ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ZVaxpy31>:
  endbr64
  movsd  (%r8),%xmm7
  movsd  0x8(%r8),%xmm6
  movsd  0x10(%r8),%xmm5
  movsd  0x18(%r8),%xmm4
  movsd  0x20(%r8),%xmm3
  movsd  0x28(%r8),%xmm2
  test   %edi,%edi
  jle    L3
  movslq %edi,%rdi
  unpcklpd %xmm7,%xmm7
  unpcklpd %xmm6,%xmm6
  xor    %eax,%eax
  unpcklpd %xmm5,%xmm5
  unpcklpd %xmm4,%xmm4
  unpcklpd %xmm3,%xmm3
  shl    $0x4,%rdi
  unpcklpd %xmm2,%xmm2
L19:
  movupd (%r9,%rax,1),%xmm0
  movapd %xmm3,%xmm8
  movapd %xmm5,%xmm10
  movapd %xmm2,%xmm9
  movapd %xmm4,%xmm1
  movupd (%rsi,%rax,1),%xmm13
  mulpd  %xmm0,%xmm8
  movapd %xmm0,%xmm11
  mulpd  %xmm7,%xmm11
  mulpd  %xmm0,%xmm10
  mulpd  %xmm0,%xmm9
  mulpd  %xmm0,%xmm1
  mulpd  %xmm6,%xmm0
  movapd %xmm11,%xmm12
  shufpd $0x1,%xmm9,%xmm9
  shufpd $0x1,%xmm1,%xmm1
  shufpd $0x1,%xmm0,%xmm0
  subpd  %xmm0,%xmm12
  addpd  %xmm11,%xmm0
  movsd  %xmm12,%xmm0
  addpd  %xmm13,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  movapd %xmm10,%xmm0
  subpd  %xmm1,%xmm0
  addpd  %xmm10,%xmm1
  movsd  %xmm0,%xmm1
  movupd (%rdx,%rax,1),%xmm0
  addpd  %xmm0,%xmm1
  movapd %xmm8,%xmm0
  addpd  %xmm9,%xmm0
  movups %xmm1,(%rdx,%rax,1)
  movapd %xmm8,%xmm1
  subpd  %xmm9,%xmm1
  movsd  %xmm1,%xmm0
  movupd (%rcx,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L19
L3:
  ret
```

assistant: ```c
void ZVaxpy31(int n, double y0[], double y1[], double y2[], double alpha[], double x0[]) {
  register double ar00, ar10, ar20;
  register double ai00, ai10, ai20;
  register double xr0i;
  register double xi0i;
  int ii;
  ar00 = alpha[0];
  ai00 = alpha[1];
  ar10 = alpha[2];
  ai10 = alpha[3];
  ar20 = alpha[4];
  ai20 = alpha[5];
  for (ii = 0; ii < n; ii++) {
    xr0i = x0[2 * ii];
    xi0i = x0[2 * ii + 1];
    y0[2 * ii] += (ar00 * xr0i - ai00 * xi0i);
    y0[2 * ii + 1] += (ar00 * xi0i + ai00 * xr0i);
    y1[2 * ii] += (ar10 * xr0i - ai10 * xi0i);
    y1[2 * ii + 1] += (ar10 * xi0i + ai10 * xr0i);
    y2[2 * ii] += (ar20 * xr0i - ai20 * xi0i);
    y2[2 * ii + 1] += (ar20 * xi0i + ai20 * xr0i);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<remove_edge5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x1c(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <remove_edge@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <remove_edge@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <remove_edge@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <remove_edge@plt>
  nop
  leave
  ret
```

assistant: ```c
void remove_edge5(struct graph *g, int a, int b, int c, int d, int e) {
  remove_edge(g, a, b);
  remove_edge(g, b, c);
  remove_edge(g, c, d);
  remove_edge(g, d, e);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<remove_edge5>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r13d
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  mov    %r9d,%r14d
  call   <remove_edge@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <remove_edge@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <remove_edge@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <remove_edge@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void remove_edge5(struct graph *g, int a, int b, int c, int d, int e) {
  remove_edge(g, a, b);
  remove_edge(g, b, c);
  remove_edge(g, c, d);
  remove_edge(g, d, e);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_edge5>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <remove_edge@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <remove_edge@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <remove_edge@plt>
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <remove_edge@plt>
```

assistant: ```c
void remove_edge5(struct graph *g, int a, int b, int c, int d, int e) {
  remove_edge(g, a, b);
  remove_edge(g, b, c);
  remove_edge(g, c, d);
  remove_edge(g, d, e);
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_edge5>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <remove_edge@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <remove_edge@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <remove_edge@plt>
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <remove_edge@plt>
```

assistant: ```c
