ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_umask>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x4(%rsp),%edi
  xor    %eax,%eax
  call   <umask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: %o

assistant: ```c
update_umask(str) char *str;
{
  int u;
  sscanf(str, "%o", &u);
  umask(u);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<update_umask>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x4(%rsp),%edi
  xor    %eax,%eax
  call   <umask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %o

assistant: ```c
update_umask(str) char *str;
{
  int u;
  sscanf(str, "%o", &u);
  umask(u);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<timeval_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L15
  mov    $0xffffffff,%eax
  jmp    L10
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L73
  mov    $0x1,%eax
  jmp    L10
L73:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jge    L45
  mov    $0xffffffff,%eax
  jmp    L10
L45:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jle    L13
  mov    $0x1,%eax
  jmp    L10
L13:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int timeval_cmp(struct timeval *a, struct timeval *b) {
  if (a->tv_sec < b->tv_sec) {
    return -1;
  } else if (a->tv_sec > b->tv_sec) {
    return 1;
  } else if (a->tv_usec < b->tv_usec) {
    return -1;
  } else if (a->tv_usec > b->tv_usec) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timeval_cmp>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jl     L15
  mov    $0x1,%eax
  jg     L15
  mov    0x8(%rdi),%rcx
  mov    0x8(%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jl     L15
  setg   %al
  movzbl %al,%eax
L15:
  ret
```

assistant: ```c
int timeval_cmp(struct timeval *a, struct timeval *b) {
  if (a->tv_sec < b->tv_sec) {
    return -1;
  } else if (a->tv_sec > b->tv_sec) {
    return 1;
  } else if (a->tv_usec < b->tv_usec) {
    return -1;
  } else if (a->tv_usec > b->tv_usec) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timeval_cmp>:
  endbr64
  mov    (%rsi),%rcx
  mov    $0xffffffff,%eax
  cmp    %rcx,(%rdi)
  jl     L19
  mov    $0x1,%eax
  jg     L19
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
L19:
  ret
```

assistant: ```c
int timeval_cmp(struct timeval *a, struct timeval *b) {
  if (a->tv_sec < b->tv_sec) {
    return -1;
  } else if (a->tv_sec > b->tv_sec) {
    return 1;
  } else if (a->tv_usec < b->tv_usec) {
    return -1;
  } else if (a->tv_usec > b->tv_usec) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timeval_cmp>:
  endbr64
  mov    (%rsi),%rcx
  mov    $0xffffffff,%eax
  cmp    %rcx,(%rdi)
  jl     L17
  mov    $0x1,%eax
  jg     L17
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
L17:
  ret
```

assistant: ```c
int timeval_cmp(struct timeval *a, struct timeval *b) {
  if (a->tv_sec < b->tv_sec) {
    return -1;
  } else if (a->tv_sec > b->tv_sec) {
    return 1;
  } else if (a->tv_usec < b->tv_usec) {
    return -1;
  } else if (a->tv_usec > b->tv_usec) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gc314LoadGC4016s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gc314LoadGC4016s(int filedes) {
  int retval;
  int status = 0;
  int temp = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<gc314LoadGC4016s>:
  endbr64
  ret
```

assistant: ```c
void gc314LoadGC4016s(int filedes) {
  int retval;
  int status = 0;
  int temp = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gc314LoadGC4016s>:
  endbr64
  ret
```

assistant: ```c
void gc314LoadGC4016s(int filedes) {
  int retval;
  int status = 0;
  int temp = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<gc314LoadGC4016s>:
  endbr64
  ret
```

