ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bilinear_interpolation_at>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  movss  %xmm0,0x20(%rsp)
  movss  %xmm1,0x24(%rsp)
  cvttss2si %xmm0,%eax
  mov    %eax,(%rsp)
  test   %r8d,%r8d
  jle    L4
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%r14d
  mov    %r8d,%ebp
  cvttss2si %xmm1,%r15d
  mov    %r8d,%edx
  mov    %rdx,0x28(%rsp)
  mov    $0x0,%ebx
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
L1:
  sub    $0x8,%rsp
  push   %rbx
  mov    %r15d,%r9d
  mov    0x10(%rsp),%r8d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <getsamplen@plt>
  movss  %xmm0,0x1c(%rsp)
  mov    %ebx,(%rsp)
  mov    %r15d,%r9d
  mov    0x14(%rsp),%r8d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <getsamplen@plt>
  movss  %xmm0,0x20(%rsp)
  lea    0x1(%r15),%eax
  mov    %ebx,(%rsp)
  mov    %eax,0x18(%rsp)
  mov    %eax,%r9d
  mov    0x10(%rsp),%r8d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <getsamplen@plt>
  movss  %xmm0,0x24(%rsp)
  mov    %ebx,(%rsp)
  mov    0x18(%rsp),%r9d
  mov    0x14(%rsp),%r8d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <getsamplen@plt>
  movaps %xmm0,%xmm3
  pxor   %xmm2,%xmm2
  cvtsi2ss %r15d,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  movss  0x34(%rsp),%xmm5
  subss  %xmm2,%xmm5
  movss  0x30(%rsp),%xmm4
  subss  %xmm1,%xmm4
  movss  0x24(%rsp),%xmm2
  movss  0x20(%rsp),%xmm1
  movss  0x1c(%rsp),%xmm0
  call   <evaluate_bilinear_cell@plt>
  mov    0x28(%rsp),%rax
  movss  %xmm0,(%rax,%rbx,4)
  add    $0x1,%rbx
  add    $0x10,%rsp
  cmp    0x28(%rsp),%rbx
  jne    L1
L4:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bilinear_interpolation_at(float *result, float *x, int w, int h, int pd, float p, float q) {
  int ip = p;
  int iq = q;
  for (int l = 0; l < (pd); l++) {
    float a = getsamplen(x, w, h, pd, ip, iq, l);
    float b = getsamplen(x, w, h, pd, ip + 1, iq, l);
    float c = getsamplen(x, w, h, pd, ip, iq + 1, l);
    float d = getsamplen(x, w, h, pd, ip + 1, iq + 1, l);
    float r = evaluate_bilinear_cell(a, b, c, d, p - ip, q - iq);
    result[l] = r;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bilinear_interpolation_at>:
  endbr64
  push   %r15
  cvttss2si %xmm0,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %eax,0x8(%rsp)
  movss  %xmm0,0x20(%rsp)
  movss  %xmm1,0x24(%rsp)
  test   %r8d,%r8d
  jle    L18
  cvttss2si %xmm1,%r15d
  pxor   %xmm3,%xmm3
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%r14d
  lea    0x1(%rax),%edx
  movslq %r8d,%rsi
  mov    %r8d,%ebp
  mov    %edx,0xc(%rsp)
  xor    %ebx,%ebx
  mov    %rsi,0x30(%rsp)
  cvtsi2ss %r15d,%xmm3
  lea    0x1(%r15),%ecx
  mov    %ecx,0x10(%rsp)
  movss  %xmm3,0x3c(%rsp)
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm3
  movss  %xmm3,0x38(%rsp)
  nopl   0x0(%rax,%rax,1)
L3:
  sub    $0x8,%rsp
  mov    %r15d,%r9d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  push   %rbx
  mov    0x18(%rsp),%r8d
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <getsamplen@plt>
  mov    0x1c(%rsp),%r8d
  mov    %r15d,%r9d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ebx,(%rsp)
  movss  %xmm0,0x2c(%rsp)
  call   <getsamplen@plt>
  mov    0x20(%rsp),%r9d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    0x18(%rsp),%r8d
