ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_cmd>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  mov    %rdi,%r14
  lea    D26(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <printf@plt>
  mov    %r13,%rdi
  call   <times@plt>
  mov    %rax,%r12
  test   %rax,%rax
  js     L62
  mov    %r14,%rdi
  call   <system@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L52
L69:
  lea    0x4(%rsp),%r14
  mov    %r14,%rdi
  call   <times@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  js     L32
L38:
  sub    %r12,%rbx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <pr_times@plt>
  mov    %ebp,%edi
  call   <pr_exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L62:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <err_sys@plt>
  mov    %r14,%rdi
  call   <system@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jns    L69
L52:
  mov    %r14,%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <err_sys@plt>
  jmp    L69
  nop
L32:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <err_sys@plt>
  jmp    L38
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type: string
name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D38
type: string

tool: D26: 
command: '%s'


tool: D13: tms error

tool: D38: error on system(%s)

assistant: ```c
void do_cmd(const char *cmd) {
  int status;
  struct tms tstart, tend;
  clock_t start, end;
  printf("\ncommand: '%s'\n", cmd);
  if ((start = times(&tstart)) < 0) {
    err_sys("tms error");
  }
  if ((status = system(cmd)) < 0) {
    err_sys("error on system(%s)", cmd);
  }
  if ((end = times(&tend)) < 0) {
    err_sys("tms error");
  }
  pr_times(end - start, &tstart, &tend);
  pr_exit(status);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_cmd>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  mov    %rdi,%r14
  lea    D31(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <printf@plt>
  mov    %r13,%rdi
  call   <times@plt>
  mov    %rax,%r12
  test   %rax,%rax
  js     L9
  mov    %r14,%rdi
  call   <system@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L66
L36:
  lea    0x4(%rsp),%r14
  mov    %r14,%rdi
  call   <times@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  js     L64
L63:
  sub    %r12,%rbx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <pr_times@plt>
  mov    %ebp,%edi
  call   <pr_exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L9:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <err_sys@plt>
  mov    %r14,%rdi
  call   <system@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jns    L36
L66:
  mov    %r14,%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <err_sys@plt>
  jmp    L36
  nop
L64:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <err_sys@plt>
  jmp    L63
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string

tool: D31: 
command: '%s'


tool: D13: tms error

tool: D30: error on system(%s)

