ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  and    $0x7fffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash_addr(void *addr) {
  unsigned long key = (unsigned long)addr;
  return (unsigned)(((key >> 3) * 2654435761) % 0x80000000);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash_addr>:
  endbr64
  mov    %rdi,%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  and    $0x7fffffff,%eax
  ret
```

assistant: ```c
unsigned hash_addr(void *addr) {
  unsigned long key = (unsigned long)addr;
  return (unsigned)(((key >> 3) * 2654435761) % 0x80000000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_addr>:
  endbr64
  mov    %rdi,%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  and    $0x7fffffff,%eax
  ret
```

assistant: ```c
unsigned hash_addr(void *addr) {
  unsigned long key = (unsigned long)addr;
  return (unsigned)(((key >> 3) * 2654435761) % 0x80000000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_addr>:
  endbr64
  mov    %rdi,%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  and    $0x7fffffff,%eax
  ret
```

assistant: ```c
unsigned hash_addr(void *addr) {
  unsigned long key = (unsigned long)addr;
  return (unsigned)(((key >> 3) * 2654435761) % 0x80000000);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a4(%rbp)
  lea    -0x1a8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L4
L39:
  mov    -0x1a8(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a8(%rbp),%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x1a8(%rbp)
  addl   $0x1,-0x1a4(%rbp)
L4:
  mov    -0x1a8(%rbp),%eax
  test   %eax,%eax
  jne    L39
  subl   $0x1,-0x1a4(%rbp)
  jmp    L14
L13:
  mov    -0x1a4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1a4(%rbp)
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  cmpl   $0x0,-0x1a4(%rbp)
  jns    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], n, i = 0;
  scanf("%d", &n);
  while (n != 0) {
    a[i] = n % 8;
    n = (n - a[i]) / 8;
    i++;
  }
  i--;
  while (i >= 0)
    printf("%d", a[i--]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L44
  mov    $0x0,%ecx
L1:
  mov    %ecx,%edi
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1d,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0x7,%edx
  sub    %esi,%edx
  mov    %edx,0x10(%rsp,%rcx,4)
  sub    %edx,%eax
  lea    0x7(%rax),%edx
  cmovns %eax,%edx
  sar    $0x3,%edx
  mov    %edx,%eax
  mov    %rcx,%rsi
  add    $0x1,%rcx
  test   %edx,%edx
  jne    L1
  movl   $0x0,0xc(%rsp)
  test   %edi,%edi
  js     L44
  movslq %edi,%rdi
  shl    $0x2,%rdi
  lea    0x10(%rsp,%rdi,1),%rbx
  lea    0xc(%rsp,%rdi,1),%rbp
  mov    %esi,%esi
  shl    $0x2,%rsi
  sub    %rsi,%rbp
  lea    D11(%rip),%r12
L23:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L23
L44:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type_infered: string

tool: D11: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], n, i = 0;
  scanf("%d", &n);
  while (n != 0) {
    a[i] = n % 8;
    n = (n - a[i]) / 8;
    i++;
  }
  i--;
  while (i >= 0)
    printf("%d", a[i--]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  xor    %ecx,%ecx
  test   %eax,%eax
  je     L27
  nopl   (%rax)
L17:
  cltd
  mov    %ecx,%ebp
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%esi
  and    $0x7,%esi
  sub    %edx,%esi
  sub    %esi,%eax
  mov    %esi,(%r12,%rcx,4)
  lea    0x7(%rax),%edx
  cmovs  %edx,%eax
  add    $0x1,%rcx
  sar    $0x3,%eax
  jne    L17
  sub    $0x1,%ebp
  movl   $0x0,0xc(%rsp)
  movslq %ebp,%rbp
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%r12,%rbp,4),%esi
  sub    $0x1,%rbp
L22:
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    $0xffffffff,%ebp
  jne    L8
L27:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], n, i = 0;
  scanf("%d", &n);
  while (n != 0) {
    a[i] = n % 8;
    n = (n - a[i]) / 8;
    i++;
  }
  i--;
  while (i >= 0)
    printf("%d", a[i--]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbp
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  xor    %ecx,%ecx
  test   %eax,%eax
  je     L34
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %eax,%esi
  movslq %ecx,%rdi
  sar    $0x1f,%esi
  shr    $0x1d,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0x7,%edx
  sub    %esi,%edx
  sub    %edx,%eax
  mov    %edx,0x0(%rbp,%rcx,4)
  lea    0x7(%rax),%edx
  cmovs  %edx,%eax
  mov    %rcx,%rdx
  add    $0x1,%rcx
  sar    $0x3,%eax
  jne    L1
  shl    $0x2,%rdi
  movl   $0x0,0xc(%rsp)
  shl    $0x2,%rdx
  add    %rdi,%r12
  add    %rdi,%rbp
  sub    %rdx,%r12
  nopl   0x0(%rax)
L8:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  sub    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L8
L34:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], n, i = 0;
  scanf("%d", &n);
  while (n != 0) {
    a[i] = n % 8;
    n = (n - a[i]) / 8;
    i++;
  }
  i--;
  while (i >= 0)
    printf("%d", a[i--]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L18
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L14
L18:
  mov    -0x14(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int mod(int a) {
  if (a < 0) {
    int b = -a;
    return b;
  } else {
    return a;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int mod(int a) {
  if (a < 0) {
    int b = -a;
    return b;
  } else {
    return a;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int mod(int a) {
  if (a < 0) {
    int b = -a;
    return b;
  } else {
    return a;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int mod(int a) {
  if (a < 0) {
    int b = -a;
    return b;
  } else {
    return a;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ftypelet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  je     L25
  mov    $0x63,%eax
  jmp    L31
L25:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L2
  mov    $0x64,%eax
  jmp    L31
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L50
  mov    $0x2d,%eax
  jmp    L31
L50:
  mov    $0x3f,%eax
L31:
  leave
  ret
```

assistant: ```c
char ftypelet(long bits) {
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISREG(bits))
    return '-';
  return '?';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ftypelet>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <S_ISCHR@plt>
  mov    %rax,%rdx
  mov    $0x63,%eax
  test   %rdx,%rdx
  je     L6
L24:
  pop    %rbx
  ret
L6:
  mov    %rbx,%rdi
  call   <S_ISDIR@plt>
  mov    %rax,%rdx
  mov    $0x64,%eax
  test   %rdx,%rdx
  jne    L24
  mov    %rbx,%rdi
  call   <S_ISREG@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x12,%eax
  add    $0x2d,%eax
  jmp    L24
```

assistant: ```c
char ftypelet(long bits) {
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISREG(bits))
    return '-';
  return '?';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ftypelet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <S_ISCHR@plt>
  mov    %rax,%r8
  mov    $0x63,%eax
  test   %r8,%r8
  je     L12
L19:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  mov    %rbp,%rdi
  call   <S_ISDIR@plt>
  mov    %rax,%r8
  mov    $0x64,%eax
  test   %r8,%r8
  jne    L19
  mov    %rbp,%rdi
  call   <S_ISREG@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x12,%eax
  add    $0x2d,%eax
  ret
```

assistant: ```c
char ftypelet(long bits) {
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISREG(bits))
    return '-';
  return '?';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ftypelet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <S_ISCHR@plt>
  mov    %rax,%r8
  mov    $0x63,%eax
  test   %r8,%r8
  je     L17
L10:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  mov    %rbp,%rdi
  call   <S_ISDIR@plt>
  mov    %rax,%r8
  mov    $0x64,%eax
  test   %r8,%r8
  jne    L10
  mov    %rbp,%rdi
  call   <S_ISREG@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x12,%eax
  add    $0x2d,%eax
  ret
```

assistant: ```c
char ftypelet(long bits) {
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISREG(bits))
    return '-';
  return '?';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putnbr_off_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L26
L1:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  cmp    $0x9,%eax
  jg     L1
  jmp    L21
L25:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  add    $0x30,%eax
  mov    %al,-0xd(%rbp)
  lea    -0xd(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L21:
  cmpl   $0x0,-0xc(%rbp)
  jg     L25
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
void ft_putnbr_off_t(off_t n, pid_t pid) {
  off_t decim;
  char c;
  decim = 1;
  while ((n / decim) > 9)
    decim *= 10;
  while (decim > 0) {
    c = (n / decim) % 10 + '0';
    write(pid, &c, 1);
    decim /= 10;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_putnbr_off_t>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  jle    L54
  mov    $0x1,%ebx
L38:
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  cmp    $0x9,%eax
  jg     L38
  test   %ebx,%ebx
  jle    L37
  lea    0x7(%rsp),%r13
L55:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,0x7(%rsp)
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    %ebx,%edx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  cmp    $0x9,%edx
  jg     L55
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%eax
  mov    %al,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  call   <write@plt>
  jmp    L37
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ft_putnbr_off_t(off_t n, pid_t pid) {
  off_t decim;
  char c;
  decim = 1;
  while ((n / decim) > 9)
    decim *= 10;
  while (decim > 0) {
    c = (n / decim) % 10 + '0';
    write(pid, &c, 1);
    decim /= 10;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_putnbr_off_t>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  jle    L5
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebp,%eax
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  cltd
  idiv   %ebx
  cmp    $0x9,%eax
  jg     L20
  lea    0x7(%rsp),%r13
  mov    $0xcccccccd,%r12d
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebp,%eax