void remove_edge5(struct graph *g, int a, int b, int c, int d, int e) {
  remove_edge(g, a, b);
  remove_edge(g, b, c);
  remove_edge(g, c, d);
  remove_edge(g, d, e);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aes_block_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <AES_encrypt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void aes_block_encrypt(const unsigned char *key, const unsigned char *plain, int blen, unsigned char *cipher) {
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_encrypt(plain, cipher, &key_ctx);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aes_block_encrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x0(,%rdx,8),%esi
  mov    %r12,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_block_encrypt(const unsigned char *key, const unsigned char *plain, int blen, unsigned char *cipher) {
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_encrypt(plain, cipher, &key_ctx);
}
```
user: What is the c source code of the assembly code below:

```asm
<aes_block_encrypt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x0(,%rdx,8),%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_block_encrypt(const unsigned char *key, const unsigned char *plain, int blen, unsigned char *cipher) {
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_encrypt(plain, cipher, &key_ctx);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aes_block_encrypt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x0(,%rdx,8),%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_block_encrypt(const unsigned char *key, const unsigned char *plain, int blen, unsigned char *cipher) {
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_encrypt(plain, cipher, &key_ctx);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trunc_dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  cmpl   $0x2f,-0xc(%rbp)
  je     L26
  subq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L32
  jmp    L23
L26:
  nop
L23:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trunc_dirname(char *dir) {
  char *s = dir + strlen(dir);
  while (s != dir) {
    int c = *s;
    *s = 0;
    if (c == '/')
      break;
    s--;
  }
  return (dir);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trunc_dirname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  je     L27
L18:
  movzbl (%rax),%edx
  movb   $0x0,(%rax)
  cmp    $0x2f,%dl
  je     L27
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L18
L27:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *trunc_dirname(char *dir) {
  char *s = dir + strlen(dir);
  while (s != dir) {
    int c = *s;
    *s = 0;
    if (c == '/')
      break;
    s--;
  }
  return (dir);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trunc_dirname>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  cmp    %rax,%r12
  jne    L19
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L35:
  sub    $0x1,%rax
  cmp    %rax,%r12
  je     L1
L19:
  movzbl (%rax),%edx
  movb   $0x0,(%rax)
  cmp    $0x2f,%dl
  jne    L35
L1:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trunc_dirname(char *dir) {
  char *s = dir + strlen(dir);
  while (s != dir) {
    int c = *s;
    *s = 0;
    if (c == '/')
      break;
    s--;
  }
  return (dir);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trunc_dirname>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  cmp    %rax,%r12
  jne    L38
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%rax
  cmp    %rax,%r12
  je     L12
L38:
  movzbl (%rax),%edx
  movb   $0x0,(%rax)
  cmp    $0x2f,%dl
  jne    L9
L12:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trunc_dirname(char *dir) {
  char *s = dir + strlen(dir);
  while (s != dir) {
    int c = *s;
    *s = 0;
    if (c == '/')
      break;
    s--;
  }
  return (dir);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  movl   $0x25,-0x38(%rbp)
  cmpl   $0x1,-0x44(%rbp)
  jle    L36
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jg     L36
  movl   $0x25,-0x38(%rbp)
L36:
  movq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L50
L33:
  mov    -0x28(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x34(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L66
L2:
  mov    -0x20(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x34(%rbp)
L66:
  cmpl   $0x8,-0x34(%rbp)
  jg     L32
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jbe    L2
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L50
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  ja     L50
  subl   $0x1,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  sub    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x28(%rbp)
L50:
  cmpl   $0x0,-0x38(%rbp)
  jg     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 37;
  if (argc > 1) {
    n = atoi(argv[1]);
    if (n <= 0)
      n = 37;
  }
  unsigned long long p0, p1, q0, q1, r0, r1;
  p0 = p1 = q1 = 1;
  q0 = 0;
  while (n > 0) {
    r0 = p0 + (p1 << 1);
    p0 = p1;
    p1 = r0;
    r0 = q0 + (q1 << 1);
    q0 = q1;
    q1 = r0;
    int digit = 0;
    r0 = q0;
    r1 = q1;
    while (digit < 9 && r0 <= p0) {
      r0 += q0;
      r1 += q1;
      digit++;
    }
    if (r1 > p1) {
      r1 -= q1;
      if (r1 <= p1) {
        n--;
        putchar(digit + '0');
        p1 -= r1;
        r0 -= q0;
        p0 -= r0;
        p0 = ((p0 << 2) + p0) << 1;
        p1 = ((p1 << 2) + p1) << 1;
      }
    }
  }
  putchar('\n');
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x25,0xc(%rsp)
  cmp    $0x1,%edi
  jg     L9
L0:
  mov    $0x1,%r13d
  mov    $0x0,%edx
  mov    $0x1,%r12d
  mov    $0x1,%eax
  jmp    L10
L9:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jg     L0
  movl   $0x25,0xc(%rsp)
  jmp    L0
L60:
  mov    %r13,%rbx
  mov    %r14,%rbp
  mov    $0x0,%eax
L65:
  subl   $0x1,0xc(%rsp)
  add    $0x30,%eax
  movsbl %al,%edi
  call   <putchar@plt>
  add    %r14,%r12
  sub    %rbp,%r12
  lea    (%r12,%r12,4),%rax
  add    %rax,%rax
  add    %r13,%r15
  sub    %rbx,%r15
  lea    (%r15,%r15,4),%r12
  add    %r12,%r12
  jmp    L59
L28:
  mov    %r12,%rax
  mov    %r15,%r12
L59:
  mov    %r14,%rdx
  cmpl   $0x0,0xc(%rsp)
  jle    L128
L10:
  lea    (%rax,%r12,2),%r15
  mov    %r13,%r14
  lea    (%rdx,%r13,2),%r13
  cmp    %r14,%r12
  jb     L31
  mov    %r13,%rbx
  mov    %r14,%rbp
  mov    $0x0,%eax
L20:
  add    %r14,%rbp
  mov    %rbx,%rdx
  add    %r13,%rbx
  add    $0x1,%eax
  cmp    $0x8,%eax
  jg     L38
  cmp    %r12,%rbp
  jbe    L20
L38:
  cmp    %rbx,%r15
  jae    L28
  cmp    %rdx,%r15
  jae    L65
  mov    %r12,%rax
  mov    %r15,%r12
  jmp    L59
L31:
  cmp    %r13,%r15
  jb     L60
  mov    %r12,%rax
  mov    %r15,%r12
  jmp    L59
L128:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 37;
  if (argc > 1) {
    n = atoi(argv[1]);
    if (n <= 0)
      n = 37;
  }
  unsigned long long p0, p1, q0, q1, r0, r1;
  p0 = p1 = q1 = 1;
  q0 = 0;
  while (n > 0) {
    r0 = p0 + (p1 << 1);
    p0 = p1;
    p1 = r0;
    r0 = q0 + (q1 << 1);
    q0 = q1;
    q1 = r0;
    int digit = 0;
    r0 = q0;
    r1 = q1;
    while (digit < 9 && r0 <= p0) {
      r0 += q0;
      r1 += q1;
      digit++;
    }
    if (r1 > p1) {
      r1 -= q1;
      if (r1 <= p1) {
        n--;
        putchar(digit + '0');
        p1 -= r1;
        r0 -= q0;
        p0 -= r0;
        p0 = ((p0 << 2) + p0) << 1;
        p1 = ((p1 << 2) + p1) << 1;
      }
    }
  }
  putchar('\n');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jg     L76
L11:
  mov    $0x25,%ecx
L43:
  mov    $0x1,%r12d
  xor    %edx,%edx
  mov    $0x1,%r13d
  mov    $0x1,%eax
  lea    (%rax,%r13,2),%r15
  lea    (%rdx,%r12,2),%r14
  cmp    %r12,%r13
  jb     L73
L90:
  mov    %r14,%rbx
  mov    %r12,%rbp
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%eax
  mov    %rbx,%rdx
  add    %r12,%rbp
  add    %r14,%rbx
  cmp    $0x8,%eax
  jg     L44
  cmp    %r13,%rbp
  jbe    L54
L44:
  cmp    %rbx,%r15
  jae    L21
  cmp    %r15,%rdx
  jbe    L108
L21:
  mov    %r12,%rdx
  mov    %r13,%rax
  mov    %r14,%r12
  mov    %r15,%r13
  lea    (%rax,%r13,2),%r15
  lea    (%rdx,%r12,2),%r14
  cmp    %r12,%r13
  jae    L90
L73:
  cmp    %r14,%r15
  jae    L21
  mov    %r12,%rbp
  mov    %r14,%rbx
  xor    %eax,%eax
L108:
  add    $0x30,%eax
  sub    $0x1,%ecx
  add    %r12,%r13
  add    %r14,%r15
  movzbl %al,%edi
  mov    %ecx,0xc(%rsp)
  sub    %rbp,%r13
  sub    %rbx,%r15
  call   <putchar@plt>