assistant: ```c
void do_cmd(const char *cmd) {
  int status;
  struct tms tstart, tend;
  clock_t start, end;
  printf("\ncommand: '%s'\n", cmd);
  if ((start = times(&tstart)) < 0) {
    err_sys("tms error");
  }
  if ((status = system(cmd)) < 0) {
    err_sys("error on system(%s)", cmd);
  }
  if ((end = times(&tend)) < 0) {
    err_sys("tms error");
  }
  pr_times(end - start, &tstart, &tend);
  pr_exit(status);
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_133_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %al,-0x4(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_133_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~T;
  stk3 = S | stk4;
  stk2 = *D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rop3_133_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  not    %esi
  or     %eax,%esi
  and    (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_133_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~T;
  stk3 = S | stk4;
  stk2 = *D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_133_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  not    %esi
  or     %eax,%esi
  and    (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_133_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~T;
  stk3 = S | stk4;
  stk2 = *D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_133_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  not    %esi
  or     %eax,%esi
  and    (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_133_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~T;
  stk3 = S | stk4;
  stk2 = *D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L34
  cmpl   $0x1,-0x14(%rbp)
  je     L10
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L15
L10:
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L34:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fib(int param1) {
  int local17;
  int o0;
  int o0_1;
  if (param1 <= 1) {
    if (param1 != 1) {
      local17 = param1;
    } else {
      local17 = 1;
    }
  } else {
    o0_1 = fib(param1 - 1);
    o0 = fib(param1 - 2);
    local17 = o0_1 + o0;
  }
  return local17;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L16
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L17
```

assistant: ```c
int fib(int param1) {
  int local17;
  int o0;
  int o0_1;
  if (param1 <= 1) {
    if (param1 != 1) {
      local17 = param1;
    } else {
      local17 = 1;
    }
  } else {
    o0_1 = fib(param1 - 1);
    o0 = fib(param1 - 2);
    local17 = o0_1 + o0;
  }
  return local17;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x2,%eax
  mov    %eax,-0x44(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L54
L68:
  mov    -0x58(%rbp),%edx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L98
  mov    -0x58(%rbp),%edx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L98
  mov    -0x58(%rbp),%edx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x54(%rbp),%eax
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x54(%rbp)
L98:
  addl   $0x1,-0x58(%rbp)
L54:
  mov    -0x58(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jb     L68
  movl   $0x0,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0xb,-0x48(%rbp)
  jmp    L38
L49:
  mov    -0x48(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L70
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,-0x4c(%rbp)
  cmpl   $0x9,-0x4c(%rbp)
  jle    L4
  mov    -0x4c(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x1(%rdx),%eax
  mov    %eax,-0x4c(%rbp)
  jmp    L4
L70:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,-0x4c(%rbp)
L4:
  mov    -0x4c(%rbp),%eax
  add    %eax,-0x50(%rbp)
  subl   $0x1,-0x48(%rbp)
L38:
  cmpl   $0x0,-0x48(%rbp)
  jns    L49
  mov    -0x50(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    $0xa,%eax
  sub    %ecx,%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jne    L66
  mov    $0x1,%eax
  jmp    L55
L66:
  mov    $0x0,%eax
L55:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

assistant: ```c
int check_sum(char isbnnum[]) {
  int numbers[13];
  unsigned int len = strlen(isbnnum) - 2;
  for (unsigned int i = 0, k = 0; i < len; i++) {
    if (isbnnum[i] >= '0' && isbnnum[i] <= '9') {
      numbers[k] = isbnnum[i] - '0';
      k++;
    }
  }
  int sum = 0, cur_sum = 0;
  for (int i = 11; i >= 0; i--) {
    if (i % 2 != 0) {
      cur_sum = 2 * numbers[i];
      if (cur_sum > 9) {
        cur_sum = cur_sum % 10 + 1;
      }
    } else {
      cur_sum = numbers[i];
    }
    sum += cur_sum;
  }
  sum = 10 - (sum % 10);
  if (sum == numbers[12]) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_sum>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L7
  mov    %rbx,%rdx
  lea    -0x3(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rdi
  mov    $0x0,%esi
  jmp    L9
L90:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L7
L9:
  movzbl (%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L90
  mov    %esi,%ecx
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,(%rsp,%rcx,4)
  add    $0x1,%esi
  jmp    L90
L7:
  lea    0x2c(%rsp),%rcx
  mov    $0xb,%edx
  mov    $0x0,%edi
  jmp    L50
L91:
  mov    (%rcx),%eax
L5:
  add    %eax,%edi
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  je     L96
L50:
  test   $0x1,%dl
  je     L91
  mov    (%rcx),%eax
  add    %eax,%eax
  cmp    $0x9,%eax
  jle    L5
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%esi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%eax
  lea    0x1(%rax),%eax
  jmp    L5
L96:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %edi,%eax
  lea    0xa(%rax),%eax
  cmp    %eax,0x30(%rsp)
  sete   %al
  movzbl %al,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x40,%rsp
  pop    %rbx
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_sum(char isbnnum[]) {
  int numbers[13];
  unsigned int len = strlen(isbnnum) - 2;
  for (unsigned int i = 0, k = 0; i < len; i++) {
    if (isbnnum[i] >= '0' && isbnnum[i] <= '9') {
      numbers[k] = isbnnum[i] - '0';
      k++;
    }
  }
  int sum = 0, cur_sum = 0;
  for (int i = 11; i >= 0; i--) {
    if (i % 2 != 0) {
      cur_sum = 2 * numbers[i];
      if (cur_sum > 9) {
        cur_sum = cur_sum % 10 + 1;
      }
    } else {
      cur_sum = numbers[i];
    }
    sum += cur_sum;
  }
  sum = 10 - (sum % 10);
  if (sum == numbers[12]) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_sum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L33
  sub    $0x3,%eax
  mov    %rbx,%rdi
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax,%rax,1)
L59:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L66
  mov    %edx,%esi
  movsbl %al,%eax
  add    $0x1,%edx
  mov    %eax,(%rsp,%rsi,4)
L66:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L59
L33:
  lea    0x2c(%rsp),%rcx
  mov    $0xb,%edx
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rcx),%eax
  test   $0x1,%dl
  je     L2
  add    %eax,%eax
  cmp    $0x9,%eax
  jle    L2
  movslq %eax,%rsi
  mov    %eax,%r8d
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%r8d
  sar    $0x22,%rsi
  sub    %r8d,%esi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%eax
  lea    0x1(%rax),%eax
L2:
  sub    $0x1,%edx
  add    %eax,%edi
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  jne    L8
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %edi,%eax
  add    $0xa,%eax
  cmp    %eax,0x30(%rsp)
  sete   %al
  movzbl %al,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x40,%rsp
  pop    %rbx
  ret
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_sum(char isbnnum[]) {
  int numbers[13];
  unsigned int len = strlen(isbnnum) - 2;
  for (unsigned int i = 0, k = 0; i < len; i++) {
    if (isbnnum[i] >= '0' && isbnnum[i] <= '9') {
      numbers[k] = isbnnum[i] - '0';
      k++;
    }
  }
  int sum = 0, cur_sum = 0;
  for (int i = 11; i >= 0; i--) {
    if (i % 2 != 0) {
      cur_sum = 2 * numbers[i];
      if (cur_sum > 9) {
        cur_sum = cur_sum % 10 + 1;
      }
    } else {
      cur_sum = numbers[i];
    }
    sum += cur_sum;
  }
  sum = 10 - (sum % 10);
  if (sum == numbers[12]) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<free_PlexLink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x33,%edi
  call   <free_object@plt>
  mov    $0x0,%eax
  call   <error@plt>
  test   %rax,%rax
  leave
  ret
```