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ebx,(%rsp)
  movss  %xmm0,0x28(%rsp)
  call   <getsamplen@plt>
  mov    0x20(%rsp),%r9d
  mov    %r14d,%edx
  mov    %ebp,%ecx
  mov    0x1c(%rsp),%r8d
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ebx,(%rsp)
  movss  %xmm0,0x24(%rsp)
  call   <getsamplen@plt>
  movss  0x34(%rsp),%xmm5
  movss  0x30(%rsp),%xmm4
  movss  0x2c(%rsp),%xmm6
  subss  0x4c(%rsp),%xmm5
  movaps %xmm0,%xmm3
  subss  0x48(%rsp),%xmm4
  movss  0x24(%rsp),%xmm2
  movss  0x28(%rsp),%xmm1
  movaps %xmm6,%xmm0
  call   <evaluate_bilinear_cell@plt>
  mov    0x38(%rsp),%rax
  movss  %xmm0,(%rax,%rbx,4)
  add    $0x1,%rbx
  pop    %rax
  pop    %rdx
  cmp    0x30(%rsp),%rbx
  jne    L3
L18:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bilinear_interpolation_at(float *result, float *x, int w, int h, int pd, float p, float q) {
  int ip = p;
  int iq = q;
  for (int l = 0; l < (pd); l++) {
    float a = getsamplen(x, w, h, pd, ip, iq, l);
    float b = getsamplen(x, w, h, pd, ip + 1, iq, l);
    float c = getsamplen(x, w, h, pd, ip, iq + 1, l);
    float d = getsamplen(x, w, h, pd, ip + 1, iq + 1, l);
    float r = evaluate_bilinear_cell(a, b, c, d, p - ip, q - iq);
    result[l] = r;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bilinear_interpolation_at>:
  endbr64
  push   %r15
  cvttss2si %xmm0,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %eax,0x8(%rsp)
  movss  %xmm0,0x20(%rsp)
  movss  %xmm1,0x24(%rsp)
  test   %r8d,%r8d
  jle    L12
  cvttss2si %xmm1,%r15d
  pxor   %xmm3,%xmm3
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%r14d
  lea    0x1(%rax),%edx
  movslq %r8d,%rsi
  mov    %r8d,%ebp
  mov    %edx,0xc(%rsp)
  xor    %ebx,%ebx
  mov    %rsi,0x30(%rsp)
  cvtsi2ss %r15d,%xmm3
  lea    0x1(%r15),%ecx
  mov    %ecx,0x10(%rsp)
  movss  %xmm3,0x3c(%rsp)
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm3
  movss  %xmm3,0x38(%rsp)
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  mov    %r15d,%r9d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  push   %rbx
  mov    0x18(%rsp),%r8d
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <getsamplen@plt>
  mov    0x1c(%rsp),%r8d
  mov    %r15d,%r9d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ebx,(%rsp)
  movss  %xmm0,0x2c(%rsp)
  call   <getsamplen@plt>
  mov    0x20(%rsp),%r9d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    0x18(%rsp),%r8d
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ebx,(%rsp)
  movss  %xmm0,0x28(%rsp)
  call   <getsamplen@plt>
  mov    0x20(%rsp),%r9d
  mov    %r14d,%edx
  mov    %ebp,%ecx
  mov    0x1c(%rsp),%r8d
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ebx,(%rsp)
  movss  %xmm0,0x24(%rsp)
  call   <getsamplen@plt>
  movss  0x34(%rsp),%xmm5
  movss  0x30(%rsp),%xmm4
  movss  0x2c(%rsp),%xmm6
  subss  0x4c(%rsp),%xmm5
  movaps %xmm0,%xmm3
  subss  0x48(%rsp),%xmm4
  movss  0x24(%rsp),%xmm2
  movss  0x28(%rsp),%xmm1
  movaps %xmm6,%xmm0
  call   <evaluate_bilinear_cell@plt>
  mov    0x38(%rsp),%rax
  movss  %xmm0,(%rax,%rbx,4)
  add    $0x1,%rbx
  pop    %rax
  pop    %rdx
  cmp    %rbx,0x30(%rsp)
  jne    L0
L12:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bilinear_interpolation_at(float *result, float *x, int w, int h, int pd, float p, float q) {
