ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    -0x2c(%rbp),%rsi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %rsp,%rcx
  lea    0x1(%rsi),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L66
L35:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L35
L66:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L4
L12:
  mov    %rsp,%rbx
  test   %esi,%esi
  jle    L47
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  mov    -0x2c(%rbp),%esi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x689df277,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2c,%rdx
  sub    %ecx,%edx
  imul   $0x2727,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%esi
  jg     L16
L47:
  lea    D19(%rip),%r13
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L79
  xor    %r12d,%r12d
  nopl   (%rax)
L46:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L46
L79:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L4:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L12
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D19
type: string

tool: D10: %d

tool: D19: %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  int arr[n + 1], j, x, count = 0;
  for (i = 0; i < n; i++) {
    arr[i] = rand() % 10023;
  }
  printf("%d\n", n);
  for (i = 0; i < n; i++)
    printf("%d\n", arr[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    -0x2c(%rbp),%rsi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %rsp,%rcx
  lea    0x1(%rsi),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L12
L50:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L50
L12:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L64
L59:
  mov    %rsp,%rbx
  test   %esi,%esi
  jle    L75
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L78:
  xor    %eax,%eax
  call   <rand@plt>
  mov    -0x2c(%rbp),%esi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x689df277,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2c,%rdx
  sub    %ecx,%edx
  imul   $0x2727,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%esi
  jg     L78
L75:
  lea    D15(%rip),%r13
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L13
  xor    %r12d,%r12d
  nopl   (%rax)
L33:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L33
L13:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L64:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L59
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string

tool: D7: %d

tool: D15: %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  int arr[n + 1], j, x, count = 0;
  for (i = 0; i < n; i++) {
    arr[i] = rand() % 10023;
  }
  printf("%d\n", n);
  for (i = 0; i < n; i++)
    printf("%d\n", arr[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<play>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
L75:
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xff,(%rax)
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L93
  movl   $0x1,-0x14(%rbp)
  jmp    L72
L93:
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x24(%rbp)
  jl     L59
  mov    -0x18(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x24(%rbp)
  jg     L59
  movl   $0x0,-0x14(%rbp)
  jmp    L72
L59:
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x24(%rbp)
  jl     L75
  mov    -0x18(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <min@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L10
L87:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L87
  jmp    L75
L72:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int play(int k, int a, int b) {
  char *positions = (char *)calloc(k + 1, sizeof(char));
  int curr = -1, winner = -1;
  while (1) {
    curr++;
    if (positions[curr] == 0) {
      positions[curr] = -1;
      if (curr == k) {
        winner = 1;
        break;
      }
      if (curr + a <= k && k <= curr + b) {
        winner = 0;
        break;
      }
      if (curr + a <= k) {
        int top = min(curr + b, k);
        for (int i = curr + a; i <= top; i++)
          positions[i] = 1;
      }
    }
  }
  free(positions);
  return winner;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<play>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%ebp
  mov    %edx,%r12d
  lea    0x1(%rdi),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r15
  mov    $0x0,%ebx
  lea    0x1(%rax),%rax
  mov    %rax,0x8(%rsp)
  jmp    L7
L13:
  add    $0x1,%rbx
  add    $0x1,%r12d
  add    $0x1,%ebp
L7:
  lea    (%rbx,%r15,1),%rax
  cmpb   $0x0,(%rax)
  jne    L13
  movb   $0xff,(%rax)
  cmp    %ebx,%r14d
  je     L50
  cmp    %r14d,%ebp
  jg     L13
  cmp    %r12d,%r14d
  jle    L89
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <min@plt>
  cmp    %eax,%ebp
  jg     L13
  movslq %ebp,%r13
  lea    0x0(%r13,%r15,1),%rdx
  add    0x8(%rsp),%r13
  sub    %ebp,%eax
  add    %r13,%rax
L83:
  movb   $0x1,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L83
  jmp    L13
L50:
  mov    $0x1,%ebx
L29:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  mov    $0x0,%ebx
  jmp    L29
```

assistant: ```c
int play(int k, int a, int b) {
  char *positions = (char *)calloc(k + 1, sizeof(char));
  int curr = -1, winner = -1;
  while (1) {
    curr++;
    if (positions[curr] == 0) {
      positions[curr] = -1;
      if (curr == k) {
        winner = 1;
        break;
      }
      if (curr + a <= k && k <= curr + b) {
        winner = 0;
        break;
      }
      if (curr + a <= k) {
        int top = min(curr + b, k);
        for (int i = curr + a; i <= top; i++)
          positions[i] = 1;
      }
    }
  }
  free(positions);
  return winner;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<play>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  add    $0x1,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  xor    %ebx,%ebx
  call   <calloc@plt>
  mov    %rax,%r14
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    %r13d,%ebp
  jg     L8
  cmp    %r13d,%r12d
  jge    L51
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <min@plt>
  cmp    %eax,%ebp
  jg     L8
  sub    %ebp,%eax
  movslq %ebp,%rdi
  mov    $0x1,%esi
  lea    0x1(%rax),%rdx
  add    %r14,%rdi
  call   <memset@plt>
  nop
L8:
  add    $0x1,%rbx
  add    $0x1,%ebp
  add    $0x1,%r12d
L37:
  lea    (%r14,%rbx,1),%rax
  cmpb   $0x0,(%rax)
  jne    L8
  movb   $0xff,(%rax)
  cmp    %ebx,%r13d
  jne    L14
  mov    $0x1,%r12d
L68:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L51:
  xor    %r12d,%r12d
  jmp    L68
```

