ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strjoin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L49
  cmpq   $0x0,-0x30(%rbp)
  jne    L10
L49:
  mov    $0x0,%eax
  jmp    L42
L10:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L42
L1:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
L34:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  jmp    L72
L52:
  mov    -0x20(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
L72:
  mov    -0x20(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L42:
  leave
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  size_t len_s1;
  size_t len_s2;
  char *new;
  size_t i;
  new = NULL;
  i = 0;
  if (s1 == NULL || s2 == NULL)
    return (NULL);
  len_s1 = ft_strlen(s1);
  len_s2 = ft_strlen(s2);
  if ((new = (char *)malloc((sizeof(char) * (len_s1 + len_s2)) + 1)) == NULL)
    return (NULL);
  while (s1[i] != '\0') {
    new[i] = s1[i];
    i++;
  }
  while (s2[i - len_s1] != '\0') {
    new[i] = s2[i - len_s1];
    i++;
  }
  new[i] = '\0';
  return (new);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strjoin>:
  endbr64
  test   %rdi,%rdi
  je     L56
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L62
  call   <ft_strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L52
  movzbl (%r12),%ecx
  test   %cl,%cl
  je     L90
  mov    $0x0,%edx
L41:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%r12,%rdx,1),%ecx
  test   %cl,%cl
  jne    L41
L39:
  mov    %rdx,%rcx
  sub    %rbp,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  test   %cl,%cl
  je     L96
  sub    %rbp,%rbx
L16:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L16
L96:
  movb   $0x0,(%rax,%rdx,1)
L94:
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L90:
  mov    $0x0,%edx
  jmp    L39
L62:
  mov    $0x0,%esi
  jmp    L94
L52:
  mov    $0x0,%esi
  jmp    L94
L56:
  mov    $0x0,%esi
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  size_t len_s1;
  size_t len_s2;
  char *new;
  size_t i;
  new = NULL;
  i = 0;
  if (s1 == NULL || s2 == NULL)
    return (NULL);
  len_s1 = ft_strlen(s1);
  len_s2 = ft_strlen(s2);
  if ((new = (char *)malloc((sizeof(char) * (len_s1 + len_s2)) + 1)) == NULL)
    return (NULL);
  while (s1[i] != '\0') {
    new[i] = s1[i];
    i++;
  }
  while (s2[i - len_s1] != '\0') {
    new[i] = s2[i - len_s1];
    i++;
  }
  new[i] = '\0';
  return (new);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strjoin>:
  endbr64
  test   %rdi,%rdi
  je     L40
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L44
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <ft_strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L44
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L68
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L33
  lea    (%rax,%rdx,1),%rsi
L2:
  mov    %rdx,%rcx
  sub    %rbx,%rcx
  movzbl (%r12,%rcx,1),%ecx
  test   %cl,%cl
  je     L76
  mov    %r12,%rsi
  sub    %rbx,%rsi
  nopl   0x0(%rax)
L62:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L62
  lea    (%rax,%rdx,1),%rsi
L76:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L44:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %rax,%rsi
  xor    %edx,%edx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  size_t len_s1;
  size_t len_s2;
  char *new;
  size_t i;
  new = NULL;
  i = 0;
  if (s1 == NULL || s2 == NULL)
    return (NULL);
  len_s1 = ft_strlen(s1);
  len_s2 = ft_strlen(s2);
  if ((new = (char *)malloc((sizeof(char) * (len_s1 + len_s2)) + 1)) == NULL)
    return (NULL);
  while (s1[i] != '\0') {
    new[i] = s1[i];
    i++;
  }
  while (s2[i - len_s1] != '\0') {
    new[i] = s2[i - len_s1];
    i++;
  }
  new[i] = '\0';
  return (new);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strjoin>:
  endbr64
  test   %rdi,%rdi
  je     L71
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L48
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <ft_strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L48
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L43
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L2
  lea    (%rax,%rdx,1),%rsi
L70:
  mov    %rdx,%rcx
  sub    %rbx,%rcx
  movzbl (%r12,%rcx,1),%ecx
  test   %cl,%cl
  je     L64
  mov    %r12,%rsi
  sub    %rbx,%rsi
  nopl   0x0(%rax)
L44:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L44
  lea    (%rax,%rdx,1),%rsi
L64:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L48:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rax,%rsi
  xor    %edx,%edx
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L71:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  size_t len_s1;
  size_t len_s2;
  char *new;
  size_t i;
  new = NULL;
  i = 0;
  if (s1 == NULL || s2 == NULL)
    return (NULL);
  len_s1 = ft_strlen(s1);
  len_s2 = ft_strlen(s2);
  if ((new = (char *)malloc((sizeof(char) * (len_s1 + len_s2)) + 1)) == NULL)
    return (NULL);
  while (s1[i] != '\0') {
    new[i] = s1[i];
    i++;
  }
  while (s2[i - len_s1] != '\0') {
    new[i] = s2[i - len_s1];
    i++;
  }
  new[i] = '\0';
  return (new);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D2: usage: macfanctld [-f]


