ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<remove_worddata_longs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <uncompress2@plt>
  mov    %eax,-0x2c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <uncompress2@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L10:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <UNPACKLONG2@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <compress3@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L7
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <progerr@plt>
L7:
  mov    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  cmp    %rax,%rdx
  je     L30
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <uncompress2@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <compress3@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L10
L30:
  nop
  mov    -0x18(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: Internal error in remove_worddata_longs

assistant: ```c
void remove_worddata_longs(unsigned char *worddata, int *sz_worddata) {
  unsigned char *src, *dst;
  unsigned int metaID, tfrequency, data_len;
  unsigned long nextposmetaID;
  src = worddata;
  tfrequency = uncompress2(&src);
  metaID = uncompress2(&src);
  dst = src;
  while (1) {
    nextposmetaID = UNPACKLONG2(src);
    src += sizeof(long);
    data_len = (int)nextposmetaID - (src - worddata);
    dst = compress3(data_len, dst);
    if (dst > src)
      progerr("Internal error in remove_worddata_longs");
    memmove(dst, src, data_len);
    src += data_len;
    dst += data_len;
    if ((src - worddata) == *sz_worddata)
      break;
    metaID = uncompress2(&src);
    dst = compress3(metaID, dst);
  }
  *sz_worddata = dst - worddata;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<remove_worddata_longs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <uncompress2@plt>
  mov    %rbx,%rdi
  call   <uncompress2@plt>
  mov    (%rsp),%r14
  lea    D1(%rip),%r13
  jmp    L39
L46:
  mov    %ebx,%edx
  mov    (%rsp),%rsi
  mov    %r14,%rdi
  call   <memmove@plt>
  mov    %ebx,%ebx
  mov    %rbx,%rax
  add    (%rsp),%rax
  mov    %rax,(%rsp)
  add    %r14,%rbx
  sub    %rbp,%rax
  movslq (%r12),%rdx
  cmp    %rdx,%rax
  je     L26
  mov    %rsp,%rdi
  call   <uncompress2@plt>
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <compress3@plt>
  mov    %rax,%r14
L39:
  mov    (%rsp),%rdi
  call   <UNPACKLONG2@plt>
  mov    %rax,%rbx
  mov    (%rsp),%rax
  add    $0x8,%rax
  mov    %rax,(%rsp)
  sub    %rbp,%rax
  sub    %eax,%ebx
  mov    %r14,%rsi
  mov    %ebx,%edi
  call   <compress3@plt>
  mov    %rax,%r14
  cmp    %rax,(%rsp)
  jae    L46
  mov    %r13,%rdi
  call   <progerr@plt>
  jmp    L46
L26:
  sub    %rbp,%rbx
  mov    %ebx,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: Internal error in remove_worddata_longs

assistant: ```c
void remove_worddata_longs(unsigned char *worddata, int *sz_worddata) {
  unsigned char *src, *dst;
  unsigned int metaID, tfrequency, data_len;
  unsigned long nextposmetaID;
  src = worddata;
  tfrequency = uncompress2(&src);
  metaID = uncompress2(&src);
  dst = src;
  while (1) {
    nextposmetaID = UNPACKLONG2(src);
    src += sizeof(long);
    data_len = (int)nextposmetaID - (src - worddata);
    dst = compress3(data_len, dst);
    if (dst > src)
      progerr("Internal error in remove_worddata_longs");
    memmove(dst, src, data_len);
    src += data_len;
    dst += data_len;
    if ((src - worddata) == *sz_worddata)
      break;
    metaID = uncompress2(&src);
    dst = compress3(metaID, dst);
  }
  *sz_worddata = dst - worddata;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_worddata_longs>:
  endbr64
  push   %r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,(%rsp)
  mov    %r13,%rdi
  call   <uncompress2@plt>
  mov    %r13,%rdi
  call   <uncompress2@plt>
  mov    (%rsp),%r15
  mov    %r15,%rdi
  jmp    L34
  nop
L41:
  mov    %ebx,%edx
  mov    %r15,%rdi
  add    %rbx,%r15
  call   <memmove@plt>
  mov    (%rsp),%rax
  movslq (%r12),%rdx
  add    %rbx,%rax
  mov    %rax,(%rsp)
  sub    %rbp,%rax
  cmp    %rdx,%rax
  je     L33
  mov    %r13,%rdi
  call   <uncompress2@plt>
