user: Demonstrate the C code that generates the assembly output below:

```asm
<printcol>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0x4,%esi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %ecx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  test   %rax,%rax
  je     L89
  mov    %rax,%r15
  mov    $0x1,%r14d
  lea    0x10(%rsp),%rbp
  test   %r12d,%r12d
  jle    L92
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <setrandstr@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   *%r13
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  addl   $0x1,(%r15,%rdx,4)
  cmp    %r14d,%r12d
  jge    L18
L92:
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  test   %ebx,%ebx
  jle    L84
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L37
  mov    %ebx,%edx
  pxor   %xmm1,%xmm1
  pcmpeqd %xmm3,%xmm3
  mov    %r15,%rax
  shr    $0x2,%edx
  movdqa D17(%rip),%xmm4
  shl    $0x4,%rdx
  add    %r15,%rdx
  nopl   (%rax)
L65:
  movdqu (%rax),%xmm0
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pcmpgtd %xmm4,%xmm0
  paddd  %xmm3,%xmm2
  pand   %xmm2,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L65
  movdqa %xmm1,%xmm0
  mov    %ebx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%esi
  test   $0x3,%bl
  je     L12
L61:
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    (%r15,%rdx,4),%edx
  lea    -0x1(%rdx,%rsi,1),%edi
  cmp    $0x1,%edx
  lea    0x1(%rax),%edx
  cmovg  %edi,%esi
  cmp    %ebx,%edx
  jge    L12
  mov    0x4(%r15,%rcx,1),%edx
  cmp    $0x1,%edx
  lea    -0x1(%rdx,%rsi,1),%edi
  cmovg  %edi,%esi
  add    $0x2,%eax
  cmp    %eax,%ebx
  jle    L12
  mov    0x8(%r15,%rcx,1),%eax
  lea    -0x1(%rax,%rsi,1),%edx
  cmp    $0x1,%eax
  cmovg  %edx,%esi
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
L84:
  pxor   %xmm1,%xmm1
  mov    0x8(%rsp),%rdx
  lea    D10(%rip),%rdi
  cvtsi2sd %r12d,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D18(%rip),%xmm0
  call   <printf@plt>
  mov    %r15,%rdi
  call   <free@plt>
L89:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L61
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
type: byte[16]
name: read_data
arguments: label: D10
type: string
name: read_data
arguments: label: D18
type: f64

tool: {"D17": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D10: collision rate: %5.2f%% (%8d) by %s


tool: D18: 100

assistant: ```c
void printcol(const char *name, int (*hfunc)(const char *, int), int rnum, int bnum) {
  int *array, i, len, col;
  char buf[32];
  if (!(array = calloc(bnum, sizeof(int))))
    return;
  for (i = 1; i <= rnum; i++) {
    len = setrandstr(buf);
    array[hfunc(buf, len) % bnum]++;
  }
  col = 0;
  for (i = 0; i < bnum; i++) {
    if (array[i] > 1)
      col += array[i] - 1;
  }
  printf("collision rate: %5.2f%% (%8d) by %s\n", ((double)col / (double)rnum) * 100.0, col, name);
  free(array);
}
```