ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<my_sin>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm3,%xmm0
  mulsd  D18(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <my_rint@plt>
  cvttss2si %xmm0,%ebx
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movapd %xmm1,%xmm2
  mulsd  D23(%rip),%xmm2
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D6(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  test   $0x1,%bl
  je     L8
  call   <cos_core@plt>
L2:
  test   $0x2,%bl
  je     L21
  xorps  D11(%rip),%xmm0
L21:
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <sin_core@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: label: D18
type: byte[8]
name: read_data
arguments: label: D23
type: byte[8]
name: read_data
arguments: label: D6
type: byte[8]
name: read_data
arguments: label: D11
type: byte[16]

tool: {"D18": [0x83,0xc8,0xc9,0x6d,0x30,0x5f,0xe4,0x3f]}

tool: {"D23": [0x00,0x00,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D6": [0x29,0x66,0x4c,0x4c,0x23,0x8c,0x86,0x3d]}

tool: {"D11": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float my_sin(float x) {
  float q, t;
  int quadrant;
  q = my_rint(x * 6.3661977236758138e-1);
  quadrant = (int)q;
  t = x - q * 1.5707963267923333e+00;
  t = t - q * 2.5633441515945189e-12;
  if (quadrant & 1) {
    t = cos_core(t);
  } else {
    t = sin_core(t);
  }
  return (quadrant & 2) ? -t : t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_sin>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movapd %xmm1,%xmm0
  sub    $0x10,%rsp
  mulsd  D25(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <my_rint@plt>
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm2
  cvttss2si %xmm0,%ebx
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  D29(%rip),%xmm2
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  test   $0x1,%bl
  je     L1
  call   <cos_core@plt>
L18:
  and    $0x2,%ebx
  je     L5
  xorps  D19(%rip),%xmm0
L5:
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  call   <sin_core@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D25
type_guessed: byte[8]
name: parse_data
arguments: label: D7
type_guessed: byte[8]
name: parse_data
arguments: label: D29
type_guessed: byte[8]
name: parse_data
arguments: label: D19
type_guessed: byte[16]

tool: {"D25": [0x83,0xc8,0xc9,0x6d,0x30,0x5f,0xe4,0x3f]}

tool: {"D7": [0x00,0x00,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D29": [0x29,0x66,0x4c,0x4c,0x23,0x8c,0x86,0x3d]}

tool: {"D19": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float my_sin(float x) {
  float q, t;
  int quadrant;
  q = my_rint(x * 6.3661977236758138e-1);
  quadrant = (int)q;
  t = x - q * 1.5707963267923333e+00;
  t = t - q * 2.5633441515945189e-12;
  if (quadrant & 1) {
    t = cos_core(t);
  } else {
    t = sin_core(t);
  }
  return (quadrant & 2) ? -t : t;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_sin>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movapd %xmm1,%xmm0
  sub    $0x10,%rsp
  mulsd  D18(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <my_rint@plt>
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm2
  cvttss2si %xmm0,%ebx
  movsd  D1(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  D24(%rip),%xmm2
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  test   $0x1,%bl
  je     L21
  call   <cos_core@plt>
L17:
  and    $0x2,%ebx
  je     L28
  xorps  D7(%rip),%xmm0
L28:
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  call   <sin_core@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: label: D18
type: byte[8]
name: disassemble_data
arguments: label: D1
type: byte[8]
name: disassemble_data
arguments: label: D24
type: byte[8]
name: disassemble_data
arguments: label: D7
type: byte[16]

tool: {"D18": [0x83,0xc8,0xc9,0x6d,0x30,0x5f,0xe4,0x3f]}

tool: {"D1": [0x00,0x00,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D24": [0x29,0x66,0x4c,0x4c,0x23,0x8c,0x86,0x3d]}

