ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movaps %xmm0,%xmm1
  mulss  D38(%rip),%xmm1
  divss  D26(%rip),%xmm1
  addss  D5(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D6(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D68
data_type: string
name: retrieve_data
arguments: data_tag: D48
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string
name: retrieve_data
arguments: data_tag: D38
data_type: byte[4]
name: retrieve_data
arguments: data_tag: D26
data_type: byte[4]
name: retrieve_data
arguments: data_tag: D5
data_type: byte[4]
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D68: 
		--------------------		
		CELSIUS==>FAHRENHEIT		
		--------------------


tool: D48: Entra la temperatura en graus Celsius:

tool: D18: %f

tool: {"D38": [0x00,0x00,0x10,0x41]}

tool: {"D26": [0x00,0x00,0xa0,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x42]}

tool: D6: 
%.2f graus Celsius son %.2f graus Fahrenheit.


assistant: ```c
int main() {
  float c, f;
  printf("\n\t\t--------------------		\n\t\tCELSIUS==>FAHRENHEIT		\n\t\t--------------------\n\n");
  printf("Entra la temperatura en graus Celsius:");
  scanf("%f", &c);
  f = c * 9 / 5 + 32;
  printf("\n%.2f graus Celsius son %.2f graus Fahrenheit.\n", c, f);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x2,%eax
  movss  D40(%rip),%xmm1
  lea    D60(%rip),%rdi
  mulss  %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  divss  D26(%rip),%xmm1
  addss  D64(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string
name: disassemble_data
arguments: data_tag: D58
type_guessed: string
name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D40
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D60
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D64
type_guessed: byte[4]

tool: D8: 
		--------------------		
		CELSIUS==>FAHRENHEIT		
		--------------------


tool: D58: Entra la temperatura en graus Celsius:

tool: D0: %f

tool: {"D40": [0x00,0x00,0x10,0x41]}

tool: D60: 
%.2f graus Celsius son %.2f graus Fahrenheit.


tool: {"D26": [0x00,0x00,0xa0,0x40]}

tool: {"D64": [0x00,0x00,0x00,0x42]}

assistant: ```c
int main() {
  float c, f;
  printf("\n\t\t--------------------		\n\t\tCELSIUS==>FAHRENHEIT		\n\t\t--------------------\n\n");
  printf("Entra la temperatura en graus Celsius:");
  scanf("%f", &c);
  f = c * 9 / 5 + 32;
  printf("\n%.2f graus Celsius son %.2f graus Fahrenheit.\n", c, f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x2,%eax
  movss  D4(%rip),%xmm1
  lea    D6(%rip),%rdi
  mulss  %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  divss  D27(%rip),%xmm1
  addss  D21(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D67
type_guessed: string
name: parse_data
arguments: data_tag: D40
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: byte[4]
name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: byte[4]
name: parse_data
arguments: data_tag: D21
type_guessed: byte[4]

tool: D3: 
		--------------------		
		CELSIUS==>FAHRENHEIT		
		--------------------


tool: D67: Entra la temperatura en graus Celsius:

tool: D40: %f

tool: {"D4": [0x00,0x00,0x10,0x41]}

tool: D6: 
%.2f graus Celsius son %.2f graus Fahrenheit.


tool: {"D27": [0x00,0x00,0xa0,0x40]}

tool: {"D21": [0x00,0x00,0x00,0x42]}

assistant: ```c
int main() {
  float c, f;
  printf("\n\t\t--------------------		\n\t\tCELSIUS==>FAHRENHEIT		\n\t\t--------------------\n\n");
  printf("Entra la temperatura en graus Celsius:");
  scanf("%f", &c);
  f = c * 9 / 5 + 32;
  printf("\n%.2f graus Celsius son %.2f graus Fahrenheit.\n", c, f);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sigchld_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  nop
L9:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void sigchld_handler(int s) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sigchld_handler>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
L6:
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L6
  pop    %rbx
  ret
```

assistant: ```c
void sigchld_handler(int s) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sigchld_handler>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L8
  pop    %rbx
  ret
```

