ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<findMinMoves>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jne    L109
L22:
  add    $0x18,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L109:
  mov    %rdi,%r15
  lea    0x4(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  movl   $0x0,(%rax)
  movslq %ebp,%rax
  lea    0x0(,%rax,4),%rbx
  test   %ebp,%ebp
  jle    L42
  mov    %ebp,%eax
  mov    %r15,%rdx
  lea    0x4(%rdi),%r13
  mov    %rdi,%r14
  lea    (%rdi,%rax,4),%rcx
  sub    %rdi,%rdx
  xor    %eax,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L95:
  add    $0x4,%r13
L67:
  add    -0x4(%r13,%rdx,1),%eax
  mov    %eax,0x0(%r13)
  cmp    %r13,%rcx
  jne    L95
  add    0x8(%rsp),%rbx
  mov    (%rbx),%ecx
  mov    %rbx,(%rsp)
  mov    %ecx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%r12d
  test   %edx,%edx
  jne    L90
  lea    -0x1(%rbp),%r9d
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  mov    %r9d,%ebx
  imul   %r12d,%ebx
  jmp    L28
  nop
L38:
  mov    %r15d,%esi
  sub    %r12d,%ebx
  add    %r12d,%r15d
  sub    %edi,%esi
  mov    %ebp,%edi
  sub    %eax,%esi
  call   <max@plt>
  mov    %eax,%ebp
  cmp    %r14,%r13
  je     L108
L45:
  mov    (%rsp),%rax
  mov    (%rax),%ecx
L28:
  mov    (%r14),%edi
  add    $0x4,%r14
  mov    %ecx,%eax
  sub    (%r14),%eax
  mov    %edi,%edx
  sub    %ebx,%eax
  sub    %r15d,%edx
  test   %eax,%edx
  js     L38
  mov    %eax,%esi
  mov    %edx,%edi
  neg    %esi
  cmovs  %eax,%esi
  neg    %edi
  cmovs  %edx,%edi
  add    %r12d,%r15d
  sub    %r12d,%ebx
  call   <max@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <max@plt>
  mov    %eax,%ebp
  cmp    %r14,%r13
  jne    L45
L108:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  jmp    L22
L42:
  mov    0x8(%rsp),%rcx
  mov    (%rcx,%rax,4),%eax
  cltd
  idiv   %ebp
  mov    %edx,%ebp
  test   %edx,%edx
  je     L108
L90:
  mov    $0xffffffff,%ebp
  jmp    L22
```

assistant: ```c
int findMinMoves(int *machines, int machinesSize) {
  int *sum, ret = 0, i, left, right, avg;
  if (!machinesSize)
    return 0;
  sum = (int *)malloc((machinesSize + 1) * sizeof(int));
  sum[0] = 0;
  for (i = 0; i < machinesSize; ++i)
    sum[i + 1] = sum[i] + machines[i];
  if (sum[machinesSize] % machinesSize)
    return -1;
  avg = sum[machinesSize] / machinesSize;
  for (i = 0; i < machinesSize; ++i) {
    left = sum[i] - avg * i;
    right = sum[machinesSize] - sum[i + 1] - avg * (machinesSize - 1 - i);
    if (left < 0 && right < 0)
      ret = max(ret, -left - right);
    else
      ret = max(ret, max(abs(left), abs(right)));
  }
  free(sum);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findMinMoves>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jne    L75
L106:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %rdi,%r12
  lea    0x4(,%rsi,4),%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    %rax,%rbp
  movslq %r13d,%rax
  lea    0x0(,%rax,4),%rbx
  test   %r13d,%r13d
  jle    L92
  lea    -0x1(%r13),%edi
  mov    %r12,%rcx
  mov    %rbp,%r14
  xor    %edx,%edx
  mov    %rdi,%r9
  shl    $0x2,%rdi
  lea    0x4(%rbp),%rax
  sub    %rbp,%rcx
  lea    0x8(%rbp,%rdi,1),%rsi
  nopl   0x0(%rax,%rax,1)
L63:
  add    -0x4(%rax,%rcx,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rsi
  jne    L63
  lea    0x0(%rbp,%rbx,1),%rax
  mov    (%rax),%ecx
  mov    %rax,0x8(%rsp)
  mov    %ecx,%eax
  cltd
  idiv   %r13d
  mov    %eax,%r12d
  test   %edx,%edx
  jne    L55
  mov    %r9d,%ebx
  lea    0x4(%rbp,%rdi,1),%rax
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  imul   %r12d,%ebx
  mov    %rax,(%rsp)
  jmp    L44
  nopl   (%rax)
L48:
  mov    %r15d,%esi
  sub    %r12d,%ebx
  add    %r12d,%r15d
  sub    %edi,%esi
  mov    %r13d,%edi
  sub    %eax,%esi
  call   <max@plt>
  mov    %eax,%r13d
  cmp    %r14,(%rsp)
  je     L76
L93:
  mov    0x8(%rsp),%rax
  mov    (%rax),%ecx
L44:
  mov    (%r14),%edi
  add    $0x4,%r14
  mov    %ecx,%eax
  sub    (%r14),%eax
  mov    %edi,%edx
  sub    %ebx,%eax
  sub    %r15d,%edx
  test   %eax,%edx
  js     L48
  mov    %eax,%esi
  mov    %edx,%edi
  neg    %esi
  cmovs  %eax,%esi
  neg    %edi
  cmovs  %edx,%edi
  add    %r12d,%r15d
