ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Power_law_no_hops>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <drand48@plt>
  movsd  D4(%rip),%xmm1
  divsd  0x8(%rsp),%xmm1
  cvttsd2si %xmm1,%edi
  call   <pow@plt>
  mulsd  (%rsp),%xmm0
  call   <ceil@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int Power_law_no_hops(double delta, double H) {
  int hop;
  double ran;
  ran = drand48();
  hop = (int)ceil(delta * pow(ran, 1 / H));
  return (hop);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L13:
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L9
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L15
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, end;
  char c;
  for (i = 0; s[i] != '\0'; i++)
    ;
  end = i--;
  for (j = 0; (i != j) && (j < i); j++, i--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
  s[end] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  lea    0x1(%rdi),%rdx
  mov    $0x0,%ecx
L3:
  mov    %ecx,%eax
  add    $0x1,%ecx
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L3
  test   %eax,%eax
  jle    L30
  cltq
  mov    $0x0,%edx
L24:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rdi,%rdx,1),%esi
  mov    %sil,(%rdi,%rax,1)
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L24
L30:
  movb   $0x0,(%r8)
  ret
L18:
  mov    %rdi,%r8
  jmp    L30
```

assistant: ```c
void reverse(char s[]) {
  int i, j, end;
  char c;
  for (i = 0; s[i] != '\0'; i++)
    ;
  end = i--;
  for (j = 0; (i != j) && (j < i); j++, i--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
  s[end] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L17
  lea    0x1(%rdi),%r8
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r8,%rcx
  movslq %edx,%rax
  lea    0x1(%r8),%r8
  add    $0x1,%edx
  cmpb   $0x0,(%rcx)
  jne    L6
  test   %eax,%eax
  je     L48
  xor    %edx,%edx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl (%rdi,%rdx,1),%esi
L16:
  movzbl (%rdi,%rax,1),%r8d
  mov    %sil,(%rdi,%rax,1)
  sub    $0x1,%rax
  mov    %r8b,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L44
L48:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L17:
  mov    %rdi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, end;
  char c;
  for (i = 0; s[i] != '\0'; i++)
    ;
  end = i--;
  for (j = 0; (i != j) && (j < i); j++, i--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
  s[end] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L37
  lea    0x1(%rdi),%rsi
  xor    %edx,%edx
  nop
L6:
  mov    %rsi,%rcx
  movslq %edx,%rax
  lea    0x1(%rsi),%rsi
  add    $0x1,%edx
  cmpb   $0x0,(%rcx)
  jne    L6
  test   %eax,%eax
  je     L14
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rdi,%rax,1),%esi
  movzbl (%rdi,%rdx,1),%r8d
  mov    %r8b,(%rdi,%rax,1)
  sub    $0x1,%rax
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L13
L14:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L37:
  mov    %rdi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, end;
  char c;
  for (i = 0; s[i] != '\0'; i++)
    ;
  end = i--;
  for (j = 0; (i != j) && (j < i); j++, i--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
  s[end] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<envoyerTrame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%r8d
  mov    %rdx,%rcx
  mov    $0x2,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: %c%s%c

assistant: ```c
void envoyerTrame(int socket, char *message) {
  char *trame = (char *)malloc(sizeof(message) + 2);
  sprintf(trame, "%c%s%c", 0x02, message, 0x03);
  write(socket, trame, strlen(trame));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<envoyerTrame>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x3,%r8d
  mov    %r12,%rcx
  mov    $0x2,%edx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <write@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: %c%s%c

assistant: ```c
void envoyerTrame(int socket, char *message) {
  char *trame = (char *)malloc(sizeof(message) + 2);
  sprintf(trame, "%c%s%c", 0x02, message, 0x03);
  write(socket, trame, strlen(trame));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<envoyerTrame>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  mov    $0xa,%edi
  push   %rbp
  call   <malloc@plt>
  mov    %r13,%rcx
  mov    $0x2,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    $0x3,%r8d
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %rax,%rdx
  pop    %r12
  xor    %eax,%eax
  pop    %r13
  jmp    1080 <write@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: %c%s%c

assistant: ```c
void envoyerTrame(int socket, char *message) {
  char *trame = (char *)malloc(sizeof(message) + 2);
  sprintf(trame, "%c%s%c", 0x02, message, 0x03);
  write(socket, trame, strlen(trame));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<envoyerTrame>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  mov    $0xa,%edi
  push   %rbp
  call   <malloc@plt>
  mov    %r13,%rcx
  mov    $0x2,%edx
  lea    D2(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    $0x3,%r8d
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %rax,%rdx
  pop    %r12
  xor    %eax,%eax
  pop    %r13
  jmp    1080 <write@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: %c%s%c

assistant: ```c
void envoyerTrame(int socket, char *message) {
  char *trame = (char *)malloc(sizeof(message) + 2);
  sprintf(trame, "%c%s%c", 0x02, message, 0x03);
  write(socket, trame, strlen(trame));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0xfff,%eax
  test   %rax,%rax
  je     L5
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  jmp    L18
L5:
  mov    -0x28(%rbp),%rax
  shr    $0xc,%rax
  mov    %rax,%r8
  mov    -0x1c(%rbp),%edi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <__mmap2@plt>
L18:
  leave
  ret
```