assistant: ```c
int play(int k, int a, int b) {
  char *positions = (char *)calloc(k + 1, sizeof(char));
  int curr = -1, winner = -1;
  while (1) {
    curr++;
    if (positions[curr] == 0) {
      positions[curr] = -1;
      if (curr == k) {
        winner = 1;
        break;
      }
      if (curr + a <= k && k <= curr + b) {
        winner = 0;
        break;
      }
      if (curr + a <= k) {
        int top = min(curr + b, k);
        for (int i = curr + a; i <= top; i++)
          positions[i] = 1;
      }
    }
  }
  free(positions);
  return winner;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<play>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  add    $0x1,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  xor    %ebx,%ebx
  call   <calloc@plt>
  mov    %rax,%r14
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L48:
  cmp    %r13d,%ebp
  jg     L55
  cmp    %r13d,%r12d
  jge    L44
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <min@plt>
  cmp    %eax,%ebp
  jg     L55
  sub    %ebp,%eax
  movslq %ebp,%rdi
  mov    $0x1,%esi
  lea    0x1(%rax),%rdx
  add    %r14,%rdi
  call   <memset@plt>
  nop
L55:
  add    $0x1,%rbx
  add    $0x1,%ebp
  add    $0x1,%r12d
L13:
  lea    (%r14,%rbx,1),%rax
  cmpb   $0x0,(%rax)
  jne    L55
  movb   $0xff,(%rax)
  cmp    %ebx,%r13d
  jne    L48
  mov    $0x1,%r12d
L29:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L44:
  xor    %r12d,%r12d
  jmp    L29
```

assistant: ```c
int play(int k, int a, int b) {
  char *positions = (char *)calloc(k + 1, sizeof(char));
  int curr = -1, winner = -1;
  while (1) {
    curr++;
    if (positions[curr] == 0) {
      positions[curr] = -1;
      if (curr == k) {
        winner = 1;
        break;
      }
      if (curr + a <= k && k <= curr + b) {
        winner = 0;
        break;
      }
      if (curr + a <= k) {
        int top = min(curr + b, k);
        for (int i = curr + a; i <= top; i++)
          positions[i] = 1;
      }
    }
  }
  free(positions);
  return winner;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<m68k_write_memory_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x3(%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <MEM_SetByte@plt>
  mov    -0x8(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MEM_SetByte@plt>
  mov    -0x8(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MEM_SetByte@plt>
  mov    -0x8(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MEM_SetByte@plt>
  nop
  leave
  ret
```

assistant: ```c
void m68k_write_memory_32(unsigned int addr, unsigned int val) {
  MEM_SetByte(addr + 3, val);
  MEM_SetByte(addr + 2, val >> 8);
  MEM_SetByte(addr + 1, val >> 16);
  MEM_SetByte(addr + 0, val >> 24);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<m68k_write_memory_32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  lea    0x3(%rdi),%edi
  call   <MEM_SetByte@plt>
  mov    %ebx,%esi
  shr    $0x8,%esi
  lea    0x2(%rbp),%edi
  call   <MEM_SetByte@plt>
  mov    %ebx,%esi
  shr    $0x10,%esi
  lea    0x1(%rbp),%edi
  call   <MEM_SetByte@plt>
  shr    $0x18,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <MEM_SetByte@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void m68k_write_memory_32(unsigned int addr, unsigned int val) {
  MEM_SetByte(addr + 3, val);
  MEM_SetByte(addr + 2, val >> 8);
  MEM_SetByte(addr + 1, val >> 16);
  MEM_SetByte(addr + 0, val >> 24);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<m68k_write_memory_32>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    0x3(%rdi),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <MEM_SetByte@plt>
  mov    %ebx,%esi
  lea    0x2(%rbp),%edi
  shr    $0x8,%esi
  call   <MEM_SetByte@plt>
  mov    %ebx,%esi
  lea    0x1(%rbp),%edi
  shr    $0x18,%ebx
  shr    $0x10,%esi
  call   <MEM_SetByte@plt>
  add    $0x8,%rsp
  mov    %ebx,%esi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <MEM_SetByte@plt>
```

assistant: ```c
void m68k_write_memory_32(unsigned int addr, unsigned int val) {
  MEM_SetByte(addr + 3, val);
  MEM_SetByte(addr + 2, val >> 8);
  MEM_SetByte(addr + 1, val >> 16);
  MEM_SetByte(addr + 0, val >> 24);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m68k_write_memory_32>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    0x3(%rdi),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <MEM_SetByte@plt>
  mov    %ebx,%esi
  lea    0x2(%rbp),%edi
  shr    $0x8,%esi
  call   <MEM_SetByte@plt>
  mov    %ebx,%esi
  lea    0x1(%rbp),%edi
  shr    $0x18,%ebx
  shr    $0x10,%esi
  call   <MEM_SetByte@plt>
  add    $0x8,%rsp
  mov    %ebx,%esi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <MEM_SetByte@plt>
```