tool: {"D7": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float my_sin(float x) {
  float q, t;
  int quadrant;
  q = my_rint(x * 6.3661977236758138e-1);
  quadrant = (int)q;
  t = x - q * 1.5707963267923333e+00;
  t = t - q * 2.5633441515945189e-12;
  if (quadrant & 1) {
    t = cos_core(t);
  } else {
    t = sin_core(t);
  }
  return (quadrant & 2) ? -t : t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stdlib_ndarray_set_int8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stdlib_ndarray_get_ptr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L7
L16:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stdlib_ndarray_set_ptr_int8@plt>
L7:
  leave
  ret
```

assistant: ```c
int8_t stdlib_ndarray_set_int8(const struct ndarray *arr, const int64_t *sub, const int8_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int8(idx, v);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stdlib_ndarray_set_int8>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <stdlib_ndarray_set_ptr_int8@plt>
L5:
  pop    %rbx
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int8_t stdlib_ndarray_set_int8(const struct ndarray *arr, const int64_t *sub, const int8_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int8(idx, v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdlib_ndarray_set_int8>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L9
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1060 <stdlib_ndarray_set_ptr_int8@plt>
L9:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_set_int8(const struct ndarray *arr, const int64_t *sub, const int8_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int8(idx, v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stdlib_ndarray_set_int8>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L3
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1060 <stdlib_ndarray_set_ptr_int8@plt>
L3:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_set_int8(const struct ndarray *arr, const int64_t *sub, const int8_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int8(idx, v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x38(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%ebx
  mov    -0x50(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    -0x1(%rax),%rcx
  mov    -0x38(%rbp),%eax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <lseek@plt>
  jmp    L22
L19:
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L22:
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  mov    $0x14,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L19
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  lseek(fd, atoi(argv[2]) - 1, SEEK_SET);
  int cnt;
  char buffer[20];
  while (cnt = read(fd, buffer, 20))
    write(1, buffer, cnt);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  mov    D4(%rip),%rax
  mov    (%rax),%r12d
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  lea    -0x1(%rax),%rsi
  mov    %r12d,%edx
  mov    %ebp,%edi
  call   <lseek@plt>
  mov    %rsp,%rbx
  jmp    L16
L14:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L16:
  mov    $0x14,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L14
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  lseek(fd, atoi(argv[2]) - 1, SEEK_SET);
  int cnt;
  char buffer[20];
  while (cnt = read(fd, buffer, 20))
    write(1, buffer, cnt);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    0x10(%rbx),%rdi
  mov    %rsp,%rbx
  mov    %eax,%ebp
  mov    D12(%rip),%rax
  mov    (%rax),%r12d
  call   <atoi@plt>
  mov    %ebp,%edi
  lea    -0x1(%rax),%rsi
  mov    %r12d,%edx
  call   <lseek@plt>
  jmp    L9
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L9:
  mov    $0x14,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  lseek(fd, atoi(argv[2]) - 1, SEEK_SET);
  int cnt;
  char buffer[20];
  while (cnt = read(fd, buffer, 20))
    write(1, buffer, cnt);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    0x10(%rbx),%rdi
  mov    %rsp,%rbx
  mov    %eax,%ebp
  mov    D4(%rip),%rax
  mov    (%rax),%r12d
  call   <atoi@plt>
  mov    %ebp,%edi
  lea    -0x1(%rax),%rsi
  mov    %r12d,%edx
  call   <lseek@plt>
  jmp    L5
  nopl   0x0(%rax)
L26:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L5:
  mov    $0x14,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L26
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  lseek(fd, atoi(argv[2]) - 1, SEEK_SET);
  int cnt;
  char buffer[20];
  while (cnt = read(fd, buffer, 20))
    write(1, buffer, cnt);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dsyrk_codegen_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L9
L26:
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L39:
  mov    -0xc(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L2
L43:
  mov    -0xc(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L43
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L39
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dsyrk_codegen_0(double *A, double *C) {
  const int n = 4 + 0 * 40 + 0 * 4;
  const int lda = 4 + 0 * 40 + 0 * 4;
  double temp;
  int ii, jj, kk;
  for (jj = 0; jj < n; jj++) {
    for (kk = 0; kk < n; kk++) {
      temp = A[jj + lda * kk];
      for (ii = jj; ii < n; ii++) {
        C[ii + lda * jj] += temp * A[ii + lda * kk];
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dsyrk_codegen_0>:
  endbr64
  mov    $0x0,%r8d
  jmp    L22
L47:
  add    $0x1,%r8
  add    $0x20,%rsi
  cmp    $0x4,%r8
  je     L39
L22:
  mov    %rdi,%rcx
  mov    $0x0,%r9d
L0:
  mov    %rcx,%rdx
  movsd  (%rcx,%r8,8),%xmm1
  cmp    $0x3,%r8d
  jg     L49
  mov    %r8,%rax
L41:
  movapd %xmm1,%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x3,%eax
  jle    L41
L49:
  add    $0x4,%r9d
  add    $0x20,%rcx
  cmp    $0x10,%r9d
  jne    L0
  jmp    L47
L39:
  ret
```