tool: D6:   -f  run in foregound


assistant: ```c
void usage() {
  printf("usage: macfanctld [-f]\n");
  printf("  -f  run in foregound\n");
  exit(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D0: usage: macfanctld [-f]


tool: D3:   -f  run in foregound


assistant: ```c
void usage() {
  printf("usage: macfanctld [-f]\n");
  printf("  -f  run in foregound\n");
  exit(-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D15
type_guessed: string

tool: D4: usage: macfanctld [-f]


tool: D15:   -f  run in foregound


assistant: ```c
void usage() {
  printf("usage: macfanctld [-f]\n");
  printf("  -f  run in foregound\n");
  exit(-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D2
data_type: string

tool: D15: usage: macfanctld [-f]


tool: D2:   -f  run in foregound


assistant: ```c
void usage() {
  printf("usage: macfanctld [-f]\n");
  printf("  -f  run in foregound\n");
  exit(-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<newgap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  je     L1
  cmpl   $0xa,-0x4(%rbp)
  jne    L2
L1:
  movl   $0xb,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  jg     L26
  movl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap == 9 || gap == 10)
    gap = 11;
  if (gap < 1)
    gap = 1;
  return gap;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<newgap>:
  endbr64
  lea    (%rdi,%rdi,4),%edx
  add    %edx,%edx
  movslq %edx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    -0x9(%rax),%edx
  test   %eax,%eax
  mov    $0x1,%ecx
  cmovle %ecx,%eax
  cmp    $0x1,%edx
  mov    $0xb,%edx
  cmovbe %edx,%eax
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap == 9 || gap == 10)
    gap = 11;
  if (gap < 1)
    gap = 1;
  return gap;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<newgap>:
  endbr64
  lea    (%rdi,%rdi,4),%edx
  mov    $0x1,%ecx
  add    %edx,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  test   %eax,%eax
  lea    -0x9(%rax),%edx
  cmovle %ecx,%eax
  cmp    $0x1,%edx
  mov    $0xb,%edx
  cmovbe %edx,%eax
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap == 9 || gap == 10)
    gap = 11;
  if (gap < 1)
    gap = 1;
  return gap;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<newgap>:
  endbr64
  lea    (%rdi,%rdi,4),%edx
  mov    $0x1,%ecx
  add    %edx,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  test   %eax,%eax
  lea    -0x9(%rax),%edx
  cmovle %ecx,%eax
  cmp    $0x1,%edx
  mov    $0xb,%edx
  cmovbe %edx,%eax
  ret
```

assistant: ```c
int newgap(int gap) {
  gap = (gap * 10) / 13;
  if (gap == 9 || gap == 10)
    gap = 11;
  if (gap < 1)
    gap = 1;
  return gap;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <m_len@plt>
  cmp    %eax,%ebx
  jl     L130
  mov    $0x1,%eax
  jmp    L20
L130:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  cmpb   $0x0,-0x15(%rbp)
  jne    L32
  mov    $0x1,%eax
  jmp    L20
L32:
  cmpb   $0x2a,-0x15(%rbp)
  je     L26
