ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<max_seq>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%edx
L12:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L12
L25:
  mov    %edx,%eax
  ret
L6:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
int max_seq(int *tab, int nelt) {
  int i, maxv;
  maxv = 0;
  for (i = 0; i < nelt; i++) {
    if (tab[i] > maxv) {
      maxv = tab[i];
    }
  }
  return maxv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max_seq>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L6
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int max_seq(int *tab, int nelt) {
  int i, maxv;
  maxv = 0;
  for (i = 0; i < nelt; i++) {
    if (tab[i] > maxv) {
      maxv = tab[i];
    }
  }
  return maxv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max_seq>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L43
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L3
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm2,%xmm2
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L7:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L7
  movdqa %xmm2,%xmm0
  mov    %edx,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%ecx
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L22
L42:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L17
  mov    0x4(%rdi,%r8,1),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jle    L17
  mov    0x8(%rdi,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  xor    %eax,%eax
L17:
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  ret
L3:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L42
```

assistant: ```c
int max_seq(int *tab, int nelt) {
  int i, maxv;
  maxv = 0;
  for (i = 0; i < nelt; i++) {
    if (tab[i] > maxv) {
      maxv = tab[i];
    }
  }
  return maxv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D6: %d + %d = %d


tool: D5: %d - %d = %d


assistant: ```c
int main() {
  int a = 4;
  int b = 2;
  print("%d + %d = %d\n", a, b, a + b);
  print("%d - %d = %d\n", a, b, a - b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%ecx
  mov    $0x2,%edx
  mov    $0x4,%esi
  lea    D3(%rip),%rdi
  call   <print@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x4,%esi
  lea    D5(%rip),%rdi
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D3: %d + %d = %d


tool: D5: %d - %d = %d


assistant: ```c
int main() {
  int a = 4;
  int b = 2;
  print("%d + %d = %d\n", a, b, a + b);
  print("%d - %d = %d\n", a, b, a - b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%ecx
  mov    $0x2,%edx
  mov    $0x4,%esi
  lea    D0(%rip),%rdi
  call   <print@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x4,%esi
  lea    D11(%rip),%rdi
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D11
type: string

tool: D0: %d + %d = %d


tool: D11: %d - %d = %d


assistant: ```c
int main() {
  int a = 4;
  int b = 2;
  print("%d + %d = %d\n", a, b, a + b);
  print("%d - %d = %d\n", a, b, a - b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%ecx
  mov    $0x2,%edx
  mov    $0x4,%esi
  lea    D5(%rip),%rdi
  call   <print@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x4,%esi
  lea    D18(%rip),%rdi
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D18
type: string

tool: D5: %d + %d = %d


tool: D18: %d - %d = %d


assistant: ```c
int main() {
  int a = 4;
  int b = 2;
  print("%d + %d = %d\n", a, b, a + b);
  print("%d - %d = %d\n", a, b, a - b);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bn_cmp_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L76
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L29
  mov    $0x1,%eax
  jmp    L15
L29:
  mov    $0xffffffff,%eax
  jmp    L15
L76:
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L37
L1:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L99
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L33
  mov    $0x1,%eax
  jmp    L15
L33:
  mov    $0xffffffff,%eax
  jmp    L15
L99:
  subl   $0x1,-0x14(%rbp)
