ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rbx
  nopl   0x0(%rax)
L37:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L14
L6:
  cmp    $0x5c,%eax
  je     L57
  cmp    $0x9,%eax
  je     L32
  cmp    $0x8,%eax
  je     L60
  mov    %eax,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L6
L14:
  xor    %eax,%eax
  pop    %rbx
  ret
L60:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L37
```

assistant: ```c
int main() {
  int c, d;
  while ((c = getchar()) != EOF) {
    d = 0;
    if (c == '\\') {
      putchar('\\');
      putchar('\\');
      d = 1;
    }
    if (c == '\t') {
      putchar('\\');
      putchar('t');
      d = 1;
    }
    if (c == '\b') {
      putchar('\\');
      putchar('b');
      d = 1;
    }
    if (d == 0)
      putchar(c);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L56
L69:
  cmp    $0x5c,%eax
  je     L52
  cmp    $0x9,%eax
  je     L48
  cmp    $0x8,%eax
  je     L73
  mov    %eax,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L69
L56:
  xor    %eax,%eax
  pop    %rbx
  ret
L73:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L51
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L51
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L51
```

assistant: ```c
int main() {
  int c, d;
  while ((c = getchar()) != EOF) {
    d = 0;
    if (c == '\\') {
      putchar('\\');
      putchar('\\');
      d = 1;
    }
    if (c == '\t') {
      putchar('\\');
      putchar('t');
      d = 1;
    }
    if (c == '\b') {
      putchar('\\');
      putchar('b');
      d = 1;
    }
    if (d == 0)
      putchar(c);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<notsafePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L60:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L59
  addl   $0x1,-0xc(%rbp)
  jmp    L55
L59:
  movl   $0x0,-0xc(%rbp)
L55:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L69
  cmpl   $0x1,-0xc(%rbp)
  jle    L60
L69:
  cmpl   $0x2,-0xc(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    $0x400,%rax
  jle    L26
L1:
  mov    $0x1,%eax
  jmp    L8
L26:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int notsafePath(char *buf) {
  int count = 0;
  char *ptr = buf;
  do {
    if (*ptr == '.')
      count++;
    else
      count = 0;
  } while (*++ptr && count < 2);
  return (count == 2) || ((ptr - buf) > 1024);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<notsafePath>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x0,%eax
  mov    $0x0,%ecx
L4:
  add    $0x1,%eax
  cmpb   $0x2e,(%rdx)
  cmovne %ecx,%eax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  je     L6
  cmp    $0x1,%eax
  jle    L4
L6:
  mov    $0x1,%ecx
  cmp    $0x2,%eax
  je     L14
  sub    %rdi,%rdx
  cmp    $0x400,%rdx
  setg   %cl
  movzbl %cl,%ecx
L14:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int notsafePath(char *buf) {
  int count = 0;
  char *ptr = buf;
  do {
    if (*ptr == '.')
      count++;
    else
      count = 0;
  } while (*++ptr && count < 2);
  return (count == 2) || ((ptr - buf) > 1024);
}
```
user: Translate the below assembly code into C programming language:

```asm
<notsafePath>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
L46:
  movzbl (%rax),%esi
  add    $0x1,%rax
  movzbl (%rax),%ecx
  cmp    $0x2e,%sil
  je     L61
L67:
  test   %cl,%cl
  je     L33
  movzbl (%rax),%esi
  xor    %edx,%edx
  add    $0x1,%rax
  movzbl (%rax),%ecx
  cmp    $0x2e,%sil
  jne    L67
L61:
  add    $0x1,%edx
  test   %cl,%cl
  je     L42
  cmp    $0x2,%edx
  je     L58
  mov    $0x1,%edx
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L42:
  cmp    $0x2,%edx
  je     L58
L33:
  sub    %rdi,%rax
  cmp    $0x400,%rax
  setg   %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L58:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int notsafePath(char *buf) {
  int count = 0;
  char *ptr = buf;
  do {
    if (*ptr == '.')
      count++;
    else
      count = 0;
  } while (*++ptr && count < 2);
  return (count == 2) || ((ptr - buf) > 1024);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<notsafePath>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%esi
  xor    %ecx,%ecx
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2e,%sil
  je     L5
  nopl   0x0(%rax)
L3:
  test   %dl,%dl
  je     L4
  xor    %ecx,%ecx
  mov    %edx,%esi
L40:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2e,%sil
  jne    L3
L5:
  add    $0x1,%ecx
  test   %dl,%dl
  je     L50
  cmp    $0x2,%ecx
  je     L0
  mov    $0x1,%ecx
  mov    %edx,%esi
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L50:
  cmp    $0x2,%ecx
  je     L0
L4:
  sub    %rdi,%rax
  cmp    $0x400,%rax
  setg   %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int notsafePath(char *buf) {
  int count = 0;
  char *ptr = buf;
  do {
    if (*ptr == '.')
      count++;
    else
      count = 0;
  } while (*++ptr && count < 2);
  return (count == 2) || ((ptr - buf) > 1024);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D113(%rip),%rax
  mov    %rax,%rdi
  call   <xstrdup@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x38(%rbp),%rax
  mov    $0x1,%edx
  lea    D119(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <test_strsep@plt>
  movabs $0x6c61206b63617473,%rax
  movabs $0x64657461636f6c,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x0,%edx
  lea    D119(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <test_strsep@plt>
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <xstrdup@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0x28(%rbp),%rax
  mov    $0x1,%edx
  lea    D66(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <test_strsep@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <strtoimax@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <strtoimax@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <strtoimax@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffec,%edi
  call   <imaxabs@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D113
type_guessed: string
name: read_data
arguments: data_tag: D119
type_guessed: string
name: read_data
arguments: data_tag: D63
type_guessed: string
name: read_data
arguments: data_tag: D66
type_guessed: string
name: read_data
arguments: data_tag: D65
type_guessed: string
name: read_data
arguments: data_tag: D9
type_guessed: string
name: read_data
arguments: data_tag: D32
type_guessed: string
name: read_data
arguments: data_tag: D41
type_guessed: string

tool: D113: hello world

tool: D119:  

tool: D63: 1,2,3,4,5,6,7,8,9,10

tool: D66: ,

tool: D65: 1023

tool: D9: %jd


tool: D32: 0x24

tool: D41: 101

assistant: ```c
int main(void) {
  char *s1 = xstrdup("hello world");
  test_strsep(&s1, " ", true);
  char s2[] = "stack allocated";
  char *p2 = s2;
  test_strsep(&p2, " ", false);
  char *s3 = xstrdup("1,2,3,4,5,6,7,8,9,10");
  test_strsep(&s3, ",", true);
  printf("%jd\n", strtoimax("1023", NULL, 0));
  printf("%jd\n", strtoimax("0x24", NULL, 0));
  printf("%jd\n", strtoimax("101", NULL, 2));
  printf("%jd\n", imaxabs(-20));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D72(%rip),%rdi
  call   <xstrdup@plt>
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  mov    $0x1,%edx
  lea    D17(%rip),%rbx
  mov    %rbx,%rsi
  call   <test_strsep@plt>
  movabs $0x6c61206b63617473,%rax
  movabs $0x64657461636f6c,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x0,%edx
  mov    %rbx,%rsi
  call   <test_strsep@plt>
  lea    D42(%rip),%rdi
  call   <xstrdup@plt>
  mov    %rax,0x18(%rsp)
  lea    0x18(%rsp),%rdi
  mov    $0x1,%edx
  lea    D51(%rip),%rsi
  call   <test_strsep@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D36(%rip),%rdi
  call   <strtoimax@plt>
  mov    %eax,%esi
  lea    D39(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D30(%rip),%rdi
  call   <strtoimax@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  lea    D60(%rip),%rdi
  call   <strtoimax@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffec,%edi
  call   <imaxabs@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D72
type: string
name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D42
type: string
name: parse_data
arguments: label: D51
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D39
type: string
name: parse_data
arguments: label: D30
type: string
name: parse_data
arguments: label: D60
type: string

tool: D72: hello world

tool: D17:  