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mls@plt>
  movzbl (%rax),%eax
  cmp    %al,-0x15(%rbp)
  jne    L69
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L20
L69:
  mov    $0x1,%eax
  jmp    L20
L26:
  nop
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  cmpb   $0x0,-0x15(%rbp)
  jne    L55
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <m_len@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  jmp    L20
L55:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L29
L140:
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mls@plt>
  movzbl (%rax),%eax
  cmp    %al,-0x15(%rbp)
  jne    L138
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L20
L138:
  addl   $0x1,-0x14(%rbp)
L29:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <m_len@plt>
  cmp    %eax,-0x14(%rbp)
  jge    L137
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mls@plt>
  movzbl (%rax),%eax
  test   %al,%al
  jne    L140
L137:
  mov    $0x1,%eax
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int match(int m, int *res, char *s, int *p) {
  int t;
  char ch;
  if (*res >= m_len(m))
    return 1;
  ch = s[*p];
  if (!ch)
    return 1;
  if (ch == '*')
    goto test_expr;
  if (ch == (*(char *)mls((m), (*res)))) {
    (*res)++;
    (*p)++;
    return 0;
  }
  return 1;
test_expr:
  (*p)++;
  ch = s[*p];
  if (ch == 0) {
    (*res) = m_len(m);
    return 0;
  }
  t = *res;
  while (t < m_len(m) && (*(char *)mls((m), (t))) != 0) {
    if ((*(char *)mls((m), (t))) == ch) {
      (*res) = t + 1;
      (*p)++;
      return 0;
    }
    t++;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<match>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    (%rsi),%r14d
  call   <m_len@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    %edx,%r14d
  jge    L107
  mov    0x0(%r13),%edx
  movslq %edx,%rax
  movzbl 0x0(%rbp,%rax,1),%r14d
  mov    $0x1,%eax
  test   %r14b,%r14b
  je     L107
  cmp    $0x2a,%r14b
  je     L55
  mov    (%r12),%esi
  mov    %ebx,%edi
  call   <mls@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  cmp    %r14b,(%rdx)
  je     L98
L107:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L55:
  add    $0x1,%edx
  mov    %edx,0x0(%r13)
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%r14d
  test   %r14b,%r14b
  je     L43
  mov    (%r12),%ebp
L33:
  mov    %ebx,%edi
  call   <m_len@plt>
  cmp    %ebp,%eax
  jle    L4
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mls@plt>
  cmpb   $0x0,(%rax)
  je     L74
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mls@plt>
  cmp    %r14b,(%rax)
  je     L26
  add    $0x1,%ebp
  jmp    L33
L98:
  addl   $0x1,(%r12)
  addl   $0x1,0x0(%r13)
  mov    $0x0,%eax
  jmp    L107
L43:
  mov    %ebx,%edi
  call   <m_len@plt>
  mov    %eax,(%r12)
  mov    $0x0,%eax
  jmp    L107
L26:
  add    $0x1,%ebp
  mov    %ebp,(%r12)
  addl   $0x1,0x0(%r13)
  mov    $0x0,%eax
  jmp    L107
L74:
  mov    $0x1,%eax
  jmp    L107
L4:
  mov    $0x1,%eax
  jmp    L107
```