  int ip = p;
  int iq = q;
  for (int l = 0; l < (pd); l++) {
    float a = getsamplen(x, w, h, pd, ip, iq, l);
    float b = getsamplen(x, w, h, pd, ip + 1, iq, l);
    float c = getsamplen(x, w, h, pd, ip, iq + 1, l);
    float d = getsamplen(x, w, h, pd, ip + 1, iq + 1, l);
    float r = evaluate_bilinear_cell(a, b, c, d, p - ip, q - iq);
    result[l] = r;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_decompose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x28(%rbp)
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L17:
  movl   $0x0,-0xc(%rbp)
  jmp    L84
L169:
  addq   $0x1,-0x8(%rbp)
L84:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L169
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L86
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L140
  movl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L63
L140:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L63
L165:
  cmpl   $0x0,-0xc(%rbp)
  jne    L88
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L81
L88:
  cmpl   $0x0,-0xc(%rbp)
  je     L168
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L163
L168:
  addq   $0x1,-0x8(%rbp)
L63:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L165
  cmpl   $0x0,-0xc(%rbp)
  jne    L165
  jmp    L153
L81:
  nop
  jmp    L153
L163:
  nop
L153:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L176
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L17
  jmp    L39
L86:
  nop
  jmp    L39
L176:
  nop
L39:
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int string_decompose(char **v, char *s, char sep, int max) {
  int i = 0, dq;
  char *ss = s;
  do {
    dq = 0;
    while (*ss == sep)
      ss++;
    if (*ss == 0)
      break;
    if (*ss == '\"') {
      dq = 1;
      v[i++] = ++ss;
    } else
      v[i++] = ss;
    while (*ss != sep || dq) {
      if (dq == 0 && *ss == 0)
        break;
      if (dq && *ss == '\"')
        break;
      ss++;
    }
    if (*ss == 0)
      break;
    *(ss++) = 0;
  } while (i < max);
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_decompose>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %ecx,%r11d
  mov    %edx,%ecx
  mov    $0x1,%r9d
  mov    $0x0,%edi
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  jmp    L56
L152:
  mov    %edx,%eax
  jmp    L114
L130:
  mov    %r9d,%r8d
  mov    %rsi,(%r10,%rdi,8)
  movzbl (%rsi),%eax
  cmp    %al,%cl
  je     L112
  mov    %rsi,%rdx
  mov    %r13d,%esi
  mov    %r12d,%r14d
  jmp    L122
L112:
  mov    %rsi,%rdx
L8:
  test   %al,%al
  je     L90
L102:
  lea    0x1(%rdx),%rsi
  movb   $0x0,(%rdx)
  add    $0x1,%rdi
  add    $0x1,%r9d
  cmp    %r8d,%r11d
  jle    L90
L56:
  mov    %edi,%r8d
  movzbl (%rsi),%edx
  cmp    %dl,%cl
  jne    L152
L138:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  cmp    %dl,%al
  je     L138
L114:
  test   %al,%al
  je     L90
  cmp    $0x22,%al
  jne    L130
  lea    0x1(%rsi),%rdx
  mov    %r9d,%r8d
  mov    %rdx,(%r10,%rdi,8)
  movzbl 0x1(%rsi),%eax
  mov    %ebp,%esi
  mov    %ebx,%r14d
L122:
  test   %al,%al
  jne    L149
  test   %r14d,%r14d
  je     L90
L149:
  cmp    $0x22,%al
  jne    L96
  test   %sil,%sil
  jne    L102
L96:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  cmp    %cl,%al
  jne    L122
  test   %sil,%sil
  jne    L122
