user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    D51(%rip),%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L64
L108:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L108
L64:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L76
L9:
  lea    0x3(%rsp),%r12
  mov    -0x30(%rbp),%esi
  mov    %r12,%rax
  and    $0xfffffffffffffffc,%r12
  shr    $0x2,%rax
  mov    %esi,0x0(,%rax,4)
  mov    %esi,0x4(,%rax,4)
  cmp    $0x2,%edx
  jle    L79
  sub    $0x3,%edx
  lea    0x8(%r12),%rax
  mov    %esi,%ecx
  lea    0x8(%r12,%rdx,4),%rdi
  mov    %esi,%edx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L41:
  mov    -0x4(%rax),%ecx
  add    $0x4,%rax
L8:
  add    %ecx,%edx
  mov    %edx,(%rax)
  cmp    %rdi,%rax
  jne    L41
L79:
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,-0x34(%rbp)
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L97
  mov    -0x34(%rbp),%esi
  xor    %ebx,%ebx
  lea    D56(%rip),%r13
  jmp    L99
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    (%r12,%rbx,4),%esi
L99:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L36
L97:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L76:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L9
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type: string
name: retrieve_data
arguments: data_label: D51
type: string
name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D48
type: string
name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D45
type: string
name: retrieve_data
arguments: data_label: D56
type: string

tool: D23: ===== Exercise 8 =====

tool: D51: %i

tool: D4: FIBONACCI NUMBERS!

tool: D48: Enter the first number. : 

tool: D14: How many numbers will be shown?: 

tool: D45: --> %i First Fibonacci Numbers


tool: D56: %i


assistant: ```c
int main(int argc, const char *argv[]) {
  int number;
  printf("===== Exercise 8 =====\n");
  printf("FIBONACCI NUMBERS!\n");
  printf("Enter the first number. : ");
  scanf("%i", &number);
  printf("How many numbers will be shown?: ");
  int TheNumberOfNumber;
  scanf("%i", &TheNumberOfNumber);
  int fibonacci[TheNumberOfNumber];
  fibonacci[0] = number;
  fibonacci[1] = number;
  for (int i = 2; i < TheNumberOfNumber; i++) {
    fibonacci[i] = fibonacci[i - 2] + fibonacci[i - 1];
  }
  printf("--> %i First Fibonacci Numbers\n", number);
  for (int j = 0; j < TheNumberOfNumber; j++) {
    printf("%i\n", fibonacci[j]);
  }
  return 0;
}
```