assistant: ```c
void gc314LoadGC4016s(int filedes) {
  int retval;
  int status = 0;
  int temp = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<disk_identify_get_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L13
L0:
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x28(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x1c(%rbp)
  subq   $0x2,-0x30(%rbp)
L13:
  cmpq   $0x0,-0x30(%rbp)
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void disk_identify_get_string(uint8_t identify[512], unsigned int offset_words, char *dest, size_t dest_len) {
  unsigned int c1;
  unsigned int c2;
  assert(identify != NULL);
  assert(dest != NULL);
  assert((dest_len & 1) == 0);
  while (dest_len > 0) {
    c1 = ((uint16_t *)identify)[offset_words] >> 8;
    c2 = ((uint16_t *)identify)[offset_words] & 0xff;
    *dest = c1;
    dest++;
    *dest = c2;
    dest++;
    offset_words++;
    dest_len -= 2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<disk_identify_get_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %rcx,%r13
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13,%rdi
  xor    $0x1,%rdi
  and    $0x1,%edi
  call   <assert@plt>
  test   %r13,%r13
  je     L17
  mov    %r12,%rax
  lea    (%r12,%r13,1),%rsi
L14:
  mov    %ebx,%edx
  mov    0x0(%rbp,%rdx,4),%edx
  movzbl %dh,%ecx
  mov    %cl,(%rax)
  mov    %dl,0x1(%rax)
  lea    0x2(%rax),%rdx
  mov    %rdx,%rax
  add    $0x1,%ebx
  cmp    %rdx,%rsi
  jne    L14
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void disk_identify_get_string(uint8_t identify[512], unsigned int offset_words, char *dest, size_t dest_len) {
  unsigned int c1;
  unsigned int c2;
  assert(identify != NULL);
  assert(dest != NULL);
  assert((dest_len & 1) == 0);
  while (dest_len > 0) {
    c1 = ((uint16_t *)identify)[offset_words] >> 8;
    c2 = ((uint16_t *)identify)[offset_words] & 0xff;
    *dest = c1;
    dest++;
    *dest = c2;
    dest++;
    offset_words++;
    dest_len -= 2;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<disk_identify_get_string>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdi
  not    %rdi
  and    $0x1,%edi
  call   <assert@plt>
  test   %r13,%r13
  je     L14
  mov    %rbx,%rax
  lea    (%rbx,%r13,1),%rcx
  nopl   0x0(%rax)
L4:
  mov    %ebp,%edx
  add    $0x2,%rax
  add    $0x1,%ebp
  mov    (%r12,%rdx,4),%edx
  mov    %dh,-0x2(%rax)
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L4
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void disk_identify_get_string(uint8_t identify[512], unsigned int offset_words, char *dest, size_t dest_len) {
  unsigned int c1;
  unsigned int c2;
  assert(identify != NULL);
  assert(dest != NULL);
  assert((dest_len & 1) == 0);
  while (dest_len > 0) {
    c1 = ((uint16_t *)identify)[offset_words] >> 8;
    c2 = ((uint16_t *)identify)[offset_words] & 0xff;
    *dest = c1;
    dest++;
    *dest = c2;
    dest++;
    offset_words++;
    dest_len -= 2;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<disk_identify_get_string>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdi
  not    %rdi
  and    $0x1,%edi
  call   <assert@plt>
  test   %r13,%r13
  je     L9
  mov    %rbx,%rax
  lea    (%rbx,%r13,1),%rcx
  nopl   0x0(%rax)
L5:
  mov    %ebp,%edx
  add    $0x2,%rax
  add    $0x1,%ebp
  mov    (%r12,%rdx,4),%edx
  mov    %dh,-0x2(%rax)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  jne    L5
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void disk_identify_get_string(uint8_t identify[512], unsigned int offset_words, char *dest, size_t dest_len) {
  unsigned int c1;
  unsigned int c2;
  assert(identify != NULL);
  assert(dest != NULL);
  assert((dest_len & 1) == 0);
  while (dest_len > 0) {
    c1 = ((uint16_t *)identify)[offset_words] >> 8;
    c2 = ((uint16_t *)identify)[offset_words] & 0xff;
    *dest = c1;
    dest++;
    *dest = c2;
    dest++;
    offset_words++;
    dest_len -= 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<isInRange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jg     L34
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jge    L34
  mov    $0x1,%eax
  jmp    L6
L34:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jge    L46
  addq   $0x15752a00,-0x8(%rbp)
  jmp    L40
L46:
  subq   $0x15752a00,-0x8(%rbp)
L40:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jg     L19
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jge    L19
  mov    $0x1,%eax
  jmp    L6
L19:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int isInRange(long x, long minx, long maxx) {
  if (minx <= x && x < maxx)
    return 1;
  if (x < minx)
    x += 360000000;
  else
    x -= 360000000;
  if (minx <= x && x < maxx)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isInRange>:
  endbr64
  cmp    %rdi,%rsi
  jg     L11
  mov    $0x1,%eax
  cmp    %rdx,%rdi
  jl     L0
L11:
  lea    0x15752a00(%rdi),%rcx
  lea    -0x15752a00(%rdi),%rax
  cmp    %rdi,%rsi
  cmovg  %rcx,%rax
  cmp    %rsi,%rax
  setge  %cl
  cmp    %rdx,%rax
  setl   %al
  movzbl %al,%eax
  and    %ecx,%eax
L0:
  ret
```

assistant: ```c
int isInRange(long x, long minx, long maxx) {
  if (minx <= x && x < maxx)
    return 1;
  if (x < minx)
    x += 360000000;
  else
    x -= 360000000;
  if (minx <= x && x < maxx)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isInRange>:
  endbr64
  cmp    %rdi,%rsi
  jg     L18
  mov    $0x1,%eax
  cmp    %rdx,%rdi
  jge    L18
  ret
  nopl   0x0(%rax)
L18:
  lea    0x15752a00(%rdi),%rcx
  cmp    %rdi,%rsi
  lea    -0x15752a00(%rdi),%rax
  cmovg  %rcx,%rax
  cmp    %rsi,%rax
  setge  %cl
  cmp    %rdx,%rax
  setl   %al
  movzbl %al,%eax
  and    %ecx,%eax
  ret
```