  mov    %r13,%rsi
  mov    %r14d,%edi
  cltd
  idiv   %ebx
  mov    %ebx,%ebx
  imul   %r12,%rbx
  shr    $0x23,%rbx
  mov    %eax,%edx
  imul   %r12,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    $0x1,%edx
  add    $0x30,%eax
  mov    %al,0x7(%rsp)
  call   <write@plt>
  test   %ebx,%ebx
  jne    L7
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  movslq %edi,%rax
  mov    %edi,%edx
  lea    0x7(%rsp),%rsi
  mov    %r14d,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    $0x1,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%eax
  mov    %al,0x7(%rsp)
  call   <write@plt>
  jmp    L35
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ft_putnbr_off_t(off_t n, pid_t pid) {
  off_t decim;
  char c;
  decim = 1;
  while ((n / decim) > 9)
    decim *= 10;
  while (decim > 0) {
    c = (n / decim) % 10 + '0';
    write(pid, &c, 1);
    decim /= 10;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_putnbr_off_t>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  jle    L46
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebp,%eax
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  cltd
  idiv   %ebx
  cmp    $0x9,%eax
  jg     L1
  lea    0x7(%rsp),%r13
  mov    $0xcccccccd,%r12d
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %ebp,%eax
  mov    %r13,%rsi
  mov    %r14d,%edi
  cltd
  idiv   %ebx
  mov    %ebx,%ebx
  imul   %r12,%rbx
  shr    $0x23,%rbx
  mov    %eax,%edx
  imul   %r12,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    $0x1,%edx
  add    $0x30,%eax
  mov    %al,0x7(%rsp)
  call   <write@plt>
  test   %ebx,%ebx
  jne    L31
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  movslq %edi,%rax
  mov    %edi,%edx
  lea    0x7(%rsp),%rsi
  mov    %r14d,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    $0x1,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%eax
  mov    %al,0x7(%rsp)
  call   <write@plt>
  jmp    L18
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ft_putnbr_off_t(off_t n, pid_t pid) {
  off_t decim;
  char c;
  decim = 1;
  while ((n / decim) > 9)
    decim *= 10;
  while (decim > 0) {
    c = (n / decim) % 10 + '0';
    write(pid, &c, 1);
    decim /= 10;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
L0:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L29
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
  jmp    L0
L29:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int res;
  while (1) {
    if ((res = tolower(*s1) - tolower(*s2)) != 0 || *s1 == '\0')
      break;
    s1++, s2++;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  jmp    L10
L0:
  add    $0x1,%rbp
  add    $0x1,%r12
L10:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <tolower@plt>
  sub    %eax,%ebx
  jne    L13
  cmpb   $0x0,0x0(%rbp)
  jne    L0
L13:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int res;
  while (1) {
    if ((res = tolower(*s1) - tolower(*s2)) != 0 || *s1 == '\0')
      break;
    s1++, s2++;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L2
L23:
  cmpb   $0x0,0x0(%rbp)
  je     L18
  add    $0x1,%rbp
  add    $0x1,%r12
L2:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  sub    %eax,%ebx
  je     L23
L18:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int res;
  while (1) {
    if ((res = tolower(*s1) - tolower(*s2)) != 0 || *s1 == '\0')
      break;
    s1++, s2++;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L0
L5:
  cmpb   $0x0,0x0(%rbp)
  je     L3
  add    $0x1,%rbp
  add    $0x1,%r12
L0:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  sub    %eax,%ebx
  je     L5
L3:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int res;
  while (1) {
    if ((res = tolower(*s1) - tolower(*s2)) != 0 || *s1 == '\0')
      break;
    s1++, s2++;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <read_tok@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: temp.txt

assistant: ```c
int main() {
  read_tok("temp.txt");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <read_tok@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: temp.txt

assistant: ```c
int main() {
  read_tok("temp.txt");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <read_tok@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: temp.txt

assistant: ```c
int main() {
  read_tok("temp.txt");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <read_tok@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: temp.txt

assistant: ```c
int main() {
  read_tok("temp.txt");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<inputDatiDouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x1,%edi
  call   <stampaErrori@plt>
L16:
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D5: %lf

tool: D0: %*[^%
]

assistant: ```c
void inputDatiDouble(double *streamOutputPtr) {
  int esitoScanf = 0;
  do {
    esitoScanf = scanf("%lf", streamOutputPtr);
    if (esitoScanf == 0) {
      scanf("%*[^%\n]");
      stampaErrori(1);
    }
  } while (esitoScanf == 0);
  return;
}
```