ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<forzarColumna>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  movslq %edx,%rbp
  mov    %esi,%edx
  push   %rbx
  movslq %ecx,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <hayConflictoConCandidatoEnColumna@plt>
  test   %eax,%eax
  jne    L9
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    0x40(%rsp),%rdi
  mov    %r14d,%edx
  mov    $0x9,%esi
  call   <addInt@plt>
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <getFilaConflictoEnColumna@plt>
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%r15,%rax,4),%rax
  movl   $0x0,(%rax,%rbx,4)
  lea    0x0(%rbp,%rbp,8),%rax
  lea    (%r15,%rax,4),%rax
  mov    %r14d,(%rax,%rbx,4)
  mov    $0x1,%eax
  mov    (%r12),%edx
  cmp    %edx,0x0(%r13)
  jne    L7
  sub    $0x1,%edx
  mov    %edx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int forzarColumna(int sudoku[9][9], int candidato, int iPosicionAtratar, int jPosicionAtratar, int *j, int *jAnterior, int *blackListForzarColumna) {
  if (!hayConflictoConCandidatoEnColumna(sudoku, jPosicionAtratar, candidato)) {
    return 0;
  }
  addInt(blackListForzarColumna, 9, candidato);
  int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, candidato);
  int jPosicionConflicto = jPosicionAtratar;
  sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
  sudoku[iPosicionAtratar][jPosicionAtratar] = candidato;
  if (*jAnterior == *j) {
    *j -= 1;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<forzarColumna>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  movslq %edx,%rbp
  mov    %esi,%edx
  push   %rbx
  movslq %ecx,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <hayConflictoConCandidatoEnColumna@plt>
  test   %eax,%eax
  jne    L16
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    0x40(%rsp),%rdi
  mov    %r14d,%edx
  mov    $0x9,%esi
  call   <addInt@plt>
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <getFilaConflictoEnColumna@plt>
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%r15,%rax,4),%rax
  movl   $0x0,(%rax,%rbx,4)
  lea    0x0(%rbp,%rbp,8),%rax
  lea    (%r15,%rax,4),%rax
  mov    %r14d,(%rax,%rbx,4)
  mov    $0x1,%eax
  mov    (%r12),%edx
  cmp    %edx,0x0(%r13)
  jne    L13
  sub    $0x1,%edx
  mov    %edx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int forzarColumna(int sudoku[9][9], int candidato, int iPosicionAtratar, int jPosicionAtratar, int *j, int *jAnterior, int *blackListForzarColumna) {
  if (!hayConflictoConCandidatoEnColumna(sudoku, jPosicionAtratar, candidato)) {
    return 0;
  }
  addInt(blackListForzarColumna, 9, candidato);
  int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, candidato);
  int jPosicionConflicto = jPosicionAtratar;
  sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
  sudoku[iPosicionAtratar][jPosicionAtratar] = candidato;
  if (*jAnterior == *j) {
    *j -= 1;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lpc_uart_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  nop
L8:
  mov    $0x0,%eax
  call   <lpc_uart_tx_full@plt>
  test   %rax,%rax
  jne    L8
  movsbl -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <lpc_uart_reg_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void lpc_uart_write(char c) {
  while (lpc_uart_tx_full()) {
    ;
  }
  lpc_uart_reg_write(0, c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lpc_uart_write>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L0:
  mov    $0x0,%eax
  call   <lpc_uart_tx_full@plt>
  test   %rax,%rax
  jne    L0
  movsbl %bl,%esi
  mov    $0x0,%edi
  call   <lpc_uart_reg_write@plt>
  pop    %rbx
  ret
```

assistant: ```c
void lpc_uart_write(char c) {
  while (lpc_uart_tx_full()) {
    ;
  }
  lpc_uart_reg_write(0, c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lpc_uart_write>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <lpc_uart_tx_full@plt>
  test   %rax,%rax
  jne    L5
  movsbl %bl,%esi
  xor    %edi,%edi
  pop    %rbx
  jmp    1070 <lpc_uart_reg_write@plt>
```

assistant: ```c
void lpc_uart_write(char c) {
  while (lpc_uart_tx_full()) {
    ;
  }
  lpc_uart_reg_write(0, c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lpc_uart_write>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <lpc_uart_tx_full@plt>