assistant: ```c
void m68k_write_memory_32(unsigned int addr, unsigned int val) {
  MEM_SetByte(addr + 3, val);
  MEM_SetByte(addr + 2, val >> 8);
  MEM_SetByte(addr + 1, val >> 16);
  MEM_SetByte(addr + 0, val >> 24);
}
```
user: What is the c source code of the assembly code below:

```asm
<twophaseLevelSetCoefficientsUpdateVelocity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L33:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L28:
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L28
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void twophaseLevelSetCoefficientsUpdateVelocity(int nPoints, int nSpace, double v_scale, double *vIn, double *vOut) {
  int i, I;
  for (i = 0; i < nPoints; i++)
    for (I = 0; I < nSpace; I++)
      vOut[i * nSpace + I] = v_scale * vIn[i * nSpace + I];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<twophaseLevelSetCoefficientsUpdateVelocity>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  jle    L53
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    %esi,%r11d
  jmp    L24
L39:
  movslq %r10d,%rsi
  lea    0x0(,%rsi,8),%rax
  add    %r11,%rsi
  shl    $0x3,%rsi
L57:
  movapd %xmm0,%xmm1
  mulsd  (%rdx,%rax,1),%xmm1
  movsd  %xmm1,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L57
L42:
  add    $0x1,%r9d
  add    %r8d,%r10d
  cmp    %r9d,%edi
  je     L53
L24:
  test   %r8d,%r8d
  jg     L39
  jmp    L42
L53:
  ret
```

assistant: ```c
void twophaseLevelSetCoefficientsUpdateVelocity(int nPoints, int nSpace, double v_scale, double *vIn, double *vOut) {
  int i, I;
  for (i = 0; i < nPoints; i++)
    for (I = 0; I < nSpace; I++)
      vOut[i * nSpace + I] = v_scale * vIn[i * nSpace + I];
}
```
user: What is the c source code of the assembly code below:

```asm
<twophaseLevelSetCoefficientsUpdateVelocity>:
  endbr64
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %rdx,%rsi
  test   %edi,%edi
  jle    L0
  lea    -0x1(%r9),%r11d
  xor    %r10d,%r10d
  xor    %edi,%edi
  add    $0x1,%r11
  xchg   %ax,%ax
L24:
  test   %r9d,%r9d
  jle    L34
  movslq %r10d,%rdx
  lea    0x0(,%rdx,8),%rax
  add    %r11,%rdx
  shl    $0x3,%rdx
  nopw   0x0(%rax,%rax,1)
L13:
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L13
L34:
  add    $0x1,%edi
  add    %r9d,%r10d
  cmp    %edi,%r8d
  jne    L24
L0:
  ret
```