  mov    %r15,%rsi
  mov    %eax,%edi
  call   <compress3@plt>
  mov    (%rsp),%rdi
  mov    %rax,%r15
L34:
  call   <UNPACKLONG2@plt>
  mov    (%rsp),%rcx
  mov    %r15,%rsi
  mov    %eax,%ebx
  lea    0x8(%rcx),%rdx
  mov    %rdx,(%rsp)
  sub    %rbp,%rdx
  sub    %edx,%ebx
  mov    %ebx,%edi
  call   <compress3@plt>
  mov    (%rsp),%rsi
  mov    %rax,%r15
  cmp    %rax,%rsi
  jae    L41
  mov    %r14,%rdi
  call   <progerr@plt>
  mov    (%rsp),%rsi
  jmp    L41
  nopl   0x0(%rax)
L33:
  sub    %rbp,%r15
  mov    %r15d,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: Internal error in remove_worddata_longs

assistant: ```c
void remove_worddata_longs(unsigned char *worddata, int *sz_worddata) {
  unsigned char *src, *dst;
  unsigned int metaID, tfrequency, data_len;
  unsigned long nextposmetaID;
  src = worddata;
  tfrequency = uncompress2(&src);
  metaID = uncompress2(&src);
  dst = src;
  while (1) {
    nextposmetaID = UNPACKLONG2(src);
    src += sizeof(long);
    data_len = (int)nextposmetaID - (src - worddata);
    dst = compress3(data_len, dst);
    if (dst > src)
      progerr("Internal error in remove_worddata_longs");
    memmove(dst, src, data_len);
    src += data_len;
    dst += data_len;
    if ((src - worddata) == *sz_worddata)
      break;
    metaID = uncompress2(&src);
    dst = compress3(metaID, dst);
  }
  *sz_worddata = dst - worddata;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remove_worddata_longs>:
  endbr64
  push   %r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,(%rsp)
  mov    %r13,%rdi
  call   <uncompress2@plt>
  mov    %r13,%rdi
  call   <uncompress2@plt>
  mov    (%rsp),%r15
  mov    %r15,%rdi
  jmp    L42
  nop
L1:
  mov    %r15,%rdi
  add    %rbx,%r15
  call   <memmove@plt>
  mov    (%rsp),%rax
  movslq (%r12),%rdx
  add    %rbx,%rax
  mov    %rax,(%rsp)
  sub    %rbp,%rax
  cmp    %rdx,%rax
  je     L27
  mov    %r13,%rdi
  call   <uncompress2@plt>
  mov    %r15,%rsi
  mov    %eax,%edi
  call   <compress3@plt>
  mov    (%rsp),%rdi
  mov    %rax,%r15
L42:
  call   <UNPACKLONG2@plt>
  mov    (%rsp),%rcx
  mov    %r15,%rsi
  mov    %eax,%ebx
  lea    0x8(%rcx),%rdx
  mov    %rdx,(%rsp)
  sub    %rbp,%rdx
  sub    %edx,%ebx
  mov    %ebx,%edi
  call   <compress3@plt>
  mov    (%rsp),%rsi
  mov    %ebx,%edx
  mov    %rax,%r15
  cmp    %rax,%rsi
  jae    L1
  mov    %r14,%rdi
  call   <progerr@plt>
  mov    (%rsp),%rsi
  mov    %ebx,%edx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L27:
  sub    %rbp,%r15
  mov    %r15d,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: Internal error in remove_worddata_longs

assistant: ```c
void remove_worddata_longs(unsigned char *worddata, int *sz_worddata) {
  unsigned char *src, *dst;
  unsigned int metaID, tfrequency, data_len;
  unsigned long nextposmetaID;
  src = worddata;
  tfrequency = uncompress2(&src);
  metaID = uncompress2(&src);
  dst = src;
  while (1) {
    nextposmetaID = UNPACKLONG2(src);
    src += sizeof(long);
    data_len = (int)nextposmetaID - (src - worddata);
    dst = compress3(data_len, dst);
    if (dst > src)
      progerr("Internal error in remove_worddata_longs");
    memmove(dst, src, data_len);
    src += data_len;
    dst += data_len;
    if ((src - worddata) == *sz_worddata)
      break;
    metaID = uncompress2(&src);
    dst = compress3(metaID, dst);
  }
  *sz_worddata = dst - worddata;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<init_curses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D38(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    D67(%rip),%rax
  mov    (%rax),%rdx
  mov    D38(%rip),%rax
  mov    %rdx,(%rax)
  mov    D67(%rip),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atexit>
  mov    D51(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <keypad@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%eax
  call   <raw@plt>
  nop
  leave
  ret
```

assistant: ```c
void init_curses(void) {
  FILE *temp = stdout;
  stdout = stderr;
  stderr = temp;
  atexit((void (*)(void))endwin);
  signal(SIGSEGV, exit);
  initscr();
  curs_set(0);
  keypad(stdscr, true);
  noecho();