L37:
  cmpl   $0x0,-0x14(%rbp)
  jns    L1
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int bn_cmp_words(unsigned long long *a, unsigned long long *b, int n) {
  int i;
  unsigned long long aa, bb;
  aa = a[n - 1];
  bb = b[n - 1];
  if (aa != bb)
    return ((aa > bb) ? 1 : -1);
  for (i = n - 2; i >= 0; i--) {
    aa = a[i];
    bb = b[i];
    if (aa != bb)
      return ((aa > bb) ? 1 : -1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bn_cmp_words>:
  endbr64
  movslq %edx,%rax
  shl    $0x3,%rax
  mov    -0x8(%rdi,%rax,1),%rcx
  mov    -0x8(%rsi,%rax,1),%rax
  cmp    %rax,%rcx
  je     L11
  cmp    %rcx,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
L11:
  sub    $0x2,%edx
  js     L20
  movslq %edx,%rax
L16:
  mov    (%rdi,%rax,8),%rdx
  mov    (%rsi,%rax,8),%rcx
  cmp    %rcx,%rdx
  jne    L7
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L16
  mov    $0x0,%eax
  ret
L7:
  cmp    %rdx,%rcx
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int bn_cmp_words(unsigned long long *a, unsigned long long *b, int n) {
  int i;
  unsigned long long aa, bb;
  aa = a[n - 1];
  bb = b[n - 1];
  if (aa != bb)
    return ((aa > bb) ? 1 : -1);
  for (i = n - 2; i >= 0; i--) {
    aa = a[i];
    bb = b[i];
    if (aa != bb)
      return ((aa > bb) ? 1 : -1);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bn_cmp_words>:
  endbr64
  movslq %edx,%rax
  shl    $0x3,%rax
  mov    -0x8(%rdi,%rax,1),%rcx
  mov    -0x8(%rsi,%rax,1),%rax
  cmp    %rax,%rcx
  je     L6
  cmp    %rcx,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  sub    $0x2,%edx
  js     L22
  movslq %edx,%rax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L27:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L22
L8:
  mov    (%rdi,%rax,8),%rdx
  mov    (%rsi,%rax,8),%rcx
  cmp    %rcx,%rdx
  je     L27
  cmp    %rdx,%rcx
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bn_cmp_words(unsigned long long *a, unsigned long long *b, int n) {
  int i;
  unsigned long long aa, bb;
  aa = a[n - 1];
  bb = b[n - 1];
  if (aa != bb)
    return ((aa > bb) ? 1 : -1);
  for (i = n - 2; i >= 0; i--) {
    aa = a[i];
    bb = b[i];
    if (aa != bb)
      return ((aa > bb) ? 1 : -1);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bn_cmp_words>:
  endbr64
  movslq %edx,%rax
  shl    $0x3,%rax
  mov    -0x8(%rdi,%rax,1),%rcx
  mov    -0x8(%rsi,%rax,1),%rax
  cmp    %rax,%rcx
  je     L15
  cmp    %rcx,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  sub    $0x2,%edx
  js     L3
  movslq %edx,%rax
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L38:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L3
L1:
  mov    (%rdi,%rax,8),%rdx
  mov    (%rsi,%rax,8),%rcx
  cmp    %rcx,%rdx
  je     L38
  cmp    %rdx,%rcx
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bn_cmp_words(unsigned long long *a, unsigned long long *b, int n) {
  int i;
  unsigned long long aa, bb;
  aa = a[n - 1];
  bb = b[n - 1];
  if (aa != bb)
    return ((aa > bb) ? 1 : -1);
  for (i = n - 2; i >= 0; i--) {
    aa = a[i];
    bb = b[i];
    if (aa != bb)
      return ((aa > bb) ? 1 : -1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x64(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gets@plt>
  mov    -0x64(%rbp),%eax
  cmp    $0xa0d00,%eax
  jne    L13
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L13:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D9: buf: %08x cookie: %08x


tool: D7: you win!

assistant: ```c
int main() {
  int cookie;
  char buf[80];
  printf("buf: %08x cookie: %08x\n", &buf, &cookie);
  gets(buf);
  if (cookie == 0x000a0d00)
    printf("you win!\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <gets@plt>
  cmpl   $0xa0d00,0xc(%rsp)
  je     L14
L26:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L14:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L26
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: string

tool: D9: buf: %08x cookie: %08x


tool: D11: you win!