assistant: ```c
void twophaseLevelSetCoefficientsUpdateVelocity(int nPoints, int nSpace, double v_scale, double *vIn, double *vOut) {
  int i, I;
  for (i = 0; i < nPoints; i++)
    for (I = 0; I < nSpace; I++)
      vOut[i * nSpace + I] = v_scale * vIn[i * nSpace + I];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<twophaseLevelSetCoefficientsUpdateVelocity>:
  endbr64
  test   %edi,%edi
  jle    L85
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  test   %esi,%esi
  jle    L75
  mov    %ebp,%eax
  mov    %rdx,%rsi
  movslq %ebp,%r13
  mov    %ebp,%r8d
  shr    %eax
  movapd %xmm0,%xmm2
  mov    %edi,%r12d
  shl    $0x3,%r13
  lea    -0x1(%rax),%r10d
  lea    -0x1(%rbp),%eax
  and    $0xfffffffe,%r8d
  xor    %edi,%edi
  mov    %rax,%r15
  shl    $0x3,%rax
  add    $0x1,%r10
  lea    0x8(%rdx),%r11
  sub    %rsi,%rax
  mov    %rcx,%rdx
  shl    $0x4,%r10
  xor    %ebx,%ebx
  mov    %rax,-0x18(%rsp)
  mov    $0xfffffffffffffff8,%rax
  unpcklpd %xmm2,%xmm2
  sub    %rsi,%rax
  mov    %rax,-0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L42:
  cmp    %r11,%rdx
  je     L24
  cmp    $0x1,%r15d
  lea    -0x8(%r11),%r9
  seta   %r14b
  xor    %eax,%eax
  test   %r14b,%r14b
  je     L24
  nopl   0x0(%rax,%rax,1)
L34:
  movupd (%r9,%rax,1),%xmm1
  mulpd  %xmm2,%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r10,%rax
  jne    L34
  cmp    %ebp,%r8d
  je     L70
  lea    (%rdi,%r8,1),%eax
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
L70:
  add    $0x1,%ebx
  add    %r13,%r11
  add    %r13,%rdx
  add    %ebp,%edi
  cmp    %ebx,%r12d
  jne    L42
L75:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    -0x10(%rsp),%rax
  mov    -0x18(%rsp),%r14
  add    %r11,%rax
  lea    (%r11,%r14,1),%r9
  nopl   0x0(%rax)
L20:
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %r9,%rax
  jne    L20
  jmp    L70
L85:
  ret
```

assistant: ```c
void twophaseLevelSetCoefficientsUpdateVelocity(int nPoints, int nSpace, double v_scale, double *vIn, double *vOut) {
  int i, I;
  for (i = 0; i < nPoints; i++)
    for (I = 0; I < nSpace; I++)
      vOut[i * nSpace + I] = v_scale * vIn[i * nSpace + I];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_MappingNotify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L62
  cmp    $0x82,%eax
  jg     L44
  cmp    $0x80,%eax
  je     L78
  cmp    $0x81,%eax
  jne    L44
  lea    D36(%rip),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L74
L62:
  lea    D16(%rip),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L74
L78:
  lea    D1(%rip),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L74
L44:
  lea    -0x12(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x12(%rbp),%rax
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
L74:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <XRefreshKeyboardMapping@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D12
datatype: string
name: unpack_data
arguments: label: D11
datatype: string

tool: D36: MappingModifier

tool: D16: MappingKeyboard

tool: D1: MappingPointer

tool: D12: %d

tool: D11:     request %s, first_keycode %d, count %d


assistant: ```c
void do_MappingNotify(XEvent *eventp) {
  XMappingEvent *e = (XMappingEvent *)eventp;
  char *r;
  char rdummy[10];
  switch (e->request) {
  case MappingModifier:
    r = "MappingModifier";
    break;
  case MappingKeyboard:
    r = "MappingKeyboard";
    break;
  case MappingPointer:
    r = "MappingPointer";
    break;
  default:
    r = rdummy;
    sprintf(rdummy, "%d", e->request);
    break;
  }
  printf("    request %s, first_keycode %d, count %d\n", r, e->first_keycode, e->count);
  XRefreshKeyboardMapping(e);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_MappingNotify>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%edx
  lea    D29(%rip),%rsi
  cmp    $0x81,%edx
  je     L3
  lea    D30(%rip),%rsi
  cmp    $0x82,%edx
  je     L3
  lea    D22(%rip),%rsi
  cmp    $0x80,%edx
  je     L3
  lea    0xe(%rsp),%rbp
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
L3:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <XRefreshKeyboardMapping@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type: string
name: disassemble_data
arguments: data_tag: D30
type: string
name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D23
type: string
name: disassemble_data
arguments: data_tag: D32
type: string

tool: D29: MappingModifier

tool: D30: MappingKeyboard

tool: D22: MappingPointer

tool: D23: %d

tool: D32:     request %s, first_keycode %d, count %d


assistant: ```c
void do_MappingNotify(XEvent *eventp) {
  XMappingEvent *e = (XMappingEvent *)eventp;
  char *r;
  char rdummy[10];
  switch (e->request) {
  case MappingModifier:
    r = "MappingModifier";
    break;
  case MappingKeyboard:
    r = "MappingKeyboard";
    break;
  case MappingPointer:
    r = "MappingPointer";
    break;
  default:
    r = rdummy;
    sprintf(rdummy, "%d", e->request);
    break;
  }
  printf("    request %s, first_keycode %d, count %d\n", r, e->first_keycode, e->count);
  XRefreshKeyboardMapping(e);
}
```