assistant: ```c
void dsyrk_codegen_0(double *A, double *C) {
  const int n = 4 + 0 * 40 + 0 * 4;
  const int lda = 4 + 0 * 40 + 0 * 4;
  double temp;
  int ii, jj, kk;
  for (jj = 0; jj < n; jj++) {
    for (kk = 0; kk < n; kk++) {
      temp = A[jj + lda * kk];
      for (ii = jj; ii < n; ii++) {
        C[ii + lda * jj] += temp * A[ii + lda * kk];
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dsyrk_codegen_0>:
  endbr64
  xor    %r8d,%r8d
L7:
  mov    %rdi,%rdx
  xor    %ecx,%ecx
L9:
  movsd  (%rdx,%r8,8),%xmm1
  mov    %r8,%rax
  movapd %xmm1,%xmm0
L21:
  mulsd  %xmm1,%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x4,%eax
  je     L36
  movsd  (%rdx,%rax,8),%xmm0
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x4,%ecx
  add    $0x20,%rdx
  cmp    $0x10,%ecx
  jne    L9
  add    $0x1,%r8
  add    $0x20,%rsi
  cmp    $0x4,%r8
  jne    L7
  ret
```

assistant: ```c
void dsyrk_codegen_0(double *A, double *C) {
  const int n = 4 + 0 * 40 + 0 * 4;
  const int lda = 4 + 0 * 40 + 0 * 4;
  double temp;
  int ii, jj, kk;
  for (jj = 0; jj < n; jj++) {
    for (kk = 0; kk < n; kk++) {
      temp = A[jj + lda * kk];
      for (ii = jj; ii < n; ii++) {
        C[ii + lda * jj] += temp * A[ii + lda * kk];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dsyrk_codegen_0>:
  endbr64
  push   %r15
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    0x8(%rdi),%r15
  push   %r14
  xor    %r10d,%r10d
  xor    %r14d,%r14d
  mov    $0x4,%r11d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x13,%ebx
  mov    %rsi,-0x10(%rsp)
L21:
  mov    %r11d,%ebp
  lea    0x3(%r10),%esi
  mov    -0x10(%rsp),%rdx
  mov    %r11d,%r13d
  and    $0xfffffffe,%ebp
  mov    %esi,-0x14(%rsp)
  shr    %r13d
  lea    -0x3(%r14),%r12d
  lea    0x0(%rbp,%r10,1),%r9d
  lea    (%r9,%r10,4),%eax
  lea    (%rdx,%rax,8),%rdi
  mov    %r15,%rdx
L18:
  movsd  -0x8(%rdx),%xmm0
  lea    (%r12,%rsi,1),%eax
  cmp    %rcx,%rdx
  je     L16
  cmp    $0x3,%r10d
  je     L16
  movupd -0x8(%rdx),%xmm1
  movapd %xmm0,%xmm2
  movupd (%rcx),%xmm3
  unpcklpd %xmm2,%xmm2
  mulpd  %xmm2,%xmm1
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rcx)
  cmp    $0x2,%r13d
  jne    L31
  movupd 0x8(%rdx),%xmm1
  movupd 0x10(%rcx),%xmm4
  mulpd  %xmm2,%xmm1
  addpd  %xmm4,%xmm1
  movups %xmm1,0x10(%rcx)
L31:
  cmp    %ebp,%r11d
  je     L59
  add    %r9d,%eax
  cltq
  mulsd  (%r8,%rax,8),%xmm0
  addsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdi)
L59:
  add    $0x4,%esi
  add    $0x20,%rdx
  cmp    %esi,%ebx
  jne    L18
  add    $0x1,%r10
  sub    $0x1,%r14d
  add    $0x1,%ebx
  add    $0x28,%rcx
  add    $0x8,%r15
  sub    $0x1,%r11d
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rcx),%xmm1
  movsd  %xmm1,(%rcx)
  cmp    $0x3,%r10
  je     L59
  lea    -0x2(%rsi),%eax
  cltq
  movsd  (%r8,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x8(%rcx),%xmm1
  movsd  %xmm1,0x8(%rcx)
  cmp    $0x2,%r10
  je     L59
  lea    -0x1(%rsi),%eax
  cmpl   $0x4,-0x14(%rsp)
  cltq
  movsd  (%r8,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x10(%rcx),%xmm1
  movsd  %xmm1,0x10(%rcx)
  je     L59
  movslq %esi,%rax
  mulsd  (%r8,%rax,8),%xmm0
  addsd  0x18(%rcx),%xmm0
  movsd  %xmm0,0x18(%rcx)
  jmp    L59
```