assistant: ```c
int main() {
  int cookie;
  char buf[80];
  printf("buf: %08x cookie: %08x\n", &buf, &cookie);
  gets(buf);
  if (cookie == 0x000a0d00)
    printf("you win!\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <gets@plt>
  cmpl   $0xa0d00,0xc(%rsp)
  je     L2
L7:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D3: buf: %08x cookie: %08x


tool: D6: you win!

assistant: ```c
int main() {
  int cookie;
  char buf[80];
  printf("buf: %08x cookie: %08x\n", &buf, &cookie);
  gets(buf);
  if (cookie == 0x000a0d00)
    printf("you win!\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <gets@plt>
  cmpl   $0xa0d00,0xc(%rsp)
  je     L9
L6:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string

tool: D8: buf: %08x cookie: %08x


tool: D11: you win!

assistant: ```c
int main() {
  int cookie;
  char buf[80];
  printf("buf: %08x cookie: %08x\n", &buf, &cookie);
  gets(buf);
  if (cookie == 0x000a0d00)
    printf("you win!\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sock_prepare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcpy@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <strlen@plt>
  cltq
  add    $0x4,%rax
  mov    %rax,-0x20(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%ecx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L3
L2:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  test   %rax,%rax
  je     L24
  mov    $0xffffffff,%eax
  jmp    L3
L24:
  mov    -0x24(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <listen@plt>
  test   %rax,%rax
  je     L63
  mov    $0xffffffff,%eax
  jmp    L3
L63:
  mov    -0x24(%rbp),%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int sock_prepare(const char const *path) {
  int sock;
  size_t sock_addr_len;
  struct sockaddr_un sock_addr = {0};
  sock_addr.sun_family = AF_UNIX;
  strcpy(sock_addr.sun_path, path);
  sock_addr_len = sizeof(sock_addr.sun_family) + strlen(sock_addr.sun_path);
  sock = socket(AF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(path);
  if (bind(sock, (struct sockaddr *)&sock_addr, sock_addr_len))
    return -1;
  if (listen(sock, 5))
    return -1;
  return sock;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sock_prepare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    D16(%rip),%rbx
  mov    (%rbx),%eax
  mov    %eax,0x10(%rsp)
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <strcpy@plt>
  mov    0xc(%rsp),%edi
  call   <strlen@plt>
  cltq
  lea    0x4(%rax),%rbp
  mov    $0x0,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    (%rbx),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L35
  mov    %r12,%rdi
  call   <unlink@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %ebx,%edi
  call   <bind@plt>
  test   %rax,%rax
  jne    L3
  mov    $0x5,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %eax,%ebx
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0xffffffff,%ebx
  jmp    L35
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_prepare(const char const *path) {
  int sock;
  size_t sock_addr_len;
  struct sockaddr_un sock_addr = {0};
  sock_addr.sun_family = AF_UNIX;
  strcpy(sock_addr.sun_path, path);
  sock_addr_len = sizeof(sock_addr.sun_family) + strlen(sock_addr.sun_path);
  sock = socket(AF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(path);
  if (bind(sock, (struct sockaddr *)&sock_addr, sock_addr_len))
    return -1;
  if (listen(sock, 5))
    return -1;
  return sock;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sock_prepare>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x20,%rsp
  mov    D15(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    (%r12),%eax
  mov    %eax,0x10(%rsp)
  call   <strcpy@plt>
  mov    0xc(%rsp),%edi
  call   <strlen@plt>
  mov    (%r12),%edi
  xor    %edx,%edx
  cltq
  lea    0x4(%rax),%r13
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <unlink@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdx
  mov    %r12d,%edi
  call   <bind@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  test   %rax,%rax
  jne    L7
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xffffffff,%r12d
  jmp    L29
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_prepare(const char const *path) {
  int sock;
  size_t sock_addr_len;