  sub    %r12d,%ebx
  call   <max@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <max@plt>
  mov    %eax,%r13d
  cmp    %r14,(%rsp)
  jne    L93
L76:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L106
  nopl   (%rax)
L92:
  mov    0x0(%rbp,%rax,4),%eax
  cltd
  idiv   %r13d
  mov    %edx,%r13d
  test   %edx,%edx
  je     L76
L55:
  mov    $0xffffffff,%r13d
  jmp    L106
```

assistant: ```c
int findMinMoves(int *machines, int machinesSize) {
  int *sum, ret = 0, i, left, right, avg;
  if (!machinesSize)
    return 0;
  sum = (int *)malloc((machinesSize + 1) * sizeof(int));
  sum[0] = 0;
  for (i = 0; i < machinesSize; ++i)
    sum[i + 1] = sum[i] + machines[i];
  if (sum[machinesSize] % machinesSize)
    return -1;
  avg = sum[machinesSize] / machinesSize;
  for (i = 0; i < machinesSize; ++i) {
    left = sum[i] - avg * i;
    right = sum[machinesSize] - sum[i + 1] - avg * (machinesSize - 1 - i);
    if (left < 0 && right < 0)
      ret = max(ret, -left - right);
    else
      ret = max(ret, max(abs(left), abs(right)));
  }
  free(sum);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  jmp    L3
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string

tool: D8: abort()


assistant: ```c
__attribute__((__noreturn__)) void abort(void) {
  printf("abort()\n");
  while (1) {
  }
  __builtin_unreachable();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
L4:
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: abort()


assistant: ```c
__attribute__((__noreturn__)) void abort(void) {
  printf("abort()\n");
  while (1) {
  }
  __builtin_unreachable();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  lea    D3(%rip),%rdi
  push   %rax
  call   <printf@plt>
L7:
  jmp    L7
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: abort()


assistant: ```c
__attribute__((__noreturn__)) void abort(void) {
  printf("abort()\n");
  while (1) {
  }
  __builtin_unreachable();
}
```
user: What is the c source code of the assembly code below?

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  lea    D1(%rip),%rdi
  push   %rax
  call   <printf@plt>
L4:
  jmp    L4
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: abort()


assistant: ```c
__attribute__((__noreturn__)) void abort(void) {
  printf("abort()\n");
  while (1) {
  }
  __builtin_unreachable();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bpnn_zero_weights>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L37:
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L9
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bpnn_zero_weights(float **w, int m, int n) {
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bpnn_zero_weights>:
  endbr64
  test   %esi,%esi
  js     L30
  mov    %rdi,%r8
  mov    %esi,%esi
  lea    0x8(%rdi,%rsi,8),%rdi
  mov    %edx,%eax
  lea    0x4(,%rax,4),%rsi
  jmp    L51
L55:
  mov    (%r8),%rcx
  movl   $0x0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L55
L31:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L30
L51:
  mov    $0x0,%eax
  test   %edx,%edx
  jns    L55
  jmp    L31
L30:
  ret
```

assistant: ```c
void bpnn_zero_weights(float **w, int m, int n) {
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bpnn_zero_weights>:
  endbr64
  test   %esi,%esi
  js     L25
  push   %r13
  movslq %esi,%rsi
  mov    %edx,%eax
  push   %r12
  lea    0x4(,%rax,4),%r13
  lea    0x8(%rdi,%rsi,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  test   %ebp,%ebp
  js     L26
  mov    (%rbx),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L26:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  ret
```

assistant: ```c
void bpnn_zero_weights(float **w, int m, int n) {
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bpnn_zero_weights>:
  endbr64
  mov    %esi,%eax
  or     %edx,%eax
  js     L4
  mov    %esi,%esi
  mov    %edx,%edx
  push   %r12
  lea    0x8(%rdi,%rsi,8),%r12
  push   %rbp
  lea    0x4(,%rdx,4),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %rbx,%r12
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void bpnn_zero_weights(float **w, int m, int n) {
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sha1_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%ecx