assistant: ```c
void sigchld_handler(int s) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sigchld_handler>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  nopl   0x0(%rax)
L5:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L5
  pop    %rbx
  ret
```

assistant: ```c
void sigchld_handler(int s) {
  while (waitpid(-1, NULL, WNOHANG) > 0)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mod_ftime0@plt>
  mov    $0x0,%eax
  call   <getfstat1@plt>
  mov    $0x0,%eax
  call   <getfstat2@plt>
  mov    $0x0,%eax
  call   <getfistat1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  mod_ftime0();
  getfstat1();
  getfstat2();
  getfistat1();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mod_ftime0@plt>
  mov    $0x0,%eax
  call   <getfstat1@plt>
  mov    $0x0,%eax
  call   <getfstat2@plt>
  mov    $0x0,%eax
  call   <getfistat1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mod_ftime0();
  getfstat1();
  getfstat2();
  getfistat1();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mod_ftime0@plt>
  xor    %eax,%eax
  call   <getfstat1@plt>
  xor    %eax,%eax
  call   <getfstat2@plt>
  xor    %eax,%eax
  call   <getfistat1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mod_ftime0();
  getfstat1();
  getfstat2();
  getfistat1();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ILibFragmentText>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9,-0x48(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x3c(%rbp),%edi
  mov    -0x30(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <ILibFragmentTextLength@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L19
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  je     L20
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x30(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%eax
  add    %eax,-0xc(%rbp)
L20:
  mov    -0x10(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    -0x2c(%rbp),%edx
  sub    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  add    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  sub    %eax,-0x10(%rbp)
L19:
  cmpl   $0x0,-0x10(%rbp)
  jne    L18
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ILibFragmentText(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength, char **RetVal) {
  char *Buffer;
  int i = 0, i2 = 0;
  int BufferSize = 0;
  *RetVal = (char *)malloc(ILibFragmentTextLength(text, textLength, delimiter, delimiterLength, tokenLength));
  Buffer = *RetVal;
  i2 = textLength;
  while (i2 != 0) {
    if (i2 != textLength) {
      memcpy(Buffer + i, delimiter, delimiterLength);
      i += delimiterLength;
      BufferSize += delimiterLength;
    }
    memcpy(Buffer + i, text + (textLength - i2), i2 > tokenLength ? tokenLength : i2);
    i += i2 > tokenLength ? tokenLength : i2;
    BufferSize += i2 > tokenLength ? tokenLength : i2;
    i2 -= i2 > tokenLength ? tokenLength : i2;
  }
  return (BufferSize);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ILibFragmentText>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%r14d
  mov    %rdx,0x10(%rsp)
  mov    %ecx,0x1c(%rsp)
  mov    %r8d,%r15d
  mov    %r9,%rbx
  call   <ILibFragmentTextLength@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %rax,(%rbx)
  mov    %r14d,%ebx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  test   %r14d,%r14d
  jne    L3
  mov    %r14d,%r13d
L12:
  mov    %r13d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  movslq %r12d,%rdi
  add    (%rsp),%rdi
  mov    0x1c(%rsp),%ebp
  mov    %ebp,%edx
  mov    0x10(%rsp),%rsi
  call   <memcpy@plt>
  add    %ebp,%r12d
  add    %ebp,%r13d
L3:
  cmp    %ebx,%r15d
  mov    %ebx,%ebp
  cmovle %r15d,%ebp
  mov    %r14d,%esi
  sub    %ebx,%esi
  movslq %esi,%rsi
  add    0x8(%rsp),%rsi
  movslq %r12d,%rdi
  add    (%rsp),%rdi
  mov    %ebp,%edx
  call   <memcpy@plt>
  add    %ebp,%r12d
  add    %ebp,%r13d
  sub    %ebp,%ebx
  je     L12
  cmp    %ebx,%r14d
  jne    L5
  jmp    L3
```