assistant: ```c
void *mmap(void *addr, size_t size, int prot, int flags, int fd, long offset) {
  if (offset & ((1UL << 12) - 1)) {
    errno = EINVAL;
    return MAP_FAILED;
  }
  return __mmap2(addr, size, prot, flags, fd, (size_t)offset >> 12);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mmap>:
  endbr64
  test   $0xfff,%r9d
  je     L9
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  ret
L9:
  sub    $0x8,%rsp
  shr    $0xc,%r9
  call   <__mmap2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *mmap(void *addr, size_t size, int prot, int flags, int fd, long offset) {
  if (offset & ((1UL << 12) - 1)) {
    errno = EINVAL;
    return MAP_FAILED;
  }
  return __mmap2(addr, size, prot, flags, fd, (size_t)offset >> 12);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mmap>:
  endbr64
  test   $0xfff,%r9d
  je     L9
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  shr    $0xc,%r9
  jmp    1050 <__mmap2@plt>
```

assistant: ```c
void *mmap(void *addr, size_t size, int prot, int flags, int fd, long offset) {
  if (offset & ((1UL << 12) - 1)) {
    errno = EINVAL;
    return MAP_FAILED;
  }
  return __mmap2(addr, size, prot, flags, fd, (size_t)offset >> 12);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mmap>:
  endbr64
  test   $0xfff,%r9d
  je     L8
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  shr    $0xc,%r9
  jmp    1050 <__mmap2@plt>
```

assistant: ```c
void *mmap(void *addr, size_t size, int prot, int flags, int fd, long offset) {
  if (offset & ((1UL << 12) - 1)) {
    errno = EINVAL;
    return MAP_FAILED;
  }
  return __mmap2(addr, size, prot, flags, fd, (size_t)offset >> 12);
}
```
user: Translate the below assembly code into C programming language:

```asm
<simple_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   $0x18df,%rax,%rax
  add    $0x14353,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t simple_hash(const void *key, uint32_t size) {
  uintptr_t k = (uintptr_t)key;
  return ((13 + k) * 6367) % size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<simple_hash>:
  endbr64
  imul   $0x18df,%rdi,%rax
  add    $0x14353,%rax
  movslq %esi,%rsi
  mov    $0x0,%edx
  div    %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t simple_hash(const void *key, uint32_t size) {
  uintptr_t k = (uintptr_t)key;
  return ((13 + k) * 6367) % size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simple_hash>:
  endbr64
  imul   $0x18df,%rdi,%rax
  movslq %esi,%rsi
  xor    %edx,%edx
  add    $0x14353,%rax
  div    %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t simple_hash(const void *key, uint32_t size) {
  uintptr_t k = (uintptr_t)key;
  return ((13 + k) * 6367) % size;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<simple_hash>:
  endbr64
  imul   $0x18df,%rdi,%rax
  movslq %esi,%rsi
  xor    %edx,%edx
  add    $0x14353,%rax
  div    %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t simple_hash(const void *key, uint32_t size) {
  uintptr_t k = (uintptr_t)key;
  return ((13 + k) * 6367) % size;
}
```
user: What is the c source code of the assembly code below?

```asm
<fpu_fyl2x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <log@plt>
  movq   %xmm0,%rbx
  mov    $0x2,%edi
  call   <log@plt>
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double fpu_fyl2x(double a, double b) {
  double c;
  c = b * (log(a) / log(2));
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fpu_fyl2x>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm1,%r14
  cvttsd2si %xmm0,%edi
  call   <log@plt>
  movq   %xmm0,%rbx
  mov    $0x2,%edi
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double fpu_fyl2x(double a, double b) {
  double c;
  c = b * (log(a) / log(2));
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fpu_fyl2x>:
  endbr64
  cvttsd2si %xmm0,%edi
  sub    $0x18,%rsp
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double fpu_fyl2x(double a, double b) {
  double c;
  c = b * (log(a) / log(2));
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fpu_fyl2x>:
  endbr64
  cvttsd2si %xmm0,%edi
  sub    $0x18,%rsp
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double fpu_fyl2x(double a, double b) {
  double c;
  c = b * (log(a) / log(2));
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <very_big@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: Result: 0x%x


assistant: ```c
int main() {
  int num = very_big();
  printf("Result: 0x%x\n", num);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <very_big@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8: Result: 0x%x


assistant: ```c
int main() {
  int num = very_big();
  printf("Result: 0x%x\n", num);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <very_big@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: Result: 0x%x


assistant: ```c
int main() {
  int num = very_big();
  printf("Result: 0x%x\n", num);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <very_big@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: Result: 0x%x