  lea    D14(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%ecx
  lea    D14(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L7:
  cmpl   $0x13,-0x10(%rbp)
  jle    L11
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D14: 0123456789abcdef

assistant: ```c
char *sha1_to_hex(const unsigned char *sha1, char *buffer) {
  static const char hex[] = "0123456789abcdef";
  char *buf = buffer;
  for (int i = 0; i < 20; i++) {
    unsigned int val = *sha1++;
    *buf++ = hex[val >> 4];
    *buf++ = hex[val & 0xf];
  }
  *buf = '\0';
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sha1_to_hex>:
  endbr64
  mov    %rsi,%rax
  mov    $0x0,%edx
  lea    D2(%rip),%rsi
L6:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %rcx,%r8
  shr    $0x4,%r8
  and    $0xf,%r8d
  movzbl (%rsi,%r8,1),%r8d
  mov    %r8b,(%rax,%rdx,2)
  and    $0xf,%ecx
  movzbl (%rsi,%rcx,1),%ecx
  mov    %cl,0x1(%rax,%rdx,2)
  add    $0x1,%rdx
  cmp    $0x14,%rdx
  jne    L6
  movb   $0x0,0x28(%rax)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: 0123456789abcdef

assistant: ```c
char *sha1_to_hex(const unsigned char *sha1, char *buffer) {
  static const char hex[] = "0123456789abcdef";
  char *buf = buffer;
  for (int i = 0; i < 20; i++) {
    unsigned int val = *sha1++;
    *buf++ = hex[val >> 4];
    *buf++ = hex[val & 0xf];
  }
  *buf = '\0';
  return buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sha1_to_hex>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  lea    D4(%rip),%rsi
L6:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %rcx,%r8
  and    $0xf,%ecx
  shr    $0x4,%r8
  movzbl (%rsi,%rcx,1),%ecx
  and    $0xf,%r8d
  movzbl (%rsi,%r8,1),%r8d
  mov    %cl,0x1(%rax,%rdx,2)
  mov    %r8b,(%rax,%rdx,2)
  add    $0x1,%rdx
  cmp    $0x14,%rdx
  jne    L6
  movb   $0x0,0x28(%rax)
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: 0123456789abcdef

assistant: ```c
char *sha1_to_hex(const unsigned char *sha1, char *buffer) {
  static const char hex[] = "0123456789abcdef";
  char *buf = buffer;
  for (int i = 0; i < 20; i++) {
    unsigned int val = *sha1++;
    *buf++ = hex[val >> 4];
    *buf++ = hex[val & 0xf];
  }
  *buf = '\0';
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sha1_to_hex>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  lea    D4(%rip),%rsi
L3:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %rcx,%r8
  and    $0xf,%ecx
  shr    $0x4,%r8
  movzbl (%rsi,%rcx,1),%ecx
  and    $0xf,%r8d
  movzbl (%rsi,%r8,1),%r8d
  mov    %cl,0x1(%rax,%rdx,2)
  mov    %r8b,(%rax,%rdx,2)
  add    $0x1,%rdx
  cmp    $0x14,%rdx
  jne    L3
  movb   $0x0,0x28(%rax)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: 0123456789abcdef

assistant: ```c
char *sha1_to_hex(const unsigned char *sha1, char *buffer) {
  static const char hex[] = "0123456789abcdef";
  char *buf = buffer;
  for (int i = 0; i < 20; i++) {
    unsigned int val = *sha1++;
    *buf++ = hex[val >> 4];
    *buf++ = hex[val & 0xf];
  }
  *buf = '\0';
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L9:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <_heap_sink@plt>
  subl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void _heapify(int *arr, int size) {
  int i;
  for (i = size / 2; i >= 0; --i) {
    _heap_sink(arr, size, i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0xffffffff,%esi
  jl     L3
L13:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_heap_sink@plt>
  sub    $0x1,%ebx
  jns    L13
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _heapify(int *arr, int size) {
  int i;
  for (i = size / 2; i >= 0; --i) {
    _heap_sink(arr, size, i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0xffffffff,%esi
  jl     L16
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_heap_sink@plt>
  sub    $0x1,%ebx
  jae    L10
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _heapify(int *arr, int size) {
  int i;
  for (i = size / 2; i >= 0; --i) {
    _heap_sink(arr, size, i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0xffffffff,%esi
  jl     L16
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_heap_sink@plt>
  sub    $0x1,%ebx
  jae    L4
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _heapify(int *arr, int size) {