assistant: ```c
int ILibFragmentText(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength, char **RetVal) {
  char *Buffer;
  int i = 0, i2 = 0;
  int BufferSize = 0;
  *RetVal = (char *)malloc(ILibFragmentTextLength(text, textLength, delimiter, delimiterLength, tokenLength));
  Buffer = *RetVal;
  i2 = textLength;
  while (i2 != 0) {
    if (i2 != textLength) {
      memcpy(Buffer + i, delimiter, delimiterLength);
      i += delimiterLength;
      BufferSize += delimiterLength;
    }
    memcpy(Buffer + i, text + (textLength - i2), i2 > tokenLength ? tokenLength : i2);
    i += i2 > tokenLength ? tokenLength : i2;
    BufferSize += i2 > tokenLength ? tokenLength : i2;
    i2 -= i2 > tokenLength ? tokenLength : i2;
  }
  return (BufferSize);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ILibFragmentText>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %ecx,0x1c(%rsp)
  call   <ILibFragmentTextLength@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    %rax,%r12
  mov    %ebx,%r13d
  test   %ebx,%ebx
  je     L38
  nopl   (%rax)
L1:
  cmp    %r13d,%ebp
  mov    %r13d,%r14d
  mov    %ebx,%esi
  movslq %r15d,%rdi
  cmovle %ebp,%r14d
  sub    %r13d,%esi
  add    %r12,%rdi
  movslq %esi,%rsi
  add    0x8(%rsp),%rsi
  mov    %r14d,%edx
  add    %r14d,%r15d
  call   <memcpy@plt>
  sub    %r14d,%r13d
  je     L38
  cmp    %r13d,%ebx
  je     L1
  mov    0x1c(%rsp),%r14d
  movslq %r15d,%rdi
  mov    0x10(%rsp),%rsi
  add    %r12,%rdi
  mov    %r14d,%edx
  add    %r14d,%r15d
  call   <memcpy@plt>
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ILibFragmentText(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength, char **RetVal) {
  char *Buffer;
  int i = 0, i2 = 0;
  int BufferSize = 0;
  *RetVal = (char *)malloc(ILibFragmentTextLength(text, textLength, delimiter, delimiterLength, tokenLength));
  Buffer = *RetVal;
  i2 = textLength;
  while (i2 != 0) {
    if (i2 != textLength) {
      memcpy(Buffer + i, delimiter, delimiterLength);
      i += delimiterLength;
      BufferSize += delimiterLength;
    }
    memcpy(Buffer + i, text + (textLength - i2), i2 > tokenLength ? tokenLength : i2);
    i += i2 > tokenLength ? tokenLength : i2;
    BufferSize += i2 > tokenLength ? tokenLength : i2;
    i2 -= i2 > tokenLength ? tokenLength : i2;
  }
  return (BufferSize);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ILibFragmentText>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %ecx,0x1c(%rsp)
  call   <ILibFragmentTextLength@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    %rax,%r12
  mov    %ebx,%r13d
  test   %ebx,%ebx
  je     L13
  nopl   (%rax)
L27:
  cmp    %r13d,%ebp
  mov    %r13d,%r14d
  mov    %ebx,%esi
  movslq %r15d,%rdi
  cmovle %ebp,%r14d
  sub    %r13d,%esi
  add    %r12,%rdi
  movslq %esi,%rsi
  add    0x8(%rsp),%rsi
  mov    %r14d,%edx
  add    %r14d,%r15d
  call   <memcpy@plt>
  sub    %r14d,%r13d
  je     L13
  cmp    %r13d,%ebx
  je     L27
  mov    0x1c(%rsp),%r14d
  movslq %r15d,%rdi
  mov    0x10(%rsp),%rsi
  add    %r12,%rdi
  mov    %r14d,%edx
  add    %r14d,%r15d
  call   <memcpy@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ILibFragmentText(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength, char **RetVal) {
  char *Buffer;
  int i = 0, i2 = 0;
  int BufferSize = 0;
  *RetVal = (char *)malloc(ILibFragmentTextLength(text, textLength, delimiter, delimiterLength, tokenLength));
  Buffer = *RetVal;
  i2 = textLength;
  while (i2 != 0) {
    if (i2 != textLength) {
      memcpy(Buffer + i, delimiter, delimiterLength);
      i += delimiterLength;
      BufferSize += delimiterLength;
    }
    memcpy(Buffer + i, text + (textLength - i2), i2 > tokenLength ? tokenLength : i2);
    i += i2 > tokenLength ? tokenLength : i2;
    BufferSize += i2 > tokenLength ? tokenLength : i2;
    i2 -= i2 > tokenLength ? tokenLength : i2;
  }
  return (BufferSize);
}
```
user: What is the c source code of the assembly code below?

```asm
<show>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  jmp    L9
L18:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
L9:
  cmpb   $0x0,-0x5(%rbp)
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void show(char s[]) {
  char c;
  int i = 0;
  c = s[i];
  while (c != '\0') {
    printf("%c", s[i++]);
    c = s[i];
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<show>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  je     L14
L17:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L17
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void show(char s[]) {
  char c;
  int i = 0;
  c = s[i];
  while (c != '\0') {
    printf("%c", s[i++]);
    c = s[i];
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<show>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  push   %rbx
  lea    0x1(%rdi),%rbx
L1:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L1
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nop
L5:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void show(char s[]) {
  char c;
  int i = 0;
  c = s[i];
  while (c != '\0') {
    printf("%c", s[i++]);
    c = s[i];
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<show>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L8:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmpb   $0x0,(%rbx)
  jne    L8
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax)
L6:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void show(char s[]) {
  char c;
  int i = 0;
  c = s[i];
  while (c != '\0') {
    printf("%c", s[i++]);
    c = s[i];
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x5329,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy12;
        copy12 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)23699;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x5329,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy12;
        copy12 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)23699;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x5329,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy12;
        copy12 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)23699;
  }
}
```