  jmp    L8
L90:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int string_decompose(char **v, char *s, char sep, int max) {
  int i = 0, dq;
  char *ss = s;
  do {
    dq = 0;
    while (*ss == sep)
      ss++;
    if (*ss == 0)
      break;
    if (*ss == '\"') {
      dq = 1;
      v[i++] = ++ss;
    } else
      v[i++] = ss;
    while (*ss != sep || dq) {
      if (dq == 0 && *ss == 0)
        break;
      if (dq && *ss == '\"')
        break;
      ss++;
    }
    if (*ss == 0)
      break;
    *(ss++) = 0;
  } while (i < max);
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_decompose>:
  endbr64
  xor    %r9d,%r9d
  jmp    L57
  nopl   0x0(%rax)
L16:
  add    $0x1,%rsi
L57:
  movzbl (%rsi),%eax
  cmp    %dl,%al
  je     L16
  test   %al,%al
  je     L80
  add    $0x1,%r9d
  cmp    $0x22,%al
  jne    L31
  lea    0x1(%rsi),%rax
  mov    $0x1,%r8d
L78:
  mov    %rax,(%rdi)
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L62:
  test   %r8d,%r8d
  jne    L33
  test   %sil,%sil
  je     L80
L81:
  add    $0x1,%rax
L45:
  movzbl (%rax),%esi
  cmp    %dl,%sil
  jne    L62
  test   %r8d,%r8d
  je     L88
L33:
  cmp    $0x22,%sil
  jne    L81
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  add    $0x8,%rdi
  cmp    %r9d,%ecx
  jg     L57
L80:
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L88:
  test   %dl,%dl
  je     L80
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  add    $0x8,%rdi
  cmp    %r9d,%ecx
  jg     L57
  jmp    L80
  xchg   %ax,%ax
L31:
  mov    %rsi,%rax
  xor    %r8d,%r8d
  jmp    L78
```

assistant: ```c
int string_decompose(char **v, char *s, char sep, int max) {
  int i = 0, dq;
  char *ss = s;
  do {
    dq = 0;
    while (*ss == sep)
      ss++;
    if (*ss == 0)
      break;
    if (*ss == '\"') {
      dq = 1;
      v[i++] = ++ss;
    } else
      v[i++] = ss;
    while (*ss != sep || dq) {
      if (dq == 0 && *ss == 0)
        break;
      if (dq && *ss == '\"')
        break;
      ss++;
    }
    if (*ss == 0)
      break;
    *(ss++) = 0;
  } while (i < max);
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_decompose>:
  endbr64
  xor    %r8d,%r8d
  jmp    L75
  nopl   0x0(%rax)
L122:
  add    $0x1,%rsi
L75:
  movzbl (%rsi),%eax
  cmp    %dl,%al
  je     L122
  test   %al,%al
  je     L43
  add    $0x1,%r8d
  cmp    $0x22,%al
  jne    L10
  lea    0x1(%rsi),%rax
  mov    %rax,(%rdi)
  cmpb   $0x22,0x1(%rsi)
  je     L78
  nopl   0x0(%rax)
L52:
  add    $0x1,%rax
  cmpb   $0x22,(%rax)
  jne    L52
L78:
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  add    $0x8,%rdi
  cmp    %r8d,%ecx
  jg     L75
L43:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L10:
  mov    %rsi,(%rdi)
  mov    %rsi,%rax
  jmp    L17
L114:
  test   %sil,%sil
  je     L43
  add    $0x1,%rax
L17:
  movzbl (%rax),%esi
  cmp    %dl,%sil
  jne    L114
  test   %dl,%dl
  je     L43
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  add    $0x8,%rdi
  cmp    %r8d,%ecx
  jg     L75
  jmp    L43
```

assistant: ```c
int string_decompose(char **v, char *s, char sep, int max) {
  int i = 0, dq;
  char *ss = s;
  do {
    dq = 0;
    while (*ss == sep)
      ss++;
    if (*ss == 0)
      break;
    if (*ss == '\"') {
      dq = 1;
      v[i++] = ++ss;
    } else
      v[i++] = ss;
