user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbp
  cmp    $0x2,%edi
  jle    L9
L3:
  mov    0x8(%rbp),%rdi
  call   <atol@plt>
  mov    %rax,%rbx
  mov    0x10(%rbp),%rdi
  call   <atof@plt>
  movapd %xmm0,%xmm5
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm2,%xmm2
  cvtsi2sd %rbx,%xmm2
  movapd %xmm0,%xmm6
  divsd  %xmm2,%xmm6
  movsd  %xmm6,0x10(%rsp)
  addsd  D54(%rip),%xmm0
  divsd  %xmm0,%xmm5
  movsd  %xmm5,(%rsp)
  cmp    $0x1,%rbx
  jle    L13
  lea    0x1(%rbx),%rdx
  mov    $0x2,%eax
L37:
  movsd  (%rsp),%xmm1
  mulsd  0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L37
L13:
  movsd  D54(%rip),%xmm1
  movapd %xmm1,%xmm3
  movsd  0x10(%rsp),%xmm7
  subsd  %xmm7,%xmm3
  movsd  (%rsp),%xmm6
  mulsd  %xmm6,%xmm7
  movapd %xmm7,%xmm0
  addsd  %xmm3,%xmm0
  movapd %xmm6,%xmm5
  divsd  %xmm0,%xmm5
  movq   %xmm5,%rbp
  mulsd  %xmm3,%xmm2
  movapd %xmm5,%xmm3
  divsd  %xmm2,%xmm3
  addsd  %xmm1,%xmm3
  movsd  %xmm3,0x18(%rsp)
  mov    %rbx,%rsi
  lea    D87(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D127(%rip),%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm0
  lea    D90(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  lea    D107(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D79(%rip),%rdi
  call   <puts@plt>
  movsd  (%rsp),%xmm0
  lea    D106(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movq   %rbp,%xmm0
  lea    D118(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm0
  lea    D78(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  0x18(%rsp),%xmm2
  movapd %xmm2,%xmm0
  lea    D126(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    (%rsi),%rsi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_tag: D54
type_guessed: byte[8]
name: unpack_data
arguments: data_tag: D87
type_guessed: string
name: unpack_data
arguments: data_tag: D127
type_guessed: string
name: unpack_data
arguments: data_tag: D90
type_guessed: string
name: unpack_data
arguments: data_tag: D107
type_guessed: string
name: unpack_data
arguments: data_tag: D79
type_guessed: string
name: unpack_data
arguments: data_tag: D106
type_guessed: string
name: unpack_data
arguments: data_tag: D118
type_guessed: string
name: unpack_data
arguments: data_tag: D78
type_guessed: string
name: unpack_data
arguments: data_tag: D126
type_guessed: string
name: unpack_data
arguments: data_tag: D50
type_guessed: string
name: unpack_data
arguments: data_tag: D45
type_guessed: string

tool: {"D54": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D87:   %ld Server System


tool: D127:   -----------------

tool: D90:   Traffic intensity:  %5.5lf


tool: D107:   Server utilization: %5.5lf


tool: D79:   

tool: D106:   Erlang B  (loss  prob): %5.5lf


tool: D118:   Erlang C  (queue prob): %5.5lf


tool: D78:   M/M/m    Normalized RT: %5.5lf


tool: D126:   M/M/m    No. in System: %5.5lf


tool: D50: Usage: %s servers traffic


tool: D45: NOTE:Per server load = traffic/servers

assistant: ```c
main(int argc, char *argv[]) {
  double erlangB;
  double erlangC;
  double traffic;
  double eb;
  double rho;
  double nrt;
  double ql;
  long m;
  long servers;
  if (argc < 3) {
    printf("Usage: %s servers traffic\n", argv[0]);
    printf("NOTE:Per server load = traffic/servers\n");
    exit(1);
  }
  servers = atol(*++argv);
  traffic = atof(*++argv);
  rho = traffic / servers;
  erlangB = traffic / (1 + traffic);
  for (m = 2; m <= servers; m++) {
    eb = erlangB;
    erlangB = eb * traffic / (m + eb * traffic);
  }
  erlangC = erlangB / (1 - rho + rho * erlangB);
  nrt = 1 + erlangC / (servers * (1 - rho));
  ql = traffic * nrt;
  printf("  %ld Server System\n", servers);
  printf("  -----------------\n");
  printf("  Traffic intensity:  %5.5lf\n", traffic);
  printf("  Server utilization: %5.5lf\n", rho);
  printf("  \n");
  printf("  Erlang B  (loss  prob): %5.5lf\n", erlangB);
  printf("  Erlang C  (queue prob): %5.5lf\n", erlangC);
  printf("  M/M/m    Normalized RT: %5.5lf\n", nrt);
  printf("  M/M/m    No. in System: %5.5lf\n", ql);
}
```