  test   %rax,%rax
  jne    L8
  movsbl %bl,%esi
  xor    %edi,%edi
  pop    %rbx
  jmp    1070 <lpc_uart_reg_write@plt>
```

assistant: ```c
void lpc_uart_write(char c) {
  while (lpc_uart_tx_full()) {
    ;
  }
  lpc_uart_reg_write(0, c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<myclock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
long myclock() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000000) + tv.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<myclock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long myclock() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000000) + tv.tv_usec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<myclock>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long myclock() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000000) + tv.tv_usec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<myclock>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long myclock() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000000) + tv.tv_usec;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x80000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int a) {
  int b = -0x7fffffff - 1;
  a &= b;
  return a == b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int f(int a) {
  int b = -0x7fffffff - 1;
  a &= b;
  return a == b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int f(int a) {
  int b = -0x7fffffff - 1;
  a &= b;
  return a == b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int f(int a) {
  int b = -0x7fffffff - 1;
  a &= b;
  return a == b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  D3(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  movsd  -0x10(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: f64
name: read_data
arguments: data_tag: D22
type_guessed: byte[8]
name: read_data
arguments: data_tag: D29
type_guessed: string

tool: D3: 1

tool: {"D22": [0x77,0x5a,0xf0,0x1a,0xdc,0xa5,0x4c,0x40]}

tool: D29: The arc tangent of %lf is %lf degrees


assistant: ```c
int main() {
  double x, ret, val;
  x = 1.0;
  val = 180.0 / 3.14159265;
  ret = atan(x) * val;
  printf("The arc tangent of %lf is %lf degrees\n", x, ret);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D23(%rip),%xmm1
  movsd  D15(%rip),%xmm0
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D15
datatype: f64
name: extract_symbolic_data
arguments: label: D12
datatype: string

tool: {"D23": [0x71,0x6c,0x6e,0x00,0x00,0x80,0x46,0x40]}

tool: D15: 1

tool: D12: The arc tangent of %lf is %lf degrees


assistant: ```c
int main() {
  double x, ret, val;
  x = 1.0;
  val = 180.0 / 3.14159265;
  ret = atan(x) * val;
  printf("The arc tangent of %lf is %lf degrees\n", x, ret);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D17(%rip),%xmm1
  movsd  D15(%rip),%xmm0
  lea    D24(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type: byte[8]
name: read_data
arguments: data_tag: D15
type: f64
name: read_data
arguments: data_tag: D24
type: string

tool: {"D17": [0x71,0x6c,0x6e,0x00,0x00,0x80,0x46,0x40]}

tool: D15: 1

tool: D24: The arc tangent of %lf is %lf degrees


assistant: ```c
int main() {
  double x, ret, val;
  x = 1.0;
  val = 180.0 / 3.14159265;
  ret = atan(x) * val;
  printf("The arc tangent of %lf is %lf degrees\n", x, ret);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D20(%rip),%xmm1
  movsd  D15(%rip),%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D20
type: byte[8]
name: retrieve_data
arguments: label: D15
type: f64
name: retrieve_data
arguments: label: D18
type: string

tool: {"D20": [0x71,0x6c,0x6e,0x00,0x00,0x80,0x46,0x40]}

tool: D15: 1

tool: D18: The arc tangent of %lf is %lf degrees


assistant: ```c
int main() {
  double x, ret, val;
  x = 1.0;
  val = 180.0 / 3.14159265;
  ret = atan(x) * val;
  printf("The arc tangent of %lf is %lf degrees\n", x, ret);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L106
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L90
L46:
  addq   $0x8,-0x8(%rbp)
L90:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L46
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  sar    $0x3,%rax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L106:
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L108