assistant: ```c
int isInRange(long x, long minx, long maxx) {
  if (minx <= x && x < maxx)
    return 1;
  if (x < minx)
    x += 360000000;
  else
    x -= 360000000;
  if (minx <= x && x < maxx)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isInRange>:
  endbr64
  cmp    %rdi,%rsi
  jg     L11
  mov    $0x1,%eax
  cmp    %rdx,%rdi
  jge    L11
  ret
  nopl   0x0(%rax)
L11:
  lea    0x15752a00(%rdi),%rcx
  cmp    %rdi,%rsi
  lea    -0x15752a00(%rdi),%rax
  cmovg  %rcx,%rax
  cmp    %rsi,%rax
  setge  %cl
  cmp    %rdx,%rax
  setl   %al
  movzbl %al,%eax
  and    %ecx,%eax
  ret
```

assistant: ```c
int isInRange(long x, long minx, long maxx) {
  if (minx <= x && x < maxx)
    return 1;
  if (x < minx)
    x += 360000000;
  else
    x -= 360000000;
  if (minx <= x && x < maxx)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reversee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strlenn@plt>
  cltq
  mov    $0x1,%edx
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x18(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void reversee(char *s) {
  char *p;
  char temp;
  p = s - (strlenn(s) - 1);
  for (; p < s; p++, s--) {
    temp = *s;
    *s = *p;
    *p = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reversee>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <strlenn@plt>
  cltq
  mov    %rbx,%rdx
  sub    %rax,%rdx
  lea    0x1(%rdx),%rax
  cmp    %rax,%rbx
  jbe    L5
L15:
  movzbl (%rbx),%edx
  movzbl (%rax),%ecx
  mov    %cl,(%rbx)
  mov    %dl,(%rax)
  add    $0x1,%rax
  sub    $0x1,%rbx
  cmp    %rbx,%rax
  jb     L15
L5:
  pop    %rbx
  ret
```

assistant: ```c
void reversee(char *s) {
  char *p;
  char temp;
  p = s - (strlenn(s) - 1);
  for (; p < s; p++, s--) {
    temp = *s;
    *s = *p;
    *p = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reversee>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <strlenn@plt>
  mov    %rbx,%rdx
  cltq
  sub    %rax,%rdx
  lea    0x1(%rdx),%rax
  cmp    %rax,%rbx
  jbe    L17
L0:
  movzbl (%rbx),%edx
  movzbl (%rax),%ecx
  sub    $0x1,%rbx
  add    $0x1,%rax
  mov    %cl,0x1(%rbx)
  mov    %dl,-0x1(%rax)
  cmp    %rbx,%rax
  jb     L0
L17:
  pop    %rbx
  ret
```

assistant: ```c
void reversee(char *s) {
  char *p;
  char temp;
  p = s - (strlenn(s) - 1);
  for (; p < s; p++, s--) {
    temp = *s;
    *s = *p;
    *p = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reversee>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <strlenn@plt>
  mov    %rbx,%rdx
  cltq
  sub    %rax,%rdx
  lea    0x1(%rdx),%rax
  cmp    %rax,%rbx
  jbe    L14
L10:
  movzbl (%rbx),%edx
  movzbl (%rax),%ecx
  sub    $0x1,%rbx
  add    $0x1,%rax
  mov    %cl,0x1(%rbx)
  mov    %dl,-0x1(%rax)
  cmp    %rbx,%rax
  jb     L10
L14:
  pop    %rbx
  ret
```