assistant: ```c
int match(int m, int *res, char *s, int *p) {
  int t;
  char ch;
  if (*res >= m_len(m))
    return 1;
  ch = s[*p];
  if (!ch)
    return 1;
  if (ch == '*')
    goto test_expr;
  if (ch == (*(char *)mls((m), (*res)))) {
    (*res)++;
    (*p)++;
    return 0;
  }
  return 1;
test_expr:
  (*p)++;
  ch = s[*p];
  if (ch == 0) {
    (*res) = m_len(m);
    return 0;
  }
  t = *res;
  while (t < m_len(m) && (*(char *)mls((m), (t))) != 0) {
    if ((*(char *)mls((m), (t))) == ch) {
      (*res) = t + 1;
      (*p)++;
      return 0;
    }
    t++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<match>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rsi),%r14d
  mov    %rdx,%rbx
  call   <m_len@plt>
  cmp    %eax,%r14d
  jge    L25
  movslq 0x0(%r13),%rdx
  movzbl (%rbx,%rdx,1),%r14d
  mov    %rdx,%rax
  test   %r14b,%r14b
  je     L25
  cmp    $0x2a,%r14b
  je     L73
  mov    (%r12),%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmp    %r14b,(%rax)
  je     L59
L25:
  mov    $0x1,%eax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L59:
  addl   $0x1,(%r12)
  xor    %eax,%eax
  addl   $0x1,0x0(%r13)
  jmp    L49
  xchg   %ax,%ax
L73:
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
  cltq
  movzbl (%rbx,%rax,1),%r14d
  test   %r14b,%r14b
  je     L124
  mov    (%r12),%ebx
  jmp    L36
  nopl   0x0(%rax)
L109:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmpb   $0x0,(%rax)
  je     L25
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <mls@plt>
  cmp    %r14b,(%rax)
  je     L18
L36:
  mov    %ebp,%edi
  call   <m_len@plt>
  cmp    %ebx,%eax
  jg     L109
  jmp    L25
  nopl   0x0(%rax)
L18:
  mov    %ebx,(%r12)
  xor    %eax,%eax
  addl   $0x1,0x0(%r13)
  jmp    L49
  nopl   (%rax)
L124:
  mov    %ebp,%edi
  call   <m_len@plt>
  mov    %eax,(%r12)
  xor    %eax,%eax
  jmp    L49
```

assistant: ```c
int match(int m, int *res, char *s, int *p) {
  int t;
  char ch;
  if (*res >= m_len(m))
    return 1;
  ch = s[*p];
  if (!ch)
    return 1;
  if (ch == '*')
    goto test_expr;
  if (ch == (*(char *)mls((m), (*res)))) {
    (*res)++;
    (*p)++;
    return 0;
  }
  return 1;
test_expr:
  (*p)++;
  ch = s[*p];
  if (ch == 0) {
    (*res) = m_len(m);
    return 0;
  }
  t = *res;
  while (t < m_len(m) && (*(char *)mls((m), (t))) != 0) {
    if ((*(char *)mls((m), (t))) == ch) {
      (*res) = t + 1;
      (*p)++;
      return 0;
    }
    t++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<match>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rsi),%r14d
  mov    %rdx,%rbx
  call   <m_len@plt>
  cmp    %eax,%r14d
  jge    L109
  movslq 0x0(%r13),%rdx
  movzbl (%rbx,%rdx,1),%r14d
  mov    %rdx,%rax
  test   %r14b,%r14b
  je     L109
  cmp    $0x2a,%r14b
  je     L10
  mov    (%r12),%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmp    %r14b,(%rax)
  je     L72
L109:
  mov    $0x1,%eax
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L72:
  addl   $0x1,(%r12)
  xor    %eax,%eax
  addl   $0x1,0x0(%r13)
  jmp    L57
  xchg   %ax,%ax
L10:
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
  cltq
  movzbl (%rbx,%rax,1),%r14d
  test   %r14b,%r14b
  je     L91
  mov    (%r12),%ebx
  jmp    L70
  nopl   0x0(%rax)
L6:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmpb   $0x0,(%rax)
  je     L109
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <mls@plt>
  cmp    %r14b,(%rax)
  je     L67
L70:
  mov    %ebp,%edi
  call   <m_len@plt>
  cmp    %ebx,%eax
  jg     L6
  jmp    L109
  nopl   0x0(%rax)
L67:
  mov    %ebx,(%r12)
  xor    %eax,%eax
  addl   $0x1,0x0(%r13)
  jmp    L57
  nopl   (%rax)
L91:
  mov    %ebp,%edi
  call   <m_len@plt>
  mov    %eax,(%r12)
  xor    %eax,%eax
  jmp    L57
```