assistant: ```c
int main() {
  int num = very_big();
  printf("Result: 0x%x\n", num);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x710,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x708(%rbp)
  mov    $0x14,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L9
L40:
  lea    -0x660(%rbp),%rcx
  mov    -0x708(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rdx,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x708(%rbp),%eax
  cltq
  mov    %rdx,-0x700(%rbp,%rax,8)
  addl   $0x1,-0x708(%rbp)
L9:
  cmpl   $0x13,-0x708(%rbp)
  jg     L16
  lea    -0x660(%rbp),%rcx
  mov    -0x708(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rdx,%rax
  add    %rcx,%rax
  mov    $0x51,%esi
  mov    %rax,%rdi
  call   <s_gets@plt>
  test   %rax,%rax
  je     L16
  mov    -0x708(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rdx,%rax
  add    %rbp,%rax
  sub    $0x660,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
L16:
  mov    -0x708(%rbp),%edx
  lea    -0x700(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x704(%rbp)
  jmp    L39
L38:
  mov    -0x704(%rbp),%eax
  cltq
  mov    -0x700(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x704(%rbp)
L39:
  mov    -0x704(%rbp),%eax
  cmp    -0x708(%rbp),%eax
  jl     L38
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D18
type: string

tool: D24: Input up to %d lines, then sort.


tool: D14: To stop, press the Enter key at a line's start.

tool: D18: 
Here's the sorted list:


assistant: ```c
int main(void) {
  char input[20][81];
  char *ptstr[20];
  int count = 0;
  int k;
  printf("Input up to %d lines, then sort.\n", 20);
  printf("To stop, press the Enter key at a line's start.\n");
  while (count < 20 && s_gets(input[count], 81) != NULL && input[count][0] != '\0') {
    ptstr[count] = input[count];
    count++;
  }
  sort(ptstr, count);
  puts("\nHere's the sorted list:\n");
  for (k = 0; k < count; k++)
    puts(ptstr[k]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x700,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x6f8(%rsp)
  xor    %eax,%eax
  mov    $0x14,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    0xa0(%rsp),%rbp
  mov    $0x0,%ebx
L58:
  mov    %ebx,%r14d
  mov    %ebx,%r12d
  mov    %rbp,%r13
  mov    $0x51,%esi
  mov    %rbp,%rdi
  call   <s_gets@plt>
  test   %rax,%rax
  je     L7
  cmpb   $0x0,0x0(%rbp)
  je     L7
  mov    %r13,(%rsp,%rbx,8)
  lea    0x1(%r14),%r12d
  add    $0x1,%rbx
  add    $0x51,%rbp
  cmp    $0x14,%rbx
  jne    L58
L7:
  mov    %rsp,%rdi
  mov    %r12d,%esi
  call   <sort@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L47
  mov    %rsp,%rbx
  lea    -0x1(%r12),%eax
  lea    0x8(%rsp,%rax,8),%rbp
L15:
  mov    (%rbx),%rdi
  call   <puts@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L15
L47:
  mov    0x6f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x700,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D20
type_guessed: string

tool: D3: Input up to %d lines, then sort.


tool: D17: To stop, press the Enter key at a line's start.

tool: D20: 
Here's the sorted list:


assistant: ```c
int main(void) {
  char input[20][81];
  char *ptstr[20];
  int count = 0;
  int k;
  printf("Input up to %d lines, then sort.\n", 20);
  printf("To stop, press the Enter key at a line's start.\n");
  while (count < 20 && s_gets(input[count], 81) != NULL && input[count][0] != '\0') {
    ptstr[count] = input[count];
    count++;
  }
  sort(ptstr, count);
  puts("\nHere's the sorted list:\n");
  for (k = 0; k < count; k++)
    puts(ptstr[k]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x14,%esi
  lea    D34(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x708,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x6f8(%rsp)
  xor    %eax,%eax
  lea    0xa0(%rsp),%rbx
  mov    %rsp,%r13
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L58:
  mov    $0x51,%esi
  mov    %rbx,%rdi
  mov    %ebp,%r12d
  call   <s_gets@plt>
  test   %rax,%rax
  je     L53
  cmpb   $0x0,(%rbx)
  je     L53
  mov    %rbx,0x0(%r13,%rbp,8)
  add    $0x1,%rbp
  add    $0x51,%rbx
  cmp    $0x14,%rbp
  jne    L58
  mov    $0x14,%esi
  mov    %r13,%rdi
  mov    $0x14,%r12d
  call   <sort@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
L21:
  xor    %ebx,%ebx
  xchg   %ax,%ax
L37:
  mov    0x0(%r13,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %ebx,%r12d
  jg     L37
L64:
  mov    0x6f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x708,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  mov    %r13,%rdi
  mov    %r12d,%esi
  call   <sort@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jne    L21
  jmp    L64
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D34: Input up to %d lines, then sort.


tool: D21: To stop, press the Enter key at a line's start.

tool: D14: 
Here's the sorted list:


assistant: ```c
int main(void) {
  char input[20][81];
  char *ptstr[20];
  int count = 0;
  int k;
  printf("Input up to %d lines, then sort.\n", 20);
  printf("To stop, press the Enter key at a line's start.\n");
  while (count < 20 && s_gets(input[count], 81) != NULL && input[count][0] != '\0') {
    ptstr[count] = input[count];
    count++;
  }
  sort(ptstr, count);
  puts("\nHere's the sorted list:\n");
  for (k = 0; k < count; k++)
    puts(ptstr[k]);
  return 0;
}
```