assistant: ```c
void reversee(char *s) {
  char *p;
  char temp;
  p = s - (strlenn(s) - 1);
  for (; p < s; p++, s--) {
    temp = *s;
    *s = *p;
    *p = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xada5000,%edi
  call   <recv_msgq@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: adasrun forever, press ctrl-C to quit...


assistant: ```c
int main() {
  printf("adasrun forever, press ctrl-C to quit...\n");
  recv_msgq(0x0ADA5000, 9);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xada5000,%edi
  call   <recv_msgq@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: adasrun forever, press ctrl-C to quit...


assistant: ```c
int main() {
  printf("adasrun forever, press ctrl-C to quit...\n");
  recv_msgq(0x0ADA5000, 9);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xada5000,%edi
  call   <recv_msgq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: adasrun forever, press ctrl-C to quit...


assistant: ```c
int main() {
  printf("adasrun forever, press ctrl-C to quit...\n");
  recv_msgq(0x0ADA5000, 9);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xada5000,%edi
  call   <recv_msgq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: adasrun forever, press ctrl-C to quit...


assistant: ```c
int main() {
  printf("adasrun forever, press ctrl-C to quit...\n");
  recv_msgq(0x0ADA5000, 9);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<lazy_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  ja     L0
  mov    -0xc(%rbp),%eax
  jmp    L23
L0:
  mov    $0x4,%eax
L23:
  lea    -0x18(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned int lazy_hash(const char *val) {
  unsigned int hash = 0;
  int len = strlen(val);
  memcpy(&hash, &val, len < sizeof(hash) ? len : sizeof(hash));
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lazy_hash>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movl   $0x0,0x14(%rsp)
  call   <strlen@plt>
  mov    $0x4,%edx
  cmp    %edx,%eax
  cmovbe %eax,%edx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int lazy_hash(const char *val) {
  unsigned int hash = 0;
  int len = strlen(val);
  memcpy(&hash, &val, len < sizeof(hash) ? len : sizeof(hash));
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lazy_hash>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <strlen@plt>
  mov    $0x4,%edx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  cmp    %edx,%eax
  cmovbe %eax,%edx
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int lazy_hash(const char *val) {
  unsigned int hash = 0;
  int len = strlen(val);
  memcpy(&hash, &val, len < sizeof(hash) ? len : sizeof(hash));
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<lazy_hash>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <strlen@plt>
  mov    $0x4,%edx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  cmp    %edx,%eax
  cmovbe %eax,%edx
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int lazy_hash(const char *val) {
  unsigned int hash = 0;
  int len = strlen(val);
  memcpy(&hash, &val, len < sizeof(hash) ? len : sizeof(hash));
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_blankline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L23
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L7
  mov    $0x0,%eax
  jmp    L20
L7:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    $0x1,%eax
L20:
  leave
  ret
```

assistant: ```c
int is_blankline(char *buffer) {
  for (; *buffer != '\0'; buffer++)
    if (!isspace(*buffer))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_blankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L9:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L26
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
  mov    $0x1,%eax
L26:
  pop    %rbx
  ret
L8:
  mov    $0x1,%eax
  jmp    L26
```

assistant: ```c
int is_blankline(char *buffer) {
  for (; *buffer != '\0'; buffer++)
    if (!isspace(*buffer))
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_blankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L13
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L33
L13:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L27
  pop    %rbx
  ret
L33:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_blankline(char *buffer) {
  for (; *buffer != '\0'; buffer++)
    if (!isspace(*buffer))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_blankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L24
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L15
L24:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L11
  pop    %rbx
  ret
L15:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_blankline(char *buffer) {
  for (; *buffer != '\0'; buffer++)
    if (!isspace(*buffer))
      return 0;
  return 1;
}
```