assistant: ```c
int match(int m, int *res, char *s, int *p) {
  int t;
  char ch;
  if (*res >= m_len(m))
    return 1;
  ch = s[*p];
  if (!ch)
    return 1;
  if (ch == '*')
    goto test_expr;
  if (ch == (*(char *)mls((m), (*res)))) {
    (*res)++;
    (*p)++;
    return 0;
  }
  return 1;
test_expr:
  (*p)++;
  ch = s[*p];
  if (ch == 0) {
    (*res) = m_len(m);
    return 0;
  }
  t = *res;
  while (t < m_len(m) && (*(char *)mls((m), (t))) != 0) {
    if ((*(char *)mls((m), (t))) == ch) {
      (*res) = t + 1;
      (*p)++;
      return 0;
    }
    t++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<exec_not>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L17
L93:
  movl   $0x0,-0x18(%rbp)
  jmp    L22
L60:
  movl   $0x0,-0x14(%rbp)
  jmp    L45
L199:
  movl   $0x0,-0x10(%rbp)
  jmp    L97
L34:
  movl   $0x0,-0xc(%rbp)
  jmp    L121
L178:
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L127:
  cmpl   $0x0,-0x1c(%rbp)
  je     L44
  mov    $0x800,%edx
  jmp    L0
L44:
  mov    $0x0,%edx
L0:
  cmpl   $0x0,-0x18(%rbp)
  je     L59
  mov    $0x80,%eax
  jmp    L105
L59:
  mov    $0x0,%eax
L105:
  or     %edx,%eax
  cmpl   $0x0,-0x14(%rbp)
  je     L149
  mov    $0x40,%edx
  jmp    L16
L149:
  mov    $0x0,%edx
L16:
  or     %edx,%eax
  cmpl   $0x0,-0x10(%rbp)
  je     L119
  mov    $0x10,%edx
  jmp    L187
L119:
  mov    $0x0,%edx
L187:
  or     %eax,%edx
  cmpl   $0x0,-0xc(%rbp)
  setne  %al
  movzbl %al,%eax
  or     %edx,%eax
  cmpl   $0x0,-0x8(%rbp)
  je     L48
  mov    $0x4,%edx
  jmp    L98
L48:
  mov    $0x0,%edx
L98:
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <exec_notl@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <exec_notw@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <exec_notb@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  cmpl   $0x1,-0x8(%rbp)
  jle    L127
  addl   $0x1,-0xc(%rbp)
L121:
  cmpl   $0x1,-0xc(%rbp)
  jle    L178
  addl   $0x1,-0x10(%rbp)
L97:
  cmpl   $0x1,-0x10(%rbp)
  jle    L34
  addl   $0x1,-0x14(%rbp)
L45:
  cmpl   $0x1,-0x14(%rbp)
  jle    L199
  addl   $0x1,-0x18(%rbp)
L22:
  cmpl   $0x1,-0x18(%rbp)
  jle    L60
  addl   $0x1,-0x1c(%rbp)
L17:
  cmpl   $0x1,-0x1c(%rbp)
  jle    L93
  nop
  nop
  leave
  ret
```

assistant: ```c
void exec_not(int s0, int s1) {
  int o, s, z, a, c, p, flags_in;
  for (o = 0; o < 2; o++) {
    for (s = 0; s < 2; s++) {
      for (z = 0; z < 2; z++) {
        for (a = 0; a < 2; a++) {
          for (c = 0; c < 2; c++) {
            for (p = 0; p < 2; p++) {
              flags_in = (o ? 0x0800 : 0) | (s ? 0x0080 : 0) | (z ? 0x0040 : 0) | (a ? 0x0010 : 0) | (c ? 0x0001 : 0) | (p ? 0x0004 : 0);
              exec_notl(s0, s1, flags_in);
              exec_notw(s0, s1, flags_in);
              exec_notb(s0, s1, flags_in);
            }
          }
        }
      }
    }
  }
}
```