.: 

tool: D12: %d

tool: D22: It's an even no


tool: D13: It's an odd no


assistant: ```c
void main() {
  int input;
  printf("Enter 1 no.: ");
  scanf("%d", &input);
  if (input % 2 == 0) {
    printf("It's an even no\n");
  } else if (input % 2 != 0) {
    printf("It's an odd no\n");
  } else {
    printf("this is an invalid input . . .\nPlease Run again . . .");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L5
  lea    D32(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  ret
L5:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D32
type: string
name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D21: Enter 1 no.: 

tool: D5: %d

tool: D32: It's an even no


tool: D7: It's an odd no


assistant: ```c
void main() {
  int input;
  printf("Enter 1 no.: ");
  scanf("%d", &input);
  if (input % 2 == 0) {
    printf("It's an even no\n");
  } else if (input % 2 != 0) {
    printf("It's an odd no\n");
  } else {
    printf("this is an invalid input . . .\nPlease Run again . . .");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x50(%rbp)
  movl   $0x2,-0x4c(%rbp)
  movl   $0x3,-0x48(%rbp)
  movl   $0x4,-0x44(%rbp)
  movl   $0x5,-0x40(%rbp)
  movl   $0x6,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  movl   $0x9,-0x30(%rbp)
  movl   $0xa,-0x2c(%rbp)
  movl   $0xa,-0x28(%rbp)
  movl   $0xa,-0x24(%rbp)
  movl   $0xb,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0xc,-0x18(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 11, 11, 12};
  printf("%d\n", search(arr, sizeof(arr), 10));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  movl   $0xa,0x28(%rsp)
  movl   $0xa,0x2c(%rsp)
  movl   $0xb,0x30(%rsp)
  movl   $0xb,0x34(%rsp)
  movl   $0xc,0x38(%rsp)
  mov    %rsp,%rdi
  mov    $0xa,%edx
  mov    $0x3c,%esi
  call   <search@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 11, 11, 12};
  printf("%d\n", search(arr, sizeof(arr), 10));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x3c,%esi
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  movl   $0xc,0x38(%rsp)
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  add    $0x1,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xb0000000b,%rax
  mov    %rax,0x30(%rsp)
  call   <search@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 11, 11, 12};
  printf("%d\n", search(arr, sizeof(arr), 10));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x3c,%esi
  mov    $0xa,%edx
  movdqa D46(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    %rsp,%rdi
  movl   $0xc,0x38(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D39(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D19(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <search@plt>
  lea    D48(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D46
data_type: byte[16]
name: disassemble_data
arguments: tag: D12
data_type: byte[8]
name: disassemble_data
arguments: tag: D39
data_type: byte[16]
name: disassemble_data
arguments: tag: D19
data_type: byte[16]
name: disassemble_data
arguments: tag: D48
data_type: string

tool: {"D46": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D12": [0x0b,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D39": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D19": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: D48: %d


assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 11, 11, 12};
  printf("%d\n", search(arr, sizeof(arr), 10));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4e0,%rsp
  mov    %edi,-0x4d4(%rbp)
  mov    %esi,-0x4d8(%rbp)
  mov    %rdx,-0x4e0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L13
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L13:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x4e0(%rbp),%rdx
  mov    -0x4c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4c4(%rbp),%esi
  mov    -0x4e0(%rbp),%rcx
  lea    -0x4c0(%rbp),%rdx
  mov    -0x4d8(%rbp),%eax
  mov    %esi,%r9d
  mov    %rcx,%r8
  mov    $0x400,%ecx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <_log_aux@plt>
  mov    -0x4c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x4c0(%rbp),%rdx
  mov    -0x4d8(%rbp),%ecx
  mov    -0x4d4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <_log_die@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void log_err(int status, int priority, const char *format, ...) {
  va_list vargs;
  char msg[1024];
  va_start(vargs, format);
  _log_aux(0, priority, msg, sizeof(msg), format, vargs);
  va_end(vargs);
  _log_die(status, priority, msg);
  assert(1);
}
```