  int i;
  for (i = size / 2; i >= 0; --i) {
    _heap_sink(arr, size, i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<legible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <long_to_string@plt>
  lea    D4(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L12
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movb   $0x2d,(%rax)
  addq   $0x1,-0x28(%rbp)
L12:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L79
L30:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x3c(%rbp)
L79:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L30
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L54
L4:
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L9
  cmpl   $0x0,-0x38(%rbp)
  je     L9
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movb   $0x2c,(%rax)
L9:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x3c(%rbp)
  addl   $0x1,-0x38(%rbp)
L54:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D4(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

assistant: ```c
char *legible(long l) {
  static char outbuf[20];
  char inbuf[20];
  int i, i1, mod;
  char *outptr, *inptr;
  long_to_string(inbuf, l);
  outptr = outbuf;
  inptr = inbuf;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<legible>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <long_to_string@plt>
  mov    %rsp,%rbp
  lea    D14(%rip),%rbx
  cmpb   $0x2d,(%rsp)
  je     L101
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  test   %eax,%eax
  jle    L59
  movzbl 0x0(%rbp),%eax
  mov    %al,(%rbx)
  cmp    $0x1,%edx
  jle    L62
  movzbl 0x1(%rbp),%eax
  mov    %al,0x1(%rbx)
L62:
  mov    %edx,%eax
  add    %rax,%rbx
L72:
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%esi
  test   %sil,%sil
  je     L110
  mov    $0x0,%ecx
  jmp    L79
L101:
  movb   $0x2d,D14(%rip)
  lea    0x1(%rsp),%rbp
  lea    0x1(%rbx),%rbx
  jmp    L24
L59:
  mov    $0x0,%edx
  jmp    L72
L118:
  mov    %rbx,%rax
L10:
  lea    0x1(%rax),%rbx
  mov    %sil,(%rax)
  add    $0x1,%ecx
  add    $0x1,%rdx
  movzbl 0x0(%rbp,%rdx,1),%esi
  test   %sil,%sil
  je     L110
L79:
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ecx
  jne    L118
  test   %edx,%edx
  je     L118
  lea    0x1(%rbx),%rax
  movb   $0x2c,(%rbx)
  jmp    L10
L110:
  movb   $0x0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  lea    D14(%rip),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *legible(long l) {
  static char outbuf[20];
  char inbuf[20];
  int i, i1, mod;
  char *outptr, *inptr;
  long_to_string(inbuf, l);
  outptr = outbuf;
  inptr = inbuf;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<legible>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %r12,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <long_to_string@plt>
  cmpb   $0x2d,(%rsp)
  jne    L15
  movb   $0x2d,D2(%rip)
  lea    0x1(%rsp),%rbp
  add    $0x1,%rbx
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rax
  mov    %edx,%esi
  mov    %rdx,%rcx
  sar    $0x1f,%esi
  shr    $0x20,%rax
  mov    %eax,%edx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L28
  movslq %edx,%rdi
  xor    %eax,%eax
L60:
  mov    %eax,%ecx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%rcx,1),%esi
  mov    %sil,(%rbx,%rcx,1)
  cmp    %edx,%eax
  jb     L60
  add    %rdi,%rbx
  lea    0x0(%rbp,%rdi,1),%rax
L71:
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L11
  movslq %edx,%rax
  xor    %edx,%edx
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %rbx,%rsi
L25:
  add    $0x1,%rax
  mov    %cl,(%rsi)
  lea    0x1(%rsi),%rbx
  add    $0x1,%edx
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %cl,%cl
  je     L11
L97:
  imul   $0xaaaaaaab,%edx,%esi
  cmp    $0x55555555,%esi
  ja     L72
  test   %eax,%eax
  je     L72
  movb   $0x2c,(%rbx)
  lea    0x1(%rbx),%rsi
  jmp    L25
  nopl   0x0(%rax)
L11:
  movb   $0x0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rax
  xor    %edx,%edx
  jmp    L71
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *legible(long l) {
  static char outbuf[20];
  char inbuf[20];
  int i, i1, mod;
  char *outptr, *inptr;
  long_to_string(inbuf, l);
  outptr = outbuf;
  inptr = inbuf;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```