  raw();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_curses>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rdx
  mov    (%rdx),%rcx
  mov    D1(%rip),%rax
  mov    (%rax),%rsi
  mov    %rsi,(%rdx)
  mov    %rcx,(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%rdi
  call   <atexit>
  mov    D31(%rip),%rax
  mov    (%rax),%esi
  mov    D45(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x1,%esi
  mov    D26(%rip),%rax
  mov    (%rax),%edi
  call   <keypad@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%eax
  call   <raw@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_curses(void) {
  FILE *temp = stdout;
  stdout = stderr;
  stderr = temp;
  atexit((void (*)(void))endwin);
  signal(SIGSEGV, exit);
  initscr();
  curs_set(0);
  keypad(stdscr, true);
  noecho();
  raw();
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_curses>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rdx
  mov    D13(%rip),%rax
  mov    (%rdx),%rcx
  mov    (%rax),%rsi
  mov    %rcx,(%rax)
  mov    D46(%rip),%rax
  mov    %rsi,(%rdx)
  mov    (%rax),%rdi
  call   <atexit>
  mov    D29(%rip),%rax
  mov    (%rax),%esi
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %edi,%edi
  call   <curs_set@plt>
  mov    D38(%rip),%rax
  mov    $0x1,%esi
  mov    (%rax),%edi
  call   <keypad@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <raw@plt>
```

assistant: ```c
void init_curses(void) {
  FILE *temp = stdout;
  stdout = stderr;
  stderr = temp;
  atexit((void (*)(void))endwin);
  signal(SIGSEGV, exit);
  initscr();
  curs_set(0);
  keypad(stdscr, true);
  noecho();
  raw();
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_curses>:
  endbr64
  sub    $0x8,%rsp
  mov    D51(%rip),%rdx
  mov    D37(%rip),%rax
  mov    (%rdx),%rcx
  mov    (%rax),%rsi
  mov    %rcx,(%rax)
  mov    D33(%rip),%rax
  mov    %rsi,(%rdx)
  mov    (%rax),%rdi
  call   <atexit>
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %edi,%edi
  call   <curs_set@plt>
  mov    D30(%rip),%rax
  mov    $0x1,%esi
  mov    (%rax),%edi
  call   <keypad@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <raw@plt>
```

assistant: ```c
void init_curses(void) {
  FILE *temp = stdout;
  stdout = stderr;
  stderr = temp;
  atexit((void (*)(void))endwin);
  signal(SIGSEGV, exit);
  initscr();
  curs_set(0);
  keypad(stdscr, true);
  noecho();
  raw();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gsw_sstar_from_sa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <gsw_saar@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd D42(%rip),%xmm0
  jp     L15
  movsd  -0x8(%rbp),%xmm0
  ucomisd D42(%rip),%xmm0
  jne    L15
  movsd  -0x8(%rbp),%xmm0
  jmp    L21
L15:
  movsd  -0x8(%rbp),%xmm1
  movsd  D5(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D47(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm2
  movsd  D47(%rip),%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
L21:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D42
type_guessed: f64
name: parse_data
arguments: tag: D5
type_guessed: f64
name: parse_data
arguments: tag: D47
type_guessed: f64

tool: D42: 9000000000000000.0

tool: D5: 0.35

tool: D47: 1

assistant: ```c
double gsw_sstar_from_sa(double sa, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sa * (1e0 - 0.35e0 * saar) / (1e0 + saar));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gsw_sstar_from_sa>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <gsw_saar@plt>
  ucomisd D2(%rip),%xmm0
  jp     L12
  je     L1
L12:
  movapd %xmm0,%xmm3
  mulsd  D29(%rip),%xmm3
  movsd  D25(%rip),%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  movq   %rbx,%xmm4
  mulsd  %xmm4,%xmm2
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
L1:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: f64
name: disassemble_data
arguments: label: D29
datatype: f64
name: disassemble_data
arguments: label: D25
datatype: f64

tool: D2: 9000000000000000.0

tool: D29: 0.35

tool: D25: 1

assistant: ```c
double gsw_sstar_from_sa(double sa, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sa * (1e0 - 0.35e0 * saar) / (1e0 + saar));
}
```
user: Translate the below assembly code into C programming language:

```asm
<gsw_sstar_from_sa>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <gsw_saar@plt>
  ucomisd D21(%rip),%xmm0
  jp     L8
  je     L9
L8:
  movsd  D2(%rip),%xmm3
  movsd  D13(%rip),%xmm1
  mulsd  %xmm0,%xmm3
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm2
  mulsd  0x8(%rsp),%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
L9:
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_guessed: f64
name: parse_data
arguments: tag: D2
type_guessed: f64
name: parse_data
arguments: tag: D13
type_guessed: f64

tool: D21: 9000000000000000.0

tool: D2: 0.35

tool: D13: 1

assistant: ```c
double gsw_sstar_from_sa(double sa, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sa * (1e0 - 0.35e0 * saar) / (1e0 + saar));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gsw_sstar_from_sa>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <gsw_saar@plt>
  ucomisd D20(%rip),%xmm0
  jp     L0
  je     L3
L0:
  movsd  D29(%rip),%xmm3
  movsd  D9(%rip),%xmm1
  mulsd  %xmm0,%xmm3
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm2
  mulsd  0x8(%rsp),%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
L3:
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D20
type_infered: f64
name: unpack_data
arguments: label: D29
type_infered: f64
name: unpack_data
arguments: label: D9
type_infered: f64

tool: D20: 9000000000000000.0

tool: D29: 0.35

tool: D9: 1

assistant: ```c
double gsw_sstar_from_sa(double sa, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sa * (1e0 - 0.35e0 * saar) / (1e0 + saar));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hflip_dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L25
L29:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  jmp    L22
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L3
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L29
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hflip_dmatrix(double **S, long nrl, long nrh, long ncl, long nch, double **D) {
  int i, j, n = ncl + nch;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      D[i][n - j] = S[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hflip_dmatrix>:
  endbr64
  mov    %rdx,%r10
  lea    (%rcx,%r8,1),%eax
  movslq %esi,%rdx
  cmp    %rdx,%r10
  jl     L10
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%rdx
  lea    (%rdi,%rdx,1),%rsi
  lea    (%r9,%rdx,1),%rdi
  lea    0x8(%rbx,%r10,8),%rbp
  movslq %ecx,%rbx
  shl    $0x3,%rbx
  lea    0x8(,%r8,8),%r10
  cltq
  lea    0x0(,%rax,8),%r9
  movslq %ecx,%r11
L4:
  cmp    %r11,%r8
  jl     L33
  mov    %rbx,%rax
L35:
  mov    (%rsi),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  mov    %r9,%rdx
  sub    %rax,%rdx
  mov    (%rdi),%rcx
  movsd  %xmm0,(%rcx,%rdx,1)
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L35
L33:
  add    $0x8,%rsi
  add    $0x8,%rdi
  cmp    %rbp,%rsi
  jne    L4
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
void hflip_dmatrix(double **S, long nrl, long nrh, long ncl, long nch, double **D) {
  int i, j, n = ncl + nch;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      D[i][n - j] = S[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hflip_dmatrix>:
  endbr64
  movslq %esi,%rsi
  lea    (%rcx,%r8,1),%eax
  cmp    %rsi,%rdx
  jl     L23
  mov    %rdi,%r11
  cltq
  movslq %ecx,%rdi
  push   %r12
  sub    %rdi,%rax
  push   %rbp
  shl    $0x3,%rsi
  lea    0x0(,%rdi,8),%rbp
  push   %rbx
  lea    0x0(,%rax,8),%r10
  lea    0x8(,%rdx,8),%rbx
  lea    0x8(,%r8,8),%r12
  nopl   0x0(%rax,%rax,1)
L15:
  cmp    %rdi,%r8
  jl     L12
  mov    (%r11,%rsi,1),%rcx
  mov    (%r9,%rsi,1),%rdx
  lea    (%rcx,%rbp,1),%rax
  add    %r10,%rdx
  add    %r12,%rcx
  nop
L38:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  sub    $0x8,%rdx
  movsd  %xmm0,0x8(%rdx)
  cmp    %rcx,%rax
  jne    L38
L12:
  add    $0x8,%rsi
  cmp    %rbx,%rsi
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  ret
```

assistant: ```c
void hflip_dmatrix(double **S, long nrl, long nrh, long ncl, long nch, double **D) {
  int i, j, n = ncl + nch;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      D[i][n - j] = S[i][j];
    }
  }
}
```