    while (*ss != sep || dq) {
      if (dq == 0 && *ss == 0)
        break;
      if (dq && *ss == '\"')
        break;
      ss++;
    }
    if (*ss == 0)
      break;
    *(ss++) = 0;
  } while (i < max);
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<good_modulus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L51
  mov    $0x0,%eax
  jmp    L35
L51:
  cmpl   $0x0,-0x18(%rbp)
  jg     L29
  mov    -0x18(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <good_modulus>
  jmp    L35
L29:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L37
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L26
L37:
  mov    -0x4(%rbp),%eax
L26:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
L35:
  leave
  ret
```

assistant: ```c
int good_modulus(int n, int p) {
  if (!p)
    return 0;
  if (p < 1)
    return good_modulus(n, -p);
  int r = n % p;
  r = r < 0 ? r + p : r;
  assert(r >= 0);
  assert(r < p);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<good_modulus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %esi,%esi
  je     L3
  mov    %esi,%ebx
  jle    L15
  mov    %edi,%eax
  cltd
  idiv   %esi
  lea    (%rdx,%rsi,1),%ebp
  test   %edx,%edx
  cmovns %edx,%ebp
  mov    %ebp,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    %ebx,%ebp
  setl   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L3:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  neg    %esi
  call   <good_modulus>
  mov    %eax,%ebp
  jmp    L3
```

assistant: ```c
int good_modulus(int n, int p) {
  if (!p)
    return 0;
  if (p < 1)
    return good_modulus(n, -p);
  int r = n % p;
  r = r < 0 ? r + p : r;
  assert(r >= 0);
  assert(r < p);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<good_modulus>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L6
  mov    %esi,%ebx
  mov    %edi,%eax
  neg    %ebx
  cmovs  %esi,%ebx
  cltd
  idiv   %ebx
  test   %edx,%edx
  lea    (%rdx,%rbx,1),%r12d
  cmovns %edx,%r12d
  mov    %r12d,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebx,%r12d
  setl   %dil
  call   <assert@plt>
L15:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L6:
  xor    %r12d,%r12d
  jmp    L15
```

assistant: ```c
int good_modulus(int n, int p) {
  if (!p)
    return 0;
  if (p < 1)
    return good_modulus(n, -p);
  int r = n % p;
  r = r < 0 ? r + p : r;
  assert(r >= 0);
  assert(r < p);
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<good_modulus>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L3
  mov    %esi,%ebx
  mov    %edi,%eax
  neg    %ebx
  cmovs  %esi,%ebx
  cltd
  idiv   %ebx
  test   %edx,%edx
  lea    (%rdx,%rbx,1),%r12d
  cmovns %edx,%r12d
  mov    %r12d,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebx,%r12d
  setl   %dil
  call   <assert@plt>
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L3:
  xor    %r12d,%r12d
  jmp    L14
```

assistant: ```c
int good_modulus(int n, int p) {
  if (!p)
    return 0;
  if (p < 1)
    return good_modulus(n, -p);
  int r = n % p;
  r = r < 0 ? r + p : r;
  assert(r >= 0);
  assert(r < p);
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_y>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L64:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L50
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L50