  struct sockaddr_un sock_addr = {0};
  sock_addr.sun_family = AF_UNIX;
  strcpy(sock_addr.sun_path, path);
  sock_addr_len = sizeof(sock_addr.sun_family) + strlen(sock_addr.sun_path);
  sock = socket(AF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(path);
  if (bind(sock, (struct sockaddr *)&sock_addr, sock_addr_len))
    return -1;
  if (listen(sock, 5))
    return -1;
  return sock;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sock_prepare>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x20,%rsp
  mov    D16(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    (%r12),%eax
  mov    %eax,0x10(%rsp)
  call   <strcpy@plt>
  mov    0xc(%rsp),%edi
  call   <strlen@plt>
  mov    (%r12),%edi
  xor    %edx,%edx
  cltq
  lea    0x4(%rax),%r13
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L29
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <unlink@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdx
  mov    %r12d,%edi
  call   <bind@plt>
  test   %rax,%rax
  jne    L29
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  test   %rax,%rax
  jne    L29
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%r12d
  jmp    L48
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_prepare(const char const *path) {
  int sock;
  size_t sock_addr_len;
  struct sockaddr_un sock_addr = {0};
  sock_addr.sun_family = AF_UNIX;
  strcpy(sock_addr.sun_path, path);
  sock_addr_len = sizeof(sock_addr.sun_family) + strlen(sock_addr.sun_path);
  sock = socket(AF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(path);
  if (bind(sock, (struct sockaddr *)&sock_addr, sock_addr_len))
    return -1;
  if (listen(sock, 5))
    return -1;
  return sock;
}
```
user: What is the c source code of the assembly code below:

```asm
<bc_table_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L3:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  mov    -0x14(%rbp),%eax
  sar    %eax
  xor    $0x8408,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L17
L14:
  sarl   -0x14(%rbp)
L17:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L3
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t bc_table_value(int bit_string, int bit_length) {
  int pos;
  for (pos = 0; pos < bit_length; pos++) {
    if (bit_string & 0x1)
      bit_string = (bit_string >> 1) ^ 0x8408;
    else
      bit_string >>= 1;
  }
  return (bit_string);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bc_table_value>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L14
  mov    $0x0,%ecx
L8:
  mov    %eax,%edx
  sar    %edx
  xor    $0x8408,%edx
  mov    %eax,%edi
  sar    %edi
  test   $0x1,%al
  mov    %edx,%eax
  cmove  %edi,%eax
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L8
L14:
  ret
```

assistant: ```c
uint16_t bc_table_value(int bit_string, int bit_length) {
  int pos;
  for (pos = 0; pos < bit_length; pos++) {
    if (bit_string & 0x1)
      bit_string = (bit_string >> 1) ^ 0x8408;
    else
      bit_string >>= 1;
  }
  return (bit_string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bc_table_value>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L19
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  mov    %eax,%edi
  sar    %eax
  mov    %eax,%ecx
  and    $0x1,%edi
  xor    $0x8408,%ecx
  test   %edi,%edi
  cmovne %ecx,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L3
L19:
  ret
```

assistant: ```c
uint16_t bc_table_value(int bit_string, int bit_length) {
  int pos;
  for (pos = 0; pos < bit_length; pos++) {
    if (bit_string & 0x1)
      bit_string = (bit_string >> 1) ^ 0x8408;
    else
      bit_string >>= 1;
  }
  return (bit_string);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bc_table_value>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L3
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  mov    %eax,%edi
  sar    %eax
  mov    %eax,%ecx
  and    $0x1,%edi
  xor    $0x8408,%ecx
  test   %edi,%edi
  cmovne %ecx,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L0
L3:
  ret
```

assistant: ```c
uint16_t bc_table_value(int bit_string, int bit_length) {
  int pos;
  for (pos = 0; pos < bit_length; pos++) {
    if (bit_string & 0x1)
      bit_string = (bit_string >> 1) ^ 0x8408;
    else
      bit_string >>= 1;
  }
  return (bit_string);
}
```