user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x3e9,-0x1c(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x34(%rbp),%ecx
  lea    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <readArgs@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    $0x2,%eax
  jle    L30
  mov    -0x28(%rbp),%eax
  cmp    $0x64,%eax
  jle    L25
L30:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L65
L25:
  movl   $0x1,-0x24(%rbp)
  jmp    L72
L59:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L43
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L43:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x24(%rbp)
  jge    L74
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L74
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L74:
  addl   $0x1,-0x24(%rbp)
L72:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L59
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L98
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L98:
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L65:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D29
datatype: string
name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D18
datatype: string

tool: D29: Invalid holds number. Aborting...

tool: D5: 
--------------------

tool: D18: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, loop;
  int *holds;
  int currentDifficulty = 0;
  int minHole = 1001;
  int dif, hole;
  if (1 == 0)
    printf("\nP1 - Minimal Difficulty:\n");
  holds = readArgs(&n, argc, argv);
  if (n < 3 || n > 100) {
    printf("Invalid holds number. Aborting...\n");
    printf("\n--------------------\n");
    return 1;
  }
  if (1 == 0)
    printf("\nProblem Solution:\n");
  for (loop = 1; loop < n; loop++) {
    if (1 == 0)
      printf("#%d: %d.\n", loop + 1, holds[loop]);
    dif = holds[loop] - holds[loop - 1];
    if (dif > currentDifficulty) {
      currentDifficulty = dif;
    }
    if (loop < n - 1) {
      hole = holds[loop + 1] - holds[loop - 1];
      if (hole < minHole)
        minHole = hole;
    }
  }
  if (minHole > currentDifficulty)
    currentDifficulty = minHole;
  printf("%d", currentDifficulty);
  if (1 == 0)
    printf("\n--------------------\n");
  return 0;
}
```