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
  jmp    L33
L50:
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
  jmp    L48
L33:
  mov    -0x24(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L64
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L41
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L41
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L48
L41:
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
L48:
  pop    %rbp
  ret
```

assistant: ```c
void set_y(int *y, char *str, int len) {
  int i;
  *y = 0;
  i = 0;
  while (i < len - 3) {
    if (str[i] >= '0' && str[i] <= '9') {
      *y *= 10;
      *y += str[i] - '0';
    } else {
      *y = -1;
      return;
    }
    i++;
  }
  if (str[i] == str[i + 1] || str[i] == str[i + 2] || str[i + 1] == str[i + 2])
    *y = -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_y>:
  endbr64
  mov    %rdi,%rcx
  movl   $0x0,(%rdi)
  cmp    $0x3,%edx
  jle    L4
  lea    -0x4(%rdx),%r8d
  add    $0x2,%r8
  mov    $0x1,%eax
L18:
  movzbl -0x1(%rsi,%rax,1),%edi
  lea    -0x30(%rdi),%edx
  cmp    $0x9,%dl
  ja     L15
  mov    (%rcx),%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %edx,(%rcx)
  movsbl -0x1(%rsi,%rax,1),%edi
  lea    -0x30(%rdx,%rdi,1),%edx
  mov    %edx,(%rcx)
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L18
L5:
  movslq %edx,%rdx
  movzbl (%rsi,%rdx,1),%edi
  movzbl 0x1(%rsi,%rdx,1),%eax
  cmp    %al,%dil
  je     L20
  movzbl 0x2(%rsi,%rdx,1),%edx
  cmp    %dl,%al
  je     L20
  cmp    %dl,%dil
  jne    L51
L20:
  movl   $0xffffffff,(%rcx)
L51:
  ret
L15:
  movl   $0xffffffff,(%rcx)
  ret
L4:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
void set_y(int *y, char *str, int len) {
  int i;
  *y = 0;
  i = 0;
  while (i < len - 3) {
    if (str[i] >= '0' && str[i] <= '9') {
      *y *= 10;
      *y += str[i] - '0';
    } else {
      *y = -1;
      return;
    }
    i++;
  }
  if (str[i] == str[i + 1] || str[i] == str[i + 2] || str[i + 1] == str[i + 2])
    *y = -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_y>:
  endbr64
  movl   $0x0,(%rdi)
  mov    %rdi,%rcx
  cmp    $0x3,%edx
  jle    L30
  lea    -0x4(%rdx),%r8d
  mov    $0x1,%eax
  add    $0x2,%r8
  jmp    L15
  nopl   0x0(%rax)
L73:
  mov    (%rcx),%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %edx,(%rcx)
  movsbl -0x1(%rsi,%rax,1),%edi
  lea    -0x30(%rdx,%rdi,1),%edx
  mov    %edx,(%rcx)
  movslq %eax,%rdx
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L58
L15:
  movzbl -0x1(%rsi,%rax,1),%edi
  lea    -0x30(%rdi),%edx
  cmp    $0x9,%dl
  jbe    L73
L18:
  movl   $0xffffffff,(%rcx)
  ret
  nopl   0x0(%rax)
L58:
  lea    (%rsi,%rdx,1),%rdi
  lea    0x1(%rdx),%rax
L21:
  movzbl (%rdi),%edi
  movzbl (%rsi,%rax,1),%eax
  cmp    %al,%dil
  je     L18
  movzbl 0x2(%rsi,%rdx,1),%edx
  cmp    %dl,%al
  je     L18
  cmp    %dl,%dil
  je     L18
  ret
L30:
  mov    %rsi,%rdi
  mov    $0x1,%eax
  xor    %edx,%edx
  jmp    L21
```

assistant: ```c
void set_y(int *y, char *str, int len) {
  int i;
  *y = 0;
  i = 0;
  while (i < len - 3) {
    if (str[i] >= '0' && str[i] <= '9') {
      *y *= 10;
      *y += str[i] - '0';
    } else {
      *y = -1;
      return;
    }
    i++;
  }
  if (str[i] == str[i + 1] || str[i] == str[i + 2] || str[i + 1] == str[i + 2])
    *y = -1;
}
```