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x3e8,-0x14(%rbp)
  jmp    L12
L108:
  mov    $0x0,%eax
  jmp    L84
L12:
  mov    -0x30(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L55
L7:
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  sar    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  cmp    %rax,%rdx
  jne    L74
  mov    -0x14(%rbp),%eax
  add    $0x3e8,%eax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L104
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  jmp    L84
L104:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x3e8,-0x14(%rbp)
L74:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
L55:
  cmpq   $0x0,-0x10(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
L84:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: string

tool: D11: 
	

assistant: ```c
char **split(char **list, char *s) {
  char *cp, **lp;
  unsigned lim;
  if (list) {
    for (lp = list; *lp; ++lp)
      ;
    lim = lp - list + 1;
  } else if ((list = (char **)malloc((1000) * sizeof(char *))))
    lp = list, lim = 1000;
  else
    return NULL;
  for (cp = strtok(s, "\n\t"); cp; cp = strtok(NULL, "\n\t")) {
    if (lp - list == lim - 1) {
      if (!(lp = (char **)realloc((list), (lim + 1000) * sizeof(char *)))) {
        list[lim - 1] = NULL;
        return list;
      }
      list = lp, lp = list + lim - 1, lim += 1000;
    }
    *lp++ = cp;
  }
  *lp++ = NULL;
  return (char **)realloc((list), ((lp - list)) * sizeof(char *));
}
```
user: Translate the below assembly code into C programming language:

```asm
<split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  test   %rdi,%rdi
  je     L119
  cmpq   $0x0,(%rdi)
  je     L128
  mov    %rdi,%rbp
L63:
  add    $0x8,%rbp
  cmpq   $0x0,0x0(%rbp)
  jne    L63
L131:
  mov    %rbp,%r12
  sub    %r13,%r12
  sar    $0x3,%r12
  add    $0x1,%r12d
L50:
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L60
  lea    D5(%rip),%r15
  jmp    L57
L128:
  mov    %rdi,%rbp
  jmp    L131
L119:
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L84
  mov    %rax,%r13
  mov    $0x3e8,%r12d
  jmp    L50
L1:
  mov    %r14d,%r14d
  movq   $0x0,0x0(%r13,%r14,8)
  mov    %r13,%rax
  jmp    L38
L125:
  lea    0x8(%rdx),%rbp
  mov    %rbx,(%rdx)
  mov    %r15,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L60
L57:
  lea    -0x1(%r12),%r14d
  mov    %rbp,%rax
  sub    %r13,%rax
  sar    $0x3,%rax
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  cmp    %rcx,%rax
  jne    L125
  lea    0x3e8(%r12),%ebp
  lea    0x0(,%rbp,8),%esi
  mov    %r13,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L1
  mov    %r12d,%r12d
  lea    -0x8(%rax,%r12,8),%rdx
  mov    %ebp,%r12d
  mov    %rax,%r13
  jmp    L125
L60:
  movq   $0x0,0x0(%rbp)
  lea    0x8(%rbp),%rsi
  sub    %r13d,%esi
  mov    %r13,%rdi
  call   <realloc@plt>
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L84:
  mov    %r13,%rax
  jmp    L38
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: 
	

assistant: ```c
char **split(char **list, char *s) {
  char *cp, **lp;
  unsigned lim;
  if (list) {
    for (lp = list; *lp; ++lp)
      ;
    lim = lp - list + 1;
  } else if ((list = (char **)malloc((1000) * sizeof(char *))))
    lp = list, lim = 1000;
  else
    return NULL;
  for (cp = strtok(s, "\n\t"); cp; cp = strtok(NULL, "\n\t")) {
    if (lp - list == lim - 1) {
      if (!(lp = (char **)realloc((list), (lim + 1000) * sizeof(char *)))) {
        list[lim - 1] = NULL;
        return list;
      }
      list = lp, lp = list + lim - 1, lim += 1000;
    }
    *lp++ = cp;
  }
  *lp++ = NULL;
  return (char **)realloc((list), ((lp - list)) * sizeof(char *));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L123
  cmpq   $0x0,(%rdi)
  mov    %rdi,%r15
  mov    %rdi,%rbp
  je     L112
  xchg   %ax,%ax
L23:
  add    $0x8,%rbp
  cmpq   $0x0,0x0(%rbp)
  jne    L23
  mov    %rbp,%r13
  sub    %r15,%r13
  sar    $0x3,%r13
  add    $0x1,%r13d
L30:
  lea    D3(%rip),%r14
  mov    %r12,%rdi
  mov    %r14,%rsi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L49
  jmp    L84
  nopl   (%rax)
L86:
  mov    %rbx,(%rdx)
  mov    %r14,%rsi
  xor    %edi,%edi
  lea    0x8(%rdx),%rbp
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L84
L49:
  mov    %rbp,%r12
  lea    -0x1(%r13),%eax
  mov    %rbp,%rdx
  sub    %r15,%r12
  sar    $0x3,%r12
  cmp    %rax,%r12
  jne    L86
  lea    0x3e8(%r13),%ebp
  mov    %r15,%rdi
  lea    0x0(,%rbp,8),%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L115
  lea    -0x8(%rax,%r13,8),%rdx
  mov    %rax,%r15
  mov    %ebp,%r13d
  jmp    L86
  nop
L84:
  movq   $0x0,0x0(%rbp)
  lea    0x8(%rbp),%rsi
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  sub    %r15d,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <realloc@plt>
  nopl   (%rax)
L115:
  movq   $0x0,(%r15,%r12,8)
  mov    %r15,%rax
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L123:
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L109
  mov    %rax,%r15
  mov    $0x3e8,%r13d
  jmp    L30
L112:
  mov    $0x1,%r13d
  jmp    L30
L109:
  xor    %eax,%eax
  jmp    L61
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: 
	

assistant: ```c
char **split(char **list, char *s) {
  char *cp, **lp;
  unsigned lim;
  if (list) {
    for (lp = list; *lp; ++lp)
      ;
    lim = lp - list + 1;
  } else if ((list = (char **)malloc((1000) * sizeof(char *))))
    lp = list, lim = 1000;
  else
    return NULL;
  for (cp = strtok(s, "\n\t"); cp; cp = strtok(NULL, "\n\t")) {
    if (lp - list == lim - 1) {
      if (!(lp = (char **)realloc((list), (lim + 1000) * sizeof(char *)))) {
        list[lim - 1] = NULL;
        return list;
      }
      list = lp, lp = list + lim - 1, lim += 1000;
    }
    *lp++ = cp;
  }
  *lp++ = NULL;
  return (char **)realloc((list), ((lp - list)) * sizeof(char *));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L88
  cmpq   $0x0,(%rdi)
  mov    %rdi,%r15
  mov    %rdi,%rbp
  je     L10
  xchg   %ax,%ax
L22:
  add    $0x8,%rbp
  cmpq   $0x0,0x0(%rbp)
  jne    L22
  mov    %rbp,%r13
  sub    %r15,%r13
  sar    $0x3,%r13
  add    $0x1,%r13d
L23:
  lea    D3(%rip),%r14
  mov    %r12,%rdi
  mov    %r14,%rsi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L102
  jmp    L43
  nopl   (%rax)
L129:
  mov    %rbx,(%rdx)
  mov    %r14,%rsi
  xor    %edi,%edi
  lea    0x8(%rdx),%rbp
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L43
L102:
  mov    %rbp,%r12
  lea    -0x1(%r13),%eax
  mov    %rbp,%rdx
  sub    %r15,%r12
  sar    $0x3,%r12
  cmp    %rax,%r12
  jne    L129
  lea    0x3e8(%r13),%ebp
  mov    %r15,%rdi
  lea    0x0(,%rbp,8),%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L30
  lea    -0x8(%rax,%r13,8),%rdx
  mov    %rax,%r15
  mov    %ebp,%r13d
  jmp    L129
  nop
L43:
  movq   $0x0,0x0(%rbp)
  lea    0x8(%rbp),%rsi
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  sub    %r15d,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <realloc@plt>
  nopl   (%rax)
L30:
  movq   $0x0,(%r15,%r12,8)
  mov    %r15,%rax
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L88:
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L38
  mov    %rax,%r15
  mov    $0x3e8,%r13d
  jmp    L23
L10:
  mov    $0x1,%r13d
  jmp    L23
L38:
  xor    %eax,%eax
  jmp    L80
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: 
	

assistant: ```c
char **split(char **list, char *s) {
  char *cp, **lp;
  unsigned lim;
  if (list) {
    for (lp = list; *lp; ++lp)
      ;
    lim = lp - list + 1;
  } else if ((list = (char **)malloc((1000) * sizeof(char *))))
    lp = list, lim = 1000;
  else
    return NULL;
  for (cp = strtok(s, "\n\t"); cp; cp = strtok(NULL, "\n\t")) {
    if (lp - list == lim - 1) {
      if (!(lp = (char **)realloc((list), (lim + 1000) * sizeof(char *)))) {
        list[lim - 1] = NULL;
        return list;
      }
      list = lp, lp = list + lim - 1, lim += 1000;
    }
    *lp++ = cp;
  }
  *lp++ = NULL;
  return (char **)realloc((list), ((lp - list)) * sizeof(char *));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cdrlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L32
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  jmp    L27
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L27:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void cdrlwr(in, iout, inlen) char in[], iout[];
int *inlen;
{
  int i;
  for (i = 0; i <= *inlen - 1; i++) {
    if (isupper(in[i])) {
      iout[i] = tolower(in[i]);
    } else {
      iout[i] = in[i];
    }
  }
}
```