  mov    0xc(%rsp),%ecx
  lea    0x0(%r13,%r13,4),%r13
  lea    (%r15,%r15,4),%r15
  add    %r13,%r13
  add    %r15,%r15
  test   %ecx,%ecx
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jg     L43
  jmp    L11
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 37;
  if (argc > 1) {
    n = atoi(argv[1]);
    if (n <= 0)
      n = 37;
  }
  unsigned long long p0, p1, q0, q1, r0, r1;
  p0 = p1 = q1 = 1;
  q0 = 0;
  while (n > 0) {
    r0 = p0 + (p1 << 1);
    p0 = p1;
    p1 = r0;
    r0 = q0 + (q1 << 1);
    q0 = q1;
    q1 = r0;
    int digit = 0;
    r0 = q0;
    r1 = q1;
    while (digit < 9 && r0 <= p0) {
      r0 += q0;
      r1 += q1;
      digit++;
    }
    if (r1 > p1) {
      r1 -= q1;
      if (r1 <= p1) {
        n--;
        putchar(digit + '0');
        p1 -= r1;
        r0 -= q0;
        p0 -= r0;
        p0 = ((p0 << 2) + p0) << 1;
        p1 = ((p1 << 2) + p1) << 1;
      }
    }
  }
  putchar('\n');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<heap_shift_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L36
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L36
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L72:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L38
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L38
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L6
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L72
  jmp    L9
L6:
  nop
L9:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L44
L36:
  nop
L44:
  pop    %rbp
  ret
```

assistant: ```c
void heap_shift_up(int *arr, int low, int high) {
  if (arr == NULL || low == high)
    return;
  int tmp = arr[low];
  int i;
  for (i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && arr[i] < arr[i + 1])
      i++;
    if (tmp >= arr[i])
      break;
    arr[low] = arr[i];
    low = i;
  }
  arr[low] = tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heap_shift_up>:
  endbr64
  test   %rdi,%rdi
  je     L73
  cmp    %edx,%esi
  je     L73
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r9d
  lea    0x1(%rsi,%rsi,1),%eax
  cmp    %eax,%edx
  jge    L79
  jmp    L69
L24:
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%eax
  cmp    %r9d,%eax
  jle    L69
  movslq %esi,%rsi
  mov    %eax,(%rdi,%rsi,4)
  lea    0x1(%rcx,%rcx,1),%eax
  cmp    %eax,%edx
  jl     L22
  mov    %ecx,%esi
L79:
  mov    %eax,%ecx
  cmp    %eax,%edx
  jle    L24
  movslq %eax,%r8
  mov    0x4(%rdi,%r8,4),%r10d
  cmp    %r10d,(%rdi,%r8,4)
  jge    L24
  lea    0x1(%rax),%ecx
  jmp    L24
L22:
  mov    %ecx,%esi
L69:
  movslq %esi,%rsi
  mov    %r9d,(%rdi,%rsi,4)
L73:
  ret
```

assistant: ```c
void heap_shift_up(int *arr, int low, int high) {
  if (arr == NULL || low == high)
    return;
  int tmp = arr[low];
  int i;
  for (i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && arr[i] < arr[i + 1])
      i++;
    if (tmp >= arr[i])
      break;
    arr[low] = arr[i];
    low = i;
  }
  arr[low] = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<heap_shift_up>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  je     L45
  cmp    %edx,%esi
  je     L45
  movslq %esi,%r10
  lea    0x1(%rsi,%rsi,1),%esi
  lea    (%rdi,%r10,4),%rax
  mov    (%rax),%r11d
  cmp    %esi,%edx
  jge    L88
  jmp    L89
  nopl   0x0(%rax)
L59:
  lea    0x1(%rcx,%rcx,1),%esi
  mov    %edi,(%rax)
  cmp    %esi,%edx
  jl     L33
  movslq %ecx,%r10
L88:
  movslq %esi,%rax
  mov    %esi,%ecx
  shl    $0x2,%rax
  lea    (%r8,%rax,1),%r9
  mov    (%r9),%edi
  cmp    %esi,%edx
  jle    L34
  lea    0x4(%r8,%rax,1),%rax
  mov    (%rax),%esi
  cmp    %edi,%esi
  jle    L34
  add    $0x1,%ecx
  mov    %esi,%edi
  mov    %rax,%r9
L34:
  lea    (%r8,%r10,4),%rax
  cmp    %edi,%r11d
  jl     L59
L89:
  mov    %r11d,(%rax)
L45:
  ret
  nopl   0x0(%rax)
L33:
  mov    %r9,%rax
  mov    %r11d,(%rax)
  jmp    L45
```

assistant: ```c
void heap_shift_up(int *arr, int low, int high) {
  if (arr == NULL || low == high)
    return;
  int tmp = arr[low];
  int i;
  for (i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && arr[i] < arr[i + 1])
      i++;
    if (tmp >= arr[i])
      break;
    arr[low] = arr[i];
    low = i;
  }
  arr[low] = tmp;
}
```