tool: D42: 1,2,3,4,5,6,7,8,9,10

tool: D51: ,

tool: D36: 1023

tool: D39: %jd


tool: D30: 0x24

tool: D60: 101

assistant: ```c
int main(void) {
  char *s1 = xstrdup("hello world");
  test_strsep(&s1, " ", true);
  char s2[] = "stack allocated";
  char *p2 = s2;
  test_strsep(&p2, " ", false);
  char *s3 = xstrdup("1,2,3,4,5,6,7,8,9,10");
  test_strsep(&s3, ",", true);
  printf("%jd\n", strtoimax("1023", NULL, 0));
  printf("%jd\n", strtoimax("0x24", NULL, 0));
  printf("%jd\n", strtoimax("101", NULL, 2));
  printf("%jd\n", imaxabs(-20));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rdi
  lea    D74(%rip),%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <xstrdup@plt>
  mov    %rbp,%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%edx
  mov    %rax,0x8(%rsp)
  call   <test_strsep@plt>
  xor    %edx,%edx
  mov    %rbp,%rsi
  lea    0x20(%rsp),%rax
  movdqa D83(%rip),%xmm0
  lea    0x10(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  lea    D84(%rip),%rbp
  movaps %xmm0,0x20(%rsp)
  call   <test_strsep@plt>
  lea    D47(%rip),%rdi
  call   <xstrdup@plt>
  lea    0x18(%rsp),%rdi
  mov    $0x1,%edx
  lea    D1(%rip),%rsi
  mov    %rax,0x18(%rsp)
  call   <test_strsep@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D88(%rip),%rdi
  call   <strtoimax@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D42(%rip),%rdi
  call   <strtoimax@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edx
  xor    %esi,%esi
  lea    D17(%rip),%rdi
  call   <strtoimax@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xffffffec,%edi
  call   <imaxabs@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D45
type_guessed: string
name: parse_data
arguments: data_tag: D74
type_guessed: string
name: parse_data
arguments: data_tag: D83
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D84
type_guessed: string
name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D88
type_guessed: string
name: parse_data
arguments: data_tag: D42
type_guessed: string
name: parse_data
arguments: data_tag: D17
type_guessed: string

tool: D45: hello world

tool: D74:  

tool: {"D83": [0x73,0x74,0x61,0x63,0x6b,0x20,0x61,0x6c,0x6c,0x6f,0x63,0x61,0x74,0x65,0x64,0x00]}

tool: D84: %jd


tool: D47: 1,2,3,4,5,6,7,8,9,10

tool: D1: ,

tool: D88: 1023

tool: D42: 0x24

tool: D17: 101

assistant: ```c
int main(void) {
  char *s1 = xstrdup("hello world");
  test_strsep(&s1, " ", true);
  char s2[] = "stack allocated";
  char *p2 = s2;
  test_strsep(&p2, " ", false);
  char *s3 = xstrdup("1,2,3,4,5,6,7,8,9,10");
  test_strsep(&s3, ",", true);
  printf("%jd\n", strtoimax("1023", NULL, 0));
  printf("%jd\n", strtoimax("0x24", NULL, 0));
  printf("%jd\n", strtoimax("101", NULL, 2));
  printf("%jd\n", imaxabs(-20));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D25(%rip),%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <xstrdup@plt>
  mov    %rbp,%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%edx
  mov    %rax,0x8(%rsp)
  call   <test_strsep@plt>
  xor    %edx,%edx
  mov    %rbp,%rsi
  lea    0x20(%rsp),%rax
  movdqa D37(%rip),%xmm0
  lea    0x10(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  lea    D79(%rip),%rbp
  movaps %xmm0,0x20(%rsp)
  call   <test_strsep@plt>
  lea    D31(%rip),%rdi
  call   <xstrdup@plt>
  lea    0x18(%rsp),%rdi
  mov    $0x1,%edx
  lea    D70(%rip),%rsi
  mov    %rax,0x18(%rsp)
  call   <test_strsep@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D73(%rip),%rdi
  call   <strtoimax@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D52(%rip),%rdi
  call   <strtoimax@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edx
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <strtoimax@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xffffffec,%edi
  call   <imaxabs@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D46
type_guessed: string
name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D37
type_guessed: byte[16]
name: parse_data
arguments: label: D79
type_guessed: string
name: parse_data
arguments: label: D31
type_guessed: string
name: parse_data
arguments: label: D70
type_guessed: string
name: parse_data
arguments: label: D73
type_guessed: string
name: parse_data
arguments: label: D52
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D46: hello world

tool: D25:  

tool: {"D37": [0x73,0x74,0x61,0x63,0x6b,0x20,0x61,0x6c,0x6c,0x6f,0x63,0x61,0x74,0x65,0x64,0x00]}