assistant: ```c
void dsyrk_codegen_0(double *A, double *C) {
  const int n = 4 + 0 * 40 + 0 * 4;
  const int lda = 4 + 0 * 40 + 0 * 4;
  double temp;
  int ii, jj, kk;
  for (jj = 0; jj < n; jj++) {
    for (kk = 0; kk < n; kk++) {
      temp = A[jj + lda * kk];
      for (ii = jj; ii < n; ii++) {
        C[ii + lda * jj] += temp * A[ii + lda * kk];
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  lea    -0x330(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ler_acessos@plt>
  mov    %eax,-0x338(%rbp)
  mov    -0x338(%rbp),%edx
  lea    -0x1a0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mais_tempo@plt>
  mov    %eax,-0x334(%rbp)
  mov    -0x338(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D14
datatype: string

tool: D4: Total de acessos: %d


tool: D14: Carro que permaneceu mais tempo: %d (%d minutos)


assistant: ```c
int main() {
  int id[100], tempo[100];
  int numAcessos = ler_acessos(id, tempo);
  int iMaior = mais_tempo(tempo, numAcessos);
  printf("Total de acessos: %d\n", numAcessos);
  printf("Carro que permaneceu mais tempo: %d (%d minutos)\n", id[iMaior], tempo[iMaior]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  lea    0x190(%rsp),%rbx
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <ler_acessos@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <mais_tempo@plt>
  mov    %eax,%ebx
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  mov    0x190(%rsp,%rax,4),%edx
  mov    (%rsp,%rax,4),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x338,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D0: Total de acessos: %d


tool: D18: Carro que permaneceu mais tempo: %d (%d minutos)


assistant: ```c
int main() {
  int id[100], tempo[100];
  int numAcessos = ler_acessos(id, tempo);
  int iMaior = mais_tempo(tempo, numAcessos);
  printf("Total de acessos: %d\n", numAcessos);
  printf("Carro que permaneceu mais tempo: %d (%d minutos)\n", id[iMaior], tempo[iMaior]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  lea    0x190(%rsp),%r12
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <ler_acessos@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <mais_tempo@plt>
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  lea    D8(%rip),%rdi
  mov    0x190(%rsp,%rax,4),%edx
  mov    (%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x330,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D11: Total de acessos: %d


tool: D8: Carro que permaneceu mais tempo: %d (%d minutos)


assistant: ```c
int main() {
  int id[100], tempo[100];
  int numAcessos = ler_acessos(id, tempo);
  int iMaior = mais_tempo(tempo, numAcessos);
  printf("Total de acessos: %d\n", numAcessos);
  printf("Carro que permaneceu mais tempo: %d (%d minutos)\n", id[iMaior], tempo[iMaior]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  lea    0x190(%rsp),%r12
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <ler_acessos@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <mais_tempo@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  lea    D7(%rip),%rdi
  mov    0x190(%rsp,%rax,4),%edx
  mov    (%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x330,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string

tool: D3: Total de acessos: %d


tool: D7: Carro que permaneceu mais tempo: %d (%d minutos)


assistant: ```c
int main() {
  int id[100], tempo[100];
  int numAcessos = ler_acessos(id, tempo);
  int iMaior = mais_tempo(tempo, numAcessos);
  printf("Total de acessos: %d\n", numAcessos);
  printf("Carro que permaneceu mais tempo: %d (%d minutos)\n", id[iMaior], tempo[iMaior]);
  return 0;
}
```