assistant: ```c
void free_PlexLink(struct PlexLink *plk) {
  free_object(51, (short *)plk);
  if (error())
    return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_PlexLink>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x33,%edi
  call   <free_object@plt>
  mov    $0x0,%eax
  call   <error@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void free_PlexLink(struct PlexLink *plk) {
  free_object(51, (short *)plk);
  if (error())
    return;
}
```
user: What is the c source code of the assembly code below:

```asm
<free_PlexLink>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x33,%edi
  call   <free_object@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <error@plt>
```

assistant: ```c
void free_PlexLink(struct PlexLink *plk) {
  free_object(51, (short *)plk);
  if (error())
    return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free_PlexLink>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x33,%edi
  call   <free_object@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <error@plt>
```

assistant: ```c
void free_PlexLink(struct PlexLink *plk) {
  free_object(51, (short *)plk);
  if (error())
    return;
}
```
user: What is the c source code of the assembly code below?

```asm
<fetch32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
uint32_t fetch32(const char *p) {
  uint32_t result;
  memcpy(&result, p, sizeof(result));
  return (result);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fetch32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t fetch32(const char *p) {
  uint32_t result;
  memcpy(&result, p, sizeof(result));
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fetch32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t fetch32(const char *p) {
  uint32_t result;
  memcpy(&result, p, sizeof(result));
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fetch32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t fetch32(const char *p) {
  uint32_t result;
  memcpy(&result, p, sizeof(result));
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CpyMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L17:
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L18:
  mov    -0x24(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CpyMat(float B[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      B[m * i + j] = A[m * i + j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CpyMat>:
  endbr64
  mov    %rdi,%r8
  test   %ecx,%ecx
  jle    L5
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    %edx,%r11d
  jmp    L19
L23:
  movslq %r10d,%rdi
  lea    0x0(,%rdi,4),%rax
  add    %r11,%rdi
  shl    $0x2,%rdi
L24:
  movss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L24
L49:
  add    $0x1,%r9d
  add    %edx,%r10d
  cmp    %r9d,%ecx
  je     L5
L19:
  test   %edx,%edx
  jg     L23
  jmp    L49
L5:
  ret
```

assistant: ```c
void CpyMat(float B[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      B[m * i + j] = A[m * i + j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CpyMat>:
  endbr64
  mov    %rsi,%r8
  test   %ecx,%ecx
  jle    L10
  lea    -0x1(%rdx),%r11d
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  add    $0x1,%r11
  nopl   0x0(%rax)
L16:
  test   %edx,%edx
  jle    L13
  movslq %r10d,%rsi
  lea    0x0(,%rsi,4),%rax
  add    %r11,%rsi
  shl    $0x2,%rsi
  cs nopw 0x0(%rax,%rax,1)
L1:
  movss  (%r8,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L1
L13:
  add    $0x1,%r9d
  add    %edx,%r10d
  cmp    %r9d,%ecx
  jne    L16
L10:
  ret
```

assistant: ```c
void CpyMat(float B[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      B[m * i + j] = A[m * i + j];
    }
  }
}
```