tool: D79: %jd


tool: D31: 1,2,3,4,5,6,7,8,9,10

tool: D70: ,

tool: D73: 1023

tool: D52: 0x24

tool: D5: 101

assistant: ```c
int main(void) {
  char *s1 = xstrdup("hello world");
  test_strsep(&s1, " ", true);
  char s2[] = "stack allocated";
  char *p2 = s2;
  test_strsep(&p2, " ", false);
  char *s3 = xstrdup("1,2,3,4,5,6,7,8,9,10");
  test_strsep(&s3, ",", true);
  printf("%jd\n", strtoimax("1023", NULL, 0));
  printf("%jd\n", strtoimax("0x24", NULL, 0));
  printf("%jd\n", strtoimax("101", NULL, 2));
  printf("%jd\n", imaxabs(-20));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtoarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L34
L21:
  addl   $0x1,-0x30(%rbp)
L34:
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L21
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x2c(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L46
L49:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x48(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x1,-0x2c(%rbp)
L46:
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L49
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int strtoarray(char *str, char *sep, char ***list) {
  int len = strlen(str);
  char *copystr = (char *)malloc((len + 1) * sizeof(char));
  strcpy(copystr, str);
  int sizelist = 0;
  char *cur, *temp;
  temp = copystr;
  while ((cur = strsep(&temp, sep))) {
    sizelist++;
  }
  (*list) = (char **)malloc(sizelist * sizeof(char *));
  int i = 0;
  int curlen;
  strcpy(copystr, str);
  temp = copystr;
  while ((cur = strsep(&temp, sep))) {
    curlen = strlen(cur);
    (*list)[i] = (char *)malloc((curlen + 1) * sizeof(char));
    strcpy((*list)[i], cur);
    i++;
  }
  free(copystr);
  return sizelist;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtoarray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,0x8(%rsp)
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,0x10(%rsp)
  mov    $0x0,%r14d
  lea    0x10(%rsp),%rbx
  jmp    L18
L40:
  add    $0x1,%r14d
L18:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strsep@plt>
  test   %rax,%rax
  jne    L40
  lea    0x0(,%r14,8),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,0x10(%rsp)
  mov    $0x0,%ebp
  lea    0x10(%rsp),%r15
  jmp    L27
L7:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    0x0(%r13),%rdx
  mov    %rax,(%rdx,%rbp,1)
  mov    0x0(%r13),%rax
  mov    (%rax,%rbp,1),%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  add    $0x8,%rbp
L27:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strsep@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L7
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %r14d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoarray(char *str, char *sep, char ***list) {
  int len = strlen(str);
  char *copystr = (char *)malloc((len + 1) * sizeof(char));
  strcpy(copystr, str);
  int sizelist = 0;
  char *cur, *temp;
  temp = copystr;
  while ((cur = strsep(&temp, sep))) {
    sizelist++;
  }
  (*list) = (char **)malloc(sizelist * sizeof(char *));
  int i = 0;
  int curlen;
  strcpy(copystr, str);
  temp = copystr;
  while ((cur = strsep(&temp, sep))) {
    curlen = strlen(cur);
    (*list)[i] = (char *)malloc((curlen + 1) * sizeof(char));
    strcpy((*list)[i], cur);
    i++;
  }
  free(copystr);
  return sizelist;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtoarray>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbx,%rsi
  mov    %rax,%r15
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <strcpy@plt>
  mov    %r15,0x10(%rsp)
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12d
L6:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strsep@plt>
  test   %rax,%rax
  jne    L18
  lea    0x0(,%r12,8),%edi
  call   <malloc@plt>
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rbx
  mov    %rax,(%r14)
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,0x10(%rsp)
  xor    %ebx,%ebx
  jmp    L16
  nopl   (%rax)
L40:
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r15,%rsi
  mov    %rax,%rdi
  mov    (%r14),%rax
  mov    %rdi,(%rax,%rbx,1)
  add    $0x8,%rbx
  call   <strcpy@plt>
L16:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strsep@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L40
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoarray(char *str, char *sep, char ***list) {
  int len = strlen(str);
  char *copystr = (char *)malloc((len + 1) * sizeof(char));
  strcpy(copystr, str);
  int sizelist = 0;
  char *cur, *temp;
  temp = copystr;
  while ((cur = strsep(&temp, sep))) {
    sizelist++;
  }
  (*list) = (char **)malloc(sizelist * sizeof(char *));
  int i = 0;
  int curlen;
  strcpy(copystr, str);
  temp = copystr;
  while ((cur = strsep(&temp, sep))) {
    curlen = strlen(cur);
    (*list)[i] = (char *)malloc((curlen + 1) * sizeof(char));
    strcpy((*list)[i], cur);
    i++;
  }
  free(copystr);
  return sizelist;
}
```